ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_revstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L3
  nop
L4:
  mov    %r12,%rdi
  call   <my_strlen@plt>
  mov    %r12,%rdi
  sub    %ebx,%eax
  cltq
  movzbl -0x1(%r12,%rax,1),%ebp
  call   <my_strlen@plt>
  movzbl (%r12,%rbx,1),%edx
  sub    %ebx,%eax
  cltq
  mov    %dl,-0x1(%r12,%rax,1)
  mov    %bpl,(%r12,%rbx,1)
  add    $0x1,%rbx
L3:
  mov    %r12,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L4
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_revstr(char *str) {
  int i;
  char c;
  i = 0;
  c = 0;
  while (i < my_strlen(str) / 2) {
    c = str[my_strlen(str) - i - 1];
    str[my_strlen(str) - i - 1] = str[i];
    str[i] = c;
    i++;
  }
  return (str);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_revstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L8
  nop
L13:
  mov    %r12,%rdi
  call   <my_strlen@plt>
  mov    %r12,%rdi
  sub    %ebx,%eax
  cltq
  movzbl -0x1(%r12,%rax,1),%ebp
  call   <my_strlen@plt>
  movzbl (%r12,%rbx,1),%edx
  sub    %ebx,%eax
  cltq
  mov    %dl,-0x1(%r12,%rax,1)
  mov    %bpl,(%r12,%rbx,1)
  add    $0x1,%rbx
L8:
  mov    %r12,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L13
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_revstr(char *str) {
  int i;
  char c;
  i = 0;
  c = 0;
  while (i < my_strlen(str) / 2) {
    c = str[my_strlen(str) - i - 1];
    str[my_strlen(str) - i - 1] = str[i];
    str[i] = c;
    i++;
  }
  return (str);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <check_float@plt>
  mov    $0x0,%eax
  call   <check_double@plt>
  mov    $0x0,%eax
  call   <check_long_double@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  check_float();
  check_double();
  check_long_double();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <check_float@plt>
  mov    $0x0,%eax
  call   <check_double@plt>
  mov    $0x0,%eax
  call   <check_long_double@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  check_float();
  check_double();
  check_long_double();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <check_float@plt>
  xor    %eax,%eax
  call   <check_double@plt>
  xor    %eax,%eax
  call   <check_long_double@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  check_float();
  check_double();
  check_long_double();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <check_float@plt>
  xor    %eax,%eax
  call   <check_double@plt>
  xor    %eax,%eax
  call   <check_long_double@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  check_float();
  check_double();
  check_long_double();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  nop
L8:
  cmpl   $0x4,-0x4(%rbp)
  jle    L8
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int i = 0;
  while (i < 5)
    ;
  printf(i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
main() {
  int i = 0;
  while (i < 5)
    ;
  printf(i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
main() {
  int i = 0;
  while (i < 5)
    ;
  printf(i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
main() {
  int i = 0;
  while (i < 5)
    ;
  printf(i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x5320574f4c4c4559,%rax
  movabs $0x454e4952414d4255,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movq   $0x0,-0x28(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x28(%rbp)
  lea    -0x28(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x14,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pad_pkcs7@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[] = "YELLOW SUBMARINE";
  size_t len = 0;
  len = strlen(input);
  pad_pkcs7(input, &len, 20);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x5320574f4c4c4559,%rax
  movabs $0x454e4952414d4255,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  mov    $0x14,%edx
  mov    %rbx,%rdi
  call   <pad_pkcs7@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[] = "YELLOW SUBMARINE";
  size_t len = 0;
  len = strlen(input);
  pad_pkcs7(input, &len, 20);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movb   $0x0,0x20(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x8(%rsp),%rsi
  mov    $0x14,%edx
  mov    %rax,0x8(%rsp)
  call   <pad_pkcs7@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D19
type_infered: string

tool: {"D6": [0x59,0x45,0x4c,0x4c,0x4f,0x57,0x20,0x53,0x55,0x42,0x4d,0x41,0x52,0x49,0x4e,0x45]}

tool: D19: 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[] = "YELLOW SUBMARINE";
  size_t len = 0;
  len = strlen(input);
  pad_pkcs7(input, &len, 20);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movb   $0x0,0x20(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x8(%rsp),%rsi
  mov    $0x14,%edx
  mov    %rax,0x8(%rsp)
  call   <pad_pkcs7@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D12
data_type: string

