ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rvm_do_params>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x320,%edi
  mov    %rbx,%r13
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%r12
  sub    %rbx,%rbp
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L40:
  movzbl (%rdx),%eax
  sub    $0x64,%eax
  jne    L49
  movzbl 0x1(%rdx),%eax
  sub    $0x6f,%eax
  jne    L49
  movzbl 0x2(%rdx),%eax
L49:
  add    $0x8,%r13
  test   %eax,%eax
  je     L29
  mov    %rdx,(%rsi)
  mov    %ecx,%r14d
L38:
  mov    %rbx,%rdi
  call   <count_params@plt>
  mov    0x0(%r13),%rdx
  lea    0x0(%rbp,%r13,1),%rsi
  lea    0x1(%r14),%ecx
  cmp    %r14d,%eax
  jg     L40
L29:
  movslq %ecx,%rcx
  mov    %rdx,(%rsi)
  mov    %r12,%rax
  movq   $0x0,(%r12,%rcx,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char **rvm_do_params(char **rvm_params) {
  int i;
  char **rvm_do_params = (char **)malloc(100 * sizeof(char **));
  for (i = 0; i < count_params(rvm_params); i++) {
    if (!strcmp(rvm_params[i], "do"))
      break;
    rvm_do_params[i] = rvm_params[i];
  }
  rvm_do_params[i] = rvm_params[i];
  rvm_do_params[++i] = NULL;
  return rvm_do_params;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x58(%rbp)
  mov    -0x70(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x50(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  movb   $0x0,-0x11(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x54(%rbp)
  lea    -0x50(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: Buffer:(%d) 
Data:%s


assistant: ```c
int main(int argc, char **argv) {
  char buffer[64];
  int x = 1;
  snprintf(buffer, sizeof(buffer), argv[1]);
  buffer[sizeof(buffer) - 1] = 0;
  int howmuch = strlen(buffer);
  printf("Buffer:(%d) \nData:%s\n", howmuch, buffer);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdx
  mov    %rsp,%rbx
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  movb   $0x0,0x3f(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Buffer:(%d) 
Data:%s


assistant: ```c
int main(int argc, char **argv) {
  char buffer[64];
  int x = 1;
  snprintf(buffer, sizeof(buffer), argv[1]);
  buffer[sizeof(buffer) - 1] = 0;
  int howmuch = strlen(buffer);
  printf("Buffer:(%d) \nData:%s\n", howmuch, buffer);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x50,%rsp
  mov    0x8(%rsi),%rdx
  mov    $0x40,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  movb   $0x0,0x3f(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: Buffer:(%d) 
Data:%s


assistant: ```c
int main(int argc, char **argv) {
  char buffer[64];
  int x = 1;
  snprintf(buffer, sizeof(buffer), argv[1]);
  buffer[sizeof(buffer) - 1] = 0;
  int howmuch = strlen(buffer);
  printf("Buffer:(%d) \nData:%s\n", howmuch, buffer);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x50,%rsp
  mov    0x8(%rsi),%rdx
  mov    $0x40,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  movb   $0x0,0x3f(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdx
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: Buffer:(%d) 
Data:%s


assistant: ```c
int main(int argc, char **argv) {
  char buffer[64];
  int x = 1;
  snprintf(buffer, sizeof(buffer), argv[1]);
  buffer[sizeof(buffer) - 1] = 0;
  int howmuch = strlen(buffer);
  printf("Buffer:(%d) \nData:%s\n", howmuch, buffer);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x80(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L25
L8:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L77
  addl   $0x1,-0x80(%rbp)
L77:
  addl   $0x1,-0x7c(%rbp)
L25:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x7c(%rbp)
  jl     L8
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x80(%rbp)
  jne    L55
  movl   $0x0,-0x78(%rbp)
  jmp    L52
L30:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x78(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x70(%rbp,%rdx,1)
  addl   $0x1,-0x78(%rbp)
L52:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x78(%rbp)
  jl     L30
L55:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x80(%rbp)
  jne    L6
  movzbl -0x70(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L6
  movzbl -0x70(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x70(%rbp)
  movl   $0x1,-0x74(%rbp)
  jmp    L11
L42:
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x74(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x70(%rbp,%rdx,1)
  addl   $0x1,-0x74(%rbp)
L11:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x74(%rbp)
  jl     L42
L6:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L83
  call   <__stack_chk_fail@plt>
L83:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string

