ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %edi,-0x7f4(%rbp)
  mov    %rsi,-0x800(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x7e4(%rbp)
  jmp    L19
L17:
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7e4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7e4(%rbp)
L19:
  mov    -0x7f0(%rbp),%eax
  cmp    %eax,-0x7e4(%rbp)
  jl     L17
  mov    -0x7f0(%rbp),%esi
  lea    -0x7e8(%rbp),%rcx
  lea    -0x7ec(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    -0x7ec(%rbp),%edx
  mov    -0x7e8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D28
type_guessed: string

tool: D4:  %d

tool: D28: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n;
  int nums[500];
  scanf(" %d", &n);
  int i;
  for (i = 0; i < n; i++) {
    scanf(" %d", &nums[i]);
  }
  int min, max;
  minmax(nums, n, &min, &max);
  printf("%d\n", min + max);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L17
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D21(%rip),%r12
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L8
L17:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  add    0x8(%rsp),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x7f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: string

tool: D21:  %d

tool: D3: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n;
  int nums[500];
  scanf(" %d", &n);
  int i;
  for (i = 0; i < n; i++) {
    scanf(" %d", &nums[i]);
  }
  int min, max;
  minmax(nums, n, &min, &max);
  printf("%d\n", min + max);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L16
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L0
L16:
  mov    %r13,%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  lea    D17(%rip),%rdi
  add    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: string

tool: D11:  %d

tool: D17: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n;
  int nums[500];
  scanf(" %d", &n);
  int i;
  for (i = 0; i < n; i++) {
    scanf(" %d", &nums[i]);
  }
  int min, max;
  minmax(nums, n, &min, &max);
  printf("%d\n", min + max);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L15
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L2
L15:
  mov    %r13,%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  lea    D8(%rip),%rdi
  add    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D11:  %d

tool: D8: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n;
  int nums[500];
  scanf(" %d", &n);
  int i;
  for (i = 0; i < n; i++) {
    scanf(" %d", &nums[i]);
  }
  int min, max;
  minmax(nums, n, &min, &max);
  printf("%d\n", min + max);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floats_squared_magnitude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float floats_squared_magnitude(const float *v, int len) {
  float acc = 0;
  for (int i = 0; i < len; i++)
    acc += v[i] * v[i];
  return acc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<floats_squared_magnitude>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm1,%xmm1
L19:
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L19
L20:
  movaps %xmm1,%xmm0
  ret
L4:
  pxor   %xmm1,%xmm1
  jmp    L20
```

assistant: ```c
float floats_squared_magnitude(const float *v, int len) {
  float acc = 0;
  for (int i = 0; i < len; i++)
    acc += v[i] * v[i];
  return acc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floats_squared_magnitude>:
  endbr64
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  pxor   %xmm1,%xmm1
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L3:
  movss  (%rdi),%xmm0
  add    $0x4,%rdi
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  cmp    %rax,%rdi
  jne    L3
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L4:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float floats_squared_magnitude(const float *v, int len) {
  float acc = 0;
  for (int i = 0; i < len; i++)
    acc += v[i] * v[i];
  return acc;
}
```
user: What is the c source code of the assembly code below?

```asm
<floats_squared_magnitude>:
  endbr64
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L58
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L52:
  movups (%rax),%xmm1
  add    $0x10,%rax
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L52
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L37
L44:
  movslq %eax,%rdx
  movss  (%rdi,%rdx,4),%xmm1
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %edx,%esi
  jle    L69
  movss  0x4(%rdi,%rcx,1),%xmm1
  add    $0x2,%eax
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %eax,%esi
  jle    L69
  movss  0x8(%rdi,%rcx,1),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L20:
  pxor   %xmm0,%xmm0
L69:
  ret
  nopl   (%rax)
L37:
  ret
L58:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L44
```

