ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readlines>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L46
  nopl   (%rax)
L21:
  cmp    %ebp,%r13d
  jle    L19
  mov    %ebx,%edi
  call   <alloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L19
  sub    $0x1,%ebx
  mov    %r12,%rsi
  mov    %rax,%rdi
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  call   <strcpy@plt>
  mov    %r15,(%r14,%rbp,8)
  add    $0x1,%rbp
L46:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    %ebp,%r15d
  call   <_getline_ptr@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L21
L34:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x3f8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0xffffffff,%r15d
  jmp    L34
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readlines(char *lineptr[], int maxlines) {
  int len, nlines;
  char *p, line[1000];
  nlines = 0;
  while ((len = _getline_ptr(line, 1000)) > 0)
    if (nlines >= maxlines || (p = alloc(len)) == NULL)
      return -1;
    else {
      line[len - 1] = '\0';
      strcpy(p, line);
      lineptr[nlines++] = p;
    }
  return nlines;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readlines>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L46
  nopl   (%rax)
L9:
  cmp    %ebp,%r13d
  jle    L28
  mov    %ebx,%edi
  call   <alloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L28
  sub    $0x1,%ebx
  mov    %r12,%rsi
  mov    %rax,%rdi
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  call   <strcpy@plt>
  mov    %r15,(%r14,%rbp,8)
  add    $0x1,%rbp
L46:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    %ebp,%r15d
  call   <_getline_ptr@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L9
L47:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x3f8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0xffffffff,%r15d
  jmp    L47
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readlines(char *lineptr[], int maxlines) {
  int len, nlines;
  char *p, line[1000];
  nlines = 0;
  while ((len = _getline_ptr(line, 1000)) > 0)
    if (nlines >= maxlines || (p = alloc(len)) == NULL)
      return -1;
    else {
      line[len - 1] = '\0';
      strcpy(p, line);
      lineptr[nlines++] = p;
    }
  return nlines;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<c_sapx>:
  endbr64
  ucomiss D8(%rip),%xmm0
  setnp  %al
  mov    $0x0,%ecx
  cmovne %ecx,%eax
  test   %al,%al
  jne    L18
  test   %edi,%edi
  jle    L18
  cmp    $0x1,%edx
  je     L53
  mov    $0x0,%eax
  test   %edx,%edx
  js     L34
L63:
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  cltq
  lea    (%rsi,%rax,4),%rax
  mov    $0x0,%edx
L9:
  movaps %xmm0,%xmm1
  addss  (%rax),%xmm1
  movss  %xmm1,(%rax)
  add    $0x1,%edx
  add    %rcx,%rax
  cmp    %edx,%edi
  jg     L9
L18:
  ret
L53:
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  mov    %edi,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jle    L43
  mov    %rsi,%rax
  lea    -0x1(%rdx),%ecx
  lea    0x4(%rsi,%rcx,4),%rcx
L97:
  movaps %xmm0,%xmm1
  addss  (%rax),%xmm1
  movss  %xmm1,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L97
L43:
  cmp    $0x4,%edi
  jle    L18
  movslq %edx,%rax
  lea    (%rsi,%rax,4),%rax
L8:
  movaps %xmm0,%xmm1
  addss  (%rax),%xmm1
  movss  %xmm1,(%rax)
  movaps %xmm0,%xmm1
  addss  0x4(%rax),%xmm1
  movss  %xmm1,0x4(%rax)
  movaps %xmm0,%xmm1
  addss  0x8(%rax),%xmm1
  movss  %xmm1,0x8(%rax)
  movaps %xmm0,%xmm1
  addss  0xc(%rax),%xmm1
  movss  %xmm1,0xc(%rax)
  movaps %xmm0,%xmm1
  addss  0x10(%rax),%xmm1
  movss  %xmm1,0x10(%rax)
  add    $0x5,%edx
  add    $0x14,%rax
  cmp    %edx,%edi
  jg     L8
  ret
L34:
  mov    $0x1,%eax
  sub    %edi,%eax
  imul   %edx,%eax
  jmp    L63
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: f32

