ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<allocateDbl3DMatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  xor    %edi,%edi
  mov    %r14d,%r15d
  push   %r13
  mov    %esi,%r13d
  imul   %esi,%r15d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %r14,%rbx
  mov    %r15d,%r12d
  imul   %edx,%r12d
  sub    $0x28,%rsp
  shl    $0x3,%r12d
  test   %r14d,%r14d
  setne  %dil
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  test   %r13d,%r13d
  setne  %dil
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  test   %ebp,%ebp
  setne  %dil
  xor    %eax,%eax
  shl    $0x3,%r14
  call   <assert@plt>
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L15
  mov    %r15d,%edi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L79
  movslq %r12d,%rdi
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L40
  test   %ebx,%ebx
  je     L69
  mov    0x18(%rsp),%rax
  add    %rax,%r14
  mov    %rax,%r12
  lea    -0x1(%r13),%eax
  lea    0x8(,%rax,8),%rax
  mov    %r14,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rbp),%eax
  lea    0x8(,%rax,8),%r14
  nopl   0x0(%rax)
L57:
  mov    %r15,(%r12)
  test   %r13d,%r13d
  je     L75
  mov    0x10(%rsp),%rax
  lea    (%r15,%rax,1),%rbx
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x8,%r15
  mov    %rcx,-0x8(%r15)
  test   %ebp,%ebp
  je     L105
  mov    %rcx,%rdi
  mov    %r14,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
  add    %r14,%rcx
L105:
  cmp    %rbx,%r15
  jne    L16
L75:
  add    $0x8,%r12
  cmp    0x8(%rsp),%r12
  jne    L57
L69:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <PyErr_NoMemory@plt>
  jmp    L69
L40:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <PyErr_NoMemory@plt>
  movq   $0x0,0x18(%rsp)
  jmp    L69
L79:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <PyErr_NoMemory@plt>
  movq   $0x0,0x18(%rsp)
  jmp    L69
```

assistant: ```c
double ***allocateDbl3DMatrix(unsigned nm, unsigned nr, unsigned nc) {
  double ***mat_list_p;
  double **mat_walk;
  double *arr;
  const int arr_len = nm * nr * nc * (sizeof(double));
  unsigned i, j, k;
  ;
  assert(nm > 0);
  assert(nr > 0);
  assert(nc > 0);
  mat_list_p = (double ***)malloc(nm * sizeof(double **));
  if (mat_list_p == 0L) {
    PyErr_NoMemory();
    return 0L;
  }
  mat_walk = (double **)malloc(nr * nm * sizeof(double *));
  if (mat_walk == 0L) {
    free(mat_list_p);
    PyErr_NoMemory();
    return 0L;
  }
  arr = (double *)malloc(arr_len);
  if (arr == 0L) {
    free(mat_list_p);
    free(mat_walk);
    PyErr_NoMemory();
    return 0L;
  }
  for (i = 0; i < nm; ++i) {
    mat_list_p[i] = mat_walk;
    for (j = 0; j < nr; ++j) {
      *mat_walk++ = arr;
      for (k = 0; k < nc; ++k) {
        *arr++ = 0.0;
      }
    }
  }
  return mat_list_p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bf_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_low_high@plt>
  mov    $0x0,%eax
  call   <test_width@plt>
  mov    $0x0,%eax
  call   <test_shift@plt>
  mov    $0x0,%eax
  call   <test_rawmask@plt>
  mov    $0x0,%eax
  call   <test_unpack@plt>
  mov    $0x0,%eax
  call   <test_pack@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bf_test(void) {
  test_low_high();
  test_width();
  test_shift();
  test_rawmask();
  test_unpack();
  test_pack();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bf_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_low_high@plt>
  mov    $0x0,%eax
  call   <test_width@plt>
  mov    $0x0,%eax
  call   <test_shift@plt>
  mov    $0x0,%eax
  call   <test_rawmask@plt>
  mov    $0x0,%eax
  call   <test_unpack@plt>
  mov    $0x0,%eax
  call   <test_pack@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bf_test(void) {
  test_low_high();
  test_width();
  test_shift();
  test_rawmask();
  test_unpack();
  test_pack();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bf_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_low_high@plt>
  xor    %eax,%eax
