ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<press>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <change@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <change@plt>
  cmpl   $0x5,-0x18(%rbp)
  jg     L33
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <change@plt>
L33:
  cmpl   $0x0,-0x18(%rbp)
  jle    L38
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <change@plt>
L38:
  cmpl   $0x6,-0x14(%rbp)
  jg     L13
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <change@plt>
L13:
  cmpl   $0x0,-0x14(%rbp)
  jle    L32
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    -0x14(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <change@plt>
L32:
  nop
  leave
  ret
```

assistant: ```c
void press(int a[6][5], int b[6][5], int x, int y) {
  change(&b[x][y]);
  change(&a[x][y]);
  if (y <= 5)
    change(&a[x][y + 1]);
  if (y > 0)
    change(&a[x][y - 1]);
  if (x <= 6)
    change(&a[x + 1][y]);
  if (x > 0)
    change(&a[x - 1][y]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<press>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %edx,%ebp
  mov    %ecx,%r12d
  movslq %edx,%rax
  lea    (%rax,%rax,4),%r13
  shl    $0x2,%r13
  movslq %ecx,%rbx
  shl    $0x2,%rbx
  lea    0x0(%r13,%rbx,1),%rax
  lea    (%rsi,%rax,1),%rdi
  call   <change@plt>
  lea    (%r14,%r13,1),%r15
  lea    (%r15,%rbx,1),%rdi
  call   <change@plt>
  cmp    $0x5,%r12d
  jle    L43
L67:
  test   %r12d,%r12d
  jg     L65
L25:
  cmp    $0x6,%ebp
  jle    L40
L5:
  test   %ebp,%ebp
  jg     L45
L55:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  lea    0x4(%r15,%rbx,1),%rdi
  call   <change@plt>
  jmp    L67
L65:
  lea    -0x4(%r15,%rbx,1),%rdi
  call   <change@plt>
  jmp    L25
L40:
  lea    0x14(%rbx,%r13,1),%rdi
  add    %r14,%rdi
  call   <change@plt>
  jmp    L5
L45:
  lea    -0x14(%rbx,%r13,1),%rax
  lea    (%r14,%rax,1),%rdi
  call   <change@plt>
  jmp    L55
```

assistant: ```c
void press(int a[6][5], int b[6][5], int x, int y) {
  change(&b[x][y]);
  change(&a[x][y]);
  if (y <= 5)
    change(&a[x][y + 1]);
  if (y > 0)
    change(&a[x][y - 1]);
  if (x <= 6)
    change(&a[x + 1][y]);
  if (x > 0)
    change(&a[x - 1][y]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<press>:
  endbr64
  movslq %edx,%rax
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  lea    (%rax,%rax,4),%rbp
  push   %rbx
  movslq %ecx,%rbx
  shl    $0x2,%rbp
  mov    %rbx,%r13
  shl    $0x2,%rbx
  lea    (%r14,%rbp,1),%r15
  lea    0x0(%rbp,%rbx,1),%rax
  sub    $0x8,%rsp
  lea    (%rsi,%rax,1),%rdi
  call   <change@plt>
  lea    (%r15,%rbx,1),%rdi
  call   <change@plt>
  cmp    $0x5,%r13d
  jle    L48
L13:
  lea    -0x4(%r15,%rbx,1),%rdi
  call   <change@plt>
  cmp    $0x6,%r12d
  jle    L34
L7:
  add    $0x8,%rsp
  lea    -0x14(%rbx,%rbp,1),%rdi
  add    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <change@plt>
  nopl   0x0(%rax)
L48:
  lea    0x4(%r15,%rbx,1),%rdi
  call   <change@plt>
  test   %r13d,%r13d
  jg     L13
  cmp    $0x6,%r12d
  jg     L7
L34:
  lea    0x14(%rbx,%rbp,1),%rdi
  add    %r14,%rdi
  call   <change@plt>
  test   %r12d,%r12d
  jg     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void press(int a[6][5], int b[6][5], int x, int y) {
  change(&b[x][y]);
  change(&a[x][y]);
  if (y <= 5)
    change(&a[x][y + 1]);
  if (y > 0)
    change(&a[x][y - 1]);
  if (x <= 6)
    change(&a[x + 1][y]);
  if (x > 0)
    change(&a[x - 1][y]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<press>:
  endbr64
  movslq %edx,%rax
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  lea    (%rax,%rax,4),%rbp
  push   %rbx
  movslq %ecx,%rbx
  shl    $0x2,%rbp
  mov    %rbx,%r13
  shl    $0x2,%rbx
  lea    (%r14,%rbp,1),%r15
  lea    0x0(%rbp,%rbx,1),%rax
  sub    $0x8,%rsp
  lea    (%rsi,%rax,1),%rdi
  call   <change@plt>
  lea    (%r15,%rbx,1),%rdi
  call   <change@plt>
  cmp    $0x5,%r13d
  jle    L29
L38:
  lea    -0x4(%r15,%rbx,1),%rdi
  call   <change@plt>
  cmp    $0x6,%r12d
  jle    L3
L8:
  add    $0x8,%rsp
  lea    -0x14(%rbx,%rbp,1),%rdi
  add    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <change@plt>
  nopl   0x0(%rax)
L29:
  lea    0x4(%r15,%rbx,1),%rdi
  call   <change@plt>
  test   %r13d,%r13d
  jg     L38
  cmp    $0x6,%r12d
  jg     L8
L3:
  lea    0x14(%rbx,%rbp,1),%rdi
  add    %r14,%rdi
  call   <change@plt>
  test   %r12d,%r12d
  jg     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void press(int a[6][5], int b[6][5], int x, int y) {
  change(&b[x][y]);
  change(&a[x][y]);
  if (y <= 5)
    change(&a[x][y + 1]);
