ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_crunch>:
  endbr64
  test   %edi,%edi
  jle    L23
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L2
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,%r13d
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  ret
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D18
data_type: string

tool: D11: 


tool: D18: #

assistant: ```c
void print_crunch(int n) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j <= i; j++) {
      printf("#");
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_sane_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L81
  mov    $0x0,%eax
  jmp    L74
L81:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L53:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L56
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L53
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L56
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L53
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  mov    $0x0,%eax
  jmp    L74
L20:
  mov    -0x18(%rbp),%rax
  mov    $0x1f,%edx
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,D38(%rip)
  movzbl D13(%rip),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,D29(%rip)
  lea    D29(%rip),%rax
L74:
  leave
  ret
```

assistant: ```c
char *get_sane_name(char *name) {
  static char str[32];
  char *cp;
  if (!isalpha(*name))
    return 0;
  for (cp = name; *cp && (isalnum(*cp) || (*cp == ' ' && isalnum(*(cp + 1)))); cp++)
    ;
  if (*cp)
    return 0;
  strncpy(str, name, 32 - 1);
  str[32 - 1] = '\0';
  *str = toupper(*str);
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_sane_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L26
  movzbl 0x0(%rbp),%edi
  mov    %rbp,%rbx
  test   %dil,%dil
  jne    L87
  jmp    L18
L77:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L18
L87:
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L77
  cmpb   $0x20,(%rbx)
  jne    L36
  movsbl 0x1(%rbx),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L77
L36:
  mov    $0x0,%eax
  cmpb   $0x0,(%rbx)
  jne    L73
L18:
  mov    $0x1f,%edx
  mov    %rbp,%rsi
  lea    D33(%rip),%rbx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,D0(%rip)
  movsbl D33(%rip),%edi
  call   <toupper@plt>
  mov    %al,D19(%rip)
  mov    %rbx,%rax
L73:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    $0x0,%eax
  jmp    L73
```

assistant: ```c
char *get_sane_name(char *name) {
  static char str[32];
  char *cp;
  if (!isalpha(*name))
    return 0;
  for (cp = name; *cp && (isalnum(*cp) || (*cp == ' ' && isalnum(*(cp + 1)))); cp++)
    ;
  if (*cp)
    return 0;
  strncpy(str, name, 32 - 1);
  str[32 - 1] = '\0';
  *str = toupper(*str);
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_sane_name>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L15
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%rbx
  test   %dil,%dil
  je     L37
  nopl   (%rax)
L46:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L48
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L18
  movsbl 0x1(%rbx),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L55
L48:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L46
L37:
  lea    D33(%rip),%rbx
  mov    %rbp,%rsi
  mov    $0x1f,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movsbl D33(%rip),%edi
  movb   $0x0,D24(%rip)
  call   <toupper@plt>
  mov    %al,D4(%rip)
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L55:
  movzbl (%rbx),%eax
L18:
  test   %al,%al
  je     L37
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *get_sane_name(char *name) {
  static char str[32];
  char *cp;
  if (!isalpha(*name))
    return 0;
  for (cp = name; *cp && (isalnum(*cp) || (*cp == ' ' && isalnum(*(cp + 1)))); cp++)
    ;
  if (*cp)
    return 0;
  strncpy(str, name, 32 - 1);
  str[32 - 1] = '\0';
  *str = toupper(*str);
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_sane_name>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L53
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%rbx
  test   %dil,%dil
  je     L43
  nopl   (%rax)
L18:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L4
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L55
  movsbl 0x1(%rbx),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L24
L4:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L18
L43:
  lea    D16(%rip),%rbx
  mov    %rbp,%rsi
  mov    $0x1f,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movsbl D16(%rip),%edi
  movb   $0x0,D36(%rip)
  call   <toupper@plt>
  mov    %al,D30(%rip)
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L24:
  movzbl (%rbx),%eax
L55:
  test   %al,%al
  je     L43
L53:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *get_sane_name(char *name) {
  static char str[32];
  char *cp;
  if (!isalpha(*name))
    return 0;
  for (cp = name; *cp && (isalnum(*cp) || (*cp == ' ' && isalnum(*(cp + 1)))); cp++)
    ;
  if (*cp)
    return 0;
  strncpy(str, name, 32 - 1);
  str[32 - 1] = '\0';
  *str = toupper(*str);
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<validate_ipv6net_negate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x48(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L6
L5:
  lea    -0x40(%rbp),%rax
  mov    $0x2b,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L21
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <validate_ipv6net@plt>
  jmp    L6
L21:
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <validate_ipv6net@plt>
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: !%43s

