ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D88(%rip),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D81(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L39
L15:
  mov    -0x68(%rbp),%eax
  mov    %eax,%esi
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  jmp    L41
L3:
  movsd  -0x60(%rbp),%xmm1
  movsd  D61(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x64(%rbp)
  lea    -0x40(%rbp),%rcx
  mov    -0x68(%rbp),%edx
  mov    -0x64(%rbp),%eax
  mov    %rcx,%rsi
  mov    %edx,%edi
  movd   %eax,%xmm0
  call   <CalcMarsSatElem@plt>
  movsd  -0x18(%rbp),%xmm5
  movsd  -0x20(%rbp),%xmm4
  movsd  -0x28(%rbp),%xmm3
  movsd  -0x30(%rbp),%xmm2
  movsd  -0x38(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mov    -0x60(%rbp),%rax
  movapd %xmm5,%xmm6
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x7,%eax
  call   <printf@plt>
  movsd  -0x60(%rbp),%xmm0
  addsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x60(%rbp)
L41:
  movsd  -0x50(%rbp),%xmm0
  comisd -0x60(%rbp),%xmm0
  jae    L3
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x68(%rbp)
L39:
  cmpl   $0x1,-0x68(%rbp)
  jle    L15
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D88
type: byte[8]
name: extract_symbolic_data
arguments: tag: D10
type: f64
name: extract_symbolic_data
arguments: tag: D81
type: f64
name: extract_symbolic_data
arguments: tag: D33
type: string
name: extract_symbolic_data
arguments: tag: D83
type: string
name: extract_symbolic_data
arguments: tag: D61
type: f64
name: extract_symbolic_data
arguments: tag: D77
type: string
name: extract_symbolic_data
arguments: tag: D40
type: string
name: extract_symbolic_data
arguments: tag: D32
type: string

tool: {"D88": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D10: 20000

tool: D81: 225

tool: D33: {

tool: D83: 	"%d": [


tool: D61: 6491.5

tool: D77: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: D40: 	],

tool: D32: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double elem[6];
  printf("{\n");
  for (body = 0; body < 2; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k <= end; jd2k += step) {
      float time = jd2k + 6491.5;
      CalcMarsSatElem(time, body, elem);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, elem[0], elem[1], elem[2], elem[3], elem[4], elem[5]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  lea    D48(%rip),%r14
  lea    D2(%rip),%r13
L9:
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xb2,%ebx
  movsd  D36(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
  lea    0x10(%rsp),%r12
L3:
  movsd  D50(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <CalcMarsSatElem@plt>
  movsd  0x38(%rsp),%xmm6
  movsd  0x30(%rsp),%xmm5
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %r13,%rdi
  mov    $0x7,%eax
  call   <printf@plt>
  movsd  D66(%rip),%xmm1
  addsd  0x8(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L3
  lea    D41(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  jne    L9
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D48
type_guessed: string
name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D36
type_guessed: byte[8]
name: read_data
arguments: tag: D50
type_guessed: f64
name: read_data
arguments: tag: D66
type_guessed: f64
name: read_data
arguments: tag: D41
type_guessed: string
name: read_data
arguments: tag: D37
type_guessed: string

tool: D16: {

tool: D48: 	"%d": [


tool: D2: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D50: 6491.5

tool: D66: 225

tool: D41: 	],

tool: D37: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double elem[6];
  printf("{\n");
  for (body = 0; body < 2; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k <= end; jd2k += step) {
      float time = jd2k + 6491.5;
      CalcMarsSatElem(time, body, elem);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, elem[0], elem[1], elem[2], elem[3], elem[4], elem[5]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  lea    D28(%rip),%rdi
  lea    D15(%rip),%r15
  push   %r14
  lea    D44(%rip),%r14
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
L11:
  mov    %ebp,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0xb2,%ebx
  call   <printf@plt>
  mov    D58(%rip),%rax
  movq   %rax,%xmm7
  nopw   0x0(%rax,%rax,1)
L18:
  movsd  D7(%rip),%xmm0
  mov    %r13,%rsi
  mov    %ebp,%edi
  movsd  %xmm7,0x8(%rsp)
  addsd  %xmm7,%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <CalcMarsSatElem@plt>
  movsd  0x8(%rsp),%xmm7
  movsd  0x38(%rsp),%xmm6
  movsd  0x30(%rsp),%xmm5
  movsd  0x28(%rsp),%xmm4
  mov    %r12,%rdi
  mov    $0x7,%eax
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movapd %xmm7,%xmm0
  movsd  0x10(%rsp),%xmm1
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm7
  addsd  D78(%rip),%xmm7
  sub    $0x1,%ebx
  jne    L18
  mov    %r14,%rdi
  call   <puts@plt>
  cmp    $0x1,%ebp
  jne    L20
  lea    D60(%rip),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  mov    $0x1,%ebp
  jmp    L11
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D44
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string
name: retrieve_data
arguments: data_tag: D58
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D7
type_infered: f64
name: retrieve_data
arguments: data_tag: D78
type_infered: f64
name: retrieve_data
arguments: data_tag: D60
type_infered: string

