ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checksize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <ftell@plt>
  cmp    $0x200,%eax
  jg     L9
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D18(%rip),%rdi
  call   <unlink@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D18
type: string

tool: D19: Compiled size greater than 512 bytes!


tool: D18: 63s_grub_cfg

assistant: ```c
void checksize(FILE *fout, FILE *fin) {
  if (ftell(fout) > 512) {
    printf("Compiled size greater than 512 bytes!\n");
    fclose(fout);
    fclose(fin);
    unlink("63s_grub_cfg");
    exit(1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<checksize>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <ftell@plt>
  cmp    $0x200,%eax
  jg     L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L6:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  lea    D1(%rip),%rdi
  call   <unlink@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    10d0 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string

tool: D12: Compiled size greater than 512 bytes!


tool: D1: 63s_grub_cfg

assistant: ```c
void checksize(FILE *fout, FILE *fin) {
  if (ftell(fout) > 512) {
    printf("Compiled size greater than 512 bytes!\n");
    fclose(fout);
    fclose(fin);
    unlink("63s_grub_cfg");
    exit(1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<checksize>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <ftell@plt>
  cmp    $0x200,%eax
  jg     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L1:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  lea    D10(%rip),%rdi
  call   <unlink@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    10d0 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D4: Compiled size greater than 512 bytes!


tool: D10: 63s_grub_cfg

assistant: ```c
void checksize(FILE *fout, FILE *fin) {
  if (ftell(fout) > 512) {
    printf("Compiled size greater than 512 bytes!\n");
    fclose(fout);
    fclose(fin);
    unlink("63s_grub_cfg");
    exit(1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UDPaddr_to_CAN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rax
  movb   $0x31,(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  movb   $0x30,(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x2,%rax
  movb   $0x30,(%rax)
  mov    -0x30(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x20(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl -0x1f(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0x5(%rax),%rdx
  movzbl -0x1e(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0x6(%rax),%rdx
  movzbl -0x1d(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0x7(%rax),%rdx
  movzbl -0x1c(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0x8(%rax),%rdx
  movzbl -0x1b(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0x9(%rax),%rdx
  movzbl -0x1a(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0xa(%rax),%rdx
  movzbl -0x19(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0xb(%rax),%rdx
  movzbl -0x15(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0xc(%rax),%rdx
  movzbl -0x14(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0xd(%rax),%rdx
  movzbl -0x13(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0xe(%rax),%rdx
  movzbl -0x12(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0xf(%rax),%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void UDPaddr_to_CAN(char *value, char shifted[18]) {
  char in[18];
  strcpy(in, value);
  shifted[0] = '1';
  shifted[1] = '0';
  shifted[2] = '0';
  shifted[3] = in[0];
  shifted[4] = in[1];
  shifted[5] = in[2];
  shifted[6] = in[3];
  shifted[7] = in[4];
  shifted[8] = in[5];
  shifted[9] = in[6];
  shifted[10] = in[7];
  shifted[11] = in[11];
  shifted[12] = in[12];
  shifted[13] = in[13];
  shifted[14] = in[14];
  shifted[15] = in[15];
  shifted[16] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<UDPaddr_to_CAN>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movb   $0x31,(%rbx)
  movb   $0x30,0x1(%rbx)
  movb   $0x30,0x2(%rbx)
  movzbl (%rsp),%eax
  mov    %al,0x3(%rbx)
  movzbl 0x1(%rsp),%eax
  mov    %al,0x4(%rbx)
  movzbl 0x2(%rsp),%eax
  mov    %al,0x5(%rbx)
  movzbl 0x3(%rsp),%eax
  mov    %al,0x6(%rbx)
  movzbl 0x4(%rsp),%eax
  mov    %al,0x7(%rbx)
  movzbl 0x5(%rsp),%eax
  mov    %al,0x8(%rbx)
  movzbl 0x6(%rsp),%eax
  mov    %al,0x9(%rbx)
  movzbl 0x7(%rsp),%eax
  mov    %al,0xa(%rbx)
  movzbl 0xb(%rsp),%eax
  mov    %al,0xb(%rbx)
  movzbl 0xc(%rsp),%eax
  mov    %al,0xc(%rbx)
  movzbl 0xd(%rsp),%eax
  mov    %al,0xd(%rbx)
  movzbl 0xe(%rsp),%eax
  mov    %al,0xe(%rbx)
  movzbl 0xf(%rsp),%eax
  mov    %al,0xf(%rbx)
  movb   $0x0,0x10(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void UDPaddr_to_CAN(char *value, char shifted[18]) {
  char in[18];
  strcpy(in, value);
  shifted[0] = '1';
  shifted[1] = '0';
  shifted[2] = '0';
  shifted[3] = in[0];
  shifted[4] = in[1];
  shifted[5] = in[2];
  shifted[6] = in[3];
  shifted[7] = in[4];
  shifted[8] = in[5];
  shifted[9] = in[6];
  shifted[10] = in[7];
  shifted[11] = in[11];
  shifted[12] = in[12];
  shifted[13] = in[13];
  shifted[14] = in[14];
  shifted[15] = in[15];
  shifted[16] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<UDPaddr_to_CAN>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%rbx
  mov    %r8,%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    $0x3031,%eax
  movb   $0x30,0x2(%rbx)
  mov    %ax,(%rbx)
  mov    (%rsp),%rax
  movb   $0x0,0x10(%rbx)
  mov    %rax,0x3(%rbx)
  mov    0xb(%rsp),%eax
  mov    %eax,0xb(%rbx)
  movzbl 0xf(%rsp),%eax
  mov    %al,0xf(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void UDPaddr_to_CAN(char *value, char shifted[18]) {
  char in[18];
  strcpy(in, value);
  shifted[0] = '1';
  shifted[1] = '0';
  shifted[2] = '0';
  shifted[3] = in[0];
  shifted[4] = in[1];
  shifted[5] = in[2];
  shifted[6] = in[3];
  shifted[7] = in[4];
  shifted[8] = in[5];
  shifted[9] = in[6];
  shifted[10] = in[7];
  shifted[11] = in[11];
  shifted[12] = in[12];
  shifted[13] = in[13];
  shifted[14] = in[14];
  shifted[15] = in[15];
  shifted[16] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UDPaddr_to_CAN>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%rbx
  mov    %r8,%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    $0x3031,%eax
  movb   $0x30,0x2(%rbx)
  mov    %ax,(%rbx)
  mov    (%rsp),%rax
  movb   $0x0,0x10(%rbx)
  mov    %rax,0x3(%rbx)
  mov    0xb(%rsp),%eax
  mov    %eax,0xb(%rbx)
  movzbl 0xf(%rsp),%eax
  mov    %al,0xf(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void UDPaddr_to_CAN(char *value, char shifted[18]) {
  char in[18];
  strcpy(in, value);
  shifted[0] = '1';
  shifted[1] = '0';
  shifted[2] = '0';
  shifted[3] = in[0];
  shifted[4] = in[1];
  shifted[5] = in[2];
  shifted[6] = in[3];
  shifted[7] = in[4];
  shifted[8] = in[5];
  shifted[9] = in[6];
  shifted[10] = in[7];
  shifted[11] = in[11];
  shifted[12] = in[12];
  shifted[13] = in[13];
  shifted[14] = in[14];
  shifted[15] = in[15];
  shifted[16] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x10000000,-0xc(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L36
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
L36:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <cuda_test_memcpy_2step@plt>
  test   %rax,%rax
  jns    L0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L0:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D17: %x

