ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  call   <initfrand@plt>
  lea    0x40(%rsp),%rbx
  lea    0x80(%rsp),%rbp
L21:
  mov    $0x3e8,%esi
  mov    $0xfffffc18,%edi
  call   <frand@plt>
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L21
  mov    %rsp,%rbx
  lea    0x10(%rsp),%rbp
L12:
  mov    $0x3e8,%esi
  mov    $0xfffffc18,%edi
  call   <frand@plt>
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L12
  lea    0x20(%rsp),%rdx
  mov    %rsp,%rbp
  lea    0x40(%rsp),%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sse_matvec_mult@plt>
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <matvec_mult@plt>
  mov    $0x0,%eax
  lea    0x20(%rsp),%rdx
  movsd  D19(%rip),%xmm3
  movsd  D38(%rip),%xmm2
L1:
  movss  0x10(%rsp,%rax,1),%xmm1
  divss  (%rax,%rdx,1),%xmm1
  cvtss2sd %xmm1,%xmm1
  movapd %xmm3,%xmm0
  subsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x30(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L1
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  call   <print_vec_float@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rdi
  call   <print_vec_float@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0x30(%rsp),%rdi
  call   <print_vec_float@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_guessed: f64
name: disassemble_data
arguments: data_label: D38
type_guessed: f64
name: disassemble_data
arguments: data_label: D42
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string

tool: D19: 1

tool: D38: 100

tool: D42:     ref = 

tool: D1:     SSE = 

tool: D26: err [%%] = 

assistant: ```c
int main() {
  int i;
  float mat[4 * 4], vec[4], res1[4], res2[4], err[4];
  initfrand();
  for (i = 0; i < 16; i++)
    mat[i] = frand(-1000, 1000);
  for (i = 0; i < 4; i++)
    vec[i] = frand(-1000, 1000);
  sse_matvec_mult(mat, vec, res2);
  matvec_mult(mat, vec, res1);
  for (i = 0; i < 4; i++)
    err[i] = 100.0 * (1.0 - res1[i] / res2[i]);
  printf("    ref = ");
  print_vec_float(res1);
  printf("    SSE = ");
  print_vec_float(res2);
  printf("err [%%] = ");
  print_vec_float(err);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%r12
  lea    0x80(%rsp),%rbp
  mov    %r12,%rbx
  call   <initfrand@plt>
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0x3e8,%esi
  mov    $0xfffffc18,%edi
  add    $0x4,%rbx
  call   <frand@plt>
  movss  %xmm0,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L39
  mov    %rsp,%r14
  lea    0x10(%rsp),%rbp
  mov    %r14,%rbx
L11:
  mov    $0x3e8,%esi
  mov    $0xfffffc18,%edi
  add    $0x4,%rbx
  call   <frand@plt>
  movss  %xmm0,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L11
  lea    0x20(%rsp),%r13
  mov    %r12,%rdi
  mov    %r14,%rsi
  mov    %r13,%rdx
  call   <sse_matvec_mult@plt>
  mov    %r12,%rdi
  mov    %rbp,%rdx
  mov    %r14,%rsi
  call   <matvec_mult@plt>
  movsd  D8(%rip),%xmm3
  xor    %eax,%eax
  lea    0x30(%rsp),%r12
  movsd  D46(%rip),%xmm2
L38:
  movapd %xmm3,%xmm0
  movss  0x0(%rbp,%rax,1),%xmm1
  divss  0x0(%r13,%rax,1),%xmm1
  cvtss2sd %xmm1,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%r12,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L38
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_vec_float@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <print_vec_float@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <print_vec_float@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: f64
name: parse_data
arguments: tag: D46
type_guessed: f64
name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D35
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string

