user: 这段汇编代码用C语言表示是什么样的:

```asm
<search>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %rsi,0x10(%rsp)
  mov    %edx,%ebp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,0xc(%rsp)
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  cmp    $0x1,%ebx
  jle    L173
  lea    -0x1(%rbx),%esi
  mov    $0x1,%edx
  mov    $0x0,%ecx
L149:
  mov    %edx,%eax
  shl    $0x8,%eax
  cltd
  idiv   %ebp
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L149
  mov    %edx,0x18(%rsp)
L9:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L105
  mov    %eax,%esi
  mov    $0x0,%ecx
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  mov    0x10(%rsp),%rdi
L8:
  shl    $0x8,%r15d
  movsbl (%r14,%rcx,1),%eax
  add    %r15d,%eax
  cltd
  idiv   %ebp
  mov    %edx,%r15d
  shl    $0x8,%ebx
  movsbl (%rdi,%rcx,1),%eax
  add    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %edx,%ebx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L8
L7:
  mov    %ebx,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%r13d
  sub    0xc(%rsp),%r13d
  js     L67
  mov    $0x0,%r12d
  mov    %r15d,0x8(%rsp)
  mov    %ebp,0x1c(%rsp)
  jmp    L66
L173:
  movl   $0x1,0x18(%rsp)
  jmp    L9
L105:
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  jmp    L7
L118:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L155
  mov    %eax,%esi
  mov    $0x0,%eax
  mov    0x10(%rsp),%rcx
  add    %r12,%rcx
L101:
  mov    %eax,%edx
  movzbl (%r14,%rax,1),%edi
  cmp    %dil,(%rcx,%rax,1)
  jne    L29
  lea    0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L101
L29:
  cmp    %edx,0xc(%rsp)
  jne    L24
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L155:
  mov    $0x0,%edx
  jmp    L29
L91:
  mov    %ebp,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r12
  cmp    %r12d,%r13d
  jl     L67
L66:
  mov    %r12d,%r15d
  mov    %r12d,%ebp
  mov    %r12d,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  cmp    %ebx,0x8(%rsp)
  je     L118
L24:
  cmp    %r12d,%r13d
  jle    L91
  mov    %ebp,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  movsbl (%rsi,%r12,1),%eax
  imul   0x18(%rsp),%eax
  sub    %eax,%ebx
  shl    $0x8,%ebx
  mov    0xc(%rsp),%eax
  lea    (%rax,%r15,1),%edx
  movslq %edx,%rdx
  movsbl (%rsi,%rdx,1),%eax
  add    %ebx,%eax
  mov    0x1c(%rsp),%ecx
  cltd
  idiv   %ecx
  lea    (%rdx,%rcx,1),%ebx
  test   %edx,%edx
  cmovns %edx,%ebx
  jmp    L91
L67:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D33
type_infered: string
name: extract_symbolic_data
arguments: data_label: D24
type_infered: string
name: extract_symbolic_data
arguments: data_label: D36
type_infered: string
name: extract_symbolic_data
arguments: data_label: D14
type_infered: string
name: extract_symbolic_data
arguments: data_label: D44
type_infered: string

tool: D33: t %d 


tool: D24: Padrao encontrado na posicao %d 


tool: D36: fim %d 


tool: D14: comeco %d 


tool: D44: fiz %d 


assistant: ```c
void search(char *pad, char *txt, int q) {
  int M = strlen(pad);
  int N = strlen(txt);
  int i, j;
  int p = 0;
  int t = 0;
  int h = 1;
  for (i = 0; i < M - 1; i++)
    h = (h * 256) % q;
  for (i = 0; i < M; i++) {
    p = (256 * p + pad[i]) % q;
    t = (256 * t + txt[i]) % q;
  }
  printf("t %d \n", t);
  for (i = 0; i <= N - M; i++) {
    printf("comeco %d \n", i);
    printf("t %d \n", t);
    if (p == t) {
      for (j = 0; j < M; j++) {
        if (txt[i + j] != pad[j])
          break;
      }
      if (j == M)
        printf("Padrao encontrado na posicao %d \n", i);
    }
    if (i < N - M) {
      printf("fiz %d \n", i);
      t = (256 * (t - txt[i] * h) + txt[i + M]) % q;
      if (t < 0)
        t = (t + q);
    }
    printf("fim %d \n", i);
  }
}
```