ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  imul   $0xfb16,%ax,%ax
  sub    $0x2e4,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  lea    0x1a66(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] = state[0UL] - state[local1];
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 681723154UL) + (unsigned short)54612;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  add    $0x1782,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] = state[0UL] - state[local1];
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 681723154UL) + (unsigned short)54612;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  add    $0x1782,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] = state[0UL] - state[local1];
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 681723154UL) + (unsigned short)54612;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  add    $0x1782,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] = state[0UL] - state[local1];
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 681723154UL) + (unsigned short)54612;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tauint_to_eta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D14(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L5
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L17
L5:
  movsd  -0x18(%rbp),%xmm0
  movsd  D14(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm2
  movsd  D14(%rip),%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L17:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: f64

tool: D14: 1

assistant: ```c
double tauint_to_eta(double tauint) {
  double eta;
  if (tauint <= 1.0)
    eta = 0.0;
  else
    eta = (tauint - 1.0) / (tauint + 1.0);
  return eta;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tauint_to_eta>:
  endbr64
  movapd %xmm0,%xmm1
  movsd  D4(%rip),%xmm0
  comisd %xmm1,%xmm0
  jae    L5
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  ret
L5:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
double tauint_to_eta(double tauint) {
  double eta;
  if (tauint <= 1.0)
    eta = 0.0;
  else
    eta = (tauint - 1.0) / (tauint + 1.0);
  return eta;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tauint_to_eta>:
  endbr64
  movsd  D6(%rip),%xmm2
  movapd %xmm0,%xmm1
  comisd %xmm0,%xmm2
  jae    L4
  subsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: f64

tool: D6: 1

assistant: ```c
double tauint_to_eta(double tauint) {
  double eta;
  if (tauint <= 1.0)
    eta = 0.0;
  else
    eta = (tauint - 1.0) / (tauint + 1.0);
  return eta;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tauint_to_eta>:
  endbr64
  movsd  D3(%rip),%xmm2
  movapd %xmm0,%xmm1
  comisd %xmm0,%xmm2
  jae    L6
  subsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: f64

tool: D3: 1

assistant: ```c
double tauint_to_eta(double tauint) {
  double eta;
  if (tauint <= 1.0)
    eta = 0.0;
  else
    eta = (tauint - 1.0) / (tauint + 1.0);
  return eta;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mumps_get_max_file_size_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xdc,0x41]}

assistant: ```c
void mumps_get_max_file_size_c(double *max_ooc_file_size) {
  *max_ooc_file_size = (double)(1879048192);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mumps_get_max_file_size_c>:
  endbr64
  mov    D3(%rip),%rax
  mov    %rax,(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xdc,0x41]}

assistant: ```c
void mumps_get_max_file_size_c(double *max_ooc_file_size) {
  *max_ooc_file_size = (double)(1879048192);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<mumps_get_max_file_size_c>:
  endbr64
  mov    D5(%rip),%rax
  mov    %rax,(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xdc,0x41]}

assistant: ```c
void mumps_get_max_file_size_c(double *max_ooc_file_size) {
  *max_ooc_file_size = (double)(1879048192);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mumps_get_max_file_size_c>:
  endbr64
  mov    D2(%rip),%rax
  mov    %rax,(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xdc,0x41]}

