ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   %rbp
  xor    %edx,%edx
  lea    D28(%rip),%rdi
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <printf@plt>
  movl   $0x4,0x10(%rsp)
  xor    %esi,%esi
  movabs $0x100000000,%rax
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
L5:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,-0x4(%r12,%rbx,4)
  cmp    $0x5,%rbx
  je     L1
  mov    (%r12,%rbx,4),%esi
  add    $0x1,%rbx
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  mov    (%rsp),%esi
L23:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x5,%ebx
  je     L48
  mov    %ebx,%esi
  jmp    L23
  nopl   (%rax)
L48:
  xor    %eax,%eax
  mov    $0x8,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D28
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D20
type_guessed: string

tool: D28: A. Wartosci: %d %d %d %d


tool: D8: %d 

tool: D20: 
%d


assistant: ```c
int main() {
  int a, b, c, d;
  a = b = c = d = 0;
  printf("A. Wartosci: %d %d %d %d\n", a, b, c, d);
  int i, N = 5, tab[5] = {0, 1, 2, 3, 4};
  for (i = 0; i < N; tab[i++] = i)
    printf("%d ", tab[i]);
  printf("\n");
  for (i = 0; i < N; tab[++i] = i)
    printf("%d ", tab[i]);
  i = 1;
  while ((i *= 2) < N)
    ;
  printf("\n%d\n", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   %r12
  xor    %esi,%esi
  lea    D13(%rip),%rdi
  lea    D39(%rip),%r13
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r12
  call   <printf@plt>
  movdqa D30(%rip),%xmm0
  movl   $0x4,0x10(%rsp)
  movaps %xmm0,(%rsp)
L6:
  mov    (%r12),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <printf@plt>
  mov    %ebp,-0x4(%r12)
  cmp    $0x5,%ebp
  jne    L6
  mov    $0xa,%edi
  xor    %ebp,%ebp
  call   <putchar@plt>
L2:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <printf@plt>
  mov    %ebp,(%rbx)
  cmp    $0x5,%ebp
  jne    L2
  xor    %eax,%eax
  mov    $0x8,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D39
type_infered: string
name: read_data
arguments: label: D30
type_infered: byte[16]
name: read_data
arguments: label: D26
type_infered: string

tool: D13: A. Wartosci: %d %d %d %d


tool: D39: %d 

tool: {"D30": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D26: 
%d


assistant: ```c
int main() {
  int a, b, c, d;
  a = b = c = d = 0;
  printf("A. Wartosci: %d %d %d %d\n", a, b, c, d);
  int i, N = 5, tab[5] = {0, 1, 2, 3, 4};
  for (i = 0; i < N; tab[i++] = i)
    printf("%d ", tab[i]);
  printf("\n");
  for (i = 0; i < N; tab[++i] = i)
    printf("%d ", tab[i]);
  i = 1;
  while ((i *= 2) < N)
    ;
  printf("\n%d\n", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L25:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L16
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L16
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  addl   $0x7,-0x4(%rbp)
L37:
  cmpl   $0x752f,-0x4(%rbp)
  jle    L25
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D8: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 30000; i = i + 7) {
    if (i % 3 == 0 && i % 2 != 0) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
  jmp    L17
L31:
  add    $0x7,%ebx
  cmp    $0x7532,%ebx
  je     L16
L17:
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  jne    L31
  test   $0x1,%bl
  je     L31
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L31
L16:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string

tool: D8: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 30000; i = i + 7) {
    if (i % 3 == 0 && i % 2 != 0) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L10
  nopl   (%rax)
L28:
  add    $0x7,%ebx
  cmp    $0x7532,%ebx
  je     L0
L10:
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  ja     L28
  test   $0x1,%bl
  je     L28
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x7,%ebx
  call   <printf@plt>
  cmp    $0x7532,%ebx
  jne    L10
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: D4: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 30000; i = i + 7) {
    if (i % 3 == 0 && i % 2 != 0) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L37
  nopl   (%rax)
L31:
  add    $0x7,%ebx
  cmp    $0x7532,%ebx
  je     L28
L37:
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  ja     L31
  test   $0x1,%bl
  je     L31
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x7,%ebx
  call   <printf@plt>
  cmp    $0x7532,%ebx
  jne    L37
L28:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 30000; i = i + 7) {
    if (i % 3 == 0 && i % 2 != 0) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cephes_pdtrc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L5
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jb     L0
L5:
  mov    $0x1,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
  jmp    L6
L0:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <cephes_igam@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L6:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: pdtrc

assistant: ```c
double cephes_pdtrc(k, m)
int k;
double m;
{
  double v;
  if ((k < 0) || (m <= 0.0)) {
    mtherr("pdtrc", 1);
    return (0.0);
  }
  v = k + 1;
  return (cephes_igam(v, m));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cephes_pdtrc>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L23
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jae    L23
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mov    $0x2,%eax
  call   <cephes_igam@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L27
L23:
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
L27:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: pdtrc

