ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stdlib_strided_dvariancetk>:
  endbr64
  test   %rdi,%rdi
  jle    L15
  pxor   %xmm5,%xmm5
  cvtsi2sd %rdi,%xmm5
  movapd %xmm5,%xmm4
  subsd  %xmm0,%xmm4
  pxor   %xmm0,%xmm0
  comisd %xmm4,%xmm0
  jae    L24
  cmp    $0x1,%rdi
  je     L33
  test   %rdx,%rdx
  je     L33
  mov    $0x0,%eax
  jns    L10
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
L10:
  lea    (%rsi,%rax,8),%rcx
  shl    $0x3,%rdx
  movapd %xmm0,%xmm2
  xor    %eax,%eax
L37:
  movsd  (%rcx),%xmm1
  add    $0x1,%rax
  add    %rdx,%rcx
  movapd %xmm1,%xmm3
  addsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm0
  cmp    %rax,%rdi
  jne    L37
  movapd %xmm2,%xmm1
  divsd  %xmm5,%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  divsd  %xmm4,%xmm0
L33:
  ret
  nopl   (%rax)
L15:
  pxor   %xmm0,%xmm0
L24:
  divsd  %xmm0,%xmm0
  ret
```

assistant: ```c
double stdlib_strided_dvariancetk(const int64_t N, const double correction, const double *X, const int64_t stride) {
  int64_t ix;
  int64_t i;
  double dN;
  double S2;
  double S;
  double n;
  double v;
  dN = (double)N;
  n = dN - correction;
  if (N <= 0 || n <= 0.0) {
    return 0.0 / 0.0;
  }
  if (N == 1 || stride == 0) {
    return 0.0;
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  S2 = 0.0;
  S = 0.0;
  for (i = 0; i < N; i++) {
    v = X[ix];
    S2 += v * v;
    S += v;
    ix += stride;
  }
  return (S2 - ((S / dN) * S)) / n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stdlib_strided_dvariancetk>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  jle    L32
  pxor   %xmm6,%xmm6
  cvtsi2sd %rdi,%xmm6
  movapd %xmm6,%xmm4
  subsd  %xmm0,%xmm4
  pxor   %xmm0,%xmm0
  comisd %xmm4,%xmm0
  jae    L61
  cmp    $0x1,%rdi
  je     L38
  test   %rdx,%rdx
  je     L38
  js     L21
  cmp    $0x1,%rdx
  jne    L42
  mov    %rdi,%rcx
  mov    %rsi,%rdx
  movapd %xmm0,%xmm1
  shr    %rcx
  shl    $0x4,%rcx
  add    %rsi,%rcx
  cs nopw 0x0(%rax,%rax,1)
L67:
  movupd (%rdx),%xmm2
  add    $0x10,%rdx
  movapd %xmm2,%xmm3
  addsd  %xmm2,%xmm1
  mulpd  %xmm2,%xmm3
  unpckhpd %xmm2,%xmm2
  addsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm0
  unpckhpd %xmm3,%xmm3
  addsd  %xmm3,%xmm0
  cmp    %rcx,%rdx
  jne    L67
  mov    %rax,%rdx
  and    $0xfffffffffffffffe,%rdx
  test   $0x1,%al
  je     L97
  movsd  (%rsi,%rdx,8),%xmm2
  movapd %xmm2,%xmm3
  addsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm3
  addsd  %xmm3,%xmm0
L97:
  movapd %xmm1,%xmm2
  divsd  %xmm6,%xmm2
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  divsd  %xmm4,%xmm0
L38:
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  pxor   %xmm0,%xmm0
L61:
  divsd  %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L21:
  mov    $0x1,%ecx
  sub    %rdi,%rcx
  imul   %rdx,%rcx
L34:
  lea    (%rsi,%rcx,8),%rsi
  shl    $0x3,%rdx
  movapd %xmm0,%xmm1
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L35:
  movsd  (%rsi),%xmm2
  add    $0x1,%rcx
  add    %rdx,%rsi
  movapd %xmm2,%xmm3
  addsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm3
  addsd  %xmm3,%xmm0
  cmp    %rcx,%rax
  jne    L35
  jmp    L97
L42:
  xor    %ecx,%ecx
  jmp    L34
```

