ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D21(%rip),%r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L13:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L14:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L14
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L13
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D21
data_type: string
name: parse_data
arguments: data_label: D1
data_type: string
name: parse_data
arguments: data_label: D18
data_type: string

tool: D21: svariancewd

tool: D1: # c::%s:len=%d


tool: D18: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "svariancewd", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D14(%rip),%r15
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L14:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L14
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L8
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D17
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D14: svariancewd

tool: D17: # c::%s:len=%d


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "svariancewd", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<StrArrMaxLen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L35
L26:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L13
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L13:
  addq   $0x8,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
  mov    -0x8(%rbp),%eax
L35:
  leave
  ret
```

assistant: ```c
int StrArrMaxLen(char **str_arr) {
  int maxlen = 0;
  int newmax;
  if (str_arr == NULL)
    return (0);
  while (*str_arr != NULL) {
    if ((newmax = strlen(*str_arr)) > maxlen)
      maxlen = newmax;
    str_arr++;
  }
  return (maxlen);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<StrArrMaxLen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L32
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L35
  mov    $0x0,%ebp
L47:
  call   <strlen@plt>
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L47
L21:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  mov    $0x0,%ebp
  jmp    L21
L35:
  mov    $0x0,%ebp
  jmp    L21
```

assistant: ```c
int StrArrMaxLen(char **str_arr) {
  int maxlen = 0;
  int newmax;
  if (str_arr == NULL)
    return (0);
  while (*str_arr != NULL) {
    if ((newmax = strlen(*str_arr)) > maxlen)
      maxlen = newmax;
    str_arr++;
  }
  return (maxlen);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<StrArrMaxLen>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L12
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  xor    %r12d,%r12d
  test   %rdi,%rdi
  je     L15
  xchg   %ax,%ax
L28:
  call   <strlen@plt>
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L28
L15:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int StrArrMaxLen(char **str_arr) {
  int maxlen = 0;
  int newmax;
  if (str_arr == NULL)
    return (0);
  while (*str_arr != NULL) {
    if ((newmax = strlen(*str_arr)) > maxlen)
      maxlen = newmax;
    str_arr++;
  }
  return (maxlen);
}
```
user: Translate the below assembly code into C programming language:

```asm
<StrArrMaxLen>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L27
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  xor    %r12d,%r12d
  test   %rdi,%rdi
  je     L11
  xchg   %ax,%ax
L22:
  call   <strlen@plt>
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L22
L11:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int StrArrMaxLen(char **str_arr) {
  int maxlen = 0;
  int newmax;
  if (str_arr == NULL)
    return (0);
  while (*str_arr != NULL) {
    if ((newmax = strlen(*str_arr)) > maxlen)
      maxlen = newmax;
    str_arr++;
  }
  return (maxlen);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x48,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <brc2@plt>
  mov    $0x5,%edi
  call   <padding@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int cup(int pn1, int pn2) {
  brc2(pn1, pn2, 'H');
  padding(5);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x48,%edx
  call   <brc2@plt>
  mov    $0x5,%edi
  call   <padding@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cup(int pn1, int pn2) {
  brc2(pn1, pn2, 'H');
  padding(5);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x48,%edx
  call   <brc2@plt>
  mov    $0x5,%edi
  call   <padding@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cup(int pn1, int pn2) {
  brc2(pn1, pn2, 'H');
  padding(5);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<start_simulation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <init_threads@plt>
L16:
  movl   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  call   <eval@plt>
  mov    $0x0,%eax
  call   <stop_simulation@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  jmp    L16
L0:
  nop
  nop
  leave
  ret
```

assistant: ```c
void start_simulation(void) {
  int kernel_st;
  int tmp;
  {
    {
      kernel_st = 0;
      init_threads();
    }
    {
      while (1) {
      while_3_continue:;
        {
          kernel_st = 1;
          eval();
          tmp = stop_simulation();
        }
        if (tmp) {
          goto while_3_break;
        } else {
        }
      }
    while_3_break:;
    }
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<start_simulation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_threads@plt>
L3:
  mov    $0x0,%eax
  call   <eval@plt>
  mov    $0x0,%eax
  call   <stop_simulation@plt>
  test   %eax,%eax
  je     L3
  add    $0x8,%rsp
  ret
```

