ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_233_0_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  not    %edi
  and    %edi,%eax
  xor    %edx,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_233_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = D & S;
  stk4 = ~stk4;
  stk3 = T & stk4;
  stk2 = S ^ stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_233_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%edx
  mov    %esi,%eax
  shl    $0x8,%edx
  shl    $0x8,%eax
  or     %edi,%edx
  or     %esi,%eax
  not    %edi
  and    %edi,%eax
  xor    %edx,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_233_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = D & S;
  stk4 = ~stk4;
  stk3 = T & stk4;
  stk2 = S ^ stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_233_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%edx
  mov    %esi,%eax
  shl    $0x8,%edx
  shl    $0x8,%eax
  or     %edi,%edx
  or     %esi,%eax
  not    %edi
  and    %edi,%eax
  xor    %edx,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_233_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = D & S;
  stk4 = ~stk4;
  stk3 = T & stk4;
  stk2 = S ^ stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Operand_soffsetx4_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x3ffff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0xe,%eax
  sar    $0xe,%eax
  shl    $0x2,%eax
  add    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_soffsetx4_decode(unsigned int *valp) {
  unsigned soffsetx4_0, offset_0;
  offset_0 = *valp & 0x3ffff;
  soffsetx4_0 = 0x4 + ((((int)offset_0 << 14) >> 14) << 2);
  *valp = soffsetx4_0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Operand_soffsetx4_decode>:
  endbr64
  mov    (%rdi),%eax
  shl    $0xe,%eax
  sar    $0xc,%eax
  add    $0x4,%eax
  mov    %eax,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Operand_soffsetx4_decode(unsigned int *valp) {
  unsigned soffsetx4_0, offset_0;
  offset_0 = *valp & 0x3ffff;
  soffsetx4_0 = 0x4 + ((((int)offset_0 << 14) >> 14) << 2);
  *valp = soffsetx4_0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Operand_soffsetx4_decode>:
  endbr64
  mov    (%rdi),%eax
  shl    $0xe,%eax
  sar    $0xc,%eax
  add    $0x4,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_soffsetx4_decode(unsigned int *valp) {
  unsigned soffsetx4_0, offset_0;
  offset_0 = *valp & 0x3ffff;
  soffsetx4_0 = 0x4 + ((((int)offset_0 << 14) >> 14) << 2);
  *valp = soffsetx4_0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Operand_soffsetx4_decode>:
  endbr64
  mov    (%rdi),%eax
  shl    $0xe,%eax
  sar    $0xc,%eax
  add    $0x4,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_soffsetx4_decode(unsigned int *valp) {
  unsigned soffsetx4_0, offset_0;
  offset_0 = *valp & 0x3ffff;
  soffsetx4_0 = 0x4 + ((((int)offset_0 << 14) >> 14) << 2);
  *valp = soffsetx4_0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x38(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D72(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movl   $0x1,-0x34(%rbp)
  jmp    L10
L16:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x34(%rbp),%xmm0
  movsd  D32(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D72(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D34(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x30(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  addl   $0x1,-0x34(%rbp)
L10:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L16
  movsd  -0x30(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  movq   %rax,%xmm0
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D36
data_type: string
name: retrieve_data
arguments: label: D69
data_type: string
name: retrieve_data
arguments: label: D9
data_type: f64
name: retrieve_data
arguments: label: D72
data_type: f64
name: retrieve_data
arguments: label: D32
data_type: f64
name: retrieve_data
arguments: label: D34
data_type: f64
name: retrieve_data
arguments: label: D70
data_type: string

tool: D36: Introduce la precision del calculo (n > 0): 

