ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0xf8,%rsp
  xor    %edx,%edx
  movdqa D1(%rip),%xmm0
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  movabs $0x696c6f696c655a,%rax
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  lea    0x40(%rsp),%rcx
  movaps %xmm0,0x80(%rsp)
  mov    %rsp,%rsi
  movdqa D14(%rip),%xmm0
  mov    %rdx,0x48(%rsp)
  xor    %edx,%edx
  mov    %rdx,0x68(%rsp)
  lea    0x20(%rsp),%rdx
  movl   $0x0,0x10(%rsp)
  movq   $0x6163754c,0x20(%rsp)
  mov    %rax,(%rsp)
  movabs $0x36333935303031,%rax
  mov    %rax,0x40(%rsp)
  movabs $0x2b2b4320432043,%rax
  mov    %rax,0x60(%rsp)
  xor    %eax,%eax
  mov    %ax,0xdc(%rsp)
  lea    0xc0(%rsp),%rax
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x50(%rsp)
  movl   $0x0,0x70(%rsp)
  movl   $0x0,0x90(%rsp)
  movq   $0x35,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movl   $0x0,0xb0(%rsp)
  movq   $0x0,0xd0(%rsp)
  movl   $0x0,0xd8(%rsp)
  movaps %xmm0,0xc0(%rsp)
  push   %rax
  lea    0xa8(%rsp),%rax
  push   %rax
  lea    0x90(%rsp),%r9
  lea    0x70(%rsp),%r8
  call   <printf@plt>
  pop    %rdx
  pop    %rcx
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0xf8,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: byte[16]
name: disassemble_data
arguments: data_label: D16
type: string
name: disassemble_data
arguments: data_label: D14
type: byte[16]

tool: {"D1": [0x73,0x75,0x70,0x65,0x72,0x20,0x48,0x69,0x67,0x68,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D16: Student:

Last name:				 %s
First name:				 %s
Student number:				 %s
Programming experience:			 %s
Motivation to learn C:			 %s
Grade I aim at:				 %s
My plan to achieve that grade:		 %s


tool: {"D14": [0x73,0x74,0x75,0x64,0x69,0x6e,0x67,0x20,0x68,0x61,0x72,0x64,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  char lastName[20] = "Zelioli";
  char firstName[20] = "Luca";
  char studentNumber[20] = "1005936";
  char programmingExp[20] = "C C C++";
  char motivationToLearn[20] = "super High";
  char grade[20] = "5";
  char myPlane[30] = "studing hard";
  printf("Student:\n\nLast name:\t\t\t\t %s\nFirst name:\t\t\t\t %s\nStudent number:\t\t\t\t %s\nProgramming experience:\t\t\t %s\nMotivation to learn C:\t\t\t %s\nGrade I aim at:\t\t\t\t %s\nMy plan to achieve that grade:\t\t %s\n", lastName, firstName, studentNumber, programmingExp, motivationToLearn, grade, myPlane);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<numcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L35
  mov    $0xffffffff,%eax
  jmp    L9
L35:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L30
  mov    $0x1,%eax
  jmp    L9
L30:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int numcmp(const char *s1, const char *s2) {
  double v1 = atof(s1);
  double v2 = atof(s2);
  if (v1 < v2)
    return -1;
  else if (v1 > v2)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<numcmp>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  call   <atof@plt>
  movq   %xmm0,%r14
  mov    %rbx,%rdi
  call   <atof@plt>
  mov    $0xffffffff,%eax
  movq   %r14,%xmm1
  comisd %xmm1,%xmm0
  ja     L9
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
int numcmp(const char *s1, const char *s2) {
  double v1 = atof(s1);
  double v2 = atof(s2);
  if (v1 < v2)
    return -1;
  else if (v1 > v2)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<numcmp>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  call   <atof@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L9
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L9:
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
int numcmp(const char *s1, const char *s2) {
  double v1 = atof(s1);
  double v2 = atof(s2);
  if (v1 < v2)
    return -1;
  else if (v1 > v2)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<numcmp>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  call   <atof@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L4
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L4:
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
int numcmp(const char *s1, const char *s2) {
  double v1 = atof(s1);
  double v2 = atof(s2);
  if (v1 < v2)
    return -1;
  else if (v1 > v2)
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_set_structure_supporting>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x76,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int is_set_structure_supporting(int *inout) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(118, inout, b, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_set_structure_supporting>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x76,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_set_structure_supporting(int *inout) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(118, inout, b, c);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_set_structure_supporting>:
  endbr64
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x76,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int is_set_structure_supporting(int *inout) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(118, inout, b, c);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_set_structure_supporting>:
  endbr64
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x76,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int is_set_structure_supporting(int *inout) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(118, inout, b, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<generate_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srandom@plt>
  mov    $0x0,%eax
  call   <random@plt>
  mov    $0x0,%edx
  divq   -0x8(%rbp)
  mov    %rdx,%rax
  leave
  ret
```

assistant: ```c
int generate_random(size_t len) {
  srandom(time(NULL));
  return random() % len;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<generate_random>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srandom@plt>
  mov    $0x0,%eax
  call   <random@plt>
  mov    $0x0,%edx
  div    %rbx
  mov    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int generate_random(size_t len) {
  srandom(time(NULL));
  return random() % len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<generate_random>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srandom@plt>
  xor    %eax,%eax
  call   <random@plt>
  xor    %edx,%edx
  div    %rbx
  pop    %rbx
  mov    %edx,%eax
  ret
```

