ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %edi,-0x824(%rbp)
  mov    %rsi,-0x830(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x400,-0x81c(%rbp)
  movl   $0x0,-0x820(%rbp)
  cmpl   $0x1,-0x824(%rbp)
  jg     L34
  mov    $0xffffffff,%eax
  jmp    L5
L34:
  mov    -0x830(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x818(%rbp)
  cmpl   $0x2,-0x824(%rbp)
  jle    L23
  mov    -0x830(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x81c(%rbp)
L23:
  mov    D5(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x81c(%rbp),%edx
  lea    -0x810(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x81c(%rbp)
  cmpl   $0x0,-0x81c(%rbp)
  jle    L44
  mov    -0x81c(%rbp),%eax
  cltq
  movb   $0x0,-0x810(%rbp,%rax,1)
  lea    -0x820(%rbp),%rcx
  lea    -0x410(%rbp),%rdx
  mov    -0x818(%rbp),%rsi
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <decode_query@plt>
  test   %rax,%rax
  jne    L44
  mov    D16(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x820(%rbp),%edx
  lea    -0x410(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    $0x0,%eax
  jmp    L5
L44:
  mov    $0xffffffff,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char qbuf[1024], val[1024];
  int len = 1024;
  int size = 0;
  if (argc < 2)
    return -1;
  char *key = argv[1];
  if (argc > 2)
    len = atoi(argv[2]);
  if ((len = fread(qbuf, 1, len, stdin)) > 0) {
    qbuf[len] = 0;
    if (decode_query(qbuf, key, val, &size) == 0) {
      fwrite(val, 1, size, stdout);
      return 0;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x820,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  cmp    $0x1,%edi
  jle    L4
  mov    0x8(%rsi),%rbx
  mov    $0x400,%edx
  cmp    $0x2,%edi
  jg     L44
L41:
  lea    0x10(%rsp),%rdi
  mov    D18(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x1,%esi
  call   <fread@plt>
  test   %eax,%eax
  jle    L52
  cltq
  movb   $0x0,0x10(%rsp,%rax,1)
  lea    0xc(%rsp),%rcx
  lea    0x410(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <decode_query@plt>
  test   %rax,%rax
  jne    L8
  lea    0x410(%rsp),%rdi
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    0xc(%rsp),%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    $0x0,%eax
L87:
  mov    0x818(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x820,%rsp
  pop    %rbx
  ret
L44:
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  jmp    L41
L4:
  mov    $0xffffffff,%eax
  jmp    L87
L52:
  mov    $0xffffffff,%eax
  jmp    L87
L8:
  mov    $0xffffffff,%eax
  jmp    L87
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char qbuf[1024], val[1024];
  int len = 1024;
  int size = 0;
  if (argc < 2)
    return -1;
  char *key = argv[1];
  if (argc > 2)
    len = atoi(argv[2]);
  if ((len = fread(qbuf, 1, len, stdin)) > 0) {
    qbuf[len] = 0;
    if (decode_query(qbuf, key, val, &size) == 0) {
      fwrite(val, 1, size, stdout);
      return 0;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x820,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  cmp    $0x1,%edi
  jle    L24
  mov    0x8(%rsi),%rbp
  mov    $0x400,%edx
  cmp    $0x2,%edi
  je     L9
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
L9:
  mov    D1(%rip),%rax
  lea    0x10(%rsp),%r12
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    (%rax),%ecx
  call   <fread@plt>
  test   %eax,%eax
  jle    L24
  lea    0x410(%rsp),%r13
  cltq
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0xc(%rsp),%rcx
  mov    %r13,%rdx
  movb   $0x0,0x10(%rsp,%rax,1)
  call   <decode_query@plt>
  test   %rax,%rax
  jne    L24
  mov    D18(%rip),%rax
  mov    0xc(%rsp),%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    (%rax),%ecx
  call   <fwrite@plt>
  xor    %eax,%eax
L21:
  mov    0x818(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x820,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  or     $0xffffffff,%eax
  jmp    L21
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char qbuf[1024], val[1024];
  int len = 1024;
  int size = 0;
  if (argc < 2)
    return -1;
  char *key = argv[1];
  if (argc > 2)
    len = atoi(argv[2]);
  if ((len = fread(qbuf, 1, len, stdin)) > 0) {
    qbuf[len] = 0;
    if (decode_query(qbuf, key, val, &size) == 0) {
      fwrite(val, 1, size, stdout);
      return 0;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x820,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  cmp    $0x1,%edi
  jle    L3
  mov    0x8(%rsi),%rbp
  mov    $0x400,%edx
  cmp    $0x2,%edi
  je     L26
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
L26:
  mov    D13(%rip),%rax
  lea    0x10(%rsp),%r12
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    (%rax),%ecx
  call   <fread@plt>
  test   %eax,%eax
  jle    L3
  lea    0x410(%rsp),%r13
