ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <dollars@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: 113213212

assistant: ```c
int main(int argc, char *argv[]) {
  char dest[20];
  char *src = "113213212";
  dollars(dest, src);
  puts(dest);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<key_gen_auto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <key_gen_run_it@plt>
  test   %rax,%rax
  je     L11
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <key_gen@plt>
  jmp    L6
L11:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <g_writeln@plt>
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D11: /etc/xrdp/rsakeys.ini

tool: D6: xrdp-keygen does not need to run

assistant: ```c
int key_gen_auto(void) {
  if (key_gen_run_it()) {
    return key_gen("/etc/xrdp/rsakeys.ini");
  }
  g_writeln("xrdp-keygen does not need to run");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<key_gen_auto>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <key_gen_run_it@plt>
  test   %rax,%rax
  jne    L5
  lea    D3(%rip),%rdi
  call   <g_writeln@plt>
  mov    $0x0,%eax
L15:
  add    $0x8,%rsp
  ret
L5:
  lea    D9(%rip),%rdi
  call   <key_gen@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: tag: D3
type: string
name: parse_data
arguments: tag: D9
type: string

tool: D3: xrdp-keygen does not need to run

tool: D9: /etc/xrdp/rsakeys.ini

assistant: ```c
int key_gen_auto(void) {
  if (key_gen_run_it()) {
    return key_gen("/etc/xrdp/rsakeys.ini");
  }
  g_writeln("xrdp-keygen does not need to run");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<key_gen_auto>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <key_gen_run_it@plt>
  test   %rax,%rax
  jne    L1
  lea    D12(%rip),%rdi
  call   <g_writeln@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <key_gen@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D12: xrdp-keygen does not need to run

tool: D8: /etc/xrdp/rsakeys.ini

assistant: ```c
int key_gen_auto(void) {
  if (key_gen_run_it()) {
    return key_gen("/etc/xrdp/rsakeys.ini");
  }
  g_writeln("xrdp-keygen does not need to run");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<key_gen_auto>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <key_gen_run_it@plt>
  test   %rax,%rax
  jne    L1
  lea    D9(%rip),%rdi
  call   <g_writeln@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <key_gen@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string
name: read_data
arguments: data_tag: D5
data_type: string

tool: D9: xrdp-keygen does not need to run

tool: D5: /etc/xrdp/rsakeys.ini

assistant: ```c
int key_gen_auto(void) {
  if (key_gen_run_it()) {
    return key_gen("/etc/xrdp/rsakeys.ini");
  }
  g_writeln("xrdp-keygen does not need to run");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mandelbort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L5
L6:
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  -0x38(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  -0x40(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L5:
  cmpl   $0x9,-0x24(%rbp)
  jle    L6
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <tanh@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double mandelbort(double cX, double cY) {
  double x = 0, y = 0;
  int i = 0;
  for (i = 0; i < 10; i++) {
    double x_ = x * x - y * y + cX;
    y = 2.0 * x * y + cY;
    x = x_;
  }
  double r = sqrt(x * x + y * y);
  return tanh(r);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mandelbort>:
  endbr64
  sub    $0x8,%rsp
  movapd %xmm0,%xmm5
  mov    $0xa,%eax
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
L15:
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm0
  movapd %xmm2,%xmm4
  mulsd  %xmm2,%xmm4
  subsd  %xmm4,%xmm0
  addsd  %xmm5,%xmm0
  addsd  %xmm3,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm1,%xmm2
  sub    $0x1,%eax
  jne    L15
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L24
  sqrtsd %xmm0,%xmm0
L22:
  call   <tanh@plt>
  add    $0x8,%rsp
  ret
L24:
  call   <sqrt@plt>
  jmp    L22
```

assistant: ```c
double mandelbort(double cX, double cY) {
  double x = 0, y = 0;
  int i = 0;
  for (i = 0; i < 10; i++) {
    double x_ = x * x - y * y + cX;
    y = 2.0 * x * y + cY;
    x = x_;
  }
  double r = sqrt(x * x + y * y);
  return tanh(r);
}
```
user: What is the c source code of the assembly code below?

```asm
<mandelbort>:
  endbr64
  pxor   %xmm6,%xmm6
  movapd %xmm0,%xmm5
  mov    $0xa,%eax
  movapd %xmm6,%xmm3
  movapd %xmm6,%xmm0
  nopl   0x0(%rax)
L4:
  movapd %xmm0,%xmm2
  movapd %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  addsd  %xmm2,%xmm2
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm3
  subsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm3
  addsd  %xmm5,%xmm0
  sub    $0x1,%eax
  jne    L4
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  addsd  %xmm3,%xmm0
  ucomisd %xmm0,%xmm6
  ja     L13
  sqrtsd %xmm0,%xmm0
  jmp    1070 <tanh@plt>
L13:
  push   %rax
  call   <sqrt@plt>
  pop    %rdx
  jmp    1070 <tanh@plt>
```

