ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<argdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <arglen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L33
  mov    $0x0,%eax
  jmp    L31
L33:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L31
L12:
  mov    -0x28(%rbp),%r8d
  mov    -0x24(%rbp),%edi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <argncpy@plt>
  mov    -0x8(%rbp),%rax
L31:
  leave
  ret
```

assistant: ```c
char *argdup(char *src, char *sep, int arg, int opt) {
  char *dst;
  int l;
  l = arglen(src, sep, arg, opt);
  if (l < 0)
    return (NULL);
  dst = malloc(++l);
  if (!dst)
    return (NULL);
  argncpy(dst, l, src, sep, arg, opt);
  return (dst);
}
```
user: Translate the below assembly code into C programming language:

```asm
<argdup>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,%r14d
  call   <arglen@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  js     L14
  lea    0x1(%rax),%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    %r14d,%r9d
  mov    %r13d,%r8d
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %r15d,%esi
  mov    %rax,%rdi
  call   <argncpy@plt>
L14:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *argdup(char *src, char *sep, int arg, int opt) {
  char *dst;
  int l;
  l = arglen(src, sep, arg, opt);
  if (l < 0)
    return (NULL);
  dst = malloc(++l);
  if (!dst)
    return (NULL);
  argncpy(dst, l, src, sep, arg, opt);
  return (dst);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<argdup>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <arglen@plt>
  test   %eax,%eax
  js     L16
  lea    0x1(%rax),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  mov    %r15d,%r9d
  mov    %ebx,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <argncpy@plt>
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *argdup(char *src, char *sep, int arg, int opt) {
  char *dst;
  int l;
  l = arglen(src, sep, arg, opt);
  if (l < 0)
    return (NULL);
  dst = malloc(++l);
  if (!dst)
    return (NULL);
  argncpy(dst, l, src, sep, arg, opt);
  return (dst);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<argdup>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <arglen@plt>
  test   %eax,%eax
  js     L13
  lea    0x1(%rax),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
  mov    %r15d,%r9d
  mov    %ebx,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <argncpy@plt>
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *argdup(char *src, char *sep, int arg, int opt) {
  char *dst;
  int l;
  l = arglen(src, sep, arg, opt);
  if (l < 0)
    return (NULL);
  dst = malloc(++l);
  if (!dst)
    return (NULL);
  argncpy(dst, l, src, sep, arg, opt);
  return (dst);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D15(%rip),%rax
  leave
  ret
```

assistant: ```c
char *kerror(key, emess)
char *key, *emess;
{
  static char ebuf[80];
  (void)strcpy(ebuf, key);
  (void)strcat(ebuf, emess);
  return ebuf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<kerror>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *kerror(key, emess)
char *key, *emess;
{
  static char ebuf[80];
  (void)strcpy(ebuf, key);
  (void)strcat(ebuf, emess);
  return ebuf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kerror>:
  endbr64
  push   %rbp
  lea    D6(%rip),%r8
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  pop    %rbp
  ret
```

assistant: ```c
char *kerror(key, emess)
char *key, *emess;
{
  static char ebuf[80];
  (void)strcpy(ebuf, key);
  (void)strcat(ebuf, emess);
  return ebuf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kerror>:
  endbr64
  push   %rbp
  lea    D3(%rip),%r8
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  pop    %rbp
  ret
```

assistant: ```c
char *kerror(key, emess)
char *key, *emess;
{
  static char ebuf[80];
  (void)strcpy(ebuf, key);
  (void)strcat(ebuf, emess);
  return ebuf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<os_shutdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <shutdown@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L6
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int os_shutdown(int sock, int how) {
  int retval;
  retval = shutdown(sock, how);
  if (retval == -1)
    retval = -errno;
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<os_shutdown>:
  endbr64
  sub    $0x8,%rsp
  call   <shutdown@plt>
  cmp    $0xffffffff,%eax
  je     L8
L16:
  add    $0x8,%rsp
  ret
L8:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L16
```

assistant: ```c
int os_shutdown(int sock, int how) {
  int retval;
  retval = shutdown(sock, how);
  if (retval == -1)
    retval = -errno;
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<os_shutdown>:
  endbr64
  sub    $0x8,%rsp
  call   <shutdown@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int os_shutdown(int sock, int how) {
  int retval;
  retval = shutdown(sock, how);
  if (retval == -1)
    retval = -errno;
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<os_shutdown>:
  endbr64
  sub    $0x8,%rsp
  call   <shutdown@plt>
  cmp    $0xffffffff,%eax
  jne    L0
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int os_shutdown(int sock, int how) {
  int retval;
  retval = shutdown(sock, how);
  if (retval == -1)
    retval = -errno;
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<setupNVIC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe000e100,%eax
  mov    (%rax),%edx
  mov    $0xe000e100,%eax
  or     $0x8,%dh
  mov    %edx,(%rax)
  mov    $0xe000e100,%eax
  mov    (%rax),%edx
  mov    $0xe000e100,%eax
  or     $0x2,%edx
  mov    %edx,(%rax)
  mov    $0xe000e100,%eax
  mov    (%rax),%edx
  mov    $0xe000e100,%eax
  or     $0x4000000,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setupNVIC() {
  *((volatile uint32_t *)0xe000e100) |= (1 << 11);
  *((volatile uint32_t *)0xe000e100) |= (1 << 1);
  *((volatile uint32_t *)0xe000e100) |= (1 << 26);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setupNVIC>:
  endbr64
  mov    $0xe000e100,%eax
  mov    (%rax),%edx
  or     $0x8,%dh
  mov    %edx,(%rax)
  mov    (%rax),%edx
  or     $0x2,%edx
  mov    %edx,(%rax)
  mov    (%rax),%edx
  or     $0x4000000,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void setupNVIC() {
  *((volatile uint32_t *)0xe000e100) |= (1 << 11);
  *((volatile uint32_t *)0xe000e100) |= (1 << 1);
  *((volatile uint32_t *)0xe000e100) |= (1 << 26);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setupNVIC>:
  endbr64
  mov    $0xe000e100,%eax
  mov    (%rax),%edx
  or     $0x8,%dh
  mov    %edx,(%rax)
  mov    (%rax),%edx
  or     $0x2,%edx
  mov    %edx,(%rax)
  mov    (%rax),%edx
  or     $0x4000000,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void setupNVIC() {
  *((volatile uint32_t *)0xe000e100) |= (1 << 11);
  *((volatile uint32_t *)0xe000e100) |= (1 << 1);
  *((volatile uint32_t *)0xe000e100) |= (1 << 26);
}
```
user: What is the c source code of the assembly code below:

```asm
<setupNVIC>:
  endbr64
  mov    $0xe000e100,%eax
  mov    (%rax),%edx
  or     $0x8,%dh
  mov    %edx,(%rax)
  mov    (%rax),%edx
  or     $0x2,%edx
  mov    %edx,(%rax)
  mov    (%rax),%edx
  or     $0x4000000,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void setupNVIC() {
  *((volatile uint32_t *)0xe000e100) |= (1 << 11);
  *((volatile uint32_t *)0xe000e100) |= (1 << 1);
  *((volatile uint32_t *)0xe000e100) |= (1 << 26);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hb_need_downmix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <hb_layout_to_mode@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <hb_mixdown_to_mode@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int hb_need_downmix(int layout, int mixdown) {
  int mode_in, mode_out;
  mode_in = hb_layout_to_mode(layout);
  mode_out = hb_mixdown_to_mode(mixdown);
  return (mode_in != mode_out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hb_need_downmix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  call   <hb_layout_to_mode@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <hb_mixdown_to_mode@plt>
  cmp    %eax,%ebx
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int hb_need_downmix(int layout, int mixdown) {
  int mode_in, mode_out;
  mode_in = hb_layout_to_mode(layout);
  mode_out = hb_mixdown_to_mode(mixdown);
  return (mode_in != mode_out);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hb_need_downmix>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <hb_layout_to_mode@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <hb_mixdown_to_mode@plt>
  cmp    %eax,%ebx
