ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x3,%r12d
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L47:
  mov    $0x2,%ecx
  nopl   (%rax)
L12:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L11
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jne    L12
  lea    0x2(%rsi),%eax
  cmp    %r12d,%eax
  je     L14
  mov    %r12d,%esi
L11:
  add    $0x1,%r12d
  cmp    $0xb,%ebx
  jne    L47
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %r12d,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r12d,%esi
  jmp    L11
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: [%d;%d]


assistant: ```c
int main() {
  int m, g, tz1, tz2;
  tz1 = 0;
  tz2 = 3;
  for (m = 2; m <= 10;) {
    for (g = 2; g <= tz2 - 1; g++) {
      if (tz2 % g == 0)
        break;
    }
    if (g == tz2) {
      if (tz2 == tz1 + 2) {
        printf("[%d;%d]\n", tz1, tz2);
        m++;
      }
      tz1 = tz2;
    }
    tz2++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x7fffffff,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  long int x = 0x7FFFFFFFL;
  assert(x > 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  long int x = 0x7FFFFFFFL;
  assert(x > 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  long int x = 0x7FFFFFFFL;
  assert(x > 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  long int x = 0x7FFFFFFFL;
  assert(x > 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x118(%rbp)
  lea    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  test   %rax,%rax
  jns    L19
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L19:
  mov    -0x114(%rbp),%eax
  lea    D53(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fdopen@plt>
  mov    %rax,-0x128(%rbp)
  mov    -0x128(%rbp),%rax
  lea    D39(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  lea    -0x100(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1d,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  mov    %ax,(%rdx)
  add    $0x2,%rdx
  mov    %al,(%rdx)
  add    $0x1,%rdx
  mov    -0x118(%rbp),%eax
  lea    D38(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fdopen@plt>
  mov    %rax,-0x120(%rbp)
  lea    -0x110(%rbp),%rdx
  mov    -0x120(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D41
type_infered: string
name: retrieve_data
arguments: tag: D53
type_infered: string
name: retrieve_data
arguments: tag: D39
type_infered: string
name: retrieve_data
arguments: tag: D38
type_infered: string
name: retrieve_data
arguments: tag: D9
type_infered: string
name: retrieve_data
arguments: tag: D23
type_infered: string

tool: D41: pipe

tool: D53: w

tool: D39: Hello_world


tool: D38: r

tool: D9: %s

tool: D23: Pipe read: %s


assistant: ```c
int main() {
  int pipefd[2] = {0};
  if (pipe(pipefd) < 0) {
    perror("pipe");
    exit(1);
  }
  FILE *write_ptr = fdopen(pipefd[1], "w");
  fprintf(write_ptr, "Hello_world\n");
  fflush(write_ptr);
  char read_str[255] = {0};
  FILE *read_ptr = fdopen(pipefd[0], "r");
  fscanf(read_ptr, "%s", read_str);
  printf("Pipe read: %s\n", read_str);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  test   %rax,%rax
  js     L7
L2:
  lea    D36(%rip),%rsi
  mov    0xc(%rsp),%edi
  call   <fdopen@plt>
  mov    %rax,%rbx
  lea    D38(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fflush@plt>
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x20(%rsp),%rdi
  mov    $0x1d,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movw   $0x0,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  lea    D41(%rip),%rsi
  mov    0x8(%rsp),%edi
  call   <fdopen@plt>
  mov    %rax,%rdi
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdx
  lea    D54(%rip),%rsi
  call   <fscanf@plt>
  mov    %rbx,%rsi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x120,%rsp
  pop    %rbx
  ret
L7:
  lea    D33(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D36
datatype: string
name: disassemble_data
arguments: data_label: D38
datatype: string
name: disassemble_data
arguments: data_label: D41
datatype: string
name: disassemble_data
arguments: data_label: D54
datatype: string
name: disassemble_data
arguments: data_label: D48
datatype: string
name: disassemble_data
arguments: data_label: D33
datatype: string

