ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<binarySearch>:
  endbr64
  mov    %rdi,%r8
  cmp    %ecx,%edx
  jle    L15
  jmp    L16
  nopl   (%rax)
L46:
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jl     L16
L15:
  lea    (%rdx,%rcx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %esi,(%r8,%rdi,4)
  jg     L46
  jge    L3
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jge    L15
L16:
  mov    $0xffffffff,%r9d
L3:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int binarySearch(int A[], int s, int l, int r) {
  int mid;
  if (l <= r) {
    mid = (l + r) / 2;
    if (A[mid] > s)
      return binarySearch(A, s, l, mid - 1);
    else if (A[mid] < s)
      return binarySearch(A, s, mid + 1, r);
    else
      return mid;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<graphicsname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *graphicsname(void) {
  static char name[] = "X11";
  return name;
}
```
user: Translate the below assembly code into C programming language:

```asm
<graphicsname>:
  endbr64
  lea    D6(%rip),%rax
  ret
```

assistant: ```c
char *graphicsname(void) {
  static char name[] = "X11";
  return name;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<graphicsname>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

assistant: ```c
char *graphicsname(void) {
  static char name[] = "X11";
  return name;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<graphicsname>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

assistant: ```c
char *graphicsname(void) {
  static char name[] = "X11";
  return name;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aux_struct>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <space@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rdx,%rax,1),%eax
  sar    %eax
  lea    0x4(,%rax,4),%edi
  call   <space@plt>
  mov    %rax,%r13
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  movzbl (%r12),%eax
  test   %al,%al
  je     L104
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D8(%rip),%r14
  jmp    L81
L79:
  movslq %ebx,%rcx
  cmpb   $0x29,0x1(%r12,%rcx,1)
  jne    L96
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%rdx
L6:
  mov    (%rdx),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rdx)
  jne    L96
  add    $0x1,%ebx
  sub    $0x1,%ebp
  add    $0x1,%rcx
  sub    $0x4,%rdx
  cmpb   $0x29,0x1(%r12,%rcx,1)
  je     L6
L96:
  movb   $0x5d,(%r12,%rcx,1)
  movslq %ebp,%rax
  movslq 0x0(%r13,%rax,4),%rax
  movb   $0x5b,(%r12,%rax,1)
  sub    $0x1,%ebp
L46:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  je     L104
L81:
  cmp    $0x29,%al
  je     L79
  cmp    $0x2e,%al
  je     L46
  cmp    $0x28,%al
  je     L105
  mov    %r14,%rdi
  call   <nrerror@plt>
  jmp    L46
L105:
  add    $0x1,%ebp
  movslq %ebp,%rax
  mov    %ebx,0x0(%r13,%rax,4)
  jmp    L46
L104:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: Junk in structure at aux_structure


assistant: ```c
char *aux_struct(const char *structure) {
  int *match_paren;
  int i, o, p;
  char *string;
  string = (char *)space(sizeof(char) * (strlen(structure) + 1));
  match_paren = (int *)space(sizeof(int) * (strlen(structure) / 2 + 1));
  strcpy(string, structure);
  i = o = 0;
  while (string[i]) {
    switch (string[i]) {
    case '.':
      break;
    case '(':
      match_paren[++o] = i;
      break;
    case ')':
      p = i;
      while ((string[p + 1] == ')') && (match_paren[o - 1] == match_paren[o] - 1)) {
        p++;
        o--;
      }
      string[p] = ']';
      i = p;
      string[match_paren[o]] = '[';
      o--;
      break;
    default:
      nrerror("Junk in structure at aux_structure\n");
    }
    i++;
  }
  free(match_paren);
  return (string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<aux_struct>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <space@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  lea    0x4(,%rax,4),%edi
  call   <space@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  movzbl (%r12),%eax
  test   %al,%al
  je     L112
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  lea    D1(%rip),%r14
  jmp    L110
L135:
  mov    %r14,%rdi
  call   <nrerror@plt>
L62:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  je     L112
L110:
  cmp    $0x29,%al
  je     L38
  cmp    $0x2e,%al
  je     L62
  cmp    $0x28,%al
  jne    L135
  add    $0x1,%ebp
  movslq %ebp,%rax
  mov    %ebx,0x0(%r13,%rax,4)
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  jne    L110
