ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  lea    D5(%rip),%r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  mov    %r15,%rdi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0x0(,%rdx,4),%rdi
  imul   %rdx,%rdx
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L71
L11:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L11
L71:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L139
L53:
  mov    %rsp,%r12
  test   %eax,%eax
  jle    L10
  shr    $0x2,%rdi
  movl   $0x0,-0x44(%rbp)
  xor    %r14d,%r14d
  mov    %rdi,-0x50(%rbp)
  test   %eax,%eax
  jle    L10
  nop
L60:
  lea    (%r12,%r14,4),%r13
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %r13,%rsi
  mov    %r15,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L21
  addl   $0x1,-0x44(%rbp)
  mov    -0x44(%rbp),%ecx
  cmp    %ecx,%eax
  jle    L106
  add    -0x50(%rbp),%r14
  test   %eax,%eax
  jg     L60
L10:
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L113:
  sub    %r9d,%r8d
  mov    %r15,%rdi
  mov    %r8d,%esi
  neg    %esi
  cmovs  %r8d,%esi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L139:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L53
L83:
  call   <__stack_chk_fail@plt>
L106:
  test   %eax,%eax
  jle    L10
  mov    -0x50(%rbp),%rdi
  xor    %r8d,%r8d
  xor    %edx,%edx
  lea    0x1(%rdi),%rsi
  nopl   (%rax)
L111:
  movslq %edx,%rcx
  add    $0x1,%edx
  imul   %rsi,%rcx
  add    (%r12,%rcx,4),%r8d
  cmp    %edx,%eax
  jne    L111
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  lea    -0x1(%rax),%r10d
  nopl   0x0(%rax,%rax,1)
L76:
  movslq %ecx,%rsi
  imul   -0x50(%rbp),%rsi
  mov    %r10d,%edx
  sub    %ecx,%edx
  add    $0x1,%ecx
  movslq %edx,%rdx
  add    %rsi,%rdx
  add    (%r12,%rdx,4),%r9d
  cmp    %ecx,%eax
  jne    L76
  jmp    L113
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: %d

assistant: ```c
int main() {
  int n, i, j, r = 0, t = 0;
  scanf("%d", &n);
  int a[n][n];
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", &a[i][j]);
    }
  }
  for (i = 0; i < n; i++)
    r = a[i][i] + r;
  for (i = 0; i < n; i++)
    t = a[i][n - i - 1] + t;
  printf("%d", abs(r - t));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_dynamic_vector_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_dynamic_vector_matrix(m, nrl, nrh, ncl, nch) struct dynamic_vector ***m;
long nch, ncl, nrh, nrl;
{
  free((char *)(m[nrl] + ncl - 1));
  free((char *)(m + nrl - 1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<free_dynamic_vector_matrix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x0(,%rsi,8),%rbp
  mov    (%rdi,%rsi,8),%rax
  lea    -0x8(%rax,%rcx,8),%rdi
  call   <free@plt>
  lea    -0x8(%rbx,%rbp,1),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_dynamic_vector_matrix(m, nrl, nrh, ncl, nch) struct dynamic_vector ***m;
long nch, ncl, nrh, nrl;
{
  free((char *)(m[nrl] + ncl - 1));
  free((char *)(m + nrl - 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<free_dynamic_vector_matrix>:
  endbr64
  push   %rbp
  lea    0x0(,%rsi,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi,%rsi,8),%rax
  lea    -0x8(%rax,%rcx,8),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  lea    -0x8(%rbx,%rbp,1),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_dynamic_vector_matrix(m, nrl, nrh, ncl, nch) struct dynamic_vector ***m;
long nch, ncl, nrh, nrl;
{
  free((char *)(m[nrl] + ncl - 1));
  free((char *)(m + nrl - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<free_dynamic_vector_matrix>:
  endbr64
  push   %rbp
  lea    0x0(,%rsi,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi,%rsi,8),%rax
  lea    -0x8(%rax,%rcx,8),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  lea    -0x8(%rbx,%rbp,1),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_dynamic_vector_matrix(m, nrl, nrh, ncl, nch) struct dynamic_vector ***m;
long nch, ncl, nrh, nrl;
{
  free((char *)(m[nrl] + ncl - 1));
  free((char *)(m + nrl - 1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <month_name@plt>
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0xc,-0x4(%rbp)
  jle    L18
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string
name: disassemble_data
arguments: tag: D8
type: string

tool: D2: %d is %s


tool: D8: 
Press any key to end...

