ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<edges_from_edge_subset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    %edx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rcx
  cltd
  idivl  -0x1c(%rbp)
  mov    %eax,(%rcx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%ecx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void edges_from_edge_subset(int *edge_subset, int n, int *e) {
  int i;
  for (i = 0; i < 2 * n; i++) {
    e[2 * i] = edge_subset[i] / n;
    e[2 * i + 1] = edge_subset[i] % n + n;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<edges_from_edge_subset>:
  endbr64
  mov    %rdx,%r8
  lea    (%rsi,%rsi,1),%r9d
  test   %r9d,%r9d
  jle    L0
  mov    %r9d,%r9d
  mov    $0x0,%ecx
L7:
  mov    (%rdi,%rcx,4),%eax
  cltd
  idiv   %esi
  mov    %eax,(%r8,%rcx,8)
  mov    (%rdi,%rcx,4),%eax
  cltd
  idiv   %esi
  add    %esi,%edx
  mov    %edx,0x4(%r8,%rcx,8)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L7
L0:
  ret
```

assistant: ```c
void edges_from_edge_subset(int *edge_subset, int n, int *e) {
  int i;
  for (i = 0; i < 2 * n; i++) {
    e[2 * i] = edge_subset[i] / n;
    e[2 * i + 1] = edge_subset[i] % n + n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<edges_from_edge_subset>:
  endbr64
  lea    (%rsi,%rsi,1),%r9d
  mov    %rdx,%r8
  test   %r9d,%r9d
  jle    L18
  movslq %r9d,%r9
  xor    %ecx,%ecx
  nopl   (%rax)
L11:
  mov    (%rdi,%rcx,4),%eax
  cltd
  idiv   %esi
  mov    %eax,(%r8,%rcx,8)
  mov    (%rdi,%rcx,4),%eax
  cltd
  idiv   %esi
  add    %esi,%edx
  mov    %edx,0x4(%r8,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L11
L18:
  ret
```

assistant: ```c
void edges_from_edge_subset(int *edge_subset, int n, int *e) {
  int i;
  for (i = 0; i < 2 * n; i++) {
    e[2 * i] = edge_subset[i] / n;
    e[2 * i + 1] = edge_subset[i] % n + n;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<edges_from_edge_subset>:
  endbr64
  lea    (%rsi,%rsi,1),%r9d
  mov    %rdx,%r8
  test   %r9d,%r9d
  jle    L12
  movslq %r9d,%r9
  xor    %ecx,%ecx
  nopl   (%rax)
L15:
  mov    (%rdi,%rcx,4),%eax
  cltd
  idiv   %esi
  mov    %eax,(%r8,%rcx,8)
  mov    (%rdi,%rcx,4),%eax
  cltd
  idiv   %esi
  add    %esi,%edx
  mov    %edx,0x4(%r8,%rcx,8)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L15
L12:
  ret
```

assistant: ```c
void edges_from_edge_subset(int *edge_subset, int n, int *e) {
  int i;
  for (i = 0; i < 2 * n; i++) {
    e[2 * i] = edge_subset[i] / n;
    e[2 * i + 1] = edge_subset[i] % n + n;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inner>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    $0x101,%eax
  mov    $0x102,%ebx
  mov    $0x103,%ecx
  mov    $0x104,%edx
  mov    $0x105,%esi
  mov    $0x106,%edi
  mov    $0x108,%esp
  movl   $0x1234,(%eax)
  ud2
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
__attribute__((no)) void inner(void) {
  __asm__ __volatile__("movl $0x101, %%eax\n"
                       "movl $0x102, %%ebx\n"
                       "movl $0x103, %%ecx\n"
                       "movl $0x104, %%edx\n"
                       "movl $0x105, %%esi\n"
                       "movl $0x106, %%edi\n"
                       "movl $0x108, %%esp\n"
                       "movl $0x1234, (%%eax)\n"
                       "ud2"
                       :
                       :
                       : "memory", "%eax", "%ebx", "%ecx", "%edx", "%esi", "%edi");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inner>:
  endbr64
  push   %rbx
  mov    $0x101,%eax
  mov    $0x102,%ebx
  mov    $0x103,%ecx
  mov    $0x104,%edx
  mov    $0x105,%esi
  mov    $0x106,%edi
  mov    $0x108,%esp
  movl   $0x1234,(%eax)
  ud2
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((no)) void inner(void) {
  __asm__ __volatile__("movl $0x101, %%eax\n"
                       "movl $0x102, %%ebx\n"
                       "movl $0x103, %%ecx\n"
