ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<WCompSz>:
  endbr64
  movsbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %ecx,%edx
  jne    L0
  test   %edx,%edx
  je     L3
  mov    $0x1,%eax
L29:
  movsbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %ecx,%edx
  jne    L0
  add    $0x1,%rax
  test   %edx,%edx
  jne    L29
  jmp    L3
L0:
  sub    %ecx,%edx
L3:
  mov    %edx,%eax
  ret
```

assistant: ```c
int WCompSz(sz1, sz2)
char *sz1;
char *sz2;
{
  int ch1, ch2;
  for (ch1 = *sz1++, ch2 = *sz2++; ch1 == ch2; ch1 = *sz1++, ch2 = *sz2++) {
    if (ch1 == 0)
      return (0);
  }
  return (ch1 - ch2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<WCompSz>:
  endbr64
  movsbl (%rdi),%r8d
  movsbl (%rsi),%edx
  cmp    %edx,%r8d
  jne    L15
  test   %r8d,%r8d
  je     L35
  mov    $0x1,%eax
  jmp    L28
  nopl   0x0(%rax)
L4:
  add    $0x1,%rax
  test   %r8d,%r8d
  je     L35
L28:
  movsbl (%rdi,%rax,1),%r8d
  movsbl (%rsi,%rax,1),%edx
  cmp    %edx,%r8d
  je     L4
L15:
  sub    %edx,%r8d
L35:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int WCompSz(sz1, sz2)
char *sz1;
char *sz2;
{
  int ch1, ch2;
  for (ch1 = *sz1++, ch2 = *sz2++; ch1 == ch2; ch1 = *sz1++, ch2 = *sz2++) {
    if (ch1 == 0)
      return (0);
  }
  return (ch1 - ch2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<WCompSz>:
  endbr64
  movsbl (%rdi),%r8d
  movsbl (%rsi),%edx
  cmp    %edx,%r8d
  jne    L24
  test   %r8d,%r8d
  je     L28
  mov    $0x1,%eax
  jmp    L19
  nopl   0x0(%rax)
L31:
  add    $0x1,%rax
  test   %r8d,%r8d
  je     L28
L19:
  movsbl (%rdi,%rax,1),%r8d
  movsbl (%rsi,%rax,1),%edx
  cmp    %edx,%r8d
  je     L31
L24:
  sub    %edx,%r8d
L28:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int WCompSz(sz1, sz2)
char *sz1;
char *sz2;
{
  int ch1, ch2;
  for (ch1 = *sz1++, ch2 = *sz2++; ch1 == ch2; ch1 = *sz1++, ch2 = *sz2++) {
    if (ch1 == 0)
      return (0);
  }
  return (ch1 - ch2);
}
```
user: What is the c source code of the assembly code below:

```asm
<read2arg>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3030303030303030,%rax
  mov    %rax,0xd(%rsp)
  movw   $0x0,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    $0x1,%edx
  cmp    %ecx,%eax
  jge    L8
  mov    %rsi,%rbp
  mov    %ecx,%esi
  mov    %eax,(%rbx)
  cltq
  movzbl (%r8,%rax,1),%eax
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  ja     L8
  movsbl %al,%eax
  sub    $0x61,%eax
  mov    %eax,(%rdi)
  mov    (%rbx),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,(%rbx)
  add    $0x2,%eax
  mov    $0x0,%edx
  cmp    %esi,%eax
  jge    L8
  movslq %ecx,%rax
  lea    (%r8,%rax,1),%rdi
  movzbl (%rdi),%eax
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L7
  movsbl %al,%eax
  sub    $0x61,%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%edx
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %edx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  sub    $0x30,%eax
  mov    $0x1,%edx
  cmp    $0x9,%al
  ja     L8
  lea    0xd(%rsp),%r12
  sub    %ecx,%esi
  mov    $0x5e,%r8d
  mov    $0x8,%ecx
  mov    %r12,%rdx
  call   <readnum@plt>
  mov    %eax,%r13d
  mov    %r12,%rdi
  call   <atoi@plt>
  shl    $0x8,%eax
  or     $0xff,%al
  mov    %eax,0x0(%rbp)
  add    %r13d,(%rbx)
  mov    $0x0,%edx
  jmp    L8
