ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<testForwardPropagation>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  lea    0x4(%rsp),%rdx
  lea    D28(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  cmpl   $0x0,0x4(%rsp)
  jle    L17
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D36(%rip),%r13
L2:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %rax,0x0(%rbp)
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,0x4(%rsp)
  jg     L2
L17:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  call   <testReadNeuralNetwork@plt>
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <forwardPropagation@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
type: string
name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D36
type: string

tool: D15: r

tool: D1: X.txt

tool: D28: %d

tool: D36: %lf

assistant: ```c
void testForwardPropagation() {
  FILE *in;
  in = fopen("X.txt", "r");
  int n;
  fscanf(in, "%d", &n);
  double **X = (double **)malloc(n * sizeof(double *));
  for (int i = 0; i < n; i++) {
    X[i] = (double *)malloc(sizeof(double));
    fscanf(in, "%lf", &X[i][0]);
  }
  fclose(in);
  testReadNeuralNetwork();
  forwardPropagation(X, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testForwardPropagation>:
  endbr64
  push   %r14
  lea    D26(%rip),%rsi
  lea    D35(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x4(%rsp),%rdx
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L29
  mov    %r13,%rbx
  xor    %r14d,%r14d
  lea    D9(%rip),%r12
  nopl   0x0(%rax)
L12:
  mov    $0x8,%edi
  add    $0x1,%r14d
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,-0x8(%rbx)
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <fscanf@plt>
  cmp    %r14d,0x4(%rsp)
  jg     L12
L29:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  call   <testReadNeuralNetwork@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <forwardPropagation@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D26
type_infered: string
name: disassemble_data
arguments: tag: D35
type_infered: string
name: disassemble_data
arguments: tag: D11
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D26: r

tool: D35: X.txt

tool: D11: %d

tool: D9: %lf

assistant: ```c
void testForwardPropagation() {
  FILE *in;
  in = fopen("X.txt", "r");
  int n;
  fscanf(in, "%d", &n);
  double **X = (double **)malloc(n * sizeof(double *));
  for (int i = 0; i < n; i++) {
    X[i] = (double *)malloc(sizeof(double));
    fscanf(in, "%lf", &X[i][0]);
  }
  fclose(in);
  testReadNeuralNetwork();
  forwardPropagation(X, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testForwardPropagation>:
  endbr64
  push   %r14
  lea    D9(%rip),%rsi
  lea    D8(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x4(%rsp),%rdx
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L26
  mov    %r13,%rbx
  xor    %r14d,%r14d
  lea    D28(%rip),%r12
  nopl   0x0(%rax)
L5:
  mov    $0x8,%edi
  add    $0x1,%r14d
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,-0x8(%rbx)
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <fscanf@plt>
  cmp    %r14d,0x4(%rsp)
  jg     L5
L26:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  call   <testReadNeuralNetwork@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <forwardPropagation@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string

