ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_user>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <fopen@plt>
  test   %rax,%rax
  je     L42
  mov    %r12,%rdi
  mov    %rax,%rbp
  movslq %r13d,%r14
  call   <strlwr@plt>
  nopl   0x0(%rax,%rax,1)
L71:
  mov    %rbp,%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L40
  movzbl (%rbx),%eax
  cmp    $0x23,%al
  je     L71
  cmp    $0xa,%al
  je     L71
  movzbl (%rbx,%r14,1),%edi
  mov    %edi,%r15d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L21
  cmp    $0x3a,%r15b
  jne    L71
L21:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strnicmp@plt>
  test   %rax,%rax
  jne    L71
  mov    %rbp,%rdi
  mov    $0x1,%r14d
  call   <fclose@plt>
L42:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <fclose@plt>
  jmp    L42
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: r

assistant: ```c
int find_user(char *user, char *user_info, char *file_name) {
  FILE *cfg_file;
  int user_len = strlen(user);
  unsigned char c;
  int success = 0;
  cfg_file = fopen(file_name, "r");
  if (!cfg_file)
    return 0;
  strlwr(user);
  while (fgets(user_info, 128, cfg_file)) {
    if (*user_info == '#' || *user_info == '\n')
      continue;
    c = user_info[user_len];
    if ((isspace(c) || c == ':') && strnicmp(user_info, user, user_len) == 0) {
      success = 1;
      break;
    }
  }
  fclose(cfg_file);
  return success;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_user>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <fopen@plt>
  test   %rax,%rax
  je     L67
  mov    %r12,%rdi
  mov    %rax,%rbp
  movslq %r13d,%r14
  call   <strlwr@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L47
  movzbl (%rbx),%eax
  cmp    $0x23,%al
  je     L8
  cmp    $0xa,%al
  je     L8
  movzbl (%rbx,%r14,1),%edi
  mov    %edi,%r15d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L73
  cmp    $0x3a,%r15b
  jne    L8
L73:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strnicmp@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbp,%rdi
  mov    $0x1,%r14d
  call   <fclose@plt>
L67:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <fclose@plt>
  jmp    L67
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3: r

assistant: ```c
int find_user(char *user, char *user_info, char *file_name) {
  FILE *cfg_file;
  int user_len = strlen(user);
  unsigned char c;
  int success = 0;
  cfg_file = fopen(file_name, "r");
  if (!cfg_file)
    return 0;
  strlwr(user);
  while (fgets(user_info, 128, cfg_file)) {
    if (*user_info == '#' || *user_info == '\n')
      continue;
    c = user_info[user_len];
    if ((isspace(c) || c == ':') && strnicmp(user_info, user, user_len) == 0) {
      success = 1;
      break;
    }
  }
  fclose(cfg_file);
  return success;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stress_memhotplug_supported>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%edi
  call   <stress_check_capability@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <pr_inf@plt>
  mov    $0xffffffff,%eax
  jmp    L4
L3:
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: %s stressor will be skipped, need to be running with CAP_SYS_ADMIN rights for this stressor


assistant: ```c
int stress_memhotplug_supported(const char *name) {
  if (!stress_check_capability((0))) {
    pr_inf("%s stressor will be skipped, "
           "need to be running with CAP_SYS_ADMIN "
           "rights for this stressor\n",
           name);
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stress_memhotplug_supported>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <stress_check_capability@plt>
  test   %eax,%eax
  je     L1
  mov    $0x0,%eax
L16:
  pop    %rbx
  ret
L1:
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <pr_inf@plt>
  mov    $0xffffffff,%eax
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: %s stressor will be skipped, need to be running with CAP_SYS_ADMIN rights for this stressor


assistant: ```c
int stress_memhotplug_supported(const char *name) {
  if (!stress_check_capability((0))) {
    pr_inf("%s stressor will be skipped, "
           "need to be running with CAP_SYS_ADMIN "
           "rights for this stressor\n",
           name);
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stress_memhotplug_supported>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <stress_check_capability@plt>
  test   %eax,%eax
  je     L0
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <pr_inf@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: %s stressor will be skipped, need to be running with CAP_SYS_ADMIN rights for this stressor


