ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<getoutputbuffer>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    D2(%rip),%rax
  lea    0x2(%r8,%r8,1),%edx
  movslq (%rax),%rbx
  cmp    %ebx,%edx
  jg     L7
L38:
  cmp    %rbx,D41(%rip)
  mov    D44(%rip),%rax
  jae    L45
  test   %rax,%rax
  je     L31
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L29:
  mov    %rax,D43(%rip)
  mov    %rbx,D43(%rip)
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x2(%rax,%rax,1),%ebx
  movslq %ebx,%rbx
  jmp    L38
  nopl   0x0(%rax)
L31:
  mov    %rbx,%rdi
  call   <malloc@plt>
  jmp    L29
```

assistant: ```c
char *getoutputbuffer(char *str) {
  static char *rv;
  static size_t len = 0;
  size_t req;
  req = ((2 * strlen(str) + 2) > (BUFSIZ) ? (2 * strlen(str) + 2) : (BUFSIZ));
  if (req > len) {
    if (rv)
      rv = realloc(rv, req);
    else
      rv = malloc(req);
    len = req;
  }
  return rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getoutputbuffer>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    D19(%rip),%rax
  lea    0x2(%r8,%r8,1),%edx
  movslq (%rax),%rbx
  cmp    %ebx,%edx
  jg     L34
L44:
  cmp    %rbx,D45(%rip)
  mov    D39(%rip),%rax
  jae    L43
  test   %rax,%rax
  je     L37
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L31:
  mov    %rax,D12(%rip)
  mov    %rbx,D12(%rip)
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L34:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x2(%rax,%rax,1),%ebx
  movslq %ebx,%rbx
  jmp    L44
  nopl   0x0(%rax)
L37:
  mov    %rbx,%rdi
  call   <malloc@plt>
  jmp    L31
```

assistant: ```c
char *getoutputbuffer(char *str) {
  static char *rv;
  static size_t len = 0;
  size_t req;
  req = ((2 * strlen(str) + 2) > (BUFSIZ) ? (2 * strlen(str) + 2) : (BUFSIZ));
  if (req > len) {
    if (rv)
      rv = realloc(rv, req);
    else
      rv = malloc(req);
    len = req;
  }
  return rv;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vector3Normalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  divss  -0x4(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  divss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  divss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void vector3Normalize(float *a) {
  float len = sqrt(a[0] * a[0] + a[1] * a[1] + a[2] * a[2]);
  a[0] /= len;
  a[1] /= len;
  a[2] /= len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector3Normalize>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm2
  movss  0x8(%rdi),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  addss  %xmm2,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  (%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rbx)
  movss  0x4(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rbx)
  movss  0x8(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void vector3Normalize(float *a) {
  float len = sqrt(a[0] * a[0] + a[1] * a[1] + a[2] * a[2]);
  a[0] /= len;
  a[1] /= len;
  a[2] /= len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vector3Normalize>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm2
  push   %rbx
  mov    %rdi,%rbx
  movss  0x8(%rdi),%xmm1
  mulss  %xmm2,%xmm2
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  (%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rbx)
  movss  0x4(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rbx)
  movss  0x8(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void vector3Normalize(float *a) {
  float len = sqrt(a[0] * a[0] + a[1] * a[1] + a[2] * a[2]);
  a[0] /= len;
  a[1] /= len;
  a[2] /= len;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<vector3Normalize>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm2
  push   %rbx
  mov    %rdi,%rbx
  movss  0x8(%rdi),%xmm1
  mulss  %xmm2,%xmm2
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  (%rbx),%xmm1
  movss  0x4(%rbx),%xmm2
  divss  %xmm0,%xmm1
  divss  %xmm0,%xmm2
  unpcklps %xmm2,%xmm1
  movlps %xmm1,(%rbx)
  movss  0x8(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void vector3Normalize(float *a) {
  float len = sqrt(a[0] * a[0] + a[1] * a[1] + a[2] * a[2]);
  a[0] /= len;
  a[1] /= len;
  a[2] /= len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x41,-0xc(%rbp)
  movl   $0x61,-0x8(%rbp)
  movl   $0x30,-0x4(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L7
L32:
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x5a,-0xc(%rbp)
  jle    L32
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L28
L35:
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L28:
  cmpl   $0x7a,-0x8(%rbp)
  jle    L35
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L49
L44:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L49:
  cmpl   $0x39,-0x4(%rbp)
  jle    L44
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D22
type_infered: string
name: read_data
arguments: label: D40
type_infered: string
name: read_data
arguments: label: D30
type_infered: string
name: read_data
arguments: label: D20
type_infered: string

