ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<strrchr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L44
  mov    %rdi,%rdx
L19:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L19
  lea    -0x1(%rdi),%rcx
L49:
  mov    %rax,%rdx
  cmp    %rcx,%rax
  je     L6
  sub    $0x1,%rax
  cmp    %sil,(%rdx)
  jne    L49
L6:
  cmp    %rdx,%rdi
  mov    $0x0,%eax
  cmovae %rax,%rdx
  mov    %rdx,%rax
  ret
L44:
  lea    -0x1(%rdi),%rdx
  jmp    L6
```

assistant: ```c
char *strrchr(const char *str, int ch) {
  char *s = (char *)str;
  while (*s)
    s++;
  while (s-- != str && *s != (char)ch)
    ;
  return s <= str ? NULL : s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strrchr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L27
  mov    %rdi,%rdx
  nopl   0x0(%rax)
L2:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L2
  lea    -0x1(%rdi),%rdx
L12:
  mov    %rax,%r8
  cmp    %rdx,%rax
  je     L20
  sub    $0x1,%rax
  cmp    %sil,(%r8)
  jne    L12
L20:
  xor    %eax,%eax
  cmp    %r8,%rdi
  cmovae %rax,%r8
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L27:
  lea    -0x1(%rdi),%r8
  xor    %eax,%eax
  cmp    %r8,%rdi
  cmovae %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strrchr(const char *str, int ch) {
  char *s = (char *)str;
  while (*s)
    s++;
  while (s-- != str && *s != (char)ch)
    ;
  return s <= str ? NULL : s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strrchr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L32
  mov    %rdi,%rdx
  nopl   0x0(%rax)
L28:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L28
  lea    -0x1(%rdi),%rdx
L22:
  mov    %rax,%r8
  cmp    %rdx,%rax
  je     L2
  sub    $0x1,%rax
  cmp    %sil,(%r8)
  jne    L22
L2:
  xor    %eax,%eax
  cmp    %r8,%rdi
  cmovae %rax,%r8
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L32:
  lea    -0x1(%rdi),%r8
  xor    %eax,%eax
  cmp    %r8,%rdi
  cmovae %rax,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strrchr(const char *str, int ch) {
  char *s = (char *)str;
  while (*s)
    s++;
  while (s-- != str && *s != (char)ch)
    ;
  return s <= str ? NULL : s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jle    L7
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <le_n_numeros@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mostra_positivos@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D8
type: string

tool: D5: Quantos inteiros?


tool: D8: %d

assistant: ```c
int main() {
  int n, *v;
  printf("Quantos inteiros?\n");
  scanf("%d", &n);
  if (n > 0) {
    v = (int *)malloc(sizeof(int) * n);
    le_n_numeros(n, v);
    mostra_positivos(n, v);
    free(v);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jg     L2
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    0x4(%rsp),%edi
  call   <le_n_numeros@plt>
  mov    %rbx,%rsi
  mov    0x4(%rsp),%edi
  call   <mostra_positivos@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L23
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D17
type: string

tool: D7: Quantos inteiros?


tool: D17: %d

assistant: ```c
int main() {
  int n, *v;
  printf("Quantos inteiros?\n");
  scanf("%d", &n);
  if (n > 0) {
    v = (int *)malloc(sizeof(int) * n);
    le_n_numeros(n, v);
    mostra_positivos(n, v);
    free(v);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D3(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L1
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <le_n_numeros@plt>
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  call   <mostra_positivos@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D3
type_guessed: string

tool: D10: Quantos inteiros?


tool: D3: %d

assistant: ```c
int main() {
  int n, *v;
  printf("Quantos inteiros?\n");
  scanf("%d", &n);
  if (n > 0) {
    v = (int *)malloc(sizeof(int) * n);
    le_n_numeros(n, v);
    mostra_positivos(n, v);
    free(v);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L12
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <le_n_numeros@plt>
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  call   <mostra_positivos@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D16: Quantos inteiros?


