ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_region_name_BW>:
  endbr64
  cmp    $0xb,%edi
  ja     L8
  mov    %edi,%edi
  lea    D91(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D40(%rip),%rax
  ret
  lea    D98(%rip),%rax
  ret
  lea    D23(%rip),%rax
  ret
  lea    D49(%rip),%rax
  ret
  lea    D96(%rip),%rax
  ret
  lea    D25(%rip),%rax
  ret
  lea    D47(%rip),%rax
  ret
  lea    D14(%rip),%rax
  ret
L8:
  mov    $0x0,%eax
  ret
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D40
datatype: string
name: unpack_data
arguments: data_tag: D98
datatype: string
name: unpack_data
arguments: data_tag: D23
datatype: string
name: unpack_data
arguments: data_tag: D49
datatype: string
name: unpack_data
arguments: data_tag: D96
datatype: string
name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D47
datatype: string
name: unpack_data
arguments: data_tag: D14
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D40: Ghanzi

tool: D98: Kgalagadi

tool: D23: Kgatleng

tool: D49: Kweneng

tool: D96: North-East

tool: D25: South-East

tool: D47: Southern

tool: D14: North-West

tool: D1: Central

assistant: ```c
const char *get_region_name_BW(int region_code) {
  switch (region_code) {
  case 1:
    return "Central";
  case 3:
    return "Ghanzi";
  case 4:
    return "Kgalagadi";
  case 5:
    return "Kgatleng";
  case 6:
    return "Kweneng";
  case 8:
    return "North-East";
  case 9:
    return "South-East";
  case 10:
    return "Southern";
  case 11:
    return "North-West";
  default:
    return NULL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_region_name_BW>:
  endbr64
  cmp    $0xb,%edi
  ja     L9
  lea    D65(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D24(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D19(%rip),%rax
  ret
  lea    D97(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D60(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D56(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D86(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D3(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D57(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D88(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
type: string
name: disassemble_data
arguments: data_tag: D19
type: string
name: disassemble_data
arguments: data_tag: D97
type: string
name: disassemble_data
arguments: data_tag: D60
type: string
name: disassemble_data
arguments: data_tag: D56
type: string
name: disassemble_data
arguments: data_tag: D86
type: string
name: disassemble_data
arguments: data_tag: D3
type: string
name: disassemble_data
arguments: data_tag: D57
type: string
name: disassemble_data
arguments: data_tag: D88
type: string

tool: D24: North-West

tool: D19: Central

tool: D97: Kgalagadi

tool: D60: Kgatleng

tool: D56: Kweneng

tool: D86: North-East

tool: D3: South-East

tool: D57: Southern

tool: D88: Ghanzi

assistant: ```c
const char *get_region_name_BW(int region_code) {
  switch (region_code) {
  case 1:
    return "Central";
  case 3:
    return "Ghanzi";
  case 4:
    return "Kgalagadi";
  case 5:
    return "Kgatleng";
  case 6:
    return "Kweneng";
  case 8:
    return "North-East";
  case 9:
    return "South-East";
  case 10:
    return "Southern";
  case 11:
    return "North-West";
  default:
    return NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_region_name_BW>:
  endbr64
  cmp    $0xb,%edi
  ja     L4
  lea    D96(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D46(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D81(%rip),%rax
  ret
  lea    D11(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D38(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D95(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D26(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D97(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D7(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D40(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D46
type_infered: string
name: unpack_data
arguments: label: D81
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D38
type_infered: string
name: unpack_data
arguments: label: D95
type_infered: string
name: unpack_data
arguments: label: D26
type_infered: string
name: unpack_data
arguments: label: D97
type_infered: string
name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D40
type_infered: string

tool: D46: North-West

tool: D81: Central

tool: D11: Kgalagadi

tool: D38: Kgatleng

tool: D95: Kweneng

tool: D26: North-East

tool: D97: South-East

tool: D7: Southern

tool: D40: Ghanzi

assistant: ```c
const char *get_region_name_BW(int region_code) {
  switch (region_code) {
  case 1:
    return "Central";
  case 3:
    return "Ghanzi";
  case 4:
    return "Kgalagadi";
  case 5:
    return "Kgatleng";
  case 6:
    return "Kweneng";
  case 8:
    return "North-East";
  case 9:
    return "South-East";
  case 10:
    return "Southern";
  case 11:
    return "North-West";
  default:
    return NULL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
L2:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%eax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x20(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L49
  movl   $0x0,-0x28(%rbp)
  jmp    L0
L49:
  mov    -0x30(%rbp),%eax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movl   $0x1,-0x20(%rbp,%rax,4)
  jmp    L2
L25:
  movl   $0x0,-0x24(%rbp)
  jmp    L57
L59:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L57:
  cmpl   $0x2,-0x24(%rbp)
  jle    L59
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x28(%rbp)
L0:
  cmpl   $0x1,-0x28(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D39
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string

