ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<emyg_dtoa>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  ucomisd %xmm0,%xmm0
  movsd  %xmm0,0x8(%rsp)
  setnp  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  xor    %edi,%edi
  movapd %xmm0,%xmm1
  andpd  D1(%rip),%xmm1
  ucomisd D5(%rip),%xmm1
  setbe  %dil
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L55
  jne    L55
  movl   $0x302e30,0x0(%rbp)
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  comisd %xmm0,%xmm1
  ja     L11
L18:
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <Grisu2@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdi
  call   <Prettify@plt>
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L11:
  movb   $0x2d,0x0(%rbp)
  xorpd  D23(%rip),%xmm0
  add    $0x1,%rbp
  jmp    L18
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: byte[16]
name: retrieve_data
arguments: label: D5
datatype: byte[8]
name: retrieve_data
arguments: label: D23
datatype: byte[16]

tool: {"D1": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D5": [0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void emyg_dtoa(double value, char *buffer) {
  assert(!isnan(value));
  assert(!isinf(value));
  if (value == 0) {
    buffer[0] = '0';
    buffer[1] = '.';
    buffer[2] = '0';
    buffer[3] = '\0';
  } else {
    if (value < 0) {
      *buffer++ = '-';
      value = -value;
    }
    int length, K;
    Grisu2(value, buffer, &length, &K);
    Prettify(buffer, length, K);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getSubMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L5:
  mov    0x10(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  add    %ecx,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x24(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%eax
  imul   0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x30(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    0x18(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void getSubMatrix(double *matrix, int size1, int size2, int O1, int O2, double *A, int size3, int size4, int nCores) {
  int j;
  for (j = 0; j < size4; j++) {
    memcpy(&A[j * size3], &matrix[(j + O2) * size1 + O1], size3 * sizeof(double));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getSubMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r13d
  mov    0x58(%rsp),%r15d
  test   %r15d,%r15d
  jle    L11
  mov    %ecx,%edx
  movslq %r13d,%r14
  shl    $0x3,%r13d
  shl    $0x3,%r14
  mov    %r9,%rbx
  movslq %esi,%rcx
  shl    $0x3,%rcx
  mov    %rcx,0x8(%rsp)
  imul   %esi,%r8d
  movslq %r8d,%r8
  movslq %edx,%rdx
  add    %rdx,%r8
  lea    (%rdi,%r8,8),%r12
  mov    $0x0,%ebp
L9:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x1,%ebp
  add    %r14,%rbx
  add    0x8(%rsp),%r12
  cmp    %ebp,%r15d
  jne    L9
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void getSubMatrix(double *matrix, int size1, int size2, int O1, int O2, double *A, int size3, int size4, int nCores) {
  int j;
  for (j = 0; j < size4; j++) {
    memcpy(&A[j * size3], &matrix[(j + O2) * size1 + O1], size3 * sizeof(double));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getSubMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%eax
  mov    0x40(%rsp),%r12d
  test   %eax,%eax
  jle    L8
  imul   %esi,%r8d
  movslq %ecx,%rdx
  movslq %r12d,%r14
  movslq %esi,%r13
  shl    $0x3,%r12d
  shl    $0x3,%r14
  mov    %r9,%rbx
  xor    %ebp,%ebp
  shl    $0x3,%r13
  movslq %r8d,%r8
  add    %rdx,%r8
  lea    (%rdi,%r8,8),%r15
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    %r12d,%edx
  add    $0x1,%ebp
  call   <memcpy@plt>
  add    %r14,%rbx
  add    %r13,%r15
  cmp    %ebp,0x48(%rsp)
  jne    L4
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void getSubMatrix(double *matrix, int size1, int size2, int O1, int O2, double *A, int size3, int size4, int nCores) {
  int j;
  for (j = 0; j < size4; j++) {
    memcpy(&A[j * size3], &matrix[(j + O2) * size1 + O1], size3 * sizeof(double));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getSubMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%eax
  mov    0x40(%rsp),%r12d
  test   %eax,%eax
  jle    L4
  imul   %esi,%r8d
  movslq %ecx,%rdx
  movslq %r12d,%r14
  movslq %esi,%r13
  shl    $0x3,%r12d
  shl    $0x3,%r14
  mov    %r9,%rbx
  xor    %ebp,%ebp
  shl    $0x3,%r13
  movslq %r8d,%r8
  add    %rdx,%r8
  lea    (%rdi,%r8,8),%r15
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    %r12d,%edx
  add    $0x1,%ebp
  call   <memcpy@plt>
  add    %r14,%rbx
  add    %r13,%r15
  cmp    %ebp,0x48(%rsp)
  jne    L3
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void getSubMatrix(double *matrix, int size1, int size2, int O1, int O2, double *A, int size3, int size4, int nCores) {
  int j;
  for (j = 0; j < size4; j++) {
    memcpy(&A[j * size3], &matrix[(j + O2) * size1 + O1], size3 * sizeof(double));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MyFunc_A>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <showBacktrace@plt>
  mov    $0xa,%eax
  pop    %rbp
  ret
```

assistant: ```c
int MyFunc_A() {
  showBacktrace();
  return 10;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MyFunc_A>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <showBacktrace@plt>
  mov    $0xa,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int MyFunc_A() {
  showBacktrace();
  return 10;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MyFunc_A>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <showBacktrace@plt>
  mov    $0xa,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int MyFunc_A() {
  showBacktrace();
  return 10;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MyFunc_A>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <showBacktrace@plt>
  mov    $0xa,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int MyFunc_A() {
  showBacktrace();
  return 10;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<name_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L7:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0x0,-0x14(%rbp)
  js     L13
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L7
L13:
  nop
  leave
  ret
```

