ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    %r8,%r14
  sub    $0x1,%esi
  imul   %edx,%esi
  mov    %esi,0xc(%rsp)
  movslq %esi,%rbx
  mov    $0x0,%ebp
  movslq %edx,%rax
  mov    %rax,(%rsp)
  test   %rbx,%rbx
  js     L30
L13:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   *%r14
  test   %eax,%eax
  jle    L30
  add    %r12d,%ebp
  sub    (%rsp),%rbx
  jns    L13
L30:
  movslq %r12d,%r14
  add    %r14,%rbx
  mov    0xc(%rsp),%eax
  add    %r12d,%eax
  cltq
  cmp    %rbx,%rax
  je     L5
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,(%rsp)
  mov    D23(%rip),%rcx
  mov    (%rcx),%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <fseek@plt>
  mov    %r15,%rcx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    (%rsp),%rdi
  call   <fread@plt>
  lea    (%r14,%rbx,1),%rsi
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    %r15,%rdi
  call   <fseek@plt>
  mov    %r15,%rcx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    (%rsp),%rdi
  call   <fwrite@plt>
  mov    %r15,%rdi
  call   <fflush@plt>
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <fseek@plt>
  mov    %r15,%rcx
  mov    $0x1,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  mov    %r15,%rdi
  call   <fflush@plt>
L5:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void insert(FILE *strings, int loc, int s, char *saved, int (*cmp)(const long, const char *)) {
  long i = (loc - 1) * s;
  int numToMove = 0;
  while (i >= 0 && cmp(i, saved) > 0) {
    i -= s;
    numToMove += s;
  }
  i += s;
  if (i == loc * s) {
    return;
  }
  char *sn = (char *)calloc(numToMove, sizeof(char));
  fseek(strings, i, SEEK_SET);
  fread(sn, numToMove, 1, strings);
  fseek(strings, i + s, SEEK_SET);
  fwrite(sn, numToMove, 1, strings);
  fflush(strings);
  fseek(strings, i, SEEK_SET);
  fwrite(saved, s, 1, strings);
  fflush(strings);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  lea    -0x1(%rsi),%r14d
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  movslq %edx,%rbx
  imul   %ebx,%r14d
  mov    %rbx,%r12
  sub    $0x18,%rsp
  mov    %r14d,0xc(%rsp)
  movslq %r14d,%r14
  mov    %rdi,(%rsp)
  test   %r14,%r14
  jns    L13
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r14,%rax
  add    %r12d,%ebp
  sub    %rbx,%rax
  js     L33
  mov    %rax,%r14
L13:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   *%r13
  test   %eax,%eax
  jg     L4
L11:
  add    %rbx,%r14
L33:
  mov    0xc(%rsp),%eax
  add    %r12d,%eax
  cltq
  cmp    %r14,%rax
  je     L14
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    (%rsp),%rdi
  mov    %r14,%rsi
  mov    %rax,%r13
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    (%rsp),%rcx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x1,%edx
  call   <fread@plt>
  mov    D18(%rip),%rax
  lea    (%r14,%rbx,1),%rsi
  mov    (%rsp),%rbx
  mov    (%rax),%edx
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %rbx,%rcx
  mov    %ebp,%esi
  mov    $0x1,%edx
  mov    %r13,%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fflush@plt>
  mov    D18(%rip),%rax
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r15,%rdi
  mov    %rbx,%rcx
  mov    %r12d,%esi
  mov    $0x1,%edx
  call   <fwrite@plt>
  add    $0x18,%rsp
  mov    %rbx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <fflush@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void insert(FILE *strings, int loc, int s, char *saved, int (*cmp)(const long, const char *)) {
  long i = (loc - 1) * s;
  int numToMove = 0;
  while (i >= 0 && cmp(i, saved) > 0) {
    i -= s;
    numToMove += s;
  }
  i += s;
  if (i == loc * s) {
    return;
  }
  char *sn = (char *)calloc(numToMove, sizeof(char));
  fseek(strings, i, SEEK_SET);
  fread(sn, numToMove, 1, strings);
  fseek(strings, i + s, SEEK_SET);
  fwrite(sn, numToMove, 1, strings);
  fflush(strings);
  fseek(strings, i, SEEK_SET);
  fwrite(saved, s, 1, strings);
  fflush(strings);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insert>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  lea    -0x1(%rsi),%r14d
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  movslq %edx,%rbx
  imul   %ebx,%r14d
  mov    %rbx,%r12
  sub    $0x18,%rsp
  mov    %r14d,0xc(%rsp)
  movslq %r14d,%r14
  mov    %rdi,(%rsp)
  test   %r14,%r14
  jns    L49
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r14,%rax
  add    %r12d,%ebp
  sub    %rbx,%rax
  js     L36
  mov    %rax,%r14
L49:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   *%r13
  test   %eax,%eax
  jg     L13
L33:
  add    %rbx,%r14
L36:
