ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<m_dump_number>:
  endbr64
  sub    $0x68,%rsp
  mov    %rdi,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x58(%rsp)
  xor    %edx,%edx
  test   %esi,%esi
  js     L25
L13:
  test   %rax,%rax
  jne    L50
  movb   $0x30,D26(%rip)
  mov    $0x1,%eax
  lea    D26(%rip),%r9
L20:
  cltq
  movb   $0x0,(%r9,%rax,1)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %r9,%rax
  add    $0x68,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  neg    %esi
  test   %rdi,%rdi
  jns    L13
  movb   $0x2d,D26(%rip)
  neg    %rax
  mov    $0x1,%edi
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L50:
  xor    %edi,%edi
L29:
  movslq %esi,%rsi
  mov    $0x1,%ecx
  lea    -0x1(%rsp),%r10
  lea    D13(%rip),%r9
  cs nopw 0x0(%rax,%rax,1)
L64:
  xor    %edx,%edx
  mov    %rax,%r8
  mov    %ecx,%r11d
  div    %rsi
  movslq %edx,%rdx
  movzbl (%r9,%rdx,1),%edx
  mov    %dl,(%r10,%rcx,1)
  add    $0x1,%rcx
  cmp    %r8,%rsi
  jbe    L64
  movslq %r11d,%rcx
  lea    -0x1(%r11),%esi
  movslq %edi,%rdx
  lea    (%rsp,%rcx,1),%rax
  lea    D26(%rip),%r9
  add    %r10,%rcx
  mov    %rsi,%r8
  add    %r9,%rdx
  sub    %rsi,%rcx
  nopl   0x0(%rax)
L32:
  movzbl -0x1(%rax),%esi
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  cmp    %rcx,%rax
  jne    L32
  lea    0x1(%rdi,%r8,1),%eax
  jmp    L20
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D13: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz

assistant: ```c
char *m_dump_number(unsigned long long num, int base) {
  static char ret[80];
  char intret[80];
  int retpos = 0;
  int intretpos = 0;
  if (base < 0) {
    unsigned long long bit63 = 1;
    bit63 <<= 63;
    base = -base;
    if (num & bit63) {
      num ^= 0xffffffffffffffffULL;
      num += 1;
      ret[retpos++] = '-';
    }
  }
  if (num == 0) {
    ret[retpos++] = '0';
  } else {
    while (num != 0) {
      unsigned long long quot = num / base;
      int dig = num % base;
      intret[intretpos++] = "0123456789"
                            "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                            "abcdefghijklmnopqrstuvwxyz"[dig];
      num = quot;
    }
    do {
      ret[retpos++] = intret[--intretpos];
    } while (intretpos != 0);
  }
  ret[retpos++] = 0;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<relogio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x20(%rbp),%xmm1
  mov    -0x18(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  D3(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: byte[8]

tool: {"D3": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double relogio() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + 1e-6 * tv.tv_usec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<relogio>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D6(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: byte[8]

tool: {"D6": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double relogio() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + 1e-6 * tv.tv_usec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<relogio>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D3(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: byte[8]

tool: {"D3": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double relogio() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + 1e-6 * tv.tv_usec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<relogio>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D9(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: byte[8]

tool: {"D9": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double relogio() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + 1e-6 * tv.tv_usec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zmalloc_20160308>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L13
  movl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,%rdx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <zlog_fatal_output@plt>
L11:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: zmalloc: insufficient memory for %ld bytes: %m

assistant: ```c
void *zmalloc_20160308(int len) {
  void *r;
  if (len < 1) {
    len = 1;
  }
  if ((r = malloc(len)) == 0) {
    { zlog_fatal_output(1, "zmalloc: insufficient memory for %ld bytes: %m", (long)len); };
  }
  ((char *)r)[0] = 0;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<zmalloc_20160308>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  mov    $0x1,%eax
  cmovg  %edi,%eax
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L13
L2:
  movb   $0x0,(%rbx)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  movslq %ebp,%rdx
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <zlog_fatal_output@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: zmalloc: insufficient memory for %ld bytes: %m

assistant: ```c
void *zmalloc_20160308(int len) {
  void *r;
  if (len < 1) {
    len = 1;
  }
  if ((r = malloc(len)) == 0) {
    { zlog_fatal_output(1, "zmalloc: insufficient memory for %ld bytes: %m", (long)len); };
  }
  ((char *)r)[0] = 0;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zmalloc_20160308>:
  endbr64
  push   %r12
  mov    $0x1,%eax
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  cmovg  %edi,%eax
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  movslq %ebx,%rdx
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  call   <zlog_fatal_output@plt>
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: zmalloc: insufficient memory for %ld bytes: %m

