ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    0x78(%rsp),%r12d
  mov    0x70(%rsp),%r15d
  mov    %r12d,%esi
  mov    %r12d,%eax
  imul   %r15d,%esi
  imul   %r13d,%eax
  imul   %edx,%esi
  add    %edi,%eax
  add    %esi,%eax
  cltq
  lea    (%r8,%rax,4),%rax
  mov    (%rax),%r10d
  test   %r10d,%r10d
  je     L29
  xor    %r10d,%r10d
L71:
  add    $0x38,%rsp
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  sub    $0x1,%r13d
  mov    %r12d,%r10d
  movl   $0xff,(%rax)
  mov    %edi,%ebp
  imul   %r13d,%r10d
  lea    -0x1(%rdi),%edi
  lea    0x2(%rbp),%r11d
  add    %esi,%r10d
L15:
  lea    (%rdi,%r10,1),%r14d
  mov    %r13d,%esi
  xor    %ebx,%ebx
L76:
  lea    -0x1(%rbx),%eax
  or     %ebp,%eax
  je     L25
  test   %edi,%edi
  jle    L124
  cmp    %edi,%r12d
  jg     L56
L124:
  cmp    $0x2,%ebx
  jne    L25
  add    $0x1,%edi
  cmp    %r11d,%edi
  jne    L15
L20:
  mov    $0x1,%r10d
  jmp    L71
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%ebx
  add    $0x1,%esi
  add    %r12d,%r14d
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L56:
  test   %esi,%esi
  jle    L124
  cmp    %r15d,%esi
  jge    L124
  movslq %r14d,%rax
  cmp    %ecx,(%r9,%rax,4)
  jl     L124
  mov    %r10d,0x2c(%rsp)
  sub    $0x8,%rsp
  mov    %r11d,0x30(%rsp)
  mov    0x88(%rsp),%eax
  push   %rax
  push   %r12
  push   %r15
  mov    %r9,0x40(%rsp)
  mov    %r8,0x38(%rsp)
  mov    %ecx,0x34(%rsp)
  mov    %edx,0x30(%rsp)
  mov    %esi,0x2c(%rsp)
  mov    %edi,0x28(%rsp)
  call   <trace>
  add    $0x20,%rsp
  mov    0x8(%rsp),%edi
  mov    0xc(%rsp),%esi
  test   %eax,%eax
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  mov    0x18(%rsp),%r8
  mov    0x20(%rsp),%r9
  mov    0x28(%rsp),%r11d
  mov    0x2c(%rsp),%r10d
  je     L124
  jmp    L20
```

assistant: ```c
int trace(int i, int j, int d, int low, int *image, int *mag, int width, int height, int depth) {
  int n, m;
  char flag = 0;
  if (image[((height) * (j) + (i) + (width) * (height) * (d))] == 0) {
    image[((height) * (j) + (i) + (width) * (height) * (d))] = 255;
    flag = 0;
    for (n = -1; n <= 1; n++) {
      for (m = -1; m <= 1; m++) {
        if (i == 0 && m == 0)
          continue;
        if (i + n > 0 && i + n < height && j + m > 0 && j + m < width && mag[((height) * (j + m) + (i + n) + (width) * (height) * (d))] >= low) {
          if (trace(i + n, j + m, d, low, image, mag, width, height, depth)) {
            flag = 1;
            break;
          }
        }
      }
      if (flag)
        break;
    }
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string

tool: D1: --ip IPv6 --iface IFACE --server-id SERVER_ID --client-id CLIENT_ID --iaid IAID [--dry-run] | --help

tool: D18: Usage: %s %s


assistant: ```c
void usage(const char *arg, FILE *stream) {
  const char *usage_string = "--ip IPv6 --iface IFACE --server-id SERVER_ID --client-id CLIENT_ID --iaid IAID [--dry-run] | --help";
  fprintf(stream, "Usage: %s %s\n", arg, usage_string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rdi
  lea    D14(%rip),%rcx
  lea    D8(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
data_type: string
name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D14: --ip IPv6 --iface IFACE --server-id SERVER_ID --client-id CLIENT_ID --iaid IAID [--dry-run] | --help

tool: D8: Usage: %s %s


assistant: ```c
void usage(const char *arg, FILE *stream) {
  const char *usage_string = "--ip IPv6 --iface IFACE --server-id SERVER_ID --client-id CLIENT_ID --iaid IAID [--dry-run] | --help";
  fprintf(stream, "Usage: %s %s\n", arg, usage_string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  mov    %rdi,%rdx
  lea    D5(%rip),%rcx
  mov    %rsi,%rdi
  lea    D7(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D7
data_type: string

tool: D5: --ip IPv6 --iface IFACE --server-id SERVER_ID --client-id CLIENT_ID --iaid IAID [--dry-run] | --help

tool: D7: Usage: %s %s


assistant: ```c
void usage(const char *arg, FILE *stream) {
  const char *usage_string = "--ip IPv6 --iface IFACE --server-id SERVER_ID --client-id CLIENT_ID --iaid IAID [--dry-run] | --help";
  fprintf(stream, "Usage: %s %s\n", arg, usage_string);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  mov    %rdi,%rdx
  lea    D19(%rip),%rcx
  mov    %rsi,%rdi
  lea    D16(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
datatype: string
name: extract_symbolic_data
arguments: data_label: D16
datatype: string

tool: D19: --ip IPv6 --iface IFACE --server-id SERVER_ID --client-id CLIENT_ID --iaid IAID [--dry-run] | --help

tool: D16: Usage: %s %s


assistant: ```c
void usage(const char *arg, FILE *stream) {
  const char *usage_string = "--ip IPv6 --iface IFACE --server-id SERVER_ID --client-id CLIENT_ID --iaid IAID [--dry-run] | --help";
  fprintf(stream, "Usage: %s %s\n", arg, usage_string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__GetStructureFieldIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
size_t __GetStructureFieldIndex(const char *structure_name, const char *field_name) {
  (void)structure_name;
  (void)field_name;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__GetStructureFieldIndex>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t __GetStructureFieldIndex(const char *structure_name, const char *field_name) {
  (void)structure_name;
  (void)field_name;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__GetStructureFieldIndex>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t __GetStructureFieldIndex(const char *structure_name, const char *field_name) {
  (void)structure_name;
  (void)field_name;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__GetStructureFieldIndex>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t __GetStructureFieldIndex(const char *structure_name, const char *field_name) {
  (void)structure_name;
  (void)field_name;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inp_printkeys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  addl   $0x6,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <setcurs@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L33:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <inp_keypr@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getkeyfor_str@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printstr@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x6,%eax
  sub    %rdx,%rax
  mov    %rax,%rsi
  mov    $0x20,%edi
  call   <putnchars@plt>
  cmpl   $0x5,-0xc(%rbp)
  jne    L26
  addl   $0x11,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <setcurs@plt>
  jmp    L0
L26:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <newln@plt>
L0:
  addl   $0x1,-0xc(%rbp)
L4:
  cmpl   $0xa,-0xc(%rbp)
  jle    L33
  nop
  nop
  leave
  ret
```

