ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<index_search>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <index_readroot@plt>
  mov    %rax,%rdi
  mov    $0x0,%edx
  mov    %rbx,%rsi
  call   <index_search__node@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *index_search(struct index_file *in, const char *key) {
  struct index_node_f *root;
  char *value;
  root = index_readroot(in);
  value = index_search__node(root, key, 0);
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<index_search>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <index_readroot@plt>
  mov    %rbp,%rsi
  xor    %edx,%edx
  pop    %rbp
  mov    %rax,%rdi
  jmp    1060 <index_search__node@plt>
```

assistant: ```c
char *index_search(struct index_file *in, const char *key) {
  struct index_node_f *root;
  char *value;
  root = index_readroot(in);
  value = index_search__node(root, key, 0);
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<index_search>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <index_readroot@plt>
  mov    %rbp,%rsi
  xor    %edx,%edx
  pop    %rbp
  mov    %rax,%rdi
  jmp    1060 <index_search__node@plt>
```

assistant: ```c
char *index_search(struct index_file *in, const char *key) {
  struct index_node_f *root;
  char *value;
  root = index_readroot(in);
  value = index_search__node(root, key, 0);
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<decode_int32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int decode_int32(const unsigned char *address) {
  unsigned u = (((((address[0] << 8) + address[1]) << 8) + address[2]) << 8) + address[3];
  return (int)u;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decode_int32>:
  endbr64
  movzbl (%rdi),%eax
  shl    $0x8,%eax
  movzbl 0x1(%rdi),%edx
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl 0x2(%rdi),%edx
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl 0x3(%rdi),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int decode_int32(const unsigned char *address) {
  unsigned u = (((((address[0] << 8) + address[1]) << 8) + address[2]) << 8) + address[3];
  return (int)u;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<decode_int32>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int decode_int32(const unsigned char *address) {
  unsigned u = (((((address[0] << 8) + address[1]) << 8) + address[2]) << 8) + address[3];
  return (int)u;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<decode_int32>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int decode_int32(const unsigned char *address) {
  unsigned u = (((((address[0] << 8) + address[1]) << 8) + address[2]) << 8) + address[3];
  return (int)u;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D18
datatype: string

tool: D1: HTTP/1.1 200 OK
xxooxxoo:xxooxox

tool: D18: %d


assistant: ```c
int main() {
  char *str = "HTTP/1.1 200 OK\nxxooxxoo:xxooxox";
  uint32_t *resp = (uint32_t *)str;
  printf("%d\n", atoi((char *)&resp[2]));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string
name: unpack_data
arguments: data_tag: D19
type: string

tool: D7:  200 OK
xxooxxoo:xxooxox

tool: D19: %d


assistant: ```c
int main() {
  char *str = "HTTP/1.1 200 OK\nxxooxxoo:xxooxox";
  uint32_t *resp = (uint32_t *)str;
  printf("%d\n", atoi((char *)&resp[2]));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <atoi@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D18
type: string

tool: D4:  200 OK
xxooxxoo:xxooxox

tool: D18: %d


assistant: ```c
int main() {
  char *str = "HTTP/1.1 200 OK\nxxooxxoo:xxooxox";
  uint32_t *resp = (uint32_t *)str;
  printf("%d\n", atoi((char *)&resp[2]));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <atoi@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string
name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D9:  200 OK
xxooxxoo:xxooxox

tool: D0: %d


assistant: ```c
int main() {
  char *str = "HTTP/1.1 200 OK\nxxooxxoo:xxooxox";
  uint32_t *resp = (uint32_t *)str;
  printf("%d\n", atoi((char *)&resp[2]));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<invert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movq   $0xffffffffffffffff,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  not    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  shlq   %cl,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int invert(int x, int p, int n) {
  long unsigned mask = ~0;
  mask = ~(mask << n);
  mask = (mask << p);
  x = mask ^ x;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<invert>:
  endbr64
  mov    $0xffffffffffffffff,%r8
  mov    %edx,%ecx
  shl    %cl,%r8
  not    %r8
  mov    %esi,%ecx
  shl    %cl,%r8
  mov    %edi,%eax
  xor    %r8d,%eax
  ret
```

assistant: ```c
int invert(int x, int p, int n) {
  long unsigned mask = ~0;
  mask = ~(mask << n);
  mask = (mask << p);
  x = mask ^ x;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<invert>:
  endbr64
  mov    %edx,%ecx
  mov    $0xffffffffffffffff,%r8
  mov    %edi,%eax
  shl    %cl,%r8
  mov    %esi,%ecx
  not    %r8
  shl    %cl,%r8
  xor    %r8d,%eax
  ret
```

