ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<djb2_hash_str>:
  endbr64
  test   %rsi,%rsi
  je     L4
  add    %rdi,%rsi
  mov    $0x1505,%eax
  nopl   0x0(%rax)
L5:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rdi,%rsi
  jne    L5
  ret
  nop
L4:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned int djb2_hash_str(const char *str, size_t str_len) {
  unsigned int hash;
  size_t i;
  hash = 5381;
  for (i = 0; i < str_len; ++i) {
    hash = ((hash << 5) + hash) + ((unsigned int)str[i]);
  }
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<USBDevEndpointDataAck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L26
  cmpl   $0x0,-0xc(%rbp)
  je     L13
  mov    $0x48,%edx
  jmp    L39
L13:
  mov    $0x40,%edx
L39:
  mov    -0x4(%rbp),%eax
  add    $0x102,%eax
  cltq
  mov    %edx,(%rax)
  jmp    L25
L26:
  mov    -0x4(%rbp),%eax
  lea    0x116(%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    $0x10,%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  lea    0x116(%rdx),%ecx
  mov    -0x8(%rbp),%edx
  sub    $0x10,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  and    $0xfffffffe,%eax
  mov    %eax,(%rdx)
L25:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBDevEndpointDataAck(uint32_t ui32Base, uint32_t ui32Endpoint, bool bIsLastPacket) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000102))) = 0x00000040 | (bIsLastPacket ? 0x00000008 : 0);
  } else {
    (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) &= ~(0x00000001);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<USBDevEndpointDataAck>:
  endbr64
  test   %esi,%esi
  jne    L0
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0x48,%eax
  add    $0x102,%edi
  movslq %edi,%rdi
  mov    %eax,(%rdi)
  ret
L0:
  lea    0x106(%rdi,%rsi,1),%eax
  cltq
  mov    (%rax),%edx
  and    $0xfffffffe,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void USBDevEndpointDataAck(uint32_t ui32Base, uint32_t ui32Endpoint, bool bIsLastPacket) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000102))) = 0x00000040 | (bIsLastPacket ? 0x00000008 : 0);
  } else {
    (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) &= ~(0x00000001);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<USBDevEndpointDataAck>:
  endbr64
  test   %esi,%esi
  jne    L2
  cmp    $0x1,%edx
  sbb    %eax,%eax
  add    $0x102,%edi
  and    $0xfffffff8,%eax
  movslq %edi,%rdi
  add    $0x48,%eax
  mov    %eax,(%rdi)
  ret
  nop
L2:
  lea    0x106(%rdi,%rsi,1),%eax
  cltq
  mov    (%rax),%edx
  and    $0xfffffffe,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void USBDevEndpointDataAck(uint32_t ui32Base, uint32_t ui32Endpoint, bool bIsLastPacket) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000102))) = 0x00000040 | (bIsLastPacket ? 0x00000008 : 0);
  } else {
    (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) &= ~(0x00000001);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<USBDevEndpointDataAck>:
  endbr64
  test   %esi,%esi
  jne    L3
  cmp    $0x1,%edx
  sbb    %eax,%eax
  add    $0x102,%edi
  and    $0xfffffff8,%eax
  movslq %edi,%rdi
  add    $0x48,%eax
  mov    %eax,(%rdi)
  ret
  nop
L3:
  lea    0x106(%rdi,%rsi,1),%eax
  cltq
  mov    (%rax),%edx
  and    $0xfffffffe,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void USBDevEndpointDataAck(uint32_t ui32Base, uint32_t ui32Endpoint, bool bIsLastPacket) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000102))) = 0x00000040 | (bIsLastPacket ? 0x00000008 : 0);
  } else {
    (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) &= ~(0x00000001);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<add_uevent_var>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int add_uevent_var(char **envp, int num_envp, int *cur_index, char *buffer, int buffer_size, int *cur_len, char const *format, void *x) {
  int a;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<add_uevent_var>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int add_uevent_var(char **envp, int num_envp, int *cur_index, char *buffer, int buffer_size, int *cur_len, char const *format, void *x) {
  int a;
