ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L39
  cmpl   $0x0,-0x18(%rbp)
  jns    L15
  mov    -0x4(%rbp),%eax
  sub    -0x18(%rbp),%eax
  jmp    L31
L15:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  jmp    L31
L39:
  mov    -0x4(%rbp),%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
unsigned m_mod(int x, int y) {
  int r = x % y;
  return r < 0 ? (y < 0 ? r - y : r + y) : r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<m_mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  js     L10
L19:
  ret
L10:
  sub    %esi,%eax
  add    %esi,%edx
  test   %esi,%esi
  cmovns %edx,%eax
  jmp    L19
```

assistant: ```c
unsigned m_mod(int x, int y) {
  int r = x % y;
  return r < 0 ? (y < 0 ? r - y : r + y) : r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m_mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jns    L2
  mov    %edx,%eax
  add    %esi,%edx
  sub    %esi,%eax
  test   %esi,%esi
  cmovs  %eax,%edx
L2:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned m_mod(int x, int y) {
  int r = x % y;
  return r < 0 ? (y < 0 ? r - y : r + y) : r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<m_mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jns    L6
  mov    %edx,%eax
  add    %esi,%edx
  sub    %esi,%eax
  test   %esi,%esi
  cmovs  %eax,%edx
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned m_mod(int x, int y) {
  int r = x % y;
  return r < 0 ? (y < 0 ? r - y : r + y) : r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DEBUG_PrintScreen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0x13,-0x4(%rbp)
  jle    L10
  addl   $0x1,-0x8(%rbp)
L22:
  cmpl   $0x13,-0x8(%rbp)
  jle    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6:      Score %03d      


assistant: ```c
void DEBUG_PrintScreen(char Screen[20][20 + 1], int Curr_Score) {
  int Y, X;
  for (Y = 0; Y < 20; Y++) {
    printf("\n");
    for (X = 0; X < 20; X++) {
      printf("%c", Screen[Y][X]);
    }
  }
  printf("\n");
  printf("     Score %03d      \n", Curr_Score);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DEBUG_PrintScreen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  lea    0x14(%rdi),%rbp
  add    $0x1b8,%r12
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x14(%rbp),%rbx
L2:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L2
  add    $0x15,%rbp
  cmp    %r12,%rbp
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13d,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4:      Score %03d      


assistant: ```c
void DEBUG_PrintScreen(char Screen[20][20 + 1], int Curr_Score) {
  int Y, X;
  for (Y = 0; Y < 20; Y++) {
    printf("\n");
    for (X = 0; X < 20; X++) {
      printf("%c", Screen[Y][X]);
    }
  }
  printf("\n");
  printf("     Score %03d      \n", Curr_Score);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<DEBUG_PrintScreen>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  add    $0x1b8,%r12
  lea    0x14(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nop
L12:
  mov    $0xa,%edi
  lea    -0x14(%rbp),%rbx
  call   <putchar@plt>
  xchg   %ax,%ax
L10:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L10
  lea    0x15(%rbx),%rbp
  cmp    %r12,%rbp
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    %r13d,%esi
  xor    %eax,%eax
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0:      Score %03d      


assistant: ```c
void DEBUG_PrintScreen(char Screen[20][20 + 1], int Curr_Score) {
  int Y, X;
  for (Y = 0; Y < 20; Y++) {
    printf("\n");
    for (X = 0; X < 20; X++) {
      printf("%c", Screen[Y][X]);
    }
  }
  printf("\n");
  printf("     Score %03d      \n", Curr_Score);
}
```
user: Translate the below assembly code into C programming language:

```asm
<DEBUG_PrintScreen>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  add    $0x1b8,%r12
  lea    0x14(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nop
L18:
  mov    $0xa,%edi
  lea    -0x14(%rbp),%rbx
  call   <putchar@plt>
  xchg   %ax,%ax
L11:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L11
  lea    0x15(%rbx),%rbp
  cmp    %r12,%rbp
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    %r13d,%esi
  xor    %eax,%eax
  pop    %rbx
  lea    D3(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3:      Score %03d      


assistant: ```c
void DEBUG_PrintScreen(char Screen[20][20 + 1], int Curr_Score) {
  int Y, X;
  for (Y = 0; Y < 20; Y++) {
    printf("\n");
    for (X = 0; X < 20; X++) {
      printf("%c", Screen[Y][X]);
    }
  }
  printf("\n");
  printf("     Score %03d      \n", Curr_Score);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%edi
  call   <a@plt>
  nop
  leave
  ret
```

