ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<encode>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%edx
  cmp    $0x19,%edx
  ja     L7
  mov    %edx,%eax
  cltq
  movsbl (%rsi,%rax,1),%eax
L7:
  ret
```

assistant: ```c
char encode(int plainChar, char *permutation) {
  int charPosition = plainChar;
  int encodedChar = 0;
  if ((plainChar >= 97) && (plainChar <= 122)) {
    charPosition = plainChar - 97;
    encodedChar = permutation[charPosition];
  } else {
    encodedChar = plainChar;
  }
  return encodedChar;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encode>:
  endbr64
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L4
  mov    %edi,%eax
  ret
  nop
L4:
  cltq
  movzbl (%rsi,%rax,1),%eax
  ret
```

assistant: ```c
char encode(int plainChar, char *permutation) {
  int charPosition = plainChar;
  int encodedChar = 0;
  if ((plainChar >= 97) && (plainChar <= 122)) {
    charPosition = plainChar - 97;
    encodedChar = permutation[charPosition];
  } else {
    encodedChar = plainChar;
  }
  return encodedChar;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<encode>:
  endbr64
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L7
  mov    %edi,%eax
  ret
  nop
L7:
  cltq
  movzbl (%rsi,%rax,1),%eax
  ret
```

assistant: ```c
char encode(int plainChar, char *permutation) {
  int charPosition = plainChar;
  int encodedChar = 0;
  if ((plainChar >= 97) && (plainChar <= 122)) {
    charPosition = plainChar - 97;
    encodedChar = permutation[charPosition];
  } else {
    encodedChar = plainChar;
  }
  return encodedChar;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<file2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L26
  mov    $0x0,%eax
  call   <error@plt>
L26:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L11
  mov    $0x0,%eax
  call   <error@plt>
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L2
  mov    $0x0,%eax
  call   <error@plt>
L2:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    -0x18(%rbp),%rdx
  cmp    %rdx,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
char *file2bin(const char *filename, size_t *size) {
  int fd;
  struct stat st;
  char *buf;
  if (stat(filename, &st) == -1)
    error();
  if ((fd = open(filename, O_RDONLY)) == -1)
    error();
  if ((buf = malloc(st.st_size)) == NULL)
    error();
  assert(read(fd, buf, st.st_size) == st.st_size);
  *size = st.st_size;
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<file2bin>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L35
L68:
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L65
L51:
  mov    (%rsp),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L44
L8:
  mov    (%rsp),%rdx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    %rax,(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rsp),%rax
  mov    %rax,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L68
L65:
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L51
L44:
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L8
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *file2bin(const char *filename, size_t *size) {
  int fd;
  struct stat st;
  char *buf;
  if (stat(filename, &st) == -1)
    error();
  if ((fd = open(filename, O_RDONLY)) == -1)
    error();
  if ((buf = malloc(st.st_size)) == NULL)
    error();
  assert(read(fd, buf, st.st_size) == st.st_size);
  *size = st.st_size;
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<file2bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L69
L0:
  mov    D7(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L15
L63:
  mov    (%rsp),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L43
L39:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  xor    %edi,%edi
  cmp    %rax,(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L69:
  xor    %eax,%eax
  call   <error@plt>
  jmp    L0
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  call   <error@plt>
  jmp    L63
L32:
  call   <__stack_chk_fail@plt>
L43:
  xor    %eax,%eax
  call   <error@plt>
  mov    (%rsp),%r13
  jmp    L39
```

assistant: ```c
char *file2bin(const char *filename, size_t *size) {
  int fd;
  struct stat st;
  char *buf;
  if (stat(filename, &st) == -1)
    error();
  if ((fd = open(filename, O_RDONLY)) == -1)
    error();
  if ((buf = malloc(st.st_size)) == NULL)
    error();
  assert(read(fd, buf, st.st_size) == st.st_size);
  *size = st.st_size;
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<file2bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L66
L58:
  mov    D4(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L59
L50:
  mov    (%rsp),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
L19:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  xor    %edi,%edi
  cmp    %rax,(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L66:
  xor    %eax,%eax
  call   <error@plt>
  jmp    L58
  nopl   0x0(%rax)
L59:
  xor    %eax,%eax
  call   <error@plt>
  jmp    L50
L51:
  call   <__stack_chk_fail@plt>
L6:
  xor    %eax,%eax
  call   <error@plt>
  mov    (%rsp),%r13
  jmp    L19
```

assistant: ```c
char *file2bin(const char *filename, size_t *size) {
  int fd;
  struct stat st;
  char *buf;
  if (stat(filename, &st) == -1)
    error();
  if ((fd = open(filename, O_RDONLY)) == -1)
    error();
  if ((buf = malloc(st.st_size)) == NULL)
    error();
  assert(read(fd, buf, st.st_size) == st.st_size);
  *size = st.st_size;
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getBuckets64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L29
  movq   $0x0,-0x10(%rbp)
  jmp    L26
L14:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L14
