ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<eval_potential>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edi,%edi
  jle    L12
  movq   %xmm1,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %edi,%r12d
  mov    $0x0,%ebx
L10:
  mov    %rbp,0x0(%r13,%rbx,8)
  movq   %rbp,%xmm0
  call   <potential@plt>
  movsd  %xmm0,(%r14,%rbx,8)
  movq   %rbp,%xmm2
  addsd  0x8(%rsp),%xmm2
  movq   %xmm2,%rbp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L10
L12:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void eval_potential(int n, double dx, double x0, double *x_buff, double *V_buff) {
  double x = x0;
  for (int i = 0; i < n; i++) {
    x_buff[i] = x;
    V_buff[i] = potential(x);
    x += dx;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eval_potential>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edi,%edi
  jle    L4
  mov    %rsi,%r12
  mov    %rdx,%r13
  movslq %edi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L14:
  movsd  %xmm1,(%r12,%rbx,8)
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <potential@plt>
  movsd  (%rsp),%xmm1
  addsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L14
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void eval_potential(int n, double dx, double x0, double *x_buff, double *V_buff) {
  double x = x0;
  for (int i = 0; i < n; i++) {
    x_buff[i] = x;
    V_buff[i] = potential(x);
    x += dx;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eval_potential>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edi,%edi
  jle    L15
  mov    %rsi,%r12
  mov    %rdx,%r13
  movslq %edi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L19:
  movsd  %xmm1,(%r12,%rbx,8)
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <potential@plt>
  movsd  (%rsp),%xmm1
  addsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L19
L15:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void eval_potential(int n, double dx, double x0, double *x_buff, double *V_buff) {
  double x = x0;
  for (int i = 0; i < n; i++) {
    x_buff[i] = x;
    V_buff[i] = potential(x);
    x += dx;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mystrstrcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int mystrstrcmp(const void *vp1, const void *vp2) {
  const char *const *a = vp1;
  const char *const *b = vp2;
  return strcmp(*a, *b);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mystrstrcmp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mystrstrcmp(const void *vp1, const void *vp2) {
  const char *const *a = vp1;
  const char *const *b = vp2;
  return strcmp(*a, *b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mystrstrcmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int mystrstrcmp(const void *vp1, const void *vp2) {
  const char *const *a = vp1;
  const char *const *b = vp2;
  return strcmp(*a, *b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mystrstrcmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int mystrstrcmp(const void *vp1, const void *vp2) {
  const char *const *a = vp1;
  const char *const *b = vp2;
  return strcmp(*a, *b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <shutdown@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sock_close(int fd) {
  int err;
  err = shutdown(fd, 2);
  if (!err)
    close(fd);
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sock_close>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x2,%esi
  call   <shutdown@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L7
L14:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L14
```

assistant: ```c
int sock_close(int fd) {
  int err;
  err = shutdown(fd, 2);
  if (!err)
    close(fd);
  return err;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sock_close>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <shutdown@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L4
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    %ebp,%edi
  call   <close@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sock_close(int fd) {
  int err;
  err = shutdown(fd, 2);
  if (!err)
    close(fd);
  return err;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sock_close>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <shutdown@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    %ebp,%edi
  call   <close@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sock_close(int fd) {