                       "movl $0x104, %%edx\n"
                       "movl $0x105, %%esi\n"
                       "movl $0x106, %%edi\n"
                       "movl $0x108, %%esp\n"
                       "movl $0x1234, (%%eax)\n"
                       "ud2"
                       :
                       :
                       : "memory", "%eax", "%ebx", "%ecx", "%edx", "%esi", "%edi");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inner>:
  endbr64
  push   %rbx
  mov    $0x101,%eax
  mov    $0x102,%ebx
  mov    $0x103,%ecx
  mov    $0x104,%edx
  mov    $0x105,%esi
  mov    $0x106,%edi
  mov    $0x108,%esp
  movl   $0x1234,(%eax)
  ud2
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((no)) void inner(void) {
  __asm__ __volatile__("movl $0x101, %%eax\n"
                       "movl $0x102, %%ebx\n"
                       "movl $0x103, %%ecx\n"
                       "movl $0x104, %%edx\n"
                       "movl $0x105, %%esi\n"
                       "movl $0x106, %%edi\n"
                       "movl $0x108, %%esp\n"
                       "movl $0x1234, (%%eax)\n"
                       "ud2"
                       :
                       :
                       : "memory", "%eax", "%ebx", "%ecx", "%edx", "%esi", "%edi");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inner>:
  endbr64
  push   %rbx
  mov    $0x101,%eax
  mov    $0x102,%ebx
  mov    $0x103,%ecx
  mov    $0x104,%edx
  mov    $0x105,%esi
  mov    $0x106,%edi
  mov    $0x108,%esp
  movl   $0x1234,(%eax)
  ud2
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((no)) void inner(void) {
  __asm__ __volatile__("movl $0x101, %%eax\n"
                       "movl $0x102, %%ebx\n"
                       "movl $0x103, %%ecx\n"
                       "movl $0x104, %%edx\n"
                       "movl $0x105, %%esi\n"
                       "movl $0x106, %%edi\n"
                       "movl $0x108, %%esp\n"
                       "movl $0x1234, (%%eax)\n"
                       "ud2"
                       :
                       :
                       : "memory", "%eax", "%ebx", "%ecx", "%edx", "%esi", "%edi");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <doStuff_pointerToConstInt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void f_1(void) {
  int t;
  int *tp = &t;
  doStuff_pointerToConstInt(tp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f_1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <doStuff_pointerToConstInt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f_1(void) {
  int t;
  int *tp = &t;
  doStuff_pointerToConstInt(tp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f_1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <doStuff_pointerToConstInt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f_1(void) {
  int t;
  int *tp = &t;
  doStuff_pointerToConstInt(tp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f_1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <doStuff_pointerToConstInt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f_1(void) {
  int t;
  int *tp = &t;
  doStuff_pointerToConstInt(tp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L5
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x8(%rbp)
  jmp    L24
L14:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x8(%rbp)
L24:
  cmpl   $0x0,-0x8(%rbp)
  jne    L14
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bcd(int I, int J) {
  int t, R;
  if (J > I) {
    t = J;
    J = I;
    I = t;
  }
  R = I % J;
  while (R != 0) {
    I = J;
    J = R;
    R = I % J;
  }
  return J;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bcd>:
  endbr64
  mov    %edi,%eax
  cmp    %edi,%esi
  jle    L38
  mov    %esi,%eax
  mov    %edi,%esi
L38:
  cltd
  idiv   %esi
  mov    %edx,%ecx
  test   %edx,%edx
  je     L36
L33:
  mov    %ecx,%edi
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%ecx
