ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<IniDgy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x28f,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x1,%esi
  mov    $0x280,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x80,%esi
  mov    $0x281,%edi
  call   <RegWriteA_LC898122AF@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x281,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl -0x9(%rbp),%eax
  or     $0x4,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x281,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x6a,%esi
  mov    $0x283,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x28a,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x282,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%edi
  call   <AccWit@plt>
  mov    $0x1b,%esi
  mov    $0x283,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x18,%esi
  mov    $0x28a,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x282,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%edi
  call   <AccWit@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x281,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0xfffffffb,%eax
  mov    %eax,%esi
  mov    $0x281,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x7c,%esi
  mov    $0x28b,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x0,%eax
  call   <GyOutSignal@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void IniDgy(void) {
  unsigned char UcGrini;
  RegWriteA_LC898122AF(0x028F, 0x01);
  RegWriteA_LC898122AF(0x0280, 0x01);
  RegWriteA_LC898122AF(0x0281, 0x80);
  RegReadA_LC898122AF(0x0281, &UcGrini);
  RegWriteA_LC898122AF(0x0281, (UcGrini | 0x04));
  RegWriteA_LC898122AF(0x0283, 0x6A);
  RegWriteA_LC898122AF(0x028A, 0x10);
  RegWriteA_LC898122AF(0x0282, 0x10);
  AccWit(0x10);
  RegWriteA_LC898122AF(0x0283, 0x1B);
  RegWriteA_LC898122AF(0x028A, (3 << 3));
  RegWriteA_LC898122AF(0x0282, 0x10);
  AccWit(0x10);
  RegReadA_LC898122AF(0x0281, &UcGrini);
  RegWriteA_LC898122AF(0x0281, (UcGrini & ~0x04));
  RegWriteA_LC898122AF(0x028B, 0x7C);
  GyOutSignal();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<IniDgy>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x28f,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x1,%esi
  mov    $0x280,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x80,%esi
  mov    $0x281,%edi
  call   <RegWriteA_LC898122AF@plt>
  lea    0x7(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0x281,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl 0x7(%rsp),%esi
  or     $0x4,%esi
  movzbl %sil,%esi
  mov    $0x281,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x6a,%esi
  mov    $0x283,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x28a,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x282,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%edi
  call   <AccWit@plt>
  mov    $0x1b,%esi
  mov    $0x283,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x18,%esi
  mov    $0x28a,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x282,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%edi
  call   <AccWit@plt>
  mov    %rbx,%rsi
  mov    $0x281,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl 0x7(%rsp),%esi
  and    $0xfffffffb,%esi
  mov    $0x281,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x7c,%esi
  mov    $0x28b,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x0,%eax
  call   <GyOutSignal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void IniDgy(void) {
  unsigned char UcGrini;
  RegWriteA_LC898122AF(0x028F, 0x01);
  RegWriteA_LC898122AF(0x0280, 0x01);
  RegWriteA_LC898122AF(0x0281, 0x80);
  RegReadA_LC898122AF(0x0281, &UcGrini);
  RegWriteA_LC898122AF(0x0281, (UcGrini | 0x04));
  RegWriteA_LC898122AF(0x0283, 0x6A);
  RegWriteA_LC898122AF(0x028A, 0x10);
  RegWriteA_LC898122AF(0x0282, 0x10);
  AccWit(0x10);
  RegWriteA_LC898122AF(0x0283, 0x1B);
  RegWriteA_LC898122AF(0x028A, (3 << 3));
  RegWriteA_LC898122AF(0x0282, 0x10);
  AccWit(0x10);
  RegReadA_LC898122AF(0x0281, &UcGrini);
  RegWriteA_LC898122AF(0x0281, (UcGrini & ~0x04));
  RegWriteA_LC898122AF(0x028B, 0x7C);
  GyOutSignal();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<IniDgy>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    $0x28f,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x1,%esi
  mov    $0x280,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x80,%esi
