user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  jle    L24
  mov    $0x0,%esi
  mov    $0x0,%eax
  jmp    L127
L12:
  lea    0x1(%rax),%edi
  movslq %edi,%rdx
  movzbl 0xe(%rsp,%rdx,1),%edx
  cmp    $0x56,%dl
  je     L120
  cmp    $0x58,%dl
  je     L79
  lea    0x1(%rax),%edx
  movslq %edx,%rdi
  cmpb   $0x4c,0xe(%rsp,%rdi,1)
  je     L151
  lea    0x1(%rax),%edx
  movslq %edx,%rdi
  cmpb   $0x43,0xe(%rsp,%rdi,1)
  jne    L221
  add    $0x63,%esi
  mov    %edx,%eax
  jmp    L221
L120:
  add    $0x4,%esi
  mov    %edi,%eax
  jmp    L201
L79:
  add    $0x9,%esi
  mov    %edi,%eax
  jmp    L124
L151:
  add    $0x30,%esi
  mov    %edx,%eax
  jmp    L221
L132:
  lea    -0x1(%rcx),%eax
  cltq
  cmpb   $0x49,0xe(%rsp,%rax,1)
  je     L38
L186:
  cmp    $0xff,%esi
  jle    L149
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L116
L141:
  mov    $0x0,%esi
L38:
  lea    -0x2(%rcx),%eax
  cltq
  cmpb   $0x49,0xe(%rsp,%rax,1)
  jne    L186
  lea    -0x3(%rcx),%eax
  cltq
  cmpb   $0x49,0xe(%rsp,%rax,1)
  je     L102
  add    $0x2,%esi
  jmp    L186
L102:
  add    $0x3,%esi
  jmp    L186
L148:
  cmp    $0x58,%dl
  jne    L5
  add    $0xa,%esi
L124:
  movslq %eax,%rdx
  movzbl 0xe(%rsp,%rdx,1),%edx
  jmp    L139
L24:
  lea    -0x1(%rax),%eax
  cltq
  cmpb   $0x49,0xe(%rsp,%rax,1)
  je     L141
  mov    $0x0,%esi
L149:
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L116:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L176
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  movslq %eax,%rdx
  movzbl 0xe(%rsp,%rdx,1),%edx
  cmp    $0x4c,%dl
  jne    L139
  add    $0x32,%esi
L221:
  add    $0x1,%eax
  cmp    %eax,%ecx
  jle    L132
L127:
  movslq %eax,%rdx
  movzbl 0xe(%rsp,%rdx,1),%edx
  cmp    $0x49,%dl
  je     L12
  cmp    $0x56,%dl
  jne    L148
  add    $0x5,%esi
L201:
  movslq %eax,%rdx
  movzbl 0xe(%rsp,%rdx,1),%edx
L139:
  cmp    $0x43,%dl
  jne    L221
  add    $0x64,%esi
  jmp    L221
L176:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D36
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string
name: retrieve_data
arguments: tag: D31
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: string

tool: D36: Strange letters number:

tool: D25: %s

tool: D31: Sorry bro, it's toooo big

tool: D13: Normal number with digits: %d

assistant: ```c
int main() {
  char a[10];
  int n, l, sum = 0;
  printf("Strange letters number:");
  scanf("%s", a);
  l = strlen(a);
  for (n = 0; n < l; n++) {
    if (a[n] == 'I' && a[n + 1] == 'V') {
      sum = sum + 4;
      n++;
    } else if (a[n] == 'V')
      sum = sum + 5;
    if (a[n] == 'I' && a[n + 1] == 'X') {
      sum = sum + 9;
      n++;
    } else if (a[n] == 'X')
      sum = sum + 10;
    if (a[n] == 'I' && a[n + 1] == 'L') {
      sum = sum + 48;
      n++;
    } else if (a[n] == 'L')
      sum = sum + 50;
    if (a[n] == 'I' && a[n + 1] == 'C') {
      sum = sum + 99;
      n++;
    } else if (a[n] == 'C')
      sum = sum + 100;
  }
  if (a[l - 1] == 'I' && a[l - 2] == 'I' && a[l - 3] == 'I') {
    sum = sum + 3;
  } else if (a[l - 1] == 'I' && a[l - 2] == 'I')
    sum = sum + 2;
  if (sum < 256) {
    printf("Normal number with digits: %d", sum);
  } else
    printf("Sorry bro, it's toooo big");
  return 0;
}
```