ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<name_to_uid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L21
  mov    %rdi,%rbx
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    %rax,%rcx
  cmp    $0xffffffffffffffff,%rax
  je     L10
  lea    0xf(%rax),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L113:
  cmp    %rdx,%rsp
  je     L22
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L113
L22:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L9
  orq    $0x0,-0x8(%rsp,%rax,1)
L9:
  lea    -0x24(%rbp),%rsi
  lea    -0x20(%rbp),%r8
  mov    %rsp,%rdx
  mov    %rbx,%rdi
  call   <getpwnam_r@plt>
  test   %rax,%rax
  jne    L86
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L119
  mov    (%rax),%eax
L12:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L101
  mov    -0x8(%rbp),%rbx
  leave
  ret
L21:
  mov    $0xffffffff,%eax
  jmp    L12
L10:
  mov    $0xffffffff,%eax
  jmp    L12
L86:
  mov    $0xffffffff,%eax
  jmp    L12
L119:
  mov    $0xffffffff,%eax
  jmp    L12
L101:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uid_t name_to_uid(char const *name) {
  if (!name) {
    return -1;
  }
  long const buflen = sysconf(_SC_GETPW_R_SIZE_MAX);
  if (buflen == -1) {
    return -1;
  }
  char buf[buflen];
  struct passwd pwbuf, *pwbufp;
  if (0 != getpwnam_r(name, &pwbuf, buf, buflen, &pwbufp) || !pwbufp) {
    return -1;
  }
  return pwbufp->pw_uid;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<name_to_uid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L78
  mov    D4(%rip),%rax
  mov    %rdi,%r12
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    %rax,%rcx
  cmp    $0xffffffffffffffff,%rax
  je     L78
  lea    0xf(%rax),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L54
L64:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L64
L54:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L56
L76:
  lea    -0x24(%rbp),%rsi
  lea    -0x20(%rbp),%r8
  mov    %rsp,%rdx
  mov    %r12,%rdi
  call   <getpwnam_r@plt>
  test   %rax,%rax
  jne    L78
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L78
  mov    (%rax),%eax
L41:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L78:
  mov    $0xffffffff,%eax
  jmp    L41
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uid_t name_to_uid(char const *name) {
  if (!name) {
    return -1;
  }
  long const buflen = sysconf(_SC_GETPW_R_SIZE_MAX);
  if (buflen == -1) {
    return -1;
  }
  char buf[buflen];
  struct passwd pwbuf, *pwbufp;
  if (0 != getpwnam_r(name, &pwbuf, buf, buflen, &pwbufp) || !pwbufp) {
    return -1;
  }
  return pwbufp->pw_uid;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<name_to_uid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L67
  mov    D7(%rip),%rax
  mov    %rdi,%r12
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    %rax,%rcx
  cmp    $0xffffffffffffffff,%rax
  je     L67
  lea    0xf(%rax),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L97
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L4
L97:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L12
L88:
  lea    -0x24(%rbp),%rsi
  lea    -0x20(%rbp),%r8
  mov    %rsp,%rdx
  mov    %r12,%rdi
  call   <getpwnam_r@plt>
  test   %rax,%rax
  jne    L67
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L67
  mov    (%rax),%eax
L86:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L94
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L67:
  mov    $0xffffffff,%eax
  jmp    L86
L94:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uid_t name_to_uid(char const *name) {
  if (!name) {
    return -1;
  }
  long const buflen = sysconf(_SC_GETPW_R_SIZE_MAX);
  if (buflen == -1) {
    return -1;
  }
  char buf[buflen];
  struct passwd pwbuf, *pwbufp;
  if (0 != getpwnam_r(name, &pwbuf, buf, buflen, &pwbufp) || !pwbufp) {
    return -1;
  }
  return pwbufp->pw_uid;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Readable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L57:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L20
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L20