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read2arg(int *pos, int *data, int *reg, int length, char *songstr) {
  int t;
  int t2;
  char tmpstr[11] = "00000000";
  if (*pos + 1 < length) {
    ++*pos;
    if (songstr[*pos] >= 'a' && songstr[*pos] <= 'z') {
      *reg = (songstr[*pos] - 'a');
      ++*pos;
    } else {
      return (1);
    }
    if (*pos + 1 < length) {
      if (songstr[*pos] >= 'a' && songstr[*pos] <= 'z') {
        *data = (songstr[*pos] - 'a');
      } else if (songstr[*pos] >= '0' && songstr[*pos] <= '9') {
        t2 = readnum(&(songstr[*pos]), length - *pos, tmpstr, 8, '^');
        t = atoi(tmpstr);
        *data = (t << 8 | 0xFF);
        *pos += t2;
      } else {
        return (1);
      }
    }
  } else {
    return (1);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read2arg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3030303030303030,%rax
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  xor    %eax,%eax
  mov    %ax,0x15(%rsp)
  mov    (%rdi),%eax
  add    $0x1,%eax
  cmp    %ecx,%eax
  jge    L47
  mov    %eax,(%rdi)
  cltq
  mov    %rdi,%rbx
  movzbl (%r8,%rax,1),%eax
  sub    $0x61,%eax
  cmp    $0x19,%al
  ja     L47
  movsbl %al,%eax
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  mov    %ecx,%esi
  mov    %eax,(%rdx)
  mov    (%rdi),%eax
  lea    0x1(%rax),%edx
  add    $0x2,%eax
  mov    %edx,(%rdi)
  cmp    %ecx,%eax
  jge    L37
  movslq %edx,%rax
  lea    (%r8,%rax,1),%rdi
  movzbl (%rdi),%eax
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  jbe    L41
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L47
  lea    0xd(%rsp),%r14
  sub    %edx,%esi
  mov    $0x5e,%r8d
  mov    $0x8,%ecx
  mov    %r14,%rdx
  call   <readnum@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <atoi@plt>
  shl    $0x8,%eax
  or     $0xff,%al
  mov    %eax,0x0(%rbp)
  add    %r13d,(%rbx)
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0x1,%r12d
L37:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  movsbl %cl,%ecx
  mov    %ecx,0x0(%rbp)
  jmp    L37
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read2arg(int *pos, int *data, int *reg, int length, char *songstr) {
  int t;
  int t2;
  char tmpstr[11] = "00000000";
  if (*pos + 1 < length) {
    ++*pos;
    if (songstr[*pos] >= 'a' && songstr[*pos] <= 'z') {
      *reg = (songstr[*pos] - 'a');
      ++*pos;
    } else {
      return (1);
    }
    if (*pos + 1 < length) {
      if (songstr[*pos] >= 'a' && songstr[*pos] <= 'z') {
        *data = (songstr[*pos] - 'a');
      } else if (songstr[*pos] >= '0' && songstr[*pos] <= '9') {
        t2 = readnum(&(songstr[*pos]), length - *pos, tmpstr, 8, '^');
        t = atoi(tmpstr);
        *data = (t << 8 | 0xFF);
        *pos += t2;
      } else {
        return (1);
      }
    }
  } else {
    return (1);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read2arg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3030303030303030,%rax
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  xor    %eax,%eax
  mov    %ax,0x15(%rsp)
  mov    (%rdi),%eax
  add    $0x1,%eax
  cmp    %ecx,%eax
  jge    L55
  mov    %eax,(%rdi)
  cltq
  mov    %rdi,%rbx
  movzbl (%r8,%rax,1),%eax
  sub    $0x61,%eax
  cmp    $0x19,%al
  ja     L55
  movsbl %al,%eax
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  mov    %ecx,%esi
