ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<G_NewString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <G_Alloc@plt>
  test   %r12d,%r12d
  jle    L47
  mov    %rax,%rsi
  xor    %edx,%edx
  mov    $0x5c,%r10d
  mov    $0xa,%r9d
  nopl   0x0(%rax)
L42:
  movslq %edx,%rcx
  mov    %rsi,%r8
  add    $0x1,%rsi
  movzbl 0x0(%rbp,%rcx,1),%edi
  cmp    %edx,%ebx
  jle    L7
  cmp    $0x5c,%dil
  je     L30
L7:
  mov    %edx,%ecx
L28:
  mov    %dil,(%r8)
  lea    0x1(%rcx),%edx
  cmp    %ecx,%ebx
  jg     L42
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  lea    0x1(%rdx),%ecx
  mov    %r9d,%edi
  movslq %ecx,%rdx
  cmpb   $0x6e,0x0(%rbp,%rdx,1)
  cmovne %r10d,%edi
  jmp    L28
```

assistant: ```c
char *G_NewString(const char *string) {
  char *newb, *new_p;
  int i, l;
  l = strlen(string) + 1;
  newb = (char *)G_Alloc(l);
  new_p = newb;
  for (i = 0; i < l; i++) {
    if (string[i] == '\\' && i < l - 1) {
      i++;
      if (string[i] == 'n') {
        *new_p++ = '\n';
      } else {
        *new_p++ = '\\';
      }
    } else {
      *new_p++ = string[i];
    }
  }
  return newb;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<G_NewString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <G_Alloc@plt>
  test   %r12d,%r12d
  jle    L11
  mov    %rax,%rsi
  xor    %edx,%edx
  mov    $0xa,%r10d
  mov    $0x5c,%r9d
  nopl   0x0(%rax)
L48:
  movslq %edx,%rcx
  mov    %rsi,%r8
  add    $0x1,%rsi
  movzbl 0x0(%rbp,%rcx,1),%edi
  cmp    %edx,%ebx
  jle    L25
  cmp    $0x5c,%dil
  je     L21
L25:
  mov    %edx,%ecx
L40:
  mov    %dil,(%r8)
  lea    0x1(%rcx),%edx
  cmp    %ecx,%ebx
  jg     L48
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  lea    0x1(%rdx),%ecx
  mov    %r9d,%edi
  movslq %ecx,%rdx
  cmpb   $0x6e,0x0(%rbp,%rdx,1)
  cmove  %r10d,%edi
  jmp    L40
```

assistant: ```c
char *G_NewString(const char *string) {
  char *newb, *new_p;
  int i, l;
  l = strlen(string) + 1;
  newb = (char *)G_Alloc(l);
  new_p = newb;
  for (i = 0; i < l; i++) {
    if (string[i] == '\\' && i < l - 1) {
      i++;
      if (string[i] == 'n') {
        *new_p++ = '\n';
      } else {
        *new_p++ = '\\';
      }
    } else {
      *new_p++ = string[i];
    }
  }
  return newb;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L33:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L29
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L1
L29:
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0xf423f,-0x4(%rbp)
  jle    L33
  nop
L1:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertArray(char *data, int *wordNumber, int *wordNumberArray, char **wordArray) {
  int i;
  for (i = 0; i < 1000000; i++) {
    if (*(wordNumberArray + i) == -1) {
      *(wordNumberArray + i) = *wordNumber;
      *(wordArray + i) = data;
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertArray>:
  endbr64
  mov    $0x0,%eax
L12:
  mov    %rdx,%r8
  cmpl   $0xffffffff,(%rdx)
  je     L19
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    $0xf4240,%rax
  jne    L12
  ret
L19:
  mov    (%rsi),%edx
  mov    %edx,(%r8)
  mov    %rdi,(%rcx,%rax,8)
  ret
```

assistant: ```c
void insertArray(char *data, int *wordNumber, int *wordNumberArray, char **wordArray) {
  int i;
  for (i = 0; i < 1000000; i++) {
    if (*(wordNumberArray + i) == -1) {
      *(wordNumberArray + i) = *wordNumber;
      *(wordArray + i) = data;
      break;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<insertArray>:
  endbr64
  xor    %eax,%eax
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    $0xf4240,%rax
  je     L22
L21:
  cmpl   $0xffffffff,(%rdx)
  jne    L26
  mov    (%rsi),%esi
  mov    %esi,(%rdx)
  mov    %rdi,(%rcx,%rax,8)
  ret
  xchg   %ax,%ax
L22:
  ret
```

