ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x64,-0x28(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movq   $0x40000000,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x28(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movb   $0x0,-0x29(%rbp)
  movsbl -0x29(%rbp),%eax
  mov    -0x28(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: f64
name: retrieve_data
arguments: tag: D21
datatype: string
name: retrieve_data
arguments: tag: D15
datatype: string
name: retrieve_data
arguments: tag: D29
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string

tool: D1: 1.2

tool: D21: you havge %d bugs at the imaginary rate of %f.


tool: D15: The entire universe has %ld bugs.


tool: D29: You are expected to have %f bugs.


tool: D39: That is only a %e portion of the universe.


tool: D8: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("you havge %d bugs at the imaginary rate of %f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 1024L * 1024L * 1024L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You are expected to have %f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D54(%rip),%xmm0
  mov    $0x64,%esi
  lea    D8(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x40000000,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x78,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D54
type: f64
name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D16
type: string
name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D54: 1.2

tool: D8: you havge %d bugs at the imaginary rate of %f.


tool: D21: The entire universe has %ld bugs.


tool: D16: You are expected to have %f bugs.


tool: D14: That is only a %e portion of the universe.


tool: D9: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("you havge %d bugs at the imaginary rate of %f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 1024L * 1024L * 1024L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You are expected to have %f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x1,%eax
  movsd  D13(%rip),%xmm0
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0x40000000,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x78,%esi
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: f64
name: parse_data
arguments: label: D48
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D58
type_infered: string
name: parse_data
arguments: label: D28
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string

tool: D13: 1.2

tool: D48: you havge %d bugs at the imaginary rate of %f.


tool: D8: The entire universe has %ld bugs.


tool: D58: You are expected to have %f bugs.


tool: D28: That is only a %e portion of the universe.


tool: D20: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("you havge %d bugs at the imaginary rate of %f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 1024L * 1024L * 1024L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You are expected to have %f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x1,%eax
  movsd  D53(%rip),%xmm0
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x40000000,%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x78,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D53
type: f64
name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D49
type: string
name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D57
type: string
name: parse_data
arguments: data_label: D50
type: string

tool: D53: 1.2

tool: D22: you havge %d bugs at the imaginary rate of %f.


tool: D49: The entire universe has %ld bugs.


tool: D7: You are expected to have %f bugs.


tool: D57: That is only a %e portion of the universe.


tool: D50: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("you havge %d bugs at the imaginary rate of %f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 1024L * 1024L * 1024L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You are expected to have %f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D26
data_type: string
name: unpack_data
arguments: data_tag: D21
data_type: string

tool: D26: %f

tool: D21: %f + %f = %f 


assistant: ```c
int main(void) {
  float a;
  float b;
  scanf("%f", &a);
  scanf("%f", &b);
  printf("%f + %f = %f \n", a, b, a + b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  movaps %xmm0,%xmm2
  addss  %xmm1,%xmm2
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
type: string
name: parse_data
arguments: tag: D18
type: string

tool: D13: %f

tool: D18: %f + %f = %f 


assistant: ```c
int main(void) {
  float a;
  float b;
  scanf("%f", &a);
  scanf("%f", &b);
  printf("%f + %f = %f \n", a, b, a + b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  lea    D16(%rip),%rdi
  movaps %xmm0,%xmm2
  addss  %xmm1,%xmm2
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string

tool: D0: %f

tool: D16: %f + %f = %f 


assistant: ```c
int main(void) {
  float a;
  float b;
  scanf("%f", &a);
  scanf("%f", &b);
  printf("%f + %f = %f \n", a, b, a + b);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  lea    D0(%rip),%rdi
  movaps %xmm0,%xmm2
  addss  %xmm1,%xmm2
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D0
type: string

