ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getNameSpaceID>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%r13
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L13
  lea    D7(%rip),%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L1:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L13:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D7
type: string

tool: D14: :

tool: D7: ipdr

assistant: ```c
int getNameSpaceID(char *service, char *key) {
  char *temp;
  char *token;
  temp = (char *)calloc(strlen(key) + 1, sizeof(char));
  strcpy(temp, key);
  token = strtok(temp, ":");
  if (!strcmp(key, token))
    strcpy(service, "ipdr");
  else
    strcpy(service, token);
  free(temp);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<storeBlocksOfN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L26
L78:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x6e,-0x11(%rbp)
  je     L28
  cmpb   $0x4e,-0x11(%rbp)
  jne    L18
L28:
  mov    $0x1,%eax
  jmp    L53
L18:
  mov    $0x0,%eax
L53:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L86
  cmpl   $0x0,-0xc(%rbp)
  jne    L97
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L97
L86:
  cmpl   $0x0,-0xc(%rbp)
  je     L97
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x40(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
L97:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L78
  cmpl   $0x0,-0xc(%rbp)
  je     L20
  mov    -0x8(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
L20:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void storeBlocksOfN(char *s, int size, unsigned *starts, unsigned *sizes) {
  int i;
  int isN, lastIsN = 0;
  int startN = 0;
  char c;
  for (i = 0; i < size; ++i) {
    c = s[i];
    isN = (c == 'n' || c == 'N');
    if (isN) {
      if (!lastIsN)
        startN = i;
    } else {
      if (lastIsN) {
        *starts++ = startN;
        *sizes++ = i - startN;
      }
    }
    lastIsN = isN;
  }
  if (lastIsN) {
    *starts = startN;
    *sizes = i - startN;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<storeBlocksOfN>:
  endbr64
  test   %esi,%esi
  jle    L61
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  mov    $0x0,%r10d
  mov    $0x0,%r8d
  jmp    L43
L56:
  test   %r9d,%r9d
  je     L1
  mov    %r10d,(%rdx)
  sub    %r10d,%edi
  mov    %edi,(%rcx)
  lea    0x4(%rcx),%rcx
  lea    0x4(%rdx),%rdx
L1:
  add    $0x1,%rax
  cmp    %rbp,%rax
  je     L13
L43:
  mov    %eax,%edi
  movzbl (%r11,%rax,1),%esi
  and    $0xffffffdf,%esi
  mov    %r8d,%r9d
  cmp    $0x4e,%sil
  sete   %r8b
  movzbl %r8b,%r8d
  jne    L56
  test   %r9d,%r9d
  cmove  %eax,%r10d
  jmp    L1
L13:
  cmp    $0x4e,%sil
  jne    L58
  mov    %r10d,(%rdx)
  sub    %r10d,%ebx
  mov    %ebx,(%rcx)
L58:
  pop    %rbx
  pop    %rbp
  ret
L61:
  ret
```

assistant: ```c
void storeBlocksOfN(char *s, int size, unsigned *starts, unsigned *sizes) {
  int i;
  int isN, lastIsN = 0;
  int startN = 0;
  char c;
  for (i = 0; i < size; ++i) {
    c = s[i];
    isN = (c == 'n' || c == 'N');
    if (isN) {
      if (!lastIsN)
        startN = i;
    } else {
      if (lastIsN) {
        *starts++ = startN;
        *sizes++ = i - startN;
      }
    }
    lastIsN = isN;
  }
  if (lastIsN) {
    *starts = startN;
    *sizes = i - startN;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<storeBlocksOfN>:
  endbr64
  test   %esi,%esi
  jle    L50
  push   %rbp
  mov    %rdi,%r11
  movslq %esi,%rbp
  xor    %eax,%eax
  push   %rbx
  xor    %r10d,%r10d
  mov    %esi,%ebx
  xor    %edi,%edi
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L54:
  test   %r8d,%r8d
  cmove  %eax,%r10d
L23:
  add    $0x1,%rax
  cmp    %rbp,%rax
  je     L27
L35:
  movzbl (%r11,%rax,1),%esi
  mov    %edi,%r8d
  xor    %edi,%edi
  mov    %eax,%r9d
  and    $0xffffffdf,%esi
  cmp    $0x4e,%sil
  sete   %dil
  je     L54
  test   %r8d,%r8d
  je     L23
  sub    %r10d,%r9d
  add    $0x1,%rax
  mov    %r10d,(%rdx)
  add    $0x4,%rcx
  mov    %r9d,-0x4(%rcx)
  add    $0x4,%rdx
  cmp    %rbp,%rax
  jne    L35
L27:
  cmp    $0x4e,%sil
  jne    L12
  sub    %r10d,%ebx
  mov    %r10d,(%rdx)
  mov    %ebx,(%rcx)
L12:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  ret
```

