ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sizerepr>:
  endbr64
  push   %r12
  cmp    $0x3ff,%rdi
  jbe    L34
  xor    %eax,%eax
  nopl   0x0(%rax)
L25:
  mov    %rdi,%rdx
  shr    $0xa,%rdi
  add    $0x1,%rax
  cmp    $0x3ff,%rdi
  jbe    L23
  cmp    $0x5,%rax
  jbe    L25
L23:
  and    $0x3ff,%edx
  pxor   %xmm1,%xmm1
  lea    D37(%rip),%rcx
  cvtsi2sd %rdx,%xmm1
  mulsd  D35(%rip),%xmm1
  movsbl (%rcx,%rax,1),%ecx
L8:
  pxor   %xmm0,%xmm0
  lea    D29(%rip),%r12
  mov    $0x40,%esi
  cvtsi2sd %rdi,%xmm0
  lea    D14(%rip),%rdx
  mov    %r12,%rdi
  addsd  %xmm1,%xmm0
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  pxor   %xmm1,%xmm1
  mov    $0x42,%ecx
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: tag: D37
data_type: string
name: disassemble_data
arguments: tag: D35
data_type: byte[8]
name: disassemble_data
arguments: tag: D14
data_type: string

tool: D37: BKMGT

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D14: %.1f%c

assistant: ```c
char *sizerepr(size_t size) {
  static char buf[64] = {0};
  size_t div = 0;
  size_t rem = 0;
  while (size >= 1024 && div < sizeof("BKMGT")) {
    rem = size % 1024;
    size /= 1024;
    ++div;
  }
  snprintf(buf, 64, "%.1f%c", (double)size + (double)rem / 1024.0, "BKMGT"[div]);
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sizerepr>:
  endbr64
  push   %r12
  cmp    $0x3ff,%rdi
  jbe    L23
  xor    %eax,%eax
  nopl   0x0(%rax)
L9:
  mov    %rdi,%rdx
  shr    $0xa,%rdi
  add    $0x1,%rax
  cmp    $0x3ff,%rdi
  jbe    L7
  cmp    $0x5,%rax
  jbe    L9
L7:
  and    $0x3ff,%edx
  pxor   %xmm1,%xmm1
  lea    D36(%rip),%rcx
  cvtsi2sd %rdx,%xmm1
  mulsd  D35(%rip),%xmm1
  movsbl (%rcx,%rax,1),%ecx
L2:
  pxor   %xmm0,%xmm0
  lea    D15(%rip),%r12
  mov    $0x40,%esi
  cvtsi2sd %rdi,%xmm0
  lea    D20(%rip),%rdx
  mov    %r12,%rdi
  addsd  %xmm1,%xmm0
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  pxor   %xmm1,%xmm1
  mov    $0x42,%ecx
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: tag: D36
type: string
name: disassemble_data
arguments: tag: D35
type: byte[8]
name: disassemble_data
arguments: tag: D20
type: string

tool: D36: BKMGT

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D20: %.1f%c

assistant: ```c
char *sizerepr(size_t size) {
  static char buf[64] = {0};
  size_t div = 0;
  size_t rem = 0;
  while (size >= 1024 && div < sizeof("BKMGT")) {
    rem = size % 1024;
    size /= 1024;
    ++div;
  }
  snprintf(buf, 64, "%.1f%c", (double)size + (double)rem / 1024.0, "BKMGT"[div]);
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<product_print_table_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D74(%rip),%r9
  lea    D25(%rip),%r8
  lea    D55(%rip),%rax
  mov    %rax,%rcx
  lea    D9(%rip),%rax
  mov    %rax,%rdx
  lea    D47(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x3,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D70
type_infered: string
name: retrieve_data
arguments: data_label: D74
type_infered: string
name: retrieve_data
arguments: data_label: D25
type_infered: string
name: retrieve_data
arguments: data_label: D55
type_infered: string
name: retrieve_data
arguments: data_label: D9
type_infered: string
name: retrieve_data
arguments: data_label: D47
type_infered: string
name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D70: +--------+---------------------------------+----------+-----------+-----------+

