ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<normalize_filename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L27
L25:
  cmp    $0x5c,%dil
  je     L10
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L25
L27:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L10:
  movb   $0x2f,(%rbx)
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L25
  pop    %rbx
  ret
```

assistant: ```c
void normalize_filename(char *name) {
  int i = 0;
  char c;
  while ((c = name[i]) != '\0') {
    if (c == '\\') {
      name[i] = '/';
    } else {
      name[i] = toupper(c);
    }
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <setup_callbacks@plt>
  mov    $0x0,%eax
  call   <display_init@plt>
  mov    $0x0,%eax
  call   <display_clear@plt>
  mov    $0x0,%eax
  call   <sceKernelSleepThread@plt>
  mov    $0x0,%eax
  call   <sceKernelExitGame@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int _main(int args, void *argp) {
  setup_callbacks();
  display_init();
  display_clear();
  sceKernelSleepThread();
  sceKernelExitGame();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <setup_callbacks@plt>
  mov    $0x0,%eax
  call   <display_init@plt>
  mov    $0x0,%eax
  call   <display_clear@plt>
  mov    $0x0,%eax
  call   <sceKernelSleepThread@plt>
  mov    $0x0,%eax
  call   <sceKernelExitGame@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _main(int args, void *argp) {
  setup_callbacks();
  display_init();
  display_clear();
  sceKernelSleepThread();
  sceKernelExitGame();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_callbacks@plt>
  xor    %eax,%eax
  call   <display_init@plt>
  xor    %eax,%eax
  call   <display_clear@plt>
  xor    %eax,%eax
  call   <sceKernelSleepThread@plt>
  xor    %eax,%eax
  call   <sceKernelExitGame@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _main(int args, void *argp) {
  setup_callbacks();
  display_init();
  display_clear();
  sceKernelSleepThread();
  sceKernelExitGame();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_callbacks@plt>
  xor    %eax,%eax
  call   <display_init@plt>
  xor    %eax,%eax
  call   <display_clear@plt>
  xor    %eax,%eax
  call   <sceKernelSleepThread@plt>
  xor    %eax,%eax
  call   <sceKernelExitGame@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _main(int args, void *argp) {
  setup_callbacks();
  display_init();
  display_clear();
  sceKernelSleepThread();
  sceKernelExitGame();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L16:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L28
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x38(%rbp)
L25:
  cmpq   $0x0,-0x38(%rbp)
  jne    L16
  jmp    L4
L28:
  nop
L4:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *cs, const void *ct, size_t count) {
  const unsigned char *su1, *su2;
  int res = 0;
  for (su1 = cs, su2 = ct; 0 < count; ++su1, ++su2, count--)
    if ((res = *su1 - *su2) != 0)
      break;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L20
  mov    $0x0,%ecx
L15:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  jne    L0
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L15
  ret
L20:
  mov    $0x0,%eax
L0:
  ret
```

assistant: ```c
int memcmp(const void *cs, const void *ct, size_t count) {
  const unsigned char *su1, *su2;
  int res = 0;
  for (su1 = cs, su2 = ct; 0 < count; ++su1, ++su2, count--)
    if ((res = *su1 - *su2) != 0)
      break;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L36
  xor    %ecx,%ecx
  jmp    L28
  nopl   (%rax)
L39:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L6
L28:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  je     L39
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *cs, const void *ct, size_t count) {
  const unsigned char *su1, *su2;
  int res = 0;
  for (su1 = cs, su2 = ct; 0 < count; ++su1, ++su2, count--)
    if ((res = *su1 - *su2) != 0)
      break;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L3
  xor    %ecx,%ecx
  jmp    L21
  nopl   (%rax)
L16:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L27
L21:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  je     L16
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  ret
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *cs, const void *ct, size_t count) {
  const unsigned char *su1, *su2;
  int res = 0;
  for (su1 = cs, su2 = ct; 0 < count; ++su1, ++su2, count--)
    if ((res = *su1 - *su2) != 0)
      break;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<start_of_next_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L97
  cmpq   $0x0,-0x20(%rbp)
  jne    L100
L97:
  mov    $0x0,%eax
  jmp    L5
L100:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L63
L83:
  addq   $0x1,-0x8(%rbp)
