ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<resolver_cleanup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <freeaddrinfo@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void resolver_cleanup(void *p) {
  if (p)
    freeaddrinfo(p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<resolver_cleanup>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <freeaddrinfo@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
void resolver_cleanup(void *p) {
  if (p)
    freeaddrinfo(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<resolver_cleanup>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <freeaddrinfo@plt>
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
void resolver_cleanup(void *p) {
  if (p)
    freeaddrinfo(p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<resolver_cleanup>:
  endbr64
  test   %rdi,%rdi
  je     L8
  jmp    1050 <freeaddrinfo@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void resolver_cleanup(void *p) {
  if (p)
    freeaddrinfo(p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L11
  addl   $0x1,-0x8(%rbp)
L11:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned count_char(char *str, const char c) {
  int count = 0;
  int i = 0;
  while (str[i] != '\0') {
    if (str[i] == c)
      count++;
    i++;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<count_char>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  add    $0x1,%rdi
  mov    $0x0,%edx
L16:
  cmp    %al,%sil
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L16
L26:
  mov    %edx,%eax
  ret
L10:
  mov    $0x0,%edx
  jmp    L26
```

assistant: ```c
unsigned count_char(char *str, const char c) {
  int count = 0;
  int i = 0;
  while (str[i] != '\0') {
    if (str[i] == c)
      count++;
    i++;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_char>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  cmp    %dl,%sil
  sete   %dl
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %edx,%eax
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L8
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned count_char(char *str, const char c) {
  int count = 0;
  int i = 0;
  while (str[i] != '\0') {
    if (str[i] == c)
      count++;
    i++;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<count_char>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L17
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L0:
  cmp    %dl,%sil
  sete   %dl
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %edx,%eax
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L0
  ret
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned count_char(char *str, const char c) {
  int count = 0;
  int i = 0;
  while (str[i] != '\0') {
    if (str[i] == c)
      count++;
    i++;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setup_vars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  jmp    L59
L49:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <save_var@plt>
  mov    -0x18(%rbp),%rax
  movb   $0x3d,(%rax)
  addq   $0x8,-0x30(%rbp)
L59:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L49
  jmp    L41
L4:
  movw   $0x0,-0xa(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0xa(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <save_var@plt>
  addq   $0x8,-0x28(%rbp)
  addl   $0x1,-0x1c(%rbp)
L41:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L16
  cmpl   $0x9,-0x1c(%rbp)
  jle    L4
L16:
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <save_var@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D10: 0

tool: D4: ?

assistant: ```c
void setup_vars(char **argv, char **envp) {
  char *equals;
  int i = 0;
  while (*envp != NULL) {
    equals = strchr(*envp, '=');
    *equals = '\0';
    save_var(*envp, equals + 1);
    *equals = '=';
    envp++;
  }
  while (*argv != NULL && i < 10) {
    char var_name[2] = {0};
    var_name[0] = '0' + i;
    save_var(var_name, *argv);
    argv++;
    i++;
  }
  save_var("?", "0");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<setup_vars>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L19
L26:
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  mov    0x0(%rbp),%rdi
  call   <save_var@plt>
  movb   $0x3d,(%rbx)
  add    $0x8,%rbp
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  jne    L26
L19:
  mov    (%r12),%rsi
  test   %rsi,%rsi
  je     L48
  mov    $0x0,%ebx
  lea    0x6(%rsp),%rbp
L1:
  movw   $0x0,0x6(%rsp)
  lea    0x30(%rbx),%eax
  mov    %al,0x6(%rsp)
  mov    %rbp,%rdi
  call   <save_var@plt>
  add    $0x8,%r12
  add    $0x1,%ebx
  mov    (%r12),%rsi
  cmp    $0x9,%ebx
  jg     L48
  test   %rsi,%rsi
  jne    L1
L48:
  lea    D1(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <save_var@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D14
datatype: string

tool: D1: 0

tool: D14: ?

assistant: ```c
void setup_vars(char **argv, char **envp) {
  char *equals;
  int i = 0;
  while (*envp != NULL) {
    equals = strchr(*envp, '=');
    *equals = '\0';
    save_var(*envp, equals + 1);
    *equals = '=';
    envp++;
  }
  while (*argv != NULL && i < 10) {
    char var_name[2] = {0};
    var_name[0] = '0' + i;
    save_var(var_name, *argv);
    argv++;
    i++;
  }
  save_var("?", "0");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<setup_vars>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    (%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  mov    %rsi,%rbp
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x3d,%esi
  add    $0x8,%rbp
  call   <strchr@plt>
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rdi
  mov    %rax,%rbx
  lea    0x1(%rax),%rsi
  call   <save_var@plt>
  movb   $0x3d,(%rbx)
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  jne    L11
L40:
  mov    (%r12),%rsi
  test   %rsi,%rsi
  je     L6
  xor    %ebx,%ebx
  lea    0x6(%rsp),%rbp
  jmp    L45
  nop
L0:
  test   %rsi,%rsi
  je     L6
L45:
  xor    %eax,%eax
  mov    %rbp,%rdi
  add    $0x8,%r12
  mov    %ax,0x6(%rsp)
  lea    0x30(%rbx),%eax
  add    $0x1,%ebx
  mov    %al,0x6(%rsp)
  call   <save_var@plt>
  mov    (%r12),%rsi
  cmp    $0xa,%ebx
  jne    L0
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  lea    D10(%rip),%rsi
  lea    D15(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <save_var@plt>
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D15
data_type: string

tool: D10: 0

tool: D15: ?