tool: D8: 0

assistant: ```c
void c_sapx(const int64_t N, const float alpha, float *X, const int64_t stride) {
  int64_t ix;
  int64_t m;
  int64_t i;
  if (N <= 0 || alpha == 0.0) {
    return;
  }
  if (stride == 1) {
    m = N % 5;
    if (m > 0) {
      for (i = 0; i < m; i++) {
        X[i] += alpha;
      }
    }
    if (N < 5) {
      return;
    }
    for (i = m; i < N; i += 5) {
      X[i] += alpha;
      X[i + 1] += alpha;
      X[i + 2] += alpha;
      X[i + 3] += alpha;
      X[i + 4] += alpha;
    }
    return;
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    X[ix] += alpha;
    ix += stride;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_sapx>:
  endbr64
  mov    %edi,%ecx
  mov    %rsi,%rdi
  test   %ecx,%ecx
  setle  %sil
  jle    L14
  ucomiss D6(%rip),%xmm0
  setnp  %al
  cmovne %esi,%eax
  test   %al,%al
  jne    L14
  cmp    $0x1,%edx
  je     L60
  xor    %eax,%eax
  test   %edx,%edx
  js     L41
L42:
  movslq %edx,%rdx
  cltq
  lea    0x0(,%rdx,4),%rsi
  lea    (%rdi,%rax,4),%rax
  xor    %edx,%edx
L89:
  movss  (%rax),%xmm1
  add    $0x1,%edx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rax)
  add    %rsi,%rax
  cmp    %edx,%ecx
  jg     L89
L14:
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    $0x1,%eax
  sub    %ecx,%eax
  imul   %edx,%eax
  jmp    L42
  nopl   0x0(%rax)
L60:
  movslq %ecx,%rdx
  mov    %ecx,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x21,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L10
  lea    -0x1(%rdx),%esi
  mov    %rdi,%rax
  lea    0x4(%rdi,%rsi,4),%rsi
L87:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x4(%rax)
  cmp    %rax,%rsi
  jne    L87
L10:
  cmp    $0x4,%ecx
  jle    L14
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rax
  nopl   0x0(%rax,%rax,1)
L19:
  movss  (%rax),%xmm1
  add    $0x5,%edx
  add    $0x14,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x14(%rax)
  movss  -0x10(%rax),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x10(%rax)
  movss  -0xc(%rax),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,-0xc(%rax)
  movss  -0x8(%rax),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x8(%rax)
  movss  -0x4(%rax),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x4(%rax)
  cmp    %edx,%ecx
  jg     L19
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: f32

tool: D6: 0

assistant: ```c
void c_sapx(const int64_t N, const float alpha, float *X, const int64_t stride) {
  int64_t ix;
  int64_t m;
  int64_t i;
  if (N <= 0 || alpha == 0.0) {
    return;
  }
  if (stride == 1) {
    m = N % 5;
    if (m > 0) {
      for (i = 0; i < m; i++) {
        X[i] += alpha;
      }
    }
    if (N < 5) {
      return;
    }
    for (i = m; i < N; i += 5) {
      X[i] += alpha;
      X[i + 1] += alpha;
      X[i + 2] += alpha;
      X[i + 3] += alpha;
      X[i + 4] += alpha;
    }
    return;
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    X[ix] += alpha;
    ix += stride;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<glmCeil3f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L7
L8:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movd   %eax,%xmm0
  call   <ceilf@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addq   $0x1,-0x18(%rbp)
L7:
  cmpq   $0x2,-0x18(%rbp)
  jbe    L8
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void glmCeil3f(float out[3], const float x[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = ceilf(x[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<glmCeil3f>:
  endbr64
  mov    $0x0,%eax
  movss  D7(%rip),%xmm4
  movss  D2(%rip),%xmm3
  movss  D9(%rip),%xmm5
  jmp    L32
L27:
  movss  %xmm2,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  je     L34
L32:
  movss  (%rsi,%rax,4),%xmm1
  movaps %xmm1,%xmm2
  movaps %xmm1,%xmm0
  andps  %xmm3,%xmm0
  ucomiss %xmm0,%xmm4
  jbe    L27
  cvttss2si %xmm1,%edx
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  cmpnless %xmm0,%xmm2
  andps  %xmm5,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm3,%xmm2
  andnps %xmm1,%xmm2
  orps   %xmm0,%xmm2
  jmp    L27
L34:
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: byte[4]
name: unpack_data
arguments: label: D2
type_guessed: byte[4]
name: unpack_data
arguments: label: D9
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x4b]}

