ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<split_paragraphs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  lea    0xc(%rsp),%rdi
  mov    $0x0,%edx
  lea    D18(%rip),%rsi
  call   <regcomp@plt>
  mov    $0x0,%r12d
  lea    D17(%rip),%r15
  jmp    L31
L44:
  mov    %r12d,%eax
  add    0x10(%rsp),%eax
  cltq
  movb   $0x0,(%r14,%rax,1)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x4(%r13,%rax,1),%rsi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  add    0x18(%rsp),%r12d
L31:
  movslq %r12d,%rbp
  add    %r14,%rbp
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdi
  mov    $0x0,%r8d
  mov    $0x1,%edx
  mov    %rbp,%rsi
  call   <regexec@plt>
  test   %eax,%eax
  je     L44
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jg     L45
L0:
  lea    0xc(%rsp),%rdi
  call   <regfree@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    %rbx,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rsi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L0
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string

tool: D18: 
\s*


tool: D17: 
<p>

assistant: ```c
char *split_paragraphs(char *string) {
  char *p = "\n<p>";
  char *out = calloc(1, 1);
  regex_t regex;
  regcomp(&regex, "\n\\s*\n", 0);
  regmatch_t matches[1];
  int start = 0;
  while (!regexec(&regex, string + start, 1, matches, 0)) {
    string[start + matches[0].rm_so] = 0;
    out = realloc(out, strlen(out) + strlen(string + start) + strlen(p));
    strcat(out, string + start);
    strcat(out, p);
    start += matches[0].rm_eo;
  }
  if (strlen(string + start) > 0) {
    out = realloc(out, strlen(out) + strlen(string + start) + 1);
    strcat(out, string + start);
  }
  regfree(&regex);
  free(string);
  return out;
}
```
user: Translate the below assembly code into C programming language:

```asm
<split_paragraphs>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%r14
  call   <calloc@plt>
  xor    %edx,%edx
  lea    D3(%rip),%rsi
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <regcomp@plt>
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x20(%rsp),%eax
  mov    %rbp,%rdi
  add    %ebx,%eax
  cltq
  movb   $0x0,0x0(%r13,%rax,1)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x4(%r15,%rax,1),%rsi
  call   <realloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    0x28(%rsp),%ebx
L38:
  movslq %ebx,%r12
  mov    0x8(%rsp),%rcx
  xor    %r8d,%r8d
  mov    $0x1,%edx
  add    %r13,%r12
  mov    %r14,%rdi
  mov    %r12,%rsi
  call   <regexec@plt>
  test   %eax,%eax
  je     L29
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L20
L32:
  mov    %r14,%rdi
  call   <regfree@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x48,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rbx,%rax,1),%rsi
  call   <realloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcat@plt>
  jmp    L32
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string
name: read_data
arguments: data_label: D13
data_type: string

tool: D3: 
\s*


tool: D13: 
<p>

assistant: ```c
char *split_paragraphs(char *string) {
  char *p = "\n<p>";
  char *out = calloc(1, 1);
  regex_t regex;
  regcomp(&regex, "\n\\s*\n", 0);
  regmatch_t matches[1];
  int start = 0;
  while (!regexec(&regex, string + start, 1, matches, 0)) {
    string[start + matches[0].rm_so] = 0;
    out = realloc(out, strlen(out) + strlen(string + start) + strlen(p));
    strcat(out, string + start);
    strcat(out, p);
    start += matches[0].rm_eo;
  }
  if (strlen(string + start) > 0) {
    out = realloc(out, strlen(out) + strlen(string + start) + 1);
    strcat(out, string + start);
  }
  regfree(&regex);
  free(string);
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<split_paragraphs>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%r14
  call   <calloc@plt>
  xor    %edx,%edx
  lea    D8(%rip),%rsi
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <regcomp@plt>
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x20(%rsp),%eax
  mov    %rbp,%rdi
  add    %ebx,%eax
  cltq
  movb   $0x0,0x0(%r13,%rax,1)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x4(%r15,%rax,1),%rsi
  call   <realloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    0x28(%rsp),%ebx
L14:
  movslq %ebx,%r12
  mov    0x8(%rsp),%rcx
  xor    %r8d,%r8d
  mov    $0x1,%edx
  add    %r13,%r12
  mov    %r14,%rdi
  mov    %r12,%rsi
  call   <regexec@plt>
  test   %eax,%eax
  je     L27
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L20
L19:
  mov    %r14,%rdi
  call   <regfree@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x48,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rbx,%rax,1),%rsi
  call   <realloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcat@plt>
  jmp    L19
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D4
datatype: string