tool: D4: %f

tool: D0: %f + %f = %f 


assistant: ```c
int main(void) {
  float a;
  float b;
  scanf("%f", &a);
  scanf("%f", &b);
  printf("%f + %f = %f \n", a, b, a + b);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<csi_dcache_clean_invalid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <__DSB@plt>
  mov    $0x0,%eax
  call   <__ISB@plt>
  mov    $0x0,%eax
  call   <__DCACHE_CIALL@plt>
  mov    $0x0,%eax
  call   <__DSB@plt>
  mov    $0x0,%eax
  call   <__ISB@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void csi_dcache_clean_invalid(void) {
  __DSB();
  __ISB();
  __DCACHE_CIALL();
  __DSB();
  __ISB();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<csi_dcache_clean_invalid>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__DSB@plt>
  mov    $0x0,%eax
  call   <__ISB@plt>
  mov    $0x0,%eax
  call   <__DCACHE_CIALL@plt>
  mov    $0x0,%eax
  call   <__DSB@plt>
  mov    $0x0,%eax
  call   <__ISB@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void csi_dcache_clean_invalid(void) {
  __DSB();
  __ISB();
  __DCACHE_CIALL();
  __DSB();
  __ISB();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csi_dcache_clean_invalid>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__DSB@plt>
  xor    %eax,%eax
  call   <__ISB@plt>
  xor    %eax,%eax
  call   <__DCACHE_CIALL@plt>
  xor    %eax,%eax
  call   <__DSB@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <__ISB@plt>
```

assistant: ```c
void csi_dcache_clean_invalid(void) {
  __DSB();
  __ISB();
  __DCACHE_CIALL();
  __DSB();
  __ISB();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<csi_dcache_clean_invalid>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__DSB@plt>
  xor    %eax,%eax
  call   <__ISB@plt>
  xor    %eax,%eax
  call   <__DCACHE_CIALL@plt>
  xor    %eax,%eax
  call   <__DSB@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <__ISB@plt>
```

assistant: ```c
void csi_dcache_clean_invalid(void) {
  __DSB();
  __ISB();
  __DCACHE_CIALL();
  __DSB();
  __ISB();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4c(%rbp)
  jmp    L109
L34:
  cmpb   $0x2f,-0x51(%rbp)
  jle    L141
  cmpb   $0x39,-0x51(%rbp)
  jle    L128
L141:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L87
L128:
  movsbl -0x51(%rbp),%eax
  lea    -0x30(%rax),%edx
  mov    -0x4c(%rbp),%eax
  cltq
  mov    %edx,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x4c(%rbp)
L109:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x51(%rbp)
  cmpb   $0xa,-0x51(%rbp)
  jne    L34
  movl   $0x1,-0x44(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L40
L39:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x48(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L13
  addl   $0x1,-0x44(%rbp)
L13:
  addl   $0x1,-0x48(%rbp)
L40:
  mov    -0x4c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x48(%rbp)
  jl     L39
  mov    -0x44(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jne    L53
  cmpl   $0x1,-0x4c(%rbp)
  je     L53
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L87
L53:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L86
L10:
  mov    -0x4c(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    -0x50(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x50(%rbp)
L86:
  mov    -0x4c(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <nextPermutation@plt>
  test   %rax,%rax
  je     L80
  mov    -0x50(%rbp),%eax
  test   %eax,%eax
  jg     L10
L80:
  mov    $0x0,%eax
L87:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D20
type_guessed: string

tool: D1: bad input

tool: D20: %d

assistant: ```c
int main() {
  int numberArray[11];
  int numberSize = 0;
  int i;
  char n;
  while ((n = getchar()) != '\n') {
    if ((n < '0') || (n > '9')) {
      printf("bad input");
      return 0;
    }
    numberArray[numberSize] = n - '0';
    numberSize++;
  }
  int equality = 1;
  for (i = 0; i < numberSize - 1; i++)
    if (numberArray[i] == numberArray[i + 1])
      equality++;
  if (equality == numberSize) {
    if (numberSize != 1) {
      printf("bad input");
      return 0;
    }
  }
  int repeat;
  scanf("%d", &repeat);
  while ((nextPermutation(numberArray, numberSize)) && (repeat > 0)) {
    printArray(numberArray, numberSize);
    repeat--;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  jmp    L8
L105:
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
L8:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L110
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L105
  lea    D22(%rip),%rdi
  call   <printf@plt>
L15:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L110:
  cmp    $0x1,%ebx
  jle    L24
  lea    0x10(%rsp),%rax
  lea    -0x2(%rbx),%edx
  lea    0x14(%rsp,%rdx,4),%rsi
  mov    $0x1,%edx
L77:
  mov    0x4(%rax),%ecx
  cmp    %ecx,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L77
L103:
  cmp    $0x1,%ebp
  je     L14
  cmp    %edx,%ebp
  je     L85
L14:
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
L125:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <nextPermutation@plt>
  test   %rax,%rax
  je     L15
  cmpl   $0x0,0xc(%rsp)
  jle    L15
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  subl   $0x1,0xc(%rsp)
  jmp    L125
L24:
  mov    $0x1,%edx
  jmp    L103
L85:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
type_guessed: string
name: read_data
arguments: data_label: D0
type_guessed: string

