ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L49
  lea    0x14(%rsp),%rcx
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %eax,%esi
  add    $0x4,%rcx
  shr    $0x1f,%esi
  lea    (%rax,%rsi,1),%edx
  add    %esi,%eax
  and    $0x1,%edx
  sub    %esi,%edx
  mov    %edx,-0x4(%rcx)
  sar    %eax
  jne    L32
L49:
  movslq 0x8(%rsp),%rax
  cmp    $0x20,%eax
  jbe    L39
  mov    $0x30,%edi
  call   <putchar@plt>
L37:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L39:
  mov    0x10(%rsp,%rax,4),%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L37
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string

tool: D5: %d%d

tool: D14: %d


assistant: ```c
int main() {
  int a, b, remainder, quotient;
  int binaryNumber[8], i = 1, j;
  scanf("%d%d", &a, &b);
  quotient = b;
  while (quotient != 0) {
    binaryNumber[i++] = quotient % 2;
    quotient = quotient / 2;
  }
  if (a > sizeof(binaryNumber)) {
    printf("0");
  } else
    printf("%d\n", binaryNumber[a]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  je     L5
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,0x14(%rsp)
  mov    %ecx,%eax
  add    %edx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L5
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x18(%rsp)
  add    %ecx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L5
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x1c(%rsp)
  add    %ecx,%eax
  sar    %eax
  je     L5
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  mov    %edx,0x20(%rsp)
  test   %eax,%eax
  je     L5
  cltd
  idiv   %ecx
  mov    %edx,0x24(%rsp)
  test   %eax,%eax
  je     L5
  cltd
  idiv   %ecx
  mov    %edx,0x28(%rsp)
  test   %eax,%eax
  je     L5
  cltd
  idiv   %ecx
  mov    %edx,0x2c(%rsp)
L5:
  movslq 0x8(%rsp),%rax
  cmp    $0x20,%eax
  jbe    L67
  mov    $0x30,%edi
  call   <putchar@plt>
L87:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L67:
  mov    0x10(%rsp,%rax,4),%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L87
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string

tool: D6: %d%d

tool: D18: %d


assistant: ```c
int main() {
  int a, b, remainder, quotient;
  int binaryNumber[8], i = 1, j;
  scanf("%d%d", &a, &b);
  quotient = b;
  while (quotient != 0) {
    binaryNumber[i++] = quotient % 2;
    quotient = quotient / 2;
  }
  if (a > sizeof(binaryNumber)) {
    printf("0");
  } else
    printf("%d\n", binaryNumber[a]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  leave
  ret
```

assistant: ```c
char *readInt(char *buf, uint32_t *val) {
  memcpy(val, buf, sizeof(uint32_t));
  *val = ntohl(*val);
  return buf + sizeof(uint32_t);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readInt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x4,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x0(%rbp),%edi
  call   <ntohl@plt>
  mov    %eax,0x0(%rbp)
  lea    0x4(%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *readInt(char *buf, uint32_t *val) {
  memcpy(val, buf, sizeof(uint32_t));
  *val = ntohl(*val);
  return buf + sizeof(uint32_t);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readInt>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x4,%edx
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memcpy@plt>
  mov    0x0(%rbp),%edi
  call   <ntohl@plt>
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  lea    0x4(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *readInt(char *buf, uint32_t *val) {
  memcpy(val, buf, sizeof(uint32_t));
  *val = ntohl(*val);
  return buf + sizeof(uint32_t);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readInt>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x4,%edx
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memcpy@plt>
  mov    0x0(%rbp),%edi
  call   <ntohl@plt>
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  lea    0x4(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *readInt(char *buf, uint32_t *val) {
  memcpy(val, buf, sizeof(uint32_t));
  *val = ntohl(*val);
  return buf + sizeof(uint32_t);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jsonp_isnint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L15
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L2
L15:
  addq   $0x1,-0x18(%rbp)
L2:
  movq   $0x0,-0x8(%rbp)
  jmp    L36
L73:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L88
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L16
L88:
  mov    $0x0,%eax
  jmp    L74
L16:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L58
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L73
L58:
  mov    $0x1,%eax
L74:
  pop    %rbp
  ret
```