L112:
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L38:
  movslq %ebx,%rsi
  movslq %ebp,%rax
  mov    %ebx,%r9d
  cmpb   $0x29,0x1(%r12,%rsi,1)
  lea    0x0(%r13,%rax,4),%rdx
  je     L81
  jmp    L76
L35:
  cmpb   $0x29,0x1(%r12,%rsi,1)
  jne    L71
L81:
  mov    %rdx,%rax
  sub    $0x4,%rdx
  mov    %r9d,%ebx
  mov    %rsi,%r8
  mov    (%rax),%ecx
  mov    %ebp,%edi
  lea    0x1(%r9),%r9d
  lea    0x1(%rsi),%rsi
  lea    -0x1(%rbp),%ebp
  sub    $0x1,%ecx
  cmp    %ecx,(%rdx)
  je     L35
  movb   $0x5d,(%r12,%r8,1)
  movslq (%rax),%rax
  lea    -0x1(%rdi),%ebp
  movb   $0x5b,(%r12,%rax,1)
  jmp    L62
L71:
  movslq %ebp,%rax
  mov    %rsi,%r8
  mov    %ebp,%edi
  mov    %r9d,%ebx
  lea    0x0(%r13,%rax,4),%rax
  movb   $0x5d,(%r12,%r8,1)
  lea    -0x1(%rdi),%ebp
  movslq (%rax),%rax
  movb   $0x5b,(%r12,%rax,1)
  jmp    L62
L76:
  lea    0x0(%r13,%rax,4),%rax
  mov    %rsi,%r8
  mov    %ebp,%edi
  movb   $0x5d,(%r12,%r8,1)
  movslq (%rax),%rax
  lea    -0x1(%rdi),%ebp
  movb   $0x5b,(%r12,%rax,1)
  jmp    L62
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: Junk in structure at aux_structure


assistant: ```c
char *aux_struct(const char *structure) {
  int *match_paren;
  int i, o, p;
  char *string;
  string = (char *)space(sizeof(char) * (strlen(structure) + 1));
  match_paren = (int *)space(sizeof(int) * (strlen(structure) / 2 + 1));
  strcpy(string, structure);
  i = o = 0;
  while (string[i]) {
    switch (string[i]) {
    case '.':
      break;
    case '(':
      match_paren[++o] = i;
      break;
    case ')':
      p = i;
      while ((string[p + 1] == ')') && (match_paren[o - 1] == match_paren[o] - 1)) {
        p++;
        o--;
      }
      string[p] = ']';
      i = p;
      string[match_paren[o]] = '[';
      o--;
      break;
    default:
      nrerror("Junk in structure at aux_structure\n");
    }
    i++;
  }
  free(match_paren);
  return (string);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aux_struct>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <space@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  lea    0x4(,%rax,4),%edi
  call   <space@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  movzbl (%r12),%eax
  test   %al,%al
  je     L90
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  lea    D1(%rip),%r14
  jmp    L38
L50:
  mov    %r14,%rdi
  call   <nrerror@plt>
L110:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  je     L90
L38:
  cmp    $0x29,%al
  je     L43
  cmp    $0x2e,%al
  je     L110
  cmp    $0x28,%al
  jne    L50
  add    $0x1,%ebp
  movslq %ebp,%rax
  mov    %ebx,0x0(%r13,%rax,4)
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  jne    L38
L90:
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L43:
  movslq %ebx,%rcx
  movslq %ebp,%rax
  cmpb   $0x29,0x1(%r12,%rcx,1)
  jne    L131
  lea    0x0(%r13,%rax,4),%rax
  mov    %ebx,%r10d
  mov    (%rax),%edi
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L83:
  cmpb   $0x29,0x1(%r12,%rcx,1)
  jne    L134
L81:
  mov    %rax,%rsi
  sub    $0x4,%rax
  mov    %edi,%edx
  mov    %r10d,%ebx
  mov    (%rax),%edi
  sub    $0x1,%edx
  mov    %rcx,%r9
  mov    %ebp,%r8d
  lea    0x1(%r10),%r10d
  lea    0x1(%rcx),%rcx
  lea    -0x1(%rbp),%ebp
  cmp    %edx,%edi
  je     L83
L17:
  movb   $0x5d,(%r12,%r9,1)
  movslq (%rsi),%rax
  lea    -0x1(%r8),%ebp
  movb   $0x5b,(%r12,%rax,1)
  jmp    L110
  nopl   0x0(%rax)
L134:
  movslq %ebp,%rax
  mov    %r10d,%ebx
  mov    %ebp,%r8d
  mov    %rcx,%r9
  lea    0x0(%r13,%rax,4),%rsi
  jmp    L17
L131:
  lea    0x0(%r13,%rax,4),%rsi
  mov    %ebp,%r8d
  mov    %rcx,%r9
  jmp    L17
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string

tool: D1: Junk in structure at aux_structure


assistant: ```c
char *aux_struct(const char *structure) {
  int *match_paren;
  int i, o, p;
  char *string;
  string = (char *)space(sizeof(char) * (strlen(structure) + 1));
  match_paren = (int *)space(sizeof(int) * (strlen(structure) / 2 + 1));
  strcpy(string, structure);
  i = o = 0;
  while (string[i]) {
    switch (string[i]) {
    case '.':
      break;
    case '(':
      match_paren[++o] = i;
      break;
    case ')':
      p = i;
      while ((string[p + 1] == ')') && (match_paren[o - 1] == match_paren[o] - 1)) {
        p++;
        o--;
      }
      string[p] = ']';
      i = p;
      string[match_paren[o]] = '[';
      o--;
      break;
    default:
      nrerror("Junk in structure at aux_structure\n");
    }
    i++;
