ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<time_getcontext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L17:
  movl   $0x0,-0x14(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <getcontext@plt>
  endbr64
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  je     L38
  movl   $0x1,-0x14(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <setcontext@plt>
  jmp    L21
L38:
  nop
L21:
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
void time_getcontext(int count) {
  int i;
  volatile int ret;
  ucontext_t uc;
  for (i = 0; i < count; i++) {
    ret = 0;
    getcontext(&uc);
    if (ret == 1)
      continue;
    ret = 1;
    setcontext(&uc);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<time_getcontext>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L26
  movl   $0x0,0x8(%rsp)
  lea    0x14(%rsp),%rax
  mov    %rax,(%rsp)
  jmp    L0
L15:
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  je     L26
L0:
  movl   $0x0,0x10(%rsp)
  mov    (%rsp),%rdi
  call   <getcontext@plt>
  endbr64
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  je     L15
  movl   $0x1,0x10(%rsp)
  mov    (%rsp),%rdi
  call   <setcontext@plt>
  jmp    L15
L26:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void time_getcontext(int count) {
  int i;
  volatile int ret;
  ucontext_t uc;
  for (i = 0; i < count; i++) {
    ret = 0;
    getcontext(&uc);
    if (ret == 1)
      continue;
    ret = 1;
    setcontext(&uc);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<time_getcontext>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L2
  lea    0x14(%rsp),%rax
  movl   $0x0,0x8(%rsp)
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L33:
  mov    (%rsp),%rdi
  movl   $0x0,0x10(%rsp)
  call   <getcontext@plt>
  endbr64
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  je     L28
  mov    (%rsp),%rdi
  movl   $0x1,0x10(%rsp)
  call   <setcontext@plt>
L28:
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  jne    L33
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void time_getcontext(int count) {
  int i;
  volatile int ret;
  ucontext_t uc;
  for (i = 0; i < count; i++) {
    ret = 0;
    getcontext(&uc);
    if (ret == 1)
      continue;
    ret = 1;
    setcontext(&uc);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<time_getcontext>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L6
  lea    0x14(%rsp),%rax
  movl   $0x0,0x8(%rsp)
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L21:
  mov    (%rsp),%rdi
  movl   $0x0,0x10(%rsp)
  call   <getcontext@plt>
  endbr64
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  je     L20
  mov    (%rsp),%rdi
  movl   $0x1,0x10(%rsp)
  call   <setcontext@plt>
L20:
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  jne    L21
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void time_getcontext(int count) {
  int i;
  volatile int ret;
  ucontext_t uc;
  for (i = 0; i < count; i++) {
    ret = 0;
    getcontext(&uc);
    if (ret == 1)
      continue;
    ret = 1;
    setcontext(&uc);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<need>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L23
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x5,%rax
  add    %rdx,%rax
  lea    0x10(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0xffffffff,%eax
  jmp    L15
L18:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L23:
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
int need(unsigned long n, char **linep, unsigned long *np) {
  char *p;
  if (*np <= n) {
    *np += (*np >> 5) + 16;
    if ((p = realloc(*linep, *np)) == 0)
      return -1;
    *linep = p;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<need>:
  endbr64
  mov    (%rdx),%rax
  mov    $0x0,%ecx
  cmp    %rdi,%rax
  jbe    L5
  mov    %ecx,%eax
  ret
L5:
  push   %rbx
  mov    %rsi,%rbx
  mov    %rax,%rcx
  shr    $0x5,%rcx
  lea    0x10(%rax,%rcx,1),%rsi
  mov    %rsi,(%rdx)
  mov    (%rbx),%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,(%rbx)
  mov    $0x0,%ecx
L8:
  mov    %ecx,%eax
  pop    %rbx
  ret
L7:
  mov    $0xffffffff,%ecx
  jmp    L8
```

assistant: ```c
int need(unsigned long n, char **linep, unsigned long *np) {
  char *p;
  if (*np <= n) {
    *np += (*np >> 5) + 16;
    if ((p = realloc(*linep, *np)) == 0)
      return -1;