  mov    %edi,%esi
  test   %edx,%edx
  jne    L33
L4:
  mov    %edi,%eax
  ret
L36:
  mov    %esi,%edi
  jmp    L4
```

assistant: ```c
int bcd(int I, int J) {
  int t, R;
  if (J > I) {
    t = J;
    J = I;
    I = t;
  }
  R = I % J;
  while (R != 0) {
    I = J;
    J = R;
    R = I % J;
  }
  return J;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bcd>:
  endbr64
  mov    %edi,%eax
  cmp    %edi,%esi
  jle    L24
  mov    %esi,%eax
  mov    %edi,%esi
L24:
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L28
  nopl   (%rax)
L23:
  mov    %esi,%eax
  mov    %edx,%r8d
  cltd
  mov    %r8d,%esi
  idiv   %r8d
  test   %edx,%edx
  jne    L23
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L28:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bcd(int I, int J) {
  int t, R;
  if (J > I) {
    t = J;
    J = I;
    I = t;
  }
  R = I % J;
  while (R != 0) {
    I = J;
    J = R;
    R = I % J;
  }
  return J;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bcd>:
  endbr64
  mov    %edi,%eax
  cmp    %edi,%esi
  jle    L4
  mov    %esi,%eax
  mov    %edi,%esi
L4:
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L28
  nopl   (%rax)
L7:
  mov    %esi,%eax
  mov    %edx,%r8d
  cltd
  mov    %r8d,%esi
  idiv   %r8d
  test   %edx,%edx
  jne    L7
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L28:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bcd(int I, int J) {
  int t, R;
  if (J > I) {
    t = J;
    J = I;
    I = t;
  }
  R = I % J;
  while (R != 0) {
    I = J;
    J = R;
    R = I % J;
  }
  return J;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<interpolate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L18
  cmpl   $0x0,-0x4(%rbp)
  jne    L49
L18:
  mov    -0x10(%rbp),%rax
  jmp    L19
L49:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jge    L29
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  imul   %rdx,%rax
  lea    0xff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L19
L29:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  imul   %rdx,%rax
  lea    0xff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x8,%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int_fast16_t interpolate(const unsigned fraction, const int_fast16_t value1, const int_fast16_t value2) {
  if (value1 == value2 || fraction == 0)
    return value1;
  if (value1 < value2)
    return value1 + (int_fast16_t)(((value2 - value1) * (int)fraction) / 256);
  else
    return value1 - (int_fast16_t)(((value1 - value2) * (int)fraction) / 256);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<interpolate>:
  endbr64
  mov    %rsi,%rax
  cmp    %rdx,%rsi
  je     L17
  test   %edi,%edi
  je     L17
  cmp    %rdx,%rsi
  jge    L5
  sub    %rsi,%rdx
  movslq %edi,%rdi
  imul   %rdi,%rdx
  lea    0xff(%rdx),%rcx
  test   %rdx,%rdx
  cmovs  %rcx,%rdx
  sar    $0x8,%rdx
  add    %rdx,%rax
  ret
L5:
  mov    %rsi,%rcx
  sub    %rdx,%rcx
  movslq %edi,%rdi
  imul   %rdi,%rcx
  lea    0xff(%rcx),%rdx
  test   %rcx,%rcx
  cmovns %rcx,%rdx
  sar    $0x8,%rdx
  sub    %rdx,%rax
L17:
  ret
```

assistant: ```c
int_fast16_t interpolate(const unsigned fraction, const int_fast16_t value1, const int_fast16_t value2) {
  if (value1 == value2 || fraction == 0)
    return value1;
  if (value1 < value2)
    return value1 + (int_fast16_t)(((value2 - value1) * (int)fraction) / 256);
  else
    return value1 - (int_fast16_t)(((value1 - value2) * (int)fraction) / 256);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<interpolate>:
  endbr64
  mov    %rsi,%rax
  cmp    %rdx,%rsi
  je     L5
  test   %edi,%edi
  je     L5
  movslq %edi,%rdi
  cmp    %rdx,%rsi
  jge    L20
  sub    %rsi,%rdx
  imul   %rdi,%rdx
  test   %rdx,%rdx
  lea    0xff(%rdx),%rcx
  cmovs  %rcx,%rdx
  sar    $0x8,%rdx
  add    %rdx,%rax
  ret
  nopl   (%rax)
L20:
  mov    %rsi,%rcx
  sub    %rdx,%rcx
  imul   %rdi,%rcx
