ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D12(%rip),%rdi
  lea    D14(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L36
  mov    %rax,%rbp
  mov    $0x1,%r14d
  lea    D32(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x42,%r12d
  xor    %ebx,%ebx
  sub    %r14d,%r12d
  jmp    L39
  nopl   (%rax)
L10:
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
L39:
  mov    %rbp,%rdi
  call   <atoi@plt>
  cmp    %ebx,%eax
  jg     L10
  mov    %r15,%rsi
  xor    %edi,%edi
  xor    $0x1,%r14d
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L48
L36:
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
data_type: string
name: unpack_data
arguments: data_label: D14
data_type: string
name: unpack_data
arguments: data_label: D32
data_type: string
name: unpack_data
arguments: data_label: D35
data_type: string

tool: D12: %[^
]

tool: D14:  

tool: D32: %c

tool: 

assistant: ```c
int main(int argc, char const *argv[]) {
  char input[63], *data, output;
  int n, isREI = 1;
  scanf("%[^\n]", input);
  data = strtok(input, " ");
  while (data != NULL) {
    output = isREI ? 'A' : 'B';
    for (int i = 0; i < atoi(data); i++)
      printf("%c", output);
    isREI = isREI ? 0 : 1;
    data = strtok(NULL, " ");
  }
  puts("");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%rdi
  lea    D35(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L43
  mov    %rax,%rbp
  mov    $0x1,%r14d
  lea    D39(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x42,%r12d
  xor    %ebx,%ebx
  sub    %r14d,%r12d
  jmp    L34
  nopl   (%rax)
L12:
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
L34:
  mov    %rbp,%rdi
  call   <atoi@plt>
  cmp    %ebx,%eax
  jg     L12
  mov    %r15,%rsi
  xor    %edi,%edi
  xor    $0x1,%r14d
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L11
L43:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string
name: unpack_data
arguments: label: D35
data_type: string
name: unpack_data
arguments: label: D39
data_type: string
name: unpack_data
arguments: label: D5
data_type: string

tool: D0: %[^
]

tool: D35:  

tool: D39: %c

tool: 

