ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<remove_nl>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%esi
  sub    $0x1,%esi
  js     L6
  cltq
  movslq %esi,%rdx
  mov    %esi,%esi
  lea    -0x2(%rbx,%rax,1),%rcx
  add    %rbx,%rdx
  sub    %rsi,%rcx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L31:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L6
L20:
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L31
  cmp    $0xd,%al
  je     L31
L6:
  pop    %rbx
  ret
```

assistant: ```c
void remove_nl(char *buf) {
  int i;
  for (i = strlen(buf) - 1; i >= 0 && (buf[i] == '\n' || buf[i] == '\r'); i--)
    buf[i] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func_13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movb   $0x35,-0x9(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0xec,%edi
  call   <step_hash@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0xed,%edi
  call   <step_hash@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0xee,%edi
  call   <step_hash@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *func_13(int *p_14, int p_15) {
  unsigned char l_335 = 0x35L;
  int *l_338 = (void *)0;
  step_hash(236);
  (*p_14) = (*p_14);
  step_hash(237);
  p_14 = &p_15;
  step_hash(238);
  return l_338;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func_13>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xec,%edi
  call   <step_hash@plt>
  mov    $0xed,%edi
  call   <step_hash@plt>
  mov    $0xee,%edi
  call   <step_hash@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *func_13(int *p_14, int p_15) {
  unsigned char l_335 = 0x35L;
  int *l_338 = (void *)0;
  step_hash(236);
  (*p_14) = (*p_14);
  step_hash(237);
  p_14 = &p_15;
  step_hash(238);
  return l_338;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func_13>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xec,%edi
  call   <step_hash@plt>
  mov    $0xed,%edi
  call   <step_hash@plt>
  mov    $0xee,%edi
  call   <step_hash@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *func_13(int *p_14, int p_15) {
  unsigned char l_335 = 0x35L;
  int *l_338 = (void *)0;
  step_hash(236);
  (*p_14) = (*p_14);
  step_hash(237);
  p_14 = &p_15;
  step_hash(238);
  return l_338;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func_13>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xec,%edi
  call   <step_hash@plt>
  mov    $0xed,%edi
  call   <step_hash@plt>
  mov    $0xee,%edi
  call   <step_hash@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *func_13(int *p_14, int p_15) {
  unsigned char l_335 = 0x35L;
  int *l_338 = (void *)0;
  step_hash(236);
  (*p_14) = (*p_14);
  step_hash(237);
  p_14 = &p_15;
  step_hash(238);
  return l_338;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L13:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L1:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L13
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *mem_set(void *s, int c, size_t n) {
  unsigned char *p = (unsigned char *)s;
  while (n--)
    *p++ = (unsigned char)c;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mem_set>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L8
  add    %rdi,%rdx
  mov    %rdi,%rcx
L18:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rcx,%rdx
  jne    L18
L8:
  ret
```

assistant: ```c
void *mem_set(void *s, int c, size_t n) {
  unsigned char *p = (unsigned char *)s;
  while (n--)
    *p++ = (unsigned char)c;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mem_set>:
  endbr64
  test   %rdx,%rdx
  je     L2
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *mem_set(void *s, int c, size_t n) {
  unsigned char *p = (unsigned char *)s;
  while (n--)
    *p++ = (unsigned char)c;
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mem_set>:
  endbr64
  test   %rdx,%rdx
  je     L5
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *mem_set(void *s, int c, size_t n) {
  unsigned char *p = (unsigned char *)s;
  while (n--)
    *p++ = (unsigned char)c;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,%edx
  je     L15
  lea    (%rax,%rax,1),%edx
L10:
  add    $0x4c2b8a7a,%edx
  mov    %edx,(%rsi)
  ret
L15:
  mov    %eax,%ecx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %cl,%dl
  movzbl %al,%eax
  shl    $0x10,%eax
  and    $0xff00ffff,%edx
  or     %eax,%edx
  jmp    L10
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  unsigned short copy16;
  unsigned short copy17;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[local1] += state[local1];
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy12;
          copy13 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy13;
        }
      } else if (state[0UL] <= local1) {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy14;
      } else {
        copy16 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy16;
        copy17 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy17;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 319257925UL) + 958663989U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  sub    $0x99f4bb,%edx
  mov    %edx,%eax
