ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<cksum>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L77
  lea    -0x1(%rsi),%eax
  cmp    $0xe,%eax
  jbe    L91
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x4,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L88:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddb  %xmm2,%xmm0
  cmp    %rax,%rcx
  jne    L88
  movdqa %xmm0,%xmm1
  mov    %edx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffff0,%esi
  paddb  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  mov    %esi,%ecx
  psadbw %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%edx
  je     L36
L92:
  mov    %edx,%r8d
  sub    %esi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L129
  movq   (%rdi,%rsi,1),%xmm1
  pxor   %xmm0,%xmm0
  movdqa %xmm1,%xmm3
  psadbw %xmm0,%xmm3
  movq   %xmm3,%rsi
  add    %esi,%eax
  mov    %r8d,%esi
  and    $0xfffffff8,%esi
  add    %esi,%ecx
  cmp    %esi,%r8d
  je     L36
L129:
  movslq %ecx,%rsi
  add    (%rdi,%rsi,1),%al
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jle    L36
  movslq %esi,%rsi
  add    (%rdi,%rsi,1),%al
  lea    0x2(%rcx),%esi
  cmp    %edx,%esi
  jge    L36
  movslq %esi,%rsi
  add    (%rdi,%rsi,1),%al
  lea    0x3(%rcx),%esi
  cmp    %esi,%edx
  jle    L36
  movslq %esi,%rsi
  add    (%rdi,%rsi,1),%al
  lea    0x4(%rcx),%esi
  cmp    %esi,%edx
  jle    L36
  movslq %esi,%rsi
  add    (%rdi,%rsi,1),%al
  lea    0x5(%rcx),%esi
  cmp    %esi,%edx
  jle    L36
  movslq %esi,%rsi
  add    $0x6,%ecx
  add    (%rdi,%rsi,1),%al
  cmp    %ecx,%edx
  jle    L36
  movslq %ecx,%rcx
  add    (%rdi,%rcx,1),%al
L36:
  neg    %eax
  ret
  nopl   (%rax)
L77:
  xor    %eax,%eax
  ret
L91:
  xor    %esi,%esi
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L92
```

assistant: ```c
unsigned char cksum(const unsigned char *buf, register int len) {
  register unsigned char csum;
  register int i;
  csum = 0;
  for (i = 0; i < len; i++)
    csum = (csum + buf[i]) % 256;
  csum = -csum;
  return (csum);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_next_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L47:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L14
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <is_rich@plt>
  cmp    $0x1,%eax
  jne    L14
  mov    -0x4(%rbp),%eax
  jmp    L5
L14:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L47
  mov    $0xffffffff,%eax
L5:
  leave
  ret
```

assistant: ```c
int get_next_one(char *u, int s, int len) {
  int i;
  for (i = s + 1; i < len - 1; i++) {
    if (u[i] != '0' && is_rich(u, i, len, 1) == 1)
      return i;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_next_one>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  lea    -0x1(%rdx),%r14d
  cmp    %r14d,%ebx
  jge    L25
  mov    %rdi,%rbp
  mov    %edx,%r13d
  movslq %ebx,%rbx
  jmp    L28
L33:
  add    $0x1,%rbx
  cmp    %ebx,%r14d
  jle    L18
L28:
  mov    %ebx,%r12d
  cmpb   $0x30,0x0(%rbp,%rbx,1)
  je     L33
  mov    $0x1,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <is_rich@plt>
  cmp    $0x1,%eax
  jne    L33
  jmp    L68
L18:
  mov    $0xffffffff,%r12d
L68:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  mov    $0xffffffff,%r12d
  jmp    L68
```

assistant: ```c
int get_next_one(char *u, int s, int len) {
  int i;
  for (i = s + 1; i < len - 1; i++) {
    if (u[i] != '0' && is_rich(u, i, len, 1) == 1)
      return i;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_next_one>:
  endbr64
  push   %r14
  push   %r13
  lea    -0x1(%rdx),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  cmp    %r13d,%ebx
  jge    L11
  mov    %rdi,%rbp
  mov    %edx,%r14d
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L5:
  cmpb   $0x30,0x0(%rbp,%rbx,1)
  mov    %ebx,%r12d
  je     L2
  mov    $0x1,%ecx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <is_rich@plt>
  cmp    $0x1,%eax
  je     L20
L2:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jg     L5
L11:
  mov    $0xffffffff,%r12d
