ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SARMenuMessageBoxTotalLines>:
  endbr64
  test   %rdi,%rdi
  je     L220
  test   %esi,%esi
  jle    L220
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L252:
  test   %al,%al
  je     L43
  add    $0x1,%r8d
  cmp    $0xa,%al
  je     L132
  cmp    $0xd,%al
  jne    L142
  jmp    L132
  nopl   (%rax)
L78:
  add    $0x1,%rdi
L142:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L78
  cmp    $0x9,%al
  je     L78
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  test   %al,%al
  je     L43
L191:
  cmp    $0x20,%al
  je     L30
  jg     L127
  cmp    $0xa,%al
  je     L237
  cmp    $0xd,%al
  jne    L165
L237:
  movzbl (%rdi),%eax
  jmp    L252
  nopl   0x0(%rax,%rax,1)
L127:
  cmp    $0x3c,%al
  jne    L57
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  test   %al,%al
  jne    L28
  jmp    L88
  cs nopw 0x0(%rax,%rax,1)
L160:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L88
L28:
  cmp    $0x3e,%al
  jne    L160
L88:
  cmp    $0x1,%al
  sbb    $0xffffffffffffffff,%rdx
  mov    %rdx,%rdi
L116:
  cmp    %esi,%ecx
  jge    L42
L63:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L191
L43:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L165:
  cmp    $0x9,%al
  jne    L57
L30:
  add    $0x1,%ecx
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L255:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L255
  cmp    $0x9,%dl
  je     L255
  mov    %rdi,%r9
  mov    %rax,%rdi
  cmp    %esi,%ecx
  jl     L63
L42:
  test   %r9,%r9
  je     L237
  mov    %r9,%rdi
  jmp    L237
  nopl   (%rax)
L132:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  jmp    L252
  nopl   (%rax)
L57:
  add    $0x1,%ecx
  add    $0x1,%rdi
  jmp    L116
  nopl   0x0(%rax)
L220:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int SARMenuMessageBoxTotalLines(const char *buf_ptr, int visible_columns) {
  char c;
  int line_count = 0, characters_drawn;
  const char *s, *buf_stop;
  if ((buf_ptr == NULL) || (visible_columns < 1))
    return (line_count);
  while ((buf_ptr != NULL) ? (*buf_ptr != '\0') : 0) {
    s = buf_ptr;
    if ((((*s) == '\n') || ((*s) == '\r'))) {
      buf_ptr = s + 1;
      line_count++;
      continue;
    }
    while ((((*s) == ' ') || ((*s) == '\t')))
      s++;
    buf_stop = NULL;
    for (characters_drawn = 0; characters_drawn < visible_columns;) {
      c = *s;
      if (c == '\0') {
        buf_stop = s;
        break;
      } else if ((((c) == ' ') || ((c) == '\t'))) {
        buf_stop = s;
        characters_drawn++;
        while ((((*s) == ' ') || ((*s) == '\t')))
          s++;
      } else if ((((c) == '\n') || ((c) == '\r'))) {
        buf_stop = s;
        break;
      } else if (((c) == '<')) {
        s++;
        while ((*s != '\0') && !((*s) == '>'))
          s++;
        if (*s != '\0')
          s++;
      } else {
        characters_drawn++;
        s++;
      }
    }
    if (buf_stop == NULL)
      buf_stop = s;
    line_count++;
    buf_ptr = buf_stop;
  }
  return (line_count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SARMenuMessageBoxTotalLines>:
  endbr64
  test   %rdi,%rdi
  je     L64
  test   %esi,%esi
  jle    L64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L3:
  test   %al,%al
  je     L103
  add    $0x1,%r8d
  cmp    $0xa,%al
  je     L8
  cmp    $0xd,%al
  jne    L78
  jmp    L8
  nopl   (%rax)
L49:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L78:
  cmp    $0x20,%al
  je     L49
  cmp    $0x9,%al
  je     L49
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  test   %al,%al
  je     L103
L255:
  cmp    $0x20,%al
  je     L232
  jg     L240
  cmp    $0xa,%al
  je     L27
  cmp    $0xd,%al
  jne    L98
L27:
  movzbl (%rdi),%eax
  jmp    L3
  nopl   0x0(%rax)
L240:
  cmp    $0x3c,%al
  jne    L200
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  test   %al,%al
  jne    L130
  jmp    L63
  cs nopw 0x0(%rax,%rax,1)
L153:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L63
L130:
  cmp    $0x3e,%al
  jne    L153
L63:
  cmp    $0x1,%al
  mov    %rdx,%rdi
  sbb    $0xffffffffffffffff,%rdi
L289:
  cmp    %esi,%ecx
  jge    L283
L102:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L255
L103:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L98:
  cmp    $0x9,%al