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<add_uevent_var>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int add_uevent_var(char **envp, int num_envp, int *cur_index, char *buffer, int buffer_size, int *cur_len, char const *format, void *x) {
  int a;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_uevent_var>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int add_uevent_var(char **envp, int num_envp, int *cur_index, char *buffer, int buffer_size, int *cur_len, char const *format, void *x) {
  int a;
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_five>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L17:
  movl   $0x0,-0x8(%rbp)
  jmp    L58
L34:
  movl   $0x0,-0x4(%rbp)
  jmp    L40
L10:
  addl   $0x1,-0x4(%rbp)
L40:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  addl   $0x1,-0x8(%rbp)
L58:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L34
  addl   $0x1,-0xc(%rbp)
L36:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_five(int x, int y, int z) {
#pragma omp simd collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      for (int i = 0; i < z; i++)
        ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_five>:
  endbr64
  mov    %edi,%r8d
  mov    $0x0,%edi
  test   %r8d,%r8d
  jg     L24
  ret
L52:
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L52
L1:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  je     L78
L3:
  mov    $0x0,%eax
  test   %edx,%edx
  jg     L52
  jmp    L1
L78:
  add    $0x1,%edi
  cmp    %edi,%r8d
  je     L59
L24:
  mov    $0x0,%ecx
  test   %esi,%esi
  jg     L3
  jmp    L78
L59:
  ret
```

assistant: ```c
void test_five(int x, int y, int z) {
#pragma omp simd collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      for (int i = 0; i < z; i++)
        ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_five>:
  endbr64
  ret
```

assistant: ```c
void test_five(int x, int y, int z) {
#pragma omp simd collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      for (int i = 0; i < z; i++)
        ;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_five>:
  endbr64
  ret
```

assistant: ```c
void test_five(int x, int y, int z) {
#pragma omp simd collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      for (int i = 0; i < z; i++)
        ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gmx_traj@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_traj(argc, argv);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_traj@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_traj(argc, argv);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_traj@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_traj(argc, argv);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_traj@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_traj(argc, argv);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L38:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <enable@plt>
  test   %rax,%rax
  jle    L39
  mov    -0x4(%rbp),%eax
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x3,%edx
  mov    $0x1000000,%esi
  mov    %eax,%edi
  call   <search@plt>
  test   %rax,%rax
  jle    L39
  addl   $0x1,-0x8(%rbp)
L39:
  addl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x1ffffff,-0x4(%rbp)
  jle    L38
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: %d

assistant: ```c
int main(void) {
  int count = 0;
  int i = 0;
  for (i = 0; i < (1 << 5 * 5); i++) {
    if (enable(i) > 0) {
      if (search(i, 1 << (5 * 5 - 1), 3, 1, 1, 1) > 0)
        count++;
    }
  }
  printf("%d", count);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L9
L36:
  add    $0x1,%ebx
  cmp    $0x2000000,%ebx
  je     L22
L9:
  mov    %ebx,%edi
  call   <enable@plt>
  test   %rax,%rax
  jle    L36
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x3,%edx
  mov    $0x1000000,%esi
  mov    %ebx,%edi
  call   <search@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  add    %eax,%ebp
  jmp    L36
L22:
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: %d

assistant: ```c
int main(void) {
  int count = 0;
  int i = 0;
  for (i = 0; i < (1 << 5 * 5); i++) {
