ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <doSystem@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <doSystem@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D5
type_infered: string

tool: D13: exit 1

tool: D5: ./does-not-exist

assistant: ```c
int main() {
  doSystem("exit 1");
  doSystem("./does-not-exist");
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <doSystem@plt>
  lea    D19(%rip),%rdi
  call   <doSystem@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string

tool: D18: exit 1

tool: D19: ./does-not-exist

assistant: ```c
int main() {
  doSystem("exit 1");
  doSystem("./does-not-exist");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <doSystem@plt>
  lea    D16(%rip),%rdi
  call   <doSystem@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D16
type: string

tool: D14: exit 1

tool: D16: ./does-not-exist

assistant: ```c
int main() {
  doSystem("exit 1");
  doSystem("./does-not-exist");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <doSystem@plt>
  lea    D14(%rip),%rdi
  call   <doSystem@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string
name: disassemble_data
arguments: label: D14
type_guessed: string

tool: D3: exit 1

tool: D14: ./does-not-exist

assistant: ```c
int main() {
  doSystem("exit 1");
  doSystem("./does-not-exist");
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<removeDuplicates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L48
  mov    -0x8(%rbp),%eax
  jmp    L13
L48:
  movl   $0x1,-0x4(%rbp)
  jmp    L42
L11:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L45
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
  jmp    L12
L45:
  nop
L12:
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  int i_idx = 0, ans_size = 0;
  if (numsSize == 0)
    return ans_size;
  for (int t_idx = 1; t_idx < numsSize; t_idx++) {
    if (nums[i_idx] == nums[t_idx]) {
      continue;
    } else {
      nums[++i_idx] = nums[t_idx];
      ans_size++;
    }
  }
  return ans_size + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<removeDuplicates>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L45
  cmp    $0x1,%esi
  jle    L21
  lea    0x4(%rdi),%rdx
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,4),%r10
  mov    $0x0,%eax
  mov    $0x0,%r8d
  jmp    L42
L36:
  add    $0x4,%rdx
  cmp    %r10,%rdx
  je     L47
L42:
  movslq %r8d,%rcx
  lea    0x0(,%rcx,4),%r9
  mov    (%rdx),%esi
  cmp    %esi,(%rdi,%rcx,4)
  je     L36
  add    $0x1,%r8d
  mov    %esi,0x4(%rdi,%r9,1)
  add    $0x1,%eax
  jmp    L36
L21:
  mov    $0x0,%eax
L47:
  add    $0x1,%eax
L45:
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  int i_idx = 0, ans_size = 0;
  if (numsSize == 0)
    return ans_size;
  for (int t_idx = 1; t_idx < numsSize; t_idx++) {
    if (nums[i_idx] == nums[t_idx]) {
      continue;
    } else {
      nums[++i_idx] = nums[t_idx];
      ans_size++;
    }
  }
  return ans_size + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<removeDuplicates>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L12
  cmp    $0x1,%esi
  jle    L19
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi),%rdx
  xor    %r8d,%r8d
  lea    0x8(%rdi,%rax,4),%r10
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L32:
  movslq %r8d,%rcx
  mov    (%rdx),%esi
  lea    0x0(,%rcx,4),%r9
  cmp    %esi,(%rdi,%rcx,4)
  je     L6
  mov    %esi,0x4(%rdi,%r9,1)
  mov    %eax,%r8d
  add    $0x1,%eax
L6:
  add    $0x4,%rdx
  cmp    %r10,%rdx
  jne    L32
  ret
  nop
L19:
  mov    $0x1,%eax
L12:
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  int i_idx = 0, ans_size = 0;
  if (numsSize == 0)
    return ans_size;
  for (int t_idx = 1; t_idx < numsSize; t_idx++) {
    if (nums[i_idx] == nums[t_idx]) {
      continue;
    } else {
      nums[++i_idx] = nums[t_idx];
      ans_size++;
    }
  }
  return ans_size + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<removeDuplicates>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L15
  cmp    $0x1,%esi
  jle    L3
  lea    -0x2(%rsi),%eax
  mov    (%rdi),%r8d
  lea    0x4(%rdi),%rdx
  xor    %esi,%esi
  lea    0x8(%rdi,%rax,4),%r9
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %eax,%rsi
  add    $0x4,%rdx
  mov    %ecx,(%rdi,%rsi,4)
  cmp    %rdx,%r9
  je     L12
L57:
  mov    %ecx,%r8d
  mov    %eax,%esi
L52:
  mov    (%rdx),%ecx
  lea    0x1(%rsi),%eax
  cmp    %r8d,%ecx
  jne    L1
  add    $0x4,%rdx
  mov    %esi,%eax
  cmp    %rdx,%r9
  jne    L57
L12:
  add    $0x1,%eax
  ret
  nopl   (%rax)
L3:
  mov    $0x1,%eax
L15:
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  int i_idx = 0, ans_size = 0;
  if (numsSize == 0)
    return ans_size;
  for (int t_idx = 1; t_idx < numsSize; t_idx++) {
    if (nums[i_idx] == nums[t_idx]) {
      continue;
    } else {
      nums[++i_idx] = nums[t_idx];
      ans_size++;
    }
  }
  return ans_size + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<make_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    %rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x2,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x4,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long make_mask(unsigned long x) {
  x = x | x >> 1;
  x = x | x >> 2;
  x = x | x >> 4;
  x = x | x >> 8;
  x = x | x >> 16;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<make_mask>:
  endbr64
  mov    %rdi,%rax
  shr    %rax
  or     %rdi,%rax
  mov    %rax,%rdx
  shr    $0x2,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x8,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long make_mask(unsigned long x) {
  x = x | x >> 1;
  x = x | x >> 2;
  x = x | x >> 4;
  x = x | x >> 8;
  x = x | x >> 16;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<make_mask>:
  endbr64
  mov    %rdi,%rax
  shr    %rax
  or     %rdi,%rax
  mov    %rax,%rdx
  shr    $0x2,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x8,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long make_mask(unsigned long x) {
  x = x | x >> 1;
  x = x | x >> 2;
  x = x | x >> 4;
  x = x | x >> 8;
  x = x | x >> 16;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_mask>:
  endbr64
  mov    %rdi,%rax
  shr    %rax
  or     %rdi,%rax
  mov    %rax,%rdx
  shr    $0x2,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x8,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long make_mask(unsigned long x) {
  x = x | x >> 1;
  x = x | x >> 2;
  x = x | x >> 4;
  x = x | x >> 8;
  x = x | x >> 16;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<misc_get_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L9
L10:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L24
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L9
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L9:
  leave
  ret
```

assistant: ```c
char *misc_get_ext(const char *path, int if_lower) {
  char *p, *ret, *r;
  if ((p = strrchr(path, '.')) == NULL)
    return NULL;
  p++;
  ret = r = malloc(strlen(p) + 1);
  if (!if_lower)
    return strcpy(r, p);
  while (*p) {
    *r++ = (char)tolower((int)*p);
    p++;
  }
  *r = '\0';
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<misc_get_ext>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  mov    $0x2e,%esi
  call   <strrchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L22
  lea    0x1(%rax),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  je     L32
  movzbl 0x1(%rbp),%edi
  mov    %rax,%rbp
  test   %dil,%dil
  je     L45
L9:
  movsbl %dil,%edi
  call   <tolower@plt>
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
L45:
  movb   $0x0,0x0(%rbp)
L29:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L29
L22:
  mov    %rax,%r12
  jmp    L29
```