assistant: ```c
void inp_printkeys(int dev, int x, int y) {
  const char *k;
  int i;
  x += 6;
  setcurs(x, y);
  for (i = 0; i < 11; i++) {
    k = getkeyfor_str(dev, inp_keypr(i));
    printstr(k);
    putnchars(' ', 6 - strlen(k));
    if (i == 5) {
      x += 17;
      setcurs(x, y);
    } else
      newln(x);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<inp_printkeys>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %edx,0xc(%rsp)
  lea    0x6(%rsi),%r13d
  mov    %edx,%esi
  mov    %r13d,%edi
  call   <setcurs@plt>
  mov    $0x1,%ebp
  mov    $0x6,%r15d
  jmp    L18
L1:
  add    $0x11,%r13d
  mov    0xc(%rsp),%esi
  mov    %r13d,%edi
  call   <setcurs@plt>
L14:
  add    $0x1,%ebp
L18:
  lea    -0x1(%rbp),%r12d
  mov    %r12d,%edi
  call   <inp_keypr@plt>
  mov    %eax,%esi
  mov    %r14d,%edi
  call   <getkeyfor_str@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <printstr@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r15,%rsi
  sub    %rax,%rsi
  mov    $0x20,%edi
  call   <putnchars@plt>
  cmp    $0x5,%r12d
  je     L1
  mov    %r13d,%edi
  call   <newln@plt>
  cmp    $0xa,%ebp
  jle    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void inp_printkeys(int dev, int x, int y) {
  const char *k;
  int i;
  x += 6;
  setcurs(x, y);
  for (i = 0; i < 11; i++) {
    k = getkeyfor_str(dev, inp_keypr(i));
    printstr(k);
    putnchars(' ', 6 - strlen(k));
    if (i == 5) {
      x += 17;
      setcurs(x, y);
    } else
      newln(x);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inp_printkeys>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    $0x6,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  lea    0x6(%rsi),%ebx
  mov    %edx,%esi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <setcurs@plt>
  nopl   (%rax)
L18:
  mov    %r15d,%edi
  add    $0x1,%r15d
  call   <inp_keypr@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <getkeyfor_str@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <printstr@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    $0x20,%edi
  sub    %rax,%rsi
  call   <putnchars@plt>
  cmp    $0x6,%r15d
  je     L27
  mov    %ebx,%edi
  call   <newln@plt>
  cmp    $0xb,%r15d
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x11,%ebx
  mov    %r14d,%esi
  mov    %ebx,%edi
  call   <setcurs@plt>
  jmp    L18
```

assistant: ```c
void inp_printkeys(int dev, int x, int y) {
  const char *k;
  int i;
  x += 6;
  setcurs(x, y);
  for (i = 0; i < 11; i++) {
    k = getkeyfor_str(dev, inp_keypr(i));
    printstr(k);
    putnchars(' ', 6 - strlen(k));
    if (i == 5) {
      x += 17;
      setcurs(x, y);
    } else
      newln(x);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inp_printkeys>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    $0x6,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  lea    0x6(%rsi),%ebx
  mov    %edx,%esi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <setcurs@plt>
  nopl   (%rax)
L10:
  mov    %r15d,%edi
  add    $0x1,%r15d
  call   <inp_keypr@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <getkeyfor_str@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <printstr@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    $0x20,%edi
  sub    %rax,%rsi
  call   <putnchars@plt>
  cmp    $0x6,%r15d
  je     L2
  mov    %ebx,%edi
  call   <newln@plt>
  cmp    $0xb,%r15d
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x11,%ebx
  mov    %r14d,%esi
  mov    %ebx,%edi
  call   <setcurs@plt>
  jmp    L10
```

