ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<transfer_rate_sigmask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L55
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D186(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D68(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D176(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D159(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D141(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D196(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <sigaddset@plt>
  jmp    L72
L82:
  mov    D116(%rip),%rax
  mov    (%rax),%rdx
  mov    D182(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L87
  nop
L72:
  mov    D195(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  lea    D48(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  test   %rax,%rax
  js     L82
  jmp    L32
L45:
  mov    D116(%rip),%rax
  mov    (%rax),%rdx
  mov    D182(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L68
  nop
L55:
  mov    D184(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  lea    D48(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  test   %rax,%rax
  js     L45
  jmp    L37
L87:
  nop
  jmp    L37
L68:
  nop
L37:
  nop
L32:
  leave
  ret
```

assistant: ```c
void transfer_rate_sigmask(int block) {
  static sigset_t sig_set;
  if (block) {
    sigemptyset(&sig_set);
    sigaddset(&sig_set, SIGCHLD);
    sigaddset(&sig_set, SIGINT);
    sigaddset(&sig_set, SIGQUIT);
    sigaddset(&sig_set, SIGURG);
    sigaddset(&sig_set, SIGIO);
    sigaddset(&sig_set, SIGBUS);
    sigaddset(&sig_set, SIGHUP);
    while (sigprocmask(SIG_BLOCK, &sig_set, NULL) < 0) {
      if (errno == EINTR) {
        continue;
      }
      break;
    }
  } else {
    while (sigprocmask(SIG_UNBLOCK, &sig_set, NULL) < 0) {
      if (errno == EINTR) {
        continue;
      }
      break;
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transfer_rate_sigmask>:
  endbr64
  push   %rbx
  lea    D90(%rip),%rbx
  test   %edi,%edi
  jne    L2
L22:
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    D25(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  test   %rax,%rax
  jns    L58
  mov    D39(%rip),%rdx
  mov    D122(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L22
L58:
  pop    %rbx
  ret
L2:
  mov    %rbx,%rdi
  call   <sigemptyset@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    D66(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    D127(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    D36(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    D78(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
L11:
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  test   %rax,%rax
  jns    L58
  mov    D39(%rip),%rdx
  mov    D122(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L58
  jmp    L11
```

assistant: ```c
void transfer_rate_sigmask(int block) {
  static sigset_t sig_set;
  if (block) {
    sigemptyset(&sig_set);
    sigaddset(&sig_set, SIGCHLD);
    sigaddset(&sig_set, SIGINT);
    sigaddset(&sig_set, SIGQUIT);
    sigaddset(&sig_set, SIGURG);
    sigaddset(&sig_set, SIGIO);
    sigaddset(&sig_set, SIGBUS);
    sigaddset(&sig_set, SIGHUP);
    while (sigprocmask(SIG_BLOCK, &sig_set, NULL) < 0) {
      if (errno == EINTR) {
        continue;
      }
      break;
    }
  } else {
    while (sigprocmask(SIG_UNBLOCK, &sig_set, NULL) < 0) {
      if (errno == EINTR) {
        continue;
      }
      break;
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<transfer_rate_sigmask>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D133(%rip),%rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L30
  mov    D98(%rip),%rbp
L15:
  mov    0x0(%rbp),%edi
  xor    %edx,%edx
  mov    %rbx,%rsi
  call   <sigprocmask@plt>
  test   %rax,%rax
  jns    L31
  mov    D5(%rip),%rax
  mov    D71(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L15
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %rbx,%rdi
  call   <sigemptyset@plt>
  mov    D26(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D114(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D56(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D53(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D104(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D3(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D91(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D125(%rip),%rbp
L4:
  mov    0x0(%rbp),%edi
  xor    %edx,%edx
  mov    %rbx,%rsi
  call   <sigprocmask@plt>
  test   %rax,%rax
  jns    L31
  mov    D5(%rip),%rax
  mov    D71(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void transfer_rate_sigmask(int block) {
  static sigset_t sig_set;
  if (block) {
    sigemptyset(&sig_set);
    sigaddset(&sig_set, SIGCHLD);
    sigaddset(&sig_set, SIGINT);
    sigaddset(&sig_set, SIGQUIT);
    sigaddset(&sig_set, SIGURG);
    sigaddset(&sig_set, SIGIO);
    sigaddset(&sig_set, SIGBUS);
