ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<my_modff>:
  endbr64
  movd   %xmm0,%eax
  movd   %xmm0,%ecx
  sar    $0x17,%ecx
  movzbl %cl,%ecx
  sub    $0x7f,%ecx
  cmp    $0x16,%ecx
  jle    L8
  cmp    $0x80,%ecx
  jne    L49
  movaps %xmm0,%xmm1
  movd   %xmm0,%esi
  shl    $0x9,%esi
  jne    L41
L49:
  and    $0x80000000,%eax
  movd   %eax,%xmm1
L41:
  movss  %xmm0,(%rdi)
  movaps %xmm1,%xmm0
  ret
L8:
  test   %ecx,%ecx
  js     L78
  mov    $0x7fffff,%edx
  sar    %cl,%edx
  test   %eax,%edx
  je     L25
  mov    $0xff800000,%edx
  sar    %cl,%edx
  and    %eax,%edx
  movd   %edx,%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movd   %edx,%xmm0
  jmp    L41
L78:
  and    $0x80000000,%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  jmp    L41
L25:
  and    $0x80000000,%eax
  movd   %eax,%xmm1
  jmp    L41
```

assistant: ```c
float my_modff(float x, float *iptr) {
  union {
    float f;
    uint32_t i;
  } u = {x};
  uint32_t mask;
  int e = (int)(u.i >> 23 & 0xff) - 0x7f;
  if (e >= 23) {
    *iptr = x;
    if (e == 0x80 && u.i << 9 != 0) {
      return x;
    }
    u.i &= 0x80000000;
    return u.f;
  }
  if (e < 0) {
    u.i &= 0x80000000;
    *iptr = u.f;
    return x;
  }
  mask = 0x007fffff >> e;
  if ((u.i & mask) == 0) {
    *iptr = x;
    u.i &= 0x80000000;
    return u.f;
  }
  u.i &= ~mask;
  *iptr = u.f;
  return x - u.f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_modff>:
  endbr64
  movd   %xmm0,%ecx
  movd   %xmm0,%eax
  sar    $0x17,%ecx
  movzbl %cl,%ecx
  sub    $0x7f,%ecx
  cmp    $0x16,%ecx
  jle    L40
  cmp    $0x80,%ecx
  je     L41
L24:
  and    $0x80000000,%eax
  movss  %xmm0,(%rdi)
  movd   %eax,%xmm1
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  test   %ecx,%ecx
  js     L14
  mov    $0x7fffff,%edx
  sar    %cl,%edx
  test   %eax,%edx
  je     L24
  mov    $0xff800000,%edx
  movaps %xmm0,%xmm1
  sar    %cl,%edx
  and    %eax,%edx
  movd   %edx,%xmm2
  movd   %edx,%xmm0
  subss  %xmm2,%xmm1
  movss  %xmm0,(%rdi)
  movaps %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  movd   %xmm0,%esi
  movaps %xmm0,%xmm1
  shl    $0x9,%esi
  je     L24
  movss  %xmm0,(%rdi)
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L14:
  and    $0x80000000,%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  movss  %xmm0,(%rdi)
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float my_modff(float x, float *iptr) {
  union {
    float f;
    uint32_t i;
  } u = {x};
  uint32_t mask;
  int e = (int)(u.i >> 23 & 0xff) - 0x7f;
  if (e >= 23) {
    *iptr = x;
    if (e == 0x80 && u.i << 9 != 0) {
      return x;
    }
    u.i &= 0x80000000;
    return u.f;
  }
  if (e < 0) {
    u.i &= 0x80000000;
    *iptr = u.f;
    return x;
  }
  mask = 0x007fffff >> e;
  if ((u.i & mask) == 0) {
    *iptr = x;
    u.i &= 0x80000000;
    return u.f;
  }
  u.i &= ~mask;
  *iptr = u.f;
  return x - u.f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_modff>:
  endbr64
  movd   %xmm0,%ecx
  movd   %xmm0,%eax
  sar    $0x17,%ecx
  movzbl %cl,%ecx
  sub    $0x7f,%ecx
  cmp    $0x16,%ecx
  jle    L8
  cmp    $0x80,%ecx