assistant: ```c
void *zmalloc_20160308(int len) {
  void *r;
  if (len < 1) {
    len = 1;
  }
  if ((r = malloc(len)) == 0) {
    { zlog_fatal_output(1, "zmalloc: insufficient memory for %ld bytes: %m", (long)len); };
  }
  ((char *)r)[0] = 0;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<zmalloc_20160308>:
  endbr64
  push   %r12
  mov    $0x1,%eax
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  cmovg  %edi,%eax
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  movslq %ebx,%rdx
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <zlog_fatal_output@plt>
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: zmalloc: insufficient memory for %ld bytes: %m

assistant: ```c
void *zmalloc_20160308(int len) {
  void *r;
  if (len < 1) {
    len = 1;
  }
  if ((r = malloc(len)) == 0) {
    { zlog_fatal_output(1, "zmalloc: insufficient memory for %ld bytes: %m", (long)len); };
  }
  ((char *)r)[0] = 0;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  shr    $0x3,%rax
  or     $0x61bab5,%rax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  mov    %rax,%rcx
  shr    $0x10,%rcx
  shl    $0x30,%rcx
  movabs $0xffffffffffff,%rdx
  and    %rax,%rdx
  or     %rcx,%rdx
  shr    $0x30,%rax
  shl    $0x10,%rax
  movabs $0xffffffff0000ffff,%rcx
  and    %rcx,%rdx
  or     %rdx,%rax
  and    $0x369937ec,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] > (local2 & local1)) {
          state[local1] = state[local2] >> ((state[local2] & 7UL) | 1UL);
          copy11 = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 7);
          *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = copy12;
          copy13 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = copy13;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 916010988UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movabs $0xffffffffffff,%rdx
  mov    (%rdi),%rax
  shr    $0x3,%rax
  or     $0x61bab5,%rax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  mov    %rax,%rcx
  and    %rax,%rdx
  shr    $0x30,%rax
  shr    $0x10,%rcx
  shl    $0x10,%rax
  shl    $0x30,%rcx
  or     %rcx,%rdx
  movabs $0xffffffff0000ffff,%rcx
  and    %rcx,%rdx
  or     %rdx,%rax
  and    $0x369937ec,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] > (local2 & local1)) {
          state[local1] = state[local2] >> ((state[local2] & 7UL) | 1UL);
          copy11 = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 7);
          *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = copy12;
          copy13 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = copy13;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 916010988UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  movabs $0xffffffffffff,%rdx
  mov    (%rdi),%rax
  shr    $0x3,%rax
  or     $0x61bab5,%rax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  mov    %rax,%rcx
  and    %rax,%rdx
  shr    $0x30,%rax
  shr    $0x10,%rcx
  shl    $0x10,%rax
  shl    $0x30,%rcx
  or     %rcx,%rdx
  movabs $0xffffffff0000ffff,%rcx
  and    %rcx,%rdx
  or     %rdx,%rax
  and    $0x369937ec,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] > (local2 & local1)) {
          state[local1] = state[local2] >> ((state[local2] & 7UL) | 1UL);
          copy11 = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 7);
          *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = copy12;
          copy13 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
          *((unsigned short *)(&state[0UL]) + 3) = copy13;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 916010988UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<show_menu_title>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x20,-0xc(%rbp)
  jg     L0
  mov    $0x21,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L17
  subl   $0x1,-0xc(%rbp)
  jmp    L17
L0:
  movl   $0x0,-0xc(%rbp)
L17:
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rcx
  lea    D14(%rip),%rdx
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D14:  

tool: D0: %*s %s


assistant: ```c
void show_menu_title(char *title, int len) {
  if (len < 33) {
    len = (33 - len) / 2;
    if (len % 2)
      --len;
  } else
    len = 0;
  printf("%*s %s\n", len, " ", title);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<show_menu_title>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    %esi,%eax
  mov    $0x0,%esi
  cmp    $0x20,%eax
  jg     L8
  mov    $0x21,%edx
  sub    %eax,%edx
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  mov    %esi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0xffffffff,%esi
L8:
  lea    D16(%rip),%rdx
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string

tool: D16:  

tool: D10: %*s %s


assistant: ```c
void show_menu_title(char *title, int len) {
  if (len < 33) {
    len = (33 - len) / 2;
    if (len % 2)
      --len;
  } else
    len = 0;
  printf("%*s %s\n", len, " ", title);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<show_menu_title>:
  endbr64
  mov    %esi,%eax
  mov    %rdi,%rcx
  xor    %esi,%esi
  cmp    $0x20,%eax
  jg     L7
  mov    $0x21,%esi
  sub    %eax,%esi
  sar    %esi
  mov    %esi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0xffffffff,%esi
L7:
  lea    D5(%rip),%rdx
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string

tool: D5:  