  }
  free(match_paren);
  return (string);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    D35(%rip),%rax
  mov    %rax,(%rsp)
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%r13
  mov    $0x1,%r12d
  lea    D26(%rip),%r14
L3:
  mov    -0x8(%r13),%rbx
  movq   %rbx,%xmm0
  call   <f@plt>
  movq   %xmm0,%rbp
  movq   %rbx,%xmm0
  call   <fp@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  divsd  %xmm1,%xmm0
  movq   %rbx,%xmm2
  subsd  %xmm0,%xmm2
  movq   %xmm2,%rbx
  movsd  %xmm2,0x0(%r13)
  movapd %xmm2,%xmm0
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%r12d
  add    $0x8,%r13
  cmp    $0x65,%r12d
  jne    L3
  movsd  D54(%rip),%xmm0
  call   <fp@plt>
  movq   %xmm0,%rbp
  movq   %rbx,%xmm0
  call   <f@plt>
  movq   %rbp,%xmm3
  divsd  %xmm3,%xmm0
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <system@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x330,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D35
type_guessed: f64
name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D11
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string
name: parse_data
arguments: label: D54
type_guessed: f64
name: parse_data
arguments: label: D21
type_guessed: string
name: parse_data
arguments: label: D59
type_guessed: string

tool: D35: 3

tool: D0: ****************************************************************

tool: D11: *  Estimacion de una solucion por el metodo de Newton-Raphson  *

tool: D26: iteracion %d
 estimacion:%.15lf


tool: D54: 2

tool: D21: error= %.18lf


tool: D59: PAUSE

assistant: ```c
int main() {
  double x[101];
  int i;
  x[0] = 3;
  double a = 2;
  double b = 3;
  double error;
  double s;
  double minFp;
  printf("****************************************************************\n");
  printf("*  Estimacion de una solucion por el metodo de Newton-Raphson  *\n");
  printf("****************************************************************\n");
  for (i = 1; i <= 100; i++) {
    x[i] = x[i - 1] - (f(x[i - 1]) / fp(x[i - 1]));
    printf("iteracion %d\n estimacion:%.15lf\n", i, x[i]);
    s = x[i];
  }
  minFp = fp(a);
  error = (f(s)) / minFp;
  printf("error= %.18lf\n", error);
  system("PAUSE");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  lea    D58(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    $0x1,%ebx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x18(%rsp),%rbp
  call   <puts@plt>
  movsd  D51(%rip),%xmm1
  jmp    L13
L16:
  add    $0x8,%rbp
L13:
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <f@plt>
  movsd  (%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <fp@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %ebx,%esi
  mov    %r12,%rdi
  movsd  (%rsp),%xmm1
  mov    $0x1,%eax
  add    $0x1,%ebx
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x0(%rbp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  cmp    $0x65,%ebx
  movsd  (%rsp),%xmm1
  jne    L16
  movsd  D40(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <fp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   <f@plt>
  mov    $0x1,%eax
  divsd  (%rsp),%xmm0
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <system@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D58
type_infered: string
name: retrieve_data
arguments: tag: D49
type_infered: string
name: retrieve_data
arguments: tag: D51
type_infered: f64
name: retrieve_data
arguments: tag: D40
type_infered: f64
name: retrieve_data
arguments: tag: D54
type_infered: string
name: retrieve_data
arguments: tag: D53
type_infered: string

tool: D17: iteracion %d
 estimacion:%.15lf


tool: D58: ****************************************************************

tool: D49: *  Estimacion de una solucion por el metodo de Newton-Raphson  *

tool: D51: 3

tool: D40: 2

tool: D54: error= %.18lf


tool: D53: PAUSE

assistant: ```c
int main() {
  double x[101];
  int i;
  x[0] = 3;
  double a = 2;
  double b = 3;
  double error;
  double s;
  double minFp;
  printf("****************************************************************\n");
  printf("*  Estimacion de una solucion por el metodo de Newton-Raphson  *\n");
  printf("****************************************************************\n");
  for (i = 1; i <= 100; i++) {
    x[i] = x[i - 1] - (f(x[i - 1]) / fp(x[i - 1]));
    printf("iteracion %d\n estimacion:%.15lf\n", i, x[i]);
    s = x[i];
  }
  minFp = fp(a);
  error = (f(s)) / minFp;
  printf("error= %.18lf\n", error);
  system("PAUSE");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  mov    D10(%rip),%rax