assistant: ```c
int main(int argc, char const *argv[]) {
  char input[63], *data, output;
  int n, isREI = 1;
  scanf("%[^\n]", input);
  data = strtok(input, " ");
  while (data != NULL) {
    output = isREI ? 'A' : 'B';
    for (int i = 0; i < atoi(data); i++)
      printf("%c", output);
    isREI = isREI ? 0 : 1;
    data = strtok(NULL, " ");
  }
  puts("");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UARTFIFOLevelGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <UARTBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x18(%rbp),%rax
  add    $0x34,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x7,%eax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  and    $0x38,%eax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void UARTFIFOLevelGet(unsigned long ulBase, unsigned long *pulTxLevel, unsigned long *pulRxLevel) {
  unsigned long ulTemp;
  DEBUG_ASSERT(UARTBaseValid(ulBase));
  ulTemp = (*((volatile unsigned long *)(ulBase + 0x00000034)));
  *pulTxLevel = ulTemp & 0x00000007;
  *pulRxLevel = ulTemp & 0x00000038;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<UARTFIFOLevelGet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <UARTBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x34(%rbx),%rax
  mov    %rax,%rdx
  and    $0x7,%edx
  mov    %rdx,(%r12)
  and    $0x38,%eax
  mov    %rax,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void UARTFIFOLevelGet(unsigned long ulBase, unsigned long *pulTxLevel, unsigned long *pulRxLevel) {
  unsigned long ulTemp;
  DEBUG_ASSERT(UARTBaseValid(ulBase));
  ulTemp = (*((volatile unsigned long *)(ulBase + 0x00000034)));
  *pulTxLevel = ulTemp & 0x00000007;
  *pulRxLevel = ulTemp & 0x00000038;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UARTFIFOLevelGet>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <UARTBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x34(%rbx),%rax
  pop    %rbx
  mov    %rax,%rdx
  and    $0x38,%eax
  and    $0x7,%edx
  mov    %rdx,(%r12)
  mov    %rax,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void UARTFIFOLevelGet(unsigned long ulBase, unsigned long *pulTxLevel, unsigned long *pulRxLevel) {
  unsigned long ulTemp;
  DEBUG_ASSERT(UARTBaseValid(ulBase));
  ulTemp = (*((volatile unsigned long *)(ulBase + 0x00000034)));
  *pulTxLevel = ulTemp & 0x00000007;
  *pulRxLevel = ulTemp & 0x00000038;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UARTFIFOLevelGet>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <UARTBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x34(%rbx),%rax
  pop    %rbx
  mov    %rax,%rdx
  and    $0x38,%eax
  and    $0x7,%edx
  mov    %rdx,(%r12)
  mov    %rax,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void UARTFIFOLevelGet(unsigned long ulBase, unsigned long *pulTxLevel, unsigned long *pulRxLevel) {
  unsigned long ulTemp;
  DEBUG_ASSERT(UARTBaseValid(ulBase));
  ulTemp = (*((volatile unsigned long *)(ulBase + 0x00000034)));
  *pulTxLevel = ulTemp & 0x00000007;
  *pulRxLevel = ulTemp & 0x00000038;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getline_x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L5
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L1
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L6
  mov    -0x8(%rbp),%eax
  cltq
  jmp    L4
L6:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
L4:
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int getline_x(char *line, int max) {
  int c, i;
  for (i = 0; i < max && (c = getchar()) != EOF; i++)
    line[i] = c;
  line[i < max ? i : max - 1] = '\0';
  return (i == 0) ? 0 : 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getline_x>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L24
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L12:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L17
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %ebx,%r12d
  jne    L12
  mov    %r12d,%ebx
L2:
  sub    $0x1,%r12d
  movslq %r12d,%r12
  jmp    L38
L17:
  cmp    %ebx,%r12d
  jle    L2
  movslq %ebx,%r12
L38:
  movb   $0x0,0x0(%r13,%r12,1)
  test   %ebx,%ebx
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    $0x0,%ebx
  jmp    L2
```

assistant: ```c
int getline_x(char *line, int max) {
  int c, i;
  for (i = 0; i < max && (c = getchar()) != EOF; i++)
    line[i] = c;
  line[i < max ? i : max - 1] = '\0';
  return (i == 0) ? 0 : 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getline_x>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L1
  mov    D1(%rip),%r12
  movslq %esi,%r14
  xor    %ebx,%ebx
  jmp    L48
  nopl   0x0(%rax)
L41:
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L20
L48:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%r12)
  jne    L41
  xor    %eax,%eax
  test   %ebx,%ebx
  setne  %al
L5:
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L20:
  mov    $0x1,%eax
L1:
  sub    $0x1,%r15d
  movslq %r15d,%rbx
  jmp    L5
```

