ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L23
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D17(%rip),%r12
L12:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jg     L12
L30:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movd   %xmm2,%ebx
  lea    D34(%rip),%rdi
  call   <printf@plt>
  movd   %ebx,%xmm0
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0x0,%ebp
  jmp    L30
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D34
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D17: %d

tool: D34: Sum: %d


tool: D18: Avg: %.2f


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i, num, sum = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &num);
    sum = sum + num;
  }
  float avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", avg);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L11
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0x14(%rsp),%ebp
  cmp    %ebx,%eax
  jg     L19
L11:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  lea    D19(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  cvtsi2ss %eax,%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  lea    D29(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string

tool: D12: %d

tool: D19: Sum: %d


tool: D29: Avg: %.2f


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i, num, sum = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &num);
    sum = sum + num;
  }
  float avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", avg);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L13
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0x14(%rsp),%ebp
  cmp    %ebx,%eax
  jg     L0
L13:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  lea    D4(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  cvtsi2ss %eax,%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  lea    D5(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D4
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string

tool: D14: %d

tool: D4: Sum: %d


tool: D5: Avg: %.2f


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i, num, sum = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &num);
    sum = sum + num;
  }
  float avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", avg);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sig_lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D40(%rip),%rax
  mov    (%rax),%edx
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D40(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D40(%rip),%rax
  mov    (%rax),%edx
  mov    D44(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sig_lock() {
  signal(SIGTERM, SIG_IGN);
  signal(SIGINT, SIG_IGN);
  signal(SIGUSR1, SIG_IGN);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sig_lock>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
  mov    (%rbx),%esi
  mov    D35(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D39(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  pop    %rbx
  ret
```

assistant: ```c
void sig_lock() {
  signal(SIGTERM, SIG_IGN);
  signal(SIGINT, SIG_IGN);
  signal(SIGUSR1, SIG_IGN);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sig_lock>:
  endbr64
  push   %rbx
  mov    D24(%rip),%rax
  mov    D29(%rip),%rbx
  mov    (%rax),%edi
  mov    (%rbx),%esi
  call   <signal@plt>
  mov    D39(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D10(%rip),%rax
  mov    (%rbx),%esi
  pop    %rbx
  mov    (%rax),%edi
  jmp    1050 <signal@plt>
```

