ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pawnPromotion>:
  endbr64
  push   %r15
  lea    0x840(%rdi),%r15
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  mov    $0xfffffffffffe6ffe,%r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L89:
  movsbq 0xe7(%rbx),%rax
  cmpb   $0x50,0x0(%rbp,%rax,1)
  je     L23
L80:
  add    $0x108,%rbx
  cmp    %rbx,%r15
  je     L10
L59:
  movsbq (%rbx),%rax
  cmpb   $0x70,0x0(%rbp,%rax,1)
  jne    L89
  cs nopw 0x0(%rax,%rax,1)
L95:
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  lea    -0x62(%rax),%edx
  cmp    $0x10,%dl
  ja     L95
  bt     %rdx,%r13
  jb     L95
  movsbq (%rbx),%rdx
  add    $0x108,%rbx
  mov    %al,0x0(%rbp,%rdx,1)
  cmp    %rbx,%r15
  jne    L59
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  lea    -0x42(%rax),%edx
  cmp    $0x10,%dl
  ja     L23
  bt     %rdx,%r13
  jb     L23
  movsbq 0xe7(%rbx),%rdx
  mov    %al,0x0(%rbp,%rdx,1)
  jmp    L80
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D16
type: string

tool: D5: 
Choose what the pawn promotes to (Q, B, N or R): 

tool: D16: 
Choose what the pawn promotes to (q, b, n or r): 