assistant: ```c
void inp_printkeys(int dev, int x, int y) {
  const char *k;
  int i;
  x += 6;
  setcurs(x, y);
  for (i = 0; i < 11; i++) {
    k = getkeyfor_str(dev, inp_keypr(i));
    printstr(k);
    putnchars(' ', 6 - strlen(k));
    if (i == 5) {
      x += 17;
      setcurs(x, y);
    } else
      newln(x);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    (%rsp),%ecx
  test   %ecx,%ecx
  jle    L100
  mov    %rax,%rdx
  mov    $0x0,%eax
L75:
  add    $0x1,%eax
  mov    %eax,(%rdx)
  mov    (%rsp),%ecx
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jl     L75
L100:
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%ebp
  pxor   %xmm2,%xmm2
  cvtsi2ss %edx,%xmm2
  movd   %xmm2,%r12d
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  movaps %xmm2,%xmm0
  divss  %xmm1,%xmm0
  call   <round@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rsp),%xmm1
  movd   %r12d,%xmm0
  divss  %xmm1,%xmm0
  call   <abs@plt>
  test   %ebp,%ebp
  jg     L16
L27:
  cmpl   $0x0,(%rsp)
  jle    L35
  mov    $0x0,%ebp
  lea    D16(%rip),%r12
L50:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,(%rsp)
  jg     L50
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebp,(%rsp)
  jle    L27
  mov    $0x0,%edi
L66:
  mov    (%rbx),%r8d
  mov    (%rsp),%ecx
  cmp    $0x1,%ecx
  jle    L105
  lea    0x4(%rbx),%rax
  mov    $0x0,%edx
L86:
  mov    (%rax),%ecx
  mov    %ecx,-0x4(%rax)
  add    $0x1,%edx
  mov    (%rsp),%ecx
  add    $0x4,%rax
  lea    -0x1(%rcx),%esi
  cmp    %edx,%esi
  jg     L86
L105:
  movslq %ecx,%rcx
  mov    %r8d,-0x4(%rbx,%rcx,4)
  add    $0x1,%edi
  mov    (%rsp),%eax
  sub    %ebp,%eax
  cmp    %edi,%eax
  jg     L66
  jmp    L27
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D22
datatype: string
name: unpack_data
arguments: label: D16
datatype: string
name: unpack_data
arguments: label: D19
datatype: string