assistant: ```c
void insertArray(char *data, int *wordNumber, int *wordNumberArray, char **wordArray) {
  int i;
  for (i = 0; i < 1000000; i++) {
    if (*(wordNumberArray + i) == -1) {
      *(wordNumberArray + i) = *wordNumber;
      *(wordArray + i) = data;
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insertArray>:
  endbr64
  xor    %eax,%eax
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    $0xf4240,%rax
  je     L10
L15:
  cmpl   $0xffffffff,(%rdx)
  jne    L25
  mov    (%rsi),%esi
  mov    %esi,(%rdx)
  mov    %rdi,(%rcx,%rax,8)
  ret
  xchg   %ax,%ax
L10:
  ret
```

assistant: ```c
void insertArray(char *data, int *wordNumber, int *wordNumberArray, char **wordArray) {
  int i;
  for (i = 0; i < 1000000; i++) {
    if (*(wordNumberArray + i) == -1) {
      *(wordNumberArray + i) = *wordNumber;
      *(wordArray + i) = data;
      break;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,%edx
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int abs(int x) {
  int sign = x >> 31;
  return (x ^ sign) + (1 && sign);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<abs>:
  endbr64
  mov    %edi,%edx
  sar    $0x1f,%edx
  xor    %edx,%edi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int abs(int x) {
  int sign = x >> 31;
  return (x ^ sign) + (1 && sign);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<abs>:
  endbr64
  mov    %edi,%edx
  sar    $0x1f,%edx
  xor    %edx,%edi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int abs(int x) {
  int sign = x >> 31;
  return (x ^ sign) + (1 && sign);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<abs>:
  endbr64
  mov    %edi,%edx
  sar    $0x1f,%edx
  xor    %edx,%edi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int abs(int x) {
  int sign = x >> 31;
  return (x ^ sign) + (1 && sign);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kernel_has_blkgetsize64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <uname@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L92
  mov    $0x0,%eax
  jmp    L99
L92:
  mov    -0x14(%rbp),%eax
  lea    -0x18(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    %rsi,%r8
  lea    D0(%rip),%rsi
  mov    %eax,%edi
  call   <sscanf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x2,-0xc(%rbp)
  jg     L80
  mov    $0x0,%eax
  jmp    L99
L80:
  mov    -0x20(%rbp),%eax
  cmp    $0x2,%eax
  jle    L119
  mov    $0x1,%eax
  jmp    L99
L119:
  mov    -0x20(%rbp),%eax
  cmp    $0x2,%eax
  jne    L55
  mov    -0x1c(%rbp),%eax
  cmp    $0x5,%eax
  jle    L55
  mov    $0x1,%eax
  jmp    L99
L55:
  mov    -0x20(%rbp),%eax
  cmp    $0x2,%eax
  jne    L83
  mov    -0x1c(%rbp),%eax
  cmp    $0x5,%eax
  jne    L83
  mov    -0x18(%rbp),%eax
  cmp    $0x3,%eax
  jle    L83
  mov    $0x1,%eax
  jmp    L99
L83:
  mov    -0x20(%rbp),%eax
  cmp    $0x2,%eax
  jne    L125
  mov    -0x1c(%rbp),%eax
  cmp    $0x4,%eax
  jne    L125
  mov    -0x18(%rbp),%eax
  cmp    $0x11,%eax
  jle    L125
  mov    $0x1,%eax
  jmp    L99
L125:
  mov    $0x0,%eax
L99:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %d.%d.%d

assistant: ```c
int kernel_has_blkgetsize64(void) {
  int major = 0, minor = 0, patch = 0, parsed;
  int rc;
  struct utsname u;
  memset(&u, 0, sizeof(u));
  rc = uname(&u);
  if (rc)
    return 0;
  parsed = sscanf(u.release, "%d.%d.%d", &major, &minor, &patch);
  if (parsed < 3)
    return 0;
  if (major > 2)
    return 1;
  if (major == 2 && minor > 5)
    return 1;
  if (major == 2 && minor == 5 && patch >= 4)
    return 1;
  if (major == 2 && minor == 4 && patch >= 18)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kernel_has_blkgetsize64>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  lea    0x14(%rsp),%rbx
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <uname@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  je     L63
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L63:
  mov    %eax,%ebx
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%r8
  lea    D9(%rip),%rsi
