ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<printAndFail>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D5(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printAndFail(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  fflush(stderr);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xfffffffd,-0x30(%rbp)
  movl   $0x7,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  movl   $0xfffffff5,-0x1c(%rbp)
  movl   $0xfffffff3,-0x18(%rbp)
  movl   $0xb,-0x14(%rbp)
  movl   $0xd,-0x10(%rbp)
  movl   $0xfffffffb,-0xc(%rbp)
  movl   $0xa,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArr@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L14
L6:
  movl   $0x0,-0x38(%rbp)
  jmp    L38
L39:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L2
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  lea    -0x30(%rbp),%rdx
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L2:
  addl   $0x1,-0x38(%rbp)
L38:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x38(%rbp)
  jl     L39
  addl   $0x1,-0x3c(%rbp)
L14:
  mov    -0x3c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L6
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArr@plt>
  mov    $0xffffffff,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

assistant: ```c
int main() {
  int arr[10] = {-3, 7, 1, 5, 9, -11, -13, 11, 13, -5};
  int length = 10;
  printArr(arr, length);
  for (int i = 0; i < length; i++) {
    for (int j = 0; j < length - 1; j++) {
      if (arr[j] > arr[j + 1])
        swap(&arr[j], &arr[j + 1]);
    }
  }
  printArr(arr, length);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xfffffffd,(%rsp)
  movl   $0x7,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  movl   $0xfffffff5,0x14(%rsp)
  movl   $0xfffffff3,0x18(%rsp)
  movl   $0xb,0x1c(%rsp)
  movl   $0xd,0x20(%rsp)
  movl   $0xfffffffb,0x24(%rsp)
  mov    %rsp,%rdi
  mov    $0xa,%esi
  call   <printArr@plt>
  mov    $0xa,%r12d
  lea    0x24(%rsp),%rbp
  jmp    L6
L32:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L33
L65:
  mov    0x4(%rbx),%eax
  cmp    %eax,(%rbx)
  jle    L32
  lea    0x4(%rbx),%rsi
  mov    %rbx,%rdi
  call   <swap@plt>
  jmp    L32
L33:
  sub    $0x1,%r12d
  je     L37
L6:
  mov    %rsp,%rbx
  jmp    L65
L37:
  mov    %rsp,%rdi
  mov    $0xa,%esi
  call   <printArr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0xffffffff,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int arr[10] = {-3, 7, 1, 5, 9, -11, -13, 11, 13, -5};
  int length = 10;
  printArr(arr, length);
  for (int i = 0; i < length; i++) {
    for (int j = 0; j < length - 1; j++) {
      if (arr[j] > arr[j + 1])
        swap(&arr[j], &arr[j + 1]);
    }
  }
  printArr(arr, length);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%esi
  push   %r12
  mov    $0xa,%r12d
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x7fffffffd,%rax
  mov    %rsp,%r13
  lea    0x24(%rsp),%rbp
  mov    %r13,%rdi
  mov    %rax,(%rsp)
  movabs $0x500000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xfffffff500000009,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xbfffffff3,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xfffffffb0000000d,%rax
  mov    %rax,0x20(%rsp)
  call   <printArr@plt>
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdi
  jmp    L55
  nopl   (%rax)
L19:
  mov    %rbx,%rdi
  cmp    %rbp,%rbx
  je     L31
L55:
  mov    0x4(%rdi),%eax
  lea    0x4(%rdi),%rbx
  cmp    %eax,(%rdi)
  jle    L19
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    %rbx,%rdi
  cmp    %rbp,%rbx
  jne    L55
L31:
  sub    $0x1,%r12d
  jne    L3
  mov    $0xa,%esi
  mov    %r13,%rdi
  call   <printArr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x38,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int arr[10] = {-3, 7, 1, 5, 9, -11, -13, 11, 13, -5};
  int length = 10;
  printArr(arr, length);
  for (int i = 0; i < length; i++) {
    for (int j = 0; j < length - 1; j++) {
      if (arr[j] > arr[j + 1])
        swap(&arr[j], &arr[j + 1]);
    }
  }
  printArr(arr, length);
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<rxn_coor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L17
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L12
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double rxn_coor(double *a, double *z, int m) {
  double rc;
  int i;
  rc = a[0];
  for (i = 1; i <= m; i = i + 1) {
    rc = rc + z[i] * a[i];
  }
  return rc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rxn_coor>:
  endbr64
  movsd  (%rdi),%xmm1
  test   %edx,%edx
  jle    L1
  lea    0x1(%rdx),%edx
  mov    $0x1,%eax
L17:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L1:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double rxn_coor(double *a, double *z, int m) {
  double rc;
  int i;
  rc = a[0];
  for (i = 1; i <= m; i = i + 1) {
    rc = rc + z[i] * a[i];
  }
  return rc;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rxn_coor>:
  endbr64
  movsd  (%rdi),%xmm1
  test   %edx,%edx
  jle    L3
  add    $0x1,%edx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L9:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L9
L3:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double rxn_coor(double *a, double *z, int m) {
  double rc;
  int i;
  rc = a[0];
  for (i = 1; i <= m; i = i + 1) {
    rc = rc + z[i] * a[i];
  }
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rxn_coor>:
  endbr64
  movsd  (%rdi),%xmm0
  test   %edx,%edx
  jle    L27
  mov    %edx,%r8d
  cmp    $0x1,%edx
  je     L10
  mov    %edx,%eax
  shr    %eax
  lea    -0x1(%rax),%ecx
  mov    $0x8,%eax
  shl    $0x4,%rcx
  add    $0x18,%rcx
  nopl   0x0(%rax,%rax,1)
L18:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rdi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L18
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  lea    0x1(%rax),%edx
  cmp    %r8d,%eax
  je     L27
L10:
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm1
  mulsd  (%rsi,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
L27:
  ret
```

assistant: ```c
double rxn_coor(double *a, double *z, int m) {
  double rc;
  int i;
  rc = a[0];
  for (i = 1; i <= m; i = i + 1) {
    rc = rc + z[i] * a[i];
  }
  return rc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L16:
  mov    $0x0,%eax
  call   <run_test@plt>
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int number_of_tests;
  scanf("%d", &number_of_tests);
  int i;
  for (i = 0; i < number_of_tests; ++i) {
    run_test();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L15
  mov    $0x0,%ebx
L21:
  mov    $0x0,%eax
  call   <run_test@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L21
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int number_of_tests;
  scanf("%d", &number_of_tests);
  int i;
  for (i = 0; i < number_of_tests; ++i) {
    run_test();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L18
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <run_test@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L19
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D4: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int number_of_tests;
  scanf("%d", &number_of_tests);
  int i;
  for (i = 0; i < number_of_tests; ++i) {
    run_test();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L12
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <run_test@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L9
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int number_of_tests;
  scanf("%d", &number_of_tests);
  int i;
  for (i = 0; i < number_of_tests; ++i) {
    run_test();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lseek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L8
  mov    -0x8(%rbp),%rax
  jmp    L11
L8:
  mov    $0xffffffffffffffff,%rax
L11:
  leave
  ret
```

