ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strdup_escape>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L55
  mov    %rdi,%r13
  xor    %ebp,%ebp
  lea    D0(%rip),%r12
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%ebp
  lea    0x1(%rax),%rdi
L35:
  mov    %r12,%rsi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L2
  mov    %r13,%rdi
  movslq %ebp,%rbp
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rcx
  jmp    L8
  xchg   %ax,%ax
L21:
  add    $0x1,%r13
  mov    %bl,(%rdx)
  lea    0x1(%rdx),%rcx
  movzbl 0x0(%r13),%ebx
  test   %bl,%bl
  je     L24
L8:
  cmp    $0x5c,%bl
  je     L75
  mov    %rcx,%rdx
  cmp    $0x22,%bl
  jne    L21
L75:
  movb   $0x5c,(%rcx)
  lea    0x1(%rcx),%rdx
  jmp    L21
  nopl   0x0(%rax)
L24:
  movb   $0x0,0x1(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L55:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D0: \"

assistant: ```c
char *strdup_escape(const char *str) {
  const char *input = str;
  char *p, *ret;
  int escapes;
  if (!strlen(str))
    return NULL;
  escapes = 0;
  while ((input = strpbrk(input, "\\\"")) != NULL) {
    escapes++;
    input++;
  }
  p = ret = malloc(strlen(str) + escapes + 1);
  while (*str) {
    if (*str == '\\' || *str == '\"')
      *p++ = '\\';
    *p++ = *str++;
  }
  *p = '\0';
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strdup_escape>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L8
  mov    %rdi,%r13
  xor    %ebp,%ebp
  lea    D1(%rip),%r12
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x1,%ebp
  lea    0x1(%rax),%rdi
L28:
  mov    %r12,%rsi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L12
  mov    %r13,%rdi
  movslq %ebp,%rbp
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  jmp    L39
  xchg   %ax,%ax
L74:
  add    $0x1,%r13
  mov    %bl,(%rdx)
  lea    0x1(%rdx),%rcx
  movzbl 0x0(%r13),%ebx
  test   %bl,%bl
  je     L15
L5:
  mov    %rcx,%rdx
L39:
  cmp    $0x5c,%bl
  je     L55
  cmp    $0x22,%bl
  jne    L74
L55:
  add    $0x1,%r13
  mov    %bl,0x1(%rdx)
  lea    0x1(%rdx),%rsi
  lea    0x2(%rdx),%rcx
  movzbl 0x0(%r13),%ebx
  movb   $0x5c,(%rdx)
  test   %bl,%bl
  jne    L5
L2:
  movb   $0x0,0x1(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rdx,%rsi
  jmp    L2
  nopl   (%rax)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: \"

assistant: ```c
char *strdup_escape(const char *str) {
  const char *input = str;
  char *p, *ret;
  int escapes;
  if (!strlen(str))
    return NULL;
  escapes = 0;
  while ((input = strpbrk(input, "\\\"")) != NULL) {
    escapes++;
    input++;
  }
  p = ret = malloc(strlen(str) + escapes + 1);
  while (*str) {
    if (*str == '\\' || *str == '\"')
      *p++ = '\\';
    *p++ = *str++;
  }
  *p = '\0';
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_header_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L19
L6:
  addq   $0x18,-0x10(%rbp)
  mov    $0x81,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x80,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: x-kahoot-session-token:

assistant: ```c
char *get_header_token(char *response) {
  char *t_header = strstr(response, "x-kahoot-session-token:");
  if (t_header == NULL) {
    return NULL;
  } else {
    t_header = t_header + 24;
    char *token = malloc(129);
    memcpy(token, t_header, 128);
    token[128] = '\0';
    return token;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_header_token>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
  lea    0x18(%rax),%rbp
  mov    $0x81,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x80,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x80(%rbx)
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: x-kahoot-session-token:

assistant: ```c
char *get_header_token(char *response) {
  char *t_header = strstr(response, "x-kahoot-session-token:");
  if (t_header == NULL) {
    return NULL;
  } else {
    t_header = t_header + 24;
    char *token = malloc(129);
    memcpy(token, t_header, 128);
    token[128] = '\0';
    return token;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_header_token>:
  endbr64
  push   %r12
  lea    D0(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    $0x81,%edi
  lea    0x18(%rax),%rbp
  call   <malloc@plt>
  mov    $0x80,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x80(%r12)
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: x-kahoot-session-token:

assistant: ```c
char *get_header_token(char *response) {
  char *t_header = strstr(response, "x-kahoot-session-token:");
  if (t_header == NULL) {
    return NULL;
  } else {
    t_header = t_header + 24;
    char *token = malloc(129);
    memcpy(token, t_header, 128);
    token[128] = '\0';
    return token;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_header_token>:
  endbr64
  push   %r12
  lea    D2(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    $0x81,%edi
  lea    0x18(%rax),%rbp
  call   <malloc@plt>
  mov    $0x80,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x80(%r12)
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: x-kahoot-session-token:

assistant: ```c
char *get_header_token(char *response) {
  char *t_header = strstr(response, "x-kahoot-session-token:");
  if (t_header == NULL) {
    return NULL;
  } else {
    t_header = t_header + 24;
    char *token = malloc(129);
    memcpy(token, t_header, 128);
    token[128] = '\0';
    return token;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<advanceToNextChunk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L8
L10:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L10
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *advanceToNextChunk(unsigned char *ptr) {
  while (!isdigit(*ptr)) {
    ptr += sizeof(char);
  }
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<advanceToNextChunk>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L5
L1:
  add    $0x1,%rbx
L5:
  movzbl (%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L1
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
unsigned char *advanceToNextChunk(unsigned char *ptr) {
  while (!isdigit(*ptr)) {
    ptr += sizeof(char);
  }
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<advanceToNextChunk>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%r12
L15:
  movzbl (%r12),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L13
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
unsigned char *advanceToNextChunk(unsigned char *ptr) {
  while (!isdigit(*ptr)) {
    ptr += sizeof(char);
  }
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<advanceToNextChunk>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%r12
L19:
  movzbl (%r12),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L11
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
unsigned char *advanceToNextChunk(unsigned char *ptr) {
  while (!isdigit(*ptr)) {
    ptr += sizeof(char);
  }
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kd_nearest_range3f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  movss  %xmm1,-0x30(%rbp)
  movss  %xmm2,-0x34(%rbp)
  movss  %xmm3,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x2c(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x30(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x34(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x38(%rbp),%ecx
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  movd   %ecx,%xmm0
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <kd_nearest_range@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
struct kdres *kd_nearest_range3f(struct kdtree *tree, float x, float y, float z, float range) {
  float buf[3];
  buf[0] = x;
  buf[1] = y;
  buf[2] = z;
  return kd_nearest_range(tree, buf, range);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kd_nearest_range3f>:
  endbr64
  sub    $0x28,%rsp
  movaps %xmm0,%xmm4
  movaps %xmm3,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movss  %xmm4,0xc(%rsp)
  movss  %xmm1,0x10(%rsp)
  movss  %xmm2,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  call   <kd_nearest_range@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct kdres *kd_nearest_range3f(struct kdtree *tree, float x, float y, float z, float range) {
  float buf[3];
  buf[0] = x;
  buf[1] = y;
  buf[2] = z;
  return kd_nearest_range(tree, buf, range);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kd_nearest_range3f>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movss  %xmm0,0xc(%rsp)
  movaps %xmm3,%xmm0
  movss  %xmm1,0x10(%rsp)
  movss  %xmm2,0x14(%rsp)
  call   <kd_nearest_range@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct kdres *kd_nearest_range3f(struct kdtree *tree, float x, float y, float z, float range) {
  float buf[3];
  buf[0] = x;
  buf[1] = y;
  buf[2] = z;
  return kd_nearest_range(tree, buf, range);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kd_nearest_range3f>:
  endbr64
  sub    $0x28,%rsp
  unpcklps %xmm1,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  movlps %xmm0,0x8(%rsp)
  movaps %xmm3,%xmm0
  movss  %xmm2,0x10(%rsp)
  call   <kd_nearest_range@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct kdres *kd_nearest_range3f(struct kdtree *tree, float x, float y, float z, float range) {
  float buf[3];
  buf[0] = x;
  buf[1] = y;
  buf[2] = z;
  return kd_nearest_range(tree, buf, range);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delay10ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L10:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  cmpl   $0x464f,-0x8(%rbp)
  jbe    L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay10ms(void) {
  unsigned int a, b = 0;
  for (a = 0; a < 18000; a++)
    b++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delay10ms>:
  endbr64
  mov    $0x4650,%eax
L0:
  sub    $0x1,%eax
  jne    L0
  ret
```

assistant: ```c
void delay10ms(void) {
  unsigned int a, b = 0;
  for (a = 0; a < 18000; a++)
    b++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delay10ms>:
  endbr64
  ret
```