    sigaddset(&sig_set, SIGHUP);
    while (sigprocmask(SIG_BLOCK, &sig_set, NULL) < 0) {
      if (errno == EINTR) {
        continue;
      }
      break;
    }
  } else {
    while (sigprocmask(SIG_UNBLOCK, &sig_set, NULL) < 0) {
      if (errno == EINTR) {
        continue;
      }
      break;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<transfer_rate_sigmask>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D73(%rip),%rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L46
  mov    D121(%rip),%rbp
L5:
  mov    0x0(%rbp),%edi
  xor    %edx,%edx
  mov    %rbx,%rsi
  call   <sigprocmask@plt>
  test   %rax,%rax
  jns    L22
  mov    D92(%rip),%rax
  mov    D38(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L5
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rbx,%rdi
  call   <sigemptyset@plt>
  mov    D101(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D116(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D18(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D80(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D48(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D122(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D95(%rip),%rax
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D134(%rip),%rbp
L7:
  mov    0x0(%rbp),%edi
  xor    %edx,%edx
  mov    %rbx,%rsi
  call   <sigprocmask@plt>
  test   %rax,%rax
  jns    L22
  mov    D92(%rip),%rax
  mov    D38(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void transfer_rate_sigmask(int block) {
  static sigset_t sig_set;
  if (block) {
    sigemptyset(&sig_set);
    sigaddset(&sig_set, SIGCHLD);
    sigaddset(&sig_set, SIGINT);
    sigaddset(&sig_set, SIGQUIT);
    sigaddset(&sig_set, SIGURG);
    sigaddset(&sig_set, SIGIO);
    sigaddset(&sig_set, SIGBUS);
    sigaddset(&sig_set, SIGHUP);
    while (sigprocmask(SIG_BLOCK, &sig_set, NULL) < 0) {
      if (errno == EINTR) {
        continue;
      }
      break;
    }
  } else {
    while (sigprocmask(SIG_UNBLOCK, &sig_set, NULL) < 0) {
      if (errno == EINTR) {
        continue;
      }
      break;
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L19
  cmpq   $0x0,-0x10(%rbp)
  jne    L29
L19:
  mov    $0x0,%eax
  jmp    L12
L29:
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
char *strsub(const char *s, const char *search, const char *replace) {
  char *p;
  int len = strlen(s);
  int slen = strlen(search);
  int rlen = strlen(replace);
  char *d;
  p = strstr(s, search);
  if (!slen || !p) {
    return NULL;
  }
  d = (char *)xmalloc(len + rlen);
  len = p - s;
  memcpy(d, s, len);
  d[len] = 0;
  strcat(d, replace);
  strcat(d, p + slen);
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strsub>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r14
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %r13d,%r13d
  je     L15
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
  lea    (%r12,%r15,1),%edi
  call   <xmalloc@plt>
  mov    %rax,%r12
  mov    %rbx,%r15
  sub    %rbp,%r15
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %r15d,%r15
  movb   $0x0,(%r12,%r15,1)
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  movslq %r13d,%r13
  lea    (%rbx,%r13,1),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L21:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    $0x0,%r12d
  jmp    L21
```

assistant: ```c
char *strsub(const char *s, const char *search, const char *replace) {
  char *p;
  int len = strlen(s);
  int slen = strlen(search);
  int rlen = strlen(replace);
  char *d;
  p = strstr(s, search);
  if (!slen || !p) {
    return NULL;
  }
  d = (char *)xmalloc(len + rlen);
  len = p - s;
  memcpy(d, s, len);
  d[len] = 0;
  strcat(d, replace);
  strcat(d, p + slen);
  return d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strsub>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    %r13,%rdi
  movslq %eax,%rbp
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %eax,0xc(%rsp)
  call   <strstr@plt>
  test   %ebp,%ebp
  je     L20
  mov    %rax,%rbx
  test   %rax,%rax
  je     L20
  mov    0xc(%rsp),%edi
  add    %r14d,%edi
  mov    %rbx,%r14
  call   <xmalloc@plt>
  sub    %r15,%r14
  mov    %r15,%rsi
  mov    %rax,%r12
  mov    %r14d,%edx
  mov    %rax,%rdi
  movslq %r14d,%r14
  call   <memcpy@plt>
  movb   $0x0,(%r12,%r14,1)
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L13:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L20:
  xor    %r12d,%r12d
  jmp    L13
```

assistant: ```c
char *strsub(const char *s, const char *search, const char *replace) {
  char *p;
  int len = strlen(s);
  int slen = strlen(search);
  int rlen = strlen(replace);
  char *d;
  p = strstr(s, search);
  if (!slen || !p) {
    return NULL;
  }
  d = (char *)xmalloc(len + rlen);
  len = p - s;
  memcpy(d, s, len);
  d[len] = 0;
  strcat(d, replace);
  strcat(d, p + slen);
  return d;
}
```
user: What is the c source code of the assembly code below?

