ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<returnDecimalFromString>:
  endbr64
  sub    $0x31,%edi
  cmp    $0x35,%dil
  ja     L3
  movzbl %dil,%edi
  lea    D6(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0xd,%eax
  ret
  mov    $0xe,%eax
  ret
  mov    $0xf,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0xd,%eax
  ret
  mov    $0xe,%eax
  ret
  mov    $0xf,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint8_t returnDecimalFromString(char hex) {
  if (hex == 'a') {
    return 0;
  } else if (hex == '1') {
    return 1;
  } else if (hex == '2') {
    return 2;
  } else if (hex == '3') {
    return 3;
  } else if (hex == '4') {
    return 4;
  } else if (hex == '5') {
    return 5;
  } else if (hex == '6') {
    return 6;
  } else if (hex == '7') {
    return 7;
  } else if (hex == '8') {
    return 8;
  } else if (hex == '9') {
    return 9;
  } else if (hex == 'A') {
    return 10;
  } else if (hex == 'B') {
    return 11;
  } else if (hex == 'C') {
    return 12;
  } else if (hex == 'D') {
    return 13;
  } else if (hex == 'E') {
    return 14;
  } else if (hex == 'F') {
    return 15;
  } else if (hex == 'a') {
    return 10;
  } else if (hex == 'b') {
    return 11;
  } else if (hex == 'c') {
    return 12;
  } else if (hex == 'd') {
    return 13;
  } else if (hex == 'e') {
    return 14;
  } else if (hex == 'f') {
    return 15;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<returnDecimalFromString>:
  endbr64
  sub    $0x31,%edi
  xor    %eax,%eax
  cmp    $0x35,%dil
  ja     L1
  movzbl %dil,%edi
  lea    D6(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L1:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: 	

assistant: ```c
uint8_t returnDecimalFromString(char hex) {
  if (hex == 'a') {
    return 0;
  } else if (hex == '1') {
    return 1;
  } else if (hex == '2') {
    return 2;
  } else if (hex == '3') {
    return 3;
  } else if (hex == '4') {
    return 4;
  } else if (hex == '5') {
    return 5;
  } else if (hex == '6') {
    return 6;
  } else if (hex == '7') {
    return 7;
  } else if (hex == '8') {
    return 8;
  } else if (hex == '9') {
    return 9;
  } else if (hex == 'A') {
    return 10;
  } else if (hex == 'B') {
    return 11;
  } else if (hex == 'C') {
    return 12;
  } else if (hex == 'D') {
    return 13;
  } else if (hex == 'E') {
    return 14;
  } else if (hex == 'F') {
    return 15;
  } else if (hex == 'a') {
    return 10;
  } else if (hex == 'b') {
    return 11;
  } else if (hex == 'c') {
    return 12;
  } else if (hex == 'd') {
    return 13;
  } else if (hex == 'e') {
    return 14;
  } else if (hex == 'f') {
    return 15;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<returnDecimalFromString>:
  endbr64
  sub    $0x31,%edi
  xor    %eax,%eax
  cmp    $0x35,%dil
  ja     L5
  movzbl %dil,%edi
  lea    D6(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L5:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: 	

assistant: ```c
uint8_t returnDecimalFromString(char hex) {
  if (hex == 'a') {
    return 0;
  } else if (hex == '1') {
    return 1;
  } else if (hex == '2') {
    return 2;
  } else if (hex == '3') {
    return 3;
  } else if (hex == '4') {
    return 4;
  } else if (hex == '5') {
    return 5;
  } else if (hex == '6') {
    return 6;
  } else if (hex == '7') {
    return 7;
  } else if (hex == '8') {
    return 8;
  } else if (hex == '9') {
    return 9;
  } else if (hex == 'A') {
    return 10;
  } else if (hex == 'B') {
    return 11;
  } else if (hex == 'C') {
    return 12;
  } else if (hex == 'D') {
    return 13;
  } else if (hex == 'E') {
    return 14;
  } else if (hex == 'F') {
    return 15;
  } else if (hex == 'a') {
    return 10;
  } else if (hex == 'b') {
    return 11;
  } else if (hex == 'c') {
    return 12;
  } else if (hex == 'd') {
    return 13;
  } else if (hex == 'e') {
    return 14;
  } else if (hex == 'f') {
    return 15;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skipBytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L7
L36:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    D7(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  je     L12
  subl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x0,-0xc(%rbp)
  jg     L36
  jmp    L4
L12:
  nop
L4:
  leave
  ret
```

assistant: ```c
void skipBytes(FILE *f, int length) {
  for (; length > 0; --length)
    if (fgetc(f) == EOF)
      return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skipBytes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L22
L19:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    D2(%rip),%rdx
  cmp    (%rdx),%rax
  je     L22
  sub    $0x1,%ebx
  jne    L19
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void skipBytes(FILE *f, int length) {
  for (; length > 0; --length)
    if (fgetc(f) == EOF)
      return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skipBytes>:
  endbr64
  test   %esi,%esi
  jle    L24
  push   %r12
  mov    D4(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x1,%ebx
  je     L38
L10:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    (%r12),%rax
  jne    L5
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  ret
```