  mov    %eax,(%rdx)
  mov    (%rdi),%eax
  lea    0x1(%rax),%edx
  add    $0x2,%eax
  mov    %edx,(%rdi)
  cmp    %ecx,%eax
  jge    L15
  movslq %edx,%rax
  lea    (%r8,%rax,1),%rdi
  movzbl (%rdi),%eax
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  jbe    L56
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L55
  lea    0xd(%rsp),%r14
  sub    %edx,%esi
  mov    $0x5e,%r8d
  mov    $0x8,%ecx
  mov    %r14,%rdx
  call   <readnum@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <atoi@plt>
  shl    $0x8,%eax
  or     $0xff,%al
  mov    %eax,0x0(%rbp)
  add    %r13d,(%rbx)
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L55:
  mov    $0x1,%r12d
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L56:
  movsbl %cl,%ecx
  mov    %ecx,0x0(%rbp)
  jmp    L15
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read2arg(int *pos, int *data, int *reg, int length, char *songstr) {
  int t;
  int t2;
  char tmpstr[11] = "00000000";
  if (*pos + 1 < length) {
    ++*pos;
    if (songstr[*pos] >= 'a' && songstr[*pos] <= 'z') {
      *reg = (songstr[*pos] - 'a');
      ++*pos;
    } else {
      return (1);
    }
    if (*pos + 1 < length) {
      if (songstr[*pos] >= 'a' && songstr[*pos] <= 'z') {
        *data = (songstr[*pos] - 'a');
      } else if (songstr[*pos] >= '0' && songstr[*pos] <= '9') {
        t2 = readnum(&(songstr[*pos]), length - *pos, tmpstr, 8, '^');
        t = atoi(tmpstr);
        *data = (t << 8 | 0xFF);
        *pos += t2;
      } else {
        return (1);
      }
    }
  } else {
    return (1);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fill_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L29
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L13
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fill_spaces(char *buf, int buf_len, int num_spaces) {
  int i;
  for (i = 0; i < num_spaces && i < buf_len - 1; i++) {
    buf[i] = ' ';
  }
  buf[i] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fill_spaces>:
  endbr64
  test   %edx,%edx
  jle    L19
  cmp    $0x1,%esi
  jle    L27
  mov    %edx,%edx
  lea    -0x2(%rsi),%esi
  add    $0x2,%rsi
  mov    $0x1,%eax
L39:
  movb   $0x20,-0x1(%rdi,%rax,1)
  mov    %eax,%ecx
  cmp    %rdx,%rax
  je     L7
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L39
L7:
  movslq %ecx,%rcx
  movb   $0x0,(%rdi,%rcx,1)
  ret
L19:
  mov    $0x0,%ecx
  jmp    L7
L27:
  mov    $0x0,%ecx
  jmp    L7
```

assistant: ```c
void fill_spaces(char *buf, int buf_len, int num_spaces) {
  int i;
  for (i = 0; i < num_spaces && i < buf_len - 1; i++) {
    buf[i] = ' ';
  }
  buf[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_spaces>:
  endbr64
  test   %edx,%edx
  jle    L45
  cmp    $0x1,%esi
  jle    L45
  sub    $0x2,%esi
  movslq %edx,%rdx
  mov    $0x1,%eax
  add    $0x2,%rsi
  jmp    L43
  xchg   %ax,%ax
L5:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L9
L43:
  movb   $0x20,-0x1(%rdi,%rax,1)
  movslq %eax,%rcx
  cmp    %rdx,%rax
  jne    L5
L9:
  add    %rcx,%rdi
L45:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void fill_spaces(char *buf, int buf_len, int num_spaces) {
  int i;
  for (i = 0; i < num_spaces && i < buf_len - 1; i++) {
    buf[i] = ' ';
  }
  buf[i] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill_spaces>:
  endbr64
  test   %edx,%edx
  jle    L20
  cmp    $0x1,%esi
  jle    L20
  sub    $0x2,%esi
  movslq %edx,%rdx
  mov    $0x1,%eax
  add    $0x2,%rsi
  jmp    L19
  xchg   %ax,%ax
L12:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L31
L19:
  movb   $0x20,-0x1(%rdi,%rax,1)
  movslq %eax,%rcx
  cmp    %rdx,%rax
  jne    L12
L31:
  add    %rcx,%rdi
L20:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void fill_spaces(char *buf, int buf_len, int num_spaces) {
  int i;
  for (i = 0; i < num_spaces && i < buf_len - 1; i++) {
    buf[i] = ' ';
  }
  buf[i] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<crc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L14:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L49:
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  xor    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L24
  mov    $0xedb88320,%eax
  jmp    L22
L24:
  mov    $0x0,%eax
L22:
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  shrl   -0x8(%rbp)
L3:
  cmpl   $0x7,-0xc(%rbp)
  jbe    L49
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int crc32(const unsigned char *databuf, unsigned int datalen) {
  unsigned int idx, bit, data, crc = 0xFFFFFFFFUL;
  for (idx = 0; idx < datalen; idx++) {
    for (data = *databuf++, bit = 0; bit < 8; bit++, data >>= 1) {
      crc = (crc >> 1) ^ (((crc ^ data) & 1) ? 0xEDB88320UL : 0);
    }
  }
  return crc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crc32>:
  endbr64
  test   %esi,%esi
  je     L37
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%r9
  mov    $0xffffffff,%eax
  mov    $0xedb88320,%r8d
  jmp    L19
L16:
  cmp    %r9,%rdi
  je     L41
L19:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%ecx
  mov    $0x8,%edx
L1:
  mov    %eax,%esi
  shr    %esi
  xor    %ecx,%eax
  and    $0x1,%eax
  cmovne %r8d,%eax
  xor    %esi,%eax
  shr    %ecx
  sub    $0x1,%edx
  jne    L1
  jmp    L16
L41:
  ret
L37:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned int crc32(const unsigned char *databuf, unsigned int datalen) {
  unsigned int idx, bit, data, crc = 0xFFFFFFFFUL;
  for (idx = 0; idx < datalen; idx++) {
    for (data = *databuf++, bit = 0; bit < 8; bit++, data >>= 1) {
      crc = (crc >> 1) ^ (((crc ^ data) & 1) ? 0xEDB88320UL : 0);
    }
  }
  return crc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<crc32>:
  endbr64
  test   %esi,%esi
  je     L7
  mov    %esi,%esi
  mov    $0xffffffff,%eax
  lea    (%rdi,%rsi,1),%r9
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  mov    $0x8,%edx
  nopl   0x0(%rax)
L5:
  mov    %eax,%esi
  xor    %ecx,%eax
  shr    %esi
  mov    %esi,%r8d
  xor    $0xedb88320,%r8d
  test   $0x1,%al
  mov    %esi,%eax
  cmovne %r8d,%eax
  shr    %ecx
  sub    $0x1,%edx
  jne    L5
  cmp    %rdi,%r9
  jne    L8
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned int crc32(const unsigned char *databuf, unsigned int datalen) {
  unsigned int idx, bit, data, crc = 0xFFFFFFFFUL;
  for (idx = 0; idx < datalen; idx++) {
    for (data = *databuf++, bit = 0; bit < 8; bit++, data >>= 1) {
      crc = (crc >> 1) ^ (((crc ^ data) & 1) ? 0xEDB88320UL : 0);
    }
  }
  return crc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crc32>:
  endbr64
  test   %esi,%esi
  je     L12
  mov    %esi,%esi
  mov    $0xffffffff,%eax
