ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<sony_decrypt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  test   %edx,%edx
  jne    L59
L17:
  test   %r12d,%r12d
  je     L26
  mov    D16(%rip),%eax
  add    $0x1,%eax
  mov    %r12d,%r12d
  lea    0x0(%rbp,%r12,4),%r10
  lea    D32(%rip),%rdi
L35:
  lea    -0x1(%rax),%edx
  cmp    $0x1,%eax
  je     L70
  mov    %edx,%ecx
  and    $0x7f,%ecx
  lea    0x40(%rax),%edx
  and    $0x7f,%edx
  mov    %eax,%esi
  and    $0x7f,%esi
  mov    (%rdi,%rdx,4),%edx
  xor    (%rdi,%rsi,4),%edx
  mov    %ecx,%esi
  mov    %edx,(%rdi,%rsi,4)
  lea    0x4(%rbp),%rsi
  mov    %edx,%r8d
  xor    0x0(%rbp),%r8d
  mov    %r8d,-0x4(%rsi)
  lea    0x1(%rax),%r9d
  cmp    %rsi,%r10
  je     L97
  mov    %r9d,%eax
  mov    %rsi,%rbp
  jmp    L35
L59:
  lea    D32(%rip),%rax
  lea    0x10(%rax),%rsi
  mov    %rax,%rdx
L41:
  imul   $0x2e90edd,%ecx,%ecx
  add    $0x1,%ecx
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L41
  mov    D32(%rip),%edx
  xor    D28(%rip),%edx
  shr    $0x1f,%edx
  mov    D118(%rip),%ebx
  lea    (%rbx,%rbx,1),%ecx
  or     %ecx,%edx
  mov    %edx,D94(%rip)
  lea    D94(%rip),%rsi
L31:
  mov    (%rax),%edx
  xor    0x8(%rax),%edx
  add    %edx,%edx
  mov    0x4(%rax),%ecx
  xor    0xc(%rax),%ecx
  shr    $0x1f,%ecx
  or     %ecx,%edx
  mov    %edx,0x10(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L31
  movl   $0x0,D16(%rip)
  mov    $0x0,%eax
  lea    D32(%rip),%r13
L61:
  mov    %eax,%ebx
  mov    0x0(%r13,%rbx,4),%edi
  call   <htonl@plt>
  mov    %eax,0x0(%r13,%rbx,4)
  mov    D16(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D27(%rip)
  cmp    $0x7e,%eax
  jbe    L61
  jmp    L17
L97:
  mov    %eax,D27(%rip)
  mov    %ecx,%ecx
  lea    D32(%rip),%rax
  mov    %edx,(%rax,%rcx,4)
  mov    %r8d,0x0(%rbp)
  jmp    L26
L70:
  movl   $0x1,D27(%rip)
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sony_decrypt(unsigned *data, int len, int start, int key) {
  static unsigned pad[128], p;
  if (start) {
    for (p = 0; p < 4; p++)
      pad[p] = key = key * 48828125 + 1;
    pad[3] = pad[3] << 1 | (pad[0] ^ pad[2]) >> 31;
    for (p = 4; p < 127; p++)
      pad[p] = (pad[p - 4] ^ pad[p - 2]) << 1 | (pad[p - 3] ^ pad[p - 1]) >> 31;
    for (p = 0; p < 127; p++)
      pad[p] = htonl(pad[p]);
  }
  while (len-- && p++)
    *data++ ^= pad[(p - 1) & 127] = pad[p & 127] ^ pad[(p + 64) & 127];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sony_decrypt>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L59