tool: D22: %d%d

tool: D16: %d 

tool: D19: Reverse Loop

assistant: ```c
int main() {
  int n, k, kactual, q, i, j, g, temp, loc;
  int *arr = NULL;
  int absolute = 0;
  float rounder = 0.0f;
  scanf("%d%d", &n, &k);
  arr = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++) {
    arr[i] = i + 1;
  }
  kactual = k % n;
  rounder = round((float)kactual / (float)n);
  absolute = abs((float)kactual / (float)n);
  if (kactual > 0) {
    printf("Reverse Loop");
    for (i = 0; i < (n - kactual); i++) {
      temp = arr[0];
      for (j = 0; j < n - 1; j++) {
        arr[j] = arr[j + 1];
      }
      arr[n - 1] = temp;
    }
  }
  for (i = 0; i < n; i++) {
    printf("%d ", arr[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%ecx
  mov    %rax,%rbp
  test   %ecx,%ecx
  jle    L49
  mov    %rax,%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L106:
  add    $0x1,%eax
  add    $0x4,%rdx
  mov    %eax,-0x4(%rdx)
  mov    0x10(%rsp),%ecx
  cmp    %ecx,%eax
  jl     L106
L49:
  mov    0x14(%rsp),%eax
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %ecx,%xmm2
  cltd
  idiv   %ecx
  cvtsi2ss %edx,%xmm1
  mov    %edx,%ebx
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  divss  %xmm2,%xmm0
  call   <round@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm0
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  call   <abs@plt>
  test   %ebx,%ebx
  jg     L103
L51:
  mov    0x10(%rsp),%eax
  xor    %ebx,%ebx
  lea    D10(%rip),%r12
  test   %eax,%eax
  jle    L73
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L23
L73:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L103:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x10(%rsp),%rsi
  cmp    %ebx,%esi
  jle    L51
  xor    %r8d,%r8d
  nop
L84:
  mov    0x0(%rbp),%r9d
  cmp    $0x1,%esi
  jle    L4
  lea    0x4(%rbp),%rax
  xor    %ecx,%ecx
  nop
L63:
  mov    (%rax),%esi
  add    $0x1,%ecx
  add    $0x4,%rax
  mov    %esi,-0x8(%rax)
  movslq 0x10(%rsp),%rsi
  lea    -0x1(%rsi),%edi
  cmp    %ecx,%edi
  jg     L63
L4:
  mov    %r9d,-0x4(%rbp,%rsi,4)
  movslq 0x10(%rsp),%rsi
  add    $0x1,%r8d
  mov    %esi,%eax
  sub    %ebx,%eax
  cmp    %r8d,%eax
  jg     L84
  jmp    L51
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D10
type_infered: string
name: read_data
arguments: label: D13
type_infered: string