assistant: ```c
float floats_squared_magnitude(const float *v, int len) {
  float acc = 0;
  for (int i = 0; i < len; i++)
    acc += v[i] * v[i];
  return acc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<endsWith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L6
  mov    $0x0,%eax
  jmp    L58
L20:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L40
  mov    $0x0,%eax
  jmp    L58
L40:
  subl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x0,-0x10(%rbp)
  js     L51
  cmpl   $0x0,-0xc(%rbp)
  jns    L20
L51:
  mov    $0x1,%eax
L58:
  leave
  ret
```

assistant: ```c
int endsWith(char s1[], char s2[]) {
  int len1 = strlen(s1);
  int len2 = strlen(s2);
  int i = len1 - 1, j = len2 - 1;
  if (len1 < len2)
    return 0;
  for (; i >= 0 && j >= 0; i--, j--) {
    if (s1[i] != s2[j])
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<endsWith>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%ebp
  jl     L20
  test   %ebp,%ebp
  jle    L22
  test   %eax,%eax
  jle    L22
  lea    -0x2(%rbp),%edx
  movslq %edx,%rdx
  movslq %eax,%rcx
  movslq %ebp,%rsi
  sub    %rsi,%rcx
  add    %rcx,%r12
  sub    %ebp,%eax
L66:
  movzbl 0x1(%rdx,%r12,1),%edi
  cmp    %dil,0x1(%rbx,%rdx,1)
  jne    L17
  lea    (%rax,%rdx,1),%ecx
  not    %ecx
  shr    $0x1f,%ecx
  mov    %edx,%esi
  not    %esi
  shr    $0x1f,%esi
  sub    $0x1,%rdx
  test   %sil,%cl
  jne    L66
  mov    $0x1,%edx
  jmp    L20
L22:
  mov    $0x1,%edx
  jmp    L20
L17:
  mov    $0x0,%edx
L20:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int endsWith(char s1[], char s2[]) {
  int len1 = strlen(s1);
  int len2 = strlen(s2);
  int i = len1 - 1, j = len2 - 1;
  if (len1 < len2)
    return 0;
  for (; i >= 0 && j >= 0; i--, j--) {
    if (s1[i] != s2[j])
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<endsWith>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %eax,%r12d
  jl     L51
  test   %r12d,%r12d
  jle    L10
  test   %eax,%eax
  jle    L10
  movslq %eax,%rcx
  movslq %r12d,%rsi
  lea    -0x2(%r12),%edx
  sub    %r12d,%eax
  sub    %rsi,%rcx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rcx,1),%rdi
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L9:
  lea    (%rax,%rdx,1),%ecx
  mov    %edx,%esi
  sub    $0x1,%rdx
  not    %ecx
  not    %esi
  shr    $0x1f,%ecx
  shr    $0x1f,%esi
  test   %sil,%cl
  je     L10
L17:
  movzbl 0x1(%rdx,%rdi,1),%ecx
  cmp    %cl,0x1(%rbx,%rdx,1)
  je     L9
  xor    %r8d,%r8d
L51:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L10:
  mov    $0x1,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  ret
```

