ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<bit_set>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%ecx
  xor    %edx,%edx
  shr    $0x5,%eax
  div    %esi
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %edx,%edx
  or     %eax,(%rdi,%rdx,4)
  ret
```

assistant: ```c
void bit_set(int *tbl, int l, unsigned int bit) {
  int b;
  b = bit % 32;
  bit = bit / 32;
  tbl[bit % l] |= 1 << b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bit_set>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%ecx
  xor    %edx,%edx
  shr    $0x5,%eax
  div    %esi
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %edx,%edx
  or     %eax,(%rdi,%rdx,4)
  ret
```

assistant: ```c
void bit_set(int *tbl, int l, unsigned int bit) {
  int b;
  b = bit % 32;
  bit = bit / 32;
  tbl[bit % l] |= 1 << b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lengthof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L6:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    $0x4,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  cmp    %eax,-0x4(%rbp)
  jge    L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int lengthof(char *i) {
  int j;
  for (j = 0; (j < (pow(2, sizeof(int)))) && (i[j] != '\0'); ++j)
    ;
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lengthof>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L14:
  mov    %ebx,%r12d
  mov    $0x4,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  cmp    %ebx,%eax
  jle    L10
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbp,%rbx,1)
  jne    L14
L10:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int lengthof(char *i) {
  int j;
  for (j = 0; (j < (pow(2, sizeof(int)))) && (i[j] != '\0'); ++j)
    ;
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lengthof>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L25
  nop
L17:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbp,%rbx,1)
  je     L7
L25:
  mov    $0x4,%esi
  mov    $0x2,%edi
  mov    %ebx,%r12d
  call   <pow@plt>
  cmp    %ebx,%eax
  jg     L17
L7:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int lengthof(char *i) {
  int j;
  for (j = 0; (j < (pow(2, sizeof(int)))) && (i[j] != '\0'); ++j)
    ;
  return j;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lengthof>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L14
  nop
L25:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbp,%rbx,1)
  je     L12
L14:
  mov    $0x4,%esi
  mov    $0x2,%edi
  mov    %ebx,%r12d
  call   <pow@plt>
  cmp    %ebx,%eax
  jg     L25
L12:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int lengthof(char *i) {
  int j;
  for (j = 0; (j < (pow(2, sizeof(int)))) && (i[j] != '\0'); ++j)
    ;
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_label>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  nop
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x1,%edx
  mov    $0xdf,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x0,%edx
  mov    $0xe4,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  movl   $0x0,-0x4(%rbp)
  addl   $0x3,-0x4(%rbp)
  addl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x8,%edx
  mov    $0xef,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string

tool: D15: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c

assistant: ```c
void test_label() {
  int x = 0;
  if (1)
  L1:
    x++;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 223, 1, x);
  ;
  int y = 0;
  if (0)
  L2:
    y++;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 228, 0, y);
  ;
  int z = 0;
  switch (7) {
    if (1)
    case 5:
      z += 2;
    if (0)
    case 7:
      z += 3;
    if (1)
    case 6:
      z += 5;
  }
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 239, 8, z);
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_label>:
  endbr64
  push   %rbx
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0xdf,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0xe4,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    $0x8,%ecx
  mov    $0x8,%edx
  mov    $0xef,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c

assistant: ```c
void test_label() {
  int x = 0;
  if (1)
  L1:
    x++;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 223, 1, x);
  ;
  int y = 0;
  if (0)
  L2:
    y++;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 228, 0, y);
  ;
  int z = 0;
  switch (7) {
    if (1)
    case 5:
      z += 2;
    if (0)
    case 7:
      z += 3;
    if (1)
    case 6:
      z += 5;
  }
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 239, 8, z);
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_label>:
  endbr64
  push   %rbp
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0xdf,%esi
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0xe4,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x8,%ecx
  pop    %rbp
  mov    $0x8,%edx
  mov    $0xef,%esi
  jmp    1050 <fexpect@plt>
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c

