user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D69(%rip),%rdi
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  lea    D41(%rip),%rdi
  call   <scanf@plt>
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L52:
  cmp    %rcx,%rsp
  je     L60
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L52
L60:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L166
  orq    $0x0,-0x8(%rsp,%rax,1)
L166:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L93
  mov    %rbx,%r13
  mov    $0x0,%r12d
  lea    D41(%rip),%r14
L64:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    -0x2c(%rbp),%eax
  add    $0x4,%r13
  cmp    %r12d,%eax
  jg     L64
  test   %eax,%eax
  jle    L21
  mov    %eax,%r9d
  lea    (%rbx,%r9,4),%rdi
  mov    $0x0,%r8d
  mov    $0x0,%r10d
  mov    $0x0,%r12d
  jmp    L161
L99:
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L63
L161:
  mov    %r8d,%r11d
  mov    (%rbx,%r8,4),%esi
  mov    %rbx,%rax
  mov    $0x0,%edx
L179:
  cmp    %esi,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L179
  cmp    %r10d,%edx
  jle    L99
  mov    %edx,%r10d
  mov    %r11d,%r12d
  jmp    L99
L93:
  mov    $0x0,%r12d
L63:
  movslq %r12d,%rax
  mov    (%rbx,%rax,4),%esi
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x2c(%rbp)
  jle    L74
  mov    $0x0,%r13d
  lea    D18(%rip),%r14
  jmp    L88
L21:
  mov    $0x0,%r12d
  jmp    L63
L57:
  add    $0x1,%r13
  cmp    %r13d,-0x2c(%rbp)
  jle    L74
L88:
  movslq %r12d,%rax
  mov    (%rbx,%rax,4),%eax
  cmp    %eax,(%rbx,%r13,4)
  jne    L57
  lea    0x1(%r13),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L74:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L124
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L124:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D69
data_type: string
name: read_data
arguments: label: D41
data_type: string
name: read_data
arguments: label: D59
data_type: string
name: read_data
arguments: label: D67
data_type: string
name: read_data
arguments: label: D13
data_type: string
name: read_data
arguments: label: D18
data_type: string

tool: D69: Input length of array: 

tool: D41: %d

tool: D59: Input array: 

tool: D67: Element: %d


tool: D13: Positions:

tool: D18:  %d

assistant: ```c
int main(int argc, char *argv[]) {
  int N;
  printf("Input length of array: ");
  scanf("%d", &N);
  printf("Input array: ");
  int arr[N];
  for (int i = 0; i < N; i++)
    scanf("%d", &arr[i]);
  int m = 0;
  int mSumma = 0;
  for (int i = 0; i < N; i++) {
    int summa = 0;
    for (int j = 0; j < N; j++)
      arr[j] == arr[i] ? summa++ : 0;
    if (mSumma < summa) {
      mSumma = summa;
      m = i;
    }
  }
  printf("Element: %d\n", arr[m]);
  printf("Positions:");
  for (int i = 0; i < N; i++) {
    arr[i] == arr[m] ? printf(" %d", i + 1) : 0;
  }
  printf("\n");
  return 0;
}
```