ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L14
  cmpl   $0x0,-0x1c(%rbp)
  jg     L31
L14:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  jmp    L11
L31:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L21:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movss  (%rax),%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  movss  -0x8(%rbp),%xmm0
L11:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: input error


assistant: ```c
float sum_array(float *arr, int len) {
  if (NULL == arr || len < 1) {
    printf("input error\n");
    return 0;
  }
  float sum = 0.0;
  for (int i = 0; i < len; ++i) {
    sum += *arr++;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sum_array>:
  endbr64
  test   %rdi,%rdi
  je     L14
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  jle    L14
L8:
  addss  (%rdi,%rax,4),%xmm0
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L8
  ret
L14:
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: input error


assistant: ```c
float sum_array(float *arr, int len) {
  if (NULL == arr || len < 1) {
    printf("input error\n");
    return 0;
  }
  float sum = 0.0;
  for (int i = 0; i < len; ++i) {
    sum += *arr++;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum_array>:
  endbr64
  test   %rdi,%rdi
  je     L7
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  jle    L7
  nopl   0x0(%rax,%rax,1)
L18:
  addss  (%rdi,%rax,4),%xmm0
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L18
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: input error


assistant: ```c
float sum_array(float *arr, int len) {
  if (NULL == arr || len < 1) {
    printf("input error\n");
    return 0;
  }
  float sum = 0.0;
  for (int i = 0; i < len; ++i) {
    sum += *arr++;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum_array>:
  endbr64
  test   %rdi,%rdi
  je     L38
  test   %esi,%esi
  jle    L38
  mov    %rdi,%rdx
  mov    $0x1,%edi
  cmovg  %esi,%edi
  cmp    $0x3,%esi
  jle    L0
  mov    %edi,%ecx
  pxor   %xmm0,%xmm0
  mov    %rdx,%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdx,%rcx,1),%rcx
  nopl   0x0(%rax)
L6:
  movups (%rax),%xmm1
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L6
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%ecx
  lea    (%rdx,%rcx,4),%rdx
  cmp    %eax,%edi
  je     L9
L50:
  lea    0x1(%rax),%ecx
  addss  (%rdx),%xmm0
  cmp    %ecx,%esi
  jle    L22
  add    $0x2,%eax
  addss  0x4(%rdx),%xmm0
  cmp    %eax,%esi
  jle    L22
  addss  0x8(%rdx),%xmm0
  ret
  nopl   0x0(%rax)
L22:
  ret
  nopl   0x0(%rax)
L38:
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L50
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: D9: input error


assistant: ```c
float sum_array(float *arr, int len) {
  if (NULL == arr || len < 1) {
    printf("input error\n");
    return 0;
  }
  float sum = 0.0;
  for (int i = 0; i < len; ++i) {
    sum += *arr++;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L16
L21:
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L16:
  cmpl   $0x9,-0x34(%rbp)
  jle    L21
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type: string

tool: D12: %d

assistant: ```c
int main() {
  int x[10], key;
  for (int i = 0; i < 10; ++i)
    scanf("%d", &x[i]);
  scanf("%d", &key);
  printf("%d", search(x, 0, 9, key));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x38(%rsp),%r12
  lea    D18(%rip),%rbp
L17:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  lea    0xc(%rsp),%rsi
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%ecx
  mov    $0x9,%edx
  mov    $0x0,%esi
  call   <search@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string

tool: D18: %d

assistant: ```c
int main() {
  int x[10], key;
  for (int i = 0; i < 10; ++i)
    scanf("%d", &x[i]);
  scanf("%d", &key);
  printf("%d", search(x, 0, 9, key));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x38(%rsp),%r12
  mov    %r13,%rbx
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L16
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    $0x9,%edx
  call   <search@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: %d

assistant: ```c
int main() {
  int x[10], key;
  for (int i = 0; i < 10; ++i)
    scanf("%d", &x[i]);
  scanf("%d", &key);
  printf("%d", search(x, 0, 9, key));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x38(%rsp),%r12
  mov    %r13,%rbx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L3
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    $0x9,%edx
  call   <search@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: %d

assistant: ```c
int main() {
  int x[10], key;
  for (int i = 0; i < 10; ++i)
    scanf("%d", &x[i]);
  scanf("%d", &key);
  printf("%d", search(x, 0, 9, key));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D37
type_guessed: string
name: disassemble_data
arguments: data_label: D19
type_guessed: string
name: disassemble_data
arguments: data_label: D34
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string