assistant: ```c
void start_simulation(void) {
  int kernel_st;
  int tmp;
  {
    {
      kernel_st = 0;
      init_threads();
    }
    {
      while (1) {
      while_3_continue:;
        {
          kernel_st = 1;
          eval();
          tmp = stop_simulation();
        }
        if (tmp) {
          goto while_3_break;
        } else {
        }
      }
    while_3_break:;
    }
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<start_simulation>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_threads@plt>
  nop
L8:
  xor    %eax,%eax
  call   <eval@plt>
  xor    %eax,%eax
  call   <stop_simulation@plt>
  test   %eax,%eax
  je     L8
  add    $0x8,%rsp
  ret
```

assistant: ```c
void start_simulation(void) {
  int kernel_st;
  int tmp;
  {
    {
      kernel_st = 0;
      init_threads();
    }
    {
      while (1) {
      while_3_continue:;
        {
          kernel_st = 1;
          eval();
          tmp = stop_simulation();
        }
        if (tmp) {
          goto while_3_break;
        } else {
        }
      }
    while_3_break:;
    }
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<start_simulation>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_threads@plt>
  nop
L1:
  xor    %eax,%eax
  call   <eval@plt>
  xor    %eax,%eax
  call   <stop_simulation@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  ret
```

assistant: ```c
void start_simulation(void) {
  int kernel_st;
  int tmp;
  {
    {
      kernel_st = 0;
      init_threads();
    }
    {
      while (1) {
      while_3_continue:;
        {
          kernel_st = 1;
          eval();
          tmp = stop_simulation();
        }
        if (tmp) {
          goto while_3_break;
        } else {
        }
      }
    while_3_break:;
    }
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<window_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L5:
  mov    $0x0,%eax
  call   <gfx_wait@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x71,-0x1(%rbp)
  je     L12
  jmp    L5
L12:
  nop
  nop
  leave
  ret
```

assistant: ```c
void window_wait() {
  char c;
  while (1) {
    c = gfx_wait();
    if (c == 'q')
      break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<window_wait>:
  endbr64
  sub    $0x8,%rsp
L1:
  mov    $0x0,%eax
  call   <gfx_wait@plt>
  cmp    $0x71,%al
  jne    L1
  add    $0x8,%rsp
  ret
```

assistant: ```c
void window_wait() {
  char c;
  while (1) {
    c = gfx_wait();
    if (c == 'q')
      break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<window_wait>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <gfx_wait@plt>
  cmp    $0x71,%al
  jne    L4
  add    $0x8,%rsp
  ret
```

assistant: ```c
void window_wait() {
  char c;
  while (1) {
    c = gfx_wait();
    if (c == 'q')
      break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<window_wait>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <gfx_wait@plt>
  cmp    $0x71,%al
  jne    L5
  add    $0x8,%rsp
  ret
```

assistant: ```c
void window_wait() {
  char c;
  while (1) {
    c = gfx_wait();
    if (c == 'q')
      break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoimax@plt>
  mov    %rax,-0x8(%rbp)
  mov    D49(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jle    L17
  mov    D48(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    D49(%rip),%rax
  mov    (%rax),%rax
  jmp    L31
L17:
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jge    L14
  mov    D48(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  jmp    L31
L14:
  mov    -0x8(%rbp),%rax
L31:
  leave
  ret
```

assistant: ```c
long strtol(const char *s, char **p, int base) {
  intmax_t x = strtoimax(s, p, base);
  if (x > LONG_MAX) {
    errno = ERANGE;
    return LONG_MAX;
  } else if (x < LONG_MIN) {
    errno = ERANGE;
    return LONG_MIN;
  }
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strtol>:
  endbr64
  sub    $0x8,%rsp
  call   <strtoimax@plt>
  mov    D18(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rax,%rdx
  jl     L4
  mov    D53(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rax,%rdx
  jg     L37
L25:
  add    $0x8,%rsp
  ret
L4:
  mov    D24(%rip),%rax
  mov    (%rax),%ecx
  mov    D52(%rip),%rax
  mov    %ecx,(%rax)
  mov    %rdx,%rax
  jmp    L25
L37:
  mov    D24(%rip),%rax
  mov    (%rax),%ecx
  mov    D52(%rip),%rax
  mov    %ecx,(%rax)
  mov    %rdx,%rax
  jmp    L25
```