tool: D9: r

tool: D8: X.txt

tool: D1: %d

tool: D28: %lf

assistant: ```c
void testForwardPropagation() {
  FILE *in;
  in = fopen("X.txt", "r");
  int n;
  fscanf(in, "%d", &n);
  double **X = (double **)malloc(n * sizeof(double *));
  for (int i = 0; i < n; i++) {
    X[i] = (double *)malloc(sizeof(double));
    fscanf(in, "%lf", &X[i][0]);
  }
  fclose(in);
  testReadNeuralNetwork();
  forwardPropagation(X, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<uart_tx_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L8:
  nop
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <uart_tx_fifo_full@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <uart_tx@plt>
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart_tx_string(struct uart *module, const char *string) {
  for (uint32_t i = 0; string[i] != 0; ++i) {
    while (uart_tx_fifo_full(module))
      ;
    uart_tx(module, string[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uart_tx_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x0,(%rsi)
  je     L26
L3:
  mov    %rbx,%rdi
  call   <uart_tx_fifo_full@plt>
  test   %rax,%rax
  jne    L3
  movsbl 0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <uart_tx@plt>
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L3
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uart_tx_string(struct uart *module, const char *string) {
  for (uint32_t i = 0; string[i] != 0; ++i) {
    while (uart_tx_fifo_full(module))
      ;
    uart_tx(module, string[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_tx_string>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L0
  nopl   (%rax)
L9:
  mov    %rbx,%rdi
  call   <uart_tx_fifo_full@plt>
  test   %rax,%rax
  jne    L9
  movsbl 0x0(%rbp),%esi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <uart_tx@plt>
  cmpb   $0x0,0x0(%rbp)
  jne    L9
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uart_tx_string(struct uart *module, const char *string) {
  for (uint32_t i = 0; string[i] != 0; ++i) {
    while (uart_tx_fifo_full(module))
      ;
    uart_tx(module, string[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uart_tx_string>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L24
  nopl   (%rax)
L27:
  mov    %rbx,%rdi
  call   <uart_tx_fifo_full@plt>
  test   %rax,%rax
  jne    L27
  movsbl 0x0(%rbp),%esi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <uart_tx@plt>
  cmpb   $0x0,0x0(%rbp)
  jne    L27
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uart_tx_string(struct uart *module, const char *string) {
  for (uint32_t i = 0; string[i] != 0; ++i) {
    while (uart_tx_fifo_full(module))
      ;
    uart_tx(module, string[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init_locale@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <parse_args@plt>
  mov    $0x0,%eax
  call   <pair_roundrobin@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_locale();
  parse_args(argc, argv);
  pair_roundrobin();
  return EXIT_SUCCESS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <init_locale@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <parse_args@plt>
  mov    $0x0,%eax
  call   <pair_roundrobin@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_locale();
  parse_args(argc, argv);
  pair_roundrobin();
  return EXIT_SUCCESS;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <init_locale@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <parse_args@plt>
  xor    %eax,%eax
  call   <pair_roundrobin@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_locale();
  parse_args(argc, argv);
  pair_roundrobin();
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <init_locale@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <parse_args@plt>
  xor    %eax,%eax
  call   <pair_roundrobin@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_locale();
  parse_args(argc, argv);
  pair_roundrobin();
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L10
L13:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L10:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memcpy(char *dst, char *src, int count) {
  while (count--)
    *dst++ = *src++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L5
  mov    %edx,%edx
  mov    $0x0,%eax
L17:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L5:
  ret
```

assistant: ```c
void memcpy(char *dst, char *src, int count) {
  while (count--)
    *dst++ = *src++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L18
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L4:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L18:
  ret
```