  int err;
  err = shutdown(fd, 2);
  if (!err)
    close(fd);
  return err;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<phyCalcVapPresR410A>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  D92(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L20
  comisd D153(%rip),%xmm0
  jbe    L7
  movsd  D153(%rip),%xmm0
  jmp    L7
L20:
  movsd  D92(%rip),%xmm0
L7:
  addsd  D53(%rip),%xmm0
  divsd  D78(%rip),%xmm0
  movapd %xmm0,%xmm2
  movsd  D135(%rip),%xmm0
  movsd  %xmm2,0x8(%rsp)
  subsd  %xmm2,%xmm0
  subsd  D142(%rip),%xmm0
  movq   %xmm0,%rbx
  mov    $0x2,%edi
  call   <pow@plt>
  movq   %rbx,%xmm1
  mulsd  D65(%rip),%xmm1
  subsd  D109(%rip),%xmm1
  mulsd  D148(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  mov    $0x3,%edi
  movq   %rbx,%xmm0
  call   <pow@plt>
  mulsd  D113(%rip),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  mov    $0x4,%edi
  movq   %rbx,%xmm0
  call   <pow@plt>
  mulsd  D32(%rip),%xmm0
  movapd %xmm0,%xmm5
  addsd  (%rsp),%xmm5
  movsd  %xmm5,(%rsp)
  mov    $0x5,%edi
  movq   %rbx,%xmm0
  call   <pow@plt>
  mulsd  D10(%rip),%xmm0
  addsd  (%rsp),%xmm0
  movsd  D135(%rip),%xmm1
  divsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  call   <exp@plt>
  mulsd  D88(%rip),%xmm0
  divsd  D99(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D92
datatype: byte[8]
name: read_data
arguments: data_tag: D153
datatype: f64[2]
name: read_data
arguments: data_tag: D53
datatype: f64
name: read_data
arguments: data_tag: D78
datatype: f64
name: read_data
arguments: data_tag: D135
datatype: f64
name: read_data
arguments: data_tag: D142
datatype: f64
name: read_data
arguments: data_tag: D65
datatype: byte[8]
name: read_data
arguments: data_tag: D109
datatype: f64
name: read_data
arguments: data_tag: D148
datatype: byte[8]
name: read_data
arguments: data_tag: D113
datatype: byte[8]
name: read_data
arguments: data_tag: D32
datatype: byte[8]
name: read_data
arguments: data_tag: D10
datatype: byte[8]
name: read_data
arguments: data_tag: D88
datatype: f64
name: read_data
arguments: data_tag: D99
datatype: f64

tool: {"D92": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0xc0]}

tool: {"D153": [72.0,273.15]}

tool: D53: 273.15

tool: D78: 345.28

tool: D135: 1

tool: D142: 0.2086902

tool: {"D65": [0x67,0x7e,0x35,0x07,0x08,0x76,0x1b,0xc0]}

tool: D109: 1.440004

tool: {"D148": [0x33,0x92,0x98,0xfb,0x3f,0x22,0xe1,0xbf]}

tool: {"D113": [0x4e,0x9d,0x47,0xc5,0xff,0xfd,0x0d,0xc0]}

tool: {"D32": [0x1e,0x19,0xab,0xcd,0xff,0x2b,0x0c,0xc0]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x1f,0xc0]}

tool: D88: 4926.1

tool: D99: 100

assistant: ```c
double phyCalcVapPresR410A(double temp) {
  const double A = -1.440004;
  const double B = -6.865265;
  const double C = -0.5354309;
  const double D = -3.749023;
  const double E = -3.521484;
  const double F = -7.75;
  const double X0 = 0.2086902;
  const double Tc = 345.28;
  const double Pc = 4926.1;
  double X, Tr;
  if (temp < -100.0)
    temp = -100.0;
  else if (temp > 72.0)
    temp = 72.0;
  Tr = (temp + 273.15) / Tc;
  X = (1.0 - Tr) - X0;
  return (double)(exp(1.0 / Tr * (A + (B * X) + (C * pow(X, 2)) + (D * pow(X, 3)) + (E * pow(X, 4)) + (F * pow(X, 5)))) * Pc / 100.0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sld_string_chop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sld_string_allocate@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L12
  cmpl   $0x1,-0xc(%rbp)
  jne    L52
L12:
  lea    D8(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L55
L52:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L8
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L8
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L55
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L55:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: 

assistant: ```c
char *sld_string_chop(char *string) {
  char *chopped_string = NULL;
  int length = strlen(string);
  chopped_string = sld_string_allocate(string);
  strcpy(chopped_string, string);
  if (length == 0 || length == 1)
    chopped_string = "";
  else {
    if (chopped_string[length - 1] == '\n' && chopped_string[length - 2] == '\r')
      chopped_string[length - 2] = '\0';
    else
      chopped_string[length - 1] = '\0';
  }