assistant: ```c
void pawnPromotion(char grid[8][8][33], char pieceTranslator[33]) {
  int x;
  char promotion;
  for (x = 0; x < 8; ++x) {
    if (pieceTranslator[(int)grid[x][0][0]] == 'p') {
      do {
        printf("\nChoose what the pawn promotes to (q, b, n or r): ");
        promotion = getch();
      } while ((promotion != 'q') && (promotion != 'b') && (promotion != 'n') && (promotion != 'r'));
      pieceTranslator[(int)grid[x][0][0]] = promotion;
    } else if (pieceTranslator[(int)grid[x][7][0]] == 'P') {
      do {
        printf("\nChoose what the pawn promotes to (Q, B, N or R): ");
        promotion = getch();
      } while ((promotion != 'Q') && (promotion != 'B') && (promotion != 'N') && (promotion != 'R'));
      pieceTranslator[(int)grid[x][7][0]] = promotion;
    }
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<value_from_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0xf,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  movb   $0x0,-0x20(%rbp,%rax,1)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int value_from_fd(int fd) {
  char buf[16];
  int read_bytes;
  memset(buf, '\0', 16);
  read_bytes = read(fd, buf, 16 - 1);
  buf[read_bytes] = '\0';
  return atoi(buf);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<value_from_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0xf,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int value_from_fd(int fd) {
  char buf[16];
  int read_bytes;
  memset(buf, '\0', 16);
  read_bytes = read(fd, buf, 16 - 1);
  buf[read_bytes] = '\0';
  return atoi(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<value_from_fd>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    %edi,%r12d
  mov    $0x10,%edx
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0xf,%edx
  mov    %r12d,%edi
  mov    %rbp,%rsi
  call   <read@plt>
  mov    %rbp,%rdi
  cltq
  movb   $0x0,(%rsp,%rax,1)
  call   <atoi@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int value_from_fd(int fd) {
  char buf[16];
  int read_bytes;
  memset(buf, '\0', 16);
  read_bytes = read(fd, buf, 16 - 1);
  buf[read_bytes] = '\0';
  return atoi(buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<value_from_fd>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    %edi,%r12d
  mov    $0x10,%edx
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0xf,%edx
  mov    %r12d,%edi
  mov    %rbp,%rsi
  call   <read@plt>
  mov    %rbp,%rdi
  cltq
  movb   $0x0,(%rsp,%rax,1)
  call   <atoi@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int value_from_fd(int fd) {
  char buf[16];
  int read_bytes;
  memset(buf, '\0', 16);
  read_bytes = read(fd, buf, 16 - 1);
  buf[read_bytes] = '\0';
  return atoi(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <docomplex@plt>
  mov    $0x0,%eax
  call   <docomplexf@plt>
  mov    $0x0,%eax
  call   <docomplexl@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  docomplex();
  docomplexf();
  docomplexl();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <docomplex@plt>
  mov    $0x0,%eax
  call   <docomplexf@plt>
  mov    $0x0,%eax
  call   <docomplexl@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  docomplex();
  docomplexf();
  docomplexl();
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <docomplex@plt>
  xor    %eax,%eax
  call   <docomplexf@plt>
  xor    %eax,%eax
  call   <docomplexl@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  docomplex();
  docomplexf();
  docomplexl();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <docomplex@plt>
  xor    %eax,%eax
  call   <docomplexf@plt>
  xor    %eax,%eax
  call   <docomplexl@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  docomplex();
  docomplexf();
  docomplexl();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_strcpy(char *src, char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    src[i] = str[i];
    i++;
  }
  src[i] = '\0';
  return (src);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L16
  mov    $0x0,%edx
L18:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L18
L1:
  movb   $0x0,(%rax,%rdx,1)
  ret
L16:
  mov    $0x0,%edx
  jmp    L1
```

assistant: ```c
char *my_strcpy(char *src, char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    src[i] = str[i];
    i++;
  }
  src[i] = '\0';
  return (src);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L12
  xor    %edx,%edx
L8:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L8
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *my_strcpy(char *src, char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    src[i] = str[i];
    i++;
  }
  src[i] = '\0';
  return (src);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L15
  xor    %edx,%edx
L13:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L13
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *my_strcpy(char *src, char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    src[i] = str[i];
    i++;
  }
  src[i] = '\0';
  return (src);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<h2r_to_r2h_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0xc,-0x14(%rbp)
  ja     L12
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D1(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  cmpl   $0x0,-0x14(%rbp)
  jle    L6
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  jmp    L49
L6:
  mov    $0x0,%eax
L49:
  or     %eax,-0x4(%rbp)
  jmp    L12
  orl    $0xf000,-0x4(%rbp)
  jmp    L12
  orl    $0x1000,-0x4(%rbp)
  nop
L12:
  orl    $0x80000000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int h2r_to_r2h_bits(int cmd) {
  unsigned int mask = 0;
  switch (cmd) {
  case 12:
  case 1:
  case 2:
  case 3:
  case 4:
  case 6:
  case 7:
  case 8:
  case 10:
  case 11:
    mask |= (((cmd) > 0) ? (1 << ((cmd)-1)) : 0);
    break;
  case 5:
    mask |= ((((13) > 0) ? (1 << ((13) - 1)) : 0) | (((14) > 0) ? (1 << ((14) - 1)) : 0) | (((15) > 0) ? (1 << ((15) - 1)) : 0) | (((16) > 0) ? (1 << ((16) - 1)) : 0));
    break;
  case 9:
    mask |= (((13) > 0) ? (1 << ((13) - 1)) : 0);
    break;
  }
  return (mask |= (((32) > 0) ? (1 << ((32) - 1)) : 0));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<h2r_to_r2h_bits>:
  endbr64
  cmp    $0xc,%edi
  ja     L22
  mov    %edi,%eax
  lea    D6(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xf000,%eax
  jmp    L17
  mov    $0x0,%eax
  test   %edi,%edi
  jle    L17
  lea    -0x1(%rdi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  jmp    L17
  mov    $0x1000,%eax
L17:
  or     $0x80000000,%eax
  ret
L22:
  mov    $0x0,%eax
  jmp    L17
```

