ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<downlo>:
  endbr64
  movslq %ecx,%rcx
  push   %r12
  mov    %rdi,%r9
  mov    %rdx,%rdi
  push   %rbp
  mov    %ecx,%edx
  lea    -0x1(%rcx),%r12d
  mov    $0xffffffff,%r10d
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%edx
  mov    %rcx,%r11
  shr    $0x1f,%ebx
  add    %ecx,%edx
  add    %esi,%ebx
  sar    %edx
  sar    %ebx
  mov    %ebx,%eax
  sub    %edx,%eax
  lea    (%r12,%rax,2),%edx
  cmp    %esi,%edx
  setge  %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  cmovns %eax,%r10d
  js     L98
  xor    %ebp,%ebp
  pxor   %xmm2,%xmm2
  xchg   %ax,%ax
L26:
  movapd %xmm2,%xmm1
  test   %r11d,%r11d
  jle    L83
  lea    0x0(%rbp,%rbp,1),%eax
  movapd %xmm2,%xmm1
  cltq
  lea    (%r9,%rax,8),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L0:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L0
L83:
  movsd  %xmm1,(%r8,%rbp,8)
  add    $0x1,%rbp
  cmp    %ebp,%r10d
  jge    L26
L98:
  add    $0x1,%r10d
  cmp    %r10d,%ebx
  jle    L92
  movslq %r10d,%rbp
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%r12,8),%r10
  nopl   0x0(%rax,%rax,1)
L65:
  lea    0x0(%rbp,%rbp,1),%eax
  test   %r11d,%r11d
  jle    L68
  mov    %rdi,%rdx
  movapd %xmm2,%xmm1
L86:
  mov    %eax,%ecx
  sub    %esi,%ecx
  cmp    %eax,%esi
  cmovle %ecx,%eax
  add    $0x8,%rdx
  movslq %eax,%rcx
  add    $0x1,%eax
  movsd  (%r9,%rcx,8),%xmm0
  mulsd  -0x8(%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cmp    %r10,%rdx
  jne    L86
  movsd  %xmm1,(%r8,%rbp,8)
  add    $0x1,%rbp
  cmp    %ebp,%ebx
  jg     L65
L92:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  movapd %xmm2,%xmm1
  movsd  %xmm1,(%r8,%rbp,8)
  add    $0x1,%rbp
  cmp    %ebp,%ebx
  jg     L65
  jmp    L92
```

assistant: ```c
void downlo(x, n, lpf, m, y) double x[], lpf[], y[];
int n, m;
{
  int n2, mlo, mhi, i, h, j;
  double s;
  n2 = n / 2;
  mlo = m / 2;
  mhi = n2 - mlo;
  if (2 * mhi + (m - 1) >= n)
    --mhi;
  if (mhi < 0)
    mhi = -1;
  for (i = 0; i <= mhi; i++) {
    s = 0.;
    for (h = 0; h < m; h++)
      s += lpf[h] * x[2 * i + h];
    y[i] = s;
  }
  for (i = mhi + 1; i < n2; i++) {
    s = 0.;
    j = 2 * i;
    for (h = 0; h < m; h++) {
      if (j >= n)
        j -= n;
      s += lpf[h] * x[j];
      j++;
    }
    y[i] = s;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<downlo>:
  endbr64
  push   %r14
  mov    %rdx,%r9
  mov    %ecx,%edx
  lea    -0x1(%rcx),%r14d
  push   %r13
  shr    $0x1f,%edx
  push   %r12
  add    %ecx,%edx
  push   %rbp
  mov    %esi,%ebp
  sar    %edx
  shr    $0x1f,%ebp
  push   %rbx
  mov    %ecx,%ebx
  mov    $0xffffffff,%ecx
  add    %esi,%ebp
  sar    %ebp
  mov    %ebp,%eax
  sub    %edx,%eax
  lea    (%r14,%rax,2),%edx
  cmp    %esi,%edx
  setge  %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  cmovns %eax,%ecx
  js     L71
  mov    %ebx,%eax
  mov    %ebx,%r13d
  mov    %rdi,%r10
  shr    %eax
  and    $0xfffffffe,%r13d
  pxor   %xmm3,%xmm3
  xor    %r12d,%r12d
  lea    -0x1(%rax),%r11d
  add    $0x1,%r11
  shl    $0x4,%r11
  nopl   0x0(%rax,%rax,1)
L34:
  movapd %xmm3,%xmm1
  test   %ebx,%ebx
  jle    L83
  lea    (%r12,%r12,1),%eax
  cmp    $0x1,%ebx
  je     L86
  xor    %edx,%edx
  movapd %xmm3,%xmm1
  nopl   0x0(%rax,%rax,1)
L117:
  movupd (%r10,%rdx,1),%xmm0
  movupd (%r9,%rdx,1),%xmm4
  add    $0x10,%rdx
  mulpd  %xmm4,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rdx,%r11
  jne    L117
  movslq %r13d,%rdx
  cmp    %ebx,%r13d
  je     L83
L95:
  add    %edx,%eax
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%r9,%rdx,8),%xmm0
  addsd  %xmm0,%xmm1
L83:
  movsd  %xmm1,(%r8,%r12,8)
