ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L15
L43:
  movq   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x5,-0x1c(%rbp)
  jmp    L20
L16:
  mov    -0x18(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    $0x0,%edx
  div    %rcx
  add    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L20:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jbe    L16
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L15:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jl     L43
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string

tool: D18: %d

tool: D11: %llu

tool: D19: %llu


assistant: ```c
int main() {
  long long unsigned int fact5, num = 0;
  int inpCnt = 0;
  scanf("%d", &inpCnt);
  int count = 0;
  for (count = 0; count < inpCnt; count++) {
    fact5 = 0;
    scanf("%llu", &num);
    int factCheck = 5;
    while (factCheck <= num) {
      fact5 += num / factCheck;
      factCheck *= 5;
    }
    printf("%llu\n", fact5);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L13
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r13
  lea    D20(%rip),%r12
  mov    $0x5,%r14d
  lea    D13(%rip),%rbp
L10:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0x4,%rsi
  jbe    L31
  mov    %r14d,%edi
  mov    $0x0,%r8d
  mov    $0x5,%ecx
L32:
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    %rax,%r8
  lea    (%rdi,%rdi,4),%ecx
  mov    %ecx,%edi
  movslq %ecx,%rcx
  cmp    %rsi,%rcx
  jbe    L32
L4:
  mov    %r8,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L10
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  mov    $0x0,%r8d
  jmp    L4
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string
name: extract_symbolic_data
arguments: label: D13
type_guessed: string

tool: D7: %d

tool: D20: %llu

tool: D13: %llu


assistant: ```c
int main() {
  long long unsigned int fact5, num = 0;
  int inpCnt = 0;
  scanf("%d", &inpCnt);
  int count = 0;
  for (count = 0; count < inpCnt; count++) {
    fact5 = 0;
    scanf("%llu", &num);
    int factCheck = 5;
    while (factCheck <= num) {
      fact5 += num / factCheck;
      factCheck *= 5;
    }
    printf("%llu\n", fact5);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L49
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r13
  lea    D28(%rip),%r12
  lea    D24(%rip),%rbp
  nopl   (%rax)
L42:
  mov    %r12,%rdi
  mov    %r13,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  cmp    $0x4,%rdi
  jbe    L29
  mov    $0x5,%esi
  xor    %r8d,%r8d
  mov    $0x5,%ecx
  nopl   (%rax)
L57:
  mov    %rdi,%rax
  xor    %edx,%edx
  lea    (%rsi,%rsi,4),%esi
  div    %rcx
  movslq %esi,%rcx
  add    %rax,%r8
  cmp    %rdi,%rcx
  jbe    L57
L5:
  mov    %r8,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L42
L49:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L29:
  xor    %r8d,%r8d
  jmp    L5
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D28
type_infered: string
name: unpack_data
arguments: data_label: D24
type_infered: string

tool: D1: %d

tool: D28: %llu

tool: D24: %llu


assistant: ```c
int main() {
  long long unsigned int fact5, num = 0;
  int inpCnt = 0;
  scanf("%d", &inpCnt);
  int count = 0;
  for (count = 0; count < inpCnt; count++) {
    fact5 = 0;
    scanf("%llu", &num);
    int factCheck = 5;
    while (factCheck <= num) {
      fact5 += num / factCheck;
      factCheck *= 5;
    }
    printf("%llu\n", fact5);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L16
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r13
  lea    D14(%rip),%r12
  lea    D9(%rip),%rbp
  nopl   (%rax)
L47:
  mov    %r12,%rdi
  mov    %r13,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  cmp    $0x4,%rdi
  jbe    L11
  mov    $0x5,%esi
  xor    %r8d,%r8d
  mov    $0x5,%ecx
  nopl   (%rax)
L54:
  mov    %rdi,%rax
  xor    %edx,%edx
  lea    (%rsi,%rsi,4),%esi
  div    %rcx
  movslq %esi,%rcx
  add    %rax,%r8
  cmp    %rdi,%rcx
  jbe    L54
L6:
  mov    %r8,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L47
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L11:
  xor    %r8d,%r8d
  jmp    L6
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D14
type: string
name: unpack_data
arguments: label: D9
type: string