assistant: ```c
void c(int arg) {
  (void)arg;
  a(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<c>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <a@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void c(int arg) {
  (void)arg;
  a(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<c>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <a@plt>
```

assistant: ```c
void c(int arg) {
  (void)arg;
  a(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<c>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <a@plt>
```

assistant: ```c
void c(int arg) {
  (void)arg;
  a(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L72
  mov    %rsi,%r12
  movslq -0x44(%rbp),%rax
  shl    $0x3,%rax
  lea    0xf(%rax),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L29:
  cmp    %rcx,%rsp
  je     L57
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L29
L72:
  lea    D40(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L59
L57:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L4
  orq    $0x0,-0x8(%rsp,%rdx,1)
L4:
  mov    %rsp,%r14
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L17:
  cmp    %rdx,%rsp
  je     L86
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L17
L86:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L27
  orq    $0x0,-0x8(%rsp,%rax,1)
L27:
  mov    %rsp,%r13
  mov    -0x44(%rbp),%r15d
  mov    $0x0,%ebx
L79:
  mov    (%r12,%rbx,8),%rdi
  call   <atof@plt>
  movsd  %xmm0,(%r14,%rbx,8)
  subsd  D32(%rip),%xmm0
  divsd  D10(%rip),%xmm0
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L79
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%r13),%rbx
  mov    -0x44(%rbp),%eax
  lea    -0x2(%rax),%eax
  lea    0x10(%r13,%rax,8),%r13
  lea    D19(%rip),%r12
L33:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
L59:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L108
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D40
type: string
name: extract_symbolic_data
arguments: tag: D32
type: byte[8]
name: extract_symbolic_data
arguments: tag: D10
type: f64
name: extract_symbolic_data
arguments: tag: D45
type: string
name: extract_symbolic_data
arguments: tag: D19
type: string

tool: D40: no values given

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: D10: 1.8

tool: D45: Temperatures in degree Celsius:
	

tool: D19: %f, 

assistant: ```c
int main(int args, char **argv) {
  if (args < 2) {
    printf("no values given\n");
    return -1;
  }
  int elements = args;
  double temp_f[elements];
  double temp_c[elements];
  int ctr = 0;
  for (ctr = 0; ctr < elements; ctr++) {
    temp_f[ctr] = atof(argv[ctr]);
    temp_c[ctr] = (temp_f[ctr] - 32) / 1.8;
  }
  printf("Temperatures in degree Celsius:\n\t");
  for (ctr = 1; ctr < elements; ctr++) {
    printf("%f, ", temp_c[ctr]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x38(%rbp)
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L7
  movslq -0x44(%rbp),%r12
  mov    %rsi,%r14
  mov    %rsp,%rsi
  lea    0xf(,%r12,8),%rdx
  mov    %rdx,%rdi
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rcx
  sub    %rdi,%rsi
  cmp    %rsi,%rsp
  je     L3
L125:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L125
L3:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L91
L31:
  mov    %rdx,%rcx
  mov    %rsp,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%r13
  and    $0xfffffffffffffff0,%rcx
  sub    %rdx,%rsi
L69:
  cmp    %rsi,%rsp
  je     L113
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L69
L91:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L31
L113:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L83
L101:
  mov    %rsp,%rbx
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L118:
  mov    (%r14,%r15,8),%rdi
  call   <atof@plt>
  movsd  %xmm0,0x0(%r13,%r15,8)
  subsd  D17(%rip),%xmm0
  divsd  D16(%rip),%xmm0
  movsd  %xmm0,(%rbx,%r15,8)
  add    $0x1,%r15
  cmp    %r12,%r15
  jne    L118
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  lea    0x8(%rbx),%r12
  call   <printf@plt>
  mov    -0x44(%rbp),%eax
  sub    $0x2,%eax
  lea    0x10(%rbx,%rax,8),%r13
  lea    D22(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L20:
  movsd  (%r12),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  add    $0x8,%r12
  call   <printf@plt>
  cmp    %r13,%r12
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
L120:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L83:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L101
L7:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L120
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: byte[8]
name: unpack_data
arguments: tag: D16
type_infered: f64
name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D22
type_infered: string
name: unpack_data
arguments: tag: D34
type_infered: string