```asm
<strsub>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    %r13,%rdi
  movslq %eax,%rbp
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %eax,0xc(%rsp)
  call   <strstr@plt>
  test   %ebp,%ebp
  je     L8
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    0xc(%rsp),%edi
  add    %r14d,%edi
  mov    %rbx,%r14
  call   <xmalloc@plt>
  sub    %r15,%r14
  mov    %r15,%rsi
  mov    %rax,%r12
  mov    %r14d,%edx
  mov    %rax,%rdi
  movslq %r14d,%r14
  call   <memcpy@plt>
  movb   $0x0,(%r12,%r14,1)
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L13:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L8:
  xor    %r12d,%r12d
  jmp    L13
```

assistant: ```c
char *strsub(const char *s, const char *search, const char *replace) {
  char *p;
  int len = strlen(s);
  int slen = strlen(search);
  int rlen = strlen(replace);
  char *d;
  p = strstr(s, search);
  if (!slen || !p) {
    return NULL;
  }
  d = (char *)xmalloc(len + rlen);
  len = p - s;
  memcpy(d, s, len);
  d[len] = 0;
  strcat(d, replace);
  strcat(d, p + slen);
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_numeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L11:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L28
  mov    $0x1,%eax
  jmp    L1
L28:
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0x8,-0x4(%rbp)
  jle    L11
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int is_numeric(int ch) {
  int i;
  for (i = 0; i < 9; ++i) {
    if (ch == i) {
      return (1);
    }
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_numeric>:
  endbr64
  test   %edi,%edi
  je     L10
  mov    $0x1,%eax
L21:
  cmp    %eax,%edi
  je     L28
  add    $0x1,%eax
  cmp    $0x9,%eax
  jne    L21
  mov    $0x0,%eax
  ret
L10:
  mov    $0x1,%eax
  ret
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_numeric(int ch) {
  int i;
  for (i = 0; i < 9; ++i) {
    if (ch == i) {
      return (1);
    }
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_numeric>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmp    %eax,%edi
  je     L2
  add    $0x1,%eax
  cmp    $0x9,%eax
  jne    L0
  xor    %eax,%eax
  ret
  nop
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_numeric(int ch) {
  int i;
  for (i = 0; i < 9; ++i) {
    if (ch == i) {
      return (1);
    }
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_numeric>:
  endbr64
  xor    %eax,%eax
  cmp    $0x8,%edi
  setbe  %al
  ret
```

assistant: ```c
int is_numeric(int ch) {
  int i;
  for (i = 0; i < 9; ++i) {
    if (ch == i) {
      return (1);
    }
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<MicoStrCompare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L49
  cmpq   $0x0,-0x10(%rbp)
  jne    L48
L49:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  jmp    L12
L26:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  mov    $0x0,%eax
  jmp    L12
L48:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  sub    $0x1,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int MicoStrCompare(const char *s1, const char *s2) {
  if ((s1 == 0) || (s2 == 0))
    return (s1 - s2);
  while (*s1 == *s2++) {
    if (*s1++ == '\0')
      return (0);
  };
  return (*s1 - s2[-1]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<MicoStrCompare>:
  endbr64
  test   %rdi,%rdi
  je     L34
  mov    $0x0,%edx
  test   %rsi,%rsi
  je     L34
L7:
  movzbl (%rdi,%rdx,1),%ecx
  movzbl (%rsi,%rdx,1),%r8d
  cmp    %r8b,%cl
  jne    L21
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L7
  mov    $0x0,%eax
  ret
L34:
  mov    %edi,%eax
  sub    %esi,%eax
  ret
L21:
  movsbl %cl,%edi
  movsbl %r8b,%r8d
  mov    %edi,%eax
  sub    %r8d,%eax
  ret
```

assistant: ```c
int MicoStrCompare(const char *s1, const char *s2) {
