ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<mmAddEntry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rdx,%rbx
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%r14
  mov    %rcx,0x10(%rsp)
  movsbl %sil,%r15d
  mov    %r15d,%esi
  call   <mmGetPtr@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x6(%rbx,%rax,1),%r13d
  mov    0x0(%rbp),%eax
  lea    -0x4(%rax),%r12d
  add    $0x4,%rbp
  cmp    %r12d,%r13d
  jg     L12
  lea    D6(%rip),%r14
  jmp    L57
L94:
  sub    %ebx,%r12d
  movslq %ebx,%rbx
  add    %rbx,%rbp
L97:
  cmp    %r13d,%r12d
  jl     L12
L57:
  mov    0x0(%rbp),%ebx
  test   %ebx,%ebx
  je     L44
  lea    0x4(%rbp),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L94
  cmp    %r13d,%ebx
  jge    L28
  sub    %ebx,%r12d
  movslq %ebx,%rbx
  add    %rbx,%rbp
  jmp    L97
L44:
  cmp    %r12d,%r13d
  jg     L12
  mov    %r13d,0x0(%rbp)
L29:
  add    $0x4,%rbp
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  mov    0x10(%rsp),%rsi
  call   <strcpy@plt>
L76:
  mov    $0x1,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  cmp    %r12d,%r13d
  jle    L29
L12:
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    0x18(%rsp),%rbx
  mov    %rbx,%rdi
  call   <mmGrowShm@plt>
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <mmAddEntry>
  jmp    L76
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6: u

assistant: ```c
int mmAddEntry(char *path, char key, char *type, char *value) {
  char *shmptr = mmGetPtr(path, key);
  int addSize = strlen(type) + strlen(value) + sizeof(int) + 2;
  int size = *(int *)shmptr - sizeof(int);
  shmptr += sizeof(int);
  while (size >= addSize) {
    if (*(int *)shmptr == 0) {
      break;
    } else {
      if (!strcmp(shmptr + sizeof(int), "u")) {
        if (*(int *)shmptr >= addSize)
          break;
        else {
          size -= *(int *)shmptr;
          shmptr += *(int *)shmptr;
        }
      } else {
        size -= *(int *)shmptr;
        shmptr += *(int *)shmptr;
      }
    }
  }
  if (size >= addSize) {
    if (*(int *)shmptr == 0) {
      *(int *)shmptr = addSize;
    }
    shmptr += sizeof(int);
    strcpy(shmptr, type);
    shmptr = strchr(shmptr, '\0') + 1;
    strcpy(shmptr, value);
  } else {
    mmGrowShm(path, key, addSize);
    mmAddEntry(path, key, type, value);
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mmAddEntry>:
  endbr64
  push   %r15
  push   %r14
  movsbl %sil,%r14d
  push   %r13
  mov    %r14d,%esi
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <mmGetPtr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r15d
  call   <strlen@plt>
  lea    0x6(%r15,%rax,1),%r8d
  mov    (%rbx),%eax
  lea    -0x4(%rax),%ecx
  cmp    %ecx,%r8d
  jg     L46
  lea    0x4(%rbx),%rax
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L49:
  cmpb   $0x75,0x4(%rax)
  jne    L42
  cmpb   $0x0,0x1(%r15)
  jne    L42
  cmp    %r8d,%edx
  jge    L3
L42:
  sub    %edx,%ecx
  add    %rdx,%rax
  cmp    %r8d,%ecx
  jl     L46
L59:
  movslq (%rax),%rdx
  lea    0x4(%rax),%r15
  test   %edx,%edx
  jne    L49
  mov    %r8d,(%rax)
L3:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %r12,%rsi
  lea    0x1(%rax),%rdi
  call   <strcpy@plt>
L6:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %r8d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mmGrowShm@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mmAddEntry>
  jmp    L6
```

assistant: ```c
int mmAddEntry(char *path, char key, char *type, char *value) {
  char *shmptr = mmGetPtr(path, key);
  int addSize = strlen(type) + strlen(value) + sizeof(int) + 2;
  int size = *(int *)shmptr - sizeof(int);
  shmptr += sizeof(int);
  while (size >= addSize) {
    if (*(int *)shmptr == 0) {
      break;
    } else {
      if (!strcmp(shmptr + sizeof(int), "u")) {
        if (*(int *)shmptr >= addSize)
          break;
        else {
          size -= *(int *)shmptr;
          shmptr += *(int *)shmptr;
        }
      } else {
        size -= *(int *)shmptr;
        shmptr += *(int *)shmptr;
      }
    }
  }
  if (size >= addSize) {
    if (*(int *)shmptr == 0) {
      *(int *)shmptr = addSize;
    }
    shmptr += sizeof(int);
    strcpy(shmptr, type);
    shmptr = strchr(shmptr, '\0') + 1;
    strcpy(shmptr, value);
  } else {
    mmGrowShm(path, key, addSize);
    mmAddEntry(path, key, type, value);
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mmAddEntry>:
  endbr64
  push   %r15
  push   %r14
  movsbl %sil,%r14d
  push   %r13
  mov    %r14d,%esi
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <mmGetPtr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r15d
  call   <strlen@plt>
  lea    0x6(%r15,%rax,1),%r8d
  mov    (%rbx),%eax
  lea    -0x4(%rax),%ecx
  cmp    %ecx,%r8d
  jg     L74
  lea    0x4(%rbx),%rax
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L31:
  cmpb   $0x75,0x4(%rax)
  jne    L51
  cmpb   $0x0,0x1(%r15)
  jne    L51
  cmp    %r8d,%edx
  jge    L2
L51:
  sub    %edx,%ecx
  add    %rdx,%rax
  cmp    %r8d,%ecx
  jl     L74
L1:
  movslq (%rax),%rdx
  lea    0x4(%rax),%r15
  test   %edx,%edx
  jne    L31
  mov    %r8d,(%rax)
L2:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %r12,%rsi
  lea    0x1(%rax),%rdi
  call   <strcpy@plt>
L64:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %r8d,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mmGrowShm@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mmAddEntry>
  jmp    L64
```