  lea    (%rdx,%rdx,1),%ecx
  and    $0xff00ff00,%eax
  test   %edx,%edx
  cmovne %ecx,%eax
  add    $0x4c2b8a7a,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  unsigned short copy16;
  unsigned short copy17;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[local1] += state[local1];
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy12;
          copy13 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy13;
        }
      } else if (state[0UL] <= local1) {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy14;
      } else {
        copy16 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy16;
        copy17 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy17;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 319257925UL) + 958663989U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  sub    $0x99f4bb,%edx
  mov    %edx,%eax
  lea    (%rdx,%rdx,1),%ecx
  and    $0xff00ff00,%eax
  test   %edx,%edx
  cmovne %ecx,%eax
  add    $0x4c2b8a7a,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  unsigned short copy16;
  unsigned short copy17;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[local1] += state[local1];
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy12;
          copy13 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy13;
        }
      } else if (state[0UL] <= local1) {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy14;
      } else {
        copy16 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy16;
        copy17 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy17;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 319257925UL) + 958663989U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<genpkey_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x2a,-0x15(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_CTX_get_app_data@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <EVP_PKEY_CTX_get_keygen_info@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L44
  movb   $0x2e,-0x15(%rbp)
L44:
  cmpl   $0x1,-0x14(%rbp)
  jne    L38
  movb   $0x2b,-0x15(%rbp)
L38:
  cmpl   $0x2,-0x14(%rbp)
  jne    L10
  movb   $0x2a,-0x15(%rbp)
L10:
  cmpl   $0x3,-0x14(%rbp)
  jne    L3
  movb   $0xa,-0x15(%rbp)
L3:
  lea    -0x15(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_flush@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int genpkey_cb(EVP_PKEY_CTX *ctx) {
  char c = '*';
  BIO *b = EVP_PKEY_CTX_get_app_data(ctx);
  int p;
  p = EVP_PKEY_CTX_get_keygen_info(ctx, 0);
  if (p == 0)
    c = '.';
  if (p == 1)
    c = '+';
  if (p == 2)
    c = '*';
  if (p == 3)
    c = '\n';
  BIO_write(b, &c, 1);
  (void)BIO_flush(b);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<genpkey_cb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x2a,0x7(%rsp)
  call   <EVP_PKEY_CTX_get_app_data@plt>
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <EVP_PKEY_CTX_get_keygen_info@plt>
  test   %eax,%eax
  jne    L66
  movb   $0x2e,0x7(%rsp)
L54:
  cmp    $0x3,%eax
  jne    L50
  movb   $0xa,0x7(%rsp)
  jmp    L50
L66:
  cmp    $0x1,%eax
  jne    L24
  movb   $0x2b,0x7(%rsp)
L50:
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <BIO_write@plt>
  mov    %rbx,%rdi
  call   <BIO_flush@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x1,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  cmp    $0x2,%eax
  jne    L54
  movb   $0x2a,0x7(%rsp)
  jmp    L50
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int genpkey_cb(EVP_PKEY_CTX *ctx) {
  char c = '*';
  BIO *b = EVP_PKEY_CTX_get_app_data(ctx);
  int p;
  p = EVP_PKEY_CTX_get_keygen_info(ctx, 0);
  if (p == 0)
    c = '.';
  if (p == 1)
    c = '+';
  if (p == 2)
    c = '*';
  if (p == 3)
    c = '\n';
  BIO_write(b, &c, 1);
  (void)BIO_flush(b);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<genpkey_cb>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x2a,0x7(%rsp)
  call   <EVP_PKEY_CTX_get_app_data@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <EVP_PKEY_CTX_get_keygen_info@plt>
  test   %eax,%eax
  jne    L71
  movb   $0x2e,0x7(%rsp)
L46:
  mov    %rbp,%rdi
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  call   <BIO_flush@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L71:
  cmp    $0x1,%eax
  jne    L64
  movb   $0x2b,0x7(%rsp)
  jmp    L46
  nopl   0x0(%rax)
L64:
  cmp    $0x2,%eax
  jne    L66
  movb   $0x2a,0x7(%rsp)
  jmp    L46
L66:
  cmp    $0x3,%eax
  jne    L46
  movb   $0xa,0x7(%rsp)
  jmp    L46
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int genpkey_cb(EVP_PKEY_CTX *ctx) {
  char c = '*';
  BIO *b = EVP_PKEY_CTX_get_app_data(ctx);
  int p;
  p = EVP_PKEY_CTX_get_keygen_info(ctx, 0);
  if (p == 0)
    c = '.';
  if (p == 1)
    c = '+';
  if (p == 2)
    c = '*';
  if (p == 3)
    c = '\n';
  BIO_write(b, &c, 1);
  (void)BIO_flush(b);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<genpkey_cb>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x2a,0x7(%rsp)
  call   <EVP_PKEY_CTX_get_app_data@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <EVP_PKEY_CTX_get_keygen_info@plt>
  test   %eax,%eax
  jne    L51