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 13; i++)
    printf("%d is %s\n", i, month_name(i));
  printf("\nPress any key to end...");
  getchar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D9(%rip),%rbp
L6:
  mov    %ebx,%edi
  call   <month_name@plt>
  mov    %rax,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xd,%ebx
  jne    L6
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string
name: unpack_data
arguments: data_tag: D17
datatype: string

tool: D9: %d is %s


tool: D17: 
Press any key to end...

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 13; i++)
    printf("%d is %s\n", i, month_name(i));
  printf("\nPress any key to end...");
  getchar();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edi
  call   <month_name@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xd,%ebx
  jne    L0
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type_guessed: string
name: read_data
arguments: data_tag: D17
type_guessed: string

tool: D14: %d is %s


tool: D17: 
Press any key to end...

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 13; i++)
    printf("%d is %s\n", i, month_name(i));
  printf("\nPress any key to end...");
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  call   <month_name@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xd,%ebx
  jne    L9
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D16: %d is %s


tool: D19: 
Press any key to end...

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 13; i++)
    printf("%d is %s\n", i, month_name(i));
  printf("\nPress any key to end...");
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<primitiveSmallInteger_GreaterThanOrEqual_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L37
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L37
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  mov    -0x4(%rbp),%eax
  sar    %eax
  or     $0xc0000000,%eax
  mov    %eax,%edx
  jmp    L77
L15:
  mov    -0x4(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
L77:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L35
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    %eax
  or     $0xc0000000,%eax
  jmp    L0
L35:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    %eax
L0:
  cmp    %eax,%edx
  jl     L42
  mov    $0x28,%eax
  jmp    L68
L42:
  mov    $0x50,%eax
  jmp    L68
L37:
  mov    $0x4,%eax
L68:
  pop    %rbp
  ret
```

assistant: ```c
int primitiveSmallInteger_GreaterThanOrEqual_(int receiver, int *arguments) {
  if ((receiver & 1) && (arguments[0] & 1)) {
    return ((receiver & 0x80000000) ? (((-1 << 31) | receiver) >> 1) : (receiver >> 1)) >= ((arguments[0] & 0x80000000) ? (((-1 << 31) | arguments[0]) >> 1) : (arguments[0] >> 1)) ? (10 << 2) : (20 << 2);
  }
  return (1 << 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<primitiveSmallInteger_GreaterThanOrEqual_>:
  endbr64
  mov    $0x4,%eax
  test   $0x1,%dil
  je     L11
  mov    (%rsi),%edx
  test   $0x1,%dl
  jne    L25
L11:
  ret
L25:
  mov    %edi,%eax
  sar    %eax
  or     $0xc0000000,%eax
  mov    %edi,%ecx
  sar    %ecx
  test   %edi,%edi
  cmovs  %eax,%ecx
  mov    %edx,%esi
  sar    %esi
  or     $0xc0000000,%esi
  mov    %edx,%eax
  sar    %eax
  test   %edx,%edx
  cmovs  %esi,%eax
  cmp    %eax,%ecx
  mov    $0x28,%eax
  mov    $0x50,%edx
  cmovl  %edx,%eax
  jmp    L11
```

