ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<msort>:
  endbr64
  push   %r14
  sub    %rdi,%rsi
  mov    $0x1e,%ecx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x100,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  rep stos %rax,%es:(%rdi)
  test   %r13,%r13
  je     L61
  nopl   (%rax)
L9:
  lea    0x0(%r13,%rbp,1),%rax
  mov    %r13,%rdi
  xor    %ebx,%ebx
  mov    (%rax),%r13
  movq   $0x0,(%rax)
  jmp    L34
  xchg   %ax,%ax
L84:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  xor    %eax,%eax
  call   <merge@plt>
  movq   $0x0,(%r14,%rbx,8)
  add    $0x1,%rbx
  movslq %eax,%rdi
  cmp    $0x1d,%rbx
  je     L2
L34:
  mov    (%r14,%rbx,8),%rsi
  movslq %ebx,%rax
  test   %rsi,%rsi
  jne    L84
  mov    %rdi,(%rsp,%rax,8)
  test   %r13,%r13
  jne    L9
L61:
  lea    0xf0(%rsp),%rbx
  xor    %edi,%edi
  nopl   0x0(%rax)
L41:
  mov    (%r14),%rsi
  test   %rsi,%rsi
  je     L15
  mov    %rbp,%rcx
  mov    %r12,%rdx
  xor    %eax,%eax
  call   <merge@plt>
  movslq %eax,%rdi
L15:
  add    $0x8,%r14
  cmp    %r14,%rbx
  jne    L41
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x100,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L2:
  mov    $0x1d,%eax
  mov    %rdi,(%rsp,%rax,8)
  test   %r13,%r13
  jne    L9
  jmp    L61
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *msort(void *list, void **next, int (*cmp)(void *, void *)) {
  unsigned long offset;
  char *ep;
  char *set[30];
  int i;
  offset = (unsigned long)next - (unsigned long)list;
  for (i = 0; i < 30; i++)
    set[i] = 0;
  while (list) {
    ep = list;
    list = (*(char **)(((unsigned long)list) + offset));
    (*(char **)(((unsigned long)ep) + offset)) = 0;
    for (i = 0; i < 30 - 1 && set[i] != 0; i++) {
      ep = merge(ep, set[i], cmp, offset);
      set[i] = 0;
    }
    set[i] = ep;
  }
  ep = 0;
  for (i = 0; i < 30; i++)
    if (set[i])
      ep = merge(ep, set[i], cmp, offset);
  return ep;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<msort>:
  endbr64
  push   %r14
  sub    %rdi,%rsi
  mov    $0x1e,%ecx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x100,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  rep stos %rax,%es:(%rdi)
  test   %r13,%r13
  je     L18
  nopl   (%rax)
L15:
  lea    0x0(%r13,%rbp,1),%rax
  mov    %r13,%rdi
  xor    %ebx,%ebx
  mov    (%rax),%r13
  movq   $0x0,(%rax)
  jmp    L39
  xchg   %ax,%ax
L69:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  xor    %eax,%eax
  call   <merge@plt>
  movq   $0x0,(%r14,%rbx,8)
  add    $0x1,%rbx
  movslq %eax,%rdi
  cmp    $0x1d,%rbx
  je     L54
L39:
  mov    (%r14,%rbx,8),%rsi
  movslq %ebx,%rax
  test   %rsi,%rsi
  jne    L69
  mov    %rdi,(%rsp,%rax,8)
  test   %r13,%r13
  jne    L15
L18:
  lea    0xf0(%rsp),%rbx
  xor    %edi,%edi
  nopl   0x0(%rax)
L37:
  mov    (%r14),%rsi
  test   %rsi,%rsi
  je     L64
  mov    %rbp,%rcx
  mov    %r12,%rdx
  xor    %eax,%eax
  call   <merge@plt>
  movslq %eax,%rdi
L64:
  add    $0x8,%r14
  cmp    %r14,%rbx
  jne    L37
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x100,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L54:
  mov    $0x1d,%eax
  mov    %rdi,(%rsp,%rax,8)
  test   %r13,%r13
  jne    L15
  jmp    L18
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *msort(void *list, void **next, int (*cmp)(void *, void *)) {
  unsigned long offset;
  char *ep;
  char *set[30];
  int i;
  offset = (unsigned long)next - (unsigned long)list;
  for (i = 0; i < 30; i++)
    set[i] = 0;
  while (list) {
    ep = list;
    list = (*(char **)(((unsigned long)list) + offset));
    (*(char **)(((unsigned long)ep) + offset)) = 0;
    for (i = 0; i < 30 - 1 && set[i] != 0; i++) {
      ep = merge(ep, set[i], cmp, offset);
      set[i] = 0;
    }
    set[i] = ep;
  }
  ep = 0;
  for (i = 0; i < 30; i++)
    if (set[i])
      ep = merge(ep, set[i], cmp, offset);
  return ep;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <createpass@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <passwd@plt>
  test   %eax,%eax
  je     L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D58
type_guessed: string
name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D54
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D2
type_guessed: string
name: disassemble_data
arguments: tag: D52
type_guessed: string
name: disassemble_data
arguments: tag: D61
type_guessed: string

