ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  cmp    $0x1b,%eax
  jne    L6
  mov    $0x0,%edi
  call   <exit@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void key(unsigned char k, int x, int y) {
  switch (k) {
  case 27:
    exit(0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<key>:
  endbr64
  cmp    $0x1b,%dil
  je     L4
  ret
L4:
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void key(unsigned char k, int x, int y) {
  switch (k) {
  case 27:
    exit(0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<key>:
  endbr64
  cmp    $0x1b,%dil
  je     L7
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %edi,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void key(unsigned char k, int x, int y) {
  switch (k) {
  case 27:
    exit(0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<key>:
  endbr64
  cmp    $0x1b,%dil
  je     L0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %edi,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void key(unsigned char k, int x, int y) {
  switch (k) {
  case 27:
    exit(0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eb_diff_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  imul   $0xf4240,%eax,%eax
  cltq
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%eax
  imul   $0xf4240,%eax,%eax
  cltq
  add    %rax,%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x8(%rbp),%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x12,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xf4240,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  shr    $0x3f,%rax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int eb_diff_time(const struct timeval *tact, const struct timeval *tlast, struct timeval *tdiff) {
  long diff;
  diff = (tact->tv_usec + 1000000 * tact->tv_sec) - (tlast->tv_usec + 1000000 * tlast->tv_sec);
  tdiff->tv_sec = diff / 1000000;
  tdiff->tv_usec = diff % 1000000;
  return (diff < 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eb_diff_time>:
  endbr64
  mov    %rdx,%r8
  imul   $0xf4240,0x8(%rdi),%ecx
  movslq %ecx,%rcx
  add    (%rdi),%rcx
  imul   $0xf4240,0x8(%rsi),%eax
  cltq
  add    (%rsi),%rax
  sub    %rax,%rcx
  movabs $0x431bde82d7b634db,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0x12,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %edx,0x8(%r8)
  imul   $0xf4240,%rdx,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,(%r8)
  shr    $0x3f,%rcx
  mov    %rcx,%rax
  ret
```

assistant: ```c
int eb_diff_time(const struct timeval *tact, const struct timeval *tlast, struct timeval *tdiff) {
  long diff;
  diff = (tact->tv_usec + 1000000 * tact->tv_sec) - (tlast->tv_usec + 1000000 * tlast->tv_sec);
  tdiff->tv_sec = diff / 1000000;
  tdiff->tv_usec = diff % 1000000;
  return (diff < 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eb_diff_time>:
  endbr64
  imul   $0xf4240,0x8(%rdi),%ecx
  mov    %rdx,%r8
  movabs $0x431bde82d7b634db,%rdx
  imul   $0xf4240,0x8(%rsi),%eax
  movslq %ecx,%rcx
  add    (%rdi),%rcx
  cltq
  add    (%rsi),%rax
  sub    %rax,%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  shr    $0x3f,%rcx
  mov    %edx,0x8(%r8)
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rax
  mov    %rax,(%r8)
  mov    %rcx,%rax
  ret
```

assistant: ```c
int eb_diff_time(const struct timeval *tact, const struct timeval *tlast, struct timeval *tdiff) {
  long diff;
  diff = (tact->tv_usec + 1000000 * tact->tv_sec) - (tlast->tv_usec + 1000000 * tlast->tv_sec);
  tdiff->tv_sec = diff / 1000000;
  tdiff->tv_usec = diff % 1000000;
  return (diff < 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eb_diff_time>:
  endbr64
  imul   $0xf4240,0x8(%rdi),%ecx
  mov    %rdx,%r8
  movabs $0x431bde82d7b634db,%rdx
  imul   $0xf4240,0x8(%rsi),%eax
  movslq %ecx,%rcx
  add    (%rdi),%rcx
  cltq
  add    (%rsi),%rax
  sub    %rax,%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  shr    $0x3f,%rcx
  mov    %edx,0x8(%r8)
  imul   $0xf4240,%rdx,%rdx
  sub    %rdx,%rax
  mov    %rax,(%r8)
  mov    %rcx,%rax
  ret
```

assistant: ```c
int eb_diff_time(const struct timeval *tact, const struct timeval *tlast, struct timeval *tdiff) {
  long diff;
  diff = (tact->tv_usec + 1000000 * tact->tv_sec) - (tlast->tv_usec + 1000000 * tlast->tv_sec);
  tdiff->tv_sec = diff / 1000000;
  tdiff->tv_usec = diff % 1000000;
  return (diff < 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Sys_FileStat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,%edi
  call   <errnoThrow@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned Sys_FileStat(const char *name) {
  struct stat s;
  errnoThrow(stat(name, &s));
  return s.st_mode;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Sys_FileStat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edi
  call   <errnoThrow@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned Sys_FileStat(const char *name) {
  struct stat s;
  errnoThrow(stat(name, &s));
  return s.st_mode;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Sys_FileStat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edi
  call   <errnoThrow@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned Sys_FileStat(const char *name) {
  struct stat s;
  errnoThrow(stat(name, &s));
  return s.st_mode;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Sys_FileStat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edi
  call   <errnoThrow@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned Sys_FileStat(const char *name) {
  struct stat s;
  errnoThrow(stat(name, &s));
  return s.st_mode;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L2:
  addl   $0x1,-0xc(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L17
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  jmp    L17
L29:
  subl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L73
  cmpl   $0x0,-0x8(%rbp)
  jns    L29
  jmp    L73
L55:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L73:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L55
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim(char *str) {
  int i = 0;
  int j = strlen(str) - 1;
  int k = 0;
  while (isspace(str[i]) && str[i] != '\0')
    i++;
  while (isspace(str[j]) && j >= 0)
    j--;
  while (i <= j)
    str[k++] = str[i++];
  str[k] = '\0';
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  mov    $0x0,%ebp
  jmp    L62
L13:
  mov    %rax,%rbp
L62:
  mov    %ebp,%r13d
  movsbl (%r12,%rbp,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L52
  lea    0x1(%rbp),%rax
  cmpb   $0x0,(%r12,%rbp,1)
  jne    L13
L52:
  movslq %ebx,%rbx
L26:
  mov    %ebx,%r14d
  movsbl (%r12,%rbx,1),%edi
  call   <isspace@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  not    %eax
  shr    $0x1f,%eax
  test   %rdx,%rdx
  setne  %dl
  mov    %rbx,%rcx
  sub    $0x1,%rbx
  test   %al,%dl
  jne    L26
  cmp    %r14d,%r13d
  jg     L3
  mov    %r12,%rax
  sub    %ebp,%ecx
  mov    %ecx,%edx
  lea    0x1(%r12,%rdx,1),%rsi
  movslq %r13d,%r13
L10:
  movzbl (%rax,%r13,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L10
  add    $0x1,%ecx
L36:
  movslq %ecx,%rcx
  movb   $0x0,(%r12,%rcx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  mov    $0x0,%ecx
  jmp    L36
```