tool: D39: find the number of the row: 

tool: D29: %i

tool: D20: find the number of the column: 

assistant: ```c
int main() {
  bool booleanMatrix[2][3] = {0};
  while (true) {
    int row;
    int col;
    printf("find the number of the row: ");
    scanf("%i", &row);
    printf("find the number of the column: ");
    scanf("%i", &col);
    if (booleanMatrix[row][col]) {
      break;
    } else {
      booleanMatrix[row][col] = true;
    }
  }
  for (int row = 0; row < 2; row++) {
    for (int col = 0; col < 3; col++) {
      printf("%i", booleanMatrix[row][col]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  lea    D1(%rip),%r13
  lea    0x8(%rsp),%r12
  lea    D17(%rip),%rbx
  lea    D4(%rip),%rbp
  jmp    L25
L23:
  movl   $0x1,0x10(%rsp,%rcx,4)
L25:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  movslq %edx,%rsi
  movslq %eax,%rcx
  lea    (%rcx,%rcx,2),%rcx
  add    %rsi,%rcx
  cmpl   $0x0,0x10(%rsp,%rcx,4)
  je     L23
  mov    0x10(%rsp),%esi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1c(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x24(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string
name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D4
datatype: string

tool: D1: find the number of the row: 

tool: D17: %i

tool: D4: find the number of the column: 

assistant: ```c
int main() {
  bool booleanMatrix[2][3] = {0};
  while (true) {
    int row;
    int col;
    printf("find the number of the row: ");
    scanf("%i", &row);
    printf("find the number of the column: ");
    scanf("%i", &col);
    if (booleanMatrix[row][col]) {
      break;
    } else {
      booleanMatrix[row][col] = true;
    }
  }
  for (int row = 0; row < 2; row++) {
    for (int col = 0; col < 3; col++) {
      printf("%i", booleanMatrix[row][col]);
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  lea    D24(%rip),%r14
  push   %r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  movaps %xmm0,0x10(%rsp)
  lea    0xc(%rsp),%rbx
  movq   $0x0,0x20(%rsp)
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L22:
  movl   $0x1,0x10(%rsp,%rax,4)
L6:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  lea    (%rax,%rax,2),%rax
  add    %rdx,%rax
  mov    0x10(%rsp,%rax,4),%edx
  test   %edx,%edx
  je     L22
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1c(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x24(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D24
type: string
name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D12
type: string

tool: D24: find the number of the row: 

tool: D1: find the number of the column: 

tool: D12: %i

assistant: ```c
int main() {
  bool booleanMatrix[2][3] = {0};
  while (true) {
    int row;
    int col;
    printf("find the number of the row: ");
    scanf("%i", &row);
    printf("find the number of the column: ");
    scanf("%i", &col);
    if (booleanMatrix[row][col]) {
      break;
    } else {
      booleanMatrix[row][col] = true;
    }
  }
  for (int row = 0; row < 2; row++) {
    for (int col = 0; col < 3; col++) {
      printf("%i", booleanMatrix[row][col]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  lea    D15(%rip),%r14
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  movaps %xmm0,0x10(%rsp)
  lea    0xc(%rsp),%rbx
  movq   $0x0,0x20(%rsp)
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L10:
  movl   $0x1,0x10(%rsp,%rax,4)
L22:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  lea    (%rax,%rax,2),%rax
  add    %rdx,%rax
  mov    0x10(%rsp,%rax,4),%edx
  test   %edx,%edx
  je     L10
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1c(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x24(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type_infered: string
name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D19
type_infered: string

tool: D15: find the number of the row: 

tool: D10: find the number of the column: 

