ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: hello world ! I love you


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("hello world ! I love you\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: hello world ! I love you


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("hello world ! I love you\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: hello world ! I love you


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("hello world ! I love you\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: hello world ! I love you


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("hello world ! I love you\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<MYwrite_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L2:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <MYwrite_char@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void MYwrite_string(int sock, char *s) {
  int i;
  for (i = 0; MYwrite_char(sock, s[i]), s[i]; i++)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MYwrite_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
L9:
  movsbl (%rbx),%esi
  mov    %ebp,%edi
  call   <MYwrite_char@plt>
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void MYwrite_string(int sock, char *s) {
  int i;
  for (i = 0; MYwrite_char(sock, s[i]), s[i]; i++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MYwrite_string>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nop
L1:
  movsbl (%rbx),%esi
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <MYwrite_char@plt>
  cmpb   $0x0,-0x1(%rbx)
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void MYwrite_string(int sock, char *s) {
  int i;
  for (i = 0; MYwrite_char(sock, s[i]), s[i]; i++)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MYwrite_string>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nop
L2:
  movsbl (%rbx),%esi
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <MYwrite_char@plt>
  cmpb   $0x0,-0x1(%rbx)
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void MYwrite_string(int sock, char *s) {
  int i;
  for (i = 0; MYwrite_char(sock, s[i]), s[i]; i++)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x400(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x418(%rbp)
  movl   $0x0,-0x414(%rbp)
  movl   $0x0,-0x410(%rbp)
  lea    -0x400(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x404(%rbp)
  jmp    L39
L105:
  mov    -0x418(%rbp),%eax
  mov    %eax,-0x40c(%rbp)
  mov    -0x414(%rbp),%eax
  mov    %eax,-0x408(%rbp)
  jmp    L48
L102:
  addl   $0x1,-0x410(%rbp)
  subl   $0x1,-0x40c(%rbp)
  addl   $0x1,-0x408(%rbp)
L48:
  cmpl   $0x0,-0x40c(%rbp)
  js     L69
  mov    -0x408(%rbp),%eax
  cmp    -0x404(%rbp),%eax
  jge    L69
  mov    -0x40c(%rbp),%eax
  cltq
  movzbl -0x400(%rbp,%rax,1),%edx
  mov    -0x408(%rbp),%eax
  cltq
  movzbl -0x400(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L102
L69:
  addl   $0x1,-0x418(%rbp)
  addl   $0x1,-0x414(%rbp)
L39:
  mov    -0x414(%rbp),%eax
  cmp    -0x404(%rbp),%eax
  jl     L105
  movl   $0x0,-0x418(%rbp)
  movl   $0x1,-0x414(%rbp)
  jmp    L82
L20:
  mov    -0x418(%rbp),%eax
  mov    %eax,-0x40c(%rbp)
  mov    -0x414(%rbp),%eax
  mov    %eax,-0x408(%rbp)
  jmp    L9
L41:
  addl   $0x1,-0x410(%rbp)
  subl   $0x1,-0x40c(%rbp)
  addl   $0x1,-0x408(%rbp)
L9:
  cmpl   $0x0,-0x40c(%rbp)
  js     L94
  mov    -0x408(%rbp),%eax
  cmp    -0x404(%rbp),%eax
  jge    L94
  mov    -0x40c(%rbp),%eax
  cltq
  movzbl -0x400(%rbp,%rax,1),%edx
  mov    -0x408(%rbp),%eax
  cltq
  movzbl -0x400(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L41
L94:
  addl   $0x1,-0x418(%rbp)
  addl   $0x1,-0x414(%rbp)
L82:
  mov    -0x414(%rbp),%eax
  cmp    -0x404(%rbp),%eax
  jl     L20
  mov    -0x410(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L119
  call   <__stack_chk_fail@plt>
L119:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main() {
  char s[1010];
  gets(s);
  int i = 0, j = 0, count = 0;
  int len = strlen(s);
  int k, l;
  while (j < len) {
    k = i;
    l = j;
    while (k >= 0 && l < len && s[k] == s[l]) {
      count++;
      k--;
      l++;
    }
    i++;
    j++;
  }
  i = 0;
  j = 1;
  while (j < len) {
    k = i;
    l = j;
    while (k >= 0 && l < len && s[k] == s[l]) {
      count++;
      k--;
      l++;
    }
    i++;
    j++;
  }
  printf("%d\n", count);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jle    L34
  mov    %eax,%ebx
  mov    $0x0,%r11d
  mov    $0x0,%esi
  lea    0x1(%rsp),%r10
  lea    -0x1(%rsp),%r9
  jmp    L28
L146:
  add    $0x1,%r11
  cmp    %rbx,%r11
  je     L124
L28:
  test   %r11d,%r11d
  js     L146
  cmp    %r11d,%edi
  jle    L146
  lea    -0x1(%r11),%rdx
  lea    0x1(%r11),%rax
L100:
  movzbl (%r9,%rax,1),%ecx
  cmp    %cl,(%r10,%rdx,1)
  jne    L146
  add    $0x1,%esi
  mov    %edx,%ecx
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %eax,%edi
  setg   %r8b
  sub    $0x1,%rdx
  add    $0x1,%rax
  test   %cl,%r8b
  jne    L100
  jmp    L146
L34:
  mov    $0x0,%esi
L124:
  mov    $0x0,%r11d
  mov    $0x1,%ebx
  lea    0x1(%rsp),%r10
  lea    -0x1(%rsp),%r9
  cmp    $0x1,%edi
  jg     L85
L25:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    $0x0,%eax
  add    $0x400,%rsp
  pop    %rbx
  ret
L55:
  add    $0x1,%ebx
  add    $0x1,%r11
  cmp    %ebx,%edi
  je     L25
L85:
  test   %r11d,%r11d
  js     L55
  cmp    %ebx,%edi
  jle    L55
  lea    -0x1(%r11),%rdx
  lea    0x2(%r11),%rax
L76:
  movzbl (%r9,%rax,1),%ecx
  cmp    %cl,(%r10,%rdx,1)
  jne    L55
  add    $0x1,%esi
  mov    %edx,%ecx
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %eax,%edi
  setg   %r8b
  sub    $0x1,%rdx
  add    $0x1,%rax
  test   %cl,%r8b
  jne    L76
  jmp    L55
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: %d