tool: D69: %i

tool: D9: 3.141592653589793

tool: D72: 1

tool: D32: 0.5

tool: D34: 4

tool: D70: El valor aproximado de PI es: %.8lf , con un error de %.8lf



assistant: ```c
int main(int argc, char *argv[]) {
  int n, i;
  printf("Introduce la precision del calculo (n > 0): ");
  scanf("%i", &n);
  double PI25DT = 3.141592653589793238462643;
  double h = 1.0 / (double)n;
  double sum = 0.0;
#pragma omp parallel for reduction(+ : sum)
  for (i = 1; i <= n; i++) {
    double x = h * ((double)i - 0.5);
    sum += (4.0 / (1.0 + x * x));
  }
  double pi = sum * h;
  printf("El valor aproximado de PI es: %.8lf , con un error de %.8lf\n\n", pi, fabs(pi - PI25DT));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  D70(%rip),%xmm3
  divsd  %xmm0,%xmm3
  test   %edx,%edx
  jle    L16
  add    $0x1,%edx
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movsd  D3(%rip),%xmm6
  movsd  D70(%rip),%xmm5
  movsd  D42(%rip),%xmm4
L19:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  subsd  %xmm6,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm5,%xmm0
  movapd %xmm4,%xmm2
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L19
L33:
  mulsd  %xmm1,%xmm3
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm3,%xmm7
  subsd  D77(%rip),%xmm7
  movapd %xmm7,%xmm0
  call   <fabs@plt>
  mov    %eax,%esi
  movsd  0x8(%rsp),%xmm0
  lea    D18(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L16:
  pxor   %xmm1,%xmm1
  jmp    L33
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D73
type_infered: string
name: read_data
arguments: tag: D30
type_infered: string
name: read_data
arguments: tag: D70
type_infered: f64
name: read_data
arguments: tag: D3
type_infered: f64
name: read_data
arguments: tag: D42
type_infered: f64
name: read_data
arguments: tag: D77
type_infered: f64
name: read_data
arguments: tag: D18
type_infered: string

tool: D73: Introduce la precision del calculo (n > 0): 

tool: D30: %i

tool: D70: 1

tool: D3: 0.5

tool: D42: 4

tool: D77: 3.141592653589793

tool: D18: El valor aproximado de PI es: %.8lf , con un error de %.8lf



assistant: ```c
int main(int argc, char *argv[]) {
  int n, i;
  printf("Introduce la precision del calculo (n > 0): ");
  scanf("%i", &n);
  double PI25DT = 3.141592653589793238462643;
  double h = 1.0 / (double)n;
  double sum = 0.0;
#pragma omp parallel for reduction(+ : sum)
  for (i = 1; i <= n; i++) {
    double x = h * ((double)i - 0.5);
    sum += (4.0 / (1.0 + x * x));
  }
  double pi = sum * h;
  printf("El valor aproximado de PI es: %.8lf , con un error de %.8lf\n\n", pi, fabs(pi - PI25DT));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  pxor   %xmm0,%xmm0
  movsd  D8(%rip),%xmm4
  cvtsi2sd %edx,%xmm0
  movapd %xmm4,%xmm3
  divsd  %xmm0,%xmm3
  test   %edx,%edx
  jle    L16
  movsd  D30(%rip),%xmm6
  add    $0x1,%edx
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movsd  D47(%rip),%xmm5
  nopl   (%rax)
L28:
  pxor   %xmm0,%xmm0
  movapd %xmm5,%xmm2
  cvtsi2sd %eax,%xmm0
  add    $0x1,%eax
  subsd  %xmm6,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm4,%xmm0
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  cmp    %edx,%eax
  jne    L28
L11:
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  subsd  D10(%rip),%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <fabs@plt>
  movsd  0x8(%rsp),%xmm3
  lea    D67(%rip),%rdi
  mov    %eax,%esi
  mov    $0x1,%eax
  movapd %xmm3,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L16:
  pxor   %xmm1,%xmm1
  jmp    L11
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D33
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D8
type_infered: f64
name: unpack_data
arguments: data_label: D30
type_infered: f64
name: unpack_data
arguments: data_label: D47
type_infered: f64
name: unpack_data
arguments: data_label: D10
type_infered: f64
name: unpack_data
arguments: data_label: D67
type_infered: string

tool: D33: Introduce la precision del calculo (n > 0): 