tool: D22: Caps

tool: D40: %c-%d


tool: D30: Small

tool: D20: Numbers

assistant: ```c
int main() {
  int num = 65;
  int num2, num3;
  num2 = 97;
  num3 = 48;
  printf("Caps\n");
  while (num < 91) {
    printf("%c-%d\n", num, num);
    num = num + 1;
  }
  printf("Small\n");
  while (num2 < 123) {
    printf("%c-%d\n", num2, num2);
    num2 = num2 + 1;
  }
  printf("Numbers\n");
  while (num3 < 58) {
    printf("%c-%d\n", num3, num3);
    num3 = num3 + 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D44(%rip),%rdi
  call   <puts@plt>
  mov    $0x41,%ebx
  lea    D50(%rip),%rbp
L11:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L11
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    $0x61,%ebx
  lea    D50(%rip),%rbp
L1:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x7b,%ebx
  jne    L1
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0x30,%ebx
  lea    D50(%rip),%rbp
L13:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x3a,%ebx
  jne    L13
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D44
type_guessed: string
name: parse_data
arguments: label: D50
type_guessed: string
name: parse_data
arguments: label: D32
type_guessed: string
name: parse_data
arguments: label: D34
type_guessed: string

tool: D44: Caps

tool: D50: %c-%d


tool: D32: Small

tool: D34: Numbers

assistant: ```c
int main() {
  int num = 65;
  int num2, num3;
  num2 = 97;
  num3 = 48;
  printf("Caps\n");
  while (num < 91) {
    printf("%c-%d\n", num, num);
    num = num + 1;
  }
  printf("Small\n");
  while (num2 < 123) {
    printf("%c-%d\n", num2, num2);
    num2 = num2 + 1;
  }
  printf("Numbers\n");
  while (num3 < 58) {
    printf("%c-%d\n", num3, num3);
    num3 = num3 + 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  lea    D38(%rip),%rbp
  push   %rbx
  mov    $0x41,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L18
  lea    D21(%rip),%rdi
  mov    $0x61,%ebx
  call   <puts@plt>
  nop
L0:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x7b,%ebx
  jne    L0
  lea    D6(%rip),%rdi
  mov    $0x30,%ebx
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x3a,%ebx
  jne    L15
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
type_guessed: string
name: retrieve_data
arguments: data_tag: D38
type_guessed: string
name: retrieve_data
arguments: data_tag: D21
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D39: Caps

tool: D38: %c-%d


tool: D21: Small

tool: D6: Numbers

assistant: ```c
int main() {
  int num = 65;
  int num2, num3;
  num2 = 97;
  num3 = 48;
  printf("Caps\n");
  while (num < 91) {
    printf("%c-%d\n", num, num);
    num = num + 1;
  }
  printf("Small\n");
  while (num2 < 123) {
    printf("%c-%d\n", num2, num2);
    num2 = num2 + 1;
  }
  printf("Numbers\n");
  while (num3 < 58) {
    printf("%c-%d\n", num3, num3);
    num3 = num3 + 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x41,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L16
  lea    D20(%rip),%rdi
  mov    $0x61,%ebx
  call   <puts@plt>
  nop
L13:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x7b,%ebx
  jne    L13
  lea    D9(%rip),%rdi
  mov    $0x30,%ebx
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x3a,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D39
type: string
name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D20
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D39: Caps

