ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<get32>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  shl    $0x18,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  mov    0x8(%rdi),%edx
  or     0xc(%rdi),%eax
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t get32(const void *p) {
  const uint8_t *x = (const uint8_t *)p;
  return (x[0] << 24) | (x[1] << 16) | (x[2] << 8) | x[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrixSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L19:
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L36:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rsi
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L36
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrixSum(int **result, int **A, int **B, int rowNum, int colNum) {
  int i = 0, j = 0;
  for (i = 0; i < rowNum; i++) {
    for (j = 0; j < colNum; j++) {
      result[i][j] = A[i][j] + B[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrixSum>:
  endbr64
  test   %ecx,%ecx
  jle    L2
  push   %rbx
  mov    %r8d,%ebx
  mov    %rsi,%r9
  mov    %rdx,%r8
  lea    -0x1(%rcx),%eax
  lea    0x8(%rsi,%rax,8),%r11
  lea    -0x1(%rbx),%eax
  lea    0x4(,%rax,4),%r10
  jmp    L52
L16:
  mov    (%rdi),%rcx
  mov    (%r9),%rsi
  mov    (%r8),%rdx
  mov    (%rdx,%rax,1),%edx
  add    (%rsi,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %r10,%rax
  jne    L16
L33:
  add    $0x8,%r9
  add    $0x8,%r8
  add    $0x8,%rdi
  cmp    %r11,%r9
  je     L56
L52:
  mov    $0x0,%eax
  test   %ebx,%ebx
  jg     L16
  jmp    L33
L56:
  pop    %rbx
  ret
L2:
  ret
```

assistant: ```c
void matrixSum(int **result, int **A, int **B, int rowNum, int colNum) {
  int i = 0, j = 0;
  for (i = 0; i < rowNum; i++) {
    for (j = 0; j < colNum; j++) {
      result[i][j] = A[i][j] + B[i][j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<matrixSum>:
  endbr64
  test   %ecx,%ecx
  jle    L0
  push   %r12
  movslq %ecx,%r11
  mov    %rdx,%r12
  xor    %r10d,%r10d
  push   %rbp
  movslq %r8d,%r9
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L10:
  test   %r8d,%r8d
  jle    L21
  mov    0x0(%rbp,%r10,8),%rdi
  mov    (%r12,%r10,8),%rsi
  xor    %eax,%eax
  mov    (%rbx,%r10,8),%rcx
  nopl   0x0(%rax)
L24:
  mov    (%rsi,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L24
L21:
  add    $0x1,%r10
  cmp    %r11,%r10
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  ret
```

assistant: ```c
void matrixSum(int **result, int **A, int **B, int rowNum, int colNum) {
  int i = 0, j = 0;
  for (i = 0; i < rowNum; i++) {
    for (j = 0; j < colNum; j++) {
      result[i][j] = A[i][j] + B[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrixSum>:
  endbr64
  test   %ecx,%ecx
  jle    L103
  test   %r8d,%r8d
  jle    L103
  push   %r15
  movslq %ecx,%rax
  mov    %r8d,%r15d
  push   %r14
  mov    %r8d,%r14d
  and    $0x3,%r15d
  push   %r13
  and    $0xfffffffc,%r14d
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %r8d,%ebx
  mov    %rax,-0x18(%rsp)
  lea    -0x1(%r8),%eax
  mov    %eax,-0xc(%rsp)
  mov    %r8d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%r9d
  add    $0x1,%r9
  shl    $0x4,%r9
  nopl   (%rax)
L2:
  mov    0x0(%rbp,%rdi,8),%rdx
  mov    0x0(%r13,%rdi,8),%rsi
  mov    (%r12,%rdi,8),%rcx
  lea    0x4(%rsi),%r10
  mov    %rdx,%rax
  sub    %r10,%rax
  lea    0x4(%rcx),%r11
  mov    %rdx,%r10
  cmp    $0x8,%rax
  seta   %al
  sub    %r11,%r10
  cmp    $0x8,%r10
  seta   %r10b
  test   %r10b,%al
  je     L104
  cmp    $0x1,%r8d
  je     L104
  cmpl   $0x2,-0xc(%rsp)
  jbe    L83
  xor    %eax,%eax
  nopl   0x0(%rax)
L100:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  paddd  %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r9
  jne    L100
  cmp    %r14d,%r8d
  je     L72
  mov    %r15d,%r11d
  cmp    $0x1,%r15d
  je     L54
  mov    %r14d,%r10d
  mov    %r14d,%eax
L135:
  movq   (%rcx,%r10,4),%xmm0
  movq   (%rsi,%r10,4),%xmm1
  paddd  %xmm1,%xmm0
  movq   %xmm0,(%rdx,%r10,4)
  mov    %r11d,%r10d
  and    $0xfffffffe,%r10d
  add    %r10d,%eax
  cmp    %r10d,%r11d
  je     L72
L23:
  cltq
  mov    (%rsi,%rax,4),%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%rdx,%rax,4)
L72:
  add    $0x1,%rdi
  cmp    %rdi,-0x18(%rsp)
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L104:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L47:
  mov    (%rcx,%rax,4),%r10d