assistant: ```c
void name_copy(char *dst, const unsigned char *src, int len) {
  memcpy(dst, src, len);
  do {
    dst[len--] = 0;
  } while (len >= 0 && dst[len] == 32);
}
```
user: What is the c source code of the assembly code below:

```asm
<name_copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%ebx
  call   <memcpy@plt>
  lea    -0x1(%rbx),%eax
  cltq
L11:
  movb   $0x0,0x1(%rbp,%rax,1)
  test   %eax,%eax
  js     L2
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rbp,%rax,1)
  je     L11
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void name_copy(char *dst, const unsigned char *src, int len) {
  memcpy(dst, src, len);
  do {
    dst[len--] = 0;
  } while (len >= 0 && dst[len] == 32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<name_copy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  lea    -0x1(%rbx),%eax
  cltq
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L14:
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rbp,%rax,1)
  jne    L13
L10:
  movb   $0x0,0x1(%rbp,%rax,1)
  test   %eax,%eax
  jns    L14
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void name_copy(char *dst, const unsigned char *src, int len) {
  memcpy(dst, src, len);
  do {
    dst[len--] = 0;
  } while (len >= 0 && dst[len] == 32);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<name_copy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  lea    -0x1(%rbx),%eax
  cltq
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L2:
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rbp,%rax,1)
  jne    L21
L28:
  movb   $0x0,0x1(%rbp,%rax,1)
  test   %eax,%eax
  jns    L2
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void name_copy(char *dst, const unsigned char *src, int len) {
  memcpy(dst, src, len);
  do {
    dst[len--] = 0;
  } while (len >= 0 && dst[len] == 32);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Util_sscanbool>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L38
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    $0x0,%eax
  jmp    L46
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L16
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    $0x1,%eax
  jmp    L46
L16:
  mov    $0xffffffff,%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
int Util_sscanbool(const char *s) {
  if (*s == '0' && s[1] == '\0')
    return 0;
  if (*s == '1' && s[1] == '\0')
    return 1;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<Util_sscanbool>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x30,%dl
  je     L4
  mov    $0xffffffff,%eax
  cmp    $0x31,%dl
  je     L19
L11:
  ret
L4:
  movzbl 0x1(%rdi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
L19:
  cmpb   $0x1,0x1(%rdi)
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  jmp    L11
```

assistant: ```c
int Util_sscanbool(const char *s) {
  if (*s == '0' && s[1] == '\0')
    return 0;
  if (*s == '1' && s[1] == '\0')
    return 1;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Util_sscanbool>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x30,%dl
  je     L13
  mov    $0xffffffff,%eax
  cmp    $0x31,%dl
  je     L18
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  cmpb   $0x1,0x1(%rdi)
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
  nopl   (%rax)
L13:
  movzbl 0x1(%rdi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
```

