ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<displayMatrix>:
  endbr64
  push   %r15
  push   %r14
  lea    D76(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14,%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  xchg   %ax,%ax
L0:
  test   %r12d,%r12d
  je     L38
L26:
  xor    %r15d,%r15d
  lea    D40(%rip),%r13
  jmp    L34
  nopl   0x0(%rax)
L27:
  mov    (%rbx,%r15,4),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x13,%r15
  je     L53
L75:
  add    $0x1,%r15
L34:
  test   %r15,%r15
  jne    L27
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  lea    D2(%rip),%rdx
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L75
  nop
L53:
  add    $0x1,%r12d
  add    $0x50,%rbx
  cmp    $0x14,%r12d
  jne    L0
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
L38:
  lea    D49(%rip),%rsi
  lea    D80(%rip),%rdi
  xor    %eax,%eax
  xor    %r13d,%r13d
  call   <printf@plt>
  nopl   0x0(%rax)
L3:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    $0x14,%r13d
  jne    L3
  mov    %r14,%rdi
  call   <puts@plt>
  lea    D49(%rip),%rsi
  lea    D80(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L77:
  xor    %eax,%eax
  lea    D34(%rip),%rsi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  sub    $0x1,%r13d
  jne    L77
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D76
datatype: string
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D40
datatype: string
name: extract_symbolic_data
arguments: data_tag: D2
datatype: string
name: extract_symbolic_data
arguments: data_tag: D49
datatype: string
name: extract_symbolic_data
arguments: data_tag: D80
datatype: string
name: extract_symbolic_data
arguments: data_tag: D34
datatype: string
name: extract_symbolic_data
arguments: data_tag: D54
datatype: string

tool: 

tool: D27:  %3d 

tool: D40:  %3d %s

tool: D2: >

tool: D49:  

tool: D80:  %3s  

tool: D34: V

tool: D54:  %3s 

assistant: ```c
void displayMatrix(const int A[][20]) {
  puts("");
  for (int i = 0; i < 20; i++) {
    if (i == 0) {
      printf(" %3s  ", " ");
      for (int j = 0; j < 20; j++) {
        printf(" %3d ", j);
      }
      puts("");
      printf(" %3s  ", " ");
      for (int j = 0; j < 20; j++) {
        printf(" %3s ", "V");
      }
    }
    for (int j = 0; j < 20; j++) {
      if (j % 20 == 0) {
        puts("");
        printf(" %3d %s", i, ">");
      }
      printf(" %3d ", A[i][j]);
    }
  }
  puts("");
}
```
user: Translate the below assembly code into C programming language:

```asm
<displayMatrix>:
  endbr64
  push   %r15
  push   %r14
  lea    D46(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D47(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14,%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  xchg   %ax,%ax
L27:
  test   %r12d,%r12d
  je     L47
L42:
  xor    %r15d,%r15d
  lea    D60(%rip),%r13
  jmp    L16
  nopl   0x0(%rax)
L35:
  mov    (%rbx,%r15,4),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x13,%r15
  je     L65
L9:
  add    $0x1,%r15
L16:
  test   %r15,%r15
  jne    L35
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  lea    D19(%rip),%rdx
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L9
  nop
L65:
  add    $0x1,%r12d
  add    $0x50,%rbx
  cmp    $0x14,%r12d
  jne    L27
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
L47:
  lea    D29(%rip),%rsi
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  xor    %r13d,%r13d
  call   <printf@plt>
  nopl   0x0(%rax)
L81:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    $0x14,%r13d
  jne    L81
  mov    %r14,%rdi
  call   <puts@plt>
  lea    D29(%rip),%rsi
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  lea    D84(%rip),%rsi
  lea    D51(%rip),%rdi
  call   <printf@plt>
  sub    $0x1,%r13d
  jne    L5
  jmp    L42
```

tool_calls: name: disassemble_data
arguments: tag: D46
data_type: string
name: disassemble_data
arguments: tag: D47
data_type: string
name: disassemble_data
arguments: tag: D60
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D68
data_type: string
name: disassemble_data
arguments: tag: D84
data_type: string
name: disassemble_data
arguments: tag: D51
data_type: string

tool: 

tool: D47:  %3d 

tool: D60:  %3d %s

tool: D19: >

tool: D29:  

tool: D68:  %3s  

tool: D84: V

tool: D51:  %3s 

assistant: ```c
void displayMatrix(const int A[][20]) {
  puts("");
  for (int i = 0; i < 20; i++) {
    if (i == 0) {
      printf(" %3s  ", " ");
      for (int j = 0; j < 20; j++) {
        printf(" %3d ", j);
      }
      puts("");
      printf(" %3s  ", " ");
      for (int j = 0; j < 20; j++) {
        printf(" %3s ", "V");
      }
    }
    for (int j = 0; j < 20; j++) {
      if (j % 20 == 0) {
        puts("");
        printf(" %3d %s", i, ">");
      }
      printf(" %3d ", A[i][j]);
    }
  }
  puts("");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m2mp_client_channels_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0xff,-0x4(%rbp)
  jle    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void m2mp_client_channels_init(char *channels[256]) {
  int i;
  for (i = 0; i < 256; ++i)
    channels[i] = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<m2mp_client_channels_init>:
  endbr64
  lea    0x800(%rdi),%rax
L0:
  movq   $0x0,(%rdi)
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L0
  ret
```

