ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<exponentialSearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L22
L12:
  movl   $0x1,-0x8(%rbp)
  jmp    L57
L4:
  shll   -0x8(%rbp)
L57:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L53
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L4
L53:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L51
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L58
L51:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L58:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binarySearch@plt>
L22:
  leave
  ret
```

assistant: ```c
int exponentialSearch(int arr[], int size, int key) {
  if (arr[0] == key)
    return 0;
  int i = 1;
  while (i < size && arr[i] <= key)
    i = i * 2;
  int x;
  if (i > size)
    x = size;
  else
    x = i;
  return binarySearch(arr, i / 2, x, key);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<exponentialSearch>:
  endbr64
  mov    $0x0,%eax
  cmp    %edx,(%rdi)
  je     L32
  sub    $0x8,%rsp
  mov    %edx,%ecx
  mov    $0x1,%eax
  cmp    $0x1,%esi
  jle    L2
L17:
  movslq %eax,%r8
  cmp    %ecx,(%rdi,%r8,4)
  jg     L2
  add    %eax,%eax
  cmp    %eax,%esi
  jg     L17
L2:
  cmp    %eax,%esi
  mov    %esi,%edx
  cmovg  %eax,%edx
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  call   <binarySearch@plt>
  add    $0x8,%rsp
  ret
L32:
  ret
```

assistant: ```c
int exponentialSearch(int arr[], int size, int key) {
  if (arr[0] == key)
    return 0;
  int i = 1;
  while (i < size && arr[i] <= key)
    i = i * 2;
  int x;
  if (i > size)
    x = size;
  else
    x = i;
  return binarySearch(arr, i / 2, x, key);
}
```
user: Translate the below assembly code into C programming language:

```asm
<exponentialSearch>:
  endbr64
  mov    %esi,%r8d
  mov    %edx,%ecx
  cmp    %edx,(%rdi)
  je     L23
  mov    $0x1,%esi
  cmp    $0x1,%r8d
  jg     L18
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L44:
  lea    (%rsi,%rsi,1),%eax
  cmp    %eax,%r8d
  jle    L35
  mov    %eax,%esi
L18:
  movslq %esi,%rax
  cmp    %ecx,(%rdi,%rax,4)
  jle    L44
  mov    %esi,%eax
  sar    %esi
L35:
  cmp    %eax,%r8d
  cmovle %r8d,%eax
  mov    %eax,%edx
  jmp    1050 <binarySearch@plt>
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  ret
L45:
  xor    %esi,%esi
  mov    $0x1,%eax
  jmp    L35
```

assistant: ```c
int exponentialSearch(int arr[], int size, int key) {
  if (arr[0] == key)
    return 0;
  int i = 1;
  while (i < size && arr[i] <= key)
    i = i * 2;
  int x;
  if (i > size)
    x = size;
  else
    x = i;
  return binarySearch(arr, i / 2, x, key);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<exponentialSearch>:
  endbr64
  mov    %esi,%r8d
  mov    %edx,%ecx
  cmp    %edx,(%rdi)
  je     L13
  mov    $0x1,%esi
  cmp    $0x1,%r8d
  jg     L35
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L47:
  lea    (%rsi,%rsi,1),%eax
  cmp    %eax,%r8d
  jle    L42
  mov    %eax,%esi
L35:
  movslq %esi,%rax
  cmp    %ecx,(%rdi,%rax,4)
  jle    L47
  mov    %esi,%eax
  sar    %esi
L42:
  cmp    %eax,%r8d
  cmovle %r8d,%eax
  mov    %eax,%edx
  jmp    1050 <binarySearch@plt>
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  ret
L28:
  xor    %esi,%esi
  mov    $0x1,%eax
  jmp    L42
```

