ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<monotonic_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <syscall@plt>
  mov    -0x20(%rbp),%rax
  imul   $0xf4240,%rax,%rcx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  add    %rcx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
unsigned long long monotonic_us(void) {
  struct timespec ts;
  syscall(__NR_clock_gettime, CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000ULL + ts.tv_nsec / 1000;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<monotonic_us>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  imul   $0xf4240,(%rsp),%rax
  mov    0x8(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long monotonic_us(void) {
  struct timespec ts;
  syscall(__NR_clock_gettime, CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000ULL + ts.tv_nsec / 1000;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<monotonic_us>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rdx
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  movslq 0x8(%rsp),%rdx
  imul   $0xf4240,(%rsp),%rax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long monotonic_us(void) {
  struct timespec ts;
  syscall(__NR_clock_gettime, CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000ULL + ts.tv_nsec / 1000;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<monotonic_us>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  mov    %rsp,%rdx
  mov    (%rax),%esi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  movslq 0x8(%rsp),%rdx
  imul   $0xf4240,(%rsp),%rax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long monotonic_us(void) {
  struct timespec ts;
  syscall(__NR_clock_gettime, CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000ULL + ts.tv_nsec / 1000;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<EPIDividerCSSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x400d0000,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x3,-0x18(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x1,-0x18(%rbp)
  jg     L1
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  cltq
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    $0xffff,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L6
L1:
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  sub    $0x2,%eax
  shl    $0x4,%eax
  mov    $0xffff,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x18(%rbp),%eax
  sub    $0x2,%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L6:
  nop
  leave
  ret
```

assistant: ```c
void EPIDividerCSSet(uint32_t ui32Base, uint32_t ui32CS, uint32_t ui32Divider) {
  uint32_t ui32Reg;
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32CS < 4);
  if (ui32CS < 2) {
    ui32Reg = (*((volatile uint32_t *)(ui32Base + 0x00000004))) & ~(0xffff << (16 * ui32CS));
    ui32Reg |= ((ui32Divider & 0xffff) << (16 * ui32CS));
    (*((volatile uint32_t *)(ui32Base + 0x00000004))) = ui32Reg;
  } else {
    ui32Reg = ((*((volatile uint32_t *)(ui32Base + 0x00000008))) & ~(0xffff << (16 * (ui32CS - 2))));
    ui32Reg |= ((ui32Divider & 0xffff) << (16 * (ui32CS - 2)));
    (*((volatile uint32_t *)(ui32Base + 0x00000008))) = ui32Reg;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EPIDividerCSSet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  cmp    $0x400d0000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  cmp    $0x3,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  cmp    $0x1,%ebx
  jle    L13
  add    $0x8,%ebp
  movslq %ebp,%rbp
  mov    0x0(%rbp),%edx
  lea    -0x2(%rbx),%ecx
  shl    $0x4,%ecx
  mov    $0xffff,%eax
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  movzwl %r12w,%r12d
  shl    %cl,%r12d
  or     %eax,%r12d
