ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clear_resume_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movb   $0x0,-0xc(%rbp)
  mov    $0x1,%edi
  call   <get_sig_offset@plt>
  mov    -0x40(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  jns    L76
  mov    $0xffffffff,%eax
  jmp    L25
L76:
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x14,%eax
  je     L14
  mov    $0xffffffff,%eax
  jmp    L25
L14:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  jns    L31
  mov    $0xffffffff,%eax
  jmp    L25
L31:
  lea    -0x20(%rbp),%rax
  add    $0xa,%rax
  lea    -0x20(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  lea    -0x20(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  cmp    $0x14,%eax
  je     L30
  mov    $0xffffffff,%eax
  jmp    L25
L30:
  mov    $0x0,%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int clear_resume_block(FILE *dev, off_t offset) {
  char buf[21] = {
      0,
  };
  off_t location = offset + get_sig_offset(1);
  if (fseek(dev, location, SEEK_SET) < 0)
    return -1;
  if (fread(buf, sizeof(char), 20, dev) != 20)
    return -1;
  if (fseek(dev, location, SEEK_SET) < 0)
    return -1;
  memmove(buf + 10, buf, 10);
  memset(buf, '\0', 10);
  if (fwrite(buf, sizeof(char), 20, dev) != 20)
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clear_resume_block>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  movb   $0x0,0x14(%rsp)
  mov    $0x1,%edi
  call   <get_sig_offset@plt>
  add    %rax,%r12
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  js     L50
  mov    %rsp,%rdi
  mov    %rbx,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    $0x14,%eax
  jne    L19
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  js     L62
  mov    %rsp,%rbp
  lea    0xa(%rsp),%rdi
  mov    $0xa,%edx
  mov    %rbp,%rsi
  call   <memmove@plt>
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbx,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  cmp    $0x14,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
L34:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  mov    $0xffffffff,%eax
  jmp    L34
L19:
  mov    $0xffffffff,%eax
  jmp    L34
L62:
  mov    $0xffffffff,%eax
  jmp    L34
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int clear_resume_block(FILE *dev, off_t offset) {
  char buf[21] = {
      0,
  };
  off_t location = offset + get_sig_offset(1);
  if (fseek(dev, location, SEEK_SET) < 0)
    return -1;
  if (fread(buf, sizeof(char), 20, dev) != 20)
    return -1;
  if (fseek(dev, location, SEEK_SET) < 0)
    return -1;
  memmove(buf + 10, buf, 10);
  memset(buf, '\0', 10);
  if (fwrite(buf, sizeof(char), 20, dev) != 20)
    return -1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clear_resume_block>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdi,%r12
  mov    $0x1,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movb   $0x0,0x14(%rsp)
  movaps %xmm0,(%rsp)
  call   <get_sig_offset@plt>
  mov    D2(%rip),%rbx
  mov    %r12,%rdi
  add    %rax,%rbp
  mov    (%rbx),%edx
  mov    %rbp,%rsi
  call   <fseek@plt>
  test   %rax,%rax
  js     L34
  mov    %rsp,%r13
  mov    %r12,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  cmp    $0x14,%eax
  jne    L34
  mov    (%rbx),%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  js     L34
  lea    0xa(%rsp),%rdi
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <memmove@plt>
  xor    %esi,%esi
  mov    $0xa,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  mov    %r12,%rcx
  mov    $0x14,%edx
  mov    %r13,%rdi
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    $0x14,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
L22:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L34:
  mov    $0xffffffff,%eax
  jmp    L22
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int clear_resume_block(FILE *dev, off_t offset) {
  char buf[21] = {
      0,
  };
  off_t location = offset + get_sig_offset(1);
  if (fseek(dev, location, SEEK_SET) < 0)
    return -1;
  if (fread(buf, sizeof(char), 20, dev) != 20)
    return -1;
  if (fseek(dev, location, SEEK_SET) < 0)
    return -1;
  memmove(buf + 10, buf, 10);
  memset(buf, '\0', 10);
  if (fwrite(buf, sizeof(char), 20, dev) != 20)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clear_resume_block>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdi,%r12
  mov    $0x1,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movb   $0x0,0x14(%rsp)
  movaps %xmm0,(%rsp)
  call   <get_sig_offset@plt>
  mov    D8(%rip),%rbx
  mov    %r12,%rdi
  add    %rax,%rbp
  mov    (%rbx),%edx
  mov    %rbp,%rsi
  call   <fseek@plt>
  test   %rax,%rax
  js     L46
  mov    %rsp,%r13
  mov    %r12,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  cmp    $0x14,%eax
  jne    L46
  mov    (%rbx),%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  js     L46
  lea    0xa(%rsp),%rdi
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <memmove@plt>
  xor    %esi,%esi
  mov    $0xa,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  mov    %r12,%rcx
  mov    $0x14,%edx
  mov    %r13,%rdi
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    $0x14,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
L39:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L46:
  mov    $0xffffffff,%eax
  jmp    L39
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int clear_resume_block(FILE *dev, off_t offset) {
  char buf[21] = {
      0,
  };
  off_t location = offset + get_sig_offset(1);
  if (fseek(dev, location, SEEK_SET) < 0)
    return -1;
  if (fread(buf, sizeof(char), 20, dev) != 20)
    return -1;
  if (fseek(dev, location, SEEK_SET) < 0)
    return -1;
  memmove(buf + 10, buf, 10);
  memset(buf, '\0', 10);
  if (fwrite(buf, sizeof(char), 20, dev) != 20)
    return -1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L13
L4:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L13:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L4
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D48
datatype: string
name: disassemble_data
arguments: data_label: D34
datatype: string

