user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x2c(%rbp)
  movl   $0x1,-0x38(%rbp)
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L8:
  mov    -0x3c(%rbp),%ebx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L69
  addl   $0x1,-0x38(%rbp)
  jmp    L8
L69:
  nop
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L19
L38:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%eax
  mov    -0x28(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fmod@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  add    %eax,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L14
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x30(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L14:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x20(%rbp)
  setl   %al
  movzbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jg     L36
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  add    %eax,-0x30(%rbp)
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L36:
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L19:
  mov    -0x34(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L38
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D54
datatype: string
name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D36
datatype: string
name: retrieve_data
arguments: data_tag: D67
datatype: string
name: retrieve_data
arguments: data_tag: D83
datatype: string
name: retrieve_data
arguments: data_tag: D28
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D23
datatype: string
name: retrieve_data
arguments: data_tag: D73
datatype: string
name: retrieve_data
arguments: data_tag: D61
datatype: string
name: retrieve_data
arguments: data_tag: D81
datatype: string

tool: D54: Enter a number: 

tool: D12: %d

tool: D36: the digit is: %d



tool: D67: The base is: %d


tool: D83: The fra is: %d


tool: D28: The mod is: %d


tool: D16: The quan is: %d


tool: D23: A

tool: D73: B

tool: D61: The n1 is: %d



tool: D81: The number of ones is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int num;
  int frac = 1;
  int digit = 1;
  printf("Enter a number: ");
  scanf("%d", &num);
  while (1) {
    frac = num / power(10, digit);
    if (frac == 0)
      break;
    digit += 1;
  }
  printf("the digit is: %d\n\n", digit);
  int j;
  int n1 = 0;
  for (j = 0; j < digit; j++) {
    int base = power(10, j + 1);
    printf("The base is: %d\n", base);
    int fra = num / base;
    printf("The fra is: %d\n", fra);
    int mod = fmod(num, base);
    printf("The mod is: %d\n", mod);
    int quan = power(10, j);
    printf("The quan is: %d\n", quan);
    n1 += fra * quan;
    if (mod > 2 * quan - 1) {
      n1 += quan;
      printf("A\n");
    }
    if (2 * quan > mod > quan - 1) {
      n1 += mod - quan + 1;
      printf("B\n");
    }
    printf("The n1 is: %d\n\n", n1);
  }
  printf("The number of ones is: %d\n", n1);
  getchar();
  getchar();
  return 0;
}
```