assistant: ```c
int getline_x(char *line, int max) {
  int c, i;
  for (i = 0; i < max && (c = getchar()) != EOF; i++)
    line[i] = c;
  line[i < max ? i : max - 1] = '\0';
  return (i == 0) ? 0 : 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<getline_x>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L14
  mov    D2(%rip),%r12
  movslq %esi,%r14
  xor    %ebx,%ebx
  jmp    L17
  nopl   0x0(%rax)
L15:
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L45
L17:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%r12)
  jne    L15
  xor    %eax,%eax
  test   %ebx,%ebx
  setne  %al
L7:
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L45:
  mov    $0x1,%eax
L14:
  sub    $0x1,%r15d
  movslq %r15d,%rbx
  jmp    L7
```

assistant: ```c
int getline_x(char *line, int max) {
  int c, i;
  for (i = 0; i < max && (c = getchar()) != EOF; i++)
    line[i] = c;
  line[i < max ? i : max - 1] = '\0';
  return (i == 0) ? 0 : 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tobf_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L22
L11:
  movb   $0x2b,-0x11(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jle    L1
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L38
  movb   $0x2b,-0x11(%rbp)
  jmp    L1
L38:
  cmpl   $0x0,-0xc(%rbp)
  jns    L40
  movb   $0x2d,-0x11(%rbp)
  jmp    L1
L40:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  movsbl -0x11(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_to@plt>
  addl   $0x1,-0x10(%rbp)
L22:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D7: .

assistant: ```c
void tobf_s(const char *S) {
  int len = strlen(S);
  for (int i = 0; i < len; ++i) {
    char ch = '+';
    int cha = S[i];
    if (i > 0) {
      cha = S[i] - S[i - 1];
      if (cha > 0)
        ch = '+';
      else if (cha < 0)
        ch = '-';
      else
        printf(".");
    }
    int zi = abs(cha);
    print_to(zi, ch);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tobf_s>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  movsbl (%r12),%ebx
  mov    %eax,%r13d
  mov    $0x1,%ebp
  mov    $0x2b,%esi
  lea    D8(%rip),%r14
  jmp    L47
L15:
  mov    $0x2b,%esi
L18:
  add    $0x1,%rbp
L47:
  movsbl %sil,%esi
  mov    %ebx,%edi
  neg    %edi
  cmovs  %ebx,%edi
  call   <print_to@plt>
  cmp    %r13,%rbp
  je     L4
  movsbl (%r12,%rbp,1),%ebx
  test   %ebp,%ebp
  jle    L15
  movsbl -0x1(%r12,%rbp,1),%eax
  sub    %eax,%ebx
  mov    $0x2b,%esi
  test   %ebx,%ebx
  jg     L18
  mov    $0x2d,%esi
  js     L18
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x2b,%esi
  jmp    L18
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: .

assistant: ```c
void tobf_s(const char *S) {
  int len = strlen(S);
  for (int i = 0; i < len; ++i) {
    char ch = '+';
    int cha = S[i];
    if (i > 0) {
      cha = S[i] - S[i - 1];
      if (cha > 0)
        ch = '+';
      else if (cha < 0)
        ch = '-';
      else
        printf(".");
    }
    int zi = abs(cha);
    print_to(zi, ch);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tobf_s>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L36
  lea    -0x1(%rax),%r12d
  movsbl 0x0(%rbp),%ebx
  mov    $0x2b,%esi
  lea    D1(%rip),%r13
  add    %rbp,%r12
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L58:
  add    $0x1,%rbp
L8:
  mov    %ebx,%edi
  neg    %edi
  cmovs  %ebx,%edi
  call   <print_to@plt>
  cmp    %r12,%rbp
  je     L36
  movsbl 0x1(%rbp),%ebx
  movsbl 0x0(%rbp),%eax
  mov    $0x2b,%esi
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L58
  mov    $0x2d,%esi
  jne    L58
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x2b,%esi
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: .

assistant: ```c
void tobf_s(const char *S) {
  int len = strlen(S);
  for (int i = 0; i < len; ++i) {
    char ch = '+';
    int cha = S[i];
    if (i > 0) {
      cha = S[i] - S[i - 1];
      if (cha > 0)
        ch = '+';
      else if (cha < 0)
        ch = '-';
      else
        printf(".");
    }
    int zi = abs(cha);
    print_to(zi, ch);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tobf_s>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L18
  lea    -0x1(%rax),%r12d
  movsbl 0x0(%rbp),%ebx
  mov    $0x2b,%esi
  lea    D3(%rip),%r13
  add    %rbp,%r12
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rbp
L44:
  mov    %ebx,%edi
  neg    %edi
  cmovs  %ebx,%edi
  call   <print_to@plt>
  cmp    %r12,%rbp
  je     L18
  movsbl 0x1(%rbp),%ebx
  movsbl 0x0(%rbp),%eax
  mov    $0x2b,%esi
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L25
