ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<su_use_stack>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x10000(%rsp),%r11
L42:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L42
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10018(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <rand@plt>
  lea    0x10(%rsp),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0x4000,%edx
  sub    %ecx,%eax
  mov    %eax,%esi
  call   <memset@plt>
  lea    0xc(%rsp),%rdi
  sub    %ebp,%edi
  call   <labs@plt>
  add    $0x4000,%eax
  cltq
  cmp    %r12,%rax
  jl     L7
L58:
  mov    0x10018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10028,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  xor    %eax,%eax
  call   <rand@plt>
  lea    0x4010(%rsp),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0x4000,%edx
  sub    %ecx,%eax
  mov    %eax,%esi
  call   <memset@plt>
  lea    0xd(%rsp),%rdi
  sub    %ebp,%edi
  call   <labs@plt>
  add    $0x4000,%eax
  cltq
  cmp    %rax,%r12
  jle    L58
  xor    %eax,%eax
  call   <rand@plt>
  lea    0x8010(%rsp),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0x4000,%edx
  sub    %ecx,%eax
  mov    %eax,%esi
  call   <memset@plt>
  lea    0xe(%rsp),%rdi
  sub    %ebp,%edi
  call   <labs@plt>
  add    $0x4000,%eax
  cltq
  cmp    %rax,%r12
  jle    L58
  xor    %eax,%eax
  call   <rand@plt>
  lea    0xc010(%rsp),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0x4000,%edx
  sub    %ecx,%eax
  mov    %eax,%esi
  call   <memset@plt>
  lea    0xf(%rsp),%rdi
  sub    %ebp,%edi
  call   <labs@plt>
  add    $0x4000,%eax
  cltq
  cmp    %rax,%r12
  jle    L58
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <su_use_stack>
  jmp    L58
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void su_use_stack(char *base, long size) {
  char arr[(16 * 1024)];
  char here;
  memset(arr, rand() % 255, (16 * 1024));
  if ((labs(&here - base) + (16 * 1024)) < size) {
    su_use_stack(base, size);
  } else {
    return;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<su_use_stack>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x10000(%rsp),%r11
L66:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L66
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10018(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <rand@plt>
  lea    0x10(%rsp),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0x4000,%edx
  sub    %ecx,%eax
  mov    %eax,%esi
  call   <memset@plt>
  lea    0xc(%rsp),%rdi
  sub    %ebp,%edi
  call   <labs@plt>
  add    $0x4000,%eax
  cltq
  cmp    %r12,%rax
  jl     L26
L62:
  mov    0x10018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10028,%rsp
  pop    %rbp
  pop    %r12
  ret
L26:
  xor    %eax,%eax
  call   <rand@plt>
  lea    0x4010(%rsp),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0x4000,%edx
  sub    %ecx,%eax
  mov    %eax,%esi
  call   <memset@plt>
  lea    0xd(%rsp),%rdi
  sub    %ebp,%edi
  call   <labs@plt>
  add    $0x4000,%eax
  cltq
  cmp    %rax,%r12
  jle    L62
  xor    %eax,%eax
  call   <rand@plt>
  lea    0x8010(%rsp),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0x4000,%edx
  sub    %ecx,%eax
  mov    %eax,%esi
  call   <memset@plt>
  lea    0xe(%rsp),%rdi
  sub    %ebp,%edi
  call   <labs@plt>
  add    $0x4000,%eax
  cltq
  cmp    %rax,%r12
  jle    L62
  xor    %eax,%eax
  call   <rand@plt>
  lea    0xc010(%rsp),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0x4000,%edx
  sub    %ecx,%eax
  mov    %eax,%esi
  call   <memset@plt>
  lea    0xf(%rsp),%rdi
  sub    %ebp,%edi
  call   <labs@plt>
  add    $0x4000,%eax
  cltq
  cmp    %rax,%r12
  jle    L62
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <su_use_stack>
  jmp    L62
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void su_use_stack(char *base, long size) {
  char arr[(16 * 1024)];
  char here;
  memset(arr, rand() % 255, (16 * 1024));
  if ((labs(&here - base) + (16 * 1024)) < size) {
    su_use_stack(base, size);
  } else {
    return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x6(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x6(%rbp),%eax
  movzbl -0x5(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  cmpb   $0x0,-0x6(%rbp)
  jne    L23
  jmp    L13
L8:
  nop
L13:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *cs, const char *ct) {
  unsigned char c1, c2;
  int res = 0;
  do {
    c1 = *cs++;
    c2 = *ct++;
    res = c1 - c2;
    if (res)
      break;
  } while (c1);
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcmp>:
  endbr64
  mov    $0x0,%edx
L6:
  movzbl (%rdi,%rdx,1),%ecx
  movzbl %cl,%eax
  movzbl (%rsi,%rdx,1),%r8d
  sub    %r8d,%eax
  add    $0x1,%rdx
  test   %cl,%cl
  je     L16
  test   %eax,%eax
  je     L6
L16:
  ret
```

assistant: ```c
int strcmp(const char *cs, const char *ct) {
  unsigned char c1, c2;
  int res = 0;
  do {
    c1 = *cs++;
    c2 = *ct++;
    res = c1 - c2;
    if (res)
      break;
  } while (c1);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcmp>:
  endbr64
  xor    %edx,%edx
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rdx
  test   %r8b,%r8b
  je     L0
L3:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  mov    %eax,%r8d
  sub    %ecx,%eax
  je     L11
L0:
  ret
```

