ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edi,%r15d
  mov    $0x4,%edi
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  mov    %r15d,(%r12)
  xor    %edx,%edx
  mov    %r14d,0x0(%r13)
  mov    %rax,%rcx
  movl   $0x0,(%rbx)
  movl   $0x0,(%rax)
  nopl   0x0(%rax)
L43:
  cmp    %edx,(%r12)
  jle    L48
  add    $0x1,%edx
  mov    %edx,(%rbx)
  test   $0x1,%dl
  jne    L43
L48:
  mov    (%rcx),%eax
  test   %eax,%eax
  jg     L56
L47:
  add    $0x1,%eax
  mov    %eax,(%rcx)
  mov    (%rbx),%edx
  test   $0x1,%dl
  je     L43
  test   %eax,%eax
  jle    L47
L56:
  add    (%rbx),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f(int k, int l) {
  int *k_ref = alloca(sizeof(int));
  int *l_ref = alloca(sizeof(int));
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  *k_ref = k;
  *l_ref = l;
  *i = 0;
  *j = 0;
L1:
  while (*i < *k_ref) {
    (*i)++;
    if (*i % 2) {
      continue;
    }
    goto L2;
  }
L2:
  while (*j < 1) {
    (*j)++;
    if (*i % 2) {
      continue;
    }
    goto L1;
  }
  return *i + *j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<submatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    -0x48(%rbp),%rax
  sub    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%rax
  sub    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L13:
  addq   $0x8,-0x8(%rbp)
  mov    -0x60(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L4
L21:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x20(%rbp)
L4:
  mov    -0x28(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jle    L21
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: allocation failure in submatrix()

assistant: ```c
double **submatrix(double **a, long oldrl, long oldrh, long oldcl, long oldch, long newrl, long newcl) {
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  double **m;
  m = (double **)malloc((size_t)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<submatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %r9,%r13
  sub    0x40(%rsp),%rcx
  mov    %rcx,%r14
  mov    %rdx,%rax
  sub    %rsi,%rax
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L38
L26:
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%r15,%rax,8),%rdi
  cmp    %rbx,%rbp
  jl     L15
  lea    0x0(,%r14,8),%rcx
  lea    0x1(%rbp),%rdx
  sub    %rbx,%r13
  lea    (%rdi,%r13,8),%rsi
L29:
  mov    %rcx,%rax
  add    (%r12,%rbx,8),%rax
  mov    %rax,(%rsi,%rbx,8)
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  jne    L29
L15:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  lea    D3(%rip),%rdi
  call   <nrerror@plt>
  jmp    L26
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: allocation failure in submatrix()

assistant: ```c
double **submatrix(double **a, long oldrl, long oldrh, long oldcl, long oldch, long newrl, long newcl) {
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  double **m;
  m = (double **)malloc((size_t)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<submatrix>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  push   %r14
  sub    %rsi,%rax
  mov    %r9,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x10(,%rax,8),%rdi
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  sub    0x40(%rsp),%rcx
  mov    %rcx,%r12
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L5
L36:
  mov    $0x1,%eax
  sub    %r14,%rax
  lea    (%r15,%rax,8),%r8
  cmp    %rbx,%rbp
  jl     L28
  sub    %rbx,%r14
  lea    0x0(,%r12,8),%rcx
  lea    0x1(%rbp),%rdx
  lea    (%r8,%r14,8),%rsi
  nopl   (%rax)
L29:
  mov    0x0(%r13,%rbx,8),%rax
  add    %rcx,%rax
  mov    %rax,(%rsi,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rdx
  jne    L29
L28:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L5:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  jmp    L36
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: string

tool: D0: allocation failure in submatrix()

assistant: ```c
double **submatrix(double **a, long oldrl, long oldrh, long oldcl, long oldch, long newrl, long newcl) {
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  double **m;
