ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<dynamic_vector_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r13
  mov    %rsi,%r12
  sub    %rdi,%r12
  mov    %rdx,0x8(%rsp)
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  lea    0x2(%r12),%rdi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    $0x1,%r14d
  mov    %r14,%rax
  mov    %r15,(%rsp)
  sub    %r15,%rax
  lea    (%rbx,%rax,8),%r15
  lea    0x1(%r12),%rdi
  imul   %rbp,%rdi
  lea    0x1(%rdi),%rdi
  mov    $0x8,%esi
  call   <calloc@plt>
  sub    0x8(%rsp),%r14
  lea    (%rax,%r14,8),%rax
  mov    %rax,0x8(%rbx)
  cmp    (%rsp),%r13
  jle    L7
  shl    $0x3,%rbp
  add    $0x8,%rbx
  lea    (%r15,%r13,8),%rdx
L3:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L3
L7:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
struct dynamic_vector ***dynamic_vector_matrix(nrl, nrh, ncl, nch)
long nch, ncl, nrh, nrl;
{
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  struct dynamic_vector ***m;
  m = (struct dynamic_vector ***)calloc(nrow + 1, sizeof(struct dynamic_vector **));
  m += 1 - nrl;
  m[nrl] = (struct dynamic_vector **)calloc(nrow * ncol + 1, sizeof(struct dynamic_vector *));
  m[nrl] += 1 - ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dynamic_vector_matrix>:
  endbr64
  push   %r15
  sub    %rdx,%rcx
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x8,%esi
  push   %rbp
  sub    %rdi,%r12
  lea    0x1(%rcx),%rbp
  push   %rbx
  lea    0x2(%r12),%rdi
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <calloc@plt>
  lea    0x1(%r12),%rdi
  mov    $0x8,%esi
  imul   %rbp,%rdi
  mov    %rax,%rbx
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%rbx,%rax,8),%r15
  add    $0x1,%rdi
  call   <calloc@plt>
  mov    0x8(%rsp),%r8
  mov    $0x1,%edx
  sub    %r8,%rdx
  lea    (%rax,%rdx,8),%rax
  mov    %rax,0x8(%rbx)
  cmp    %r13,%r14
  jle    L15
  lea    0x0(,%rbp,8),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r15,%r14,8),%rsi
  nopl   0x0(%rax)
L13:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L13
L15:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
struct dynamic_vector ***dynamic_vector_matrix(nrl, nrh, ncl, nch)
long nch, ncl, nrh, nrl;
{
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  struct dynamic_vector ***m;
  m = (struct dynamic_vector ***)calloc(nrow + 1, sizeof(struct dynamic_vector **));
  m += 1 - nrl;
  m[nrl] = (struct dynamic_vector **)calloc(nrow * ncol + 1, sizeof(struct dynamic_vector *));
  m[nrl] += 1 - ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dynamic_vector_matrix>:
  endbr64
  push   %r15
  sub    %rdx,%rcx
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x8,%esi
  push   %rbp
  sub    %rdi,%r12
  lea    0x1(%rcx),%rbp
  push   %rbx
  lea    0x2(%r12),%rdi
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <calloc@plt>
  lea    0x1(%r12),%rdi
  mov    $0x8,%esi
  imul   %rbp,%rdi
  mov    %rax,%rbx
  mov    $0x1,%eax
  sub    %r13,%rax
  add    $0x1,%r13
  lea    (%rbx,%rax,8),%r15
  add    $0x1,%rdi
  call   <calloc@plt>
  mov    0x8(%rsp),%r8
  mov    $0x1,%edx
  sub    %r8,%rdx
  lea    (%rax,%rdx,8),%rdx
  mov    %rdx,0x8(%rbx)
  cmp    %r13,%r14
  jl     L15
  lea    0x0(,%rbp,8),%rcx
  lea    0x10(%rbx),%rax
  lea    0x8(%r15,%r14,8),%rsi
  xchg   %ax,%ax
L19:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rsi,%rax
  jne    L19
L15:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
struct dynamic_vector ***dynamic_vector_matrix(nrl, nrh, ncl, nch)
long nch, ncl, nrh, nrl;
{
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  struct dynamic_vector ***m;
  m = (struct dynamic_vector ***)calloc(nrow + 1, sizeof(struct dynamic_vector **));
  m += 1 - nrl;
  m[nrl] = (struct dynamic_vector **)calloc(nrow * ncol + 1, sizeof(struct dynamic_vector *));
  m[nrl] += 1 - ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L74
L67:
  movl   $0x1,-0x18(%rbp)
  jmp    L71
L12:
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L38
L21:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L72
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cmp    $0x3e8,%eax
  jne    L72
  mov    -0x1c(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
L72:
  addl   $0x1,-0x14(%rbp)
L38:
  cmpl   $0x3e7,-0x14(%rbp)
  jle    L21
  addl   $0x1,-0x18(%rbp)
L71:
  cmpl   $0x3e7,-0x18(%rbp)