assistant: ```c
int strcmp(const char *cs, const char *ct) {
  unsigned char c1, c2;
  int res = 0;
  do {
    c1 = *cs++;
    c2 = *ct++;
    res = c1 - c2;
    if (res)
      break;
  } while (c1);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strcmp>:
  endbr64
  xor    %edx,%edx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rdx
  test   %r8b,%r8b
  je     L26
L1:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  mov    %eax,%r8d
  sub    %ecx,%eax
  je     L25
L26:
  ret
```

assistant: ```c
int strcmp(const char *cs, const char *ct) {
  unsigned char c1, c2;
  int res = 0;
  do {
    c1 = *cs++;
    c2 = *ct++;
    res = c1 - c2;
    if (res)
      break;
  } while (c1);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<showUsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: usage: %s [-2] [-s seconds] <ifile> <ofile>
 -2   use 2400 baud as output baudrate
 -s   define gap time (in seconds) between blocks (default 2)


assistant: ```c
void showUsage(char *progname) {
  printf("usage: %s [-2] [-s seconds] <ifile> <ofile>\n"
         " -2   use 2400 baud as output baudrate\n"
         " -s   define gap time (in seconds) between blocks (default 2)\n",
         progname);
}
```
user: What is the c source code of the assembly code below?

```asm
<showUsage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: usage: %s [-2] [-s seconds] <ifile> <ofile>
 -2   use 2400 baud as output baudrate
 -s   define gap time (in seconds) between blocks (default 2)


assistant: ```c
void showUsage(char *progname) {
  printf("usage: %s [-2] [-s seconds] <ifile> <ofile>\n"
         " -2   use 2400 baud as output baudrate\n"
         " -s   define gap time (in seconds) between blocks (default 2)\n",
         progname);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<showUsage>:
  endbr64
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: usage: %s [-2] [-s seconds] <ifile> <ofile>
 -2   use 2400 baud as output baudrate
 -s   define gap time (in seconds) between blocks (default 2)


assistant: ```c
void showUsage(char *progname) {
  printf("usage: %s [-2] [-s seconds] <ifile> <ofile>\n"
         " -2   use 2400 baud as output baudrate\n"
         " -s   define gap time (in seconds) between blocks (default 2)\n",
         progname);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<showUsage>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: usage: %s [-2] [-s seconds] <ifile> <ofile>
 -2   use 2400 baud as output baudrate
 -s   define gap time (in seconds) between blocks (default 2)


assistant: ```c
void showUsage(char *progname) {
  printf("usage: %s [-2] [-s seconds] <ifile> <ofile>\n"
         " -2   use 2400 baud as output baudrate\n"
         " -s   define gap time (in seconds) between blocks (default 2)\n",
         progname);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <series@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <series@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x5,%edi
  call   <series@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x6,%edi
  call   <series@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x30(%rbp)
  movsd  -0x48(%rbp),%xmm1
  movsd  D21(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  subsd  -0x38(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D13(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    $0x10,%edi
  movq   %rax,%xmm0
  call   <ihex@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x4c(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
type_infered: f64
name: read_data
arguments: data_label: D13
type_infered: f64
name: read_data
arguments: data_label: D17
type_infered: string

tool: D21: 4

tool: D13: 1

tool: D17:  position = %i
 fraction = %.15f 
 hex digits =  %10.10s


assistant: ```c
main() {
  double pid, s1, s2, s3, s4;
  double series(int m, int n);
  void ihex(double x, int m, char c[]);
  int id = 0;
  char chx[16];
  s1 = series(1, id);
  s2 = series(4, id);
  s3 = series(5, id);
  s4 = series(6, id);
  pid = 4. * s1 - 2. * s2 - s3 - s4;
  pid = pid - (int)pid + 1.;
  ihex(pid, 16, chx);
  printf(" position = %i\n fraction = %.15f \n hex digits =  %10.10s\n", id, pid, chx);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <series@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <series@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%esi
  mov    $0x5,%edi
  call   <series@plt>
  movq   %xmm0,%r14
  mov    $0x0,%esi
  mov    $0x6,%edi
  call   <series@plt>
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm3
  mulsd  D0(%rip),%xmm3
  movapd %xmm3,%xmm0
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm1
  subsd  %xmm1,%xmm0
  movq   %r14,%xmm4
  subsd  %xmm4,%xmm0
  subsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  addsd  D4(%rip),%xmm0
  movq   %xmm0,%r14
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0x10,%edi
