ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<f6>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <__builtin_object_size@plt>
  mov    %eax,%r8d
  lea    0x9(%rsp),%rbx
  mov    $0x5,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <__builtin___memccpy_chk@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <__builtin_object_size@plt>
  mov    %eax,%r8d
  mov    $0xa,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__builtin___memccpy_chk@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f6(void) {
  char b[5];
  char buf[10];
  __builtin___memccpy_chk(buf, b, '\0', sizeof(b), __builtin_object_size(buf, 0));
  __builtin___memccpy_chk(b, buf, '\0', sizeof(buf), __builtin_object_size(b, 0));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f6>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  lea    0x9(%rsp),%rbp
  mov    %r12,%rdi
  call   <__builtin_object_size@plt>
  xor    %edx,%edx
  mov    $0x5,%ecx
  mov    %rbp,%rsi
  mov    %eax,%r8d
  mov    %r12,%rdi
  call   <__builtin___memccpy_chk@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <__builtin_object_size@plt>
  xor    %edx,%edx
  mov    $0xa,%ecx
  mov    %r12,%rsi
  mov    %eax,%r8d
  mov    %rbp,%rdi
  call   <__builtin___memccpy_chk@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f6(void) {
  char b[5];
  char buf[10];
  __builtin___memccpy_chk(buf, b, '\0', sizeof(b), __builtin_object_size(buf, 0));
  __builtin___memccpy_chk(b, buf, '\0', sizeof(buf), __builtin_object_size(b, 0));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f6>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  lea    0x9(%rsp),%rbp
  mov    %r12,%rdi
  call   <__builtin_object_size@plt>
  xor    %edx,%edx
  mov    $0x5,%ecx
  mov    %rbp,%rsi
  mov    %eax,%r8d
  mov    %r12,%rdi
  call   <__builtin___memccpy_chk@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <__builtin_object_size@plt>
  xor    %edx,%edx
  mov    $0xa,%ecx
  mov    %r12,%rsi
  mov    %eax,%r8d
  mov    %rbp,%rdi
  call   <__builtin___memccpy_chk@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f6(void) {
  char b[5];
  char buf[10];
  __builtin___memccpy_chk(buf, b, '\0', sizeof(b), __builtin_object_size(buf, 0));
  __builtin___memccpy_chk(b, buf, '\0', sizeof(buf), __builtin_object_size(b, 0));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0xa,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L14
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L14
L72:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L19
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  cmp    $0xffffff9d,%eax
  jl     L19
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  cmp    $0x63,%eax
  jg     L19
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L35
L19:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L72
L35:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D45
datatype: string
name: parse_data
arguments: data_label: D33
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string
name: parse_data
arguments: data_label: D47
datatype: string
name: parse_data
arguments: data_label: D37
datatype: string

tool: D45: Enter an integer > 

tool: D33: %d

tool: D14: 0

tool: D47: %d


tool: D37: That's all, have a nice day!

assistant: ```c
int main(void) {
  int number, digit, j, digit1;
  printf("Enter an integer > ");
  scanf("%d", &number);
  printf("\n");
  j = 10;
  if (number == 0) {
    printf("0\n");
  }
  while (number != 0) {
    digit = number % j;
    if (digit < 0 && abs(number * 10) < 100) {
      printf("%d\n", digit);
      break;
    } else
      digit1 = abs(digit);
    printf("%d\n", digit1);
    number = number / 10;
  }
  printf("That's all, have a nice day!\n");
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L16
L45:
  lea    D3(%rip),%rbx
  jmp    L10
L16:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L45
  jmp    L70
L34:
  mov    %esi,%eax
  neg    %eax
  cmovns %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  je     L70
L10:
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  cltd
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  add    %edx,%edx
  mov    %eax,%esi
  sub    %edx,%esi
  jns    L34
  lea    (%rax,%rax,4),%eax
  lea    0x63(%rax,%rax,1),%eax
  cmp    $0xc6,%eax
  ja     L34
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L70:
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D42
type: string
name: disassemble_data
arguments: tag: D3
type: string
name: disassemble_data
arguments: tag: D20
type: string
name: disassemble_data
arguments: tag: D37
type: string

tool: D17: Enter an integer > 

tool: D42: %d

tool: D3: %d


tool: D20: 0

tool: D37: That's all, have a nice day!

assistant: ```c
int main(void) {
  int number, digit, j, digit1;
  printf("Enter an integer > ");
  scanf("%d", &number);
  printf("\n");
  j = 10;
  if (number == 0) {
    printf("0\n");
  }
  while (number != 0) {
    digit = number % j;
    if (digit < 0 && abs(number * 10) < 100) {
      printf("%d\n", digit);
      break;
    } else
      digit1 = abs(digit);
    printf("%d\n", digit1);
    number = number / 10;
  }
  printf("That's all, have a nice day!\n");
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D48(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L76
L67:
  lea    D37(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L35:
  movslq %eax,%rsi
  cltd
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  mov    %eax,%esi
  add    %edx,%edx
  sub    %edx,%esi
  jns    L9
  lea    (%rax,%rax,4),%eax
  lea    0x63(%rax,%rax,1),%eax
  cmp    $0xc6,%eax
  jbe    L64
L9:
  mov    %esi,%eax
  mov    %rbp,%rdi
  neg    %eax
  cmovns %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  jne    L35
L20:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L64:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L20
L76:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L67
  jmp    L20
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D46
datatype: string
name: parse_data
arguments: tag: D48
datatype: string
name: parse_data
arguments: tag: D37
datatype: string
name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D12
datatype: string

tool: D46: Enter an integer > 

tool: D48: %d

tool: D37: %d


tool: D9: That's all, have a nice day!