assistant: ```c
double mandelbort(double cX, double cY) {
  double x = 0, y = 0;
  int i = 0;
  for (i = 0; i < 10; i++) {
    double x_ = x * x - y * y + cX;
    y = 2.0 * x * y + cY;
    x = x_;
  }
  double r = sqrt(x * x + y * y);
  return tanh(r);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mandelbort>:
  endbr64
  pxor   %xmm5,%xmm5
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm3
  addsd  %xmm5,%xmm2
  addsd  %xmm5,%xmm3
  movapd %xmm0,%xmm6
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm0
  mulsd  %xmm3,%xmm4
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm2
  mulsd  %xmm2,%xmm3
  subsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm3
  addsd  %xmm6,%xmm0
  movapd %xmm3,%xmm4
  movapd %xmm0,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm3
  subsd  %xmm4,%xmm2
  addsd  %xmm1,%xmm3
  addsd  %xmm6,%xmm2
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm0
  mulsd  %xmm3,%xmm4
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm2
  mulsd  %xmm2,%xmm3
  subsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm3
  addsd  %xmm6,%xmm0
  movapd %xmm3,%xmm4
  movapd %xmm0,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm3
  subsd  %xmm4,%xmm2
  addsd  %xmm1,%xmm3
  addsd  %xmm6,%xmm2
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm0
  mulsd  %xmm3,%xmm4
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm2
  mulsd  %xmm2,%xmm3
  subsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm3
  addsd  %xmm6,%xmm0
  movapd %xmm3,%xmm4
  movapd %xmm0,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm4,%xmm2
  addsd  %xmm6,%xmm2
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm2,%xmm3
  addsd  %xmm2,%xmm2
  mulsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm2
  subsd  %xmm4,%xmm3
  movapd %xmm2,%xmm4
  addsd  %xmm1,%xmm4
  addsd  %xmm6,%xmm3
  movapd %xmm4,%xmm0
  movapd %xmm3,%xmm2
  mulsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm2
  addsd  %xmm3,%xmm3
  mulsd  %xmm4,%xmm3
  subsd  %xmm0,%xmm2
  addsd  %xmm1,%xmm3
  addsd  %xmm6,%xmm2
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm6,%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm5
  ja     L2
  sqrtsd %xmm0,%xmm0
  jmp    1070 <tanh@plt>
L2:
  push   %rax
  call   <sqrt@plt>
  pop    %rdx
  jmp    1070 <tanh@plt>
```

assistant: ```c
double mandelbort(double cX, double cY) {
  double x = 0, y = 0;
  int i = 0;
  for (i = 0; i < 10; i++) {
    double x_ = x * x - y * y + cX;
    y = 2.0 * x * y + cY;
    x = x_;
  }
  double r = sqrt(x * x + y * y);
  return tanh(r);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L68:
  cmp    %rdx,%rsp
  je     L99
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L68
L99:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L31
  orq    $0x0,-0x8(%rsp,%rax,1)
L31:
  mov    %rsp,%r12
  lea    D4(%rip),%r13
  jmp    L104
L121:
  movslq %ebx,%rdx
  mov    %eax,(%r12,%rdx,4)
  add    $0x1,%ebx
L105:
  mov    -0x30(%rbp),%ecx
  cmp    %ebx,%ecx
  jle    L119
L104:
  lea    -0x2c(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   $0x1,%al
  je     L105
  jmp    L121
L119:
  cmp    $0x1,%ecx
  jle    L2
  mov    $0x0,%ebx
  lea    D10(%rip),%r13
L3:
  sub    %ebx,%ecx
  sub    $0x1,%ecx
  movslq %ecx,%rcx
  mov    (%r12,%rbx,4),%esi
  sub    (%r12,%rcx,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x30(%rbp),%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  mov    %edx,%eax
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jg     L3
L110:
  test   $0x1,%cl
