user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x78(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L81
L31:
  mov    -0x68(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,-0x6c(%rbp)
  mov    -0x6c(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L72
  mov    -0x6c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x6c(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
L72:
  mov    -0x6c(%rbp),%eax
  cltq
  movl   $0x2,-0x60(%rbp,%rax,4)
  mov    -0x68(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x68(%rbp)
L81:
  mov    -0x68(%rbp),%rax
  test   %rax,%rax
  jg     L31
  movl   $0x0,-0x74(%rbp)
  jmp    L80
L63:
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  add    %eax,-0x78(%rbp)
  addl   $0x1,-0x74(%rbp)
L80:
  cmpl   $0x9,-0x74(%rbp)
  jle    L63
  cmpl   $0x0,-0x78(%rbp)
  jne    L73
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L60
L73:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x70(%rbp)
  jmp    L20
L18:
  mov    -0x70(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  jle    L6
  mov    -0x70(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  addl   $0x1,-0x70(%rbp)
L20:
  cmpl   $0x9,-0x70(%rbp)
  jle    L18
  mov    $0xa,%edi
  call   <putchar@plt>
L60:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D33
type_guessed: string
name: read_data
arguments: label: D38
type_guessed: string
name: read_data
arguments: label: D32
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D37
type_guessed: string

tool: D33: Enter a number: 

tool: D38: %ld

tool: D32: No repeated digits

tool: D29: Repeated digit(s): 

tool: D37: %d 

assistant: ```c
int main(void) {
  int digit_seen[10] = {0};
  int duplicates[10] = {0};
  int digit;
  int empty = 0;
  long n;
  printf("Enter a number: ");
  scanf("%ld", &n);
  while (n > 0) {
    digit = n % 10;
    if (digit_seen[digit]) {
      duplicates[digit] += 1;
    }
    digit_seen[digit] = 2;
    n /= 10;
  }
  for (int i = 0; i < 10; i += 1) {
    empty += duplicates[i];
  }
  if (empty == 0) {
    printf("No repeated digits\n");
  } else {
    printf("Repeated digit(s): ");
    for (int i = 0; i < 10; i += 1) {
      if (duplicates[i] > 0) {
        printf("%d ", i);
      }
    }
    printf("\n");
  }
  return 0;
}
```