ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<varint_decode>:
  endbr64
  movq   $0x0,(%rdx)
  mov    %rdi,%r9
  test   %esi,%esi
  jle    L4
  lea    0x0(,%rsi,8),%r10d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  sub    %esi,%r10d
  mov    $0x1,%esi
  jmp    L21
  nopl   0x0(%rax)
L7:
  add    $0x7,%ecx
  add    $0x1,%rsi
  cmp    %r10d,%ecx
  je     L5
L21:
  mov    -0x4(%r9,%rsi,4),%edi
  mov    %edi,%eax
  and    $0x7f,%eax
  shl    %cl,%eax
  cltq
  add    %rax,%r8
  and    $0x80,%edi
  mov    %esi,%eax
  jne    L7
  mov    %r8,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r8,(%rdx)
  mov    $0xffffffff,%eax
  ret
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int varint_decode(uint8_t *buffer, int bufsize, uint64_t *value) {
  int i, bits;
  *value = 0;
  for (i = 0, bits = 0; i < bufsize; i++, bits += 7) {
    *value += (buffer[i] & 0x7F) << bits;
    if ((buffer[i] & 0x80) == 0) {
      return (i + 1);
    }
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_cat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *string_cat(const char *l, const char *r) {
  size_t lSz = strlen(l);
  size_t rSz = strlen(r);
  char *newString = malloc(lSz + rSz + 1);
  strncpy(newString, l, lSz + rSz);
  strncpy(newString + lSz, r, rSz);
  newString[lSz + rSz] = '\0';
  return newString;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_cat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  lea    0x0(%rbp,%rax,1),%r14
  lea    0x1(%r14),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    (%rbx,%rbp,1),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r14,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *string_cat(const char *l, const char *r) {
  size_t lSz = strlen(l);
  size_t rSz = strlen(r);
  char *newString = malloc(lSz + rSz + 1);
  strncpy(newString, l, lSz + rSz);
  strncpy(newString + lSz, r, rSz);
  newString[lSz + rSz] = '\0';
  return newString;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<string_cat>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%r15
  mov    %rax,%r13
  lea    0x1(%r15),%rdi
  call   <malloc@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%r15,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *string_cat(const char *l, const char *r) {
  size_t lSz = strlen(l);
  size_t rSz = strlen(r);
  char *newString = malloc(lSz + rSz + 1);
  strncpy(newString, l, lSz + rSz);
  strncpy(newString + lSz, r, rSz);
  newString[lSz + rSz] = '\0';
  return newString;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_cat>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%r15
  mov    %rax,%r13
  lea    0x1(%r15),%rdi
  call   <malloc@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%r15,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *string_cat(const char *l, const char *r) {
  size_t lSz = strlen(l);
  size_t rSz = strlen(r);
  char *newString = malloc(lSz + rSz + 1);
  strncpy(newString, l, lSz + rSz);
  strncpy(newString + lSz, r, rSz);
  newString[lSz + rSz] = '\0';
  return newString;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OS_SHA1_File>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x850,%rsp
  mov    %rdi,-0x848(%rbp)
  mov    %rsi,-0x850(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x850(%rbp),%rax
  mov    $0x41,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x0,-0xf(%rbp)
  mov    -0x848(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x838(%rbp)
  cmpq   $0x0,-0x838(%rbp)
  jne    L22
  mov    $0xffffffff,%eax
  jmp    L35
L22:
  lea    -0x840(%rbp),%rax
  mov    %rax,%rdi
  call   <SHA1_Init@plt>
  jmp    L6
L2:
  mov    -0x83c(%rbp),%eax
  cltq
  movb   $0x0,-0x810(%rbp,%rax,1)
  mov    -0x83c(%rbp),%eax
  movslq %eax,%rdx
  lea    -0x810(%rbp),%rcx
  lea    -0x840(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SHA1_Update@plt>
L6:
  mov    -0x838(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x800,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x83c(%rbp)
  cmpl   $0x0,-0x83c(%rbp)
  jg     L2
  lea    -0x840(%rbp),%rdx
  lea    -0x830(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <SHA1_Final@plt>
  movl   $0x0,-0x83c(%rbp)
  jmp    L47
L34:
  mov    -0x83c(%rbp),%eax
  cltq
  movzbl -0x830(%rbp,%rax,1),%eax
  movzbl %al,%edx
  mov    -0x850(%rbp),%rax
  mov    %edx,%ecx
  lea    D6(%rip),%rdx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  addq   $0x2,-0x850(%rbp)
  addl   $0x1,-0x83c(%rbp)
L47:
  cmpl   $0x13,-0x83c(%rbp)
  jle    L34
  mov    -0x838(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D15
data_type: string
name: read_data
arguments: tag: D6
data_type: string

