ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<r_reflection>:
  endbr64
  test   %edx,%edx
  jle    L15
  movslq %edx,%r9
  xor    %r8d,%r8d
  lea    -0x1(%r9),%r11
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r11,%r10
  xor    %eax,%eax
  sub    %r8,%r10
L14:
  mov    (%rdi,%rax,8),%rdx
  movzbl (%rdx,%r10,1),%ecx
  mov    (%rsi,%rax,8),%rdx
  add    $0x1,%rax
  mov    %cl,(%rdx,%r8,1)
  cmp    %rax,%r9
  jne    L14
  add    $0x1,%r8
  cmp    %r8,%r9
  jne    L6
L15:
  ret
```

assistant: ```c
void r_reflection(char **arr, char **arr2, int n) {
  int i, j;
  for (j = n - 1; j >= 0; j--)
    for (i = 0; i < n; i++)
      arr2[i][n - j - 1] = arr[i][j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverseSwapPointer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverseSwapPointer(char *string) {
  int lengthVal = length(string);
  for (int i = 0; i < (lengthVal / 2); i++) {
    char temp = string[i];
    string[i] = string[lengthVal - i - 1];
    string[lengthVal - i - 1] = temp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reverseSwapPointer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <length@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L3
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  mov    $0x0,%eax
L8:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%rdx),%esi
  mov    %sil,(%rbx,%rax,1)
  mov    %cl,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%edi
  jg     L8
L3:
  pop    %rbx
  ret
```

assistant: ```c
void reverseSwapPointer(char *string) {
  int lengthVal = length(string);
  for (int i = 0; i < (lengthVal / 2); i++) {
    char temp = string[i];
    string[i] = string[lengthVal - i - 1];
    string[lengthVal - i - 1] = temp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverseSwapPointer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <length@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L15
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  movzbl (%rdx),%esi
  movzbl (%rbx,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rbx,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%edi
  jg     L1
L15:
  pop    %rbx
  ret
```

assistant: ```c
void reverseSwapPointer(char *string) {
  int lengthVal = length(string);
  for (int i = 0; i < (lengthVal / 2); i++) {
    char temp = string[i];
    string[i] = string[lengthVal - i - 1];
    string[lengthVal - i - 1] = temp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverseSwapPointer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <length@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L8
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  movzbl (%rdx),%esi
  movzbl (%rbx,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rbx,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%edi
  jg     L3
L8:
  pop    %rbx
  ret
```

assistant: ```c
void reverseSwapPointer(char *string) {
  int lengthVal = length(string);
  for (int i = 0; i < (lengthVal / 2); i++) {
    char temp = string[i];
    string[i] = string[lengthVal - i - 1];
    string[lengthVal - i - 1] = temp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sub_bym>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bym@plt>
  mov    $0x0,%eax
  call   <sub@plt>
  nop
  leave
  ret
```

assistant: ```c
void sub_bym(uint32_t x) {
  bym(x);
  sub();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sub_bym>:
  endbr64
  sub    $0x8,%rsp
  call   <bym@plt>
  mov    $0x0,%eax
  call   <sub@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sub_bym(uint32_t x) {
  bym(x);
  sub();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sub_bym>:
  endbr64
  sub    $0x8,%rsp
  call   <bym@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <sub@plt>
```

assistant: ```c
void sub_bym(uint32_t x) {
  bym(x);
  sub();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6d202c6f6c6c6548,%rax
  movabs $0x6e696c7261642079,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movabs $0x21656669772067,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(void) {
  char s[] = "Hello, my darling wife!";
  vprintf(s);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6d202c6f6c6c6548,%rax
  movabs $0x6e696c7261642079,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x21656669772067,%rax
  mov    %rax,0x10(%rsp)
  mov    %rsp,%rdi
  call   <vprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char s[] = "Hello, my darling wife!";
  vprintf(s);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movabs $0x21656669772067,%rax
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <vprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: byte[16]

