ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  lea    D37(%rip),%rsi
  lea    D1(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  lea    D11(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    $0xc8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L19:
  mov    %r12,%rdx
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L19
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D34(%rip),%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  lea    D0(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  lea    D61(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    $0xc8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
L8:
  mov    %r12,%rdx
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L8
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D37
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D29
type_guessed: string
name: retrieve_data
arguments: data_label: D11
type_guessed: string
name: retrieve_data
arguments: data_label: D34
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: string
name: retrieve_data
arguments: data_label: D61
type_guessed: string

tool: D37: w

tool: D1: r

tool: D29: Lyrics.txt

tool: D11: Hey This is inital file..

tool: D34: a

tool: D0: 
here we have a simple line

tool: D61: 
here we have another simple line

assistant: ```c
int main() {
  char *pline;
  FILE *fptr;
  fptr = fopen("Lyrics.txt", "w");
  fprintf(fptr, "Hey This is inital file..");
  fclose(fptr);
  fptr = fopen("Lyrics.txt", "r");
  pline = (char *)malloc(200 * sizeof(char));
  while (1) {
    fgets(pline, 200, fptr);
    puts(pline);
    if (feof(fptr)) {
      break;
    }
  }
  fclose(fptr);
  free(pline);
  fptr = fopen("Lyrics.txt", "a");
  fprintf(fptr, "\nhere we have a simple line");
  fprintf(fptr, "\nhere we have another simple line");
  fclose(fptr);
  fptr = fopen("Lyrics.txt", "r");
  pline = (char *)malloc(200 * sizeof(char));
  while (1) {
    fgets(pline, 200, fptr);
    puts(pline);
    if (feof(fptr)) {
      break;
    }
  }
  fclose(fptr);
  free(pline);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init_interpreter@plt>
  mov    $0x0,%eax
  call   <get_program@plt>
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <print_program@plt>
  mov    $0x0,%eax
  call   <interpreter@plt>
  mov    $0x0,%eax
  call   <exit_interpreter@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  init_interpreter();
  get_program();
  print_program(-1, -1);
  interpreter();
  exit_interpreter();
  return (EXIT_SUCCESS);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_interpreter@plt>
  mov    $0x0,%eax
  call   <get_program@plt>
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <print_program@plt>
  mov    $0x0,%eax
  call   <interpreter@plt>
  mov    $0x0,%eax
  call   <exit_interpreter@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  init_interpreter();
  get_program();
  print_program(-1, -1);
  interpreter();
  exit_interpreter();
  return (EXIT_SUCCESS);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_interpreter@plt>
  xor    %eax,%eax
  call   <get_program@plt>
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <print_program@plt>
  xor    %eax,%eax
  call   <interpreter@plt>
  xor    %eax,%eax
  call   <exit_interpreter@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  init_interpreter();
  get_program();
  print_program(-1, -1);
  interpreter();
  exit_interpreter();
  return (EXIT_SUCCESS);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_interpreter@plt>
  xor    %eax,%eax
  call   <get_program@plt>
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <print_program@plt>
  xor    %eax,%eax
  call   <interpreter@plt>
  xor    %eax,%eax
  call   <exit_interpreter@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  init_interpreter();
  get_program();
  print_program(-1, -1);
  interpreter();
  exit_interpreter();
  return (EXIT_SUCCESS);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<imaddhistf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0xe8,%rsp
  mov    %rdi,-0xf8(%rbp)
  mov    %rsi,-0x100(%rbp)
  mov    %rdx,-0xc0(%rbp)
  mov    %rcx,-0xb8(%rbp)
  mov    %r8,-0xb0(%rbp)
  mov    %r9,-0xa8(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0xa0(%rbp)
  movaps %xmm1,-0x90(%rbp)
  movaps %xmm2,-0x80(%rbp)
  movaps %xmm3,-0x70(%rbp)
  movaps %xmm4,-0x60(%rbp)
  movaps %xmm5,-0x50(%rbp)
  movaps %xmm6,-0x40(%rbp)
  movaps %xmm7,-0x30(%rbp)
L8:
  mov    %fs:0x28,%rax
  mov    %rax,-0xd8(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0xe8(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L16:
  cmp    %rdx,%rsp
  je     L47
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L16
L47:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L43
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L43:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0xe0(%rbp)
  mov    -0x100(%rbp),%rdx
  mov    -0xec(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xec(%rbp),%edx
  mov    -0x100(%rbp),%rcx
  mov    -0xe0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0xec(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xe0(%rbp),%rdx
  mov    -0xf8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <imaddhist@plt>
  nop
  mov    %rbx,%rsp
  mov    -0xd8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void imaddhistf(struct icom *comp, char *format, ...) {
  char line[BUFSIZ];
  va_list va;
  va_start(va, format);
  vsprintf(line, format, va);
  va_end(va);
  imaddhist(comp, line);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<imaddhistf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L23:
  cmp    %rdx,%rsp
  je     L27
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L23
L27:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L3
  orq    $0x0,-0x8(%rsp,%rax,1)
L3:
  mov    %rbx,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <imaddhist@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void imaddhistf(struct icom *comp, char *format, ...) {
  char line[BUFSIZ];
  va_list va;
  va_start(va, format);
  vsprintf(line, format, va);
  va_end(va);
  imaddhist(comp, line);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<imaddhistf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D9(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L13
L18:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L18
L13:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L42
L19:
  xor    %r13d,%r13d
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %rsp,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <imaddhist@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  lea    -0x18(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L19
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void imaddhistf(struct icom *comp, char *format, ...) {
  char line[BUFSIZ];
  va_list va;
  va_start(va, format);
  vsprintf(line, format, va);
  va_end(va);
  imaddhist(comp, line);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<imaddhistf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D1(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L9
L23:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L23
L9:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L48
L6:
  xor    %r13d,%r13d
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %rsp,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <imaddhist@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  lea    -0x18(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L6
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void imaddhistf(struct icom *comp, char *format, ...) {
  char line[BUFSIZ];
  va_list va;
  va_start(va, format);
  vsprintf(line, format, va);
  va_end(va);
  imaddhist(comp, line);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_repetition_score>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L8:
  mov    -0x8(%rbp),%eax
  add    $0x20,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L21
L38:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L14
  addl   $0x1,-0xc(%rbp)
L14:
  addl   $0x20,-0x4(%rbp)
L21:
  mov    -0x1c(%rbp),%eax
  sub    $0x20,%eax
  cmp    %eax,-0x4(%rbp)
  jb     L38
  addl   $0x20,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L8
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int find_repetition_score(char *line, unsigned int size) {
  unsigned int rep_score = 0;
  for (unsigned int i = 0; i < size; i += 32) {
    for (unsigned int j = i + 32; j < (size - 32); j += 32) {
      if (strncmp(line + i, line + j, 32) == 0) {
        rep_score++;
      }
    }
  }
  return rep_score;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_repetition_score>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L7
  mov    %rdi,%r13
  mov    $0x0,%r15d
  mov    $0x0,%ebp
  lea    -0x20(%rsi),%r14d
L4:
  mov    %r15d,%r12d
  add    $0x20,%r15d
  cmp    %r14d,%r15d
  jae    L20
  mov    %r15d,%ebx
  mov    %r12d,%r12d
  add    %r13,%r12
L9:
  mov    %ebx,%esi
  add    %r13,%rsi
  mov    $0x20,%edx
  mov    %r12,%rdi
  call   <strncmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  add    $0x20,%ebx
  cmp    %r14d,%ebx
  jb     L9
L20:
  cmp    %r15d,0xc(%rsp)
  ja     L4
L29:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    0xc(%rsp),%ebp
  jmp    L29
```

assistant: ```c
unsigned int find_repetition_score(char *line, unsigned int size) {
  unsigned int rep_score = 0;
  for (unsigned int i = 0; i < size; i += 32) {
    for (unsigned int j = i + 32; j < (size - 32); j += 32) {
      if (strncmp(line + i, line + j, 32) == 0) {
        rep_score++;
      }
    }
  }
  return rep_score;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_repetition_score>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L12
  mov    %rdi,%rbp
  lea    -0x20(%rsi),%r13d
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %r14d,%ebx
  add    $0x20,%r14d
  cmp    %r14d,%r13d
  jbe    L5
  add    %rbp,%rbx
  mov    %r14d,%r15d
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r15d,%esi
  mov    $0x20,%edx
  mov    %rbx,%rdi
  add    %rbp,%rsi
  call   <strncmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
  add    $0x20,%r15d
  cmp    %r15d,%r13d
  ja     L36
L5:
  cmp    %r14d,0xc(%rsp)
  ja     L46
L4:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  xor    %r12d,%r12d
  jmp    L4
```