tool: D36: w

tool: D38: Hello_world


tool: D41: r

tool: D54: %s

tool: D48: Pipe read: %s


tool: D33: pipe

assistant: ```c
int main() {
  int pipefd[2] = {0};
  if (pipe(pipefd) < 0) {
    perror("pipe");
    exit(1);
  }
  FILE *write_ptr = fdopen(pipefd[1], "w");
  fprintf(write_ptr, "Hello_world\n");
  fflush(write_ptr);
  char read_str[255] = {0};
  FILE *read_ptr = fdopen(pipefd[0], "r");
  fscanf(read_ptr, "%s", read_str);
  printf("Pipe read: %s\n", read_str);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  call   <pipe@plt>
  test   %rax,%rax
  js     L12
L6:
  mov    0xc(%rsp),%edi
  lea    D11(%rip),%rsi
  call   <fdopen@plt>
  lea    D38(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rbp
  call   <fflush@plt>
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1d,%ecx
  lea    D36(%rip),%rsi
  movaps %xmm0,0x10(%rsp)
  rep stos %rax,%es:(%rdi)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  mov    %ax,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  mov    0x8(%rsp),%edi
  call   <fdopen@plt>
  lea    D41(%rip),%rsi
  mov    %rbp,%rdx
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L12:
  lea    D25(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L6
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D38
data_type: string
name: read_data
arguments: data_label: D36
data_type: string
name: read_data
arguments: data_label: D41
data_type: string
name: read_data
arguments: data_label: D3
data_type: string
name: read_data
arguments: data_label: D25
data_type: string

tool: D11: w

tool: D38: Hello_world


tool: D36: r

tool: D41: %s

tool: D3: Pipe read: %s


tool: D25: pipe

assistant: ```c
int main() {
  int pipefd[2] = {0};
  if (pipe(pipefd) < 0) {
    perror("pipe");
    exit(1);
  }
  FILE *write_ptr = fdopen(pipefd[1], "w");
  fprintf(write_ptr, "Hello_world\n");
  fflush(write_ptr);
  char read_str[255] = {0};
  FILE *read_ptr = fdopen(pipefd[0], "r");
  fscanf(read_ptr, "%s", read_str);
  printf("Pipe read: %s\n", read_str);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  call   <pipe@plt>
  test   %rax,%rax
  js     L11
L16:
  mov    0xc(%rsp),%edi
  lea    D58(%rip),%rsi
  call   <fdopen@plt>
  lea    D36(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rbp
  call   <fflush@plt>
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1d,%ecx
  lea    D39(%rip),%rsi
  movaps %xmm0,0x10(%rsp)
  rep stos %rax,%es:(%rdi)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  mov    %ax,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  mov    0x8(%rsp),%edi
  call   <fdopen@plt>
  lea    D5(%rip),%rsi
  mov    %rbp,%rdx
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L11:
  lea    D34(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L16
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D58
type: string
name: extract_symbolic_data
arguments: data_label: D36
type: string
name: extract_symbolic_data
arguments: data_label: D39
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D34
type: string