  jle    L12
  addl   $0x1,-0x1c(%rbp)
L74:
  cmpl   $0x3e7,-0x1c(%rbp)
  jle    L67
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    $0x1e65fb8,%esi
  mov    $0x9,%edi
  call   <check@plt>
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int a, b, c, a2, b2, c2;
  int product = 0;
  for (a = 1; a < 1000; a++) {
    for (b = 1; b < 1000; b++) {
      a2 = a * a;
      b2 = b * b;
      for (c = 1; c < 1000; c++) {
        c2 = c * c;
        if ((a2 + b2 == c2) && (a + b + c == 1000)) {
          product = a * b * c;
        }
      }
    }
  }
  return check(9, 31875000, product);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x1,%ebp
  jmp    L47
L71:
  add    $0x1,%eax
  add    %esi,%edx
  cmp    $0x3e8,%eax
  je     L28
L36:
  mov    %eax,%ecx
  imul   %eax,%ecx
  cmp    %ecx,%edi
  jne    L71
  lea    (%rax,%r9,1),%ecx
  cmp    $0x3e8,%ecx
  cmove  %edx,%r8d
  jmp    L71
L28:
  add    $0x1,%r10d
  add    %r11d,%esi
  add    $0x1,%r9d
  cmp    $0x3e8,%r10d
  je     L64
L68:
  mov    %r10d,%edi
  imul   %r10d,%edi
  mov    %esi,%edx
  mov    $0x1,%eax
  add    %ebx,%edi
  jmp    L36
L64:
  add    $0x1,%ebp
  cmp    $0x3e8,%ebp
  je     L57
L47:
  mov    %ebp,%ebx
  imul   %ebp,%ebx
  mov    %ebp,%r11d
  lea    0x1(%rbp),%r9d
  mov    %ebp,%esi
  mov    $0x1,%r10d
  jmp    L68
L57:
  mov    %r8d,%edx
  mov    $0x1e65fb8,%esi
  mov    $0x9,%edi
  call   <check@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int a, b, c, a2, b2, c2;
  int product = 0;
  for (a = 1; a < 1000; a++) {
    for (b = 1; b < 1000; b++) {
      a2 = a * a;
      b2 = b * b;
      for (c = 1; c < 1000; c++) {
        c2 = c * c;
        if ((a2 + b2 == c2) && (a + b + c == 1000)) {
          product = a * b * c;
        }
      }
    }
  }
  return check(9, 31875000, product);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %r8d,%r8d
  mov    $0x1,%r11d
  push   %rbx
L51:
  mov    %r11d,%ebx
  lea    0x1(%r11),%ebp
  mov    %r11d,%esi
  mov    $0x1,%r10d
  imul   %r11d,%ebx
  mov    %ebp,%r9d
L8:
  mov    %r10d,%edi
  mov    $0x1,%eax
  lea    (%rsi,%rsi,1),%edx
  imul   %r10d,%edi
  add    $0x1,%eax
  add    %ebx,%edi
  cmp    $0x3e8,%eax
  je     L11
  nopl   0x0(%rax)
L15:
  mov    %eax,%ecx
  imul   %eax,%ecx
  cmp    %ecx,%edi
  je     L57
  add    %esi,%edx
L52:
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  jne    L15
L11:
  add    $0x1,%r10d
  add    %r11d,%esi
  add    $0x1,%r9d
  cmp    $0x3e8,%r10d
  jne    L8
  mov    %ebp,%r11d
  cmp    $0x3e8,%ebp
  jne    L51
  pop    %rbx
  mov    %r8d,%edx
  mov    $0x1e65fb8,%esi
  mov    $0x9,%edi
  pop    %rbp
  jmp    1050 <check@plt>
L57:
  lea    (%rax,%r9,1),%ecx
  cmp    $0x3e8,%ecx
  cmove  %edx,%r8d
  add    %esi,%edx
  jmp    L52
```

assistant: ```c
int main(int argc, char **argv) {
  int a, b, c, a2, b2, c2;
  int product = 0;
  for (a = 1; a < 1000; a++) {
    for (b = 1; b < 1000; b++) {
      a2 = a * a;
      b2 = b * b;
      for (c = 1; c < 1000; c++) {
        c2 = c * c;
        if ((a2 + b2 == c2) && (a + b + c == 1000)) {
          product = a * b * c;
        }
      }
    }
  }
  return check(9, 31875000, product);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mat_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L9:
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L21:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x6,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L21
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0:  %d%*c

assistant: ```c
void mat_read(int m[][80], int r, int c) {
  int i, j;
  for (i = 0; i < r; ++i)
    for (j = 0; j < c; ++j)
      scanf(" %d%*c", &m[i][j]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mat_read>:
  endbr64
  test   %esi,%esi
  jle    L31
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r14d
  lea    -0x1(%rdx),%r13d
  lea    0x4(%rdi,%r13,4),%rbp
  lea    -0x1(%rsi),%eax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  add    %r13,%rax
  lea    0x144(%rdi,%rax,4),%r15
  not    %r13
  shl    $0x2,%r13
  lea    D6(%rip),%r12
  jmp    L7
L29:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L29
L6:
  add    $0x140,%rbp
  cmp    %r15,%rbp
  je     L47
L7:
  lea    0x0(%r13,%rbp,1),%rbx
  test   %r14d,%r14d
  jg     L29
  jmp    L6
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6:  %d%*c

assistant: ```c
