ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<stdlib_strided_dssumors>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jle    L31
  cmp    $0x1,%edi
  je     L23
  test   %edx,%edx
  je     L23
  cmp    $0x1,%edx
  je     L109
  xor    %ecx,%ecx
  test   %edx,%edx
  js     L56
L96:
  movslq %ecx,%rcx
  movslq %edx,%rdx
  pxor   %xmm0,%xmm0
  lea    (%rsi,%rcx,4),%rsi
  shl    $0x2,%rdx
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L89:
  pxor   %xmm1,%xmm1
  add    $0x1,%ecx
  cvtss2sd (%rsi),%xmm1
  add    %rdx,%rsi
  addsd  %xmm1,%xmm0
  cmp    %ecx,%eax
  jne    L89
  ret
  nop
L23:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rsi),%xmm0
  ret
  nopl   0x0(%rax)
L31:
  pxor   %xmm0,%xmm0
L43:
  ret
  nopl   (%rax)
L56:
  mov    $0x1,%ecx
  sub    %edi,%ecx
  imul   %edx,%ecx
  jmp    L96
  nopl   0x0(%rax)
L109:
  movslq %edi,%rcx
  cltd
  pxor   %xmm0,%xmm0
  imul   $0x2aaaaaab,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %edx,%ecx
  lea    (%rcx,%rcx,2),%edx
  mov    %edi,%ecx
  add    %edx,%edx
  sub    %edx,%ecx
  je     L97
  lea    -0x1(%rcx),%edi
  mov    %rsi,%rdx
  lea    0x4(%rsi,%rdi,4),%rdi
L108:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdx
  cvtss2sd -0x4(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rdi
  jne    L108
L97:
  cmp    $0x5,%eax
  jle    L43
  movslq %ecx,%rdx
  lea    (%rsi,%rdx,4),%rdx
  nopl   (%rax)
L3:
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  add    $0x6,%ecx
  add    $0x18,%rdx
  cvtss2sd -0x14(%rdx),%xmm2
  cvtss2sd -0x18(%rdx),%xmm1
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x10(%rdx),%xmm2
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rdx),%xmm2
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x8(%rdx),%xmm2
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rdx),%xmm2
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %ecx,%eax
  jg     L3
  ret
```

assistant: ```c
double stdlib_strided_dssumors(const int64_t N, const float *X, const int64_t stride) {
  double sum;
  int64_t ix;
  int64_t m;
  int64_t i;
  sum = 0.0;
  if (N <= 0) {
    return sum;
  }
  if (N == 1 || stride == 0) {
    return X[0];
  }
  if (stride == 1) {
    m = N % 6;
    if (m > 0) {
      for (i = 0; i < m; i++) {
        sum += (double)X[i];
      }
    }
    if (N < 6) {
      return sum;
    }
    for (i = m; i < N; i += 6) {
      sum += (double)X[i] + (double)X[i + 1] + (double)X[i + 2] + (double)X[i + 3] + (double)X[i + 4] + (double)X[i + 5];
    }
    return sum;
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    sum += (double)X[ix];
    ix += stride;
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stdlib_strided_dssumors>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jle    L53
  cmp    $0x1,%edi
  je     L39
  test   %edx,%edx
  je     L39
  cmp    $0x1,%edx
  je     L130
  xor    %ecx,%ecx
  test   %edx,%edx
  js     L45
L66:
  movslq %ecx,%rcx
  movslq %edx,%rdx
  pxor   %xmm0,%xmm0
  lea    (%rsi,%rcx,4),%rsi
  shl    $0x2,%rdx
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L50:
  pxor   %xmm1,%xmm1
  add    $0x1,%ecx
  cvtss2sd (%rsi),%xmm1
  add    %rdx,%rsi
  addsd  %xmm1,%xmm0
  cmp    %ecx,%eax
  jne    L50
  ret
  nop
L39:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rsi),%xmm0
  ret
  nopl   0x0(%rax)
L53:
  pxor   %xmm0,%xmm0
L122:
  ret
  nopl   (%rax)
L45:
  mov    $0x1,%ecx
  sub    %edi,%ecx
  imul   %edx,%ecx
  jmp    L66
  nopl   0x0(%rax)
L130:
  movslq %edi,%rcx
  cltd
  pxor   %xmm0,%xmm0
  imul   $0x2aaaaaab,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %edx,%ecx
  lea    (%rcx,%rcx,2),%edx
  mov    %edi,%ecx
  add    %edx,%edx
  sub    %edx,%ecx
  je     L89
  pxor   %xmm1,%xmm1
  cvtss2sd (%rsi),%xmm1
  addsd  %xmm1,%xmm0
  cmp    $0x1,%ecx
  je     L89
  pxor   %xmm1,%xmm1
  cvtss2sd 0x4(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  cmp    $0x2,%ecx
  je     L89
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  cmp    $0x3,%ecx
  je     L89
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  cmp    $0x5,%ecx
  jne    L89
  pxor   %xmm1,%xmm1
  cvtss2sd 0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
L89:
  cmp    $0x5,%eax
  jle    L122
  movslq %ecx,%rdx
  lea    (%rsi,%rdx,4),%rdx
  nopl   0x0(%rax)
L91:
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  add    $0x6,%ecx
  add    $0x18,%rdx
  cvtss2sd -0x14(%rdx),%xmm2
  cvtss2sd -0x18(%rdx),%xmm1
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x10(%rdx),%xmm2
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rdx),%xmm2
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x8(%rdx),%xmm2
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rdx),%xmm2
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %ecx,%eax
  jg     L91
  ret
```