assistant: ```c
int invert(int x, int p, int n) {
  long unsigned mask = ~0;
  mask = ~(mask << n);
  mask = (mask << p);
  x = mask ^ x;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<invert>:
  endbr64
  mov    %edx,%ecx
  mov    $0xffffffffffffffff,%r8
  mov    %edi,%eax
  shl    %cl,%r8
  mov    %esi,%ecx
  not    %r8
  shl    %cl,%r8
  xor    %r8d,%eax
  ret
```

assistant: ```c
int invert(int x, int p, int n) {
  long unsigned mask = ~0;
  mask = ~(mask << n);
  mask = (mask << p);
  x = mask ^ x;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_fwd_until_dst_word_aligned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7,-0x4(%rbp)
  ja     L9
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D9(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x20(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L9:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int copy_fwd_until_dst_word_aligned(uint8_t *d, const uint8_t *s) {
  int dstal = ((uint32_t)d) % sizeof(uint32_t);
  switch (dstal) {
  case 1:
    *d++ = *s++;
  case 2:
    *d++ = *s++;
  case 3:
    *d++ = *s++;
  case 4:
    *d++ = *s++;
  case 5:
    *d++ = *s++;
  case 6:
    *d++ = *s++;
  case 7:
    *d = *s;
  }
  return dstal;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_fwd_until_dst_word_aligned>:
  endbr64
  mov    %rdi,%rax
  mov    %edi,%ecx
  and    $0x3,%ecx
  mov    %ecx,%edx
  lea    D1(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  mov    (%rsi),%edx
  mov    %edx,(%rax)
  lea    0x4(%rsi),%rsi
  lea    0x4(%rax),%rax
  mov    (%rsi),%edx
  mov    %edx,(%rax)
  lea    0x4(%rsi),%rsi
  lea    0x4(%rax),%rax
  lea    0x4(%rsi),%rdi
  lea    0x4(%rax),%rdx
  mov    (%rsi),%esi
  mov    %esi,(%rax)
L12:
  lea    0x4(%rdi),%rsi
  lea    0x4(%rdx),%rax
  mov    (%rdi),%edi
  mov    %edi,(%rdx)
  lea    0x4(%rsi),%rdi
  lea    0x4(%rax),%rdx
  mov    (%rsi),%esi
  mov    %esi,(%rax)
L1:
  lea    0x4(%rdi),%rsi
  lea    0x4(%rdx),%rax
  mov    (%rdi),%edi
  mov    %edi,(%rdx)
  mov    (%rsi),%edx
  mov    %edx,(%rax)
  mov    %ecx,%eax
  ret
  mov    %rsi,%rdi
  mov    %rax,%rdx
  jmp    L12
  mov    %rsi,%rdi
  mov    %rax,%rdx
  jmp    L1
```

