ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L0
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jae    L0
  mov    -0x28(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  add    %rax,-0x10(%rbp)
  jmp    L41
L4:
  subq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L41:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L4
  jmp    L2
L19:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L0:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L19
L2:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memmove(void *dst_void, const void *src_void, long length) {
  char *dst = dst_void;
  const char *src = src_void;
  if (src < dst && dst < src + length) {
    src += length;
    dst += length;
    while (length--) {
      *--dst = *--src;
    }
  } else {
    while (length--) {
      *dst++ = *src++;
    }
  }
  return dst_void;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  ja     L44
L8:
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L36
L42:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L42
L48:
  ret
L36:
  ret
L44:
  lea    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rdi
  jae    L8
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L48
L47:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L47
  ret
```

assistant: ```c
void *memmove(void *dst_void, const void *src_void, long length) {
  char *dst = dst_void;
  const char *src = src_void;
  if (src < dst && dst < src + length) {
    src += length;
    dst += length;
    while (length--) {
      *--dst = *--src;
    }
  } else {
    while (length--) {
      *dst++ = *src++;
    }
  }
  return dst_void;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%rcx
  cmp    %rsi,%rdi
  jbe    L19
  lea    (%rsi,%rdx,1),%rdi
  cmp    %rdi,%rax
  jae    L19
  test   %rdx,%rdx
  je     L13
  xchg   %ax,%ax
L38:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L38
  ret
  xchg   %ax,%ax
L19:
  xor    %ecx,%ecx
  test   %rdx,%rdx
  je     L7
  nopw   0x0(%rax,%rax,1)
L21:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L21
L13:
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void *memmove(void *dst_void, const void *src_void, long length) {
  char *dst = dst_void;
  const char *src = src_void;
  if (src < dst && dst < src + length) {
    src += length;
    dst += length;
    while (length--) {
      *--dst = *--src;
    }
  } else {
    while (length--) {
      *dst++ = *src++;
    }
  }
  return dst_void;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memmove>:
  endbr64
  mov    %rdi,%r8
  lea    -0x1(%rdx),%rax
  cmp    %rsi,%rdi
  jbe    L173
  lea    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rdi
  jb     L171
L173:
  test   %rdx,%rdx
  je     L183
  lea    0x1(%rsi),%rdi
  mov    %r8,%rcx
  sub    %rdi,%rcx
  cmp    $0xe,%rcx
  jbe    L115
  cmp    $0x6,%rax
  jbe    L115
  cmp    $0xe,%rax
  jbe    L2
  mov    %rdx,%rdi
  xor    %ecx,%ecx
  and    $0xfffffffffffffff0,%rdi
  nopw   0x0(%rax,%rax,1)
L87:
  movdqu (%rsi,%rcx,1),%xmm0
  movups %xmm0,(%r8,%rcx,1)
  add    $0x10,%rcx
  cmp    %rdi,%rcx
  jne    L87
  mov    %rdx,%rcx
  and    $0xfffffffffffffff0,%rcx
  lea    (%r8,%rcx,1),%rdi
  lea    (%rsi,%rcx,1),%r9
  sub    %rcx,%rax
  cmp    %rcx,%rdx
  je     L183
L66:
  sub    %rcx,%rdx
  lea    -0x1(%rdx),%r10
  cmp    $0x6,%r10
  jbe    L28
  mov    (%rsi,%rcx,1),%rsi
  mov    %rsi,(%r8,%rcx,1)
  mov    %rdx,%rcx
  and    $0xfffffffffffffff8,%rcx
  add    %rcx,%rdi
  add    %rcx,%r9
  sub    %rcx,%rax
  cmp    %rcx,%rdx
  je     L183
L28:
  movzbl (%r9),%edx
  mov    %dl,(%rdi)
  test   %rax,%rax
  je     L183
  movzbl 0x1(%r9),%edx
  mov    %dl,0x1(%rdi)
  cmp    $0x1,%rax
  je     L183
  movzbl 0x2(%r9),%edx
  mov    %dl,0x2(%rdi)
  cmp    $0x2,%rax
  je     L183
  movzbl 0x3(%r9),%edx
  mov    %dl,0x3(%rdi)
  cmp    $0x3,%rax
  je     L183
  movzbl 0x4(%r9),%edx
  mov    %dl,0x4(%rdi)
  cmp    $0x4,%rax
  je     L183
  movzbl 0x5(%r9),%edx
  mov    %dl,0x5(%rdi)
  cmp    $0x5,%rax
  je     L183
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%rdi)
L183:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L171:
  test   %rdx,%rdx
