ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<unrar_mkpath>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L75
  cmpb   $0x0,(%rdi)
  je     L75
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L75
  movzbl (%rax),%eax
  test   %al,%al
  je     L88
  mov    %rbp,%rbx
  xor    %r12d,%r12d
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L44
L41:
  cmp    $0x2f,%al
  jne    L25
  movb   $0x0,(%rbx)
  cmpb   $0x0,0x0(%rbp)
  jne    L119
L103:
  movb   $0x2f,(%rbx)
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L41
L44:
  mov    %rbp,%rdi
  call   <free@plt>
L55:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L119:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  mov    %eax,%r12d
  jmp    L103
  nopw   0x0(%rax,%rax,1)
L88:
  xor    %r12d,%r12d
  jmp    L44
L75:
  mov    $0xffffffff,%r12d
  jmp    L55
```

assistant: ```c
int unrar_mkpath(char *path) {
  char *path_tmp;
  int i, ret = 0;
  if (path == NULL || path[0] == '\0')
    return (-1);
  path_tmp = strdup(path);
  if (path_tmp == NULL)
    return (-1);
  for (i = 0; path_tmp[i] != '\0'; i++) {
    if (path_tmp[i] == '/') {
      path_tmp[i] = '\0';
      if (path_tmp[0] != '\0') {
        ret = mkdir(path_tmp, 0777);
      }
      path_tmp[i] = '/';
    }
  }
  free(path_tmp);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L45:
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jge    L23
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isgraph@plt>
  test   %eax,%eax
  je     L45
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L50
L0:
  subl   $0x1,-0xc(%rbp)
L50:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L33
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isgraph@plt>
  test   %eax,%eax
  je     L0
L33:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *Strip(char *strIn) {
  int iStart;
  int iEnd;
  char *strOut;
  for (iStart = 0; iStart < strlen(strIn) && !isgraph(strIn[iStart]); iStart++)
    ;
  for (iEnd = strlen(strIn); iEnd > iStart && !isgraph(strIn[iEnd]); iEnd--)
    ;
  strOut = malloc(iEnd - iStart + 2);
  memcpy(strOut, &strIn[iStart], iEnd - iStart + 1);
  strOut[iEnd - iStart + 1] = 0;
  free(strIn);
  return strOut;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Strip>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x0,%ebx
L40:
  mov    %ebx,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L13
  movsbl (%r12,%rbx,1),%edi
  call   <isgraph@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  je     L40
L13:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    %eax,%r13d
  jge    L31
  movslq %eax,%rbp
  add    %r12,%rbp
L8:
  movsbl 0x0(%rbp),%edi
  call   <isgraph@plt>
  test   %eax,%eax
  jne    L31
  sub    $0x1,%ebx
  sub    $0x1,%rbp
  cmp    %ebx,%r13d
  jne    L8
L31:
  sub    %r13d,%ebx
  lea    0x2(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x1(%rbx),%edx
  movslq %r13d,%rsi
  add    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x1(%rbp,%rbx,1)
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *Strip(char *strIn) {
  int iStart;
  int iEnd;
  char *strOut;
  for (iStart = 0; iStart < strlen(strIn) && !isgraph(strIn[iStart]); iStart++)
    ;
  for (iEnd = strlen(strIn); iEnd > iStart && !isgraph(strIn[iEnd]); iEnd--)
    ;
  strOut = malloc(iEnd - iStart + 2);
  memcpy(strOut, &strIn[iStart], iEnd - iStart + 1);
  strOut[iEnd - iStart + 1] = 0;
  free(strIn);
  return strOut;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Strip>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L25:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <isgraph@plt>
  test   %eax,%eax
  jne    L52
L59:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  lea    0x0(%rbp,%rbx,1),%r13
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L25
L52:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    %eax,%r12d
  jge    L31
  movslq %eax,%r14
  add    %rbp,%r14
