ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L6
L66:
  mov    -0x38(%rbp),%eax
  cltq
  movl   $0xffffffff,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x38(%rbp)
L6:
  cmpl   $0x5,-0x38(%rbp)
  jle    L66
  movl   $0x3e7,-0x34(%rbp)
  jmp    L121
L123:
  movl   $0x3e7,-0x38(%rbp)
  jmp    L96
L20:
  movl   $0x0,-0x28(%rbp)
  mov    -0x38(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L101
L82:
  mov    -0x30(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x2c(%rbp)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x30(%rbp)
L101:
  cmpl   $0x0,-0x30(%rbp)
  jg     L82
  movl   $0x0,-0x30(%rbp)
  jmp    L3
L46:
  mov    -0x30(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x2c(%rbp),%eax
  sub    -0x30(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  je     L43
  movl   $0x1,-0x28(%rbp)
L43:
  addl   $0x1,-0x30(%rbp)
L3:
  cmpl   $0x2,-0x30(%rbp)
  jle    L46
  cmpl   $0x0,-0x28(%rbp)
  jne    L79
  mov    -0x38(%rbp),%eax
  imul   -0x34(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jge    L79
  mov    -0x38(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,-0x24(%rbp)
L79:
  subl   $0x1,-0x38(%rbp)
L96:
  cmpl   $0x63,-0x38(%rbp)
  jg     L20
  subl   $0x1,-0x34(%rbp)
L121:
  cmpl   $0x63,-0x34(%rbp)
  jg     L123
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: found: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int i, m, j, k[6], counter;
  int flag;
  int big;
  big = 0;
  for (i = 0; i < 6; i++) {
    k[i] = -1;
  }
  for (m = 999; m > 99; m--) {
    for (i = 999; i > 99; i--) {
      flag = 0;
      j = i * m;
      counter = 0;
      while (j > 0) {
        k[counter] = j % 10;
        counter++;
        j = j / 10;
      }
      for (j = 0; j < 3; j++) {
        if (k[j] != k[counter - j - 1]) {
          flag = 1;
        }
      }
      if (flag == 0) {
        if ((i * m) > big) {
          big = i * m;
        }
      }
    }
  }
  printf("found: %d", big);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  movl   $0xffffffff,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  mov    $0xf3a71,%r12d
  mov    $0xfffffc19,%ebx
  mov    $0x0,%r8d
  mov    $0x0,%ebp
  lea    0xc(%rsp),%r10
  mov    $0x1,%r9d
  jmp    L32
L23:
  mov    %ebp,%r14d
  jmp    L7
L96:
  cmp    %esi,%r8d
  cmovge %r8d,%esi
  test   %ecx,%ecx
  cmove  %esi,%r8d
  add    %ebx,%edi
  sub    $0x1,%r11d
  je     L6
L97:
  mov    %edi,%esi
  test   %edi,%edi
  jle    L23
  mov    %edi,%edx
  mov    $0x1,%ecx
L86:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r13d
  sar    $0x1f,%r13d
  sub    %r13d,%eax
  lea    (%rax,%rax,4),%r13d
  add    %r13d,%r13d
  mov    %edx,%r14d
  sub    %r13d,%r14d
  mov    %r14d,-0x4(%rsp,%rcx,4)
  mov    %ecx,%r14d
  mov    %edx,%r13d
  mov    %eax,%edx
  add    $0x1,%rcx
  cmp    $0x9,%r13d
  jg     L86
L7:
  mov    %rsp,%rax
  movslq %r14d,%r14
  lea    (%rax,%r14,4),%rdx
  mov    $0x0,%ecx
L35:
  mov    -0x4(%rdx),%r14d
  cmp    %r14d,(%rax)
  cmovne %r9d,%ecx
  add    $0x4,%rax
  sub    $0x4,%rdx
  cmp    %rax,%r10
  jne    L35
  jmp    L96
L6:
  add    $0x1,%ebx
  sub    $0x3e7,%r12d
  cmp    $0x18255,%r12d
  je     L59
L32:
  mov    %r12d,%edi
  mov    $0x384,%r11d
  jmp    L97
L59:
  mov    %r8d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: found: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int i, m, j, k[6], counter;
  int flag;
  int big;
  big = 0;
  for (i = 0; i < 6; i++) {
    k[i] = -1;
  }
  for (m = 999; m > 99; m--) {
    for (i = 999; i > 99; i--) {
      flag = 0;
      j = i * m;
      counter = 0;
      while (j > 0) {
        k[counter] = j % 10;
        counter++;
        j = j / 10;
      }
      for (j = 0; j < 3; j++) {
        if (k[j] != k[counter - j - 1]) {
          flag = 1;
        }
      }
      if (flag == 0) {
        if ((i * m) > big) {
          big = i * m;
        }
      }
    }
  }
  printf("found: %d", big);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %r11d,%r11d
  mov    $0xf3a71,%ebp
  push   %rbx
  mov    $0xfffffc19,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  mov    %rsp,%r8
  movq   $0xffffffffffffffff,0x8(%rsp)
  movl   $0xffffffff,0x10(%rsp)
L68:
  mov    %ebp,%r9d
  mov    $0x384,%r10d
  nopl   0x0(%rax)
L59:
  mov    %r9d,%edx
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L48:
  movslq %edx,%rax
