ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lengthOfLastWord>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L35
  jmp    L39
L28:
  cmp    $0x20,%al
  setne  %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  je     L39
L35:
  cmpb   $0x20,-0x1(%rdi)
  jne    L28
  cmp    $0x20,%al
  je     L28
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  mov    $0x1,%r8d
  test   %al,%al
  jne    L35
L39:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int lengthOfLastWord(char *s) {
  int len = 0;
  while (*s != '\0') {
    if (s[-1] == ' ' && s[0] != ' ') {
      len = 1;
    } else if (*s != ' ') {
      len++;
    }
    s++;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lengthOfLastWord>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  movzbl -0x1(%rdi),%ecx
  xor    %r8d,%r8d
  jmp    L38
  nopl   0x0(%rax)
L57:
  xor    %edx,%edx
  cmp    $0x20,%al
  mov    %eax,%ecx
  setne  %dl
  add    $0x1,%rdi
  add    %edx,%r8d
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L53
L26:
  mov    %edx,%eax
L38:
  cmp    $0x20,%al
  je     L57
  cmp    $0x20,%cl
  jne    L57
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  mov    $0x1,%r8d
  mov    %eax,%ecx
  test   %dl,%dl
  jne    L26
L53:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int lengthOfLastWord(char *s) {
  int len = 0;
  while (*s != '\0') {
    if (s[-1] == ' ' && s[0] != ' ') {
      len = 1;
    } else if (*s != ' ') {
      len++;
    }
    s++;
  }
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<frame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x630,%rsp
  mov    %rdi,-0x618(%rbp)
  mov    %rsi,-0x620(%rbp)
  mov    %edx,-0x624(%rbp)
  mov    %rcx,-0x630(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xd0c0b0a,-0x608(%rbp)
  movl   $0x0,-0x604(%rbp)
  movl   $0x0,-0x60c(%rbp)
  mov    -0x60c(%rbp),%eax
  lea    -0x600(%rbp),%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    -0x618(%rbp),%rax
  mov    $0x6,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <framecpy@plt>
  add    %eax,-0x60c(%rbp)
  mov    -0x60c(%rbp),%eax
  lea    -0x600(%rbp),%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    -0x620(%rbp),%rax
  mov    $0x6,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <framecpy@plt>
  add    %eax,-0x60c(%rbp)
  mov    -0x60c(%rbp),%eax
  lea    -0x600(%rbp),%rdx
  lea    (%rdx,%rax,1),%rcx
  lea    -0x608(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <framecpy@plt>
  add    %eax,-0x60c(%rbp)
  mov    -0x624(%rbp),%edx
  mov    -0x60c(%rbp),%eax
  lea    -0x600(%rbp),%rcx
  add    %rax,%rcx
  mov    -0x630(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <framecpy@plt>
  add    %eax,-0x60c(%rbp)
  mov    -0x60c(%rbp),%eax
  lea    -0x600(%rbp),%rdx
  lea    (%rdx,%rax,1),%rcx
  lea    -0x604(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <framecpy@plt>
  add    %eax,-0x60c(%rbp)
  movl   $0x0,-0x610(%rbp)
  jmp    L17
L5:
  mov    -0x610(%rbp),%eax
  movzbl -0x600(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x610(%rbp)
L17:
  mov    -0x610(%rbp),%eax
  cmp    -0x60c(%rbp),%eax
  jb     L5
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: %02x

assistant: ```c
void frame(unsigned char dst[6], unsigned char src[6], unsigned count, unsigned char buf[1500]) {
  unsigned char packet_type[4] = {0xa, 0xb, 0xc, 0xd};
  unsigned char checksum[4] = {0x0, 0x0, 0x0, 0x0};
  unsigned char frame[6 + 6 + 4 + 1500 + 4];
  unsigned i, ptr = 0;