tool: {"D1": [0x48,0x65,0x6c,0x6c,0x6f,0x2c,0x20,0x6d,0x79,0x20,0x64,0x61,0x72,0x6c,0x69,0x6e]}

assistant: ```c
int main(void) {
  char s[] = "Hello, my darling wife!";
  vprintf(s);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movabs $0x21656669772067,%rax
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <vprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: byte[16]

tool: {"D1": [0x48,0x65,0x6c,0x6c,0x6f,0x2c,0x20,0x6d,0x79,0x20,0x64,0x61,0x72,0x6c,0x69,0x6e]}

assistant: ```c
int main(void) {
  char s[] = "Hello, my darling wife!";
  vprintf(s);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_str_is_numeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L24
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L49
L24:
  mov    $0x0,%eax
  jmp    L21
L49:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    $0x1,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int ft_str_is_numeric(char *str) {
  int x;
  x = 0;
  while (str[x]) {
    if ((str[x] < 48) || (str[x] > 57))
      return (0);
    x++;
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_str_is_numeric>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  add    $0x1,%rdi
L29:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L5
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L29
  mov    $0x1,%eax
  ret
L8:
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_str_is_numeric(char *str) {
  int x;
  x = 0;
  while (str[x]) {
    if ((str[x] < 48) || (str[x] > 57))
      return (0);
    x++;
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_str_is_numeric>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  add    $0x1,%rdi
  jmp    L14
  nopl   0x0(%rax)
L6:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L4
L14:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L6
  xor    %eax,%eax
  ret
  nopl   (%rax)
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ft_str_is_numeric(char *str) {
  int x;
  x = 0;
  while (str[x]) {
    if ((str[x] < 48) || (str[x] > 57))
      return (0);
    x++;
  }
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_str_is_numeric>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L27
  add    $0x1,%rdi
  jmp    L22
  nopl   0x0(%rax)
L4:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L27
L22:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L4
  xor    %eax,%eax
  ret
  nopl   (%rax)
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ft_str_is_numeric(char *str) {
  int x;
  x = 0;
  while (str[x]) {
    if ((str[x] < 48) || (str[x] > 57))
      return (0);
    x++;
  }
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7c(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L6
L8:
  addl   $0x1,-0x7c(%rbp)
  addq   $0x1,-0x78(%rbp)
L6:
  mov    -0x78(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x7c(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D11
datatype: string

tool: D1: Enter a string: 

tool: D11: The length is: %d

assistant: ```c
int main(void) {
  int len = 0;
  char str[100];
  char *ptr = str;
  printf("Enter a string: ");
  gets(str);
  while (*ptr != '\0') {
    len++;
    ptr++;
  }
  printf("The length is: %d", len);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  call   <gets@plt>
  cmpb   $0x0,0x10(%rsp)
  je     L18
  lea    0x10(%rsp),%rax
  mov    $0x71,%edx
  lea    0x80(%rsp),%rcx
  mov    %rcx,0x8(%rsp)
  sub    0x8(%rsp),%edx
L13:
  lea    (%rdx,%rax,1),%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L13
L25:
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x88,%rsp
  ret
L18:
  mov    $0x0,%esi
  jmp    L25
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
datatype: string
name: read_data
arguments: data_label: D10
datatype: string

tool: D12: Enter a string: 

tool: D10: The length is: %d

assistant: ```c
int main(void) {
  int len = 0;
  char str[100];
  char *ptr = str;
  printf("Enter a string: ");
  gets(str);
  while (*ptr != '\0') {
    len++;
    ptr++;
  }
  printf("The length is: %d", len);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L1
  mov    $0x1,%edx
  mov    %rbx,%rax
  sub    %ebx,%edx
L17:
  lea    (%rdx,%rax,1),%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L17
L24:
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  xor    %esi,%esi
  jmp    L24
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
type: string
name: parse_data
arguments: data_label: D4
type: string