  jne    L83
L28:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L2:
  mov    $0x2,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  jmp    L110
L83:
  cltq
  mov    (%r12,%rax,4),%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D10
data_type: string

tool: D4: %d

tool: D10: %d


assistant: ```c
int main() {
  int n;
  int i;
  int e;
  int z;
  scanf("%d", &n);
  int dps[n];
  do {
    scanf("%d", &e);
    if (e % 2 != 0) {
      dps[i] = e;
      i++;
    }
  } while (i < n);
  for (i = 0; i < n / 2; i++) {
    z = (n - i) - 1;
    printf("%d\n", dps[i] - dps[z]);
  }
  if (n % 2 != 0) {
    printf("%d\n", dps[n / 2]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D0(%rip),%r13
  lea    -0x30(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L5
L0:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L0
L5:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L104
L64:
  mov    %rsp,%rbx
  lea    -0x2c(%rbp),%r14
  nopw   0x0(%rax,%rax,1)
L86:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   $0x1,%al
  je     L106
  movslq %r12d,%rdx
  add    $0x1,%r12d
  mov    %eax,(%rbx,%rdx,4)
L106:
  mov    -0x30(%rbp),%ecx
  cmp    %r12d,%ecx
  jg     L86
  cmp    $0x1,%ecx
  jle    L32
  xor    %r13d,%r13d
  lea    D21(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L12:
  sub    %r13d,%ecx
  mov    (%rbx,%r13,4),%esi
  mov    %r12,%rdi
  add    $0x1,%r13
  sub    $0x1,%ecx
  movslq %ecx,%rcx
  sub    (%rbx,%rcx,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %r13d,%eax
  jg     L12
L70:
  and    $0x1,%ecx
  jne    L20
L46:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L20:
  cltq
  lea    D21(%rip),%rdi
  mov    (%rbx,%rax,4),%esi
  call   <printf@plt>
  jmp    L46
L104:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L64
L32:
  mov    %ecx,%eax
  mov    $0x2,%esi
  cltd
  idiv   %esi
  jmp    L70
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string
name: parse_data
arguments: tag: D21
data_type: string

tool: D0: %d

tool: D21: %d


assistant: ```c
int main() {
  int n;
  int i;
  int e;
  int z;
  scanf("%d", &n);
  int dps[n];
  do {
    scanf("%d", &e);
    if (e % 2 != 0) {
      dps[i] = e;
      i++;
    }
  } while (i < n);
  for (i = 0; i < n / 2; i++) {
    z = (n - i) - 1;
    printf("%d\n", dps[i] - dps[z]);
  }
  if (n % 2 != 0) {
    printf("%d\n", dps[n / 2]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D13(%rip),%r13
  lea    -0x30(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L129
L34:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L34
L129:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L25
L130:
  mov    %rsp,%rbx
  lea    -0x2c(%rbp),%r14
  nopw   0x0(%rax,%rax,1)
L94:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   $0x1,%al
  je     L23
  mov    -0x30(%rbp),%ecx
  movslq %r12d,%rdx
  add    $0x1,%r12d
  mov    %eax,(%rbx,%rdx,4)
  cmp    %ecx,%r12d
  jl     L94
L137:
  cmp    $0x1,%ecx
  jle    L8
  xor    %r13d,%r13d
  lea    D23(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L64:
  sub    %r13d,%ecx
  mov    (%rbx,%r13,4),%esi
  mov    %r12,%rdi
  add    $0x1,%r13
  sub    $0x1,%ecx
  movslq %ecx,%rcx
  sub    (%rbx,%rcx,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %r13d,%eax
  jg     L64
L127:
  and    $0x1,%ecx
  jne    L36
L100:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L138
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L23:
  mov    -0x30(%rbp),%ecx
  cmp    %r12d,%ecx
  jg     L94
  jmp    L137
L36:
  cltq
  lea    D23(%rip),%rdi
