user: 请从给定的汇编指令推导出C源代码：

```asm
<MMX_SUB_8b_AUTOTEST>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  shl    $0x10,%ebx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x10,%ecx
  lea    (%rax,%rcx,1),%edx
  movzwl %dx,%edx
  sub    %ecx,%edx
  and    %edx,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <rand@plt>
  shl    $0x10,%r12d
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x10,%ecx
  lea    (%rax,%rcx,1),%edx
  movzwl %dx,%edx
  sub    %ecx,%edx
  and    %edx,%r12d
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <instr_v8sub@plt>
  mov    %eax,%r14d
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <prog_v8sub@plt>
  mov    %eax,%r13d
  cmp    %eax,%r14d
  jne    L19
  add    $0x1,%ebp
  cmp    $0xa,%ebp
  jne    L4
  lea    D69(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  sar    $0x10,%edx
  movzbl %dl,%edx
  mov    %ebx,%esi
  shr    $0x18,%esi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  sar    $0x10,%edx
  movzbl %dl,%edx
  mov    %r12d,%esi
  shr    $0x18,%esi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14d,%eax
  movzbl %ah,%ecx
  mov    %r14d,%edx
  sar    $0x10,%edx
  movzbl %dl,%edx
  mov    %r14d,%esi
  shr    $0x18,%esi
  movzbl %r14b,%r8d
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13d,%eax
  movzbl %ah,%ecx
  mov    %r13d,%edx
  sar    $0x10,%edx
  movzbl %dl,%edx
  mov    %r13d,%esi
  shr    $0x18,%esi
  movzbl %r13b,%r8d
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L11
```

tool_calls: name: parse_data
arguments: label: D46
type_guessed: string
name: parse_data
arguments: label: D69
type_guessed: string
name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D36
type_guessed: string
name: parse_data
arguments: label: D41
type_guessed: string
name: parse_data
arguments: label: D43
type_guessed: string
name: parse_data
arguments: label: D37
type_guessed: string

tool: D46: LAUNCHING THE (MMX_SUB) RESOURCE AUTOTEST...

tool: D69: - TEST OF THE MMX_SUB_8b RESOURCE => OK

tool: D28: - TEST OF THE (MMX_SUB) RESOURCE => FAILED !

tool: D2:   + %d COMPUTATION(s) BEFORE ERROR...


tool: D36:   + OPERANDE 1 [%.3d %.3d %.3d %.3d]


tool: D41:   + OPERANDE 2 [%.3d %.3d %.3d %.3d]


tool: D43:   + ASM INSTR. [%.3d %.3d %.3d %.3d]


tool: D37:   + REF C CODE [%.3d %.3d %.3d %.3d]


assistant: ```c
int MMX_SUB_8b_AUTOTEST() {
  printf("LAUNCHING THE (MMX_SUB) RESOURCE AUTOTEST...\n");
  int i, j;
  for (j = 0; j < 10; j++) {
    int op1 = ((rand() % 65536) << 16) & (rand() % 65536);
    int op2 = ((rand() % 65536) << 16) & (rand() % 65536);
    int op3 = instr_v8sub(op1, op2);
    int op4 = prog_v8sub(op1, op2);
    if (op3 != op4) {
      printf("- TEST OF THE (MMX_SUB) RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION(s) BEFORE ERROR...\n", j);
      printf("  + OPERANDE 1 [%.3d %.3d %.3d %.3d]\n", ((op1 & 0xFF000000) >> 24), ((op1 & 0x00FF0000) >> 16), ((op1 & 0x0000FF00) >> 8), ((op1 & 0x000000FF)));
      printf("  + OPERANDE 2 [%.3d %.3d %.3d %.3d]\n", ((op2 & 0xFF000000) >> 24), ((op2 & 0x00FF0000) >> 16), ((op2 & 0x0000FF00) >> 8), ((op2 & 0x000000FF)));
      printf("  + ASM INSTR. [%.3d %.3d %.3d %.3d]\n", ((op3 & 0xFF000000) >> 24), ((op3 & 0x00FF0000) >> 16), ((op3 & 0x0000FF00) >> 8), ((op3 & 0x000000FF)));
      printf("  + REF C CODE [%.3d %.3d %.3d %.3d]\n", ((op4 & 0xFF000000) >> 24), ((op4 & 0x00FF0000) >> 16), ((op4 & 0x0000FF00) >> 8), ((op4 & 0x000000FF)));
      return 0;
    }
  }
  printf("- TEST OF THE MMX_SUB_8b RESOURCE => OK\n");
  return 1;
}
```