user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D36(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
  lea    D17(%rip),%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  movsbl 0x10(%rsp),%edi
  movq   $0x0,0x8(%rsp)
  test   %dil,%dil
  je     L48
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L63:
  call   <digitValue@plt>
  test   %rax,%rax
  js     L33
L5:
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    %ebx,%eax
  cmp    $0x2,%eax
  jle    L39
  movsbl 0x10(%rsp,%rbp,1),%edi
  call   <digitValue@plt>
  mov    %rax,%r14
  lea    0x2(%rbx),%eax
  cltq
  movsbl 0x10(%rsp,%rax,1),%edi
  call   <digitValue@plt>
  cmp    %rax,%r14
  jl     L89
L39:
  movsbl 0x10(%rsp,%rbp,1),%edi
  lea    0x1(%rbx),%r14d
  movslq %r14d,%r12
  call   <digitValue@plt>
  movsbl 0x10(%rsp,%r12,1),%edi
  mov    %rax,%r15
  call   <digitValue@plt>
  cmp    %rax,%r15
  jl     L61
  movsbl 0x10(%rsp,%rbp,1),%edi
  call   <digitValue@plt>
  movsbl 0x10(%rsp,%r12,1),%edi
  add    %rax,0x8(%rsp)
  test   %dil,%dil
  je     L48
  mov    %r14d,%ebx
  mov    %r12,%rbp
  call   <digitValue@plt>
  test   %rax,%rax
  jns    L5
L33:
  movsbl 0x10(%rsp,%rbp,1),%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L73
  nopl   0x0(%rax)
L61:
  movsbl 0x10(%rsp,%r12,1),%edi
  add    $0x2,%ebx
  call   <digitValue@plt>
  movsbl 0x10(%rsp,%rbp,1),%edi
  movslq %ebx,%rbp
  mov    %rax,%r14
  call   <digitValue@plt>
  movsbl 0x10(%rsp,%rbp,1),%edi
  sub    %rax,%r14
  add    %r14,0x8(%rsp)
  test   %dil,%dil
  jne    L63
L48:
  mov    0x8(%rsp),%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L73:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x408,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L89:
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L73
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D36
type_infered: string
name: retrieve_data
arguments: label: D17
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D39
type_infered: string

tool: D36: Enter any roman number (Valid digits are I, V, X, L, C, D, M):  

tool: D17: %s

tool: D1: Invalid roman digit : %c

tool: D7: Its decimal value is : %ld

tool: D39: Invalid roman number

assistant: ```c
int main() {
  char roman_Number[1000];
  int i = 0;
  long int number = 0;
  printf("Enter any roman number (Valid digits are I, V, X, L, C, D, M):  \n");
  scanf("%s", roman_Number);
  while (roman_Number[i]) {
    if (digitValue(roman_Number[i]) < 0) {
      printf("Invalid roman digit : %c", roman_Number[i]);
      return 0;
    }
    if ((strlen(roman_Number) - i) > 2) {
      if (digitValue(roman_Number[i]) < digitValue(roman_Number[i + 2])) {
        printf("Invalid roman number");
        return 0;
      }
    }
    if (digitValue(roman_Number[i]) >= digitValue(roman_Number[i + 1]))
      number = number + digitValue(roman_Number[i]);
    else {
      number = number + (digitValue(roman_Number[i + 1]) - digitValue(roman_Number[i]));
      i++;
    }
    i++;
  }
  printf("Its decimal value is : %ld", number);
  return 0;
}
```