ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<check_realpath_recurse>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D33(%rip),%rax
  mov    %rsp,%rsi
  mov    %rsp,%r15
  mov    (%rax),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L57
L154:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L154
L57:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L30
L17:
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %edx,-0x44(%rbp)
  mov    %rsp,%r14
  call   <check_realpath_step_by_step@plt>
  mov    -0x44(%rbp),%edx
  test   %edx,%edx
  jle    L6
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    -0x44(%rbp),%edx
  mov    %rax,%r13
  lea    -0x1(%rdx),%eax
  mov    %eax,-0x44(%rbp)
  test   %r13,%r13
  je     L106
L71:
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L157
L77:
  mov    (%rax),%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <pathncat@plt>
  test   %eax,%eax
  je     L153
  mov    -0x44(%rbp),%esi
  mov    %r14,%rdi
  call   <check_realpath_recurse>
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L77
L157:
  mov    %r13,%rdi
  call   <closedir@plt>
  test   %rax,%rax
  js     L78
L6:
  mov    %r15,%rsp
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L146
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L153:
  mov    $0xef,%edi
  call   <e@plt>
  jmp    L71
  nopl   0x0(%rax)
L30:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L78:
  mov    $0xf6,%edi
  call   <e@plt>
  jmp    L6
  nopl   0x0(%rax)
L106:
  mov    D34(%rip),%rax
  mov    D16(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L6
  mov    D11(%rip),%rdx
  cmp    (%rdx),%rax
  je     L6
  mov    $0xe7,%edi
  call   <e@plt>
  jmp    L6
L146:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void check_realpath_recurse(const char *path, int depth) {
  DIR *dir;
  struct dirent *dirent;
  char pathsub[PATH_MAX + 1];
  check_realpath_step_by_step(path, 0);
  if (depth < 1)
    return;
  if (!(dir = opendir(path))) {
    if (errno != ENOENT && errno != ENOTDIR)
      (e(231));
    return;
  }
  while (dirent = readdir(dir)) {
    if (!pathncat(pathsub, sizeof(pathsub), path, dirent->d_name)) {
      (e(239));
      continue;
    }
    check_realpath_recurse(pathsub, depth - 1);
  }
  if (closedir(dir) < 0)
    (e(246));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_realpath_recurse>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %rsp,%rsi
  mov    %rsp,%r15
  mov    (%rax),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L19
L93:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L93
L19:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L69
L44:
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %edx,-0x44(%rbp)
  mov    %rsp,%r14
  call   <check_realpath_step_by_step@plt>
  mov    -0x44(%rbp),%edx
  test   %edx,%edx
  jle    L119
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    -0x44(%rbp),%edx
  mov    %rax,%r13
  lea    -0x1(%rdx),%eax
  mov    %eax,-0x44(%rbp)
  test   %r13,%r13
  je     L47
L83:
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L155
L53:
  mov    (%rax),%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <pathncat@plt>
  test   %eax,%eax
  je     L76
  mov    -0x44(%rbp),%esi
  mov    %r14,%rdi
  call   <check_realpath_recurse>
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L53
L155:
  mov    %r13,%rdi
  call   <closedir@plt>
  test   %rax,%rax
  js     L91
L119:
  mov    %r15,%rsp
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  mov    $0xef,%edi
  call   <e@plt>
  jmp    L83
  nopl   0x0(%rax)
L69:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L91:
  mov    $0xf6,%edi
  call   <e@plt>
  jmp    L119
  nopl   0x0(%rax)
L47:
  mov    D8(%rip),%rax
  mov    D26(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L119
  mov    D2(%rip),%rdx
  cmp    (%rdx),%rax
  je     L119
  mov    $0xe7,%edi
  call   <e@plt>
  jmp    L119
L82:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void check_realpath_recurse(const char *path, int depth) {
  DIR *dir;
  struct dirent *dirent;
  char pathsub[PATH_MAX + 1];
  check_realpath_step_by_step(path, 0);
  if (depth < 1)
    return;
  if (!(dir = opendir(path))) {
    if (errno != ENOENT && errno != ENOTDIR)
      (e(231));
    return;
  }
  while (dirent = readdir(dir)) {
    if (!pathncat(pathsub, sizeof(pathsub), path, dirent->d_name)) {
