ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<set_nl_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <NLMSG_SPACE@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <NLMSG_SPACE@plt>
  mov    -0x8(%rbp),%rdx
  mov    %eax,0x4(%rdx)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    -0x8(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
unsigned char *set_nl_header(unsigned char *data, int size) {
  struct nlmsghdr *nlh = (struct nlmsghdr *)data;
  memset(nlh, 0, NLMSG_SPACE(size));
  nlh->nlmsg_len = NLMSG_SPACE(size);
  nlh->nlmsg_pid = getpid();
  return data + NLMSG_HDRLEN;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_nl_header>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <NLMSG_SPACE@plt>
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %ebp,%edi
  call   <NLMSG_SPACE@plt>
  mov    %eax,0x4(%rbx)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,(%rbx)
  mov    D4(%rip),%rax
  movslq (%rax),%rax
  add    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *set_nl_header(unsigned char *data, int size) {
  struct nlmsghdr *nlh = (struct nlmsghdr *)data;
  memset(nlh, 0, NLMSG_SPACE(size));
  nlh->nlmsg_len = NLMSG_SPACE(size);
  nlh->nlmsg_pid = getpid();
  return data + NLMSG_HDRLEN;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_nl_header>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x8,%rsp
  call   <NLMSG_SPACE@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <memset@plt>
  mov    %ebp,%edi
  call   <NLMSG_SPACE@plt>
  mov    %eax,0x4(%rbx)
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %eax,(%rbx)
  mov    D8(%rip),%rax
  movslq (%rax),%rax
  add    $0x8,%rsp
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *set_nl_header(unsigned char *data, int size) {
  struct nlmsghdr *nlh = (struct nlmsghdr *)data;
  memset(nlh, 0, NLMSG_SPACE(size));
  nlh->nlmsg_len = NLMSG_SPACE(size);
  nlh->nlmsg_pid = getpid();
  return data + NLMSG_HDRLEN;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_nl_header>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x8,%rsp
  call   <NLMSG_SPACE@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <memset@plt>
  mov    %ebp,%edi
  call   <NLMSG_SPACE@plt>
  mov    %eax,0x4(%rbx)
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %eax,(%rbx)
  mov    D7(%rip),%rax
  movslq (%rax),%rax
  add    $0x8,%rsp
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *set_nl_header(unsigned char *data, int size) {
  struct nlmsghdr *nlh = (struct nlmsghdr *)data;
  memset(nlh, 0, NLMSG_SPACE(size));
  nlh->nlmsg_len = NLMSG_SPACE(size);
  nlh->nlmsg_pid = getpid();
  return data + NLMSG_HDRLEN;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L1:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc_err@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *make_string(char *ostr, const char *nstr) {
  if (ostr != NULL)
    free(ostr);
  ostr = malloc_err(strlen(nstr) + 1);
  strcpy(ostr, nstr);
  return ostr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<make_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L9
  call   <free@plt>
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc_err@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *make_string(char *ostr, const char *nstr) {
  if (ostr != NULL)
    free(ostr);
  ostr = malloc_err(strlen(nstr) + 1);
  strcpy(ostr, nstr);
  return ostr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<make_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L3
  call   <free@plt>
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc_err@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *make_string(char *ostr, const char *nstr) {
  if (ostr != NULL)
    free(ostr);
  ostr = malloc_err(strlen(nstr) + 1);
  strcpy(ostr, nstr);
  return ostr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<make_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L3
  call   <free@plt>
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc_err@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *make_string(char *ostr, const char *nstr) {
  if (ostr != NULL)
    free(ostr);
  ostr = malloc_err(strlen(nstr) + 1);
  strcpy(ostr, nstr);
