user: 下面的汇编指令对应的C源代码是什么:

```asm
<hybrid>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  lea    -0x4(%rsi),%rcx
  push   %r14
  sub    %rdi,%rax
  push   %r13
  sar    $0x2,%rax
  push   %r12
  add    $0x1,%eax
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  lea    -0x5(%rsi),%rcx
  mov    %rsi,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  cmp    $0x34,%eax
  jle    L37
  mov    %rdi,%r15
L5:
  sar    %eax
  mov    0x10(%rsp),%r14
  mov    %r15,%rdi
  mov    %r15,%r12
  cltq
  lea    (%r15,%rax,4),%rbp
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <sort3@plt>
  mov    0x8(%rsp),%rbx
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <stack_swap@plt>
  mov    -0x4(%r14),%ebp
  mov    %rbx,(%rsp)
  mov    %r15,%r14
  jmp    L130
  nopl   (%rax)
L53:
  mov    %r13,%r14
L130:
  lea    0x4(%r14),%r13
  cmp    %ebp,0x4(%r14)
  jl     L53
  sub    $0x4,%rbx
  cmp    %ebp,(%rbx)
  jle    L159
  nopl   (%rax)
L119:
  cmp    %r15,%rbx
  je     L159
  sub    $0x4,%rbx
  cmp    %ebp,(%rbx)
  jg     L119
L159:
  cmp    %rbx,%r13
  jae    L61
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <stack_swap@plt>
  cmp    %ebp,0x0(%r13)
  je     L24
L117:
  cmp    %ebp,(%rbx)
  jne    L53
  subq   $0x4,(%rsp)
  mov    (%rsp),%rax
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <stack_swap@plt>
  jmp    L53
  nopl   (%rax)
L24:
  add    $0x4,%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <stack_swap@plt>
  jmp    L117
  nopl   0x0(%rax)
L61:
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  lea    0x8(%r14),%rbp
  call   <stack_swap@plt>
  cmp    %r15,%r12
  jbe    L27
  mov    %r14,%r13
  mov    %r15,%rbx
  nopl   0x0(%rax)
L48:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  add    $0x4,%rbx
  sub    $0x4,%r13
  call   <stack_swap@plt>
  cmp    %rbx,%r12
  ja     L48
  mov    %r15,%rax
  sub    %r12,%rax
  and    $0xfffffffffffffffc,%rax
  add    %rax,%r14
L27:
  mov    0x8(%rsp),%rax
  cmp    %rax,(%rsp)
  jae    L148
  mov    %rax,%r12
  mov    %rbp,%rbx
  cs nopw 0x0(%rax,%rax,1)
L143:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  sub    $0x4,%r12
  call   <stack_swap@plt>
  cmp    %r12,(%rsp)
  jb     L143
  mov    0x18(%rsp),%rax
  sub    (%rsp),%rax
  shr    $0x2,%rax
  lea    0x4(%rbp,%rax,4),%rbp
L148:
  mov    0x10(%rsp),%rbx
  mov    (%rbx),%eax
  cmp    %eax,(%r15)
  je     L37
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <hybrid>
  mov    %rbx,%rax
  sub    %rbp,%rax
  sar    $0x2,%rax
  add    $0x1,%eax
  cmp    $0x34,%eax
  jle    L37
  mov    %rbp,%r15
  jmp    L5
L37:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void hybrid(int *start, int *end) {
  int *left;
  int *mid;
  int *right;
  int *inner;
  int *outer;
  int n;
  int pivot;
  n = end - start + 1;
  if (n < 53)
    return;
  mid = start + (n / 2);
  sort3(start, mid, end);
  stack_swap(mid, end - 1);
  pivot = *(end - 1);
  inner = left = start;
  outer = right = end - 1;
  while (1) {
    while (*(++left) < pivot)
      ;
    while (*(--right) > pivot)
      if (right == start)
        break;
    if (left >= right)
      break;
    stack_swap(left, right);
    if (*left == pivot)
      stack_swap(++inner, left);
    if (*right == pivot)
      stack_swap(--outer, right);
  }
  stack_swap(left, end - 1);
  right = left++ - 1;
  for (mid = start; mid < inner;)
    stack_swap(mid++, right--);
  for (mid = end - 1; mid > outer;)
    stack_swap(mid--, left++);
  if (*start == *end)
    return;
  hybrid(start, right);
  hybrid(left, end);
}
```