ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<openbsd_reallocarray>:
  endbr64
  mov    %rsi,%rax
  mov    %rdx,%rcx
  or     %rdx,%rax
  shr    $0x20,%rax
  je     L46
  test   %rsi,%rsi
  je     L37
  mov    D15(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%rax
  div    %rsi
  cmp    %rcx,%rax
  jb     L27
L46:
  test   %rcx,%rcx
  je     L37
  test   %rsi,%rsi
  je     L37
  imul   %rcx,%rsi
  jmp    1050 <realloc@plt>
  nop
L27:
  mov    D25(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  mov    %edx,(%rax)
L37:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *openbsd_reallocarray(void *optr, size_t nmemb, size_t size) {
  if ((nmemb >= ((size_t)1 << (sizeof(size_t) * 4)) || size >= ((size_t)1 << (sizeof(size_t) * 4))) && nmemb > 0 && UINTPTR_MAX / nmemb < size) {
    errno = ENOMEM;
    return NULL;
  }
  if (size == 0 || nmemb == 0)
    return NULL;
  return realloc(optr, size * nmemb);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<openbsd_reallocarray>:
  endbr64
  mov    %rsi,%rax
  mov    %rdx,%rcx
  or     %rdx,%rax
  shr    $0x20,%rax
  je     L27
  test   %rsi,%rsi
  je     L26
  mov    D12(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%rax
  div    %rsi
  cmp    %rcx,%rax
  jb     L39
L27:
  test   %rcx,%rcx
  je     L26
  test   %rsi,%rsi
  je     L26
  imul   %rcx,%rsi
  jmp    1050 <realloc@plt>
  nop
L39:
  mov    D20(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *openbsd_reallocarray(void *optr, size_t nmemb, size_t size) {
  if ((nmemb >= ((size_t)1 << (sizeof(size_t) * 4)) || size >= ((size_t)1 << (sizeof(size_t) * 4))) && nmemb > 0 && UINTPTR_MAX / nmemb < size) {
    errno = ENOMEM;
    return NULL;
  }
  if (size == 0 || nmemb == 0)
    return NULL;
  return realloc(optr, size * nmemb);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: %s <rom file>


assistant: ```c
void usage(const char *s) {
  printf("%s <rom file>\n", s);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: %s <rom file>


assistant: ```c
void usage(const char *s) {
  printf("%s <rom file>\n", s);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: %s <rom file>


assistant: ```c
void usage(const char *s) {
  printf("%s <rom file>\n", s);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: %s <rom file>


assistant: ```c
void usage(const char *s) {
  printf("%s <rom file>\n", s);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aphelion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D4(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: f64

tool: D4: 1

assistant: ```c
double aphelion(double sma, double e) {
  double r;
  r = sma * (1.0 + e);
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aphelion>:
  endbr64
  addsd  D9(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: f64

tool: D9: 1

assistant: ```c
double aphelion(double sma, double e) {
  double r;
  r = sma * (1.0 + e);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aphelion>:
  endbr64
  addsd  D4(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: f64

tool: D4: 1

assistant: ```c
double aphelion(double sma, double e) {
  double r;
  r = sma * (1.0 + e);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aphelion>:
  endbr64
  addsd  D8(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: f64

tool: D8: 1

assistant: ```c
double aphelion(double sma, double e) {
  double r;
  r = sma * (1.0 + e);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<childhandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D9: Caught signal from child!


assistant: ```c
void childhandler(int signo __attribute__((unused))) {
  printf("Caught signal from child!\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<childhandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
datatype: string

tool: D6: Caught signal from child!


assistant: ```c
void childhandler(int signo __attribute__((unused))) {
  printf("Caught signal from child!\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<childhandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string

tool: D5: Caught signal from child!


assistant: ```c
void childhandler(int signo __attribute__((unused))) {
  printf("Caught signal from child!\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<childhandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8: Caught signal from child!


assistant: ```c
void childhandler(int signo __attribute__((unused))) {
  printf("Caught signal from child!\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movabs $0xef34ca9f65fb16,%rdx
  imul   %rdx,%rax
  movabs $0xdf61e99ee5b9fd1c,%rdx
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  mov    $0xa392912d,%edx
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy13;
  unsigned short copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
        state[local1] = state[0UL] + state[local1];
      } else {
        state[0UL] -= state[local1];
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
        state[local1] -= state[0UL];
      } else {
        copy14 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy14;
        copy15 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = copy15;
        copy15 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy15;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 307931096UL) + 2436360533UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  movabs $0xdf61e99f894c8e49,%rdx
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy13;
  unsigned short copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
        state[local1] = state[0UL] + state[local1];
      } else {
        state[0UL] -= state[local1];
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
        state[local1] -= state[0UL];
      } else {
        copy14 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy14;
        copy15 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = copy15;
        copy15 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy15;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 307931096UL) + 2436360533UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  movabs $0xdf61e99f894c8e49,%rdx
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy13;
  unsigned short copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
        state[local1] = state[0UL] + state[local1];
      } else {
        state[0UL] -= state[local1];
      }
      if (state[0UL] > local1) {
        copy13 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
        state[local1] -= state[0UL];
      } else {
        copy14 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy14;
        copy15 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = copy15;
        copy15 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy15;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 307931096UL) + 2436360533UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xd0(%rbp)
  movl   $0xa,-0xcc(%rbp)
  movl   $0x2,-0xc8(%rbp)
  movl   $0x6,-0xc4(%rbp)
  movl   $0x3,-0xc0(%rbp)
  lea    -0xd0(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <sort@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xd0(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <print@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L48
L32:
  lea    -0xb0(%rbp),%rdx
  mov    -0xd4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xd4(%rbp)
L48:
  cmpl   $0x9,-0xd4(%rbp)
  jle    L32
  lea    -0xb0(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <sort@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xb0(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L11
L28:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %edx,-0x80(%rbp,%rax,4)
  addl   $0x1,-0xd4(%rbp)
L11:
  cmpl   $0x1d,-0xd4(%rbp)
  jle    L28
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x80(%rbp),%rax
  mov    $0x1e,%esi
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x80(%rbp),%rax
  mov    $0x1e,%esi
  mov    %rax,%rdi
  call   <sort@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x80(%rbp),%rax
  mov    $0x1e,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D35
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string
name: retrieve_data
arguments: tag: D58
datatype: string
name: retrieve_data
arguments: tag: D41
datatype: string

