ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_249_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  notb   -0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_249_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk2 = ~stk2;
  stk1 = T | stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_249_0_1>:
  endbr64
  mov    %esi,%ecx
  xor    (%rdi),%cl
  not    %ecx
  or     %edx,%ecx
  mov    %edx,%eax
  not    %eax
  or     %esi,%eax
  and    %ecx,%eax
  not    %esi
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_249_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk2 = ~stk2;
  stk1 = T | stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_249_0_1>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %edx,%eax
  not    %eax
  xor    %esi,%ecx
  or     %esi,%eax
  not    %esi
  not    %ecx
  and    %edx,%esi
  and    (%rdi),%sil
  or     %edx,%ecx
  and    %ecx,%eax
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_249_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk2 = ~stk2;
  stk1 = T | stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<somaElementos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L14
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  jmp    L11
L14:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <somaElementos>
  add    %ebx,%eax
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int somaElementos(int *arr, int n) {
  if (n == 0)
    return arr[0];
  return arr[n] + somaElementos(arr, n - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<somaElementos>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %esi,%esi
  jne    L14
  mov    (%rdi),%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    %esi,%ebx
  lea    -0x1(%rsi),%esi
  call   <somaElementos>
  movslq %ebx,%rbx
  add    0x0(%rbp,%rbx,4),%eax
  jmp    L11
```

assistant: ```c
int somaElementos(int *arr, int n) {
  if (n == 0)
    return arr[0];
  return arr[n] + somaElementos(arr, n - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<somaElementos>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L12
  movslq %esi,%rdx
  xor    %eax,%eax
  nop
L11:
  add    (%rdi,%rdx,4),%eax
  sub    $0x1,%rdx
  test   %edx,%edx
  jne    L11
L12:
  add    (%rdi),%eax
  ret
```

assistant: ```c
int somaElementos(int *arr, int n) {
  if (n == 0)
    return arr[0];
  return arr[n] + somaElementos(arr, n - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<somaElementos>:
  endbr64
  mov    %rdi,%rcx
  xor    %eax,%eax
  test   %esi,%esi
  je     L7
  lea    -0x1(%rsi),%edx
  mov    %esi,%r9d
  cmp    $0x2,%edx
  jbe    L47
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  lea    -0xc(%rdi,%rax,4),%rdx
  mov    %esi,%edi
  shr    $0x2,%edi
  lea    -0x10(%rdx),%rax
  lea    -0x1(%rdi),%r8d
  mov    %rax,%rdi
  shl    $0x4,%r8
  sub    %r8,%rdi
  jmp    L37
  nopl   (%rax)
L31:
  sub    $0x10,%rax
L37:
  movdqu (%rdx),%xmm1
  mov    %rax,%rdx
  pshufd $0x1b,%xmm1,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L31
  movdqa %xmm0,%xmm1
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  sub    %edx,%esi
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%r9d
  je     L7
  lea    -0x1(%rsi),%edx
L15:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rcx,%rdi,4),%eax
  test   %edx,%edx
  je     L7
  add    -0x4(%rcx,%r8,1),%eax
  cmp    $0x2,%esi
  je     L7
  add    -0x8(%rcx,%r8,1),%eax
L7:
  add    (%rcx),%eax
  ret
L47:
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