tool: {"D2": [0xff,0xff,0xff,0x7f]}

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmCeil3f(float out[3], const float x[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = ceilf(x[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<glmCeil3f>:
  endbr64
  movss  D7(%rip),%xmm4
  movss  D23(%rip),%xmm3
  xor    %eax,%eax
  movss  D15(%rip),%xmm5
L16:
  movss  (%rsi,%rax,4),%xmm0
  movaps %xmm0,%xmm1
  andps  %xmm3,%xmm1
  ucomiss %xmm1,%xmm4
  jbe    L1
  cvttss2si %xmm0,%edx
  pxor   %xmm1,%xmm1
  movaps %xmm0,%xmm2
  cvtsi2ss %edx,%xmm1
  cmpnless %xmm1,%xmm2
  andps  %xmm5,%xmm2
  addss  %xmm2,%xmm1
  movaps %xmm3,%xmm2
  andnps %xmm0,%xmm2
  movaps %xmm1,%xmm0
  orps   %xmm2,%xmm0
L1:
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L16
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: byte[4]
name: read_data
arguments: label: D23
datatype: byte[4]
name: read_data
arguments: label: D15
datatype: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x4b]}

tool: {"D23": [0xff,0xff,0xff,0x7f]}

tool: {"D15": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmCeil3f(float out[3], const float x[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = ceilf(x[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<glmCeil3f>:
  endbr64
  movss  (%rsi),%xmm1
  movss  D32(%rip),%xmm0
  movss  D0(%rip),%xmm3
  mov    %rdi,%rax
  movaps %xmm0,%xmm4
  movaps %xmm1,%xmm2
  andps  %xmm0,%xmm2
  ucomiss %xmm2,%xmm3
  jbe    L24
  cvttss2si %xmm1,%edx
  pxor   %xmm2,%xmm2
  movaps %xmm1,%xmm5
  movss  D42(%rip),%xmm6
  andnps %xmm1,%xmm4
  cvtsi2ss %edx,%xmm2
  cmpnless %xmm2,%xmm5
  andps  %xmm6,%xmm5
  addss  %xmm5,%xmm2
  movaps %xmm2,%xmm1
  orps   %xmm4,%xmm1
L24:
  movss  %xmm1,(%rax)
  movss  0x4(%rsi),%xmm1
  movaps %xmm0,%xmm4
  movaps %xmm1,%xmm2
  andps  %xmm0,%xmm2
  ucomiss %xmm2,%xmm3
  jbe    L11
  cvttss2si %xmm1,%edx
  pxor   %xmm2,%xmm2
  movaps %xmm1,%xmm5
  movss  D42(%rip),%xmm6
  andnps %xmm1,%xmm4
  cvtsi2ss %edx,%xmm2
  cmpnless %xmm2,%xmm5
  andps  %xmm6,%xmm5
  addss  %xmm5,%xmm2
  movaps %xmm2,%xmm1
  orps   %xmm4,%xmm1
L11:
  movss  %xmm1,0x4(%rax)
  movss  0x8(%rsi),%xmm1
  movaps %xmm1,%xmm2
  andps  %xmm0,%xmm2
  ucomiss %xmm2,%xmm3
  jbe    L6
  cvttss2si %xmm1,%edx
  pxor   %xmm2,%xmm2
  movaps %xmm1,%xmm3
  movss  D42(%rip),%xmm4
  andnps %xmm1,%xmm0
  cvtsi2ss %edx,%xmm2
  cmpnless %xmm2,%xmm3
  andps  %xmm4,%xmm3
  addss  %xmm3,%xmm2
  movaps %xmm2,%xmm1
  orps   %xmm0,%xmm1
L6:
  movss  %xmm1,0x8(%rax)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D32
data_type: byte[4]
name: unpack_data
arguments: tag: D0
data_type: byte[4]
name: unpack_data
arguments: tag: D42
data_type: byte[4]

tool: {"D32": [0xff,0xff,0xff,0x7f]}

tool: {"D0": [0x00,0x00,0x00,0x4b]}

tool: {"D42": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmCeil3f(float out[3], const float x[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = ceilf(x[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L37
  mov    $0xffffffff,%eax
  jmp    L6
L37:
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L12
  mov    $0x1,%eax
  jmp    L6
L12:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int sign(double x) {
  if (x < 0.0)
    return (-1);
  else if (x > 0.0)
    return (+1);
  else
    return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sign>:
  endbr64
  mov    $0xffffffff,%eax
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L9
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
L9:
  ret
```

assistant: ```c
int sign(double x) {
  if (x < 0.0)
    return (-1);
  else if (x > 0.0)
    return (+1);
  else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sign>:
  endbr64
  pxor   %xmm1,%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm0,%xmm1
  ja     L3
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
L3:
  ret
```