assistant: ```c
unsigned int find_repetition_score(char *line, unsigned int size) {
  unsigned int rep_score = 0;
  for (unsigned int i = 0; i < size; i += 32) {
    for (unsigned int j = i + 32; j < (size - 32); j += 32) {
      if (strncmp(line + i, line + j, 32) == 0) {
        rep_score++;
      }
    }
  }
  return rep_score;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_repetition_score>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L26
  mov    %rdi,%rbp
  lea    -0x20(%rsi),%r13d
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r14d,%ebx
  add    $0x20,%r14d
  cmp    %r14d,%r13d
  jbe    L20
  add    %rbp,%rbx
  mov    %r14d,%r15d
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %r15d,%esi
  mov    $0x20,%edx
  mov    %rbx,%rdi
  add    %rbp,%rsi
  call   <strncmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
  add    $0x20,%r15d
  cmp    %r15d,%r13d
  ja     L44
L20:
  cmp    %r14d,0xc(%rsp)
  ja     L27
L28:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  xor    %r12d,%r12d
  jmp    L28
```

assistant: ```c
unsigned int find_repetition_score(char *line, unsigned int size) {
  unsigned int rep_score = 0;
  for (unsigned int i = 0; i < size; i += 32) {
    for (unsigned int j = i + 32; j < (size - 32); j += 32) {
      if (strncmp(line + i, line + j, 32) == 0) {
        rep_score++;
      }
    }
  }
  return rep_score;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<polyirreducible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fls64@plt>
  sub    $0x1,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L30:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <polymmult@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  xor    $0x2,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <polygcd@plt>
  cmp    $0x1,%eax
  je     L27
  mov    $0x0,%eax
  jmp    L37
L27:
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L30
  mov    $0x1,%eax
L37:
  leave
  ret
```

