ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_vars>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xffffffff,%esi
  je     L5
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %edx,%edi
  sub    %esi,%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  cmp    %ebx,%r13d
  jge    L23
  movslq %r13d,%rdx
  mov    %rdx,%rax
  mov    %rbp,%rcx
  sub    %rdx,%rcx
L54:
  movzbl (%r14,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L54
  sub    %r13d,%ebx
L9:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  cmp    $0x2,%r12d
  je     L63
L68:
  mov    %rbp,%rdi
  call   <puts@plt>
L40:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    $0x0,%ebx
  jmp    L9
L63:
  mov    %rbp,%rdi
  call   <atoi@plt>
  cmp    $0x2,%eax
  jne    L68
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L40
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D0: 2 ------------> NETWORK TYPE PROBE!

assistant: ```c
int print_vars(char *str, int first, int last, int num) {
  int n;
  int i = 0;
  char *vars;
  if (first == -1)
    return 1;
  vars = malloc((last - first) * sizeof(char) + 1);
  for (n = first; n < last; n++)
    vars[i++] = str[n];
  vars[i] = '\0';
  if ((num == 2) && (atoi(vars) == 2)) {
    printf("2 ------------> NETWORK TYPE PROBE!\n");
  } else {
    printf("%s\n", vars);
  }
  free(vars);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_vars>:
  endbr64
  cmp    $0xffffffff,%esi
  je     L64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  sub    %esi,%r14d
  push   %r12
  mov    %rdi,%r12
  lea    0x1(%r14),%edi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    %ebp,%ebx
  jge    L42
  movslq %ebx,%rsi
  mov    %rax,%rdx
  sub    %rsi,%rdx
  nopl   0x0(%rax,%rax,1)
L67:
  movzbl (%r12,%rsi,1),%eax
  mov    %al,(%rdx,%rsi,1)
  add    $0x1,%rsi
  cmp    %esi,%ebp
  jg     L67
  movslq %r14d,%r14
  add    %r13,%r14
L15:
  movb   $0x0,(%r14)
  cmp    $0x2,%r15d
  je     L65
L69:
  mov    %r13,%rdi
  call   <puts@plt>
L9:
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L65:
  mov    %r13,%rdi
  call   <atoi@plt>
  cmp    $0x2,%eax
  jne    L69
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L64:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L42:
  mov    %rax,%r14
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: 2 ------------> NETWORK TYPE PROBE!

assistant: ```c
int print_vars(char *str, int first, int last, int num) {
  int n;
  int i = 0;
  char *vars;
  if (first == -1)
    return 1;
  vars = malloc((last - first) * sizeof(char) + 1);
  for (n = first; n < last; n++)
    vars[i++] = str[n];
  vars[i] = '\0';
  if ((num == 2) && (atoi(vars) == 2)) {
    printf("2 ------------> NETWORK TYPE PROBE!\n");
  } else {
    printf("%s\n", vars);
  }
  free(vars);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cipher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L13
  movb   $0x61,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L38
  movb   $0x41,-0x1(%rbp)
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movsbl -0x1(%rbp),%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L13:
  addq   $0x1,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cipher>
  jmp    L9
L26:
  nop
L9:
  leave
  ret
```

assistant: ```c
void cipher(char *word, int x) {
  if (*word == 0)
    return;
  if (isalpha(*word)) {
    char first = 'a';
    if (isupper(*word))
      first = 'A';
    *word = first + (*word + x - first) % 26;
  }
  cipher(++word, x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cipher>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L16
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %esi,%ebp
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L13
L22:
  lea    0x1(%rbx),%rdi
  mov    %ebp,%esi
  call   <cipher>
  jmp    L26
L13:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  cmp    $0x1,%rax
  sbb    %ecx,%ecx
  and    $0x20,%ecx
  add    $0x41,%ecx
  movsbl (%rbx),%eax
  add    %ebp,%eax
  movsbl %cl,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    %eax,%ecx
  mov    %cl,(%rbx)
  jmp    L22
```

assistant: ```c
void cipher(char *word, int x) {
  if (*word == 0)
    return;
  if (isalpha(*word)) {
    char first = 'a';
    if (isupper(*word))
      first = 'A';
    *word = first + (*word + x - first) % 26;
  }
  cipher(++word, x);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cipher>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L43
  mov    %esi,%ebp
  jmp    L25
  nopl   0x0(%rax)
L23:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L43
L25:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L23
  movsbl (%rbx),%edi
  call   <isupper@plt>
  movsbl (%rbx),%ecx
  mov    %ebp,%esi
  cmp    $0x1,%rax
  sbb    %edx,%edx
  and    $0x20,%edx
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x1,%rbx
  and    $0x20,%eax
  sub    %eax,%esi
  lea    -0x41(%rsi,%rcx,1),%ecx
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x23,%rax
  sub    %esi,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ecx
  lea    0x41(%rdx,%rcx,1),%edx
  mov    %dl,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L25
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cipher(char *word, int x) {
  if (*word == 0)
    return;
  if (isalpha(*word)) {
    char first = 'a';
    if (isupper(*word))
      first = 'A';
    *word = first + (*word + x - first) % 26;
  }
  cipher(++word, x);
}
```
user: What is the c source code of the assembly code below?