  cltq
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0xc(%rsp),%rcx
  mov    %r13,%rdx
  movb   $0x0,0x10(%rsp,%rax,1)
  call   <decode_query@plt>
  test   %rax,%rax
  jne    L3
  mov    D1(%rip),%rax
  mov    0xc(%rsp),%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    (%rax),%ecx
  call   <fwrite@plt>
  xor    %eax,%eax
L33:
  mov    0x818(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x820,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  or     $0xffffffff,%eax
  jmp    L33
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char qbuf[1024], val[1024];
  int len = 1024;
  int size = 0;
  if (argc < 2)
    return -1;
  char *key = argv[1];
  if (argc > 2)
    len = atoi(argv[2]);
  if ((len = fread(qbuf, 1, len, stdin)) > 0) {
    qbuf[len] = 0;
    if (decode_query(qbuf, key, val, &size) == 0) {
      fwrite(val, 1, size, stdout);
      return 0;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pe_utils_str_array_join>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,%eax
  mov    %al,-0x44(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L0
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L59
L0:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L48
L59:
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L73
L85:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  addq   $0x1,-0x28(%rbp)
L73:
  mov    -0x28(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L85
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L48
L4:
  subq   $0x1,-0x30(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L2
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L8
L14:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x44(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
L8:
  addq   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L11
  mov    -0x8(%rbp),%rax
L48:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: 

assistant: ```c
char *pe_utils_str_array_join(char *strings[], size_t count, char delimiter) {
  if (strings == NULL || strings[0] == NULL)
    return strdup("");
  size_t result_length = 0;
  for (size_t i = 0; i < count; i++) {
    result_length += strlen(strings[i]) + 1;
  }
  char *result = malloc(result_length);
  if (result == NULL)
    return NULL;
  result[--result_length] = '\0';
  char **current_string = strings;
  char *current_char = current_string[0];
  for (size_t i = 0; i < result_length; i++) {
    if (*current_char != '\0') {
      result[i] = *current_char++;
    } else {
      result[i] = delimiter;
      current_string++;
      current_char = current_string[0];
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pe_utils_str_array_join>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L22
  mov    %rdi,%r13
  mov    %edx,%r14d
  mov    (%rdi),%r12
  test   %r12,%r12
  je     L22
  test   %rsi,%rsi
  je     L24
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,8),%r15
  mov    $0x0,%ebp
L94:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rbp
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L94
  mov    %rbp,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L13
  movb   $0x0,-0x1(%rax,%rbp,1)
  sub    $0x1,%rbp
  je     L13
L61:
  mov    $0x0,%edx
  jmp    L28
L22:
  lea    D0(%rip),%rdi
  call   <strdup@plt>
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  mov    %r14b,(%rax,%rdx,1)
  mov    0x8(%r13),%r12
  lea    0x8(%r13),%r13
L15:
  add    $0x1,%rdx
  cmp    %rbp,%rdx
  jae    L13
L28:
  movzbl (%r12),%ecx
  test   %cl,%cl
  je     L69
  add    $0x1,%r12
  mov    %cl,(%rax,%rdx,1)
  jmp    L15
L24:
  mov    $0x0,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L13
  movb   $0x0,-0x1(%rax)
  mov    $0xffffffffffffffff,%rbp
  jmp    L61
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: 

assistant: ```c
char *pe_utils_str_array_join(char *strings[], size_t count, char delimiter) {
  if (strings == NULL || strings[0] == NULL)
    return strdup("");
  size_t result_length = 0;
  for (size_t i = 0; i < count; i++) {
    result_length += strlen(strings[i]) + 1;
  }
  char *result = malloc(result_length);
  if (result == NULL)
    return NULL;
  result[--result_length] = '\0';
  char **current_string = strings;
  char *current_char = current_string[0];
  for (size_t i = 0; i < result_length; i++) {
    if (*current_char != '\0') {
      result[i] = *current_char++;
    } else {
      result[i] = delimiter;
      current_string++;
      current_char = current_string[0];
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pe_utils_str_array_join>:
  endbr64
  test   %rdi,%rdi
  je     L53
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r14
  test   %r14,%r14
  je     L110
  mov    %edx,%r13d
  test   %rsi,%rsi
  je     L34
