ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writeResetToDefaults>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3430314b544d5024,%rax
  mov    %rax,-0x16(%rbp)
  movl   $0xd37332a,-0xe(%rbp)
  movw   $0xa,-0xa(%rbp)
  lea    -0x16(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0xe,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L5
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L5:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string

tool: D3: error writing


tool: D10: perror writing

assistant: ```c
void writeResetToDefaults(int fd) {
  unsigned char command[] = "$PMTK104*37\r\n";
  if (write(fd, command, sizeof(command)) == -1) {
    printf("error writing\n");
    perror("perror writing");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writeResetToDefaults>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3430314b544d5024,%rax
  mov    %rax,0xa(%rsp)
  movl   $0xd37332a,0x12(%rsp)
  movw   $0xa,0x16(%rsp)
  lea    0xa(%rsp),%rsi
  mov    $0xe,%edx
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L16
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L16:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <perror@plt>
  jmp    L21
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string
name: parse_data
arguments: data_label: D19
data_type: string

tool: D6: error writing


tool: D19: perror writing

assistant: ```c
void writeResetToDefaults(int fd) {
  unsigned char command[] = "$PMTK104*37\r\n";
  if (write(fd, command, sizeof(command)) == -1) {
    printf("error writing\n");
    perror("perror writing");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<writeResetToDefaults>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xe,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3430314b544d5024,%rax
  lea    0xa(%rsp),%rsi
  movl   $0xd37332a,0x12(%rsp)
  mov    %rax,0xa(%rsp)
  mov    $0xa,%eax
  mov    %ax,0x16(%rsp)
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L22
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  ret
L22:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <perror@plt>
  jmp    L21
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string

tool: D4: error writing


tool: D6: perror writing

assistant: ```c
void writeResetToDefaults(int fd) {
  unsigned char command[] = "$PMTK104*37\r\n";
  if (write(fd, command, sizeof(command)) == -1) {
    printf("error writing\n");
    perror("perror writing");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writeResetToDefaults>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xe,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3430314b544d5024,%rax
  lea    0xa(%rsp),%rsi
  movl   $0xd37332a,0x12(%rsp)
  mov    %rax,0xa(%rsp)
  mov    $0xa,%eax
  mov    %ax,0x16(%rsp)
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L11
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L11:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <perror@plt>
  jmp    L6
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D10
data_type: string

tool: D14: error writing


tool: D10: perror writing

assistant: ```c
void writeResetToDefaults(int fd) {
  unsigned char command[] = "$PMTK104*37\r\n";
  if (write(fd, command, sizeof(command)) == -1) {
    printf("error writing\n");
    perror("perror writing");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L46
L12:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    $0x0,%eax
  jmp    L37
L46:
  movzbl (%rbx),%edx
  movzbl (%r12),%eax
  cmp    %al,%dl
  jne    L12
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L12
  mov    %rbx,%rax
L37:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(s, wanted)
register char *s, *wanted;
{
  int len = strlen(wanted);
  while (*s != *wanted || strncmp(s, wanted, len)) {
    if (*s++ == '\0')
      return 0;
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  movzbl 0x0(%r13),%r12d
  movslq %eax,%r14
  jmp    L36
L25:
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L19
L36:
  movzbl (%rbx),%ebp
  cmp    %r12b,%bpl
  jne    L25
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L25
  mov    %rbx,%rax
  jmp    L20
L19:
  mov    $0x0,%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(s, wanted)
register char *s, *wanted;
{
  int len = strlen(wanted);
  while (*s != *wanted || strncmp(s, wanted, len)) {
    if (*s++ == '\0')
      return 0;
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  movzbl 0x0(%r13),%r12d
  movslq %eax,%r14
  jmp    L31
  nopl   0x0(%rax)
L26:
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L3
L31:
  movzbl (%rbx),%ebp
  cmp    %r12b,%bpl
  jne    L26
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L26
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(s, wanted)
register char *s, *wanted;
{
  int len = strlen(wanted);
  while (*s != *wanted || strncmp(s, wanted, len)) {
    if (*s++ == '\0')
      return 0;
  }
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  movzbl 0x0(%r13),%r12d
  movslq %eax,%r14
  jmp    L4
  nopl   0x0(%rax)
L32:
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L24
L4:
  movzbl (%rbx),%ebp
  cmp    %r12b,%bpl
  jne    L32
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L32
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(s, wanted)
register char *s, *wanted;
{
  int len = strlen(wanted);
  while (*s != *wanted || strncmp(s, wanted, len)) {
    if (*s++ == '\0')
      return 0;
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D51(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jae    L18
  comiss 0x8(%rsp),%xmm0
  jae    L78
  comiss 0xc(%rsp),%xmm0
  jae    L48
  comiss 0x10(%rsp),%xmm0
  jb     L16
  mov    $0x44,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L72
L18:
  mov    $0x41,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L72:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L78:
  mov    $0x42,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L72
L48:
  mov    $0x43,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L72
L16:
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L72
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D59
type_infered: string
name: read_data
arguments: data_label: D51
type_infered: string
name: read_data
arguments: data_label: D53
type_infered: string
name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D49
type_infered: string

