ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<s_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L19
L17:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
L19:
  leave
  ret
```

assistant: ```c
char *s_dup(const char *s) {
  if (!s)
    return NULL;
  return strdup(s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<s_dup>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  call   <strdup@plt>
  add    $0x8,%rsp
  ret
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *s_dup(const char *s) {
  if (!s)
    return NULL;
  return strdup(s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s_dup>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <strdup@plt>
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *s_dup(const char *s) {
  if (!s)
    return NULL;
  return strdup(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<s_dup>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <strdup@plt>
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *s_dup(const char *s) {
  if (!s)
    return NULL;
  return strdup(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_201_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x20(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_201_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | *D;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_201_1_0>:
  endbr64
  or     %esi,%edx
  or     (%rdi),%dl
  not    %edx
  and    (%rdi),%sil
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_201_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | *D;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rop3_201_1_0>:
  endbr64
  or     %esi,%edx
  or     (%rdi),%dl
  and    (%rdi),%sil
  not    %edx
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_201_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | *D;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rop3_201_1_0>:
  endbr64
  or     %esi,%edx
  or     (%rdi),%dl
  and    (%rdi),%sil
  not    %edx
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_201_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | *D;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L0
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fib(int param1) {
  int i0;
  int o0;
  int o0_1;
  i0 = param1;
  if (param1 > 1) {
    o0_1 = fib(param1 - 1);
    o0 = fib(param1 - 2);
    i0 = o0_1 + o0;
  }
  return i0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L11
L3:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  lea    0x0(%rbp,%rax,1),%ebx
  jmp    L3
```

assistant: ```c
int fib(int param1) {
  int i0;
  int o0;
  int o0_1;
  i0 = param1;
  if (param1 > 1) {
    o0_1 = fib(param1 - 1);
    o0 = fib(param1 - 2);
    i0 = o0_1 + o0;
  }
  return i0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SmFreeReasons>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L28
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L26
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L28:
  nop
  leave
  ret
```

assistant: ```c
void SmFreeReasons(int count, char **reasonMsgs) {
  if (reasonMsgs) {
    int i;
    for (i = 0; i < count; i++)
      free(reasonMsgs[i]);
    free((char *)reasonMsgs);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SmFreeReasons>:
  endbr64
  test   %rsi,%rsi
  je     L28
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  test   %edi,%edi
  jle    L20
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
L3:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L3
L20:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  ret
```

assistant: ```c
void SmFreeReasons(int count, char **reasonMsgs) {
  if (reasonMsgs) {
    int i;
    for (i = 0; i < count; i++)
      free(reasonMsgs[i]);
    free((char *)reasonMsgs);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<SmFreeReasons>:
  endbr64
  test   %rsi,%rsi
  je     L0
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L25
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x8(%rsi,%rax,8),%rbp
  nop
L14:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L14
L25:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
  nopl   (%rax)
L0:
  ret
```

assistant: ```c
void SmFreeReasons(int count, char **reasonMsgs) {
  if (reasonMsgs) {
    int i;
    for (i = 0; i < count; i++)
      free(reasonMsgs[i]);
    free((char *)reasonMsgs);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<SmFreeReasons>:
  endbr64
  test   %rsi,%rsi
  je     L13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L25
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x8(%rsi,%rax,8),%rbp
  nop
L29:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L29
L25:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
  nopl   (%rax)
L13:
  ret
```

assistant: ```c
void SmFreeReasons(int count, char **reasonMsgs) {
  if (reasonMsgs) {
    int i;
    for (i = 0; i < count; i++)
      free(reasonMsgs[i]);
    free((char *)reasonMsgs);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fd_cleanup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L24
L12:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  cmp    %edx,%eax
  je     L29
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <close@plt>
L29:
  addq   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void fd_cleanup(int *fd_arr, size_t n) {
  for (size_t i = 0; i < n; i++) {
    if (fd_arr[i] != (int)i) {
      close(fd_arr[i]);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fd_cleanup>:
  endbr64
  test   %rsi,%rsi
  je     L36
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  jmp    L8
L47:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L19
L8:
  mov    (%r12,%rbx,4),%edi
  cmp    %ebx,%edi
  je     L47
  call   <close@plt>
  jmp    L47
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  ret
```

assistant: ```c
void fd_cleanup(int *fd_arr, size_t n) {
  for (size_t i = 0; i < n; i++) {
    if (fd_arr[i] != (int)i) {
      close(fd_arr[i]);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fd_cleanup>:
  endbr64
  test   %rsi,%rsi
  je     L23
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L10:
  mov    (%r12,%rbx,4),%edi
  cmp    %ebx,%edi
  je     L0
  call   <close@plt>
L0:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  ret
```