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L73
L20:
  nop
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L57
L73:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L77
  movl   $0x0,-0x8(%rbp)
  jmp    L113
L77:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x23,-0x9(%rbp)
  je     L109
  cmpb   $0xa,-0x9(%rbp)
  je     L109
  cmpb   $0x0,-0x9(%rbp)
  je     L109
  cmpb   $0xd,-0x9(%rbp)
  je     L109
  movl   $0x1,-0x8(%rbp)
  jmp    L113
L109:
  movl   $0x0,-0x8(%rbp)
L113:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Readable(const char *cmdstr) {
  int readable;
  int i;
  char ch;
  for (i = 0; i < strlen(cmdstr); i++) {
    if (cmdstr[i] == 32 || cmdstr[i] == '\t' || cmdstr[i] == ' ') {
      continue;
    } else {
      break;
    }
  }
  if (i >= strlen(cmdstr)) {
    readable = 0;
  } else {
    ch = cmdstr[i];
    if (ch != '#' && ch != '\n' && ch != '\0' && ch != '\r') {
      readable = 1;
    } else {
      readable = 0;
    }
  }
  return readable;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Readable>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L15:
  mov    %ebx,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L34
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    $0x9,%al
  je     L15
  cmp    $0x20,%al
  je     L15
L34:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %r12d,%edx
  jle    L19
  movslq %r12d,%r12
  movzbl 0x0(%rbp,%r12,1),%ecx
  mov    $0x1,%eax
  cmp    $0x23,%cl
  ja     L8
  movabs $0x800002401,%rax
  shr    %cl,%rax
  xor    $0x1,%rax
  and    $0x1,%eax
L8:
  movzbl %al,%eax
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Readable(const char *cmdstr) {
  int readable;
  int i;
  char ch;
  for (i = 0; i < strlen(cmdstr); i++) {
    if (cmdstr[i] == 32 || cmdstr[i] == '\t' || cmdstr[i] == ' ') {
      continue;
    } else {
      break;
    }
  }
  if (i >= strlen(cmdstr)) {
    readable = 0;
  } else {
    ch = cmdstr[i];
    if (ch != '#' && ch != '\n' && ch != '\0' && ch != '\r') {
      readable = 1;
    } else {
      readable = 0;
    }
  }
  return readable;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Readable>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L12:
  mov    %rbp,%rdi
  movslq %ebx,%r12
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L48
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L12
  cmp    $0x9,%al
  je     L12
L48:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r12d,%r8d
  jle    L22
  movzbl 0x0(%rbp,%r12,1),%ecx
  mov    $0x1,%eax
  cmp    $0x23,%cl
  ja     L22
  movabs $0xfffffff7ffffdbfe,%rax
  sar    %cl,%rax
  and    $0x1,%eax
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Readable(const char *cmdstr) {
  int readable;
  int i;
  char ch;
  for (i = 0; i < strlen(cmdstr); i++) {
    if (cmdstr[i] == 32 || cmdstr[i] == '\t' || cmdstr[i] == ' ') {
      continue;
    } else {
      break;
    }
  }
  if (i >= strlen(cmdstr)) {
    readable = 0;
  } else {
    ch = cmdstr[i];
    if (ch != '#' && ch != '\n' && ch != '\0' && ch != '\r') {
      readable = 1;
    } else {
      readable = 0;
    }
  }
  return readable;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Readable>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L16:
  mov    %rbp,%rdi
  movslq %ebx,%r12
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L42
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L16
  cmp    $0x9,%al
  je     L16
L42:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r12d,%r8d
  jle    L2
  movzbl 0x0(%rbp,%r12,1),%ecx
  mov    $0x1,%eax
  cmp    $0x23,%cl
  ja     L2
  movabs $0xfffffff7ffffdbfe,%rax
  sar    %cl,%rax
  and    $0x1,%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Readable(const char *cmdstr) {
  int readable;
  int i;
  char ch;
  for (i = 0; i < strlen(cmdstr); i++) {
    if (cmdstr[i] == 32 || cmdstr[i] == '\t' || cmdstr[i] == ' ') {
      continue;
    } else {
      break;
    }
  }
  if (i >= strlen(cmdstr)) {
    readable = 0;
  } else {
    ch = cmdstr[i];
    if (ch != '#' && ch != '\n' && ch != '\0' && ch != '\r') {