assistant: ```c
void mumps_get_max_file_size_c(double *max_ooc_file_size) {
  *max_ooc_file_size = (double)(1879048192);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kernel_bicg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L43:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L57:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L43
  movl   $0x0,-0x8(%rbp)
  jmp    L50
L20:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L47
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x3b60,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x3b60,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L47:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  addl   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L20
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void kernel_bicg(int m, int n, double A[2100 + 0][1900 + 0], double s[1900 + 0], double q[2100 + 0], double p[1900 + 0], double r[2100 + 0]) {
  int i, j;
#pragma scop
  for (i = 0; i < m; i++)
    s[i] = 0;
  for (i = 0; i < n; i++) {
    q[i] = 0.0;
    for (j = 0; j < m; j++) {
      s[j] = s[j] + r[i] * A[i][j];
      q[i] = q[i] + A[i][j] * p[j];
    }
  }
#pragma endscop
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kernel_bicg>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%r10d
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %rcx,%rsi
  test   %edi,%edi
  jle    L46
  mov    %rcx,%rax
  lea    -0x1(%rdi),%edx
  lea    0x8(%rcx,%rdx,8),%rdx
L58:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L58
L46:
  test   %ebp,%ebp
  jle    L38
  mov    %r8,%r11
  mov    0x18(%rsp),%rdi
  lea    -0x1(%rbp),%eax
  lea    0x8(%r8,%rax,8),%rbp
  mov    %r10d,%r8d
L37:
  mov    %r11,%rdx
  movq   $0x0,(%r11)
  test   %r10d,%r10d
  jle    L2
  mov    %rbx,%rcx
  mov    $0x0,%eax
L9:
  movsd  (%rdi),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%r9,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L9
L2:
  add    $0x8,%r11
  add    $0x8,%rdi
  add    $0x3b60,%rbx
  cmp    %rbp,%r11
  jne    L37
L38:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kernel_bicg(int m, int n, double A[2100 + 0][1900 + 0], double s[1900 + 0], double q[2100 + 0], double p[1900 + 0], double r[2100 + 0]) {
  int i, j;
#pragma scop
  for (i = 0; i < m; i++)
    s[i] = 0;
  for (i = 0; i < n; i++) {
    q[i] = 0.0;
    for (j = 0; j < m; j++) {
      s[j] = s[j] + r[i] * A[i][j];
      q[i] = q[i] + A[i][j] * p[j];
    }
  }
#pragma endscop
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kernel_bicg>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8,%rbx
  test   %edi,%edi
  jle    L11
  movslq %edi,%rdx
  xor    %esi,%esi
  mov    %rcx,%rdi
  shl    $0x3,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
L11:
  test   %r14d,%r14d
  jle    L0
  lea    -0x1(%r14),%eax
  mov    0x30(%rsp),%rsi
  mov    %rbx,%r8
  mov    %r13,%rdx
  lea    0x8(%rbx,%rax,8),%r9
  movslq %ebp,%rdi
  xchg   %ax,%ax
L14:
  movq   $0x0,(%r8)
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L5
  nopl   (%rax)
L28:
  movsd  (%rsi),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  (%r12,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  (%r8),%xmm0
  movsd  %xmm0,(%r8)
  cmp    %rax,%rdi
  jne    L28
L5:
  add    $0x8,%r8
  add    $0x8,%rsi
  add    $0x3b60,%rdx
  cmp    %r9,%r8
  jne    L14
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void kernel_bicg(int m, int n, double A[2100 + 0][1900 + 0], double s[1900 + 0], double q[2100 + 0], double p[1900 + 0], double r[2100 + 0]) {
  int i, j;
#pragma scop
  for (i = 0; i < m; i++)
    s[i] = 0;
  for (i = 0; i < n; i++) {
    q[i] = 0.0;
    for (j = 0; j < m; j++) {
      s[j] = s[j] + r[i] * A[i][j];
      q[i] = q[i] + A[i][j] * p[j];
    }
  }
#pragma endscop
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<kernel_bicg>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8,%rbx
  test   %edi,%edi
  jle    L32
  movslq %edi,%rdx
  xor    %esi,%esi
  mov    %rcx,%rdi
  shl    $0x3,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
L32:
  test   %r14d,%r14d
  jle    L13
  lea    -0x1(%r14),%eax
  mov    0x30(%rsp),%rsi
  mov    %rbx,%r8
  mov    %r13,%rdx
  lea    0x8(%rbx,%rax,8),%r9
  movslq %ebp,%rdi
  xchg   %ax,%ax
L29:
  movq   $0x0,(%r8)
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L18
  nopl   (%rax)
L16:
  movsd  (%rsi),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  (%r12,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  (%r8),%xmm0
  movsd  %xmm0,(%r8)
  cmp    %rax,%rdi
  jne    L16
L18:
  add    $0x8,%r8
  add    $0x8,%rsi
  add    $0x3b60,%rdx
  cmp    %r8,%r9
  jne    L29
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void kernel_bicg(int m, int n, double A[2100 + 0][1900 + 0], double s[1900 + 0], double q[2100 + 0], double p[1900 + 0], double r[2100 + 0]) {
  int i, j;
#pragma scop
  for (i = 0; i < m; i++)
    s[i] = 0;
  for (i = 0; i < n; i++) {
    q[i] = 0.0;
    for (j = 0; j < m; j++) {
      s[j] = s[j] + r[i] * A[i][j];
      q[i] = q[i] + A[i][j] * p[j];
    }
  }
#pragma endscop
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D56(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm3,%xmm3
  cvtss2sd -0xc(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D42
data_type: string
name: parse_data
arguments: label: D9
data_type: string
name: parse_data
arguments: label: D56
data_type: f64
name: parse_data
arguments: label: D4
data_type: byte[8]
name: parse_data
arguments: label: D23
data_type: string
name: parse_data
arguments: label: D65
data_type: string