L63:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L79
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L83
  jmp    L79
L86:
  addq   $0x1,-0x8(%rbp)
L79:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L86
L65:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0x0,%eax
  jmp    L5
L15:
  mov    -0x8(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
char *start_of_next_field(const char *s, const char *delimiters) {
  const char *pc;
  if (!s || !delimiters)
    return NULL;
  for (pc = s; *pc != '\0' && !strchr(delimiters, *pc); ++pc)
    ;
  for (; *pc != '\0' && strchr(delimiters, *pc); ++pc)
    ;
  if (*pc == '\0')
    return NULL;
  return (char *)pc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<start_of_next_field>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L123
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L123
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L126
L4:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L106
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L4
  jmp    L126
L106:
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L126
L74:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L17
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L74
L126:
  mov    $0x0,%ebx
  jmp    L122
L17:
  cmpb   $0x0,(%rbx)
  je     L3
L122:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x0,%ebx
  jmp    L122
L123:
  mov    $0x0,%ebx
  jmp    L122
```

assistant: ```c
char *start_of_next_field(const char *s, const char *delimiters) {
  const char *pc;
  if (!s || !delimiters)
    return NULL;
  for (pc = s; *pc != '\0' && !strchr(delimiters, *pc); ++pc)
    ;
  for (; *pc != '\0' && strchr(delimiters, *pc); ++pc)
    ;
  if (*pc == '\0')
    return NULL;
  return (char *)pc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<start_of_next_field>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L86
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L86
  movsbl (%rdi),%esi
  mov    %rdi,%r12
  test   %sil,%sil
  jne    L48
  jmp    L86
  nopl   (%rax)
L6:
  movsbl 0x1(%r12),%esi
  add    $0x1,%r12
  test   %sil,%sil
  je     L86
L48:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x1,%r12
L15:
  movsbl (%r12),%esi
  test   %sil,%sil
  je     L86
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L9
  cmpb   $0x0,(%r12)
  je     L86
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L86:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *start_of_next_field(const char *s, const char *delimiters) {
  const char *pc;
  if (!s || !delimiters)
    return NULL;
  for (pc = s; *pc != '\0' && !strchr(delimiters, *pc); ++pc)
    ;
  for (; *pc != '\0' && strchr(delimiters, *pc); ++pc)
    ;
  if (*pc == '\0')
    return NULL;
  return (char *)pc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<start_of_next_field>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L57
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L57
  movsbl (%rdi),%esi
  mov    %rdi,%r12
  test   %sil,%sil
  jne    L50
  jmp    L57
  nopl   (%rax)
L78:
  movsbl 0x1(%r12),%esi
  add    $0x1,%r12
  test   %sil,%sil
  je     L57
L50:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L78
  jmp    L72
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x1,%r12
L72:
  movsbl (%r12),%esi
  test   %sil,%sil
  je     L57
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L8
  cmpb   $0x0,(%r12)
  je     L57
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L57:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *start_of_next_field(const char *s, const char *delimiters) {
  const char *pc;
  if (!s || !delimiters)
    return NULL;
  for (pc = s; *pc != '\0' && !strchr(delimiters, *pc); ++pc)
    ;
  for (; *pc != '\0' && strchr(delimiters, *pc); ++pc)
    ;
  if (*pc == '\0')
    return NULL;
  return (char *)pc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<alloc_parse_doubles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r12
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x2(%rax),%edx
  movslq %edx,%rdx
  add    $0xf,%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L21:
  cmp    %rcx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L21
L15:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L86
  orq    $0x0,-0x8(%rsp,%rdx,1)
L86:
  mov    %rsp,%rbx
  movb   $0x20,(%rsp)
  test   %eax,%eax
  js     L66
  lea    0x1(%rax),%ecx
  mov    $0x0,%eax
L12:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,0x1(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L12
L66:
  lea    0x0(,%r14,8),%edi
  call   <malloc@plt>
  mov    %rax,-0x50(%rbp)
  test   %r14d,%r14d
  jle    L72
  mov    %rax,%r13
  mov    $0x0,%r12d
  lea    D1(%rip),%r15
L32:
  lea    -0x3c(%rbp),%rcx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L69
