ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<convert_dmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  sub    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x58(%rbp),%rax
  sub    -0x50(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L25:
  addq   $0x8,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x50(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  movq   $0x1,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L19
L21:
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x20(%rbp)
L19:
  mov    -0x28(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L21
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: allocation failure in convert_dmatrix()

assistant: ```c
double **convert_dmatrix(double *a, long nrl, long nrh, long ncl, long nch) {
  long i, j, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  double **m;
  m = (double **)malloc((size_t)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure in convert_dmatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = a - ncl;
  for (i = 1, j = nrl + 1; i < nrow; i++, j++)
    m[j] = m[j - 1] + ncol;
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_dmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r14
  mov    %rcx,%r12
  mov    %rdx,%r15
  sub    %rsi,%r15
  sub    %rcx,%r8
  lea    0x1(%r8),%rbp
  lea    0x10(,%r15,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L15:
  mov    $0x1,%eax
  sub    0x8(%rsp),%rax
  lea    (%rbx,%rax,8),%rcx
  shl    $0x3,%r12
  sub    %r12,%r13
  mov    %r13,0x8(%rbx)
  test   %r15,%r15
  jle    L18
  shl    $0x3,%rbp
  add    $0x8,%rbx
  lea    (%rcx,%r14,8),%rdx
L17:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L17
L18:
  mov    %rcx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  lea    D7(%rip),%rdi
  call   <nrerror@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: allocation failure in convert_dmatrix()

assistant: ```c
double **convert_dmatrix(double *a, long nrl, long nrh, long ncl, long nch) {
  long i, j, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  double **m;
  m = (double **)malloc((size_t)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure in convert_dmatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = a - ncl;
  for (i = 1, j = nrl + 1; i < nrow; i++, j++)
    m[j] = m[j - 1] + ncol;
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<convert_dmatrix>:
  endbr64
  push   %r15
  sub    %rcx,%r8
  mov    %rdx,%r15
  push   %r14
  lea    0x1(%r8),%rax
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    %rsi,%rbp
  lea    0x10(,%rbp,8),%rdi
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L13:
  mov    $0x1,%eax
  shl    $0x3,%r12
  sub    %r14,%rax
  sub    %r12,%r13
  mov    %r13,0x8(%rbx)
  lea    (%rbx,%rax,8),%r8
  test   %rbp,%rbp
  jle    L14
  mov    0x8(%rsp),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r15,8),%rsi
  shl    $0x3,%rcx
  nopw   0x0(%rax,%rax,1)
L35:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L35
L14:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L16:
  lea    D3(%rip),%rdi
  call   <nrerror@plt>
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: allocation failure in convert_dmatrix()

assistant: ```c
double **convert_dmatrix(double *a, long nrl, long nrh, long ncl, long nch) {
  long i, j, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  double **m;
  m = (double **)malloc((size_t)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure in convert_dmatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = a - ncl;
  for (i = 1, j = nrl + 1; i < nrow; i++, j++)
    m[j] = m[j - 1] + ncol;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_dmatrix>:
  endbr64
  push   %r15
  sub    %rcx,%r8
  mov    %rdx,%r15
  push   %r14
  lea    0x1(%r8),%rax
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    %rsi,%r12
  mov    %rdi,%rbp
  push   %rbx
  lea    0x10(,%r12,8),%rdi
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L33
L19:
  mov    $0x1,%eax
  shl    $0x3,%r13
  mov    %rbp,%rdx
  sub    %r14,%rax
  sub    %r13,%rdx
  mov    %rdx,0x8(%rbx)
  lea    (%rbx,%rax,8),%r8
  test   %r12,%r12
  jle    L39
  mov    0x8(%rsp),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r15,8),%rsi
  shl    $0x3,%rcx
  nopl   (%rax)
L21:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L21
L39:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L33:
  lea    D7(%rip),%rdi
  call   <nrerror@plt>
  jmp    L19
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string

tool: D7: allocation failure in convert_dmatrix()