assistant: ```c
unsigned int h2r_to_r2h_bits(int cmd) {
  unsigned int mask = 0;
  switch (cmd) {
  case 12:
  case 1:
  case 2:
  case 3:
  case 4:
  case 6:
  case 7:
  case 8:
  case 10:
  case 11:
    mask |= (((cmd) > 0) ? (1 << ((cmd)-1)) : 0);
    break;
  case 5:
    mask |= ((((13) > 0) ? (1 << ((13) - 1)) : 0) | (((14) > 0) ? (1 << ((14) - 1)) : 0) | (((15) > 0) ? (1 << ((15) - 1)) : 0) | (((16) > 0) ? (1 << ((16) - 1)) : 0));
    break;
  case 9:
    mask |= (((13) > 0) ? (1 << ((13) - 1)) : 0);
    break;
  }
  return (mask |= (((32) > 0) ? (1 << ((32) - 1)) : 0));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<h2r_to_r2h_bits>:
  endbr64
  cmp    $0xc,%edi
  ja     L0
  lea    D1(%rip),%rdx
  mov    %edi,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    -0x1(%rdi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     $0x80000000,%eax
  ret
  mov    $0x80001000,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0x8000f000,%eax
  ret
L0:
  mov    $0x80000000,%eax
  ret
```

assistant: ```c
unsigned int h2r_to_r2h_bits(int cmd) {
  unsigned int mask = 0;
  switch (cmd) {
  case 12:
  case 1:
  case 2:
  case 3:
  case 4:
  case 6:
  case 7:
  case 8:
  case 10:
  case 11:
    mask |= (((cmd) > 0) ? (1 << ((cmd)-1)) : 0);
    break;
  case 5:
    mask |= ((((13) > 0) ? (1 << ((13) - 1)) : 0) | (((14) > 0) ? (1 << ((14) - 1)) : 0) | (((15) > 0) ? (1 << ((15) - 1)) : 0) | (((16) > 0) ? (1 << ((16) - 1)) : 0));
    break;
  case 9:
    mask |= (((13) > 0) ? (1 << ((13) - 1)) : 0);
    break;
  }
  return (mask |= (((32) > 0) ? (1 << ((32) - 1)) : 0));
}
```
user: Translate the below assembly code into C programming language:

```asm
<h2r_to_r2h_bits>:
  endbr64
  cmp    $0xc,%edi
  ja     L1
  lea    D7(%rip),%rdx
  mov    %edi,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    -0x1(%rdi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     $0x80000000,%eax
  ret
  mov    $0x80001000,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0x8000f000,%eax
  ret
L1:
  mov    $0x80000000,%eax
  ret
```

assistant: ```c
unsigned int h2r_to_r2h_bits(int cmd) {
  unsigned int mask = 0;
  switch (cmd) {
  case 12:
  case 1:
  case 2:
  case 3:
  case 4:
  case 6:
  case 7:
  case 8:
  case 10:
  case 11:
    mask |= (((cmd) > 0) ? (1 << ((cmd)-1)) : 0);
    break;
  case 5:
    mask |= ((((13) > 0) ? (1 << ((13) - 1)) : 0) | (((14) > 0) ? (1 << ((14) - 1)) : 0) | (((15) > 0) ? (1 << ((15) - 1)) : 0) | (((16) > 0) ? (1 << ((16) - 1)) : 0));
    break;
  case 9:
    mask |= (((13) > 0) ? (1 << ((13) - 1)) : 0);
    break;
  }
  return (mask |= (((32) > 0) ? (1 << ((32) - 1)) : 0));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L19:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L19
  cmpb   $0x0,-0x5(%rbp)
  jne    L4
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L4:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string

tool: D10: %c


tool: D14: \0

assistant: ```c
void print_str(char *s) {
  int i = 0;
  char c;
  while (c = *s++)
    printf("%c\n", c);
  if (c == '\0')
    printf("\\0\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L7
  lea    0x1(%rdi),%rbx
  lea    D3(%rip),%rbp
L19:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L19
L7:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D16
type: string

