ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D46(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  cmp    $0x7d0,%eax
  jle    L21
  sub    $0x7d1,%eax
  cmp    $0xbb7,%eax
  jbe    L19
  mulsd  D32(%rip),%xmm0
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  mulsd  D57(%rip),%xmm0
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L45
L21:
  mulsd  D24(%rip),%xmm0
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L45
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D46
data_type: string
name: retrieve_data
arguments: data_tag: D28
data_type: string
name: retrieve_data
arguments: data_tag: D32
data_type: f64
name: retrieve_data
arguments: data_tag: D22
data_type: string
name: retrieve_data
arguments: data_tag: D57
data_type: f64
name: retrieve_data
arguments: data_tag: D24
data_type: f64

tool: D46: Please enter your total sales to the nearest dollar.

tool: D28: %d

tool: D32: 0.2

tool: D22: %g


tool: D57: 0.15

tool: D24: 0.1

assistant: ```c
int main() {
  int sales;
  double commission;
  printf("Please enter your total sales to the nearest dollar.\n");
  scanf("%d", &sales);
  if (sales <= 2000) {
    commission = sales * 0.1;
    printf("%g\n", commission);
  } else if (sales > 2000 && sales <= 5000) {
    commission = sales * 0.15;
    printf("%g\n", commission);
  } else {
    commission = sales * 0.2;
    printf("%g\n", commission);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D75(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  cmp    $0x7d0,%eax
  jle    L11
  sub    $0x7d1,%eax
  cmp    $0xbb7,%eax
  jbe    L23
  mulsd  D25(%rip),%xmm0
  lea    D77(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  mulsd  D55(%rip),%xmm0
  lea    D77(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L46
L11:
  mulsd  D71(%rip),%xmm0
  lea    D77(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L46
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D75
datatype: string
name: unpack_data
arguments: tag: D50
datatype: string
name: unpack_data
arguments: tag: D25
datatype: f64
name: unpack_data
arguments: tag: D77
datatype: string
name: unpack_data
arguments: tag: D55
datatype: f64
name: unpack_data
arguments: tag: D71
datatype: f64

tool: D75: Please enter your total sales to the nearest dollar.

tool: D50: %d

tool: D25: 0.2

tool: D77: %g


tool: D55: 0.15

tool: D71: 0.1

assistant: ```c
int main() {
  int sales;
  double commission;
  printf("Please enter your total sales to the nearest dollar.\n");
  scanf("%d", &sales);
  if (sales <= 2000) {
    commission = sales * 0.1;
    printf("%g\n", commission);
  } else if (sales > 2000 && sales <= 5000) {
    commission = sales * 0.15;
    printf("%g\n", commission);
  } else {
    commission = sales * 0.2;
    printf("%g\n", commission);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x25(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x25(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  movl   $0x0,-0x30(%rbp)
  jmp    L10
L5:
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L37
L21:
  mov    -0x38(%rbp),%eax
  cltq
  movzbl -0x25(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <karti@plt>
  mov    %rax,%rbx
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x25(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <karti@plt>
  cmp    %rax,%rbx
  jle    L38
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x38(%rbp)
L38:
  addl   $0x1,-0x34(%rbp)
L37:
  mov    -0x34(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L21
  mov    -0x38(%rbp),%eax
  cltq
  movzbl -0x25(%rbp,%rax,1),%eax
  mov    %al,-0x39(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  movzbl -0x25(%rbp,%rax,1),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    %dl,-0x25(%rbp,%rax,1)
  mov    -0x30(%rbp),%eax
  cltq
  movzbl -0x39(%rbp),%edx
  mov    %dl,-0x25(%rbp,%rax,1)
  addl   $0x1,-0x30(%rbp)
L10:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L5
  lea    -0x25(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: vuvedi karti