  jmp    L11
  nopl   (%rax)
L41:
  sub    $0x1,%ebx
  sub    $0x1,%r14
  cmp    %ebx,%r12d
  je     L31
L11:
  movsbl (%r14),%edi
  call   <isgraph@plt>
  test   %eax,%eax
  je     L41
L31:
  sub    %r12d,%ebx
  lea    0x2(%rbx),%edi
  call   <malloc@plt>
  lea    0x1(%rbx),%edx
  mov    %r13,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *Strip(char *strIn) {
  int iStart;
  int iEnd;
  char *strOut;
  for (iStart = 0; iStart < strlen(strIn) && !isgraph(strIn[iStart]); iStart++)
    ;
  for (iEnd = strlen(strIn); iEnd > iStart && !isgraph(strIn[iEnd]); iEnd--)
    ;
  strOut = malloc(iEnd - iStart + 2);
  memcpy(strOut, &strIn[iStart], iEnd - iStart + 1);
  strOut[iEnd - iStart + 1] = 0;
  free(strIn);
  return strOut;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Strip>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <isgraph@plt>
  test   %eax,%eax
  jne    L47
L43:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  lea    0x0(%rbp,%rbx,1),%r13
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L2
L47:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    %eax,%r12d
  jge    L69
  movslq %eax,%r14
  add    %rbp,%r14
  jmp    L42
  nopl   (%rax)
L18:
  sub    $0x1,%ebx
  sub    $0x1,%r14
  cmp    %ebx,%r12d
  je     L69
L42:
  movsbl (%r14),%edi
  call   <isgraph@plt>
  test   %eax,%eax
  je     L18
L69:
  sub    %r12d,%ebx
  lea    0x2(%rbx),%edi
  call   <malloc@plt>
  lea    0x1(%rbx),%edx
  mov    %r13,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *Strip(char *strIn) {
  int iStart;
  int iEnd;
  char *strOut;
  for (iStart = 0; iStart < strlen(strIn) && !isgraph(strIn[iStart]); iStart++)
    ;
  for (iEnd = strlen(strIn); iEnd > iStart && !isgraph(strIn[iEnd]); iEnd--)
    ;
  strOut = malloc(iEnd - iStart + 2);
  memcpy(strOut, &strIn[iStart], iEnd - iStart + 1);
  strOut[iEnd - iStart + 1] = 0;
  free(strIn);
  return strOut;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x8(%rbp)
  jmp    L3
L6:
  movl   $0x5,-0x4(%rbp)
  jmp    L39
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0x8(%rbp)
L3:
  cmpl   $0x0,-0x8(%rbp)
  jg     L6
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string

tool: D8: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 5; i >= 1; i--) {
    for (j = 5; j >= i; j--) {
      printf("%d", j);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebp
  lea    D0(%rip),%r12
  jmp    L6
L15:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  cmp    %ebp,%ebx
  jge    L15
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  je     L27
L6:
  mov    $0x5,%ebx
  cmp    $0x5,%ebp
  jle    L15
  jmp    L0
L27:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 5; i >= 1; i--) {
    for (j = 5; j >= i; j--) {
      printf("%d", j);
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
L8:
  mov    $0x5,%ebx
L18:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L18
  mov    $0xa,%edi
  lea    -0x1(%rbx),%ebp
  call   <putchar@plt>
  test   %ebx,%ebx
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 5; i >= 1; i--) {
    for (j = 5; j >= i; j--) {
      printf("%d", j);
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
L8:
  mov    $0x5,%ebx
L16:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L16
  mov    $0xa,%edi
  lea    -0x1(%rbx),%ebp
  call   <putchar@plt>
  test   %ebx,%ebx
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 5; i >= 1; i--) {
    for (j = 5; j >= i; j--) {
      printf("%d", j);
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  call   <bad_mem@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xrealloc(void *buf, unsigned int size) {
  void *ret = realloc(buf, size);
  if (ret == NULL)
    bad_mem();
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrealloc>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L0:
  mov    %rbx,%rax
  pop    %rbx
  ret
L17:
  mov    $0x0,%eax
  call   <bad_mem@plt>
  jmp    L0
```