assistant: ```c
int main() {
  char s[1010];
  gets(s);
  int i = 0, j = 0, count = 0;
  int len = strlen(s);
  int k, l;
  while (j < len) {
    k = i;
    l = j;
    while (k >= 0 && l < len && s[k] == s[l]) {
      count++;
      k--;
      l++;
    }
    i++;
    j++;
  }
  i = 0;
  j = 1;
  while (j < len) {
    k = i;
    l = j;
    while (k >= 0 && l < len && s[k] == s[l]) {
      count++;
      k--;
      l++;
    }
    i++;
    j++;
  }
  printf("%d\n", count);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L87
  mov    %eax,%edi
  movslq %eax,%rbx
  xor    %esi,%esi
  xor    %eax,%eax
  lea    0x1(%rsp),%r10
  lea    -0x1(%rsp),%r9
  xchg   %ax,%ax
L74:
  lea    0x1(%rax),%r11
  cmp    %eax,%edi
  jle    L40
  lea    0x1(%rax),%r11
  lea    -0x1(%rax),%rdx
  mov    %r11,%rax
  jmp    L120
  nopl   (%rax)
L41:
  mov    %edx,%ecx
  add    $0x1,%esi
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %eax,%edi
  setg   %r8b
  sub    $0x1,%rdx
  add    $0x1,%rax
  test   %cl,%r8b
  je     L40
L120:
  movzbl (%r9,%rax,1),%ecx
  cmp    %cl,(%r10,%rdx,1)
  je     L41
L40:
  mov    %r11,%rax
  cmp    %rbx,%r11
  jne    L74
  cmp    $0x1,%edi
  jle    L54
  mov    $0x1,%r11d
  lea    0x1(%rsp),%r10
  lea    -0x1(%rsp),%r9
  mov    $0xffffffffffffffff,%rbx
  nopl   0x0(%rax)
L100:
  cmp    %r11d,%edi
  jle    L67
  lea    0x3(%rbx),%rdx
  mov    %rbx,%rax
  jmp    L96
  cs nopw 0x0(%rax,%rax,1)
L117:
  mov    %eax,%ecx
  add    $0x1,%esi
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %edx,%edi
  setg   %r8b
  sub    $0x1,%rax
  add    $0x1,%rdx
  test   %cl,%r8b
  je     L67
L96:
  movzbl (%r9,%rdx,1),%ecx
  cmp    %cl,(%r10,%rax,1)
  je     L117
L67:
  add    $0x1,%r11d
  add    $0x1,%rbx
  cmp    %r11d,%edi
  jne    L100
L54:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  add    $0x408,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L87:
  xor    %esi,%esi
  jmp    L54
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: %d