assistant: ```c
int exponentialSearch(int arr[], int size, int key) {
  if (arr[0] == key)
    return 0;
  int i = 1;
  while (i < size && arr[i] <= key)
    i = i * 2;
  int x;
  if (i > size)
    x = size;
  else
    x = i;
  return binarySearch(arr, i / 2, x, key);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L53
L18:
  movl   $0x0,-0x4(%rbp)
  jmp    L41
L55:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  jne    L22
  mov    -0xc(%rbp),%eax
  jmp    L27
L22:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L41:
  cmpl   $0x3,-0x4(%rbp)
  jle    L55
  addl   $0x1,-0x8(%rbp)
L53:
  cmpl   $0x3,-0x8(%rbp)
  jle    L18
  mov    $0xffffffff,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int find_zero(int arr[][4]) {
  int pos = 0;
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      if (arr[i][j] == 0)
        return pos;
      pos++;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_zero>:
  endbr64
  lea    0x40(%rdi),%rsi
  mov    $0x0,%eax
  jmp    L5
L11:
  add    $0x10,%rdi
  cmp    %rsi,%rdi
  je     L34
L5:
  lea    0x4(%rax),%ecx
  mov    %rdi,%rdx
L30:
  cmpl   $0x0,(%rdx)
  je     L41
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L30
  jmp    L11
L34:
  mov    $0xffffffff,%eax
L41:
  ret
```

assistant: ```c
int find_zero(int arr[][4]) {
  int pos = 0;
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      if (arr[i][j] == 0)
        return pos;
      pos++;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_zero>:
  endbr64
  lea    0x40(%rdi),%rsi
  xor    %eax,%eax
L26:
  lea    0x4(%rax),%ecx
  mov    %rdi,%rdx
L16:
  mov    (%rdx),%r8d
  test   %r8d,%r8d
  je     L6
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L16
  add    $0x10,%rdi
  cmp    %rsi,%rdi
  jne    L26
  mov    $0xffffffff,%eax
L6:
  ret
```

assistant: ```c
int find_zero(int arr[][4]) {
  int pos = 0;
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      if (arr[i][j] == 0)
        return pos;
      pos++;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_zero>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L131
  mov    0x4(%rdi),%eax
  test   %eax,%eax
  je     L109
  mov    0x8(%rdi),%eax
  test   %eax,%eax
  je     L142
  mov    0xc(%rdi),%eax
  test   %eax,%eax
  je     L125
  mov    0x10(%rdi),%eax
  test   %eax,%eax
  je     L191
  mov    0x14(%rdi),%eax
  test   %eax,%eax
  je     L72
  mov    0x18(%rdi),%eax
  test   %eax,%eax
  je     L118
  mov    0x1c(%rdi),%eax
  test   %eax,%eax
  je     L69
  mov    0x20(%rdi),%eax
  test   %eax,%eax
  je     L107
  mov    0x24(%rdi),%r11d
  test   %r11d,%r11d
  je     L77
  mov    0x28(%rdi),%r10d
  test   %r10d,%r10d
  je     L73
  mov    0x2c(%rdi),%r9d
  test   %r9d,%r9d
  je     L68
  mov    0x30(%rdi),%r8d
  test   %r8d,%r8d
  je     L27
  mov    0x34(%rdi),%esi
  mov    $0xc,%eax
  test   %esi,%esi
  je     L109
  mov    0x38(%rdi),%ecx
  mov    $0xc,%eax
  test   %ecx,%ecx
  je     L142
  mov    0x3c(%rdi),%edx
  mov    $0xffffffff,%eax
  test   %edx,%edx
  je     L45
L131:
  ret
L72:
  mov    $0x4,%eax
L109:
  add    $0x1,%eax
  ret
L118:
  mov    $0x4,%eax
L142:
  add    $0x2,%eax
  ret
L69:
  mov    $0x4,%eax
L125:
  add    $0x3,%eax
  ret
L45:
  mov    $0xc,%eax
  jmp    L125
L191:
  mov    $0x4,%eax
  ret
L107:
  mov    $0x8,%eax
  ret
L77:
  mov    $0x8,%eax
  jmp    L109
L73:
  mov    $0x8,%eax
  jmp    L142
L68:
  mov    $0x8,%eax
  jmp    L125
L27:
  mov    $0xc,%eax
  ret
```

assistant: ```c
int find_zero(int arr[][4]) {
  int pos = 0;
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      if (arr[i][j] == 0)
        return pos;
      pos++;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Camellia_cfb128_encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %rcx,0x8(%rsp)
  mov    %r8,%r13
  mov    %r9,%r15
  test   %rdi,%rdi
  je     L66
  test   %rsi,%rsi
  je     L66
  test   %r8,%r8
  setne  %al
  test   %r9,%r9
  setne  %dl
  and    %edx,%eax
  test   %rcx,%rcx
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
L7:
  call   <assert@plt>
  mov    (%r15),%ebp
  cmpl   $0x0,0x50(%rsp)
  jne    L101
  mov    %r14,%rax
  lea    (%rbx,%r14,1),%r14
  test   %rax,%rax
  jne    L120
L22:
  mov    %ebp,(%r15)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  mov    $0x0,%edi
  jmp    L7
L101:
  test   %r14,%r14
  je     L22
  add    %rbx,%r14
  jmp    L95
L55:
  add    $0x1,%rbx
  mov    %ebp,%eax
  add    %r13,%rax
  add    $0x1,%r12
  movzbl -0x1(%rbx),%edx
  xor    (%rax),%dl
  mov    %dl,-0x1(%r12)
  mov    %dl,(%rax)
  lea    0x1(%rbp),%eax
  mov    D5(%rip),%rsi
  mov    $0x0,%edx
  divl   (%rsi)
  mov    %edx,%ebp
  cmp    %r14,%rbx
  je     L22
L95:
  test   %ebp,%ebp
  jne    L55
  mov    0x8(%rsp),%rdx
  mov    %r13,%rsi
  mov    %r13,%rdi
  call   <Camellia_encrypt@plt>
  jmp    L55
L68:
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  mov    %ebp,%eax
  add    %r13,%rax
  add    $0x1,%r12
  mov    %edx,%ecx
  xor    (%rax),%cl
  mov    %cl,-0x1(%r12)
  mov    %dl,(%rax)
  lea    0x1(%rbp),%eax
  mov    D5(%rip),%rdi
  mov    $0x0,%edx
  divl   (%rdi)
  mov    %edx,%ebp
  cmp    %r14,%rbx
  je     L22
L120:
  test   %ebp,%ebp
  jne    L68
  mov    0x8(%rsp),%rdx
  mov    %r13,%rsi
  mov    %r13,%rdi
  call   <Camellia_encrypt@plt>
  jmp    L68
```

