ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_spec_indented_and_max_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L69:
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L5
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L55
L90:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L90
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L71
L63:
  subl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L27
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L63
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L85
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L23
L121:
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L85
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L121
L85:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L108
L10:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L108:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L10
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x1,-0x10(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L69
L71:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type: string

tool: D11:         

assistant: ```c
void print_spec_indented_and_max_length(const char *str, int len, int Num) {
  int notfirsttime = 0;
  int slen = strlen(str);
  int lo = 0, hi = 0;
  while (hi < slen) {
    hi = lo + len;
    if (hi >= slen) {
      printf("        ");
      for (lo += notfirsttime; lo < slen; lo++)
        printf("%c", str[lo]);
      printf("\n");
      return;
    }
    while (!(isspace(str[hi])) && hi > lo)
      hi--;
    if (hi == lo) {
      hi = lo + len;
      while (!(isspace(str[hi])) && hi < slen)
        hi++;
    }
    printf("        ");
    for (lo += notfirsttime; lo < hi; lo++)
      printf("%c", str[lo]);
    printf("\n");
    notfirsttime = 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_spec_indented_and_max_length>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %esi,0xc(%rsp)
  call   <strlen@plt>
  test   %eax,%eax
  jle    L55
  mov    %eax,%r15d
  cmp    %ebx,%eax
  jle    L104
  mov    %ebx,%r14d
  mov    $0x0,%ebp
  movl   $0x0,0x8(%rsp)
  jmp    L7
L61:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1(%rbp),%ebx
  cmp    %ebx,%r15d
  jle    L82
L119:
  movslq %ebx,%rbx
L43:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jg     L43
L82:
  mov    $0xa,%edi
  call   <putchar@plt>
L55:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L101:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    0x8(%rsp),%ebp
  cmp    %ebp,%r12d
  jle    L137
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,1),%rbx
  lea    0x1(%r13,%rax,1),%rdx
  mov    %r12d,%eax
  sub    %ebp,%eax
  lea    -0x1(%rax),%eax
  lea    (%rdx,%rax,1),%rbp
L54:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L54
  mov    %r12d,%ebp
L137:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r15d,%r12d
  jge    L55
  mov    0xc(%rsp),%eax
  lea    (%rax,%rbp,1),%r14d
  movl   $0x1,0x8(%rsp)
  cmp    %r14d,%r15d
  jle    L61
L7:
  movslq %r14d,%r14
  mov    %r14,%rbx
L38:
  mov    %ebx,%r12d
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <isspace@plt>
  cmp    %ebx,%ebp
  setl   %dl
  test   %eax,%eax
  sete   %al
  sub    $0x1,%rbx
  test   %al,%dl
  jne    L38
  cmp    %ebp,%r12d
  jne    L101
L65:
  mov    %r14d,%r12d
  movsbl 0x0(%r13,%r14,1),%edi
  call   <isspace@plt>
  cmp    %r14d,%r15d
  setg   %dl
  test   %eax,%eax
  sete   %al
  add    $0x1,%r14
  test   %al,%dl
  jne    L65
  jmp    L101
L104:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L119
```

tool_calls: name: retrieve_data
arguments: tag: D23
type_infered: string

tool: D23:         

assistant: ```c
void print_spec_indented_and_max_length(const char *str, int len, int Num) {
  int notfirsttime = 0;
  int slen = strlen(str);
  int lo = 0, hi = 0;
  while (hi < slen) {
    hi = lo + len;
    if (hi >= slen) {
      printf("        ");
      for (lo += notfirsttime; lo < slen; lo++)
        printf("%c", str[lo]);
      printf("\n");
      return;
    }
    while (!(isspace(str[hi])) && hi > lo)
      hi--;
    if (hi == lo) {
      hi = lo + len;
      while (!(isspace(str[hi])) && hi < slen)
        hi++;
    }
    printf("        ");
    for (lo += notfirsttime; lo < hi; lo++)
      printf("%c", str[lo]);
    printf("\n");
    notfirsttime = 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_spec_indented_and_max_length>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  call   <strlen@plt>
  test   %eax,%eax
  jle    L56
  mov    %eax,%r14d
  cmp    %ebx,%eax
  jle    L126
  lea    0x1(%r12),%rax
  movl   $0x0,(%rsp)
  mov    %ebx,%r13d
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L52:
  movslq %r13d,%r13
  mov    %r13,%r15
  cs nopw 0x0(%rax,%rax,1)
L32:
  movsbl (%r12,%r15,1),%edi
  mov    %r15d,%ebp
  call   <isspace@plt>
  test   %eax,%eax