  mov    0xc(%rsp),%eax
  add    %r12d,%eax
  cltq
  cmp    %r14,%rax
  je     L40
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    (%rsp),%rdi
  mov    %r14,%rsi
  mov    %rax,%r13
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    (%rsp),%rcx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x1,%edx
  call   <fread@plt>
  mov    D21(%rip),%rax
  lea    (%r14,%rbx,1),%rsi
  mov    (%rsp),%rbx
  mov    (%rax),%edx
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %rbx,%rcx
  mov    %ebp,%esi
  mov    $0x1,%edx
  mov    %r13,%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fflush@plt>
  mov    D21(%rip),%rax
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r15,%rdi
  mov    %rbx,%rcx
  mov    %r12d,%esi
  mov    $0x1,%edx
  call   <fwrite@plt>
  add    $0x18,%rsp
  mov    %rbx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <fflush@plt>
  nopw   0x0(%rax,%rax,1)
L40:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void insert(FILE *strings, int loc, int s, char *saved, int (*cmp)(const long, const char *)) {
  long i = (loc - 1) * s;
  int numToMove = 0;
  while (i >= 0 && cmp(i, saved) > 0) {
    i -= s;
    numToMove += s;
  }
  i += s;
  if (i == loc * s) {
    return;
  }
  char *sn = (char *)calloc(numToMove, sizeof(char));
  fseek(strings, i, SEEK_SET);
  fread(sn, numToMove, 1, strings);
  fseek(strings, i + s, SEEK_SET);
  fwrite(sn, numToMove, 1, strings);
  fflush(strings);
  fseek(strings, i, SEEK_SET);
  fwrite(saved, s, 1, strings);
  fflush(strings);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lvterm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <lvfactor@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L27
  mov    -0x10(%rbp),%rax
  jmp    L76
L30:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x2f,%eax
  je     L12
  cmp    $0x2f,%eax
  jg     L150
  cmp    $0x25,%eax
  je     L71
  cmp    $0x2a,%eax
  jne    L150
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <lvfactor@plt>
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L41
L12:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <lvfactor@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L128
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rax,-0x10(%rbp)
  jmp    L41
L128:
  mov    -0x28(%rbp),%rax
  movl   $0xa,(%rax)
  jmp    L41
L71:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <lvfactor@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L104
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  jmp    L41
L104:
  mov    -0x28(%rbp),%rax
  movl   $0xa,(%rax)
  jmp    L41
L150:
  mov    -0x10(%rbp),%rax
  jmp    L76
L41:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L27
  mov    -0x10(%rbp),%rax
  jmp    L76
L27:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    -0x10(%rbp),%rax
L76:
  leave
  ret
```

assistant: ```c
long int lvterm(const char **ps, int level, int *perrval) {
  long int value;
  long int divisor;
  *perrval = 0;
  value = lvfactor(ps, level, perrval);
  if (*perrval != 0)
    return (value);
  while (**ps) {
    switch (**ps) {
    case '*':
      (*ps)++;
      value *= lvfactor(ps, level, perrval);
      break;
    case '/':
      (*ps)++;
      divisor = lvfactor(ps, level, perrval);
      if (divisor != 0l)
        value /= divisor;
      else
        *perrval = 10;
      break;
    case '%':
      (*ps)++;
      divisor = lvfactor(ps, level, perrval);
      if (divisor != 0l)
        value %= divisor;
      else
        *perrval = 10;
      break;
    default:
      return (value);
    }
    if (*perrval != 0)
      return (value);
  }
  return (value);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lvterm>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %rdx,%rbp
  movl   $0x0,(%rdx)
  call   <lvfactor@plt>
  mov    %rax,%r12
  cmpl   $0x0,0x0(%rbp)
  je     L81
  jmp    L88
L24:
  add    $0x1,%rsi
  mov    %rsi,(%rbx)
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <lvfactor@plt>
  imul   %rax,%r12
L18:
  cmpl   $0x0,0x0(%rbp)
  jne    L88
L81:
  mov    (%rbx),%rsi
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L88
  cmp    $0x2a,%cl
  je     L24
  cmp    $0x2f,%cl
  je     L49
  cmp    $0x25,%cl
  je     L27
L88:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  add    $0x1,%rsi
  mov    %rsi,(%rbx)
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <lvfactor@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L50
  mov    %r12,%rax
  cqto
  idiv   %rcx
  mov    %rax,%r12
  jmp    L18
L27:
  add    $0x1,%rsi
  mov    %rsi,(%rbx)
