ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0xa,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <quicksort@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  jmp    L3
L7:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
L3:
  cmp    -0x14(%rbp),%ebx
  jl     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D25
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string

tool: D25: Lista ordenada:

tool: D10: %6d

assistant: ```c
main() {
  static int lista[] = {10, 3, 7, 5, 12, 1, 27, 3, 8, 13};
  int n_elementos = sizeof(lista) / sizeof(int);
  register i;
  quicksort(lista, n_elementos);
  printf("Lista ordenada:\n");
  for (i = 0; i < n_elementos; i++)
    printf("%6d", lista[i]);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xa,%esi
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <quicksort@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    0x28(%rbx),%r12
  lea    D0(%rip),%rbp
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string

tool: D10: Lista ordenada:

tool: D0: %6d

assistant: ```c
main() {
  static int lista[] = {10, 3, 7, 5, 12, 1, 27, 3, 8, 13};
  int n_elementos = sizeof(lista) / sizeof(int);
  register i;
  quicksort(lista, n_elementos);
  printf("Lista ordenada:\n");
  for (i = 0; i < n_elementos; i++)
    printf("%6d", lista[i]);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  lea    0x28(%rbx),%r12
  call   <quicksort@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D28
type: string

tool: D12: %6d

tool: D28: Lista ordenada:

assistant: ```c
main() {
  static int lista[] = {10, 3, 7, 5, 12, 1, 27, 3, 8, 13};
  int n_elementos = sizeof(lista) / sizeof(int);
  register i;
  quicksort(lista, n_elementos);
  printf("Lista ordenada:\n");
  for (i = 0; i < n_elementos; i++)
    printf("%6d", lista[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  lea    0x28(%rbx),%r12
  call   <quicksort@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D20
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string

tool: D20: %6d

tool: D13: Lista ordenada:

assistant: ```c
main() {
  static int lista[] = {10, 3, 7, 5, 12, 1, 27, 3, 8, 13};
  int n_elementos = sizeof(lista) / sizeof(int);
  register i;
  quicksort(lista, n_elementos);
  printf("Lista ordenada:\n");
  for (i = 0; i < n_elementos; i++)
    printf("%6d", lista[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x1,-0x24(%rbp)
  jg     L38
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L38:
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L29
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L29:
  movl   $0x0,-0x1c(%rbp)
  jmp    L4
L36:
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <nextword@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L36
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D23
type: string
name: unpack_data
arguments: tag: D49
type: string
name: unpack_data
arguments: tag: D31
type: string
name: unpack_data
arguments: tag: D5
type: string
name: unpack_data
arguments: tag: D40
type: string
name: unpack_data
arguments: tag: D29
type: string

tool: D23: Program that separates text to words.

tool: D49: Usage: towords filename

tool: D31: r

tool: D5: Could not open file %s


tool: D40: %d: %s


tool: D29: words total = %d


assistant: ```c
int main(int argc, char **argv) {
  printf("Program that separates text to words.\n");
  if (argc < 2) {
    printf("Usage: towords filename\n");
    exit(1);
  }
  char *fileName = argv[1];
  FILE *fd = fopen(fileName, "r");
  if (fd == NULL) {
    printf("Could not open file %s\n", fileName);
    exit(1);
  }
  char *w;
  int wordCount = 0;
  while ((w = nextword(fd)) != NULL) {
    printf("%d: %s\n", wordCount, w);
    wordCount++;
  }
  printf("words total = %d\n", wordCount);
  fclose(fd);
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  lea    D19(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebp
  jle    L24
L48:
  mov    0x8(%rbx),%rbx
  lea    D54(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L44
L32:
  mov    $0x0,%ebx
  lea    D14(%rip),%r12
  jmp    L8
L24:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L48
L44:
  mov    %rbx,%rsi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L32
L29:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
L8:
  mov    %rbp,%rdi
  call   <nextword@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  jne    L29
  mov    %ebx,%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
datatype: string
name: extract_symbolic_data
arguments: data_tag: D54
datatype: string
name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string
name: extract_symbolic_data
arguments: data_tag: D59
datatype: string
name: extract_symbolic_data
arguments: data_tag: D44
datatype: string

tool: D19: Program that separates text to words.