  mov    (%rbx,%rax,4),%esi
  call   <printf@plt>
  jmp    L100
L25:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L130
L8:
  mov    %ecx,%eax
  mov    $0x2,%esi
  cltd
  idiv   %esi
  jmp    L127
L138:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
type: string
name: unpack_data
arguments: tag: D23
type: string

tool: D13: %d

tool: D23: %d


assistant: ```c
int main() {
  int n;
  int i;
  int e;
  int z;
  scanf("%d", &n);
  int dps[n];
  do {
    scanf("%d", &e);
    if (e % 2 != 0) {
      dps[i] = e;
      i++;
    }
  } while (i < n);
  for (i = 0; i < n / 2; i++) {
    z = (n - i) - 1;
    printf("%d\n", dps[i] - dps[z]);
  }
  if (n % 2 != 0) {
    printf("%d\n", dps[n / 2]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getvlr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %edi,-0x434(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %rdx,-0x448(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x42c(%rbp)
  movl   $0x0,-0x41c(%rbp)
  jmp    L11
L53:
  mov    -0x448(%rbp),%rsi
  lea    -0x410(%rbp),%rcx
  lea    -0x448(%rbp),%rdx
  mov    -0x434(%rbp),%eax
  mov    %eax,%edi
  call   <getvlrelem@plt>
  cmp    $0xffffffff,%eax
  jne    L68
  mov    $0xffffffff,%eax
  jmp    L12
L68:
  addl   $0x1,-0x41c(%rbp)
  cmpl   $0x1,-0x41c(%rbp)
  jne    L35
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <read_blk2len@plt>
  mov    %rax,-0x418(%rbp)
  mov    -0x418(%rbp),%rax
  mov    %eax,-0x428(%rbp)
  movl   $0xf,-0x420(%rbp)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <read_blk2size@plt>
  sub    $0xf,%eax
  mov    %eax,-0x424(%rbp)
  jmp    L32
L35:
  movl   $0x7,-0x420(%rbp)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <read_blk2size@plt>
  sub    $0x7,%eax
  mov    %eax,-0x424(%rbp)
L32:
  mov    -0x424(%rbp),%eax
  cmp    -0x428(%rbp),%eax
  jle    L59
  mov    -0x428(%rbp),%eax
  mov    %eax,-0x424(%rbp)
L59:
  mov    -0x424(%rbp),%eax
  sub    %eax,-0x428(%rbp)
  mov    -0x420(%rbp),%eax
  cltq
  lea    -0x410(%rbp),%rdx
  lea    (%rdx,%rax,1),%rsi
  mov    -0x42c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x440(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x424(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memmove@plt>
  mov    -0x424(%rbp),%eax
  add    %eax,-0x42c(%rbp)
L11:
  mov    -0x448(%rbp),%rax
  test   %rax,%rax
  jne    L53
  mov    -0x418(%rbp),%rax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int getvlr(int fp, unsigned char *bf, long pos) {
  unsigned char datablk[1024];
  int offset, data_left, data_size, data_indx;
  long actual_len;
  int nblks;
  offset = 0;
  nblks = 0;
  while (pos != 0) {
    if ((getvlrelem(fp, pos, &pos, datablk)) == -1) {
      return (-1);
    } else {
      if (++nblks == 1) {
        data_left = actual_len = read_blk2len(datablk);
        data_indx = (7 + sizeof(long));
        data_size = read_blk2size(datablk) - (7 + sizeof(long));
      } else {
        data_indx = 7;
        data_size = read_blk2size(datablk) - 7;
      }
      if (data_size > data_left)
        data_size = data_left;
      data_left -= data_size;
      memmove(bf + offset, datablk + data_indx, data_size);
      offset += data_size;
    }
  }
  return (actual_len);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getvlr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L41
  mov    %edi,%r15d
  mov    %rdx,%rsi
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    0x20(%rsp),%r12
  jmp    L9
L5:
  mov    %r12,%rdi
  call   <read_blk2len@plt>