  return chopped_string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sld_string_chop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <sld_string_allocate@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmp    $0x1,%r12d
  jbe    L23
  movslq %r12d,%r12
  lea    -0x1(%rbx,%r12,1),%rax
  cmpb   $0xa,(%rax)
  je     L49
L13:
  movb   $0x0,(%rax)
L29:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  lea    -0x2(%rbx,%r12,1),%rdx
  cmpb   $0xd,(%rdx)
  jne    L13
  movb   $0x0,(%rdx)
  jmp    L29
L23:
  lea    D4(%rip),%rbx
  jmp    L29
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: 

assistant: ```c
char *sld_string_chop(char *string) {
  char *chopped_string = NULL;
  int length = strlen(string);
  chopped_string = sld_string_allocate(string);
  strcpy(chopped_string, string);
  if (length == 0 || length == 1)
    chopped_string = "";
  else {
    if (chopped_string[length - 1] == '\n' && chopped_string[length - 2] == '\r')
      chopped_string[length - 2] = '\0';
    else
      chopped_string[length - 1] = '\0';
  }
  return chopped_string;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sld_string_chop>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <sld_string_allocate@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  cmp    $0x1,%ebx
  jbe    L19
  lea    -0x1(%r12,%rbx,1),%rax
  cmpb   $0xa,(%rax)
  je     L37
L28:
  movb   $0x0,(%rax)
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  lea    -0x2(%r12,%rbx,1),%rdx
  cmpb   $0xd,(%rdx)
  jne    L28
  movb   $0x0,(%rdx)
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L19:
  lea    D9(%rip),%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: 

assistant: ```c
char *sld_string_chop(char *string) {
  char *chopped_string = NULL;
  int length = strlen(string);
  chopped_string = sld_string_allocate(string);
  strcpy(chopped_string, string);
  if (length == 0 || length == 1)
    chopped_string = "";
  else {
    if (chopped_string[length - 1] == '\n' && chopped_string[length - 2] == '\r')
      chopped_string[length - 2] = '\0';
    else
      chopped_string[length - 1] = '\0';
  }
  return chopped_string;
}
```
user: What is the c source code of the assembly code below?

```asm
<sld_string_chop>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <sld_string_allocate@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  cmp    $0x1,%ebx
  jbe    L3
  lea    -0x1(%r12,%rbx,1),%rax
  cmpb   $0xa,(%rax)
  je     L37
L32:
  movb   $0x0,(%rax)
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  lea    -0x2(%r12,%rbx,1),%rdx
  cmpb   $0xd,(%rdx)
  jne    L32
  movb   $0x0,(%rdx)
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L3:
  lea    D2(%rip),%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: 

assistant: ```c
char *sld_string_chop(char *string) {
  char *chopped_string = NULL;
  int length = strlen(string);
  chopped_string = sld_string_allocate(string);
  strcpy(chopped_string, string);
  if (length == 0 || length == 1)
    chopped_string = "";
  else {
    if (chopped_string[length - 1] == '\n' && chopped_string[length - 2] == '\r')
      chopped_string[length - 2] = '\0';
    else
      chopped_string[length - 1] = '\0';
  }
  return chopped_string;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L11
L24:
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   $0x0,-0x10(%rbp)
  jmp    L43
L45:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fibo@plt>
  add    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L43:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jle    L45
  mov    -0x10(%rbp),%rcx
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L11:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D23
type: string
name: retrieve_data
arguments: data_tag: D4
type: string

tool: D2: %d

tool: D23: %llu %llu

tool: D4: %llu


assistant: ```c
int main() {
  int cases, i;
  scanf("%d", &cases);
  for (i = 0; i < cases; ++i) {
    long long a, b;
    scanf("%llu %llu", &a, &b);
    long long s = 0;
    while (a <= b) {
      s += fibo(a);
      a = a + 1;
    }
    printf("%llu\n", s % 1000000007);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L12
  mov    $0x0,%ebp
  lea    0x10(%rsp),%r15
  lea    D16(%rip),%r14
  movabs $0x89705f3112a28fe5,%r13
  lea    D11(%rip),%r12
L37:
  lea    0x8(%rsp),%rsi
  mov    %r15,%rdx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  cmp    0x10(%rsp),%rdi
  jg     L4
