ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<mdup>:
  endbr64
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L18
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  ret
```

assistant: ```c
void *mdup(const void *src, size_t n) {
  if (n == 0) {
    return NULL;
  }
  void *dst = malloc(n);
  if (dst == NULL) {
    return NULL;
  }
  return memcpy(dst, src, n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mdup>:
  endbr64
  test   %rsi,%rsi
  je     L14
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *mdup(const void *src, size_t n) {
  if (n == 0) {
    return NULL;
  }
  void *dst = malloc(n);
  if (dst == NULL) {
    return NULL;
  }
  return memcpy(dst, src, n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mdup>:
  endbr64
  test   %rsi,%rsi
  je     L9
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L19
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *mdup(const void *src, size_t n) {
  if (n == 0) {
    return NULL;
  }
  void *dst = malloc(n);
  if (dst == NULL) {
    return NULL;
  }
  return memcpy(dst, src, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rand31_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  movzwl %ax,%eax
  imul   $0x41a7,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x10,%eax
  imul   $0x41a7,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  and    $0x7fff0000,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0xf,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t rand31_r(uint32_t *seedp) {
  uint32_t hi, lo;
  lo = 16807 * (*seedp & 0xffff);
  hi = 16807 * (*seedp >> 16);
  lo += (hi & 0x7fff) << 16;
  lo += hi >> 15;
  if (lo > 0x7fffffff)
    lo -= 0x7fffffff;
  return (*seedp = lo);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rand31_r>:
  endbr64
  mov    (%rdi),%eax
  movzwl %ax,%ecx
  imul   $0x41a7,%ecx,%ecx
  sar    $0x10,%eax
  imul   $0x41a7,%eax,%eax
  mov    %eax,%edx
  shl    $0x10,%edx
  and    $0x7fff0000,%edx
  add    %ecx,%edx
  sar    $0xf,%eax
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
uint32_t rand31_r(uint32_t *seedp) {
  uint32_t hi, lo;
  lo = 16807 * (*seedp & 0xffff);
  hi = 16807 * (*seedp >> 16);
  lo += (hi & 0x7fff) << 16;
  lo += hi >> 15;
  if (lo > 0x7fffffff)
    lo -= 0x7fffffff;
  return (*seedp = lo);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rand31_r>:
  endbr64
  mov    (%rdi),%eax
  movzwl %ax,%ecx
  sar    $0x10,%eax
  imul   $0x41a7,%eax,%eax
  imul   $0x41a7,%ecx,%ecx
  mov    %eax,%edx
  sar    $0xf,%eax
  shl    $0x10,%edx
  and    $0x7fff0000,%edx
  add    %ecx,%edx
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
uint32_t rand31_r(uint32_t *seedp) {
  uint32_t hi, lo;
  lo = 16807 * (*seedp & 0xffff);
  hi = 16807 * (*seedp >> 16);
  lo += (hi & 0x7fff) << 16;
  lo += hi >> 15;
  if (lo > 0x7fffffff)
    lo -= 0x7fffffff;
  return (*seedp = lo);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m_shadow>:
  endbr64
  movss  (%rdi),%xmm1
  mulss  (%rsi),%xmm1
  movss  0x4(%rdi),%xmm0
  mulss  0x4(%rsi),%xmm0
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm2
  mulss  0x8(%rsi),%xmm2
  addss  %xmm2,%xmm0
  movss  0xc(%rdi),%xmm2
  mulss  0xc(%rsi),%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm0,%xmm2
  subss  %xmm1,%xmm2
  movss  %xmm2,(%rdx)
  movss  0x4(%rsi),%xmm2
  movss  D8(%rip),%xmm1
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0x4(%rdx)
  movss  0x8(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0x8(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0xc(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x10(%rdx)
  movss  0x4(%rsi),%xmm2
  mulss  0x4(%rdi),%xmm2
  movaps %xmm0,%xmm3
  subss  %xmm2,%xmm3
  movss  %xmm3,0x14(%rdx)
  movss  0x8(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x18(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x1c(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x20(%rdx)
