ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf_s@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rsi
  imul   $0x68db8bad,%rsi,%rsi
  sar    $0x2c,%rsi
  mov    %eax,%edi
  sar    $0x1f,%edi
  mov    %esi,%ecx
  sub    %edi,%ecx
  imul   $0x2710,%ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%r10d
  sar    $0x1f,%r10d
  mov    %edx,%eax
  sub    %r10d,%eax
  imul   $0x3e8,%eax,%r8d
  mov    %ecx,%eax
  sub    %r8d,%eax
  movslq %eax,%rcx
  imul   $0x51eb851f,%rcx,%rcx
  sar    $0x25,%rcx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  mov    %ecx,%r9d
  sub    %r11d,%r9d
  imul   $0x64,%r9d,%r8d
  sub    %r8d,%eax
  mov    %eax,%r9d
  movslq %eax,%r8
  imul   $0x66666667,%r8,%r8
  sar    $0x22,%r8
  sar    $0x1f,%eax
  sub    %eax,%r8d
  lea    (%r8,%r8,4),%eax
  add    %eax,%eax
  sub    %r11d,%ecx
  sub    %r10d,%edx
  sub    %edi,%esi
  sub    %eax,%r9d
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D33
type_infered: string
name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D31
type_infered: string
name: disassemble_data
arguments: data_label: D23
type_infered: string

tool: D33: Enter a number(5 digits): 

tool: D7: %d

tool: D31: %d	%d	%d	%d	%d


tool: D23: pause

assistant: ```c
main() {
  int number, a, temp, b, c, d, e;
  printf("Enter a number(5 digits): ");
  scanf_s("%d", &number);
  a = number / 10000;
  temp = number % 10000;
  b = temp / 1000;
  temp = temp % 1000;
  c = temp / 100;
  temp = temp % 100;
  d = temp / 10;
  e = temp % 10;
  printf("%d\t%d\t%d\t%d\t%d\n", a, b, c, d, e);
  system("pause");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf_s@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x68db8bad,%rsi,%rsi
  mov    %eax,%edi
  sar    $0x1f,%edi
  sar    $0x2c,%rsi
  mov    %esi,%ecx
  sub    %edi,%esi
  sub    %edi,%ecx
  lea    D2(%rip),%rdi
  imul   $0x2710,%ecx,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  mov    %ecx,%r10d
  sar    $0x1f,%r10d
  sar    $0x26,%rdx
  mov    %edx,%eax
  sub    %r10d,%edx
  sub    %r10d,%eax
  imul   $0x3e8,%eax,%r8d
  mov    %ecx,%eax
  sub    %r8d,%eax
  movslq %eax,%rcx
  mov    %eax,%r11d
  imul   $0x51eb851f,%rcx,%rcx
  sar    $0x1f,%r11d
  sar    $0x25,%rcx
  mov    %ecx,%r9d
  sub    %r11d,%ecx
  sub    %r11d,%r9d
  imul   $0x64,%r9d,%r8d
  sub    %r8d,%eax
  movslq %eax,%r8
  sar    $0x1f,%eax
  mov    %r8,%r9
  imul   $0x66666667,%r8,%r8
  sar    $0x22,%r8
  sub    %eax,%r8d
  lea    (%r8,%r8,4),%eax
  add    %eax,%eax
  sub    %eax,%r9d
  xor    %eax,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
datatype: string
name: disassemble_data
arguments: data_tag: D25
datatype: string
name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D35
datatype: string

tool: D21: Enter a number(5 digits): 

