user: 这段汇编代码用C语言表示是什么样的?

```asm
<float_i2f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x94(%rbp),%eax
  and    $0x80000000,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x33000000,-0x84(%rbp)
  movl   $0x0,-0x80(%rbp)
  movl   $0x0,-0x7c(%rbp)
  movl   $0x0,-0x78(%rbp)
  cmpl   $0x0,-0x94(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L77
L13:
  cmpl   $0x0,-0xc(%rbp)
  je     L41
  negq   -0x8(%rbp)
L41:
  shlq   $0x17,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0x70(%rbp)
  jmp    L33
L36:
  addl   $0x800000,-0x84(%rbp)
  cmpl   $0x0,-0x7c(%rbp)
  je     L46
  movl   $0x1,-0x80(%rbp)
L46:
  mov    -0x78(%rbp),%eax
  mov    %eax,-0x7c(%rbp)
  shrq   -0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  mov    %eax,-0x78(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x40(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,-0x48(%rbp)
  mov    -0x50(%rbp),%eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x50(%rbp)
  mov    -0x58(%rbp),%eax
  mov    %eax,-0x54(%rbp)
  mov    -0x5c(%rbp),%eax
  mov    %eax,-0x58(%rbp)
  mov    -0x60(%rbp),%eax
  mov    %eax,-0x5c(%rbp)
  mov    -0x64(%rbp),%eax
  mov    %eax,-0x60(%rbp)
  mov    -0x68(%rbp),%eax
  mov    %eax,-0x64(%rbp)
  mov    -0x6c(%rbp),%eax
  mov    %eax,-0x68(%rbp)
  mov    -0x70(%rbp),%eax
  mov    %eax,-0x6c(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0x70(%rbp)
  cmpl   $0x0,-0x7c(%rbp)
  je     L33
  mov    -0x80(%rbp),%eax
  mov    %eax,-0x74(%rbp)
  cmpl   $0x0,-0x78(%rbp)
  je     L51
  movl   $0x1,-0x74(%rbp)
L51:
  cmpl   $0x0,-0x74(%rbp)
  je     L33
  addl   $0x1,-0x70(%rbp)
L33:
  cmpq   $0x0,-0x8(%rbp)
  jne    L36
  mov    -0xc(%rbp),%eax
  xor    -0x84(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
L77:
  leave
  ret
```

assistant: ```c
unsigned float_i2f(int x) {
  unsigned long long lx = x;
  int sign = x & 0x80000000;
  int exp = 0x33000000;
  int round = 0;
  int last = 0;
  int now = 0;
  int tempround;
  int lans0, lans1, lans2, lans3, lans4, lans5, lans6, lans7, lans8, lans9, lans10, lans11, lans12, lans13, lans14, lans15, lans16, lans17, lans18, lans19, lans20, lans21, lans22, lans23, lans24;
  if (x)
    ;
  else
    return 0;
  if (sign)
    lx = -lx;
  lx <<= 23;
  lans0 = lx;
  while (lx) {
    exp += 0x800000;
    if (last)
      round = 1;
    last = now;
    lx >>= 1;
    now = lx & 1;
    lans24 = lans23;
    lans23 = lans22;
    lans22 = lans21;
    lans21 = lans20;
    lans20 = lans19;
    lans19 = lans18;
    lans18 = lans17;
    lans17 = lans16;
    lans16 = lans15;
    lans15 = lans14;
    lans14 = lans13;
    lans13 = lans12;
    lans12 = lans11;
    lans11 = lans10;
    lans10 = lans9;
    lans9 = lans8;
    lans8 = lans7;
    lans7 = lans6;
    lans6 = lans5;
    lans5 = lans4;
    lans4 = lans3;
    lans3 = lans2;
    lans2 = lans1;
    lans1 = lans0;
    lans0 = lx;
    if (last) {
      tempround = round;
      if (now)
        tempround = 1;
      if (tempround)
        ++lans0;
    }
  }
  return (sign ^ exp) + lans24;
}
```