tool: D74: Disc %

tool: D25: Price

tool: D55: In stock

tool: D9: Name

tool: D47: ID

tool: D2: | %6s | %-31s | %8s | %9s | %9s |


assistant: ```c
int product_print_table_header(void) {
  printf("+--------+---------------------------------+----------"
         "+-----------+-----------+\n");
  printf("| %6s | %-31s | %8s | %9s | %9s |\n", "ID", "Name", "In stock", "Price", "Disc %");
  printf("+--------+---------------------------------+----------"
         "+-----------+-----------+\n");
  return 3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<product_print_table_header>:
  endbr64
  push   %rbx
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D61(%rip),%r9
  lea    D17(%rip),%r8
  lea    D25(%rip),%rcx
  lea    D29(%rip),%rdx
  lea    D34(%rip),%rsi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0x3,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D26
type: string
name: read_data
arguments: label: D61
type: string
name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D25
type: string
name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D34
type: string
name: read_data
arguments: label: D57
type: string

tool: D26: +--------+---------------------------------+----------+-----------+-----------+

tool: D61: Disc %

tool: D17: Price

tool: D25: In stock

tool: D29: Name

tool: D34: ID

tool: D57: | %6s | %-31s | %8s | %9s | %9s |


assistant: ```c
int product_print_table_header(void) {
  printf("+--------+---------------------------------+----------"
         "+-----------+-----------+\n");
  printf("| %6s | %-31s | %8s | %9s | %9s |\n", "ID", "Name", "In stock", "Price", "Disc %");
  printf("+--------+---------------------------------+----------"
         "+-----------+-----------+\n");
  return 3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<product_print_table_header>:
  endbr64
  push   %rbp
  lea    D57(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D4(%rip),%r9
  xor    %eax,%eax
  lea    D20(%rip),%r8
  lea    D31(%rip),%rcx
  lea    D12(%rip),%rdx
  lea    D0(%rip),%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x3,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D57
type: string
name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D20
type: string
name: unpack_data
arguments: label: D31
type: string
name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D0
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D57: +--------+---------------------------------+----------+-----------+-----------+

tool: D4: Disc %

tool: D20: Price

tool: D31: In stock

tool: D12: Name

tool: D0: ID

tool: D11: | %6s | %-31s | %8s | %9s | %9s |


assistant: ```c
int product_print_table_header(void) {
  printf("+--------+---------------------------------+----------"
         "+-----------+-----------+\n");
  printf("| %6s | %-31s | %8s | %9s | %9s |\n", "ID", "Name", "In stock", "Price", "Disc %");
  printf("+--------+---------------------------------+----------"
         "+-----------+-----------+\n");
  return 3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<product_print_table_header>:
  endbr64
  push   %rbp
  lea    D45(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D5(%rip),%r9
  xor    %eax,%eax
  lea    D34(%rip),%r8
  lea    D54(%rip),%rcx
  lea    D8(%rip),%rdx
  lea    D6(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x3,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D45
type: string
name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D34
type: string
name: read_data
arguments: tag: D54
type: string
name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D1
type: string

tool: D45: +--------+---------------------------------+----------+-----------+-----------+

