ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<conf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ecx
  mov    %esi,%ebx
  mov    %rdx,%rbp
  lea    -0x1(%rsi),%esi
  test   %ebx,%ebx
  je     L33
  movslq %esi,%rax
  add    %rdx,%rax
  movslq %ebx,%rdx
  lea    -0x2(%rbp,%rdx,1),%rdx
  lea    -0x1(%rbx),%edi
  sub    %rdi,%rdx
L27:
  movb   $0x20,(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L27
L33:
  movslq %ecx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  lea    (%rdi,%rdi,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  lea    0x30(%rcx),%r12d
  movslq %esi,%rax
  test   %edi,%edi
  jne    L26
L35:
  mov    %r12b,0x0(%rbp,%rax,1)
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    %rbp,%rdx
  mov    $0x0,%eax
  call   <conf>
  cltq
  jmp    L35
```

assistant: ```c
conf(n, width, buf) char *buf;
{
  auto i, a;
  i = width;
  while (i--)
    buf[i] = ' ';
  buf[(a = n / 10) ? conf(a, --width, buf) : --width] = n % 10 + '0';
  return (++width);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<conf>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L7
  mov    %r13d,%eax
  movslq %r13d,%rdi
  mov    $0x20,%esi
  sub    %rax,%rdi
  lea    0x1(%rax),%rdx
  add    %rbp,%rdi
  call   <memset@plt>
L7:
  movslq %ebx,%rdi
  mov    %ebx,%eax
  imul   $0x66666667,%rdi,%rdi
  sar    $0x1f,%eax
  sar    $0x22,%rdi
  sub    %eax,%edi
  lea    (%rdi,%rdi,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  movslq %r13d,%rax
  add    $0x30,%ebx
  test   %edi,%edi
  jne    L18
L10:
  mov    %bl,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %rbp,%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  call   <conf>
  cltq
  jmp    L10
```

