ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<rmse>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L40
  cmp    $0x1,%edx
  je     L29
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L33:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  subpd  %xmm3,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L33
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%dl
  je     L48
L21:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L48:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  divsd  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D2(%rip),%xmm0
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  pxor   %xmm0,%xmm0
  jmp    L48
L29:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: f64

tool: D2: 255

assistant: ```c
double rmse(double *x1, double *x2, int l) {
  double diff;
  double rmse = 0.0;
  for (int i = 0; i < l; i++) {
    diff = x1[i] - x2[i];
    rmse += diff * diff;
  }
  rmse = sqrt(rmse / (double)l) / 255.;
  return rmse;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<assert_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x410(%rbp)
  movq   $0x0,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %eax,%edx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L13
  mov    $0x0,%edi
  call   <exit@plt>
L13:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D0:  

tool: D4: exit

assistant: ```c
void assert_exit(char *cmd) {
  char temp[1024] = "";
  strcpy(temp, cmd);
  if (!strcmp(strtok(temp, " "), "exit"))
    exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assert_exit>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %eax,%edi
  lea    D14(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L18
L25:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x410,%rsp
  pop    %rbx
  ret
L18:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L25
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D14
type_infered: string

tool: D8:  

tool: D14: exit

assistant: ```c
void assert_exit(char *cmd) {
  char temp[1024] = "";
  strcpy(temp, cmd);
  if (!strcmp(strtok(temp, " "), "exit"))
    exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<assert_exit>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  lea    D8(%rip),%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L0
L20:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x410,%rsp
  pop    %rbp
  ret
  nop
L0:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L20
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string
name: unpack_data
arguments: label: D8
type: string

tool: D9:  

tool: D8: exit

assistant: ```c
void assert_exit(char *cmd) {
  char temp[1024] = "";
  strcpy(temp, cmd);
  if (!strcmp(strtok(temp, " "), "exit"))
    exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assert_exit>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  lea    D7(%rip),%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L29
L2:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x410,%rsp
  pop    %rbp
  ret
  nop
L29:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L2
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string
name: read_data
arguments: data_label: D7
datatype: string

tool: D0:  

