ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_putendl_fd>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  mov    $0x1,%edx
  pop    %rbp
  lea    D5(%rip),%rsi
  pop    %r12
  jmp    1060 <write@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string

tool: D5: 


assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  if (!s)
    return;
  write(fd, s, ft_strlen(s));
  write(fd, "\n", 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getcwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L106
  cmpq   $0x0,-0x28(%rbp)
  je     L95
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0x0,%eax
  jmp    L35
L95:
  mov    $0x0,%eax
  call   <getpagesize@plt>
  mov    %eax,%edx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <MAX@plt>
  mov    %rax,-0x8(%rbp)
L106:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L86
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L86
  mov    $0x0,%eax
  jmp    L35
L86:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__syscall_getcwd@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L41
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L41
  cmpq   $0x0,-0x28(%rbp)
  jne    L116
  cmpq   $0x0,-0x30(%rbp)
  jne    L116
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x28(%rbp)
L116:
  cmpq   $0x0,-0x28(%rbp)
  jne    L104
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L104:
  mov    -0x28(%rbp),%rax
  jmp    L35
L41:
  cmpq   $0x0,-0x28(%rbp)
  jne    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L0:
  mov    $0x0,%eax
L35:
  leave
  ret
```

assistant: ```c
char *getcwd(char *buf, size_t size) {
  int ret;
  char *path;
  size_t alloc_size = size;
  if (size == 0) {
    if (buf != NULL) {
      __set_errno(EINVAL);
      return NULL;
    }
    alloc_size = MAX(PATH_MAX, getpagesize());
  }
  path = buf;
  if (buf == NULL) {
    path = malloc(alloc_size);
    if (path == NULL)
      return NULL;
  }
  ret = __syscall_getcwd(path, alloc_size);
  if (ret > 0 && path[0] == '/') {
    if (buf == NULL && size == 0)
      buf = realloc(path, ret);
    if (buf == NULL)
      buf = path;
    return buf;
  }
  if (buf == NULL)
    free(path);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getcwd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  jne    L146
  test   %rdi,%rdi
  jne    L78
  mov    $0x0,%eax
  call   <getpagesize@plt>
  mov    %eax,%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <MAX@plt>
  mov    %rax,%r13
L38:
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L25
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <__syscall_getcwd@plt>
  test   %eax,%eax
  jle    L91
  cmpb   $0x2f,(%r12)
  jne    L16
  or     %rbx,%rbp
  jne    L103
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %r12,%rbx
  jmp    L76
L78:
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0x0,%eax
  jmp    L25
L146:
  test   %rdi,%rdi
  je     L3
  call   <__syscall_getcwd@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jle    L25
  cmpb   $0x2f,(%rbx)
  je     L151
  mov    %rbx,%r12
L16:
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L91
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    %rsi,%r13
  jmp    L38
L103:
  mov    %rbx,%rax
  mov    %r12,%rbx
  jmp    L76
L151:
  mov    %rbx,%rax
L76:
  test   %rax,%rax
  cmove  %rbx,%rax
  jmp    L25
L91:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L25
```

