ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<insertionSort>:
  endbr64
  push   %r15
  movslq %edi,%rax
  push   %r14
  mov    %rax,%r15
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    -0x4(%rsi,%rax,4),%r12d
  sub    $0x1,%eax
  movslq %eax,%rbp
  lea    (%rsi,%rbp,4),%rbx
  test   %eax,%eax
  js     L23
  mov    %rsi,%r13
  jmp    L82
L25:
  jl     L33
L80:
  sub    $0x1,%rbp
  sub    $0x4,%rbx
  cmp    $0xffffffff,%ebp
  je     L23
L82:
  mov    (%rbx),%eax
  cmp    %r12d,%eax
  jle    L25
  mov    %eax,0x4(%rbx)
  mov    %r13,%rsi
  mov    %r15d,%edi
  lea    0x4(%rbx),%r14
  call   <print_arr@plt>
  cmp    %r12d,(%rbx)
  jl     L9
  jle    L80
  test   %ebp,%ebp
  jne    L80
  mov    %r12d,(%rbx)
L38:
  add    $0x8,%rsp
  mov    %r13,%rsi
  mov    %r15d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <print_arr@plt>
  nop
L33:
  lea    0x4(%r13,%rbp,4),%r14
L9:
  mov    %r12d,(%r14)
  jmp    L38
L23:
  pop    %rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void insertionSort(int ar_size, int *ar) {
  int temp = ar[ar_size - 1];
  for (int i = ar_size - 1; i > -1; i--) {
    if (ar[i] > temp) {
      ar[i + 1] = ar[i];
      print_arr(ar_size, ar);
    }
    if (ar[i] < temp) {
      ar[i + 1] = temp;
      print_arr(ar_size, ar);
      break;
    }
    if ((i == 0) && (ar[i] > temp)) {
      ar[i] = temp;
      print_arr(ar_size, ar);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checkfordiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  mov    %eax,%edx
  sub    %esi,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L22
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L11
  mov    $0x4,%eax
  jmp    L27
L11:
  mov    $0x0,%eax
  jmp    L27
L22:
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int checkfordiv(int num) {
  if (num % 6 == 0)
    if (num % 4 == 0)
      return 4;
    else
      return 0;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<checkfordiv>:
  endbr64
  movslq %edi,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  add    %eax,%eax
  mov    $0x0,%edx
  cmp    %eax,%edi
  jne    L1
  test   $0x3,%dil
  sete   %dl
  movzbl %dl,%edx
  shl    $0x2,%edx
L1:
  mov    %edx,%eax
  ret
```

assistant: ```c
int checkfordiv(int num) {
  if (num % 6 == 0)
    if (num % 4 == 0)
      return 4;
    else
      return 0;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkfordiv>:
  endbr64
  imul   $0xaaaaaaab,%edi,%eax
  xor    %r8d,%r8d
  add    $0x2aaaaaaa,%eax
  ror    %eax
  cmp    $0x2aaaaaaa,%eax
  ja     L6
  xor    %r8d,%r8d
  and    $0x3,%edi
  sete   %r8b
  shl    $0x2,%r8d
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int checkfordiv(int num) {
  if (num % 6 == 0)
    if (num % 4 == 0)
      return 4;
    else
      return 0;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<checkfordiv>:
  endbr64
  imul   $0xaaaaaaab,%edi,%eax
  xor    %r8d,%r8d
  add    $0x2aaaaaaa,%eax
  ror    %eax
  cmp    $0x2aaaaaaa,%eax
  ja     L9
  xor    %r8d,%r8d
  and    $0x3,%edi
  sete   %r8b
  shl    $0x2,%r8d
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int checkfordiv(int num) {
  if (num % 6 == 0)
    if (num % 4 == 0)
      return 4;
    else
      return 0;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bam_reg2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  subl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0xe,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0xe,%eax
  cmp    %eax,%edx
  jne    L54
  mov    -0x4(%rbp),%eax
  sar    $0xe,%eax
  add    $0x1249,%eax