assistant: ```c
void m2mp_client_channels_init(char *channels[256]) {
  int i;
  for (i = 0; i < 256; ++i)
    channels[i] = NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<m2mp_client_channels_init>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  lea    0x8(%rdi),%rdi
  movq   $0x0,0x7f0(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rax
  lea    0x800(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  ret
```

assistant: ```c
void m2mp_client_channels_init(char *channels[256]) {
  int i;
  for (i = 0; i < 256; ++i)
    channels[i] = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m2mp_client_channels_init>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  lea    0x8(%rdi),%rdi
  movq   $0x0,0x7f0(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rax
  lea    0x800(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  ret
```

assistant: ```c
void m2mp_client_channels_init(char *channels[256]) {
  int i;
  for (i = 0; i < 256; ++i)
    channels[i] = NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GrOffScreen1BPPColorTranslate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  movzbl %al,%eax
  imul   $0x4ccd,%eax,%edx
  mov    -0xc(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%eax
  imul   $0x970a,%eax,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  imul   $0x1c29,%eax,%eax
  add    %edx,%eax
  shr    $0x17,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int GrOffScreen1BPPColorTranslate(void *pvDisplayData, unsigned int ulValue) {
  ;
  return (((((((ulValue)&0x00ff0000) >> 16) * 19661) + ((((ulValue)&0x0000ff00) >> 8) * 38666) + (((ulValue)&0x000000ff) * 7209)) / (65536 * 128)));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GrOffScreen1BPPColorTranslate>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  shr    $0x10,%eax
  movzbl %al,%eax
  imul   $0x4ccd,%eax,%eax
  movzbl %dh,%ecx
  imul   $0x970a,%ecx,%ecx
  add    %ecx,%eax
  movzbl %sil,%edx
  imul   $0x1c29,%edx,%edx
  add    %edx,%eax
  shr    $0x17,%eax
  ret
```

assistant: ```c
unsigned int GrOffScreen1BPPColorTranslate(void *pvDisplayData, unsigned int ulValue) {
  ;
  return (((((((ulValue)&0x00ff0000) >> 16) * 19661) + ((((ulValue)&0x0000ff00) >> 8) * 38666) + (((ulValue)&0x000000ff) * 7209)) / (65536 * 128)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GrOffScreen1BPPColorTranslate>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  shr    $0x10,%eax
  movzbl %dh,%ecx
  movzbl %sil,%edx
  movzbl %al,%eax
  imul   $0x970a,%ecx,%ecx
  imul   $0x4ccd,%eax,%eax
  imul   $0x1c29,%edx,%edx
  add    %ecx,%eax
  add    %edx,%eax
  shr    $0x17,%eax
  ret
```

assistant: ```c
unsigned int GrOffScreen1BPPColorTranslate(void *pvDisplayData, unsigned int ulValue) {
  ;
  return (((((((ulValue)&0x00ff0000) >> 16) * 19661) + ((((ulValue)&0x0000ff00) >> 8) * 38666) + (((ulValue)&0x000000ff) * 7209)) / (65536 * 128)));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GrOffScreen1BPPColorTranslate>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  shr    $0x10,%eax
  movzbl %dh,%ecx
  movzbl %sil,%edx
  movzbl %al,%eax
  imul   $0x970a,%ecx,%ecx
  imul   $0x4ccd,%eax,%eax
  imul   $0x1c29,%edx,%edx
  add    %ecx,%eax
  add    %edx,%eax
  shr    $0x17,%eax
  ret
```

assistant: ```c
unsigned int GrOffScreen1BPPColorTranslate(void *pvDisplayData, unsigned int ulValue) {
  ;
  return (((((((ulValue)&0x00ff0000) >> 16) * 19661) + ((((ulValue)&0x0000ff00) >> 8) * 38666) + (((ulValue)&0x000000ff) * 7209)) / (65536 * 128)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L1
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L6
L19:
  nop
  jmp    L18
L1:
  nop
L18:
  pop    %rbp
  ret
```

