ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D75(%rip),%rax
  mov    %rax,-0x60(%rbp)
  lea    D79(%rip),%rax
  mov    %rax,-0x58(%rbp)
  lea    D64(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D102(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D70(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D68(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D107(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x78(%rbp)
  jmp    L10
L21:
  mov    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x70(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <str_trim@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L10:
  mov    -0x78(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x78(%rbp)
  mov    -0x60(%rbp,%rax,8),%rax
  mov    %rax,-0x70(%rbp)
  cmpq   $0x0,-0x70(%rbp)
  jne    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D75
type: string
name: read_data
arguments: data_label: D79
type: string
name: read_data
arguments: data_label: D64
type: string
name: read_data
arguments: data_label: D102
type: string
name: read_data
arguments: data_label: D35
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D6
type: string
name: read_data
arguments: data_label: D70
type: string
name: read_data
arguments: data_label: D68
type: string
name: read_data
arguments: data_label: D107
type: string
name: read_data
arguments: data_label: D18
type: string

tool: 

tool: D79:     

tool: D64:   a

tool: D102:  a 

tool: D35: a  

tool: D23: abc

tool: D6:    ab c

tool: D70: a bc   

tool: D68:     a  b c    

tool: D107:        a b   c        d   e     fgh    

tool: D18: [%s]


assistant: ```c
int main(void) {
  char *strs[] = {"", "    ", "  a", " a ", "a  ", "abc", "   ab c", "a bc   ", "    a  b c    ", "       a b   c        d   e     fgh    ", NULL};
  char *str;
  char *new_str;
  size_t i = 0UL;
  while ((str = strs[i++])) {
    new_str = str_trim(str, strlen(str), NULL);
    printf("[%s]\n", new_str);
    free(new_str);
  };
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rbx
  mov    %rbx,(%rsp)
  lea    D37(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D66(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D25(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D14(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D58(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D17(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D12(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D4(%rip),%rax
  mov    %rax,0x40(%rsp)
  lea    D53(%rip),%rax
  mov    %rax,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  lea    0x8(%rsp),%rbp
  lea    D64(%rip),%r12
L15:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <str_trim@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rbp
  mov    -0x8(%rbp),%rbx
  test   %rbx,%rbx
  jne    L15
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string
name: disassemble_data
arguments: data_tag: D37
type_guessed: string
name: disassemble_data
arguments: data_tag: D66
type_guessed: string
name: disassemble_data
arguments: data_tag: D25
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D58
type_guessed: string
name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D12
type_guessed: string
name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D53
type_guessed: string
name: disassemble_data
arguments: data_tag: D64
type_guessed: string

tool: 

tool: D37:     

tool: D66:   a

tool: D25:  a 

tool: D14: a  

tool: D58: abc

tool: D17:    ab c

tool: D12: a bc   

tool: D4:     a  b c    

tool: D53:        a b   c        d   e     fgh    

tool: D64: [%s]


assistant: ```c
int main(void) {
  char *strs[] = {"", "    ", "  a", " a ", "a  ", "abc", "   ab c", "a bc   ", "    a  b c    ", "       a b   c        d   e     fgh    ", NULL};
  char *str;
  char *new_str;
  size_t i = 0UL;
  while ((str = strs[i++])) {
    new_str = str_trim(str, strlen(str), NULL);
    printf("[%s]\n", new_str);
    free(new_str);
  };
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D72(%rip),%rbp
  push   %rbx
  lea    D100(%rip),%rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  lea    D29(%rip),%rax
  lea    0x8(%rsp),%r12
  movq   $0x0,0x50(%rsp)
  mov    %rax,0x8(%rsp)
  lea    D97(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D8(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D68(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D35(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D20(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D43(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D31(%rip),%rax
  mov    %rax,0x40(%rsp)
  lea    D108(%rip),%rax
  mov    %rax,0x48(%rsp)
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  add    $0x8,%r12
  call   <strlen@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <str_trim@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    -0x8(%r12),%rbp
  test   %rbp,%rbp
  jne    L18
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D72
type_infered: string
name: extract_symbolic_data
arguments: data_label: D100
type_infered: string
name: extract_symbolic_data
arguments: data_label: D29
type_infered: string
name: extract_symbolic_data
arguments: data_label: D97
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string
name: extract_symbolic_data
arguments: data_label: D68
type_infered: string
name: extract_symbolic_data
arguments: data_label: D35
type_infered: string
name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D43
type_infered: string
name: extract_symbolic_data
arguments: data_label: D31
type_infered: string
name: extract_symbolic_data
arguments: data_label: D108
type_infered: string