  call   <test_width@plt>
  xor    %eax,%eax
  call   <test_shift@plt>
  xor    %eax,%eax
  call   <test_rawmask@plt>
  xor    %eax,%eax
  call   <test_unpack@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <test_pack@plt>
```

assistant: ```c
void bf_test(void) {
  test_low_high();
  test_width();
  test_shift();
  test_rawmask();
  test_unpack();
  test_pack();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: getopt test program
Usage: test [OPTION] [INPUT]
   INPUT           set input filename (doesn't do anything)
   -h              help menu (this screen)
   -i              interactive mode (doesn't do anything)
   -f              force mode (doesn't do anything)
   -r              recursive mode (doesn't do anything)
   -v[level]       set verbosity level (5 is default; doesn't do anything)
   -o filename     set output filename (doesn't do anything)


assistant: ```c
void help() {
  printf("getopt test program\n"
         "Usage: test [OPTION] [INPUT]\n"
         "   INPUT           set input filename (doesn't do anything)\n"
         "   -h              help menu (this screen)\n"
         "   -i              interactive mode (doesn't do anything)\n"
         "   -f              force mode (doesn't do anything)\n"
         "   -r              recursive mode (doesn't do anything)\n"
         "   -v[level]       set verbosity level (5 is default; doesn't do anything)\n"
         "   -o filename     set output filename (doesn't do anything)\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: getopt test program
Usage: test [OPTION] [INPUT]
   INPUT           set input filename (doesn't do anything)
   -h              help menu (this screen)
   -i              interactive mode (doesn't do anything)
   -f              force mode (doesn't do anything)
   -r              recursive mode (doesn't do anything)
   -v[level]       set verbosity level (5 is default; doesn't do anything)
   -o filename     set output filename (doesn't do anything)


assistant: ```c
void help() {
  printf("getopt test program\n"
         "Usage: test [OPTION] [INPUT]\n"
         "   INPUT           set input filename (doesn't do anything)\n"
         "   -h              help menu (this screen)\n"
         "   -i              interactive mode (doesn't do anything)\n"
         "   -f              force mode (doesn't do anything)\n"
         "   -r              recursive mode (doesn't do anything)\n"
         "   -v[level]       set verbosity level (5 is default; doesn't do anything)\n"
         "   -o filename     set output filename (doesn't do anything)\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<help>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: getopt test program
Usage: test [OPTION] [INPUT]
   INPUT           set input filename (doesn't do anything)
   -h              help menu (this screen)
   -i              interactive mode (doesn't do anything)
   -f              force mode (doesn't do anything)
   -r              recursive mode (doesn't do anything)
   -v[level]       set verbosity level (5 is default; doesn't do anything)
   -o filename     set output filename (doesn't do anything)


assistant: ```c
void help() {
  printf("getopt test program\n"
         "Usage: test [OPTION] [INPUT]\n"
         "   INPUT           set input filename (doesn't do anything)\n"
         "   -h              help menu (this screen)\n"
         "   -i              interactive mode (doesn't do anything)\n"
         "   -f              force mode (doesn't do anything)\n"
         "   -r              recursive mode (doesn't do anything)\n"
         "   -v[level]       set verbosity level (5 is default; doesn't do anything)\n"
         "   -o filename     set output filename (doesn't do anything)\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<help>:
  endbr64
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: getopt test program
Usage: test [OPTION] [INPUT]
