ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<JsonEscapeString>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x318,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x308(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L65:
  movb   $0x2e,(%r15,%rbx,1)
L70:
  add    $0x1,%rbx
L11:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L48
  movsbl (%r15,%rbx,1),%edx
  cmp    $0x22,%dl
  je     L25
  cmp    $0x2c,%dl
  je     L65
  movslq %ebp,%rdi
  mov    %r13,%rsi
  add    %rbx,%rdi
  add    %r12,%rdi
  call   <sprintf@plt>
  jmp    L70
  nop
L25:
  movslq %ebp,%rdi
  mov    $0x22,%edx
  mov    %r14,%rsi
  add    $0x1,%ebp
  add    %rbx,%rdi
  add    %r12,%rdi
  call   <sprintf@plt>
  jmp    L70
  nopl   0x0(%rax,%rax,1)
L48:
  test   %ebp,%ebp
  je     L73
  mov    %r15,%rdi
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %eax,%edx
  call   <memset@plt>
  mov    %rsp,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
L73:
  mov    0x308(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x318,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string

tool: D0: \%c

tool: D8: %c

assistant: ```c
int JsonEscapeString(char *str) {
  char buffer[3 * 256];
  int i = 0, n = 0;
  for (i = 0; i < strlen(str); ++i) {
    if (str[i] == '"') {
      sprintf(buffer + i + n, "\\%c", str[i]);
      ++n;
    } else if (str[i] == ',') {
      str[i] = '.';
    } else {
      sprintf(buffer + i + n, "%c", str[i]);
    }
  }
  if (n > 0) {
    memset(str, 0, strlen(str));
    strcpy(str, buffer);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<SerialOutputString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L10
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <print_byte@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L25
  mov    $0xd,%edi
  call   <print_byte@plt>
L25:
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void SerialOutputString(const char *s) {
  while (*s != 0) {
    print_byte(*s);
    if (*s == '\n')
      print_byte('\r');
    s++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SerialOutputString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L3
L4:
  pop    %rbx
  ret
L17:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L4
L3:
  movsbl %dil,%edi
  call   <print_byte@plt>
  cmpb   $0xa,(%rbx)
  jne    L17
  mov    $0xd,%edi
  call   <print_byte@plt>
  jmp    L17
```

assistant: ```c
void SerialOutputString(const char *s) {
  while (*s != 0) {
    print_byte(*s);
    if (*s == '\n')
      print_byte('\r');
    s++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SerialOutputString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L45
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L30:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L31
L45:
  call   <print_byte@plt>
  cmpb   $0xa,(%rbx)
  jne    L30
  mov    $0xd,%edi
  add    $0x1,%rbx
  call   <print_byte@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L45
L31:
  pop    %rbx
  ret
```

assistant: ```c
void SerialOutputString(const char *s) {
  while (*s != 0) {
    print_byte(*s);
    if (*s == '\n')
      print_byte('\r');
    s++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SerialOutputString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
L21:
  call   <print_byte@plt>
  cmpb   $0xa,(%rbx)
  je     L12
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L21
L10:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L12:
  mov    $0xd,%edi
  add    $0x1,%rbx
  call   <print_byte@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L21
  pop    %rbx
  ret
```

assistant: ```c
void SerialOutputString(const char *s) {
  while (*s != 0) {
    print_byte(*s);
    if (*s == '\n')
      print_byte('\r');
    s++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <stmg_no_wrap@plt>
  mov    $0x1,%edx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  call   <stmg_wrap@plt>
  mov    $0x1,%edx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string

tool: D4: 


assistant: ```c
int main(void) {
  stmg_no_wrap();
  write(1, "\n", 1);
  stmg_wrap();
  write(1, "\n", 1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <stmg_no_wrap@plt>
  mov    $0x1,%edx
  lea    D0(%rip),%rbx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  call   <stmg_wrap@plt>
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: 


assistant: ```c
int main(void) {
  stmg_no_wrap();
  write(1, "\n", 1);
  stmg_wrap();
  write(1, "\n", 1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D0(%rip),%rbp
  call   <stmg_no_wrap@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  call   <stmg_wrap@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: 


assistant: ```c