void mat_read(int m[][80], int r, int c) {
  int i, j;
  for (i = 0; i < r; ++i)
    for (j = 0; j < c; ++j)
      scanf(" %d%*c", &m[i][j]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mat_read>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  push   %r15
  lea    -0x1(%rdx),%ecx
  push   %r14
  lea    (%rax,%rax,4),%rax
  mov    $0xfffffffffffffffc,%r14
  push   %r13
  shl    $0x4,%rax
  mov    %edx,%r13d
  lea    0x0(,%rcx,4),%rdx
  push   %r12
  add    %rcx,%rax
  sub    %rdx,%r14
  lea    D0(%rip),%r12
  push   %rbp
  lea    0x144(%rdi,%rax,4),%r15
  lea    0x4(%rdi,%rdx,1),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L16:
  lea    (%r14,%rbp,1),%rbx
  test   %r13d,%r13d
  jle    L4
  nopl   0x0(%rax)
L23:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %rbp,%rbx
  jne    L23
L4:
  add    $0x140,%rbp
  cmp    %r15,%rbp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0:  %d%*c

assistant: ```c
void mat_read(int m[][80], int r, int c) {
  int i, j;
  for (i = 0; i < r; ++i)
    for (j = 0; j < c; ++j)
      scanf(" %d%*c", &m[i][j]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mat_read>:
  endbr64
  test   %esi,%esi
  jle    L34
  test   %edx,%edx
  jle    L34
  lea    -0x1(%rsi),%eax
  push   %r14
  lea    -0x1(%rdx),%ecx
  lea    (%rax,%rax,4),%rax
  push   %r13
  lea    0x0(,%rcx,4),%rdx
  mov    $0xfffffffffffffffc,%r13
  push   %r12
  shl    $0x4,%rax
  lea    D8(%rip),%r12
  sub    %rdx,%r13
  push   %rbp
  add    %rcx,%rax
  lea    0x4(%rdi,%rdx,1),%rbp
  push   %rbx
  lea    0x144(%rdi,%rax,4),%r14
  nopl   0x0(%rax,%rax,1)
L7:
  lea    0x0(%r13,%rbp,1),%rbx
  nopl   (%rax)
L27:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %rbp,%rbx
  jne    L27
  add    $0x140,%rbp
  cmp    %r14,%rbp
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8:  %d%*c

assistant: ```c
void mat_read(int m[][80], int r, int c) {
  int i, j;
  for (i = 0; i < r; ++i)
    for (j = 0; j < c; ++j)
      scanf(" %d%*c", &m[i][j]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x44(%rbp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x44(%rbp)
  jle    L119
  mov    $0x0,%r15d
  lea    D43(%rip),%r14
  jmp    L50
L82:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L11
  orq    $0x0,-0x8(%rsp,%rax,1)
L11:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L104
  mov    $0x0,%r13d
  mov    $0x0,%r12d
L12:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,(%rbx)
  setle  %al
  movzbl %al,%eax
  add    %eax,%r13d
  add    $0x1,%r12d
  add    $0x4,%rbx
  cmp    %r12d,-0x40(%rbp)
  jg     L12
L7:
  cmp    %r13d,-0x3c(%rbp)
  jg     L100
  lea    D40(%rip),%rdi
  call   <printf@plt>
L58:
  mov    -0x58(%rbp),%rsp
  add    $0x1,%r15d
  cmp    %r15d,-0x44(%rbp)
  jle    L119
L50:
  mov    %rsp,-0x58(%rbp)
  lea    -0x3c(%rbp),%rdx
  lea    -0x40(%rbp),%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L1:
  cmp    %rcx,%rsp
  je     L82
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L1
L104:
  mov    $0x0,%r13d
  jmp    L7
L100:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L58
L119:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D43
data_type: string
name: retrieve_data
arguments: tag: D40
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D12
data_type: string

tool: D43: %d

tool: D40: NO


tool: D28: %d %d

tool: D12: YES


assistant: ```c
int main() {
  int t, j, i, p, n;
  scanf("%d", &t);
  for (j = 0; j < t; j++) {
    int n;
    int k;
    scanf("%d %d", &n, &k);
    int a[n];
    p = 0;
    for (i = 0; i < n; i++) {
      scanf("%d", &a[i]);
      if (a[i] <= 0)
        p++;
    }
    if (p >= k)
      printf("NO\n");
    else
      printf("YES\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x44(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D34(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x44(%rbp),%ecx
  test   %ecx,%ecx
  jle    L18
  lea    -0x3c(%rbp),%rax
  movl   $0x0,-0x54(%rbp)
  mov    %rax,-0x68(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  nopl   0x0(%rax)
L3:
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rsi
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  movslq -0x40(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L98
L85:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L85
L98:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L56
