ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<eliminacion>:
  endbr64
  cmp    $0x1,%edx
  jle    L20
  push   %r15
  lea    -0x1(%rdx),%eax
  mov    %rcx,%r11
  mov    $0x8,%r15d
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %edx,%ebx
  mov    %eax,-0x2c(%rsp)
  lea    -0x2(%rdx),%eax
  add    $0x2,%rax
  mov    %edx,-0x28(%rsp)
  mov    %rax,-0x10(%rsp)
  movq   $0x10,-0x18(%rsp)
  movq   $0x1,-0x20(%rsp)
L40:
  cmp    -0x20(%rsp),%ebx
  jle    L37
  mov    -0x2c(%rsp),%esi
  mov    0x0(%r13,%rbp,1),%r12
  mov    %esi,%eax
  lea    (%r12,%rbp,1),%r14
  lea    (%r12,%r15,1),%r9
  and    $0xfffffffe,%esi
  shr    %eax
  mov    %esi,%r8d
  mov    %esi,-0x24(%rsp)
  mov    -0x20(%rsp),%rsi
  lea    -0x1(%rax),%edi
  mov    -0x18(%rsp),%rax
  add    %esi,%r8d
  add    $0x1,%rdi
  add    %r12,%rax
  movslq %r8d,%r8
  shl    $0x4,%rdi
  mov    %rax,-0x38(%rsp)
  shl    $0x3,%r8
  lea    (%r12,%r8,1),%r10
  nopl   0x0(%rax)
L73:
  mov    0x0(%r13,%rsi,8),%rdx
  movsd  (%rdx,%rbp,1),%xmm2
  lea    (%rdx,%r15,1),%rcx
  divsd  (%r14),%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm2,%xmm2
  cmp    -0x38(%rsp),%rcx
  je     L60
  cmpl   $0x2,-0x28(%rsp)
  je     L60
  movapd %xmm2,%xmm3
  xor    %eax,%eax
  unpcklpd %xmm3,%xmm3
  nopl   0x0(%rax,%rax,1)
L24:
  movupd (%r9,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm0
  mulpd  %xmm3,%xmm1
  subpd  %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L24
  mov    -0x2c(%rsp),%ecx
  cmp    %ecx,-0x24(%rsp)
  je     L3
  movsd  (%r10),%xmm1
  add    %r8,%rdx
  movsd  (%rdx),%xmm0
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
L3:
  mulsd  (%r11,%rbp,1),%xmm2
  movsd  (%r11,%rsi,8),%xmm0
  subsd  %xmm2,%xmm0
  movsd  %xmm0,(%r11,%rsi,8)
  add    $0x1,%rsi
  cmp    %esi,%ebx
  jg     L73
L37:
  addq   $0x1,-0x20(%rsp)
  add    $0x8,%rbp
  mov    -0x20(%rsp),%rax
  add    $0x8,%r15
  subl   $0x1,-0x28(%rsp)
  addq   $0x8,-0x18(%rsp)
  subl   $0x1,-0x2c(%rsp)
  cmp    -0x10(%rsp),%rax
  jne    L40
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L60:
  mov    -0x20(%rsp),%rax
  nopl   (%rax)
L64:
  movsd  (%r12,%rax,8),%xmm1
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L64
  jmp    L3
L20:
  ret
```

assistant: ```c
void eliminacion(double **a, double *x, int filas, double *b) {
  int i, j, k, n;
  float factor;
  n = filas;
  for (k = 0; k <= n - 2; k++) {
    for (i = k + 1; i <= n - 1; i++) {
      factor = a[i][k] / a[k][k];
      for (j = k + 1; j <= n - 1; j++) {
        a[i][j] = a[i][j] - factor * a[k][j];
      }
      b[i] = b[i] - factor * b[k];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<gfmul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L32:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L30
  mov    -0x14(%rbp),%eax
  xor    %eax,-0x4(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L23
  mov    $0x1d,%eax
  jmp    L43
L23:
  mov    $0x0,%eax
L43:
  xor    %edx,%eax
  mov    %eax,-0x14(%rbp)
  sarl   -0x18(%rbp)
L27:
  cmpl   $0x0,-0x18(%rbp)
  jne    L32
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t gfmul(uint8_t a, uint8_t b) {
  uint8_t v = 0;
  while (b) {
    if (b & 1) {
      v ^= a;