int main(void) {
  stmg_no_wrap();
  write(1, "\n", 1);
  stmg_wrap();
  write(1, "\n", 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D7(%rip),%rbp
  call   <stmg_no_wrap@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  call   <stmg_wrap@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: 


assistant: ```c
int main(void) {
  stmg_no_wrap();
  write(1, "\n", 1);
  stmg_wrap();
  write(1, "\n", 1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L1
L6:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <task@plt>
  addq   $0x1,-0x8(%rbp)
L1:
  cmpq   $0x4,-0x8(%rbp)
  jle    L6
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string
name: read_data
arguments: data_tag: D3
type: string

tool: D5: Main started


tool: D3: Main completed


assistant: ```c
int main() {
  printf("Main started\n");
  long t;
  for (t = 0; t < 5; t++) {
    task(t);
  }
  printf("Main completed\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <task@plt>
  mov    $0x1,%edi
  call   <task@plt>
  mov    $0x2,%edi
  call   <task@plt>
  mov    $0x3,%edi
  call   <task@plt>
  mov    $0x4,%edi
  call   <task@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D18: Main started


tool: D5: Main completed


assistant: ```c
int main() {
  printf("Main started\n");
  long t;
  for (t = 0; t < 5; t++) {
    task(t);
  }
  printf("Main completed\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <task@plt>
  mov    $0x1,%edi
  call   <task@plt>
  mov    $0x2,%edi
  call   <task@plt>
  mov    $0x3,%edi
  call   <task@plt>
  mov    $0x4,%edi
  call   <task@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D0
type: string

tool: D14: Main started


tool: D0: Main completed


assistant: ```c
int main() {
  printf("Main started\n");
  long t;
  for (t = 0; t < 5; t++) {
    task(t);
  }
  printf("Main completed\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <task@plt>
  mov    $0x1,%edi
  call   <task@plt>
  mov    $0x2,%edi
  call   <task@plt>
  mov    $0x3,%edi
  call   <task@plt>
  mov    $0x4,%edi
  call   <task@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D0: Main started


tool: D4: Main completed


assistant: ```c
int main() {
  printf("Main started\n");
  long t;
  for (t = 0; t < 5; t++) {
    task(t);
  }
  printf("Main completed\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<backward_substitution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <check_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L5
L18:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L37
L11:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  subl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L11
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  subl   $0x1,-0x10(%rbp)
L5:
  cmpl   $0x0,-0x10(%rbp)
  jns    L18
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: Allocation failed for Solution vector in function solve.

assistant: ```c
float *backward_substitution(int N, float **A) {
  float *x = (float *)check_malloc(N * sizeof(float), "Allocation failed for Solution vector in function solve.");
  for (int i = N - 1; i >= 0; i--) {
    x[i] = A[i][N];
    for (int j = (N - 1); j > i; j--) {
      x[i] -= (A[i][j] * x[j]);
    }
    x[i] = x[i] / A[i][i];
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<backward_substitution>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  movslq %edi,%rbp
  lea    0x0(,%rdi,4),%edi
  lea    D4(%rip),%rsi
  call   <check_malloc@plt>
  mov    %rax,%rsi
  mov    %ebx,%eax
  sub    $0x1,%eax
  js     L2
  cltq
  lea    (%r12,%rax,8),%rcx
  lea    0x0(,%rbp,4),%r13
  lea    -0x4(%r13),%r9
  lea    (%rsi,%r9,1),%rdx
  mov    (%rcx),%rdi
  movss  (%rdi,%rbp,4),%xmm0
  movss  %xmm0,(%rdx)
  lea    -0x8(%r12,%rax,8),%r10
  lea    -0x1(%rbx),%r11d
  movslq %r11d,%r12
  shl    $0x2,%r12
  mov    $0x0,%r8d
  jmp    L40
L34:
  mov    %r10,%rcx
  sub    $0x4,%r9
  lea    (%rsi,%r9,1),%rdx
  mov    (%r10),%rax
  movss  (%rax,%r13,1),%xmm0
  movss  %xmm0,(%rdx)
  mov    %r11d,%eax
  sub    %r8d,%eax
  cmp    %eax,%ebx
  jle    L32
  mov    %r8d,%edi
  mov    %rbp,%rax
  sub    %rdi,%rax
  lea    -0x8(,%rax,4),%rdi
  mov    %r12,%rax
L44:
  mov    (%rcx),%r14
  movss  (%r14,%rax,1),%xmm1
  mulss  (%rax,%rsi,1),%xmm1
  movss  (%rdx),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  sub    $0x4,%rax
  cmp    %rdi,%rax
  jne    L44
L32:
  add    $0x1,%r8d
  sub    $0x8,%r10
L40:
  mov    (%rcx),%rax
  movss  (%rdx),%xmm0
  divss  (%rax,%r9,1),%xmm0
  movss  %xmm0,(%rdx)
  cmp    %r11d,%r8d
  jne    L34
L2:
  mov    %rsi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4: Allocation failed for Solution vector in function solve.