  jne    L200
L232:
  add    $0x1,%ecx
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L162:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L162
  cmp    $0x9,%dl
  je     L162
  mov    %rdi,%r9
  mov    %rax,%rdi
  cmp    %esi,%ecx
  jl     L102
L283:
  test   %r9,%r9
  je     L27
  mov    %r9,%rdi
  jmp    L27
  nopl   (%rax)
L8:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  jmp    L3
  nopl   (%rax)
L200:
  add    $0x1,%ecx
  add    $0x1,%rdi
  jmp    L289
  nopl   0x0(%rax)
L64:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int SARMenuMessageBoxTotalLines(const char *buf_ptr, int visible_columns) {
  char c;
  int line_count = 0, characters_drawn;
  const char *s, *buf_stop;
  if ((buf_ptr == NULL) || (visible_columns < 1))
    return (line_count);
  while ((buf_ptr != NULL) ? (*buf_ptr != '\0') : 0) {
    s = buf_ptr;
    if ((((*s) == '\n') || ((*s) == '\r'))) {
      buf_ptr = s + 1;
      line_count++;
      continue;
    }
    while ((((*s) == ' ') || ((*s) == '\t')))
      s++;
    buf_stop = NULL;
    for (characters_drawn = 0; characters_drawn < visible_columns;) {
      c = *s;
      if (c == '\0') {
        buf_stop = s;
        break;
      } else if ((((c) == ' ') || ((c) == '\t'))) {
        buf_stop = s;
        characters_drawn++;
        while ((((*s) == ' ') || ((*s) == '\t')))
          s++;
      } else if ((((c) == '\n') || ((c) == '\r'))) {
        buf_stop = s;
        break;
      } else if (((c) == '<')) {
        s++;
        while ((*s != '\0') && !((*s) == '>'))
          s++;
        if (*s != '\0')
          s++;
      } else {
        characters_drawn++;
        s++;
      }
    }
    if (buf_stop == NULL)
      buf_stop = s;
    line_count++;
    buf_ptr = buf_stop;
  }
  return (line_count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    $0x16,%edx
  imul   %edx,%eax
  add    $0x1c,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L43
L19:
  movb   $0x0,-0xb(%rbp)
  jmp    L2
L31:
  movzbl -0x9(%rbp),%ecx
  movzbl -0xb(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xb(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl -0x9(%rbp),%edx
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0xb(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xb(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xb(%rbp)
  jb     L31
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L43:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L19
  movzbl -0x9(%rbp),%eax
  mov    $0x45,%edx
  imul   %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] = state[0UL] + state[local2];
        state[0UL] = state[local1] - state[0UL];
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] * (unsigned char)69;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%edx
  mov    %edx,%eax
  mulb   (%rdi)
  add    $0x1c,%eax
  movzbl 0x1(%rdi),%edx
  mov    $0x0,%ecx
  test   %dl,%dl
  je     L2
L14:
  mov    $0x0,%eax
L12:
  add    $0x1,%eax
  cmp    %dl,%al
  jne    L12
  add    $0x1,%ecx
  cmp    %dl,%cl
  jne    L14
  mov    $0x0,%eax
L2:
  mov    $0x45,%edx
  imul   %edx,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] = state[0UL] + state[local2];
        state[0UL] = state[local1] - state[0UL];
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] * (unsigned char)69;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  mov    %eax,%edx
  xor    %eax,%eax
  add    $0x1c,%edx
  cmpb   $0x0,0x1(%rdi)
  je     L2
  mov    %al,(%rsi)
  ret
L2:
  mov    $0x45,%ecx
  mov    %edx,%eax
  imul   %ecx,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] = state[0UL] + state[local2];
        state[0UL] = state[local1] - state[0UL];
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] * (unsigned char)69;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  mov    %eax,%edx
  xor    %eax,%eax
  add    $0x1c,%edx
  cmpb   $0x0,0x1(%rdi)
  je     L1
  mov    %al,(%rsi)
  ret
L1:
  mov    $0x45,%ecx
  mov    %edx,%eax
  imul   %ecx,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] = state[0UL] + state[local2];
        state[0UL] = state[local1] - state[0UL];
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] * (unsigned char)69;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim_title>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L35