int somaElementos(int *arr, int n) {
  if (n == 0)
    return arr[0];
  return arr[n] + somaElementos(arr, n - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gemver>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%r12
  mov    %rdx,%r10
  mov    %rcx,%rsi
  mov    %r9,%rbp
  mov    0x30(%rsp),%rdi
  mov    0x38(%rsp),%r14
  mov    0x40(%rsp),%r13
  mov    %r11,%r9
  mov    %r12,%rcx
  add    $0x8000,%r12
  mov    %r11,%rbx
L51:
  mov    %rbx,%rdx
  mov    $0x0,%eax
L60:
  movsd  (%rcx),%xmm0
  mulsd  (%r10,%rax,1),%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  (%r8,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x8000,%rax
  jne    L60
  add    $0x8000,%rbx
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %r12,%rcx
  jne    L51
  mov    %rdi,%rcx
  lea    0x8000000(%r11),%rsi
  add    $0x8008000,%r11
L32:
  lea    -0x8000000(%rsi),%rax
  mov    %r14,%rdx
L50:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8000,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rax
  jne    L50
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %r11,%rsi
  jne    L32
  mov    $0x0,%eax
L0:
  movsd  (%rdi,%rax,1),%xmm0
  addsd  0x0(%r13,%rax,1),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    $0x8000,%rax
  jne    L0
  mov    %rbp,%rdx
  add    $0x8000,%rbp
L1:
  mov    %r9,%rcx
  mov    $0x0,%eax
L63:
  movsd  (%rcx,%rax,1),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    $0x8000,%rax
  jne    L63
  add    $0x8,%rdx
  add    $0x8000,%r9
  cmp    %rdx,%rbp
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void gemver(double A[4096][4096], double u1[4096], double v1[4096], double u2[4096], double v2[4096], double w[4096], double x[4096], double y[4096], double z[4096]) {
  int i, j;
#pragma scop
#pragma live - out w
  for (i = 0; i < 4096; i++)
    for (j = 0; j < 4096; j++)
      A[i][j] = A[i][j] + u1[i] * v1[j] + u2[i] * v2[j];
  for (i = 0; i < 4096; i++)
    for (j = 0; j < 4096; j++)
      x[i] = x[i] + A[j][i] * y[j];
  for (i = 0; i < 4096; i++)
    x[i] = x[i] + z[i];
  for (i = 0; i < 4096; i++)
    for (j = 0; j < 4096; j++)
      w[i] = w[i] + A[i][j] * x[j];
#pragma endscop
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gemver>:
  endbr64
  push   %r13
  mov    %rdi,%r10
  lea    0x8000(%rsi),%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %r8,%r12
  mov    %r10,%rdx
  push   %rbp
  mov    %rcx,%rbp
  mov    %r9,%rcx
  mov    %r10,%r9
  push   %rbx
  mov    0x28(%rsp),%r8
  mov    0x30(%rsp),%rbx
  mov    0x38(%rsp),%r11
L64:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  0x0(%rbp),%xmm1
  mulsd  (%r12,%rax,1),%xmm1
  movsd  (%rsi),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x8000,%rax
  jne    L11
  add    $0x8,%rsi
  add    $0x8000,%rdx
  add    $0x8,%rbp
  cmp    %rsi,%r13
  jne    L64
  lea    0x8000000(%r10),%rsi
  mov    %r8,%rdi
  add    $0x8008000,%r10
L69:
  movsd  (%rdi),%xmm1
  lea    -0x8000000(%rsi),%rax
  mov    %rbx,%rdx
  nopl   0x0(%rax)
L25:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8000,%rax
  add    $0x8,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  cmp    %rax,%rsi
  jne    L25
  add    $0x8,%rsi
  add    $0x8,%rdi
  cmp    %rsi,%r10
  jne    L69
  xor    %eax,%eax
L50:
  movsd  (%r8,%rax,1),%xmm0
  addsd  (%r11,%rax,1),%xmm0
  movsd  %xmm0,(%r8,%rax,1)
  add    $0x8,%rax
  cmp    $0x8000,%rax
  jne    L50
  mov    %rcx,%rdx
  lea    0x8000(%rcx),%rcx
L13:
  movsd  (%rdx),%xmm1
  xor    %eax,%eax
