ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D3
data_type: string

tool: D5: Unitialized x = %i


tool: D3: x with 1 + 2 = %i


assistant: ```c
int main(int argc, char **argv) {
  int x;
  printf("Unitialized x = %i\n", x);
  x = 1 + 2;
  printf("x with 1 + 2 = %i\n", x);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string

tool: D6: Unitialized x = %i


tool: D17: x with 1 + 2 = %i


assistant: ```c
int main(int argc, char **argv) {
  int x;
  printf("Unitialized x = %i\n", x);
  x = 1 + 2;
  printf("x with 1 + 2 = %i\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tok_ini0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cnt@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L16
L0:
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  movq   $0x0,-0x20(%rbp)
L16:
  mov    -0x40(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L0
  mov    -0x48(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x50(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void tok_ini0(char *s, char *del, int *pc, char ***pv) {
  int i, c;
  char *tok;
  char **v;
  c = cnt(s, del);
  v = malloc(c * sizeof(v[0]));
  tok = s;
  i = 0;
  while ((tok = strtok(tok, del)) != NULL) {
    v[i++] = strdup(tok);
    tok = NULL;
  }
  *pc = c;
  *pv = v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tok_ini0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <cnt@plt>
  mov    %eax,%r15d
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%rbx
  mov    $0x0,%r13d
  jmp    L9
L8:
  call   <strdup@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  mov    %r13,%rbp
L9:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L8
  mov    (%rsp),%rax
  mov    %r15d,(%rax)
  mov    0x8(%rsp),%rax
  mov    %r14,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void tok_ini0(char *s, char *del, int *pc, char ***pv) {
  int i, c;
  char *tok;
  char **v;
  c = cnt(s, del);
  v = malloc(c * sizeof(v[0]));
  tok = s;
  i = 0;
  while ((tok = strtok(tok, del)) != NULL) {
    v[i++] = strdup(tok);
    tok = NULL;
  }
  *pc = c;
  *pv = v;
}
```
user: What is the c source code of the assembly code below:

```asm
<tok_ini0>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <cnt@plt>
  lea    0x0(,%rax,8),%edi
  mov    %eax,%r13d
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  mov    %rax,%r12
  mov    %rax,%rbx
  jmp    L9
  nopl   0x0(%rax)
L8:
  call   <strdup@plt>
  add    $0x8,%rbx
  xor    %r8d,%r8d
  mov    %rax,-0x8(%rbx)
L9:
  mov    %r8,%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L8
  mov    %r13d,(%r15)
  mov    %r12,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void tok_ini0(char *s, char *del, int *pc, char ***pv) {
  int i, c;
  char *tok;
  char **v;
  c = cnt(s, del);
  v = malloc(c * sizeof(v[0]));
  tok = s;
  i = 0;
  while ((tok = strtok(tok, del)) != NULL) {
    v[i++] = strdup(tok);
    tok = NULL;
  }
  *pc = c;
  *pv = v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tok_ini0>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <cnt@plt>
  lea    0x0(,%rax,8),%edi
  mov    %eax,%r13d
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  mov    %rax,%r12
  mov    %rax,%rbx
  jmp    L3
  nopl   0x0(%rax)
L9:
  call   <strdup@plt>
  add    $0x8,%rbx
  xor    %r8d,%r8d
  mov    %rax,-0x8(%rbx)
L3:
  mov    %r8,%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L9
  mov    %r13d,(%r15)
  mov    %r12,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void tok_ini0(char *s, char *del, int *pc, char ***pv) {
  int i, c;
  char *tok;
  char **v;
  c = cnt(s, del);
  v = malloc(c * sizeof(v[0]));
  tok = s;
  i = 0;
  while ((tok = strtok(tok, del)) != NULL) {
    v[i++] = strdup(tok);
    tok = NULL;
  }
  *pc = c;
  *pv = v;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<yatzy_hand_score_straight1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x18,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    $0xf,%eax
  jmp    L5
L22:
  mov    $0x0,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int yatzy_hand_score_straight1(int dice[], int count[]) {
  int target[] = {1, 1, 1, 1, 1, 0};
  if (memcmp(count, target, sizeof(target)) == 0) {
    return 15;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<yatzy_hand_score_straight1>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  mov    %rsp,%rsi
  mov    $0x18,%edx
  call   <memcmp@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xf,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yatzy_hand_score_straight1(int dice[], int count[]) {
  int target[] = {1, 1, 1, 1, 1, 0};
  if (memcmp(count, target, sizeof(target)) == 0) {
    return 15;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yatzy_hand_score_straight1>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%rdi
  mov    $0x18,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000001,%rax
  mov    %rsp,%rsi
  movq   $0x1,0x10(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <memcmp@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xf,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yatzy_hand_score_straight1(int dice[], int count[]) {
  int target[] = {1, 1, 1, 1, 1, 0};
  if (memcmp(count, target, sizeof(target)) == 0) {
    return 15;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<yatzy_hand_score_straight1>:
  endbr64
  sub    $0x28,%rsp
  movdqa D1(%rip),%xmm0
  mov    %rsi,%rdi
  mov    $0x18,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <memcmp@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xf,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: byte[16]
name: unpack_data
arguments: label: D2
datatype: byte[8]