assistant: ```c
char *misc_get_ext(const char *path, int if_lower) {
  char *p, *ret, *r;
  if ((p = strrchr(path, '.')) == NULL)
    return NULL;
  p++;
  ret = r = malloc(strlen(p) + 1);
  if (!if_lower)
    return strcpy(r, p);
  while (*p) {
    *r++ = (char)tolower((int)*p);
    p++;
  }
  *r = '\0';
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<misc_get_ext>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0x2e,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L39
  lea    0x1(%rax),%rbp
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  je     L25
  movsbl 0x1(%rbx),%edi
  mov    %rax,%rbx
  test   %dil,%dil
  je     L1
  nopl   0x0(%rax)
L24:
  call   <tolower@plt>
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L24
L1:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <strcpy@plt>
  nopl   (%rax)
L39:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *misc_get_ext(const char *path, int if_lower) {
  char *p, *ret, *r;
  if ((p = strrchr(path, '.')) == NULL)
    return NULL;
  p++;
  ret = r = malloc(strlen(p) + 1);
  if (!if_lower)
    return strcpy(r, p);
  while (*p) {
    *r++ = (char)tolower((int)*p);
    p++;
  }
  *r = '\0';
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<misc_get_ext>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0x2e,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L28
  lea    0x1(%rax),%rbp
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  je     L26
  movsbl 0x1(%rbx),%edi
  mov    %rax,%rbx
  test   %dil,%dil
  je     L14
  nopl   0x0(%rax)
L30:
  call   <tolower@plt>
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L30
L14:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <strcpy@plt>
  nopl   (%rax)
L28:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *misc_get_ext(const char *path, int if_lower) {
  char *p, *ret, *r;
  if ((p = strrchr(path, '.')) == NULL)
    return NULL;
  p++;
  ret = r = malloc(strlen(p) + 1);
  if (!if_lower)
    return strcpy(r, p);
  while (*p) {
    *r++ = (char)tolower((int)*p);
    p++;
  }
  *r = '\0';
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mystrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <mystrlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L15
L6:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mystrdup(char *s) {
  char *new = (char *)malloc(mystrlen(s) + 1);
  char *n = new;
  char *s1 = s;
  while (*s1 != '\0') {
    *n = *s1;
    n++;
    s1++;
  }
  *n = '\0';
  return new;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mystrdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mystrlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L26
  mov    %rax,%rdx
  sub    %rax,%rbx
  mov    %rbx,%rsi
L29:
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  movzbl (%rdx,%rsi,1),%ecx
  test   %cl,%cl
  jne    L29
L12:
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
L26:
  mov    %rax,%rdx
  jmp    L12
```

assistant: ```c
char *mystrdup(char *s) {
  char *new = (char *)malloc(mystrlen(s) + 1);
  char *n = new;
  char *s1 = s;
  while (*s1 != '\0') {
    *n = *s1;
    n++;
    s1++;
  }
  *n = '\0';
  return new;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mystrdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mystrlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%ecx
  mov    %rax,%rdx
  test   %cl,%cl
  je     L19
  sub    %rax,%rbx
  mov    %rbx,%rdi
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %cl,(%rdx)
  movzbl 0x1(%rdx,%rdi,1),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L7
L19:
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
```