assistant: ```c
void sig_lock() {
  signal(SIGTERM, SIG_IGN);
  signal(SIGINT, SIG_IGN);
  signal(SIGUSR1, SIG_IGN);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sig_lock>:
  endbr64
  push   %rbx
  mov    D38(%rip),%rax
  mov    D14(%rip),%rbx
  mov    (%rax),%edi
  mov    (%rbx),%esi
  call   <signal@plt>
  mov    D0(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D10(%rip),%rax
  mov    (%rbx),%esi
  pop    %rbx
  mov    (%rax),%edi
  jmp    1050 <signal@plt>
```

assistant: ```c
void sig_lock() {
  signal(SIGTERM, SIG_IGN);
  signal(SIGINT, SIG_IGN);
  signal(SIGUSR1, SIG_IGN);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no, noclone)) void foo(char *a, char *b) {
  a[0] = b[0] = 0;
  __builtin_memcpy(a, b, 4);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  movb   $0x0,(%rsi)
  movb   $0x0,(%rdi)
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
__attribute__((no, noclone)) void foo(char *a, char *b) {
  a[0] = b[0] = 0;
  __builtin_memcpy(a, b, 4);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  movb   $0x0,(%rsi)
  movb   $0x0,(%rdi)
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
__attribute__((no, noclone)) void foo(char *a, char *b) {
  a[0] = b[0] = 0;
  __builtin_memcpy(a, b, 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mtxLoadRotateY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x28(%rax),%rbx
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <cosf@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  movss  (%rbx),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rbx
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinf@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  movss  D13(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x3c,%rax
  movss  D2(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rdx
  add    $0x14,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0x38,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rdx
  add    $0x34,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rdx
  add    $0x2c,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0x24,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rdx
  add    $0x1c,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rdx
  add    $0x10,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rdx
  add    $0x4,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
type: byte[4]
name: parse_data
arguments: data_tag: D2
type: f32

tool: {"D13": [0x00,0x00,0x00,0x80]}

tool: D2: 1

assistant: ```c
void mtxLoadRotateY(float *mtx, float rad) {
  mtx[0] = mtx[10] = cosf(rad);
  mtx[2] = sinf(rad);
  mtx[8] = -mtx[2];
  mtx[5] = mtx[15] = 1.0;
  mtx[1] = mtx[3] = mtx[4] = mtx[6] = mtx[7] = mtx[9] = mtx[11] = mtx[12] = mtx[13] = mtx[14] = 0.0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mtxLoadRotateY>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  movss  %xmm1,0x28(%rbx)
  movss  %xmm1,(%rbx)
  movss  %xmm0,0x8(%rbx)
  xorps  D6(%rip),%xmm0
  movss  %xmm0,0x20(%rbx)
  movss  D9(%rip),%xmm0
  movss  %xmm0,0x3c(%rbx)
  movss  %xmm0,0x14(%rbx)
  movl   $0x0,0x38(%rbx)
  movl   $0x0,0x34(%rbx)
  movl   $0x0,0x30(%rbx)
  movl   $0x0,0x2c(%rbx)
  movl   $0x0,0x24(%rbx)
  movl   $0x0,0x1c(%rbx)
  movl   $0x0,0x18(%rbx)
  movl   $0x0,0x10(%rbx)
  movl   $0x0,0xc(%rbx)
  movl   $0x0,0x4(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: byte[16]
name: parse_data
arguments: data_tag: D9
type_infered: f32

tool: {"D6": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D9: 1

assistant: ```c
void mtxLoadRotateY(float *mtx, float rad) {
  mtx[0] = mtx[10] = cosf(rad);
  mtx[2] = sinf(rad);
  mtx[8] = -mtx[2];
  mtx[5] = mtx[15] = 1.0;
  mtx[1] = mtx[3] = mtx[4] = mtx[6] = mtx[7] = mtx[9] = mtx[11] = mtx[12] = mtx[13] = mtx[14] = 0.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mtxLoadRotateY>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  movq   $0x0,0x2c(%rbx)
  movq   $0x0,0x34(%rbx)
  movss  %xmm0,0x8(%rbx)
  xorps  D0(%rip),%xmm0
  movl   $0x3f800000,0x3c(%rbx)
  movl   $0x0,0x24(%rbx)
  movq   $0x0,0xc(%rbx)
  movq   $0x3f800000,0x14(%rbx)
  movl   $0x0,0x1c(%rbx)
  movl   $0x0,0x4(%rbx)
  movss  %xmm1,0x28(%rbx)
  movss  %xmm1,(%rbx)
  movss  %xmm0,0x20(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: byte[16]

tool: {"D0": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void mtxLoadRotateY(float *mtx, float rad) {
  mtx[0] = mtx[10] = cosf(rad);
  mtx[2] = sinf(rad);
  mtx[8] = -mtx[2];
  mtx[5] = mtx[15] = 1.0;
  mtx[1] = mtx[3] = mtx[4] = mtx[6] = mtx[7] = mtx[9] = mtx[11] = mtx[12] = mtx[13] = mtx[14] = 0.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mtxLoadRotateY>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  movq   $0x0,0x2c(%rbx)
  movq   $0x0,0x34(%rbx)
  movss  %xmm0,0x8(%rbx)
  xorps  D3(%rip),%xmm0
  movl   $0x3f800000,0x3c(%rbx)
  movl   $0x0,0x24(%rbx)
  movq   $0x0,0xc(%rbx)
  movq   $0x3f800000,0x14(%rbx)
  movl   $0x0,0x1c(%rbx)
  movl   $0x0,0x4(%rbx)
  movss  %xmm1,0x28(%rbx)
  movss  %xmm1,(%rbx)
  movss  %xmm0,0x20(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void mtxLoadRotateY(float *mtx, float rad) {
  mtx[0] = mtx[10] = cosf(rad);
  mtx[2] = sinf(rad);
  mtx[8] = -mtx[2];
  mtx[5] = mtx[15] = 1.0;
  mtx[1] = mtx[3] = mtx[4] = mtx[6] = mtx[7] = mtx[9] = mtx[11] = mtx[12] = mtx[13] = mtx[14] = 0.0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<POS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L39
  cmpb   $0x5a,-0x4(%rbp)
  jg     L39
  movsbl -0x4(%rbp),%eax
  sub    $0x41,%eax
  jmp    L93
L39:
  cmpb   $0x60,-0x4(%rbp)
  jle    L86
  cmpb   $0x7a,-0x4(%rbp)
  jg     L86
  movsbl -0x4(%rbp),%eax
  sub    $0x47,%eax
  jmp    L93
L86:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L136
  cmpb   $0x39,-0x4(%rbp)
  jg     L136
  movsbl -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L93
L136:
  cmpb   $0x2b,-0x4(%rbp)
  jne    L100
  mov    $0x3e,%eax
  jmp    L93
L100:
  cmpb   $0x2f,-0x4(%rbp)
  jne    L85
  mov    $0x3f,%eax
  jmp    L93
L85:
  cmpb   $0x3d,-0x4(%rbp)
  jne    L121
  mov    $0xffffffff,%eax
  jmp    L93
L121:
  mov    $0xfffffffe,%eax
L93:
  pop    %rbp
  ret
```

