ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<i3strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x20(%rbp),%r13
  mov    -0x28(%rbp),%r12
  mov    -0x30(%rbp),%rbx
  test   %rbx,%rbx
  je     L72
  sub    $0x1,%rbx
  test   %rbx,%rbx
  je     L72
L31:
  mov    %r12,%rdx
  lea    0x1(%rdx),%r12
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L73
  sub    $0x1,%rbx
  test   %rbx,%rbx
  jne    L31
  jmp    L72
L73:
  nop
L72:
  test   %rbx,%rbx
  jne    L22
  cmpq   $0x0,-0x30(%rbp)
  je     L1
  movb   $0x0,0x0(%r13)
L1:
  nop
L75:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
L22:
  mov    %r12,%rax
  sub    -0x28(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
size_t i3strlcpy(char *dst, const char *src, size_t siz) {
  register char *d = dst;
  register const char *s = src;
  register size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i3strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L84
  sub    $0x1,%rdx
  je     L63
  mov    %rsi,%rax
L78:
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdi)
  test   %cl,%cl
  je     L76
  sub    $0x1,%rdx
  jne    L78
  jmp    L32
L84:
  mov    %rsi,%rax
L39:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L39
L40:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L63:
  mov    %rsi,%rax
L32:
  movb   $0x0,(%rdi)
  jmp    L39
L76:
  test   %rdx,%rdx
  jne    L40
  jmp    L32
```

assistant: ```c
size_t i3strlcpy(char *dst, const char *src, size_t siz) {
  register char *d = dst;
  register const char *s = src;
  register size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<i3strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L74
  cmp    $0x1,%rdx
  je     L5
  mov    %rdi,%rcx
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  je     L9
L52:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L20
L48:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   (%rax)
L9:
  mov    %rcx,%rdi
L5:
  movb   $0x0,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L74:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L48
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L74
  jmp    L48
```

assistant: ```c
size_t i3strlcpy(char *dst, const char *src, size_t siz) {
  register char *d = dst;
  register const char *s = src;
  register size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<i3strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L49
  cmp    $0x1,%rdx
  je     L26
  mov    %rdi,%rcx
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  je     L78
L43:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L46
L52:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   (%rax)
L78:
  mov    %rcx,%rdi
L26:
  movb   $0x0,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L49:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L52
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L49
  jmp    L52
```

assistant: ```c
size_t i3strlcpy(char *dst, const char *src, size_t siz) {
  register char *d = dst;
  register const char *s = src;
  register size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L25:
  cmpl   $0x64,-0x8(%rbp)
  jg     L26
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  jmp    L39
L26:
  nop
L39:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(int *arr, int len) {
  int i = 0;
  int sum = 0;
  while (i < len) {
    if (i > 100)
      break;
    sum += arr[i];
    i++;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  test   %esi,%esi
  jle    L25
  mov    $0x1,%eax
  mov    $0x0,%ecx
L34:
  add    -0x4(%rdi,%rax,4),%ecx
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    $0x64,%edx
  jg     L17
  cmp    %edx,%esi
  jg     L34
L17:
  mov    %ecx,%eax
  ret
L25:
  mov    $0x0,%ecx
  jmp    L17
```

assistant: ```c
int foo(int *arr, int len) {
  int i = 0;
  int sum = 0;
  while (i < len) {
    if (i > 100)
      break;
    sum += arr[i];
    i++;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  test   %esi,%esi
  jle    L30
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L49:
  cmp    %edx,%esi
  jle    L16
L28:
  mov    %eax,%edx
  add    -0x4(%rdi,%rax,4),%r8d
  add    $0x1,%rax
  cmp    $0x65,%edx
  jne    L49
L16:
  mov    %r8d,%eax
  ret
L30:
  xor    %r8d,%r8d
  jmp    L16
```

assistant: ```c
int foo(int *arr, int len) {
  int i = 0;
  int sum = 0;
  while (i < len) {
    if (i > 100)
      break;
    sum += arr[i];
    i++;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  test   %esi,%esi
  jle    L35
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L12:
  cmp    %edx,%esi
  jle    L18
L1:
  mov    %eax,%edx
  add    -0x4(%rdi,%rax,4),%r8d
  add    $0x1,%rax
  cmp    $0x65,%edx
  jne    L12
L18:
  mov    %r8d,%eax
  ret
L35:
  xor    %r8d,%r8d
  jmp    L18
```

