ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<mat_inverse_matrix_d3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movq   %xmm0,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <mat_get_determinant_d3@plt>
  movsd  %xmm0,0x8(%rsp)
  call   <mat_Dabs@plt>
  mov    $0x0,%eax
  movq   %r12,%xmm4
  comisd %xmm0,%xmm4
  jbe    L8
L29:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  movsd  0x20(%rbx),%xmm0
  movsd  0x40(%rbx),%xmm3
  movsd  0x28(%rbx),%xmm5
  movsd  0x38(%rbx),%xmm6
  movapd %xmm0,%xmm1
  mulsd  %xmm3,%xmm1
  movapd %xmm5,%xmm2
  mulsd  %xmm6,%xmm2
  subsd  %xmm2,%xmm1
  movsd  0x8(%rsp),%xmm10
  divsd  %xmm10,%xmm1
  movsd  %xmm1,0x10(%rsp)
  movsd  0x30(%rbx),%xmm2
  movsd  0x18(%rbx),%xmm4
  movapd %xmm5,%xmm1
  mulsd  %xmm2,%xmm1
  movapd %xmm3,%xmm7
  mulsd  %xmm4,%xmm7
  subsd  %xmm7,%xmm1
  divsd  %xmm10,%xmm1
  movsd  %xmm1,0x28(%rsp)
  movapd %xmm6,%xmm1
  mulsd  %xmm4,%xmm1
  movapd %xmm0,%xmm7
  mulsd  %xmm2,%xmm7
  subsd  %xmm7,%xmm1
  divsd  %xmm10,%xmm1
  movsd  %xmm1,0x40(%rsp)
  movsd  0x10(%rbx),%xmm1
  movsd  0x8(%rbx),%xmm8
  movapd %xmm6,%xmm7
  mulsd  %xmm1,%xmm7
  movapd %xmm3,%xmm9
  mulsd  %xmm8,%xmm9
  subsd  %xmm9,%xmm7
  divsd  %xmm10,%xmm7
  movsd  %xmm7,0x18(%rsp)
  movsd  (%rbx),%xmm7
  mulsd  %xmm7,%xmm3
  movapd %xmm2,%xmm9
  mulsd  %xmm1,%xmm9
  subsd  %xmm9,%xmm3
  divsd  %xmm10,%xmm3
  movsd  %xmm3,0x30(%rsp)
  mulsd  %xmm8,%xmm2
  mulsd  %xmm7,%xmm6
  subsd  %xmm6,%xmm2
  divsd  %xmm10,%xmm2
  movsd  %xmm2,0x48(%rsp)
  movapd %xmm5,%xmm2
  mulsd  %xmm8,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm1,%xmm3
  subsd  %xmm3,%xmm2
  divsd  %xmm10,%xmm2
  movsd  %xmm2,0x20(%rsp)
  mulsd  %xmm4,%xmm1
  mulsd  %xmm7,%xmm5
  subsd  %xmm5,%xmm1
  divsd  %xmm10,%xmm1
  movsd  %xmm1,0x38(%rsp)
  mulsd  %xmm7,%xmm0
  mulsd  %xmm8,%xmm4
  subsd  %xmm4,%xmm0
  divsd  %xmm10,%xmm0
  movsd  %xmm0,0x50(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <mat_copy_matrix_d3@plt>
  mov    $0x1,%eax
  jmp    L29
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mat_inverse_matrix_d3(double m[3][3], double a[3][3], const double precision) {
  double det;
  double c[3][3];
  det = mat_get_determinant_d3(a);
  if (mat_Dabs(det) < precision) {
    ;
    ;
    return 0;
  }
  c[0][0] = (a[1][1] * a[2][2] - a[1][2] * a[2][1]) / det;
  c[1][0] = (a[1][2] * a[2][0] - a[1][0] * a[2][2]) / det;
  c[2][0] = (a[1][0] * a[2][1] - a[1][1] * a[2][0]) / det;
  c[0][1] = (a[2][1] * a[0][2] - a[2][2] * a[0][1]) / det;
  c[1][1] = (a[2][2] * a[0][0] - a[2][0] * a[0][2]) / det;
  c[2][1] = (a[2][0] * a[0][1] - a[2][1] * a[0][0]) / det;
  c[0][2] = (a[0][1] * a[1][2] - a[0][2] * a[1][1]) / det;
  c[1][2] = (a[0][2] * a[1][0] - a[0][0] * a[1][2]) / det;
  c[2][2] = (a[0][0] * a[1][1] - a[0][1] * a[1][0]) / det;
  mat_copy_matrix_d3(m, c);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mat_inverse_matrix_d3>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x68,%rsp
