ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<config_parse_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    0x10(%rbp),%rdi
  call   <assert@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <is_number@plt>
  test   %eax,%eax
  jne    L14
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L10
L14:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x8(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
int config_parse_int(const char *filename, unsigned line, const char *section, const char *lvalue, int ltype, const char *rvalue, void *data) {
  int *i = data;
  assert(filename);
  assert(lvalue);
  assert(rvalue);
  assert(data);
  if (!is_number(rvalue, strlen(rvalue)))
    return -EINVAL;
  *i = atoi(rvalue);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<config_parse_int>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbp
  mov    %r9,%rbx
  mov    0x20(%rsp),%r12
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <is_number@plt>
  test   %eax,%eax
  jne    L14
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  mov    $0x0,%eax
  jmp    L9
```

assistant: ```c
int config_parse_int(const char *filename, unsigned line, const char *section, const char *lvalue, int ltype, const char *rvalue, void *data) {
  int *i = data;
  assert(filename);
  assert(lvalue);
  assert(rvalue);
  assert(data);
  if (!is_number(rvalue, strlen(rvalue)))
    return -EINVAL;
  *i = atoi(rvalue);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<config_parse_int>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    0x20(%rsp),%rbx
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <is_number@plt>
  test   %eax,%eax
  jne    L2
  mov    D6(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  neg    %eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int config_parse_int(const char *filename, unsigned line, const char *section, const char *lvalue, int ltype, const char *rvalue, void *data) {
  int *i = data;
  assert(filename);
  assert(lvalue);
  assert(rvalue);
  assert(data);
  if (!is_number(rvalue, strlen(rvalue)))
    return -EINVAL;
  *i = atoi(rvalue);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<config_parse_int>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    0x20(%rsp),%rbx
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <is_number@plt>
  test   %eax,%eax
  jne    L2
  mov    D9(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  neg    %eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int config_parse_int(const char *filename, unsigned line, const char *section, const char *lvalue, int ltype, const char *rvalue, void *data) {
  int *i = data;
  assert(filename);
  assert(lvalue);
  assert(rvalue);
  assert(data);
  if (!is_number(rvalue, strlen(rvalue)))
    return -EINVAL;
  *i = atoi(rvalue);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<unlinkat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <dir_mutex_lock@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jne    L8
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <rmdir@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L10
L8:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    %eax,-0x4(%rbp)
L10:
  mov    $0x0,%eax
  call   <dir_mutex_unlock@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int unlinkat(int dirfd, const char *pathname, int flags) {
  int rc;
  dir_mutex_lock(dirfd);
  if (flags == AT_REMOVEDIR)
    rc = rmdir(pathname);
  else
    rc = unlink(pathname);
  dir_mutex_unlock();
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unlinkat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  call   <dir_mutex_lock@plt>
  mov    D9(%rip),%rax
  cmp    %ebp,(%rax)
  je     L15
  mov    %rbx,%rdi
  call   <unlink@plt>
  mov    %eax,%ebx
L13:
  mov    $0x0,%eax
  call   <dir_mutex_unlock@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %rbx,%rdi
  call   <rmdir@plt>
  mov    %eax,%ebx
  jmp    L13
```

assistant: ```c
int unlinkat(int dirfd, const char *pathname, int flags) {
  int rc;
  dir_mutex_lock(dirfd);
  if (flags == AT_REMOVEDIR)
    rc = rmdir(pathname);
  else
    rc = unlink(pathname);
  dir_mutex_unlock();
  return rc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unlinkat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <dir_mutex_lock@plt>
  mov    D9(%rip),%rax
  mov    %r12,%rdi
  cmp    %ebx,(%rax)
  je     L18
  call   <unlink@plt>
  mov    %eax,%r12d
L3:
  xor    %eax,%eax
  call   <dir_mutex_unlock@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L18:
  call   <rmdir@plt>
  mov    %eax,%r12d
  jmp    L3
```

assistant: ```c
int unlinkat(int dirfd, const char *pathname, int flags) {
  int rc;
  dir_mutex_lock(dirfd);
  if (flags == AT_REMOVEDIR)
    rc = rmdir(pathname);
  else
    rc = unlink(pathname);
  dir_mutex_unlock();
  return rc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<unlinkat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <dir_mutex_lock@plt>
  mov    D5(%rip),%rax
  mov    %r12,%rdi
  cmp    %ebx,(%rax)
  je     L14
  call   <unlink@plt>
  mov    %eax,%r12d
L10:
  xor    %eax,%eax
  call   <dir_mutex_unlock@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L14:
  call   <rmdir@plt>
  mov    %eax,%r12d
  jmp    L10
```

assistant: ```c
int unlinkat(int dirfd, const char *pathname, int flags) {
  int rc;
  dir_mutex_lock(dirfd);
  if (flags == AT_REMOVEDIR)
    rc = rmdir(pathname);
  else
    rc = unlink(pathname);
  dir_mutex_unlock();
  return rc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<compare>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%r14d
  mov    %edx,%r15d
  and    $0xfffffff8,%r15d
  jle    L12
  mov    $0x0,%r13d
L98:
  mov    %r12,%rdi
  call   <load_u64@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <load_u64@plt>
  cmp    %eax,%ebx
  jne    L63
  add    $0x20,%r12
  add    $0x20,%rbp
  add    $0x8,%r13d
  cmp    %r13d,%r15d
  jg     L98
L79:
  mov    %r14d,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%r14d
  and    $0x7,%r14d
  sub    %eax,%r14d
  cmp    $0x7,%r14d
  ja     L91
  mov    %r14d,%r14d
  lea    D5(%rip),%rdx
  movslq (%rdx,%r14,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L63:
  xor    %eax,%ebx
  mov    %ebx,%edi
  call   <tzbytecnt@plt>
  add    %eax,%r13d
L91:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    $0x0,%r13d
  jmp    L79
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r12)
  jne    L91
  add    $0x4,%r12
  add    $0x4,%rbp
  add    $0x1,%r13d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r12)
  jne    L91
  add    $0x4,%r12
  add    $0x4,%rbp
  add    $0x1,%r13d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r12)
  jne    L91
  add    $0x4,%r12
  add    $0x4,%rbp
  add    $0x1,%r13d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r12)
  jne    L91
  add    $0x4,%r12
  add    $0x4,%rbp
  add    $0x1,%r13d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r12)
  jne    L91
  add    $0x4,%r12
  add    $0x4,%rbp
  add    $0x1,%r13d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r12)
  jne    L91
  add    $0x4,%r12
  add    $0x4,%rbp
  add    $0x1,%r13d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r12)
  sete   %al
  movzbl %al,%eax
  add    %eax,%r13d
  jmp    L91
```

assistant: ```c
int compare(uint8_t *str1, uint8_t *str2, uint32_t max_length) {
  uint32_t count;
  uint64_t test;
  uint64_t loop_length;
  loop_length = max_length & ~0x7;
  for (count = 0; count < loop_length; count += 8) {
    test = load_u64(str1);
    test ^= load_u64(str2);
    if (test != 0)
      return count + tzbytecnt(test);
    str1 += 8;
    str2 += 8;
  }
  switch (max_length % 8) {
  case 7:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 6:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 5:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 4:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 3:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 2:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 1:
    if (*str1 != *str2)
      return count;
    count++;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compare>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  and    $0xfffffff8,%r13d
  jg     L103
  jmp    L84
  nopl   0x0(%rax)
L64:
  add    $0x8,%r15d
  add    $0x20,%r14
  add    $0x20,%rbp
  cmp    %r15d,%r13d
  jle    L84
L103:
  mov    %r14,%rdi
  call   <load_u64@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <load_u64@plt>
  cmp    %eax,%ebx
  je     L64
  xor    %eax,%ebx
  mov    %ebx,%edi
  call   <tzbytecnt@plt>
  add    %eax,%r15d
L8:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L84:
  mov    %r12d,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%r12d
  and    $0x7,%r12d
  sub    %eax,%r12d
  cmp    $0x7,%r12d
  ja     L8
  lea    D6(%rip),%rdx
  movslq (%rdx,%r12,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L8
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L8
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L8
