ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<p>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%eax
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%r11
  mov    (%r11),%r8d
  cmp    %edx,%esi
  jl     L45
  jmp    L15
L31:
  cmp    %eax,%edx
  jle    L15
  movslq %eax,%rcx
  lea    (%r9,%rcx,4),%rcx
L30:
  cmp    %r8d,(%rcx)
  jg     L51
  add    $0x1,%eax
  add    $0x4,%rcx
  cmp    %edx,%eax
  jne    L30
  mov    %edx,%eax
L15:
  movslq %eax,%rdx
  lea    (%r9,%rdx,4),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%r11)
  mov    %r8d,(%rdx)
  ret
L51:
  cmp    %edx,%eax
  jge    L15
  movslq %eax,%rcx
  lea    (%r9,%rcx,4),%rcx
  mov    (%rcx),%r10d
  mov    %edi,(%rcx)
  mov    %r10d,(%rsi)
L45:
  movslq %edx,%rcx
  lea    (%r9,%rcx,4),%rsi
  mov    (%rsi),%edi
  cmp    %r8d,%edi
  jl     L31
  sub    $0x1,%edx
  cmp    %eax,%edx
  jg     L45
  jmp    L15
```

assistant: ```c
int p(int *nums, int left, int right) {
  int i = left, j = right, tmp;
  int v = nums[left];
  while (i < j) {
    while (i < j && nums[j] >= v)
      j--;
    while (i < j && nums[i] <= v)
      i++;
    if (i < j) {
      tmp = nums[i];
      nums[i] = nums[j];
      nums[j] = tmp;
    }
  }
  nums[left] = nums[i];
  nums[i] = v;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<p>:
  endbr64
  movslq %esi,%r11
  push   %rbx
  mov    %rdi,%r10
  lea    (%rdi,%r11,4),%rbx
  mov    %r11,%rcx
  mov    (%rbx),%edi
  cmp    %edx,%r11d
  jge    L14
  movslq %edx,%rax
  mov    %edi,%edx
  mov    (%r10,%rax,4),%esi
  jmp    L2
  nopl   0x0(%rax)
L81:
  mov    (%r10,%rax,4),%esi
L2:
  mov    %eax,%r8d
  cmp    %esi,%edi
  jg     L5
  sub    $0x1,%rax
  cmp    %eax,%ecx
  jl     L81
L86:
  lea    (%r10,%r11,4),%r9
  mov    %ecx,%r8d
L93:
  mov    %edx,(%rbx)
  mov    %r8d,%eax
  mov    %edi,(%r9)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  cmp    %eax,%ecx
  jge    L86
  lea    0x4(%r10,%r11,4),%rax
  jmp    L87
  nopl   0x0(%rax,%rax,1)
L102:
  mov    %rax,%r9
  add    $0x1,%ecx
  add    $0x4,%rax
  mov    -0x4(%rax),%edx
  cmp    %r8d,%ecx
  je     L93
L87:
  cmp    %edx,%edi
  jge    L102
  movslq %ecx,%r11
  movslq %r8d,%rax
  lea    (%r10,%r11,4),%r9
  mov    %esi,(%r9)
  mov    %edx,(%r10,%rax,4)
  cmp    %r8d,%ecx
  jge    L91
  mov    %edx,%esi
  mov    (%r9),%edx
  jmp    L2
L14:
  mov    %rbx,%r9
  mov    %edi,%edx
  mov    %r11d,%r8d
  mov    %edx,(%rbx)
  mov    %r8d,%eax
  mov    %edi,(%r9)
  pop    %rbx
  ret
L91:
  mov    (%r9),%edx
  mov    %ecx,%r8d
  jmp    L93
```