  jmp    L10
L29:
  movq   $0x0,-0x10(%rbp)
  jmp    L39
L9:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L9
L10:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getBuckets64(const long long *C, long long *B, long long k, long long end) {
  long long i, sum = 0;
  if (end) {
    for (i = 0; i < k; ++i) {
      sum += C[i];
      B[i] = sum;
    }
  } else {
    for (i = 0; i < k; ++i) {
      sum += C[i];
      B[i] = sum - C[i];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getBuckets64>:
  endbr64
  test   %rcx,%rcx
  jne    L36
  mov    %rcx,%rax
  test   %rdx,%rdx
  jle    L39
L35:
  mov    %rax,%r8
  add    (%rdi,%rcx,8),%rax
  mov    %r8,(%rsi,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L35
L34:
  ret
L39:
  ret
L36:
  test   %rdx,%rdx
  jle    L34
  mov    $0x0,%r8d
  mov    $0x0,%eax
L47:
  mov    %r8,%rcx
  add    (%rdi,%rax,8),%rcx
  mov    %rcx,%r8
  mov    %rcx,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L47
  ret
```

assistant: ```c
void getBuckets64(const long long *C, long long *B, long long k, long long end) {
  long long i, sum = 0;
  if (end) {
    for (i = 0; i < k; ++i) {
      sum += C[i];
      B[i] = sum;
    }
  } else {
    for (i = 0; i < k; ++i) {
      sum += C[i];
      B[i] = sum - C[i];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getBuckets64>:
  endbr64
  test   %rcx,%rcx
  jne    L4
  xor    %eax,%eax
  test   %rdx,%rdx
  jle    L16
L10:
  mov    %rcx,%r8
  add    (%rdi,%rax,8),%rcx
  mov    %r8,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L10
L39:
  ret
  nopl   (%rax)
L4:
  test   %rdx,%rdx
  jle    L39
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L15:
  add    (%rdi,%rax,8),%rcx
  mov    %rcx,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L15
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void getBuckets64(const long long *C, long long *B, long long k, long long end) {
  long long i, sum = 0;
  if (end) {
    for (i = 0; i < k; ++i) {
      sum += C[i];
      B[i] = sum;
    }
  } else {
    for (i = 0; i < k; ++i) {
      sum += C[i];
      B[i] = sum - C[i];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getBuckets64>:
  endbr64
  test   %rcx,%rcx
  jne    L24
  xor    %eax,%eax
  test   %rdx,%rdx
  jle    L49
L35:
  mov    %rcx,%r8
  add    (%rdi,%rax,8),%rcx
  mov    %r8,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L35
L16:
  ret
  nopl   (%rax)
L24:
  test   %rdx,%rdx
  jle    L16
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L40:
  add    (%rdi,%rax,8),%rcx
  mov    %rcx,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L40
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  ret
```

assistant: ```c
void getBuckets64(const long long *C, long long *B, long long k, long long end) {
  long long i, sum = 0;
  if (end) {
    for (i = 0; i < k; ++i) {
      sum += C[i];
      B[i] = sum;
    }
  } else {
    for (i = 0; i < k; ++i) {
      sum += C[i];
      B[i] = sum - C[i];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<replace_env>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <find_env@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x13a,%edx
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <xfree@plt>
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/gary9872/tf40s1/refs/heads/master/src/variable.c

assistant: ```c
void replace_env(str) char *str;
{
  char **envp;
  envp = find_env(str);
  xfree((void *)(*envp), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/gary9872/tf40s1/refs/heads/master/src/variable.c", 314);
  *envp = str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<replace_env>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <find_env@plt>
  movslq %eax,%rbx
  mov    $0x13a,%edx
  lea    D9(%rip),%rsi
  mov    (%rbx),%rdi
  mov    $0x0,%eax
  call   <xfree@plt>
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/gary9872/tf40s1/refs/heads/master/src/variable.c

assistant: ```c
void replace_env(str) char *str;
{
  char **envp;
  envp = find_env(str);
  xfree((void *)(*envp), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/gary9872/tf40s1/refs/heads/master/src/variable.c", 314);
  *envp = str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<replace_env>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <find_env@plt>
  mov    $0x13a,%edx
  lea    D7(%rip),%rsi
  movslq %eax,%rbx
  xor    %eax,%eax
  mov    (%rbx),%rdi
  call   <xfree@plt>
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/gary9872/tf40s1/refs/heads/master/src/variable.c

assistant: ```c
void replace_env(str) char *str;
{
  char **envp;
  envp = find_env(str);
  xfree((void *)(*envp), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/gary9872/tf40s1/refs/heads/master/src/variable.c", 314);
  *envp = str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<replace_env>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <find_env@plt>
  mov    $0x13a,%edx
  lea    D6(%rip),%rsi
  movslq %eax,%rbx
  xor    %eax,%eax
  mov    (%rbx),%rdi
  call   <xfree@plt>
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/gary9872/tf40s1/refs/heads/master/src/variable.c

assistant: ```c
void replace_env(str) char *str;
{
  char **envp;
  envp = find_env(str);
  xfree((void *)(*envp), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/gary9872/tf40s1/refs/heads/master/src/variable.c", 314);
  *envp = str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <report@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void fatal(const char *label) {
  report(label);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  call   <report@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fatal(const char *label) {