  sete   %cl
  cmp    %r15d,%ebx
  setl   %al
  sub    $0x1,%r15
  test   %al,%cl
  jne    L32
  cmp    %ebx,%ebp
  je     L18
L60:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    (%rsp),%ebx
  cmp    %ebx,%ebp
  jle    L47
  mov    %ebp,%edx
  movslq %ebx,%rax
  sub    %ebx,%edx
  lea    (%r12,%rax,1),%r13
  add    0x8(%rsp),%rax
  lea    -0x1(%rdx),%ebx
  add    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L113:
  movsbl 0x0(%r13),%edi
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L113
  mov    %ebp,%ebx
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r14d,%ebp
  jge    L56
  mov    0x4(%rsp),%eax
  movl   $0x1,(%rsp)
  lea    (%rax,%rbx,1),%r13d
  cmp    %r13d,%r14d
  jg     L52
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L74
L68:
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L72:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r14d
  jg     L72
L74:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  movsbl (%r12,%r13,1),%edi
  mov    %r13d,%ebp
  call   <isspace@plt>
  cmp    %r13d,%r14d
  setg   %dl
  test   %eax,%eax
  sete   %al
  add    $0x1,%r13
  test   %al,%dl
  jne    L18
  jmp    L60
L56:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L126:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  jmp    L68
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2:         

assistant: ```c
void print_spec_indented_and_max_length(const char *str, int len, int Num) {
  int notfirsttime = 0;
  int slen = strlen(str);
  int lo = 0, hi = 0;
  while (hi < slen) {
    hi = lo + len;
    if (hi >= slen) {
      printf("        ");
      for (lo += notfirsttime; lo < slen; lo++)
        printf("%c", str[lo]);
      printf("\n");
      return;
    }
    while (!(isspace(str[hi])) && hi > lo)
      hi--;
    if (hi == lo) {
      hi = lo + len;
      while (!(isspace(str[hi])) && hi < slen)
        hi++;
    }
    printf("        ");
    for (lo += notfirsttime; lo < hi; lo++)
      printf("%c", str[lo]);
    printf("\n");
    notfirsttime = 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_spec_indented_and_max_length>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  call   <strlen@plt>
  test   %eax,%eax
  jle    L36
  mov    %eax,%r14d
  cmp    %ebx,%eax
  jle    L112
  lea    0x1(%r12),%rax
  movl   $0x0,(%rsp)
  mov    %ebx,%r13d
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L10:
  movslq %r13d,%r13
  mov    %r13,%r15
  cs nopw 0x0(%rax,%rax,1)
L126:
  movsbl (%r12,%r15,1),%edi
  mov    %r15d,%ebp
  call   <isspace@plt>
  test   %eax,%eax
  sete   %cl
  cmp    %r15d,%ebx
  setl   %al
  sub    $0x1,%r15
  test   %al,%cl
  jne    L126
  cmp    %ebx,%ebp
  je     L59
L22:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    (%rsp),%ebx
  cmp    %ebx,%ebp
  jle    L52
  mov    %ebp,%edx
  movslq %ebx,%rax
  sub    %ebx,%edx
  lea    (%r12,%rax,1),%r13
  add    0x8(%rsp),%rax
  sub    $0x1,%edx
  lea    (%rax,%rdx,1),%rbx
  nopl   0x0(%rax)
L2:
  movsbl 0x0(%r13),%edi
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L2
  mov    %ebp,%ebx
L52:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r14d,%ebp
  jge    L36
  mov    0x4(%rsp),%eax
  movl   $0x1,(%rsp)
  lea    (%rax,%rbx,1),%r13d
  cmp    %r13d,%r14d
  jg     L10
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L39
L78:
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L44:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r14d
  jg     L44
L39:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L59:
  movsbl (%r12,%r13,1),%edi
  mov    %r13d,%ebp
  call   <isspace@plt>
  cmp    %r13d,%r14d
  setg   %dl
  test   %eax,%eax
  sete   %al
  add    $0x1,%r13
  test   %al,%dl
  jne    L59
  jmp    L22
L36:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L112:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  jmp    L78
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1:         

assistant: ```c
void print_spec_indented_and_max_length(const char *str, int len, int Num) {
  int notfirsttime = 0;
  int slen = strlen(str);
  int lo = 0, hi = 0;
  while (hi < slen) {
    hi = lo + len;
    if (hi >= slen) {
      printf("        ");
      for (lo += notfirsttime; lo < slen; lo++)
        printf("%c", str[lo]);
      printf("\n");
      return;
    }
    while (!(isspace(str[hi])) && hi > lo)
      hi--;
    if (hi == lo) {
      hi = lo + len;
      while (!(isspace(str[hi])) && hi < slen)
        hi++;
    }
    printf("        ");
    for (lo += notfirsttime; lo < hi; lo++)
      printf("%c", str[lo]);
    printf("\n");
    notfirsttime = 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max(int x, int y) {
  int z;
  z = x > y ? x : y;
  return (z);
}
```
user: What is the c source code of the assembly code below?

```asm
<max>:
  endbr64
  cmp    %edi,%esi
  mov    %edi,%eax
  cmovge %esi,%eax
  ret
```

