ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<dbchr>:
  endbr64
  test   $0x80,%dil
  jne    L4
  lea    D23(%rip),%r8
  movzbl %dil,%edi
  mov    %r8,%rax
  cmp    $0x1f,%edi
  jg     L19
L31:
  lea    0x2(%rax),%rdx
  xor    $0x40,%edi
  movb   $0x5e,(%rax)
  mov    %dil,0x1(%rax)
  mov    %r8,%rax
  movb   $0x0,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D10(%rip),%rax
  and    $0x7f,%edi
  movb   $0x7e,D23(%rip)
  lea    -0x1(%rax),%r8
  cmp    $0x1f,%edi
  jle    L31
L19:
  cmp    $0x7f,%edi
  je     L20
  lea    0x1(%rax),%rdx
  mov    %dil,(%rax)
  mov    %r8,%rax
  movb   $0x0,(%rdx)
  ret
  nopl   (%rax)
L20:
  lea    0x2(%rax),%rdx
  mov    $0x3f5e,%ecx
  mov    %cx,(%rax)
  mov    %r8,%rax
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *dbchr(c)
int c;
{
  static char s[8];
  char *cp = s;
  c &= 0xff;
  if (c & 0x80) {
    *cp++ = '~';
    c &= 0x7f;
  }
  if (c < 32) {
    *cp++ = '^';
    *cp++ = (char)(((c) ^ 64) & 0xFF);
  } else if (c == 127) {
    *cp++ = '^';
    *cp++ = '?';
  } else {
    *cp++ = (char)c;
  }
  *cp = '\0';
  cp = s;
  return (cp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L7:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memcpy(char *dest, char *src, unsigned int n) {
  for (unsigned int i = 0; i < n; i++) {
    *(dest + i) = *(src + i);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L3
  mov    %edx,%edx
  mov    $0x0,%eax
L4:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L3:
  ret
```

assistant: ```c
void memcpy(char *dest, char *src, unsigned int n) {
  for (unsigned int i = 0; i < n; i++) {
    *(dest + i) = *(src + i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L0
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L19:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
L0:
  ret
```

assistant: ```c
void memcpy(char *dest, char *src, unsigned int n) {
  for (unsigned int i = 0; i < n; i++) {
    *(dest + i) = *(src + i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  je     L88
  lea    0x1(%rsi),%r8
  lea    -0x1(%rdx),%eax
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L154
  cmp    $0x6,%eax
  jbe    L154
  mov    %edx,%edi
  cmp    $0xe,%eax
  jbe    L108
  shr    $0x4,%edi
  xor    %eax,%eax
  shl    $0x4,%rdi
L40:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L40
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  test   $0xf,%dl
  je     L88
  mov    %edx,%edi
  sub    %eax,%edi
  lea    -0x1(%rdi),%r8d
  cmp    $0x6,%r8d
  jbe    L73
L124:
  mov    %eax,%r8d
  mov    (%rsi,%r8,1),%r9
  mov    %r9,(%rcx,%r8,1)
  mov    %edi,%r8d
  and    $0xfffffff8,%r8d
  add    %r8d,%eax
  cmp    %r8d,%edi
  je     L88
L73:
  mov    %eax,%edi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jbe    L88
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jbe    L88
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jbe    L88
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jbe    L88
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jbe    L88
  movzbl (%rsi,%rdi,1),%r8d
  add    $0x6,%eax
  mov    %r8b,(%rcx,%rdi,1)
  cmp    %eax,%edx
  jbe    L88
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  ret
  cs nopw 0x0(%rax,%rax,1)
L154:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L50:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L50
L88:
  ret
L108:
  xor    %eax,%eax
  jmp    L124
```

assistant: ```c
void memcpy(char *dest, char *src, unsigned int n) {
  for (unsigned int i = 0; i < n; i++) {
    *(dest + i) = *(src + i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<asprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xe0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L23
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L23:
  mov    -0xd8(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0xe0(%rbp),%rdx
  mov    -0xc0(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc0(%rbp),%edx
  mov    -0xe0(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %eax,-0xc4(%rbp)
  mov    -0xc0(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc4(%rbp),%eax
  cltq
  add    $0x1,%rax
  mov    %rax,-0xb8(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0xd8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xd8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  movl   $0xffffffff,-0xc4(%rbp)
  jmp    L12
L4:
  mov    -0xe0(%rbp),%rdx
  mov    -0xc0(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xd8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xc0(%rbp),%ecx
  mov    -0xe0(%rbp),%rdx
  mov    -0xb8(%rbp),%rsi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xbc(%rbp)
  mov    -0xc0(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xbc(%rbp),%eax
  cmp    -0xc4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L12:
  mov    -0xc4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int asprintf(char **ptr, const char *fmt, ...) {
  va_list ap;
  size_t str_m;
  int str_l;
  *ptr = NULL;
  va_start(ap, fmt);
  str_l = vsnprintf(NULL, (size_t)0, fmt, ap);
  va_end(ap);
  assert(str_l >= 0);
  *ptr = (char *)malloc(str_m = (size_t)str_l + 1);
  if (*ptr == NULL) {
    errno = ENOMEM;
    str_l = -1;
  } else {
    int str_l2;
    va_start(ap, fmt);
    str_l2 = vsnprintf(*ptr, str_m, fmt, ap);
    va_end(ap);
    assert(str_l2 == str_l);
  }
  return str_l;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<asprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  movq   $0x0,(%rdi)
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%ecx
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <va_end@plt>
  mov    %ebp,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  movslq %ebp,%r14
  add    $0x1,%r14
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L7
  mov    %r12,%rsi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    0x0(%r13),%rdi
  call   <vsnprintf@plt>
  mov    %eax,%r12d
  mov    %ebx,%edi
  call   <va_end@plt>
  cmp    %r12d,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
L2:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%ebp
  jmp    L2
```