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int hb_need_downmix(int layout, int mixdown) {
  int mode_in, mode_out;
  mode_in = hb_layout_to_mode(layout);
  mode_out = hb_mixdown_to_mode(mixdown);
  return (mode_in != mode_out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hb_need_downmix>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <hb_layout_to_mode@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <hb_mixdown_to_mode@plt>
  cmp    %eax,%ebx
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int hb_need_downmix(int layout, int mixdown) {
  int mode_in, mode_out;
  mode_in = hb_layout_to_mode(layout);
  mode_out = hb_mixdown_to_mode(mixdown);
  return (mode_in != mode_out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<part_is_in_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L47
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jb     L32
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%ecx
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    -0x30(%rbp),%rdx
  add    %rsi,%rdx
  mov    (%rdx),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jb     L8
L32:
  mov    $0x0,%eax
  jmp    L49
L8:
  addl   $0x1,-0x4(%rbp)
L47:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  mov    $0x1,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int part_is_in_range(int dims, const unsigned int *point, const unsigned int *start, const unsigned int *size) {
  int i;
  for (i = 0; i < dims; i++)
    if (point[i] < start[i] || point[i] >= start[i] + size[i])
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<part_is_in_range>:
  endbr64
  test   %edi,%edi
  jle    L15
  mov    %edi,%edi
  mov    $0x0,%eax
L1:
  mov    (%rsi,%rax,4),%r9d
  mov    (%rdx,%rax,4),%r8d
  cmp    %r8d,%r9d
  jb     L5
  add    (%rcx,%rax,4),%r8d
  cmp    %r8d,%r9d
  jae    L24
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L1
  mov    $0x1,%eax
  ret
L15:
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
L24:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int part_is_in_range(int dims, const unsigned int *point, const unsigned int *start, const unsigned int *size) {
  int i;
  for (i = 0; i < dims; i++)
    if (point[i] < start[i] || point[i] >= start[i] + size[i])
      return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<part_is_in_range>:
  endbr64
  test   %edi,%edi
  jle    L1
  movslq %edi,%rdi
  xor    %eax,%eax
  jmp    L27
  nop
L6:
  add    (%rcx,%rax,4),%r8d
  cmp    %r8d,%r9d
  jae    L25
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L1
L27:
  mov    (%rsi,%rax,4),%r9d
  mov    (%rdx,%rax,4),%r8d
  cmp    %r8d,%r9d
  jae    L6
L25:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int part_is_in_range(int dims, const unsigned int *point, const unsigned int *start, const unsigned int *size) {
  int i;
  for (i = 0; i < dims; i++)
    if (point[i] < start[i] || point[i] >= start[i] + size[i])
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<part_is_in_range>:
  endbr64
  test   %edi,%edi
  jle    L5
  movslq %edi,%rdi
  xor    %eax,%eax
  jmp    L33
  nop
L20:
  add    (%rcx,%rax,4),%r8d
  cmp    %r8d,%r9d
  jae    L29
  add    $0x1,%rax
  cmp    %rax,%rdi
  je     L5
L33:
  mov    (%rsi,%rax,4),%r9d
  mov    (%rdx,%rax,4),%r8d
  cmp    %r8d,%r9d
  jae    L20
L29:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int part_is_in_range(int dims, const unsigned int *point, const unsigned int *start, const unsigned int *size) {
  int i;
  for (i = 0; i < dims; i++)
    if (point[i] < start[i] || point[i] >= start[i] + size[i])
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L5:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L45:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jle    L31
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L31
  cmpl   $0xa,-0x8(%rbp)
  jne    L5
L31:
  cmpl   $0xa,-0x8(%rbp)
  jne    L22
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L22:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getln(char s[], int lim) {
  int c, i;
  i = 0;
  while (lim-- > 0 && (c = getchar()) != EOF && c != '\n')
    s[i++] = c;
  if (c == '\n')
    s[i++] = c;
  s[i] = '\0';
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getln>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  test   %esi,%esi
  jle    L26