assistant: ```c
int max(int x, int y) {
  int z;
  z = x > y ? x : y;
  return (z);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<max>:
  endbr64
  cmp    %edi,%esi
  mov    %edi,%eax
  cmovge %esi,%eax
  ret
```

assistant: ```c
int max(int x, int y) {
  int z;
  z = x > y ? x : y;
  return (z);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_twenty_six>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1a,%eax
  jne    L28
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1a,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1a,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1a,(%rax)
  jmp    L10
L28:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  nop
L10:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void is_twenty_six(int hand_score[], int len) {
  for (int i = 0; i < len; i++)
    if (hand_score[i] == 26) {
      hand_score[i] = 0;
      hand_score[(i + 1) % len] = 26;
      hand_score[(i + 2) % len] = 26;
      hand_score[(i + 3) % len] = 26;
      break;
    }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_twenty_six>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    %rdi,%rdx
  mov    $0x0,%ecx
L8:
  cmpl   $0x1a,(%rdx)
  je     L3
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %ecx,%esi
  jne    L8
L15:
  ret
L3:
  movl   $0x0,(%rdx)
  lea    0x1(%rcx),%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  lea    0x2(%rcx),%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  lea    0x3(%rcx),%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  ret
```

assistant: ```c
void is_twenty_six(int hand_score[], int len) {
  for (int i = 0; i < len; i++)
    if (hand_score[i] == 26) {
      hand_score[i] = 0;
      hand_score[(i + 1) % len] = 26;
      hand_score[(i + 2) % len] = 26;
      hand_score[(i + 3) % len] = 26;
      break;
    }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_twenty_six>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L20
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L4
  nopl   0x0(%rax)
L0:
  add    $0x4,%rdx
  cmp    %eax,%ecx
  je     L20
L4:
  mov    %eax,%esi
  add    $0x1,%eax
  cmpl   $0x1a,(%rdx)
  jne    L0
  movl   $0x0,(%rdx)
  cltd
  idiv   %ecx
  lea    0x2(%rsi),%eax
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  cltd
  idiv   %ecx
  lea    0x3(%rsi),%eax
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  cltd
  idiv   %ecx
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  ret
  xchg   %ax,%ax
L20:
  ret
```

assistant: ```c
void is_twenty_six(int hand_score[], int len) {
  for (int i = 0; i < len; i++)
    if (hand_score[i] == 26) {
      hand_score[i] = 0;
      hand_score[(i + 1) % len] = 26;
      hand_score[(i + 2) % len] = 26;
      hand_score[(i + 3) % len] = 26;
      break;
    }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_twenty_six>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L38
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L30
  nopl   0x0(%rax)
L29:
  add    $0x4,%rdx
  cmp    %eax,%ecx
  je     L38
L30:
  mov    %eax,%esi
  add    $0x1,%eax
  cmpl   $0x1a,(%rdx)
  jne    L29
  movl   $0x0,(%rdx)
  cltd
  idiv   %ecx
  lea    0x2(%rsi),%eax