  mov    0x14(%rsp),%edi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jle    L31
  mov    0x8(%rsp),%eax
  cmp    $0x2,%eax
  jg     L34
  jne    L31
  mov    0xc(%rsp),%eax
  cmp    $0x5,%eax
  jg     L26
  je     L38
  cmp    $0x4,%eax
  jne    L31
  cmpl   $0x11,0x10(%rsp)
  setg   %bl
  movzbl %bl,%ebx
  jmp    L31
L38:
  cmpl   $0x3,0x10(%rsp)
  setg   %bl
  movzbl %bl,%ebx
  jmp    L31
L34:
  mov    $0x1,%ebx
  jmp    L31
L26:
  mov    $0x1,%ebx
  jmp    L31
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: %d.%d.%d

assistant: ```c
int kernel_has_blkgetsize64(void) {
  int major = 0, minor = 0, patch = 0, parsed;
  int rc;
  struct utsname u;
  memset(&u, 0, sizeof(u));
  rc = uname(&u);
  if (rc)
    return 0;
  parsed = sscanf(u.release, "%d.%d.%d", &major, &minor, &patch);
  if (parsed < 3)
    return 0;
  if (major > 2)
    return 1;
  if (major == 2 && minor > 5)
    return 1;
  if (major == 2 && minor == 5 && patch >= 4)
    return 1;
  if (major == 2 && minor == 4 && patch >= 18)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kernel_has_blkgetsize64>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x4,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  movl   $0x0,0x8(%rsp)
  mov    %rbp,%rdi
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <uname@plt>
  test   %eax,%eax
  je     L33
L32:
  xor    %eax,%eax
L3:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L84
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L33:
  mov    0x14(%rsp),%edi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%r8
  lea    D9(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jle    L32
  cmpl   $0x2,0x8(%rsp)
  mov    $0x1,%eax
  jg     L3
  jne    L32
  mov    0xc(%rsp),%edx
  cmp    $0x5,%edx
  jg     L3
  je     L2
  cmp    $0x4,%edx
  jne    L32
  xor    %eax,%eax
  cmpl   $0x11,0x10(%rsp)
  setg   %al
  jmp    L3
  xchg   %ax,%ax
L2:
  cmpl   $0x3,0x10(%rsp)
  jle    L32
  jmp    L3
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: D9: %d.%d.%d

assistant: ```c
int kernel_has_blkgetsize64(void) {
  int major = 0, minor = 0, patch = 0, parsed;
  int rc;
  struct utsname u;
  memset(&u, 0, sizeof(u));
  rc = uname(&u);
  if (rc)
    return 0;
  parsed = sscanf(u.release, "%d.%d.%d", &major, &minor, &patch);
  if (parsed < 3)
    return 0;
  if (major > 2)
    return 1;
  if (major == 2 && minor > 5)
    return 1;
  if (major == 2 && minor == 5 && patch >= 4)
    return 1;
  if (major == 2 && minor == 4 && patch >= 18)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kernel_has_blkgetsize64>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x4,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  movl   $0x0,0x8(%rsp)
  mov    %rbp,%rdi
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <uname@plt>
  test   %eax,%eax
  je     L0
L71:
  xor    %eax,%eax
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  mov    0x14(%rsp),%edi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%r8
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jle    L71
  cmpl   $0x2,0x8(%rsp)
  mov    $0x1,%eax
  jg     L16
  jne    L71
  mov    0xc(%rsp),%edx
  cmp    $0x5,%edx
  jg     L16
  je     L89
  cmp    $0x4,%edx
  jne    L71
  xor    %eax,%eax
  cmpl   $0x11,0x10(%rsp)
  setg   %al
  jmp    L16
  xchg   %ax,%ax
L89:
  cmpl   $0x3,0x10(%rsp)
  jle    L71
  jmp    L16
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d.%d.%d

assistant: ```c
int kernel_has_blkgetsize64(void) {
  int major = 0, minor = 0, patch = 0, parsed;
  int rc;
  struct utsname u;
  memset(&u, 0, sizeof(u));
  rc = uname(&u);
  if (rc)
    return 0;
  parsed = sscanf(u.release, "%d.%d.%d", &major, &minor, &patch);
  if (parsed < 3)
    return 0;
  if (major > 2)
    return 1;
  if (major == 2 && minor > 5)
    return 1;
  if (major == 2 && minor == 5 && patch >= 4)
    return 1;
  if (major == 2 && minor == 4 && patch >= 18)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vwarnx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  leave
  ret
```

