ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<uws_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <uws_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *uws_calloc(size_t nmemb, size_t size) {
  int s = nmemb * size;
  void *p = uws_malloc(s);
  bzero(p, s);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uws_calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  imul   %esi,%ebp
  mov    %ebp,%edi
  call   <uws_malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *uws_calloc(size_t nmemb, size_t size) {
  int s = nmemb * size;
  void *p = uws_malloc(s);
  bzero(p, s);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uws_calloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  imul   %esi,%ebp
  sub    $0x8,%rsp
  mov    %ebp,%edi
  call   <uws_malloc@plt>
  mov    %ebp,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <bzero@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *uws_calloc(size_t nmemb, size_t size) {
  int s = nmemb * size;
  void *p = uws_malloc(s);
  bzero(p, s);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uws_calloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  imul   %esi,%ebp
  sub    $0x8,%rsp
  mov    %ebp,%edi
  call   <uws_malloc@plt>
  mov    %ebp,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <bzero@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *uws_calloc(size_t nmemb, size_t size) {
  int s = nmemb * size;
  void *p = uws_malloc(s);
  bzero(p, s);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  D18(%rip),%xmm0
  mov    D13(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fpTest@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
datatype: f64
name: retrieve_data
arguments: label: D13
datatype: f64

tool: D18: 45

tool: D13: 35.7

assistant: ```c
int main() {
  fpTest(35.7, 45.0);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D14(%rip),%xmm1
  movsd  D6(%rip),%xmm0
  call   <fpTest@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: f64
name: read_data
arguments: data_tag: D6
datatype: f64

tool: D14: 45

tool: D6: 35.7

assistant: ```c
int main() {
  fpTest(35.7, 45.0);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D18(%rip),%xmm1
  movsd  D13(%rip),%xmm0
  call   <fpTest@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: f64
name: retrieve_data
arguments: tag: D13
data_type: f64

tool: D18: 45

tool: D13: 35.7

assistant: ```c
int main() {
  fpTest(35.7, 45.0);
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D18(%rip),%xmm1
  movsd  D16(%rip),%xmm0
  call   <fpTest@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type_guessed: f64
name: parse_data
arguments: tag: D16
type_guessed: f64

tool: D18: 45

tool: D16: 35.7

assistant: ```c
int main() {
  fpTest(35.7, 45.0);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numbtrop_standard_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2d0,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int numbtrop_standard_size(int *nbt) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(720, nbt, b, c);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<numbtrop_standard_size>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x2d0,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int numbtrop_standard_size(int *nbt) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(720, nbt, b, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<numbtrop_standard_size>:
  endbr64
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x2d0,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int numbtrop_standard_size(int *nbt) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(720, nbt, b, c);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numbtrop_standard_size>:
  endbr64
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x2d0,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int numbtrop_standard_size(int *nbt) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(720, nbt, b, c);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<logCauchy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D14(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: f64
name: disassemble_data
arguments: data_label: D14
type_infered: byte[8]

tool: D1: 3.141592653589793

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double logCauchy(double x, double mu, double sigma) {
  double diff = log(x) - mu;
  return 1 / (x * 3.14159265358979323846) * sigma / (diff * diff + sigma * sigma);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<logCauchy>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  movsd  %xmm2,0x8(%rsp)
  call   <log@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm5
  subsd  %xmm5,%xmm1
  movq   %rbx,%xmm3
  mulsd  D6(%rip),%xmm3
  movsd  D11(%rip),%xmm2
  movapd %xmm2,%xmm0
  divsd  %xmm3,%xmm0
  movsd  0x8(%rsp),%xmm4
  mulsd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm1
  movapd %xmm4,%xmm2
  mulsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: f64
name: unpack_data
arguments: label: D11
data_type: byte[8]