assistant: ```c
int p(int *nums, int left, int right) {
  int i = left, j = right, tmp;
  int v = nums[left];
  while (i < j) {
    while (i < j && nums[j] >= v)
      j--;
    while (i < j && nums[i] <= v)
      i++;
    if (i < j) {
      tmp = nums[i];
      nums[i] = nums[j];
      nums[j] = tmp;
    }
  }
  nums[left] = nums[i];
  nums[i] = v;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<p>:
  endbr64
  movslq %esi,%rcx
  push   %rbx
  mov    %rdi,%r11
  lea    (%rdi,%rcx,4),%rbx
  mov    %rcx,%rax
  mov    (%rbx),%r10d
  mov    %rbx,%rdi
  mov    %r10d,%r8d
  cmp    %edx,%ecx
  jge    L96
  nop
L45:
  movslq %edx,%rsi
  lea    (%r11,%rsi,4),%rsi
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rsi),%r9d
  cmp    %r10d,%r9d
  jl     L29
  sub    $0x1,%edx
  sub    $0x4,%rsi
  cmp    %edx,%eax
  jl     L0
L16:
  lea    (%r11,%rcx,4),%rdi
L96:
  mov    %r8d,(%rbx)
  mov    %r10d,(%rdi)
  pop    %rbx
  ret
  nop
L29:
  cmp    %edx,%eax
  jge    L16
  lea    (%r11,%rcx,4),%rcx
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L94:
  add    $0x1,%eax
  lea    0x4(%rdi),%rcx
  cmp    %edx,%eax
  je     L15
L61:
  mov    (%rcx),%r8d
  mov    %rcx,%rdi
  cmp    %r10d,%r8d
  jle    L94
  mov    %r9d,(%rcx)
  mov    %r8d,(%rsi)
  cmp    %edx,%eax
  jge    L12
  mov    (%rcx),%r8d
  movslq %eax,%rcx
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L15:
  movslq %eax,%rdx
  lea    (%r11,%rdx,4),%rdi
  mov    (%rdi),%r8d
  mov    %r8d,(%rbx)
  mov    %r10d,(%rdi)
  pop    %rbx
  ret
L12:
  mov    (%rcx),%r8d
  jmp    L96
```

assistant: ```c
int p(int *nums, int left, int right) {
  int i = left, j = right, tmp;
  int v = nums[left];
  while (i < j) {
    while (i < j && nums[j] >= v)
      j--;
    while (i < j && nums[i] <= v)
      i++;
    if (i < j) {
      tmp = nums[i];
      nums[i] = nums[j];
      nums[j] = tmp;
    }
  }
  nums[left] = nums[i];
  nums[i] = v;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strlenw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L13:
  addq   $0x8,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t ft_strlenw(const wchar_t *str) {
  size_t length;
  length = 0;
  while (*str) {
    str++;
    length++;
  }
  return (length);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strlenw>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L4
  mov    $0x0,%eax
L16:
  add    $0x1,%rax
  cmpq   $0x0,(%rdi,%rax,8)
  jne    L16
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t ft_strlenw(const wchar_t *str) {
  size_t length;
  length = 0;
  while (*str) {
    str++;
    length++;
  }
  return (length);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strlenw>:
  endbr64
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L5
  nopl   0x0(%rax)
L15:
  add    $0x1,%rax
  cmpq   $0x0,(%rdi,%rax,8)
  jne    L15
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
size_t ft_strlenw(const wchar_t *str) {
  size_t length;
  length = 0;
  while (*str) {
    str++;
    length++;
  }
  return (length);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strlenw>:
  endbr64
  xor    %eax,%eax
  cmpq   $0x0,(%rdi)
  je     L3
  nopl   0x0(%rax)
L1:
  add    $0x1,%rax
  cmpq   $0x0,(%rdi,%rax,8)
  jne    L1
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
size_t ft_strlenw(const wchar_t *str) {
  size_t length;
  length = 0;
  while (*str) {
    str++;
    length++;
  }
  return (length);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_nsntrace_cleanup_ns_signal_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <_nsntrace_cleanup_ns@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _nsntrace_cleanup_ns_signal_callback() {
  _nsntrace_cleanup_ns();
  exit(EXIT_SUCCESS);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_nsntrace_cleanup_ns_signal_callback>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <_nsntrace_cleanup_ns@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _nsntrace_cleanup_ns_signal_callback() {
  _nsntrace_cleanup_ns();
  exit(EXIT_SUCCESS);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_nsntrace_cleanup_ns_signal_callback>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_nsntrace_cleanup_ns@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void _nsntrace_cleanup_ns_signal_callback() {
