ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<intSize>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int intSize() {
  int intArray[10];
  int *intPtr1;
  int *intPtr2;
  return 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<intSize>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int intSize() {
  int intArray[10];
  int *intPtr1;
  int *intPtr2;
  return 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<intSize>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int intSize() {
  int intArray[10];
  int *intPtr1;
  int *intPtr2;
  return 2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L14:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_strlen(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    i = i + 1;
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L0
  mov    $0x1,%eax
L20:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L20
L23:
  mov    %edx,%eax
  ret
L0:
  mov    $0x0,%edx
  jmp    L23
```

assistant: ```c
int my_strlen(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    i = i + 1;
  }
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x1,%eax
  xchg   %ax,%ax
L13:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int my_strlen(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    i = i + 1;
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  mov    $0x1,%eax
  xchg   %ax,%ax
L13:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int my_strlen(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    i = i + 1;
  }
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s2funxzr_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    0x28(%rbp),%rax
  movss  (%rax),%xmm4
  mov    0x20(%rbp),%rax
  movss  (%rax),%xmm3
  mov    0x18(%rbp),%rax
  mov    (%rax),%ecx
  mov    0x10(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x40(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edi
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rax
  movaps %xmm4,%xmm5
  movaps %xmm3,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %edi,%xmm0
  mov    %rax,%rdi
  call   <s2funxzr@plt>
  nop
  leave
  ret
```

assistant: ```c
void s2funxzr_(void *fxz, int *nx, int *nz, float *xmin, float *xmax, float *zmin, float *zmax, int *ctl, float *rmin, float *rmax) {
  float (*the_fxz)(float *, float *) = (float (*)(float *, float *))fxz;
  s2funxzr(the_fxz, *nx, *nz, *xmin, *xmax, *zmin, *zmax, *ctl, *rmin, *rmax);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s2funxzr_>:
  endbr64
  sub    $0x8,%rsp
  mov    %rcx,%rax
  mov    0x28(%rsp),%rcx
  movss  (%rcx),%xmm5
  mov    0x20(%rsp),%rcx
  movss  (%rcx),%xmm4
  mov    0x18(%rsp),%rcx
  mov    (%rcx),%ecx
  mov    0x10(%rsp),%r10
  movss  (%r10),%xmm3
  movss  (%r9),%xmm2
  movss  (%r8),%xmm1
  movss  (%rax),%xmm0
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  call   <s2funxzr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void s2funxzr_(void *fxz, int *nx, int *nz, float *xmin, float *xmax, float *zmin, float *zmax, int *ctl, float *rmin, float *rmax) {
  float (*the_fxz)(float *, float *) = (float (*)(float *, float *))fxz;
  s2funxzr(the_fxz, *nx, *nz, *xmin, *xmax, *zmin, *zmax, *ctl, *rmin, *rmax);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s2funxzr_>:
  endbr64
  mov    0x20(%rsp),%rax
  mov    %rcx,%r10
  movss  (%r9),%xmm2
  movss  (%r8),%xmm1
  movss  (%r10),%xmm0
  movss  (%rax),%xmm5
  mov    0x18(%rsp),%rax
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  movss  (%rax),%xmm4
  mov    0x10(%rsp),%rax
  mov    (%rax),%ecx
  mov    0x8(%rsp),%rax
  movss  (%rax),%xmm3
  jmp    1050 <s2funxzr@plt>
```

assistant: ```c
void s2funxzr_(void *fxz, int *nx, int *nz, float *xmin, float *xmax, float *zmin, float *zmax, int *ctl, float *rmin, float *rmax) {
  float (*the_fxz)(float *, float *) = (float (*)(float *, float *))fxz;
  s2funxzr(the_fxz, *nx, *nz, *xmin, *xmax, *zmin, *zmax, *ctl, *rmin, *rmax);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<s2funxzr_>:
  endbr64
  mov    0x20(%rsp),%rax
  mov    %rcx,%r10
  movss  (%r9),%xmm2
  movss  (%r8),%xmm1
  movss  (%r10),%xmm0
  movss  (%rax),%xmm5
  mov    0x18(%rsp),%rax
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  movss  (%rax),%xmm4
  mov    0x10(%rsp),%rax
  mov    (%rax),%ecx
  mov    0x8(%rsp),%rax
  movss  (%rax),%xmm3
  jmp    1050 <s2funxzr@plt>
```

assistant: ```c
void s2funxzr_(void *fxz, int *nx, int *nz, float *xmin, float *xmax, float *zmin, float *zmax, int *ctl, float *rmin, float *rmax) {