tool: D7: exit

assistant: ```c
void assert_exit(char *cmd) {
  char temp[1024] = "";
  strcpy(temp, cmd);
  if (!strcmp(strtok(temp, " "), "exit"))
    exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<to_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L58:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L33
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x57,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L46
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
L46:
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  mov    -0xc(%rbp),%eax
  shl    $0x4,%eax
  add    %eax,-0x8(%rbp)
  jmp    L40
L0:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
L40:
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x1,-0x4(%rbp)
  jle    L58
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int to_dec(char *hex_number) {
  int temp;
  int result = 0;
  for (int i = 0; i < 2; i++) {
    if (hex_number[i] > '9') {
      temp = hex_number[i] - 'a' + 10;
    } else
      temp = hex_number[i] - '0';
    if (i == 0)
      result = temp * 16 + result;
    else
      result = result + temp;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<to_dec>:
  endbr64
  mov    $0x1,%esi
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L8
L23:
  movsbl %al,%eax
  sub    $0x30,%eax
  jmp    L3
L45:
  shl    $0x4,%eax
  add    %eax,%ecx
L48:
  add    $0x1,%rdx
  add    $0x1,%esi
L8:
  movzbl (%rdi,%rdx,1),%eax
  cmp    $0x39,%al
  jle    L23
  movsbl %al,%eax
  sub    $0x57,%eax
L3:
  test   %edx,%edx
  je     L45
  add    %eax,%ecx
  cmp    $0x1,%esi
  jle    L48
  mov    %ecx,%eax
  ret
```

assistant: ```c
int to_dec(char *hex_number) {
  int temp;
  int result = 0;
  for (int i = 0; i < 2; i++) {
    if (hex_number[i] > '9') {
      temp = hex_number[i] - 'a' + 10;
    } else
      temp = hex_number[i] - '0';
    if (i == 0)
      result = temp * 16 + result;
    else
      result = result + temp;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_dec>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0x39,%al
  jg     L10
  movsbl 0x1(%rdi),%edx
  sub    $0x30,%eax
  shl    $0x4,%eax
  cmp    $0x39,%dl
  jg     L8
L29:
  sub    $0x30,%edx
  add    %edx,%eax
  ret
L10:
  sub    $0x57,%eax
  movsbl 0x1(%rdi),%edx
  movsbl %al,%eax
  shl    $0x4,%eax
  cmp    $0x39,%dl
  jle    L29
L8:
  sub    $0x57,%edx
  movsbl %dl,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int to_dec(char *hex_number) {
  int temp;
  int result = 0;
  for (int i = 0; i < 2; i++) {
    if (hex_number[i] > '9') {
      temp = hex_number[i] - 'a' + 10;
    } else
      temp = hex_number[i] - '0';
    if (i == 0)
      result = temp * 16 + result;
    else
      result = result + temp;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_dec>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0x39,%al
  jg     L17
  movsbl 0x1(%rdi),%edx
  sub    $0x30,%eax
  shl    $0x4,%eax
  cmp    $0x39,%dl
  jg     L29
L7:
  sub    $0x30,%edx
  add    %edx,%eax
  ret
L17:
  sub    $0x57,%eax
  movsbl 0x1(%rdi),%edx
  movsbl %al,%eax
  shl    $0x4,%eax
  cmp    $0x39,%dl
  jle    L7
L29:
  sub    $0x57,%edx
  movsbl %dl,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int to_dec(char *hex_number) {
  int temp;
  int result = 0;
  for (int i = 0; i < 2; i++) {
    if (hex_number[i] > '9') {
      temp = hex_number[i] - 'a' + 10;
    } else
      temp = hex_number[i] - '0';
    if (i == 0)
      result = temp * 16 + result;
    else
      result = result + temp;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D37
type_infered: string
name: parse_data
arguments: data_label: D45
type_infered: string

tool: D37: *******


tool: D45: *


assistant: ```c
void main() {
  printf("*******\n");
  printf("*\n");
  printf("*\n");
  printf("*\n");
  printf("*\n");
  printf("*******\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type: string
name: unpack_data
arguments: data_label: D8
type: string

tool: D16: *******


tool: D8: *


assistant: ```c
void main() {
  printf("*******\n");
  printf("*\n");
  printf("*\n");
  printf("*\n");
  printf("*\n");
  printf("*******\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D14(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D14
type: string

tool: D19: *******


tool: D14: *


assistant: ```c
void main() {
  printf("*******\n");
  printf("*\n");
  printf("*\n");
  printf("*\n");
  printf("*\n");
  printf("*******\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D0(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D19: *******


tool: D0: *


assistant: ```c
void main() {
  printf("*******\n");
  printf("*\n");
  printf("*\n");
  printf("*\n");
  printf("*\n");
  printf("*******\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HexDecode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L27
  cmpb   $0x39,-0x4(%rbp)
  jg     L27
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L66
L27:
  cmpb   $0x40,-0x4(%rbp)
  jle    L83
  cmpb   $0x46,-0x4(%rbp)
  jg     L83
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L66
L83:
  cmpb   $0x60,-0x4(%rbp)
  jle    L7
  cmpb   $0x66,-0x4(%rbp)
  jg     L7
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L66
L7:
  mov    $0xffffffff,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int HexDecode(char x) {
  if (x >= '0' && x <= '9')
    return (x - '0');
  if (x >= 'A' && x <= 'F')
    return (x - 'A' + 10);
  if (x >= 'a' && x <= 'f')
    return (x - 'a' + 10);
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HexDecode>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L13
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L12
  lea    -0x61(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x57,%eax
  cmp    $0x6,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L13:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L12:
  movsbl %dil,%edi
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
int HexDecode(char x) {
  if (x >= '0' && x <= '9')
    return (x - '0');
  if (x >= 'A' && x <= 'F')
    return (x - 'A' + 10);
  if (x >= 'a' && x <= 'f')
    return (x - 'a' + 10);
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<HexDecode>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L6
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L11
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl %al,%eax
  ret
```