  jmp    L23
L54:
  mov    -0x4(%rbp),%eax
  sar    $0x11,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x11,%eax
  cmp    %eax,%edx
  jne    L26
  mov    -0x4(%rbp),%eax
  sar    $0x11,%eax
  add    $0x249,%eax
  jmp    L23
L26:
  mov    -0x4(%rbp),%eax
  sar    $0x14,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x14,%eax
  cmp    %eax,%edx
  jne    L16
  mov    -0x4(%rbp),%eax
  sar    $0x14,%eax
  add    $0x49,%eax
  jmp    L23
L16:
  mov    -0x4(%rbp),%eax
  sar    $0x17,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x17,%eax
  cmp    %eax,%edx
  jne    L68
  mov    -0x4(%rbp),%eax
  sar    $0x17,%eax
  add    $0x9,%eax
  jmp    L23
L68:
  mov    -0x4(%rbp),%eax
  sar    $0x1a,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x1a,%eax
  cmp    %eax,%edx
  jne    L69
  mov    -0x4(%rbp),%eax
  sar    $0x1a,%eax
  add    $0x1,%eax
  jmp    L23
L69:
  mov    $0x0,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int bam_reg2bin(uint32_t beg, uint32_t end) {
  --end;
  if (beg >> 14 == end >> 14) {
    return 4681 + (beg >> 14);
  }
  if (beg >> 17 == end >> 17) {
    return 585 + (beg >> 17);
  }
  if (beg >> 20 == end >> 20) {
    return 73 + (beg >> 20);
  }
  if (beg >> 23 == end >> 23) {
    return 9 + (beg >> 23);
  }
  if (beg >> 26 == end >> 26) {
    return 1 + (beg >> 26);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bam_reg2bin>:
  endbr64
  sub    $0x1,%esi
  mov    %edi,%eax
  sar    $0xe,%eax
  mov    %esi,%edx
  sar    $0xe,%edx
  cmp    %edx,%eax
  je     L32
  mov    %edi,%eax
  sar    $0x11,%eax
  mov    %esi,%edx
  sar    $0x11,%edx
  cmp    %edx,%eax
  je     L27
  mov    %edi,%eax
  sar    $0x14,%eax
  mov    %esi,%edx
  sar    $0x14,%edx
  cmp    %edx,%eax
  je     L7
  mov    %edi,%eax
  sar    $0x17,%eax
  mov    %esi,%edx
  sar    $0x17,%edx
  cmp    %edx,%eax
  je     L26
  sar    $0x1a,%edi
  sar    $0x1a,%esi
  lea    0x1(%rdi),%eax
  cmp    %esi,%edi
  mov    $0x0,%edx
  cmovne %edx,%eax
  ret
L32:
  add    $0x1249,%eax
  ret
L27:
  add    $0x249,%eax
  ret
L7:
  add    $0x49,%eax
  ret
L26:
  add    $0x9,%eax
  ret
```

assistant: ```c
int bam_reg2bin(uint32_t beg, uint32_t end) {
  --end;
  if (beg >> 14 == end >> 14) {
    return 4681 + (beg >> 14);
  }
  if (beg >> 17 == end >> 17) {
    return 585 + (beg >> 17);
  }
  if (beg >> 20 == end >> 20) {
    return 73 + (beg >> 20);
  }
  if (beg >> 23 == end >> 23) {
    return 9 + (beg >> 23);
  }
  if (beg >> 26 == end >> 26) {
    return 1 + (beg >> 26);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bam_reg2bin>:
  endbr64
  sub    $0x1,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  sar    $0xe,%eax
  sar    $0xe,%edx
  cmp    %edx,%eax
  je     L26
  mov    %edi,%eax
  mov    %esi,%edx
  sar    $0x11,%eax
  sar    $0x11,%edx
  cmp    %edx,%eax
  je     L12
  mov    %edi,%eax
  mov    %esi,%edx
  sar    $0x14,%eax
  sar    $0x14,%edx
  cmp    %edx,%eax
  je     L39
  mov    %edi,%eax
  mov    %esi,%edx
  sar    $0x17,%eax
  sar    $0x17,%edx
  cmp    %edx,%eax
  je     L10
  sar    $0x1a,%edi
  sar    $0x1a,%esi
  xor    %edx,%edx
  lea    0x1(%rdi),%eax
  cmp    %esi,%edi
  cmovne %edx,%eax
  ret
L26:
  add    $0x1249,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L39:
  add    $0x49,%eax
  ret
  nopl   0x0(%rax)
L12:
  add    $0x249,%eax
  ret
  xchg   %ax,%ax
L10:
  add    $0x9,%eax
  ret
```

assistant: ```c
int bam_reg2bin(uint32_t beg, uint32_t end) {
  --end;
  if (beg >> 14 == end >> 14) {
    return 4681 + (beg >> 14);
  }
  if (beg >> 17 == end >> 17) {
