user: 这段汇编代码用C语言表示是什么样的：

```asm
<binomialCoeff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %esi,-0x68(%rbp)
  mov    %fs:0x28,%rcx
  mov    %rcx,-0x38(%rbp)
  xor    %ecx,%ecx
  mov    %rsp,%rcx
  mov    %rcx,%r15
  mov    -0x68(%rbp),%ecx
  add    $0x1,%ecx
  mov    -0x64(%rbp),%esi
  add    $0x1,%esi
  movslq %ecx,%rdi
  sub    $0x1,%rdi
  mov    %rdi,-0x50(%rbp)
  movslq %ecx,%rdi
  mov    %rdi,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%rbx
  movslq %esi,%rdi
  sub    $0x1,%rdi
  mov    %rdi,-0x48(%rbp)
  movslq %ecx,%rdi
  mov    %rdi,%r12
  mov    $0x0,%r13d
  movslq %esi,%rdi
  mov    %rdi,%rax
  mov    $0x0,%edx
  mov    %r13,%r14
  imul   %rax,%r14
  mov    %rdx,%rdi
  imul   %r12,%rdi
  add    %r14,%rdi
  mul    %r12
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movslq %esi,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    %r11,%rdx
  imul   %r8,%rdx
  mov    %r9,%rax
  imul   %r10,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    %r10,%rax
  mul    %r8
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rdx
  movslq %esi,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L8:
  cmp    %rdx,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L8
L12:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L41
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L41:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L31
L94:
  movl   $0x0,-0x54(%rbp)
  jmp    L86
L14:
  cmpl   $0x0,-0x54(%rbp)
  je     L3
  mov    -0x54(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jne    L97
L3:
  mov    %rbx,%rcx
  shr    $0x2,%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rsi
  mov    -0x58(%rbp),%edx
  movslq %edx,%rdx
  imul   %rcx,%rdx
  add    %rsi,%rdx
  movl   $0x1,(%rax,%rdx,4)
  jmp    L21
L97:
  mov    %rbx,%rcx
  shr    $0x2,%rcx
  mov    -0x58(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x54(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x40(%rbp),%rax
  movslq %esi,%rsi
  movslq %edx,%rdx
  imul   %rcx,%rdx
  add    %rsi,%rdx
  mov    (%rax,%rdx,4),%edi
  mov    %rbx,%rcx
  shr    $0x2,%rcx
  mov    -0x58(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%r8
  movslq %esi,%rdx
  imul   %rcx,%rdx
  add    %r8,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %rbx,%rsi
  shr    $0x2,%rsi
  lea    (%rdi,%rax,1),%ecx
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdi
  mov    -0x58(%rbp),%edx
  movslq %edx,%rdx
  imul   %rsi,%rdx
  add    %rdi,%rdx
  mov    %ecx,(%rax,%rdx,4)
L21:
  addl   $0x1,-0x54(%rbp)
L86:
  mov    -0x68(%rbp),%edx
  mov    -0x58(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  cmp    %eax,-0x54(%rbp)
  jle    L14
  addl   $0x1,-0x58(%rbp)
L31:
  mov    -0x58(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jle    L94
  shr    $0x2,%rbx
  mov    %rbx,%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x68(%rbp),%edx
  movslq %edx,%rsi
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  imul   %rcx,%rdx
  add    %rsi,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %r15,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int binomialCoeff(int n, int k) {
  int C[n + 1][k + 1];
  int i, j;
  for (i = 0; i <= n; i++) {
    for (j = 0; j <= min(i, k); j++) {
      if (j == 0 || j == i) {
        C[i][j] = 1;
      } else {
        C[i][j] = C[i - 1][j - 1] + C[i - 1][j];
      }
    }
  }
  return C[n][k];
}
```