assistant: ```c
conf(n, width, buf) char *buf;
{
  auto i, a;
  i = width;
  while (i--)
    buf[i] = ' ';
  buf[(a = n / 10) ? conf(a, --width, buf) : --width] = n % 10 + '0';
  return (++width);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Get_Bits32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x20,%edi
  call   <Show_Bits@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <Flush_Buffer32@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int Get_Bits32() {
  unsigned int l;
  l = Show_Bits(32);
  Flush_Buffer32();
  return l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Get_Bits32>:
  endbr64
  push   %rbx
  mov    $0x20,%edi
  call   <Show_Bits@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <Flush_Buffer32@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int Get_Bits32() {
  unsigned int l;
  l = Show_Bits(32);
  Flush_Buffer32();
  return l;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Get_Bits32>:
  endbr64
  push   %r12
  mov    $0x20,%edi
  call   <Show_Bits@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <Flush_Buffer32@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned int Get_Bits32() {
  unsigned int l;
  l = Show_Bits(32);
  Flush_Buffer32();
  return l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Get_Bits32>:
  endbr64
  push   %r12
  mov    $0x20,%edi
  call   <Show_Bits@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <Flush_Buffer32@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned int Get_Bits32() {
  unsigned int l;
  l = Show_Bits(32);
  Flush_Buffer32();
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_start_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%r9
  lea    -0x1c(%rbp),%r8
  lea    -0x24(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  lea    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x10(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <get_racetrack_params@plt>
  add    $0x10,%rsp
  mov    -0x28(%rbp),%eax
  mov    -0x20(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x24(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void get_start_pos(int *start_x, int *start_y) {
  int x0, y0, xr_outer, yr_outer, xr_inner, yr_inner;
  double p;
  get_racetrack_params(&x0, &xr_outer, &xr_inner, &y0, &yr_outer, &yr_inner, &p);
  (*start_x) = x0 - xr_outer + (xr_outer - xr_inner) / 2;
  (*start_y) = y0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_start_pos>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  sub    $0x8,%rsp
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x2c(%rsp),%r9
  lea    0x24(%rsp),%r8
  call   <get_racetrack_params@plt>
  mov    0x20(%rsp),%ecx
  mov    %ecx,%edx
  sub    0x28(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    0x18(%rsp),%edx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    %eax,0x0(%rbp)
  mov    0x1c(%rsp),%eax
  mov    %eax,(%rbx)
  add    $0x10,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_start_pos(int *start_x, int *start_y) {
  int x0, y0, xr_outer, yr_outer, xr_inner, yr_inner;
  double p;
  get_racetrack_params(&x0, &xr_outer, &xr_inner, &y0, &yr_outer, &yr_inner, &p);
  (*start_x) = x0 - xr_outer + (xr_outer - xr_inner) / 2;
  (*start_y) = y0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_start_pos>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  sub    $0x8,%rsp
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x2c(%rsp),%r9
  lea    0x24(%rsp),%r8
  call   <get_racetrack_params@plt>
  mov    0x20(%rsp),%ecx
  mov    %ecx,%edx
  sub    0x28(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    0x18(%rsp),%edx
  sar    %eax
  sub    %ecx,%edx
  add    %edx,%eax
  mov    %eax,0x0(%rbp)
  mov    0x1c(%rsp),%eax
  mov    %eax,(%rbx)
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_start_pos(int *start_x, int *start_y) {
  int x0, y0, xr_outer, yr_outer, xr_inner, yr_inner;
  double p;
  get_racetrack_params(&x0, &xr_outer, &xr_inner, &y0, &yr_outer, &yr_inner, &p);
  (*start_x) = x0 - xr_outer + (xr_outer - xr_inner) / 2;
  (*start_y) = y0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_start_pos>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  sub    $0x8,%rsp
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x2c(%rsp),%r9
  lea    0x24(%rsp),%r8
  call   <get_racetrack_params@plt>
  mov    0x20(%rsp),%ecx
  mov    %ecx,%edx
  sub    0x28(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    0x18(%rsp),%edx
  sar    %eax
  sub    %ecx,%edx
  add    %edx,%eax
  mov    %eax,0x0(%rbp)
  mov    0x1c(%rsp),%eax
  mov    %eax,(%rbx)
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_start_pos(int *start_x, int *start_y) {
  int x0, y0, xr_outer, yr_outer, xr_inner, yr_inner;
  double p;
  get_racetrack_params(&x0, &xr_outer, &xr_inner, &y0, &yr_outer, &yr_inner, &p);
  (*start_x) = x0 - xr_outer + (xr_outer - xr_inner) / 2;
  (*start_y) = y0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2073692073696874,%rax
  movabs $0x6d20676e6f6c2061,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x676e6f6c202c6773,%rax
  movabs $0x206e656874207265,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x34,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <printStr@plt>
  movl   $0x1,-0x50(%rbp)
  movl   $0x2,-0x4c(%rbp)
  movl   $0x3,-0x48(%rbp)
  movl   $0x4,-0x44(%rbp)
  movl   $0x5,-0x40(%rbp)
  movl   $0x6,-0x3c(%rbp)
  movl   $0x7,-0x38(%rbp)
  movl   $0x8,-0x34(%rbp)
  mov    $0x20,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <printArr@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: sizeof(arr) = %d


assistant: ```c
int main() {
  char msg[] = "this is a long msg, longer then 4";
  printStr(msg);
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
  printf("sizeof(arr) = %d\n", sizeof(arr));
  printArr(arr, sizeof(arr) / sizeof(int));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x2073692073696874,%rax
  movabs $0x6d20676e6f6c2061,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x676e6f6c202c6773,%rax
  movabs $0x206e656874207265,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movw   $0x34,0x40(%rsp)
  lea    0x20(%rsp),%rdi
  call   <printStr@plt>
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  mov    $0x20,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  mov    $0x8,%esi
  call   <printArr@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: sizeof(arr) = %d