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: D16: 1.8

tool: D18: Temperatures in degree Celsius:
	

tool: D22: %f, 

tool: D34: no values given

assistant: ```c
int main(int args, char **argv) {
  if (args < 2) {
    printf("no values given\n");
    return -1;
  }
  int elements = args;
  double temp_f[elements];
  double temp_c[elements];
  int ctr = 0;
  for (ctr = 0; ctr < elements; ctr++) {
    temp_f[ctr] = atof(argv[ctr]);
    temp_c[ctr] = (temp_f[ctr] - 32) / 1.8;
  }
  printf("Temperatures in degree Celsius:\n\t");
  for (ctr = 1; ctr < elements; ctr++) {
    printf("%f, ", temp_c[ctr]);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x38(%rbp)
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L15
  movslq -0x44(%rbp),%r12
  mov    %rsi,%r14
  mov    %rsp,%rsi
  lea    0xf(,%r12,8),%rdx
  mov    %rdx,%rdi
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rcx
  sub    %rdi,%rsi
  cmp    %rsi,%rsp
  je     L105
L84:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L84
L105:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L107
L12:
  mov    %rdx,%rcx
  mov    %rsp,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%r13
  and    $0xfffffffffffffff0,%rcx
  sub    %rdx,%rsi
L31:
  cmp    %rsi,%rsp
  je     L55
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L31
L107:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L12
L55:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L1
L123:
  mov    %rsp,%rbx
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L92:
  mov    (%r14,%r15,8),%rdi
  call   <atof@plt>
  movsd  %xmm0,0x0(%r13,%r15,8)
  subsd  D7(%rip),%xmm0
  divsd  D24(%rip),%xmm0
  movsd  %xmm0,(%rbx,%r15,8)
  add    $0x1,%r15
  cmp    %r12,%r15
  jne    L92
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  lea    0x8(%rbx),%r12
  call   <printf@plt>
  mov    -0x44(%rbp),%eax
  sub    $0x2,%eax
  lea    0x10(%rbx,%rax,8),%r13
  lea    D26(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L38:
  movsd  (%r12),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  add    $0x8,%r12
  call   <printf@plt>
  cmp    %r12,%r13
  jne    L38
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
L93:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L117
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L1:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L123
L15:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L93
L117:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: byte[8]
name: retrieve_data
arguments: tag: D24
data_type: f64
name: retrieve_data
arguments: tag: D17
data_type: string
name: retrieve_data
arguments: tag: D26
data_type: string
name: retrieve_data
arguments: tag: D39
data_type: string

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: D24: 1.8

tool: D17: Temperatures in degree Celsius:
	

tool: D26: %f, 

tool: D39: no values given

assistant: ```c
int main(int args, char **argv) {
  if (args < 2) {
    printf("no values given\n");
    return -1;
  }
  int elements = args;
  double temp_f[elements];
  double temp_c[elements];
  int ctr = 0;
  for (ctr = 0; ctr < elements; ctr++) {
    temp_f[ctr] = atof(argv[ctr]);
    temp_c[ctr] = (temp_f[ctr] - 32) / 1.8;
  }
  printf("Temperatures in degree Celsius:\n\t");
  for (ctr = 1; ctr < elements; ctr++) {
    printf("%f, ", temp_c[ctr]);
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<serial_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L4
L11:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <serial_putc@plt>
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    $0x7d00,%edi
  call   <delay_tick@plt>
  nop
  leave
  ret
```

assistant: ```c
void serial_puts(const char *s) {
  while (*s != '\0') {
    serial_putc(*s++);
  }
  delay_tick(32 * 1000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serial_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L11
L3:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <serial_putc@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L3
L11:
  mov    $0x7d00,%edi
  call   <delay_tick@plt>
  pop    %rbx
  ret
```

