ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L12
L68:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L68
  movl   $0x1,-0xc(%rbp)
  jmp    L72
L13:
  cmpl   $0x9,-0xc(%rbp)
  jg     L33
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L0
L33:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L0:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    $0x7,%eax
  jle    L74
  movl   $0x1,-0x14(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
L74:
  addl   $0x1,-0xc(%rbp)
L72:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D62
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string
name: extract_symbolic_data
arguments: label: D50
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D23: Enter number of days in month: 

tool: D62: %d

tool: D14: Enter starting day (1=Sun, ..., 7=Sat): 

tool: D25:    

tool: D50:  %d 

tool: D2: %d 

assistant: ```c
int main() {
  int n = 0, day = 0;
  printf("Enter number of days in month: ");
  scanf("%d", &n);
  printf("Enter starting day (1=Sun, ..., 7=Sat): ");
  scanf("%d", &day);
  printf("\n");
  int i;
  for (i = 1; i < day; i++)
    printf("   ");
  int j;
  for (j = 1; j <= n; j++) {
    j < 10 ? printf(" %d ", j) : printf("%d ", j);
    day++;
    if (day > 7) {
      day = 1;
      printf("\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L80
  mov    $0x1,%ebx
  lea    D4(%rip),%rbp
L58:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L58
L80:
  cmpl   $0x0,(%rsp)
  jle    L32
  mov    $0x1,%ebx
  lea    D18(%rip),%r12
  lea    D37(%rip),%rbp
  jmp    L44
L4:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L33:
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  cmp    $0x7,%eax
  jg     L77
  mov    %eax,0x4(%rsp)
L45:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L32
L44:
  cmp    $0x9,%ebx
  jg     L4
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
L77:
  movl   $0x1,0x4(%rsp)
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L45
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string
name: parse_data
arguments: data_tag: D44
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D37
data_type: string

tool: D14: Enter number of days in month: 

tool: D10: %d

tool: D44: Enter starting day (1=Sun, ..., 7=Sat): 

tool: D4:    

tool: D18: %d 

tool: D37:  %d 

assistant: ```c
int main() {
  int n = 0, day = 0;
  printf("Enter number of days in month: ");
  scanf("%d", &n);
  printf("Enter starting day (1=Sun, ..., 7=Sat): ");
  scanf("%d", &day);
  printf("\n");
  int i;
  for (i = 1; i < day; i++)
    printf("   ");
  int j;
  for (j = 1; j <= n; j++) {
    j < 10 ? printf(" %d ", j) : printf("%d ", j);
    day++;
    if (day > 7) {
      day = 1;
      printf("\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D22(%rip),%rdi
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L86
  mov    $0x1,%ebx
  lea    D31(%rip),%rbp
  nopl   0x0(%rax)
L26:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L26
L86:
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L25
  mov    $0x1,%ebx
  lea    D23(%rip),%r12
  lea    D8(%rip),%rbp
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  cmp    $0x7,%eax
  jg     L90
L47:
  mov    %eax,0x4(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L25
L64:
  mov    %ebx,%esi
  cmp    $0x9,%ebx
  jle    L29
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  cmp    $0x7,%eax
  jle    L47
L90:
  mov    $0xa,%edi
  movl   $0x1,0x4(%rsp)
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,(%rsp)
  jge    L64
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string
name: retrieve_data
arguments: data_tag: D29
datatype: string
name: retrieve_data
arguments: data_tag: D31
datatype: string
name: retrieve_data
arguments: data_tag: D23
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: D22: Enter number of days in month: 

tool: D17: %d

tool: D29: Enter starting day (1=Sun, ..., 7=Sat): 

tool: D31:    