  m = (double **)malloc((size_t)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<submatrix>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  mov    %r9,%r15
  push   %r14
  sub    %rsi,%rax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  lea    0x10(,%rax,8),%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  sub    0x40(%rsp),%rbx
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L87
L0:
  mov    $0x1,%eax
  sub    %r15,%rax
  lea    (%r14,%rax,8),%r8
  cmp    %rbp,%r13
  jl     L41
  lea    0x1(%rbp),%rcx
  mov    %r13,%rsi
  lea    0x8(%r14),%rax
  lea    0x0(,%rcx,8),%r9
  lea    0x0(,%rbx,8),%rdx
  sub    %rbp,%rsi
  lea    (%r12,%r9,1),%rdi
  cmp    %rdi,%rax
  je     L95
  cmp    $0x2,%rsi
  jbe    L95
  lea    0x1(%rsi),%rcx
  movq   %rdx,%xmm1
  mov    %rcx,%rsi
  punpcklqdq %xmm1,%xmm1
  shr    %rsi
  shl    $0x4,%rsi
  lea    0x8(%r14,%rsi,1),%rdi
  mov    %r12,%rsi
  sub    %r14,%rsi
  lea    -0x8(%rsi,%r9,1),%rsi
  cs nopw 0x0(%rax,%rax,1)
L82:
  movdqu -0x8(%rax,%rsi,1),%xmm0
  add    $0x10,%rax
  paddq  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdi
  jne    L82
  mov    %rcx,%rax
  and    $0xfffffffffffffffe,%rax
  add    %rax,%rbp
  lea    (%r15,%rax,1),%r9
  cmp    %rax,%rcx
  je     L41
  mov    (%r12,%rbp,8),%rax
  add    %rdx,%rax
  mov    %rax,(%r8,%r9,8)
L41:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  jmp    L0
  nopl   0x0(%rax)
L95:
  sub    %rbp,%r15
  add    $0x1,%r13
  lea    (%r8,%r15,8),%rsi
  jmp    L36
  nopl   (%rax)
L94:
  add    $0x1,%rcx
L36:
  mov    (%r12,%rbp,8),%rax
  add    %rdx,%rax
  mov    %rax,(%rsi,%rbp,8)
  mov    %rcx,%rbp
  cmp    %r13,%rcx
  jne    L94
  jmp    L41
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D0: allocation failure in submatrix()

assistant: ```c
double **submatrix(double **a, long oldrl, long oldrh, long oldcl, long oldch, long newrl, long newcl) {
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  double **m;
  m = (double **)malloc((size_t)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ends_in_chr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int ends_in_chr(char c, char *st) {
  int len = strlen(st);
  return st[len - 1] == c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ends_in_chr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cltq
  cmp    %bpl,-0x1(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ends_in_chr(char c, char *st) {
  int len = strlen(st);
  return st[len - 1] == c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ends_in_chr>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  cmp    %bpl,-0x1(%rbx,%rax,1)
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ends_in_chr(char c, char *st) {
  int len = strlen(st);
  return st[len - 1] == c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ends_in_chr>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  cmp    %bpl,-0x1(%rbx,%rax,1)
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ends_in_chr(char c, char *st) {
  int len = strlen(st);
  return st[len - 1] == c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<igcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L14
L4:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L14:
  cmpl   $0x0,-0x14(%rbp)
  jne    L4
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int igcd(int a, int b) {
  int c;
  while (a) {
    c = a;
    a = b % a;
    b = c;
  }
  return abs(b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<igcd>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  jne    L15
  mov    %esi,%edi
  jmp    L16
L10:
  mov    %edx,%edi
L15:
  cltd
  idiv   %edi
  mov    %edi,%eax
  test   %edx,%edx
  jne    L10
L16:
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int igcd(int a, int b) {
  int c;
  while (a) {
    c = a;
    a = b % a;
    b = c;
  }
  return abs(b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<igcd>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  jne    L7
  jmp    L24
  nopl   0x0(%rax)
L2:
  mov    %edx,%edi
L7:
  cltd
  idiv   %edi
  mov    %edi,%eax
  test   %edx,%edx
  jne    L2
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %esi,%edi
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int igcd(int a, int b) {