assistant: ```c
void skip_space(const char **s) {
  for (;;) {
    if (**s == '\0')
      return;
    if (**s > 32)
      return;
    (*s)++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_space>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jg     L17
  test   %dl,%dl
  je     L17
  add    $0x1,%rax
L18:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jg     L17
  test   %dl,%dl
  jne    L18
L17:
  ret
```

assistant: ```c
void skip_space(const char **s) {
  for (;;) {
    if (**s == '\0')
      return;
    if (**s > 32)
      return;
    (*s)++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skip_space>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jg     L39
  test   %dl,%dl
  je     L39
  add    $0x1,%rax
  jmp    L20
  nopl   0x0(%rax)
L18:
  cmp    $0x20,%dl
  jg     L39
L20:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L18
L39:
  ret
```

assistant: ```c
void skip_space(const char **s) {
  for (;;) {
    if (**s == '\0')
      return;
    if (**s > 32)
      return;
    (*s)++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<skip_space>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jg     L21
  test   %dl,%dl
  je     L21
  add    $0x1,%rax
  jmp    L44
  nopl   0x0(%rax)
L4:
  cmp    $0x20,%dl
  jg     L21
L44:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L4
L21:
  ret
```

assistant: ```c
void skip_space(const char **s) {
  for (;;) {
    if (**s == '\0')
      return;
    if (**s > 32)
      return;
    (*s)++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<floordivmodc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L27
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L22
L27:
  cmpl   $0x0,-0x8(%rbp)
  jns    L18
  negl   -0x4(%rbp)
  negl   -0x8(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L22
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L22:
  pop    %rbp
  ret
```

assistant: ```c
void floordivmodc(int n, int d, int *f, int *m) {
  if (d == 0) {
    *f = 0;
    *m = 0;
    return;
  }
  if (d < 0) {
    n = -n;
    d = -d;
  }
  *f = n / d;
  *m = n % d;
  if (*m < 0) {
    (*f)--;
    *m += d;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<floordivmodc>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  test   %esi,%esi
  je     L41
  js     L23
L29:
  cltd
  idiv   %esi
  mov    %eax,(%rdi)
  mov    %edx,(%rcx)
  test   %edx,%edx
  js     L31
L36:
  ret
L41:
  movl   $0x0,(%rdx)
  movl   $0x0,(%rcx)
  ret
L23:
  neg    %eax
  neg    %esi
  jmp    L29
L31:
  subl   $0x1,(%rdi)
  add    %esi,(%rcx)
  jmp    L36
```

assistant: ```c
void floordivmodc(int n, int d, int *f, int *m) {
  if (d == 0) {
    *f = 0;
    *m = 0;
    return;
  }
  if (d < 0) {
    n = -n;
    d = -d;
  }
  *f = n / d;
  *m = n % d;
  if (*m < 0) {
    (*f)--;
    *m += d;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<floordivmodc>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  test   %esi,%esi
  je     L20
  js     L9
  cltd
  idiv   %esi
  mov    %eax,(%rdi)
  mov    %edx,(%rcx)
  test   %edx,%edx
  js     L32
L13:
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  subl   $0x1,(%rdi)
  add    %esi,(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  neg    %eax
  neg    %esi
  cltd
  idiv   %esi
  mov    %eax,(%rdi)
  mov    %edx,(%rcx)
  test   %edx,%edx
  jns    L13
  jmp    L32
  nopl   0x0(%rax)
L20:
  movl   $0x0,(%rdx)
  movl   $0x0,(%rcx)
  ret
```