    *linep = p;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<need>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdx),%rax
  cmp    %rdi,%rax
  jbe    L3
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  mov    %rax,%rcx
  mov    %rsi,%rbx
  shr    $0x5,%rcx
  mov    (%rbx),%rdi
  lea    0x10(%rax,%rcx,1),%rsi
  mov    %rsi,(%rdx)
  call   <realloc@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L14:
  mov    $0xffffffff,%r12d
  jmp    L2
```

assistant: ```c
int need(unsigned long n, char **linep, unsigned long *np) {
  char *p;
  if (*np <= n) {
    *np += (*np >> 5) + 16;
    if ((p = realloc(*linep, *np)) == 0)
      return -1;
    *linep = p;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<need>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdx),%rax
  cmp    %rdi,%rax
  jbe    L2
L25:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  mov    %rax,%rcx
  mov    %rsi,%rbx
  shr    $0x5,%rcx
  mov    (%rbx),%rdi
  lea    0x10(%rax,%rcx,1),%rsi
  mov    %rsi,(%rdx)
  call   <realloc@plt>
  test   %rax,%rax
  je     L16
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L16:
  mov    $0xffffffff,%r12d
  jmp    L25
```

assistant: ```c
int need(unsigned long n, char **linep, unsigned long *np) {
  char *p;
  if (*np <= n) {
    *np += (*np >> 5) + 16;
    if ((p = realloc(*linep, *np)) == 0)
      return -1;
    *linep = p;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<socket_keepalive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void socket_keepalive(int fd) {
  int keepalive = 1;
  setsockopt(fd, SOL_SOCKET, SO_KEEPALIVE, (void *)&keepalive, sizeof(keepalive));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<socket_keepalive>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    $0x4,%r8d
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void socket_keepalive(int fd) {
  int keepalive = 1;
  setsockopt(fd, SOL_SOCKET, SO_KEEPALIVE, (void *)&keepalive, sizeof(keepalive));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<socket_keepalive>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%rcx
  movl   $0x1,0x4(%rsp)
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void socket_keepalive(int fd) {
  int keepalive = 1;
  setsockopt(fd, SOL_SOCKET, SO_KEEPALIVE, (void *)&keepalive, sizeof(keepalive));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<socket_keepalive>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  lea    0x4(%rsp),%rcx
  movl   $0x1,0x4(%rsp)
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void socket_keepalive(int fd) {
  int keepalive = 1;
  setsockopt(fd, SOL_SOCKET, SO_KEEPALIVE, (void *)&keepalive, sizeof(keepalive));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<frand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7731764175303074,%rax
  movabs $0x7a44337943783242,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x4836734735464534,%rax
  movabs $0x4b644a6337624961,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x684d6739664c6538,%rax
  movabs $0x526b516a50694f4e,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x57566f55546e536d,%rax
  movabs $0x725a70595871,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x70(%rbp)
  mov    -0x70(%rbp),%rcx
  mov    %rcx,%rax
  shr    %rax
  movabs $0xa3d70a3d70a3d70b,%rdx
  mul    %rdx
  shr    $0x4,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x78(%rbp)
  mov    -0x78(%rbp),%eax
  add    $0x9,%eax
  mov    %eax,-0x74(%rbp)
  movb   $0x0,-0x59(%rbp)
  mov    -0x70(%rbp),%rcx
  mov    %rcx,%rax
  shr    %rax
  movabs $0xa3d70a3d70a3d70b,%rdx
  mul    %rdx
  shr    $0x4,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  mov    %eax,%edi
  call   <srand@plt>
  mov    -0x78(%rbp),%eax
  mov    %eax,-0x7c(%rbp)
  jmp    L27
L29:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x7c(%rbp)
  mov    %edx,%eax
  add    $0x1,%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  movsbl %al,%edx
  lea    -0x5b(%rbp),%rax
  mov    %edx,%ecx
  lea    D9(%rip),%rdx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x5b(%rbp),%rdx
  lea    -0x59(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  addl   $0x1,-0x7c(%rbp)
L27:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L29
  lea    -0x59(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: %c

assistant: ```c
char *frand(void) {
  char str[64] = "t00uAv1wB2xCy3Dz4EF5Gs6HaIb7cJdK8eLf9gMhNOiPjQkRmSnTUoVWqXYpZr";
  int i, start, end;
