ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<emovo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rbx
  mov    -0x30(%rbp),%rax
  lea    0xa(%rax),%r12
  mov    %rbx,%rax
  lea    0x2(%rax),%rbx
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  cmpw   $0x0,-0x12(%rbp)
  je     L68
  mov    %rbx,%rax
  lea    0x2(%rax),%rbx
  movzwl (%rax),%edx
  mov    %r12,%rax
  lea    -0x2(%rax),%r12
  or     $0x8000,%dx
  mov    %dx,(%rax)
  jmp    L15
L68:
  mov    %rbx,%rdx
  lea    0x2(%rdx),%rbx
  mov    %r12,%rax
  lea    -0x2(%rax),%r12
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
L15:
  lea    -0x2(%rbx),%rax
  movzwl (%rax),%eax
  cmp    $0x7fff,%ax
  jne    L17
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <eiisnan@plt>
  test   %eax,%eax
  je     L23
  mov    -0x30(%rbp),%rax
  mov    $0x50,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <enan@plt>
  jmp    L75
L23:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <einfin@plt>
  jmp    L75
L17:
  add    $0x2,%rbx
  movw   $0x0,-0x12(%rbp)
  jmp    L19
L27:
  mov    %rbx,%rdx
  lea    0x2(%rdx),%rbx
  mov    %r12,%rax
  lea    -0x2(%rax),%r12
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
  movzwl -0x12(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x12(%rbp)
L19:
  cmpw   $0x4,-0x12(%rbp)
  jbe    L27
L75:
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void emovo(a, b) unsigned short *a, *b;
{
  register unsigned short *p, *q;
  unsigned short i;
  p = a;
  q = b + (6 - 1);
  i = *p++;
  if (i)
    *q-- = *p++ | 0x8000;
  else
    *q-- = *p++;
  if (*(p - 1) == 0x7fff) {
    if (eiisnan(a)) {
      enan(b, (((6 + 3) - 4) * 16));
      return;
    }
    einfin(b);
    return;
  }
  ++p;
  for (i = 0; i < 6 - 1; i++)
    *q-- = *p++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emovo>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmpw   $0x0,(%rdi)
  je     L68
  lea    0x4(%rdi),%rcx
  lea    0x8(%rsi),%rdx
  movzwl 0x2(%rdi),%eax
  or     $0x8000,%ax
L40:
  mov    %ax,0xa(%rbx)
  lea    0x2(%rcx),%rax
  lea    0xc(%rcx),%rsi
  cmpw   $0x7fff,-0x2(%rcx)
  je     L37
L26:
  add    $0x2,%rax
  sub    $0x2,%rdx
  movzwl -0x2(%rax),%ecx
  mov    %cx,0x2(%rdx)
  cmp    %rax,%rsi
  jne    L26
L46:
  pop    %rbx
  ret
L68:
  lea    0x4(%rdi),%rcx
  lea    0x8(%rsi),%rdx
  movzwl 0x2(%rdi),%eax
  jmp    L40
L37:
  mov    $0x0,%eax
  call   <eiisnan@plt>
  test   %eax,%eax
  je     L67
  mov    $0x50,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <enan@plt>
  jmp    L46
L67:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <einfin@plt>
  jmp    L46
```

assistant: ```c
void emovo(a, b) unsigned short *a, *b;
{
  register unsigned short *p, *q;
  unsigned short i;
  p = a;
  q = b + (6 - 1);
  i = *p++;
  if (i)
    *q-- = *p++ | 0x8000;
  else
    *q-- = *p++;
  if (*(p - 1) == 0x7fff) {
    if (eiisnan(a)) {
      enan(b, (((6 + 3) - 4) * 16));
      return;
    }
    einfin(b);
    return;
  }
  ++p;
  for (i = 0; i < 6 - 1; i++)
    *q-- = *p++;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<emovo>:
  endbr64
  movzwl 0x2(%rdi),%eax
  mov    %eax,%ecx
  or     $0x8000,%cx
  cmpw   $0x0,(%rdi)
  cmovne %ecx,%eax
  mov    %ax,0xa(%rsi)
  cmpw   $0x7fff,0x2(%rdi)
  je     L29
  lea    0x8(%rsi),%rdx
  lea    0x6(%rdi),%rax
  lea    0x10(%rdi),%rsi
L15:
  movzwl (%rax),%ecx
  add    $0x2,%rax
  sub    $0x2,%rdx
  mov    %cx,0x2(%rdx)
  cmp    %rax,%rsi
  jne    L15
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  call   <eiisnan@plt>
  test   %eax,%eax
  je     L9
  mov    %rbp,%rdi
  mov    $0x50,%esi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <enan@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <einfin@plt>
```

assistant: ```c
void emovo(a, b) unsigned short *a, *b;
{
  register unsigned short *p, *q;
  unsigned short i;
