user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D64(%rip),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x28(%rbp),%rsi
  lea    -0x38(%rbp),%rcx
  lea    -0x40(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rsi,%r8
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  mov    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L35
L54:
  lea    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    D32(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1,(%rax)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
L35:
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jne    L54
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   $0x1,(%rax)
  movq   $0x0,-0x30(%rbp)
  jmp    L12
L59:
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    -0x38(%rbp),%rcx
  sub    %rcx,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  lea    0x3b9aca07(%rax),%rcx
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
L46:
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x30(%rbp)
L12:
  mov    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  cmp    %rax,%rdx
  jl     L59
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D64
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D32
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D60
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string

tool: D64: r

tool: D3: quacau.inp

tool: D10: %ld %ld %Ld

tool: D32: %ld

tool: D27: w

tool: D60: quacau.out

tool: D19: %Ld


assistant: ```c
int main() {
  FILE *f = fopen("quacau.inp", "r");
  long n, m, i;
  long long k, *ways;
  char *broken;
  fscanf(f, "%ld %ld %Ld", &n, &m, &k);
  broken = calloc(n + 1, sizeof(char));
  for (; k; k--) {
    fscanf(f, "%ld", &i);
    broken[i] = 1;
  }
  fclose(f);
  ways = (long long *)calloc(n + m + 1, sizeof(long long)) + m;
  *ways = 1;
  for (i = 0; i < n; i++) {
    k = (ways[i] + k - ways[i - m] + 1000000007) % 1000000007;
    if (!broken[i + 1])
      ways[i + 1] = k;
  }
  f = fopen("quacau.out", "w");
  fprintf(f, "%Ld\n", ways[n]);
  fclose(f);
  return 0;
}
```