assistant: ```c
int foo(int *arr, int len) {
  int i = 0;
  int sum = 0;
  while (i < len) {
    if (i > 100)
      break;
    sum += arr[i];
    i++;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L45:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L33
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L33
  cmpl   $0xa,-0x8(%rbp)
  jne    L11
L33:
  cmpl   $0xa,-0x8(%rbp)
  jne    L34
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_line(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L59
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L27:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D4(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L0
  cmp    $0xa,%eax
  je     L0
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L27
  mov    %r12d,%ebx
  jmp    L39
L59:
  mov    $0x0,%ebx
L0:
  cmp    $0xa,%eax
  je     L37
L39:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  add    $0x1,%ebx
  jmp    L39
```

assistant: ```c
int get_line(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_line>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L48
  mov    D1(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L59:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L18
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L20
  mov    %edx,%r14d
L58:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L59
  cmp    $0xa,%eax
  je     L13
L48:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  lea    0x1(%r14),%edx
L18:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L20:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_line(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_line>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L29
  mov    D4(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L35:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L58
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L34
  mov    %edx,%r14d
L41:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L35
  cmp    $0xa,%eax
  je     L44
L29:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  lea    0x1(%r14),%edx
L58:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L34:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_line(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<otoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L24
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x37,%al
  jg     L24
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
L24:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int otoi(const char *p) {
  int r = 0;
  while (*p) {
    if (*p >= '0' && *p <= '7')
      r = r * 8 + (*(p++) - '0');
    else
      break;
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<otoi>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L22
  mov    $0x0,%edx
L1:
  lea    -0x30(%rax),%ecx
  cmp    $0x7,%cl
  ja     L21
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,8),%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L1
L21:
  mov    %edx,%eax
  ret
L22:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
int otoi(const char *p) {
  int r = 0;
  while (*p) {
    if (*p >= '0' && *p <= '7')
      r = r * 8 + (*(p++) - '0');
    else
      break;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<otoi>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L0
  jmp    L8
L27:
  movsbl %al,%eax
  add    $0x1,%rdi
  lea    (%rax,%r8,8),%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
L0:
  sub    $0x30,%eax
  cmp    $0x7,%al
  jbe    L27
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int otoi(const char *p) {
  int r = 0;
  while (*p) {
    if (*p >= '0' && *p <= '7')
      r = r * 8 + (*(p++) - '0');
    else
      break;
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<otoi>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L15
  jmp    L3
L16:
  movsbl %al,%eax
  add    $0x1,%rdi
  lea    (%rax,%r8,8),%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
L15:
  sub    $0x30,%eax
  cmp    $0x7,%al
  jbe    L16
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int otoi(const char *p) {
  int r = 0;
  while (*p) {
    if (*p >= '0' && *p <= '7')
      r = r * 8 + (*(p++) - '0');
    else
      break;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<csum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  jmp    L11
L31:
  mov    -0x28(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %rax,%rbx
  subl   $0x2,-0x2c(%rbp)
L11:
  cmpl   $0x1,-0x2c(%rbp)
  jg     L31
  cmpl   $0x1,-0x2c(%rbp)
  jne    L19
  movw   $0x0,-0x1a(%rbp)
  lea    -0x1a(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  movzwl -0x1a(%rbp),%eax
  movzwl %ax,%eax
  add    %rax,%rbx
L19:
  mov    %rbx,%rdx
  sar    $0x10,%rdx
  movzwl %bx,%eax
  lea    (%rdx,%rax,1),%rbx
  mov    %rbx,%rax
  sar    $0x10,%rax
  add    %rax,%rbx
  mov    %ebx,%eax
  not    %eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned short csum(unsigned short *ptr, int nbytes) {
  register long sum;
  unsigned short oddbyte;
  register short answer;
  sum = 0;
  while (nbytes > 1) {
    sum += *ptr++;
    nbytes -= 2;
  }
  if (nbytes == 1) {
    oddbyte = 0;
    *((u_char *)&oddbyte) = *(u_char *)ptr;
    sum += oddbyte;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum = sum + (sum >> 16);
  answer = (short)~sum;
  return (answer);
}
```
user: What is the c source code of the assembly code below:

```asm
<csum>:
  endbr64
  cmp    $0x1,%esi
  jle    L3
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L24:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L24
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L32:
  cmp    $0x1,%esi
  je     L43
L10:
  mov    %rax,%rdx
  sar    $0x10,%rdx
  movzwl %ax,%eax
  add    %rax,%rdx
  mov    %rdx,%rax
  sar    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
L3:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L32
L43:
  movzwl (%rcx),%edx
  add    %rdx,%rax
  jmp    L10
```