  mov    %r12d,0x0(%rbp)
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  add    $0x4,%ebp
  movslq %ebp,%rbp
  mov    0x0(%rbp),%edx
  shl    $0x4,%ebx
  mov    %ebx,%ecx
  mov    $0xffff,%eax
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  movzwl %r12w,%r12d
  shl    %cl,%r12d
  or     %eax,%r12d
  mov    %r12d,0x0(%rbp)
  jmp    L9
```

assistant: ```c
void EPIDividerCSSet(uint32_t ui32Base, uint32_t ui32CS, uint32_t ui32Divider) {
  uint32_t ui32Reg;
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32CS < 4);
  if (ui32CS < 2) {
    ui32Reg = (*((volatile uint32_t *)(ui32Base + 0x00000004))) & ~(0xffff << (16 * ui32CS));
    ui32Reg |= ((ui32Divider & 0xffff) << (16 * ui32CS));
    (*((volatile uint32_t *)(ui32Base + 0x00000004))) = ui32Reg;
  } else {
    ui32Reg = ((*((volatile uint32_t *)(ui32Base + 0x00000008))) & ~(0xffff << (16 * (ui32CS - 2))));
    ui32Reg |= ((ui32Divider & 0xffff) << (16 * (ui32CS - 2)));
    (*((volatile uint32_t *)(ui32Base + 0x00000008))) = ui32Reg;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<EPIDividerCSSet>:
  endbr64
  push   %r12
  cmp    $0x400d0000,%edi
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  sete   %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %esi,%ebx
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x3,%ebx
  setle  %dil
  call   <ASSERT@plt>
  movzwl %r12w,%edx
  cmp    $0x1,%ebx
  jle    L5
  lea    -0x2(%rbx),%ecx
  add    $0x8,%ebp
  mov    $0xffff,%eax
  movslq %ebp,%rbp
  shl    $0x4,%ecx
  mov    0x0(%rbp),%esi
  shl    %cl,%eax
  shl    %cl,%edx
  not    %eax
  and    %esi,%eax
  or     %edx,%eax
  mov    %eax,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L5:
  shl    $0x4,%ebx
  add    $0x4,%ebp
  mov    $0xffff,%esi
  movslq %ebp,%rbp
  mov    %ebx,%ecx
  mov    0x0(%rbp),%eax
  shl    %cl,%esi
  shl    %cl,%edx
  not    %esi
  and    %eax,%esi
  or     %esi,%edx
  mov    %edx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void EPIDividerCSSet(uint32_t ui32Base, uint32_t ui32CS, uint32_t ui32Divider) {
  uint32_t ui32Reg;
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32CS < 4);
  if (ui32CS < 2) {
    ui32Reg = (*((volatile uint32_t *)(ui32Base + 0x00000004))) & ~(0xffff << (16 * ui32CS));
    ui32Reg |= ((ui32Divider & 0xffff) << (16 * ui32CS));
    (*((volatile uint32_t *)(ui32Base + 0x00000004))) = ui32Reg;
  } else {
    ui32Reg = ((*((volatile uint32_t *)(ui32Base + 0x00000008))) & ~(0xffff << (16 * (ui32CS - 2))));
    ui32Reg |= ((ui32Divider & 0xffff) << (16 * (ui32CS - 2)));
    (*((volatile uint32_t *)(ui32Base + 0x00000008))) = ui32Reg;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<EPIDividerCSSet>:
  endbr64
  push   %r12
  cmp    $0x400d0000,%edi
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  sete   %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %esi,%ebx
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x3,%ebx
  setle  %dil
  call   <ASSERT@plt>
  movzwl %r12w,%edx
  cmp    $0x1,%ebx
  jle    L8
  lea    -0x2(%rbx),%ecx
  add    $0x8,%ebp
  mov    $0xffff,%eax
  movslq %ebp,%rbp
  shl    $0x4,%ecx
  mov    0x0(%rbp),%esi
  shl    %cl,%eax
  shl    %cl,%edx
  not    %eax
  and    %esi,%eax
  or     %edx,%eax
  mov    %eax,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L8:
  shl    $0x4,%ebx
  add    $0x4,%ebp
  mov    $0xffff,%esi
  movslq %ebp,%rbp
  mov    %ebx,%ecx
  mov    0x0(%rbp),%eax
  shl    %cl,%esi
  shl    %cl,%edx
  not    %esi
  and    %eax,%esi
  or     %esi,%edx
  mov    %edx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void EPIDividerCSSet(uint32_t ui32Base, uint32_t ui32CS, uint32_t ui32Divider) {
  uint32_t ui32Reg;
