ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x64726546,-0x18(%rbp)
  movw   $0x6c,-0x14(%rbp)
  movabs $0x6e616e6964726546,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x64,-0xa(%rbp)
  mov    $0x4,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D60
type_infered: string
name: parse_data
arguments: tag: D13
type_infered: string
name: parse_data
arguments: tag: D33
type_infered: string
name: parse_data
arguments: tag: D43
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string

tool: D11: the size of an int is %lu bytes


tool: D31: the size of iarray is %ld bytes


tool: D60: the number of ints in iarray is %ld


tool: D13: the size of a char is %ld bytes


tool: D33: the size of fname is %ld bytes


tool: D43: the number of chars in fname is %ld


tool: D5: the size of fname_array is %ld bytes


tool: D18: the number of chars in fname_array is %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int iarray[] = {1, 2, 3, 4};
  char fname[] = "Ferdl";
  char fname_array[] = {'F', 'e', 'r', 'd', 'i', 'n', 'a', 'n', 'd', '\0'};
  printf("the size of an int is %lu bytes\n", sizeof(int));
  printf("the size of iarray is %ld bytes\n", sizeof(iarray));
  printf("the number of ints in iarray is %ld\n", sizeof(iarray) / sizeof(int));
  printf("the size of a char is %ld bytes\n", sizeof(char));
  printf("the size of fname is %ld bytes\n", sizeof(fname));
  printf("the number of chars in fname is %ld\n", sizeof(fname) / sizeof(char));
  printf("the size of fname_array is %ld bytes\n", sizeof(fname_array));
  printf("the number of chars in fname_array is %ld\n", sizeof(fname_array) / sizeof(char));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D29
type_guessed: string
name: unpack_data
arguments: tag: D24
type_guessed: string
name: unpack_data
arguments: tag: D53
type_guessed: string
name: unpack_data
arguments: tag: D54
type_guessed: string
name: unpack_data
arguments: tag: D25
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D45
type_guessed: string
name: unpack_data
arguments: tag: D21
type_guessed: string

tool: D29: the size of an int is %lu bytes


tool: D24: the size of iarray is %ld bytes


tool: D53: the number of ints in iarray is %ld


tool: D54: the size of a char is %ld bytes


tool: D25: the size of fname is %ld bytes


tool: D0: the number of chars in fname is %ld


tool: D45: the size of fname_array is %ld bytes


tool: D21: the number of chars in fname_array is %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int iarray[] = {1, 2, 3, 4};
  char fname[] = "Ferdl";
  char fname_array[] = {'F', 'e', 'r', 'd', 'i', 'n', 'a', 'n', 'd', '\0'};
  printf("the size of an int is %lu bytes\n", sizeof(int));
  printf("the size of iarray is %ld bytes\n", sizeof(iarray));
  printf("the number of ints in iarray is %ld\n", sizeof(iarray) / sizeof(int));
  printf("the size of a char is %ld bytes\n", sizeof(char));
  printf("the size of fname is %ld bytes\n", sizeof(fname));
  printf("the number of chars in fname is %ld\n", sizeof(fname) / sizeof(char));
  printf("the size of fname_array is %ld bytes\n", sizeof(fname_array));
  printf("the number of chars in fname_array is %ld\n", sizeof(fname_array) / sizeof(char));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D65(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D62(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D74(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D65
data_type: string
name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D62
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string
name: extract_symbolic_data
arguments: data_tag: D74
data_type: string
name: extract_symbolic_data
arguments: data_tag: D48
data_type: string
name: extract_symbolic_data
arguments: data_tag: D25
data_type: string