assistant: ```c
int Util_sscanbool(const char *s) {
  if (*s == '0' && s[1] == '\0')
    return 0;
  if (*s == '1' && s[1] == '\0')
    return 1;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<Util_sscanbool>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x30,%dl
  je     L1
  mov    $0xffffffff,%eax
  cmp    $0x31,%dl
  je     L17
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  cmpb   $0x1,0x1(%rdi)
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
  nopl   (%rax)
L1:
  movzbl 0x1(%rdi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
```

assistant: ```c
int Util_sscanbool(const char *s) {
  if (*s == '0' && s[1] == '\0')
    return 0;
  if (*s == '1' && s[1] == '\0')
    return 1;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<safe_strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <safe_strncpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void safe_strncat(char *const to, const char *const from, const size_t size) {
  size_t l;
  l = strlen(to);
  safe_strncpy(&to[l], from, size - l);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<safe_strncat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdx
  sub    %rax,%rdx
  lea    (%rbx,%rax,1),%rdi
  mov    %r12,%rsi
  call   <safe_strncpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void safe_strncat(char *const to, const char *const from, const size_t size) {
  size_t l;
  l = strlen(to);
  safe_strncpy(&to[l], from, size - l);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<safe_strncat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    (%rbx,%rax,1),%rdi
  sub    %rax,%rdx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <safe_strncpy@plt>
```

assistant: ```c
void safe_strncat(char *const to, const char *const from, const size_t size) {
  size_t l;
  l = strlen(to);
  safe_strncpy(&to[l], from, size - l);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<safe_strncat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    (%rbx,%rax,1),%rdi
  sub    %rax,%rdx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <safe_strncpy@plt>
```

assistant: ```c
void safe_strncat(char *const to, const char *const from, const size_t size) {
  size_t l;
  l = strlen(to);
  safe_strncpy(&to[l], from, size - l);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<namex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <resets@plt>
  mov    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <resets@plt>
  mov    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <resets@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    D25(%rip),%rax
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x4(%rbp),%eax
  mov    D61(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <itoa@plt>
  mov    D61(%rip),%rax
  mov    %rax,%rsi
  mov    D25(%rip),%rax
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void namex(int i, char *s, char *r) {
  extern char s1[], s2[];
  extern void resets();
  resets(r);
  resets(s1);
  resets(s2);
  strcpy(s1, s);
  itoa(i, s2);
  strcat(s1, s2);
  strcpy(r, s1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<namex>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <resets@plt>
  mov    D15(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <resets@plt>
  mov    D1(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <resets@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <itoa@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void namex(int i, char *s, char *r) {
  extern char s1[], s2[];
  extern void resets();
  resets(r);
  resets(s1);
  resets(s2);
  strcpy(s1, s);
  itoa(i, s2);
  strcat(s1, s2);
  strcpy(r, s1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<namex>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rsi,%r15
  push   %r14
  mov    %edi,%r14d
  mov    %rdx,%rdi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  call   <resets@plt>
  mov    D17(%rip),%r12
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <resets@plt>
  mov    D6(%rip),%r13
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <resets@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <itoa@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <strcpy@plt>
```

assistant: ```c
void namex(int i, char *s, char *r) {
  extern char s1[], s2[];
  extern void resets();
  resets(r);
  resets(s1);
  resets(s2);
  strcpy(s1, s);
  itoa(i, s2);
  strcat(s1, s2);
  strcpy(r, s1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<namex>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rsi,%r15
  push   %r14
  mov    %edi,%r14d
  mov    %rdx,%rdi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  call   <resets@plt>
  mov    D1(%rip),%r12
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <resets@plt>
  mov    D0(%rip),%r13
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <resets@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <itoa@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <strcpy@plt>
```

assistant: ```c
void namex(int i, char *s, char *r) {
  extern char s1[], s2[];
  extern void resets();
  resets(r);
  resets(s1);
  resets(s2);
  strcpy(s1, s);
  itoa(i, s2);
  strcat(s1, s2);
  strcpy(r, s1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lf_to_crlf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L30
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L32
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xd,%edi
  call   <fputc@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L10
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  jmp    L10
L30:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L69
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L69
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  jmp    L10
L69:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L65
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0xd,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L10
L65:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
L10:
  nop
  leave
  ret
```

