ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rawfile_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L12
  mov    %rsi,%rdi
  xor    %ecx,%ecx
  lea    D2(%rip),%rsi
  call   <util_concat@plt>
  mov    %rax,%rbp
L19:
  mov    %rbp,%rdi
  call   <ioutil_remove@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <lib_free@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  sar    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  and    $0xfffffffd,%eax
  add    $0x4,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  call   <lib_stralloc@plt>
  mov    %rax,%rbp
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string

tool: D2: /

assistant: ```c
unsigned int rawfile_remove(const char *src_name, const char *path) {
  char *complete_src;
  int rc;
  if (path == NULL)
    complete_src = lib_stralloc(src_name);
  else
    complete_src = util_concat(path, "/", src_name, NULL);
  rc = ioutil_remove(complete_src);
  lib_free(complete_src);
  if (rc < 0)
    return 1;
  return 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *ret;
  int len;
  len = strlen(s) + 1;
  ret = malloc(len);
  if (ret)
    memcpy(ret, s, len);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L9:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *ret;
  int len;
  len = strlen(s) + 1;
  ret = malloc(len);
  if (ret)
    memcpy(ret, s, len);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L7:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *ret;
  int len;
  len = strlen(s) + 1;
  ret = malloc(len);
  if (ret)
    memcpy(ret, s, len);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L3:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *ret;
  int len;
  len = strlen(s) + 1;
  ret = malloc(len);
  if (ret)
    memcpy(ret, s, len);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: Main


assistant: ```c
int main() {
  printf("Main\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: Main


assistant: ```c
int main() {
  printf("Main\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: Main


assistant: ```c
int main() {
  printf("Main\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: Main


assistant: ```c
int main() {
  printf("Main\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <init_torus@plt>
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init() {
  void init_bondi(void);
  void init_torus(void);
  void init_sndwave(void);
  void init_entwave(void);
  void init_monopole(double Rout_val);
  switch (4) {
  case 1:
  case 2:
    init_monopole(1e3);
    break;
  case 3:
    init_monopole(100.);
    break;
  case 4:
    init_torus();
    break;
  case 7:
    init_sndwave();
    break;
  case 8:
    init_entwave();
    break;
  case 5:
  case 6:
    init_bondi();
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  call   <init_torus@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init() {
  void init_bondi(void);
  void init_torus(void);
  void init_sndwave(void);
  void init_entwave(void);
  void init_monopole(double Rout_val);
  switch (4) {
  case 1:
  case 2:
    init_monopole(1e3);
    break;
  case 3:
    init_monopole(100.);
    break;
  case 4:
    init_torus();
    break;
  case 7:
    init_sndwave();
    break;
  case 8:
    init_entwave();
    break;
  case 5:
  case 6:
    init_bondi();
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init>:
  endbr64
  jmp    1050 <init_torus@plt>
```

assistant: ```c
void init() {
  void init_bondi(void);
  void init_torus(void);
  void init_sndwave(void);
  void init_entwave(void);
  void init_monopole(double Rout_val);
  switch (4) {
  case 1:
  case 2:
    init_monopole(1e3);
    break;
  case 3:
    init_monopole(100.);
    break;
  case 4:
    init_torus();
    break;
  case 7:
    init_sndwave();
    break;
  case 8:
    init_entwave();
    break;
  case 5:
  case 6:
    init_bondi();
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init>:
  endbr64
  jmp    1050 <init_torus@plt>
```

