ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atol>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L109
  cmp    $0x9,%al
  jne    L93
L109:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L109
  cmp    $0x9,%al
  je     L109
L93:
  cmp    $0x2d,%al
  je     L40
  mov    $0x0,%esi
  cmp    $0x2b,%al
  je     L19
L95:
  movzbl (%rdi),%eax
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L59
  mov    $0x0,%ecx
L57:
  add    $0x1,%rdi
  lea    (%rcx,%rcx,4),%rdx
  movsbq %al,%rax
  lea    -0x30(%rax,%rdx,2),%rcx
  movzbl (%rdi),%eax
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L57
L70:
  mov    %rcx,%rax
  neg    %rax
  test   %esi,%esi
  cmovne %rax,%rcx
  mov    %rcx,%rax
  ret
L40:
  add    $0x1,%rdi
  mov    $0x1,%esi
  jmp    L95
L19:
  add    $0x1,%rdi
  jmp    L95
L59:
  mov    $0x0,%ecx
  jmp    L70
```

assistant: ```c
long atol(cp)
register char *cp;
{
  long n;
  register sign;
  while (*cp == ' ' || *cp == '\t')
    ++cp;
  sign = 0;
  if (*cp == '-') {
    sign = 1;
    ++cp;
  } else if (*cp == '+')
    ++cp;
  for (n = 0; isdigit(*cp);)
    n = n * 10 + *cp++ - '0';
  return sign ? -n : n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atol>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L20
  nop
L41:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L41
L20:
  cmp    $0x9,%dl
  je     L41
  cmp    $0x2d,%dl
  je     L86
  cmp    $0x2b,%dl
  je     L33
  movsbq (%rax),%rcx
  mov    %rcx,%rdx
  sub    $0x30,%ecx
  cmp    $0x9,%ecx
  ja     L6
  xor    %edi,%edi
L18:
  xor    %r8d,%r8d
L76:
  lea    (%r8,%r8,4),%rcx
  add    $0x1,%rax
  lea    (%rdx,%rcx,2),%rsi
  movsbq (%rax),%rdx
  lea    -0x30(%rsi),%r8
  movsbl %dl,%ecx
  sub    $0x30,%ecx
  cmp    $0x9,%ecx
  jbe    L76
  mov    $0x30,%eax
  sub    %rsi,%rax
  test   %edi,%edi
  cmovne %rax,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L33:
  movsbq 0x1(%rax),%rcx
  xor    %edi,%edi
  add    $0x1,%rax
  mov    %rcx,%rdx
  sub    $0x30,%ecx
  cmp    $0x9,%ecx
  jbe    L18
L6:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
  nopl   (%rax)
L86:
  movsbq 0x1(%rax),%rcx
  mov    $0x1,%edi
  add    $0x1,%rax
  mov    %rcx,%rdx
  sub    $0x30,%ecx
  cmp    $0x9,%ecx
  jbe    L18
  jmp    L6
```

assistant: ```c
long atol(cp)
register char *cp;
{
  long n;
  register sign;
  while (*cp == ' ' || *cp == '\t')
    ++cp;
  sign = 0;
  if (*cp == '-') {
    sign = 1;
    ++cp;
  } else if (*cp == '+')
    ++cp;
  for (n = 0; isdigit(*cp);)
    n = n * 10 + *cp++ - '0';
  return sign ? -n : n;
}
```
user: What is the c source code of the assembly code below:

```asm
<atol>:
  endbr64
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L96:
  add    $0x1,%rdi
L13:
  movsbq (%rdi),%rax
  cmp    $0x20,%al
  je     L96
  cmp    $0x9,%al
  je     L96
  cmp    $0x2d,%al
  je     L63
  cmp    $0x2b,%al
  je     L92
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L29
  xor    %esi,%esi
L42:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L81:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%rcx
  movsbq (%rdi),%rax
  lea    -0x30(%rcx),%r8
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L81
  mov    $0x30,%eax
  sub    %rcx,%rax
  test   %esi,%esi
  cmovne %rax,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L92:
  movsbq 0x1(%rdi),%rdx
  xor    %esi,%esi
  add    $0x1,%rdi
  mov    %rdx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L42
L29:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
  nopl   (%rax)
L63:
  movsbq 0x1(%rdi),%rdx
  mov    $0x1,%esi
  add    $0x1,%rdi
  mov    %rdx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L42
  jmp    L29
```

assistant: ```c
long atol(cp)
register char *cp;
{
  long n;
  register sign;
  while (*cp == ' ' || *cp == '\t')
    ++cp;
  sign = 0;
  if (*cp == '-') {
    sign = 1;
    ++cp;
  } else if (*cp == '+')
    ++cp;
  for (n = 0; isdigit(*cp);)
    n = n * 10 + *cp++ - '0';
  return sign ? -n : n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readU32FromChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L72
L28:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L72:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L3
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L28
L3:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x4b,%al
  je     L1
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x4d,%al
  jne    L64
L1:
  shll   $0xa,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x4d,%al
  jne    L9
  shll   $0xa,-0x4(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x69,%al
  jne    L66
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L66:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x42,%al
  jne    L64
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L64:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned readU32FromChar(const char **stringPtr) {
  unsigned result = 0;
  while ((**stringPtr >= '0') && (**stringPtr <= '9'))
    result *= 10, result += **stringPtr - '0', (*stringPtr)++;
  if ((**stringPtr == 'K') || (**stringPtr == 'M')) {
    result <<= 10;
    if (**stringPtr == 'M')
      result <<= 10;
    (*stringPtr)++;
    if (**stringPtr == 'i')
      (*stringPtr)++;
    if (**stringPtr == 'B')
      (*stringPtr)++;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readU32FromChar>:
  endbr64
  mov    (%rdi),%r8
  movzbl (%r8),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L77
  lea    0x1(%r8),%rcx
  mov    $0x0,%eax
L10:
  lea    (%rax,%rax,4),%eax
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rax,2),%eax
  mov    %rcx,%r8
  mov    %rcx,(%rdi)
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L10
L53:
  lea    -0x4b(%rdx),%ecx
  test   $0xfd,%cl
  jne    L65
  mov    %eax,%ecx
  shl    $0xa,%ecx
  shl    $0x14,%eax
  cmp    $0x4d,%dl
  cmovne %ecx,%eax
  lea    0x1(%r8),%rdx
  mov    %rdx,(%rdi)
  cmpb   $0x69,0x1(%r8)
  je     L68
L41:
  mov    (%rdi),%rdx
  cmpb   $0x42,(%rdx)
  je     L16
L65:
  ret
L77:
  mov    $0x0,%eax
  jmp    L53
L68:
  add    $0x2,%r8
  mov    %r8,(%rdi)
  jmp    L41
L16:
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  jmp    L65
```

assistant: ```c
unsigned readU32FromChar(const char **stringPtr) {
  unsigned result = 0;
  while ((**stringPtr >= '0') && (**stringPtr <= '9'))
    result *= 10, result += **stringPtr - '0', (*stringPtr)++;
  if ((**stringPtr == 'K') || (**stringPtr == 'M')) {
    result <<= 10;
    if (**stringPtr == 'M')
      result <<= 10;
    (*stringPtr)++;
    if (**stringPtr == 'i')
      (*stringPtr)++;
    if (**stringPtr == 'B')
      (*stringPtr)++;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readU32FromChar>:
  endbr64
  mov    (%rdi),%r8
  movsbl (%r8),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L46
  lea    0x1(%r8),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L58:
  lea    (%rax,%rax,4),%eax
  mov    %rcx,(%rdi)
  mov    %rcx,%r8
  add    $0x1,%rcx
  lea    -0x30(%rdx,%rax,2),%eax
  movsbl -0x1(%rcx),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L58
L50:
  lea    -0x4b(%rdx),%ecx
  and    $0xfd,%ecx
  jne    L14
  mov    %eax,%ecx
  shl    $0x14,%eax
  shl    $0xa,%ecx
  cmp    $0x4d,%dl
  lea    0x1(%r8),%rdx
  mov    %rdx,(%rdi)
  cmovne %ecx,%eax
  movzbl 0x1(%r8),%ecx
  cmp    $0x69,%cl
  je     L40
  cmp    $0x42,%cl
  je     L24
L14:
  ret
  xchg   %ax,%ax
L24:
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  lea    0x2(%r8),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x2(%r8),%ecx
  cmp    $0x42,%cl
  jne    L14
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L46:
  xor    %eax,%eax
  jmp    L50
```

assistant: ```c
unsigned readU32FromChar(const char **stringPtr) {
  unsigned result = 0;
  while ((**stringPtr >= '0') && (**stringPtr <= '9'))
    result *= 10, result += **stringPtr - '0', (*stringPtr)++;
  if ((**stringPtr == 'K') || (**stringPtr == 'M')) {
    result <<= 10;
    if (**stringPtr == 'M')
      result <<= 10;
    (*stringPtr)++;
    if (**stringPtr == 'i')
      (*stringPtr)++;
    if (**stringPtr == 'B')
      (*stringPtr)++;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readU32FromChar>:
  endbr64
  mov    (%rdi),%r8
  movsbl (%r8),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L23
  lea    0x1(%r8),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L47:
  lea    (%rax,%rax,4),%eax
  mov    %rcx,(%rdi)
  mov    %rcx,%r8
  add    $0x1,%rcx
  lea    -0x30(%rdx,%rax,2),%eax
  movsbl -0x1(%rcx),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L47
L61:
  lea    -0x4b(%rdx),%ecx
  and    $0xfd,%ecx
  jne    L13
  mov    %eax,%ecx
  shl    $0x14,%eax
  shl    $0xa,%ecx
  cmp    $0x4d,%dl
  lea    0x1(%r8),%rdx
  mov    %rdx,(%rdi)
  cmovne %ecx,%eax
  movzbl 0x1(%r8),%ecx
  cmp    $0x69,%cl
  je     L21
  cmp    $0x42,%cl
  je     L71
L13:
  ret
  xchg   %ax,%ax
L71:
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  lea    0x2(%r8),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x2(%r8),%ecx
  cmp    $0x42,%cl
  jne    L13
  jmp    L71
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  jmp    L61
```