assistant: ```c
char *trim(char *str) {
  int i = 0;
  int j = strlen(str) - 1;
  int k = 0;
  while (isspace(str[i]) && str[i] != '\0')
    i++;
  while (isspace(str[j]) && j >= 0)
    j--;
  while (i <= j)
    str[k++] = str[i++];
  str[k] = '\0';
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L44:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%r12,%rbx,1)
  je     L46
L26:
  movsbl (%r12,%rbx,1),%edi
  mov    %ebx,%r14d
  movslq %ebx,%r13
  call   <isspace@plt>
  test   %rax,%rax
  jne    L44
L46:
  movslq %ebp,%rbx
  nopl   0x0(%rax)
L9:
  movsbl (%r12,%rbx,1),%edi
  mov    %ebx,%ebp
  call   <isspace@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  not    %eax
  shr    $0x1f,%eax
  test   %r8,%r8
  setne  %dl
  sub    $0x1,%rbx
  test   %al,%dl
  jne    L9
  cmp    %ebp,%r13d
  jg     L22
  sub    %r14d,%ebp
  mov    %r12,%rax
  mov    %ebp,%edx
  lea    0x1(%r12,%rdx,1),%rcx
  xchg   %ax,%ax
L3:
  movzbl (%rax,%r13,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L3
  add    $0x1,%ebp
  mov    %r12,%rax
  movslq %ebp,%rbp
  add    %r12,%rbp
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r12,%rbp
  mov    %r12,%rax
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *trim(char *str) {
  int i = 0;
  int j = strlen(str) - 1;
  int k = 0;
  while (isspace(str[i]) && str[i] != '\0')
    i++;
  while (isspace(str[j]) && j >= 0)
    j--;
  while (i <= j)
    str[k++] = str[i++];
  str[k] = '\0';
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rsi
  lea    -0x12(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rcx
  lea    D13(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D28
type_guessed: string

tool: D22: 0123456789

tool: D13: %s

tool: D28: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char b[10];
  size_t len = atoi(argv[1]);
  (void)snprintf(b, len, "%s", "0123456789");
  (void)printf("%s\n", b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %rax,%rsi
  lea    0xe(%rsp),%rbx
  lea    D4(%rip),%rcx
  lea    D12(%rip),%rdx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D11
type: string

tool: D4: 0123456789

tool: D12: %s

tool: D11: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char b[10];
  size_t len = atoi(argv[1]);
  (void)snprintf(b, len, "%s", "0123456789");
  (void)printf("%s\n", b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <atoi@plt>
  mov    %rbp,%rdi
  lea    D29(%rip),%rcx
  lea    D26(%rip),%rdx
  mov    %rax,%rsi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D29
data_type: string
name: unpack_data
arguments: data_label: D26
data_type: string
name: unpack_data
arguments: data_label: D4
data_type: string

tool: D29: 0123456789

tool: D26: %s

tool: D4: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char b[10];
  size_t len = atoi(argv[1]);
  (void)snprintf(b, len, "%s", "0123456789");
  (void)printf("%s\n", b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <atoi@plt>
  mov    %rbp,%rdi
  lea    D6(%rip),%rcx
  lea    D28(%rip),%rdx
  mov    %rax,%rsi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string
name: parse_data
arguments: label: D28
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string

