ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<get_damage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmpb   $0x0,(%rdi)
  mov    %esi,0xc(%rsp)
  je     L82
  mov    %rdi,%r15
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L114:
  xor    %eax,%eax
  call   <get_number@plt>
  mov    %eax,%ebp
  lea    0x1(%r13),%eax
  cltq
  nop
L100:
  mov    %eax,%esi
  mov    %eax,%r13d
  add    $0x1,%rax
  cmpb   $0x64,-0x2(%r15,%rax,1)
  jne    L100
  movslq %esi,%r8
  xor    %eax,%eax
  mov    %esi,0x8(%rsp)
  lea    (%r15,%r8,1),%rbx
  mov    %r8,(%rsp)
  mov    %rbx,%rdi
  call   <get_number@plt>
  movzbl (%rbx),%edx
  mov    %eax,%r14d
  cmp    $0x2f,%dl
  je     L97
  test   %dl,%dl
  je     L97
  mov    (%rsp),%r8
  mov    0x8(%rsp),%esi
  lea    0x1(%r15,%r8,1),%rax
  add    $0x1,%esi
  sub    %eax,%esi
  nopl   0x0(%rax,%rax,1)
L36:
  movzbl (%rax),%edx
  lea    (%rsi,%rax,1),%r13d
  mov    %rax,%rbx
  add    $0x1,%rax
  cmp    $0x2f,%dl
  je     L97
  test   %dl,%dl
  jne    L36
L97:
  test   %ebp,%ebp
  jle    L41
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L69
  lea    -0x1(%rbp),%eax
  add    %r14d,%r12d
  imul   %r14d,%eax
  add    %eax,%r12d
L25:
  movzbl (%rbx),%edx
L41:
  xor    %eax,%eax
  cmp    $0x2f,%dl
  sete   %al
  add    %eax,%r13d
  movslq %r13d,%rdi
  add    %r15,%rdi
  cmpb   $0x0,(%rdi)
  jne    L114
L51:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L69:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L93:
  mov    %r14d,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  mov    %edx,(%rsp)
  call   <get_rand@plt>
  mov    (%rsp),%edx
  add    %eax,%r12d
  add    $0x1,%edx
  cmp    %edx,%ebp
  jne    L93
  jmp    L25
L82:
  xor    %r12d,%r12d
  jmp    L51
```

assistant: ```c
int get_damage(ds, r)
char *ds;
int r;
{
  register int i = 0, j, n, d, total = 0;
  while (ds[i]) {
    n = get_number(ds + i);
    while (ds[i++] != 'd')
      ;
    d = get_number(ds + i);
    while ((ds[i] != '/') && ds[i])
      i++;
    for (j = 0; j < n; j++) {
      if (r) {
        total += get_rand(1, d);
      } else {
        total += d;
      }
    }
    if (ds[i] == '/') {
      i++;
    }
  }
  return (total);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ifconfigSplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  mov    0x10(%rbp),%eax
  mov    %al,-0x38(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x34(%rbp)
  jle    L88
  mov    $0x0,%eax
  jmp    L69
L88:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L65
L77:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x38(%rbp)
  jne    L79
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L30
L79:
  addl   $0x1,-0x8(%rbp)
L65:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L77
L30:
  cmpl   $0x0,-0x4(%rbp)
  jg     L37
  mov    $0x0,%eax
  jmp    L69
L37:
  mov    -0x4(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ifconfigCheckCopyInput@plt>
  test   %eax,%eax
  jne    L114
  mov    $0x0,%eax
  jmp    L69
L114:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ifconfigCheckCopyInput@plt>
  test   %eax,%eax
  jne    L11
  mov    $0x0,%eax
  jmp    L69
L11:
  mov    $0x1,%eax
L69:
  leave
  ret
```

assistant: ```c
int ifconfigSplit(char *a_out, const int a_len, char *b_out, const int b_len, const char *in, const int in_len, const char split_char) {
  int i;
  int s;
  if ((a_len + 1 + b_len) < in_len)
    return 0;
  i = 0;
  s = 0;
  while (i < in_len) {
    if (in[i] == split_char) {