assistant: ```c
int stress_memhotplug_supported(const char *name) {
  if (!stress_check_capability((0))) {
    pr_inf("%s stressor will be skipped, "
           "need to be running with CAP_SYS_ADMIN "
           "rights for this stressor\n",
           name);
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stress_memhotplug_supported>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <stress_check_capability@plt>
  test   %eax,%eax
  je     L1
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <pr_inf@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: %s stressor will be skipped, need to be running with CAP_SYS_ADMIN rights for this stressor


assistant: ```c
int stress_memhotplug_supported(const char *name) {
  if (!stress_check_capability((0))) {
    pr_inf("%s stressor will be skipped, "
           "need to be running with CAP_SYS_ADMIN "
           "rights for this stressor\n",
           name);
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninitvar_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uninitvar_strcmp(void) {
  char *str1;
  char *str2;
  (void)strcmp(str1, str2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uninitvar_strcmp>:
  endbr64
  ret
```

assistant: ```c
void uninitvar_strcmp(void) {
  char *str1;
  char *str2;
  (void)strcmp(str1, str2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uninitvar_strcmp>:
  endbr64
  ret
```

assistant: ```c
void uninitvar_strcmp(void) {
  char *str1;
  char *str2;
  (void)strcmp(str1, str2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uninitvar_strcmp>:
  endbr64
  ret
```

assistant: ```c
void uninitvar_strcmp(void) {
  char *str1;
  char *str2;
  (void)strcmp(str1, str2);
}
```
user: What is the c source code of the assembly code below:

```asm
<simple_object_set_big_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %ax,-0xc(%rbp)
  movzwl -0xc(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzwl -0xc(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void simple_object_set_big_16(unsigned char *buf, unsigned short val) {
  buf[0] = (val >> 8) & 0xff;
  buf[1] = val & 0xff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simple_object_set_big_16>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  mov    %dl,(%rdi)
  mov    %sil,0x1(%rdi)
  ret
```

assistant: ```c
void simple_object_set_big_16(unsigned char *buf, unsigned short val) {
  buf[0] = (val >> 8) & 0xff;
  buf[1] = val & 0xff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<simple_object_set_big_16>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void simple_object_set_big_16(unsigned char *buf, unsigned short val) {
  buf[0] = (val >> 8) & 0xff;
  buf[1] = val & 0xff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<simple_object_set_big_16>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void simple_object_set_big_16(unsigned char *buf, unsigned short val) {
  buf[0] = (val >> 8) & 0xff;
  buf[1] = val & 0xff;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<setmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setmem(int address, int value) {
  int *address_as_pointer = (int *)address;
  *address_as_pointer = value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<setmem>:
  endbr64
  movslq %edi,%rdi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void setmem(int address, int value) {
  int *address_as_pointer = (int *)address;
  *address_as_pointer = value;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<setmem>:
  endbr64
  movslq %edi,%rdi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void setmem(int address, int value) {
  int *address_as_pointer = (int *)address;
  *address_as_pointer = value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setmem>:
  endbr64
  movslq %edi,%rdi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void setmem(int address, int value) {
  int *address_as_pointer = (int *)address;
  *address_as_pointer = value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L167
  mov    $0x3,%eax
  jmp    L108
L167:
  cmpl   $0x4,-0x4(%rbp)
  jg     L119
  mov    $0x0,%eax
  jmp    L108
L119:
  cmpl   $0x5,-0x4(%rbp)
  je     L122
  cmpl   $0x13,-0x4(%rbp)
  je     L122
  cmpl   $0x17,-0x4(%rbp)
  sete   %dl
  cmpl   $0x1a,-0x4(%rbp)
  sete   %al
  or     %edx,%eax
  test   %al,%al
  jne    L122
  cmpl   $0x41,-0x4(%rbp)
  jne    L106
L122:
  mov    $0x1,%eax
  jmp    L108
L106:
  cmpl   $0x13,-0x4(%rbp)
  jle    L18
  cmpl   $0x16,-0x4(%rbp)
  jle    L81
L18:
  cmpl   $0x1b,-0x4(%rbp)
  je     L81
  cmpl   $0x26,-0x4(%rbp)
  je     L81
  cmpl   $0x2d,-0x4(%rbp)
  je     L81
  cmpl   $0x2f,-0x4(%rbp)
  je     L81
  cmpl   $0x42,-0x4(%rbp)
  jne    L20
L81:
  mov    $0x2,%eax
  jmp    L108
L20:
  mov    $0x3,%eax
L108:
  pop    %rbp
  ret
```

assistant: ```c
int bar(int x) {
  if (x < 0)
    return 3;
  if (x < 5)
    return 0;
  if (x == 5 || x == 19 || x == 23 | x == 26 || x == 65)
    return 1;
  if ((x >= 20 && x <= 22) || x == 27 || x == 38 || x == 45 || x == 47 || x == 66)
    return 2;
  return 3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  test   %edi,%edi
  js     L30
  mov    $0x0,%eax
  cmp    $0x4,%edi
  jle    L5
  lea    -0x5(%rdi),%ecx
  cmp    $0x3d,%ecx
  ja     L23
  mov    $0x1,%eax
  shl    %cl,%rax
  movabs $0x2000050200438000,%rdx
  test   %rdx,%rax
  jne    L19
  movabs $0x1000000000244001,%rdx
  and    %rdx,%rax
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  add    $0x1,%eax
  ret
L30:
  mov    $0x3,%eax
  ret
L23:
  mov    $0x3,%eax
  ret
L19:
  mov    $0x2,%eax
L5:
  ret
```

