ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<funcion_uno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  sub    $0x4,%rax
  cmp    $0x3,%rax
  jbe    L96
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L9:
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L27:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L51
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  shr    $0x2,%rdx
  imul   %rdx,%rax
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L51:
  addl   $0x1,-0x8(%rbp)
L57:
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x20(%rbp)
  cmp    %eax,-0x8(%rbp)
  jl     L27
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  shr    $0x2,%rdx
  cmp    %rdx,%rax
  jb     L9
  jmp    L62
L96:
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L28:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L8:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x20(%rbp)
  cmp    %eax,-0x8(%rbp)
  jl     L28
L62:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string

tool: D4: p[%d][%d]=%d


tool: D17: p[%d]=%d


assistant: ```c
void funcion_uno(int *arreglo, int size_arr, int size_arr_pointeur) {
  int i, j;
  if (size_arr_pointeur / sizeof(int) != 1) {
    for (j = 0; j < size_arr_pointeur / sizeof(int); j++) {
      for (i = 0; i < size_arr / size_arr_pointeur; i++) {
        if ((i + j) % 2 != 0) {
          printf("p[%d][%d]=%d\n", i, j, *(arreglo + (i + j * (size_arr_pointeur / sizeof(int)))));
        }
      }
    }
  } else {
    for (i = 0; i < size_arr / size_arr_pointeur; i++) {
      if (i % 2 != 0) {
        printf("p[%d]=%d\n", i, *(arreglo + i));
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<funcion_uno>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %esi,%eax
  mov    %edx,%ecx
  movslq %edx,%rdx
  lea    -0x4(%rdx),%rsi
  cmp    $0x3,%rsi
  ja     L121
  cltd
  idiv   %ecx
  test   %eax,%eax
  jle    L63
  mov    %eax,%ebp
  mov    $0x1,%ebx
  lea    D5(%rip),%r12
  mov    %rdi,%r13
  jmp    L30
L121:
  mov    %rdx,%rdi
  shr    $0x2,%rdi
  mov    %rdi,0x18(%rsp)
  cmp    $0x3,%rdx
  jbe    L63
  cltd
  idiv   %ecx
  mov    %eax,0xc(%rsp)
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  jmp    L80
L114:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L13
L106:
  mov    %ebx,%esi
  lea    0x0(%rbp,%rbx,1),%eax
  test   $0x1,%al
  je     L114
  mov    (%r15,%rbx,4),%ecx
  mov    0x8(%rsp),%edx
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L114
L13:
  add    $0x1,%r13
  mov    0x18(%rsp),%rax
  add    %rax,%r14
  cmp    %r13,%rax
  jbe    L63
L80:
  mov    %r13d,%ebp
  mov    %r13d,0x8(%rsp)
  cmpl   $0x0,0xc(%rsp)
  jle    L13
  mov    0xc(%rsp),%r12d
  mov    0x10(%rsp),%rax
  lea    (%rax,%r14,4),%r15
  mov    $0x0,%ebx
  jmp    L106
L98:
  add    $0x1,%rbx
L30:
  mov    %ebx,%esi
  cmp    %rbp,%rbx
  je     L63
  test   $0x1,%bl
  je     L98
  mov    0x0(%r13,%rbx,4),%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L98
L63:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string
name: extract_symbolic_data
arguments: tag: D19
type: string