  _nsntrace_cleanup_ns();
  exit(EXIT_SUCCESS);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_nsntrace_cleanup_ns_signal_callback>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_nsntrace_cleanup_ns@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void _nsntrace_cleanup_ns_signal_callback() {
  _nsntrace_cleanup_ns();
  exit(EXIT_SUCCESS);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L28
L8:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D10
data_type: string
name: retrieve_data
arguments: tag: D7
data_type: string
name: retrieve_data
arguments: tag: D37
data_type: string

tool: D1: This program prints a table of squares.

tool: D10: Enter number of entries in table:

tool: D7: %d

tool: D37: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table:");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    printf("%10d%10d\n", i, i * i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L26
  mov    $0x1,%ebx
  lea    D2(%rip),%rbp
L24:
  mov    %ebx,%edx
  imul   %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L24
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D23
datatype: string
name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D36: This program prints a table of squares.

tool: D28: Enter number of entries in table:

tool: D23: %d

tool: D2: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table:");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    printf("%10d%10d\n", i, i * i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L27
  mov    $0x1,%ebx
  lea    D10(%rip),%rbp
  nopl   0x0(%rax)
L5:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %ebx,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L5
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D2
data_type: string
name: disassemble_data
arguments: data_label: D36
data_type: string
name: disassemble_data
arguments: data_label: D10
data_type: string

tool: D0: This program prints a table of squares.

tool: D2: Enter number of entries in table:

tool: D36: %d

tool: D10: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table:");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    printf("%10d%10d\n", i, i * i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L26
  mov    $0x1,%ebx
  lea    D1(%rip),%rbp
  nopl   0x0(%rax)
L24:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %ebx,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L24
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
datatype: string
name: unpack_data
arguments: tag: D22
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string

tool: D11: This program prints a table of squares.

tool: D22: Enter number of entries in table:

tool: D26: %d

tool: D1: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table:");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    printf("%10d%10d\n", i, i * i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_apropos_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,0x10(%rsp)
  mov    %rdx,%r12
  mov    %rcx,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  mov    $0x28,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbx
  lea    0x1(%rax),%r14
  lea    D44(%rip),%rsi
  mov    %r14,%rdi
  call   <strcspn@plt>
  mov    %eax,%r13d
  movslq %eax,%r15
  lea    0x1(%rbx,%r15,1),%rax
  cmp    %rax,%r14
  je     L70
  cmpb   $0x29,(%rax)
  je     L55
L70:
  lea    D18(%rip),%rdi
  call   <status_bar_error@plt>
  mov    $0x1,%eax
L50:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  lea    D35(%rip),%rdi
  call   <status_bar_error@plt>
  mov    $0x1,%eax
  jmp    L50
L55:
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  test   %r12,%r12
  je     L45
  sub    $0x1,%r12
  cmp    %r12,%r15
  ja     L45
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  je     L45
  sub    %rbp,%rax
  mov    %rcx,%rdx
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jae    L40
L45:
  lea    D31(%rip),%rdi
  call   <status_bar_error@plt>
  mov    $0x1,%eax
  jmp    L50
L40:
  lea    0x1(%rax),%esi
  mov    %rbp,%rdx
  mov    0x18(%rsp),%rdi
  call   <copy_str@plt>
  lea    0x1(%r13),%esi
  mov    %r14,%rdx
  mov    0x10(%rsp),%rdi
  call   <copy_str@plt>
  mov    $0x0,%eax
  jmp    L50
```

