ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<arrayf_get_lsq_slope>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %r8d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movslq %r8d,%r15
  mov    %r8d,%esi
  shl    $0x4,%esi
  lea    0x18(%rsp),%rdi
  mov    $0xa,%ecx
  lea    D0(%rip),%rdx
  call   <willus_mem_alloc_warn@plt>
  mov    0x18(%rsp),%rax
  lea    (%rax,%r15,8),%rsi
  test   %r12d,%r12d
  jle    L14
  mov    %r12d,%edx
  mov    $0x0,%eax
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
L15:
  pxor   %xmm1,%xmm1
  cvtss2sd (%rbx,%rax,4),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x0(%rbp,%rax,4),%xmm1
  addsd  %xmm1,%xmm2
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L15
  pxor   %xmm3,%xmm3
  cvtsi2sd %r12d,%xmm3
  movapd %xmm0,%xmm1
  divsd  %xmm3,%xmm1
  divsd  %xmm3,%xmm2
  movsd  %xmm2,0x8(%rsp)
  mov    $0x0,%eax
L23:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%rax,4),%xmm0
  subsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rcx
  movsd  %xmm0,(%rcx,%rax,8)
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp,%rax,4),%xmm0
  subsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L23
L8:
  lea    0x20(%rsp),%r8
  mov    $0x1,%ecx
  mov    %r12d,%edx
  mov    0x18(%rsp),%rdi
  call   <gslpolyfit@plt>
  lea    0x18(%rsp),%rdi
  lea    D0(%rip),%rsi
  call   <willus_mem_free@plt>
  pxor   %xmm0,%xmm0
  cvtsd2ss 0x28(%rsp),%xmm0
  movss  %xmm0,0x0(%r13)
  movsd  0x8(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%r14)
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  pxor   %xmm1,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  jmp    L8
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: arrayf_get_lsq_slope

assistant: ```c
void arrayf_get_lsq_slope(float *m, float *b, float *x, float *y, int n) {
  double c[2];
  double *tx, *ty;
  double xoff, yoff;
  int i;
  willus_mem_alloc_warn((void **)&tx, sizeof(double) * 2 * n, "arrayf_get_lsq_slope", 10);
  ty = &tx[n];
  for (xoff = yoff = 0., i = 0; i < n; i++) {
    xoff += x[i];
    yoff += y[i];
  }
  xoff /= n;
  yoff /= n;
  for (i = 0; i < n; i++) {
    tx[i] = x[i] - xoff;
    ty[i] = y[i] - yoff;
  }
  gslpolyfit(tx, ty, n, 1, c);
  willus_mem_free((double **)&tx, "arrayf_get_lsq_slope");
  (*m) = (float)c[1];
  (*b) = (float)(c[0] + yoff);
}
```
user: What is the c source code of the assembly code below?

```asm
<arrayf_get_lsq_slope>:
  endbr64
  push   %r15
  movslq %r8d,%r8
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  mov    $0xa,%ecx
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rbp,%rdx
  sub    $0x48,%rsp
  mov    %rsi,(%rsp)
  lea    0x18(%rsp),%r15
  mov    %r8d,%esi
  shl    $0x4,%esi
  mov    %r15,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %r8,0x8(%rsp)
  call   <willus_mem_alloc_warn@plt>
  mov    0x18(%rsp),%rdi
  mov    0x8(%rsp),%r8
  lea    (%rdi,%r8,8),%rsi
  test   %r14d,%r14d
  jle    L19
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  movapd %xmm0,%xmm1
  nopl   (%rax)
L8:
  pxor   %xmm2,%xmm2
  cvtss2sd (%rbx,%rax,4),%xmm2
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd (%r12,%rax,4),%xmm2
  add    $0x1,%rax
  addsd  %xmm2,%xmm0
  cmp    %rax,%r8
  jne    L8
  pxor   %xmm3,%xmm3
  movapd %xmm1,%xmm2
  xor    %eax,%eax
  cvtsi2sd %r14d,%xmm3
  divsd  %xmm3,%xmm2
  divsd  %xmm3,%xmm0
  nopl   0x0(%rax,%rax,1)
L46:
  pxor   %xmm1,%xmm1
  cvtss2sd (%rbx,%rax,4),%xmm1
  subsd  %xmm2,%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  pxor   %xmm1,%xmm1
  cvtss2sd (%r12,%rax,4),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L46
L6:
  lea    0x20(%rsp),%r8
  mov    $0x1,%ecx
  mov    %r14d,%edx
  movsd  %xmm0,0x8(%rsp)
  call   <gslpolyfit@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <willus_mem_free@plt>
  movsd  0x8(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  mov    (%rsp),%rax
  cvtsd2ss 0x28(%rsp),%xmm1
  movss  %xmm1,0x0(%r13)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %r14d,%xmm1
  divsd  %xmm1,%xmm0
  jmp    L6
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: arrayf_get_lsq_slope