  mov    $0x2d,%esi
  jne    L25
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x2b,%esi
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: .

assistant: ```c
void tobf_s(const char *S) {
  int len = strlen(S);
  for (int i = 0; i < len; ++i) {
    char ch = '+';
    int cha = S[i];
    if (i > 0) {
      cha = S[i] - S[i - 1];
      if (cha > 0)
        ch = '+';
      else if (cha < 0)
        ch = '-';
      else
        printf(".");
    }
    int zi = abs(cha);
    print_to(zi, ch);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  cmovbe %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L11
L19:
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  const size_t src_len = strlen(src);
  const size_t max_len = size - 1;
  const size_t len = src_len > max_len ? max_len : src_len;
  if (!size)
    return 0;
  memcpy(dst, src, len);
  dst[len] = 0;
  return src_len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlcpy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jne    L9
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  sub    $0x1,%rbx
  cmp    %rax,%rbx
  cmova  %rax,%rbx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %r13,%rbx
  jmp    L3
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  const size_t src_len = strlen(src);
  const size_t max_len = size - 1;
  const size_t len = src_len > max_len ? max_len : src_len;
  if (!size)
    return 0;
  memcpy(dst, src, len);
  dst[len] = 0;
  return src_len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strlcpy>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L4
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  sub    $0x1,%r12
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  cmp    %rax,%r12
  mov    %rax,%r13
  cmova  %rax,%r12
  mov    %r12,%rdx
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  mov    %r13,%r12
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  const size_t src_len = strlen(src);
  const size_t max_len = size - 1;
  const size_t len = src_len > max_len ? max_len : src_len;
  if (!size)
    return 0;
  memcpy(dst, src, len);
  dst[len] = 0;
  return src_len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlcpy>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L6
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  sub    $0x1,%r12
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  cmp    %rax,%r12
  mov    %rax,%r13
  cmova  %rax,%r12
  mov    %r12,%rdx
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  mov    %r13,%r12
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  const size_t src_len = strlen(src);
  const size_t max_len = size - 1;
  const size_t len = src_len > max_len ? max_len : src_len;
  if (!size)
    return 0;
  memcpy(dst, src, len);
  dst[len] = 0;
  return src_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<genYRotMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  pxor   %xmm0,%xmm0
  subsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,0x10(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,0x10(%rax)
  mov    -0x10(%rbp),%rax
  movsd  0x10(%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x30,%rax
  pxor   %xmm0,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x30,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,0x8(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x30(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,0x10(%rdx)
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: f64

tool: D4: 1

assistant: ```c
void genYRotMatrix(double theta, double m[3][3]) {
  m[0][0] = cos(theta);
  m[0][1] = 0.;
  m[0][2] = 0. - sin(theta);
  m[1][0] = 0.;
  m[1][1] = 1.;
  m[1][2] = 0.;
  m[2][0] = 0. - m[0][2];
  m[2][1] = 0.;
  m[2][2] = m[0][0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<genYRotMatrix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %rdi,%rbx
  call   <cos@plt>
  movsd  %xmm0,(%rbx)
  movq   $0x0,0x8(%rbx)
  movq   %rbp,%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbx)
  movq   $0x0,0x18(%rbx)
  mov    D7(%rip),%rax
  mov    %rax,0x20(%rbx)
  movq   $0x0,0x28(%rbx)
  pxor   %xmm0,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x30(%rbx)
  movq   $0x0,0x38(%rbx)
  movsd  (%rbx),%xmm0
  movsd  %xmm0,0x40(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type: f64

tool: D7: 1

assistant: ```c
void genYRotMatrix(double theta, double m[3][3]) {
  m[0][0] = cos(theta);
  m[0][1] = 0.;
  m[0][2] = 0. - sin(theta);
  m[1][0] = 0.;
  m[1][1] = 1.;
  m[1][2] = 0.;
  m[2][0] = 0. - m[0][2];
  m[2][1] = 0.;
  m[2][2] = m[0][0];
}
```