assistant: ```c
int main() {
  char s[1010];
  gets(s);
  int i = 0, j = 0, count = 0;
  int len = strlen(s);
  int k, l;
  while (j < len) {
    k = i;
    l = j;
    while (k >= 0 && l < len && s[k] == s[l]) {
      count++;
      k--;
      l++;
    }
    i++;
    j++;
  }
  i = 0;
  j = 1;
  while (j < len) {
    k = i;
    l = j;
    while (k >= 0 && l < len && s[k] == s[l]) {
      count++;
      k--;
      l++;
    }
    i++;
    j++;
  }
  printf("%d\n", count);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %esi,%esi
  test   %eax,%eax
  jle    L59
  lea    0x1(%rax),%ebp
  mov    %eax,%r9d
  mov    $0x1,%r11d
  xor    %esi,%esi
  mov    %rbp,%rbx
  lea    0x1(%rsp),%r8
  lea    -0x1(%rsp),%rdi
  nopl   0x0(%rax,%rax,1)
L68:
  lea    -0x2(%r11),%rdx
  mov    %r11,%rax
  jmp    L71
  nopl   0x0(%rax)
L129:
  mov    %edx,%ecx
  add    $0x1,%esi
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %eax,%r9d
  setg   %r10b
  sub    $0x1,%rdx
  add    $0x1,%rax
  test   %cl,%r10b
  je     L65
L71:
  movzbl (%rdi,%rax,1),%ecx
  cmp    %cl,(%r8,%rdx,1)
  je     L129
L65:
  mov    %r11d,%eax
  add    $0x1,%r11
  cmp    %rbp,%r11
  jne    L68
  cmp    %eax,%r9d
  jle    L51
L111:
  mov    $0x2,%r11d
  nop
L45:
  lea    -0x3(%r11),%rdx
  mov    %r11,%rax
  jmp    L128
  nopl   0x0(%rax)
L70:
  mov    %edx,%ecx
  add    $0x1,%esi
  not    %ecx
  shr    $0x1f,%ecx
  cmp    %eax,%r9d
  setg   %r10b
  sub    $0x1,%rdx
  add    $0x1,%rax
  test   %cl,%r10b
  je     L35
L128:
  movzbl (%rdi,%rax,1),%ecx
  cmp    %cl,(%r8,%rdx,1)
  je     L70
L35:
  add    $0x1,%r11
  cmp    %r11,%rbx
  jne    L45
L59:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x408,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L51:
  cmp    $0x1,%r9d
  jle    L59
  jmp    L111
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main() {
  char s[1010];
  gets(s);
  int i = 0, j = 0, count = 0;
  int len = strlen(s);
  int k, l;
  while (j < len) {
    k = i;
    l = j;
    while (k >= 0 && l < len && s[k] == s[l]) {
      count++;
      k--;
      l++;
    }
    i++;
    j++;
  }
  i = 0;
  j = 1;
  while (j < len) {
    k = i;
    l = j;
    while (k >= 0 && l < len && s[k] == s[l]) {
      count++;
      k--;
      l++;
    }
    i++;
    j++;
  }
  printf("%d\n", count);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f6c6c6568,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  lea    -0x12(%rbp),%rax
  mov    $0x5,%edx
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L8
  mov    $0x1,%eax
  jmp    L19
L8:
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: hello