tool: D37: sizeof(char) ==> %d


tool: D19: sizeof(int) ==> %d


tool: D34: sizeof(double) ==> %d


tool: D11: sizeof(pad) ==> %d


assistant: ```c
int main() {
  struct {
    char a;
    int b;
    double c;
  } pad;
  printf("sizeof(char)"
         " ==> %d\n",
         sizeof(char));
  printf("sizeof(int)"
         " ==> %d\n",
         sizeof(int));
  printf("sizeof(double)"
         " ==> %d\n",
         sizeof(double));
  printf("sizeof(pad)"
         " ==> %d\n",
         sizeof(pad));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D3
type: string
name: read_data
arguments: data_label: D37
type: string

tool: D16: sizeof(char) ==> %d


tool: D1: sizeof(int) ==> %d


tool: D3: sizeof(double) ==> %d


tool: D37: sizeof(pad) ==> %d


assistant: ```c
int main() {
  struct {
    char a;
    int b;
    double c;
  } pad;
  printf("sizeof(char)"
         " ==> %d\n",
         sizeof(char));
  printf("sizeof(int)"
         " ==> %d\n",
         sizeof(int));
  printf("sizeof(double)"
         " ==> %d\n",
         sizeof(double));
  printf("sizeof(pad)"
         " ==> %d\n",
         sizeof(pad));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D39
type_guessed: string
name: parse_data
arguments: data_label: D36
type_guessed: string
name: parse_data
arguments: data_label: D1
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D39: sizeof(char) ==> %d


tool: D36: sizeof(int) ==> %d


tool: D1: sizeof(double) ==> %d


tool: D8: sizeof(pad) ==> %d


assistant: ```c
int main() {
  struct {
    char a;
    int b;
    double c;
  } pad;
  printf("sizeof(char)"
         " ==> %d\n",
         sizeof(char));
  printf("sizeof(int)"
         " ==> %d\n",
         sizeof(int));
  printf("sizeof(double)"
         " ==> %d\n",
         sizeof(double));
  printf("sizeof(pad)"
         " ==> %d\n",
         sizeof(pad));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D21
type: string
name: read_data
arguments: tag: D38
type: string
name: read_data
arguments: tag: D19
type: string
name: read_data
arguments: tag: D39
type: string