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32CS < 4);
  if (ui32CS < 2) {
    ui32Reg = (*((volatile uint32_t *)(ui32Base + 0x00000004))) & ~(0xffff << (16 * ui32CS));
    ui32Reg |= ((ui32Divider & 0xffff) << (16 * ui32CS));
    (*((volatile uint32_t *)(ui32Base + 0x00000004))) = ui32Reg;
  } else {
    ui32Reg = ((*((volatile uint32_t *)(ui32Base + 0x00000008))) & ~(0xffff << (16 * (ui32CS - 2))));
    ui32Reg |= ((ui32Divider & 0xffff) << (16 * (ui32CS - 2)));
    (*((volatile uint32_t *)(ui32Base + 0x00000008))) = ui32Reg;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x3,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <tohIterative@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  unsigned num_of_disks = 3;
  struct Stack *src, *dest, *aux;
  src = createStack(num_of_disks);
  aux = createStack(num_of_disks);
  dest = createStack(num_of_disks);
  tohIterative(num_of_disks, src, aux, dest);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <createStack@plt>
  mov    %rax,%rbx
  mov    $0x3,%edi
  call   <createStack@plt>
  mov    %rax,%rbp
  mov    $0x3,%edi
  call   <createStack@plt>
  mov    %rax,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <tohIterative@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unsigned num_of_disks = 3;
  struct Stack *src, *dest, *aux;
  src = createStack(num_of_disks);
  aux = createStack(num_of_disks);
  dest = createStack(num_of_disks);
  tohIterative(num_of_disks, src, aux, dest);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <createStack@plt>
  mov    $0x3,%edi
  mov    %rax,%rbp
  call   <createStack@plt>
  mov    $0x3,%edi
  mov    %rax,%r12
  call   <createStack@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  mov    %rax,%rcx
  call   <tohIterative@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  unsigned num_of_disks = 3;
  struct Stack *src, *dest, *aux;
  src = createStack(num_of_disks);
  aux = createStack(num_of_disks);
  dest = createStack(num_of_disks);
  tohIterative(num_of_disks, src, aux, dest);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <createStack@plt>
  mov    $0x3,%edi
  mov    %rax,%rbp
  call   <createStack@plt>
  mov    $0x3,%edi
  mov    %rax,%r12
  call   <createStack@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  mov    %rax,%rcx
  call   <tohIterative@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  unsigned num_of_disks = 3;
  struct Stack *src, *dest, *aux;
  src = createStack(num_of_disks);
  aux = createStack(num_of_disks);
  dest = createStack(num_of_disks);
  tohIterative(num_of_disks, src, aux, dest);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_nss_puavoadmins_getgrgid_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  cmpl   $0x22b,-0x4(%rbp)
  je     L15
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L0
L15:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fill_group@plt>
L0:
  leave
  ret
```

assistant: ```c
enum nss_status _nss_puavoadmins_getgrgid_r(const gid_t gid, struct group *const gr, char *const buf, const size_t bufsize, int *const errnop) {
  if (gid != 555) {
    *errnop = ENOENT;
    return NSS_STATUS_NOTFOUND;
  }
  return fill_group(gr, buf, bufsize, errnop);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_nss_puavoadmins_getgrgid_r>:
  endbr64
  cmp    $0x22b,%edi
  je     L8
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%r8)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  ret
L8:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %r8,%rcx
  call   <fill_group@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
enum nss_status _nss_puavoadmins_getgrgid_r(const gid_t gid, struct group *const gr, char *const buf, const size_t bufsize, int *const errnop) {