  add    $0x1,%r12
  add    $0x10,%r10
  cmp    %r12d,%ecx
  jge    L34
L71:
  add    $0x1,%ecx
  cmp    %ecx,%ebp
  jle    L29
  movslq %ecx,%r11
  lea    0x8(%r9,%r14,8),%r10
  pxor   %xmm3,%xmm3
  cs nopw 0x0(%rax,%rax,1)
L84:
  lea    (%r11,%r11,1),%eax
  test   %ebx,%ebx
  jle    L81
  mov    %r9,%rdx
  movapd %xmm3,%xmm1
  nop
L97:
  mov    %eax,%ecx
  sub    %esi,%ecx
  cmp    %eax,%esi
  cmovle %ecx,%eax
  add    $0x8,%rdx
  movslq %eax,%rcx
  add    $0x1,%eax
  movsd  (%rdi,%rcx,8),%xmm0
  mulsd  -0x8(%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rdx,%r10
  jne    L97
  movsd  %xmm1,(%r8,%r11,8)
  add    $0x1,%r11
  cmp    %r11d,%ebp
  jg     L84
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L81:
  movapd %xmm3,%xmm1
  movsd  %xmm1,(%r8,%r11,8)
  add    $0x1,%r11
  cmp    %r11d,%ebp
  jg     L84
  jmp    L29
L86:
  movapd %xmm3,%xmm1
  xor    %edx,%edx
  jmp    L95
```

assistant: ```c
void downlo(x, n, lpf, m, y) double x[], lpf[], y[];
int n, m;
{
  int n2, mlo, mhi, i, h, j;
  double s;
  n2 = n / 2;
  mlo = m / 2;
  mhi = n2 - mlo;
  if (2 * mhi + (m - 1) >= n)
    --mhi;
  if (mhi < 0)
    mhi = -1;
  for (i = 0; i <= mhi; i++) {
    s = 0.;
    for (h = 0; h < m; h++)
      s += lpf[h] * x[2 * i + h];
    y[i] = s;
  }
  for (i = mhi + 1; i < n2; i++) {
    s = 0.;
    j = 2 * i;
    for (h = 0; h < m; h++) {
      if (j >= n)
        j -= n;
      s += lpf[h] * x[j];
      j++;
    }
    y[i] = s;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: usage: exim_lock [-v] [-q] [-lockfile] [-fcntl] [-flock] [-mbx]
       [-retries <n>] [-interval <n>] [-timeout <n>] [-restore-times]
       <file name> [command]


assistant: ```c
void usage(void) {
  printf("usage: exim_lock [-v] [-q] [-lockfile] [-fcntl] [-flock] [-mbx]\n"
         "       [-retries <n>] [-interval <n>] [-timeout <n>] [-restore-times]\n"
         "       <file name> [command]\n");
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: usage: exim_lock [-v] [-q] [-lockfile] [-fcntl] [-flock] [-mbx]
       [-retries <n>] [-interval <n>] [-timeout <n>] [-restore-times]
       <file name> [command]


assistant: ```c
void usage(void) {
  printf("usage: exim_lock [-v] [-q] [-lockfile] [-fcntl] [-flock] [-mbx]\n"
         "       [-retries <n>] [-interval <n>] [-timeout <n>] [-restore-times]\n"
         "       <file name> [command]\n");
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: usage: exim_lock [-v] [-q] [-lockfile] [-fcntl] [-flock] [-mbx]
       [-retries <n>] [-interval <n>] [-timeout <n>] [-restore-times]
       <file name> [command]


assistant: ```c
void usage(void) {
  printf("usage: exim_lock [-v] [-q] [-lockfile] [-fcntl] [-flock] [-mbx]\n"
         "       [-retries <n>] [-interval <n>] [-timeout <n>] [-restore-times]\n"
         "       <file name> [command]\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: usage: exim_lock [-v] [-q] [-lockfile] [-fcntl] [-flock] [-mbx]
       [-retries <n>] [-interval <n>] [-timeout <n>] [-restore-times]
       <file name> [command]


assistant: ```c
void usage(void) {
  printf("usage: exim_lock [-v] [-q] [-lockfile] [-fcntl] [-flock] [-mbx]\n"
         "       [-retries <n>] [-interval <n>] [-timeout <n>] [-restore-times]\n"
         "       <file name> [command]\n");
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <fini@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  init();
  test();
  fini();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <fini@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  init();
  test();
  fini();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  call   <fini@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  init();
