ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<testArgs>:
  endbr64
  push   %rbp
  mov    $0x3,%ecx
  lea    D16(%rip),%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  mov    D14(%rip),%rax
  lea    0x8(%rsp),%rdi
  movl   $0x2,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rax,0x18(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x0,0x30(%rsp)
  call   <vectorAdd@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x28(%rsp),%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x2c(%rsp),%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x30(%rsp),%xmm0
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x40,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D14
data_type: byte[8]
name: read_data
arguments: label: D12
data_type: string

tool: D16:  %g

tool: {"D14": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D12: testArgs:

assistant: ```c
void testArgs() {
  int a[3], b[3];
  float c[3];
  int i;
  int len = 3;
  for (i = 0; i < len; i++) {
    a[i] = i;
    b[i] = i;
    c[i] = 0;
  }
  vectorAdd(a, b, c, len);
  printf("testArgs:");
  for (i = 0; i < len; i++) {
    printf(" %g", c[i]);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getCardSuit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L5:
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L15:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L67
  movl   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L69
L67:
  cmpl   $0x0,-0x8(%rbp)
  jne    L20
  addl   $0x1,-0xc(%rbp)
L39:
  cmpl   $0xc,-0xc(%rbp)
  jle    L15
  jmp    L69
L20:
  nop
L69:
  addl   $0x1,-0x10(%rbp)
L3:
  cmpl   $0x3,-0x10(%rbp)
  jle    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getCardSuit(const int wDeck[][13], int cardPosition) {
  int row, column, foundCard = 0;
  int suit = 0;
  for (row = 0; row <= 3; row++) {
    for (column = 0; column <= 12; column++) {
      if (wDeck[row][column] == cardPosition) {
        foundCard = 1;
        suit = row;
        break;
      }
      if (foundCard)
        break;
    }
  }
  return suit;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getCardSuit>:
  endbr64
  add    $0x34,%rdi
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x0,%ecx
  mov    $0x1,%r9d
  jmp    L43
L31:
  mov    %ecx,%r8d
  mov    %r9d,%edx
L33:
  add    $0x1,%ecx
  add    $0x34,%rdi
  cmp    $0x4,%ecx
  je     L9
L43:
  lea    -0x34(%rdi),%rax
L20:
  cmp    %esi,(%rax)
  je     L31
  test   %edx,%edx
  jne    L33
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L20
  jmp    L33
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getCardSuit(const int wDeck[][13], int cardPosition) {
  int row, column, foundCard = 0;
  int suit = 0;
  for (row = 0; row <= 3; row++) {
    for (column = 0; column <= 12; column++) {
      if (wDeck[row][column] == cardPosition) {
        foundCard = 1;
        suit = row;
        break;
      }
      if (foundCard)
        break;
    }
  }
  return suit;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getCardSuit>:
  endbr64
  add    $0x34,%rdi
  xor    %r8d,%r8d
  xor    %edx,%edx
  xor    %ecx,%ecx
L21:
  lea    -0x34(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L52:
  cmp    %esi,(%rax)
  je     L35
  test   %edx,%edx
  jne    L10
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L52
L10:
  add    $0x1,%ecx
  add    $0x34,%rdi
  cmp    $0x4,%ecx
  jne    L21
L29:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L35:
  mov    %ecx,%r8d
  add    $0x1,%ecx
  mov    $0x1,%edx
  add    $0x34,%rdi
  cmp    $0x4,%ecx
  jne    L21
  jmp    L29
```

assistant: ```c
int getCardSuit(const int wDeck[][13], int cardPosition) {
  int row, column, foundCard = 0;
  int suit = 0;
  for (row = 0; row <= 3; row++) {
    for (column = 0; column <= 12; column++) {
      if (wDeck[row][column] == cardPosition) {
        foundCard = 1;
        suit = row;
        break;
      }
      if (foundCard)
        break;
    }
  }
  return suit;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getCardSuit>:
  endbr64
  xor    %r8d,%r8d
  xor    %edx,%edx
  xor    %eax,%eax
L103:
  cmp    (%rdi),%esi
  je     L39
  test   %edx,%edx
  jne    L115
  cmp    0x4(%rdi),%esi
  je     L39
  cmp    0x8(%rdi),%esi
  je     L39
  cmp    0xc(%rdi),%esi
  je     L39
  cmp    0x10(%rdi),%esi
  je     L39
  cmp    0x14(%rdi),%esi
  je     L39
  cmp    0x18(%rdi),%esi
  je     L39
  cmp    0x1c(%rdi),%esi
  je     L39
  cmp    0x20(%rdi),%esi
  je     L39
  cmp    0x24(%rdi),%esi
  je     L39
  cmp    0x28(%rdi),%esi
  je     L39
  cmp    0x2c(%rdi),%esi
  je     L39
  cmp    0x30(%rdi),%esi
  sete   %dl
  cmove  %eax,%r8d
  movzbl %dl,%edx
L115:
  add    $0x1,%eax
  add    $0x34,%rdi
  cmp    $0x4,%eax
  jne    L103
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %eax,%r8d
  mov    $0x1,%edx
  jmp    L115
```