  mov    $0x0,%ebx
L50:
  call   <fibo@plt>
  add    %rax,%rbx
  mov    0x8(%rsp),%rax
  lea    0x1(%rax),%rdi
  mov    %rdi,0x8(%rsp)
  cmp    0x10(%rsp),%rdi
  jle    L50
L45:
  mov    %rbx,%rax
  imul   %r13
  lea    (%rdx,%rbx,1),%rax
  sar    $0x1d,%rax
  mov    %rbx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rax
  mov    %rbx,%rsi
  sub    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jg     L37
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    $0x0,%ebx
  jmp    L45
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D16
type: string
name: parse_data
arguments: data_tag: D11
type: string

tool: D5: %d

tool: D16: %llu %llu

tool: D11: %llu


assistant: ```c
int main() {
  int cases, i;
  scanf("%d", &cases);
  for (i = 0; i < cases; ++i) {
    long long a, b;
    scanf("%llu %llu", &a, &b);
    long long s = 0;
    while (a <= b) {
      s += fibo(a);
      a = a + 1;
    }
    printf("%llu\n", s % 1000000007);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D6(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L55
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  lea    D7(%rip),%r12
  lea    D2(%rip),%rbp
  nopl   0x0(%rax)
L9:
  mov    %r12,%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  cmp    0x10(%rsp),%rdi
  jg     L29
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L38:
  call   <fibo@plt>
  add    %rax,%r15
  mov    0x8(%rsp),%rax
  lea    0x1(%rax),%rdi
  mov    %rdi,0x8(%rsp)
  cmp    0x10(%rsp),%rdi
  jle    L38
  movabs $0x89705f3112a28fe5,%rax
  imul   %r15
  mov    %r15,%rax
  sar    $0x3f,%rax
  lea    (%rdx,%r15,1),%rsi
  sar    $0x1d,%rsi
  sub    %rax,%rsi
  imul   $0x3b9aca07,%rsi,%rax
  mov    %r15,%rsi
  sub    %rax,%rsi
L12:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L9
L55:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %esi,%esi
  jmp    L12
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D7
type: string
name: unpack_data
arguments: data_tag: D2
type: string

tool: D6: %d

tool: D7: %llu %llu

tool: D2: %llu


assistant: ```c
int main() {
  int cases, i;
  scanf("%d", &cases);
  for (i = 0; i < cases; ++i) {
    long long a, b;
    scanf("%llu %llu", &a, &b);
    long long s = 0;
    while (a <= b) {
      s += fibo(a);
      a = a + 1;
    }
    printf("%llu\n", s % 1000000007);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D17(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L56
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  lea    D24(%rip),%r12
  lea    D10(%rip),%rbp
  nopl   0x0(%rax)
L39:
  mov    %r12,%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  cmp    0x10(%rsp),%rdi
  jg     L26
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L52:
  call   <fibo@plt>
  add    %rax,%r15
  mov    0x8(%rsp),%rax
  lea    0x1(%rax),%rdi
  mov    %rdi,0x8(%rsp)
  cmp    0x10(%rsp),%rdi
  jle    L52
  movabs $0x89705f3112a28fe5,%rax
  imul   %r15
  mov    %r15,%rax
  sar    $0x3f,%rax
  lea    (%rdx,%r15,1),%rsi
  sar    $0x1d,%rsi
  sub    %rax,%rsi
  imul   $0x3b9aca07,%rsi,%rax
  mov    %r15,%rsi
  sub    %rax,%rsi
L5:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L39
L56:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %esi,%esi
  jmp    L5
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
data_type: string
name: parse_data
arguments: data_label: D24
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string

tool: D17: %d

tool: D24: %llu %llu

tool: D10: %llu


assistant: ```c
int main() {
  int cases, i;
  scanf("%d", &cases);
  for (i = 0; i < cases; ++i) {
    long long a, b;
    scanf("%llu %llu", &a, &b);
    long long s = 0;
    while (a <= b) {
      s += fibo(a);
      a = a + 1;
    }
    printf("%llu\n", s % 1000000007);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L19
L5:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L19:
  cmpl   $0x0,-0x18(%rbp)
  jg     L5
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int m, int n) {
  int r;
  while (n > 0) {
    r = m % n;
    m = n;
    n = r;
  }
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jle    L0
L10:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jg     L10
L7:
  mov    %ecx,%eax
  ret
L0:
  mov    %edi,%ecx
  jmp    L7
```

assistant: ```c
int gcd(int m, int n) {
  int r;
  while (n > 0) {
    r = m % n;
    m = n;
    n = r;
  }
  return m;
}
```