tool: D6: 3.141592653589793

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double logCauchy(double x, double mu, double sigma) {
  double diff = log(x) - mu;
  return 1 / (x * 3.14159265358979323846) * sigma / (diff * diff + sigma * sigma);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<logCauchy>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm0,0x10(%rsp)
  call   <log@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  D19(%rip),%xmm4
  subsd  0x8(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm2
  mulsd  %xmm3,%xmm4
  movsd  D9(%rip),%xmm3
  add    $0x28,%rsp
  movapd %xmm0,%xmm1
  mulsd  %xmm1,%xmm1
  divsd  %xmm4,%xmm3
  movapd %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type_infered: f64
name: read_data
arguments: data_tag: D9
type_infered: byte[8]

tool: D19: 3.141592653589793

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double logCauchy(double x, double mu, double sigma) {
  double diff = log(x) - mu;
  return 1 / (x * 3.14159265358979323846) * sigma / (diff * diff + sigma * sigma);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<logCauchy>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm0,0x10(%rsp)
  call   <log@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  D15(%rip),%xmm4
  subsd  0x8(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm2
  mulsd  %xmm3,%xmm4
  movsd  D5(%rip),%xmm3
  add    $0x28,%rsp
  movapd %xmm0,%xmm1
  mulsd  %xmm1,%xmm1
  divsd  %xmm4,%xmm3
  movapd %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type_guessed: f64
name: read_data
arguments: tag: D5
type_guessed: byte[8]

