ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  xor    %r14d,%r14d
  mov    %r8,%r13
  mov    %rdi,%rbp
  mov    %edx,%r15d
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  mov    %esi,%r12d
  call   <wattron@plt>
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  lea    0x10(%rsp),%rcx
  mov    %r13,%rsi
  mov    %r14d,%edx
  mov    %rcx,%rdi
  mov    %rcx,0x8(%rsp)
  call   <vsprintf@plt>
  mov    0x8(%rsp),%rcx
  mov    %r15d,%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <mvwprintw@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <wattroff@plt>
  mov    0x1018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x1028,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wprintf(WINDOW *win, int attr, int y, int x, const char *format, ...) {
  char dest[4096];
  wattron(win, attr);
  va_list argptr;
  va_start(argptr, format);
  vsprintf(dest, format, argptr);
  int ret = mvwprintw(win, y, x, dest);
  va_end(argptr);
  wattroff(win, attr);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  xor    %r14d,%r14d
  mov    %r8,%r13
  mov    %rdi,%rbp
  mov    %edx,%r15d
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  mov    %esi,%r12d
  call   <wattron@plt>
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  lea    0x10(%rsp),%rcx
  mov    %r13,%rsi
  mov    %r14d,%edx
  mov    %rcx,%rdi
  mov    %rcx,0x8(%rsp)
  call   <vsprintf@plt>
  mov    0x8(%rsp),%rcx
  mov    %r15d,%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <mvwprintw@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <wattroff@plt>
  mov    0x1018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1028,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int wprintf(WINDOW *win, int attr, int y, int x, const char *format, ...) {
  char dest[4096];
  wattron(win, attr);
  va_list argptr;
  va_start(argptr, format);
  vsprintf(dest, format, argptr);
  int ret = mvwprintw(win, y, x, dest);
  va_end(argptr);
  wattroff(win, attr);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skip_white>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L14
L8:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
L10:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *skip_white(const char *line) {
  while (*line && isspace(*line))
    line++;
  return line;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skip_white>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  mov    %rbx,%rax
  test   %dil,%dil
  je     L33
L36:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L1
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L36
  mov    %rbx,%rax
  jmp    L33
L1:
  mov    %rbx,%rax
L33:
  pop    %rbx
  ret
```

assistant: ```c
const char *skip_white(const char *line) {
  while (*line && isspace(*line))
    line++;
  return line;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_white>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L38
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L19:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L37
L38:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
L37:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *skip_white(const char *line) {
  while (*line && isspace(*line))
    line++;
  return line;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skip_white>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L20
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L17
L20:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
L17:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *skip_white(const char *line) {
  while (*line && isspace(*line))
    line++;
  return line;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ez_def_mutex_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void ez_def_mutex_destroy(void *_mutex) {
  free(_mutex);
  _mutex = ((void *)0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ez_def_mutex_destroy>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ez_def_mutex_destroy(void *_mutex) {
  free(_mutex);
  _mutex = ((void *)0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ez_def_mutex_destroy>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void ez_def_mutex_destroy(void *_mutex) {
  free(_mutex);
  _mutex = ((void *)0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ez_def_mutex_destroy>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void ez_def_mutex_destroy(void *_mutex) {
  free(_mutex);
  _mutex = ((void *)0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L34:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L1
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
L1:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L34
  cmpl   $0x1,-0x4(%rbp)
  jne    L36
  mov    $0x1,%eax
  jmp    L44
L36:
  mov    $0x0,%eax
L44:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: %d-%d - not equal


assistant: ```c
int check(char str[], int i, int pos) {
  int j, k;
  int flag = 0;
  for (j = i + 1, k = pos + 1; j < pos; j++, k++) {
    if (str[j] != str[k]) {
      printf("%d-%d - not equal\n", j, k);
      flag = 1;
    }
  }
