ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calcMeanSquare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x1c(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  divss  %xmm1,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float calcMeanSquare(float *buffer, int blocksize) {
  float sumsquare = 0.0f;
  for (int i = 0; i < blocksize; i++) {
    sumsquare += buffer[i] * buffer[i];
  }
  return sumsquare / (float)blocksize;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calcMeanSquare>:
  endbr64
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L28:
  movss  (%rax),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L28
L11:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
L19:
  pxor   %xmm0,%xmm0
  jmp    L11
```

assistant: ```c
float calcMeanSquare(float *buffer, int blocksize) {
  float sumsquare = 0.0f;
  for (int i = 0; i < blocksize; i++) {
    sumsquare += buffer[i] * buffer[i];
  }
  return sumsquare / (float)blocksize;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calcMeanSquare>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L17:
  movss  (%rdi),%xmm1
  add    $0x4,%rdi
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L17
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float calcMeanSquare(float *buffer, int blocksize) {
  float sumsquare = 0.0f;
  for (int i = 0; i < blocksize; i++) {
    sumsquare += buffer[i] * buffer[i];
  }
  return sumsquare / (float)blocksize;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calcMeanSquare>:
  endbr64
  test   %esi,%esi
  jle    L60
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L14
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L29:
  movups (%rax),%xmm1
  add    $0x10,%rax
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L29
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L57
L16:
  movslq %eax,%rdx
  movss  (%rdi,%rdx,4),%xmm1
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %edx,%esi
  jle    L57
  movss  0x4(%rdi,%rcx,1),%xmm1
  add    $0x2,%eax
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %eax,%esi
  jle    L57
  movss  0x8(%rdi,%rcx,1),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
L57:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
L14:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L16
```

assistant: ```c
float calcMeanSquare(float *buffer, int blocksize) {
  float sumsquare = 0.0f;
  for (int i = 0; i < blocksize; i++) {
    sumsquare += buffer[i] * buffer[i];
  }
  return sumsquare / (float)blocksize;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x1c(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D14: %d %d %lf

tool: D0: VALOR A PAGAR: R$ %.2lf


assistant: ```c
int main() {
  int c1, c2, n1, n2;
  double v1, v2;
  scanf("%d %d %lf", &c1, &n1, &v1);
  scanf("%d %d %lf", &c2, &n2, &v2);
  printf("VALOR A PAGAR: R$ %.2lf\n", n1 * v1 + n2 * v2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x20(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x10(%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x14(%rsp),%xmm1
  mulsd  0x20(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string

tool: D11: %d %d %lf

tool: D13: VALOR A PAGAR: R$ %.2lf


assistant: ```c
int main() {
  int c1, c2, n1, n2;
  double v1, v2;
  scanf("%d %d %lf", &c1, &n1, &v1);
  scanf("%d %d %lf", &c2, &n2, &v2);
  printf("VALOR A PAGAR: R$ %.2lf\n", n1 * v1 + n2 * v2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  lea    0x20(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D5(%rip),%rdi
  cvtsi2sdl 0x10(%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm0
  cvtsi2sdl 0x14(%rsp),%xmm1
  mulsd  0x20(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D4: %d %d %lf

tool: D5: VALOR A PAGAR: R$ %.2lf


assistant: ```c
int main() {
  int c1, c2, n1, n2;
  double v1, v2;
  scanf("%d %d %lf", &c1, &n1, &v1);
  scanf("%d %d %lf", &c2, &n2, &v2);
  printf("VALOR A PAGAR: R$ %.2lf\n", n1 * v1 + n2 * v2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  lea    0x20(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D7(%rip),%rdi
  cvtsi2sdl 0x10(%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm0
  cvtsi2sdl 0x14(%rsp),%xmm1
  mulsd  0x20(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D7
type: string

