ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<all_c_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_dir@plt>
  test   %rax,%rax
  je     L13
  mov    -0x8(%rbp),%rax
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <starts_with@plt>
  test   %rax,%rax
  jne    L13
  mov    $0x1,%eax
  jmp    L4
L13:
  mov    -0x8(%rbp),%rax
  lea    D35(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <starts_with@plt>
  test   %rax,%rax
  je     L76
  mov    $0x0,%eax
  jmp    L4
L76:
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ends_with@plt>
  test   %rax,%rax
  jne    L45
  mov    -0x8(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ends_with@plt>
  test   %rax,%rax
  je     L28
L45:
  mov    $0x1,%eax
  jmp    L4
L28:
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D30
type_guessed: string
name: disassemble_data
arguments: data_label: D35
type_guessed: string
name: disassemble_data
arguments: data_label: D2
type_guessed: string
name: disassemble_data
arguments: data_label: D31
type_guessed: string

tool: D30: .

tool: D35: _

tool: D2: .h

tool: D31: .c

assistant: ```c
int all_c_code(const char *f) {
  if (is_dir(f) && !starts_with(f, ".")) {
    return 1;
  }
  if (starts_with(f, "_")) {
    return 0;
  }
  if (ends_with(f, ".h") || ends_with(f, ".c")) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<all_c_code>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <is_dir@plt>
  test   %rax,%rax
  je     L16
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <starts_with@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L28
L16:
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <starts_with@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L8
L28:
  pop    %rbx
  ret
L8:
  lea    D23(%rip),%rsi
  mov    %rbx,%rdi
  call   <ends_with@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L28
  lea    D35(%rip),%rsi
  mov    %rbx,%rdi
  call   <ends_with@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L28
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D23
type_infered: string
name: unpack_data
arguments: data_label: D35
type_infered: string

tool: D4: .

tool: D10: _

tool: D23: .h

tool: D35: .c

assistant: ```c
int all_c_code(const char *f) {
  if (is_dir(f) && !starts_with(f, ".")) {
    return 1;
  }
  if (starts_with(f, "_")) {
    return 0;
  }
  if (ends_with(f, ".h") || ends_with(f, ".c")) {
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<all_c_code>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <is_dir@plt>
  test   %rax,%rax
  je     L24
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <starts_with@plt>
  test   %rax,%rax
  je     L37
L24:
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <starts_with@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L21
  pop    %rbp
  ret
  nopl   0x0(%rax)
L21:
  lea    D29(%rip),%rsi
  mov    %rbp,%rdi
  call   <ends_with@plt>
  test   %rax,%rax
  je     L13
L37:
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  call   <ends_with@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D39
type_guessed: string
name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D3: .

tool: D39: _

tool: D29: .h

tool: D1: .c

assistant: ```c
int all_c_code(const char *f) {
  if (is_dir(f) && !starts_with(f, ".")) {
    return 1;
  }
  if (starts_with(f, "_")) {
    return 0;
  }
  if (ends_with(f, ".h") || ends_with(f, ".c")) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<all_c_code>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <is_dir@plt>
  test   %rax,%rax
  je     L7
  lea    D31(%rip),%rsi
  mov    %rbp,%rdi
  call   <starts_with@plt>
  test   %rax,%rax
  je     L0
L7:
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <starts_with@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L18
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  call   <ends_with@plt>
  test   %rax,%rax
  je     L34
L0:
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rbp,%rdi
  lea    D36(%rip),%rsi
  call   <ends_with@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
data_type: string
name: retrieve_data
arguments: data_tag: D3
data_type: string
name: retrieve_data
arguments: data_tag: D37
data_type: string
name: retrieve_data
arguments: data_tag: D36
data_type: string

tool: D31: .

tool: D3: _

tool: D37: .h

tool: D36: .c

assistant: ```c
int all_c_code(const char *f) {
  if (is_dir(f) && !starts_with(f, ".")) {
    return 1;
  }
  if (starts_with(f, "_")) {
    return 0;
  }
  if (ends_with(f, ".h") || ends_with(f, ".c")) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  cmp    $0x24,%eax
  seta   %dl
  test   %dl,%dl
  jne    L67
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  movabs $0x1000000010,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L30
  movabs $0x200000002,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L14
  movabs $0x100000001,%rdx
  and    %rdx,%rax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L67
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L49
L14:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L49
L30:
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L67:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L49:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D0
type_infered: string
name: disassemble_data
arguments: label: D38
type_infered: string
name: disassemble_data
arguments: label: D52
type_infered: string
name: disassemble_data
arguments: label: D30
type_infered: string
name: disassemble_data
arguments: label: D40
type_infered: string
name: disassemble_data
arguments: label: D8
type_infered: string
name: disassemble_data
arguments: label: D60
type_infered: string
name: disassemble_data
arguments: label: D19
type_infered: string

tool: D18: ******** MAIN MENU **************


tool: D0:  a. Formula 1 


tool: D38:  b. Formula 2 


tool: D52:  e. EXIT program 


tool: D30: %c

tool: D40: Solving Formula 1 


tool: D8: Solving Formula 2 


tool: D60: Exiting program...