tool: D15: rb

tool: D6: %02x

assistant: ```c
int OS_SHA1_File(char *fname, char *output) {
  SHA_CTX c;
  FILE *fp;
  unsigned char buf[2048 + 2];
  unsigned char md[20];
  int n;
  memset(output, 0, 65);
  buf[2049] = '\0';
  fp = fopen(fname, "rb");
  if (!fp)
    return (-1);
  SHA1_Init(&c);
  while ((n = fread(buf, 1, 2048, fp)) > 0) {
    buf[n] = '\0';
    SHA1_Update(&c, buf, (unsigned long)n);
  }
  SHA1_Final(&(md[0]), &c);
  for (n = 0; n < 20; n++) {
    snprintf(output, 3, "%02x", md[n]);
    output += 2;
  }
  fclose(fp);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OS_SHA1_File>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x840,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x838(%rsp)
  xor    %eax,%eax
  mov    $0x41,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  movb   $0x0,0x831(%rsp)
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%r12
  lea    0xc(%rsp),%rdi
  call   <SHA1_Init@plt>
  lea    0x30(%rsp),%rbx
  jmp    L21
L33:
  movslq %eax,%rdx
  movb   $0x0,0x30(%rsp,%rdx,1)
  lea    0xc(%rsp),%rdi
  mov    %rbx,%rsi
  call   <SHA1_Update@plt>
L21:
  mov    %r12,%rcx
  mov    $0x800,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %eax,%eax
  jg     L33
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <SHA1_Final@plt>
  lea    0x24(%rsp),%r14
  lea    D16(%rip),%r13
L53:
  movzbl (%rbx),%ecx
  mov    %r13,%rdx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  add    $0x2,%rbp
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L53
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L8:
  mov    0x838(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x840,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L8
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string

tool: D17: rb

tool: D16: %02x

assistant: ```c
int OS_SHA1_File(char *fname, char *output) {
  SHA_CTX c;
  FILE *fp;
  unsigned char buf[2048 + 2];
  unsigned char md[20];
  int n;
  memset(output, 0, 65);
  buf[2049] = '\0';
  fp = fopen(fname, "rb");
  if (!fp)
    return (-1);
  SHA1_Init(&c);
  while ((n = fread(buf, 1, 2048, fp)) > 0) {
    buf[n] = '\0';
    SHA1_Update(&c, buf, (unsigned long)n);
  }
  SHA1_Final(&(md[0]), &c);
  for (n = 0; n < 20; n++) {
    snprintf(output, 3, "%02x", md[n]);
    output += 2;
  }
  fclose(fp);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OS_SHA1_File>:
  endbr64
  push   %r14
  mov    $0x41,%edx
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x840,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x838(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  movb   $0x0,0x831(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L34
  lea    0xc(%rsp),%r13
  mov    %rax,%r12
  lea    0x30(%rsp),%rbx
  mov    %r13,%rdi
  call   <SHA1_Init@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %eax,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  movb   $0x0,0x30(%rsp,%rdx,1)
  call   <SHA1_Update@plt>
L47:
  mov    %r12,%rcx
  mov    $0x800,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %eax,%eax
  jg     L1
  lea    0x10(%rsp),%rbx
  mov    %r13,%rsi
  lea    0x24(%rsp),%r14
  mov    %rbx,%rdi
  lea    D17(%rip),%r13
  call   <SHA1_Final@plt>
L29:
  movzbl (%rbx),%ecx
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    $0x3,%esi
  add    $0x1,%rbx
  add    $0x2,%rbp
  call   <snprintf@plt>
  cmp    %rbx,%r14
  jne    L29
  mov    %r12,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L39:
  mov    0x838(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x840,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  mov    $0xffffffff,%eax
  jmp    L39
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D17
type_infered: string