  mov    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  mov    %eax,%esi
  mov    %edx,%eax
  add    %edi,%edi
  mov    %esi,%edx
  sub    %edi,%eax
  mov    %ecx,%edi
  mov    %eax,-0x4(%r8,%rcx,4)
  add    $0x1,%rcx
  test   %esi,%esi
  jne    L48
  xor    %edx,%edx
  cmp    %eax,(%rsp)
  lea    -0x2(%rdi),%eax
  mov    0x4(%rsp),%ecx
  cltq
  setne  %dl
  cmp    %ecx,(%rsp,%rax,4)
  je     L36
L31:
  add    %ebx,%r9d
  sub    $0x1,%r10d
  jne    L59
  sub    $0x3e7,%ebp
  add    $0x1,%ebx
  cmp    $0x18255,%ebp
  jne    L68
  mov    %r11d,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L36:
  sub    $0x3,%edi
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  cmp    %eax,0x8(%rsp)
  jne    L31
  test   %edx,%edx
  jne    L31
  cmp    %r9d,%r11d
  cmovl  %r9d,%r11d
  jmp    L31
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: found: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int i, m, j, k[6], counter;
  int flag;
  int big;
  big = 0;
  for (i = 0; i < 6; i++) {
    k[i] = -1;
  }
  for (m = 999; m > 99; m--) {
    for (i = 999; i > 99; i--) {
      flag = 0;
      j = i * m;
      counter = 0;
      while (j > 0) {
        k[counter] = j % 10;
        counter++;
        j = j / 10;
      }
      for (j = 0; j < 3; j++) {
        if (k[j] != k[counter - j - 1]) {
          flag = 1;
        }
      }
      if (flag == 0) {
        if ((i * m) > big) {
          big = i * m;
        }
      }
    }
  }
  printf("found: %d", big);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xf3a71,%r11d
  mov    $0xfffffc19,%r9d
  xor    %r10d,%r10d
  push   %rbx
  mov    $0xcccccccd,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
L56:
  mov    %r11d,%edi
  mov    $0x384,%r8d
  jmp    L67
  nopl   0x0(%rax)
L61:
  add    %r9d,%edi
  sub    $0x1,%r8d
  je     L45
L67:
  mov    %edi,%ecx
  imul   %rsi,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%edx
  mov    %ecx,%eax
  mov    %edi,%ecx
  add    %edx,%edx
  sub    %edx,%ecx
  mov    %eax,%edx
  imul   %rsi,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ebx
  add    %ebx,%ebx
  sub    %ebx,%eax
  mov    %eax,0x4(%rsp)
  mov    %edx,%eax
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ebx
  add    %ebx,%ebx
  sub    %ebx,%edx
  mov    %edx,0x8(%rsp)
  mov    %eax,%edx
  imul   %rsi,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ebx
  add    %ebx,%ebx
  sub    %ebx,%eax
  mov    %eax,0xc(%rsp)
  mov    %edx,%eax
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ebp
  mov    %eax,%ebx
  mov    %edx,%eax
  mov    $0x5,%edx
  add    %ebp,%ebp
  sub    %ebp,%eax
  mov    %eax,0x10(%rsp)
  test   %ebx,%ebx
  je     L49
L34:
  lea    -0x1(%rdx),%eax
  cltq
  mov    (%rsp,%rax,4),%eax
  cmp    %eax,0x4(%rsp)
  jne    L61
  sub    $0x2,%edx
  mov    0x8(%rsp),%eax
  movslq %edx,%rdx
  cmp    %eax,(%rsp,%rdx,4)
  jne    L61
  cmp    %ebx,%ecx
  mov    %edi,%eax
  sete   %dl
  cmp    %edi,%r10d
  cmovge %r10d,%eax
  test   %dl,%dl
  cmovne %eax,%r10d
  add    %r9d,%edi
  sub    $0x1,%r8d
  jne    L67
L45:
  sub    $0x3e7,%r11d
  add    $0x1,%r9d
  cmp    $0x18255,%r11d
  jne    L56
  mov    %r10d,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L49:
  mov    %eax,%ebx
  mov    $0x4,%edx
  jmp    L34
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: found: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int i, m, j, k[6], counter;
  int flag;
  int big;
  big = 0;
  for (i = 0; i < 6; i++) {
    k[i] = -1;
  }
  for (m = 999; m > 99; m--) {
    for (i = 999; i > 99; i--) {
      flag = 0;
      j = i * m;
      counter = 0;
      while (j > 0) {
        k[counter] = j % 10;
        counter++;
        j = j / 10;
      }
      for (j = 0; j < 3; j++) {
        if (k[j] != k[counter - j - 1]) {
          flag = 1;
        }
      }
      if (flag == 0) {
        if ((i * m) > big) {
          big = i * m;
        }
      }
    }
  }
  printf("found: %d", big);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetLongStringLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <CreateLongString@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t GetLongStringLength(void) {
  char *pStr = CreateLongString();
  size_t length = strlen(pStr);
  free(pStr);
  pStr = NULL;
