ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<group_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <getgrgid@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L18
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
L18:
  leave
  ret
```

assistant: ```c
char *group_name(gid_t id) {
  struct group *gr;
  gr = getgrgid(id);
  if (!gr)
    return NULL;
  return gr->gr_name;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<group_name>:
  endbr64
  sub    $0x8,%rsp
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L0
  mov    (%rax),%rax
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *group_name(gid_t id) {
  struct group *gr;
  gr = getgrgid(id);
  if (!gr)
    return NULL;
  return gr->gr_name;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<group_name>:
  endbr64
  sub    $0x8,%rsp
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L6
  mov    (%rax),%rax
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *group_name(gid_t id) {
  struct group *gr;
  gr = getgrgid(id);
  if (!gr)
    return NULL;
  return gr->gr_name;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<group_name>:
  endbr64
  sub    $0x8,%rsp
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L7
  mov    (%rax),%rax
L7:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *group_name(gid_t id) {
  struct group *gr;
  gr = getgrgid(id);
  if (!gr)
    return NULL;
  return gr->gr_name;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <preencherCache@plt>
  jmp    L12
L23:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  lea    -0x1a4(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1a4(%rbp),%eax
  test   %eax,%eax
  jg     L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D15
type: string

tool: D7: %d


tool: D15: %d

assistant: ```c
int main(void) {
  int quadrados, cache[100 + 1];
  preencherCache(cache, 100);
  while (scanf("%d", &quadrados), quadrados > 0) {
    printf("%d\n", cache[quadrados]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x64,%esi
  call   <preencherCache@plt>
  lea    0xc(%rsp),%rbp
  lea    D3(%rip),%rbx
  lea    D0(%rip),%r12
  jmp    L24
L4:
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
L24:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jg     L4
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D0
type: string

tool: D3: %d

tool: D0: %d


assistant: ```c
int main(void) {
  int quadrados, cache[100 + 1];
  preencherCache(cache, 100);
  while (scanf("%d", &quadrados), quadrados > 0) {
    printf("%d\n", cache[quadrados]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%rbp
  call   <preencherCache@plt>
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    0x10(%rsp,%rax,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
L22:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  test   %eax,%eax
  jg     L14
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: string

tool: D5: %d


tool: D14: %d

assistant: ```c
int main(void) {
  int quadrados, cache[100 + 1];
  preencherCache(cache, 100);
  while (scanf("%d", &quadrados), quadrados > 0) {
    printf("%d\n", cache[quadrados]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%rbp
  call   <preencherCache@plt>
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    0x10(%rsp,%rax,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
L3:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  test   %eax,%eax
  jg     L0
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D14: %d


tool: D18: %d

assistant: ```c
int main(void) {
  int quadrados, cache[100 + 1];
  preencherCache(cache, 100);
  while (scanf("%d", &quadrados), quadrados > 0) {
    printf("%d\n", cache[quadrados]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binary_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L46
L27:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L58
  mov    -0x4(%rbp),%eax
  jmp    L3
L58:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L30
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L46
L30:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L46:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L27
  mov    $0xffffffff,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int binary_search(int key, int *arr, int size) {
  int left, right, middle;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (int)(left + right) / 2;
    if (key == arr[middle])
      return (middle);
    if (key > arr[middle])
      left = middle + 1;
    else
      right = middle - 1;
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<binary_search>:
  endbr64
  sub    $0x1,%edx
  js     L13
  mov    $0x0,%r8d
  jmp    L66
L14:
  lea    -0x1(%rax),%edx
L32:
  cmp    %edx,%r8d
  jg     L61
L66:
  lea    (%r8,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rsi,%rcx,4),%ecx
  cmp    %edi,%ecx
  je     L64
  jge    L14
  lea    0x1(%rax),%r8d
  jmp    L32
L61:
  mov    $0xffffffff,%r9d
L64:
  mov    %r9d,%eax
  ret
L13:
  mov    $0xffffffff,%r9d
  jmp    L64
```

