ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<get_2d_mem_char>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %esi,%ebx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L64
L35:
  test   %ebp,%ebp
  jle    L37
  mov    %r12,%r14
  lea    (%r12,%rbp,8),%rbp
  lea    D3(%rip),%r13
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x8,%r14
  cmp    %rbp,%r14
  je     L37
L56:
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L1
  mov    %r13,%rdi
  add    $0x8,%r14
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  cmp    %rbp,%r14
  jne    L56
L37:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L64:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L35
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: Cannot allocate memory in get_2d_mem_char


assistant: ```c
char **get_2d_mem_char(int dim1, int dim2) {
  char **array_2d;
  int k;
  if (!(array_2d = (char **)calloc(dim1, sizeof(char *)))) {
    printf("Cannot allocate memory in get_2d_mem_char\n");
    exit(1);
  }
  for (k = 0; k < dim1; k++) {
    if (!(array_2d[k] = (char *)calloc(dim2, sizeof(char)))) {
      printf("Cannot allocate memory in get_2d_mem_char\n");
      exit(1);
    }
  }
  return array_2d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<edit_distance>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rax,0x30(%rsp)
  mov    %eax,%ebp
  mov    %eax,0x1c(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,0x38(%rsp)
  mov    %eax,%r12d
  lea    0x8(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  mov    $0x0,%ebx
  lea    0x1(%r12),%r14d
  mov    %r12d,(%rsp)
  mov    %ebp,%r12d
  mov    %rax,%r15
L11:
  mov    %ebx,%eax
  lea    (%r15,%rax,8),%rbp
  mov    $0x4,%esi
  mov    %r14d,%edi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jae    L11
  mov    (%rsp),%r12d
  mov    0x30(%rsp),%ecx
  mov    $0x0,%eax
  mov    0x10(%rsp),%rsi
L36:
  mov    (%rsi,%rax,8),%rdx
  mov    %eax,(%rdx)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L36
  mov    $0x0,%eax
  mov    0x10(%rsp),%rsi
L78:
  mov    %eax,%ecx
  mov    (%rsi),%rdx
  mov    %eax,(%rdx,%rcx,4)
  add    $0x1,%eax
  cmp    %eax,%r12d
  jae    L78
  mov    0x38(%rsp),%rax
  test   %eax,%eax
  je     L46
  mov    %r13,%rbp
  lea    -0x1(%rax),%eax
  lea    0x1(%r13,%rax,1),%rax
  mov    %rax,0x28(%rsp)
  mov    0x30(%rsp),%rax
  lea    -0x1(%rax),%eax
  mov    0x10(%rsp),%rcx
  lea    0x8(%rcx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r13d
  jmp    L20
L15:
  mov    (%rbx),%rax
  mov    (%rax,%r13,1),%eax
  mov    %rax,(%rsp)
  movsbl 0x0(%rbp),%esi
  movsbl (%r12),%edi
  call   <delta@plt>
  mov    %rax,%rdx
  mov    0x8(%rbx),%rax
  lea    (%rax,%r14,1),%r15
  add    (%rsp),%rdx
  mov    (%rax,%r13,1),%esi
  add    $0x1,%esi
  mov    (%rbx),%rax
  mov    (%rax,%r14,1),%edi
  add    $0x1,%edi
  call   <minimo@plt>
  mov    %eax,(%r15)
  add    $0x8,%rbx
  add    $0x1,%r12
  cmp    %rbx,0x8(%rsp)
  jne    L15
L38:
  add    $0x4,%r13
  add    $0x1,%rbp
  cmp    0x28(%rsp),%rbp
  je     L46
L20:
  lea    0x4(%r13),%r14
  mov    0x20(%rsp),%r12
  mov    0x10(%rsp),%rbx
  cmpl   $0x0,0x1c(%rsp)
  jne    L15
  jmp    L38
L46:
  mov    0x30(%rsp),%eax
  mov    0x38(%rsp),%edx
  mov    0x10(%rsp),%rcx
  mov    (%rcx,%rax,8),%rax
  mov    (%rax,%rdx,4),%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned int edit_distance(const char *p1, const char *p2) {
  unsigned int i, j, m = (unsigned int)strlen(p1), n = (unsigned int)strlen(p2), **C;
  C = malloc((1 + m) * sizeof(unsigned int *));
  for (i = 0; i <= m; i++)
    C[i] = calloc(1 + n, sizeof(unsigned int));
  for (i = 0; i <= m; i++)
    C[i][0] = i;
  for (i = 0; i <= n; i++)
    C[0][i] = i;
  for (j = 1; j <= n; j++)
    for (i = 1; i <= m; i++)
      C[i][j] = minimo(C[i - 1][j] + 1, C[i][j - 1] + 1, C[i - 1][j - 1] + delta(p1[i - 1], p2[j - 1]));