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L6
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0x0,-0x4(%rbp)
  jns    L18
  jmp    L30
L6:
  nop
L30:
  nop
  leave
  ret
```

assistant: ```c
void trim_title(char *title) {
  int i;
  for (i = strlen(title) - 1; i >= 0; --i) {
    if (isspace(title[i]))
      title[i] = 0;
    else
      break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trim_title>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L7
  movslq %ebx,%rbx
  add    %rbp,%rbx
  movslq %eax,%rdx
  lea    -0x2(%rbp,%rdx,1),%rbp
  lea    -0x1(%rax),%eax
  sub    %rax,%rbp
L9:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void trim_title(char *title) {
  int i;
  for (i = strlen(title) - 1; i >= 0; --i) {
    if (isspace(title[i]))
      title[i] = 0;
    else
      break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim_title>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L1
  movslq %edx,%rbx
  cltq
  mov    %edx,%edx
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
  jmp    L27
  nopl   (%rax)
L30:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L1
L27:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L30
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void trim_title(char *title) {
  int i;
  for (i = strlen(title) - 1; i >= 0; --i) {
    if (isspace(title[i]))
      title[i] = 0;
    else
      break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim_title>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L25
  movslq %edx,%rbx
  cltq
  mov    %edx,%edx
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
  jmp    L28
  nopl   (%rax)
L1:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L25
L28:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void trim_title(char *title) {
  int i;
  for (i = strlen(title) - 1; i >= 0; --i) {
    if (isspace(title[i]))
      title[i] = 0;
    else
      break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L0
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickPartition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSort>
L0:
  nop
  leave
  ret
```

assistant: ```c
void quickSort(int a[], int p, int r) {
  int q;
  if (p < r) {
    q = quickPartition(a, p, r);
    quickSort(a, p, q - 1);
    quickSort(a, q + 1, r);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quickSort>:
  endbr64
  cmp    %edx,%esi
  jl     L4
  ret
L4:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <quickPartition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quickSort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quickSort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quickSort(int a[], int p, int r) {
  int q;
  if (p < r) {
    q = quickPartition(a, p, r);
    quickSort(a, p, q - 1);
    quickSort(a, q + 1, r);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log10Pow5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0xa3c,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  imul   $0xb2efb,%eax,%eax
  sar    $0x14,%eax
  leave
  ret
```

assistant: ```c
uint32_t log10Pow5(const int32_t e) {
  assert(e >= 0);
  assert(e <= 2620);
  return (((uint32_t)e) * 732923) >> 20;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<log10Pow5>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    $0xa3c,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  imul   $0xb2efb,%ebx,%eax
  sar    $0x14,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t log10Pow5(const int32_t e) {
  assert(e >= 0);
  assert(e <= 2620);
  return (((uint32_t)e) * 732923) >> 20;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log10Pow5>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0xa3c,%ebx
  setle  %dil
  call   <assert@plt>
  imul   $0xb2efb,%ebx,%eax
  pop    %rbx
  sar    $0x14,%eax
  ret
```

assistant: ```c
uint32_t log10Pow5(const int32_t e) {
  assert(e >= 0);
  assert(e <= 2620);
  return (((uint32_t)e) * 732923) >> 20;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log10Pow5>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0xa3c,%ebx
  setle  %dil
  call   <assert@plt>
  imul   $0xb2efb,%ebx,%eax
  pop    %rbx
  sar    $0x14,%eax
  ret
```

assistant: ```c
uint32_t log10Pow5(const int32_t e) {
  assert(e >= 0);
  assert(e <= 2620);