tool: D5: rb

tool: D17: %02x

assistant: ```c
int OS_SHA1_File(char *fname, char *output) {
  SHA_CTX c;
  FILE *fp;
  unsigned char buf[2048 + 2];
  unsigned char md[20];
  int n;
  memset(output, 0, 65);
  buf[2049] = '\0';
  fp = fopen(fname, "rb");
  if (!fp)
    return (-1);
  SHA1_Init(&c);
  while ((n = fread(buf, 1, 2048, fp)) > 0) {
    buf[n] = '\0';
    SHA1_Update(&c, buf, (unsigned long)n);
  }
  SHA1_Final(&(md[0]), &c);
  for (n = 0; n < 20; n++) {
    snprintf(output, 3, "%02x", md[n]);
    output += 2;
  }
  fclose(fp);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<OS_SHA1_File>:
  endbr64
  push   %r14
  mov    $0x41,%edx
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x840,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x838(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  lea    D13(%rip),%rsi
  mov    %r12,%rdi
  movb   $0x0,0x831(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L27
  lea    0xc(%rsp),%r13
  mov    %rax,%r12
  lea    0x30(%rsp),%rbx
  mov    %r13,%rdi
  call   <SHA1_Init@plt>
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L57:
  movslq %eax,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  movb   $0x0,0x30(%rsp,%rdx,1)
  call   <SHA1_Update@plt>
L51:
  mov    %r12,%rcx
  mov    $0x800,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %eax,%eax
  jg     L57
  lea    0x10(%rsp),%rbx
  mov    %r13,%rsi
  lea    0x24(%rsp),%r14
  mov    %rbx,%rdi
  lea    D4(%rip),%r13
  call   <SHA1_Final@plt>
L0:
  movzbl (%rbx),%ecx
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    $0x3,%esi
  add    $0x1,%rbx
  add    $0x2,%rbp
  call   <snprintf@plt>
  cmp    %r14,%rbx
  jne    L0
  mov    %r12,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L33:
  mov    0x838(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x840,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  mov    $0xffffffff,%eax
  jmp    L33
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string

tool: D13: rb

tool: D4: %02x

assistant: ```c
int OS_SHA1_File(char *fname, char *output) {
  SHA_CTX c;
  FILE *fp;
  unsigned char buf[2048 + 2];
  unsigned char md[20];
  int n;
  memset(output, 0, 65);
  buf[2049] = '\0';
  fp = fopen(fname, "rb");
  if (!fp)
    return (-1);
  SHA1_Init(&c);
  while ((n = fread(buf, 1, 2048, fp)) > 0) {
    buf[n] = '\0';
    SHA1_Update(&c, buf, (unsigned long)n);
  }
  SHA1_Final(&(md[0]), &c);
  for (n = 0; n < 20; n++) {
    snprintf(output, 3, "%02x", md[n]);
    output += 2;
  }
  fclose(fp);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L20
L14:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L20:
  cmpl   $0xa,-0xc(%rbp)
  jle    L14
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D13
type_infered: string

tool: D13: %d

assistant: ```c
int main() {
  int temp, sum = 0;
  int i;
  for (i = 1; i <= 10; i++) {
    scanf("%d", &temp);
    sum = sum + temp;
  }
  printf("%d", sum / 10);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%ebx
  mov    $0x0,%ebp
  lea    D4(%rip),%r12
L4:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  sub    $0x1,%ebx
  jne    L4
  movslq %ebp,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sar    $0x1f,%ebp
  sub    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: %d

assistant: ```c
int main() {
  int temp, sum = 0;
  int i;
  for (i = 1; i <= 10; i++) {
    scanf("%d", &temp);
    sum = sum + temp;
  }
  printf("%d", sum / 10);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L16:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  sub    $0x1,%ebx
  jne    L16
  movslq %ebp,%rsi
  sar    $0x1f,%ebp
  mov    %r12,%rdi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main() {
  int temp, sum = 0;
  int i;
  for (i = 1; i <= 10; i++) {
    scanf("%d", &temp);
    sum = sum + temp;
  }
  printf("%d", sum / 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L18:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  sub    $0x1,%ebx
  jne    L18
  movslq %ebp,%rsi
  sar    $0x1f,%ebp
  mov    %r12,%rdi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: %d

