user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x60000000,-0x40(%rbp)
  movl   $0x800,-0x3c(%rbp)
  movl   $0x7ff,-0x38(%rbp)
  movl   $0x801,-0x34(%rbp)
  movl   $0x1fff,-0x30(%rbp)
  movl   $0x40,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x8,-0x20(%rbp)
  movl   $0x11,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x80000000,-0x14(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L8
L18:
  mov    $0x0,%eax
  call   <time_clocks@plt>
  mov    %eax,-0x48(%rbp)
  mov    -0x58(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  lea    -0x60(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <errUnsignedToBase2Exponent@plt>
  mov    %eax,-0x50(%rbp)
  mov    $0x0,%eax
  call   <time_clocks@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  sub    -0x48(%rbp),%eax
  mov    %eax,%esi
  mov    -0x60(%rbp),%ecx
  mov    -0x58(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x50(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x58(%rbp)
L8:
  mov    -0x58(%rbp),%eax
  cmp    $0xb,%eax
  jbe    L18
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x800,-0x54(%rbp)
  lea    -0x5c(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <errUnsignedToBase2Exponent@plt>
  mov    %eax,-0x50(%rbp)
  mov    -0x5c(%rbp),%eax
  mov    %eax,%edx
  mov    $0xaaaaaaab,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    %eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x5c(%rbp),%ecx
  mov    -0x4c(%rbp),%esi
  mov    -0x54(%rbp),%edx
  mov    -0x50(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4c(%rbp),%eax
  movzwl %ax,%ecx
  mov    -0x4c(%rbp),%eax
  shr    $0x10,%eax
  movzbl %al,%edx
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D25
type_guessed: string
name: parse_data
arguments: tag: D48
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D47
type_guessed: string
name: parse_data
arguments: tag: D54
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string

tool: D25: Error=%02d	number=0x%08X	Base2Exponent=0x%08X		clocks:%d


tool: D48: 

------------------------- cube root demo ---------------------

tool: D19: Error=%02d	number=0x%08X	Base2Exponent=0x%08X	0x%08X


tool: D47: exact: 2048 ^ (1/3) = 12.699208

tool: D54: result: %X integer part = %X  fractional part = %X


tool: D2: means: 2 ^ ( 3 + 1/2 + 1/8 + 1/32 + 1/128 .... + 1/32768) = 12.699118

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned num[] = {0x60000000, 2048, 2047, 2049, 0x1FFF, 0x40, 2, 4, 8, 17, 0, 0x80000000};
  unsigned n, n1, n2, exp, exp1, exp2;
  int err, i;
  int start, end;
  for (i = 0; i < sizeof(num) / sizeof(unsigned); i++) {
    start = time_clocks();
    err = errUnsignedToBase2Exponent(num[i], &exp);
    end = time_clocks();
    printf("Error=%02d\tnumber=0x%08X\tBase2Exponent=0x%08X\t\tclocks:%d\n", err, num[i], exp, end - start);
  }
  printf("\n\n------------------------- cube root demo ---------------------\n");
  n1 = 2048;
  err = errUnsignedToBase2Exponent(n1, &exp1);
  exp2 = exp1 / 3;
  printf("Error=%02d\tnumber=0x%08X\tBase2Exponent=0x%08X\t0x%08X\n", err, n1, exp1, exp2);
  printf("exact: 2048 ^ (1/3) = 12.699208\n");
  printf("result: %X integer part = %X  fractional part = %X\n", exp2, (exp2 & 0xFF0000) >> 16, exp2 & 0xFFFF);
  printf("means: 2 ^ ( 3 + 1/2 + 1/8 + 1/32 + 1/128 .... + 1/32768) = 12.699118\n");
  return 0;
}
```