tool: D3: %c


tool: D16: \0

assistant: ```c
void print_str(char *s) {
  int i = 0;
  char c;
  while (c = *s++)
    printf("%c\n", c);
  if (c == '\0')
    printf("\\0\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_str>:
  endbr64
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L8
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L6:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L6
  add    $0x8,%rsp
  lea    D16(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <puts@plt>
  nopl   0x0(%rax)
L8:
  lea    D16(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D16
type: string

tool: D1: %c


tool: D16: \0

assistant: ```c
void print_str(char *s) {
  int i = 0;
  char c;
  while (c = *s++)
    printf("%c\n", c);
  if (c == '\0')
    printf("\\0\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_str>:
  endbr64
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L14
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L6:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L6
  add    $0x8,%rsp
  lea    D17(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <puts@plt>
  nopl   0x0(%rax)
L14:
  lea    D17(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D29: %c


tool: D17: \0

assistant: ```c
void print_str(char *s) {
  int i = 0;
  char c;
  while (c = *s++)
    printf("%c\n", c);
  if (c == '\0')
    printf("\\0\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  sub    $0x17447d68,%edx
  mov    %edx,%eax
  je     L8
  mov    %edx,%ecx
  shr    $0x10,%ecx
  movzwl %dx,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  mov    %cx,%ax
  movsbl %ah,%edx
  mov    %eax,%ecx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %cl,%ah
  movzbl %dl,%edx
  shl    $0x10,%edx
  and    $0xff00ffff,%eax
  or     %edx,%eax
L8:
  ror    $0xb,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = copy11;
          state[local1] -= state[0UL];
        } else {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy13 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy13;
        }
      } else {
        state[0UL] |= (state[local1] * state[0UL] & 31U) << 3UL;
        state[local1] |= (state[0UL] * state[0UL] & 15U) << 3UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 11U) | (state[0UL] << 21U);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x17447d68,%eax
  je     L3
  mov    %eax,%ecx
  movzwl %ax,%edx
  shl    $0x10,%ecx
  or     %ecx,%edx
  mov    %eax,%ecx
  shr    $0x10,%ecx
  mov    %cx,%dx
  mov    %al,%dh
  shr    $0x18,%eax
  shl    $0x10,%eax
  and    $0xff00ffff,%edx
  or     %edx,%eax
L3:
  ror    $0xb,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = copy11;
          state[local1] -= state[0UL];
        } else {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy13 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy13;
        }
      } else {
        state[0UL] |= (state[local1] * state[0UL] & 31U) << 3UL;
        state[local1] |= (state[0UL] * state[0UL] & 15U) << 3UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 11U) | (state[0UL] << 21U);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x17447d68,%eax
  je     L9
  mov    %eax,%edx
  rol    $0x10,%edx
  mov    %al,%dh
  shr    $0x18,%eax
  shl    $0x10,%eax
  and    $0xff00ffff,%edx
  or     %edx,%eax
L9:
  ror    $0xb,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = copy11;
          state[local1] -= state[0UL];
        } else {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy13 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy13;
        }
      } else {
        state[0UL] |= (state[local1] * state[0UL] & 31U) << 3UL;
        state[local1] |= (state[0UL] * state[0UL] & 15U) << 3UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 11U) | (state[0UL] << 21U);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L8
L19:
  subq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L8:
  cmpq   $0x0,-0x18(%rbp)
  je     L27
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L19
L27:
  cmpq   $0x0,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
bool matches(const char *a, const char *b, size_t n) {
  for (; n && *a == *b; --n, ++a, ++b)
    ;
  return !n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<matches>:
  endbr64
  mov    $0x0,%eax
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L11
L29:
  mov    %rdx,%rcx
  sub    %rax,%rcx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,(%rdi,%rax,1)
  jne    L11
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L29
  mov    $0x0,%ecx
L11:
  test   %rcx,%rcx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool matches(const char *a, const char *b, size_t n) {
  for (; n && *a == *b; --n, ++a, ++b)
    ;
  return !n;
}
```