ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<NextState>:
  endbr64
  mov    %edx,%r8d
  cmp    %edi,%edx
  jge    L83
  movslq %edx,%rax
  movsbl (%rsi,%rax,1),%eax
  cmp    %ecx,%eax
  je     L52
L83:
  lea    -0x1(%r8),%r11d
  test   %r8d,%r8d
  jle    L49
  movslq %r11d,%rax
  lea    -0x2(%r8),%edi
  mov    %rsi,%rdx
  movsbl (%rsi,%rax,1),%r10d
  add    $0x2,%rdi
  jmp    L36
  nopl   0x0(%rax)
L87:
  add    $0x1,%rdx
  sub    $0x1,%r8d
  je     L30
L36:
  cmp    %ecx,%r10d
  jne    L87
  test   %r11d,%r11d
  jle    L73
  mov    $0x1,%eax
  nopl   0x0(%rax)
L80:
  movzbl (%rdx,%rax,1),%r9d
  cmp    %r9b,-0x1(%rsi,%rax,1)
  jne    L87
  mov    %eax,%r9d
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L80
  cmp    %r9d,%r11d
  jne    L87
L30:
  mov    %r8d,%eax
  ret
L52:
  add    $0x1,%r8d
  mov    %r8d,%eax
  ret
L73:
  xor    %r9d,%r9d
  cmp    %r9d,%r11d
  jne    L87
  jmp    L30
L49:
  xor    %r8d,%r8d
  jmp    L30
```

assistant: ```c
int NextState(int m, char *pattern, int state, int symbol) {
  if (state < m && pattern[state] == symbol) {
    return state + 1;
  }
  for (int next = state, prev = next - 1, i = 0; next > 0; next--) {
    if (pattern[prev] == symbol) {
      for (i = 0; i < prev; i++) {
        if (pattern[i] != pattern[state - next + 1 + i]) {
          break;
        }
      }
      if (i == prev) {
        return next;
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncpy_term>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  cmpq   $0x0,-0x28(%rbp)
  je     L17
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L17:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strncpy_term(char *dst, const char *src, const size_t len) {
  char *res = strncpy(dst, src, len);
  if (res && len > 0)
    dst[len - 1] = '\0';
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strncpy_term>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  call   <strncpy@plt>
  test   %rbx,%rbx
  je     L9
  movb   $0x0,-0x1(%rbp,%rbx,1)
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy_term(char *dst, const char *src, const size_t len) {
  char *res = strncpy(dst, src, len);
  if (res && len > 0)
    dst[len - 1] = '\0';
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncpy_term>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <strncpy@plt>
  test   %rbx,%rbx
  je     L0
  movb   $0x0,-0x1(%rax,%rbx,1)
L0:
  pop    %rbx
  ret
```

assistant: ```c
char *strncpy_term(char *dst, const char *src, const size_t len) {
  char *res = strncpy(dst, src, len);
  if (res && len > 0)
    dst[len - 1] = '\0';
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<strncpy_term>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <strncpy@plt>
  test   %rbx,%rbx
  je     L8
  movb   $0x0,-0x1(%rax,%rbx,1)
L8:
  pop    %rbx
  ret
```

assistant: ```c
char *strncpy_term(char *dst, const char *src, const size_t len) {
  char *res = strncpy(dst, src, len);
  if (res && len > 0)
    dst[len - 1] = '\0';
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x77,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: usage: prime [-h|--help]
       prime [-s|--short] [--] <num>...
       prime [-s|--short] -r|--range [<start>] <stop>


assistant: ```c
void usage(FILE *stream) {
  fputs("usage: "
        "prime"
        " [-h|--help]\n       "
        "prime"
        " [-s|--short] [--] <num>...\n       "
        "prime"
        " [-s|--short] -r|--range [<start>] <stop>\n",
        stream);
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    $0x77,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string

tool: D7: usage: prime [-h|--help]
       prime [-s|--short] [--] <num>...