tool: D5: Disc %

tool: D34: Price

tool: D54: In stock

tool: D8: Name

tool: D6: ID

tool: D1: | %6s | %-31s | %8s | %9s | %9s |


assistant: ```c
int product_print_table_header(void) {
  printf("+--------+---------------------------------+----------"
         "+-----------+-----------+\n");
  printf("| %6s | %-31s | %8s | %9s | %9s |\n", "ID", "Name", "In stock", "Price", "Disc %");
  printf("+--------+---------------------------------+----------"
         "+-----------+-----------+\n");
  return 3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<euler_problem_10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x2,-0x8(%rbp)
  movl   $0x3,-0xc(%rbp)
  jmp    L26
L10:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L28
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L28:
  addl   $0x2,-0xc(%rbp)
L26:
  cmpl   $0x1e847f,-0xc(%rbp)
  jle    L10
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long euler_problem_10() {
  unsigned long long sum = 2;
  int i;
  for (i = 3; i < 2000000; i += 2) {
    if (is_prime(i)) {
      sum += i;
    }
  }
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<euler_problem_10>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%ebx
  mov    $0x2,%ebp
L8:
  mov    %ebx,%edi
  call   <is_prime@plt>
  mov    %rax,%rdx
  lea    0x0(%rbp,%rbx,1),%rax
  test   %rdx,%rdx
  cmovne %rax,%rbp
  add    $0x2,%rbx
  cmp    $0x1e8481,%rbx
  jne    L8
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long euler_problem_10() {
  unsigned long long sum = 2;
  int i;
  for (i = 3; i < 2000000; i += 2) {
    if (is_prime(i)) {
      sum += i;
    }
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<euler_problem_10>:
  endbr64
  push   %r12
  mov    $0x2,%r12d
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  call   <is_prime@plt>
  mov    %rax,%r8
  lea    (%r12,%rbx,1),%rax
  test   %r8,%r8
  cmovne %rax,%r12
  add    $0x2,%rbx
  cmp    $0x1e8481,%rbx
  jne    L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
long long euler_problem_10() {
  unsigned long long sum = 2;
  int i;
  for (i = 3; i < 2000000; i += 2) {
    if (is_prime(i)) {
      sum += i;
    }
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<euler_problem_10>:
  endbr64
  push   %r12
  mov    $0x2,%r12d
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  call   <is_prime@plt>
  mov    %rax,%r8
  lea    (%r12,%rbx,1),%rax
  test   %r8,%r8
  cmovne %rax,%r12
  add    $0x2,%rbx
  cmp    $0x1e8481,%rbx
  jne    L6
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
long long euler_problem_10() {
  unsigned long long sum = 2;
  int i;
  for (i = 3; i < 2000000; i += 2) {
    if (is_prime(i)) {
      sum += i;
    }
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L18
L17:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D19(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D24(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <acos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L41
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L11
L41:
  addl   $0x1,-0x24(%rbp)
L18:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L17
L11:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: f32[2]
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string

tool: {"D19": [0.0,-2.0]}

tool: D24: 1

tool: D11: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (-2.0 * rand_double()) + 0.0;
    y = acos(1.0 + x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
L23:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D26(%rip),%xmm0
  pxor   %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  addsd  D23(%rip),%xmm0
  call   <acos@plt>
  ucomisd %xmm0,%xmm0
  jp     L27
  sub    $0x1,%ebx
  jne    L23
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm3
  subsd  %xmm3,%xmm0
  movq   %xmm0,%rbx
  jmp    L4
L27:
  lea    D18(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L4:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_guessed: f32[2]
name: disassemble_data
arguments: data_label: D23
type_guessed: f64
name: disassemble_data
arguments: data_label: D18
type_guessed: string

tool: {"D26": [0.0,-2.0]}

tool: D23: 1

tool: D18: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (-2.0 * rand_double()) + 0.0;
    y = acos(1.0 + x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L11
  xchg   %ax,%ax
L22:
  sub    $0x1,%ebx
  je     L10
L11:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D22(%rip),%xmm0
  pxor   %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  addsd  D7(%rip),%xmm0
  call   <acos@plt>
  ucomisd %xmm0,%xmm0
  jnp    L22
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type_infered: f32[2]
name: unpack_data
arguments: data_tag: D7
type_infered: f64
name: unpack_data
arguments: data_tag: D19
type_infered: string

tool: {"D22": [0.0,-2.0]}

tool: D7: 1

tool: D19: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (-2.0 * rand_double()) + 0.0;
    y = acos(1.0 + x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L5
  xchg   %ax,%ax
L21:
  sub    $0x1,%ebx
  je     L8
L5:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D14(%rip),%xmm0
  pxor   %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  addsd  D24(%rip),%xmm0
  call   <acos@plt>
  ucomisd %xmm0,%xmm0
  jnp    L21
  lea    D20(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
data_type: f32[2]
name: unpack_data
arguments: data_tag: D24
data_type: f64
name: unpack_data
arguments: data_tag: D20
data_type: string