assistant: ```c
void test_label() {
  int x = 0;
  if (1)
  L1:
    x++;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 223, 1, x);
  ;
  int y = 0;
  if (0)
  L2:
    y++;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 228, 0, y);
  ;
  int z = 0;
  switch (7) {
    if (1)
    case 5:
      z += 2;
    if (0)
    case 7:
      z += 3;
    if (1)
    case 6:
      z += 5;
  }
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 239, 8, z);
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_label>:
  endbr64
  push   %rbp
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0xdf,%esi
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0xe4,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x8,%ecx
  pop    %rbp
  mov    $0x8,%edx
  mov    $0xef,%esi
  jmp    1050 <fexpect@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c

assistant: ```c
void test_label() {
  int x = 0;
  if (1)
  L1:
    x++;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 223, 1, x);
  ;
  int y = 0;
  if (0)
  L2:
    y++;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 228, 0, y);
  ;
  int z = 0;
  switch (7) {
    if (1)
    case 5:
      z += 2;
    if (0)
    case 7:
      z += 3;
    if (1)
    case 6:
      z += 5;
  }
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/control.c", 239, 8, z);
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crlb_polyfact>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  mov    D17(%rip),%rcx
  mov    %rcx,0x8(%rsi)
  test   %edi,%edi
  jle    L100
  lea    0x1(%rdi),%eax
  mov    %eax,0xc(%rsp)
  mov    $0x2,%r14d
  mov    $0x1,%r15d
L20:
  mov    %r15d,%eax
  mov    %r15d,0x8(%rsp)
  add    $0x1,%r15d
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm0,%xmm0
  addsd  D17(%rip),%xmm0
  addsd  %xmm0,%xmm0
  lea    0x2(%rax),%edx
  imul   %r15d,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%rsp),%rcx
  lea    (%rcx,%rax,8),%rbp
  pxor   %xmm4,%xmm4
  ucomisd %xmm0,%xmm4
  ja     L21
  sqrtsd %xmm0,%xmm0
L80:
  movsd  %xmm0,0x0(%rbp)
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L28
  lea    -0x1(%rax),%ebx
L7:
  mov    %rbp,%r13
  mov    0x0(%rbp),%r12
  mov    %r14d,%eax
  sub    %ebx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  addsd  D17(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D17(%rip),%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm3,%xmm3
  ucomisd %xmm0,%xmm3
  ja     L38
  sqrtsd %xmm0,%xmm0
L89:
  movq   %r12,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,-0x8(%r13)
  sub    $0x8,%rbp
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L7
L28:
  add    $0x2,%r14d
  cmp    0xc(%rsp),%r15d
  jne    L20
  mov    $0x1,%ebx
L15:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  addsd  %xmm0,%xmm0
  addsd  D17(%rip),%xmm0
  lea    0x2(%rbp),%edx