  if (gid != 555) {
    *errnop = ENOENT;
    return NSS_STATUS_NOTFOUND;
  }
  return fill_group(gr, buf, bufsize, errnop);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_nss_puavoadmins_getgrgid_r>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  cmp    $0x22b,%r9d
  je     L1
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%r8)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  ret
  nop
L1:
  mov    %r8,%rcx
  jmp    1050 <fill_group@plt>
```

assistant: ```c
enum nss_status _nss_puavoadmins_getgrgid_r(const gid_t gid, struct group *const gr, char *const buf, const size_t bufsize, int *const errnop) {
  if (gid != 555) {
    *errnop = ENOENT;
    return NSS_STATUS_NOTFOUND;
  }
  return fill_group(gr, buf, bufsize, errnop);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_nss_puavoadmins_getgrgid_r>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  cmp    $0x22b,%r9d
  je     L0
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%r8)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  ret
  nop
L0:
  mov    %r8,%rcx
  jmp    1050 <fill_group@plt>
```

assistant: ```c
enum nss_status _nss_puavoadmins_getgrgid_r(const gid_t gid, struct group *const gr, char *const buf, const size_t bufsize, int *const errnop) {
  if (gid != 555) {
    *errnop = ENOENT;
    return NSS_STATUS_NOTFOUND;
  }
  return fill_group(gr, buf, bufsize, errnop);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<npush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pop    %rax
  mov    %rsp,%r13
  mov    %r14,%rsp
  push   %rax
  mov    %rsp,%r14
  mov    %r13,%rsp
  subq   $0x8,(%r15)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void npush() {
  asm volatile("popq %%rax\n\t"
               "movq %%rsp, %%r13\n\t"
               "movq %%r14, %%rsp\n\t"
               "pushq %%rax\n\t"
               "movq %%rsp, %%r14\n\t"
               "movq %%r13, %%rsp\n\t"
               "subq $0x8, (%%r15)\n\t" ::
                   :);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<npush>:
  endbr64
  pop    %rax
  mov    %rsp,%r13
  mov    %r14,%rsp
  push   %rax
  mov    %rsp,%r14
  mov    %r13,%rsp
  subq   $0x8,(%r15)
  ret
```

assistant: ```c
void npush() {
  asm volatile("popq %%rax\n\t"
               "movq %%rsp, %%r13\n\t"
               "movq %%r14, %%rsp\n\t"
               "pushq %%rax\n\t"
               "movq %%rsp, %%r14\n\t"
               "movq %%r13, %%rsp\n\t"
               "subq $0x8, (%%r15)\n\t" ::
                   :);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<npush>:
  endbr64
  pop    %rax
  mov    %rsp,%r13
  mov    %r14,%rsp
  push   %rax
  mov    %rsp,%r14
  mov    %r13,%rsp
  subq   $0x8,(%r15)
  ret
```

assistant: ```c
void npush() {
  asm volatile("popq %%rax\n\t"
               "movq %%rsp, %%r13\n\t"
               "movq %%r14, %%rsp\n\t"
               "pushq %%rax\n\t"
               "movq %%rsp, %%r14\n\t"
               "movq %%r13, %%rsp\n\t"
               "subq $0x8, (%%r15)\n\t" ::
                   :);
}
```
user: What is the c source code of the assembly code below?

```asm
<npush>:
  endbr64
  pop    %rax
  mov    %rsp,%r13
  mov    %r14,%rsp
  push   %rax
  mov    %rsp,%r14
  mov    %r13,%rsp
  subq   $0x8,(%r15)
  ret
```

assistant: ```c
void npush() {
  asm volatile("popq %%rax\n\t"
               "movq %%rsp, %%r13\n\t"
               "movq %%r14, %%rsp\n\t"
               "pushq %%rax\n\t"
               "movq %%rsp, %%r14\n\t"
               "movq %%r13, %%rsp\n\t"
               "subq $0x8, (%%r15)\n\t" ::
                   :);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3f293d232b353726,%rax