tool: D8: 1

tool: D46: 100

tool: D6:     ref = 

tool: D35:     SSE = 

tool: D9: err [%%] = 

assistant: ```c
int main() {
  int i;
  float mat[4 * 4], vec[4], res1[4], res2[4], err[4];
  initfrand();
  for (i = 0; i < 16; i++)
    mat[i] = frand(-1000, 1000);
  for (i = 0; i < 4; i++)
    vec[i] = frand(-1000, 1000);
  sse_matvec_mult(mat, vec, res2);
  matvec_mult(mat, vec, res1);
  for (i = 0; i < 4; i++)
    err[i] = 100.0 * (1.0 - res1[i] / res2[i]);
  printf("    ref = ");
  print_vec_float(res1);
  printf("    SSE = ");
  print_vec_float(res2);
  printf("err [%%] = ");
  print_vec_float(err);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%r12
  lea    0x80(%rsp),%rbp
  mov    %r12,%rbx
  call   <initfrand@plt>
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x3e8,%esi
  mov    $0xfffffc18,%edi
  add    $0x4,%rbx
  call   <frand@plt>
  movss  %xmm0,-0x4(%rbx)
  cmp    %rbx,%rbp
  jne    L29
  mov    %rsp,%r13
  lea    0x10(%rsp),%rbx
  mov    %r13,%rbp
L5:
  mov    $0x3e8,%esi
  mov    $0xfffffc18,%edi
  add    $0x4,%rbp
  call   <frand@plt>
  movss  %xmm0,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L5
  lea    0x20(%rsp),%r14
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %r14,%rdx
  call   <sse_matvec_mult@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <matvec_mult@plt>
  movapd D14(%rip),%xmm0
  movaps 0x10(%rsp),%xmm3
  divps  0x20(%rsp),%xmm3
  cvtps2pd %xmm3,%xmm2
  movapd D34(%rip),%xmm4
  lea    D18(%rip),%rdi
  movapd %xmm0,%xmm1
  subpd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  movhlps %xmm3,%xmm2
  cvtps2pd %xmm2,%xmm2
  subpd  %xmm2,%xmm0
  mulpd  %xmm4,%xmm1
  mulpd  %xmm4,%xmm0
  cvtpd2ps %xmm1,%xmm1
  cvtpd2ps %xmm0,%xmm0
  movlhps %xmm0,%xmm1
  movaps %xmm1,0x30(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_vec_float@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <print_vec_float@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    0x30(%rsp),%rdi
  call   <print_vec_float@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D14
type_guessed: f64[2]
name: read_data
arguments: label: D34
type_guessed: f64[2]
name: read_data
arguments: label: D18
type_guessed: string
name: read_data
arguments: label: D45
type_guessed: string
name: read_data
arguments: label: D33
type_guessed: string

tool: {"D14": [1.0,1.0]}

tool: {"D34": [100.0,100.0]}

tool: D18:     ref = 

tool: D45:     SSE = 

tool: D33: err [%%] = 

assistant: ```c
int main() {
  int i;
  float mat[4 * 4], vec[4], res1[4], res2[4], err[4];
  initfrand();
  for (i = 0; i < 16; i++)
    mat[i] = frand(-1000, 1000);
  for (i = 0; i < 4; i++)
    vec[i] = frand(-1000, 1000);
  sse_matvec_mult(mat, vec, res2);
  matvec_mult(mat, vec, res1);
  for (i = 0; i < 4; i++)
    err[i] = 100.0 * (1.0 - res1[i] / res2[i]);
  printf("    ref = ");
  print_vec_float(res1);
  printf("    SSE = ");
  print_vec_float(res2);
  printf("err [%%] = ");
  print_vec_float(err);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0xd8(%rbp)
  movl   $0x2,-0xd0(%rbp)
  movl   $0x3,-0xcc(%rbp)
  movl   $0x5,-0xe0(%rbp)
  jmp    L26
L63:
  movl   $0x1,-0xd4(%rbp)
  movl   $0x1,-0xdc(%rbp)
  jmp    L97
L83:
  mov    -0xdc(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%ecx
  mov    -0xe0(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L36
  movl   $0x0,-0xd4(%rbp)
L36:
  addl   $0x1,-0xdc(%rbp)
L97:
  cmpl   $0x0,-0xd4(%rbp)
  je     L93
  mov    -0xdc(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%esi
  mov    -0xe0(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,%edx
  mov    -0xdc(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jge    L83
L93:
  cmpl   $0x1,-0xd4(%rbp)
  jne    L33
  mov    -0xd8(%rbp),%eax
  cltq
  mov    -0xe0(%rbp),%edx
  mov    %edx,-0xd0(%rbp,%rax,4)
  addl   $0x1,-0xd8(%rbp)
L33:
  addl   $0x2,-0xe0(%rbp)
L26:
  cmpl   $0x32,-0xe0(%rbp)
  jle    L63
  movl   $0x0,-0xdc(%rbp)
  jmp    L53
L16:
  mov    -0xdc(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xdc(%rbp)
L53:
  mov    -0xdc(%rbp),%eax
  cmp    -0xd8(%rbp),%eax
  jl     L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %i 