    return 585 + (beg >> 17);
  }
  if (beg >> 20 == end >> 20) {
    return 73 + (beg >> 20);
  }
  if (beg >> 23 == end >> 23) {
    return 9 + (beg >> 23);
  }
  if (beg >> 26 == end >> 26) {
    return 1 + (beg >> 26);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bam_reg2bin>:
  endbr64
  sub    $0x1,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  sar    $0xe,%eax
  sar    $0xe,%edx
  cmp    %edx,%eax
  je     L35
  mov    %edi,%eax
  mov    %esi,%edx
  sar    $0x11,%eax
  sar    $0x11,%edx
  cmp    %edx,%eax
  je     L31
  mov    %edi,%eax
  mov    %esi,%edx
  sar    $0x14,%eax
  sar    $0x14,%edx
  cmp    %edx,%eax
  je     L18
  mov    %edi,%eax
  mov    %esi,%edx
  sar    $0x17,%eax
  sar    $0x17,%edx
  cmp    %edx,%eax
  je     L14
  sar    $0x1a,%edi
  sar    $0x1a,%esi
  xor    %edx,%edx
  lea    0x1(%rdi),%eax
  cmp    %esi,%edi
  cmovne %edx,%eax
  ret
L35:
  add    $0x1249,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x49,%eax
  ret
  nopl   0x0(%rax)
L31:
  add    $0x249,%eax
  ret
  xchg   %ax,%ax
L14:
  add    $0x9,%eax
  ret
```

assistant: ```c
int bam_reg2bin(uint32_t beg, uint32_t end) {
  --end;
  if (beg >> 14 == end >> 14) {
    return 4681 + (beg >> 14);
  }
  if (beg >> 17 == end >> 17) {
    return 585 + (beg >> 17);
  }
  if (beg >> 20 == end >> 20) {
    return 73 + (beg >> 20);
  }
  if (beg >> 23 == end >> 23) {
    return 9 + (beg >> 23);
  }
  if (beg >> 26 == end >> 26) {
    return 1 + (beg >> 26);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<file_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L11
L5:
  mov    $0x0,%eax
L11:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type: string

tool: D7: r

assistant: ```c
int file_exists(const char *filename) {
  FILE *file = fopen(filename, "r");
  if (file != 0) {
    fclose(file);
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_exists>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  jne    L14
L0:
  add    $0x8,%rsp
  ret
L14:
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L0
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0: r

assistant: ```c
int file_exists(const char *filename) {
  FILE *file = fopen(filename, "r");
  if (file != 0) {
    fclose(file);
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<file_exists>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  call   <fclose@plt>
  mov    $0x1,%eax
L6:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: r

assistant: ```c
int file_exists(const char *filename) {
  FILE *file = fopen(filename, "r");
  if (file != 0) {
    fclose(file);
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_exists>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L7
  call   <fclose@plt>
  mov    $0x1,%eax
L7:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: r

assistant: ```c
int file_exists(const char *filename) {
  FILE *file = fopen(filename, "r");
  if (file != 0) {
    fclose(file);
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<movptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x9,-0x8(%rbp)
  ja     L94
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D62(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D62(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D48(%rip),%rax
  jmp    L92
  lea    D96(%rip),%rax
  jmp    L92
  lea    D63(%rip),%rax
  jmp    L92
  lea    D78(%rip),%rax
  jmp    L92
  cmpl   $0x1,-0x4(%rbp)
  jne    L75
  lea    D29(%rip),%rax
  jmp    L92
L75:
  lea    D106(%rip),%rax
  jmp    L92
  cmpl   $0x1,-0x4(%rbp)
  jne    L23
