ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<cose>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  addsd  D110(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  comisd D29(%rip),%xmm1
  jbe    L13
  subsd  D14(%rip),%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
L13:
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L25
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  mulsd  D49(%rip),%xmm1
  movapd %xmm0,%xmm2
  mulsd  D23(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  ja     L21
  movaps %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D101(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
L25:
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  mulsd  D23(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  D49(%rip),%xmm0
  addsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  ja     L5
  movaps %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D101(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
L5:
  movaps %xmm1,%xmm0
  xorps  D1(%rip),%xmm0
  mulss  %xmm1,%xmm0
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D101(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
L21:
  movaps %xmm1,%xmm0
  xorps  D1(%rip),%xmm0
  mulss  %xmm1,%xmm0
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D101(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D110
type_infered: f64
name: retrieve_data
arguments: data_tag: D29
type_infered: f64[2]
name: retrieve_data
arguments: data_tag: D14
type_infered: f64
name: retrieve_data
arguments: data_tag: D49
type_infered: f64
name: retrieve_data
arguments: data_tag: D23
type_infered: f64
name: retrieve_data
arguments: data_tag: D101
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D1
type_infered: byte[16]

tool: D110: 1.57079632

tool: {"D29": [3.14159265,6.28318531]}

tool: D14: 6.28318531

tool: D49: 1.27323954

tool: D23: 0.405284735

tool: {"D101": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xcc,0x3f]}

tool: {"D1": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float cose(float x) {
  x += 1.57079632;
  if (x > 3.14159265)
    x -= 6.28318531;
  float result = 0.0;
  if (x < 0) {
    result = 1.27323954 * x + 0.405284735 * x * x;
    if (result < 0)
      result = .225 * (result * -result - result) + result;
    else
      result = .225 * (result * result - result) + result;
  } else {
    result = 1.27323954 * x - 0.405284735 * x * x;
    if (result < 0)
      result = .225 * (result * -result - result) + result;
    else
      result = .225 * (result * result - result) + result;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cose>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  addsd  D46(%rip),%xmm0
  pxor   %xmm2,%xmm2
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm2
  comisd D16(%rip),%xmm2
  jbe    L23
  subsd  D24(%rip),%xmm2
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
L23:
  movsd  D67(%rip),%xmm3
  movsd  D69(%rip),%xmm1
  mulsd  %xmm2,%xmm3
  mulsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm2
  pxor   %xmm3,%xmm3
  comiss %xmm0,%xmm3
  ja     L5
  subsd  %xmm2,%xmm1
L9:
  cvtsd2ss %xmm1,%xmm1
  comiss %xmm1,%xmm3
  pxor   %xmm2,%xmm2
  movaps %xmm1,%xmm0
  cvtss2sd %xmm1,%xmm2
  jbe    L28
  xorps  D15(%rip),%xmm0
L28:
  mulss  %xmm1,%xmm0
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D36(%rip),%xmm0
  addsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nop
L5:
  addsd  %xmm2,%xmm1
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: tag: D46
data_type: f64
name: disassemble_data
arguments: tag: D16
data_type: f64[2]
name: disassemble_data
arguments: tag: D24
data_type: f64
name: disassemble_data
arguments: tag: D67
data_type: f64
name: disassemble_data
arguments: tag: D69
data_type: f64
name: disassemble_data
arguments: tag: D15
data_type: byte[16]
name: disassemble_data
arguments: tag: D36
data_type: byte[8]

tool: D46: 1.57079632

tool: {"D16": [3.14159265,6.28318531]}

tool: D24: 6.28318531

tool: D67: 0.405284735

tool: D69: 1.27323954

tool: {"D15": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D36": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xcc,0x3f]}