  movsd  %xmm0,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <mat_get_determinant_d3@plt>
  movsd  %xmm0,0x8(%rsp)
  call   <mat_Dabs@plt>
  movsd  (%rsp),%xmm2
  xor    %eax,%eax
  comisd %xmm0,%xmm2
  ja     L17
  movsd  0x20(%rbx),%xmm0
  movsd  0x28(%rbx),%xmm8
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rsi
  movsd  0x40(%rbx),%xmm4
  movsd  0x38(%rbx),%xmm9
  movapd %xmm0,%xmm2
  movapd %xmm8,%xmm3
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rbx),%xmm5
  mulsd  %xmm9,%xmm3
  movapd %xmm4,%xmm6
  movapd %xmm9,%xmm7
  mulsd  %xmm4,%xmm2
  movapd %xmm4,%xmm10
  mulsd  %xmm5,%xmm6
  subsd  %xmm3,%xmm2
  movsd  0x30(%rbx),%xmm3
  divsd  %xmm1,%xmm2
  movsd  %xmm2,0x10(%rsp)
  movapd %xmm8,%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm6,%xmm2
  movapd %xmm0,%xmm6
  mulsd  %xmm3,%xmm6
  divsd  %xmm1,%xmm2
  movsd  %xmm2,0x28(%rsp)
  movapd %xmm9,%xmm2
  mulsd  %xmm5,%xmm2
  subsd  %xmm6,%xmm2
  movsd  0x8(%rbx),%xmm6
  mulsd  %xmm6,%xmm10
  divsd  %xmm1,%xmm2
  movsd  %xmm2,0x40(%rsp)
  movsd  0x10(%rbx),%xmm2
  mulsd  %xmm2,%xmm7
  subsd  %xmm10,%xmm7
  movapd %xmm3,%xmm10
  mulsd  %xmm2,%xmm10
  mulsd  %xmm6,%xmm3
  divsd  %xmm1,%xmm7
  movsd  %xmm7,0x18(%rsp)
  movsd  (%rbx),%xmm7
  mulsd  %xmm7,%xmm4
  mulsd  %xmm7,%xmm9
  subsd  %xmm10,%xmm4
  subsd  %xmm9,%xmm3
  divsd  %xmm1,%xmm4
  divsd  %xmm1,%xmm3
  movsd  %xmm4,0x30(%rsp)
  movapd %xmm0,%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  %xmm7,%xmm0
  mulsd  %xmm5,%xmm2
  mulsd  %xmm6,%xmm5
  subsd  %xmm5,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm3,0x48(%rsp)
  movapd %xmm8,%xmm3
  mulsd  %xmm6,%xmm3
  mulsd  %xmm7,%xmm8
  subsd  %xmm4,%xmm3
  subsd  %xmm8,%xmm2
  divsd  %xmm1,%xmm3
  movsd  %xmm0,0x50(%rsp)
  divsd  %xmm1,%xmm2
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm2,0x38(%rsp)
  call   <mat_copy_matrix_d3@plt>
  mov    $0x1,%eax
L17:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mat_inverse_matrix_d3(double m[3][3], double a[3][3], const double precision) {
  double det;
  double c[3][3];
  det = mat_get_determinant_d3(a);
  if (mat_Dabs(det) < precision) {
    ;
    ;
    return 0;
  }
  c[0][0] = (a[1][1] * a[2][2] - a[1][2] * a[2][1]) / det;
  c[1][0] = (a[1][2] * a[2][0] - a[1][0] * a[2][2]) / det;
  c[2][0] = (a[1][0] * a[2][1] - a[1][1] * a[2][0]) / det;
  c[0][1] = (a[2][1] * a[0][2] - a[2][2] * a[0][1]) / det;
  c[1][1] = (a[2][2] * a[0][0] - a[2][0] * a[0][2]) / det;
  c[2][1] = (a[2][0] * a[0][1] - a[2][1] * a[0][0]) / det;
  c[0][2] = (a[0][1] * a[1][2] - a[0][2] * a[1][1]) / det;
  c[1][2] = (a[0][2] * a[1][0] - a[0][0] * a[1][2]) / det;
  c[2][2] = (a[0][0] * a[1][1] - a[0][1] * a[1][0]) / det;
  mat_copy_matrix_d3(m, c);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mat_inverse_matrix_d3>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x78,%rsp