  mov    %esi,%r12d
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L6:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D4(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L29
  cmp    $0xa,%eax
  je     L29
  add    $0x1,%ebx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %ebx,%r12d
  jne    L6
  mov    %r12d,%ebx
  jmp    L7
L26:
  mov    $0x0,%ebx
L29:
  cmp    $0xa,%eax
  je     L54
L7:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  lea    0x1(%rbx),%ebx
  jmp    L7
```

assistant: ```c
int getln(char s[], int lim) {
  int c, i;
  i = 0;
  while (lim-- > 0 && (c = getchar()) != EOF && c != '\n')
    s[i++] = c;
  if (c == '\n')
    s[i++] = c;
  s[i] = '\0';
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getln>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L14
  mov    D3(%rip),%r12
  mov    %esi,%ebp
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L7:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L53
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L51
  mov    %edx,%r14d
L44:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L7
  cmp    $0xa,%eax
  je     L3
L14:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  lea    0x1(%r14),%edx
L53:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L51:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getln(char s[], int lim) {
  int c, i;
  i = 0;
  while (lim-- > 0 && (c = getchar()) != EOF && c != '\n')
    s[i++] = c;
  if (c == '\n')
    s[i++] = c;
  s[i] = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getln>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L57
  mov    D2(%rip),%r12
  mov    %esi,%ebp
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L13:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L59
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L15
  mov    %edx,%r14d
L52:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L13
  cmp    $0xa,%eax
  je     L12
L57:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  lea    0x1(%r14),%edx
L59:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L15:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getln(char s[], int lim) {
  int c, i;
  i = 0;
  while (lim-- > 0 && (c = getchar()) != EOF && c != '\n')
    s[i++] = c;
  if (c == '\n')
    s[i++] = c;
  s[i] = '\0';
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<switch4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L42
  cmpl   $0x3,-0x4(%rbp)
  je     L52
  cmpl   $0xfffffffe,-0x4(%rbp)
  jne    L45
  mov    $0x1,%eax
  jmp    L47
L42:
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  jmp    L47
L52:
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  jmp    L47
L45:
  mov    $0x2c,%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int switch4(unsigned a) {
  switch (a) {
  case -2:
    return 1;
  case -1:
    return a + 3;
  case 3:
    return a + 3;
  default:
    return 44;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<switch4>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xfffffffe,%edi
  je     L7
  mov    $0x2,%eax
  cmp    $0xffffffff,%edi
  je     L7
  cmp    $0x3,%edi
  mov    $0x2c,%eax
  mov    $0x6,%edx
  cmove  %edx,%eax
L7:
  ret
```

assistant: ```c
int switch4(unsigned a) {
  switch (a) {
  case -2:
    return 1;
  case -1:
    return a + 3;
  case 3:
    return a + 3;
  default:
    return 44;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<switch4>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xfffffffe,%edi
  je     L11
  mov    $0x2,%eax
  cmp    $0xffffffff,%edi
  je     L11
  cmp    $0x3,%edi
  mov    $0x2c,%eax
  mov    $0x6,%edx
  cmove  %edx,%eax
L11:
  ret
```

assistant: ```c
int switch4(unsigned a) {
  switch (a) {
  case -2:
    return 1;
  case -1:
    return a + 3;
  case 3:
    return a + 3;
  default:
    return 44;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<switch4>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xfffffffe,%edi
  je     L8
  mov    $0x2,%eax
  cmp    $0xffffffff,%edi
  je     L8
  cmp    $0x3,%edi
  mov    $0x2c,%eax
  mov    $0x6,%edx
  cmove  %edx,%eax
L8:
  ret
```

assistant: ```c
int switch4(unsigned a) {
  switch (a) {
  case -2:
    return 1;
  case -1:
    return a + 3;
  case 3:
    return a + 3;
  default:
    return 44;
  }
}
```