ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<human_size_brief>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  cmp    $0x4e1fff,%rdi
  jle    L9
  mov    %rdi,%rdx
  cmp    $0x7fffffff,%rdi
  jle    L15
  sar    $0xa,%rdx
  lea    D33(%rip),%r12
  sar    $0x1e,%rcx
  movabs $0x6401db08d069ddf7,%rsi
  and    $0xfffff,%edx
  mov    %r12,%rdi
  add    $0x147a,%rdx
  mov    %rdx,%rax
  mul    %rsi
  mov    $0x1e,%esi
  shr    $0xc,%rdx
  mov    %rdx,%r8
  lea    D41(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L15:
  and    $0xfffff,%edx
  lea    D33(%rip),%r12
  sar    $0x14,%rcx
  movabs $0x6401db08d069ddf7,%rsi
  add    $0x147a,%rdx
  mov    %r12,%rdi
  mov    %rdx,%rax
  mul    %rsi
  mov    $0x1e,%esi
  shr    $0xc,%rdx
  mov    %rdx,%r8
  lea    D20(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    %rdi,%rax
  sar    $0xa,%rcx
  lea    D33(%rip),%r12
  lea    D3(%rip),%rdx
  and    $0x3ff,%eax
  mov    %r12,%rdi
  mov    $0x1e,%esi
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x200(,%rax,4),%r8
  shr    $0xa,%r8
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D41
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D3
type_infered: string

tool: D41: %ld.%02ldGiB

tool: D20: %ld.%02ldMiB

tool: D3: %ld.%02ldKiB

assistant: ```c
char *human_size_brief(long long bytes) {
  static char buf[30];
  if (bytes < 5000 * 1024)
    snprintf(buf, sizeof(buf), "%ld.%02ldKiB", (long)(bytes >> 10), (long)(((bytes & 1023) * 100 + 512) / 1024));
  else if (bytes < 2 * 1024LL * 1024LL * 1024LL)
    snprintf(buf, sizeof(buf), "%ld.%02ldMiB", (long)(bytes >> 20), (long)((bytes & 0xfffff) + 0x100000 / 200) / (0x100000 / 100));
  else
    snprintf(buf, sizeof(buf), "%ld.%02ldGiB", (long)(bytes >> 30), (long)(((bytes >> 10) & 0xfffff) + 0x100000 / 200) / (0x100000 / 100));
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<human_size_brief>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  cmp    $0x4e1fff,%rdi
  jle    L10
  mov    %rdi,%rdx
  cmp    $0x7fffffff,%rdi
  jle    L0
  sar    $0xa,%rdx
  lea    D7(%rip),%r12
  sar    $0x1e,%rcx
  movabs $0x6401db08d069ddf7,%rsi
  and    $0xfffff,%edx
  mov    %r12,%rdi
  add    $0x147a,%rdx
  mov    %rdx,%rax
  mul    %rsi
  mov    $0x1e,%esi
  shr    $0xc,%rdx
  mov    %rdx,%r8
  lea    D35(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L0:
  and    $0xfffff,%edx
  lea    D7(%rip),%r12
  sar    $0x14,%rcx
  movabs $0x6401db08d069ddf7,%rsi
  add    $0x147a,%rdx
  mov    %r12,%rdi
  mov    %rdx,%rax
  mul    %rsi
  mov    $0x1e,%esi
  shr    $0xc,%rdx
  mov    %rdx,%r8
  lea    D57(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  mov    %rdi,%rax
  sar    $0xa,%rcx
  lea    D7(%rip),%r12
  lea    D49(%rip),%rdx
  and    $0x3ff,%eax
  mov    %r12,%rdi
  mov    $0x1e,%esi
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x200(,%rax,4),%r8
  shr    $0xa,%r8
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D35
datatype: string
name: unpack_data
arguments: data_tag: D57
datatype: string
name: unpack_data
arguments: data_tag: D49
datatype: string