  call   <ihex@plt>
  mov    %rbx,%rdx
  movq   %r14,%xmm0
  mov    $0x0,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: f64
name: disassemble_data
arguments: tag: D4
type_guessed: f64
name: disassemble_data
arguments: tag: D18
type_guessed: string

tool: D0: 4

tool: D4: 1

tool: D18:  position = %i
 fraction = %.15f 
 hex digits =  %10.10s


assistant: ```c
main() {
  double pid, s1, s2, s3, s4;
  double series(int m, int n);
  void ihex(double x, int m, char c[]);
  int id = 0;
  char chx[16];
  s1 = series(1, id);
  s2 = series(4, id);
  s3 = series(5, id);
  s4 = series(6, id);
  pid = 4. * s1 - 2. * s2 - s3 - s4;
  pid = pid - (int)pid + 1.;
  ihex(pid, 16, chx);
  printf(" position = %i\n fraction = %.15f \n hex digits =  %10.10s\n", id, pid, chx);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x1,%edi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  call   <series@plt>
  xor    %esi,%esi
  mov    $0x4,%edi
  movsd  %xmm0,0x18(%rsp)
  call   <series@plt>
  xor    %esi,%esi
  mov    $0x5,%edi
  movsd  %xmm0,0x10(%rsp)
  call   <series@plt>
  xor    %esi,%esi
  mov    $0x6,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <series@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
  mov    %r12,%rsi
  mulsd  D14(%rip),%xmm1
  movapd %xmm0,%xmm3
  mov    $0x10,%edi
  addsd  %xmm2,%xmm2
  movapd %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  subsd  %xmm2,%xmm0
  subsd  0x8(%rsp),%xmm0
  subsd  %xmm3,%xmm0
  cvttsd2si %xmm0,%eax
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  addsd  D0(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <ihex@plt>
  movsd  0x8(%rsp),%xmm0
  xor    %esi,%esi
  mov    %r12,%rdx
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: f64
name: extract_symbolic_data
arguments: label: D0
type: f64
name: extract_symbolic_data
arguments: label: D15
type: string

tool: D14: 4

tool: D0: 1

tool: D15:  position = %i
 fraction = %.15f 
 hex digits =  %10.10s


assistant: ```c
main() {
  double pid, s1, s2, s3, s4;
  double series(int m, int n);
  void ihex(double x, int m, char c[]);
  int id = 0;
  char chx[16];
  s1 = series(1, id);
  s2 = series(4, id);
  s3 = series(5, id);
  s4 = series(6, id);
  pid = 4. * s1 - 2. * s2 - s3 - s4;
  pid = pid - (int)pid + 1.;
  ihex(pid, 16, chx);
  printf(" position = %i\n fraction = %.15f \n hex digits =  %10.10s\n", id, pid, chx);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x1,%edi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  call   <series@plt>
  xor    %esi,%esi
  mov    $0x4,%edi
  movsd  %xmm0,0x18(%rsp)
  call   <series@plt>
  xor    %esi,%esi
  mov    $0x5,%edi
  movsd  %xmm0,0x10(%rsp)
  call   <series@plt>
  xor    %esi,%esi
  mov    $0x6,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <series@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
  mov    %r12,%rsi
  mulsd  D20(%rip),%xmm1
  movapd %xmm0,%xmm3
  mov    $0x10,%edi
  addsd  %xmm2,%xmm2
  movapd %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  subsd  %xmm2,%xmm0
  subsd  0x8(%rsp),%xmm0
  subsd  %xmm3,%xmm0
  cvttsd2si %xmm0,%eax
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  addsd  D12(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <ihex@plt>
  movsd  0x8(%rsp),%xmm0
  xor    %esi,%esi
  mov    %r12,%rdx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D20
data_type: f64
name: unpack_data
arguments: tag: D12
data_type: f64
name: unpack_data
arguments: tag: D4
data_type: string

tool: D20: 4

tool: D12: 1

tool: D4:  position = %i
 fraction = %.15f 
 hex digits =  %10.10s


assistant: ```c
main() {
  double pid, s1, s2, s3, s4;
  double series(int m, int n);
  void ihex(double x, int m, char c[]);
  int id = 0;
  char chx[16];
  s1 = series(1, id);
  s2 = series(4, id);
  s3 = series(5, id);
  s4 = series(6, id);
  pid = 4. * s1 - 2. * s2 - s3 - s4;
  pid = pid - (int)pid + 1.;
  ihex(pid, 16, chx);
  printf(" position = %i\n fraction = %.15f \n hex digits =  %10.10s\n", id, pid, chx);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<powi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L0
  movl   $0x1,-0x8(%rbp)
  jmp    L26
L0:
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L23:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L23
L26:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int powi(int base, int exponent) {
  int result = base;
  int i;
  if (exponent == 0) {
    result = 1;
  } else {
    for (i = 0; i < exponent - 1; ++i) {
      result *= base;
    }
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<powi>:
  endbr64
  mov    $0x1,%edx
  test   %esi,%esi
  je     L15
  cmp    $0x1,%esi
  jle    L4
  sub    $0x1,%esi
  mov    %edi,%edx
  mov    $0x0,%eax
L9:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L9
L15:
  mov    %edx,%eax
  ret
L4:
  mov    %edi,%edx
  jmp    L15
```