assistant: ```c
void vwarnx(const char *fmt, va_list args) {
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  abort();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vwarnx>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdi,%rsi
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebx,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void vwarnx(const char *fmt, va_list args) {
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vwarnx>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <abort@plt>
```

assistant: ```c
void vwarnx(const char *fmt, va_list args) {
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<vwarnx>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <abort@plt>
```

assistant: ```c
void vwarnx(const char *fmt, va_list args) {
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  mov    -0x18(%rbp),%rdx
  mov    $0x1,%eax
  sub    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D4: allocation failure in vector

assistant: ```c
float *vector(long nl, long nh) {
  float *v;
  v = (float *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(float)));
  if (!v)
    printf("allocation failure in vector");
  return v - nl + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  sub    %rdi,%rsi
  lea    0x8(,%rsi,4),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
L7:
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    (%rbx,%rax,4),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string

tool: D3: allocation failure in vector

assistant: ```c
float *vector(long nl, long nh) {
  float *v;
  v = (float *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(float)));
  if (!v)
    printf("allocation failure in vector");
  return v - nl + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vector>:
  endbr64
  push   %rbp
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  push   %rbx
  lea    0x8(,%rsi,4),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L15:
  mov    $0x1,%eax
  add    $0x8,%rsp
  sub    %rbp,%rax
  lea    (%rbx,%rax,4),%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: allocation failure in vector

assistant: ```c
float *vector(long nl, long nh) {
  float *v;
  v = (float *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(float)));
  if (!v)
    printf("allocation failure in vector");
  return v - nl + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vector>:
  endbr64
  push   %rbp
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  push   %rbx
  lea    0x8(,%rsi,4),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
L10:
  mov    $0x1,%eax
  add    $0x8,%rsp
  sub    %rbp,%rax
  lea    (%rbx,%rax,4),%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: allocation failure in vector

assistant: ```c
float *vector(long nl, long nh) {
  float *v;
  v = (float *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(float)));
  if (!v)
    printf("allocation failure in vector");
  return v - nl + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <nested@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <different_line@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D46
datatype: string

tool: D46: x = %d


assistant: ```c
int main() {
  int x = 4;
  printf("x = %d\n", x);
  foo(&x);
  printf("x = %d\n", x);
  bar(&x);
  printf("x = %d\n", x);
  nested(&x);
  printf("x = %d\n", x);
  different_line(&x);
  printf("x = %d\n", x);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x4(%rsp)
  mov    $0x4,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <foo@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <nested@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <different_line@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: x = %d


assistant: ```c
int main() {
  int x = 4;
  printf("x = %d\n", x);
  foo(&x);
  printf("x = %d\n", x);
  bar(&x);
  printf("x = %d\n", x);
  nested(&x);
  printf("x = %d\n", x);
  different_line(&x);
  printf("x = %d\n", x);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  movl   $0x4,0x4(%rsp)
  call   <printf@plt>
  mov    %r12,%rdi
  call   <foo@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <nested@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <different_line@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: x = %d


assistant: ```c
int main() {
  int x = 4;
  printf("x = %d\n", x);
  foo(&x);
  printf("x = %d\n", x);
  bar(&x);
  printf("x = %d\n", x);
  nested(&x);
  printf("x = %d\n", x);
  different_line(&x);
  printf("x = %d\n", x);
  return 0;
}
```