      readable = 1;
    } else {
      readable = 0;
    }
  }
  return readable;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<merge>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%r14d
  mov    %ecx,%ebp
  lea    0x1(%rdx),%r13d
  lea    0x4(,%rcx,4),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    %r14d,%r12d
  jg     L61
  cmp    %ebp,%r13d
  jg     L61
  movslq %r12d,%rax
  lea    (%rdi,%rax,4),%rdx
  mov    %r12d,%ecx
  mov    %r12d,%eax
  jmp    L134
L30:
  add    $0x1,%r13d
  mov    %esi,(%rdx)
L99:
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %r14d,%eax
  jg     L44
  cmp    %ebp,%r13d
  jg     L44
L134:
  movslq %eax,%rsi
  mov    (%rbx,%rsi,4),%r8d
  movslq %r13d,%rsi
  mov    (%rbx,%rsi,4),%esi
  cmp    %esi,%r8d
  jg     L30
  add    $0x1,%eax
  mov    %r8d,(%rdx)
  jmp    L99
L61:
  mov    %r12d,%ecx
  mov    %r12d,%eax
L44:
  cmp    %eax,%r14d
  jl     L15
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rdx
  sub    %eax,%r14d
  add    %rcx,%r14
  lea    0x4(%rdi,%r14,4),%rsi
  cltq
  sub    %rcx,%rax
  lea    (%rbx,%rax,4),%rcx
  sub    %rdi,%rcx
L89:
  mov    (%rcx,%rdx,1),%eax
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L89
  jmp    L43
L15:
  cmp    %r13d,%ebp
  jl     L43
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  mov    %ebp,%edx
  sub    %r13d,%edx
  add    %rcx,%rdx
  lea    0x4(%rdi,%rdx,4),%rsi
  movslq %r13d,%r13
  sub    %rcx,%r13
  lea    (%rbx,%r13,4),%rcx
  sub    %rdi,%rcx
L11:
  mov    (%rcx,%rax,1),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L11
L43:
  cmp    %ebp,%r12d
  jg     L138
  movslq %r12d,%rdx
  lea    (%rdi,%rdx,4),%rax
  sub    %r12d,%ebp
  lea    0x1(%rdx,%rbp,1),%rdx
  lea    (%rdi,%rdx,4),%rcx
  sub    %rdi,%rbx
L133:
  mov    (%rax),%edx
  mov    %edx,(%rbx,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L133
L138:
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void merge(int arr[], int left, int mid, int right) {
  int fIdx = left;
  int rIdx = mid + 1;
  int i;
  int *sortArr = (int *)malloc(sizeof(int) * (right + 1));
  int sIdx = left;
  while (fIdx <= mid && rIdx <= right) {
    if (arr[fIdx] <= arr[rIdx])
      sortArr[sIdx] = arr[fIdx++];
    else
      sortArr[sIdx] = arr[rIdx++];
    sIdx++;
  }
  if (fIdx > mid) {
    for (i = rIdx; i <= right; i++, sIdx++)
      sortArr[sIdx] = arr[i];
  } else {
    for (i = fIdx; i <= mid; i++, sIdx++)
      sortArr[sIdx] = arr[i];
  }
  for (i = left; i <= right; i++) {
    arr[i] = sortArr[i];
  }
  free(sortArr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<merge>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x4(,%rcx,4),%edi
  push   %rbx
  lea    0x1(%rdx),%ebx
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    %r13d,%ebx
  jg     L11
  cmp    %r14d,%r12d
  jg     L11
  movslq %r12d,%rax
  mov    %r12d,%esi
  lea    (%rdi,%rax,4),%rcx
  mov    %r12d,%eax
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L83:
  add    $0x1,%eax
  mov    %edx,(%rcx)
  add    $0x1,%esi
  add    $0x4,%rcx
  cmp    %r14d,%eax
  jg     L84
L37:
  cmp    %r13d,%ebx
  jg     L84
L66:
  movslq %eax,%rdx
  movslq %ebx,%r8
  mov    0x0(%rbp,%rdx,4),%edx
  mov    0x0(%rbp,%r8,4),%r8d
  cmp    %r8d,%edx
  jle    L83
  mov    %r8d,%edx
  add    $0x1,%ebx
  add    $0x1,%esi
  add    $0x4,%rcx
  mov    %edx,-0x4(%rcx)
  cmp    %r14d,%eax
  jle    L37
L84:
  cmp    %eax,%r14d
  jge    L103
  cmp    %ebx,%r13d
  jl     L110
  mov    %r13d,%eax
  movslq %esi,%rsi
  sub    %ebx,%eax
  lea    0x0(,%rsi,4),%rcx
  add    %rsi,%rax
  lea    (%rdi,%rcx,1),%rdx
  lea    0x4(%rdi,%rax,4),%rsi
  movslq %ebx,%rax
  shl    $0x2,%rax
  sub    %rcx,%rax
  sub    %rdi,%rax
  add    %rbp,%rax
  nopl   0x0(%rax)
L77:
  mov    (%rax,%rdx,1),%ecx
  add    $0x4,%rdx
  mov    %ecx,-0x4(%rdx)
  cmp    %rdx,%rsi
  jne    L77
L110:
  cmp    %r13d,%r12d
  jg     L57
  movslq %r12d,%rdx
  sub    %r12d,%r13d
  sub    %rdi,%rbp
  lea    (%rdi,%rdx,4),%rax
  lea    0x1(%rdx,%r13,1),%rdx
  lea    (%rdi,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L109:
  mov    (%rax),%edx