  test   %rcx,%rcx
  lea    0xff(%rcx),%rdx
  cmovns %rcx,%rdx
  sar    $0x8,%rdx
  sub    %rdx,%rax
L5:
  ret
```

assistant: ```c
int_fast16_t interpolate(const unsigned fraction, const int_fast16_t value1, const int_fast16_t value2) {
  if (value1 == value2 || fraction == 0)
    return value1;
  if (value1 < value2)
    return value1 + (int_fast16_t)(((value2 - value1) * (int)fraction) / 256);
  else
    return value1 - (int_fast16_t)(((value1 - value2) * (int)fraction) / 256);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<interpolate>:
  endbr64
  mov    %rsi,%rax
  cmp    %rdx,%rsi
  je     L2
  test   %edi,%edi
  je     L2
  movslq %edi,%rdi
  cmp    %rdx,%rsi
  jge    L17
  sub    %rsi,%rdx
  imul   %rdi,%rdx
  test   %rdx,%rdx
  lea    0xff(%rdx),%rcx
  cmovs  %rcx,%rdx
  sar    $0x8,%rdx
  add    %rdx,%rax
  ret
  nopl   (%rax)
L17:
  mov    %rsi,%rcx
  sub    %rdx,%rcx
  imul   %rdi,%rcx
  test   %rcx,%rcx
  lea    0xff(%rcx),%rdx
  cmovns %rcx,%rdx
  sar    $0x8,%rdx
  sub    %rdx,%rax
L2:
  ret
```

assistant: ```c
int_fast16_t interpolate(const unsigned fraction, const int_fast16_t value1, const int_fast16_t value2) {
  if (value1 == value2 || fraction == 0)
    return value1;
  if (value1 < value2)
    return value1 + (int_fast16_t)(((value2 - value1) * (int)fraction) / 256);
  else
    return value1 - (int_fast16_t)(((value1 - value2) * (int)fraction) / 256);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitstuff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r9d
  cltq
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %r9d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  lea    0x1(%rax,%rax,1),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L10:
  cmp    %rdx,%rsp
  je     L83
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L10
L83:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L106
  orq    $0x0,-0x8(%rsp,%rax,1)
L106:
  mov    %rsp,%r10
  test   %r9d,%r9d
  jle    L50
  mov    $0x0,%edi
  mov    $0x0,%ecx
  jmp    L59
L66:
  cmp    $0x5,%r8d
  je     L109
L20:
  add    $0x1,%ecx
  add    $0x1,%edi
  cmp    %ecx,%r9d
  jle    L122
L59:
  movslq %ecx,%rdx
  add    %rbx,%rdx
  movzbl (%rdx),%eax
  movslq %edi,%rsi
  mov    %al,(%r10,%rsi,1)
  cmp    $0x30,%al
  jne    L20
  mov    $0x1,%eax
  mov    $0x0,%r8d
L61:
  movsbl (%rdx,%rax,1),%esi
  lea    -0x30(%r8,%rsi,1),%r8d
  mov    %eax,%esi
  add    $0x1,%rax
  cmp    $0x4,%esi
  jg     L66
  cmp    %r9d,%esi
  jl     L61
  jmp    L66
L109:
  add    $0x5,%ecx
  lea    0x1(%rdi),%eax
  cltq
  movb   $0x31,(%r10,%rax,1)
  lea    0x2(%rdi),%eax
  cltq
  movb   $0x31,(%r10,%rax,1)
  lea    0x3(%rdi),%eax
  cltq
  movb   $0x31,(%r10,%rax,1)
  lea    0x4(%rdi),%eax
  cltq
  movb   $0x31,(%r10,%rax,1)
  lea    0x5(%rdi),%eax
  cltq
  movb   $0x31,(%r10,%rax,1)
  add    $0x6,%edi
  movslq %edi,%rax
  movb   $0x30,(%r10,%rax,1)
  jmp    L20
L50:
  mov    $0x0,%edi
L122:
  movslq %edi,%rdi
  movb   $0x0,(%r10,%rdi,1)
  mov    %r10,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  mov    -0x8(%rbp),%rbx
  leave
  ret
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0: 
Stuffed Data : %s


assistant: ```c
void bitstuff(char *data) {
  int len = strlen(data);
  char stuffedString[(len / 5) * 6 + 1];
  int i = 0, j, k = 0, sum;
  while (i < len) {
    stuffedString[k] = data[i];
    if (data[i] == '0') {
      j = 0;
      sum = 0;
      while (j < 5 && j < len) {
        sum += data[j + i + 1] - '0';
        j++;
      }
      if (sum == 5) {
        i += 5;
        k++;
        j = 0;
        while (j < 5) {
          stuffedString[k] = '1';
          k++;
          j++;
        }
        stuffedString[k] = '0';
      }
    }
    i++;
    k++;
  }
  stuffedString[k] = '\0';
  strcpy(data, stuffedString);
  printf("\nStuffed Data : %s\n", data);
}
```
user: What is the c source code of the assembly code below?