assistant: ```c
int POS(char c) {
  if (c >= 'A' && c <= 'Z')
    return c - 'A';
  if (c >= 'a' && c <= 'z')
    return c - 'a' + 26;
  if (c >= '0' && c <= '9')
    return c - '0' + 52;
  if (c == '+')
    return 62;
  if (c == '/')
    return 63;
  if (c == '=')
    return -1;
  return -2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<POS>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L7
  cmp    $0x39,%dil
  jg     L38
  cmp    $0x2f,%dil
  jg     L28
  mov    $0x3e,%eax
  cmp    $0x2b,%dil
  je     L25
  cmp    $0x2f,%dil
  mov    $0xfffffffe,%eax
  mov    $0x3f,%edx
  cmove  %edx,%eax
  ret
L7:
  movsbl %dil,%edi
  lea    -0x41(%rdi),%eax
  ret
L38:
  mov    $0xffffffff,%eax
  cmp    $0x3d,%dil
  je     L25
  lea    -0x61(%rdi),%eax
  movsbl %dil,%edi
  sub    $0x47,%edi
  cmp    $0x1a,%al
  mov    $0xfffffffe,%eax
  cmovb  %edi,%eax
  ret
L28:
  movsbl %dil,%edi
  lea    0x4(%rdi),%eax
L25:
  ret
```

assistant: ```c
int POS(char c) {
  if (c >= 'A' && c <= 'Z')
    return c - 'A';
  if (c >= 'a' && c <= 'z')
    return c - 'a' + 26;
  if (c >= '0' && c <= '9')
    return c - '0' + 52;
  if (c == '+')
    return 62;
  if (c == '/')
    return 63;
  if (c == '=')
    return -1;
  return -2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<POS>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L36
  cmp    $0x39,%dil
  jg     L45
  cmp    $0x2f,%dil
  jg     L37
  mov    $0x3e,%eax
  cmp    $0x2b,%dil
  je     L14
  cmp    $0x2f,%dil
  mov    $0x3f,%edx
  mov    $0xfffffffe,%eax
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax)
L45:
  mov    $0xffffffff,%eax
  cmp    $0x3d,%dil
  je     L14
  lea    -0x61(%rdi),%eax
  sub    $0x47,%edi
  movsbl %dil,%edi
  cmp    $0x1a,%al
  mov    $0xfffffffe,%eax
  cmovb  %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  add    $0x4,%edi
  movsbl %dil,%eax
L14:
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  movsbl %al,%eax
  ret
```

