ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  lea    0x100(%rdi),%r10
  xor    %eax,%eax
  nopl   (%rax)
L17:
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  nopl   (%rax)
L2:
  movswl (%rsi,%rcx,1),%r8d
  movswl (%rdi,%rcx,1),%edx
  sub    %r8d,%edx
  mov    %edx,%r8d
  neg    %r8d
  cmovns %r8d,%edx
  add    $0x2,%rcx
  add    %edx,%r9d
  cmp    $0x10,%rcx
  jne    L2
  add    $0x20,%rdi
  add    %r9d,%eax
  add    $0x10,%rsi
  cmp    %rdi,%r10
  jne    L17
  ret
```

assistant: ```c
short foo(short image[][16], short block[][8]) {
  int sad, diff = 0;
  int i, j;
  int tmp;
  for (i = 0; i < 8; i++) {
    sad = 0;
    for (j = 0; j < 8; j++) {
      tmp = image[i][j] - block[i][j];
      sad += (tmp < 0) ? -tmp : tmp;
    }
    diff += sad;
  }
  return diff;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  lea    0x100(%rdi),%r9
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L2:
  movswl (%rcx),%esi
  movswl (%rdx),%edi
  movswl 0x2(%rcx),%r8d
  sub    %esi,%edi
  mov    %edi,%esi
  neg    %esi
  cmovs  %edi,%esi
  movswl 0x2(%rdx),%edi
  sub    %r8d,%edi
  mov    %edi,%r8d
  neg    %r8d
  cmovns %r8d,%edi
  movswl 0x4(%rdx),%r8d
  add    %edi,%esi
  movswl 0x4(%rcx),%edi
  sub    %edi,%r8d
  mov    %r8d,%edi
  neg    %edi
  cmovs  %r8d,%edi
  movswl 0x6(%rdx),%r8d
  add    %esi,%edi
  movswl 0x6(%rcx),%esi
  sub    %esi,%r8d
  mov    %r8d,%esi
  neg    %esi
  cmovs  %r8d,%esi
  movswl 0x8(%rdx),%r8d
  add    %edi,%esi
  movswl 0x8(%rcx),%edi
  sub    %edi,%r8d
  mov    %r8d,%edi
  neg    %edi
  cmovs  %r8d,%edi
  movswl 0xa(%rdx),%r8d
  add    %esi,%edi
  movswl 0xa(%rcx),%esi
  sub    %esi,%r8d
  mov    %r8d,%esi
  neg    %esi
  cmovs  %r8d,%esi
  movswl 0xc(%rdx),%r8d
  add    %edi,%esi
  movswl 0xc(%rcx),%edi
  sub    %edi,%r8d
  mov    %r8d,%edi
  neg    %edi
  cmovs  %r8d,%edi
  movswl 0xe(%rdx),%r8d
  add    %esi,%edi
  movswl 0xe(%rcx),%esi
  sub    %esi,%r8d
  mov    %r8d,%esi
  neg    %esi
  cmovs  %r8d,%esi
  add    $0x20,%rdx
  add    $0x10,%rcx
  add    %edi,%esi
  add    %esi,%eax
  cmp    %rdx,%r9
  jne    L2
  ret
```

assistant: ```c
short foo(short image[][16], short block[][8]) {
  int sad, diff = 0;
  int i, j;
  int tmp;
  for (i = 0; i < 8; i++) {
    sad = 0;
    for (j = 0; j < 8; j++) {
      tmp = image[i][j] - block[i][j];
      sad += (tmp < 0) ? -tmp : tmp;
    }
    diff += sad;
  }
  return diff;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L26
L25:
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %ebx,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L38
  mov    -0x18(%rbp),%rax
  jmp    L11
L38:
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L25
  mov    $0x0,%eax
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *sindex(char *s1, char *s2) {
  register int s2len = strlen(s2);
  char *s = s1;
  while ((s = strchr(s, (int)*s2)) != 0) {
    if (strncmp(s, s2, s2len) == 0)
      return (s);
    s++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<sindex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L13
L10:
  add    $0x1,%rbx
L13:
  movsbl 0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L11
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L10
L11:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *sindex(char *s1, char *s2) {
  register int s2len = strlen(s2);
  char *s = s1;
  while ((s = strchr(s, (int)*s2)) != 0) {
    if (strncmp(s, s2, s2len) == 0)
      return (s);
    s++;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sindex>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L14
  add    $0x1,%r12
L11:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L19
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *sindex(char *s1, char *s2) {
  register int s2len = strlen(s2);
  char *s = s1;
  while ((s = strchr(s, (int)*s2)) != 0) {
    if (strncmp(s, s2, s2len) == 0)
      return (s);
    s++;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sindex>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L12
  add    $0x1,%r12
L9:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L26
L12:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *sindex(char *s1, char *s2) {
  register int s2len = strlen(s2);
  char *s = s1;