assistant: ```c
int copy_fwd_until_dst_word_aligned(uint8_t *d, const uint8_t *s) {
  int dstal = ((uint32_t)d) % sizeof(uint32_t);
  switch (dstal) {
  case 1:
    *d++ = *s++;
  case 2:
    *d++ = *s++;
  case 3:
    *d++ = *s++;
  case 4:
    *d++ = *s++;
  case 5:
    *d++ = *s++;
  case 6:
    *d++ = *s++;
  case 7:
    *d = *s;
  }
  return dstal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_fwd_until_dst_word_aligned>:
  endbr64
  mov    %edi,%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L38
  cmp    $0x3,%eax
  je     L21
  cmp    $0x1,%eax
  je     L39
  ret
  nopl   0x0(%rax)
L39:
  lea    0x4(%rsi),%rcx
  mov    (%rsi),%esi
  lea    0x4(%rdi),%rdx
  mov    %esi,(%rdi)
L20:
  lea    0x4(%rcx),%rsi
  mov    (%rcx),%ecx
  lea    0x4(%rdx),%rdi
  mov    %ecx,(%rdx)
L21:
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    0x4(%rsi),%edx
  mov    %edx,0x4(%rdi)
  mov    0x8(%rsi),%edx
  mov    %edx,0x8(%rdi)
  mov    0xc(%rsi),%edx
  mov    %edx,0xc(%rdi)
  mov    0x10(%rsi),%edx
  mov    %edx,0x10(%rdi)
  ret
  nopl   (%rax)
L38:
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  jmp    L20
```

assistant: ```c
int copy_fwd_until_dst_word_aligned(uint8_t *d, const uint8_t *s) {
  int dstal = ((uint32_t)d) % sizeof(uint32_t);
  switch (dstal) {
  case 1:
    *d++ = *s++;
  case 2:
    *d++ = *s++;
  case 3:
    *d++ = *s++;
  case 4:
    *d++ = *s++;
  case 5:
    *d++ = *s++;
  case 6:
    *d++ = *s++;
  case 7:
    *d = *s;
  }
  return dstal;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_fwd_until_dst_word_aligned>:
  endbr64
  mov    %edi,%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L28
  cmp    $0x3,%eax
  je     L37
  cmp    $0x1,%eax
  je     L3
  ret
  nopl   0x0(%rax)
L3:
  lea    0x4(%rsi),%rcx
  mov    (%rsi),%esi
  lea    0x4(%rdi),%rdx
  mov    %esi,(%rdi)
L9:
  lea    0x4(%rcx),%rsi
  mov    (%rcx),%ecx
  lea    0x4(%rdx),%rdi
  mov    %ecx,(%rdx)
L37:
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    0x4(%rsi),%edx
  mov    %edx,0x4(%rdi)
  mov    0x8(%rsi),%edx
  mov    %edx,0x8(%rdi)
  mov    0xc(%rsi),%edx
  mov    %edx,0xc(%rdi)
  mov    0x10(%rsi),%edx
  mov    %edx,0x10(%rdi)
  ret
  nopl   (%rax)
L28:
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  jmp    L9
```