tool: D23: %d 

tool: D8:  %d 

assistant: ```c
int main() {
  int n = 0, day = 0;
  printf("Enter number of days in month: ");
  scanf("%d", &n);
  printf("Enter starting day (1=Sun, ..., 7=Sat): ");
  scanf("%d", &day);
  printf("\n");
  int i;
  for (i = 1; i < day; i++)
    printf("   ");
  int j;
  for (j = 1; j <= n; j++) {
    j < 10 ? printf(" %d ", j) : printf("%d ", j);
    day++;
    if (day > 7) {
      day = 1;
      printf("\n");
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D39(%rip),%rdi
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L88
  mov    $0x1,%ebx
  lea    D10(%rip),%rbp
  nopl   0x0(%rax)
L37:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L37
L88:
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L17
  mov    $0x1,%ebx
  lea    D52(%rip),%r12
  lea    D6(%rip),%rbp
  nopl   (%rax)
L76:
  mov    %ebx,%esi
  cmp    $0x9,%ebx
  jg     L25
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  cmp    $0x7,%eax
  jg     L59
L73:
  mov    %eax,0x4(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L76
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  cmp    $0x7,%eax
  jle    L73
L59:
  mov    $0xa,%edi
  movl   $0x1,0x4(%rsp)
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,(%rsp)
  jge    L76
  jmp    L17
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D39
data_type: string
name: read_data
arguments: label: D2
data_type: string
name: read_data
arguments: label: D11
data_type: string
name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D52
data_type: string
name: read_data
arguments: label: D6
data_type: string

tool: D39: Enter number of days in month: 

tool: D2: %d

tool: D11: Enter starting day (1=Sun, ..., 7=Sat): 

tool: D10:    