  movsd  %xmm0,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <mat_get_determinant_d3@plt>
  movapd %xmm0,%xmm4
  movsd  %xmm0,0x8(%rsp)
  unpcklpd %xmm4,%xmm4
  movaps %xmm4,0x10(%rsp)
  call   <mat_Dabs@plt>
  movsd  (%rsp),%xmm2
  xor    %eax,%eax
  comisd %xmm0,%xmm2
  ja     L12
  movsd  0x40(%rbx),%xmm9
  movsd  0x20(%rbx),%xmm5
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  movsd  0x28(%rbx),%xmm11
  movupd 0x30(%rbx),%xmm6
  movupd (%rbx),%xmm0
  movsd  0x38(%rbx),%xmm8
  movapd %xmm5,%xmm7
  movapd %xmm9,%xmm2
  movsd  0x10(%rbx),%xmm13
  movapd %xmm6,%xmm12
  movapd %xmm11,%xmm14
  movapd 0x10(%rsp),%xmm4
  unpcklpd %xmm8,%xmm7
  unpcklpd %xmm9,%xmm14
  unpckhpd %xmm0,%xmm12
  movsd  0x30(%rbx),%xmm10
  unpcklpd %xmm13,%xmm2
  movupd 0x10(%rbx),%xmm3
  unpcklpd %xmm0,%xmm6
  movsd  0x8(%rsp),%xmm1
  mulpd  %xmm14,%xmm12
  unpcklpd %xmm10,%xmm8
  mulpd  %xmm7,%xmm2
  mulpd  %xmm7,%xmm6
  subpd  %xmm12,%xmm2
  movapd %xmm10,%xmm12
  unpcklpd %xmm12,%xmm12
  divpd  %xmm4,%xmm2
  movaps %xmm2,0x20(%rsp)
  movapd %xmm0,%xmm2
  unpckhpd %xmm12,%xmm2
  movapd %xmm11,%xmm12
  unpcklpd %xmm12,%xmm12
  mulpd  %xmm12,%xmm2
  movapd %xmm5,%xmm12
  unpcklpd %xmm9,%xmm12
  mulpd  %xmm3,%xmm12
  subpd  %xmm12,%xmm2
  movapd %xmm3,%xmm12
  movsd  %xmm9,%xmm12
  movapd %xmm3,%xmm9
  unpcklpd %xmm0,%xmm9
  divpd  %xmm4,%xmm2
  movaps %xmm2,0x30(%rsp)
  movapd %xmm0,%xmm2
  unpcklpd %xmm13,%xmm2
  mulpd  %xmm12,%xmm2
  movapd %xmm10,%xmm12
  unpcklpd %xmm11,%xmm12
  mulpd  %xmm12,%xmm9
  subpd  %xmm9,%xmm2
  divpd  %xmm4,%xmm2
  movaps %xmm2,0x40(%rsp)
  movapd %xmm3,%xmm2
  unpckhpd %xmm3,%xmm3
  unpckhpd %xmm0,%xmm2
  mulpd  %xmm8,%xmm2
  subpd  %xmm6,%xmm2
  divpd  %xmm4,%xmm2
  movaps %xmm2,0x50(%rsp)
  movapd %xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  mulsd  %xmm5,%xmm2
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movsd  %xmm2,0x60(%rsp)
  call   <mat_copy_matrix_d3@plt>
  mov    $0x1,%eax
L12:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mat_inverse_matrix_d3(double m[3][3], double a[3][3], const double precision) {
  double det;
  double c[3][3];
  det = mat_get_determinant_d3(a);
  if (mat_Dabs(det) < precision) {
    ;
    ;
    return 0;
  }
  c[0][0] = (a[1][1] * a[2][2] - a[1][2] * a[2][1]) / det;
  c[1][0] = (a[1][2] * a[2][0] - a[1][0] * a[2][2]) / det;
  c[2][0] = (a[1][0] * a[2][1] - a[1][1] * a[2][0]) / det;
  c[0][1] = (a[2][1] * a[0][2] - a[2][2] * a[0][1]) / det;
  c[1][1] = (a[2][2] * a[0][0] - a[2][0] * a[0][2]) / det;
  c[2][1] = (a[2][0] * a[0][1] - a[2][1] * a[0][0]) / det;
  c[0][2] = (a[0][1] * a[1][2] - a[0][2] * a[1][1]) / det;
  c[1][2] = (a[0][2] * a[1][0] - a[0][0] * a[1][2]) / det;
  c[2][2] = (a[0][0] * a[1][1] - a[0][1] * a[1][0]) / det;
  mat_copy_matrix_d3(m, c);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<help_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <printa@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D3
datatype: string