  char tmp[2];
  unsigned long l;
  char str_rand[9], *p;
  l = time(0);
  start = l % 50 + 1;
  end = start + 9;
  str_rand[0] = '\0';
  srand((unsigned int)(l % 50));
  for (i = start; i < end; i++) {
    snprintf(tmp, 2, "%c", str[(rand() % i) + 1]);
    strcat(str_rand, tmp);
  }
  p = strdup(str_rand);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<frand>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movabs $0x7731764175303074,%rax
  movabs $0x7a44337943783242,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x4836734735464534,%rax
  movabs $0x4b644a6337624961,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x684d6739664c6538,%rax
  movabs $0x526b516a50694f4e,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x57566f55546e536d,%rax
  movabs $0x725a70595871,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%r12
  mov    %rax,%rdx
  shr    %rdx
  movabs $0xa3d70a3d70a3d70b,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  add    %rax,%rax
  sub    %rax,%r12
  mov    %r12d,%edi
  lea    0x1(%r12),%ebp
  lea    0xa(%r12),%r13d
  movb   $0x0,0x7(%rsp)
  call   <srand@plt>
  cmp    %r13d,%ebp
  jge    L23
  mov    %ebp,%ebx
  add    $0x2,%r12d
  cmp    %r12d,%r13d
  setge  %al
  movzbl %al,%eax
  lea    0x1(,%rax,8),%r13d
  lea    D3(%rip),%r12
L1:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  add    $0x1,%edx
  movslq %edx,%rdx
  movsbl 0x10(%rsp,%rdx,1),%ecx
  lea    0x5(%rsp),%r14
  mov    %r12,%rdx
  mov    $0x2,%esi
  mov    %r14,%rdi
  call   <snprintf@plt>
  lea    0x7(%rsp),%rdi
  mov    %r14,%rsi
  call   <strcat@plt>
  add    $0x1,%ebx
  lea    0x0(%rbp,%r13,1),%eax
  cmp    %eax,%ebx
  jne    L1
L23:
  lea    0x7(%rsp),%rdi
  call   <strdup@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: %c

assistant: ```c
char *frand(void) {
  char str[64] = "t00uAv1wB2xCy3Dz4EF5Gs6HaIb7cJdK8eLf9gMhNOiPjQkRmSnTUoVWqXYpZr";
  int i, start, end;
  char tmp[2];
  unsigned long l;
  char str_rand[9], *p;
  l = time(0);
  start = l % 50 + 1;
  end = start + 9;
  str_rand[0] = '\0';
  srand((unsigned int)(l % 50));
  for (i = start; i < end; i++) {
    snprintf(tmp, 2, "%c", str[(rand() % i) + 1]);
    strcat(str_rand, tmp);
  }
  p = strdup(str_rand);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<frand>:
  endbr64
  push   %r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  movdqa D25(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D11(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D46(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D9(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <time@plt>
  movb   $0x0,0x7(%rsp)
  movabs $0xa3d70a3d70a3d70b,%rcx
  mov    %rax,%rdx
  mov    %rax,%rbp
  shr    %rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  add    %rax,%rax
  sub    %rax,%rbp
  lea    0x1(%rbp),%ebx
  lea    0xa(%rbp),%r12d
  mov    %ebp,%edi
  call   <srand@plt>
  cmp    %r12d,%ebx
  jge    L8
  add    $0x2,%ebp
  xor    %eax,%eax
  lea    D36(%rip),%r14
  cmp    %ebp,%r12d
  lea    0x5(%rsp),%rbp
  lea    0x7(%rsp),%r12
  setge  %al
  lea    0x1(%rbx,%rax,8),%r13d
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <rand@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  cltd
  idiv   %ebx
  add    $0x1,%ebx
  add    $0x1,%edx
  movslq %edx,%rdx
  movsbl 0x10(%rsp,%rdx,1),%ecx
  mov    %r14,%rdx
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  cmp    %r13d,%ebx
  jne    L6
L37:
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L8:
  lea    0x7(%rsp),%r12
  jmp    L37
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D25
type: byte[16]
name: parse_data
arguments: label: D11
type: byte[16]
name: parse_data
arguments: label: D46
type: byte[16]
name: parse_data
arguments: label: D9
type: byte[16]
name: parse_data
arguments: label: D36
type: string

tool: {"D25": [0x74,0x30,0x30,0x75,0x41,0x76,0x31,0x77,0x42,0x32,0x78,0x43,0x79,0x33,0x44,0x7a]}

tool: {"D11": [0x34,0x45,0x46,0x35,0x47,0x73,0x36,0x48,0x61,0x49,0x62,0x37,0x63,0x4a,0x64,0x4b]}

tool: {"D46": [0x38,0x65,0x4c,0x66,0x39,0x67,0x4d,0x68,0x4e,0x4f,0x69,0x50,0x6a,0x51,0x6b,0x52]}

tool: {"D9": [0x6d,0x53,0x6e,0x54,0x55,0x6f,0x56,0x57,0x71,0x58,0x59,0x70,0x5a,0x72,0x00,0x00]}

tool: D36: %c

assistant: ```c
char *frand(void) {
  char str[64] = "t00uAv1wB2xCy3Dz4EF5Gs6HaIb7cJdK8eLf9gMhNOiPjQkRmSnTUoVWqXYpZr";
  int i, start, end;
  char tmp[2];