assistant: ```c
float *backward_substitution(int N, float **A) {
  float *x = (float *)check_malloc(N * sizeof(float), "Allocation failed for Solution vector in function solve.");
  for (int i = N - 1; i >= 0; i--) {
    x[i] = A[i][N];
    for (int j = (N - 1); j > i; j--) {
      x[i] -= (A[i][j] * x[j]);
    }
    x[i] = x[i] / A[i][i];
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<backward_substitution>:
  endbr64
  push   %r15
  push   %r14
  movslq %edi,%r14
  push   %r13
  lea    0x0(,%r14,4),%edi
  push   %r12
  mov    %r14d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  lea    D6(%rip),%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <check_malloc@plt>
  mov    %rax,%r10
  sub    $0x1,%r12d
  js     L8
  movslq %r12d,%rdi
  lea    0x0(,%r14,4),%r13
  lea    -0x1(%r14),%r11
  mov    %r14,%rbx
  mov    0x0(%rbp,%rdi,8),%r8
  lea    -0x4(%r13),%r9
  lea    (%r10,%rdi,4),%r15
  lea    (%rax,%r9,1),%rdx
  mov    %r12d,%eax
  movss  (%r8,%r14,4),%xmm1
  sub    %rax,%r11
  lea    -0x8(%r10,%r13,1),%r14
  movss  %xmm1,(%rdx)
  divss  (%r8,%r9,1),%xmm1
  movss  %xmm1,(%rdx)
  cmp    %r11,%rdi
  je     L8
  nopl   0x0(%rax,%rax,1)
L17:
  mov    -0x8(%rbp,%rdi,8),%r8
  sub    $0x4,%r9
  lea    (%r10,%r9,1),%rdx
  movss  (%r8,%r13,1),%xmm1
  movss  %xmm1,(%rdx)
  cmp    %edi,%ebx
  jle    L23
  mov    %r12d,%eax
  mov    %r14,%rsi
  mov    %r8,%rcx
  sub    %edi,%eax
  sub    %r10,%rcx
  shl    $0x2,%rax
  sub    %rax,%rsi
  mov    %r15,%rax
  nopl   0x0(%rax,%rax,1)
L37:
  movss  (%rcx,%rax,1),%xmm0
  mulss  (%rax),%xmm0
  sub    $0x4,%rax
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %rax,%rsi
  jne    L37
L23:
  sub    $0x1,%rdi
  divss  (%r8,%r9,1),%xmm1
  movss  %xmm1,(%rdx)
  cmp    %r11,%rdi
  jne    L17
L8:
  add    $0x8,%rsp
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: Allocation failed for Solution vector in function solve.

assistant: ```c
float *backward_substitution(int N, float **A) {
  float *x = (float *)check_malloc(N * sizeof(float), "Allocation failed for Solution vector in function solve.");
  for (int i = N - 1; i >= 0; i--) {
    x[i] = A[i][N];
    for (int j = (N - 1); j > i; j--) {
      x[i] -= (A[i][j] * x[j]);
    }
    x[i] = x[i] / A[i][i];
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<backward_substitution>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  movslq %edi,%r12
  push   %rbp
  lea    0x0(,%r12,4),%edi
  mov    %rsi,%rbp
  lea    D8(%rip),%rsi
  push   %rbx
  call   <check_malloc@plt>
  mov    %r12d,%r10d
  mov    %rax,%r9
  sub    $0x1,%r10d
  js     L0
  movslq %r10d,%rcx
  lea    0x0(,%r12,4),%r11
  mov    0x0(%rbp,%rcx,8),%rdx
  lea    -0x4(%rax,%r11,1),%rax
  movss  (%rdx,%r12,4),%xmm0
  movss  %xmm0,(%rax)
  divss  -0x4(%rdx,%r11,1),%xmm0
  movss  %xmm0,(%rax)
  test   %r10d,%r10d
  je     L0
  mov    %r12,%rbx
  lea    -0x8(%r11),%r8
  lea    (%r9,%rcx,4),%r13
  xor    %edi,%edi
  lea    -0x8(%r9,%r11,1),%r12
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x0(%rbp,%r8,2),%r14
  mov    %r10d,%eax
  lea    (%r9,%r8,1),%rdx
  sub    %edi,%eax
  movss  (%r14,%r11,1),%xmm1
  movss  %xmm1,(%rdx)
  cmp    %eax,%ebx
  jle    L37
  mov    %edi,%eax
  mov    %r12,%rsi
  mov    %r14,%rcx
  shl    $0x2,%rax
  sub    %r9,%rcx
  sub    %rax,%rsi
  mov    %r13,%rax
  nopl   0x0(%rax)
L18:
  movss  (%rcx,%rax,1),%xmm0
  mulss  (%rax),%xmm0
  sub    $0x4,%rax
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %rax,%rsi
  jne    L18
L37:
  add    $0x1,%edi
  divss  (%r14,%r8,1),%xmm1
  sub    $0x4,%r8
  movss  %xmm1,(%rdx)
  cmp    %r10d,%edi
  jne    L29
L0:
  pop    %rbx
  mov    %r9,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: Allocation failed for Solution vector in function solve.

