ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<fold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x3c(%rbp)
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%ebx
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L1:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L1
  jmp    L38
L25:
  mov    -0x30(%rbp),%eax
  add    %eax,-0x3c(%rbp)
L38:
  cmpl   $0x0,-0x3c(%rbp)
  js     L25
  mov    -0x3c(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %edx,-0x3c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L58
L57:
  mov    -0x3c(%rbp),%eax
  and    %ebx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x3c(%rbp),%eax
  and    %ebx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x3c(%rbp)
L58:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L57
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void fold(float I[], float W[], int Nw, float O[], int N, int n) {
  int i;
  register unsigned mask = N - 1;
  for (i = 0; i < N; i++)
    O[i] = 0.;
  while (n < 0)
    n += N;
  n %= N;
  for (i = 0; i < Nw; ++i, ++n) {
    O[n & mask] += I[i] * W[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fold>:
  endbr64
  mov    %edx,%r11d
  mov    %rcx,%r10
  mov    %r9d,%eax
  lea    -0x1(%r8),%r9d
  test   %r8d,%r8d
  jle    L35
  mov    %rcx,%rdx
  lea    -0x1(%r8),%ecx
  lea    0x4(%r10,%rcx,4),%rcx
L53:
  movl   $0x0,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L53
L35:
  test   %eax,%eax
  jns    L58
L31:
  add    %r8d,%eax
  js     L31
L58:
  cltd
  idiv   %r8d
  test   %r11d,%r11d
  jle    L44
  mov    %r11d,%r11d
  mov    $0x0,%eax
L47:
  lea    (%rdx,%rax,1),%ecx
  and    %r9d,%ecx
  lea    (%r10,%rcx,4),%rcx
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x1,%rax
  cmp    %r11,%rax
  jne    L47
L44:
  ret
```

assistant: ```c
void fold(float I[], float W[], int Nw, float O[], int N, int n) {
  int i;
  register unsigned mask = N - 1;
  for (i = 0; i < N; i++)
    O[i] = 0.;
  while (n < 0)
    n += N;
  n %= N;
  for (i = 0; i < Nw; ++i, ++n) {
    O[n & mask] += I[i] * W[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fold>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  movslq %edx,%r14
  push   %r13
  lea    -0x1(%r8),%r13d
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rcx,%rdi
  sub    $0x8,%rsp
  test   %r8d,%r8d
  jle    L30
  movslq %r8d,%rdx
  xor    %esi,%esi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
L30:
  test   %r12d,%r12d
  jns    L33
  nopl   0x0(%rax,%rax,1)
L21:
  add    %r15d,%r12d
  js     L21
L33:
  mov    %r12d,%eax
  cltd
  idiv   %r15d
  test   %r14d,%r14d
  jle    L28
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L47:
  lea    (%rdx,%rax,1),%ecx
  movss  (%rbx,%rax,4),%xmm0
  mulss  0x0(%rbp,%rax,4),%xmm0
  add    $0x1,%rax
  and    %r13d,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rcx
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  cmp    %r14,%rax
  jne    L47
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void fold(float I[], float W[], int Nw, float O[], int N, int n) {
  int i;
  register unsigned mask = N - 1;
  for (i = 0; i < N; i++)
    O[i] = 0.;
  while (n < 0)
    n += N;
  n %= N;
  for (i = 0; i < Nw; ++i, ++n) {
    O[n & mask] += I[i] * W[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fold>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  movslq %edx,%r14
  push   %r13
  lea    -0x1(%r8),%r13d
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rcx,%rdi
  sub    $0x8,%rsp
  test   %r8d,%r8d
  jle    L1
  movslq %r8d,%rdx
  xor    %esi,%esi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
L1:
  test   %r12d,%r12d
  jns    L4
  nopl   0x0(%rax,%rax,1)
L2:
  add    %r15d,%r12d
  js     L2
L4:
  mov    %r12d,%eax
  cltd
  idiv   %r15d
  test   %r14d,%r14d
  jle    L44
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L42:
  lea    (%rdx,%rax,1),%ecx
  movss  (%rbx,%rax,4),%xmm0
  mulss  0x0(%rbp,%rax,4),%xmm0
  add    $0x1,%rax
  and    %r13d,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rcx