tool: D8: Show summary information about your Pit database. This command is as simple as:


tool: D3:    pit info


assistant: ```c
void help_info() {
  char *msg[] = {"Show summary information about your Pit database. This command is as simple as:\n", "   pit info\n", NULL};
  printa(msg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<help_info>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,(%rsp)
  lea    D9(%rip),%rax
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rdi
  call   <printa@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D9
datatype: string

tool: D17: Show summary information about your Pit database. This command is as simple as:


tool: D9:    pit info


assistant: ```c
void help_info() {
  char *msg[] = {"Show summary information about your Pit database. This command is as simple as:\n", "   pit info\n", NULL};
  printa(msg);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<help_info>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D15(%rip),%rax
  mov    %rsp,%rdi
  movq   $0x0,0x10(%rsp)
  mov    %rax,(%rsp)
  lea    D10(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <printa@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
datatype: string
name: extract_symbolic_data
arguments: tag: D10
datatype: string

tool: D15: Show summary information about your Pit database. This command is as simple as:


tool: D10:    pit info


assistant: ```c
void help_info() {
  char *msg[] = {"Show summary information about your Pit database. This command is as simple as:\n", "   pit info\n", NULL};
  printa(msg);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<help_info>:
  endbr64
  sub    $0x28,%rsp
  lea    D13(%rip),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D18(%rip),%rax
  movq   %rdx,%xmm0
  mov    %rsp,%rdi
  movq   $0x0,0x10(%rsp)
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <printa@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string

tool: D13: Show summary information about your Pit database. This command is as simple as:


tool: D18:    pit info


assistant: ```c
void help_info() {
  char *msg[] = {"Show summary information about your Pit database. This command is as simple as:\n", "   pit info\n", NULL};
  printa(msg);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<anexo2>:
  endbr64
  cmp    $0x21,%edi
  ja     L2
  mov    %edi,%edi
  lea    D4(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x32,%eax
  ret
  mov    $0x33,%eax
  ret
  mov    $0x34,%eax
  ret
  mov    $0x35,%eax
  ret
  mov    $0x36,%eax
  ret
  mov    $0x37,%eax
  ret
  mov    $0x38,%eax
  ret
  mov    $0x39,%eax
  ret
  mov    $0x41,%eax
  ret
  mov    $0x42,%eax
  ret
  mov    $0x43,%eax
  ret
  mov    $0x44,%eax
  ret
  mov    $0x45,%eax
  ret
  mov    $0x46,%eax
  ret
  mov    $0x47,%eax
  ret
  mov    $0x48,%eax
  ret
  mov    $0x49,%eax
  ret
  mov    $0x4a,%eax
  ret
  mov    $0x4b,%eax
  ret
  mov    $0x4c,%eax
  ret
  mov    $0x4d,%eax
  ret
  mov    $0x4e,%eax
  ret
  mov    $0x50,%eax
  ret
  mov    $0x51,%eax
  ret
  mov    $0x52,%eax
  ret
  mov    $0x53,%eax
  ret
  mov    $0x54,%eax
  ret
  mov    $0x55,%eax
  ret
  mov    $0x56,%eax
  ret
  mov    $0x57,%eax
  ret
  mov    $0x58,%eax
  ret
  mov    $0x59,%eax
  ret
  mov    $0x5a,%eax
  ret
L2:
  mov    $0x20,%eax
  ret
  mov    $0x31,%eax
  ret
```

assistant: ```c
char anexo2(const unsigned int n) {
  if (n == 0)
    return '1';
  else if (n == 1)
    return '2';
  else if (n == 2)
    return '3';
  else if (n == 3)
    return '4';
  else if (n == 4)
    return '5';
  else if (n == 5)
    return '6';
  else if (n == 6)
    return '7';
  else if (n == 7)
    return '8';
  else if (n == 8)
    return '9';
  else if (n == 9)
    return 'A';
  else if (n == 10)
    return 'B';
  else if (n == 11)
    return 'C';
  else if (n == 12)
    return 'D';
  else if (n == 13)
    return 'E';
  else if (n == 14)
    return 'F';
  else if (n == 15)
    return 'G';
  else if (n == 16)
    return 'H';
  else if (n == 17)
    return 'I';
  else if (n == 18)
    return 'J';
  else if (n == 19)
    return 'K';
  else if (n == 20)
    return 'L';
  else if (n == 21)
    return 'M';
  else if (n == 22)
    return 'N';
  else if (n == 23)
    return 'P';
  else if (n == 24)
    return 'Q';
  else if (n == 25)
    return 'R';
  else if (n == 26)
    return 'S';
  else if (n == 27)
    return 'T';
  else if (n == 28)
    return 'U';
  else if (n == 29)
    return 'V';
  else if (n == 30)
    return 'W';
  else if (n == 31)
    return 'X';
  else if (n == 32)
    return 'Y';
  else if (n == 33)
    return 'Z';
  else
    return ' ';
  return ' ';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<anexo2>:
  endbr64
  mov    $0x20,%eax
  cmp    $0x21,%edi
  ja     L2
  mov    %edi,%edi
  lea    D1(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L2:
  ret
```