assistant: ```c
char *getcwd(char *buf, size_t size) {
  int ret;
  char *path;
  size_t alloc_size = size;
  if (size == 0) {
    if (buf != NULL) {
      __set_errno(EINVAL);
      return NULL;
    }
    alloc_size = MAX(PATH_MAX, getpagesize());
  }
  path = buf;
  if (buf == NULL) {
    path = malloc(alloc_size);
    if (path == NULL)
      return NULL;
  }
  ret = __syscall_getcwd(path, alloc_size);
  if (ret > 0 && path[0] == '/') {
    if (buf == NULL && size == 0)
      buf = realloc(path, ret);
    if (buf == NULL)
      buf = path;
    return buf;
  }
  if (buf == NULL)
    free(path);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getcwd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  jne    L28
  test   %rdi,%rdi
  jne    L14
  xor    %eax,%eax
  call   <getpagesize@plt>
  mov    %eax,%esi
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <MAX@plt>
  mov    %rax,%r13
L115:
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L114
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <__syscall_getcwd@plt>
  test   %eax,%eax
  jle    L56
  cmpb   $0x2f,(%r12)
  je     L85
L56:
  mov    %r12,%rdi
  call   <free@plt>
  nopw   0x0(%rax,%rax,1)
L114:
  xor    %r12d,%r12d
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L28:
  test   %rdi,%rdi
  je     L4
  call   <__syscall_getcwd@plt>
  test   %eax,%eax
  jle    L114
  cmpb   $0x2f,(%rbx)
  jne    L114
  mov    %rbx,%r12
  jmp    L12
L14:
  mov    D16(%rip),%rax
  xor    %r12d,%r12d
  mov    (%rax),%edi
  call   <__set_errno@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L85:
  test   %rbp,%rbp
  jne    L12
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <realloc@plt>
  test   %rax,%rax
  cmovne %rax,%r12
  jmp    L12
L4:
  mov    %rsi,%r13
  jmp    L115
```

assistant: ```c
char *getcwd(char *buf, size_t size) {
  int ret;
  char *path;
  size_t alloc_size = size;
  if (size == 0) {
    if (buf != NULL) {
      __set_errno(EINVAL);
      return NULL;
    }
    alloc_size = MAX(PATH_MAX, getpagesize());
  }
  path = buf;
  if (buf == NULL) {
    path = malloc(alloc_size);
    if (path == NULL)
      return NULL;
  }
  ret = __syscall_getcwd(path, alloc_size);
  if (ret > 0 && path[0] == '/') {
    if (buf == NULL && size == 0)
      buf = realloc(path, ret);
    if (buf == NULL)
      buf = path;
    return buf;
  }
  if (buf == NULL)
    free(path);
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getcwd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  jne    L36
  test   %rdi,%rdi
  jne    L40
  xor    %eax,%eax
  call   <getpagesize@plt>
  mov    %eax,%esi
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <MAX@plt>
  mov    %rax,%r13
L2:
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L51
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <__syscall_getcwd@plt>
  test   %eax,%eax
  jle    L20
  cmpb   $0x2f,(%r12)
  je     L17
L20:
  mov    %r12,%rdi
  call   <free@plt>
  nopw   0x0(%rax,%rax,1)
L51:
  xor    %r12d,%r12d
L33:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L36:
  test   %rdi,%rdi
  je     L48
  call   <__syscall_getcwd@plt>
  test   %eax,%eax
  jle    L51
  cmpb   $0x2f,(%rbx)
  jne    L51
  mov    %rbx,%r12
  jmp    L33
L40:
  mov    D13(%rip),%rax
  xor    %r12d,%r12d
  mov    (%rax),%edi
  call   <__set_errno@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L17:
  test   %rbp,%rbp
  jne    L33
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <realloc@plt>
  test   %rax,%rax
  cmovne %rax,%r12
  jmp    L33
L48:
  mov    %rsi,%r13
  jmp    L2
```

assistant: ```c
char *getcwd(char *buf, size_t size) {
  int ret;
  char *path;
  size_t alloc_size = size;
  if (size == 0) {
    if (buf != NULL) {
      __set_errno(EINVAL);
      return NULL;
    }
    alloc_size = MAX(PATH_MAX, getpagesize());
  }
  path = buf;
  if (buf == NULL) {
    path = malloc(alloc_size);
    if (path == NULL)
      return NULL;
  }
  ret = __syscall_getcwd(path, alloc_size);
  if (ret > 0 && path[0] == '/') {
    if (buf == NULL && size == 0)
      buf = realloc(path, ret);
    if (buf == NULL)
      buf = path;
    return buf;
  }
  if (buf == NULL)
    free(path);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <inorderTraversal@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main() {
  int count = 0;
  inorderTraversal(NULL, &count);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edi
  call   <inorderTraversal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int count = 0;
  inorderTraversal(NULL, &count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <inorderTraversal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int count = 0;
  inorderTraversal(NULL, &count);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <inorderTraversal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int count = 0;
  inorderTraversal(NULL, &count);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  subl   $0x1,-0x74(%rbp)
  jmp    L25
L6:
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  subl   $0x1,-0x74(%rbp)
L25:
  cmpl   $0x0,-0x74(%rbp)
  jns    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: %[^
]s

assistant: ```c
int main() {
  char text[100];
  int l;
  scanf("%[^\n]s", text);
  l = strlen(text);
  for (l--; l >= 0; l--) {
    printf("%c", text[l]);
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L23
  movslq %eax,%rbx
  mov    %rsp,%rbp
L22:
  movsbl (%rbx,%rbp,1),%edi
  call   <putchar@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L22
L23:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: %[^
]s

assistant: ```c
int main() {
  char text[100];
  int l;
  scanf("%[^\n]s", text);
  l = strlen(text);
  for (l--; l >= 0; l--) {
    printf("%c", text[l]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L18
  movslq %eax,%rbx
  nopl   0x0(%rax)
L24:
  movsbl 0x0(%rbp,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
  test   %ebx,%ebx
  jns    L24
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: %[^
]s