tool: D5: p[%d]=%d


tool: D19: p[%d][%d]=%d


assistant: ```c
void funcion_uno(int *arreglo, int size_arr, int size_arr_pointeur) {
  int i, j;
  if (size_arr_pointeur / sizeof(int) != 1) {
    for (j = 0; j < size_arr_pointeur / sizeof(int); j++) {
      for (i = 0; i < size_arr / size_arr_pointeur; i++) {
        if ((i + j) % 2 != 0) {
          printf("p[%d][%d]=%d\n", i, j, *(arreglo + (i + j * (size_arr_pointeur / sizeof(int)))));
        }
      }
    }
  } else {
    for (i = 0; i < size_arr / size_arr_pointeur; i++) {
      if (i % 2 != 0) {
        printf("p[%d]=%d\n", i, *(arreglo + i));
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<funcion_uno>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  lea    -0x4(%r13),%rdx
  mov    %r13,%rcx
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x20(%rsp)
  cmp    $0x3,%rdx
  ja     L41
  cltd
  idiv   %r13d
  test   %eax,%eax
  jle    L57
  movslq %eax,%rbp
  mov    $0x1,%ebx
  lea    D5(%rip),%r12
  mov    %rdi,%r13
  jmp    L105
  nopl   (%rax)
L48:
  test   $0x1,%bl
  je     L59
  mov    0x0(%r13,%rbx,4),%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L59:
  add    $0x1,%rbx
L105:
  mov    %ebx,%esi
  cmp    %rbp,%rbx
  jne    L48
L57:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  shr    $0x2,%r13
  mov    %r13,0x28(%rsp)
  je     L57
  cltd
  lea    D2(%rip),%r14
  movq   $0x0,0x10(%rsp)
  idiv   %ecx
  movq   $0x0,0x8(%rsp)
  mov    %eax,0x1c(%rsp)
  nopl   0x0(%rax,%rax,1)
L19:
  mov    0x8(%rsp),%rax
  mov    %eax,%r13d
  mov    %eax,%r15d
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L61
  mov    0x20(%rsp),%rax
  mov    0x10(%rsp),%rdi
  xor    %r12d,%r12d
  movslq 0x1c(%rsp),%rbx
  lea    (%rax,%rdi,4),%rbp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L52:
  add    $0x1,%r12
  cmp    %r12,%rbx
  je     L61
L4:
  lea    0x0(%r13,%r12,1),%eax
  mov    %r12d,%esi
  test   $0x1,%al
  je     L52
  mov    0x0(%rbp,%r12,4),%ecx
  mov    %r15d,%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
L61:
  addq   $0x1,0x8(%rsp)
  mov    0x28(%rsp),%rdx
  mov    0x8(%rsp),%rax
  add    %rdx,0x10(%rsp)
  cmp    %rdx,%rax
  jne    L19
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D2
type: string

tool: D5: p[%d]=%d


tool: D2: p[%d][%d]=%d


assistant: ```c
void funcion_uno(int *arreglo, int size_arr, int size_arr_pointeur) {
  int i, j;
  if (size_arr_pointeur / sizeof(int) != 1) {
    for (j = 0; j < size_arr_pointeur / sizeof(int); j++) {
      for (i = 0; i < size_arr / size_arr_pointeur; i++) {
        if ((i + j) % 2 != 0) {
          printf("p[%d][%d]=%d\n", i, j, *(arreglo + (i + j * (size_arr_pointeur / sizeof(int)))));
        }
      }
    }
  } else {
    for (i = 0; i < size_arr / size_arr_pointeur; i++) {
      if (i % 2 != 0) {
        printf("p[%d]=%d\n", i, *(arreglo + i));
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<funcion_uno>:
  endbr64
  push   %r15
  mov    %esi,%eax
  mov    %rdi,%r15
  push   %r14
  movslq %edx,%r14
  push   %r13
  lea    -0x4(%r14),%rdx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmp    $0x3,%rdx
  ja     L47
  cltd
  mov    $0x1,%ebx
  lea    D18(%rip),%r13
  idiv   %r14d
  movslq %eax,%r12
  cmp    $0x1,%eax
  jle    L99
  nopl   0x0(%rax)
L58:
  mov    %ebx,%esi
  test   $0x1,%bl
  je     L50
  mov    (%r15,%rbx,4),%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L50:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L58
L99:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L47:
  mov    %r14,%rdi
  shr    $0x2,%rdi
  mov    %rdi,0x10(%rsp)
  je     L99
  cltd
  idiv   %r14d
  test   %eax,%eax
  jle    L99
  lea    0x0(,%rdi,4),%rdx
  movslq %eax,%r14
  movq   $0x0,0x8(%rsp)
  lea    D15(%rip),%r13
  mov    %rdx,0x18(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L66:
  mov    0x8(%rsp),%rax
  xor    %ebx,%ebx
  mov    %eax,%ebp
  mov    %eax,%r12d
  jmp    L51
  xchg   %ax,%ax
L9:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L39
L51:
  lea    0x0(%rbp,%rbx,1),%eax
  mov    %ebx,%esi
  test   $0x1,%al
  je     L9
  mov    (%r15,%rbx,4),%ecx
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L51
L39:
  addq   $0x1,0x8(%rsp)
  add    0x18(%rsp),%r15
  mov    0x8(%rsp),%rax
  cmp    0x10(%rsp),%rax
  jne    L66
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D18: p[%d]=%d


