ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L60:
  cmp    %rcx,%rsp
  je     L117
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L60
L117:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L102
  orq    $0x0,-0x8(%rsp,%rax,1)
L102:
  mov    %rsp,%r13
  test   %edx,%edx
  jle    L24
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D21(%rip),%r14
L99:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x2c(%rbp)
  jg     L99
L24:
  mov    -0x2c(%rbp),%esi
  lea    -0x1(%rsi),%edi
  test   %edi,%edi
  jle    L112
  mov    $0x0,%ebx
  lea    D1(%rip),%r12
L29:
  lea    0x1(%rbx),%eax
  cmp    %eax,%esi
  jle    L26
  mov    0x0(%r13,%rbx,4),%edx
  lea    0x0(%r13,%rbx,4),%rax
  lea    -0x2(%rsi),%ecx
  sub    %ebx,%ecx
  add    %rbx,%rcx
  lea    0x4(%r13,%rcx,4),%rcx
L5:
  cmp    0x4(%rax),%edx
  je     L76
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L5
L26:
  sub    $0x2,%esi
  cmp    %ebx,%esi
  je     L66
L44:
  mov    -0x2c(%rbp),%esi
  lea    -0x1(%rsi),%edi
  add    $0x1,%rbx
  cmp    %ebx,%edi
  jg     L29
  jmp    L112
L76:
  lea    D17(%rip),%rdi
  call   <printf@plt>
L112:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L66:
  movslq %edi,%rdi
  mov    0x0(%r13,%rdi,4),%eax
  cmp    %eax,0x0(%r13,%rbx,4)
  je     L44
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L44
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D21
datatype: string
name: retrieve_data
arguments: tag: D1
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D21: %d

tool: D1: NO

tool: D17: YES

assistant: ```c
int main() {
  int n, j, p, i, k = 0;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (j = 0; j < n - 1; j++) {
    for (p = j + 1; p < n; p++) {
      if (a[j] == a[p]) {
        k = 1;
        printf("YES");
        break;
      }
    }
    if (k == 1) {
      break;
    }
    if ((j == n - 2) && (a[j] != a[n - 1]))
      printf("NO");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L44
L95:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L95
L44:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L113
L126:
  mov    %rsp,%r13
  test   %edx,%edx
  jle    L114
  mov    %r13,%r12
  xor    %ebx,%ebx
  nop
L165:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  cmp    %ebx,%edx
  jg     L165
L114:
  lea    -0x1(%rdx),%edi
  xor    %ebx,%ebx
  lea    D6(%rip),%r12
  test   %edi,%edi
  jle    L104
L108:
  lea    0x1(%rbx),%eax
  lea    -0x2(%rdx),%r8d
  cmp    %eax,%edx
  jle    L147
  lea    -0x2(%rdx),%r8d
  mov    0x0(%r13,%rbx,4),%ecx
  lea    0x0(%r13,%rbx,4),%rax
  mov    %r8d,%esi
  sub    %ebx,%esi
  add    %rbx,%rsi
  lea    0x4(%r13,%rsi,4),%rsi
  jmp    L152
  nopl   0x0(%rax)
L32:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L147
L152:
  cmp    0x4(%rax),%ecx
  jne    L32
  lea    D25(%rip),%rdi
  call   <printf@plt>
L104:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L100
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L147:
  cmp    %ebx,%r8d
  je     L80
L70:
  lea    -0x1(%rdx),%edi
  add    $0x1,%rbx
  cmp    %ebx,%edi
  jg     L108
  jmp    L104
L80:
  movslq %edi,%rdi
  mov    0x0(%r13,%rdi,4),%eax
  cmp    %eax,0x0(%r13,%rbx,4)
  je     L70
  mov    %r12,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  jmp    L70
L113:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L126
L100:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
type: string
name: read_data
arguments: data_tag: D6
type: string
name: read_data
arguments: data_tag: D25
type: string

