ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<blur_cusp2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r11d
  mov    $0x100,%r9d
  sub    %r8d,%r9d
  mov    (%rdi),%eax
  imul   %edx,%ecx
  mov    %ecx,%r10d
  test   %ecx,%ecx
  jle    L0
  mov    %ecx,%ebx
  mov    $0x0,%edx
L125:
  mov    %r9d,%ecx
  imul   (%rdi,%rdx,4),%ecx
  imul   %r8d,%eax
  add    %ecx,%eax
  sar    $0x8,%eax
  mov    %eax,(%rsi,%rdx,4)
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  jne    L125
  movslq %r10d,%rax
  lea    -0x4(%rsi,%rax,4),%rbp
  mov    0x0(%rbp),%eax
  lea    -0x1(%r10),%edx
  movslq %edx,%rdx
L11:
  mov    %r9d,%ecx
  imul   (%rsi,%rdx,4),%ecx
  imul   %r8d,%eax
  add    %ecx,%eax
  sar    $0x8,%eax
  mov    %eax,(%rdi,%rdx,4)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L11
L117:
  mov    (%rdi),%eax
  test   %r11d,%r11d
  jle    L120
  mov    %r11d,%r13d
  mov    $0x0,%r12d
  movslq %r11d,%rbx
  jmp    L121
L0:
  movslq %ecx,%rax
  lea    -0x4(%rsi,%rax,4),%rbp
  jmp    L117
L7:
  mov    %r9d,%ecx
  imul   (%rdi,%rdx,4),%ecx
  imul   %r8d,%eax
  add    %ecx,%eax
  sar    $0x8,%eax
  mov    %eax,(%rsi,%rdx,4)
  add    %rbx,%rdx
  cmp    %edx,%r10d
  jg     L7
L71:
  add    $0x1,%r12
  cmp    %r13,%r12
  je     L13
L121:
  mov    %r12,%rdx
  cmp    %r12d,%r10d
  jg     L7
  jmp    L71
L13:
  mov    0x0(%rbp),%edx
  lea    -0x1(%r11),%ebx
  lea    -0x1(%r10),%ebp
  sub    %r11d,%r10d
  movslq %r10d,%r12
  movslq %ebx,%rax
  add    %rax,%r12
  neg    %r11d
  movslq %r11d,%r10
L23:
  test   %ebp,%ebp
  js     L99
  mov    %r12,%rax
L41:
  mov    %r9d,%ecx
  imul   (%rsi,%rax,4),%ecx
  imul   %r8d,%edx
  add    %ecx,%edx
  sar    $0x8,%edx
  mov    %edx,(%rdi,%rax,4)
  add    %r10,%rax
  test   %eax,%eax
  jns    L41
L99:
  sub    $0x1,%ebp
  sub    $0x1,%r12
  sub    $0x1,%ebx
  jns    L23
L120:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void blur_cusp2(int *in, int *tmp, int w, int h, int amount) {
  int ramount;
  int sum;
  int i, j;
  ramount = 256 - amount;
  sum = in[0];
  for (i = 0; i < w * h; i++) {
    sum = (sum * amount + in[i] * ramount) >> 8;
    tmp[i] = sum;
  }
  sum = tmp[w * h - 1];
  for (i = w * h - 1; i >= 0; i--) {
    sum = (sum * amount + tmp[i] * ramount) >> 8;
    in[i] = sum;
  }
  sum = in[0];
  for (j = 0; j < w; j++) {
    for (i = j; i < w * h; i += w) {
      sum = (sum * amount + in[i] * ramount) >> 8;
      tmp[i] = sum;
    }
  }
  sum = tmp[w * h - 1];
  for (j = w - 1; j >= 0; j--) {
    for (i = w * (h - 1) + j; i >= 0; i -= w) {
      sum = (sum * amount + tmp[i] * ramount) >> 8;
      in[i] = sum;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<blur_cusp2>:
  endbr64
  imul   %edx,%ecx
  push   %r14
  mov    $0x100,%r9d
  mov    (%rdi),%eax
  push   %r13
  sub    %r8d,%r9d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  movslq %ecx,%rdx
  mov    %rdx,%r10
  lea    -0x4(%rsi,%rdx,4),%r14
  lea    -0x1(%rdx),%r13d
  test   %edx,%edx
  jle    L27
  mov    %r13d,%r11d
  mov    %eax,%ecx
  xor    %edx,%edx
  shl    $0x2,%r11
  jmp    L29
L11:
  mov    0x4(%rdi,%rdx,1),%ecx
  add    $0x4,%rdx
L29:
  imul   %r8d,%eax
  imul   %r9d,%ecx
  add    %ecx,%eax
  sar    $0x8,%eax
  mov    %eax,(%rsi,%rdx,1)
  cmp    %rdx,%r11
  jne    L11
L109:
  mov    (%r14),%eax
  movslq %r13d,%rdx
  nopl   0x0(%rax,%rax,1)
L7:
  mov    (%rsi,%rdx,4),%ecx
  imul   %r8d,%eax
  imul   %r9d,%ecx
  add    %ecx,%eax
  sar    $0x8,%eax
  mov    %eax,(%rdi,%rdx,4)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L7
  mov    (%rdi),%eax
  lea    -0x1(%rbx),%r11d
  test   %ebx,%ebx
  jle    L112
L31:
  movslq %ebx,%rbp
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L102:
  mov    %r12,%rdx
  cmp    %r12d,%r10d
  jle    L101
  nopl   0x0(%rax,%rax,1)
L55:
  mov    (%rdi,%rdx,4),%ecx
  imul   %r8d,%eax
  imul   %r9d,%ecx
  add    %ecx,%eax
  sar    $0x8,%eax
  mov    %eax,(%rsi,%rdx,4)
  add    %rbp,%rdx
  cmp    %edx,%r10d
  jg     L55
L101:
  add    $0x1,%r12
  cmp    %r12,%rbp
  jne    L102
L26:
  sub    %ebx,%r10d
  movslq %r11d,%rax
  neg    %ebx
  mov    (%r14),%edx
  movslq %r10d,%rbp
  movslq %ebx,%r10
  add    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L10:
  test   %r13d,%r13d
  js     L24
  mov    %rbp,%rax
  nopl   0x0(%rax,%rax,1)
L40:
  mov    (%rsi,%rax,4),%ecx
  imul   %r8d,%edx
  imul   %r9d,%ecx
  add    %ecx,%edx
  sar    $0x8,%edx
  mov    %edx,(%rdi,%rax,4)
  add    %r10,%rax
  test   %eax,%eax
  jns    L40
L24:
  sub    $0x1,%r11d
  sub    $0x1,%r13d
  sub    $0x1,%rbp
  cmp    $0xffffffff,%r11d
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  test   %r13d,%r13d
  jns    L109
  lea    -0x1(%rbx),%r11d
  test   %ebx,%ebx
  jg     L31
L112:
  test   %r11d,%r11d
  jns    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void blur_cusp2(int *in, int *tmp, int w, int h, int amount) {
  int ramount;
  int sum;
  int i, j;
  ramount = 256 - amount;
  sum = in[0];
  for (i = 0; i < w * h; i++) {
    sum = (sum * amount + in[i] * ramount) >> 8;
    tmp[i] = sum;
  }
  sum = tmp[w * h - 1];
  for (i = w * h - 1; i >= 0; i--) {
    sum = (sum * amount + tmp[i] * ramount) >> 8;
    in[i] = sum;
  }
  sum = in[0];
  for (j = 0; j < w; j++) {
    for (i = j; i < w * h; i += w) {
      sum = (sum * amount + in[i] * ramount) >> 8;
      tmp[i] = sum;
    }
  }
  sum = tmp[w * h - 1];
  for (j = w - 1; j >= 0; j--) {
    for (i = w * (h - 1) + j; i >= 0; i -= w) {
      sum = (sum * amount + tmp[i] * ramount) >> 8;
      in[i] = sum;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse_inplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L29:
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L31
L10:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x10(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x10(%rbp)
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverse_inplace(char *str) {
  char *idx = str;
  while (*idx)
    idx++;
  int length = idx - str;
  for (int i = 0; i < length / 2; i++) {
    swap(&str[i], &str[length - 1 - i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse_inplace>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rax
L14:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L14
  sub    %rbp,%rax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0x1,%eax
  jle    L2
  mov    $0x0,%ebx
  cltq
  lea    -0x1(%rbp,%rax,1),%r13
L32:
  mov    %r13,%rsi
  sub    %rbx,%rsi
  lea    (%rbx,%rbp,1),%rdi
  call   <swap@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L32
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