tool: D8: 
\s*


tool: D4: 
<p>

assistant: ```c
char *split_paragraphs(char *string) {
  char *p = "\n<p>";
  char *out = calloc(1, 1);
  regex_t regex;
  regcomp(&regex, "\n\\s*\n", 0);
  regmatch_t matches[1];
  int start = 0;
  while (!regexec(&regex, string + start, 1, matches, 0)) {
    string[start + matches[0].rm_so] = 0;
    out = realloc(out, strlen(out) + strlen(string + start) + strlen(p));
    strcat(out, string + start);
    strcat(out, p);
    start += matches[0].rm_eo;
  }
  if (strlen(string + start) > 0) {
    out = realloc(out, strlen(out) + strlen(string + start) + 1);
    strcat(out, string + start);
  }
  regfree(&regex);
  free(string);
  return out;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<interpret_post_turing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x14,%edi
  call   <display_tape@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L72:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  je     L96
  cmp    $0x2,%eax
  jg     L65
  test   %eax,%eax
  je     L71
  cmp    $0x1,%eax
  je     L64
  jmp    L65
L71:
  mov    $0x0,%eax
  call   <Right@plt>
  jmp    L103
L64:
  mov    $0x0,%eax
  call   <Left@plt>
  jmp    L103
L96:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    0x4(%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <Print@plt>
  jmp    L103
L65:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    0x4(%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    $0x2,%eax
  movsbl %al,%eax
  lea    -0xc(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Cond@plt>
  nop
L103:
  mov    $0x14,%edi
  call   <display_tape@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jg     L72
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
void interpret_post_turing(int line, int code[1024][2]) {
  int instruction;
  display_tape(20);
  for (instruction = 0; instruction < line; instruction++) {
    switch (code[instruction][0]) {
    case 0:
      Right();
      break;
    case 1:
      Left();
      break;
    case 2:
      Print((char)code[instruction][1]);
      break;
    default:
      Cond((char)(code[instruction][0] - 2), code[instruction][1], &instruction);
      break;
    }
    display_tape(20);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<interpret_post_turing>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x14,%edi
  call   <display_tape@plt>
  movl   $0x0,0x4(%rsp)
  test   %ebx,%ebx
  jle    L91
  mov    $0x0,%eax
  lea    0x4(%rsp),%r12
  jmp    L21
L27:
  mov    $0x0,%eax
  call   <Right@plt>
L54:
  mov    $0x14,%edi
  call   <display_tape@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    %ebx,%eax
  jge    L91
L21:
  cltq
  lea    0x0(%rbp,%rax,8),%rax
  mov    (%rax),%edi
  cmp    $0x1,%edi
  je     L2
  cmp    $0x2,%edi
  je     L99
  test   %edi,%edi
  je     L27
  mov    0x4(%rax),%esi
  sub    $0x2,%edi
  movsbl %dil,%edi
  mov    %r12,%rdx
  call   <Cond@plt>
  jmp    L54
L2:
  mov    $0x0,%eax
  call   <Left@plt>
  jmp    L54
L99:
  movsbl 0x4(%rax),%edi
  call   <Print@plt>
  jmp    L54
L91:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void interpret_post_turing(int line, int code[1024][2]) {
  int instruction;
  display_tape(20);
  for (instruction = 0; instruction < line; instruction++) {
    switch (code[instruction][0]) {
    case 0:
      Right();
      break;
    case 1:
      Left();
      break;
    case 2:
      Print((char)code[instruction][1]);
      break;
    default:
      Cond((char)(code[instruction][0] - 2), code[instruction][1], &instruction);
      break;
    }
    display_tape(20);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<interpret_post_turing>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x14,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <display_tape@plt>
