ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tms_get_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x4,-0x24(%rbp)
  jle    L5
  movl   $0x4,-0x24(%rbp)
L5:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L21
L25:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movzbl %al,%eax
  or     %ecx,%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L21:
  cmpl   $0x0,-0x8(%rbp)
  jns    L25
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t tms_get_int(uint8_t *msg, int32_t *s, int32_t n) {
  int32_t i;
  int32_t b = 0;
  if (n > 4) {
    n = 4;
  }
  for (i = n - 1; i >= 0; i--) {
    b = (b << 8) | (msg[(*s) + i] & 0xFF);
  }
  (*s) += n;
  return (b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tms_get_int>:
  endbr64
  mov    $0x4,%eax
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    %edx,%ecx
  sub    $0x1,%ecx
  js     L7
  movslq %ecx,%rcx
  movslq (%rsi),%rax
  lea    (%rdi,%rax,4),%r8
  mov    $0x0,%eax
L18:
  shl    $0x8,%eax
  movzbl (%r8,%rcx,4),%edi
  or     %edi,%eax
  sub    $0x1,%rcx
  test   %ecx,%ecx
  jns    L18
L2:
  add    %edx,(%rsi)
  ret
L7:
  mov    $0x0,%eax
  jmp    L2
```

assistant: ```c
int32_t tms_get_int(uint8_t *msg, int32_t *s, int32_t n) {
  int32_t i;
  int32_t b = 0;
  if (n > 4) {
    n = 4;
  }
  for (i = n - 1; i >= 0; i--) {
    b = (b << 8) | (msg[(*s) + i] & 0xFF);
  }
  (*s) += n;
  return (b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tms_get_int>:
  endbr64
  mov    $0x4,%eax
  mov    (%rsi),%r9d
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    %edx,%ecx
  sub    $0x1,%ecx
  js     L2
  movslq %r9d,%rax
  movslq %ecx,%rcx
  lea    (%rdi,%rax,4),%r8
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  movzbl (%r8,%rcx,4),%edi
  shl    $0x8,%eax
  sub    $0x1,%rcx
  or     %edi,%eax
  test   %ecx,%ecx
  jns    L10
  add    %r9d,%edx
  mov    %edx,(%rsi)
  ret
L2:
  add    %r9d,%edx
  xor    %eax,%eax
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
int32_t tms_get_int(uint8_t *msg, int32_t *s, int32_t n) {
  int32_t i;
  int32_t b = 0;
  if (n > 4) {
    n = 4;
  }
  for (i = n - 1; i >= 0; i--) {
    b = (b << 8) | (msg[(*s) + i] & 0xFF);
  }
  (*s) += n;
  return (b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tms_get_int>:
  endbr64
  mov    $0x4,%eax
  mov    %rdi,%rcx
  mov    (%rsi),%edi
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  js     L15
  add    %edi,%eax
  lea    -0x2(%rdx),%r8d
  cltq
  movzbl (%rcx,%rax,4),%eax
  cmp    $0x1,%edx
  je     L16
  add    %edi,%r8d
  shl    $0x8,%eax
  lea    -0x3(%rdx),%r9d
  movslq %r8d,%r8
  movzbl (%rcx,%r8,4),%r8d
  or     %r8d,%eax
  cmp    $0x2,%edx
  je     L16
  lea    (%r9,%rdi,1),%r8d
  shl    $0x8,%eax
  movslq %r8d,%r8
  movzbl (%rcx,%r8,4),%r8d
  or     %r8d,%eax
  test   %r9d,%r9d
  je     L16
  movslq %edi,%r8
  shl    $0x8,%eax
  movzbl (%rcx,%r8,4),%ecx
  or     %ecx,%eax
L16:
  add    %edi,%edx
  mov    %edx,(%rsi)
  ret
  xchg   %ax,%ax
L15:
  add    %edi,%edx
  xor    %eax,%eax
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
int32_t tms_get_int(uint8_t *msg, int32_t *s, int32_t n) {
  int32_t i;
  int32_t b = 0;
  if (n > 4) {
    n = 4;
  }
  for (i = n - 1; i >= 0; i--) {
    b = (b << 8) | (msg[(*s) + i] & 0xFF);
  }
  (*s) += n;
  return (b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mbtowc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L11
L8:
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L11
L7:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L22
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L22:
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int mbtowc(wchar_t *pwc, const char *s, size_t n) {
  if (s == 0)
    return 0;
  if (n == 0)
    return -1;
  else {
    wchar_t wc = *(unsigned char *)s;
    if (pwc)
      *pwc = wc;
    return (wc != 0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mbtowc>:
  endbr64
  test   %rsi,%rsi
  je     L13
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  je     L12
  movzbl (%rsi),%eax
  test   %rdi,%rdi
  je     L19
  mov    %rax,(%rdi)
L19:
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
L13:
  mov    $0x0,%eax
L12:
  ret
```

