ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find_p_indx>:
  endbr64
  cmp    $0x1,%esi
  jle    L26
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  lea    -0x2(%rsi),%r13d
  mov    $0x0,%ebx
  jmp    L42
L41:
  mov    %rax,%rbx
L42:
  mov    0x8(%rbp,%rbx,8),%rsi
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r12,%rdx
  call   <isbetween@plt>
  test   %rax,%rax
  jne    L31
  lea    0x1(%rbx),%rax
  cmp    %r13,%rbx
  jne    L41
  mov    $0x0,%eax
  jmp    L0
L31:
  lea    0x1(%rbx),%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int find_p_indx(long double **nvp, int n_nvp, long double *p) {
  int i;
  for (i = 0; i < (n_nvp - 1); i++)
    if (isbetween(nvp[i], nvp[i + 1], p))
      return i + 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_p_indx>:
  endbr64
  cmp    $0x1,%esi
  jle    L5
  push   %r13
  lea    -0x2(%rsi),%r13d
  push   %r12
  add    $0x2,%r13
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L21
L33:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    -0x8(%rbp,%rbx,8),%rdi
  mov    %r12,%rdx
  call   <isbetween@plt>
  mov    %ebx,%r8d
  test   %rax,%rax
  je     L35
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L21:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int find_p_indx(long double **nvp, int n_nvp, long double *p) {
  int i;
  for (i = 0; i < (n_nvp - 1); i++)
    if (isbetween(nvp[i], nvp[i + 1], p))
      return i + 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_p_indx>:
  endbr64
  cmp    $0x1,%esi
  jle    L30
  push   %r13
  lea    -0x2(%rsi),%r13d
  push   %r12
  add    $0x2,%r13
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L15
L11:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    -0x8(%rbp,%rbx,8),%rdi
  mov    %r12,%rdx
  call   <isbetween@plt>
  mov    %ebx,%r8d
  test   %rax,%rax
  je     L13
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  xor    %eax,%eax
  ret
```

assistant: ```c
int find_p_indx(long double **nvp, int n_nvp, long double *p) {
  int i;
  for (i = 0; i < (n_nvp - 1); i++)
    if (isbetween(nvp[i], nvp[i + 1], p))
      return i + 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<QuickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L48
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L27:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L27
L8:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L8
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L30
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L27
L30:
  nop
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <QuickSort>
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <QuickSort>
L48:
  nop
  leave
  ret
```