  return C[m][n];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<edit_distance>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x20(%rsp)
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  mov    %eax,0x1c(%rsp)
  mov    %eax,%r15d
  call   <strlen@plt>
  lea    0x8(,%r12,8),%edi
  mov    %rax,%r14
  mov    %eax,%ebx
  mov    %rax,0x30(%rsp)
  call   <malloc@plt>
  mov    %r12,0x8(%rsp)
  lea    0x1(%r14),%ebp
  xor    %r14d,%r14d
  mov    %rax,0x10(%rsp)
  mov    %ebx,(%rsp)
  mov    %r14d,%ebx
  mov    %ebp,%r14d
  mov    %rax,%rbp
  nopl   (%rax)
L36:
  mov    %ebx,%eax
  mov    $0x4,%esi
  mov    %r14d,%edi
  add    $0x1,%ebx
  lea    0x0(%rbp,%rax,8),%r12
  call   <calloc@plt>
  mov    %rax,(%r12)
  cmp    %ebx,%r15d
  jae    L36
  mov    0x8(%rsp),%r12
  mov    (%rsp),%ebx
  xor    %eax,%eax
  mov    0x10(%rsp),%rcx
  mov    %r12d,%esi
  mov    %rsi,0x38(%rsp)
  nop
L28:
  mov    (%rcx,%rax,8),%rdx
  mov    %eax,(%rdx)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rsi
  jne    L28
  mov    0x10(%rsp),%rax
  mov    (%rax),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  mov    %eax,%edx
  mov    %eax,(%rcx,%rdx,4)
  add    $0x1,%eax
  cmp    %eax,%ebx
  jae    L8
  mov    0x30(%rsp),%rax
  test   %eax,%eax
  je     L55
  sub    $0x1,%eax
  mov    0x10(%rsp),%rcx
  mov    %r13,(%rsp)
  xor    %ebx,%ebx
  lea    0x1(%r13,%rax,1),%rax
  mov    %rax,0x28(%rsp)
  lea    -0x1(%r12),%eax
  lea    0x8(%rcx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
L68:
  mov    0x20(%rsp),%r14
  mov    0x1c(%rsp),%eax
  lea    0x4(%rbx),%rbp
  mov    0x10(%rsp),%r15
  mov    %r14,%r13
  test   %eax,%eax
  je     L69
  nopl   0x0(%rax)
L18:
  mov    (%r15),%rax
  movsbl 0x0(%r13),%edi
  add    $0x8,%r15
  add    $0x1,%r13
  mov    (%rax,%rbx,1),%r14d
  mov    (%rsp),%rax
  movsbl (%rax),%esi
  call   <delta@plt>
  mov    %rax,%r9
  mov    (%r15),%rax
  lea    (%r14,%r9,1),%rdx
  mov    (%rax,%rbx,1),%esi
  lea    (%rax,%rbp,1),%r12
  mov    -0x8(%r15),%rax
  mov    (%rax,%rbp,1),%edi
  add    $0x1,%esi
  add    $0x1,%edi
  call   <minimo@plt>
  mov    %eax,(%r12)
  cmp    0x8(%rsp),%r15
  jne    L18
L69:
  addq   $0x1,(%rsp)
  mov    %rbp,%rbx
  mov    (%rsp),%rax
  cmp    %rax,0x28(%rsp)
  jne    L68
L55:
  mov    0x38(%rsp),%rbx
  mov    0x10(%rsp),%rcx
  mov    0x30(%rsp),%eax
  mov    (%rcx,%rbx,8),%rdx
  mov    (%rdx,%rax,4),%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned int edit_distance(const char *p1, const char *p2) {
  unsigned int i, j, m = (unsigned int)strlen(p1), n = (unsigned int)strlen(p2), **C;
  C = malloc((1 + m) * sizeof(unsigned int *));
  for (i = 0; i <= m; i++)
    C[i] = calloc(1 + n, sizeof(unsigned int));
  for (i = 0; i <= m; i++)
    C[i][0] = i;
  for (i = 0; i <= n; i++)
    C[0][i] = i;
  for (j = 1; j <= n; j++)
    for (i = 1; i <= m; i++)
      C[i][j] = minimo(C[i - 1][j] + 1, C[i][j - 1] + 1, C[i - 1][j - 1] + delta(p1[i - 1], p2[j - 1]));
  return C[m][n];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L11:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void initialize(char *arr, int length) {
  int i;
  for (i = 0; i < length; i++) {
    arr[i] = length - i;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<initialize>:
  endbr64
  test   %esi,%esi
  jle    L11
  mov    %esi,%ecx
  mov    $0x0,%eax
L0:
  mov    %esi,%edx
  sub    %eax,%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L0
L11:
  ret
```

assistant: ```c
void initialize(char *arr, int length) {
  int i;
  for (i = 0; i < length; i++) {
    arr[i] = length - i;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<initialize>:
  endbr64
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  add    %edi,%esi
  lea    0x1(%rdi,%rax,1),%rdx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %esi,%eax
  sub    %edi,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rdx,%rdi
  jne    L13
L4:
  ret
```