assistant: ```c
void *xrealloc(void *buf, unsigned int size) {
  void *ret = realloc(buf, size);
  if (ret == NULL)
    bad_mem();
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  call   <bad_mem@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *xrealloc(void *buf, unsigned int size) {
  void *ret = realloc(buf, size);
  if (ret == NULL)
    bad_mem();
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<xrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <bad_mem@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *xrealloc(void *buf, unsigned int size) {
  void *ret = realloc(buf, size);
  if (ret == NULL)
    bad_mem();
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<called_party_num_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %ecx,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x78(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  movzbl %al,%eax
  and    $0x1,%eax
  mov    %eax,-0x54(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x78(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  lea    D24(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  movzbl %al,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  lea    D38(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x7,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x70(%rbp),%eax
  lea    -0x2(%rax),%edi
  mov    -0x78(%rbp),%rax
  lea    0x2(%rax),%rsi
  mov    -0x54(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <isup_get_number@plt>
  lea    -0x50(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  lea    D37(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x70(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D38
type: string
name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D37
type: string

tool: D24: 			Nature of address: %x


tool: D38: 			NI: %x


tool: D7: 			Numbering plan: %x


tool: D37: 			Address signals: %s


assistant: ```c
int((called_party_num_dump))(struct ss7 *ss7, int messagetype, unsigned char *parm, int len) {
  int oddeven = (parm[0] >> 7) & 0x1;
  char numbuf[64] = "";
  ss7_message(ss7, "\t\t\tNature of address: %x\n", parm[0] & 0x7f);
  ss7_message(ss7, "\t\t\tNI: %x\n", (parm[1] >> 7) & 0x1);
  ss7_message(ss7, "\t\t\tNumbering plan: %x\n", (parm[1] >> 4) & 0x7);
  isup_get_number(numbuf, &parm[2], len - 2, oddeven);
  ss7_message(ss7, "\t\t\tAddress signals: %s\n", numbuf);
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<called_party_num_dump>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movzbl (%rdx),%r12d
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  mov    %r12d,%edx
  and    $0x7f,%edx
  lea    D21(%rip),%rsi
  call   <ss7_message@plt>
  movzbl 0x1(%rbx),%edx
  shr    $0x7,%dl
  movzbl %dl,%edx
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  movzbl 0x1(%rbx),%edx
  shr    $0x4,%dl
  and    $0x7,%edx
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  shr    $0x7,%r12b
  movzbl %r12b,%ecx
  lea    -0x2(%r13),%edx
  lea    0x2(%rbx),%rsi
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <isup_get_number@plt>
  mov    %rbx,%rdx
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %r13d,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
type: string
name: extract_symbolic_data
arguments: data_tag: D37
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string

tool: D21: 			Nature of address: %x


tool: D37: 			NI: %x


tool: D24: 			Numbering plan: %x


tool: D28: 			Address signals: %s


assistant: ```c
int((called_party_num_dump))(struct ss7 *ss7, int messagetype, unsigned char *parm, int len) {
  int oddeven = (parm[0] >> 7) & 0x1;
  char numbuf[64] = "";
  ss7_message(ss7, "\t\t\tNature of address: %x\n", parm[0] & 0x7f);
  ss7_message(ss7, "\t\t\tNI: %x\n", (parm[1] >> 7) & 0x1);
  ss7_message(ss7, "\t\t\tNumbering plan: %x\n", (parm[1] >> 4) & 0x7);
  isup_get_number(numbuf, &parm[2], len - 2, oddeven);
  ss7_message(ss7, "\t\t\tAddress signals: %s\n", numbuf);
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<called_party_num_dump>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rsi
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x58,%rsp
  movzbl (%rdx),%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %r12d,%edx
  movaps %xmm0,0x10(%rsp)
  shr    $0x7,%r12b
  and    $0x7f,%edx
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <ss7_message@plt>
  movzbl 0x1(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D34(%rip),%rsi
  shr    $0x7,%dl
  movzbl %dl,%edx
  call   <ss7_message@plt>
  movzbl 0x1(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D15(%rip),%rsi
  shr    $0x4,%dl
  and    $0x7,%edx
  call   <ss7_message@plt>
  movzbl %r12b,%ecx
  mov    %rsp,%r12
  lea    -0x2(%r13),%edx
  lea    0x2(%rbx),%rsi
  mov    %r12,%rdi
  call   <isup_get_number@plt>
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D22(%rip),%rsi
  call   <ss7_message@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x58,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D34
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D22
type_guessed: string