assistant: ```c
int binary_search(int key, int *arr, int size) {
  int left, right, middle;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (int)(left + right) / 2;
    if (key == arr[middle])
      return (middle);
    if (key > arr[middle])
      left = middle + 1;
    else
      right = middle - 1;
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<binary_search>:
  endbr64
  sub    $0x1,%edx
  js     L39
  xor    %ecx,%ecx
  jmp    L11
  nopl   (%rax)
L55:
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jl     L39
L11:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edi,(%rsi,%r8,4)
  je     L26
  jl     L55
  lea    -0x1(%rax),%edx
  cmp    %ecx,%edx
  jge    L11
L39:
  mov    $0xffffffff,%eax
L26:
  ret
```

assistant: ```c
int binary_search(int key, int *arr, int size) {
  int left, right, middle;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (int)(left + right) / 2;
    if (key == arr[middle])
      return (middle);
    if (key > arr[middle])
      left = middle + 1;
    else
      right = middle - 1;
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<binary_search>:
  endbr64
  sub    $0x1,%edx
  js     L23
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L30:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edi,(%rsi,%r8,4)
  je     L35
  jge    L18
  lea    0x1(%rax),%ecx
  cmp    %edx,%ecx
  jle    L30
L23:
  mov    $0xffffffff,%eax
L35:
  ret
  nopl   (%rax)
L18:
  lea    -0x1(%rax),%edx
  cmp    %ecx,%edx
  jge    L30
  mov    $0xffffffff,%eax
  jmp    L35
```

assistant: ```c
int binary_search(int key, int *arr, int size) {
  int left, right, middle;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (int)(left + right) / 2;
    if (key == arr[middle])
      return (middle);
    if (key > arr[middle])
      left = middle + 1;
    else
      right = middle - 1;
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %esi,-0x11c(%rbp)
  mov    %edx,-0x120(%rbp)
  mov    %ecx,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x11c(%rbp),%eax
  imul   -0x124(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x118(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x124(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x120(%rbp),%eax
  imul   -0x124(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x118(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x11c(%rbp),%eax
  imul   -0x124(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x118(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x124(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x120(%rbp),%eax
  imul   -0x124(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x118(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x124(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void _swap(void *a, int l, int r, int sz) {
  char t[255];
  memcpy(t, &((char *)a)[l * sz], sz);
  memcpy(&((char *)a)[l * sz], &((char *)a)[r * sz], sz);
  memcpy(&((char *)a)[r * sz], t, sz);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_swap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  imul   %ecx,%esi
  movslq %esi,%rbx
  add    %rdi,%rbx
  mov    %rsp,%r14
  mov    %ecx,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  imul   %r13d,%ebp
  movslq %ebp,%rbp
  add    %r12,%rbp
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _swap(void *a, int l, int r, int sz) {
  char t[255];
  memcpy(t, &((char *)a)[l * sz], sz);
  memcpy(&((char *)a)[l * sz], &((char *)a)[r * sz], sz);
  memcpy(&((char *)a)[r * sz], t, sz);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_swap>:
  endbr64
  push   %r14
  imul   %ecx,%esi
  push   %r13
  mov    %edx,%r13d
  mov    %ecx,%edx
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  imul   %r12d,%r13d
  movslq %esi,%rbp
  push   %rbx
  add    %rdi,%rbp
  mov    %rdi,%rbx
  mov    %rbp,%rsi
  movslq %r13d,%r13
  sub    $0x110,%rsp
  add    %rbx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _swap(void *a, int l, int r, int sz) {
  char t[255];
  memcpy(t, &((char *)a)[l * sz], sz);
  memcpy(&((char *)a)[l * sz], &((char *)a)[r * sz], sz);
  memcpy(&((char *)a)[r * sz], t, sz);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_swap>:
  endbr64
  push   %r14
  imul   %ecx,%esi
  push   %r13
  mov    %edx,%r13d
  mov    %ecx,%edx
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  imul   %r12d,%r13d
  movslq %esi,%rbp
  push   %rbx
  add    %rdi,%rbp
  mov    %rdi,%rbx
  mov    %rbp,%rsi
  movslq %r13d,%r13
  sub    $0x110,%rsp
  add    %rbx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _swap(void *a, int l, int r, int sz) {
  char t[255];
  memcpy(t, &((char *)a)[l * sz], sz);
  memcpy(&((char *)a)[l * sz], &((char *)a)[r * sz], sz);
  memcpy(&((char *)a)[r * sz], t, sz);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cipher_xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x30(%rbp)
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x38(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cipher_xor(unsigned char *data, size_t datalen, unsigned char *key, size_t keylen, unsigned char *out) {
  size_t i;
  for (i = 0; i < datalen; ++i)
    out[i] = data[i] ^ key[i % keylen];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cipher_xor>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%rdi
  mov    %rdx,%r10
  test   %rsi,%rsi
  je     L0
  mov    $0x0,%esi
L5:
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  movzbl (%r10,%rdx,1),%eax
  xor    (%r9,%rsi,1),%al
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %rsi,%rdi
  jne    L5
L0:
  ret
```

assistant: ```c
void cipher_xor(unsigned char *data, size_t datalen, unsigned char *key, size_t keylen, unsigned char *out) {
  size_t i;
  for (i = 0; i < datalen; ++i)
    out[i] = data[i] ^ key[i % keylen];
}
```
user: Translate the below assembly code into C programming language:

```asm
<cipher_xor>:
  endbr64
  mov    %rdi,%r9
  mov    %rdx,%r10
  mov    %rsi,%rdi
  test   %rsi,%rsi
  je     L15
  xor    %esi,%esi
  nopl   0x0(%rax)
L11:
  mov    %rsi,%rax
  xor    %edx,%edx
  div    %rcx
  movzbl (%r10,%rdx,1),%eax
  xor    (%r9,%rsi,1),%al
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %rsi,%rdi
  jne    L11
L15:
  ret
```