      (e(239));
      continue;
    }
    check_realpath_recurse(pathsub, depth - 1);
  }
  if (closedir(dir) < 0)
    (e(246));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<byteReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  shl    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  or     %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x18(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  uint32_t t;
  do {
    t = (uint32_t)((unsigned)buf[3] << 8 | buf[2]) << 16 | ((unsigned)buf[1] << 8 | buf[0]);
    *(uint32_t *)buf = t;
    buf += 4;
  } while (--longs);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<byteReverse>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L3:
  movzbl 0x3(%rdi),%eax
  shl    $0x8,%eax
  movzbl 0x2(%rdi),%edx
  or     %edx,%eax
  shl    $0x10,%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%edx
  movzbl (%rdi),%ecx
  or     %ecx,%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L3
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  uint32_t t;
  do {
    t = (uint32_t)((unsigned)buf[3] << 8 | buf[2]) << 16 | ((unsigned)buf[1] << 8 | buf[0]);
    *(uint32_t *)buf = t;
    buf += 4;
  } while (--longs);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byteReverse>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L9:
  add    $0x4,%rdi
  cmp    %rdi,%rax
  jne    L9
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  uint32_t t;
  do {
    t = (uint32_t)((unsigned)buf[3] << 8 | buf[2]) << 16 | ((unsigned)buf[1] << 8 | buf[0]);
    *(uint32_t *)buf = t;
    buf += 4;
  } while (--longs);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<byteReverse>:
  endbr64
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L15
  sub    $0x4,%esi
  xor    %eax,%eax
  shr    $0x2,%esi
  lea    0x1(%rsi),%edx
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x1,%eax
  cmp    %eax,%edx
  ja     L10
L15:
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  uint32_t t;
  do {
    t = (uint32_t)((unsigned)buf[3] << 8 | buf[2]) << 16 | ((unsigned)buf[1] << 8 | buf[0]);
    *(uint32_t *)buf = t;
    buf += 4;
  } while (--longs);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<size_of_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %rax,-0x8(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long size_of_file(FILE *fileS1) {
  long size_file;
  fseek(fileS1, 0, SEEK_END);
  size_file = ftell(fileS1);
  fseek(fileS1, 0, SEEK_SET);
  return size_file;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<size_of_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <fseek@plt>
  mov    %rbx,%rdi
  call   <ftell@plt>
  mov    %rax,%rbp
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long size_of_file(FILE *fileS1) {
  long size_file;
  fseek(fileS1, 0, SEEK_END);
  size_file = ftell(fileS1);
  fseek(fileS1, 0, SEEK_SET);
  return size_file;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<size_of_file>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    %rax,%r12
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long size_of_file(FILE *fileS1) {
  long size_file;
  fseek(fileS1, 0, SEEK_END);
  size_file = ftell(fileS1);
  fseek(fileS1, 0, SEEK_SET);
  return size_file;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<size_of_file>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    %rax,%r12
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long size_of_file(FILE *fileS1) {
  long size_file;
  fseek(fileS1, 0, SEEK_END);
  size_file = ftell(fileS1);
  fseek(fileS1, 0, SEEK_SET);
  return size_file;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unescapestr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L46
  mov    $0x0,%eax
  jmp    L21
L46:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L64
L68:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L7
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  movl   $0x1,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L64
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
L64:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
L21:
  pop    %rbp
  ret
```

assistant: ```c
char *unescapestr(char *src) {
  char *p1, *p2;
  int fl;
  if (src == NULL)
    return NULL;
  p2 = src;
  p1 = p2;
  fl = 0;
  while (*p2) {
    if (*p2 == '\\' && !fl) {
      fl = 1;
      p2++;
    } else {
      *p1 = *p2;
      p1++;
