ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<anerd_salt>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmpl   $0x0,D1(%rip)
  je     L8
L15:
  mov    $0x0,%eax
  call   <random@plt>
  xor    %ebx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x30,%rsp
  pop    %rbx
  ret
L8:
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x10(%rsp),%edi
  movslq %edi,%rdi
  add    0x18(%rsp),%rdi
  call   <srandom@plt>
  addl   $0x1,D1(%rip)
  jmp    L15
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t anerd_salt(uint64_t salt) {
  struct timeval tv;
  struct timezone tz;
  static int init = 0;
  if (!init) {
    gettimeofday(&tv, &tz);
    srandom(1000000 * tv.tv_sec + tv.tv_usec);
    init++;
  }
  salt ^= random();
  return salt;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<anerd_salt>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%eax
  test   %eax,%eax
  je     L22
L27:
  xor    %eax,%eax
  call   <random@plt>
  xor    %ebx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x30,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L22:
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x10(%rsp),%edi
  movslq %edi,%rdi
  add    0x18(%rsp),%rdi
  call   <srandom@plt>
  addl   $0x1,D12(%rip)
  jmp    L27
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t anerd_salt(uint64_t salt) {
  struct timeval tv;
  struct timezone tz;
  static int init = 0;
  if (!init) {
    gettimeofday(&tv, &tz);
    srandom(1000000 * tv.tv_sec + tv.tv_usec);
    init++;
  }
  salt ^= random();
  return salt;
}
```
user: What is the c source code of the assembly code below?

```asm
<anerd_salt>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%eax
  test   %eax,%eax
  je     L3
L25:
  xor    %eax,%eax
  call   <random@plt>
  xor    %ebx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x30,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x10(%rsp),%edi
  movslq %edi,%rdi
  add    0x18(%rsp),%rdi
  call   <srandom@plt>
  addl   $0x1,D8(%rip)
  jmp    L25
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t anerd_salt(uint64_t salt) {
  struct timeval tv;
  struct timezone tz;
  static int init = 0;
  if (!init) {
    gettimeofday(&tv, &tz);
    srandom(1000000 * tv.tv_sec + tv.tv_usec);
    init++;
  }
  salt ^= random();
  return salt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x34(%rbp)
  je     L14
  mov    $0x1,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L14:
  movl   $0x0,-0x28(%rbp)
  jmp    L8
L49:
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x18(%rbp,%rax,8)
  addl   $0x1,-0x28(%rbp)
L8:
  cmpl   $0x0,-0x28(%rbp)
  jle    L49
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0x10(%rbp),%rax
  movabs $0x1565ae3682b98262,%rdx
  cmp    %rdx,%rax
  jne    L0
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L0:
  movl   $0x0,-0x24(%rbp)
  jmp    L58
L25:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L58:
  cmpl   $0x0,-0x24(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string
name: unpack_data
arguments: data_tag: D28
data_type: string
name: unpack_data
arguments: data_tag: D27
data_type: string

tool: D4: Call this program with %i arguments


tool: D28: You win!

tool: D27: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1541829996588925538UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L3
L48:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  movabs $0x1565ae3682b98262,%rax
  cmp    %rax,0x10(%rsp)
  je     L45
L17:
  mov    0x10(%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x1,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L48
L45:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L17
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D27
datatype: string
name: read_data
arguments: tag: D16
datatype: string

tool: D22: %lu


tool: D27: Call this program with %i arguments


tool: D16: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1541829996588925538UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L33
  lea    D15(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L33:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0x1565ae3682b98262,%rax
  cmp    %rax,%rsi
  je     L0
L35:
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L35
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D29
type_infered: string

tool: D15: Call this program with %i arguments


tool: D16: %lu


tool: D29: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1541829996588925538UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L0
  lea    D22(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L0:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0x1565ae3682b98262,%rax
  cmp    %rax,%rsi
  je     L19
L38:
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L38
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
data_type: string
name: read_data
arguments: data_label: D24
data_type: string
name: read_data
arguments: data_label: D3
data_type: string

tool: D22: Call this program with %i arguments


tool: D24: %lu


tool: D3: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1541829996588925538UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<s9_Compression>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0xfffffff,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L56
L21:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffe,%eax
  jbe    L40
  mov    -0x18(%rbp),%edx
  lea    -0x1c(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <s9_encode@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  je     L38
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L38:
  addq   $0x4,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x28(%rbp)
  addq   $0x4,-0x10(%rbp)
  jmp    L56
L40:
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <s9_encode@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  addq   $0x4,-0x10(%rbp)
L56:
  cmpl   $0x0,-0x18(%rbp)
  jg     L21
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sar    $0x2,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: 