  add    $0x1,%r12d
  movslq -0x3c(%rbp),%rax
  add    %rax,%rbx
  add    $0x8,%r13
  cmp    %r12d,%r14d
  jne    L32
  mov    %r14d,%r12d
L69:
  mov    -0x48(%rbp),%rax
  mov    %r12d,(%rax)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  mov    -0x50(%rbp),%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L72:
  mov    $0x0,%r12d
  jmp    L69
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: %*[][ 
	,:;]%lf%n

assistant: ```c
double *alloc_parse_doubles(int nmax, const char *ss, int *n) {
  int ns = strlen(ss);
  char t[2 + ns], *s = t;
  s[0] = ' ';
  for (int i = 0; i <= ns; i++)
    s[i + 1] = ss[i];
  double *r = (double *)malloc(nmax * sizeof *r);
  int i = 0, w;
  while (i < nmax && 1 == sscanf(s, "%*[][ \n\t,:;]%lf%n", r + i, &w)) {
    i += 1;
    s += w;
  }
  *n = i;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<alloc_parse_doubles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,%rdi
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    0x2(%rax),%ecx
  movslq %ecx,%rcx
  add    $0xf,%rcx
  mov    %rcx,%rdx
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L90
L39:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L39
L90:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L17
L49:
  movb   $0x20,(%rsp)
  mov    %rsp,%rbx
  test   %eax,%eax
  js     L68
  cltq
  lea    0x1(%rsp),%rdi
  mov    %r12,%rsi
  lea    0x1(%rax),%rdx
  call   <memcpy@plt>
L68:
  mov    -0x44(%rbp),%r15d
  lea    0x0(,%r15,8),%edi
  call   <malloc@plt>
  mov    %rax,-0x58(%rbp)
  test   %r15d,%r15d
  jle    L84
  mov    %rax,%r14
  xor    %r15d,%r15d
  lea    -0x3c(%rbp),%r13
  lea    D7(%rip),%r12
  jmp    L95
  nopl   0x0(%rax,%rax,1)
L70:
  movslq -0x3c(%rbp),%rax
  add    $0x1,%r15d
  add    $0x8,%r14
  add    %rax,%rbx
  cmp    %r15d,-0x44(%rbp)
  je     L26
L95:
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L70
L26:
  mov    -0x50(%rbp),%rax
  mov    %r15d,(%rax)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    -0x58(%rbp),%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L17:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L49
L84:
  xor    %r15d,%r15d
  jmp    L26
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: %*[][ 
	,:;]%lf%n

assistant: ```c
double *alloc_parse_doubles(int nmax, const char *ss, int *n) {
  int ns = strlen(ss);
  char t[2 + ns], *s = t;
  s[0] = ' ';
  for (int i = 0; i <= ns; i++)
    s[i + 1] = ss[i];
  double *r = (double *)malloc(nmax * sizeof *r);
  int i = 0, w;
  while (i < nmax && 1 == sscanf(s, "%*[][ \n\t,:;]%lf%n", r + i, &w)) {
    i += 1;
    s += w;
  }
  *n = i;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc_parse_doubles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,%rdi
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    0x2(%rax),%ecx
  movslq %ecx,%rcx
  add    $0xf,%rcx
  mov    %rcx,%rdx
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L18
L60:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L60
L18:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L0
L81:
  movb   $0x20,(%rsp)
  mov    %rsp,%rbx
  test   %eax,%eax
  js     L23
  cltq
  lea    0x1(%rsp),%rdi
  mov    %r12,%rsi
  lea    0x1(%rax),%rdx
  call   <memcpy@plt>
L23:
  mov    -0x44(%rbp),%r15d
  lea    0x0(,%r15,8),%edi
  call   <malloc@plt>
  mov    %rax,-0x58(%rbp)
  test   %r15d,%r15d
  jle    L77
  mov    %rax,%r14
  xor    %r15d,%r15d
  lea    -0x3c(%rbp),%r13
  lea    D2(%rip),%r12
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L94:
  movslq -0x3c(%rbp),%rax
  add    $0x1,%r15d
  add    $0x8,%r14
  add    %rax,%rbx
  cmp    %r15d,-0x44(%rbp)
  je     L46
L34:
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L94
L46:
  mov    -0x50(%rbp),%rax
  mov    %r15d,(%rax)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    -0x58(%rbp),%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L81
L77:
  xor    %r15d,%r15d
  jmp    L46
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string

tool: D2: %*[][ 
	,:;]%lf%n

assistant: ```c
double *alloc_parse_doubles(int nmax, const char *ss, int *n) {
  int ns = strlen(ss);
  char t[2 + ns], *s = t;
  s[0] = ' ';
  for (int i = 0; i <= ns; i++)
    s[i + 1] = ss[i];
  double *r = (double *)malloc(nmax * sizeof *r);
  int i = 0, w;
  while (i < nmax && 1 == sscanf(s, "%*[][ \n\t,:;]%lf%n", r + i, &w)) {
    i += 1;
    s += w;
  }
  *n = i;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readSLEB128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
L4:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  or     %rax,-0x10(%rbp)
  addq   $0x7,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L18
  jmp    L4
L18:
  nop
  cmpq   $0x3f,-0x8(%rbp)
  ja     L7