assistant: ```c
char anexo2(const unsigned int n) {
  if (n == 0)
    return '1';
  else if (n == 1)
    return '2';
  else if (n == 2)
    return '3';
  else if (n == 3)
    return '4';
  else if (n == 4)
    return '5';
  else if (n == 5)
    return '6';
  else if (n == 6)
    return '7';
  else if (n == 7)
    return '8';
  else if (n == 8)
    return '9';
  else if (n == 9)
    return 'A';
  else if (n == 10)
    return 'B';
  else if (n == 11)
    return 'C';
  else if (n == 12)
    return 'D';
  else if (n == 13)
    return 'E';
  else if (n == 14)
    return 'F';
  else if (n == 15)
    return 'G';
  else if (n == 16)
    return 'H';
  else if (n == 17)
    return 'I';
  else if (n == 18)
    return 'J';
  else if (n == 19)
    return 'K';
  else if (n == 20)
    return 'L';
  else if (n == 21)
    return 'M';
  else if (n == 22)
    return 'N';
  else if (n == 23)
    return 'P';
  else if (n == 24)
    return 'Q';
  else if (n == 25)
    return 'R';
  else if (n == 26)
    return 'S';
  else if (n == 27)
    return 'T';
  else if (n == 28)
    return 'U';
  else if (n == 29)
    return 'V';
  else if (n == 30)
    return 'W';
  else if (n == 31)
    return 'X';
  else if (n == 32)
    return 'Y';
  else if (n == 33)
    return 'Z';
  else
    return ' ';
  return ' ';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<anexo2>:
  endbr64
  mov    $0x20,%eax
  cmp    $0x21,%edi
  ja     L0
  mov    %edi,%edi
  lea    D9(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L0:
  ret
```

assistant: ```c
char anexo2(const unsigned int n) {
  if (n == 0)
    return '1';
  else if (n == 1)
    return '2';
  else if (n == 2)
    return '3';
  else if (n == 3)
    return '4';
  else if (n == 4)
    return '5';
  else if (n == 5)
    return '6';
  else if (n == 6)
    return '7';
  else if (n == 7)
    return '8';
  else if (n == 8)
    return '9';
  else if (n == 9)
    return 'A';
  else if (n == 10)
    return 'B';
  else if (n == 11)
    return 'C';
  else if (n == 12)
    return 'D';
  else if (n == 13)
    return 'E';
  else if (n == 14)
    return 'F';
  else if (n == 15)
    return 'G';
  else if (n == 16)
    return 'H';
  else if (n == 17)
    return 'I';
  else if (n == 18)
    return 'J';
  else if (n == 19)
    return 'K';
  else if (n == 20)
    return 'L';
  else if (n == 21)
    return 'M';
  else if (n == 22)
    return 'N';
  else if (n == 23)
    return 'P';
  else if (n == 24)
    return 'Q';
  else if (n == 25)
    return 'R';
  else if (n == 26)
    return 'S';
  else if (n == 27)
    return 'T';
  else if (n == 28)
    return 'U';
  else if (n == 29)
    return 'V';
  else if (n == 30)
    return 'W';
  else if (n == 31)
    return 'X';
  else if (n == 32)
    return 'Y';
  else if (n == 33)
    return 'Z';
  else
    return ' ';
  return ' ';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2b,-0x30(%rbp)
  movl   $0x35,-0x2c(%rbp)
  movl   $0xc,-0x28(%rbp)
  movl   $0x40,-0x24(%rbp)
  movl   $0xf,-0x20(%rbp)
  movl   $0x43,-0x1c(%rbp)
  movl   $0x57,-0x18(%rbp)
  movl   $0xa,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x5a,-0xc(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x9,-0x34(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L13