tool: D28: {

tool: D15: 	"%d": [


tool: D44: 	],

tool: D14: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D7: 6491.5

tool: D78: 225

tool: D60: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double elem[6];
  printf("{\n");
  for (body = 0; body < 2; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k <= end; jd2k += step) {
      float time = jd2k + 6491.5;
      CalcMarsSatElem(time, body, elem);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, elem[0], elem[1], elem[2], elem[3], elem[4], elem[5]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  lea    D72(%rip),%rdi
  lea    D17(%rip),%r15
  push   %r14
  lea    D38(%rip),%r14
  push   %r13
  push   %r12
  lea    D31(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
L14:
  mov    %ebp,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0xb2,%ebx
  call   <printf@plt>
  mov    D71(%rip),%rax
  movq   %rax,%xmm7
  nopw   0x0(%rax,%rax,1)
L8:
  movsd  D63(%rip),%xmm0
  mov    %r13,%rsi
  mov    %ebp,%edi
  movsd  %xmm7,0x8(%rsp)
  addsd  %xmm7,%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <CalcMarsSatElem@plt>
  movsd  0x8(%rsp),%xmm7
  movsd  0x38(%rsp),%xmm6
  movsd  0x30(%rsp),%xmm5
  movsd  0x28(%rsp),%xmm4
  mov    %r12,%rdi
  mov    $0x7,%eax
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movapd %xmm7,%xmm0
  movsd  0x10(%rsp),%xmm1
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm7
  addsd  D24(%rip),%xmm7
  sub    $0x1,%ebx
  jne    L8
  mov    %r14,%rdi
  call   <puts@plt>
  cmp    $0x1,%ebp
  jne    L39
  lea    D64(%rip),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    $0x1,%ebp
  jmp    L14
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D72
data_type: string
name: parse_data
arguments: label: D17
data_type: string
name: parse_data
arguments: label: D38
data_type: string
name: parse_data
arguments: label: D31
data_type: string
name: parse_data
arguments: label: D71
data_type: byte[8]
name: parse_data
arguments: label: D63
data_type: f64
name: parse_data
arguments: label: D24
data_type: f64
name: parse_data
arguments: label: D64
data_type: string

tool: D72: {

tool: D17: 	"%d": [


tool: D38: 	],

tool: D31: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D71": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D63: 6491.5

tool: D24: 225

tool: D64: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double elem[6];
  printf("{\n");
  for (body = 0; body < 2; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k <= end; jd2k += step) {
      float time = jd2k + 6491.5;
      CalcMarsSatElem(time, body, elem);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, elem[0], elem[1], elem[2], elem[3], elem[4], elem[5]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipWhite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L27:
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
L10:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *skipWhite(const char *inString) {
  const char *retval = inString;
  while ('\0' != *retval && isspace(*retval)) {
    retval++;
  }
  return retval;
}
```
user: What is the c source code of the assembly code below?

```asm
<skipWhite>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  mov    %rbx,%rax
  test   %dil,%dil
  je     L16
L31:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L35
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L31
  mov    %rbx,%rax
  jmp    L16
L35:
  mov    %rbx,%rax
L16:
  pop    %rbx
  ret
```

assistant: ```c
const char *skipWhite(const char *inString) {
  const char *retval = inString;
  while ('\0' != *retval && isspace(*retval)) {
    retval++;
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skipWhite>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L30
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L36:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L33
L30:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L36
L33:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *skipWhite(const char *inString) {
  const char *retval = inString;
  while ('\0' != *retval && isspace(*retval)) {
    retval++;
  }
  return retval;
}
```
user: What is the c source code of the assembly code below:

```asm
<skipWhite>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L11
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L31:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L33
L11:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
L33:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *skipWhite(const char *inString) {
  const char *retval = inString;
  while ('\0' != *retval && isspace(*retval)) {
    retval++;
  }
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmp_tx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  jmp    L2
L12:
  mov    $0xffffffff,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_tx(const void *x, const void *y) {
  int a = ((int *)x)[1], b = ((int *)y)[1];
  return a < b ? -1 : a == b ? 0 : +1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmp_tx>:
  endbr64
  mov    0x4(%rdi),%ecx
  mov    0x4(%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,%ecx
  jl     L2
  setne  %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
int cmp_tx(const void *x, const void *y) {
  int a = ((int *)x)[1], b = ((int *)y)[1];
  return a < b ? -1 : a == b ? 0 : +1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmp_tx>:
  endbr64
  mov    0x4(%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,0x4(%rdi)
  jl     L4
  setne  %al
  movzbl %al,%eax
L4:
  ret
```