assistant: ```c
int sign(double x) {
  if (x < 0.0)
    return (-1);
  else if (x > 0.0)
    return (+1);
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sign>:
  endbr64
  pxor   %xmm1,%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm0,%xmm1
  ja     L3
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
L3:
  ret
```

assistant: ```c
int sign(double x) {
  if (x < 0.0)
    return (-1);
  else if (x > 0.0)
    return (+1);
  else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xs_putll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x38,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x30,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    $0x28,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    $0x20,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void xs_putll(unsigned char *buf, uint64_t val) {
  buf[0] = (unsigned char)((val >> 56) & 0xff);
  buf[1] = (unsigned char)((val >> 48) & 0xff);
  buf[2] = (unsigned char)((val >> 40) & 0xff);
  buf[3] = (unsigned char)((val >> 32) & 0xff);
  buf[4] = (unsigned char)((val >> 24) & 0xff);
  buf[5] = (unsigned char)((val >> 16) & 0xff);
  buf[6] = (unsigned char)((val >> 8) & 0xff);
  buf[7] = (unsigned char)(val & 0xff);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xs_putll>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  mov    $0x38,%ecx
  sar    %cl,%edx
  mov    %dl,(%rdi)
  mov    %esi,%edx
  mov    $0x30,%ecx
  sar    %cl,%edx
  mov    %dl,0x1(%rdi)
  mov    %esi,%edx
  mov    $0x28,%ecx
  sar    %cl,%edx
  mov    %dl,0x2(%rdi)
  mov    %esi,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  mov    %dl,0x3(%rdi)
  mov    %esi,%edx
  sar    $0x18,%edx
  mov    %dl,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %dl,0x5(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x6(%rdi)
  mov    %sil,0x7(%rdi)
  ret
```

assistant: ```c
void xs_putll(unsigned char *buf, uint64_t val) {
  buf[0] = (unsigned char)((val >> 56) & 0xff);
  buf[1] = (unsigned char)((val >> 48) & 0xff);
  buf[2] = (unsigned char)((val >> 40) & 0xff);
  buf[3] = (unsigned char)((val >> 32) & 0xff);
  buf[4] = (unsigned char)((val >> 24) & 0xff);
  buf[5] = (unsigned char)((val >> 16) & 0xff);
  buf[6] = (unsigned char)((val >> 8) & 0xff);
  buf[7] = (unsigned char)(val & 0xff);
}
```
user: What is the c source code of the assembly code below:

```asm
<xs_putll>:
  endbr64
  mov    %esi,%eax
  mov    $0x38,%ecx
  sar    %cl,%eax
  mov    $0x30,%ecx
  mov    %al,(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x28,%ecx
  mov    %al,0x1(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x20,%ecx
  mov    %al,0x2(%rdi)
  mov    %esi,%eax
  bswap  %esi
  sar    %cl,%eax
  mov    %esi,0x4(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void xs_putll(unsigned char *buf, uint64_t val) {
  buf[0] = (unsigned char)((val >> 56) & 0xff);
  buf[1] = (unsigned char)((val >> 48) & 0xff);
  buf[2] = (unsigned char)((val >> 40) & 0xff);
  buf[3] = (unsigned char)((val >> 32) & 0xff);
  buf[4] = (unsigned char)((val >> 24) & 0xff);
  buf[5] = (unsigned char)((val >> 16) & 0xff);
  buf[6] = (unsigned char)((val >> 8) & 0xff);
  buf[7] = (unsigned char)(val & 0xff);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xs_putll>:
  endbr64
  mov    %esi,%edx
  mov    $0x38,%ecx
  mov    %esi,%eax
  push   %r14
  sar    %cl,%edx
  mov    $0x30,%ecx
  push   %rbx
  mov    %esi,%ebx
  sar    %cl,%eax
  sar    $0x8,%ebx
  mov    %esi,%r8d
  mov    %esi,%r9d
  mov    %eax,%r14d
  movzbl %sil,%eax
  mov    %esi,%r10d
  mov    %esi,%r11d
  shl    $0x8,%rax
  movzbl %bl,%esi
  sar    $0x10,%r11d
  mov    $0x28,%ecx
  or     %rsi,%rax
  movzbl %r11b,%esi
  sar    $0x18,%r10d
  movzbl %dl,%edx
  shl    $0x8,%rax
  sar    %cl,%r8d
  mov    $0x20,%ecx
  pop    %rbx
  or     %rsi,%rax
  movzbl %r10b,%esi
  sar    %cl,%r9d
  movzbl %r14b,%ecx
  shl    $0x8,%rax
  pop    %r14
  or     %rsi,%rax
  movzbl %r9b,%esi
  shl    $0x8,%rax
  or     %rsi,%rax
  movzbl %r8b,%esi
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void xs_putll(unsigned char *buf, uint64_t val) {
  buf[0] = (unsigned char)((val >> 56) & 0xff);
  buf[1] = (unsigned char)((val >> 48) & 0xff);
  buf[2] = (unsigned char)((val >> 40) & 0xff);
  buf[3] = (unsigned char)((val >> 32) & 0xff);
  buf[4] = (unsigned char)((val >> 24) & 0xff);
  buf[5] = (unsigned char)((val >> 16) & 0xff);
  buf[6] = (unsigned char)((val >> 8) & 0xff);
  buf[7] = (unsigned char)(val & 0xff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Resize_Definition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: struct Resize {
  void (*resize)(var, size_t);
};