  orq    $0x0,-0x8(%rsp,%rdx,1)
L56:
  mov    %rsp,%rdx
  test   %ecx,%ecx
  jle    L108
  mov    %rdx,%r13
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L0:
  mov    %r13,%rsi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x0(%r13),%edx
  xor    %eax,%eax
  test   %edx,%edx
  setle  %al
  add    $0x1,%r15d
  add    $0x4,%r13
  add    %eax,%ebx
  cmp    %r15d,-0x40(%rbp)
  jg     L0
L86:
  cmp    %ebx,-0x3c(%rbp)
  jg     L58
  lea    D2(%rip),%rdi
  call   <printf@plt>
L69:
  mov    %r14,%rsp
  addl   $0x1,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  cmp    %eax,-0x44(%rbp)
  jg     L3
L18:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L58:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L108:
  xor    %ebx,%ebx
  jmp    L86
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D34
datatype: string
name: extract_symbolic_data
arguments: label: D32
datatype: string
name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D34: %d

tool: D32: %d %d

tool: D2: NO


tool: D8: YES


assistant: ```c
int main() {
  int t, j, i, p, n;
  scanf("%d", &t);
  for (j = 0; j < t; j++) {
    int n;
    int k;
    scanf("%d %d", &n, &k);
    int a[n];
    p = 0;
    for (i = 0; i < n; i++) {
      scanf("%d", &a[i]);
      if (a[i] <= 0)
        p++;
    }
    if (p >= k)
      printf("NO\n");
    else
      printf("YES\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x44(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x44(%rbp),%ecx
  test   %ecx,%ecx
  jle    L44
  lea    -0x3c(%rbp),%rax
  movl   $0x0,-0x54(%rbp)
  mov    %rax,-0x68(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  nopl   0x0(%rax)
L52:
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rsi
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  movslq -0x40(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L54
L63:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L63
L54:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L119
  orq    $0x0,-0x8(%rsp,%rdx,1)
L119:
  mov    %rsp,%rdx
  test   %ecx,%ecx
  jle    L47
  mov    %rdx,%r13
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L65:
  mov    %r13,%rsi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x0(%r13),%edx
  xor    %eax,%eax
  test   %edx,%edx
  setle  %al
  add    $0x1,%r15d
  add    $0x4,%r13
  add    %eax,%ebx
  cmp    %r15d,-0x40(%rbp)
  jg     L65
L97:
  cmp    %ebx,-0x3c(%rbp)
  jg     L48
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rsp
  addl   $0x1,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L52
L44:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rsp
  addl   $0x1,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  cmp    %eax,-0x44(%rbp)
  jg     L52
  jmp    L44
L47:
  xor    %ebx,%ebx
  jmp    L97
L109:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D34
datatype: string
name: parse_data
arguments: tag: D20
datatype: string
name: parse_data
arguments: tag: D4
datatype: string

tool: D16: %d

tool: D34: %d %d

tool: D20: NO


tool: D4: YES


assistant: ```c
int main() {
  int t, j, i, p, n;
  scanf("%d", &t);
  for (j = 0; j < t; j++) {
    int n;
    int k;
    scanf("%d %d", &n, &k);
    int a[n];
    p = 0;
    for (i = 0; i < n; i++) {
      scanf("%d", &a[i]);
      if (a[i] <= 0)
        p++;
    }
    if (p >= k)
      printf("NO\n");
    else
      printf("YES\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_138_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_138_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = S | stk3;
  stk1 = *D & stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_138_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  not    %edx
  or     %esi,%edx
  and    (%rdi),%dl
  mov    %eax,%ecx
  not    %ecx
  and    %ecx,%edx
  and    (%rdi),%al
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_138_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = S | stk3;
  stk1 = *D & stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_138_1_1>:
  endbr64
  mov    %edx,%eax
  not    %edx
  or     %esi,%eax
  or     %esi,%edx
  and    (%rdi),%dl
  mov    %eax,%ecx
  and    (%rdi),%al
  not    %ecx
  and    %ecx,%edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_138_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = S | stk3;
  stk1 = *D & stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```