ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reader_main>:
  endbr64
  sub    $0x8,%rsp
  call   <reader@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *reader_main(void *user) {
  struct pipeduino *state = (struct pipeduino *)user;
  reader(state);
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<reader_main>:
  endbr64
  sub    $0x8,%rsp
  call   <reader@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *reader_main(void *user) {
  struct pipeduino *state = (struct pipeduino *)user;
  reader(state);
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reader_main>:
  endbr64
  sub    $0x8,%rsp
  call   <reader@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *reader_main(void *user) {
  struct pipeduino *state = (struct pipeduino *)user;
  reader(state);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<insert_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: %d

assistant: ```c
void insert_array(int tamanho, int *vetor) {
  int i;
  for (i = 0; i < tamanho; i += 1) {
    scanf("%d", &vetor[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<insert_array>:
  endbr64
  test   %edi,%edi
  jle    L12
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r12
  lea    D2(%rip),%rbp
L19:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: %d

assistant: ```c
void insert_array(int tamanho, int *vetor) {
  int i;
  for (i = 0; i < tamanho; i += 1) {
    scanf("%d", &vetor[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<insert_array>:
  endbr64
  test   %edi,%edi
  jle    L13
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L2:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: %d

assistant: ```c
void insert_array(int tamanho, int *vetor) {
  int i;
  for (i = 0; i < tamanho; i += 1) {
    scanf("%d", &vetor[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<insert_array>:
  endbr64
  test   %edi,%edi
  jle    L9
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L13:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: %d

assistant: ```c
void insert_array(int tamanho, int *vetor) {
  int i;
  for (i = 0; i < tamanho; i += 1) {
    scanf("%d", &vetor[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<heapSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L0:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <max_Heapify@plt>
L9:
  cmpl   $0x1,-0x8(%rbp)
  jg     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapSort(int arr[], int n, int k) {
  int len = n;
  while (len > 1) {
    int temp = arr[0];
    arr[0] = arr[len - 1];
    arr[len - 1] = temp;
    len--;
    max_Heapify(arr, 0, len, k);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<heapSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L16
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %edx,%r12d
  movslq %esi,%rbx
L19:
  mov    0x0(%rbp),%eax
  mov    -0x4(%rbp,%rbx,4),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,-0x4(%rbp,%rbx,4)
  lea    -0x1(%rbx),%edx
  mov    %r12d,%ecx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <max_Heapify@plt>
  sub    $0x1,%rbx
  cmp    $0x1,%ebx
  jg     L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  ret
```

assistant: ```c
void heapSort(int arr[], int n, int k) {
  int len = n;
  while (len > 1) {
    int temp = arr[0];
    arr[0] = arr[len - 1];
    arr[len - 1] = temp;
    len--;
    max_Heapify(arr, 0, len, k);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L7
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    -0x4(%rbp,%rbx,4),%edx
  mov    0x0(%rbp),%eax
  mov    %r12d,%ecx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %edx,0x0(%rbp)
  lea    -0x1(%rbx),%edx
  mov    %eax,-0x4(%rbp,%rbx,4)
  sub    $0x1,%rbx
  call   <max_Heapify@plt>
  cmp    $0x1,%ebx
  jg     L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
void heapSort(int arr[], int n, int k) {
  int len = n;
  while (len > 1) {
    int temp = arr[0];
    arr[0] = arr[len - 1];
    arr[len - 1] = temp;
    len--;
    max_Heapify(arr, 0, len, k);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<heapSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L12
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    -0x4(%rbp,%rbx,4),%edx
  mov    0x0(%rbp),%eax
  mov    %r12d,%ecx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %edx,0x0(%rbp)
  lea    -0x1(%rbx),%edx
  mov    %eax,-0x4(%rbp,%rbx,4)
  sub    $0x1,%rbx
  call   <max_Heapify@plt>
  cmp    $0x1,%ebx
  jg     L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  ret
```

