ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printheader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x4c(%rbp)
  je     L44
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x76c(%rax),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D16(%rip),%rdx
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  lea    0x76c(%rax),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L9
L44:
  mov    -0x48(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D22(%rip),%rdx
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    %rax,-0x38(%rbp)
L9:
  movq   $0x0,-0x40(%rbp)
  jmp    L49
L41:
  lea    -0x2a(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addq   $0x1,-0x40(%rbp)
L49:
  mov    $0x15,%eax
  sub    -0x38(%rbp),%rax
  shr    %rax
  cmp    %rax,-0x40(%rbp)
  jb     L41
  lea    -0x2a(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  lea    -0x20(%rbp),%rdx
  lea    -0x2a(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D22
data_type: string
name: extract_symbolic_data
arguments: label: D23
data_type: string

tool: D16: %B %Y

tool: D22: %B

tool: D23: %s%s


assistant: ```c
void printheader(struct tm *time, bool printyear) {
  char buffer[22], spaces[10];
  size_t i, output;
  if (printyear) {
    time->tm_year -= 1900;
    output = strftime(buffer, 80, "%B %Y", time);
    time->tm_year += 1900;
  } else
    output = strftime(buffer, 80, "%B", time);
  for (i = 0; i < (21 - output) / 2; i++)
    spaces[i] = ' ';
  spaces[i] = 0;
  printf("%s%s\n", spaces, buffer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printheader>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L28
  subl   $0x76c,(%rdi)
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rcx
  lea    D27(%rip),%rdx
  mov    $0x50,%esi
  call   <strftime@plt>
  addl   $0x76c,(%rbx)
L19:
  mov    $0x15,%ecx
  sub    %rax,%rcx
  mov    %rcx,%rdx
  shr    %rdx
  cmp    $0x1,%rcx
  jbe    L24
  mov    $0x0,%eax
L50:
  movb   $0x20,0x6(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jb     L50
  cmp    $0x1,%rcx
  mov    $0x1,%eax
  cmovbe %rax,%rdx
L39:
  movb   $0x0,0x6(%rsp,%rdx,1)
  lea    0x10(%rsp),%rdx
  lea    0x6(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x30,%rsp
  pop    %rbx
  ret
L28:
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rcx
  lea    D26(%rip),%rdx
  mov    $0x50,%esi
  call   <strftime@plt>
  jmp    L19
L24:
  mov    $0x0,%edx
  jmp    L39
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D0
type_infered: string
name: unpack_data
arguments: tag: D26
type_infered: string

tool: D27: %B %Y

tool: D0: %s%s


tool: D26: %B

assistant: ```c
void printheader(struct tm *time, bool printyear) {
  char buffer[22], spaces[10];
  size_t i, output;
  if (printyear) {
    time->tm_year -= 1900;
    output = strftime(buffer, 80, "%B %Y", time);
    time->tm_year += 1900;
  } else
    output = strftime(buffer, 80, "%B", time);
  for (i = 0; i < (21 - output) / 2; i++)
    spaces[i] = ' ';
  spaces[i] = 0;
  printf("%s%s\n", spaces, buffer);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printheader>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L24
  subl   $0x76c,(%rdi)
  lea    0x10(%rsp),%r13
  mov    %rdi,%rcx
  mov    $0x50,%esi
  lea    D18(%rip),%rdx
  mov    %r13,%rdi
  call   <strftime@plt>
  addl   $0x76c,(%r12)
L17:
  mov    $0x15,%edx
  lea    0x6(%rsp),%r8
  sub    %rax,%rdx
  mov    %rdx,%rbx
  shr    %rbx
  je     L18
  mov    %r8,%rdi
  mov    %rbx,%rdx
  mov    $0x20,%esi
  call   <memset@plt>
  mov    %rax,%r8
L18:
  mov    %r13,%rdx
  mov    %r8,%rsi
  movb   $0x0,0x6(%rsp,%rbx,1)
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  lea    0x10(%rsp),%r13
  mov    %rdi,%rcx
  mov    $0x50,%esi
  lea    D22(%rip),%rdx
  mov    %r13,%rdi
  call   <strftime@plt>
  jmp    L17
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D22
type: string