   INPUT           set input filename (doesn't do anything)
   -h              help menu (this screen)
   -i              interactive mode (doesn't do anything)
   -f              force mode (doesn't do anything)
   -r              recursive mode (doesn't do anything)
   -v[level]       set verbosity level (5 is default; doesn't do anything)
   -o filename     set output filename (doesn't do anything)


assistant: ```c
void help() {
  printf("getopt test program\n"
         "Usage: test [OPTION] [INPUT]\n"
         "   INPUT           set input filename (doesn't do anything)\n"
         "   -h              help menu (this screen)\n"
         "   -i              interactive mode (doesn't do anything)\n"
         "   -f              force mode (doesn't do anything)\n"
         "   -r              recursive mode (doesn't do anything)\n"
         "   -v[level]       set verbosity level (5 is default; doesn't do anything)\n"
         "   -o filename     set output filename (doesn't do anything)\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<limit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L20
  mov    -0x8(%rbp),%eax
  jmp    L24
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L7
  mov    -0xc(%rbp),%eax
  jmp    L24
L7:
  mov    -0x4(%rbp),%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int limit(int val, int min, int max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<limit>:
  endbr64
  cmp    %edx,%edi
  cmovle %edi,%edx
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edx,%eax
  ret
```

assistant: ```c
int limit(int val, int min, int max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<limit>:
  endbr64
  cmp    %edx,%edi
  mov    %esi,%eax
  cmovle %edi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int limit(int val, int min, int max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<limit>:
  endbr64
  cmp    %edx,%edi
  mov    %esi,%eax
  cmovle %edi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int limit(int val, int min, int max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a;
  a = 1 + 2;
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  a = 1 + 2;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  a = 1 + 2;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  a = 1 + 2;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_checkadd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  xor    -0x1c(%rbp),%eax
  shr    $0x1f,%eax
  and    $0x1,%eax
  test   %al,%al
  je     L64
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L13
L64:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L53
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  neg    %eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_longadd@plt>
  mov    -0x10(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L38
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L38
  mov    $0x1,%eax
  jmp    L13
L38:
  mov    $0x0,%eax
  jmp    L13
L53:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_longadd@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  not    %eax
  shr    $0x1f,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
char _checkadd(int *s1, int s2) {
  unsigned u1, u2;
  if ((*s1 < 0) ^ (s2 < 0)) {
    *s1 += s2;
    return 1;
  }
  if (s2 < 0) {
    u1 = -*s1;
    u2 = -s2;
    _longadd(&u1, &u2);
    *s1 = -(int)u1;
    return u2 == 0 && *s1 < 0;
  }
  u1 = *s1;
  u2 = s2;
  _longadd(&u1, &u2);
  *s1 = u1;
  return *s1 >= 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<_checkadd>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  mov    %eax,%ecx
  xor    %esi,%ecx
  js     L43
  test   %esi,%esi
  js     L18
  mov    %eax,(%rsp)
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <_longadd@plt>
  mov    (%rsp),%eax
  mov    %eax,(%rbx)
  not    %eax
  shr    $0x1f,%eax
L40:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  ret
L43:
  add    %esi,%eax
  mov    %eax,(%rdi)
  mov    $0x1,%eax
  jmp    L40
L18:
  neg    %eax
