ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<do_tests_on_empty_root>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D15(%rip),%rbp
  mov    %rbp,%rsi
  call   <st_lookup_string@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <st_rm_string@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <st_lookup_string@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <st_rm_string@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D2(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <st_lookup_string@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <st_rm_string@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D5(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <st_lookup_string@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <st_rm_string@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x8,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D15: foo

tool: 

tool: D5: 


assistant: ```c
int do_tests_on_empty_root(struct st_root *root) {
  unsigned int tests = 0;
  assert(st_lookup_string(root, "foo") == NULL);
  assert(st_rm_string(root, "foo") == NULL);
  tests += 2;
  assert(st_lookup_string(root, NULL) == NULL);
  assert(st_rm_string(root, NULL) == NULL);
  tests += 2;
  assert(st_lookup_string(root, "") == NULL);
  assert(st_rm_string(root, "") == NULL);
  tests += 2;
  assert(st_lookup_string(root, "\n") == NULL);
  assert(st_rm_string(root, "\n") == NULL);
  tests += 2;
  return tests;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_tests_on_empty_root>:
  endbr64
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <st_lookup_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D21(%rip),%r12
  call   <st_rm_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <st_lookup_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <st_rm_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <st_lookup_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D2(%rip),%r12
  call   <st_rm_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <st_lookup_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <st_rm_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    $0x8,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D23: foo

tool: 

tool: D2: 


assistant: ```c
int do_tests_on_empty_root(struct st_root *root) {
  unsigned int tests = 0;
  assert(st_lookup_string(root, "foo") == NULL);
  assert(st_rm_string(root, "foo") == NULL);
  tests += 2;
  assert(st_lookup_string(root, NULL) == NULL);
  assert(st_rm_string(root, NULL) == NULL);
  tests += 2;
  assert(st_lookup_string(root, "") == NULL);
  assert(st_rm_string(root, "") == NULL);
  tests += 2;
  assert(st_lookup_string(root, "\n") == NULL);
  assert(st_rm_string(root, "\n") == NULL);
  tests += 2;
  return tests;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_tests_on_empty_root>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <st_lookup_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D20(%rip),%r12
  call   <st_rm_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <st_lookup_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <st_rm_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <st_lookup_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D3(%rip),%r12
  call   <st_rm_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <st_lookup_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <st_rm_string@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    $0x8,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D20
type: string
name: disassemble_data
arguments: data_tag: D3
type: string

tool: D4: foo

tool: 

tool: D3: 