      s = i;
      break;
    }
    i++;
  }
  if (!(s > 0))
    return 0;
  if (!ifconfigCheckCopyInput(a_out, a_len, &in[0], s))
    return 0;
  if (!ifconfigCheckCopyInput(b_out, b_len, &in[(s + 1)], (in_len - (s + 1))))
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ifconfigSplit>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r13
  mov    %ecx,%r12d
  movzbl 0x30(%rsp),%ecx
  lea    0x1(%rsi,%r12,1),%edx
  mov    $0x0,%eax
  cmp    %r9d,%edx
  jl     L29
  mov    %esi,%r10d
  mov    %r8,%rbx
  mov    %r9d,%ebp
  test   %r9d,%r9d
  jle    L44
  lea    -0x1(%r9),%esi
  mov    $0x0,%eax
  jmp    L12
L46:
  mov    %rdx,%rax
L12:
  mov    %eax,%r14d
  cmp    %cl,(%rbx,%rax,1)
  je     L38
  lea    0x1(%rax),%rdx
  cmp    %rsi,%rax
  jne    L46
  mov    $0x0,%eax
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  test   %eax,%eax
  jle    L65
  mov    %eax,%ecx
  mov    %rbx,%rdx
  mov    %r10d,%esi
  call   <ifconfigCheckCopyInput@plt>
  test   %eax,%eax
  je     L29
  lea    0x1(%r14),%eax
  mov    %ebp,%ecx
  sub    %eax,%ecx
  movslq %r14d,%r14
  lea    0x1(%rbx,%r14,1),%rdx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <ifconfigCheckCopyInput@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L29
L44:
  mov    $0x0,%eax
  jmp    L29
L65:
  mov    $0x0,%eax
  jmp    L29
```

assistant: ```c
int ifconfigSplit(char *a_out, const int a_len, char *b_out, const int b_len, const char *in, const int in_len, const char split_char) {
  int i;
  int s;
  if ((a_len + 1 + b_len) < in_len)
    return 0;
  i = 0;
  s = 0;
  while (i < in_len) {
    if (in[i] == split_char) {
      s = i;
      break;
    }
    i++;
  }
  if (!(s > 0))
    return 0;
  if (!ifconfigCheckCopyInput(a_out, a_len, &in[0], s))
    return 0;
  if (!ifconfigCheckCopyInput(b_out, b_len, &in[(s + 1)], (in_len - (s + 1))))
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ifconfigSplit>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  lea    0x1(%rsi,%rcx,1),%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl 0x40(%rsp),%eax
  cmp    %r9d,%edx
  jl     L23
  mov    %r9d,%r15d
  test   %r9d,%r9d
  jle    L23
  mov    %ecx,%r13d
  mov    %r8,%rbp
  movslq %r9d,%rdx
  xor    %ebx,%ebx
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L58:
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  je     L23
L29:
  mov    %ebx,%r12d
  cmp    %al,0x0(%rbp,%rbx,1)
  jne    L58
  test   %ebx,%ebx
  je     L23
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  call   <ifconfigCheckCopyInput@plt>
  test   %eax,%eax
  jne    L63
L23:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L63:
  add    $0x1,%r12d
  mov    %r15d,%ecx
  lea    0x1(%rbp,%rbx,1),%rdx
  mov    %r13d,%esi
  sub    %r12d,%ecx
  mov    %r14,%rdi
  call   <ifconfigCheckCopyInput@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ifconfigSplit(char *a_out, const int a_len, char *b_out, const int b_len, const char *in, const int in_len, const char split_char) {
  int i;
  int s;
  if ((a_len + 1 + b_len) < in_len)
    return 0;
  i = 0;
  s = 0;
  while (i < in_len) {
    if (in[i] == split_char) {
      s = i;
      break;
    }
    i++;
  }
  if (!(s > 0))
    return 0;
  if (!ifconfigCheckCopyInput(a_out, a_len, &in[0], s))
    return 0;
  if (!ifconfigCheckCopyInput(b_out, b_len, &in[(s + 1)], (in_len - (s + 1))))
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ifconfigSplit>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  lea    0x1(%rsi,%rcx,1),%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl 0x40(%rsp),%eax
