user: What would the C source look like for the assembly code provided here:

```asm
<ksplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x200,%edi
  call   <kralloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x200,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L166
L154:
  addq   $0x1,-0x28(%rbp)
L192:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L38
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L154
L38:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L125
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  je     L139
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  je     L5
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L158
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L27
L158:
  mov    $0x100,%edi
  call   <kralloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L184
  addq   $0x1,-0x28(%rbp)
  jmp    L193
L182:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L193:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L182
L53:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L120
  addq   $0x1,-0x28(%rbp)
L120:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  jmp    L166
L44:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L184:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L128
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L44
L128:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L166:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L192
  jmp    L74
L125:
  nop
  jmp    L74
L139:
  nop
  jmp    L74
L5:
  nop
  jmp    L74
L27:
  nop
L74:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **ksplit(char *s) {
  char **a, *t;
  int i;
  a = kralloc(64 * sizeof(char *));
  memset(a, 0, 64 * sizeof(char *));
  i = 0;
  while (*s) {
    while (*s && (*s <= ' '))
      s++;
    if (!*s)
      break;
    if (*s == '#')
      break;
    if (*s == ';')
      break;
    if ((s[0] == '/') && (s[1] == '/'))
      break;
    t = kralloc(256);
    a[i++] = t;
    if (*s == '"') {
      s++;
      while (*s && (*s != '"'))
        *t++ = *s++;
      if (*s == '"')
        s++;
      *t++ = 0;
      continue;
    }
    while (*s && (*s > ' '))
      *t++ = *s++;
    *t++ = 0;
  }
  a[i] = NULL;
  return (a);
}
```