  lea    D44(%rip),%rax
  jmp    L92
L23:
  lea    D64(%rip),%rax
  jmp    L92
L94:
  lea    D105(%rip),%rax
L92:
  pop    %rbp
  ret
```

assistant: ```c
int *movptr(int attack, int pc) {
  static int knightd[9] = {-31, -33, -14, -18, 14, 18, 33, 31, 0};
  static int bishopd[5] = {-15, -17, 15, 17, 0};
  static int rookd[5] = {-16, -1, 16, 1, 0};
  static int queend[9] = {-15, -17, 15, 17, -16, -1, 16, 1, 0};
  static int kingd[9] = {-15, -17, 15, 17, -16, -1, 16, 1, 0};
  static int wpattd[3] = {-15, -17, 0};
  static int bpattd[3] = {15, 17, 0};
  static int wpmovd[4] = {-15, -16, -17, 0};
  static int bpmovd[4] = {15, 16, 17, 0};
  switch (pc) {
  case 2:
  case 3:
    return knightd;
  case 4:
  case 5:
    return bishopd;
  case 6:
  case 7:
    return rookd;
  case 8:
  case 9:
    return queend;
  case 0:
    switch (attack) {
    case 1:
      return wpattd;
    default:
      return wpmovd;
    }
  case 1:
    switch (attack) {
    case 1:
      return bpattd;
    default:
      return bpmovd;
    }
  default:
    return kingd;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<movptr>:
  endbr64
  cmp    $0x9,%esi
  ja     L2
  mov    %esi,%esi
  lea    D28(%rip),%rdx
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D41(%rip),%rax
  ret
  lea    D81(%rip),%rax
  ret
  lea    D11(%rip),%rax
  ret
  cmp    $0x1,%edi
  lea    D97(%rip),%rax
  lea    D56(%rip),%rdx
  cmovne %rdx,%rax
  ret
  cmp    $0x1,%edi
  lea    D24(%rip),%rax
  lea    D82(%rip),%rdx
  cmovne %rdx,%rax
  ret
L2:
  lea    D86(%rip),%rax
  ret
  lea    D43(%rip),%rax
  ret
```

assistant: ```c
int *movptr(int attack, int pc) {
  static int knightd[9] = {-31, -33, -14, -18, 14, 18, 33, 31, 0};
  static int bishopd[5] = {-15, -17, 15, 17, 0};
  static int rookd[5] = {-16, -1, 16, 1, 0};
  static int queend[9] = {-15, -17, 15, 17, -16, -1, 16, 1, 0};
  static int kingd[9] = {-15, -17, 15, 17, -16, -1, 16, 1, 0};
  static int wpattd[3] = {-15, -17, 0};
  static int bpattd[3] = {15, 17, 0};
  static int wpmovd[4] = {-15, -16, -17, 0};
  static int bpmovd[4] = {15, 16, 17, 0};
  switch (pc) {
  case 2:
  case 3:
    return knightd;
  case 4:
  case 5:
    return bishopd;
  case 6:
  case 7:
    return rookd;
  case 8:
  case 9:
    return queend;
  case 0:
    switch (attack) {
    case 1:
      return wpattd;
    default:
      return wpmovd;
    }
  case 1:
    switch (attack) {
    case 1:
      return bpattd;
    default:
      return bpmovd;
    }
  default:
    return kingd;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<movptr>:
  endbr64
  cmp    $0x9,%esi
  ja     L5
  lea    D56(%rip),%rdx
  mov    %esi,%esi
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D68(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D18(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D48(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D52(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  cmp    $0x1,%edi
  lea    D33(%rip),%rdx
  lea    D53(%rip),%rax
  cmovne %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
  cmp    $0x1,%edi
  lea    D46(%rip),%rdx
  lea    D35(%rip),%rax
  cmovne %rdx,%rax
  ret
L5:
  lea    D59(%rip),%rax
  ret
```

assistant: ```c
int *movptr(int attack, int pc) {
  static int knightd[9] = {-31, -33, -14, -18, 14, 18, 33, 31, 0};
  static int bishopd[5] = {-15, -17, 15, 17, 0};
  static int rookd[5] = {-16, -1, 16, 1, 0};
  static int queend[9] = {-15, -17, 15, 17, -16, -1, 16, 1, 0};
  static int kingd[9] = {-15, -17, 15, 17, -16, -1, 16, 1, 0};
  static int wpattd[3] = {-15, -17, 0};
