ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<expandmem>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  test   %rdi,%rdi
  je     L28
  mov    %ebx,%esi
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <checkmem@plt>
  lea    0x18(%rbx,%rbp,1),%esi
  lea    -0x10(%r12),%rdi
  movslq %esi,%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
L26:
  lea    0x0(%rbp,%rbx,1),%r14d
  lea    0x10(%r12),%r13
  mov    %r14d,0xc(%r12)
  movslq %ebp,%r12
  test   %ebp,%ebp
  jle    L59
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L59:
  add    %r12,%rbx
  mov    %r14d,%esi
  mov    %r13,%rdi
  movabs $0x646e655f6d656d,%rax
  mov    %rax,0x0(%r13,%rbx,1)
  xor    %eax,%eax
  call   <checkmem@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L28:
  lea    0x18(%rdx),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L18
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <die@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  movabs $0x6765625f6d656d5f,%rax
  movl   $0x5f6e69,0x8(%r12)
  mov    %rax,(%r12)
  jmp    L26
L6:
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <die@plt>
  jmp    L26
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: expandmem: no more memory (%d)

assistant: ```c
void *expandmem(void *vp, int size, int by) {
  int allocated;
  char *mem, *p = vp;
  int expand_by = by;
  if (p) {
    checkmem(p, size);
    allocated = (strlen("_mem_begin_") + 1 + sizeof(int) + strlen("mem_end") + 1) + size;
    p -= (strlen("_mem_begin_") + 1 + sizeof(int));
  } else {
    allocated = 0;
    expand_by += (strlen("_mem_begin_") + 1 + sizeof(int) + strlen("mem_end") + 1);
  }
  p = realloc(p, allocated + expand_by);
  if (!p)
    die("expandmem: no more memory (%d)", size);
  if (!vp) {
    strcpy(p, "_mem_begin_");
  }
  mem = p + strlen("_mem_begin_") + 1 + sizeof(int);
  *(int *)(p + strlen("_mem_begin_") + 1) = size + by;
  if (by > 0)
    memset(mem + size, 0, by);
  strcpy(mem + size + by, "mem_end");
  checkmem(mem, size + by);
  return mem;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<expandmem>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  test   %rdi,%rdi
  je     L0
  mov    %ebx,%esi
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <checkmem@plt>
  lea    0x18(%rbx,%rbp,1),%esi
  lea    -0x10(%r12),%rdi
  movslq %esi,%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L41
L37:
  lea    0x0(%rbp,%rbx,1),%r14d
  lea    0x10(%r12),%r13
  mov    %r14d,0xc(%r12)
  movslq %ebp,%r12
  test   %ebp,%ebp
  jle    L8
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L8:
  add    %r12,%rbx
  mov    %r14d,%esi
  mov    %r13,%rdi
  movabs $0x646e655f6d656d,%rax
  mov    %rax,0x0(%r13,%rbx,1)
  xor    %eax,%eax
  call   <checkmem@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L0:
  lea    0x18(%rdx),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L33
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <die@plt>
  nopl   0x0(%rax,%rax,1)
L33:
  movabs $0x6765625f6d656d5f,%rax
  movl   $0x5f6e69,0x8(%r12)
  mov    %rax,(%r12)
  jmp    L37
L41:
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <die@plt>
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: expandmem: no more memory (%d)