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  cltd
  idiv   %ecx
  lea    0x3(%rsi),%eax
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  cltd
  idiv   %ecx
  movslq %edx,%rdx
  movl   $0x1a,(%rdi,%rdx,4)
  ret
  xchg   %ax,%ax
L38:
  ret
```

assistant: ```c
void is_twenty_six(int hand_score[], int len) {
  for (int i = 0; i < len; i++)
    if (hand_score[i] == 26) {
      hand_score[i] = 0;
      hand_score[(i + 1) % len] = 26;
      hand_score[(i + 2) % len] = 26;
      hand_score[(i + 3) % len] = 26;
      break;
    }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x11(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L33
L21:
  mov    -0x3c(%rbp),%eax
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  sarl   -0x3c(%rbp)
  addl   $0x1,-0x38(%rbp)
L33:
  cmpl   $0x0,-0x3c(%rbp)
  jle    L6
  cmpl   $0x1e,-0x38(%rbp)
  jle    L21
L6:
  cmpl   $0x1e,-0x38(%rbp)
  jg     L35
  mov    -0x38(%rbp),%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
L35:
  subl   $0x1,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L40
L38:
  mov    -0x38(%rbp),%eax
  sub    -0x34(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  mov    %al,-0x41(%rbp)
  mov    -0x38(%rbp),%eax
  sub    -0x34(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%edx
  movslq %ecx,%rax
  mov    %dl,-0x30(%rbp,%rax,1)
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x41(%rbp),%edx
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x34(%rbp)
L40:
  mov    -0x38(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x34(%rbp)
  jle    L38
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string
name: retrieve_data
arguments: label: D0
data_type: string

tool: D15: %d

tool: D25: 0b%s


tool: D0: 0x%x


assistant: ```c
int main(int argc, char *argv[]) {
  int i, b;
  char B[32];
  int j, k;
  char tmp;
  B[31] = '\0';
  scanf("%d", &i);
  b = i;
  for (j = 0; b > 0 && j < 31; j++) {
    B[j] = (b & 0x1) + '0';
    b >>= 1;
  }
  if (j < 31)
    B[j] = '\0';
  j--;
  for (k = 0; k <= j / 2; k++) {
    tmp = B[j - k];
    B[j - k] = B[k];
    B[k] = tmp;
  }
  printf("0b%s\n", B);
  printf("0x%x\n", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x2f(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L34
  mov    $0x1,%edx
  lea    0xf(%rsp),%r8
L67:
  mov    %ecx,%eax
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %al,(%r8,%rdx,1)
  sar    %ecx
  mov    %edx,%eax
  test   %ecx,%ecx
  setg   %dil
  cmp    $0x1e,%edx
  setle  %sil
  add    $0x1,%rdx
  test   %sil,%dil
  jne    L67
  cmp    $0x1e,%eax
  jle    L61
L64:
  lea    -0x1(%rax),%edx
  mov    %edx,%r8d
  shr    $0x1f,%r8d
  add    %edx,%r8d
  sar    %r8d
  cmp    $0xffffffff,%edx
  jl     L23
  lea    0x10(%rsp),%rdx
  cltq
  add    %rdx,%rax
  mov    $0x0,%ecx
L43:
  movzbl -0x1(%rax),%esi
  movzbl (%rdx),%edi
  mov    %dil,-0x1(%rax)
  mov    %sil,(%rdx)
  add    $0x1,%ecx
  sub    $0x1,%rax
  add    $0x1,%rdx
  cmp    %r8d,%ecx
  jle    L43
L23:
  lea    0x10(%rsp),%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L34:
  mov    $0x0,%eax
L61:
  movslq %eax,%rdx
  movb   $0x0,0x10(%rsp,%rdx,1)
  jmp    L64
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D24
type: string