assistant: ```c
int mmAddEntry(char *path, char key, char *type, char *value) {
  char *shmptr = mmGetPtr(path, key);
  int addSize = strlen(type) + strlen(value) + sizeof(int) + 2;
  int size = *(int *)shmptr - sizeof(int);
  shmptr += sizeof(int);
  while (size >= addSize) {
    if (*(int *)shmptr == 0) {
      break;
    } else {
      if (!strcmp(shmptr + sizeof(int), "u")) {
        if (*(int *)shmptr >= addSize)
          break;
        else {
          size -= *(int *)shmptr;
          shmptr += *(int *)shmptr;
        }
      } else {
        size -= *(int *)shmptr;
        shmptr += *(int *)shmptr;
      }
    }
  }
  if (size >= addSize) {
    if (*(int *)shmptr == 0) {
      *(int *)shmptr = addSize;
    }
    shmptr += sizeof(int);
    strcpy(shmptr, type);
    shmptr = strchr(shmptr, '\0') + 1;
    strcpy(shmptr, value);
  } else {
    mmGrowShm(path, key, addSize);
    mmAddEntry(path, key, type, value);
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<display_minute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <get_cutoff@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <get_acc_minlen@plt>
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L14
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L2
L14:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  movsd  D37(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type: string
name: extract_symbolic_data
arguments: tag: D31
type: string
name: extract_symbolic_data
arguments: tag: D37
type: f64
name: extract_symbolic_data
arguments: tag: D27
type: string

tool: D19:  (%u) %i 

tool: D31: ?

tool: D37: 10000

tool: D27: %6.4f


assistant: ```c
void display_minute(int minlen) {
  int cutoff;
  cutoff = get_cutoff();
  printf(" (%u) %i ", get_acc_minlen(), minlen);
  if (cutoff == -1) {
    printf("?\n");
  } else {
    printf("%6.4f\n", cutoff / 1e4);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<display_minute>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%eax
  call   <get_cutoff@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <get_acc_minlen@plt>
  mov    %eax,%esi
  mov    %ebp,%edx
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0xffffffff,%ebx
  je     L15
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  divsd  D37(%rip),%xmm0
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D37
type_guessed: f64
name: read_data
arguments: label: D22
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string

tool: D25:  (%u) %i 

tool: D37: 10000

tool: D22: %6.4f


tool: D26: ?