tool: 

tool: D100: [%s]


tool: D29:     

tool: D97:   a

tool: D8:  a 

tool: D68: a  

tool: D35: abc

tool: D20:    ab c

tool: D43: a bc   

tool: D31:     a  b c    

tool: D108:        a b   c        d   e     fgh    

assistant: ```c
int main(void) {
  char *strs[] = {"", "    ", "  a", " a ", "a  ", "abc", "   ab c", "a bc   ", "    a  b c    ", "       a b   c        d   e     fgh    ", NULL};
  char *str;
  char *new_str;
  size_t i = 0UL;
  while ((str = strs[i++])) {
    new_str = str_trim(str, strlen(str), NULL);
    printf("[%s]\n", new_str);
    free(new_str);
  };
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D107(%rip),%rcx
  push   %rbp
  movq   %rcx,%xmm0
  lea    D109(%rip),%rcx
  lea    D88(%rip),%rbp
  push   %rbx
  lea    D56(%rip),%rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  lea    D38(%rip),%rax
  lea    0x8(%rsp),%r12
  movq   $0x0,0x50(%rsp)
  movq   %rax,%xmm1
  lea    D42(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  lea    D99(%rip),%rax
  movups %xmm0,0x8(%rsp)
  movq   %rcx,%xmm0
  movq   %rax,%xmm3
  lea    D75(%rip),%rcx
  punpcklqdq %xmm2,%xmm0
  lea    D94(%rip),%rax
  movups %xmm0,0x18(%rsp)
  movq   %rcx,%xmm0
  movq   %rax,%xmm4
  lea    D77(%rip),%rcx
  punpcklqdq %xmm3,%xmm0
  lea    D103(%rip),%rax
  movups %xmm0,0x28(%rsp)
  movq   %rcx,%xmm0
  mov    %rax,0x48(%rsp)
  punpcklqdq %xmm4,%xmm0
  movups %xmm0,0x38(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  add    $0x8,%r12
  call   <strlen@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <str_trim@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    -0x8(%r12),%rbp
  test   %rbp,%rbp
  jne    L3
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D107
type_guessed: string
name: unpack_data
arguments: label: D109
type_guessed: string
name: unpack_data
arguments: label: D88
type_guessed: string
name: unpack_data
arguments: label: D56
type_guessed: string
name: unpack_data
arguments: label: D38
type_guessed: string
name: unpack_data
arguments: label: D42
type_guessed: string
name: unpack_data
arguments: label: D99
type_guessed: string
name: unpack_data
arguments: label: D75
type_guessed: string
name: unpack_data
arguments: label: D94
type_guessed: string
name: unpack_data
arguments: label: D77
type_guessed: string
name: unpack_data
arguments: label: D103
type_guessed: string

tool: D107:     

tool: D109:  a 

tool: 

tool: D56: [%s]


tool: D38:   a

tool: D42: a  

tool: D99:    ab c

tool: D75: abc

tool: D94:     a  b c    

tool: D77: a bc   

tool: D103:        a b   c        d   e     fgh    

assistant: ```c
int main(void) {
  char *strs[] = {"", "    ", "  a", " a ", "a  ", "abc", "   ab c", "a bc   ", "    a  b c    ", "       a b   c        d   e     fgh    ", NULL};
  char *str;
  char *new_str;
  size_t i = 0UL;
  while ((str = strs[i++])) {
    new_str = str_trim(str, strlen(str), NULL);
    printf("[%s]\n", new_str);
    free(new_str);
  };
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isSupported>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  jne    L17
  mov    $0x1,%eax
  jmp    L6
L17:
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: PALETTE