assistant: ```c
int main(int argc, char **buffer) {
  char buf[10] = "hello";
  int cmp;
  if ((cmp = memcmp(buf, "hello", 5)))
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6f6c6c6568,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  lea    0xe(%rsp),%rdi
  mov    $0x5,%edx
  lea    D5(%rip),%rsi
  call   <memcmp@plt>
  test   %eax,%eax
  setne  %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: hello

assistant: ```c
int main(int argc, char **buffer) {
  char buf[10] = "hello";
  int cmp;
  if ((cmp = memcmp(buf, "hello", 5)))
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x5,%edx
  lea    D5(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6f6c6c6568,%rax
  lea    0xe(%rsp),%rdi
  mov    %rax,0xe(%rsp)
  xor    %eax,%eax
  mov    %ax,0x16(%rsp)
  call   <memcmp@plt>
  test   %eax,%eax
  setne  %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: hello

assistant: ```c
int main(int argc, char **buffer) {
  char buf[10] = "hello";
  int cmp;
  if ((cmp = memcmp(buf, "hello", 5)))
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x5,%edx
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6f6c6c6568,%rax
  lea    0xe(%rsp),%rdi
  mov    %rax,0xe(%rsp)
  xor    %eax,%eax
  mov    %ax,0x16(%rsp)
  call   <memcmp@plt>
  test   %eax,%eax
  setne  %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: hello

assistant: ```c
int main(int argc, char **buffer) {
  char buf[10] = "hello";
  int cmp;
  if ((cmp = memcmp(buf, "hello", 5)))
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rotate_square_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L26:
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  addl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rotate_square_matrix(const int *input, const int n, int *result) {
  int row = 0, i = 0;
  for (; row < n; ++row, i = 0)
    for (; i < n; ++i)
      result[(row * n) + i] = input[(n - i - 1) * n + row];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rotate_square_matrix>:
  endbr64
  test   %esi,%esi
  jle    L29
  push   %rbx
  mov    %esi,%r10d
  lea    -0x1(%rsi),%eax
  mov    %eax,%ecx
  imul   %esi,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%r9
  movslq %esi,%rbx
  shl    $0x2,%rbx
  mov    %eax,%eax
  lea    0x4(%rdx,%rax,4),%rsi
  mov    %r10d,%edi
  neg    %edi
  movslq %edi,%rdi
  shl    $0x2,%rdi
  mov    $0x0,%r8d
  mov    %r10d,%r11d
  neg    %r11
  shl    $0x2,%r11
L16:
  lea    (%r11,%rsi,1),%rax
  mov    %r9,%rdx
L27:
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  add    %rdi,%rdx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L27
  add    $0x1,%r8d
  add    $0x4,%r9
  add    %rbx,%rsi
  cmp    %r8d,%r10d
  jne    L16
  pop    %rbx
  ret
L29:
  ret
```

assistant: ```c
void rotate_square_matrix(const int *input, const int n, int *result) {
  int row = 0, i = 0;
  for (; row < n; ++row, i = 0)
    for (; i < n; ++i)
      result[(row * n) + i] = input[(n - i - 1) * n + row];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotate_square_matrix>:
  endbr64
  mov    %esi,%r10d
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  mov    $0xfffffffffffffffc,%r11
  xor    %r8d,%r8d
  mov    %eax,%ecx
  shl    $0x2,%rax
  imul   %esi,%ecx
  sub    %rax,%r11
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%r9
  movslq %esi,%rdi
  lea    0x4(%rdx,%rax,1),%rsi
  shl    $0x2,%rdi
  nopw   0x0(%rax,%rax,1)
L17:
  lea    (%r11,%rsi,1),%rax
  mov    %r9,%rdx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rdx),%ecx
  add    $0x4,%rax
  sub    %rdi,%rdx
  mov    %ecx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L5
  add    $0x1,%r8d
  add    $0x4,%r9
  add    %rdi,%rsi
  cmp    %r8d,%r10d
  jne    L17
L20:
  ret
```

