ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<freeMatrix>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %sil,%sil
  jle    L13
  sub    $0x1,%esi
  mov    %rdi,%rbx
  movzbl %sil,%esi
  lea    0x8(%rdi,%rsi,8),%rbp
  nop
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L0
L13:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeMatrix(float **matrix, char rows, char cols) {
  char i = 0;
  for (i = 0; i < rows; i++) {
    free(matrix[i]);
  }
  free(matrix);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_ip_in_whitelist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  cmp    $0x7f,%eax
  jne    L10
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L10
  mov    $0x1,%eax
  jmp    L16
L10:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int is_ip_in_whitelist(u_int32_t ip) {
  if ((ip & 0xff) == 127 && (ip >> 8 & 0xff) == 0)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_ip_in_whitelist>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x7f,%dil
  je     L5
L18:
  ret
L5:
  test   $0xff00,%edi
  sete   %al
  movzbl %al,%eax
  jmp    L18
```

assistant: ```c
int is_ip_in_whitelist(u_int32_t ip) {
  if ((ip & 0xff) == 127 && (ip >> 8 & 0xff) == 0)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_ip_in_whitelist>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7f,%dil
  je     L3
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  and    $0xff00,%edi
  sete   %al
  ret
```

assistant: ```c
int is_ip_in_whitelist(u_int32_t ip) {
  if ((ip & 0xff) == 127 && (ip >> 8 & 0xff) == 0)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_ip_in_whitelist>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7f,%dil
  je     L8
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  and    $0xff00,%edi
  sete   %al
  ret
```

assistant: ```c
int is_ip_in_whitelist(u_int32_t ip) {
  if ((ip & 0xff) == 127 && (ip >> 8 & 0xff) == 0)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L56
L30:
  addq   $0x1,-0x18(%rbp)
L56:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  jmp    L31
L36:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    -0x8(%rbp),%rax
  jmp    L45
L31:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L36
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L45:
  pop    %rbp
  ret
```

assistant: ```c
char *strncat(char *dest, const char *src, size_t n) {
  char *ret = dest;
  while (*dest)
    dest++;
  while (n--)
    if (!(*dest++ = *src++))
      return ret;
  *dest = 0;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L8
  mov    %rdi,%rcx
L34:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L34
L46:
  add    %rsi,%rdx
L30:
  cmp    %rdx,%rsi
  je     L32
  add    $0x1,%rsi
  add    $0x1,%rcx
  movzbl -0x1(%rsi),%r8d
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L30
  jmp    L16
L8:
  mov    %rdi,%rcx
  jmp    L46
L32:
  movb   $0x0,(%rcx)
L16:
  ret
```

assistant: ```c
char *strncat(char *dest, const char *src, size_t n) {
  char *ret = dest;
  while (*dest)
    dest++;
  while (n--)
    if (!(*dest++ = *src++))
      return ret;
  *dest = 0;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  je     L30
  nop
L29:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L29
L30:
  add    %rsi,%rdx
  jmp    L35
  xchg   %ax,%ax
L1:
  movzbl (%rsi),%r8d
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  je     L32
L35:
  cmp    %rdx,%rsi
  jne    L1
  movb   $0x0,(%rcx)
L32:
  ret
```

assistant: ```c
char *strncat(char *dest, const char *src, size_t n) {
  char *ret = dest;
  while (*dest)
    dest++;
  while (n--)
    if (!(*dest++ = *src++))
      return ret;
  *dest = 0;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  je     L26
  nop
L24:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L24
L26:
  add    %rsi,%rdx
  jmp    L44
  xchg   %ax,%ax
L41:
  movzbl (%rsi),%r8d
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  je     L48
L44:
  cmp    %rdx,%rsi
  jne    L41
  movb   $0x0,(%rcx)
L48:
  ret
```