  if (flag == 1) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<check>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  cmp    %edx,%ebx
  jge    L38
  mov    %rdi,%r12
  lea    0x1(%rdx),%ebp
  movslq %ebx,%rbx
  movslq %ebp,%rbp
  sub    $0x2,%edx
  sub    %esi,%edx
  movslq %esi,%rsi
  lea    0x2(%rdx,%rsi,1),%r13
  mov    $0x0,%eax
  lea    D9(%rip),%r14
  jmp    L32
L16:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  je     L45
L32:
  mov    %ebp,%edx
  mov    %ebx,%esi
  movzbl (%r12,%rbp,1),%ecx
  cmp    %cl,(%r12,%rbx,1)
  je     L16
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L16
L38:
  mov    $0x0,%eax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: %d-%d - not equal


assistant: ```c
int check(char str[], int i, int pos) {
  int j, k;
  int flag = 0;
  for (j = i + 1, k = pos + 1; j < pos; j++, k++) {
    if (str[j] != str[k]) {
      printf("%d-%d - not equal\n", j, k);
      flag = 1;
    }
  }
  if (flag == 1) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  cmp    %edx,%ebx
  jge    L0
  lea    0x1(%rdx),%ebp
  sub    $0x2,%edx
  mov    %rdi,%r12
  movslq %ebx,%rbx
  sub    %esi,%edx
  movslq %esi,%rsi
  movslq %ebp,%rbp
  xor    %eax,%eax
  lea    0x2(%rdx,%rsi,1),%r13
  lea    D5(%rip),%r14
  nopl   (%rax)
L7:
  movzbl (%r12,%rbp,1),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  cmp    %cl,(%r12,%rbx,1)
  je     L20
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L20:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: %d-%d - not equal


assistant: ```c
int check(char str[], int i, int pos) {
  int j, k;
  int flag = 0;
  for (j = i + 1, k = pos + 1; j < pos; j++, k++) {
    if (str[j] != str[k]) {
      printf("%d-%d - not equal\n", j, k);
      flag = 1;
    }
  }
  if (flag == 1) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<check>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  cmp    %edx,%ebx
  jge    L7
  lea    0x1(%rdx),%ebp
  sub    $0x2,%edx
  mov    %rdi,%r12
  movslq %ebx,%rbx
  sub    %esi,%edx
  movslq %esi,%rsi
  movslq %ebp,%rbp
  xor    %eax,%eax
  lea    0x2(%rdx,%rsi,1),%r13
  lea    D9(%rip),%r14
  nopl   (%rax)
L1:
  movzbl (%r12,%rbp,1),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  cmp    %cl,(%r12,%rbx,1)
  je     L5
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L5:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9: %d-%d - not equal


assistant: ```c
int check(char str[], int i, int pos) {
  int j, k;
  int flag = 0;
  for (j = i + 1, k = pos + 1; j < pos; j++, k++) {
    if (str[j] != str[k]) {
      printf("%d-%d - not equal\n", j, k);
      flag = 1;
    }
  }
  if (flag == 1) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stdbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdi,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x8(%rbp)
  xor    %edx,%edx
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    %rdx,-0x18(%rbp)
  add    $0x8,%rax
  movl   $0x0,-0x1c(%rbp)
  jmp    L19
L16:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,-0x18(%rbp)
  sub    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x1c(%rbp)
L19:
  cmpl   $0x7,-0x1c(%rbp)
  jle    L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int stdbl(val, p)
double val;
register char *p;
{
  union {
    double rval;
    char sval[8];
  } x;
  char *q;
  int i;
  x.rval = val;
  q = x.sval;
  p += 8;
  for (i = 0; i < 8; i++)
    *--p = *q++;
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stdbl>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  add    $0x8,%rdi
  mov    %rsp,%rax
  lea    0x8(%rsp),%rcx
L4:
  add    $0x1,%rax
  sub    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  mov    %dl,(%rdi)
  cmp    %rcx,%rax
  jne    L4
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int stdbl(val, p)
double val;
register char *p;
{
  union {
    double rval;
    char sval[8];
  } x;
  char *q;
  int i;
  x.rval = val;
  q = x.sval;
  p += 8;
  for (i = 0; i < 8; i++)
    *--p = *q++;
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stdbl>:
  endbr64
  sub    $0x18,%rsp
  add    $0x8,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  movsd  %xmm0,(%rsp)
  mov    %rsp,%rax
  nopl   0x0(%rax)
L0:
  movzbl (%rax),%edx
  add    $0x1,%rax
  sub    $0x1,%rdi
  mov    %dl,(%rdi)
  cmp    %rcx,%rax
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int stdbl(val, p)
double val;
register char *p;
{
  union {
    double rval;
    char sval[8];
  } x;
  char *q;
  int i;
  x.rval = val;
  q = x.sval;
  p += 8;
  for (i = 0; i < 8; i++)
    *--p = *q++;
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stdbl>:
  endbr64
  movq   %xmm0,%rdx
  push   %rbx
  movq   %xmm0,%r10
  movd   %xmm0,%r9d
  movzbl %dl,%eax
  movzbl %dh,%ebx
  shr    $0x10,%r10
  movq   %xmm0,%r8
  shl    $0x8,%rax
  and    $0xff,%r10d
  sar    $0x18,%r9d
  movq   %xmm0,%rsi
  or     %rbx,%rax
  movzbl %r9b,%r9d
  shl    $0x18,%r8
  movq   %xmm0,%rcx
  shl    $0x8,%rax
  shr    $0x38,%r8
  pop    %rbx
  shl    $0x10,%rsi
  or     %r10,%rax
  shl    $0x8,%rcx
  shl    $0x8,%rax