  imul   %ebx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%rsp),%rsi
  lea    (%rsi,%rax,8),%r12
  pxor   %xmm5,%xmm5
  ucomisd %xmm0,%xmm5
  ja     L85
  sqrtsd %xmm0,%xmm0
L96:
  movsd  %xmm0,(%r12)
  cmp    %ebp,0x8(%rsp)
  jne    L15
L100:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <sqrt@plt>
  jmp    L80
L38:
  call   <sqrt@plt>
  jmp    L89
L85:
  call   <sqrt@plt>
  jmp    L96
```

tool_calls: name: unpack_data
arguments: tag: D17
data_type: f64

tool: D17: 1

assistant: ```c
void crlb_polyfact(int n, double *pfact) {
  int l, k, m;
  pfact[1] = 1.0;
  for (l = 1; l <= n; l++) {
    k = (l + 1) * (l + 2) / 2;
    pfact[k] = sqrt(2.0 * (2.0 * l + 1.0));
    for (m = 1; m <= l; m++) {
      k = (l + 1) * (l + 2) / 2 - m;
      pfact[k] = pfact[k + 1] * sqrt(1.0 / ((l + m) * (l - m + 1.0)));
    }
  }
  for (l = 1; l <= n; l++) {
    k = (l + 1) * (l + 2) / 2;
    pfact[k] = sqrt(2.0 * l + 1.0);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<crlb_polyfact>:
  endbr64
  movsd  D28(%rip),%xmm3
  movsd  %xmm3,0x8(%rsi)
  test   %edi,%edi
  jle    L99
  push   %r15
  pxor   %xmm4,%xmm4
  mov    $0x1,%r15d
  push   %r14
  mov    $0x2,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x1(%rdi),%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L48:
  mov    %r15d,%ebx
  pxor   %xmm0,%xmm0
  add    $0x1,%r15d
  cvtsi2sd %ebx,%xmm0
  lea    0x2(%rbx),%eax
  imul   %r15d,%eax
  addsd  %xmm0,%xmm0
  sar    %eax
  cltq
  lea    0x0(%r13,%rax,8),%rbp
  addsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L3
  sqrtsd %xmm0,%xmm0
L45:
  movsd  %xmm0,0x0(%rbp)
  sub    $0x1,%ebx
  nopl   0x0(%rax)
L74:
  pxor   %xmm0,%xmm0
  mov    %r14d,%eax
  pxor   %xmm2,%xmm2
  movsd  0x0(%rbp),%xmm1
  cvtsi2sd %ebx,%xmm0
  sub    %ebx,%eax
  cvtsi2sd %eax,%xmm2
  addsd  %xmm3,%xmm0
  mulsd  %xmm0,%xmm2
  movapd %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L16
  sqrtsd %xmm0,%xmm0
L28:
  mulsd  %xmm0,%xmm1
  sub    $0x8,%rbp
  movsd  %xmm1,0x0(%rbp)
  sub    $0x1,%ebx
  jae    L74
  add    $0x2,%r14d
  cmp    %r12d,%r15d
  jne    L48
  mov    $0x1,%ebx
L19:
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  add    $0x1,%ebx
  cvtsi2sd %eax,%xmm0
  add    $0x2,%eax
  imul   %ebx,%eax
  addsd  %xmm0,%xmm0
  sar    %eax
  cltq
  lea    0x0(%r13,%rax,8),%rbp
  addsd  %xmm3,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L75
  sqrtsd %xmm0,%xmm0
L18:
  movsd  %xmm0,0x0(%rbp)
  cmp    %r12d,%ebx
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L99:
  ret
L16:
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  mov    D28(%rip),%rax
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm4,%xmm4
  movq   %rax,%xmm3
  jmp    L28
L75:
  call   <sqrt@plt>
  mov    D28(%rip),%rax
  pxor   %xmm4,%xmm4
  movq   %rax,%xmm3
  jmp    L18