  mov    $0x281,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    %rbp,%rsi
  mov    $0x281,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl 0x7(%rsp),%esi
  mov    $0x281,%edi
  or     $0x4,%esi
  movzbl %sil,%esi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x6a,%esi
  mov    $0x283,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x28a,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x282,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%edi
  call   <AccWit@plt>
  mov    $0x1b,%esi
  mov    $0x283,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x18,%esi
  mov    $0x28a,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x282,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%edi
  call   <AccWit@plt>
  mov    %rbp,%rsi
  mov    $0x281,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl 0x7(%rsp),%esi
  mov    $0x281,%edi
  and    $0xfffffffb,%esi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x7c,%esi
  mov    $0x28b,%edi
  call   <RegWriteA_LC898122AF@plt>
  xor    %eax,%eax
  call   <GyOutSignal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void IniDgy(void) {
  unsigned char UcGrini;
  RegWriteA_LC898122AF(0x028F, 0x01);
  RegWriteA_LC898122AF(0x0280, 0x01);
  RegWriteA_LC898122AF(0x0281, 0x80);
  RegReadA_LC898122AF(0x0281, &UcGrini);
  RegWriteA_LC898122AF(0x0281, (UcGrini | 0x04));
  RegWriteA_LC898122AF(0x0283, 0x6A);
  RegWriteA_LC898122AF(0x028A, 0x10);
  RegWriteA_LC898122AF(0x0282, 0x10);
  AccWit(0x10);
  RegWriteA_LC898122AF(0x0283, 0x1B);
  RegWriteA_LC898122AF(0x028A, (3 << 3));
  RegWriteA_LC898122AF(0x0282, 0x10);
  AccWit(0x10);
  RegReadA_LC898122AF(0x0281, &UcGrini);
  RegWriteA_LC898122AF(0x0281, (UcGrini & ~0x04));
  RegWriteA_LC898122AF(0x028B, 0x7C);
  GyOutSignal();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<IniDgy>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    $0x28f,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x1,%esi
  mov    $0x280,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x80,%esi
  mov    $0x281,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    %rbp,%rsi
  mov    $0x281,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl 0x7(%rsp),%esi
  mov    $0x281,%edi
  or     $0x4,%esi
  movzbl %sil,%esi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x6a,%esi
  mov    $0x283,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x28a,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x282,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%edi
  call   <AccWit@plt>
  mov    $0x1b,%esi
  mov    $0x283,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x18,%esi
  mov    $0x28a,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%esi
  mov    $0x282,%edi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x10,%edi
  call   <AccWit@plt>
  mov    %rbp,%rsi
  mov    $0x281,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl 0x7(%rsp),%esi
  mov    $0x281,%edi
  and    $0xfffffffb,%esi
  call   <RegWriteA_LC898122AF@plt>
  mov    $0x7c,%esi
  mov    $0x28b,%edi
  call   <RegWriteA_LC898122AF@plt>
  xor    %eax,%eax
  call   <GyOutSignal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void IniDgy(void) {
  unsigned char UcGrini;
  RegWriteA_LC898122AF(0x028F, 0x01);
  RegWriteA_LC898122AF(0x0280, 0x01);
  RegWriteA_LC898122AF(0x0281, 0x80);
  RegReadA_LC898122AF(0x0281, &UcGrini);
  RegWriteA_LC898122AF(0x0281, (UcGrini | 0x04));
  RegWriteA_LC898122AF(0x0283, 0x6A);
  RegWriteA_LC898122AF(0x028A, 0x10);
  RegWriteA_LC898122AF(0x0282, 0x10);
  AccWit(0x10);
  RegWriteA_LC898122AF(0x0283, 0x1B);
  RegWriteA_LC898122AF(0x028A, (3 << 3));
  RegWriteA_LC898122AF(0x0282, 0x10);
  AccWit(0x10);
  RegReadA_LC898122AF(0x0281, &UcGrini);
  RegWriteA_LC898122AF(0x0281, (UcGrini & ~0x04));
  RegWriteA_LC898122AF(0x028B, 0x7C);
  GyOutSignal();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L24
L19:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rdx
  cmpl   $0x1,-0x24(%rbp)
  jg     L31
  lea    D12(%rip),%rax
  jmp    L36
L31:
  lea    D15(%rip),%rax
L36:
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L24:
  cmpl   $0x2,-0x24(%rbp)
  jle    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D10
type_infered: string
name: parse_data
arguments: label: D35
type_infered: string
name: parse_data
arguments: label: D27
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D11: Reykjavik