  lea    D121(%rip),%rdx
  lea    -0x10(%rdx),%r13
  mov    %r13,%rax
  nopw   0x0(%rax,%rax,1)
L47:
  imul   $0x2e90edd,%ecx,%ecx
  add    $0x4,%rax
  add    $0x1,%ecx
  mov    %ecx,-0x4(%rax)
  cmp    %rax,%rdx
  jne    L47
  mov    D40(%rip),%ecx
  mov    D117(%rip),%esi
  mov    D64(%rip),%eax
  mov    %ecx,%edx
  xor    %esi,%edx
  add    %eax,%eax
  shr    $0x1f,%edx
  or     %edx,%eax
  lea    D79(%rip),%rdx
  mov    %eax,D97(%rip)
  lea    0x1e8(%rdx),%rdi
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L64:
  mov    0x8(%rdx),%esi
  add    $0x4,%rdx
L11:
  xor    %esi,%ecx
  lea    (%rcx,%rcx,1),%esi
  mov    (%rdx),%ecx
  xor    %ecx,%eax
  shr    $0x1f,%eax
  or     %esi,%eax
  mov    %eax,0xc(%rdx)
  cmp    %rdx,%rdi
  jne    L64
  movl   $0x0,D97(%rip)
  xor    %eax,%eax
  nopl   0x0(%rax)
L69:
  mov    %eax,%ebp
  mov    0x0(%r13,%rbp,4),%edi
  call   <htonl@plt>
  mov    %eax,0x0(%r13,%rbp,4)
  mov    D97(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D74(%rip)
  cmp    $0x7e,%eax
  jbe    L69
L59:
  test   %r12d,%r12d
  je     L77
  mov    D74(%rip),%eax
  lea    (%rbx,%r12,4),%r8
  lea    D40(%rip),%rsi
  add    $0x1,%eax
  jmp    L44
L19:
  lea    0x40(%rax),%edx
  mov    %eax,%edi
  and    $0x7f,%ecx
  add    $0x4,%rbx
  and    $0x7f,%edx
  and    $0x7f,%edi
  mov    (%rsi,%rdx,4),%edx
  xor    (%rsi,%rdi,4),%edx
  mov    %edx,(%rsi,%rcx,4)
  xor    %edx,-0x4(%rbx)
  lea    0x1(%rax),%edx
  cmp    %r8,%rbx
  je     L4
  mov    %edx,%eax
L44:
  lea    -0x1(%rax),%ecx
  cmp    $0x1,%eax
  jne    L19
  movl   $0x1,D74(%rip)
L77:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  mov    %eax,D74(%rip)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sony_decrypt(unsigned *data, int len, int start, int key) {
  static unsigned pad[128], p;
  if (start) {
    for (p = 0; p < 4; p++)
      pad[p] = key = key * 48828125 + 1;
    pad[3] = pad[3] << 1 | (pad[0] ^ pad[2]) >> 31;
    for (p = 4; p < 127; p++)
      pad[p] = (pad[p - 4] ^ pad[p - 2]) << 1 | (pad[p - 3] ^ pad[p - 1]) >> 31;
    for (p = 0; p < 127; p++)
      pad[p] = htonl(pad[p]);
  }
  while (len-- && p++)
    *data++ ^= pad[(p - 1) & 127] = pad[p & 127] ^ pad[(p + 64) & 127];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x18(%rbp)
  movl   $0xa,-0x14(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  movl   $0xa,(%rax)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D55
type: string
name: extract_symbolic_data
arguments: label: D29
type: string
name: extract_symbolic_data
arguments: label: D13
type: string