  je     L3
L30:
  and    $0x80000000,%eax
  movss  %xmm0,(%rdi)
  movd   %eax,%xmm1
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  test   %ecx,%ecx
  js     L23
  mov    $0x7fffff,%edx
  sar    %cl,%edx
  test   %eax,%edx
  je     L30
  mov    $0xff800000,%edx
  movaps %xmm0,%xmm1
  sar    %cl,%edx
  and    %eax,%edx
  movd   %edx,%xmm2
  movd   %edx,%xmm0
  subss  %xmm2,%xmm1
  movss  %xmm0,(%rdi)
  movaps %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  movd   %xmm0,%esi
  movaps %xmm0,%xmm1
  shl    $0x9,%esi
  je     L30
  movss  %xmm0,(%rdi)
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L23:
  and    $0x80000000,%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  movss  %xmm0,(%rdi)
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float my_modff(float x, float *iptr) {
  union {
    float f;
    uint32_t i;
  } u = {x};
  uint32_t mask;
  int e = (int)(u.i >> 23 & 0xff) - 0x7f;
  if (e >= 23) {
    *iptr = x;
    if (e == 0x80 && u.i << 9 != 0) {
      return x;
    }
    u.i &= 0x80000000;
    return u.f;
  }
  if (e < 0) {
    u.i &= 0x80000000;
    *iptr = u.f;
    return x;
  }
  mask = 0x007fffff >> e;
  if ((u.i & mask) == 0) {
    *iptr = x;
    u.i &= 0x80000000;
    return u.f;
  }
  u.i &= ~mask;
  *iptr = u.f;
  return x - u.f;
}
```
user: What is the c source code of the assembly code below?

```asm
<txtacc_fmt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <grecs_txtacc_grow@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int txtacc_fmt(const char *str, void *data) {
  struct grecs_txtacc *acc = data;
  grecs_txtacc_grow(acc, str, strlen(str));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<txtacc_fmt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <grecs_txtacc_grow@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int txtacc_fmt(const char *str, void *data) {
  struct grecs_txtacc *acc = data;
  grecs_txtacc_grow(acc, str, strlen(str));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<txtacc_fmt>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <grecs_txtacc_grow@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int txtacc_fmt(const char *str, void *data) {
  struct grecs_txtacc *acc = data;
  grecs_txtacc_grow(acc, str, strlen(str));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L31
  mov    $0x0,%eax
  jmp    L14
L31:
  movl   $0x1,-0x4(%rbp)
  jmp    L34
L4:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L4
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  jmp    L14
L2:
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int ft_sqrt(int nb) {
  int sqrt;
  if (nb < 0)
    return (0);
  sqrt = 1;
  while ((sqrt * sqrt) < nb)
    sqrt++;
  return (((sqrt * sqrt) == nb) ? sqrt : 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_sqrt>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L14
  cmp    $0x1,%edi
  jle    L3
  mov    $0x1,%eax
L30:
  add    $0x1,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jl     L30
L24:
  cmp    %edx,%edi
  mov    $0x0,%edx
  cmovne %edx,%eax
L14:
  ret
L3:
  mov    $0x1,%eax
  mov    $0x1,%edx
  jmp    L24
```

