ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_array_i32>:
  endbr64
  test   %edx,%edx
  je     L12
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  sub    $0x1,%ebx
  jne    L24
  lea    D2(%rip),%r12
  nopl   0x0(%rax)
L44:
  mov    %ebx,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    (%r14,%rax,4),%edx
  xor    %eax,%eax
  call   <fprintf@plt>
L7:
  cmp    %ebx,%r13d
  ja     L44
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  cmp    %ebx,%edx
  mov    %rsi,%r15
  lea    D2(%rip),%r12
  cmovbe %edx,%ebx
  mov    %ebx,0xc(%rsp)
  xor    %ebx,%ebx
  nopl   (%rax)
L27:
  mov    (%r15),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%r15
  call   <fprintf@plt>
  mov    %rbp,%rsi
  mov    $0x2c,%edi
  call   <fputc@plt>
  cmp    0xc(%rsp),%ebx
  jb     L27
  jmp    L7
  nopl   0x0(%rax)
L12:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: %d

assistant: ```c
void write_array_i32(FILE *f, const int *x, const unsigned int len) {
  unsigned int i;
  for (i = 0; i < len; i++) {
    fprintf(f, "%d", x[i]);
    if (i < len - 1) {
      fprintf(f, ",");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vectorSubtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <allocateDoubleVector@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L7:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *vectorSubtract(double *a, double *b, int n) {
  int i;
  double *c;
  c = allocateDoubleVector(n);
  for (i = 0; i < n; i++)
    c[i] = a[i] - b[i];
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vectorSubtract>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %edx,%edi
  call   <allocateDoubleVector@plt>
  test   %ebx,%ebx
  jle    L10
  mov    %ebx,%edx
  mov    $0x0,%ecx
L4:
  movsd  0x0(%rbp,%rcx,8),%xmm0
  subsd  (%r12,%rcx,8),%xmm0
  movsd  %xmm0,(%rax,%rcx,8)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L4
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *vectorSubtract(double *a, double *b, int n) {
  int i;
  double *c;
  c = allocateDoubleVector(n);
  for (i = 0; i < n; i++)
    c[i] = a[i] - b[i];
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vectorSubtract>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %edx,%ebx
  call   <allocateDoubleVector@plt>
  test   %ebx,%ebx
  jle    L2
  movslq %ebx,%rdx
  xor    %ecx,%ecx
L18:
  movsd  0x0(%rbp,%rcx,8),%xmm0
  subsd  (%r12,%rcx,8),%xmm0
  movsd  %xmm0,(%rax,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L18
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *vectorSubtract(double *a, double *b, int n) {
  int i;
  double *c;
  c = allocateDoubleVector(n);
  for (i = 0; i < n; i++)
    c[i] = a[i] - b[i];
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vectorSubtract>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,%edi
  call   <allocateDoubleVector@plt>
  mov    %rax,%r8
  test   %r12d,%r12d
  jle    L31
  lea    0x8(%rbp),%rax
  cmp    %rax,%r8
  lea    0x8(%rbx),%rax
  setne  %dl
  cmp    %rax,%r8
  setne  %al
  test   %al,%dl
  je     L12
  lea    -0x1(%r12),%eax
  cmp    $0x1,%eax
  jbe    L12
  mov    %r12d,%edx
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  xchg   %ax,%ax
L29:
  movupd (%rbx,%rax,1),%xmm0
  movupd 0x0(%rbp,%rax,1),%xmm1
  subpd  %xmm1,%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L29
  mov    %r12d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r12d
  je     L31
  movsd  (%rbx,%rax,8),%xmm0
  subsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
L31:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L36:
  movsd  (%rbx,%rax,8),%xmm0
  subsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L36
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *vectorSubtract(double *a, double *b, int n) {
  int i;
  double *c;
  c = allocateDoubleVector(n);
  for (i = 0; i < n; i++)
    c[i] = a[i] - b[i];
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fibonachi@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
type: string
name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D26: Enter number to count up to in fibonachi:

tool: D21: %d

tool: D9: fibonachi %d times:


assistant: ```c
int main() {
  int g = 0;
  printf("Enter number to count up to in fibonachi:\n");
  scanf("%d", &g);
  printf("fibonachi %d times:\n", g);
  fibonachi(g);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <fibonachi@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string

tool: D19: Enter number to count up to in fibonachi:

tool: D17: %d

tool: D12: fibonachi %d times:


assistant: ```c
int main() {
  int g = 0;
  printf("Enter number to count up to in fibonachi:\n");
  scanf("%d", &g);
  printf("fibonachi %d times:\n", g);
  fibonachi(g);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <fibonachi@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string
name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D22: Enter number to count up to in fibonachi:

tool: D19: %d

tool: D0: fibonachi %d times:


assistant: ```c
int main() {
  int g = 0;
  printf("Enter number to count up to in fibonachi:\n");
  scanf("%d", &g);
  printf("fibonachi %d times:\n", g);
  fibonachi(g);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <fibonachi@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_guessed: string
name: retrieve_data
arguments: data_label: D11
type_guessed: string
name: retrieve_data
arguments: data_label: D29
type_guessed: string

tool: D18: Enter number to count up to in fibonachi:

tool: D11: %d

tool: D29: fibonachi %d times:


assistant: ```c
int main() {
  int g = 0;
  printf("Enter number to count up to in fibonachi:\n");
  scanf("%d", &g);
  printf("fibonachi %d times:\n", g);
  fibonachi(g);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<copys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %rbx,%r12
  test   %r12,%r12
  jne    L8
  mov    $0x0,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L8:
  nop
L1:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: Cannot allocate memory

assistant: ```c
char *copys(char *s) {
  register char *t, *t0;
  if ((t0 = t = calloc(strlen(s) + 1, sizeof(*t))) == NULL)
    fatal("Cannot allocate memory", (char *)NULL);
  while (*t++ = *s++)
    ;
  return (t0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copys>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L6:
  mov    $0x0,%eax
L23:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L23
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0x0,%esi
  lea    D7(%rip),%rdi
  call   <fatal@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: Cannot allocate memory

assistant: ```c
char *copys(char *s) {
  register char *t, *t0;
  if ((t0 = t = calloc(strlen(s) + 1, sizeof(*t))) == NULL)
    fatal("Cannot allocate memory", (char *)NULL);
  while (*t++ = *s++)
    ;
  return (t0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copys>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L14:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L12
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  call   <fatal@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: Cannot allocate memory

assistant: ```c
char *copys(char *s) {
  register char *t, *t0;
  if ((t0 = t = calloc(strlen(s) + 1, sizeof(*t))) == NULL)
    fatal("Cannot allocate memory", (char *)NULL);
  while (*t++ = *s++)
    ;
  return (t0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copys>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L20:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  call   <fatal@plt>
  jmp    L20
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: Cannot allocate memory

assistant: ```c
char *copys(char *s) {
  register char *t, *t0;
  if ((t0 = t = calloc(strlen(s) + 1, sizeof(*t))) == NULL)
    fatal("Cannot allocate memory", (char *)NULL);
  while (*t++ = *s++)
    ;
  return (t0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printArr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: %d 

assistant: ```c
void printArr(int arr[], int m) {
  int i;
  for (i = 0; i < m; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printArr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D6(%rip),%rbp
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L13
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: %d 

assistant: ```c
void printArr(int arr[], int m) {
  int i;
  for (i = 0; i < m; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printArr>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: %d 

assistant: ```c
void printArr(int arr[], int m) {
  int i;
  for (i = 0; i < m; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printArr>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
void printArr(int arr[], int m) {
  int i;
  for (i = 0; i < m; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lwan_append_str_to_strbuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L7
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lwan_strbuf_append_strz@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void lwan_append_str_to_strbuf(struct lwan_strbuf *buf, void *ptr) {
  const char *str = *(char **)ptr;
  if (__builtin_expect((!!(str)), (1)))
    lwan_strbuf_append_strz(buf, str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lwan_append_str_to_strbuf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rsi),%rbp
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  mov    $0x1,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L1
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <lwan_strbuf_append_strz@plt>
  jmp    L13
```

assistant: ```c
void lwan_append_str_to_strbuf(struct lwan_strbuf *buf, void *ptr) {
  const char *str = *(char **)ptr;
  if (__builtin_expect((!!(str)), (1)))
    lwan_strbuf_append_strz(buf, str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lwan_append_str_to_strbuf>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  mov    (%rsi),%r12
  mov    $0x1,%esi
  test   %r12,%r12
  setne  %dil
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <lwan_strbuf_append_strz@plt>
```