  je     L183
  nopl   (%rax)
L124:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  sub    $0x1,%rax
  jae    L124
  mov    %r8,%rax
  ret
L2:
  mov    %rsi,%r9
  mov    %r8,%rdi
  xor    %ecx,%ecx
  jmp    L66
  nop
L115:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L122:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L122
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memmove(void *dst_void, const void *src_void, long length) {
  char *dst = dst_void;
  const char *src = src_void;
  if (src < dst && dst < src + length) {
    src += length;
    dst += length;
    while (length--) {
      *--dst = *--src;
    }
  } else {
    while (length--) {
      *dst++ = *src++;
    }
  }
  return dst_void;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4c(%rbp)
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x58(%rbp),%eax
  cmp    $0x1f4,%eax
  jg     L82
  mov    -0x58(%rbp),%eax
  test   %eax,%eax
  jle    L82
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L80:
  cmp    %rdx,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L80
L12:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L68
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L68:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  jmp    L23
L0:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L23:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L0
  mov    -0x58(%rbp),%esi
  lea    -0x50(%rbp),%rcx
  lea    -0x54(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    -0x54(%rbp),%edx
  mov    -0x50(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  nop
  mov    $0x0,%eax
  jmp    L51
L82:
  mov    $0x0,%eax
L51:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
data_type: string

tool: D15: %d

assistant: ```c
int main() {
  int n, min, max, i = 0;
  scanf("%d", &n);
  if (n <= 500 && n >= 1) {
    int arr[n];
    while (i < n) {
      scanf("%d", &arr[i]);
      i++;
    }
    minmax(arr, n, &min, &max);
    printf("%d", min + max);
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x44(%rbp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f3,%edx
  ja     L24
  mov    %rsp,%r14
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L38:
  cmp    %rdx,%rsp
  je     L31
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L38
L31:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L37
  orq    $0x0,-0x8(%rsp,%rax,1)
L37:
  mov    %rsp,%r15
  mov    %r15,%r12
  mov    $0x0,%ebx
  lea    D29(%rip),%r13
L51:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x44(%rbp),%esi
  add    $0x4,%r12
  cmp    %ebx,%esi
  jg     L51
  lea    -0x3c(%rbp),%rcx
  lea    -0x40(%rbp),%rdx
  mov    %r15,%rdi
  call   <minmax@plt>
  mov    -0x3c(%rbp),%esi
  add    -0x40(%rbp),%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rsp
L24:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D29
datatype: string

tool: D29: %d

assistant: ```c
int main() {
  int n, min, max, i = 0;
  scanf("%d", &n);
  if (n <= 500 && n >= 1) {
    int arr[n];
    while (i < n) {
      scanf("%d", &arr[i]);
      i++;
    }
    minmax(arr, n, &min, &max);
    printf("%d", min + max);
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  lea    D4(%rip),%r15
  push   %r14
  lea    -0x44(%rbp),%rsi
  mov    %r15,%rdi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x44(%rbp),%rax
  lea    -0x1(%rax),%edx
  cmp    $0x1f3,%edx
  ja     L56
  lea    0xf(,%rax,4),%rax
  mov    %rsp,%rcx
  mov    %rsp,%r13
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  and    $0xfffffffffffffff0,%rdx
  sub    %rax,%rcx
L30:
  cmp    %rcx,%rsp
  je     L14
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L30
L14:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L43
  orq    $0x0,-0x8(%rsp,%rdx,1)
L43:
  mov    %rsp,%r14
  xor    %ebx,%ebx
  mov    %r14,%r12
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r12,%rsi
  mov    %r15,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x44(%rbp),%esi
  cmp    %ebx,%esi
  jg     L23
  lea    -0x3c(%rbp),%rcx
  lea    -0x40(%rbp),%rdx
  mov    %r14,%rdi
  call   <minmax@plt>
  mov    -0x3c(%rbp),%esi
  mov    %r15,%rdi
  add    -0x40(%rbp),%esi