    if (enable(i) > 0) {
      if (search(i, 1 << (5 * 5 - 1), 3, 1, 1, 1) > 0)
        count++;
    }
  }
  printf("%d", count);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L7:
  mov    %ebx,%edi
  call   <enable@plt>
  test   %rax,%rax
  jle    L16
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    %ebx,%edi
  mov    $0x3,%edx
  mov    $0x1000000,%esi
  call   <search@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  add    %eax,%ebp
L16:
  add    $0x1,%ebx
  cmp    $0x2000000,%ebx
  jne    L7
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: %d

assistant: ```c
int main(void) {
  int count = 0;
  int i = 0;
  for (i = 0; i < (1 << 5 * 5); i++) {
    if (enable(i) > 0) {
      if (search(i, 1 << (5 * 5 - 1), 3, 1, 1, 1) > 0)
        count++;
    }
  }
  printf("%d", count);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L9:
  mov    %ebx,%edi
  call   <enable@plt>
  test   %rax,%rax
  jle    L8
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    %ebx,%edi
  mov    $0x3,%edx
  mov    $0x1000000,%esi
  call   <search@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  add    %eax,%ebp
L8:
  add    $0x1,%ebx
  cmp    $0x2000000,%ebx
  jne    L9
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int main(void) {
  int count = 0;
  int i = 0;
  for (i = 0; i < (1 << 5 * 5); i++) {
    if (enable(i) > 0) {
      if (search(i, 1 << (5 * 5 - 1), 3, 1, 1, 1) > 0)
        count++;
    }
  }
  printf("%d", count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Title>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1: 
MTE Search Tool v1.1
Copyright (C) 2013 CUE



assistant: ```c
void Title(void) {
  printf("\n"
         "MTE Search Tool v1.1\n"
         "Copyright (C) 2013 CUE\n"
         "\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Title>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: 
MTE Search Tool v1.1
Copyright (C) 2013 CUE



assistant: ```c
void Title(void) {
  printf("\n"
         "MTE Search Tool v1.1\n"
         "Copyright (C) 2013 CUE\n"
         "\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Title>:
  endbr64
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: 
MTE Search Tool v1.1
Copyright (C) 2013 CUE



assistant: ```c
void Title(void) {
  printf("\n"
         "MTE Search Tool v1.1\n"
         "Copyright (C) 2013 CUE\n"
         "\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Title>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string

tool: D0: 
MTE Search Tool v1.1
Copyright (C) 2013 CUE



assistant: ```c
void Title(void) {
  printf("\n"
         "MTE Search Tool v1.1\n"
         "Copyright (C) 2013 CUE\n"
         "\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: *
**
***


assistant: ```c
int main() {
  printf("*\n**\n***\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: *
**
***


assistant: ```c
int main() {
  printf("*\n**\n***\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: *
**
***


assistant: ```c
int main() {
  printf("*\n**\n***\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string

tool: D7: *
**
***


assistant: ```c
int main() {
  printf("*\n**\n***\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<insn_type01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf8000000,%eax
  cmp    $0x68000000,%eax
  je     L3
  cmp    $0x68000000,%eax
  ja     L41
  cmp    $0x40000000,%eax
  je     L65
  cmp    $0x50000000,%eax
  je     L79
  jmp    L41
L65:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <insn_arithmetic_op@plt>
  jmp    L26
L79:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <insn_logic_op@plt>
  jmp    L26
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <insn_iterative_op@plt>
  jmp    L26
L41:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <sim_warning@plt>
  nop
L26:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: Unimplemented type01

assistant: ```c
void insn_type01(uint32_t insn) {
  switch (insn & 0xf8000000) {
  case 0x40000000:
    insn_arithmetic_op(insn);
    break;
  case 0x50000000:
    insn_logic_op(insn);
    break;
  case 0x68000000:
    insn_iterative_op(insn);