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  cmp    %r14,%rax
  jne    L42
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void fold(float I[], float W[], int Nw, float O[], int N, int n) {
  int i;
  register unsigned mask = N - 1;
  for (i = 0; i < N; i++)
    O[i] = 0.;
  while (n < 0)
    n += N;
  n %= N;
  for (i = 0; i < Nw; ++i, ++n) {
    O[n & mask] += I[i] * W[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<htoles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  lea    -0xc(%rbp),%rax
  add    $0x8,%rax
  movslq %edx,%rdx
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
uint16_t htoles(uint16_t value) {
  uint16_t tmp;
  ((uint8_t *)&tmp)[0] = (uint8_t)(value >> 0);
  ((uint8_t *)&tmp)[1] = (uint8_t)(value >> 8);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<htoles>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint16_t htoles(uint16_t value) {
  uint16_t tmp;
  ((uint8_t *)&tmp)[0] = (uint8_t)(value >> 0);
  ((uint8_t *)&tmp)[1] = (uint8_t)(value >> 8);
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<htoles>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint16_t htoles(uint16_t value) {
  uint16_t tmp;
  ((uint8_t *)&tmp)[0] = (uint8_t)(value >> 0);
  ((uint8_t *)&tmp)[1] = (uint8_t)(value >> 8);
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<htoles>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint16_t htoles(uint16_t value) {
  uint16_t tmp;
  ((uint8_t *)&tmp)[0] = (uint8_t)(value >> 0);
  ((uint8_t *)&tmp)[1] = (uint8_t)(value >> 8);
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L11:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void shuffle(int arr[], int len) {
  int t, i, j, s;
  for (t = 0; t < len; ++t) {
    i = rand() % len;
    j = rand() % len;
    s = arr[i];
    arr[i] = arr[j];
    arr[j] = s;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<shuffle>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    $0x0,%ebp
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,%r13d
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %r13d,%r13
  lea    (%r12,%r13,4),%rcx
  mov    (%rcx),%esi
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  ret
```

assistant: ```c
void shuffle(int arr[], int len) {
  int t, i, j, s;
  for (t = 0; t < len; ++t) {
    i = rand() % len;
    j = rand() % len;
    s = arr[i];
    arr[i] = arr[j];
    arr[j] = s;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<shuffle>:
  endbr64
  test   %esi,%esi
  jle    L13
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%rbp
  call   <rand@plt>
  lea    0x0(%r13,%rbp,4),%rcx
  cltd
  mov    (%rcx),%esi
  idiv   %ebx
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  cmp    %r12d,%ebx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  ret
```

assistant: ```c
void shuffle(int arr[], int len) {
  int t, i, j, s;
  for (t = 0; t < len; ++t) {
    i = rand() % len;
    j = rand() % len;
    s = arr[i];
    arr[i] = arr[j];
    arr[j] = s;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shuffle>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%rbp
  call   <rand@plt>
  lea    0x0(%r13,%rbp,4),%rcx
  cltd
  mov    (%rcx),%esi
  idiv   %ebx
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  cmp    %r12d,%ebx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  ret
```

assistant: ```c
void shuffle(int arr[], int len) {
  int t, i, j, s;
  for (t = 0; t < len; ++t) {
    i = rand() % len;
    j = rand() % len;
    s = arr[i];
    arr[i] = arr[j];
    arr[j] = s;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Findjob_set_false>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Findjob_set_prop_filter@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Findjob_set_false(struct FindjoB *o, int value, int flag) {
  int ret;
  ret = Findjob_set_prop_filter(o, 0, value, flag & 1);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Findjob_set_false>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%ecx
  and    $0x1,%ecx
  mov    %esi,%edx
  mov    $0x0,%esi