assistant: ```c
int HexDecode(char x) {
  if (x >= '0' && x <= '9')
    return (x - '0');
  if (x >= 'A' && x <= 'F')
    return (x - 'A' + 10);
  if (x >= 'a' && x <= 'f')
    return (x - 'a' + 10);
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HexDecode>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L15
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L13
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movsbl %al,%eax
  ret
```

assistant: ```c
int HexDecode(char x) {
  if (x >= '0' && x <= '9')
    return (x - '0');
  if (x >= 'A' && x <= 'F')
    return (x - 'A' + 10);
  if (x >= 'a' && x <= 'f')
    return (x - 'a' + 10);
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_45_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_45_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_45_1_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  or     $0xffffff00,%edi
  xor    %edi,%esi
  mov    %esi,%eax
  xor    $0xff,%al
  and    %edx,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_45_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_45_1_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%eax
  mov    %edi,%edx
  mov    %eax,%esi
  shl    $0x8,%edx
  shl    $0x8,%esi
  or     %edi,%edx
  or     %eax,%esi
  or     $0xffffff00,%edi
  xor    %edi,%esi
  mov    %esi,%eax
  xor    $0xff,%al
  and    %edx,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_45_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrop3_45_1_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%eax
  mov    %edi,%edx
  mov    %eax,%esi
  shl    $0x8,%edx
  shl    $0x8,%esi
  or     %edi,%edx
  or     %eax,%esi
  or     $0xffffff00,%edi
  xor    %edi,%esi
  mov    %esi,%eax
  xor    $0xff,%al
  and    %edx,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_45_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<string_decode_base16>:
  endbr64
  test   %rdi,%rdi
  je     L74
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L18
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movb   $0x0,0x0(%rbp)
  cmp    $0x1,%edi
  jle    L61
  mov    $0x0,%edx
  jmp    L12
L27:
  lea    -0x61(%rcx),%esi
  cmp    $0x5,%sil
  ja     L42
  shl    $0x4,%ecx
  lea    -0x70(%rcx),%esi
L56:
  movzbl 0x1(%rbx,%rdx,2),%ecx
  lea    -0x30(%rcx),%r8d
  cmp    $0x9,%r8b
  ja     L128
  or     %r8d,%esi
L30:
  mov    %sil,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jle    L33
L12:
  movzbl (%rbx,%rdx,2),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  ja     L27
  mov    %ecx,%esi
  shl    $0x4,%esi
  jmp    L56
L42:
  lea    -0x41(%rcx),%r8d
  shl    $0x4,%ecx
  sub    $0x70,%ecx
  cmp    $0x6,%r8b
  mov    $0x0,%esi
  cmovb  %ecx,%esi
  jmp    L56
L128:
  lea    -0x61(%rcx),%r8d
  cmp    $0x5,%r8b
  ja     L132
  sub    $0x57,%ecx
  or     %ecx,%esi
  jmp    L30
L132:
  lea    -0x41(%rcx),%r8d
  sub    $0x37,%ecx
  or     %esi,%ecx
  cmp    $0x6,%r8b
  cmovb  %ecx,%esi
  jmp    L30
L33:
  lea    -0x1(%rax),%edx
  add    $0x1,%rdx
  cmp    $0x1,%edi
  mov    $0x1,%ecx
  cmovle %rcx,%rdx
  add    %rdx,%rbp
  test   %eax,%eax
  mov    $0x1,%edx
  cmovle %edx,%eax
L83:
  movb   $0x0,0x0(%rbp)
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L61:
  mov    $0x0,%eax
  jmp    L83
L74:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int string_decode_base16(const char *from, char *to) {
  int length, to_length, i, pos;
  unsigned char *ptr_to, value;
  if (!from || !to)
    return 0;
  length = strlen(from) / 2;
  ptr_to = (unsigned char *)to;
  ptr_to[0] = '\0';
  to_length = 0;
  for (i = 0; i < length; i++) {
    pos = i * 2;
    value = 0;
    if ((from[pos] >= '0') && (from[pos] <= '9'))
      value |= (from[pos] - '0') << 4;
    else if ((from[pos] >= 'a') && (from[pos] <= 'f'))
      value |= (from[pos] - 'a' + 10) << 4;
    else if ((from[pos] >= 'A') && (from[pos] <= 'F'))
      value |= (from[pos] - 'A' + 10) << 4;
    pos++;
    if ((from[pos] >= '0') && (from[pos] <= '9'))
      value |= from[pos] - '0';
    else if ((from[pos] >= 'a') && (from[pos] <= 'f'))
      value |= from[pos] - 'a' + 10;
    else if ((from[pos] >= 'A') && (from[pos] <= 'F'))
      value |= from[pos] - 'A' + 10;
    ptr_to[0] = value;
    ptr_to++;
    to_length++;
  }
  ptr_to[0] = '\0';
  return to_length;
}
```