assistant: ```c
void memcpy(char *dst, char *src, int count) {
  while (count--)
    *dst++ = *src++;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%edi
  test   %edx,%edx
  je     L63
  lea    0x1(%rsi),%r8
  mov    %rcx,%rax
  sub    %r8,%rax
  cmp    $0xe,%rax
  jbe    L39
  cmp    $0x6,%edi
  jbe    L39
  cmp    $0xe,%edi
  jbe    L11
  mov    %edx,%r8d
  xor    %eax,%eax
  shr    $0x4,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L82:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L82
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%r8d
  sub    %eax,%edi
  lea    (%rcx,%r8,1),%r9
  add    %rsi,%r8
  cmp    %eax,%edx
  je     L112
L54:
  sub    %eax,%edx
  lea    -0x1(%rdx),%r10d
  cmp    $0x6,%r10d
  jbe    L84
  mov    (%rsi,%rax,1),%rsi
  mov    %rsi,(%rcx,%rax,1)
  mov    %edx,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%ecx
  sub    %eax,%edi
  add    %rcx,%r9
  add    %rcx,%r8
  cmp    %eax,%edx
  je     L63
L84:
  movzbl (%r8),%eax
  mov    %al,(%r9)
  test   %edi,%edi
  je     L63
  movzbl 0x1(%r8),%eax
  mov    %al,0x1(%r9)
  cmp    $0x1,%edi
  je     L63
  movzbl 0x2(%r8),%eax
  mov    %al,0x2(%r9)
  cmp    $0x2,%edi
  je     L63
  movzbl 0x3(%r8),%eax
  mov    %al,0x3(%r9)
  cmp    $0x3,%edi
  je     L63
  movzbl 0x4(%r8),%eax
  mov    %al,0x4(%r9)
  cmp    $0x4,%edi
  je     L63
  movzbl 0x5(%r8),%eax
  mov    %al,0x5(%r9)
  cmp    $0x5,%edi
  je     L63
  movzbl 0x6(%r8),%eax
  mov    %al,0x6(%r9)
  ret
  nopl   (%rax)
L39:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L156:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L156
L63:
  ret
L11:
  mov    %rsi,%r8
  mov    %rcx,%r9
  xor    %eax,%eax
  jmp    L54
L112:
  ret
```

assistant: ```c
void memcpy(char *dst, char *src, int count) {
  while (count--)
    *dst++ = *src++;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_tok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x88(%rbp),%rax
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x78(%rbp)
  jmp    L6
L25:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L6
  lea    -0x70(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x80(%rbp)
  jmp    L47
L59:
  mov    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x80(%rbp)
L47:
  cmpq   $0x0,-0x80(%rbp)
  jne    L59
L6:
  mov    -0x78(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L25
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D30
type: string
name: disassemble_data
arguments: data_tag: D16
type: string
name: disassemble_data
arguments: data_tag: D4
type: string

tool: D30: r

tool: D16:  !,.?


tool: D4: %s


assistant: ```c
void read_tok(char *fname) {
  char buffer[100];
  FILE *fp = fopen(fname, "r");
  while (fgets(buffer, sizeof(buffer), fp)) {
    if (strlen(buffer) != 1) {
      char *pch = strtok(buffer, " !,.?\n");
      while (pch != NULL) {
        printf("%s\n", pch);
        pch = strtok(NULL, " !,.?\n");
      }
    }
  }
  fclose(fp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_tok>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rsp,%rbx
  lea    D15(%rip),%r12
  lea    D28(%rip),%r13
L15:
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L22
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L15
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L15
L52:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L52
  jmp    L15
L22:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type: string
name: extract_symbolic_data
arguments: data_label: D15
type: string
name: extract_symbolic_data
arguments: data_label: D28
type: string

tool: D12: r

tool: D15:  !,.?


tool: D28: %s


assistant: ```c
void read_tok(char *fname) {
  char buffer[100];
  FILE *fp = fopen(fname, "r");
  while (fgets(buffer, sizeof(buffer), fp)) {
    if (strlen(buffer) != 1) {
      char *pch = strtok(buffer, " !,.?\n");
      while (pch != NULL) {
        printf("%s\n", pch);
        pch = strtok(NULL, " !,.?\n");
      }
    }
  }
  fclose(fp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_tok>:
  endbr64
  push   %r13
  lea    D17(%rip),%rsi
  lea    D6(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L55
L35:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L22
L55:
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L35
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L22:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L55
  nopl   0x0(%rax,%rax,1)
L69:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L69
  jmp    L55
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D21
datatype: string

tool: D17: r

tool: D6: %s


tool: D21:  !,.?


assistant: ```c
void read_tok(char *fname) {
  char buffer[100];
  FILE *fp = fopen(fname, "r");
  while (fgets(buffer, sizeof(buffer), fp)) {
    if (strlen(buffer) != 1) {
      char *pch = strtok(buffer, " !,.?\n");
      while (pch != NULL) {
        printf("%s\n", pch);
        pch = strtok(NULL, " !,.?\n");
      }
    }
  }
  fclose(fp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_tok>:
  endbr64
  push   %r13
  lea    D26(%rip),%rsi
  lea    D8(%rip),%r13
  push   %r12
  lea    D29(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L41
L46:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L12
L41:
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L46
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L12:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L41
  nopl   0x0(%rax,%rax,1)
L60:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L60
  jmp    L41
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string

tool: D26: r

tool: D8: %s


tool: D29:  !,.?


assistant: ```c
void read_tok(char *fname) {
  char buffer[100];
  FILE *fp = fopen(fname, "r");
  while (fgets(buffer, sizeof(buffer), fp)) {
    if (strlen(buffer) != 1) {
      char *pch = strtok(buffer, " !,.?\n");
      while (pch != NULL) {
        printf("%s\n", pch);
        pch = strtok(NULL, " !,.?\n");
      }
    }
  }
  fclose(fp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x0,-0x50(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,%edi
  call   <getSize@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L72:
  cmp    %rdx,%rsp
  je     L41
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L72
L41:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L76
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L76:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L95
L107:
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%eax
  cltq
  movb   $0x30,(%rdx,%rax,1)
  addl   $0x1,-0x50(%rbp)
L95:
  mov    -0x50(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L107
  movl   $0x0,-0x50(%rbp)
  jmp    L34
L36:
  mov    -0x54(%rbp),%eax
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %eax,%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  sarl   -0x54(%rbp)
  addl   $0x1,-0x50(%rbp)
L34:
  cmpl   $0x0,-0x54(%rbp)
  jne    L36
  mov    -0x4c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x50(%rbp)
  jmp    L73
L46:
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x50(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L94
  mov    $0x20,%edi
  call   <putchar@plt>
L94:
  subl   $0x1,-0x50(%rbp)
L73:
  cmpl   $0x0,-0x50(%rbp)
  jns    L46
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void printBits(int x) {
  int i = 0;
  int size = getSize(x);
  char bytes[size];
  for (i = 0; i < size; i++)
    bytes[i] = '0';
  for (i = 0; x; x >>= 1, i++)
    bytes[i] = ('0' + (char)(x & 1));
  for (i = size - 1; i >= 0; i--) {
    printf("%c", bytes[i]);
    if (i % 8 == 0)
      printf(" ");
  }
}
```