assistant: ```c
int jsonp_isnint(const char *s, size_t n) {
  size_t i = 0;
  if (*s != '\0' && (*s == '-' || *s == '+'))
    ++s;
  for (i = 0; *s != 0 && i < n; ++i, ++s)
    if (*s < '0' || *s > '9')
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jsonp_isnint>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x1,%edx
  test   %al,%al
  je     L9
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%rdi
  movzbl (%rdi),%eax
  test   %rsi,%rsi
  je     L0
  test   %al,%al
  je     L0
  mov    $0x0,%edx
L4:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L77
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    %rdx,%rsi
  jbe    L56
  test   %al,%al
  jne    L4
L56:
  mov    $0x1,%edx
L9:
  mov    %edx,%eax
  ret
L0:
  mov    $0x1,%edx
  jmp    L9
L77:
  mov    $0x0,%edx
  jmp    L9
```

assistant: ```c
int jsonp_isnint(const char *s, size_t n) {
  size_t i = 0;
  if (*s != '\0' && (*s == '-' || *s == '+'))
    ++s;
  for (i = 0; *s != 0 && i < n; ++i, ++s)
    if (*s < '0' || *s > '9')
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jsonp_isnint>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x1,%r8d
  test   %al,%al
  je     L75
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  je     L11
L42:
  test   %rsi,%rsi
  je     L25
  test   %al,%al
  je     L25
  xor    %edx,%edx
  jmp    L12
  nopl   0x0(%rax)
L66:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    %rdx,%rsi
  jbe    L25
  test   %al,%al
  je     L25
L12:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L66
  xor    %r8d,%r8d
L75:
  mov    %r8d,%eax
  ret
  nop
L25:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  jmp    L42
```

assistant: ```c
int jsonp_isnint(const char *s, size_t n) {
  size_t i = 0;
  if (*s != '\0' && (*s == '-' || *s == '+'))
    ++s;
  for (i = 0; *s != 0 && i < n; ++i, ++s)
    if (*s < '0' || *s > '9')
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jsonp_isnint>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x1,%r8d
  test   %al,%al
  je     L18
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  je     L1
L2:
  test   %rsi,%rsi
  je     L50
  test   %al,%al
  je     L50
  xor    %edx,%edx
  jmp    L66
  nopl   0x0(%rax)
L74:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    %rdx,%rsi
  jbe    L50
  test   %al,%al
  je     L50
L66:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L74
  xor    %r8d,%r8d
L18:
  mov    %r8d,%eax
  ret
  nop
L50:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  jmp    L2
```

assistant: ```c
int jsonp_isnint(const char *s, size_t n) {
  size_t i = 0;
  if (*s != '\0' && (*s == '-' || *s == '+'))
    ++s;
  for (i = 0; *s != 0 && i < n; ++i, ++s)
    if (*s < '0' || *s > '9')
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L7
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %eax,-0xc(%rbp)
L7:
  mov    $0x0,%eax
  call   <init@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <setNum1@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <num1@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <release@plt>
  movq   $0x0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D8: number: %i


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr;
  int i;
  i = 0;
  if (argc > 1)
    i = atol(argv[1]);
  ptr = init();
  setNum1(ptr, 5);
  printf("number: %i\n", num1(ptr));
  sleep(i);
  release(ptr);
  ptr = NULL;
  sleep(i);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  cmp    $0x1,%edi
  jg     L12
L15:
  mov    $0x0,%eax
  call   <init@plt>
  mov    %rax,%rbx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <setNum1@plt>
  mov    %rbx,%rdi
  call   <num1@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <release@plt>
  mov    %ebp,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%ebp
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: number: %i


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr;
  int i;
  i = 0;
  if (argc > 1)
    i = atol(argv[1]);
  ptr = init();
  setNum1(ptr, 5);
  printf("number: %i\n", num1(ptr));
  sleep(i);
  release(ptr);
  ptr = NULL;
  sleep(i);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L4
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%r12d
L4:
  xor    %eax,%eax
  call   <init@plt>
  mov    $0x5,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <setNum1@plt>
  mov    %rbp,%rdi
  call   <num1@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <release@plt>
  mov    %r12d,%edi
  call   <sleep@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string

tool: D7: number: %i


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr;
  int i;
  i = 0;
  if (argc > 1)
    i = atol(argv[1]);
  ptr = init();
  setNum1(ptr, 5);
  printf("number: %i\n", num1(ptr));
  sleep(i);
  release(ptr);
  ptr = NULL;
  sleep(i);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L4
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%r12d
L4:
  xor    %eax,%eax
  call   <init@plt>
  mov    $0x5,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <setNum1@plt>
  mov    %rbp,%rdi
  call   <num1@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <release@plt>
  mov    %r12d,%edi
  call   <sleep@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: number: %i


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr;
  int i;
  i = 0;
  if (argc > 1)
    i = atol(argv[1]);
  ptr = init();
  setNum1(ptr, 5);
  printf("number: %i\n", num1(ptr));
  sleep(i);
  release(ptr);
  ptr = NULL;
  sleep(i);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<randomize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L35:
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L32:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L32
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L35
  nop
  nop
  leave
  ret
```