  movl   $0x0,0x4(%rsp)
  test   %ebx,%ebx
  jle    L28
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L82
L87:
  test   %edi,%edi
  je     L38
  sub    $0x2,%edi
  mov    0x4(%rax),%esi
  mov    %r12,%rdx
  movsbl %dil,%edi
  call   <Cond@plt>
L25:
  mov    $0x14,%edi
  call   <display_tape@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    %ebx,%eax
  jge    L28
L82:
  cltq
  lea    0x0(%rbp,%rax,8),%rax
  mov    (%rax),%edi
  cmp    $0x1,%edi
  je     L32
  cmp    $0x2,%edi
  jne    L87
  movsbl 0x4(%rax),%edi
  call   <Print@plt>
  jmp    L25
  nopl   (%rax)
L32:
  xor    %eax,%eax
  call   <Left@plt>
  jmp    L25
  nopl   0x0(%rax)
L38:
  xor    %eax,%eax
  call   <Right@plt>
  jmp    L25
  nopl   0x0(%rax)
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L95:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void interpret_post_turing(int line, int code[1024][2]) {
  int instruction;
  display_tape(20);
  for (instruction = 0; instruction < line; instruction++) {
    switch (code[instruction][0]) {
    case 0:
      Right();
      break;
    case 1:
      Left();
      break;
    case 2:
      Print((char)code[instruction][1]);
      break;
    default:
      Cond((char)(code[instruction][0] - 2), code[instruction][1], &instruction);
      break;
    }
    display_tape(20);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<interpret_post_turing>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x14,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <display_tape@plt>
  movl   $0x0,0x4(%rsp)
  test   %ebx,%ebx
  jle    L95
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L59
L84:
  test   %edi,%edi
  je     L94
  sub    $0x2,%edi
  mov    0x4(%rax),%esi
  mov    %r12,%rdx
  movsbl %dil,%edi
  call   <Cond@plt>
L21:
  mov    $0x14,%edi
  call   <display_tape@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    %ebx,%eax
  jge    L95
L59:
  cltq
  lea    0x0(%rbp,%rax,8),%rax
  mov    (%rax),%edi
  cmp    $0x1,%edi
  je     L64
  cmp    $0x2,%edi
  jne    L84
  movsbl 0x4(%rax),%edi
  call   <Print@plt>
  jmp    L21
  nopl   (%rax)
L64:
  xor    %eax,%eax
  call   <Left@plt>
  jmp    L21
  nopl   0x0(%rax)
L94:
  xor    %eax,%eax
  call   <Right@plt>
  jmp    L21
  nopl   0x0(%rax)
L95:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L99:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void interpret_post_turing(int line, int code[1024][2]) {
  int instruction;
  display_tape(20);
  for (instruction = 0; instruction < line; instruction++) {
    switch (code[instruction][0]) {
    case 0:
      Right();
      break;
    case 1:
      Left();
      break;
    case 2:
      Print((char)code[instruction][1]);
      break;
    default:
      Cond((char)(code[instruction][0] - 2), code[instruction][1], &instruction);
      break;
    }
    display_tape(20);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<led_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x3f200000,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  or     $0x200000,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
volatile unsigned int *led_init() {
  volatile unsigned int *gpio = (unsigned int *)0x3F200000;
  gpio[4] |= (1 << 21);
  return gpio;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<led_init>:
  endbr64
  mov    0x3f200010,%eax
  or     $0x200000,%eax
  mov    %eax,0x3f200010
  mov    $0x3f200000,%eax
  ret
```

assistant: ```c
volatile unsigned int *led_init() {
  volatile unsigned int *gpio = (unsigned int *)0x3F200000;
  gpio[4] |= (1 << 21);
  return gpio;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<led_init>:
  endbr64
  mov    0x3f200010,%eax
  or     $0x200000,%eax
  mov    %eax,0x3f200010
  mov    $0x3f200000,%eax
  ret
```

