ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L39:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L11:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L39
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int min(int dist[], int vis[], int V) {
  int min = INT_MAX, min_index, i;
  for (i = 0; i < V; i++)
    if (vis[i] == 0 && dist[i] <= min) {
      min = dist[i];
      min_index = i;
    }
  return min_index;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%r9d
  test   %edx,%edx
  jle    L45
  mov    %edx,%edx
  mov    $0x0,%r10d
  mov    $0x0,%eax
  jmp    L0
L26:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L4
L0:
  cmpl   $0x0,(%rsi,%rax,4)
  jne    L26
  mov    (%rdi,%rax,4),%ecx
  cmp    %r9d,%ecx
  jg     L26
  mov    %eax,%r10d
  mov    %ecx,%r9d
  jmp    L26
L45:
  mov    $0x0,%r10d
L4:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int min(int dist[], int vis[], int V) {
  int min = INT_MAX, min_index, i;
  for (i = 0; i < V; i++)
    if (vis[i] == 0 && dist[i] <= min) {
      min = dist[i];
      min_index = i;
    }
  return min_index;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<min>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%r8d
  test   %edx,%edx
  jle    L10
  movslq %edx,%rdx
  xor    %r9d,%r9d
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L31:
  mov    (%rsi,%rax,4),%ecx
  test   %ecx,%ecx
  jne    L3
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jg     L3
  mov    %eax,%r9d
  mov    %ecx,%r8d
L3:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L31
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int min(int dist[], int vis[], int V) {
  int min = INT_MAX, min_index, i;
  for (i = 0; i < V; i++)
    if (vis[i] == 0 && dist[i] <= min) {
      min = dist[i];
      min_index = i;
    }
  return min_index;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<min>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%r8d
  test   %edx,%edx
  jle    L31
  movslq %edx,%rdx
  xor    %r9d,%r9d
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rsi,%rax,4),%ecx
  test   %ecx,%ecx
  jne    L29
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jg     L29
  mov    %eax,%r9d
  mov    %ecx,%r8d
L29:
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int min(int dist[], int vis[], int V) {
  int min = INT_MAX, min_index, i;
  for (i = 0; i < V; i++)
    if (vis[i] == 0 && dist[i] <= min) {
      min = dist[i];
      min_index = i;
    }
  return min_index;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ObjWrite24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ObjWrite8@plt>
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  mov    %rax,%rdi
  call   <ObjWrite8@plt>
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rdi
  call   <ObjWrite8@plt>
  nop
  leave
  ret
```

assistant: ```c
void ObjWrite24(unsigned long V) {
  ObjWrite8(V);
  ObjWrite8(V >> 8);
  ObjWrite8(V >> 16);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ObjWrite24>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ObjWrite8@plt>
  mov    %rbx,%rdi
  shr    $0x8,%rdi
  call   <ObjWrite8@plt>
  shr    $0x10,%rbx
  mov    %rbx,%rdi
  call   <ObjWrite8@plt>
  pop    %rbx
  ret
```

assistant: ```c
void ObjWrite24(unsigned long V) {
  ObjWrite8(V);
  ObjWrite8(V >> 8);
  ObjWrite8(V >> 16);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ObjWrite24>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ObjWrite8@plt>
  mov    %rbx,%rdi
  shr    $0x10,%rbx
  shr    $0x8,%rdi
  call   <ObjWrite8@plt>
  mov    %rbx,%rdi
  pop    %rbx
  jmp    1050 <ObjWrite8@plt>
```

assistant: ```c
void ObjWrite24(unsigned long V) {
  ObjWrite8(V);
  ObjWrite8(V >> 8);
  ObjWrite8(V >> 16);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ObjWrite24>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ObjWrite8@plt>
  mov    %rbx,%rdi
  shr    $0x10,%rbx
  shr    $0x8,%rdi
  call   <ObjWrite8@plt>
  mov    %rbx,%rdi
  pop    %rbx
  jmp    1050 <ObjWrite8@plt>
```

assistant: ```c
void ObjWrite24(unsigned long V) {
  ObjWrite8(V);
  ObjWrite8(V >> 8);
  ObjWrite8(V >> 16);
}
```
user: What is the c source code of the assembly code below?