```asm
<cipher>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L36
  mov    %esi,%ebp
  jmp    L38
  nopl   0x0(%rax)
L4:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L36
L38:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L4
  movsbl (%rbx),%edi
  call   <isupper@plt>
  movsbl (%rbx),%ecx
  mov    %ebp,%esi
  cmp    $0x1,%rax
  sbb    %edx,%edx
  and    $0x20,%edx
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x1,%rbx
  and    $0x20,%eax
  sub    %eax,%esi
  lea    -0x41(%rsi,%rcx,1),%ecx
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x23,%rax
  sub    %esi,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ecx
  lea    0x41(%rdx,%rcx,1),%edx
  mov    %dl,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L38
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cipher(char *word, int x) {
  if (*word == 0)
    return;
  if (isalpha(*word)) {
    char first = 'a';
    if (isupper(*word))
      first = 'A';
    *word = first + (*word + x - first) % 26;
  }
  cipher(++word, x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<namco_setParams58XX_SetN163>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <namcoSetN163@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <namco_setParams58XX@plt>
  nop
  leave
  ret
```

assistant: ```c
void namco_setParams58XX_SetN163(uint16_t addr, uint8_t val) {
  namcoSetN163(addr);
  namco_setParams58XX(addr, val);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<namco_setParams58XX_SetN163>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <namcoSetN163@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <namco_setParams58XX@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void namco_setParams58XX_SetN163(uint16_t addr, uint8_t val) {
  namcoSetN163(addr);
  namco_setParams58XX(addr, val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<namco_setParams58XX_SetN163>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <namcoSetN163@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <namco_setParams58XX@plt>
```

assistant: ```c
void namco_setParams58XX_SetN163(uint16_t addr, uint8_t val) {
  namcoSetN163(addr);
  namco_setParams58XX(addr, val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<namco_setParams58XX_SetN163>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <namcoSetN163@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <namco_setParams58XX@plt>
```

assistant: ```c
void namco_setParams58XX_SetN163(uint16_t addr, uint8_t val) {
  namcoSetN163(addr);
  namco_setParams58XX(addr, val);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<err_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D0: %s

tool: D16: Hit Enter:

assistant: ```c
void err_exit(const char *message, const int error_code) {
  if (message)
    printf("%s", message);
  printf("Hit Enter:\n");
  getchar();
  exit(error_code);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<err_exit>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  test   %rdi,%rdi
  je     L7
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D11
type_infered: string

tool: D5: %s

tool: D11: Hit Enter:

assistant: ```c
void err_exit(const char *message, const int error_code) {
  if (message)
    printf("%s", message);
  printf("Hit Enter:\n");
  getchar();
  exit(error_code);
}
```
user: What is the c source code of the assembly code below?

```asm
<err_exit>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  test   %rdi,%rdi
  je     L4
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
L4:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    10b0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D18
type: string

tool: D17: %s

tool: D18: Hit Enter:

assistant: ```c
void err_exit(const char *message, const int error_code) {
  if (message)
    printf("%s", message);
  printf("Hit Enter:\n");
  getchar();
  exit(error_code);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<err_exit>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  test   %rdi,%rdi
  je     L9
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
L9:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    10b0 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D19
type: string

tool: D8: %s

tool: D19: Hit Enter:

assistant: ```c
void err_exit(const char *message, const int error_code) {
  if (message)
    printf("%s", message);
  printf("Hit Enter:\n");
  getchar();
  exit(error_code);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L50
L25:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <upcase@plt>
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <upcase@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jge    L26
  mov    $0xffffffff,%eax
  jmp    L13
L26:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jle    L50
  mov    $0x1,%eax
  jmp    L13
L50:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jg     L25
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int strncasecmp(char *s1, char *s2, int len) {
  char c1, c2;
  while (len-- > 0) {
    c1 = upcase(*s1++);
    c2 = upcase(*s2++);
    if (c1 < c2)
      return -1;
    if (c1 > c2)
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncasecmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    (%rdx,%rsi,1),%r13d
L12:
  mov    %r13d,%eax
  sub    %ebp,%eax
  test   %eax,%eax
  jle    L27
  add    $0x1,%r12
  movsbl -0x1(%r12),%edi
  call   <upcase@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%edi
  call   <upcase@plt>
  cmp    %al,%bl
  jl     L19
  jle    L12
  mov    $0x1,%eax
  jmp    L48
L27:
  mov    $0x0,%eax
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0xffffffff,%eax
  jmp    L48
```