tool: {"D8": [0x59,0x45,0x4c,0x4c,0x4f,0x57,0x20,0x53,0x55,0x42,0x4d,0x41,0x52,0x49,0x4e,0x45]}

tool: D12: 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[] = "YELLOW SUBMARINE";
  size_t len = 0;
  len = strlen(input);
  pad_pkcs7(input, &len, 20);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L18:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L18
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, unsigned int len) {
  unsigned int size = 0;
  while (size < len) {
    dest[size] = src[size];
    size++;
  }
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L18
  mov    %edx,%edx
  mov    $0x0,%ecx
L11:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L11
L18:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, unsigned int len) {
  unsigned int size = 0;
  while (size < len) {
    dest[size] = src[size];
    size++;
  }
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L15
  mov    %edx,%edx
  xor    %ecx,%ecx
  nop
L8:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L8
L15:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, unsigned int len) {
  unsigned int size = 0;
  while (size < len) {
    dest[size] = src[size];
    size++;
  }
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strncpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  test   %edx,%edx
  je     L103
  lea    0x1(%rsi),%rdi
  mov    %r8,%rsi
  lea    -0x1(%rdx),%eax
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L87
  cmp    $0x6,%eax
  jbe    L87
  mov    %edx,%esi
  cmp    $0xe,%eax
  jbe    L66
  shr    $0x4,%esi
  xor    %eax,%eax
  shl    $0x4,%rsi
  cs nopw 0x0(%rax,%rax,1)
L37:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L37
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  test   $0xf,%dl
  je     L103
  mov    %edx,%esi
  sub    %eax,%esi
  lea    -0x1(%rsi),%edi
  cmp    $0x6,%edi
  jbe    L146
L99:
  mov    %eax,%edi
  mov    (%rcx,%rdi,1),%r9
  mov    %r9,(%r8,%rdi,1)
  mov    %esi,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%esi
  je     L103
L146:
  mov    %eax,%esi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x1(%rax),%esi
  cmp    %esi,%edx
  jbe    L103
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x2(%rax),%esi
  cmp    %esi,%edx
  jbe    L103
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x3(%rax),%esi
  cmp    %esi,%edx
  jbe    L103
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x4(%rax),%esi
  cmp    %esi,%edx
  jbe    L103
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x5(%rax),%esi
  cmp    %esi,%edx
  jbe    L103
  movzbl (%rcx,%rsi,1),%edi
  add    $0x6,%eax
  mov    %dil,(%r8,%rsi,1)
  cmp    %eax,%edx
  jbe    L103
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
L103:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L62:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L62
  mov    %r8,%rax
  ret
L66:
  xor    %eax,%eax
  jmp    L99
```

assistant: ```c
char *strncpy(char *dest, const char *src, unsigned int len) {
  unsigned int size = 0;
  while (size < len) {
    dest[size] = src[size];
    size++;
  }
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<scan0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L8
  nop
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  jmp    L43
L33:
  nop
  mov    -0x18(%rbp),%rax
  jmp    L0
L8:
  nop
  addq   $0x1,-0x18(%rbp)
  mov    $0x0,%eax
  jmp    L0
L36:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
L43:
  movsbl -0x1(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L33
  jmp    L36
L0:
  pop    %rbp
  ret
```