assistant: ```c
double cephes_pdtrc(k, m)
int k;
double m;
{
  double v;
  if ((k < 0) || (m <= 0.0)) {
    mtherr("pdtrc", 1);
    return (0.0);
  }
  v = k + 1;
  return (cephes_igam(v, m));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cephes_pdtrc>:
  endbr64
  sub    $0x18,%rsp
  test   %edi,%edi
  js     L2
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jae    L19
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  mov    $0x2,%eax
  cvtsi2sd %edi,%xmm0
  call   <cephes_igam@plt>
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  cvtsi2sd %eax,%xmm0
  ret
  nopl   0x0(%rax)
L2:
  pxor   %xmm0,%xmm0
L19:
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <mtherr@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: pdtrc

assistant: ```c
double cephes_pdtrc(k, m)
int k;
double m;
{
  double v;
  if ((k < 0) || (m <= 0.0)) {
    mtherr("pdtrc", 1);
    return (0.0);
  }
  v = k + 1;
  return (cephes_igam(v, m));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cephes_pdtrc>:
  endbr64
  sub    $0x18,%rsp
  test   %edi,%edi
  js     L15
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jae    L4
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  mov    $0x2,%eax
  cvtsi2sd %edi,%xmm0
  call   <cephes_igam@plt>
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  cvtsi2sd %eax,%xmm0
  ret
  nopl   0x0(%rax)
L15:
  pxor   %xmm0,%xmm0
L4:
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <mtherr@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: pdtrc

assistant: ```c
double cephes_pdtrc(k, m)
int k;
double m;
{
  double v;
  if ((k < 0) || (m <= 0.0)) {
    mtherr("pdtrc", 1);
    return (0.0);
  }
  v = k + 1;
  return (cephes_igam(v, m));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<irand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <drand@plt>
  mov    -0x20(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L6
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jge    L6
  mov    $0x1,%eax
  jmp    L2
L6:
  mov    $0x0,%eax
L2:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint32_t irand(double *seed, uint32_t size) {
  uint32_t x = (uint32_t)(drand(seed) * size);
  assert(0 <= x && x < size);
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<irand>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <drand@plt>
  imul   %rbp,%rax
  mov    %rax,%rbx
  not    %rax
  shr    $0x3f,%rax
  cmp    %rbx,%rbp
  setg   %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t irand(double *seed, uint32_t size) {
  uint32_t x = (uint32_t)(drand(seed) * size);
  assert(0 <= x && x < size);
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<irand>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <drand@plt>
  imul   %rbx,%rax
  mov    %rax,%r12
  not    %rax
  shr    $0x3f,%rax
  cmp    %r12,%rbx
  setg   %dil
  and    %eax,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
uint32_t irand(double *seed, uint32_t size) {
  uint32_t x = (uint32_t)(drand(seed) * size);
  assert(0 <= x && x < size);
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<irand>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <drand@plt>
  imul   %rbx,%rax
  mov    %rax,%r12
  not    %rax
  shr    $0x3f,%rax
  cmp    %r12,%rbx
  setg   %dil
  and    %eax,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
uint32_t irand(double *seed, uint32_t size) {
  uint32_t x = (uint32_t)(drand(seed) * size);
  assert(0 <= x && x < size);
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<list_del_from>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <list_empty@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <list_del@plt>
  nop
  leave
  ret
```

assistant: ```c
void list_del_from(struct list_head *h, struct list_node *n) {
  assert(!list_empty(h));
  list_del(n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<list_del_from>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <list_empty@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <list_del@plt>
  pop    %rbx
  ret
```

assistant: ```c
void list_del_from(struct list_head *h, struct list_node *n) {
  assert(!list_empty(h));
  list_del(n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<list_del_from>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <list_empty@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <list_del@plt>
```

assistant: ```c
void list_del_from(struct list_head *h, struct list_node *n) {
  assert(!list_empty(h));
  list_del(n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<list_del_from>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <list_empty@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <list_del@plt>
```