assistant: ```c
void initialize(char *arr, int length) {
  int i;
  for (i = 0; i < length; i++) {
    arr[i] = length - i;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mixedSignedness5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x80000000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  setb   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  mov    -0x14(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  setb   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  mov    -0x14(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  setb   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  nop
  leave
  ret
```

assistant: ```c
void mixedSignedness5(unsigned a) {
  int min = (-((~0U) & ((~0U) >> 1)) - 1);
  clang_analyzer_eval(a < min);
  clang_analyzer_eval((a + 2) < min);
  clang_analyzer_eval((a + 2U) < min);
}
```
user: What is the c source code of the assembly code below:

```asm
<mixedSignedness5>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <clang_analyzer_eval@plt>
  add    $0x2,%ebx
  not    %ebx
  shr    $0x1f,%ebx
  mov    %ebx,%edi
  call   <clang_analyzer_eval@plt>
  mov    %ebx,%edi
  call   <clang_analyzer_eval@plt>
  pop    %rbx
  ret
```

assistant: ```c
void mixedSignedness5(unsigned a) {
  int min = (-((~0U) & ((~0U) >> 1)) - 1);
  clang_analyzer_eval(a < min);
  clang_analyzer_eval((a + 2) < min);
  clang_analyzer_eval((a + 2U) < min);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mixedSignedness5>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  not    %edi
  add    $0x2,%ebp
  shr    $0x1f,%edi
  not    %ebp
  call   <clang_analyzer_eval@plt>
  shr    $0x1f,%ebp
  mov    %ebp,%edi
  call   <clang_analyzer_eval@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1050 <clang_analyzer_eval@plt>
```

assistant: ```c
void mixedSignedness5(unsigned a) {
  int min = (-((~0U) & ((~0U) >> 1)) - 1);
  clang_analyzer_eval(a < min);
  clang_analyzer_eval((a + 2) < min);
  clang_analyzer_eval((a + 2U) < min);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mixedSignedness5>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  not    %edi
  add    $0x2,%ebp
  shr    $0x1f,%edi
  not    %ebp
  call   <clang_analyzer_eval@plt>
  shr    $0x1f,%ebp
  mov    %ebp,%edi
  call   <clang_analyzer_eval@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1050 <clang_analyzer_eval@plt>
```