assistant: ```c
void Camellia_cfb128_encrypt(const unsigned char *in, unsigned char *out, const unsigned long length, const CAMELLIA_KEY *key, unsigned char *ivec, int *num, const int enc) {
  unsigned int n;
  unsigned long l = length;
  unsigned char c;
  assert(in && out && key && ivec && num);
  n = *num;
  if (enc) {
    while (l--) {
      if (n == 0) {
        Camellia_encrypt(ivec, ivec, key);
      }
      ivec[n] = *(out++) = *(in++) ^ ivec[n];
      n = (n + 1) % CAMELLIA_BLOCK_SIZE;
    }
  } else {
    while (l--) {
      if (n == 0) {
        Camellia_encrypt(ivec, ivec, key);
      }
      c = *(in);
      *(out++) = *(in++) ^ ivec[n];
      ivec[n] = c;
      n = (n + 1) % CAMELLIA_BLOCK_SIZE;
    }
  }
  *num = n;
}
```
user: What is the c source code of the assembly code below:

```asm
<Camellia_cfb128_encrypt>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %r9,(%rsp)
  test   %rdi,%rdi
  je     L49
  test   %rsi,%rsi
  je     L49
  test   %rcx,%rcx
  setne  %al
  test   %r8,%r8
  setne  %dl
  xor    %edi,%edi
  and    %edx,%eax
  test   %r9,%r9
  setne  %dil
  and    %eax,%edi
L79:
  call   <assert@plt>
  mov    (%rsp),%rax
  mov    (%rax),%ebp
  mov    0x50(%rsp),%eax
  test   %eax,%eax
  jne    L5
  test   %r15,%r15
  je     L33
  lea    (%rbx,%r15,1),%rcx
  mov    D12(%rip),%r15
  jmp    L96
  nopl   (%rax)
L0:
  mov    %ebp,%eax
  movzbl (%rbx),%edx
  add    $0x1,%r12
  add    $0x1,%rbx
  add    %r14,%rax
  movzbl (%rax),%esi
  xor    %edx,%esi
  mov    %sil,-0x1(%r12)
  mov    %dl,(%rax)
  lea    0x1(%rbp),%eax
  xor    %edx,%edx
  divl   (%r15)
  mov    %edx,%ebp
  cmp    %rcx,%rbx
  je     L33
L96:
  test   %ebp,%ebp
  jne    L0
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r14,%rdi
  mov    %rcx,0x8(%rsp)
  call   <Camellia_encrypt@plt>
  mov    0x8(%rsp),%rcx
  jmp    L0
  nopl   0x0(%rax)
L5:
  test   %r15,%r15
  jne    L9
L33:
  mov    (%rsp),%rax
  mov    %ebp,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  xor    %edi,%edi
  jmp    L79
  nop
L9:
  lea    (%rbx,%r15,1),%rcx
  mov    D12(%rip),%r15
  jmp    L117
  nopl   (%rax)
L81:
  mov    %ebp,%eax
  movzbl (%rbx),%edx
  add    $0x1,%r12
  add    $0x1,%rbx
  add    %r14,%rax
  xor    (%rax),%dl
  mov    %dl,-0x1(%r12)
  mov    %dl,(%rax)
  lea    0x1(%rbp),%eax
  xor    %edx,%edx
  divl   (%r15)
  mov    %edx,%ebp
  cmp    %rcx,%rbx
  je     L33
L117:
  test   %ebp,%ebp
  jne    L81
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r14,%rdi
  mov    %rcx,0x8(%rsp)
  call   <Camellia_encrypt@plt>
  mov    0x8(%rsp),%rcx
  jmp    L81
```

assistant: ```c
void Camellia_cfb128_encrypt(const unsigned char *in, unsigned char *out, const unsigned long length, const CAMELLIA_KEY *key, unsigned char *ivec, int *num, const int enc) {