  ptr += framecpy(frame + ptr, dst, 6);
  ptr += framecpy(frame + ptr, src, 6);
  ptr += framecpy(frame + ptr, packet_type, 4);
  ptr += framecpy(frame + ptr, buf, count);
  ptr += framecpy(frame + ptr, checksum, 4);
  for (i = 0; i < ptr; i++) {
    printf("%02x", frame[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<frame>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x610,%rsp
  mov    %rsi,%rbx
  mov    %edx,%r14d
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x608(%rsp)
  xor    %eax,%eax
  movl   $0xd0c0b0a,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  mov    $0x6,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <framecpy@plt>
  mov    %rax,%r12
  mov    %eax,%edi
  add    %rbp,%rdi
  mov    $0x6,%edx
  mov    %rbx,%rsi
  call   <framecpy@plt>
  lea    (%r12,%rax,1),%ebx
  lea    0x8(%rsp),%rsi
  mov    %ebx,%edi
  add    %rbp,%rdi
  mov    $0x4,%edx
  call   <framecpy@plt>
  add    %eax,%ebx
  mov    %ebx,%edi
  add    %rbp,%rdi
  mov    %r14d,%edx
  mov    %r13,%rsi
  call   <framecpy@plt>
  add    %eax,%ebx
  lea    0xc(%rsp),%rsi
  mov    %ebx,%eax
  lea    0x0(%rbp,%rax,1),%rdi
  mov    $0x4,%edx
  call   <framecpy@plt>
  add    %ebx,%eax
  je     L23
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x11(%rsp,%rax,1),%r12
  lea    D1(%rip),%rbp
L6:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L6
L23:
  mov    0x608(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x610,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: %02x

assistant: ```c
void frame(unsigned char dst[6], unsigned char src[6], unsigned count, unsigned char buf[1500]) {
  unsigned char packet_type[4] = {0xa, 0xb, 0xc, 0xd};
  unsigned char checksum[4] = {0x0, 0x0, 0x0, 0x0};
  unsigned char frame[6 + 6 + 4 + 1500 + 4];
  unsigned i, ptr = 0;
  ptr += framecpy(frame + ptr, dst, 6);
  ptr += framecpy(frame + ptr, src, 6);
  ptr += framecpy(frame + ptr, packet_type, 4);
  ptr += framecpy(frame + ptr, buf, count);
  ptr += framecpy(frame + ptr, checksum, 4);
  for (i = 0; i < ptr; i++) {
    printf("%02x", frame[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<frame>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdi,%rsi
  push   %r13
  mov    %edx,%r13d
  mov    $0x6,%edx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  sub    $0x610,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x608(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  movl   $0xd0c0b0a,0x8(%rsp)
  mov    %rbx,%rdi
  movl   $0x0,0xc(%rsp)
  call   <framecpy@plt>
  mov    $0x6,%edx
  mov    %r14,%rsi
  mov    %eax,%edi
  mov    %rax,%rbp
  add    %rbx,%rdi
  call   <framecpy@plt>
  lea    0x8(%rsp),%rsi
  mov    $0x4,%edx
  lea    0x0(%rbp,%rax,1),%edi
  mov    %rdi,%rbp
  add    %rbx,%rdi
  call   <framecpy@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  lea    0x0(%rbp,%rax,1),%edi
  mov    %rdi,%rbp
  add    %rbx,%rdi
  call   <framecpy@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  lea    0x0(%rbp,%rax,1),%edi
  mov    %rdi,%rbp
  add    %rbx,%rdi
  call   <framecpy@plt>
  add    %eax,%ebp
  je     L17
  lea    -0x1(%rbp),%eax
  lea    D4(%rip),%rbp
  lea    0x11(%rsp,%rax,1),%r12
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L21
L17:
  mov    0x608(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x610,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: %02x

assistant: ```c
void frame(unsigned char dst[6], unsigned char src[6], unsigned count, unsigned char buf[1500]) {