assistant: ```c
int main(void) {
  int p, i;
  int primes[50];
  int primeIndex = 2;
  int isPrime;
  primes[0] = 2;
  primes[1] = 3;
  for (p = 5; p <= 50; p = p + 2) {
    isPrime = 1;
    for (i = 1; isPrime && p / primes[i] >= primes[i]; ++i) {
      if (p % primes[i] == 0) {
        isPrime = 0;
      }
    }
    if (isPrime == 1) {
      primes[primeIndex] = p;
      ++primeIndex;
    }
  }
  for (i = 0; i < primeIndex; ++i) {
    printf("%i ", primes[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x3,0x4(%rsp)
  mov    $0x2,%r8d
  mov    $0x5,%esi
L29:
  lea    0x4(%rsp),%rdi
L36:
  mov    (%rdi),%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    %eax,%ecx
  jg     L44
  add    $0x4,%rdi
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L36
L10:
  add    $0x2,%esi
  cmp    $0x33,%esi
  jne    L29
  test   %r8d,%r8d
  jle    L5
  mov    %rsp,%rbx
  lea    -0x1(%r8),%eax
  lea    0x4(%rsp,%rax,4),%r12
  lea    D1(%rip),%rbp
L21:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L21
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  movslq %r8d,%rax
  mov    %esi,(%rsp,%rax,4)
  add    $0x1,%r8d
  jmp    L10
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: %i 

assistant: ```c
int main(void) {
  int p, i;
  int primes[50];
  int primeIndex = 2;
  int isPrime;
  primes[0] = 2;
  primes[1] = 3;
  for (p = 5; p <= 50; p = p + 2) {
    isPrime = 1;
    for (i = 1; isPrime && p / primes[i] >= primes[i]; ++i) {
      if (p % primes[i] == 0) {
        isPrime = 0;
      }
    }
    if (isPrime == 1) {
      primes[primeIndex] = p;
      ++primeIndex;
    }
  }
  for (i = 0; i < primeIndex; ++i) {
    printf("%i ", primes[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%r8d
  mov    $0x5,%esi
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movl   $0x3,0x4(%rsp)
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L45:
  add    $0x2,%esi
  cmp    $0x33,%esi
  je     L4
L81:
  lea    0x8(%rsp),%rdi
  mov    $0x3,%ecx
  cmp    $0x8,%esi
  jle    L31
  nopw   0x0(%rax,%rax,1)
L72:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L45
  mov    (%rdi),%ecx
  mov    %esi,%eax
  add    $0x4,%rdi
  cltd
  idiv   %ecx
  cmp    %eax,%ecx
  jle    L72
L31:
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %esi,(%rsp,%rax,4)
  add    $0x2,%esi
  cmp    $0x33,%esi
  jne    L81
L4:
  lea    0x4(%rsp),%rbx
  lea    -0x1(%r8),%eax
  mov    $0x2,%esi
  lea    (%rbx,%rax,4),%r12
  lea    D0(%rip),%rbp
  jmp    L43
  nopl   (%rax)
L22:
  mov    (%rbx),%esi
  add    $0x4,%rbx
L43:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: %i 