  if (y > 0)
    change(&a[x][y - 1]);
  if (x <= 6)
    change(&a[x + 1][y]);
  if (x > 0)
    change(&a[x - 1][y]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<align>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  and    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L9
L19:
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
L9:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t align(size_t x, size_t pow2) {
  size_t r = x & (pow2 - 1);
  if (!r)
    return 0;
  return pow2 - r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<align>:
  endbr64
  lea    -0x1(%rsi),%rax
  and    %rdi,%rax
  sub    %rax,%rsi
  test   %rax,%rax
  cmovne %rsi,%rax
  ret
```

assistant: ```c
uint32_t align(size_t x, size_t pow2) {
  size_t r = x & (pow2 - 1);
  if (!r)
    return 0;
  return pow2 - r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<align>:
  endbr64
  lea    -0x1(%rsi),%rax
  and    %rdi,%rax
  sub    %rax,%rsi
  test   %rax,%rax
  cmovne %rsi,%rax
  ret
```

assistant: ```c
uint32_t align(size_t x, size_t pow2) {
  size_t r = x & (pow2 - 1);
  if (!r)
    return 0;
  return pow2 - r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<align>:
  endbr64
  lea    -0x1(%rsi),%rax
  and    %rdi,%rax
  sub    %rax,%rsi
  test   %rax,%rax
  cmovne %rsi,%rax
  ret
```

assistant: ```c
uint32_t align(size_t x, size_t pow2) {
  size_t r = x & (pow2 - 1);
  if (!r)
    return 0;
  return pow2 - r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<regSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x1ffffff8,-0x8(%rbp)
  mov    $0x10202240,%eax
  movl   $0x39,(%rax)
  mov    $0x10202a40,%eax
  movl   $0x39,(%rax)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  nop
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L6
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,%rdx
  mov    $0x0,%eax
  call   *%rdx
  nop
  leave
  ret
```

assistant: ```c
void regSet() {
  volatile uint32_t *entry = (uint32_t *)0x1FFFFFF8;
  *((volatile uint32_t *)0x10202240) = 0x39;
  *((volatile uint32_t *)0x10202A40) = 0x39;
  *entry = 0;
  while (!*entry)
    ;
  ((void (*)()) * entry)();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<regSet>:
  endbr64
  sub    $0x8,%rsp
  movl   $0x39,0x10202240
  movl   $0x39,0x10202a40
  movl   $0x0,0x1ffffff8
L3:
  mov    0x1ffffff8,%eax
  test   %eax,%eax
  je     L3
  mov    0x1ffffff8,%edx
  movslq %edx,%rdx
  mov    $0x0,%eax
  call   *%rdx
  add    $0x8,%rsp
  ret
```

assistant: ```c
void regSet() {
  volatile uint32_t *entry = (uint32_t *)0x1FFFFFF8;
  *((volatile uint32_t *)0x10202240) = 0x39;
  *((volatile uint32_t *)0x10202A40) = 0x39;
  *entry = 0;
  while (!*entry)
    ;
  ((void (*)()) * entry)();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<regSet>:
  endbr64
  movl   $0x39,0x10202240
  movl   $0x39,0x10202a40
  movl   $0x0,0x1ffffff8
  nopl   (%rax)
L9:
  mov    0x1ffffff8,%eax
  test   %eax,%eax
  je     L9
  movslq 0x1ffffff8,%rdx
  xor    %eax,%eax
  jmp    *%rdx
```

assistant: ```c
void regSet() {
  volatile uint32_t *entry = (uint32_t *)0x1FFFFFF8;
  *((volatile uint32_t *)0x10202240) = 0x39;
  *((volatile uint32_t *)0x10202A40) = 0x39;
  *entry = 0;
  while (!*entry)
    ;
  ((void (*)()) * entry)();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<regSet>:
  endbr64
  movl   $0x39,0x10202240
  movl   $0x39,0x10202a40
  movl   $0x0,0x1ffffff8
  nopl   (%rax)
L4:
  mov    0x1ffffff8,%eax
  test   %eax,%eax
  je     L4
  movslq 0x1ffffff8,%rdx
  xor    %eax,%eax
  jmp    *%rdx
```

assistant: ```c
void regSet() {
  volatile uint32_t *entry = (uint32_t *)0x1FFFFFF8;
  *((volatile uint32_t *)0x10202240) = 0x39;
  *((volatile uint32_t *)0x10202A40) = 0x39;
  *entry = 0;
  while (!*entry)
    ;
  ((void (*)()) * entry)();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  int3
  int3
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L6:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0x9,-0x8(%rbp)
  jle    L6
  int3
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i = 0, x = 0;
  asm volatile("int3");
  asm volatile("int3");
  for (i = 0; i < 10; i++)
    x = x + 1;
  asm volatile("int3");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  int3
  int3
  int3
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i = 0, x = 0;
  asm volatile("int3");
  asm volatile("int3");
  for (i = 0; i < 10; i++)
    x = x + 1;
  asm volatile("int3");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  int3
  int3
  int3
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i = 0, x = 0;
