ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<mp_encode_int8>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    D21(%rip),%rax
  cmp    %ebx,(%rax)
  jle    L44
  mov    D17(%rip),%rax
  cmp    %ebx,(%rax)
  jle    L49
  mov    D2(%rip),%rax
  cmp    %ebx,(%rax)
  jg     L37
  mov    $0xd2,%esi
  mov    %rbp,%rdi
  call   <mp_store_u8@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <mp_store_u32@plt>
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  mov    $0xd0,%esi
  mov    %rbp,%rdi
  call   <mp_store_u8@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <mp_store_u8@plt>
  jmp    L47
L49:
  mov    $0xd1,%esi
  mov    %rbp,%rdi
  call   <mp_store_u8@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <mp_store_u16@plt>
  jmp    L47
L37:
  mov    $0xd3,%esi
  mov    %rbp,%rdi
  call   <mp_store_u8@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <mp_store_u64@plt>
  jmp    L47
```

assistant: ```c
char *mp_encode_int8(char *data, int64_t num) {
  assert(num < 0);
  if (num >= INT8_MIN) {
    data = mp_store_u8(data, 0xd0);
    return mp_store_u8(data, num);
  } else if (num >= INT16_MIN) {
    data = mp_store_u8(data, 0xd1);
    return mp_store_u16(data, num);
  } else if (num >= INT32_MIN) {
    data = mp_store_u8(data, 0xd2);
    return mp_store_u32(data, num);
  } else {
    data = mp_store_u8(data, 0xd3);
    return mp_store_u64(data, num);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<mp_encode_int8>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  shr    $0x1f,%edi
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    D8(%rip),%rax
  cmp    %ebp,(%rax)
  jle    L8
  mov    D2(%rip),%rax
  cmp    %ebp,(%rax)
  jle    L13
  mov    D22(%rip),%rax
  cmp    %ebp,(%rax)
  jg     L14
  mov    %r12,%rdi
  mov    $0xd2,%esi
  call   <mp_store_u8@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    10c0 <mp_store_u32@plt>
  nopl   0x0(%rax)
L14:
  mov    %r12,%rdi
  mov    $0xd3,%esi
  call   <mp_store_u8@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <mp_store_u64@plt>
  xchg   %ax,%ax
L8:
  mov    %r12,%rdi
  mov    $0xd0,%esi
  call   <mp_store_u8@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <mp_store_u8@plt>
  xchg   %ax,%ax
L13:
  mov    %r12,%rdi
  mov    $0xd1,%esi
  call   <mp_store_u8@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <mp_store_u16@plt>
```

assistant: ```c
char *mp_encode_int8(char *data, int64_t num) {
  assert(num < 0);
  if (num >= INT8_MIN) {
    data = mp_store_u8(data, 0xd0);
    return mp_store_u8(data, num);
  } else if (num >= INT16_MIN) {
    data = mp_store_u8(data, 0xd1);
    return mp_store_u16(data, num);
  } else if (num >= INT32_MIN) {
    data = mp_store_u8(data, 0xd2);
    return mp_store_u32(data, num);
  } else {
    data = mp_store_u8(data, 0xd3);
    return mp_store_u64(data, num);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mp_encode_int8>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  shr    $0x1f,%edi
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    D15(%rip),%rax
  cmp    %ebp,(%rax)
  jle    L3
  mov    D10(%rip),%rax
  cmp    %ebp,(%rax)
  jle    L18
  mov    D6(%rip),%rax
  cmp    %ebp,(%rax)
  jg     L17
  mov    %r12,%rdi
  mov    $0xd2,%esi
  call   <mp_store_u8@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    10c0 <mp_store_u32@plt>
  nopl   0x0(%rax)
L17:
  mov    %r12,%rdi
  mov    $0xd3,%esi
  call   <mp_store_u8@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <mp_store_u64@plt>
  xchg   %ax,%ax
L3:
  mov    %r12,%rdi
  mov    $0xd0,%esi
  call   <mp_store_u8@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <mp_store_u8@plt>
  xchg   %ax,%ax
L18:
  mov    %r12,%rdi
  mov    $0xd1,%esi
  call   <mp_store_u8@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <mp_store_u16@plt>
```

assistant: ```c
char *mp_encode_int8(char *data, int64_t num) {
  assert(num < 0);
  if (num >= INT8_MIN) {
    data = mp_store_u8(data, 0xd0);
    return mp_store_u8(data, num);
  } else if (num >= INT16_MIN) {
    data = mp_store_u8(data, 0xd1);
    return mp_store_u16(data, num);
  } else if (num >= INT32_MIN) {
    data = mp_store_u8(data, 0xd2);
    return mp_store_u32(data, num);
  } else {
    data = mp_store_u8(data, 0xd3);
    return mp_store_u64(data, num);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L22
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L22
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L22:
  mov    $0x0,%eax
  call   <get_default_receiver@plt>
  mov    %rax,-0x10(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L7
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D18
type_infered: string
name: parse_data
arguments: data_label: D5
type_infered: string

tool: D8: -h

tool: D18: usage: %s RECEIVER


tool: D5: hello %s!


assistant: ```c
int main(int argc, char *argv[]) {
  const char *progname = argv[0];
  if (argc > 1 && !strcmp(argv[1], "-h")) {
    printf("usage: %s RECEIVER\n", progname);
    exit(0);
  }
  const char *receiver = get_default_receiver();
  if (argc > 1)
    receiver = argv[1];
  printf("hello %s!\n", receiver);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rbp
  cmp    $0x1,%edi
  jle    L20
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  lea    D18(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L11
L26:
  mov    $0x0,%eax
  call   <get_default_receiver@plt>
  mov    0x8(%rbx),%rsi
L4:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L26
L20:
  mov    $0x0,%eax
  call   <get_default_receiver@plt>
  mov    %rax,%rsi
  jmp    L4
```