assistant: ```c
void fd_cleanup(int *fd_arr, size_t n) {
  for (size_t i = 0; i < n; i++) {
    if (fd_arr[i] != (int)i) {
      close(fd_arr[i]);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fd_cleanup>:
  endbr64
  test   %rsi,%rsi
  je     L15
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L13:
  mov    (%r12,%rbx,4),%edi
  cmp    %ebx,%edi
  je     L28
  call   <close@plt>
L28:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void fd_cleanup(int *fd_arr, size_t n) {
  for (size_t i = 0; i < n; i++) {
    if (fd_arr[i] != (int)i) {
      close(fd_arr[i]);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fillGrid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  movw   $0x0,-0x4(%rbp)
  jmp    L22
L7:
  movw   $0x0,-0x2(%rbp)
  jmp    L32
L5:
  movswq -0x4(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movswq -0x2(%rbp),%rax
  add    %rax,%rax
  add    %rax,%rdx
  movzwl -0x1c(%rbp),%eax
  mov    %ax,(%rdx)
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L32:
  cmpw   $0x1c,-0x2(%rbp)
  jle    L5
  movzwl -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4(%rbp)
L22:
  cmpw   $0x4e,-0x4(%rbp)
  jle    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fillGrid(short **grid, short fillValue) {
  short i, j;
  for (i = 0; i < (100 - 20 - 1); i++) {
    for (j = 0; j < ((31 + 5) - 5 - 2); j++) {
      grid[i][j] = fillValue;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fillGrid>:
  endbr64
  mov    %rdi,%rcx
  add    $0x278,%rdi
  jmp    L13
L6:
  add    $0x8,%rcx
  cmp    %rdi,%rcx
  je     L12
L13:
  mov    $0x0,%eax
L2:
  mov    (%rcx),%rdx
  mov    %si,(%rdx,%rax,1)
  add    $0x2,%rax
  cmp    $0x3a,%rax
  jne    L2
  jmp    L6
L12:
  ret
```

assistant: ```c
void fillGrid(short **grid, short fillValue) {
  short i, j;
  for (i = 0; i < (100 - 20 - 1); i++) {
    for (j = 0; j < ((31 + 5) - 5 - 2); j++) {
      grid[i][j] = fillValue;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fillGrid>:
  endbr64
  mov    %esi,%ecx
  mov    %rdi,%rsi
  lea    0x278(%rdi),%rdi
L13:
  mov    (%rsi),%rax
  lea    0x3a(%rax),%rdx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %cx,(%rax)
  add    $0x2,%rax
  cmp    %rdx,%rax
  jne    L4
  add    $0x8,%rsi
  cmp    %rdi,%rsi
  jne    L13
  ret
```