```asm
<pevent_get_common_field_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9d,-0x3c(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L12
  mov    $0xffffffff,%eax
  jmp    L18
L12:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pevent_find_common_field@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x3c(%rbp),%r8d
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <get_field_val@plt>
L18:
  leave
  ret
```

assistant: ```c
int pevent_get_common_field_val(struct trace_seq *s, struct event_format *event, const char *name, struct pevent_record *record, unsigned long long *val, int err) {
  struct format_field *field;
  if (!event)
    return -1;
  field = pevent_find_common_field(event, name);
  return get_field_val(s, field, name, record, val, err);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pevent_get_common_field_val>:
  endbr64
  test   %rsi,%rsi
  je     L9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9d,%r14d
  mov    %rdx,%rsi
  call   <pevent_find_common_field@plt>
  mov    %rax,%rsi
  mov    %r14d,%r9d
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <get_field_val@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pevent_get_common_field_val(struct trace_seq *s, struct event_format *event, const char *name, struct pevent_record *record, unsigned long long *val, int err) {
  struct format_field *field;
  if (!event)
    return -1;
  field = pevent_find_common_field(event, name);
  return get_field_val(s, field, name, record, val, err);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pevent_get_common_field_val>:
  endbr64
  test   %rsi,%rsi
  je     L3
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %rbx
  mov    %r8,%rbx
  call   <pevent_find_common_field@plt>
  mov    %r14d,%r9d
  mov    %rbx,%r8
  mov    %r13,%rcx
  pop    %rbx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <get_field_val@plt>
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pevent_get_common_field_val(struct trace_seq *s, struct event_format *event, const char *name, struct pevent_record *record, unsigned long long *val, int err) {
  struct format_field *field;
  if (!event)
    return -1;
  field = pevent_find_common_field(event, name);
  return get_field_val(s, field, name, record, val, err);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pevent_get_common_field_val>:
  endbr64
  test   %rsi,%rsi
  je     L5
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %rbx
  mov    %r8,%rbx
  call   <pevent_find_common_field@plt>
  mov    %r14d,%r9d
  mov    %rbx,%r8
  mov    %r13,%rcx
  pop    %rbx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <get_field_val@plt>
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pevent_get_common_field_val(struct trace_seq *s, struct event_format *event, const char *name, struct pevent_record *record, unsigned long long *val, int err) {
  struct format_field *field;
  if (!event)
    return -1;
  field = pevent_find_common_field(event, name);
  return get_field_val(s, field, name, record, val, err);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_post_entity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L59:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L44
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L4
  addl   $0x2,-0x8(%rbp)
  jmp    L43
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x24(%rbp)
  je     L41
  jmp    L59
L41:
  nop
L43:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x26,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L19
  jmp    L59
L44:
  nop
  jmp    L30
L19:
  nop
L30:
  leave
  ret
```

