ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gcd>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  cmp    %esi,%edi
  jg     L29
  cltd
  idiv   %edi
  mov    %edi,%eax
  test   %edx,%edx
  jne    L22
L14:
  add    $0x8,%rsp
  ret
L29:
  mov    %edi,%esi
  mov    %eax,%edi
  call   <gcd>
  jmp    L14
L22:
  mov    %edi,%esi
  mov    %edx,%edi
  call   <gcd>
  jmp    L14
```

assistant: ```c
int gcd(int a, int b) {
  if (a > b)
    return gcd(b, a);
  if (b % a == 0)
    return a;
  return gcd(b % a, a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gcd>:
  endbr64
  mov    %edi,%r8d
  jmp    L26
  nopl   0x0(%rax)
L6:
  mov    %r8d,%eax
  mov    %esi,%r8d
  mov    %eax,%esi
L26:
  cmp    %esi,%r8d
  jg     L6
  mov    %esi,%eax
  cltd
  idiv   %r8d
  mov    %edx,%esi
  test   %edx,%edx
  jne    L6
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (a > b)
    return gcd(b, a);
  if (b % a == 0)
    return a;
  return gcd(b % a, a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  mov    %edi,%r8d
  jmp    L0
  nopl   0x0(%rax)
L26:
  mov    %r8d,%eax
  mov    %esi,%r8d
  mov    %eax,%esi
L0:
  cmp    %esi,%r8d
  jg     L26
  mov    %esi,%eax
  cltd
  idiv   %r8d
  mov    %edx,%esi
  test   %edx,%edx
  jne    L26
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (a > b)
    return gcd(b, a);
  if (b % a == 0)
    return a;
  return gcd(b % a, a);
}
```
user: What is the c source code of the assembly code below?

```asm
<inportl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int inportl(unsigned short __port) {
  unsigned int __val;
  __asm__ volatile("inl %1,%0" : "=a"(__val) : "dN"(__port));
  return __val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inportl>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%eax
  ret
```

assistant: ```c
unsigned int inportl(unsigned short __port) {
  unsigned int __val;
  __asm__ volatile("inl %1,%0" : "=a"(__val) : "dN"(__port));
  return __val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inportl>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%eax
  ret
```

assistant: ```c
unsigned int inportl(unsigned short __port) {
  unsigned int __val;
  __asm__ volatile("inl %1,%0" : "=a"(__val) : "dN"(__port));
  return __val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inportl>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%eax
  ret
```

assistant: ```c
unsigned int inportl(unsigned short __port) {
  unsigned int __val;
  __asm__ volatile("inl %1,%0" : "=a"(__val) : "dN"(__port));
  return __val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L57
L34:
  lea    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x48(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L30
  addl   $0x1,-0x44(%rbp)
L30:
  mov    -0x48(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  je     L48
  addl   $0x1,-0x48(%rbp)
L57:
  cmpl   $0x30,-0x48(%rbp)
  jle    L34
  jmp    L12
L48:
  nop
L12:
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D25
type_guessed: string
name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D28
type_guessed: string
name: unpack_data
arguments: data_label: D7
type_guessed: string

tool: D25: This Program count spaces in a string


tool: D10: Please enter a string:

tool: D28: %c

tool: D7: The spaces count is: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  char ch[50];
  int i, count;
  printf("This Program count spaces in a string\n\n");
  printf("Please enter a string:\n");
  for (i = 0; i < 49; i++) {
    scanf("%c", &ch[i]);
    if (ch[i] == ' ') {
      count++;
    }
    if (ch[i] == '\n') {
      break;
    }
  }
  printf("The spaces count is: %d\n", count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x31(%rsp),%r12
  lea    D4(%rip),%rbp
  jmp    L4
L48:
  add    $0x1,%r13d
L13:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L34
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L48
  cmp    $0xa,%al
  jne    L13
L34:
  mov    %r13d,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string
name: extract_symbolic_data
arguments: data_label: D33
type_infered: string
name: extract_symbolic_data
arguments: data_label: D4
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D5: This Program count spaces in a string


tool: D33: Please enter a string:

tool: D4: %c

tool: D6: The spaces count is: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  char ch[50];
  int i, count;
  printf("This Program count spaces in a string\n\n");
  printf("Please enter a string:\n");
  for (i = 0; i < 49; i++) {
    scanf("%c", &ch[i]);
    if (ch[i] == ' ') {
      count++;
    }
    if (ch[i] == '\n') {
      break;
    }
  }
  printf("The spaces count is: %d\n", count);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x31(%rsp),%r12
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L45:
  cmp    $0xa,%al
  je     L11
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L11
L28:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L45
  add    $0x1,%rbx
  add    $0x1,%r13d
  cmp    %rbx,%r12
  jne    L28
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  mov    %r13d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string
name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D19: This Program count spaces in a string


tool: D3: %c

tool: D16: Please enter a string:

tool: D9: The spaces count is: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  char ch[50];
  int i, count;
  printf("This Program count spaces in a string\n\n");
  printf("Please enter a string:\n");
  for (i = 0; i < 49; i++) {
    scanf("%c", &ch[i]);
    if (ch[i] == ' ') {
      count++;
    }
    if (ch[i] == '\n') {
      break;
    }
  }
  printf("The spaces count is: %d\n", count);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D33(%rip),%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x31(%rsp),%r12
  call   <puts@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L19:
  cmp    $0xa,%al
  je     L16
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L16
L11:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L19
  add    $0x1,%rbx
  add    $0x1,%r13d
  cmp    %rbx,%r12
  jne    L11
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  mov    %r13d,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D33
datatype: string
name: retrieve_data
arguments: label: D38
datatype: string
name: retrieve_data
arguments: label: D29
datatype: string

tool: D3: This Program count spaces in a string


tool: D33: %c

tool: D38: Please enter a string:

tool: D29: The spaces count is: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  char ch[50];
  int i, count;
  printf("This Program count spaces in a string\n\n");
  printf("Please enter a string:\n");
  for (i = 0; i < 49; i++) {
    scanf("%c", &ch[i]);
    if (ch[i] == ' ') {
      count++;
    }
    if (ch[i] == '\n') {
      break;
    }
  }
  printf("The spaces count is: %d\n", count);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x7,-0xc(%rbp)
  movq   $0xb8000,-0x8(%rbp)
  jmp    L14
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void kprint(char *string) {
  int color = 0x07;
  volatile char *video = (volatile char *)0xB8000;
  while (*string != 0) {
    *video = *string;
    string++;
    video++;
    *video = color;
    video++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kprint>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L12
  mov    $0xb8000,%eax
L19:
  mov    %dl,(%rax)
  add    $0x1,%rdi
  movb   $0x7,0x1(%rax)
  add    $0x2,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
L12:
  ret
```

assistant: ```c
void kprint(char *string) {
  int color = 0x07;
  volatile char *video = (volatile char *)0xB8000;
  while (*string != 0) {
    *video = *string;
    string++;
    video++;
    *video = color;
    video++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kprint>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L6
  mov    $0xb8000,%eax
L11:
  add    $0x1,%rdi
  mov    %dl,(%rax)
  add    $0x2,%rax
  movb   $0x7,-0x1(%rax)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L11
L6:
  ret
```

