ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getMaxElement>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rdx
  mov    %esi,%ecx
  cmp    $0x1,%esi
  jle    L34
  lea    -0x1(%rsi),%edi
  lea    -0x2(%rsi),%esi
  cmp    $0x2,%esi
  jbe    L67
  mov    %edi,%esi
  movd   %eax,%xmm3
  lea    0x4(%rdx),%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm3,%xmm0
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x14(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax)
L21:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm2
  pcmpgtd %xmm0,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  por    %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L21
  movdqa %xmm0,%xmm2
  mov    %edi,%r8d
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%r8d
  movdqa %xmm2,%xmm1
  lea    0x1(%r8),%esi
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    %r8d,%edi
  je     L63
L62:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r8
  mov    (%rdx,%rdi,4),%edi
  cmp    %edi,%eax
  cmovl  %edi,%eax
  lea    0x1(%rsi),%edi
  cmp    %edi,%ecx
  jle    L34
  mov    0x4(%rdx,%r8,1),%edi
  cmp    %edi,%eax
  cmovl  %edi,%eax
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L34
  mov    0x8(%rdx,%r8,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
L34:
  ret
  nopl   0x0(%rax)
L63:
  ret
L67:
  mov    $0x1,%esi
  jmp    L62
```

assistant: ```c
int getMaxElement(int array[], int size) {
  int max = array[0];
  for (int i = 1; i < size; i++) {
    if (array[i] > max) {
      max = array[i];
    }
  }
  return max;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stdlib_strided_dnannsumpw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sumpw@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double stdlib_strided_dnannsumpw(const int64_t N, const double *X, const int64_t stride, int64_t *n) {
  *n = 0;
  return sumpw(N, X, stride, n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stdlib_strided_dnannsumpw>:
  endbr64
  sub    $0x8,%rsp
  movq   $0x0,(%rcx)
  call   <sumpw@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double stdlib_strided_dnannsumpw(const int64_t N, const double *X, const int64_t stride, int64_t *n) {
  *n = 0;
  return sumpw(N, X, stride, n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stdlib_strided_dnannsumpw>:
  endbr64
  movq   $0x0,(%rcx)
  jmp    1050 <sumpw@plt>
```

assistant: ```c
double stdlib_strided_dnannsumpw(const int64_t N, const double *X, const int64_t stride, int64_t *n) {
  *n = 0;
  return sumpw(N, X, stride, n);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_sha1_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x6665646362613938,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movb   $0x0,-0x18(%rbp)
  movl   $0x0,-0x54(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L21
L17:
  mov    -0x54(%rbp),%edx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x54(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  movslq %edx,%rax
  movzbl -0x50(%rbp,%rax,1),%eax
  mov    %ecx,%edx
  mov    %al,-0x40(%rbp,%rdx,1)
  mov    -0x54(%rbp),%edx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x54(%rbp),%eax
  add    %eax,%eax
  lea    0x1(%rax),%ecx
  movslq %edx,%rax
  movzbl -0x50(%rbp,%rax,1),%eax
  mov    %ecx,%edx
  mov    %al,-0x40(%rbp,%rdx,1)
  addl   $0x1,-0x54(%rbp)
L21:
  cmpl   $0x13,-0x54(%rbp)
  jbe    L17
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <eina_stringshare_add@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
const char *_sha1_to_string(const unsigned char *hashout) {
  const char hextab[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  char sha1[41] = {0};
  unsigned int i = 0;
  for (i = 0; i < 20; i++) {
    sha1[2 * i] = hextab[(hashout[i] >> 4) & 0x0f];
    sha1[2 * i + 1] = hextab[hashout[i] & 0x0f];
  }
  return eina_stringshare_add(sha1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_sha1_to_string>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x6665646362613938,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movb   $0x0,0x38(%rsp)
  lea    0x11(%rsp),%rax
  lea    0x39(%rsp),%rsi
L16:
  movzbl (%rdi),%edx
  mov    %edx,%ecx
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,-0x1(%rax)
  and    $0xf,%edx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rdi
  add    $0x2,%rax
  cmp    %rsi,%rax
  jne    L16
  lea    0x10(%rsp),%rdi
  call   <eina_stringshare_add@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x58,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *_sha1_to_string(const unsigned char *hashout) {
  const char hextab[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  char sha1[41] = {0};
  unsigned int i = 0;
  for (i = 0; i < 20; i++) {
    sha1[2 * i] = hextab[(hashout[i] >> 4) & 0x0f];
    sha1[2 * i + 1] = hextab[hashout[i] & 0x0f];
  }
  return eina_stringshare_add(sha1);
}
```
user: What is the c source code of the assembly code below?