  float (*the_fxz)(float *, float *) = (float (*)(float *, float *))fxz;
  s2funxzr(the_fxz, *nx, *nz, *xmin, *xmax, *zmin, *zmax, *ctl, *rmin, *rmax);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ccnl_ndntlv_prependNonNegIntVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L60:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  test   %eax,%eax
  jg     L7
  mov    $0xffffffff,%eax
  jmp    L79
L7:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
  shrl   $0x8,-0x14(%rbp)
L6:
  cmpl   $0x0,-0x14(%rbp)
  jne    L60
  mov    -0x8(%rbp),%eax
  cltq
  lea    D4(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L16:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  test   %eax,%eax
  jg     L29
  mov    $0xffffffff,%eax
  jmp    L79
L29:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x4(%rbp)
  jg     L16
  mov    -0x8(%rbp),%eax
L79:
  pop    %rbp
  ret
```

assistant: ```c
int ccnl_ndntlv_prependNonNegIntVal(unsigned int val, int *offset, unsigned char *buf) {
  int len = 0, i;
  static char fill[] = {1, 0, 0, 1, 0, 3, 2, 1, 0};
  while (val) {
    if ((*offset)-- < 1)
      return -1;
    buf[*offset] = (unsigned char)(val & 0xff);
    len++;
    val = val >> 8;
  }
  for (i = fill[len]; i > 0; i--) {
    if ((*offset)-- < 1)
      return -1;
    buf[*offset] = 0;
    len++;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ccnl_ndntlv_prependNonNegIntVal>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdx,%r8
  test   %edi,%edi
  je     L48
  mov    $0x0,%esi
L7:
  mov    (%rcx),%edx
  lea    -0x1(%rdx),%eax
  mov    %eax,(%rcx)
  test   %edx,%edx
  jle    L45
  cltq
  mov    %dil,(%r8,%rax,1)
  add    $0x1,%esi
  shr    $0x8,%edi
  jne    L7
  movslq %esi,%rax
  lea    D2(%rip),%rdx
  movsbl (%rdx,%rax,1),%eax
  test   %eax,%eax
  jle    L38
L12:
  mov    %esi,%edx
  add    %eax,%esi
L41:
  mov    (%rcx),%edi
  lea    -0x1(%rdi),%eax
  mov    %eax,(%rcx)
  test   %edi,%edi
  jle    L11
  cltq
  movb   $0x0,(%r8,%rax,1)
  add    $0x1,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  test   %eax,%eax
  jg     L41
  jmp    L54
L48:
  mov    $0x1,%eax
  mov    $0x0,%esi
  jmp    L12
L45:
  mov    $0xffffffff,%edx
L54:
  mov    %edx,%eax
  ret
L38:
  mov    %esi,%edx
  jmp    L54
L11:
  mov    $0xffffffff,%edx
  jmp    L54
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2: 

assistant: ```c
int ccnl_ndntlv_prependNonNegIntVal(unsigned int val, int *offset, unsigned char *buf) {
  int len = 0, i;
  static char fill[] = {1, 0, 0, 1, 0, 3, 2, 1, 0};
  while (val) {
    if ((*offset)-- < 1)
      return -1;
    buf[*offset] = (unsigned char)(val & 0xff);
    len++;
    val = val >> 8;
  }
  for (i = fill[len]; i > 0; i--) {
    if ((*offset)-- < 1)
      return -1;
    buf[*offset] = 0;
    len++;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ccnl_ndntlv_prependNonNegIntVal>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdx,%r8
  test   %edi,%edi
  je     L16
  xor    %eax,%eax
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L74:
  movslq %edx,%rdx
  add    $0x1,%eax
  mov    %dil,(%r8,%rdx,1)
  shr    $0x8,%edi
  je     L94
L49:
  mov    (%rcx),%esi
  lea    -0x1(%rsi),%edx
  mov    %edx,(%rcx)
  test   %esi,%esi
  jg     L74
L48:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L94:
  movslq %eax,%rdx
  lea    D8(%rip),%rsi
  movsbl (%rsi,%rdx,1),%edi
  test   %edi,%edi
  jle    L55
L0:
  add    %eax,%edi
  jmp    L77
  cs nopw 0x0(%rax,%rax,1)
L1:
  movslq %edx,%rdx
  add    $0x1,%eax
  movb   $0x0,(%r8,%rdx,1)
  mov    %edi,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jle    L73
L77:
  mov    (%rcx),%esi
  lea    -0x1(%rsi),%edx
  mov    %edx,(%rcx)
  test   %esi,%esi
  jg     L1
  jmp    L48
L73:
  ret
L16:
  mov    $0x1,%edi
  xor    %eax,%eax
  jmp    L0
L55:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: 

assistant: ```c
int ccnl_ndntlv_prependNonNegIntVal(unsigned int val, int *offset, unsigned char *buf) {
  int len = 0, i;
  static char fill[] = {1, 0, 0, 1, 0, 3, 2, 1, 0};
  while (val) {
    if ((*offset)-- < 1)
      return -1;
    buf[*offset] = (unsigned char)(val & 0xff);
    len++;
    val = val >> 8;
  }
  for (i = fill[len]; i > 0; i--) {
    if ((*offset)-- < 1)
      return -1;
    buf[*offset] = 0;
    len++;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ccnl_ndntlv_prependNonNegIntVal>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdx,%r8