assistant: ```c
int isSupported(char *type) {
  if (!strcasecmp(type, "PALETTE"))
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isSupported>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: PALETTE

assistant: ```c
int isSupported(char *type) {
  if (!strcasecmp(type, "PALETTE"))
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isSupported>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: PALETTE

assistant: ```c
int isSupported(char *type) {
  if (!strcasecmp(type, "PALETTE"))
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isSupported>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: PALETTE

assistant: ```c
int isSupported(char *type) {
  if (!strcasecmp(type, "PALETTE"))
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  sar    $0x3,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f1(int n, int x[], int y[]) {
  int i;
  for (i = 0; i < n; ++i)
    y[i] = x[i] >> 3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f1>:
  endbr64
  test   %edi,%edi
  jle    L7
  mov    %edi,%edi
  mov    $0x0,%eax
L9:
  mov    (%rsi,%rax,4),%ecx
  sar    $0x3,%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L9
L7:
  ret
```

assistant: ```c
void f1(int n, int x[], int y[]) {
  int i;
  for (i = 0; i < n; ++i)
    y[i] = x[i] >> 3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f1>:
  endbr64
  test   %edi,%edi
  jle    L8
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L5:
  mov    (%rsi,%rax,4),%ecx
  sar    $0x3,%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L5
L8:
  ret
```

assistant: ```c
void f1(int n, int x[], int y[]) {
  int i;
  for (i = 0; i < n; ++i)
    y[i] = x[i] >> 3;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f1>:
  endbr64
  mov    %edi,%r10d
  mov    %rsi,%rcx
  test   %edi,%edi
  jle    L57
  lea    0x4(%rsi),%rsi
  mov    %rdx,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L72
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L72
  shr    $0x2,%edi
  xor    %eax,%eax
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L13:
  movdqu (%rcx,%rax,1),%xmm0
  psrad  $0x3,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L13
  mov    %r10d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r10b
  je     L57
  mov    %eax,%r8d
  lea    0x1(%rax),%esi
  mov    (%rcx,%r8,4),%r9d
  lea    0x0(,%r8,4),%rdi
  sar    $0x3,%r9d
  mov    %r9d,(%rdx,%r8,4)
  cmp    %esi,%r10d
  jle    L57
  mov    0x4(%rcx,%rdi,1),%esi
  add    $0x2,%eax
  sar    $0x3,%esi
  mov    %esi,0x4(%rdx,%rdi,1)
  cmp    %eax,%r10d
  jle    L57
  mov    0x8(%rcx,%rdi,1),%eax
  sar    $0x3,%eax
  mov    %eax,0x8(%rdx,%rdi,1)
  ret
  nopl   0x0(%rax)
L72:
  mov    %r10d,%esi
  xor    %eax,%eax
  nopl   (%rax)
L3:
  mov    (%rcx,%rax,4),%edi
  sar    $0x3,%edi
  mov    %edi,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L3
L57:
  ret
```

assistant: ```c
void f1(int n, int x[], int y[]) {
  int i;
  for (i = 0; i < n; ++i)
    y[i] = x[i] >> 3;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int snprintf(char *output_buf, size_t max_char, const char *format, ...) {
  va_list args;
  va_start(args, format);
  int parsed_chars = vsnprintf(output_buf, max_char, format, args);
  va_end(args);
  return parsed_chars;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int snprintf(char *output_buf, size_t max_char, const char *format, ...) {
  va_list args;
  va_start(args, format);
  int parsed_chars = vsnprintf(output_buf, max_char, format, args);
  va_end(args);
  return parsed_chars;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int snprintf(char *output_buf, size_t max_char, const char *format, ...) {
  va_list args;
  va_start(args, format);
  int parsed_chars = vsnprintf(output_buf, max_char, format, args);
  va_end(args);
  return parsed_chars;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int snprintf(char *output_buf, size_t max_char, const char *format, ...) {
  va_list args;
  va_start(args, format);
  int parsed_chars = vsnprintf(output_buf, max_char, format, args);
  va_end(args);
  return parsed_chars;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<h1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void h1(float *c, float *a, double b[], int size) {
  int t = 0;
#pragma omp simd safelen(16) linear(t) aligned(c : 32) aligned(a, b)
  for (int i = 0; i < size; ++i) {
    c[i] = a[i] * a[i] + b[i] * b[t];
    ++t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<h1>:
  endbr64
  test   %ecx,%ecx
  jle    L9
  mov    %ecx,%ecx
  mov    $0x0,%eax
L6:
  movss  (%rsi,%rax,4),%xmm0
  movsd  (%rdx,%rax,8),%xmm1
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
L9:
  ret
```