assistant: ```c
float cose(float x) {
  x += 1.57079632;
  if (x > 3.14159265)
    x -= 6.28318531;
  float result = 0.0;
  if (x < 0) {
    result = 1.27323954 * x + 0.405284735 * x * x;
    if (result < 0)
      result = .225 * (result * -result - result) + result;
    else
      result = .225 * (result * result - result) + result;
  } else {
    result = 1.27323954 * x - 0.405284735 * x * x;
    if (result < 0)
      result = .225 * (result * -result - result) + result;
    else
      result = .225 * (result * result - result) + result;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cose>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  addsd  D56(%rip),%xmm0
  pxor   %xmm2,%xmm2
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm2
  comisd D42(%rip),%xmm2
  jbe    L28
  subsd  D53(%rip),%xmm2
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
L28:
  movsd  D67(%rip),%xmm3
  movsd  D65(%rip),%xmm1
  mulsd  %xmm2,%xmm3
  mulsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm2
  pxor   %xmm3,%xmm3
  comiss %xmm0,%xmm3
  ja     L16
  subsd  %xmm2,%xmm1
L18:
  cvtsd2ss %xmm1,%xmm1
  comiss %xmm1,%xmm3
  pxor   %xmm2,%xmm2
  movaps %xmm1,%xmm0
  cvtss2sd %xmm1,%xmm2
  jbe    L38
  xorps  D63(%rip),%xmm0
L38:
  mulss  %xmm1,%xmm0
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D0(%rip),%xmm0
  addsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nop
L16:
  addsd  %xmm2,%xmm1
  jmp    L18
```

tool_calls: name: unpack_data
arguments: tag: D56
data_type: f64
name: unpack_data
arguments: tag: D42
data_type: f64[2]
name: unpack_data
arguments: tag: D53
data_type: f64
name: unpack_data
arguments: tag: D67
data_type: f64
name: unpack_data
arguments: tag: D65
data_type: f64
name: unpack_data
arguments: tag: D63
data_type: byte[16]
name: unpack_data
arguments: tag: D0
data_type: byte[8]

tool: D56: 1.57079632

tool: {"D42": [3.14159265,6.28318531]}

tool: D53: 6.28318531

tool: D67: 0.405284735

tool: D65: 1.27323954

tool: {"D63": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D0": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xcc,0x3f]}

assistant: ```c
float cose(float x) {
  x += 1.57079632;
  if (x > 3.14159265)
    x -= 6.28318531;
  float result = 0.0;
  if (x < 0) {
    result = 1.27323954 * x + 0.405284735 * x * x;
    if (result < 0)
      result = .225 * (result * -result - result) + result;
    else
      result = .225 * (result * result - result) + result;
  } else {
    result = 1.27323954 * x - 0.405284735 * x * x;
    if (result < 0)
      result = .225 * (result * -result - result) + result;
    else
      result = .225 * (result * result - result) + result;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L12:
  cmp    %rdx,%rsp
  je     L1
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L12
L1:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L58
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L58:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L21
L36:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L21:
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L36
  mov    -0x50(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubbleSort@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x50(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D15
type: string

tool: D30: What is the size of the array?


tool: D25: %d

tool: D28: Enter elements of the array one by one


tool: D34: 
%d

tool: D15: Sorted array: 

assistant: ```c
int main() {
  int n, i;
  printf("What is the size of the array?\n");
  scanf("%d", &n);
  int a[n];
  printf("Enter elements of the array one by one\n");
  for (i = 0; i < n; i++) {
    scanf("\n%d", &a[i]);
  }
  bubbleSort(a, n);
  printf("Sorted array: ");
  print(a, n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L50:
  cmp    %rdx,%rsp
  je     L52
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L50
L52:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L48
  orq    $0x0,-0x8(%rsp,%rax,1)
L48:
  mov    %rsp,%r14
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  test   %esi,%esi
  jle    L23
  mov    %r14,%r12
  mov    $0x0,%ebx
  lea    D18(%rip),%r13
L21:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%esi
  add    $0x4,%r12
  cmp    %ebx,%esi
  jg     L21
L23:
  mov    %r14,%rdi
  call   <bubbleSort@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <print@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
datatype: string
name: retrieve_data
arguments: label: D46
datatype: string
name: retrieve_data
arguments: label: D15
datatype: string
name: retrieve_data
arguments: label: D18
datatype: string
name: retrieve_data
arguments: label: D20
datatype: string

tool: D26: What is the size of the array?


tool: D46: %d

tool: D15: Enter elements of the array one by one


tool: D18: 
%d

tool: D20: Sorted array: 

assistant: ```c
int main() {
  int n, i;
  printf("What is the size of the array?\n");
  scanf("%d", &n);
  int a[n];
  printf("Enter elements of the array one by one\n");
  for (i = 0; i < n; i++) {
    scanf("\n%d", &a[i]);
  }
  bubbleSort(a, n);
  printf("Sorted array: ");
  print(a, n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L60
L23:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L23
L60:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L46
L1:
  lea    D9(%rip),%rdi
  mov    %rsp,%r14
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  test   %esi,%esi
  jle    L4
  mov    %r14,%r12
  xor    %ebx,%ebx
  lea    D11(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  cmp    %ebx,%esi
  jg     L0
L4:
  mov    %r14,%rdi
  call   <bubbleSort@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <print@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L46:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L1
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D20
type: string
name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D28
type: string

tool: D29: What is the size of the array?


tool: D20: %d

tool: D9: Enter elements of the array one by one


tool: D11: 
%d

tool: D28: Sorted array: 

assistant: ```c
int main() {
  int n, i;
  printf("What is the size of the array?\n");
  scanf("%d", &n);
  int a[n];
  printf("Enter elements of the array one by one\n");
  for (i = 0; i < n; i++) {
    scanf("\n%d", &a[i]);
  }
  bubbleSort(a, n);
  printf("Sorted array: ");
  print(a, n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D42(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L9
L28:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L28
L9:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L57
L40:
  lea    D10(%rip),%rdi
  mov    %rsp,%r14
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  test   %esi,%esi
  jle    L29
  mov    %r14,%r12
  xor    %ebx,%ebx
  lea    D30(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  cmp    %ebx,%esi
  jg     L58
L29:
  mov    %r14,%rdi
  call   <bubbleSort@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <print@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L57:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D42
data_type: string
name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D30
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: D42: What is the size of the array?


tool: D17: %d

tool: D10: Enter elements of the array one by one


tool: D30: 
%d

tool: D14: Sorted array: 

assistant: ```c
int main() {
  int n, i;
  printf("What is the size of the array?\n");
  scanf("%d", &n);
  int a[n];
  printf("Enter elements of the array one by one\n");
  for (i = 0; i < n; i++) {
    scanf("\n%d", &a[i]);
  }
  bubbleSort(a, n);
  printf("Sorted array: ");
  print(a, n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sweep_forward>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L13
L7:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L29:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L29
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sweep_forward(int n, double *x, double **A, double *b) {
  int i, j;
  double sum;
  for (i = 0; i < n; i++) {
    sum = 0;
    for (j = 0; j < i; j++) {
      sum += A[i][j] * x[j];
    }
    x[i] = b[i] - sum;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sweep_forward>:
  endbr64
  mov    $0x8,%r8d
  mov    $0x0,%r10d
  pxor   %xmm1,%xmm1
  test   %edi,%edi
  jg     L40
  ret
L35:
  mov    (%rdx,%r8,1),%r9
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L42:
  movsd  (%r9,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L42
L30:
  add    $0x8,%r8
L40:
  movsd  -0x8(%rcx,%r8,1),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rsi,%r8,1)
  add    $0x1,%r10d
  cmp    %r10d,%edi
  je     L47
  test   %r10d,%r10d
  jg     L35
  pxor   %xmm1,%xmm1
  jmp    L30
L47:
  ret
```