tool: D35: %ld.%02ldGiB

tool: D57: %ld.%02ldMiB

tool: D49: %ld.%02ldKiB

assistant: ```c
char *human_size_brief(long long bytes) {
  static char buf[30];
  if (bytes < 5000 * 1024)
    snprintf(buf, sizeof(buf), "%ld.%02ldKiB", (long)(bytes >> 10), (long)(((bytes & 1023) * 100 + 512) / 1024));
  else if (bytes < 2 * 1024LL * 1024LL * 1024LL)
    snprintf(buf, sizeof(buf), "%ld.%02ldMiB", (long)(bytes >> 20), (long)((bytes & 0xfffff) + 0x100000 / 200) / (0x100000 / 100));
  else
    snprintf(buf, sizeof(buf), "%ld.%02ldGiB", (long)(bytes >> 30), (long)(((bytes >> 10) & 0xfffff) + 0x100000 / 200) / (0x100000 / 100));
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solcon_write_solution_diagnostics>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L22:
  cmp    %rdx,%rsp
  je     L28
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L22
L28:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L1
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L1:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xcf,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x3c(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L26
L29:
  mov    -0x30(%rbp),%rax
  mov    -0x40(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%edx
  mov    -0x40(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x50(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x40(%rbp)
L26:
  mov    -0x40(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L29
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x3c(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int solcon_write_solution_diagnostics(int k, int n, char *s) {
  int a[2], b[n], fail, i;
  double *c;
  a[0] = k;
  a[1] = n;
  fail = _ada_use_c2phc4c(207, a, b, c, 0);
  for (i = 0; i < n; i++)
    s[i] = b[i];
  s[n] = '\0';
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<solcon_write_solution_diagnostics>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%r14d
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%r13
  lea    0xf(,%r13,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L42:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L42
L13:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L11
  orq    $0x0,-0x8(%rsp,%rax,1)
L11:
  mov    %rsp,%r12
  mov    %edi,-0x30(%rbp)
  mov    %r14d,-0x2c(%rbp)
  lea    -0x30(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %r12,%rdx
  mov    $0xcf,%edi
  call   <_ada_use_c2phc4c@plt>
  test   %r14d,%r14d
  jle    L22
  mov    %r14d,%esi
  mov    $0x0,%edx
L49:
  mov    (%r12,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L49
L22:
  movb   $0x0,(%rbx,%r13,1)
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_write_solution_diagnostics(int k, int n, char *s) {
  int a[2], b[n], fail, i;
  double *c;
  a[0] = k;
  a[1] = n;
  fail = _ada_use_c2phc4c(207, a, b, c, 0);
  for (i = 0; i < n; i++)
    s[i] = b[i];
  s[n] = '\0';
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<solcon_write_solution_diagnostics>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbx
  mov    %rdx,%rbx
  mov    %r12,%r14
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r12,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L3
L35:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L35
L3:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L54
L40:
  mov    %rsp,%r13
  mov    %edi,-0x30(%rbp)
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  lea    -0x30(%rbp),%rsi
  mov    %r13,%rdx
  mov    $0xcf,%edi
  mov    %r14d,-0x2c(%rbp)
  call   <_ada_use_c2phc4c@plt>
  test   %r14d,%r14d
  jle    L19
  xor    %edx,%edx
  nopl   (%rax)
L60:
  mov    0x0(%r13,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %r12,%rdx
  jne    L60
L19:
  movb   $0x0,(%rbx,%r12,1)
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_write_solution_diagnostics(int k, int n, char *s) {
  int a[2], b[n], fail, i;
  double *c;
  a[0] = k;
  a[1] = n;
  fail = _ada_use_c2phc4c(207, a, b, c, 0);
  for (i = 0; i < n; i++)
    s[i] = b[i];
  s[n] = '\0';
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%ebx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %ebx,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <binarysearch@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("%d\n", binarysearch(argv[1], strlen(argv[1]), argv[2][0]));
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    0x10(%rsi),%rax
  movsbl (%rax),%ebp
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    0x8(%rbx),%rdi
  mov    %ebp,%edx
  call   <binarysearch@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("%d\n", binarysearch(argv[1], strlen(argv[1]), argv[2][0]));
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%rdi
  movsbl (%rax),%r12d
  call   <strlen@plt>
  mov    0x8(%rbx),%rdi
  mov    %r12d,%edx
  mov    %eax,%esi
  call   <binarysearch@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("%d\n", binarysearch(argv[1], strlen(argv[1]), argv[2][0]));
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%rdi
  movsbl (%rax),%r12d
  call   <strlen@plt>
  mov    0x8(%rbx),%rdi
  mov    %r12d,%edx
  mov    %eax,%esi
  call   <binarysearch@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("%d\n", binarysearch(argv[1], strlen(argv[1]), argv[2][0]));
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L2
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L56
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <eprintf@plt>
L56:
  mov    $0x0,%eax
  call   <agetcwd@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  jne    L101
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <eprintf@plt>
  jmp    L101
L59:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L101
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    D46(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L101
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x40(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
L101:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L59
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <eprintf@plt>
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L66
L2:
  nop
L66:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D27
type: string
name: read_data
arguments: data_label: D35
type: string
name: read_data
arguments: data_label: D8
type: string
name: read_data
arguments: data_label: D46
type: string