tool: D58: Now Test Passwd.c


tool: D5: Test createpass():
Enter Your Password:


tool: D54: %s

tool: D12: CREATING PASSWORD...


tool: D2: PASSWORD CREATED SUCCESSFULLY!
File name:"passwd"

tool: D52: Now, you enter.


tool: D61: 	Enter Password:


assistant: ```c
int main(void) {
  char a[20];
  printf("Now Test Passwd.c\n");
  printf("Test createpass():\n"
         "Enter Your Password:\n");
  scanf("%s", a);
  printf("CREATING PASSWORD...\n");
  createpass(a);
  printf("PASSWORD CREATED SUCCESSFULLY!\nFile name:\"passwd\"");
  printf("Now, you enter.\n");
  do {
    printf("\tEnter Password:\n");
  } while (!passwd());
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <createpass@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rbx
L18:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <passwd@plt>
  test   %eax,%eax
  je     L18
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D64
type: string
name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D41
type: string
name: read_data
arguments: label: D58
type: string
name: read_data
arguments: label: D10
type: string

tool: D17: Now Test Passwd.c


tool: D64: Test createpass():
Enter Your Password:


tool: D1: %s

tool: D29: CREATING PASSWORD...


tool: D41: PASSWORD CREATED SUCCESSFULLY!
File name:"passwd"

tool: D58: Now, you enter.


tool: D10: 	Enter Password:


assistant: ```c
int main(void) {
  char a[20];
  printf("Now Test Passwd.c\n");
  printf("Test createpass():\n"
         "Enter Your Password:\n");
  scanf("%s", a);
  printf("CREATING PASSWORD...\n");
  createpass(a);
  printf("PASSWORD CREATED SUCCESSFULLY!\nFile name:\"passwd\"");
  printf("Now, you enter.\n");
  do {
    printf("\tEnter Password:\n");
  } while (!passwd());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D54(%rip),%rdi
  push   %rbx
  lea    D55(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <createpass@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <passwd@plt>
  test   %eax,%eax
  je     L3
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D54
type_guessed: string
name: parse_data
arguments: label: D55
type_guessed: string
name: parse_data
arguments: label: D41
type_guessed: string
name: parse_data
arguments: label: D16
type_guessed: string
name: parse_data
arguments: label: D62
type_guessed: string
name: parse_data
arguments: label: D44
type_guessed: string
name: parse_data
arguments: label: D27
type_guessed: string

tool: D54: Now Test Passwd.c


tool: D55: 	Enter Password:


tool: D41: Test createpass():
Enter Your Password:


tool: D16: %s

tool: D62: CREATING PASSWORD...


tool: D44: PASSWORD CREATED SUCCESSFULLY!
File name:"passwd"

tool: D27: Now, you enter.


