user: 这段汇编代码用C语言表示是什么样的：

```asm
<dwt_decode_53>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%edi
  test   %ecx,%ecx
  jne    L161
  test   %esi,%esi
  jg     L62
  cmp    $0x1,%edx
  jg     L62
  ret
  nop
L161:
  test   %edx,%edx
  jne    L187
  cmp    $0x1,%esi
  jne    L187
  mov    (%rax),%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  mov    %edx,(%rax)
  ret
  nopw   0x0(%rax,%rax,1)
L187:
  test   %edi,%edi
  jle    L340
  lea    -0x2(%rsi,%rsi,1),%edx
  lea    0x4(%rax),%rcx
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%r11
  xor    %edx,%edx
  jmp    L201
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x1,%edx
  mov    (%r11),%r10d
  cmp    %esi,%edx
  jl     L326
L302:
  mov    (%r11),%r9d
L210:
  lea    0x2(%r10,%r9,1),%r9d
  add    $0x8,%rcx
  sar    $0x2,%r9d
  sub    %r9d,%r8d
  mov    %r8d,-0x8(%rcx)
  cmp    %edi,%edx
  je     L340
L201:
  mov    (%rcx),%r8d
  cmp    %edx,%esi
  jle    L73
  add    $0x1,%edx
  mov    -0x4(%rcx),%r10d
  cmp    %esi,%edx
  jge    L302
L326:
  lea    (%rdx,%rdx,1),%r9d
  movslq %r9d,%r9
  mov    (%rax,%r9,4),%r9d
  jmp    L210
  nopl   0x0(%rax,%rax,1)
L62:
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L209
  lea    -0x1(%rsi,%rsi,1),%edx
  movslq %edi,%rbx
  mov    $0x1,%r10d
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%rbp
  xor    %edx,%edx
  jmp    L87
  xchg   %ax,%ax
L136:
  cmp    %edx,%esi
  jge    L17
  mov    0x0(%rbp),%r9d
  mov    %r9d,%r11d
L369:
  lea    0x2(%r9,%r11,1),%r9d
  add    $0x2,%r10d
  sar    $0x2,%r9d
  sub    %r9d,%r8d
  mov    %r8d,(%rax,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  je     L209
L87:
  mov    (%rax,%rdx,8),%r8d
  mov    %edx,%r9d
  test   %rdx,%rdx
  jne    L136
  mov    0x4(%rax),%r11d
  cmp    %r9d,%esi
  jle    L352
L252:
  mov    %r10d,%r9d
  mov    (%rax,%r9,4),%r9d
  jmp    L369
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    -0x4(%rax,%rdx,8),%r11d
  cmp    %r9d,%esi
  jg     L252
L352:
  mov    0x0(%rbp),%r9d
  jmp    L369
L209:
  test   %esi,%esi
  jle    L162
  lea    -0x2(%rdi,%rdi,1),%edx
  lea    0x4(%rax),%r8
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%r11
  jmp    L24
  nopl   (%rax)
L26:
  add    $0x1,%ecx
  mov    (%r11),%edx
  cmp    %edi,%ecx
  jl     L109
L228:
  mov    (%r11),%r10d
L95:
  add    %r10d,%edx
  add    $0x8,%r8
  sar    %edx
  add    %r9d,%edx
  mov    %edx,-0x8(%r8)
  cmp    %esi,%ecx
  je     L162
L24:
  mov    (%r8),%r9d
  cmp    %ecx,%edi
  jle    L26
  add    $0x1,%ecx
  mov    -0x4(%r8),%edx
  cmp    %edi,%ecx
  jge    L228
L109:
  lea    (%rcx,%rcx,1),%r10d
  movslq %r10d,%r10
  mov    (%rax,%r10,4),%r10d
  jmp    L95
  nopl   0x0(%rax,%rax,1)
L162:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L340:
  test   %esi,%esi
  jle    L52
  lea    -0x1(%rdi,%rdi,1),%edx
  movslq %esi,%rsi
  mov    $0x1,%r8d
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%r11
  xor    %edx,%edx
  jmp    L119
  nopl   0x0(%rax)
L45:
  mov    (%r11),%r9d
  test   %edx,%edx
  je     L365
  cmp    %edx,%edi
  jge    L367
  mov    %r9d,%ecx
L183:
  add    %r9d,%ecx
  add    $0x2,%r8d
  sar    %ecx
  add    %r10d,%ecx
  mov    %ecx,(%rax,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  je     L182
L119:
  mov    (%rax,%rdx,8),%r10d
  cmp    %edx,%edi
  jle    L45
  mov    %r8d,%ecx
  mov    (%rax,%rcx,4),%r9d
  test   %edx,%edx
  je     L365
L367:
  mov    -0x4(%rax,%rdx,8),%ecx
  jmp    L183
  nopw   0x0(%rax,%rax,1)
L365:
  mov    0x4(%rax),%ecx
  jmp    L183
  nopl   (%rax)
L182:
  ret
  nopl   0x0(%rax)
L52:
  ret
```

assistant: ```c
void dwt_decode_53(int *a, int dn, int sn, int cas) {
  int i;
  if (!cas) {
    if ((dn > 0) || (sn > 1)) {
      for (i = 0; i < sn; i++) {
        a[(i)*2] -= (((i - 1) < 0 ? a[(1 + (0) * 2)] : ((i - 1) >= dn ? a[(1 + (dn - 1) * 2)] : a[(1 + (i - 1) * 2)])) + ((i) < 0 ? a[(1 + (0) * 2)] : ((i) >= dn ? a[(1 + (dn - 1) * 2)] : a[(1 + (i)*2)])) + 2) >> 2;
      }
      for (i = 0; i < dn; i++) {
        a[(1 + (i)*2)] += (((i) < 0 ? a[(0) * 2] : ((i) >= sn ? a[(sn - 1) * 2] : a[(i)*2])) + ((i + 1) < 0 ? a[(0) * 2] : ((i + 1) >= sn ? a[(sn - 1) * 2] : a[(i + 1) * 2]))) >> 1;
      }
    }
  } else {
    if (!sn && dn == 1) {
      a[(0) * 2] /= 2;
    } else {
      for (i = 0; i < sn; i++) {
        a[(1 + (i)*2)] -= (((i) < 0 ? a[(0) * 2] : ((i) >= dn ? a[(dn - 1) * 2] : a[(i)*2])) + ((i + 1) < 0 ? a[(0) * 2] : ((i + 1) >= dn ? a[(dn - 1) * 2] : a[(i + 1) * 2])) + 2) >> 2;
      }
      for (i = 0; i < dn; i++) {
        a[(i)*2] += (((i) < 0 ? a[(1 + (0) * 2)] : ((i) >= sn ? a[(1 + (sn - 1) * 2)] : a[(1 + (i)*2)])) + ((i - 1) < 0 ? a[(1 + (0) * 2)] : ((i - 1) >= sn ? a[(1 + (sn - 1) * 2)] : a[(1 + (i - 1) * 2)]))) >> 1;
      }
    }
  }
}
```