  unsigned long l;
  char str_rand[9], *p;
  l = time(0);
  start = l % 50 + 1;
  end = start + 9;
  str_rand[0] = '\0';
  srand((unsigned int)(l % 50));
  for (i = start; i < end; i++) {
    snprintf(tmp, 2, "%c", str[(rand() % i) + 1]);
    strcat(str_rand, tmp);
  }
  p = strdup(str_rand);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<frand>:
  endbr64
  push   %r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  movdqa D39(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D40(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D20(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D48(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <time@plt>
  movb   $0x0,0x7(%rsp)
  movabs $0xa3d70a3d70a3d70b,%rcx
  mov    %rax,%rdx
  mov    %rax,%rbp
  shr    %rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  add    %rax,%rax
  sub    %rax,%rbp
  lea    0x1(%rbp),%ebx
  lea    0xa(%rbp),%r12d
  mov    %ebp,%edi
  call   <srand@plt>
  cmp    %r12d,%ebx
  jge    L35
  add    $0x2,%ebp
  xor    %eax,%eax
  lea    D23(%rip),%r14
  cmp    %ebp,%r12d
  lea    0x5(%rsp),%rbp
  lea    0x7(%rsp),%r12
  setge  %al
  lea    0x1(%rbx,%rax,8),%r13d
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  call   <rand@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  cltd
  idiv   %ebx
  add    $0x1,%ebx
  add    $0x1,%edx
  movslq %edx,%rdx
  movsbl 0x10(%rsp,%rdx,1),%ecx
  mov    %r14,%rdx
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  cmp    %r13d,%ebx
  jne    L11
L28:
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L35:
  lea    0x7(%rsp),%r12
  jmp    L28
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D40
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D20
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D48
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D23
type_infered: string

tool: {"D39": [0x74,0x30,0x30,0x75,0x41,0x76,0x31,0x77,0x42,0x32,0x78,0x43,0x79,0x33,0x44,0x7a]}

tool: {"D40": [0x34,0x45,0x46,0x35,0x47,0x73,0x36,0x48,0x61,0x49,0x62,0x37,0x63,0x4a,0x64,0x4b]}

tool: {"D20": [0x38,0x65,0x4c,0x66,0x39,0x67,0x4d,0x68,0x4e,0x4f,0x69,0x50,0x6a,0x51,0x6b,0x52]}

tool: {"D48": [0x6d,0x53,0x6e,0x54,0x55,0x6f,0x56,0x57,0x71,0x58,0x59,0x70,0x5a,0x72,0x00,0x00]}

tool: D23: %c

assistant: ```c
char *frand(void) {
  char str[64] = "t00uAv1wB2xCy3Dz4EF5Gs6HaIb7cJdK8eLf9gMhNOiPjQkRmSnTUoVWqXYpZr";
  int i, start, end;
  char tmp[2];
  unsigned long l;
  char str_rand[9], *p;
  l = time(0);
  start = l % 50 + 1;
  end = start + 9;
  str_rand[0] = '\0';
  srand((unsigned int)(l % 50));
  for (i = start; i < end; i++) {
    snprintf(tmp, 2, "%c", str[(rand() % i) + 1]);
    strcat(str_rand, tmp);
  }
  p = strdup(str_rand);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L44
L1:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  movss  D98(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L5
  movss  D98(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  je     L54
L5:
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x18(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
L54:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L44:
  movss  -0x18(%rbp),%xmm0
  movss  D98(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L1
  movss  D98(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jne    L1
  movss  -0xc(%rbp),%xmm0
  divss  -0x10(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D98
type_infered: byte[4]
name: disassemble_data
arguments: tag: D91
type_infered: string
name: disassemble_data
arguments: tag: D35
type_infered: string
name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D29: Informe quantos litros abasteceu (-1 para terminar): 

tool: D14: %f

tool: {"D98": [0x00,0x00,0x80,0xbf]}

tool: D91: Informe quantos km dirigiu: 

tool: D35: O consumo atual e de %.6f km/l

tool: D16: 


tool: D0: O consumo geral foi de %.6f km/l

assistant: ```c
int main() {
  float litros = 0, km, tLitros = 0, tKm = 0;
  while (litros != -1) {
    printf("Informe quantos litros abasteceu (-1 para terminar): ");
    scanf("%f", &litros);
    if (litros != -1) {
      printf("Informe quantos km dirigiu: ");
      scanf("%f", &km);
      printf("O consumo atual e de %.6f km/l", km / litros);
      tLitros += litros;
      tKm += km;
    }
    printf("\n\n");
  }
  printf("O consumo geral foi de %.6f km/l", tKm / tLitros);
}
```