assistant: ```c
char *mystrdup(char *s) {
  char *new = (char *)malloc(mystrlen(s) + 1);
  char *n = new;
  char *s1 = s;
  while (*s1 != '\0') {
    *n = *s1;
    n++;
    s1++;
  }
  *n = '\0';
  return new;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mystrdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mystrlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%ecx
  mov    %rax,%rdx
  test   %cl,%cl
  je     L14
  sub    %rax,%rbx
  mov    %rbx,%rdi
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %cl,(%rdx)
  movzbl 0x1(%rdx,%rdi,1),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L6
L14:
  movb   $0x0,(%rdx)
  pop    %rbx
  ret
```

assistant: ```c
char *mystrdup(char *s) {
  char *new = (char *)malloc(mystrlen(s) + 1);
  char *n = new;
  char *s1 = s;
  while (*s1 != '\0') {
    *n = *s1;
    n++;
    s1++;
  }
  *n = '\0';
  return new;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<u8_read_escape_sequence>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl 0x0(%rbp),%ebx
  movsbl %bl,%r12d
  mov    %r12d,%edi
  call   <octal_digit@plt>
  test   %rax,%rax
  je     L53
  mov    $0x0,%ebx
  lea    0x1d(%rsp),%r14
L147:
  add    $0x1,%rbx
  mov    %ebx,%r12d
  movzbl -0x1(%rbp,%rbx,1),%eax
  mov    %al,(%r14,%rbx,1)
  cmp    %rbx,%r13
  jbe    L74
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <octal_digit@plt>
  cmp    $0x2,%ebx
  jg     L74
  test   %rax,%rax
  jne    L147
L74:
  movslq %r12d,%r12
  movb   $0x0,0x1e(%rsp,%r12,1)
  lea    0x1e(%rsp),%rdi
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
L12:
  mov    0x8(%rsp),%rcx
  mov    %rax,(%rcx)
L7:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L161
  mov    %rbx,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  cmp    $0x75,%bl
  je     L25
  cmp    $0x78,%bl
  je     L94
  cmp    $0x55,%bl
  je     L109
  mov    %r12d,%edi
  call   <read_escape_control_char@plt>
  mov    $0x1,%ebx
  jmp    L12
L25:
  mov    $0x4,%r14d
  jmp    L107
L94:
  mov    $0x2,%r14d
L107:
  cmp    $0x1,%r13
  jbe    L127
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  lea    0x1c(%rsp),%r15
L159:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <hex_digit@plt>
  cmp    %r12d,%r14d
  jle    L167
  test   %rax,%rax
  je     L167
  add    $0x1,%rbx
  add    $0x1,%r12d
  movzbl -0x1(%rbp,%rbx,1),%eax
  mov    %al,(%r15,%rbx,1)
  cmp    %rbx,%r13
  jne    L159
  mov    %r13,%rbx
L167:
  test   %r12d,%r12d
  je     L124
  movslq %r12d,%r12
  movb   $0x0,0x1e(%rsp,%r12,1)
  lea    0x1e(%rsp),%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  jmp    L12
L109:
  mov    $0x8,%r14d
  jmp    L107
L127:
  mov    $0x0,%ebx
  jmp    L7
L124:
  mov    $0x0,%ebx
  jmp    L7
L161:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t u8_read_escape_sequence(const char *str, size_t ssz, u_int32_t *dest) {
  assert(ssz > 0);
  u_int32_t ch;
  char digs[10];
  int dno = 0, ndig;
  size_t i = 1;
  char c0 = str[0];
  if (octal_digit(c0)) {
    i = 0;
    do {
      digs[dno++] = str[i++];
    } while (i < ssz && octal_digit(str[i]) && dno < 3);
    digs[dno] = '\0';
    ch = strtol(digs, NULL, 8);