  mov    %rax,0x10(%rsp)
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <read_blk2size@plt>
  lea    -0xf(%rax),%ebx
  mov    $0xf,%esi
L16:
  cmp    %ebx,%ebp
  cmovle %ebp,%ebx
  sub    %ebx,%ebp
  movslq %esi,%rsi
  add    %r12,%rsi
  movslq %r13d,%rdi
  add    0x8(%rsp),%rdi
  mov    %ebx,%edx
  call   <memmove@plt>
  add    %ebx,%r13d
  mov    0x18(%rsp),%rsi
  test   %rsi,%rsi
  je     L41
L9:
  lea    0x18(%rsp),%rdx
  mov    %r12,%rcx
  mov    %r15d,%edi
  call   <getvlrelem@plt>
  cmp    $0xffffffff,%eax
  je     L54
  add    $0x1,%r14d
  cmp    $0x1,%r14d
  je     L5
  mov    %r12,%rdi
  call   <read_blk2size@plt>
  lea    -0x7(%rax),%ebx
  mov    $0x7,%esi
  jmp    L16
L41:
  mov    0x10(%rsp),%eax
L54:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getvlr(int fp, unsigned char *bf, long pos) {
  unsigned char datablk[1024];
  int offset, data_left, data_size, data_indx;
  long actual_len;
  int nblks;
  offset = 0;
  nblks = 0;
  while (pos != 0) {
    if ((getvlrelem(fp, pos, &pos, datablk)) == -1) {
      return (-1);
    } else {
      if (++nblks == 1) {
        data_left = actual_len = read_blk2len(datablk);
        data_indx = (7 + sizeof(long));
        data_size = read_blk2size(datablk) - (7 + sizeof(long));
      } else {
        data_indx = 7;
        data_size = read_blk2size(datablk) - 7;
      }
      if (data_size > data_left)
        data_size = data_left;
      data_left -= data_size;
      memmove(bf + offset, datablk + data_indx, data_size);
      offset += data_size;
    }
  }
  return (actual_len);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getvlr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L12
  lea    0x18(%rsp),%rax
  mov    %edi,%r14d
  mov    %rdx,%rsi
  xor    %r13d,%r13d
  mov    %rax,(%rsp)
  xor    %r12d,%r12d
  lea    0x20(%rsp),%rbp
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L52:
  call   <read_blk2size@plt>
  mov    $0x7,%esi
  lea    -0x7(%rax),%edx
L30:
  cmp    %edx,%ebx
  movslq %r12d,%rdi
  cmovle %ebx,%edx
  add    %rbp,%rsi
  add    0x8(%rsp),%rdi
  mov    %edx,%r15d
  sub    %edx,%ebx
  call   <memmove@plt>
  mov    0x18(%rsp),%rsi
  add    %r15d,%r12d
  test   %rsi,%rsi
  je     L12
L46:
  mov    (%rsp),%rdx
  mov    %rbp,%rcx
  mov    %r14d,%edi
  call   <getvlrelem@plt>
  cmp    $0xffffffff,%eax
  je     L55
  add    $0x1,%r13d
  mov    %rbp,%rdi
  cmp    $0x1,%r13d
  jne    L52
  call   <read_blk2len@plt>
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  mov    %eax,%ebx
  call   <read_blk2size@plt>
  mov    $0xf,%esi
  lea    -0xf(%rax),%edx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L12:
  mov    0x10(%rsp),%eax
L55:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getvlr(int fp, unsigned char *bf, long pos) {
  unsigned char datablk[1024];
  int offset, data_left, data_size, data_indx;
  long actual_len;
  int nblks;
  offset = 0;
  nblks = 0;
  while (pos != 0) {
    if ((getvlrelem(fp, pos, &pos, datablk)) == -1) {
      return (-1);
    } else {
      if (++nblks == 1) {
        data_left = actual_len = read_blk2len(datablk);
        data_indx = (7 + sizeof(long));
        data_size = read_blk2size(datablk) - (7 + sizeof(long));
      } else {
        data_indx = 7;
        data_size = read_blk2size(datablk) - 7;
      }
      if (data_size > data_left)
        data_size = data_left;
      data_left -= data_size;
      memmove(bf + offset, datablk + data_indx, data_size);
      offset += data_size;
    }
  }
  return (actual_len);
}
```