tool: D54: r

tool: D14: %d: %s


tool: D21: Usage: towords filename

tool: D59: Could not open file %s


tool: D44: words total = %d


assistant: ```c
int main(int argc, char **argv) {
  printf("Program that separates text to words.\n");
  if (argc < 2) {
    printf("Usage: towords filename\n");
    exit(1);
  }
  char *fileName = argv[1];
  FILE *fd = fopen(fileName, "r");
  if (fd == NULL) {
    printf("Could not open file %s\n", fileName);
    exit(1);
  }
  char *w;
  int wordCount = 0;
  while ((w = nextword(fd)) != NULL) {
    printf("%d: %s\n", wordCount, w);
    wordCount++;
  }
  printf("words total = %d\n", wordCount);
  fclose(fd);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D9(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <puts@plt>
  cmp    $0x1,%ebp
  jle    L59
L21:
  mov    0x8(%rbx),%rbp
  lea    D45(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L53
L17:
  xor    %ebp,%ebp
  lea    D2(%rip),%rbx
  jmp    L28
  nopl   0x0(%rax)
L40:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
L28:
  mov    %r12,%rdi
  call   <nextword@plt>
  mov    %ebp,%esi
  mov    %rax,%rdx
  test   %rax,%rax
  jne    L40
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  xor    %edi,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L59:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L21
L53:
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D45
datatype: string
name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D10
datatype: string
name: read_data
arguments: data_tag: D24
datatype: string
name: read_data
arguments: data_tag: D28
datatype: string

tool: D9: Program that separates text to words.

tool: D45: r

tool: D2: %d: %s


tool: D10: words total = %d


tool: D24: Usage: towords filename

tool: D28: Could not open file %s


assistant: ```c
int main(int argc, char **argv) {
  printf("Program that separates text to words.\n");
  if (argc < 2) {
    printf("Usage: towords filename\n");
    exit(1);
  }
  char *fileName = argv[1];
  FILE *fd = fopen(fileName, "r");
  if (fd == NULL) {
    printf("Could not open file %s\n", fileName);
    exit(1);
  }
  char *w;
  int wordCount = 0;
  while ((w = nextword(fd)) != NULL) {
    printf("%d: %s\n", wordCount, w);
    wordCount++;
  }
  printf("words total = %d\n", wordCount);
  fclose(fd);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <puts@plt>
  cmp    $0x1,%ebp
  jle    L11
L49:
  mov    0x8(%rbx),%rbp
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L8:
  xor    %ebp,%ebp
  lea    D24(%rip),%rbx
  jmp    L3
  nopl   0x0(%rax)
L56:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
L3:
  mov    %r12,%rdi
  call   <nextword@plt>
  mov    %ebp,%esi
  mov    %rax,%rdx
  test   %rax,%rax
  jne    L56
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  xor    %edi,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L11:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L49
L2:
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string
name: extract_symbolic_data
arguments: data_label: D24
type_infered: string
name: extract_symbolic_data
arguments: data_label: D56
type_infered: string
name: extract_symbolic_data
arguments: data_label: D7
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D1: Program that separates text to words.