tool: D15: %d %d %lf

tool: D7: VALOR A PAGAR: R$ %.2lf


assistant: ```c
int main() {
  int c1, c2, n1, n2;
  double v1, v2;
  scanf("%d %d %lf", &c1, &n1, &v1);
  scanf("%d %d %lf", &c2, &n2, &v2);
  printf("VALOR A PAGAR: R$ %.2lf\n", n1 * v1 + n2 * v2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lop>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rdi,%r8
  mov    %edx,%r11d
  lea    -0x1(%rdx),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D6(%rip),%xmm3
  movapd %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm3
  cmp    $0x2,%edx
  jle    L0
  mov    %rsi,%rcx
  mov    %edx,%r10d
  lea    0x0(,%r10,8),%rbx
  mov    $0x10,%edi
  movsd  D14(%rip),%xmm4
L50:
  mov    %rdi,%rdx
  add    $0x8,%rdi
  lea    -0x8(%rdx),%r9
  mov    $0x2,%eax
L15:
  mov    (%rcx,%rax,8),%rbp
  movsd  0x0(%rbp,%rdx,1),%xmm1
  mov    (%r8,%rax,8),%rsi
  mov    0x8(%rcx,%rax,8),%r14
  movsd  (%r14,%rdx,1),%xmm0
  mov    -0x8(%rcx,%rax,8),%r14
  addsd  (%r14,%rdx,1),%xmm0
  addsd  0x0(%rbp,%rdi,1),%xmm0
  addsd  0x0(%rbp,%r9,1),%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rdx,1)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L15
  cmp    %rdi,%rbx
  jne    L50
L21:
  movslq %r11d,%rcx
  shl    $0x3,%rcx
  lea    (%r8,%rcx,1),%rsi
  mov    $0x1,%eax
L56:
  mov    (%rsi),%rdx
  movq   $0x0,(%rdx,%rax,8)
  mov    0x8(%r8),%rdx
  movq   $0x0,(%rdx,%rax,8)
  mov    (%r8,%rax,8),%rdx
  movq   $0x0,(%rdx,%rcx,1)
  mov    (%r8,%rax,8),%rdx
  movq   $0x0,0x8(%rdx)
  add    $0x1,%rax
  cmp    %eax,%r11d
  jge    L56
L32:
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L0:
  test   %edx,%edx
  jle    L32
  jmp    L21
```

tool_calls: name: read_data
arguments: label: D6
type: f64
name: read_data
arguments: label: D14
type: f64

tool: D6: 1

tool: D14: 4

assistant: ```c
void lop(double **out, double **u, int n) {
  int i, j;
  double h, h2i;
  h = 1.0 / (n - 1);
  h2i = 1.0 / (h * h);
  for (j = 2; j < n; j++)
    for (i = 2; i < n; i++)
      out[i][j] = h2i * (u[i + 1][j] + u[i - 1][j] + u[i][j + 1] + u[i][j - 1] - 4.0 * u[i][j]) + u[i][j] * u[i][j];
  for (i = 1; i <= n; i++)
    out[i][1] = out[i][n] = out[1][i] = out[n][i] = 0.0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lop>:
  endbr64
  lea    -0x1(%rdx),%eax
  pxor   %xmm1,%xmm1
  push   %r14
  mov    %rdi,%r8
  cvtsi2sd %eax,%xmm1
  movsd  D13(%rip),%xmm3
  push   %rbp
  mov    %edx,%r11d
  push   %rbx
  movapd %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm3
  cmp    $0x2,%edx
  jle    L32
  movslq %edx,%r10
  movsd  D18(%rip),%xmm4
  mov    %rsi,%rcx
  mov    $0x10,%edi
  lea    0x0(,%r10,8),%rbx
  nopl   (%rax)
L36:
  mov    %rdi,%rdx
  mov    $0x2,%eax
  add    $0x8,%rdi
  lea    -0x8(%rdx),%r9
  nopl   0x0(%rax,%rax,1)
L50:
  mov    (%rcx,%rax,8),%rbp
  mov    0x8(%rcx,%rax,8),%r14
  mov    (%r8,%rax,8),%rsi
  movsd  0x0(%rbp,%rdx,1),%xmm1
  movsd  (%r14,%rdx,1),%xmm0
  mov    -0x8(%rcx,%rax,8),%r14
  add    $0x1,%rax
  movapd %xmm1,%xmm2
  mulsd  %xmm4,%xmm2
  addsd  (%r14,%rdx,1),%xmm0
  addsd  0x0(%rbp,%rdi,1),%xmm0
  addsd  0x0(%rbp,%r9,1),%xmm0
  mulsd  %xmm1,%xmm1
  subsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rdx,1)
  cmp    %rax,%r10
  jne    L50
  cmp    %rbx,%rdi
  jne    L36
L11:
  mov    (%r8,%r10,8),%rsi
  mov    0x8(%r8),%rcx
  mov    $0x1,%eax
  lea    0x0(,%r10,8),%rdi
  nopl   0x0(%rax)
L19:
  mov    (%r8,%rax,8),%rdx
  movq   $0x0,(%rsi,%rax,8)
  movq   $0x0,(%rcx,%rax,8)
  add    $0x1,%rax
  movq   $0x0,(%rdx,%rdi,1)
  movq   $0x0,0x8(%rdx)
  cmp    %eax,%r11d
  jge    L19
L30:
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L32:
  test   %edx,%edx
  jle    L30
  movslq %edx,%r10
  jmp    L11
```