  mov    %edx,0x0(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L109
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <free@plt>
  nopl   0x0(%rax)
L103:
  movslq %esi,%rsi
  sub    %eax,%r14d
  cltq
  lea    0x0(,%rsi,4),%rcx
  shl    $0x2,%rax
  add    %rsi,%r14
  sub    %rcx,%rax
  lea    (%rcx,%rdi,1),%rdx
  lea    0x4(%rdi,%r14,4),%rsi
  sub    %rdi,%rax
  add    %rbp,%rax
  nopl   0x0(%rax)
L19:
  mov    (%rax,%rdx,1),%ecx
  add    $0x4,%rdx
  mov    %ecx,-0x4(%rdx)
  cmp    %rsi,%rdx
  jne    L19
  jmp    L110
  nopl   0x0(%rax)
L11:
  mov    %r12d,%esi
  mov    %r12d,%eax
  jmp    L84
```

assistant: ```c
void merge(int arr[], int left, int mid, int right) {
  int fIdx = left;
  int rIdx = mid + 1;
  int i;
  int *sortArr = (int *)malloc(sizeof(int) * (right + 1));
  int sIdx = left;
  while (fIdx <= mid && rIdx <= right) {
    if (arr[fIdx] <= arr[rIdx])
      sortArr[sIdx] = arr[fIdx++];
    else
      sortArr[sIdx] = arr[rIdx++];
    sIdx++;
  }
  if (fIdx > mid) {
    for (i = rIdx; i <= right; i++, sIdx++)
      sortArr[sIdx] = arr[i];
  } else {
    for (i = fIdx; i <= mid; i++, sIdx++)
      sortArr[sIdx] = arr[i];
  }
  for (i = left; i <= right; i++) {
    arr[i] = sortArr[i];
  }
  free(sortArr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<disable_irq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    $0x21,%edi
  call   <inb@plt>
  mov    %al,-0x2(%rbp)
  mov    $0xa1,%edi
  call   <inb@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x7,-0x14(%rbp)
  jbe    L5
  movzbl -0x14(%rbp),%eax
  sub    $0x8,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  or     %edx,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0xa1,%edi
  call   <outb@plt>
  jmp    L8
L5:
  movzbl -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  movzbl -0x2(%rbp),%eax
  or     %edx,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x21,%edi
  call   <outb@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void disable_irq(unsigned char irq) {
  unsigned char mask_master, mask_slave;
  mask_master = inb(0x21);
  mask_slave = inb(0xa1);
  if (irq > 7) {
    outb(0xa1, mask_slave | (1 << (irq - 8)));
  } else {
    outb(0x21, mask_master | (1 << irq));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<disable_irq>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x21,%edi
  call   <inb@plt>
  mov    %eax,%ebp
  mov    $0xa1,%edi
  call   <inb@plt>
  cmp    $0x7,%bl
  jbe    L1
  lea    -0x8(%rbx),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  or     %edx,%eax
  movzbl %al,%esi
  mov    $0xa1,%edi
  call   <outb@plt>
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  or     %ebp,%eax
  movzbl %al,%esi
  mov    $0x21,%edi
  call   <outb@plt>
  jmp    L13
```

assistant: ```c
void disable_irq(unsigned char irq) {
  unsigned char mask_master, mask_slave;
  mask_master = inb(0x21);
  mask_slave = inb(0xa1);
  if (irq > 7) {
    outb(0xa1, mask_slave | (1 << (irq - 8)));
  } else {
    outb(0x21, mask_master | (1 << irq));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<disable_irq>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x21,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <inb@plt>
  mov    $0xa1,%edi
  mov    %eax,%ebx
  call   <inb@plt>
  movzbl %bpl,%ecx
  cmp    $0x7,%bpl
  jbe    L8
  sub    $0x8,%ecx
  mov    $0x1,%edx
  add    $0x8,%rsp
  mov    $0xa1,%edi
  shl    %cl,%edx
  pop    %rbx
  pop    %rbp
  or     %edx,%eax
  movzbl %al,%esi
  jmp    1070 <outb@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%eax
  add    $0x8,%rsp
  mov    $0x21,%edi
  shl    %cl,%eax
  or     %eax,%ebx
  movzbl %bl,%esi
  pop    %rbx
  pop    %rbp
  jmp    1070 <outb@plt>
```

assistant: ```c
void disable_irq(unsigned char irq) {
  unsigned char mask_master, mask_slave;
  mask_master = inb(0x21);
  mask_slave = inb(0xa1);
  if (irq > 7) {
    outb(0xa1, mask_slave | (1 << (irq - 8)));
  } else {
    outb(0x21, mask_master | (1 << irq));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<disable_irq>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x21,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <inb@plt>