  int c;
  while (a) {
    c = a;
    a = b % a;
    b = c;
  }
  return abs(b);
}
```
user: What is the c source code of the assembly code below:

```asm
<igcd>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  jne    L21
  jmp    L9
  nopl   0x0(%rax)
L22:
  mov    %edx,%edi
L21:
  cltd
  idiv   %edi
  mov    %edi,%eax
  test   %edx,%edx
  jne    L22
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %esi,%edi
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int igcd(int a, int b) {
  int c;
  while (a) {
    c = a;
    a = b % a;
    b = c;
  }
  return abs(b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L31:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L23
  mov    -0x8(%rbp),%eax
  jmp    L37
L23:
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L31
  mov    $0xffffffff,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int search(int arr[], int x) {
  int i = 0, size = arr[0];
  for (i = 0; i < size; i++)
    if (arr[i] == x)
      return i;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<search>:
  endbr64
  mov    (%rdi),%edx
  test   %edx,%edx
  jle    L6
  mov    %edx,%edx
  mov    $0x0,%eax
L1:
  mov    %eax,%ecx
  cmp    %esi,(%rdi,%rax,4)
  je     L29
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L1
  mov    $0xffffffff,%ecx
L29:
  mov    %ecx,%eax
  ret
L6:
  mov    $0xffffffff,%ecx
  jmp    L29
```

assistant: ```c
int search(int arr[], int x) {
  int i = 0, size = arr[0];
  for (i = 0; i < size; i++)
    if (arr[i] == x)
      return i;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<search>:
  endbr64
  mov    (%rdi),%edx
  test   %edx,%edx
  jle    L19
  movslq %edx,%rcx
  xor    %eax,%eax
  jmp    L7
  nopl   0x0(%rax)
L2:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L19
  mov    (%rdi,%rax,4),%edx
L7:
  mov    %eax,%r8d
  cmp    %edx,%esi
  jne    L2
  mov    %r8d,%eax
  ret
  nop
L19:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int search(int arr[], int x) {
  int i = 0, size = arr[0];
  for (i = 0; i < size; i++)
    if (arr[i] == x)
      return i;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<search>:
  endbr64
  movslq (%rdi),%rdx
  test   %edx,%edx
  jle    L25
  xor    %eax,%eax
  jmp    L9
  nop
L27:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L25
L9:
  mov    %eax,%r8d
  cmp    %esi,(%rdi,%rax,4)
  jne    L27
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L25:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int search(int arr[], int x) {
  int i = 0, size = arr[0];
  for (i = 0; i < size; i++)
    if (arr[i] == x)
      return i;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L13
L63:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L1
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L68
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
  jmp    L68
L1:
  nop
L68:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L69
  mov    $0x0,%eax
  jmp    L31
L69:
  mov    $0x1,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; (*s1 != '\0') && (*s2 != '\0'); s1++, s2++) {
    if (*s1 != *s2)
      break;
  }
  if (*s1 == *s2)
    return 0;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
L30:
  movzbl (%rsi),%edx
  cmp    %al,%dl
  jne    L33
  test   %dl,%dl
  je     L33
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L30
L33:
  cmp    %al,(%rsi)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; (*s1 != '\0') && (*s2 != '\0'); s1++, s2++) {
    if (*s1 != *s2)
      break;
  }
  if (*s1 == *s2)
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L55
  jmp    L11
  nopl   (%rax)
L59:
  test   %al,%al
  jne    L10
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L33
  mov    %rdx,%rsi
L55:
  movzbl (%rsi),%edx
  cmp    %al,%dl
  setne  %al
  test   %dl,%dl
  jne    L59
L10:
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  cmpb   $0x0,0x1(%rsi)
  setne  %al
  movzbl %al,%eax
  ret
L11:
  cmpb   $0x0,(%rsi)
  setne  %al
  jmp    L10
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; (*s1 != '\0') && (*s2 != '\0'); s1++, s2++) {
    if (*s1 != *s2)
      break;
  }
  if (*s1 == *s2)
