ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_area>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x9,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    $0x8,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  sub    $0x1,%ebx
  call   <get_area_start@plt>
  mov    %rax,%rdx
  cmp    $0x2,%ebx
  ja     L2
  lea    D17(%rip),%rax
  movslq (%rax,%rbx,4),%rcx
  lea    D14(%rip),%rax
  movslq (%rax,%rbx,4),%rax
  shl    $0x2,%rcx
  shl    $0x2,%rax
L23:
  lea    (%rcx,%rcx,1),%r8
  lea    0x48(%r12),%r9
  lea    (%r8,%rcx,1),%rdi
  add    %rax,%rdi
  mov    %r12,%rax
L9:
  lea    (%rcx,%rdx,1),%rsi
  mov    %rdx,(%rax)
  add    $0x18,%rax
  mov    %rsi,-0x10(%rax)
  lea    (%r8,%rdx,1),%rsi
  add    %rdi,%rdx
  mov    %rsi,-0x8(%rax)
  cmp    %r9,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L23
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string

tool: D17: 	

tool: 

assistant: ```c
int **get_area(int *cell, int choice, int *grid_start) {
  int **container_area = (int **)calloc(9, sizeof(int *));
  int **container_pointer = container_area;
  int *cell_pointer = get_area_start(cell, choice, grid_start);
  int main_increment = 0, secondary_increment = 0;
  switch (choice) {
  case 1:
    main_increment = 9;
    break;
  case 2:
    main_increment = 1;
    break;
  case 3:
    main_increment = 1;
    secondary_increment = 6;
    break;
  }
  for (int secondary_loop = 0; secondary_loop < 3; ++secondary_loop) {
    for (int main_loop = 0; main_loop < 3; ++main_loop) {
      *(container_pointer++) = cell_pointer;
      cell_pointer += main_increment;
    }
    cell_pointer += secondary_increment;
  }
  return container_area;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_area>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x9,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    $0x8,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %ebx,%esi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  mov    %rax,%r12
  sub    $0x1,%ebx
  call   <get_area_start@plt>
  mov    %rax,%rcx
  cmp    $0x2,%ebx
  ja     L7
  lea    D11(%rip),%rax
  movslq (%rax,%rbx,4),%rdx
  lea    D12(%rip),%rax
  movslq (%rax,%rbx,4),%rax
  shl    $0x2,%rdx
  lea    (%rdx,%rax,4),%rsi
L11:
  lea    (%rcx,%rdx,1),%rax
  movq   %rcx,%xmm0
  movq   %rax,%xmm1
  add    %rdx,%rax
  mov    %rax,0x10(%r12)
  add    %rsi,%rax
  punpcklqdq %xmm1,%xmm0
  mov    %rax,0x18(%r12)
  add    %rdx,%rax
  mov    %rax,0x20(%r12)
  add    %rdx,%rax
  mov    %rax,0x28(%r12)
  add    %rsi,%rax
  mov    %rax,0x30(%r12)
  add    %rdx,%rax
  mov    %rax,0x38(%r12)
  add    %rdx,%rax
  mov    %rax,0x40(%r12)
  mov    %r12,%rax
  movups %xmm0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L7:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
type: string
name: retrieve_data
arguments: data_tag: D12
type: string

tool: D11: 	

tool: 