  movb   $0x2e,0x7(%rsp)
L62:
  mov    %rbp,%rdi
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  call   <BIO_flush@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L51:
  cmp    $0x1,%eax
  jne    L16
  movb   $0x2b,0x7(%rsp)
  jmp    L62
  nopl   0x0(%rax)
L16:
  cmp    $0x2,%eax
  jne    L21
  movb   $0x2a,0x7(%rsp)
  jmp    L62
L21:
  cmp    $0x3,%eax
  jne    L62
  movb   $0xa,0x7(%rsp)
  jmp    L62
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int genpkey_cb(EVP_PKEY_CTX *ctx) {
  char c = '*';
  BIO *b = EVP_PKEY_CTX_get_app_data(ctx);
  int p;
  p = EVP_PKEY_CTX_get_keygen_info(ctx, 0);
  if (p == 0)
    c = '.';
  if (p == 1)
    c = '+';
  if (p == 2)
    c = '*';
  if (p == 3)
    c = '\n';
  BIO_write(b, &c, 1);
  (void)BIO_flush(b);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<filecopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x20000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0x40,%rsp
  mov    %edi,-0x20034(%rbp)
  mov    %esi,-0x20038(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20028(%rbp),%rdx
  mov    -0x20038(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jns    L19
  mov    $0xffffffff,%eax
  jmp    L49
L19:
  mov    -0x20028(%rbp),%eax
  test   %eax,%eax
  jne    L21
  mov    $0x0,%eax
  jmp    L49
L21:
  mov    -0x20028(%rbp),%eax
  mov    %eax,-0x20024(%rbp)
L61:
  movl   $0x0,-0x20020(%rbp)
  mov    -0x20024(%rbp),%eax
  mov    %eax,-0x2001c(%rbp)
  mov    -0x20024(%rbp),%eax
  cmp    $0x20000,%eax
  jbe    L63
  movl   $0x20000,-0x2001c(%rbp)
L63:
  mov    -0x2001c(%rbp),%edx
  lea    -0x20010(%rbp),%rcx
  mov    -0x20038(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x20018(%rbp)
  cmpl   $0x0,-0x20018(%rbp)
  jg     L18
  mov    $0xffffffff,%eax
  jmp    L49
L18:
  mov    -0x20018(%rbp),%eax
  sub    %eax,-0x20024(%rbp)
L117:
  mov    -0x20020(%rbp),%eax
  cltq
  lea    -0x20010(%rbp),%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20018(%rbp),%edx
  mov    -0x20034(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x20014(%rbp)
  cmpl   $0x0,-0x20014(%rbp)
  jg     L110
  mov    $0xffffffff,%eax
  jmp    L49
L110:
  mov    -0x20014(%rbp),%eax
  sub    %eax,-0x20018(%rbp)
  mov    -0x20014(%rbp),%eax
  add    %eax,-0x20020(%rbp)
  cmpl   $0x0,-0x20018(%rbp)
  jne    L117
  cmpl   $0x0,-0x20024(%rbp)
  jne    L61
  mov    $0x0,%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

assistant: ```c
int filecopy(int out, int in) {
  char block[32 * 4096];
  ssize_t todo;
  struct stat st;
  if (fstat(in, &st) < 0) {
    ;
    return -1;
  }
  if (!st.st_size) {
    ;
    return 0;
  };
  todo = st.st_size;
  do {
    ssize_t wr_off = 0;
    ssize_t readsize = todo;
    if (todo > sizeof(block))
      readsize = sizeof(block);
    ssize_t res = read(in, block, readsize);
    if (res <= 0) {
      ;
      return -1;
    } else {
      todo -= res;
    }
    do {
      ssize_t written = write(out, block + wr_off, res);
      if (written <= 0) {
        ;
        return -1;
      } else {
        res -= written;
        wr_off += written;
      }
    } while (res);
  } while (todo);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<filecopy>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L80:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L80
  sub    $0x38,%rsp
  mov    %edi,%r12d
  mov    %esi,%edi
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x20028(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <fstat@plt>
  test   %rax,%rax
  js     L32
  mov    0x1c(%rsp),%r14d
  test   %r14d,%r14d
  je     L107
L52:
  cmp    $0x20001,%r14d
  mov    $0x20000,%edx
  cmovb  %r14d,%edx
  lea    0x20(%rsp),%rsi
  mov    0xc(%rsp),%edi
  call   <read@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jle    L33
  mov    %eax,%ebx
  mov    $0x0,%ebp
  lea    0x20(%rsp),%r13
L47:
  movslq %ebp,%rsi
  add    %r13,%rsi
  mov    %ebx,%edx
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L31
  add    %eax,%ebp
  sub    %eax,%ebx
  jne    L47
  sub    %r15d,%r14d
  jne    L52
  jmp    L107
L32:
  mov    $0xffffffff,%r14d
  jmp    L107
L33:
  mov    $0xffffffff,%r14d
  jmp    L107
L31:
  mov    $0xffffffff,%r14d
L107:
  mov    0x20028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  mov    %r14d,%eax
  add    $0x20038,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L105:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filecopy(int out, int in) {
  char block[32 * 4096];
  ssize_t todo;
  struct stat st;
  if (fstat(in, &st) < 0) {
    ;
    return -1;
  }
  if (!st.st_size) {
    ;
    return 0;
  };
  todo = st.st_size;
  do {
    ssize_t wr_off = 0;
    ssize_t readsize = todo;
    if (todo > sizeof(block))
      readsize = sizeof(block);
    ssize_t res = read(in, block, readsize);
    if (res <= 0) {
      ;
      return -1;
    } else {
      todo -= res;
    }
    do {
      ssize_t written = write(out, block + wr_off, res);
      if (written <= 0) {
        ;
        return -1;
      } else {
        res -= written;
        wr_off += written;
      }
    } while (res);
  } while (todo);
  return 0;
}
```