assistant: ```c
unsigned short csum(unsigned short *ptr, int nbytes) {
  register long sum;
  unsigned short oddbyte;
  register short answer;
  sum = 0;
  while (nbytes > 1) {
    sum += *ptr++;
    nbytes -= 2;
  }
  if (nbytes == 1) {
    oddbyte = 0;
    *((u_char *)&oddbyte) = *(u_char *)ptr;
    sum += oddbyte;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum = sum + (sum >> 16);
  answer = (short)~sum;
  return (answer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csum>:
  endbr64
  cmp    $0x1,%esi
  jle    L34
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L17:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L17
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L37:
  cmp    $0x1,%esi
  jne    L32
  movzwl (%rcx),%edx
  add    %rdx,%rax
L32:
  mov    %rax,%rdx
  movzwl %ax,%eax
  sar    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  sar    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L37
```

assistant: ```c
unsigned short csum(unsigned short *ptr, int nbytes) {
  register long sum;
  unsigned short oddbyte;
  register short answer;
  sum = 0;
  while (nbytes > 1) {
    sum += *ptr++;
    nbytes -= 2;
  }
  if (nbytes == 1) {
    oddbyte = 0;
    *((u_char *)&oddbyte) = *(u_char *)ptr;
    sum += oddbyte;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum = sum + (sum >> 16);
  answer = (short)~sum;
  return (answer);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<csum>:
  endbr64
  mov    %rdi,%rdx
  cmp    $0x1,%esi
  jle    L79
  lea    -0x2(%rsi),%r10d
  mov    %r10d,%r9d
  shr    %r9d
  lea    0x1(%r9),%ecx
  cmp    $0xd,%r10d
  jbe    L106
  pxor   %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopl   0x0(%rax,%rax,1)
L17:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm2
  punpckhwd %xmm4,%xmm1
  punpcklwd %xmm4,%xmm2
  movdqa %xmm2,%xmm5
  punpckhdq %xmm3,%xmm2
  punpckldq %xmm3,%xmm5
  paddq  %xmm5,%xmm0
  paddq  %xmm2,%xmm0
  movdqa %xmm1,%xmm2
  punpckhdq %xmm3,%xmm1
  punpckldq %xmm3,%xmm2
  paddq  %xmm2,%xmm0
  paddq  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L17
  mov    %ecx,%r8d
  movdqa %xmm0,%xmm1
  and    $0xfffffff8,%r8d
  psrldq $0x8,%xmm1
  mov    %r8d,%r11d
  paddq  %xmm1,%xmm0
  mov    %r8d,%edi
  neg    %r11d
  movq   %xmm0,%rax
  lea    (%rdx,%rdi,2),%rdi
  lea    (%rsi,%r11,2),%esi
  cmp    %ecx,%r8d
  je     L24
L110:
  movzwl (%rdi),%r8d
  add    %r8,%rax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L24
  movzwl 0x2(%rdi),%r8d
  add    %r8,%rax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L24
  movzwl 0x4(%rdi),%r8d
  add    %r8,%rax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L24
  movzwl 0x6(%rdi),%r8d
  add    %r8,%rax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L24
  movzwl 0x8(%rdi),%r8d
  add    %r8,%rax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L24
  movzwl 0xa(%rdi),%r8d
  add    %r8,%rax
  cmp    $0xd,%esi
  jle    L24
  movzwl 0xc(%rdi),%esi
  add    %rsi,%rax
L24:
  mov    %ecx,%esi
  mov    %r9d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r10,%rcx,2),%esi
L101:
  cmp    $0x1,%esi
  jne    L18
  movzwl (%rdx),%edx
  add    %rdx,%rax
L18:
  mov    %rax,%rdx
  movzwl %ax,%eax
  sar    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  sar    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax)
L79:
  xor    %eax,%eax
  jmp    L101
L106:
  xor    %eax,%eax
  jmp    L110
```

assistant: ```c
unsigned short csum(unsigned short *ptr, int nbytes) {
  register long sum;
  unsigned short oddbyte;
  register short answer;
  sum = 0;
  while (nbytes > 1) {
    sum += *ptr++;
    nbytes -= 2;
  }
  if (nbytes == 1) {
    oddbyte = 0;
    *((u_char *)&oddbyte) = *(u_char *)ptr;
    sum += oddbyte;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum = sum + (sum >> 16);
  answer = (short)~sum;
  return (answer);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: Usage: %s [--help] [FILE]...


assistant: ```c
int help(const char *name) {
  printf("Usage: %s [--help] [FILE]...\n", name);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string

tool: D6: Usage: %s [--help] [FILE]...


assistant: ```c
int help(const char *name) {
  printf("Usage: %s [--help] [FILE]...\n", name);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3: Usage: %s [--help] [FILE]...


assistant: ```c
int help(const char *name) {
  printf("Usage: %s [--help] [FILE]...\n", name);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: Usage: %s [--help] [FILE]...


assistant: ```c
int help(const char *name) {
  printf("Usage: %s [--help] [FILE]...\n", name);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eputxs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L5:
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    %eax,%edi
  call   <eputxc@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void eputxs(const char *string, int x, int y, int modifier) {
  int i = 0;
  for (i = 0; *(string + i) != '\0'; i += 1)
    eputxc(*(string + i), x + i, y, modifier);
}
```