tool: D30: r

tool: D24: %d: %s


tool: D56: words total = %d


tool: D7: Usage: towords filename

tool: D8: Could not open file %s


assistant: ```c
int main(int argc, char **argv) {
  printf("Program that separates text to words.\n");
  if (argc < 2) {
    printf("Usage: towords filename\n");
    exit(1);
  }
  char *fileName = argv[1];
  FILE *fd = fopen(fileName, "r");
  if (fd == NULL) {
    printf("Could not open file %s\n", fileName);
    exit(1);
  }
  char *w;
  int wordCount = 0;
  while ((w = nextword(fd)) != NULL) {
    printf("%d: %s\n", wordCount, w);
    wordCount++;
  }
  printf("words total = %d\n", wordCount);
  fclose(fd);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pdist_minkowski>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L22
L29:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L35
L4:
  mov    -0x38(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <minkowski_distance@plt>
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  addq   $0x8,-0x18(%rbp)
L35:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L4
  addl   $0x1,-0x20(%rbp)
L22:
  mov    -0x20(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L29
  nop
  nop
  leave
  ret
```

assistant: ```c
void pdist_minkowski(const double *X, double *dm, int m, int n, double p) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = minkowski_distance(u, v, n, p);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pdist_minkowski>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edx,%edx
  jle    L28
  mov    %rsi,%rbx
  mov    %ecx,%r14d
  lea    -0x2(%rdx),%r15d
  movslq %ecx,%rax
  lea    0x0(,%rax,8),%rcx
  mov    %rcx,(%rsp)
  add    %rcx,%rdi
  mov    %rdi,0x10(%rsp)
  neg    %rax
  shl    $0x3,%rax
  mov    %rax,0x18(%rsp)
L29:
  cmp    $0xffffffff,%r15d
  je     L28
  mov    0x10(%rsp),%rbp
  mov    %rbp,%r13
  add    0x18(%rsp),%r13
  mov    %r15d,%eax
  lea    0x8(%rbx,%rax,8),%r12
L5:
  movsd  0x8(%rsp),%xmm0
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <minkowski_distance@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  add    (%rsp),%rbp
  cmp    %r12,%rbx
  jne    L5
  sub    $0x1,%r15d
  mov    (%rsp),%rcx
  add    %rcx,0x10(%rsp)
  mov    %r12,%rbx
  jmp    L29
L28:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pdist_minkowski(const double *X, double *dm, int m, int n, double p) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = minkowski_distance(u, v, n, p);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pdist_minkowski>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edx,%edx
  jle    L2
  movslq %ecx,%rbx
  lea    -0x2(%rdx),%eax
  mov    %rsi,%r15
  mov    %ecx,%r13d
  shl    $0x3,%rbx
  mov    %eax,0x14(%rsp)
  lea    (%rdi,%rbx,1),%rax
  mov    %rax,0x18(%rsp)
  mov    0x14(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L2
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x18(%rsp),%r14
  lea    0x1(%rax),%edx
  lea    (%r15,%rdx,8),%rbp
  mov    %r14,%r12
  sub    %rbx,%r12
  nopw   0x0(%rax,%rax,1)
L26:
  movsd  0x8(%rsp),%xmm0
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %r12,%rdi
  add    $0x8,%r15
  add    %rbx,%r14
  call   <minkowski_distance@plt>
  movsd  %xmm0,-0x8(%r15)
  cmp    %rbp,%r15
  jne    L26
  subl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  add    %rbx,0x18(%rsp)
  cmp    $0xffffffff,%eax
  jne    L1
L2:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pdist_minkowski(const double *X, double *dm, int m, int n, double p) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = minkowski_distance(u, v, n, p);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pdist_minkowski>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %edx,0xc(%rsp)
  movsd  %xmm0,0x10(%rsp)
  cmp    $0x1,%edx
  jle    L23
  movslq %ecx,%rbx
  mov    %edx,%eax
  movl   $0x1,0x28(%rsp)
  mov    %ecx,%r13d
  shl    $0x3,%rbx
  sub    $0x1,%eax
  lea    (%rdi,%rbx,1),%rsi
  mov    %eax,0x2c(%rsp)
  mov    %rsi,0x20(%rsp)
  xchg   %ax,%ax
L6:
  mov    0x20(%rsp),%rbp
  mov    0x18(%rsp),%r14
  mov    0x28(%rsp),%r15d
  mov    %rbp,%r12
  sub    %rbx,%r12
  nopl   (%rax)
L4:
  movsd  0x10(%rsp),%xmm0
  mov    %rbp,%rsi
  mov    %r13d,%edx
  mov    %r12,%rdi
  add    $0x1,%r15d
  add    $0x8,%r14
  add    %rbx,%rbp
  call   <minkowski_distance@plt>
  movsd  %xmm0,-0x8(%r14)
  cmp    %r15d,0xc(%rsp)
  jg     L4
  mov    0x28(%rsp),%ecx
  mov    0x2c(%rsp),%eax
  mov    0x18(%rsp),%rdx
  add    %rbx,0x20(%rsp)
  sub    %ecx,%eax
  add    $0x1,%ecx
  lea    0x8(%rdx,%rax,8),%rax
  mov    %ecx,0x28(%rsp)
  mov    %rax,0x18(%rsp)
  cmp    %ecx,0xc(%rsp)
  jne    L6
L23:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pdist_minkowski(const double *X, double *dm, int m, int n, double p) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = minkowski_distance(u, v, n, p);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jg     L107
  mov    -0x18(%rbp),%rax
  jmp    L28
L107:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x20(%rbp)
  jae    L115
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L119
L115:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L28
L119:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L63
  jmp    L95
L90:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L95:
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L90
  jmp    L6
L63:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L6
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  jmp    L102
L62:
  subq   $0x1,-0x20(%rbp)
  subq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L102:
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L62
L6:
  mov    -0x8(%rbp),%rax
L28:
  leave
  ret
```