  nopl   0x0(%rax)
L41:
  movsd  (%r9,%rax,1),%xmm0
  mulsd  (%r8,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    $0x8000,%rax
  jne    L41
  add    $0x8,%rdx
  add    $0x8000,%r9
  cmp    %rdx,%rcx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void gemver(double A[4096][4096], double u1[4096], double v1[4096], double u2[4096], double v2[4096], double w[4096], double x[4096], double y[4096], double z[4096]) {
  int i, j;
#pragma scop
#pragma live - out w
  for (i = 0; i < 4096; i++)
    for (j = 0; j < 4096; j++)
      A[i][j] = A[i][j] + u1[i] * v1[j] + u2[i] * v2[j];
  for (i = 0; i < 4096; i++)
    for (j = 0; j < 4096; j++)
      x[i] = x[i] + A[j][i] * y[j];
  for (i = 0; i < 4096; i++)
    x[i] = x[i] + z[i];
  for (i = 0; i < 4096; i++)
    for (j = 0; j < 4096; j++)
      w[i] = w[i] + A[i][j] * x[j];
#pragma endscop
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_25_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x3(%rbp)
  notb   -0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_25_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_25_1_1>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%edx
  or     %eax,%esi
  not    %edx
  and    (%rdi),%dl
  or     %esi,%edx
  not    %edx
  mov    %esi,%eax
  and    (%rdi),%al
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_25_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rop3_25_1_1>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%edx
  or     %eax,%esi
  movzbl (%rdi),%eax
  not    %edx
  and    (%rdi),%dl
  or     %esi,%edx
  and    %esi,%eax
  not    %edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_25_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_25_1_1>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%edx
  or     %eax,%esi
  movzbl (%rdi),%eax
  not    %edx
  and    (%rdi),%dl
  or     %esi,%edx
  and    %esi,%eax
  not    %edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_25_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    $0x3,%eax
  jmp    L4
L6:
  mov    $0x2,%eax
L4:
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int var1;
  int var2;
  int cond1 = 0;
  int cond2 = 1;
  var1 = cond1 ? 0 : 1;
  var2 = cond2 ? 1 : 0;
  var1 = var2 ? 3 : 2;
  return var1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main(void) {
  int var1;
  int var2;
  int cond1 = 0;
  int cond2 = 1;
  var1 = cond1 ? 0 : 1;
  var2 = cond2 ? 1 : 0;
  var1 = var2 ? 3 : 2;
  return var1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main(void) {
  int var1;
  int var2;
  int cond1 = 0;
  int cond2 = 1;
  var1 = cond1 ? 0 : 1;
  var2 = cond2 ? 1 : 0;
  var1 = var2 ? 3 : 2;
  return var1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main(void) {
  int var1;
  int var2;
  int cond1 = 0;
  int cond2 = 1;
  var1 = cond1 ? 0 : 1;
  var2 = cond2 ? 1 : 0;
  var1 = var2 ? 3 : 2;
  return var1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  leave
  ret
```

assistant: ```c
char *ft_strdup(const char *s1) {
  char *copy;
  copy = malloc(sizeof(char) * ft_strlen(s1) + 1);
  return (ft_strcpy(copy, s1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <ft_strcpy@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *ft_strdup(const char *s1) {
  char *copy;
  copy = malloc(sizeof(char) * ft_strlen(s1) + 1);
  return (ft_strcpy(copy, s1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <ft_strcpy@plt>
```

assistant: ```c
char *ft_strdup(const char *s1) {
  char *copy;
