user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  test   %esi,%esi
  jle    L44
  lea    D23(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    %esi,%ebp
  xor    %r15d,%r15d
  mov    %rax,0x10(%rsp)
  cmp    $0xf,%esi
  jle    L134
  lea    0x4(%rdi),%rax
  lea    D16(%rip),%r13
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L155:
  mov    0x10(%rsp),%rdi
  mov    %r15d,%esi
  xor    %eax,%eax
  add    $0x10,%r15d
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  mov    0x8(%rsp),%rdx
  mov    0x18(%rsp),%rcx
  lea    (%rdx,%rax,4),%rbx
  lea    0x3c(%rcx,%rax,4),%r12
  mov    %rbx,%r14
  cs nopw 0x0(%rax,%rax,1)
L91:
  mov    (%r14),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %r12,%r14
  jne    L91
  cs nopw 0x0(%rax,%rax,1)
L152:
  mov    (%rbx),%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L78
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %r12,%rbx
  jne    L152
L135:
  mov    $0xa,%edi
  sub    $0x10,%ebp
  call   <putchar@plt>
  addl   $0x10,0x4(%rsp)
  cmp    $0xf,%ebp
  jg     L155
  test   %ebp,%ebp
  je     L44
L50:
  mov    0x10(%rsp),%rdi
  mov    %r15d,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%r14
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  lea    (%rax,%r14,4),%rbx
  lea    -0x1(%rbp),%eax
  add    %r14,%rax
  mov    %rbx,%r12
  lea    (%rdx,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L113:
  mov    (%r12),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %r14,%r12
  jne    L113
  lea    D0(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    $0x10,%ebp
  jne    L4
  nopw   0x0(%rax,%rax,1)
L158:
  mov    (%rbx),%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L45
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %rbx,%r14
  jne    L158
L101:
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <putchar@plt>
  nopl   0x0(%rax)
L45:
  mov    $0x2e,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %r14,%rbx
  jne    L158
  jmp    L101
  nopl   (%rax)
L78:
  mov    $0x2e,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %r12,%rbx
  jne    L152
  jmp    L135
  nopl   0x0(%rax)
L134:
  mov    0x8(%rsp),%rax
  lea    D16(%rip),%r13
  add    $0x4,%rax
  mov    %rax,0x18(%rsp)
  jmp    L50
L44:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: string
name: disassemble_data
arguments: label: D0
type_infered: string

tool: D23: %06X  

tool: D16: %2.02X 

tool: D0:    

assistant: ```c
void print_data(const uint8_t *data, int length) {
  int i, x, j, c;
  int w = 0;
  for (i = 0; length > 0; length -= 16) {
    c = length >= 16 ? 16 : length;
    printf("%06X  ", w);
    w += 16;
    for (j = 0; j < c; j++)
      printf("%2.02X ", data[i + j]);
    for (x = length; x < 16; x++)
      printf("   ");
    for (j = 0; j < c; j++)
      printf("%c", (isprint(data[i + j]) ? data[i + j] : '.'));
    printf("\n");
    i += c;
  }
}
```