assistant: ```c
void init() {
  void init_bondi(void);
  void init_torus(void);
  void init_sndwave(void);
  void init_entwave(void);
  void init_monopole(double Rout_val);
  switch (4) {
  case 1:
  case 2:
    init_monopole(1e3);
    break;
  case 3:
    init_monopole(100.);
    break;
  case 4:
    init_torus();
    break;
  case 7:
    init_sndwave();
    break;
  case 8:
    init_entwave();
    break;
  case 5:
  case 6:
    init_bondi();
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CyBtldr_ParseRowData>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x320,%rsp
  mov    %rdx,%r13
  mov    0x350(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x318(%rsp)
  xor    %eax,%eax
  mov    $0x3,%edx
  cmp    $0x6,%edi
  jbe    L22
  mov    %rcx,%r12
  mov    %r8,%rbp
  mov    %r9,%rbx
  mov    $0x5,%edx
  cmpb   $0x3a,(%rsi)
  je     L60
L22:
  mov    0x318(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    %edx,%eax
  add    $0x320,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L60:
  lea    0x10(%rsp),%rcx
  lea    0xe(%rsp),%rdx
  add    $0x1,%rsi
  sub    $0x1,%edi
  call   <CyBtldr_FromAscii@plt>
  mov    %eax,%edx
  movzbl 0x10(%rsp),%eax
  mov    %al,0x0(%r13)
  movzbl 0x11(%rsp),%ecx
  shl    $0x8,%ecx
  movzbl 0x12(%rsp),%eax
  or     %ecx,%eax
  mov    %ax,(%r12)
  movzbl 0x13(%rsp),%ecx
  shl    $0x8,%ecx
  movzbl 0x14(%rsp),%eax
  or     %ecx,%eax
  mov    %ax,(%rbx)
  movzwl 0xe(%rsp),%ecx
  lea    -0x1(%rcx),%eax
  cltq
  movzbl 0x10(%rsp,%rax,1),%eax
  mov    %al,(%r14)
  movzwl (%rbx),%esi
  movzwl %si,%eax
  add    $0x6,%eax
  cmp    %eax,%ecx
  je     L25
  mov    $0x4,%edx
  jmp    L22
L25:
  test   %si,%si
  je     L22
  mov    $0x0,%eax
  lea    0x15(%rsp),%rsi
L63:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  movzwl (%rbx),%ecx
  cmp    %eax,%ecx
  ja     L63
  jmp    L22
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CyBtldr_ParseRowData(unsigned int bufSize, unsigned char *buffer, unsigned char *arrayId, unsigned short *rowNum, unsigned char *rowData, unsigned short *size, unsigned char *checksum) {
  const unsigned short MIN_SIZE = 6;
  const int DATA_OFFSET = 5;
  unsigned int i;
  unsigned short hexSize;
  unsigned char hexData[768];
  int err = 0x00;
  if (bufSize <= MIN_SIZE)
    err = 0x03;
  else if (buffer[0] == ':') {
    err = CyBtldr_FromAscii(bufSize - 1, &buffer[1], &hexSize, hexData);
    *arrayId = hexData[0];
    *rowNum = (hexData[1] << 8) | (hexData[2]);
    *size = (hexData[3] << 8) | (hexData[4]);
    *checksum = (hexData[hexSize - 1]);
    if ((*size + MIN_SIZE) == hexSize) {
      for (i = 0; i < *size; i++) {
        rowData[i] = (hexData[DATA_OFFSET + i]);
      }
    } else
      err = 0x04;
  } else
    err = 0x05;
  return err;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CyBtldr_ParseRowData>:
  endbr64
  push   %r14
  mov    $0x3,%r10d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x320,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x318(%rsp)
  xor    %eax,%eax
  mov    0x350(%rsp),%r14
  cmp    $0x6,%edi
  jbe    L39
  cmpb   $0x3a,(%rsi)
  mov    $0x5,%r10d
  je     L50
L39:
  mov    0x318(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x320,%rsp
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L50:
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  lea    0xe(%rsp),%rdx
  add    $0x1,%rsi
  lea    0x10(%rsp),%rcx
  sub    $0x1,%edi
  mov    %r9,%r13
  mov    %r8,%r12
  call   <CyBtldr_FromAscii@plt>
  movzwl 0xe(%rsp),%edx
  mov    %eax,%r10d
  movzbl 0x10(%rsp),%eax
  mov    %al,(%rbx)
  movzwl 0x11(%rsp),%eax
  rol    $0x8,%ax
  mov    %ax,0x0(%rbp)
  movzwl 0x13(%rsp),%eax
  rol    $0x8,%ax
  mov    %ax,0x0(%r13)
  lea    -0x1(%rdx),%eax
  cltq
  movzbl 0x10(%rsp,%rax,1),%eax
  mov    %al,(%r14)
  movzwl 0x0(%r13),%eax
  mov    %eax,%ecx
  add    $0x6,%eax
  cmp    %eax,%edx
  je     L35
  mov    $0x4,%r10d
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L35:
  test   %cx,%cx
  je     L39
  xor    %eax,%eax
  lea    0x15(%rsp),%rcx
  nopl   0x0(%rax,%rax,1)
L64:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  movzwl 0x0(%r13),%edx
  add    $0x1,%rax
  cmp    %eax,%edx
  ja     L64
  jmp    L39
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CyBtldr_ParseRowData(unsigned int bufSize, unsigned char *buffer, unsigned char *arrayId, unsigned short *rowNum, unsigned char *rowData, unsigned short *size, unsigned char *checksum) {