assistant: ```c
int strncasecmp(char *s1, char *s2, int len) {
  char c1, c2;
  while (len-- > 0) {
    c1 = upcase(*s1++);
    c2 = upcase(*s2++);
    if (c1 < c2)
      return -1;
    if (c1 > c2)
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncasecmp>:
  endbr64
  push   %r13
  lea    (%rdx,%rsi,1),%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L23:
  movsbl (%r12),%edi
  add    $0x1,%rbx
  add    $0x1,%r12
  call   <upcase@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%ebp
  call   <upcase@plt>
  cmp    %al,%bpl
  jl     L9
  jg     L8
L27:
  mov    %r13d,%eax
  sub    %ebx,%eax
  test   %eax,%eax
  jg     L23
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strncasecmp(char *s1, char *s2, int len) {
  char c1, c2;
  while (len-- > 0) {
    c1 = upcase(*s1++);
    c2 = upcase(*s2++);
    if (c1 < c2)
      return -1;
    if (c1 > c2)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncasecmp>:
  endbr64
  push   %r13
  lea    (%rdx,%rsi,1),%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl (%r12),%edi
  add    $0x1,%rbx
  add    $0x1,%r12
  call   <upcase@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%ebp
  call   <upcase@plt>
  cmp    %al,%bpl
  jl     L0
  jg     L23
L15:
  mov    %r13d,%eax
  sub    %ebx,%eax
  test   %eax,%eax
  jg     L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strncasecmp(char *s1, char *s2, int len) {
  char c1, c2;
  while (len-- > 0) {
    c1 = upcase(*s1++);
    c2 = upcase(*s2++);
    if (c1 < c2)
      return -1;
    if (c1 > c2)
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nordisrndsq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L26
L36:
  movl   $0x1,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L14
L16:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <edisrnd@plt>
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x20(%rbp)
L14:
  cmpl   $0xc,-0x20(%rbp)
  jle    L16
  movsd  -0x10(%rbp),%xmm0
  movsd  D4(%rip),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  -0x30(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
  addq   $0x8,-0x18(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L36
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: f64

tool: D4: 6

assistant: ```c
double *nordisrndsq(double u, double g, double *r, int n) {
  double *value, *vp, temp;
  int i, count;
  value = (double *)malloc(n * sizeof(double));
  for (count = 0, vp = value; count < n; count++, vp++) {
    for (i = 1, temp = .0; i <= 12; i++)
      temp = temp + edisrnd(r);
    *vp = u + g * (temp - 6.0);
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nordisrndsq>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L8
  mov    %ebx,%ebx
  lea    (%rax,%rbx,8),%r13
  mov    %rax,%r12
L4:
  mov    $0xc,%ebx
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L0:
  mov    %rbp,%rdi
  call   <edisrnd@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L0
  subsd  D0(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  movsd  %xmm0,(%r12)
  add    $0x8,%r12
  cmp    %r13,%r12
  jne    L4
L8:
  mov    %r14,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: f64

tool: D0: 6

assistant: ```c
double *nordisrndsq(double u, double g, double *r, int n) {
  double *value, *vp, temp;
  int i, count;
  value = (double *)malloc(n * sizeof(double));
  for (count = 0, vp = value; count < n; count++, vp++) {
    for (i = 1, temp = .0; i <= 12; i++)
      temp = temp + edisrnd(r);
    *vp = u + g * (temp - 6.0);
  }
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nordisrndsq>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,8),%edi
  sub    $0x20,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  call   <malloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L20
  lea    (%rax,%rbx,8),%r13
  mov    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L21:
  movq   $0x0,0x8(%rsp)
  mov    $0xc,%ebx
  xchg   %ax,%ax
L25:
  mov    %rbp,%rdi
  call   <edisrnd@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L25
  subsd  D9(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  add    $0x8,%r12
  addsd  0x10(%rsp),%xmm0
  movsd  %xmm0,-0x8(%r12)
  cmp    %r13,%r12
  jne    L21
L20:
  add    $0x20,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: f64

tool: D9: 6

assistant: ```c
double *nordisrndsq(double u, double g, double *r, int n) {
  double *value, *vp, temp;
  int i, count;
  value = (double *)malloc(n * sizeof(double));
  for (count = 0, vp = value; count < n; count++, vp++) {
    for (i = 1, temp = .0; i <= 12; i++)
      temp = temp + edisrnd(r);
    *vp = u + g * (temp - 6.0);
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nordisrndsq>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,8),%edi
  sub    $0x20,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  call   <malloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L0
  lea    (%rax,%rbx,8),%r13
  mov    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L13:
  movq   $0x0,0x8(%rsp)
  mov    $0xc,%ebx
  xchg   %ax,%ax
L7:
  mov    %rbp,%rdi
  call   <edisrnd@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L7
  subsd  D7(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  add    $0x8,%r12
  addsd  0x10(%rsp),%xmm0
  movsd  %xmm0,-0x8(%r12)
  cmp    %r13,%r12
  jne    L13
L0:
  add    $0x20,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: f64

tool: D7: 6

assistant: ```c
double *nordisrndsq(double u, double g, double *r, int n) {
  double *value, *vp, temp;
  int i, count;
  value = (double *)malloc(n * sizeof(double));
  for (count = 0, vp = value; count < n; count++, vp++) {
    for (i = 1, temp = .0; i <= 12; i++)
      temp = temp + edisrnd(r);
    *vp = u + g * (temp - 6.0);
  }
  return value;
}
```