assistant: ```c
double stdlib_strided_dvariancetk(const int64_t N, const double correction, const double *X, const int64_t stride) {
  int64_t ix;
  int64_t i;
  double dN;
  double S2;
  double S;
  double n;
  double v;
  dN = (double)N;
  n = dN - correction;
  if (N <= 0 || n <= 0.0) {
    return 0.0 / 0.0;
  }
  if (N == 1 || stride == 0) {
    return 0.0;
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  S2 = 0.0;
  S = 0.0;
  for (i = 0; i < N; i++) {
    v = X[ix];
    S2 += v * v;
    S += v;
    ix += stride;
  }
  return (S2 - ((S / dN) * S)) / n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L12
  movzbl -0x1(%rbp),%eax
  test   %al,%al
  jns    L11
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L17
L11:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L17
L12:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D23
data_type: string
name: unpack_data
arguments: data_tag: D25
data_type: string
name: unpack_data
arguments: data_tag: D28
data_type: string

tool: D23: win


tool: D25: lose


tool: D28: Usage: program-name character


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char c = argv[1][0];
  if (argc > 1) {
    if (c > 127)
      printf("win\n");
    else
      printf("lose\n");
  } else {
    printf("Usage: program-name character\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%edi
  jle    L8
  test   %al,%al
  js     L39
  lea    D8(%rip),%rdi
  call   <printf@plt>
L36:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L39:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L8:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L36
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D23
type_guessed: string

tool: D8: lose


tool: D10: win


tool: D23: Usage: program-name character


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char c = argv[1][0];
  if (argc > 1) {
    if (c > 127)
      printf("win\n");
    else
      printf("lose\n");
  } else {
    printf("Usage: program-name character\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%edi
  jle    L6
  test   %al,%al
  js     L18
  lea    D16(%rip),%rdi
  call   <printf@plt>
L22:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L18:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L6:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L22
```

tool_calls: name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D8
datatype: string

tool: D16: lose


tool: D7: win


tool: D8: Usage: program-name character


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char c = argv[1][0];
  if (argc > 1) {
    if (c > 127)
      printf("win\n");
    else
      printf("lose\n");
  } else {
    printf("Usage: program-name character\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%edi
  jle    L38
  test   %al,%al
  js     L23
  lea    D22(%rip),%rdi
  call   <printf@plt>
L16:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L23:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L38:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D29
datatype: string

tool: D22: lose


tool: D1: win


tool: D29: Usage: program-name character


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char c = argv[1][0];
  if (argc > 1) {
    if (c > 127)
      printf("win\n");
    else
      printf("lose\n");
  } else {
    printf("Usage: program-name character\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x14,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  movsbl -0x2d(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  cmpl   $0xa,-0x20(%rbp)
  je     L61
  mov    $0x1,%eax
  jmp    L70
L61:
  cmpl   $0xa,-0x24(%rbp)
  je     L12
  mov    $0x2,%eax
  jmp    L70
L12:
  cmpl   $0xa,-0x1c(%rbp)
  je     L86
  mov    $0x3,%eax
  jmp    L70
L86:
  cmpl   $0xa,-0x18(%rbp)
  je     L132
  mov    $0x4,%eax
  jmp    L70
L132:
  cmpl   $0xa,-0x14(%rbp)
  je     L45
  mov    $0x5,%eax
  jmp    L70
L45:
  cmpl   $0xa,-0x10(%rbp)
  je     L2
  mov    $0x6,%eax
  jmp    L70
L2:
  cmpl   $0x14,-0xc(%rbp)
  je     L1
  mov    $0x7,%eax
  jmp    L70
L1:
  mov    $0x0,%eax
L70:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L115
  call   <__stack_chk_fail@plt>
L115:
  leave
  ret
```