  movss  0x4(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x24(%rdx)
  movss  0x8(%rsi),%xmm2
  mulss  0x8(%rdi),%xmm2
  movaps %xmm0,%xmm3
  subss  %xmm2,%xmm3
  movss  %xmm3,0x28(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x2c(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x30(%rdx)
  movss  0x4(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x34(%rdx)
  movss  0x8(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x38(%rdx)
  movss  0xc(%rsi),%xmm1
  mulss  0xc(%rdi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x3c(%rdx)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x80]}

assistant: ```c
void m_shadow(const float *plane, const float *light, float *out) {
  float dot;
  dot = plane[0] * light[0] + plane[1] * light[1] + plane[2] * light[2] + plane[3] * light[3];
  out[0] = -light[0] * plane[0] + dot;
  out[1] = -light[1] * plane[0];
  out[2] = -light[2] * plane[0];
  out[3] = -light[3] * plane[0];
  out[4] = -light[0] * plane[1];
  out[5] = -light[1] * plane[1] + dot;
  out[6] = -light[2] * plane[1];
  out[7] = -light[3] * plane[1];
  out[8] = -light[0] * plane[2];
  out[9] = -light[1] * plane[2];
  out[10] = -light[2] * plane[2] + dot;
  out[11] = -light[3] * plane[2];
  out[12] = -light[0] * plane[3];
  out[13] = -light[1] * plane[3];
  out[14] = -light[2] * plane[3];
  out[15] = -light[3] * plane[3] + dot;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<m_shadow>:
  endbr64
  movss  (%rdi),%xmm1
  movss  0x4(%rdi),%xmm0
  mulss  (%rsi),%xmm1
  movss  0x8(%rdi),%xmm2
  mulss  0x4(%rsi),%xmm0
  mulss  0x8(%rsi),%xmm2
  addss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  movss  0xc(%rdi),%xmm2
  mulss  0xc(%rsi),%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm0,%xmm2
  movaps %xmm0,%xmm3
  subss  %xmm1,%xmm2
  movss  D6(%rip),%xmm1
  movss  %xmm2,(%rdx)
  movss  0x4(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0x4(%rdx)
  movss  0x8(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0x8(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0xc(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x10(%rdx)
  movss  0x4(%rsi),%xmm2
  mulss  0x4(%rdi),%xmm2
  subss  %xmm2,%xmm3
  movss  %xmm3,0x14(%rdx)
  movss  0x8(%rsi),%xmm2
  movaps %xmm0,%xmm3
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x18(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x1c(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x20(%rdx)
  movss  0x4(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x24(%rdx)
  movss  0x8(%rsi),%xmm2
  mulss  0x8(%rdi),%xmm2
  subss  %xmm2,%xmm3
  movss  %xmm3,0x28(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x2c(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x30(%rdx)
  movss  0x4(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x34(%rdx)
  movss  0x8(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x38(%rdx)
  movss  0xc(%rsi),%xmm1
  mulss  0xc(%rdi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x3c(%rdx)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x80]}

assistant: ```c
void m_shadow(const float *plane, const float *light, float *out) {
  float dot;
  dot = plane[0] * light[0] + plane[1] * light[1] + plane[2] * light[2] + plane[3] * light[3];
  out[0] = -light[0] * plane[0] + dot;
  out[1] = -light[1] * plane[0];
  out[2] = -light[2] * plane[0];
  out[3] = -light[3] * plane[0];
  out[4] = -light[0] * plane[1];
  out[5] = -light[1] * plane[1] + dot;
  out[6] = -light[2] * plane[1];
  out[7] = -light[3] * plane[1];
  out[8] = -light[0] * plane[2];
  out[9] = -light[1] * plane[2];
  out[10] = -light[2] * plane[2] + dot;
  out[11] = -light[3] * plane[2];
  out[12] = -light[0] * plane[3];
  out[13] = -light[1] * plane[3];
  out[14] = -light[2] * plane[3];
  out[15] = -light[3] * plane[3] + dot;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<m_shadow>:
  endbr64
  movss  (%rdi),%xmm1
  movss  0x4(%rdi),%xmm0
  mulss  (%rsi),%xmm1
  movss  0x8(%rdi),%xmm2
  mulss  0x4(%rsi),%xmm0
  mulss  0x8(%rsi),%xmm2
  addss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  movss  0xc(%rdi),%xmm2
  mulss  0xc(%rsi),%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm0,%xmm2
  movaps %xmm0,%xmm3
  subss  %xmm1,%xmm2
  movss  D0(%rip),%xmm1
  movss  %xmm2,(%rdx)
  movss  0x4(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0x4(%rdx)
  movss  0x8(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0x8(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  (%rdi),%xmm2
  movss  %xmm2,0xc(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x10(%rdx)
  movss  0x4(%rsi),%xmm2
  mulss  0x4(%rdi),%xmm2
  subss  %xmm2,%xmm3
  movss  %xmm3,0x14(%rdx)
  movss  0x8(%rsi),%xmm2
  movaps %xmm0,%xmm3
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x18(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x4(%rdi),%xmm2
  movss  %xmm2,0x1c(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x20(%rdx)
  movss  0x4(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x24(%rdx)
  movss  0x8(%rsi),%xmm2
  mulss  0x8(%rdi),%xmm2
  subss  %xmm2,%xmm3
  movss  %xmm3,0x28(%rdx)
  movss  0xc(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0x8(%rdi),%xmm2
  movss  %xmm2,0x2c(%rdx)
  movss  (%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x30(%rdx)
  movss  0x4(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x34(%rdx)
  movss  0x8(%rsi),%xmm2
  xorps  %xmm1,%xmm2
  mulss  0xc(%rdi),%xmm2
  movss  %xmm2,0x38(%rdx)
  movss  0xc(%rsi),%xmm1
  mulss  0xc(%rdi),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x3c(%rdx)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x80]}

assistant: ```c
void m_shadow(const float *plane, const float *light, float *out) {
  float dot;
  dot = plane[0] * light[0] + plane[1] * light[1] + plane[2] * light[2] + plane[3] * light[3];
  out[0] = -light[0] * plane[0] + dot;
  out[1] = -light[1] * plane[0];
  out[2] = -light[2] * plane[0];
  out[3] = -light[3] * plane[0];
  out[4] = -light[0] * plane[1];
  out[5] = -light[1] * plane[1] + dot;
  out[6] = -light[2] * plane[1];
  out[7] = -light[3] * plane[1];
  out[8] = -light[0] * plane[2];
  out[9] = -light[1] * plane[2];
  out[10] = -light[2] * plane[2] + dot;
  out[11] = -light[3] * plane[2];
  out[12] = -light[0] * plane[3];
  out[13] = -light[1] * plane[3];
  out[14] = -light[2] * plane[3];
  out[15] = -light[3] * plane[3] + dot;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%edx
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string
name: read_data
arguments: label: D7
type_guessed: string

tool: D5: %c

tool: D7: %c:%i


assistant: ```c
int main() {
  char c;
  scanf("%c", &c);
  printf("%c:%i\n", c, c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  mov    %esi,%edx
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string
name: retrieve_data
arguments: data_tag: D11
type: string

tool: D3: %c

tool: D11: %c:%i


assistant: ```c
int main() {
  char c;
  scanf("%c", &c);
  printf("%c:%i\n", c, c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  lea    D13(%rip),%rdi
  mov    %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D11
datatype: string
name: unpack_data
arguments: data_label: D13
datatype: string

tool: D11: %c

tool: D13: %c:%i


assistant: ```c
int main() {
  char c;
  scanf("%c", &c);
  printf("%c:%i\n", c, c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  lea    D0(%rip),%rdi
  mov    %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D5: %c

tool: D0: %c:%i


assistant: ```c
int main() {
  char c;
  scanf("%c", &c);
  printf("%c:%i\n", c, c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L5
L18:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L5:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L18