assistant: ```c
void lwan_append_str_to_strbuf(struct lwan_strbuf *buf, void *ptr) {
  const char *str = *(char **)ptr;
  if (__builtin_expect((!!(str)), (1)))
    lwan_strbuf_append_strz(buf, str);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lwan_append_str_to_strbuf>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  mov    (%rsi),%r12
  mov    $0x1,%esi
  test   %r12,%r12
  setne  %dil
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L2
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <lwan_strbuf_append_strz@plt>
```

assistant: ```c
void lwan_append_str_to_strbuf(struct lwan_strbuf *buf, void *ptr) {
  const char *str = *(char **)ptr;
  if (__builtin_expect((!!(str)), (1)))
    lwan_strbuf_append_strz(buf, str);
}
```
user: What is the c source code of the assembly code below:

```asm
<primer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L1
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L39
  mov    $0x0,%eax
  jmp    L25
L39:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L18
  mov    $0x1,%eax
L25:
  leave
  ret
```

assistant: ```c
int primer(long long j) {
  int i, temp;
  temp = (int)sqrt(j) + 1;
  for (i = 2; i <= temp; i++)
    if (j % i == 0)
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<primer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <sqrt@plt>
  test   %eax,%eax
  jle    L2
  mov    %eax,%esi
  test   $0x1,%bl
  je     L36
  mov    $0x3,%ecx
L29:
  lea    -0x1(%rcx),%eax
  cmp    %eax,%esi
  jl     L8
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  test   %rdx,%rdx
  jne    L29
  mov    $0x0,%eax
  jmp    L16
L8:
  mov    $0x1,%eax
L16:
  pop    %rbx
  ret
L2:
  mov    $0x1,%eax
  jmp    L16
L36:
  mov    $0x0,%eax
  jmp    L16
```

assistant: ```c
int primer(long long j) {
  int i, temp;
  temp = (int)sqrt(j) + 1;
  for (i = 2; i <= temp; i++)
    if (j % i == 0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<primer>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <sqrt@plt>
  test   %eax,%eax
  jle    L28
  test   $0x1,%r12b
  je     L13
  mov    %eax,%esi
  mov    $0x3,%ecx
  jmp    L2
  nopl   0x0(%rax)
L18:
  mov    %r12,%rax
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  test   %rdx,%rdx
  je     L13
L2:
  lea    -0x1(%rcx),%eax
  cmp    %eax,%esi
  jge    L18
L28:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  pop    %r12
  ret
```

assistant: ```c
int primer(long long j) {
  int i, temp;
  temp = (int)sqrt(j) + 1;
  for (i = 2; i <= temp; i++)
    if (j % i == 0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<primer>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <sqrt@plt>
  test   %eax,%eax
  jle    L44
  test   $0x1,%r12b
  je     L24
  mov    %eax,%esi
  mov    $0x3,%ecx
  jmp    L12
  nopl   0x0(%rax)
L26:
  mov    %r12,%rax
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  test   %rdx,%rdx
  je     L24
L12:
  lea    -0x1(%rcx),%eax
  cmp    %eax,%esi
  jge    L26
L44:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  pop    %r12
  ret
```

assistant: ```c
int primer(long long j) {
  int i, temp;
  temp = (int)sqrt(j) + 1;
  for (i = 2; i <= temp; i++)
    if (j % i == 0)
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MakeMark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D31
type_infered: string
name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D31: w

tool: D6: MARK

tool: D20: mark: can't open file


tool: D1: %s


assistant: ```c
void MakeMark(char *sMark) {
  FILE *hFilename;
  hFilename = fopen("MARK", "w");
  if (hFilename == NULL) {
    printf("mark: can't open file\n");
  }
  fprintf(hFilename, "%s\n", sMark);
}
```