user: 请从给定的汇编指令推导出C源代码:

```asm
<find_k_closest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    -0x3c(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x40(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <get_index@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  test   %eax,%eax
  cmovle %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L41
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  jmp    L36
L41:
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
L36:
  mov    %eax,-0x20(%rbp)
  jmp    L135
L31:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,%edi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rax,%rbx
  jge    L42
  subl   $0x1,-0x24(%rbp)
  jmp    L135
L42:
  addl   $0x1,-0x20(%rbp)
L135:
  cmpl   $0x0,-0x24(%rbp)
  jle    L56
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L31
L56:
  mov    -0x20(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L23
L132:
  subl   $0x1,-0x24(%rbp)
  addl   $0x1,-0x1c(%rbp)
L23:
  cmpl   $0x0,-0x24(%rbp)
  jle    L98
  mov    -0x1c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L132
  jmp    L98
L103:
  addl   $0x1,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
L98:
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jge    L123
  mov    -0x1c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L103
L123:
  cmpl   $0x0,-0x24(%rbp)
  js     L169
  mov    -0x3c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L5
L169:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L39
L134:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L134
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string
name: unpack_data
arguments: data_label: D19
datatype: string

tool: D3: error

tool: D19: %d 

assistant: ```c
void find_k_closest(int a[], int len, int x, int k) {
  int index = get_index(a, 0, len - 1, x);
  int left = (index > 0) ? (index - 1) : 0;
  int right = (index < len - 1) ? index + 1 : len - 1;
  while (left > 0 && right < len - 1) {
    if (abs(a[left] - a[index]) < abs(a[right] - a[index])) {
      left--;
    } else {
      right++;
    }
  }
  int count = right - left;
  while (left > 0 && count < k) {
    left--;
    count++;
  }
  while (right < len - 1 && count < k) {
    right++;
    count++;
  }
  if (left < 0 || right > len - 1) {
    printf("error");
  }
  for (int i = left; i <= right; i++) {
    printf("%d ", a[i]);
  }
}
```