tool: D3: %c-%d


tool: D20: Small

tool: D9: Numbers

assistant: ```c
int main() {
  int num = 65;
  int num2, num3;
  num2 = 97;
  num3 = 48;
  printf("Caps\n");
  while (num < 91) {
    printf("%c-%d\n", num, num);
    num = num + 1;
  }
  printf("Small\n");
  while (num2 < 123) {
    printf("%c-%d\n", num2, num2);
    num2 = num2 + 1;
  }
  printf("Numbers\n");
  while (num3 < 58) {
    printf("%c-%d\n", num3, num3);
    num3 = num3 + 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<intToStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  cmpl   $0x0,-0x74(%rbp)
  jns    L34
  mov    -0x80(%rbp),%rax
  movb   $0x2d,(%rax)
  negl   -0x74(%rbp)
  movl   $0x1,-0x64(%rbp)
L34:
  mov    -0x74(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x68(%rbp),%eax
  cltq
  mov    %dl,-0x60(%rbp,%rax,1)
  addl   $0x1,-0x68(%rbp)
  mov    -0x74(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x74(%rbp)
  cmpl   $0x0,-0x74(%rbp)
  jne    L34
  subl   $0x1,-0x68(%rbp)
  jmp    L20
L44:
  mov    -0x68(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  lea    0x30(%rax),%ecx
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x64(%rbp)
  subl   $0x1,-0x68(%rbp)
L20:
  cmpl   $0x0,-0x68(%rbp)
  jns    L44
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void intToStr(int value, char result[]) {
  char intString[81];
  int i, j = 0;
  if (value < 0) {
    result[0] = '-';
    value = -value;
    j = 1;
  }
  do {
    intString[i] = value % 10;
    ++i;
    value = value / 10;
  } while (value != 0);
  for (--i; i >= 0; --i) {
    result[j] = intString[i] + '0';
    ++j;
  }
  result[j] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<intToStr>:
  endbr64
  sub    $0x68,%rsp
  mov    %edi,%edx
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r8d
  test   %edi,%edi
  js     L8
L58:
  mov    $0x0,%ecx
L24:
  mov    %ecx,%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  mov    %dl,(%rsp,%rcx,1)
  mov    %eax,%edx
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L24
  test   %edi,%edi
  js     L0
  movslq %edi,%rax
  lea    (%rsp,%rax,1),%rcx
  movslq %r8d,%rdx
  lea    (%r9,%rdx,1),%rax
  lea    0x1(%r9,%rdx,1),%rdx
  mov    %edi,%esi
  add    %rdx,%rsi
L44:
  movzbl (%rcx),%edx
  add    $0x30,%edx
  mov    %dl,(%rax)
  sub    $0x1,%rcx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L44
  lea    0x1(%rdi,%r8,1),%r8d
L0:
  movslq %r8d,%r8
  movb   $0x0,(%r9,%r8,1)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x68,%rsp
  ret
L8:
  movb   $0x2d,(%rsi)
  neg    %edx
  mov    $0x1,%r8d
  jmp    L58
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void intToStr(int value, char result[]) {
  char intString[81];
  int i, j = 0;
  if (value < 0) {
    result[0] = '-';
    value = -value;
    j = 1;
  }
  do {
    intString[i] = value % 10;
    ++i;
    value = value / 10;
  } while (value != 0);
  for (--i; i >= 0; --i) {
    result[j] = intString[i] + '0';
    ++j;
  }
  result[j] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<intToStr>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  mov    %rsi,%r8
  xor    %r9d,%r9d
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jns    L26
  movb   $0x2d,(%rsi)
  neg    %edx
  lea    0x1(%rsi),%rbx
  mov    $0x1,%r9d
L26:
  xor    %ecx,%ecx
  mov    %rsp,%r10
  mov    $0xcccccccd,%r11d
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %edx,%eax
  mov    %ecx,%edi
  imul   %r11,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  mov    %dl,(%r10,%rcx,1)
  mov    %edx,%esi
  add    $0x1,%rcx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L39
  test   %edi,%edi
  js     L4
  movslq %r9d,%rcx
  movslq %edi,%rax
  mov    %edi,%ebp
  lea    (%r8,%rcx,1),%rdx
  lea    0x1(%r8,%rcx,1),%rcx
  add    %r10,%rax
  add    %rbp,%rcx
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L16:
  movzbl (%rax),%esi
L48:
  add    $0x30,%esi
  add    $0x1,%rdx
  sub    $0x1,%rax
  mov    %sil,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L16
  lea    0x1(%rdi,%r9,1),%ebx
  movslq %ebx,%rbx
  add    %r8,%rbx
L4:
  movb   $0x0,(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void intToStr(int value, char result[]) {
  char intString[81];
  int i, j = 0;
  if (value < 0) {
    result[0] = '-';
    value = -value;
    j = 1;
  }
  do {
    intString[i] = value % 10;
    ++i;
    value = value / 10;
  } while (value != 0);
  for (--i; i >= 0; --i) {
    result[j] = intString[i] + '0';
    ++j;
  }
  result[j] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intToStr>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  mov    %rsi,%r9
  mov    %rsi,%rbx
  xor    %r10d,%r10d
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jns    L27
  movb   $0x2d,(%rsi)
  neg    %edx
  lea    0x1(%rsi),%rbx
  mov    $0x1,%r10d
L27:
  xor    %ecx,%ecx
  mov    %rsp,%rdi
  mov    $0xcccccccd,%r11d
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %edx,%eax
  mov    %ecx,%r8d
  imul   %r11,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  mov    %dl,(%rdi,%rcx,1)
  mov    %eax,%edx
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L40
  test   %r8d,%r8d
  js     L33
  movslq %r10d,%rcx
  movslq %r8d,%rax
  mov    %r8d,%esi
  lea    (%r9,%rcx,1),%rdx
  lea    0x1(%r9,%rcx,1),%rcx
  add    %rdi,%rax
  add    %rcx,%rsi
  cs nopw 0x0(%rax,%rax,1)
L1:
  movzbl (%rax),%ebx
  add    $0x1,%rdx
  sub    $0x1,%rax
  lea    0x30(%rbx),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%rsi
  jne    L1
  lea    0x1(%r8,%r10,1),%ebx
  movslq %ebx,%rbx
  add    %r9,%rbx
L33:
  movb   $0x0,(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x60,%rsp
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void intToStr(int value, char result[]) {
  char intString[81];
  int i, j = 0;
  if (value < 0) {
    result[0] = '-';
    value = -value;
    j = 1;
  }
  do {
    intString[i] = value % 10;
    ++i;
    value = value / 10;
  } while (value != 0);
  for (--i; i >= 0; --i) {
    result[j] = intString[i] + '0';
    ++j;
  }
  result[j] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<disable_apic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xf0,%edi
  call   <hal_io_apic_read32@plt>
  and    $0xfe,%ah
  mov    %eax,%esi
  mov    $0xf0,%edi
  call   <hal_io_apic_write32@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void disable_apic() {
  hal_io_apic_write32(0x000000F0, hal_io_apic_read32(0x000000F0) & (~0x100));
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<disable_apic>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0,%edi
  call   <hal_io_apic_read32@plt>
  and    $0xfe,%ah
  mov    %eax,%esi
  mov    $0xf0,%edi
  call   <hal_io_apic_write32@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void disable_apic() {
  hal_io_apic_write32(0x000000F0, hal_io_apic_read32(0x000000F0) & (~0x100));
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<disable_apic>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0,%edi
  call   <hal_io_apic_read32@plt>
  mov    $0xf0,%edi
  add    $0x8,%rsp
  and    $0xfe,%ah
  mov    %eax,%esi
  jmp    1060 <hal_io_apic_write32@plt>
```

assistant: ```c
void disable_apic() {
  hal_io_apic_write32(0x000000F0, hal_io_apic_read32(0x000000F0) & (~0x100));
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<disable_apic>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0,%edi
  call   <hal_io_apic_read32@plt>
  mov    $0xf0,%edi
  add    $0x8,%rsp
  and    $0xfe,%ah
  mov    %eax,%esi
  jmp    1060 <hal_io_apic_write32@plt>
```