assistant: ```c
int main(void) {
  char a[20];
  printf("Now Test Passwd.c\n");
  printf("Test createpass():\n"
         "Enter Your Password:\n");
  scanf("%s", a);
  printf("CREATING PASSWORD...\n");
  createpass(a);
  printf("PASSWORD CREATED SUCCESSFULLY!\nFile name:\"passwd\"");
  printf("Now, you enter.\n");
  do {
    printf("\tEnter Password:\n");
  } while (!passwd());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D37(%rip),%rdi
  push   %rbx
  lea    D63(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <createpass@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rbx,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <passwd@plt>
  test   %eax,%eax
  je     L17
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D37
data_type: string
name: disassemble_data
arguments: data_label: D63
data_type: string
name: disassemble_data
arguments: data_label: D65
data_type: string
name: disassemble_data
arguments: data_label: D34
data_type: string
name: disassemble_data
arguments: data_label: D62
data_type: string
name: disassemble_data
arguments: data_label: D26
data_type: string
name: disassemble_data
arguments: data_label: D45
data_type: string

tool: D37: Now Test Passwd.c


tool: D63: 	Enter Password:


tool: D65: Test createpass():
Enter Your Password:


tool: D34: %s

tool: D62: CREATING PASSWORD...


tool: D26: PASSWORD CREATED SUCCESSFULLY!
File name:"passwd"

tool: D45: Now, you enter.


assistant: ```c
int main(void) {
  char a[20];
  printf("Now Test Passwd.c\n");
  printf("Test createpass():\n"
         "Enter Your Password:\n");
  scanf("%s", a);
  printf("CREATING PASSWORD...\n");
  createpass(a);
  printf("PASSWORD CREATED SUCCESSFULLY!\nFile name:\"passwd\"");
  printf("Now, you enter.\n");
  do {
    printf("\tEnter Password:\n");
  } while (!passwd());
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_upper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L16
L1:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L1
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void str_upper(char *str) {
  int i = 0;
  int length = strlen(str);
  for (i = 0; i < length; i++)
    str[i] = toupper(str[i]);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_upper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L5
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rbp
L9:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void str_upper(char *str) {
  int i = 0;
  int length = strlen(str);
  for (i = 0; i < length; i++)
    str[i] = toupper(str[i]);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_upper>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L3
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  xchg   %ax,%ax
L2:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L2
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void str_upper(char *str) {
  int i = 0;
  int length = strlen(str);
  for (i = 0; i < length; i++)
    str[i] = toupper(str[i]);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_upper>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L10
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  xchg   %ax,%ax
L0:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L0
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void str_upper(char *str) {
  int i = 0;
  int length = strlen(str);
  for (i = 0; i < length; i++)
    str[i] = toupper(str[i]);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tuple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jge    L8
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L8:
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int64_t tuple(const int32_t x, const int32_t y) {
  int_fast32_t min, max;
  if (x < y) {
    min = x;
    max = y;
  } else {
    min = y;
    max = x;
  }
  return (max * (max + 1)) / 2 + min;
}
```
user: What is the c source code of the assembly code below:

```asm
<tuple>:
  endbr64
  mov    %esi,%ecx
  cmp    %rsi,%rdi
  jge    L4
  mov    %edi,%ecx
  mov    %esi,%edi
L4:
  lea    0x1(%rdi),%edx
  imul   %edi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int64_t tuple(const int32_t x, const int32_t y) {
  int_fast32_t min, max;
  if (x < y) {
    min = x;
    max = y;
  } else {
    min = y;
    max = x;
  }
  return (max * (max + 1)) / 2 + min;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tuple>:
  endbr64
  cmp    %rsi,%rdi
  mov    %esi,%ecx
  cmovge %edi,%esi
  cmovl  %edi,%ecx
  lea    0x1(%rsi),%edx
  imul   %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int64_t tuple(const int32_t x, const int32_t y) {
  int_fast32_t min, max;
  if (x < y) {
    min = x;
    max = y;
  } else {
    min = y;
    max = x;
  }
  return (max * (max + 1)) / 2 + min;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tuple>:
  endbr64
  cmp    %rsi,%rdi
  mov    %esi,%ecx
  cmovge %edi,%esi
  cmovl  %edi,%ecx
  lea    0x1(%rsi),%edx
  imul   %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %ecx,%eax
  ret
```

assistant: ```c
int64_t tuple(const int32_t x, const int32_t y) {
  int_fast32_t min, max;
  if (x < y) {
    min = x;
    max = y;
  } else {
    min = y;
    max = x;
  }
  return (max * (max + 1)) / 2 + min;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L16
L9:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L16
L3:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L16:
  leave
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *t;
  int l;
  if (!s)
    return 0;
  l = strlen(s) + 1;
  t = (char *)malloc(l);
  if (!t)
    return 0;
  memcpy(t, s, l);
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  mov    %rax,%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *t;
  int l;
  if (!s)
    return 0;
  l = strlen(s) + 1;
  t = (char *)malloc(l);
  if (!t)
    return 0;
  memcpy(t, s, l);
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strdup>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
L4:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *t;
  int l;
  if (!s)
    return 0;
  l = strlen(s) + 1;
  t = (char *)malloc(l);
  if (!t)
    return 0;
  memcpy(t, s, l);
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strdup>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
L1:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *t;
  int l;
  if (!s)
    return 0;
  l = strlen(s) + 1;
  t = (char *)malloc(l);
  if (!t)
    return 0;
  memcpy(t, s, l);
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L3:
  mov    $0x3e7,%edi
  call   <myclock@plt>
  mov    $0x0,%eax
  call   <mywrapper@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L3
```

assistant: ```c
void loop() {
  while (1) {
    myclock(999);
    mywrapper();
    sleep(1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
L0:
  mov    $0x3e7,%edi
  call   <myclock@plt>
  mov    $0x0,%eax
  call   <mywrapper@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L0
```

assistant: ```c
void loop() {
  while (1) {
    myclock(999);
    mywrapper();
    sleep(1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x3e7,%edi
  call   <myclock@plt>
  xor    %eax,%eax
  call   <mywrapper@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L8
```

assistant: ```c
void loop() {
  while (1) {
    myclock(999);
    mywrapper();
    sleep(1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x3e7,%edi
  call   <myclock@plt>
  xor    %eax,%eax
  call   <mywrapper@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L5
```

assistant: ```c
void loop() {
  while (1) {
    myclock(999);
    mywrapper();
    sleep(1);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x7f,-0x4(%rbp)
  addq   $0x2,-0x18(%rbp)
  jmp    L18
L13:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(char *v, signed int M) {
  signed int h = 0;
  signed int a = 127;
  v += 2;
  for (; *v != '\0'; v++) {
    h = (a * h + (signed int)*v) % M;
  }
  return ((unsigned int)h);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  lea    0x2(%rdi),%r8
  movzbl 0x2(%rdi),%ecx
  test   %cl,%cl
  je     L4
  mov    $0x0,%edx
L23:
  mov    %edx,%eax
  shl    $0x7,%eax
  sub    %edx,%eax
  movsbl %cl,%ecx
  add    %ecx,%eax
  cltd
  idiv   %esi
  add    $0x1,%r8
  movzbl (%r8),%ecx
  test   %cl,%cl
  jne    L23
L6:
  mov    %edx,%eax
  ret
L4:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
unsigned int hash(char *v, signed int M) {
  signed int h = 0;
  signed int a = 127;
  v += 2;
  for (; *v != '\0'; v++) {
    h = (a * h + (signed int)*v) % M;
  }
  return ((unsigned int)h);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  movsbl 0x2(%rdi),%ecx
  lea    0x2(%rdi),%r8
  test   %cl,%cl
  je     L4
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %edx,%eax
  add    $0x1,%r8
  shl    $0x7,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  movsbl (%r8),%ecx
  cltd
  idiv   %esi
  test   %cl,%cl
  jne    L17
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash(char *v, signed int M) {
  signed int h = 0;
  signed int a = 127;
  v += 2;
  for (; *v != '\0'; v++) {
    h = (a * h + (signed int)*v) % M;
  }
  return ((unsigned int)h);
}
```