tool_calls: name: retrieve_data
arguments: data_label: D44
type_guessed: string
name: retrieve_data
arguments: data_label: D18
type_guessed: string
name: retrieve_data
arguments: data_label: D35
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D31
type_guessed: string

tool: D44:  	()

tool: D18: Wrong section number format.

tool: D35: Failed to find section number.

tool: D1:  (

tool: D31: Internal buffer is too small.

assistant: ```c
int parse_apropos_line(const char line[], char section[], size_t section_len, char topic[], size_t topic_len) {
  const char *sec_l, *sec_r;
  const char *sep;
  sec_l = strchr(line, '(');
  if (sec_l == NULL) {
    status_bar_error("Failed to find section number.");
    return 1;
  }
  sec_r = sec_l + 1 + strcspn(sec_l + 1, " \t()");
  if (sec_r == sec_l + 1 || *sec_r != ')') {
    status_bar_error("Wrong section number format.");
    return 1;
  }
  sep = strpbrk(line, " (");
  if (section_len == 0 || section_len - 1 < (size_t)(sec_r - (sec_l + 1)) || topic_len == 0 || topic_len - 1 < (size_t)(sep - line)) {
    status_bar_error("Internal buffer is too small.");
    return 1;
  }
  copy_str(topic, sep - line + 1, line);
  copy_str(section, sec_r - (sec_l + 1) + 1, sec_l + 1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_apropos_line>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    $0x28,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  lea    0x1(%rax),%r14
  lea    D7(%rip),%rsi
  mov    %rax,%rbx
  mov    %r14,%rdi
  call   <strcspn@plt>
  movslq %eax,%rdx
  lea    0x1(%rbx,%rdx,1),%rax
  cmp    %rax,%r14
  je     L56
  cmpb   $0x29,(%rax)
  jne    L56
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  mov    %rdx,0x10(%rsp)
  mov    %edx,0x1c(%rsp)
  call   <strpbrk@plt>
  test   %rbp,%rbp
  je     L77
  mov    0x10(%rsp),%rdx
  sub    $0x1,%rbp
  cmp    %rbp,%rdx
  ja     L77
  test   %r13,%r13
  je     L77
  sub    %r12,%rax
  sub    $0x1,%r13
  mov    0x1c(%rsp),%ecx
  cmp    %rax,%r13
  jb     L77
  lea    0x1(%rax),%esi
  mov    %r12,%rdx
  mov    %r15,%rdi
  mov    %ecx,0x10(%rsp)
  call   <copy_str@plt>
  mov    0x10(%rsp),%ecx
  mov    0x8(%rsp),%rdi
  mov    %r14,%rdx
  lea    0x1(%rcx),%esi
  call   <copy_str@plt>
  xor    %eax,%eax
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L56:
  lea    D11(%rip),%rdi
  call   <status_bar_error@plt>
  mov    $0x1,%eax
L58:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L77:
  lea    D15(%rip),%rdi
  call   <status_bar_error@plt>
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  lea    D1(%rip),%rdi
  call   <status_bar_error@plt>
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string
name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string

tool: D7:  	()

tool: D2:  (

tool: D11: Wrong section number format.

tool: D15: Internal buffer is too small.

tool: D1: Failed to find section number.

