ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<str_diffn>:
  endbr64
  test   %edx,%edx
  je     L99
L1:
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  cmp    %al,%cl
  jne    L16
  test   %cl,%cl
  je     L122
  cmp    $0x1,%edx
  je     L99
  movzbl 0x1(%rdi),%eax
  movzbl 0x1(%rsi),%ecx
  cmp    %al,%cl
  jne    L16
  test   %cl,%cl
  je     L122
  cmp    $0x2,%edx
  je     L99
  movzbl 0x2(%rdi),%eax
  movzbl 0x2(%rsi),%ecx
  cmp    %al,%cl
  jne    L16
  test   %cl,%cl
  je     L122
  cmp    $0x3,%edx
  je     L99
  movzbl 0x3(%rdi),%eax
  movzbl 0x3(%rsi),%ecx
  cmp    %al,%cl
  jne    L16
  test   %al,%al
  je     L122
  add    $0x4,%rdi
  add    $0x4,%rsi
  sub    $0x4,%edx
  jne    L1
L99:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L122:
  xor    %eax,%eax
L16:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int str_diffn(s, t, len)
register char *s;
register char *t;
unsigned int len;
{
  register char x;
  for (;;) {
    if (!len--)
      return 0;
    x = *s;
    if (x != *t)
      break;
    if (!x)
      break;
    ++s;
    ++t;
    if (!len--)
      return 0;
    x = *s;
    if (x != *t)
      break;
    if (!x)
      break;
    ++s;
    ++t;
    if (!len--)
      return 0;
    x = *s;
    if (x != *t)
      break;
    if (!x)
      break;
    ++s;
    ++t;
    if (!len--)
      return 0;
    x = *s;
    if (x != *t)
      break;
    if (!x)
      break;
    ++s;
    ++t;
  }
  return ((int)(unsigned int)(unsigned char)x) - ((int)(unsigned int)(unsigned char)*t);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf_s@plt>
  jmp    L11
L4:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
datatype: string
name: unpack_data
arguments: tag: D8
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D22
datatype: string
name: unpack_data
arguments: tag: D49
datatype: string

tool: D18: Enter a number: 

tool: D8: %d

tool: D26: %d	

tool: D22: Number of digits is : %d

tool: D49: pause

assistant: ```c
main() {
  int number, x;
  int count = 0;
  printf("Enter a number: ");
  scanf_s("%d", &number);
  while (number > 0) {
    x = number % 10;
    printf("%d\t", x);
    count++;
    number = number / 10;
  }
  printf("\n");
  printf("Number of digits is : %d", count);
  printf("\n");
  system("pause");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L10
  mov    $0x0,%ebx
  lea    D14(%rip),%rbp
L34:
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  cltd
  sub    %edx,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L34
L39:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D38(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x0,%ebx
  jmp    L39
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D45
type_infered: string
name: read_data
arguments: data_label: D41
type_infered: string
name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D19
type_infered: string
name: read_data
arguments: data_label: D38
type_infered: string

tool: D45: Enter a number: 

tool: D41: %d

tool: D14: %d	

tool: D19: Number of digits is : %d

tool: D38: pause

assistant: ```c
main() {
  int number, x;
  int count = 0;
  printf("Enter a number: ");
  scanf_s("%d", &number);
  while (number > 0) {
    x = number % 10;
    printf("%d\t", x);
    count++;
    number = number / 10;
  }
  printf("\n");
  printf("Number of digits is : %d", count);
  printf("\n");
  system("pause");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D44(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L3
  lea    D11(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L12:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  add    $0x1,%ebp
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  cltd
  sar    $0x22,%rsi
  sub    %edx,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L12
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D9(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D44
datatype: string
name: unpack_data
arguments: data_label: D10
datatype: string
name: unpack_data
arguments: data_label: D11
datatype: string
name: unpack_data
arguments: data_label: D28
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string

tool: D44: Enter a number: 

