ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<typset_add>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <typ_is_tentative@plt>
  test   %rax,%rax
  jne    L25
  mov    %rbx,%rdi
  call   <typ_hash_ready@plt>
  test   %eax,%eax
  jne    L20
L25:
  mov    %rbx,%rdi
  call   <typ_permanent_loc@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <add_tentative@plt>
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <add_final@plt>
  jmp    L15
```

assistant: ```c
void typset_add(struct typset *set, struct typ *t) {
  if (typ_is_tentative(t) || !typ_hash_ready(t)) {
    add_tentative(set, typ_permanent_loc(t));
  } else {
    add_final(set, t);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<typset_add>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <typ_is_tentative@plt>
  test   %rax,%rax
  jne    L14
  mov    %rbp,%rdi
  call   <typ_hash_ready@plt>
  test   %eax,%eax
  jne    L15
L14:
  mov    %rbp,%rdi
  call   <typ_permanent_loc@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    10a0 <add_tentative@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <add_final@plt>
```

assistant: ```c
void typset_add(struct typset *set, struct typ *t) {
  if (typ_is_tentative(t) || !typ_hash_ready(t)) {
    add_tentative(set, typ_permanent_loc(t));
  } else {
    add_final(set, t);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<typset_add>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <typ_is_tentative@plt>
  test   %rax,%rax
  jne    L0
  mov    %rbp,%rdi
  call   <typ_hash_ready@plt>
  test   %eax,%eax
  jne    L15
L0:
  mov    %rbp,%rdi
  call   <typ_permanent_loc@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    10a0 <add_tentative@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <add_final@plt>
```

assistant: ```c
void typset_add(struct typset *set, struct typ *t) {
  if (typ_is_tentative(t) || !typ_hash_ready(t)) {
    add_tentative(set, typ_permanent_loc(t));
  } else {
    add_final(set, t);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<count_nodes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L28
L30:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L35
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L19
  addl   $0x1,-0xc(%rbp)
L19:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0xc(%rbp),%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int count_nodes(char *path) {
  int i;
  char *tmp;
  if (!path)
    return 0;
  for (i = 0, tmp = path; *tmp != '\0'; tmp++)
    if (*tmp == '/')
      i++;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<count_nodes>:
  endbr64
  test   %rdi,%rdi
  je     L35
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  mov    $0x0,%edx
L31:
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L31
L44:
  mov    %edx,%eax
  ret
L35:
  mov    $0x0,%edx
  jmp    L44
L18:
  mov    $0x0,%edx
  jmp    L44
```

assistant: ```c
int count_nodes(char *path) {
  int i;
  char *tmp;
  if (!path)
    return 0;
  for (i = 0, tmp = path; *tmp != '\0'; tmp++)
    if (*tmp == '/')
      i++;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_nodes>:
  endbr64
  test   %rdi,%rdi
  je     L6
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L20
  nopl   0x0(%rax,%rax,1)
L17:
  cmp    $0x2f,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L17
L20:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_nodes(char *path) {
  int i;
  char *tmp;
  if (!path)
    return 0;
  for (i = 0, tmp = path; *tmp != '\0'; tmp++)
    if (*tmp == '/')
      i++;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_nodes>:
  endbr64
  test   %rdi,%rdi
  je     L17
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L23
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    $0x2f,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
L23:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_nodes(char *path) {
  int i;
  char *tmp;
  if (!path)
    return 0;
  for (i = 0, tmp = path; *tmp != '\0'; tmp++)
    if (*tmp == '/')
      i++;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strrep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <is_subst_here@plt>
  test   %rax,%rax
  je     L0
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <replst@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,-0x8(%rbp)
L0:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L14
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int strrep(char *str, const char *srch, const char *repl) {