  p = a;
  q = b + (6 - 1);
  i = *p++;
  if (i)
    *q-- = *p++ | 0x8000;
  else
    *q-- = *p++;
  if (*(p - 1) == 0x7fff) {
    if (eiisnan(a)) {
      enan(b, (((6 + 3) - 4) * 16));
      return;
    }
    einfin(b);
    return;
  }
  ++p;
  for (i = 0; i < 6 - 1; i++)
    *q-- = *p++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<emovo>:
  endbr64
  push   %rbp
  movzwl 0x2(%rdi),%eax
  mov    %rsi,%rbp
  mov    %eax,%edx
  or     $0x8000,%dx
  cmpw   $0x0,(%rdi)
  cmovne %edx,%eax
  mov    %ax,0xa(%rsi)
  cmpw   $0x7fff,0x2(%rdi)
  je     L39
  lea    0x4(%rdi),%rsi
  lea    0x8(%rbp),%rcx
  cmp    %rcx,%rsi
  jae    L14
  lea    0x10(%rdi),%rax
  cmp    %rax,%rbp
  jb     L33
L14:
  movq   0x6(%rdi),%xmm0
  pshuflw $0x1b,%xmm0,%xmm0
  movq   %xmm0,0x2(%rbp)
  movzwl 0xe(%rdi),%eax
  mov    %ax,0x0(%rbp)
  pop    %rbp
  ret
  nopl   (%rax)
L39:
  xor    %eax,%eax
  call   <eiisnan@plt>
  test   %eax,%eax
  je     L36
  mov    %rbp,%rdi
  mov    $0x50,%esi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <enan@plt>
  nopl   0x0(%rax,%rax,1)
L33:
  movzwl 0x6(%rdi),%eax
  mov    %ax,0x8(%rbp)
  movzwl 0x8(%rdi),%eax
  mov    %ax,0x6(%rbp)
  movzwl 0xa(%rdi),%eax
  mov    %ax,0x4(%rbp)
  movzwl 0xc(%rdi),%eax
  mov    %ax,0x2(%rbp)
  movzwl 0xe(%rdi),%eax
  mov    %ax,0x0(%rbp)
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <einfin@plt>
```

assistant: ```c
void emovo(a, b) unsigned short *a, *b;
{
  register unsigned short *p, *q;
  unsigned short i;
  p = a;
  q = b + (6 - 1);
  i = *p++;
  if (i)
    *q-- = *p++ | 0x8000;
  else
    *q-- = *p++;
  if (*(p - 1) == 0x7fff) {
    if (eiisnan(a)) {
      enan(b, (((6 + 3) - 4) * 16));
      return;
    }
    einfin(b);
    return;
  }
  ++p;
  for (i = 0; i < 6 - 1; i++)
    *q-- = *p++;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,-0x70(%rbp)
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movzbl -0x58(%rbp),%eax
  cmp    $0x50,%al
  jne    L19
  mov    -0x70(%rbp),%rax
  movb   $0x5,(%rax)
L19:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: r

assistant: ```c
int main(int argc, char **argv) {
  char buf[80], *p = malloc(128);
  FILE *f = fopen(argv[1], "r");
  fgets(buf, sizeof buf, f);
  free(p);
  if (buf[8] == 'P')
    *p = 5;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    0x8(%rbp),%rdi
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdx
  mov    %rsp,%rdi
  mov    $0x50,%esi
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  cmpb   $0x50,0x8(%rsp)
  je     L25
L4:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  movb   $0x5,(%rbx)
  jmp    L4
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: r

assistant: ```c
int main(int argc, char **argv) {
  char buf[80], *p = malloc(128);
  FILE *f = fopen(argv[1], "r");
  fgets(buf, sizeof buf, f);
  free(p);
  if (buf[8] == 'P')
    *p = 5;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x80,%edi
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    0x8(%rbp),%rdi
  lea    D5(%rip),%rsi
  mov    %rax,%rbx
  call   <fopen@plt>
  mov    %rsp,%rdi
  mov    $0x50,%esi
  mov    %rax,%rdx
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  cmpb   $0x50,0x8(%rsp)
  jne    L9
  movb   $0x5,(%rbx)
L9:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D5: r

assistant: ```c
int main(int argc, char **argv) {
  char buf[80], *p = malloc(128);
  FILE *f = fopen(argv[1], "r");
  fgets(buf, sizeof buf, f);
  free(p);
  if (buf[8] == 'P')
    *p = 5;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x80,%edi
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    0x8(%rbp),%rdi
  lea    D5(%rip),%rsi
  mov    %rax,%rbx
  call   <fopen@plt>
  mov    %rsp,%rdi
  mov    $0x50,%esi
  mov    %rax,%rdx
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  cmpb   $0x50,0x8(%rsp)
  jne    L18
  movb   $0x5,(%rbx)
