ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<sixteen>:
  endbr64
  push   %rbx
  mov    $0x7,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: Hello

assistant: ```c
char *sixteen() {
  char *s = (char *)malloc(sizeof(char) * 7);
  strcpy(s, "Hello");
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sixteen>:
  endbr64
  push   %r12
  mov    $0x7,%edi
  call   <malloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: Hello

assistant: ```c
char *sixteen() {
  char *s = (char *)malloc(sizeof(char) * 7);
  strcpy(s, "Hello");
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sixteen>:
  endbr64
  push   %r12
  mov    $0x7,%edi
  call   <malloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: Hello

assistant: ```c
char *sixteen() {
  char *s = (char *)malloc(sizeof(char) * 7);
  strcpy(s, "Hello");
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x94(%rbp)
  jmp    L24
L9:
  mov    -0x94(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D45(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x94(%rbp),%ecx
  lea    (%rcx,%rcx,1),%esi
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  movslq %esi,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D45(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
  mov    -0x94(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D45(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x94(%rbp),%ecx
  add    %ecx,%ecx
  lea    0x1(%rcx),%esi
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  movslq %esi,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D45(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
  addl   $0x1,-0x94(%rbp)
L24:
  cmpl   $0xf,-0x94(%rbp)
  jle    L9
  movl   $0x0,-0x94(%rbp)
  jmp    L34
L4:
  mov    -0x94(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D45(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    -0x94(%rbp),%eax
  add    %eax,%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x94(%rbp),%ecx
  lea    (%rcx,%rcx,1),%esi
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  movslq %esi,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D45(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
  mov    -0x94(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D45(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    -0x94(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x94(%rbp),%ecx
  add    %ecx,%ecx
  lea    0x1(%rcx),%esi
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  movslq %esi,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D45(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
  addl   $0x1,-0x94(%rbp)
L34:
  cmpl   $0xf,-0x94(%rbp)
  jle    L4
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
void test_3(void) {
  static unsigned int bm[32];
  int am[32];
  int j;
  for (j = 0; j < 32 / 2; j++) {
    bm[2 * j] <<= am[j];
    bm[2 * j + 1] <<= am[j];
  }
  for (j = 0; j < 32 / 2; j++) {
    bm[2 * j] <<= am[2 * j];
    bm[2 * j + 1] <<= am[2 * j + 1];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_3>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rsp,%rsi
  lea    0x80(%rax),%r8
  mov    %rsi,%rdi
  mov    %rax,%rdx
L20:
  mov    (%rdi),%ecx
  shll   %cl,(%rdx)
  shll   %cl,0x4(%rdx)
  add    $0x8,%rdx
  add    $0x4,%rdi
  cmp    %r8,%rdx
  jne    L20
L18:
  mov    (%rsi),%ecx
  shll   %cl,(%rax)
  mov    0x4(%rsi),%ecx
  shll   %cl,0x4(%rax)
  add    $0x8,%rax
  add    $0x8,%rsi
  cmp    %r8,%rax
  jne    L18
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x98,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_3(void) {
  static unsigned int bm[32];
  int am[32];
  int j;
  for (j = 0; j < 32 / 2; j++) {
    bm[2 * j] <<= am[j];
    bm[2 * j + 1] <<= am[j];
  }
  for (j = 0; j < 32 / 2; j++) {
    bm[2 * j] <<= am[2 * j];
    bm[2 * j + 1] <<= am[2 * j + 1];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_3>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  lea    D2(%rip),%rax
  mov    %rsp,%rsi
  mov    %rsi,%rdi
  lea    0x80(%rax),%r8
  mov    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L27:
  mov    (%rdi),%ecx
  shll   %cl,(%rdx)
  add    $0x4,%rdi
  shll   %cl,0x4(%rdx)
  add    $0x8,%rdx
  cmp    %r8,%rdx
  jne    L27
  nopl   0x0(%rax)
L5:
  mov    (%rsi),%ecx
  shll   %cl,(%rax)
  add    $0x8,%rsi
  mov    -0x4(%rsi),%ecx
  shll   %cl,0x4(%rax)
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L5
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x98,%rsp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_3(void) {
  static unsigned int bm[32];
  int am[32];
  int j;
  for (j = 0; j < 32 / 2; j++) {
    bm[2 * j] <<= am[j];
    bm[2 * j + 1] <<= am[j];
  }
  for (j = 0; j < 32 / 2; j++) {
    bm[2 * j] <<= am[2 * j];
    bm[2 * j + 1] <<= am[2 * j + 1];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<transpose33d33d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x18(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x30(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x20(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x28(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x38(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x30(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x38(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x28(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x40(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transpose33d33d(double *m1, double *m2) {
  m2[0] = m1[0];
  m2[1] = m1[3];
  m2[2] = m1[6];
  m2[3] = m1[1];
  m2[4] = m1[4];
  m2[5] = m1[7];
  m2[6] = m1[2];
  m2[7] = m1[5];
  m2[8] = m1[8];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<transpose33d33d>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x18(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x38(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x30(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x38(%rsi)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  ret
```

assistant: ```c
void transpose33d33d(double *m1, double *m2) {
  m2[0] = m1[0];
  m2[1] = m1[3];
  m2[2] = m1[6];
  m2[3] = m1[1];
  m2[4] = m1[4];
  m2[5] = m1[7];
  m2[6] = m1[2];
  m2[7] = m1[5];
  m2[8] = m1[8];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<transpose33d33d>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x18(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x38(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x30(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x38(%rsi)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  ret
```