assistant: ```c
int getCardSuit(const int wDeck[][13], int cardPosition) {
  int row, column, foundCard = 0;
  int suit = 0;
  for (row = 0; row <= 3; row++) {
    for (column = 0; column <= 12; column++) {
      if (wDeck[row][column] == cardPosition) {
        foundCard = 1;
        suit = row;
        break;
      }
      if (foundCard)
        break;
    }
  }
  return suit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0xb45,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  imul   $0x274f,%ax,%dx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (!(state[0UL] > local1)) {
        state[0UL] = state[local1] + state[local1];
        state[0UL] = state[local1] + state[local1];
      }
      if (state[0UL] != local1) {
        state[local1] = state[0UL] * state[0UL];
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy13;
      } else {
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
        copy15 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy15;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] * 679664205UL) * (unsigned short)56843;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0xb45,%ax
  imul   $0x274f,%ax,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (!(state[0UL] > local1)) {
        state[0UL] = state[local1] + state[local1];
        state[0UL] = state[local1] + state[local1];
      }
      if (state[0UL] != local1) {
        state[local1] = state[0UL] * state[0UL];
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy13;
      } else {
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
        copy15 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy15;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] * 679664205UL) * (unsigned short)56843;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0xb45,%ax
  imul   $0x274f,%ax,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (!(state[0UL] > local1)) {
        state[0UL] = state[local1] + state[local1];
        state[0UL] = state[local1] + state[local1];
      }
      if (state[0UL] != local1) {
        state[local1] = state[0UL] * state[0UL];
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy13;
      } else {
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
        copy15 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy15;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] * 679664205UL) * (unsigned short)56843;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0xb45,%ax
  imul   $0x274f,%ax,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (!(state[0UL] > local1)) {
        state[0UL] = state[local1] + state[local1];
        state[0UL] = state[local1] + state[local1];
      }
      if (state[0UL] != local1) {
        state[local1] = state[0UL] * state[0UL];
        copy13 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy13;
      } else {
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
        copy15 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy15;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] * 679664205UL) * (unsigned short)56843;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<say_hello>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: Hello, World!

assistant: ```c
void *say_hello(void *dummy) {
  (void)dummy;
  puts("Hello, World!");
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<say_hello>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: Hello, World!

assistant: ```c
void *say_hello(void *dummy) {
  (void)dummy;
  puts("Hello, World!");
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<say_hello>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: Hello, World!

assistant: ```c
void *say_hello(void *dummy) {
  (void)dummy;
  puts("Hello, World!");
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<say_hello>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: Hello, World!

assistant: ```c
void *say_hello(void *dummy) {
  (void)dummy;
  puts("Hello, World!");
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L18:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L21
  mov    $0x1,%eax
  jmp    L26
L21:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L18
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int check_square(int number) {
  int i;
  for (i = 0; i <= number; i++) {
    if (number == i * i) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_square>:
  endbr64
  test   %edi,%edi
  js     L2
  je     L38
  mov    $0x1,%eax
L34:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  je     L0
  add    $0x1,%eax
  cmp    %eax,%edi
  jge    L34
  mov    $0x0,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
L38:
  mov    $0x1,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_square(int number) {
  int i;
  for (i = 0; i <= number; i++) {
    if (number == i * i) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_square>:
  endbr64
  test   %edi,%edi
  js     L10
  mov    $0x1,%eax
  je     L25
  nop
L8:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  je     L3
  add    $0x1,%eax
  cmp    %eax,%edi
  jge    L8
L10:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%eax
  ret
L25:
  ret
```

assistant: ```c
int check_square(int number) {
  int i;
  for (i = 0; i <= number; i++) {
    if (number == i * i) {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_square>:
  endbr64
  test   %edi,%edi
  js     L11
  mov    $0x1,%eax
  je     L13
  nop
L23:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  je     L34
  add    $0x1,%eax
  cmp    %eax,%edi
  jge    L23
L11:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%eax
  ret
L13:
  ret
```