L3:
  call   <sqrt@plt>
  mov    D28(%rip),%rax
  pxor   %xmm4,%xmm4
  movq   %rax,%xmm3
  jmp    L45
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_infered: f64

tool: D28: 1

assistant: ```c
void crlb_polyfact(int n, double *pfact) {
  int l, k, m;
  pfact[1] = 1.0;
  for (l = 1; l <= n; l++) {
    k = (l + 1) * (l + 2) / 2;
    pfact[k] = sqrt(2.0 * (2.0 * l + 1.0));
    for (m = 1; m <= l; m++) {
      k = (l + 1) * (l + 2) / 2 - m;
      pfact[k] = pfact[k + 1] * sqrt(1.0 / ((l + m) * (l - m + 1.0)));
    }
  }
  for (l = 1; l <= n; l++) {
    k = (l + 1) * (l + 2) / 2;
    pfact[k] = sqrt(2.0 * l + 1.0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crlb_polyfact>:
  endbr64
  movsd  D9(%rip),%xmm3
  movsd  %xmm3,0x8(%rsi)
  test   %edi,%edi
  jle    L92
  push   %r15
  pxor   %xmm4,%xmm4
  mov    $0x1,%r15d
  push   %r14
  mov    $0x2,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x1(%rdi),%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L71:
  mov    %r15d,%ebx
  pxor   %xmm0,%xmm0
  add    $0x1,%r15d
  cvtsi2sd %ebx,%xmm0
  lea    0x2(%rbx),%eax
  imul   %r15d,%eax
  addsd  %xmm0,%xmm0
  sar    %eax
  cltq
  lea    0x0(%r13,%rax,8),%rbp
  addsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L24
  sqrtsd %xmm0,%xmm0
L22:
  movsd  %xmm0,0x0(%rbp)
  sub    $0x1,%ebx
  nopl   0x0(%rax)
L18:
  pxor   %xmm0,%xmm0
  mov    %r14d,%eax
  pxor   %xmm2,%xmm2
  movsd  0x0(%rbp),%xmm1
  cvtsi2sd %ebx,%xmm0
  sub    %ebx,%eax
  cvtsi2sd %eax,%xmm2
  addsd  %xmm3,%xmm0
  mulsd  %xmm0,%xmm2
  movapd %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L111
  sqrtsd %xmm0,%xmm0
  sub    $0x8,%rbp
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  sub    $0x1,%ebx
  jae    L18
L3:
  add    $0x2,%r14d
  cmp    %r12d,%r15d
  jne    L71
  mov    $0x1,%eax
  nopl   0x0(%rax)
L59:
  pxor   %xmm0,%xmm0
  lea    0x1(%rax),%ebx
  cvtsi2sd %eax,%xmm0
  add    $0x2,%eax
  imul   %ebx,%eax
  addsd  %xmm0,%xmm0
  sar    %eax
  cltq
  lea    0x0(%r13,%rax,8),%rbp
  addsd  %xmm3,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L86
  sqrtsd %xmm0,%xmm0
  movsd  %xmm0,0x0(%rbp)
  cmp    %r12d,%ebx
  je     L54
L42:
  mov    %ebx,%eax
  jmp    L59
L86:
  call   <sqrt@plt>
  mov    D9(%rip),%rax
  cmp    %r12d,%ebx
  pxor   %xmm4,%xmm4
  movsd  %xmm0,0x0(%rbp)
  movq   %rax,%xmm3
  jne    L42
L54:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L92:
  ret
L111:
  movsd  %xmm1,0x8(%rsp)
  sub    $0x1,%ebx
  sub    $0x8,%rbp
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  mov    D9(%rip),%rax
  pxor   %xmm4,%xmm4
  mulsd  %xmm0,%xmm1
  movq   %rax,%xmm3
  movsd  %xmm1,0x0(%rbp)
  cmp    $0xffffffff,%ebx
  jne    L18
  jmp    L3
L24:
  call   <sqrt@plt>
  mov    D9(%rip),%rax
  pxor   %xmm4,%xmm4
  movq   %rax,%xmm3
  jmp    L22
```