assistant: ```c
int main() {
  char text[100];
  int l;
  scanf("%[^\n]s", text);
  l = strlen(text);
  for (l--; l >= 0; l--) {
    printf("%c", text[l]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L25
  movslq %eax,%rbx
  nopl   0x0(%rax)
L15:
  movsbl 0x0(%rbp,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
  test   %ebx,%ebx
  jns    L15
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %[^
]s

assistant: ```c
int main() {
  char text[100];
  int l;
  scanf("%[^\n]s", text);
  l = strlen(text);
  for (l--; l >= 0; l--) {
    printf("%c", text[l]);
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NumTypeToNumBytesAndFormat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  and    $0xfffffffe,%eax
  cmp    $0x60,%eax
  je     L148
  cmp    $0x60,%eax
  jg     L168
  cmp    $0x50,%eax
  je     L44
  cmp    $0x50,%eax
  jg     L168
  cmp    $0x20,%eax
  jg     L119
  test   %eax,%eax
  js     L168
  cmp    $0x20,%eax
  ja     L168
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D13(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D13(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L119:
  cmp    $0x48,%eax
  je     L155
  jmp    L168
  mov    -0x20(%rbp),%rax
  movl   $0x8,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x3,(%rax)
  jmp    L59
  mov    -0x20(%rbp),%rax
  movl   $0x4,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x3,(%rax)
  jmp    L59
  mov    -0x20(%rbp),%rax
  movl   $0x4,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L59
  mov    -0x20(%rbp),%rax
  movl   $0x2,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L59
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L59
L148:
  mov    -0x20(%rbp),%rax
  movl   $0x4,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x2,(%rax)
  jmp    L59
L44:
  mov    -0x20(%rbp),%rax
  movl   $0x2,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x2,(%rax)
  jmp    L59
L155:
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x2,(%rax)
  jmp    L59
  movl   $0x176,-0x4(%rbp)
  jmp    L59
L168:
  movl   $0x11,-0x4(%rbp)
  nop
L59:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int NumTypeToNumBytesAndFormat(int numType, int *numBytesPerValuePtr, int *dataFormatPtr, int *isComplexPtr) {
  int err = 0;
  *isComplexPtr = numType & 1;
  switch (numType & ~1) {
  case 4:
    *numBytesPerValuePtr = 8;
    *dataFormatPtr = 3;
    break;
  case 2:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 3;
    break;
  case 0x20:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 1;
    break;
  case 0x10:
    *numBytesPerValuePtr = 2;
    *dataFormatPtr = 1;
    break;
  case 8:
    *numBytesPerValuePtr = 1;
    *dataFormatPtr = 1;
    break;
  case 0x20 | 0x40:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 2;
    break;
  case 0x10 | 0x40:
    *numBytesPerValuePtr = 2;
    *dataFormatPtr = 2;
    break;
  case 8 | 0x40:
    *numBytesPerValuePtr = 1;
    *dataFormatPtr = 2;
    break;
  case 0:
    err = 374;
    break;
  default:
    err = 17;
    break;
  }
  return err;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<NumTypeToNumBytesAndFormat>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  mov    %eax,(%rcx)
  and    $0xfffffffe,%edi
  cmp    $0x20,%edi
  jg     L1
  mov    $0x11,%eax
  test   %edi,%edi
  js     L44
  cmp    $0x20,%edi
  ja     L48
  mov    %edi,%edi
  lea    D0(%rip),%rcx
  movslq (%rcx,%rdi,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
L48:
  mov    $0x11,%eax
  ret
L1:
  cmp    $0x50,%edi
  je     L29
  cmp    $0x60,%edi
  jne    L42
  movl   $0x4,(%rsi)
  movl   $0x2,(%rdx)
  mov    $0x0,%eax
  ret
L42:
  cmp    $0x48,%edi