assistant: ```c
int primitiveSmallInteger_GreaterThanOrEqual_(int receiver, int *arguments) {
  if ((receiver & 1) && (arguments[0] & 1)) {
    return ((receiver & 0x80000000) ? (((-1 << 31) | receiver) >> 1) : (receiver >> 1)) >= ((arguments[0] & 0x80000000) ? (((-1 << 31) | arguments[0]) >> 1) : (arguments[0] >> 1)) ? (10 << 2) : (20 << 2);
  }
  return (1 << 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<primitiveSmallInteger_GreaterThanOrEqual_>:
  endbr64
  mov    $0x4,%eax
  test   $0x1,%dil
  je     L3
  mov    (%rsi),%edx
  test   $0x1,%dl
  jne    L17
L3:
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  sar    %edi
  sar    %edx
  mov    $0x28,%eax
  cmp    %edx,%edi
  mov    $0x50,%edx
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int primitiveSmallInteger_GreaterThanOrEqual_(int receiver, int *arguments) {
  if ((receiver & 1) && (arguments[0] & 1)) {
    return ((receiver & 0x80000000) ? (((-1 << 31) | receiver) >> 1) : (receiver >> 1)) >= ((arguments[0] & 0x80000000) ? (((-1 << 31) | arguments[0]) >> 1) : (arguments[0] >> 1)) ? (10 << 2) : (20 << 2);
  }
  return (1 << 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<primitiveSmallInteger_GreaterThanOrEqual_>:
  endbr64
  mov    $0x4,%eax
  test   $0x1,%dil
  je     L12
  mov    (%rsi),%edx
  test   $0x1,%dl
  jne    L1
L12:
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  sar    %edi
  sar    %edx
  mov    $0x28,%eax
  cmp    %edx,%edi
  mov    $0x50,%edx
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int primitiveSmallInteger_GreaterThanOrEqual_(int receiver, int *arguments) {
  if ((receiver & 1) && (arguments[0] & 1)) {
    return ((receiver & 0x80000000) ? (((-1 << 31) | receiver) >> 1) : (receiver >> 1)) >= ((arguments[0] & 0x80000000) ? (((-1 << 31) | arguments[0]) >> 1) : (arguments[0] >> 1)) ? (10 << 2) : (20 << 2);
  }
  return (1 << 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sb_hash_lang>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  add    %edx,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t sb_hash_lang(uint32_t h, uint32_t lang) {
  h ^= (h << 5) + lang + (h >> 2);
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sb_hash_lang>:
  endbr64
  mov    %edi,%eax
  shl    $0x5,%eax
  add    %esi,%eax
  mov    %edi,%edx
  sar    $0x2,%edx
  add    %edx,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
uint32_t sb_hash_lang(uint32_t h, uint32_t lang) {
  h ^= (h << 5) + lang + (h >> 2);
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sb_hash_lang>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  shl    $0x5,%eax
  sar    $0x2,%edx
  add    %esi,%eax
  add    %edx,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
uint32_t sb_hash_lang(uint32_t h, uint32_t lang) {
  h ^= (h << 5) + lang + (h >> 2);
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<sb_hash_lang>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  shl    $0x5,%eax
  sar    $0x2,%edx
  add    %esi,%eax
  add    %edx,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
uint32_t sb_hash_lang(uint32_t h, uint32_t lang) {
  h ^= (h << 5) + lang + (h >> 2);
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x7f80,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L36:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L0:
  cmpl   $0xff,-0x10(%rbp)
  jle    L36
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <reduction_simd@plt>
  cmp    %eax,-0xc(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L28
L17:
  mov    $0x1,%eax
L28:
  leave
  ret
```

assistant: ```c
int main() {
  int *a = (int *)malloc(256 * sizeof(int));
  int i, s = (256 - 1) * 256 / 2;
  for (i = 0; i < 256; i++) {
    a[i] = i;
  }
  if (s == reduction_simd(a))
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rcx
  mov    $0x0,%edx
L6:
  mov    %edx,(%rcx)
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    $0x100,%edx
  jne    L6
  call   <reduction_simd@plt>
  cmp    $0x7f80,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int *a = (int *)malloc(256 * sizeof(int));
  int i, s = (256 - 1) * 256 / 2;
  for (i = 0; i < 256; i++) {
    a[i] = i;
  }
  if (s == reduction_simd(a))
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x400,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edx,%edx
  mov    %rax,%rdi
  mov    %rax,%rcx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %edx,(%rcx)
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    $0x100,%edx
  jne    L1
  call   <reduction_simd@plt>
  cmp    $0x7f80,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int main() {
  int *a = (int *)malloc(256 * sizeof(int));
  int i, s = (256 - 1) * 256 / 2;
  for (i = 0; i < 256; i++) {
    a[i] = i;
  }
  if (s == reduction_simd(a))
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x400,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  movdqa D10(%rip),%xmm0
  movdqa D6(%rip),%xmm2
  mov    %rax,%rdi
  mov    %rax,%rdx
  lea    0x400(%rax),%rcx
  nop
