user: 这段汇编代码用C语言表示是什么样的？

```asm
<kthSmallest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %esi,-0x44(%rbp)
  mov    %edx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L131
  mov    %edx,%eax
  mov    %ecx,%r12d
  sub    %esi,%eax
  lea    0x1(%rax),%ebx
  mov    %ebx,-0x4c(%rbp)
  cmp    %ecx,%ebx
  jl     L131
  lea    0x5(%rax),%edx
  mov    %rsp,%rcx
  mov    %rsp,-0x58(%rbp)
  mov    %rdi,%r14
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sub    %edx,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L144
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L38
L144:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L51
  orq    $0x0,-0x8(%rsp,%rdx,1)
L51:
  movslq -0x4c(%rbp),%rsi
  lea    0x3(%rsp),%r15
  mov    %r15,%rax
  mov    %r15,%rdi
  imul   $0x66666667,%rsi,%rbx
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%rdi
  mov    %rsi,-0x70(%rbp)
  mov    %rax,-0x68(%rbp)
  mov    %rsi,%rax
  sar    $0x1f,%eax
  mov    %rdi,-0x60(%rbp)
  sar    $0x21,%rbx
  sub    %eax,%ebx
  cmp    $0x4,%esi
  jle    L134
  mov    -0x44(%rbp),%r15d
  mov    %r12d,-0x50(%rbp)
  xor    %r13d,%r13d
  mov    %r15d,%r12d
  mov    %rdi,%r15
  nop
L58:
  lea    0x4(%r12),%edx
  mov    %r12d,%esi
  mov    $0x5,%ecx
  mov    %r14,%rdi
  call   <findMedian@plt>
  add    $0x5,%r12d
  mov    %eax,(%r15,%r13,4)
  add    $0x1,%r13
  cmp    %r13d,%ebx
  jg     L58
  mov    -0x4c(%rbp),%edi
  test   %ebx,%ebx
  mov    $0x1,%r8d
  lea    (%rbx,%rbx,4),%eax
  cmovg  %ebx,%r8d
  mov    $0x5,%edx
  mov    -0x50(%rbp),%r12d
  cmp    $0x4,%edi
  cmovle %edx,%eax
  cmp    %eax,%edi
  jg     L18
L49:
  cmp    $0x1,%r8d
  jne    L129
  mov    -0x68(%rbp),%rax
  mov    0x0(,%rax,4),%ecx
L16:
  mov    -0x44(%rbp),%ebx
  mov    -0x48(%rbp),%edx
  mov    %r14,%rdi
  mov    %ebx,%esi
  call   <partition@plt>
  lea    -0x1(%r12),%ecx
  mov    %eax,%edx
  sub    %ebx,%edx
  cmp    %ecx,%edx
  je     L9
  cmp    %r12d,%edx
  jl     L114
  mov    -0x44(%rbp),%esi
  lea    -0x1(%rax),%edx
  mov    %r12d,%ecx
  mov    %r14,%rdi
  call   <kthSmallest>
L44:
  mov    -0x58(%rbp),%rsp
  jmp    L32
  nopl   0x0(%rax)
L131:
  mov    $0xf,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  sub    $0x1,%eax
L32:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L157
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L129:
  mov    %r8d,%ecx
  mov    -0x60(%rbp),%rdi
  lea    -0x1(%r8),%edx
  xor    %esi,%esi
  sar    %ecx
  call   <kthSmallest>
  mov    %eax,%ecx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L114:
  mov    -0x44(%rbp),%edi
  sub    %eax,%r12d
  mov    -0x48(%rbp),%edx
  lea    0x1(%rax),%esi
  lea    -0x1(%rdi,%r12,1),%ecx
  mov    %r14,%rdi
  call   <kthSmallest>
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r8d
  lea    (%r8,%r8,4),%esi
L17:
  mov    -0x4c(%rbp),%edi
  imul   $0x66666667,-0x70(%rbp),%rax
  mov    %r8d,-0x50(%rbp)
  add    -0x44(%rbp),%esi
  mov    %edi,%edx
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  mov    -0x48(%rbp),%edx
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edi
  mov    %edi,%ecx
  mov    %r14,%rdi
  call   <findMedian@plt>
  mov    -0x60(%rbp),%rdi
  mov    %eax,%r10d
  movslq -0x50(%rbp),%rax
  mov    %r10d,(%rdi,%rax,4)
  mov    %rax,%r8
  jmp    L49
  xchg   %ax,%ax
L9:
  cltq
  mov    (%r14,%rax,4),%eax
  jmp    L44
L134:
  mov    $0x5,%esi
  mov    $0x1,%r8d
  jmp    L17
L157:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kthSmallest(int arr[], int l, int r, int k) {
  if (k > 0 && k <= r - l + 1) {
    int n = r - l + 1;
    int i, median[(n + 4) / 5];
    for (i = 0; i < n / 5; i++)
      median[i] = findMedian(arr, l + i * 5, 5 * (i + 1) - n + r, 5);
    if (i * 5 < n) {
      i++;
      median[i] = findMedian(arr, l + i * 5, r, n % 5);
    }
    int medOfMed = (i == 1) ? median[i - 1] : kthSmallest(median, 0, i - 1, i / 2);
    int pos = partition(arr, l, r, medOfMed);
    if (pos - l == k - 1)
      return arr[pos];
    if (pos - l > k - 1)
      return kthSmallest(arr, l, pos - 1, k);
    return kthSmallest(arr, pos + 1, r, k - pos + l - 1);
  }
  return pow(2, 15) - 1;
}
```