tool: D14: %d

tool: D6: NO

tool: D25: YES

assistant: ```c
int main() {
  int n, j, p, i, k = 0;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (j = 0; j < n - 1; j++) {
    for (p = j + 1; p < n; p++) {
      if (a[j] == a[p]) {
        k = 1;
        printf("YES");
        break;
      }
    }
    if (k == 1) {
      break;
    }
    if ((j == n - 2) && (a[j] != a[n - 1]))
      printf("NO");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D24(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L153
L61:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L61
L153:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L159
L15:
  mov    %rsp,%r13
  test   %edx,%edx
  jle    L79
  mov    %r13,%r12
  xor    %ebx,%ebx
  nop
L0:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  cmp    %ebx,%edx
  jg     L0
L79:
  lea    -0x1(%rdx),%edi
  xor    %ebx,%ebx
  lea    D21(%rip),%r12
  test   %edi,%edi
  jle    L161
L64:
  lea    0x1(%rbx),%eax
  lea    -0x2(%rdx),%r8d
  cmp    %eax,%edx
  jle    L73
  lea    -0x2(%rdx),%r8d
  mov    0x0(%r13,%rbx,4),%ecx
  lea    0x0(%r13,%rbx,4),%rax
  mov    %r8d,%esi
  sub    %ebx,%esi
  add    %rbx,%rsi
  lea    0x4(%r13,%rsi,4),%rsi
  jmp    L30
  nopl   0x0(%rax)
L122:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L73
L30:
  cmp    0x4(%rax),%ecx
  jne    L122
  lea    D29(%rip),%rdi
  call   <printf@plt>
L161:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L146
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L73:
  cmp    %ebx,%r8d
  je     L46
L9:
  lea    -0x1(%rdx),%edi
  add    $0x1,%rbx
  cmp    %ebx,%edi
  jg     L64
  jmp    L161
L46:
  movslq %edi,%rdi
  mov    0x0(%r13,%rdi,4),%eax
  cmp    %eax,0x0(%r13,%rbx,4)
  je     L9
  mov    %r12,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  jmp    L9
L159:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L15
L146:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D24
type: string
name: unpack_data
arguments: label: D21
type: string
name: unpack_data
arguments: label: D29
type: string