assistant: ```c
void display_minute(int minlen) {
  int cutoff;
  cutoff = get_cutoff();
  printf(" (%u) %i ", get_acc_minlen(), minlen);
  if (cutoff == -1) {
    printf("?\n");
  } else {
    printf("%6.4f\n", cutoff / 1e4);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<display_minute>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  call   <get_cutoff@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <get_acc_minlen@plt>
  mov    %r12d,%edx
  lea    D36(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xffffffff,%ebx
  je     L8
  pxor   %xmm0,%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2sd %ebx,%xmm0
  divsd  D33(%rip),%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  jmp    10a0 <printf@plt>
  xchg   %ax,%ax
L8:
  add    $0x8,%rsp
  lea    D35(%rip),%rdi
  pop    %rbx
  pop    %r12
  jmp    1080 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D36
data_type: string
name: retrieve_data
arguments: tag: D24
data_type: string
name: retrieve_data
arguments: tag: D33
data_type: f64
name: retrieve_data
arguments: tag: D35
data_type: string

tool: D36:  (%u) %i 

tool: D24: %6.4f


tool: D33: 10000

tool: D35: ?

assistant: ```c
void display_minute(int minlen) {
  int cutoff;
  cutoff = get_cutoff();
  printf(" (%u) %i ", get_acc_minlen(), minlen);
  if (cutoff == -1) {
    printf("?\n");
  } else {
    printf("%6.4f\n", cutoff / 1e4);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<display_minute>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  call   <get_cutoff@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <get_acc_minlen@plt>
  mov    %r12d,%edx
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xffffffff,%ebx
  je     L2
  pxor   %xmm0,%xmm0
  lea    D8(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2sd %ebx,%xmm0
  divsd  D17(%rip),%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  jmp    10a0 <printf@plt>
  xchg   %ax,%ax
L2:
  add    $0x8,%rsp
  lea    D23(%rip),%rdi
  pop    %rbx
  pop    %r12
  jmp    1080 <puts@plt>
```

tool_calls: name: read_data
arguments: tag: D19
datatype: string
name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D17
datatype: f64
name: read_data
arguments: tag: D23
datatype: string

tool: D19:  (%u) %i 

tool: D8: %6.4f


tool: D17: 10000

tool: D23: ?

assistant: ```c
void display_minute(int minlen) {
  int cutoff;
  cutoff = get_cutoff();
  printf(" (%u) %i ", get_acc_minlen(), minlen);
  if (cutoff == -1) {
    printf("?\n");
  } else {
    printf("%6.4f\n", cutoff / 1e4);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  sub    $0x8,%rsp
  push   $0xa
  push   $0xa
  push   $0x5
  mov    $0x4,%r9d
  mov    $0xa,%r8d
  mov    $0xa,%ecx
  mov    $0x5,%edx
  mov    $0x5,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    D13(%rip),%rax
  movq   %rax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D49
datatype: string
name: parse_data
arguments: label: D47
datatype: string
name: parse_data
arguments: label: D43
datatype: string
name: parse_data
arguments: label: D41
datatype: string
name: parse_data
arguments: label: D13
datatype: f64
name: parse_data
arguments: label: D37
datatype: string
name: parse_data
arguments: label: D44
datatype: string

tool: D49: Grade Report for: Nicholas Tello

tool: D47: Assignment 01	Test 01	Quiz 01	Worksheet 01

tool: D43: %d/%d		%d/%d	%d/%d	%d/%d


tool: D41: Total Points:	29/30

tool: D13: 96.67

tool: D37: Average: 	%.2f


tool: D44: Letter Grade: 	%c


assistant: ```c
int main() {
  printf("Grade Report for: Nicholas Tello\n");
  printf("Assignment 01\tTest 01\tQuiz 01\tWorksheet 01\n");
  printf("%d/%d\t\t%d/%d\t%d/%d\t%d/%d\n", 5, 5, 10, 10, 4, 5, 10, 10);
  printf("\n");
  printf("Total Points:\t29/30\n");
  printf("Average: \t%.2f\n", 96.67);
  printf("Letter Grade: \t%c\n", 'A');