assistant: ```c
double **convert_dmatrix(double *a, long nrl, long nrh, long ncl, long nch) {
  long i, j, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  double **m;
  m = (double **)malloc((size_t)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure in convert_dmatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = a - ncl;
  for (i = 1, j = nrl + 1; i < nrow; i++, j++)
    m[j] = m[j - 1] + ncol;
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<enableinterrupt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <is_interruptible@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  call   <read_cop0_status@plt>
  and    $0xfffffff8,%eax
  or     $0x1,%eax
  mov    %eax,%edi
  call   <write_cop0_status@plt>
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void enableinterrupt(void) {
  if (!is_interruptible()) {
    write_cop0_status((read_cop0_status() & ~0x00000002 & ~0x00000004) | 0x00000001);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<enableinterrupt>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <is_interruptible@plt>
  test   %eax,%eax
  je     L5
L18:
  add    $0x8,%rsp
  ret
L5:
  call   <read_cop0_status@plt>
  and    $0xfffffff8,%eax
  mov    %eax,%edi
  or     $0x1,%edi
  call   <write_cop0_status@plt>
  jmp    L18
```

assistant: ```c
void enableinterrupt(void) {
  if (!is_interruptible()) {
    write_cop0_status((read_cop0_status() & ~0x00000002 & ~0x00000004) | 0x00000001);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<enableinterrupt>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <is_interruptible@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  call   <read_cop0_status@plt>
  add    $0x8,%rsp
  and    $0xfffffff8,%eax
  mov    %eax,%edi
  or     $0x1,%edi
  jmp    1090 <write_cop0_status@plt>
```

assistant: ```c
void enableinterrupt(void) {
  if (!is_interruptible()) {
    write_cop0_status((read_cop0_status() & ~0x00000002 & ~0x00000004) | 0x00000001);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<enableinterrupt>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <is_interruptible@plt>
  test   %eax,%eax
  je     L0
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  call   <read_cop0_status@plt>
  add    $0x8,%rsp
  and    $0xfffffff8,%eax
  mov    %eax,%edi
  or     $0x1,%edi
  jmp    1090 <write_cop0_status@plt>
```

assistant: ```c
void enableinterrupt(void) {
  if (!is_interruptible()) {
    write_cop0_status((read_cop0_status() & ~0x00000002 & ~0x00000004) | 0x00000001);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dstrb_beta_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <dstrb_log_gamma_function@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <dstrb_log_gamma_function@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <dstrb_log_gamma_function@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double dstrb_beta_function(const double x, const double y) {
  const double gx = dstrb_log_gamma_function(x);
  const double gy = dstrb_log_gamma_function(y);
  const double gz = dstrb_log_gamma_function(x + y);
  const double logbeta = gx + gy - gz;
  return exp(logbeta);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dstrb_beta_function>:
  endbr64
  push   %r15
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  call   <dstrb_log_gamma_function@plt>
  movq   %xmm0,%r15
  movq   %r14,%xmm0
  call   <dstrb_log_gamma_function@plt>
  movq   %xmm0,%rbp
  movq   %rbx,%xmm0
  movq   %r14,%xmm2
  addsd  %xmm2,%xmm0
  call   <dstrb_log_gamma_function@plt>
  movapd %xmm0,%xmm1
  movq   %r15,%xmm0
  movq   %rbp,%xmm3
  addsd  %xmm3,%xmm0
  subsd  %xmm1,%xmm0
  call   <exp@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double dstrb_beta_function(const double x, const double y) {
  const double gx = dstrb_log_gamma_function(x);
  const double gy = dstrb_log_gamma_function(y);
  const double gz = dstrb_log_gamma_function(x + y);
  const double logbeta = gx + gy - gz;
  return exp(logbeta);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dstrb_beta_function>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x18(%rsp)
  call   <dstrb_log_gamma_function@plt>
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rsp),%xmm0
  call   <dstrb_log_gamma_function@plt>
  movsd  (%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  addsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  call   <dstrb_log_gamma_function@plt>
  movsd  0x8(%rsp),%xmm4
  addsd  0x10(%rsp),%xmm4
  add    $0x28,%rsp
  movapd %xmm0,%xmm1
  movapd %xmm4,%xmm0
  subsd  %xmm1,%xmm0
  jmp    1060 <exp@plt>
```

assistant: ```c
double dstrb_beta_function(const double x, const double y) {
  const double gx = dstrb_log_gamma_function(x);
  const double gy = dstrb_log_gamma_function(y);
  const double gz = dstrb_log_gamma_function(x + y);
  const double logbeta = gx + gy - gz;
  return exp(logbeta);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dstrb_beta_function>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x18(%rsp)
  call   <dstrb_log_gamma_function@plt>
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rsp),%xmm0
  call   <dstrb_log_gamma_function@plt>
  movsd  (%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  addsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  call   <dstrb_log_gamma_function@plt>
  movsd  0x8(%rsp),%xmm4
  addsd  0x10(%rsp),%xmm4
  add    $0x28,%rsp
  movapd %xmm0,%xmm1
  movapd %xmm4,%xmm0
  subsd  %xmm1,%xmm0
  jmp    1060 <exp@plt>
```

assistant: ```c
double dstrb_beta_function(const double x, const double y) {
  const double gx = dstrb_log_gamma_function(x);
  const double gy = dstrb_log_gamma_function(y);
  const double gz = dstrb_log_gamma_function(x + y);
  const double logbeta = gx + gy - gz;
  return exp(logbeta);
}
```
user: Translate the below assembly code into C programming language:

```asm
<utoa64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x5f5e0ff,-0x14(%rbp)
  jle    L22
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55e63b89,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x19,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55e63b89,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x19,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5f5e100,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1f,-0x4(%rbp)
L45:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    D9(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L45
  cmpl   $0x0,-0x8(%rbp)
  jle    L47
  movl   $0xf,-0x4(%rbp)
L30:
  mov    -0x8(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    D9(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jg     L30
L47:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  lea    D9(%rip),%rax
  add    %rdx,%rax
  jmp    L37
L22:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <utoa32@plt>
L37:
  leave
  ret
```