assistant: ```c
int polyirreducible(u_int64_t f) {
  u_int64_t u = 2;
  int i;
  int m = (fls64(f) - 1) >> 1;
  for (i = 0; i < m; i++) {
    u = polymmult(u, u, f);
    if (polygcd(f, u ^ 2) != 1)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<polyirreducible>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  call   <fls64@plt>
  lea    -0x1(%rax),%r13d
  sar    %r13d
  test   %r13d,%r13d
  jle    L19
  mov    $0x0,%ebp
  mov    $0x2,%ebx
L4:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <polymmult@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    $0x2,%esi
  mov    %r12d,%edi
  call   <polygcd@plt>
  cmp    $0x1,%eax
  jne    L36
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L4
  jmp    L23
L19:
  mov    $0x1,%eax
  jmp    L23
L36:
  mov    $0x0,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int polyirreducible(u_int64_t f) {
  u_int64_t u = 2;
  int i;
  int m = (fls64(f) - 1) >> 1;
  for (i = 0; i < m; i++) {
    u = polymmult(u, u, f);
    if (polygcd(f, u ^ 2) != 1)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<polyirreducible>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fls64@plt>
  lea    -0x1(%rax),%r13d
  sar    %r13d
  test   %r13d,%r13d
  jle    L14
  xor    %ebx,%ebx
  mov    $0x2,%ebp
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  je     L14
L32:
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %r12d,%edx
  call   <polymmult@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    $0x2,%esi
  call   <polygcd@plt>
  cmp    $0x1,%eax
  je     L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L14:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int polyirreducible(u_int64_t f) {
  u_int64_t u = 2;
  int i;
  int m = (fls64(f) - 1) >> 1;
  for (i = 0; i < m; i++) {
    u = polymmult(u, u, f);
    if (polygcd(f, u ^ 2) != 1)
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<polyirreducible>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fls64@plt>
  lea    -0x1(%rax),%r13d
  sar    %r13d
  test   %r13d,%r13d
  jle    L21
  xor    %ebx,%ebx
  mov    $0x2,%ebp
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  je     L21
L35:
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %r12d,%edx
  call   <polymmult@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    $0x2,%esi
  call   <polygcd@plt>
  cmp    $0x1,%eax
  je     L18
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L21:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int polyirreducible(u_int64_t f) {
  u_int64_t u = 2;
  int i;
  int m = (fls64(f) - 1) >> 1;
  for (i = 0; i < m; i++) {
    u = polymmult(u, u, f);
    if (polygcd(f, u ^ 2) != 1)
      return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D36(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D45(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L15:
  movss  -0x14(%rbp),%xmm0
  movss  D65(%rip),%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D39(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x14(%rbp),%xmm2
  movq   %xmm2,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  -0x14(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
L13:
  movss  -0xc(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jae    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D36
type: byte[4]
name: unpack_data
arguments: tag: D45
type: byte[4]
name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D21
type: string
name: unpack_data
arguments: tag: D2
type: string
name: unpack_data
arguments: tag: D65
type: byte[4]
name: unpack_data
arguments: tag: D39
type: byte[8]
name: unpack_data
arguments: tag: D69
type: string

tool: {"D36": [0x00,0x00,0x96,0x43]}

tool: {"D45": [0x00,0x00,0xa0,0x41]}

tool: D3: Celsius

tool: D21: Fahr

tool: D2: %3s %7s


tool: {"D65": [0x00,0x00,0x00,0x42]}

tool: {"D39": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D69: %3.0f %6.1f


assistant: ```c
main() {
  float fahr, celsius;
  float lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  printf("%3s %7s\n", "Fahr", "Celsius");
  while (fahr <= upper) {
    celsius = (5.0 / 9.0) * (fahr - 32);
    printf("%3.0f %6.1f\n", fahr, celsius);
    fahr = fahr + step;
  }
}
```