assistant: ```c
int generate_random(size_t len) {
  srandom(time(NULL));
  return random() % len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<generate_random>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srandom@plt>
  xor    %eax,%eax
  call   <random@plt>
  xor    %edx,%edx
  div    %rbx
  pop    %rbx
  mov    %edx,%eax
  ret
```

assistant: ```c
int generate_random(size_t len) {
  srandom(time(NULL));
  return random() % len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basLTrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <popString@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ltrim@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <eFree@plt>
  nop
  leave
  ret
```

assistant: ```c
void basLTrim() {
  char *string;
  char *dest;
  string = popString();
  dest = ltrim(string);
  pushStringCopy(dest);
  eFree(string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<basLTrim>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <popString@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <ltrim@plt>
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  mov    %rbx,%rdi
  call   <eFree@plt>
  pop    %rbx
  ret
```

assistant: ```c
void basLTrim() {
  char *string;
  char *dest;
  string = popString();
  dest = ltrim(string);
  pushStringCopy(dest);
  eFree(string);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<basLTrim>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <popString@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <ltrim@plt>
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10b0 <eFree@plt>
```

assistant: ```c
void basLTrim() {
  char *string;
  char *dest;
  string = popString();
  dest = ltrim(string);
  pushStringCopy(dest);
  eFree(string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<basLTrim>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <popString@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <ltrim@plt>
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10b0 <eFree@plt>
```

assistant: ```c
void basLTrim() {
  char *string;
  char *dest;
  string = popString();
  dest = ltrim(string);
  pushStringCopy(dest);
  eFree(string);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<backtrackSubsets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L5
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printSubset@plt>
  jmp    L4
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <backtrackSubsets>
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <backtrackSubsets>
L4:
  nop
  leave
  ret
```