assistant: ```c
char *utoa64(const uint64_t x) {
  static char buf[32 + 1];
  uint32_t a, b, i;
  if (x > 99999999) {
    a = x / 100000000;
    b = x % 100000000;
    i = 31;
    do {
      buf[i--] = (a % 10) + '0';
      a /= 10;
    } while (a > 0);
    if (b > 0) {
      i = 31 - 16;
      do {
        buf[i--] = (b % 10) + '0';
        b /= 10;
      } while (b > 0);
    }
    return buf + i + 1;
  } else
    return utoa32(x);
}
```
user: What is the c source code of the assembly code below?

```asm
<utoa64>:
  endbr64
  cmp    $0x5f5e0ff,%edi
  jle    L37
  movslq %edi,%rdx
  imul   $0x55e63b89,%rdx,%rdx
  sar    $0x39,%rdx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  imul   $0x5f5e100,%edx,%eax
  sub    %eax,%edi
  mov    $0x1e,%ecx
  lea    D18(%rip),%r10
L5:
  mov    %ecx,%r9d
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%r8d
  add    %r8d,%r8d
  mov    %edx,%esi
  sub    %r8d,%esi
  add    $0x30,%esi
  mov    %sil,(%rcx,%r10,1)
  mov    %edx,%esi
  mov    %eax,%edx
  sub    $0x1,%rcx
  cmp    $0x9,%esi
  jg     L5
  test   %edi,%edi
  jle    L0
  mov    $0xe,%edx
  lea    D18(%rip),%r8
L32:
  mov    %edx,%r9d
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edi,%ecx
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rdx,%r8,1)
  mov    %edi,%ecx
  mov    %eax,%edi
  sub    $0x1,%rdx
  cmp    $0x9,%ecx
  jg     L32
L0:
  lea    0x1(%r9),%eax
  cltq
  lea    D20(%rip),%rdx
  add    %rdx,%rax
  ret
L37:
  sub    $0x8,%rsp
  call   <utoa32@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *utoa64(const uint64_t x) {
  static char buf[32 + 1];
  uint32_t a, b, i;
  if (x > 99999999) {
    a = x / 100000000;
    b = x % 100000000;
    i = 31;
    do {
      buf[i--] = (a % 10) + '0';
      a /= 10;
    } while (a > 0);
    if (b > 0) {
      i = 31 - 16;
      do {
        buf[i--] = (b % 10) + '0';
        b /= 10;
      } while (b > 0);
    }
    return buf + i + 1;
  } else
    return utoa32(x);
}
```
user: What is the c source code of the assembly code below?