tool: {"D14": [0.0,-2.0]}

tool: D24: 1

tool: D20: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (-2.0 * rand_double()) + 0.0;
    y = acos(1.0 + x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  if (1 != 1)
    abort();
  if (2 != 2)
    abort();
  if (3 != 3)
    abort();
  if (4 != 4)
    abort();
  if (5 != 5)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  if (1 != 1)
    abort();
  if (2 != 2)
    abort();
  if (3 != 3)
    abort();
  if (4 != 4)
    abort();
  if (5 != 5)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  if (1 != 1)
    abort();
  if (2 != 2)
    abort();
  if (3 != 3)
    abort();
  if (4 != 4)
    abort();
  if (5 != 5)
    abort();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  if (1 != 1)
    abort();
  if (2 != 2)
    abort();
  if (3 != 3)
    abort();
  if (4 != 4)
    abort();
  if (5 != 5)
    abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ftime_gettime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L14
  mov    $0x0,%eax
  jmp    L1
L14:
  mov    -0x18(%rbp),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
unsigned long long ftime_gettime() {
  struct timeval tv;
  int ret = gettimeofday(&tv, NULL);
  if (ret) {
    return 0;
  }
  return (unsigned long long)tv.tv_sec * 1000000l + (unsigned long long)tv.tv_usec;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ftime_gettime>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L8
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long ftime_gettime() {
  struct timeval tv;
  int ret = gettimeofday(&tv, NULL);
  if (ret) {
    return 0;
  }
  return (unsigned long long)tv.tv_sec * 1000000l + (unsigned long long)tv.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ftime_gettime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L6
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x28,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long ftime_gettime() {
  struct timeval tv;
  int ret = gettimeofday(&tv, NULL);
  if (ret) {
    return 0;
  }
  return (unsigned long long)tv.tv_sec * 1000000l + (unsigned long long)tv.tv_usec;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ftime_gettime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L10
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long ftime_gettime() {
  struct timeval tv;
  int ret = gettimeofday(&tv, NULL);
  if (ret) {
    return 0;
  }
  return (unsigned long long)tv.tv_sec * 1000000l + (unsigned long long)tv.tv_usec;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CANErrCntrGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <_CANBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  movzbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L3
  mov    $0x1,%eax
  jmp    L0
L3:
  mov    $0x0,%eax
L0:
  leave
  ret
```

assistant: ```c
bool CANErrCntrGet(uint32_t ui32Base, uint32_t *pui32RxCount, uint32_t *pui32TxCount) {
  uint32_t ui32CANError;
  ASSERT(_CANBaseValid(ui32Base));
  ui32CANError = (*((volatile uint32_t *)(ui32Base + 0x00000008)));
  *pui32RxCount = (ui32CANError & 0x00007F00) >> 8;
  *pui32TxCount = (ui32CANError & 0x000000FF) >> 0;
  if (ui32CANError & 0x00008000) {
    return (true);
  }
  return (false);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CANErrCntrGet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <_CANBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  add    $0x8,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  and    $0x7f,%edx
  mov    %edx,(%r12)
  movzbl %al,%edx
  mov    %edx,0x0(%rbp)
  shr    $0xf,%eax
  and    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool CANErrCntrGet(uint32_t ui32Base, uint32_t *pui32RxCount, uint32_t *pui32TxCount) {
  uint32_t ui32CANError;
  ASSERT(_CANBaseValid(ui32Base));
  ui32CANError = (*((volatile uint32_t *)(ui32Base + 0x00000008)));
  *pui32RxCount = (ui32CANError & 0x00007F00) >> 8;
  *pui32TxCount = (ui32CANError & 0x000000FF) >> 0;
  if (ui32CANError & 0x00008000) {
    return (true);
  }
  return (false);
}
```