  int i, n = strlen(str);
  for (i = 0; i < n; i++) {
    if (is_subst_here(&str[i], srch)) {
      replst(str, i, strlen(srch), repl);
      i += strlen(repl);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strrep>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r14
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  mov    %eax,%r13d
  mov    $0x0,%ebx
  jmp    L21
L48:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jle    L4
L21:
  movslq %ebx,%rdi
  add    %rbp,%rdi
  mov    %r12,%rsi
  call   <is_subst_here@plt>
  test   %rax,%rax
  je     L48
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r14,%rcx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <replst@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  jmp    L48
L4:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strrep(char *str, const char *srch, const char *repl) {
  int i, n = strlen(str);
  for (i = 0; i < n; i++) {
    if (is_subst_here(&str[i], srch)) {
      replst(str, i, strlen(srch), repl);
      i += strlen(repl);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strrep>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L32
  mov    %eax,%r13d
  xor    %ebx,%ebx
  jmp    L2
  nopl   (%rax)
L38:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jle    L32
L2:
  movslq %ebx,%rdi
  mov    %r12,%rsi
  add    %rbp,%rdi
  call   <is_subst_here@plt>
  test   %rax,%rax
  je     L38
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebx,%esi
  mov    %r14,%rcx
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <replst@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jg     L2
L32:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strrep(char *str, const char *srch, const char *repl) {
  int i, n = strlen(str);
  for (i = 0; i < n; i++) {
    if (is_subst_here(&str[i], srch)) {
      replst(str, i, strlen(srch), repl);
      i += strlen(repl);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strrep>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L19
  mov    %eax,%r13d
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L3:
  movslq %ebx,%rdi
  mov    %r12,%rsi
  add    %rbp,%rdi
  call   <is_subst_here@plt>
  test   %rax,%rax
  jne    L6
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jg     L3
L19:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L6:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebx,%esi
  mov    %r14,%rcx
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <replst@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%ebx
  cmp    %r13d,%ebx
  jl     L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strrep(char *str, const char *srch, const char *repl) {
  int i, n = strlen(str);
  for (i = 0; i < n; i++) {
    if (is_subst_here(&str[i], srch)) {
      replst(str, i, strlen(srch), repl);
      i += strlen(repl);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rotate2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  jmp    L25
L8:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L29:
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L29
  mov    -0x20(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
L25:
  mov    -0x20(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void rotate2(int *nums, int size, int k) {
  for (; k %= size; size -= k, nums += k)
    for (int i = 0; i < k; i++)
      swap(nums + i, nums + size - k + i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotate2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r14d
  mov    %edx,%eax
  cltd
  idiv   %esi
  mov    %edx,%r13d
  test   %edx,%edx
  jne    L26
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    %r15,%rbx
  lea    -0x1(%r13),%eax
  lea    0x4(%r15,%rax,4),%r12
  movslq %r13d,%rax
  movslq %r14d,%rbp
  sub    %rax,%rbp
  shl    $0x2,%rbp
L0:
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    %rbx,%rdi
  call   <swap@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
L10:
  sub    %r13d,%r14d
  movslq %r13d,%rax
  lea    (%r15,%rax,4),%r15
  mov    %r13d,%eax
  cltd
  idiv   %r14d
  mov    %edx,%r13d
  test   %edx,%edx
  je     L15
L26:
  test   %r13d,%r13d
  jg     L25
  jmp    L10
```

assistant: ```c
void rotate2(int *nums, int size, int k) {
  for (; k %= size; size -= k, nums += k)
    for (int i = 0; i < k; i++)
      swap(nums + i, nums + size - k + i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rotate2>:
  endbr64
