ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matrix_multiply_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x54(%rbp)
  mov    %esi,-0x58(%rbp)
  mov    %edx,-0x5c(%rbp)
  mov    %rcx,-0x68(%rbp)
  mov    %r8,-0x70(%rbp)
  mov    %r9,-0x78(%rbp)
  mov    -0x58(%rbp),%edx
  movslq %edx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x38(%rbp)
  movslq %edx,%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    -0x5c(%rbp),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %eax,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x44(%rbp)
  jmp    L16
L3:
  movl   $0x0,-0x3c(%rbp)
  jmp    L59
L55:
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x78(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rdi,%rsi,4)
  movl   $0x0,-0x40(%rbp)
  jmp    L5
L18:
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x78(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm1
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x68(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm2
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x70(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x78(%rbp),%rsi
  add    %rsi,%rdi
  addss  %xmm1,%xmm0
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  movss  %xmm0,(%rdi,%rsi,4)
  addl   $0x1,-0x40(%rbp)
L5:
  mov    -0x40(%rbp),%esi
  cmp    -0x58(%rbp),%esi
  jl     L18
  addl   $0x1,-0x3c(%rbp)
L59:
  mov    -0x3c(%rbp),%esi
  cmp    -0x5c(%rbp),%esi
  jl     L55
  addl   $0x1,-0x44(%rbp)
L16:
  mov    -0x44(%rbp),%esi
  cmp    -0x54(%rbp),%esi
  jl     L3
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void matrix_multiply_float(int l, int m, int n, float A[l][m], float B[m][n], float C[l][n]) {
  int i, j, k;
  for (i = 0; i < l; ++i)
    for (k = 0; k < n; ++k) {
      C[i][k] = 0;
      for (j = 0; j < m; ++j) {
        C[i][k] = C[i][k] + A[i][j] * B[k][j];
      }
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matrix_multiply_float>:
  endbr64
  test   %edi,%edi
  jle    L72
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    %r8,%r14
  movslq %esi,%rcx
  movslq %edx,%r11
  shl    $0x2,%r11
  lea    -0x1(%rdx),%eax
  lea    0x4(%r9,%rax,4),%r10
  shl    $0x2,%rcx
  mov    %rcx,-0x10(%rsp)
  mov    $0x0,%r15d
  not    %rax
  shl    $0x2,%rax
  mov    %rax,-0x8(%rsp)
  mov    %esi,%edi
  jmp    L15
L74:
  mov    %r8,%rdx
  movl   $0x0,(%r8)
  test   %ebp,%ebp
  jle    L52
  mov    %r9,%rcx
  mov    $0x0,%eax
L47:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rcx,%rax,4),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L47
L52:
  add    $0x4,%r8
  add    %r11,%r9
  cmp    %r10,%r8
  jne    L74
L57:
  add    $0x1,%r15d
  add    %r11,%r10
  add    -0x10(%rsp),%r13
  cmp    %r15d,%ebx
  je     L19
L15:
  mov    %r13,%rsi
  mov    -0x8(%rsp),%rax
  lea    (%rax,%r10,1),%r8
  mov    %r14,%r9
  test   %r12d,%r12d
  jg     L74
  jmp    L57
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  ret
```

assistant: ```c
void matrix_multiply_float(int l, int m, int n, float A[l][m], float B[m][n], float C[l][n]) {
  int i, j, k;
  for (i = 0; i < l; ++i)
    for (k = 0; k < n; ++k) {
      C[i][k] = 0;
      for (j = 0; j < m; ++j) {
        C[i][k] = C[i][k] + A[i][j] * B[k][j];
      }
    }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<matrix_multiply_float>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jle    L55
  mov    %edx,%ebp
  movslq %esi,%rdi