assistant: ```c
void QuickSort(int a[], int m, int n) {
  int i, j, v, x;
  if (n > m) {
    i = m - 1;
    j = n;
    v = a[n];
    while (1) {
      do {
        ++i;
      } while (a[i] < v);
      do {
        --j;
      } while (a[j] > v);
      if (i >= j)
        break;
      x = a[i];
      a[i] = a[j];
      a[j] = x;
    }
    x = a[i];
    a[i] = a[n];
    a[n] = x;
    QuickSort(a, m, j);
    QuickSort(a, i + 1, n);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<QuickSort>:
  endbr64
  cmp    %esi,%edx
  jle    L1
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  lea    -0x1(%rsi),%ebx
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r14
  mov    (%r14),%esi
  movslq %ebx,%rax
  lea    0x4(%rdi,%rax,4),%r8
  jmp    L45
L48:
  add    $0x4,%r8
  mov    %r10d,%ebx
L45:
  lea    0x1(%rbx),%r10d
  mov    %r8,%r11
  mov    (%r8),%r9d
  cmp    %esi,%r9d
  jl     L48
  movslq %edx,%rax
  lea    -0x4(%rbp,%rax,4),%rax
L31:
  sub    $0x1,%edx
  mov    %rax,%rdi
  sub    $0x4,%rax
  mov    0x4(%rax),%ecx
  cmp    %esi,%ecx
  jg     L31
  cmp    %edx,%r10d
  jge    L17
  mov    %ecx,(%r11)
  mov    %r9d,(%rdi)
  jmp    L48
L17:
  mov    (%r14),%eax
  mov    %eax,(%r11)
  mov    %r9d,(%r14)
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <QuickSort>
  lea    0x2(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <QuickSort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  ret
```

assistant: ```c
void QuickSort(int a[], int m, int n) {
  int i, j, v, x;
  if (n > m) {
    i = m - 1;
    j = n;
    v = a[n];
    while (1) {
      do {
        ++i;
      } while (a[i] < v);
      do {
        --j;
      } while (a[j] > v);
      if (i >= j)
        break;
      x = a[i];
      a[i] = a[j];
      a[j] = x;
    }
    x = a[i];
    a[i] = a[n];
    a[n] = x;
    QuickSort(a, m, j);
    QuickSort(a, i + 1, n);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<QuickSort>:
  endbr64
  cmp    %edx,%esi
  jge    L58
  push   %r13
  movslq %edx,%rax
  mov    %rdi,%r13
  mov    %esi,%r11d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  sub    $0x8,%rsp
L37:
  movslq %r11d,%rax
  mov    0x0(%rbp),%esi
  lea    -0x1(%r11),%ebx
  mov    %r12d,%edx
  lea    0x0(%r13,%rax,4),%r8
  nopl   0x0(%rax,%rax,1)
L24:
  mov    (%r8),%r9d
  lea    0x1(%rbx),%r10d
  cmp    %esi,%r9d
  jl     L19
  movslq %edx,%rax
  lea    -0x4(%r13,%rax,4),%rax
  nopl   0x0(%rax)
L55:
  mov    %rax,%rdi
  mov    (%rax),%ecx
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %esi,%ecx
  jg     L55
  cmp    %edx,%r10d
  jge    L46
  mov    %ecx,(%r8)
  mov    %r9d,(%rdi)
L19:
  add    $0x4,%r8
  mov    %r10d,%ebx
  jmp    L24
  nopl   0x0(%rax)
L46:
  mov    0x0(%rbp),%eax
  mov    %r11d,%esi
  mov    %r13,%rdi
  mov    %eax,(%r8)
  mov    %r9d,0x0(%rbp)
  call   <QuickSort>
  lea    0x2(%rbx),%r11d
  cmp    %r12d,%r11d
  jl     L37
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  ret
```

assistant: ```c
void QuickSort(int a[], int m, int n) {
  int i, j, v, x;
  if (n > m) {
    i = m - 1;
    j = n;
    v = a[n];
    while (1) {
      do {
        ++i;
      } while (a[i] < v);
      do {
        --j;
      } while (a[j] > v);
      if (i >= j)
        break;
      x = a[i];
      a[i] = a[j];
      a[j] = x;
    }
    x = a[i];
    a[i] = a[n];
    a[n] = x;
    QuickSort(a, m, j);
    QuickSort(a, i + 1, n);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  imul   %ecx,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D24
type_infered: string
name: disassemble_data
arguments: tag: D8
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string

tool: D24: 
 Vavedi a:

tool: D8: %d

tool: D15: %d
%d

assistant: ```c
int main() {
  int a;
  printf("\n Vavedi a:");
  scanf("%d", &a);
  printf("%d\n%d", a * a, a * a * a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D25
datatype: string

tool: D23: 
 Vavedi a:

tool: D14: %d

tool: D25: %d
%d

assistant: ```c
int main() {
  int a;
  printf("\n Vavedi a:");
  scanf("%d", &a);
  printf("%d\n%d", a * a, a * a * a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D6
type: string

tool: D11: 
 Vavedi a:

tool: D26: %d

tool: D6: %d
%d

assistant: ```c
int main() {
  int a;
  printf("\n Vavedi a:");
  scanf("%d", &a);
  printf("%d\n%d", a * a, a * a * a);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D6
datatype: string
name: extract_symbolic_data
arguments: data_label: D10
datatype: string

tool: D11: 
 Vavedi a:

tool: D6: %d

tool: D10: %d
%d

assistant: ```c
int main() {
  int a;
  printf("\n Vavedi a:");
  scanf("%d", &a);
  printf("%d\n%d", a * a, a * a * a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<concat_rpn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L9
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L9:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5:  

assistant: ```c
void concat_rpn(char *str, char *exp) {
  if (strlen(str) > 0)
    strcat(str, " ");
  strncat(str, exp, strlen(exp));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<concat_rpn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  test   %rax,%rax
  jg     L18
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3:  

assistant: ```c
void concat_rpn(char *str, char *exp) {
  if (strlen(str) > 0)
    strcat(str, " ");
  strncat(str, exp, strlen(exp));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat_rpn>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  jne    L1
L14:
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  pop    %rbp
  pop    %r12
  jmp    1080 <strncat@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2:  

assistant: ```c
void concat_rpn(char *str, char *exp) {
  if (strlen(str) > 0)
    strcat(str, " ");
  strncat(str, exp, strlen(exp));
}
```
user: Translate the below assembly code into C programming language:

```asm
<concat_rpn>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  jne    L7
L15:
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  pop    %rbp
  pop    %r12
  jmp    1080 <strncat@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3:  

assistant: ```c
void concat_rpn(char *str, char *exp) {
  if (strlen(str) > 0)
    strcat(str, " ");
  strncat(str, exp, strlen(exp));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xor160>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D103(%rip),%eax
  lea    0x0(,%rax,4),%edx
  mov    D103(%rip),%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    D115(%rip),%eax
  mov    %eax,D82(%rip)
  mov    D82(%rip),%eax
  mov    %eax,D10(%rip)
  mov    D10(%rip),%eax
  mov    %eax,D106(%rip)
  mov    D106(%rip),%eax
  mov    %eax,D87(%rip)
  mov    D106(%rip),%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    D106(%rip),%eax
  xor    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    %eax
  xor    -0x4(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,D87(%rip)
  mov    D87(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t xor160() {
  static uint32_t x = 123456789, y = 362436069, z = 521288629, w = 88675123, v = 5783321;
  uint32_t t = (x ^ (x << 2));
  x = y;
  y = z;
  z = w;
  w = v;
  return v = (v ^ (v >> 4)) ^ (t ^ (t >> 1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xor160>:
  endbr64
  mov    D18(%rip),%eax
  lea    0x0(,%rax,4),%edx
  xor    %eax,%edx
  mov    D24(%rip),%eax
  mov    %eax,D31(%rip)
  mov    D31(%rip),%eax
  mov    %eax,D16(%rip)
  mov    D16(%rip),%eax
  mov    %eax,D30(%rip)
  mov    D30(%rip),%ecx
  mov    %ecx,D22(%rip)
  mov    %ecx,%eax
  sar    $0x4,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  sar    %edx
  xor    %edx,%eax
  mov    %eax,D22(%rip)
  ret
```

assistant: ```c
uint32_t xor160() {
  static uint32_t x = 123456789, y = 362436069, z = 521288629, w = 88675123, v = 5783321;
  uint32_t t = (x ^ (x << 2));
  x = y;
  y = z;
  z = w;
  w = v;
  return v = (v ^ (v >> 4)) ^ (t ^ (t >> 1));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xor160>:
  endbr64
  mov    D70(%rip),%eax
  mov    D43(%rip),%ecx
  lea    0x0(,%rax,4),%edx
  xor    %eax,%edx
  mov    D99(%rip),%eax
  mov    %eax,D0(%rip)
  mov    D0(%rip),%eax
  mov    %eax,D88(%rip)
  mov    D88(%rip),%eax
  mov    %ecx,D79(%rip)
  mov    %eax,D79(%rip)
  mov    %ecx,%eax
  sar    $0x4,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  sar    %edx
  xor    %edx,%eax
  mov    %eax,D79(%rip)
  ret
```

assistant: ```c
uint32_t xor160() {
  static uint32_t x = 123456789, y = 362436069, z = 521288629, w = 88675123, v = 5783321;
  uint32_t t = (x ^ (x << 2));
  x = y;
  y = z;
  z = w;
  w = v;
  return v = (v ^ (v >> 4)) ^ (t ^ (t >> 1));
}
```
user: What is the c source code of the assembly code below:

```asm
<xor160>:
  endbr64
  mov    D26(%rip),%eax
  mov    D51(%rip),%ecx
  lea    0x0(,%rax,4),%edx
  xor    %eax,%edx
  mov    D17(%rip),%eax
  mov    %eax,D9(%rip)
  mov    D9(%rip),%eax
  mov    %eax,D52(%rip)
  mov    D52(%rip),%eax
  mov    %ecx,D21(%rip)
  mov    %eax,D21(%rip)
  mov    %ecx,%eax
  sar    $0x4,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  sar    %edx
  xor    %edx,%eax
  mov    %eax,D21(%rip)
  ret
```

assistant: ```c
uint32_t xor160() {
  static uint32_t x = 123456789, y = 362436069, z = 521288629, w = 88675123, v = 5783321;
  uint32_t t = (x ^ (x << 2));
  x = y;
  y = z;
  z = w;
  w = v;
  return v = (v ^ (v >> 4)) ^ (t ^ (t >> 1));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getNonBlank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getTexChar@plt>
  mov    %al,-0x1(%rbp)
  jmp    L21
L28:
  mov    $0x0,%eax
  call   <getTexChar@plt>
  mov    %al,-0x1(%rbp)
L21:
  cmpb   $0x20,-0x1(%rbp)
  je     L28
  cmpb   $0xa,-0x1(%rbp)
  je     L28
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char getNonBlank(void) {
  char c;
  c = getTexChar();
  while (c == ' ' || c == '\n') {
    c = getTexChar();
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getNonBlank>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getTexChar@plt>
  cmp    $0x20,%al
  je     L3
  cmp    $0xa,%al
  jne    L21
L3:
  mov    $0x0,%eax
  call   <getTexChar@plt>
  cmp    $0x20,%al
  je     L3
  cmp    $0xa,%al
  je     L3
L21:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char getNonBlank(void) {
  char c;
  c = getTexChar();
  while (c == ' ' || c == '\n') {
    c = getTexChar();
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getNonBlank>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  call   <getTexChar@plt>
  cmp    $0x20,%al
  je     L18
  cmp    $0xa,%al
  je     L18
  add    $0x8,%rsp
  ret
```

assistant: ```c
char getNonBlank(void) {
  char c;
  c = getTexChar();
  while (c == ' ' || c == '\n') {
    c = getTexChar();
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getNonBlank>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <getTexChar@plt>
  cmp    $0x20,%al
  je     L13
  cmp    $0xa,%al
  je     L13
  add    $0x8,%rsp
  ret
```

assistant: ```c
char getNonBlank(void) {
  char c;
  c = getTexChar();
  while (c == ' ' || c == '\n') {
    c = getTexChar();
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  struct shmid_ds ds = {};
  (void)ds;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  struct shmid_ds ds = {};
  (void)ds;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  struct shmid_ds ds = {};
  (void)ds;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  struct shmid_ds ds = {};
  (void)ds;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test12>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test12() {
  switch (1) {
  case 2: {
    int a;
    a = 42;
  }
  case 1:
    break;
  case 42:;
    int x;
    x = 4;
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test12>:
  endbr64
  ret
```

assistant: ```c
void test12() {
  switch (1) {
  case 2: {
    int a;
    a = 42;
  }
  case 1:
    break;
  case 42:;
    int x;
    x = 4;
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test12>:
  endbr64
  ret
```

assistant: ```c
void test12() {
  switch (1) {
  case 2: {
    int a;
    a = 42;
  }
  case 1:
    break;
  case 42:;
    int x;
    x = 4;
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test12>:
  endbr64
  ret
```

assistant: ```c
void test12() {
  switch (1) {
  case 2: {
    int a;
    a = 42;
  }
  case 1:
    break;
  case 42:;
    int x;
    x = 4;
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FATAL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <REPORT@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  leave
  ret
```

assistant: ```c
void FATAL(const char *x) {
  REPORT(x);
  abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<FATAL>:
  endbr64
  sub    $0x8,%rsp
  call   <REPORT@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void FATAL(const char *x) {
  REPORT(x);
  abort();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<FATAL>:
  endbr64
  sub    $0x8,%rsp
  call   <REPORT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

assistant: ```c
void FATAL(const char *x) {
  REPORT(x);
  abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<FATAL>:
  endbr64
  sub    $0x8,%rsp
  call   <REPORT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

assistant: ```c
void FATAL(const char *x) {
  REPORT(x);
  abort();
}
```