  asm volatile("int3");
  asm volatile("int3");
  for (i = 0; i < 10; i++)
    x = x + 1;
  asm volatile("int3");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  int3
  int3
  int3
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i = 0, x = 0;
  asm volatile("int3");
  asm volatile("int3");
  for (i = 0; i < 10; i++)
    x = x + 1;
  asm volatile("int3");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<terminate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <stop_rpc@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void terminate(int signo) {
  stop_rpc();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<terminate>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <stop_rpc@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void terminate(int signo) {
  stop_rpc();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<terminate>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <stop_rpc@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void terminate(int signo) {
  stop_rpc();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<terminate>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <stop_rpc@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void terminate(int signo) {
  stop_rpc();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stdlib_ndarray_get_uint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stdlib_ndarray_get_ptr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L9
L10:
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stdlib_ndarray_get_ptr_uint32@plt>
L9:
  leave
  ret
```

assistant: ```c
int8_t stdlib_ndarray_get_uint32(const struct ndarray *arr, const int64_t *sub, uint32_t *out) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_get_ptr_uint32(idx, out);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stdlib_ndarray_get_uint32>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <stdlib_ndarray_get_ptr_uint32@plt>
L18:
  pop    %rbx
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int8_t stdlib_ndarray_get_uint32(const struct ndarray *arr, const int64_t *sub, uint32_t *out) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_get_ptr_uint32(idx, out);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stdlib_ndarray_get_uint32>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1060 <stdlib_ndarray_get_ptr_uint32@plt>
L1:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t stdlib_ndarray_get_uint32(const struct ndarray *arr, const int64_t *sub, uint32_t *out) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_get_ptr_uint32(idx, out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stdlib_ndarray_get_uint32>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L7
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1060 <stdlib_ndarray_get_ptr_uint32@plt>
L7:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t stdlib_ndarray_get_uint32(const struct ndarray *arr, const int64_t *sub, uint32_t *out) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_get_ptr_uint32(idx, out);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_lit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1,%esi
  mov    $0x3039,%edi
  call   <__builtin_aligned_alloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0x303a,%edi
  call   <__builtin_aligned_alloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%edi
  call   <__builtin_alloca@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x303b,%edi
  call   <__builtin_alloca@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0x3039,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%esi
  mov    $0x1,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    $0x3039,%esi
  mov    %eax,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,%esi
  mov    $0x3039,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3,%esi
  mov    $0x181c,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1013,%esi
  mov    $0x4,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x303c,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3039,%esi
  mov    %rax,%rdi
  call   <__builtin_realloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x303d,%esi
  mov    %rax,%rdi
  call   <__builtin_realloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_lit(char *p, char *q) {
  sink(__builtin_aligned_alloc(12345, 1));
  sink(__builtin_aligned_alloc(12345 + 1, 1));
  sink(__builtin_alloca(12345));
  sink(__builtin_alloca(12345 + 2));
  sink(__builtin_calloc(12345, 1));
  sink(__builtin_calloc(1, 12345));
  sink(__builtin_calloc(p - q, 1));
