ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printIntro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D81
type: string
name: unpack_data
arguments: label: D56
type: string
name: unpack_data
arguments: label: D69
type: string
name: unpack_data
arguments: label: D29
type: string
name: unpack_data
arguments: label: D76
type: string
name: unpack_data
arguments: label: D24
type: string
name: unpack_data
arguments: label: D89
type: string
name: unpack_data
arguments: label: D53
type: string

tool: D81: =========================================


tool: D56: |  |  __         ___            __          


tool: D69: |__| |  | |\  | |     |\    /| |  | |\  |


tool: D29: |  | |__| | \ | | __  | \  / | |__| | \ |


tool: D76: |  | |  | |  \| |___| |  \/  | |  | |  \|


tool: D24: By Aaron Chelvan


tool: D89: 


tool: D53: Guess the word in less than 7 mistakes to win.


assistant: ```c
void printIntro(void) {
  printf("=========================================\n");
  printf("|  |  __         ___            __          \n");
  printf("|__| |  | |\\  | |     |\\    /| |  | |\\  |\n");
  printf("|  | |__| | \\ | | __  | \\  / | |__| | \\ |\n");
  printf("|  | |  | |  \\| |___| |  \\/  | |  | |  \\|\n");
  printf("=========================================\n");
  printf("By Aaron Chelvan\n");
  printf("\n");
  printf("Guess the word in less than 7 mistakes to win.\n");
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printIntro>:
  endbr64
  push   %rbx
  lea    D54(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D72(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D55(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D54
datatype: string
name: parse_data
arguments: tag: D44
datatype: string
name: parse_data
arguments: tag: D42
datatype: string
name: parse_data
arguments: tag: D53
datatype: string
name: parse_data
arguments: tag: D47
datatype: string
name: parse_data
arguments: tag: D15
datatype: string
name: parse_data
arguments: tag: D72
datatype: string
name: parse_data
arguments: tag: D55
datatype: string

tool: D54: =========================================


tool: D44: |  |  __         ___            __          


tool: D42: |__| |  | |\  | |     |\    /| |  | |\  |


tool: D53: |  | |__| | \ | | __  | \  / | |__| | \ |


tool: D47: |  | |  | |  \| |___| |  \/  | |  | |  \|


tool: D15: By Aaron Chelvan


tool: D72: 


tool: D55: Guess the word in less than 7 mistakes to win.


assistant: ```c
void printIntro(void) {
  printf("=========================================\n");
  printf("|  |  __         ___            __          \n");
  printf("|__| |  | |\\  | |     |\\    /| |  | |\\  |\n");
  printf("|  | |__| | \\ | | __  | \\  / | |__| | \\ |\n");
  printf("|  | |  | |  \\| |___| |  \\/  | |  | |  \\|\n");
  printf("=========================================\n");
  printf("By Aaron Chelvan\n");
  printf("\n");
  printf("Guess the word in less than 7 mistakes to win.\n");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printIntro>:
  endbr64
  push   %rbp
  lea    D35(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D9(%rip),%rbp
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D35
type: string
name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D45
type: string
name: unpack_data
arguments: data_tag: D48
type: string
name: unpack_data
arguments: data_tag: D20
type: string
name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D53
type: string
name: unpack_data
arguments: data_tag: D40
type: string

tool: D35: =========================================


tool: D17: |  |  __         ___            __          


tool: D45: |__| |  | |\  | |     |\    /| |  | |\  |


tool: D48: |  | |__| | \ | | __  | \  / | |__| | \ |


tool: D20: |  | |  | |  \| |___| |  \/  | |  | |  \|


tool: D9: 


tool: D53: By Aaron Chelvan


tool: D40: Guess the word in less than 7 mistakes to win.


