ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<openOutFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L47
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L45
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    $0x1e4,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  mov    -0x18(%rbp),%rax
  movb   $0x5c,(%rax)
L45:
  addq   $0x1,-0x18(%rbp)
L47:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x10(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L44
  mov    -0x10(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L35
L44:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L35:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string

tool: D1: rb

tool: D19: wb

assistant: ```c
int openOutFile(char *inname, FILE **outfile) {
  char *name;
  char *t;
  FILE *infile;
  name = malloc(strlen(inname) + 1);
  strcpy(name, inname);
  for (t = name; *t; t++) {
    if (*t == '\\') {
      *t = '\0';
      mkdir(name, 0744);
      *t = '\\';
    }
  }
  if (!(infile = fopen(name, "rb"))) {
    *outfile = fopen(name, "wb");
    free(name);
    return 0;
  } else {
    fclose(infile);
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<openOutFile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L35
  mov    %rbp,%rbx
  jmp    L26
L49:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L35
L26:
  cmp    $0x5c,%al
  jne    L49
  movb   $0x0,(%rbx)
  mov    $0x1e4,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  movb   $0x5c,(%rbx)
  jmp    L49
L35:
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L19
  call   <fclose@plt>
  mov    $0x1,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,(%r12)
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L21
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D17
type_guessed: string

tool: D5: rb

tool: D17: wb

assistant: ```c
int openOutFile(char *inname, FILE **outfile) {
  char *name;
  char *t;
  FILE *infile;
  name = malloc(strlen(inname) + 1);
  strcpy(name, inname);
  for (t = name; *t; t++) {
    if (*t == '\\') {
      *t = '\0';
      mkdir(name, 0744);
      *t = '\\';
    }
  }
  if (!(infile = fopen(name, "rb"))) {
    *outfile = fopen(name, "wb");
    free(name);
    return 0;
  } else {
    fclose(infile);
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<openOutFile>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L10
  mov    %rbp,%rbx
  jmp    L50
  nopl   (%rax)
L26:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L10
L50:
  cmp    $0x5c,%al
  jne    L26
  movb   $0x0,(%rbx)
  mov    $0x1e4,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <mkdir@plt>
  movb   $0x5c,-0x1(%rbx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L50
  nop
L10:
  mov    %rbp,%rdi
  lea    D12(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L40
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L40:
  mov    %rbp,%rdi
  lea    D19(%rip),%rsi
  call   <fopen@plt>
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D19
type_infered: string

tool: D12: rb

tool: D19: wb

assistant: ```c
int openOutFile(char *inname, FILE **outfile) {
  char *name;
  char *t;
  FILE *infile;
  name = malloc(strlen(inname) + 1);
  strcpy(name, inname);
  for (t = name; *t; t++) {
    if (*t == '\\') {
      *t = '\0';
      mkdir(name, 0744);
      *t = '\\';
    }
  }
  if (!(infile = fopen(name, "rb"))) {
    *outfile = fopen(name, "wb");
    free(name);
    return 0;
  } else {
    fclose(infile);
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<openOutFile>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L36
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L42:
  cmp    $0x5c,%al
  je     L4
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L42
L36:
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L56
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  movb   $0x0,(%rbx)
  mov    $0x1e4,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <mkdir@plt>
  movb   $0x5c,-0x1(%rbx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L42
  jmp    L36
  nopl   0x0(%rax)
L56:
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D10
type: string

tool: D11: rb

tool: D10: wb

assistant: ```c
int openOutFile(char *inname, FILE **outfile) {
  char *name;
  char *t;
  FILE *infile;
  name = malloc(strlen(inname) + 1);
  strcpy(name, inname);
  for (t = name; *t; t++) {
    if (*t == '\\') {
      *t = '\0';
      mkdir(name, 0744);
      *t = '\\';
    }
  }
  if (!(infile = fopen(name, "rb"))) {
    *outfile = fopen(name, "wb");
    free(name);
    return 0;
  } else {
    fclose(infile);
    return 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <allocate_map@plt>
  cmp    $0xffffffff,%eax
  jne    L7
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L37
L7:
  movl   $0x1,-0x4(%rbp)
  jmp    L1
L28:
  mov    $0x0,%eax
  call   <allocate_pid@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x12c,-0x4(%rbp)
  jle    L28
  mov    $0x1f4,%edi
  call   <release_pid@plt>
  mov    $0x0,%eax
  call   <allocate_pid@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L37:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: string