  mov    %r9,%rdx
  mov    $0xfffffffffffffffc,%r12
  lea    -0x1(%rbp),%eax
  movslq %ebp,%r9
  mov    %r8,%r13
  mov    %rdi,%r10
  shl    $0x2,%rax
  mov    %rcx,%rsi
  shl    $0x2,%r9
  xor    %r11d,%r11d
  lea    0x4(%rdx,%rax,1),%r8
  lea    0x0(,%rdi,4),%r14
  pxor   %xmm2,%xmm2
  sub    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L27:
  lea    (%r12,%r8,1),%rdx
  mov    %r13,%rcx
  test   %ebp,%ebp
  jle    L0
  nopl   0x0(%rax,%rax,1)
L56:
  movl   $0x0,(%rdx)
  xor    %eax,%eax
  movaps %xmm2,%xmm1
  test   %r10d,%r10d
  jle    L15
  nopl   0x0(%rax,%rax,1)
L9:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rcx,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %rdi,%rax
  jne    L9
L15:
  add    $0x4,%rdx
  add    %r9,%rcx
  cmp    %r8,%rdx
  jne    L56
L0:
  add    $0x1,%r11d
  add    %r9,%r8
  add    %r14,%rsi
  cmp    %r11d,%ebx
  jne    L27
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void matrix_multiply_float(int l, int m, int n, float A[l][m], float B[m][n], float C[l][n]) {
  int i, j, k;
  for (i = 0; i < l; ++i)
    for (k = 0; k < n; ++k) {
      C[i][k] = 0;
      for (j = 0; j < m; ++j) {
        C[i][k] = C[i][k] + A[i][j] * B[k][j];
      }
    }
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix_multiply_float>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0xc(%rsp)
  mov    %r8,-0x8(%rsp)
  test   %edi,%edi
  jle    L48
  movslq %edx,%r12
  test   %r12d,%r12d
  jle    L48
  movslq %esi,%rdi
  mov    %r9,%rbp
  mov    %rcx,%rsi
  xor    %r11d,%r11d
  mov    %rdi,%r10
  lea    -0x1(%r12),%r14d
  pxor   %xmm2,%xmm2
  xor    %ebx,%ebx
  lea    0x0(,%rdi,4),%r15
  lea    0x0(,%r12,4),%r9
  lea    0x4(%rbp),%r13
  nopl   0x0(%rax)
L1:
  lea    (%r14,%r11,1),%rax
  mov    -0x8(%rsp),%rcx
  lea    0x0(%rbp,%r11,4),%rdx
  lea    0x0(%r13,%rax,4),%r8
  nopl   0x0(%rax,%rax,1)
L41:
  movl   $0x0,(%rdx)
  xor    %eax,%eax
  movaps %xmm2,%xmm1
  test   %r10d,%r10d
  jle    L52
  nopl   0x0(%rax,%rax,1)
L29:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rcx,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %rax,%rdi
  jne    L29
L52:
  add    $0x4,%rdx
  add    %r9,%rcx
  cmp    %r8,%rdx
  jne    L41
  add    $0x1,%ebx
  add    %r15,%rsi
  add    %r12,%r11
  cmp    %ebx,-0xc(%rsp)
  jne    L1
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrix_multiply_float(int l, int m, int n, float A[l][m], float B[m][n], float C[l][n]) {
  int i, j, k;
  for (i = 0; i < l; ++i)
    for (k = 0; k < n; ++k) {
      C[i][k] = 0;
      for (j = 0; j < m; ++j) {
        C[i][k] = C[i][k] + A[i][j] * B[k][j];
      }
    }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<col_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L7:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jg     L7
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *col_dup(const char *src) {
  char *dst;
  int length = 0;
  while (src[length] > 31)
    length++;
  dst = malloc(length + 1);
  strncpy(dst, src, length);
  dst[length] = 0;
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<col_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmpb   $0x1f,(%rdi)
  jle    L9
  mov    $0x1,%eax
L10:
  mov    %eax,%ebp
  mov    %rax,%r12
  add    $0x1,%rax
  cmpb   $0x1f,-0x1(%rbx,%rax,1)
  jg     L10
L16:
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%r12,1)
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L16
```