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D42(%rip),%rdi
  call   <puts@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  sub    $0x8,%rsp
  push   $0xa
  push   $0xa
  push   $0x5
  mov    $0x4,%r9d
  mov    $0xa,%r8d
  mov    $0xa,%ecx
  mov    $0x5,%edx
  mov    $0x5,%esi
  lea    D65(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  movsd  D10(%rip),%xmm0
  lea    D41(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D63(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D42
type: string
name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D65
type: string
name: parse_data
arguments: label: D51
type: string
name: parse_data
arguments: label: D10
type: f64
name: parse_data
arguments: label: D41
type: string
name: parse_data
arguments: label: D63
type: string

tool: D42: Grade Report for: Nicholas Tello

tool: D36: Assignment 01	Test 01	Quiz 01	Worksheet 01

tool: D65: %d/%d		%d/%d	%d/%d	%d/%d


tool: D51: Total Points:	29/30

tool: D10: 96.67

tool: D41: Average: 	%.2f


tool: D63: Letter Grade: 	%c


assistant: ```c
int main() {
  printf("Grade Report for: Nicholas Tello\n");
  printf("Assignment 01\tTest 01\tQuiz 01\tWorksheet 01\n");
  printf("%d/%d\t\t%d/%d\t%d/%d\t%d/%d\n", 5, 5, 10, 10, 4, 5, 10, 10);
  printf("\n");
  printf("Total Points:\t29/30\n");
  printf("Average: \t%.2f\n", 96.67);
  printf("Letter Grade: \t%c\n", 'A');
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  sub    $0x8,%rsp
  mov    $0xa,%ecx
  xor    %eax,%eax
  push   $0xa
  mov    $0x4,%r9d
  mov    $0xa,%r8d
  mov    $0x5,%edx
  push   $0xa
  mov    $0x5,%esi
  lea    D3(%rip),%rdi
  push   $0x5
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  movsd  D26(%rip),%xmm0
  mov    $0x1,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string
name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D26
type: f64
name: disassemble_data
arguments: data_label: D15
type: string
name: disassemble_data
arguments: data_label: D40
type: string

tool: D8: Grade Report for: Nicholas Tello

tool: D6: Assignment 01	Test 01	Quiz 01	Worksheet 01

tool: D3: %d/%d		%d/%d	%d/%d	%d/%d


tool: D14: Total Points:	29/30

tool: D26: 96.67

tool: D15: Average: 	%.2f


tool: D40: Letter Grade: 	%c


assistant: ```c
int main() {
  printf("Grade Report for: Nicholas Tello\n");
  printf("Assignment 01\tTest 01\tQuiz 01\tWorksheet 01\n");
  printf("%d/%d\t\t%d/%d\t%d/%d\t%d/%d\n", 5, 5, 10, 10, 4, 5, 10, 10);
  printf("\n");
  printf("Total Points:\t29/30\n");
  printf("Average: \t%.2f\n", 96.67);
  printf("Letter Grade: \t%c\n", 'A');
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  sub    $0x8,%rsp
  mov    $0xa,%ecx
  xor    %eax,%eax
  push   $0xa
  mov    $0x4,%r9d
  mov    $0xa,%r8d
  mov    $0x5,%edx
  push   $0xa
  mov    $0x5,%esi
  lea    D42(%rip),%rdi
  push   $0x5
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  movsd  D18(%rip),%xmm0
  mov    $0x1,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D27
data_type: string
name: unpack_data
arguments: data_tag: D56
data_type: string
name: unpack_data
arguments: data_tag: D42
data_type: string
name: unpack_data
arguments: data_tag: D36
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: f64
name: unpack_data
arguments: data_tag: D22
data_type: string
name: unpack_data
arguments: data_tag: D69
data_type: string

tool: D27: Grade Report for: Nicholas Tello

tool: D56: Assignment 01	Test 01	Quiz 01	Worksheet 01

tool: D42: %d/%d		%d/%d	%d/%d	%d/%d


tool: D36: Total Points:	29/30

tool: D18: 96.67

tool: D22: Average: 	%.2f


tool: D69: Letter Grade: 	%c


assistant: ```c
int main() {
  printf("Grade Report for: Nicholas Tello\n");
  printf("Assignment 01\tTest 01\tQuiz 01\tWorksheet 01\n");
  printf("%d/%d\t\t%d/%d\t%d/%d\t%d/%d\n", 5, 5, 10, 10, 4, 5, 10, 10);