assistant: ```c
int endsWith(char s1[], char s2[]) {
  int len1 = strlen(s1);
  int len2 = strlen(s2);
  int i = len1 - 1, j = len2 - 1;
  if (len1 < len2)
    return 0;
  for (; i >= 0 && j >= 0; i--, j--) {
    if (s1[i] != s2[j])
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<endsWith>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %eax,%r12d
  jl     L36
  test   %r12d,%r12d
  jle    L58
  test   %eax,%eax
  jle    L58
  movslq %eax,%rcx
  movslq %r12d,%rsi
  lea    -0x2(%r12),%edx
  sub    %r12d,%eax
  sub    %rsi,%rcx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rcx,1),%rdi
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L57:
  lea    (%rax,%rdx,1),%ecx
  mov    %edx,%esi
  sub    $0x1,%rdx
  not    %ecx
  not    %esi
  shr    $0x1f,%ecx
  shr    $0x1f,%esi
  test   %sil,%cl
  je     L58
L1:
  movzbl 0x1(%rdx,%rdi,1),%ecx
  cmp    %cl,0x1(%rbx,%rdx,1)
  je     L57
  xor    %r8d,%r8d
L36:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L58:
  mov    $0x1,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  ret
```

assistant: ```c
int endsWith(char s1[], char s2[]) {
  int len1 = strlen(s1);
  int len2 = strlen(s2);
  int i = len1 - 1, j = len2 - 1;
  if (len1 < len2)
    return 0;
  for (; i >= 0 && j >= 0; i--, j--) {
    if (s1[i] != s2[j])
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MmdQ81753274112731_br_find_bin_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <MmdQ81753274112731_br_find_prefix@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L35
  cmpq   $0x0,-0x18(%rbp)
  je     L34
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L38
L34:
  mov    $0x0,%eax
  jmp    L38
L35:
  mov    -0x10(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <MmdQ81753274112731_br_build_path@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L38:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D5: bin

assistant: ```c
char *MmdQ81753274112731_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = MmdQ81753274112731_br_find_prefix((const char *)((void *)0));
  if (prefix == (char *)((void *)0)) {
    if (default_bin_dir != (const char *)((void *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((void *)0);
  }
  dir = MmdQ81753274112731_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MmdQ81753274112731_br_find_bin_dir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <MmdQ81753274112731_br_find_prefix@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <MmdQ81753274112731_br_build_path@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <free@plt>
L24:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    %rbp,%r12
  test   %rbp,%rbp
  je     L24
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: bin

assistant: ```c
char *MmdQ81753274112731_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = MmdQ81753274112731_br_find_prefix((const char *)((void *)0));
  if (prefix == (char *)((void *)0)) {
    if (default_bin_dir != (const char *)((void *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((void *)0);
  }
  dir = MmdQ81753274112731_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MmdQ81753274112731_br_find_bin_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <MmdQ81753274112731_br_find_prefix@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbp
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <MmdQ81753274112731_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  test   %r12,%r12
  je     L14
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L14:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: bin

assistant: ```c
char *MmdQ81753274112731_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = MmdQ81753274112731_br_find_prefix((const char *)((void *)0));
  if (prefix == (char *)((void *)0)) {
    if (default_bin_dir != (const char *)((void *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((void *)0);
  }
  dir = MmdQ81753274112731_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<MmdQ81753274112731_br_find_bin_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <MmdQ81753274112731_br_find_prefix@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rbp
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <MmdQ81753274112731_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  test   %r12,%r12
  je     L10
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L10:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: bin

assistant: ```c
char *MmdQ81753274112731_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = MmdQ81753274112731_br_find_prefix((const char *)((void *)0));
  if (prefix == (char *)((void *)0)) {
    if (default_bin_dir != (const char *)((void *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((void *)0);
  }
  dir = MmdQ81753274112731_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nmult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %r8d,-0x48(%rbp)
  mov    %r9d,-0x4c(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    $0x0,%ebx
  jmp    L8
L35:
  mov    $0x0,%r13d
  jmp    L5
L57:
  mov    %ebx,%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    %ebx,%eax
  imul   -0x4c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    %r13d,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    $0x0,%r12d
  jmp    L43
L54:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x24(%rbp),%eax
  add    %r12d,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    %r12d,%eax
  imul   -0x4c(%rbp),%eax
  add    %r13d,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x1,%r12d
L43:
  cmp    -0x28(%rbp),%r12d
  jl     L54
  add    $0x1,%r13d
L5:
  cmp    -0x4c(%rbp),%r13d
  jl     L57
  add    $0x1,%ebx
L8:
  cmp    -0x44(%rbp),%ebx
  jl     L35
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void nmult(double *A, double *B, double *C, int ra, int ca, int cb) {
  register int i, j, k;
  int u, v, t, rb;
  rb = ca;
#pragma omp parallel for private(i, j, k, v, u, t)
  for (i = 0; i < ra; ++i) {
    for (j = 0; j < cb; ++j) {
      v = i * rb;
      u = i * cb;
      t = j + u;
      C[t] = 0.;
      for (k = 0; k < rb; ++k) {
        C[t] += A[k + v] * B[j + k * cb];
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nmult>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x20(%rsp)
  mov    %rdx,-0x18(%rsp)
  mov    %ecx,-0x24(%rsp)
  test   %ecx,%ecx
  jle    L53
  mov    %rdi,%rbx
  mov    %r8d,%ebp
  mov    %r9d,%r11d
  movslq %r9d,%rdi
  shl    $0x3,%rdi
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    -0x1(%r8),%eax
  mov    %rax,-0x10(%rsp)
  lea    0x8(%rbx),%rax
  mov    %rax,-0x8(%rsp)
  jmp    L6
L60:
  movslq %r14d,%rax
  mov    -0x18(%rsp),%rsi
  lea    (%rsi,%rax,8),%r8
  mov    -0x20(%rsp),%r10
  movslq %r15d,%rax
  lea    (%rbx,%rax,8),%r12
  add    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rsi
  lea    (%rsi,%rax,8),%rsi
  mov    $0x0,%r9d
L2:
  mov    %r8,%rcx
  movq   $0x0,(%r8)
  test   %ebp,%ebp
  jle    L57
  mov    %r10,%rdx
  mov    %r12,%rax
L51:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  add    %rdi,%rdx
  cmp    %rsi,%rax
  jne    L51
L57:
  add    $0x1,%r9d
  add    $0x8,%r8
  add    $0x8,%r10
  cmp    %r9d,%r11d
  jne    L2
L65:
  add    $0x1,%r13d
  add    %r11d,%r14d
  add    %ebp,%r15d
  cmp    %r13d,-0x24(%rsp)
  je     L53
L6:
  test   %r11d,%r11d
  jg     L60
  jmp    L65
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void nmult(double *A, double *B, double *C, int ra, int ca, int cb) {
  register int i, j, k;
  int u, v, t, rb;
  rb = ca;
#pragma omp parallel for private(i, j, k, v, u, t)
  for (i = 0; i < ra; ++i) {
    for (j = 0; j < cb; ++j) {
      v = i * rb;
      u = i * cb;
      t = j + u;
      C[t] = 0.;
      for (k = 0; k < rb; ++k) {
        C[t] += A[k + v] * B[j + k * cb];
      }
    }
  }
}
```