ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_25_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x3(%rbp)
  notb   -0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_25_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rop3_25_0_0>:
  endbr64
  and    %esi,%edx
  not    %edx
  and    (%rdi),%dl
  xor    %esi,%edx
  not    %edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_25_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_25_0_0>:
  endbr64
  and    %esi,%edx
  not    %edx
  and    (%rdi),%dl
  xor    %esi,%edx
  not    %edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_25_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_25_0_0>:
  endbr64
  and    %esi,%edx
  not    %edx
  and    (%rdi),%dl
  xor    %esi,%edx
  not    %edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_25_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<myabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: x=0x%x, y=0x%x, z=0x%x


assistant: ```c
uint32_t myabs(int x) {
  uint32_t n;
  int y;
  int z;
  y = x >> 31;
  z = x + y;
  n = z ^ y;
  printf("x=0x%x, y=0x%x, z=0x%x\n", x, y, z);
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<myabs>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%edx
  sar    $0x1f,%edx
  lea    (%rdi,%rdx,1),%ecx
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  neg    %eax
  cmovs  %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: x=0x%x, y=0x%x, z=0x%x


assistant: ```c
uint32_t myabs(int x) {
  uint32_t n;
  int y;
  int z;
  y = x >> 31;
  z = x + y;
  n = z ^ y;
  printf("x=0x%x, y=0x%x, z=0x%x\n", x, y, z);
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myabs>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  mov    %edi,%ebx
  mov    %edi,%esi
  sar    $0x1f,%edx
  lea    (%rdi,%rdx,1),%ecx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  neg    %eax
  cmovs  %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: x=0x%x, y=0x%x, z=0x%x


assistant: ```c
uint32_t myabs(int x) {
  uint32_t n;
  int y;
  int z;
  y = x >> 31;
  z = x + y;
  n = z ^ y;
  printf("x=0x%x, y=0x%x, z=0x%x\n", x, y, z);
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<myabs>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  mov    %edi,%ebx
  mov    %edi,%esi
  sar    $0x1f,%edx
  lea    (%rdi,%rdx,1),%ecx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  neg    %eax
  cmovs  %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: x=0x%x, y=0x%x, z=0x%x