tool: D15: p[%d][%d]=%d


assistant: ```c
void funcion_uno(int *arreglo, int size_arr, int size_arr_pointeur) {
  int i, j;
  if (size_arr_pointeur / sizeof(int) != 1) {
    for (j = 0; j < size_arr_pointeur / sizeof(int); j++) {
      for (i = 0; i < size_arr / size_arr_pointeur; i++) {
        if ((i + j) % 2 != 0) {
          printf("p[%d][%d]=%d\n", i, j, *(arreglo + (i + j * (size_arr_pointeur / sizeof(int)))));
        }
      }
    }
  } else {
    for (i = 0; i < size_arr / size_arr_pointeur; i++) {
      if (i % 2 != 0) {
        printf("p[%d]=%d\n", i, *(arreglo + i));
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6c6c6568,-0xf(%rbp)
  movw   $0xa6f,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  movb   $0x78,-0xf(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string

tool: D6: hello


assistant: ```c
int main(void) {
  char s[] = "hello\n";
  s[0] = 'x';
  printf("hello\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: hello


assistant: ```c
int main(void) {
  char s[] = "hello\n";
  s[0] = 'x';
  printf("hello\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: hello


assistant: ```c
int main(void) {
  char s[] = "hello\n";
  s[0] = 'x';
  printf("hello\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: hello


assistant: ```c
int main(void) {
  char s[] = "hello\n";
  s[0] = 'x';
  printf("hello\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D37
data_type: string
name: unpack_data
arguments: label: D18
data_type: string
name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D1
data_type: string

tool: D37: 1

tool: D18: 11

tool: D11: 111

tool: D1: 1111

assistant: ```c
void func1(void *arg) {
  puts("1");
  puts("11");
  puts("111");
  puts("1111");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func1>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D33
type_guessed: string
name: unpack_data
arguments: tag: D36
type_guessed: string

tool: D18: 1

tool: D1: 11

tool: D33: 111

tool: D36: 1111

assistant: ```c
void func1(void *arg) {
  puts("1");
  puts("11");
  puts("111");
  puts("1111");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func1>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    D38(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D18
type: string
name: extract_symbolic_data
arguments: data_label: D38
type: string

tool: D20: 1

tool: D9: 11

tool: D18: 111

tool: D38: 1111

assistant: ```c
void func1(void *arg) {
  puts("1");
  puts("11");
  puts("111");
  puts("1111");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func1>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D29
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D9: 1

tool: D14: 11

tool: D29: 111

tool: D5: 1111

assistant: ```c
void func1(void *arg) {
  puts("1");
  puts("11");
  puts("111");
  puts("1111");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L35
L22:
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x28(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L32
  movsd  -0x18(%rbp),%xmm1
  movsd  D24(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L32:
  movsd  -0x20(%rbp),%xmm1
  movsd  D24(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
L35:
  movsd  D11(%rip),%xmm0
  comisd -0x20(%rbp),%xmm0
  ja     L22
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
datatype: string
name: parse_data
arguments: data_label: D24
datatype: f32[2]
name: parse_data
arguments: data_label: D11
datatype: f32[2]
name: parse_data
arguments: data_label: D1
datatype: string