  return length;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GetLongStringLength>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CreateLongString@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t GetLongStringLength(void) {
  char *pStr = CreateLongString();
  size_t length = strlen(pStr);
  free(pStr);
  pStr = NULL;
  return length;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetLongStringLength>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <CreateLongString@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t GetLongStringLength(void) {
  char *pStr = CreateLongString();
  size_t length = strlen(pStr);
  free(pStr);
  pStr = NULL;
  return length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GetLongStringLength>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <CreateLongString@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t GetLongStringLength(void) {
  char *pStr = CreateLongString();
  size_t length = strlen(pStr);
  free(pStr);
  pStr = NULL;
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GPIOPinTypeFan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <GPIODirModeSet@plt>
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    $0x8,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <GPIOPadConfigSet@plt>
  nop
  leave
  ret
```

assistant: ```c
void GPIOPinTypeFan(uint32_t ui32Port, uint8_t ui8Pins) {
  ;
  GPIODirModeSet(ui32Port, ui8Pins, 0x00000002);
  GPIOPadConfigSet(ui32Port, ui8Pins, 0x00000001, 0x00000008);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GPIOPinTypeFan>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x2,%edx
  call   <GPIODirModeSet@plt>
  mov    $0x8,%ecx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <GPIOPadConfigSet@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void GPIOPinTypeFan(uint32_t ui32Port, uint8_t ui8Pins) {
  ;
  GPIODirModeSet(ui32Port, ui8Pins, 0x00000002);
  GPIOPadConfigSet(ui32Port, ui8Pins, 0x00000001, 0x00000008);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GPIOPinTypeFan>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <GPIODirModeSet@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x8,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <GPIOPadConfigSet@plt>
```

assistant: ```c
void GPIOPinTypeFan(uint32_t ui32Port, uint8_t ui8Pins) {
  ;
  GPIODirModeSet(ui32Port, ui8Pins, 0x00000002);
  GPIOPadConfigSet(ui32Port, ui8Pins, 0x00000001, 0x00000008);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GPIOPinTypeFan>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <GPIODirModeSet@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x8,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1070 <GPIOPadConfigSet@plt>
```

assistant: ```c
void GPIOPinTypeFan(uint32_t ui32Port, uint8_t ui8Pins) {
  ;
  GPIODirModeSet(ui32Port, ui8Pins, 0x00000002);
  GPIOPadConfigSet(ui32Port, ui8Pins, 0x00000001, 0x00000008);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <parse_int_easy_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  parse_int_easy_test();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <parse_int_easy_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  parse_int_easy_test();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <parse_int_easy_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  parse_int_easy_test();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <parse_int_easy_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  parse_int_easy_test();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_assert_memory_not_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memory_not_equal_display_error@plt>
  test   %eax,%eax
  jne    L0
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_fail@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void _assert_memory_not_equal(const void *const a, const void *const b, const size_t size, const char *const file, const int line) {
  if (!memory_not_equal_display_error((const char *)a, (const char *)b, size)) {
    _fail(file, line);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_assert_memory_not_equal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rcx,%rbx
  mov    %r8d,%ebp
  call   <memory_not_equal_display_error@plt>
  test   %eax,%eax
  je     L5
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_fail@plt>
  jmp    L11
```

assistant: ```c
void _assert_memory_not_equal(const void *const a, const void *const b, const size_t size, const char *const file, const int line) {