tool: D48: %d

tool: D34: %d %d


assistant: ```c
int main(void) {
  int a, b;
  scanf("%d", &a);
  scanf("%d", &b);
  while (a <= b) {
    scanf("%d", &a);
    scanf("%d", &b);
  }
  printf("%d %d\n", a, b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  jg     L0
L20:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  jle    L20
L0:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D5
type_infered: string

tool: D2: %d

tool: D5: %d %d


assistant: ```c
int main(void) {
  int a, b;
  scanf("%d", &a);
  scanf("%d", &b);
  while (a <= b) {
    scanf("%d", &a);
    scanf("%d", &b);
  }
  printf("%d %d\n", a, b);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4(%rsp),%rbp
  mov    %r12,%rsi
  call   <scanf@plt>
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L2:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  jle    L1
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D1
type: string

tool: D8: %d

tool: D1: %d %d


assistant: ```c
int main(void) {
  int a, b;
  scanf("%d", &a);
  scanf("%d", &b);
  while (a <= b) {
    scanf("%d", &a);
    scanf("%d", &b);
  }
  printf("%d %d\n", a, b);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4(%rsp),%rbp
  mov    %r12,%rsi
  call   <scanf@plt>
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L1:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  jle    L28
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string

tool: D14: %d

tool: D13: %d %d


assistant: ```c
int main(void) {
  int a, b;
  scanf("%d", &a);
  scanf("%d", &b);
  while (a <= b) {
    scanf("%d", &a);
    scanf("%d", &b);
  }
  printf("%d %d\n", a, b);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  je     L82
  mov    $0x1,%eax
  jmp    L3
L82:
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  je     L75
  mov    $0x1,%eax
  jmp    L3
L75:
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  je     L69
  mov    $0x1,%eax
  jmp    L3
L69:
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x0,%edi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  je     L36
  mov    $0x1,%eax
  jmp    L3
L36:
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    $0xffffffff,%edi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  je     L99
  mov    $0x1,%eax
  jmp    L3
L99:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (test__umoddi3(0, 1, 0))
    return 1;
  if (test__umoddi3(2, 1, 0))
    return 1;
  if (test__umoddi3(0x8000000000000000uLL, 1, 0x0uLL))
    return 1;
  if (test__umoddi3(0x8000000000000000uLL, 2, 0x0uLL))
    return 1;
  if (test__umoddi3(0xFFFFFFFFFFFFFFFFuLL, 2, 0x1uLL))
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <test__umoddi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L26
L18:
  add    $0x8,%rsp
  ret
L26:
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <test__umoddi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L18
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <test__umoddi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L18
  mov    $0x2,%esi
  mov    $0x0,%edi
  call   <test__umoddi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L18
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    $0xffffffff,%edi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L18
```

assistant: ```c
int main() {
  if (test__umoddi3(0, 1, 0))
    return 1;
  if (test__umoddi3(2, 1, 0))
    return 1;
  if (test__umoddi3(0x8000000000000000uLL, 1, 0x0uLL))
    return 1;
  if (test__umoddi3(0x8000000000000000uLL, 2, 0x0uLL))
    return 1;
  if (test__umoddi3(0xFFFFFFFFFFFFFFFFuLL, 2, 0x1uLL))
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  je     L29
L16:
  mov    $0x1,%eax
L32:
  add    $0x8,%rsp
  ret
L29:
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  jne    L16
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  jne    L16
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x2,%esi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  jne    L16
  or     $0xffffffff,%edi
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L32
```

