ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<slip_esc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xc0,(%rax)
  jmp    L26
L22:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  cmp    $0xc0,%eax
  je     L68
  cmp    $0xdb,%eax
  je     L18
  jmp    L35
L68:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xdb,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xdc,(%rax)
  jmp    L26
L18:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xdb,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xdd,(%rax)
  jmp    L26
L35:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  nop
L26:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jg     L22
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xc0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int slip_esc(unsigned char *s, unsigned char *d, int len) {
  unsigned char *ptr = d;
  unsigned char c;
  *ptr++ = 0300;
  while (len-- > 0) {
    switch (c = *s++) {
    case 0300:
      *ptr++ = 0333;
      *ptr++ = 0334;
      break;
    case 0333:
      *ptr++ = 0333;
      *ptr++ = 0335;
      break;
    default:
      *ptr++ = c;
      break;
    }
  }
  *ptr++ = 0300;
  return (ptr - d);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<slip_esc>:
  endbr64
  lea    0x1(%rsi),%rax
  movb   $0xc0,(%rsi)
  test   %edx,%edx
  jle    L68
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%rcx
  jmp    L38
L67:
  movb   $0xdb,(%rax)
  movb   $0xdc,0x1(%rax)
  lea    0x2(%rax),%rax
L62:
  cmp    %rdi,%rcx
  je     L68
L38:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  cmp    $0xc0,%dl
  je     L67
  cmp    $0xdb,%dl
  je     L35
  mov    %dl,(%rax)
  lea    0x1(%rax),%rax
  jmp    L62
L35:
  movb   $0xdb,(%rax)
  movb   $0xdd,0x1(%rax)
  lea    0x2(%rax),%rax
  jmp    L62
L68:
  movb   $0xc0,(%rax)
  add    $0x1,%rax
  sub    %esi,%eax
  ret
```

assistant: ```c
int slip_esc(unsigned char *s, unsigned char *d, int len) {
  unsigned char *ptr = d;
  unsigned char c;
  *ptr++ = 0300;
  while (len-- > 0) {
    switch (c = *s++) {
    case 0300:
      *ptr++ = 0333;
      *ptr++ = 0334;
      break;
    case 0333:
      *ptr++ = 0333;
      *ptr++ = 0335;
      break;
    default:
      *ptr++ = c;
      break;
    }
  }
  *ptr++ = 0300;
  return (ptr - d);
}
```
user: Translate the below assembly code into C programming language:

```asm
<slip_esc>:
  endbr64
  movb   $0xc0,(%rsi)
  lea    0x1(%rsi),%rax
  test   %edx,%edx
  jle    L9
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%rcx
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %dl,(%rax)
  add    $0x1,%rax
L36:
  cmp    %rdi,%rcx
  je     L9
L22:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  cmp    $0xc0,%dl
  je     L16
  cmp    $0xdb,%dl
  jne    L39
  mov    $0xffffdddb,%edx
  add    $0x2,%rax
  mov    %dx,-0x2(%rax)
  cmp    %rdi,%rcx
  jne    L22
L9:
  movb   $0xc0,(%rax)
  add    $0x1,%rax
  sub    %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffffdcdb,%r8d
  add    $0x2,%rax
  mov    %r8w,-0x2(%rax)
  jmp    L36
```