assistant: ```c
int copy_fwd_until_dst_word_aligned(uint8_t *d, const uint8_t *s) {
  int dstal = ((uint32_t)d) % sizeof(uint32_t);
  switch (dstal) {
  case 1:
    *d++ = *s++;
  case 2:
    *d++ = *s++;
  case 3:
    *d++ = *s++;
  case 4:
    *d++ = *s++;
  case 5:
    *d++ = *s++;
  case 6:
    *d++ = *s++;
  case 7:
    *d = *s;
  }
  return dstal;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<affine_multiply>:
  endbr64
  movsd  (%rsi),%xmm3
  movsd  (%rdx),%xmm2
  movsd  0x8(%rsi),%xmm7
  movsd  0x10(%rdx),%xmm6
  movsd  0x8(%rdx),%xmm1
  movsd  0x18(%rdx),%xmm5
  movsd  0x10(%rsi),%xmm10
  movsd  0x18(%rsi),%xmm9
  movsd  0x20(%rsi),%xmm0
  movsd  0x28(%rsi),%xmm8
  movapd %xmm2,%xmm4
  mulsd  %xmm0,%xmm4
  movapd %xmm6,%xmm11
  mulsd  %xmm8,%xmm11
  addsd  %xmm11,%xmm4
  addsd  0x20(%rdx),%xmm4
  mulsd  %xmm1,%xmm0
  mulsd  %xmm5,%xmm8
  addsd  %xmm8,%xmm0
  addsd  0x28(%rdx),%xmm0
  movapd %xmm3,%xmm8
  mulsd  %xmm2,%xmm8
  movapd %xmm7,%xmm11
  mulsd  %xmm6,%xmm11
  addsd  %xmm11,%xmm8
  movsd  %xmm8,(%rdi)
  mulsd  %xmm1,%xmm3
  mulsd  %xmm5,%xmm7
  addsd  %xmm7,%xmm3
  movsd  %xmm3,0x8(%rdi)
  mulsd  %xmm10,%xmm2
  mulsd  %xmm9,%xmm6
  addsd  %xmm6,%xmm2
  movsd  %xmm2,0x10(%rdi)
  mulsd  %xmm10,%xmm1
  mulsd  %xmm9,%xmm5
  addsd  %xmm5,%xmm1
  movsd  %xmm1,0x18(%rdi)
  movsd  %xmm4,0x20(%rdi)
  movsd  %xmm0,0x28(%rdi)
  ret
```

assistant: ```c
void affine_multiply(double dst[6], const double src1[6], const double src2[6]) {
  double d0, d1, d2, d3, d4, d5;
  d0 = src1[0] * src2[0] + src1[1] * src2[2];
  d1 = src1[0] * src2[1] + src1[1] * src2[3];
  d2 = src1[2] * src2[0] + src1[3] * src2[2];
  d3 = src1[2] * src2[1] + src1[3] * src2[3];
  d4 = src1[4] * src2[0] + src1[5] * src2[2] + src2[4];
  d5 = src1[4] * src2[1] + src1[5] * src2[3] + src2[5];
  dst[0] = d0;
  dst[1] = d1;
  dst[2] = d2;
  dst[3] = d3;
  dst[4] = d4;
  dst[5] = d5;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<affine_multiply>:
  endbr64
  movsd  (%rdx),%xmm2
  movsd  0x10(%rdx),%xmm8
  movsd  0x8(%rdx),%xmm1
  movsd  0x18(%rdx),%xmm5
  movsd  0x20(%rsi),%xmm0
  movsd  0x28(%rsi),%xmm10
  movapd %xmm2,%xmm4
  movapd %xmm8,%xmm11
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm9
  mulsd  %xmm10,%xmm11
  movsd  0x10(%rsi),%xmm7
  movsd  0x18(%rsi),%xmm6
  mulsd  %xmm5,%xmm10
  mulsd  %xmm0,%xmm4
  mulsd  %xmm1,%xmm0
  addsd  %xmm11,%xmm4
  movapd %xmm9,%xmm11
  addsd  0x20(%rdx),%xmm4
  addsd  %xmm10,%xmm0
  movapd %xmm3,%xmm10
  addsd  0x28(%rdx),%xmm0
  mulsd  %xmm2,%xmm10
  mulsd  %xmm8,%xmm11
  movsd  %xmm4,0x20(%rdi)
  mulsd  %xmm1,%xmm3
  movsd  %xmm0,0x28(%rdi)
  mulsd  %xmm5,%xmm9
  mulsd  %xmm7,%xmm2
  mulsd  %xmm6,%xmm8
  mulsd  %xmm7,%xmm1
  addsd  %xmm11,%xmm10
  mulsd  %xmm6,%xmm5
  addsd  %xmm9,%xmm3
  movsd  %xmm10,(%rdi)
  addsd  %xmm8,%xmm2
  movsd  %xmm3,0x8(%rdi)
  addsd  %xmm5,%xmm1
  movsd  %xmm2,0x10(%rdi)
  movsd  %xmm1,0x18(%rdi)
  ret
```

assistant: ```c
void affine_multiply(double dst[6], const double src1[6], const double src2[6]) {
  double d0, d1, d2, d3, d4, d5;
  d0 = src1[0] * src2[0] + src1[1] * src2[2];
  d1 = src1[0] * src2[1] + src1[1] * src2[3];
  d2 = src1[2] * src2[0] + src1[3] * src2[2];
  d3 = src1[2] * src2[1] + src1[3] * src2[3];
  d4 = src1[4] * src2[0] + src1[5] * src2[2] + src2[4];
  d5 = src1[4] * src2[1] + src1[5] * src2[3] + src2[5];
  dst[0] = d0;
  dst[1] = d1;
  dst[2] = d2;
  dst[3] = d3;
  dst[4] = d4;
  dst[5] = d5;
}
```
user: What is the c source code of the assembly code below?