tool: D7: %i

tool: D8: 1

tool: D30: 0.5

tool: D47: 4

tool: D10: 3.141592653589793

tool: D67: El valor aproximado de PI es: %.8lf , con un error de %.8lf



assistant: ```c
int main(int argc, char *argv[]) {
  int n, i;
  printf("Introduce la precision del calculo (n > 0): ");
  scanf("%i", &n);
  double PI25DT = 3.141592653589793238462643;
  double h = 1.0 / (double)n;
  double sum = 0.0;
#pragma omp parallel for reduction(+ : sum)
  for (i = 1; i <= n; i++) {
    double x = h * ((double)i - 0.5);
    sum += (4.0 / (1.0 + x * x));
  }
  double pi = sum * h;
  printf("El valor aproximado de PI es: %.8lf , con un error de %.8lf\n\n", pi, fabs(pi - PI25DT));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D52(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  pxor   %xmm0,%xmm0
  movsd  D34(%rip),%xmm4
  cvtsi2sd %edx,%xmm0
  movapd %xmm4,%xmm3
  divsd  %xmm0,%xmm3
  test   %edx,%edx
  jle    L22
  movsd  D0(%rip),%xmm6
  add    $0x1,%edx
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movsd  D45(%rip),%xmm5
  nopl   (%rax)
L13:
  pxor   %xmm0,%xmm0
  movapd %xmm5,%xmm2
  cvtsi2sd %eax,%xmm0
  add    $0x1,%eax
  subsd  %xmm6,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm4,%xmm0
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  cmp    %edx,%eax
  jne    L13
L15:
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  subsd  D56(%rip),%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <fabs@plt>
  movsd  0x8(%rsp),%xmm3
  lea    D67(%rip),%rdi
  mov    %eax,%esi
  mov    $0x1,%eax
  movapd %xmm3,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L22:
  pxor   %xmm1,%xmm1
  jmp    L15
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D52
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D34
type: f64
name: read_data
arguments: data_tag: D0
type: f64
name: read_data
arguments: data_tag: D45
type: f64
name: read_data
arguments: data_tag: D56
type: f64
name: read_data
arguments: data_tag: D67
type: string

tool: D52: Introduce la precision del calculo (n > 0): 

tool: D25: %i

tool: D34: 1

tool: D0: 0.5

tool: D45: 4

tool: D56: 3.141592653589793

tool: D67: El valor aproximado de PI es: %.8lf , con un error de %.8lf



assistant: ```c
int main(int argc, char *argv[]) {
  int n, i;
  printf("Introduce la precision del calculo (n > 0): ");
  scanf("%i", &n);
  double PI25DT = 3.141592653589793238462643;
  double h = 1.0 / (double)n;
  double sum = 0.0;
#pragma omp parallel for reduction(+ : sum)
  for (i = 1; i <= n; i++) {
    double x = h * ((double)i - 0.5);
    sum += (4.0 / (1.0 + x * x));
  }
  double pi = sum * h;
  printf("El valor aproximado de PI es: %.8lf , con un error de %.8lf\n\n", pi, fabs(pi - PI25DT));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_str_startswith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D59(%rip),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <str_starts_with@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <str_starts_with@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <str_ends_with@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D59
type: string
name: retrieve_data
arguments: data_label: D51
type: string
name: retrieve_data
arguments: data_label: D33
type: string
name: retrieve_data
arguments: data_label: D6
type: string

tool: D59: He

tool: D51: Hello

tool: D33: Ao

tool: 

assistant: ```c
void test_str_startswith() {
  assert(str_starts_with("Hello", "He") == true);
  assert(str_starts_with("Hello", "Ao") == false);
  assert(str_ends_with("Hello", "") == true);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_str_startswith>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rsi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <str_starts_with@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D34(%rip),%rsi
  mov    %rbx,%rdi
  call   <str_starts_with@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <str_ends_with@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
data_type: string
name: read_data
arguments: data_label: D8
data_type: string
name: read_data
arguments: data_label: D34
data_type: string
name: read_data
arguments: data_label: D9
data_type: string

tool: D13: He

tool: D8: Hello

tool: D34: Ao

tool: 