assistant: ```c
void storeBlocksOfN(char *s, int size, unsigned *starts, unsigned *sizes) {
  int i;
  int isN, lastIsN = 0;
  int startN = 0;
  char c;
  for (i = 0; i < size; ++i) {
    c = s[i];
    isN = (c == 'n' || c == 'N');
    if (isN) {
      if (!lastIsN)
        startN = i;
    } else {
      if (lastIsN) {
        *starts++ = startN;
        *sizes++ = i - startN;
      }
    }
    lastIsN = isN;
  }
  if (lastIsN) {
    *starts = startN;
    *sizes = i - startN;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<storeBlocksOfN>:
  endbr64
  test   %esi,%esi
  jle    L46
  push   %rbp
  mov    %rdi,%r11
  movslq %esi,%rbp
  xor    %eax,%eax
  push   %rbx
  xor    %r10d,%r10d
  mov    %esi,%ebx
  xor    %edi,%edi
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L19:
  test   %r8d,%r8d
  cmove  %eax,%r10d
L59:
  add    $0x1,%rax
  cmp    %rax,%rbp
  je     L56
L31:
  movzbl (%r11,%rax,1),%esi
  mov    %edi,%r8d
  xor    %edi,%edi
  mov    %eax,%r9d
  and    $0xffffffdf,%esi
  cmp    $0x4e,%sil
  sete   %dil
  je     L19
  test   %r8d,%r8d
  je     L59
  sub    %r10d,%r9d
  add    $0x1,%rax
  mov    %r10d,(%rdx)
  add    $0x4,%rcx
  mov    %r9d,-0x4(%rcx)
  add    $0x4,%rdx
  cmp    %rax,%rbp
  jne    L31
L56:
  cmp    $0x4e,%sil
  jne    L57
  sub    %r10d,%ebx
  mov    %r10d,(%rdx)
  mov    %ebx,(%rcx)
L57:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  ret
```

assistant: ```c
void storeBlocksOfN(char *s, int size, unsigned *starts, unsigned *sizes) {
  int i;
  int isN, lastIsN = 0;
  int startN = 0;
  char c;
  for (i = 0; i < size; ++i) {
    c = s[i];
    isN = (c == 'n' || c == 'N');
    if (isN) {
      if (!lastIsN)
        startN = i;
    } else {
      if (lastIsN) {
        *starts++ = startN;
        *sizes++ = i - startN;
      }
    }
    lastIsN = isN;
  }
  if (lastIsN) {
    *starts = startN;
    *sizes = i - startN;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ssds_get_argc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L16:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_del@plt>
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
L4:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ssds_get_argc(char *buf, char *argv[], int max) {
  char *sp;
  int ix;
  sp = buf;
  ix = 0;
  while (*sp && (ix < max)) {
    sp = get_del(sp, argv, ix);
    ix++;
  }
  return ix;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ssds_get_argc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L33
  mov    %rsi,%r12
  mov    %edx,%ebp
  test   %edx,%edx
  jle    L33
  mov    $0x0,%ebx
L24:
  mov    %ebx,%edx
  mov    %r12,%rsi
  call   <get_del@plt>
  mov    %rax,%rdi
  add    $0x1,%ebx
  cmpb   $0x0,(%rax)
  je     L15
  cmp    %ebx,%ebp
  jg     L24
L15:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    $0x0,%ebx
  jmp    L15
```