tool: D65: the size of an int is %lu bytes


tool: D8: the size of iarray is %ld bytes


tool: D62: the number of ints in iarray is %ld


tool: D21: the size of a char is %ld bytes


tool: D6: the size of fname is %ld bytes


tool: D74: the number of chars in fname is %ld


tool: D48: the size of fname_array is %ld bytes


tool: D25: the number of chars in fname_array is %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int iarray[] = {1, 2, 3, 4};
  char fname[] = "Ferdl";
  char fname_array[] = {'F', 'e', 'r', 'd', 'i', 'n', 'a', 'n', 'd', '\0'};
  printf("the size of an int is %lu bytes\n", sizeof(int));
  printf("the size of iarray is %ld bytes\n", sizeof(iarray));
  printf("the number of ints in iarray is %ld\n", sizeof(iarray) / sizeof(int));
  printf("the size of a char is %ld bytes\n", sizeof(char));
  printf("the size of fname is %ld bytes\n", sizeof(fname));
  printf("the number of chars in fname is %ld\n", sizeof(fname) / sizeof(char));
  printf("the size of fname_array is %ld bytes\n", sizeof(fname_array));
  printf("the number of chars in fname_array is %ld\n", sizeof(fname_array) / sizeof(char));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D71(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D66(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D54
type_guessed: string
name: parse_data
arguments: tag: D58
type_guessed: string
name: parse_data
arguments: tag: D71
type_guessed: string
name: parse_data
arguments: tag: D66
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D35
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string

tool: D54: the size of an int is %lu bytes


tool: D58: the size of iarray is %ld bytes


tool: D71: the number of ints in iarray is %ld


tool: D66: the size of a char is %ld bytes


tool: D27: the size of fname is %ld bytes


tool: D3: the number of chars in fname is %ld


tool: D35: the size of fname_array is %ld bytes


tool: D36: the number of chars in fname_array is %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int iarray[] = {1, 2, 3, 4};
  char fname[] = "Ferdl";
  char fname_array[] = {'F', 'e', 'r', 'd', 'i', 'n', 'a', 'n', 'd', '\0'};
  printf("the size of an int is %lu bytes\n", sizeof(int));
  printf("the size of iarray is %ld bytes\n", sizeof(iarray));
  printf("the number of ints in iarray is %ld\n", sizeof(iarray) / sizeof(int));
  printf("the size of a char is %ld bytes\n", sizeof(char));
  printf("the size of fname is %ld bytes\n", sizeof(fname));
  printf("the number of chars in fname is %ld\n", sizeof(fname) / sizeof(char));
  printf("the size of fname_array is %ld bytes\n", sizeof(fname_array));
  printf("the number of chars in fname_array is %ld\n", sizeof(fname_array) / sizeof(char));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_dos_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x83,%edi
  call   <putCMD@plt>
  mov    $0x1b,%edi
  call   <putPT@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putPT_L@plt>
L6:
  jmp    L6
```

assistant: ```c
int _dos_exit(int retcode) {
  putCMD(0x83);
  putPT(0x1b);
  putPT_L(retcode);
  for (;;)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_dos_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x83,%edi
  call   <putCMD@plt>
  mov    $0x1b,%edi
  call   <putPT@plt>
  mov    %ebx,%edi
  call   <putPT_L@plt>
L0:
  jmp    L0
```

assistant: ```c
int _dos_exit(int retcode) {
  putCMD(0x83);
  putPT(0x1b);
  putPT_L(retcode);
  for (;;)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_dos_exit>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x83,%edi
  call   <putCMD@plt>
  mov    $0x1b,%edi
  call   <putPT@plt>
  mov    %ebp,%edi
  call   <putPT_L@plt>
L1:
  jmp    L1
```

assistant: ```c
int _dos_exit(int retcode) {
  putCMD(0x83);
  putPT(0x1b);
  putPT_L(retcode);
  for (;;)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_dos_exit>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x83,%edi
  call   <putCMD@plt>
  mov    $0x1b,%edi
  call   <putPT@plt>
  mov    %ebp,%edi
  call   <putPT_L@plt>
L3:
  jmp    L3
```