assistant: ```c
double stdlib_strided_dssumors(const int64_t N, const float *X, const int64_t stride) {
  double sum;
  int64_t ix;
  int64_t m;
  int64_t i;
  sum = 0.0;
  if (N <= 0) {
    return sum;
  }
  if (N == 1 || stride == 0) {
    return X[0];
  }
  if (stride == 1) {
    m = N % 6;
    if (m > 0) {
      for (i = 0; i < m; i++) {
        sum += (double)X[i];
      }
    }
    if (N < 6) {
      return sum;
    }
    for (i = m; i < N; i += 6) {
      sum += (double)X[i] + (double)X[i + 1] + (double)X[i + 2] + (double)X[i + 3] + (double)X[i + 4] + (double)X[i + 5];
    }
    return sum;
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    sum += (double)X[ix];
    ix += stride;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<HO_deriv_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  D45(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   D69(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  D29(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D44(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   D69(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  D61(%rip),%xmm1
  movapd %xmm0,%xmm3
  divsd  %xmm1,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm4
  mulsd  -0x28(%rbp),%xmm4
  movsd  %xmm4,-0x28(%rbp)
  movsd  D42(%rip),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D45
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D69
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D29
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D44
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D61
datatype: f64
name: extract_symbolic_data
arguments: tag: D42
datatype: byte[8]

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x40]}

tool: {"D69": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D29": [0x5f,0xfa,0x11,0x70,0x38,0x09,0xe8,0x3f]}

tool: {"D44": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xf6,0x3f]}

tool: D61: 2

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0xf4,0x3f]}

assistant: ```c
double HO_deriv_2(const double a, const double x) {
  double retval = -(a * x * x - 0.5e1 / 0.2e1) * pow(0.3141592654e1, -0.1e1 / 0.4e1) * sqrt(0.2e1) * x * exp(-a * x * x / 0.2e1) * pow(a, 0.5e1 / 0.4e1);
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<HO_deriv_2>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm0,%xmm4
  mulsd  %xmm1,%xmm4
  movapd %xmm4,%xmm2
  movsd  %xmm1,0x18(%rsp)
  mulsd  %xmm1,%xmm2
  movsd  %xmm2,0x10(%rsp)
  movapd %xmm2,%xmm3
  xorpd  D20(%rip),%xmm3
  movapd %xmm3,%xmm0
  mulsd  D23(%rip),%xmm0
  call   <exp@plt>
  movq   %xmm0,%rbx
  movsd  D44(%rip),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  0x10(%rsp),%xmm0
  subsd  D14(%rip),%xmm0
  xorpd  D20(%rip),%xmm0
  mulsd  D47(%rip),%xmm0
  mulsd  D67(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  movq   %rbx,%xmm6
  mulsd  %xmm6,%xmm0
  mulsd  %xmm1,%xmm0
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D20
data_type: byte[16]
name: disassemble_data
arguments: label: D23
data_type: byte[8]
name: disassemble_data
arguments: label: D44
data_type: byte[8]
name: disassemble_data
arguments: label: D14
data_type: byte[8]
name: disassemble_data
arguments: label: D47
data_type: byte[8]
name: disassemble_data
arguments: label: D67
data_type: byte[8]