assistant: ```c
void skipBytes(FILE *f, int length) {
  for (; length > 0; --length)
    if (fgetc(f) == EOF)
      return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipBytes>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %r12
  mov    D0(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L2:
  sub    $0x1,%ebx
  je     L16
L14:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    (%r12),%rax
  jne    L2
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  ret
```

assistant: ```c
void skipBytes(FILE *f, int length) {
  for (; length > 0; --length)
    if (fgetc(f) == EOF)
      return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
L93:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0xa,%eax
  jne    L93
  sub    $0x1,%ebp
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%r12
  test   %ebp,%ebp
  jg     L20
  jmp    L160
L171:
  mov    (%rsp),%edi
  cmp    $0x20,%edi
  je     L27
  cmp    $0xa,%edi
  je     L27
L43:
  add    $0x1,%ebx
  movslq %ebx,%rbx
L183:
  call   <putchar@plt>
  mov    %ebx,%ebp
  mov    (%r12,%rbx,4),%edi
  add    $0x1,%rbx
  cmp    $0x20,%edi
  je     L66
  cmp    $0xa,%edi
  jne    L183
L66:
  cmp    $0xa,%edi
  je     L204
  cmp    $0x20,%edi
  je     L204
  movslq %ebp,%rax
  lea    -0x1(%rbp),%ebx
  movslq %ebx,%rbx
  cmpl   $0x20,(%rsp,%rax,4)
  jne    L36
L18:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %ebx,%ebp
  sub    $0x1,%rbx
  cmpl   $0x20,0x4(%r12,%rbx,4)
  je     L18
L36:
  test   %ebp,%ebp
  jle    L160
L20:
  movslq %ebp,%rax
  lea    (%r12,%rax,4),%rax
L85:
  mov    %rax,%rcx
  mov    (%rax),%edx
  cmp    $0x20,%edx
  je     L87
  cmp    $0xa,%edx
  je     L87
  lea    -0x1(%rbp),%ebx
  cmpl   $0x20,-0x4(%rcx)
  je     L59
  sub    $0x4,%rax
  test   %ebx,%ebx
  je     L171
  mov    %ebx,%ebp
  jmp    L85
L27:
  mov    %ebx,%ebp
  jmp    L66
L204:
  sub    $0x1,%ebp
L160:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L120
  mov    $0x0,%eax
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  movslq %ebp,%rax
  mov    (%rsp,%rax,4),%edi
  mov    %ebp,%ebx
  jmp    L43
L87:
  movslq %ebp,%rax
  mov    (%rsp,%rax,4),%edi
  jmp    L66
L120:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D14
type: string
name: retrieve_data
arguments: label: D16
type: string

tool: D12: Enter a sentence: 

tool: D14: Words reversed: 

tool: D16: i = %d


assistant: ```c
int main(void) {
  int words[40];
  int i = 0;
  printf("Enter a sentence: ");
  while ((words[i] = getchar()) != '\n') {
    i += 1;
  }
  i -= 1;
  printf("Words reversed: ");
  while (i > 0) {
    while (words[i] != ' ' && words[i] != '\n') {
      i -= 1;
      if (words[i] == ' ') {
        i += 1;
        break;
      }
      if (i == 0) {
        break;
      }
    }
    while (words[i] != ' ' && words[i] != '\n') {
      printf("%c", words[i]);
      i += 1;
    }
    if (words[i] == '\n' || words[i] == ' ') {
      i -= 1;
      break;
    }
    while (words[i] != ' ' && words[i] != '\n') {
      i -= 1;
      if (i == 0) {
        break;
      }
    }
    while (words[i] == ' ') {
      printf(" ");
      i -= 1;
    }
  }
  printf("\n");
  printf("i = %d\n", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  nopl   0x0(%rax)
L44:
  xor    %eax,%eax
  mov    %r12d,%ebp
  call   <getchar@plt>
  mov    %eax,(%rbx,%r12,4)
  add    $0x1,%r12
  cmp    $0xa,%eax
  jne    L44
  sub    $0x1,%ebp