assistant: ```c
void randomize(int **map, int width, int height) {
  srand(time(NULL));
  for (int y = 0; y < height; y++) {
    for (int x = 0; x < width; x++) {
      map[y][x] = rand() % 2;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<randomize>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L40
  mov    %r12,%rbp
  lea    -0x1(%rbx),%eax
  lea    0x8(%r12,%rax,8),%r14
  lea    -0x1(%r13),%eax
  lea    0x4(,%rax,4),%r12
  jmp    L48
L47:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    0x0(%rbp),%rcx
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,(%rcx,%rbx,1)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L47
L5:
  add    $0x8,%rbp
  cmp    %r14,%rbp
  je     L40
L48:
  mov    $0x0,%ebx
  test   %r13d,%r13d
  jg     L47
  jmp    L5
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void randomize(int **map, int width, int height) {
  srand(time(NULL));
  for (int y = 0; y < height; y++) {
    for (int x = 0; x < width; x++) {
      map[y][x] = rand() % 2;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<randomize>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L13
  lea    -0x1(%rbx),%eax
  lea    0x8(%r14,%rax,8),%r12
  lea    -0x1(%rbp),%eax
  lea    0x4(,%rax,4),%rbx
  nopl   0x0(%rax,%rax,1)
L30:
  xor    %r13d,%r13d
  test   %ebp,%ebp
  jle    L11
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%r14),%rcx
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,(%rcx,%r13,1)
  add    $0x4,%r13
  cmp    %r13,%rbx
  jne    L1
L11:
  add    $0x8,%r14
  cmp    %r12,%r14
  jne    L30
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void randomize(int **map, int width, int height) {
  srand(time(NULL));
  for (int y = 0; y < height; y++) {
    for (int x = 0; x < width; x++) {
      map[y][x] = rand() % 2;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<randomize>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebp,%ebp
  jle    L27
  test   %ebx,%ebx
  jle    L27
  lea    -0x1(%rbp),%eax
  shl    $0x2,%rbx
  lea    0x8(%r13,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <rand@plt>
  mov    0x0(%r13),%rcx
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,(%rcx,%r12,1)
  add    $0x4,%r12
  cmp    %r12,%rbx
  jne    L3
  add    $0x8,%r13
  cmp    %rbp,%r13
  jne    L0
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void randomize(int **map, int width, int height) {
  srand(time(NULL));
  for (int y = 0; y < height; y++) {
    for (int x = 0; x < width; x++) {
      map[y][x] = rand() % 2;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <get_s@plt>
  mov    $0x0,%eax
  call   <get_s3@plt>
  mov    $0x0,%eax
  call   <get_i@plt>
  mov    $0x0,%eax
  call   <get_e@plt>
  mov    $0x0,%eax
  call   <get_s@plt>
  mov    $0x0,%eax
  call   <get_s3@plt>
  mov    $0x0,%eax
  call   <get_i@plt>
  mov    $0x0,%eax
  call   <get_e@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f2(void) {
  get_s();
  get_s3();
  get_i();
  get_e();
  (void)get_s();
  (void)get_s3();
  (void)get_i();
  (void)get_e();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_s@plt>
  mov    $0x0,%eax
  call   <get_s3@plt>
  mov    $0x0,%eax
  call   <get_i@plt>
  mov    $0x0,%eax
  call   <get_e@plt>
  mov    $0x0,%eax
  call   <get_s@plt>
  mov    $0x0,%eax
  call   <get_s3@plt>
  mov    $0x0,%eax
  call   <get_i@plt>
  mov    $0x0,%eax
  call   <get_e@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f2(void) {
  get_s();
  get_s3();
  get_i();
  get_e();
  (void)get_s();
  (void)get_s3();
  (void)get_i();
  (void)get_e();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_s@plt>
  xor    %eax,%eax
  call   <get_s3@plt>
  xor    %eax,%eax
  call   <get_i@plt>
  xor    %eax,%eax
  call   <get_e@plt>
  xor    %eax,%eax
  call   <get_s@plt>
  xor    %eax,%eax
  call   <get_s3@plt>
  xor    %eax,%eax
  call   <get_i@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <get_e@plt>
```

assistant: ```c
void f2(void) {
  get_s();
  get_s3();
  get_i();
  get_e();
  (void)get_s();
  (void)get_s3();
  (void)get_i();
  (void)get_e();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_s@plt>
  xor    %eax,%eax
  call   <get_s3@plt>
  xor    %eax,%eax
  call   <get_i@plt>
  xor    %eax,%eax
  call   <get_e@plt>
  xor    %eax,%eax
  call   <get_s@plt>
  xor    %eax,%eax
  call   <get_s3@plt>
  xor    %eax,%eax
  call   <get_i@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <get_e@plt>
```