  return ostr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x1e8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1e4(%rbp)
  jmp    L35
L101:
  mov    -0x1e4(%rbp),%eax
  cltq
  movl   $0x0,-0x1d0(%rbp,%rax,4)
  addl   $0x1,-0x1e4(%rbp)
L35:
  cmpl   $0x63,-0x1e4(%rbp)
  jle    L101
  mov    -0x1e8(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x1e0(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L20:
  cmp    %rdx,%rsp
  je     L80
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L20
L80:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L72
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L72:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x1d8(%rbp)
  movl   $0x0,-0x1e4(%rbp)
  jmp    L102
L7:
  mov    -0x1e4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1d8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1d8(%rbp),%rax
  mov    -0x1e4(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  movslq %eax,%rdx
  mov    -0x1d0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x1d0(%rbp,%rax,4)
  addl   $0x1,-0x1e4(%rbp)
L102:
  mov    -0x1e8(%rbp),%eax
  cmp    %eax,-0x1e4(%rbp)
  jl     L7
  movl   $0x0,-0x1e4(%rbp)
  jmp    L44
L90:
  mov    -0x1e4(%rbp),%eax
  cltq
  mov    -0x1d0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L98
  mov    -0x1e4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L98:
  addl   $0x1,-0x1e4(%rbp)
L44:
  cmpl   $0x63,-0x1e4(%rbp)
  jle    L90
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  int res;
  int n, i, count[100];
  scanf("%d", &n);
  for (i = 0; i < 100; i++)
    count[i] = 0;
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    count[a[i]]++;
  }
  for (i = 0; i < 100; i++)
    if (count[i] == 1)
      printf("%d", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x1c4(%rbp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  lea    -0x1c0(%rbp),%rax
  lea    -0x30(%rbp),%rdx
L70:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L70
  mov    -0x1c4(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L49:
  cmp    %rcx,%rsp
  je     L44
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L49
L44:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L77
  orq    $0x0,-0x8(%rsp,%rax,1)
L77:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L39
  mov    $0x0,%r12d
  lea    D10(%rip),%r13
L46:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movslq (%rbx),%rax
  addl   $0x1,-0x1c0(%rbp,%rax,4)
  add    $0x1,%r12d
  add    $0x4,%rbx
  cmp    %r12d,-0x1c4(%rbp)
  jg     L46
L39:
  mov    $0x0,%ebx
  lea    D10(%rip),%r12
  jmp    L30
L54:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L93
L30:
  mov    %ebx,%esi
  cmpl   $0x1,-0x1c0(%rbp,%rbx,4)
  jne    L54
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L54
L93:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  mov    $0x0,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D10: %d

assistant: ```c
int main() {
  int res;
  int n, i, count[100];
  scanf("%d", &n);
  for (i = 0; i < 100; i++)
    count[i] = 0;
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    count[a[i]]++;
  }
  for (i = 0; i < 100; i++)
    if (count[i] == 1)
      printf("%d", i);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D2(%rip),%r13
  lea    -0x1c4(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  lea    -0x1c0(%rbp),%r12
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %eax,%eax
  mov    $0x32,%ecx
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  movslq -0x1c4(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L17
L80:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L80
L17:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L72
L49:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L76
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L62:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%r14d
  add    $0x4,%rbx
  call   <scanf@plt>
  movslq -0x4(%rbx),%rax
  addl   $0x1,-0x1c0(%rbp,%rax,4)
  cmp    %r14d,-0x1c4(%rbp)
  jg     L62
L76:
  xor    %ebx,%ebx
  jmp    L9
  nopl   0x0(%rax)
L50:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L45
L9:
  cmpl   $0x1,(%r12,%rbx,4)
  mov    %ebx,%esi
  jne    L50
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L9