tool: D15: %d

tool: D14: %llu

tool: D9: %llu


assistant: ```c
int main() {
  long long unsigned int fact5, num = 0;
  int inpCnt = 0;
  scanf("%d", &inpCnt);
  int count = 0;
  for (count = 0; count < inpCnt; count++) {
    fact5 = 0;
    scanf("%llu", &num);
    int factCheck = 5;
    while (factCheck <= num) {
      fact5 += num / factCheck;
      factCheck *= 5;
    }
    printf("%llu\n", fact5);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<powerof2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L12:
  shll   -0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int powerof2(int ex) {
  int i, n = 1;
  for (i = 0; i < ex; i++)
    n *= 2;
  return (n);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<powerof2>:
  endbr64
  test   %edi,%edi
  jle    L25
  mov    $0x1,%edx
  mov    $0x0,%eax
L10:
  add    %edx,%edx
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L10
L24:
  mov    %edx,%eax
  ret
L25:
  mov    $0x1,%edx
  jmp    L24
```

assistant: ```c
int powerof2(int ex) {
  int i, n = 1;
  for (i = 0; i < ex; i++)
    n *= 2;
  return (n);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<powerof2>:
  endbr64
  mov    $0x1,%r8d
  test   %edi,%edi
  jle    L10
  xor    %eax,%eax
L8:
  add    $0x1,%eax
  add    %r8d,%r8d
  cmp    %eax,%edi
  jne    L8
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int powerof2(int ex) {
  int i, n = 1;
  for (i = 0; i < ex; i++)
    n *= 2;
  return (n);
}
```
user: What is the c source code of the assembly code below?

```asm
<powerof2>:
  endbr64
  test   %edi,%edi
  jle    L36
  cmp    $0x1,%edi
  je     L39
  movq   D0(%rip),%xmm0
  mov    %edi,%edx
  xor    %eax,%eax
  shr    %edx
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%eax
  pslld  $0x1,%xmm0
  cmp    %eax,%edx
  jne    L28
  movd   %xmm0,%eax
  pshufd $0xe5,%xmm0,%xmm1
  movd   %xmm1,%edx
  imul   %edx,%eax
  and    $0x1,%edi
  je     L31
L9:
  add    %eax,%eax
  ret
  nopl   0x0(%rax)
L31:
  ret
  nopl   0x0(%rax)
L36:
  mov    $0x1,%eax
  ret
L39:
  mov    $0x1,%eax
  jmp    L9
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: byte[8]

tool: {"D0": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int powerof2(int ex) {
  int i, n = 1;
  for (i = 0; i < ex; i++)
    n *= 2;
  return (n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0xb45,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L17
L13:
  addw   $0x2,-0xc(%rbp)
L17:
  cmpw   $0x0,-0xc(%rbp)
  je     L13
  movzwl -0xa(%rbp),%eax
  lea    0x1838(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
      }
      if (state[0UL] == local1) {
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 316086328UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x237d,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
      }
      if (state[0UL] == local1) {
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 316086328UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x237d,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
      }
      if (state[0UL] == local1) {
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 316086328UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x237d,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
      }
      if (state[0UL] == local1) {
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 316086328UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_string_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L2
L23:
  addq   $0x1,-0x30(%rbp)
  addq   $0x8,-0x28(%rbp)
L2:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L23
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L19
L5:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  addq   $0x1,-0x20(%rbp)
L19:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L5
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **copy_string_array(const char **orig) {
  size_t num_entries = 0;
  for (const char **current = orig; *current; current++) {
    num_entries += 1;
  }
  char **copy = calloc(num_entries + 1, sizeof(char *));
  for (size_t i = 0; i < num_entries; i++) {
    copy[i] = strdup(orig[i]);
  }
  return copy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_string_array>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  je     L33
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L10:
  mov    %rbx,%r12
  add    $0x1,%rbx
  cmpq   $0x0,0x0(%rbp,%rbx,8)
  jne    L10
  lea    0x2(%r12),%rdi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rbx,%rbx
  je     L6
  mov    $0x0,%ebx
L17:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%r13,%rbx,8)
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%r12
  jne    L17
L6:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  mov    $0x8,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  jmp    L6
```