assistant: ```c
char *strncat(char *dest, const char *src, size_t n) {
  char *ret = dest;
  while (*dest)
    dest++;
  while (n--)
    if (!(*dest++ = *src++))
      return ret;
  *dest = 0;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<base_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L10
L18:
  nop
  subq   $0x1,-0x8(%rbp)
L10:
  cmpq   $0x1,-0x8(%rbp)
  jbe    L24
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L18
L24:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t base_len(char const *name) {
  size_t len;
  for (len = strlen(name); 1 < len && ((name[len - 1]) == '/'); len--)
    continue;
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<base_len>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
L0:
  cmp    $0x1,%rax
  jbe    L12
  lea    -0x1(%rax),%rdx
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  je     L14
L12:
  pop    %rbx
  ret
L14:
  mov    %rdx,%rax
  jmp    L0
```

assistant: ```c
size_t base_len(char const *name) {
  size_t len;
  for (len = strlen(name); 1 < len && ((name[len - 1]) == '/'); len--)
    continue;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<base_len>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
L7:
  cmp    $0x1,%rax
  jbe    L10
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  lea    -0x1(%rax),%rdx
  je     L6
L10:
  pop    %rbx
  ret
L6:
  mov    %rdx,%rax
  jmp    L7
```

assistant: ```c
size_t base_len(char const *name) {
  size_t len;
  for (len = strlen(name); 1 < len && ((name[len - 1]) == '/'); len--)
    continue;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<base_len>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
L7:
  cmp    $0x1,%rax
  jbe    L22
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  lea    -0x1(%rax),%rdx
  je     L23
L22:
  pop    %rbx
  ret
L23:
  mov    %rdx,%rax
  jmp    L7
```

assistant: ```c
size_t base_len(char const *name) {
  size_t len;
  for (len = strlen(name); 1 < len && ((name[len - 1]) == '/'); len--)
    continue;
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IO_Read_BE_ULONG>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L45
  cmpq   $0x0,-0x40(%rbp)
  je     L45
  mov    $0x1,%eax
  jmp    L42
L45:
  mov    $0x0,%eax
L42:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x30(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  je     L75
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x2c(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x2c(%rbp)
  je     L75
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x28(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x28(%rbp)
  je     L75
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x24(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L15
L75:
  mov    $0x0,%eax
  jmp    L34
L15:
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <IO_ConvertUnsigned@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  and    $0xff,%eax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  and    $0xff,%eax
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  and    $0xff,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x18,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x10,%rax
  or     %rax,%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  or     -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L34:
  leave
  ret
```

assistant: ```c
int IO_Read_BE_ULONG(unsigned long *buffer, FILE *fp) {
  int c1, c2, c3, c4;
  assert(buffer && fp);
  if (((c1 = fgetc(fp)) == EOF) || ((c2 = fgetc(fp)) == EOF) || ((c3 = fgetc(fp)) == EOF) || ((c4 = fgetc(fp)) == EOF)) {
    return 0;
  } else {
    unsigned long b1 = (unsigned long)(IO_ConvertUnsigned(c1));
    unsigned long b2 = ((unsigned long)c2) & 0xFF;
    unsigned long b3 = ((unsigned long)c3) & 0xFF;
    unsigned long b4 = ((unsigned long)c4) & 0xFF;
    *buffer = (b1 << 24) | (b2 << 16) | (b3 << 8) | b4;
    return 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<IO_Read_BE_ULONG>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  mov    D12(%rip),%rdx