assistant: ```c
char *col_dup(const char *src) {
  char *dst;
  int length = 0;
  while (src[length] > 31)
    length++;
  dst = malloc(length + 1);
  strncpy(dst, src, length);
  dst[length] = 0;
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<col_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x1f,(%rdi)
  jle    L14
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rax,%rbx
  mov    %eax,%r12d
  cmpb   $0x1f,0x0(%rbp,%rbx,1)
  lea    0x1(%rbx),%rax
  jg     L27
  lea    0x1(%r12),%edi
L12:
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    $0x1,%edi
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L12
```

assistant: ```c
char *col_dup(const char *src) {
  char *dst;
  int length = 0;
  while (src[length] > 31)
    length++;
  dst = malloc(length + 1);
  strncpy(dst, src, length);
  dst[length] = 0;
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<col_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x1f,(%rdi)
  jle    L22
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rax,%rbx
  mov    %eax,%r12d
  cmpb   $0x1f,0x0(%rbp,%rbx,1)
  lea    0x1(%rbx),%rax
  jg     L10
  lea    0x1(%r12),%edi
L11:
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    $0x1,%edi
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L11
```

assistant: ```c
char *col_dup(const char *src) {
  char *dst;
  int length = 0;
  while (src[length] > 31)
    length++;
  dst = malloc(length + 1);
  strncpy(dst, src, length);
  dst[length] = 0;
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %esi,-0x22c(%rbp)
  mov    %edx,-0x230(%rbp)
  mov    %ecx,-0x234(%rbp)
  mov    %r8,-0x240(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x240(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    $0x0,%ecx
  lea    D12(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x240(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <open_file@plt>
  mov    %rax,-0x218(%rbp)
  mov    -0x22c(%rbp),%eax
  cltq
  mov    %eax,%edx
  mov    -0x230(%rbp),%eax
  cltq
  imul   %edx,%eax
  mov    -0x234(%rbp),%edx
  movslq %edx,%rdx
  imul   %edx,%eax
  shl    $0x3,%eax
  mov    %eax,%esi
  mov    -0x218(%rbp),%rdx
  mov    -0x228(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string

tool: D12: %s%06d.dat

tool: D6: w

tool: D28: Subdivision de %s OK


assistant: ```c
void output(double *q, int nx, int ny, int nz, char *name) {
  FILE *f;
  char filename[512];
  int i, j, k;
  sprintf(filename, "%s%06d.dat", name, 0);
  f = open_file(name, 0, "w");
  fwrite(q, sizeof(double) * nx * ny * nz, 1, f);
  printf("Subdivision de %s OK\n", filename);
  fclose(f);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<output>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%r12
  mov    %esi,%r14d
  mov    %edx,%ebx
  mov    %ecx,%r15d
  mov    %r8,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    $0x0,%ecx
  mov    %r8,%rdx
  lea    D20(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  lea    D21(%rip),%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <open_file@plt>
  mov    %rax,%rbp
  imul   %r15d,%ebx
  imul   %r14d,%ebx
  lea    0x0(,%rbx,8),%esi
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    %r12,%rdi
  call   <fwrite@plt>
  mov    %r13,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D20
datatype: string
name: unpack_data
arguments: data_label: D21
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string

tool: D20: %s%06d.dat

tool: D21: w

tool: D5: Subdivision de %s OK


assistant: ```c
void output(double *q, int nx, int ny, int nz, char *name) {
  FILE *f;
  char filename[512];
  int i, j, k;
  sprintf(filename, "%s%06d.dat", name, 0);
  f = open_file(name, 0, "w");
  fwrite(q, sizeof(double) * nx * ny * nz, 1, f);
  printf("Subdivision de %s OK\n", filename);
  fclose(f);
}
```
user: What is the c source code of the assembly code below?

