ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D7(%rip),%r15
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L2:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L0:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L0
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L2
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string
name: read_data
arguments: tag: D29
datatype: string
name: read_data
arguments: tag: D10
datatype: string

tool: D7: dswap

tool: D29: # c::%s:len=%d


tool: D10: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dswap", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D6(%rip),%r15
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L9:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L9
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L8
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string

tool: D6: dswap

tool: D11: # c::%s:len=%d


tool: D17: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dswap", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_fixed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L18
L13:
  mov    -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <read_byte@plt>
  or     %ebx,%eax
  mov    %eax,-0x18(%rbp)
  subl   $0x1,-0x14(%rbp)
L18:
  cmpl   $0x0,-0x14(%rbp)
  jg     L13
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint64_t read_fixed(int bytes) {
  uint64_t value = 0;
  int i;
  for (i = bytes; i > 0; --i)
    value = (value << 8) | read_byte();
  return value;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_fixed>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L20
  mov    %edi,%ebp
  mov    $0x0,%ebx
L26:
  shl    $0x8,%ebx
  mov    $0x0,%eax
  call   <read_byte@plt>
  or     %eax,%ebx
  sub    $0x1,%ebp
  jne    L26
L22:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x0,%ebx
  jmp    L22
```

assistant: ```c
uint64_t read_fixed(int bytes) {
  uint64_t value = 0;
  int i;
  for (i = bytes; i > 0; --i)
    value = (value << 8) | read_byte();
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_fixed>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L1
  mov    %edi,%ebp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  shl    $0x8,%ebx
  call   <read_byte@plt>
  or     %eax,%ebx
  sub    $0x1,%ebp
  jne    L11
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %ebx,%ebx
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t read_fixed(int bytes) {
  uint64_t value = 0;
  int i;
  for (i = bytes; i > 0; --i)
    value = (value << 8) | read_byte();
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_fixed>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L1
  mov    %edi,%ebp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  shl    $0x8,%ebx
  call   <read_byte@plt>
  or     %eax,%ebx
  sub    $0x1,%ebp
  jne    L10
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %ebx,%ebx
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t read_fixed(int bytes) {
  uint64_t value = 0;
  int i;
  for (i = bytes; i > 0; --i)
    value = (value << 8) | read_byte();
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compareFloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L20
  mov    $0xffffffff,%eax
  jmp    L11
L20:
  movss  -0x8(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L27
  mov    $0x1,%eax
  jmp    L11
L27:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
signed char compareFloat(void *t1, void *t2) {
  float _t1 = *(float *)t1;
  float _t2 = *(float *)t2;
  if (_t1 < _t2)
    return -1;
  else if (_t1 > _t2)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compareFloat>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L2
  comiss %xmm0,%xmm1
  seta   %al
L2:
  ret
```

assistant: ```c
signed char compareFloat(void *t1, void *t2) {
  float _t1 = *(float *)t1;
  float _t2 = *(float *)t2;
  if (_t1 < _t2)
    return -1;
  else if (_t1 > _t2)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compareFloat>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L5
  comiss %xmm0,%xmm1
  seta   %al
L5:
  ret
```

assistant: ```c
signed char compareFloat(void *t1, void *t2) {
  float _t1 = *(float *)t1;
  float _t2 = *(float *)t2;
  if (_t1 < _t2)
    return -1;
  else if (_t1 > _t2)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compareFloat>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L6
  comiss %xmm0,%xmm1
  seta   %al
L6:
  ret
```