  mov    $0xa1,%edi
  mov    %eax,%ebx
  call   <inb@plt>
  movzbl %bpl,%ecx
  cmp    $0x7,%bpl
  jbe    L8
  sub    $0x8,%ecx
  mov    $0x1,%edx
  add    $0x8,%rsp
  mov    $0xa1,%edi
  shl    %cl,%edx
  pop    %rbx
  pop    %rbp
  or     %edx,%eax
  movzbl %al,%esi
  jmp    1070 <outb@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%eax
  add    $0x8,%rsp
  mov    $0x21,%edi
  shl    %cl,%eax
  or     %eax,%ebx
  movzbl %bl,%esi
  pop    %rbx
  pop    %rbp
  jmp    1070 <outb@plt>
```

assistant: ```c
void disable_irq(unsigned char irq) {
  unsigned char mask_master, mask_slave;
  mask_master = inb(0x21);
  mask_slave = inb(0xa1);
  if (irq > 7) {
    outb(0xa1, mask_slave | (1 << (irq - 8)));
  } else {
    outb(0x21, mask_master | (1 << irq));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_ln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L0:
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int string_ln(char *p) {
  int count = 0;
  while (*p != '\0') {
    count++;
    p++;
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_ln>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    %rdi,%rax
  mov    $0x1,%edx
  sub    %edi,%edx
L7:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L7
L16:
  mov    %ecx,%eax
  ret
L1:
  mov    $0x0,%ecx
  jmp    L16
```

assistant: ```c
int string_ln(char *p) {
  int count = 0;
  while (*p != '\0') {
    count++;
    p++;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_ln>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L0
  mov    $0x1,%eax
  sub    %edi,%eax
L3:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L3
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L0:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int string_ln(char *p) {
  int count = 0;
  while (*p != '\0') {
    count++;
    p++;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_ln>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L17
  mov    $0x1,%eax
  sub    %edi,%eax
L2:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L2
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int string_ln(char *p) {
  int count = 0;
  while (*p != '\0') {
    count++;
    p++;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<otrl_base64_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L4:
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <encodeblock@plt>
  addq   $0x4,-0x18(%rbp)
  addq   $0x4,-0x8(%rbp)
  addq   $0x3,-0x20(%rbp)
  subq   $0x3,-0x28(%rbp)
L10:
  cmpq   $0x2,-0x28(%rbp)
  ja     L4
  cmpq   $0x0,-0x28(%rbp)
  je     L29
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <encodeblock@plt>
  addq   $0x4,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t otrl_base64_encode(char *base64data, const unsigned char *data, size_t datalen) {
  size_t base64len = 0;
  while (datalen > 2) {
    encodeblock(base64data, data, 3);
    base64data += 4;
    base64len += 4;
    data += 3;
    datalen -= 3;
  }
  if (datalen > 0) {
    encodeblock(base64data, data, datalen);
    base64len += 4;
  }
  return base64len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<otrl_base64_encode>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  cmp    $0x2,%rdx
  jbe    L9
  mov    $0x0,%r13d
L3:
  mov    $0x3,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <encodeblock@plt>
  add    $0x4,%rbp
  add    $0x4,%r13
  add    $0x3,%r12
  sub    $0x3,%rbx
  cmp    $0x2,%rbx
  ja     L3
L30:
  test   %rbx,%rbx
  jne    L15
L10:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0x0,%r13d
  jmp    L30
L15:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <encodeblock@plt>
  add    $0x4,%r13
  jmp    L10
```

assistant: ```c
size_t otrl_base64_encode(char *base64data, const unsigned char *data, size_t datalen) {
  size_t base64len = 0;
  while (datalen > 2) {
    encodeblock(base64data, data, 3);
    base64data += 4;
    base64len += 4;
    data += 3;
    datalen -= 3;
  }
  if (datalen > 0) {
    encodeblock(base64data, data, datalen);
    base64len += 4;
  }
  return base64len;
}
```