assistant: ```c
void serial_puts(const char *s) {
  while (*s != '\0') {
    serial_putc(*s++);
  }
  delay_tick(32 * 1000);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<serial_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
L14:
  call   <serial_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L14
L4:
  mov    $0x7d00,%edi
  pop    %rbx
  jmp    1070 <delay_tick@plt>
```

assistant: ```c
void serial_puts(const char *s) {
  while (*s != '\0') {
    serial_putc(*s++);
  }
  delay_tick(32 * 1000);
}
```
user: What is the c source code of the assembly code below:

```asm
<serial_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L12
L15:
  call   <serial_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L15
L12:
  mov    $0x7d00,%edi
  pop    %rbx
  jmp    1070 <delay_tick@plt>
```

assistant: ```c
void serial_puts(const char *s) {
  while (*s != '\0') {
    serial_putc(*s++);
  }
  delay_tick(32 * 1000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<roundup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  mov    %rdx,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L6
L13:
  mov    -0x18(%rbp),%rax
L6:
  pop    %rbp
  ret
```

assistant: ```c
size_t roundup(size_t x, size_t y) {
  size_t r = x % y;
  if (r)
    return x + (y - r);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<roundup>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rsi
  add    %rdi,%rsi
  sub    %rdx,%rsi
  test   %rdx,%rdx
  cmovne %rsi,%rdi
  mov    %rdi,%rax
  ret
```

assistant: ```c
size_t roundup(size_t x, size_t y) {
  size_t r = x % y;
  if (r)
    return x + (y - r);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<roundup>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %rdi,%r8
  div    %rsi
  add    %rdi,%rsi
  sub    %rdx,%rsi
  test   %rdx,%rdx
  cmovne %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t roundup(size_t x, size_t y) {
  size_t r = x % y;
  if (r)
    return x + (y - r);
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<roundup>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %rdi,%r8
  div    %rsi
  add    %rdi,%rsi
  sub    %rdx,%rsi
  test   %rdx,%rdx
  cmovne %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t roundup(size_t x, size_t y) {
  size_t r = x % y;
  if (r)
    return x + (y - r);
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sendMessage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rdx),%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movb   $0x81,0xe(%rsp)
  cmp    $0x7d,%ebp
  jg     L45
  mov    %bpl,0xf(%rsp)
  mov    $0x2,%r12d
L56:
  lea    0xe(%rsp),%rsi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movslq %r12d,%rdi
  add    %rbx,%rdi
  mov    %ebp,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  test   %rax,%rax
  jle    L54
L33:
  mov    %r15d,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  lea    -0x7e(%rbp),%eax
  cmp    $0xff81,%eax
  jbe    L3
  movb   $0x7f,0xf(%rsp)
  movsbl %bpl,%eax
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x15(%rsp)
  sar    $0x8,%eax
  mov    %al,0x16(%rsp)
  mov    %bpl,0x17(%rsp)
  mov    $0xa,%r12d
  jmp    L56
L3:
  movb   $0x7e,0xf(%rsp)
  mov    %ebp,%edi
  call   <htons@plt>
  mov    %al,0xd(%rsp)
  lea    0xd(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x2,%edx
  call   <memcpy@plt>
  mov    $0x4,%r12d
  jmp    L56
L54:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: 

WE ARE NOT WRITING!!



assistant: ```c
void *sendMessage(int sock, char *s, int len) {
  int frameCount;
  uint16_t len16;
  char frame[10];
  char *reply = malloc(sizeof(char) * (len + 8));
  frame[0] = '\x81';
  if (len <= 125) {
    frame[1] = len;
    frameCount = 2;
  } else if (len >= 126 && len <= 65535) {
    frame[1] = 126;
    len16 = htons(len);
    memcpy(frame + 2, &len16, 2);
    frameCount = 4;
  } else {
    frame[1] = 127;
    frame[7] = (char)(((char)len >> 16) & (char)255);
    frame[8] = (char)(((char)len >> 8) & (char)255);
    frame[9] = (char)(((char)len) & (char)255);
    frameCount = 10;
  }
  memcpy(reply, frame, frameCount);
  memcpy(reply + frameCount, s, len);
  if (write(sock, reply, strlen(reply)) <= 0) {
    printf("\n\nWE ARE NOT WRITING!!\n\n");
  } else {
  }
  memset(reply, '\0', sizeof(char) * (len + 8));
  free(reply);
  reply = NULL;
  return NULL;
}
```