assistant: ```c
void get_post_entity(char *request, char *entity, int len) {
  int i = 0, j = 0;
  for (;;) {
    for (;;) {
      if (request[i] == '\0')
        return;
      if (request[i] == '\r') {
        i += 2;
        break;
      }
      entity[j] = request[i];
      i += 1, j += 1;
      if (j + 1 == len)
        break;
    }
    entity[j] = '\0';
    j = 0;
    if (strchr(entity, '&'))
      break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_post_entity>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    $0x0,%edx
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  jmp    L38
L1:
  add    $0x2,%ebx
  mov    %edx,%eax
L22:
  cltq
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    $0x26,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L48
  mov    %r14d,%edx
L6:
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  je     L48
L38:
  cmp    $0xd,%al
  je     L1
  movslq %edx,%rcx
  mov    %al,0x0(%rbp,%rcx,1)
  add    $0x1,%ebx
  lea    0x1(%rdx),%eax
  lea    0x2(%rdx),%ecx
  mov    %eax,%edx
  cmp    %r13d,%ecx
  jne    L6
  jmp    L22
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  ret
```

assistant: ```c
void get_post_entity(char *request, char *entity, int len) {
  int i = 0, j = 0;
  for (;;) {
    for (;;) {
      if (request[i] == '\0')
        return;
      if (request[i] == '\r') {
        i += 2;
        break;
      }
      entity[j] = request[i];
      i += 1, j += 1;
      if (j + 1 == len)
        break;
    }
    entity[j] = '\0';
    j = 0;
    if (strchr(entity, '&'))
      break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_post_entity>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  xor    %edx,%edx
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L27:
  movslq %edx,%rcx
  add    $0x1,%ebx
  mov    %al,(%r12,%rcx,1)
  lea    0x1(%rdx),%eax
  lea    0x2(%rdx),%ecx
  mov    %eax,%edx
  cmp    %ebp,%ecx
  je     L41
  movslq %ebx,%rax
  movzbl 0x0(%r13,%rax,1),%eax
  test   %al,%al
  je     L50
L37:
  cmp    $0xd,%al
  jne    L27
  add    $0x2,%ebx
  mov    %edx,%eax
L41:
  cltq
  mov    $0x26,%esi
  mov    %r12,%rdi
  movb   $0x0,(%r12,%rax,1)
  call   <strchr@plt>
  test   %rax,%rax
  jne    L50
  movslq %ebx,%rax
  xor    %edx,%edx
  movzbl 0x0(%r13,%rax,1),%eax
  test   %al,%al
  jne    L37
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  ret
```

assistant: ```c
void get_post_entity(char *request, char *entity, int len) {
  int i = 0, j = 0;
  for (;;) {
    for (;;) {
      if (request[i] == '\0')
        return;
      if (request[i] == '\r') {
        i += 2;
        break;
      }
      entity[j] = request[i];
      i += 1, j += 1;
      if (j + 1 == len)
        break;
    }
    entity[j] = '\0';
    j = 0;
    if (strchr(entity, '&'))
      break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_post_entity>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  xor    %edx,%edx
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L35:
  movslq %edx,%rcx
  add    $0x1,%ebx
  mov    %al,(%r12,%rcx,1)
  lea    0x1(%rdx),%eax
  lea    0x2(%rdx),%ecx
  mov    %eax,%edx
  cmp    %ebp,%ecx
  je     L52
  movslq %ebx,%rax
  movzbl 0x0(%r13,%rax,1),%eax
  test   %al,%al
  je     L62
L30:
  cmp    $0xd,%al
  jne    L35
  add    $0x2,%ebx
  mov    %edx,%eax
L52:
  cltq
  mov    $0x26,%esi
  mov    %r12,%rdi
  movb   $0x0,(%r12,%rax,1)
  call   <strchr@plt>
  test   %rax,%rax
  jne    L62
  movslq %ebx,%rax
  xor    %edx,%edx
  movzbl 0x0(%r13,%rax,1),%eax
  test   %al,%al
  jne    L30
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  ret
```

assistant: ```c
void get_post_entity(char *request, char *entity, int len) {
  int i = 0, j = 0;
  for (;;) {
    for (;;) {
      if (request[i] == '\0')
        return;
      if (request[i] == '\r') {
        i += 2;
        break;
      }
      entity[j] = request[i];
      i += 1, j += 1;
      if (j + 1 == len)
        break;
    }
    entity[j] = '\0';
    j = 0;
    if (strchr(entity, '&'))
      break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L4
L0:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L4:
  leave
  ret
```