assistant: ```c
void arrayf_get_lsq_slope(float *m, float *b, float *x, float *y, int n) {
  double c[2];
  double *tx, *ty;
  double xoff, yoff;
  int i;
  willus_mem_alloc_warn((void **)&tx, sizeof(double) * 2 * n, "arrayf_get_lsq_slope", 10);
  ty = &tx[n];
  for (xoff = yoff = 0., i = 0; i < n; i++) {
    xoff += x[i];
    yoff += y[i];
  }
  xoff /= n;
  yoff /= n;
  for (i = 0; i < n; i++) {
    tx[i] = x[i] - xoff;
    ty[i] = y[i] - yoff;
  }
  gslpolyfit(tx, ty, n, 1, c);
  willus_mem_free((double **)&tx, "arrayf_get_lsq_slope");
  (*m) = (float)c[1];
  (*b) = (float)(c[0] + yoff);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<emalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x40,%edx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <eprintf@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/carlo0815/gstreamer1.7.1/refs/heads/master/libs/gst/check/libcheck/check_error.c

tool: D8: malloc of %u bytes failed:

assistant: ```c
void *emalloc(size_t n) {
  void *p;
  p = malloc(n);
  if (p == NULL)
    eprintf("malloc of %u bytes failed:", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/carlo0815/gstreamer1.7.1/refs/heads/master/libs/gst/check/libcheck/check_error.c", 66 - 2, n);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L12:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rcx
  mov    $0x40,%edx
  lea    D16(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <eprintf@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: label: D16
data_type: string
name: unpack_data
arguments: label: D9
data_type: string

tool: D16: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/carlo0815/gstreamer1.7.1/refs/heads/master/libs/gst/check/libcheck/check_error.c

tool: D9: malloc of %u bytes failed:

assistant: ```c
void *emalloc(size_t n) {
  void *p;
  p = malloc(n);
  if (p == NULL)
    eprintf("malloc of %u bytes failed:", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/carlo0815/gstreamer1.7.1/refs/heads/master/libs/gst/check/libcheck/check_error.c", 66 - 2, n);
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<emalloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L5:
  mov    %r13,%rcx
  mov    $0x40,%edx
  lea    D19(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <eprintf@plt>
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string

tool: D19: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/carlo0815/gstreamer1.7.1/refs/heads/master/libs/gst/check/libcheck/check_error.c

tool: D0: malloc of %u bytes failed:

assistant: ```c
void *emalloc(size_t n) {
  void *p;
  p = malloc(n);
  if (p == NULL)
    eprintf("malloc of %u bytes failed:", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/carlo0815/gstreamer1.7.1/refs/heads/master/libs/gst/check/libcheck/check_error.c", 66 - 2, n);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<emalloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L4:
  mov    %r13,%rcx
  mov    $0x40,%edx
  lea    D10(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <eprintf@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: string
name: parse_data
arguments: tag: D9
data_type: string

