user: What would the C source look like for the assembly code provided here?

```asm
<call_Littlewood_Richardson_homotopies>:
  endbr64
  push   %rbp
  mov    %edx,%r10d
  mov    %rsp,%rbp
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  sub    $0x98,%rsp
  movslq 0x10(%rbp),%r12
  mov    0x18(%rbp),%r11
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0xf(,%r12,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L24
L53:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L53
L24:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L78
L36:
  lea    -0x91(%rbp),%rsi
  lea    D21(%rip),%rdi
  mov    %r10d,-0xa8(%rbp)
  mov    %rsp,%r14
  mov    %r11,-0xc0(%rbp)
  lea    -0x90(%rbp),%r13
  mov    %r9d,-0xb8(%rbp)
  mov    %r8d,-0xb4(%rbp)
  mov    %rcx,-0xb0(%rbp)
  call   <scanf@plt>
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  lea    D32(%rip),%rdi
  mov    %eax,%edx
  mov    %eax,-0xa4(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0xc0(%rbp),%r11
  push   %r14
  mov    %ebx,%edi
  mov    -0xa4(%rbp),%edx
  mov    -0xb8(%rbp),%r9d
  mov    %r15d,%esi
  mov    -0xb4(%rbp),%r8d
  mov    -0xb0(%rbp),%rcx
  push   %r11
  push   %r13
  push   %rdx
  mov    -0xa8(%rbp),%edx
  call   <standard_Littlewood_Richardson_homotopies@plt>
  mov    %r14,%rsp
  lea    D34(%rip),%rdi
  mov    %eax,-0xa4(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rbp),%eax
  test   %eax,%eax
  jle    L50
  add    %ebx,%ebx
  xor    %r15d,%r15d
  lea    D1(%rip),%r13
  jmp    L75
  nopl   0x0(%rax)
L22:
  movsd  (%r14,%r15,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r12,%r15
  je     L50
L75:
  mov    %r15d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L50:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  mov    -0xa4(%rbp),%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  xchg   %ax,%ax
L78:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L36
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D32
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D34
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D21: %c

tool: D0: Give the name of the output file : 

tool: D20: %s

tool: D32: Number of characters in %s is %d


tool: D34: 
The coefficients of the fixed flag :

tool: D1:  %+.1e

assistant: ```c
int call_Littlewood_Richardson_homotopies(int n, int k, int c, int *brackets, int verbose, int verify, int size, int *r) {
  double flags[size];
  char ans, filename[80];
  int i, fail, nbname, prec;
  scanf("%c", &ans);
  printf("Give the name of the output file : ");
  scanf("%s", filename);
  nbname = strlen(filename);
  printf("Number of characters in %s is %d\n", filename, nbname);
  if (prec == 0)
    fail = standard_Littlewood_Richardson_homotopies(n, k, c, brackets, verbose, verify, nbname, filename, r, flags);
  if (prec == 1)
    fail = dobldobl_Littlewood_Richardson_homotopies(n, k, c, brackets, verbose, verify, nbname, filename, r, flags);
  if (prec == 2)
    fail = quaddobl_Littlewood_Richardson_homotopies(n, k, c, brackets, verbose, verify, nbname, filename, r, flags);
  printf("\nThe coefficients of the fixed flag :");
  for (i = 0; i < size; i++) {
    if (i % (2 * n) == 0)
      printf("\n");
    printf(" %+.1e", flags[i]);
  }
  printf("\n");
  return fail;
}
```