  lea    0x8(%rdi),%rbx
  lea    (%rdi,%rsi,8),%r15
  xor    %ebp,%ebp
  mov    %r14,%rdi
  jmp    L121
  nopl   (%rax)
L28:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
L121:
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rbp
  cmp    %r15,%rbx
  jne    L28
  mov    %rbp,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L87
  movb   $0x0,-0x1(%rax,%rbp,1)
  sub    $0x1,%rbp
  je     L66
L95:
  xor    %edx,%edx
  jmp    L86
  xchg   %ax,%ax
L7:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  add    $0x1,%r14
  cmp    %rbp,%rdx
  jae    L66
L86:
  movzbl (%r14),%ecx
  test   %cl,%cl
  jne    L7
  mov    %r13b,(%rax,%rdx,1)
  add    $0x1,%rdx
  mov    0x8(%r12),%r14
  add    $0x8,%r12
  cmp    %rbp,%rdx
  jb     L86
L66:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L110:
  add    $0x8,%rsp
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <strdup@plt>
  nopw   0x0(%rax,%rax,1)
L34:
  xor    %edi,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L87
  movb   $0x0,-0x1(%rax)
  mov    $0xffffffffffffffff,%rbp
  jmp    L95
  nopl   0x0(%rax)
L53:
  lea    D8(%rip),%rdi
  jmp    1090 <strdup@plt>
L87:
  xor    %eax,%eax
  jmp    L66
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: 

assistant: ```c
char *pe_utils_str_array_join(char *strings[], size_t count, char delimiter) {
  if (strings == NULL || strings[0] == NULL)
    return strdup("");
  size_t result_length = 0;
  for (size_t i = 0; i < count; i++) {
    result_length += strlen(strings[i]) + 1;
  }
  char *result = malloc(result_length);
  if (result == NULL)
    return NULL;
  result[--result_length] = '\0';
  char **current_string = strings;
  char *current_char = current_string[0];
  for (size_t i = 0; i < result_length; i++) {
    if (*current_char != '\0') {
      result[i] = *current_char++;
    } else {
      result[i] = delimiter;
      current_string++;
      current_char = current_string[0];
    }
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pe_utils_str_array_join>:
  endbr64
  test   %rdi,%rdi
  je     L79
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r14
  test   %r14,%r14
  je     L80
  mov    %edx,%r13d
  test   %rsi,%rsi
  je     L54
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,8),%r15
  xor    %ebp,%ebp
  nop
L11:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rbp
  cmp    %rbx,%r15
  jne    L11
  mov    %rbp,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L88
  movb   $0x0,-0x1(%rax,%rbp,1)
  sub    $0x1,%rbp
  je     L50
L15:
  xor    %edx,%edx
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  add    $0x1,%r14
  cmp    %rbp,%rdx
  jae    L50
L24:
  movzbl (%r14),%ecx
  test   %cl,%cl
  jne    L39
  mov    %r13b,(%rax,%rdx,1)
  add    $0x1,%rdx
  mov    0x8(%r12),%r14
  add    $0x8,%r12
  cmp    %rbp,%rdx
  jb     L24
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L80:
  add    $0x8,%rsp
  lea    D11(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <strdup@plt>
  nopw   0x0(%rax,%rax,1)
L54:
  xor    %edi,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L88
  movb   $0x0,-0x1(%rax)
  mov    $0xffffffffffffffff,%rbp
  jmp    L15
  nopl   0x0(%rax)
L79:
  lea    D11(%rip),%rdi
  jmp    1090 <strdup@plt>
L88:
  xor    %eax,%eax
  jmp    L50
```

tool_calls: name: disassemble_data
arguments: data_label: D11
datatype: string

tool: 

assistant: ```c
char *pe_utils_str_array_join(char *strings[], size_t count, char delimiter) {
  if (strings == NULL || strings[0] == NULL)
    return strdup("");
  size_t result_length = 0;
  for (size_t i = 0; i < count; i++) {
    result_length += strlen(strings[i]) + 1;
  }
  char *result = malloc(result_length);
  if (result == NULL)
    return NULL;
  result[--result_length] = '\0';
  char **current_string = strings;
  char *current_char = current_string[0];
  for (size_t i = 0; i < result_length; i++) {
    if (*current_char != '\0') {
      result[i] = *current_char++;
    } else {
      result[i] = delimiter;
      current_string++;
      current_char = current_string[0];
    }
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ptr_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x6968,-0xa(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L46
L1:
  lea    -0xa(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  ja     L11
  addl   $0x2,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  jmp    L5
L11:
  nop
L5:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void ptr_cmp(char *end, int size) {
  char buf[2] = "hi";
  for (int i = 0; i < size; i += 2) {
    if (buf < end) {
      return;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ptr_cmp>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L13
  lea    0x6(%rsp),%rax
  cmp    %rax,%rdi