assistant: ```c
int validate_ipv6net_negate(const char *str) {
  if (!str)
    return 0;
  char ipv6net[43];
  memset(ipv6net, '\0', 43);
  if (sscanf(str, "!%43s", ipv6net) != 1)
    return validate_ipv6net(str);
  return validate_ipv6net(ipv6net);
}
```
user: What is the c source code of the assembly code below?

```asm
<validate_ipv6net_negate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L28
  mov    %rdi,%rbx
  mov    %rsp,%rbp
  mov    $0x2b,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L24
  mov    %rbx,%rdi
  call   <validate_ipv6net@plt>
L28:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    %rsp,%rdi
  call   <validate_ipv6net@plt>
  jmp    L28
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: !%43s

assistant: ```c
int validate_ipv6net_negate(const char *str) {
  if (!str)
    return 0;
  char ipv6net[43];
  memset(ipv6net, '\0', 43);
  if (sscanf(str, "!%43s", ipv6net) != 1)
    return validate_ipv6net(str);
  return validate_ipv6net(ipv6net);
}
```
user: Translate the below assembly code into C programming language:

```asm
<validate_ipv6net_negate>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L3
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    %rdi,%rbp
  mov    $0x2b,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L1
  mov    %rbp,%rdi
  call   <validate_ipv6net@plt>
L3:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    %r12,%rdi
  call   <validate_ipv6net@plt>
  jmp    L3
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: !%43s

assistant: ```c
int validate_ipv6net_negate(const char *str) {
  if (!str)
    return 0;
  char ipv6net[43];
  memset(ipv6net, '\0', 43);
  if (sscanf(str, "!%43s", ipv6net) != 1)
    return validate_ipv6net(str);
  return validate_ipv6net(ipv6net);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<validate_ipv6net_negate>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L9
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    %rdi,%rbp
  mov    $0x2b,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L12
  mov    %rbp,%rdi
  call   <validate_ipv6net@plt>
L9:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  mov    %r12,%rdi
  call   <validate_ipv6net@plt>
  jmp    L9
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: !%43s

assistant: ```c
int validate_ipv6net_negate(const char *str) {
  if (!str)
    return 0;
  char ipv6net[43];
  memset(ipv6net, '\0', 43);
  if (sscanf(str, "!%43s", ipv6net) != 1)
    return validate_ipv6net(str);
  return validate_ipv6net(ipv6net);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<upper_case>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x20,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int upper_case(int l) {
  int upper_letter = l - 32;
  return upper_letter;
}
```
user: Translate the below assembly code into C programming language:

```asm
<upper_case>:
  endbr64
  lea    -0x20(%rdi),%eax
  ret
```

assistant: ```c
int upper_case(int l) {
  int upper_letter = l - 32;
  return upper_letter;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<upper_case>:
  endbr64
  lea    -0x20(%rdi),%eax
  ret
```