assistant: ```c
uint32_t myabs(int x) {
  uint32_t n;
  int y;
  int z;
  y = x >> 31;
  z = x + y;
  n = z ^ y;
  printf("x=0x%x, y=0x%x, z=0x%x\n", x, y, z);
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_fp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L58:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L58
  sub    $0x48,%rsp
  mov    %rdi,-0x4048(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x4030(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L53:
  cmp    %rdx,%rsp
  je     L51
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L53
L51:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L11
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L11:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x4028(%rbp)
  mov    -0x4048(%rbp),%rax
  mov    %rax,%rdi
  call   <fileno@plt>
  mov    %eax,-0x4038(%rbp)
  lea    -0x403c(%rbp),%rax
  mov    %rax,%rdi
  call   <SHA_Init@plt>
L17:
  lea    -0x4020(%rbp),%rcx
  mov    -0x4038(%rbp),%eax
  mov    $0x4000,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4034(%rbp)
  cmpl   $0x0,-0x4034(%rbp)
  jle    L54
  mov    -0x4034(%rbp),%eax
  movslq %eax,%rdx
  lea    -0x4020(%rbp),%rcx
  lea    -0x403c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SHA_Update@plt>
  jmp    L17
L54:
  nop
  mov    -0x4028(%rbp),%rax
  lea    -0x403c(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <SHA_Final@plt>
  mov    -0x4028(%rbp),%rax
  mov    %rax,%rdi
  call   <pt@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void do_fp(FILE *f) {
  SHA_CTX c;
  unsigned char md[SHA_DIGEST_LENGTH];
  int fd;
  int i;
  unsigned char buf[1024 * 16];
  fd = fileno(f);
  SHA_Init(&c);
  for (;;) {
    i = read(fd, buf, 1024 * 16);
    if (i <= 0)
      break;
    SHA_Update(&c, buf, (unsigned long)i);
  }
  SHA_Final(&(md[0]), &c);
  pt(md);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_fp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x4000(%rsp),%r11
L40:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L40
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L17:
  cmp    %rdx,%rsp
  je     L30
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L17
L30:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L25
  orq    $0x0,-0x8(%rsp,%rax,1)
L25:
  mov    %rsp,%r13
  call   <fileno@plt>
  mov    %eax,%r12d
  lea    -0x4034(%rbp),%rdi
  call   <SHA_Init@plt>
  lea    -0x4030(%rbp),%rbx
  jmp    L27
L20:
  movslq %eax,%rdx
  lea    -0x4034(%rbp),%rdi
  mov    %rbx,%rsi
  call   <SHA_Update@plt>
L27:
  mov    $0x4000,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L20
  lea    -0x4034(%rbp),%rsi
  mov    %r13,%rdi
  call   <SHA_Final@plt>
  mov    %r13,%rdi
  call   <pt@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_fp(FILE *f) {
  SHA_CTX c;
  unsigned char md[SHA_DIGEST_LENGTH];
  int fd;
  int i;
  unsigned char buf[1024 * 16];
  fd = fileno(f);
  SHA_Init(&c);
  for (;;) {
    i = read(fd, buf, 1024 * 16);
    if (i <= 0)
      break;
    SHA_Update(&c, buf, (unsigned long)i);
  }
  SHA_Final(&(md[0]), &c);
  pt(md);
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_fp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x4000(%rsp),%r11
L57:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L57
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D5(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L43
L73:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L73
L43:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L54
L3:
  call   <fileno@plt>
  lea    -0x4034(%rbp),%r13
  mov    %rsp,%r14
  lea    -0x4030(%rbp),%rbx
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <SHA_Init@plt>
  jmp    L52
  nopl   (%rax)
L70:
  movslq %eax,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <SHA_Update@plt>
L52:
  mov    $0x4000,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L70
  mov    %r14,%rdi
  mov    %r13,%rsi
  call   <SHA_Final@plt>
  mov    %r14,%rdi
  call   <pt@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L54:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L3
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_fp(FILE *f) {
  SHA_CTX c;
  unsigned char md[SHA_DIGEST_LENGTH];
  int fd;
  int i;
  unsigned char buf[1024 * 16];
  fd = fileno(f);
  SHA_Init(&c);
  for (;;) {
    i = read(fd, buf, 1024 * 16);
    if (i <= 0)
      break;
    SHA_Update(&c, buf, (unsigned long)i);
  }
  SHA_Final(&(md[0]), &c);
  pt(md);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_fp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x4000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D2(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L28
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L21
L28:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L6
L44:
  call   <fileno@plt>
  lea    -0x4034(%rbp),%r13
  mov    %rsp,%r14
  lea    -0x4030(%rbp),%rbx
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <SHA_Init@plt>
  jmp    L64
  nopl   (%rax)
L2:
  movslq %eax,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <SHA_Update@plt>
L64:
  mov    $0x4000,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L2
  mov    %r14,%rdi
  mov    %r13,%rsi
  call   <SHA_Final@plt>
  mov    %r14,%rdi
  call   <pt@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L44
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_fp(FILE *f) {
  SHA_CTX c;
  unsigned char md[SHA_DIGEST_LENGTH];
  int fd;
  int i;
  unsigned char buf[1024 * 16];
  fd = fileno(f);
  SHA_Init(&c);
  for (;;) {
    i = read(fd, buf, 1024 * 16);
    if (i <= 0)
      break;
    SHA_Update(&c, buf, (unsigned long)i);
  }
  SHA_Final(&(md[0]), &c);
  pt(md);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L10
L26:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D18(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D6(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <abs2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L14
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L37
L14:
  addl   $0x1,-0x24(%rbp)
L10:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L26
L37:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L24
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L24:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
type_infered: f64
name: parse_data
arguments: data_label: D6
type_infered: f64
name: parse_data
arguments: data_label: D34
type_infered: string

tool: D18: 1000

tool: D6: 500

tool: D34: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 500.0;
    y = abs2(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
L13:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D26(%rip),%xmm0
  subsd  D27(%rip),%xmm0
  call   <abs2@plt>
  ucomisd %xmm0,%xmm0
  jp     L16
  sub    $0x1,%ebx
  jne    L13
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L8
L16:
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L8:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type: f64
name: extract_symbolic_data
arguments: tag: D27
type: f64
name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D26: 1000

tool: D27: 500

tool: D2: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 500.0;
    y = abs2(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L1
  xchg   %ax,%ax
L24:
  sub    $0x1,%ebx
  je     L18
L1:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D12(%rip),%xmm0
  subsd  D21(%rip),%xmm0
  call   <abs2@plt>
  ucomisd %xmm0,%xmm0
  jnp    L24
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L18:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_guessed: f64
name: parse_data
arguments: data_tag: D21
type_guessed: f64
name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D12: 1000