tool: D35: Sorted: 

tool: D13: Read 10 values: 

tool: D0: %d

tool: D58: 
Sorted: 

tool: D41: Unsorted: 

assistant: ```c
int main() {
  int Data1[5] = {5, 10, 2, 6, 3}, Data2[10], Data3[30], i;
  sort(Data1, 5);
  printf("Sorted: ");
  print(Data1, 5);
  printf("Read 10 values: ");
  for (i = 0; i < 10; i++)
    scanf("%d", &Data2[i]);
  sort(Data2, 10);
  printf("\nSorted: ");
  print(Data2, 10);
  srand(time(NULL));
  for (i = 0; i < 30; i++)
    Data3[i] = rand() % 100;
  printf("Unsorted: ");
  print(Data3, 30);
  sort(Data3, 30);
  printf("Sorted: ");
  print(Data3, 30);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0xa,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  mov    %rsp,%rbx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <sort@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rbx
  lea    0x48(%rsp),%r12
  lea    D52(%rip),%rbp
L17:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  lea    0x20(%rsp),%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <sort@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x50(%rsp),%rbx
  lea    0xc8(%rsp),%rbp
L5:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L5
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    0x50(%rsp),%rbx
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <sort@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D37
datatype: string
name: retrieve_data
arguments: label: D21
datatype: string
name: retrieve_data
arguments: label: D52
datatype: string
name: retrieve_data
arguments: label: D30
datatype: string
name: retrieve_data
arguments: label: D39
datatype: string

tool: D37: Sorted: 

tool: D21: Read 10 values: 

tool: D52: %d

tool: D30: 
Sorted: 

tool: D39: Unsorted: 

assistant: ```c
int main() {
  int Data1[5] = {5, 10, 2, 6, 3}, Data2[10], Data3[30], i;
  sort(Data1, 5);
  printf("Sorted: ");
  print(Data1, 5);
  printf("Read 10 values: ");
  for (i = 0; i < 10; i++)
    scanf("%d", &Data2[i]);
  sort(Data2, 10);
  printf("\nSorted: ");
  print(Data2, 10);
  srand(time(NULL));
  for (i = 0; i < 30; i++)
    Data3[i] = rand() % 100;
  printf("Unsorted: ");
  print(Data3, 30);
  sort(Data3, 30);
  printf("Sorted: ");
  print(Data3, 30);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x5,%esi
  push   %r13
  push   %r12
  lea    D32(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  movabs $0xa00000005,%rax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r14
  lea    0x48(%rsp),%r13
  mov    %rbp,%rdi
  movl   $0x3,0x10(%rsp)
  mov    %r14,%rbx
  mov    %rax,(%rsp)
  movabs $0x600000002,%rax
  mov    %rax,0x8(%rsp)
  call   <sort@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%esi
  lea    D48(%rip),%rbp
  call   <print@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  nopl   (%rax)
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L4
  mov    $0xa,%esi
  mov    %r14,%rdi
  lea    0x50(%rsp),%rbp
  call   <sort@plt>
  lea    D39(%rip),%rdi
  mov    %rbp,%r13
  lea    0xc8(%rsp),%rbx
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %r14,%rdi
  call   <print@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L9:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r13)
  cmp    %rbx,%r13
  jne    L9
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%esi
  mov    %rbp,%rdi
  call   <print@plt>
  mov    $0x1e,%esi
  mov    %rbp,%rdi
  call   <sort@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1e,%esi
  mov    %rbp,%rdi
  call   <print@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D32
type_infered: string
name: unpack_data
arguments: data_label: D48
type_infered: string
name: unpack_data
arguments: data_label: D47
type_infered: string
name: unpack_data
arguments: data_label: D39
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D32: Sorted: 

tool: D48: %d

tool: D47: Read 10 values: 

tool: D39: 
Sorted: 

tool: D5: Unsorted: 

assistant: ```c
int main() {
  int Data1[5] = {5, 10, 2, 6, 3}, Data2[10], Data3[30], i;
  sort(Data1, 5);
  printf("Sorted: ");
  print(Data1, 5);
  printf("Read 10 values: ");
  for (i = 0; i < 10; i++)
    scanf("%d", &Data2[i]);
  sort(Data2, 10);
  printf("\nSorted: ");
  print(Data2, 10);
  srand(time(NULL));
  for (i = 0; i < 30; i++)
    Data3[i] = rand() % 100;
  printf("Unsorted: ");
  print(Data3, 30);
  sort(Data3, 30);
  printf("Sorted: ");
  print(Data3, 30);
  return 0;
}
```