tool: D24: &hoge..%p


tool: D4: &piyo..%p


tool: D55: &hoge_p..%p


tool: D29: *hoge_p..%d


tool: D13: hoge..%d


assistant: ```c
int main(void) {
  int hoge = 5;
  int piyo = 10;
  int *hoge_p;
  printf("&hoge..%p\n", &hoge);
  printf("&piyo..%p\n", &piyo);
  printf("&hoge_p..%p\n", &hoge_p);
  hoge_p = &hoge;
  printf("&hoge_p..%p\n", hoge_p);
  printf("*hoge_p..%d\n", *hoge_p);
  *hoge_p = 10;
  printf("hoge..%d\n", hoge);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x8(%rsp)
  movl   $0xa,0xc(%rsp)
  lea    0x8(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D49(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,0x10(%rsp)
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  movl   $0xa,(%rax)
  mov    0x8(%rsp),%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string
name: extract_symbolic_data
arguments: tag: D49
type_infered: string
name: extract_symbolic_data
arguments: tag: D45
type_infered: string
name: extract_symbolic_data
arguments: tag: D16
type_infered: string

tool: D30: &hoge..%p


tool: D20: &piyo..%p


tool: D49: &hoge_p..%p


tool: D45: *hoge_p..%d


tool: D16: hoge..%d


assistant: ```c
int main(void) {
  int hoge = 5;
  int piyo = 10;
  int *hoge_p;
  printf("&hoge..%p\n", &hoge);
  printf("&piyo..%p\n", &piyo);
  printf("&hoge_p..%p\n", &hoge_p);
  hoge_p = &hoge;
  printf("&hoge_p..%p\n", hoge_p);
  printf("*hoge_p..%d\n", *hoge_p);
  *hoge_p = 10;
  printf("hoge..%d\n", hoge);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%rdi
  lea    D10(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  movl   $0x5,0x8(%rsp)
  mov    %rbp,%rsi
  movl   $0xa,0xc(%rsp)
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rbp,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    D47(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    D36(%rip),%rdi
  movl   $0xa,(%rax)
  mov    0x8(%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
datatype: string
name: disassemble_data
arguments: tag: D10
datatype: string
name: disassemble_data
arguments: tag: D49
datatype: string
name: disassemble_data
arguments: tag: D47
datatype: string
name: disassemble_data
arguments: tag: D36
datatype: string

tool: D25: &hoge..%p


tool: D10: &hoge_p..%p


tool: D49: &piyo..%p


tool: D47: *hoge_p..%d


tool: D36: hoge..%d


assistant: ```c
int main(void) {
  int hoge = 5;
  int piyo = 10;
  int *hoge_p;
  printf("&hoge..%p\n", &hoge);
  printf("&piyo..%p\n", &piyo);
  printf("&hoge_p..%p\n", &hoge_p);
  hoge_p = &hoge;
  printf("&hoge_p..%p\n", hoge_p);
  printf("*hoge_p..%d\n", *hoge_p);
  *hoge_p = 10;
  printf("hoge..%d\n", hoge);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  lea    D47(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  movl   $0x5,0x8(%rsp)
  mov    %rbp,%rsi
  movl   $0xa,0xc(%rsp)
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rbp,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    D12(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    D8(%rip),%rdi
  movl   $0xa,(%rax)
  mov    0x8(%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
datatype: string
name: unpack_data
arguments: tag: D47
datatype: string
name: unpack_data
arguments: tag: D39
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D8
datatype: string

tool: D23: &hoge..%p


tool: D47: &hoge_p..%p


tool: D39: &piyo..%p


tool: D12: *hoge_p..%d


tool: D8: hoge..%d


assistant: ```c
int main(void) {
  int hoge = 5;
  int piyo = 10;
  int *hoge_p;
  printf("&hoge..%p\n", &hoge);
  printf("&piyo..%p\n", &piyo);
  printf("&hoge_p..%p\n", &hoge_p);
  hoge_p = &hoge;
  printf("&hoge_p..%p\n", hoge_p);
  printf("*hoge_p..%d\n", *hoge_p);
  *hoge_p = 10;
  printf("hoge..%d\n", hoge);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<child_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x82,-0x4(%rbp)
  je     L0
  cmpl   $0x82,-0x4(%rbp)
  jg     L40
  cmpl   $0x80,-0x4(%rbp)
  je     L30
  cmpl   $0x81,-0x4(%rbp)
  je     L50
  jmp    L40
L0:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L73
L30:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L73
L50:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L73
L40:
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  mov    %eax,%edi
  call   <exit@plt>
  nop
L73:
  nop
  leave
  ret
```

assistant: ```c
void child_handler(int signum) {
  switch (signum) {
  case SIGALRM:
    exit(1);
    break;
  case SIGUSR1:
    exit(0);
    break;
  case SIGCHLD:
    exit(1);
    break;
  default:
    exit((int)SIG_DFL);
    break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<child_handler>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x81,%edi
  je     L56
  cmp    $0x82,%edi
  je     L47
  cmp    $0x80,%edi
  je     L53
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L35
L47:
  mov    $0x1,%edi
  call   <exit@plt>
L35:
  add    $0x8,%rsp
  ret
L53:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L35
L56:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L35
```