assistant: ```c
int asprintf(char **ptr, const char *fmt, ...) {
  va_list ap;
  size_t str_m;
  int str_l;
  *ptr = NULL;
  va_start(ap, fmt);
  str_l = vsnprintf(NULL, (size_t)0, fmt, ap);
  va_end(ap);
  assert(str_l >= 0);
  *ptr = (char *)malloc(str_m = (size_t)str_l + 1);
  if (*ptr == NULL) {
    errno = ENOMEM;
    str_l = -1;
  } else {
    int str_l2;
    va_start(ap, fmt);
    str_l2 = vsnprintf(*ptr, str_m, fmt, ap);
    va_end(ap);
    assert(str_l2 == str_l);
  }
  return str_l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<asprintf>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  movq   $0x0,(%rdi)
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r13,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  movslq %eax,%r14
  call   <va_end@plt>
  mov    %r14d,%edi
  mov    %r14,%r12
  add    $0x1,%r14
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L7
  xor    %ebp,%ebp
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    (%rbx),%rdi
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <va_end@plt>
  xor    %edi,%edi
  cmp    %ebx,%r12d
  sete   %dil
  call   <assert@plt>
L0:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L7:
  mov    D14(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  jmp    L0
```

assistant: ```c
int asprintf(char **ptr, const char *fmt, ...) {
  va_list ap;
  size_t str_m;
  int str_l;
  *ptr = NULL;
  va_start(ap, fmt);
  str_l = vsnprintf(NULL, (size_t)0, fmt, ap);
  va_end(ap);
  assert(str_l >= 0);
  *ptr = (char *)malloc(str_m = (size_t)str_l + 1);
  if (*ptr == NULL) {
    errno = ENOMEM;
    str_l = -1;
  } else {
    int str_l2;
    va_start(ap, fmt);
    str_l2 = vsnprintf(*ptr, str_m, fmt, ap);
    va_end(ap);
    assert(str_l2 == str_l);
  }
  return str_l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<asprintf>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  movq   $0x0,(%rdi)
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r13,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  movslq %eax,%r14
  call   <va_end@plt>
  mov    %r14d,%edi
  mov    %r14,%r12
  add    $0x1,%r14
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L19
  xor    %ebp,%ebp
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    (%rbx),%rdi
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <va_end@plt>
  xor    %edi,%edi
  cmp    %ebx,%r12d
  sete   %dil
  call   <assert@plt>
L18:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L19:
  mov    D16(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  jmp    L18
```

