user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D22(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L3
  xor    %ebx,%ebx
  lea    0x50(%rsp),%r12
  lea    0x10(%rsp),%r15
  lea    0x90(%rsp),%r14
  lea    0x8f(%rsp),%rbp
  nopl   0x0(%rax)
L60:
  mov    %r12,%rdx
  mov    %r15,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jge    L85
  lea    0x0(%r13,%r13,1),%esi
  xor    %edi,%edi
  test   %esi,%esi
  jle    L65
L110:
  xor    %eax,%eax
  nopl   0x0(%rax)
L30:
  movzbl (%r15,%rax,1),%edx
  mov    %dl,(%r14,%rax,2)
  movzbl (%r12,%rax,1),%edx
  mov    %dl,0x1(%r14,%rax,2)
  add    $0x1,%rax
  lea    (%rax,%rax,1),%edx
  cmp    %edx,%esi
  jg     L30
  lea    -0x1(%rsi),%eax
  mov    $0x1,%edx
  shr    %eax
  add    $0x1,%eax
  test   %esi,%esi
  cmovg  %eax,%edx
  add    %eax,%eax
  test   %esi,%esi
  mov    $0x2,%esi
  cmovg  %eax,%esi
  mov    %esi,%r9d
  cmp    $0x1,%edi
  je     L165
  cmp    $0xffffffff,%edi
  je     L39
L197:
  movslq %edx,%rdx
  movzbl 0x50(%rsp,%rdx,1),%edi
  test   %dil,%dil
  je     L179
  lea    0x1(%rsi),%eax
  movslq %esi,%rsi
  sub    %rsi,%rdx
  cltq
  add    %r12,%rdx
  nopl   0x0(%rax)
L86:
  mov    %dil,0x0(%rbp,%rax,1)
  mov    %eax,%r9d
  add    $0x1,%rax
  movzbl -0x1(%rdx,%rax,1),%edi
  test   %dil,%dil
  jne    L86
L165:
  movslq %r9d,%rax
  mov    %r14,%rsi
  lea    D37(%rip),%rdi
  add    $0x1,%ebx
  movb   $0x0,0x90(%rsp,%rax,1)
  call   <printf@plt>
  lea    D16(%rip),%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L60
L3:
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L142
  add    $0x108,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  lea    (%rax,%rax,1),%esi
  jle    L5
  mov    $0xffffffff,%edi
  test   %esi,%esi
  jg     L110
  xor    %edx,%edx
  xor    %esi,%esi
  cs nopw 0x0(%rax,%rax,1)
L39:
  movslq %edx,%rdx
  movzbl 0x10(%rsp,%rdx,1),%r10d
  test   %r10b,%r10b
  je     L179
  lea    0x1(%rsi),%edi
  movslq %esi,%rsi
  sub    %rsi,%rdx
  movslq %edi,%rdi
  add    %r15,%rdx
  nopl   (%rax)
L4:
  mov    %r10b,0x0(%rbp,%rdi,1)
  mov    %edi,%r9d
  add    $0x1,%rdi
  movzbl -0x1(%rdx,%rdi,1),%r10d
  test   %r10b,%r10b
  jne    L4
  jmp    L165
  nopl   0x0(%rax)
L5:
  test   %esi,%esi
  jle    L53
  mov    $0x1,%edi
  jmp    L110
L179:
  mov    %esi,%r9d
  jmp    L165
L65:
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    L197
L53:
  xor    %r9d,%r9d
  jmp    L165
L142:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
type: string
name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D37
type: string
name: retrieve_data
arguments: tag: D16
type: string

tool: D22: %d

tool: D7: %s%s

tool: D37: %s


tool: 

assistant: ```c
int main() {
  int N, Cont, I, J, TamResult, TamStr1, TamStr2, Bolean;
  char string1[53], string2[53], Result[102];
  scanf("%d", &N);
  for (Cont = 0; Cont < N; Cont++) {
    scanf("%s%s", string1, string2);
    TamStr1 = strlen(string1);
    TamStr2 = strlen(string2);
    Bolean = 0;
    if (TamStr1 < TamStr2)
      TamResult = TamStr1 * 2;
    else {
      if (TamStr1 > TamStr2) {
        TamResult = TamStr2 * 2;
        Bolean = -1;
      } else {
        TamResult = TamStr2 * 2;
        Bolean = 1;
      }
    }
    J = 0;
    for (I = 0; I < TamResult; I = I + 2) {
      Result[I] = string1[J];
      Result[I + 1] = string2[J];
      J++;
    }
    if (Bolean == 0 || Bolean == -1) {
      if (Bolean == -1)
        for (J = J; string1[J] != '\0'; J++) {
          Result[I] = string1[J];
          I++;
        }
      else
        for (J = J; string2[J] != '\0'; J++) {
          Result[I] = string2[J];
          I++;
        }
    }
    Result[I] = '\0';
    printf("%s\n", Result);
    strcpy(Result, "");
  }
  return 0;
}
```