user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r14
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L50
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%rbp
  test   %edi,%edi
  jle    L35
  mov    %rax,%r13
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L27:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r15d
  add    $0x4,%r13
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    %r15d,%edi
  jg     L27
L35:
  shl    $0x2,%edi
  movslq 0x0(%rbp),%r15
  call   <malloc@plt>
  mov    0x0(%rbp),%ecx
  mov    %rax,%r13
  mov    %r15,%rsi
  mov    %ecx,(%rax)
  movslq 0x4(%rsp),%rax
  cmp    $0x1,%rax
  jbe    L77
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L49:
  mov    0x0(%rbp,%rax,4),%edx
  movslq %edx,%rdi
  test   %r15,%r15
  js     L73
L19:
  add    %r15,%rdi
  test   %edx,%edx
  cmovg  %rdi,%r15
L52:
  test   %ecx,%ecx
  jle    L80
  add    %edx,%ecx
  movslq %ecx,%rdx
  mov    %ecx,0x0(%r13,%rax,4)
  cmp    %rdx,%rsi
  cmovl  %rdx,%rsi
  movslq 0x4(%rsp),%rdx
  add    $0x1,%rax
  cmp    %rdx,%rax
  jb     L49
L77:
  mov    %r15,%rdx
  lea    D17(%rip),%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  cmp    %r12d,(%rsp)
  jg     L38
L50:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L80:
  movslq %edx,%rcx
  mov    %edx,0x0(%r13,%rax,4)
  cmp    %rcx,%rsi
  cmovl  %rcx,%rsi
  movslq 0x4(%rsp),%rcx
  add    $0x1,%rax
  cmp    %rax,%rcx
  jbe    L77
  mov    %edx,%ecx
  mov    0x0(%rbp,%rax,4),%edx
  movslq %edx,%rdi
  test   %r15,%r15
  jns    L19
L73:
  cmp    %rdi,%r15
  cmovl  %rdi,%r15
  jmp    L52
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D6: %i

tool: D17: %lld %lld


assistant: ```c
int main() {
  int t;
  scanf("%i", &t);
  for (int a0 = 0; a0 < t; a0++) {
    int n;
    scanf("%i", &n);
    int *arr = malloc(sizeof(int) * n);
    for (int arr_i = 0; arr_i < n; arr_i++) {
      scanf("%i", &arr[arr_i]);
    }
    long long ret_subarrays = arr[0];
    long long ret_subsequences = arr[0];
    int *sum_subarrays = malloc(n * sizeof(int));
    sum_subarrays[0] = arr[0];
    for (size_t i = 1; i < n; i++) {
      if (ret_subsequences < 0) {
        if (ret_subsequences < arr[i]) {
          ret_subsequences = arr[i];
        }
      } else {
        if (0 < arr[i]) {
          ret_subsequences += arr[i];
        }
      }
      if (sum_subarrays[i - 1] + arr[i] > arr[i]) {
        sum_subarrays[i] = sum_subarrays[i - 1] + arr[i];
      } else {
        sum_subarrays[i] = arr[i];
      }
      if (sum_subarrays[i] > ret_subarrays) {
        ret_subarrays = sum_subarrays[i];
      }
    }
    printf("%lld %lld\n", ret_subarrays, ret_subsequences);
    free(arr);
    free(sum_subarrays);
  }
  return 0;
}
```