ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convert>:
  endbr64
  test   %rdi,%rdi
  je     L31
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    $0x2,%eax
  jle    L33
  cmp    $0x1,%r12d
  je     L33
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  cmp    %r12d,%ebx
  mov    %r12d,%r10d
  lea    -0x1(%r12),%r11d
  cmovle %ebx,%r10d
  mov    %rax,%r8
  lea    (%r11,%r11,1),%edi
  test   %r10d,%r10d
  jle    L94
  xor    %r12d,%r12d
  xor    %esi,%esi
  movslq %edi,%r9
  nopl   0x0(%rax)
L123:
  test   %esi,%esi
  je     L3
  cmp    %esi,%r11d
  je     L52
  lea    (%rsi,%rsi,1),%r13d
  cmp    %esi,%ebx
  jle    L85
  lea    0x1(%r12),%eax
  mov    %esi,%edx
  mov    $0x1,%ecx
  cltq
  jmp    L67
  nopl   (%rax)
L103:
  add    %edi,%edx
  xor    %ecx,%ecx
  add    $0x1,%rax
  cmp    %edx,%ebx
  jle    L85
L67:
  movslq %edx,%r14
  movslq %eax,%r12
  movzbl 0x0(%rbp,%r14,1),%r14d
  mov    %r14b,-0x1(%r8,%rax,1)
  test   %ecx,%ecx
  jne    L103
  add    %r13d,%edx
  mov    $0x1,%ecx
  add    $0x1,%rax
  cmp    %edx,%ebx
  jg     L67
L85:
  add    $0x1,%esi
  sub    $0x2,%edi
  cmp    %r10d,%esi
  jne    L123
L84:
  add    %r8,%r12
L154:
  movb   $0x0,(%r12)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  movslq %r11d,%rax
  cmp    %r11d,%ebx
  jle    L85
L8:
  lea    0x1(%r12),%edx
  movslq %edx,%rdx
L152:
  movzbl 0x0(%rbp,%rax,1),%ecx
  add    %r9,%rax
  movslq %edx,%r12
  mov    %cl,-0x1(%r8,%rdx,1)
  add    $0x1,%rdx
  cmp    %eax,%ebx
  jg     L152
  add    $0x1,%esi
  sub    $0x2,%edi
  cmp    %r10d,%esi
  jne    L123
  jmp    L84
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  jmp    L8
  nopl   0x0(%rax)
L33:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <strdup@plt>
L94:
  mov    %rax,%r12
  jmp    L154
L31:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *convert(char *s, int numRows) {
  if (!s)
    return (0);
  char *res;
  int i, j, l, step1, step2, flag, p, k;
  l = strlen(s);
  if (l <= 2 || numRows == 1)
    return (strdup(s));
  res = malloc(l + 1);
  k = 2 * numRows - 2;
  p = 0;
  for (i = 0; i < numRows && i < l; i++) {
    if (i == 0 || i == (numRows - 1)) {
      for (j = i; j < l; j += k)
        res[p++] = s[j];
      continue;
    }
    step1 = k - i * 2;
    step2 = k - step1;
    flag = 1;
    for (j = i; j < l;) {
      res[p++] = s[j];
      if (flag) {
        flag = 0;
        j += step1;
      } else {
        flag = 1;
        j += step2;
      }
    }
  }
  res[p] = 0;
  return (res);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<encodefd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %esi,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L15:
  lea    -0xa0(%rbp),%rcx
  mov    -0xb4(%rbp),%eax
  mov    $0x36,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0xb0(%rbp)
  cmpq   $0x0,-0xb0(%rbp)
  je     L24
  lea    -0x60(%rbp),%rdx
  mov    -0xb0(%rbp),%rcx
  lea    -0xa0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <encode@plt>
  mov    %rax,-0xa8(%rbp)
  mov    -0xa8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0xa8(%rbp)
  movb   $0xa,-0x60(%rbp,%rax,1)
  mov    -0xa8(%rbp),%rdx
  lea    -0x60(%rbp),%rcx
  mov    -0xb8(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  jmp    L15
L24:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
void encodefd(int fdin, int fdout) {
  while (1) {
    char in[54], out[73];
    size_t inlen = read(fdin, &in, sizeof in);
    if (inlen == 0)
      break;
    size_t outlen = encode(in, inlen, out);
    out[outlen++] = '\n';
    write(fdout, out, outlen);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<encodefd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L20
L26:
  lea    0x40(%rsp),%rbx
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <encode@plt>
  movb   $0xa,0x40(%rsp,%rax,1)
  lea    0x1(%rax),%rdx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <write@plt>
L20:
  mov    $0x36,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L26
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void encodefd(int fdin, int fdout) {
  while (1) {
    char in[54], out[73];
    size_t inlen = read(fdin, &in, sizeof in);
    if (inlen == 0)
      break;
    size_t outlen = encode(in, inlen, out);
    out[outlen++] = '\n';
    write(fdout, out, outlen);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<encodefd>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%rbp
  jmp    L16
  nopl   0x0(%rax)
L7:
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <encode@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  lea    0x1(%rax),%rdx
  movb   $0xa,0x40(%rsp,%rax,1)
  call   <write@plt>
L16:
  mov    %rbx,%rsi
  mov    $0x36,%edx
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L7
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void encodefd(int fdin, int fdout) {
  while (1) {
    char in[54], out[73];
    size_t inlen = read(fdin, &in, sizeof in);
    if (inlen == 0)
      break;
    size_t outlen = encode(in, inlen, out);
    out[outlen++] = '\n';
    write(fdout, out, outlen);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<encodefd>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%rbp
  jmp    L16
  nopl   0x0(%rax)
L28:
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <encode@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  lea    0x1(%rax),%rdx
  movb   $0xa,0x40(%rsp,%rax,1)
  call   <write@plt>
L16:
  mov    %rbx,%rsi
  mov    $0x36,%edx
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L28
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void encodefd(int fdin, int fdout) {
  while (1) {
    char in[54], out[73];
    size_t inlen = read(fdin, &in, sizeof in);
    if (inlen == 0)
      break;
    size_t outlen = encode(in, inlen, out);
    out[outlen++] = '\n';
    write(fdout, out, outlen);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calc_mv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L12:
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  0x4(%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  0x8(%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  0xc(%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void calc_mv(long n, float matrix[][4], float vector[], float mv[]) {
  long i;
  for (i = 0; i < n; i++)
    mv[i] = matrix[i][0] * vector[0] + matrix[i][1] * vector[1] + matrix[i][2] * vector[2] + matrix[i][3] * vector[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calc_mv>:
  endbr64
  test   %rdi,%rdi
  jle    L15
  mov    %rsi,%rax
  shl    $0x4,%rdi
  add    %rdi,%rsi
L12:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  movss  0x4(%rax),%xmm1
  mulss  0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rax),%xmm1
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rax),%xmm1
  mulss  0xc(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rcx)
  add    $0x10,%rax
  add    $0x4,%rcx
  cmp    %rsi,%rax
  jne    L12
L15:
  ret
```

assistant: ```c
void calc_mv(long n, float matrix[][4], float vector[], float mv[]) {
  long i;
  for (i = 0; i < n; i++)
    mv[i] = matrix[i][0] * vector[0] + matrix[i][1] * vector[1] + matrix[i][2] * vector[2] + matrix[i][3] * vector[3];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calc_mv>:
  endbr64
  test   %rdi,%rdi
  jle    L4
  shl    $0x4,%rdi
  lea    (%rsi,%rdi,1),%rax
  nopl   0x0(%rax)
L14:
  movss  (%rsi),%xmm0
  mulss  (%rdx),%xmm0
  add    $0x10,%rsi
  add    $0x4,%rcx
  movss  -0xc(%rsi),%xmm1
  mulss  0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  -0x8(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  -0x4(%rsi),%xmm1
  mulss  0xc(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rcx)
  cmp    %rsi,%rax
  jne    L14
L4:
  ret
```

assistant: ```c
void calc_mv(long n, float matrix[][4], float vector[], float mv[]) {
  long i;
  for (i = 0; i < n; i++)
    mv[i] = matrix[i][0] * vector[0] + matrix[i][1] * vector[1] + matrix[i][2] * vector[2] + matrix[i][3] * vector[3];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mm_prod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L14:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mm_prod(int n, double *m, double *r) {
  int i;
  int b_sqr = n * n;
  for (i = 0; i < b_sqr; ++i) {
    r[i] += m[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mm_prod>:
  endbr64
  imul   %edi,%edi
  test   %edi,%edi
  jle    L15
  mov    %edi,%edi
  mov    $0x0,%eax
L8:
  movsd  (%rdx,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L8
L15:
  ret
```

assistant: ```c
void mm_prod(int n, double *m, double *r) {
  int i;
  int b_sqr = n * n;
  for (i = 0; i < b_sqr; ++i) {
    r[i] += m[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mm_prod>:
  endbr64
  imul   %edi,%edi
  test   %edi,%edi
  je     L17
  movslq %edi,%rdi
  xor    %eax,%eax
L6:
  movsd  (%rdx,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L6
L17:
  ret
```

assistant: ```c
void mm_prod(int n, double *m, double *r) {
  int i;
  int b_sqr = n * n;
  for (i = 0; i < b_sqr; ++i) {