    }
    a = (a << 1) ^ (a & 0x80 ? 0x1d : 0);
    b >>= 1;
  }
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gfmul>:
  endbr64
  test   %esi,%esi
  je     L6
  mov    $0x0,%eax
  mov    $0x1d,%ecx
L11:
  mov    %eax,%edx
  xor    %edi,%edx
  test   $0x1,%sil
  cmovne %edx,%eax
  lea    (%rdi,%rdi,1),%edx
  and    $0x80,%edi
  cmovne %ecx,%edi
  xor    %edx,%edi
  sar    %esi
  jne    L11
  ret
L6:
  mov    %esi,%eax
  ret
```

assistant: ```c
uint8_t gfmul(uint8_t a, uint8_t b) {
  uint8_t v = 0;
  while (b) {
    if (b & 1) {
      v ^= a;
    }
    a = (a << 1) ^ (a & 0x80 ? 0x1d : 0);
    b >>= 1;
  }
  return v;
}
```
user: What is the c source code of the assembly code below:

```asm
<gfmul>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L17
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %eax,%edx
  xor    %edi,%edx
  test   $0x1,%sil
  cmovne %edx,%eax
  lea    (%rdi,%rdi,1),%edx
  mov    %edx,%ecx
  xor    $0x1d,%ecx
  and    $0x80,%edi
  mov    %edx,%edi
  cmovne %ecx,%edi
  sar    %esi
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
uint8_t gfmul(uint8_t a, uint8_t b) {
  uint8_t v = 0;
  while (b) {
    if (b & 1) {
      v ^= a;
    }
    a = (a << 1) ^ (a & 0x80 ? 0x1d : 0);
    b >>= 1;
  }
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gfmul>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L2
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %eax,%edx
  xor    %edi,%edx
  test   $0x1,%sil
  cmovne %edx,%eax
  lea    (%rdi,%rdi,1),%edx
  mov    %edx,%ecx
  xor    $0x1d,%ecx
  and    $0x80,%edi
  mov    %edx,%edi
  cmovne %ecx,%edi
  sar    %esi
  jne    L4
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
uint8_t gfmul(uint8_t a, uint8_t b) {
  uint8_t v = 0;
  while (b) {
    if (b & 1) {
      v ^= a;
    }
    a = (a << 1) ^ (a & 0x80 ? 0x1d : 0);
    b >>= 1;
  }
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<intf_name_best_cpus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <intf_numa_node@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L8
  mov    $0xffffffff,%eax
  jmp    L4
L8:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <numa_node_to_cpusmask@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L4:
  leave
  ret
```

assistant: ```c
int intf_name_best_cpus(const char *if_name, uint64_t *cpusmask, int *nr) {
  int numa_node, retval;
  numa_node = intf_numa_node(if_name);
  if (numa_node < 0)
    return -1;
  retval = numa_node_to_cpusmask(numa_node, cpusmask, nr);
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intf_name_best_cpus>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <intf_numa_node@plt>
  test   %eax,%eax
  js     L11
  mov    %eax,%edi
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <numa_node_to_cpusmask@plt>
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L15
```

assistant: ```c
int intf_name_best_cpus(const char *if_name, uint64_t *cpusmask, int *nr) {
  int numa_node, retval;
  numa_node = intf_numa_node(if_name);
  if (numa_node < 0)
    return -1;
  retval = numa_node_to_cpusmask(numa_node, cpusmask, nr);
  return retval;
}
```
user: What is the c source code of the assembly code below?