assistant: ```c
int mbtowc(wchar_t *pwc, const char *s, size_t n) {
  if (s == 0)
    return 0;
  if (n == 0)
    return -1;
  else {
    wchar_t wc = *(unsigned char *)s;
    if (pwc)
      *pwc = wc;
    return (wc != 0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mbtowc>:
  endbr64
  test   %rsi,%rsi
  je     L11
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  je     L14
  movzbl (%rsi),%eax
  test   %rdi,%rdi
  je     L22
  mov    %rax,(%rdi)
L22:
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
L14:
  ret
```

assistant: ```c
int mbtowc(wchar_t *pwc, const char *s, size_t n) {
  if (s == 0)
    return 0;
  if (n == 0)
    return -1;
  else {
    wchar_t wc = *(unsigned char *)s;
    if (pwc)
      *pwc = wc;
    return (wc != 0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mbtowc>:
  endbr64
  test   %rsi,%rsi
  je     L28
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  je     L5
  movzbl (%rsi),%eax
  test   %rdi,%rdi
  je     L13
  mov    %rax,(%rdi)
L13:
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
L5:
  ret
```

assistant: ```c
int mbtowc(wchar_t *pwc, const char *s, size_t n) {
  if (s == 0)
    return 0;
  if (n == 0)
    return -1;
  else {
    wchar_t wc = *(unsigned char *)s;
    if (pwc)
      *pwc = wc;
    return (wc != 0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parseline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parselist@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct cmd *parseline(char **ps, char *es) {
  struct cmd *cmd;
  cmd = parselist(ps, es);
  return cmd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parseline>:
  endbr64
  sub    $0x8,%rsp
  call   <parselist@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct cmd *parseline(char **ps, char *es) {
  struct cmd *cmd;
  cmd = parselist(ps, es);
  return cmd;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parseline>:
  endbr64
  jmp    1050 <parselist@plt>
```

assistant: ```c
struct cmd *parseline(char **ps, char *es) {
  struct cmd *cmd;
  cmd = parselist(ps, es);
  return cmd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parseline>:
  endbr64
  jmp    1050 <parselist@plt>
```

assistant: ```c
struct cmd *parseline(char **ps, char *es) {
  struct cmd *cmd;
  cmd = parselist(ps, es);
  return cmd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CPU_getCPUIDFeaturesExt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int CPU_getCPUIDFeaturesExt() {
  int features = 0;
  return features;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CPU_getCPUIDFeaturesExt>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int CPU_getCPUIDFeaturesExt() {
  int features = 0;
  return features;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CPU_getCPUIDFeaturesExt>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int CPU_getCPUIDFeaturesExt() {
  int features = 0;
  return features;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CPU_getCPUIDFeaturesExt>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int CPU_getCPUIDFeaturesExt() {
  int features = 0;
  return features;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nullPointer_fesetenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fesetenv@plt>
  mov    $0x0,%edi
  call   <fesetenv@plt>
  nop
  leave
  ret
```

assistant: ```c
void nullPointer_fesetenv(void) {
  fenv_t *envp = 0;
  (void)fesetenv(envp);
  (void)fesetenv(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nullPointer_fesetenv>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <fesetenv@plt>
  mov    $0x0,%edi
  call   <fesetenv@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void nullPointer_fesetenv(void) {
  fenv_t *envp = 0;
  (void)fesetenv(envp);
  (void)fesetenv(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<nullPointer_fesetenv>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <fesetenv@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1050 <fesetenv@plt>
```