assistant: ```c
void sweep_forward(int n, double *x, double **A, double *b) {
  int i, j;
  double sum;
  for (i = 0; i < n; i++) {
    sum = 0;
    for (j = 0; j < i; j++) {
      sum += A[i][j] * x[j];
    }
    x[i] = b[i] - sum;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sweep_forward>:
  endbr64
  test   %edi,%edi
  jle    L34
  pxor   %xmm2,%xmm2
  mov    $0x8,%r8d
  xor    %r10d,%r10d
  movapd %xmm2,%xmm1
  nopl   0x0(%rax)
L16:
  movsd  -0x8(%rcx,%r8,1),%xmm0
  add    $0x1,%r10d
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rsi,%r8,1)
  cmp    %r10d,%edi
  je     L31
  mov    (%rdx,%r8,1),%r9
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L15:
  movsd  (%r9,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L15
  add    $0x8,%r8
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L31:
  ret
L34:
  ret
```

assistant: ```c
void sweep_forward(int n, double *x, double **A, double *b) {
  int i, j;
  double sum;
  for (i = 0; i < n; i++) {
    sum = 0;
    for (j = 0; j < i; j++) {
      sum += A[i][j] * x[j];
    }
    x[i] = b[i] - sum;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sweep_forward>:
  endbr64
  mov    %rdx,%r11
  test   %edi,%edi
  jle    L69
  movsd  (%rcx),%xmm0
  movslq %edi,%r10
  mov    $0x1,%r8d
  pxor   %xmm3,%xmm3
  movsd  %xmm0,(%rsi)
  cmp    $0x1,%edi
  je     L14
  nopl   (%rax)
L21:
  mov    (%r11,%r8,8),%rdx
  mov    %r8d,%r9d
  cmp    $0x1,%r8
  je     L17
  mov    %r8d,%edi
  xor    %eax,%eax
  movapd %xmm3,%xmm1
  shr    %edi
  shl    $0x4,%rdi
  nopl   0x0(%rax)
L45:
  movupd (%rsi,%rax,1),%xmm0
  movupd (%rdx,%rax,1),%xmm4
  add    $0x10,%rax
  mulpd  %xmm4,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdi
  jne    L45
  mov    %r9d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r9d
  je     L40
L62:
  cltq
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
L40:
  movsd  (%rcx,%r8,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%r8,8)
  add    $0x1,%r8
  cmp    %r10,%r8
  jne    L21
  ret
L69:
  ret
L17:
  movapd %xmm3,%xmm1
  xor    %eax,%eax
  jmp    L62
L14:
  ret
```