tool: D19: %i

assistant: ```c
int main() {
  bool booleanMatrix[2][3] = {0};
  while (true) {
    int row;
    int col;
    printf("find the number of the row: ");
    scanf("%i", &row);
    printf("find the number of the column: ");
    scanf("%i", &col);
    if (booleanMatrix[row][col]) {
      break;
    } else {
      booleanMatrix[row][col] = true;
    }
  }
  for (int row = 0; row < 2; row++) {
    for (int col = 0; col < 3; col++) {
      printf("%i", booleanMatrix[row][col]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hash_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L14:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    $0x0,%edx
  divl   -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash_string(const char *string, unsigned n_buckets) {
  unsigned value = 0;
  while (*string)
    value = ((value * 31 + (int)*(const unsigned char *)string++) % n_buckets);
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash_string>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L7
  mov    $0x0,%edx
L0:
  add    $0x1,%rdi
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  movzbl %cl,%ecx
  add    %ecx,%eax
  mov    $0x0,%edx
  div    %esi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L0
L21:
  mov    %edx,%eax
  ret
L7:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
unsigned hash_string(const char *string, unsigned n_buckets) {
  unsigned value = 0;
  while (*string)
    value = ((value * 31 + (int)*(const unsigned char *)string++) % n_buckets);
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash_string>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %edx,%edx
  test   %cl,%cl
  je     L18
  nopl   (%rax)
L6:
  mov    %edx,%eax
  add    $0x1,%rdi
  shl    $0x5,%eax
  sub    %edx,%eax
  xor    %edx,%edx
  add    %ecx,%eax
  movzbl (%rdi),%ecx
  div    %esi
  test   %cl,%cl
  jne    L6
L18:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned hash_string(const char *string, unsigned n_buckets) {
  unsigned value = 0;
  while (*string)
    value = ((value * 31 + (int)*(const unsigned char *)string++) % n_buckets);
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_string>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %edx,%edx
  test   %cl,%cl
  je     L12
  nopl   (%rax)
L9:
  mov    %edx,%eax
  add    $0x1,%rdi
  shl    $0x5,%eax
  sub    %edx,%eax
  xor    %edx,%edx
  add    %ecx,%eax
  movzbl (%rdi),%ecx
  div    %esi
  test   %cl,%cl
  jne    L9
L12:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned hash_string(const char *string, unsigned n_buckets) {
  unsigned value = 0;
  while (*string)
    value = ((value * 31 + (int)*(const unsigned char *)string++) % n_buckets);
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inst_mc68851_pbcc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <slog@plt>
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D15
type_guessed: string

tool: D11: inst_mc68851_pbcc

tool: D15: %s: Error, not implemented!


assistant: ```c
void inst_mc68851_pbcc() {
  slog("%s: Error, not implemented!\n", __func__);
  assert(!"blowup");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inst_mc68851_pbcc>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <slog@plt>
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D7
datatype: string

tool: D11: inst_mc68851_pbcc

tool: D7: %s: Error, not implemented!


assistant: ```c
void inst_mc68851_pbcc() {
  slog("%s: Error, not implemented!\n", __func__);
  assert(!"blowup");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<inst_mc68851_pbcc>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  lea    D5(%rip),%rsi
  xor    %eax,%eax
  call   <slog@plt>
  xor    %edi,%edi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

tool_calls: name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D5
type: string

tool: D14: %s: Error, not implemented!


tool: D5: inst_mc68851_pbcc

assistant: ```c
void inst_mc68851_pbcc() {
  slog("%s: Error, not implemented!\n", __func__);
  assert(!"blowup");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inst_mc68851_pbcc>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  lea    D19(%rip),%rsi
  xor    %eax,%eax
  call   <slog@plt>
  xor    %edi,%edi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D19
datatype: string

tool: D1: %s: Error, not implemented!


tool: D19: inst_mc68851_pbcc

assistant: ```c
void inst_mc68851_pbcc() {
  slog("%s: Error, not implemented!\n", __func__);
  assert(!"blowup");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0x9,-0x34(%rbp)
  jmp    L11
L0:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  subl   $0x1,-0x34(%rbp)
L11:
  cmpl   $0x4,-0x34(%rbp)
  jg     L0
  movl   $0x58,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L1
L30:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L1:
  cmpl   $0x9,-0x34(%rbp)
  jle    L30
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: array[%d]=%d


assistant: ```c
int main(void) {
  int array[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  int i;
  for (i = 10 - 1; i > 4; i--) {
    array[i] = array[i - 1];
  }
  array[4] = 88;
  for (i = 0; i < 10; i++) {
    printf("array[%d]=%d\n", i, array[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x9,0x24(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x58,0x10(%rsp)
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L7:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L7
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: array[%d]=%d


assistant: ```c
int main(void) {
  int array[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  int i;
  for (i = 10 - 1; i > 4; i--) {
    array[i] = array[i - 1];
  }
  array[4] = 88;
  for (i = 0; i < 10; i++) {
    printf("array[%d]=%d\n", i, array[i]);
  }
  return 0;
}
```