assistant: ```c
void transpose33d33d(double *m1, double *m2) {
  m2[0] = m1[0];
  m2[1] = m1[3];
  m2[2] = m1[6];
  m2[3] = m1[1];
  m2[4] = m1[4];
  m2[5] = m1[7];
  m2[6] = m1[2];
  m2[7] = m1[5];
  m2[8] = m1[8];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transpose33d33d>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x18(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x38(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x30(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x38(%rsi)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  ret
```

assistant: ```c
void transpose33d33d(double *m1, double *m2) {
  m2[0] = m1[0];
  m2[1] = m1[3];
  m2[2] = m1[6];
  m2[3] = m1[1];
  m2[4] = m1[4];
  m2[5] = m1[7];
  m2[6] = m1[2];
  m2[7] = m1[5];
  m2[8] = m1[8];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<io_change>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int io_change(int fd, uint32_t events, int *val) {
  *val = fd;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<io_change>:
  endbr64
  mov    %edi,(%rdx)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int io_change(int fd, uint32_t events, int *val) {
  *val = fd;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<io_change>:
  endbr64
  mov    %edi,(%rdx)
  xor    %eax,%eax
  ret
```

assistant: ```c
int io_change(int fd, uint32_t events, int *val) {
  *val = fd;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<io_change>:
  endbr64
  mov    %edi,(%rdx)
  xor    %eax,%eax
  ret
```

assistant: ```c
int io_change(int fd, uint32_t events, int *val) {
  *val = fd;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<removeElement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L52
  mov    $0x0,%eax
  jmp    L11
L52:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  je     L28
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L33
L28:
  subl   $0x1,-0xc(%rbp)
L33:
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L23
  mov    -0xc(%rbp),%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int removeElement(int *nums, int numsSize, int val) {
  if (numsSize == 0)
    return 0;
  int length = numsSize;
  int k = 0;
  for (int i = 0; i < numsSize; i++) {
    if (nums[i] != val)
      nums[k++] = nums[i];
    else
      length--;
  }
  return length;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<removeElement>:
  endbr64
  mov    %esi,%r9d
  test   %esi,%esi
  je     L25
  jle    L25
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%r10
  mov    $0x0,%esi
  jmp    L14
L7:
  movslq %esi,%r8
  mov    %ecx,(%rdi,%r8,4)
  lea    0x1(%rsi),%esi
L23:
  add    $0x4,%rax
  cmp    %r10,%rax
  je     L25
L14:
  mov    (%rax),%ecx
  cmp    %edx,%ecx
  jne    L7
  sub    $0x1,%r9d
  jmp    L23
L25:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int removeElement(int *nums, int numsSize, int val) {
  if (numsSize == 0)
    return 0;
  int length = numsSize;
  int k = 0;
  for (int i = 0; i < numsSize; i++) {
    if (nums[i] != val)
      nums[k++] = nums[i];
    else
      length--;
  }
  return length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<removeElement>:
  endbr64
  xor    %r9d,%r9d
  test   %esi,%esi
  je     L59
  jle    L41
  lea    -0x1(%rsi),%ecx
  mov    %esi,%r9d
  mov    %rdi,%rax
  xor    %esi,%esi
  lea    0x4(%rdi,%rcx,4),%r10
  jmp    L39
  nop
L65:
  movslq %esi,%r8
  add    $0x4,%rax
  add    $0x1,%esi
  mov    %ecx,(%rdi,%r8,4)
  cmp    %r10,%rax
  je     L59
L39:
  mov    (%rax),%ecx
  cmp    %edx,%ecx
  jne    L65
  add    $0x4,%rax
  sub    $0x1,%r9d
  cmp    %r10,%rax
  jne    L39
L59:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %esi,%r9d
  jmp    L59
```