  call   <Findjob_set_prop_filter@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Findjob_set_false(struct FindjoB *o, int value, int flag) {
  int ret;
  ret = Findjob_set_prop_filter(o, 0, value, flag & 1);
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Findjob_set_false>:
  endbr64
  mov    %edx,%ecx
  mov    %esi,%edx
  xor    %esi,%esi
  and    $0x1,%ecx
  jmp    1050 <Findjob_set_prop_filter@plt>
```

assistant: ```c
int Findjob_set_false(struct FindjoB *o, int value, int flag) {
  int ret;
  ret = Findjob_set_prop_filter(o, 0, value, flag & 1);
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Findjob_set_false>:
  endbr64
  mov    %edx,%ecx
  mov    %esi,%edx
  xor    %esi,%esi
  and    $0x1,%ecx
  jmp    1050 <Findjob_set_prop_filter@plt>
```

assistant: ```c
int Findjob_set_false(struct FindjoB *o, int value, int flag) {
  int ret;
  ret = Findjob_set_prop_filter(o, 0, value, flag & 1);
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gdb_putstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L6
L16:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <gdb_putchar@plt>
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void gdb_putstr(const char *str) {
  while (*str)
    gdb_putchar(*str++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gdb_putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L9:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <gdb_putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
L7:
  pop    %rbx
  ret
```

assistant: ```c
void gdb_putstr(const char *str) {
  while (*str)
    gdb_putchar(*str++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gdb_putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
L13:
  call   <gdb_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L13
L10:
  pop    %rbx
  ret
```

assistant: ```c
void gdb_putstr(const char *str) {
  while (*str)
    gdb_putchar(*str++);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gdb_putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L9
L12:
  call   <gdb_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L12
L9:
  pop    %rbx
  ret
```

assistant: ```c
void gdb_putstr(const char *str) {
  while (*str)
    gdb_putchar(*str++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inet6_rth_space2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jne    L16
  cmpl   $0x0,-0x8(%rbp)
  js     L7
  cmpl   $0x7f,-0x8(%rbp)
  jle    L11
L7:
  mov    $0x0,%eax
  jmp    L20
L11:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x2,%eax
  jmp    L20
L16:
  mov    $0x0,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
socklen_t inet6_rth_space2(int type, int segments) {
  switch (type) {
  case 2:
    if (segments < 0 || segments > 127)
      return 0;
    return sizeof(struct ip6_rthdr0) + segments * sizeof(struct in6_addr);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inet6_rth_space2>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x2,%edi
  je     L8
L17:
  ret
L8:
  lea    0x4(,%rsi,4),%eax
  cmp    $0x80,%esi
  mov    $0x0,%edx
  cmovae %edx,%eax
  jmp    L17
```

assistant: ```c
socklen_t inet6_rth_space2(int type, int segments) {
  switch (type) {
  case 2:
    if (segments < 0 || segments > 127)
      return 0;
    return sizeof(struct ip6_rthdr0) + segments * sizeof(struct in6_addr);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inet6_rth_space2>:
  endbr64
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L2
  ret
  nopl   0x0(%rax)
L2:
  lea    0x4(,%rsi,4),%edx
  cmp    $0x80,%esi
  cmovb  %edx,%eax
  ret
```

assistant: ```c
socklen_t inet6_rth_space2(int type, int segments) {
  switch (type) {
  case 2:
    if (segments < 0 || segments > 127)
      return 0;
    return sizeof(struct ip6_rthdr0) + segments * sizeof(struct in6_addr);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inet6_rth_space2>:
  endbr64
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L0
  ret
  nopl   0x0(%rax)
L0:
  lea    0x4(,%rsi,4),%edx
  cmp    $0x80,%esi
  cmovb  %edx,%eax
  ret
```

assistant: ```c
socklen_t inet6_rth_space2(int type, int segments) {
  switch (type) {
  case 2:
    if (segments < 0 || segments > 127)
      return 0;
    return sizeof(struct ip6_rthdr0) + segments * sizeof(struct in6_addr);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_picks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L7:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L0
  addl   $0x1,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  subl   $0x1,-0x14(%rbp)
  jmp    L35
L0:
  subl   $0x1,-0x14(%rbp)
L35:
  cmpl   $0x0,-0x14(%rbp)
  jns    L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_picks(int item, int size, int *weights, int **picks) {
  int count = 0;
  while (item >= 0) {
    if (picks[item][size] == 1) {
      count++;
      size = weights[item];
      item--;
    } else {
      item--;
    }
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<count_picks>:
  endbr64
  mov    %esi,%r9d
  test   %edi,%edi
  js     L47
  movslq %edi,%rax
  lea    (%rcx,%rax,8),%rcx
  sub    $0x1,%edi
  lea    (%rdx,%rax,4),%rdx
  mov    $0x0,%r10d
  jmp    L30
L20:
  sub    $0x8,%rcx
  sub    $0x1,%edi
  sub    $0x4,%rdx
  test   %esi,%esi
  js     L29
L30:
  movslq %r9d,%rax
  mov    (%rcx),%r8
  mov    %edi,%esi
  cmpl   $0x1,(%r8,%rax,4)
  jne    L20
  add    $0x1,%r10d
  mov    (%rdx),%r9d
  jmp    L20
L47:
  mov    $0x0,%r10d
L29:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int count_picks(int item, int size, int *weights, int **picks) {
  int count = 0;
  while (item >= 0) {
    if (picks[item][size] == 1) {
      count++;
      size = weights[item];
      item--;
    } else {
      item--;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<count_picks>:
  endbr64
  test   %edi,%edi
  js     L12
  movslq %edi,%rdi
  xor    %r9d,%r9d
  xchg   %ax,%ax
L3:
  mov    (%rcx,%rdi,8),%r8
  movslq %esi,%rax
  cmpl   $0x1,(%r8,%rax,4)
  jne    L6
  mov    (%rdx,%rdi,4),%esi
  add    $0x1,%r9d
L6:
  sub    $0x1,%rdi
  test   %edi,%edi
  jns    L3
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L12:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int count_picks(int item, int size, int *weights, int **picks) {
  int count = 0;
  while (item >= 0) {
    if (picks[item][size] == 1) {
      count++;
      size = weights[item];
      item--;
    } else {
      item--;
    }
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<count_picks>:
  endbr64
  test   %edi,%edi
  js     L23
  movslq %edi,%rdi
  xor    %r9d,%r9d
  xchg   %ax,%ax
L18:
  mov    (%rcx,%rdi,8),%r8
  movslq %esi,%rax
  cmpl   $0x1,(%r8,%rax,4)
  jne    L26
  mov    (%rdx,%rdi,4),%esi
  add    $0x1,%r9d
L26:
  sub    $0x1,%rdi
  test   %edi,%edi
  jns    L18
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L23:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int count_picks(int item, int size, int *weights, int **picks) {
  int count = 0;
  while (item >= 0) {
    if (picks[item][size] == 1) {
      count++;
      size = weights[item];
      item--;
    } else {
      item--;
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<countWays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L56:
  cmp    %rdx,%rsp
  je     L7
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L56
L7:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L23
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L23:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x1,0x8(%rax)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x2,0xc(%rax)
  movl   $0x4,-0x2c(%rbp)
  jmp    L11
L53:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%ecx
  mov    -0x2c(%rbp),%eax
  lea    -0x3(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,%ecx
  mov    -0x2c(%rbp),%eax
  lea    -0x4(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x2c(%rbp)
L11:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L53
  mov    -0x20(%rbp),%rax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %rsi,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int countWays(int n) {
  int DP[n + 1];
  DP[0] = DP[1] = DP[2] = 1;
  DP[3] = 2;
  for (int i = 4; i <= n; i++)
    DP[i] = DP[i - 1] + DP[i - 3] + DP[i - 4];
  return DP[n];
}
```