  sink(__builtin_calloc(1, q - p));
  sink(__builtin_calloc(p - q, 12345));
  sink(__builtin_calloc(12345, q - p));
  sink(__builtin_calloc(12345 / 2, 3));
  sink(__builtin_calloc(4, 12345 / 3));
  sink(__builtin_malloc(12345));
  sink(__builtin_malloc(12345 + 3));
  sink(__builtin_realloc(p, 12345));
  sink(__builtin_realloc(p, 12345 + 4));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_lit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x1,%esi
  mov    $0x3039,%edi
  call   <__builtin_aligned_alloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0x303a,%edi
  call   <__builtin_aligned_alloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%edi
  call   <__builtin_alloca@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x303b,%edi
  call   <__builtin_alloca@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0x3039,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%esi
  mov    $0x1,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %ebp,%r12d
  sub    %ebx,%r12d
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  sub    %ebp,%ebx
  mov    %ebx,%esi
  mov    $0x1,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%esi
  mov    %r12d,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %ebx,%esi
  mov    $0x3039,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3,%esi
  mov    $0x181c,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1013,%esi
  mov    $0x4,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x303c,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%esi
  mov    %rbp,%rdi
  call   <__builtin_realloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x303d,%esi
  mov    %rbp,%rdi
  call   <__builtin_realloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test_lit(char *p, char *q) {
  sink(__builtin_aligned_alloc(12345, 1));
  sink(__builtin_aligned_alloc(12345 + 1, 1));
  sink(__builtin_alloca(12345));
  sink(__builtin_alloca(12345 + 2));
  sink(__builtin_calloc(12345, 1));
  sink(__builtin_calloc(1, 12345));
  sink(__builtin_calloc(p - q, 1));
  sink(__builtin_calloc(1, q - p));
  sink(__builtin_calloc(p - q, 12345));
  sink(__builtin_calloc(12345, q - p));
  sink(__builtin_calloc(12345 / 2, 3));
  sink(__builtin_calloc(4, 12345 / 3));
  sink(__builtin_malloc(12345));
  sink(__builtin_malloc(12345 + 3));
  sink(__builtin_realloc(p, 12345));
  sink(__builtin_realloc(p, 12345 + 4));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_lit>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x3039,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x1,%esi
  mov    %r12d,%r13d
  sub    %ebp,%r13d
  sub    %r12d,%ebp
  call   <__builtin_aligned_alloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0x303a,%edi
  call   <__builtin_aligned_alloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%edi
  call   <__builtin_alloca@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x303b,%edi
  call   <__builtin_alloca@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0x3039,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%esi
  mov    $0x1,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    %r13d,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %ebp,%esi
  mov    $0x1,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%esi
  mov    %r13d,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %ebp,%esi
  mov    $0x3039,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3,%esi
  mov    $0x181c,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1013,%esi
  mov    $0x4,%edi
  call   <__builtin_calloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x303c,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3039,%esi
  mov    %r12,%rdi
  call   <__builtin_realloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %r12,%rdi
  mov    $0x303d,%esi
  call   <__builtin_realloc@plt>
  pop    %rbp
  pop    %r12
  mov    %eax,%edi
  pop    %r13
  jmp    10e0 <sink@plt>
```

assistant: ```c
void test_lit(char *p, char *q) {
  sink(__builtin_aligned_alloc(12345, 1));
  sink(__builtin_aligned_alloc(12345 + 1, 1));
  sink(__builtin_alloca(12345));
  sink(__builtin_alloca(12345 + 2));
  sink(__builtin_calloc(12345, 1));
  sink(__builtin_calloc(1, 12345));
  sink(__builtin_calloc(p - q, 1));
  sink(__builtin_calloc(1, q - p));
  sink(__builtin_calloc(p - q, 12345));
  sink(__builtin_calloc(12345, q - p));
  sink(__builtin_calloc(12345 / 2, 3));
  sink(__builtin_calloc(4, 12345 / 3));
  sink(__builtin_malloc(12345));
  sink(__builtin_malloc(12345 + 3));
  sink(__builtin_realloc(p, 12345));
  sink(__builtin_realloc(p, 12345 + 4));
}
```