assistant: ```c
void kprint(char *string) {
  int color = 0x07;
  volatile char *video = (volatile char *)0xB8000;
  while (*string != 0) {
    *video = *string;
    string++;
    video++;
    *video = color;
    video++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kprint>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  mov    $0xb8000,%eax
L19:
  add    $0x1,%rdi
  mov    %dl,(%rax)
  add    $0x2,%rax
  movb   $0x7,-0x1(%rax)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
L15:
  ret
```

assistant: ```c
void kprint(char *string) {
  int color = 0x07;
  volatile char *video = (volatile char *)0xB8000;
  while (*string != 0) {
    *video = *string;
    string++;
    video++;
    *video = color;
    video++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<concat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L9
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L9:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void concat(char **s1, const char *s2) {
  if (s2) {
    *s1 = (char *)realloc(*s1, strlen(*s1) + strlen(s2) + 1 + 1);
    strcat(*s1, s2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat>:
  endbr64
  test   %rsi,%rsi
  je     L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    (%rdi),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rsi
  mov    %r13,%rdi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  mov    %rbx,%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

assistant: ```c
void concat(char **s1, const char *s2) {
  if (s2) {
    *s1 = (char *)realloc(*s1, strlen(*s1) + strlen(s2) + 1 + 1);
    strcat(*s1, s2);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<concat>:
  endbr64
  test   %rsi,%rsi
  je     L3
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x2(%r12,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <strcat@plt>
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void concat(char **s1, const char *s2) {
  if (s2) {
    *s1 = (char *)realloc(*s1, strlen(*s1) + strlen(s2) + 1 + 1);
    strcat(*s1, s2);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<concat>:
  endbr64
  test   %rsi,%rsi
  je     L9
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x2(%r12,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <strcat@plt>
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void concat(char **s1, const char *s2) {
  if (s2) {
    *s1 = (char *)realloc(*s1, strlen(*s1) + strlen(s2) + 1 + 1);
    strcat(*s1, s2);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mp_mul_csqu>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%r13
  lea    0x8(%rsi),%r14
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %r14,%rdx
  mov    $0x1,%esi
  call   <cdft@plt>
  mov    0x4(%r12),%eax
  shl    $0x2,%eax
  cmp    %ebp,%eax
  jl     L2
L7:
  movsd  (%rbx),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rbx)
  movsd  0x8(%rbx),%xmm0
  movsd  0x10(%rbx),%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm1,%xmm3
  mulsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm2
  movsd  %xmm2,0x8(%rbx)
  addsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbx)
  cmp    $0x2,%ebp
  jg     L10
L18:
  movslq %ebp,%rax
  lea    0x8(%rbx,%rax,8),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    $0xffffffff,%esi
  mov    %ebp,%edi
  call   <cdft@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  movslq (%r12),%rax
  lea    0x0(%r13,%rax,8),%rdx
  mov    %ebp,%edi
  sar    $0x2,%edi
  mov    %r12,%rsi
  call   <makect@plt>
  jmp    L7
L10:
  movslq (%r12),%rax
  lea    0x0(%r13,%rax,8),%rcx
  mov    0x4(%r12),%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <mp_mul_rcsqu@plt>
  jmp    L18
```