tool: D59: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D51: %f %f %f %f

tool: D53: Thank you. Now enter student score (percent) >

tool: D37: %f

tool: D18: Student has an %c grade


tool: D49: Student has failed the course

assistant: ```c
int main() {
  float a;
  float b;
  float c;
  float d;
  float perc;
  char grade;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f %f %f %f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &perc);
  if (perc >= a) {
    grade = 'A';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= b) {
    grade = 'B';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= c) {
    grade = 'C';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= d) {
    grade = 'D';
    printf("Student has an %c grade\n", grade);
  } else {
    grade = 'F';
    printf("Student has failed the course");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D55(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jae    L6
  comiss 0x8(%rsp),%xmm0
  jae    L35
  comiss 0xc(%rsp),%xmm0
  jae    L45
  comiss 0x10(%rsp),%xmm0
  jb     L25
  mov    $0x44,%esi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L65
L35:
  mov    $0x42,%esi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L65:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  mov    $0x41,%esi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L65
L25:
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L65
L45:
  mov    $0x43,%esi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L65
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D55
type_infered: string
name: parse_data
arguments: data_label: D40
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D20
type_infered: string
name: parse_data
arguments: data_label: D88
type_infered: string
name: parse_data
arguments: data_label: D25
type_infered: string

tool: D55: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D40: %f %f %f %f

tool: D10: Thank you. Now enter student score (percent) >

tool: D20: %f

tool: D88: Student has an %c grade


tool: D25: Student has failed the course

assistant: ```c
int main() {
  float a;
  float b;
  float c;
  float d;
  float perc;
  char grade;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f %f %f %f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &perc);
  if (perc >= a) {
    grade = 'A';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= b) {
    grade = 'B';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= c) {
    grade = 'C';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= d) {
    grade = 'D';
    printf("Student has an %c grade\n", grade);
  } else {
    grade = 'F';
    printf("Student has failed the course");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jae    L10
  comiss 0x8(%rsp),%xmm0
  jae    L78
  comiss 0xc(%rsp),%xmm0
  jae    L87
  comiss 0x10(%rsp),%xmm0
  jb     L40
  mov    $0x44,%esi
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L81
L78:
  mov    $0x42,%esi
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L81:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L10:
  mov    $0x41,%esi
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L81
L40:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L81
L87:
  mov    $0x43,%esi
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L81
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: string
name: read_data
arguments: data_label: D13
data_type: string
name: read_data
arguments: data_label: D51
data_type: string
name: read_data
arguments: data_label: D28
data_type: string
name: read_data
arguments: data_label: D79
data_type: string
name: read_data
arguments: data_label: D26
data_type: string