assistant: ```c
void h1(float *c, float *a, double b[], int size) {
  int t = 0;
#pragma omp simd safelen(16) linear(t) aligned(c : 32) aligned(a, b)
  for (int i = 0; i < size; ++i) {
    c[i] = a[i] * a[i] + b[i] * b[t];
    ++t;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<h1>:
  endbr64
  test   %ecx,%ecx
  jle    L13
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L5:
  movss  (%rsi,%rax,4),%xmm0
  movsd  (%rdx,%rax,8),%xmm1
  mulss  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L5
L13:
  ret
```

assistant: ```c
void h1(float *c, float *a, double b[], int size) {
  int t = 0;
#pragma omp simd safelen(16) linear(t) aligned(c : 32) aligned(a, b)
  for (int i = 0; i < size; ++i) {
    c[i] = a[i] * a[i] + b[i] * b[t];
    ++t;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<h1>:
  endbr64
  test   %ecx,%ecx
  jle    L41
  lea    0x4(%rsi),%r8
  mov    %rdi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L72
  lea    -0x1(%rcx),%eax
  cmp    $0x2,%eax
  jbe    L72
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    $0x2,%r8d
  shl    $0x4,%r8
  nopl   0x0(%rax)
L24:
  movups (%rsi,%rax,1),%xmm1
  movupd (%rdx,%rax,2),%xmm2
  mulps  %xmm1,%xmm1
  mulpd  %xmm2,%xmm2
  cvtps2pd %xmm1,%xmm0
  movhlps %xmm1,%xmm3
  addpd  %xmm2,%xmm0
  movupd 0x10(%rdx,%rax,2),%xmm2
  cvtps2pd %xmm3,%xmm1
  mulpd  %xmm2,%xmm2
  cvtpd2ps %xmm0,%xmm0
  addpd  %xmm2,%xmm1
  cvtpd2ps %xmm1,%xmm1
  movlhps %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L24
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%cl
  je     L41
  mov    %eax,%r9d
  movss  (%rsi,%r9,4),%xmm0
  movsd  (%rdx,%r9,8),%xmm1
  lea    0x0(,%r9,4),%r8
  lea    0x0(,%r9,8),%r10
  mulss  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdi,%r9,4)
  lea    0x1(%rax),%r9d
  cmp    %r9d,%ecx
  jle    L41
  movss  0x4(%rsi,%r8,1),%xmm0
  movsd  0x8(%rdx,%r10,1),%xmm1
  add    $0x2,%eax
  mulss  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x4(%rdi,%r8,1)
  cmp    %eax,%ecx
  jle    L41
  movss  0x8(%rsi,%r8,1),%xmm0
  movsd  0x10(%rdx,%r10,1),%xmm1
  mulss  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x8(%rdi,%r8,1)
  ret
  nopl   0x0(%rax)
L72:
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L59:
  movss  (%rsi,%rax,4),%xmm0
  movsd  (%rdx,%rax,8),%xmm1
  mulss  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L59
L41:
  ret
```

assistant: ```c
void h1(float *c, float *a, double b[], int size) {
  int t = 0;
#pragma omp simd safelen(16) linear(t) aligned(c : 32) aligned(a, b)
  for (int i = 0; i < size; ++i) {
    c[i] = a[i] * a[i] + b[i] * b[t];
    ++t;
  }
}
```