assistant: ```c
void reverse_inplace(char *str) {
  char *idx = str;
  while (*idx)
    idx++;
  int length = idx - str;
  for (int i = 0; i < length / 2; i++) {
    swap(&str[i], &str[length - 1 - i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse_inplace>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L39
  push   %r13
  mov    %rdi,%rax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L17
  sub    %rbp,%rax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0x1,%eax
  jle    L26
  cltq
  xor    %ebx,%ebx
  lea    -0x1(%rbp,%rax,1),%r13
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r13,%rsi
  lea    0x0(%rbp,%rbx,1),%rdi
  sub    %rbx,%rsi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %ebx,%r12d
  jg     L4
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L39:
  ret
```

assistant: ```c
void reverse_inplace(char *str) {
  char *idx = str;
  while (*idx)
    idx++;
  int length = idx - str;
  for (int i = 0; i < length / 2; i++) {
    swap(&str[i], &str[length - 1 - i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse_inplace>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L29
  push   %r13
  mov    %rdi,%rax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L4
  sub    %rbp,%rax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0x1,%eax
  jle    L24
  cltq
  xor    %ebx,%ebx
  lea    -0x1(%rbp,%rax,1),%r13
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r13,%rsi
  lea    0x0(%rbp,%rbx,1),%rdi
  sub    %rbx,%rsi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %ebx,%r12d
  jg     L5
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  ret
```