tool: D10: Akureyri

tool: D35: Bolungarvik

tool: D27: These are few Icelandic cities: 

tool: D12: %s


tool: D15: %s

assistant: ```c
void main(int argc, char argv[]) {
  char *icelandic_cities[] = {"Reykjavik", "Akureyri", "Bolungarvik"};
  printf("These are few Icelandic cities: \n");
  for (int i = 0; i < 3; i++) {
    printf(i < 2 ? "%s\n" : "%s", icelandic_cities[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D42(%rip),%rdi
  call   <puts@plt>
  lea    D44(%rip),%rdi
  call   <puts@plt>
  lea    D43(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rsi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D42
type_infered: string
name: read_data
arguments: label: D44
type_infered: string
name: read_data
arguments: label: D43
type_infered: string
name: read_data
arguments: label: D8
type_infered: string
name: read_data
arguments: label: D34
type_infered: string

tool: D42: These are few Icelandic cities: 

tool: D44: Reykjavik

tool: D43: Akureyri

tool: D8: Bolungarvik

tool: D34: %s

assistant: ```c
void main(int argc, char argv[]) {
  char *icelandic_cities[] = {"Reykjavik", "Akureyri", "Bolungarvik"};
  printf("These are few Icelandic cities: \n");
  for (int i = 0; i < 3; i++) {
    printf(i < 2 ? "%s\n" : "%s", icelandic_cities[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D13(%rip),%rdi
  lea    D34(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1070 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D47
type_infered: string
name: parse_data
arguments: data_label: D20
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D34
type_infered: string

tool: D2: These are few Icelandic cities: 

tool: D47: Reykjavik

tool: D20: Akureyri

tool: D13: %s

tool: D34: Bolungarvik

assistant: ```c
void main(int argc, char argv[]) {
  char *icelandic_cities[] = {"Reykjavik", "Akureyri", "Bolungarvik"};
  printf("These are few Icelandic cities: \n");
  for (int i = 0; i < 3; i++) {
    printf(i < 2 ? "%s\n" : "%s", icelandic_cities[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D43(%rip),%rdi
  call   <puts@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  lea    D23(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1070 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D43
data_type: string
name: read_data
arguments: data_tag: D33
data_type: string
name: read_data
arguments: data_tag: D34
data_type: string
name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D23
data_type: string

tool: D43: These are few Icelandic cities: 

tool: D33: Reykjavik

tool: D34: Akureyri

tool: D12: %s

tool: D23: Bolungarvik

assistant: ```c
void main(int argc, char argv[]) {
  char *icelandic_cities[] = {"Reykjavik", "Akureyri", "Bolungarvik"};
  printf("These are few Icelandic cities: \n");
  for (int i = 0; i < 3; i++) {
    printf(i < 2 ? "%s\n" : "%s", icelandic_cities[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_port_foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D12(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D6(%rip)
  mov    D6(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_port_foo(void) {
  static int counter = 10000;
  return ++counter;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_port_foo>:
  endbr64
  mov    D19(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D6(%rip)
  ret
```

assistant: ```c
int get_port_foo(void) {
  static int counter = 10000;
  return ++counter;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_port_foo>:
  endbr64
  mov    D14(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D13(%rip)
  ret
```

assistant: ```c
int get_port_foo(void) {
  static int counter = 10000;
  return ++counter;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_port_foo>:
  endbr64
  mov    D15(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D5(%rip)
  ret
```

assistant: ```c
int get_port_foo(void) {
  static int counter = 10000;
  return ++counter;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x1f,-0x4(%rbp)
  jbe    L8
  movzbl -0x4(%rbp),%eax
  test   %al,%al
  js     L8
  movzbl -0x4(%rbp),%eax
  jmp    L29
L8:
  mov    $0x3f,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
char xx(unsigned char c) {
  if (c >= 32 && c < 128)
    return c;
  return '?';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xx>:
  endbr64
  lea    -0x20(%rdi),%eax
  cmp    $0x60,%al
  mov    $0x3f,%eax
  cmovb  %edi,%eax
  ret
```

assistant: ```c
char xx(unsigned char c) {
  if (c >= 32 && c < 128)
    return c;
  return '?';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xx>:
  endbr64
  lea    -0x20(%rdi),%eax
  cmp    $0x60,%al
  mov    $0x3f,%eax
  cmovb  %edi,%eax
  ret
```

assistant: ```c
char xx(unsigned char c) {
  if (c >= 32 && c < 128)
    return c;
  return '?';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xx>:
  endbr64
  lea    -0x20(%rdi),%eax
  cmp    $0x60,%al
  mov    $0x3f,%eax
  cmovb  %edi,%eax
  ret
```