assistant: ```c
int parse_apropos_line(const char line[], char section[], size_t section_len, char topic[], size_t topic_len) {
  const char *sec_l, *sec_r;
  const char *sep;
  sec_l = strchr(line, '(');
  if (sec_l == NULL) {
    status_bar_error("Failed to find section number.");
    return 1;
  }
  sec_r = sec_l + 1 + strcspn(sec_l + 1, " \t()");
  if (sec_r == sec_l + 1 || *sec_r != ')') {
    status_bar_error("Wrong section number format.");
    return 1;
  }
  sep = strpbrk(line, " (");
  if (section_len == 0 || section_len - 1 < (size_t)(sec_r - (sec_l + 1)) || topic_len == 0 || topic_len - 1 < (size_t)(sep - line)) {
    status_bar_error("Internal buffer is too small.");
    return 1;
  }
  copy_str(topic, sep - line + 1, line);
  copy_str(section, sec_r - (sec_l + 1) + 1, sec_l + 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_apropos_line>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    $0x28,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L72
  lea    0x1(%rax),%r14
  lea    D14(%rip),%rsi
  mov    %rax,%rbx
  mov    %r14,%rdi
  call   <strcspn@plt>
  movslq %eax,%rdx
  lea    0x1(%rbx,%rdx,1),%rax
  cmp    %rax,%r14
  je     L28
  cmpb   $0x29,(%rax)
  jne    L28
  lea    D13(%rip),%rsi
  mov    %r12,%rdi
  mov    %rdx,0x10(%rsp)
  mov    %edx,0x1c(%rsp)
  call   <strpbrk@plt>
  test   %rbp,%rbp
  je     L42
  mov    0x10(%rsp),%rdx
  sub    $0x1,%rbp
  cmp    %rbp,%rdx
  ja     L42
  test   %r13,%r13
  je     L42
  sub    %r12,%rax
  sub    $0x1,%r13
  mov    0x1c(%rsp),%ecx
  cmp    %rax,%r13
  jb     L42
  lea    0x1(%rax),%esi
  mov    %r12,%rdx
  mov    %r15,%rdi
  mov    %ecx,0x10(%rsp)
  call   <copy_str@plt>
  mov    0x10(%rsp),%ecx
  mov    0x8(%rsp),%rdi
  mov    %r14,%rdx
  lea    0x1(%rcx),%esi
  call   <copy_str@plt>
  xor    %eax,%eax
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L28:
  lea    D25(%rip),%rdi
  call   <status_bar_error@plt>
  mov    $0x1,%eax
L6:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  lea    D30(%rip),%rdi
  call   <status_bar_error@plt>
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  lea    D20(%rip),%rdi
  call   <status_bar_error@plt>
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
datatype: string
name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D25
datatype: string
name: parse_data
arguments: tag: D30
datatype: string
name: parse_data
arguments: tag: D20
datatype: string

tool: D14:  	()

tool: D13:  (

tool: D25: Wrong section number format.

tool: D30: Internal buffer is too small.

tool: D20: Failed to find section number.

assistant: ```c
int parse_apropos_line(const char line[], char section[], size_t section_len, char topic[], size_t topic_len) {
  const char *sec_l, *sec_r;
  const char *sep;
  sec_l = strchr(line, '(');
  if (sec_l == NULL) {
    status_bar_error("Failed to find section number.");
    return 1;
  }
  sec_r = sec_l + 1 + strcspn(sec_l + 1, " \t()");
  if (sec_r == sec_l + 1 || *sec_r != ')') {
    status_bar_error("Wrong section number format.");
    return 1;
  }
  sep = strpbrk(line, " (");
  if (section_len == 0 || section_len - 1 < (size_t)(sec_r - (sec_l + 1)) || topic_len == 0 || topic_len - 1 < (size_t)(sep - line)) {
    status_bar_error("Internal buffer is too small.");
    return 1;
  }
  copy_str(topic, sep - line + 1, line);
  copy_str(section, sec_r - (sec_l + 1) + 1, sec_l + 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setMinMax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <setMax@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <setMin@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int setMinMax(unsigned int e, int i, int j) {
  e = setMax(e, i);
  e = setMin(e, j);
  return e;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setMinMax>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <setMax@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <setMin@plt>
  pop    %rbx
  ret
```

assistant: ```c
unsigned int setMinMax(unsigned int e, int i, int j) {
  e = setMax(e, i);
  e = setMin(e, j);
  return e;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setMinMax>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <setMax@plt>
  mov    %ebp,%esi
  pop    %rbp
  mov    %eax,%edi
  jmp    1070 <setMin@plt>
```

assistant: ```c
unsigned int setMinMax(unsigned int e, int i, int j) {
  e = setMax(e, i);
  e = setMin(e, j);
  return e;
}
```