assistant: ```c
void *expandmem(void *vp, int size, int by) {
  int allocated;
  char *mem, *p = vp;
  int expand_by = by;
  if (p) {
    checkmem(p, size);
    allocated = (strlen("_mem_begin_") + 1 + sizeof(int) + strlen("mem_end") + 1) + size;
    p -= (strlen("_mem_begin_") + 1 + sizeof(int));
  } else {
    allocated = 0;
    expand_by += (strlen("_mem_begin_") + 1 + sizeof(int) + strlen("mem_end") + 1);
  }
  p = realloc(p, allocated + expand_by);
  if (!p)
    die("expandmem: no more memory (%d)", size);
  if (!vp) {
    strcpy(p, "_mem_begin_");
  }
  mem = p + strlen("_mem_begin_") + 1 + sizeof(int);
  *(int *)(p + strlen("_mem_begin_") + 1) = size + by;
  if (by > 0)
    memset(mem + size, 0, by);
  strcpy(mem + size + by, "mem_end");
  checkmem(mem, size + by);
  return mem;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7420746365707845,%rax
  movabs $0x2e74736562206568,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x6572617065725020,%rax
  movabs $0x65687420726f6620,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x202e7473726f7720,%rax
  movabs $0x696c617469706143,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6877206e6f20657a,%rax
  movabs $0x73656d6f63207461,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0xa2e,-0x10(%rbp)
  movb   $0x0,-0xe(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <leet@plt>
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
datatype: string

tool: D17: %s

assistant: ```c
int main(void) {
  char s[] = "Expect the best. Prepare for the worst. Capitalize on what comes.\n";
  char *p;
  p = leet(s);
  printf("%s", p);
  printf("%s", s);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x7420746365707845,%rax
  movabs $0x2e74736562206568,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x6572617065725020,%rax
  movabs $0x65687420726f6620,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x202e7473726f7720,%rax
  movabs $0x696c617469706143,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6877206e6f20657a,%rax
  movabs $0x73656d6f63207461,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movw   $0xa2e,0x40(%rsp)
  movb   $0x0,0x42(%rsp)
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <leet@plt>
  mov    %rax,%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: %s

assistant: ```c
int main(void) {
  char s[] = "Expect the best. Prepare for the worst. Capitalize on what comes.\n";
  char *p;
  p = leet(s);
  printf("%s", p);
  printf("%s", s);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  sub    $0x58,%rsp
  movdqa D46(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    $0xa2e,%eax
  movb   $0x0,0x42(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D44(%rip),%xmm0
  mov    %r12,%rdi
  mov    %ax,0x40(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D27(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <leet@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D46
type: byte[16]
name: unpack_data
arguments: tag: D44
type: byte[16]
name: unpack_data
arguments: tag: D27
type: byte[16]
name: unpack_data
arguments: tag: D7
type: byte[16]

tool: D1: %s

tool: {"D46": [0x45,0x78,0x70,0x65,0x63,0x74,0x20,0x74,0x68,0x65,0x20,0x62,0x65,0x73,0x74,0x2e]}

tool: {"D44": [0x20,0x50,0x72,0x65,0x70,0x61,0x72,0x65,0x20,0x66,0x6f,0x72,0x20,0x74,0x68,0x65]}

tool: {"D27": [0x20,0x77,0x6f,0x72,0x73,0x74,0x2e,0x20,0x43,0x61,0x70,0x69,0x74,0x61,0x6c,0x69]}

tool: {"D7": [0x7a,0x65,0x20,0x6f,0x6e,0x20,0x77,0x68,0x61,0x74,0x20,0x63,0x6f,0x6d,0x65,0x73]}

assistant: ```c
int main(void) {
  char s[] = "Expect the best. Prepare for the worst. Capitalize on what comes.\n";
  char *p;
  p = leet(s);
  printf("%s", p);
  printf("%s", s);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  sub    $0x58,%rsp
  movdqa D41(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    $0xa2e,%eax
  movb   $0x0,0x42(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D17(%rip),%xmm0
  mov    %r12,%rdi
  mov    %ax,0x40(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D19(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D0(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <leet@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D41
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D17
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D19
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D0
data_type: byte[16]

tool: D10: %s

tool: {"D41": [0x45,0x78,0x70,0x65,0x63,0x74,0x20,0x74,0x68,0x65,0x20,0x62,0x65,0x73,0x74,0x2e]}

tool: {"D17": [0x20,0x50,0x72,0x65,0x70,0x61,0x72,0x65,0x20,0x66,0x6f,0x72,0x20,0x74,0x68,0x65]}

tool: {"D19": [0x20,0x77,0x6f,0x72,0x73,0x74,0x2e,0x20,0x43,0x61,0x70,0x69,0x74,0x61,0x6c,0x69]}