    break;
  default:
    sim_warning("Unimplemented type01");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<insn_type01>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  and    $0xf8000000,%eax
  cmp    $0x50000000,%eax
  je     L45
  cmp    $0x68000000,%eax
  je     L21
  cmp    $0x40000000,%eax
  je     L43
  lea    D8(%rip),%rdi
  call   <sim_warning@plt>
  jmp    L29
L43:
  call   <insn_arithmetic_op@plt>
L29:
  add    $0x8,%rsp
  ret
L45:
  call   <insn_logic_op@plt>
  jmp    L29
L21:
  call   <insn_iterative_op@plt>
  jmp    L29
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string

tool: D8: Unimplemented type01

assistant: ```c
void insn_type01(uint32_t insn) {
  switch (insn & 0xf8000000) {
  case 0x40000000:
    insn_arithmetic_op(insn);
    break;
  case 0x50000000:
    insn_logic_op(insn);
    break;
  case 0x68000000:
    insn_iterative_op(insn);
    break;
  default:
    sim_warning("Unimplemented type01");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<insn_type01>:
  endbr64
  mov    %edi,%eax
  and    $0xf8000000,%eax
  cmp    $0x50000000,%eax
  je     L29
  cmp    $0x68000000,%eax
  je     L25
  cmp    $0x40000000,%eax
  je     L11
  lea    D5(%rip),%rdi
  jmp    1090 <sim_warning@plt>
  nopl   0x0(%rax)
L29:
  jmp    1080 <insn_logic_op@plt>
  nopl   (%rax)
L11:
  jmp    10a0 <insn_arithmetic_op@plt>
  nopl   (%rax)
L25:
  jmp    10b0 <insn_iterative_op@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: Unimplemented type01

assistant: ```c
void insn_type01(uint32_t insn) {
  switch (insn & 0xf8000000) {
  case 0x40000000:
    insn_arithmetic_op(insn);
    break;
  case 0x50000000:
    insn_logic_op(insn);
    break;
  case 0x68000000:
    insn_iterative_op(insn);
    break;
  default:
    sim_warning("Unimplemented type01");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<insn_type01>:
  endbr64
  mov    %edi,%eax
  and    $0xf8000000,%eax
  cmp    $0x50000000,%eax
  je     L2
  cmp    $0x68000000,%eax
  je     L29
  cmp    $0x40000000,%eax
  je     L3
  lea    D6(%rip),%rdi
  jmp    1090 <sim_warning@plt>
  nopl   0x0(%rax)
L2:
  jmp    1080 <insn_logic_op@plt>
  nopl   (%rax)
L3:
  jmp    10a0 <insn_arithmetic_op@plt>
  nopl   (%rax)
L29:
  jmp    10b0 <insn_iterative_op@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Unimplemented type01

assistant: ```c
void insn_type01(uint32_t insn) {
  switch (insn & 0xf8000000) {
  case 0x40000000:
    insn_arithmetic_op(insn);
    break;
  case 0x50000000:
    insn_logic_op(insn);
    break;
  case 0x68000000:
    insn_iterative_op(insn);
    break;
  default:
    sim_warning("Unimplemented type01");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L1
  addl   $0x1,-0x10(%rbp)
  jmp    L20
L1:
  nop
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type: string

tool: D18: %d

assistant: ```c
int main() {
  int N, c, p;
  scanf("%d", &N);
  for (p = N;; p++) {
    c = check_prime(p);
    if (c == 0)
      break;
  }
  printf("%d", p);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  jmp    L29
L14:
  add    $0x1,%ebx
L29:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L14
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int main() {
  int N, c, p;
  scanf("%d", &N);
  for (p = N;; p++) {
    c = check_prime(p);
    if (c == 0)
      break;
  }
  printf("%d", p);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  jmp    L22
  nopl   (%rax)
L14:
  add    $0x1,%ebp
L22:
  mov    %ebp,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L14
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d

assistant: ```c
int main() {
  int N, c, p;
  scanf("%d", &N);
  for (p = N;; p++) {
    c = check_prime(p);
    if (c == 0)
      break;
  }
  printf("%d", p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  jmp    L26
  nopl   (%rax)
L2:
  add    $0x1,%ebp
L26:
  mov    %ebp,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L2
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  int N, c, p;
  scanf("%d", &N);
  for (p = N;; p++) {
    c = check_prime(p);
    if (c == 0)
      break;
  }
  printf("%d", p);
  return 0;
}
```