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L8
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L8
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L8
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  sete   %al
  movzbl %al,%eax
  add    %eax,%r15d
  jmp    L8
```

assistant: ```c
int compare(uint8_t *str1, uint8_t *str2, uint32_t max_length) {
  uint32_t count;
  uint64_t test;
  uint64_t loop_length;
  loop_length = max_length & ~0x7;
  for (count = 0; count < loop_length; count += 8) {
    test = load_u64(str1);
    test ^= load_u64(str2);
    if (test != 0)
      return count + tzbytecnt(test);
    str1 += 8;
    str2 += 8;
  }
  switch (max_length % 8) {
  case 7:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 6:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 5:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 4:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 3:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 2:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 1:
    if (*str1 != *str2)
      return count;
    count++;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  and    $0xfffffff8,%r13d
  jg     L104
  jmp    L112
  nopl   0x0(%rax)
L106:
  add    $0x8,%r15d
  add    $0x20,%r14
  add    $0x20,%rbp
  cmp    %r15d,%r13d
  jle    L112
L104:
  mov    %r14,%rdi
  call   <load_u64@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <load_u64@plt>
  cmp    %eax,%ebx
  je     L106
  xor    %eax,%ebx
  mov    %ebx,%edi
  call   <tzbytecnt@plt>
  add    %eax,%r15d
L42:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L112:
  mov    %r12d,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%r12d
  and    $0x7,%r12d
  sub    %eax,%r12d
  cmp    $0x7,%r12d
  ja     L42
  lea    D7(%rip),%rdx
  movslq (%rdx,%r12,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L42
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L42
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L42
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L42
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L42
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  jne    L42
  add    $0x4,%r14
  add    $0x4,%rbp
  add    $0x1,%r15d
  mov    0x0(%rbp),%eax
  cmp    %eax,(%r14)
  sete   %al
  movzbl %al,%eax
  add    %eax,%r15d
  jmp    L42
```

assistant: ```c
int compare(uint8_t *str1, uint8_t *str2, uint32_t max_length) {
  uint32_t count;
  uint64_t test;
  uint64_t loop_length;
  loop_length = max_length & ~0x7;
  for (count = 0; count < loop_length; count += 8) {
    test = load_u64(str1);
    test ^= load_u64(str2);
    if (test != 0)
      return count + tzbytecnt(test);
    str1 += 8;
    str2 += 8;
  }
  switch (max_length % 8) {
  case 7:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 6:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 5:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 4:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 3:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 2:
    if (*str1++ != *str2++)
      return count;
    count++;
  case 1:
    if (*str1 != *str2)
      return count;
    count++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<call_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpl   $0x5,-0xc(%rbp)
  ja     L55
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D9(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x8(%rbp),%rdx
  mov    $0x0,%eax
  call   *%rdx
  jmp    L35
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rdx
  jmp    L35
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rcx
  jmp    L35
  mov    -0x8(%rbp),%r8
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%r8
  jmp    L35
  mov    -0x8(%rbp),%r8
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rsi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%r8
  jmp    L35
  mov    -0x8(%rbp),%r9
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rdi
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rsi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%r9
  jmp    L35
L55:
  nop
L35:
  leave
  ret
```

assistant: ```c
void call_func(void *func, int nb_args, void **args, unsigned char *args_type) {
  switch (nb_args) {
  case 0:
    ((void (*)())func)();
    break;
  case 1:
    ((void (*)())func)(args[0]);
    break;
  case 2:
    ((void (*)())func)(args[0], args[1]);
    break;
  case 3:
    ((void (*)())func)(args[0], args[1], args[2]);
    break;
  case 4:
    ((void (*)())func)(args[0], args[1], args[2], args[3]);
    break;