  mov    %edx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L0
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L30:
  movslq %r12d,%rax
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  jle    L7
  lea    -0x1(%r12),%eax
  movslq %r13d,%rbx
  sub    0x8(%rsp),%rbx
  mov    %r14,%r15
  lea    0x4(%r14,%rax,4),%rbp
  shl    $0x2,%rbx
  cs nopw 0x0(%rax,%rax,1)
L25:
  lea    (%rbx,%r15,1),%rsi
  mov    %r15,%rdi
  add    $0x4,%r15
  call   <swap@plt>
  cmp    %rbp,%r15
  jne    L25
L7:
  mov    0x8(%rsp),%rax
  sub    %r12d,%r13d
  lea    (%r14,%rax,4),%r14
  mov    %r12d,%eax
  cltd
  idiv   %r13d
  mov    %edx,%r12d
  test   %edx,%edx
  jne    L30
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  ret
```

assistant: ```c
void rotate2(int *nums, int size, int k) {
  for (; k %= size; size -= k, nums += k)
    for (int i = 0; i < k; i++)
      swap(nums + i, nums + size - k + i);
}
```
user: What is the c source code of the assembly code below:

```asm
<rotate2>:
  endbr64
  mov    %edx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L24
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  movslq %r12d,%rax
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  jle    L36
  lea    -0x1(%r12),%eax
  movslq %r13d,%rbx
  sub    0x8(%rsp),%rbx
  mov    %r14,%r15
  lea    0x4(%r14,%rax,4),%rbp
  shl    $0x2,%rbx
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    (%r15,%rbx,1),%rsi
  mov    %r15,%rdi
  add    $0x4,%r15
  call   <swap@plt>
  cmp    %r15,%rbp
  jne    L6
L36:
  mov    0x8(%rsp),%rax
  sub    %r12d,%r13d
  lea    (%r14,%rax,4),%r14
  mov    %r12d,%eax
  cltd
  idiv   %r13d
  mov    %edx,%r12d
  test   %edx,%edx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  ret
```

assistant: ```c
void rotate2(int *nums, int size, int k) {
  for (; k %= size; size -= k, nums += k)
    for (int i = 0; i < k; i++)
      swap(nums + i, nums + size - k + i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cbFix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%r12d
  mov    $0x92003,%r13d
  jmp    L36
L29:
  movb   $0x3,(%rbx,%r12,1)
L110:
  cmp    $0x55,%al
  jne    L109
  movb   $0x25,(%rbx,%r12,1)
L62:
  cmp    $0x52,%al
  jne    L87
  movb   $0x1a,(%rbx,%r12,1)
  jmp    L87
L57:
  add    $0x1,%rbp
  movzbl (%rbx,%rbp,1),%eax
  mov    %al,-0x1(%rbx,%rbp,1)
L87:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmp    %rbp,%rax
  ja     L57
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
L61:
  add    $0x1,%r12
L36:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmp    %r12,%rax
  jbe    L106
  cmpb   $0x25,(%rbx,%r12,1)
  jne    L61
  lea    0x1(%r12),%rbp
  movzbl 0x1(%rbx,%r12,1),%eax
  lea    -0x42(%rax),%edx
  cmp    $0x13,%dl
  ja     L61
  bt     %rdx,%r13
  jae    L61
  cmp    $0x43,%al
  je     L29
  cmp    $0x42,%al
  jne    L110
  movb   $0x2,(%rbx,%r12,1)
L109:
  cmp    $0x4f,%al
  jne    L62
  movb   $0x11,(%rbx,%r12,1)
  jmp    L87
L106:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void cbFix(char *line) {
  size_t i;
  for (i = 0; i < strlen(line); i++) {
    size_t j;
    if (line[i] == '%') {
      if ((line[i + 1] == 'C') || (line[i + 1] == 'B') || (line[i + 1] == 'U') || (line[i + 1] == 'O') || (line[i + 1] == 'R')) {
        if (line[i + 1] == 'C')
          line[i] = 3;
        if (line[i + 1] == 'B')
          line[i] = 2;
        if (line[i + 1] == 'U')
          line[i] = 37;
        if (line[i + 1] == 'O')
          line[i] = 17;
        if (line[i + 1] == 'R')
          line[i] = 26;
        for (j = i + 1; j < strlen(line) - 1; j++) {
          line[j] = line[j + 1];
        }
        line[strlen(line) - 1] = 0;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cbFix>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L106:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmp    %r12,%rax
  jbe    L92
L57:
  movzbl (%rbx,%r12,1),%eax
  add    $0x1,%r12
  cmp    $0x25,%al
  jne    L106
  movzbl (%rbx,%r12,1),%eax
  lea    -0x42(%rax),%edx
  cmp    $0x1,%dl
  jbe    L174
  cmp    $0x55,%al
  je     L174
  cmp    $0x52,%al
  je     L56
  cmp    $0x4f,%al
  jne    L106
L176:
  movb   $0x11,-0x1(%rbx,%r12,1)
L140:
  mov    %r12,%rbp
  jmp    L13
L109:
  add    $0x1,%rbp
  movzbl (%rbx,%rbp,1),%eax
  mov    %al,-0x1(%rbx,%rbp,1)
L13:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmp    %rbp,%rax
  ja     L109
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  call   <strlen@plt>
  cltq