  test();
  fini();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  call   <fini@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  init();
  test();
  fini();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  jmp    L23
L12:
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L38:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L38
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x5,-0x8(%rbp)
  jle    L12
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 5; i++) {
    for (j = 0; j < i; j++) {
      printf("%d", i);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebp
  lea    D6(%rip),%r12
  jmp    L0
L40:
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L40
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    $0x6,%ebp
  je     L34
L0:
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jg     L40
  jmp    L10
L34:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 5; i++) {
    for (j = 0; j < i; j++) {
      printf("%d", i);
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
L11:
  xor    %ebx,%ebx
L10:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L10
  mov    $0xa,%edi
  lea    0x1(%rbx),%ebp
  call   <putchar@plt>
  cmp    $0x5,%ebx
  jne    L11
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 5; i++) {
    for (j = 0; j < i; j++) {
      printf("%d", i);
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
L18:
  xor    %ebx,%ebx
L3:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L3
  mov    $0xa,%edi
  lea    0x1(%rbx),%ebp
  call   <putchar@plt>
  cmp    $0x5,%ebx
  jne    L18
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 5; i++) {
    for (j = 0; j < i; j++) {
      printf("%d", i);
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L4:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L18:
  cmpl   $0x0,-0x14(%rbp)
  jne    L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int factorial(int num) {
  int result = 1;
  while (num)
    result *= num--;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<factorial>:
  endbr64
  test   %edi,%edi
  je     L18
  mov    $0x1,%eax
L4:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L4
  ret
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int factorial(int num) {
  int result = 1;
  while (num)
    result *= num--;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L4
  nopl   (%rax)
L15:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L15
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
int factorial(int num) {
  int result = 1;
  while (num)
    result *= num--;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L12
  nopl   (%rax)
L3:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L3
  ret
  nopl   0x0(%rax)
L12:
  ret
```

assistant: ```c
int factorial(int num) {
  int result = 1;
  while (num)
    result *= num--;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBHostEndpointDataToggle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  cmp    $0x40050000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  mov    %ebp,%eax
  and    $0xffffffef,%eax
  je     L35
  cmp    $0x70,%ebp
  jg     L120
  cmp    $0x3f,%ebp
  jle    L99
  lea    -0x40(%rbp),%eax
  movabs $0x1000100010001,%rdx
  bt     %rax,%rdx
  jb     L110
L120:
  mov    $0x0,%edi
  call   <ASSERT@plt>
  test   %ebx,%ebx
  jne    L76
L17:
  test   %r13d,%r13d
  jne    L85
  lea    0x107(%r12,%rbp,1),%edx
  movslq %edx,%rdx
  mov    (%rdx),%eax
  and    $0xfffffff9,%eax
  or     %ebx,%eax
  or     $0x4,%eax
  mov    %eax,(%rdx)
  jmp    L61
L99:
  cmp    $0x20,%eax
  jne    L120
L110:
  mov    $0x1,%edi