tool: {"D1": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D2": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int yatzy_hand_score_straight1(int dice[], int count[]) {
  int target[] = {1, 1, 1, 1, 1, 0};
  if (memcmp(count, target, sizeof(target)) == 0) {
    return 15;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: Estou funcionando!


assistant: ```c
int main() {
  printf("Estou funcionando!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D7: Estou funcionando!


assistant: ```c
int main() {
  printf("Estou funcionando!\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string

tool: D0: Estou funcionando!


assistant: ```c
int main() {
  printf("Estou funcionando!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: Estou funcionando!


assistant: ```c
int main() {
  printf("Estou funcionando!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_2d(float **array) {
  free(array[0]);
  free(array);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_2d>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void free_2d(float **array) {
  free(array[0]);
  free(array);
}
```
user: What is the c source code of the assembly code below:

```asm
<free_2d>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_2d(float **array) {
  free(array[0]);
  free(array);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<free_2d>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_2d(float **array) {
  free(array[0]);
  free(array);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L49:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0xa,-0x5(%rbp)
  je     L44
  cmpb   $0xd,-0x5(%rbp)
  je     L44
  cmpb   $0x9,-0x5(%rbp)
  je     L44
  cmpb   $0x20,-0x5(%rbp)
  jne    L29
L44:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x0,-0x4(%rbp)
  jns    L49
L29:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void str_strip(char *str, int len) {
  int i;
  char c;
  for (i = len - 1; i >= 0; i++) {
    c = str[i];
    if (c == '\n' || c == '\r' || c == '\t' || c == ' ')
      str[i] = 0;
    else
      break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_strip>:
  endbr64
  sub    $0x1,%esi
  js     L45
  movslq %esi,%rsi
  movabs $0x100002600,%rdx
  jmp    L49
L0:
  movb   $0x0,(%rdi,%rsi,1)
  add    $0x1,%rsi
  test   %esi,%esi
  js     L45
L49:
  movzbl (%rdi,%rsi,1),%eax
  cmp    $0x20,%al
  ja     L45
  bt     %rax,%rdx
  jb     L0
L45:
  ret
```

assistant: ```c
void str_strip(char *str, int len) {
  int i;
  char c;
  for (i = len - 1; i >= 0; i++) {
    c = str[i];
    if (c == '\n' || c == '\r' || c == '\t' || c == ' ')
      str[i] = 0;
    else
      break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_strip>:
  endbr64
  sub    $0x1,%esi
  js     L31
  movabs $0xfffffffeffffd9ff,%rdx
  movslq %esi,%rsi
  add    %rsi,%rdi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  ja     L31
L10:
  bt     %rax,%rdx
  jb     L31
  movb   $0x0,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  jbe    L10
L31:
  ret
```