  add    (%rsi,%rax,4),%r10d
  mov    %r10d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L47
  jmp    L72
L83:
  mov    %r8d,%r11d
  xor    %r10d,%r10d
  xor    %eax,%eax
  jmp    L135
L54:
  mov    %r14d,%eax
  jmp    L23
L103:
  ret
```

assistant: ```c
void matrixSum(int **result, int **A, int **B, int rowNum, int colNum) {
  int i = 0, j = 0;
  for (i = 0; i < rowNum; i++) {
    for (j = 0; j < colNum; j++) {
      result[i][j] = A[i][j] + B[i][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uart_getc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L2:
  movabs $0x900000007f000000,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x800000,%eax
  test   %eax,%eax
  je     L2
  sarl   $0x18,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char uart_getc() {
  int val;
  while (((val = (*(volatile int *)((((0x7f000000) | 0x9000000000000000))))) & 0x00800000) == 0)
    ;
  val >>= 24;
  return (char)val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uart_getc>:
  endbr64
  movabs $0x900000007f000000,%rdx
L5:
  mov    (%rdx),%eax
  test   $0x800000,%eax
  je     L5
  shr    $0x18,%eax
  ret
```

assistant: ```c
char uart_getc() {
  int val;
  while (((val = (*(volatile int *)((((0x7f000000) | 0x9000000000000000))))) & 0x00800000) == 0)
    ;
  val >>= 24;
  return (char)val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uart_getc>:
  endbr64
  movabs $0x900000007f000000,%rdx
  xchg   %ax,%ax
L9:
  mov    (%rdx),%eax
  test   $0x800000,%eax
  je     L9
  shr    $0x18,%eax
  ret
```

assistant: ```c
char uart_getc() {
  int val;
  while (((val = (*(volatile int *)((((0x7f000000) | 0x9000000000000000))))) & 0x00800000) == 0)
    ;
  val >>= 24;
  return (char)val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uart_getc>:
  endbr64
  movabs $0x900000007f000000,%rdx
  xchg   %ax,%ax
L4:
  mov    (%rdx),%eax
  test   $0x800000,%eax
  je     L4
  shr    $0x18,%eax
  ret
```

assistant: ```c
char uart_getc() {
  int val;
  while (((val = (*(volatile int *)((((0x7f000000) | 0x9000000000000000))))) & 0x00800000) == 0)
    ;
  val >>= 24;
  return (char)val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<slow_down>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L19:
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x270f,-0x4(%rbp)
  jle    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void slow_down() {
  int k;
  for (k = 0; k < 10000; k++)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slow_down>:
  endbr64
  mov    $0x2710,%eax
L1:
  sub    $0x1,%eax
  jne    L1
  ret
```

assistant: ```c
void slow_down() {
  int k;
  for (k = 0; k < 10000; k++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<slow_down>:
  endbr64
  ret
```

assistant: ```c
void slow_down() {
  int k;
  for (k = 0; k < 10000; k++)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slow_down>:
  endbr64
  ret
```

assistant: ```c
void slow_down() {
  int k;
  for (k = 0; k < 10000; k++)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prng_rand_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L14
L16:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <prng_rand_byte@plt>
  mov    %eax,(%rbx)
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L16
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void prng_rand_bytes(uint8_t *buffer, size_t buffer_len) {
  for (size_t i = 0; i < buffer_len; ++i) {
    buffer[i] = prng_rand_byte();
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prng_rand_bytes>:
  endbr64
  test   %rsi,%rsi
  je     L1
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L10:
  mov    $0x0,%eax
  call   <prng_rand_byte@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  ret
```

assistant: ```c
void prng_rand_bytes(uint8_t *buffer, size_t buffer_len) {
  for (size_t i = 0; i < buffer_len; ++i) {
    buffer[i] = prng_rand_byte();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<prng_rand_bytes>:
  endbr64
  test   %rsi,%rsi
  je     L1
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L19:
  xor    %eax,%eax
  call   <prng_rand_byte@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void prng_rand_bytes(uint8_t *buffer, size_t buffer_len) {
  for (size_t i = 0; i < buffer_len; ++i) {
    buffer[i] = prng_rand_byte();
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prng_rand_bytes>:
  endbr64
  test   %rsi,%rsi
  je     L16