assistant: ```c
int main(void) {
  int p, i;
  int primes[50];
  int primeIndex = 2;
  int isPrime;
  primes[0] = 2;
  primes[1] = 3;
  for (p = 5; p <= 50; p = p + 2) {
    isPrime = 1;
    for (i = 1; isPrime && p / primes[i] >= primes[i]; ++i) {
      if (p % primes[i] == 0) {
        isPrime = 0;
      }
    }
    if (isPrime == 1) {
      primes[primeIndex] = p;
      ++primeIndex;
    }
  }
  for (i = 0; i < primeIndex; ++i) {
    printf("%i ", primes[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%r8d
  mov    $0x5,%esi
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    %rax,(%rsp)
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x2,%esi
  cmp    $0x33,%esi
  je     L29
L65:
  lea    0x8(%rsp),%rdi
  mov    $0x3,%ecx
  cmp    $0x8,%esi
  jle    L60
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L37
  mov    (%rdi),%ecx
  mov    %esi,%eax
  add    $0x4,%rdi
  cltd
  idiv   %ecx
  cmp    %eax,%ecx
  jle    L40
L60:
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %esi,(%rsp,%rax,4)
  add    $0x2,%esi
  cmp    $0x33,%esi
  jne    L65
L29:
  lea    -0x1(%r8),%eax
  mov    %rsp,%rbx
  lea    D12(%rip),%rbp
  lea    0x4(%rsp,%rax,4),%r12
  nopl   (%rax)
L24:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L24
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
datatype: byte[8]
name: retrieve_data
arguments: tag: D12
datatype: string

tool: {"D15": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D12: %i 

assistant: ```c
int main(void) {
  int p, i;
  int primes[50];
  int primeIndex = 2;
  int isPrime;
  primes[0] = 2;
  primes[1] = 3;
  for (p = 5; p <= 50; p = p + 2) {
    isPrime = 1;
    for (i = 1; isPrime && p / primes[i] >= primes[i]; ++i) {
      if (p % primes[i] == 0) {
        isPrime = 0;
      }
    }
    if (isPrime == 1) {
      primes[primeIndex] = p;
      ++primeIndex;
    }
  }
  for (i = 0; i < primeIndex; ++i) {
    printf("%i ", primes[i]);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(void *v[], int i, int j) {
  void *temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rcx
  mov    (%rcx),%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *v[], int i, int j) {
  void *temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,8),%rcx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rcx),%rsi
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *v[], int i, int j) {
  void *temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,8),%rcx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rcx),%rsi
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *v[], int i, int j) {
  void *temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L26:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L26
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D34
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string

tool: D34: %d

tool: D15: %d %d %d

assistant: ```c
int main() {
  int a, b, c, n, i;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d", a, b, c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L18
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rbp
L12:
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  call   <rotr@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jg     L12
L18:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D18
type: string

tool: D12: %d

tool: D18: %d %d %d

assistant: ```c
int main() {
  int a, b, c, n, i;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d", a, b, c);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%r13
  mov    %r12,%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L11
  xor    %ebx,%ebx
  xchg   %ax,%ax
L0:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L0
L11:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D2(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
datatype: string
name: unpack_data
arguments: data_tag: D2
datatype: string

tool: D18: %d

tool: D2: %d %d %d

assistant: ```c
int main() {
  int a, b, c, n, i;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d", a, b, c);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%r13
  mov    %r12,%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L29
  xor    %ebx,%ebx
  xchg   %ax,%ax
L18:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L18
L29:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D9(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D3: %d

tool: D9: %d %d %d

assistant: ```c
int main() {
  int a, b, c, n, i;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d", a, b, c);
}
```