ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isMatched>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%r11
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L168:
  cmp    %rdx,%rsp
  je     L41
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L168
L41:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L18
  orq    $0x0,-0x8(%rsp,%rax,1)
L18:
  mov    %rsp,%r9
  test   %edi,%edi
  jle    L70
  mov    %edi,%edx
  mov    $0x0,%eax
  mov    $0x0,%r10d
  mov    $0x2e,%edi
  mov    $0x62,%r12d
  jmp    L67
L34:
  mov    %cl,(%r9,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L24
L67:
  mov    %edi,%ecx
  movzbl (%r11,%rax,1),%r14d
  cmp    %r14b,(%rsi,%rax,1)
  jne    L34
  add    $0x1,%r10d
  mov    %r12d,%ecx
  jmp    L34
L87:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L1
L122:
  cmp    %dil,(%rsi,%rax,1)
  jne    L87
  cmpb   $0x2e,(%r9,%rax,1)
  jne    L87
  add    $0x1,%r8d
  movslq %eax,%rcx
  movb   $0x77,(%r9,%rcx,1)
L1:
  add    $0x1,%r10
  cmp    %r10,%rdx
  je     L68
L72:
  cmpb   $0x62,(%r9,%r10,1)
  je     L1
  movzbl (%r11,%r10,1),%edi
  mov    $0x0,%eax
  jmp    L122
L70:
  mov    $0x0,%eax
  test   %r8d,%r8d
  jne    L105
L68:
  cmp    %r8d,%ebx
  sete   %al
  movzbl %al,%eax
L105:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L159
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r14
  pop    %rbp
  ret
L24:
  mov    $0x0,%eax
  cmp    %r8d,%r10d
  jne    L105
  mov    $0x0,%r10d
  mov    $0x0,%r8d
  jmp    L72
L159:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isMatched(int n, char *key, char *guess, int wpeg, int bpeg) {
  int bctr = 0, wctr = 0;
  int i;
  char result[n];
  int m;
  bool check = true;
  for (i = 0; i < n; i++) {
    if (key[i] == guess[i]) {
      bctr++;
      result[i] = 'b';
    } else {
      result[i] = '.';
    }
  }
  if (bctr != bpeg)
    return 0;
  for (i = 0; i < n; i++) {
    if (result[i] != 'b') {
      check = false;
    } else {
      check = true;
    }
    for (m = 0; m < n && check == false; m++) {
      if (key[m] == guess[i] && result[m] == '.') {
        wctr++;
        result[m] = 'w';
        check = true;
      }
    }
  }
  if (bctr == bpeg && wctr == wpeg)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isMatched>:
  endbr64
  push   %rbp
  mov    %rdx,%r11
  movslq %edi,%rdx
  mov    %rsp,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rsp,%r9
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r9
  and    $0xfffffffffffffff0,%rcx
  cmp    %r9,%rsp
  je     L152
L20:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r9,%rsp
  jne    L20
L152:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L32
L133:
  mov    %rsp,%r9
  test   %edi,%edi
  jle    L115
  xor    %eax,%eax
  xor    %edi,%edi
  cs nopw 0x0(%rax,%rax,1)
L43:
  movzbl (%r11,%rax,1),%r10d
  mov    $0x2e,%ecx
  cmp    %r10b,(%rsi,%rax,1)
  jne    L109
  add    $0x1,%edi
  mov    $0x62,%ecx
L109:
  mov    %cl,(%r9,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L43
  cmp    %r8d,%edi
  jne    L68
  xor    %r10d,%r10d
  xor    %r8d,%r8d
L138:
  cmpb   $0x62,(%r9,%r10,1)
  je     L127
  movzbl (%r11,%r10,1),%edi
  xor    %eax,%eax
  jmp    L123
L7:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L127
L123:
  movslq %eax,%rcx
  cmp    %dil,(%rsi,%rax,1)
  jne    L7
  cmpb   $0x2e,(%r9,%rax,1)
  jne    L7
  movb   $0x77,(%r9,%rcx,1)
  add    $0x1,%r8d
L127:
  add    $0x1,%r10
  cmp    %r10,%rdx
  jne    L138
L4:
  xor    %eax,%eax
  cmp    %r8d,%ebx
  sete   %al
L136:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L98
  mov    -0x8(%rbp),%rbx
  leave
  ret
L115:
  test   %r8d,%r8d
  je     L4
  nopl   (%rax)
L68:
  xor    %eax,%eax
  jmp    L136
L32:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L133
L98:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isMatched(int n, char *key, char *guess, int wpeg, int bpeg) {
  int bctr = 0, wctr = 0;
  int i;
  char result[n];
  int m;
  bool check = true;
  for (i = 0; i < n; i++) {
    if (key[i] == guess[i]) {
      bctr++;
      result[i] = 'b';