assistant: ```c
void heapSort(int arr[], int n, int k) {
  int len = n;
  while (len > 1) {
    int temp = arr[0];
    arr[0] = arr[len - 1];
    arr[len - 1] = temp;
    len--;
    max_Heapify(arr, 0, len, k);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_int16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
L6:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *get_int16(unsigned char *buffer, int *val) {
  if (val) {
    int myval = (*buffer) + ((*(buffer + 1)) << 8);
    *val = myval;
  }
  return buffer + 2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_int16>:
  endbr64
  test   %rsi,%rsi
  je     L5
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl (%rdi),%edx
  add    %edx,%eax
  mov    %eax,(%rsi)
L5:
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
unsigned char *get_int16(unsigned char *buffer, int *val) {
  if (val) {
    int myval = (*buffer) + ((*(buffer + 1)) << 8);
    *val = myval;
  }
  return buffer + 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_int16>:
  endbr64
  test   %rsi,%rsi
  je     L0
  movzbl 0x1(%rdi),%eax
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,(%rsi)
L0:
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
unsigned char *get_int16(unsigned char *buffer, int *val) {
  if (val) {
    int myval = (*buffer) + ((*(buffer + 1)) << 8);
    *val = myval;
  }
  return buffer + 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_int16>:
  endbr64
  test   %rsi,%rsi
  je     L5
  movzbl 0x1(%rdi),%eax
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,(%rsi)
L5:
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
unsigned char *get_int16(unsigned char *buffer, int *val) {
  if (val) {
    int myval = (*buffer) + ((*(buffer + 1)) << 8);
    *val = myval;
  }
  return buffer + 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <turn_to_heading@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  turn_to_heading();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <turn_to_heading@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  turn_to_heading();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <turn_to_heading@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  turn_to_heading();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <turn_to_heading@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  turn_to_heading();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tic_str_compute_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L2
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    %al,-0x1(%rbp)
  addq   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  andb   $0x3f,-0x1(%rbp)
  addb   $0x20,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char tic_str_compute_checksum(char *strbuf) {
  unsigned char chks = 0;
  while (*strbuf != '\0') {
    chks += *strbuf;
    strbuf++;
  }
  chks &= 0x3F;
  chks += 0x20;
  return (chks);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tic_str_compute_checksum>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L29
  mov    $0x0,%eax
L26:
  add    %edx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L26
L9:
  and    $0x3f,%eax
  add    $0x20,%eax
  ret
L29:
  mov    $0x0,%eax
  jmp    L9
```

assistant: ```c
unsigned char tic_str_compute_checksum(char *strbuf) {
  unsigned char chks = 0;
  while (*strbuf != '\0') {
    chks += *strbuf;
    strbuf++;
  }
  chks &= 0x3F;
  chks += 0x20;
  return (chks);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tic_str_compute_checksum>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  xor    %eax,%eax
  nopl   (%rax)
L19:
  add    $0x1,%rdi
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
  and    $0x3f,%eax
  add    $0x20,%eax
  ret
  nopl   0x0(%rax)
L15:
  mov    $0x20,%eax
  ret
```