```asm
<utoa64>:
  endbr64
  cmp    $0x5f5e0ff,%edi
  jle    L28
  movslq %edi,%rcx
  mov    %edi,%eax
  mov    $0x1f,%esi
  mov    $0xcccccccd,%r11d
  imul   $0x55e63b89,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x39,%rcx
  sub    %eax,%ecx
  imul   $0x5f5e100,%ecx,%eax
  sub    %eax,%edi
  lea    D4(%rip),%rax
  nop
L19:
  mov    %ecx,%edx
  mov    %ecx,%r8d
  movslq %esi,%r10
  imul   %r11,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%r8d
  add    $0x30,%r8d
  mov    %r8b,(%rax,%rsi,1)
  mov    %ecx,%r8d
  sub    $0x1,%rsi
  mov    %edx,%ecx
  cmp    $0x9,%r8d
  jg     L19
  test   %edi,%edi
  je     L34
  mov    $0xf,%ecx
  mov    $0xcccccccd,%r9d
L30:
  mov    %edi,%edx
  mov    %edi,%esi
  movslq %ecx,%r10
  imul   %r9,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%esi
  add    $0x30,%esi
  mov    %sil,(%rax,%rcx,1)
  mov    %edi,%esi
  sub    $0x1,%rcx
  mov    %edx,%edi
  cmp    $0x9,%esi
  jg     L30
L34:
  add    %r10,%rax
  ret
  nopl   0x0(%rax)
L28:
  jmp    1050 <utoa32@plt>
```

assistant: ```c
char *utoa64(const uint64_t x) {
  static char buf[32 + 1];
  uint32_t a, b, i;
  if (x > 99999999) {
    a = x / 100000000;
    b = x % 100000000;
    i = 31;
    do {
      buf[i--] = (a % 10) + '0';
      a /= 10;
    } while (a > 0);
    if (b > 0) {
      i = 31 - 16;
      do {
        buf[i--] = (b % 10) + '0';
        b /= 10;
      } while (b > 0);
    }
    return buf + i + 1;
  } else
    return utoa32(x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<utoa64>:
  endbr64
  cmp    $0x5f5e0ff,%edi
  jle    L133
  movslq %edi,%rcx
  mov    %edi,%eax
  mov    $0x1f,%esi
  mov    $0xcccccccd,%r10d
  imul   $0x55e63b89,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x39,%rcx
  sub    %eax,%ecx
  imul   $0x5f5e100,%ecx,%eax
  sub    %eax,%edi
  lea    D72(%rip),%rax
  nop
L139:
  mov    %ecx,%edx
  mov    %ecx,%r8d
  movslq %esi,%r11
  imul   %r10,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%r8d
  add    $0x30,%r8d
  mov    %r8b,(%rax,%rsi,1)
  mov    %ecx,%r8d
  sub    $0x1,%rsi
  mov    %edx,%ecx
  cmp    $0x9,%r8d
  jg     L139
  test   %edi,%edi
  je     L32
  mov    %edi,%edx
  mov    %edi,%ecx
  imul   %r10,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,D0(%rip)
  cmp    $0x9,%edi
  jle    L35
  mov    %edx,%ecx
  imul   %r10,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,D49(%rip)
  cmp    $0x63,%edi
  jle    L4
  mov    %ecx,%edx
  imul   %r10,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,D87(%rip)
  cmp    $0x3e7,%edi
  jle    L36
  mov    %edx,%ecx
  imul   %r10,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,D11(%rip)
  cmp    $0x270f,%edi
  jle    L34
  mov    %ecx,%edx
  imul   %r10,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,D47(%rip)
  cmp    $0x1869f,%edi
  jle    L153
  mov    %edx,%ecx
  imul   %r10,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,D35(%rip)
  cmp    $0xf423f,%edi
  jle    L55
  mov    %ecx,%edx
  imul   %r10,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,D86(%rip)
  cmp    $0x98967f,%edi
  jle    L14
  add    $0x30,%edx
  mov    $0x8,%r11d
  mov    %dl,D10(%rip)
L32:
  add    %r11,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L133:
  jmp    1050 <utoa32@plt>
L153:
  mov    $0xb,%r11d
  jmp    L32
L35:
  mov    $0xf,%r11d
  jmp    L32
L4:
  mov    $0xe,%r11d
  jmp    L32
L36:
  mov    $0xd,%r11d
  jmp    L32
L34:
  mov    $0xc,%r11d
  jmp    L32
L55:
  mov    $0xa,%r11d
  jmp    L32
L14:
  mov    $0x9,%r11d
  jmp    L32
```

assistant: ```c
char *utoa64(const uint64_t x) {
  static char buf[32 + 1];
  uint32_t a, b, i;
  if (x > 99999999) {
    a = x / 100000000;
    b = x % 100000000;
    i = 31;
    do {
      buf[i--] = (a % 10) + '0';
      a /= 10;
    } while (a > 0);
    if (b > 0) {
      i = 31 - 16;
      do {
        buf[i--] = (b % 10) + '0';
        b /= 10;
      } while (b > 0);
    }
    return buf + i + 1;
  } else
    return utoa32(x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<EPIModeSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EPIModeSet(uint32_t ui32Base, uint32_t ui32Mode) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) = ui32Mode;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<EPIModeSet>:
  endbr64
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void EPIModeSet(uint32_t ui32Base, uint32_t ui32Mode) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) = ui32Mode;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<EPIModeSet>:
  endbr64
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void EPIModeSet(uint32_t ui32Base, uint32_t ui32Mode) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) = ui32Mode;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<EPIModeSet>:
  endbr64
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void EPIModeSet(uint32_t ui32Base, uint32_t ui32Mode) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) = ui32Mode;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninitvar_fpclassify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  flds   -0x1c(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <fpclassify@plt>
  add    $0x10,%rsp
  fldl   -0x18(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <fpclassify@plt>
  add    $0x10,%rsp
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  call   <fpclassify@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_fpclassify(void) {
  float f;
  (void)fpclassify(f);
  double d;
  (void)fpclassify(d);
  long double ld;
  (void)fpclassify(ld);
}
```