assistant: ```c
int do_tests_on_empty_root(struct st_root *root) {
  unsigned int tests = 0;
  assert(st_lookup_string(root, "foo") == NULL);
  assert(st_rm_string(root, "foo") == NULL);
  tests += 2;
  assert(st_lookup_string(root, NULL) == NULL);
  assert(st_rm_string(root, NULL) == NULL);
  tests += 2;
  assert(st_lookup_string(root, "") == NULL);
  assert(st_rm_string(root, "") == NULL);
  tests += 2;
  assert(st_lookup_string(root, "\n") == NULL);
  assert(st_rm_string(root, "\n") == NULL);
  tests += 2;
  return tests;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<warshal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L26
L23:
  movl   $0x1,-0xc(%rbp)
  jmp    L111
L119:
  movl   $0x1,-0x8(%rbp)
  jmp    L12
L19:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,%ecx
  jle    L62
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L62
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  jmp    L74
L62:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L33
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L33
  mov    $0x1,%edx
  jmp    L74
L33:
  mov    $0x0,%edx
L74:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x3,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %edx,(%rcx,%rax,4)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L19
  addl   $0x1,-0xc(%rbp)
L111:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L119
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void warshal(int p[10][10], int n) {
  int i, j, k;
  for (k = 1; k <= n; k++)
    for (i = 1; i <= n; i++)
      for (j = 1; j <= n; j++)
        p[i][j] = (p[i][j] > p[i][k] && p[k][j] ? p[i][j] : p[i][k] && p[k][j]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<warshal>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%r8d
  lea    (%r8,%r8,4),%rax
  lea    0x54(%rdi,%rax,8),%r11
  lea    0x28(%rdi),%rbx
  mov    %r8,%rax
  neg    %rax
  lea    -0x8(,%rax,4),%r12
  mov    $0xfffffffffffffffc,%r10
  mov    %rbx,%rbp
  add    $0x2,%r8
  jmp    L88
L92:
  test   %edx,%edx
  je     L37
  cmpl   $0x0,(%r9,%rax,4)
  setne  %dl
  movzbl %dl,%edx
L37:
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L81
L19:
  mov    (%rsi,%rax,4),%ecx
  mov    (%rdi),%edx
  cmp    %edx,%ecx
  jle    L92
  mov    (%r9,%rax,4),%edx
  test   %edx,%edx
  cmovne %ecx,%edx
  jmp    L37
L81:
  add    $0x28,%rdi
  cmp    %r11,%rdi
  je     L1
L80:
  lea    (%rdi,%r10,1),%rsi
  mov    $0x1,%eax
  jmp    L19
L1:
  add    $0x4,%r11
  add    $0x28,%rbx
  sub    $0x4,%r10
  cmp    %r12,%r10
  je     L36
L88:
  mov    %rbx,%r9
  mov    %rbp,%rdi
  sub    %r10,%rdi
  jmp    L80
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  ret
```

assistant: ```c
void warshal(int p[10][10], int n) {
  int i, j, k;
  for (k = 1; k <= n; k++)
    for (i = 1; i <= n; i++)
      for (j = 1; j <= n; j++)
        p[i][j] = (p[i][j] > p[i][k] && p[k][j] ? p[i][j] : p[i][k] && p[k][j]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<warshal>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    %esi,%eax
  push   %rbp
  mov    $0xfffffffffffffffc,%r10
  sub    $0x1,%eax
  push   %rbx
  mov    %rdi,%rbx
  lea    (%rax,%rax,4),%rdx
  add    $0x28,%rbx
  lea    0x2(%rax),%r8
  lea    0x54(%rdi,%rdx,8),%r11
  mov    %rax,%rdx
  mov    %rbx,%r9
  neg    %rdx
  lea    -0x8(,%rdx,4),%rbp
  nop
L62:
  mov    %rbx,%rdi
  sub    %r10,%rdi
  cs nopw 0x0(%rax,%rax,1)
L70:
  lea    (%rdi,%r10,1),%rsi
  mov    $0x1,%eax
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L66:
  mov    (%r9,%rax,4),%edx
  test   %edx,%edx
  cmovne %ecx,%edx
L21:
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L6
L9:
  mov    (%rsi,%rax,4),%ecx
  mov    (%rdi),%edx
  cmp    %edx,%ecx
  jg     L66
  test   %edx,%edx
  je     L21
  mov    (%r9,%rax,4),%ecx
  xor    %edx,%edx
  test   %ecx,%ecx
  setne  %dl
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L9
L6:
  add    $0x28,%rdi
  cmp    %r11,%rdi
  jne    L70
  sub    $0x4,%r10
  add    $0x4,%r11
  add    $0x28,%r9
  cmp    %rbp,%r10
  jne    L62
  pop    %rbx
  pop    %rbp
  ret
L13:
  ret
```