```asm
<bitstuff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  mov    %eax,%edi
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  lea    0x1(%rax,%rax,1),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L122
L81:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L81
L122:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L54
L135:
  mov    %rsp,%r10
  xor    %ecx,%ecx
  test   %edi,%edi
  jle    L31
  xor    %edx,%edx
  jmp    L129
  nopl   0x0(%rax,%rax,1)
L109:
  add    $0x1,%edx
  add    $0x1,%ecx
  cmp    %edx,%edi
  jle    L31
L129:
  movslq %edx,%rax
  movslq %ecx,%r8
  add    %r12,%rax
  movzbl (%rax),%esi
  mov    %sil,(%r10,%r8,1)
  cmp    $0x30,%sil
  jne    L109
  mov    $0x1,%esi
  xor    %r9d,%r9d
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L121:
  cmp    %r8d,%edi
  jle    L63
L40:
  movsbl (%rax,%rsi,1),%r8d
  lea    -0x30(%r9,%r8,1),%r9d
  mov    %esi,%r8d
  add    $0x1,%rsi
  cmp    $0x4,%r8d
  jle    L121
L63:
  cmp    $0x5,%r9d
  jne    L109
  lea    0x1(%rcx),%eax
  add    $0x5,%edx
  add    $0x6,%ecx
  cltq
  add    $0x1,%edx
  add    %r10,%rax
  movl   $0x31313131,(%rax)
  movb   $0x31,0x4(%rax)
  movslq %ecx,%rax
  add    $0x1,%ecx
  movb   $0x30,(%r10,%rax,1)
  cmp    %edx,%edi
  jg     L129
  nopl   0x0(%rax)
L31:
  movslq %ecx,%rcx
  mov    %r10,%rsi
  mov    %r12,%rdi
  movb   $0x0,(%r10,%rcx,1)
  call   <strcpy@plt>
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L125
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L135
L125:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: 
Stuffed Data : %s


assistant: ```c
void bitstuff(char *data) {
  int len = strlen(data);
  char stuffedString[(len / 5) * 6 + 1];
  int i = 0, j, k = 0, sum;
  while (i < len) {
    stuffedString[k] = data[i];
    if (data[i] == '0') {
      j = 0;
      sum = 0;
      while (j < 5 && j < len) {
        sum += data[j + i + 1] - '0';
        j++;
      }
      if (sum == 5) {
        i += 5;
        k++;
        j = 0;
        while (j < 5) {
          stuffedString[k] = '1';
          k++;
          j++;
        }
        stuffedString[k] = '0';
      }
    }
    i++;
    k++;
  }
  stuffedString[k] = '\0';
  strcpy(data, stuffedString);
  printf("\nStuffed Data : %s\n", data);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_putbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x80,-0x1(%rbp)
  jmp    L0
L21:
  movzbl -0x14(%rbp),%eax
  and    -0x1(%rbp),%al
  test   %al,%al
  je     L24
  mov    $0x31,%eax
  jmp    L3
L24:
  mov    $0x30,%eax
L3:
  mov    %eax,%edi
  call   <ft_putchar@plt>
  shrb   -0x1(%rbp)
L0:
  cmpb   $0x0,-0x1(%rbp)
  jne    L21
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_putbits(unsigned char c) {
  unsigned char b;
  b = (char)128;
  while (b) {
    ft_putchar(c & b ? '1' : '0');
    b = b >> 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_putbits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x8,%ebp
  mov    $0xffffff80,%ebx
L1:
  test   %bl,%r12b
  setne  %dil
  movzbl %dil,%edi
  add    $0x30,%edi
  call   <ft_putchar@plt>
  shr    %bl
  sub    $0x1,%ebp
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ft_putbits(unsigned char c) {
  unsigned char b;
  b = (char)128;
  while (b) {
    ft_putchar(c & b ? '1' : '0');
    b = b >> 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_putbits>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    $0xffffff80,%ebx
  nopl   (%rax)
L6:
  xor    %edi,%edi
  test   %bl,%r12b
  setne  %dil
  shr    %bl
  add    $0x30,%edi
  call   <ft_putchar@plt>
  sub    $0x1,%ebp
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ft_putbits(unsigned char c) {
  unsigned char b;
  b = (char)128;
  while (b) {
    ft_putchar(c & b ? '1' : '0');
    b = b >> 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_putbits>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    $0xffffff80,%ebx
  nopl   (%rax)
L8:
  test   %bl,%r12b
  je     L7
  mov    $0x31,%edi
  shr    %bl
  call   <ft_putchar@plt>
  sub    $0x1,%ebp
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x30,%edi
  shr    %bl
  call   <ft_putchar@plt>
  sub    $0x1,%ebp
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ft_putbits(unsigned char c) {
  unsigned char b;
  b = (char)128;
  while (b) {
    ft_putchar(c & b ? '1' : '0');
    b = b >> 1;
  }
}
```