  test   %edi,%edi
  je     L87
  xor    %eax,%eax
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %edx,%rdx
  add    $0x1,%eax
  mov    %dil,(%r8,%rdx,1)
  shr    $0x8,%edi
  je     L99
L88:
  mov    (%rcx),%esi
  lea    -0x1(%rsi),%edx
  mov    %edx,(%rcx)
  test   %esi,%esi
  jg     L1
L35:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L99:
  movslq %eax,%rdx
  lea    D1(%rip),%rsi
  movsbl (%rsi,%rdx,1),%edi
  test   %edi,%edi
  jle    L71
L92:
  add    %eax,%edi
  jmp    L89
  cs nopw 0x0(%rax,%rax,1)
L76:
  movslq %edx,%rdx
  add    $0x1,%eax
  movb   $0x0,(%r8,%rdx,1)
  mov    %edi,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jle    L37
L89:
  mov    (%rcx),%esi
  lea    -0x1(%rsi),%edx
  mov    %edx,(%rcx)
  test   %esi,%esi
  jg     L76
  jmp    L35
L37:
  ret
L87:
  mov    $0x1,%edi
  xor    %eax,%eax
  jmp    L92
L71:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: 

assistant: ```c
int ccnl_ndntlv_prependNonNegIntVal(unsigned int val, int *offset, unsigned char *buf) {
  int len = 0, i;
  static char fill[] = {1, 0, 0, 1, 0, 3, 2, 1, 0};
  while (val) {
    if ((*offset)-- < 1)
      return -1;
    buf[*offset] = (unsigned char)(val & 0xff);
    len++;
    val = val >> 8;
  }
  for (i = fill[len]; i > 0; i--) {
    if ((*offset)-- < 1)
      return -1;
    buf[*offset] = 0;
    len++;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nibble2ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jle    L7
  mov    -0x4(%rbp),%eax
  add    $0x37,%eax
  jmp    L10
L7:
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t nibble2ascii(uint8_t value) {
  uint8_t result = value & 0x0f;
  if (result > 9)
    return result + 0x41 - 0x0A;
  else
    return result + 0x30;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nibble2ascii>:
  endbr64
  and    $0xf,%edi
  lea    0x37(%rdi),%edx
  lea    0x30(%rdi),%eax
  cmp    $0xa,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
uint8_t nibble2ascii(uint8_t value) {
  uint8_t result = value & 0x0f;
  if (result > 9)
    return result + 0x41 - 0x0A;
  else
    return result + 0x30;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nibble2ascii>:
  endbr64
  and    $0xf,%edi
  lea    0x37(%rdi),%edx
  lea    0x30(%rdi),%eax
  cmp    $0xa,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
uint8_t nibble2ascii(uint8_t value) {
  uint8_t result = value & 0x0f;
  if (result > 9)
    return result + 0x41 - 0x0A;
  else
    return result + 0x30;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string

tool: D30: GCD TEST will print the gcd from your input:

tool: D11: Please input two integer:

tool: D12: %d %d

tool: D23: The result of GCD(%d,%d) is %d


assistant: ```c
void gcd_test() {
  int i, a, b;
  int result;
  printf("GCD TEST will print the gcd from your input:\n");
  printf("Please input two integer:\n");
  scanf("%d %d", &a, &b);
  result = gcd(a, b);
  printf("The result of GCD(%d,%d) is %d\n", a, b, result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gcd_test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <gcd@plt>
  mov    %eax,%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
datatype: string
name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: string

tool: D27: GCD TEST will print the gcd from your input:

tool: D15: Please input two integer:

tool: D28: %d %d

tool: D26: The result of GCD(%d,%d) is %d


assistant: ```c
void gcd_test() {
  int i, a, b;
  int result;
  printf("GCD TEST will print the gcd from your input:\n");
  printf("Please input two integer:\n");
  scanf("%d %d", &a, &b);
  result = gcd(a, b);
  printf("The result of GCD(%d,%d) is %d\n", a, b, result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd_test>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <gcd@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D18(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D38
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string

tool: D12: GCD TEST will print the gcd from your input:

tool: D38: Please input two integer:

tool: D25: %d %d

tool: D18: The result of GCD(%d,%d) is %d


assistant: ```c
void gcd_test() {
  int i, a, b;
  int result;
  printf("GCD TEST will print the gcd from your input:\n");
  printf("Please input two integer:\n");
  scanf("%d %d", &a, &b);
  result = gcd(a, b);
  printf("The result of GCD(%d,%d) is %d\n", a, b, result);
}
```
user: What is the c source code of the assembly code below?