assistant: ```c
char xx(unsigned char c) {
  if (c >= 32 && c < 128)
    return c;
  return '?';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wildcard_matchn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L77
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L81
  mov    $0x1,%eax
  jmp    L82
L81:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L106
  mov    $0x0,%eax
  jmp    L82
L106:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L77:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L100
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L100
  cmpl   $0x0,-0x14(%rbp)
  jne    L24
L100:
  cmpl   $0x0,-0x14(%rbp)
  je     L45
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L3
L45:
  mov    $0x1,%eax
  jmp    L82
L3:
  mov    $0x0,%eax
L82:
  pop    %rbp
  ret
```

assistant: ```c
int wildcard_matchn(const char *wildcard, const char *match, int num) {
  while (*wildcard && *match && num) {
    if (*wildcard == '*')
      return 1;
    if (*wildcard != *match)
      return 0;
    ++wildcard;
    ++match;
    --num;
  }
  return (!num) || (*wildcard == *match);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wildcard_matchn>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L69
  movzbl (%rsi),%ecx
  test   %edx,%edx
  je     L69
  test   %cl,%cl
  je     L69
L49:
  cmp    $0x2a,%al
  je     L21
  cmp    %cl,%al
  jne    L71
  add    $0x1,%rdi
  add    $0x1,%rsi
  sub    $0x1,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L69
  movzbl (%rsi),%ecx
  test   %edx,%edx
  je     L69
  test   %cl,%cl
  jne    L49
L69:
  mov    $0x1,%ecx
  test   %edx,%edx
  je     L30
  cmp    %al,(%rsi)
  sete   %cl
  movzbl %cl,%ecx
L30:
  mov    %ecx,%eax
  ret
L21:
  mov    $0x1,%ecx
  jmp    L30
L71:
  mov    $0x0,%ecx
  jmp    L30
```

assistant: ```c
int wildcard_matchn(const char *wildcard, const char *match, int num) {
  while (*wildcard && *match && num) {
    if (*wildcard == '*')
      return 1;
    if (*wildcard != *match)
      return 0;
    ++wildcard;
    ++match;
    --num;
  }
  return (!num) || (*wildcard == *match);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wildcard_matchn>:
  endbr64
  jmp    L68
  cs nopw 0x0(%rax,%rax,1)
L49:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L20
  test   %edx,%edx
  je     L5
  cmp    $0x2a,%al
  je     L5
  cmp    %al,%cl
  jne    L19
  add    $0x1,%rdi
  add    $0x1,%rsi
  sub    $0x1,%edx
L68:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L49
L20:
  mov    $0x1,%r8d
  test   %edx,%edx
  je     L7
  xor    %r8d,%r8d
  cmp    %al,(%rsi)
  sete   %r8b
L7:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int wildcard_matchn(const char *wildcard, const char *match, int num) {
  while (*wildcard && *match && num) {
    if (*wildcard == '*')
      return 1;
    if (*wildcard != *match)
      return 0;
    ++wildcard;
    ++match;
    --num;
  }
  return (!num) || (*wildcard == *match);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wildcard_matchn>:
  endbr64
  jmp    L62
  cs nopw 0x0(%rax,%rax,1)
L23:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L54
  test   %edx,%edx
  je     L27
  cmp    $0x2a,%al
  je     L27
  cmp    %al,%cl
  jne    L13
  add    $0x1,%rdi
  add    $0x1,%rsi
  sub    $0x1,%edx
L62:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L23
L54:
  mov    $0x1,%r8d
  test   %edx,%edx
  je     L12
  xor    %r8d,%r8d
  cmp    %al,(%rsi)
  sete   %r8b
L12:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L27:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int wildcard_matchn(const char *wildcard, const char *match, int num) {
  while (*wildcard && *match && num) {
    if (*wildcard == '*')
      return 1;
    if (*wildcard != *match)
      return 0;
    ++wildcard;
    ++match;
    --num;
  }
  return (!num) || (*wildcard == *match);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sem_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <semop@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void sem_unlock(int semid) {
  struct sembuf operation[] = {
      {0, 1, SEM_UNDO},
  };
  semop(semid, operation, (sizeof(operation) / sizeof(struct sembuf)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sem_unlock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  call   <semop@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sem_unlock(int semid) {
  struct sembuf operation[] = {
      {0, 1, SEM_UNDO},
  };
  semop(semid, operation, (sizeof(operation) / sizeof(struct sembuf)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<sem_unlock>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000000,%rax
  lea    0xc(%rsp),%rsi
  mov    %rax,0xc(%rsp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  call   <semop@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sem_unlock(int semid) {
  struct sembuf operation[] = {
      {0, 1, SEM_UNDO},
  };
  semop(semid, operation, (sizeof(operation) / sizeof(struct sembuf)));
}
```