tool: D25: %d

tool: D2: %d	%d	%d	%d	%d


tool: D35: pause

assistant: ```c
main() {
  int number, a, temp, b, c, d, e;
  printf("Enter a number(5 digits): ");
  scanf_s("%d", &number);
  a = number / 10000;
  temp = number % 10000;
  b = temp / 1000;
  temp = temp % 1000;
  c = temp / 100;
  temp = temp % 100;
  d = temp / 10;
  e = temp % 10;
  printf("%d\t%d\t%d\t%d\t%d\n", a, b, c, d, e);
  system("pause");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf_s@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x68db8bad,%rsi,%rsi
  mov    %eax,%edi
  sar    $0x1f,%edi
  sar    $0x2c,%rsi
  mov    %esi,%ecx
  sub    %edi,%esi
  sub    %edi,%ecx
  lea    D4(%rip),%rdi
  imul   $0x2710,%ecx,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  mov    %ecx,%r10d
  sar    $0x1f,%r10d
  sar    $0x26,%rdx
  mov    %edx,%eax
  sub    %r10d,%edx
  sub    %r10d,%eax
  imul   $0x3e8,%eax,%r8d
  mov    %ecx,%eax
  sub    %r8d,%eax
  movslq %eax,%rcx
  mov    %eax,%r11d
  imul   $0x51eb851f,%rcx,%rcx
  sar    $0x1f,%r11d
  sar    $0x25,%rcx
  mov    %ecx,%r9d
  sub    %r11d,%ecx
  sub    %r11d,%r9d
  imul   $0x64,%r9d,%r8d
  sub    %r8d,%eax
  movslq %eax,%r8
  sar    $0x1f,%eax
  mov    %r8,%r9
  imul   $0x66666667,%r8,%r8
  sar    $0x22,%r8
  sub    %eax,%r8d
  lea    (%r8,%r8,4),%eax
  add    %eax,%eax
  sub    %eax,%r9d
  xor    %eax,%eax
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D30
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D38
type: string

tool: D18: Enter a number(5 digits): 