```asm
<intf_name_best_cpus>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <intf_numa_node@plt>
  test   %eax,%eax
  js     L4
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <numa_node_to_cpusmask@plt>
  xchg   %ax,%ax
L4:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int intf_name_best_cpus(const char *if_name, uint64_t *cpusmask, int *nr) {
  int numa_node, retval;
  numa_node = intf_numa_node(if_name);
  if (numa_node < 0)
    return -1;
  retval = numa_node_to_cpusmask(numa_node, cpusmask, nr);
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<intf_name_best_cpus>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <intf_numa_node@plt>
  test   %eax,%eax
  js     L0
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <numa_node_to_cpusmask@plt>
  xchg   %ax,%ax
L0:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int intf_name_best_cpus(const char *if_name, uint64_t *cpusmask, int *nr) {
  int numa_node, retval;
  numa_node = intf_numa_node(if_name);
  if (numa_node < 0)
    return -1;
  retval = numa_node_to_cpusmask(numa_node, cpusmask, nr);
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<C_write_with_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  lea    0x2(%rax),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <write_raw_varint32@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <C_write_delimited_to@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int C_write_with_tag(struct C *_C, void *_buffer, int offset, int tag) {
  offset = write_raw_varint32((tag << 3) + 2, _buffer, offset);
  offset = C_write_delimited_to(_C, _buffer, offset);
  return offset;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<C_write_with_tag>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x2(,%rcx,8),%edi
  call   <write_raw_varint32@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <C_write_delimited_to@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int C_write_with_tag(struct C *_C, void *_buffer, int offset, int tag) {
  offset = write_raw_varint32((tag << 3) + 2, _buffer, offset);
  offset = C_write_delimited_to(_C, _buffer, offset);
  return offset;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<C_write_with_tag>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    0x2(,%rcx,8),%edi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <write_raw_varint32@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <C_write_delimited_to@plt>
```

assistant: ```c
int C_write_with_tag(struct C *_C, void *_buffer, int offset, int tag) {
  offset = write_raw_varint32((tag << 3) + 2, _buffer, offset);
  offset = C_write_delimited_to(_C, _buffer, offset);
  return offset;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<C_write_with_tag>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    0x2(,%rcx,8),%edi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <write_raw_varint32@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <C_write_delimited_to@plt>
```

assistant: ```c
int C_write_with_tag(struct C *_C, void *_buffer, int offset, int tag) {
  offset = write_raw_varint32((tag << 3) + 2, _buffer, offset);
  offset = C_write_delimited_to(_C, _buffer, offset);
  return offset;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_even>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L0
  mov    $0x0,%eax
  jmp    L6
L0:
  mov    $0xffffffff,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int is_even(int *val) {
  if (*val % 2 == 0)
    return 0;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_even>:
  endbr64
  mov    (%rdi),%eax
  and    $0x1,%eax
  neg    %eax
  ret
```

assistant: ```c
int is_even(int *val) {
  if (*val % 2 == 0)
    return 0;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_even>:
  endbr64
  mov    (%rdi),%eax
  and    $0x1,%eax
  neg    %eax
  ret
```

assistant: ```c
int is_even(int *val) {
  if (*val % 2 == 0)
    return 0;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_even>:
  endbr64
  mov    (%rdi),%eax
  and    $0x1,%eax
  neg    %eax
  ret
```

assistant: ```c
int is_even(int *val) {
  if (*val % 2 == 0)
    return 0;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quipper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    $0x8,%edi
  call   <d@plt>
  mov    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %ebx,%eax
  sub    $0x8,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  lea    D19(%rip),%rdx
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <nicename@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L14
L10:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  test   %eax,%eax
  cmovle %edx,%eax
  mov    -0x18(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  ja     L10
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D4
type: string
name: unpack_data
arguments: tag: D22
type: string

tool: D19: MM 284

tool: D4: swarm of quippers

tool: D22: %d: %d hp

assistant: ```c
void quipper(unsigned count) {
  int i;
  int hp = d(8) + d(8) + d(8) + d(8) + d(8) + d(8) + d(8) + d(8) - 8;
  nicename(count, "swarm of quippers", "MM 284");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp", i + 1, (hp > 0) ? hp : 1);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quipper>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    $0x8,%edi
  call   <d@plt>
  mov    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0x8,%edi
  call   <d@plt>
  lea    -0x8(%rbx,%rax,1),%ebp
  lea    D16(%rip),%rdx
  lea    D3(%rip),%rsi
  mov    %r12d,%edi
  call   <nicename@plt>
  test   %r12d,%r12d
  je     L13
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L10:
  add    $0x1,%ebx
  test   %ebp,%ebp
  mov    $0x1,%edx
  cmovg  %ebp,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L10
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type_guessed: string
name: unpack_data
arguments: label: D3
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string

tool: D16: MM 284

tool: D3: swarm of quippers

tool: D0: %d: %d hp

assistant: ```c
void quipper(unsigned count) {
  int i;
  int hp = d(8) + d(8) + d(8) + d(8) + d(8) + d(8) + d(8) + d(8) - 8;
  nicename(count, "swarm of quippers", "MM 284");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp", i + 1, (hp > 0) ? hp : 1);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quipper>:
  endbr64
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x8,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <d@plt>
  mov    $0x8,%edi
  mov    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  lea    D15(%rip),%rdx
  lea    D1(%rip),%rsi
  mov    %ebp,%edi
  lea    -0x8(%rbx,%rax,1),%r12d
  call   <nicename@plt>
  test   %r12d,%r12d
  mov    $0x1,%eax
  cmovle %eax,%r12d
  xor    %ebx,%ebx
  test   %ebp,%ebp
  je     L1
  nopl   0x0(%rax)
L17:
  add    $0x1,%ebx
  mov    %r13,%rdi
  mov    %r12d,%edx
  mov    %ebx,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L17
L1:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D15
type: string
name: disassemble_data
arguments: data_label: D1
type: string

tool: D17: %d: %d hp

tool: D15: MM 284

tool: D1: swarm of quippers

assistant: ```c
void quipper(unsigned count) {
  int i;
  int hp = d(8) + d(8) + d(8) + d(8) + d(8) + d(8) + d(8) + d(8) - 8;
  nicename(count, "swarm of quippers", "MM 284");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp", i + 1, (hp > 0) ? hp : 1);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quipper>:
  endbr64
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x8,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <d@plt>
  mov    $0x8,%edi
  mov    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0x8,%edi
  add    %eax,%ebx
  call   <d@plt>
  lea    D27(%rip),%rdx
  lea    D6(%rip),%rsi
  mov    %ebp,%edi
  lea    -0x8(%rbx,%rax,1),%r12d
  call   <nicename@plt>
  test   %r12d,%r12d
  mov    $0x1,%eax
  cmovle %eax,%r12d
  xor    %ebx,%ebx
  test   %ebp,%ebp
  je     L16
  nopl   0x0(%rax)
L18:
  add    $0x1,%ebx
  mov    %r13,%rdi
  mov    %r12d,%edx
  mov    %ebx,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L18
L16:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D29: %d: %d hp

tool: D27: MM 284

tool: D6: swarm of quippers

assistant: ```c
void quipper(unsigned count) {
  int i;
  int hp = d(8) + d(8) + d(8) + d(8) + d(8) + d(8) + d(8) + d(8) - 8;
  nicename(count, "swarm of quippers", "MM 284");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp", i + 1, (hp > 0) ? hp : 1);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <itol@plt>
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <itol@plt>
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  sete   %al
  mov    %al,-0x21(%rbp)
  cmpb   $0x0,-0x21(%rbp)
  je     L5
  addq   $0x1,-0x40(%rbp)
  jmp    L5
L8:
  mov    -0x40(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  lea    -0x1c(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <itol@plt>
  mov    %eax,%ebx
  lea    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lmul@plt>
  mov    %eax,%ecx
  mov    -0x38(%rbp),%rax
  mov    %ebx,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ladd@plt>
L5:
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L8
  cmpb   $0x0,-0x21(%rbp)
  je     L33
  lea    -0x1c(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <itol@plt>
  mov    %eax,%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lsub@plt>
  cltq
  jmp    L57
L33:
  mov    -0x38(%rbp),%rax
L57:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *atol(result, s)
char *result, *s;
{
  char ten[4], temp[4], sign;
  itol(ten, 10);
  itol(result, 0);
  if (sign = (*s == '-'))
    s++;
  while (isdigit(*s))
    ladd(result, lmul(result, result, ten), itol(temp, *s++ - '0'));
  return (sign ? lsub(result, itol(temp, 0), result) : result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atol>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xa,%esi
  call   <itol@plt>
  mov    $0x0,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <itol@plt>
  movzbl (%rbx),%r13d
  cmp    $0x2d,%r13b
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  movzbl (%rbx),%esi
  movsbl %sil,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L1
  lea    0x4(%rsp),%r12
L44:
  add    $0x1,%rbx
  movsbl %sil,%esi
  sub    $0x30,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <itol@plt>
  mov    %eax,%r14d
  mov    %rsp,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <lmul@plt>
  mov    %eax,%esi
  mov    %r14d,%edx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <ladd@plt>
  movzbl (%rbx),%esi
  movsbl %sil,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L44
L1:
  cmp    $0x2d,%r13b
  je     L13
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  mov    $0x0,%eax
  call   <itol@plt>
  mov    %eax,%esi
  mov    %rbp,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <lsub@plt>
  movslq %eax,%rbp
  jmp    L32
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *atol(result, s)
char *result, *s;
{
  char ten[4], temp[4], sign;
  itol(ten, 10);
  itol(result, 0);
  if (sign = (*s == '-'))
    s++;
  while (isdigit(*s))
    ladd(result, lmul(result, result, ten), itol(temp, *s++ - '0'));
  return (sign ? lsub(result, itol(temp, 0), result) : result);
}
```