tool: D6: 0123456789

tool: D28: %s

tool: D9: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char b[10];
  size_t len = atoi(argv[1]);
  (void)snprintf(b, len, "%s", "0123456789");
  (void)printf("%s\n", b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ShowUpperTriangMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L22
L35:
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L14:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L14
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L44
L45:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L45
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string
name: read_data
arguments: data_label: D10
type_infered: string

tool: D9: Upper triang matrix:

tool: D15:          

tool: D10: %.6f 

assistant: ```c
void ShowUpperTriangMatrix(double *values, int squareSize) {
  int i, j, index;
  index = 0;
  printf("Upper triang matrix:\n");
  for (i = 0; i < squareSize; i++) {
    for (j = 0; j < i; j++)
      printf("         ");
    for (j = i + 1; j < squareSize; j++) {
      printf("%.6f ", values[index]);
      index++;
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<ShowUpperTriangMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %rdi,0x10(%rsp)
  mov    %esi,%ebx
  mov    %esi,0xc(%rsp)
  lea    D23(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L45
  mov    %ebx,%eax
  sub    $0x2,%eax
  mov    %eax,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    $0x0,%ebp
  lea    0x8(%r15),%rax
  mov    %rax,0x18(%rsp)
  lea    D25(%rip),%r14
  lea    D21(%rip),%r13
  jmp    L66
L50:
  mov    $0x0,%ebx
L6:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L6
L43:
  subl   $0x1,0x8(%rsp)
  mov    %r15d,%ebp
L66:
  lea    0x1(%rbp),%r15d
  cmp    %r15d,0xc(%rsp)
  je     L67
  movslq 0x4(%rsp),%rdx
  mov    0x10(%rsp),%rax
  lea    (%rax,%rdx,8),%rbx
  mov    0x8(%rsp),%eax
  add    %rdx,%rax
  mov    0x18(%rsp),%rcx
  lea    (%rcx,%rax,8),%r12
L21:
  movsd  (%rbx),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L21
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%esi
  lea    0x1(%rax,%rsi,1),%eax
  mov    %eax,0x4(%rsp)
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %r15d,%r15d
  jg     L50
  jmp    L43
L67:
  mov    $0xa,%edi
  call   <putchar@plt>
L45:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D23
datatype: string
name: retrieve_data
arguments: tag: D25
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string

tool: D23: Upper triang matrix:

tool: D25: %.6f 

tool: D21:          

assistant: ```c
void ShowUpperTriangMatrix(double *values, int squareSize) {
  int i, j, index;
  index = 0;
  printf("Upper triang matrix:\n");
  for (i = 0; i < squareSize; i++) {
    for (j = 0; j < i; j++)
      printf("         ");
    for (j = i + 1; j < squareSize; j++) {
      printf("%.6f ", values[index]);
      index++;
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<ShowUpperTriangMatrix>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  lea    D20(%rip),%rdi
  mov    %esi,0xc(%rsp)
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L2
  lea    0x8(%r15),%rax
  lea    -0x2(%rbx),%r14d
  xor    %ebx,%ebx
  movl   $0x0,0x4(%rsp)
  mov    %rax,0x18(%rsp)
  lea    0x1(%rbx),%eax
  lea    D21(%rip),%r13
  mov    %eax,0x8(%rsp)
  lea    D0(%rip),%r12
  cmp    %eax,0xc(%rsp)
  je     L24
  nopw   0x0(%rax,%rax,1)
L46:
  movslq 0x4(%rsp),%rcx
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rsi
  lea    (%rax,%rcx,8),%r15
  mov    %r14d,%eax
  add    %rcx,%rax
  lea    (%rsi,%rax,8),%rbp
  nopl   (%rax)
L38:
  movsd  (%r15),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x8,%r15
  call   <printf@plt>
  cmp    %rbp,%r15
  jne    L38
  mov    0x4(%rsp),%eax
  mov    $0xa,%edi
  xor    %ebp,%ebp
  lea    0x1(%rax,%r14,1),%eax
  mov    %eax,0x4(%rsp)
  call   <putchar@plt>
  nopl   0x0(%rax)
L30:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%eax
  add    $0x1,%ebp
  cmp    %eax,%ebx
  jne    L30
  mov    0x8(%rsp),%ebx
  sub    $0x1,%r14d
  lea    0x1(%rbx),%eax
  mov    %eax,0x8(%rsp)
  cmp    %eax,0xc(%rsp)
  jne    L46
L24:
  mov    $0xa,%edi
  call   <putchar@plt>
L2:
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D21
data_type: string
name: retrieve_data
arguments: label: D0
data_type: string

tool: D20: Upper triang matrix:

tool: D21: %.6f 

tool: D0:          

assistant: ```c
void ShowUpperTriangMatrix(double *values, int squareSize) {
  int i, j, index;
  index = 0;
  printf("Upper triang matrix:\n");
  for (i = 0; i < squareSize; i++) {
    for (j = 0; j < i; j++)
      printf("         ");
    for (j = i + 1; j < squareSize; j++) {
      printf("%.6f ", values[index]);
      index++;
    }
    printf("\n");
  }
  printf("\n");
}
```