  while ((s = strchr(s, (int)*s2)) != 0) {
    if (strncmp(s, s2, s2len) == 0)
      return (s);
    s++;
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sum_DWTAnlz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L29:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  cmpq   $0x0,-0x28(%rbp)
  je     L16
  mov    -0x28(%rbp),%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
L16:
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float sum_DWTAnlz(float *dwt, int n, float *sum) {
  float tsum = 0;
  for (int i = 1; i < n; i++)
    tsum += dwt[i];
  if (sum)
    *sum = tsum;
  return tsum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sum_DWTAnlz>:
  endbr64
  cmp    $0x1,%esi
  jle    L33
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%ecx
  lea    0x8(%rdi,%rcx,4),%rcx
  pxor   %xmm0,%xmm0
L32:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L32
L7:
  test   %rdx,%rdx
  je     L36
  movss  %xmm0,(%rdx)
L36:
  ret
L33:
  pxor   %xmm0,%xmm0
  jmp    L7
```

assistant: ```c
float sum_DWTAnlz(float *dwt, int n, float *sum) {
  float tsum = 0;
  for (int i = 1; i < n; i++)
    tsum += dwt[i];
  if (sum)
    *sum = tsum;
  return tsum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sum_DWTAnlz>:
  endbr64
  cmp    $0x1,%esi
  jle    L11
  lea    -0x2(%rsi),%ecx
  lea    0x4(%rdi),%rax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rcx,4),%rcx
  nopl   0x0(%rax)
L20:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L20
L10:
  test   %rdx,%rdx
  je     L15
  movss  %xmm0,(%rdx)
L15:
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  pxor   %xmm0,%xmm0
  jmp    L10
```

assistant: ```c
float sum_DWTAnlz(float *dwt, int n, float *sum) {
  float tsum = 0;
  for (int i = 1; i < n; i++)
    tsum += dwt[i];
  if (sum)
    *sum = tsum;
  return tsum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sum_DWTAnlz>:
  endbr64
  mov    %esi,%ecx
  mov    %rdx,%rsi
  cmp    $0x1,%ecx
  jle    L51
  lea    -0x2(%rcx),%eax
  lea    -0x1(%rcx),%r8d
  cmp    $0x2,%eax
  jbe    L26
  mov    %r8d,%edx
  lea    0x4(%rdi),%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x14(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L19:
  movups (%rax),%xmm1
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L19
  mov    %r8d,%edx
  and    $0xfffffffc,%edx
  lea    0x1(%rdx),%eax
  cmp    %edx,%r8d
  je     L64
L56:
  movslq %eax,%rdx
  addss  (%rdi,%rdx,4),%xmm0
  lea    0x0(,%rdx,4),%r8
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jle    L64
  add    $0x2,%eax
  addss  0x4(%rdi,%r8,1),%xmm0
  cmp    %eax,%ecx
  jle    L64
  addss  0x8(%rdi,%r8,1),%xmm0
L64:
  test   %rsi,%rsi
  je     L84
  movss  %xmm0,(%rsi)
L84:
  ret
  nopl   0x0(%rax)
L51:
  pxor   %xmm0,%xmm0
  jmp    L64
L26:
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
  jmp    L56
```

assistant: ```c
float sum_DWTAnlz(float *dwt, int n, float *sum) {
  float tsum = 0;
  for (int i = 1; i < n; i++)
    tsum += dwt[i];
  if (sum)
    *sum = tsum;
  return tsum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D40
data_type: string
name: extract_symbolic_data
arguments: data_label: D21
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string
name: extract_symbolic_data
arguments: data_label: D88
data_type: string
name: extract_symbolic_data
arguments: data_label: D51
data_type: string
name: extract_symbolic_data
arguments: data_label: D50
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string
name: extract_symbolic_data
arguments: data_label: D53
data_type: string
name: extract_symbolic_data
arguments: data_label: D19
data_type: string

tool: D40: 
Usage: %s [-i] [-l] [-e] [-n value] [-t seconds]


tool: D21: -i --inode	Display the inode of the directory/file

tool: D17: -l --link	Mark symbolic links

tool: D88: -h --help	Print this help screen

tool: D51: -e --empty	Mark empty files

tool: D50: -s --size	Print file size in bytes/kilobytes

tool: D0: -n --nice	Set niceness range from %d to 19


tool: D53: -t --time	Set maximum execution time in seconds

tool: D19: -v --version	Print version info and license


assistant: ```c
void usage(int nbl, char *argv[]) {
  printf("\nUsage: %s [-i] [-l] [-e] [-n value] [-t seconds]\n", argv[0]);
  printf("-i --inode	Display the inode of the directory/file\n");