  mov    %eax,(%rsp)
  neg    %esi
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <_longadd@plt>
  mov    (%rsp),%edx
  mov    %edx,%eax
  neg    %eax
  mov    %eax,(%rbx)
  cmpl   $0x0,0x4(%rsp)
  sete   %al
  test   %edx,%edx
  setg   %dl
  and    %edx,%eax
  jmp    L40
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char _checkadd(int *s1, int s2) {
  unsigned u1, u2;
  if ((*s1 < 0) ^ (s2 < 0)) {
    *s1 += s2;
    return 1;
  }
  if (s2 < 0) {
    u1 = -*s1;
    u2 = -s2;
    _longadd(&u1, &u2);
    *s1 = -(int)u1;
    return u2 == 0 && *s1 < 0;
  }
  u1 = *s1;
  u2 = s2;
  _longadd(&u1, &u2);
  *s1 = u1;
  return *s1 >= 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<_checkadd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  mov    %eax,%ecx
  xor    %esi,%ecx
  js     L15
  test   %esi,%esi
  js     L38
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rdi
  lea    0x4(%rsp),%rsi
  mov    %eax,(%rsp)
  call   <_longadd@plt>
  mov    (%rsp),%eax
  mov    %eax,(%rbx)
  not    %eax
  shr    $0x1f,%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  add    %esi,%eax
  mov    %eax,(%rdi)
  mov    $0x1,%eax
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L38:
  neg    %esi
  neg    %eax
  mov    %rsp,%rdi
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %eax,(%rsp)
  call   <_longadd@plt>
  mov    (%rsp),%edx
  mov    %edx,%eax
  neg    %eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  sete   %al
  test   %edx,%edx
  setg   %dl
  and    %edx,%eax
  jmp    L3
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char _checkadd(int *s1, int s2) {
  unsigned u1, u2;
  if ((*s1 < 0) ^ (s2 < 0)) {
    *s1 += s2;
    return 1;
  }
  if (s2 < 0) {
    u1 = -*s1;
    u2 = -s2;
    _longadd(&u1, &u2);
    *s1 = -(int)u1;
    return u2 == 0 && *s1 < 0;
  }
  u1 = *s1;
  u2 = s2;
  _longadd(&u1, &u2);
  *s1 = u1;
  return *s1 >= 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_checkadd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  mov    %eax,%ecx
  xor    %esi,%ecx
  js     L2
  test   %esi,%esi
  js     L27
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rdi
  lea    0x4(%rsp),%rsi
  mov    %eax,(%rsp)
  call   <_longadd@plt>
  mov    (%rsp),%eax
  mov    %eax,(%rbx)
  not    %eax
  shr    $0x1f,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  add    %esi,%eax
  mov    %eax,(%rdi)
  mov    $0x1,%eax
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L27:
  neg    %esi
  neg    %eax
  mov    %rsp,%rdi
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %eax,(%rsp)
  call   <_longadd@plt>
  mov    (%rsp),%edx
  mov    %edx,%eax
  neg    %eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  sete   %al
  test   %edx,%edx
  setg   %dl
  and    %edx,%eax
  jmp    L9
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char _checkadd(int *s1, int s2) {
  unsigned u1, u2;
  if ((*s1 < 0) ^ (s2 < 0)) {
    *s1 += s2;
    return 1;
  }
  if (s2 < 0) {
    u1 = -*s1;
    u2 = -s2;
    _longadd(&u1, &u2);
    *s1 = -(int)u1;
    return u2 == 0 && *s1 < 0;
  }
  u1 = *s1;
  u2 = s2;
  _longadd(&u1, &u2);
  *s1 = u1;
  return *s1 >= 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mode_Mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L13
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L18
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L18:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L9
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int mode_Mult(double *th, int lo, int hi) {
  int i, j;
  i = 0;
  for (j = 1; j <= hi - lo; j++) {
    if (th[j] > th[i]) {
      i = j;
    }
  }
  return i + lo;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mode_Mult>:
  endbr64
  sub    %esi,%edx
  test   %edx,%edx
  jle    L23
  lea    0x1(%rdx),%r9d
  mov    $0x1,%edx
  mov    $0x0,%ecx
L6:
  movslq %ecx,%r8
  movsd  (%rdi,%rdx,8),%xmm0
  ucomisd (%rdi,%r8,8),%xmm0
  cmova  %edx,%ecx
  add    $0x1,%rdx