```asm
<output>:
  endbr64
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  xor    %ecx,%ecx
  push   %r13
  mov    %esi,%r13d
  lea    D17(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %r8,%rdx
  imul   %r14d,%ebx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  imul   %r13d,%ebx
  mov    %r15,%rdi
  call   <sprintf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  lea    D4(%rip),%rdx
  call   <open_file@plt>
  lea    0x0(,%rbx,8),%esi
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <fwrite@plt>
  lea    D18(%rip),%rdi
  mov    %r15,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string

tool: D17: %s%06d.dat

tool: D4: w

tool: D18: Subdivision de %s OK


assistant: ```c
void output(double *q, int nx, int ny, int nz, char *name) {
  FILE *f;
  char filename[512];
  int i, j, k;
  sprintf(filename, "%s%06d.dat", name, 0);
  f = open_file(name, 0, "w");
  fwrite(q, sizeof(double) * nx * ny * nz, 1, f);
  printf("Subdivision de %s OK\n", filename);
  fclose(f);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<output>:
  endbr64
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  xor    %ecx,%ecx
  push   %r13
  mov    %esi,%r13d
  lea    D13(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %r8,%rdx
  imul   %r14d,%ebx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  imul   %r13d,%ebx
  mov    %r15,%rdi
  call   <sprintf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  lea    D26(%rip),%rdx
  call   <open_file@plt>
  lea    0x0(,%rbx,8),%esi
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <fwrite@plt>
  lea    D29(%rip),%rdi
  mov    %r15,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D13
data_type: string
name: read_data
arguments: data_label: D26
data_type: string
name: read_data
arguments: data_label: D29
data_type: string

tool: D13: %s%06d.dat

tool: D26: w

tool: D29: Subdivision de %s OK


assistant: ```c
void output(double *q, int nx, int ny, int nz, char *name) {
  FILE *f;
  char filename[512];
  int i, j, k;
  sprintf(filename, "%s%06d.dat", name, 0);
  f = open_file(name, 0, "w");
  fwrite(q, sizeof(double) * nx * ny * nz, 1, f);
  printf("Subdivision de %s OK\n", filename);
  fclose(f);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__strsep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L26
L20:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L106
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L121
L106:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L43
  movq   $0x0,-0x10(%rbp)
  jmp    L62
L43:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x11(%rbp)
  jne    L91
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L62
L91:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  movq   $0x0,-0x10(%rbp)
  jmp    L62
L8:
  movsbl -0x11(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L62
L121:
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x10(%rbp)
L62:
  cmpq   $0x0,-0x10(%rbp)
  je     L31
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L52
L31:
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
L52:
  mov    -0x8(%rbp),%rax
L26:
  leave
  ret
```

assistant: ```c
char *__strsep(char **stringp, const char *delim) {
  char *begin, *end;
  begin = *stringp;
  if (begin == NULL)
    return NULL;
  if (delim[0] == '\0' || delim[1] == '\0') {
    char ch = delim[0];
    if (ch == '\0')
      end = NULL;
    else {
      if (*begin == ch)
        end = begin;
      else if (*begin == '\0')
        end = NULL;
      else
        end = strchr(begin + 1, ch);
    }
  } else
    end = strpbrk(begin, delim);
  if (end) {
    *end++ = '\0';
    *stringp = end;
  } else
    *stringp = NULL;
  return begin;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__strsep>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  test   %rbp,%rbp
  je     L35
  mov    %rdi,%rbx
  movzbl (%rsi),%eax
  test   %al,%al
  je     L21
  cmpb   $0x0,0x1(%rsi)
  jne    L11
  movzbl 0x0(%rbp),%edx
  cmp    %dl,%al
  je     L65
  test   %dl,%dl
  jne    L59
L21:
  movq   $0x0,(%rbx)
L35:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L59:
  movsbl %al,%esi
  lea    0x1(%rbp),%rdi
  call   <strchr@plt>
  jmp    L17
L11:
  mov    %rbp,%rdi
  call   <strpbrk@plt>
L17:
  test   %rax,%rax
  je     L21
L31:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,(%rbx)
  jmp    L35
L65:
  mov    %rbp,%rax
  jmp    L31
```