tool: D30: %d

tool: D4: %d	%d	%d	%d	%d


tool: D38: pause

assistant: ```c
main() {
  int number, a, temp, b, c, d, e;
  printf("Enter a number(5 digits): ");
  scanf_s("%d", &number);
  a = number / 10000;
  temp = number % 10000;
  b = temp / 1000;
  temp = temp % 1000;
  c = temp / 100;
  temp = temp % 100;
  d = temp / 10;
  e = temp % 10;
  printf("%d\t%d\t%d\t%d\t%d\n", a, b, c, d, e);
  system("pause");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L10:
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void substring(char s[], char sub[], int p, int l) {
  int c = 0;
  while (c < l) {
    sub[c] = s[p + c - 1];
    c++;
  }
  sub[c] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<substring>:
  endbr64
  test   %ecx,%ecx
  jle    L0
  mov    %ecx,%r8d
  mov    $0x0,%eax
  movslq %edx,%rdx
  add    %rdx,%rdi
L11:
  movzbl -0x1(%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L11
L10:
  movslq %ecx,%rcx
  movb   $0x0,(%rsi,%rcx,1)
  ret
L0:
  mov    $0x0,%ecx
  jmp    L10
```

assistant: ```c
void substring(char s[], char sub[], int p, int l) {
  int c = 0;
  while (c < l) {
    sub[c] = s[p + c - 1];
    c++;
  }
  sub[c] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<substring>:
  endbr64
  test   %ecx,%ecx
  jle    L11
  movslq %edx,%rdx
  movslq %ecx,%rcx
  xor    %eax,%eax
  add    %rdx,%rdi
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl -0x1(%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L12
  add    %rcx,%rsi
L11:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void substring(char s[], char sub[], int p, int l) {
  int c = 0;
  while (c < l) {
    sub[c] = s[p + c - 1];
    c++;
  }
  sub[c] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<substring>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%edi
  mov    %ecx,%edx
  test   %ecx,%ecx
  jle    L15
  movslq %edi,%rax
  mov    %rsi,%r11
  mov    %ecx,%r10d
  lea    (%r8,%rax,1),%r9
  lea    -0x1(%rcx),%ecx
  sub    %r9,%r11
  cmp    $0xe,%r11
  jbe    L118
  cmp    $0x6,%ecx
  jbe    L118
  cmp    $0xe,%ecx
  jbe    L153
  mov    %edx,%ecx
  lea    -0x1(%r8,%rax,1),%r10
  xor    %eax,%eax
  shr    $0x4,%ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L113:
  movdqu (%r10,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L113
  mov    %edx,%ecx
  and    $0xfffffff0,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%edx
  je     L119
  mov    %edx,%r10d
  sub    %ecx,%r10d
  lea    -0x1(%r10),%r11d
  cmp    $0x6,%r11d
  jbe    L155
L160:
  mov    -0x1(%rcx,%r9,1),%r9
  mov    %r9,(%rsi,%rcx,1)
  mov    %r10d,%ecx
  and    $0xfffffff8,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r10d
  je     L119
L155:
  lea    (%rdi,%rax,1),%ecx
  movslq %ecx,%rcx
  movzbl -0x1(%r8,%rcx,1),%r9d
  movslq %eax,%rcx
  mov    %r9b,(%rsi,%rcx,1)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jle    L119
  lea    (%rdi,%rcx,1),%r9d
  movslq %ecx,%rcx
  movslq %r9d,%r9
  movzbl -0x1(%r8,%r9,1),%r9d
  mov    %r9b,(%rsi,%rcx,1)
  lea    0x2(%rax),%ecx
  cmp    %ecx,%edx
  jle    L119
  lea    (%rdi,%rcx,1),%r9d
  movslq %ecx,%rcx
  movslq %r9d,%r9
  movzbl -0x1(%r8,%r9,1),%r9d
  mov    %r9b,(%rsi,%rcx,1)
  lea    0x3(%rax),%ecx
  cmp    %ecx,%edx
  jle    L119
  lea    (%rdi,%rcx,1),%r9d
  movslq %ecx,%rcx
  movslq %r9d,%r9
  movzbl -0x1(%r8,%r9,1),%r9d
  mov    %r9b,(%rsi,%rcx,1)
  lea    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L119
  lea    (%rdi,%rcx,1),%r9d
  movslq %ecx,%rcx
  movslq %r9d,%r9
  movzbl -0x1(%r8,%r9,1),%r9d
  mov    %r9b,(%rsi,%rcx,1)
  lea    0x5(%rax),%ecx
  cmp    %ecx,%edx
  jle    L119
  lea    (%rdi,%rcx,1),%r9d
  add    $0x6,%eax
  movslq %ecx,%rcx
  movslq %r9d,%r9
  movzbl -0x1(%r8,%r9,1),%r9d
  mov    %r9b,(%rsi,%rcx,1)
  cmp    %eax,%edx
  jle    L119
  add    %eax,%edi
  cltq
  movslq %edi,%rdi
  movzbl -0x1(%r8,%rdi,1),%ecx
  mov    %cl,(%rsi,%rax,1)
L119:
  movslq %edx,%rdx
  add    %rdx,%rsi
L15:
  movb   $0x0,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L118:
  mov    %edx,%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L22:
  movzbl -0x1(%r9,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L22
  jmp    L119
L153:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L160
```

assistant: ```c
void substring(char s[], char sub[], int p, int l) {
  int c = 0;
  while (c < l) {
    sub[c] = s[p + c - 1];
    c++;
  }
  sub[c] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Setsockopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    -0x20(%rbp),%edi
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L2
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <Sys_failure@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D9: setsockopt

assistant: ```c
void Setsockopt(int s, int level, int optname, const void *optval, socklen_t optlen) {
  int retval;
  retval = setsockopt(s, level, optname, optval, optlen);
  if (retval == -1)
    Sys_failure("setsockopt");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Setsockopt>:
  endbr64
  sub    $0x8,%rsp
  call   <setsockopt@plt>
  cmp    $0xffffffff,%eax
  je     L10
L3:
  add    $0x8,%rsp
  ret
L10:
  lea    D4(%rip),%rdi
  call   <Sys_failure@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: label: D4
type: string