tool: D18: %100s

tool: D13: %s


assistant: ```c
int main() {
  char word[101];
  scanf("%100s", word);
  int number_of_upper = 0;
  for (int i = 0; i < strlen(word); i++) {
    if (isupper(word[i])) {
      number_of_upper++;
    }
  }
  if (number_of_upper == strlen(word)) {
    for (int i = 0; i < strlen(word); i++) {
      word[i] = tolower(word[i]);
    }
  }
  if (number_of_upper == (strlen(word) - 1) && islower(word[0])) {
    word[0] = toupper(word[0]);
    for (int i = 1; i < strlen(word); i++) {
      word[i] = tolower(word[i]);
    }
  }
  printf("%s\n", word);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    %rsp,%r12
  jmp    L52
L16:
  movsbl (%rbx,%r12,1),%edi
  call   <isupper@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
L52:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  mov    %rsp,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  je     L86
L36:
  mov    %rsp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebp,%eax
  je     L14
L74:
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L86:
  mov    %rsp,%r12
  mov    %r12,%rbx
  mov    %rsp,%r13
  jmp    L11
L114:
  movsbl -0x1(%rbx),%edi
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
L11:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  add    $0x1,%rbx
  lea    -0x1(%rbx),%eax
  sub    %r12d,%eax
  cmp    %eax,%edx
  jg     L114
  jmp    L36
L14:
  movsbl (%rsp),%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L74
  movsbl (%rsp),%edi
  call   <toupper@plt>
  mov    %al,(%rsp)
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L73
L106:
  movsbl (%rbx,%rbp,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
L73:
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L106
  jmp    L74
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D14
type: string

tool: D10: %100s

tool: D14: %s


assistant: ```c
int main() {
  char word[101];
  scanf("%100s", word);
  int number_of_upper = 0;
  for (int i = 0; i < strlen(word); i++) {
    if (isupper(word[i])) {
      number_of_upper++;
    }
  }
  if (number_of_upper == strlen(word)) {
    for (int i = 0; i < strlen(word); i++) {
      word[i] = tolower(word[i]);
    }
  }
  if (number_of_upper == (strlen(word) - 1) && islower(word[0])) {
    word[0] = toupper(word[0]);
    for (int i = 1; i < strlen(word); i++) {
      word[i] = tolower(word[i]);
    }
  }
  printf("%s\n", word);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L35
  nopl   (%rax)
L47:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isupper@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%rbx
L35:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L47
  mov    %rbp,%rdi
  mov    %rbp,%rbx
  call   <strlen@plt>
  cmp    %r12d,%eax
  je     L36
L22:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  je     L58
L49:
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L89:
  movsbl -0x1(%rbx),%edi
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
L36:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  lea    -0x1(%rbx),%eax
  sub    %ebp,%eax
  cmp    %eax,%r8d
  jg     L89
  jmp    L22
L58:
  movsbl (%rsp),%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L49
  movsbl (%rsp),%edi
  xor    %ebx,%ebx
  call   <toupper@plt>
  mov    %al,(%rsp)
  jmp    L7
L105:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
L7:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L105
  jmp    L49
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D18
datatype: string