assistant: ```c
void *memdup(const void *p, size_t n) {
  void *r = malloc(n);
  if (r == NULL)
    return NULL;
  return memcpy(r, p, n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *memdup(const void *p, size_t n) {
  void *r = malloc(n);
  if (r == NULL)
    return NULL;
  return memcpy(r, p, n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memdup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
L8:
  pop    %rdx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *memdup(const void *p, size_t n) {
  void *r = malloc(n);
  if (r == NULL)
    return NULL;
  return memcpy(r, p, n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memdup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
L2:
  pop    %rdx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *memdup(const void *p, size_t n) {
  void *r = malloc(n);
  if (r == NULL)
    return NULL;
  return memcpy(r, p, n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitCount_fun_uint8_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L0:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  add    %eax,-0x4(%rbp)
L11:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t bitCount_fun_uint8_t(uint8_t x) {
  uint32_t r = x & 1;
  while (x >>= 1)
    r += x & 1;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitCount_fun_uint8_t>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  sar    %edi
  je     L8
L11:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  sar    %edi
  jne    L11
L8:
  ret
```

assistant: ```c
uint32_t bitCount_fun_uint8_t(uint8_t x) {
  uint32_t r = x & 1;
  while (x >>= 1)
    r += x & 1;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bitCount_fun_uint8_t>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  sar    %edi
  je     L4
  nopl   (%rax)
L12:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  sar    %edi
  jne    L12
L4:
  ret
```

assistant: ```c
uint32_t bitCount_fun_uint8_t(uint8_t x) {
  uint32_t r = x & 1;
  while (x >>= 1)
    r += x & 1;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bitCount_fun_uint8_t>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  sar    %edi
  je     L9
  nopl   (%rax)
L1:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  sar    %edi
  jne    L1
L9:
  ret
```

assistant: ```c
uint32_t bitCount_fun_uint8_t(uint8_t x) {
  uint32_t r = x & 1;
  while (x >>= 1)
    r += x & 1;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L0
L11:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L0:
  leave
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strnlen(s, n);
  char *new = malloc(len + 1);
  if (new == NULL)
    return NULL;
  new[len] = '\0';
  return (char *)memcpy(new, s, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strndup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strnlen@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax,%rbx,1)
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strnlen(s, n);
  char *new = malloc(len + 1);
  if (new == NULL)
    return NULL;
  new[len] = '\0';
  return (char *)memcpy(new, s, len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strnlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
L4:
  pop    %rdx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strnlen(s, n);
  char *new = malloc(len + 1);
  if (new == NULL)
    return NULL;
  new[len] = '\0';
  return (char *)memcpy(new, s, len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strnlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
L8:
  pop    %rdx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strnlen(s, n);
  char *new = malloc(len + 1);
  if (new == NULL)
    return NULL;
  new[len] = '\0';
  return (char *)memcpy(new, s, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dummy_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L11
L15:
  subq   $0x1,-0x8(%rbp)
L11:
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dummy_aux(uint32_t n) {
  for (; n != 0; --n) {
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<dummy_aux>:
  endbr64
  test   %rdi,%rdi
  je     L7
L8:
  sub    $0x1,%rdi
  jne    L8
L7:
  ret
```

assistant: ```c
void dummy_aux(uint32_t n) {
  for (; n != 0; --n) {
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<dummy_aux>:
  endbr64
  ret
```

assistant: ```c
void dummy_aux(uint32_t n) {
  for (; n != 0; --n) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dummy_aux>:
  endbr64
  ret
```

assistant: ```c
void dummy_aux(uint32_t n) {
  for (; n != 0; --n) {
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<c2_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <c2ck_set@plt>
  mov    $0x19,%edi
  call   <usleep@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <c2ck_set@plt>
  mov    $0x1,%edi
  call   <usleep@plt>
  nop
  leave
  ret
```

assistant: ```c
void c2_reset(struct c2interface *c2if) {
  c2ck_set(c2if, 0);
  usleep(25);
  c2ck_set(c2if, 1);
  usleep(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<c2_reset>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%esi
  call   <c2ck_set@plt>
  mov    $0x19,%edi
  call   <usleep@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <c2ck_set@plt>
  mov    $0x1,%edi
  call   <usleep@plt>
  pop    %rbx
  ret
```

assistant: ```c
void c2_reset(struct c2interface *c2if) {
  c2ck_set(c2if, 0);
  usleep(25);
  c2ck_set(c2if, 1);
  usleep(1);
}
```