tool: D5: Test failed


tool: D6: Test passed


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int size = 0x10000000;
  if (argc > 1)
    sscanf(argv[1], "%x", &size);
  if (cuda_test_memcpy_2step(size) < 0)
    printf("Test failed\n");
  else
    printf("Test passed\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x10000000,0x4(%rsp)
  cmp    $0x1,%edi
  jg     L38
L4:
  mov    0x4(%rsp),%edi
  call   <cuda_test_memcpy_2step@plt>
  test   %rax,%rax
  js     L13
  lea    D8(%rip),%rdi
  call   <printf@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L38:
  lea    0x4(%rsp),%rdx
  mov    0x8(%rsi),%rdi
  lea    D20(%rip),%rsi
  call   <sscanf@plt>
  jmp    L4
L13:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D16
type_infered: string

tool: D8: Test passed


tool: D20: %x

tool: D16: Test failed


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int size = 0x10000000;
  if (argc > 1)
    sscanf(argv[1], "%x", &size);
  if (cuda_test_memcpy_2step(size) < 0)
    printf("Test failed\n");
  else
    printf("Test passed\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x10000000,0x4(%rsp)
  cmp    $0x1,%edi
  jle    L18
  mov    0x8(%rsi),%rdi
  lea    0x4(%rsp),%rdx
  lea    D29(%rip),%rsi
  call   <sscanf@plt>
L18:
  mov    0x4(%rsp),%edi
  call   <cuda_test_memcpy_2step@plt>
  test   %rax,%rax
  js     L5
  lea    D18(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D29: %x