  unsigned char packet_type[4] = {0xa, 0xb, 0xc, 0xd};
  unsigned char checksum[4] = {0x0, 0x0, 0x0, 0x0};
  unsigned char frame[6 + 6 + 4 + 1500 + 4];
  unsigned i, ptr = 0;
  ptr += framecpy(frame + ptr, dst, 6);
  ptr += framecpy(frame + ptr, src, 6);
  ptr += framecpy(frame + ptr, packet_type, 4);
  ptr += framecpy(frame + ptr, buf, count);
  ptr += framecpy(frame + ptr, checksum, 4);
  for (i = 0; i < ptr; i++) {
    printf("%02x", frame[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<frame>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdi,%rsi
  push   %r13
  mov    %edx,%r13d
  mov    $0x6,%edx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  sub    $0x610,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x608(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  movl   $0xd0c0b0a,0x8(%rsp)
  mov    %rbx,%rdi
  movl   $0x0,0xc(%rsp)
  call   <framecpy@plt>
  mov    $0x6,%edx
  mov    %r14,%rsi
  mov    %eax,%edi
  mov    %rax,%rbp
  add    %rbx,%rdi
  call   <framecpy@plt>
  lea    0x8(%rsp),%rsi
  mov    $0x4,%edx
  lea    0x0(%rbp,%rax,1),%edi
  mov    %rdi,%rbp
  add    %rbx,%rdi
  call   <framecpy@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  lea    0x0(%rbp,%rax,1),%edi
  mov    %rdi,%rbp
  add    %rbx,%rdi
  call   <framecpy@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  lea    0x0(%rbp,%rax,1),%edi
  mov    %rdi,%rbp
  add    %rbx,%rdi
  call   <framecpy@plt>
  add    %eax,%ebp
  je     L0
  lea    -0x1(%rbp),%eax
  lea    D3(%rip),%rbp
  lea    0x11(%rsp,%rax,1),%r12
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
L0:
  mov    0x608(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x610,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: %02x

assistant: ```c
void frame(unsigned char dst[6], unsigned char src[6], unsigned count, unsigned char buf[1500]) {
  unsigned char packet_type[4] = {0xa, 0xb, 0xc, 0xd};
  unsigned char checksum[4] = {0x0, 0x0, 0x0, 0x0};
  unsigned char frame[6 + 6 + 4 + 1500 + 4];
  unsigned i, ptr = 0;
  ptr += framecpy(frame + ptr, dst, 6);
  ptr += framecpy(frame + ptr, src, 6);
  ptr += framecpy(frame + ptr, packet_type, 4);
  ptr += framecpy(frame + ptr, buf, count);
  ptr += framecpy(frame + ptr, checksum, 4);
  for (i = 0; i < ptr; i++) {
    printf("%02x", frame[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stdlib_strided_dsumkbn2>:
  endbr64
  test   %rdi,%rdi
  jle    L56
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r15
  cmp    $0x1,%rdi
  je     L4
  test   %rdx,%rdx
  je     L4
  mov    $0x0,%eax
  js     L30
L75:
  lea    0x0(,%rdx,8),%rcx
  mov    %rcx,0x28(%rsp)
  lea    (%rsi,%rax,8),%r14
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x18(%rsp)
  mov    $0x0,%r13d
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm2,(%rsp)
  jmp    L115
L4:
  movsd  (%rsi),%xmm0
  jmp    L61
L30:
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
  jmp    L75
L84:
  movq   %rbp,%xmm0
  subsd  (%rsp),%xmm0
  movq   %rbx,%xmm2
  addsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rsp)
  jmp    L48
L41:
  movsd  0x8(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
L18:
  addsd  0x20(%rsp),%xmm0
  movsd  %xmm0,0x20(%rsp)
  add    $0x1,%r13
  add    0x28(%rsp),%r14
  cmp    %r13,%r15
  je     L104
  movsd  0x10(%rsp),%xmm6
  movsd  %xmm6,0x18(%rsp)
L115:
  mov    (%r14),%rbp
  mov    (%rsp),%rbx
  movq   %rbp,%xmm3
  addsd  (%rsp),%xmm3
  movsd  %xmm3,(%rsp)
  movq   %rbx,%xmm0
  call   <fabs@plt>
  mov    %rax,%r12
  movq   %rbp,%xmm0
