ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mat3_cofactor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mat3_minor@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L0
  movss  -0x4(%rbp),%xmm0
  jmp    L14
L0:
  movss  -0x4(%rbp),%xmm0
  movss  D1(%rip),%xmm1
  xorps  %xmm1,%xmm0
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x80]}

assistant: ```c
float mat3_cofactor(struct mat3 *mat, unsigned int col, unsigned int row) {
  float cofactor = mat3_minor(mat, col, row);
  if ((col + row) % 2 == 0)
    return cofactor;
  return -cofactor;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mat3_cofactor>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %edx,%ebp
  call   <mat3_minor@plt>
  add    %ebp,%ebx
  test   $0x1,%bl
  je     L2
  xorps  D0(%rip),%xmm0
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: byte[16]

tool: {"D0": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float mat3_cofactor(struct mat3 *mat, unsigned int col, unsigned int row) {
  float cofactor = mat3_minor(mat, col, row);
  if ((col + row) % 2 == 0)
    return cofactor;
  return -cofactor;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mat3_cofactor>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  add    %ebp,%ebx
  sub    $0x8,%rsp
  call   <mat3_minor@plt>
  and    $0x1,%ebx
  je     L2
  xorps  D1(%rip),%xmm0
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float mat3_cofactor(struct mat3 *mat, unsigned int col, unsigned int row) {
  float cofactor = mat3_minor(mat, col, row);
  if ((col + row) % 2 == 0)
    return cofactor;
  return -cofactor;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mat3_cofactor>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  add    %ebp,%ebx
  sub    $0x8,%rsp
  call   <mat3_minor@plt>
  and    $0x1,%ebx
  je     L3
  xorps  D9(%rip),%xmm0
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float mat3_cofactor(struct mat3 *mat, unsigned int col, unsigned int row) {
  float cofactor = mat3_minor(mat, col, row);
  if ((col + row) % 2 == 0)
    return cofactor;
  return -cofactor;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0xa,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L26
L46:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  jmp    L48
L57:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L28
  movl   $0x0,-0x18(%rbp)
L28:
  addl   $0x1,-0x14(%rbp)
L48:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L57
  cmpl   $0x1,-0x18(%rbp)
  jne    L40
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L40:
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L46
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: %d Prime


assistant: ```c
int main() {
  int check, a, i, m, n, j;
  m = 1;
  n = 10;
  for (j = m; j <= n; j++) {
    a = j;
    check = 1;
    for (i = 2; i < a; i++) {
      if (a % i == 0)
        check = 0;
    }
    if (check == 1)
      printf("%d Prime\n", a);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D5(%rip),%rbp
  jmp    L24
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L26:
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  je     L14
L24:
  mov    $0x2,%ecx
  mov    $0x1,%esi
  cmp    $0x2,%ebx
  jle    L7
L52:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %edx,%esi
  add    $0x1,%ecx
  cmp    %ebx,%ecx
  jne    L52
  cmp    $0x1,%esi
  jne    L26
  jmp    L7
L14:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: %d Prime


assistant: ```c
int main() {
  int check, a, i, m, n, j;
  m = 1;
  n = 10;
  for (j = m; j <= n; j++) {
    a = j;
    check = 1;
    for (i = 2; i < a; i++) {
      if (a % i == 0)
        check = 0;
    }
    if (check == 1)
      printf("%d Prime\n", a);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0x2,%ecx
  mov    $0x1,%esi
  xor    %edi,%edi
  cmp    $0x2,%r12d
  jle    L3
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %edi,%esi
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jne    L32
  cmp    $0x1,%esi
  je     L3
L48:
  add    $0x1,%r12d
  cmp    $0xb,%r12d
  jne    L25
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L48
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: %d Prime