assistant: ```c
int **get_area(int *cell, int choice, int *grid_start) {
  int **container_area = (int **)calloc(9, sizeof(int *));
  int **container_pointer = container_area;
  int *cell_pointer = get_area_start(cell, choice, grid_start);
  int main_increment = 0, secondary_increment = 0;
  switch (choice) {
  case 1:
    main_increment = 9;
    break;
  case 2:
    main_increment = 1;
    break;
  case 3:
    main_increment = 1;
    secondary_increment = 6;
    break;
  }
  for (int secondary_loop = 0; secondary_loop < 3; ++secondary_loop) {
    for (int main_loop = 0; main_loop < 3; ++main_loop) {
      *(container_pointer++) = cell_pointer;
      cell_pointer += main_increment;
    }
    cell_pointer += secondary_increment;
  }
  return container_area;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MFRC522_Write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x40(%rbp)
  mov    %al,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0xa0,-0x20(%rbp)
  movzbl -0x34(%rbp),%eax
  mov    %al,-0x1f(%rbp)
  lea    -0x20(%rbp),%rax
  lea    0x2(%rax),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <MFRC522_CRC@plt>
  lea    -0x24(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  mov    %al,-0x26(%rbp)
  cmpb   $0x0,-0x26(%rbp)
  jne    L15
  mov    -0x24(%rbp),%eax
  cmp    $0x4,%eax
  jne    L15
  movzbl -0x20(%rbp),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  cmp    $0xa,%eax
  je     L3
L15:
  movb   $0x2,-0x26(%rbp)
L3:
  cmpb   $0x0,-0x26(%rbp)
  jne    L32
  movb   $0x0,-0x25(%rbp)
  jmp    L99
L96:
  movsbq -0x25(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  movsbl -0x25(%rbp),%eax
  movzbl (%rdx),%edx
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  movzbl -0x25(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x25(%rbp)
L99:
  cmpb   $0xf,-0x25(%rbp)
  jle    L96
  lea    -0x20(%rbp),%rax
  lea    0x10(%rax),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <MFRC522_CRC@plt>
  lea    -0x24(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x12,%edx
  mov    %rax,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  mov    %al,-0x26(%rbp)
  cmpb   $0x0,-0x26(%rbp)
  jne    L55
  mov    -0x24(%rbp),%eax
  cmp    $0x4,%eax
  jne    L55
  movzbl -0x20(%rbp),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  cmp    $0xa,%eax
  je     L32
L55:
  movb   $0x2,-0x26(%rbp)
L32:
  movzbl -0x26(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  leave
  ret
```

assistant: ```c
char MFRC522_Write(char blockAddr, char *writeData) {
  char _status;
  unsigned recvBits;
  char i;
  char buff[18];
  buff[0] = 0xA0;
  buff[1] = blockAddr;
  MFRC522_CRC(buff, 2, &buff[2]);
  _status = MFRC522_ToCard(0x0C, buff, 4, buff, &recvBits);
  if ((_status != 0) || (recvBits != 4) || ((buff[0] & 0x0F) != 0x0A)) {
    _status = 2;
  }
  if (_status == 0) {
    for (i = 0; i < 16; i++) {
      buff[i] = writeData[i];
    }
    MFRC522_CRC(buff, 16, &buff[16]);
    _status = MFRC522_ToCard(0x0C, buff, 18, buff, &recvBits);
    if ((_status != 0) || (recvBits != 4) || ((buff[0] & 0x0F) != 0x0A)) {
      _status = 2;
    }
  }
  return _status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MFRC522_Write>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0xa0,0x10(%rsp)
  mov    %dil,0x11(%rsp)
  lea    0x10(%rsp),%rbp
  lea    0x12(%rsp),%rdx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <MFRC522_CRC@plt>
  lea    0xc(%rsp),%r8
  mov    %rbp,%rcx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %dl,%dl
  jne    L77
  cmpl   $0x4,0xc(%rsp)
  je     L41
L77:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L41:
  movzbl 0x10(%rsp),%edx
  and    $0xf,%edx
  cmp    $0xa,%dl
  jne    L77
  mov    $0x0,%eax
L48:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x10(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L48
  lea    0x10(%rsp),%rbx
  lea    0x20(%rsp),%rdx
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <MFRC522_CRC@plt>
  lea    0xc(%rsp),%r8
  mov    %rbx,%rcx
  mov    $0x12,%edx
  mov    %rbx,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %dl,%dl
  jne    L77
  cmpl   $0x4,0xc(%rsp)
  jne    L77
  movzbl 0x10(%rsp),%eax
  and    $0xf,%eax
  cmp    $0xa,%al
  setne  %al
  add    %eax,%eax
  jmp    L77
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char MFRC522_Write(char blockAddr, char *writeData) {