assistant: ```c
unsigned char tic_str_compute_checksum(char *strbuf) {
  unsigned char chks = 0;
  while (*strbuf != '\0') {
    chks += *strbuf;
    strbuf++;
  }
  chks &= 0x3F;
  chks += 0x20;
  return (chks);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tic_str_compute_checksum>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L19
  xor    %eax,%eax
  nopl   (%rax)
L0:
  add    $0x1,%rdi
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L0
  and    $0x3f,%eax
  add    $0x20,%eax
  ret
  nopl   0x0(%rax)
L19:
  mov    $0x20,%eax
  ret
```

assistant: ```c
unsigned char tic_str_compute_checksum(char *strbuf) {
  unsigned char chks = 0;
  while (*strbuf != '\0') {
    chks += *strbuf;
    strbuf++;
  }
  chks &= 0x3F;
  chks += 0x20;
  return (chks);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x6f,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strindex@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D15: hello world

tool: D4: return %d


assistant: ```c
int main() {
  int v = strindex("hello world", 'o');
  printf("return %d\n", v);
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x6f,%esi
  lea    D6(%rip),%rdi
  call   <strindex@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string

tool: D6: hello world

tool: D17: return %d


assistant: ```c
int main() {
  int v = strindex("hello world", 'o');
  printf("return %d\n", v);
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x6f,%esi
  lea    D19(%rip),%rdi
  call   <strindex@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D8
datatype: string

tool: D19: hello world

tool: D8: return %d


assistant: ```c
int main() {
  int v = strindex("hello world", 'o');
  printf("return %d\n", v);
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x6f,%esi
  lea    D3(%rip),%rdi
  call   <strindex@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D3: hello world

tool: D4: return %d


assistant: ```c
int main() {
  int v = strindex("hello world", 'o');
  printf("return %d\n", v);
  return v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<niceFrame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L47:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L23
L22:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L22
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L16
  cmpl   $0x1,-0x8(%rbp)
  jle    L18
  mov    -0x18(%rbp),%eax
  add    %eax,-0xc(%rbp)
L18:
  cmpl   $0x1,-0x8(%rbp)
  jg     L47
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int niceFrame(int num, int idnum, int limit) {
  int numin, numtmp, ifac;
  numin = 2 * ((num + 1) / 2);
  do {
    numtmp = numin;
    for (ifac = 2; ifac <= limit; ifac++)
      while (numtmp % ifac == 0)
        numtmp = numtmp / ifac;
    if (numtmp > 1)
      numin += idnum;
  } while (numtmp > 1);
  return numin;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<niceFrame>:
  endbr64
  mov    %esi,%r10d
  mov    %edx,%r9d
  lea    0x1(%rdi),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  and    $0xfffffffe,%r8d
  lea    0x1(%rdx),%edi
  jmp    L46
L18:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L18
L40:
  add    $0x1,%esi
  cmp    %edi,%esi
  je     L78
L71:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L18
  jmp    L40
L52:
  mov    %r8d,%ecx
L78:
  cmp    $0x1,%ecx
  jle    L56
  add    %r10d,%r8d
L46:
  cmp    $0x1,%r9d
  jle    L52
  mov    %r8d,%ecx
  mov    $0x2,%esi
  jmp    L71
L56:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int niceFrame(int num, int idnum, int limit) {
  int numin, numtmp, ifac;
  numin = 2 * ((num + 1) / 2);
  do {
    numtmp = numin;
    for (ifac = 2; ifac <= limit; ifac++)
      while (numtmp % ifac == 0)
        numtmp = numtmp / ifac;
    if (numtmp > 1)
      numin += idnum;
  } while (numtmp > 1);
  return numin;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<niceFrame>:
  endbr64
  lea    0x1(%rdi),%eax
  mov    %esi,%r10d
  lea    0x1(%rdx),%edi
  mov    %edx,%r9d
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  and    $0xfffffffe,%r8d
L11:
  mov    %r8d,%ecx
  cmp    $0x1,%r9d
  jle    L35
  mov    $0x2,%esi
  nopl   0x0(%rax)
L34:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L1
  nopl   0x0(%rax)
L3:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  cltd
  mov    %eax,%ecx
  idiv   %esi
  test   %edx,%edx
  je     L3
L1:
  add    $0x1,%esi
  cmp    %edi,%esi
  jne    L34
L35:
  cmp    $0x1,%ecx
  jle    L23
  add    %r10d,%r8d
  jmp    L11
L23:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int niceFrame(int num, int idnum, int limit) {
  int numin, numtmp, ifac;
  numin = 2 * ((num + 1) / 2);
  do {
    numtmp = numin;
    for (ifac = 2; ifac <= limit; ifac++)
      while (numtmp % ifac == 0)
        numtmp = numtmp / ifac;
    if (numtmp > 1)
      numin += idnum;
  } while (numtmp > 1);
  return numin;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<niceFrame>:
  endbr64
  lea    0x1(%rdi),%eax
  mov    %esi,%r10d
  lea    0x1(%rdx),%edi
  mov    %edx,%r9d
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  and    $0xfffffffe,%r8d
L50:
  mov    %r8d,%ecx
  cmp    $0x1,%r9d
  jle    L2
  mov    $0x2,%esi
  nopl   0x0(%rax)
L55:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L27
  nopl   0x0(%rax)
L39:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  cltd
  mov    %eax,%ecx
  idiv   %esi
  test   %edx,%edx
  je     L39
L27:
  add    $0x1,%esi
  cmp    %edi,%esi
  jne    L55
L2:
  cmp    $0x1,%ecx
  jle    L11
  add    %r10d,%r8d
  jmp    L50
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int niceFrame(int num, int idnum, int limit) {
  int numin, numtmp, ifac;
  numin = 2 * ((num + 1) / 2);
  do {
    numtmp = numin;
    for (ifac = 2; ifac <= limit; ifac++)
      while (numtmp % ifac == 0)
        numtmp = numtmp / ifac;
    if (numtmp > 1)
      numin += idnum;
  } while (numtmp > 1);
  return numin;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<addressOK>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jne    L6
  movl   $0x20,-0xc(%rbp)
  movl   $0x4,-0x8(%rbp)
  jmp    L32
L6:
  movl   $0x80,-0xc(%rbp)
  movl   $0x10,-0x8(%rbp)
L32:
  mov    -0x2c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L23
  mov    $0x1,%eax
  jmp    L17
L23:
  mov    -0x2c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movb   $0xff,-0x11(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L85
  movzbl -0x11(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x11(%rbp)
  jmp    L85
L77:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  and    -0x11(%rbp),%al
  test   %al,%al
  je     L71
  mov    $0x0,%eax
  jmp    L17
L71:
  movb   $0xff,-0x11(%rbp)
  addl   $0x1,-0x10(%rbp)
L85:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L77
  mov    $0x1,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int addressOK(unsigned char *a, int bits, int family) {
  int byte;
  int nbits;
  int maxbits;
  int maxbytes;
  unsigned char mask;
  if (family == (AF_INET + 0)) {
    maxbits = 32;
    maxbytes = 4;
  } else {
    maxbits = 128;
    maxbytes = 16;
  }
  if (bits >= maxbits)
    return 1;
  byte = bits / 8;
  nbits = bits % 8;
  mask = 0xff;
  if (bits != 0)
    mask >>= nbits;
  while (byte < maxbytes) {
    if ((a[byte] & mask) != 0)
      return 0;
    mask = 0xff;
    byte++;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<addressOK>:
  endbr64
  mov    %esi,%ecx
  mov    D1(%rip),%rax
  cmp    %edx,(%rax)
  mov    $0x4,%esi
  mov    $0x10,%r8d
  cmovne %r8d,%esi
  mov    $0x20,%eax
  mov    $0x80,%edx
  cmovne %edx,%eax
  mov    $0x1,%edx
  cmp    %ecx,%eax
  jle    L68
  lea    0x7(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x3,%eax
  test   %ecx,%ecx
  je     L70
  and    $0x7,%ecx
  mov    $0xff,%edx
  sar    %cl,%edx
  cmp    %eax,%esi
  jg     L47
  mov    $0x1,%edx
  jmp    L68
L70:
  mov    $0xffffffff,%edx
L47:
  movslq %eax,%rcx
  and    (%rdi,%rcx,1),%dl
  jne    L76
  add    $0x1,%eax
  cltq
L34:
  cmp    %eax,%esi
  jle    L18
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  je     L34
  mov    $0x0,%edx
  jmp    L68
L18:
  mov    $0x1,%edx
L68:
  mov    %edx,%eax
  ret
L76:
  mov    $0x0,%edx
  jmp    L68
```