assistant: ```c
void test_str_startswith() {
  assert(str_starts_with("Hello", "He") == true);
  assert(str_starts_with("Hello", "Ao") == false);
  assert(str_ends_with("Hello", "") == true);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_str_startswith>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rbp
  lea    D38(%rip),%rsi
  mov    %rbp,%rdi
  call   <str_starts_with@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  call   <str_starts_with@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  call   <str_ends_with@plt>
  xor    %edi,%edi
  pop    %rbp
  cmp    $0x1,%eax
  sete   %dil
  jmp    1080 <assert@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
data_type: string
name: disassemble_data
arguments: label: D38
data_type: string
name: disassemble_data
arguments: label: D32
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string

tool: D17: Hello

tool: D38: He

tool: D32: Ao

tool: 

assistant: ```c
void test_str_startswith() {
  assert(str_starts_with("Hello", "He") == true);
  assert(str_starts_with("Hello", "Ao") == false);
  assert(str_ends_with("Hello", "") == true);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_str_startswith>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rbp
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <str_starts_with@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <str_starts_with@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  lea    D0(%rip),%rsi
  call   <str_ends_with@plt>
  xor    %edi,%edi
  pop    %rbp
  cmp    $0x1,%eax
  sete   %dil
  jmp    1080 <assert@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D11
type_infered: string
name: extract_symbolic_data
arguments: label: D2
type_infered: string
name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D28: Hello

tool: D11: He

tool: D2: Ao

tool: 

assistant: ```c
void test_str_startswith() {
  assert(str_starts_with("Hello", "He") == true);
  assert(str_starts_with("Hello", "Ao") == false);
  assert(str_ends_with("Hello", "") == true);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L19
L1:
  movl   $0x2,-0x8(%rbp)
  jmp    L57
L29:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L50
  mov    $0x0,%eax
  jmp    L19
L50:
  addl   $0x1,-0x8(%rbp)
L57:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L29
  mov    $0x1,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int check_prime(int num) {
  int j, r;
  if (num == 1)
    return 0;
  for (j = 2; j < num; j++) {
    r = num % j;
    if (r == 0)
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L56
  cmp    $0x2,%edi
  jle    L44
  test   $0x1,%dil
  je     L29
  mov    $0x2,%ecx
L40:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L48
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L40
L56:
  ret
L48:
  mov    $0x1,%eax
  ret
L44:
  mov    $0x1,%eax
  ret
L29:
  mov    $0x0,%eax
  jmp    L56
```

assistant: ```c
int check_prime(int num) {
  int j, r;
  if (num == 1)
    return 0;
  for (j = 2; j < num; j++) {
    r = num % j;
    if (r == 0)
      return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_prime>:
  endbr64
  xor    %edx,%edx
  cmp    $0x1,%edi
  je     L18
  cmp    $0x2,%edi
  jle    L34
  test   $0x1,%dil
  je     L18
  mov    $0x2,%ecx
  jmp    L1
  nopl   (%rax)
L50:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L18
L1:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L50
L34:
  mov    $0x1,%edx
L18:
  mov    %edx,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int j, r;
  if (num == 1)
    return 0;
  for (j = 2; j < num; j++) {
    r = num % j;
    if (r == 0)
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_prime>:
  endbr64
  xor    %edx,%edx
  cmp    $0x1,%edi
  je     L12
  cmp    $0x2,%edi
  jle    L52
  test   $0x1,%dil
  je     L12
  mov    $0x2,%ecx
  jmp    L2
  nopl   (%rax)
L57:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L12
L2:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L57
L52:
  mov    $0x1,%edx
L12:
  mov    %edx,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int j, r;
  if (num == 1)
    return 0;
  for (j = 2; j < num; j++) {
    r = num % j;
    if (r == 0)
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L63
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L9
  jmp    L68
L63:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L67
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L49
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L49:
  addl   $0x1,-0xc(%rbp)
L67:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L8
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sort>
L68:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: string

tool: D7: %d


assistant: ```c
void sort(int array[], int startpoint, int top) {
  int i, k;
  int index1;
  if (startpoint == top - 1) {
    for (k = 0; k < top; k++)
      printf("%d\n", array[k]);
  } else {
    index1 = startpoint;
    for (i = startpoint; i < top; i++)
      if (array[i] < array[index1])
        index1 = i;
    swap(array, startpoint, index1);
    sort(array, startpoint + 1, top);
  }
}
```