assistant: ```c
int ft_sqrt(int nb) {
  int sqrt;
  if (nb < 0)
    return (0);
  sqrt = 1;
  while ((sqrt * sqrt) < nb)
    sqrt++;
  return (((sqrt * sqrt) == nb) ? sqrt : 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_sqrt>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L28
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L24
  nopl   0x0(%rax)
L34:
  add    $0x1,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jl     L34
L15:
  cmp    %edx,%edi
  mov    $0x0,%edx
  cmovne %edx,%eax
L28:
  ret
  nop
L24:
  mov    $0x1,%edx
  jmp    L15
```

assistant: ```c
int ft_sqrt(int nb) {
  int sqrt;
  if (nb < 0)
    return (0);
  sqrt = 1;
  while ((sqrt * sqrt) < nb)
    sqrt++;
  return (((sqrt * sqrt) == nb) ? sqrt : 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_sqrt>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L17
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L25
  nopl   0x0(%rax)
L21:
  add    $0x1,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jl     L21
L29:
  cmp    %edx,%edi
  mov    $0x0,%edx
  cmovne %edx,%eax
L17:
  ret
  nop
L25:
  mov    $0x1,%edx
  jmp    L29
```

assistant: ```c
int ft_sqrt(int nb) {
  int sqrt;
  if (nb < 0)
    return (0);
  sqrt = 1;
  while ((sqrt * sqrt) < nb)
    sqrt++;
  return (((sqrt * sqrt) == nb) ? sqrt : 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<validercolonne>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  jmp    L58
L75:
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L32
L27:
  mov    -0x38(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %eax,%edx
  mov    -0x3c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L71
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L12
  mov    -0x50(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L31
L12:
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x1,-0x30(%rbp,%rax,4)
L71:
  addl   $0x1,-0x38(%rbp)
L32:
  cmpl   $0x8,-0x38(%rbp)
  jle    L27
  addl   $0x1,-0x3c(%rbp)
L58:
  cmpl   $0x8,-0x3c(%rbp)
  jle    L75
L31:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void validercolonne(int sudoku[], bool *valide) {
  for (int j = 0; j < 9; j++) {
    bool memoire[10] = {false};
    for (int i = 0; i < 9; i++) {
      int numero = sudoku[i * 9 + j];
      if (numero != 0) {
        if (memoire[numero]) {
          *valide = false;
          return;
        } else {
          memoire[numero] = true;
        }
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<validercolonne>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  add    $0x144,%rdi
  mov    $0x0,%r8d
  jmp    L42
L23:
  movl   $0x0,(%rsi)
L72:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  ret
L34:
  add    $0x24,%rax
  cmp    %rdi,%rax
  je     L67
L68:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L34
  movslq %edx,%rcx
  cmpl   $0x0,(%rsp,%rcx,4)
  jne    L23
  movslq %edx,%rdx
  movl   $0x1,(%rsp,%rdx,4)
  jmp    L34
L67:
  add    $0x1,%r8d
  add    $0x4,%rdi
  cmp    $0x9,%r8d
  je     L72
L42:
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  lea    -0x144(%rdi),%rax
  jmp    L68
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void validercolonne(int sudoku[], bool *valide) {
  for (int j = 0; j < 9; j++) {
    bool memoire[10] = {false};
    for (int i = 0; i < 9; i++) {
      int numero = sudoku[i * 9 + j];
      if (numero != 0) {
        if (memoire[numero]) {
          *valide = false;
          return;
        } else {
          memoire[numero] = true;
        }
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<validercolonne>:
  endbr64
  sub    $0x38,%rsp
  add    $0x144,%rdi
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
L37:
  movq   $0x0,0x20(%rsp)
  pxor   %xmm0,%xmm0
  lea    -0x144(%rdi),%rax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  xchg   %ax,%ax
L31:
  movslq (%rax),%rdx
  test   %edx,%edx
  je     L26
  mov    (%rsp,%rdx,4),%r8d
  test   %r8d,%r8d
  jne    L29
  movl   $0x1,(%rsp,%rdx,4)
L26:
  add    $0x24,%rax
  cmp    %rdi,%rax
  jne    L31
