ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <test_locking_reader@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L20
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
L20:
  lea    0x4(%rsp),%rdi
  call   <test_locking_writer@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L9
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  pthread_rwlock_t rwlock;
  int result = 1;
  if (test_locking_reader(&rwlock) == 0 && test_locking_writer(&rwlock) == 0)
    result = 0;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <test_locking_reader@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L12
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbp
  ret
L12:
  mov    %rbp,%rdi
  call   <test_locking_writer@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L13
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  pthread_rwlock_t rwlock;
  int result = 1;
  if (test_locking_reader(&rwlock) == 0 && test_locking_writer(&rwlock) == 0)
    result = 0;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <test_locking_reader@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L24
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbp
  ret
L24:
  mov    %rbp,%rdi
  call   <test_locking_writer@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L25
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  pthread_rwlock_t rwlock;
  int result = 1;
  if (test_locking_reader(&rwlock) == 0 && test_locking_writer(&rwlock) == 0)
    result = 0;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: cl_d3d11.h standalone test PASSED.


assistant: ```c
int main(void) {
  printf("cl_d3d11.h standalone test PASSED.\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: cl_d3d11.h standalone test PASSED.


assistant: ```c
int main(void) {
  printf("cl_d3d11.h standalone test PASSED.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: cl_d3d11.h standalone test PASSED.


assistant: ```c
int main(void) {
  printf("cl_d3d11.h standalone test PASSED.\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: cl_d3d11.h standalone test PASSED.


assistant: ```c
int main(void) {
  printf("cl_d3d11.h standalone test PASSED.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  add    $0x7296,%dx
  test   $0x8,%dl
  je     L21
  test   $0x1,%dl
  je     L18
  mov    $0x0,%eax
  mov    %dl,%al
  mov    %dh,%ah
  jmp    L28
L18:
  movzwl %dx,%edi
  mov    %edx,%r8d
  and    $0xe,%r8d
  or     $0x1,%r8d
  mov    $0x10,%ecx
  sub    %r8d,%ecx
  mov    %edi,%eax
  sar    %cl,%eax
  mov    %r8d,%ecx
  shl    %cl,%edi
  or     %edi,%eax
  shl    $0x3,%eax
  movzbl %al,%eax
  or     %edx,%eax
  jmp    L28
L21:
  movzwl %dx,%edi
  mov    %edx,%r8d
  and    $0xe,%r8d
  or     $0x1,%r8d
  mov    $0x10,%ecx
  sub    %r8d,%ecx
  mov    %edi,%eax
  sar    %cl,%eax
  mov    %r8d,%ecx
  shl    %cl,%edi
  or     %edi,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %edx,%eax
L28:
  imul   $0xe429,%ax,%dx
  shl    $0x9,%edx
  movzwl %ax,%eax
  imul   $0x12c8e429,%rax,%rax
  shr    $0x7,%rax
  or     %edx,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if (state[0UL] & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
        } else {
          state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned short)63) << 4UL;
        }
      } else {
        state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - ((state[0UL] & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 3UL;
      }
    } else {
      state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - ((state[0UL] & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
    }
    output[0UL] = (state[0UL] * 315155497UL << (unsigned short)9) | (state[0UL] * 315155497UL >> (unsigned short)7);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  movzwl %ax,%edi
  test   $0x8,%al
  je     L0
  test   $0x1,%al
  je     L22
L6:
  imul   $0xe429,%ax,%dx
  movzwl %ax,%eax
  imul   $0x12c8e429,%rax,%rax
  shl    $0x9,%edx
  shr    $0x7,%rax
  or     %edx,%eax
  mov    %ax,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %eax,%r8d
  mov    $0x10,%ecx
  mov    %edi,%edx
  and    $0xe,%r8d
  or     $0x1,%r8d
  sub    %r8d,%ecx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%edi
  or     %edi,%edx
  shl    $0x4,%edx
  and    $0x1f0,%dx
  or     %edx,%eax
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %eax,%r8d
  mov    $0x10,%ecx
  mov    %edi,%edx
  and    $0xe,%r8d
  or     $0x1,%r8d
  sub    %r8d,%ecx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%edi
  or     %edi,%edx
  shl    $0x3,%edx
  movzbl %dl,%edx
  or     %edx,%eax
  jmp    L6
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if (state[0UL] & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
        } else {
          state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned short)63) << 4UL;
        }
      } else {
        state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - ((state[0UL] & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 3UL;
      }
    } else {
      state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - ((state[0UL] & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
    }
    output[0UL] = (state[0UL] * 315155497UL << (unsigned short)9) | (state[0UL] * 315155497UL >> (unsigned short)7);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  movzwl %ax,%edi
  test   $0x8,%al
  je     L5
  test   $0x1,%al
  je     L38
L17:
  imul   $0xe429,%ax,%dx
  movzwl %ax,%eax
  imul   $0x12c8e429,%rax,%rax
  shl    $0x9,%edx
  shr    $0x7,%rax
  or     %edx,%eax
  mov    %ax,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %eax,%r8d
  mov    $0x10,%ecx
  mov    %edi,%edx
  and    $0xe,%r8d
  or     $0x1,%r8d
  sub    %r8d,%ecx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%edi
  or     %edi,%edx
  shl    $0x4,%edx
  and    $0x1f0,%dx
  or     %edx,%eax
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %eax,%r8d
  mov    $0x10,%ecx
  mov    %edi,%edx
  and    $0xe,%r8d
  or     $0x1,%r8d
  sub    %r8d,%ecx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%edi
  or     %edi,%edx
  shl    $0x3,%edx
  movzbl %dl,%edx
  or     %edx,%eax
  jmp    L17
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if (state[0UL] & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
        } else {
          state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned short)63) << 4UL;
        }
      } else {
        state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - ((state[0UL] & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 3UL;
      }
    } else {
      state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - ((state[0UL] & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
    }
    output[0UL] = (state[0UL] * 315155497UL << (unsigned short)9) | (state[0UL] * 315155497UL >> (unsigned short)7);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x3,-0xc(%rbp)
  jmp    L27
L13:
  movl   $0x3,-0x8(%rbp)
  jmp    L14
L36:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <do_exp@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x7,-0x8(%rbp)
  jle    L36
  addl   $0x1,-0xc(%rbp)
L27:
  cmpl   $0x7,-0xc(%rbp)
  jle    L13
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D1
type_infered: string