assistant: ```c
int powi(int base, int exponent) {
  int result = base;
  int i;
  if (exponent == 0) {
    result = 1;
  } else {
    for (i = 0; i < exponent - 1; ++i) {
      result *= base;
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<powi>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L24
  sub    $0x1,%esi
  mov    %edi,%r8d
  test   %esi,%esi
  jle    L24
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L17
L24:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int powi(int base, int exponent) {
  int result = base;
  int i;
  if (exponent == 0) {
    result = 1;
  } else {
    for (i = 0; i < exponent - 1; ++i) {
      result *= base;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<powi>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L18
  sub    $0x1,%esi
  mov    %edi,%r8d
  test   %esi,%esi
  jle    L18
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L23:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L23
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int powi(int base, int exponent) {
  int result = base;
  int i;
  if (exponent == 0) {
    result = 1;
  } else {
    for (i = 0; i < exponent - 1; ++i) {
      result *= base;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_filenames>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  cmp    $0x1,%r14d
  jle    L36
  mov    $0x1,%ebx
  jmp    L57
L73:
  add    $0x1,%ebx
  mov    0x8(%r13,%rbp,1),%rax
  mov    %rax,(%r15)
L97:
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jle    L36
L57:
  movslq %ebx,%rbp
  shl    $0x3,%rbp
  lea    0x0(%r13,%rbp,1),%r12
  lea    D26(%rip),%rsi
  mov    (%r12),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L73
  lea    D15(%rip),%rsi
  mov    (%r12),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L60
  add    $0x1,%ebx
  mov    0x8(%r13,%rbp,1),%rax
  mov    %rax,0x8(%r15)
  jmp    L97
L60:
  lea    D24(%rip),%rsi
  mov    (%r12),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L74
  add    $0x1,%ebx
  mov    0x8(%r13,%rbp,1),%rax
  mov    %rax,0x10(%r15)
  jmp    L97
L74:
  lea    D25(%rip),%rsi
  mov    (%r12),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L97
  add    $0x1,%ebx
  mov    0x8(%r13,%rbp,1),%rax
  mov    %rax,0x18(%r15)
  jmp    L97
L36:
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D26
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D24
datatype: string
name: read_data
arguments: data_tag: D25
datatype: string

tool: D26: --or

tool: D15: --and

tool: D24: --impl

tool: D25: --not

assistant: ```c
char **get_filenames(int argc, char **argv) {
  char **filenames = malloc(4 * sizeof(char *));
  for (int i = 1; i < argc; i++) {
    if (strcmp(argv[i], "--or") == 0) {
      i++;
      filenames[0] = argv[i];
    } else {
      if (strcmp(argv[i], "--and") == 0) {
        i++;
        filenames[1] = argv[i];
      } else {
        if (strcmp(argv[i], "--impl") == 0) {
          i++;
          filenames[2] = argv[i];
        } else {
          if (strcmp(argv[i], "--not") == 0) {
            i++;
            filenames[3] = argv[i];
          }
        }
      }
    }
  }
  return filenames;
}
```