assistant: ```c
void mp_mul_csqu(int nfft, double d1[], int ip[], double w[]) {
  void makect(int nc, int *ip, double *c);
  void cdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_rcsqu(int n, double *a, int nc, double *c);
  double xr, xi;
  cdft(nfft, 1, &d1[1], ip, w);
  if (nfft > (ip[1] << 2)) {
    makect(nfft >> 2, ip, &w[ip[0]]);
  }
  d1[0] *= 2;
  xr = d1[1] * d1[1] + d1[2] * d1[2];
  xi = 2 * d1[1] * d1[2];
  d1[1] = xr;
  d1[2] = xi;
  if (nfft > 2) {
    mp_mul_rcsqu(nfft, &d1[1], ip[1], &w[ip[0]]);
  }
  d1[nfft + 1] *= d1[nfft + 1];
  cdft(nfft, -1, &d1[1], ip, w);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mp_mul_csqu>:
  endbr64
  push   %r14
  lea    0x8(%rsi),%r14
  mov    %rcx,%r8
  push   %r13
  mov    %rcx,%r13
  mov    %rdx,%rcx
  push   %r12
  mov    %rdx,%r12
  mov    %r14,%rdx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <cdft@plt>
  mov    0x4(%r12),%eax
  shl    $0x2,%eax
  cmp    %ebp,%eax
  jl     L10
L16:
  movsd  (%rbx),%xmm0
  movsd  0x10(%rbx),%xmm1
  addsd  %xmm0,%xmm0
  movapd %xmm1,%xmm3
  mulsd  %xmm1,%xmm3
  movsd  %xmm0,(%rbx)
  movsd  0x8(%rbx),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm2
  movsd  %xmm0,0x10(%rbx)
  movsd  %xmm2,0x8(%rbx)
  cmp    $0x2,%ebp
  jg     L29
L24:
  movslq %ebp,%rax
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %r14,%rdx
  lea    0x8(%rbx,%rax,8),%rax
  mov    %ebp,%edi
  mov    $0xffffffff,%esi
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <cdft@plt>
  nopl   0x0(%rax)
L10:
  movslq (%r12),%rax
  mov    %ebp,%edi
  mov    %r12,%rsi
  sar    $0x2,%edi
  lea    0x0(%r13,%rax,8),%rdx
  call   <makect@plt>
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L29:
  movslq (%r12),%rax
  mov    0x4(%r12),%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  lea    0x0(%r13,%rax,8),%rcx
  call   <mp_mul_rcsqu@plt>
  jmp    L24
```

assistant: ```c
void mp_mul_csqu(int nfft, double d1[], int ip[], double w[]) {
  void makect(int nc, int *ip, double *c);
  void cdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_rcsqu(int n, double *a, int nc, double *c);
  double xr, xi;
  cdft(nfft, 1, &d1[1], ip, w);
  if (nfft > (ip[1] << 2)) {
    makect(nfft >> 2, ip, &w[ip[0]]);
  }
  d1[0] *= 2;
  xr = d1[1] * d1[1] + d1[2] * d1[2];
  xi = 2 * d1[1] * d1[2];
  d1[1] = xr;
  d1[2] = xi;
  if (nfft > 2) {
    mp_mul_rcsqu(nfft, &d1[1], ip[1], &w[ip[0]]);
  }
  d1[nfft + 1] *= d1[nfft + 1];
  cdft(nfft, -1, &d1[1], ip, w);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mp_mul_csqu>:
  endbr64
  push   %r14
  lea    0x8(%rsi),%r14
  mov    %rcx,%r8
  push   %r13
  mov    %rcx,%r13
  mov    %rdx,%rcx
  push   %r12
  mov    %rdx,%r12
  mov    %r14,%rdx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <cdft@plt>
  mov    0x4(%r12),%eax
  shl    $0x2,%eax
  cmp    %ebp,%eax
  jl     L1
L26:
  movsd  0x8(%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  movsd  (%rbx),%xmm1
  movapd %xmm0,%xmm3
  movapd %xmm2,%xmm4
  mulsd  %xmm0,%xmm3
  addsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm4
  mulsd  %xmm2,%xmm0
  addsd  %xmm4,%xmm3
  movsd  %xmm0,0x10(%rbx)
  unpcklpd %xmm3,%xmm1
  movups %xmm1,(%rbx)
  cmp    $0x2,%ebp
  jg     L22
L33:
  movslq %ebp,%rax
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %r14,%rdx
  lea    0x8(%rbx,%rax,8),%rax
  mov    %ebp,%edi
  mov    $0xffffffff,%esi
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <cdft@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  movslq (%r12),%rax
  mov    %ebp,%edi
  mov    %r12,%rsi
  sar    $0x2,%edi
  lea    0x0(%r13,%rax,8),%rdx
  call   <makect@plt>
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L22:
  movslq (%r12),%rax
  mov    0x4(%r12),%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  lea    0x0(%r13,%rax,8),%rcx
  call   <mp_mul_rcsqu@plt>
  jmp    L33
```

assistant: ```c
void mp_mul_csqu(int nfft, double d1[], int ip[], double w[]) {
  void makect(int nc, int *ip, double *c);
  void cdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_rcsqu(int n, double *a, int nc, double *c);
  double xr, xi;
  cdft(nfft, 1, &d1[1], ip, w);
  if (nfft > (ip[1] << 2)) {
    makect(nfft >> 2, ip, &w[ip[0]]);
  }
  d1[0] *= 2;
  xr = d1[1] * d1[1] + d1[2] * d1[2];
  xi = 2 * d1[1] * d1[2];
  d1[1] = xr;
  d1[2] = xi;
  if (nfft > 2) {
    mp_mul_rcsqu(nfft, &d1[1], ip[1], &w[ip[0]]);
  }
  d1[nfft + 1] *= d1[nfft + 1];
  cdft(nfft, -1, &d1[1], ip, w);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    %eax,%edi
  call   <funkcja@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_guessed: string
name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D19: %d %d

tool: D3: Iloraz: %d
Reszta: %d


assistant: ```c
int main() {
  int iloraz, reszta, l1, l2;
  scanf("%d %d", &l1, &l2);
  funkcja(l1, l2, &iloraz, &reszta);
  printf("Iloraz: %d\nReszta: %d\n", iloraz, reszta);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <funkcja@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string

tool: D12: %d %d

tool: D16: Iloraz: %d
Reszta: %d


assistant: ```c
int main() {
  int iloraz, reszta, l1, l2;
  scanf("%d %d", &l1, &l2);
  funkcja(l1, l2, &iloraz, &reszta);
  printf("Iloraz: %d\nReszta: %d\n", iloraz, reszta);
}
```