tool: D24: %d

tool: D21: NO

tool: D29: YES

assistant: ```c
int main() {
  int n, j, p, i, k = 0;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (j = 0; j < n - 1; j++) {
    for (p = j + 1; p < n; p++) {
      if (a[j] == a[p]) {
        k = 1;
        printf("YES");
        break;
      }
    }
    if (k == 1) {
      break;
    }
    if ((j == n - 2) && (a[j] != a[n - 1]))
      printf("NO");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aligned_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0xf,%eax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L19:
  movdqa (%rax),%xmm6
  pcmpistri $0x3a,%xmm6,%xmm6
  jb     L11
  add    $0x10,%rax
  jmp    L19
L11:
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
int aligned_strlen(const char *const s) {
  assert(((unsigned long)s & 0x0F) == 0);
  const char *p = s;
  __asm__ __volatile__("\n1:\n"
                       "\tmovdqa (%0),%%xmm6\n"
                       "\tpcmpistri $0x3a,%%xmm6,%%xmm6\n"
                       "\tjc 2f\n"
                       "\tadd $0x10,%0\n"
                       "\tjmp 1b\n"
                       "2:\n"
                       "\tadd %%rcx,%0\n"
                       : "=p"(p)
                       : "0"(p)
                       : "xmm6", "rcx", "cc", "memory");
  return p - s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aligned_strlen>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   $0xf,%dil
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %rbx,%rax
L19:
  movdqa (%rax),%xmm6
  pcmpistri $0x3a,%xmm6,%xmm6
  jb     L5
  add    $0x10,%rax
  jmp    L19
L5:
  add    %rcx,%rax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int aligned_strlen(const char *const s) {
  assert(((unsigned long)s & 0x0F) == 0);
  const char *p = s;
  __asm__ __volatile__("\n1:\n"
                       "\tmovdqa (%0),%%xmm6\n"
                       "\tpcmpistri $0x3a,%%xmm6,%%xmm6\n"
                       "\tjc 2f\n"
                       "\tadd $0x10,%0\n"
                       "\tjmp 1b\n"
                       "2:\n"
                       "\tadd %%rcx,%0\n"
                       : "=p"(p)
                       : "0"(p)
                       : "xmm6", "rcx", "cc", "memory");
  return p - s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aligned_strlen>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   $0xf,%bl
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    %rbx,%rax
L15:
  movdqa (%rax),%xmm6
  pcmpistri $0x3a,%xmm6,%xmm6
  jb     L18
  add    $0x10,%rax
  jmp    L15
L18:
  add    %rcx,%rax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int aligned_strlen(const char *const s) {
  assert(((unsigned long)s & 0x0F) == 0);
  const char *p = s;
  __asm__ __volatile__("\n1:\n"
                       "\tmovdqa (%0),%%xmm6\n"
                       "\tpcmpistri $0x3a,%%xmm6,%%xmm6\n"
                       "\tjc 2f\n"
                       "\tadd $0x10,%0\n"
                       "\tjmp 1b\n"
                       "2:\n"
                       "\tadd %%rcx,%0\n"
                       : "=p"(p)
                       : "0"(p)
                       : "xmm6", "rcx", "cc", "memory");
  return p - s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aligned_strlen>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   $0xf,%bl
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    %rbx,%rax
L12:
  movdqa (%rax),%xmm6
  pcmpistri $0x3a,%xmm6,%xmm6
  jb     L17
  add    $0x10,%rax
  jmp    L12
L17:
  add    %rcx,%rax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int aligned_strlen(const char *const s) {
  assert(((unsigned long)s & 0x0F) == 0);
  const char *p = s;
  __asm__ __volatile__("\n1:\n"
                       "\tmovdqa (%0),%%xmm6\n"
                       "\tpcmpistri $0x3a,%%xmm6,%%xmm6\n"
                       "\tjc 2f\n"
                       "\tadd $0x10,%0\n"
                       "\tjmp 1b\n"
                       "2:\n"
                       "\tadd %%rcx,%0\n"
                       : "=p"(p)
                       : "0"(p)
                       : "xmm6", "rcx", "cc", "memory");
  return p - s;
}
```
user: What is the c source code of the assembly code below:

```asm
<glyph_name_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <glyph_name_to_unicode@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <unicode_string_to_hex@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *glyph_name_to_hex(const char *glyph_name) {
  unsigned int *unicode_string;
  char *hex_string;
  unicode_string = glyph_name_to_unicode(glyph_name);
  hex_string = unicode_string_to_hex(unicode_string);
  free(unicode_string);
  return hex_string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<glyph_name_to_hex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <glyph_name_to_unicode@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <unicode_string_to_hex@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *glyph_name_to_hex(const char *glyph_name) {
  unsigned int *unicode_string;
  char *hex_string;
  unicode_string = glyph_name_to_unicode(glyph_name);
  hex_string = unicode_string_to_hex(unicode_string);
  free(unicode_string);
  return hex_string;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<glyph_name_to_hex>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <glyph_name_to_unicode@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <unicode_string_to_hex@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *glyph_name_to_hex(const char *glyph_name) {
  unsigned int *unicode_string;
  char *hex_string;
  unicode_string = glyph_name_to_unicode(glyph_name);
  hex_string = unicode_string_to_hex(unicode_string);
  free(unicode_string);
  return hex_string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<glyph_name_to_hex>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <glyph_name_to_unicode@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <unicode_string_to_hex@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *glyph_name_to_hex(const char *glyph_name) {
  unsigned int *unicode_string;
  char *hex_string;
  unicode_string = glyph_name_to_unicode(glyph_name);
  hex_string = unicode_string_to_hex(unicode_string);
  free(unicode_string);
  return hex_string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcmp1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    $0x0,%eax
  jmp    L5
L11:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp1(char *s, char *t) {
  int i;
  for (i = 0; s[i] == t[i]; i++)
    if (s[i] == '\0')
      return 0;
  return s[i] - t[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcmp1>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L6
  mov    $0x1,%eax
L0:
  test   %dl,%dl
  je     L3
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L0
L6:
  movsbl %dl,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strcmp1(char *s, char *t) {
  int i;
  for (i = 0; s[i] == t[i]; i++)
    if (s[i] == '\0')
      return 0;
  return s[i] - t[i];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcmp1>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L18
  mov    $0x1,%eax
  jmp    L38
  nopl   (%rax)
L12:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L18
L38:
  test   %dl,%dl
  jne    L12
  xor    %eax,%eax
  ret
L18:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp1(char *s, char *t) {
  int i;
  for (i = 0; s[i] == t[i]; i++)
    if (s[i] == '\0')
      return 0;
  return s[i] - t[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcmp1>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L30
  mov    $0x1,%eax
  jmp    L10
  nopl   (%rax)
L6:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L30
L10:
  test   %dl,%dl
  jne    L6
  xor    %eax,%eax
  ret
L30:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp1(char *s, char *t) {
  int i;
  for (i = 0; s[i] == t[i]; i++)
    if (s[i] == '\0')
      return 0;
  return s[i] - t[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cp_pname_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void cp_pname_field(char *dest, const char *src) {
  ++src;
  strcpy(dest, src);
  int i = 0;
  while (src[i] != '\0') {
    dest[i] = src[i];
    ++i;
  }
  dest[i - 1] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<cp_pname_field>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rsi
  call   <strcpy@plt>
  movzbl 0x1(%rbp),%edx
  test   %dl,%dl
  je     L19
  mov    $0x0,%eax
L24:
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  movzbl 0x1(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L24
L10:
  movb   $0x0,-0x1(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
void cp_pname_field(char *dest, const char *src) {
  ++src;
  strcpy(dest, src);
  int i = 0;
  while (src[i] != '\0') {
    dest[i] = src[i];
    ++i;
  }
  dest[i - 1] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cp_pname_field>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  add    $0x1,%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strcpy@plt>
  movzbl 0x1(%rbp),%edx
  test   %dl,%dl
  je     L10
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %dl,(%rbx,%rax,1)
  mov    %rax,%rcx
  add    $0x1,%rax
  movzbl 0x1(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L11
  movb   $0x0,(%rbx,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    $0xffffffffffffffff,%rcx
  movb   $0x0,(%rbx,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cp_pname_field(char *dest, const char *src) {
  ++src;
  strcpy(dest, src);
  int i = 0;
  while (src[i] != '\0') {
    dest[i] = src[i];
    ++i;
  }
  dest[i - 1] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cp_pname_field>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  add    $0x1,%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strcpy@plt>
  movzbl 0x1(%rbp),%edx
  test   %dl,%dl
  je     L15
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %dl,(%rbx,%rax,1)
  mov    %rax,%rcx
  add    $0x1,%rax
  movzbl 0x1(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L7
  movb   $0x0,(%rbx,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    $0xffffffffffffffff,%rcx
  movb   $0x0,(%rbx,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cp_pname_field(char *dest, const char *src) {
  ++src;
  strcpy(dest, src);
  int i = 0;
  while (src[i] != '\0') {
    dest[i] = src[i];
    ++i;
  }
  dest[i - 1] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<upper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  jmp    L15
L14:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L17
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
L17:
  add    $0x1,%rbx
L15:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L14
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
upper(s) register char *s;
{
  while (*s != '\0') {
    if (islower(*s))
      *s = toupper(*s);
    s++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<upper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L15
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L36
L15:
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L20
  mov    %ebx,%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp)
  jmp    L20
```

assistant: ```c
upper(s) register char *s;
{
  while (*s != '\0') {
    if (islower(*s))
      *s = toupper(*s);
    s++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<upper>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L28
  nopl   (%rax)
L0:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L29
  mov    %ebp,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
L29:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L0
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
upper(s) register char *s;
{
  while (*s != '\0') {
    if (islower(*s))
      *s = toupper(*s);
    s++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<upper>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L29
  nopl   (%rax)
L31:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L3
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L31
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L31
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
upper(s) register char *s;
{
  while (*s != '\0') {
    if (islower(*s))
      *s = toupper(*s);
    s++;
  }
}
```