L18:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: r

assistant: ```c
int main(int argc, char **argv) {
  char buf[80], *p = malloc(128);
  FILE *f = fopen(argv[1], "r");
  fgets(buf, sizeof buf, f);
  free(p);
  if (buf[8] == 'P')
    *p = 5;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string

tool: D18: %j123

tool: D15: ret:%d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  ret = printf("%j123");
  printf("ret"
         ":%d\n",
         (ret));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_infered: string
name: unpack_data
arguments: tag: D16
type_infered: string

tool: D19: %j123

tool: D16: ret:%d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  ret = printf("%j123");
  printf("ret"
         ":%d\n",
         (ret));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D18
type_infered: string

tool: D7: %j123

tool: D18: ret:%d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  ret = printf("%j123");
  printf("ret"
         ":%d\n",
         (ret));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string
name: parse_data
arguments: label: D10
data_type: string

tool: D6: %j123

tool: D10: ret:%d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  ret = printf("%j123");
  printf("ret"
         ":%d\n",
         (ret));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AutoCorr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L32
L21:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L21
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x2c(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L15
L5:
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x8(%rbp),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L5
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double AutoCorr(double *x, int n, int delay) {
  int i, k;
  double sum = 0, mean = 0;
  for (i = 0; i < n; i++)
    mean += x[i];
  mean /= n;
  for (i = 0; i < n; i++) {
    k = (i + delay) % n;
    sum += (x[i] - mean) * (x[k] - mean);
  }
  return (sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<AutoCorr>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L2
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm1,%xmm1
L18:
  addsd  (%rax),%xmm1
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L18
  pxor   %xmm2,%xmm2
  cvtsi2sd %esi,%xmm2
  divsd  %xmm2,%xmm1
  mov    %esi,%r9d
  mov    $0x0,%ecx
  pxor   %xmm3,%xmm3
L19:
  lea    (%r8,%rcx,1),%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  (%rdi,%rcx,8),%xmm2
  subsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm3
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L19
L21:
  movapd %xmm3,%xmm0
  ret
L2:
  pxor   %xmm3,%xmm3
  jmp    L21
```

assistant: ```c
double AutoCorr(double *x, int n, int delay) {
  int i, k;
  double sum = 0, mean = 0;
  for (i = 0; i < n; i++)
    mean += x[i];
  mean /= n;
  for (i = 0; i < n; i++) {
    k = (i + delay) % n;
    sum += (x[i] - mean) * (x[k] - mean);
  }
  return (sum);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AutoCorr>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L24
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  pxor   %xmm1,%xmm1
  lea    0x8(%rdi,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L10:
  addsd  (%rax),%xmm1
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L10
  pxor   %xmm2,%xmm2
  mov    %esi,%r9d
  pxor   %xmm3,%xmm3
  xor    %ecx,%ecx
  cvtsi2sd %esi,%xmm2
  divsd  %xmm2,%xmm1
  nopw   0x0(%rax,%rax,1)
L8:
  lea    (%r8,%rcx,1),%eax
  movsd  (%rdi,%rcx,8),%xmm2
  add    $0x1,%rcx
  cltd
  idiv   %esi
  subsd  %xmm1,%xmm2
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm3
  cmp    %rcx,%r9
  jne    L8
  movapd %xmm3,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  ret
```

assistant: ```c
double AutoCorr(double *x, int n, int delay) {
  int i, k;