assistant: ```c
int addressOK(unsigned char *a, int bits, int family) {
  int byte;
  int nbits;
  int maxbits;
  int maxbytes;
  unsigned char mask;
  if (family == (AF_INET + 0)) {
    maxbits = 32;
    maxbytes = 4;
  } else {
    maxbits = 128;
    maxbytes = 16;
  }
  if (bits >= maxbits)
    return 1;
  byte = bits / 8;
  nbits = bits % 8;
  mask = 0xff;
  if (bits != 0)
    mask >>= nbits;
  while (byte < maxbytes) {
    if ((a[byte] & mask) != 0)
      return 0;
    mask = 0xff;
    byte++;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<addressOK>:
  endbr64
  mov    D7(%rip),%rax
  mov    $0x80,%ecx
  mov    $0x1,%r9d
  cmp    %edx,(%rax)
  mov    $0x10,%eax
  mov    $0x4,%edx
  cmovne %eax,%edx
  mov    $0x20,%eax
  cmovne %ecx,%eax
  cmp    %esi,%eax
  jle    L55
  test   %esi,%esi
  lea    0x7(%rsi),%eax
  cmovns %esi,%eax
  sar    $0x3,%eax
  test   %esi,%esi
  jne    L40
  mov    $0xffffffff,%ecx
L76:
  movslq %eax,%rsi
  and    (%rdi,%rsi,1),%cl
  jne    L30
  add    $0x1,%eax
  cltq
  jmp    L71
  nopl   0x0(%rax)
L5:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L30
L71:
  cmp    %eax,%edx
  jg     L5
  mov    $0x1,%r9d
L55:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L40:
  and    $0x7,%esi
  mov    $0xff,%r8d
  mov    %esi,%ecx
  sar    %cl,%r8d
  mov    %r8d,%ecx
  cmp    %eax,%edx
  jg     L76
  jmp    L55
  nop
L30:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int addressOK(unsigned char *a, int bits, int family) {
  int byte;
  int nbits;
  int maxbits;
  int maxbytes;
  unsigned char mask;
  if (family == (AF_INET + 0)) {
    maxbits = 32;
    maxbytes = 4;
  } else {
    maxbits = 128;
    maxbytes = 16;
  }
  if (bits >= maxbits)
    return 1;
  byte = bits / 8;
  nbits = bits % 8;
  mask = 0xff;
  if (bits != 0)
    mask >>= nbits;
  while (byte < maxbytes) {
    if ((a[byte] & mask) != 0)
      return 0;
    mask = 0xff;
    byte++;
  }
  return 1;
}
```