 deberia ser 1, pero es %u




assistant: ```c
int s9_Compression(unsigned int *input, unsigned int *output, int size) {
  int left = size;
  int ret;
  unsigned int escape = ((1u << 28u) - 1);
  unsigned *tmp = output;
  while (left > 0) {
    if ((*input) >= ((1u << 28u) - 1)) {
      ret = s9_encode(tmp, &escape, left);
      left -= ret;
      if (ret != 1) {
        printf("\n\n deberia ser 1, pero es %u\n\n\n", ret);
      }
      tmp++;
      *tmp = *input;
      input++;
      tmp++;
    } else {
      ret = s9_encode(tmp, input, left);
      input += ret;
      left -= ret;
      tmp++;
    }
  }
  return tmp - output;
}
```
user: Translate the below assembly code into C programming language:

```asm
<s9_Compression>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xfffffff,0x4(%rsp)
  test   %edx,%edx
  jle    L59
  mov    %rdi,%r12
  mov    %edx,%ebx
  mov    %rsi,%rbp
  lea    D4(%rip),%r14
  jmp    L48
L31:
  mov    (%r12),%eax
  mov    %eax,0x4(%rbp)
  add    $0x4,%r12
  add    $0x8,%rbp
L2:
  test   %ebx,%ebx
  jle    L67
L48:
  cmpl   $0xffffffe,(%r12)
  jbe    L4
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <s9_encode@plt>
  sub    %eax,%ebx
  cmp    $0x1,%eax
  je     L31
  mov    %eax,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L31
L4:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <s9_encode@plt>
  movslq %eax,%rdx
  lea    (%r12,%rdx,4),%r12
  sub    %eax,%ebx
  add    $0x4,%rbp
  jmp    L2
L59:
  mov    %rsi,%rbp
L67:
  mov    %rbp,%rax
  sub    %r13,%rax
  sar    $0x2,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string

tool: D4: 

 deberia ser 1, pero es %u




assistant: ```c
int s9_Compression(unsigned int *input, unsigned int *output, int size) {
  int left = size;
  int ret;
  unsigned int escape = ((1u << 28u) - 1);
  unsigned *tmp = output;
  while (left > 0) {
    if ((*input) >= ((1u << 28u) - 1)) {
      ret = s9_encode(tmp, &escape, left);
      left -= ret;
      if (ret != 1) {
        printf("\n\n deberia ser 1, pero es %u\n\n\n", ret);
      }
      tmp++;
      *tmp = *input;
      input++;
      tmp++;
    } else {
      ret = s9_encode(tmp, input, left);
      input += ret;
      left -= ret;
      tmp++;
    }
  }
  return tmp - output;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<s9_Compression>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xfffffff,0x4(%rsp)
  test   %edx,%edx
  jle    L64
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %rsi,%rbp
  lea    D2(%rip),%r14
  jmp    L70
  nopl   0x0(%rax)
L67:
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <s9_encode@plt>
  mov    %eax,%esi
  sub    %eax,%ebx
  cmp    $0x1,%eax
  je     L34
  mov    %r14,%rdi
  call   <printf@plt>
L34:
  mov    (%r12),%eax
  add    $0x8,%rbp
  add    $0x4,%r12
  mov    %eax,-0x4(%rbp)
  test   %ebx,%ebx
  jle    L51
L70:
  cmpl   $0xffffffe,(%r12)
  ja     L67
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbp
  call   <s9_encode@plt>
  movslq %eax,%rdx
  sub    %eax,%ebx
  lea    (%r12,%rdx,4),%r12
  test   %ebx,%ebx
  jg     L70
L51:
  mov    %rbp,%rax
  sub    %r13,%rax
  sar    $0x2,%rax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
  jmp    L15
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: 