assistant: ```c
int _dos_exit(int retcode) {
  putCMD(0x83);
  putPT(0x1b);
  putPT_L(retcode);
  for (;;)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inet_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  movw   $0x0,-0x1a(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <dectoul@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0xffffffffffffffff,-0x10(%rbp)
  jne    L14
  movq   $0x0,-0x10(%rbp)
  jmp    L192
L179:
  cmpb   $0x2e,-0x1b(%rbp)
  jne    L34
  cmpl   $0x0,-0x14(%rbp)
  jne    L223
  mov    $0xffffffffffffffff,%rax
  jmp    L229
L223:
  cmpq   $0x18,-0x8(%rbp)
  jne    L197
  mov    $0xffffffffffffffff,%rax
  jmp    L229
L197:
  movzwl -0x1a(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    %edx,%ecx
  shl    %cl,%eax
  cltq
  or     %rax,-0x10(%rbp)
  addq   $0x8,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movw   $0x0,-0x1a(%rbp)
  jmp    L192
L34:
  cmpl   $0x3,-0x14(%rbp)
  jne    L44
  mov    $0xffffffffffffffff,%rax
  jmp    L229
L44:
  cmpl   $0x2,-0x14(%rbp)
  jne    L3
  cmpw   $0x0,-0x1a(%rbp)
  jne    L3
  mov    $0xffffffffffffffff,%rax
  jmp    L229
L3:
  addl   $0x1,-0x14(%rbp)
  cmpb   $0x2f,-0x1b(%rbp)
  jle    L0
  cmpb   $0x39,-0x1b(%rbp)
  jle    L146
L0:
  mov    $0xffffffffffffffff,%rax
  jmp    L229
L146:
  movzwl -0x1a(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movsbw -0x1b(%rbp),%ax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %ax,-0x1a(%rbp)
  cmpw   $0xff,-0x1a(%rbp)
  jbe    L192
  mov    $0xffffffffffffffff,%rax
  jmp    L229
L192:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1b(%rbp)
  cmpb   $0x0,-0x1b(%rbp)
  jne    L179
  cmpl   $0x0,-0x14(%rbp)
  jne    L51
  mov    $0xffffffffffffffff,%rax
  jmp    L229
L51:
  cmpq   $0x18,-0x8(%rbp)
  je     L167
  mov    $0xffffffffffffffff,%rax
  jmp    L229
L167:
  movzwl -0x1a(%rbp),%eax
  shl    $0x18,%eax
  cltq
  or     %rax,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%rax
L229:
  leave
  ret
```

assistant: ```c
unsigned long inet_addr(const char *ipstr) {
  int p = 0, cc = 0;
  char nc;
  unsigned long ip, s = 0;
  unsigned short v = 0;
  if ((ip = dectoul(ipstr)) == -1) {
    ip = 0;
    while ((nc = ipstr[p++])) {
      if (nc == '.') {
        if (!cc)
          return (-1);
        if (s == 24)
          return (-1);
        ip |= (v << s);
        s += 8;
        cc = 0;
        v = 0;
        continue;
      }
      if (cc == 3)
        return (-1);
      if (cc == 2)
        if (!v)
          return (-1);
      cc++;
      if ((nc < '0') || (nc > '9'))
        return (-1);
      if ((v = (v * 10) + (nc - '0')) > 255)
        return (-1);
    }
    if (!cc)
      return (-1);
    if (s != 24)
      return (-1);
    ip |= (v << 24);
  }
  return (ip);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inet_addr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <dectoul@plt>
  mov    %rax,%r8
  cmp    $0xffffffffffffffff,%rax
  je     L120
L139:
  mov    %r8,%rax
  pop    %rbx
  ret
L120:
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L139
  lea    0x1(%rbx),%rdi
  mov    $0x0,%eax
  mov    $0x0,%ecx
  mov    $0x0,%r10d
  mov    $0x0,%esi
  mov    $0x0,%r11d
  jmp    L133
L77:
  cmp    $0x18,%rcx
  je     L139
  test   %esi,%esi
  je     L139
  movzwl %ax,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%r10
  add    $0x8,%rcx
  mov    %r11d,%eax
  mov    $0x0,%esi
  jmp    L49
L129:
  add    $0x1,%esi
  lea    -0x30(%rdx),%r9d
  cmp    $0x9,%r9b
  ja     L139
  lea    (%rax,%rax,4),%eax
  movsbw %dl,%dx
  lea    -0x30(%rdx,%rax,2),%eax
  cmp    $0xff,%ax
  ja     L139
L49:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L76
L133:
  cmp    $0x2e,%dl
  je     L77
  cmp    $0x3,%esi
  je     L139
  test   %ax,%ax
  jne    L129
  cmp    $0x2,%esi
  jne    L129
  jmp    L139
L76:
  cmp    $0x18,%rcx
  jne    L139
  test   %esi,%esi
  je     L139
  shl    $0x18,%eax
  cltq
  or     %r10,%rax
  mov    %rax,%r8
  jmp    L139
```