assistant: ```c
void str_strip(char *str, int len) {
  int i;
  char c;
  for (i = len - 1; i >= 0; i++) {
    c = str[i];
    if (c == '\n' || c == '\r' || c == '\t' || c == ' ')
      str[i] = 0;
    else
      break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_strip>:
  endbr64
  sub    $0x1,%esi
  js     L18
  movabs $0xfffffffeffffd9ff,%rdx
  movslq %esi,%rsi
  add    %rsi,%rdi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  ja     L18
L9:
  bt     %rax,%rdx
  jb     L18
  movb   $0x0,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  jbe    L9
L18:
  ret
```

assistant: ```c
void str_strip(char *str, int len) {
  int i;
  char c;
  for (i = len - 1; i >= 0; i++) {
    c = str[i];
    if (c == '\n' || c == '\r' || c == '\t' || c == ' ')
      str[i] = 0;
    else
      break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<acf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L51
L37:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addq   $0x1,-0x20(%rbp)
L51:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L37
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  js     L19
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L88
L19:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L88:
  movsd  -0x10(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L82
L24:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L0
L72:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x8(%rbp),%xmm2
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L72
  addq   $0x1,-0x20(%rbp)
L82:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jbe    L24
  cmpq   $0x0,-0x40(%rbp)
  je     L103
  movq   $0x1,-0x20(%rbp)
  jmp    L31
L21:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x20(%rbp)
L31:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jbe    L21
  mov    -0x48(%rbp),%rax
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,(%rax)
L103:
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: f64

tool: D0: 1

assistant: ```c
void acf(double *x, int32_t N, int64_t k, int16_t norm, double *rxx) {
  int64_t i, n;
  double sum = 0, mean = 0;
  for (i = 0; i < N; i++)
    sum += x[i];
  mean = sum / N;
  for (i = 0; i <= k; i++) {
    rxx[i] = 0.0;
    for (n = i; n < N; n++)
      rxx[i] += (x[n] - mean) * (x[n - i] - mean);
  }
  if (norm) {
    for (i = 1; i <= k; i++)
      rxx[i] /= rxx[0];
    rxx[0] = 1.0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<acf>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  test   %rsi,%rsi
  je     L118
  mov    %rdi,%rax
  lea    (%rdi,%rsi,8),%rdx
  pxor   %xmm2,%xmm2
L102:
  addsd  (%rax),%xmm2
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L102
L50:
  test   %r11,%r11
  js     L40
  pxor   %xmm0,%xmm0
  cvtsi2sd %r11,%xmm0
L100:
  divsd  %xmm0,%xmm2
  lea    (%r10,%r11,8),%rsi
  mov    %r8,%rdi
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  jmp    L80
L118:
  pxor   %xmm2,%xmm2
  jmp    L50
L40:
  mov    %r11,%rax
  shr    %rax
  mov    %r11,%rdx
  and    $0x1,%edx
  or     %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L100
L115:
  mov    %rax,%r9
L80:
  mov    %rdi,%rdx
  movq   $0x0,(%rdi)
  cmp    %r9,%r11
  jbe    L116
  mov    %r10,%rax
  sub    %rcx,%rax
L96:
  movsd  (%rax),%xmm0
  subsd  %xmm2,%xmm0
  movsd  (%rax,%rcx,1),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L96
L116:
  lea    0x1(%r9),%rax
  add    $0x8,%rdi
  sub    $0x8,%rcx
  cmp    %r9,%rbx
  jne    L115
  test   %rbp,%rbp
  je     L94
  test   %rbx,%rbx
  je     L44