tool: D15: 3.141592653589793

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double logCauchy(double x, double mu, double sigma) {
  double diff = log(x) - mu;
  return 1 / (x * 3.14159265358979323846) * sigma / (diff * diff + sigma * sigma);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int y = 0;
  int *x = calloc(1, sizeof(int));
  free(x);
  y += x[0];
  sleep(1);
  y += x[0];
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <free@plt>
  mov    (%rbx),%ebp
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %ebp,%eax
  add    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int y = 0;
  int *x = calloc(1, sizeof(int));
  free(x);
  y += x[0];
  sleep(1);
  y += x[0];
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  mov    $0x1,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <free@plt>
  mov    $0x1,%edi
  mov    (%rbx),%ebp
  call   <sleep@plt>
  mov    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int y = 0;
  int *x = calloc(1, sizeof(int));
  free(x);
  y += x[0];
  sleep(1);
  y += x[0];
  return y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  mov    $0x1,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <free@plt>
  mov    $0x1,%edi
  mov    (%rbx),%ebp
  call   <sleep@plt>
  mov    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int y = 0;
  int *x = calloc(1, sizeof(int));
  free(x);
  y += x[0];
  sleep(1);
  y += x[0];
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sappend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *sappend(const char *left, const char *right, const int right_len) {
  size_t ls = strlen(left);
  size_t rs = (size_t)right_len;
  char *ss = (char *)malloc(ls + rs + 1);
  memcpy(ss, left, ls);
  memcpy(ss + ls, right, rs);
  ss[ls + rs] = '\0';
  return ss;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sappend>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r13
  mov    %edx,%r12d
  call   <strlen@plt>
  mov    %rax,%rbx
  movslq %r12d,%r12
  lea    (%rax,%r12,1),%r14
  lea    0x1(%r14),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%r14,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *sappend(const char *left, const char *right, const int right_len) {
  size_t ls = strlen(left);
  size_t rs = (size_t)right_len;
  char *ss = (char *)malloc(ls + rs + 1);
  memcpy(ss, left, ls);
  memcpy(ss + ls, right, rs);
  ss[ls + rs] = '\0';
  return ss;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sappend>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    (%rax,%r13,1),%r15
  mov    %rax,%rbx
  lea    0x1(%r15),%rdi
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%r15,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *sappend(const char *left, const char *right, const int right_len) {
  size_t ls = strlen(left);
  size_t rs = (size_t)right_len;
  char *ss = (char *)malloc(ls + rs + 1);
  memcpy(ss, left, ls);
  memcpy(ss + ls, right, rs);
  ss[ls + rs] = '\0';
  return ss;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sappend>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    (%rax,%r13,1),%r15
  mov    %rax,%rbx
  lea    0x1(%r15),%rdi
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%r15,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *sappend(const char *left, const char *right, const int right_len) {
  size_t ls = strlen(left);
  size_t rs = (size_t)right_len;
  char *ss = (char *)malloc(ls + rs + 1);
  memcpy(ss, left, ls);
  memcpy(ss + ls, right, rs);
  ss[ls + rs] = '\0';
  return ss;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<expandp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L50
L89:
  cmpb   $0x1f,-0x1(%rbp)
  jle    L56
  cmpb   $0x7f,-0x1(%rbp)
  jne    L31
L56:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x5e,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl -0x1(%rbp),%edx
  xor    $0x40,%edx
  mov    %dl,(%rax)
  subl   $0x2,-0x24(%rbp)
  jmp    L86
L31:
  cmpb   $0x25,-0x1(%rbp)
  jne    L66
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x25,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x25,(%rax)
  subl   $0x2,-0x24(%rbp)
  jmp    L86
L66:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x24(%rbp)
L86:
  cmpl   $0x3,-0x24(%rbp)
  jg     L50
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x24,(%rax)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L76
L50:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L89
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
L76:
  pop    %rbp
  ret
```

assistant: ```c
void expandp(char *srcstr, char *deststr, int maxlength) {
  char c;
  while ((c = *srcstr++) != 0) {
    if (c < 0x20 || c == 0x7f) {
      *deststr++ = '^';
      *deststr++ = c ^ 0x40;
      maxlength -= 2;
    } else if (c == '%') {
      *deststr++ = '%';
      *deststr++ = '%';
      maxlength -= 2;
    } else {
      *deststr++ = c;
      maxlength--;
    }
    if (maxlength < 4) {
      *deststr++ = '$';
      *deststr = '\0';
      return;
    }
  }
  *deststr = '\0';
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<expandp>:
  endbr64
  jmp    L9
L59:
  cmp    $0x25,%al
  je     L65