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L5
  jmp    L57
  nopl   (%rax)
L0:
  test   %al,%al
  jne    L29
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L50
  mov    %rdx,%rsi
L5:
  movzbl (%rsi),%edx
  cmp    %al,%dl
  setne  %al
  test   %dl,%dl
  jne    L0
L29:
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  cmpb   $0x0,0x1(%rsi)
  setne  %al
  movzbl %al,%eax
  ret
L57:
  cmpb   $0x0,(%rsi)
  setne  %al
  jmp    L29
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; (*s1 != '\0') && (*s2 != '\0'); s1++, s2++) {
    if (*s1 != *s2)
      break;
  }
  if (*s1 == *s2)
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_long_timestamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <do_datestamp@plt>
  mov    -0x48(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <do_timestamp@plt>
  movzbl -0x20(%rbp),%eax
  cmp    $0x20,%al
  jne    L6
  lea    -0x20(%rbp),%rax
  add    $0x1,%rax
  lea    -0x40(%rbp),%rdx
  mov    %rax,%rcx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L0
L6:
  lea    -0x20(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
L0:
  lea    D49(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: %s %s

assistant: ```c
char *do_long_timestamp(struct tm *t) {
  static char longbuf[40];
  char datebuf[20], timebuf[20];
  do_datestamp(datebuf, t);
  do_timestamp(timebuf, t);
  if (timebuf[0] == ' ')
    sprintf(longbuf, "%s %s", datebuf, timebuf + 1);
  else
    sprintf(longbuf, "%s %s", datebuf, timebuf);
  return longbuf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_long_timestamp>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <do_datestamp@plt>
  lea    0x20(%rsp),%rdi
  mov    %rbx,%rsi
  call   <do_timestamp@plt>
  cmpb   $0x20,0x20(%rsp)
  je     L22
  lea    0x20(%rsp),%rcx
  mov    %rsp,%rdx
  lea    D2(%rip),%rsi
  lea    D47(%rip),%rdi
  call   <sprintf@plt>
L10:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  lea    D47(%rip),%rax
  add    $0x40,%rsp
  pop    %rbx
  ret
L22:
  lea    0x21(%rsp),%rcx
  mov    %rsp,%rdx
  lea    D2(%rip),%rsi
  lea    D47(%rip),%rdi
  call   <sprintf@plt>
  jmp    L10
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: %s %s

assistant: ```c
char *do_long_timestamp(struct tm *t) {
  static char longbuf[40];
  char datebuf[20], timebuf[20];
  do_datestamp(datebuf, t);
  do_timestamp(timebuf, t);
  if (timebuf[0] == ' ')
    sprintf(longbuf, "%s %s", datebuf, timebuf + 1);
  else
    sprintf(longbuf, "%s %s", datebuf, timebuf);
  return longbuf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_long_timestamp>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%r13
  mov    %r12,%rdi
  call   <do_datestamp@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <do_timestamp@plt>
  cmpb   $0x20,0x20(%rsp)
  lea    0x21(%rsp),%rcx
  je     L13
  mov    %r13,%rcx
L13:
  mov    %r12,%rdx
  lea    D16(%rip),%r12
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x40,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: %s %s

assistant: ```c
char *do_long_timestamp(struct tm *t) {
  static char longbuf[40];
  char datebuf[20], timebuf[20];
  do_datestamp(datebuf, t);
  do_timestamp(timebuf, t);
  if (timebuf[0] == ' ')
    sprintf(longbuf, "%s %s", datebuf, timebuf + 1);
  else
    sprintf(longbuf, "%s %s", datebuf, timebuf);
  return longbuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_long_timestamp>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%r13
  mov    %r12,%rdi
  call   <do_datestamp@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <do_timestamp@plt>
  cmpb   $0x20,0x20(%rsp)
  lea    0x21(%rsp),%rcx
  je     L5
  mov    %r13,%rcx
L5:
  mov    %r12,%rdx
  lea    D10(%rip),%r12
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x40,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string

tool: D14: %s %s

assistant: ```c
char *do_long_timestamp(struct tm *t) {
  static char longbuf[40];
  char datebuf[20], timebuf[20];
  do_datestamp(datebuf, t);
  do_timestamp(timebuf, t);
  if (timebuf[0] == ' ')
    sprintf(longbuf, "%s %s", datebuf, timebuf + 1);
  else
    sprintf(longbuf, "%s %s", datebuf, timebuf);
  return longbuf;
}
```