      p2++;
      fl = 0;
    }
  }
  *p1 = 0;
  return src;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unescapestr>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L47
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L65
  lea    0x1(%rdi),%rcx
  mov    %rdi,%rsi
  mov    $0x0,%r8d
  mov    $0x0,%edi
  mov    $0x1,%r9d
  jmp    L22
L61:
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  mov    %rcx,%rdx
  mov    %edi,%r8d
L32:
  movzbl (%rdx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L55
L22:
  test   %r8d,%r8d
  jne    L61
  cmp    $0x5c,%dl
  jne    L61
  mov    %rcx,%rdx
  mov    %r9d,%r8d
  jmp    L32
L65:
  mov    %rdi,%rsi
L55:
  movb   $0x0,(%rsi)
L47:
  ret
```

assistant: ```c
char *unescapestr(char *src) {
  char *p1, *p2;
  int fl;
  if (src == NULL)
    return NULL;
  p2 = src;
  p1 = p2;
  fl = 0;
  while (*p2) {
    if (*p2 == '\\' && !fl) {
      fl = 1;
      p2++;
    } else {
      *p1 = *p2;
      p1++;
      p2++;
      fl = 0;
    }
  }
  *p1 = 0;
  return src;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unescapestr>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L28
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  mov    %rax,%rdi
  mov    %rax,%rsi
  cmp    $0x5c,%dl
  je     L41
L76:
  mov    %rdi,%rcx
L43:
  add    $0x1,%rcx
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L10
  cmp    $0x5c,%dl
  jne    L43
  movzbl 0x1(%rcx),%edx
  lea    0x1(%rcx),%rdi
  test   %dl,%dl
  jne    L76
L10:
  movb   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %rax,%rcx
  movzbl 0x1(%rcx),%edx
  lea    0x1(%rcx),%rdi
  test   %dl,%dl
  jne    L76
  jmp    L10
  nopl   0x0(%rax)
L15:
  mov    %rdi,%rsi
  movb   $0x0,(%rsi)
  ret
L28:
  ret
```

assistant: ```c
char *unescapestr(char *src) {
  char *p1, *p2;
  int fl;
  if (src == NULL)
    return NULL;
  p2 = src;
  p1 = p2;
  fl = 0;
  while (*p2) {
    if (*p2 == '\\' && !fl) {
      fl = 1;
      p2++;
    } else {
      *p1 = *p2;
      p1++;
      p2++;
      fl = 0;
    }
  }
  *p1 = 0;
  return src;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unescapestr>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L48
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L74
  mov    %rax,%rdi
  mov    %rax,%rsi
  cmp    $0x5c,%dl
  je     L35
L18:
  mov    %rdi,%rcx
L28:
  add    $0x1,%rcx
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L36
  cmp    $0x5c,%dl
  jne    L28
  movzbl 0x1(%rcx),%edx
  lea    0x1(%rcx),%rdi
  test   %dl,%dl
  jne    L18
L36:
  movb   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rax,%rcx
  movzbl 0x1(%rcx),%edx
  lea    0x1(%rcx),%rdi
  test   %dl,%dl
  jne    L18
  jmp    L36
  nopl   0x0(%rax)
L74:
  mov    %rdi,%rsi
  movb   $0x0,(%rsi)
  ret
L48:
  ret
```

assistant: ```c
char *unescapestr(char *src) {
  char *p1, *p2;
  int fl;
  if (src == NULL)
    return NULL;
  p2 = src;
  p1 = p2;
  fl = 0;
  while (*p2) {
    if (*p2 == '\\' && !fl) {
      fl = 1;
      p2++;
    } else {
      *p1 = *p2;
      p1++;
      p2++;
      fl = 0;
    }
  }
  *p1 = 0;
  return src;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<div_with_reminder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
uint64_t div_with_reminder(uint64_t dividend, uint32_t divisor, uint32_t *remainder) {
  dividend |= ((uint64_t)*remainder) << 32;
  *remainder = dividend % divisor;
  return dividend / divisor;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<div_with_reminder>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rcx
  cltd
  idiv   %esi
  mov    %edx,(%rcx)
  ret
```

assistant: ```c
uint64_t div_with_reminder(uint64_t dividend, uint32_t divisor, uint32_t *remainder) {
  dividend |= ((uint64_t)*remainder) << 32;
  *remainder = dividend % divisor;
  return dividend / divisor;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<div_with_reminder>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%r8
  cltd
  idiv   %esi
  mov    %edx,(%r8)
  ret
```

assistant: ```c
uint64_t div_with_reminder(uint64_t dividend, uint32_t divisor, uint32_t *remainder) {
  dividend |= ((uint64_t)*remainder) << 32;
  *remainder = dividend % divisor;
  return dividend / divisor;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<div_with_reminder>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%r8
  cltd
  idiv   %esi
  mov    %edx,(%r8)
  ret