assistant: ```c
void printIntro(void) {
  printf("=========================================\n");
  printf("|  |  __         ___            __          \n");
  printf("|__| |  | |\\  | |     |\\    /| |  | |\\  |\n");
  printf("|  | |__| | \\ | | __  | \\  / | |__| | \\ |\n");
  printf("|  | |  | |  \\| |___| |  \\/  | |  | |  \\|\n");
  printf("=========================================\n");
  printf("By Aaron Chelvan\n");
  printf("\n");
  printf("Guess the word in less than 7 mistakes to win.\n");
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printIntro>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D17(%rip),%rbp
  call   <printf@plt>
  lea    D71(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D2
type: string
name: retrieve_data
arguments: label: D41
type: string
name: retrieve_data
arguments: label: D34
type: string
name: retrieve_data
arguments: label: D33
type: string
name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D71
type: string
name: retrieve_data
arguments: label: D23
type: string

tool: D29: =========================================


tool: D2: |  |  __         ___            __          


tool: D41: |__| |  | |\  | |     |\    /| |  | |\  |


tool: D34: |  | |__| | \ | | __  | \  / | |__| | \ |


tool: D33: |  | |  | |  \| |___| |  \/  | |  | |  \|


tool: D17: 


tool: D71: By Aaron Chelvan


tool: D23: Guess the word in less than 7 mistakes to win.