assistant: ```c
void child_handler(int signum) {
  switch (signum) {
  case SIGALRM:
    exit(1);
    break;
  case SIGUSR1:
    exit(0);
    break;
  case SIGCHLD:
    exit(1);
    break;
  default:
    exit((int)SIG_DFL);
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<child_handler>:
  endbr64
  cmp    $0x80,%edi
  je     L11
  sub    $0x81,%edi
  cmp    $0x1,%edi
  ja     L8
  mov    $0x1,%edi
  jmp    1050 <exit@plt>
  nopl   0x0(%rax)
L11:
  xor    %edi,%edi
  jmp    1050 <exit@plt>
  nop
L8:
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void child_handler(int signum) {
  switch (signum) {
  case SIGALRM:
    exit(1);
    break;
  case SIGUSR1:
    exit(0);
    break;
  case SIGCHLD:
    exit(1);
    break;
  default:
    exit((int)SIG_DFL);
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<child_handler>:
  endbr64
  cmp    $0x80,%edi
  je     L9
  sub    $0x81,%edi
  cmp    $0x1,%edi
  ja     L16
  mov    $0x1,%edi
  jmp    1050 <exit@plt>
  nopl   0x0(%rax)
L9:
  xor    %edi,%edi
  jmp    1050 <exit@plt>
  nop
L16:
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void child_handler(int signum) {
  switch (signum) {
  case SIGALRM:
    exit(1);
    break;
  case SIGUSR1:
    exit(0);
    break;
  case SIGCHLD:
    exit(1);
    break;
  default:
    exit((int)SIG_DFL);
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FindInTheWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  movb   $0x0,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x2(%rbp)
  jmp    L16
L36:
  movsbq -0x2(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L8
  movsbq -0x2(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1,(%rax)
  movb   $0x1,-0x1(%rbp)
L8:
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %al,-0x2(%rbp)
  jl     L36
  cmpb   $0x0,-0x1(%rbp)
  jne    L12
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %dl,(%rax)
L12:
  nop
  leave
  ret
```

assistant: ```c
void FindInTheWord(char MotSecret[], char Discover[], char Letter, char *Essai) {
  char i = 0, Find = 0;
  for (i = 0; i < strlen(MotSecret); i++) {
    if (Letter == MotSecret[i]) {
      Discover[i] = 1;
      Find = 1;
    }
  }
  if (Find == 0) {
    *Essai = *Essai - 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<FindInTheWord>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rcx,%r15
  mov    %edx,%r12d
  mov    $0x0,%r14d
  mov    $0x0,%ebx
  jmp    L30
L17:
  add    $0x1,%ebx
L30:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jle    L28
  movsbq %bl,%rax
  cmp    %r12b,0x0(%rbp,%rax,1)
  jne    L17
  movb   $0x1,0x0(%r13,%rax,1)
  mov    $0x1,%r14d
  jmp    L17
L28:
  test   %r14b,%r14b
  jne    L32
  subb   $0x1,(%r15)
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void FindInTheWord(char MotSecret[], char Discover[], char Letter, char *Essai) {
  char i = 0, Find = 0;
  for (i = 0; i < strlen(MotSecret); i++) {
    if (Letter == MotSecret[i]) {
      Discover[i] = 1;
      Find = 1;
    }
  }
  if (Find == 0) {
    *Essai = *Essai - 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FindInTheWord>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L29
  nopl   (%rax)
L38:
  movsbq %bl,%rax
  cmp    %r12b,0x0(%rbp,%rax,1)
  jne    L22
  movb   $0x1,0x0(%r13,%rax,1)
  mov    $0x1,%r14d
L22:
  add    $0x1,%ebx
L29:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jg     L38
  test   %r14b,%r14b
  jne    L39
  subb   $0x1,(%r15)
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void FindInTheWord(char MotSecret[], char Discover[], char Letter, char *Essai) {
  char i = 0, Find = 0;
  for (i = 0; i < strlen(MotSecret); i++) {
    if (Letter == MotSecret[i]) {
      Discover[i] = 1;
      Find = 1;
    }
  }
  if (Find == 0) {
    *Essai = *Essai - 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<FindInTheWord>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L35
  nopl   (%rax)
L29:
  movsbq %bl,%rax
  cmp    %r12b,0x0(%rbp,%rax,1)
  jne    L12
  movb   $0x1,0x0(%r13,%rax,1)
  mov    $0x1,%r14d
L12:
  add    $0x1,%ebx
L35:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jg     L29
  test   %r14b,%r14b
  jne    L7
  subb   $0x1,(%r15)
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void FindInTheWord(char MotSecret[], char Discover[], char Letter, char *Essai) {
  char i = 0, Find = 0;
  for (i = 0; i < strlen(MotSecret); i++) {
    if (Letter == MotSecret[i]) {
      Discover[i] = 1;
      Find = 1;
    }
  }
  if (Find == 0) {
    *Essai = *Essai - 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_mem(void const *p, void const *ctx) {
  (void)ctx;
  free((void *)p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_mem>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void free_mem(void const *p, void const *ctx) {
  (void)ctx;
  free((void *)p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<free_mem>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void free_mem(void const *p, void const *ctx) {
  (void)ctx;
  free((void *)p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_mem>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void free_mem(void const *p, void const *ctx) {
  (void)ctx;
  free((void *)p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<plot_hline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L30
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L30:
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L15
L20:
  mov    -0x18(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    $0xe003,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <plot_pixel@plt>
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L20
  nop
  leave
  ret
```