assistant: ```c
void setup_vars(char **argv, char **envp) {
  char *equals;
  int i = 0;
  while (*envp != NULL) {
    equals = strchr(*envp, '=');
    *equals = '\0';
    save_var(*envp, equals + 1);
    *equals = '=';
    envp++;
  }
  while (*argv != NULL && i < 10) {
    char var_name[2] = {0};
    var_name[0] = '0' + i;
    save_var(var_name, *argv);
    argv++;
    i++;
  }
  save_var("?", "0");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setup_vars>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    (%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L32
  mov    %rsi,%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x3d,%esi
  add    $0x8,%rbp
  call   <strchr@plt>
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rdi
  mov    %rax,%rbx
  lea    0x1(%rax),%rsi
  call   <save_var@plt>
  movb   $0x3d,(%rbx)
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  jne    L0
L32:
  mov    (%r12),%rsi
  test   %rsi,%rsi
  je     L18
  xor    %ebx,%ebx
  lea    0x6(%rsp),%rbp
  jmp    L22
  nop
L25:
  test   %rsi,%rsi
  je     L18
L22:
  xor    %eax,%eax
  mov    %rbp,%rdi
  add    $0x8,%r12
  mov    %ax,0x6(%rsp)
  lea    0x30(%rbx),%eax
  add    $0x1,%ebx
  mov    %al,0x6(%rsp)
  call   <save_var@plt>
  mov    (%r12),%rsi
  cmp    $0xa,%ebx
  jne    L25
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  lea    D17(%rip),%rsi
  lea    D12(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <save_var@plt>
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D17
type_infered: string
name: read_data
arguments: tag: D12
type_infered: string

tool: D17: 0

tool: D12: ?

assistant: ```c
void setup_vars(char **argv, char **envp) {
  char *equals;
  int i = 0;
  while (*envp != NULL) {
    equals = strchr(*envp, '=');
    *equals = '\0';
    save_var(*envp, equals + 1);
    *equals = '=';
    envp++;
  }
  while (*argv != NULL && i < 10) {
    char var_name[2] = {0};
    var_name[0] = '0' + i;
    save_var(var_name, *argv);
    argv++;
    i++;
  }
  save_var("?", "0");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ce_utf8_strlen_between>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L78
L130:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L54
  movl   $0x1,-0x8(%rbp)
  jmp    L118
L54:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  jne    L103
  movl   $0x2,-0x8(%rbp)
  jmp    L118
L103:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf0,%eax
  cmp    $0xe0,%eax
  jne    L148
  movl   $0x3,-0x8(%rbp)
  jmp    L118
L148:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf8,%eax
  cmp    $0xf0,%eax
  jne    L1
  movl   $0x4,-0x8(%rbp)
  jmp    L118
L1:
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  jmp    L108
L118:
  movl   $0x0,-0x4(%rbp)
  jmp    L101
L58:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L84
  mov    $0xffffffff,%eax
  jmp    L108
L84:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L101:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L58
  addl   $0x1,-0xc(%rbp)
L78:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L130
  mov    -0xc(%rbp),%eax
L108:
  leave
  ret
```

assistant: ```c
int64_t ce_utf8_strlen_between(const char *start, const char *end) {
  int64_t len = 0;
  int64_t byte_count = 0;
  while (start <= end) {
    if ((*start & 0x80) == 0) {
      byte_count = 1;
    } else if ((*start & 0xE0) == 0xC0) {
      byte_count = 2;
    } else if ((*start & 0xF0) == 0xE0) {
      byte_count = 3;
    } else if ((*start & 0xF8) == 0xF0) {
      byte_count = 4;
    } else {
      assert(!"unicode character claiming it has more than 4 bytes?!");
      return -1;
    }
    for (int64_t i = 0; i < byte_count; i++) {
      if (*start == 0)
        return -1;
      start++;
    }
    len++;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ce_utf8_strlen_between>:
  endbr64
  cmp    %rsi,%rdi
  ja     L55
  mov    %rdi,%rax
  mov    $0x0,%edi
  mov    $0x1,%r8d
  mov    $0x2,%r10d
  mov    $0x3,%r11d
  mov    $0x4,%r9d
L121:
  movzbl (%rax),%ecx
  mov    %r8d,%edx
  test   %cl,%cl
  js     L65
L14:
  mov    %edx,%edx
  add    %rax,%rdx
L46:
  cmpb   $0x0,(%rax)
  je     L75
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L46
  add    $0x1,%edi
  cmp    %rax,%rsi
  jae    L121
  jmp    L126
L65:
  movsbl %cl,%edx
  and    $0xe0,%ecx
  cmp    $0xc0,%ecx
  je     L91
  mov    %edx,%ecx
  and    $0xf0,%ecx
  cmp    $0xe0,%ecx
  je     L3
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  jne    L99