assistant: ```c
int bar(int x) {
  if (x < 0)
    return 3;
  if (x < 5)
    return 0;
  if (x == 5 || x == 19 || x == 23 | x == 26 || x == 65)
    return 1;
  if ((x >= 20 && x <= 22) || x == 27 || x == 38 || x == 45 || x == 47 || x == 66)
    return 2;
  return 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  test   %edi,%edi
  js     L22
  xor    %eax,%eax
  cmp    $0x4,%edi
  jle    L17
  lea    -0x5(%rdi),%ecx
  cmp    $0x3d,%ecx
  ja     L22
  movabs $0x2000050200438000,%rdx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %rdx,%rax
  jne    L19
  movabs $0x1000000000244001,%rdx
  and    %rdx,%rax
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  add    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0x2,%eax
L17:
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int bar(int x) {
  if (x < 0)
    return 3;
  if (x < 5)
    return 0;
  if (x == 5 || x == 19 || x == 23 | x == 26 || x == 65)
    return 1;
  if ((x >= 20 && x <= 22) || x == 27 || x == 38 || x == 45 || x == 47 || x == 66)
    return 2;
  return 3;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bar>:
  endbr64
  test   %edi,%edi
  js     L4
  xor    %eax,%eax
  cmp    $0x4,%edi
  jle    L17
  lea    -0x5(%rdi),%ecx
  cmp    $0x3d,%ecx
  ja     L4
  movabs $0x2000050200438000,%rdx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %rdx,%rax
  jne    L32
  movabs $0x1000000000244001,%rdx
  and    %rdx,%rax
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  add    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x2,%eax
L17:
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int bar(int x) {
  if (x < 0)
    return 3;
  if (x < 5)
    return 0;
  if (x == 5 || x == 19 || x == 23 | x == 26 || x == 65)
    return 1;
  if ((x >= 20 && x <= 22) || x == 27 || x == 38 || x == 45 || x == 47 || x == 66)
    return 2;
  return 3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<user_memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L28
L26:
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzbl -0x1(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L14
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L28:
  cmpb   $0x13,-0x1(%rbp)
  jbe    L26
  jmp    L0
L14:
  nop
L0:
  cmpb   $0x14,-0x2(%rbp)
  jne    L29
  mov    $0x0,%eax
  jmp    L52
L29:
  cmpb   $0x3,-0x2(%rbp)
  jle    L17
  movzbl -0x2(%rbp),%eax
  jmp    L52
L17:
  mov    $0xffffffff,%eax
L52:
  pop    %rbp
  ret
```

assistant: ```c
signed char user_memcmp(const unsigned char *const a, const unsigned char *const b) {
  char count = 0;
  for (unsigned char i = 0; i < 20; i++) {
    if (a[i] != b[i])
      break;
    else
      count++;
  }
  if (count == 20)
    return 0;
  if (count >= 4)
    return count;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<user_memcmp>:
  endbr64
  mov    $0x0,%eax
L45:
  mov    %eax,%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jne    L1
  lea    0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x14,%rax
  jne    L45
L1:
  cmp    $0x14,%dl
  je     L27
  cmp    $0x3,%dl
  jle    L13
L25:
  mov    %edx,%eax
  ret
L13:
  mov    $0xffffffff,%edx
  jmp    L25
L27:
  mov    $0x0,%edx
  jmp    L25
```