  add    $0x1,%ecx
  add    $0x4,%rdi
  cmp    $0x9,%ecx
  jne    L37
L15:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L29:
  movl   $0x0,(%rsi)
  jmp    L15
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void validercolonne(int sudoku[], bool *valide) {
  for (int j = 0; j < 9; j++) {
    bool memoire[10] = {false};
    for (int i = 0; i < 9; i++) {
      int numero = sudoku[i * 9 + j];
      if (numero != 0) {
        if (memoire[numero]) {
          *valide = false;
          return;
        } else {
          memoire[numero] = true;
        }
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<validercolonne>:
  endbr64
  sub    $0x38,%rsp
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    %rdi,%rax
  lea    0x24(%rax),%rsi
L123:
  movq   $0x0,0x20(%rsp)
  movslq (%rax),%rdx
  pxor   %xmm0,%xmm0
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  test   %edx,%edx
  je     L70
  movl   $0x1,(%rsp,%rdx,4)
L70:
  movslq 0x24(%rax),%rdx
  test   %edx,%edx
  je     L111
  mov    (%rsp,%rdx,4),%r8d
  test   %r8d,%r8d
  jne    L191
  movl   $0x1,(%rsp,%rdx,4)
L111:
  movslq 0x48(%rax),%rdx
  test   %edx,%edx
  je     L83
  mov    (%rsp,%rdx,4),%edi
  test   %edi,%edi
  jne    L191
  movl   $0x1,(%rsp,%rdx,4)
L83:
  movslq 0x6c(%rax),%rdx
  test   %edx,%edx
  je     L186
  mov    (%rsp,%rdx,4),%r11d
  test   %r11d,%r11d
  jne    L191
  movl   $0x1,(%rsp,%rdx,4)
L186:
  movslq 0x90(%rax),%rdx
  test   %edx,%edx
  je     L51
  mov    (%rsp,%rdx,4),%r10d
  test   %r10d,%r10d
  jne    L191
  movl   $0x1,(%rsp,%rdx,4)
L51:
  movslq 0xb4(%rax),%rdx
  test   %edx,%edx
  je     L58
  mov    (%rsp,%rdx,4),%r9d
  test   %r9d,%r9d
  jne    L191
  movl   $0x1,(%rsp,%rdx,4)
L58:
  movslq 0xd8(%rax),%rdx
  test   %edx,%edx
  je     L23
  mov    (%rsp,%rdx,4),%r8d
  test   %r8d,%r8d
  jne    L191
  movl   $0x1,(%rsp,%rdx,4)
L23:
  movslq 0xfc(%rax),%rdx
  test   %edx,%edx
  je     L34
  mov    (%rsp,%rdx,4),%edi
  test   %edi,%edi
  jne    L191
  movl   $0x1,(%rsp,%rdx,4)
L34:
  movslq 0x120(%rax),%rdx
  test   %edx,%edx
  je     L138
  mov    (%rsp,%rdx,4),%edx
  test   %edx,%edx
  jne    L191
L138:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L123
L90:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L116
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L191:
  movl   $0x0,(%rcx)
  jmp    L90
L116:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void validercolonne(int sudoku[], bool *valide) {
  for (int j = 0; j < 9; j++) {
    bool memoire[10] = {false};
    for (int i = 0; i < 9; i++) {
      int numero = sudoku[i * 9 + j];
      if (numero != 0) {
        if (memoire[numero]) {
          *valide = false;
          return;
        } else {
          memoire[numero] = true;
        }
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<doubles_mat_transform_xyz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x48,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x50,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x58,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void doubles_mat_transform_xyz(const double M[16], const double xyz[3], double r[3]) {
  r[0] = M[0] * xyz[0] + M[1] * xyz[1] + M[2] * xyz[2] + M[3];
  r[1] = M[4] * xyz[0] + M[5] * xyz[1] + M[6] * xyz[2] + M[7];
  r[2] = M[8] * xyz[0] + M[9] * xyz[1] + M[10] * xyz[2] + M[11];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<doubles_mat_transform_xyz>:
  endbr64
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x18(%rdi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x20(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x28(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x30(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x38(%rdi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x40(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x48(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x50(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x58(%rdi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void doubles_mat_transform_xyz(const double M[16], const double xyz[3], double r[3]) {