tool: D4: setsockopt

assistant: ```c
void Setsockopt(int s, int level, int optname, const void *optval, socklen_t optlen) {
  int retval;
  retval = setsockopt(s, level, optname, optval, optlen);
  if (retval == -1)
    Sys_failure("setsockopt");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Setsockopt>:
  endbr64
  sub    $0x8,%rsp
  call   <setsockopt@plt>
  cmp    $0xffffffff,%eax
  je     L3
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <Sys_failure@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: setsockopt

assistant: ```c
void Setsockopt(int s, int level, int optname, const void *optval, socklen_t optlen) {
  int retval;
  retval = setsockopt(s, level, optname, optval, optlen);
  if (retval == -1)
    Sys_failure("setsockopt");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Setsockopt>:
  endbr64
  sub    $0x8,%rsp
  call   <setsockopt@plt>
  cmp    $0xffffffff,%eax
  je     L0
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <Sys_failure@plt>
```

tool_calls: name: read_data
arguments: label: D8
datatype: string

tool: D8: setsockopt

assistant: ```c
void Setsockopt(int s, int level, int optname, const void *optval, socklen_t optlen) {
  int retval;
  retval = setsockopt(s, level, optname, optval, optlen);
  if (retval == -1)
    Sys_failure("setsockopt");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa,%edi
  call   <func2@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: a = %d


assistant: ```c
int func1(void) {
  int a;
  a = func2(10);
  printf("a = %d\n", a);
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<func1>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <func2@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: a = %d


assistant: ```c
int func1(void) {
  int a;
  a = func2(10);
  printf("a = %d\n", a);
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func1>:
  endbr64
  push   %r12
  mov    $0xa,%edi
  call   <func2@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: a = %d


assistant: ```c
int func1(void) {
  int a;
  a = func2(10);
  printf("a = %d\n", a);
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<func1>:
  endbr64
  push   %r12
  mov    $0xa,%edi
  call   <func2@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: a = %d


assistant: ```c
int func1(void) {
  int a;
  a = func2(10);
  printf("a = %d\n", a);
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maccmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L30
  cmpq   $0x0,-0x30(%rbp)
  jne    L5
L30:
  mov    $0xffffffff,%eax
  jmp    L45
L5:
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L54:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L26
  mov    $0xffffffff,%eax
  jmp    L45
L26:
  addl   $0x1,-0x14(%rbp)
L1:
  cmpl   $0x5,-0x14(%rbp)
  jle    L54
  mov    $0x0,%eax
L45:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int maccmp(unsigned char *mac1, unsigned char *mac2) {
  int i = 0;
  if (mac1 == NULL || mac2 == NULL)
    return -1;
  for (i = 0; i < 6; i++) {
    if (toupper(mac1[i]) != toupper(mac2[i]))
      return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<maccmp>:
  endbr64
  test   %rdi,%rdi
  je     L25
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L7
  mov    $0x0,%ebx
L42:
  movzbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %rax,%rbp
  movzbl 0x0(%r13,%rbx,1),%edi
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L41
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L42
  mov    $0x0,%eax
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L40
L41:
  mov    $0xffffffff,%eax
  jmp    L40
L25:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int maccmp(unsigned char *mac1, unsigned char *mac2) {
  int i = 0;
  if (mac1 == NULL || mac2 == NULL)
    return -1;
  for (i = 0; i < 6; i++) {
    if (toupper(mac1[i]) != toupper(mac2[i]))
      return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maccmp>:
  endbr64
  test   %rdi,%rdi
  je     L22
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L30
  mov    %rdi,%r12
  xor    %ebx,%ebx
L21:
  movzbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  movzbl 0x0(%r13,%rbx,1),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L30
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L21
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L30:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int maccmp(unsigned char *mac1, unsigned char *mac2) {
  int i = 0;
  if (mac1 == NULL || mac2 == NULL)
    return -1;
  for (i = 0; i < 6; i++) {
    if (toupper(mac1[i]) != toupper(mac2[i]))
      return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<maccmp>:
  endbr64
  test   %rdi,%rdi
  je     L14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L35
  mov    %rdi,%r12
  xor    %ebx,%ebx
L32:
  movzbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  movzbl 0x0(%r13,%rbx,1),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L35
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L32
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L35:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int maccmp(unsigned char *mac1, unsigned char *mac2) {
  int i = 0;
  if (mac1 == NULL || mac2 == NULL)
    return -1;
  for (i = 0; i < 6; i++) {
    if (toupper(mac1[i]) != toupper(mac2[i]))
      return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_array_to_bit_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L24:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  add    $0x7,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L35:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  and    $0x1,%edx
  mov    %edx,(%rax)
  sarl   -0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L35
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void byte_array_to_bit_array(uint8_t *byte_array, size_t size, uint8_t *bit_array) {
  int i;
  for (i = 0; i < size; i++) {
    uint8_t t = byte_array[i];
    int j;
    for (j = 8 * i + 7; j >= 8 * i; j--) {
      bit_array[j] = t & 1;
      t >>= 1;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byte_array_to_bit_array>:
  endbr64
  test   %rsi,%rsi
  je     L13
  lea    -0x4(%rdx),%r8
  lea    0x7(,%rsi,8),%r10d
  mov    $0x7,%r9d
  jmp    L10
L8:
  add    $0x4,%rdi
  add    $0x8,%r9d
  cmp    %r10d,%r9d
  je     L13
L10:
  mov    (%rdi),%edx
  mov    %r8,%rsi
  add    $0x20,%r8
  mov    %r8,%rax
L40:
  mov    %edx,%ecx
  and    $0x1,%ecx
  mov    %ecx,(%rax)
  sar    %edx
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L40
  jmp    L8
L13:
  ret
```

