ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<getlinelength>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L25
  mov    D9(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L40:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L4
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L44
  mov    %edx,%r14d
L1:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L40
  cmp    $0xa,%eax
  je     L19
L25:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  lea    0x1(%r14),%edx
L4:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L44:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getlinelength(char line[], int limit) {
  int c, i;
  for (i = 0; i < limit - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    line[i] = c;
  if (c == '\n') {
    line[i] = c;
    ++i;
  }
  line[i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 2;
  int b = 3;
  int c = a + b;
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int a = 2;
  int b = 3;
  int c = a + b;
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int a = 2;
  int b = 3;
  int c = a + b;
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int a = 2;
  int b = 3;
  int c = a + b;
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: argv[%d] = %s


assistant: ```c
int main(int argc, char *argv[]) {
  for (int i = 0; i < argc; ++i) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
L14:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L14
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: argv[%d] = %s


assistant: ```c
int main(int argc, char *argv[]) {
  for (int i = 0; i < argc; ++i) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: argv[%d] = %s


assistant: ```c
int main(int argc, char *argv[]) {
  for (int i = 0; i < argc; ++i) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L10:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L10
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: argv[%d] = %s


assistant: ```c
int main(int argc, char *argv[]) {
  for (int i = 0; i < argc; ++i) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<binbuf_read_via_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x408(%rbp)
  mov    %rsi,-0x410(%rbp)
  mov    %rdx,-0x418(%rbp)
  mov    %ecx,-0x41c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f8(%rbp),%rcx
  lea    -0x3f0(%rbp),%rdx
  mov    -0x410(%rbp),%rsi
  mov    -0x418(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x3e8,%r9d
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D11(%rip),%rdx
  mov    %rax,%rdi
  call   <open_via_path@plt>
  add    $0x10,%rsp
  mov    %eax,-0x3fc(%rbp)
  cmpl   $0x0,-0x3fc(%rbp)
  jns    L11
  mov    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L46
L11:
  mov    -0x3fc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x3f8(%rbp),%rsi
  mov    -0x41c(%rbp),%ecx
  lea    -0x3f0(%rbp),%rdx
  mov    -0x408(%rbp),%rax
  mov    %rax,%rdi
  call   <binbuf_read@plt>
  test   %rax,%rax
  je     L42
  mov    $0x1,%eax
  jmp    L46
L42:
  mov    $0x0,%eax
L46:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D11
data_type: string
name: read_data
arguments: tag: D16
data_type: string

tool: 

tool: D16: %s: can't open

assistant: ```c
int binbuf_read_via_path(struct _binbuf *b, char *filename, char *dirname, int crflag) {
  int filedesc;
  char buf[1000], *bufptr;
  if ((filedesc = open_via_path(dirname, filename, "", buf, &bufptr, 1000, 0)) < 0) {
    error("%s: can't open", filename);
    return (1);
  } else
    close(filedesc);
  if (binbuf_read(b, bufptr, buf, crflag))
    return (1);
  else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binbuf_read_via_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x400,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rdi
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x3e8,%r9d
  lea    0x18(%rsp),%r8
  lea    D3(%rip),%rdx
  call   <open_via_path@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  js     L18
  mov    %eax,%edi
  call   <close@plt>
  lea    0x10(%rsp),%rdx
  mov    %r12d,%ecx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <binbuf_read@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L2:
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x400,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L2
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string
name: read_data
arguments: label: D2
type_infered: string

tool: 

tool: D2: %s: can't open

assistant: ```c
int binbuf_read_via_path(struct _binbuf *b, char *filename, char *dirname, int crflag) {
  int filedesc;
  char buf[1000], *bufptr;
  if ((filedesc = open_via_path(dirname, filename, "", buf, &bufptr, 1000, 0)) < 0) {
    error("%s: can't open", filename);
    return (1);
  } else
    close(filedesc);
  if (binbuf_read(b, bufptr, buf, crflag))
    return (1);
  else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<binbuf_read_via_path>:
  endbr64
  push   %r14
  mov    $0x3e8,%r9d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  lea    D0(%rip),%rdx
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  sub    $0x8,%rsp
  push   $0x0
  mov    %r14,%rcx
  lea    0x18(%rsp),%r8
  call   <open_via_path@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  js     L5
  mov    %eax,%edi
  call   <close@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rdi
  call   <binbuf_read@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L12:
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x408,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L12
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D1
type_guessed: string

tool: 