tool: D19: Invalid option!

assistant: ```c
int main() {
  char selection;
  printf("******** MAIN MENU **************\n");
  printf(" a. Formula 1 \n");
  printf(" b. Formula 2 \n");
  printf(" e. EXIT program \n");
  scanf("%c", &selection);
  switch (selection) {
  case 'A':
  case 'a':
    printf("Solving Formula 1 \n");
    break;
  case 'B':
  case 'b':
    printf("Solving Formula 2 \n");
    break;
  case 'E':
  case 'e':
    printf("Exiting program...\n");
  default:
    printf("Invalid option!");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x41(%rax),%ecx
  cmp    $0x24,%cl
  ja     L53
  mov    $0x1,%eax
  shl    %cl,%rax
  movabs $0x1000000010,%rdx
  test   %rdx,%rax
  jne    L18
  movabs $0x200000002,%rdx
  test   %rdx,%rax
  jne    L38
  movabs $0x100000001,%rdx
  test   %rdx,%rax
  jne    L59
L53:
  lea    D40(%rip),%rdi
  call   <printf@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L59:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L38:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L18:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D35
type: string
name: parse_data
arguments: data_label: D43
type: string
name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D8
type: string
name: parse_data
arguments: data_label: D50
type: string
name: parse_data
arguments: data_label: D40
type: string
name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D26
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: D35: ******** MAIN MENU **************


tool: D43:  a. Formula 1 


tool: D2:  b. Formula 2 


tool: D8:  e. EXIT program 


tool: D50: %c

tool: D40: Invalid option!

tool: D3: Solving Formula 1 


tool: D26: Solving Formula 2 


tool: D0: Exiting program...


assistant: ```c
int main() {
  char selection;
  printf("******** MAIN MENU **************\n");
  printf(" a. Formula 1 \n");
  printf(" b. Formula 2 \n");
  printf(" e. EXIT program \n");
  scanf("%c", &selection);
  switch (selection) {
  case 'A':
  case 'a':
    printf("Solving Formula 1 \n");
    break;
  case 'B':
  case 'b':
    printf("Solving Formula 2 \n");
    break;
  case 'E':
  case 'e':
    printf("Exiting program...\n");
  default:
    printf("Invalid option!");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D65(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x41(%rax),%ecx
  cmp    $0x24,%cl
  ja     L64
  movabs $0x1000000010,%rdx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %rdx,%rax
  jne    L57
  movabs $0x200000002,%rdx
  test   %rdx,%rax
  jne    L6
  movabs $0x100000001,%rdx
  test   %rdx,%rax
  jne    L72
L64:
  lea    D35(%rip),%rdi
  call   <printf@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L57:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L64
L72:
  lea    D76(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L6:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D65
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D47
type_guessed: string
name: parse_data
arguments: data_tag: D64
type_guessed: string
name: parse_data
arguments: data_tag: D39
type_guessed: string
name: parse_data
arguments: data_tag: D35
type_guessed: string
name: parse_data
arguments: data_tag: D41
type_guessed: string
name: parse_data
arguments: data_tag: D76
type_guessed: string
name: parse_data
arguments: data_tag: D53
type_guessed: string

tool: D65: ******** MAIN MENU **************


tool: D29:  a. Formula 1 


tool: D47:  b. Formula 2 


tool: D64:  e. EXIT program 


tool: D39: %c

tool: D35: Invalid option!

tool: D41: Exiting program...


tool: D76: Solving Formula 1 


tool: D53: Solving Formula 2 


assistant: ```c
int main() {
  char selection;
  printf("******** MAIN MENU **************\n");
  printf(" a. Formula 1 \n");
  printf(" b. Formula 2 \n");
  printf(" e. EXIT program \n");
  scanf("%c", &selection);
  switch (selection) {
  case 'A':
  case 'a':
    printf("Solving Formula 1 \n");
    break;
  case 'B':
  case 'b':
    printf("Solving Formula 2 \n");
    break;
  case 'E':
  case 'e':
    printf("Exiting program...\n");
  default:
    printf("Invalid option!");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D76(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x41(%rax),%ecx
  cmp    $0x24,%cl
  ja     L30
  movabs $0x1000000010,%rdx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %rdx,%rax
  jne    L39
  movabs $0x200000002,%rdx
  test   %rdx,%rax
  jne    L2
  movabs $0x100000001,%rdx
  test   %rdx,%rax
  jne    L6
L30:
  lea    D6(%rip),%rdi
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L39:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L6:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L2:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D23
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string
name: extract_symbolic_data
arguments: data_tag: D73
data_type: string
name: extract_symbolic_data
arguments: data_tag: D76
data_type: string
name: extract_symbolic_data
arguments: data_tag: D54
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string
name: extract_symbolic_data
arguments: data_tag: D53
data_type: string
name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D29
data_type: string

tool: D23: ******** MAIN MENU **************


tool: D18:  a. Formula 1 


tool: D73:  b. Formula 2 


tool: D76:  e. EXIT program 


tool: D54: %c

tool: D6: Invalid option!