tool: D18: %B %Y

tool: D15: %s%s


tool: D22: %B

assistant: ```c
void printheader(struct tm *time, bool printyear) {
  char buffer[22], spaces[10];
  size_t i, output;
  if (printyear) {
    time->tm_year -= 1900;
    output = strftime(buffer, 80, "%B %Y", time);
    time->tm_year += 1900;
  } else
    output = strftime(buffer, 80, "%B", time);
  for (i = 0; i < (21 - output) / 2; i++)
    spaces[i] = ' ';
  spaces[i] = 0;
  printf("%s%s\n", spaces, buffer);
}
```
user: What is the c source code of the assembly code below:

```asm
<printheader>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L21
  subl   $0x76c,(%rdi)
  lea    0x10(%rsp),%r13
  mov    %rdi,%rcx
  mov    $0x50,%esi
  lea    D26(%rip),%rdx
  mov    %r13,%rdi
  call   <strftime@plt>
  addl   $0x76c,(%r12)
L28:
  mov    $0x15,%edx
  lea    0x6(%rsp),%r8
  sub    %rax,%rdx
  mov    %rdx,%rbx
  shr    %rbx
  je     L39
  mov    %r8,%rdi
  mov    %rbx,%rdx
  mov    $0x20,%esi
  call   <memset@plt>
  mov    %rax,%r8
L39:
  mov    %r13,%rdx
  mov    %r8,%rsi
  movb   $0x0,0x6(%rsp,%rbx,1)
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  lea    0x10(%rsp),%r13
  mov    %rdi,%rcx
  mov    $0x50,%esi
  lea    D0(%rip),%rdx
  mov    %r13,%rdi
  call   <strftime@plt>
  jmp    L28
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type_infered: string
name: unpack_data
arguments: data_tag: D22
type_infered: string
name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D26: %B %Y