assistant: ```c
void rotate_square_matrix(const int *input, const int n, int *result) {
  int row = 0, i = 0;
  for (; row < n; ++row, i = 0)
    for (; i < n; ++i)
      result[(row * n) + i] = input[(n - i - 1) * n + row];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotate_square_matrix>:
  endbr64
  mov    %esi,%r10d
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  mov    $0xfffffffffffffffc,%r11
  xor    %r8d,%r8d
  mov    %eax,%ecx
  shl    $0x2,%rax
  imul   %esi,%ecx
  sub    %rax,%r11
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%r9
  movslq %esi,%rdi
  lea    0x4(%rdx,%rax,1),%rsi
  shl    $0x2,%rdi
  nopw   0x0(%rax,%rax,1)
L15:
  lea    (%r11,%rsi,1),%rax
  mov    %r9,%rdx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rdx),%ecx
  add    $0x4,%rax
  sub    %rdi,%rdx
  mov    %ecx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L19
  add    $0x1,%r8d
  add    $0x4,%r9
  add    %rdi,%rsi
  cmp    %r8d,%r10d
  jne    L15
L18:
  ret
```

assistant: ```c
void rotate_square_matrix(const int *input, const int n, int *result) {
  int row = 0, i = 0;
  for (; row < n; ++row, i = 0)
    for (; i < n; ++i)
      result[(row * n) + i] = input[(n - i - 1) * n + row];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x14(%rbp)
  jmp    L11
L10:
  mov    -0x2c(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  mov    %dl,-0xe(%rbp,%rax,1)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x2c(%rbp)
  subl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x0,-0x14(%rbp)
  jns    L10
  movb   $0x0,-0x9(%rbp)
  mov    -0x30(%rbp),%ecx
  lea    -0xe(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <text@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void number(unsigned x, unsigned y, unsigned n, unsigned color) {
  char s[6];
  int i;
  for (i = 4; i >= 0; --i) {
    s[i] = '0' + n % 10;
    n /= 10;
  }
  s[5] = 0;
  text(x, y, s, color);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<number>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%r8d
  mov    %esi,%r9d
  mov    %ecx,%r11d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rcx
  lea    -0x3(%rsp),%r10
  mov    $0xcccccccd,%edi
L8:
  mov    %edx,%eax
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,0x4(%rcx)
  mov    %eax,%edx
  sub    $0x1,%rcx
  cmp    %r10,%rcx
  jne    L8
  movb   $0x0,0x7(%rsp)
  lea    0x2(%rsp),%rdx
  mov    %r11d,%ecx
  mov    %r9d,%esi
  mov    %r8d,%edi
  call   <text@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void number(unsigned x, unsigned y, unsigned n, unsigned color) {
  char s[6];
  int i;
  for (i = 4; i >= 0; --i) {
    s[i] = '0' + n % 10;
    n /= 10;
  }
  s[5] = 0;
  text(x, y, s, color);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<number>:
  endbr64
  push   %r12
  mov    %edi,%r9d
  mov    %ecx,%r12d
  mov    %esi,%r10d
  mov    $0xcccccccd,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%r11
  lea    -0x3(%rsp),%r8
  mov    %r11,%rcx
L1:
  mov    %edx,%eax
  sub    $0x1,%rcx
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,0x5(%rcx)
  mov    %eax,%edx
  cmp    %r8,%rcx
  jne    L1
  mov    %r12d,%ecx
  mov    %r11,%rdx
  mov    %r10d,%esi
  mov    %r9d,%edi
  movb   $0x0,0x7(%rsp)
  call   <text@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void number(unsigned x, unsigned y, unsigned n, unsigned color) {
  char s[6];
  int i;
  for (i = 4; i >= 0; --i) {
    s[i] = '0' + n % 10;
    n /= 10;
  }
  s[5] = 0;
  text(x, y, s, color);
}
```