assistant: ```c
void sweep_forward(int n, double *x, double **A, double *b) {
  int i, j;
  double sum;
  for (i = 0; i < n; i++) {
    sum = 0;
    for (j = 0; j < i; j++) {
      sum += A[i][j] * x[j];
    }
    x[i] = b[i] - sum;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<uDMAIntStatus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400ff504,%eax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long uDMAIntStatus(void) {
  ;
  ;
  ;
  ;
  return ((*((volatile unsigned long *)(0x400FF504))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uDMAIntStatus>:
  endbr64
  mov    0x400ff504,%rax
  ret
```

assistant: ```c
unsigned long uDMAIntStatus(void) {
  ;
  ;
  ;
  ;
  return ((*((volatile unsigned long *)(0x400FF504))));
}
```
user: Translate the below assembly code into C programming language:

```asm
<uDMAIntStatus>:
  endbr64
  mov    0x400ff504,%rax
  ret
```

assistant: ```c
unsigned long uDMAIntStatus(void) {
  ;
  ;
  ;
  ;
  return ((*((volatile unsigned long *)(0x400FF504))));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uDMAIntStatus>:
  endbr64
  mov    0x400ff504,%rax
  ret
```

assistant: ```c
unsigned long uDMAIntStatus(void) {
  ;
  ;
  ;
  ;
  return ((*((volatile unsigned long *)(0x400FF504))));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getsym>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <dlopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L3
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dlsym@plt>
L3:
  leave
  ret
```

assistant: ```c
void *getsym(const char *sym) {
  void *dlh = dlopen(NULL, RTLD_LAZY);
  if (!dlh) {
    return NULL;
  }
  return dlsym(dlh, sym);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getsym>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <dlopen@plt>
  test   %rax,%rax
  je     L1
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <dlsym@plt>
L1:
  pop    %rbx
  ret
```

assistant: ```c
void *getsym(const char *sym) {
  void *dlh = dlopen(NULL, RTLD_LAZY);
  if (!dlh) {
    return NULL;
  }
  return dlsym(dlh, sym);
}
```