user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xc,%ecx
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  lea    D29(%rip),%rbx
  sub    $0xb8,%rsp
  movdqa D15(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rsi
  mov    %dx,0x30(%rsp)
  lea    0x3b(%rsp),%rbp
  mov    %rsi,%rdi
  movaps %xmm0,(%rsp)
  movdqa D24(%rip),%xmm0
  movl   $0x0,0x3b(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D23(%rip),%xmm0
  movb   $0x0,0x3f(%rsp)
  movaps %xmm0,0x20(%rsp)
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsbl 0x40(%rsp),%edx
  test   %dl,%dl
  je     L88
  lea    0x41(%rsp),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L82:
  add    $0x1,%rcx
  lea    -0x30(%rax,%rdx,1),%eax
  movsbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L82
  lea    0x3b(%rsp),%rbp
  mov    %rbp,%rsi
  test   %eax,%eax
  je     L88
  nopl   0x0(%rax)
L28:
  movslq %eax,%rdx
  mov    %eax,%ecx
  add    $0x1,%rsi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rsi)
  mov    %edx,%eax
  test   %edx,%edx
  jne    L28
L88:
  mov    $0x4,%r13d
  mov    %rsp,%r12
  nopl   (%rax)
L52:
  movsbl 0x0(%rbp,%r13,1),%eax
  test   %al,%al
  jne    L6
L4:
  sub    $0x1,%r13
  jae    L52
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  sub    $0x30,%eax
  mov    %rbx,%rdi
  cltq
  lea    (%rax,%rax,4),%rsi
  xor    %eax,%eax
  add    %r12,%rsi
  call   <printf@plt>
  test   %r13,%r13
  je     L10
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L4
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: byte[16]
name: disassemble_data
arguments: data_label: D24
data_type: byte[16]
name: disassemble_data
arguments: data_label: D23
data_type: byte[16]

tool: D29: %s

tool: {"D15": [0x6c,0x69,0x6e,0x67,0x00,0x79,0x69,0x00,0x00,0x00,0x65,0x72,0x00,0x00,0x00,0x73]}

tool: {"D24": [0x61,0x6e,0x00,0x00,0x73,0x69,0x00,0x00,0x00,0x77,0x75,0x00,0x00,0x00,0x6c,0x69]}

tool: {"D23": [0x75,0x00,0x00,0x71,0x69,0x00,0x00,0x00,0x62,0x61,0x00,0x00,0x00,0x6a,0x69,0x75]}

assistant: ```c
int main(void) {
  char num[10][5] = {"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"};
  char input[100];
  char output[5];
  int sum = 0;
  int i = 0;
  int j = 0;
  memset(input, 0, sizeof(input) / sizeof(char));
  memset(output, 0, sizeof(output) / sizeof(char));
  scanf("%s", input);
  while (input[i] != '\0') {
    sum += input[i] - '0';
    i++;
  }
  while (sum != 0) {
    output[j] = sum % 10 + '0';
    sum /= 10;
    j++;
  }
  for (int j = 4; j >= 0; j--) {
    if (output[j] != '\0') {
      printf("%s", num[output[j] - '0']);
      if (j != 0) {
        printf(" ");
      }
    }
  }
  return 0;
}
```