tool: D1: %d

assistant: ```c
int main() {
  int n, *v;
  printf("Quantos inteiros?\n");
  scanf("%d", &n);
  if (n > 0) {
    v = (int *)malloc(sizeof(int) * n);
    le_n_numeros(n, v);
    mostra_positivos(n, v);
    free(v);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x8,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: %i


assistant: ```c
int main(int argc, char **argv) {
  printf("%i\n", sizeof(long long));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string

tool: D2: %i


assistant: ```c
int main(int argc, char **argv) {
  printf("%i\n", sizeof(long long));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: %i


assistant: ```c
int main(int argc, char **argv) {
  printf("%i\n", sizeof(long long));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: %i


assistant: ```c
int main(int argc, char **argv) {
  printf("%i\n", sizeof(long long));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mat_get_similar_matrix_d3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  movsd  %xmm0,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x70(%rbp),%rcx
  mov    -0x68(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat_inverse_matrix_d3@plt>
  test   %eax,%eax
  jne    L25
  mov    $0x0,%eax
  jmp    L18
L25:
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    -0x58(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    $0x1,%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int mat_get_similar_matrix_d3(double m[3][3], double a[3][3], double b[3][3], const double precision) {
  double c[3][3];
  if (!mat_inverse_matrix_d3(c, b, precision)) {
    ;
    return 0;
  }
  mat_multiply_matrix_d3(m, a, b);
  mat_multiply_matrix_d3(m, c, m);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mat_get_similar_matrix_d3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rdx,%rsi
  call   <mat_inverse_matrix_d3@plt>
  test   %eax,%eax
  jne    L21
L15:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdx
  mov    %rbp,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    $0x1,%eax
  jmp    L15
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mat_get_similar_matrix_d3(double m[3][3], double a[3][3], double b[3][3], const double precision) {
  double c[3][3];
  if (!mat_inverse_matrix_d3(c, b, precision)) {
    ;
    return 0;
  }
  mat_multiply_matrix_d3(m, a, b);
  mat_multiply_matrix_d3(m, c, m);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mat_get_similar_matrix_d3>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <mat_inverse_matrix_d3@plt>
  test   %eax,%eax
  je     L8
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    $0x1,%eax
L8:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mat_get_similar_matrix_d3(double m[3][3], double a[3][3], double b[3][3], const double precision) {
  double c[3][3];
  if (!mat_inverse_matrix_d3(c, b, precision)) {
    ;
    return 0;
  }
  mat_multiply_matrix_d3(m, a, b);
  mat_multiply_matrix_d3(m, c, m);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mat_get_similar_matrix_d3>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <mat_inverse_matrix_d3@plt>
  test   %eax,%eax
  je     L1
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <mat_multiply_matrix_d3@plt>
  mov    $0x1,%eax
L1:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mat_get_similar_matrix_d3(double m[3][3], double a[3][3], double b[3][3], const double precision) {
  double c[3][3];
  if (!mat_inverse_matrix_d3(c, b, precision)) {
    ;
    return 0;
  }
  mat_multiply_matrix_d3(m, a, b);
  mat_multiply_matrix_d3(m, c, m);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  jmp    L14
L16:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  or     $0xe,%ah
  mov    $0xf,%edx
  mov    %edx,%ebx
  int    $0x10
  addq   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void print(const char *s) {
  while (*s) {
    __asm__ __volatile__("int $0x10" : : "a"(0x0E00 | *s), "b"(0x000F));
    s++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  push   %rbx
  mov    $0xf,%ebx
L11:
  movsbl %al,%eax
  or     $0xe,%ah
  int    $0x10
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L11
  pop    %rbx
  ret
L16:
  ret
```

