user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x16,(%rsp)
  movl   $0x24,0x4(%rsp)
  movl   $0x1b,0x8(%rsp)
  movl   $0x17,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  lea    D76(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D101(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D104(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D22(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D124(%rip),%rax
  mov    %rax,0x40(%rsp)
  mov    $0x0,%ebx
  lea    D70(%rip),%rbp
L32:
  mov    (%rsp,%rbx,4),%edx
  mov    0x20(%rsp,%rbx,8),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L32
  lea    D111(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D83(%rip),%rbp
L42:
  mov    (%rsp,%rbx,4),%edx
  mov    0x20(%rsp,%rbx,8),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L42
  lea    D111(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D94(%rip),%rbp
L31:
  mov    (%rsp,%rbx,4),%edx
  mov    0x20(%rsp,%rbx,8),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L31
  lea    D111(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    D76(%rip),%r13
  lea    D122(%rip),%r12
  mov    %rsp,%rbp
L48:
  mov    (%rbx),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  mov    %rbx,%rax
  sub    %rbp,%rax
  cmp    $0x10,%rax
  jle    L48
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D76
data_type: string
name: read_data
arguments: label: D101
data_type: string
name: read_data
arguments: label: D104
data_type: string
name: read_data
arguments: label: D22
data_type: string
name: read_data
arguments: label: D124
data_type: string
name: read_data
arguments: label: D70
data_type: string
name: read_data
arguments: label: D111
data_type: string
name: read_data
arguments: label: D83
data_type: string
name: read_data
arguments: label: D94
data_type: string
name: read_data
arguments: label: D122
data_type: string

tool: D76: Alan

tool: D101: Frank

tool: D104: Mary

tool: D22: John

tool: D124: Lisa

tool: D70: %s is %d years old


tool: D111: ---

tool: D83: %s is %d years alive


tool: D94: %s has lived %d years


tool: D122: %s's age is %d


assistant: ```c
int main(int argc, char *argv[]) {
  int ages[] = {22, 36, 27, 23, 2};
  char *names[] = {"Alan", "Frank", "Mary", "John", "Lisa"};
  int count = sizeof(ages) / sizeof(int);
  int i = 0;
  for (; i < count; i++) {
    printf("%s is %d years old\n", names[i], ages[i]);
  }
  printf("---\n");
  int *cur_age = ages;
  char **cur_name = names;
  for (i = 0; i < count + 1; i++) {
    printf("%s is %d years alive\n", *(cur_name + i), *(cur_age + i));
  }
  printf("---\n");
  for (i = -1; i++, i < count;) {
    printf("%s has lived %d years\n", cur_name[i], cur_age[i]);
  }
  printf("---\n");
  for (cur_age = ages, cur_name = names; (cur_age - ages) < count; cur_age++) {
    printf("%s's age is %d\n", *cur_name, *cur_age);
  }
  return 0;
}
```