assistant: ```c
volatile unsigned int *led_init() {
  volatile unsigned int *gpio = (unsigned int *)0x3F200000;
  gpio[4] |= (1 << 21);
  return gpio;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<led_init>:
  endbr64
  mov    0x3f200010,%eax
  or     $0x200000,%eax
  mov    %eax,0x3f200010
  mov    $0x3f200000,%eax
  ret
```

assistant: ```c
volatile unsigned int *led_init() {
  volatile unsigned int *gpio = (unsigned int *)0x3F200000;
  gpio[4] |= (1 << 21);
  return gpio;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memory_equal_display_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L18
L42:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movzbl -0xe(%rbp),%eax
  cmp    -0xd(%rbp),%al
  je     L7
  movsbl -0xd(%rbp),%edx
  movsbl -0xe(%rbp),%eax
  mov    -0x8(%rbp),%rcx
  mov    %ecx,%esi
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <cm_print_error@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L42
  cmpl   $0x0,-0xc(%rbp)
  je     L17
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <cm_print_error@plt>
  mov    $0x0,%eax
  jmp    L6
L17:
  mov    $0x1,%eax
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D4
type: string

tool: D19: difference at offset %zd 0x%02x 0x%02x


tool: D4: %d bytes of %s and %s differ


assistant: ```c
int memory_equal_display_error(const char *const a, const char *const b, const size_t size) {
  int differences = 0;
  size_t i;
  for (i = 0; i < size; i++) {
    const char l = a[i];
    const char r = b[i];
    if (l != r) {
      cm_print_error("difference at offset %"
                     "zd"
                     " 0x%02x 0x%02x\n",
                     i, l, r);
      differences++;
    }
  }
  if (differences) {
    cm_print_error("%d bytes of %s and %s differ\n", differences, a, b);
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memory_equal_display_error>:
  endbr64
  test   %rdx,%rdx
  je     L2
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  lea    D3(%rip),%r15
  jmp    L63
L56:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L43
L63:
  movzbl (%r12,%rbx,1),%edx
  movzbl 0x0(%r13,%rbx,1),%ecx
  cmp    %cl,%dl
  je     L56
  movsbl %cl,%ecx
  movsbl %dl,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <cm_print_error@plt>
  add    $0x1,%r14d
  jmp    L56
L43:
  mov    $0x1,%eax
  test   %r14d,%r14d
  jne    L55
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14d,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <cm_print_error@plt>
  mov    $0x0,%eax
  jmp    L10
L2:
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string

tool: D3: difference at offset %zd 0x%02x 0x%02x


tool: D14: %d bytes of %s and %s differ


assistant: ```c
int memory_equal_display_error(const char *const a, const char *const b, const size_t size) {
  int differences = 0;
  size_t i;
  for (i = 0; i < size; i++) {
    const char l = a[i];
    const char r = b[i];
    if (l != r) {
      cm_print_error("difference at offset %"
                     "zd"
                     " 0x%02x 0x%02x\n",
                     i, l, r);
      differences++;
    }
  }
  if (differences) {
    cm_print_error("%d bytes of %s and %s differ\n", differences, a, b);
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memory_equal_display_error>:
  endbr64
  test   %rdx,%rdx
  je     L18
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L16:
  movsbl 0x0(%r13,%rbx,1),%edx
  movsbl (%r14,%rbx,1),%ecx
  cmp    %cl,%dl
  je     L20
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <cm_print_error@plt>
L20:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L16
  mov    $0x1,%eax
  test   %r15d,%r15d
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r15d,%esi
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <cm_print_error@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    $0x1,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string

tool: D3: difference at offset %zd 0x%02x 0x%02x


tool: D12: %d bytes of %s and %s differ


assistant: ```c
int memory_equal_display_error(const char *const a, const char *const b, const size_t size) {
  int differences = 0;
  size_t i;
  for (i = 0; i < size; i++) {
    const char l = a[i];
    const char r = b[i];
    if (l != r) {
      cm_print_error("difference at offset %"
                     "zd"
                     " 0x%02x 0x%02x\n",
                     i, l, r);
      differences++;
    }
  }
  if (differences) {
    cm_print_error("%d bytes of %s and %s differ\n", differences, a, b);
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<memory_equal_display_error>:
  endbr64
  test   %rdx,%rdx
  je     L10
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L15:
  movsbl 0x0(%r13,%rbx,1),%edx
  movsbl (%r14,%rbx,1),%ecx
  cmp    %cl,%dl
  je     L4
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <cm_print_error@plt>
L4:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L15
  mov    $0x1,%eax
  test   %r15d,%r15d
  jne    L38
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L38:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r15d,%esi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <cm_print_error@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    $0x1,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D13
datatype: string
name: read_data
arguments: label: D10
datatype: string

tool: D13: difference at offset %zd 0x%02x 0x%02x


tool: D10: %d bytes of %s and %s differ


assistant: ```c
int memory_equal_display_error(const char *const a, const char *const b, const size_t size) {
  int differences = 0;
  size_t i;
  for (i = 0; i < size; i++) {
    const char l = a[i];
    const char r = b[i];
    if (l != r) {
      cm_print_error("difference at offset %"
                     "zd"
                     " 0x%02x 0x%02x\n",
                     i, l, r);
      differences++;
    }
  }
  if (differences) {
    cm_print_error("%d bytes of %s and %s differ\n", differences, a, b);
    return 0;
  }
  return 1;
}
```