  double sum = 0, mean = 0;
  for (i = 0; i < n; i++)
    mean += x[i];
  mean /= n;
  for (i = 0; i < n; i++) {
    k = (i + delay) % n;
    sum += (x[i] - mean) * (x[k] - mean);
  }
  return (sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<AutoCorr>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L12
  cmp    $0x1,%esi
  je     L33
  mov    %esi,%edx
  pxor   %xmm0,%xmm0
  mov    %rdi,%rax
  shr    %edx
  movapd %xmm0,%xmm1
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L57:
  movsd  (%rax),%xmm2
  add    $0x10,%rax
  addsd  %xmm2,%xmm1
  movsd  -0x8(%rax),%xmm2
  addsd  %xmm2,%xmm1
  cmp    %rax,%rdx
  jne    L57
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%sil
  je     L21
L10:
  cltq
  addsd  (%rdi,%rax,8),%xmm1
L21:
  pxor   %xmm2,%xmm2
  movslq %esi,%r9
  xor    %ecx,%ecx
  cvtsi2sd %esi,%xmm2
  divsd  %xmm2,%xmm1
  nopl   (%rax)
L3:
  lea    (%r8,%rcx,1),%eax
  movsd  (%rdi,%rcx,8),%xmm3
  add    $0x1,%rcx
  cltd
  idiv   %esi
  subsd  %xmm1,%xmm3
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm2
  subsd  %xmm1,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %r9,%rcx
  jne    L3
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  pxor   %xmm0,%xmm0
  ret
L33:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  movapd %xmm0,%xmm1
  jmp    L10
```

assistant: ```c
double AutoCorr(double *x, int n, int delay) {
  int i, k;
  double sum = 0, mean = 0;
  for (i = 0; i < n; i++)
    mean += x[i];
  mean /= n;
  for (i = 0; i < n; i++) {
    k = (i + delay) % n;
    sum += (x[i] - mean) * (x[k] - mean);
  }
  return (sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__SubStrings__LP__WhitespaceJump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
  jmp    L151
L117:
  add    $0x1,%rbx
L151:
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L150
  movzbl (%rbx),%eax
  cmp    $0x9,%al
  je     L150
  movzbl (%rbx),%eax
  cmp    $0xd,%al
  je     L150
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L150
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L117
L150:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L74
  movzbl (%rbx),%eax
  cmp    $0xd,%al
  je     L74
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  jne    L5
L74:
  mov    $0x0,%eax
  jmp    L142
L21:
  add    $0x1,%rbx
L5:
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L21
  movzbl (%rbx),%eax
  cmp    $0x9,%al
  je     L21
  movzbl (%rbx),%eax
  test   %al,%al
  je     L8
  movzbl (%rbx),%eax
  cmp    $0xd,%al
  je     L8
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  jne    L129
L8:
  mov    $0x0,%eax
  jmp    L142
L129:
  mov    %rbx,%rax
L142:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *__SubStrings__LP__WhitespaceJump(const char *InStream) {
  register const char *Worker = InStream;
  while (*Worker != ' ' && *Worker != '\t' && *Worker != '\r' && *Worker != '\n' && *Worker != '\0')
    ++Worker;
  if (*Worker == '\0' || *Worker == '\r' || *Worker == '\n')
    return ((void *)0);
  while (*Worker == ' ' || *Worker == '\t')
    ++Worker;
  if (*Worker == '\0' || *Worker == '\r' || *Worker == '\n')
    return ((void *)0);
  return (char *)Worker;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__SubStrings__LP__WhitespaceJump>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  ja     L54
  mov    %rdi,%rax
  movabs $0x100002601,%rcx
  bt     %rdx,%rcx
  jb     L34
L54:
  mov    %rdi,%rax
  movabs $0x100002601,%rcx
L49:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  ja     L49
  bt     %rdx,%rcx
  jae    L49
L34:
  cmp    $0xd,%dl
  ja     L21
  mov    $0x2401,%ecx
  bt     %rdx,%rcx
  jb     L7
L21:
  movzbl (%rax),%ecx
  cmp    $0x20,%cl
  je     L62
  cmp    $0x9,%cl
  jne    L95
L62:
  add    $0x1,%rax
  movzbl (%rax),%ecx
  cmp    $0x20,%cl
  je     L62
  cmp    $0x9,%cl
  je     L62
L95:
  cmp    $0xd,%cl
  ja     L104
  mov    $0x2401,%edx
  shr    %cl,%rdx
  test   $0x1,%dl
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
L7:
  mov    $0x0,%eax
L104:
  ret
```

assistant: ```c
char *__SubStrings__LP__WhitespaceJump(const char *InStream) {
  register const char *Worker = InStream;
  while (*Worker != ' ' && *Worker != '\t' && *Worker != '\r' && *Worker != '\n' && *Worker != '\0')
    ++Worker;
  if (*Worker == '\0' || *Worker == '\r' || *Worker == '\n')
    return ((void *)0);
  while (*Worker == ' ' || *Worker == '\t')
    ++Worker;
  if (*Worker == '\0' || *Worker == '\r' || *Worker == '\n')
    return ((void *)0);
  return (char *)Worker;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__SubStrings__LP__WhitespaceJump>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L65
  cmp    $0x9,%al
  je     L65
  mov    $0xffffffffffffdbfe,%rdx
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L148:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  je     L65
  cmp    $0x9,%al
  je     L65
L28:
  cmp    $0xd,%al
  ja     L148
  bt     %rax,%rdx
  jb     L148
L99:
  xor    %r8d,%r8d
L77:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L65:
  mov    %rdi,%r8
  cmp    $0xd,%al
  jbe    L32
L43:
  movzbl (%rdi),%ecx
  cmp    $0x9,%cl
  je     L70
  cmp    $0x20,%cl
  jne    L46
  nopl   0x0(%rax)
L70:
  movzbl 0x1(%r8),%ecx
  add    $0x1,%r8
  cmp    $0x20,%cl
  je     L70
  cmp    $0x9,%cl
  je     L70
L46:
  cmp    $0xd,%cl
  ja     L77
  mov    $0xffffffffffffdbfe,%rax
  sar    %cl,%rax
  test   $0x1,%al
  mov    $0x0,%eax
  cmove  %rax,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L32:
  mov    $0xffffffffffffdbfe,%rdx
  bt     %rax,%rdx
  jb     L43
  jmp    L99
```

assistant: ```c
char *__SubStrings__LP__WhitespaceJump(const char *InStream) {
  register const char *Worker = InStream;
  while (*Worker != ' ' && *Worker != '\t' && *Worker != '\r' && *Worker != '\n' && *Worker != '\0')
    ++Worker;
  if (*Worker == '\0' || *Worker == '\r' || *Worker == '\n')
    return ((void *)0);
  while (*Worker == ' ' || *Worker == '\t')
    ++Worker;
  if (*Worker == '\0' || *Worker == '\r' || *Worker == '\n')
    return ((void *)0);
  return (char *)Worker;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__SubStrings__LP__WhitespaceJump>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L25
  cmp    $0x9,%dl
  je     L25
  mov    $0xffffffffffffdbfe,%rax
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L90:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  cmp    $0x20,%dl
  je     L25
  cmp    $0x9,%dl
  je     L25
L12:
  cmp    $0xd,%dl
  ja     L90
  bt     %rdx,%rax
  jb     L90
L124:
  xor    %eax,%eax
  ret
L25:
  cmp    $0xd,%dl
  jbe    L140
  cmp    $0x20,%dl
  jne    L119
L38:
  mov    %rdi,%rax
  nopl   (%rax)
L37:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  cmp    $0x20,%cl
  je     L37
  cmp    $0x9,%cl
  je     L37
  cmp    $0xd,%cl
  ja     L97
L29:
  mov    $0xffffffffffffdbfe,%rdx
  sar    %cl,%rdx
  and    $0x1,%edx
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
  xchg   %ax,%ax
L140:
  mov    $0xffffffffffffdbfe,%rax
  bt     %rdx,%rax
  jae    L124
  cmp    $0x9,%dl
  je     L38
  mov    %edx,%ecx
  mov    %rdi,%rax
  jmp    L29
  nopl   0x0(%rax)
L97:
  ret
L119:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *__SubStrings__LP__WhitespaceJump(const char *InStream) {
  register const char *Worker = InStream;
  while (*Worker != ' ' && *Worker != '\t' && *Worker != '\r' && *Worker != '\n' && *Worker != '\0')
    ++Worker;
  if (*Worker == '\0' || *Worker == '\r' || *Worker == '\n')
    return ((void *)0);
  while (*Worker == ' ' || *Worker == '\t')
    ++Worker;
  if (*Worker == '\0' || *Worker == '\r' || *Worker == '\n')
    return ((void *)0);
  return (char *)Worker;
}
```