assistant: ```c
int main() {
  signed a;
  int b;
  int c;
  int d;
  int e;
  int f;
  int g;
  int h;
  a = b = 10;
  c = a;
  d = b;
  (e) = c;
  ((f)) = d;
  g = 20;
  int i;
  int j;
  char k;
  &i;
  &j;
  i = g;
  j = i;
  j = k;
  if (a != 10)
    return 1;
  if (b != 10)
    return 2;
  if (c != 10)
    return 3;
  if (d != 10)
    return 4;
  if (e != 10)
    return 5;
  if (f != 10)
    return 6;
  if (g != 20)
    return 7;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  signed a;
  int b;
  int c;
  int d;
  int e;
  int f;
  int g;
  int h;
  a = b = 10;
  c = a;
  d = b;
  (e) = c;
  ((f)) = d;
  g = 20;
  int i;
  int j;
  char k;
  &i;
  &j;
  i = g;
  j = i;
  j = k;
  if (a != 10)
    return 1;
  if (b != 10)
    return 2;
  if (c != 10)
    return 3;
  if (d != 10)
    return 4;
  if (e != 10)
    return 5;
  if (f != 10)
    return 6;
  if (g != 20)
    return 7;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  signed a;
  int b;
  int c;
  int d;
  int e;
  int f;
  int g;
  int h;
  a = b = 10;
  c = a;
  d = b;
  (e) = c;
  ((f)) = d;
  g = 20;
  int i;
  int j;
  char k;
  &i;
  &j;
  i = g;
  j = i;
  j = k;
  if (a != 10)
    return 1;
  if (b != 10)
    return 2;
  if (c != 10)
    return 3;
  if (d != 10)
    return 4;
  if (e != 10)
    return 5;
  if (f != 10)
    return 6;
  if (g != 20)
    return 7;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  signed a;
  int b;
  int c;
  int d;
  int e;
  int f;
  int g;
  int h;
  a = b = 10;
  c = a;
  d = b;
  (e) = c;
  ((f)) = d;
  g = 20;
  int i;
  int j;
  char k;
  &i;
  &j;
  i = g;
  j = i;
  j = k;
  if (a != 10)
    return 1;
  if (b != 10)
    return 2;
  if (c != 10)
    return 3;
  if (d != 10)
    return 4;
  if (e != 10)
    return 5;
  if (f != 10)
    return 6;
  if (g != 20)
    return 7;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<query_domain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <chomp@plt>
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x78(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x60(%rbp)
  mov    -0x68(%rbp),%rax
  lea    D27(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x58(%rbp)
  mov    -0x60(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x60(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x58(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <ReadFile@plt>
  test   %eax,%eax
  jne    L0
  mov    $0x0,%eax
  jmp    L12
L0:
  mov    $0x1,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D27
type_infered: string
name: retrieve_data
arguments: data_label: D26
type_infered: string
name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D27: .

tool: D26: %s_%s.txt


tool: D2: %s_%s.txt

assistant: ```c
int query_domain(char domainname[56]) {
  char domain_file[60];
  char *tld;
  char *domain;
  char *tmp;
  chomp(domainname);
  tmp = strdup(domainname);
  tld = strchr(domainname, '.');
  domain = strtok(tmp, ".");
  printf("%s_%s.txt\n", tld + 1, domain);
  sprintf(domain_file, "%s_%s.txt", tld + 1, domain);
  if (!ReadFile(domain_file)) {
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<query_domain>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <chomp@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,%rbp
  add    $0x1,%rbx
  mov    %rax,%rdx
  mov    %rbx,%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%r12
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <ReadFile@plt>
  test   %eax,%eax
  setne  %al
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  movzbl %al,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D15
type_guessed: string
name: read_data
arguments: data_tag: D26
type_guessed: string
name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D15: .

tool: D26: %s_%s.txt


tool: D4: %s_%s.txt

assistant: ```c
int query_domain(char domainname[56]) {
  char domain_file[60];
  char *tld;
  char *domain;
  char *tmp;
  chomp(domainname);
  tmp = strdup(domainname);
  tld = strchr(domainname, '.');
  domain = strtok(tmp, ".");
  printf("%s_%s.txt\n", tld + 1, domain);
  sprintf(domain_file, "%s_%s.txt", tld + 1, domain);
  if (!ReadFile(domain_file)) {
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<query_domain>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <chomp@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %r12,%rdi
  mov    $0x2e,%esi
  mov    %rax,%r13
  call   <strchr@plt>
  mov    %r13,%rdi
  lea    D1(%rip),%rsi
  mov    %rax,%r12
  call   <strtok@plt>
  add    $0x1,%r12
  lea    D22(%rip),%rdi
  mov    %rax,%r13
  mov    %rax,%rdx
  mov    %r12,%rsi
  call   <printf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D25(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <ReadFile@plt>
  test   %eax,%eax
  setne  %al
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x50,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string

tool: D1: .