  copy = malloc(sizeof(char) * ft_strlen(s1) + 1);
  return (ft_strcpy(copy, s1));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <ft_strcpy@plt>
```

assistant: ```c
char *ft_strdup(const char *s1) {
  char *copy;
  copy = malloc(sizeof(char) * ft_strlen(s1) + 1);
  return (ft_strcpy(copy, s1));
}
```
user: What is the c source code of the assembly code below:

```asm
<write_ramdisk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  imul   -0x8(%rbp),%eax
  cmp    $0x200000,%eax
  jle    L4
  mov    $0xffffffff,%eax
  jmp    L3
L4:
  mov    -0x8(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  add    $0x100000,%eax
  cltq
  mov    %rax,%rdi
  mov    -0x10(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rsi
  mov    %ds,%bx
  mov    %es,%dx
  mov    $0x10,%ax
  mov    %eax,%es
  mov    %eax,%ds
  cld
  rep movsl %ds:(%rsi),%es:(%rdi)
  mov    %edx,%es
  mov    %ebx,%ds
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int write_ramdisk(int nth_zone, int zone_size, unsigned char *p_src) {
  if (zone_size * (nth_zone + 1) > 2 * 1024 * 1024)
    return -1;
  else {
    __asm__("mov %%ds,%%bx\n\t"
            "mov %%es,%%dx\n\t"
            "mov $0x10,%%ax\n\t"
            "mov %%ax,%%es\n\t"
            "mov %%ax,%%ds\n\t"
            "cld\n\t"
            "rep\n\t"
            "movsl\n\t"
            "mov %%dx,%%es\n\t"
            "mov %%bx,%%ds\n\t" ::"c"(zone_size / 4),
            "D"((unsigned char *)(0x100000 + zone_size * nth_zone)), "S"(p_src));
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_ramdisk>:
  endbr64
  add    $0x1,%edi
  imul   %esi,%edi
  cmp    $0x200000,%edi
  jg     L4
  lea    0x3(%rsi),%ecx
  test   %esi,%esi
  cmovns %esi,%ecx
  sar    $0x2,%ecx
  sub    %esi,%edi
  add    $0x100000,%edi
  movslq %edi,%rdi
  mov    %rdx,%rsi
  mov    %ds,%bx
  mov    %es,%dx
  mov    $0x10,%ax
  mov    %eax,%es
  mov    %eax,%ds
  cld
  rep movsl %ds:(%rsi),%es:(%rdi)
  mov    %edx,%es
  mov    %ebx,%ds
  mov    $0x0,%eax
  ret
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int write_ramdisk(int nth_zone, int zone_size, unsigned char *p_src) {
  if (zone_size * (nth_zone + 1) > 2 * 1024 * 1024)
    return -1;
  else {
    __asm__("mov %%ds,%%bx\n\t"
            "mov %%es,%%dx\n\t"
            "mov $0x10,%%ax\n\t"
            "mov %%ax,%%es\n\t"
            "mov %%ax,%%ds\n\t"
            "cld\n\t"
            "rep\n\t"
            "movsl\n\t"
            "mov %%dx,%%es\n\t"
            "mov %%bx,%%ds\n\t" ::"c"(zone_size / 4),
            "D"((unsigned char *)(0x100000 + zone_size * nth_zone)), "S"(p_src));
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_ramdisk>:
  endbr64
  add    $0x1,%edi
  imul   %esi,%edi
  cmp    $0x200000,%edi
  jg     L4
  test   %esi,%esi
  lea    0x3(%rsi),%ecx
  cmovns %esi,%ecx
  sub    %esi,%edi
  mov    %rdx,%rsi
  add    $0x100000,%edi
  sar    $0x2,%ecx
  movslq %edi,%rdi
  mov    %ds,%bx
  mov    %es,%dx
  mov    $0x10,%ax
  mov    %eax,%es
  mov    %eax,%ds
  cld
  rep movsl %ds:(%rsi),%es:(%rdi)
  mov    %edx,%es
  mov    %ebx,%ds
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int write_ramdisk(int nth_zone, int zone_size, unsigned char *p_src) {
  if (zone_size * (nth_zone + 1) > 2 * 1024 * 1024)
    return -1;
  else {
    __asm__("mov %%ds,%%bx\n\t"
            "mov %%es,%%dx\n\t"
            "mov $0x10,%%ax\n\t"
            "mov %%ax,%%es\n\t"
            "mov %%ax,%%ds\n\t"
            "cld\n\t"
            "rep\n\t"
            "movsl\n\t"