    r[i] += m[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mm_prod>:
  endbr64
  imul   %edi,%edi
  mov    %rsi,%rcx
  test   %edi,%edi
  je     L27
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdx
  je     L5
  lea    -0x1(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L5
  mov    %edi,%esi
  xor    %eax,%eax
  shr    %esi
  shl    $0x4,%rsi
  nopl   (%rax)
L58:
  movupd (%rdx,%rax,1),%xmm0
  movupd (%rcx,%rax,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L58
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L27
  lea    (%rdx,%rax,8),%rdx
  movsd  (%rdx),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L55:
  movsd  (%rdx,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L55
L27:
  ret
```

assistant: ```c
void mm_prod(int n, double *m, double *r) {
  int i;
  int b_sqr = n * n;
  for (i = 0; i < b_sqr; ++i) {
    r[i] += m[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_hash_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shr    $0x2,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L26
L9:
  mov    -0x1c(%rbp),%eax
  mov    -0x28(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L28
  mov    -0x20(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  xor    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x28(%rbp)
L28:
  addq   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L9
  mov    -0x28(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int get_hash_code(const char *s) {
  const unsigned int bits_in_uint = sizeof(unsigned int) * CHAR_BIT;
  const unsigned int three_quarters = (bits_in_uint * 3) / 4;
  const unsigned int one_eighth = bits_in_uint / 8;
  const unsigned int high_bits = ~((~0U) >> one_eighth);
  const size_t length = strlen(s);
  unsigned int hash = 0;
  for (size_t n = 0; n < length; n++) {
    hash = (hash << one_eighth) + (unsigned int)(s[n]);
    const unsigned int i = hash & high_bits;
    if (i != 0)
      hash = (hash ^ (i >> three_quarters)) & ~high_bits;
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_hash_code>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    D6(%rip),%rax
  mov    (%rax),%ebp
  lea    0x0(%rbp,%rbp,2),%r13d
  and    $0x3fffffff,%r13d
  shl    $0x2,%ebp
  shr    $0x3,%ebp
  mov    $0xffffffff,%r12d
  mov    %ebp,%ecx
  shr    %cl,%r12d
  call   <strlen@plt>
  test   %rax,%rax
  je     L39
  mov    %r12d,%ebx
  not    %ebx
  mov    %r14,%rdx
  lea    (%r14,%rax,1),%rdi
  mov    $0x0,%eax
  jmp    L44
L14:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L34
L44:
  mov    %ebp,%ecx
  shl    %cl,%eax
  movsbl (%rdx),%ecx
  add    %ecx,%eax
  mov    %ebx,%esi
  and    %eax,%esi
  je     L14
  mov    %r13d,%ecx
  shr    %cl,%esi
  xor    %esi,%eax
  and    %r12d,%eax
  jmp    L14
L39:
  mov    $0x0,%eax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int get_hash_code(const char *s) {
  const unsigned int bits_in_uint = sizeof(unsigned int) * CHAR_BIT;
  const unsigned int three_quarters = (bits_in_uint * 3) / 4;
  const unsigned int one_eighth = bits_in_uint / 8;
  const unsigned int high_bits = ~((~0U) >> one_eighth);
  const size_t length = strlen(s);
  unsigned int hash = 0;
  for (size_t n = 0; n < length; n++) {
    hash = (hash << one_eighth) + (unsigned int)(s[n]);
    const unsigned int i = hash & high_bits;
    if (i != 0)
      hash = (hash ^ (i >> three_quarters)) & ~high_bits;
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_hash_code>:
  endbr64
  mov    D8(%rip),%rax
  push   %r14
  push   %r13
  mov    $0xffffffff,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rax),%r12d
  mov    %rdi,%rbx
  lea    (%r12,%r12,2),%r14d
  shl    $0x2,%r12d
  shr    $0x3,%r12d
  and    $0x3fffffff,%r14d
  mov    %r12d,%ecx
  shr    %cl,%r13d
  call   <strlen@plt>
  test   %rax,%rax
  je     L7
  mov    %r13d,%ebp
  lea    (%rbx,%rax,1),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  not    %ebp
L2:
  movsbl (%rdi),%edx
  mov    %r12d,%ecx
  shl    %cl,%eax
  add    %edx,%eax
  mov    %ebp,%edx
  and    %eax,%edx
  je     L23
  mov    %r14d,%ecx
  shr    %cl,%edx
  xor    %edx,%eax
  and    %r13d,%eax
L23:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int get_hash_code(const char *s) {
  const unsigned int bits_in_uint = sizeof(unsigned int) * CHAR_BIT;
  const unsigned int three_quarters = (bits_in_uint * 3) / 4;
  const unsigned int one_eighth = bits_in_uint / 8;
  const unsigned int high_bits = ~((~0U) >> one_eighth);
  const size_t length = strlen(s);
  unsigned int hash = 0;
  for (size_t n = 0; n < length; n++) {