L20:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_next_one(char *u, int s, int len) {
  int i;
  for (i = s + 1; i < len - 1; i++) {
    if (u[i] != '0' && is_rich(u, i, len, 1) == 1)
      return i;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_next_one>:
  endbr64
  push   %r14
  push   %r13
  lea    -0x1(%rdx),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  cmp    %r13d,%ebx
  jge    L32
  mov    %rdi,%rbp
  mov    %edx,%r14d
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L1:
  cmpb   $0x30,0x0(%rbp,%rbx,1)
  mov    %ebx,%r12d
  je     L6
  mov    $0x1,%ecx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <is_rich@plt>
  cmp    $0x1,%eax
  je     L13
L6:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jg     L1
L32:
  mov    $0xffffffff,%r12d
L13:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_next_one(char *u, int s, int len) {
  int i;
  for (i = s + 1; i < len - 1; i++) {
    if (u[i] != '0' && is_rich(u, i, len, 1) == 1)
      return i;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FX_GetVolume>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <MV_GetVolume@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int FX_GetVolume(void) {
  int volume;
  volume = MV_GetVolume();
  return (volume);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<FX_GetVolume>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <MV_GetVolume@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int FX_GetVolume(void) {
  int volume;
  volume = MV_GetVolume();
  return (volume);
}
```
user: Translate the below assembly code into C programming language:

```asm
<FX_GetVolume>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <MV_GetVolume@plt>
```

assistant: ```c
int FX_GetVolume(void) {
  int volume;
  volume = MV_GetVolume();
  return (volume);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<FX_GetVolume>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <MV_GetVolume@plt>
```

assistant: ```c
int FX_GetVolume(void) {
  int volume;
  volume = MV_GetVolume();
  return (volume);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mesh_memclear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L42:
  cmpq   $0x8,-0x20(%rbp)
  ja     L0
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  lea    -0xc(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mesh_memcpy@plt>
  jmp    L30
L0:
  lea    -0xc(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mesh_memcpy@plt>
  addq   $0x8,-0x18(%rbp)
  addq   $0x8,-0x20(%rbp)
L18:
  cmpq   $0x0,-0x20(%rbp)
  jne    L42
L30:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void mesh_memclear(uintptr_t dst, size_t size) {
  const uint64_t zero = 0;
  while (size) {
    if (size <= 8) {
      mesh_memcpy(dst, &zero, size);
      return;
    }
    mesh_memcpy(dst, &zero, 8);
    dst += 8;
    size += 8;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mesh_memclear>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %rsi,%rsi
  je     L31
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  cmp    $0x8,%rsi
  jbe    L0
  lea    0x4(%rsp),%r12
L34:
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mesh_memcpy@plt>
  add    $0x8,%rbp
  add    $0x8,%rbx
  je     L31
  cmp    $0x8,%rbx
  ja     L34
L0:
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <mesh_memcpy@plt>
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mesh_memclear(uintptr_t dst, size_t size) {
  const uint64_t zero = 0;
  while (size) {
    if (size <= 8) {
      mesh_memcpy(dst, &zero, size);
      return;
    }
    mesh_memcpy(dst, &zero, 8);
    dst += 8;
    size += 8;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mesh_memclear>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %rsi,%rsi
  je     L22
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x4(%rsp),%r12
  cmp    $0x8,%rsi
  ja     L40
  jmp    L61
  nopl   0x0(%rax)
L8:
  cmp    $0x8,%rbx
  jbe    L61
L40:
  mov    %rbp,%rdi
  mov    $0x8,%edx
  mov    %r12,%rsi
  add    $0x8,%rbp
  call   <mesh_memcpy@plt>
  add    $0x8,%rbx
  jne    L8