  mov    -0x14(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L7
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  neg    %eax
  cltq
  or     %rax,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uintptr_t readSLEB128(const uint8_t **data) {
  uintptr_t result = 0;
  uintptr_t shift = 0;
  uint8_t byte = 0;
  while (true) {
    byte = **data;
    (*data)++;
    result |= ((byte & 0x7f) << shift);
    shift += 7;
    if ((byte & 0x80) == 0) {
      break;
    }
  }
  if ((shift < sizeof(result) * 8) && (byte & 0x40)) {
    result |= -(1 << shift);
  }
  return (intptr_t)result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<readSLEB128>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%esi
L14:
  mov    (%rdi),%rax
  mov    (%rax),%edx
  add    $0x4,%rax
  mov    %rax,(%rdi)
  mov    %edx,%eax
  and    $0x7f,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%rsi
  add    $0x7,%rcx
  test   $0x80,%dl
  jne    L14
  cmp    $0x3f,%rcx
  ja     L11
  test   $0x40,%dl
  je     L11
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%rsi
L11:
  mov    %rsi,%rax
  ret
```

assistant: ```c
uintptr_t readSLEB128(const uint8_t **data) {
  uintptr_t result = 0;
  uintptr_t shift = 0;
  uint8_t byte = 0;
  while (true) {
    byte = **data;
    (*data)++;
    result |= ((byte & 0x7f) << shift);
    shift += 7;
    if ((byte & 0x80) == 0) {
      break;
    }
  }
  if ((shift < sizeof(result) * 8) && (byte & 0x40)) {
    result |= -(1 << shift);
  }
  return (intptr_t)result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readSLEB128>:
  endbr64
  mov    (%rdi),%rdx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L2:
  mov    (%rdx),%esi
  add    $0x4,%rdx
  mov    %esi,%eax
  and    $0x7f,%eax
  shl    %cl,%eax
  add    $0x7,%rcx
  cltq
  or     %rax,%r8
  test   $0x80,%sil
  jne    L2
  mov    %rdx,(%rdi)
  cmp    $0x3f,%rcx
  ja     L18
  and    $0x40,%esi
  je     L18
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%r8
L18:
  mov    %r8,%rax
  ret
```

assistant: ```c
uintptr_t readSLEB128(const uint8_t **data) {
  uintptr_t result = 0;
  uintptr_t shift = 0;
  uint8_t byte = 0;
  while (true) {
    byte = **data;
    (*data)++;
    result |= ((byte & 0x7f) << shift);
    shift += 7;
    if ((byte & 0x80) == 0) {
      break;
    }
  }
  if ((shift < sizeof(result) * 8) && (byte & 0x40)) {
    result |= -(1 << shift);
  }
  return (intptr_t)result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readSLEB128>:
  endbr64
  mov    (%rdi),%rdx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L11:
  mov    (%rdx),%esi
  add    $0x4,%rdx
  mov    %esi,%eax
  and    $0x7f,%eax
  shl    %cl,%eax
  add    $0x7,%rcx
  cltq
  or     %rax,%r8
  test   $0x80,%sil
  jne    L11
  mov    %rdx,(%rdi)
  cmp    $0x3f,%rcx
  ja     L20
  and    $0x40,%esi
  je     L20
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%r8
L20:
  mov    %r8,%rax
  ret
```

assistant: ```c
uintptr_t readSLEB128(const uint8_t **data) {
  uintptr_t result = 0;
  uintptr_t shift = 0;
  uint8_t byte = 0;
  while (true) {
    byte = **data;
    (*data)++;
    result |= ((byte & 0x7f) << shift);
    shift += 7;
    if ((byte & 0x80) == 0) {
      break;
    }
  }
  if ((shift < sizeof(result) * 8) && (byte & 0x40)) {
    result |= -(1 << shift);
  }
  return (intptr_t)result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<triad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  movl   $0x10,-0x4(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dumb_compare@plt>
  test   %rax,%rax
  jne    L12
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <FOO1@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L3
L12:
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <FOO2@plt>
  mov    %eax,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
long triad(int len, char *str_arg, char *str_arg2, double *restrict a, double *restrict b, double *restrict c) {
  int i, bytes = 16;
  if (dumb_compare(str_arg, str_arg2) == 0) {
    bytes = FOO1(a, b, c);
  } else {
    bytes = FOO2(a, b, c);
  }
  return bytes;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<triad>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rbx
  mov    %r8,%rbp
  mov    %r9,%r12
  call   <dumb_compare@plt>
  test   %rax,%rax
  jne    L16
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <FOO1@plt>
L9:
  cltq
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <FOO2@plt>
  jmp    L9
```

assistant: ```c
long triad(int len, char *str_arg, char *str_arg2, double *restrict a, double *restrict b, double *restrict c) {
  int i, bytes = 16;
  if (dumb_compare(str_arg, str_arg2) == 0) {
    bytes = FOO1(a, b, c);
  } else {
    bytes = FOO2(a, b, c);
  }
  return bytes;
}
```