L45:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L72:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L49
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  int res;
  int n, i, count[100];
  scanf("%d", &n);
  for (i = 0; i < 100; i++)
    count[i] = 0;
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    count[a[i]]++;
  }
  for (i = 0; i < 100; i++)
    if (count[i] == 1)
      printf("%d", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D7(%rip),%r13
  lea    -0x1c4(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  lea    -0x1c0(%rbp),%r12
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %eax,%eax
  mov    $0x32,%ecx
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  movslq -0x1c4(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L66
L0:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L0
L66:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L87
L15:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L28
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L107:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%r14d
  add    $0x4,%rbx
  call   <scanf@plt>
  movslq -0x4(%rbx),%rax
  addl   $0x1,-0x1c0(%rbp,%rax,4)
  cmp    %r14d,-0x1c4(%rbp)
  jg     L107
L28:
  xor    %ebx,%ebx
  jmp    L35
  nopl   0x0(%rax)
L71:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L67
L35:
  cmpl   $0x1,(%r12,%rbx,4)
  mov    %ebx,%esi
  jne    L71
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L35
L67:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L87:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L15
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: %d

assistant: ```c
int main() {
  int res;
  int n, i, count[100];
  scanf("%d", &n);
  for (i = 0; i < 100; i++)
    count[i] = 0;
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    count[a[i]]++;
  }
  for (i = 0; i < 100; i++)
    if (count[i] == 1)
      printf("%d", i);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ar_num_probs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x42c(%rbp)
  mov    -0x438(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x420(%rbp)
  movq   $0x0,-0x418(%rbp)
  jmp    L16
L0:
  movq   $0x0,-0x428(%rbp)
  jmp    L15
L19:
  lea    -0x410(%rbp),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L28
  addl   $0x1,-0x42c(%rbp)
L28:
  addq   $0x1,-0x428(%rbp)
L15:
  mov    -0x428(%rbp),%rax
  cmp    -0x418(%rbp),%rax
  jb     L19
L16:
  mov    -0x420(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L0
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x42c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string

tool: D8: r

assistant: ```c
unsigned int ar_num_probs(char *file) {
  unsigned int num_probs = 0;
  FILE *fh = fopen(file, "r");
  char rbuf[1024];
  size_t readc = 0;
  while ((readc = fread(rbuf, sizeof(char), 1024, fh))) {
    size_t c;
    for (c = 0; c < readc; c++) {
      if (rbuf[c] == '\n') {
        num_probs++;
      }
    }
  }
  fclose(fh);
  return num_probs;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ar_num_probs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  mov    %rsp,%r12
L30:
  mov    %rbp,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  test   %rax,%rax
  je     L17
  mov    %rsp,%rdx
  add    %rdx,%rax
L20:
  cmpb   $0xa,(%rdx)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%ebx
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L20
  jmp    L30
L17:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    %ebx,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: r

assistant: ```c
unsigned int ar_num_probs(char *file) {
  unsigned int num_probs = 0;
  FILE *fh = fopen(file, "r");
  char rbuf[1024];
  size_t readc = 0;
  while ((readc = fread(rbuf, sizeof(char), 1024, fh))) {
    size_t c;
    for (c = 0; c < readc; c++) {
      if (rbuf[c] == '\n') {
        num_probs++;
      }
    }
  }
  fclose(fh);
  return num_probs;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ar_num_probs>:
  endbr64
  push   %r12
  lea    D2(%rip),%rsi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <fopen@plt>
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %rbp,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %rax,%rax
  je     L30
  mov    %rbx,%rdx
  add    %rbx,%rax