assistant: ```c
void mixedSignedness5(unsigned a) {
  int min = (-((~0U) & ((~0U) >> 1)) - 1);
  clang_analyzer_eval(a < min);
  clang_analyzer_eval((a + 2) < min);
  clang_analyzer_eval((a + 2U) < min);
}
```
user: What is the c source code of the assembly code below:

```asm
<bam_swap_endian_4p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <bam_swap_endian_4@plt>
  mov    -0x8(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *bam_swap_endian_4p(void *x) {
  *(uint32_t *)x = bam_swap_endian_4(*(uint32_t *)x);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bam_swap_endian_4p>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  call   <bam_swap_endian_4@plt>
  mov    %eax,(%rbx)
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *bam_swap_endian_4p(void *x) {
  *(uint32_t *)x = bam_swap_endian_4(*(uint32_t *)x);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bam_swap_endian_4p>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    (%rdi),%edi
  call   <bam_swap_endian_4@plt>
  mov    %eax,(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *bam_swap_endian_4p(void *x) {
  *(uint32_t *)x = bam_swap_endian_4(*(uint32_t *)x);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bam_swap_endian_4p>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    (%rdi),%edi
  call   <bam_swap_endian_4@plt>
  mov    %eax,(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *bam_swap_endian_4p(void *x) {
  *(uint32_t *)x = bam_swap_endian_4(*(uint32_t *)x);
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<PSItoMB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: f64

tool: D7: 68.9476

assistant: ```c
double PSItoMB(double PSI) {
  double MB = 68.9476 * PSI;
  return MB;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PSItoMB>:
  endbr64
  mulsd  D5(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: f64

tool: D5: 68.9476

assistant: ```c
double PSItoMB(double PSI) {
  double MB = 68.9476 * PSI;
  return MB;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PSItoMB>:
  endbr64
  mulsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: f64

tool: D0: 68.9476

assistant: ```c
double PSItoMB(double PSI) {
  double MB = 68.9476 * PSI;
  return MB;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PSItoMB>:
  endbr64
  mulsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: f64