  cmp    %r9d,%edx
  jl     L22
  mov    %r9d,%r15d
  test   %r9d,%r9d
  jle    L22
  mov    %ecx,%r13d
  mov    %r8,%rbp
  movslq %r9d,%rdx
  xor    %ebx,%ebx
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  je     L22
L32:
  mov    %ebx,%r12d
  cmp    %al,0x0(%rbp,%rbx,1)
  jne    L7
  test   %ebx,%ebx
  je     L22
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  call   <ifconfigCheckCopyInput@plt>
  test   %eax,%eax
  jne    L33
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L33:
  add    $0x1,%r12d
  mov    %r15d,%ecx
  lea    0x1(%rbp,%rbx,1),%rdx
  mov    %r13d,%esi
  sub    %r12d,%ecx
  mov    %r14,%rdi
  call   <ifconfigCheckCopyInput@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ifconfigSplit(char *a_out, const int a_len, char *b_out, const int b_len, const char *in, const int in_len, const char split_char) {
  int i;
  int s;
  if ((a_len + 1 + b_len) < in_len)
    return 0;
  i = 0;
  s = 0;
  while (i < in_len) {
    if (in[i] == split_char) {
      s = i;
      break;
    }
    i++;
  }
  if (!(s > 0))
    return 0;
  if (!ifconfigCheckCopyInput(a_out, a_len, &in[0], s))
    return 0;
  if (!ifconfigCheckCopyInput(b_out, b_len, &in[(s + 1)], (in_len - (s + 1))))
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<loadFileSectors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x6(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L18
  mov    -0x8(%rbp),%eax
  shl    $0x9,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <readSector@plt>
  addl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x19,-0x8(%rbp)
  jle    L19
  jmp    L1
L18:
  nop
L1:
  leave
  ret
```

assistant: ```c
void loadFileSectors(char *buffer, char *dir) {
  int sector, curSector;
  for (sector = 0; sector < (32 - 6); sector++) {
    curSector = *(dir + 6 + sector);
    if (curSector != 0x00) {
      readSector(buffer + 512 * sector, curSector);
    } else {
      return;
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<loadFileSectors>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x6(%rsi),%rbp
  mov    %rdi,%rbx
  lea    0x3400(%rdi),%r12
L13:
  movsbl 0x0(%rbp),%esi
  test   %esi,%esi
  je     L0
  mov    %rbx,%rdi
  call   <readSector@plt>
  add    $0x1,%rbp
  add    $0x200,%rbx
  cmp    %r12,%rbx
  jne    L13
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void loadFileSectors(char *buffer, char *dir) {
  int sector, curSector;
  for (sector = 0; sector < (32 - 6); sector++) {
    curSector = *(dir + 6 + sector);
    if (curSector != 0x00) {
      readSector(buffer + 512 * sector, curSector);
    } else {
      return;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loadFileSectors>:
  endbr64
  push   %r12
  lea    0x3400(%rdi),%r12
  push   %rbp
  lea    0x6(%rsi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdi
  add    $0x200,%rbx
  add    $0x1,%rbp
  call   <readSector@plt>
  cmp    %r12,%rbx
  je     L23
L14:
  movsbl 0x0(%rbp),%esi
  test   %esi,%esi
  jne    L2
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void loadFileSectors(char *buffer, char *dir) {
  int sector, curSector;
  for (sector = 0; sector < (32 - 6); sector++) {
    curSector = *(dir + 6 + sector);
    if (curSector != 0x00) {
      readSector(buffer + 512 * sector, curSector);
    } else {
      return;
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<loadFileSectors>:
  endbr64