```asm
<affine_multiply>:
  endbr64
  movupd 0x20(%rsi),%xmm2
  movupd (%rdx),%xmm5
  movupd 0x10(%rdx),%xmm4
  movupd (%rsi),%xmm1
  movapd %xmm2,%xmm3
  movupd 0x10(%rsi),%xmm0
  unpcklpd %xmm2,%xmm3
  unpckhpd %xmm2,%xmm2
  mulpd  %xmm5,%xmm3
  mulpd  %xmm4,%xmm2
  addpd  %xmm3,%xmm2
  movupd 0x20(%rdx),%xmm3
  addpd  %xmm3,%xmm2
  movapd %xmm1,%xmm3
  unpcklpd %xmm1,%xmm3
  unpckhpd %xmm1,%xmm1
  mulpd  %xmm5,%xmm3
  mulpd  %xmm4,%xmm1
  movups %xmm2,0x20(%rdi)
  addpd  %xmm3,%xmm1
  movups %xmm1,(%rdi)
  movapd %xmm0,%xmm1
  unpcklpd %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  mulpd  %xmm5,%xmm1
  mulpd  %xmm4,%xmm0
  addpd  %xmm1,%xmm0
  movups %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void affine_multiply(double dst[6], const double src1[6], const double src2[6]) {
  double d0, d1, d2, d3, d4, d5;
  d0 = src1[0] * src2[0] + src1[1] * src2[2];
  d1 = src1[0] * src2[1] + src1[1] * src2[3];
  d2 = src1[2] * src2[0] + src1[3] * src2[2];
  d3 = src1[2] * src2[1] + src1[3] * src2[3];
  d4 = src1[4] * src2[0] + src1[5] * src2[2] + src2[4];
  d5 = src1[4] * src2[1] + src1[5] * src2[3] + src2[5];
  dst[0] = d0;
  dst[1] = d1;
  dst[2] = d2;
  dst[3] = d3;
  dst[4] = d4;
  dst[5] = d5;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<DoUrl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <SkipQuotes@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int DoUrl(char *s) {
  SkipQuotes(&s);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<DoUrl>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <SkipQuotes@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int DoUrl(char *s) {
  SkipQuotes(&s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DoUrl>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <SkipQuotes@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int DoUrl(char *s) {
  SkipQuotes(&s);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DoUrl>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <SkipQuotes@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int DoUrl(char *s) {
  SkipQuotes(&s);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pmu_adc_disable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xfc7ff,%edx
  mov    $0x3b,%esi
  mov    $0x3,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0x64,%edi
  call   <delay@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pmu_adc_disable() {
  mbus_remote_register_write(0x3, 0x3B, ((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3) | (1 << 4) | (1 << 5) | (1 << 6) | (1 << 7) | (1 << 8) | (1 << 9) | (1 << 10) | (0 << 11) | (0 << 12) | (0 << 13) | (1 << 14) | (1 << 15) | (1 << 16) | (1 << 17) | (1 << 18) | (1 << 19)));
  delay(100);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pmu_adc_disable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xfc7ff,%edx
  mov    $0x3b,%esi
  mov    $0x3,%edi
  call   <mbus_remote_register_write@plt>
  mov    $0x64,%edi
  call   <delay@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pmu_adc_disable() {
  mbus_remote_register_write(0x3, 0x3B, ((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3) | (1 << 4) | (1 << 5) | (1 << 6) | (1 << 7) | (1 << 8) | (1 << 9) | (1 << 10) | (0 << 11) | (0 << 12) | (0 << 13) | (1 << 14) | (1 << 15) | (1 << 16) | (1 << 17) | (1 << 18) | (1 << 19)));
  delay(100);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pmu_adc_disable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  mov    $0xfc7ff,%edx
  mov    $0x3b,%esi
  call   <mbus_remote_register_write@plt>
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1070 <delay@plt>
```

assistant: ```c
void pmu_adc_disable() {
  mbus_remote_register_write(0x3, 0x3B, ((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3) | (1 << 4) | (1 << 5) | (1 << 6) | (1 << 7) | (1 << 8) | (1 << 9) | (1 << 10) | (0 << 11) | (0 << 12) | (0 << 13) | (1 << 14) | (1 << 15) | (1 << 16) | (1 << 17) | (1 << 18) | (1 << 19)));
  delay(100);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pmu_adc_disable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  mov    $0xfc7ff,%edx
  mov    $0x3b,%esi
  call   <mbus_remote_register_write@plt>
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1070 <delay@plt>
```

assistant: ```c
void pmu_adc_disable() {
  mbus_remote_register_write(0x3, 0x3B, ((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3) | (1 << 4) | (1 << 5) | (1 << 6) | (1 << 7) | (1 << 8) | (1 << 9) | (1 << 10) | (0 << 11) | (0 << 12) | (0 << 13) | (1 << 14) | (1 << 15) | (1 << 16) | (1 << 17) | (1 << 18) | (1 << 19)));
  delay(100);
}
```