assistant: ```c
char **copy_string_array(const char **orig) {
  size_t num_entries = 0;
  for (const char **current = orig; *current; current++) {
    num_entries += 1;
  }
  char **copy = calloc(num_entries + 1, sizeof(char *));
  for (size_t i = 0; i < num_entries; i++) {
    copy[i] = strdup(orig[i]);
  }
  return copy;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_string_array>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L9
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L38:
  mov    %rbx,%rbp
  lea    0x1(%rbx),%rbx
  cmpq   $0x0,0x8(%r12,%rbp,8)
  jne    L38
  lea    0x2(%rbp),%rdi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rbx,%rbx
  je     L39
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%r12,%rbx,8),%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%r13,%rbx,8)
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rbp
  jne    L14
L39:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x8,%esi
  mov    $0x1,%edi
  jmp    1060 <calloc@plt>
```

assistant: ```c
char **copy_string_array(const char **orig) {
  size_t num_entries = 0;
  for (const char **current = orig; *current; current++) {
    num_entries += 1;
  }
  char **copy = calloc(num_entries + 1, sizeof(char *));
  for (size_t i = 0; i < num_entries; i++) {
    copy[i] = strdup(orig[i]);
  }
  return copy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_string_array>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L4
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L28:
  mov    %rbx,%rbp
  lea    0x1(%rbx),%rbx
  cmpq   $0x0,0x8(%r12,%rbp,8)
  jne    L28
  lea    0x2(%rbp),%rdi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rbx,%rbx
  je     L16
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%r12,%rbx,8),%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%r13,%rbx,8)
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rbp
  jne    L11
L16:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x8,%esi
  mov    $0x1,%edi
  jmp    1060 <calloc@plt>
```

assistant: ```c
char **copy_string_array(const char **orig) {
  size_t num_entries = 0;
  for (const char **current = orig; *current; current++) {
    num_entries += 1;
  }
  char **copy = calloc(num_entries + 1, sizeof(char *));
  for (size_t i = 0; i < num_entries; i++) {
    copy[i] = strdup(orig[i]);
  }
  return copy;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<COMDIV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  mov    %rax,%rbx
  mov    -0x40(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  cmp    %rax,%rbx
  jle    L4
  movsd  -0x40(%rbp),%xmm0
  divsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x40(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  divsd  -0x38(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  divsd  -0x38(%rbp),%xmm0
  mov    -0x50(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L6
L4:
  movsd  -0x38(%rbp),%xmm0
  divsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  movsd  -0x40(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  divsd  -0x40(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  divsd  -0x40(%rbp),%xmm0
  mov    -0x50(%rbp),%rax
  movsd  %xmm0,(%rax)
L6:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void COMDIV(double ar, double ai, double br, double bi, double *cr, double *ci) {
  double tmp;
  if (fabs(br) > fabs(bi)) {
    tmp = bi / br;
    br = tmp * bi + br;
    *cr = (ar + tmp * ai) / br;
    *ci = (ai - tmp * ar) / br;
  } else {
    tmp = br / bi;
    bi = tmp * br + bi;
    *cr = (tmp * ar + ai) / bi;
    *ci = (tmp * ai - ar) / bi;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<COMDIV>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movq   %xmm2,%r14
  movq   %xmm3,%r15
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movapd %xmm2,%xmm0
  call   <fabs@plt>
  mov    %rax,%r12
  movq   %r15,%xmm0
  call   <fabs@plt>
  cmp    %rax,%r12
  jle    L19
  movq   %r15,%xmm6
  movq   %r15,%xmm7
  movq   %r14,%xmm2
  divsd  %xmm2,%xmm7
  mulsd  %xmm7,%xmm6
  movapd %xmm6,%xmm3
  addsd  %xmm2,%xmm3
  movsd  0x8(%rsp),%xmm4
  movapd %xmm4,%xmm2
  mulsd  %xmm7,%xmm2
  movsd  (%rsp),%xmm5
  addsd  %xmm5,%xmm2
  divsd  %xmm3,%xmm2
  mulsd  %xmm7,%xmm5
  subsd  %xmm5,%xmm4
  movapd %xmm4,%xmm0
  divsd  %xmm3,%xmm0
L7:
  movsd  %xmm2,0x0(%rbp)
  movsd  %xmm0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
L19:
  movq   %r14,%xmm7
  movq   %r14,%xmm0
  movq   %r15,%xmm6
  divsd  %xmm6,%xmm0
  mulsd  %xmm0,%xmm7
  movapd %xmm7,%xmm1
  addsd  %xmm6,%xmm1
  movsd  (%rsp),%xmm4
  movapd %xmm4,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm5
  addsd  %xmm5,%xmm2
  divsd  %xmm1,%xmm2
  mulsd  %xmm5,%xmm0
  subsd  %xmm4,%xmm0
  divsd  %xmm1,%xmm0
  jmp    L7
```

assistant: ```c
void COMDIV(double ar, double ai, double br, double bi, double *cr, double *ci) {
  double tmp;
  if (fabs(br) > fabs(bi)) {
    tmp = bi / br;
    br = tmp * bi + br;
    *cr = (ar + tmp * ai) / br;
    *ci = (ai - tmp * ar) / br;
  } else {
    tmp = br / bi;
    bi = tmp * br + bi;
    *cr = (tmp * ar + ai) / bi;
    *ci = (tmp * ai - ar) / bi;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<COMDIV>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <fabs@plt>
  movsd  (%rsp),%xmm3
  mov    %rax,%r12
  movapd %xmm3,%xmm0
  call   <fabs@plt>
  movsd  (%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  cmp    %rax,%r12
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm4
  jle    L2
  movapd %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm3
  addsd  %xmm2,%xmm3
  movapd %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  addsd  %xmm4,%xmm2
  mulsd  %xmm0,%xmm4
  divsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm3,%xmm0
L18:
  movsd  %xmm2,0x0(%rbp)
  movsd  %xmm0,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  movapd %xmm2,%xmm0
  divsd  %xmm3,%xmm0
  mulsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm3
  movapd %xmm0,%xmm2
  mulsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm0
  addsd  %xmm1,%xmm2
  subsd  %xmm4,%xmm0
  divsd  %xmm3,%xmm2
  divsd  %xmm3,%xmm0
  jmp    L18
```