  push   %r12
  lea    0x3400(%rdi),%r12
  push   %rbp
  lea    0x6(%rsi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rbx,%rdi
  add    $0x200,%rbx
  add    $0x1,%rbp
  call   <readSector@plt>
  cmp    %r12,%rbx
  je     L29
L26:
  movsbl 0x0(%rbp),%esi
  test   %esi,%esi
  jne    L12
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void loadFileSectors(char *buffer, char *dir) {
  int sector, curSector;
  for (sector = 0; sector < (32 - 6); sector++) {
    curSector = *(dir + 6 + sector);
    if (curSector != 0x00) {
      readSector(buffer + 512 * sector, curSector);
    } else {
      return;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<search>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L27
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L100
  mov    $0x0,%edx
  jmp    L23
L11:
  cmp    %r8d,%ecx
  jle    L68
  lea    -0x1(%rax),%esi
L186:
  cmp    %esi,%edx
  jge    L175
L23:
  lea    (%rdx,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %r8d,%ecx
  je     L181
  movslq %edx,%r9
  mov    (%rdi,%r9,4),%r10d
  movslq %esi,%r9
  mov    (%rdi,%r9,4),%r9d
  cmp    %r9d,%r10d
  jl     L11
  cmp    %r9d,%ecx
  jl     L189
  cmp    %r8d,%ecx
  jge    L74
  lea    0x1(%rax),%edx
  jmp    L186
L68:
  lea    0x1(%rax),%edx
  jmp    L186
L189:
  cmp    %r8d,%ecx
  jle    L121
  lea    -0x1(%rax),%esi
  jmp    L186
L121:
  cmp    %r8d,%r9d
  jl     L53
  lea    0x1(%rax),%edx
  jmp    L186
L53:
  lea    -0x1(%rax),%esi
  jmp    L186
L74:
  cmp    %r8d,%r10d
  jg     L163
  lea    -0x1(%rax),%esi
  jmp    L186
L163:
  lea    0x1(%rax),%edx
  jmp    L186
L100:
  mov    $0x0,%edx
L175:
  movslq %edx,%rax
  cmp    %r8d,(%rdi,%rax,4)
  mov    $0xffffffff,%r9d
  cmove  %edx,%r9d
L181:
  mov    %r9d,%eax
  ret
L27:
  mov    $0xffffffff,%r9d
  jmp    L181
```

assistant: ```c
int search(int *nums, int numsSize, int target) {
  if (numsSize <= 0)
    return (-1);
  int left = 0, right = numsSize - 1;
  while (left < right) {
    int mid = (left + right) / 2;
    if (nums[mid] == target)
      return (mid);
    if (nums[left] < nums[right]) {
      if (nums[mid] > target)
        right = mid - 1;
      else
        left = mid + 1;
      continue;
    }
    if (nums[mid] < nums[right]) {
      if (target < nums[mid])
        right = mid - 1;
      else if (target <= nums[right])
        left = mid + 1;
      else
        right = mid - 1;
      continue;
    }
    if (target > nums[mid])
      left = mid + 1;
    else if (target >= nums[left])
      right = mid - 1;
    else
      left = mid + 1;
  }
  return (nums[left] == target ? left : -1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<search>:
  endbr64
  mov    %rdi,%r8
  test   %esi,%esi
  jle    L31
  sub    $0x1,%esi
  je     L100
  xor    %ecx,%ecx
  jmp    L95
  nopl   0x0(%rax)
L17:
  cmp    %r9d,%edi
  jl     L81
  cmp    %edx,%edi
  jl     L126
  cmp    %edx,%r10d
  jg     L126
L148:
  lea    -0x1(%rax),%esi
  cmp    %esi,%ecx
  jge    L146
L95:
  lea    (%rsi,%rcx,1),%eax
  sar    %eax
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  cmp    %edx,%edi
  je     L21
  movslq %ecx,%r9
  mov    (%r8,%r9,4),%r10d
  movslq %esi,%r9
  mov    (%r8,%r9,4),%r9d
  cmp    %r9d,%r10d
  jge    L17
  cmp    %edx,%edi
  jg     L148
L126:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jl     L95
L146:
  movslq %ecx,%rax
  lea    (%r8,%rax,4),%r8
  mov    %ecx,%eax
L70:
  cmp    %edx,(%r8)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
