ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<gamestart>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clearScreen@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: 
	 Press ENTER to start the game.
	Enjoy and have fun! 

assistant: ```c
int gamestart() {
  clearScreen();
  printf("\n\t Press ENTER to start the game.\n\tEnjoy and have fun! ");
  getchar();
  getchar();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strclr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ft_memset@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (s)
    ft_memset(s, '\0', ft_strlen(s));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <ft_memset@plt>
  pop    %rbx
  ret
L9:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (s)
    ft_memset(s, '\0', ft_strlen(s));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  je     L7
  push   %rbp
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  mov    %eax,%edx
  jmp    1070 <ft_memset@plt>
  nop
L7:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (s)
    ft_memset(s, '\0', ft_strlen(s));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %rbp
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  mov    %eax,%edx
  jmp    1070 <ft_memset@plt>
  nop
L5:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (s)
    ft_memset(s, '\0', ft_strlen(s));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x2111,%edi
  call   <__send_to_ppe@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(unsigned long long speid, unsigned long long argp, unsigned long long envp) {
  __send_to_ppe(0x2111, 0, NULL);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x2111,%edi
  call   <__send_to_ppe@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(unsigned long long speid, unsigned long long argp, unsigned long long envp) {
  __send_to_ppe(0x2111, 0, NULL);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x2111,%edi
  call   <__send_to_ppe@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(unsigned long long speid, unsigned long long argp, unsigned long long envp) {
  __send_to_ppe(0x2111, 0, NULL);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x2111,%edi
  call   <__send_to_ppe@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(unsigned long long speid, unsigned long long argp, unsigned long long envp) {
  __send_to_ppe(0x2111, 0, NULL);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L5
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void Stat(const char *path, struct stat *info) {
  int success = stat(path, info);
  if (success == -1) {
    do {
      int e = errno;
      perror(path);
      exit(e);
    } while (0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Stat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L18
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    D5(%rip),%rax
  mov    (%rax),%ebp
  mov    %rbx,%rdi
  call   <perror@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  jmp    L13
```

assistant: ```c
void Stat(const char *path, struct stat *info) {
  int success = stat(path, info);
  if (success == -1) {
    do {
      int e = errno;
      perror(path);
      exit(e);
    } while (0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Stat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L2
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    D4(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%r12d
  call   <perror@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
```