  r[0] = M[0] * xyz[0] + M[1] * xyz[1] + M[2] * xyz[2] + M[3];
  r[1] = M[4] * xyz[0] + M[5] * xyz[1] + M[6] * xyz[2] + M[7];
  r[2] = M[8] * xyz[0] + M[9] * xyz[1] + M[10] * xyz[2] + M[11];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<doubles_mat_transform_xyz>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x18(%rdi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x20(%rdi),%xmm0
  movsd  0x28(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x30(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x38(%rdi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x40(%rdi),%xmm0
  movsd  0x48(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x50(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x58(%rdi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void doubles_mat_transform_xyz(const double M[16], const double xyz[3], double r[3]) {
  r[0] = M[0] * xyz[0] + M[1] * xyz[1] + M[2] * xyz[2] + M[3];
  r[1] = M[4] * xyz[0] + M[5] * xyz[1] + M[6] * xyz[2] + M[7];
  r[2] = M[8] * xyz[0] + M[9] * xyz[1] + M[10] * xyz[2] + M[11];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_region_name_MY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x11,-0x4(%rbp)
  ja     L132
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D115(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D115(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D36(%rip),%rax
  jmp    L49
  lea    D80(%rip),%rax
  jmp    L49
  lea    D177(%rip),%rax
  jmp    L49
  lea    D178(%rip),%rax
  jmp    L49
  lea    D160(%rip),%rax
  jmp    L49
  lea    D61(%rip),%rax
  jmp    L49
  lea    D25(%rip),%rax
  jmp    L49
  lea    D124(%rip),%rax
  jmp    L49
  lea    D75(%rip),%rax
  jmp    L49
  lea    D168(%rip),%rax
  jmp    L49
  lea    D122(%rip),%rax
  jmp    L49
  lea    D84(%rip),%rax
  jmp    L49
  lea    D155(%rip),%rax
  jmp    L49
  lea    D157(%rip),%rax
  jmp    L49
  lea    D76(%rip),%rax
  jmp    L49
  lea    D56(%rip),%rax
  jmp    L49
L132:
  mov    $0x0,%eax
L49:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D36
datatype: string
name: retrieve_data
arguments: tag: D80
datatype: string
name: retrieve_data
arguments: tag: D177
datatype: string
name: retrieve_data
arguments: tag: D178
datatype: string
name: retrieve_data
arguments: tag: D160
datatype: string
name: retrieve_data
arguments: tag: D61
datatype: string
name: retrieve_data
arguments: tag: D25
datatype: string
name: retrieve_data
arguments: tag: D124
datatype: string
name: retrieve_data
arguments: tag: D75
datatype: string
name: retrieve_data
arguments: tag: D168
datatype: string
name: retrieve_data
arguments: tag: D122
datatype: string
name: retrieve_data
arguments: tag: D84
datatype: string
name: retrieve_data
arguments: tag: D155
datatype: string
name: retrieve_data
arguments: tag: D157
datatype: string
name: retrieve_data
arguments: tag: D76
datatype: string
name: retrieve_data
arguments: tag: D56
datatype: string

tool: D36: Johor

tool: D80: Kedah

tool: D177: Kelantan

tool: D178: Melaka

tool: D160: Negeri Sembilan

tool: D61: Pahang

tool: D25: Perak

tool: D124: Perlis

tool: D75: Pulau Pinang

tool: D168: Sarawak

tool: D122: Selangor

tool: D84: Terengganu

tool: D155: Kuala Lumpur

tool: D157: Labuan

tool: D76: Sabah

tool: D56: Putrajaya

assistant: ```c
const char *get_region_name_MY(int region_code) {
  switch (region_code) {
  case 1:
    return "Johor";
  case 2:
    return "Kedah";
  case 3:
    return "Kelantan";
  case 4:
    return "Melaka";
  case 5:
    return "Negeri Sembilan";
  case 6:
    return "Pahang";
  case 7:
    return "Perak";
  case 8:
    return "Perlis";
  case 9:
    return "Pulau Pinang";
  case 11:
    return "Sarawak";
  case 12:
    return "Selangor";
  case 13:
    return "Terengganu";
  case 14:
    return "Kuala Lumpur";
  case 15:
    return "Labuan";
  case 16:
    return "Sabah";
  case 17:
    return "Putrajaya";
  default:
    return NULL;
  }
}
```