    hash = (hash << one_eighth) + (unsigned int)(s[n]);
    const unsigned int i = hash & high_bits;
    if (i != 0)
      hash = (hash ^ (i >> three_quarters)) & ~high_bits;
  }
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_hash_code>:
  endbr64
  mov    D0(%rip),%rax
  push   %r14
  push   %r13
  mov    $0xffffffff,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rax),%r12d
  mov    %rdi,%rbx
  lea    (%r12,%r12,2),%r14d
  shl    $0x2,%r12d
  shr    $0x3,%r12d
  and    $0x3fffffff,%r14d
  mov    %r12d,%ecx
  shr    %cl,%r13d
  call   <strlen@plt>
  test   %rax,%rax
  je     L16
  mov    %r13d,%ebp
  lea    (%rbx,%rax,1),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  not    %ebp
L13:
  movsbl (%rdi),%edx
  mov    %r12d,%ecx
  shl    %cl,%eax
  add    %edx,%eax
  mov    %ebp,%edx
  and    %eax,%edx
  je     L19
  mov    %r14d,%ecx
  shr    %cl,%edx
  xor    %edx,%eax
  and    %r13d,%eax
L19:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L16:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int get_hash_code(const char *s) {
  const unsigned int bits_in_uint = sizeof(unsigned int) * CHAR_BIT;
  const unsigned int three_quarters = (bits_in_uint * 3) / 4;
  const unsigned int one_eighth = bits_in_uint / 8;
  const unsigned int high_bits = ~((~0U) >> one_eighth);
  const size_t length = strlen(s);
  unsigned int hash = 0;
  for (size_t n = 0; n < length; n++) {
    hash = (hash << one_eighth) + (unsigned int)(s[n]);
    const unsigned int i = hash & high_bits;
    if (i != 0)
      hash = (hash ^ (i >> three_quarters)) & ~high_bits;
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L16:
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rcx
  movabs $0x8888888888888889,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0xe,-0x4(%rbp)
  jle    L16
  mov    -0x20(%rbp),%rax
  add    $0xf,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_string(src, des, off) const char *src;
char *des;
int off;
{
  int i;
  for (i = 0; i < (int)(20 - sizeof(int) - 1); i++)
    des[i] = src[(off + i) % (20 - sizeof(int) - 1)];
  des[20 - sizeof(int) - 1] = '\0';
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_string>:
  endbr64
  mov    %rsi,%r10
  movslq %edx,%rdx
  lea    0xf(%rdx),%r9
  mov    %rdx,%rcx
  movabs $0x8888888888888889,%r8
  sub    %rdx,%rsi
L7:
  mov    %rcx,%rax
  mul    %r8
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  movzbl (%rdi,%rdx,1),%eax
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L7
  movb   $0x0,0xf(%r10)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int get_string(src, des, off) const char *src;
char *des;
int off;
{
  int i;
  for (i = 0; i < (int)(20 - sizeof(int) - 1); i++)
    des[i] = src[(off + i) % (20 - sizeof(int) - 1)];
  des[20 - sizeof(int) - 1] = '\0';
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_string>:
  endbr64
  movabs $0x8888888888888889,%r8
  movslq %edx,%rcx
  mov    %rsi,%r9
  lea    0xf(%rcx),%r10
  sub    %rcx,%rsi
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rcx,%rax
  mul    %r8
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  movzbl (%rdi,%rdx,1),%eax
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    %r10,%rcx
  jne    L4
  movb   $0x0,0xf(%r9)
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_string(src, des, off) const char *src;
char *des;
int off;
{
  int i;
  for (i = 0; i < (int)(20 - sizeof(int) - 1); i++)
    des[i] = src[(off + i) % (20 - sizeof(int) - 1)];
  des[20 - sizeof(int) - 1] = '\0';
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RSA2048_load_pubkey_E>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%ecx
  lea    D4(%rip),%rsi
  mov    %eax,%edi
  call   <RSA2048_load@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L15
  mov    $0x1,%eax
  jmp    L13
L15:
  mov    $0x0,%eax
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string

tool: D4: BF51000004

assistant: ```c
int RSA2048_load_pubkey_E(int fd, unsigned char *RSA2048_E) {
  int ret;
  ret = RSA2048_load(fd, "BF51000004", RSA2048_E, 4);
  if (ret != 0)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RSA2048_load_pubkey_E>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    $0x4,%ecx
  lea    D9(%rip),%rsi
  call   <RSA2048_load@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type: string

tool: D9: BF51000004

assistant: ```c
int RSA2048_load_pubkey_E(int fd, unsigned char *RSA2048_E) {
  int ret;
  ret = RSA2048_load(fd, "BF51000004", RSA2048_E, 4);
  if (ret != 0)
    return 1;
  return 0;
}
```