tool: D12: Enter a string: 

tool: D4: The length is: %d

assistant: ```c
int main(void) {
  int len = 0;
  char str[100];
  char *ptr = str;
  printf("Enter a string: ");
  gets(str);
  while (*ptr != '\0') {
    len++;
    ptr++;
  }
  printf("The length is: %d", len);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L38
  mov    $0x1,%edx
  mov    %rbx,%rax
  sub    %ebx,%edx
L17:
  lea    (%rdx,%rax,1),%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L17
L2:
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L38:
  xor    %esi,%esi
  jmp    L2
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D18
type: string

tool: D13: Enter a string: 

tool: D18: The length is: %d

assistant: ```c
int main(void) {
  int len = 0;
  char str[100];
  char *ptr = str;
  printf("Enter a string: ");
  gets(str);
  while (*ptr != '\0') {
    len++;
    ptr++;
  }
  printf("The length is: %d", len);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ciao_at_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%edi
  call   <fflush@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void ciao_at_exit(int result) {
  fflush(NULL);
  exit(result);
}
```
user: What is the c source code of the assembly code below:

```asm
<ciao_at_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edi
  call   <fflush@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void ciao_at_exit(int result) {
  fflush(NULL);
  exit(result);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ciao_at_exit>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <fflush@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

assistant: ```c
void ciao_at_exit(int result) {
  fflush(NULL);
  exit(result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ciao_at_exit>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <fflush@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

assistant: ```c
void ciao_at_exit(int result) {
  fflush(NULL);
  exit(result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiplyMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L50:
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L6:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L57:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm1
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L57
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L6
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L50
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void multiplyMatrix(double first[][3], double second[][3], double result[][3], int rows1, int cols2, int rowcol) {
  int i, j, k;
  for (i = 0; i < rows1; ++i) {
    for (j = 0; j < cols2; ++j) {
      result[i][j] = 0;
      for (k = 0; k < rowcol; ++k) {
        result[i][j] = result[i][j] + first[i][k] * second[k][j];
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<multiplyMatrix>:
  endbr64
  test   %ecx,%ecx
  jle    L42
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %r8d,%ebp
  lea    -0x1(%r8),%eax
  lea    0x8(%rdx,%rax,8),%r11
  lea    -0x1(%rcx),%ecx
  lea    (%rcx,%rcx,2),%rcx
  add    %rax,%rcx
  lea    0x20(%rdx,%rcx,8),%r12
  not    %rax
  lea    0x0(,%rax,8),%r8
  jmp    L41
L66:
  mov    %rsi,%rcx
  movq   $0x0,(%rsi)
  test   %r9d,%r9d
  jle    L45
  mov    %r10,%rdx
  mov    $0x0,%eax
L8:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x1,%rax
  add    $0x18,%rdx
  cmp    %eax,%r9d
  jg     L8
L45:
  add    $0x8,%rsi
  add    $0x8,%r10
  cmp    %r11,%rsi
  jne    L66
L70:
  add    $0x18,%r11
  add    $0x18,%rdi
  cmp    %r12,%r11
  je     L58
L41:
  lea    (%r8,%r11,1),%rsi
  mov    %rbx,%r10
  test   %ebp,%ebp
  jg     L66
  jmp    L70
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  ret
```

assistant: ```c
void multiplyMatrix(double first[][3], double second[][3], double result[][3], int rows1, int cols2, int rowcol) {
  int i, j, k;
  for (i = 0; i < rows1; ++i) {
    for (j = 0; j < cols2; ++j) {
      result[i][j] = 0;
      for (k = 0; k < rowcol; ++k) {
        result[i][j] = result[i][j] + first[i][k] * second[k][j];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<multiplyMatrix>:
  endbr64
  test   %ecx,%ecx
  jle    L7
  push   %r12
  mov    %rdx,%rax
  mov    $0xfffffffffffffff8,%r11
  mov    %rsi,%r10
  push   %rbp
  mov    %rdi,%rsi
  pxor   %xmm2,%xmm2
  push   %rbx
  mov    %r8d,%ebx
  lea    -0x1(%r8),%r8d
  lea    0x0(,%r8,8),%r12
  lea    0x8(%rdx,%r12,1),%rbp
  lea    -0x1(%rcx),%edx
  sub    %r12,%r11
  lea    (%rdx,%rdx,2),%rdx
  add    %r8,%rdx
  lea    0x20(%rax,%rdx,8),%r8
  nopw   0x0(%rax,%rax,1)
L27:
  lea    (%r11,%rbp,1),%rcx
  mov    %r10,%rdi
  test   %ebx,%ebx
  jle    L8
L38:
  movq   $0x0,(%rcx)
  test   %r9d,%r9d
  jle    L14
  mov    %rdi,%rdx
  xor    %eax,%eax
  movapd %xmm2,%xmm1
L17:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x1,%rax
  add    $0x18,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %eax,%r9d
  jg     L17
L14:
  add    $0x8,%rcx
  add    $0x8,%rdi
  cmp    %rbp,%rcx
  jne    L38
L8:
  add    $0x18,%rbp
  add    $0x18,%rsi
  cmp    %r8,%rbp
  jne    L27
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  ret
```