  if ((s1 == 0) || (s2 == 0))
    return (s1 - s2);
  while (*s1 == *s2++) {
    if (*s1++ == '\0')
      return (0);
  };
  return (*s1 - s2[-1]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MicoStrCompare>:
  endbr64
  test   %rdi,%rdi
  je     L19
  xor    %edx,%edx
  test   %rsi,%rsi
  jne    L37
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L43:
  add    $0x1,%rdx
  test   %cl,%cl
  je     L5
L37:
  movzbl (%rdi,%rdx,1),%ecx
  movsbl (%rsi,%rdx,1),%r8d
  cmp    %r8b,%cl
  je     L43
  movsbl %cl,%edi
  mov    %edi,%eax
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %edi,%eax
  sub    %esi,%eax
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int MicoStrCompare(const char *s1, const char *s2) {
  if ((s1 == 0) || (s2 == 0))
    return (s1 - s2);
  while (*s1 == *s2++) {
    if (*s1++ == '\0')
      return (0);
  };
  return (*s1 - s2[-1]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<MicoStrCompare>:
  endbr64
  test   %rdi,%rdi
  je     L5
  xor    %edx,%edx
  test   %rsi,%rsi
  jne    L4
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rdx
  test   %cl,%cl
  je     L49
L4:
  movzbl (%rdi,%rdx,1),%ecx
  movsbl (%rsi,%rdx,1),%r8d
  cmp    %r8b,%cl
  je     L37
  movsbl %cl,%edi
  mov    %edi,%eax
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %edi,%eax
  sub    %esi,%eax
  ret
  nopl   (%rax)
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
int MicoStrCompare(const char *s1, const char *s2) {
  if ((s1 == 0) || (s2 == 0))
    return (s1 - s2);
  while (*s1 == *s2++) {
    if (*s1++ == '\0')
      return (0);
  };
  return (*s1 - s2[-1]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <func2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: Hello from subdir2/prog2.c


assistant: ```c
int main(void) {
  printf("Hello from subdir2/prog2.c\n");
  func2();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <func2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: Hello from subdir2/prog2.c


assistant: ```c
int main(void) {
  printf("Hello from subdir2/prog2.c\n");
  func2();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <func2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: Hello from subdir2/prog2.c


assistant: ```c
int main(void) {
  printf("Hello from subdir2/prog2.c\n");
  func2();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <func2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: Hello from subdir2/prog2.c


assistant: ```c
int main(void) {
  printf("Hello from subdir2/prog2.c\n");
  func2();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strc2p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strc2p(char *pstr, char *cstr) {
  int i;
  for (i = 0; cstr[i] != 0; i++)
    pstr[i + 1] = cstr[i];
  pstr[0] = i;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strc2p>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L24
  mov    $0x1,%eax
L6:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L6
L8:
  mov    %cl,(%rdi)
  mov    %ecx,%eax
  ret
L24:
  mov    $0x0,%ecx
  jmp    L8
```

assistant: ```c
int strc2p(char *pstr, char *cstr) {
  int i;
  for (i = 0; cstr[i] != 0; i++)
    pstr[i + 1] = cstr[i];
  pstr[0] = i;
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strc2p>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L4
  mov    $0x1,%eax
L18:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%r8d
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L18
  mov    %r8d,%edx
  mov    %r8d,%eax
  mov    %dl,(%rdi)
  ret
  nopl   0x0(%rax)
L4:
  xor    %r8d,%r8d
  mov    %dl,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strc2p(char *pstr, char *cstr) {
  int i;
  for (i = 0; cstr[i] != 0; i++)
    pstr[i + 1] = cstr[i];
  pstr[0] = i;
  return i;
}
```