assistant: ```c
int main() {
  char k, cards[13];
  int l, min, j, i;
  printf("vuvedi karti");
  gets(cards);
  l = strlen(cards) - 1;
  for (i = 0; i <= l; ++i) {
    min = i;
    for (j = i; j <= l; ++j)
      if (karti(cards[min]) > karti(cards[j]))
        min = j;
    k = cards[min];
    cards[min] = cards[i];
    cards[i] = k;
  }
  puts(cards);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x1b(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  sub    $0x1,%r14d
  js     L65
  lea    -0x1(%rax),%eax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r15d
  mov    %rbx,%r13
  jmp    L14
L32:
  movslq %r12d,%rax
  movsbl 0x1b(%rsp,%rax,1),%edi
  call   <karti@plt>
  mov    %rax,%rbp
  movsbl (%rbx,%r13,1),%edi
  call   <karti@plt>
  cmp    %rax,%rbp
  cmovg  %ebx,%r12d
  add    $0x1,%rbx
  cmp    %ebx,%r14d
  jge    L32
L23:
  movslq %r12d,%r12
  movzbl 0x1b(%rsp,%r12,1),%eax
  movzbl (%r15,%r13,1),%edx
  mov    %dl,0x1b(%rsp,%r12,1)
  mov    %al,(%r15,%r13,1)
  lea    0x1(%r15),%rax
  cmp    0x8(%rsp),%r15
  je     L65
  mov    %rax,%r15
L14:
  mov    %r15d,%r12d
  mov    %r15,%rbx
  cmp    %r15d,%r14d
  jge    L32
  jmp    L23
L65:
  lea    0x1b(%rsp),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: vuvedi karti

assistant: ```c
int main() {
  char k, cards[13];
  int l, min, j, i;
  printf("vuvedi karti");
  gets(cards);
  l = strlen(cards) - 1;
  for (i = 0; i <= l; ++i) {
    min = i;
    for (j = i; j <= l; ++j)
      if (karti(cards[min]) > karti(cards[j]))
        min = j;
    k = cards[min];
    cards[min] = cards[i];
    cards[i] = k;
  }
  puts(cards);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D3(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1b(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L31
  mov    %eax,%r13d
  mov    %eax,%eax
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L19:
  mov    %r14,%rbx
  movslq %r14d,%r15
  xchg   %ax,%ax
L23:
  movsbl 0x1b(%rsp,%r15,1),%edi
  call   <karti@plt>
  movsbl (%r12,%rbx,1),%edi
  mov    %rax,%rbp
  call   <karti@plt>
  mov    %rax,%r8
  movslq %ebx,%rax
  cmp    %r8,%rbp
  cmovg  %rax,%r15
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L23
  movzbl 0x1b(%rsp,%r15,1),%eax
  movzbl (%r12,%r14,1),%ecx
  mov    %cl,0x1b(%rsp,%r15,1)
  mov    %al,(%r12,%r14,1)
  lea    0x1(%r14),%rax
  cmp    0x8(%rsp),%r14
  je     L31
  mov    %rax,%r14
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: vuvedi karti

assistant: ```c
int main() {
  char k, cards[13];
  int l, min, j, i;
  printf("vuvedi karti");
  gets(cards);
  l = strlen(cards) - 1;
  for (i = 0; i <= l; ++i) {
    min = i;
    for (j = i; j <= l; ++j)
      if (karti(cards[min]) > karti(cards[j]))
        min = j;
    k = cards[min];
    cards[min] = cards[i];
    cards[i] = k;
  }
  puts(cards);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1b(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L22
  mov    %eax,%r13d
  mov    %eax,%eax
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L12:
  mov    %r14,%rbx
  movslq %r14d,%r15
  xchg   %ax,%ax
L49:
  movsbl 0x1b(%rsp,%r15,1),%edi
  call   <karti@plt>
  movsbl (%r12,%rbx,1),%edi
  mov    %rax,%rbp
  call   <karti@plt>
  mov    %rax,%r8
  movslq %ebx,%rax
  cmp    %r8,%rbp
  cmovg  %rax,%r15
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L49
  movzbl 0x1b(%rsp,%r15,1),%eax
  movzbl (%r12,%r14,1),%ecx
  mov    %cl,0x1b(%rsp,%r15,1)
  mov    %al,(%r12,%r14,1)
  lea    0x1(%r14),%rax
  cmp    0x8(%rsp),%r14
  je     L22
  mov    %rax,%r14
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: vuvedi karti