assistant: ```c
int main() {
  int check, a, i, m, n, j;
  m = 1;
  n = 10;
  for (j = m; j <= n; j++) {
    a = j;
    check = 1;
    for (i = 2; i < a; i++) {
      if (a % i == 0)
        check = 0;
    }
    if (check == 1)
      printf("%d Prime\n", a);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    $0xcccccccd,%r12d
  push   %rbp
  mov    $0xaaaaaaab,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L208
  nopw   0x0(%rax,%rax,1)
L55:
  cmp    $0x3,%ebx
  je     L120
L104:
  mov    %ebx,%eax
  mov    %rax,%rdx
  imul   %rbp,%rdx
  shr    $0x21,%rdx
  lea    (%rdx,%rdx,2),%edx
  cmp    %edx,%ebx
  je     L118
  cmp    $0x4,%ebx
  je     L167
  test   $0x3,%bl
  je     L37
L15:
  cmp    $0x5,%ebx
  je     L167
L92:
  mov    %rax,%rdx
  imul   %r12,%rdx
  shr    $0x22,%rdx
  lea    (%rdx,%rdx,4),%edx
  cmp    %edx,%ebx
  je     L12
  cmp    $0x6,%ebx
  je     L167
L220:
  mov    %rax,%rdx
  imul   %rbp,%rdx
  shr    $0x22,%rdx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  cmp    %edx,%ebx
  je     L50
  cmp    $0x7,%ebx
  je     L167
L151:
  imul   $0x24924925,%rax,%rdx
  mov    %ebx,%eax
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  cmp    %edx,%ebx
  je     L120
L167:
  cmp    $0x1,%ecx
  je     L139
L120:
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  je     L19
L208:
  cmp    $0x2,%ebx
  jle    L139
  mov    %ebx,%ecx
  and    $0x1,%ecx
  je     L55
  cmp    $0x3,%ebx
  jne    L104
L139:
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L208
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L118:
  xor    %ecx,%ecx
  cmp    $0x4,%ebx
  je     L120
  test   $0x3,%bl
  jne    L15
L37:
  xor    %ecx,%ecx
  cmp    $0x5,%ebx
  jne    L92
  jmp    L120
  nopl   (%rax)
L12:
  xor    %ecx,%ecx
  cmp    $0x6,%ebx
  jne    L220
  jmp    L120
  nopl   (%rax)
L50:
  xor    %ecx,%ecx
  cmp    $0x7,%ebx
  jne    L151
  jmp    L120
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: %d Prime


assistant: ```c
int main() {
  int check, a, i, m, n, j;
  m = 1;
  n = 10;
  for (j = m; j <= n; j++) {
    a = j;
    check = 1;
    for (i = 2; i < a; i++) {
      if (a % i == 0)
        check = 0;
    }
    if (check == 1)
      printf("%d Prime\n", a);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L0
  mov    $0x1,%edi
  call   <hash@plt>
  mov    $0x0,%edi
  call   <hash@plt>
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    $0x2,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L76
L69:
  cmpl   $0x0,-0x8(%rbp)
  jle    L36
  mov    $0x2,%edi
  call   <hash@plt>
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    $0x0,%edi
  call   <hash@plt>
L36:
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L34
L60:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <hash@plt>
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L39
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  jmp    L18
L39:
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  sub    $0x2,%eax
L18:
  cmp    -0x4(%rbp),%eax
  jge    L60
  cmpl   $0x0,-0x8(%rbp)
  jg     L7
  mov    $0x1,%edi
  call   <hash@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <hash@plt>
L7:
  addl   $0x1,-0x8(%rbp)
L76:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L69
  mov    $0x2,%edi
  call   <hash@plt>
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    $0x0,%edi
  call   <hash@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void test(int N) {
  int p;
  int i, j;
  if (N >= 1) {
    {
      hash(1);
      hash(0);
      hash(N - 1);
    };
    for (p = -N + 2; p <= N - 1; p++) {
      if (p >= 1) {
        {
          hash(2);
          hash(p - 1);
          hash(0);
        };
      }
      for (i = ((0) > (p) ? (0) : (p)); i <= ((N - 1) < (p + N - 2) ? (N - 1) : (p + N - 2)); i++) {
        {
          hash(1);
          hash(i);
          hash(-p + i);
        };
        {
          hash(2);
          hash(i);
          hash(-p + i + 1);
        };
      }
      if (p <= 0) {