assistant: ```c
off_t lseek(int fildes, off_t offset, int whence) {
  int n;
  off_t tmp;
  n = __infer_nondet_int();
  tmp = __infer_nondet_int();
  if (n > 0)
    return tmp;
  else
    return (off_t)-1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lseek>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  test   %ebx,%ebx
  mov    $0xffffffffffffffff,%rdx
  cmovle %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
off_t lseek(int fildes, off_t offset, int whence) {
  int n;
  off_t tmp;
  n = __infer_nondet_int();
  tmp = __infer_nondet_int();
  if (n > 0)
    return tmp;
  else
    return (off_t)-1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lseek>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  test   %ebx,%ebx
  mov    $0xffffffffffffffff,%rdx
  pop    %rbx
  cmovle %rdx,%rax
  ret
```

assistant: ```c
off_t lseek(int fildes, off_t offset, int whence) {
  int n;
  off_t tmp;
  n = __infer_nondet_int();
  tmp = __infer_nondet_int();
  if (n > 0)
    return tmp;
  else
    return (off_t)-1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lseek>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  test   %ebx,%ebx
  mov    $0xffffffffffffffff,%rdx
  pop    %rbx
  cmovle %rdx,%rax
  ret
```

assistant: ```c
off_t lseek(int fildes, off_t offset, int whence) {
  int n;
  off_t tmp;
  n = __infer_nondet_int();
  tmp = __infer_nondet_int();
  if (n > 0)
    return tmp;
  else
    return (off_t)-1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<util_maxpow2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L37
L22:
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L13:
  shll   -0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L13
  mov    -0x4(%rbp),%eax
  sar    %eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int util_maxpow2(int val) {
  if (val == 1)
    return 0;
  int result = 1;
  while (result <= val)
    result = result << 1;
  return result >> 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<util_maxpow2>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L2
  test   %edi,%edi
  jle    L5
  mov    $0x1,%eax
L8:
  add    %eax,%eax
  cmp    %eax,%edi
  jge    L8
L18:
  sar    %eax
L2:
  ret
L5:
  mov    $0x1,%eax
  jmp    L18
```

assistant: ```c
int util_maxpow2(int val) {
  if (val == 1)
    return 0;
  int result = 1;
  while (result <= val)
    result = result << 1;
  return result >> 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<util_maxpow2>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L6
  test   %edi,%edi
  jle    L6
  mov    $0x1,%eax
  nopl   0x0(%rax)
L21:
  add    %eax,%eax
  cmp    %eax,%edi
  jge    L21
  sar    %eax
L6:
  ret
```