tool: D10: %d

tool: D11: %d	

tool: D28: Number of digits is : %d

tool: D9: pause

assistant: ```c
main() {
  int number, x;
  int count = 0;
  printf("Enter a number: ");
  scanf_s("%d", &number);
  while (number > 0) {
    x = number % 10;
    printf("%d\t", x);
    count++;
    number = number / 10;
  }
  printf("\n");
  printf("Number of digits is : %d", count);
  printf("\n");
  system("pause");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L14
  lea    D38(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L19:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  add    $0x1,%ebp
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  cltd
  sar    $0x22,%rsi
  sub    %edx,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L19
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D1(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D21
datatype: string
name: unpack_data
arguments: tag: D38
datatype: string
name: unpack_data
arguments: tag: D43
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string

tool: D26: Enter a number: 

tool: D21: %d

tool: D38: %d	

tool: D43: Number of digits is : %d

tool: D1: pause

assistant: ```c
main() {
  int number, x;
  int count = 0;
  printf("Enter a number: ");
  scanf_s("%d", &number);
  while (number > 0) {
    x = number % 10;
    printf("%d\t", x);
    count++;
    number = number / 10;
  }
  printf("\n");
  printf("Number of digits is : %d", count);
  printf("\n");
  system("pause");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lcd_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <pmp_set_address@plt>
  mov    $0x0,%eax
  call   <pmp_master_read@plt>
  mov    $0x0,%eax
  call   <pmp_master_read@plt>
  leave
  ret
```

assistant: ```c
int lcd_read(int addr) {
  pmp_set_address(addr);
  pmp_master_read();
  return pmp_master_read();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lcd_read>:
  endbr64
  sub    $0x8,%rsp
  call   <pmp_set_address@plt>
  mov    $0x0,%eax
  call   <pmp_master_read@plt>
  mov    $0x0,%eax
  call   <pmp_master_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int lcd_read(int addr) {
  pmp_set_address(addr);
  pmp_master_read();
  return pmp_master_read();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcd_read>:
  endbr64
  sub    $0x8,%rsp
  call   <pmp_set_address@plt>
  xor    %eax,%eax
  call   <pmp_master_read@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <pmp_master_read@plt>
```

assistant: ```c
int lcd_read(int addr) {
  pmp_set_address(addr);
  pmp_master_read();
  return pmp_master_read();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lcd_read>:
  endbr64
  sub    $0x8,%rsp
  call   <pmp_set_address@plt>
  xor    %eax,%eax
  call   <pmp_master_read@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <pmp_master_read@plt>
```

assistant: ```c
int lcd_read(int addr) {
  pmp_set_address(addr);
  pmp_master_read();
  return pmp_master_read();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <Rf_initialize_R@plt>
  mov    $0x0,%eax
  call   <Rf_mainloop@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int ac, char **av) {
  Rf_initialize_R(ac, av);
  Rf_mainloop();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <Rf_initialize_R@plt>
  mov    $0x0,%eax
  call   <Rf_mainloop@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int ac, char **av) {
  Rf_initialize_R(ac, av);
  Rf_mainloop();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <Rf_initialize_R@plt>
  xor    %eax,%eax
  call   <Rf_mainloop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int ac, char **av) {
  Rf_initialize_R(ac, av);
  Rf_mainloop();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <Rf_initialize_R@plt>
  xor    %eax,%eax
  call   <Rf_mainloop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int ac, char **av) {
  Rf_initialize_R(ac, av);
  Rf_mainloop();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<scm_page_north>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <scm_page_level@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <scm_page_root@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <scm_page_row@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <scm_page_col@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jle    L13
  subq   $0x1,-0x30(%rbp)
  jmp    L15
L13:
  cmpq   $0x0,-0x38(%rbp)
  jne    L98
  movq   $0x2,-0x38(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L15
L98:
  cmpq   $0x1,-0x38(%rbp)
  jne    L67
  movq   $0x2,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L15
L67:
  cmpq   $0x2,-0x38(%rbp)
  jne    L71
  movq   $0x5,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L15
L71:
  cmpq   $0x3,-0x38(%rbp)
  jne    L113
  movq   $0x4,-0x38(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L15
L113:
  cmpq   $0x4,-0x38(%rbp)
  jne    L0
  movq   $0x2,-0x38(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L15
L0:
  movq   $0x2,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L15:
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <scm_page_index@plt>
  leave
  ret
```