assistant: ```c
void lf_to_crlf(char *line, ssize_t linelen, FILE *output_stream) {
  if (linelen == 1) {
    if (line[0] == '\n') {
      fputc('\r', output_stream);
      fputc('\n', output_stream);
    } else {
      fputc(line[0], output_stream);
    }
  } else {
    if (line[linelen - 2] == '\r' && line[linelen - 1] == '\n') {
      fputs(line, output_stream);
    } else if (line[linelen - 1] == '\n') {
      line[linelen - 1] = '\r';
      fputs(line, output_stream);
      fputc('\n', output_stream);
    } else {
      fputs(line, output_stream);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lf_to_crlf>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  cmp    $0x1,%esi
  je     L58
  movslq %esi,%rsi
  cmpb   $0xd,-0x2(%rdi,%rsi,1)
  je     L30
  lea    -0x1(%rdi,%rsi,1),%rax
  cmpb   $0xa,(%rax)
  je     L29
L5:
  mov    %rbx,%rsi
  call   <fputs@plt>
L62:
  pop    %rbx
  ret
L58:
  movzbl (%rdi),%edi
  cmp    $0xa,%dil
  je     L64
  movsbl %dil,%edi
  mov    %rdx,%rsi
  call   <fputc@plt>
  jmp    L62
L64:
  mov    %rdx,%rsi
  mov    $0xd,%edi
  call   <fputc@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L62
L30:
  cmpb   $0xa,-0x1(%rdi,%rsi,1)
  jne    L5
  mov    %rdx,%rsi
  call   <fputs@plt>
  jmp    L62
L29:
  movb   $0xd,(%rax)
  mov    %rdx,%rsi
  call   <fputs@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L62
```

assistant: ```c
void lf_to_crlf(char *line, ssize_t linelen, FILE *output_stream) {
  if (linelen == 1) {
    if (line[0] == '\n') {
      fputc('\r', output_stream);
      fputc('\n', output_stream);
    } else {
      fputc(line[0], output_stream);
    }
  } else {
    if (line[linelen - 2] == '\r' && line[linelen - 1] == '\n') {
      fputs(line, output_stream);
    } else if (line[linelen - 1] == '\n') {
      line[linelen - 1] = '\r';
      fputs(line, output_stream);
      fputc('\n', output_stream);
    } else {
      fputs(line, output_stream);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lf_to_crlf>:
  endbr64
  movslq %esi,%rax
  push   %rbp
  mov    %rdx,%rbp
  cmp    $0x1,%eax
  je     L27
  lea    -0x1(%rdi,%rax,1),%rdx
  cmpb   $0xd,-0x2(%rdi,%rax,1)
  movzbl (%rdx),%ecx
  je     L8
  cmp    $0xa,%cl
  jne    L8
  movb   $0xd,(%rdx)
  mov    %rbp,%rsi
  call   <fputs@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
L30:
  pop    %rbp
  jmp    1070 <fputc@plt>
  nopl   (%rax)
L8:
  mov    %rbp,%rsi
  pop    %rbp
  jmp    1060 <fputs@plt>
  nopl   0x0(%rax)
L27:
  movsbl (%rdi),%edi
  mov    %rdx,%rsi
  cmp    $0xa,%dil
  jne    L30
  mov    $0xd,%edi
  call   <fputc@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <fputc@plt>
```

assistant: ```c
void lf_to_crlf(char *line, ssize_t linelen, FILE *output_stream) {
  if (linelen == 1) {
    if (line[0] == '\n') {
      fputc('\r', output_stream);
      fputc('\n', output_stream);
    } else {
      fputc(line[0], output_stream);
    }
  } else {
    if (line[linelen - 2] == '\r' && line[linelen - 1] == '\n') {
      fputs(line, output_stream);
    } else if (line[linelen - 1] == '\n') {
      line[linelen - 1] = '\r';
      fputs(line, output_stream);
      fputc('\n', output_stream);
    } else {
      fputs(line, output_stream);
    }
  }
}
```