  cmp    %r12d,(%rdx)
  je     L46
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%r13d
  mov    $0x0,%eax
  mov    D12(%rip),%rdx
  cmp    %r13d,(%rdx)
  je     L46
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%r14d
  mov    $0x0,%eax
  mov    D12(%rip),%rdx
  cmp    %r14d,(%rdx)
  je     L46
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  mov    D12(%rip),%rdx
  cmp    %ebx,(%rdx)
  jne    L42
L46:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  mov    %r12d,%edi
  call   <IO_ConvertUnsigned@plt>
  movzbl %r13b,%r13d
  shl    $0x10,%r13
  movzbl %r14b,%r14d
  shl    $0x8,%r14
  or     %r14,%r13
  movzbl %bl,%ebx
  or     %rbx,%r13
  shl    $0x18,%rax
  or     %rax,%r13
  mov    %r13,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L46
```

assistant: ```c
int IO_Read_BE_ULONG(unsigned long *buffer, FILE *fp) {
  int c1, c2, c3, c4;
  assert(buffer && fp);
  if (((c1 = fgetc(fp)) == EOF) || ((c2 = fgetc(fp)) == EOF) || ((c3 = fgetc(fp)) == EOF) || ((c4 = fgetc(fp)) == EOF)) {
    return 0;
  } else {
    unsigned long b1 = (unsigned long)(IO_ConvertUnsigned(c1));
    unsigned long b2 = ((unsigned long)c2) & 0xFF;
    unsigned long b3 = ((unsigned long)c3) & 0xFF;
    unsigned long b4 = ((unsigned long)c4) & 0xFF;
    *buffer = (b1 << 24) | (b2 << 16) | (b3 << 8) | b4;
    return 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IO_Read_BE_ULONG>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    D5(%rip),%r14
  cmp    %eax,(%r14)
  je     L12
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fgetc@plt>
  mov    %eax,%r13d
  cmp    %eax,(%r14)
  je     L12
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%r15d
  cmp    %eax,(%r14)
  je     L12
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  jne    L30
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L30:
  movzbl %r13b,%r13d
  movzbl %r15b,%r15d
  mov    %r12d,%edi
  movzbl %bpl,%ebp
  call   <IO_ConvertUnsigned@plt>
  shl    $0x8,%r15
  shl    $0x10,%r13
  or     %r15,%r13
  shl    $0x18,%rax
  or     %rbp,%r13
  or     %rax,%r13
  mov    $0x1,%eax
  mov    %r13,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int IO_Read_BE_ULONG(unsigned long *buffer, FILE *fp) {
  int c1, c2, c3, c4;
  assert(buffer && fp);
  if (((c1 = fgetc(fp)) == EOF) || ((c2 = fgetc(fp)) == EOF) || ((c3 = fgetc(fp)) == EOF) || ((c4 = fgetc(fp)) == EOF)) {
    return 0;
  } else {
    unsigned long b1 = (unsigned long)(IO_ConvertUnsigned(c1));
    unsigned long b2 = ((unsigned long)c2) & 0xFF;
    unsigned long b3 = ((unsigned long)c3) & 0xFF;
    unsigned long b4 = ((unsigned long)c4) & 0xFF;
    *buffer = (b1 << 24) | (b2 << 16) | (b3 << 8) | b4;
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<IO_Read_BE_ULONG>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    D3(%rip),%r14
  cmp    %eax,(%r14)
  je     L19
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fgetc@plt>
  mov    %eax,%r13d
  cmp    %eax,(%r14)
  je     L19
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%r15d
  cmp    %eax,(%r14)
  je     L19
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  jne    L36
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L36:
  movzbl %r13b,%r13d
  movzbl %r15b,%r15d
  mov    %r12d,%edi
  movzbl %bpl,%ebp
  call   <IO_ConvertUnsigned@plt>
  shl    $0x8,%r15
  shl    $0x10,%r13
  or     %r15,%r13
  shl    $0x18,%rax
  or     %rbp,%r13
  or     %rax,%r13
  mov    $0x1,%eax
  mov    %r13,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int IO_Read_BE_ULONG(unsigned long *buffer, FILE *fp) {
  int c1, c2, c3, c4;
  assert(buffer && fp);
  if (((c1 = fgetc(fp)) == EOF) || ((c2 = fgetc(fp)) == EOF) || ((c3 = fgetc(fp)) == EOF) || ((c4 = fgetc(fp)) == EOF)) {
    return 0;
  } else {
    unsigned long b1 = (unsigned long)(IO_ConvertUnsigned(c1));
    unsigned long b2 = ((unsigned long)c2) & 0xFF;
    unsigned long b3 = ((unsigned long)c3) & 0xFF;