  static int bpattd[3] = {15, 17, 0};
  static int wpmovd[4] = {-15, -16, -17, 0};
  static int bpmovd[4] = {15, 16, 17, 0};
  switch (pc) {
  case 2:
  case 3:
    return knightd;
  case 4:
  case 5:
    return bishopd;
  case 6:
  case 7:
    return rookd;
  case 8:
  case 9:
    return queend;
  case 0:
    switch (attack) {
    case 1:
      return wpattd;
    default:
      return wpmovd;
    }
  case 1:
    switch (attack) {
    case 1:
      return bpattd;
    default:
      return bpmovd;
    }
  default:
    return kingd;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<movptr>:
  endbr64
  cmp    $0x9,%esi
  ja     L2
  lea    D91(%rip),%rdx
  mov    %esi,%esi
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D94(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D35(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D77(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D97(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  cmp    $0x1,%edi
  lea    D73(%rip),%rdx
  lea    D21(%rip),%rax
  cmovne %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
  cmp    $0x1,%edi
  lea    D64(%rip),%rdx
  lea    D4(%rip),%rax
  cmovne %rdx,%rax
  ret
L2:
  lea    D75(%rip),%rax
  ret
```

assistant: ```c
int *movptr(int attack, int pc) {
  static int knightd[9] = {-31, -33, -14, -18, 14, 18, 33, 31, 0};
  static int bishopd[5] = {-15, -17, 15, 17, 0};
  static int rookd[5] = {-16, -1, 16, 1, 0};
  static int queend[9] = {-15, -17, 15, 17, -16, -1, 16, 1, 0};
  static int kingd[9] = {-15, -17, 15, 17, -16, -1, 16, 1, 0};
  static int wpattd[3] = {-15, -17, 0};
  static int bpattd[3] = {15, 17, 0};
  static int wpmovd[4] = {-15, -16, -17, 0};
  static int bpmovd[4] = {15, 16, 17, 0};
  switch (pc) {
  case 2:
  case 3:
    return knightd;
  case 4:
  case 5:
    return bishopd;
  case 6:
  case 7:
    return rookd;
  case 8:
  case 9:
    return queend;
  case 0:
    switch (attack) {
    case 1:
      return wpattd;
    default:
      return wpmovd;
    }
  case 1:
    switch (attack) {
    case 1:
      return bpattd;
    default:
      return bpmovd;
    }
  default:
    return kingd;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<istrrand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L7:
  mov    $0x0,%eax
  call   <nondet_int@plt>
  cmp    $0x1,%eax
  jne    L20
  mov    -0x4(%rbp),%eax
  jmp    L24
L20:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0xffffffff,%eax
L24:
  leave
  ret
```

assistant: ```c
int istrrand(char *s) {
  int i;
  for (i = 0; s[i] != 0; i++)
    if (nondet_int() == 1)
      return i;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<istrrand>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L16
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L29:
  mov    %ebx,%r12d
  mov    $0x0,%eax
  call   <nondet_int@plt>
  cmp    $0x1,%eax
  je     L32
  add    $0x1,%rbx
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  jne    L29
  mov    $0xffffffff,%r12d
L32:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    $0xffffffff,%r12d
  jmp    L32
```

assistant: ```c
int istrrand(char *s) {
  int i;
  for (i = 0; s[i] != 0; i++)
    if (nondet_int() == 1)
      return i;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<istrrand>:
  endbr64
  cmpb   $0x0,(%rdi)
  push   %r12
  push   %rbp
  push   %rbx
  je     L7
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L36
  nopl   0x0(%rax)
L2:
  add    $0x1,%rbx
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  je     L7
L36:
  xor    %eax,%eax