assistant: ```c
unsigned long inet_addr(const char *ipstr) {
  int p = 0, cc = 0;
  char nc;
  unsigned long ip, s = 0;
  unsigned short v = 0;
  if ((ip = dectoul(ipstr)) == -1) {
    ip = 0;
    while ((nc = ipstr[p++])) {
      if (nc == '.') {
        if (!cc)
          return (-1);
        if (s == 24)
          return (-1);
        ip |= (v << s);
        s += 8;
        cc = 0;
        v = 0;
        continue;
      }
      if (cc == 3)
        return (-1);
      if (cc == 2)
        if (!v)
          return (-1);
      cc++;
      if ((nc < '0') || (nc > '9'))
        return (-1);
      if ((v = (v * 10) + (nc - '0')) > 255)
        return (-1);
    }
    if (!cc)
      return (-1);
    if (s != 24)
      return (-1);
    ip |= (v << 24);
  }
  return (ip);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inet_addr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <dectoul@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L43
L37:
  pop    %rbx
  ret
  nopl   (%rax)
L43:
  movsbw (%rbx),%si
  test   %sil,%sil
  je     L37
  lea    0x1(%rbx),%rdi
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r10d,%r10d
  xor    %r8d,%r8d
  jmp    L22
  nopl   0x0(%rax)
L92:
  cmp    $0x3,%r8d
  je     L37
  cmp    $0x2,%r8d
  jne    L94
  test   %dx,%dx
  je     L37
L94:
  lea    -0x30(%rsi),%r9d
  add    $0x1,%r8d
  cmp    $0x9,%r9b
  ja     L37
  lea    (%rdx,%rdx,4),%edx
  lea    -0x30(%rsi,%rdx,2),%edx
  cmp    $0xff,%dx
  ja     L37
L147:
  movsbw (%rdi),%si
  add    $0x1,%rdi
  test   %sil,%sil
  je     L84
L22:
  cmp    $0x2e,%sil
  jne    L92
  cmp    $0x18,%rcx
  je     L37
  test   %r8d,%r8d
  je     L37
  movzwl %dx,%edx
  xor    %r8d,%r8d
  shl    %cl,%edx
  add    $0x8,%rcx
  movslq %edx,%rdx
  or     %rdx,%r10
  xor    %edx,%edx
  jmp    L147
  nopl   0x0(%rax)
L84:
  test   %r8d,%r8d
  je     L37
  cmp    $0x18,%rcx
  jne    L37
  shl    $0x18,%edx
  pop    %rbx
  movslq %edx,%rax
  or     %r10,%rax
  ret
```

assistant: ```c
unsigned long inet_addr(const char *ipstr) {
  int p = 0, cc = 0;
  char nc;
  unsigned long ip, s = 0;
  unsigned short v = 0;
  if ((ip = dectoul(ipstr)) == -1) {
    ip = 0;
    while ((nc = ipstr[p++])) {
      if (nc == '.') {
        if (!cc)
          return (-1);
        if (s == 24)
          return (-1);
        ip |= (v << s);
        s += 8;
        cc = 0;
        v = 0;
        continue;
      }
      if (cc == 3)
        return (-1);
      if (cc == 2)
        if (!v)
          return (-1);
      cc++;
      if ((nc < '0') || (nc > '9'))
        return (-1);
      if ((v = (v * 10) + (nc - '0')) > 255)
        return (-1);
    }
    if (!cc)
      return (-1);
    if (s != 24)
      return (-1);
    ip |= (v << 24);
  }
  return (ip);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inet_addr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <dectoul@plt>
  mov    %rax,%r10
  cmp    $0xffffffffffffffff,%rax
  je     L132
L105:
  mov    %r10,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L132:
  movsbw (%rbx),%dx
  test   %dl,%dl
  je     L105
  lea    0x1(%rbx),%rsi
  xor    %eax,%eax
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  xor    %edi,%edi
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L57:
  cmp    $0x3,%edi
  je     L105
  cmp    $0x2,%edi
  sete   %r8b
  test   %ax,%ax
  sete   %r11b
  and    %r11b,%r8b
  jne    L105
  lea    -0x30(%rdx),%r11d
  add    $0x1,%edi
  cmp    $0x9,%r11b
  ja     L105
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rdx,%rax,2),%eax
  cmp    $0xff,%ax
  ja     L105
L19:
  movsbw (%rsi),%dx
  add    $0x1,%rsi
  test   %dl,%dl
  je     L46
L65:
  cmp    $0x2e,%dl
  jne    L57
  cmp    $0x18,%rcx
  je     L105
  test   %edi,%edi
  je     L105
  movzwl %ax,%eax
  mov    $0x1,%r8d
  xor    %edi,%edi
  shl    %cl,%eax
  add    $0x8,%rcx
  cltq
  or     %rax,%r9
  xor    %eax,%eax
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L46:
  cmp    $0x18,%rcx
  jne    L105
  test   %r8b,%r8b
  jne    L105
  shl    $0x18,%eax
  cltq
  or     %r9,%rax
  mov    %rax,%r10
  jmp    L105
```