assistant: ```c
long strtol(const char *s, char **p, int base) {
  intmax_t x = strtoimax(s, p, base);
  if (x > LONG_MAX) {
    errno = ERANGE;
    return LONG_MAX;
  } else if (x < LONG_MIN) {
    errno = ERANGE;
    return LONG_MIN;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtol>:
  endbr64
  sub    $0x8,%rsp
  call   <strtoimax@plt>
  mov    D18(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rax,%rdx
  jl     L12
  mov    D25(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rax,%rdx
  jg     L12
  add    $0x8,%rsp
  ret
L12:
  mov    D23(%rip),%rax
  mov    (%rax),%ecx
  mov    D5(%rip),%rax
  mov    %ecx,(%rax)
  mov    %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long strtol(const char *s, char **p, int base) {
  intmax_t x = strtoimax(s, p, base);
  if (x > LONG_MAX) {
    errno = ERANGE;
    return LONG_MAX;
  } else if (x < LONG_MIN) {
    errno = ERANGE;
    return LONG_MIN;
  }
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<strtol>:
  endbr64
  sub    $0x8,%rsp
  call   <strtoimax@plt>
  mov    D23(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rax,%rdx
  jl     L10
  mov    D39(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rax,%rdx
  jg     L10
  add    $0x8,%rsp
  ret
L10:
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    D37(%rip),%rax
  mov    %ecx,(%rax)
  mov    %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long strtol(const char *s, char **p, int base) {
  intmax_t x = strtoimax(s, p, base);
  if (x > LONG_MAX) {
    errno = ERANGE;
    return LONG_MAX;
  } else if (x < LONG_MIN) {
    errno = ERANGE;
    return LONG_MIN;
  }
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x0,-0x1a(%rbp)
  jmp    L35
L36:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  cqto
  shr    $0x3f,%rdx
  add    %rdx,%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L25
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L25:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1a(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L35:
  movzwl -0x1a(%rbp),%eax
  test   %ax,%ax
  je     L36
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string
name: disassemble_data
arguments: tag: D22
type_infered: string
name: disassemble_data
arguments: tag: D12
type_infered: string

tool: D6: %d

tool: D22: zawji

tool: D12: fardi

assistant: ```c
int main() {
  short run = 0;
  while (run == 0) {
    long num;
    scanf("%d", &num);
    long natej = num % 2;
    if (natej == 0) {
      printf("zawji");
    } else {
      printf("fardi");
      scanf("%d", &run);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movw   $0x0,0xe(%rsp)
  lea    0x10(%rsp),%rbp
  lea    D26(%rip),%rbx
  lea    D2(%rip),%r13
  lea    D28(%rip),%r12
  jmp    L2
L43:
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0xe(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L17:
  cmpw   $0x0,0xe(%rsp)
  jne    L32
L2:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  testb  $0x1,0x10(%rsp)
  jne    L43
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L17
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type: string
name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D28
type: string

tool: D26: %d

tool: D2: fardi

tool: D28: zawji

assistant: ```c
int main() {
  short run = 0;
  while (run == 0) {
    long num;
    scanf("%d", &num);
    long natej = num % 2;
    if (natej == 0) {
      printf("zawji");
    } else {
      printf("fardi");
      scanf("%d", &run);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xe(%rsp),%r13
  mov    %ax,0xe(%rsp)
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %r12,%rdi
  call   <printf@plt>
  cmpw   $0x0,0xe(%rsp)
  jne    L40
L8:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  testb  $0x1,0x10(%rsp)
  je     L41
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpw   $0x0,0xe(%rsp)
  je     L8
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string

tool: D28: fardi

tool: D18: zawji

tool: D1: %d

assistant: ```c
int main() {
  short run = 0;
  while (run == 0) {
    long num;
    scanf("%d", &num);
    long natej = num % 2;
    if (natej == 0) {
      printf("zawji");
    } else {
      printf("fardi");
      scanf("%d", &run);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xe(%rsp),%r13
  mov    %ax,0xe(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  testb  $0x1,0x10(%rsp)
  jne    L34
  mov    %r12,%rdi
  call   <printf@plt>
  cmpw   $0x0,0xe(%rsp)
  je     L9
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpw   $0x0,0xe(%rsp)
  je     L9
  jmp    L44
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D21
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D22: fardi

tool: D21: zawji

tool: D12: %d

assistant: ```c
int main() {
  short run = 0;
  while (run == 0) {
    long num;
    scanf("%d", &num);
    long natej = num % 2;
    if (natej == 0) {
      printf("zawji");
    } else {
      printf("fardi");
      scanf("%d", &run);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bswap_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t bswap_32(uint32_t x) {
  x = ((x << 8) & 0xFF00FF00) | ((x >> 8) & 0x00FF00FF);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bswap_32>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%edi
  and    $0xff00ff00,%edi
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  or     %eax,%edi
  mov    %edi,%eax
  sar    $0x10,%eax
  shl    $0x10,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
uint32_t bswap_32(uint32_t x) {
  x = ((x << 8) & 0xFF00FF00) | ((x >> 8) & 0x00FF00FF);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bswap_32>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%edi
  sar    $0x8,%eax
  and    $0xff00ff00,%edi
  and    $0xff00ff,%eax
  or     %eax,%edi
  mov    %edi,%eax
  shl    $0x10,%edi
  sar    $0x10,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
uint32_t bswap_32(uint32_t x) {
  x = ((x << 8) & 0xFF00FF00) | ((x >> 8) & 0x00FF00FF);
  x = (x >> 16) | (x << 16);
  return x;
}
```