assistant: ```c
char *__strsep(char **stringp, const char *delim) {
  char *begin, *end;
  begin = *stringp;
  if (begin == NULL)
    return NULL;
  if (delim[0] == '\0' || delim[1] == '\0') {
    char ch = delim[0];
    if (ch == '\0')
      end = NULL;
    else {
      if (*begin == ch)
        end = begin;
      else if (*begin == '\0')
        end = NULL;
      else
        end = strchr(begin + 1, ch);
    }
  } else
    end = strpbrk(begin, delim);
  if (end) {
    *end++ = '\0';
    *stringp = end;
  } else
    *stringp = NULL;
  return begin;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__strsep>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r12
  test   %r12,%r12
  je     L33
  movzbl (%rsi),%eax
  mov    %rdi,%rbx
  test   %al,%al
  je     L51
  cmpb   $0x0,0x1(%rsi)
  je     L72
  mov    %r12,%rdi
  call   <strpbrk@plt>
L58:
  test   %rax,%rax
  je     L51
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,(%rbx)
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L72:
  movzbl (%r12),%edx
  cmp    %dl,%al
  je     L62
  test   %dl,%dl
  jne    L43
L51:
  movq   $0x0,(%rbx)
L33:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  movsbl %al,%esi
  lea    0x1(%r12),%rdi
  call   <strchr@plt>
  jmp    L58
  nop
L62:
  mov    %r12,%rax
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,(%rbx)
  jmp    L15
```

assistant: ```c
char *__strsep(char **stringp, const char *delim) {
  char *begin, *end;
  begin = *stringp;
  if (begin == NULL)
    return NULL;
  if (delim[0] == '\0' || delim[1] == '\0') {
    char ch = delim[0];
    if (ch == '\0')
      end = NULL;
    else {
      if (*begin == ch)
        end = begin;
      else if (*begin == '\0')
        end = NULL;
      else
        end = strchr(begin + 1, ch);
    }
  } else
    end = strpbrk(begin, delim);
  if (end) {
    *end++ = '\0';
    *stringp = end;
  } else
    *stringp = NULL;
  return begin;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__strsep>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r12
  test   %r12,%r12
  je     L14
  movzbl (%rsi),%eax
  mov    %rdi,%rbx
  test   %al,%al
  je     L15
  cmpb   $0x0,0x1(%rsi)
  je     L22
  mov    %r12,%rdi
  call   <strpbrk@plt>
L25:
  test   %rax,%rax
  je     L15
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,(%rbx)
L43:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L22:
  movzbl (%r12),%edx
  cmp    %dl,%al
  je     L58
  test   %dl,%dl
  jne    L1
L15:
  movq   $0x0,(%rbx)
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movsbl %al,%esi
  lea    0x1(%r12),%rdi
  call   <strchr@plt>
  jmp    L25
  nop
L58:
  mov    %r12,%rax
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,(%rbx)
  jmp    L43
```

assistant: ```c
char *__strsep(char **stringp, const char *delim) {
  char *begin, *end;
  begin = *stringp;
  if (begin == NULL)
    return NULL;
  if (delim[0] == '\0' || delim[1] == '\0') {
    char ch = delim[0];
    if (ch == '\0')
      end = NULL;
    else {
      if (*begin == ch)
        end = begin;
      else if (*begin == '\0')
        end = NULL;
      else
        end = strchr(begin + 1, ch);
    }
  } else
    end = strpbrk(begin, delim);
  if (end) {
    *end++ = '\0';
    *stringp = end;
  } else
    *stringp = NULL;
  return begin;
}
```