assistant: ```c
char *scan0(char *p) {
  char *q;
  {
    char yych;
    if ((p - p) < 2)
      ;
    yych = *p;
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy2;
    default:
      goto yy4;
    }
  yy2:
    ++p;
    yych = *p;
    goto yy7;
  yy3 : { return p; }
  yy4:
    ++p;
    { return ((char *)0); }
  yy6:
    ++p;
    if (p <= p)
      ;
    yych = *p;
  yy7:
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy6;
    default:
      goto yy3;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scan0>:
  endbr64
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  mov    $0x0,%edx
  cmp    $0x9,%eax
  ja     L9
  lea    0x1(%rdi),%rdx
  movsbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L9
L4:
  add    $0x1,%rdx
  movsbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L4
L9:
  mov    %rdx,%rax
  ret
```

assistant: ```c
char *scan0(char *p) {
  char *q;
  {
    char yych;
    if ((p - p) < 2)
      ;
    yych = *p;
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy2;
    default:
      goto yy4;
    }
  yy2:
    ++p;
    yych = *p;
    goto yy7;
  yy3 : { return p; }
  yy4:
    ++p;
    { return ((char *)0); }
  yy6:
    ++p;
    if (p <= p)
      ;
    yych = *p;
  yy7:
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy6;
    default:
      goto yy3;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scan0>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L27
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L27
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl 0x1(%r8),%eax
  add    $0x1,%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L5
L27:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *scan0(char *p) {
  char *q;
  {
    char yych;
    if ((p - p) < 2)
      ;
    yych = *p;
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy2;
    default:
      goto yy4;
    }
  yy2:
    ++p;
    yych = *p;
    goto yy7;
  yy3 : { return p; }
  yy4:
    ++p;
    { return ((char *)0); }
  yy6:
    ++p;
    if (p <= p)
      ;
    yych = *p;
  yy7:
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy6;
    default:
      goto yy3;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<scan0>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L29
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L29
  nopw   0x0(%rax,%rax,1)
L11:
  movsbl 0x1(%r8),%eax
  add    $0x1,%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L11
L29:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *scan0(char *p) {
  char *q;
  {
    char yych;
    if ((p - p) < 2)
      ;
    yych = *p;
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy2;
    default:
      goto yy4;
    }
  yy2:
    ++p;
    yych = *p;
    goto yy7;
  yy3 : { return p; }
  yy4:
    ++p;
    { return ((char *)0); }
  yy6:
    ++p;
    if (p <= p)
      ;
    yych = *p;
  yy7:
    switch (yych) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      goto yy6;
    default:
      goto yy3;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: Out of memory (unable to allocate %z bytes)

assistant: ```c
void *xmalloc(size_t size) {
  void *p = malloc(size);
  if (!p)
    die("Out of memory (unable to allocate %z bytes)", size);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <die@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D0: Out of memory (unable to allocate %z bytes)

assistant: ```c
void *xmalloc(size_t size) {
  void *p = malloc(size);
  if (!p)
    die("Out of memory (unable to allocate %z bytes)", size);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<xmalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <die@plt>
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: Out of memory (unable to allocate %z bytes)

assistant: ```c
void *xmalloc(size_t size) {
  void *p = malloc(size);
  if (!p)
    die("Out of memory (unable to allocate %z bytes)", size);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xmalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <die@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: Out of memory (unable to allocate %z bytes)

assistant: ```c
void *xmalloc(size_t size) {
  void *p = malloc(size);
  if (!p)
    die("Out of memory (unable to allocate %z bytes)", size);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x5,%edi
  jne    L39
L29:
  mov    0x8(%rbx),%rdi
  lea    D11(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x10(%rbx),%rdi
  lea    D48(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x20(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  mov    0x18(%rbx),%rdx
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  cmp    $0x1,%r13d
  jle    L8
  sub    $0x1,%r13d
  mov    $0x0,%ebx
  lea    D4(%rip),%r14
L16:
  lea    0x6(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <fread@plt>
  movswl 0x6(%rsp),%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L16
L8:
  lea    0x6(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <fread@plt>
  movswl 0x6(%rsp),%edx
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  mov    (%rsi),%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L29
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D48
type: string
name: extract_symbolic_data
arguments: data_label: D28
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D22
type: string

tool: D11: rb

tool: D48: wt

tool: D28: short %s[] = {


tool: D4: %d,


tool: D17: %d
};


tool: D22: usage: %s inputRawFile outputHeaderFile arrayName samples


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fraw, *fheader;
  int i, samples;
  short sam;
  if (argc != 5) {
    printf("usage: %s inputRawFile outputHeaderFile arrayName samples\n", argv[0]);
    exit(1);
  }
  fraw = fopen(argv[1], "rb");
  assert(fraw != NULL);
  fheader = fopen(argv[2], "wt");
  assert(fheader != NULL);
  samples = atoi(argv[4]);
  fprintf(fheader, "short %s[] = {\n", argv[3]);
  for (i = 0; i < samples - 1; i++) {
    fread(&sam, sizeof(short), 1, fraw);
    fprintf(fheader, "%d,\n", sam);
  }
  fread(&sam, sizeof(short), 1, fraw);
  fprintf(fheader, "%d\n};\n", sam);
  fclose(fraw);
  fclose(fheader);
  return 0;
}
```