assistant: ```c
int removeElement(int *nums, int numsSize, int val) {
  if (numsSize == 0)
    return 0;
  int length = numsSize;
  int k = 0;
  for (int i = 0; i < numsSize; i++) {
    if (nums[i] != val)
      nums[k++] = nums[i];
    else
      length--;
  }
  return length;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<removeElement>:
  endbr64
  xor    %r9d,%r9d
  test   %esi,%esi
  je     L40
  jle    L30
  lea    -0x1(%rsi),%ecx
  mov    %esi,%r9d
  mov    %rdi,%rax
  xor    %esi,%esi
  lea    0x4(%rdi,%rcx,4),%r10
  jmp    L62
  nop
L23:
  movslq %esi,%r8
  add    $0x4,%rax
  add    $0x1,%esi
  mov    %ecx,(%rdi,%r8,4)
  cmp    %r10,%rax
  je     L40
L62:
  mov    (%rax),%ecx
  cmp    %edx,%ecx
  jne    L23
  add    $0x4,%rax
  sub    $0x1,%r9d
  cmp    %r10,%rax
  jne    L62
L40:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %esi,%r9d
  jmp    L40
```

assistant: ```c
int removeElement(int *nums, int numsSize, int val) {
  if (numsSize == 0)
    return 0;
  int length = numsSize;
  int k = 0;
  for (int i = 0; i < numsSize; i++) {
    if (nums[i] != val)
      nums[k++] = nums[i];
    else
      length--;
  }
  return length;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skipwhite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L4:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skipwhite(q)
char *q;
{
  char *p = q;
  while (isspace(*p))
    ++p;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skipwhite>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L9
L19:
  add    $0x1,%rbx
L9:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L19
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skipwhite(q)
char *q;
{
  char *p = q;
  while (isspace(*p))
    ++p;
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skipwhite>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12
L19:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L0
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipwhite(q)
char *q;
{
  char *p = q;
  while (isspace(*p))
    ++p;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skipwhite>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12
L1:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L0
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipwhite(q)
char *q;
{
  char *p = q;
  while (isspace(*p))
    ++p;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uart_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L0:
  mov    $0x20215054,%edi
  call   <get_mem@plt>
  movsbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L0
  mov    $0x20215040,%edi
  call   <get_mem@plt>
  pop    %rbp
  ret
```

assistant: ```c
char uart_get() {
  while ((get_mem(0x20000000 + 0x00215054) & 0x1) == 0) {
  }
  return get_mem(0x20000000 + 0x00215040);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uart_get>:
  endbr64
  sub    $0x8,%rsp
L6:
  mov    $0x20215054,%edi
  call   <get_mem@plt>
  test   $0x1,%al
  je     L6
  mov    $0x20215040,%edi
  call   <get_mem@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char uart_get() {
  while ((get_mem(0x20000000 + 0x00215054) & 0x1) == 0) {
  }
  return get_mem(0x20000000 + 0x00215040);
}
```
user: What is the c source code of the assembly code below?

```asm
<uart_get>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x20215054,%edi
  call   <get_mem@plt>
  test   $0x1,%al
  je     L2
  mov    $0x20215040,%edi
  add    $0x8,%rsp
  jmp    1050 <get_mem@plt>
```

assistant: ```c
char uart_get() {
  while ((get_mem(0x20000000 + 0x00215054) & 0x1) == 0) {
  }
  return get_mem(0x20000000 + 0x00215040);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uart_get>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x20215054,%edi
  call   <get_mem@plt>
  test   $0x1,%al
  je     L7
  mov    $0x20215040,%edi
  add    $0x8,%rsp
  jmp    1050 <get_mem@plt>
```

assistant: ```c
char uart_get() {
  while ((get_mem(0x20000000 + 0x00215054) & 0x1) == 0) {
  }
  return get_mem(0x20000000 + 0x00215040);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <dummy@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void c(void) {
  __label__ l;
  dummy();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<c>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dummy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void c(void) {
  __label__ l;
  dummy();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<c>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <dummy@plt>
```

assistant: ```c
void c(void) {
  __label__ l;
  dummy();
}
```
user: Translate the below assembly code into C programming language:

```asm
<c>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <dummy@plt>
```

assistant: ```c
void c(void) {
  __label__ l;
  dummy();
}
```
user: What is the c source code of the assembly code below?