tool: D11: Map allocation failed

tool: D21: Allocated %d


assistant: ```c
int main() {
  if (allocate_map() == -1) {
    printf("Map allocation failed\n");
    return -1;
  }
  for (int i = 1; i <= 300; ++i)
    printf("Allocated %d\n", allocate_pid());
  release_pid(500);
  printf("Allocated %d\n", allocate_pid());
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <allocate_map@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    $0x12c,%ebx
  lea    D4(%rip),%rbp
L14:
  mov    $0x0,%eax
  call   <allocate_pid@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L14
  mov    $0x1f4,%edi
  call   <release_pid@plt>
  mov    $0x0,%eax
  call   <allocate_pid@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
L28:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    %eax,%ebx
  lea    D5(%rip),%rdi
  call   <puts@plt>
  jmp    L28
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string
name: read_data
arguments: tag: D5
type_infered: string

tool: D4: Allocated %d


tool: D5: Map allocation failed

assistant: ```c
int main() {
  if (allocate_map() == -1) {
    printf("Map allocation failed\n");
    return -1;
  }
  for (int i = 1; i <= 300; ++i)
    printf("Allocated %d\n", allocate_pid());
  release_pid(500);
  printf("Allocated %d\n", allocate_pid());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <allocate_map@plt>
  cmp    $0xffffffff,%eax
  je     L8
  mov    $0x12c,%ebx
  lea    D13(%rip),%rbp
L17:
  xor    %eax,%eax
  call   <allocate_pid@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L17
  mov    $0x1f4,%edi
  xor    %r12d,%r12d
  call   <release_pid@plt>
  xor    %eax,%eax
  call   <allocate_pid@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L20:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  lea    D11(%rip),%rdi
  mov    %eax,%r12d
  call   <puts@plt>
  jmp    L20
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D13: Allocated %d


tool: D11: Map allocation failed

assistant: ```c
int main() {
  if (allocate_map() == -1) {
    printf("Map allocation failed\n");
    return -1;
  }
  for (int i = 1; i <= 300; ++i)
    printf("Allocated %d\n", allocate_pid());
  release_pid(500);
  printf("Allocated %d\n", allocate_pid());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <allocate_map@plt>
  cmp    $0xffffffff,%eax
  je     L7
  mov    $0x12c,%ebx
  lea    D0(%rip),%rbp
L6:
  xor    %eax,%eax
  call   <allocate_pid@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x1f4,%edi
  xor    %r12d,%r12d
  call   <release_pid@plt>
  xor    %eax,%eax
  call   <allocate_pid@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L25:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  lea    D3(%rip),%rdi
  mov    %eax,%r12d
  call   <puts@plt>
  jmp    L25
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D3
type: string

tool: D0: Allocated %d


tool: D3: Map allocation failed

assistant: ```c
int main() {
  if (allocate_map() == -1) {
    printf("Map allocation failed\n");
    return -1;
  }
  for (int i = 1; i <= 300; ++i)
    printf("Allocated %d\n", allocate_pid());
  release_pid(500);
  printf("Allocated %d\n", allocate_pid());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GPIOPinTypeComparator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  movzbl -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <GPIODirModeSet@plt>
  movzbl -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <GPIOPadConfigSet@plt>
  nop
  leave
  ret
```

assistant: ```c
void GPIOPinTypeComparator(unsigned long ulPort, unsigned char ucPins) {
  ;
  GPIODirModeSet(ulPort, ucPins, 0x00000000);
  GPIOPadConfigSet(ulPort, ucPins, 0x00000001, 0x00000000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GPIOPinTypeComparator>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl %sil,%ebp
  mov    $0x0,%edx
  mov    %ebp,%esi
  call   <GPIODirModeSet@plt>
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <GPIOPadConfigSet@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void GPIOPinTypeComparator(unsigned long ulPort, unsigned char ucPins) {
  ;
  GPIODirModeSet(ulPort, ucPins, 0x00000000);
  GPIOPadConfigSet(ulPort, ucPins, 0x00000001, 0x00000000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GPIOPinTypeComparator>:
  endbr64
  push   %r12
  movzbl %sil,%r12d
  xor    %edx,%edx
  push   %rbp
  mov    %r12d,%esi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <GPIODirModeSet@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <GPIOPadConfigSet@plt>
```