L81:
  cmp    %edx,%edi
  jg     L148
  cmp    %edx,%r9d
  jl     L148
  jmp    L126
L31:
  mov    $0xffffffff,%eax
L21:
  ret
L100:
  xor    %eax,%eax
  jmp    L70
```

assistant: ```c
int search(int *nums, int numsSize, int target) {
  if (numsSize <= 0)
    return (-1);
  int left = 0, right = numsSize - 1;
  while (left < right) {
    int mid = (left + right) / 2;
    if (nums[mid] == target)
      return (mid);
    if (nums[left] < nums[right]) {
      if (nums[mid] > target)
        right = mid - 1;
      else
        left = mid + 1;
      continue;
    }
    if (nums[mid] < nums[right]) {
      if (target < nums[mid])
        right = mid - 1;
      else if (target <= nums[right])
        left = mid + 1;
      else
        right = mid - 1;
      continue;
    }
    if (target > nums[mid])
      left = mid + 1;
    else if (target >= nums[left])
      right = mid - 1;
    else
      left = mid + 1;
  }
  return (nums[left] == target ? left : -1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<search>:
  endbr64
  mov    %rdi,%r8
  test   %esi,%esi
  jle    L69
  sub    $0x1,%esi
  je     L114
  xor    %ecx,%ecx
  jmp    L126
  nopl   0x0(%rax)
L9:
  cmp    %r9d,%edi
  jl     L6
  cmp    %edx,%edi
  jl     L125
  cmp    %edx,%r10d
  jg     L125
L28:
  lea    -0x1(%rax),%esi
  cmp    %esi,%ecx
  jge    L31
L126:
  lea    (%rsi,%rcx,1),%eax
  sar    %eax
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  cmp    %edx,%edi
  je     L17
  movslq %ecx,%r9
  mov    (%r8,%r9,4),%r10d
  movslq %esi,%r9
  mov    (%r8,%r9,4),%r9d
  cmp    %r9d,%r10d
  jge    L9
  cmp    %edx,%edi
  jg     L28
L125:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jl     L126
L31:
  movslq %ecx,%rax
  lea    (%r8,%rax,4),%r8
  mov    %ecx,%eax
L91:
  cmp    %edx,(%r8)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
L6:
  cmp    %edx,%edi
  jg     L28
  cmp    %edx,%r9d
  jl     L28
  jmp    L125
L69:
  mov    $0xffffffff,%eax
L17:
  ret
L114:
  xor    %eax,%eax
  jmp    L91
```

assistant: ```c
int search(int *nums, int numsSize, int target) {
  if (numsSize <= 0)
    return (-1);
  int left = 0, right = numsSize - 1;
  while (left < right) {
    int mid = (left + right) / 2;
    if (nums[mid] == target)
      return (mid);
    if (nums[left] < nums[right]) {
      if (nums[mid] > target)
        right = mid - 1;
      else
        left = mid + 1;
      continue;
    }
    if (nums[mid] < nums[right]) {
      if (target < nums[mid])
        right = mid - 1;
      else if (target <= nums[right])
        left = mid + 1;
      else
        right = mid - 1;
      continue;
    }
    if (target > nums[mid])
      left = mid + 1;
    else if (target >= nums[left])
      right = mid - 1;
    else
      left = mid + 1;
  }
  return (nums[left] == target ? left : -1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<evl_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t evl_memcpy(void *dest, const void *src, size_t n) {
  size_t nb = n;
  memcpy(dest, src, nb);
  return nb;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<evl_memcpy>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t evl_memcpy(void *dest, const void *src, size_t n) {
  size_t nb = n;
  memcpy(dest, src, nb);
  return nb;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<evl_memcpy>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t evl_memcpy(void *dest, const void *src, size_t n) {
  size_t nb = n;
  memcpy(dest, src, nb);