       prime [-s|--short] -r|--range [<start>] <stop>


assistant: ```c
void usage(FILE *stream) {
  fputs("usage: "
        "prime"
        " [-h|--help]\n       "
        "prime"
        " [-s|--short] [--] <num>...\n       "
        "prime"
        " [-s|--short] -r|--range [<start>] <stop>\n",
        stream);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  mov    %rdi,%rcx
  mov    $0x77,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  jmp    1050 <fwrite@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: usage: prime [-h|--help]
       prime [-s|--short] [--] <num>...
       prime [-s|--short] -r|--range [<start>] <stop>


assistant: ```c
void usage(FILE *stream) {
  fputs("usage: "
        "prime"
        " [-h|--help]\n       "
        "prime"
        " [-s|--short] [--] <num>...\n       "
        "prime"
        " [-s|--short] -r|--range [<start>] <stop>\n",
        stream);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usage>:
  endbr64
  mov    %rdi,%rcx
  mov    $0x77,%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  jmp    1050 <fwrite@plt>
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: usage: prime [-h|--help]
       prime [-s|--short] [--] <num>...
       prime [-s|--short] -r|--range [<start>] <stop>


assistant: ```c
void usage(FILE *stream) {
  fputs("usage: "
        "prime"
        " [-h|--help]\n       "
        "prime"
        " [-s|--short] [--] <num>...\n       "
        "prime"
        " [-s|--short] -r|--range [<start>] <stop>\n",
        stream);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strtok_r>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdi,%rax
  mov    %rdx,%r8
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    %rsp,%rdx
  lea    0x20(%rsp),%rcx
L70:
  movb   $0x0,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L70
  mov    $0x1,%r9d
L49:
  movzbl (%rsi),%edi
  mov    %edi,%edx
  sar    $0x3,%dl
  movsbq %dl,%rdx
  mov    %edi,%ecx
  and    $0x7,%ecx
  mov    %r9d,%r10d
  shl    %cl,%r10d
  or     %r10b,(%rsp,%rdx,1)
  add    $0x1,%rsi
  test   %dil,%dil
  jne    L49
  test   %rax,%rax
  je     L56
L76:
  movzbl (%rax),%ecx
  mov    %ecx,%edx
  sar    $0x3,%dl
  movsbq %dl,%rdx
  movsbl (%rsp,%rdx,1),%esi
  mov    %ecx,%edx
  and    $0x7,%edx
  bt     %edx,%esi
  jae    L51
  test   %cl,%cl
  je     L51
L11:
  add    $0x1,%rax
  movzbl (%rax),%ecx
  mov    %ecx,%edx
  sar    $0x3,%dl
  movsbq %dl,%rdx
  movsbl (%rsp,%rdx,1),%esi
  mov    %ecx,%edx
  and    $0x7,%edx
  bt     %edx,%esi
  jae    L51
  test   %cl,%cl
  jne    L11
L51:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L124
  mov    %rax,%rsi
L103:
  mov    %edx,%ecx
  sar    $0x3,%cl
  movsbq %cl,%rcx
  movsbl (%rsp,%rcx,1),%ecx
  and    $0x7,%edx
  bt     %edx,%ecx
  jb     L89
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L103
  jmp    L22
L56:
  mov    (%r8),%rax
  jmp    L76
L89:
  movb   $0x0,(%rsi)
  lea    0x1(%rsi),%rsi
L22:
  cmp    %rax,%rsi
  mov    $0x0,%edx
  cmove  %rdx,%rax
L93:
  mov    %rsi,(%r8)
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L123
  add    $0x38,%rsp
  ret
L124:
  mov    %rax,%rsi
  mov    $0x0,%eax
  jmp    L93
L123:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtok_r(char *string, const char *control, char **lasts) {
  char *str;
  const char *ctrl = control;
  char map[32];
  int n;
  for (n = 0; n < 32; n++)
    map[n] = 0;
  do {
    map[*ctrl >> 3] |= (1 << (*ctrl & 7));
  } while (*ctrl++);
  if (string) {
    str = string;
  } else {
    str = *lasts;
  }
  while ((map[*str >> 3] & (1 << (*str & 7))) && *str)
    str++;
  string = str;
  for (; *str; str++) {
    if (map[*str >> 3] & (1 << (*str & 7))) {
      *str++ = '\0';
      break;
    }
  }
  *lasts = str;
  if (string == (char *)str) {
    return NULL;
  } else {
    return string;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strtok_r>:
  endbr64
  sub    $0x38,%rsp
  pxor   %xmm0,%xmm0
  mov    %rdx,%r8
  mov    %rdi,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    $0x1,%r9d