  call   <ASSERT@plt>
  test   %ebx,%ebx
  je     L17
L76:
  test   %ebp,%ebp
  sete   %bl
  test   %r13d,%r13d
  sete   %al
  or     %eax,%ebx
  movzbl %bl,%ebx
  add    $0x1,%ebx
L12:
  test   %ebp,%ebp
  jne    L17
  add    $0x103,%r12d
  movslq %r12d,%r12
  mov    (%r12),%eax
  and    $0xfffffff9,%eax
  or     %ebx,%eax
  or     $0x4,%eax
  mov    %eax,(%r12)
L61:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  mov    $0x1,%edi
  call   <ASSERT@plt>
  test   %ebx,%ebx
  je     L12
  jmp    L76
L85:
  lea    0x103(%r12,%rbp,1),%edx
  movslq %edx,%rdx
  mov    (%rdx),%eax
  and    $0xfffffffc,%eax
  or     %ebx,%eax
  or     $0x2,%eax
  mov    %eax,(%rdx)
  jmp    L61
```

assistant: ```c
void USBHostEndpointDataToggle(uint32_t ui32Base, uint32_t ui32Endpoint, bool bDataToggle, uint32_t ui32Flags) {
  uint32_t ui32DataToggle;
  ASSERT(ui32Base == 0x40050000);
  ASSERT((ui32Endpoint == 0x00000000) || (ui32Endpoint == 0x00000010) || (ui32Endpoint == 0x00000020) || (ui32Endpoint == 0x00000030) || (ui32Endpoint == 0x00000040) || (ui32Endpoint == 0x00000050) || (ui32Endpoint == 0x00000060) || (ui32Endpoint == 0x00000070));
  ui32DataToggle = 0;
  if (bDataToggle) {
    if (ui32Endpoint == 0x00000000) {
      ui32DataToggle = 0x00000002;
    } else if (ui32Flags == 0x00000000) {
      ui32DataToggle = 0x00000002;
    } else {
      ui32DataToggle = 0x00000001;
    }
  }
  if (ui32Endpoint == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000103))) = (((*((volatile uint8_t *)(ui32Base + 0x00000103))) & ~(0x00000004 | 0x00000002)) | (ui32DataToggle | 0x00000004));
  } else if (ui32Flags == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000117 + (ui32Endpoint - 0x10)))) = (((*((volatile uint8_t *)(ui32Base + 0x00000117 + (ui32Endpoint - 0x10)))) & ~(0x00000004 | 0x00000002)) | (ui32DataToggle | 0x00000004));
  } else {
    (*((volatile uint8_t *)(ui32Base + 0x00000113 + (ui32Endpoint - 0x10)))) = (((*((volatile uint8_t *)(ui32Base + 0x00000113 + (ui32Endpoint - 0x10)))) & ~(0x00000002 | 0x00000001)) | (ui32DataToggle | 0x00000002));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<allocate2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L17
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
L17:
  mov    $0x0,%eax
  jmp    L36
L38:
  movl   $0x0,-0x14(%rbp)
  jmp    L33
L42:
  mov    -0x14(%rbp),%eax
  imul   -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L42
  mov    -0x8(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
char **allocate2D(int n) {
  char *temp = malloc(n * n * sizeof(char));
  char **a = malloc(n * sizeof(char *));
  if (!temp || !a)
    return NULL;
  for (int i = 0; i < n; i++)
    a[i] = temp + i * n;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<allocate2D>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  imul   %edi,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  test   %rbx,%rbx
  je     L17
  movslq %ebp,%r12
  test   %rax,%rax
  je     L17
  test   %ebp,%ebp
  jle    L39
  mov    %rbx,%rcx
  mov    %rax,%rdx
  mov    %ebp,%ebp
  lea    (%rax,%rbp,8),%rsi
L37:
  mov    %rcx,(%rdx)
  add    %r12,%rcx
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L37
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
char **allocate2D(int n) {
  char *temp = malloc(n * n * sizeof(char));
  char **a = malloc(n * sizeof(char *));
  if (!temp || !a)
    return NULL;
  for (int i = 0; i < n; i++)
    a[i] = temp + i * n;
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<allocate2D>:
  endbr64
  push   %r12
  movslq %edi,%r12
  mov    %r12d,%edi
  push   %rbp
  imul   %r12d,%edi
  push   %rbx
  call   <malloc@plt>