tool: D12: 0

assistant: ```c
int main(void) {
  int number, digit, j, digit1;
  printf("Enter an integer > ");
  scanf("%d", &number);
  printf("\n");
  j = 10;
  if (number == 0) {
    printf("0\n");
  }
  while (number != 0) {
    digit = number % j;
    if (digit < 0 && abs(number * 10) < 100) {
      printf("%d\n", digit);
      break;
    } else
      digit1 = abs(digit);
    printf("%d\n", digit1);
    number = number / 10;
  }
  printf("That's all, have a nice day!\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D42(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L43
L1:
  lea    D36(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L24:
  movslq %eax,%rsi
  cltd
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  mov    %eax,%esi
  add    %edx,%edx
  sub    %edx,%esi
  jns    L2
  lea    (%rax,%rax,4),%eax
  lea    0x63(%rax,%rax,1),%eax
  cmp    $0xc6,%eax
  jbe    L48
L2:
  mov    %esi,%eax
  mov    %rbp,%rdi
  neg    %eax
  cmovns %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  jne    L24
L61:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L48:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L61
L43:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L1
  jmp    L61
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D42
type_infered: string
name: extract_symbolic_data
arguments: label: D32
type_infered: string
name: extract_symbolic_data
arguments: label: D36
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D15
type_infered: string

tool: D42: Enter an integer > 

tool: D32: %d

tool: D36: %d


tool: D14: That's all, have a nice day!