assistant: ```c
int main() {
  if (test__umoddi3(0, 1, 0))
    return 1;
  if (test__umoddi3(2, 1, 0))
    return 1;
  if (test__umoddi3(0x8000000000000000uLL, 1, 0x0uLL))
    return 1;
  if (test__umoddi3(0x8000000000000000uLL, 2, 0x0uLL))
    return 1;
  if (test__umoddi3(0xFFFFFFFFFFFFFFFFuLL, 2, 0x1uLL))
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  je     L41
L9:
  mov    $0x1,%eax
L18:
  add    $0x8,%rsp
  ret
L41:
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  jne    L9
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  jne    L9
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x2,%esi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  jne    L9
  or     $0xffffffff,%edi
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <test__umoddi3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L18
```

assistant: ```c
int main() {
  if (test__umoddi3(0, 1, 0))
    return 1;
  if (test__umoddi3(2, 1, 0))
    return 1;
  if (test__umoddi3(0x8000000000000000uLL, 1, 0x0uLL))
    return 1;
  if (test__umoddi3(0x8000000000000000uLL, 2, 0x0uLL))
    return 1;
  if (test__umoddi3(0xFFFFFFFFFFFFFFFFuLL, 2, 0x1uLL))
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foreach_file_callbk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <filename_ext@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  jmp    L5
L18:
  lea    D2(%rip),%rax
L5:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    %rax,%rcx
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D2: null

tool: D13: %s/%s (ext:`%s')


assistant: ```c
int foreach_file_callbk(const char *filename, void *arg) {
  char *path = (char *)arg;
  char *ext = filename_ext(filename);
  printf("%s/%s (ext:`%s')\n", path, filename, (ext == NULL) ? "null" : ext);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<foreach_file_callbk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <filename_ext@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  lea    D7(%rip),%rax
  cmove  %rax,%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string

tool: D7: null

tool: D17: %s/%s (ext:`%s')


assistant: ```c
int foreach_file_callbk(const char *filename, void *arg) {
  char *path = (char *)arg;
  char *ext = filename_ext(filename);
  printf("%s/%s (ext:`%s')\n", path, filename, (ext == NULL) ? "null" : ext);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foreach_file_callbk>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <filename_ext@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  test   %rax,%rax
  mov    %rax,%rcx
  lea    D12(%rip),%rax
  cmove  %rax,%rcx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string

tool: D11: %s/%s (ext:`%s')


tool: D12: null

assistant: ```c
int foreach_file_callbk(const char *filename, void *arg) {
  char *path = (char *)arg;
  char *ext = filename_ext(filename);
  printf("%s/%s (ext:`%s')\n", path, filename, (ext == NULL) ? "null" : ext);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foreach_file_callbk>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <filename_ext@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  test   %rax,%rax
  mov    %rax,%rcx
  lea    D11(%rip),%rax
  cmove  %rax,%rcx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string
name: extract_symbolic_data
arguments: tag: D11
datatype: string

tool: D8: %s/%s (ext:`%s')


tool: D11: null

assistant: ```c
int foreach_file_callbk(const char *filename, void *arg) {
  char *path = (char *)arg;
  char *ext = filename_ext(filename);
  printf("%s/%s (ext:`%s')\n", path, filename, (ext == NULL) ? "null" : ext);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heaviestCharacter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  movl   $0x0,-0x74(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L4
L85:
  mov    -0x78(%rbp),%eax
  cltq
  movl   $0x0,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x78(%rbp)
L4:
  cmpl   $0x19,-0x78(%rbp)
  jle    L85
  movl   $0x0,-0x78(%rbp)
  jmp    L40
L71:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x79(%rbp)
  cmpb   $0x40,-0x79(%rbp)
  jle    L89
  cmpb   $0x5a,-0x79(%rbp)
  jle    L83
L89:
  cmpb   $0x60,-0x79(%rbp)
  jle    L115
  cmpb   $0x7a,-0x79(%rbp)
  jg     L115
L83:
  cmpb   $0x40,-0x79(%rbp)
  jle    L93
  cmpb   $0x5a,-0x79(%rbp)
  jg     L93
  movzbl -0x79(%rbp),%eax
  add    $0x20,%eax
  mov    %al,-0x79(%rbp)
L93:
  movsbl -0x79(%rbp),%eax
  sub    $0x61,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
L115:
  addl   $0x1,-0x78(%rbp)
L40:
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x78(%rbp)
  jl     L71
  movl   $0x0,-0x78(%rbp)
  jmp    L121
L14:
  mov    -0x78(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%edx
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L100
  mov    -0x78(%rbp),%eax
  mov    %eax,-0x74(%rbp)
L100:
  addl   $0x1,-0x78(%rbp)
L121:
  cmpl   $0x19,-0x78(%rbp)
  jle    L14
  mov    -0x74(%rbp),%eax
  add    $0x61,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L72
  call   <__stack_chk_fail@plt>
L72:
  leave
  ret
```

assistant: ```c
char heaviestCharacter(const char *string) {
  int characterCount[26];
  int i = 0;
  int maximum = 0;
  char temp;
  for (i = 0; i < 26; i++)
    characterCount[i] = 0;
  for (i = 0; i < strlen(string); i++) {
    temp = string[i];
    if ((temp >= 'A' && temp <= 'Z') || (temp >= 'a' && temp <= 'z')) {
      if (temp >= 'A' && temp <= 'Z')
        temp = temp + 32;
      characterCount[temp - 97]++;
    }
  }
  for (i = 0; i < 26; i++) {
    if (characterCount[i] > characterCount[maximum])
      maximum = i;
  }
  return (maximum + 97);
}
```