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0xf4,0x3f]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x40]}

tool: {"D47": [0x5f,0xfa,0x11,0x70,0x38,0x09,0xe8,0x3f]}

tool: {"D67": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xf6,0x3f]}

assistant: ```c
double HO_deriv_2(const double a, const double x) {
  double retval = -(a * x * x - 0.5e1 / 0.2e1) * pow(0.3141592654e1, -0.1e1 / 0.4e1) * sqrt(0.2e1) * x * exp(-a * x * x / 0.2e1) * pow(a, 0.5e1 / 0.4e1);
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HO_deriv_2>:
  endbr64
  movapd %xmm0,%xmm2
  sub    $0x28,%rsp
  movq   D3(%rip),%xmm5
  mulsd  %xmm1,%xmm2
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  mulsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  xorpd  %xmm5,%xmm0
  mulsd  D2(%rip),%xmm0
  call   <exp@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  D49(%rip),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm4,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  subsd  D9(%rip),%xmm2
  movq   D3(%rip),%xmm5
  movapd %xmm0,%xmm1
  movsd  0x10(%rsp),%xmm3
  movsd  D63(%rip),%xmm0
  xorpd  %xmm5,%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  D15(%rip),%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x28,%rsp
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: byte[8]
name: read_data
arguments: data_label: D2
type_infered: byte[8]
name: read_data
arguments: data_label: D49
type_infered: byte[8]
name: read_data
arguments: data_label: D9
type_infered: byte[8]
name: read_data
arguments: data_label: D63
type_infered: byte[8]
name: read_data
arguments: data_label: D15
type_infered: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0xf4,0x3f]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x40]}

tool: {"D63": [0x5f,0xfa,0x11,0x70,0x38,0x09,0xe8,0x3f]}

tool: {"D15": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xf6,0x3f]}

assistant: ```c
double HO_deriv_2(const double a, const double x) {
  double retval = -(a * x * x - 0.5e1 / 0.2e1) * pow(0.3141592654e1, -0.1e1 / 0.4e1) * sqrt(0.2e1) * x * exp(-a * x * x / 0.2e1) * pow(a, 0.5e1 / 0.4e1);
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HO_deriv_2>:
  endbr64
  movapd %xmm0,%xmm2
  sub    $0x28,%rsp
  movq   D0(%rip),%xmm5
  mulsd  %xmm1,%xmm2
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  mulsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  xorpd  %xmm5,%xmm0
  mulsd  D20(%rip),%xmm0
  call   <exp@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  D4(%rip),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm4,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  subsd  D65(%rip),%xmm2
  movq   D0(%rip),%xmm5
  movapd %xmm0,%xmm1
  movsd  0x10(%rsp),%xmm3
  movsd  D58(%rip),%xmm0
  xorpd  %xmm5,%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  D15(%rip),%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x28,%rsp
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: byte[8]
name: disassemble_data
arguments: tag: D20
type: byte[8]
name: disassemble_data
arguments: tag: D4
type: byte[8]
name: disassemble_data
arguments: tag: D65
type: byte[8]
name: disassemble_data
arguments: tag: D58
type: byte[8]
name: disassemble_data
arguments: tag: D15
type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf4,0x3f]}