  jne    L43
  movl   $0x1,(%rsi)
  movl   $0x2,(%rdx)
  mov    $0x0,%eax
  ret
L43:
  mov    $0x11,%eax
  ret
  movl   $0x8,(%rsi)
  movl   $0x3,(%rdx)
  mov    $0x0,%eax
  ret
  movl   $0x4,(%rsi)
  movl   $0x3,(%rdx)
  mov    $0x0,%eax
  ret
  movl   $0x4,(%rsi)
  movl   $0x1,(%rdx)
  mov    $0x0,%eax
  ret
  movl   $0x2,(%rsi)
  movl   $0x1,(%rdx)
  mov    $0x0,%eax
  ret
  movl   $0x1,(%rsi)
  movl   $0x1,(%rdx)
  mov    $0x0,%eax
  ret
L29:
  movl   $0x2,(%rsi)
  movl   $0x2,(%rdx)
  mov    $0x0,%eax
  ret
  mov    $0x176,%eax
L44:
  ret
```

assistant: ```c
int NumTypeToNumBytesAndFormat(int numType, int *numBytesPerValuePtr, int *dataFormatPtr, int *isComplexPtr) {
  int err = 0;
  *isComplexPtr = numType & 1;
  switch (numType & ~1) {
  case 4:
    *numBytesPerValuePtr = 8;
    *dataFormatPtr = 3;
    break;
  case 2:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 3;
    break;
  case 0x20:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 1;
    break;
  case 0x10:
    *numBytesPerValuePtr = 2;
    *dataFormatPtr = 1;
    break;
  case 8:
    *numBytesPerValuePtr = 1;
    *dataFormatPtr = 1;
    break;
  case 0x20 | 0x40:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 2;
    break;
  case 0x10 | 0x40:
    *numBytesPerValuePtr = 2;
    *dataFormatPtr = 2;
    break;
  case 8 | 0x40:
    *numBytesPerValuePtr = 1;
    *dataFormatPtr = 2;
    break;
  case 0:
    err = 374;
    break;
  default:
    err = 17;
    break;
  }
  return err;
}
```
user: Translate the below assembly code into C programming language:

```asm
<NumTypeToNumBytesAndFormat>:
  endbr64
  mov    %edi,%eax
  and    $0xfffffffe,%edi
  and    $0x1,%eax
  mov    %eax,(%rcx)
  cmp    $0x20,%edi
  jg     L33
  mov    $0x11,%eax
  test   %edi,%edi
  js     L12
  cmp    $0x20,%edi
  ja     L26
  lea    D5(%rip),%rcx
  movslq (%rcx,%rdi,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0x11,%eax
  ret
  xchg   %ax,%ax
  mov    $0x176,%eax
L12:
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  cmp    $0x50,%edi
  je     L36
  cmp    $0x60,%edi
  jne    L39
  movl   $0x4,(%rsi)
  xor    %eax,%eax
  movl   $0x2,(%rdx)
  ret
L39:
  cmp    $0x48,%edi
  jne    L26
  movl   $0x1,(%rsi)
  xor    %eax,%eax
  movl   $0x2,(%rdx)
  ret
  nopl   (%rax)
  movl   $0x4,(%rsi)
  xor    %eax,%eax
  movl   $0x1,(%rdx)
  ret
  nop
  movl   $0x4,(%rsi)
  xor    %eax,%eax
  movl   $0x3,(%rdx)
  ret
  nop
  movl   $0x8,(%rsi)
  xor    %eax,%eax
  movl   $0x3,(%rdx)
  ret
  nop
  movl   $0x1,(%rsi)
  xor    %eax,%eax
  movl   $0x1,(%rdx)
  ret
  nop
  movl   $0x2,(%rsi)
  xor    %eax,%eax
  movl   $0x1,(%rdx)
  ret
  nop
L36:
  movl   $0x2,(%rsi)
  xor    %eax,%eax
  movl   $0x2,(%rdx)
  ret
```

assistant: ```c
int NumTypeToNumBytesAndFormat(int numType, int *numBytesPerValuePtr, int *dataFormatPtr, int *isComplexPtr) {
  int err = 0;
  *isComplexPtr = numType & 1;
  switch (numType & ~1) {
  case 4:
    *numBytesPerValuePtr = 8;
    *dataFormatPtr = 3;
    break;
  case 2:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 3;
    break;
  case 0x20:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 1;
    break;
  case 0x10:
    *numBytesPerValuePtr = 2;
    *dataFormatPtr = 1;
    break;
  case 8:
    *numBytesPerValuePtr = 1;
    *dataFormatPtr = 1;
    break;
  case 0x20 | 0x40:
    *numBytesPerValuePtr = 4;
    *dataFormatPtr = 2;
    break;
  case 0x10 | 0x40:
    *numBytesPerValuePtr = 2;
    *dataFormatPtr = 2;
    break;
  case 8 | 0x40:
    *numBytesPerValuePtr = 1;
    *dataFormatPtr = 2;
    break;
  case 0:
    err = 374;
    break;
  default:
    err = 17;
    break;
  }
  return err;
}
```