  unsigned int n;
  unsigned long l = length;
  unsigned char c;
  assert(in && out && key && ivec && num);
  n = *num;
  if (enc) {
    while (l--) {
      if (n == 0) {
        Camellia_encrypt(ivec, ivec, key);
      }
      ivec[n] = *(out++) = *(in++) ^ ivec[n];
      n = (n + 1) % CAMELLIA_BLOCK_SIZE;
    }
  } else {
    while (l--) {
      if (n == 0) {
        Camellia_encrypt(ivec, ivec, key);
      }
      c = *(in);
      *(out++) = *(in++) ^ ivec[n];
      ivec[n] = c;
      n = (n + 1) % CAMELLIA_BLOCK_SIZE;
    }
  }
  *num = n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Camellia_cfb128_encrypt>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L56
  test   %rsi,%rsi
  je     L56
  test   %rcx,%rcx
  setne  %al
  test   %r8,%r8
  setne  %dl
  xor    %edi,%edi
  and    %edx,%eax
  test   %r9,%r9
  setne  %dil
  and    %eax,%edi
L45:
  call   <assert@plt>
  mov    0x50(%rsp),%eax
  mov    0x0(%r13),%edx
  test   %eax,%eax
  jne    L19
  test   %r14,%r14
  je     L113
  lea    (%rbx,%r14,1),%r8
  mov    D11(%rip),%r14
L50:
  test   %edx,%edx
  je     L29
  mov    %edx,%eax
  movzbl (%rbx),%esi
  add    $0x1,%rbp
  add    $0x1,%rbx
  add    %r15,%rax
  movzbl (%rax),%edi
  xor    %esi,%edi
  mov    %dil,-0x1(%rbp)
  mov    %sil,(%rax)
  lea    0x1(%rdx),%eax
  xor    %edx,%edx
  divl   (%r14)
  cmp    %r8,%rbx
  jne    L50
L113:
  mov    %edx,0x0(%r13)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L19:
  test   %r14,%r14
  je     L113
  lea    (%rbx,%r14,1),%r8
  mov    D11(%rip),%r14
L28:
  test   %edx,%edx
  je     L2
L109:
  mov    %edx,%eax
  movzbl (%rbx),%esi
  add    $0x1,%rbp
  add    $0x1,%rbx
  add    %r15,%rax
  xor    (%rax),%sil
  mov    %sil,-0x1(%rbp)
  mov    %sil,(%rax)
  lea    0x1(%rdx),%eax
  xor    %edx,%edx
  divl   (%r14)
  cmp    %r8,%rbx
  je     L113
  test   %edx,%edx
  jne    L109
L2:
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r15,%rdi
  add    $0x1,%rbx
  mov    %r8,0x8(%rsp)
  add    $0x1,%rbp
  call   <Camellia_encrypt@plt>
  movzbl (%r15),%eax
  xor    -0x1(%rbx),%al
  xor    %edx,%edx
  mov    %al,-0x1(%rbp)
  mov    0x8(%rsp),%r8
  mov    %al,(%r15)
  mov    $0x1,%eax
  divl   (%r14)
  cmp    %rbx,%r8
  jne    L28
  jmp    L113
  nopl   0x0(%rax,%rax,1)
L56:
  xor    %edi,%edi
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r15,%rdi
  mov    %r8,0x8(%rsp)
  call   <Camellia_encrypt@plt>
  movzbl (%rbx),%eax
  movzbl (%r15),%edx
  add    $0x1,%rbp
  mov    0x8(%rsp),%r8
  add    $0x1,%rbx
  xor    %eax,%edx
  mov    %dl,-0x1(%rbp)
  xor    %edx,%edx
  mov    %al,(%r15)
  mov    $0x1,%eax
  divl   (%r14)
  cmp    %r8,%rbx
  jne    L50
  jmp    L113
```