assistant: ```c
void Stat(const char *path, struct stat *info) {
  int success = stat(path, info);
  if (success == -1) {
    do {
      int e = errno;
      perror(path);
      exit(e);
    } while (0);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<Stat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    D3(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%r12d
  call   <perror@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
```

assistant: ```c
void Stat(const char *path, struct stat *info) {
  int success = stat(path, info);
  if (success == -1) {
    do {
      int e = errno;
      perror(path);
      exit(e);
    } while (0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ls@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; ++i)
    ls(argv[i]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L2
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L8:
  mov    (%rbx),%rdi
  call   <ls@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L8
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; ++i)
    ls(argv[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <ls@plt>
  cmp    %rbp,%rbx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; ++i)
    ls(argv[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L15
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <ls@plt>
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; ++i)
    ls(argv[i]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CG_getBindKeyName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L2:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <trap_Key_GetBindingBuf@plt>
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Q_stricmp@plt>
  test   %eax,%eax
  jne    L31
  mov    -0x20(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <trap_Key_KeynumToStringBuf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Q_strupr@plt>
  mov    -0x20(%rbp),%rax
  jmp    L34
L18:
  nop
L31:
  addl   $0x1,-0x4(%rbp)
L21:
  cmpl   $0xff,-0x4(%rbp)
  jle    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <va@plt>
  mov    %eax,%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Q_strncpyz@plt>
  mov    -0x20(%rbp),%rax
L34:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: (%s)

assistant: ```c
char *CG_getBindKeyName(const char *cmd, char *buf, int len) {
  int j;
  for (j = 0; j < 256; j++) {
    trap_Key_GetBindingBuf(j, buf, len);
    if (*buf == 0)
      continue;
    if (!Q_stricmp(buf, cmd)) {
      trap_Key_KeynumToStringBuf(j, buf, 256);
      Q_strupr(buf);
      return (buf);
    }
  }
  Q_strncpyz(buf, va("(%s)", cmd), len);
  return (buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CG_getBindKeyName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    $0x0,%ebx
  jmp    L20
L19:
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  je     L16
L20:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <trap_Key_GetBindingBuf@plt>
  cmpb   $0x0,0x0(%rbp)
  je     L19
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <Q_stricmp@plt>
  test   %eax,%eax
  jne    L19
  mov    $0x100,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <trap_Key_KeynumToStringBuf@plt>
  mov    %rbp,%rdi
  call   <Q_strupr@plt>
L35:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    %r13,%rsi
  lea    D8(%rip),%rdi
  call   <va@plt>
  mov    %eax,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <Q_strncpyz@plt>
  jmp    L35
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D8: (%s)

assistant: ```c
char *CG_getBindKeyName(const char *cmd, char *buf, int len) {
  int j;
  for (j = 0; j < 256; j++) {
    trap_Key_GetBindingBuf(j, buf, len);
    if (*buf == 0)
      continue;
    if (!Q_stricmp(buf, cmd)) {
      trap_Key_KeynumToStringBuf(j, buf, 256);
      Q_strupr(buf);
      return (buf);
    }
  }
  Q_strncpyz(buf, va("(%s)", cmd), len);
  return (buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CG_getBindKeyName>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  sub    $0x8,%rsp
  jmp    L17
  nopl   0x0(%rax)
L15:
  add    $0x1,%ebp
  cmp    $0x100,%ebp
  je     L37
L17:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <trap_Key_GetBindingBuf@plt>
  cmpb   $0x0,(%r12)
  je     L15
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <Q_stricmp@plt>
  test   %eax,%eax
  jne    L15
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    $0x100,%edx
  call   <trap_Key_KeynumToStringBuf@plt>
  mov    %r12,%rdi
  call   <Q_strupr@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  mov    %r14,%rsi
  lea    D6(%rip),%rdi
  call   <va@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <Q_strncpyz@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: (%s)

assistant: ```c
char *CG_getBindKeyName(const char *cmd, char *buf, int len) {
  int j;
  for (j = 0; j < 256; j++) {
    trap_Key_GetBindingBuf(j, buf, len);
    if (*buf == 0)
      continue;
    if (!Q_stricmp(buf, cmd)) {
      trap_Key_KeynumToStringBuf(j, buf, 256);
      Q_strupr(buf);
      return (buf);
    }
  }
  Q_strncpyz(buf, va("(%s)", cmd), len);
  return (buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<CG_getBindKeyName>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  sub    $0x8,%rsp
  jmp    L34
  nopl   0x0(%rax)
L6:
  add    $0x1,%ebp
  cmp    $0x100,%ebp
  je     L27
L34:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <trap_Key_GetBindingBuf@plt>
  cmpb   $0x0,(%r12)
  je     L6
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <Q_stricmp@plt>
  test   %eax,%eax
  jne    L6
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    $0x100,%edx
  call   <trap_Key_KeynumToStringBuf@plt>
  mov    %r12,%rdi
  call   <Q_strupr@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  mov    %r14,%rsi
  lea    D8(%rip),%rdi
  call   <va@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <Q_strncpyz@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D8: (%s)

assistant: ```c
char *CG_getBindKeyName(const char *cmd, char *buf, int len) {
  int j;
  for (j = 0; j < 256; j++) {
    trap_Key_GetBindingBuf(j, buf, len);
    if (*buf == 0)
      continue;
    if (!Q_stricmp(buf, cmd)) {
      trap_Key_KeynumToStringBuf(j, buf, 256);
      Q_strupr(buf);
      return (buf);
    }
  }
  Q_strncpyz(buf, va("(%s)", cmd), len);
  return (buf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fpattern_matchn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L48
  mov    $0x0,%eax
  jmp    L32
L48:
  cmpq   $0x0,-0x18(%rbp)
  jne    L49
  mov    $0x0,%eax
  jmp    L32
L49:
  cmpl   $0x0,-0x24(%rbp)
  jns    L59
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
L59:
  cmpl   $0x0,-0x28(%rbp)
  je     L63
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fpattern_submatch@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L23
L63:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fpattern_submatch_tolower@plt>
  mov    %eax,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
L32:
  leave
  ret
```

assistant: ```c
int fpattern_matchn(const char *pat, const char *fname, int flength, int keepcase) {
  int rc;
  if (fname == ((void *)0))
    return (0);
  if (pat == ((void *)0))
    return (0);
  ;
  if (flength < 0)
    flength = strlen(fname);
  if (keepcase)
    rc = fpattern_submatch(pat, fname, flength);
  else
    rc = fpattern_submatch_tolower(pat, fname, flength);
  return (rc);
}
```
user: What is the c source code of the assembly code below:

```asm
<fpattern_matchn>:
  endbr64
  test   %rdi,%rdi
  je     L26
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %ecx,%r12d
  test   %rsi,%rsi
  je     L28
  test   %edx,%edx
  js     L3
L0:
  test   %r12d,%r12d
  je     L16
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fpattern_submatch@plt>
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L0
L16:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fpattern_submatch_tolower@plt>
  jmp    L15
L28:
  mov    $0x0,%eax
  jmp    L15
L26:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int fpattern_matchn(const char *pat, const char *fname, int flength, int keepcase) {
  int rc;
  if (fname == ((void *)0))
    return (0);
  if (pat == ((void *)0))
    return (0);
  ;
  if (flength < 0)
    flength = strlen(fname);
  if (keepcase)
    rc = fpattern_submatch(pat, fname, flength);
  else
    rc = fpattern_submatch_tolower(pat, fname, flength);
  return (rc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fpattern_matchn>:
  endbr64
  test   %rdi,%rdi
  je     L44
  test   %rsi,%rsi
  je     L44
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  test   %edx,%edx
  js     L27
  mov    %r12,%rdi
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L36
L45:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  jmp    1090 <fpattern_submatch@plt>
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  jmp    1070 <fpattern_submatch_tolower@plt>
  nopl   0x0(%rax)
L27:
  mov    %rsi,%rdi
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L36
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  ret
```

assistant: ```c
int fpattern_matchn(const char *pat, const char *fname, int flength, int keepcase) {
  int rc;
  if (fname == ((void *)0))
    return (0);
  if (pat == ((void *)0))
    return (0);
  ;
  if (flength < 0)
    flength = strlen(fname);
  if (keepcase)
    rc = fpattern_submatch(pat, fname, flength);
  else
    rc = fpattern_submatch_tolower(pat, fname, flength);
  return (rc);
}
```
user: What is the c source code of the assembly code below?

```asm
<fpattern_matchn>:
  endbr64
  test   %rdi,%rdi
  je     L4
  test   %rsi,%rsi
  je     L4
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  test   %edx,%edx
  js     L34
  mov    %r12,%rdi
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L43
L56:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  jmp    1090 <fpattern_submatch@plt>
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  jmp    1070 <fpattern_submatch_tolower@plt>
  nopl   0x0(%rax)
L34:
  mov    %rsi,%rdi
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L43
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int fpattern_matchn(const char *pat, const char *fname, int flength, int keepcase) {
  int rc;
  if (fname == ((void *)0))
    return (0);
  if (pat == ((void *)0))
    return (0);
  ;
  if (flength < 0)
    flength = strlen(fname);
  if (keepcase)
    rc = fpattern_submatch(pat, fname, flength);
  else
    rc = fpattern_submatch_tolower(pat, fname, flength);
  return (rc);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x1505,-0x8(%rbp)
  jmp    L19
L2:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L2
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash_function(const char *str, int size) {
  unsigned long hash = 5381;
  int c;
  while (c = *str++)
    hash = ((hash << 5) + hash) + c;
  return hash % size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash_function>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L8
  mov    $0x1505,%eax
L4:
  mov    %rax,%rdi
  shl    $0x5,%rdi
  add    %rdi,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L4
L29:
  movslq %esi,%rsi
  mov    $0x0,%edx
  div    %rsi
  mov    %edx,%eax
  ret
L8:
  mov    $0x1505,%eax
  jmp    L29
```

assistant: ```c
unsigned int hash_function(const char *str, int size) {
  unsigned long hash = 5381;
  int c;
  while (c = *str++)
    hash = ((hash << 5) + hash) + c;
  return hash % size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_function>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L15
  nopl   (%rax)
L7:
  mov    %rax,%rdi
  add    $0x1,%rcx
  shl    $0x5,%rdi
  add    %rdi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L7
L15:
  movslq %esi,%rsi
  xor    %edx,%edx
  div    %rsi
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int hash_function(const char *str, int size) {
  unsigned long hash = 5381;
  int c;
  while (c = *str++)
    hash = ((hash << 5) + hash) + c;
  return hash % size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash_function>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L18
  nopl   (%rax)
L6:
  mov    %rax,%rdi
  add    $0x1,%rcx
  shl    $0x5,%rdi
  add    %rdi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L6
L18:
  movslq %esi,%rsi
  xor    %edx,%edx
  div    %rsi
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int hash_function(const char *str, int size) {
  unsigned long hash = 5381;
  int c;
  while (c = *str++)
    hash = ((hash << 5) + hash) + c;
  return hash % size;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  lea    -0x4(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int my_putchar(char c) {
  write(1, &c, 1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_putchar>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int my_putchar(char c) {
  write(1, &c, 1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_putchar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %dil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int my_putchar(char c) {
  write(1, &c, 1);
  return (0);
}
```