tool: D52: %d 

tool: D6:  %d 

assistant: ```c
int main() {
  int n = 0, day = 0;
  printf("Enter number of days in month: ");
  scanf("%d", &n);
  printf("Enter starting day (1=Sun, ..., 7=Sat): ");
  scanf("%d", &day);
  printf("\n");
  int i;
  for (i = 1; i < day; i++)
    printf("   ");
  int j;
  for (j = 1; j <= n; j++) {
    j < 10 ? printf(" %d ", j) : printf("%d ", j);
    day++;
    if (day > 7) {
      day = 1;
      printf("\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hxf_to_ihfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %esi,-0x428(%rbp)
  mov    %edx,-0x42c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x42c(%rbp),%eax
  lea    0x1ff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x9,%eax
  mov    %eax,-0x418(%rbp)
  mov    -0x42c(%rbp),%eax
  cltd
  shr    $0x17,%edx
  add    %edx,%eax
  and    $0x1ff,%eax
  sub    %edx,%eax
  mov    %eax,-0x414(%rbp)
  movl   $0x0,-0x41c(%rbp)
  jmp    L17
L23:
  lea    -0x410(%rbp),%rcx
  mov    -0x424(%rbp),%eax
  mov    $0x200,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  lea    -0x410(%rbp),%rcx
  mov    -0x428(%rbp),%eax
  mov    $0x200,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  addl   $0x1,-0x41c(%rbp)
L17:
  mov    -0x41c(%rbp),%eax
  cmp    -0x418(%rbp),%eax
  jl     L23
  cmpl   $0x0,-0x414(%rbp)
  jle    L5
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    -0x424(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    -0x428(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    $0x200,%eax
  sub    -0x414(%rbp),%eax
  mov    %eax,%edx
  lea    -0x210(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x200,%eax
  sub    -0x414(%rbp),%eax
  mov    %eax,%edx
  lea    -0x210(%rbp),%rcx
  mov    -0x428(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
L5:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
void hxf_to_ihfs(int hxf_img, int ihfs_img, int filesize) {
  char buf[512];
  char ff[512];
  int i, n, rem;
  n = filesize / 512;
  rem = filesize % 512;
  for (i = 0; i < n; ++i) {
    read(hxf_img, buf, 512);
    write(ihfs_img, buf, 512);
  }
  if (rem > 0) {
    read(hxf_img, buf, rem);
    write(ihfs_img, buf, rem);
    memset(ff, 0xff, 512 - rem);
    write(ihfs_img, ff, 512 - rem);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<hxf_to_ihfs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x1ff(%rdx),%r12d
  test   %edx,%edx
  cmovns %edx,%r12d
  sar    $0x9,%r12d
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x17,%eax
  lea    (%rdx,%rax,1),%r15d
  and    $0x1ff,%r15d
  sub    %eax,%r15d
  cmp    $0x1ff,%edx
  jle    L44
  mov    $0x0,%ebx
  mov    %rsp,%rbp
L3:
  mov    $0x200,%edx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  mov    $0x200,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jg     L3
L44:
  test   %r15d,%r15d
  jg     L7
L24:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    %rsp,%rbx
  mov    %r15d,%edx
  mov    %rbx,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  mov    %r15d,%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    $0x200,%ebx
  sub    %r15d,%ebx
  lea    0x200(%rsp),%rbp
  mov    %ebx,%edx
  mov    $0xff,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  jmp    L24
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hxf_to_ihfs(int hxf_img, int ihfs_img, int filesize) {
  char buf[512];
  char ff[512];
  int i, n, rem;
  n = filesize / 512;
  rem = filesize % 512;
  for (i = 0; i < n; ++i) {
    read(hxf_img, buf, 512);
    write(ihfs_img, buf, 512);
  }
  if (rem > 0) {
    read(hxf_img, buf, rem);
    write(ihfs_img, buf, rem);
    memset(ff, 0xff, 512 - rem);
    write(ihfs_img, ff, 512 - rem);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<hxf_to_ihfs>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  lea    0x1ff(%rdx),%r12d
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  mov    %edx,%eax
  cmovns %edx,%r12d
  sar    $0x1f,%eax
  shr    $0x17,%eax
  lea    (%rdx,%rax,1),%r15d
  sar    $0x9,%r12d
  and    $0x1ff,%r15d
  sub    %eax,%r15d
  cmp    $0x1ff,%edx
  jle    L9
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x200,%edx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  add    $0x1,%ebx
  call   <read@plt>
  mov    $0x200,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %ebx,%r12d
  jg     L1
L9:
  test   %r15d,%r15d
  jle    L20
  mov    %rsp,%rbp
  mov    %r15d,%edx
  mov    %r14d,%edi
  mov    $0x200,%r12d
  mov    %rbp,%rsi
  sub    %r15d,%r12d
  call   <read@plt>
  mov    %rbp,%rsi
  mov    %r15d,%edx
  mov    %r13d,%edi
  call   <write@plt>
  lea    0x200(%rsp),%rbp
  mov    %r12d,%edx
  mov    $0xff,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
L20:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hxf_to_ihfs(int hxf_img, int ihfs_img, int filesize) {
  char buf[512];
  char ff[512];
  int i, n, rem;
  n = filesize / 512;
  rem = filesize % 512;
  for (i = 0; i < n; ++i) {
    read(hxf_img, buf, 512);
    write(ihfs_img, buf, 512);
  }
  if (rem > 0) {
    read(hxf_img, buf, rem);
    write(ihfs_img, buf, rem);
    memset(ff, 0xff, 512 - rem);
    write(ihfs_img, ff, 512 - rem);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hxf_to_ihfs>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  lea    0x1ff(%rdx),%r12d
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  mov    %edx,%eax
  cmovns %edx,%r12d
  sar    $0x1f,%eax
  shr    $0x17,%eax
  lea    (%rdx,%rax,1),%r15d
  sar    $0x9,%r12d
  and    $0x1ff,%r15d
  sub    %eax,%r15d
  cmp    $0x1ff,%edx
  jle    L19
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x200,%edx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  add    $0x1,%ebx
  call   <read@plt>
  mov    $0x200,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %ebx,%r12d
  jg     L20
L19:
  test   %r15d,%r15d
  jle    L31
  mov    %rsp,%rbp
  mov    %r15d,%edx
  mov    %r14d,%edi
  mov    $0x200,%r12d
  mov    %rbp,%rsi
  sub    %r15d,%r12d
  call   <read@plt>
  mov    %rbp,%rsi
  mov    %r15d,%edx
  mov    %r13d,%edi
  call   <write@plt>
  lea    0x200(%rsp),%rbp
  mov    %r12d,%edx
  mov    $0xff,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
L31:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hxf_to_ihfs(int hxf_img, int ihfs_img, int filesize) {
  char buf[512];
  char ff[512];
  int i, n, rem;
  n = filesize / 512;
  rem = filesize % 512;
  for (i = 0; i < n; ++i) {
    read(hxf_img, buf, 512);
    write(ihfs_img, buf, 512);
  }
  if (rem > 0) {
    read(hxf_img, buf, rem);
    write(ihfs_img, buf, rem);
    memset(ff, 0xff, 512 - rem);
    write(ihfs_img, ff, 512 - rem);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nmiISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L3:
  jmp    L3
```

assistant: ```c
void nmiISR(void) {
  while (1) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nmiISR>:
  endbr64
L1:
  jmp    L1
```