assistant: ```c
const char *Resize_Definition(void) {
  return "struct Resize {\n"
         "  void (*resize)(var, size_t);\n"
         "};\n";
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Resize_Definition>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D8: struct Resize {
  void (*resize)(var, size_t);
};


assistant: ```c
const char *Resize_Definition(void) {
  return "struct Resize {\n"
         "  void (*resize)(var, size_t);\n"
         "};\n";
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Resize_Definition>:
  endbr64
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: struct Resize {
  void (*resize)(var, size_t);
};


assistant: ```c
const char *Resize_Definition(void) {
  return "struct Resize {\n"
         "  void (*resize)(var, size_t);\n"
         "};\n";
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Resize_Definition>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9: struct Resize {
  void (*resize)(var, size_t);
};


assistant: ```c
const char *Resize_Definition(void) {
  return "struct Resize {\n"
         "  void (*resize)(var, size_t);\n"
         "};\n";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eeh_memset_io>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  movabs $0xe000000000000000,%rax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
  leave
  ret
```

assistant: ```c
void eeh_memset_io(void *addr, int c, unsigned long n) {
  void *vaddr = (void *)((((unsigned long)(addr)) & 0xFFFFFFFF) | (0xEUL << 60));
  memset(vaddr, c, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eeh_memset_io>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edi
  movabs $0xe000000000000000,%rax
  or     %rax,%rdi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void eeh_memset_io(void *addr, int c, unsigned long n) {
  void *vaddr = (void *)((((unsigned long)(addr)) & 0xFFFFFFFF) | (0xEUL << 60));
  memset(vaddr, c, n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eeh_memset_io>:
  endbr64
  movabs $0xe000000000000000,%rax
  mov    %edi,%edi
  or     %rax,%rdi
  jmp    1050 <memset@plt>
```

assistant: ```c
void eeh_memset_io(void *addr, int c, unsigned long n) {
  void *vaddr = (void *)((((unsigned long)(addr)) & 0xFFFFFFFF) | (0xEUL << 60));
  memset(vaddr, c, n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eeh_memset_io>:
  endbr64
  movabs $0xe000000000000000,%rax
  mov    %edi,%edi
  or     %rax,%rdi
  jmp    1050 <memset@plt>
```

assistant: ```c
void eeh_memset_io(void *addr, int c, unsigned long n) {
  void *vaddr = (void *)((((unsigned long)(addr)) & 0xFFFFFFFF) | (0xEUL << 60));
  memset(vaddr, c, n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<odd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L9
L18:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <even@plt>
L9:
  leave
  ret
```

assistant: ```c
long odd(long x) {
  if (x == 0)
    return 0;
  return even(x - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<odd>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  jne    L6
  ret
L6:
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%rdi
  call   <even@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long odd(long x) {
  if (x == 0)
    return 0;
  return even(x - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<odd>:
  endbr64
  test   %rdi,%rdi
  jne    L4
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L4:
  sub    $0x1,%rdi
  jmp    1050 <even@plt>
```

assistant: ```c
long odd(long x) {
  if (x == 0)
    return 0;
  return even(x - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<odd>:
  endbr64
  test   %rdi,%rdi
  jne    L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L6:
  sub    $0x1,%rdi
  jmp    1050 <even@plt>
```

assistant: ```c
long odd(long x) {
  if (x == 0)
    return 0;
  return even(x - 1);
}
```