tool: {"D65": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x40]}

tool: {"D58": [0x5f,0xfa,0x11,0x70,0x38,0x09,0xe8,0x3f]}

tool: {"D15": [0xcd,0x3b,0x7f,0x66,0x9e,0xa0,0xf6,0x3f]}

assistant: ```c
double HO_deriv_2(const double a, const double x) {
  double retval = -(a * x * x - 0.5e1 / 0.2e1) * pow(0.3141592654e1, -0.1e1 / 0.4e1) * sqrt(0.2e1) * x * exp(-a * x * x / 0.2e1) * pow(a, 0.5e1 / 0.4e1);
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L50
L3:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L50:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L45
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x28(%rbp)
  ja     L3
L45:
  cmpq   $0x0,-0x28(%rbp)
  je     L44
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L44
L48:
  addq   $0x1,-0x8(%rbp)
L44:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t Strlcpy(char *dest, const char *src, size_t size) {
  size_t i;
  for (i = 0; src[i] && i + 1 < size; i++)
    dest[i] = src[i];
  if (size > 0)
    dest[i] = '\0';
  while (src[i])
    i++;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Strlcpy>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L17
  cmp    $0x1,%rdx
  jbe    L107
  mov    $0x1,%eax
  jmp    L20
L56:
  mov    %r8,%rax
L20:
  mov    %cl,-0x1(%rdi,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L87
  lea    0x1(%rax),%r8
  cmp    %r8,%rdx
  jne    L56
L87:
  movb   $0x0,(%rdi,%rax,1)
  cmpb   $0x0,(%rsi,%rax,1)
  je     L55
L13:
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L13
  ret
L92:
  mov    $0x0,%eax
  jmp    L87
L102:
  mov    $0x0,%eax
  jmp    L87
L107:
  test   %rdx,%rdx
  jne    L92
  mov    %rdx,%rax
  jmp    L13
L17:
  test   %rdx,%rdx
  jne    L102
  mov    %rdx,%rax
L55:
  ret
```

assistant: ```c
size_t Strlcpy(char *dest, const char *src, size_t size) {
  size_t i;
  for (i = 0; src[i] && i + 1 < size; i++)
    dest[i] = src[i];
  if (size > 0)
    dest[i] = '\0';
  while (src[i])
    i++;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Strlcpy>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L33
  cmp    $0x1,%rdx
  jbe    L90
  mov    $0x1,%eax
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L66:
  lea    0x1(%rax),%r8
  cmp    %rdx,%r8
  je     L88
  mov    %r8,%rax
L7:
  mov    %cl,-0x1(%rdi,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  lea    (%rsi,%rax,1),%r9
  test   %cl,%cl
  jne    L66
L88:
  movb   $0x0,(%rdi,%rax,1)
  cmpb   $0x0,(%r9)
  je     L73
  cs nopw 0x0(%rax,%rax,1)
L50:
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L50
  ret
L33:
  test   %rdx,%rdx
  jne    L13
  xor    %eax,%eax
L73:
  ret
L90:
  test   %rdx,%rdx
  jne    L13
  xor    %eax,%eax
  jmp    L50
L13:
  mov    %rsi,%r9
  xor    %eax,%eax
  jmp    L88
```