assistant: ```c
int slip_esc(unsigned char *s, unsigned char *d, int len) {
  unsigned char *ptr = d;
  unsigned char c;
  *ptr++ = 0300;
  while (len-- > 0) {
    switch (c = *s++) {
    case 0300:
      *ptr++ = 0333;
      *ptr++ = 0334;
      break;
    case 0333:
      *ptr++ = 0333;
      *ptr++ = 0335;
      break;
    default:
      *ptr++ = c;
      break;
    }
  }
  *ptr++ = 0300;
  return (ptr - d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slip_esc>:
  endbr64
  movb   $0xc0,(%rsi)
  lea    0x1(%rsi),%rax
  test   %edx,%edx
  jle    L61
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%rcx
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %dl,(%rax)
  add    $0x1,%rax
L8:
  cmp    %rcx,%rdi
  je     L61
L51:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  cmp    $0xc0,%dl
  je     L63
  cmp    $0xdb,%dl
  jne    L46
  mov    $0xffffdddb,%edx
  add    $0x2,%rax
  mov    %dx,-0x2(%rax)
  cmp    %rcx,%rdi
  jne    L51
L61:
  movb   $0xc0,(%rax)
  add    $0x1,%rax
  sub    %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  mov    $0xffffdcdb,%r8d
  add    $0x2,%rax
  mov    %r8w,-0x2(%rax)
  jmp    L8
```

assistant: ```c
int slip_esc(unsigned char *s, unsigned char *d, int len) {
  unsigned char *ptr = d;
  unsigned char c;
  *ptr++ = 0300;
  while (len-- > 0) {
    switch (c = *s++) {
    case 0300:
      *ptr++ = 0333;
      *ptr++ = 0334;
      break;
    case 0333:
      *ptr++ = 0333;
      *ptr++ = 0335;
      break;
    default:
      *ptr++ = c;
      break;
    }
  }
  *ptr++ = 0300;
  return (ptr - d);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    $0x1,%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int x = 0;
  return 1 % x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  mov    $0x0,%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  ret
```

assistant: ```c
int main(void) {
  int x = 0;
  return 1 % x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  ud2
```

assistant: ```c
int main(void) {
  int x = 0;
  return 1 % x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  ud2
```

assistant: ```c
int main(void) {
  int x = 0;
  return 1 % x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Phi_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x2a,-0xc(%rbp)
  jmp    L3
L18:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L3:
  cmpl   $0x0,-0xc(%rbp)
  jg     L18
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double Phi_1(double x) {
  double s;
  int n;
  s = x;
  for (n = 42; n >= 1; n--)
    s = x + n / s;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Phi_1>:
  endbr64
  movapd %xmm0,%xmm2
  mov    $0x2a,%eax
L7:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  sub    $0x1,%eax
  jne    L7
  ret
```

assistant: ```c
double Phi_1(double x) {
  double s;
  int n;
  s = x;
  for (n = 42; n >= 1; n--)
    s = x + n / s;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Phi_1>:
  endbr64
  movapd %xmm0,%xmm2
  mov    $0x2a,%eax
  nopl   (%rax)
L6:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  sub    $0x1,%eax
  jne    L6
  ret
```

assistant: ```c
double Phi_1(double x) {
  double s;
  int n;
  s = x;
  for (n = 42; n >= 1; n--)
    s = x + n / s;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Phi_1>:
  endbr64
  movapd %xmm0,%xmm2
  mov    $0x2a,%eax
  nopl   (%rax)
L2:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  sub    $0x1,%eax
  jne    L2
  ret
```

assistant: ```c
double Phi_1(double x) {
  double s;
  int n;
  s = x;
  for (n = 42; n >= 1; n--)
    s = x + n / s;
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sortArrayByParity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L12
L10:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L6
  mov    -0x28(%rbp),%rax
  mov    -0x34(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x28(%rbp)
  jmp    L3
L6:
  mov    -0x30(%rbp),%rax
  mov    -0x34(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x30(%rbp)
L3:
  addl   $0x1,-0x38(%rbp)
L12:
  mov    -0x38(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L10
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L2:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *sortArrayByParity(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  size_t mallocSize = sizeof(int) * (*returnSize);
  int *retval = (int *)malloc(mallocSize);
  bzero((void *)retval, mallocSize);
  int *rp = retval;
  int *oddList = (int *)malloc(mallocSize);
  bzero((void *)oddList, mallocSize);
  int *op = oddList;
  for (int i = 0; i < ASize; i++) {
    int n = A[i];
    if ((n & 0x00000001)) {
      *op = n;
      op++;
    } else {
      *rp = n;
      rp++;
    }
  }
  size_t copySize = (op - oddList) * sizeof(int);
  if (copySize > 0) {
    memcpy((void *)rp, (void *)oddList, copySize);
  }
  free(oddList);
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sortArrayByParity>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %esi,(%rdx)
  movslq %esi,%r12
  shl    $0x2,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <bzero@plt>
  test   %r13d,%r13d
  jle    L32
  mov    %r14,%rax
  lea    -0x1(%r13),%edx
  lea    0x4(%r14,%rdx,4),%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  jmp    L63
L35:
  mov    %ecx,(%rdi)
  add    $0x4,%rdi
L40:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L12
L63:
  mov    (%rax),%ecx
  test   $0x1,%cl
  je     L35
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  jmp    L40
L12:
  sub    %rbx,%rdx
  jne    L7
L32:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    %rbx,%rsi
  call   <memcpy@plt>
  jmp    L32
```