tool: D22: %s%s


tool: D0: %B

assistant: ```c
void printheader(struct tm *time, bool printyear) {
  char buffer[22], spaces[10];
  size_t i, output;
  if (printyear) {
    time->tm_year -= 1900;
    output = strftime(buffer, 80, "%B %Y", time);
    time->tm_year += 1900;
  } else
    output = strftime(buffer, 80, "%B", time);
  for (i = 0; i < (21 - output) / 2; i++)
    spaces[i] = ' ';
  spaces[i] = 0;
  printf("%s%s\n", spaces, buffer);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitreverse32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    %eax
  and    $0x55555555,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  and    $0xaaaaaaaa,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  and    $0xcccccccc,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  and    $0xf0f0f0f0,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t bitreverse32(uint32_t x) {
  x = ((x >> 1) & 0x55555555) | ((x & 0x55555555) << 1);
  x = ((x >> 2) & 0x33333333) | ((x & 0x33333333) << 2);
  x = ((x >> 4) & 0x0f0f0f0f) | ((x & 0x0f0f0f0f) << 4);
  x = ((x >> 8) & 0x00ff00ff) | ((x & 0x00ff00ff) << 8);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitreverse32>:
  endbr64
  mov    %edi,%eax
  sar    %edi
  and    $0x55555555,%edi
  add    %eax,%eax
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edx
  and    $0x33333333,%edx
  shl    $0x2,%edi
  and    $0xcccccccc,%edi
  or     %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  and    $0xf0f0f0f,%eax
  shl    $0x4,%edx
  and    $0xf0f0f0f0,%edx
  or     %edx,%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  and    $0xff00ff,%edx
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  or     %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t bitreverse32(uint32_t x) {
  x = ((x >> 1) & 0x55555555) | ((x & 0x55555555) << 1);
  x = ((x >> 2) & 0x33333333) | ((x & 0x33333333) << 2);
  x = ((x >> 4) & 0x0f0f0f0f) | ((x & 0x0f0f0f0f) << 4);
  x = ((x >> 8) & 0x00ff00ff) | ((x & 0x00ff00ff) << 8);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitreverse32>:
  endbr64
  mov    %edi,%eax
  sar    %edi
  add    %eax,%eax
  and    $0x55555555,%edi
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%edx
  shl    $0x2,%edi
  sar    $0x2,%edx
  and    $0xcccccccc,%edi
  and    $0x33333333,%edx
  or     %edi,%edx
  mov    %edx,%eax
  shl    $0x4,%edx
  sar    $0x4,%eax
  and    $0xf0f0f0f0,%edx
  and    $0xf0f0f0f,%eax
  or     %edx,%eax
  mov    %eax,%edx
  shl    $0x8,%eax
  sar    $0x8,%edx
  and    $0xff00ff00,%eax
  and    $0xff00ff,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x10,%edx
  sar    $0x10,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t bitreverse32(uint32_t x) {
  x = ((x >> 1) & 0x55555555) | ((x & 0x55555555) << 1);
  x = ((x >> 2) & 0x33333333) | ((x & 0x33333333) << 2);
  x = ((x >> 4) & 0x0f0f0f0f) | ((x & 0x0f0f0f0f) << 4);
  x = ((x >> 8) & 0x00ff00ff) | ((x & 0x00ff00ff) << 8);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bitreverse32>:
  endbr64
  mov    %edi,%eax
  sar    %edi
  add    %eax,%eax
  and    $0x55555555,%edi
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%edx
  shl    $0x2,%edi
  sar    $0x2,%edx
  and    $0xcccccccc,%edi
  and    $0x33333333,%edx
  or     %edi,%edx
  mov    %edx,%eax
  shl    $0x4,%edx
  sar    $0x4,%eax
  and    $0xf0f0f0f0,%edx
  and    $0xf0f0f0f,%eax
  or     %edx,%eax
  mov    %eax,%edx
  shl    $0x8,%eax
  sar    $0x8,%edx
  and    $0xff00ff00,%eax
  and    $0xff00ff,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shl    $0x10,%edx
  sar    $0x10,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t bitreverse32(uint32_t x) {
  x = ((x >> 1) & 0x55555555) | ((x & 0x55555555) << 1);
  x = ((x >> 2) & 0x33333333) | ((x & 0x33333333) << 2);
  x = ((x >> 4) & 0x0f0f0f0f) | ((x & 0x0f0f0f0f) << 4);
  x = ((x >> 8) & 0x00ff00ff) | ((x & 0x00ff00ff) << 8);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<aux_hasing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xf8000000,%eax
  mov    %eax,-0x4(%rbp)
  shll   $0x5,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x1b,%eax
  xor    %eax,-0x14(%rbp)
  movsbl -0x18(%rbp),%eax
  xor    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int aux_hasing(unsigned int h, char k) {
  int hightorder = h & 0xf8000000;
  h = h << 5;
  h = h ^ (hightorder >> 27);
  h = h ^ k;
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aux_hasing>:
  endbr64
  mov    %edi,%eax
  sar    $0x1b,%eax
  shl    $0x5,%edi
  movsbl %sil,%esi
  xor    %esi,%edi
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned int aux_hasing(unsigned int h, char k) {
  int hightorder = h & 0xf8000000;
  h = h << 5;
  h = h ^ (hightorder >> 27);
  h = h ^ k;
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aux_hasing>:
  endbr64
  mov    %edi,%eax
  movsbl %sil,%esi
  shl    $0x5,%edi
  sar    $0x1b,%eax
  xor    %esi,%edi
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned int aux_hasing(unsigned int h, char k) {
  int hightorder = h & 0xf8000000;
  h = h << 5;
  h = h ^ (hightorder >> 27);
  h = h ^ k;
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<aux_hasing>:
  endbr64
  mov    %edi,%eax
  movsbl %sil,%esi
  shl    $0x5,%edi
  sar    $0x1b,%eax
  xor    %esi,%edi
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned int aux_hasing(unsigned int h, char k) {
  int hightorder = h & 0xf8000000;
  h = h << 5;
  h = h ^ (hightorder >> 27);
  h = h ^ k;
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  mov    $0x1,%edi
  call   <sleep@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: console ..