assistant: ```c
signed char compareFloat(void *t1, void *t2) {
  float _t1 = *(float *)t1;
  float _t2 = *(float *)t2;
  if (_t1 < _t2)
    return -1;
  else if (_t1 > _t2)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_stat_ctime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_stat_ctime_ns@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct timespec get_stat_ctime(struct stat const *st) {
  struct timespec t;
  t.tv_sec = st->st_ctime;
  t.tv_nsec = get_stat_ctime_ns(st);
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_stat_ctime>:
  endbr64
  push   %rbx
  mov    (%rdi),%ebx
  call   <get_stat_ctime_ns@plt>
  shl    $0x20,%rbx
  mov    %eax,%eax
  or     %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
struct timespec get_stat_ctime(struct stat const *st) {
  struct timespec t;
  t.tv_sec = st->st_ctime;
  t.tv_nsec = get_stat_ctime_ns(st);
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_stat_ctime>:
  endbr64
  push   %rbx
  mov    (%rdi),%ebx
  shl    $0x20,%rbx
  call   <get_stat_ctime_ns@plt>
  mov    %eax,%eax
  or     %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
struct timespec get_stat_ctime(struct stat const *st) {
  struct timespec t;
  t.tv_sec = st->st_ctime;
  t.tv_nsec = get_stat_ctime_ns(st);
  return t;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_stat_ctime>:
  endbr64
  push   %rbx
  mov    (%rdi),%ebx
  call   <get_stat_ctime_ns@plt>
  movd   %ebx,%xmm1
  pop    %rbx
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,%rax
  ret
```

assistant: ```c
struct timespec get_stat_ctime(struct stat const *st) {
  struct timespec t;
  t.tv_sec = st->st_ctime;
  t.tv_nsec = get_stat_ctime_ns(st);
  return t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x41eb,-0x4(%rbp)
  jmp    L2
L28:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L1
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bar@plt>
L1:
  sarl   -0x4(%rbp)
L2:
  cmpl   $0x0,-0x4(%rbp)
  jne    L28
  nop
  nop
  leave
  ret
```

assistant: ```c
void foo(void) {
  int n = 16875;
  while (n) {
    if (n & 1)
      bar(n);
    n >>= 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xf,%ebp
  mov    $0x41eb,%ebx
  jmp    L12
L17:
  sar    %ebx
  sub    $0x1,%ebp
  je     L26
L12:
  test   $0x1,%bl
  je     L17
  mov    %ebx,%edi
  call   <bar@plt>
  jmp    L17
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void foo(void) {
  int n = 16875;
  while (n) {
    if (n & 1)
      bar(n);
    n >>= 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    $0xf,%ebp
  push   %rbx
  mov    $0x41eb,%ebx
  sub    $0x8,%rsp
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L13:
  sar    %ebx
  sub    $0x1,%ebp
  je     L0
L7:
  test   $0x1,%bl
  je     L13
  mov    %ebx,%edi
  sar    %ebx
  call   <bar@plt>
  sub    $0x1,%ebp
  jne    L7
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void foo(void) {
  int n = 16875;
  while (n) {
    if (n & 1)
      bar(n);
    n >>= 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41eb,%edi
  call   <bar@plt>
  mov    $0x20f5,%edi
  call   <bar@plt>
  mov    $0x83d,%edi
  call   <bar@plt>
  mov    $0x20f,%edi
  call   <bar@plt>
  mov    $0x107,%edi
  call   <bar@plt>
  mov    $0x83,%edi
  call   <bar@plt>
  mov    $0x41,%edi
  call   <bar@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <bar@plt>
```

assistant: ```c
void foo(void) {
  int n = 16875;
  while (n) {
    if (n & 1)
      bar(n);
    n >>= 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<display_binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1000,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L27:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L24
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L39
L24:
  mov    $0x30,%edi
  call   <putchar@plt>
L39:
  sarl   -0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0xc,-0x8(%rbp)
  jle    L27
  nop
  nop
  leave
  ret
```