assistant: ```c
int *sortArrayByParity(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  size_t mallocSize = sizeof(int) * (*returnSize);
  int *retval = (int *)malloc(mallocSize);
  bzero((void *)retval, mallocSize);
  int *rp = retval;
  int *oddList = (int *)malloc(mallocSize);
  bzero((void *)oddList, mallocSize);
  int *op = oddList;
  for (int i = 0; i < ASize; i++) {
    int n = A[i];
    if ((n & 0x00000001)) {
      *op = n;
      op++;
    } else {
      *rp = n;
      rp++;
    }
  }
  size_t copySize = (op - oddList) * sizeof(int);
  if (copySize > 0) {
    memcpy((void *)rp, (void *)oddList, copySize);
  }
  free(oddList);
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sortArrayByParity>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %r12,%r14
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,(%rdx)
  shl    $0x2,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <bzero@plt>
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <bzero@plt>
  test   %r14d,%r14d
  jle    L27
  lea    -0x1(%r14),%edx
  mov    %rbx,%rax
  mov    %r13,%rdi
  lea    0x4(%rbx,%rdx,4),%rsi
  mov    %rbp,%rdx
  jmp    L41
  nopl   0x0(%rax)
L40:
  add    $0x4,%rax
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    %rsi,%rax
  je     L69
L41:
  mov    (%rax),%ecx
  test   $0x1,%cl
  jne    L40
  add    $0x4,%rax
  mov    %ecx,(%rdi)
  add    $0x4,%rdi
  cmp    %rsi,%rax
  jne    L41
L69:
  sub    %rbp,%rdx
  jne    L38
L27:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    %rbp,%rsi
  call   <memcpy@plt>
  jmp    L27
```

assistant: ```c
int *sortArrayByParity(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  size_t mallocSize = sizeof(int) * (*returnSize);
  int *retval = (int *)malloc(mallocSize);
  bzero((void *)retval, mallocSize);
  int *rp = retval;
  int *oddList = (int *)malloc(mallocSize);
  bzero((void *)oddList, mallocSize);
  int *op = oddList;
  for (int i = 0; i < ASize; i++) {
    int n = A[i];
    if ((n & 0x00000001)) {
      *op = n;
      op++;
    } else {
      *rp = n;
      rp++;
    }
  }
  size_t copySize = (op - oddList) * sizeof(int);
  if (copySize > 0) {
    memcpy((void *)rp, (void *)oddList, copySize);
  }
  free(oddList);
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sortArrayByParity>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %r12,%r14
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,(%rdx)
  shl    $0x2,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <bzero@plt>
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <bzero@plt>
  test   %r14d,%r14d
  jle    L68
  lea    -0x1(%r14),%edx
  mov    %rbx,%rax
  mov    %r13,%rdi
  lea    0x4(%rbx,%rdx,4),%rsi
  mov    %rbp,%rdx
  jmp    L58
  nopl   0x0(%rax)
L43:
  add    $0x4,%rax
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    %rsi,%rax
  je     L60
L58:
  mov    (%rax),%ecx
  test   $0x1,%cl
  jne    L43
  add    $0x4,%rax
  mov    %ecx,(%rdi)
  add    $0x4,%rdi
  cmp    %rsi,%rax
  jne    L58
L60:
  sub    %rbp,%rdx
  jne    L34
L68:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    %rbp,%rsi
  call   <memcpy@plt>
  jmp    L68
```

assistant: ```c
int *sortArrayByParity(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  size_t mallocSize = sizeof(int) * (*returnSize);
  int *retval = (int *)malloc(mallocSize);
  bzero((void *)retval, mallocSize);
  int *rp = retval;
  int *oddList = (int *)malloc(mallocSize);
  bzero((void *)oddList, mallocSize);
  int *op = oddList;
  for (int i = 0; i < ASize; i++) {
    int n = A[i];
    if ((n & 0x00000001)) {
      *op = n;
      op++;
    } else {
      *rp = n;
      rp++;
    }
  }
  size_t copySize = (op - oddList) * sizeof(int);
  if (copySize > 0) {
    memcpy((void *)rp, (void *)oddList, copySize);
  }
  free(oddList);
  return retval;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_canon_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x34(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string
name: disassemble_data
arguments: tag: D11
data_type: string