assistant: ```c
void f2(void) {
  get_s();
  get_s3();
  get_i();
  get_e();
  (void)get_s();
  (void)get_s3();
  (void)get_i();
  (void)get_e();
}
```
user: What is the c source code of the assembly code below:

```asm
<creerNouveauPersonnage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <demanderNomNouveauPersonnage@plt>
  mov    $0x0,%eax
  call   <demanderRaceNouveauPersonnage@plt>
  mov    $0x0,%eax
  call   <demanderMetierNouveauPersonnage@plt>
  mov    $0x0,%eax
  call   <initialiserNouveauPersonnage@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void creerNouveauPersonnage(void) {
  demanderNomNouveauPersonnage();
  demanderRaceNouveauPersonnage();
  demanderMetierNouveauPersonnage();
  initialiserNouveauPersonnage();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<creerNouveauPersonnage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <demanderNomNouveauPersonnage@plt>
  mov    $0x0,%eax
  call   <demanderRaceNouveauPersonnage@plt>
  mov    $0x0,%eax
  call   <demanderMetierNouveauPersonnage@plt>
  mov    $0x0,%eax
  call   <initialiserNouveauPersonnage@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void creerNouveauPersonnage(void) {
  demanderNomNouveauPersonnage();
  demanderRaceNouveauPersonnage();
  demanderMetierNouveauPersonnage();
  initialiserNouveauPersonnage();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<creerNouveauPersonnage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <demanderNomNouveauPersonnage@plt>
  xor    %eax,%eax
  call   <demanderRaceNouveauPersonnage@plt>
  xor    %eax,%eax
  call   <demanderMetierNouveauPersonnage@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <initialiserNouveauPersonnage@plt>
```

assistant: ```c
void creerNouveauPersonnage(void) {
  demanderNomNouveauPersonnage();
  demanderRaceNouveauPersonnage();
  demanderMetierNouveauPersonnage();
  initialiserNouveauPersonnage();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<creerNouveauPersonnage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <demanderNomNouveauPersonnage@plt>
  xor    %eax,%eax
  call   <demanderRaceNouveauPersonnage@plt>
  xor    %eax,%eax
  call   <demanderMetierNouveauPersonnage@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <initialiserNouveauPersonnage@plt>
```

assistant: ```c
void creerNouveauPersonnage(void) {
  demanderNomNouveauPersonnage();
  demanderRaceNouveauPersonnage();
  demanderMetierNouveauPersonnage();
  initialiserNouveauPersonnage();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: foo

assistant: ```c
char *test_foo() {
  char *foo = "foo";
  return foo;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_foo>:
  endbr64
  lea    D5(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: foo

assistant: ```c
char *test_foo() {
  char *foo = "foo";
  return foo;
}
```