```asm
<gcd_test>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <gcd@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D26(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D27
data_type: string
name: unpack_data
arguments: tag: D24
data_type: string
name: unpack_data
arguments: tag: D11
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string

tool: D27: GCD TEST will print the gcd from your input:

tool: D24: Please input two integer:

tool: D11: %d %d

tool: D26: The result of GCD(%d,%d) is %d


assistant: ```c
void gcd_test() {
  int i, a, b;
  int result;
  printf("GCD TEST will print the gcd from your input:\n");
  printf("Please input two integer:\n");
  scanf("%d %d", &a, &b);
  result = gcd(a, b);
  printf("The result of GCD(%d,%d) is %d\n", a, b, result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<calcu__>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    0x1(%rdx),%eax
  pop    %rbp
  ret
```

assistant: ```c
int calcu__(unsigned char *s) {
  int score = 0;
  for (; *s;)
    score += *s++;
  return (score % 100) + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calcu__>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L10
  mov    $0x0,%eax
L25:
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L25
L17:
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  jmp    L17
```

assistant: ```c
int calcu__(unsigned char *s) {
  int score = 0;
  for (; *s;)
    score += *s++;
  return (score % 100) + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calcu__>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L7
  xor    %eax,%eax
  nopl   (%rax)
L10:
  add    $0x1,%rdi
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
  mov    %eax,%edx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x25,%rdx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int calcu__(unsigned char *s) {
  int score = 0;
  for (; *s;)
    score += *s++;
  return (score % 100) + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calcu__>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L3
  xor    %eax,%eax
  nopl   (%rax)
L7:
  add    $0x1,%rdi
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L7
  mov    %eax,%edx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x25,%rdx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int calcu__(unsigned char *s) {
  int score = 0;
  for (; *s;)
    score += *s++;
  return (score % 100) + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Clamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  movss  %xmm0,-0x8(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jg     L15
  pxor   %xmm0,%xmm0
  jmp    L17
L15:
  mov    -0x4(%rbp),%eax
  sub    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rbp),%xmm1
  divss  %xmm1,%xmm0
L17:
  pop    %rbp
  ret
```

assistant: ```c
float Clamp(int iters_left, float t) {
  if (iters_left < 3) {
    return 0.0;
  }
  return (iters_left - 2) * t / iters_left;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Clamp>:
  endbr64
  cmp    $0x2,%edi
  jle    L2
  lea    -0x2(%rdi),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm1
  divss  %xmm1,%xmm0
  ret
L2:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float Clamp(int iters_left, float t) {
  if (iters_left < 3) {
    return 0.0;
  }
  return (iters_left - 2) * t / iters_left;
}
```
user: What is the c source code of the assembly code below?

```asm
<Clamp>:
  endbr64
  cmp    $0x2,%edi
  jle    L0
  lea    -0x2(%rdi),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopl   (%rax)
L0:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float Clamp(int iters_left, float t) {
  if (iters_left < 3) {
    return 0.0;
  }
  return (iters_left - 2) * t / iters_left;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Clamp>:
  endbr64
  cmp    $0x2,%edi
  jle    L3
  lea    -0x2(%rdi),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopl   (%rax)
L3:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float Clamp(int iters_left, float t) {
  if (iters_left < 3) {
    return 0.0;
  }
  return (iters_left - 2) * t / iters_left;
}
```