assistant: ```c
int main() {
  char msg[] = "this is a long msg, longer then 4";
  printStr(msg);
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
  printf("sizeof(arr) = %d\n", sizeof(arr));
  printArr(arr, sizeof(arr) / sizeof(int));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  movdqa D15(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    $0x34,%eax
  movaps %xmm0,0x20(%rsp)
  movdqa D14(%rip),%xmm0
  mov    %ax,0x40(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <printStr@plt>
  mov    $0x20,%esi
  movabs $0x200000001,%rax
  lea    D10(%rip),%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  call   <printf@plt>
  mov    %rsp,%rdi
  mov    $0x8,%esi
  call   <printArr@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: byte[16]
name: read_data
arguments: data_tag: D14
datatype: byte[16]
name: read_data
arguments: data_tag: D10
datatype: string

tool: {"D15": [0x74,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x6c,0x6f,0x6e,0x67,0x20,0x6d]}

tool: {"D14": [0x73,0x67,0x2c,0x20,0x6c,0x6f,0x6e,0x67,0x65,0x72,0x20,0x74,0x68,0x65,0x6e,0x20]}

tool: D10: sizeof(arr) = %d


assistant: ```c
int main() {
  char msg[] = "this is a long msg, longer then 4";
  printStr(msg);
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
  printf("sizeof(arr) = %d\n", sizeof(arr));
  printArr(arr, sizeof(arr) / sizeof(int));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  movdqa D25(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    $0x34,%eax
  movaps %xmm0,0x20(%rsp)
  movdqa D46(%rip),%xmm0
  mov    %ax,0x40(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <printStr@plt>
  movdqa D36(%rip),%xmm0
  mov    $0x20,%esi
  lea    D38(%rip),%rdi
  movaps %xmm0,(%rsp)
  movdqa D22(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %rsp,%rdi
  mov    $0x8,%esi
  call   <printArr@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
type: byte[16]
name: retrieve_data
arguments: data_label: D46
type: byte[16]
name: retrieve_data
arguments: data_label: D36
type: byte[16]
name: retrieve_data
arguments: data_label: D38
type: string
name: retrieve_data
arguments: data_label: D22
type: byte[16]

tool: {"D25": [0x74,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x6c,0x6f,0x6e,0x67,0x20,0x6d]}

tool: {"D46": [0x73,0x67,0x2c,0x20,0x6c,0x6f,0x6e,0x67,0x65,0x72,0x20,0x74,0x68,0x65,0x6e,0x20]}

tool: {"D36": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D38: sizeof(arr) = %d


tool: {"D22": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main() {
  char msg[] = "this is a long msg, longer then 4";
  printStr(msg);
  int arr[] = {1, 2, 3, 4, 5, 6, 7, 8};
  printf("sizeof(arr) = %d\n", sizeof(arr));
  printArr(arr, sizeof(arr) / sizeof(int));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ide_padstr8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L11:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L29
L31:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L29:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ide_padstr8(uint8_t *buf, int buf_size, const char *src) {
  int i;
  for (i = 0; i < buf_size; i++) {
    if (*src != '\0') {
      buf[i] = *src++;
    } else {
      buf[i] = ' ';
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ide_padstr8>:
  endbr64
  test   %esi,%esi
  jle    L41
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x1(%rdi,%rcx,1),%rsi
  jmp    L12
L25:
  movb   $0x20,(%rax)
L0:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L41
L12:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L25
  add    $0x1,%rdx
  mov    %cl,(%rax)
  jmp    L0
L41:
  ret
```

assistant: ```c
void ide_padstr8(uint8_t *buf, int buf_size, const char *src) {
  int i;
  for (i = 0; i < buf_size; i++) {
    if (*src != '\0') {
      buf[i] = *src++;
    } else {
      buf[i] = ' ';
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ide_padstr8>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %al,(%rdi)
  add    $0x1,%rdi
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  je     L15
L38:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L48
  mov    $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rcx,%rdi
  jne    L38
L15:
  ret
```