```asm
<tkh_micros_from_timeval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jns    L5
  mov    $0xffffffffffffffff,%rax
  jmp    L13
L5:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    %rdx,%rax
L13:
  pop    %rbp
  ret
```

assistant: ```c
long long tkh_micros_from_timeval(const struct timeval *tv) {
  if (tv->tv_usec < 0)
    return -1;
  else
    return ((long long)tv->tv_sec) * 1000000 + tv->tv_usec;
}
```
user: What is the c source code of the assembly code below:

```asm
<tkh_micros_from_timeval>:
  endbr64
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  js     L9
  imul   $0xf4240,0x8(%rdi),%rax
  add    %rdx,%rax
  ret
L9:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long long tkh_micros_from_timeval(const struct timeval *tv) {
  if (tv->tv_usec < 0)
    return -1;
  else
    return ((long long)tv->tv_sec) * 1000000 + tv->tv_usec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tkh_micros_from_timeval>:
  endbr64
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  js     L8
  imul   $0xf4240,0x8(%rdi),%rax
  add    %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long long tkh_micros_from_timeval(const struct timeval *tv) {
  if (tv->tv_usec < 0)
    return -1;
  else
    return ((long long)tv->tv_sec) * 1000000 + tv->tv_usec;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tkh_micros_from_timeval>:
  endbr64
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  js     L8
  imul   $0xf4240,0x8(%rdi),%rax
  add    %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long long tkh_micros_from_timeval(const struct timeval *tv) {
  if (tv->tv_usec < 0)
    return -1;
  else
    return ((long long)tv->tv_sec) * 1000000 + tv->tv_usec;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L24
  cmpl   $0xd,-0x4(%rbp)
  jne    L2
L24:
  cmpl   $0x5,-0x4(%rbp)
  je     L2
  cmpl   $0x14,-0x4(%rbp)
  jne    L30
L2:
  mov    $0x1,%eax
  jmp    L1
L30:
  mov    $0xffffffff,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int __attribute__((no)) foo(int x) {
  if ((x != 0 && x != 13) || x == 5 || x == 20)
    return 1;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  test   %edi,%edi
  je     L41
  mov    $0x1,%eax
  cmp    $0xd,%edi
  jne    L3
L41:
  cmp    $0x5,%edi
  je     L17
  mov    $0xffffffff,%eax
  cmp    $0x14,%edi
  je     L17
L3:
  ret
L17:
  mov    $0x1,%eax
  jmp    L3
```

assistant: ```c
int __attribute__((no)) foo(int x) {
  if ((x != 0 && x != 13) || x == 5 || x == 20)
    return 1;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  test   %edi,%edi
  je     L3
  cmp    $0xd,%edi
  je     L3
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int __attribute__((no)) foo(int x) {
  if ((x != 0 && x != 13) || x == 5 || x == 20)
    return 1;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  test   %edi,%edi
  je     L10
  cmp    $0xd,%edi
  je     L10
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int __attribute__((no)) foo(int x) {
  if ((x != 0 && x != 13) || x == 5 || x == 20)
    return 1;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<placeInArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L26:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  jmp    L34
L5:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L26
  mov    $0xffffffff,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int placeInArray(char val, char *arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (arr[i] == val)
      return i;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<placeInArray>:
  endbr64
  test   %edx,%edx
  jle    L22
  mov    %edx,%edx
  mov    $0x0,%eax
L37:
  mov    %eax,%ecx
  cmp    %dil,(%rsi,%rax,1)
  je     L9
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L37
  mov    $0xffffffff,%ecx
L9:
  mov    %ecx,%eax
  ret
L22:
  mov    $0xffffffff,%ecx
  jmp    L9
```

assistant: ```c
int placeInArray(char val, char *arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (arr[i] == val)
      return i;
  }
  return -1;
}
```