    unsigned long b4 = ((unsigned long)c4) & 0xFF;
    *buffer = (b1 << 24) | (b2 << 16) | (b3 << 8) | b4;
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfc8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0xfc0(%rsp),%rbp
  mov    %rax,%rbx
L70:
  mov    $0x0,%eax
  call   <__NONDET__@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L70
  movl   $0x3e8,0x4(%rsp)
  lea    0x1c(%rsp),%r14
L189:
  mov    $0x0,%eax
  call   <__NONDET__@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L14
  mov    $0x0,%eax
  call   <__NONDET__@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  js     L116
  jle    L82
  mov    0x8(%rsp),%rbp
  lea    0x4(%rbp),%r15
  jmp    L171
L18:
  add    $0x4,%rbx
  cmpl   $0x0,-0x4(%rbx)
  je     L204
L87:
  cmpl   $0x1,0x0(%rbp)
  jne    L18
  mov    0x4(%rsp),%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  jmp    L18
L204:
  lea    0x20(%rsp),%rdi
  call   <bar@plt>
  cmp    $0xffffffff,%eax
  je     L65
L5:
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  je     L82
L171:
  mov    %r14,%rdi
  call   <foo@plt>
  cmp    $0x1,%eax
  jbe    L136
  cmp    $0xffffffff,%eax
  je     L5
  cmpl   $0x0,0x20(%rsp)
  je     L204
  lea    0x24(%rsp),%rbx
  jmp    L87
L65:
  lea    0x20(%rsp),%rdi
  call   <strlen@plt>
  cmp    $0x14,%eax
  jle    L93
  movl   $0x0,0x0(%rbp)
  jmp    L5
L93:
  test   %eax,%eax
  jle    L5
  movl   $0xffffffff,0x0(%rbp)
  jmp    L5
L82:
  addq   $0x4,0x8(%rsp)
  subl   $0x1,0x4(%rsp)
  jne    L189
  mov    $0x1,%eax
  jmp    L69
L14:
  mov    $0xffffffff,%eax
  jmp    L69
L116:
  mov    $0xffffffff,%eax
  jmp    L69
L136:
  mov    $0x1,%eax
L69:
  mov    0xfc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0xfd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i, j, ret, offset, tmp_cnt, tel_data, klen;
  int x[1000];
  for (i = 0; i < 1000; ++i)
    x[i] = __NONDET__();
  for (i = 0; i < 1000; ++i) {
    ret = __NONDET__();
    if (ret != 0)
      return -1;
    tmp_cnt = __NONDET__();
    if (tmp_cnt < 0)
      return -1;
    for (offset = 0; offset < tmp_cnt; offset++) {
      ret = foo(&tel_data);
      if ((ret == 0) || (ret == 1)) {
        return 1;
      } else if (ret == -1) {
        continue;
      }
      for (j = 0; x[j] != 0; j++) {
        if (x[i] == 1) {
          memmove(&x[i], &x[i + 1], (1001) - (i + 1));
        }
      }
      ret = bar(x);
      if (ret != -1) {
        continue;
      }
      klen = strlen(x);
      if (klen > 20) {
        x[i] = 0;
      } else if (klen > 0) {
        x[i] = -1;
      }
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfc8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rax
  lea    0xfc0(%rsp),%r12
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
  mov    %rax,%rbx
L51:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <__NONDET__@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbp
  jne    L51
  mov    $0x3e8,%r12d
  lea    0x1c(%rsp),%r14
L1:
  xor    %eax,%eax
  call   <__NONDET__@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L45
  xor    %eax,%eax
  call   <__NONDET__@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  js     L45
  lea    0x4(%rbx),%r13
  je     L133
  nopl   0x0(%rax,%rax,1)
L166:
  mov    %r14,%rdi
  call   <foo@plt>
  cmp    $0x1,%eax
  jbe    L165
  cmp    $0xffffffff,%eax
  je     L124
  mov    0x20(%rsp),%edx
  test   %edx,%edx
  je     L169
  lea    0x24(%rsp),%r15
  jmp    L37
  nopl   0x0(%rax)
L163:
  mov    (%r15),%eax
  add    $0x4,%r15
  test   %eax,%eax
  je     L169
L37:
  cmpl   $0x1,(%rbx)
  jne    L163
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r15
  call   <memmove@plt>
  mov    -0x4(%r15),%eax
  test   %eax,%eax
  jne    L37
  nopw   0x0(%rax,%rax,1)
L169:
  mov    0x8(%rsp),%rdi
  call   <bar@plt>
  cmp    $0xffffffff,%eax
  je     L157
L124:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jne    L166
L133:
  mov    %r13,%rbx
  sub    $0x1,%r12d
  jne    L1
L165:
  mov    $0x1,%eax
L50:
  mov    0xfc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L176
  add    $0xfd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L157:
  mov    0x8(%rsp),%rdi
  call   <strlen@plt>
  cmp    $0x14,%eax
  jle    L33
  movl   $0x0,(%rbx)
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jne    L166
  jmp    L133
  nopl   0x0(%rax)
L33:
  test   %eax,%eax
  jle    L124
  movl   $0xffffffff,(%rbx)
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jne    L166
  jmp    L133
L45:
  or     $0xffffffff,%eax
  jmp    L50
L176:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i, j, ret, offset, tmp_cnt, tel_data, klen;
  int x[1000];
  for (i = 0; i < 1000; ++i)
    x[i] = __NONDET__();
  for (i = 0; i < 1000; ++i) {
    ret = __NONDET__();
    if (ret != 0)
      return -1;
    tmp_cnt = __NONDET__();
    if (tmp_cnt < 0)
      return -1;
    for (offset = 0; offset < tmp_cnt; offset++) {
      ret = foo(&tel_data);
      if ((ret == 0) || (ret == 1)) {
        return 1;
      } else if (ret == -1) {
        continue;
      }
      for (j = 0; x[j] != 0; j++) {
        if (x[i] == 1) {
          memmove(&x[i], &x[i + 1], (1001) - (i + 1));
        }
      }
      ret = bar(x);
      if (ret != -1) {
        continue;
      }
      klen = strlen(x);
      if (klen > 20) {
        x[i] = 0;
      } else if (klen > 0) {
        x[i] = -1;
      }
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfc8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rax
  lea    0xfc0(%rsp),%r12
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
  mov    %rax,%rbx
L85:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <__NONDET__@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbp
  jne    L85
  mov    $0x3e8,%r12d
  lea    0x1c(%rsp),%r14
L83:
  xor    %eax,%eax
  call   <__NONDET__@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L194
  xor    %eax,%eax
  call   <__NONDET__@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  js     L194
  lea    0x4(%rbx),%r13
  jne    L48
  jmp    L134
  nopl   (%rax)
L6:
  mov    0x8(%rsp),%rdi
  call   <bar@plt>
  cmp    $0xffffffff,%eax
  je     L42
L133:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  je     L134
L48:
  mov    %r14,%rdi
  call   <foo@plt>
  cmp    $0x1,%eax
  jbe    L50
  cmp    $0xffffffff,%eax
  je     L133
  mov    0x20(%rsp),%edx
  test   %edx,%edx
  je     L6
  lea    0x24(%rsp),%r15
L12:
  cmpl   $0x1,(%rbx)
  jne    L6
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  mov    (%r15),%eax
  test   %eax,%eax
  je     L6
  add    $0x4,%r15
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L42:
  mov    0x8(%rsp),%rdi
  call   <strlen@plt>
  cmp    $0x14,%eax
  jle    L65
  movl   $0x0,(%rbx)
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jne    L48
L134:
  mov    %r13,%rbx
  sub    $0x1,%r12d
  jne    L83
L50:
  mov    $0x1,%eax
L123:
  mov    0xfc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L104
  add    $0xfd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L65:
  test   %eax,%eax
  jle    L133
  movl   $0xffffffff,(%rbx)
  jmp    L133
L194:
  or     $0xffffffff,%eax
  jmp    L123
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i, j, ret, offset, tmp_cnt, tel_data, klen;
  int x[1000];
  for (i = 0; i < 1000; ++i)
    x[i] = __NONDET__();
  for (i = 0; i < 1000; ++i) {
    ret = __NONDET__();
    if (ret != 0)
      return -1;
    tmp_cnt = __NONDET__();
    if (tmp_cnt < 0)
      return -1;
    for (offset = 0; offset < tmp_cnt; offset++) {
      ret = foo(&tel_data);
      if ((ret == 0) || (ret == 1)) {
        return 1;
      } else if (ret == -1) {
        continue;
      }
      for (j = 0; x[j] != 0; j++) {
        if (x[i] == 1) {
          memmove(&x[i], &x[i + 1], (1001) - (i + 1));
        }
      }
      ret = bar(x);
      if (ret != -1) {
        continue;
      }
      klen = strlen(x);
      if (klen > 20) {
        x[i] = 0;
      } else if (klen > 0) {
        x[i] = -1;
      }
    }
  }
  return 1;
}
```