assistant: ```c
void byte_array_to_bit_array(uint8_t *byte_array, size_t size, uint8_t *bit_array) {
  int i;
  for (i = 0; i < size; i++) {
    uint8_t t = byte_array[i];
    int j;
    for (j = 8 * i + 7; j >= 8 * i; j--) {
      bit_array[j] = t & 1;
      t >>= 1;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<byte_array_to_bit_array>:
  endbr64
  test   %rsi,%rsi
  je     L12
  lea    -0x4(%rdx),%r8
  lea    0x7(,%rsi,8),%r10d
  mov    $0x7,%r9d
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %r8,%rsi
  mov    (%rdi),%edx
  add    $0x20,%r8
  mov    %r8,%rax
  nopl   0x0(%rax)
L10:
  mov    %edx,%ecx
  sub    $0x4,%rax
  sar    %edx
  and    $0x1,%ecx
  mov    %ecx,0x4(%rax)
  cmp    %rsi,%rax
  jne    L10
  add    $0x8,%r9d
  add    $0x4,%rdi
  cmp    %r10d,%r9d
  jne    L27
L12:
  ret
```

assistant: ```c
void byte_array_to_bit_array(uint8_t *byte_array, size_t size, uint8_t *bit_array) {
  int i;
  for (i = 0; i < size; i++) {
    uint8_t t = byte_array[i];
    int j;
    for (j = 8 * i + 7; j >= 8 * i; j--) {
      bit_array[j] = t & 1;
      t >>= 1;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<xerbla_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: xerbla: On entry to %6s, parameter number %2d had an illegal value.


assistant: ```c
int xerbla_(char *srname, int *info) {
  printf("xerbla: On entry to %6s, parameter number %2d had an illegal value.\n", srname, *info);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xerbla_>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%edx
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: xerbla: On entry to %6s, parameter number %2d had an illegal value.


assistant: ```c
int xerbla_(char *srname, int *info) {
  printf("xerbla: On entry to %6s, parameter number %2d had an illegal value.\n", srname, *info);
  return 0;
}
```