assistant: ```c
void fillGrid(short **grid, short fillValue) {
  short i, j;
  for (i = 0; i < (100 - 20 - 1); i++) {
    for (j = 0; j < ((31 + 5) - 5 - 2); j++) {
      grid[i][j] = fillValue;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fillGrid>:
  endbr64
  mov    %esi,%ecx
  mov    %rdi,%rdx
  lea    0x278(%rdi),%rsi
  movd   %ecx,%xmm0
  movd   %ecx,%xmm2
  punpcklwd %xmm0,%xmm0
  pshuflw $0x0,%xmm2,%xmm1
  pshufd $0x0,%xmm0,%xmm0
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  mov    %cx,0x38(%rax)
  movups %xmm0,(%rax)
  movups %xmm0,0x10(%rax)
  movups %xmm0,0x20(%rax)
  movq   %xmm1,0x30(%rax)
  cmp    %rsi,%rdx
  jne    L6
  ret
```

assistant: ```c
void fillGrid(short **grid, short fillValue) {
  short i, j;
  for (i = 0; i < (100 - 20 - 1); i++) {
    for (j = 0; j < ((31 + 5) - 5 - 2); j++) {
      grid[i][j] = fillValue;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decrypt_speck_128x128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L8:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  xor    %edx,%eax
  sar    $0x3,%eax
  mov    %eax,%esi
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  xor    %edx,%eax
  mov    $0x3d,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  or     %esi,%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    $0x1f,%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  shl    $0x8,%eax
  mov    %eax,%esi
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    $0x1f,%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x38,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L8
  nop
  pop    %rbp
  ret
```

assistant: ```c
void decrypt_speck_128x128(uint64_t *cipher_text, uint64_t *plain_text, uint64_t *key) {
  int i;
  plain_text[0] = cipher_text[0];
  plain_text[1] = cipher_text[1];
  for (i = 0; i < 32; i++) {
    plain_text[1] = ((((plain_text[0] ^ plain_text[1])) >> (3)) | (((plain_text[0] ^ plain_text[1])) << (64 - (3))));
    plain_text[0] = ((((plain_text[0] ^ key[31 - i]) - plain_text[1]) << (8)) | (((plain_text[0] ^ key[31 - i]) - plain_text[1]) >> (64 - (8))));
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decrypt_speck_128x128>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  mov    0x4(%rdi),%eax
  mov    %eax,0x4(%rsi)
  lea    0x7c(%rdx),%rdi
L1:
  mov    (%rsi),%eax
  mov    %eax,%ecx
  xor    0x4(%rsi),%ecx
  sar    $0x3,%ecx
  mov    %ecx,0x4(%rsi)
  xor    (%rdi),%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x8,%ecx
  mov    %ecx,%r8d
  mov    $0x38,%ecx
  sar    %cl,%eax
  or     %r8d,%eax
  mov    %eax,(%rsi)
  mov    %rdi,%rax
  sub    $0x4,%rdi
  cmp    %rdx,%rax
  jne    L1
  ret
```

assistant: ```c
void decrypt_speck_128x128(uint64_t *cipher_text, uint64_t *plain_text, uint64_t *key) {
  int i;
  plain_text[0] = cipher_text[0];
  plain_text[1] = cipher_text[1];
  for (i = 0; i < 32; i++) {
    plain_text[1] = ((((plain_text[0] ^ plain_text[1])) >> (3)) | (((plain_text[0] ^ plain_text[1])) << (64 - (3))));
    plain_text[0] = ((((plain_text[0] ^ key[31 - i]) - plain_text[1]) << (8)) | (((plain_text[0] ^ key[31 - i]) - plain_text[1]) >> (64 - (8))));
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decrypt_speck_128x128>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  mov    0x4(%rdi),%r9d
  lea    0x7c(%rdx),%rdi
L5:
  mov    %r9d,%ecx
  xor    %eax,%ecx
  sar    $0x3,%ecx
  mov    %ecx,0x4(%rsi)
  xor    (%rdi),%eax
  mov    %ecx,%r9d
  sub    %ecx,%eax
  mov    $0x38,%ecx
  mov    %eax,%r8d
  sar    %cl,%eax
  shl    $0x8,%r8d
  or     %r8d,%eax
  mov    %rdi,%r8
  sub    $0x4,%rdi
  mov    %eax,(%rsi)
  cmp    %rdx,%r8
  jne    L5
  ret
```

