user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L73
L79:
  mov    -0x44(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <to_edge@plt>
  mov    %eax,%esi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x9,%edx
  jne    L88
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L88:
  addl   $0x1,-0x44(%rbp)
L73:
  cmpl   $0x19a0,-0x44(%rbp)
  jle    L79
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L45
L35:
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L34
L39:
  mov    -0x44(%rbp),%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L30
  lea    (%rbx,%rbx,1),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %eax,%r12d
L30:
  add    $0x1,%ebx
L34:
  cmp    $0x7,%ebx
  jle    L39
  mov    %r12d,%esi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x9,%edx
  jne    L91
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L91:
  addl   $0x1,-0x44(%rbp)
L45:
  cmpl   $0xff,-0x44(%rbp)
  jle    L35
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  add    $0x40,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D68
data_type: string
name: unpack_data
arguments: data_label: D79
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string
name: unpack_data
arguments: data_label: D9
data_type: string
name: unpack_data
arguments: data_label: D11
data_type: string
name: unpack_data
arguments: data_label: D25
data_type: string

tool: D68: unsigned short Edge_To_Quat[6561] = 
{
    

tool: D79:  %5u,

tool: D16: 
    

tool: D9: 
};


tool: D11: unsigned short String_To_Quat[256] = 
{
    

tool: D25: 
};

assistant: ```c
main() {
  int edge[8], i;
  printf("unsigned short Edge_To_Quat[6561] = \n{\n    ");
  for (i = 0; i < 6561; i++) {
    printf(" %5u,", to_edge(edge, i));
    if (i % 10 == 9)
      printf("\n    ");
  }
  printf("\n};\n\n");
  printf("unsigned short String_To_Quat[256] = \n{\n    ");
  for (i = 0; i < 256; i++) {
    register j, total;
    total = 0;
    for (j = 0; j < 8; j++)
      if (((i >> j) & 1) == 1)
        total += 1 << (2 * j);
    printf(" %5u,", total);
    if (i % 10 == 9)
      printf("\n    ");
  }
  printf("\n};\n");
  return 0;
}
```