  printf("-l --link	Mark symbolic links\n");
  printf("-h --help	Print this help screen\n");
  printf("-e --empty	Mark empty files\n");
  printf("-s --size	Print file size in bytes/kilobytes\n");
  printf("-n --nice	Set niceness range from %d to 19\n", nbl);
  printf("-t --time	Set maximum execution time in seconds\n");
  printf("-v --version	Print version info and license\n\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    (%rsi),%rsi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    D44(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  lea    D85(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D34
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D56
data_type: string
name: extract_symbolic_data
arguments: data_tag: D51
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D44
data_type: string
name: extract_symbolic_data
arguments: data_tag: D85
data_type: string
name: extract_symbolic_data
arguments: data_tag: D33
data_type: string
name: extract_symbolic_data
arguments: data_tag: D38
data_type: string

tool: D34: 
Usage: %s [-i] [-l] [-e] [-n value] [-t seconds]


tool: D11: -i --inode	Display the inode of the directory/file

tool: D56: -l --link	Mark symbolic links

tool: D51: -h --help	Print this help screen

tool: D10: -e --empty	Mark empty files

tool: D44: -s --size	Print file size in bytes/kilobytes

tool: D85: -n --nice	Set niceness range from %d to 19


tool: D33: -t --time	Set maximum execution time in seconds

tool: D38: -v --version	Print version info and license


assistant: ```c
void usage(int nbl, char *argv[]) {
  printf("\nUsage: %s [-i] [-l] [-e] [-n value] [-t seconds]\n", argv[0]);
  printf("-i --inode	Display the inode of the directory/file\n");
  printf("-l --link	Mark symbolic links\n");
  printf("-h --help	Print this help screen\n");
  printf("-e --empty	Mark empty files\n");
  printf("-s --size	Print file size in bytes/kilobytes\n");
  printf("-n --nice	Set niceness range from %d to 19\n", nbl);
  printf("-t --time	Set maximum execution time in seconds\n");
  printf("-v --version	Print version info and license\n\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    (%rsi),%rsi
  mov    %edi,%ebp
  xor    %eax,%eax
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    D53(%rip),%rdi
  call   <puts@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  lea    D86(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: label: D66
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string
name: parse_data
arguments: label: D53
type_guessed: string
name: parse_data
arguments: label: D56
type_guessed: string
name: parse_data
arguments: label: D63
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D24
type_guessed: string
name: parse_data
arguments: label: D37
type_guessed: string
name: parse_data
arguments: label: D86
type_guessed: string

tool: D66: 
Usage: %s [-i] [-l] [-e] [-n value] [-t seconds]


tool: D26: -i --inode	Display the inode of the directory/file

tool: D53: -l --link	Mark symbolic links

tool: D56: -h --help	Print this help screen

tool: D63: -e --empty	Mark empty files

tool: D5: -s --size	Print file size in bytes/kilobytes

tool: D24: -n --nice	Set niceness range from %d to 19


tool: D37: -t --time	Set maximum execution time in seconds

tool: D86: -v --version	Print version info and license


assistant: ```c
void usage(int nbl, char *argv[]) {
  printf("\nUsage: %s [-i] [-l] [-e] [-n value] [-t seconds]\n", argv[0]);
  printf("-i --inode	Display the inode of the directory/file\n");
  printf("-l --link	Mark symbolic links\n");
  printf("-h --help	Print this help screen\n");
  printf("-e --empty	Mark empty files\n");
  printf("-s --size	Print file size in bytes/kilobytes\n");
  printf("-n --nice	Set niceness range from %d to 19\n", nbl);
  printf("-t --time	Set maximum execution time in seconds\n");
  printf("-v --version	Print version info and license\n\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    (%rsi),%rsi
  mov    %edi,%ebp
  xor    %eax,%eax
  lea    D71(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D50(%rip),%rdi
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D79(%rip),%rdi
  call   <puts@plt>