assistant: ```c
void nullPointer_fesetenv(void) {
  fenv_t *envp = 0;
  (void)fesetenv(envp);
  (void)fesetenv(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nullPointer_fesetenv>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <fesetenv@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1050 <fesetenv@plt>
```

assistant: ```c
void nullPointer_fesetenv(void) {
  fenv_t *envp = 0;
  (void)fesetenv(envp);
  (void)fesetenv(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L62
L50:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L36
L12:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L36:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L12
  mov    -0x18(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <find_element@plt>
  test   %rax,%rax
  js     L32
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L62
L32:
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L62:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jg     L50
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D40
data_type: string
name: retrieve_data
arguments: data_label: D33
data_type: string
name: retrieve_data
arguments: data_label: D44
data_type: string

tool: D40: %d

tool: D33: YES


tool: D44: NO


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  while (T-- > 0) {
    int *ar;
    int n;
    scanf("%d", &n);
    ar = (int *)malloc(n * sizeof(int));
    for (int i = 0; i < n; i++) {
      scanf("%d", &ar[i]);
    }
    if (find_element(n, ar) >= 0) {
      printf("YES\n");
    } else {
      printf("NO\n");
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jle    L20
  lea    0x4(%rsp),%r14
  lea    D19(%rip),%r12
  lea    D2(%rip),%r15
  jmp    L72
L58:
  lea    D33(%rip),%rdi
  call   <printf@plt>
L12:
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jle    L20
L72:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L66
  mov    %rax,%rbp
  mov    $0x0,%ebx
L41:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%edi
  add    $0x4,%rbp
  cmp    %ebx,%edi
  jg     L41
L66:
  mov    %r13,%rsi
  call   <find_element@plt>
  test   %rax,%rax
  js     L58
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L12
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D33
type_guessed: string

tool: D19: %d

tool: D2: YES


tool: D33: NO


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  while (T-- > 0) {
    int *ar;
    int n;
    scanf("%d", &n);
    ar = (int *)malloc(n * sizeof(int));
    for (int i = 0; i < n; i++) {
      scanf("%d", &ar[i]);
    }
    if (find_element(n, ar) >= 0) {
      printf("YES\n");
    } else {
      printf("NO\n");
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jle    L49
  lea    0x4(%rsp),%r13
  lea    D13(%rip),%r14
  nopl   (%rax)
L15:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%r12
  test   %edi,%edi
  jle    L32
  mov    %rax,%r15
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x4,%r15
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    %ebx,%edi
  jg     L21
L32:
  mov    %r12,%rsi
  call   <find_element@plt>
  test   %rax,%rax
  js     L50
  mov    %r14,%rdi
  call   <printf@plt>
L12:
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jg     L15
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L50:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D23
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string

tool: D23: %d

tool: D13: YES


tool: D5: NO


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  while (T-- > 0) {
    int *ar;
    int n;
    scanf("%d", &n);
    ar = (int *)malloc(n * sizeof(int));
    for (int i = 0; i < n; i++) {
      scanf("%d", &ar[i]);
    }
    if (find_element(n, ar) >= 0) {
      printf("YES\n");
    } else {
      printf("NO\n");
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jle    L6
  lea    0x4(%rsp),%r13
  lea    D25(%rip),%r14
  nopl   0x0(%rax)
L31:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%r12
  test   %edi,%edi
  jle    L18
  mov    %rax,%r15
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x4,%r15
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    %ebx,%edi
  jg     L22
L18:
  mov    %r12,%rsi
  call   <find_element@plt>
  mov    %r14,%rdi
  test   %rax,%rax
  jns    L11
  lea    D8(%rip),%rdi
L11:
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jg     L31
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D25
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string

tool: D5: %d

tool: D25: YES


tool: D8: NO


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  while (T-- > 0) {
    int *ar;
    int n;
    scanf("%d", &n);
    ar = (int *)malloc(n * sizeof(int));
    for (int i = 0; i < n; i++) {
      scanf("%d", &ar[i]);
    }
    if (find_element(n, ar) >= 0) {
      printf("YES\n");
    } else {
      printf("NO\n");
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L17
  movsd  -0x10(%rbp),%xmm0
  jmp    L5
L17:
  movsd  -0x8(%rbp),%xmm0
L5:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double max(double a, double b) {
  if (a < b) {
    return b;
  } else {
    return a;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<max>:
  endbr64
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double max(double a, double b) {
  if (a < b) {
    return b;
  } else {
    return a;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<max>:
  endbr64
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double max(double a, double b) {
  if (a < b) {
    return b;
  } else {
    return a;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<max>:
  endbr64
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double max(double a, double b) {
  if (a < b) {
    return b;
  } else {
    return a;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<eh_fmt_unsigned_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,%eax
  mov    %esi,-0xc(%rbp)
  mov    $0x1,%ebx
  jmp    L2
L18:
  mov    $0x0,%edx
  divl   -0xc(%rbp)
  add    $0x1,%ebx
L2:
  mov    -0xc(%rbp),%edx
  sub    $0x1,%edx
  cmp    %edx,%eax
  ja     L18
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
size_t eh_fmt_unsigned_len(register unsigned n, const unsigned b) {
  register unsigned l = 1;
  for (; n > (b - 1); n /= b, l++)
    ;
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eh_fmt_unsigned_len>:
  endbr64
  lea    -0x1(%rsi),%r8d
  cmp    %r8d,%edi
  jbe    L15
  mov    $0x1,%ecx
L9:
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  mov    %eax,%edi
  add    $0x1,%ecx
  cmp    %r8d,%eax
  ja     L9
L26:
  mov    %ecx,%eax
  ret
L15:
  mov    $0x1,%ecx
  jmp    L26
```