  mov    %r9d,%edx
  jmp    L14
L99:
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0xffffffff,%edi
  mov    %edi,%eax
  add    $0x8,%rsp
  ret
L91:
  mov    %r10d,%edx
  jmp    L14
L3:
  mov    %r11d,%edx
  jmp    L14
L55:
  mov    $0x0,%edi
  jmp    L126
L75:
  mov    $0xffffffff,%edi
L126:
  mov    %edi,%eax
  ret
```

assistant: ```c
int64_t ce_utf8_strlen_between(const char *start, const char *end) {
  int64_t len = 0;
  int64_t byte_count = 0;
  while (start <= end) {
    if ((*start & 0x80) == 0) {
      byte_count = 1;
    } else if ((*start & 0xE0) == 0xC0) {
      byte_count = 2;
    } else if ((*start & 0xF0) == 0xE0) {
      byte_count = 3;
    } else if ((*start & 0xF8) == 0xF0) {
      byte_count = 4;
    } else {
      assert(!"unicode character claiming it has more than 4 bytes?!");
      return -1;
    }
    for (int64_t i = 0; i < byte_count; i++) {
      if (*start == 0)
        return -1;
      start++;
    }
    len++;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ce_utf8_strlen_between>:
  endbr64
  xor    %r8d,%r8d
  cmp    %rsi,%rdi
  ja     L89
L49:
  movzbl (%rdi),%eax
  mov    $0x1,%edx
  test   %al,%al
  js     L64
L70:
  add    %rdi,%rdx
  jmp    L37
  nopl   (%rax)
L106:
  movzbl (%rdi),%eax
L37:
  test   %al,%al
  je     L100
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  jne    L106
  add    $0x1,%r8d
  cmp    %rdi,%rsi
  jae    L49
L89:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L100:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %eax,%ecx
  movsbl %al,%edx
  and    $0xe0,%ecx
  cmp    $0xc0,%ecx
  je     L68
  mov    %edx,%ecx
  and    $0xf0,%ecx
  cmp    $0xe0,%ecx
  je     L46
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  jne    L15
  mov    $0x4,%edx
  jmp    L70
  nopl   0x0(%rax,%rax,1)
L68:
  mov    $0x2,%edx
  jmp    L70
L46:
  mov    $0x3,%edx
  jmp    L70
L15:
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int64_t ce_utf8_strlen_between(const char *start, const char *end) {
  int64_t len = 0;
  int64_t byte_count = 0;
  while (start <= end) {
    if ((*start & 0x80) == 0) {
      byte_count = 1;
    } else if ((*start & 0xE0) == 0xC0) {
      byte_count = 2;
    } else if ((*start & 0xF0) == 0xE0) {
      byte_count = 3;
    } else if ((*start & 0xF8) == 0xF0) {
      byte_count = 4;
    } else {
      assert(!"unicode character claiming it has more than 4 bytes?!");
      return -1;
    }
    for (int64_t i = 0; i < byte_count; i++) {
      if (*start == 0)
        return -1;
      start++;
    }
    len++;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ce_utf8_strlen_between>:
  endbr64
  xor    %r8d,%r8d
  cmp    %rsi,%rdi
  ja     L17
L84:
  movzbl (%rdi),%eax
  test   %al,%al
  js     L130
  je     L80
  add    $0x1,%rdi
L122:
  add    $0x1,%r8d
  cmp    %rsi,%rdi
  jbe    L84
L17:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L130:
  movsbl %al,%edx
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  je     L132
  mov    %edx,%eax
  and    $0xf0,%eax
  cmp    $0xe0,%eax
  je     L88
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  jne    L128
  lea    0x1(%rdi),%rax
  mov    $0x4,%edx
L103:
  cmpb   $0x0,(%rax)
  je     L80
  cmpb   $0x0,0x1(%rax)
  je     L80
  lea    0x2(%rax),%rdi
  cmp    $0x4,%edx
  jne    L122
  cmpb   $0x0,0x2(%rax)
  je     L80
  lea    0x3(%rax),%rdi
  jmp    L122
  nopl   0x0(%rax)
L132:
  cmpb   $0x0,0x1(%rdi)
  jne    L121
L80:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
L88:
  lea    0x1(%rdi),%rax
  mov    $0x3,%edx
  jmp    L103
L121:
  add    $0x2,%rdi
  jmp    L122
L128:
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int64_t ce_utf8_strlen_between(const char *start, const char *end) {
  int64_t len = 0;
  int64_t byte_count = 0;
  while (start <= end) {
    if ((*start & 0x80) == 0) {
      byte_count = 1;
    } else if ((*start & 0xE0) == 0xC0) {
      byte_count = 2;
    } else if ((*start & 0xF0) == 0xE0) {
      byte_count = 3;
    } else if ((*start & 0xF8) == 0xF0) {
      byte_count = 4;
    } else {
      assert(!"unicode character claiming it has more than 4 bytes?!");
      return -1;
    }
    for (int64_t i = 0; i < byte_count; i++) {
      if (*start == 0)
        return -1;
      start++;
    }
    len++;
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<IsEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L8