  call   <printf@plt>
  mov    %r13,%rsp
L56:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: %d

assistant: ```c
int main() {
  int n, min, max, i = 0;
  scanf("%d", &n);
  if (n <= 500 && n >= 1) {
    int arr[n];
    while (i < n) {
      scanf("%d", &arr[i]);
      i++;
    }
    minmax(arr, n, &min, &max);
    printf("%d", min + max);
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  lea    D5(%rip),%r15
  push   %r14
  lea    -0x44(%rbp),%rsi
  mov    %r15,%rdi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x44(%rbp),%rax
  lea    -0x1(%rax),%edx
  cmp    $0x1f3,%edx
  ja     L17
  lea    0xf(,%rax,4),%rax
  mov    %rsp,%rcx
  mov    %rsp,%r13
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  and    $0xfffffffffffffff0,%rdx
  sub    %rax,%rcx
L13:
  cmp    %rcx,%rsp
  je     L48
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L13
L48:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L3
  orq    $0x0,-0x8(%rsp,%rdx,1)
L3:
  mov    %rsp,%r14
  xor    %ebx,%ebx
  mov    %r14,%r12
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rsi
  mov    %r15,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x44(%rbp),%esi
  cmp    %ebx,%esi
  jg     L10
  lea    -0x3c(%rbp),%rcx
  lea    -0x40(%rbp),%rdx
  mov    %r14,%rdi
  call   <minmax@plt>
  mov    -0x3c(%rbp),%esi
  mov    %r15,%rdi
  add    -0x40(%rbp),%esi
  call   <printf@plt>
  mov    %r13,%rsp
L17:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D5: %d

assistant: ```c
int main() {
  int n, min, max, i = 0;
  scanf("%d", &n);
  if (n <= 500 && n >= 1) {
    int arr[n];
    while (i < n) {
      scanf("%d", &arr[i]);
      i++;
    }
    minmax(arr, n, &min, &max);
    printf("%d", min + max);
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L22
L11:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L4:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L1:
  cmpl   $0x2,-0x14(%rbp)
  jle    L4
  addl   $0x1,-0x18(%rbp)
L22:
  cmpl   $0x6,-0x18(%rbp)
  jle    L11
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D15
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D3: smaxabs

tool: D15: # c::%s:len=%d


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smaxabs", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D2(%rip),%r15
  jmp    L14
L8:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L16
L14:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L1:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L1
  jmp    L8
L16:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D2: smaxabs

tool: D7: # c::%s:len=%d


tool: D1: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smaxabs", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D25(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L2:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L2
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L8
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D25
datatype: string
name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D13
datatype: string

tool: D25: smaxabs

tool: D15: # c::%s:len=%d


tool: D13: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smaxabs", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D26(%rip),%r15
  push   %r14
  lea    D24(%rip),%r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L13:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L8:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L8
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L13
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
type_guessed: string
name: parse_data
arguments: data_label: D24
type_guessed: string
name: parse_data
arguments: data_label: D21
type_guessed: string

tool: D26: smaxabs

tool: D24: # c::%s:len=%d


tool: D21: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smaxabs", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  jmp    L14
L11:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L14:
  nop
  leave
  ret
```

assistant: ```c
void split(char c, char *string, char **resto) {
  char *pos = strchr(string, c);
  if (pos == NULL) {
    *resto = strchr(string, '\0');
  } else {
    *pos++ = '\0';
    *resto = pos;
  }
}
```