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L13:
  xor    %eax,%eax
  call   <prng_rand_byte@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  ret
```

assistant: ```c
void prng_rand_bytes(uint8_t *buffer, size_t buffer_len) {
  for (size_t i = 0; i < buffer_len; ++i) {
    buffer[i] = prng_rand_byte();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xc,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L84
L88:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L84:
  cmpl   $0x5,-0x2c(%rbp)
  jle    L88
  movl   $0x1,-0x2c(%rbp)
  jmp    L41
L97:
  movl   $0x0,-0x28(%rbp)
  jmp    L62
L0:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L55
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x24(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
L55:
  addl   $0x1,-0x28(%rbp)
L62:
  cmpl   $0x4,-0x28(%rbp)
  jle    L0
  addl   $0x1,-0x2c(%rbp)
L41:
  cmpl   $0x5,-0x2c(%rbp)
  jle    L97
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L17
L4:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L17:
  cmpl   $0x5,-0x2c(%rbp)
  jle    L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L92
  call   <__stack_chk_fail@plt>
L92:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D37
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D28
data_type: string

tool: D37: La lista DESORDENADA es: 

tool: D13: %3d

tool: D28: 
Los valores ORDENADOS de lista son: 

assistant: ```c
int main() {
  int lista[6] = {12, 10, 5, 6, 1, 3};
  int temp = 0;
  int i, j;
  printf("La lista DESORDENADA es: \n");
  for (i = 0; i < 6; i++)
    printf("%3d", lista[i]);
  for (i = 1; i < 6; i++) {
    for (j = 0; j < 6 - 1; j++) {
      if (lista[j] > lista[j + 1]) {
        temp = lista[j];
        lista[j] = lista[j + 1];
        lista[j + 1] = temp;
      }
    }
  }
  printf("\nLos valores ORDENADOS de lista son: \n");
  for (i = 0; i < 6; i++)
    printf("%3d", lista[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xc,(%rsp)
  movl   $0xa,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x18(%rsp),%rbp
  mov    %rbx,%r12
  lea    D35(%rip),%r13
L6:
  mov    (%r12),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L6
  mov    $0x5,%edi
  lea    0x14(%rbx),%rsi
  jmp    L51
L11:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L44
L67:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L11
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L11
L44:
  sub    $0x1,%edi
  je     L71
L51:
  mov    %rbx,%rax
  jmp    L67
L71:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D35(%rip),%r12
L28:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L28
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D38
type: string
name: read_data
arguments: label: D35
type: string
name: read_data
arguments: label: D36
type: string

tool: D38: La lista DESORDENADA es: 

tool: D35: %3d

tool: D36: 
Los valores ORDENADOS de lista son: 

assistant: ```c
int main() {
  int lista[6] = {12, 10, 5, 6, 1, 3};
  int temp = 0;
  int i, j;
  printf("La lista DESORDENADA es: \n");
  for (i = 0; i < 6; i++)
    printf("%3d", lista[i]);
  for (i = 1; i < 6; i++) {
    for (j = 0; j < 6 - 1; j++) {
      if (lista[j] > lista[j + 1]) {
        temp = lista[j];
        lista[j] = lista[j + 1];
        lista[j + 1] = temp;
      }
    }
  }
  printf("\nLos valores ORDENADOS de lista son: \n");
  for (i = 0; i < 6; i++)
    printf("%3d", lista[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%rdi
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa0000000c,%rax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%rbp
  mov    %rbx,%r13
  mov    %rax,(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x300000001,%rax
  mov    %rax,0x10(%rsp)
  call   <puts@plt>
  mov    $0xc,%esi
  jmp    L33
  nopl   (%rax)
L23:
  mov    0x0(%r13),%esi
L33:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L23
  mov    $0x5,%edi
  mov    $0xa,%ecx
  mov    $0xc,%edx
  lea    0x14(%rbx),%rsi
L54:
  mov    %rbx,%rax
  cmp    %ecx,%edx
  jle    L56
L89:
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L56:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L75
L0:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jg     L89
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L0
L75:
  mov    (%rsp),%edx
  sub    $0x1,%edi
  je     L82
  mov    0x4(%rsp),%ecx
  jmp    L54
  nop