  const unsigned short MIN_SIZE = 6;
  const int DATA_OFFSET = 5;
  unsigned int i;
  unsigned short hexSize;
  unsigned char hexData[768];
  int err = 0x00;
  if (bufSize <= MIN_SIZE)
    err = 0x03;
  else if (buffer[0] == ':') {
    err = CyBtldr_FromAscii(bufSize - 1, &buffer[1], &hexSize, hexData);
    *arrayId = hexData[0];
    *rowNum = (hexData[1] << 8) | (hexData[2]);
    *size = (hexData[3] << 8) | (hexData[4]);
    *checksum = (hexData[hexSize - 1]);
    if ((*size + MIN_SIZE) == hexSize) {
      for (i = 0; i < *size; i++) {
        rowData[i] = (hexData[DATA_OFFSET + i]);
      }
    } else
      err = 0x04;
  } else
    err = 0x05;
  return err;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<CyBtldr_ParseRowData>:
  endbr64
  push   %r14
  mov    $0x3,%r10d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x320,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x318(%rsp)
  xor    %eax,%eax
  mov    0x350(%rsp),%r14
  cmp    $0x6,%edi
  jbe    L17
  cmpb   $0x3a,(%rsi)
  mov    $0x5,%r10d
  je     L0
L17:
  mov    0x318(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x320,%rsp
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L0:
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  lea    0xe(%rsp),%rdx
  add    $0x1,%rsi
  lea    0x10(%rsp),%rcx
  sub    $0x1,%edi
  mov    %r9,%r13
  mov    %r8,%r12
  call   <CyBtldr_FromAscii@plt>
  movzwl 0xe(%rsp),%edx
  mov    %eax,%r10d
  movzbl 0x10(%rsp),%eax
  mov    %al,(%rbx)
  movzwl 0x11(%rsp),%eax
  rol    $0x8,%ax
  mov    %ax,0x0(%rbp)
  movzwl 0x13(%rsp),%eax
  rol    $0x8,%ax
  mov    %ax,0x0(%r13)
  lea    -0x1(%rdx),%eax
  cltq
  movzbl 0x10(%rsp,%rax,1),%eax
  mov    %al,(%r14)
  movzwl 0x0(%r13),%eax
  mov    %eax,%ecx
  add    $0x6,%eax
  cmp    %eax,%edx
  je     L53
  mov    $0x4,%r10d
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L53:
  test   %cx,%cx
  je     L17
  xor    %eax,%eax
  lea    0x15(%rsp),%rcx
  nopl   0x0(%rax,%rax,1)
L16:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  movzwl 0x0(%r13),%edx
  add    $0x1,%rax
  cmp    %eax,%edx
  ja     L16
  jmp    L17
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CyBtldr_ParseRowData(unsigned int bufSize, unsigned char *buffer, unsigned char *arrayId, unsigned short *rowNum, unsigned char *rowData, unsigned short *size, unsigned char *checksum) {
  const unsigned short MIN_SIZE = 6;
  const int DATA_OFFSET = 5;
  unsigned int i;
  unsigned short hexSize;
  unsigned char hexData[768];
  int err = 0x00;
  if (bufSize <= MIN_SIZE)
    err = 0x03;
  else if (buffer[0] == ':') {
    err = CyBtldr_FromAscii(bufSize - 1, &buffer[1], &hexSize, hexData);
    *arrayId = hexData[0];
    *rowNum = (hexData[1] << 8) | (hexData[2]);
    *size = (hexData[3] << 8) | (hexData[4]);
    *checksum = (hexData[hexSize - 1]);
    if ((*size + MIN_SIZE) == hexSize) {
      for (i = 0; i < *size; i++) {
        rowData[i] = (hexData[DATA_OFFSET + i]);
      }
    } else
      err = 0x04;
  } else
    err = 0x05;
  return err;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x1,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x48(%rbp)
  movq   $0x1,-0x40(%rbp)
  mov    -0x48(%rbp),%rax
  movq   $0x1,(%rax)
  movq   $0x2,-0x38(%rbp)
  jmp    L83
L36:
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L59
L67:
  mov    -0x28(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  cmp    %rax,%rdx
  jb     L47
  lea    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <grow@plt>
  mov    %rax,-0x48(%rbp)
L47:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  imul   -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rdi
  sar    $0x3f,%rdi
  sub    %rdi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,(%rsi)
  mov    -0x10(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  addq   $0x1,-0x28(%rbp)
L59:
  mov    -0x28(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jl     L67
  cmpq   $0x0,-0x30(%rbp)
  jne    L67
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  addq   $0x1,-0x38(%rbp)
L83:
  mov    -0x38(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jle    L36
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L25
L39:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jl     L39
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