L19:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L13:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L19
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%ecx
  lea    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <qsort@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L14
L10:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L14:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D22
datatype: string

tool: D16: Unsorted Array

tool: D15:  %d

tool: D22: 
Sorted Array

assistant: ```c
int main(void) {
  int i, left, right, v[10] = {43, 53, 12, 64, 15, 67, 87, 10, 6, 90};
  left = 0;
  right = 9;
  printf("Unsorted Array\n");
  for (i = 0; i <= 9; ++i)
    printf(" %d", v[i]);
  qsort(v, left, right);
  printf("\nSorted Array\n");
  for (i = 0; i <= 9; ++i)
    printf(" %d", v[i]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2b,(%rsp)
  movl   $0x35,0x4(%rsp)
  movl   $0xc,0x8(%rsp)
  movl   $0x40,0xc(%rsp)
  movl   $0xf,0x10(%rsp)
  movl   $0x43,0x14(%rsp)
  movl   $0x57,0x18(%rsp)
  movl   $0xa,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  movl   $0x5a,0x24(%rsp)
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
  lea    D13(%rip),%r13
L18:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L18
  mov    %rsp,%rdi
  mov    $0x9,%edx
  mov    $0x0,%esi
  call   <qsort@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    D13(%rip),%rbp
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L15
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D38
datatype: string
name: unpack_data
arguments: data_label: D13
datatype: string
name: unpack_data
arguments: data_label: D17
datatype: string

tool: D38: Unsorted Array

tool: D13:  %d

tool: D17: 
Sorted Array

assistant: ```c
int main(void) {
  int i, left, right, v[10] = {43, 53, 12, 64, 15, 67, 87, 10, 6, 90};
  left = 0;
  right = 9;
  printf("Unsorted Array\n");
  for (i = 0; i <= 9; ++i)
    printf(" %d", v[i]);
  qsort(v, left, right);
  printf("\nSorted Array\n");
  for (i = 0; i <= 9; ++i)
    printf(" %d", v[i]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%rdi
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x350000002b,%rax
  mov    %rsp,%r14
  lea    0x28(%rsp),%r12
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,(%rsp)
  movabs $0x400000000c,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x430000000f,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xa00000057,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x5a00000006,%rax
  mov    %rax,0x20(%rsp)
  call   <puts@plt>
  nopl   0x0(%rax)
L21:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L21
  mov    %r14,%rdi
  mov    $0x9,%edx
  xor    %esi,%esi
  call   <qsort@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L4:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D5: Unsorted Array

tool: D4:  %d

tool: D1: 
Sorted Array

assistant: ```c
int main(void) {
  int i, left, right, v[10] = {43, 53, 12, 64, 15, 67, 87, 10, 6, 90};
  left = 0;
  right = 9;
  printf("Unsorted Array\n");
  for (i = 0; i <= 9; ++i)
    printf(" %d", v[i]);
  qsort(v, left, right);
  printf("\nSorted Array\n");
  for (i = 0; i <= 9; ++i)
    printf(" %d", v[i]);
  return 0;
}
```