assistant: ```c
void print(const char *s) {
  while (*s) {
    __asm__ __volatile__("int $0x10" : : "a"(0x0E00 | *s), "b"(0x000F));
    s++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L5
  push   %rbx
  mov    $0xf,%ebx
  nopl   0x0(%rax)
L2:
  or     $0xe,%ah
  int    $0x10
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L2
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void print(const char *s) {
  while (*s) {
    __asm__ __volatile__("int $0x10" : : "a"(0x0E00 | *s), "b"(0x000F));
    s++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L18
  push   %rbx
  mov    $0xf,%ebx
  nopl   0x0(%rax)
L0:
  or     $0xe,%ah
  int    $0x10
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L0
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void print(const char *s) {
  while (*s) {
    __asm__ __volatile__("int $0x10" : : "a"(0x0E00 | *s), "b"(0x000F));
    s++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L18
L49:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x18(%rbp)
L18:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L49
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <binary_search@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L25
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L41
L25:
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L41:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D62
type_guessed: string
name: read_data
arguments: tag: D48
type_guessed: string
name: read_data
arguments: tag: D30
type_guessed: string
name: read_data
arguments: tag: D69
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string
name: read_data
arguments: tag: D70
type_guessed: string

tool: D62: How many items? 

tool: D48: %d

tool: D30: Enter numbers: 

tool: D69: Find: 

tool: D26: Data found at position %d

tool: D70: Data not found

assistant: ```c
int main() {
  int n, find;
  printf("How many items? ");
  scanf("%d", &n);
  int *input = (int *)malloc(n * sizeof(int));
  printf("Enter numbers: ");
  for (int i = 0; i < n; i++) {
    scanf("%d", input + i);
  }
  printf("Find: ");
  scanf("%d", &find);
  int position = binary_search(input, find, n);
  if (position != -1) {
    printf("Data found at position %d", position);
  } else {
    printf("Data not found");
  }
  free(input);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D70(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  lea    D76(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,(%rsp)
  jle    L1
  mov    %r13,%rbp
  mov    $0x0,%ebx
  lea    D35(%rip),%r12
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,(%rsp)
  jg     L8
L1:
  lea    D68(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <binary_search@plt>
  cmp    $0xffffffff,%eax
  je     L18
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D70
type: string
name: retrieve_data
arguments: data_label: D35
type: string
name: retrieve_data
arguments: data_label: D76
type: string
name: retrieve_data
arguments: data_label: D68
type: string
name: retrieve_data
arguments: data_label: D13
type: string
name: retrieve_data
arguments: data_label: D7
type: string

tool: D70: How many items? 

tool: D35: %d

tool: D76: Enter numbers: 

tool: D68: Find: 

tool: D13: Data found at position %d

tool: D7: Data not found

assistant: ```c
int main() {
  int n, find;
  printf("How many items? ");
  scanf("%d", &n);
  int *input = (int *)malloc(n * sizeof(int));
  printf("Enter numbers: ");
  for (int i = 0; i < n; i++) {
    scanf("%d", input + i);
  }
  printf("Find: ");
  scanf("%d", &find);
  int position = binary_search(input, find, n);
  if (position != -1) {
    printf("Data found at position %d", position);
  } else {
    printf("Data not found");
  }
  free(input);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D31(%rip),%rdi
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L44
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,(%rsp)
  jg     L28
L44:
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edx
  mov    %r13,%rdi
  call   <binary_search@plt>
  mov    %eax,%esi
  cmp    $0xffffffff,%eax
  je     L34
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L36:
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L36
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D31
type: string
name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D7
type: string
name: read_data
arguments: data_label: D54
type: string
name: read_data
arguments: data_label: D39
type: string
name: read_data
arguments: data_label: D16
type: string

tool: D31: How many items? 

tool: D12: %d

tool: D7: Enter numbers: 

tool: D54: Find: 

tool: D39: Data found at position %d

tool: D16: Data not found

assistant: ```c
int main() {
  int n, find;
  printf("How many items? ");
  scanf("%d", &n);
  int *input = (int *)malloc(n * sizeof(int));
  printf("Enter numbers: ");
  for (int i = 0; i < n; i++) {
    scanf("%d", input + i);
  }
  printf("Find: ");
  scanf("%d", &find);
  int position = binary_search(input, find, n);
  if (position != -1) {
    printf("Data found at position %d", position);
  } else {
    printf("Data not found");
  }
  free(input);
  return 0;
}
```