assistant: ```c
void floordivmodc(int n, int d, int *f, int *m) {
  if (d == 0) {
    *f = 0;
    *m = 0;
    return;
  }
  if (d < 0) {
    n = -n;
    d = -d;
  }
  *f = n / d;
  *m = n % d;
  if (*m < 0) {
    (*f)--;
    *m += d;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<floordivmodc>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  test   %esi,%esi
  je     L22
  js     L33
  cltd
  idiv   %esi
  mov    %eax,(%rdi)
  mov    %edx,(%rcx)
  test   %edx,%edx
  js     L48
L31:
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  subl   $0x1,(%rdi)
  add    %esi,(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  neg    %eax
  neg    %esi
  cltd
  idiv   %esi
  mov    %eax,(%rdi)
  mov    %edx,(%rcx)
  test   %edx,%edx
  jns    L31
  jmp    L48
  nopl   0x0(%rax)
L22:
  movl   $0x0,(%rdx)
  movl   $0x0,(%rcx)
  ret
```

assistant: ```c
void floordivmodc(int n, int d, int *f, int *m) {
  if (d == 0) {
    *f = 0;
    *m = 0;
    return;
  }
  if (d < 0) {
    n = -n;
    d = -d;
  }
  *f = n / d;
  *m = n % d;
  if (*m < 0) {
    (*f)--;
    *m += d;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L97
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D10(%rip),%r12
L25:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L25
L97:
  lea    -0x1(%rax),%edi
  test   %edi,%edi
  jle    L13
  lea    0x14(%rsp),%r8
  jmp    L31
L89:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L70
L129:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L89
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L89
L70:
  sub    $0x1,%edi
  je     L13
L31:
  test   %edi,%edi
  jle    L70
  lea    0x10(%rsp),%rax
  lea    -0x1(%rdi),%edx
  lea    (%r8,%rdx,4),%rsi
  jmp    L129
L13:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L40
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
L82:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L82
L40:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L105:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D31
datatype: string
name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D54
datatype: string
name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D3
datatype: string

tool: D31: Enter number of elements

tool: D10: %d

tool: D54: Enter %d integers


tool: D17: Sorted list:

tool: D3: %d


assistant: ```c
int main() {
  int array[100], n, c, d, swap;
  printf("Enter number of elements\n");
  scanf("%d", &n);
  printf("Enter %d integers\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  for (c = 0; c < (n - 1); c++) {
    for (d = 0; d < n - c - 1; d++) {
      if (array[d] > array[d + 1]) {
        swap = array[d];
        array[d] = array[d + 1];
        array[d + 1] = swap;
      }
    }
  }
  printf("Sorted list:\n");
  for (c = 0; c < n; c++)
    printf("%d\n", array[c]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  lea    D41(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L38
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L54
L38:
  lea    -0x1(%rax),%edx
  test   %edx,%edx
  jle    L50
  lea    0x10(%rsp),%rbp
  lea    0x14(%rsp),%r8
  nopl   0x0(%rax,%rax,1)
L52:
  sub    $0x1,%edx
  mov    %rbp,%rax
  mov    %rdx,%rdi
  lea    (%r8,%rdx,4),%rsi
  nopl   (%rax)
L7:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L8
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L8:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L7
  mov    %edi,%edx
  test   %edi,%edi
  jne    L52
L50:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L70
  xor    %ebx,%ebx
  lea    0x10(%rsp),%rbp
  lea    D8(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L29:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L29
L70:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string
name: disassemble_data
arguments: tag: D41
data_type: string
name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string

tool: D3: Enter number of elements

tool: D41: %d

tool: D12: Enter %d integers


tool: D29: Sorted list:

tool: D8: %d


assistant: ```c
int main() {
  int array[100], n, c, d, swap;
  printf("Enter number of elements\n");
  scanf("%d", &n);
  printf("Enter %d integers\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  for (c = 0; c < (n - 1); c++) {
    for (d = 0; d < n - c - 1; d++) {
      if (array[d] > array[d + 1]) {
        swap = array[d];
        array[d] = array[d + 1];
        array[d + 1] = swap;
      }
    }
  }
  printf("Sorted list:\n");
  for (c = 0; c < n; c++)
    printf("%d\n", array[c]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D41(%rip),%rdi
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L59
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L17
L59:
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L78
  lea    0x10(%rsp),%rbp
  lea    0x14(%rsp),%r8
  nopl   0x0(%rax,%rax,1)
L24:
  sub    $0x1,%eax
  mov    %rbp,%rdx
  mov    %rax,%rdi
  lea    (%r8,%rax,4),%rsi
  nopl   (%rax)
L75:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L1
  movq   %xmm1,(%rdx)
L1:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L75
  mov    %edi,%eax
  test   %edi,%edi
  jne    L24
L78:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L0
  xor    %ebx,%ebx
  lea    0x10(%rsp),%rbp
  lea    D33(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L28:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L28
L0:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D41
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D38
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D33
type_guessed: string

tool: D41: Enter number of elements

tool: D0: %d

tool: D38: Enter %d integers


tool: D5: Sorted list:

tool: D33: %d


assistant: ```c
int main() {
  int array[100], n, c, d, swap;
  printf("Enter number of elements\n");
  scanf("%d", &n);
  printf("Enter %d integers\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  for (c = 0; c < (n - 1); c++) {
    for (d = 0; d < n - c - 1; d++) {
      if (array[d] > array[d + 1]) {
        swap = array[d];
        array[d] = array[d + 1];
        array[d + 1] = swap;
      }
    }
  }
  printf("Sorted list:\n");
  for (c = 0; c < n; c++)
    printf("%d\n", array[c]);
  return 0;
}
```