assistant: ```c
int main() {
  char k, cards[13];
  int l, min, j, i;
  printf("vuvedi karti");
  gets(cards);
  l = strlen(cards) - 1;
  for (i = 0; i <= l; ++i) {
    min = i;
    for (j = i; j <= l; ++j)
      if (karti(cards[min]) > karti(cards[j]))
        min = j;
    k = cards[min];
    cards[min] = cards[i];
    cards[i] = k;
  }
  puts(cards);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsbl -0x1(%rbp),%eax
  cmp    $0x43,%eax
  je     L4
  cmp    $0x43,%eax
  jg     L29
  cmp    $0x41,%eax
  je     L50
  cmp    $0x42,%eax
  je     L66
  jmp    L29
L50:
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L66:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L4:
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L29:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L64:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D54
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D57
type_infered: string
name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D58
type_infered: string
name: parse_data
arguments: data_label: D24
type_infered: string

tool: D54: Print a character: 

tool: D14: %c

tool: D57: Hello.


tool: D15: Happy Birthday.


tool: D58: Welcome.


tool: D24: Not a recognized character.

assistant: ```c
int main() {
  char myChar;
  printf("Print a character: ");
  scanf("%c", myChar);
  switch (myChar) {
  case 'A':
    printf("Hello.\n");
    break;
  case 'B':
    printf("Happy Birthday.\n");
    break;
  case 'C':
    printf("Welcome.\n");
    break;
  default:
    printf("Not a recognized character.");
    break;
  };
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string
name: extract_symbolic_data
arguments: label: D9
type_infered: string
name: extract_symbolic_data
arguments: label: D16
type_infered: string

tool: D5: Print a character: 

tool: D9: %c

tool: D16: Not a recognized character.

assistant: ```c
int main() {
  char myChar;
  printf("Print a character: ");
  scanf("%c", myChar);
  switch (myChar) {
  case 'A':
    printf("Hello.\n");
    break;
  case 'B':
    printf("Happy Birthday.\n");
    break;
  case 'C':
    printf("Welcome.\n");
    break;
  default:
    printf("Not a recognized character.");
    break;
  };
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D25
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string

tool: D22: Print a character: 

tool: D25: %c

tool: D14: Not a recognized character.

assistant: ```c
int main() {
  char myChar;
  printf("Print a character: ");
  scanf("%c", myChar);
  switch (myChar) {
  case 'A':
    printf("Hello.\n");
    break;
  case 'B':
    printf("Happy Birthday.\n");
    break;
  case 'C':
    printf("Welcome.\n");
    break;
  default:
    printf("Not a recognized character.");
    break;
  };
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D22
type_infered: string
name: unpack_data
arguments: tag: D19
type_infered: string

tool: D3: Print a character: 

tool: D22: %c

tool: D19: Not a recognized character.

assistant: ```c
int main() {
  char myChar;
  printf("Print a character: ");
  scanf("%c", myChar);
  switch (myChar) {
  case 'A':
    printf("Hello.\n");
    break;
  case 'B':
    printf("Happy Birthday.\n");
    break;
  case 'C':
    printf("Welcome.\n");
    break;
  default:
    printf("Not a recognized character.");
    break;
  };
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L32
L39:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L0:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L13:
  cmpl   $0x2,-0x14(%rbp)
  jle    L0
  addl   $0x1,-0x18(%rbp)
L32:
  cmpl   $0x6,-0x18(%rbp)
  jle    L39
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
data_type: string
name: disassemble_data
arguments: data_tag: D23
data_type: string
name: disassemble_data
arguments: data_tag: D26
data_type: string

tool: D27: dcusumkbn2

tool: D23: # c::%s:len=%d


tool: D26: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dcusumkbn2", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D6(%rip),%r15
  jmp    L25
L31:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L22
L25:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L39:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L39
  jmp    L31
L22:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D8
datatype: string
name: extract_symbolic_data
arguments: label: D22
datatype: string

tool: D6: dcusumkbn2

tool: D8: # c::%s:len=%d


tool: D22: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dcusumkbn2", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D9(%rip),%r15
  push   %r14
  lea    D23(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L10:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L18:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L18
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L10
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string
name: read_data
arguments: data_tag: D23
type_guessed: string
name: read_data
arguments: data_tag: D15
type_guessed: string

tool: D9: dcusumkbn2

tool: D23: # c::%s:len=%d


tool: D15: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dcusumkbn2", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```