ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  lea    D14(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsd  D26(%rip),%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  cvtss2sd %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  mulsd  %xmm0,%xmm1
  addsd  D37(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D6(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D26
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D37
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: byte[4]

tool: D12:   C      F

tool: D14: %3.0f %6.1f


tool: {"D26": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: {"D6": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  printf("  C      F\n");
  celsius = lower;
  while (celsius <= upper) {
    fahr = celsius * (9.0 / 5.0) + 32;
    printf("%3.0f %6.1f\n", celsius, fahr);
    celsius = celsius + step;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  lea    D48(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L3:
  movsd  D3(%rip),%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  cvtss2sd %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  mulsd  %xmm0,%xmm1
  addsd  D37(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D29(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D46
data_type: string
name: read_data
arguments: tag: D48
data_type: string
name: read_data
arguments: tag: D3
data_type: byte[8]
name: read_data
arguments: tag: D37
data_type: byte[8]
name: read_data
arguments: tag: D29
data_type: byte[4]

tool: D46:   C      F

tool: D48: %3.0f %6.1f


tool: {"D3": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: {"D29": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  printf("  C      F\n");
  celsius = lower;
  while (celsius <= upper) {
    fahr = celsius * (9.0 / 5.0) + 32;
    printf("%3.0f %6.1f\n", celsius, fahr);
    celsius = celsius + step;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x136ff696,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    0x32060f04(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] + state[0UL];
      } else {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = copy13;
        copy13 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 839257860UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x4576059a,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] + state[0UL];
      } else {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = copy13;
        copy13 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 839257860UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x4576059a,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] + state[0UL];
      } else {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = copy13;
        copy13 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 839257860UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x4576059a,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] + state[0UL];
      } else {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = copy13;
        copy13 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 839257860UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<random_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  sub    -0x14(%rbp),%eax
  mov    -0x14(%rbp),%edx
  lea    0x1(%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x8(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L6
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int random_integer(int m) {
  assert(m >= 0);
  assert(m <= RAND_MAX);
  const int r = (RAND_MAX - m) % (m + 1);
  int value;
  do {
    value = rand();
  } while (value > RAND_MAX - r);
  const int result = value % (m + 1);
  assert(result >= 0);
  assert(result <= m);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<random_integer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    D17(%rip),%rbx
  cmp    %ebp,(%rbx)
  setge  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x1(%rbp),%r12d
  mov    (%rbx),%eax
  sub    %ebp,%eax
  cltd
  idiv   %r12d
  mov    %edx,%ebx
L0:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    D17(%rip),%rdx
  mov    (%rdx),%edx
  sub    %ebx,%edx
  cmp    %eax,%edx
  jl     L0
  cltd
  idiv   %r12d
  mov    %edx,%ebx
  mov    %edx,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    %ebx,%ebp
  setge  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int random_integer(int m) {
  assert(m >= 0);
  assert(m <= RAND_MAX);
  const int r = (RAND_MAX - m) % (m + 1);
  int value;
  do {
    value = rand();
  } while (value > RAND_MAX - r);
  const int result = value % (m + 1);
  assert(result >= 0);
  assert(result <= m);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<random_integer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  not    %edi
  push   %rbx
  shr    $0x1f,%edi
  lea    0x1(%rbp),%r12d
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    D5(%rip),%rbx
  xor    %edi,%edi
  cmp    %ebp,(%rbx)
  setge  %dil
  call   <assert@plt>
  mov    (%rbx),%eax
  sub    %ebp,%eax
  cltd
  idiv   %r12d
  mov    %edx,%r13d
  nopl   (%rax)
L0:
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%rbx),%ecx
  sub    %r13d,%ecx
  cmp    %eax,%ecx
  jl     L0
  cltd
  idiv   %r12d
  mov    %edx,%edi
  mov    %edx,%r13d
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r13d,%ebp
  setge  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int random_integer(int m) {
  assert(m >= 0);
  assert(m <= RAND_MAX);
  const int r = (RAND_MAX - m) % (m + 1);
  int value;
  do {
    value = rand();
  } while (value > RAND_MAX - r);
  const int result = value % (m + 1);
  assert(result >= 0);
  assert(result <= m);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<random_integer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  not    %edi
  push   %rbx
  shr    $0x1f,%edi
  lea    0x1(%rbp),%r12d
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    D9(%rip),%rbx
  xor    %edi,%edi
  cmp    %ebp,(%rbx)
  setge  %dil
  call   <assert@plt>
  mov    (%rbx),%eax
  sub    %ebp,%eax
  cltd
  idiv   %r12d
  mov    %edx,%r13d
  nopl   (%rax)
L9:
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%rbx),%ecx
  sub    %r13d,%ecx
  cmp    %eax,%ecx
  jl     L9
  cltd
  idiv   %r12d
  mov    %edx,%edi
  mov    %edx,%r13d
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r13d,%ebp
  setge  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int random_integer(int m) {
  assert(m >= 0);
  assert(m <= RAND_MAX);
  const int r = (RAND_MAX - m) % (m + 1);
  int value;
  do {
    value = rand();
  } while (value > RAND_MAX - r);
  const int result = value % (m + 1);
  assert(result >= 0);
  assert(result <= m);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L1
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L32
  mov    $0xffffffff,%eax
  jmp    L12
L32:
  mov    $0x1,%eax
  jmp    L12
L1:
  cmpl   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int _strcasecmp(char *s1, char *s2) {
  int c1, c2;
  do {
    c1 = tolower(*s1++);
    c2 = tolower(*s2++);
    if (c1 != c2)
      return c1 < c2 ? -1 : 1;
  } while (c1 != 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
L12:
  add    $0x1,%r12
  movsbl -0x1(%r12),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L8
  test   %ebx,%ebx
  jne    L12
  jmp    L5
L8:
  setge  %bl
  movzbl %bl,%ebx
  lea    -0x1(%rbx,%rbx,1),%ebx
L5:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _strcasecmp(char *s1, char *s2) {
  int c1, c2;
  do {
    c1 = tolower(*s1++);
    c2 = tolower(*s2++);
    if (c1 != c2)
      return c1 < c2 ? -1 : 1;
  } while (c1 != 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L19
L14:
  test   %r12d,%r12d
  je     L9
L19:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <tolower@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%r12d
  call   <tolower@plt>
  cmp    %eax,%r12d
  je     L14
  setge  %r12b
  movzbl %r12b,%r12d
  lea    -0x1(%r12,%r12,1),%r12d
L9:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _strcasecmp(char *s1, char *s2) {
  int c1, c2;
  do {
    c1 = tolower(*s1++);
    c2 = tolower(*s2++);
    if (c1 != c2)
      return c1 < c2 ? -1 : 1;
  } while (c1 != 0);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<_strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L17
L11:
  test   %r12d,%r12d
  je     L22
L17:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <tolower@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%r12d
  call   <tolower@plt>
  cmp    %eax,%r12d
  je     L11
  setge  %r12b
  movzbl %r12b,%r12d
  lea    -0x1(%r12,%r12,1),%r12d
L22:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _strcasecmp(char *s1, char *s2) {
  int c1, c2;
  do {
    c1 = tolower(*s1++);
    c2 = tolower(*s2++);
    if (c1 != c2)
      return c1 < c2 ? -1 : 1;
  } while (c1 != 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  jmp    L3
L10:
  lea    -0xd(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <to_bin_naive@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <nibble_from_string@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  lea    -0xd(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x18(%rbp)
L3:
  cmpl   $0xf,-0x18(%rbp)
  jle    L10
  movb   $0x3f,-0xd(%rbp)
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <nibble_from_string@plt>
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: %d => '%s' => %d