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L114:
  movzbl (%rsi),%edi
  mov    %r9d,%r10d
  add    $0x1,%rsi
  mov    %edi,%edx
  mov    %edi,%ecx
  sar    $0x3,%dl
  and    $0x7,%ecx
  movsbq %dl,%rdx
  shl    %cl,%r10d
  or     %r10b,(%rsp,%rdx,1)
  test   %dil,%dil
  jne    L114
  test   %rax,%rax
  jne    L61
  jmp    L119
  nopl   0x0(%rax,%rax,1)
L74:
  test   %dl,%dl
  je     L89
  add    $0x1,%rax
L61:
  movzbl (%rax),%edx
  mov    %edx,%ecx
  sar    $0x3,%cl
  movsbq %cl,%rcx
  movsbl (%rsp,%rcx,1),%esi
  mov    %edx,%ecx
  and    $0x7,%ecx
  bt     %ecx,%esi
  jb     L74
  test   %dl,%dl
  je     L89
  mov    %rax,%rcx
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L58:
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L23
L46:
  mov    %edx,%esi
  and    $0x7,%edx
  mov    %rcx,%rdi
  add    $0x1,%rcx
  sar    $0x3,%sil
  movsbq %sil,%rsi
  movsbl (%rsp,%rsi,1),%esi
  bt     %edx,%esi
  jae    L58
  movb   $0x0,(%rdi)
L23:
  xor    %edx,%edx
  cmp    %rcx,%rax
  cmove  %rdx,%rax
L82:
  mov    %rcx,(%r8)
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x38,%rsp
  ret
L119:
  mov    (%r8),%rax
  jmp    L61
  nopl   (%rax)
L89:
  mov    %rax,%rcx
  xor    %eax,%eax
  jmp    L82
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtok_r(char *string, const char *control, char **lasts) {
  char *str;
  const char *ctrl = control;
  char map[32];
  int n;
  for (n = 0; n < 32; n++)
    map[n] = 0;
  do {
    map[*ctrl >> 3] |= (1 << (*ctrl & 7));
  } while (*ctrl++);
  if (string) {
    str = string;
  } else {
    str = *lasts;
  }
  while ((map[*str >> 3] & (1 << (*str & 7))) && *str)
    str++;
  string = str;
  for (; *str; str++) {
    if (map[*str >> 3] & (1 << (*str & 7))) {
      *str++ = '\0';
      break;
    }
  }
  *lasts = str;
  if (string == (char *)str) {
    return NULL;
  } else {
    return string;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtok_r>:
  endbr64
  sub    $0x38,%rsp
  pxor   %xmm0,%xmm0
  mov    %rdx,%r8
  mov    %rdi,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    $0x1,%r9d
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L16:
  movzbl (%rsi),%edi
  mov    %r9d,%r10d
  add    $0x1,%rsi
  mov    %edi,%edx
  mov    %edi,%ecx
  sar    $0x3,%dl
  and    $0x7,%ecx
  movsbq %dl,%rdx
  shl    %cl,%r10d
  or     %r10b,(%rsp,%rdx,1)
  test   %dil,%dil
  jne    L16
  test   %rax,%rax
  jne    L7
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L39:
  test   %dl,%dl
  je     L109
  add    $0x1,%rax
L7:
  movzbl (%rax),%edx
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x3,%cl
  and    $0x7,%esi
  movsbq %cl,%rcx
  movsbl (%rsp,%rcx,1),%ecx
  bt     %esi,%ecx
  jb     L39
  test   %dl,%dl
  je     L109
  mov    %rax,%rsi
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L34:
  movzbl 0x1(%rsi),%edx
  test   %dl,%dl
  je     L85
  mov    %edx,%ecx
  mov    %rdi,%rsi
  sar    $0x3,%cl
  movsbq %cl,%rcx
  movsbl (%rsp,%rcx,1),%ecx
L97:
  and    $0x7,%edx
  lea    0x1(%rsi),%rdi
  bt     %edx,%ecx
  jae    L34
  movb   $0x0,(%rsi)
L85:
  xor    %edx,%edx
  cmp    %rdi,%rax
  cmove  %rdx,%rax
L63:
  mov    %rdi,(%r8)
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L65
  add    $0x38,%rsp
  ret
L46:
  mov    (%r8),%rax
  jmp    L7
  nopl   (%rax)
L109:
  mov    %rax,%rdi
  xor    %eax,%eax
  jmp    L63
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtok_r(char *string, const char *control, char **lasts) {
  char *str;
  const char *ctrl = control;
  char map[32];
  int n;
  for (n = 0; n < 32; n++)
    map[n] = 0;
  do {
    map[*ctrl >> 3] |= (1 << (*ctrl & 7));
  } while (*ctrl++);
  if (string) {
    str = string;
  } else {
    str = *lasts;
  }
  while ((map[*str >> 3] & (1 << (*str & 7))) && *str)
    str++;
  string = str;
  for (; *str; str++) {
    if (map[*str >> 3] & (1 << (*str & 7))) {
      *str++ = '\0';
      break;
    }
  }
  *lasts = str;
  if (string == (char *)str) {
    return NULL;
  } else {
    return string;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L12
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L12:
  mov    $0x0,%eax
  call   <nondet@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *r;
  int y;
  r = (int *)malloc(4);
  *r = 0;
  while (nondet()) {
    *r = *r + 1;
  }
  foo(r);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  jmp    L5
L17:
  mov    (%rbx),%eax
  add    $0x1,%eax
L5:
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  call   <nondet@plt>
  test   %rax,%rax
  jne    L17
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int *r;
  int y;
  r = (int *)malloc(4);
  *r = 0;
  while (nondet()) {
    *r = *r + 1;
  }
  foo(r);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    0x0(%rbp),%eax
  add    $0x1,%eax
L17:
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  call   <nondet@plt>
  test   %rax,%rax
  jne    L11
  mov    %rbp,%rdi
  call   <foo@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int *r;
  int y;
  r = (int *)malloc(4);
  *r = 0;
  while (nondet()) {
    *r = *r + 1;
  }
  foo(r);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    0x0(%rbp),%eax
  add    $0x1,%eax
L13:
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  call   <nondet@plt>
  test   %rax,%rax
  jne    L3
  mov    %rbp,%rdi
  call   <foo@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int *r;
  int y;
  r = (int *)malloc(4);
  *r = 0;
  while (nondet()) {
    *r = *r + 1;
  }
  foo(r);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<renderText>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <glColor3d@plt>
  mov    $0xffffff9c,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <glRasterPos3d@plt>
  jmp    L14
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glutBitmapCharacter@plt>
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void renderText(char *x) {
  glColor3d(1, 0, 0);
  glRasterPos3d(0, 0, -100);
  while ((*x) != '\0')
    glutBitmapCharacter(GLUT_BITMAP_9_BY_15, *x++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<renderText>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <glColor3d@plt>
  mov    $0xffffff9c,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <glRasterPos3d@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L6
  mov    D9(%rip),%rbp
L2:
  add    $0x1,%rbx
  movsbl %sil,%esi
  mov    0x0(%rbp),%edi
  call   <glutBitmapCharacter@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L2
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void renderText(char *x) {
  glColor3d(1, 0, 0);
  glRasterPos3d(0, 0, -100);
  while ((*x) != '\0')
    glutBitmapCharacter(GLUT_BITMAP_9_BY_15, *x++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<renderText>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <glColor3d@plt>
  xor    %esi,%esi
  mov    $0xffffff9c,%edx
  xor    %edi,%edi
  call   <glRasterPos3d@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  je     L17
  mov    D1(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp),%edi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L0
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void renderText(char *x) {
  glColor3d(1, 0, 0);
  glRasterPos3d(0, 0, -100);
  while ((*x) != '\0')
    glutBitmapCharacter(GLUT_BITMAP_9_BY_15, *x++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<renderText>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <glColor3d@plt>
  xor    %esi,%esi
  mov    $0xffffff9c,%edx
  xor    %edi,%edi
  call   <glRasterPos3d@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  je     L17
  mov    D8(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x0(%rbp),%edi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L5
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void renderText(char *x) {
  glColor3d(1, 0, 0);
  glRasterPos3d(0, 0, -100);
  while ((*x) != '\0')
    glutBitmapCharacter(GLUT_BITMAP_9_BY_15, *x++);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <bar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2d,-0x4(%rbp)
  je     L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int res;
  res = bar();
  if (res != 45)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bar@plt>