tool: D22: %s_%s.txt


tool: D25: %s_%s.txt

assistant: ```c
int query_domain(char domainname[56]) {
  char domain_file[60];
  char *tld;
  char *domain;
  char *tmp;
  chomp(domainname);
  tmp = strdup(domainname);
  tld = strchr(domainname, '.');
  domain = strtok(tmp, ".");
  printf("%s_%s.txt\n", tld + 1, domain);
  sprintf(domain_file, "%s_%s.txt", tld + 1, domain);
  if (!ReadFile(domain_file)) {
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<query_domain>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <chomp@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %r12,%rdi
  mov    $0x2e,%esi
  mov    %rax,%r13
  call   <strchr@plt>
  mov    %r13,%rdi
  lea    D10(%rip),%rsi
  mov    %rax,%r12
  call   <strtok@plt>
  add    $0x1,%r12
  lea    D0(%rip),%rdi
  mov    %rax,%r13
  mov    %rax,%rdx
  mov    %r12,%rsi
  call   <printf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <ReadFile@plt>
  test   %eax,%eax
  setne  %al
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x50,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
data_type: string
name: parse_data
arguments: label: D0
data_type: string
name: parse_data
arguments: label: D2
data_type: string

tool: D10: .

tool: D0: %s_%s.txt


tool: D2: %s_%s.txt

assistant: ```c
int query_domain(char domainname[56]) {
  char domain_file[60];
  char *tld;
  char *domain;
  char *tmp;
  chomp(domainname);
  tmp = strdup(domainname);
  tld = strchr(domainname, '.');
  domain = strtok(tmp, ".");
  printf("%s_%s.txt\n", tld + 1, domain);
  sprintf(domain_file, "%s_%s.txt", tld + 1, domain);
  if (!ReadFile(domain_file)) {
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fibonacci_computing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fibonacci_computing(unsigned int *lastTerm, unsigned int *oldTerm) {
  unsigned int tmp_oldTerm = *oldTerm;
  *oldTerm = *lastTerm;
  *lastTerm = tmp_oldTerm + *lastTerm;
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fibonacci_computing>:
  endbr64
  mov    (%rsi),%edx
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fibonacci_computing(unsigned int *lastTerm, unsigned int *oldTerm) {
  unsigned int tmp_oldTerm = *oldTerm;
  *oldTerm = *lastTerm;
  *lastTerm = tmp_oldTerm + *lastTerm;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fibonacci_computing>:
  endbr64
  mov    (%rsi),%edx
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fibonacci_computing(unsigned int *lastTerm, unsigned int *oldTerm) {
  unsigned int tmp_oldTerm = *oldTerm;
  *oldTerm = *lastTerm;
  *lastTerm = tmp_oldTerm + *lastTerm;
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fibonacci_computing>:
  endbr64
  mov    (%rsi),%edx
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fibonacci_computing(unsigned int *lastTerm, unsigned int *oldTerm) {
  unsigned int tmp_oldTerm = *oldTerm;
  *oldTerm = *lastTerm;
  *lastTerm = tmp_oldTerm + *lastTerm;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<testInplaceReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xb,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <build123Array@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <outArrInt@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <inplaceReverse@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <outArrInt@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void testInplaceReverse() {
  int size = 11;
  int *elems = build123Array(size);
  outArrInt(elems, size);
  inplaceReverse(elems, size);
  outArrInt(elems, size);
  free(elems);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testInplaceReverse>:
  endbr64
  push   %rbx
  mov    $0xb,%edi
  call   <build123Array@plt>
  mov    %rax,%rbx
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <outArrInt@plt>
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <inplaceReverse@plt>
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <outArrInt@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void testInplaceReverse() {
  int size = 11;
  int *elems = build123Array(size);
  outArrInt(elems, size);
  inplaceReverse(elems, size);
  outArrInt(elems, size);
  free(elems);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testInplaceReverse>:
  endbr64
  push   %rbp
  mov    $0xb,%edi
  call   <build123Array@plt>
  mov    $0xb,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <outArrInt@plt>
  mov    %rbp,%rdi
  mov    $0xb,%esi
  call   <inplaceReverse@plt>
  mov    %rbp,%rdi
  mov    $0xb,%esi
  call   <outArrInt@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
```

assistant: ```c
void testInplaceReverse() {
  int size = 11;
  int *elems = build123Array(size);
  outArrInt(elems, size);
  inplaceReverse(elems, size);
  outArrInt(elems, size);
  free(elems);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<testInplaceReverse>:
  endbr64
  push   %rbp
  mov    $0xb,%edi
  call   <build123Array@plt>
  mov    $0xb,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <outArrInt@plt>
  mov    %rbp,%rdi
  mov    $0xb,%esi
  call   <inplaceReverse@plt>
  mov    %rbp,%rdi
  mov    $0xb,%esi
  call   <outArrInt@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
```

assistant: ```c
void testInplaceReverse() {
  int size = 11;
  int *elems = build123Array(size);
  outArrInt(elems, size);
  inplaceReverse(elems, size);
  outArrInt(elems, size);
  free(elems);
}
```