assistant: ```c
void reverse_inplace(char *str) {
  char *idx = str;
  while (*idx)
    idx++;
  int length = idx - str;
  for (int i = 0; i < length / 2; i++) {
    swap(&str[i], &str[length - 1 - i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xcalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  imul   %edx,%eax
  mov    %eax,%edx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <err@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: xcalloc can not allocate %lu bytes

assistant: ```c
void *xcalloc(size_t nmem, size_t size) {
  void *ret = calloc(nmem, size);
  if (ret == NULL)
    err(2, "xcalloc can not allocate %lu bytes", (u_long)(size * nmem));
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xcalloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
L12:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %ebp,%edx
  imul   %r12d,%edx
  lea    D4(%rip),%rsi
  mov    $0x2,%edi
  call   <err@plt>
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: xcalloc can not allocate %lu bytes

assistant: ```c
void *xcalloc(size_t nmem, size_t size) {
  void *ret = calloc(nmem, size);
  if (ret == NULL)
    err(2, "xcalloc can not allocate %lu bytes", (u_long)(size * nmem));
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xcalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %ebx,%edx
  lea    D3(%rip),%rsi
  mov    $0x2,%edi
  imul   %ebp,%edx
  call   <err@plt>
  jmp    L3
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: xcalloc can not allocate %lu bytes

assistant: ```c
void *xcalloc(size_t nmem, size_t size) {
  void *ret = calloc(nmem, size);
  if (ret == NULL)
    err(2, "xcalloc can not allocate %lu bytes", (u_long)(size * nmem));
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xcalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %ebx,%edx
  lea    D0(%rip),%rsi
  mov    $0x2,%edi
  imul   %ebp,%edx
  call   <err@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: xcalloc can not allocate %lu bytes

assistant: ```c
void *xcalloc(size_t nmem, size_t size) {
  void *ret = calloc(nmem, size);
  if (ret == NULL)
    err(2, "xcalloc can not allocate %lu bytes", (u_long)(size * nmem));
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x13000(%rsp),%r11
L21:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L21
  sub    $0xbc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x13bb0(%rbp),%rdx
  lea    -0x13890(%rbp),%rcx
  lea    -0x13bc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <le_entrada@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x13bbc(%rbp)
  jmp    L2
L29:
  mov    -0x13bbc(%rbp),%eax
  cltq
  mov    -0x13bb0(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x13bbc(%rbp)
L2:
  mov    -0x13bc0(%rbp),%eax
  cmp    %eax,-0x13bbc(%rbp)
  jl     L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x13bc0(%rbp),%eax
  lea    -0x13bb0(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <norma2_sem_overflow@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x13bb8(%rbp)
  mov    -0x13bb8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string

tool: D6: b eh :

tool: D19: %lf 

tool: D22: Norma: %lf


assistant: ```c
int main() {
  int n;
  double A[100][100];
  double b[100];
  double norma;
  int p[100];
  int ret;
  int i;
  le_entrada(&n, A, b);
  printf("b eh :");
  for (i = 0; i < n; i++)
    printf("%lf ", b[i]);
  printf("\n");
  norma = norma2_sem_overflow(n, b);
  printf("Norma: %lf\n", norma);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x13000(%rsp),%r11
L28:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L28
  sub    $0xbc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x13bb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x330(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <le_entrada@plt>
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L37
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L1:
  movsd  0x10(%rsp,%rbx,8),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L1
L37:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x10(%rsp),%rsi
  mov    0xc(%rsp),%edi
  call   <norma2_sem_overflow@plt>
  lea    D12(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x13bb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x13bc8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
datatype: string
name: extract_symbolic_data
arguments: data_tag: D5
datatype: string
name: extract_symbolic_data
arguments: data_tag: D12
datatype: string