  call   <fabs@plt>
  cmp    %rax,%r12
  jl     L84
  movq   %rbx,%xmm0
  subsd  (%rsp),%xmm0
  movq   %rbp,%xmm7
  addsd  %xmm0,%xmm7
  movsd  %xmm7,0x8(%rsp)
L48:
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rsp)
  call   <fabs@plt>
  mov    %rax,%rbx
  movsd  0x8(%rsp),%xmm0
  call   <fabs@plt>
  cmp    %rax,%rbx
  jl     L41
  movsd  0x18(%rsp),%xmm7
  subsd  0x10(%rsp),%xmm7
  movapd %xmm7,%xmm0
  addsd  0x8(%rsp),%xmm0
  jmp    L18
L104:
  movsd  (%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
L61:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double stdlib_strided_dsumkbn2(const int64_t N, const double *X, const int64_t stride) {
  double sum;
  double ccs;
  int64_t ix;
  int64_t i;
  double cs;
  double cc;
  double v;
  double t;
  double c;
  if (N <= 0) {
    return 0.0;
  }
  if (N == 1 || stride == 0) {
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  sum = 0.0;
  ccs = 0.0;
  cs = 0.0;
  for (i = 0; i < N; i++) {
    v = X[ix];
    t = sum + v;
    if (fabs(sum) >= fabs(v)) {
      c = (sum - t) + v;
    } else {
      c = (v - t) + sum;
    }
    sum = t;
    t = cs + c;
    if (fabs(cs) >= fabs(c)) {
      cc = (cs - t) + c;
    } else {
      cc = (c - t) + cs;
    }
    cs = t;
    ccs += cc;
    ix += stride;
  }
  return sum + cs + ccs;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stdlib_strided_dsumkbn2>:
  endbr64
  test   %rdi,%rdi
  jle    L0
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  cmp    $0x1,%rdi
  je     L81
  test   %rdx,%rdx
  je     L81
  mov    $0x0,%eax
  jns    L97
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
L97:
  pxor   %xmm2,%xmm2
  lea    0x0(,%rdx,8),%r13
  lea    (%rsi,%rax,8),%r12
  xor    %ebp,%ebp
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm3
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L9:
  subsd  %xmm3,%xmm4
  addsd  %xmm4,%xmm1
L61:
  movapd %xmm1,%xmm4
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x28(%rsp)
  addsd  %xmm2,%xmm4
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm4,0x20(%rsp)
  call   <fabs@plt>
  movsd  0x10(%rsp),%xmm1
  mov    %rax,%rbx
  movapd %xmm1,%xmm0
  call   <fabs@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  cmp    %rax,%rbx
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm3
  jl     L7
  subsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm1
L63:
  addsd  0x8(%rsp),%xmm1
  add    $0x1,%rbp
  add    %r13,%r12
  movsd  %xmm1,0x8(%rsp)
  cmp    %rbp,%r14
  je     L84
  movapd %xmm4,%xmm2
L26:
  movsd  (%r12),%xmm1
  movapd %xmm3,%xmm4
  movsd  %xmm2,0x28(%rsp)
  movapd %xmm4,%xmm0
  movsd  %xmm4,0x18(%rsp)
  addsd  %xmm1,%xmm3
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm3,0x20(%rsp)
  call   <fabs@plt>
  movsd  0x10(%rsp),%xmm1
  mov    %rax,%rbx
  movapd %xmm1,%xmm0
  call   <fabs@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm4
  cmp    %rax,%rbx
  movsd  0x20(%rsp),%xmm3
  movsd  0x28(%rsp),%xmm2
  jge    L9
  subsd  %xmm3,%xmm1
  addsd  %xmm4,%xmm1
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L81:
  movsd  (%rsi),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  subsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  jmp    L63
  nopl   (%rax)
L84:
  movapd %xmm3,%xmm0
  add    $0x30,%rsp
  addsd  %xmm4,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L0:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double stdlib_strided_dsumkbn2(const int64_t N, const double *X, const int64_t stride) {