assistant: ```c
void warshal(int p[10][10], int n) {
  int i, j, k;
  for (k = 1; k <= n; k++)
    for (i = 1; i <= n; i++)
      for (j = 1; j <= n; j++)
        p[i][j] = (p[i][j] > p[i][k] && p[k][j] ? p[i][j] : p[i][k] && p[k][j]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<warshal>:
  endbr64
  test   %esi,%esi
  jle    L69
  mov    %esi,%eax
  push   %rbp
  mov    $0xfffffffffffffffc,%r10
  sub    $0x1,%eax
  push   %rbx
  mov    %rdi,%rbx
  lea    (%rax,%rax,4),%rdx
  add    $0x28,%rbx
  lea    0x2(%rax),%r8
  lea    0x54(%rdi,%rdx,8),%r11
  mov    %rax,%rdx
  mov    %rbx,%r9
  neg    %rdx
  lea    -0x8(,%rdx,4),%rbp
  nop
L16:
  mov    %rbx,%rdi
  sub    %r10,%rdi
  cs nopw 0x0(%rax,%rax,1)
L76:
  lea    (%rdi,%r10,1),%rsi
  mov    $0x1,%eax
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L15:
  mov    (%r9,%rax,4),%edx
  test   %edx,%edx
  cmovne %ecx,%edx
L17:
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L4
L38:
  mov    (%rsi,%rax,4),%ecx
  mov    (%rdi),%edx
  cmp    %edx,%ecx
  jg     L15
  test   %edx,%edx
  je     L17
  mov    (%r9,%rax,4),%ecx
  xor    %edx,%edx
  test   %ecx,%ecx
  setne  %dl
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L38
L4:
  add    $0x28,%rdi
  cmp    %r11,%rdi
  jne    L76
  sub    $0x4,%r10
  add    $0x4,%r11
  add    $0x28,%r9
  cmp    %rbp,%r10
  jne    L16
  pop    %rbx
  pop    %rbp
  ret
L69:
  ret
```

assistant: ```c
void warshal(int p[10][10], int n) {
  int i, j, k;
  for (k = 1; k <= n; k++)
    for (i = 1; i <= n; i++)
      for (j = 1; j <= n; j++)
        p[i][j] = (p[i][j] > p[i][k] && p[k][j] ? p[i][j] : p[i][k] && p[k][j]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(int agrv, char *argc[]) {
  int i = 0;
  while (1) {
    printf("%d\n", i++);
    sleep(5);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D8(%rip),%rbp
L6:
  lea    0x1(%rsi),%ebx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main(int agrv, char *argc[]) {
  int i = 0;
  while (1) {
    printf("%d\n", i++);
    sleep(5);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  lea    0x1(%rsi),%ebx
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  jmp    L9
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: %d


assistant: ```c
int main(int agrv, char *argc[]) {
  int i = 0;
  while (1) {
    printf("%d\n", i++);
    sleep(5);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  lea    0x1(%rsi),%ebx
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    %ebx,%esi
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: %d


assistant: ```c
int main(int agrv, char *argc[]) {
  int i = 0;
  while (1) {
    printf("%d\n", i++);
    sleep(5);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x2,%rax
  shl    $0x2,%eax
  mov    %eax,%eax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    $0x1,%eax
  sub    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
float *vector(nl, nh)
long nh, nl;
{
  float *v;
  v = (float *)malloc((unsigned int)((nh - nl + 1 + 1) * sizeof(float)));
  return v - nl + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vector>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    %rdi,%rsi
  lea    0x8(,%rsi,4),%edi
  mov    %edi,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  sub    %rbx,%rax
  lea    (%rdx,%rax,4),%rax
  pop    %rbx
  ret
```

assistant: ```c
float *vector(nl, nh)
long nh, nl;
{
  float *v;
  v = (float *)malloc((unsigned int)((nh - nl + 1 + 1) * sizeof(float)));
  return v - nl + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vector>:
  endbr64
  push   %rbx
  sub    %rdi,%rsi
  mov    %rdi,%rbx
  lea    0x8(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  sub    %rbx,%rax
  pop    %rbx
  lea    (%r8,%rax,4),%rax
  ret
```

assistant: ```c
float *vector(nl, nh)
long nh, nl;
{
  float *v;
  v = (float *)malloc((unsigned int)((nh - nl + 1 + 1) * sizeof(float)));
  return v - nl + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<vector>:
  endbr64
  push   %rbx
  sub    %rdi,%rsi
  mov    %rdi,%rbx
  lea    0x8(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  sub    %rbx,%rax
  pop    %rbx
  lea    (%r8,%rax,4),%rax
  ret
```