  add    %rdi,%rsi
  cs nopw 0x0(%rax,%rax,1)
L17:
  movzbl (%rdi),%edx
  mov    %eax,%ecx
  add    $0x1,%rdi
  shr    %ecx
  xor    %edx,%eax
  mov    %ecx,%r8d
  xor    $0xedb88320,%r8d
  test   $0x1,%al
  cmovne %r8d,%ecx
  mov    %edx,%r8d
  shr    %r8d
  mov    %ecx,%eax
  xor    %r8d,%ecx
  shr    %eax
  mov    %eax,%r8d
  xor    $0xedb88320,%r8d
  and    $0x1,%ecx
  cmovne %r8d,%eax
  mov    %edx,%r8d
  shr    $0x2,%r8d
  mov    %eax,%ecx
  xor    %r8d,%eax
  shr    %ecx
  mov    %ecx,%r8d
  xor    $0xedb88320,%r8d
  test   $0x1,%al
  cmovne %r8d,%ecx
  mov    %edx,%r8d
  shr    $0x3,%r8d
  mov    %ecx,%eax
  xor    %r8d,%ecx
  shr    %eax
  mov    %eax,%r8d
  xor    $0xedb88320,%r8d
  and    $0x1,%ecx
  cmovne %r8d,%eax
  mov    %edx,%r8d
  shr    $0x4,%r8d
  mov    %eax,%ecx
  xor    %r8d,%eax
  shr    %ecx
  mov    %ecx,%r8d
  xor    $0xedb88320,%r8d
  test   $0x1,%al
  cmovne %r8d,%ecx
  mov    %edx,%r8d
  shr    $0x5,%r8d
  mov    %ecx,%eax
  xor    %r8d,%ecx
  shr    %eax
  mov    %eax,%r8d
  xor    $0xedb88320,%r8d
  and    $0x1,%ecx
  cmovne %r8d,%eax
  mov    %edx,%r8d
  shr    $0x6,%r8d
  mov    %eax,%ecx
  xor    %r8d,%eax
  shr    %ecx
  mov    %ecx,%r8d
  xor    $0xedb88320,%r8d
  test   $0x1,%al
  cmovne %r8d,%ecx
  shr    $0x7,%edx
  mov    %ecx,%eax
  xor    %ecx,%edx
  shr    %eax
  mov    %eax,%ecx
  xor    $0xedb88320,%ecx
  and    $0x1,%edx
  cmovne %ecx,%eax
  cmp    %rdi,%rsi
  jne    L17
  ret
L12:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned int crc32(const unsigned char *databuf, unsigned int datalen) {
  unsigned int idx, bit, data, crc = 0xFFFFFFFFUL;
  for (idx = 0; idx < datalen; idx++) {
    for (data = *databuf++, bit = 0; bit < 8; bit++, data >>= 1) {
      crc = (crc >> 1) ^ (((crc ^ data) & 1) ? 0xEDB88320UL : 0);
    }
  }
  return crc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<next_generation>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,0x8(%rsp)
  movslq %edx,%rax
  lea    -0x4(%rsi,%rax,4),%r15
  lea    -0x1(%rdx),%eax
  mov    %rax,(%rsp)
  lea    0x4(%rdi,%rax,4),%r13
  movl   $0x3e8,0xc(%rsp)
  jmp    L41
L5:
  cmpl   $0x1,(%r14)
  je     L13
L90:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  je     L57
L1:
  mov    %rbx,%r14
  cmpl   $0x0,(%rbx)
  jne    L5
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L13:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L90
L57:
  mov    %rbp,%rax
  mov    $0x0,%edx
L14:
  cmpl   $0x1,(%rax)
  adc    $0x0,%edx
  add    $0x4,%rax
  cmp    %r13,%rax
  jne    L14
  mov    0x8(%rsp),%eax
  cmp    %eax,%edx
  je     L32
  cmp    $0x2,%eax
  je     L92
  lea    -0x3(%rax),%ecx
  add    $0x2,%rcx
  mov    $0x1,%eax
L37:
  movl   $0x0,(%r12)
  movl   $0x0,(%r15)
  mov    0x4(%rbp,%rax,4),%esi
  cmp    %esi,-0x4(%rbp,%rax,4)
  setne  %dl
  movzbl %dl,%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L37
L92:
  mov    $0x0,%eax
L12:
  mov    (%r12,%rax,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    (%rsp),%rdx
  jne    L12
  subl   $0x1,0xc(%rsp)
  je     L32
L41:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  je     L32
  mov    %rbp,%rbx
  jmp    L1
L32:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type: string
name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D12
type: string

tool: D13: .