assistant: ```c
size_t eh_fmt_unsigned_len(register unsigned n, const unsigned b) {
  register unsigned l = 1;
  for (; n > (b - 1); n /= b, l++)
    ;
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eh_fmt_unsigned_len>:
  endbr64
  mov    %edi,%eax
  lea    -0x1(%rsi),%edi
  cmp    %edi,%eax
  jbe    L13
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %edx,%edx
  add    $0x1,%ecx
  div    %esi
  cmp    %edi,%eax
  ja     L8
  mov    %ecx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t eh_fmt_unsigned_len(register unsigned n, const unsigned b) {
  register unsigned l = 1;
  for (; n > (b - 1); n /= b, l++)
    ;
  return l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<eh_fmt_unsigned_len>:
  endbr64
  mov    %edi,%eax
  lea    -0x1(%rsi),%edi
  cmp    %edi,%eax
  jbe    L5
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %edx,%edx
  add    $0x1,%ecx
  div    %esi
  cmp    %edi,%eax
  ja     L14
  mov    %ecx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t eh_fmt_unsigned_len(register unsigned n, const unsigned b) {
  register unsigned l = 1;
  for (; n > (b - 1); n /= b, l++)
    ;
  return l;
}
```
user: What is the c source code of the assembly code below:

```asm
<decode_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x6,%edi
  mov    $0x0,%eax
  call   <count_ones@plt>
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x7,-0x14(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L36
L53:
  cmpl   $0x1,-0x14(%rbp)
  jne    L50
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <get_bits@plt>
  test   %eax,%eax
  je     L59
  movl   $0x1,-0x14(%rbp)
  jmp    L50
L59:
  mov    $0x1,%eax
  jmp    L36
L50:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %edx,%ebx
  mov    %eax,%ecx
  shl    %cl,%ebx
  mov    -0x14(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <get_bits@plt>
  not    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  sub    $0x1,%eax
  and    %edx,%eax
  add    %ebx,%eax
L36:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: decode_number 

assistant: ```c
int decode_number(unsigned char **data, unsigned short *len, unsigned char *bitpos) {
  int num_bits;
  printf("decode_number ");
  num_bits = count_ones(6, data, len, bitpos) + 1;
  if (num_bits == 7)
    return 0;
  if (num_bits == 1) {
    if (get_bits(data, len, bitpos, 1))
      num_bits = 1;
    else
      return 1;
  }
  return (1 << num_bits) + (~get_bits(data, len, bitpos, num_bits) & ((1 << num_bits) - 1));
}
```