            "mov %%dx,%%es\n\t"
            "mov %%bx,%%ds\n\t" ::"c"(zone_size / 4),
            "D"((unsigned char *)(0x100000 + zone_size * nth_zone)), "S"(p_src));
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_ramdisk>:
  endbr64
  add    $0x1,%edi
  imul   %esi,%edi
  cmp    $0x200000,%edi
  jg     L2
  test   %esi,%esi
  lea    0x3(%rsi),%ecx
  cmovns %esi,%ecx
  sub    %esi,%edi
  mov    %rdx,%rsi
  add    $0x100000,%edi
  sar    $0x2,%ecx
  movslq %edi,%rdi
  mov    %ds,%bx
  mov    %es,%dx
  mov    $0x10,%ax
  mov    %eax,%es
  mov    %eax,%ds
  cld
  rep movsl %ds:(%rsi),%es:(%rdi)
  mov    %edx,%es
  mov    %ebx,%ds
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int write_ramdisk(int nth_zone, int zone_size, unsigned char *p_src) {
  if (zone_size * (nth_zone + 1) > 2 * 1024 * 1024)
    return -1;
  else {
    __asm__("mov %%ds,%%bx\n\t"
            "mov %%es,%%dx\n\t"
            "mov $0x10,%%ax\n\t"
            "mov %%ax,%%es\n\t"
            "mov %%ax,%%ds\n\t"
            "cld\n\t"
            "rep\n\t"
            "movsl\n\t"
            "mov %%dx,%%es\n\t"
            "mov %%bx,%%ds\n\t" ::"c"(zone_size / 4),
            "D"((unsigned char *)(0x100000 + zone_size * nth_zone)), "S"(p_src));
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ADCIntStatus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L7
  mov    -0x14(%rbp),%eax
  add    $0xc,%eax
  cltq
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    $0x10001,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L8
L7:
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  cltq
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  or     $0x10000,%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x10000,%eax
  test   %eax,%eax
  je     L8
  orl    $0xf0000,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x10000,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    %eax,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ADCIntStatus(uint32_t ui32Base, uint32_t ui32SequenceNum, bool bMasked) {
  uint32_t ui32Temp;
  ;
  ;
  if (bMasked) {
    ui32Temp = (*((volatile uint32_t *)(ui32Base + 0x0000000C))) & (0x10001 << ui32SequenceNum);
  } else {
    ui32Temp = ((*((volatile uint32_t *)(ui32Base + 0x00000004))) & (0x10000 | (1 << ui32SequenceNum)));
    if (ui32Temp & 0x10000) {
      ui32Temp |= 0xF0000;
      ui32Temp &= ~(0x10000 << ui32SequenceNum);
    }
  }
  return (ui32Temp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ADCIntStatus>:
  endbr64
  mov    %esi,%ecx
  test   %edx,%edx
  je     L15
  add    $0xc,%edi
  movslq %edi,%rdi
  mov    (%rdi),%edx
  mov    $0x10001,%eax
  shl    %cl,%eax
  and    %edx,%eax
  ret
L15:
  add    $0x4,%edi
  movslq %edi,%rdi
  mov    (%rdi),%edx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     $0x10000,%eax
  and    %edx,%eax
  test   $0x10000,%eax
  je     L19
  or     $0xf0000,%eax
  mov    $0x10000,%edx
  shl    %cl,%edx
  not    %edx
  and    %edx,%eax
L19:
  ret
```

assistant: ```c
uint32_t ADCIntStatus(uint32_t ui32Base, uint32_t ui32SequenceNum, bool bMasked) {
  uint32_t ui32Temp;
  ;
  ;
  if (bMasked) {
    ui32Temp = (*((volatile uint32_t *)(ui32Base + 0x0000000C))) & (0x10001 << ui32SequenceNum);
  } else {
    ui32Temp = ((*((volatile uint32_t *)(ui32Base + 0x00000004))) & (0x10000 | (1 << ui32SequenceNum)));
    if (ui32Temp & 0x10000) {
      ui32Temp |= 0xF0000;
      ui32Temp &= ~(0x10000 << ui32SequenceNum);
    }
  }
  return (ui32Temp);
}
```