  double sum;
  double ccs;
  int64_t ix;
  int64_t i;
  double cs;
  double cc;
  double v;
  double t;
  double c;
  if (N <= 0) {
    return 0.0;
  }
  if (N == 1 || stride == 0) {
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  sum = 0.0;
  ccs = 0.0;
  cs = 0.0;
  for (i = 0; i < N; i++) {
    v = X[ix];
    t = sum + v;
    if (fabs(sum) >= fabs(v)) {
      c = (sum - t) + v;
    } else {
      c = (v - t) + sum;
    }
    sum = t;
    t = cs + c;
    if (fabs(cs) >= fabs(c)) {
      cc = (cs - t) + c;
    } else {
      cc = (c - t) + cs;
    }
    cs = t;
    ccs += cc;
    ix += stride;
  }
  return sum + cs + ccs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stdlib_strided_dsumkbn2>:
  endbr64
  test   %rdi,%rdi
  jle    L35
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  cmp    $0x1,%rdi
  je     L49
  test   %rdx,%rdx
  je     L49
  mov    $0x0,%eax
  jns    L28
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
L28:
  pxor   %xmm2,%xmm2
  lea    0x0(,%rdx,8),%r13
  lea    (%rsi,%rax,8),%r12
  xor    %ebp,%ebp
  movsd  %xmm2,0x10(%rsp)
  movapd %xmm2,%xmm3
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L73:
  subsd  0x8(%rsp),%xmm3
  addsd  %xmm3,%xmm1
L78:
  movapd %xmm1,%xmm3
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x20(%rsp)
  addsd  %xmm2,%xmm3
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x28(%rsp)
  call   <fabs@plt>
  movsd  0x18(%rsp),%xmm1
  mov    %rax,%rbx
  movapd %xmm1,%xmm0
  call   <fabs@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm2
  cmp    %rax,%rbx
  movsd  0x28(%rsp),%xmm3
  jl     L47
  subsd  %xmm3,%xmm2
  add    $0x1,%rbp
  add    %r13,%r12
  addsd  %xmm1,%xmm2
  addsd  0x10(%rsp),%xmm2
  movsd  %xmm2,0x10(%rsp)
  cmp    %rbp,%r14
  je     L24
L90:
  movapd %xmm3,%xmm2
  movsd  0x8(%rsp),%xmm3
L66:
  movsd  (%r12),%xmm1
  movapd %xmm3,%xmm0
  movsd  %xmm2,0x28(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movapd %xmm1,%xmm4
  movsd  %xmm1,0x18(%rsp)
  addsd  %xmm3,%xmm4
  movsd  %xmm4,0x8(%rsp)
  call   <fabs@plt>
  movsd  0x18(%rsp),%xmm1
  mov    %rax,%rbx
  movapd %xmm1,%xmm0
  call   <fabs@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm3
  cmp    %rax,%rbx
  movsd  0x28(%rsp),%xmm2
  jge    L73
  subsd  0x8(%rsp),%xmm1
  addsd  %xmm3,%xmm1
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L49:
  movsd  (%rsi),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L47:
  subsd  %xmm3,%xmm1
  add    $0x1,%rbp
  add    %r13,%r12
  addsd  %xmm2,%xmm1
  addsd  0x10(%rsp),%xmm1
  movsd  %xmm1,0x10(%rsp)
  cmp    %rbp,%r14
  jne    L90
L24:
  movsd  0x8(%rsp),%xmm0
  addsd  %xmm3,%xmm0
  addsd  0x10(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L35:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double stdlib_strided_dsumkbn2(const int64_t N, const double *X, const int64_t stride) {
  double sum;
  double ccs;
  int64_t ix;
  int64_t i;
  double cs;
  double cc;
  double v;
  double t;
  double c;
  if (N <= 0) {
    return 0.0;
  }
  if (N == 1 || stride == 0) {
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  sum = 0.0;
  ccs = 0.0;
  cs = 0.0;
  for (i = 0; i < N; i++) {
    v = X[ix];
    t = sum + v;
    if (fabs(sum) >= fabs(v)) {
      c = (sum - t) + v;
    } else {
      c = (v - t) + sum;
    }
    sum = t;
    t = cs + c;
    if (fabs(cs) >= fabs(c)) {
      cc = (cs - t) + c;
    } else {
      cc = (c - t) + cs;
    }
    cs = t;
    ccs += cc;
    ix += stride;
  }