assistant: ```c
void ide_padstr8(uint8_t *buf, int buf_size, const char *src) {
  int i;
  for (i = 0; i < buf_size; i++) {
    if (*src != '\0') {
      buf[i] = *src++;
    } else {
      buf[i] = ' ';
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ide_padstr8>:
  endbr64
  test   %esi,%esi
  jle    L37
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %al,(%rdi)
  add    $0x1,%rdi
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  je     L37
L24:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L45
  mov    $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rcx,%rdi
  jne    L24
L37:
  ret
```

assistant: ```c
void ide_padstr8(uint8_t *buf, int buf_size, const char *src) {
  int i;
  for (i = 0; i < buf_size; i++) {
    if (*src != '\0') {
      buf[i] = *src++;
    } else {
      buf[i] = ' ';
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cfg_increment_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int cfg_increment_handler(const char *optarg, void *value_addr, const struct argconfig_options *opt) {
  (*((int *)value_addr))++;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cfg_increment_handler>:
  endbr64
  addl   $0x1,(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int cfg_increment_handler(const char *optarg, void *value_addr, const struct argconfig_options *opt) {
  (*((int *)value_addr))++;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cfg_increment_handler>:
  endbr64
  addl   $0x1,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int cfg_increment_handler(const char *optarg, void *value_addr, const struct argconfig_options *opt) {
  (*((int *)value_addr))++;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cfg_increment_handler>:
  endbr64
  addl   $0x1,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int cfg_increment_handler(const char *optarg, void *value_addr, const struct argconfig_options *opt) {
  (*((int *)value_addr))++;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<finn_mat4_look_at>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  mov    %rbp,%rdx
  mov    %r13,%rdi
  call   <finn_vec3_sub_vec3@plt>
  lea    0x14(%rsp),%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <finn_vec3_normalize@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <finn_vec3_cross@plt>
  lea    0x20(%rsp),%r14
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <finn_vec3_normalize@plt>
  lea    0x2c(%rsp),%r13
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <finn_vec3_cross@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <finn_vec3_dot@plt>
  movd   %xmm0,%r14d
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <finn_vec3_dot@plt>
  movd   %xmm0,%r13d
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <finn_vec3_dot@plt>
  movd   %xmm0,%ebp
  mov    %rbx,%rdi
  call   <finn_mat4_identity@plt>
  movss  0x20(%rsp),%xmm0
  movss  %xmm0,(%rbx)
  movss  0x24(%rsp),%xmm0
  movss  %xmm0,0x4(%rbx)
  movss  0x28(%rsp),%xmm0
  movss  %xmm0,0x8(%rbx)
  movss  0x2c(%rsp),%xmm0
  movss  %xmm0,0x10(%rbx)
  movss  0x30(%rsp),%xmm0
  movss  %xmm0,0x14(%rbx)
  movss  0x34(%rsp),%xmm0
  movss  %xmm0,0x18(%rbx)
  movss  D9(%rip),%xmm1
  movss  0x14(%rsp),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x20(%rbx)
  movss  0x18(%rsp),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x24(%rbx)
  movss  0x1c(%rsp),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x28(%rbx)
  mov    %r14d,0x30(%rbx)
  mov    %r13d,0x34(%rbx)
  mov    %ebp,0x38(%rbx)
  movl   $0x3f800000,0x3c(%rbx)
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x80]}

assistant: ```c
void finn_mat4_look_at(float *result, float *eye, float *at, float *up) {
  float temp[3];
  float f[3];
  finn_vec3_sub_vec3(temp, at, eye);
  finn_vec3_normalize(f, temp);
  float s[3];
  finn_vec3_cross(temp, f, up);
  finn_vec3_normalize(s, temp);
  float u[3];
  finn_vec3_cross(u, s, f);
  float s_eye_dot = finn_vec3_dot(s, eye);
  float u_eye_dot = finn_vec3_dot(u, eye);
  float f_eye_dot = finn_vec3_dot(f, eye);
  finn_mat4_identity(result);
  result[0] = s[0];
  result[1] = s[1];
  result[2] = s[2];
  result[4] = u[0];
  result[5] = u[1];
  result[6] = u[2];
  result[8] = -f[0];
  result[9] = -f[1];
  result[10] = -f[2];
  result[12] = s_eye_dot;
  result[13] = u_eye_dot;
  result[14] = f_eye_dot;
  result[15] = 1.0f;
}
```