 deberia ser 1, pero es %u




assistant: ```c
int s9_Compression(unsigned int *input, unsigned int *output, int size) {
  int left = size;
  int ret;
  unsigned int escape = ((1u << 28u) - 1);
  unsigned *tmp = output;
  while (left > 0) {
    if ((*input) >= ((1u << 28u) - 1)) {
      ret = s9_encode(tmp, &escape, left);
      left -= ret;
      if (ret != 1) {
        printf("\n\n deberia ser 1, pero es %u\n\n\n", ret);
      }
      tmp++;
      *tmp = *input;
      input++;
      tmp++;
    } else {
      ret = s9_encode(tmp, input, left);
      input += ret;
      left -= ret;
      tmp++;
    }
  }
  return tmp - output;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<s9_Compression>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xfffffff,0x4(%rsp)
  test   %edx,%edx
  jle    L79
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %rsi,%rbp
  lea    D9(%rip),%r14
  jmp    L3
  nopl   0x0(%rax)
L30:
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <s9_encode@plt>
  mov    %eax,%esi
  sub    %eax,%ebx
  cmp    $0x1,%eax
  je     L52
  mov    %r14,%rdi
  call   <printf@plt>
L52:
  mov    (%r12),%eax
  add    $0x8,%rbp
  add    $0x4,%r12
  mov    %eax,-0x4(%rbp)
  test   %ebx,%ebx
  jle    L35
L3:
  cmpl   $0xffffffe,(%r12)
  ja     L30
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbp
  call   <s9_encode@plt>
  movslq %eax,%rdx
  sub    %eax,%ebx
  lea    (%r12,%rdx,4),%r12
  test   %ebx,%ebx
  jg     L3
L35:
  mov    %rbp,%rax
  sub    %r13,%rax
  sar    $0x2,%rax
L53:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  xor    %eax,%eax
  jmp    L53
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: 

 deberia ser 1, pero es %u




assistant: ```c
int s9_Compression(unsigned int *input, unsigned int *output, int size) {
  int left = size;
  int ret;
  unsigned int escape = ((1u << 28u) - 1);
  unsigned *tmp = output;
  while (left > 0) {
    if ((*input) >= ((1u << 28u) - 1)) {
      ret = s9_encode(tmp, &escape, left);
      left -= ret;
      if (ret != 1) {
        printf("\n\n deberia ser 1, pero es %u\n\n\n", ret);
      }
      tmp++;
      *tmp = *input;
      input++;
      tmp++;
    } else {
      ret = s9_encode(tmp, input, left);
      input += ret;
      left -= ret;
      tmp++;
    }
  }
  return tmp - output;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<drvOCM_Munmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <munmap@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int drvOCM_Munmap(void *pntr, int len) {
  munmap(pntr, len);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<drvOCM_Munmap>:
  endbr64
  sub    $0x8,%rsp
  call   <munmap@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int drvOCM_Munmap(void *pntr, int len) {
  munmap(pntr, len);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drvOCM_Munmap>:
  endbr64
  sub    $0x8,%rsp
  call   <munmap@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int drvOCM_Munmap(void *pntr, int len) {
  munmap(pntr, len);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<drvOCM_Munmap>:
  endbr64
  sub    $0x8,%rsp
  call   <munmap@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int drvOCM_Munmap(void *pntr, int len) {
  munmap(pntr, len);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<remove_lb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L8
L38:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L32
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L58
L10:
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L58:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L10
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L38
  jmp    L26
L32:
  nop
L26:
  leave
  ret
```

assistant: ```c
void remove_lb(char *s) {
  int i, l;
  char *p;
  while (*s == ' ') {
    l = strlen(s);
    if (l <= 0)
      return;
    for (i = 0, p = s; i < l; i++, p++)
      *p = *(p + 1);
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<remove_lb>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x20,(%rdi)
  je     L5
L23:
  pop    %rbx
  ret
L20:
  cmpb   $0x20,(%rbx)
  jne    L23
L5:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L23
  mov    %eax,%eax
  lea    (%rbx,%rax,1),%rdx
  mov    %rbx,%rax
L37:
  movzbl 0x1(%rax),%ecx
  mov    %cl,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L37
  jmp    L20
```

assistant: ```c
void remove_lb(char *s) {
  int i, l;
  char *p;
  while (*s == ' ') {
    l = strlen(s);
    if (l <= 0)
      return;
    for (i = 0, p = s; i < l; i++, p++)
      *p = *(p + 1);
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remove_lb>:
  endbr64
  cmpb   $0x20,(%rdi)
  jne    L35
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %eax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  cmpb   $0x20,(%rbx)
  jne    L18
L38:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L13
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  ret
```

assistant: ```c
void remove_lb(char *s) {
  int i, l;
  char *p;
  while (*s == ' ') {
    l = strlen(s);
    if (l <= 0)
      return;
    for (i = 0, p = s; i < l; i++, p++)
      *p = *(p + 1);
  }
  return;
}
```