tool: D21: sizeof(char) ==> %d


tool: D38: sizeof(int) ==> %d


tool: D19: sizeof(double) ==> %d


tool: D39: sizeof(pad) ==> %d


assistant: ```c
int main() {
  struct {
    char a;
    int b;
    double c;
  } pad;
  printf("sizeof(char)"
         " ==> %d\n",
         sizeof(char));
  printf("sizeof(int)"
         " ==> %d\n",
         sizeof(int));
  printf("sizeof(double)"
         " ==> %d\n",
         sizeof(double));
  printf("sizeof(pad)"
         " ==> %d\n",
         sizeof(pad));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wc_get_word_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %edi,-0x1034(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x1028(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1034(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  jmp    L29
L37:
  movq   $0x1,-0x1020(%rbp)
  jmp    L4
L54:
  mov    -0x1020(%rbp),%rax
  sub    $0x1,%rax
  movzbl -0x1010(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L39
  lea    -0x1010(%rbp),%rdx
  mov    -0x1020(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L39
  addq   $0x1,-0x1028(%rbp)
L39:
  addq   $0x1,-0x1020(%rbp)
L4:
  mov    -0x1020(%rbp),%rax
  cmp    -0x1018(%rbp),%rax
  jb     L54
L29:
  lea    -0x1010(%rbp),%rcx
  mov    -0x1034(%rbp),%eax
  mov    $0x1000,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x1018(%rbp)
  cmpq   $0x0,-0x1018(%rbp)
  jne    L37
  mov    -0x1028(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
size_t wc_get_word_count(int fd) {
  char buf[4096];
  size_t num = 0;
  ssize_t n;
  lseek(fd, 0, SEEK_SET);
  while ((n = read(fd, buf, 4096)) > 0) {
    for (size_t i = 1; i < n; i++) {
      if (!isspace(buf[i - 1]) && isspace(buf[i])) {
        num++;
      }
    }
  }
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wc_get_word_count>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %edi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <lseek@plt>
  mov    $0x0,%r12d
  mov    %rsp,%r13
L61:
  mov    $0x1000,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L57
  lea    0x1(%rsp),%rbx
  lea    0x0(%r13,%rax,1),%rbp
  cmp    $0x1,%rax
  ja     L62
  jmp    L61
L55:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L61
L62:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L55
  movsbl (%rbx),%edi
  call   <isspace@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r12
  jmp    L55
L57:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %r12,%rax
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wc_get_word_count(int fd) {
  char buf[4096];
  size_t num = 0;
  ssize_t n;
  lseek(fd, 0, SEEK_SET);
  while ((n = read(fd, buf, 4096)) > 0) {
    for (size_t i = 1; i < n; i++) {
      if (!isspace(buf[i - 1]) && isspace(buf[i])) {
        num++;
      }
    }
  }
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wc_get_word_count>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  xor    %esi,%esi
  xor    %r12d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  mov    D4(%rip),%rax
  mov    %edi,%r14d
  mov    %rsp,%r13
  mov    (%rax),%edx
  call   <lseek@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0x1000,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L14
  lea    0x1(%rsp),%rbx
  lea    0x0(%r13,%rax,1),%rbp
  cmp    $0x1,%rax
  jne    L22
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L4
L22:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  movsbl (%rbx),%edi
  call   <isspace@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r12
  jmp    L2
  nopl   0x0(%rax)
L14:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x1010,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wc_get_word_count(int fd) {
  char buf[4096];
  size_t num = 0;
  ssize_t n;
  lseek(fd, 0, SEEK_SET);
  while ((n = read(fd, buf, 4096)) > 0) {
    for (size_t i = 1; i < n; i++) {
      if (!isspace(buf[i - 1]) && isspace(buf[i])) {
        num++;
      }
    }
  }
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wc_get_word_count>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  xor    %esi,%esi
  xor    %r12d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  mov    D0(%rip),%rax
  mov    %edi,%r14d
  mov    %rsp,%r13
  mov    (%rax),%edx
  call   <lseek@plt>
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    $0x1000,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L68
  lea    0x1(%rsp),%rbx
  lea    0x0(%r13,%rax,1),%rbp
  cmp    $0x1,%rax
  jne    L6
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L33
L6:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
  movsbl (%rbx),%edi
  call   <isspace@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r12
  jmp    L18
  nopl   0x0(%rax)
L68:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x1010,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wc_get_word_count(int fd) {
  char buf[4096];
  size_t num = 0;
  ssize_t n;
  lseek(fd, 0, SEEK_SET);
  while ((n = read(fd, buf, 4096)) > 0) {
    for (size_t i = 1; i < n; i++) {
      if (!isspace(buf[i - 1]) && isspace(buf[i])) {
        num++;
      }
    }
  }
  return num;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  movl   $0x0,(%rax)
  lea    -0x60(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x70(%rbp)
  mov    -0x70(%rbp),%rax
  lea    -0x60(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main(void) {
  int u[20];
  int *p = malloc(sizeof(int) * 100);
  int *n;
  int *x;
  p[0] = 0;
  n = (int *)((long)p + (long)u);
  x = (int *)((long)n - (long)u);
  x[0] = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int u[20];
  int *p = malloc(sizeof(int) * 100);
  int *n;
  int *x;
  p[0] = 0;
  n = (int *)((long)p + (long)u);
  x = (int *)((long)n - (long)u);
  x[0] = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int u[20];
  int *p = malloc(sizeof(int) * 100);
  int *n;
  int *x;
  p[0] = 0;
  n = (int *)((long)p + (long)u);
  x = (int *)((long)n - (long)u);
  x[0] = 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int u[20];
  int *p = malloc(sizeof(int) * 100);
  int *n;
  int *x;
  p[0] = 0;
  n = (int *)((long)p + (long)u);
  x = (int *)((long)n - (long)u);
  x[0] = 0;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<IsBlankline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L31
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L17
  mov    $0x0,%eax
  jmp    L0
L17:
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x1,%eax
L0:
  leave
  ret
```

assistant: ```c
int IsBlankline(char *s) {
  for (; *s != '\0'; s++)
    if (!isspace(*s))
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<IsBlankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L30
L18:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L24
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
  mov    $0x1,%eax
L24:
  pop    %rbx
  ret
L30:
  mov    $0x1,%eax
  jmp    L24
```

assistant: ```c
int IsBlankline(char *s) {
  for (; *s != '\0'; s++)
    if (!isspace(*s))
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<IsBlankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L29
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L11
L29:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L27
  pop    %rbx
  ret
L11:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int IsBlankline(char *s) {
  for (; *s != '\0'; s++)
    if (!isspace(*s))
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<IsBlankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L39
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L20:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L13
L39:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L20
  pop    %rbx
  ret
L13:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int IsBlankline(char *s) {
  for (; *s != '\0'; s++)
    if (!isspace(*s))
      return 0;
  return 1;
}
```