  ja     L13
  mov    $0x0,%eax
L5:
  add    $0x2,%eax
  cmp    %eax,%esi
  jg     L5
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x18,%rsp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ptr_cmp(char *end, int size) {
  char buf[2] = "hi";
  for (int i = 0; i < size; i += 2) {
    if (buf < end) {
      return;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ptr_cmp>:
  endbr64
  ret
```

assistant: ```c
void ptr_cmp(char *end, int size) {
  char buf[2] = "hi";
  for (int i = 0; i < size; i += 2) {
    if (buf < end) {
      return;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ptr_cmp>:
  endbr64
  ret
```

assistant: ```c
void ptr_cmp(char *end, int size) {
  char buf[2] = "hi";
  for (int i = 0; i < size; i += 2) {
    if (buf < end) {
      return;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<interrogate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x21,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x5a,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0xa6,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int interrogate(uint8_t *pack) {
  uint8_t ptr = 0;
  pack[ptr++] = '!';
  pack[ptr++] = 'Z';
  pack[ptr++] = 0;
  pack[ptr++] = 0xA6;
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<interrogate>:
  endbr64
  movl   $0x21,(%rdi)
  movl   $0x5a,0x4(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0xa6,0xc(%rdi)
  mov    $0x4,%eax
  ret
```

assistant: ```c
int interrogate(uint8_t *pack) {
  uint8_t ptr = 0;
  pack[ptr++] = '!';
  pack[ptr++] = 'Z';
  pack[ptr++] = 0;
  pack[ptr++] = 0xA6;
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<interrogate>:
  endbr64
  movabs $0x5a00000021,%rax
  mov    %rax,(%rdi)
  movabs $0xa600000000,%rax
  mov    %rax,0x8(%rdi)
  mov    $0x4,%eax
  ret
```

assistant: ```c
int interrogate(uint8_t *pack) {
  uint8_t ptr = 0;
  pack[ptr++] = '!';
  pack[ptr++] = 'Z';
  pack[ptr++] = 0;
  pack[ptr++] = 0xA6;
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<interrogate>:
  endbr64
  movdqa D8(%rip),%xmm0
  mov    $0x4,%eax
  movups %xmm0,(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: byte[16]

tool: {"D8": [0x21,0x00,0x00,0x00,0x5a,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xa6,0x00,0x00,0x00]}

assistant: ```c
int interrogate(uint8_t *pack) {
  uint8_t ptr = 0;
  pack[ptr++] = '!';
  pack[ptr++] = 'Z';
  pack[ptr++] = 0;
  pack[ptr++] = 0xA6;
  return ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L75
  cmpl   $0x3,-0x14(%rbp)
  jne    L4
L75:
  mov    $0x1,%eax
  jmp    L64
L4:
  cmpl   $0x1,-0x14(%rbp)
  jle    L78
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L78
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L1
L78:
  mov    $0x0,%eax
  jmp    L64
L1:
  movl   $0x5,-0x8(%rbp)
  jmp    L17
L101:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L5
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L53
L5:
  mov    $0x0,%eax
  jmp    L64
L53:
  addl   $0x6,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L101
  mov    $0x1,%eax
L64:
  leave
  ret
```

assistant: ```c
bool is_prime(const uint64_t num) {
  const uint64_t num_sqrt = (uint64_t)sqrt(num);
  uint64_t i;
  if (num == 2 || num == 3) {
    return true;
  } else if (num < 2 || num % 2 == 0 || num % 3 == 0) {
    return false;
  }
  for (i = 5; i <= num_sqrt; i += 6) {
    if (num % i == 0 || num % (i + 2) == 0) {
      return false;
    }
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_prime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  mov    %eax,%ecx
  lea    -0x2(%rbx),%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  jbe    L41
  mov    $0x0,%eax
  cmp    $0x1,%ebx
  jle    L41
  test   $0x1,%bl
  je     L41
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L41
  cmp    $0x4,%ecx
  jle    L8
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L41
  movslq %ebx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x2,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L41
  mov    $0x5,%esi
L119:
  mov    %esi,%edi
  add    $0x6,%esi
  cmp    %esi,%ecx
  jl     L56
  mov    %ebx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  je     L41
  add    $0x8,%edi
  mov    %ebx,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  test   %edx,%edx
  jne    L119
  jmp    L41
L56:
  mov    $0x1,%eax
L41:
  pop    %rbx
  ret
L8:
  mov    $0x1,%eax
  jmp    L41
```

assistant: ```c
bool is_prime(const uint64_t num) {
  const uint64_t num_sqrt = (uint64_t)sqrt(num);
  uint64_t i;
  if (num == 2 || num == 3) {
    return true;
  } else if (num < 2 || num % 2 == 0 || num % 3 == 0) {
    return false;
  }
  for (i = 5; i <= num_sqrt; i += 6) {
    if (num % i == 0 || num % (i + 2) == 0) {
      return false;
    }
  }
  return true;
}
```