assistant: ```c
void nmiISR(void) {
  while (1) {
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nmiISR>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
void nmiISR(void) {
  while (1) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nmiISR>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
void nmiISR(void) {
  while (1) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D34(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L0:
  mov    -0x24(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  D17(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movq   D7(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  D60(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  jbe    L20
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  nop
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  jmp    L28
L20:
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L0
L28:
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D34
type_infered: f64
name: unpack_data
arguments: label: D6
type_infered: string
name: unpack_data
arguments: label: D68
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: byte[8]
name: unpack_data
arguments: label: D7
type_infered: qword
name: unpack_data
arguments: label: D60
type_infered: f64
name: unpack_data
arguments: label: D26
type_infered: string

tool: D34: 1

tool: D6: Enter  a positive number: 

tool: D68: %d

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D7: 9223372036854775807

tool: D60: 1e-05

tool: D26: Square root: %f


assistant: ```c
int main(void) {
  int x;
  double y = 1;
  double new_y;
  double z;
  printf("Enter  a positive number: ");
  scanf("%d", &x);
  for (;;) {
    z = x / y;
    new_y = (y + z) / 2;
    if (fabs(new_y - y) < (y * 0.00001)) {
      y = new_y;
      break;
    } else {
      y = new_y;
    }
  }
  printf("Square root: %f\n", y);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm6,%xmm6
  cvtsi2sdl 0x4(%rsp),%xmm6
  movsd  D69(%rip),%xmm0
  movsd  D41(%rip),%xmm5
  movq   D37(%rip),%xmm4
  movsd  D63(%rip),%xmm3
L7:
  movapd %xmm0,%xmm1
  movapd %xmm6,%xmm2
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm0
  mulsd  %xmm5,%xmm0
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  andpd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm1
  comisd %xmm2,%xmm1
  jbe    L7
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D59
type: string
name: unpack_data
arguments: tag: D35
type: string
name: unpack_data
arguments: tag: D69
type: f64
name: unpack_data
arguments: tag: D41
type: byte[8]
name: unpack_data
arguments: tag: D37
type: qword
name: unpack_data
arguments: tag: D63
type: f64
name: unpack_data
arguments: tag: D30
type: string

tool: D59: Enter  a positive number: 

tool: D35: %d

tool: D69: 1

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D37: 9223372036854775807

tool: D63: 1e-05

tool: D30: Square root: %f


assistant: ```c
int main(void) {
  int x;
  double y = 1;
  double new_y;
  double z;
  printf("Enter  a positive number: ");
  scanf("%d", &x);
  for (;;) {
    z = x / y;
    new_y = (y + z) / 2;
    if (fabs(new_y - y) < (y * 0.00001)) {
      y = new_y;
      break;
    } else {
      y = new_y;
    }
  }
  printf("Square root: %f\n", y);
}
```