assistant: ```c
void multiplyMatrix(double first[][3], double second[][3], double result[][3], int rows1, int cols2, int rowcol) {
  int i, j, k;
  for (i = 0; i < rows1; ++i) {
    for (j = 0; j < cols2; ++j) {
      result[i][j] = 0;
      for (k = 0; k < rowcol; ++k) {
        result[i][j] = result[i][j] + first[i][k] * second[k][j];
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<multiplyMatrix>:
  endbr64
  test   %ecx,%ecx
  jle    L19
  test   %r8d,%r8d
  jle    L19
  mov    %rsi,%r11
  movslq %ecx,%rcx
  lea    -0x1(%r8),%eax
  push   %rbp
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdx,%r10
  lea    (%rcx,%rcx,2),%rbp
  lea    0x8(%r11,%rax,8),%rdi
  xor    %ebx,%ebx
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    %r11,%rdx
  mov    %r10,%rax
L30:
  movq   $0x0,(%rax)
  test   %r9d,%r9d
  jle    L39
  movsd  (%rdx),%xmm0
  mulsd  (%rsi),%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rax)
  cmp    $0x1,%r9d
  je     L39
  movsd  0x8(%rsi),%xmm1
  mulsd  0x18(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  cmp    $0x2,%r9d
  je     L39
  movsd  0x10(%rsi),%xmm1
  mulsd  0x30(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  cmp    $0x3,%r9d
  je     L39
  movsd  0x18(%rsi),%xmm1
  mulsd  0x48(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  cmp    $0x4,%r9d
  je     L39
  mov    %rdx,%r8
  mov    $0x4,%ecx
L12:
  movsd  (%rsi,%rcx,8),%xmm1
  mulsd  0x60(%r8),%xmm1
  add    $0x1,%rcx
  add    $0x18,%r8
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  cmp    %ecx,%r9d
  jg     L12
  nopl   0x0(%rax)
L39:
  add    $0x8,%rdx
  add    $0x8,%rax
  cmp    %rdi,%rdx
  jne    L30
  add    $0x3,%rbx
  add    $0x18,%r10
  add    $0x18,%rsi
  cmp    %rbp,%rbx
  jne    L23
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
void multiplyMatrix(double first[][3], double second[][3], double result[][3], int rows1, int cols2, int rowcol) {
  int i, j, k;
  for (i = 0; i < rows1; ++i) {
    for (j = 0; j < cols2; ++j) {
      result[i][j] = 0;
      for (k = 0; k < rowcol; ++k) {
        result[i][j] = result[i][j] + first[i][k] * second[k][j];
      }
    }
  }
}
```