tool: D23: %d

tool: D12: 0b%s


tool: D24: 0x%x


assistant: ```c
int main(int argc, char *argv[]) {
  int i, b;
  char B[32];
  int j, k;
  char tmp;
  B[31] = '\0';
  scanf("%d", &i);
  b = i;
  for (j = 0; b > 0 && j < 31; j++) {
    B[j] = (b & 0x1) + '0';
    b >>= 1;
  }
  if (j < 31)
    B[j] = '\0';
  j--;
  for (k = 0; k <= j / 2; k++) {
    tmp = B[j - k];
    B[j - k] = B[k];
    B[k] = tmp;
  }
  printf("0b%s\n", B);
  printf("0x%x\n", i);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movb   $0x0,0x2f(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L5
  mov    $0x1,%eax
  lea    0xf(%rsp),%rsi
  nopl   0x0(%rax)
L53:
  mov    %edx,%ecx
  sar    %edx
  mov    %eax,%r8d
  and    $0x1,%ecx
  add    $0x30,%ecx
  test   %edx,%edx
  setg   %dil
  cmp    $0x1e,%eax
  mov    %cl,(%rax,%rsi,1)
  setle  %cl
  add    $0x1,%rax
  test   %cl,%dil
  jne    L53
  mov    $0x1f,%ecx
  cmp    $0x1f,%r8d
  je     L0
L2:
  movslq %r8d,%rcx
  movb   $0x0,0x10(%rsp,%rcx,1)
L0:
  lea    0x10(%rsp),%r9
  sub    $0x1,%r8d
  add    %rcx,%rsi
  lea    (%r9,%rcx,1),%rax
  mov    %r8d,%ecx
  mov    %r9,%rdx
  shr    $0x1f,%ecx
  add    %r8d,%ecx
  sar    %ecx
  movslq %ecx,%rcx
  sub    %rcx,%rsi
  nopl   0x0(%rax)
L28:
  movzbl (%rdx),%edi
  movzbl -0x1(%rax),%ecx
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %dil,(%rax)
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rax
  jne    L28
  mov    %r9,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L5:
  xor    %r8d,%r8d
  lea    0xf(%rsp),%rsi
  jmp    L2
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string
name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D18
datatype: string

tool: D5: %d

tool: D17: 0b%s


tool: D18: 0x%x


assistant: ```c
int main(int argc, char *argv[]) {
  int i, b;
  char B[32];
  int j, k;
  char tmp;
  B[31] = '\0';
  scanf("%d", &i);
  b = i;
  for (j = 0; b > 0 && j < 31; j++) {
    B[j] = (b & 0x1) + '0';
    b >>= 1;
  }
  if (j < 31)
    B[j] = '\0';
  j--;
  for (k = 0; k <= j / 2; k++) {
    tmp = B[j - k];
    B[j - k] = B[k];
    B[k] = tmp;
  }
  printf("0b%s\n", B);
  printf("0x%x\n", i);
  return 0;
}
```