tool: {"D0": [0x7a,0x65,0x20,0x6f,0x6e,0x20,0x77,0x68,0x61,0x74,0x20,0x63,0x6f,0x6d,0x65,0x73]}

assistant: ```c
int main(void) {
  char s[] = "Expect the best. Prepare for the worst. Capitalize on what comes.\n";
  char *p;
  p = leet(s);
  printf("%s", p);
  printf("%s", s);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_last_block_portion_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x17,%edx
  add    %edx,%eax
  and    $0x1ff,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L3
  mov    -0x4(%rbp),%eax
  jmp    L13
L3:
  mov    $0x200,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int get_last_block_portion_size(int filesize) {
  const int partial = filesize % 512;
  return (partial > 0 ? partial : 512);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_last_block_portion_size>:
  endbr64
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x17,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1ff,%eax
  sub    %edx,%eax
  test   %eax,%eax
  mov    $0x200,%edx
  cmovle %edx,%eax
  ret
```

assistant: ```c
int get_last_block_portion_size(int filesize) {
  const int partial = filesize % 512;
  return (partial > 0 ? partial : 512);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_last_block_portion_size>:
  endbr64
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x17,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1ff,%eax
  sub    %edx,%eax
  mov    $0x200,%edx
  test   %eax,%eax
  cmovle %edx,%eax
  ret
```

assistant: ```c
int get_last_block_portion_size(int filesize) {
  const int partial = filesize % 512;
  return (partial > 0 ? partial : 512);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_last_block_portion_size>:
  endbr64
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x17,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1ff,%eax
  sub    %edx,%eax
  mov    $0x200,%edx
  test   %eax,%eax
  cmovle %edx,%eax
  ret
```

assistant: ```c
int get_last_block_portion_size(int filesize) {
  const int partial = filesize % 512;
  return (partial > 0 ? partial : 512);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  movl   $0x5,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: %d %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int p1[] = {0, 1, 2, 3, 4, 5};
  int *p2 = p1 + 2;
  printf("%d %d\n", *p1, (int)(*p2));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  mov    $0x0,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: %d %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int p1[] = {0, 1, 2, 3, 4, 5};
  int *p2 = p1 + 2;
  printf("%d %d\n", *p1, (int)(*p2));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: %d %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int p1[] = {0, 1, 2, 3, 4, 5};
  int *p2 = p1 + 2;
  printf("%d %d\n", *p1, (int)(*p2));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: %d %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int p1[] = {0, 1, 2, 3, 4, 5};
  int *p2 = p1 + 2;
  printf("%d %d\n", *p1, (int)(*p2));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_arg_from_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <get_pointer_to_arg@plt>
  mov    %rax,-0x18(%rbp)
  nop
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L24
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L24
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
L24:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_arg_from_command(char *start, int arg) {
  char *buffer = calloc(strlen(start), 1);
  char *rolling = buffer;
  start = get_pointer_to_arg(start, arg);
  while (*start != '\n' && *start != ' ' && (*rolling++ = *start++))
    ;
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_arg_from_command>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <strlen@plt>
  mov    %eax,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <get_pointer_to_arg@plt>
  mov    $0x0,%ecx
L29:
  movzbl (%rax,%rcx,1),%edx
  cmp    $0xa,%dl
  je     L6
  cmp    $0x20,%dl
  je     L6
  mov    %dl,(%rbx,%rcx,1)
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L29
L6:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_arg_from_command(char *start, int arg) {
  char *buffer = calloc(strlen(start), 1);
  char *rolling = buffer;
  start = get_pointer_to_arg(start, arg);
  while (*start != '\n' && *start != ' ' && (*rolling++ = *start++))
    ;
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_arg_from_command>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <get_pointer_to_arg@plt>
  xor    %ecx,%ecx
L22:
  movzbl (%rax,%rcx,1),%edx
  cmp    $0xa,%dl
  je     L29
  cmp    $0x20,%dl
  je     L29
  mov    %dl,(%r12,%rcx,1)
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L22
L29:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_arg_from_command(char *start, int arg) {
  char *buffer = calloc(strlen(start), 1);
  char *rolling = buffer;
  start = get_pointer_to_arg(start, arg);
  while (*start != '\n' && *start != ' ' && (*rolling++ = *start++))
    ;
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_arg_from_command>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <get_pointer_to_arg@plt>
  xor    %ecx,%ecx
L13:
  movzbl (%rax,%rcx,1),%edx
  cmp    $0xa,%dl
  je     L12
  cmp    $0x20,%dl
  je     L12
  mov    %dl,(%r12,%rcx,1)
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L13
L12:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_arg_from_command(char *start, int arg) {
  char *buffer = calloc(strlen(start), 1);
  char *rolling = buffer;
  start = get_pointer_to_arg(start, arg);
  while (*start != '\n' && *start != ' ' && (*rolling++ = *start++))
    ;
  return buffer;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetAttribute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L43
L38:
  mov    -0x18(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L70
  mov    $0x0,%eax
  jmp    L43
L70:
  mov    -0x18(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L43
L15:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L46
  mov    $0x0,%eax
  jmp    L43
L46:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L43:
  leave
  ret
```