tool: D3: 
 ** CONVERSOR DE TEMPERATURA FAHRENHEIT EM CELSIUS **

tool: D42: 
Digite a temperatura em Fahrenheit: 

tool: D9: %f

tool: D56: 32

tool: {"D4": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D23: 
A temperatura em Celsius e: %i.


tool: D65: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float F, C;
  printf("\n ** CONVERSOR DE TEMPERATURA FAHRENHEIT EM CELSIUS **\n");
  printf("\nDigite a temperatura em Fahrenheit: ");
  scanf("%f", &F);
  C = 5.0 / 9.0 * (F - 32.0);
  printf("\nA temperatura em Celsius e: %i.\n", C);
  printf("\n\n<< Marco_Tulio >>");
  getchar(), getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D60(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  subsd  D39(%rip),%xmm0
  mulsd  D0(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D9(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D58
type_guessed: string
name: retrieve_data
arguments: data_tag: D26
type_guessed: string
name: retrieve_data
arguments: data_tag: D60
type_guessed: string
name: retrieve_data
arguments: data_tag: D39
type_guessed: f64
name: retrieve_data
arguments: data_tag: D0
type_guessed: byte[8]
name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string

tool: D58: 
 ** CONVERSOR DE TEMPERATURA FAHRENHEIT EM CELSIUS **

tool: D26: 
Digite a temperatura em Fahrenheit: 

tool: D60: %f

tool: D39: 32

tool: {"D0": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D9: 
A temperatura em Celsius e: %i.


tool: D17: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float F, C;
  printf("\n ** CONVERSOR DE TEMPERATURA FAHRENHEIT EM CELSIUS **\n");
  printf("\nDigite a temperatura em Fahrenheit: ");
  scanf("%f", &F);
  C = 5.0 / 9.0 * (F - 32.0);
  printf("\nA temperatura em Celsius e: %i.\n", C);
  printf("\n\n<< Marco_Tulio >>");
  getchar(), getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D64(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D63(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D69(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D17(%rip),%rdi
  cvtss2sd 0x4(%rsp),%xmm0
  subsd  D47(%rip),%xmm0
  mulsd  D15(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D64
data_type: string
name: retrieve_data
arguments: label: D63
data_type: string
name: retrieve_data
arguments: label: D69
data_type: string
name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D47
data_type: f64
name: retrieve_data
arguments: label: D15
data_type: byte[8]
name: retrieve_data
arguments: label: D5
data_type: string

tool: D64: 
 ** CONVERSOR DE TEMPERATURA FAHRENHEIT EM CELSIUS **

tool: D63: 
Digite a temperatura em Fahrenheit: 

tool: D69: %f

tool: D17: 
A temperatura em Celsius e: %i.


tool: D47: 32

tool: {"D15": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D5: 

<< Marco_Tulio >>

assistant: ```c
main() {
  float F, C;
  printf("\n ** CONVERSOR DE TEMPERATURA FAHRENHEIT EM CELSIUS **\n");
  printf("\nDigite a temperatura em Fahrenheit: ");
  scanf("%f", &F);
  C = 5.0 / 9.0 * (F - 32.0);
  printf("\nA temperatura em Celsius e: %i.\n", C);
  printf("\n\n<< Marco_Tulio >>");
  getchar(), getchar();
}
```