  } else if ((c0 == 'x' && (ndig = 2)) || (c0 == 'u' && (ndig = 4)) || (c0 == 'U' && (ndig = 8))) {
    while (i < ssz && hex_digit(str[i]) && dno < ndig) {
      digs[dno++] = str[i++];
    }
    if (dno == 0)
      return 0;
    digs[dno] = '\0';
    ch = strtol(digs, NULL, 16);
  } else {
    ch = (u_int32_t)read_escape_control_char(c0);
  }
  *dest = ch;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<u8_read_escape_sequence>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  movsbl (%r14),%r12d
  mov    %r12d,%edi
  call   <octal_digit@plt>
  test   %rax,%rax
  je     L59
  xor    %r12d,%r12d
  lea    0x1d(%rsp),%r13
L64:
  add    $0x1,%r12
  movzbl -0x1(%r14,%r12,1),%eax
  movslq %r12d,%rbx
  mov    %al,0x0(%r13,%r12,1)
  cmp    %r12,%rbp
  jbe    L32
  movsbl (%r14,%r12,1),%edi
  call   <octal_digit@plt>
  test   %rax,%rax
  je     L32
  cmp    $0x3,%r12
  jne    L64
  mov    $0x3,%ebx
L32:
  lea    0x1e(%rsp),%rdi
  mov    $0x8,%edx
  xor    %esi,%esi
  movb   $0x0,0x1e(%rsp,%rbx,1)
  call   <strtol@plt>
L114:
  mov    0x8(%rsp),%rcx
  mov    %rax,(%rcx)
L149:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x38,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L59:
  cmp    $0x75,%r12b
  je     L37
  cmp    $0x78,%r12b
  je     L7
  cmp    $0x55,%r12b
  je     L146
  mov    %r12d,%edi
  mov    $0x1,%r12d
  call   <read_escape_control_char@plt>
  jmp    L114
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    $0x2,%r12d
L172:
  cmp    $0x1,%rbp
  jbe    L163
  add    $0x1,%r12d
  mov    $0x1,%ebx
  xor    %r13d,%r13d
  movslq %r12d,%r12
  lea    0x1c(%rsp),%r15
  jmp    L199
  nopw   0x0(%rax,%rax,1)
L30:
  cmp    %r12,%rbx
  je     L69
  add    $0x1,%rbx
  movzbl -0x1(%r14,%rbx,1),%eax
  lea    -0x1(%rbx),%r13d
  mov    %al,(%r15,%rbx,1)
  cmp    %rbx,%rbp
  je     L182
L199:
  movsbl (%r14,%rbx,1),%edi
  call   <hex_digit@plt>
  test   %rax,%rax
  jne    L30
  test   %r13d,%r13d
  jne    L93
L163:
  xor    %r12d,%r12d
  jmp    L149
L146:
  mov    $0x8,%r12d
  jmp    L172
  nopl   0x0(%rax,%rax,1)
L37:
  mov    $0x4,%r12d
  jmp    L172
  nopl   0x0(%rax,%rax,1)
L182:
  mov    %rbp,%r12
L69:
  movslq %r13d,%r13
  lea    0x1e(%rsp),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  movb   $0x0,0x1e(%rsp,%r13,1)
  call   <strtol@plt>
  jmp    L114
L54:
  call   <__stack_chk_fail@plt>
L93:
  mov    %rbx,%r12
  jmp    L69
```

assistant: ```c
size_t u8_read_escape_sequence(const char *str, size_t ssz, u_int32_t *dest) {
  assert(ssz > 0);
  u_int32_t ch;
  char digs[10];
  int dno = 0, ndig;
  size_t i = 1;
  char c0 = str[0];
  if (octal_digit(c0)) {
    i = 0;
    do {
      digs[dno++] = str[i++];
    } while (i < ssz && octal_digit(str[i]) && dno < 3);
    digs[dno] = '\0';
    ch = strtol(digs, NULL, 8);
  } else if ((c0 == 'x' && (ndig = 2)) || (c0 == 'u' && (ndig = 4)) || (c0 == 'U' && (ndig = 8))) {
    while (i < ssz && hex_digit(str[i]) && dno < ndig) {
      digs[dno++] = str[i++];
    }
    if (dno == 0)
      return 0;
    digs[dno] = '\0';
    ch = strtol(digs, NULL, 16);
  } else {
    ch = (u_int32_t)read_escape_control_char(c0);
  }
  *dest = ch;
  return i;
}
```