assistant: ```c
void list_del_from(struct list_head *h, struct list_node *n) {
  assert(!list_empty(h));
  list_del(n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L16:
  mov    -0x8(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jg     L16
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long power(long x, long y) {
  long result;
  int index;
  result = 1;
  for (index = 0; index < y; index++) {
    result = result * x;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<power>:
  endbr64
  test   %rsi,%rsi
  jle    L24
  mov    $0x0,%eax
  mov    $0x1,%edx
L3:
  imul   %rdi,%rdx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L3
L19:
  mov    %rdx,%rax
  ret
L24:
  mov    $0x1,%edx
  jmp    L19
```

assistant: ```c
long power(long x, long y) {
  long result;
  int index;
  result = 1;
  for (index = 0; index < y; index++) {
    result = result * x;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<power>:
  endbr64
  test   %rsi,%rsi
  jle    L6
  xor    %eax,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L2:
  add    $0x1,%eax
  imul   %rdi,%r8
  cmp    %eax,%esi
  jne    L2
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long power(long x, long y) {
  long result;
  int index;
  result = 1;
  for (index = 0; index < y; index++) {
    result = result * x;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<power>:
  endbr64
  test   %rsi,%rsi
  jle    L5
  xor    %eax,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L15:
  add    $0x1,%eax
  imul   %rdi,%r8
  cmp    %eax,%esi
  jne    L15
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long power(long x, long y) {
  long result;
  int index;
  result = 1;
  for (index = 0; index < y; index++) {
    result = result * x;
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<ascii_toint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x60,-0x4(%rbp)
  jle    L17
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L4
L17:
  cmpb   $0x40,-0x4(%rbp)
  jle    L3
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L4
L3:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L18
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L4
L18:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ascii_toint(char c) {
  if (c >= 'a')
    return c - 'a' + 10;
  if (c >= 'A')
    return c - 'A' + 10;
  if (c >= '0')
    return c - '0';
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ascii_toint>:
  endbr64
  cmp    $0x60,%dil
  jg     L2
  cmp    $0x40,%dil
  jg     L7
  movsbl %dil,%eax
  sub    $0x30,%eax
  cmp    $0x2f,%dil
  mov    $0x0,%edx
  cmovle %edx,%eax
  ret
L2:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
L7:
  movsbl %dil,%edi
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
unsigned int ascii_toint(char c) {
  if (c >= 'a')
    return c - 'a' + 10;
  if (c >= 'A')
    return c - 'A' + 10;
  if (c >= '0')
    return c - '0';
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ascii_toint>:
  endbr64
  cmp    $0x60,%dil
  jg     L14
  cmp    $0x40,%dil
  jg     L11
  lea    -0x30(%rdi),%eax
  xor    %edx,%edx
  cmp    $0x2f,%dil
  movsbl %al,%eax
  cmovle %edx,%eax
  ret
L11:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
```

assistant: ```c
unsigned int ascii_toint(char c) {
  if (c >= 'a')
    return c - 'a' + 10;
  if (c >= 'A')
    return c - 'A' + 10;
  if (c >= '0')
    return c - '0';
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ascii_toint>:
  endbr64
  cmp    $0x60,%dil
  jg     L13
  cmp    $0x40,%dil
  jg     L11
  lea    -0x30(%rdi),%eax
  xor    %edx,%edx
  cmp    $0x2f,%dil
  movsbl %al,%eax
  cmovle %edx,%eax
  ret
L11:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
```

assistant: ```c
unsigned int ascii_toint(char c) {
  if (c >= 'a')
    return c - 'a' + 10;
  if (c >= 'A')
    return c - 'A' + 10;
  if (c >= '0')
    return c - '0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L38
L34:
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L52:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L58
L48:
  mov    -0x10(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L58:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L48
  mov    -0x10(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L52
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void times(int rows, int mid, int cols, const int *a, const int *b, int *c) {
  for (int i = 0; i < rows; i++) {
    for (int k = 0; k < cols; k++) {
      int s = 0;
      for (int j = 0; j < mid; j++) {
        s += a[i * mid + j] * b[j * cols + k];
      }
      c[i * cols + k] = s;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<times>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x2c(%rsp)
  mov    %edx,-0x30(%rsp)
  mov    %rcx,-0x28(%rsp)
  mov    %r8,-0x20(%rsp)
  mov    %r9,-0x18(%rsp)
  test   %edi,%edi
  jle    L62
  mov    %esi,%r11d
  movslq %edx,%r8
  shl    $0x2,%r8
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    %edx,%r12d
  lea    -0x1(%rsi),%eax
  mov    %rax,-0x10(%rsp)
  lea    0x4(%rcx),%rax
  mov    %rax,-0x8(%rsp)
  jmp    L3
L69:
  mov    (%rax),%edx
  imul   (%rcx),%edx
  add    %edx,%esi
  add    $0x4,%rax
  add    %r8,%rcx
  cmp    %rdi,%rax
  jne    L69
L60:
  mov    %esi,(%rbx,%r9,4)
  add    $0x1,%r9
  add    $0x4,%r10
  cmp    %r12,%r9
  je     L71
L5:
  mov    %r10,%rcx
  mov    %rbp,%rax
  mov    $0x0,%esi
  test   %r11d,%r11d
  jg     L69
  jmp    L60
L71:
  add    $0x1,%r13d
  add    -0x30(%rsp),%r14d
  add    %r11d,%r15d
  cmp    %r13d,-0x2c(%rsp)
  je     L62
L3:
  cmpl   $0x0,-0x30(%rsp)
  jle    L71
  mov    -0x20(%rsp),%r10
  movslq %r15d,%rax
  mov    -0x28(%rsp),%rbx
  lea    (%rbx,%rax,4),%rbp
  add    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rbx
  lea    (%rbx,%rax,4),%rdi
  movslq %r14d,%rax
  mov    -0x18(%rsp),%rbx
  lea    (%rbx,%rax,4),%rbx
  mov    $0x0,%r9d
  jmp    L5
L62:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void times(int rows, int mid, int cols, const int *a, const int *b, int *c) {
  for (int i = 0; i < rows; i++) {
    for (int k = 0; k < cols; k++) {
      int s = 0;
      for (int j = 0; j < mid; j++) {
        s += a[i * mid + j] * b[j * cols + k];
      }
      c[i * cols + k] = s;
    }
  }
}
```