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L61:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mesh_memcpy@plt>
  jmp    L22
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mesh_memclear(uintptr_t dst, size_t size) {
  const uint64_t zero = 0;
  while (size) {
    if (size <= 8) {
      mesh_memcpy(dst, &zero, size);
      return;
    }
    mesh_memcpy(dst, &zero, 8);
    dst += 8;
    size += 8;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mesh_memclear>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %rsi,%rsi
  je     L50
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x4(%rsp),%r12
  cmp    $0x8,%rsi
  ja     L5
  jmp    L51
  nopl   0x0(%rax)
L15:
  cmp    $0x8,%rbx
  jbe    L51
L5:
  mov    %rbp,%rdi
  mov    $0x8,%edx
  mov    %r12,%rsi
  add    $0x8,%rbp
  call   <mesh_memcpy@plt>
  add    $0x8,%rbx
  jne    L15
L50:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L51:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mesh_memcpy@plt>
  jmp    L50
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mesh_memclear(uintptr_t dst, size_t size) {
  const uint64_t zero = 0;
  while (size) {
    if (size <= 8) {
      mesh_memcpy(dst, &zero, size);
      return;
    }
    mesh_memcpy(dst, &zero, 8);
    dst += 8;
    size += 8;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<PrintBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x80000000,-0x4(%rbp)
  jmp    L7
L12:
  mov    -0x4(%rbp),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  shrl   -0x4(%rbp)
L7:
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string

tool: D8: %u

assistant: ```c
void PrintBits(unsigned num) {
  unsigned max_pow = 1 << sizeof(unsigned) * 8 - 1;
  while (max_pow) {
    printf("%u", !!(max_pow & num));
    max_pow >>= 1;
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PrintBits>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    $0x20,%ebp
  mov    $0x80000000,%ebx
  lea    D1(%rip),%r13
L4:
  test   %ebx,%r12d
  setne  %sil
  movzbl %sil,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  shr    %ebx
  sub    $0x1,%ebp
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: %u

assistant: ```c
void PrintBits(unsigned num) {
  unsigned max_pow = 1 << sizeof(unsigned) * 8 - 1;
  while (max_pow) {
    printf("%u", !!(max_pow & num));
    max_pow >>= 1;
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PrintBits>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  mov    $0x80000000,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %esi,%esi
  test   %ebx,%r12d
  mov    %r13,%rdi
  setne  %sil
  xor    %eax,%eax
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L7
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: %u

assistant: ```c
void PrintBits(unsigned num) {
  unsigned max_pow = 1 << sizeof(unsigned) * 8 - 1;
  while (max_pow) {
    printf("%u", !!(max_pow & num));
    max_pow >>= 1;
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PrintBits>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  mov    $0x80000000,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %esi,%esi
  test   %ebx,%r12d
  mov    %r13,%rdi
  setne  %sil
  xor    %eax,%eax
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L9
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: %u

assistant: ```c
void PrintBits(unsigned num) {
  unsigned max_pow = 1 << sizeof(unsigned) * 8 - 1;
  while (max_pow) {
    printf("%u", !!(max_pow & num));
    max_pow >>= 1;
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sran32_tod_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    -0x10(%rbp),%edx
  xor    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  add    $0x1,%eax
  xor    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void sran32_tod_r(unsigned *pstate0, unsigned *pstate1) {
  struct timeval tod;
  (void)gettimeofday(&tod, 0);
  *pstate0 = getpid() ^ tod.tv_usec;
  *pstate1 = tod.tv_sec ^ (tod.tv_usec * tod.tv_usec + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sran32_tod_r>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    (%rsp),%edx