tool: D10: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/carlo0815/gstreamer1.7.1/refs/heads/master/libs/gst/check/libcheck/check_error.c

tool: D9: malloc of %u bytes failed:

assistant: ```c
void *emalloc(size_t n) {
  void *p;
  p = malloc(n);
  if (p == NULL)
    eprintf("malloc of %u bytes failed:", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/carlo0815/gstreamer1.7.1/refs/heads/master/libs/gst/check/libcheck/check_error.c", 66 - 2, n);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jle    L4
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <f2@plt>
  jmp    L7
L4:
  nop
L7:
  leave
  ret
```

assistant: ```c
void f(int n) {
  if (n < 3)
    return;
  n--;
  f2(n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  cmp    $0x2,%edi
  jg     L8
  ret
L8:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  call   <f2@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f(int n) {
  if (n < 3)
    return;
  n--;
  f2(n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  cmp    $0x2,%edi
  jg     L2
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  sub    $0x1,%edi
  jmp    1050 <f2@plt>
```

assistant: ```c
void f(int n) {
  if (n < 3)
    return;
  n--;
  f2(n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  cmp    $0x2,%edi
  jg     L9
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%edi
  jmp    1050 <f2@plt>
```

assistant: ```c
void f(int n) {
  if (n < 3)
    return;
  n--;
  f2(n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clad_compared>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L35
  mov    $0xffffffff,%eax
  jmp    L16
L35:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L17
  mov    $0x1,%eax
  jmp    L16
L17:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int clad_compared(double one, double two) {
  if (one < two)
    return -1;
  if (one > two)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clad_compared>:
  endbr64
  mov    $0xffffffff,%eax
  comisd %xmm0,%xmm1
  ja     L9
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
L9:
  ret
```

assistant: ```c
int clad_compared(double one, double two) {
  if (one < two)
    return -1;
  if (one > two)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clad_compared>:
  endbr64
  comisd %xmm0,%xmm1
  mov    $0xffffffff,%eax
  ja     L3
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
L3:
  ret
```

assistant: ```c
int clad_compared(double one, double two) {
  if (one < two)
    return -1;
  if (one > two)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clad_compared>:
  endbr64
  comisd %xmm0,%xmm1
  mov    $0xffffffff,%eax
  ja     L9
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
L9:
  ret
```