  char _status;
  unsigned recvBits;
  char i;
  char buff[18];
  buff[0] = 0xA0;
  buff[1] = blockAddr;
  MFRC522_CRC(buff, 2, &buff[2]);
  _status = MFRC522_ToCard(0x0C, buff, 4, buff, &recvBits);
  if ((_status != 0) || (recvBits != 4) || ((buff[0] & 0x0F) != 0x0A)) {
    _status = 2;
  }
  if (_status == 0) {
    for (i = 0; i < 16; i++) {
      buff[i] = writeData[i];
    }
    MFRC522_CRC(buff, 16, &buff[16]);
    _status = MFRC522_ToCard(0x0C, buff, 18, buff, &recvBits);
    if ((_status != 0) || (recvBits != 4) || ((buff[0] & 0x0F) != 0x0A)) {
      _status = 2;
    }
  }
  return _status;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MFRC522_Write>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x2,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %dil,0x11(%rsp)
  lea    0x12(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rbx
  movb   $0xa0,0x10(%rsp)
  call   <MFRC522_CRC@plt>
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  test   %al,%al
  jne    L66
  cmpl   $0x4,0xc(%rsp)
  je     L19
L66:
  mov    $0x2,%eax
L21:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl 0x10(%rsp),%eax
  and    $0xf,%eax
  cmp    $0xa,%al
  jne    L66
  movdqu (%r12),%xmm0
  lea    0x20(%rsp),%rdx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <MFRC522_CRC@plt>
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    $0x12,%edx
  mov    %rbp,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  test   %al,%al
  jne    L66
  cmpl   $0x4,0xc(%rsp)
  jne    L66
  movzbl 0x10(%rsp),%edx
  and    $0xf,%edx
  cmp    $0xa,%dl
  jne    L66
  jmp    L21
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char MFRC522_Write(char blockAddr, char *writeData) {
  char _status;
  unsigned recvBits;
  char i;
  char buff[18];
  buff[0] = 0xA0;
  buff[1] = blockAddr;
  MFRC522_CRC(buff, 2, &buff[2]);
  _status = MFRC522_ToCard(0x0C, buff, 4, buff, &recvBits);
  if ((_status != 0) || (recvBits != 4) || ((buff[0] & 0x0F) != 0x0A)) {
    _status = 2;
  }
  if (_status == 0) {
    for (i = 0; i < 16; i++) {
      buff[i] = writeData[i];
    }
    MFRC522_CRC(buff, 16, &buff[16]);
    _status = MFRC522_ToCard(0x0C, buff, 18, buff, &recvBits);
    if ((_status != 0) || (recvBits != 4) || ((buff[0] & 0x0F) != 0x0A)) {
      _status = 2;
    }
  }
  return _status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MFRC522_Write>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x2,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %dil,0x11(%rsp)
  lea    0x12(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rbx
  movb   $0xa0,0x10(%rsp)
  call   <MFRC522_CRC@plt>
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  test   %al,%al
  jne    L77
  cmpl   $0x4,0xc(%rsp)
  je     L45
L77:
  mov    $0x2,%eax
L33:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  movzbl 0x10(%rsp),%eax
  and    $0xf,%eax
  cmp    $0xa,%al
  jne    L77
  movdqu (%r12),%xmm0
  lea    0x20(%rsp),%rdx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <MFRC522_CRC@plt>
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    $0x12,%edx
  mov    %rbp,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  test   %al,%al
  jne    L77
  cmpl   $0x4,0xc(%rsp)
  jne    L77
  movzbl 0x10(%rsp),%edx
  and    $0xf,%edx
  cmp    $0xa,%dl
  jne    L77
  jmp    L33
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char MFRC522_Write(char blockAddr, char *writeData) {
  char _status;
  unsigned recvBits;
  char i;
  char buff[18];
  buff[0] = 0xA0;
  buff[1] = blockAddr;
  MFRC522_CRC(buff, 2, &buff[2]);
  _status = MFRC522_ToCard(0x0C, buff, 4, buff, &recvBits);
  if ((_status != 0) || (recvBits != 4) || ((buff[0] & 0x0F) != 0x0A)) {
    _status = 2;
  }
  if (_status == 0) {
    for (i = 0; i < 16; i++) {
      buff[i] = writeData[i];
    }
    MFRC522_CRC(buff, 16, &buff[16]);
    _status = MFRC522_ToCard(0x0C, buff, 18, buff, &recvBits);
    if ((_status != 0) || (recvBits != 4) || ((buff[0] & 0x0F) != 0x0A)) {
      _status = 2;
    }
  }
  return _status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LZ4_read_ARCH>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <LZ4_64bits@plt>
  test   %rax,%rax
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <LZ4_read64@plt>
  cltq
  jmp    L9
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <LZ4_read32@plt>
  cltq
L9:
  leave
  ret
```