assistant: ```c
float *vector(nl, nh)
long nh, nl;
{
  float *v;
  v = (float *)malloc((unsigned int)((nh - nl + 1 + 1) * sizeof(float)));
  return v - nl + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<preparePosteriorBoundaries>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x989680,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <space@plt>
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <space@plt>
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L12:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x989680,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  neg    %rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  neg    %rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void preparePosteriorBoundaries(int size, int shift, int *min_k, int *max_k, int **min_l, int **max_l) {
  int i;
  *min_k = 10000000;
  *max_k = 0;
  *min_l = (int *)space(sizeof(int) * size);
  *max_l = (int *)space(sizeof(int) * size);
  for (i = 0; i < size; i++) {
    (*min_l)[i] = 10000000;
    (*max_l)[i] = 0;
  }
  *min_l -= shift;
  *max_l -= shift;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<preparePosteriorBoundaries>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %r8,%rbp
  mov    %r9,%rbx
  movl   $0x989680,(%rdx)
  movl   $0x0,(%rcx)
  lea    0x0(,%rdi,4),%r14d
  mov    %r14d,%edi
  call   <space@plt>
  mov    %rax,0x0(%rbp)
  mov    %r14d,%edi
  call   <space@plt>
  mov    %rax,(%rbx)
  test   %r13d,%r13d
  jle    L12
  mov    %r13d,%ecx
  shl    $0x2,%rcx
  mov    $0x0,%eax
L11:
  mov    0x0(%rbp),%rdx
  movl   $0x989680,(%rdx,%rax,1)
  mov    (%rbx),%rdx
  movl   $0x0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L11
L12:
  movslq %r12d,%r12
  shl    $0x2,%r12
  sub    %r12,0x0(%rbp)
  sub    %r12,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void preparePosteriorBoundaries(int size, int shift, int *min_k, int *max_k, int **min_l, int **max_l) {
  int i;
  *min_k = 10000000;
  *max_k = 0;
  *min_l = (int *)space(sizeof(int) * size);
  *max_l = (int *)space(sizeof(int) * size);
  for (i = 0; i < size; i++) {
    (*min_l)[i] = 10000000;
    (*max_l)[i] = 0;
  }
  *min_l -= shift;
  *max_l -= shift;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<preparePosteriorBoundaries>:
  endbr64
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,4),%r14d
  mov    %r8,%rbp
  push   %rbx
  mov    %r14d,%edi
  movslq %esi,%rbx
  movl   $0x989680,(%rdx)
  movl   $0x0,(%rcx)
  call   <space@plt>
  mov    %r14d,%edi
  mov    %rax,0x0(%rbp)
  call   <space@plt>
  mov    %rax,0x0(%r13)
  mov    0x0(%rbp),%rsi
  test   %r12d,%r12d
  jle    L6
  mov    %rsi,%rdx
  lea    (%rax,%r12,4),%rcx
  sub    %rax,%rdx
  nopw   0x0(%rax,%rax,1)
L13:
  movl   $0x989680,(%rdx,%rax,1)
  add    $0x4,%rax
  movl   $0x0,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L13
L6:
  shl    $0x2,%rbx
  sub    %rbx,%rsi
  mov    %rsi,0x0(%rbp)
  sub    %rbx,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void preparePosteriorBoundaries(int size, int shift, int *min_k, int *max_k, int **min_l, int **max_l) {
  int i;
  *min_k = 10000000;
  *max_k = 0;
  *min_l = (int *)space(sizeof(int) * size);
  *max_l = (int *)space(sizeof(int) * size);
  for (i = 0; i < size; i++) {
    (*min_l)[i] = 10000000;
    (*max_l)[i] = 0;
  }
  *min_l -= shift;
  *max_l -= shift;
}
```