L82:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L36:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L36
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D22
type: string

tool: D8: La lista DESORDENADA es: 

tool: D3: %3d

tool: D22: 
Los valores ORDENADOS de lista son: 

assistant: ```c
int main() {
  int lista[6] = {12, 10, 5, 6, 1, 3};
  int temp = 0;
  int i, j;
  printf("La lista DESORDENADA es: \n");
  for (i = 0; i < 6; i++)
    printf("%3d", lista[i]);
  for (i = 1; i < 6; i++) {
    for (j = 0; j < 6 - 1; j++) {
      if (lista[j] > lista[j + 1]) {
        temp = lista[j];
        lista[j] = lista[j + 1];
        lista[j + 1] = temp;
      }
    }
  }
  printf("\nLos valores ORDENADOS de lista son: \n");
  for (i = 0; i < 6; i++)
    printf("%3d", lista[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D16(%rip),%rdi
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D36(%rip),%xmm0
  mov    D17(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  mov    %r14,0x10(%rsp)
  mov    %rbx,%rbp
  movaps %xmm0,(%rsp)
  call   <puts@plt>
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L3
  mov    D54(%rip),%rax
  lea    D49(%rip),%rdi
  mov    %r14,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L24:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L24
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D13
type_infered: string
name: unpack_data
arguments: tag: D36
type_infered: byte[16]
name: unpack_data
arguments: tag: D17
type_infered: byte[8]
name: unpack_data
arguments: tag: D54
type_infered: byte[8]
name: unpack_data
arguments: tag: D49
type_infered: string

tool: D16: La lista DESORDENADA es: 

tool: D13: %3d

tool: {"D36": [0x0c,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D17": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D54": [0x0a,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: D49: 
Los valores ORDENADOS de lista son: 

assistant: ```c
int main() {
  int lista[6] = {12, 10, 5, 6, 1, 3};
  int temp = 0;
  int i, j;
  printf("La lista DESORDENADA es: \n");
  for (i = 0; i < 6; i++)
    printf("%3d", lista[i]);
  for (i = 1; i < 6; i++) {
    for (j = 0; j < 6 - 1; j++) {
      if (lista[j] > lista[j + 1]) {
        temp = lista[j];
        lista[j] = lista[j + 1];
        lista[j + 1] = temp;
      }
    }
  }
  printf("\nLos valores ORDENADOS de lista son: \n");
  for (i = 0; i < 6; i++)
    printf("%3d", lista[i]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__fdim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0x4(%rbp)
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L25
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L25
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L59
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L59
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L59
L25:
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  jmp    L44
L59:
  movsd  -0x20(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L79
  pxor   %xmm0,%xmm0
  jmp    L44
L79:
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
L44:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double __fdim(double x, double y) {
  int clsx = fpclassify(x);
  int clsy = fpclassify(y);
  if (clsx == FP_NAN || clsy == FP_NAN || (y < 0 && clsx == FP_INFINITE && clsy == FP_INFINITE))
    return x - y;
  return x <= y ? 0 : x - y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__fdim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  movsd  %xmm1,0x8(%rsp)
  call   <fpclassify@plt>
  mov    %eax,%ebp
  movsd  0x8(%rsp),%xmm0
  call   <fpclassify@plt>
  mov    D4(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %eax,%edx
  je     L10
  cmp    %ebp,%edx
  je     L10
  pxor   %xmm0,%xmm0
  comisd 0x8(%rsp),%xmm0
  ja     L0
L3:
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm3
  movq   %rbx,%xmm4
  comisd %xmm4,%xmm3
  jae    L4
  movq   %rbx,%xmm0
  subsd  %xmm3,%xmm0
  jmp    L4
L0:
  mov    D13(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %eax,%edx
  jne    L3
  cmp    %ebp,%edx
  jne    L3
L10:
  movq   %rbx,%xmm0
  subsd  0x8(%rsp),%xmm0
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double __fdim(double x, double y) {
  int clsx = fpclassify(x);
  int clsy = fpclassify(y);
  if (clsx == FP_NAN || clsy == FP_NAN || (y < 0 && clsx == FP_INFINITE && clsy == FP_INFINITE))
    return x - y;
  return x <= y ? 0 : x - y;
}
```