        {
          hash(1);
          hash(p + N - 1);
          hash(N - 1);
        };
      }
    }
    {
      hash(2);
      hash(N - 1);
      hash(0);
    };
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x8(%rsp)
  test   %edi,%edi
  jg     L104
L73:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L104:
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <hash@plt>
  mov    $0x0,%edi
  call   <hash@plt>
  lea    -0x1(%rbx),%eax
  mov    %eax,0xc(%rsp)
  mov    %eax,%edi
  call   <hash@plt>
  mov    $0x2,%r14d
  sub    %ebx,%r14d
  cmp    %r14d,%ebx
  jle    L72
  mov    $0x0,%r13d
  jmp    L29
L92:
  mov    $0x2,%edi
  call   <hash@plt>
  lea    -0x1(%r14),%edi
  call   <hash@plt>
  mov    $0x0,%edi
  call   <hash@plt>
  jmp    L23
L48:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  mov    %r12d,%ebp
L106:
  lea    0x1(%rbp),%r12d
  cmp    %r13d,%ebx
  jle    L48
  test   %r14d,%r14d
  jle    L68
L35:
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  je     L72
  mov    %r15d,%r13d
L29:
  test   %r14d,%r14d
  jg     L92
L23:
  test   %r14d,%r14d
  mov    $0x0,%ebx
  cmovns %r14d,%ebx
  lea    0x1(%r13),%r15d
  cmp    %r15d,0x8(%rsp)
  cmovl  0xc(%rsp),%r13d
  mov    %ebx,%ebp
  sub    %r14d,%ebp
  jmp    L106
L68:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r15d,%edi
  call   <hash@plt>
  mov    0xc(%rsp),%edi
  call   <hash@plt>
  jmp    L35
L72:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    0xc(%rsp),%edi
  call   <hash@plt>
  mov    $0x0,%edi
  call   <hash@plt>
  jmp    L73
```

assistant: ```c
void test(int N) {
  int p;
  int i, j;
  if (N >= 1) {
    {
      hash(1);
      hash(0);
      hash(N - 1);
    };
    for (p = -N + 2; p <= N - 1; p++) {
      if (p >= 1) {
        {
          hash(2);
          hash(p - 1);
          hash(0);
        };
      }
      for (i = ((0) > (p) ? (0) : (p)); i <= ((N - 1) < (p + N - 2) ? (N - 1) : (p + N - 2)); i++) {
        {
          hash(1);
          hash(i);
          hash(-p + i);
        };
        {
          hash(2);
          hash(i);
          hash(-p + i + 1);
        };
      }
      if (p <= 0) {
        {
          hash(1);
          hash(p + N - 1);
          hash(N - 1);
        };
      }
    }
    {
      hash(2);
      hash(N - 1);
      hash(0);
    };
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x8(%rsp)
  test   %edi,%edi
  jg     L72
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L72:
  mov    %edi,%ebx
  mov    $0x1,%edi
  mov    $0x2,%r12d
  call   <hash@plt>
  xor    %edi,%edi
  sub    %ebx,%r12d
  call   <hash@plt>
  lea    -0x1(%rbx),%eax
  mov    %eax,%edi
  mov    %eax,0xc(%rsp)
  call   <hash@plt>
  cmp    %r12d,%ebx
  jle    L3
  xor    %ebp,%ebp
  nopl   (%rax)
L88:
  test   %r12d,%r12d
  jle    L77
  mov    $0x2,%edi
  call   <hash@plt>
  lea    -0x1(%r12),%edi
  call   <hash@plt>
  xor    %edi,%edi
  call   <hash@plt>
L77:
  xor    %edx,%edx
  test   %r12d,%r12d
  lea    0x1(%rbp),%r14d
  cmovns %r12d,%edx
  cmp    %r14d,0x8(%rsp)
  cmovl  0xc(%rsp),%ebp
  mov    %edx,%r15d
  mov    %edx,%r13d
  sub    %r12d,%r15d
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L85:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %r15d,%edi
  mov    %ebx,%r15d
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  add    $0x1,%r13d
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
L57:
  lea    0x1(%r15),%ebx
  cmp    %ebp,%r13d
  jle    L85
  test   %r12d,%r12d
  jle    L4
  add    $0x1,%r12d
  cmp    %r12d,0x8(%rsp)
  je     L3
L6:
  mov    %r14d,%ebp
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%edi
  add    $0x1,%r12d
  call   <hash@plt>
  mov    %r14d,%edi
  call   <hash@plt>
  mov    0xc(%rsp),%edi
  call   <hash@plt>
  cmp    %r12d,0x8(%rsp)
  jne    L6
L3:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    0xc(%rsp),%edi
  call   <hash@plt>
  add    $0x18,%rsp
  xor    %edi,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <hash@plt>
```