assistant: ```c
void delay10ms(void) {
  unsigned int a, b = 0;
  for (a = 0; a < 18000; a++)
    b++;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<delay10ms>:
  endbr64
  ret
```

assistant: ```c
void delay10ms(void) {
  unsigned int a, b = 0;
  for (a = 0; a < 18000; a++)
    b++;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<string_relation>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L28
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L12:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L83
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L12
L83:
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L12
L5:
  lea    D37(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  lea    0x100(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  test   %r14d,%r14d
  jle    L105
  mov    %r14d,%r14d
  mov    $0x0,%ebx
L29:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L29
L105:
  test   %r13d,%r13d
  jle    L70
  mov    %r13d,%r12d
  mov    $0x0,%ebx
L111:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x100(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L111
L70:
  lea    0x100(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %r13d,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L12
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D20
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D15
data_type: string
name: unpack_data
arguments: data_tag: D37
data_type: string

tool: D20: =

tool: D10: ==

tool: D15: !=

tool: D37: matches

assistant: ```c
int string_relation(char *operator, char * s1, char *s2) {
  int t, l1, l2, i;
  char s3[255], s4[255];
  if (strcmp(operator, "=") == 0) {
    t = (strcmp(s1, s2) == 0);
  } else if (strcmp(operator, "==") == 0) {
    t = (strcmp(s1, s2) == 0);
  } else if (strcmp(operator, "!=") == 0) {
    t = (strcmp(s1, s2) != 0);
  } else if (strcmp(operator, "matches") == 0) {
    l1 = strlen(s1);
    l2 = strlen(s2);
    strcpy(s3, s1);
    strcpy(s4, s2);
    for (i = 0; i < l1; i++)
      s3[i] = toupper(s1[i]);
    for (i = 0; i < l2; i++)
      s4[i] = toupper(s2[i]);
    t = (strncmp(s3, s4, l2) == 0);
  } else
    t = 0;
  return (t);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<string_relation>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D10(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
L22:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L58:
  mov    0x218(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L105
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  lea    D35(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L51
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L51:
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L58
  mov    %r12,%rdi
  lea    0x10(%rsp),%r14
  lea    0x110(%rsp),%r15
  call   <strlen@plt>
  mov    %r13,%rdi
  movslq %eax,%rbp
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %eax,0xc(%rsp)
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  test   %ebp,%ebp
  jle    L68
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L62:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L62
L68:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L29
  movslq %eax,%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L88:
  movsbl 0x0(%r13,%rbp,1),%edi
  call   <toupper@plt>
  mov    %al,(%r15,%rbp,1)
  add    $0x1,%rbp
  cmp    %rbp,%r12
  jne    L88
L29:
  mov    0xc(%rsp),%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L58
L105:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
type_guessed: string
name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D35
type_guessed: string
name: unpack_data
arguments: tag: D32
type_guessed: string

tool: D10: =

tool: D30: ==

tool: D35: !=

tool: D32: matches

assistant: ```c
int string_relation(char *operator, char * s1, char *s2) {
  int t, l1, l2, i;
  char s3[255], s4[255];
  if (strcmp(operator, "=") == 0) {
    t = (strcmp(s1, s2) == 0);
  } else if (strcmp(operator, "==") == 0) {
    t = (strcmp(s1, s2) == 0);
  } else if (strcmp(operator, "!=") == 0) {
    t = (strcmp(s1, s2) != 0);
  } else if (strcmp(operator, "matches") == 0) {
    l1 = strlen(s1);
    l2 = strlen(s2);
    strcpy(s3, s1);
    strcpy(s4, s2);
    for (i = 0; i < l1; i++)
      s3[i] = toupper(s1[i]);
    for (i = 0; i < l2; i++)
      s4[i] = toupper(s2[i]);
    t = (strncmp(s3, s4, l2) == 0);
  } else
    t = 0;
  return (t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_relation>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D23(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  call   <strcmp@plt>
  test   %rax,%rax
  je     L33
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L39
L33:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L66:
  mov    0x218(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L61
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L61:
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L66
  mov    %r12,%rdi
  lea    0x10(%rsp),%r14
  lea    0x110(%rsp),%r15
  call   <strlen@plt>
  mov    %r13,%rdi
  movslq %eax,%rbp
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %eax,0xc(%rsp)
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  test   %ebp,%ebp
  jle    L84
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L16:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L16
L84:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L19
  movslq %eax,%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L94:
  movsbl 0x0(%r13,%rbp,1),%edi
  call   <toupper@plt>
  mov    %al,(%r15,%rbp,1)
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L94
L19:
  mov    0xc(%rsp),%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L66
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D23
type_guessed: string
name: disassemble_data
arguments: tag: D39
type_guessed: string
name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D30
type_guessed: string

tool: D23: =

tool: D39: ==

tool: D3: !=

tool: D30: matches

assistant: ```c
int string_relation(char *operator, char * s1, char *s2) {
  int t, l1, l2, i;
  char s3[255], s4[255];
  if (strcmp(operator, "=") == 0) {
    t = (strcmp(s1, s2) == 0);
  } else if (strcmp(operator, "==") == 0) {
    t = (strcmp(s1, s2) == 0);
  } else if (strcmp(operator, "!=") == 0) {
    t = (strcmp(s1, s2) != 0);
  } else if (strcmp(operator, "matches") == 0) {
    l1 = strlen(s1);
    l2 = strlen(s2);
    strcpy(s3, s1);
    strcpy(s4, s2);
    for (i = 0; i < l1; i++)
      s3[i] = toupper(s1[i]);
    for (i = 0; i < l2; i++)
      s4[i] = toupper(s2[i]);
    t = (strncmp(s3, s4, l2) == 0);
  } else
    t = 0;
  return (t);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xcb_icccm_get_wm_transient_for_reply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <xcb_get_property_reply@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xcb_icccm_get_wm_transient_for_from_reply@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint8_t xcb_icccm_get_wm_transient_for_reply(xcb_connection_t *c, xcb_get_property_cookie_t cookie, xcb_window_t *prop, xcb_generic_error_t **e) {
  xcb_get_property_reply_t *reply = xcb_get_property_reply(c, cookie, e);
  uint8_t ret = xcb_icccm_get_wm_transient_for_from_reply(prop, reply);
  free(reply);
  return ret;
}
```