assistant: ```c
size_t Strlcpy(char *dest, const char *src, size_t size) {
  size_t i;
  for (i = 0; src[i] && i + 1 < size; i++)
    dest[i] = src[i];
  if (size > 0)
    dest[i] = '\0';
  while (src[i])
    i++;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Strlcpy>:
  endbr64
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L38
  cmp    $0x1,%rdx
  jbe    L51
  mov    $0x1,%eax
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L30:
  lea    0x1(%rax),%r8
  cmp    %rdx,%r8
  je     L12
  mov    %r8,%rax
L75:
  mov    %cl,-0x1(%rdi,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  lea    (%rsi,%rax,1),%r9
  test   %cl,%cl
  jne    L30
L12:
  movb   $0x0,(%rdi,%rax,1)
  cmpb   $0x0,(%r9)
  je     L34
  cs nopw 0x0(%rax,%rax,1)
L89:
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L89
  ret
L38:
  test   %rdx,%rdx
  jne    L92
  xor    %eax,%eax
L34:
  ret
L51:
  test   %rdx,%rdx
  jne    L92
  xor    %eax,%eax
  jmp    L89
L92:
  mov    %rsi,%r9
  xor    %eax,%eax
  jmp    L12
```

assistant: ```c
size_t Strlcpy(char *dest, const char *src, size_t size) {
  size_t i;
  for (i = 0; src[i] && i + 1 < size; i++)
    dest[i] = src[i];
  if (size > 0)
    dest[i] = '\0';
  while (src[i])
    i++;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x1c(%rbp),%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L16:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movd   %eax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x3,-0x4(%rbp)
  jle    L16
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
datatype: string
name: parse_data
arguments: tag: D9
datatype: string

tool: D12: The score of NO.%d are:


tool: D9: %5.2f 

assistant: ```c
void search(float (*p)[4], int n) {
  int i;
  printf("The score of NO.%d are:\n", n);
  for (i = 0; i < 4; i++) {
    printf("%5.2f ", *(*(p + n) + i));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<search>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  lea    D5(%rip),%rdi
  call   <printf@plt>
  movslq %ebx,%rsi
  shl    $0x4,%rsi
  lea    0x0(%rbp,%rsi,1),%rbx
  lea    0x10(%rbp,%rsi,1),%r12
  lea    D13(%rip),%rbp
L6:
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D13
datatype: string

tool: D5: The score of NO.%d are:


tool: D13: %5.2f 

assistant: ```c
void search(float (*p)[4], int n) {
  int i;
  printf("The score of NO.%d are:\n", n);
  for (i = 0; i < 4; i++) {
    printf("%5.2f ", *(*(p + n) + i));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<search>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %r12
  cvtsi2ss %esi,%xmm0
  push   %rbp
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  call   <printf@plt>
  movslq %ebx,%rsi
  shl    $0x4,%rsi
  lea    0x0(%rbp,%rsi,1),%rbx
  lea    0x10(%rbp,%rsi,1),%r12
  lea    D10(%rip),%rbp
L7:
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D10
data_type: string

tool: D0: The score of NO.%d are:


tool: D10: %5.2f 

assistant: ```c
void search(float (*p)[4], int n) {
  int i;
  printf("The score of NO.%d are:\n", n);
  for (i = 0; i < 4; i++) {
    printf("%5.2f ", *(*(p + n) + i));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<search>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %r12
  cvtsi2ss %esi,%xmm0
  push   %rbp
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  call   <printf@plt>
  movslq %ebx,%rsi
  shl    $0x4,%rsi
  lea    0x0(%rbp,%rsi,1),%rbx
  lea    0x10(%rbp,%rsi,1),%r12
  lea    D16(%rip),%rbp
L7:
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D16
type_infered: string

tool: D0: The score of NO.%d are:


tool: D16: %5.2f 

assistant: ```c
void search(float (*p)[4], int n) {
  int i;
  printf("The score of NO.%d are:\n", n);
  for (i = 0; i < 4; i++) {
    printf("%5.2f ", *(*(p + n) + i));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<utf8casecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L30:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x40,-0x12(%rbp)
  jbe    L94
  cmpb   $0x5a,-0x12(%rbp)
  ja     L94
  orb    $0x20,-0x12(%rbp)
L94:
  cmpb   $0x40,-0x11(%rbp)
  jbe    L106
  cmpb   $0x5a,-0x11(%rbp)
  ja     L106
  orb    $0x20,-0x11(%rbp)
L106:
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  jae    L109
  mov    $0xffffffff,%eax
  jmp    L67
L109:
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  jbe    L85
  mov    $0x1,%eax
  jmp    L67
L85:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    $0x0,%eax
L67:
  pop    %rbp
  ret
```

assistant: ```c
int utf8casecmp(const void *src1, const void *src2) {
  const unsigned char *s1 = (const unsigned char *)src1;
  const unsigned char *s2 = (const unsigned char *)src2;
  while (('\0' != *s1) || ('\0' != *s2)) {
    unsigned char a = *s1;
    unsigned char b = *s2;
    if (('A' <= a) && ('Z' >= a)) {
      a |= 0x20;
    }
    if (('A' <= b) && ('Z' >= b)) {
      b |= 0x20;
    }
    if (a < b) {
      return -1;
    } else if (a > b) {
      return 1;
    }
    s1++;
    s2++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<utf8casecmp>:
  endbr64
  jmp    L77
L61:
  movzbl (%rsi),%edx
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L38
  or     $0x20,%eax
L38:
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L37
L30:
  or     $0x20,%edx
L37:
  cmp    %al,%dl
  ja     L62
  jb     L58
  add    $0x1,%rdi
  add    $0x1,%rsi
L77:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L61
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L28
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  jbe    L30
  mov    $0xffffffff,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
L62:
  mov    $0xffffffff,%eax
  ret
L58:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int utf8casecmp(const void *src1, const void *src2) {
  const unsigned char *s1 = (const unsigned char *)src1;
  const unsigned char *s2 = (const unsigned char *)src2;
  while (('\0' != *s1) || ('\0' != *s2)) {
    unsigned char a = *s1;
    unsigned char b = *s2;
    if (('A' <= a) && ('Z' >= a)) {
      a |= 0x20;
    }
    if (('A' <= b) && ('Z' >= b)) {
      b |= 0x20;
    }
    if (a < b) {
      return -1;
    } else if (a > b) {
      return 1;
    }
    s1++;
    s2++;
  }
  return 0;
}
```