  lea    D73(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D77(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    D58(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: label: D71
data_type: string
name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D50
data_type: string
name: parse_data
arguments: label: D29
data_type: string
name: parse_data
arguments: label: D79
data_type: string
name: parse_data
arguments: label: D73
data_type: string
name: parse_data
arguments: label: D77
data_type: string
name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D58
data_type: string

tool: D71: 
Usage: %s [-i] [-l] [-e] [-n value] [-t seconds]


tool: D1: -i --inode	Display the inode of the directory/file

tool: D50: -l --link	Mark symbolic links

tool: D29: -h --help	Print this help screen

tool: D79: -e --empty	Mark empty files

tool: D73: -s --size	Print file size in bytes/kilobytes

tool: D77: -n --nice	Set niceness range from %d to 19


tool: D18: -t --time	Set maximum execution time in seconds

tool: D58: -v --version	Print version info and license


assistant: ```c
void usage(int nbl, char *argv[]) {
  printf("\nUsage: %s [-i] [-l] [-e] [-n value] [-t seconds]\n", argv[0]);
  printf("-i --inode	Display the inode of the directory/file\n");
  printf("-l --link	Mark symbolic links\n");
  printf("-h --help	Print this help screen\n");
  printf("-e --empty	Mark empty files\n");
  printf("-s --size	Print file size in bytes/kilobytes\n");
  printf("-n --nice	Set niceness range from %d to 19\n", nbl);
  printf("-t --time	Set maximum execution time in seconds\n");
  printf("-v --version	Print version info and license\n\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  sub    $0x17447d68,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L23
  mov    %rsp,%rsi
  mov    $0x0,%edx
L48:
  mov    (%rsp),%rcx
  cmp    %rdx,%rcx
  jbe    L11
  mov    (%rsi),%eax
  mov    0x4(%rsi),%ecx
  mov    %ecx,(%rsi)
  mov    %eax,0x4(%rsi)
  mov    (%rsp),%rcx
  mov    %rcx,%rax
  shl    $0x4,%rax
  and    $0x1f0,%eax
  or     %rcx,%rax
L15:
  mov    %rax,(%rsp)
  add    $0x1,%rdx
  add    $0x8,%rsi
  cmp    %rdi,%rdx
  jne    L48
L23:
  mov    (%rsp),%rax
  ror    $0x7,%rax
  mov    %rax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  ret
L11:
  mov    %rcx,%rax
  shl    $0x4,%rax
  and    $0x1f0,%eax
  or     %rcx,%rax
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  jmp    L15
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          state[0UL] |= (state[0UL] & 15UL) << 3UL;
          state[local1] |= (state[local1] * state[0UL] & 15UL) << 3UL;
        } else {
          copy11 = *((unsigned int *)(&state[local1]) + 0);
          *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
          *((unsigned int *)(&state[local1]) + 1) = copy11;
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else {
        state[local1] |= ((state[0UL] | state[local1]) & 31UL) << 4UL;
        state[0UL] = state[local1] << ((state[local1] & 7UL) | 1UL);
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 7UL) | (state[0UL] << 57UL);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%r8
  sub    $0x17447d68,%rax
  test   %r8,%r8
  je     L18
  xor    %edi,%edi
L34:
  mov    %rax,%rdx
  shl    $0x4,%rdx
  and    $0x1f0,%edx
  or     %rax,%rdx
  cmp    %rdi,%rax
  ja     L36
  mov    %edx,%ecx
  mov    %rdx,%rax
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L39:
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L34
L18:
  ror    $0x7,%rax
  mov    %rax,(%rsi)
  ret
  nopl   0x0(%rax)
L36:
  mov    %rdx,%rax
  jmp    L39
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          state[0UL] |= (state[0UL] & 15UL) << 3UL;
          state[local1] |= (state[local1] * state[0UL] & 15UL) << 3UL;
        } else {
          copy11 = *((unsigned int *)(&state[local1]) + 0);
          *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
          *((unsigned int *)(&state[local1]) + 1) = copy11;
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else {
        state[local1] |= ((state[0UL] | state[local1]) & 31UL) << 4UL;
        state[0UL] = state[local1] << ((state[local1] & 7UL) | 1UL);
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 7UL) | (state[0UL] << 57UL);
  }
}
```