tool_calls: name: read_data
arguments: tag: D13
type: f64
name: read_data
arguments: tag: D18
type: f64

tool: D13: 1

tool: D18: 4

assistant: ```c
void lop(double **out, double **u, int n) {
  int i, j;
  double h, h2i;
  h = 1.0 / (n - 1);
  h2i = 1.0 / (h * h);
  for (j = 2; j < n; j++)
    for (i = 2; i < n; i++)
      out[i][j] = h2i * (u[i + 1][j] + u[i - 1][j] + u[i][j + 1] + u[i][j - 1] - 4.0 * u[i][j]) + u[i][j] * u[i][j];
  for (i = 1; i <= n; i++)
    out[i][1] = out[i][n] = out[1][i] = out[n][i] = 0.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lop>:
  endbr64
  lea    -0x1(%rdx),%eax
  pxor   %xmm1,%xmm1
  push   %r14
  mov    %rdi,%r8
  cvtsi2sd %eax,%xmm1
  movsd  D9(%rip),%xmm3
  push   %rbp
  mov    %edx,%r11d
  push   %rbx
  movapd %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm3
  cmp    $0x2,%edx
  jle    L41
  movslq %edx,%r10
  movsd  D18(%rip),%xmm4
  mov    %rsi,%rcx
  mov    $0x10,%edi
  lea    0x0(,%r10,8),%rbx
  nopl   (%rax)
L9:
  mov    %rdi,%rdx
  mov    $0x2,%eax
  add    $0x8,%rdi
  lea    -0x8(%rdx),%r9
  nopl   0x0(%rax,%rax,1)
L32:
  mov    (%rcx,%rax,8),%rbp
  mov    0x8(%rcx,%rax,8),%r14
  mov    (%r8,%rax,8),%rsi
  movsd  0x0(%rbp,%rdx,1),%xmm1
  movsd  (%r14,%rdx,1),%xmm0
  mov    -0x8(%rcx,%rax,8),%r14
  add    $0x1,%rax
  movapd %xmm1,%xmm2
  mulsd  %xmm4,%xmm2
  addsd  (%r14,%rdx,1),%xmm0
  addsd  0x0(%rbp,%rdi,1),%xmm0
  addsd  0x0(%rbp,%r9,1),%xmm0
  mulsd  %xmm1,%xmm1
  subsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rdx,1)
  cmp    %rax,%r10
  jne    L32
  cmp    %rbx,%rdi
  jne    L9
L31:
  mov    (%r8,%r10,8),%rsi
  mov    0x8(%r8),%rcx
  mov    $0x1,%eax
  lea    0x0(,%r10,8),%rdi
  nopl   0x0(%rax)
L14:
  mov    (%r8,%rax,8),%rdx
  movq   $0x0,(%rsi,%rax,8)
  movq   $0x0,(%rcx,%rax,8)
  add    $0x1,%rax
  movq   $0x0,(%rdx,%rdi,1)
  movq   $0x0,0x8(%rdx)
  cmp    %eax,%r11d
  jge    L14
L59:
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L41:
  test   %edx,%edx
  jle    L59
  movslq %edx,%r10
  jmp    L31
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: f64
name: unpack_data
arguments: label: D18
data_type: f64

tool: D9: 1

tool: D18: 4

assistant: ```c
void lop(double **out, double **u, int n) {
  int i, j;
  double h, h2i;
  h = 1.0 / (n - 1);
  h2i = 1.0 / (h * h);
  for (j = 2; j < n; j++)
    for (i = 2; i < n; i++)
      out[i][j] = h2i * (u[i + 1][j] + u[i - 1][j] + u[i][j + 1] + u[i][j - 1] - 4.0 * u[i][j]) + u[i][j] * u[i][j];
  for (i = 1; i <= n; i++)
    out[i][1] = out[i][n] = out[1][i] = out[n][i] = 0.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x61,0x4(%rsp)
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D24(%rip),%r13
  mov    %r13,%rdi
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  movsbl 0x5(%rsp),%edx
  movsbl 0x4(%rsp),%esi
  movsbl 0x7(%rsp),%r8d
  lea    D53(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movb   $0x5a,0x4(%rsp)
  movb   $0x65,0x5(%rsp)
  movb   $0x64,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  movsbl 0x5(%rsp),%edx
  movsbl 0x4(%rsp),%esi
  movsbl 0x7(%rsp),%r8d
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D44(%rip),%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%r8d
  mov    $0x64,%ecx
  mov    $0x65,%edx
  mov    $0x5a,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type_infered: string
name: extract_symbolic_data
arguments: label: D53
type_infered: string
name: extract_symbolic_data
arguments: label: D8
type_infered: string
name: extract_symbolic_data
arguments: label: D44
type_infered: string
name: extract_symbolic_data
arguments: label: D19
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D24: numbers: %d, %d, %d, %d