assistant: ```c
void COMDIV(double ar, double ai, double br, double bi, double *cr, double *ci) {
  double tmp;
  if (fabs(br) > fabs(bi)) {
    tmp = bi / br;
    br = tmp * bi + br;
    *cr = (ar + tmp * ai) / br;
    *ci = (ai - tmp * ar) / br;
  } else {
    tmp = br / bi;
    bi = tmp * br + bi;
    *cr = (tmp * ar + ai) / bi;
    *ci = (tmp * ai - ar) / bi;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<COMDIV>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <fabs@plt>
  movsd  (%rsp),%xmm3
  mov    %rax,%r12
  movapd %xmm3,%xmm0
  call   <fabs@plt>
  movsd  (%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  cmp    %rax,%r12
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm4
  jle    L11
  movapd %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm3
  addsd  %xmm2,%xmm3
  movapd %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  addsd  %xmm4,%xmm2
  mulsd  %xmm0,%xmm4
  divsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm3,%xmm0
L18:
  movsd  %xmm2,0x0(%rbp)
  movsd  %xmm0,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  movapd %xmm2,%xmm0
  divsd  %xmm3,%xmm0
  mulsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm3
  movapd %xmm0,%xmm2
  mulsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm0
  addsd  %xmm1,%xmm2
  subsd  %xmm4,%xmm0
  divsd  %xmm3,%xmm2
  divsd  %xmm3,%xmm0
  jmp    L18
```

assistant: ```c
void COMDIV(double ar, double ai, double br, double bi, double *cr, double *ci) {
  double tmp;
  if (fabs(br) > fabs(bi)) {
    tmp = bi / br;
    br = tmp * bi + br;
    *cr = (ar + tmp * ai) / br;
    *ci = (ai - tmp * ar) / br;
  } else {
    tmp = br / bi;
    bi = tmp * br + bi;
    *cr = (tmp * ar + ai) / bi;
    *ci = (tmp * ai - ar) / bi;
  }
}
```