  cmp    %r12,%rax
  ja     L57
L92:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L174:
  cmp    $0x43,%al
  jne    L169
  movb   $0x3,-0x1(%rbx,%r12,1)
  jmp    L140
  nopl   0x0(%rax)
L56:
  cmp    $0x4f,%al
  je     L176
  cmp    $0x52,%al
  jne    L140
  movb   $0x1a,-0x1(%rbx,%r12,1)
  jmp    L140
  nopl   0x0(%rax,%rax,1)
L169:
  cmp    $0x42,%al
  jne    L154
  movb   $0x2,-0x1(%rbx,%r12,1)
  jmp    L140
L154:
  cmp    $0x55,%al
  jne    L56
  movb   $0x25,-0x1(%rbx,%r12,1)
  jmp    L140
```

assistant: ```c
void cbFix(char *line) {
  size_t i;
  for (i = 0; i < strlen(line); i++) {
    size_t j;
    if (line[i] == '%') {
      if ((line[i + 1] == 'C') || (line[i + 1] == 'B') || (line[i + 1] == 'U') || (line[i + 1] == 'O') || (line[i + 1] == 'R')) {
        if (line[i + 1] == 'C')
          line[i] = 3;
        if (line[i + 1] == 'B')
          line[i] = 2;
        if (line[i + 1] == 'U')
          line[i] = 37;
        if (line[i + 1] == 'O')
          line[i] = 17;
        if (line[i + 1] == 'R')
          line[i] = 26;
        for (j = i + 1; j < strlen(line) - 1; j++) {
          line[j] = line[j + 1];
        }
        line[strlen(line) - 1] = 0;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cbFix>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L75:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmp    %r12,%rax
  jbe    L130
L109:
  movzbl (%rbx,%r12,1),%eax
  add    $0x1,%r12
  cmp    $0x25,%al
  jne    L75
  movzbl (%rbx,%r12,1),%eax
  lea    -0x42(%rax),%edx
  cmp    $0x1,%dl
  jbe    L110
  cmp    $0x55,%al
  je     L110
  cmp    $0x52,%al
  je     L45
  cmp    $0x4f,%al
  jne    L75
L74:
  movb   $0x11,-0x1(%rbx,%r12,1)
L123:
  mov    %r12,%rbp
  jmp    L121
L129:
  add    $0x1,%rbp
  movzbl (%rbx,%rbp,1),%eax
  mov    %al,-0x1(%rbx,%rbp,1)
L121:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmp    %rbp,%rax
  ja     L129
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  call   <strlen@plt>
  cltq
  cmp    %r12,%rax
  ja     L109
L130:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L110:
  cmp    $0x43,%al
  jne    L60
  movb   $0x3,-0x1(%rbx,%r12,1)
  jmp    L123
  nopl   0x0(%rax)
L45:
  cmp    $0x4f,%al
  je     L74
  cmp    $0x52,%al
  jne    L123
  movb   $0x1a,-0x1(%rbx,%r12,1)
  jmp    L123
  nopl   0x0(%rax,%rax,1)
L60:
  cmp    $0x42,%al
  jne    L23
  movb   $0x2,-0x1(%rbx,%r12,1)
  jmp    L123
L23:
  cmp    $0x55,%al
  jne    L45
  movb   $0x25,-0x1(%rbx,%r12,1)
  jmp    L123
```

assistant: ```c
void cbFix(char *line) {
  size_t i;
  for (i = 0; i < strlen(line); i++) {
    size_t j;
    if (line[i] == '%') {
      if ((line[i + 1] == 'C') || (line[i + 1] == 'B') || (line[i + 1] == 'U') || (line[i + 1] == 'O') || (line[i + 1] == 'R')) {
        if (line[i + 1] == 'C')
          line[i] = 3;
        if (line[i + 1] == 'B')
          line[i] = 2;
        if (line[i + 1] == 'U')
          line[i] = 37;
        if (line[i + 1] == 'O')
          line[i] = 17;
        if (line[i + 1] == 'R')
          line[i] = 26;
        for (j = i + 1; j < strlen(line) - 1; j++) {
          line[j] = line[j + 1];
        }
        line[strlen(line) - 1] = 0;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strnappend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L102
  cmpq   $0x0,-0x20(%rbp)
  jne    L102
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L74
L102:
  cmpq   $0x0,-0x18(%rbp)
  jne    L57
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strndup@plt>
  jmp    L74
L57:
  cmpq   $0x0,-0x20(%rbp)
  jne    L46
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L74
L46:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  not    %rax
  cmp    %rax,-0x28(%rbp)
  jbe    L53
  mov    $0x0,%eax
  jmp    L74
L53:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L67
  mov    $0x0,%eax
  jmp    L74
L67:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L74:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: 

assistant: ```c
char *strnappend(const char *s, const char *suffix, size_t b) {
  size_t a;
  char *r;
  if (!s && !suffix)
    return strdup("");
  if (!s)
    return strndup(suffix, b);
  if (!suffix)
    return strdup(s);
  assert(s);
  assert(suffix);
  a = strlen(s);
  if (b > ((size_t)-1) - a)
    return NULL;
  r = ((char *)malloc(sizeof(char) * (a + b + 1)));
  if (!r)
    return NULL;
  memcpy(r, s, a);
  memcpy(r + a, suffix, b);
  r[a + b] = 0;
  return r;
}
```