    } else {
      result[i] = '.';
    }
  }
  if (bctr != bpeg)
    return 0;
  for (i = 0; i < n; i++) {
    if (result[i] != 'b') {
      check = false;
    } else {
      check = true;
    }
    for (m = 0; m < n && check == false; m++) {
      if (key[m] == guess[i] && result[m] == '.') {
        wctr++;
        result[m] = 'w';
        check = true;
      }
    }
  }
  if (bctr == bpeg && wctr == wpeg)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_match_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: /

assistant: ```c
char *get_match_path(const char *dir_name, const char *key) {
  const char *seperator = "/";
  unsigned path_len = strlen(dir_name) + strlen(seperator) + strlen(key);
  char *path = (char *)malloc((path_len + 1) * sizeof(char));
  *path = '\0';
  strcat(path, dir_name);
  strcat(path, seperator);
  strcat(path, key);
  return path;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_match_path>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    D3(%rip),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movb   $0x0,(%rax)
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: /

assistant: ```c
char *get_match_path(const char *dir_name, const char *key) {
  const char *seperator = "/";
  unsigned path_len = strlen(dir_name) + strlen(seperator) + strlen(key);
  char *path = (char *)malloc((path_len + 1) * sizeof(char));
  *path = '\0';
  strcat(path, dir_name);
  strcat(path, seperator);
  strcat(path, key);
  return path;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_match_path>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  movb   $0x0,(%rax)
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: /

assistant: ```c
char *get_match_path(const char *dir_name, const char *key) {
  const char *seperator = "/";
  unsigned path_len = strlen(dir_name) + strlen(seperator) + strlen(key);
  char *path = (char *)malloc((path_len + 1) * sizeof(char));
  *path = '\0';
  strcat(path, dir_name);
  strcat(path, seperator);
  strcat(path, key);
  return path;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_match_path>:
  endbr64
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  movb   $0x0,(%rax)
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: /

assistant: ```c
char *get_match_path(const char *dir_name, const char *key) {
  const char *seperator = "/";
  unsigned path_len = strlen(dir_name) + strlen(seperator) + strlen(key);
  char *path = (char *)malloc((path_len + 1) * sizeof(char));
  *path = '\0';
  strcat(path, dir_name);
  strcat(path, seperator);
  strcat(path, key);
  return path;
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  movabs $0x8123ff5f6603c0,%rdx
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[0UL] += state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 36349851719828416UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movabs $0x8123ff5ecc0f05,%rax
  add    (%rdi),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[0UL] += state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 36349851719828416UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movabs $0x8123ff5ecc0f05,%rax
  add    (%rdi),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[0UL] += state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 36349851719828416UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movabs $0x8123ff5ecc0f05,%rax
  add    (%rdi),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[0UL] += state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 36349851719828416UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__mulhi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x14(%rbp)
  mov    %ax,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L22:
  movswl -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L3
  movswl -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
  sarw   -0x14(%rbp)
  movswl -0x18(%rbp),%eax
  add    %eax,%eax
  mov    %ax,-0x18(%rbp)
L3:
  cmpw   $0x0,-0x14(%rbp)
  jne    L22
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short __mulhi3(short a, short b) {