assistant: ```c
int main() {
  int temp, sum = 0;
  int i;
  for (i = 1; i <= 10; i++) {
    scanf("%d", &temp);
    sum = sum + temp;
  }
  printf("%d", sum / 10);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <new_matrix_double@plt>
  mov    -0x38(%rbp),%rdx
  mov    %rax,(%rdx)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L14
L16:
  movq   $0x0,-0x10(%rbp)
  jmp    L20
L46:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  test   %rax,%rax
  je     L39
  addq   $0x1,-0x8(%rbp)
  jmp    L59
L39:
  mov    $0xffffffff,%eax
  jmp    L13
L59:
  addq   $0x1,-0x10(%rbp)
L20:
  mov    -0x30(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jb     L46
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x2c(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jb     L16
  mov    -0x8(%rbp),%rax
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: %lf

assistant: ```c
int read_set(FILE *input, int setlen, int nobj, double ***pset) {
  size_t i, j, ctr;
  (*pset) = new_matrix_double(setlen, nobj);
  ctr = 0;
  for (i = 0; i < setlen; i++) {
    for (j = 0; j < nobj; j++) {
      if (fscanf(input, "%lf", &(*pset)[i][j]))
        ctr++;
      else
        return -1;
    }
  }
  return ctr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_set>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    %edx,0x14(%rsp)
  mov    %rcx,%r12
  mov    %ebx,%edi
  call   <new_matrix_double@plt>
  mov    %rax,(%r12)
  movslq %ebx,%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%ebx
  movq   $0x0,0x8(%rsp)
  lea    D4(%rip),%r15
  test   %rax,%rax
  je     L6
L54:
  movslq 0x14(%rsp),%rax
  mov    0x8(%rsp),%rcx
  lea    0x0(,%rcx,8),%r13
  lea    (%rax,%rbx,1),%r14
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L0
L7:
  mov    (%r12),%rax
  mov    %rbp,%rdx
  add    (%rax,%r13,1),%rdx
  mov    %r15,%rsi
  mov    (%rsp),%rdi
  call   <fscanf@plt>
  test   %rax,%rax
  je     L24
  add    $0x1,%rbx
  add    $0x8,%rbp
  cmp    %rbx,%r14
  jne    L7
  mov    %r14,%rbx
L0:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    0x18(%rsp),%rax
  jne    L54
  mov    %rbx,0x18(%rsp)
L6:
  mov    0x18(%rsp),%eax
  jmp    L26
L24:
  mov    $0xffffffff,%eax
L26:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D4: %lf

assistant: ```c
int read_set(FILE *input, int setlen, int nobj, double ***pset) {
  size_t i, j, ctr;
  (*pset) = new_matrix_double(setlen, nobj);
  ctr = 0;
  for (i = 0; i < setlen; i++) {
    for (j = 0; j < nobj; j++) {
      if (fscanf(input, "%lf", &(*pset)[i][j]))
        ctr++;
      else
        return -1;
    }
  }
  return ctr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_set>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    %edx,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  sub    $0x28,%rsp
  call   <new_matrix_double@plt>
  mov    %rax,(%r15)
  movslq %ebp,%rax
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L5
  movslq %r14d,%rax
  lea    D8(%rip),%r12
  xor    %r14d,%r14d
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x10(%rsp)
L0:
  mov    0x8(%rsp),%rax
  xor    %r13d,%r13d
  lea    0x0(,%rax,8),%rbp
  mov    0x10(%rsp),%rax
  lea    (%rax,%r14,1),%rcx
  mov    %rcx,(%rsp)
  test   %rax,%rax
  jne    L10
  jmp    L74
  nopl   0x0(%rax)
L78:
  add    $0x1,%r14
  add    $0x8,%r13
  cmp    %r14,(%rsp)
  je     L74
L10:
  mov    (%r15),%rax
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    (%rax,%rbp,1),%rdx
  add    %r13,%rdx
  call   <fscanf@plt>
  test   %rax,%rax
  jne    L78
  mov    $0xffffffff,%eax
L71:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L74:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    0x18(%rsp),%rax
  jne    L0
  mov    %r14d,%eax
  jmp    L71
L5:
  xor    %eax,%eax
  jmp    L71
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8: %lf

assistant: ```c
int read_set(FILE *input, int setlen, int nobj, double ***pset) {
  size_t i, j, ctr;
  (*pset) = new_matrix_double(setlen, nobj);
  ctr = 0;
  for (i = 0; i < setlen; i++) {
    for (j = 0; j < nobj; j++) {
      if (fscanf(input, "%lf", &(*pset)[i][j]))
        ctr++;
      else
        return -1;
    }
  }
  return ctr;
}
```