tool: D8: %*s %s


assistant: ```c
void show_menu_title(char *title, int len) {
  if (len < 33) {
    len = (33 - len) / 2;
    if (len % 2)
      --len;
  } else
    len = 0;
  printf("%*s %s\n", len, " ", title);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<show_menu_title>:
  endbr64
  mov    %esi,%eax
  mov    %rdi,%rcx
  xor    %esi,%esi
  cmp    $0x20,%eax
  jg     L7
  mov    $0x21,%esi
  sub    %eax,%esi
  sar    %esi
  mov    %esi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0xffffffff,%esi
L7:
  lea    D7(%rip),%rdx
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D5
datatype: string

tool: D7:  

tool: D5: %*s %s


assistant: ```c
void show_menu_title(char *title, int len) {
  if (len < 33) {
    len = (33 - len) / 2;
    if (len % 2)
      --len;
  } else
    len = 0;
  printf("%*s %s\n", len, " ", title);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wctombs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <wcstombs@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0xffffffffffffffff,-0x18(%rbp)
  je     L2
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstombs@plt>
  mov    %rax,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
size_t wctombs(char *dest, wchar_t x) {
  wchar_t wstr[] = {x, 0};
  size_t size = wcstombs(NULL, wstr, 0);
  if (size != (size_t)-1)
    size = wcstombs(dest, wstr, size + 1);
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wctombs>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    $0x0,%edi
  call   <wcstombs@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L12
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  ret
L12:
  lea    0x1(%rax),%rdx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <wcstombs@plt>
  jmp    L21
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wctombs(char *dest, wchar_t x) {
  wchar_t wstr[] = {x, 0};
  size_t size = wcstombs(NULL, wstr, 0);
  if (size != (size_t)-1)
    size = wcstombs(dest, wstr, size + 1);
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wctombs>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %esi,(%rsp)
  mov    %r12,%rsi
  movl   $0x0,0x4(%rsp)
  call   <wcstombs@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L6
  lea    0x1(%rax),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wcstombs@plt>
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wctombs(char *dest, wchar_t x) {
  wchar_t wstr[] = {x, 0};
  size_t size = wcstombs(NULL, wstr, 0);
  if (size != (size_t)-1)
    size = wcstombs(dest, wstr, size + 1);
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wctombs>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %esi,(%rsp)
  mov    %r12,%rsi
  movl   $0x0,0x4(%rsp)
  call   <wcstombs@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L16
  lea    0x1(%rax),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wcstombs@plt>
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wctombs(char *dest, wchar_t x) {
  wchar_t wstr[] = {x, 0};
  size_t size = wcstombs(NULL, wstr, 0);
  if (size != (size_t)-1)
    size = wcstombs(dest, wstr, size + 1);
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L92
  movl   $0x0,-0x8(%rbp)
  jmp    L76
L92:
  cmpl   $0x2,-0x14(%rbp)
  je     L15
  cmpl   $0x3,-0x14(%rbp)
  jne    L34
L15:
  movl   $0x1,-0x8(%rbp)
  jmp    L76
L34:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L113
  movl   $0x0,-0x8(%rbp)
  jmp    L76
L113:
  movl   $0x3,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
L91:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L39
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L39
  addl   $0x2,-0x4(%rbp)
  jmp    L91
L39:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L23
  movl   $0x1,-0x8(%rbp)
  jmp    L76
L23:
  movl   $0x0,-0x8(%rbp)
L76:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int isPrime(int n) {
  int result;
  int i;
  if (n <= 1) {
    result = 0;
  } else if ((n == 2) || (n == 3)) {
    result = 1;
  } else if (n % 2 == 0) {
    result = 0;
  } else {
    i = 3;
    result = 1;
    while (1) {
      if ((i * i > n) || (n % i == 0))
        break;
      i += 2;
    }
    if (i * i > n)
      result = 1;
    else
      result = 0;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isPrime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L86
  lea    -0x2(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  jbe    L86
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L86
  cmp    $0x8,%edi
  jle    L7
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  je     L53
  mov    $0x3,%ecx
L18:
  add    $0x2,%ecx
  mov    %ecx,%esi
  imul   %ecx,%esi
  cmp    %edi,%esi
  jg     L30
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L18
L30:
  cmp    %esi,%edi
  setl   %al
  movzbl %al,%eax
L86:
  ret
L7:
  mov    $0x9,%esi
  jmp    L30
L53:
  mov    $0x9,%esi
  jmp    L30
```

assistant: ```c
int isPrime(int n) {
  int result;
  int i;
  if (n <= 1) {
    result = 0;
  } else if ((n == 2) || (n == 3)) {
    result = 1;
  } else if (n % 2 == 0) {
    result = 0;
  } else {
    i = 3;
    result = 1;
    while (1) {
      if ((i * i > n) || (n % i == 0))
        break;
      i += 2;
    }
    if (i * i > n)
      result = 1;
    else
      result = 0;
  }
  return result;
}
```