assistant: ```c
long long scm_page_north(long long i) {
  long long l = scm_page_level(i);
  long long f = scm_page_root(i);
  long long r = scm_page_row(i);
  long long c = scm_page_col(i);
  long long n = 1LL << l, m = n - 1, t = m - c;
  if (r > 0) {
    r = r - 1;
  } else if (f == 0) {
    f = 2;
    r = t;
    c = m;
  } else if (f == 1) {
    f = 2;
    r = c;
    c = 0;
  } else if (f == 2) {
    f = 5;
    r = 0;
    c = t;
  } else if (f == 3) {
    f = 4;
    r = m;
  } else if (f == 4) {
    f = 2;
    r = m;
  } else {
    f = 2;
    r = 0;
    c = t;
  }
  return scm_page_index(f, l, r, c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scm_page_north>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  call   <scm_page_level@plt>
  mov    %rax,%r12
  mov    %r13,%rdi
  call   <scm_page_root@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <scm_page_row@plt>
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <scm_page_col@plt>
  lea    -0x1(%rbx),%rdx
  test   %rbx,%rbx
  jle    L71
L28:
  mov    %rax,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scm_page_index@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  mov    $0x1,%edx
  mov    %r12d,%ecx
  shl    %cl,%rdx
  sub    $0x1,%rdx
  mov    %rdx,%rdi
  sub    %rax,%rdi
  cmp    $0x4,%rbp
  ja     L55
  lea    D6(%rip),%rsi
  movslq (%rsi,%rbp,4),%rcx
  add    %rsi,%rcx
  notrack jmp *%rcx
  mov    %rdx,%rax
  mov    %rdi,%rdx
  mov    $0x2,%ebp
  jmp    L28
  mov    %rax,%rdx
  mov    $0x0,%eax
  mov    $0x2,%ebp
  jmp    L28
  mov    %rdi,%rax
  mov    $0x0,%edx
  mov    $0x5,%ebp
  jmp    L28
  mov    $0x4,%ebp
  jmp    L28
  mov    $0x2,%ebp
  jmp    L28
L55:
  mov    %rdi,%rax
  mov    $0x0,%edx
  mov    $0x2,%ebp
  jmp    L28
```

assistant: ```c
long long scm_page_north(long long i) {
  long long l = scm_page_level(i);
  long long f = scm_page_root(i);
  long long r = scm_page_row(i);
  long long c = scm_page_col(i);
  long long n = 1LL << l, m = n - 1, t = m - c;
  if (r > 0) {
    r = r - 1;
  } else if (f == 0) {
    f = 2;
    r = t;
    c = m;
  } else if (f == 1) {
    f = 2;
    r = c;
    c = 0;
  } else if (f == 2) {
    f = 5;
    r = 0;
    c = t;
  } else if (f == 3) {
    f = 4;
    r = m;
  } else if (f == 4) {
    f = 2;
    r = m;
  } else {
    f = 2;
    r = 0;
    c = t;
  }
  return scm_page_index(f, l, r, c);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scm_page_north>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <scm_page_level@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <scm_page_root@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <scm_page_row@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <scm_page_col@plt>
  mov    %rax,%r8
  test   %rbx,%rbx
  jle    L34
  lea    -0x1(%rbx),%rdx
L50:
  add    $0x8,%rsp
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %r8,%rcx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <scm_page_index@plt>
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%edx
  mov    %r13d,%ecx
  shl    %cl,%rdx
  sub    $0x1,%rdx
  mov    %rdx,%rsi
  sub    %rax,%rsi
  cmp    $0x4,%r12
  ja     10e0 <scm_page_north.cold>
  lea    D2(%rip),%rcx
  movslq (%rcx,%r12,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  mov    %rdx,%r8
  mov    $0x2,%r12d
  mov    %rsi,%rdx
  jmp    L50
  xchg   %ax,%ax
  mov    $0x2,%r12d
  jmp    L50
  nopl   0x0(%rax,%rax,1)
  mov    $0x4,%r12d
  jmp    L50
  nopl   0x0(%rax,%rax,1)
  mov    %rsi,%r8
  xor    %edx,%edx
  mov    $0x5,%r12d
  jmp    L50
  mov    %r8,%rdx
  mov    $0x2,%r12d
  xor    %r8d,%r8d
  jmp    L50
```