assistant: ```c
void printIntro(void) {
  printf("=========================================\n");
  printf("|  |  __         ___            __          \n");
  printf("|__| |  | |\\  | |     |\\    /| |  | |\\  |\n");
  printf("|  | |__| | \\ | | __  | \\  / | |__| | \\ |\n");
  printf("|  | |  | |  \\| |___| |  \\/  | |  | |  \\|\n");
  printf("=========================================\n");
  printf("By Aaron Chelvan\n");
  printf("\n");
  printf("Guess the word in less than 7 mistakes to win.\n");
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Distancia>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8d,-0x40(%rbp)
  mov    %r9d,-0x44(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x40(%rbp),%eax
  imul   $0x2710,%eax,%edx
  mov    -0x3c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x44(%rbp),%eax
  imul   $0x2710,%eax,%edx
  mov    -0x3c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  mov    -0x40(%rbp),%eax
  imul   $0x2710,%eax,%edx
  mov    -0x3c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x44(%rbp),%eax
  imul   $0x2710,%eax,%edx
  mov    -0x3c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  add    %rax,%rbx
  mov    -0x40(%rbp),%eax
  imul   $0x2710,%eax,%edx
  mov    -0x3c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x44(%rbp),%eax
  imul   $0x2710,%eax,%edx
  mov    -0x3c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double Distancia(double *posX, double *posY, double *posZ, int t, int p1, int p2) {
  double d = 0;
  d = sqrt(pow(posX[p1 * 10000 + t] - posX[p2 * 10000 + t], 2) + pow(posY[p1 * 10000 + t] - posY[p2 * 10000 + t], 2) + pow(posZ[p1 * 10000 + t] - posZ[p2 * 10000 + t], 2));
  return d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Distancia>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r14
  mov    %rdx,%r13
  imul   $0x2710,%r8d,%r12d
  add    %ecx,%r12d
  movslq %r12d,%r12
  imul   $0x2710,%r9d,%ebx
  add    %ecx,%ebx
  movslq %ebx,%rbx
  movsd  (%rdi,%r12,8),%xmm0
  subsd  (%rdi,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %rax,%rbp
  movsd  (%r14,%r12,8),%xmm0
  subsd  (%r14,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  add    %rax,%rbp
  movsd  0x0(%r13,%r12,8),%xmm0
  subsd  0x0(%r13,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  lea    0x0(%rbp,%rax,1),%rdi
  call   <sqrt@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double Distancia(double *posX, double *posY, double *posZ, int t, int p1, int p2) {
  double d = 0;
  d = sqrt(pow(posX[p1 * 10000 + t] - posX[p2 * 10000 + t], 2) + pow(posY[p1 * 10000 + t] - posY[p2 * 10000 + t], 2) + pow(posZ[p1 * 10000 + t] - posZ[p2 * 10000 + t], 2));
  return d;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Distancia>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  imul   $0x2710,%r8d,%ebp
  push   %rbx
  imul   $0x2710,%r9d,%ebx
  add    %ecx,%ebp
  add    %ecx,%ebx
  movslq %ebp,%rbp
  movslq %ebx,%rbx
  movsd  (%rdi,%rbp,8),%xmm0
  subsd  (%rdi,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  movsd  0x0(%r13,%rbp,8),%xmm0
  mov    $0x2,%edi
  subsd  0x0(%r13,%rbx,8),%xmm0
  mov    %rax,%r14
  call   <pow@plt>
  movsd  (%r12,%rbp,8),%xmm0
  mov    $0x2,%edi
  subsd  (%r12,%rbx,8),%xmm0
  add    %rax,%r14
  call   <pow@plt>
  pop    %rbx
  pop    %rbp
  lea    (%r14,%rax,1),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double Distancia(double *posX, double *posY, double *posZ, int t, int p1, int p2) {
  double d = 0;
  d = sqrt(pow(posX[p1 * 10000 + t] - posX[p2 * 10000 + t], 2) + pow(posY[p1 * 10000 + t] - posY[p2 * 10000 + t], 2) + pow(posZ[p1 * 10000 + t] - posZ[p2 * 10000 + t], 2));
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Distancia>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  imul   $0x2710,%r8d,%ebp
  push   %rbx
  imul   $0x2710,%r9d,%ebx
  add    %ecx,%ebp
  add    %ecx,%ebx
  movslq %ebp,%rbp
  movslq %ebx,%rbx
  movsd  (%rdi,%rbp,8),%xmm0
  subsd  (%rdi,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  movsd  0x0(%r13,%rbp,8),%xmm0
  mov    $0x2,%edi
  subsd  0x0(%r13,%rbx,8),%xmm0
  mov    %rax,%r14
  call   <pow@plt>
  movsd  (%r12,%rbp,8),%xmm0
  mov    $0x2,%edi
  subsd  (%r12,%rbx,8),%xmm0
  add    %rax,%r14
  call   <pow@plt>
  pop    %rbx
  pop    %rbp
  lea    (%r14,%rax,1),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double Distancia(double *posX, double *posY, double *posZ, int t, int p1, int p2) {
  double d = 0;
  d = sqrt(pow(posX[p1 * 10000 + t] - posX[p2 * 10000 + t], 2) + pow(posY[p1 * 10000 + t] - posY[p2 * 10000 + t], 2) + pow(posZ[p1 * 10000 + t] - posZ[p2 * 10000 + t], 2));
  return d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<build_segment_tree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L17
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L1
L17:
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  lea    0x1(%rax),%edi
  mov    -0x4(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <build_segment_tree>
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <build_segment_tree>
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    -0x2c(%rbp),%ecx
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%rsi
  mov    -0x18(%rbp),%rcx
  add    %rsi,%rcx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,(%rcx)
L1:
  leave
  ret
```

assistant: ```c
void build_segment_tree(int *segment_tree, int *input, int low, int high, int pos) {
  int mid;
  if (low == high) {
    segment_tree[pos] = input[low];
    return;
  }
  mid = (low + high) / 2;
  build_segment_tree(segment_tree, input, low, mid, (2 * pos + 1));
  build_segment_tree(segment_tree, input, mid + 1, high, (2 * pos + 2));
  segment_tree[pos] = ((segment_tree[2 * pos + 1]) > (segment_tree[2 * pos + 2]) ? (segment_tree[2 * pos + 1]) : (segment_tree[2 * pos + 2]));
}
```
user: Translate the below assembly code into C programming language:

```asm
<build_segment_tree>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %r8d,%ebx
  cmp    %ecx,%edx
  je     L15
  mov    %ecx,%r13d
  lea    (%rdx,%rcx,1),%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  lea    (%r8,%r8,1),%r15d
  lea    0x1(%r15),%r8d
  mov    %r12d,%ecx
  call   <build_segment_tree>
  lea    0x1(%r12),%edx
  lea    0x2(%r15),%r8d
  mov    %r13d,%ecx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <build_segment_tree>
  movslq %r15d,%r15
  movslq %ebx,%rbx
  mov    0x8(%rbp,%r15,4),%eax
  mov    0x4(%rbp,%r15,4),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  movslq %edx,%rdx
  mov    (%rsi,%rdx,4),%eax
  movslq %r8d,%rbx
  mov    %eax,(%rdi,%rbx,4)
  jmp    L14
```