assistant: ```c
int main(void) {
  while (1) {
    sleep(1);
    printf("console ..\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
L0:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: console ..


assistant: ```c
int main(void) {
  while (1) {
    sleep(1);
    printf("console ..\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  nopl   0x0(%rax)
L0:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: console ..


assistant: ```c
int main(void) {
  while (1) {
    sleep(1);
    printf("console ..\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  nopl   0x0(%rax)
L6:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: console ..


assistant: ```c
int main(void) {
  while (1) {
    sleep(1);
    printf("console ..\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_164_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  notb   -0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_164_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_164_0_0>:
  endbr64
  or     %edx,%esi
  not    %esi
  or     (%rdi),%sil
  xor    %edx,%esi
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_164_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_164_0_0>:
  endbr64
  or     %edx,%esi
  not    %esi
  or     (%rdi),%sil
  xor    %edx,%esi
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_164_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rop3_164_0_0>:
  endbr64
  or     %edx,%esi
  not    %esi
  or     (%rdi),%sil
  xor    %edx,%esi
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_164_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: What is the c source code of the assembly code below?

```asm
<convex_hull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L25:
  cmp    %rdx,%rsp
  je     L17
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L25
L17:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L5
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L5:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L32
L18:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x38(%rbp)
L32:
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L18
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x245,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int convex_hull(int nc_pts, char *pts) {
  int fail, i;
  int points[nc_pts];
  double *c;
  for (i = 0; i < nc_pts; i++)
    points[i] = (int)pts[i];
  fail = _ada_use_c2phc(581, &nc_pts, points, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<convex_hull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%ecx
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L58:
  cmp    %rdx,%rsp
  je     L7
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L58
L7:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L10
  orq    $0x0,-0x8(%rsp,%rax,1)
L10:
  mov    %rsp,%rdi
  test   %ecx,%ecx
  jle    L15
  mov    %ecx,%ecx
  mov    $0x0,%eax
L43:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L43
L15:
  lea    -0x14(%rbp),%rsi
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x245,%edi
  call   <_ada_use_c2phc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  leave
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int convex_hull(int nc_pts, char *pts) {
  int fail, i;
  int points[nc_pts];
  double *c;
  for (i = 0; i < nc_pts; i++)
    points[i] = (int)pts[i];
  fail = _ada_use_c2phc(581, &nc_pts, points, c);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<convex_hull>:
  endbr64
  push   %rbp
  movslq %edi,%rcx
  mov    %rcx,%rdx
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsp,%r8
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rcx,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rdi
  cmp    %r8,%rsp
  je     L49
L52:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L52
L49:
  and    $0xfff,%edi
  sub    %rdi,%rsp
  test   %rdi,%rdi
  jne    L40
L21:
  mov    %rsp,%r8
  test   %edx,%edx
  jle    L43
  xor    %eax,%eax
L60:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L60
L43:
  xor    %ecx,%ecx
  mov    %r8,%rdx
  lea    -0x14(%rbp),%rsi
  mov    $0x245,%edi
  call   <_ada_use_c2phc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  leave
  ret
  nopl   (%rax)
L40:
  orq    $0x0,-0x8(%rsp,%rdi,1)
  jmp    L21
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int convex_hull(int nc_pts, char *pts) {
  int fail, i;
  int points[nc_pts];
  double *c;
  for (i = 0; i < nc_pts; i++)
    points[i] = (int)pts[i];
  fail = _ada_use_c2phc(581, &nc_pts, points, c);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_hexa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x10(%rbp)
  jmp    L12
L16:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L16
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D3: %s

tool: D5: %02hhx

assistant: ```c
void print_hexa(const char *prepend, const void *buffer, size_t len) {
  const uint8_t *buff = buffer;
  printf("%s", prepend);
  for (size_t i = 0; i < len; i++) {
    printf("%02hhx", buff[i]);
  }
  printf("\n");
}
```