tool: D2: Fast exponentiation test

tool: D1: %lld ^ %lld = %lld.


assistant: ```c
int main(int argc, char **argv) {
  printf("Fast exponentiation test\n");
  uint64_t base;
  for (base = 3; base <= 7; base++) {
    uint64_t exp;
    for (exp = 3; exp <= 7; exp++) {
      uint64_t result = do_exp(base, exp);
      printf("%lld ^ %lld = %lld.\n", base, exp, result);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x3,%ebp
  lea    D6(%rip),%r12
L12:
  mov    $0x3,%ebx
L6:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <do_exp@plt>
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L6
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L12
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D10: Fast exponentiation test

tool: D6: %lld ^ %lld = %lld.


assistant: ```c
int main(int argc, char **argv) {
  printf("Fast exponentiation test\n");
  uint64_t base;
  for (base = 3; base <= 7; base++) {
    uint64_t exp;
    for (exp = 3; exp <= 7; exp++) {
      uint64_t result = do_exp(base, exp);
      printf("%lld ^ %lld = %lld.\n", base, exp, result);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%rdi
  lea    D19(%rip),%r12
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  call   <puts@plt>
L1:
  mov    $0x3,%ebx
L15:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <do_exp@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  add    $0x1,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x8,%ebx
  jne    L15
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D19
type_infered: string

tool: D18: Fast exponentiation test

tool: D19: %lld ^ %lld = %lld.


assistant: ```c
int main(int argc, char **argv) {
  printf("Fast exponentiation test\n");
  uint64_t base;
  for (base = 3; base <= 7; base++) {
    uint64_t exp;
    for (exp = 3; exp <= 7; exp++) {
      uint64_t result = do_exp(base, exp);
      printf("%lld ^ %lld = %lld.\n", base, exp, result);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  lea    D14(%rip),%r12
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  call   <puts@plt>
L7:
  mov    $0x3,%ebx
L19:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <do_exp@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  add    $0x1,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x8,%ebx
  jne    L19
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: D16: Fast exponentiation test

tool: D14: %lld ^ %lld = %lld.


