ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<listadditem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x2c(%rbp)
  jg     L16
  mov    $0x0,%eax
  jmp    L8
L16:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %edx,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int listadditem(char **list, char *item, int *count, int capacity) {
  if (*count >= capacity) {
    return 0;
  }
  list[*count] = malloc(strlen(item) / sizeof(char));
  strcpy(list[*count], item);
  *count += 1;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<listadditem>:
  endbr64
  mov    $0x0,%eax
  cmp    %ecx,(%rdx)
  jl     L0
  ret
L0:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  movslq (%rbx),%rax
  lea    0x0(%rbp,%rax,8),%r13
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  movslq (%rbx),%rax
  mov    0x0(%rbp,%rax,8),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  addl   $0x1,(%rbx)
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int listadditem(char **list, char *item, int *count, int capacity) {
  if (*count >= capacity) {
    return 0;
  }
  list[*count] = malloc(strlen(item) / sizeof(char));
  strcpy(list[*count], item);
  *count += 1;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<listadditem>:
  endbr64
  cmp    %ecx,(%rdx)
  jl     L1
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  movslq (%rbx),%rax
  lea    (%r12,%rax,8),%r13
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,0x0(%r13)
  movslq (%rbx),%rax
  mov    (%r12,%rax,8),%rdi
  call   <strcpy@plt>
  addl   $0x1,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int listadditem(char **list, char *item, int *count, int capacity) {
  if (*count >= capacity) {
    return 0;
  }
  list[*count] = malloc(strlen(item) / sizeof(char));
  strcpy(list[*count], item);
  *count += 1;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<listadditem>:
  endbr64
  cmp    %ecx,(%rdx)
  jl     L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  movslq (%rbx),%rax
  lea    (%r12,%rax,8),%r13
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,0x0(%r13)
  movslq (%rbx),%rax
  mov    (%r12,%rax,8),%rdi
  call   <strcpy@plt>
  addl   $0x1,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int listadditem(char **list, char *item, int *count, int capacity) {
  if (*count >= capacity) {
    return 0;
  }
  list[*count] = malloc(strlen(item) / sizeof(char));
  strcpy(list[*count], item);
  *count += 1;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dAccumulate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    $0x0,%ebx
  jmp    L7
L12:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  add    $0x1,%ebx
L7:
  cmp    -0x24(%rbp),%ebx
  jl     L12
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double dAccumulate(double v[], int n) {
  double result = 0.0;
  register int i;
  for (i = 0; i < n; i++)
    result += v[i];
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dAccumulate>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L12:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L12
  ret
L6:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double dAccumulate(double v[], int n) {
  double result = 0.0;
  register int i;
  for (i = 0; i < n; i++)
    result += v[i];
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dAccumulate>:
  endbr64
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L15:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L15
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double dAccumulate(double v[], int n) {
  double result = 0.0;
  register int i;
  for (i = 0; i < n; i++)
    result += v[i];
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dAccumulate>:
  endbr64
  test   %esi,%esi
  jle    L30
  cmp    $0x1,%esi
  je     L32
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L49:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L49
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L29
L13:
  cltq
  addsd  (%rdi,%rax,8),%xmm0
  ret
  nopl   0x0(%rax)
L29:
  ret
  nopl   0x0(%rax)
L30:
  pxor   %xmm0,%xmm0
  ret
L32:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L13
```

assistant: ```c
double dAccumulate(double v[], int n) {
  double result = 0.0;
  register int i;
  for (i = 0; i < n; i++)
    result += v[i];
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: main


assistant: ```c
int main() {
  printf("main\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: main


assistant: ```c
int main() {
  printf("main\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: main


assistant: ```c
int main() {
  printf("main\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: main


assistant: ```c
int main() {
  printf("main\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L34
L13:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x24(%rbp)
L34:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L13
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x2c(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <count_sort_parallel@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L8
L19:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L8:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
type_infered: string
name: parse_data
arguments: data_label: D36
type_infered: string
name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string

tool: D18: %d

tool: D36: %lf

tool: D6: %.2lf 

tool: D27: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  int i, len, n_threads;
  scanf("%d", &n_threads);
  scanf("%d", &len);
  double *sequence = (double *)malloc(len * sizeof(double)), *sorted;
  for (i = 0; i < len; i++)
    scanf("%lf", &sequence[i]);
  double time_elapsed = omp_get_wtime();
  sorted = count_sort_parallel(sequence, len, n_threads);
  time_elapsed = omp_get_wtime() - time_elapsed;
  for (i = 0; i < len; i++)
    printf("%.2lf ", sorted[i]);
  printf("\n");
  printf("%lf\n", time_elapsed);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmpl   $0x0,(%rsp)
  jle    L33
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D11(%rip),%r12
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,(%rsp)
  jg     L14
L33:
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rbx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %r13,%rdi
  call   <count_sort_parallel@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %rbx,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%r13
  cmpl   $0x0,(%rsp)
  jle    L13
  mov    $0x0,%ebx
  lea    D16(%rip),%r12
L49:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,(%rsp)
  jg     L49