tool: D22: bad input

tool: D0: %d

assistant: ```c
int main() {
  int numberArray[11];
  int numberSize = 0;
  int i;
  char n;
  while ((n = getchar()) != '\n') {
    if ((n < '0') || (n > '9')) {
      printf("bad input");
      return 0;
    }
    numberArray[numberSize] = n - '0';
    numberSize++;
  }
  int equality = 1;
  for (i = 0; i < numberSize - 1; i++)
    if (numberArray[i] == numberArray[i + 1])
      equality++;
  if (equality == numberSize) {
    if (numberSize != 1) {
      printf("bad input");
      return 0;
    }
  }
  int repeat;
  scanf("%d", &repeat);
  while ((nextPermutation(numberArray, numberSize)) && (repeat > 0)) {
    printArray(numberArray, numberSize);
    repeat--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  jmp    L75
  xchg   %ax,%ax
L60:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L68
  movsbl %al,%eax
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
L75:
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L60
  cmp    $0x1,%ebx
  jle    L101
  lea    -0x2(%rbx),%ecx
  mov    0x10(%rsp),%edx
  lea    0x14(%rsp),%rax
  lea    0x18(%rsp,%rcx,4),%rdi
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %edx,%esi
  mov    (%rax),%edx
  cmp    %esi,%edx
  sete   %sil
  add    $0x4,%rax
  movzbl %sil,%esi
  add    %esi,%ecx
  cmp    %rdi,%rax
  jne    L16
L2:
  cmp    %ecx,%ebp
  jne    L53
  cmp    $0x1,%ebp
  jne    L68
L53:
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L61:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L3
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  subl   $0x1,0xc(%rsp)
L59:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <nextPermutation@plt>
  test   %rax,%rax
  jne    L61
  jmp    L3
L68:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L3:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L101:
  mov    $0x1,%ecx
  jmp    L2
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D8
type: string

tool: D0: %d

tool: D8: bad input

assistant: ```c
int main() {
  int numberArray[11];
  int numberSize = 0;
  int i;
  char n;
  while ((n = getchar()) != '\n') {
    if ((n < '0') || (n > '9')) {
      printf("bad input");
      return 0;
    }
    numberArray[numberSize] = n - '0';
    numberSize++;
  }
  int equality = 1;
  for (i = 0; i < numberSize - 1; i++)
    if (numberArray[i] == numberArray[i + 1])
      equality++;
  if (equality == numberSize) {
    if (numberSize != 1) {
      printf("bad input");
      return 0;
    }
  }
  int repeat;
  scanf("%d", &repeat);
  while ((nextPermutation(numberArray, numberSize)) && (repeat > 0)) {
    printArray(numberArray, numberSize);
    repeat--;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parseLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L9:
  cmp    %rdx,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L9
L12:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L23
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L23:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  lea    -0x30(%rbp),%rsi
  lea    -0x34(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rsi,%r8
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x30(%rbp),%ecx
  mov    -0x34(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <executeDll@plt>
  lea    -0x35(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  mov    %eax,-0x2c(%rbp)
  movzbl -0x35(%rbp),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x2c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <executeGpl@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D15
type: string

tool: D10: %s %d %d

tool: D15: %s %c

assistant: ```c
void parseLine(char *line, size_t *nbytes) {
  int nargs;
  char command[*nbytes], c;
  int a1 = 0, a2 = 0;
  nargs = sscanf(line, "%s %d %d", command, &a1, &a2);
  executeDll(nargs, command, a1, a2);
  nargs = sscanf(line, "%s %c", command, &c);
  executeGpl(nargs, command, c);
}
```