tool: D1: %s: can't open

assistant: ```c
int binbuf_read_via_path(struct _binbuf *b, char *filename, char *dirname, int crflag) {
  int filedesc;
  char buf[1000], *bufptr;
  if ((filedesc = open_via_path(dirname, filename, "", buf, &bufptr, 1000, 0)) < 0) {
    error("%s: can't open", filename);
    return (1);
  } else
    close(filedesc);
  if (binbuf_read(b, bufptr, buf, crflag))
    return (1);
  else
    return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binbuf_read_via_path>:
  endbr64
  push   %r14
  mov    $0x3e8,%r9d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  lea    D6(%rip),%rdx
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  sub    $0x8,%rsp
  push   $0x0
  mov    %r14,%rcx
  lea    0x18(%rsp),%r8
  call   <open_via_path@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  js     L27
  mov    %eax,%edi
  call   <close@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rdi
  call   <binbuf_read@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L8:
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x408,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L27:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L8
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string
name: disassemble_data
arguments: tag: D3
type: string

tool: 

tool: D3: %s: can't open

assistant: ```c
int binbuf_read_via_path(struct _binbuf *b, char *filename, char *dirname, int crflag) {
  int filedesc;
  char buf[1000], *bufptr;
  if ((filedesc = open_via_path(dirname, filename, "", buf, &bufptr, 1000, 0)) < 0) {
    error("%s: can't open", filename);
    return (1);
  } else
    close(filedesc);
  if (binbuf_read(b, bufptr, buf, crflag))
    return (1);
  else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<quit_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0xe,%edi
  call   <write_instr@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int quit_handler(char **save) {
  (void)save;
  write_instr(0x0E);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quit_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe,%edi
  call   <write_instr@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int quit_handler(char **save) {
  (void)save;
  write_instr(0x0E);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quit_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe,%edi
  call   <write_instr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int quit_handler(char **save) {
  (void)save;
  write_instr(0x0E);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quit_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe,%edi
  call   <write_instr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int quit_handler(char **save) {
  (void)save;
  write_instr(0x0E);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pow_cpu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  movss  %xmm0,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L16:
  mov    -0x14(%rbp),%eax
  imul   -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  imul   -0x38(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x40(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movss  -0x28(%rbp),%xmm0
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <pow@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void pow_cpu(int N, float ALPHA, float *X, int INCX, float *Y, int INCY) {
  int i;
  for (i = 0; i < N; ++i)
    Y[i * INCY] = pow(X[i * INCX], ALPHA);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pow_cpu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  test   %edi,%edi
  jle    L1
  mov    %edi,%r15d
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%r14
  mov    %rsi,%rbp
  movslq %r8d,%r8
  lea    0x0(,%r8,4),%r13
  mov    %rcx,%rbx
  mov    $0x0,%r12d
L6:
  movss  0xc(%rsp),%xmm1
  movss  0x0(%rbp),%xmm0
  call   <pow@plt>
  movss  %xmm0,(%rbx)
  add    $0x1,%r12d
  add    %r14,%rbp
  add    %r13,%rbx
  cmp    %r12d,%r15d
  jne    L6
L1:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pow_cpu(int N, float ALPHA, float *X, int INCX, float *Y, int INCY) {
  int i;
  for (i = 0; i < N; ++i)
    Y[i * INCY] = pow(X[i * INCX], ALPHA);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pow_cpu>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r15
  movslq %edx,%rdx
  movslq %r8d,%r8
  movaps %xmm0,%xmm1
  push   %r14
  xor    %r15d,%r15d
  lea    0x0(,%r8,4),%r14
  push   %r13
  lea    0x0(,%rdx,4),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L15:
  movss  0x0(%rbp),%xmm0
  movss  %xmm1,0xc(%rsp)
  add    $0x1,%r15d
  add    %r13,%rbp
  call   <pow@plt>
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,(%rbx)
  add    %r14,%rbx
  cmp    %r15d,%r12d
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void pow_cpu(int N, float ALPHA, float *X, int INCX, float *Y, int INCY) {
  int i;
  for (i = 0; i < N; ++i)
    Y[i * INCY] = pow(X[i * INCX], ALPHA);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pow_cpu>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %r15
  movslq %edx,%rdx
  movslq %r8d,%r8
  movaps %xmm0,%xmm1
  push   %r14
  xor    %r15d,%r15d
  lea    0x0(,%r8,4),%r14
  push   %r13
  lea    0x0(,%rdx,4),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L14:
  movss  0x0(%rbp),%xmm0
  movss  %xmm1,0xc(%rsp)
  add    $0x1,%r15d
  add    %r13,%rbp
  call   <pow@plt>
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,(%rbx)
  add    %r14,%rbx
  cmp    %r15d,%r12d
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void pow_cpu(int N, float ALPHA, float *X, int INCX, float *Y, int INCY) {
  int i;
  for (i = 0; i < N; ++i)
    Y[i * INCY] = pow(X[i * INCX], ALPHA);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L26
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,%rdi
  call   <free@plt>
L26:
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L0
  mov    $0x0,%eax
  jmp    L5
L0:
  mov    $0xffffffff,%eax
L5:
  leave
  ret
```

assistant: ```c
int close(int fildes) {
  int n;
  if (fildes != -1)
    free((int *)(long)fildes);
  n = __infer_nondet_int();
  if (n > 0)
    return 0;
  else
    return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<close>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  jne    L6
L18:
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  test   %eax,%eax
  setle  %al
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  ret
L6:
  movslq %edi,%rdi
  call   <free@plt>
  jmp    L18
```

