user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D83(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  movss  0x1c(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  comiss %xmm3,%xmm0
  jbe    L41
  lea    0x20(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D85(%rip),%r13
  lea    D86(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L50:
  add    $0x1,%ebx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  movss  0x1c(%rsp),%xmm1
  add    $0x4,%rbp
  cvtsi2ss %ebx,%xmm0
  comiss %xmm0,%xmm1
  ja     L50
L41:
  xor    %eax,%eax
  mov    $0x78,%esi
  mov    $0x1,%ebx
  lea    D17(%rip),%rdi
  lea    0x20(%rsp),%rbp
  call   <printf@plt>
  movss  0x1c(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm0,%xmm1
  jbe    L10
  nopl   0x0(%rax,%rax,1)
L2:
  mov    -0x4(%rbp,%rbx,4),%edi
  mov    $0xffffffffffffffff,%rsi
  movss  %xmm0,(%rsp)
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  movss  (%rsp),%xmm0
  mov    %ebx,%esi
  cvtsi2ss %rax,%xmm1
  movss  0x1c(%rsp),%xmm2
  add    $0x1,%rbx
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  comiss %xmm1,%xmm2
  ja     L2
L23:
  movss  D12(%rip),%xmm1
  lea    D0(%rip),%rdi
  mov    $0x1,%eax
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  lea    D39(%rip),%rdi
  mulss  D6(%rip),%xmm1
  mov    $0x2,%eax
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  xor    %esi,%esi
  jmp    L23
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D83
type_infered: string
name: disassemble_data
arguments: data_label: D40
type_infered: string
name: disassemble_data
arguments: data_label: D85
type_infered: string
name: disassemble_data
arguments: data_label: D86
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string
name: disassemble_data
arguments: data_label: D12
type_infered: byte[4]
name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D39
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: f32

tool: D83: Kac tane musluk olacak: 

tool: D40: %f

tool: D85: %d. musluk kac saatte doldurur: 

tool: D86: %d

tool: D17: %lu

tool: {"D12": [0x00,0x00,0x80,0x3f]}

tool: D0: 
%d musluk %.3f saatte doldurur


tool: D39: %.3f saat = %.3f dakika


tool: D6: 60

assistant: ```c
int main() {
  float musluk, total, size;
  int i, adet[30];
  printf("Kac tane musluk olacak: ");
  scanf("%f", &size);
  for (i = 0; i < size; i++) {
    printf("%d. musluk kac saatte doldurur: ", i + 1);
    scanf("%d", &adet[i]);
  }
  printf("%lu", sizeof(adet));
  musluk = 0;
  for (i = 0; i < size; i++) {
    musluk += pow(adet[i], 0 - 1);
  }
  total = 1 / musluk;
  printf("\n%d musluk %.3f saatte doldurur\n", i, total);
  float dk = 60 * total;
  printf("%.3f saat = %.3f dakika\n", total, dk);
}
```