assistant: ```c
void display_binary(int x) {
  int c, v = 0x1000;
  for (c = 0; c < 13; c++) {
    if (x & v)
      putchar('1');
    else
      putchar('0');
    v >>= 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<display_binary>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0xd,%ebp
  mov    $0x1000,%ebx
  jmp    L2
L14:
  mov    $0x30,%edi
  call   <putchar@plt>
L20:
  sar    %ebx
  sub    $0x1,%ebp
  je     L33
L2:
  test   %ebx,%r12d
  je     L14
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L20
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void display_binary(int x) {
  int c, v = 0x1000;
  for (c = 0; c < 13; c++) {
    if (x & v)
      putchar('1');
    else
      putchar('0');
    v >>= 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<display_binary>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0xd,%ebp
  push   %rbx
  mov    $0x1000,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x31,%edi
  sar    %ebx
  call   <putchar@plt>
  sub    $0x1,%ebp
  je     L30
L16:
  test   %ebx,%r12d
  jne    L6
  mov    $0x30,%edi
  sar    %ebx
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L16
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void display_binary(int x) {
  int c, v = 0x1000;
  for (c = 0; c < 13; c++) {
    if (x & v)
      putchar('1');
    else
      putchar('0');
    v >>= 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<display_binary>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0xd,%ebp
  push   %rbx
  mov    $0x1000,%ebx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L22:
  mov    $0x31,%edi
  sar    %ebx
  call   <putchar@plt>
  sub    $0x1,%ebp
  je     L23
L35:
  test   %ebx,%r12d
  jne    L22
  mov    $0x30,%edi
  sar    %ebx
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L35
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void display_binary(int x) {
  int c, v = 0x1000;
  for (c = 0; c < 13; c++) {
    if (x & v)
      putchar('1');
    else
      putchar('0');
    v >>= 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<plainstring_add_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  movsd  %xmm0,-0x120(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x120(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <cstr_loaddouble@plt>
  lea    -0x110(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <plainstring_add@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void plainstring_add_double(struct plainstring *this_string, double d) {
  char buffer[0xFF];
  cstr_loaddouble(buffer, d);
  plainstring_add(this_string, buffer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<plainstring_add_double>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <cstr_loaddouble@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <plainstring_add@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void plainstring_add_double(struct plainstring *this_string, double d) {
  char buffer[0xFF];
  cstr_loaddouble(buffer, d);
  plainstring_add(this_string, buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<plainstring_add_double>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <cstr_loaddouble@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <plainstring_add@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void plainstring_add_double(struct plainstring *this_string, double d) {
  char buffer[0xFF];
  cstr_loaddouble(buffer, d);
  plainstring_add(this_string, buffer);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<plainstring_add_double>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <cstr_loaddouble@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <plainstring_add@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void plainstring_add_double(struct plainstring *this_string, double d) {
  char buffer[0xFF];
  cstr_loaddouble(buffer, d);
  plainstring_add(this_string, buffer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x762,-0x4(%rbp)
  jmp    L72
L62:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L5
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L14
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L60
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L60:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  addl   $0x1,-0x4(%rbp)
L72:
  cmpl   $0x776,-0x4(%rbp)
  jle    L62
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D3: %4d is a leap year


tool: D1: %4d is not a leap year.


assistant: ```c
int main() {
  int x;
  for (x = 1890; x <= 1910; ++x) {
    if (x % 4 == 0) {
      if (x % 100 == 0) {
        if (x % 400 == 0)
          printf("%4d is a leap year\n", x);
        else
          printf("%4d is not a leap year.\n", x);
      } else
        printf("%4d is a leap year\n", x);
    } else
      printf("%4d is not a leap year.\n", x);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x762,%ebx
  lea    D7(%rip),%rbp
  lea    D10(%rip),%r12
  jmp    L50
L19:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L68
L48:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L68
L28:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L68:
  add    $0x1,%ebx
  cmp    $0x777,%ebx
  je     L59
L50:
  test   $0x3,%bl
  jne    L28
  movslq %ebx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x64,%eax,%eax
  cmp    %eax,%ebx
  jne    L48
  movslq %ebx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%ebx
  jne    L19
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L68
L59:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D10
data_type: string

tool: D7: %4d is not a leap year.


tool: D10: %4d is a leap year


assistant: ```c
int main() {
  int x;
  for (x = 1890; x <= 1910; ++x) {
    if (x % 4 == 0) {
      if (x % 100 == 0) {
        if (x % 400 == 0)
          printf("%4d is a leap year\n", x);
        else
          printf("%4d is not a leap year.\n", x);
      } else
        printf("%4d is a leap year\n", x);
    } else
      printf("%4d is not a leap year.\n", x);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  mov    $0x762,%ebx
  jmp    L66
  nopl   (%rax)
L22:
  imul   $0xc28f5c29,%ebx,%eax
  mov    %eax,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L57
  ror    $0x4,%eax
  mov    %ebx,%esi
  cmp    $0xa3d70a,%eax
  ja     L26
L37:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x777,%ebx
  je     L25
L66:
  test   $0x3,%bl
  je     L22
  mov    %ebx,%esi
L26:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x777,%ebx
  jne    L66
L25:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %ebx,%esi
  jmp    L37
```

tool_calls: name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D18
type: string

tool: D17: %4d is a leap year


tool: D18: %4d is not a leap year.


assistant: ```c
int main() {
  int x;
  for (x = 1890; x <= 1910; ++x) {
    if (x % 4 == 0) {
      if (x % 100 == 0) {
        if (x % 400 == 0)
          printf("%4d is a leap year\n", x);
        else
          printf("%4d is not a leap year.\n", x);
      } else
        printf("%4d is a leap year\n", x);
    } else
      printf("%4d is not a leap year.\n", x);
  }
  return 0;
}
```