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D49
datatype: string
name: disassemble_data
arguments: label: D47
datatype: string
name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string

tool: D1: Enter a positive number: 

tool: D49: %d

tool: D47: Please enter number %d: 

tool: D18: %lf

tool: D15: Sum = %.1f

assistant: ```c
int main() {
  int n;
  printf("Enter a positive number: ");
  scanf("%d", &n);
  int i;
  double sum = 0, currentNum;
  for (i = 1; i <= n; i++) {
    printf("Please enter number %d: ", i);
    scanf("%lf", &currentNum);
    sum += currentNum;
  }
  printf("Sum = %.1f", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L0
  mov    D37(%rip),%rbp
  mov    $0x1,%ebx
  lea    D57(%rip),%r14
  lea    0x10(%rsp),%r13
  lea    D69(%rip),%r12
L5:
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   %rbp,%xmm1
  addsd  0x10(%rsp),%xmm1
  movq   %xmm1,%rbp
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jge    L5
L19:
  movq   %rbp,%xmm0
  lea    D23(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  mov    D37(%rip),%rbp
  jmp    L19
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D52
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string
name: retrieve_data
arguments: label: D37
data_type: f64
name: retrieve_data
arguments: label: D57
data_type: string
name: retrieve_data
arguments: label: D69
data_type: string
name: retrieve_data
arguments: label: D23
data_type: string

tool: D52: Enter a positive number: 

tool: D25: %d

tool: D37: 0

tool: D57: Please enter number %d: 

tool: D69: %lf

tool: D23: Sum = %.1f

assistant: ```c
int main() {
  int n;
  printf("Enter a positive number: ");
  scanf("%d", &n);
  int i;
  double sum = 0, currentNum;
  for (i = 1; i <= n; i++) {
    printf("Please enter number %d: ", i);
    scanf("%lf", &currentNum);
    sum += currentNum;
  }
  printf("Sum = %.1f", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L24
  mov    $0x1,%ebx
  lea    D12(%rip),%r13
  lea    0x20(%rsp),%r12
  lea    D9(%rip),%rbp
  nopl   0x0(%rax)
L27:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  movsd  0x8(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  cmp    %ebx,0x1c(%rsp)
  jge    L27
L24:
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D41
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D13
type_guessed: string

tool: D11: Enter a positive number: 

tool: D41: %d

tool: D12: Please enter number %d: 

tool: D9: %lf

tool: D13: Sum = %.1f

assistant: ```c
int main() {
  int n;
  printf("Enter a positive number: ");
  scanf("%d", &n);
  int i;
  double sum = 0, currentNum;
  for (i = 1; i <= n; i++) {
    printf("Please enter number %d: ", i);
    scanf("%lf", &currentNum);
    sum += currentNum;
  }
  printf("Sum = %.1f", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D40(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L19
  mov    $0x1,%ebx
  lea    D14(%rip),%r13
  lea    0x20(%rsp),%r12
  lea    D11(%rip),%rbp
  nopl   0x0(%rax)
L25:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  movsd  0x8(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  cmp    %ebx,0x1c(%rsp)
  jge    L25
L19:
  lea    D46(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D40
datatype: string
name: unpack_data
arguments: data_label: D10
datatype: string
name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D11
datatype: string
name: unpack_data
arguments: data_label: D46
datatype: string

tool: D40: Enter a positive number: 

tool: D10: %d

tool: D14: Please enter number %d: 

tool: D11: %lf

tool: D46: Sum = %.1f

assistant: ```c
int main() {
  int n;
  printf("Enter a positive number: ");
  scanf("%d", &n);
  int i;
  double sum = 0, currentNum;
  for (i = 1; i <= n; i++) {
    printf("Please enter number %d: ", i);
    scanf("%lf", &currentNum);
    sum += currentNum;
  }
  printf("Sum = %.1f", sum);
  return 0;
}
```