tool: D1: 			Nature of address: %x


tool: D34: 			NI: %x


tool: D15: 			Numbering plan: %x


tool: D22: 			Address signals: %s


assistant: ```c
int((called_party_num_dump))(struct ss7 *ss7, int messagetype, unsigned char *parm, int len) {
  int oddeven = (parm[0] >> 7) & 0x1;
  char numbuf[64] = "";
  ss7_message(ss7, "\t\t\tNature of address: %x\n", parm[0] & 0x7f);
  ss7_message(ss7, "\t\t\tNI: %x\n", (parm[1] >> 7) & 0x1);
  ss7_message(ss7, "\t\t\tNumbering plan: %x\n", (parm[1] >> 4) & 0x7);
  isup_get_number(numbuf, &parm[2], len - 2, oddeven);
  ss7_message(ss7, "\t\t\tAddress signals: %s\n", numbuf);
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<called_party_num_dump>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  lea    D28(%rip),%rsi
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x58,%rsp
  movzbl (%rdx),%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %r12d,%edx
  movaps %xmm0,0x10(%rsp)
  shr    $0x7,%r12b
  and    $0x7f,%edx
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <ss7_message@plt>
  movzbl 0x1(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D37(%rip),%rsi
  shr    $0x7,%dl
  movzbl %dl,%edx
  call   <ss7_message@plt>
  movzbl 0x1(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D3(%rip),%rsi
  shr    $0x4,%dl
  and    $0x7,%edx
  call   <ss7_message@plt>
  movzbl %r12b,%ecx
  mov    %rsp,%r12
  lea    -0x2(%r13),%edx
  lea    0x2(%rbx),%rsi
  mov    %r12,%rdi
  call   <isup_get_number@plt>
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D34(%rip),%rsi
  call   <ss7_message@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x58,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
data_type: string
name: disassemble_data
arguments: data_label: D37
data_type: string
name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D34
data_type: string

tool: D28: 			Nature of address: %x


tool: D37: 			NI: %x


tool: D3: 			Numbering plan: %x


tool: D34: 			Address signals: %s


assistant: ```c
int((called_party_num_dump))(struct ss7 *ss7, int messagetype, unsigned char *parm, int len) {
  int oddeven = (parm[0] >> 7) & 0x1;
  char numbuf[64] = "";
  ss7_message(ss7, "\t\t\tNature of address: %x\n", parm[0] & 0x7f);
  ss7_message(ss7, "\t\t\tNI: %x\n", (parm[1] >> 7) & 0x1);
  ss7_message(ss7, "\t\t\tNumbering plan: %x\n", (parm[1] >> 4) & 0x7);
  isup_get_number(numbuf, &parm[2], len - 2, oddeven);
  ss7_message(ss7, "\t\t\tAddress signals: %s\n", numbuf);
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strlenn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int strlenn(char *s) {
  char *p;
  p = s;
  while (*s++ != '\0')
    ;
  return s - p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strlenn>:
  endbr64
  mov    %rdi,%rax
L0:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L0
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlenn(char *s) {
  char *p;
  p = s;
  while (*s++ != '\0')
    ;
  return s - p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlenn>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L1
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlenn(char *s) {
  char *p;
  p = s;
  while (*s++ != '\0')
    ;
  return s - p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlenn>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L7
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlenn(char *s) {
  char *p;
  p = s;
  while (*s++ != '\0')
    ;
  return s - p;
}
```