  printf("\n");
  printf("Total Points:\t29/30\n");
  printf("Average: \t%.2f\n", 96.67);
  printf("Letter Grade: \t%c\n", 'A');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__set_64bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x10(%rbp),%rsi
  mov    -0x14(%rbp),%r8d
  mov    -0x18(%rbp),%ecx
  mov    %rsi,%rdi
  mov    %r8d,%ebx
L3:
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  lock cmpxchg8b (%rdi)
  jne    L3
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void __set_64bit(unsigned long long *ptr, unsigned int low, unsigned int high) {
  __asm__ __volatile__("\n1:\t"
                       "movl (%0), %%eax\n\t"
                       "movl 4(%0), %%edx\n\t"
                       "lock cmpxchg8b (%0)\n\t"
                       "jnz 1b"
                       :
                       : "D"(ptr), "b"(low), "c"(high)
                       : "ax", "dx", "memory");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__set_64bit>:
  endbr64
  push   %rbx
  mov    %edx,%ecx
  mov    %esi,%ebx
L7:
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  lock cmpxchg8b (%rdi)
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) void __set_64bit(unsigned long long *ptr, unsigned int low, unsigned int high) {
  __asm__ __volatile__("\n1:\t"
                       "movl (%0), %%eax\n\t"
                       "movl 4(%0), %%edx\n\t"
                       "lock cmpxchg8b (%0)\n\t"
                       "jnz 1b"
                       :
                       : "D"(ptr), "b"(low), "c"(high)
                       : "ax", "dx", "memory");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__set_64bit>:
  endbr64
  push   %rbx
  mov    %edx,%ecx
  mov    %esi,%ebx
L1:
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  lock cmpxchg8b (%rdi)
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) void __set_64bit(unsigned long long *ptr, unsigned int low, unsigned int high) {
  __asm__ __volatile__("\n1:\t"
                       "movl (%0), %%eax\n\t"
                       "movl 4(%0), %%edx\n\t"
                       "lock cmpxchg8b (%0)\n\t"
                       "jnz 1b"
                       :
                       : "D"(ptr), "b"(low), "c"(high)
                       : "ax", "dx", "memory");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__set_64bit>:
  endbr64
  push   %rbx
  mov    %edx,%ecx
  mov    %esi,%ebx
L7:
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  lock cmpxchg8b (%rdi)
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) void __set_64bit(unsigned long long *ptr, unsigned int low, unsigned int high) {
  __asm__ __volatile__("\n1:\t"
                       "movl (%0), %%eax\n\t"
                       "movl 4(%0), %%edx\n\t"
                       "lock cmpxchg8b (%0)\n\t"
                       "jnz 1b"
                       :
                       : "D"(ptr), "b"(low), "c"(high)
                       : "ax", "dx", "memory");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_sl4_hash_func_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L4
L3:
  addq   $0x1000193,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t _sl4_hash_func_str(const void *key) {
  size_t h;
  const unsigned char *k;
  k = (const unsigned char *)key;
  for (h = 0; *k; k++) {
    h += 16777619;
    h ^= *k;
  }
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_sl4_hash_func_str>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L0
  mov    $0x0,%eax
L19:
  add    $0x1000193,%rax
  movzbl %dl,%edx
  xor    %rdx,%rax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t _sl4_hash_func_str(const void *key) {
  size_t h;
  const unsigned char *k;
  k = (const unsigned char *)key;
  for (h = 0; *k; k++) {
    h += 16777619;
    h ^= *k;
  }
  return h;
}
```