assistant: ```c
int ssds_get_argc(char *buf, char *argv[], int max) {
  char *sp;
  int ix;
  sp = buf;
  ix = 0;
  while (*sp && (ix < max)) {
    sp = get_del(sp, argv, ix);
    ix++;
  }
  return ix;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ssds_get_argc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L18
  mov    %edx,%ebx
  test   %edx,%edx
  jle    L18
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L43:
  cmp    %r12d,%ebx
  jle    L16
L10:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  add    $0x1,%r12d
  call   <get_del@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rdi
  jne    L43
L16:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ssds_get_argc(char *buf, char *argv[], int max) {
  char *sp;
  int ix;
  sp = buf;
  ix = 0;
  while (*sp && (ix < max)) {
    sp = get_del(sp, argv, ix);
    ix++;
  }
  return ix;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ssds_get_argc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L21
  mov    %edx,%ebx
  test   %edx,%edx
  jle    L21
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L10:
  cmp    %r12d,%ebx
  jle    L35
L0:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  add    $0x1,%r12d
  call   <get_del@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rdi
  jne    L10
L35:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ssds_get_argc(char *buf, char *argv[], int max) {
  char *sp;
  int ix;
  sp = buf;
  ix = 0;
  while (*sp && (ix < max)) {
    sp = get_del(sp, argv, ix);
    ix++;
  }
  return ix;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L84
L2:
  movl   $0x1,-0xc(%rbp)
  jmp    L70
L18:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jg     L41
  cmpl   $0x1,-0x10(%rbp)
  je     L16
  cmpl   $0x1,-0xc(%rbp)
  je     L16
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L27
L16:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L41
L27:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L41:
  addl   $0x1,-0xc(%rbp)
L70:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L18
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L84:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L89
  call   <__stack_chk_fail@plt>
L89:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D40
type_infered: string
name: parse_data
arguments: label: D46
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string
name: parse_data
arguments: label: D22
type_infered: string

tool: D40: Enter Number : 

tool: D46: %d

tool: D15: * 

tool: D4:   

tool: D22: 


assistant: ```c
int main() {
  int i, j, k, n;
  printf("Enter Number : ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      if (j <= (n + 1 - i)) {
        if (i == 1 || j == 1 || j == (n + 1 - i))
          printf("* ");
        else
          printf("  ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%ebp
  lea    D24(%rip),%r12
  lea    D47(%rip),%r13
  lea    D32(%rip),%r14
  cmpl   $0x0,0x4(%rsp)
  jg     L94
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L65:
  mov    %r12,%rdi
  call   <printf@plt>
L47:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jl     L1
L70:
  add    $0x1,%eax
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jl     L47
  cmp    $0x1,%ebx
  sete   %dl
  cmp    %ebx,%eax
  sete   %al
  or     %al,%dl
  jne    L65
  cmp    $0x1,%ebp
  je     L65
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L47
L1:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jl     L30
L94:
  mov    0x4(%rsp),%eax
  mov    $0x1,%ebx
  test   %eax,%eax
  jg     L70
  jmp    L1
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D36
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D47
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D32
type_guessed: string

tool: D29: Enter Number : 

tool: D36: %d

tool: D24: * 

tool: D47:   

tool: D32: 


assistant: ```c
int main() {
  int i, j, k, n;
  printf("Enter Number : ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      if (j <= (n + 1 - i)) {
        if (i == 1 || j == 1 || j == (n + 1 - i))
          printf("* ");
        else
          printf("  ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D38(%rip),%rdi
  mov    $0x1,%r14d
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D47(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L89
L84:
  mov    $0x1,%ebx
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L48:
  cmp    $0x1,%r14d
  je     L16
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
L8:
  add    $0x1,%ebx
  cmp    %ebx,%edx
  jl     L85
L68:
  lea    0x1(%rdx),%eax
  sub    %r14d,%eax
  cmp    %ebx,%eax
  jl     L8
  cmp    $0x1,%ebx
  sete   %dl
  cmp    %ebx,%eax
  sete   %al
  or     %al,%dl
  je     L48
L16:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jge    L68
L85:
  mov    %r13,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  cmp    %r14d,%edx
  jge    L84
L89:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D38
datatype: string
name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D34
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D47
datatype: string

tool: D38: Enter Number : 

tool: D6: 