assistant: ```c
void test(int N) {
  int p;
  int i, j;
  if (N >= 1) {
    {
      hash(1);
      hash(0);
      hash(N - 1);
    };
    for (p = -N + 2; p <= N - 1; p++) {
      if (p >= 1) {
        {
          hash(2);
          hash(p - 1);
          hash(0);
        };
      }
      for (i = ((0) > (p) ? (0) : (p)); i <= ((N - 1) < (p + N - 2) ? (N - 1) : (p + N - 2)); i++) {
        {
          hash(1);
          hash(i);
          hash(-p + i);
        };
        {
          hash(2);
          hash(i);
          hash(-p + i + 1);
        };
      }
      if (p <= 0) {
        {
          hash(1);
          hash(p + N - 1);
          hash(N - 1);
        };
      }
    }
    {
      hash(2);
      hash(N - 1);
      hash(0);
    };
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  test   %edi,%edi
  jg     L41
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L41:
  mov    %edi,%ebx
  mov    $0x1,%edi
  mov    $0x2,%r14d
  call   <hash@plt>
  lea    -0x1(%rbx),%r15d
  xor    %edi,%edi
  sub    %ebx,%r14d
  call   <hash@plt>
  mov    %r15d,%edi
  call   <hash@plt>
  cmp    %r14d,%ebx
  jle    L7
  cmp    $0x1,%r14d
  je     L63
  xor    %r13d,%r13d
  xchg   %ax,%ax
L73:
  mov    %r13d,%r12d
  mov    $0x1,%ebp
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  cmovl  %r15d,%r12d
  sub    %r14d,%ebp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L32:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  lea    -0x1(%rbp),%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <hash@plt>
  cmp    %ebx,%r12d
  jge    L32
  mov    $0x1,%edi
  add    $0x1,%r14d
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %r15d,%edi
  call   <hash@plt>
  cmp    $0x1,%r14d
  jne    L73
  cmpl   $0x1,0xc(%rsp)
  je     L7
L63:
  mov    %r15d,%r14d
  mov    $0x1,%r13d
  nopl   0x0(%rax)
L84:
  mov    $0x2,%edi
  mov    %r14d,%r12d
  add    $0x1,%r14d
  call   <hash@plt>
  lea    -0x1(%r13),%edi
  call   <hash@plt>
  xor    %edi,%edi
  call   <hash@plt>
  cmp    %r14d,0xc(%rsp)
  cmovl  %r15d,%r12d
  cmp    %r12d,%r13d
  jg     L13
  mov    %r13d,%ebx
  mov    $0x1,%ebp
  nop
L34:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  lea    -0x1(%rbp),%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <hash@plt>
  cmp    %ebx,%r12d
  jge    L34
L13:
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  jg     L84
L7:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %r15d,%edi
  call   <hash@plt>
  add    $0x18,%rsp
  xor    %edi,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <hash@plt>
```

assistant: ```c
void test(int N) {
  int p;
  int i, j;
  if (N >= 1) {
    {
      hash(1);
      hash(0);
      hash(N - 1);
    };
    for (p = -N + 2; p <= N - 1; p++) {
      if (p >= 1) {
        {
          hash(2);
          hash(p - 1);
          hash(0);
        };
      }
      for (i = ((0) > (p) ? (0) : (p)); i <= ((N - 1) < (p + N - 2) ? (N - 1) : (p + N - 2)); i++) {
        {
          hash(1);
          hash(i);
          hash(-p + i);
        };
        {
          hash(2);
          hash(i);
          hash(-p + i + 1);
        };
      }
      if (p <= 0) {
        {
          hash(1);
          hash(p + N - 1);
          hash(N - 1);
        };
      }
    }
    {
      hash(2);
      hash(N - 1);
      hash(0);
    };
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dd_mlt_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x18(%rbp),%rdx
  movsd  -0x30(%rbp),%xmm0
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dd_two_prod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  movsd  -0x18(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dd_quick_two_sum@plt>
  movq   %xmm0,%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void dd_mlt_d(double *a, double b) {
  double p1, p2;
  p1 = dd_two_prod(a[0], b, &p2);
  p2 += a[1] * b;
  a[0] = dd_quick_two_sum(p1, p2, &a[1]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dd_mlt_d>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movapd %xmm0,%xmm1
  movsd  0x0(%rbp),%xmm0
  call   <dd_two_prod@plt>
  movq   %rbx,%xmm1
  mulsd  0x8(%rbp),%xmm1
  addsd  (%rsp),%xmm1
  movsd  %xmm1,(%rsp)
  lea    0x8(%rbp),%rdi
  call   <dd_quick_two_sum@plt>
  movsd  %xmm0,0x0(%rbp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dd_mlt_d(double *a, double b) {
  double p1, p2;
  p1 = dd_two_prod(a[0], b, &p2);
  p2 += a[1] * b;
  a[0] = dd_quick_two_sum(p1, p2, &a[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dd_mlt_d>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movapd %xmm0,%xmm1
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rbx),%xmm0
  lea    0x10(%rsp),%rdi
  call   <dd_two_prod@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  0x8(%rbx),%xmm1
  lea    0x8(%rbx),%rdi
  addsd  0x10(%rsp),%xmm1
  movsd  %xmm1,0x10(%rsp)
  call   <dd_quick_two_sum@plt>
  movsd  %xmm0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dd_mlt_d(double *a, double b) {
  double p1, p2;
  p1 = dd_two_prod(a[0], b, &p2);
  p2 += a[1] * b;
  a[0] = dd_quick_two_sum(p1, p2, &a[1]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dd_mlt_d>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movapd %xmm0,%xmm1
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rbx),%xmm0
  lea    0x10(%rsp),%rdi
  call   <dd_two_prod@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  0x8(%rbx),%xmm1
  lea    0x8(%rbx),%rdi
  addsd  0x10(%rsp),%xmm1
  movsd  %xmm1,0x10(%rsp)
  call   <dd_quick_two_sum@plt>
  movsd  %xmm0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dd_mlt_d(double *a, double b) {
  double p1, p2;
  p1 = dd_two_prod(a[0], b, &p2);
  p2 += a[1] * b;
  a[0] = dd_quick_two_sum(p1, p2, &a[1]);
}
```