  case 5:
    ((void (*)())func)(args[0], args[1], args[2], args[3], args[4]);
    break;
  default:
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<call_func>:
  endbr64
  cmp    $0x5,%esi
  ja     L10
  sub    $0x8,%rsp
  mov    %rdi,%r9
  mov    %rdx,%rax
  mov    %esi,%esi
  lea    D7(%rip),%rcx
  movslq (%rcx,%rsi,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0x0,%eax
  call   *%rdi
L32:
  add    $0x8,%rsp
  ret
  mov    (%rax),%rdi
  mov    $0x0,%eax
  call   *%r9
  jmp    L32
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  mov    $0x0,%eax
  call   *%r9
  jmp    L32
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  mov    $0x0,%eax
  call   *%r9
  jmp    L32
  mov    0x18(%rax),%rcx
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  mov    $0x0,%eax
  call   *%r9
  jmp    L32
  mov    0x18(%rax),%rcx
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    0x20(%rax),%r8
  mov    (%rax),%rdi
  mov    $0x0,%eax
  call   *%r9
  jmp    L32
L10:
  ret
```

assistant: ```c
void call_func(void *func, int nb_args, void **args, unsigned char *args_type) {
  switch (nb_args) {
  case 0:
    ((void (*)())func)();
    break;
  case 1:
    ((void (*)())func)(args[0]);
    break;
  case 2:
    ((void (*)())func)(args[0], args[1]);
    break;
  case 3:
    ((void (*)())func)(args[0], args[1], args[2]);
    break;
  case 4:
    ((void (*)())func)(args[0], args[1], args[2], args[3]);
    break;
  case 5:
    ((void (*)())func)(args[0], args[1], args[2], args[3], args[4]);
    break;
  default:
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<call_func>:
  endbr64
  mov    %rdi,%r9
  mov    %rdx,%rax
  cmp    $0x5,%esi
  ja     L8
  lea    D8(%rip),%rcx
  mov    %esi,%esi
  movslq (%rcx,%rsi,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  cs nopw 0x0(%rax,%rax,1)
  mov    0x18(%rax),%rcx
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
  nopl   0x0(%rax)
  mov    0x18(%rax),%rcx
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    0x20(%rax),%r8
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
  xor    %eax,%eax
  jmp    *%rdi
  nopl   0x0(%rax)
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
  nopl   0x0(%rax)
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
L8:
  ret
```

assistant: ```c
void call_func(void *func, int nb_args, void **args, unsigned char *args_type) {
  switch (nb_args) {
  case 0:
    ((void (*)())func)();
    break;
  case 1:
    ((void (*)())func)(args[0]);
    break;
  case 2:
    ((void (*)())func)(args[0], args[1]);
    break;
  case 3:
    ((void (*)())func)(args[0], args[1], args[2]);
    break;
  case 4:
    ((void (*)())func)(args[0], args[1], args[2], args[3]);
    break;
  case 5:
    ((void (*)())func)(args[0], args[1], args[2], args[3], args[4]);
    break;
  default:
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<call_func>:
  endbr64
  mov    %rdi,%r9
  mov    %rdx,%rax
  cmp    $0x5,%esi
  ja     L1
  lea    D7(%rip),%rcx
  mov    %esi,%esi
  movslq (%rcx,%rsi,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  cs nopw 0x0(%rax,%rax,1)
  mov    0x18(%rax),%rcx
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
  nopl   0x0(%rax)
  mov    0x18(%rax),%rcx
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    0x20(%rax),%r8
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
  xor    %eax,%eax
  jmp    *%rdi
  nopl   0x0(%rax)
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
  nopl   0x0(%rax)
  mov    0x10(%rax),%rdx
  mov    0x8(%rax),%rsi
  mov    (%rax),%rdi
  xor    %eax,%eax
  jmp    *%r9
L1:
  ret
```

assistant: ```c
void call_func(void *func, int nb_args, void **args, unsigned char *args_type) {
  switch (nb_args) {
  case 0:
    ((void (*)())func)();
    break;
  case 1:
    ((void (*)())func)(args[0]);
    break;
  case 2:
    ((void (*)())func)(args[0], args[1]);
    break;
  case 3:
    ((void (*)())func)(args[0], args[1], args[2]);
    break;
  case 4:
    ((void (*)())func)(args[0], args[1], args[2], args[3]);
    break;
  case 5:
    ((void (*)())func)(args[0], args[1], args[2], args[3], args[4]);
    break;
  default:
    return;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetCharInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <FlushInput@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D13
type_infered: string

tool: D1:  %c

tool: D13: 


assistant: ```c
char GetCharInput(char *c) {
  scanf(" %c", c);
  FlushInput();
  printf("\n");
  *c = toupper(*c);
  return *c;
}
```