tool_calls: name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D24
type_infered: string

tool: D18: -h

tool: D12: hello %s!


tool: D24: usage: %s RECEIVER


assistant: ```c
int main(int argc, char *argv[]) {
  const char *progname = argv[0];
  if (argc > 1 && !strcmp(argv[1], "-h")) {
    printf("usage: %s RECEIVER\n", progname);
    exit(0);
  }
  const char *receiver = get_default_receiver();
  if (argc > 1)
    receiver = argv[1];
  printf("hello %s!\n", receiver);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rbp
  cmp    $0x1,%edi
  jle    L23
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  lea    D16(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L38
L37:
  xor    %eax,%eax
  call   <get_default_receiver@plt>
  mov    0x8(%rbx),%rsi
L0:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  xor    %eax,%eax
  call   <get_default_receiver@plt>
  mov    %rax,%rsi
  jmp    L0
L38:
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L37
```

tool_calls: name: unpack_data
arguments: data_label: D16
type: string
name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D14
type: string

tool: D16: -h

tool: D10: hello %s!


tool: D14: usage: %s RECEIVER


assistant: ```c
int main(int argc, char *argv[]) {
  const char *progname = argv[0];
  if (argc > 1 && !strcmp(argv[1], "-h")) {
    printf("usage: %s RECEIVER\n", progname);
    exit(0);
  }
  const char *receiver = get_default_receiver();
  if (argc > 1)
    receiver = argv[1];
  printf("hello %s!\n", receiver);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rbp
  cmp    $0x1,%edi
  jle    L16
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  lea    D23(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L27
L34:
  xor    %eax,%eax
  call   <get_default_receiver@plt>
  mov    0x8(%rbx),%rsi
L4:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  xor    %eax,%eax
  call   <get_default_receiver@plt>
  mov    %rax,%rsi
  jmp    L4
L27:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L34
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D23: -h

tool: D24: hello %s!


tool: D3: usage: %s RECEIVER


assistant: ```c
int main(int argc, char *argv[]) {
  const char *progname = argv[0];
  if (argc > 1 && !strcmp(argv[1], "-h")) {
    printf("usage: %s RECEIVER\n", progname);
    exit(0);
  }
  const char *receiver = get_default_receiver();
  if (argc > 1)
    receiver = argv[1];
  printf("hello %s!\n", receiver);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<handle_fork>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L19
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <handle_request@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L3
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void handle_fork(int msgsock) {
  if (fork() == 0) {
    handle_request(msgsock);
    exit(0);
  } else {
    close(msgsock);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<handle_fork>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L3
  mov    %ebx,%edi
  call   <handle_request@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L9:
  pop    %rbx
  ret
L3:
  mov    %ebx,%edi
  call   <close@plt>
  jmp    L9
```

assistant: ```c
void handle_fork(int msgsock) {
  if (fork() == 0) {
    handle_request(msgsock);
    exit(0);
  } else {
    close(msgsock);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<handle_fork>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <fork@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  jne    L5
  call   <handle_request@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    10a0 <exit@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  pop    %rbp
  jmp    1080 <close@plt>
```

assistant: ```c
void handle_fork(int msgsock) {
  if (fork() == 0) {
    handle_request(msgsock);
    exit(0);
  } else {
    close(msgsock);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<handle_fork>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <fork@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  jne    L4
  call   <handle_request@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    10a0 <exit@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  pop    %rbp
  jmp    1080 <close@plt>
```