tool: D53: name each: %c, %c, %c, %c


tool: D8: name: %s


tool: D44: Zed

tool: D19: another: %s


tool: D12: another each: %c %c %c %c


assistant: ```c
int main(int argc, char *argv[]) {
  int numbers[4] = {0};
  char name[4] = {'a'};
  printf("numbers: %d, %d, %d, %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c, %c, %c, %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  numbers[0] = 1;
  numbers[1] = 2;
  numbers[2] = 3;
  numbers[3] = 4;
  name[0] = 'Z';
  name[1] = 'e';
  name[2] = 'd';
  name[3] = '\0';
  printf("numbers: %d, %d, %d, %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c, %c, %c, %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  char *another = "Zed";
  printf("another: %s\n", another);
  printf("another each: %c %c %c %c\n", another[0], another[1], another[2], another[3]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D52(%rip),%r14
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   %r13
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  push   %r12
  lea    D51(%rip),%r13
  push   %rbp
  lea    D35(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x61,0x4(%rsp)
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%r8d
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  movl   $0x64655a,0x4(%rsp)
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D0(%rip),%rsi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    $0x64,%ecx
  mov    $0x65,%edx
  mov    $0x5a,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D52
type_guessed: string
name: retrieve_data
arguments: label: D51
type_guessed: string
name: retrieve_data
arguments: label: D35
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D47
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string

tool: D52: numbers: %d, %d, %d, %d


tool: D51: name each: %c, %c, %c, %c


tool: D35: name: %s


tool: D0: Zed

tool: D47: another: %s


tool: D19: another each: %c %c %c %c


assistant: ```c
int main(int argc, char *argv[]) {
  int numbers[4] = {0};
  char name[4] = {'a'};
  printf("numbers: %d, %d, %d, %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c, %c, %c, %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  numbers[0] = 1;
  numbers[1] = 2;
  numbers[2] = 3;
  numbers[3] = 4;
  name[0] = 'Z';
  name[1] = 'e';
  name[2] = 'd';
  name[3] = '\0';
  printf("numbers: %d, %d, %d, %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c, %c, %c, %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  char *another = "Zed";
  printf("another: %s\n", another);
  printf("another each: %c %c %c %c\n", another[0], another[1], another[2], another[3]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D50(%rip),%r14
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   %r13
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  push   %r12
  lea    D35(%rip),%r13
  push   %rbp
  lea    D18(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x61,0x4(%rsp)
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%r8d
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  movl   $0x64655a,0x4(%rsp)
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    $0x64,%ecx
  mov    $0x65,%edx
  mov    $0x5a,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D50
type_infered: string
name: disassemble_data
arguments: tag: D35
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D12
type_infered: string
name: disassemble_data
arguments: tag: D24
type_infered: string

tool: D50: numbers: %d, %d, %d, %d


tool: D35: name each: %c, %c, %c, %c


tool: D18: name: %s


tool: D7: Zed

tool: D12: another: %s


tool: D24: another each: %c %c %c %c


assistant: ```c
int main(int argc, char *argv[]) {
  int numbers[4] = {0};
  char name[4] = {'a'};
  printf("numbers: %d, %d, %d, %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c, %c, %c, %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  numbers[0] = 1;
  numbers[1] = 2;
  numbers[2] = 3;
  numbers[3] = 4;
  name[0] = 'Z';
  name[1] = 'e';
  name[2] = 'd';
  name[3] = '\0';
  printf("numbers: %d, %d, %d, %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c, %c, %c, %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  char *another = "Zed";
  printf("another: %s\n", another);
  printf("another each: %c %c %c %c\n", another[0], another[1], another[2], another[3]);
  return 0;
}
```