tool: D27: opendir %s:

tool: D35: chdir %s:

tool: D8: .

tool: D46: ..

assistant: ```c
void recurse(const char *path, void (*fn)(const char *)) {
  char *cwd;
  struct dirent *d;
  struct stat st;
  DIR *dp;
  if (lstat(path, &st) == -1 || !S_ISDIR(st.st_mode)) {
    return;
  } else if (!(dp = opendir(path))) {
    eprintf("opendir %s:", path);
  }
  cwd = agetcwd();
  if (chdir(path) == -1)
    eprintf("chdir %s:", path);
  while ((d = readdir(dp))) {
    if (strcmp(d->d_name, ".") && strcmp(d->d_name, ".."))
      fn(d->d_name);
  }
  closedir(dp);
  if (chdir(cwd) == -1)
    eprintf("chdir %s:", cwd);
  free(cwd);
}
```
user: Translate the below assembly code into C programming language:

```asm
<recurse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  cmp    $0xffffffff,%eax
  je     L33
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L116
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L116:
  mov    %rbx,%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L72
L87:
  mov    $0x0,%eax
  call   <agetcwd@plt>
  mov    %rax,%r14
  mov    %rbx,%rdi
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  je     L57
L50:
  lea    D1(%rip),%r12
  lea    D27(%rip),%r15
L10:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L94
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L10
  mov    %r15,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L10
  mov    (%rbx),%rdi
  call   *%r13
  jmp    L10
L72:
  mov    %rbx,%rsi
  lea    D46(%rip),%rdi
  call   <eprintf@plt>
  jmp    L87
L57:
  mov    %rbx,%rsi
  lea    D49(%rip),%rdi
  call   <eprintf@plt>
  jmp    L50
L94:
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    %r14,%rdi
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  je     L80
L60:
  mov    %r14,%rdi
  call   <free@plt>
  jmp    L33
L80:
  mov    %r14,%rsi
  lea    D49(%rip),%rdi
  call   <eprintf@plt>
  jmp    L60
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D27
datatype: string
name: extract_symbolic_data
arguments: data_label: D46
datatype: string
name: extract_symbolic_data
arguments: data_label: D49
datatype: string

tool: D1: .

tool: D27: ..

tool: D46: opendir %s:

tool: D49: chdir %s:

assistant: ```c
void recurse(const char *path, void (*fn)(const char *)) {
  char *cwd;
  struct dirent *d;
  struct stat st;
  DIR *dp;
  if (lstat(path, &st) == -1 || !S_ISDIR(st.st_mode)) {
    return;
  } else if (!(dp = opendir(path))) {
    eprintf("opendir %s:", path);
  }
  cwd = agetcwd();
  if (chdir(path) == -1)
    eprintf("chdir %s:", path);
  while ((d = readdir(dp))) {
    if (strcmp(d->d_name, ".") && strcmp(d->d_name, ".."))
      fn(d->d_name);
  }
  closedir(dp);
  if (chdir(cwd) == -1)
    eprintf("chdir %s:", cwd);
  free(cwd);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<recurse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  cmp    $0xffffffff,%eax
  je     L122
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L47
L122:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L145
L28:
  xor    %eax,%eax
  call   <agetcwd@plt>
  mov    %r12,%rdi
  mov    %rax,%r14
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  je     L94
L11:
  lea    D42(%rip),%r12
  lea    D24(%rip),%r15
  jmp    L41
  nop
L82:
  mov    (%rbx),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
L41:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L82
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    %r14,%rdi
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  je     L65
L127:
  mov    %r14,%rdi
  call   <free@plt>
  jmp    L122
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L41
  mov    (%rbx),%rdi
  call   *%r13
  jmp    L41
L65:
  mov    %r14,%rsi
  lea    D46(%rip),%rdi
  call   <eprintf@plt>
  jmp    L127
  nopl   0x0(%rax)
L94:
  mov    %r12,%rsi
  lea    D46(%rip),%rdi
  call   <eprintf@plt>
  jmp    L11
L145:
  mov    %r12,%rsi
  lea    D15(%rip),%rdi
  call   <eprintf@plt>
  jmp    L28
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D42
type_infered: string
name: parse_data
arguments: data_tag: D24
type_infered: string
name: parse_data
arguments: data_tag: D46
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string

tool: D42: .

tool: D24: ..

tool: D46: chdir %s:

tool: D15: opendir %s:

assistant: ```c
void recurse(const char *path, void (*fn)(const char *)) {
  char *cwd;
  struct dirent *d;
  struct stat st;
  DIR *dp;
  if (lstat(path, &st) == -1 || !S_ISDIR(st.st_mode)) {
    return;
  } else if (!(dp = opendir(path))) {
    eprintf("opendir %s:", path);
  }
  cwd = agetcwd();
  if (chdir(path) == -1)
    eprintf("chdir %s:", path);
  while ((d = readdir(dp))) {
    if (strcmp(d->d_name, ".") && strcmp(d->d_name, ".."))
      fn(d->d_name);
  }
  closedir(dp);
  if (chdir(cwd) == -1)
    eprintf("chdir %s:", cwd);
  free(cwd);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<recurse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  cmp    $0xffffffff,%eax
  je     L74
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L141
L74:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L139
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L141:
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L58
L149:
  xor    %eax,%eax
  call   <agetcwd@plt>
  mov    %r12,%rdi
  mov    %rax,%r14
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  je     L47
L120:
  lea    D39(%rip),%r12
  lea    D22(%rip),%r15
  jmp    L132
  nop
L92:
  mov    (%rbx),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L114
L132:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L92
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    %r14,%rdi
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  je     L137
L34:
  mov    %r14,%rdi
  call   <free@plt>
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L114:
  mov    (%rbx),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L132
  mov    (%rbx),%rdi
  call   *%r13
  jmp    L132
L137:
  mov    %r14,%rsi
  lea    D16(%rip),%rdi
  call   <eprintf@plt>
  jmp    L34
  nopl   0x0(%rax)
L47:
  mov    %r12,%rsi
  lea    D16(%rip),%rdi
  call   <eprintf@plt>
  jmp    L120
L58:
  mov    %r12,%rsi
  lea    D21(%rip),%rdi
  call   <eprintf@plt>
  jmp    L149
L139:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_guessed: string
name: unpack_data
arguments: data_label: D22
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D21
type_guessed: string

tool: D39: .

tool: D22: ..

tool: D16: chdir %s:

tool: D21: opendir %s:

assistant: ```c
void recurse(const char *path, void (*fn)(const char *)) {
  char *cwd;
  struct dirent *d;
  struct stat st;
  DIR *dp;
  if (lstat(path, &st) == -1 || !S_ISDIR(st.st_mode)) {
    return;
  } else if (!(dp = opendir(path))) {
    eprintf("opendir %s:", path);
  }
  cwd = agetcwd();
  if (chdir(path) == -1)
    eprintf("chdir %s:", path);
  while ((d = readdir(dp))) {
    if (strcmp(d->d_name, ".") && strcmp(d->d_name, ".."))
      fn(d->d_name);
  }
  closedir(dp);
  if (chdir(cwd) == -1)
    eprintf("chdir %s:", cwd);
  free(cwd);
}
```