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  movq   %r13,%xmm0
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D23
type_infered: string
name: read_data
arguments: data_tag: D11
type_infered: string
name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D21
type_infered: string

tool: D23: %d

tool: D11: %lf

tool: D16: %.2lf 

tool: D21: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  int i, len, n_threads;
  scanf("%d", &n_threads);
  scanf("%d", &len);
  double *sequence = (double *)malloc(len * sizeof(double)), *sorted;
  for (i = 0; i < len; i++)
    scanf("%lf", &sequence[i]);
  double time_elapsed = omp_get_wtime();
  sorted = count_sort_parallel(sequence, len, n_threads);
  time_elapsed = omp_get_wtime() - time_elapsed;
  for (i = 0; i < len; i++)
    printf("%.2lf ", sorted[i]);
  printf("\n");
  printf("%lf\n", time_elapsed);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D30(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%edx
  mov    %rax,%r13
  test   %edx,%edx
  jle    L34
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D6(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x8,%rbp
  cmp    %ebx,0x10(%rsp)
  jg     L22
L34:
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <count_sort_parallel@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    0x10(%rsp),%eax
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  movq   %xmm1,%r13
  test   %eax,%eax
  jle    L21
  xor    %ebx,%ebx
  lea    D27(%rip),%r12
  nopl   0x0(%rax)
L17:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L17
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
  movq   %r13,%xmm0
  mov    $0x1,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D30
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string
name: retrieve_data
arguments: data_label: D27
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string

tool: D30: %d

tool: D6: %lf

tool: D27: %.2lf 

tool: D20: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  int i, len, n_threads;
  scanf("%d", &n_threads);
  scanf("%d", &len);
  double *sequence = (double *)malloc(len * sizeof(double)), *sorted;
  for (i = 0; i < len; i++)
    scanf("%lf", &sequence[i]);
  double time_elapsed = omp_get_wtime();
  sorted = count_sort_parallel(sequence, len, n_threads);
  time_elapsed = omp_get_wtime() - time_elapsed;
  for (i = 0; i < len; i++)
    printf("%.2lf ", sorted[i]);
  printf("\n");
  printf("%lf\n", time_elapsed);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%edx
  mov    %rax,%r13
  test   %edx,%edx
  jle    L19
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D34(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x8,%rbp
  cmp    %ebx,0x10(%rsp)
  jg     L14
L19:
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <count_sort_parallel@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    0x10(%rsp),%eax
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  movq   %xmm1,%r13
  test   %eax,%eax
  jle    L46
  xor    %ebx,%ebx
  lea    D5(%rip),%r12
  nopl   0x0(%rax)
L13:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L13
L46:
  mov    $0xa,%edi
  call   <putchar@plt>
  movq   %r13,%xmm0
  mov    $0x1,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
type_infered: string
name: read_data
arguments: tag: D34
type_infered: string
name: read_data
arguments: tag: D5
type_infered: string
name: read_data
arguments: tag: D39
type_infered: string

tool: D28: %d

tool: D34: %lf

tool: D5: %.2lf 

tool: D39: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  int i, len, n_threads;
  scanf("%d", &n_threads);
  scanf("%d", &len);
  double *sequence = (double *)malloc(len * sizeof(double)), *sorted;
  for (i = 0; i < len; i++)
    scanf("%lf", &sequence[i]);
  double time_elapsed = omp_get_wtime();
  sorted = count_sort_parallel(sequence, len, n_threads);
  time_elapsed = omp_get_wtime() - time_elapsed;
  for (i = 0; i < len; i++)
    printf("%.2lf ", sorted[i]);
  printf("\n");
  printf("%lf\n", time_elapsed);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strdup_until>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L13
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  jmp    L7
L13:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L7:
  leave
  ret
```

assistant: ```c
char *strdup_until(const char *s, const char *endchars) {
  char *endloc = strpbrk(s, endchars);
  char *ret;
  if (!endloc) {
    ret = malloc((strlen(s) + 1) * sizeof(char));
    strcpy(ret, s);
    return ret;
  } else {
    ret = malloc((endloc - s + 1) * sizeof(char));
    memcpy(ret, s, (endloc - s) * sizeof(char));
    ret[(endloc - s)] = '\0';
    return ret;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strdup_until>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L18:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L18
```

assistant: ```c
char *strdup_until(const char *s, const char *endchars) {
  char *endloc = strpbrk(s, endchars);
  char *ret;
  if (!endloc) {
    ret = malloc((strlen(s) + 1) * sizeof(char));
    strcpy(ret, s);
    return ret;
  } else {
    ret = malloc((endloc - s + 1) * sizeof(char));
    memcpy(ret, s, (endloc - s) * sizeof(char));
    ret[(endloc - s)] = '\0';
    return ret;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strdup_until>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup_until(const char *s, const char *endchars) {
  char *endloc = strpbrk(s, endchars);
  char *ret;
  if (!endloc) {
    ret = malloc((strlen(s) + 1) * sizeof(char));
    strcpy(ret, s);
    return ret;
  } else {
    ret = malloc((endloc - s + 1) * sizeof(char));
    memcpy(ret, s, (endloc - s) * sizeof(char));
    ret[(endloc - s)] = '\0';
    return ret;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strdup_until>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup_until(const char *s, const char *endchars) {
  char *endloc = strpbrk(s, endchars);
  char *ret;
  if (!endloc) {
    ret = malloc((strlen(s) + 1) * sizeof(char));
    strcpy(ret, s);
    return ret;
  } else {
    ret = malloc((endloc - s + 1) * sizeof(char));
    memcpy(ret, s, (endloc - s) * sizeof(char));
    ret[(endloc - s)] = '\0';
    return ret;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_striter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  cmpq   $0x0,-0x10(%rbp)
  je     L20
  jmp    L23
L27:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  jmp    L16
L20:
  nop
L16:
  leave
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  if (!s || !f)
    return;
  while (*s)
    f(s++);
}
```