  xor    %edx,%eax
  mov    %eax,0x0(%rbp)
  imul   %edx,%edx
  add    $0x1,%edx
  xor    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sran32_tod_r(unsigned *pstate0, unsigned *pstate1) {
  struct timeval tod;
  (void)gettimeofday(&tod, 0);
  *pstate0 = getpid() ^ tod.tv_usec;
  *pstate1 = tod.tv_sec ^ (tod.tv_usec * tod.tv_usec + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<sran32_tod_r>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  mov    (%rsp),%edx
  xor    %edx,%eax
  imul   %edx,%edx
  mov    %eax,0x0(%rbp)
  add    $0x1,%edx
  xor    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sran32_tod_r(unsigned *pstate0, unsigned *pstate1) {
  struct timeval tod;
  (void)gettimeofday(&tod, 0);
  *pstate0 = getpid() ^ tod.tv_usec;
  *pstate1 = tod.tv_sec ^ (tod.tv_usec * tod.tv_usec + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sran32_tod_r>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  mov    (%rsp),%edx
  xor    %edx,%eax
  imul   %edx,%edx
  mov    %eax,0x0(%rbp)
  add    $0x1,%edx
  xor    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sran32_tod_r(unsigned *pstate0, unsigned *pstate1) {
  struct timeval tod;
  (void)gettimeofday(&tod, 0);
  *pstate0 = getpid() ^ tod.tv_usec;
  *pstate1 = tod.tv_sec ^ (tod.tv_usec * tod.tv_usec + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<eng2num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L5
  cmpl   $0x34,-0x4(%rbp)
  jg     L5
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x2,%edx
  jg     L5
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  lea    (%rax,%rdx,1),%esi
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rsi,%rcx,1),%eax
  jmp    L27
L5:
  mov    $0xffffffff,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int eng2num(int engine) {
  if (engine >= 0 && engine <= 52 && (engine % 10) <= 2)
    return ((engine / 10) * 3 + (engine % 10));
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<eng2num>:
  endbr64
  cmp    $0x34,%edi
  ja     L4
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  mov    %edi,%edx
  sub    %eax,%edx
  cmp    $0x2,%edx
  jg     L17
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,2),%eax
  add    %edx,%eax
  ret
L4:
  mov    $0xffffffff,%eax
  ret
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int eng2num(int engine) {
  if (engine >= 0 && engine <= 52 && (engine % 10) <= 2)
    return ((engine / 10) * 3 + (engine % 10));
  else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<eng2num>:
  endbr64
  cmp    $0x34,%edi
  ja     L19
  movslq %edi,%rdx
  mov    %edi,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  cmp    $0x2,%edi
  jg     L19
  lea    (%rdx,%rdx,2),%eax
  add    %edi,%eax
  ret
L19:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int eng2num(int engine) {
  if (engine >= 0 && engine <= 52 && (engine % 10) <= 2)
    return ((engine / 10) * 3 + (engine % 10));
  else
    return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<eng2num>:
  endbr64
  cmp    $0x34,%edi
  ja     L6
  movslq %edi,%rdx
  mov    %edi,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  cmp    $0x2,%edi
  jg     L6
  lea    (%rdx,%rdx,2),%eax
  add    %edi,%eax
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int eng2num(int engine) {
  if (engine >= 0 && engine <= 52 && (engine % 10) <= 2)
    return ((engine / 10) * 3 + (engine % 10));
  else
    return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *copy(s)
char *s;
{
  char *new;
  new = (char *)malloc(strlen(s) + 1);
  strcpy(new, s);
  return (new);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *copy(s)
char *s;
{
  char *new;
  new = (char *)malloc(strlen(s) + 1);
  strcpy(new, s);
  return (new);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy(s)
char *s;
{
  char *new;
  new = (char *)malloc(strlen(s) + 1);
  strcpy(new, s);
  return (new);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy(s)
char *s;
{
  char *new;
  new = (char *)malloc(strlen(s) + 1);
  strcpy(new, s);
  return (new);
}
```