assistant: ```c
int POS(char c) {
  if (c >= 'A' && c <= 'Z')
    return c - 'A';
  if (c >= 'a' && c <= 'z')
    return c - 'a' + 26;
  if (c >= '0' && c <= '9')
    return c - '0' + 52;
  if (c == '+')
    return 62;
  if (c == '/')
    return 63;
  if (c == '=')
    return -1;
  return -2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<POS>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L18
  cmp    $0x39,%dil
  jg     L24
  cmp    $0x2f,%dil
  jg     L47
  mov    $0x3e,%eax
  cmp    $0x2b,%dil
  je     L31
  cmp    $0x2f,%dil
  mov    $0x3f,%edx
  mov    $0xfffffffe,%eax
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax)
L24:
  mov    $0xffffffff,%eax
  cmp    $0x3d,%dil
  je     L31
  lea    -0x61(%rdi),%eax
  sub    $0x47,%edi
  movsbl %dil,%edi
  cmp    $0x1a,%al
  mov    $0xfffffffe,%eax
  cmovb  %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  add    $0x4,%edi
  movsbl %dil,%eax
L31:
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  movsbl %al,%eax
  ret
```

assistant: ```c
int POS(char c) {
  if (c >= 'A' && c <= 'Z')
    return c - 'A';
  if (c >= 'a' && c <= 'z')
    return c - 'a' + 26;
  if (c >= '0' && c <= '9')
    return c - '0' + 52;
  if (c == '+')
    return 62;
  if (c == '/')
    return 63;
  if (c == '=')
    return -1;
  return -2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<float_to_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t float_to_bits(float a) {
  union {
    float f;
    uint32_t i;
  } x;
  x.f = a;
  return x.i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<float_to_bits>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
uint32_t float_to_bits(float a) {
  union {
    float f;
    uint32_t i;
  } x;
  x.f = a;
  return x.i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<float_to_bits>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
uint32_t float_to_bits(float a) {
  union {
    float f;
    uint32_t i;
  } x;
  x.f = a;
  return x.i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<float_to_bits>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
uint32_t float_to_bits(float a) {
  union {
    float f;
    uint32_t i;
  } x;
  x.f = a;
  return x.i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thread_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <pause@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: thread started...


assistant: ```c
void *thread_run(void *arg) {
  printf("thread started...\n");
  pause();
  return (void *)0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<thread_run>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <pause@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D3: thread started...


assistant: ```c
void *thread_run(void *arg) {
  printf("thread started...\n");
  pause();
  return (void *)0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<thread_run>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <pause@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: thread started...


assistant: ```c
void *thread_run(void *arg) {
  printf("thread started...\n");
  pause();
  return (void *)0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thread_run>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <pause@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D8: thread started...


assistant: ```c
void *thread_run(void *arg) {
  printf("thread started...\n");
  pause();
  return (void *)0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<min_route>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    -0x20(%rbp),%rax
  jmp    L1
L15:
  cmpq   $0x0,-0x20(%rbp)
  jne    L8
  mov    -0x18(%rbp),%rax
  jmp    L1
L8:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rt_cmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L4
  mov    -0x18(%rbp),%rax
  jmp    L1
L4:
  mov    -0x20(%rbp),%rax
L1:
  leave
  ret
```

assistant: ```c
const struct babel_route *min_route(const struct babel_route *r1, const struct babel_route *r2) {
  int rc;
  if (!r1)
    return r2;
  if (!r2)
    return r1;
  rc = rt_cmp(r1, r2);
  return rc <= 0 ? r1 : r2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<min_route>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%rbx
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L26
  call   <rt_cmp@plt>
  test   %eax,%eax
  mov    %rbp,%rax
  cmovle %rbx,%rax
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rsi,%rax
  jmp    L26
```

assistant: ```c
const struct babel_route *min_route(const struct babel_route *r1, const struct babel_route *r2) {
  int rc;
  if (!r1)
    return r2;
  if (!r2)
    return r1;
  rc = rt_cmp(r1, r2);
  return rc <= 0 ? r1 : r2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<min_route>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L18
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L7
  call   <rt_cmp@plt>
  test   %eax,%eax
  jle    L7
L18:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const struct babel_route *min_route(const struct babel_route *r1, const struct babel_route *r2) {
  int rc;
  if (!r1)
    return r2;
  if (!r2)
    return r1;
  rc = rt_cmp(r1, r2);
  return rc <= 0 ? r1 : r2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min_route>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L10
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L19
  call   <rt_cmp@plt>
  test   %eax,%eax
  jle    L19
L10:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L19:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const struct babel_route *min_route(const struct babel_route *r1, const struct babel_route *r2) {
  int rc;
  if (!r1)
    return r2;
  if (!r2)
    return r1;
  rc = rt_cmp(r1, r2);
  return rc <= 0 ? r1 : r2;
}
```