assistant: ```c
unsigned long inet_addr(const char *ipstr) {
  int p = 0, cc = 0;
  char nc;
  unsigned long ip, s = 0;
  unsigned short v = 0;
  if ((ip = dectoul(ipstr)) == -1) {
    ip = 0;
    while ((nc = ipstr[p++])) {
      if (nc == '.') {
        if (!cc)
          return (-1);
        if (s == 24)
          return (-1);
        ip |= (v << s);
        s += 8;
        cc = 0;
        v = 0;
        continue;
      }
      if (cc == 3)
        return (-1);
      if (cc == 2)
        if (!v)
          return (-1);
      cc++;
      if ((nc < '0') || (nc > '9'))
        return (-1);
      if ((v = (v * 10) + (nc - '0')) > 255)
        return (-1);
    }
    if (!cc)
      return (-1);
    if (s != 24)
      return (-1);
    ip |= (v << 24);
  }
  return (ip);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_radix_sort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%ebp
  test   %edx,%edx
  jle    L67
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
L86:
  mov    (%rax),%edx
  cmp    %edx,%ebp
  cmovl  %edx,%ebp
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L86
L67:
  test   %ebp,%ebp
  jle    L88
  lea    -0x1(%r12),%r11d
  lea    0x4(%r8,%r11,4),%rbx
  mov    $0x1,%ecx
  lea    0x28(%rsp),%r10
  lea    -0x1(%r12),%r13d
  jmp    L26
L115:
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  test   %eax,%eax
  jle    L88
L26:
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  test   %r12d,%r12d
  jle    L28
  mov    %r8,%rsi
L38:
  mov    (%rsi),%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edi
  add    %edi,%edi
  sub    %edi,%eax
  movslq %eax,%rdx
  addl   $0x1,(%rsp,%rdx,4)
  add    $0x4,%rsi
  cmp    %rbx,%rsi
  jne    L38
L28:
  lea    0x4(%rsp),%rax
L54:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r10,%rax
  jne    L54
  test   %r13d,%r13d
  js     L134
  movslq %r13d,%rsi
L124:
  mov    (%r8,%rsi,4),%edi
  mov    %edi,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r14d
  sar    $0x1f,%r14d
  sub    %r14d,%edx
  lea    (%rdx,%rdx,4),%r14d
  add    %r14d,%r14d
  sub    %r14d,%eax
  movslq %eax,%rdx
  mov    (%rsp,%rdx,4),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp,%rdx,4)
  cltq
  mov    %edi,(%r9,%rax,4)
  sub    $0x1,%rsi
  test   %esi,%esi
  jns    L124
L134:
  test   %r12d,%r12d
  jle    L115
  mov    $0x0,%eax
L73:
  mov    (%r9,%rax,4),%edx
  mov    %edx,(%r8,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %r11,%rdx
  jne    L73
  jmp    L115
L88:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L87:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _radix_sort(int *vet, int *sorted, int s) {
  int i;
  int max = vet[0];
  int exp = 1;
  for (i = 0; i < s; i++)
    if (vet[i] > max)
      max = vet[i];
  while (max / exp > 0) {
    int buckets[10] = {0};
    for (i = 0; i < s; i++)
      buckets[(vet[i] / exp) % 10]++;
    for (i = 1; i < 10; i++)
      buckets[i] += buckets[i - 1];
    for (i = s - 1; i >= 0; i--)
      sorted[--buckets[(vet[i] / exp) % 10]] = vet[i];
    for (i = 0; i < s; i++)
      vet[i] = sorted[i];
    exp *= 10;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_c_language>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L3
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
L3:
  mov    $0x1,%eax
  jmp    L13
L9:
  mov    $0x0,%eax
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D14
datatype: string

tool: D12: c

tool: D14: cpp

assistant: ```c
int is_c_language(char *project_type) {
  if ((strcmp(project_type, "c") == 0) || (strcmp(project_type, "cpp") == 0)) {
    return 1;
  }
  return 0;
}
```