tool: D21: 500

tool: D9: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 500.0;
    y = abs2(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L20
  xchg   %ax,%ax
L27:
  sub    $0x1,%ebx
  je     L11
L20:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D19(%rip),%xmm0
  subsd  D21(%rip),%xmm0
  call   <abs2@plt>
  ucomisd %xmm0,%xmm0
  jnp    L27
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L11:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: f64
name: read_data
arguments: label: D21
type_guessed: f64
name: read_data
arguments: label: D17
type_guessed: string

tool: D19: 1000

tool: D21: 500

tool: D17: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 500.0;
    y = abs2(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<safeSnprintfAppend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L80
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L80:
  cmpq   $0x0,-0xc8(%rbp)
  je     L76
  cmpq   $0x0,-0xd0(%rbp)
  je     L76
  cmpq   $0x0,-0xd8(%rbp)
  jne    L100
L76:
  mov    $0xffffffff,%eax
  jmp    L3
L100:
  mov    -0xd0(%rbp),%rdx
  mov    -0xc8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <safeStrnlen@plt>
  mov    %eax,-0xbc(%rbp)
  cmpl   $0xffffffff,-0xbc(%rbp)
  jne    L49
  mov    -0xc8(%rbp),%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0xbc(%rbp)
L49:
  mov    -0xd0(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xd0(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  mov    -0xbc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc8(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0xb8(%rbp),%edx
  mov    -0xd8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpl   $0x0,-0xb4(%rbp)
  jns    L12
  mov    $0xffffffff,%eax
  jmp    L3
L12:
  mov    -0xd0(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  mov    -0xb4(%rbp),%eax
  cltq
  cmp    %rax,-0xd0(%rbp)
  ja     L18
L47:
  mov    -0xd0(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L3
L18:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int safeSnprintfAppend(char *buf, size_t buf_size, const char *format, ...) {
  int str_len;
  int ret;
  va_list ap;
  if (buf == NULL || buf_size <= 0 || format == NULL)
    return -1;
  str_len = safeStrnlen(buf, buf_size);
  if (str_len == -1) {
    buf[0] = '\0';
    str_len = 0;
  }
  buf[buf_size - 1] = '\0';
  va_start(ap, format);
  ret = vsnprintf(buf + str_len, buf_size - (size_t)str_len, format, ap);
  va_end(ap);
  if (ret < 0)
    return -1;
  if (buf[buf_size - 1] != '\0' || (size_t)ret >= buf_size) {
    buf[buf_size - 1] = '\0';
    return -2;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<safeSnprintfAppend>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L29
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %rdi,%rdi
  je     L29
  call   <safeStrnlen@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L66
L95:
  lea    -0x1(%rbx,%r12,1),%r15
  movb   $0x0,(%r15)
  mov    %r13,%rsi
  mov    $0x0,%r14d
  mov    %r14d,%edi
  call   <va_start@plt>
  movslq %ebp,%rbp
  mov    %r12,%rsi
  sub    %rbp,%rsi
  lea    (%rbx,%rbp,1),%rdi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %r14d,%edi
  call   <va_end@plt>
  test   %ebx,%ebx
  js     L57
  cmpb   $0x0,(%r15)
  jne    L41
  movslq %ebx,%rbx
  cmp    %r12,%rbx
  jae    L41
  mov    $0x0,%eax
L60:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  movb   $0x0,(%rbx)
  mov    $0x0,%ebp
  jmp    L95
L41:
  movb   $0x0,(%r15)
  mov    $0xfffffffe,%eax
  jmp    L60
L29:
  mov    $0xffffffff,%eax
  jmp    L60
L57:
  mov    $0xffffffff,%eax
  jmp    L60
```

assistant: ```c
int safeSnprintfAppend(char *buf, size_t buf_size, const char *format, ...) {
  int str_len;
  int ret;
  va_list ap;
  if (buf == NULL || buf_size <= 0 || format == NULL)
    return -1;
  str_len = safeStrnlen(buf, buf_size);
  if (str_len == -1) {
    buf[0] = '\0';
    str_len = 0;
  }
  buf[buf_size - 1] = '\0';
  va_start(ap, format);
  ret = vsnprintf(buf + str_len, buf_size - (size_t)str_len, format, ap);
  va_end(ap);
  if (ret < 0)
    return -1;
  if (buf[buf_size - 1] != '\0' || (size_t)ret >= buf_size) {
    buf[buf_size - 1] = '\0';
    return -2;
  }
  return 0;
}
```