assistant: ```c
void build_segment_tree(int *segment_tree, int *input, int low, int high, int pos) {
  int mid;
  if (low == high) {
    segment_tree[pos] = input[low];
    return;
  }
  mid = (low + high) / 2;
  build_segment_tree(segment_tree, input, low, mid, (2 * pos + 1));
  build_segment_tree(segment_tree, input, mid + 1, high, (2 * pos + 2));
  segment_tree[pos] = ((segment_tree[2 * pos + 1]) > (segment_tree[2 * pos + 2]) ? (segment_tree[2 * pos + 1]) : (segment_tree[2 * pos + 2]));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<build_segment_tree>:
  endbr64
  push   %r15
  movslq %r8d,%rax
  mov    %rsi,%r15
  push   %r14
  lea    (%rdi,%rax,4),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %ecx,%edx
  je     L4
  lea    (%rdx,%rcx,1),%eax
  lea    (%r8,%r8,1),%r13d
  mov    %rdi,%rbx
  mov    %ecx,%r12d
  mov    %eax,%ebp
  lea    0x1(%r13),%r8d
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  mov    %ebp,%ecx
  call   <build_segment_tree>
  lea    0x1(%rbp),%edx
  lea    0x2(%r13),%r8d
  mov    %r12d,%ecx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <build_segment_tree>
  movslq %r13d,%r8
  mov    0x8(%rbx,%r8,4),%eax
  mov    0x4(%rbx,%r8,4),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
L1:
  mov    %eax,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movslq %edx,%rdx
  mov    (%rsi,%rdx,4),%eax
  jmp    L1
```

assistant: ```c
void build_segment_tree(int *segment_tree, int *input, int low, int high, int pos) {
  int mid;
  if (low == high) {
    segment_tree[pos] = input[low];
    return;
  }
  mid = (low + high) / 2;
  build_segment_tree(segment_tree, input, low, mid, (2 * pos + 1));
  build_segment_tree(segment_tree, input, mid + 1, high, (2 * pos + 2));
  segment_tree[pos] = ((segment_tree[2 * pos + 1]) > (segment_tree[2 * pos + 2]) ? (segment_tree[2 * pos + 1]) : (segment_tree[2 * pos + 2]));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfb4(%rbp)
  jmp    L9
L16:
  mov    -0xfb4(%rbp),%eax
  add    $0x64,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfb4(%rbp)
L9:
  cmpl   $0x64,-0xfb4(%rbp)
  jle    L16
  mov    -0xf80(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  int x[1000];
  for (i = 0; i < 101; i++)
    x[i] = x[i + 100];
  return x[12];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x194(%rsp),%rcx
L7:
  mov    0x190(%rax),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L7
  mov    0x30(%rsp),%eax
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0xfb8,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int i;
  int x[1000];
  for (i = 0; i < 101; i++)
    x[i] = x[i + 100];
  return x[12];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    $0x194,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x190(%rsp),%rsi
  call   <memmove@plt>
  mov    0x30(%rsp),%eax
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0xfb8,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int i;
  int x[1000];
  for (i = 0; i < 101; i++)
    x[i] = x[i + 100];
  return x[12];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    $0x194,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x190(%rsp),%rsi
  call   <memmove@plt>
  mov    0x30(%rsp),%eax
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0xfb8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int i;
  int x[1000];
  for (i = 0; i < 101; i++)
    x[i] = x[i + 100];
  return x[12];
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_for_valid_filename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L49:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jle    L82
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x21,%al
  jle    L24
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jle    L82
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L59
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L82
L59:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L82
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  je     L82
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7f,%al
  jne    L27
L82:
  mov    $0xfffff82f,%eax
  jmp    L1
L27:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L49
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int check_for_valid_filename(const char *data_string, const int length) {
  int temp_count;
  for (temp_count = 0; temp_count < length; temp_count++) {
    if ((*(data_string + temp_count) < 32) || (((*(data_string + temp_count)) > 33) && ((*(data_string + temp_count)) < 43)) || (((*(data_string + temp_count)) > 57) && ((*(data_string + temp_count)) < 65)) || (*(data_string + temp_count) == 92) || (*(data_string + temp_count) == 124) || (*(data_string + temp_count) > 126))
      return -2001;
  }
  return -0;
}
```