tool: D4: 68.9476

assistant: ```c
double PSItoMB(double PSI) {
  double MB = 68.9476 * PSI;
  return MB;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<synth_ntom_mono>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %rdx,-0x448(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    %rax,-0x418(%rbp)
  movl   $0x0,-0x424(%rbp)
  lea    -0x424(%rbp),%rcx
  lea    -0x410(%rbp),%rdx
  mov    -0x438(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <synth_ntom@plt>
  mov    %eax,-0x41c(%rbp)
  mov    -0x448(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    %rax,-0x440(%rbp)
  movl   $0x0,-0x420(%rbp)
  jmp    L12
L19:
  mov    -0x418(%rbp),%rax
  movzwl (%rax),%edx
  mov    -0x440(%rbp),%rax
  mov    %dx,(%rax)
  addq   $0x2,-0x440(%rbp)
  addq   $0x4,-0x418(%rbp)
  addl   $0x1,-0x420(%rbp)
L12:
  mov    -0x424(%rbp),%eax
  sar    $0x2,%eax
  cmp    %eax,-0x420(%rbp)
  jl     L19
  mov    -0x448(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    -0x424(%rbp),%eax
  sar    $0x2,%eax
  cltq
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x448(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x41c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int synth_ntom_mono(double *bandPtr, unsigned char *samples, int *pnt) {
  short samples_tmp[8 * 64];
  short *tmp1 = samples_tmp;
  int i, ret;
  int pnt1 = 0;
  ret = synth_ntom(bandPtr, 0, (unsigned char *)samples_tmp, &pnt1);
  samples += *pnt;
  for (i = 0; i < (pnt1 >> 2); i++) {
    *((short *)samples) = *tmp1;
    samples += sizeof(short);
    tmp1 += 2;
  }
  *pnt += (pnt1 >> 2) * sizeof(short);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<synth_ntom_mono>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    $0x0,%esi
  call   <synth_ntom@plt>
  movslq 0x0(%rbp),%rdx
  lea    (%rbx,%rdx,1),%rsi
  mov    0xc(%rsp),%r8d
  sar    $0x2,%r8d
  test   %r8d,%r8d
  jle    L26
  mov    %r8d,%edi
  mov    $0x0,%edx
L24:
  movzwl 0x10(%rsp,%rdx,4),%ecx
  mov    %cx,(%rsi,%rdx,2)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L24
L26:
  add    %r8d,%r8d
  add    %r8d,0x0(%rbp)
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synth_ntom_mono(double *bandPtr, unsigned char *samples, int *pnt) {
  short samples_tmp[8 * 64];
  short *tmp1 = samples_tmp;
  int i, ret;
  int pnt1 = 0;
  ret = synth_ntom(bandPtr, 0, (unsigned char *)samples_tmp, &pnt1);
  samples += *pnt;
  for (i = 0; i < (pnt1 >> 2); i++) {
    *((short *)samples) = *tmp1;
    samples += sizeof(short);
    tmp1 += 2;
  }
  *pnt += (pnt1 >> 2) * sizeof(short);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<synth_ntom_mono>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rcx
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%rdx
  call   <synth_ntom@plt>
  mov    0xc(%rsp),%r8d
  movslq (%r12),%rdx
  sar    $0x2,%r8d
  mov    %rdx,%r9
  lea    (%rbx,%rdx,1),%rsi
  test   %r8d,%r8d
  jle    L15
  movslq %r8d,%rdi
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L24:
  movzwl 0x0(%rbp,%rdx,4),%ecx
  mov    %cx,(%rsi,%rdx,2)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L24
L15:
  lea    (%r9,%r8,2),%edx
  mov    %edx,(%r12)
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x420,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synth_ntom_mono(double *bandPtr, unsigned char *samples, int *pnt) {
  short samples_tmp[8 * 64];
  short *tmp1 = samples_tmp;
  int i, ret;
  int pnt1 = 0;
  ret = synth_ntom(bandPtr, 0, (unsigned char *)samples_tmp, &pnt1);
  samples += *pnt;
  for (i = 0; i < (pnt1 >> 2); i++) {
    *((short *)samples) = *tmp1;
    samples += sizeof(short);