assistant: ```c
int util_maxpow2(int val) {
  if (val == 1)
    return 0;
  int result = 1;
  while (result <= val)
    result = result << 1;
  return result >> 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<util_maxpow2>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L15
  test   %edi,%edi
  jle    L15
  mov    $0x1,%eax
  nopl   0x0(%rax)
L1:
  add    %eax,%eax
  cmp    %eax,%edi
  jge    L1
  sar    %eax
L15:
  ret
```

assistant: ```c
int util_maxpow2(int val) {
  if (val == 1)
    return 0;
  int result = 1;
  while (result <= val)
    result = result << 1;
  return result >> 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hasdirectory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L9
L0:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
L9:
  leave
  ret
```

assistant: ```c
int hasdirectory(char *source, char *result) {
  char *tp2;
  if ((tp2 = strrchr(source, '/')) == NULL)
    return (0);
  strncpy(result, source, tp2 - source + 1);
  result[tp2 - source + 1] = '\0';
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hasdirectory>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x2f,%esi
  call   <strrchr@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  je     L7
  sub    %rbp,%rax
  mov    %rax,%rbx
  lea    0x1(%rax),%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  mov    $0x1,%edx
L7:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int hasdirectory(char *source, char *result) {
  char *tp2;
  if ((tp2 = strrchr(source, '/')) == NULL)
    return (0);
  strncpy(result, source, tp2 - source + 1);
  result[tp2 - source + 1] = '\0';
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hasdirectory>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strrchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L3
  sub    %rbp,%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  lea    0x1(%rax),%edx
  call   <strncpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  mov    $0x1,%r8d
L3:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int hasdirectory(char *source, char *result) {
  char *tp2;
  if ((tp2 = strrchr(source, '/')) == NULL)
    return (0);
  strncpy(result, source, tp2 - source + 1);
  result[tp2 - source + 1] = '\0';
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<hasdirectory>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strrchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L2
  sub    %rbp,%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  lea    0x1(%rax),%edx
  call   <strncpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  mov    $0x1,%r8d
L2:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int hasdirectory(char *source, char *result) {
  char *tp2;
  if ((tp2 = strrchr(source, '/')) == NULL)
    return (0);
  strncpy(result, source, tp2 - source + 1);
  result[tp2 - source + 1] = '\0';
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mknum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L1
L7:
  mov    -0x4(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L1:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mknum(char *s) {
  int len = strlen(s);
  int i, d, n = 0;
  for (i = 0, d = 1; i < len; i++, d *= 10)
    n += (s[len - i - 1] - '0') * d;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mknum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L21
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rcx
  lea    -0x2(%rbx,%rdx,1),%rdi
  lea    -0x1(%rax),%eax
  sub    %rax,%rdi
  mov    $0x0,%esi
  mov    $0x1,%eax
L19:
  movsbl (%rcx),%edx
  sub    $0x30,%edx
  imul   %eax,%edx
  add    %edx,%esi
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L19
L20:
  mov    %esi,%eax
  pop    %rbx
  ret
L21:
  mov    $0x0,%esi
  jmp    L20
```

assistant: ```c
int mknum(char *s) {
  int len = strlen(s);
  int i, d, n = 0;
  for (i = 0, d = 1; i < len; i++, d *= 10)
    n += (s[len - i - 1] - '0') * d;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mknum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  movslq %eax,%rdx
  sub    $0x1,%eax
  xor    %r8d,%r8d
  lea    -0x2(%rbx,%rdx,1),%rsi
  lea    -0x1(%rbx,%rdx,1),%rcx
  sub    %rax,%rsi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L15:
  movsbl (%rcx),%edx
  sub    $0x1,%rcx
  sub    $0x30,%edx
  imul   %eax,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    %edx,%r8d
  cmp    %rsi,%rcx
  jne    L15
  mov    %r8d,%eax
  pop    %rbx
  ret
  nop
L2:
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int mknum(char *s) {
  int len = strlen(s);
  int i, d, n = 0;
  for (i = 0, d = 1; i < len; i++, d *= 10)
    n += (s[len - i - 1] - '0') * d;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mknum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L6
  movslq %eax,%rdx
  sub    $0x1,%eax
  xor    %r8d,%r8d
  lea    -0x2(%rbx,%rdx,1),%rsi
  lea    -0x1(%rbx,%rdx,1),%rcx
  sub    %rax,%rsi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L15:
  movsbl (%rcx),%edx
  sub    $0x1,%rcx
  sub    $0x30,%edx
  imul   %eax,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    %edx,%r8d
  cmp    %rcx,%rsi
  jne    L15
  mov    %r8d,%eax
  pop    %rbx
  ret
  nop
L6:
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int mknum(char *s) {
  int len = strlen(s);
  int i, d, n = 0;
  for (i = 0, d = 1; i < len; i++, d *= 10)
    n += (s[len - i - 1] - '0') * d;
  return n;
}
```