  lea    0x0(,%r12,8),%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  test   %rbx,%rbx
  je     L25
  test   %rax,%rax
  je     L25
  test   %r12d,%r12d
  jle    L0
  mov    %r12d,%ebp
  mov    %rbx,%rcx
  mov    %rax,%rdx
  lea    (%rax,%rbp,8),%rsi
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rcx,(%rdx)
  add    $0x8,%rdx
  add    %r12,%rcx
  cmp    %rsi,%rdx
  jne    L20
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **allocate2D(int n) {
  char *temp = malloc(n * n * sizeof(char));
  char **a = malloc(n * sizeof(char *));
  if (!temp || !a)
    return NULL;
  for (int i = 0; i < n; i++)
    a[i] = temp + i * n;
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<allocate2D>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  imul   %edi,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  test   %rbp,%rbp
  je     L81
  mov    %rax,%r8
  test   %rax,%rax
  je     L81
  test   %ebx,%ebx
  jle    L30
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L27
  movd   %ebx,%xmm5
  mov    %ebx,%edx
  movq   %rbp,%xmm3
  mov    %r8,%rax
  pshufd $0x0,%xmm5,%xmm4
  shr    $0x2,%edx
  punpcklqdq %xmm3,%xmm3
  movdqa D9(%rip),%xmm2
  shl    $0x5,%rdx
  movdqa %xmm4,%xmm6
  movdqa D3(%rip),%xmm7
  pxor   %xmm5,%xmm5
  add    %r8,%rdx
  psrlq  $0x20,%xmm6
  nopw   0x0(%rax,%rax,1)
L67:
  movdqa %xmm2,%xmm1
  movdqa %xmm5,%xmm8
  paddd  %xmm7,%xmm2
  add    $0x20,%rax
  movdqa %xmm1,%xmm0
  psrlq  $0x20,%xmm1
  pmuludq %xmm4,%xmm0
  pmuludq %xmm6,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  pcmpgtd %xmm0,%xmm8
  movdqa %xmm0,%xmm1
  punpckldq %xmm8,%xmm1
  punpckhdq %xmm8,%xmm0
  paddq  %xmm3,%xmm1
  paddq  %xmm3,%xmm0
  movups %xmm1,-0x20(%rax)
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L67
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L30
L29:
  mov    %ebx,%edx
  movslq %eax,%rdi
  imul   %eax,%edx
  lea    0x0(,%rdi,8),%rsi
  movslq %edx,%rcx
  add    %rbp,%rcx
  mov    %rcx,(%r8,%rdi,8)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%ebx
  jle    L30
  add    %ebx,%edx
  add    $0x2,%eax
  movslq %edx,%rcx
  add    %rbp,%rcx
  mov    %rcx,0x8(%r8,%rsi,1)
  cmp    %eax,%ebx
  jle    L30
  add    %edx,%ebx
  movslq %ebx,%rbx
  add    %rbx,%rbp
  mov    %rbp,0x10(%r8,%rsi,1)
L30:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L81:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L27:
  xor    %eax,%eax
  jmp    L29
```

tool_calls: name: parse_data
arguments: tag: D9
type: byte[16]
name: parse_data
arguments: tag: D3
type: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D3": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
char **allocate2D(int n) {
  char *temp = malloc(n * n * sizeof(char));
  char **a = malloc(n * sizeof(char *));
  if (!temp || !a)
    return NULL;
  for (int i = 0; i < n; i++)
    a[i] = temp + i * n;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strnzcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <vassert@plt>
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <vassert@plt>
  jmp    L18
L7:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L18:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  cmpq   $0x1,-0x28(%rbp)
  ja     L7
L16:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string
name: parse_data
arguments: data_label: D13
data_type: string

tool: D5: from == NULL

tool: D13: to == NULL

assistant: ```c
size_t strnzcpy(char *to, const char *from, size_t size) {
  char *res = to;
  vassert(from != NULL, "from == NULL");
  vassert(to != NULL, "to == NULL");
  while (*from && size > 1) {
    *to++ = *from++;
    size--;
  }
  *to = '\0';
  return to - res;
}
```