  return sum + cs + ccs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x20(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  and    $0xfffffff3,%eax
  or     $0x8,%eax
  mov    %al,-0x20(%rbp)
  movzbl -0x10(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %al,-0x10(%rbp)
  movzbl -0x10(%rbp),%eax
  and    $0xfffffff3,%eax
  or     $0x8,%eax
  mov    %al,-0x10(%rbp)
  movzbl -0xc(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %al,-0xc(%rbp)
  movzbl -0xc(%rbp),%eax
  and    $0xfffffff3,%eax
  mov    %al,-0xc(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0xfffffffc,%eax
  or     $0x2,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0xfffffff3,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    $0xfffffffc,%eax
  or     $0x2,%eax
  mov    %al,-0x1c(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    $0xfffffff3,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movzbl -0x18(%rbp),%eax
  and    $0xfffffffc,%eax
  or     $0x2,%eax
  mov    %al,-0x18(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void test3() {
  struct A {
    unsigned int foo : 2;
    int bar : 2;
  };
  struct A a = {0, 10};
  struct A b[] = {0, 10, 0, 0};
  struct A c[] = {{10, 0}};
  struct A d = (struct A){10, 0};
  struct A e = {.foo = 10};
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3() {
  struct A {
    unsigned int foo : 2;
    int bar : 2;
  };
  struct A a = {0, 10};
  struct A b[] = {0, 10, 0, 0};
  struct A c[] = {{10, 0}};
  struct A d = (struct A){10, 0};
  struct A e = {.foo = 10};
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3() {
  struct A {
    unsigned int foo : 2;
    int bar : 2;
  };
  struct A a = {0, 10};
  struct A b[] = {0, 10, 0, 0};
  struct A c[] = {{10, 0}};
  struct A d = (struct A){10, 0};
  struct A e = {.foo = 10};
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3() {
  struct A {
    unsigned int foo : 2;
    int bar : 2;
  };
  struct A a = {0, 10};
  struct A b[] = {0, 10, 0, 0};
  struct A c[] = {{10, 0}};
  struct A d = (struct A){10, 0};
  struct A e = {.foo = 10};
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init_symtbl@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <lispcalc@plt>
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_symtbl();
  return lispcalc(STDIN_FILENO);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_symtbl@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <lispcalc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_symtbl();
  return lispcalc(STDIN_FILENO);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_symtbl@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1060 <lispcalc@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  init_symtbl();
  return lispcalc(STDIN_FILENO);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_symtbl@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1060 <lispcalc@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  init_symtbl();
  return lispcalc(STDIN_FILENO);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findNotEmpty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L32
L35:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L17
  mov    -0x8(%rbp),%rax
  jmp    L12
L17:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L35
  mov    $0xffffffffffffffff,%rax
L12:
  pop    %rbp
  ret
```

assistant: ```c
size_t findNotEmpty(size_t *shared, size_t size) {
  size_t i;
  for (i = 0; i < size; i++) {
    if (shared[i] != 0) {
      return i;
    }
  }
  return -1;
}
```