assistant: ```c
void handle_fork(int msgsock) {
  if (fork() == 0) {
    handle_request(msgsock);
    exit(0);
  } else {
    close(msgsock);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_my_rank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int get_my_rank(void) {
  pid_t pid = getpid();
  return (pid & 0xFF);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_my_rank>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int get_my_rank(void) {
  pid_t pid = getpid();
  return (pid & 0xFF);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_my_rank>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int get_my_rank(void) {
  pid_t pid = getpid();
  return (pid & 0xFF);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_my_rank>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int get_my_rank(void) {
  pid_t pid = getpid();
  return (pid & 0xFF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D11: number of args %d


tool: D16: arg %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  printf("number of args %d\n", argc);
  for (int i = 0; i < argc; i++) {
    printf("arg %d is %s\n", i, argv[i]);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L9
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D15(%rip),%r13
L16:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L16
L9:
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string
name: read_data
arguments: label: D15
type: string

tool: D4: number of args %d


tool: D15: arg %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  printf("number of args %d\n", argc);
  for (int i = 0; i < argc; i++) {
    printf("arg %d is %s\n", i, argv[i]);
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D3(%rip),%rdi
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L1
  xor    %ebx,%ebx
  lea    D1(%rip),%r13
  nopl   0x0(%rax)
L4:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L4
L1:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D3: number of args %d


tool: D1: arg %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  printf("number of args %d\n", argc);
  for (int i = 0; i < argc; i++) {
    printf("arg %d is %s\n", i, argv[i]);
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D0(%rip),%rdi
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L8
  xor    %ebx,%ebx
  lea    D9(%rip),%r13
  nopl   0x0(%rax)
L4:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L4
L8:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string
name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D0: number of args %d


tool: D9: arg %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  printf("number of args %d\n", argc);
  for (int i = 0; i < argc; i++) {
    printf("arg %d is %s\n", i, argv[i]);
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L4:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L4
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D58
type_infered: string

tool: D23: Inserire il numero dei numeri

tool: D2: %d

tool: D9: Inserire il numero

tool: D7: %f

tool: D58: PAUSE

assistant: ```c
main() {
  int N;
  int I;
  int Num;
  int Somma;
  float Media;
  printf("Inserire il numero dei numeri");
  scanf("%d", &N);
  Somma = 0;
  I = 0;
  while (I < N) {
    printf("Inserire il numero");
    scanf("%d", &Num);
    Somma = Somma + Num;
    I++;
  }
  Media = Somma / N;
  printf("%f", Media);
  system("PAUSE");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  test   %ecx,%ecx
  jle    L34
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D49(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D20(%rip),%r12
L37:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  mov    (%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L37
L28:
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D58(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  mov    $0x0,%ebp
  jmp    L28
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D20
type: string
name: retrieve_data
arguments: label: D49
type: string
name: retrieve_data
arguments: label: D58
type: string
name: retrieve_data
arguments: label: D2
type: string

tool: D11: Inserire il numero dei numeri

tool: D20: %d

tool: D49: Inserire il numero

tool: D58: %f

tool: D2: PAUSE

assistant: ```c
main() {
  int N;
  int I;
  int Num;
  int Somma;
  float Media;
  printf("Inserire il numero dei numeri");
  scanf("%d", &N);
  Somma = 0;
  I = 0;
  while (I < N) {
    printf("Inserire il numero");
    scanf("%d", &Num);
    Somma = Somma + Num;
    I++;
  }
  Media = Somma / N;
  printf("%f", Media);
  system("PAUSE");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  lea    D49(%rip),%rdi
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  test   %ecx,%ecx
  jle    L8
  xor    %ebx,%ebx
  lea    D16(%rip),%r14
  lea    0x4(%rsp),%r13
  nopl   (%rax)
L29:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  add    0x4(%rsp),%ebp
  cmp    %ebx,%ecx
  jg     L29
L8:
  mov    %ebp,%eax
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rdi
  cltd
  idiv   %ecx
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D49
datatype: string
name: read_data
arguments: data_label: D14
datatype: string
name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D1
datatype: string
name: read_data
arguments: data_label: D29
datatype: string

tool: D49: Inserire il numero dei numeri

tool: D14: %d

tool: D16: Inserire il numero

tool: D1: %f

tool: D29: PAUSE

assistant: ```c
main() {
  int N;
  int I;
  int Num;
  int Somma;
  float Media;
  printf("Inserire il numero dei numeri");
  scanf("%d", &N);
  Somma = 0;
  I = 0;
  while (I < N) {
    printf("Inserire il numero");
    scanf("%d", &Num);
    Somma = Somma + Num;
    I++;
  }
  Media = Somma / N;
  printf("%f", Media);
  system("PAUSE");
}
```