assistant: ```c
char *memmove(char *dst, char *src, int n) {
  char *realdst = dst;
  if (n <= 0)
    return dst;
  if (src >= dst + n || dst >= src + n)
    return memcpy(dst, src, n);
  if (src > dst) {
    while (--n >= 0)
      *dst++ = *src++;
  } else if (src < dst) {
    src += n;
    dst += n;
    while (--n >= 0)
      *--dst = *--src;
  }
  return realdst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L35
  movslq %edx,%rcx
  lea    (%rdi,%rcx,1),%rdi
  cmp    %rsi,%rdi
  jbe    L10
  add    %rsi,%rcx
  cmp    %rax,%rcx
  jbe    L10
  cmp    %rsi,%rax
  jae    L11
  mov    %edx,%edx
  mov    $0x0,%ecx
L62:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L62
  ret
L10:
  sub    $0x8,%rsp
  mov    %rax,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
L11:
  jbe    L35
  lea    -0x1(%rdx),%edx
  mov    $0xfffffffffffffffe,%r8
  sub    %rdx,%r8
  mov    $0xffffffffffffffff,%rdx
L26:
  movzbl (%rcx,%rdx,1),%esi
  mov    %sil,(%rdi,%rdx,1)
  sub    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L26
  ret
L35:
  ret
```

assistant: ```c
char *memmove(char *dst, char *src, int n) {
  char *realdst = dst;
  if (n <= 0)
    return dst;
  if (src >= dst + n || dst >= src + n)
    return memcpy(dst, src, n);
  if (src > dst) {
    while (--n >= 0)
      *dst++ = *src++;
  } else if (src < dst) {
    src += n;
    dst += n;
    while (--n >= 0)
      *--dst = *--src;
  }
  return realdst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memmove>:
  endbr64
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L42
  movslq %edx,%rcx
  lea    (%rdi,%rcx,1),%rdi
  cmp    %rsi,%rdi
  jbe    L2
  lea    (%rsi,%rcx,1),%r9
  cmp    %r8,%r9
  jbe    L2
  cmp    %rsi,%r8
  jb     L6
  jbe    L42
  lea    -0x1(%rdx),%eax
  mov    $0xfffffffffffffffe,%rcx
  sub    %rax,%rcx
  mov    $0xffffffffffffffff,%rax
  nopl   0x0(%rax,%rax,1)
L30:
  movzbl (%r9,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L30
L42:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L2:
  mov    %r8,%rdi
  jmp    1050 <memcpy@plt>
L6:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L49:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L49
  mov    %r8,%rax
  ret
```

assistant: ```c
char *memmove(char *dst, char *src, int n) {
  char *realdst = dst;
  if (n <= 0)
    return dst;
  if (src >= dst + n || dst >= src + n)
    return memcpy(dst, src, n);
  if (src > dst) {
    while (--n >= 0)
      *dst++ = *src++;
  } else if (src < dst) {
    src += n;
    dst += n;
    while (--n >= 0)
      *--dst = *--src;
  }
  return realdst;
}
```