assistant: ```c
int upper_case(int l) {
  int upper_letter = l - 32;
  return upper_letter;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<upper_case>:
  endbr64
  lea    -0x20(%rdi),%eax
  ret
```

assistant: ```c
int upper_case(int l) {
  int upper_letter = l - 32;
  return upper_letter;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L7
L39:
  movl   $0x2,-0x8(%rbp)
  jmp    L5
L58:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L19
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L58
  jmp    L16
L19:
  nop
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L13
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L39
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D14: 
Prime number from %d to %d:-


tool: D16: %d	

tool: D4: 
Total prime numbers between %d and %d is %d

assistant: ```c
void prime(int start, int end) {
  int i;
  int j;
  int counter = 0;
  printf("\nPrime number from %d to %d:-\n", start, end);
  for (i = start; i < end; i++) {
    for (j = 2; j < i; j++) {
      if ((i % j) == 0) {
        break;
      }
    }
    if (i == j) {
      printf("%d\t", i);
      counter++;
    }
  }
  printf("\nTotal prime numbers between %d and %d is %d", start, end, counter);
}
```
user: What is the c source code of the assembly code below?

```asm
<prime>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%ebx
  mov    $0x0,%r13d
  lea    D3(%rip),%r14
  cmp    %ebp,%r12d
  jl     L41
L27:
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L67:
  je     L56
L33:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L27
L41:
  cmp    $0x2,%ebx
  jle    L67
  test   $0x1,%bl
  je     L33
  mov    $0x2,%ecx
L78:
  add    $0x1,%ecx
  cmp    %ebx,%ecx
  je     L56
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L78
  jmp    L33
L56:
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r13d
  jmp    L33
```

tool_calls: name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D4
type_guessed: string