tool: D21: b eh :

tool: D5: %lf 

tool: D12: Norma: %lf


assistant: ```c
int main() {
  int n;
  double A[100][100];
  double b[100];
  double norma;
  int p[100];
  int ret;
  int i;
  le_entrada(&n, A, b);
  printf("b eh :");
  for (i = 0; i < n; i++)
    printf("%lf ", b[i]);
  printf("\n");
  norma = norma2_sem_overflow(n, b);
  printf("Norma: %lf\n", norma);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x13000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0xbc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x13bb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x330(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rdx
  call   <le_entrada@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L6
  xor    %ebx,%ebx
  lea    D22(%rip),%r12
  nopl   0x0(%rax)
L34:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L34
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <norma2_sem_overflow@plt>
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x13bb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x13bc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D22
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string

tool: D9: b eh :

tool: D22: %lf 

tool: D20: Norma: %lf


assistant: ```c
int main() {
  int n;
  double A[100][100];
  double b[100];
  double norma;
  int p[100];
  int ret;
  int i;
  le_entrada(&n, A, b);
  printf("b eh :");
  for (i = 0; i < n; i++)
    printf("%lf ", b[i]);
  printf("\n");
  norma = norma2_sem_overflow(n, b);
  printf("Norma: %lf\n", norma);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x13000(%rsp),%r11
L5:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L5
  sub    $0xbc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x13bb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x330(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rdx
  call   <le_entrada@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L22
  xor    %ebx,%ebx
  lea    D11(%rip),%r12
  nopl   0x0(%rax)
L17:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L17
L22:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <norma2_sem_overflow@plt>
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x13bb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x13bc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string

tool: D29: b eh :

tool: D11: %lf 

tool: D20: Norma: %lf


assistant: ```c
int main() {
  int n;
  double A[100][100];
  double b[100];
  double norma;
  int p[100];
  int ret;
  int i;
  le_entrada(&n, A, b);
  printf("b eh :");
  for (i = 0; i < n; i++)
    printf("%lf ", b[i]);
  printf("\n");
  norma = norma2_sem_overflow(n, b);
  printf("Norma: %lf\n", norma);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cse_match_suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
L23:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L26
L53:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L38
L4:
  mov    $0x1,%eax
  jmp    L26
L38:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    $0x0,%eax
L26:
  leave
  ret
```

assistant: ```c
int cse_match_suffix(const char *full, const char *suffix) {
  int len = strlen(suffix);
  do {
    char *match = strstr(full, suffix);
    if (!match)
      return 0;
    if (!match[len] || match[len] == '/')
      return 1;
    full = match + len;
  } while (*full);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cse_match_suffix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  movslq %eax,%r12
L33:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L32
  lea    (%rax,%r12,1),%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L22
  cmp    $0x2f,%al
  jne    L33
L22:
  mov    $0x1,%eax
  jmp    L11
L32:
  mov    $0x0,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cse_match_suffix(const char *full, const char *suffix) {
  int len = strlen(suffix);
  do {
    char *match = strstr(full, suffix);
    if (!match)
      return 0;
    if (!match[len] || match[len] == '/')
      return 1;
    full = match + len;
  } while (*full);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cse_match_suffix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  movslq %eax,%r12
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L25:
  lea    (%rax,%r12,1),%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L23
  cmp    $0x2f,%al
  je     L23
L26:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L25
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cse_match_suffix(const char *full, const char *suffix) {
  int len = strlen(suffix);
  do {
    char *match = strstr(full, suffix);
    if (!match)
      return 0;
    if (!match[len] || match[len] == '/')
      return 1;
    full = match + len;
  } while (*full);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cse_match_suffix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  movslq %eax,%r12
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L24:
  lea    (%rax,%r12,1),%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L14
  cmp    $0x2f,%al
  je     L14
L22:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L24
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cse_match_suffix(const char *full, const char *suffix) {
  int len = strlen(suffix);
  do {
    char *match = strstr(full, suffix);
    if (!match)
      return 0;
    if (!match[len] || match[len] == '/')
      return 1;
    full = match + len;
  } while (*full);
  return 0;
}
```