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <lvfactor@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L50
  mov    %r12,%rax
  cqto
  idiv   %rdi
  mov    %rdx,%r12
  jmp    L18
L50:
  movl   $0xa,0x0(%rbp)
  jmp    L88
```

assistant: ```c
long int lvterm(const char **ps, int level, int *perrval) {
  long int value;
  long int divisor;
  *perrval = 0;
  value = lvfactor(ps, level, perrval);
  if (*perrval != 0)
    return (value);
  while (**ps) {
    switch (**ps) {
    case '*':
      (*ps)++;
      value *= lvfactor(ps, level, perrval);
      break;
    case '/':
      (*ps)++;
      divisor = lvfactor(ps, level, perrval);
      if (divisor != 0l)
        value /= divisor;
      else
        *perrval = 10;
      break;
    case '%':
      (*ps)++;
      divisor = lvfactor(ps, level, perrval);
      if (divisor != 0l)
        value %= divisor;
      else
        *perrval = 10;
      break;
    default:
      return (value);
    }
    if (*perrval != 0)
      return (value);
  }
  return (value);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lvterm>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  movl   $0x0,(%rdx)
  call   <lvfactor@plt>
  mov    (%rbx),%edx
  mov    %rax,%r12
  test   %edx,%edx
  jne    L93
L65:
  mov    0x0(%rbp),%rsi
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L93
  cmp    $0x2a,%cl
  je     L12
  cmp    $0x2f,%cl
  je     L13
  cmp    $0x25,%cl
  je     L42
L93:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  add    $0x1,%rsi
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  mov    %rsi,0x0(%rbp)
  mov    %r13d,%esi
  call   <lvfactor@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L15
  mov    %r12,%rax
  cqto
  idiv   %rdi
  mov    %rdx,%r12
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %rsi,0x0(%rbp)
  mov    %r13d,%esi
  call   <lvfactor@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  jne    L45
L15:
  movl   $0xa,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %rsi,0x0(%rbp)
  mov    %r13d,%esi
  call   <lvfactor@plt>
  imul   %rax,%r12
L66:
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L65
  jmp    L93
  nopl   0x0(%rax)
L45:
  mov    %r12,%rax
  cqto
  idiv   %rcx
  mov    %rax,%r12
  jmp    L66
```

assistant: ```c
long int lvterm(const char **ps, int level, int *perrval) {
  long int value;
  long int divisor;
  *perrval = 0;
  value = lvfactor(ps, level, perrval);
  if (*perrval != 0)
    return (value);
  while (**ps) {
    switch (**ps) {
    case '*':
      (*ps)++;
      value *= lvfactor(ps, level, perrval);
      break;
    case '/':
      (*ps)++;
      divisor = lvfactor(ps, level, perrval);
      if (divisor != 0l)
        value /= divisor;
      else
        *perrval = 10;
      break;
    case '%':
      (*ps)++;
      divisor = lvfactor(ps, level, perrval);
      if (divisor != 0l)
        value %= divisor;
      else
        *perrval = 10;
      break;
    default:
      return (value);
    }
    if (*perrval != 0)
      return (value);
  }
  return (value);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lvterm>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  movl   $0x0,(%rdx)
  call   <lvfactor@plt>
  mov    (%rbx),%edx
  mov    %rax,%r12
  test   %edx,%edx
  jne    L40
L9:
  mov    0x0(%rbp),%rsi
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L40
  cmp    $0x2a,%cl
  je     L35
  cmp    $0x2f,%cl
  je     L88
  cmp    $0x25,%cl
  je     L25
L40:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rsi
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  mov    %rsi,0x0(%rbp)
  mov    %r13d,%esi
  call   <lvfactor@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L90
  mov    %r12,%rax
  cqto
  idiv   %rdi
  mov    %rdx,%r12
  jmp    L91
  nopl   0x0(%rax,%rax,1)
L88:
  add    $0x1,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %rsi,0x0(%rbp)
  mov    %r13d,%esi
  call   <lvfactor@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  jne    L49
L90:
  movl   $0xa,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %rsi,0x0(%rbp)
  mov    %r13d,%esi
  call   <lvfactor@plt>
  imul   %rax,%r12
L91:
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L9
  jmp    L40
  nopl   0x0(%rax)
L49:
  mov    %r12,%rax
  cqto
  idiv   %rcx
  mov    %rax,%r12
  jmp    L91
```

assistant: ```c
long int lvterm(const char **ps, int level, int *perrval) {
  long int value;
  long int divisor;
  *perrval = 0;
  value = lvfactor(ps, level, perrval);
  if (*perrval != 0)
    return (value);
  while (**ps) {
    switch (**ps) {
    case '*':
      (*ps)++;
      value *= lvfactor(ps, level, perrval);