assistant: ```c
int close(int fildes) {
  int n;
  if (fildes != -1)
    free((int *)(long)fildes);
  n = __infer_nondet_int();
  if (n > 0)
    return 0;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<close>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  je     L9
  movslq %edi,%rdi
  call   <free@plt>
L9:
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  test   %eax,%eax
  setle  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int close(int fildes) {
  int n;
  if (fildes != -1)
    free((int *)(long)fildes);
  n = __infer_nondet_int();
  if (n > 0)
    return 0;
  else
    return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<close>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  je     L8
  movslq %edi,%rdi
  call   <free@plt>
L8:
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  test   %eax,%eax
  setle  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int close(int fildes) {
  int n;
  if (fildes != -1)
    free((int *)(long)fildes);
  n = __infer_nondet_int();
  if (n > 0)
    return 0;
  else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StrNCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *StrNCopy(char *dest, const char *src, size_t n) {
  char *s;
  s = strncpy(dest, src, n - 1);
  dest[n - 1] = '\0';
  return (s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<StrNCopy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  lea    -0x1(%rdx),%rdx
  call   <strncpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *StrNCopy(char *dest, const char *src, size_t n) {
  char *s;
  s = strncpy(dest, src, n - 1);
  dest[n - 1] = '\0';
  return (s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<StrNCopy>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  lea    -0x1(%rdx),%rdx
  call   <strncpy@plt>
  movb   $0x0,-0x1(%rax,%rbx,1)
  pop    %rbx
  ret
```

assistant: ```c
char *StrNCopy(char *dest, const char *src, size_t n) {
  char *s;
  s = strncpy(dest, src, n - 1);
  dest[n - 1] = '\0';
  return (s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<StrNCopy>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  lea    -0x1(%rdx),%rdx
  call   <strncpy@plt>
  movb   $0x0,-0x1(%rax,%rbx,1)
  pop    %rbx
  ret
```

assistant: ```c
char *StrNCopy(char *dest, const char *src, size_t n) {
  char *s;
  s = strncpy(dest, src, n - 1);
  dest[n - 1] = '\0';
  return (s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x14(%rbp)
  jle    L7
  addl   $0x2,-0x4(%rbp)
  jmp    L18
L7:
  subl   $0x3,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) int bar(int y) {
  int d = y;
  if (y > 10)
    d += 2;
  else
    d -= 3;
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bar>:
  endbr64
  lea    0x2(%rdi),%edx
  lea    -0x3(%rdi),%eax
  cmp    $0xb,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
__attribute__((no)) int bar(int y) {
  int d = y;
  if (y > 10)
    d += 2;
  else
    d -= 3;
  return d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  lea    0x2(%rdi),%edx
  lea    -0x3(%rdi),%eax
  cmp    $0xb,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
__attribute__((no)) int bar(int y) {
  int d = y;
  if (y > 10)
    d += 2;
  else
    d -= 3;
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bar>:
  endbr64
  lea    0x2(%rdi),%edx
  lea    -0x3(%rdi),%eax
  cmp    $0xb,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
__attribute__((no)) int bar(int y) {
  int d = y;
  if (y > 10)
    d += 2;
  else
    d -= 3;
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D7(%rip),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  jmp    L15
L6:
  cmpb   $0x20,-0x1(%rbp)
  je     L77
  cmpb   $0x9,-0x1(%rbp)
  je     L77
  cmpb   $0xa,-0x1(%rbp)
  jne    L51
L77:
  cmpb   $0x20,-0x2(%rbp)
  je     L7
  cmpb   $0x9,-0x2(%rbp)
  je     L7
  cmpb   $0xa,-0x2(%rbp)
  je     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L7
L51:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L82
L7:
  nop
L82:
  movzbl -0x1(%rbp),%eax
  mov    %al,-0x2(%rbp)
L15:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  mov    D7(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L6
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c, a = EOF;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\t' || c == '\n') {
      if (a == ' ' || a == '\t' || a == '\n')
        ;
      else
        putchar('\n');
    } else
      putchar(c);
    a = c;
  }
  return 0;
}
```