assistant: ```c
void plot_hline(int start_x, int start_y, int length) {
  int x;
  int init_x;
  int end_x;
  if (length > 0) {
    init_x = start_x;
    end_x = start_x + length;
  } else {
    init_x = start_x + length;
    end_x = start_x;
  }
  for (x = init_x; x < end_x; x++)
    plot_pixel(x, start_y, 0xE003);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<plot_hline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    (%rdx,%rdi,1),%r12d
  test   %edx,%edx
  jle    L13
L7:
  cmp    %r12d,%ebx
  jge    L33
L12:
  mov    $0xe003,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <plot_pixel@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L12
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %edi,%r12d
  lea    (%rdx,%rdi,1),%ebx
  jmp    L7
```

assistant: ```c
void plot_hline(int start_x, int start_y, int length) {
  int x;
  int init_x;
  int end_x;
  if (length > 0) {
    init_x = start_x;
    end_x = start_x + length;
  } else {
    init_x = start_x + length;
    end_x = start_x;
  }
  for (x = init_x; x < end_x; x++)
    plot_pixel(x, start_y, 0xE003);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<plot_hline>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    (%rdx,%rdi,1),%ebx
  test   %edx,%edx
  jle    L20
  mov    %ebx,%eax
  mov    %edi,%ebx
  mov    %eax,%ebp
L20:
  cmp    %ebp,%ebx
  jge    L26
  xchg   %ax,%ax
L12:
  mov    %ebx,%edi
  mov    $0xe003,%edx
  mov    %r12d,%esi
  add    $0x1,%ebx
  call   <plot_pixel@plt>
  cmp    %ebx,%ebp
  jne    L12
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void plot_hline(int start_x, int start_y, int length) {
  int x;
  int init_x;
  int end_x;
  if (length > 0) {
    init_x = start_x;
    end_x = start_x + length;
  } else {
    init_x = start_x + length;
    end_x = start_x;
  }
  for (x = init_x; x < end_x; x++)
    plot_pixel(x, start_y, 0xE003);
  return;
}
```