assistant: ```c
void disable_apic() {
  hal_io_apic_write32(0x000000F0, hal_io_apic_read32(0x000000F0) & (~0x100));
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
L25:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L31
  mov    $0xffffffff,%eax
  jmp    L38
L31:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x18(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L38
L20:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  jmp    L25
L38:
  leave
  ret
```

assistant: ```c
int do_read(int fd, unsigned char *buffer, int size) {
  int n, from = 0;
  while (1) {
    n = read(fd, &buffer[from], size - from);
    if (n <= 0)
      return -1;
    if (n + from == size)
      return 0;
    from += n;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x0,%ebx
L22:
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r12,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L26
  add    %eax,%ebx
  cmp    %ebp,%ebx
  jne    L22
  mov    $0x0,%eax
  jmp    L17
L26:
  mov    $0xffffffff,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int do_read(int fd, unsigned char *buffer, int size) {
  int n, from = 0;
  while (1) {
    n = read(fd, &buffer[from], size - from);
    if (n <= 0)
      return -1;
    if (n + from == size)
      return 0;
    from += n;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<do_read>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L5:
  add    %eax,%ebx
  cmp    %ebp,%ebx
  je     L20
L15:
  mov    %ebp,%edx
  movslq %ebx,%rsi
  mov    %r13d,%edi
  sub    %ebx,%edx
  add    %r12,%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L5
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L20:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int do_read(int fd, unsigned char *buffer, int size) {
  int n, from = 0;
  while (1) {
    n = read(fd, &buffer[from], size - from);
    if (n <= 0)
      return -1;
    if (n + from == size)
      return 0;
    from += n;
  }
}
```