  lea    0x8(%r8),%rax
  lea    0x8(%r8,%rbx,8),%rdx
L108:
  movsd  (%rax),%xmm0
  divsd  (%r8),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L108
L44:
  mov    D2(%rip),%rax
  mov    %rax,(%r8)
L94:
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: f64

tool: D2: 1

assistant: ```c
void acf(double *x, int32_t N, int64_t k, int16_t norm, double *rxx) {
  int64_t i, n;
  double sum = 0, mean = 0;
  for (i = 0; i < N; i++)
    sum += x[i];
  mean = sum / N;
  for (i = 0; i <= k; i++) {
    rxx[i] = 0.0;
    for (n = i; n < N; n++)
      rxx[i] += (x[n] - mean) * (x[n - i] - mean);
  }
  if (norm) {
    for (i = 1; i <= k; i++)
      rxx[i] /= rxx[0];
    rxx[0] = 1.0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<acf>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r9
  mov    %rdx,%r11
  mov    %rcx,%rbx
  test   %rsi,%rsi
  je     L48
  pxor   %xmm4,%xmm4
  mov    %rdi,%rax
  lea    (%rdi,%rsi,8),%rdx
  movapd %xmm4,%xmm3
  nopl   0x0(%rax)
L42:
  addsd  (%rax),%xmm3
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L42
L78:
  pxor   %xmm0,%xmm0
  lea    (%r10,%r9,8),%rsi
  mov    %r8,%rcx
  xor    %edx,%edx
  cvtsi2sd %r9,%xmm0
  xor    %edi,%edi
  divsd  %xmm0,%xmm3
  nopl   (%rax)
L15:
  mov    %r10,%rax
  movq   $0x0,(%rcx)
  movapd %xmm4,%xmm2
  sub    %rdx,%rax
  cmp    %rdi,%r9
  jbe    L93
  xchg   %ax,%ax
L75:
  movsd  (%rax),%xmm0
  movsd  (%rax,%rdx,1),%xmm1
  add    $0x8,%rax
  subsd  %xmm3,%xmm0
  subsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
  movsd  %xmm2,(%rcx)
  cmp    %rax,%rsi
  jne    L75
L93:
  lea    0x1(%rdi),%rax
  add    $0x8,%rcx
  sub    $0x8,%rdx
  cmp    %rdi,%r11
  je     L14
  mov    %rax,%rdi
  jmp    L15
  nopl   0x0(%rax)
L14:
  test   %rbx,%rbx
  je     L31
  lea    0x8(%r8),%rax
  lea    (%rax,%r11,8),%rdx
  test   %r11,%r11
  je     L27
  nopw   0x0(%rax,%rax,1)
L79:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  divsd  (%r8),%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L79
L27:
  mov    D3(%rip),%rax
  mov    %rax,(%r8)
L31:
  pop    %rbx
  ret
L48:
  pxor   %xmm4,%xmm4
  movapd %xmm4,%xmm3
  jmp    L78
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: f64

tool: D3: 1

assistant: ```c
void acf(double *x, int32_t N, int64_t k, int16_t norm, double *rxx) {
  int64_t i, n;
  double sum = 0, mean = 0;
  for (i = 0; i < N; i++)
    sum += x[i];
  mean = sum / N;
  for (i = 0; i <= k; i++) {
    rxx[i] = 0.0;
    for (n = i; n < N; n++)
      rxx[i] += (x[n] - mean) * (x[n - i] - mean);
  }
  if (norm) {
    for (i = 1; i <= k; i++)
      rxx[i] /= rxx[0];
    rxx[0] = 1.0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bad_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: error :  in bad mode!!!!


assistant: ```c
void bad_mode(void) {
  printf("error :  in bad mode!!!!\n\r");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bad_mode>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D0: error :  in bad mode!!!!


assistant: ```c
void bad_mode(void) {
  printf("error :  in bad mode!!!!\n\r");
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bad_mode>:
  endbr64
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: error :  in bad mode!!!!


assistant: ```c
void bad_mode(void) {
  printf("error :  in bad mode!!!!\n\r");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bad_mode>:
  endbr64
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: error :  in bad mode!!!!


assistant: ```c
void bad_mode(void) {
  printf("error :  in bad mode!!!!\n\r");
  return;
}
```