assistant: ```c
int asprintf(char **ptr, const char *fmt, ...) {
  va_list ap;
  size_t str_m;
  int str_l;
  *ptr = NULL;
  va_start(ap, fmt);
  str_l = vsnprintf(NULL, (size_t)0, fmt, ap);
  va_end(ap);
  assert(str_l >= 0);
  *ptr = (char *)malloc(str_m = (size_t)str_l + 1);
  if (*ptr == NULL) {
    errno = ENOMEM;
    str_l = -1;
  } else {
    int str_l2;
    va_start(ap, fmt);
    str_l2 = vsnprintf(*ptr, str_m, fmt, ap);
    va_end(ap);
    assert(str_l2 == str_l);
  }
  return str_l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<map_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <map_destroy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void map_delete(struct map *__restrict map) {
  map_destroy(map);
  free(map);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<map_delete>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <map_destroy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void map_delete(struct map *__restrict map) {
  map_destroy(map);
  free(map);
}
```
user: Translate the below assembly code into C programming language:

```asm
<map_delete>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <map_destroy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void map_delete(struct map *__restrict map) {
  map_destroy(map);
  free(map);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<map_delete>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <map_destroy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void map_delete(struct map *__restrict map) {
  map_destroy(map);
  free(map);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L3
L21:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D14: %d

tool: D0: %i


assistant: ```c
int main() {
  int num, a;
  scanf("%d", &num);
  for (a = 1; a <= num; a += 2)
    printf("%i\n", a);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L26
  mov    $0x1,%ebx
  lea    D6(%rip),%rbp
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L13
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string

tool: D2: %d

tool: D6: %i


assistant: ```c
int main() {
  int num, a;
  scanf("%d", &num);
  for (a = 1; a <= num; a += 2)
    printf("%i\n", a);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L5
  mov    $0x1,%ebx
  lea    D15(%rip),%rbp
  nop
L15:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L15
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string

tool: D10: %d

tool: D15: %i


assistant: ```c
int main() {
  int num, a;
  scanf("%d", &num);
  for (a = 1; a <= num; a += 2)
    printf("%i\n", a);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L27
  mov    $0x1,%ebx
  lea    D9(%rip),%rbp
  nop
L29:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L29
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D2: %d

tool: D9: %i


assistant: ```c
int main() {
  int num, a;
  scanf("%d", &num);
  for (a = 1; a <= num; a += 2)
    printf("%i\n", a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x5,-0x14(%rbp)
  jne    L12
  mov    $0x42,%edi
  call   <putchar@plt>
  jmp    L8
L12:
  mov    -0x20(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 5) {
    putchar('B');
  } else {
    char *enemy_hist = argv[2];
    size_t len = strlen(enemy_hist);
    putchar(enemy_hist[len - 1]);
  }
  putchar('\n');
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x5,%edi
  je     L14
  mov    0x10(%rsi),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <putchar@plt>
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L14:
  mov    $0x42,%edi
  call   <putchar@plt>
  jmp    L19
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 5) {
    putchar('B');
  } else {
    char *enemy_hist = argv[2];
    size_t len = strlen(enemy_hist);
    putchar(enemy_hist[len - 1]);
  }
  putchar('\n');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x5,%edi
  je     L4
  mov    0x10(%rsi),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <putchar@plt>
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L4:
  mov    $0x42,%edi
  call   <putchar@plt>
  jmp    L8
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 5) {
    putchar('B');
  } else {
    char *enemy_hist = argv[2];
    size_t len = strlen(enemy_hist);
    putchar(enemy_hist[len - 1]);
  }
  putchar('\n');
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x5,%edi
  je     L8
  mov    0x10(%rsi),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <putchar@plt>
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  mov    $0x42,%edi
  call   <putchar@plt>
  jmp    L17
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 5) {
    putchar('B');
  } else {
    char *enemy_hist = argv[2];
    size_t len = strlen(enemy_hist);
    putchar(enemy_hist[len - 1]);
  }
  putchar('\n');
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L78:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L8
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L78
  jmp    L57
L8:
  nop
L57:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L60
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L30
  subl   $0x1,-0x4(%rbp)
L60:
  cmpl   $0x0,-0x4(%rbp)
  jns    L33
  jmp    L43
L30:
  nop
L43:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  leave
  ret
```

assistant: ```c
int trim(char *str) {
  int x;
  for (x = 0; x < strlen(str); x++)
    if (str[x] != ' ')
      break;
  strncpy(str, str + x, strlen(str) + 1);
  for (x = strlen(str) - 1; x >= 0; x--)
    if (str[x] != ' ')
      break;
  str[x + 1] = 0;
  return strlen(str);
}
```