  cmp    %r9,%rdx
  jne    L6
L10:
  lea    (%rsi,%rcx,1),%eax
  ret
L23:
  mov    $0x0,%ecx
  jmp    L10
```

assistant: ```c
int mode_Mult(double *th, int lo, int hi) {
  int i, j;
  i = 0;
  for (j = 1; j <= hi - lo; j++) {
    if (th[j] > th[i]) {
      i = j;
    }
  }
  return i + lo;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mode_Mult>:
  endbr64
  sub    %esi,%edx
  test   %edx,%edx
  jle    L10
  lea    0x1(%rdx),%r9d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopl   (%rax)
L0:
  movslq %ecx,%r8
  movsd  (%rdi,%rdx,8),%xmm0
  ucomisd (%rdi,%r8,8),%xmm0
  cmova  %edx,%ecx
  add    $0x1,%rdx
  cmp    %rdx,%r9
  jne    L0
  lea    (%rcx,%rsi,1),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %esi,%eax
  ret
```

assistant: ```c
int mode_Mult(double *th, int lo, int hi) {
  int i, j;
  i = 0;
  for (j = 1; j <= hi - lo; j++) {
    if (th[j] > th[i]) {
      i = j;
    }
  }
  return i + lo;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mode_Mult>:
  endbr64
  sub    %esi,%edx
  test   %edx,%edx
  jle    L2
  movsd  (%rdi),%xmm0
  lea    0x1(%rdx),%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopl   0x0(%rax)
L17:
  movsd  (%rdi,%rdx,8),%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %edx,%ecx
  add    $0x1,%rdx
  movapd %xmm1,%xmm0
  cmp    %rdx,%r8
  jne    L17
  lea    (%rcx,%rsi,1),%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    %esi,%eax
  ret
```

assistant: ```c
int mode_Mult(double *th, int lo, int hi) {
  int i, j;
  i = 0;
  for (j = 1; j <= hi - lo; j++) {
    if (th[j] > th[i]) {
      i = j;
    }
  }
  return i + lo;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitmap_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jg     L35
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rsi
  mov    D5(%rip),%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L33
  mov    D5(%rip),%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  sub    $0x1,%rax
  jmp    L3
L33:
  mov    $0xffffffffffffffff,%rax
L3:
  and    %rsi,%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L37
L35:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__bitmap_empty@plt>
L37:
  leave
  ret
```

assistant: ```c
int bitmap_empty(const unsigned long *src, int nbits) {
  if (nbits <= __WORDSIZE)
    return !(*src & (((nbits) % __WORDSIZE) ? (1UL << ((nbits) % __WORDSIZE)) - 1 : ~0UL));
  else
    return __bitmap_empty(src, nbits);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bitmap_empty>:
  endbr64
  mov    %esi,%eax
  mov    D9(%rip),%rdx
  mov    (%rdx),%esi
  cmp    %eax,%esi
  jl     L18
  mov    (%rdi),%rdi
  cltd
  idiv   %esi
  mov    $0xffffffffffffffff,%rax
  test   %edx,%edx
  je     L16
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%rax
  sub    $0x1,%rax
L16:
  test   %rax,%rdi
  sete   %al
  movzbl %al,%eax
  ret
L18:
  sub    $0x8,%rsp
  mov    %eax,%esi
  call   <__bitmap_empty@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bitmap_empty(const unsigned long *src, int nbits) {
  if (nbits <= __WORDSIZE)
    return !(*src & (((nbits) % __WORDSIZE) ? (1UL << ((nbits) % __WORDSIZE)) - 1 : ~0UL));
  else
    return __bitmap_empty(src, nbits);
}
```
user: What is the c source code of the assembly code below:

```asm
<bitmap_empty>:
  endbr64
  mov    D0(%rip),%rdx
  mov    %esi,%eax
  mov    (%rdx),%esi
  cmp    %eax,%esi
  jl     L5
  cltd
  mov    (%rdi),%rdi
  idiv   %esi
  test   %edx,%edx
  je     L12
  mov    $0xffffffffffffffff,%rax
  mov    %edx,%ecx
  shl    %cl,%rax
  not    %rax
  and    %rax,%rdi
L12:
  xor    %eax,%eax
  test   %rdi,%rdi
  sete   %al
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%esi
  jmp    1050 <__bitmap_empty@plt>
```

assistant: ```c
int bitmap_empty(const unsigned long *src, int nbits) {
  if (nbits <= __WORDSIZE)
    return !(*src & (((nbits) % __WORDSIZE) ? (1UL << ((nbits) % __WORDSIZE)) - 1 : ~0UL));
  else
    return __bitmap_empty(src, nbits);
}
```