assistant: ```c
void backtrackSubsets(int A[], int k, int n) {
  if (k == n) {
    printSubset(A, k);
  } else {
    A[k] = 0;
    backtrackSubsets(A, k + 1, n);
    A[k] = 1;
    backtrackSubsets(A, k + 1, n);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<backtrackSubsets>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  cmp    %edx,%esi
  je     L8
  mov    %edx,%r12d
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r13
  movl   $0x0,0x0(%r13)
  lea    0x1(%rsi),%ebx
  mov    %ebx,%esi
  call   <backtrackSubsets>
  movl   $0x1,0x0(%r13)
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <backtrackSubsets>
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <printSubset@plt>
  jmp    L4
```

assistant: ```c
void backtrackSubsets(int A[], int k, int n) {
  if (k == n) {
    printSubset(A, k);
  } else {
    A[k] = 0;
    backtrackSubsets(A, k + 1, n);
    A[k] = 1;
    backtrackSubsets(A, k + 1, n);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%ebp
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    D33(%rip),%r15
  jmp    L10
L7:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    0x8(%rsp),%rdi
  call   <realloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L83
L77:
  lea    0x1(%rbp),%r12d
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  movslq %ebp,%rbp
  movzbl 0x17(%rsp),%eax
  mov    %al,(%rbx,%rbp,1)
  add    $0x1,%r14d
  mov    %r12d,%ebp
L10:
  lea    0x17(%rsp),%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L58
  movzbl 0x17(%rsp),%eax
  cmp    $0x20,%al
  je     L11
  cmp    $0xa,%al
  jne    L77
L11:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    0x8(%rsp),%rdi
  call   <strlen@plt>
  cmp    %eax,%ebp
  jg     L7
L83:
  add    $0x1,%r13d
  cmpb   $0xa,0x17(%rsp)
  je     L58
  mov    $0x0,%ebp
  jmp    L10
L58:
  mov    %r13d,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %r14d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r13d,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D41(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D21
data_type: string
name: parse_data
arguments: label: D33
data_type: string
name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D28
data_type: string
name: parse_data
arguments: label: D41
data_type: string

tool: D21: Frase? 

tool: D33: %c

tool: D2: Numero de palavras: %d


tool: D28: Palavra maior: %s


tool: D41: Comprimento medio: %.1f


assistant: ```c
int main() {
  char c, *max, *p;
  int n = 0, l = 0, i = 0;
  printf("Frase? ");
  max = (char *)malloc(sizeof(char));
  p = (char *)malloc(sizeof(char));
  while (scanf("%c", &c) == 1) {
    if (c == ' ' || c == '\n') {
      if (strlen(p) > strlen(max)) {
        max = (char *)realloc(max, sizeof(char) * strlen(p));
        strcpy(max, p);
      }
      n++;
      i = 0;
      if (c == '\n')
        break;
    } else {
      p = (char *)realloc(p, sizeof(char) * (i + 1));
      p[i] = c;
      l++;
      i++;
    }
  }
  printf("Numero de palavras: %d\n", n);
  printf("Palavra maior: %s\n", max);
  printf("Comprimento medio: %.1f\n", (float)l / (float)n);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tst_float_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <fabsf@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  fldt   (%rax)
  fstpl  -0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  call   <fabs@plt>
  mov    -0x10(%rbp),%rax
  fstpt  (%rax)
  mov    -0x10(%rbp),%rax
  fldt   (%rax)
  fstpl  -0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  call   <fabs@plt>
  mov    -0x10(%rbp),%rax
  fstpt  (%rax)
  nop
  leave
  ret
```

assistant: ```c
void tst_float_size(double *pd, long double *pld) {
  *pd = fabsf(*pd);
  *pld = fabs(*pld);
  *pld = fabs((double)*pld);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<tst_float_size>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movsd  (%rdi),%xmm0
  call   <fabsf@plt>
  movsd  %xmm0,0x0(%rbp)
  fldt   (%rbx)
  fstpl  0x8(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <fabs@plt>
  fld    %st(0)
  fstpt  (%rbx)
  fstpl  0x8(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <fabs@plt>
  fstpt  (%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void tst_float_size(double *pd, long double *pld) {
  *pd = fabsf(*pd);
  *pld = fabs(*pld);
  *pld = fabs((double)*pld);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tst_float_size>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movsd  (%rdi),%xmm0
  call   <fabsf@plt>
  fldt   (%rbx)
  movsd  %xmm0,0x0(%rbp)
  fstpl  0x8(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <fabs@plt>
  fld    %st(0)
  fstpt  (%rbx)
  fstpl  0x8(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <fabs@plt>
  fstpt  (%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void tst_float_size(double *pd, long double *pld) {
  *pd = fabsf(*pd);
  *pld = fabs(*pld);
  *pld = fabs((double)*pld);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tst_float_size>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movsd  (%rdi),%xmm0
  call   <fabsf@plt>
  fldt   (%rbx)
  movsd  %xmm0,0x0(%rbp)
  fstpl  0x8(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <fabs@plt>
  fld    %st(0)
  fstpt  (%rbx)
  fstpl  0x8(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <fabs@plt>
  fstpt  (%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void tst_float_size(double *pd, long double *pld) {
  *pd = fabsf(*pd);
  *pld = fabs(*pld);
  *pld = fabs((double)*pld);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<intToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L5:
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  lea    D3(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  sarl   $0x4,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x3,-0x4(%rbp)
  jle    L5
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string

