user: 这段汇编代码用C语言表示是什么样的：

```asm
<pseudoinverse>:
  endbr64
  push   %r15
  mov    %rdi,%rcx
  mov    %rsi,%r9
  mov    %edx,%r10d
  push   %r14
  pxor   %xmm2,%xmm2
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rdx),%eax
  mov    %rsp,%rdi
  lea    (%rax,%rax,2),%rax
  mov    %rdi,%rbx
  lea    0x18(%rcx,%rax,8),%r8
  mov    %r8,%rsi
L21:
  mov    $0x1,%eax
  movapd %xmm2,%xmm0
  jmp    L70
  nopl   0x0(%rax,%rax,1)
L151:
  add    $0x1,%rax
L70:
  movsd  %xmm0,-0x8(%rbx,%rax,8)
  cmp    $0x6,%rax
  je     L143
  movapd %xmm2,%xmm0
  cmp    %eax,%ebp
  jne    L151
  mov    D9(%rip),%rdx
  movq   %rdx,%xmm0
  jmp    L151
  xchg   %ax,%ax
L143:
  lea    -0x3(%r12),%rdx
  mov    %rbx,%r11
L33:
  test   %r10d,%r10d
  jle    L37
  movsd  (%r11),%xmm1
  mov    %r13,%rax
  nopl   (%rax)
L162:
  movsd  (%rax),%xmm0
  mulsd  (%rax,%rdx,8),%xmm0
  add    $0x18,%rax
  addsd  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L162
  movsd  %xmm1,(%r11)
L37:
  add    $0x1,%rdx
  add    $0x8,%r11
  cmp    %r12,%rdx
  jne    L33
  add    $0x30,%rbx
  add    $0x1,%ebp
  add    $0x8,%r13
  add    $0x8,%rsi
  sub    $0x1,%rdx
  mov    %rdx,%r12
  jne    L21
  lea    0x30(%rdi),%r12
  xor    %esi,%esi
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  mov    %r12,%r11
L152:
  movsd  0x0(%rbp),%xmm1
  lea    -0x30(%r11),%rax
  nopl   0x0(%rax,%rax,1)
L97:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %r11,%rax
  jne    L97
  mov    %r12,%rdx
  xor    %r13d,%r13d
  xor    %r14d,%r14d
L169:
  cmp    %ebx,%r14d
  je     L113
  movsd  -0x30(%rdx,%rbx,8),%xmm3
  lea    -0x30(%rdx),%rax
  cs nopw 0x0(%rax,%rax,1)
L161:
  lea    (%rax,%r13,1),%r15
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  (%r15,%rsi,1),%xmm1
  mulsd  %xmm3,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rdx,%rax
  jne    L161
L113:
  add    $0x1,%r14d
  sub    $0x30,%r13
  add    $0x30,%rdx
  cmp    $0x3,%r14d
  jne    L169
  add    $0x1,%rbx
  add    $0x38,%rbp
  add    $0x30,%rsi
  add    $0x30,%r11
  cmp    $0x3,%rbx
  jne    L152
  lea    0x90(%rdi),%rsi
  test   %r10d,%r10d
  jle    L95
  nopl   0x0(%rax)
L160:
  mov    %rdi,%rdx
  mov    %r9,%rax
L88:
  movq   $0x0,(%rax)
  movsd  (%rcx),%xmm1
  add    $0x30,%rdx
  add    $0x8,%rax
  mulsd  -0x18(%rdx),%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,-0x8(%rax)
  movsd  0x8(%rcx),%xmm0
  mulsd  -0x10(%rdx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rdx),%xmm1
  movsd  %xmm0,-0x8(%rax)
  mulsd  0x10(%rcx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rsi,%rdx
  jne    L88
  add    $0x18,%rcx
  add    $0x18,%r9
  cmp    %r8,%rcx
  jne    L160
L95:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L142
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L142:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void pseudoinverse(double (*in)[3], double (*out)[3], int size) {
  double work[3][6], num;
  int i, j, k;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 6; j++)
      work[i][j] = j == i + 3;
    for (j = 0; j < 3; j++)
      for (k = 0; k < size; k++)
        work[i][j] += in[k][i] * in[k][j];
  }
  for (i = 0; i < 3; i++) {
    num = work[i][i];
    for (j = 0; j < 6; j++)
      work[i][j] /= num;
    for (k = 0; k < 3; k++) {
      if (k == i)
        continue;
      num = work[k][i];
      for (j = 0; j < 6; j++)
        work[k][j] -= work[i][j] * num;
    }
  }
  for (i = 0; i < size; i++)
    for (j = 0; j < 3; j++)
      for (out[i][j] = k = 0; k < 3; k++)
        out[i][j] += work[j][k + 3] * in[i][k];
}
```