assistant: ```c
int main(int argc, char **argv) {
  printf("Fast exponentiation test\n");
  uint64_t base;
  for (base = 3; base <= 7; base++) {
    uint64_t exp;
    for (exp = 3; exp <= 7; exp++) {
      uint64_t result = do_exp(base, exp);
      printf("%lld ^ %lld = %lld.\n", base, exp, result);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gettimeofday_resolution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <get_seconds_gettimeofday@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  nop
L10:
  mov    $0x0,%eax
  call   <get_seconds_gettimeofday@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jp     L12
  movsd  -0x8(%rbp),%xmm0
  ucomisd -0x10(%rbp),%xmm0
  je     L10
L12:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double gettimeofday_resolution() {
  double t0, t1;
  t0 = get_seconds_gettimeofday();
  while ((t1 = get_seconds_gettimeofday()) == t0)
    ;
  assert(t1 > t0);
  return t1 - t0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gettimeofday_resolution>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x0,%eax
  call   <get_seconds_gettimeofday@plt>
  movsd  %xmm0,(%rsp)
L6:
  mov    $0x0,%eax
  call   <get_seconds_gettimeofday@plt>
  movsd  %xmm0,0x8(%rsp)
  movsd  (%rsp),%xmm2
  ucomisd %xmm0,%xmm2
  jp     L15
  je     L6
L15:
  movsd  0x8(%rsp),%xmm3
  comisd (%rsp),%xmm3
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  subsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double gettimeofday_resolution() {
  double t0, t1;
  t0 = get_seconds_gettimeofday();
  while ((t1 = get_seconds_gettimeofday()) == t0)
    ;
  assert(t1 > t0);
  return t1 - t0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gettimeofday_resolution>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <get_seconds_gettimeofday@plt>
  movsd  %xmm0,(%rsp)
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  call   <get_seconds_gettimeofday@plt>
  movsd  (%rsp),%xmm1
  ucomisd %xmm0,%xmm1
  jp     L3
  je     L12
L3:
  comisd (%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  subsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double gettimeofday_resolution() {
  double t0, t1;
  t0 = get_seconds_gettimeofday();
  while ((t1 = get_seconds_gettimeofday()) == t0)
    ;
  assert(t1 > t0);
  return t1 - t0;
}
```
user: What is the c source code of the assembly code below:

```asm
<gettimeofday_resolution>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <get_seconds_gettimeofday@plt>
  movsd  %xmm0,(%rsp)
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  call   <get_seconds_gettimeofday@plt>
  movsd  (%rsp),%xmm1
  ucomisd %xmm0,%xmm1
  jp     L17
  je     L14
L17:
  comisd (%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  subsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double gettimeofday_resolution() {
  double t0, t1;
  t0 = get_seconds_gettimeofday();
  while ((t1 = get_seconds_gettimeofday()) == t0)
    ;
  assert(t1 > t0);
  return t1 - t0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x28,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D11
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D11: sizeof(short) = %zu


tool: D17: sizeof(int) = %zu


tool: D16: sizeof(float[10]) = %zu


tool: D15: sizeof(struct{char c; int n;}) = %zu


assistant: ```c
int main(void) {
  printf("sizeof(short) = %zu\n", sizeof(short));
  printf("sizeof(int) = %zu\n", sizeof(int));
  printf("sizeof(float[10]) = %zu\n", sizeof(float[10]));
  printf("sizeof(struct{char c; int n;}) = %zu\n", sizeof(struct {
           char c;
           int n;
         }));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x28,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D34
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: string
name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D11
type_infered: string

tool: D34: sizeof(short) = %zu


tool: D23: sizeof(int) = %zu


tool: D19: sizeof(float[10]) = %zu


tool: D11: sizeof(struct{char c; int n;}) = %zu


assistant: ```c
int main(void) {
  printf("sizeof(short) = %zu\n", sizeof(short));
  printf("sizeof(int) = %zu\n", sizeof(int));
  printf("sizeof(float[10]) = %zu\n", sizeof(float[10]));
  printf("sizeof(struct{char c; int n;}) = %zu\n", sizeof(struct {
           char c;
           int n;
         }));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x28,%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D31
type_infered: string
name: disassemble_data
arguments: label: D29
type_infered: string
name: disassemble_data
arguments: label: D23
type_infered: string
name: disassemble_data
arguments: label: D36
type_infered: string

tool: D31: sizeof(short) = %zu


tool: D29: sizeof(int) = %zu


tool: D23: sizeof(float[10]) = %zu


tool: D36: sizeof(struct{char c; int n;}) = %zu


assistant: ```c
int main(void) {
  printf("sizeof(short) = %zu\n", sizeof(short));
  printf("sizeof(int) = %zu\n", sizeof(int));
  printf("sizeof(float[10]) = %zu\n", sizeof(float[10]));
  printf("sizeof(struct{char c; int n;}) = %zu\n", sizeof(struct {
           char c;
           int n;
         }));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x28,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D39
type_infered: string
name: disassemble_data
arguments: data_tag: D35
type_infered: string
name: disassemble_data
arguments: data_tag: D20
type_infered: string
name: disassemble_data
arguments: data_tag: D24
type_infered: string

tool: D39: sizeof(short) = %zu


tool: D35: sizeof(int) = %zu


tool: D20: sizeof(float[10]) = %zu


tool: D24: sizeof(struct{char c; int n;}) = %zu


assistant: ```c
int main(void) {
  printf("sizeof(short) = %zu\n", sizeof(short));
  printf("sizeof(int) = %zu\n", sizeof(int));
  printf("sizeof(float[10]) = %zu\n", sizeof(float[10]));
  printf("sizeof(struct{char c; int n;}) = %zu\n", sizeof(struct {
           char c;
           int n;
         }));
  return 0;
}
```