```asm
<_sha1_to_string>:
  endbr64
  sub    $0x58,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x38(%rsp)
  lea    0x11(%rsp),%rax
  lea    0x39(%rsp),%rsi
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl (%rdi),%edx
  add    $0x2,%rax
  add    $0x1,%rdi
  mov    %edx,%ecx
  and    $0xf,%edx
  shr    $0x4,%cl
  movzbl (%rsp,%rdx,1),%edx
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %dl,-0x2(%rax)
  mov    %cl,-0x3(%rax)
  cmp    %rax,%rsi
  jne    L17
  lea    0x10(%rsp),%rdi
  call   <eina_stringshare_add@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x58,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: byte[16]

tool: {"D4": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x61,0x62,0x63,0x64,0x65,0x66]}

assistant: ```c
const char *_sha1_to_string(const unsigned char *hashout) {
  const char hextab[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  char sha1[41] = {0};
  unsigned int i = 0;
  for (i = 0; i < 20; i++) {
    sha1[2 * i] = hextab[(hashout[i] >> 4) & 0x0f];
    sha1[2 * i + 1] = hextab[hashout[i] & 0x0f];
  }
  return eina_stringshare_add(sha1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_sha1_to_string>:
  endbr64
  sub    $0x58,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x38(%rsp)
  lea    0x10(%rsp),%r8
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  nopl   (%rax)
L18:
  movzbl (%rdi,%rax,1),%edx
  xor    %ecx,%ecx
  mov    %edx,%esi
  and    $0xf,%edx
  shr    $0x4,%sil
  and    $0xf,%esi
  mov    (%rsp,%rsi,1),%cl
  mov    (%rsp,%rdx,1),%ch
  mov    %cx,(%r8,%rax,2)
  add    $0x1,%rax
  cmp    $0x14,%rax
  jne    L18
  mov    %r8,%rdi
  call   <eina_stringshare_add@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type: byte[16]

tool: {"D9": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x61,0x62,0x63,0x64,0x65,0x66]}

assistant: ```c
const char *_sha1_to_string(const unsigned char *hashout) {
  const char hextab[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  char sha1[41] = {0};
  unsigned int i = 0;
  for (i = 0; i < 20; i++) {
    sha1[2 * i] = hextab[(hashout[i] >> 4) & 0x0f];
    sha1[2 * i + 1] = hextab[hashout[i] & 0x0f];
  }
  return eina_stringshare_add(sha1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrop3_125_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  notl   -0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_125_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T ^ S;
  stk2 = ~stk2;
  stk1 = D & stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xrop3_125_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  xor    %edx,%eax
  or     $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_125_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T ^ S;
  stk2 = ~stk2;
  stk1 = D & stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_125_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %edi,%eax
  or     %esi,%edx
  xor    %edx,%eax
  or     $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_125_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T ^ S;
  stk2 = ~stk2;
  stk1 = D & stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_125_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %edi,%eax
  or     %esi,%edx
  xor    %edx,%eax
  or     $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_125_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T ^ S;
  stk2 = ~stk2;
  stk1 = D & stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L16:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  sub    %rdx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jg     L16
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *reverse_endian(long length, unsigned char *buffer) {
  unsigned char *temp = calloc(1, sizeof(char) * length);
  int i;
  for (i = 0; i < length; i++) {
    temp[i] = buffer[length - i - 1];
  }
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<reverse_endian>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  test   %rbp,%rbp
  jle    L4
  lea    -0x1(%rbx,%rbp,1),%rdx
  mov    %rax,%rcx
L10:
  movzbl (%rdx),%esi
  mov    %sil,(%rcx)
  mov    %rdx,%rsi
  sub    $0x1,%rdx
  add    $0x1,%rcx
  cmp    %rbx,%rsi
  jne    L10
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *reverse_endian(long length, unsigned char *buffer) {
  unsigned char *temp = calloc(1, sizeof(char) * length);
  int i;
  for (i = 0; i < length; i++) {
    temp[i] = buffer[length - i - 1];
  }
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverse_endian>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %rbp,%rbp
  jle    L18
  lea    -0x1(%rbx,%rbp,1),%rdx
  mov    %rax,%rcx
  nopl   0x0(%rax)
L11:
  movzbl (%rdx),%esi
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  mov    %rdx,%rsi
  sub    $0x1,%rdx
  cmp    %rbx,%rsi
  jne    L11
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *reverse_endian(long length, unsigned char *buffer) {
  unsigned char *temp = calloc(1, sizeof(char) * length);
  int i;
  for (i = 0; i < length; i++) {
    temp[i] = buffer[length - i - 1];
  }
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse_endian>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %rbp,%rbp
  jle    L13
  lea    -0x1(%rbx,%rbp,1),%rdx
  mov    %rax,%rcx
  nopl   0x0(%rax)
L6:
  movzbl (%rdx),%esi
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  mov    %rdx,%rsi
  sub    $0x1,%rdx
  cmp    %rsi,%rbx
  jne    L6
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *reverse_endian(long length, unsigned char *buffer) {
  unsigned char *temp = calloc(1, sizeof(char) * length);
  int i;
  for (i = 0; i < length; i++) {
    temp[i] = buffer[length - i - 1];
  }
  return temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L16:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L16
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x6(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x6(%rbp),%eax
  movzbl -0x5(%rbp),%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  unsigned char us1;
  unsigned char us2;
  int i;
  i = 0;
  while (s1[i] && s2[i] && s1[i] == s2[i])
    i++;
  us1 = s1[i];
  us2 = s2[i];
  return (us1 - us2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x0,%edx
  test   %al,%al
  je     L36
L20:
  movzbl (%rsi,%rdx,1),%ecx
  cmp    %al,%cl
  jne    L36
  test   %cl,%cl
  je     L36
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L20
L36:
  movzbl %al,%eax
  movzbl (%rsi,%rdx,1),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  unsigned char us1;
  unsigned char us2;
  int i;
  i = 0;
  while (s1[i] && s2[i] && s1[i] == s2[i])
    i++;
  us1 = s1[i];
  us2 = s2[i];
  return (us1 - us2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  xor    %edx,%edx
  test   %al,%al
  jne    L27
  jmp    L51
  nop
L44:
  test   %cl,%cl
  je     L38
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L26
L27:
  movzbl (%rsi,%rdx,1),%ecx
  cmp    %al,%cl
  je     L44
L38:
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  movzbl (%rsi,%rdx,1),%ecx
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
L51:
  movzbl (%rsi),%ecx
  xor    %eax,%eax
  jmp    L38
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  unsigned char us1;
  unsigned char us2;
  int i;
  i = 0;
  while (s1[i] && s2[i] && s1[i] == s2[i])
    i++;
  us1 = s1[i];
  us2 = s2[i];
  return (us1 - us2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  xor    %edx,%edx
  test   %al,%al
  jne    L12
  jmp    L11
  nop
L35:
  test   %cl,%cl
  je     L33
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L31
L12:
  movzbl (%rsi,%rdx,1),%ecx
  cmp    %al,%cl
  je     L35
L33:
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  movzbl (%rsi,%rdx,1),%ecx
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
L11:
  movzbl (%rsi),%ecx
  xor    %eax,%eax
  jmp    L33
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  unsigned char us1;
  unsigned char us2;
  int i;
  i = 0;
  while (s1[i] && s2[i] && s1[i] == s2[i])
    i++;
  us1 = s1[i];
  us2 = s2[i];
  return (us1 - us2);
}
```
user: What is the c source code of the assembly code below:

```asm
<tcgetsid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  jns    L24
  mov    $0xffffffff,%eax
  jmp    L20
L24:
  mov    -0xc(%rbp),%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
pid_t tcgetsid(int fd) {
  int sid;
  if (ioctl(fd, TIOCGSID, &sid) < 0)
    return -1;
  return sid;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tcgetsid>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L9
  mov    0x4(%rsp),%eax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L15
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
pid_t tcgetsid(int fd) {
  int sid;
  if (ioctl(fd, TIOCGSID, &sid) < 0)
    return -1;
  return sid;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tcgetsid>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L15
  mov    0x4(%rsp),%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L0
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
pid_t tcgetsid(int fd) {
  int sid;
  if (ioctl(fd, TIOCGSID, &sid) < 0)
    return -1;
  return sid;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tcgetsid>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L3
  mov    0x4(%rsp),%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L0
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
pid_t tcgetsid(int fd) {
  int sid;
  if (ioctl(fd, TIOCGSID, &sid) < 0)
    return -1;
  return sid;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <solveKT@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  solveKT();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <solveKT@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  solveKT();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <solveKT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  solveKT();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <solveKT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  solveKT();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x47,%eax
  cmp    $0x26,%eax
  seta   %dl
  test   %dl,%dl
  jne    L58
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  movabs $0x100000001,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L39
  movabs $0x4000000040,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L32
  movabs $0x1000000010,%rdx
  and    %rdx,%rax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L58
  shll   $0xa,-0x14(%rbp)
  jmp    L58
L32:
  shll   $0x14,-0x14(%rbp)
  jmp    L58
L39:
  shll   $0x1e,-0x14(%rbp)
  nop
L58:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int parse_size(const char *size) {
  int value;
  char *end;
  value = strtol(size, &end, 10);
  switch (*end) {
  case 'k':
  case 'K':
    value *= 1024;
    break;
  case 'm':
  case 'M':
    value *= 1024 * 1024;
    break;
  case 'g':
  case 'G':
    value *= 1024 * 1024 * 1024;
    break;
  }
  return value;
}
```