assistant: ```c
void cipher_xor(unsigned char *data, size_t datalen, unsigned char *key, size_t keylen, unsigned char *out) {
  size_t i;
  for (i = 0; i < datalen; ++i)
    out[i] = data[i] ^ key[i % keylen];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cipher_xor>:
  endbr64
  mov    %rdi,%r9
  mov    %rdx,%r10
  mov    %rsi,%rdi
  test   %rsi,%rsi
  je     L4
  xor    %esi,%esi
  nopl   0x0(%rax)
L9:
  mov    %rsi,%rax
  xor    %edx,%edx
  div    %rcx
  movzbl (%r10,%rdx,1),%eax
  xor    (%r9,%rsi,1),%al
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %rsi,%rdi
  jne    L9
L4:
  ret
```

assistant: ```c
void cipher_xor(unsigned char *data, size_t datalen, unsigned char *key, size_t keylen, unsigned char *out) {
  size_t i;
  for (i = 0; i < datalen; ++i)
    out[i] = data[i] ^ key[i % keylen];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cgc_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L7:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L6:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L7
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *cgc_memset(void *dst, int c, unsigned int n) {
  char *d = (char *)dst;
  while (n--) {
    *d++ = (char)c;
  }
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cgc_memset>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%ecx
  test   %edx,%edx
  je     L3
  mov    %ecx,%ecx
  lea    0x1(%rdi,%rcx,1),%rcx
  mov    %rdi,%rdx
L2:
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L2
L3:
  ret
```

assistant: ```c
void *cgc_memset(void *dst, int c, unsigned int n) {
  char *d = (char *)dst;
  while (n--) {
    *d++ = (char)c;
  }
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cgc_memset>:
  endbr64
  test   %edx,%edx
  je     L3
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *cgc_memset(void *dst, int c, unsigned int n) {
  char *d = (char *)dst;
  while (n--) {
    *d++ = (char)c;
  }
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cgc_memset>:
  endbr64
  test   %edx,%edx
  je     L8
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *cgc_memset(void *dst, int c, unsigned int n) {
  char *d = (char *)dst;
  while (n--) {
    *d++ = (char)c;
  }
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<udelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <usectospec@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <udelayspec@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void udelay(long long usecs) {
  struct timespec rem = {0, 0};
  usectospec(usecs, &rem);
  udelayspec(rem);
}
```
user: Translate the below assembly code into C programming language:

```asm
<udelay>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    %rsp,%rsi
  call   <usectospec@plt>
  mov    (%rsp),%rdi
  call   <udelayspec@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void udelay(long long usecs) {
  struct timespec rem = {0, 0};
  usectospec(usecs, &rem);
  udelayspec(rem);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<udelay>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <usectospec@plt>
  mov    (%rsp),%rdi
  call   <udelayspec@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void udelay(long long usecs) {
  struct timespec rem = {0, 0};
  usectospec(usecs, &rem);
  udelayspec(rem);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<udelay>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <usectospec@plt>
  mov    (%rsp),%rdi
  call   <udelayspec@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void udelay(long long usecs) {
  struct timespec rem = {0, 0};
  usectospec(usecs, &rem);
  udelayspec(rem);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mystrlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L5:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
size_t mystrlen(const char *s) {
  int i;
  i = 0;
  while (s[i] != '\0') {
    i++;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mystrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L23
  mov    $0x1,%eax
L7:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L7
L22:
  mov    %rdx,%rax
  ret
L23:
  mov    $0x0,%edx
  jmp    L22
```

assistant: ```c
size_t mystrlen(const char *s) {
  int i;
  i = 0;
  while (s[i] != '\0') {
    i++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mystrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L6
  mov    $0x1,%eax
  xchg   %ax,%ax
L1:
  mov    %rax,%r8
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L1
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t mystrlen(const char *s) {
  int i;
  i = 0;
  while (s[i] != '\0') {
    i++;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mystrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L5
  mov    $0x1,%eax
  xchg   %ax,%ax
L8:
  mov    %rax,%r8
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L8
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t mystrlen(const char *s) {
  int i;
  i = 0;
  while (s[i] != '\0') {
    i++;
  }
  return i;
}
```