assistant: ```c
void Camellia_cfb128_encrypt(const unsigned char *in, unsigned char *out, const unsigned long length, const CAMELLIA_KEY *key, unsigned char *ivec, int *num, const int enc) {
  unsigned int n;
  unsigned long l = length;
  unsigned char c;
  assert(in && out && key && ivec && num);
  n = *num;
  if (enc) {
    while (l--) {
      if (n == 0) {
        Camellia_encrypt(ivec, ivec, key);
      }
      ivec[n] = *(out++) = *(in++) ^ ivec[n];
      n = (n + 1) % CAMELLIA_BLOCK_SIZE;
    }
  } else {
    while (l--) {
      if (n == 0) {
        Camellia_encrypt(ivec, ivec, key);
      }
      c = *(in);
      *(out++) = *(in++) ^ ivec[n];
      ivec[n] = c;
      n = (n + 1) % CAMELLIA_BLOCK_SIZE;
    }
  }
  *num = n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fun_e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D28(%rip),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,D17(%rip)
  mov    D17(%rip),%eax
  mov    %eax,%edi
  call   <fun_f@plt>
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int fun_e(int arge) {
  static int loce = 0;
  loce += arge;
  return fun_f(loce);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fun_e>:
  endbr64
  sub    $0x8,%rsp
  add    D13(%rip),%edi
  mov    %edi,D10(%rip)
  call   <fun_f@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
__attribute__((always_)) int fun_e(int arge) {
  static int loce = 0;
  loce += arge;
  return fun_f(loce);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fun_e>:
  endbr64
  add    D7(%rip),%edi
  mov    %edi,D1(%rip)
  jmp    1050 <fun_f@plt>
```

assistant: ```c
__attribute__((always_)) int fun_e(int arge) {
  static int loce = 0;
  loce += arge;
  return fun_f(loce);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fun_e>:
  endbr64
  add    D19(%rip),%edi
  mov    %edi,D9(%rip)
  jmp    1050 <fun_f@plt>
```