assistant: ```c
void decrypt_speck_128x128(uint64_t *cipher_text, uint64_t *plain_text, uint64_t *key) {
  int i;
  plain_text[0] = cipher_text[0];
  plain_text[1] = cipher_text[1];
  for (i = 0; i < 32; i++) {
    plain_text[1] = ((((plain_text[0] ^ plain_text[1])) >> (3)) | (((plain_text[0] ^ plain_text[1])) << (64 - (3))));
    plain_text[0] = ((((plain_text[0] ^ key[31 - i]) - plain_text[1]) << (8)) | (((plain_text[0] ^ key[31 - i]) - plain_text[1]) >> (64 - (8))));
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<decrypt_speck_128x128>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  mov    0x4(%rdi),%r9d
  lea    0x7c(%rdx),%rdi
L6:
  mov    %r9d,%ecx
  xor    %eax,%ecx
  sar    $0x3,%ecx
  mov    %ecx,0x4(%rsi)
  xor    (%rdi),%eax
  mov    %ecx,%r9d
  sub    %ecx,%eax
  mov    $0x38,%ecx
  mov    %eax,%r8d
  sar    %cl,%eax
  shl    $0x8,%r8d
  or     %r8d,%eax
  mov    %rdi,%r8
  sub    $0x4,%rdi
  mov    %eax,(%rsi)
  cmp    %rdx,%r8
  jne    L6
  ret
```

assistant: ```c
void decrypt_speck_128x128(uint64_t *cipher_text, uint64_t *plain_text, uint64_t *key) {
  int i;
  plain_text[0] = cipher_text[0];
  plain_text[1] = cipher_text[1];
  for (i = 0; i < 32; i++) {
    plain_text[1] = ((((plain_text[0] ^ plain_text[1])) >> (3)) | (((plain_text[0] ^ plain_text[1])) << (64 - (3))));
    plain_text[0] = ((((plain_text[0] ^ key[31 - i]) - plain_text[1]) << (8)) | (((plain_text[0] ^ key[31 - i]) - plain_text[1]) >> (64 - (8))));
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L3
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L3:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strcpy(char *dst, const char *src) {
  int i;
  i = -1;
  while (src[++i] != '\0')
    dst[i] = src[i];
  dst[i] = '\0';
  return (dst);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L22
  mov    $0x0,%edx
L16:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L16
L11:
  movb   $0x0,(%rax,%rdx,1)
  ret
L22:
  mov    $0x0,%edx
  jmp    L11
```

assistant: ```c
char *ft_strcpy(char *dst, const char *src) {
  int i;
  i = -1;
  while (src[++i] != '\0')
    dst[i] = src[i];
  dst[i] = '\0';
  return (dst);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L15
  xor    %edx,%edx
L14:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L14
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *ft_strcpy(char *dst, const char *src) {
  int i;
  i = -1;
  while (src[++i] != '\0')
    dst[i] = src[i];
  dst[i] = '\0';
  return (dst);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L10
  xor    %edx,%edx
L12:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L12
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *ft_strcpy(char *dst, const char *src) {
  int i;
  i = -1;
  while (src[++i] != '\0')
    dst[i] = src[i];
  dst[i] = '\0';
  return (dst);
}
```
user: What is the c source code of the assembly code below?

```asm
<dlopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *dlopen(path, mode)
char *path;
int mode;
{ return 0; }
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dlopen>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *dlopen(path, mode)
char *path;
int mode;
{ return 0; }
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dlopen>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
void *dlopen(path, mode)
char *path;
int mode;
{ return 0; }
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dlopen>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
void *dlopen(path, mode)
char *path;
int mode;
{ return 0; }
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
L5:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *_strndup(const char *str, int nlen) {
  char *str2;
  if (nlen == -1) {
    nlen = strlen(str);
  }
  str2 = (char *)malloc(nlen + 1);
  if (str2) {
    memcpy(str2, str, nlen);
    str2[nlen] = '\0';
  }
  return str2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  cmp    $0xffffffff,%esi
  je     L19
L30:
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L5
L27:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L30
L5:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  jmp    L27
```

assistant: ```c
char *_strndup(const char *str, int nlen) {
  char *str2;
  if (nlen == -1) {
    nlen = strlen(str);
  }
  str2 = (char *)malloc(nlen + 1);
  if (str2) {
    memcpy(str2, str, nlen);
    str2[nlen] = '\0';
  }
  return str2;
}
```