user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L95
L129:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L95:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jle    L129
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L184
L107:
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L148:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L148
  movl   $0x0,-0xc(%rbp)
  jmp    L102
L193:
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L102:
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L193
  movl   $0x0,-0xc(%rbp)
  jmp    L173
L204:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L173:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L204
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L184:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x10(%rbp)
  jl     L107
  subl   $0x2,-0x10(%rbp)
  jmp    L84
L195:
  movl   $0x0,-0xc(%rbp)
  jmp    L132
L83:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L132:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L83
  movl   $0x0,-0xc(%rbp)
  jmp    L101
L146:
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L101:
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L146
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L141:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L141
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x10(%rbp)
L84:
  cmpl   $0x0,-0x10(%rbp)
  jns    L195
  movl   $0x0,-0x10(%rbp)
  jmp    L122
L182:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L122:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jle    L182
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L191
  call   <__stack_chk_fail@plt>
L191:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D56
type_infered: string
name: parse_data
arguments: tag: D0
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: string
name: parse_data
arguments: tag: D48
type_infered: string

tool: D56: %d

tool: D0: *

tool: D29: 


tool: D48:  

assistant: ```c
int main() {
  int n, i, j;
  scanf("%d", &n);
  for (i = 0; i < n / 2 * 2 + 1; i++) {
    printf("*");
  }
  printf("\n");
  for (i = 0; i < n / 2; i++) {
    for (j = 0; j < n / 2 - i; j++) {
      printf("*");
    }
    for (j = 0; j < i * 2 + 1; j++) {
      printf(" ");
    }
    for (j = 0; j < n / 2 - i; j++) {
      printf("*");
    }
    printf("\n");
  }
  for (i -= 2; i >= 0; i--) {
    for (j = 0; j < n / 2 - i; j++) {
      printf("*");
    }
    for (j = 0; j < i * 2 + 1; j++) {
      printf(" ");
    }
    for (j = 0; j < n / 2 - i; j++) {
      printf("*");
    }
    printf("\n");
  }
  for (i = 0; i < n / 2 * 2 + 1; i++) {
    printf("*");
  }
  printf("\n");
  return 0;
}
```