  report(label);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  call   <report@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <exit@plt>
```

assistant: ```c
void fatal(const char *label) {
  report(label);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  call   <report@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <exit@plt>
```

assistant: ```c
void fatal(const char *label) {
  report(label);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <check_atoi_safe@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  check_atoi_safe();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <check_atoi_safe@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  check_atoi_safe();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <check_atoi_safe@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  check_atoi_safe();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <check_atoi_safe@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  check_atoi_safe();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_int_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1c,-0x10(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <print_string@plt>
  movl   $0xf0000000,-0x14(%rbp)
  jmp    L4
L7:
  mov    -0x24(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <print_char@plt>
  subl   $0x4,-0x10(%rbp)
  sarl   $0x4,-0x14(%rbp)
L4:
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    $0x0,%eax
  call   <print_done@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string

tool: D18: 0123456789ABCDEF

tool: D10: 0x

assistant: ```c
void print_int_hex(value) int value;
{
  const char *alphabet = "0123456789ABCDEF";
  int mask;
  int nibble_index = 32 - 4;
  int nibble;
  print_string("0x");
  for (mask = 0xF0000000; mask != 0; mask >>= 4) {
    nibble = (value & mask) >> nibble_index;
    print_char(alphabet[nibble]);
    nibble_index -= 4;
  }
  print_done();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_int_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <print_string@plt>
  mov    $0x1c,%ebp
  mov    $0xf0000000,%ebx
  lea    D14(%rip),%r13
L6:
  mov    %ebx,%eax
  and    %r12d,%eax
  mov    %ebp,%ecx
  sar    %cl,%eax
  cltq
  movsbl 0x0(%r13,%rax,1),%edi
  mov    $0x0,%eax
  call   <print_char@plt>
  sub    $0x4,%ebp
  sar    $0x4,%ebx
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string

tool: D3: 0x

tool: D14: 0123456789ABCDEF

assistant: ```c
void print_int_hex(value) int value;
{
  const char *alphabet = "0123456789ABCDEF";
  int mask;
  int nibble_index = 32 - 4;
  int nibble;
  print_string("0x");
  for (mask = 0xF0000000; mask != 0; mask >>= 4) {
    nibble = (value & mask) >> nibble_index;
    print_char(alphabet[nibble]);
    nibble_index -= 4;
  }
  print_done();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_int_hex>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    $0x1c,%r13d
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D3(%rip),%rdi
  push   %rbx
  mov    $0xf0000000,%ebx
  sub    $0x8,%rsp
  call   <print_string@plt>
L5:
  mov    %ebx,%eax
  mov    %r13d,%ecx
  sar    $0x4,%ebx
  sub    $0x4,%r13d
  and    %ebp,%eax
  sar    %cl,%eax
  cltq
  movsbl (%r12,%rax,1),%edi
  xor    %eax,%eax
  call   <print_char@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D1: 0123456789ABCDEF

tool: D3: 0x

assistant: ```c
void print_int_hex(value) int value;
{
  const char *alphabet = "0123456789ABCDEF";
  int mask;
  int nibble_index = 32 - 4;
  int nibble;
  print_string("0x");
  for (mask = 0xF0000000; mask != 0; mask >>= 4) {
    nibble = (value & mask) >> nibble_index;
    print_char(alphabet[nibble]);
    nibble_index -= 4;
  }
  print_done();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_int_hex>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    $0x1c,%r13d
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D7(%rip),%rdi
  push   %rbx
  mov    $0xf0000000,%ebx
  sub    $0x8,%rsp
  call   <print_string@plt>
L6:
  mov    %ebx,%eax
  mov    %r13d,%ecx
  sar    $0x4,%ebx
  sub    $0x4,%r13d
  and    %ebp,%eax
  sar    %cl,%eax
  cltq
  movsbl (%r12,%rax,1),%edi
  xor    %eax,%eax
  call   <print_char@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D7
data_type: string

tool: D19: 0123456789ABCDEF

tool: D7: 0x

assistant: ```c
void print_int_hex(value) int value;
{
  const char *alphabet = "0123456789ABCDEF";
  int mask;
  int nibble_index = 32 - 4;
  int nibble;
  print_string("0x");
  for (mask = 0xF0000000; mask != 0; mask >>= 4) {
    nibble = (value & mask) >> nibble_index;
    print_char(alphabet[nibble]);
    nibble_index -= 4;
  }
  print_done();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<allocate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *allocate(int n) {
  int *allocated = (int *)malloc(n * sizeof(int));
  return allocated;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<allocate>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x2,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *allocate(int n) {
  int *allocated = (int *)malloc(n * sizeof(int));
  return allocated;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<allocate>:
  endbr64
  shl    $0x2,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
int *allocate(int n) {
  int *allocated = (int *)malloc(n * sizeof(int));
  return allocated;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<allocate>:
  endbr64
  shl    $0x2,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
int *allocate(int n) {
  int *allocated = (int *)malloc(n * sizeof(int));
  return allocated;
}
```