assistant: ```c
void GPIOPinTypeComparator(unsigned long ulPort, unsigned char ucPins) {
  ;
  GPIODirModeSet(ulPort, ucPins, 0x00000000);
  GPIOPadConfigSet(ulPort, ucPins, 0x00000001, 0x00000000);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GPIOPinTypeComparator>:
  endbr64
  push   %r12
  movzbl %sil,%r12d
  xor    %edx,%edx
  push   %rbp
  mov    %r12d,%esi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <GPIODirModeSet@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <GPIOPadConfigSet@plt>
```

assistant: ```c
void GPIOPinTypeComparator(unsigned long ulPort, unsigned char ucPins) {
  ;
  GPIODirModeSet(ulPort, ucPins, 0x00000000);
  GPIOPadConfigSet(ulPort, ucPins, 0x00000001, 0x00000000);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <fork@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: This message should appear twice.

assistant: ```c
int main(void) {
  fork();
  puts("This message should appear twice.");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string

tool: D2: This message should appear twice.

assistant: ```c
int main(void) {
  fork();
  puts("This message should appear twice.");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: This message should appear twice.

assistant: ```c
int main(void) {
  fork();
  puts("This message should appear twice.");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: This message should appear twice.

assistant: ```c
int main(void) {
  fork();
  puts("This message should appear twice.");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L6
L33:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    $0x1,%eax
  jmp    L26
L38:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L33
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int cmp(const char *s, const char *t) {
  while (*s == *t) {
    if (*s == 0)
      return (1);
    s++;
    t++;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cmp>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L10
  mov    $0x1,%eax
L0:
  test   %dl,%dl
  je     L16
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  je     L0
  mov    $0x0,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cmp(const char *s, const char *t) {
  while (*s == *t) {
    if (*s == 0)
      return (1);
    s++;
    t++;
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmp>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L8
  mov    $0x1,%eax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  jne    L8
L26:
  test   %dl,%dl
  jne    L25
  mov    $0x1,%eax
  ret
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmp(const char *s, const char *t) {
  while (*s == *t) {
    if (*s == 0)
      return (1);
    s++;
    t++;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L4
  mov    $0x1,%eax
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L20:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  jne    L4
L19:
  test   %dl,%dl
  jne    L20
  mov    $0x1,%eax
  ret
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmp(const char *s, const char *t) {
  while (*s == *t) {
    if (*s == 0)
      return (1);
    s++;
    t++;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sen_data_can_sel_as_ref>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L143
  mov    $0x0,%eax
  jmp    L13
L143:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L71
L2:
  mov    -0x18(%rbp),%eax
  jmp    L13
L71:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L89
L72:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L31
  addl   $0x1,-0x4(%rbp)
L89:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L94
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L72
  jmp    L94
L31:
  nop
L94:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L127
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L96
L127:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
L96:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L63
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L63
  movl   $0x1,-0xc(%rbp)
L63:
  cmpl   $0x1,-0xc(%rbp)
  jne    L125
  negl   -0x8(%rbp)
L125:
  mov    -0x8(%rbp),%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int sen_data_can_sel_as_ref(int sen_line, int *sen_indices, int ref_line, int *ref_indices, int ref_prem) {
  if (ref_line >= sen_line)
    return 0;
  int entire;
  if (ref_prem || ref_indices[0] == -1)
    return ref_line;
  int common_line;
  int i;
  common_line = 0;
  for (i = 0; sen_indices[i] != -1 && ref_indices[i] != -1; i++) {
    if (sen_indices[i] != ref_indices[i])
      break;
  }
  if (ref_indices[i] == -1) {
    common_line = ref_line;
    entire = 0;
  } else {
    common_line = ref_indices[i];
    entire = 1;
  }
  if (ref_indices[i] != -1 && sen_indices[i] == -1)
    entire = 1;
  if (entire == 1)
    common_line *= -1;
  return common_line;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sen_data_can_sel_as_ref>:
  endbr64
  mov    %rsi,%r9
  mov    $0x0,%eax
  cmp    %edi,%edx
  jge    L12
  mov    %edx,%eax
  test   %r8d,%r8d
  jne    L12
  mov    (%rcx),%edi
  cmp    $0xffffffff,%edi
  je     L12
  mov    (%rsi),%esi
  mov    $0x0,%eax
  cmp    $0xffffffff,%esi
  je     L63
L69:
  mov    (%rcx,%rax,1),%edi
  cmp    %esi,%edi
  jne    L61
  cmp    $0xffffffff,%edi
  je     L61
  add    $0x4,%rax
  mov    (%r9,%rax,1),%esi
  cmp    $0xffffffff,%esi
  jne    L69
L61:
  mov    (%rcx,%rax,1),%edi
  cmp    $0xffffffff,%edi
  je     L76
L63:
  mov    %edi,%eax
  neg    %eax
L12:
  ret
L76:
  mov    %edx,%eax
  ret
```

assistant: ```c
int sen_data_can_sel_as_ref(int sen_line, int *sen_indices, int ref_line, int *ref_indices, int ref_prem) {
  if (ref_line >= sen_line)
    return 0;
  int entire;
  if (ref_prem || ref_indices[0] == -1)
    return ref_line;
  int common_line;
  int i;
  common_line = 0;
  for (i = 0; sen_indices[i] != -1 && ref_indices[i] != -1; i++) {
    if (sen_indices[i] != ref_indices[i])
      break;
  }
  if (ref_indices[i] == -1) {
    common_line = ref_line;
    entire = 0;
  } else {
    common_line = ref_indices[i];
    entire = 1;
  }
  if (ref_indices[i] != -1 && sen_indices[i] == -1)
    entire = 1;
  if (entire == 1)
    common_line *= -1;
  return common_line;
}
```