assistant: ```c
unsigned readU32FromChar(const char **stringPtr) {
  unsigned result = 0;
  while ((**stringPtr >= '0') && (**stringPtr <= '9'))
    result *= 10, result += **stringPtr - '0', (*stringPtr)++;
  if ((**stringPtr == 'K') || (**stringPtr == 'M')) {
    result <<= 10;
    if (**stringPtr == 'M')
      result <<= 10;
    (*stringPtr)++;
    if (**stringPtr == 'i')
      (*stringPtr)++;
    if (**stringPtr == 'B')
      (*stringPtr)++;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rbx
  mov    $0x1,%eax
  int    $0x80
  mov    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int system(const char *command) {
  int retval;
  asm volatile("movl $0x1, %%eax; int $0x80; movl %%eax, %0" : "=a"(retval) : "b"(command) : "%ecx", "edx");
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<system>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%eax
  int    $0x80
  mov    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int system(const char *command) {
  int retval;
  asm volatile("movl $0x1, %%eax; int $0x80; movl %%eax, %0" : "=a"(retval) : "b"(command) : "%ecx", "edx");
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<system>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%eax
  int    $0x80
  mov    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int system(const char *command) {
  int retval;
  asm volatile("movl $0x1, %%eax; int $0x80; movl %%eax, %0" : "=a"(retval) : "b"(command) : "%ecx", "edx");
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<system>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%eax
  int    $0x80
  mov    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int system(const char *command) {
  int retval;
  asm volatile("movl $0x1, %%eax; int $0x80; movl %%eax, %0" : "=a"(retval) : "b"(command) : "%ecx", "edx");
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hackedbranchfree_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L45
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L31
L30:
  mov    -0x20(%rbp),%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    -0x24(%rbp),%eax
  sar    $0x1f,%eax
  cltq
  and    -0x8(%rbp),%rax
  shl    $0x2,%rax
  add    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x20(%rbp)
L31:
  cmpq   $0x1,-0x20(%rbp)
  ja     L30
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L58
  mov    $0x4,%edx
  jmp    L42
L58:
  mov    $0x0,%edx
L42:
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
L45:
  pop    %rbp
  ret
```

assistant: ```c
size_t hackedbranchfree_search(int *source, size_t n, int target) {
  if (n == 0)
    return 0;
  int *base = source;
  while (n > 1) {
    size_t half = n >> 1;
    base += ((base[half] - target) >> 31) & half;
    n -= half;
  }
  return (*base < target) + base - source;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hackedbranchfree_search>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L19
  cmp    $0x1,%rsi
  jbe    L15
L6:
  mov    %rsi,%rcx
  shr    %rcx
  mov    (%rdi,%rcx,4),%eax
  sub    %edx,%eax
  sar    $0x1f,%eax
  cltq
  and    %rcx,%rax
  lea    (%rdi,%rax,4),%rdi
  sub    %rcx,%rsi
  cmp    $0x1,%rsi
  ja     L6
L15:
  cmp    %edx,(%rdi)
  setl   %al
  movzbl %al,%eax
  lea    (%rdi,%rax,4),%rax
  sub    %r8,%rax
  sar    $0x2,%rax
L19:
  ret
```