tool: D3: Regular read in canonical mode

tool: D11: read(%d): %s

assistant: ```c
void read_canon_mode(void) {
  char buf[32] = {0};
  int r;
  printf("Regular read in canonical mode\n");
  r = read(0, buf, 32);
  printf("read(%d): %s", r, buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_canon_mode>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    $0x20,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D2: Regular read in canonical mode

tool: D1: read(%d): %s

assistant: ```c
void read_canon_mode(void) {
  char buf[32] = {0};
  int r;
  printf("Regular read in canonical mode\n");
  r = read(0, buf, 32);
  printf("read(%d): %s", r, buf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_canon_mode>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D14(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  xor    %edi,%edi
  mov    $0x20,%edx
  mov    %r12,%rsi
  call   <read@plt>
  mov    %r12,%rdx
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D16
type_infered: string

tool: D14: Regular read in canonical mode

tool: D16: read(%d): %s

assistant: ```c
void read_canon_mode(void) {
  char buf[32] = {0};
  int r;
  printf("Regular read in canonical mode\n");
  r = read(0, buf, 32);
  printf("read(%d): %s", r, buf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_canon_mode>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D12(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  xor    %edi,%edi
  mov    $0x20,%edx
  mov    %r12,%rsi
  call   <read@plt>
  mov    %r12,%rdx
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D0
type: string

tool: D12: Regular read in canonical mode

tool: D0: read(%d): %s

assistant: ```c
void read_canon_mode(void) {
  char buf[32] = {0};
  int r;
  printf("Regular read in canonical mode\n");
  r = read(0, buf, 32);
  printf("read(%d): %s", r, buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uint_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L25
  mov    $0x0,%eax
  jmp    L0
L25:
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jg     L25
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L41
  mov    $0x0,%eax
  jmp    L0
L41:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string

tool: D9: %d

assistant: ```c
char *uint_to_str(int i) {
  int tmp = i;
  int dig = 0;
  char *ret;
  if (i < 0)
    return NULL;
  do {
    dig++;
    tmp = tmp / 10;
  } while (tmp > 0);
  if ((ret = (char *)calloc(dig + 1, sizeof(char))) == NULL) {
    return NULL;
  }
  sprintf(ret, "%d", i);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uint_to_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L38
  mov    %edi,%ebx
  mov    %edi,%edx
  mov    $0x0,%ecx
L14:
  mov    %ecx,%edi
  add    $0x1,%ecx
  mov    %edx,%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  cmp    $0x9,%esi
  jg     L14
  add    $0x2,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L15
  mov    %rax,%rbp
  mov    %ebx,%edx
  lea    D3(%rip),%rsi
  call   <sprintf@plt>
L15:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    $0x0,%ebp
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D3: %d

assistant: ```c
char *uint_to_str(int i) {
  int tmp = i;
  int dig = 0;
  char *ret;
  if (i < 0)
    return NULL;
  do {
    dig++;
    tmp = tmp / 10;
  } while (tmp > 0);
  if ((ret = (char *)calloc(dig + 1, sizeof(char))) == NULL) {
    return NULL;
  }
  sprintf(ret, "%d", i);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uint_to_str>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L16
  mov    %edi,%r13d
  mov    %edi,%eax
  xor    %ecx,%ecx
  mov    $0xcccccccd,%r8d
  nopl   (%rax)
L26:
  mov    %eax,%eax
  mov    %ecx,%edi
  add    $0x1,%ecx
  mov    %rax,%rsi
  imul   %r8,%rax
  shr    $0x23,%rax
  cmp    $0x9,%esi
  jg     L26
  add    $0x2,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  mov    %r13d,%edx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
char *uint_to_str(int i) {
  int tmp = i;
  int dig = 0;
  char *ret;
  if (i < 0)
    return NULL;
  do {
    dig++;
    tmp = tmp / 10;
  } while (tmp > 0);
  if ((ret = (char *)calloc(dig + 1, sizeof(char))) == NULL) {
    return NULL;
  }
  sprintf(ret, "%d", i);
  return ret;
}
```