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L168
  nopl   0x0(%rax)
L173:
  movslq %ebp,%rax
  mov    (%rsp,%rax,4),%edi
  jmp    L94
L55:
  sub    $0x1,%rax
  mov    %eax,%ebp
  test   %eax,%eax
  je     L108
  mov    %edx,%edi
L94:
  mov    %eax,%ebp
  cmp    $0x20,%edi
  je     L104
  cmp    $0xa,%edi
  je     L148
  mov    -0x4(%rbx,%rax,4),%edx
  cmp    $0x20,%edx
  jne    L55
L29:
  add    $0x1,%ebp
  movslq %ebp,%r12
  nop
L39:
  call   <putchar@plt>
  mov    (%rbx,%r12,4),%edi
  mov    %r12d,%ebp
  add    $0x1,%r12
  cmp    $0x20,%edi
  je     L104
  cmp    $0xa,%edi
  jne    L39
L148:
  sub    $0x1,%ebp
L168:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L120
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L108:
  mov    (%rsp),%edi
  cmp    $0xa,%edi
  je     L148
  cmp    $0x20,%edi
  jne    L29
  nopl   (%rax)
L104:
  cmp    $0xa,%edi
  je     L148
  cmp    $0x20,%edi
  je     L148
  movslq %ebp,%rax
  lea    -0x1(%rbp),%r12d
  cmpl   $0x20,(%rsp,%rax,4)
  movslq %r12d,%r12
  jne    L4
  nopw   0x0(%rax,%rax,1)
L132:
  mov    $0x20,%edi
  mov    %r12d,%ebp
  sub    $0x1,%r12
  call   <putchar@plt>
  cmpl   $0x20,0x4(%rbx,%r12,4)
  je     L132
L4:
  test   %ebp,%ebp
  jg     L173
  jmp    L168
L120:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: D7: Enter a sentence: 

tool: D28: Words reversed: 

tool: D16: i = %d


assistant: ```c
int main(void) {
  int words[40];
  int i = 0;
  printf("Enter a sentence: ");
  while ((words[i] = getchar()) != '\n') {
    i += 1;
  }
  i -= 1;
  printf("Words reversed: ");
  while (i > 0) {
    while (words[i] != ' ' && words[i] != '\n') {
      i -= 1;
      if (words[i] == ' ') {
        i += 1;
        break;
      }
      if (i == 0) {
        break;
      }
    }
    while (words[i] != ' ' && words[i] != '\n') {
      printf("%c", words[i]);
      i += 1;
    }
    if (words[i] == '\n' || words[i] == ' ') {
      i -= 1;
      break;
    }
    while (words[i] != ' ' && words[i] != '\n') {
      i -= 1;
      if (i == 0) {
        break;
      }
    }
    while (words[i] == ' ') {
      printf(" ");
      i -= 1;
    }
  }
  printf("\n");
  printf("i = %d\n", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D15(%rip),%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <getchar@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    $0xa,%eax
  jne    L32
  sub    $0x1,%ebp
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L145
  movslq %ebp,%rax
  mov    (%rsp,%rax,4),%edi
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L118:
  sub    $0x1,%rax
  mov    %edx,%edi
  mov    %eax,%ebp
  test   %eax,%eax
  je     L79
L42:
  mov    %eax,%ebp
  cmp    $0x20,%edi
  je     L77
  cmp    $0xa,%edi
  je     L101
  mov    -0x4(%r12,%rax,4),%edx
  cmp    $0x20,%edx
  jne    L118
L129:
  add    $0x1,%ebp
  movslq %ebp,%rbx
L41:
  call   <putchar@plt>
  mov    (%r12,%rbx,4),%edi
  mov    %ebx,%ebp
  add    $0x1,%rbx
  cmp    $0x20,%edi
  je     L77
  cmp    $0xa,%edi
  jne    L41
L101:
  sub    $0x1,%ebp
L145:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  mov    (%rsp),%edi
  cmp    $0xa,%edi
  je     L61
  cmp    $0x20,%edi
  jne    L129
  jmp    L101
  nop
L77:
  cmp    $0xa,%edi
  je     L101
  cmp    $0x20,%edi
  je     L101
  movslq %ebp,%rax
  jmp    L42
L36:
  call   <__stack_chk_fail@plt>
L61:
  cmp    $0x20,%edi
  je     L101
  cmp    $0xa,%edi
  jne    L145
  jmp    L101
```