assistant: ```c
char *GetAttribute(const char *strAttribute, const char *strElement) {
  char *pMatch;
  char *pEnd;
  char *strOut;
  pMatch = strstr(strElement, strAttribute);
  if (NULL == pMatch)
    return NULL;
  pMatch = strchr(pMatch, '=');
  if (NULL == pMatch)
    return NULL;
  pMatch = strchr(pMatch, '\"');
  if (NULL == pMatch)
    return NULL;
  pMatch++;
  pEnd = strchr(pMatch, '\"');
  if (NULL == pEnd)
    return NULL;
  strOut = malloc(pEnd - pMatch + 1);
  memcpy(strOut, pMatch, pEnd - pMatch);
  strOut[pEnd - pMatch] = '\0';
  return strOut;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GetAttribute>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rax,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L24
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L24
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L24
  lea    0x1(%rax),%rbp
  mov    $0x22,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L24
  sub    %rbp,%rbx
  mov    %rbx,%r12
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
L24:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *GetAttribute(const char *strAttribute, const char *strElement) {
  char *pMatch;
  char *pEnd;
  char *strOut;
  pMatch = strstr(strElement, strAttribute);
  if (NULL == pMatch)
    return NULL;
  pMatch = strchr(pMatch, '=');
  if (NULL == pMatch)
    return NULL;
  pMatch = strchr(pMatch, '\"');
  if (NULL == pMatch)
    return NULL;
  pMatch++;
  pEnd = strchr(pMatch, '\"');
  if (NULL == pEnd)
    return NULL;
  strOut = malloc(pEnd - pMatch + 1);
  memcpy(strOut, pMatch, pEnd - pMatch);
  strOut[pEnd - pMatch] = '\0';
  return strOut;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GetAttribute>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  mov    %rsi,%rdi
  push   %rbp
  mov    %r8,%rsi
  push   %rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L1
  mov    $0x22,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  lea    0x1(%rax),%rbp
  mov    $0x22,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *GetAttribute(const char *strAttribute, const char *strElement) {
  char *pMatch;
  char *pEnd;
  char *strOut;
  pMatch = strstr(strElement, strAttribute);
  if (NULL == pMatch)
    return NULL;
  pMatch = strchr(pMatch, '=');
  if (NULL == pMatch)
    return NULL;
  pMatch = strchr(pMatch, '\"');
  if (NULL == pMatch)
    return NULL;
  pMatch++;
  pEnd = strchr(pMatch, '\"');
  if (NULL == pEnd)
    return NULL;
  strOut = malloc(pEnd - pMatch + 1);
  memcpy(strOut, pMatch, pEnd - pMatch);
  strOut[pEnd - pMatch] = '\0';
  return strOut;
}
```