tool: D2: %100s

tool: D18: %s


assistant: ```c
int main() {
  char word[101];
  scanf("%100s", word);
  int number_of_upper = 0;
  for (int i = 0; i < strlen(word); i++) {
    if (isupper(word[i])) {
      number_of_upper++;
    }
  }
  if (number_of_upper == strlen(word)) {
    for (int i = 0; i < strlen(word); i++) {
      word[i] = tolower(word[i]);
    }
  }
  if (number_of_upper == (strlen(word) - 1) && islower(word[0])) {
    word[0] = toupper(word[0]);
    for (int i = 1; i < strlen(word); i++) {
      word[i] = tolower(word[i]);
    }
  }
  printf("%s\n", word);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L6
  nopl   (%rax)
L101:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isupper@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%rbx
L6:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L101
  mov    %rbp,%rdi
  mov    %rbp,%rbx
  call   <strlen@plt>
  cmp    %r12d,%eax
  je     L98
L46:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  je     L87
L92:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L91
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L48:
  movsbl -0x1(%rbx),%edi
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
L98:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  lea    -0x1(%rbx),%eax
  sub    %ebp,%eax
  cmp    %eax,%r8d
  jg     L48
  jmp    L46
L87:
  movsbl (%rsp),%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L92
  movsbl (%rsp),%edi
  xor    %ebx,%ebx
  call   <toupper@plt>
  mov    %al,(%rsp)
  jmp    L38
L11:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
L38:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L11
  jmp    L92
L91:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D8: %100s

tool: D0: %s


assistant: ```c
int main() {
  char word[101];
  scanf("%100s", word);
  int number_of_upper = 0;
  for (int i = 0; i < strlen(word); i++) {
    if (isupper(word[i])) {
      number_of_upper++;
    }
  }
  if (number_of_upper == strlen(word)) {
    for (int i = 0; i < strlen(word); i++) {
      word[i] = tolower(word[i]);
    }
  }
  if (number_of_upper == (strlen(word) - 1) && islower(word[0])) {
    word[0] = toupper(word[0]);
    for (int i = 1; i < strlen(word); i++) {
      word[i] = tolower(word[i]);
    }
  }
  printf("%s\n", word);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    $0x1,%eax
  jmp    L2
L7:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fak>
  imul   -0x4(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
unsigned int fak(unsigned int n) {
  if (n == 0) {
    return 1;
  } else {
    return n * fak(n - 1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fak>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L3
  ret
L3:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fak>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int fak(unsigned int n) {
  if (n == 0) {
    return 1;
  } else {
    return n * fak(n - 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fak>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L1
  nopl   (%rax)
L11:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L11
L1:
  ret
```

assistant: ```c
unsigned int fak(unsigned int n) {
  if (n == 0) {
    return 1;
  } else {
    return n * fak(n - 1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fak>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L11
  nopl   (%rax)
L5:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L5
L11:
  ret
```

assistant: ```c
unsigned int fak(unsigned int n) {
  if (n == 0) {
    return 1;
  } else {
    return n * fak(n - 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<priority>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0xe,%eax
  cmp    $0x14,%eax
  ja     L3
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D8(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
  jmp    L28
  mov    $0x1,%eax
  jmp    L28
  mov    $0x0,%eax
  jmp    L28
L3:
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int priority(int op) {
  switch (op) {
  case 14:
    return (2);
  case 24:
  case 19:
    return (1);
  case 34:
  case 29:
    return (0);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<priority>:
  endbr64
  sub    $0xe,%edi
  cmp    $0x14,%edi
  ja     L6
  mov    %edi,%edi
  lea    D7(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
  mov    $0x0,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
  mov    $0x2,%eax
  ret
```

assistant: ```c
int priority(int op) {
  switch (op) {
  case 14:
    return (2);
  case 24:
  case 19:
    return (1);
  case 34:
  case 29:
    return (0);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<priority>:
  endbr64
  sub    $0xe,%edi
  xor    %eax,%eax
  cmp    $0x14,%edi
  ja     L7
  lea    D4(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: 

assistant: ```c
int priority(int op) {
  switch (op) {
  case 14:
    return (2);
  case 24:
  case 19:
    return (1);
  case 34:
  case 29:
    return (0);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<priority>:
  endbr64
  sub    $0xe,%edi
  xor    %eax,%eax
  cmp    $0x14,%edi
  ja     L6
  lea    D6(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L6:
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string

tool: D6: 

assistant: ```c
int priority(int op) {
  switch (op) {
  case 14:
    return (2);
  case 24:
  case 19:
    return (1);
  case 34:
  case 29:
    return (0);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<boxfill8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L14
L28:
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L26:
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x20(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jle    L26
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L28
  nop
  pop    %rbp
  ret
```