tool: D53: Exiting program...


tool: D9: Solving Formula 1 


tool: D29: Solving Formula 2 


assistant: ```c
int main() {
  char selection;
  printf("******** MAIN MENU **************\n");
  printf(" a. Formula 1 \n");
  printf(" b. Formula 2 \n");
  printf(" e. EXIT program \n");
  scanf("%c", &selection);
  switch (selection) {
  case 'A':
  case 'a':
    printf("Solving Formula 1 \n");
    break;
  case 'B':
  case 'b':
    printf("Solving Formula 2 \n");
    break;
  case 'E':
  case 'e':
    printf("Exiting program...\n");
  default:
    printf("Invalid option!");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checkizero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <xlfail@plt>
L8:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D8: division by zero

assistant: ```c
checkizero(long int iarg) {
  if (iarg == 0)
    xlfail("division by zero");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checkizero>:
  endbr64
  test   %rdi,%rdi
  je     L3
  ret
L3:
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <xlfail@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: division by zero

assistant: ```c
checkizero(long int iarg) {
  if (iarg == 0)
    xlfail("division by zero");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<checkizero>:
  endbr64
  test   %rdi,%rdi
  je     L2
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D8(%rip),%rdi
  jmp    1050 <xlfail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: division by zero

assistant: ```c
checkizero(long int iarg) {
  if (iarg == 0)
    xlfail("division by zero");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checkizero>:
  endbr64
  test   %rdi,%rdi
  je     L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  lea    D1(%rip),%rdi
  jmp    1050 <xlfail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string

tool: D1: division by zero

assistant: ```c
checkizero(long int iarg) {
  if (iarg == 0)
    xlfail("division by zero");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getline@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fatal@plt>
L1:
  lea    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <outp@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: missing string

assistant: ```c
long str(data, maxl, rcp)
char *data;
long maxl;
struct res *rcp;
{
  char *lp, *getline();
  char *datap = data;
  char *outp(), *outs(), *outl(), *outc();
  if ((lp = getline()) == 0)
    fatal("missing string");
  datap = outp(datap, lp, &maxl, 1);
  return (datap - data);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x8(%rsp)
  mov    $0x0,%eax
  call   <getline@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
L9:
  lea    0x8(%rsp),%rdx
  mov    $0x1,%ecx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <outp@plt>
  sub    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <fatal@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: missing string

assistant: ```c
long str(data, maxl, rcp)
char *data;
long maxl;
struct res *rcp;
{
  char *lp, *getline();
  char *datap = data;
  char *outp(), *outs(), *outl(), *outc();
  if ((lp = getline()) == 0)
    fatal("missing string");
  datap = outp(datap, lp, &maxl, 1);
  return (datap - data);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %rsi,0x8(%rsp)
  call   <getline@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L11
L2:
  lea    0x8(%rsp),%rdx
  mov    %rbx,%rdi
  mov    $0x1,%ecx
  xor    %eax,%eax
  call   <outp@plt>
  add    $0x10,%rsp
  sub    %rbx,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L11:
  mov    %rax,(%rsp)
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <fatal@plt>
  mov    (%rsp),%rsi
  jmp    L2
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: string

tool: D8: missing string

assistant: ```c
long str(data, maxl, rcp)
char *data;
long maxl;
struct res *rcp;
{
  char *lp, *getline();
  char *datap = data;
  char *outp(), *outs(), *outl(), *outc();
  if ((lp = getline()) == 0)
    fatal("missing string");
  datap = outp(datap, lp, &maxl, 1);
  return (datap - data);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %rsi,0x8(%rsp)
  call   <getline@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L1
L15:
  lea    0x8(%rsp),%rdx
  mov    %rbx,%rdi
  mov    $0x1,%ecx
  xor    %eax,%eax
  call   <outp@plt>
  add    $0x10,%rsp
  sub    %rbx,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L1:
  mov    %rax,(%rsp)
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <fatal@plt>
  mov    (%rsp),%rsi
  jmp    L15
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: missing string

assistant: ```c
long str(data, maxl, rcp)
char *data;
long maxl;
struct res *rcp;
{
  char *lp, *getline();
  char *datap = data;
  char *outp(), *outs(), *outl(), *outc();
  if ((lp = getline()) == 0)
    fatal("missing string");
  datap = outp(datap, lp, &maxl, 1);
  return (datap - data);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L31
  negl   -0x14(%rbp)
L31:
  cmpl   $0x0,-0x14(%rbp)
  jne    L51
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  jmp    L18
L51:
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L40:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L16:
  cmpl   $0x0,-0x14(%rbp)
  jg     L40
L18:
  cmpl   $0x0,-0x4(%rbp)
  jns    L56
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L56:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void itos(int n, char *s) {
  int j = 0, sign;
  if ((sign = n) < 0) {
    n = -n;
  }
  if (n == 0) {
    s[j++] = 0 + '0';
  } else {
    for (j = 0; n > 0; j++, n /= 10) {
      s[j] = n % 10 + '0';
    }
  }
  if (sign < 0) {
    s[j++] = '-';
  }
  s[j] = '\0';
}
```