assistant: ```c
uint64_t solve(uint64_t n) {
  size_t nalloc = 1;
  uint8_t *digits = calloc(nalloc, sizeof(uint8_t));
  uint32_t nused = 1;
  digits[0] = 1;
  for (uint32_t x = 2; x <= n; ++x) {
    uint32_t carry = 0;
    uint32_t i = 0;
    for (i = 0; i < nused || carry; ++i) {
      if (i >= nalloc)
        digits = grow(digits, &nalloc);
      uint32_t value = carry + x * digits[i];
      digits[i] = value % 10;
      carry = value / 10;
    }
    nused = i;
  }
  uint64_t sum = 0;
  for (uint64_t i = 0; i < nused; ++i) {
    sum += digits[i];
  }
  free(digits);
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<solve>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x1,0x10(%rsp)
  mov    $0x8,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  movq   $0x1,(%rax)
  mov    $0x2,%r13d
  mov    $0x1,%r14d
  movabs $0x6666666666666667,%r15
  cmp    $0x1,%rbx
  jg     L54
  mov    (%rax),%rbp
  jmp    L99
L29:
  mov    %rbx,%r12
  cmp    %rbx,0x10(%rsp)
  jbe    L73
L37:
  lea    (%rdi,%r12,8),%rsi
  mov    %r13,%rcx
  imul   (%rsi),%rcx
  add    %rbp,%rcx
  mov    %rcx,%rax
  imul   %r15
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,(%rsi)
  mov    %rdx,%rbp
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jl     L29
  test   %rdx,%rdx
  jne    L29
L13:
  add    $0x1,%r13
  cmp    %r13,0x8(%rsp)
  jl     L70
  mov    %rbx,%r14
L54:
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  test   %r14,%r14
  jg     L29
  jmp    L13
L73:
  lea    0x10(%rsp),%rsi
  call   <grow@plt>
  mov    %rax,%rdi
  jmp    L37
L70:
  test   %rbx,%rbx
  jle    L93
  mov    $0x0,%eax
  mov    $0x0,%ebp
L101:
  add    (%rdi,%rax,8),%rbp
  add    $0x1,%rax
  cmp    %rbx,%rax
  jl     L101
L99:
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    %rbp,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L93:
  mov    $0x0,%ebp
  jmp    L99
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t solve(uint64_t n) {
  size_t nalloc = 1;
  uint8_t *digits = calloc(nalloc, sizeof(uint8_t));
  uint32_t nused = 1;
  digits[0] = 1;
  for (uint32_t x = 2; x <= n; ++x) {
    uint32_t carry = 0;
    uint32_t i = 0;
    for (i = 0; i < nused || carry; ++i) {
      if (i >= nalloc)
        digits = grow(digits, &nalloc);
      uint32_t value = carry + x * digits[i];
      digits[i] = value % 10;
      carry = value / 10;
    }
    nused = i;
  }
  uint64_t sum = 0;
  for (uint64_t i = 0; i < nused; ++i) {
    sum += digits[i];
  }
  free(digits);
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<solve>:
  endbr64
  push   %r15
  mov    $0x8,%esi
  push   %r14
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x1,(%rsp)
  call   <calloc@plt>
  movq   $0x1,(%rax)
  mov    %rax,%rdi
  cmp    $0x1,%rbp
  jle    L65
  mov    $0x2,%r13d
  mov    $0x1,%r14d
  movabs $0x6666666666666667,%r15
  nopl   0x0(%rax)
L16:
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  nopl   (%rax)
L33:
  cmp    %r12,(%rsp)
  jbe    L66
L63:
  lea    0x0(,%r12,8),%r8
  add    $0x1,%r12
  lea    (%rdi,%r8,1),%rsi
  mov    (%rsi),%rcx
  imul   %r13,%rcx
  add    %rbx,%rcx
  mov    %rcx,%rax
  imul   %r15
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rdx,%rbx
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,(%rsi)
  cmp    %r14,%r12
  jl     L33
  test   %rdx,%rdx
  jne    L33
  add    $0x1,%r13
  cmp    %r13,%rbp
  jl     L76
  mov    %r12,%r14
  jmp    L16
  nopl   0x0(%rax)
L66:
  mov    %rsp,%rsi
  call   <grow@plt>
  mov    %rax,%rdi
  jmp    L63
  nopl   (%rax)
L76:
  mov    %rdi,%rax
  lea    0x8(%rdi,%r8,1),%rdx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L75:
  add    (%rax),%r12
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L75
L65:
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t solve(uint64_t n) {
  size_t nalloc = 1;
  uint8_t *digits = calloc(nalloc, sizeof(uint8_t));
  uint32_t nused = 1;
  digits[0] = 1;
  for (uint32_t x = 2; x <= n; ++x) {
    uint32_t carry = 0;
    uint32_t i = 0;
    for (i = 0; i < nused || carry; ++i) {
      if (i >= nalloc)
        digits = grow(digits, &nalloc);
      uint32_t value = carry + x * digits[i];
      digits[i] = value % 10;
      carry = value / 10;
    }
    nused = i;
  }
  uint64_t sum = 0;
  for (uint64_t i = 0; i < nused; ++i) {
    sum += digits[i];
  }
  free(digits);
  return sum;
}
```