  if (!memory_not_equal_display_error((const char *)a, (const char *)b, size)) {
    _fail(file, line);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_assert_memory_not_equal>:
  endbr64
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <memory_not_equal_display_error@plt>
  test   %eax,%eax
  je     L5
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_fail@plt>
```

assistant: ```c
void _assert_memory_not_equal(const void *const a, const void *const b, const size_t size, const char *const file, const int line) {
  if (!memory_not_equal_display_error((const char *)a, (const char *)b, size)) {
    _fail(file, line);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_assert_memory_not_equal>:
  endbr64
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <memory_not_equal_display_error@plt>
  test   %eax,%eax
  je     L8
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_fail@plt>
```

assistant: ```c
void _assert_memory_not_equal(const void *const a, const void *const b, const size_t size, const char *const file, const int line) {
  if (!memory_not_equal_display_error((const char *)a, (const char *)b, size)) {
    _fail(file, line);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calculateSpan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L31:
  movl   $0x1,-0xc(%rbp)
  jmp    L13
L21:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <peek@plt>
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  jne    L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <peek@plt>
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L21
L8:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L31
  nop
  nop
  leave
  ret
```

assistant: ```c
void calculateSpan(int price[], int n, int span[]) {
  struct stack *stack = createStack(n);
  for (int i = 0; i < n; i++) {
    int cnt = 1;
    while (!isEmpty(stack) && price[peek(stack)] < price[i]) {
      cnt += span[peek(stack)];
      pop(stack);
    }
    push(stack, i);
    span[i] = cnt;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculateSpan>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%r15d
  mov    %rdx,%r14
  mov    %esi,%edi
  call   <createStack@plt>
  test   %r15d,%r15d
  jle    L46
  mov    %rax,%rbx
  mov    %r15d,%r15d
  mov    $0x0,%r13d
  jmp    L47
L17:
  mov    %rbx,%rdi
  call   <peek@plt>
  add    (%r14,%rax,4),%ebp
  mov    %rbx,%rdi
  call   <pop@plt>
L23:
  mov    %rbx,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  jne    L4
  mov    %rbx,%rdi
  call   <peek@plt>
  mov    (%r12,%r13,4),%ecx
  cmp    %ecx,(%r12,%rax,4)
  jl     L17
L4:
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    %ebp,(%r14,%r13,4)
  add    $0x1,%r13
  cmp    %r15,%r13
  je     L46
L47:
  mov    %r13d,0xc(%rsp)
  mov    $0x1,%ebp
  jmp    L23
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void calculateSpan(int price[], int n, int span[]) {
  struct stack *stack = createStack(n);
  for (int i = 0; i < n; i++) {
    int cnt = 1;
    while (!isEmpty(stack) && price[peek(stack)] < price[i]) {
      cnt += span[peek(stack)];
      pop(stack);
    }
    push(stack, i);
    span[i] = cnt;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calculateSpan>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <createStack@plt>
  mov    %rax,%rbx
  movslq %ebp,%rax
  mov    %rax,0x8(%rsp)
  test   %ebp,%ebp
  jle    L48
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r13d,%r15d
  mov    $0x1,%ebp
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rbx,%rdi
  call   <peek@plt>
  mov    (%r12,%r13,4),%ecx
  cmp    %ecx,(%r12,%rax,4)
  jge    L47
  mov    %rbx,%rdi
  call   <peek@plt>
  mov    %rbx,%rdi
  add    (%r14,%rax,4),%ebp
  call   <pop@plt>
L16:
  mov    %rbx,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  je     L7
L47:
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    %ebp,(%r14,%r13,4)
  add    $0x1,%r13
  cmp    0x8(%rsp),%r13
  jne    L0
L48:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void calculateSpan(int price[], int n, int span[]) {
  struct stack *stack = createStack(n);
  for (int i = 0; i < n; i++) {
    int cnt = 1;
    while (!isEmpty(stack) && price[peek(stack)] < price[i]) {
      cnt += span[peek(stack)];
      pop(stack);
    }
    push(stack, i);
    span[i] = cnt;
  }
}
```