L2:
  movdqa %xmm0,%xmm1
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rdx)
  cmp    %rdx,%rcx
  jne    L2
  call   <reduction_simd@plt>
  cmp    $0x7f80,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D6
type: byte[16]

tool: {"D10": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D6": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int *a = (int *)malloc(256 * sizeof(int));
  int i, s = (256 - 1) * 256 / 2;
  for (i = 0; i < 256; i++) {
    a[i] = i;
  }
  if (s == reduction_simd(a))
    return 0;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timespec_addms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  cltq
  sub    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  imul   $0xf4240,%rax,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  movabs $0x112e0be826d694b3,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x1a,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    %esi,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  movabs $0x112e0be826d694b3,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x1a,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca00,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void timespec_addms(struct timespec *ts, long ms) {
  int sec = ms / 1000;
  ms = ms - sec * 1000;
  ts->tv_nsec += ms * 1000000;
  ts->tv_sec += ts->tv_nsec / 1000000000 + sec;
  ts->tv_nsec = ts->tv_nsec % 1000000000;
}
```
user: What is the c source code of the assembly code below:

```asm
<timespec_addms>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x7,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3e8,%edx,%eax
  cltq
  sub    %rax,%rsi
  imul   $0xf4240,%rsi,%rsi
  add    (%rdi),%rsi
  mov    %edx,%ecx
  add    0x8(%rdi),%ecx
  movabs $0x112e0be826d694b3,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x1a,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  add    %edx,%ecx
  mov    %ecx,0x8(%rdi)
  imul   $0x3b9aca00,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void timespec_addms(struct timespec *ts, long ms) {
  int sec = ms / 1000;
  ms = ms - sec * 1000;
  ts->tv_nsec += ms * 1000000;
  ts->tv_sec += ts->tv_nsec / 1000000000 + sec;
  ts->tv_nsec = ts->tv_nsec % 1000000000;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timespec_addms>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rsi,%rax
  mov    0x8(%rdi),%ecx
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  imul   $0x3e8,%edx,%eax
  add    %edx,%ecx
  movabs $0x112e0be826d694b3,%rdx
  cltq
  sub    %rax,%rsi
  imul   $0xf4240,%rsi,%rsi
  add    (%rdi),%rsi
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x1a,%rdx
  sub    %rax,%rdx
  add    %edx,%ecx
  imul   $0x3b9aca00,%rdx,%rdx
  mov    %ecx,0x8(%rdi)
  sub    %rdx,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void timespec_addms(struct timespec *ts, long ms) {
  int sec = ms / 1000;
  ms = ms - sec * 1000;
  ts->tv_nsec += ms * 1000000;
  ts->tv_sec += ts->tv_nsec / 1000000000 + sec;
  ts->tv_nsec = ts->tv_nsec % 1000000000;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<timespec_addms>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rsi,%rax
  mov    0x8(%rdi),%ecx
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  imul   $0x3e8,%edx,%eax
  add    %edx,%ecx
  movabs $0x112e0be826d694b3,%rdx
  cltq
  sub    %rax,%rsi
  imul   $0xf4240,%rsi,%rsi
  add    (%rdi),%rsi
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x1a,%rdx
  sub    %rax,%rdx
  add    %edx,%ecx
  imul   $0x3b9aca00,%rdx,%rdx
  mov    %ecx,0x8(%rdi)
  sub    %rdx,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void timespec_addms(struct timespec *ts, long ms) {
  int sec = ms / 1000;
  ms = ms - sec * 1000;
  ts->tv_nsec += ms * 1000000;
  ts->tv_sec += ts->tv_nsec / 1000000000 + sec;
  ts->tv_nsec = ts->tv_nsec % 1000000000;
}
```
user: What is the c source code of the assembly code below?

```asm
<mystrlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L14
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L12
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  jmp    L16
L12:
  mov    -0x10(%rbp),%rax
L16:
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L14:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t mystrlcpy(char *dst, const char *src, size_t size) {
  size_t ret = strlen(src);
  if (size) {
    size_t len = (ret >= size) ? size - 1 : ret;
    memcpy(dst, src, len);
    dst[len] = '\0';
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mystrlcpy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L8
  lea    -0x1(%rbp),%rax
  cmp    %rbp,%rbx
  cmovb  %rbx,%rax
  mov    %rax,%rbp
  mov    %rax,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbp,1)
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t mystrlcpy(char *dst, const char *src, size_t size) {
  size_t ret = strlen(src);
  if (size) {
    size_t len = (ret >= size) ? size - 1 : ret;
    memcpy(dst, src, len);
    dst[len] = '\0';
  }
  return ret;
}
```