tool: D18: Test passed


tool: D4: Test failed


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int size = 0x10000000;
  if (argc > 1)
    sscanf(argv[1], "%x", &size);
  if (cuda_test_memcpy_2step(size) < 0)
    printf("Test failed\n");
  else
    printf("Test passed\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x10000000,0x4(%rsp)
  cmp    $0x1,%edi
  jle    L29
  mov    0x8(%rsi),%rdi
  lea    0x4(%rsp),%rdx
  lea    D4(%rip),%rsi
  call   <sscanf@plt>
L29:
  mov    0x4(%rsp),%edi
  call   <cuda_test_memcpy_2step@plt>
  test   %rax,%rax
  js     L33
  lea    D8(%rip),%rdi
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L33:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string
name: disassemble_data
arguments: tag: D8
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string

tool: D4: %x

tool: D8: Test passed


tool: D26: Test failed


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int size = 0x10000000;
  if (argc > 1)
    sscanf(argv[1], "%x", &size);
  if (cuda_test_memcpy_2step(size) < 0)
    printf("Test failed\n");
  else
    printf("Test passed\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x4,%esi
  mov    $0x1000000,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x20(%rbp)
  jmp    L13
L1:
  mov    $0x0,%eax
  call   <wall_clock_time@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L37:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%eax
  add    %eax,-0x1c(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  cmp    $0xffffff,%eax
  jbe    L37
  mov    $0x0,%eax
  call   <wall_clock_time@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  D24(%rip),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  movq   %rax,%xmm0
  mov    %rdx,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  shll   -0x20(%rbp)
L13:
  mov    -0x20(%rbp),%eax
  cmp    $0xff,%eax
  jbe    L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D23
datatype: string
name: unpack_data
arguments: tag: D24
datatype: byte[4]
name: unpack_data
arguments: tag: D14
datatype: string

tool: D23: start testing!

tool: {"D24": [0x00,0x24,0x74,0x49]}

tool: D14: stepsize: %3lu  time:%lf


assistant: ```c
int main() {
  long long start, end;
  int stepsize, i;
  int *array = calloc(64 * 1024 * 1024 / sizeof(int), sizeof(int));
  printf("start testing!\n");
  for (stepsize = 1; stepsize < 1024 / sizeof(int); stepsize *= 2) {
    start = wall_clock_time();
    for (i = 0; i < 64 * 1024 * 1024 / sizeof(int); i += stepsize) {
      array[i]++;
    }
    end = wall_clock_time();
    printf("stepsize: %3lu  time:%lf\n", stepsize * sizeof(int), ((float)(end - start) / 1000000));
  }
  free(array);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x1000000,%edi
  call   <calloc@plt>
  mov    %rax,%r14
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x8,%r13d
  mov    $0x1,%ebp
  lea    D23(%rip),%r15
L10:
  mov    $0x0,%eax
  call   <wall_clock_time@plt>
  mov    %rax,%r12
  movslq %ebp,%rbx
  shl    $0x2,%rbx
  mov    %r14,%rax
  mov    $0x0,%edx
L3:
  addl   $0x1,(%rax)
  add    %ebp,%edx
  add    %rbx,%rax
  cmp    $0xffffff,%edx
  jbe    L3
  mov    $0x0,%eax
  call   <wall_clock_time@plt>
  sub    %r12,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  divss  D22(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %rbx,%rsi
  mov    %r15,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    %ebp,%ebp
  sub    $0x1,%r13d
  jne    L10
  mov    %r14,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D23
type_guessed: string
name: read_data
arguments: data_label: D22
type_guessed: byte[4]

tool: D17: start testing!