assistant: ```c
int cmp_tx(const void *x, const void *y) {
  int a = ((int *)x)[1], b = ((int *)y)[1];
  return a < b ? -1 : a == b ? 0 : +1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmp_tx>:
  endbr64
  mov    0x4(%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,0x4(%rdi)
  jl     L2
  setne  %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
int cmp_tx(const void *x, const void *y) {
  int a = ((int *)x)[1], b = ((int *)y)[1];
  return a < b ? -1 : a == b ? 0 : +1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0x64,%eax,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x63,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D12
datatype: string

tool: D0: Input an integer with 3 digits:

tool: D19: %d

tool: D12: up=%d,down=%d

assistant: ```c
int main() {
  int n, up, down;
  printf("Input an integer with 3 digits:");
  scanf("%d", &n);
  down = (n / 100) * 100;
  up = down + 99;
  printf("up=%d,down=%d", up, down);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  imul   $0x64,%edx,%edx
  lea    0x63(%rdx),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string
name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D5: Input an integer with 3 digits:

tool: D0: %d

tool: D1: up=%d,down=%d

assistant: ```c
int main() {
  int n, up, down;
  printf("Input an integer with 3 digits:");
  scanf("%d", &n);
  down = (n / 100) * 100;
  up = down + 99;
  printf("up=%d,down=%d", up, down);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D20(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rdx
  lea    D1(%rip),%rdi
  mov    %rdx,%rax
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x25,%rdx
  sub    %eax,%edx
  xor    %eax,%eax
  imul   $0x64,%edx,%edx
  lea    0x63(%rdx),%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
datatype: string
name: extract_symbolic_data
arguments: data_tag: D2
datatype: string
name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D20: Input an integer with 3 digits:

tool: D2: %d

tool: D1: up=%d,down=%d

assistant: ```c
int main() {
  int n, up, down;
  printf("Input an integer with 3 digits:");
  scanf("%d", &n);
  down = (n / 100) * 100;
  up = down + 99;
  printf("up=%d,down=%d", up, down);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rdx
  lea    D4(%rip),%rdi
  mov    %rdx,%rax
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x25,%rdx
  sub    %eax,%edx
  xor    %eax,%eax
  imul   $0x64,%edx,%edx
  lea    0x63(%rdx),%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D28
type: string
name: retrieve_data
arguments: tag: D27
type: string
name: retrieve_data
arguments: tag: D4
type: string

tool: D28: Input an integer with 3 digits:

tool: D27: %d

tool: D4: up=%d,down=%d

assistant: ```c
int main() {
  int n, up, down;
  printf("Input an integer with 3 digits:");
  scanf("%d", &n);
  down = (n / 100) * 100;
  up = down + 99;
  printf("up=%d,down=%d", up, down);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_command_line_arg_as_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void get_command_line_arg_as_string(char **variable, char *cli_input) {
  *variable = malloc((strlen(cli_input) + 1) * sizeof(char));
  strncpy(*variable, cli_input, strlen(cli_input));
  *(&(*variable)[strlen(cli_input)]) = '\x0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_command_line_arg_as_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,0x0(%rbp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    0x0(%rbp),%rdx
  movb   $0x0,(%rdx,%rax,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void get_command_line_arg_as_string(char **variable, char *cli_input) {
  *variable = malloc((strlen(cli_input) + 1) * sizeof(char));
  strncpy(*variable, cli_input, strlen(cli_input));
  *(&(*variable)[strlen(cli_input)]) = '\x0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_command_line_arg_as_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,(%rbx)
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdx
  movb   $0x0,(%rdx,%rax,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void get_command_line_arg_as_string(char **variable, char *cli_input) {
  *variable = malloc((strlen(cli_input) + 1) * sizeof(char));
  strncpy(*variable, cli_input, strlen(cli_input));
  *(&(*variable)[strlen(cli_input)]) = '\x0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_command_line_arg_as_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,(%rbx)
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdx
  movb   $0x0,(%rdx,%rax,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void get_command_line_arg_as_string(char **variable, char *cli_input) {
  *variable = malloc((strlen(cli_input) + 1) * sizeof(char));
  strncpy(*variable, cli_input, strlen(cli_input));
  *(&(*variable)[strlen(cli_input)]) = '\x0';
}
```