  movl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int IsEqual(int x, int y) {
  int e = 0;
  if (x == y)
    e = 1;
  return e;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<IsEqual>:
  endbr64
  cmp    %esi,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int IsEqual(int x, int y) {
  int e = 0;
  if (x == y)
    e = 1;
  return e;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IsEqual>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  sete   %al
  ret
```

assistant: ```c
int IsEqual(int x, int y) {
  int e = 0;
  if (x == y)
    e = 1;
  return e;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<IsEqual>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  sete   %al
  ret
```

assistant: ```c
int IsEqual(int x, int y) {
  int e = 0;
  if (x == y)
    e = 1;
  return e;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<model_finalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <view_clearStack@plt>
  mov    $0x0,%eax
  call   <model_array_clear@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void model_finalize(void) {
  view_clearStack();
  model_array_clear();
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<model_finalize>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <view_clearStack@plt>
  mov    $0x0,%eax
  call   <model_array_clear@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void model_finalize(void) {
  view_clearStack();
  model_array_clear();
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<model_finalize>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <view_clearStack@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <model_array_clear@plt>
```

assistant: ```c
void model_finalize(void) {
  view_clearStack();
  model_array_clear();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<model_finalize>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <view_clearStack@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <model_array_clear@plt>
```

assistant: ```c
void model_finalize(void) {
  view_clearStack();
  model_array_clear();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<asinh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <isfinite@plt>
  test   %eax,%eax
  jne    L18
  movsd  -0x18(%rbp),%xmm0
  jmp    L31
L18:
  movsd  -0x18(%rbp),%xmm0
  movq   D20(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D25(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <__fast_sqrt@plt>
  movsd  D25(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  addsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <__fast_log1p@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L4
  movsd  -0x8(%rbp),%xmm0
  jmp    L31
L4:
  movsd  -0x8(%rbp),%xmm0
  movq   D17(%rip),%xmm1
  xorpd  %xmm1,%xmm0
L31:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D20
data_type: qword
name: disassemble_data
arguments: label: D25
data_type: f64
name: disassemble_data
arguments: label: D17
data_type: f32[2]

tool: D20: 9223372036854775807

tool: D25: 1

tool: {"D17": [0.0,-0.0]}

assistant: ```c
double asinh(double x) {
  double z;
  if (!isfinite(x))
    return x;
  z = fabs(x);
  z = __fast_log1p(z + z * z / (__fast_sqrt(z * z + 1.0) + 1.0));
  return (x > 0.0 ? z : -z);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<asinh>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  call   <isfinite@plt>
  test   %eax,%eax
  jne    L8
L3:
  movq   %rbx,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  movq   %rbx,%xmm2
  mulsd  %xmm2,%xmm2
  movsd  D12(%rip),%xmm3
  movsd  %xmm2,0x8(%rsp)
  addsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  call   <__fast_sqrt@plt>
  movsd  D12(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %rbx,%xmm1
  andpd  D42(%rip),%xmm1
  addsd  %xmm1,%xmm0
  call   <__fast_log1p@plt>
  movq   %rbx,%xmm5
  movq   %xmm0,%rbx
  comisd D8(%rip),%xmm5
  ja     L3
  xorpd  D44(%rip),%xmm0
  movq   %xmm0,%rbx
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type: f64
name: retrieve_data
arguments: data_label: D42
type: qword[2]
name: retrieve_data
arguments: data_label: D8
type: f64[2]
name: retrieve_data
arguments: data_label: D44
type: byte[16]

tool: D12: 1

tool: {"D42": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D8": [0.0,-0.0]}

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double asinh(double x) {
  double z;
  if (!isfinite(x))
    return x;
  z = fabs(x);
  z = __fast_log1p(z + z * z / (__fast_sqrt(z * z + 1.0) + 1.0));
  return (x > 0.0 ? z : -z);
}
```