tool: D14:  %lf

tool: {"D24": [0.0,1.875]}

tool: {"D11": [0.0,2.375]}

tool: D1: %0.0lf valores positivos
%0.1lf


assistant: ```c
int main() {
  double i = 0, cont = 0, X, media = 0;
  while (i < 6) {
    scanf(" %lf", &X);
    if (X > 0) {
      cont++;
      media += X;
    }
    i++;
  }
  printf("%0.0lf valores positivos\n%0.1lf\n", cont, media / cont);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x6,%ebx
  mov    D23(%rip),%rbp
  mov    %rbp,%r14
  mov    %rsp,%r13
  lea    D24(%rip),%r12
  jmp    L10
L3:
  sub    $0x1,%ebx
  je     L1
L10:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm0
  jbe    L3
  movq   %r14,%xmm3
  addsd  D33(%rip),%xmm3
  movq   %xmm3,%r14
  movq   %rbp,%xmm4
  addsd  %xmm0,%xmm4
  movq   %xmm4,%rbp
  jmp    L3
L1:
  movq   %rbp,%xmm1
  movq   %r14,%xmm5
  divsd  %xmm5,%xmm1
  movq   %r14,%xmm0
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D23
type: f64
name: disassemble_data
arguments: tag: D24
type: string
name: disassemble_data
arguments: tag: D33
type: byte[8]
name: disassemble_data
arguments: tag: D36
type: string

tool: D23: 0

tool: D24:  %lf

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D36: %0.0lf valores positivos
%0.1lf


assistant: ```c
int main() {
  double i = 0, cont = 0, X, media = 0;
  while (i < 6) {
    scanf(" %lf", &X);
    if (X > 0) {
      cont++;
      media += X;
    }
    i++;
  }
  printf("%0.0lf valores positivos\n%0.1lf\n", cont, media / cont);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  lea    0x10(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  xchg   %ax,%ax
L11:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm0
  jbe    L26
  addsd  0x8(%rsp),%xmm0
  movsd  D5(%rip),%xmm3
  addsd  (%rsp),%xmm3
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm3,(%rsp)
L26:
  sub    $0x1,%ebx
  jne    L11
  movsd  (%rsp),%xmm6
  movsd  0x8(%rsp),%xmm1
  lea    D23(%rip),%rdi
  divsd  %xmm6,%xmm1
  movapd %xmm6,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D5
type: f32[2]
name: retrieve_data
arguments: label: D23
type: string

tool: D0:  %lf

tool: {"D5": [0.0,1.875]}

tool: D23: %0.0lf valores positivos
%0.1lf


assistant: ```c
int main() {
  double i = 0, cont = 0, X, media = 0;
  while (i < 6) {
    scanf(" %lf", &X);
    if (X > 0) {
      cont++;
      media += X;
    }
    i++;
  }
  printf("%0.0lf valores positivos\n%0.1lf\n", cont, media / cont);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  lea    0x10(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  xchg   %ax,%ax
L25:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm0
  jbe    L1
  addsd  0x8(%rsp),%xmm0
  movsd  D2(%rip),%xmm3
  addsd  (%rsp),%xmm3
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm3,(%rsp)
L1:
  sub    $0x1,%ebx
  jne    L25
  movsd  (%rsp),%xmm6
  movsd  0x8(%rsp),%xmm1
  lea    D13(%rip),%rdi
  divsd  %xmm6,%xmm1
  movapd %xmm6,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D2
type_infered: f32[2]
name: read_data
arguments: data_label: D13
type_infered: string

tool: D10:  %lf

tool: {"D2": [0.0,1.875]}

tool: D13: %0.0lf valores positivos
%0.1lf


assistant: ```c
int main() {
  double i = 0, cont = 0, X, media = 0;
  while (i < 6) {
    scanf(" %lf", &X);
    if (X > 0) {
      cont++;
      media += X;
    }
    i++;
  }
  printf("%0.0lf valores positivos\n%0.1lf\n", cont, media / cont);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L15
L5:
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0xc(%rbp),%edx
  cmp    %dl,%al
  jne    L5
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L45
  mov    -0x8(%rbp),%rax
  jmp    L29
L45:
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
L22:
  cmp    %sil,%al
  je     L23
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L22
L23:
  movsbl %al,%eax
  cmp    %esi,%eax
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  mov    %esi,%edx
  jmp    L7
  nop
L8:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L5
L7:
  cmp    %al,%dl
  jne    L8
  movsbl %sil,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L5:
  xor    %eax,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  mov    %esi,%edx
  jmp    L11
  nop
L7:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L8
L11:
  cmp    %al,%dl
  jne    L7
  movsbl %sil,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L8:
  xor    %eax,%eax
  cmp    %eax,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s != '\0' && *s != (char)c)
    s++;
  return ((*s == c) ? (char *)s : 0);
}
```