tool: D28: %d%d

tool: D10: %d 

tool: D13: Reverse Loop

assistant: ```c
int main() {
  int n, k, kactual, q, i, j, g, temp, loc;
  int *arr = NULL;
  int absolute = 0;
  float rounder = 0.0f;
  scanf("%d%d", &n, &k);
  arr = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++) {
    arr[i] = i + 1;
  }
  kactual = k % n;
  rounder = round((float)kactual / (float)n);
  absolute = abs((float)kactual / (float)n);
  if (kactual > 0) {
    printf("Reverse Loop");
    for (i = 0; i < (n - kactual); i++) {
      temp = arr[0];
      for (j = 0; j < n - 1; j++) {
        arr[j] = arr[j + 1];
      }
      arr[n - 1] = temp;
    }
  }
  for (i = 0; i < n; i++) {
    printf("%d ", arr[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%ecx
  mov    %rax,%rbp
  test   %ecx,%ecx
  jle    L43
  mov    %rax,%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x1,%eax
  add    $0x4,%rdx
  mov    %eax,-0x4(%rdx)
  mov    0x10(%rsp),%ecx
  cmp    %ecx,%eax
  jl     L24
L43:
  mov    0x14(%rsp),%eax
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %ecx,%xmm2
  cltd
  idiv   %ecx
  cvtsi2ss %edx,%xmm1
  mov    %edx,%ebx
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  divss  %xmm2,%xmm0
  call   <round@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm0
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  call   <abs@plt>
  test   %ebx,%ebx
  jg     L67
L100:
  mov    0x10(%rsp),%eax
  xor    %ebx,%ebx
  lea    D13(%rip),%r12
  test   %eax,%eax
  jle    L46
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L69
L46:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L67:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x10(%rsp),%rsi
  cmp    %ebx,%esi
  jle    L100
  xor    %r8d,%r8d
  nop
L107:
  mov    0x0(%rbp),%r9d
  cmp    $0x1,%esi
  jle    L50
  lea    0x4(%rbp),%rax
  xor    %ecx,%ecx
  nop
L38:
  mov    (%rax),%esi
  add    $0x1,%ecx
  add    $0x4,%rax
  mov    %esi,-0x8(%rax)
  movslq 0x10(%rsp),%rsi
  lea    -0x1(%rsi),%edi
  cmp    %ecx,%edi
  jg     L38
L50:
  mov    %r9d,-0x4(%rbp,%rsi,4)
  movslq 0x10(%rsp),%rsi
  add    $0x1,%r8d
  mov    %esi,%eax
  sub    %ebx,%eax
  cmp    %r8d,%eax
  jg     L107
  jmp    L100
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D24
type_infered: string

tool: D11: %d%d

tool: D13: %d 

tool: D24: Reverse Loop

assistant: ```c
int main() {
  int n, k, kactual, q, i, j, g, temp, loc;
  int *arr = NULL;
  int absolute = 0;
  float rounder = 0.0f;
  scanf("%d%d", &n, &k);
  arr = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++) {
    arr[i] = i + 1;
  }
  kactual = k % n;
  rounder = round((float)kactual / (float)n);
  absolute = abs((float)kactual / (float)n);
  if (kactual > 0) {
    printf("Reverse Loop");
    for (i = 0; i < (n - kactual); i++) {
      temp = arr[0];
      for (j = 0; j < n - 1; j++) {
        arr[j] = arr[j + 1];
      }
      arr[n - 1] = temp;
    }
  }
  for (i = 0; i < n; i++) {
    printf("%d ", arr[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__mingw_aligned_offset_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  and    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L24
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L56
L24:
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L56
L30:
  cmpq   $0x7,-0x20(%rbp)
  ja     L26
  movq   $0x8,-0x20(%rbp)
L26:
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %edx,%eax
  add    $0x8,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L60
  mov    $0x0,%eax
  jmp    L56
L60:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  lea    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  neg    %rax
  and    %rdx,%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0xfffffffffffffff8,%rax
  sub    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
L56:
  leave
  ret
```

assistant: ```c
void *__mingw_aligned_offset_malloc(size_t size, size_t alignment, size_t offset) {
  void *p0, *p;
  if ((((alignment) & ((alignment)-1)))) {
    errno = EINVAL;
    return ((void *)0);
  }
  if (size == 0)
    return ((void *)0);
  if (alignment < sizeof(void *))
    alignment = sizeof(void *);
  p0 = malloc(size + (alignment + sizeof(void *)));
  if (!p0)
    return ((void *)0);
  p = ((void *)(((((uintptr_t)(p0)) + (alignment + sizeof(void *)) + offset) & (~((uintptr_t)(alignment - 1)))) - offset));
  (*(((void **)(((uintptr_t)(p)) & (~((uintptr_t)(sizeof(void *) - 1))))) - 1)) = p0;
  return p;
}
```