  lea    0x18(%rsp),%rbx
  mov    %rax,0x10(%rsp)
  call   <puts@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    D62(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  movsd  -0x8(%rbx),%xmm1
  add    $0x8,%rbx
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <f@plt>
  movsd  (%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <fp@plt>
  movsd  (%rsp),%xmm1
  mov    %r12d,%esi
  mov    %rbp,%rdi
  movsd  0x8(%rsp),%xmm2
  mov    $0x1,%eax
  add    $0x1,%r12d
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,-0x8(%rbx)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  cmp    $0x65,%r12d
  movsd  (%rsp),%xmm1
  jne    L2
  movsd  D30(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <fp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   <f@plt>
  mov    $0x1,%eax
  divsd  (%rsp),%xmm0
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <system@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type_infered: string
name: unpack_data
arguments: label: D10
type_infered: f64
name: unpack_data
arguments: label: D52
type_infered: string
name: unpack_data
arguments: label: D62
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: f64
name: unpack_data
arguments: label: D48
type_infered: string
name: unpack_data
arguments: label: D50
type_infered: string

tool: D17: ****************************************************************

tool: D10: 3

tool: D52: *  Estimacion de una solucion por el metodo de Newton-Raphson  *

tool: D62: iteracion %d
 estimacion:%.15lf


tool: D30: 2

tool: D48: error= %.18lf


tool: D50: PAUSE

assistant: ```c
int main() {
  double x[101];
  int i;
  x[0] = 3;
  double a = 2;
  double b = 3;
  double error;
  double s;
  double minFp;
  printf("****************************************************************\n");
  printf("*  Estimacion de una solucion por el metodo de Newton-Raphson  *\n");
  printf("****************************************************************\n");
  for (i = 1; i <= 100; i++) {
    x[i] = x[i - 1] - (f(x[i - 1]) / fp(x[i - 1]));
    printf("iteracion %d\n estimacion:%.15lf\n", i, x[i]);
    s = x[i];
  }
  minFp = fp(a);
  error = (f(s)) / minFp;
  printf("error= %.18lf\n", error);
  system("PAUSE");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fields_buffer_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void fields_buffer_free(void *source) {
  struct fields_buffer *self = source;
  free(self);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fields_buffer_free>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fields_buffer_free(void *source) {
  struct fields_buffer *self = source;
  free(self);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fields_buffer_free>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void fields_buffer_free(void *source) {
  struct fields_buffer *self = source;
  free(self);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fields_buffer_free>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void fields_buffer_free(void *source) {
  struct fields_buffer *self = source;
  free(self);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cbc_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: %.02x

assistant: ```c
void cbc_print(unsigned char *str, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%.02x", str[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cbc_print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D8(%rip),%rbp
L15:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L15
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D8: %.02x

assistant: ```c
void cbc_print(unsigned char *str, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%.02x", str[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cbc_print>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L7:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L18:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D8: %.02x

assistant: ```c
void cbc_print(unsigned char *str, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%.02x", str[i]);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cbc_print>:
  endbr64
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L17:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L4:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string

tool: D9: %.02x

assistant: ```c
void cbc_print(unsigned char *str, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%.02x", str[i]);
  printf("\n");
}
```