  mov    %ebx,%r12d
  call   <nondet_int@plt>
  cmp    $0x1,%eax
  jne    L2
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int istrrand(char *s) {
  int i;
  for (i = 0; s[i] != 0; i++)
    if (nondet_int() == 1)
      return i;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<istrrand>:
  endbr64
  cmpb   $0x0,(%rdi)
  push   %r12
  push   %rbp
  push   %rbx
  je     L13
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L11
  nopl   0x0(%rax)
L27:
  add    $0x1,%rbx
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  je     L13
L11:
  xor    %eax,%eax
  mov    %ebx,%r12d
  call   <nondet_int@plt>
  cmp    $0x1,%eax
  jne    L27
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int istrrand(char *s) {
  int i;
  for (i = 0; s[i] != 0; i++)
    if (nondet_int() == 1)
      return i;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stopPatternSearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,%eax
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,%edx
  mov    %al,-0xc(%rbp)
  mov    %edx,%eax
  mov    %al,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L29
  mov    $0x1,%eax
  jmp    L44
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L34
  mov    $0x1,%eax
  jmp    L44
L34:
  movzbl -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%al
  jae    L26
  mov    $0x1,%eax
  jmp    L44
L26:
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
int stopPatternSearch(int xpat, int npat, unsigned char fpat, int x, int n, unsigned char f) {
  if (xpat < x)
    return 1;
  if (npat < n)
    return 1;
  if (fpat < f)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stopPatternSearch>:
  endbr64
  cmp    %r8d,%esi
  setl   %al
  cmp    %r9b,%dl
  setb   %dl
  or     %edx,%eax
  cmp    %ecx,%edi
  setl   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int stopPatternSearch(int xpat, int npat, unsigned char fpat, int x, int n, unsigned char f) {
  if (xpat < x)
    return 1;
  if (npat < n)
    return 1;
  if (fpat < f)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stopPatternSearch>:
  endbr64
  cmp    %r8d,%esi
  setl   %al
  cmp    %r9b,%dl
  setb   %dl
  or     %edx,%eax
  cmp    %ecx,%edi
  setl   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int stopPatternSearch(int xpat, int npat, unsigned char fpat, int x, int n, unsigned char f) {
  if (xpat < x)
    return 1;
  if (npat < n)
    return 1;
  if (fpat < f)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stopPatternSearch>:
  endbr64
  cmp    %r8d,%esi
  setl   %al
  cmp    %r9b,%dl
  setb   %dl
  or     %edx,%eax
  cmp    %ecx,%edi
  setl   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int stopPatternSearch(int xpat, int npat, unsigned char fpat, int x, int n, unsigned char f) {
  if (xpat < x)
    return 1;
  if (npat < n)
    return 1;
  if (fpat < f)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<picolCommand9Chain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x24(%rbp),%eax
  sub    $0x2,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <JoinWithSpaces@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <AddCR@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <Os9Chain@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <Error@plt>
  leave
  ret
```

assistant: ```c
int picolCommand9Chain(int argc, char **argv, void *pd) {
  char *program = argv[1];
  const char *params = JoinWithSpaces(argc - 2, argv + 2);
  params = AddCR((char *)params);
  int e = Os9Chain(program, params, strlen(params), 0, 0);
  return Error(argv[1], e);
}
```