tool: D34:   

tool: D7: * 

tool: D47: %d

assistant: ```c
int main() {
  int i, j, k, n;
  printf("Enter Number : ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      if (j <= (n + 1 - i)) {
        if (i == 1 || j == 1 || j == (n + 1 - i))
          printf("* ");
        else
          printf("  ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D36(%rip),%rdi
  mov    $0x1,%r14d
  push   %r13
  lea    D47(%rip),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  lea    D44(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L41
L0:
  mov    $0x1,%ebx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L89:
  cmp    $0x1,%r14d
  je     L12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
L23:
  add    $0x1,%ebx
  cmp    %edx,%ebx
  jg     L54
L29:
  lea    0x1(%rdx),%eax
  sub    %r14d,%eax
  cmp    %ebx,%eax
  jl     L23
  cmp    $0x1,%ebx
  sete   %dl
  cmp    %ebx,%eax
  sete   %al
  or     %al,%dl
  je     L89
L12:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  cmp    %edx,%ebx
  jle    L29
L54:
  mov    %r13,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  cmp    %r14d,%edx
  jge    L0
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D36
type_guessed: string
name: read_data
arguments: label: D47
type_guessed: string
name: read_data
arguments: label: D8
type_guessed: string
name: read_data
arguments: label: D44
type_guessed: string
name: read_data
arguments: label: D16
type_guessed: string

tool: D36: Enter Number : 

tool: D47: 


tool: D8:   