tool: D23: stepsize: %3lu  time:%lf


tool: {"D22": [0x00,0x24,0x74,0x49]}

assistant: ```c
int main() {
  long long start, end;
  int stepsize, i;
  int *array = calloc(64 * 1024 * 1024 / sizeof(int), sizeof(int));
  printf("start testing!\n");
  for (stepsize = 1; stepsize < 1024 / sizeof(int); stepsize *= 2) {
    start = wall_clock_time();
    for (i = 0; i < 64 * 1024 * 1024 / sizeof(int); i += stepsize) {
      array[i]++;
    }
    end = wall_clock_time();
    printf("stepsize: %3lu  time:%lf\n", stepsize * sizeof(int), ((float)(end - start) / 1000000));
  }
  free(array);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%esi
  mov    $0x1000000,%edi
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x8,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  lea    D28(%rip),%rdi
  mov    %rax,%r12
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  movslq %r14d,%rbp
  call   <wall_clock_time@plt>
  shl    $0x2,%rbp
  mov    %r12,%rdx
  xor    %ecx,%ecx
  mov    %rax,%r15
  xchg   %ax,%ax
L0:
  add    %r14d,%ecx
  addl   $0x1,(%rdx)
  add    %rbp,%rdx
  cmp    $0xffffff,%ecx
  jle    L0
  xor    %eax,%eax
  add    %r14d,%r14d
  call   <wall_clock_time@plt>
  pxor   %xmm0,%xmm0
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %r15,%rax
  cvtsi2ss %rax,%xmm0
  mov    $0x1,%eax
  divss  D22(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L17
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D28
type: string
name: parse_data
arguments: label: D22
type: byte[4]

tool: D13: stepsize: %3lu  time:%lf


tool: D28: start testing!

tool: {"D22": [0x00,0x24,0x74,0x49]}

assistant: ```c
int main() {
  long long start, end;
  int stepsize, i;
  int *array = calloc(64 * 1024 * 1024 / sizeof(int), sizeof(int));
  printf("start testing!\n");
  for (stepsize = 1; stepsize < 1024 / sizeof(int); stepsize *= 2) {
    start = wall_clock_time();
    for (i = 0; i < 64 * 1024 * 1024 / sizeof(int); i += stepsize) {
      array[i]++;
    }
    end = wall_clock_time();
    printf("stepsize: %3lu  time:%lf\n", stepsize * sizeof(int), ((float)(end - start) / 1000000));
  }
  free(array);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%esi
  mov    $0x1000000,%edi
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x8,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  lea    D15(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  call   <wall_clock_time@plt>
  cmp    $0x1,%r13d
  mov    %rbp,%rdx
  movdqa D0(%rip),%xmm1
  mov    %rax,%r15
  lea    0x4000000(%rbp),%rcx
  jne    L16
  nopw   0x0(%rax,%rax,1)
L20:
  movdqu (%rdx),%xmm0
  add    $0x10,%rdx
  paddd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rdx,%rcx
  jne    L20
  mov    $0x1,%r14d
L41:
  xor    %eax,%eax
  add    %r13d,%r13d
  call   <wall_clock_time@plt>
  pxor   %xmm0,%xmm0
  lea    0x0(,%r14,4),%rsi
  mov    %r12,%rdi
  sub    %r15,%rax
  cvtsi2ss %rax,%xmm0
  mov    $0x1,%eax
  divss  D24(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L12
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  movslq %r13d,%r14
  xor    %ecx,%ecx
  lea    0x0(,%r14,4),%rax
  nopl   (%rax)
L32:
  add    %r13d,%ecx
  addl   $0x1,(%rdx)
  add    %rax,%rdx
  cmp    $0xffffff,%ecx
  jle    L32
  jmp    L41
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D24
datatype: byte[4]

tool: D17: stepsize: %3lu  time:%lf


tool: D15: start testing!

tool: {"D0": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D24": [0x00,0x24,0x74,0x49]}

assistant: ```c
int main() {
  long long start, end;
  int stepsize, i;
  int *array = calloc(64 * 1024 * 1024 / sizeof(int), sizeof(int));
  printf("start testing!\n");
  for (stepsize = 1; stepsize < 1024 / sizeof(int); stepsize *= 2) {
    start = wall_clock_time();
    for (i = 0; i < 64 * 1024 * 1024 / sizeof(int); i += stepsize) {
      array[i]++;
    }
    end = wall_clock_time();
    printf("stepsize: %3lu  time:%lf\n", stepsize * sizeof(int), ((float)(end - start) / 1000000));
  }
  free(array);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mm_escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L53
L8:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L37
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x74,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x9,(%rax)
  jmp    L35
L0:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L35
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x5c,(%rax)
  jmp    L35
L37:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L35:
  addq   $0x1,-0x10(%rbp)
L53:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *mm_escape(char *s) {
  char *p, *q;
  for (p = q = s; *p; ++p) {
    if (*p == '\\') {
      ++p;
      if (*p == 't')
        *q++ = '\t';
      else if (*p == '\\')
        *q++ = '\\';
    } else
      *q++ = *p;
  }
  *q = '\0';
  return s;
}
```