  return nb;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<evl_memcpy>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t evl_memcpy(void *dest, const void *src, size_t n) {
  size_t nb = n;
  memcpy(dest, src, nb);
  return nb;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test3(void) {
  struct test4 {
    int i;
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3(void) {
  struct test4 {
    int i;
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3(void) {
  struct test4 {
    int i;
  };
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3(void) {
  struct test4 {
    int i;
  };
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<enDES>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  movl   $0x80,0x89(%rsp)
  movw   $0x0,0x8d(%rsp)
  movb   $0x0,0x8f(%rsp)
  test   %rdi,%rdi
  je     L77
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8,%r14
  test   %rcx,%rcx
  je     L77
  test   %rdx,%rdx
  sete   %al
  test   %r8,%r8
  sete   %dl
  or     %dl,%al
  jne    L87
  test   %esi,%esi
  je     L87
  mov    %esi,%r15d
  shr    $0x3,%r15d
  mov    %esi,%eax
  and    $0x7,%eax
  jne    L29
L13:
  shl    $0x3,%r15d
  mov    %r15d,(%r14)
  movb   $0x0,0x90(%rsp)
  movb   $0x0,0x91(%rsp)
  movb   $0x0,0x92(%rsp)
  movb   $0x0,0x93(%rsp)
  movb   $0x0,0x94(%rsp)
  movb   $0x0,0x95(%rsp)
  movb   $0x0,0x96(%rsp)
  movb   $0x0,0x97(%rsp)
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <genKey@plt>
  mov    %rsp,%r13
  mov    $0x1,%eax
  test   %ebp,%ebp
  jg     L66
  jmp    L30
L29:
  mov    $0x8,%edx
  sub    %eax,%edx
  lea    0x89(%rsp),%rsi
  mov    %ebp,%edi
  add    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x1,%r15d
  jmp    L13
L73:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x90(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L73
L120:
  lea    0x90(%rsp),%rdi
  mov    $0x1,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <comDES@plt>
  add    $0x8,%rbx
  add    $0x8,%r12
  sub    $0x8,%ebp
  test   %ebp,%ebp
  jle    L146
L66:
  movb   $0x0,0x90(%rsp)
  movb   $0x0,0x91(%rsp)
  movb   $0x0,0x92(%rsp)
  movb   $0x0,0x93(%rsp)
  movb   $0x0,0x94(%rsp)
  movb   $0x0,0x95(%rsp)
  movb   $0x0,0x96(%rsp)
  movb   $0x0,0x97(%rsp)
  mov    $0x8,%ecx
  cmp    %ecx,%ebp
  cmovle %ebp,%ecx
  mov    $0x0,%eax
  test   %ebp,%ebp
  jg     L73
  jmp    L120
L77:
  mov    $0x0,%eax
  jmp    L30
L87:
  mov    $0x0,%eax
L30:
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L146:
  mov    $0x1,%eax
  jmp    L30
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char enDES(unsigned char *indata, unsigned int inlen, unsigned char *key, unsigned char *outdata, unsigned int *outlen) {
  unsigned char *p, *p1, s_key[16][8], tt[8];
  int tlen = 0, i = 0, ttlen = 0;
  unsigned char padding[7] = {0x80, 0, 0, 0, 0, 0, 0};
  if ((indata == NULL) || (outdata == NULL) || (key == NULL) || (outlen == NULL) || (inlen <= 0))
    return 0;
  p = indata;
  tlen = inlen / 8;
  if (inlen % 8 != 0) {
    memcpy(indata + inlen, padding, 8 - (inlen % 8));
    tlen = tlen + 1;
  }
  tlen = tlen * 8;
  *outlen = tlen;
  p1 = outdata;
  tlen = inlen;
  for (i = 0; i < 8; i++)
    tt[i] = 0;
  genKey(key, s_key);
  while (tlen > 0) {
    for (i = 0; i < 8; i++)
      tt[i] = 0;
    ttlen = (tlen < 8) ? tlen : 8;
    for (i = 0; i < ttlen; i++)
      tt[i] = *(p + i);
    comDES(tt, p1, s_key, 1);
    p = p + 8;
    p1 = p1 + 8;
    tlen = tlen - 8;
  }
  return 1;
}
```