tool: D14: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D13: %f %f %f %f

tool: D51: Thank you. Now enter student score (percent) >

tool: D28: %f

tool: D79: Student has an %c grade


tool: D26: Student has failed the course

assistant: ```c
int main() {
  float a;
  float b;
  float c;
  float d;
  float perc;
  char grade;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f %f %f %f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &perc);
  if (perc >= a) {
    grade = 'A';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= b) {
    grade = 'B';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= c) {
    grade = 'C';
    printf("Student has an %c grade\n", grade);
  } else if (perc >= d) {
    grade = 'D';
    printf("Student has an %c grade\n", grade);
  } else {
    grade = 'F';
    printf("Student has failed the course");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7a,-0x4(%rbp)
  jg     L15
  cmpl   $0x60,-0x4(%rbp)
  jle    L15
  subl   $0x20,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c < 123 && c > 96)
    c -= 32;
  return (c);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_toupper>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%ecx
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c < 123 && c > 96)
    c -= 32;
  return (c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c < 123 && c > 96)
    c -= 32;
  return (c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c < 123 && c > 96)
    c -= 32;
  return (c);
}
```
user: What is the c source code of the assembly code below?

```asm
<mylog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movsd  D0(%rip),%xmm0
  movq   %rax,%xmm1
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: byte[8]

tool: {"D0": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
float mylog2(x)
double x;
{
  double log();
  return ((float)(log(x) / log((double)2.0)));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mylog2>:
  endbr64
  sub    $0x8,%rsp
  call   <log@plt>
  divsd  D3(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: byte[8]

tool: {"D3": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
float mylog2(x)
double x;
{
  double log();
  return ((float)(log(x) / log((double)2.0)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mylog2>:
  endbr64
  sub    $0x8,%rsp
  call   <log@plt>
  divsd  D0(%rip),%xmm0
  add    $0x8,%rsp
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: byte[8]

tool: {"D0": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
float mylog2(x)
double x;
{
  double log();
  return ((float)(log(x) / log((double)2.0)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mylog2>:
  endbr64
  sub    $0x8,%rsp
  call   <log@plt>
  divsd  D5(%rip),%xmm0
  add    $0x8,%rsp
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: byte[8]

tool: {"D5": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
float mylog2(x)
double x;
{
  double log();
  return ((float)(log(x) / log((double)2.0)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L57:
  cmp    %rdx,%rsp
  je     L6
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L57
L6:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L68
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L68:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L11
L31:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L11:
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L31
  mov    -0x50(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4c(%rbp)
  jmp    L13
L69:
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4c(%rbp)
L13:
  cmpl   $0x0,-0x4c(%rbp)
  jns    L69
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
data_type: string
name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D25: %d

tool: D0: 
%d

assistant: ```c
int main() {
  int i, n;
  scanf("%d", &n);
  int m[n];
  for (i = 0; i < n;) {
    scanf("%d", &m[i]);
    i++;
  }
  for (i = n - 1; i >= 0;) {
    printf("\n%d", m[i]);
    i--;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%ebx
  movslq %ebx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L10:
  cmp    %rdx,%rsp
  je     L68
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L10
L68:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L72
  orq    $0x0,-0x8(%rsp,%rax,1)
L72:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L47
  mov    %r13,%r14
  mov    $0x0,%r12d
  lea    D24(%rip),%r15
L51:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    -0x3c(%rbp),%ebx
  add    $0x4,%r14
  cmp    %r12d,%ebx
  jg     L51
L47:
  sub    $0x1,%ebx
  js     L75
  movslq %ebx,%rbx
  lea    D12(%rip),%r12
L63:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L63
L75:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D24
datatype: string
name: parse_data
arguments: tag: D12
datatype: string

tool: D24: %d

tool: D12: 
%d

assistant: ```c
int main() {
  int i, n;
  scanf("%d", &n);
  int m[n];
  for (i = 0; i < n;) {
    scanf("%d", &m[i]);
    i++;
  }
  for (i = n - 1; i >= 0;) {
    printf("\n%d", m[i]);
    i--;
  }
  return 0;
}
```