assistant: ```c
size_t hackedbranchfree_search(int *source, size_t n, int target) {
  if (n == 0)
    return 0;
  int *base = source;
  while (n > 1) {
    size_t half = n >> 1;
    base += ((base[half] - target) >> 31) & half;
    n -= half;
  }
  return (*base < target) + base - source;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hackedbranchfree_search>:
  endbr64
  mov    %rdi,%r8
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L14
  cmp    $0x1,%rsi
  je     L15
  nopl   0x0(%rax)
L8:
  mov    %rsi,%rcx
  shr    %rcx
  mov    (%rdi,%rcx,4),%eax
  sub    %rcx,%rsi
  sub    %edx,%eax
  sar    $0x1f,%eax
  cltq
  and    %rcx,%rax
  lea    (%rdi,%rax,4),%rdi
  cmp    $0x1,%rsi
  ja     L8
L15:
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  setl   %al
  lea    (%rdi,%rax,4),%rax
  sub    %r8,%rax
  sar    $0x2,%rax
L14:
  ret
```

assistant: ```c
size_t hackedbranchfree_search(int *source, size_t n, int target) {
  if (n == 0)
    return 0;
  int *base = source;
  while (n > 1) {
    size_t half = n >> 1;
    base += ((base[half] - target) >> 31) & half;
    n -= half;
  }
  return (*base < target) + base - source;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hackedbranchfree_search>:
  endbr64
  mov    %rdi,%r8
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L6
  cmp    $0x1,%rsi
  je     L11
  nopl   0x0(%rax)
L21:
  mov    %rsi,%rcx
  shr    %rcx
  mov    (%rdi,%rcx,4),%eax
  sub    %rcx,%rsi
  sub    %edx,%eax
  sar    $0x1f,%eax
  cltq
  and    %rcx,%rax
  lea    (%rdi,%rax,4),%rdi
  cmp    $0x1,%rsi
  ja     L21
L11:
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  setl   %al
  lea    (%rdi,%rax,4),%rax
  sub    %r8,%rax
  sar    $0x2,%rax
L6:
  ret
```

assistant: ```c
size_t hackedbranchfree_search(int *source, size_t n, int target) {
  if (n == 0)
    return 0;
  int *base = source;
  while (n > 1) {
    size_t half = n >> 1;
    base += ((base[half] - target) >> 31) & half;
    n -= half;
  }
  return (*base < target) + base - source;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rot13_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L1
L9:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <rot13_char@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x18(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void rot13_string(char *s) {
  int len = strlen(s);
  int i;
  for (i = 0; i < len; i++)
    s[i] = rot13_char(s[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rot13_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rbp
L17:
  movsbl (%rbx),%edi
  call   <rot13_char@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rot13_string(char *s) {
  int len = strlen(s);
  int i;
  for (i = 0; i < len; i++)
    s[i] = rot13_char(s[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rot13_string>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L14
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  xchg   %ax,%ax
L6:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <rot13_char@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L6
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rot13_string(char *s) {
  int len = strlen(s);
  int i;
  for (i = 0; i < len; i++)
    s[i] = rot13_char(s[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rot13_string>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L0
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  xchg   %ax,%ax
L14:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <rot13_char@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L14
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rot13_string(char *s) {
  int len = strlen(s);
  int i;
  for (i = 0; i < len; i++)
    s[i] = rot13_char(s[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<truncar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <truncf@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double truncar(double num, int exp) {
  double fac = pow(10, exp);
  return truncf(num * fac) / fac;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<truncar>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movq   %rbx,%xmm1
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <truncf@plt>
  divsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double truncar(double num, int exp) {
  double fac = pow(10, exp);
  return truncf(num * fac) / fac;
}
```
user: Translate the below assembly code into C programming language:

```asm
<truncar>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    $0xa,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <truncf@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  divsd  %xmm2,%xmm0
  ret
```

assistant: ```c
double truncar(double num, int exp) {
  double fac = pow(10, exp);
  return truncf(num * fac) / fac;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<truncar>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    $0xa,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <truncf@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  divsd  %xmm2,%xmm0
  ret
```

assistant: ```c
double truncar(double num, int exp) {
  double fac = pow(10, exp);
  return truncf(num * fac) / fac;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x44(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x35(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x26(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x17(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x17(%rbp),%rsi
  lea    -0x26(%rbp),%rcx
  lea    -0x35(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D38
type_guessed: string
name: retrieve_data
arguments: tag: D18
type_guessed: string
name: retrieve_data
arguments: tag: D19
type_guessed: string
name: retrieve_data
arguments: tag: D74
type_guessed: string
name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D53
type_guessed: string
name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D38: String 1: 

tool: D18: %s

tool: D19: String 2: 

tool: D74: String 3: 

tool: D20: String 4: 

tool: D53: ** "Output" **

tool: D7: %.3s
%.4s
%.5s
%.6s


assistant: ```c
int main(void) {
  char text1[15], text2[15], text3[15], text4[15];
  printf("String 1: ");
  scanf("%s", text1);
  printf("String 2: ");
  scanf("%s", text2);
  printf("String 3: ");
  scanf("%s", text3);
  printf("String 4: ");
  scanf("%s", text4);
  printf("** \"Output\" **\n");
  printf("%.3s\n%.4s\n%.5s\n%.6s\n", text1, text2, text3, text4);
  return 0;
}
```