tool: D15: 0

assistant: ```c
int main(void) {
  int number, digit, j, digit1;
  printf("Enter an integer > ");
  scanf("%d", &number);
  printf("\n");
  j = 10;
  if (number == 0) {
    printf("0\n");
  }
  while (number != 0) {
    digit = number % j;
    if (digit < 0 && abs(number * 10) < 100) {
      printf("%d\n", digit);
      break;
    } else
      digit1 = abs(digit);
    printf("%d\n", digit1);
    number = number / 10;
  }
  printf("That's all, have a nice day!\n");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rtpp_zmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *rtpp_zmalloc(size_t msize) {
  void *rval;
  rval = malloc(msize);
  if (rval != NULL) {
    memset(rval, '\0', msize);
  }
  return (rval);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rtpp_zmalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *rtpp_zmalloc(size_t msize) {
  void *rval;
  rval = malloc(msize);
  if (rval != NULL) {
    memset(rval, '\0', msize);
  }
  return (rval);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rtpp_zmalloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *rtpp_zmalloc(size_t msize) {
  void *rval;
  rval = malloc(msize);
  if (rval != NULL) {
    memset(rval, '\0', msize);
  }
  return (rval);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rtpp_zmalloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *rtpp_zmalloc(size_t msize) {
  void *rval;
  rval = malloc(msize);
  if (rval != NULL) {
    memset(rval, '\0', msize);
  }
  return (rval);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  jmp    L5
L4:
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L4
L25:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *getnum(const char *n, int *num) {
  *num = atoi(n);
  while (*n >= '0' && *n <= '9')
    n++;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getnum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <atoi@plt>
  mov    %eax,0x0(%rbp)
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L8
L1:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L1
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *getnum(const char *n, int *num) {
  *num = atoi(n);
  while (*n >= '0' && *n <= '9')
    n++;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getnum>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <atoi@plt>
  mov    %eax,(%rbx)
  movzbl (%r12),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L10
  nopl   0x0(%rax)
L15:
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L15
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *getnum(const char *n, int *num) {
  *num = atoi(n);
  while (*n >= '0' && *n <= '9')
    n++;
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<getnum>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <atoi@plt>
  mov    %eax,(%rbx)
  movzbl (%r12),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L14
  nopl   0x0(%rax)
L8:
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L8
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
const char *getnum(const char *n, int *num) {
  *num = atoi(n);
  while (*n >= '0' && *n <= '9')
    n++;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <g@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0xc(%rax),%eax
  leave
  ret
```

assistant: ```c
int f(int **arr) {
  int *a = g(arr);
  return a[3];
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  call   <g@plt>
  mov    0xc(%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f(int **arr) {
  int *a = g(arr);
  return a[3];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  call   <g@plt>
  mov    0xc(%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f(int **arr) {
  int *a = g(arr);
  return a[3];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<math_log>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jae    L11
  mov    0x4(%rsp),%eax
  shr    $0x4,%eax
  and    $0xffff7ff,%eax
  ucomisd %xmm1,%xmm0
  jp     L25
  je     L5
L25:
  mulsd  D48(%rip),%xmm0
  movsd  D79(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  addsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  mulsd  D40(%rip),%xmm0
  addsd  D76(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D53(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D10(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D26(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  sub    $0x3fe,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  D61(%rip),%xmm1
  mulsd  D64(%rip),%xmm1
  addsd  %xmm1,%xmm0
  ret
L5:
  sub    $0x3ff,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D64(%rip),%xmm0
  ret
L11:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D48
datatype: f64
name: parse_data
arguments: tag: D79
datatype: f64
name: parse_data
arguments: tag: D40
datatype: f64
name: parse_data
arguments: tag: D76
datatype: f64
name: parse_data
arguments: tag: D53
datatype: f64
name: parse_data
arguments: tag: D10
datatype: f64
name: parse_data
arguments: tag: D26
datatype: f64
name: parse_data
arguments: tag: D61
datatype: f64
name: parse_data
arguments: tag: D64
datatype: byte[8]

tool: D48: 1.4142135623730951

tool: D79: 1

tool: D40: 0.2376245609

tool: D76: 0.28525381498

tool: D53: 0.4000059794795

tool: D10: 0.666666635059382

tool: D26: 2.000000000046727

tool: D61: 0.5

tool: {"D64": [0xec,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
double math_log(double x) {
  typedef union {
    double d;
    unsigned u[4];
  } DBL;
  double y, z, z2, p;
  unsigned ex;
  int ix;
  DBL *xp, *yp;
  xp = (DBL *)&x;
  if (xp->d <= 0.0)
    return (y);
  y = 0.0;
  yp = (DBL *)&y;
  yp->u[3] = xp->u[3] & ~0100017;
  ix = (yp->u[3] >> 4) - 1023;
  if ((xp->d - yp->d) == 0.0)
    return (.693147180559945 * (double)ix);
  xp->u[3] -= ++ix << 4;
  xp->d *= 1.4142135623730950488;
  z = (xp->d - 1.0) / (xp->d + 1.0);
  z2 = z * z;
  y = z * (2.000000000046727 + z2 * (0.666666635059382 + z2 * (0.4000059794795 + z2 * (0.28525381498 + z2 * 0.2376245609))));
  y = y + .693147180559945 * ((double)ix - 0.5);
  return (yp->d);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<math_log>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jae    L15
  mov    0x4(%rsp),%eax
  shr    $0x4,%eax
  and    $0xffff7ff,%eax
  ucomisd %xmm1,%xmm0
  jp     L19
  je     L10
L19:
  mulsd  D49(%rip),%xmm0
  movsd  D4(%rip),%xmm2
  sub    $0x3fe,%eax
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movsd  D57(%rip),%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm0
  addsd  D73(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D65(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D0(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D95(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  D3(%rip),%xmm1
  mulsd  D16(%rip),%xmm1
  addsd  %xmm1,%xmm0
  ret
L10:
  sub    $0x3ff,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D16(%rip),%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D49
data_type: f64
name: disassemble_data
arguments: data_tag: D4
data_type: f64
name: disassemble_data
arguments: data_tag: D57
data_type: f64
name: disassemble_data
arguments: data_tag: D73
data_type: f64
name: disassemble_data
arguments: data_tag: D65
data_type: f64
name: disassemble_data
arguments: data_tag: D0
data_type: f64
name: disassemble_data
arguments: data_tag: D95
data_type: f64
name: disassemble_data
arguments: data_tag: D3
data_type: f64
name: disassemble_data
arguments: data_tag: D16
data_type: byte[8]

tool: D49: 1.4142135623730951

tool: D4: 1

tool: D57: 0.2376245609

tool: D73: 0.28525381498

tool: D65: 0.4000059794795

tool: D0: 0.666666635059382

tool: D95: 2.000000000046727

tool: D3: 0.5

tool: {"D16": [0xec,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
double math_log(double x) {
  typedef union {
    double d;
    unsigned u[4];
  } DBL;
  double y, z, z2, p;
  unsigned ex;
  int ix;
  DBL *xp, *yp;
  xp = (DBL *)&x;
  if (xp->d <= 0.0)
    return (y);
  y = 0.0;
  yp = (DBL *)&y;
  yp->u[3] = xp->u[3] & ~0100017;
  ix = (yp->u[3] >> 4) - 1023;
  if ((xp->d - yp->d) == 0.0)
    return (.693147180559945 * (double)ix);
  xp->u[3] -= ++ix << 4;
  xp->d *= 1.4142135623730950488;
  z = (xp->d - 1.0) / (xp->d + 1.0);
  z2 = z * z;
  y = z * (2.000000000046727 + z2 * (0.666666635059382 + z2 * (0.4000059794795 + z2 * (0.28525381498 + z2 * 0.2376245609))));
  y = y + .693147180559945 * ((double)ix - 0.5);
  return (yp->d);
}
```