assistant: ```c
size_t LZ4_read_ARCH(const void *p) {
  if (LZ4_64bits())
    return (size_t)LZ4_read64(p);
  else
    return (size_t)LZ4_read32(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LZ4_read_ARCH>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <LZ4_64bits@plt>
  test   %rax,%rax
  je     L12
  mov    %rbx,%rdi
  call   <LZ4_read64@plt>
  cltq
L8:
  pop    %rbx
  ret
L12:
  mov    %rbx,%rdi
  call   <LZ4_read32@plt>
  cltq
  jmp    L8
```

assistant: ```c
size_t LZ4_read_ARCH(const void *p) {
  if (LZ4_64bits())
    return (size_t)LZ4_read64(p);
  else
    return (size_t)LZ4_read32(p);
}
```
user: What is the c source code of the assembly code below?

```asm
<LZ4_read_ARCH>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <LZ4_64bits@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L4
  call   <LZ4_read64@plt>
  pop    %rbp
  cltq
  ret
L4:
  call   <LZ4_read32@plt>
  pop    %rbp
  cltq
  ret
```

assistant: ```c
size_t LZ4_read_ARCH(const void *p) {
  if (LZ4_64bits())
    return (size_t)LZ4_read64(p);
  else
    return (size_t)LZ4_read32(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<LZ4_read_ARCH>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <LZ4_64bits@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L6
  call   <LZ4_read64@plt>
  pop    %rbp
  cltq
  ret
L6:
  call   <LZ4_read32@plt>
  pop    %rbp
  cltq
  ret
```

assistant: ```c
size_t LZ4_read_ARCH(const void *p) {
  if (LZ4_64bits())
    return (size_t)LZ4_read64(p);
  else
    return (size_t)LZ4_read32(p);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__v1_tx_user_ready>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <__sync_synchronize@plt>
  nop
  leave
  ret
```

assistant: ```c
void __v1_tx_user_ready(struct tpacket_hdr *hdr) {
  hdr->tp_status = TP_STATUS_SEND_REQUEST;
  __sync_synchronize();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__v1_tx_user_ready>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi)
  mov    $0x0,%eax
  call   <__sync_synchronize@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __v1_tx_user_ready(struct tpacket_hdr *hdr) {
  hdr->tp_status = TP_STATUS_SEND_REQUEST;
  __sync_synchronize();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__v1_tx_user_ready>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  jmp    1050 <__sync_synchronize@plt>
```

assistant: ```c
void __v1_tx_user_ready(struct tpacket_hdr *hdr) {
  hdr->tp_status = TP_STATUS_SEND_REQUEST;
  __sync_synchronize();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__v1_tx_user_ready>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  jmp    1050 <__sync_synchronize@plt>
```