assistant: ```c
__attribute__((always_)) int fun_e(int arge) {
  static int loce = 0;
  loce += arge;
  return fun_f(loce);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_change>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <do_del@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  call   <insert_mode@plt>
  jmp    L10
L8:
  mov    $0x1,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int do_change(void) {
  if (!do_del())
    return insert_mode();
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_change>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <do_del@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L17
L14:
  add    $0x8,%rsp
  ret
L17:
  mov    $0x0,%eax
  call   <insert_mode@plt>
  jmp    L14
```

assistant: ```c
int do_change(void) {
  if (!do_del())
    return insert_mode();
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_change>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <do_del@plt>
  test   %eax,%eax
  je     L3
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L3:
  add    $0x8,%rsp
  jmp    1070 <insert_mode@plt>
```

assistant: ```c
int do_change(void) {
  if (!do_del())
    return insert_mode();
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_change>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <do_del@plt>
  test   %eax,%eax
  je     L8
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L8:
  add    $0x8,%rsp
  jmp    1070 <insert_mode@plt>
```

assistant: ```c
int do_change(void) {
  if (!do_del())
    return insert_mode();
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<NumberOfSetBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x18,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t NumberOfSetBits(uint32_t i) {
  i = i - ((i >> 1) & 0x55555555);
  i = (i & 0x33333333) + ((i >> 2) & 0x33333333);
  return (((i + (i >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24;
}
```
user: What is the c source code of the assembly code below:

```asm
<NumberOfSetBits>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x18,%eax
  ret
```

assistant: ```c
uint8_t NumberOfSetBits(uint32_t i) {
  i = i - ((i >> 1) & 0x55555555);
  i = (i & 0x33333333) + ((i >> 2) & 0x33333333);
  return (((i + (i >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<NumberOfSetBits>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x18,%eax
  ret
```

assistant: ```c
uint8_t NumberOfSetBits(uint32_t i) {
  i = i - ((i >> 1) & 0x55555555);
  i = (i & 0x33333333) + ((i >> 2) & 0x33333333);
  return (((i + (i >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<NumberOfSetBits>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x18,%eax
  ret
```

assistant: ```c
uint8_t NumberOfSetBits(uint32_t i) {
  i = i - ((i >> 1) & 0x55555555);
  i = (i & 0x33333333) + ((i >> 2) & 0x33333333);
  return (((i + (i >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_hx_cst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%ecx
  lea    D48(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <snprintf@plt>
  cmp    $0x1,%eax
  je     L48
  call   <failure_on_line_114@plt>
L48:
  mov    $0x0,%ecx
  lea    D26(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <snprintf@plt>
  cmp    $0x2,%eax
  je     L45
  call   <failure_on_line_115@plt>
L45:
  mov    $0x1,%ecx
  lea    D48(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <snprintf@plt>
  cmp    $0x3,%eax
  je     L31
  call   <failure_on_line_117@plt>
L31:
  mov    $0x1,%ecx
  lea    D26(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <snprintf@plt>
  cmp    $0x4,%eax
  je     L29
  call   <failure_on_line_118@plt>
L29:
  mov    $0x1,%ecx
  lea    D3(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <snprintf@plt>
  cmp    $0x5,%eax
  je     L1
  call   <failure_on_line_119@plt>
L1:
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D48
type: string
name: disassemble_data
arguments: data_label: D26
type: string
name: disassemble_data
arguments: data_label: D3
type: string

tool: D48: %#.1hx

tool: D26: %#.2hx

tool: D3: %#.3hx

assistant: ```c
void test_hx_cst(void) {
  do {
    extern void failure_on_line_114(void);
    if (!(1 == __builtin_snprintf(0, 0, "%#.1hx", 0)))
      failure_on_line_114();
  } while (0);
  do {
    extern void failure_on_line_115(void);
    if (!(2 == __builtin_snprintf(0, 0, "%#.2hx", 0)))
      failure_on_line_115();
  } while (0);
  do {
    extern void failure_on_line_117(void);
    if (!(3 == __builtin_snprintf(0, 0, "%#.1hx", 1)))
      failure_on_line_117();
  } while (0);
  do {
    extern void failure_on_line_118(void);
    if (!(4 == __builtin_snprintf(0, 0, "%#.2hx", 1)))
      failure_on_line_118();
  } while (0);
  do {
    extern void failure_on_line_119(void);
    if (!(5 == __builtin_snprintf(0, 0, "%#.3hx", 1)))
      failure_on_line_119();
  } while (0);
}
```