  return (((uint32_t)e) * 732923) >> 20;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L29
L4:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L38
L35:
  addq   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L35
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L67
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  jmp    L1
L67:
  nop
L1:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strspn(const char *s, const char *accept) {
  size_t l = 0;
  const char *a;
  for (; *s; s++) {
    for (a = accept; *a && *s != *a; a++)
      ;
    if (!*a)
      break;
    else
      l++;
  }
  return l;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L78
  movzbl (%rsi),%r9d
  test   %r9b,%r9b
  setne  %r10b
  mov    $0x0,%r8d
  jmp    L35
L86:
  mov    %r9d,%edx
L85:
  test   %dl,%dl
  je     L8
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  je     L8
L35:
  cmp    %cl,%r9b
  je     L86
  mov    %rsi,%rax
  test   %r10b,%r10b
  je     L86
L9:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %cl,%dl
  je     L85
  test   %dl,%dl
  jne    L9
  jmp    L85
L78:
  mov    $0x0,%r8d
L8:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t strspn(const char *s, const char *accept) {
  size_t l = 0;
  const char *a;
  for (; *s; s++) {
    for (a = accept; *a && *s != *a; a++)
      ;
    if (!*a)
      break;
    else
      l++;
  }
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %r8d,%r8d
  test   %cl,%cl
  je     L34
  movzbl (%rsi),%r9d
  xor    %r8d,%r8d
  nopl   (%rax)
L3:
  test   %r9b,%r9b
  je     L34
  mov    %rsi,%rdx
  mov    %r9d,%eax
  jmp    L57
  nopl   (%rax)
L22:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L34
L57:
  cmp    %al,%cl
  jne    L22
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L3
L34:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t strspn(const char *s, const char *accept) {
  size_t l = 0;
  const char *a;
  for (; *s; s++) {
    for (a = accept; *a && *s != *a; a++)
      ;
    if (!*a)
      break;
    else
      l++;
  }
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %r8d,%r8d
  test   %cl,%cl
  je     L8
  movzbl (%rsi),%r9d
  xor    %r8d,%r8d
  nopl   (%rax)
L25:
  test   %r9b,%r9b
  je     L8
  mov    %rsi,%rdx
  mov    %r9d,%eax
  jmp    L36
  nopl   (%rax)
L23:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L8
L36:
  cmp    %al,%cl
  jne    L23
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L25
L8:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t strspn(const char *s, const char *accept) {
  size_t l = 0;
  const char *a;
  for (; *s; s++) {
    for (a = accept; *a && *s != *a; a++)
      ;
    if (!*a)
      break;
    else
      l++;
  }
  return l;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_socket_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  jmp    L17
L7:
  lea    D2(%rip),%rax
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string

tool: D17: ENVOY_SOCKET

tool: D2: @/vodik/envoy

assistant: ```c
const char *get_socket_path(void) {
  const char *socket = getenv("ENVOY_SOCKET");
  return socket ? socket : "@/vodik/envoy";
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_socket_path>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  lea    D8(%rip),%rdx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string

tool: D13: ENVOY_SOCKET

tool: D8: @/vodik/envoy

assistant: ```c
const char *get_socket_path(void) {
  const char *socket = getenv("ENVOY_SOCKET");
  return socket ? socket : "@/vodik/envoy";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_socket_path>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <getenv@plt>
  lea    D13(%rip),%rdx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string

tool: D12: ENVOY_SOCKET

tool: D13: @/vodik/envoy

assistant: ```c
const char *get_socket_path(void) {
  const char *socket = getenv("ENVOY_SOCKET");
  return socket ? socket : "@/vodik/envoy";
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_socket_path>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <getenv@plt>
  lea    D14(%rip),%rdx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string

tool: D7: ENVOY_SOCKET

tool: D14: @/vodik/envoy

assistant: ```c
const char *get_socket_path(void) {
  const char *socket = getenv("ENVOY_SOCKET");
  return socket ? socket : "@/vodik/envoy";
}
```