assistant: ```c
void __v1_tx_user_ready(struct tpacket_hdr *hdr) {
  hdr->tp_status = TP_STATUS_SEND_REQUEST;
  __sync_synchronize();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<store_solutions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x33,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int store_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(51, a, b, c);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store_solutions>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x33,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int store_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(51, a, b, c);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<store_solutions>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x33,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int store_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(51, a, b, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<store_solutions>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x33,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int store_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(51, a, b, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insertsortsad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L44
L41:
  movl   $0x0,-0x10(%rbp)
  jmp    L66
L34:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L56
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L10
L59:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L59
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L56:
  addl   $0x1,-0x10(%rbp)
L66:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L34
  addl   $0x1,-0x14(%rbp)
L44:
  mov    -0x34(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L41
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertsortsad(int arr[], int idx[], int len) {
  int i, j, k;
  for (i = 1; i <= len - 1; ++i) {
    for (j = 0; j < i; ++j) {
      if (arr[j] > arr[i]) {
        int temp, tempi;
        temp = arr[i];
        tempi = idx[i];
        for (k = i; k > j; k--) {
          arr[k] = arr[k - 1];
          idx[k] = idx[k - 1];
        }
        arr[j] = temp;
        idx[j] = tempi;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertsortsad>:
  endbr64
  cmp    $0x1,%edx
  jle    L51
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rcx
  lea    0x4(%rdi),%r11
  mov    %edx,%r12d
  mov    $0x1,%r10d
  jmp    L85
L4:
  mov    %r9d,(%rcx,%rdx,4)
  mov    %ebx,(%rsi,%rdx,4)
L89:
  add    $0x1,%rdx
  cmp    %r10,%rdx
  je     L82
L75:
  mov    (%r11),%r9d
  cmp    %r9d,(%rcx,%rdx,4)
  jle    L89
  mov    (%rsi,%r10,4),%ebx
  mov    %edx,%r8d
  cmp    %ebp,%edx
  jge    L4
  mov    %r10,%rax
L19:
  mov    -0x4(%rcx,%rax,4),%edi
  mov    %edi,(%rcx,%rax,4)
  mov    -0x4(%rsi,%rax,4),%edi
  mov    %edi,(%rsi,%rax,4)
  sub    $0x1,%rax
  cmp    %eax,%r8d
  jl     L19
  jmp    L4
L82:
  add    $0x1,%r10
  add    $0x4,%r11
  cmp    %r12,%r10
  je     L13
L85:
  mov    %r10d,%ebp
  mov    $0x0,%edx
  test   %r10d,%r10d
  jg     L75
  jmp    L82
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  ret
```

assistant: ```c
void insertsortsad(int arr[], int idx[], int len) {
  int i, j, k;
  for (i = 1; i <= len - 1; ++i) {
    for (j = 0; j < i; ++j) {
      if (arr[j] > arr[i]) {
        int temp, tempi;
        temp = arr[i];
        tempi = idx[i];
        for (k = i; k > j; k--) {
          arr[k] = arr[k - 1];
          idx[k] = idx[k - 1];
        }
        arr[j] = temp;
        idx[j] = tempi;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<insertsortsad>:
  endbr64
  cmp    $0x1,%edx
  jle    L65
  push   %rbp
  mov    %rdi,%rcx
  lea    0x4(%rdi),%r11
  movslq %edx,%rbp
  push   %rbx
  mov    $0x1,%r10d
  nopl   0x0(%rax,%rax,1)
L79:
  xor    %edx,%edx
  jmp    L67
  nopl   0x0(%rax)
L14:
  add    $0x1,%rdx
  cmp    %rdx,%r10
  je     L49
L67:
  mov    (%r11),%r9d
  cmp    %r9d,(%rcx,%rdx,4)
  jle    L14
  mov    (%rsi,%r10,4),%ebx
  mov    %edx,%r8d
  cmp    %r10d,%edx
  jge    L30
  mov    %r10,%rax
  nopl   0x0(%rax)
L43:
  mov    -0x4(%rcx,%rax,4),%edi
  mov    %edi,(%rcx,%rax,4)
  mov    -0x4(%rsi,%rax,4),%edi
  mov    %edi,(%rsi,%rax,4)
  sub    $0x1,%rax
  cmp    %eax,%r8d
  jl     L43
L30:
  mov    %r9d,(%rcx,%rdx,4)
  mov    %ebx,(%rsi,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r10
  jne    L67
L49:
  add    $0x1,%r10
  add    $0x4,%r11
  cmp    %rbp,%r10
  jne    L79
  pop    %rbx
  pop    %rbp
  ret
L65:
  ret
```

assistant: ```c
void insertsortsad(int arr[], int idx[], int len) {
  int i, j, k;
  for (i = 1; i <= len - 1; ++i) {
    for (j = 0; j < i; ++j) {
      if (arr[j] > arr[i]) {
        int temp, tempi;
        temp = arr[i];
        tempi = idx[i];
        for (k = i; k > j; k--) {
          arr[k] = arr[k - 1];
          idx[k] = idx[k - 1];
        }
        arr[j] = temp;
        idx[j] = tempi;
      }
    }
  }
}
```