assistant: ```c
void boxfill8(unsigned char *vram, int xsize, unsigned char c, int x0, int y0, int x1, int y1) {
  int i, j;
  for (i = x0; i <= x1; i++)
    for (j = y0; j <= y1; j++) {
      vram[j * xsize + i] = c;
    }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<boxfill8>:
  endbr64
  push   %rbx
  mov    0x10(%rsp),%ebx
  cmp    %r9d,%ecx
  jg     L43
  mov    %rdi,%r11
  mov    %esi,%eax
  mov    %ecx,%r10d
  mov    %edx,%esi
  mov    %r8d,%edx
  imul   %eax,%edx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  add    %rcx,%rdx
  add    %rdx,%r11
  add    $0x1,%r9d
  movslq %eax,%rcx
  lea    0x1(%rbx),%edi
  jmp    L7
L55:
  mov    %sil,(%rdx)
  add    $0x1,%eax
  add    %rcx,%rdx
  cmp    %edi,%eax
  jne    L55
L20:
  add    $0x1,%r10d
  add    $0x1,%r11
  cmp    %r9d,%r10d
  je     L43
L7:
  mov    %r11,%rdx
  mov    %r8d,%eax
  cmp    %ebx,%r8d
  jle    L55
  jmp    L20
L43:
  pop    %rbx
  ret
```

assistant: ```c
void boxfill8(unsigned char *vram, int xsize, unsigned char c, int x0, int y0, int x1, int y1) {
  int i, j;
  for (i = x0; i <= x1; i++)
    for (j = y0; j <= y1; j++) {
      vram[j * xsize + i] = c;
    }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<boxfill8>:
  endbr64
  push   %rbx
  mov    0x10(%rsp),%ebx
  cmp    %r9d,%ecx
  jg     L2
  mov    %esi,%eax
  mov    %edx,%esi
  mov    %r8d,%edx
  mov    %ecx,%r10d
  imul   %eax,%edx
  movslq %ecx,%rcx
  mov    %rdi,%r11
  add    $0x1,%r9d
  lea    0x1(%rbx),%edi
  movslq %edx,%rdx
  add    %rcx,%rdx
  movslq %eax,%rcx
  add    %rdx,%r11
  nopl   0x0(%rax)
L16:
  mov    %r11,%rdx
  mov    %r8d,%eax
  cmp    %ebx,%r8d
  jg     L30
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%eax
  mov    %sil,(%rdx)
  add    %rcx,%rdx
  cmp    %edi,%eax
  jne    L25
L30:
  add    $0x1,%r10d
  add    $0x1,%r11
  cmp    %r9d,%r10d
  jne    L16
L2:
  pop    %rbx
  ret
```

assistant: ```c
void boxfill8(unsigned char *vram, int xsize, unsigned char c, int x0, int y0, int x1, int y1) {
  int i, j;
  for (i = x0; i <= x1; i++)
    for (j = y0; j <= y1; j++) {
      vram[j * xsize + i] = c;
    }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<boxfill8>:
  endbr64
  mov    %rdi,%r11
  mov    %esi,%eax
  mov    0x8(%rsp),%edi
  mov    %ecx,%r10d
  mov    %edx,%esi
  cmp    %r9d,%ecx
  jg     L13
  cmp    %edi,%r8d
  jg     L13
  mov    %r8d,%edx
  movslq %ecx,%rcx
  add    $0x1,%r9d
  add    $0x1,%edi
  imul   %eax,%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  movslq %eax,%rcx
  add    %rdx,%r11
  nopl   0x0(%rax,%rax,1)
L35:
  mov    %r11,%rdx
  mov    %r8d,%eax
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x1,%eax
  mov    %sil,(%rdx)
  add    %rcx,%rdx
  cmp    %eax,%edi
  jne    L29
  add    $0x1,%r10d
  add    $0x1,%r11
  cmp    %r9d,%r10d
  jne    L35
L13:
  ret
```

assistant: ```c
void boxfill8(unsigned char *vram, int xsize, unsigned char c, int x0, int y0, int x1, int y1) {
  int i, j;
  for (i = x0; i <= x1; i++)
    for (j = y0; j <= y1; j++) {
      vram[j * xsize + i] = c;
    }
  return;
}
```