assistant: ```c
int check_square(int number) {
  int i;
  for (i = 0; i <= number; i++) {
    if (number == i * i) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vsub(const float src1[3], const float src2[3], float dst[3]) {
  dst[0] = src1[0] - src2[0];
  dst[1] = src1[1] - src2[1];
  dst[2] = src1[2] - src2[2];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vsub>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void vsub(const float src1[3], const float src2[3], float dst[3]) {
  dst[0] = src1[0] - src2[0];
  dst[1] = src1[1] - src2[1];
  dst[2] = src1[2] - src2[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vsub>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void vsub(const float src1[3], const float src2[3], float dst[3]) {
  dst[0] = src1[0] - src2[0];
  dst[1] = src1[1] - src2[1];
  dst[2] = src1[2] - src2[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vsub>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void vsub(const float src1[3], const float src2[3], float dst[3]) {
  dst[0] = src1[0] - src2[0];
  dst[1] = src1[1] - src2[1];
  dst[2] = src1[2] - src2[2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x24(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0x13(%rbp),%rax
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  movb   $0x0,-0x9(%rbp)
  lea    -0x13(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x13(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %F

assistant: ```c
void get_date(char *date) {
  time_t now = time(NULL);
  struct tm *tm = localtime(&now);
  char s[11];
  strftime(s, sizeof(s), "%F", tm);
  s[10] = '\0';
  strncpy(date, s, strlen(s));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_date>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  lea    0xd(%rsp),%rbp
  lea    D0(%rip),%rdx
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <strftime@plt>
  movb   $0x0,0x17(%rsp)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: %F

assistant: ```c
void get_date(char *date) {
  time_t now = time(NULL);
  struct tm *tm = localtime(&now);
  char s[11];
  strftime(s, sizeof(s), "%F", tm);
  s[10] = '\0';
  strncpy(date, s, strlen(s));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_date>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%r12
  call   <time@plt>
  lea    0x8(%rsp),%rdi
  mov    %eax,0x8(%rsp)
  call   <localtime@plt>
  lea    D3(%rip),%rdx
  mov    $0xb,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r12,%rdi
  movb   $0x0,0x17(%rsp)
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: %F

assistant: ```c
void get_date(char *date) {
  time_t now = time(NULL);
  struct tm *tm = localtime(&now);
  char s[11];
  strftime(s, sizeof(s), "%F", tm);
  s[10] = '\0';
  strncpy(date, s, strlen(s));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_date>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%r12
  call   <time@plt>
  lea    0x8(%rsp),%rdi
  mov    %eax,0x8(%rsp)
  call   <localtime@plt>
  lea    D8(%rip),%rdx
  mov    $0xb,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r12,%rdi
  movb   $0x0,0x17(%rsp)
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D8: %F

assistant: ```c
void get_date(char *date) {
  time_t now = time(NULL);
  struct tm *tm = localtime(&now);
  char s[11];
  strftime(s, sizeof(s), "%F", tm);
  s[10] = '\0';
  strncpy(date, s, strlen(s));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_pointer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x4,-0x4(%rbp)
  jle    L13
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D9: %d: *(p+%d)=%2d


assistant: ```c
void print_pointer(int *p, int size) {
  int ii;
  for (ii = 0; ii < 5; ii++)
    printf("%d: *(p+%d)=%2d\n", ii, ii, *(p + ii));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_pointer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D3(%rip),%r12
L4:
  mov    %ebx,%esi
  mov    0x0(%rbp,%rbx,4),%ecx
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: %d: *(p+%d)=%2d


assistant: ```c
void print_pointer(int *p, int size) {
  int ii;
  for (ii = 0; ii < 5; ii++)
    printf("%d: *(p+%d)=%2d\n", ii, ii, *(p + ii));
}
```