tool: D3: 0123456789ABCDEF

assistant: ```c
void intToHex(int32_t value, char *buffer) {
  uint8_t i;
  for (i = 0; i < 4; i++) {
    buffer[i] = "0123456789ABCDEF"[value & 0xF];
    value >>= 4;
  }
  buffer[4] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intToHex>:
  endbr64
  mov    %rsi,%rax
  lea    0x4(%rsi),%r8
  lea    D8(%rip),%rcx
L8:
  mov    %edi,%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rax)
  sar    $0x4,%edi
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L8
  movb   $0x0,0x4(%rsi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: 0123456789ABCDEF

assistant: ```c
void intToHex(int32_t value, char *buffer) {
  uint8_t i;
  for (i = 0; i < 4; i++) {
    buffer[i] = "0123456789ABCDEF"[value & 0xF];
    value >>= 4;
  }
  buffer[4] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<intToHex>:
  endbr64
  mov    %rsi,%rax
  lea    0x4(%rsi),%r8
  lea    D9(%rip),%rcx
L9:
  mov    %edi,%edx
  add    $0x1,%rax
  sar    $0x4,%edi
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,-0x1(%rax)
  cmp    %r8,%rax
  jne    L9
  movb   $0x0,0x4(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: 0123456789ABCDEF

assistant: ```c
void intToHex(int32_t value, char *buffer) {
  uint8_t i;
  for (i = 0; i < 4; i++) {
    buffer[i] = "0123456789ABCDEF"[value & 0xF];
    value >>= 4;
  }
  buffer[4] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<intToHex>:
  endbr64
  mov    %edi,%edx
  lea    D3(%rip),%rax
  movb   $0x0,0x4(%rsi)
  and    $0xf,%edx
  movzbl (%rax,%rdx,1),%edx
  mov    %dl,(%rsi)
  mov    %edi,%edx
  sar    $0x4,%edx
  and    $0xf,%edx
  movzbl (%rax,%rdx,1),%edx
  mov    %dl,0x1(%rsi)
  mov    %edi,%edx
  sar    $0xc,%edi
  sar    $0x8,%edx
  and    $0xf,%edi
  and    $0xf,%edx
  movzbl (%rax,%rdx,1),%edx
  movzbl (%rax,%rdi,1),%eax
  mov    %dl,0x2(%rsi)
  mov    %al,0x3(%rsi)
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: 0123456789ABCDEF

assistant: ```c
void intToHex(int32_t value, char *buffer) {
  uint8_t i;
  for (i = 0; i < 4; i++) {
    buffer[i] = "0123456789ABCDEF"[value & 0xF];
    value >>= 4;
  }
  buffer[4] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stdlib_strided_snanmeanwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jg     L25
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  jmp    L124
L25:
  cmpq   $0x1,-0x28(%rbp)
  je     L89
  cmpq   $0x0,-0x38(%rbp)
  jne    L53
L89:
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm0
  jmp    L124
L53:
  cmpq   $0x0,-0x38(%rbp)
  jns    L108
  mov    $0x1,%eax
  sub    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L96
L108:
  movq   $0x0,-0x18(%rbp)
L96:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L55
L76:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x1c(%rbp),%xmm0
  ucomiss -0x1c(%rbp),%xmm0
  jp     L97
  movsd  -0x8(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movss  -0x1c(%rbp),%xmm0
  subss  -0x20(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  -0x8(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  -0x20(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x20(%rbp)
L97:
  mov    -0x38(%rbp),%rax
  add    %rax,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L55:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L76
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L127
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L127
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  jmp    L124
L127:
  movss  -0x20(%rbp),%xmm0
L124:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type: f64

tool: D8: 1

assistant: ```c
float stdlib_strided_snanmeanwd(const int64_t N, const float *X, const int64_t stride) {
  int64_t ix;
  int64_t i;
  double n;
  float mu;
  float v;
  if (N <= 0) {
    return 0.0f / 0.0f;
  }
  if (N == 1 || stride == 0) {
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  mu = 0.0f;
  n = 0.0;
  for (i = 0; i < N; i++) {
    v = X[ix];
    if (v == v) {
      n += 1.0;
      mu += (float)((double)(v - mu) / n);
    }
    ix += stride;
  }
  if (n == 0.0) {
    return 0.0f / 0.0f;
  }
  return mu;
}
```