assistant: ```c
long long scm_page_north(long long i) {
  long long l = scm_page_level(i);
  long long f = scm_page_root(i);
  long long r = scm_page_row(i);
  long long c = scm_page_col(i);
  long long n = 1LL << l, m = n - 1, t = m - c;
  if (r > 0) {
    r = r - 1;
  } else if (f == 0) {
    f = 2;
    r = t;
    c = m;
  } else if (f == 1) {
    f = 2;
    r = c;
    c = 0;
  } else if (f == 2) {
    f = 5;
    r = 0;
    c = t;
  } else if (f == 3) {
    f = 4;
    r = m;
  } else if (f == 4) {
    f = 2;
    r = m;
  } else {
    f = 2;
    r = 0;
    c = t;
  }
  return scm_page_index(f, l, r, c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scm_page_north>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <scm_page_level@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <scm_page_root@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <scm_page_row@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <scm_page_col@plt>
  mov    %rax,%r8
  test   %rbx,%rbx
  jle    L14
  lea    -0x1(%rbx),%rdx
L29:
  add    $0x8,%rsp
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %r8,%rcx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <scm_page_index@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%edx
  mov    %r13d,%ecx
  shl    %cl,%rdx
  sub    $0x1,%rdx
  mov    %rdx,%rsi
  sub    %rax,%rsi
  cmp    $0x4,%r12
  ja     10e0 <scm_page_north.cold>
  lea    D4(%rip),%rcx
  movslq (%rcx,%r12,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  mov    %rdx,%r8
  mov    $0x2,%r12d
  mov    %rsi,%rdx
  jmp    L29
  xchg   %ax,%ax
  mov    $0x2,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
  mov    $0x4,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
  mov    %rsi,%r8
  xor    %edx,%edx
  mov    $0x5,%r12d
  jmp    L29
  mov    %r8,%rdx
  mov    $0x2,%r12d
  xor    %r8d,%r8d
  jmp    L29
```

assistant: ```c
long long scm_page_north(long long i) {
  long long l = scm_page_level(i);
  long long f = scm_page_root(i);
  long long r = scm_page_row(i);
  long long c = scm_page_col(i);
  long long n = 1LL << l, m = n - 1, t = m - c;
  if (r > 0) {
    r = r - 1;
  } else if (f == 0) {
    f = 2;
    r = t;
    c = m;
  } else if (f == 1) {
    f = 2;
    r = c;
    c = 0;
  } else if (f == 2) {
    f = 5;
    r = 0;
    c = t;
  } else if (f == 3) {
    f = 4;
    r = m;
  } else if (f == 4) {
    f = 2;
    r = m;
  } else {
    f = 2;
    r = 0;
    c = t;
  }
  return scm_page_index(f, l, r, c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  lea    D23(%rip),%rax
  mov    %rax,%rdx
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <mount@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <get_meminfo@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <domain_policy_test@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exception_policy_test@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <BUG@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
type_guessed: string
name: parse_data
arguments: data_tag: D27
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string
name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D23: proc

tool: D27: /proc/

tool: D8: /proc

tool: D2: Policy read/write test: Success


assistant: ```c
int main(void) {
  unsigned int before;
  mount("/proc", "/proc/", "proc", 0, NULL);
  get_meminfo(&before);
  domain_policy_test(before);
  exception_policy_test(before);
  BUG("Policy read/write test: Success\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  lea    D10(%rip),%rdx
  lea    D39(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <mount@plt>
  lea    0x4(%rsp),%rdi
  call   <get_meminfo@plt>
  mov    0x4(%rsp),%edi
  call   <domain_policy_test@plt>
  mov    0x4(%rsp),%edi
  call   <exception_policy_test@plt>
  lea    D19(%rip),%rdi
  call   <BUG@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D10
type: string
name: read_data
arguments: tag: D39
type: string
name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D19
type: string

tool: D10: proc

tool: D39: /proc/

tool: D8: /proc

tool: D19: Policy read/write test: Success


assistant: ```c
int main(void) {
  unsigned int before;
  mount("/proc", "/proc/", "proc", 0, NULL);
  get_meminfo(&before);
  domain_policy_test(before);
  exception_policy_test(before);
  BUG("Policy read/write test: Success\n");
  return 0;
}
```