      break;
    case '/':
      (*ps)++;
      divisor = lvfactor(ps, level, perrval);
      if (divisor != 0l)
        value /= divisor;
      else
        *perrval = 10;
      break;
    case '%':
      (*ps)++;
      divisor = lvfactor(ps, level, perrval);
      if (divisor != 0l)
        value %= divisor;
      else
        *perrval = 10;
      break;
    default:
      return (value);
    }
    if (*perrval != 0)
      return (value);
  }
  return (value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L24
L27:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
L24:
  mov    -0x24(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L12
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void strip_directory(char *inbuf, char *outbuf, int maxlen) {
  char *strippt;
  int cpylen;
  strippt = strrchr(inbuf, '/');
  if (strippt == NULL) {
    cpylen = strlen(inbuf);
    strippt = inbuf;
  } else {
    strippt++;
    cpylen = strlen(strippt);
  }
  if (cpylen > maxlen - 1)
    cpylen = maxlen - 1;
  strncpy(outbuf, strippt, cpylen);
  outbuf[cpylen] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strip_directory>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L6
  lea    0x1(%rax),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
L5:
  lea    -0x1(%r13),%eax
  cmp    %r13d,%ebx
  cmovge %eax,%ebx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L5
```

assistant: ```c
void strip_directory(char *inbuf, char *outbuf, int maxlen) {
  char *strippt;
  int cpylen;
  strippt = strrchr(inbuf, '/');
  if (strippt == NULL) {
    cpylen = strlen(inbuf);
    strippt = inbuf;
  } else {
    strippt++;
    cpylen = strlen(strippt);
  }
  if (cpylen > maxlen - 1)
    cpylen = maxlen - 1;
  strncpy(outbuf, strippt, cpylen);
  outbuf[cpylen] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strip_directory>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  lea    0x1(%rax),%rbp
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebx
  lea    -0x1(%r13),%eax
  cmp    %r13d,%ebx
  cmovge %eax,%ebx
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strip_directory(char *inbuf, char *outbuf, int maxlen) {
  char *strippt;
  int cpylen;
  strippt = strrchr(inbuf, '/');
  if (strippt == NULL) {
    cpylen = strlen(inbuf);
    strippt = inbuf;
  } else {
    strippt++;
    cpylen = strlen(strippt);
  }
  if (cpylen > maxlen - 1)
    cpylen = maxlen - 1;
  strncpy(outbuf, strippt, cpylen);
  outbuf[cpylen] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strip_directory>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L3
  lea    0x1(%rax),%rbp
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebx
  lea    -0x1(%r13),%eax
  cmp    %r13d,%ebx
  cmovge %eax,%ebx
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strip_directory(char *inbuf, char *outbuf, int maxlen) {
  char *strippt;
  int cpylen;
  strippt = strrchr(inbuf, '/');
  if (strippt == NULL) {
    cpylen = strlen(inbuf);
    strippt = inbuf;
  } else {
    strippt++;
    cpylen = strlen(strippt);
  }
  if (cpylen > maxlen - 1)
    cpylen = maxlen - 1;
  strncpy(outbuf, strippt, cpylen);
  outbuf[cpylen] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <create_bitstream@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_bitstream@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string

tool: D1: babilon_amphi.jpg

assistant: ```c
int main(void) {
  struct bitstream *bs = create_bitstream("babilon_amphi.jpg");
  uint32_t read = 0;
  free_bitstream(bs);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <create_bitstream@plt>
  mov    %rax,%rdi
  call   <free_bitstream@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string

tool: D7: babilon_amphi.jpg

assistant: ```c
int main(void) {
  struct bitstream *bs = create_bitstream("babilon_amphi.jpg");
  uint32_t read = 0;
  free_bitstream(bs);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <create_bitstream@plt>
  mov    %rax,%rdi
  call   <free_bitstream@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: babilon_amphi.jpg

assistant: ```c
int main(void) {
  struct bitstream *bs = create_bitstream("babilon_amphi.jpg");
  uint32_t read = 0;
  free_bitstream(bs);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <create_bitstream@plt>
  mov    %rax,%rdi
  call   <free_bitstream@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: babilon_amphi.jpg

assistant: ```c
int main(void) {
  struct bitstream *bs = create_bitstream("babilon_amphi.jpg");
  uint32_t read = 0;
  free_bitstream(bs);
  return 0;
}
```