  mov    %al,(%rsi)
  sub    $0x1,%edx
  lea    0x1(%rsi),%rsi
L27:
  cmp    $0x3,%edx
  jle    L39
L9:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L2
  lea    -0x20(%rax),%ecx
  cmp    $0x5e,%cl
  jbe    L59
  movb   $0x5e,(%rsi)
  xor    $0x40,%eax
  mov    %al,0x1(%rsi)
  sub    $0x2,%edx
  lea    0x2(%rsi),%rsi
  jmp    L27
L65:
  movb   $0x25,(%rsi)
  movb   $0x25,0x1(%rsi)
  sub    $0x2,%edx
  lea    0x2(%rsi),%rsi
  jmp    L27
L39:
  movb   $0x24,(%rsi)
  movb   $0x0,0x1(%rsi)
  ret
L2:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void expandp(char *srcstr, char *deststr, int maxlength) {
  char c;
  while ((c = *srcstr++) != 0) {
    if (c < 0x20 || c == 0x7f) {
      *deststr++ = '^';
      *deststr++ = c ^ 0x40;
      maxlength -= 2;
    } else if (c == '%') {
      *deststr++ = '%';
      *deststr++ = '%';
      maxlength -= 2;
    } else {
      *deststr++ = c;
      maxlength--;
    }
    if (maxlength < 4) {
      *deststr++ = '$';
      *deststr = '\0';
      return;
    }
  }
  *deststr = '\0';
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<expandp>:
  endbr64
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L39:
  xor    $0x40,%eax
  movb   $0x5e,(%rsi)
  sub    $0x2,%edx
  add    $0x2,%rsi
  mov    %al,-0x1(%rsi)
L24:
  cmp    $0x3,%edx
  jle    L29
L11:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L56
  lea    -0x20(%rax),%ecx
  cmp    $0x5e,%cl
  ja     L39
  cmp    $0x25,%al
  je     L2
  sub    $0x1,%edx
  mov    %al,(%rsi)
  add    $0x1,%rsi
  cmp    $0x3,%edx
  jg     L11
L29:
  mov    $0x24,%eax
  mov    %ax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x2525,%ecx
  sub    $0x2,%edx
  add    $0x2,%rsi
  mov    %cx,-0x2(%rsi)
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L56:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void expandp(char *srcstr, char *deststr, int maxlength) {
  char c;
  while ((c = *srcstr++) != 0) {
    if (c < 0x20 || c == 0x7f) {
      *deststr++ = '^';
      *deststr++ = c ^ 0x40;
      maxlength -= 2;
    } else if (c == '%') {
      *deststr++ = '%';
      *deststr++ = '%';
      maxlength -= 2;
    } else {
      *deststr++ = c;
      maxlength--;
    }
    if (maxlength < 4) {
      *deststr++ = '$';
      *deststr = '\0';
      return;
    }
  }
  *deststr = '\0';
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<expandp>:
  endbr64
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L32:
  xor    $0x40,%eax
  movb   $0x5e,(%rsi)
  sub    $0x2,%edx
  add    $0x2,%rsi
  mov    %al,-0x1(%rsi)
L28:
  cmp    $0x3,%edx
  jle    L8
L3:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L53
  lea    -0x20(%rax),%ecx
  cmp    $0x5e,%cl
  ja     L32
  cmp    $0x25,%al
  je     L46
  sub    $0x1,%edx
  mov    %al,(%rsi)
  add    $0x1,%rsi
  cmp    $0x3,%edx
  jg     L3
L8:
  mov    $0x24,%eax
  mov    %ax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    $0x2525,%ecx
  sub    $0x2,%edx
  add    $0x2,%rsi
  mov    %cx,-0x2(%rsi)
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L53:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void expandp(char *srcstr, char *deststr, int maxlength) {
  char c;
  while ((c = *srcstr++) != 0) {
    if (c < 0x20 || c == 0x7f) {
      *deststr++ = '^';
      *deststr++ = c ^ 0x40;
      maxlength -= 2;
    } else if (c == '%') {
      *deststr++ = '%';
      *deststr++ = '%';
      maxlength -= 2;
    } else {
      *deststr++ = c;
      maxlength--;
    }
    if (maxlength < 4) {
      *deststr++ = '$';
      *deststr = '\0';
      return;
    }
  }
  *deststr = '\0';
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<HSMMCSDIsIntClockStable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  add    $0x22c,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  shr    %eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x1,%eax
  je     L11
  cmpl   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L3
L11:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int HSMMCSDIsIntClockStable(unsigned int baseAddr, unsigned int retry) {
  volatile unsigned int status = 0;
  do {
    status = ((*((volatile unsigned int *)(baseAddr + (0x22C)))) & (0x00000002u)) >> (0x00000001u);
    if ((status == 1) || (retry == 0)) {
      break;
    }
  } while (retry--);
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HSMMCSDIsIntClockStable>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  lea    0x22c(%rdi),%edx
  mov    0x22c(%edi),%eax
  shr    %eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  test   %esi,%esi
  je     L6
  cmp    $0x1,%eax
  je     L6
L0:
  mov    (%rdx),%eax
  shr    %eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  sub    $0x1,%esi
  je     L6
  cmp    $0x1,%eax
  jne    L0
L6:
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
unsigned int HSMMCSDIsIntClockStable(unsigned int baseAddr, unsigned int retry) {
  volatile unsigned int status = 0;
  do {
    status = ((*((volatile unsigned int *)(baseAddr + (0x22C)))) & (0x00000002u)) >> (0x00000001u);
    if ((status == 1) || (retry == 0)) {
      break;
    }
  } while (retry--);
  return status;
}
```