tool: D44: * 

tool: D16: %d

assistant: ```c
int main() {
  int i, j, k, n;
  printf("Enter Number : ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      if (j <= (n + 1 - i)) {
        if (i == 1 || j == 1 || j == (n + 1 - i))
          printf("* ");
        else
          printf("  ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<crc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L10
L12:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  xor    -0x14(%rbp),%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x8,-0xc(%rbp)
  jmp    L46
L21:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L55
  mov    -0x10(%rbp),%eax
  sar    %eax
  xor    $0xedb88320,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L20
L55:
  sarl   -0x10(%rbp)
L20:
  subl   $0x1,-0xc(%rbp)
L46:
  cmpl   $0x0,-0xc(%rbp)
  jg     L21
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  subq   $0x1,-0x30(%rbp)
L10:
  cmpq   $0x0,-0x30(%rbp)
  jne    L12
  mov    -0x14(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t crc32(void *data, size_t length) {
  uint32_t crc, x;
  uint8_t i, *d;
  for (d = data, crc = 0xFFFFFFFF; length; length--) {
    x = (crc ^ *(d++)) & 0xFF;
    for (i = 8; i > 0; i--) {
      if (x & 1)
        x = (x >> 1) ^ 0xEDB88320;
      else
        x >>= 1;
    }
    crc = (crc >> 8) ^ x;
  }
  return (crc ^ 0xFFFFFFFF);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crc32>:
  endbr64
  test   %rsi,%rsi
  je     L28
  mov    $0x0,%r10d
  mov    $0xffffffff,%eax
  jmp    L34
L21:
  sar    $0x8,%eax
  xor    %edx,%eax
  add    $0x1,%r10
  cmp    %rsi,%r10
  je     L36
L34:
  mov    %eax,%edx
  xor    (%rdi,%r10,4),%edx
  movzbl %dl,%edx
  mov    $0x8,%r8d
L22:
  mov    %edx,%ecx
  sar    %ecx
  xor    $0xedb88320,%ecx
  mov    %edx,%r9d
  sar    %r9d
  test   $0x1,%dl
  mov    %ecx,%edx
  cmove  %r9d,%edx
  sub    $0x1,%r8d
  jne    L22
  jmp    L21
L28:
  mov    $0xffffffff,%eax
L36:
  not    %eax
  ret
```

assistant: ```c
uint32_t crc32(void *data, size_t length) {
  uint32_t crc, x;
  uint8_t i, *d;
  for (d = data, crc = 0xFFFFFFFF; length; length--) {
    x = (crc ^ *(d++)) & 0xFF;
    for (i = 8; i > 0; i--) {
      if (x & 1)
        x = (x >> 1) ^ 0xEDB88320;
      else
        x >>= 1;
    }
    crc = (crc >> 8) ^ x;
  }
  return (crc ^ 0xFFFFFFFF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crc32>:
  endbr64
  test   %rsi,%rsi
  je     L27
  xor    %r10d,%r10d
  mov    $0xffffffff,%eax
  nopl   0x0(%rax)
L20:
  mov    (%rdi,%r10,4),%edx
  mov    $0x8,%ecx
  xor    %eax,%edx
  movzbl %dl,%edx
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %edx,%r9d
  sar    %edx
  mov    %edx,%r8d
  and    $0x1,%r9d
  xor    $0xedb88320,%r8d
  test   %r9d,%r9d
  cmovne %r8d,%edx
  sub    $0x1,%ecx
  jne    L24
  sar    $0x8,%eax
  add    $0x1,%r10
  xor    %edx,%eax
  cmp    %rsi,%r10
  jne    L20
  not    %eax
  ret
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t crc32(void *data, size_t length) {
  uint32_t crc, x;
  uint8_t i, *d;
  for (d = data, crc = 0xFFFFFFFF; length; length--) {
    x = (crc ^ *(d++)) & 0xFF;
    for (i = 8; i > 0; i--) {
      if (x & 1)
        x = (x >> 1) ^ 0xEDB88320;
      else
        x >>= 1;
    }
    crc = (crc >> 8) ^ x;
  }
  return (crc ^ 0xFFFFFFFF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crc32>:
  endbr64
  mov    %rsi,%r8
  test   %rsi,%rsi
  je     L16
  xor    %esi,%esi
  mov    $0xffffffff,%eax
  nopw   0x0(%rax,%rax,1)
L35:
  mov    (%rdi,%rsi,4),%ecx
  xor    %eax,%ecx
  mov    %ecx,%edx
  sar    %edx
  and    $0x7f,%edx
  mov    %edx,%r9d
  xor    $0xedb88320,%r9d
  and    $0x1,%ecx
  cmovne %r9d,%edx
  mov    %edx,%ecx
  sar    %ecx
  mov    %ecx,%r9d
  xor    $0xedb88320,%r9d
  and    $0x1,%edx
  cmovne %r9d,%ecx
  mov    %ecx,%edx
  sar    %edx
  mov    %edx,%r9d
  xor    $0xedb88320,%r9d
  and    $0x1,%ecx
  cmovne %r9d,%edx
  mov    %edx,%ecx
  sar    %ecx
  mov    %ecx,%r9d
  xor    $0xedb88320,%r9d
  and    $0x1,%edx
  cmovne %r9d,%ecx
  mov    %ecx,%edx
  sar    %edx
  mov    %edx,%r9d
  xor    $0xedb88320,%r9d
  and    $0x1,%ecx
  cmovne %r9d,%edx
  mov    %edx,%ecx
  sar    %ecx
  mov    %ecx,%r9d
  xor    $0xedb88320,%r9d
  and    $0x1,%edx
  cmovne %r9d,%ecx
  mov    %ecx,%edx
  sar    %edx
  mov    %edx,%r9d
  xor    $0xedb88320,%r9d
  and    $0x1,%ecx
  cmovne %r9d,%edx
  sar    $0x8,%eax
  mov    %edx,%ecx
  sar    %ecx
  and    $0x1,%edx
  je     L31
  xor    $0xedb88320,%ecx
  add    $0x1,%rsi
  xor    %ecx,%eax
  cmp    %rsi,%r8
  jne    L35
  not    %eax
  ret
  nop
L31:
  add    $0x1,%rsi
  xor    %ecx,%eax
  cmp    %rsi,%r8
  jne    L35
  not    %eax
  ret
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t crc32(void *data, size_t length) {
  uint32_t crc, x;
  uint8_t i, *d;
  for (d = data, crc = 0xFFFFFFFF; length; length--) {
    x = (crc ^ *(d++)) & 0xFF;
    for (i = 8; i > 0; i--) {
      if (x & 1)
        x = (x >> 1) ^ 0xEDB88320;
      else
        x >>= 1;
    }
    crc = (crc >> 8) ^ x;
  }
  return (crc ^ 0xFFFFFFFF);
}
```