  int r;
  r = 0;
  while (a) {
    if (a & 1) {
      r += b;
      a >>= 1;
      b <<= 1;
    }
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__mulhi3>:
  endbr64
  mov    $0x0,%eax
L18:
  mov    %edi,%edx
  and    $0x1,%edx
L7:
  test   %di,%di
  je     L20
  test   %dx,%dx
  je     L7
  movswl %si,%esi
  add    %esi,%eax
  sar    %di
  add    %esi,%esi
  jmp    L18
L20:
  ret
```

assistant: ```c
short __mulhi3(short a, short b) {
  int r;
  r = 0;
  while (a) {
    if (a & 1) {
      r += b;
      a >>= 1;
      b <<= 1;
    }
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__mulhi3>:
  endbr64
  xor    %eax,%eax
L28:
  mov    %edi,%edx
  and    $0x1,%edx
  jmp    L24
  nopl   (%rax)
L14:
  test   %dx,%dx
  jne    L31
L24:
  test   %di,%di
  jne    L14
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  movswl %si,%esi
  sar    %di
  add    %esi,%eax
  add    %esi,%esi
  jmp    L28
```

assistant: ```c
short __mulhi3(short a, short b) {
  int r;
  r = 0;
  while (a) {
    if (a & 1) {
      r += b;
      a >>= 1;
      b <<= 1;
    }
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__mulhi3>:
  endbr64
  mov    %edi,%edx
  xor    %eax,%eax
  and    $0x1,%edx
  test   %di,%di
  je     L35
L8:
  test   %dx,%dx
  jne    L33
L14:
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L33:
  sar    %di
  movswl %si,%esi
  mov    %edi,%edx
  add    %esi,%eax
  add    %esi,%esi
  and    $0x1,%edx
  test   %di,%di
  jne    L8
L35:
  ret
```

assistant: ```c
short __mulhi3(short a, short b) {
  int r;
  r = 0;
  while (a) {
    if (a & 1) {
      r += b;
      a >>= 1;
      b <<= 1;
    }
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byte_to_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L50
L38:
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L11:
  cmpl   $0x0,-0x14(%rbp)
  jne    L58
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  and    $0x1,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L8
L58:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    $0x7,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  and    $0x1,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
L8:
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x7,-0x4(%rbp)
  jle    L11
  addl   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L38
  mov    -0x18(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int byte_to_bit(int endian, unsigned char *ibuf, int ilen, unsigned char *obuf, int *olen) {
  int i, j;
  for (i = 0; i < ilen; i++) {
    for (j = 0; j < 8; j++) {
      if (endian == 0) {
        obuf[(i * 8) + j] = (ibuf[i] >> j) & 1;
      } else {
        obuf[(i * 8) + j] = (ibuf[i] >> (7 - j)) & 1;
      }
    }
  }
  *olen = ilen * 8;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<byte_to_bit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %r8,%rbp
  test   %edx,%edx
  jle    L12
  mov    %edi,%r9d
  mov    %rcx,%r10
  mov    %rsi,%rdi
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%r8
  mov    $0x0,%esi
  mov    $0x7,%r11d
  jmp    L29
L24:
  lea    (%rax,%rsi,1),%r12d
  movslq %r12d,%r12
  movzbl (%rdi),%edx
  mov    %r11d,%ecx
  sub    %eax,%ecx
  sar    %cl,%edx
  and    $0x1,%edx
  mov    %dl,(%r10,%r12,1)
L68:
  add    $0x1,%eax
  cmp    $0x8,%eax
  je     L18
L31:
  test   %r9d,%r9d
  jne    L24
  lea    (%rax,%rsi,1),%r12d
  movslq %r12d,%r12
  movzbl (%rdi),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  and    $0x1,%edx
  mov    %dl,(%r10,%r12,1)
  jmp    L68
L18:
  add    $0x1,%rdi
  add    $0x8,%esi
  cmp    %r8,%rdi
  je     L12
L29:
  mov    $0x0,%eax
  jmp    L31
L12:
  shl    $0x3,%ebx
  mov    %ebx,0x0(%rbp)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int byte_to_bit(int endian, unsigned char *ibuf, int ilen, unsigned char *obuf, int *olen) {
  int i, j;
  for (i = 0; i < ilen; i++) {
    for (j = 0; j < 8; j++) {
      if (endian == 0) {
        obuf[(i * 8) + j] = (ibuf[i] >> j) & 1;
      } else {
        obuf[(i * 8) + j] = (ibuf[i] >> (7 - j)) & 1;
      }
    }
  }