```

assistant: ```c
uint64_t div_with_reminder(uint64_t dividend, uint32_t divisor, uint32_t *remainder) {
  dividend |= ((uint64_t)*remainder) << 32;
  *remainder = dividend % divisor;
  return dividend / divisor;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<my_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x20(%rbp),%r13
  mov    -0x28(%rbp),%r12
  mov    -0x30(%rbp),%rbx
  test   %rbx,%rbx
  je     L57
  sub    $0x1,%rbx
  test   %rbx,%rbx
  je     L57
L68:
  mov    %r12,%rdx
  lea    0x1(%rdx),%r12
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L3
  sub    $0x1,%rbx
  test   %rbx,%rbx
  jne    L68
  jmp    L57
L3:
  nop
L57:
  test   %rbx,%rbx
  jne    L12
  cmpq   $0x0,-0x30(%rbp)
  je     L46
  movb   $0x0,0x0(%r13)
L46:
  nop
L77:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
L12:
  mov    %r12,%rax
  sub    -0x28(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
size_t my_strlcpy(char *dst, const char *src, size_t siz) {
  register char *d = dst;
  register const char *s = src;
  register size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L38
  sub    $0x1,%rdx
  je     L53
  mov    %rsi,%rax
L8:
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdi)
  test   %cl,%cl
  je     L32
  sub    $0x1,%rdx
  jne    L8
  jmp    L55
L38:
  mov    %rsi,%rax
L5:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L5
L74:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L53:
  mov    %rsi,%rax
L55:
  movb   $0x0,(%rdi)
  jmp    L5
L32:
  test   %rdx,%rdx
  jne    L74
  jmp    L55
```

assistant: ```c
size_t my_strlcpy(char *dst, const char *src, size_t siz) {
  register char *d = dst;
  register const char *s = src;
  register size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L37
  cmp    $0x1,%rdx
  je     L41
  mov    %rdi,%rcx
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  je     L31
L55:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L60
L67:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   (%rax)
L31:
  mov    %rcx,%rdi
L41:
  movb   $0x0,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L37:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L67
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L37
  jmp    L67
```

assistant: ```c
size_t my_strlcpy(char *dst, const char *src, size_t siz) {
  register char *d = dst;
  register const char *s = src;
  register size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L31
  cmp    $0x1,%rdx
  je     L45
  mov    %rdi,%rcx
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L77:
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  je     L10
L33:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L77
L43:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   (%rax)
L10:
  mov    %rcx,%rdi
L45:
  movb   $0x0,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L31:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L43
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L31
  jmp    L43
```

assistant: ```c
size_t my_strlcpy(char *dst, const char *src, size_t siz) {
  register char *d = dst;
  register const char *s = src;
  register size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SLsmg_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %rdi,-0x3f8(%rbp)
  mov    %esi,-0x3fc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3fc(%rbp),%edx
  mov    -0x3f8(%rbp),%rcx
  lea    -0x3f0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <SLsmg_write_string@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void SLsmg_vprintf(char *fmt, va_list ap) {
  char p[1000];
  (void)vsprintf(p, fmt, ap);
  SLsmg_write_string(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SLsmg_vprintf>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <vsprintf@plt>
  mov    %rbx,%rdi
  call   <SLsmg_write_string@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SLsmg_vprintf(char *fmt, va_list ap) {
  char p[1000];
  (void)vsprintf(p, fmt, ap);
  SLsmg_write_string(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SLsmg_vprintf>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <vsprintf@plt>
  mov    %rbp,%rdi
  call   <SLsmg_write_string@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x3f0,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SLsmg_vprintf(char *fmt, va_list ap) {
  char p[1000];
  (void)vsprintf(p, fmt, ap);
  SLsmg_write_string(p);
}
```