assistant: ```c
void verify() {
  char buf[5];
  for (int x = 0; x < 16; x++) {
    to_bin_naive(x, buf);
    const int parsed = nibble_from_string(buf);
    printf("%d => '%s' => %d\n", x, buf, parsed);
    assert(x == parsed);
  }
  buf[0] = '?';
  assert(nibble_from_string(buf) < 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<verify>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
L17:
  lea    0x3(%rsp),%r12
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <to_bin_naive@plt>
  mov    %r12,%rdi
  call   <nibble_from_string@plt>
  mov    %eax,%ebp
  mov    %eax,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L17
  movb   $0x3f,0x3(%rsp)
  mov    %r12,%rdi
  call   <nibble_from_string@plt>
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: %d => '%s' => %d


assistant: ```c
void verify() {
  char buf[5];
  for (int x = 0; x < 16; x++) {
    to_bin_naive(x, buf);
    const int parsed = nibble_from_string(buf);
    printf("%d => '%s' => %d\n", x, buf, parsed);
    assert(x == parsed);
  }
  buf[0] = '?';
  assert(nibble_from_string(buf) < 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<verify>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  nopl   0x0(%rax)
L16:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <to_bin_naive@plt>
  mov    %r12,%rdi
  call   <nibble_from_string@plt>
  mov    %ebx,%esi
  mov    %r12,%rdx
  mov    %r13,%rdi
  mov    %eax,%ebp
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %edi,%edi
  cmp    %ebx,%ebp
  sete   %dil
  add    $0x1,%ebx
  call   <assert@plt>
  cmp    $0x10,%ebx
  jne    L16
  mov    %r12,%rdi
  movb   $0x3f,0x3(%rsp)
  call   <nibble_from_string@plt>
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: %d => '%s' => %d


assistant: ```c
void verify() {
  char buf[5];
  for (int x = 0; x < 16; x++) {
    to_bin_naive(x, buf);
    const int parsed = nibble_from_string(buf);
    printf("%d => '%s' => %d\n", x, buf, parsed);
    assert(x == parsed);
  }
  buf[0] = '?';
  assert(nibble_from_string(buf) < 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<verify>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  nopl   0x0(%rax)
L1:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <to_bin_naive@plt>
  mov    %r12,%rdi
  call   <nibble_from_string@plt>
  mov    %ebx,%esi
  mov    %r12,%rdx
  mov    %r13,%rdi
  mov    %eax,%ebp
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %edi,%edi
  cmp    %ebx,%ebp
  sete   %dil
  add    $0x1,%ebx
  call   <assert@plt>
  cmp    $0x10,%ebx
  jne    L1
  mov    %r12,%rdi
  movb   $0x3f,0x3(%rsp)
  call   <nibble_from_string@plt>
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %d => '%s' => %d


assistant: ```c
void verify() {
  char buf[5];
  for (int x = 0; x < 16; x++) {
    to_bin_naive(x, buf);
    const int parsed = nibble_from_string(buf);
    printf("%d => '%s' => %d\n", x, buf, parsed);
    assert(x == parsed);
  }
  buf[0] = '?';
  assert(nibble_from_string(buf) < 0);
}
```