  *olen = ilen * 8;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<byte_to_bit>:
  endbr64
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  test   %edx,%edx
  jle    L5
  lea    -0x1(%rdx),%eax
  mov    %edi,%r9d
  mov    %rcx,%rbx
  xor    %r11d,%r11d
  lea    0x1(%rsi,%rax,1),%r8
  mov    $0x7,%r10d
  nopl   0x0(%rax,%rax,1)
L27:
  movslq %r11d,%rdi
  xor    %edx,%edx
  add    %rbx,%rdi
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %edx,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x8,%rdx
  je     L16
L15:
  movzbl (%rsi),%eax
  test   %r9d,%r9d
  je     L54
  mov    %r10d,%ecx
  sub    %edx,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x8,%rdx
  jne    L15
L16:
  add    $0x1,%rsi
  add    $0x8,%r11d
  cmp    %rsi,%r8
  jne    L27
L5:
  shl    $0x3,%ebp
  pop    %rbx
  xor    %eax,%eax
  mov    %ebp,(%r12)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int byte_to_bit(int endian, unsigned char *ibuf, int ilen, unsigned char *obuf, int *olen) {
  int i, j;
  for (i = 0; i < ilen; i++) {
    for (j = 0; j < 8; j++) {
      if (endian == 0) {
        obuf[(i * 8) + j] = (ibuf[i] >> j) & 1;
      } else {
        obuf[(i * 8) + j] = (ibuf[i] >> (7 - j)) & 1;
      }
    }
  }
  *olen = ilen * 8;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<loop1_constant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x64,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L1:
  mov    $0x0,%eax
  call   <foo_constant@plt>
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L1
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int loop1_constant() {
  int k = 100;
  for (int i = 0; i < k; i++) {
    foo_constant();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<loop1_constant>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
L7:
  mov    $0x0,%eax
  call   <foo_constant@plt>
  sub    $0x1,%ebx
  jne    L7
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int loop1_constant() {
  int k = 100;
  for (int i = 0; i < k; i++) {
    foo_constant();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<loop1_constant>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <foo_constant@plt>
  sub    $0x1,%ebx
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int loop1_constant() {
  int k = 100;
  for (int i = 0; i < k; i++) {
    foo_constant();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loop1_constant>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <foo_constant@plt>
  sub    $0x1,%ebx
  jne    L7
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int loop1_constant() {
  int k = 100;
  for (int i = 0; i < k; i++) {
    foo_constant();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<malloc_more>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    -0x1c(%rbp),%edx
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <ft_memalloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L2
L7:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L2:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_free@plt>
  nop
  leave
  ret
```

assistant: ```c
void malloc_more(char **buf, int size) {
  int i;
  char *tmp;
  tmp = *buf;
  *buf = ft_memalloc(sizeof(char) * (ft_strlen(tmp) + size + 1));
  i = -1;
  while (tmp[++i] != '\0')
    (*buf)[i] = tmp[i];
  (*buf)[i] = '\0';
  ft_free(tmp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<malloc_more>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <ft_strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <ft_memalloc@plt>
  mov    %rax,(%rbx)
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L12
  mov    $0x0,%eax
L22:
  mov    (%rbx),%rcx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L22
L6:
  mov    (%rbx),%rdx
  movb   $0x0,(%rdx,%rax,1)
  mov    %rbp,%rdi
  call   <ft_free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0x0,%eax
  jmp    L6
```

assistant: ```c
void malloc_more(char **buf, int size) {
  int i;
  char *tmp;
  tmp = *buf;
  *buf = ft_memalloc(sizeof(char) * (ft_strlen(tmp) + size + 1));
  i = -1;
  while (tmp[++i] != '\0')
    (*buf)[i] = tmp[i];
  (*buf)[i] = '\0';
  ft_free(tmp);
}
```