user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0xfd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfc8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L40
  lea    0x1c(%rsp),%r15
  lea    D9(%rip),%r14
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L24
  lea    0x20(%rsp),%r12
  pxor   %xmm0,%xmm0
  xor    %ebp,%ebp
  mov    %r12,%rbx
  nopl   (%rax)
L15:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  movss  %xmm0,0xc(%rsp)
  add    $0x1,%ebp
  call   <scanf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  mov    0x1c(%rsp),%eax
  cvtsi2ssl (%rbx),%xmm1
  add    $0x4,%rbx
  addss  %xmm1,%xmm0
  cmp    %ebp,%eax
  jg     L15
  pxor   %xmm5,%xmm5
  cvtsi2ss %eax,%xmm5
  divss  %xmm5,%xmm0
  test   %eax,%eax
  jle    L65
  lea    -0x1(%rax),%edx
  cmp    $0x2,%edx
  jbe    L48
  mov    %eax,%edx
  movaps %xmm0,%xmm4
  pxor   %xmm1,%xmm1
  shr    $0x2,%edx
  shufps $0x0,%xmm4,%xmm4
  lea    -0x1(%rdx),%ecx
  lea    0x10(%r12),%rdx
  shl    $0x4,%rcx
  add    %rdx,%rcx
  jmp    L118
  nopl   0x0(%rax,%rax,1)
L47:
  add    $0x10,%rdx
L118:
  movaps %xmm4,%xmm2
  cvtdq2ps (%r12),%xmm3
  mov    %rdx,%r12
  cmpltps %xmm3,%xmm2
  psubd  %xmm2,%xmm1
  cmp    %rdx,%rcx
  jne    L47
  movdqa %xmm1,%xmm2
  mov    %eax,%ecx
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%ecx
  paddd  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  paddd  %xmm2,%xmm1
  movd   %xmm1,%edx
  test   $0x3,%al
  je     L105
L63:
  movslq %ecx,%rsi
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x20(%rsp,%rsi,4),%xmm1
  xor    %esi,%esi
  comiss %xmm0,%xmm1
  seta   %sil
  add    %esi,%edx
  lea    0x1(%rcx),%esi
  cmp    %esi,%eax
  jle    L105
  movslq %esi,%rsi
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x20(%rsp,%rsi,4),%xmm1
  xor    %esi,%esi
  comiss %xmm0,%xmm1
  seta   %sil
  add    $0x2,%ecx
  add    %esi,%edx
  cmp    %ecx,%eax
  jle    L105
  movslq %ecx,%rcx
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  cvtsi2ssl 0x20(%rsp,%rcx,4),%xmm1
  comiss %xmm0,%xmm1
  seta   %al
  add    %eax,%edx
L105:
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
L144:
  divss  %xmm5,%xmm0
  mov    %r14,%rdi
  mulss  D10(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jne    L68
L40:
  mov    0xfc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0xfd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L24:
  pxor   %xmm5,%xmm5
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm5
  jmp    L144
L48:
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L63
L65:
  pxor   %xmm0,%xmm0
  jmp    L144
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: byte[4]

tool: D12: %d

tool: D9: %.3lf%%


tool: {"D10": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int main() {
  int n, c, ara[1000], i, j = 0;
  float ans, avarage = 0;
  scanf("%d", &n);
  while (n--) {
    scanf("%d", &c);
    for (i = 0; i < c; i++) {
      scanf("%d", &ara[i]);
      avarage += (float)(ara[i]);
    }
    avarage /= c;
    for (i = 0; i < c; i++) {
      if (ara[i] > avarage)
        j++;
    }
    ans = (float)j / c * 100;
    printf("%.3lf%%\n", ans);
    avarage = j = 0;
  }
  return 0;
}
```