    tmp1 += 2;
  }
  *pnt += (pnt1 >> 2) * sizeof(short);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<synth_ntom_mono>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rcx
  movl   $0x0,0xc(%rsp)
  mov    %r12,%rdx
  call   <synth_ntom@plt>
  mov    0xc(%rsp),%ecx
  movslq (%rbx),%r10
  mov    %eax,%r8d
  sar    $0x2,%ecx
  mov    %r10,%r9
  lea    0x0(%rbp,%r10,1),%rdi
  test   %ecx,%ecx
  jle    L48
  lea    -0x1(%rcx),%eax
  cmp    $0x6,%eax
  jbe    L66
  mov    %ecx,%esi
  mov    %r12,%rax
  mov    %rdi,%rdx
  shr    $0x3,%esi
  sub    $0x1,%esi
  shl    $0x5,%rsi
  lea    0x30(%rsp,%rsi,1),%rsi
  cs nopw 0x0(%rax,%rax,1)
L0:
  movdqa (%rax),%xmm0
  add    $0x20,%rax
  add    $0x10,%rdx
  movdqa %xmm0,%xmm1
  punpcklwd -0x10(%rax),%xmm0
  punpckhwd -0x10(%rax),%xmm1
  movdqa %xmm0,%xmm2
  punpcklwd %xmm1,%xmm0
  punpckhwd %xmm1,%xmm2
  punpcklwd %xmm2,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rax,%rsi
  jne    L0
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  mov    %edx,%eax
  lea    (%rdi,%rax,2),%rdi
  lea    (%r12,%rax,4),%rsi
  mov    %edx,%eax
  cmp    %edx,%ecx
  je     L48
L8:
  mov    %ecx,%r11d
  sub    %edx,%r11d
  lea    -0x1(%r11),%r13d
  cmp    $0x2,%r13d
  jbe    L59
  lea    (%r12,%rdx,4),%r12
  lea    0x0(%rbp,%rdx,2),%rdx
  movq   (%r12),%xmm0
  movq   0x8(%r12),%xmm1
  movdqa %xmm0,%xmm2
  punpcklwd %xmm1,%xmm0
  punpcklwd %xmm1,%xmm2
  pshufd $0xe,%xmm2,%xmm2
  punpcklwd %xmm2,%xmm0
  movq   %xmm0,(%rdx,%r10,1)
  mov    %r11d,%edx
  and    $0xfffffffc,%edx
  mov    %edx,%r10d
  add    %edx,%eax
  lea    (%rdi,%r10,2),%rdi
  lea    (%rsi,%r10,4),%rsi
  cmp    %edx,%r11d
  je     L48
L59:
  movzwl (%rsi),%edx
  mov    %dx,(%rdi)
  lea    0x1(%rax),%edx
  cmp    %ecx,%edx
  jge    L48
  movzwl 0x4(%rsi),%edx
  add    $0x2,%eax
  mov    %dx,0x2(%rdi)
  cmp    %eax,%ecx
  jle    L48
  movzwl 0x8(%rsi),%eax
  mov    %ax,0x4(%rdi)
L48:
  lea    (%r9,%rcx,2),%eax
  mov    %eax,(%rbx)
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  add    $0x428,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  xor    %edx,%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  jmp    L8
L93:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synth_ntom_mono(double *bandPtr, unsigned char *samples, int *pnt) {
  short samples_tmp[8 * 64];
  short *tmp1 = samples_tmp;
  int i, ret;
  int pnt1 = 0;
  ret = synth_ntom(bandPtr, 0, (unsigned char *)samples_tmp, &pnt1);
  samples += *pnt;
  for (i = 0; i < (pnt1 >> 2); i++) {
    *((short *)samples) = *tmp1;
    samples += sizeof(short);
    tmp1 += 2;
  }
  *pnt += (pnt1 >> 2) * sizeof(short);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <f@plt>
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <f@plt>
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <f@plt>
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <f@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <f@plt>
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <f@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <f@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 7, b = 6, c = 4, d = 7, e = 2;
  f(a || b % c, 1);
  f(a ? b % c : 0, 2);
  f(a = b % c, 2);
  f(a *= b % c, 4);
  f(a /= b % c, 2);
  f(a %= b % c, 0);
  f(a += b % c, 2);
  f(d || c && e, 1);
  f(d ? c && e : 0, 1);
  f(d = c && e, 1);
  f(d *= c && e, 1);
  f(d %= c && e, 0);
  f(d += c && e, 1);
  f(d -= c && e, 0);
  f(d || c || e, 1);
  f(d ? c || e : 0, 0);
  f(d = c || e, 1);
  f(d *= c || e, 1);
  f(d %= c || e, 0);
  f(d += c || e, 1);
  f(d -= c || e, 0);
  exit(0);
}
```