assistant: ```c
signed char user_memcmp(const unsigned char *const a, const unsigned char *const b) {
  char count = 0;
  for (unsigned char i = 0; i < 20; i++) {
    if (a[i] != b[i])
      break;
    else
      count++;
  }
  if (count == 20)
    return 0;
  if (count >= 4)
    return count;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<user_memcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L23:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    $0x14,%rax
  je     L30
L59:
  movzbl (%rsi,%rax,1),%edx
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  je     L23
L34:
  cmp    $0x3,%r8b
  jle    L36
L24:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L30:
  cmp    $0x14,%r8b
  jne    L34
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
L36:
  mov    $0xffffffff,%r8d
  jmp    L24
```

assistant: ```c
signed char user_memcmp(const unsigned char *const a, const unsigned char *const b) {
  char count = 0;
  for (unsigned char i = 0; i < 20; i++) {
    if (a[i] != b[i])
      break;
    else
      count++;
  }
  if (count == 20)
    return 0;
  if (count >= 4)
    return count;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<user_memcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L28:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    $0x14,%rax
  je     L47
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  je     L28
L10:
  cmp    $0x3,%r8b
  jle    L1
L5:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L47:
  cmp    $0x14,%r8b
  jne    L10
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
L1:
  mov    $0xffffffff,%r8d
  jmp    L5
```

assistant: ```c
signed char user_memcmp(const unsigned char *const a, const unsigned char *const b) {
  char count = 0;
  for (unsigned char i = 0; i < 20; i++) {
    if (a[i] != b[i])
      break;
    else
      count++;
  }
  if (count == 20)
    return 0;
  if (count >= 4)
    return count;
  else
    return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x8,-0x10(%rbp)
  movl   $0x13,-0xc(%rbp)
  mov    $0x18,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
datatype: string
name: extract_symbolic_data
arguments: data_label: D53
datatype: string
name: extract_symbolic_data
arguments: data_label: D60
datatype: string
name: extract_symbolic_data
arguments: data_label: D2
datatype: string
name: extract_symbolic_data
arguments: data_label: D6
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D66
datatype: string

tool: D19: main sizeof(a)=%lu


tool: D53: main a=%p


tool: D60: a[0]=%d


tool: D2: min=%d, max=%d


tool: D6: *p=%d


tool: D3: p[0]=%d


tool: D66: *a=%d


assistant: ```c
int main(void) {
  int a[] = {1, 3, 5, 6, 8, 19};
  int min, max;
  printf("main sizeof(a)=%lu\n", sizeof(a));
  printf("main a=%p\n", a);
  minmax(a, sizeof(a) / sizeof(a[0]), &min, &max);
  printf("a[0]=%d\n", a[0]);
  printf("min=%d, max=%d\n", min, max);
  int *p = &min;
  printf("*p=%d\n", *p);
  printf("p[0]=%d\n", p[0]);
  printf("*a=%d\n", *a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0x13,0x24(%rsp)
  mov    $0x18,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <minmax@plt>
  mov    0x10(%rsp),%esi
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  lea    D68(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D25
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D64
datatype: string
name: parse_data
arguments: data_tag: D57
datatype: string
name: parse_data
arguments: data_tag: D68
datatype: string
name: parse_data
arguments: data_tag: D58
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string

tool: D25: main sizeof(a)=%lu


tool: D18: main a=%p


tool: D64: a[0]=%d


tool: D57: min=%d, max=%d


tool: D68: *p=%d


tool: D58: p[0]=%d


tool: D19: *a=%d


assistant: ```c
int main(void) {
  int a[] = {1, 3, 5, 6, 8, 19};
  int min, max;
  printf("main sizeof(a)=%lu\n", sizeof(a));
  printf("main a=%p\n", a);
  minmax(a, sizeof(a) / sizeof(a[0]), &min, &max);
  printf("a[0]=%d\n", a[0]);
  printf("min=%d, max=%d\n", min, max);
  int *p = &min;
  printf("*p=%d\n", *p);
  printf("p[0]=%d\n", p[0]);
  printf("*a=%d\n", *a);
  return 0;
}
```