tool: D18: *

tool: D12: 


assistant: ```c
void next_generation(int *current, int *next, int length) {
  int count = 0, count2 = 0, help = 0;
  while (count2 != 1000) {
    count = 0;
    printf("\n");
    while (count != length) {
      if (current[count] == 0)
        printf(".");
      if (current[count] == 1)
        printf("*");
      count++;
    }
    for (count = 0, help = 0; count != length; count++) {
      if (current[count] == 0)
        help++;
    }
    if (help == length)
      break;
    for (count = 1; count != length - 1; count++) {
      next[0] = 0;
      next[length - 1] = 0;
      if (current[count - 1] == current[count + 1])
        next[count] = 0;
      else
        next[count] = 1;
    }
    for (count = 0; count != length; count++) {
      current[count] = next[count];
    }
    count2++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<next_generation>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    -0x4(%rsi,%rax,4),%rbp
  push   %rbx
  mov    %rax,%rbx
  sub    $0x1,%ebx
  lea    0x4(%rdi,%rbx,4),%r15
  sub    $0x18,%rsp
  mov    %eax,0x8(%rsp)
  movl   $0x3e8,0xc(%rsp)
  nopw   0x0(%rax,%rax,1)
L64:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L122
  mov    %r14,%r13
  jmp    L114
  nopl   (%rax)
L51:
  cmp    $0x1,%eax
  je     L31
L35:
  add    $0x4,%r13
  cmp    %r15,%r13
  je     L98
L114:
  mov    0x0(%r13),%eax
  test   %eax,%eax
  jne    L51
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x0(%r13),%eax
  cmp    $0x1,%eax
  jne    L35
L31:
  lea    D21(%rip),%rdi
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %r15,%r13
  jne    L114
L98:
  mov    %r14,%rax
  xor    %edx,%edx
  nopl   (%rax)
L86:
  cmpl   $0x1,(%rax)
  adc    $0x0,%edx
  add    $0x4,%rax
  cmp    %r15,%rax
  jne    L86
  mov    0x8(%rsp),%esi
  cmp    %esi,%edx
  je     L122
  lea    -0x3(%rsi),%edi
  xor    %eax,%eax
  cmp    $0x2,%esi
  je     L115
  nopl   0x0(%rax)
L78:
  movl   $0x0,(%r12)
  xor    %edx,%edx
  movl   $0x0,0x0(%rbp)
  mov    0x8(%r14,%rax,4),%ecx
  cmp    %ecx,(%r14,%rax,4)
  setne  %dl
  mov    %edx,0x4(%r12,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L78
L115:
  xor    %eax,%eax
L82:
  mov    (%r12,%rax,4),%edx
  mov    %edx,(%r14,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rbx,%rdx
  jne    L82
  subl   $0x1,0xc(%rsp)
  jne    L64
L122:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D21
type_infered: string

tool: D18: 


tool: D15: .

tool: D21: *

assistant: ```c
void next_generation(int *current, int *next, int length) {
  int count = 0, count2 = 0, help = 0;
  while (count2 != 1000) {
    count = 0;
    printf("\n");
    while (count != length) {
      if (current[count] == 0)
        printf(".");
      if (current[count] == 1)
        printf("*");
      count++;
    }
    for (count = 0, help = 0; count != length; count++) {
      if (current[count] == 0)
        help++;
    }
    if (help == length)
      break;
    for (count = 1; count != length - 1; count++) {
      next[0] = 0;
      next[length - 1] = 0;
      if (current[count - 1] == current[count + 1])
        next[count] = 0;
      else
        next[count] = 1;
    }
    for (count = 0; count != length; count++) {
      current[count] = next[count];
    }
    count2++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmpstr_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L9
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
L9:
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L49:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L21
  mov    $0x1,%eax
  jmp    L42
L21:
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L49
  mov    $0x0,%eax
L42:
  leave
  ret
```

assistant: ```c
int cmpstr_min(char *in1, char *in2) {
  int i;
  int max = strlen(in1);
  if (strlen(in2) < max)
    max = strlen(in2);
  for (i = 0; i < max; i++) {
    if (in1[i] != in2[i])
      return 1;
  }
  return 0;
}
```