L38:
  xor    %ecx,%ecx
  cmpb   $0xa,(%rdx)
  sete   %cl
  add    $0x1,%rdx
  add    %ecx,%r12d
  cmp    %rax,%rdx
  jne    L38
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: r

assistant: ```c
unsigned int ar_num_probs(char *file) {
  unsigned int num_probs = 0;
  FILE *fh = fopen(file, "r");
  char rbuf[1024];
  size_t readc = 0;
  while ((readc = fread(rbuf, sizeof(char), 1024, fh))) {
    size_t c;
    for (c = 0; c < readc; c++) {
      if (rbuf[c] == '\n') {
        num_probs++;
      }
    }
  }
  fclose(fh);
  return num_probs;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ipv6netmask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x10(%rbp)
  mov    $0x10,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0x10(%rbp)
  je     L6
  movb   $0xff,-0x15(%rbp)
  movzbl -0x15(%rbp),%edx
  mov    $0x8,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x15(%rbp),%eax
  mov    %al,(%rdx)
L6:
  nop
  leave
  ret
```

assistant: ```c
void ipv6netmask(unsigned prefix_length, struct sockaddr_in6 *sa) {
  unsigned char *hb = sa->sin6_addr.s6_addr;
  unsigned onebytes = prefix_length / 8;
  unsigned bits = prefix_length % 8;
  unsigned nullbytes = 16 - onebytes;
  memset(hb, -1, onebytes);
  memset(hb + onebytes, 0, nullbytes);
  if (bits) {
    unsigned char x = -1;
    x <<= 8 - bits;
    hb[onebytes] = x;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ipv6netmask>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rsi),%rbp
  mov    %edi,%r12d
  shr    $0x3,%r12d
  mov    %edi,%ebx
  and    $0x7,%ebx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%eax
  add    %rax,%rbp
  mov    $0x10,%edx
  sub    %r12d,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  je     L4
  mov    $0x8,%ecx
  sub    %ebx,%ecx
  mov    $0xff,%eax
  shl    %cl,%eax
  mov    %al,0x0(%rbp)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ipv6netmask(unsigned prefix_length, struct sockaddr_in6 *sa) {
  unsigned char *hb = sa->sin6_addr.s6_addr;
  unsigned onebytes = prefix_length / 8;
  unsigned bits = prefix_length % 8;
  unsigned nullbytes = 16 - onebytes;
  memset(hb, -1, onebytes);
  memset(hb + onebytes, 0, nullbytes);
  if (bits) {
    unsigned char x = -1;
    x <<= 8 - bits;
    hb[onebytes] = x;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ipv6netmask>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  shr    $0x3,%r12d
  push   %rbx
  mov    (%rsi),%rbp
  mov    %edi,%ebx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  and    $0x7,%ebx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%eax
  mov    $0x10,%edx
  xor    %esi,%esi
  add    %rax,%rbp
  sub    %r12d,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  je     L3
  mov    $0x8,%ecx
  mov    $0xff,%eax
  sub    %ebx,%ecx
  shl    %cl,%eax
  mov    %al,0x0(%rbp)
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ipv6netmask(unsigned prefix_length, struct sockaddr_in6 *sa) {
  unsigned char *hb = sa->sin6_addr.s6_addr;
  unsigned onebytes = prefix_length / 8;
  unsigned bits = prefix_length % 8;
  unsigned nullbytes = 16 - onebytes;
  memset(hb, -1, onebytes);
  memset(hb + onebytes, 0, nullbytes);
  if (bits) {
    unsigned char x = -1;
    x <<= 8 - bits;
    hb[onebytes] = x;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipv6netmask>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  shr    $0x3,%r12d
  push   %rbx
  mov    (%rsi),%rbp
  mov    %edi,%ebx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  and    $0x7,%ebx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%eax
  mov    $0x10,%edx
  xor    %esi,%esi
  add    %rax,%rbp
  sub    %r12d,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  je     L5
  mov    $0x8,%ecx
  mov    $0xff,%eax
  sub    %ebx,%ecx
  shl    %cl,%eax
  mov    %al,0x0(%rbp)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ipv6netmask(unsigned prefix_length, struct sockaddr_in6 *sa) {
  unsigned char *hb = sa->sin6_addr.s6_addr;
  unsigned onebytes = prefix_length / 8;
  unsigned bits = prefix_length % 8;
  unsigned nullbytes = 16 - onebytes;
  memset(hb, -1, onebytes);
  memset(hb + onebytes, 0, nullbytes);
  if (bits) {
    unsigned char x = -1;
    x <<= 8 - bits;
    hb[onebytes] = x;
  }
}
```