  shr    $0x38,%rsi
  shr    $0x38,%rcx
  or     %r9,%rax
  shr    $0x38,%rdx
  shl    $0x8,%rax
  or     %r8,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int stdbl(val, p)
double val;
register char *p;
{
  union {
    double rval;
    char sval[8];
  } x;
  char *q;
  int i;
  x.rval = val;
  q = x.sval;
  p += 8;
  for (i = 0; i < 8; i++)
    *--p = *q++;
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fisher0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x18(%rbp),%r9
  lea    -0x20(%rbp),%r8
  mov    -0x30(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  sub    $0x8,%rsp
  lea    -0x10(%rbp),%rdi
  push   %rdi
  mov    %eax,%edi
  call   <fisher@plt>
  add    $0x10,%rsp
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double fisher0(int a, int b, int c, int d) {
  double p_left = 0;
  double p_right = 0;
  double p_twotail = 0;
  fisher(a, b, c, d, &p_left, &p_right, &p_twotail);
  return p_left;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fisher0>:
  endbr64
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <fisher@plt>
  movsd  0x10(%rsp),%xmm0
  add    $0x10,%rsp
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double fisher0(int a, int b, int c, int d) {
  double p_left = 0;
  double p_right = 0;
  double p_twotail = 0;
  fisher(a, b, c, d, &p_left, &p_right, &p_twotail);
  return p_left;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fisher0>:
  endbr64
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <fisher@plt>
  movsd  0x10(%rsp),%xmm0
  pop    %rax
  pop    %rdx
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double fisher0(int a, int b, int c, int d) {
  double p_left = 0;
  double p_right = 0;
  double p_twotail = 0;
  fisher(a, b, c, d, &p_left, &p_right, &p_twotail);
  return p_left;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fisher0>:
  endbr64
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <fisher@plt>
  movsd  0x10(%rsp),%xmm0
  pop    %rax
  pop    %rdx
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double fisher0(int a, int b, int c, int d) {
  double p_left = 0;
  double p_right = 0;
  double p_twotail = 0;
  fisher(a, b, c, d, &p_left, &p_right, &p_twotail);
  return p_left;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int getch(void) {
  char ch;
  read(0, &ch, 1);
  return ch;
}
```
user: What is the c source code of the assembly code below?

```asm
<getch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%edi
  call   <read@plt>
  movsbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getch(void) {
  char ch;
  read(0, &ch, 1);
  return ch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getch>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <read@plt>
  movsbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getch(void) {
  char ch;
  read(0, &ch, 1);
  return ch;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getch>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <read@plt>
  movsbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getch(void) {
  char ch;
  read(0, &ch, 1);
  return ch;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  cmpl   $0x0,(%rsp)
  jle    L108
  mov    %rax,%r13
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    D0(%rip),%r14
  jmp    L112
L32:
  movl   $0x1,0x0(%r13,%rax,1)
  jmp    L17
L47:
  movslq %ebp,%rax
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%ebp
  movl   $0x0,0x0(%r13,%rax,4)
L17:
  add    $0x1,%r12d
  cmp    %r12d,(%rsp)
  jle    L124
L112:
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  test   %ebp,%ebp
  jle    L47
  mov    0x4(%rsp),%ecx
  mov    %ebp,%edx
  shl    $0x2,%rdx
  mov    $0x0,%eax
L22:
  cmp    %ecx,(%rbx,%rax,1)
  je     L32
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L22
  jmp    L47
L124:
  test   %ebp,%ebp
  jle    L108
  mov    %r13,%rax
  lea    -0x1(%rbp),%edx
  lea    0x4(%r13,%rdx,4),%rdx
  mov    $0x0,%esi
L55:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L55
  test   %esi,%esi
  jg     L90
L108:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L119
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L90:
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L108
L119:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
type_infered: string
name: parse_data
arguments: tag: D0
type_infered: string
name: parse_data
arguments: tag: D32
type_infered: string

tool: D17: Entre com N: 

tool: D0: %d

tool: D32: 
%d repetidos

assistant: ```c
int main() {
  int N, repetidos = 0;
  printf("Entre com N: ");
  scanf("%d", &N);
  int *v1 = malloc(N * sizeof(int));
  int *flag = malloc(N * sizeof(int));
  int cont = 0;
  for (int i = 0; i < N; i++) {
    int valor = 0;
    scanf("%d", &valor);
    int achou = 0;
    for (int j = 0; j < cont; j++) {
      if (valor == v1[j]) {
        flag[j] = 1;
        achou = 1;
        break;
      }
    }
    if (!achou) {
      v1[cont] = valor;
      flag[cont++] = 0;
    }
  }
  for (int i = 0; i < cont; i++)
    repetidos += flag[i];
  if (repetidos > 0)
    printf("\n%d repetidos", repetidos);
}
```