tool: D15: 
Prime number from %d to %d:-


tool: D3: %d	

tool: D4: 
Total prime numbers between %d and %d is %d

assistant: ```c
void prime(int start, int end) {
  int i;
  int j;
  int counter = 0;
  printf("\nPrime number from %d to %d:-\n", start, end);
  for (i = start; i < end; i++) {
    for (j = 2; j < i; j++) {
      if ((i % j) == 0) {
        break;
      }
    }
    if (i == j) {
      printf("%d\t", i);
      counter++;
    }
  }
  printf("\nTotal prime numbers between %d and %d is %d", start, end, counter);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prime>:
  endbr64
  push   %r14
  mov    %esi,%edx
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  mov    %esi,%r13d
  mov    %edi,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D22(%rip),%rdi
  push   %rbx
  mov    %ebp,%r12d
  lea    D28(%rip),%rbx
  call   <printf@plt>
  cmp    %r13d,%ebp
  jge    L2
  nopl   (%rax)
L75:
  cmp    $0x2,%r12d
  jle    L14
  test   $0x1,%r12b
  je     L70
  mov    $0x2,%ecx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L48:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L70
L15:
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jne    L48
L59:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <printf@plt>
L70:
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  jne    L75
L2:
  pop    %rbx
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
L14:
  jne    L70
  jmp    L59
```

tool_calls: name: disassemble_data
arguments: tag: D22
datatype: string
name: disassemble_data
arguments: tag: D28
datatype: string
name: disassemble_data
arguments: tag: D12
datatype: string

tool: D22: 
Prime number from %d to %d:-


tool: D28: %d	

tool: D12: 
Total prime numbers between %d and %d is %d

assistant: ```c
void prime(int start, int end) {
  int i;
  int j;
  int counter = 0;
  printf("\nPrime number from %d to %d:-\n", start, end);
  for (i = start; i < end; i++) {
    for (j = 2; j < i; j++) {
      if ((i % j) == 0) {
        break;
      }
    }
    if (i == j) {
      printf("%d\t", i);
      counter++;
    }
  }
  printf("\nTotal prime numbers between %d and %d is %d", start, end, counter);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prime>:
  endbr64
  push   %r14
  mov    %esi,%edx
  xor    %eax,%eax
  push   %r13
  mov    %esi,%r13d
  mov    %edi,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  cmp    %r13d,%ebp
  jge    L20
  cmp    $0x2,%ebp
  jle    L75
  mov    %ebp,%r12d
  xor    %r14d,%r14d
L29:
  lea    D28(%rip),%rbx
  xchg   %ax,%ax
L8:
  test   $0x1,%r12b
  je     L33
  mov    $0x2,%ecx
  jmp    L64
  nopl   (%rax)
L14:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L33
L64:
  add    $0x1,%ecx
  cmp    %ecx,%r12d
  jg     L14
  jne    L33
  mov    %r12d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <printf@plt>
L33:
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  jg     L8
L48:
  pop    %rbx
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L75:
  lea    -0x1(%r13),%eax
  mov    $0x2,%edx
  mov    %ebp,%r12d
  cmp    %edx,%eax
  cmovg  %edx,%eax
  nopl   0x0(%rax)
L71:
  cmp    $0x2,%r12d
  je     L90
  add    $0x1,%r12d
  cmp    %eax,%r12d
  jle    L71
  xor    %r14d,%r14d
L135:
  cmp    %r13d,%r12d
  jl     L29
  jmp    L48
  nopl   (%rax)
L90:
  mov    $0x2,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  mov    $0x3,%r12d
  call   <printf@plt>
  mov    $0x1,%r14d
  jmp    L135
L20:
  xor    %r14d,%r14d
  jmp    L48
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D28
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string

tool: D1: 
Prime number from %d to %d:-


tool: D28: %d	

tool: D9: 
Total prime numbers between %d and %d is %d

assistant: ```c
void prime(int start, int end) {
  int i;
  int j;
  int counter = 0;
  printf("\nPrime number from %d to %d:-\n", start, end);
  for (i = start; i < end; i++) {
    for (j = 2; j < i; j++) {
      if ((i % j) == 0) {
        break;
      }
    }
    if (i == j) {
      printf("%d\t", i);
      counter++;
    }
  }
  printf("\nTotal prime numbers between %d and %d is %d", start, end, counter);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EratosthenesSieve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x2,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L36:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x24(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  ja     L36
  movl   $0x2,-0x14(%rbp)
  jmp    L16
L38:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L28
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L66
L12:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L66:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  ja     L12
L28:
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L38
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *EratosthenesSieve(unsigned int num) {
  int i = 0, j = 0, k = 0;
  int *sieve = malloc(sizeof(int) * (num - 2));
  for (i = 0; i < (num - 2); i++) {
    sieve[i] = 1;
  }
  for (i = 2; i < sqrt(num); i++) {
    if (sieve[i - 2] == 1) {
      k = 0;
      j = (pow(i, 2) + k * i);
      while (j < num) {
        sieve[j - 2] = 0;
        k++;
        j = (pow(i, 2) + k * i);
      }
    }
  }
  return sieve;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EratosthenesSieve>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  lea    -0x2(%rdi),%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  je     L14
  lea    -0x2(%rbp),%edx
  lea    (%rax,%rdx,4),%rdx
L56:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L56
L14:
  mov    $0x2,%ebx
  jmp    L20
L13:
  add    $0x1,%rbx
L20:
  mov    %ebx,%r15d
  mov    %ebx,%r14d
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jle    L41
  cmpl   $0x1,-0x8(%r12,%rbx,4)
  jne    L13
  mov    $0x2,%esi
  mov    %r14d,%edi
  call   <pow@plt>
  cmp    %eax,%ebp
  jbe    L13
  mov    %r15d,%r13d
L40:
  cltq
  movl   $0x0,-0x8(%r12,%rax,4)
  mov    $0x2,%esi
  mov    %r14d,%edi
  call   <pow@plt>
  add    %r13d,%eax
  add    %r15d,%r13d
  cmp    %ebp,%eax
  jb     L40
  jmp    L13
L41:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *EratosthenesSieve(unsigned int num) {
  int i = 0, j = 0, k = 0;
  int *sieve = malloc(sizeof(int) * (num - 2));
  for (i = 0; i < (num - 2); i++) {
    sieve[i] = 1;
  }
  for (i = 2; i < sqrt(num); i++) {
    if (sieve[i - 2] == 1) {
      k = 0;
      j = (pow(i, 2) + k * i);
      while (j < num) {
        sieve[j - 2] = 0;
        k++;
        j = (pow(i, 2) + k * i);
      }
    }
  }
  return sieve;
}
```