assistant: ```c
int clad_compared(double one, double two) {
  if (one < two)
    return -1;
  if (one > two)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_char@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int print_string(struct spe_fd *fd, const char *string) {
  int i;
  for (i = 0; string[i] != 0; i++) {
    print_char(fd, string[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_string>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L13
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rbx
L10:
  movsbl %al,%esi
  mov    %rbp,%rdi
  call   <print_char@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L10
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int print_string(struct spe_fd *fd, const char *string) {
  int i;
  for (i = 0; string[i] != 0; i++) {
    print_char(fd, string[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_string>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  movsbl %al,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <print_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int print_string(struct spe_fd *fd, const char *string) {
  int i;
  for (i = 0; string[i] != 0; i++) {
    print_char(fd, string[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_string>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl %al,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <print_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L11
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int print_string(struct spe_fd *fd, const char *string) {
  int i;
  for (i = 0; string[i] != 0; i++) {
    print_char(fd, string[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<luaO_int2fb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L23:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  shr    %eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L37:
  cmpl   $0xf,-0x14(%rbp)
  ja     L23
  cmpl   $0x7,-0x14(%rbp)
  ja     L29
  mov    -0x14(%rbp),%eax
  jmp    L2
L29:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x14(%rbp),%eax
  sub    $0x8,%eax
  or     %edx,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int luaO_int2fb(unsigned int x) {
  int e = 0;
  while (x >= 16) {
    x = (x + 1) >> 1;
    e++;
  }
  if (x < 8)
    return x;
  else
    return ((e + 1) << 3) | (((int)((x))) - 8);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<luaO_int2fb>:
  endbr64
  cmp    $0xf,%edi
  jbe    L35
  mov    $0x0,%edx
L22:
  lea    0x1(%rdi),%eax
  mov    %eax,%edi
  shr    %edi
  add    $0x1,%edx
  cmp    $0x1f,%eax
  ja     L22
L6:
  cmp    $0x7,%edi
  ja     L17
  mov    %edi,%eax
  ret
L35:
  mov    $0x0,%edx
  jmp    L6
L17:
  lea    0x8(,%rdx,8),%eax
  sub    $0x8,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
int luaO_int2fb(unsigned int x) {
  int e = 0;
  while (x >= 16) {
    x = (x + 1) >> 1;
    e++;
  }
  if (x < 8)
    return x;
  else
    return ((e + 1) << 3) | (((int)((x))) - 8);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<luaO_int2fb>:
  endbr64
  mov    %edi,%eax
  xor    %ecx,%ecx
  cmp    $0xf,%edi
  jbe    L23
  nopl   (%rax)
L22:
  lea    0x1(%rax),%edx
  add    $0x1,%ecx
  mov    %edx,%eax
  shr    %eax
  cmp    $0x1f,%edx
  ja     L22
L23:
  cmp    $0x7,%eax
  jbe    L25
  lea    0x8(,%rcx,8),%edx
  sub    $0x8,%eax
  or     %edx,%eax
L25:
  ret
```

assistant: ```c
int luaO_int2fb(unsigned int x) {
  int e = 0;
  while (x >= 16) {
    x = (x + 1) >> 1;
    e++;
  }
  if (x < 8)
    return x;
  else
    return ((e + 1) << 3) | (((int)((x))) - 8);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<luaO_int2fb>:
  endbr64
  mov    %edi,%eax
  xor    %ecx,%ecx
  cmp    $0xf,%edi
  jbe    L25
  nopl   (%rax)
L8:
  lea    0x1(%rax),%edx
  add    $0x1,%ecx
  mov    %edx,%eax
  shr    %eax
  cmp    $0x1f,%edx
  ja     L8
L25:
  cmp    $0x7,%eax
  jbe    L18
  lea    0x8(,%rcx,8),%edx
  sub    $0x8,%eax
  or     %edx,%eax
L18:
  ret
```

assistant: ```c
int luaO_int2fb(unsigned int x) {
  int e = 0;
  while (x >= 16) {
    x = (x + 1) >> 1;
    e++;
  }
  if (x < 8)
    return x;
  else
    return ((e + 1) << 3) | (((int)((x))) - 8);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L25
L37:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jae    L19
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x13(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x1(%rax),%rdx
  movzbl -0x13(%rbp),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
  lea    -0xc(%rbp),%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
  jmp    L39
L19:
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
L39:
  addl   $0x1,-0x10(%rbp)
L25:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L37
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] |= (state[0UL] & 31U) << 4UL;
        state[local1] *= state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] << 5U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%edi
  test   %edi,%edi
  je     L6
  lea    0x4(%rsp),%rax
  mov    $0x0,%edx
L44:
  mov    0x4(%rsp),%r8d
  cmp    %edx,%r8d
  jbe    L4
  movzbl (%rax),%ecx
  movzbl 0x1(%rax),%r8d
  mov    %r8b,(%rax)
  mov    %cl,0x1(%rax)
  movzwl 0x6(%rsp),%ecx
  movzwl 0x4(%rsp),%r8d
  mov    %r8w,0x6(%rsp)
  mov    %cx,0x4(%rsp)
L38:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edi,%edx
  jne    L44
L6:
  mov    0x4(%rsp),%eax
  shl    $0x5,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x18,%rsp
  ret
L4:
  mov    %r8d,%ecx
  shl    $0x4,%ecx
  and    $0x1f0,%ecx
  or     %r8d,%ecx
  imul   %ecx,%ecx
  mov    %ecx,(%rax)
  jmp    L38
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] |= (state[0UL] & 31U) << 4UL;
        state[local1] *= state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] << 5U;
  }
}
```