tool_calls: name: unpack_data
arguments: data_tag: D15
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D20
datatype: string

tool: D15: Enter a sentence: 

tool: D10: Words reversed: 

tool: D20: i = %d


assistant: ```c
int main(void) {
  int words[40];
  int i = 0;
  printf("Enter a sentence: ");
  while ((words[i] = getchar()) != '\n') {
    i += 1;
  }
  i -= 1;
  printf("Words reversed: ");
  while (i > 0) {
    while (words[i] != ' ' && words[i] != '\n') {
      i -= 1;
      if (words[i] == ' ') {
        i += 1;
        break;
      }
      if (i == 0) {
        break;
      }
    }
    while (words[i] != ' ' && words[i] != '\n') {
      printf("%c", words[i]);
      i += 1;
    }
    if (words[i] == '\n' || words[i] == ' ') {
      i -= 1;
      break;
    }
    while (words[i] != ' ' && words[i] != '\n') {
      i -= 1;
      if (i == 0) {
        break;
      }
    }
    while (words[i] == ' ') {
      printf(" ");
      i -= 1;
    }
  }
  printf("\n");
  printf("i = %d\n", i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0xe,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D11
datatype: string

tool: D22: 
MACRO1 Defined

tool: D17: 
MACRO2 Defined

tool: D11: result : %d


assistant: ```c
int main(void) {
  printf("\nMACRO1 Defined\n");
  printf("\nMACRO2 Defined\n");
  int result = 2 * (2 + 5);
  printf("result : %d\n", result);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    $0xe,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D10
type: string

tool: D12: 
MACRO1 Defined

tool: D11: 
MACRO2 Defined

tool: D10: result : %d


assistant: ```c
int main(void) {
  printf("\nMACRO1 Defined\n");
  printf("\nMACRO2 Defined\n");
  int result = 2 * (2 + 5);
  printf("result : %d\n", result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0xe,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string

tool: D4: 
MACRO1 Defined

tool: D14: 
MACRO2 Defined

tool: D17: result : %d


assistant: ```c
int main(void) {
  printf("\nMACRO1 Defined\n");
  printf("\nMACRO2 Defined\n");
  int result = 2 * (2 + 5);
  printf("result : %d\n", result);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0xe,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D2: 
MACRO1 Defined

tool: D12: 
MACRO2 Defined

tool: D11: result : %d


assistant: ```c
int main(void) {
  printf("\nMACRO1 Defined\n");
  printf("\nMACRO2 Defined\n");
  int result = 2 * (2 + 5);
  printf("result : %d\n", result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x20(%rbp),%xmm1
  mov    -0x18(%rbp),%rax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movsd  D0(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: byte[8]

tool: {"D0": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
void dtime(double *t) {
  struct timeval timev;
  gettimeofday(&timev, NULL);
  *t = timev.tv_sec + (double)timev.tv_usec * 1e-6;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dtime>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm0
  mulsd  D5(%rip),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: byte[8]

tool: {"D5": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
void dtime(double *t) {
  struct timeval timev;
  gettimeofday(&timev, NULL);
  *t = timev.tv_sec + (double)timev.tv_usec * 1e-6;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dtime>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm0
  mulsd  D0(%rip),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: byte[8]

tool: {"D0": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
void dtime(double *t) {
  struct timeval timev;
  gettimeofday(&timev, NULL);
  *t = timev.tv_sec + (double)timev.tv_usec * 1e-6;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dtime>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm0
  mulsd  D3(%rip),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type: byte[8]

tool: {"D3": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
void dtime(double *t) {
  struct timeval timev;
  gettimeofday(&timev, NULL);
  *t = timev.tv_sec + (double)timev.tv_usec * 1e-6;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<palMap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  movsd  %xmm0,-0xb8(%rbp)
  movsd  %xmm1,-0xc0(%rbp)
  movsd  %xmm2,-0xc8(%rbp)
  movsd  %xmm3,-0xd0(%rbp)
  movsd  %xmm4,-0xd8(%rbp)
  movsd  %xmm5,-0xe0(%rbp)
  movsd  %xmm6,-0xe8(%rbp)
  movsd  %xmm7,-0xf0(%rbp)
  mov    %rdi,-0xf8(%rbp)
  mov    %rsi,-0x100(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xb0(%rbp),%rdx
  movsd  -0xf0(%rbp),%xmm0
  mov    -0xe8(%rbp),%rax
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <palMappa@plt>
  mov    -0x100(%rbp),%rdx
  mov    -0xf8(%rbp),%rsi
  lea    -0xb0(%rbp),%rcx
  movsd  -0xe0(%rbp),%xmm4
  movsd  -0xd8(%rbp),%xmm3
  movsd  -0xd0(%rbp),%xmm2
  movsd  -0xc8(%rbp),%xmm1
  movsd  -0xc0(%rbp),%xmm0
  mov    -0xb8(%rbp),%rax
  mov    %rcx,%rdi
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <palMapqk@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void palMap(double rm, double dm, double pr, double pd, double px, double rv, double eq, double date, double *ra, double *da) {
  double amprms[21];
  palMappa(eq, date, amprms);
  palMapqk(rm, dm, pr, pd, px, rv, amprms, ra, da);
}
```