assistant: ```c
float *backward_substitution(int N, float **A) {
  float *x = (float *)check_malloc(N * sizeof(float), "Allocation failed for Solution vector in function solve.");
  for (int i = N - 1; i >= 0; i--) {
    x[i] = A[i][N];
    for (int j = (N - 1); j > i; j--) {
      x[i] -= (A[i][j] * x[j]);
    }
    x[i] = x[i] / A[i][i];
  }
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<expandKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x10,-0xf(%rbp)
  movb   $0x0,-0xe(%rbp)
  movb   $0x0,-0xd(%rbp)
  jmp    L73
L27:
  movzbl -0xd(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl -0xd(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzbl -0xd(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xd(%rbp)
L73:
  cmpb   $0xf,-0xd(%rbp)
  jbe    L27
  jmp    L96
L51:
  movzbl -0xf(%rbp),%eax
  sub    $0x4,%eax
  mov    %al,-0xd(%rbp)
  jmp    L48
L49:
  movzbl -0xd(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl -0xd(%rbp),%edx
  add    $0x4,%edx
  movzbl -0xf(%rbp),%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  movzbl (%rax),%edx
  movslq %ecx,%rax
  mov    %dl,-0xc(%rbp,%rax,1)
  movzbl -0xd(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xd(%rbp)
L48:
  movzbl -0xd(%rbp),%eax
  cmp    -0xf(%rbp),%al
  jb     L49
  movzbl -0xf(%rbp),%eax
  and    $0xf,%eax
  test   %al,%al
  jne    L10
  movzbl -0xe(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xe(%rbp)
  movzbl -0xe(%rbp),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <keySchedCore@plt>
L10:
  movb   $0x0,-0xd(%rbp)
  jmp    L74
L52:
  movzbl -0xf(%rbp),%eax
  lea    -0x10(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  movzbl -0xd(%rbp),%eax
  cltq
  movzbl -0xc(%rbp,%rax,1),%edx
  movzbl -0xf(%rbp),%esi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  movzbl -0xf(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xf(%rbp)
  movzbl -0xd(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xd(%rbp)
L74:
  cmpb   $0x3,-0xd(%rbp)
  jbe    L52
L96:
  cmpb   $0xaf,-0xf(%rbp)
  jbe    L51
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
void expandKey(unsigned char *key, unsigned char *exp_key) {
  unsigned char size = 16;
  unsigned char rcon_count = 0;
  unsigned char word[4];
  unsigned char i;
  for (i = 0; i < 16; i++)
    exp_key[i] = key[i];
  while (size < 176) {
    for (i = size - 4; i < size; i++)
      word[i + 4 - size] = exp_key[i];
    if (!(size % 16)) {
      rcon_count++;
      keySchedCore(word, rcon_count);
    }
    for (i = 0; i < 4; i++) {
      exp_key[size] = exp_key[size - 16] ^ word[i];
      size++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<expandKey>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
L61:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L61
  lea    0x4(%rsp),%r13
  mov    $0x10,%r12d
  sub    %r13d,%r12d
  mov    $0x10,%ebp
  mov    $0x0,%r14d
  mov    %r13,%r15
  jmp    L59
L17:
  lea    0x4(%r13),%rsi
  mov    %r13,%rax
L4:
  lea    (%r12,%rax,1),%edx
  movzbl %dl,%edx
  movzbl -0x10(%rbx,%rdx,1),%ecx
  xor    (%rax),%cl
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L4
  add    $0x4,%r12d
  add    $0x4,%ebp
  cmp    $0xb0,%ebp
  je     L79
L59:
  mov    %ebp,%esi
  lea    -0x4(%rbp),%edx
  cmp    $0x3,%bpl
  jbe    L69
L28:
  movzbl %dl,%eax
  add    $0x4,%eax
  sub    %ebp,%eax
  cltq
  movzbl %dl,%ecx
  movzbl (%rbx,%rcx,1),%ecx
  mov    %cl,0x4(%rsp,%rax,1)
  add    $0x1,%edx
  cmp    %sil,%dl
  jne    L28
L69:
  test   $0xf,%sil
  jne    L17
  add    $0x1,%r14d
  movzbl %r14b,%esi
  mov    %r15,%rdi
  call   <keySchedCore@plt>
  jmp    L17
L79:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void expandKey(unsigned char *key, unsigned char *exp_key) {
  unsigned char size = 16;
  unsigned char rcon_count = 0;
  unsigned char word[4];
  unsigned char i;
  for (i = 0; i < 16; i++)
    exp_key[i] = key[i];
  while (size < 176) {
    for (i = size - 4; i < size; i++)
      word[i + 4 - size] = exp_key[i];
    if (!(size % 16)) {
      rcon_count++;
      keySchedCore(word, rcon_count);
    }
    for (i = 0; i < 4; i++) {
      exp_key[size] = exp_key[size - 16] ^ word[i];
      size++;
    }
  }
}
```