  movabs $0x392825243b2a3827,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x362c3e2e222f2d32,%rax
  mov    %rax,-0x20(%rbp)
  movw   $0x3334,-0x18(%rbp)
  movb   $0x0,-0x16(%rbp)
  mov    -0x50(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L36
L8:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  sub    $0x20,%eax
  mov    %al,-0x3b(%rbp)
  movw   $0x6,-0x3a(%rbp)
  nop
L59:
  movsbl -0x3b(%rbp),%edx
  movzwl -0x3a(%rbp),%eax
  sub    $0x1,%eax
  mov    %ax,-0x3a(%rbp)
  movswl -0x3a(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L59
  jmp    L40
L63:
  movsbl -0x3b(%rbp),%edx
  movswl -0x3a(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L38
  mov    $0x2e,%eax
  jmp    L75
L38:
  mov    $0x2d,%eax
L75:
  mov    %eax,%edi
  call   <putchar@plt>
L40:
  movzwl -0x3a(%rbp),%eax
  mov    %eax,%edx
  sub    $0x1,%edx
  mov    %dx,-0x3a(%rbp)
  test   %ax,%ax
  jne    L63
  addq   $0x1,-0x38(%rbp)
L36:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char e[] = "&75+#=)?'8*;$%(92-/\".>,643";
  for (char *p = argv[1]; *p; p++) {
    char x = e[*p - 97] - 32;
    short i = 6;
    while (!((x >> --i) & 1))
      ;
    while (i--)
      putchar((x >> i) & 1 ? '.' : '-');
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x3f293d232b353726,%rax
  movabs $0x392825243b2a3827,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x362c3e2e222f2d32,%rax
  mov    %rax,0x10(%rsp)
  movw   $0x3334,0x18(%rsp)
  movb   $0x0,0x1a(%rsp)
  mov    0x8(%rsi),%r12
  movzbl (%r12),%eax
  test   %al,%al
  je     L6
L52:
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  movzbl (%rsp,%rax,1),%ebp
  sub    $0x20,%ebp
  mov    $0x6,%eax
  movsbl %bpl,%ebp
L49:
  mov    %eax,%ebx
  sub    $0x1,%eax
  bt     %eax,%ebp
  jae    L49
  sub    $0x2,%ebx
  test   %ax,%ax
  je     L41
L53:
  mov    %ebp,%edi
  mov    %ebx,%ecx
  sar    %cl,%edi
  and    $0x1,%edi
  add    $0x2d,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  sub    $0x1,%ebx
  test   %ax,%ax
  jne    L53
L41:
  add    $0x1,%r12
  movzbl (%r12),%eax
  test   %al,%al
  jne    L52
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char e[] = "&75+#=)?'8*;$%(92-/\".>,643";
  for (char *p = argv[1]; *p; p++) {
    char x = e[*p - 97] - 32;
    short i = 6;
    while (!((x >> --i) & 1))
      ;
    while (i--)
      putchar((x >> i) & 1 ? '.' : '-');
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D3(%rip),%xmm0
  mov    0x8(%rsi),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x1a(%rsp)
  movabs $0x362c3e2e222f2d32,%rax
  mov    %rax,0x10(%rsp)
  mov    $0x3334,%eax
  mov    %ax,0x18(%rsp)
  movaps %xmm0,(%rsp)
  movsbl 0x0(%rbp),%eax
  test   %al,%al
  je     L32
  nopw   0x0(%rax,%rax,1)
L20:
  sub    $0x61,%eax
  cltq
  movzbl (%rsp,%rax,1),%r12d
  mov    $0x6,%eax
  sub    $0x20,%r12d
  movsbl %r12b,%r12d
  nop
L22:
  mov    %eax,%ebx
  sub    $0x1,%eax
  bt     %eax,%r12d
  jae    L22
  sub    $0x2,%ebx
  test   %ax,%ax
  je     L52
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %ebx,%ecx
  mov    %r12d,%edi
  sar    %cl,%edi
  and    $0x1,%edi
  add    $0x2d,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  sub    $0x1,%ebx
  test   %ax,%ax
  jne    L26
L52:
  movsbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  test   %al,%al
  jne    L20
L32:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: byte[16]

tool: {"D3": [0x26,0x37,0x35,0x2b,0x23,0x3d,0x29,0x3f,0x27,0x38,0x2a,0x3b,0x24,0x25,0x28,0x39]}

assistant: ```c
int main(int argc, char *argv[]) {
  char e[] = "&75+#=)?'8*;$%(92-/\".>,643";
  for (char *p = argv[1]; *p; p++) {
    char x = e[*p - 97] - 32;
    short i = 6;
    while (!((x >> --i) & 1))
      ;
    while (i--)
      putchar((x >> i) & 1 ? '.' : '-');
  }
}
```