tool_calls: name: read_data
arguments: label: D9
type: f64

tool: D9: 1

assistant: ```c
void crlb_polyfact(int n, double *pfact) {
  int l, k, m;
  pfact[1] = 1.0;
  for (l = 1; l <= n; l++) {
    k = (l + 1) * (l + 2) / 2;
    pfact[k] = sqrt(2.0 * (2.0 * l + 1.0));
    for (m = 1; m <= l; m++) {
      k = (l + 1) * (l + 2) / 2 - m;
      pfact[k] = pfact[k + 1] * sqrt(1.0 / ((l + m) * (l - m + 1.0)));
    }
  }
  for (l = 1; l <= n; l++) {
    k = (l + 1) * (l + 2) / 2;
    pfact[k] = sqrt(2.0 * l + 1.0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memcpyx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1c(%rbp),%eax
  mov    %al,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void memcpyx(char *target, const void *source, uint32_t ct, const char extra_char) {
  memcpy(target, source, ct);
  target[ct] = extra_char;
}
```
user: What is the c source code of the assembly code below:

```asm
<memcpyx>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  call   <memcpy@plt>
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void memcpyx(char *target, const void *source, uint32_t ct, const char extra_char) {
  memcpy(target, source, ct);
  target[ct] = extra_char;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpyx>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <memcpy@plt>
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void memcpyx(char *target, const void *source, uint32_t ct, const char extra_char) {
  memcpy(target, source, ct);
  target[ct] = extra_char;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memcpyx>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <memcpy@plt>
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void memcpyx(char *target, const void *source, uint32_t ct, const char extra_char) {
  memcpy(target, source, ct);
  target[ct] = extra_char;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swapBigRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jg     L21
  cmpl   $0x2,-0x8(%rbp)
  jle    L14
L21:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L14:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swapLittleRow@plt>
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swapLittleRow@plt>
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    0x2(%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    $0x2,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swapLittleRow@plt>
  nop
L7:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: BIG ERROR

assistant: ```c
void swapBigRow(int brow1, int brow2) {
  if (brow1 > 2 || brow2 > 2)
    printf("BIG ERROR");
  else {
    swapLittleRow(brow1 * 3, brow2 * 3);
    swapLittleRow(brow1 * 3 + 1, brow2 * 3 + 1);
    swapLittleRow(brow1 * 3 + 2, brow2 * 3 + 2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swapBigRow>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jg     L24
  cmp    $0x2,%esi
  jg     L24
  lea    (%rsi,%rsi,2),%ebp
  lea    (%rdi,%rdi,2),%ebx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <swapLittleRow@plt>
  lea    0x1(%rbp),%esi
  lea    0x1(%rbx),%edi
  call   <swapLittleRow@plt>
  lea    0x2(%rbp),%esi
  lea    0x2(%rbx),%edi
  call   <swapLittleRow@plt>
  jmp    L4
L24:
  lea    D4(%rip),%rdi
  call   <printf@plt>
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: BIG ERROR

assistant: ```c
void swapBigRow(int brow1, int brow2) {
  if (brow1 > 2 || brow2 > 2)
    printf("BIG ERROR");
  else {
    swapLittleRow(brow1 * 3, brow2 * 3);
    swapLittleRow(brow1 * 3 + 1, brow2 * 3 + 1);
    swapLittleRow(brow1 * 3 + 2, brow2 * 3 + 2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swapBigRow>:
  endbr64
  cmp    $0x2,%edi
  jg     L19
  cmp    $0x2,%esi
  jg     L19
  push   %rbp
  lea    (%rsi,%rsi,2),%ebp
  push   %rbx
  lea    (%rdi,%rdi,2),%ebx
  mov    %ebp,%esi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <swapLittleRow@plt>
  lea    0x1(%rbp),%esi
  lea    0x1(%rbx),%edi
  call   <swapLittleRow@plt>
  add    $0x8,%rsp
  lea    0x2(%rbp),%esi
  lea    0x2(%rbx),%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <swapLittleRow@plt>
  nop
L19:
  lea    D0(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D0: BIG ERROR

assistant: ```c
void swapBigRow(int brow1, int brow2) {
  if (brow1 > 2 || brow2 > 2)
    printf("BIG ERROR");
  else {
    swapLittleRow(brow1 * 3, brow2 * 3);
    swapLittleRow(brow1 * 3 + 1, brow2 * 3 + 1);
    swapLittleRow(brow1 * 3 + 2, brow2 * 3 + 2);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swapBigRow>:
  endbr64
  cmp    $0x2,%edi
  jg     L7
  cmp    $0x2,%esi
  jg     L7
  push   %rbp
  lea    (%rsi,%rsi,2),%ebp
  push   %rbx
  lea    (%rdi,%rdi,2),%ebx
  mov    %ebp,%esi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <swapLittleRow@plt>
  lea    0x1(%rbp),%esi
  lea    0x1(%rbx),%edi
  call   <swapLittleRow@plt>
  add    $0x8,%rsp
  lea    0x2(%rbp),%esi
  lea    0x2(%rbx),%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <swapLittleRow@plt>
  nop
L7:
  lea    D8(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D8: BIG ERROR

assistant: ```c
void swapBigRow(int brow1, int brow2) {
  if (brow1 > 2 || brow2 > 2)
    printf("BIG ERROR");
  else {
    swapLittleRow(brow1 * 3, brow2 * 3);
    swapLittleRow(brow1 * 3 + 1, brow2 * 3 + 1);
    swapLittleRow(brow1 * 3 + 2, brow2 * 3 + 2);
  }
}
```