user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L164
  lea    0x10(%rsp),%r13
  mov    %r13,%r14
  mov    $0x0,%r12d
  lea    D0(%rip),%r15
L178:
  mov    %r14,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    0x8(%rsp),%r9d
  add    $0x14,%r14
  cmp    %r12d,%r9d
  jg     L178
  test   %r9d,%r9d
  jle    L35
  mov    0xc(%rsp),%edi
  mov    $0x0,%r10d
  mov    $0x0,%r11d
  mov    $0x0,%r8d
  sub    $0x1,%r13
  jmp    L85
L59:
  cmp    $0x47,%r14b
  sete   %r14b
  movzbl %r14b,%r14d
  add    %r14d,%eax
  sub    $0x14,%rdx
L58:
  movzbl (%rdx),%r14d
  cmp    $0x23,%r14b
  jne    L59
  lea    0x15(%rcx),%r14
  jmp    L170
L171:
  cmp    $0x47,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  add    $0x14,%r14
L170:
  movzbl (%r14),%edx
  cmp    $0x23,%dl
  jne    L171
  lea    0x2(%rcx),%r14
  jmp    L24
L80:
  cmp    $0x47,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  add    $0x1,%r14
L24:
  movzbl (%r14),%edx
  cmp    $0x23,%dl
  jne    L80
  mov    %rcx,%r14
  jmp    L34
L26:
  cmp    $0x47,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  sub    $0x1,%r14
L34:
  movzbl (%r14),%edx
  cmp    $0x23,%dl
  jne    L26
  cmp    %r11d,%eax
  jle    L106
  mov    %esi,%ebp
  mov    %r12d,%ebx
  mov    %eax,%r11d
L106:
  add    $0x1,%esi
  add    $0x1,%rcx
  cmp    %edi,%esi
  je     L73
L173:
  lea    -0x13(%rcx),%rdx
  mov    $0x0,%eax
  cmpb   $0x2e,0x1(%rcx)
  jne    L106
  jmp    L58
L73:
  add    $0x1,%r8d
  add    $0x14,%r10
  cmp    %r8d,%r9d
  je     L128
L85:
  lea    0x0(%r13,%r10,1),%rcx
  mov    $0x0,%esi
  mov    %r8d,%r12d
  test   %edi,%edi
  jg     L173
  jmp    L73
L164:
  mov    $0x0,%r11d
L128:
  mov    %r11d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L123
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    $0x0,%r11d
  jmp    L128
L123:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D12
datatype: string

tool: D8: %d %d

tool: D0: %s

tool: D12: please set bomb on(%d,%d),elimate %d enemy


assistant: ```c
int main() {
  char a[20][20];
  int i, j, sum, map = 0, p, q, x, y, n, m;
  scanf("%d %d", &n, &m);
  for (i = 0; i <= n - 1; i++)
    scanf("%s", a[i]);
  for (i = 0; i <= n - 1; i++) {
    for (j = 0; j <= m - 1; j++) {
      if (a[i][j] == '.') {
        sum = 0;
        x = i;
        y = j;
        while (a[x][y] != '#') {
          if (a[x][y] == 'G')
            sum++;
          x = x - 1;
        }
        x = i;
        y = j;
        while (a[x][y] != '#') {
          if (a[x][y] == 'G')
            sum++;
          x = x + 1;
        }
        x = i;
        y = j;
        while (a[x][y] != '#') {
          if (a[x][y] == 'G')
            sum++;
          y = y + 1;
        }
        x = i;
        y = j;
        while (a[x][y] != '#') {
          if (a[x][y] == 'G')
            sum++;
          y = y - 1;
        }
        if (sum > map) {
          map = sum;
          p = i;
          q = j;
        }
      }
    }
  }
  printf("please set bomb on(%d,%d),elimate %d enemy\n", p, q, map);
  return 0;
}
```