  cmp    $0x2d,%eax
  jne    L9
L18:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L9:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L18
```

assistant: ```c
int main(void) {
  int res;
  res = bar();
  if (res != 45)
    abort();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  cmp    $0x2d,%eax
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int res;
  res = bar();
  if (res != 45)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  cmp    $0x2d,%eax
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int res;
  res = bar();
  if (res != 45)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NearestPrimePIZZA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L46:
  movq   $0x2,-0x8(%rbp)
  jmp    L37
L24:
  addq   $0x1,-0x8(%rbp)
L37:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x10(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  cmp    %rax,-0x8(%rbp)
  jg     L13
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L24
L13:
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L8
  addq   $0x1,-0x10(%rbp)
  jmp    L46
L8:
  nop
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long NearestPrimePIZZA(unsigned long n) {
  long position;
  long index;
  for (position = n;; position++) {
    for (index = 2; index <= (long)sqrt((double)position) && position % index != 0; index++)
      ;
    if (position % index != 0) {
      break;
    }
  }
  return position;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<NearestPrimePIZZA>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  jmp    L37
L39:
  add    $0x1,%rbx
L3:
  movq   %r14,%xmm0
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jl     L22
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L39
L49:
  add    $0x1,%rbp
L37:
  mov    $0x2,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rbp,%xmm1
  movq   %xmm1,%r14
  jmp    L3
L22:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L49
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
unsigned long NearestPrimePIZZA(unsigned long n) {
  long position;
  long index;
  for (position = n;; position++) {
    for (index = 2; index <= (long)sqrt((double)position) && position % index != 0; index++)
      ;
    if (position % index != 0) {
      break;
    }
  }
  return position;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<NearestPrimePIZZA>:
  endbr64
  push   %r14
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  nopl   0x0(%rax)
L43:
  pxor   %xmm1,%xmm1
  mov    $0x2,%ebx
  cvtsi2sd %r12,%xmm1
  movq   %xmm1,%r14
  jmp    L20
  nopl   (%rax)
L33:
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L3
  add    $0x1,%rbx
L20:
  movq   %r14,%xmm0
  call   <sqrt@plt>
  cmp    %rbx,%rax
  mov    %r12,%rax
  jge    L33
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L0
L3:
  add    $0x1,%r12
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
unsigned long NearestPrimePIZZA(unsigned long n) {
  long position;
  long index;
  for (position = n;; position++) {
    for (index = 2; index <= (long)sqrt((double)position) && position % index != 0; index++)
      ;
    if (position % index != 0) {
      break;
    }
  }
  return position;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<NearestPrimePIZZA>:
  endbr64
  push   %r14
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  nopl   0x0(%rax)
L41:
  pxor   %xmm1,%xmm1
  mov    $0x2,%ebx
  cvtsi2sd %r12,%xmm1
  movq   %xmm1,%r14
  jmp    L26
  nopl   (%rax)
L47:
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L9
  add    $0x1,%rbx
L26:
  movq   %r14,%xmm0
  call   <sqrt@plt>
  cmp    %rbx,%rax
  mov    %r12,%rax
  jge    L47
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L49
L9:
  add    $0x1,%r12
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
unsigned long NearestPrimePIZZA(unsigned long n) {
  long position;
  long index;
  for (position = n;; position++) {
    for (index = 2; index <= (long)sqrt((double)position) && position % index != 0; index++)
      ;
    if (position % index != 0) {
      break;
    }
  }
  return position;
}
```