user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%r12
  lea    0xc(%rsp),%rbp
  lea    D20(%rip),%rbx
L73:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  lea    -0x1(%rdx),%eax
  cmp    $0xe,%eax
  ja     L73
  test   $0x1,%dl
  je     L73
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rcx
  mov    $0x0,%esi
L186:
  mov    $0x0,%eax
L60:
  movl   $0x0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L60
  add    $0x1,%esi
  add    $0x40,%rcx
  cmp    %esi,%edx
  jg     L186
  test   %edx,%edx
  mov    $0x1,%ecx
  cmovg  %edx,%ecx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  cltq
  movl   $0x1,0x10(%rsp,%rax,4)
  mov    %edx,%r9d
  imul   %edx,%r9d
  cmp    $0x1,%r9d
  jle    L149
  mov    $0x1,%edi
  mov    $0x0,%r10d
  jmp    L163
L123:
  lea    -0x1(%rdx),%ecx
  mov    %eax,%esi
  test   %r8d,%r8d
  js     L23
  mov    %r8d,%ecx
  cmp    %eax,%edx
  cmovle %r10d,%eax
  mov    %eax,%esi
L23:
  movslq %esi,%r8
  movslq %ecx,%rax
  shl    $0x4,%rax
  add    %r8,%rax
  cmpl   $0x0,0x10(%rsp,%rax,4)
  jne    L14
  movslq %ecx,%rax
  shl    $0x4,%rax
  add    %r8,%rax
  mov    %edi,0x10(%rsp,%rax,4)
L83:
  add    $0x1,%edi
  cmp    %r9d,%edi
  je     L149
L163:
  lea    -0x1(%rcx),%r8d
  lea    0x1(%rsi),%eax
  cmp    %eax,%edx
  jg     L123
  add    $0x1,%ecx
  test   %r8d,%r8d
  jns    L123
  jmp    L23
L14:
  add    $0x2,%ecx
  sub    $0x1,%esi
  movslq %esi,%r8
  movslq %ecx,%rax
  shl    $0x4,%rax
  add    %r8,%rax
  mov    %edi,0x10(%rsp,%rax,4)
  jmp    L83
L149:
  mov    $0x0,%r13d
  lea    D23(%rip),%r12
  jmp    L189
L179:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L179
L173:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    $0x40,%rbp
  cmp    %r13d,0xc(%rsp)
  jle    L131
L189:
  mov    $0x0,%ebx
  cmpl   $0x0,0xc(%rsp)
  jg     L179
  jmp    L173
L131:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string
name: disassemble_data
arguments: data_tag: D20
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string

tool: D4: enter n(n=1 to 15):

tool: D20: %d

tool: D23: %4d

assistant: ```c
void main() {
  int a[16][16], i, j, k, n, p;
  p = 1;
  while (p == 1) {
    printf("enter n(n=1 to 15):");
    scanf("%d", &n);
    if ((n > 0) && (n < 16) && (n % 2 != 0))
      p = 0;
  }
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      a[i][j] = 0;
  j = n / 2;
  a[0][j] = 1;
  for (k = 1; k < n * n; k++) {
    i = i - 1;
    j = j + 1;
    if ((i < 0) && (j > n - 1)) {
      i = i + 2;
      j = j - 1;
    } else {
      if (i < 0)
        i = n - 1;
      if (j > n - 1)
        j = 0;
    }
    if (a[i][j] == 0)
      a[i][j] = k;
    else {
      i = i + 2;
      j = j - 1;
      a[i][j] = k;
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++)
      printf("%4d", a[i][j]);
    printf("\n");
  }
}
```