tool: D58: w

tool: D36: Hello_world


tool: D39: r

tool: D5: %s

tool: D19: Pipe read: %s


tool: D34: pipe

assistant: ```c
int main() {
  int pipefd[2] = {0};
  if (pipe(pipefd) < 0) {
    perror("pipe");
    exit(1);
  }
  FILE *write_ptr = fdopen(pipefd[1], "w");
  fprintf(write_ptr, "Hello_world\n");
  fflush(write_ptr);
  char read_str[255] = {0};
  FILE *read_ptr = fdopen(pipefd[0], "r");
  fscanf(read_ptr, "%s", read_str);
  printf("Pipe read: %s\n", read_str);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x1,-0x2c(%rbp)
  jne    L13
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  jmp    L16
L13:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L18
L3:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L3
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int rob(int *nums, int size) {
  if (size == 1)
    return nums[0];
  int inFirst = nums[0], exFirst = 0;
  int inNoFirst = 0, exNoFirst = 0;
  for (int i = 1; i < size; i++) {
    int preInFirst = inFirst;
    inFirst = exFirst + nums[i];
    exFirst = preInFirst > exFirst ? preInFirst : exFirst;
    int preInNoFirst = inNoFirst;
    inNoFirst = exNoFirst + nums[i];
    exNoFirst = preInNoFirst > exNoFirst ? preInNoFirst : exNoFirst;
  }
  return inNoFirst > exFirst ? inNoFirst : exFirst;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rob>:
  endbr64
  cmp    $0x1,%esi
  je     L19
  mov    (%rdi),%r9d
  jle    L31
  lea    0x4(%rdi),%rcx
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,4),%r10
  mov    $0x0,%edx
  mov    $0x0,%r8d
  mov    $0x0,%eax
L32:
  mov    (%rcx),%edi
  mov    %r9d,%esi
  lea    (%rdi,%rax,1),%r9d
  cmp    %esi,%eax
  cmovl  %esi,%eax
  mov    %r8d,%esi
  lea    (%rdi,%rdx,1),%r8d
  cmp    %esi,%edx
  cmovl  %esi,%edx
  add    $0x4,%rcx
  cmp    %r10,%rcx
  jne    L32
L33:
  cmp    %r8d,%eax
  cmovl  %r8d,%eax
  ret
L19:
  mov    (%rdi),%eax
  ret
L31:
  mov    $0x0,%r8d
  mov    $0x0,%eax
  jmp    L33
```

assistant: ```c
int rob(int *nums, int size) {
  if (size == 1)
    return nums[0];
  int inFirst = nums[0], exFirst = 0;
  int inNoFirst = 0, exNoFirst = 0;
  for (int i = 1; i < size; i++) {
    int preInFirst = inFirst;
    inFirst = exFirst + nums[i];
    exFirst = preInFirst > exFirst ? preInFirst : exFirst;
    int preInNoFirst = inNoFirst;
    inNoFirst = exNoFirst + nums[i];
    exNoFirst = preInNoFirst > exNoFirst ? preInNoFirst : exNoFirst;
  }
  return inNoFirst > exFirst ? inNoFirst : exFirst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rob>:
  endbr64
  mov    (%rdi),%r8d
  cmp    $0x1,%esi
  je     L6
  jle    L39
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi),%rcx
  xor    %edx,%edx
  xor    %r9d,%r9d
  lea    0x8(%rdi,%rax,4),%r10
  xor    %eax,%eax
  nopl   0x0(%rax)
L21:
  mov    %r8d,%esi
  mov    (%rcx),%edi
  cmp    %esi,%eax
  lea    (%rdi,%rax,1),%r8d
  cmovl  %esi,%eax
  mov    %r9d,%esi
  cmp    %esi,%edx
  lea    (%rdi,%rdx,1),%r9d
  cmovl  %esi,%edx
  add    $0x4,%rcx
  cmp    %rcx,%r10
  jne    L21
  cmp    %r9d,%eax
  cmovge %eax,%r9d
  mov    %r9d,%r8d
L6:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L39:
  xor    %r8d,%r8d
  jmp    L6
```

assistant: ```c
int rob(int *nums, int size) {
  if (size == 1)
    return nums[0];
  int inFirst = nums[0], exFirst = 0;
  int inNoFirst = 0, exNoFirst = 0;
  for (int i = 1; i < size; i++) {
    int preInFirst = inFirst;
    inFirst = exFirst + nums[i];
    exFirst = preInFirst > exFirst ? preInFirst : exFirst;
    int preInNoFirst = inNoFirst;
    inNoFirst = exNoFirst + nums[i];
    exNoFirst = preInNoFirst > exNoFirst ? preInNoFirst : exNoFirst;
  }
  return inNoFirst > exFirst ? inNoFirst : exFirst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rob>:
  endbr64
  mov    (%rdi),%r8d
  cmp    $0x1,%esi
  je     L36
  jle    L34
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi),%rcx
  xor    %edx,%edx
  xor    %r9d,%r9d
  lea    0x8(%rdi,%rax,4),%r10
  xor    %eax,%eax
  nopl   0x0(%rax)
L11:
  mov    %r8d,%esi
  mov    (%rcx),%edi
  cmp    %esi,%eax
  lea    (%rdi,%rax,1),%r8d
  cmovl  %esi,%eax
  mov    %r9d,%esi
  cmp    %esi,%edx
  lea    (%rdi,%rdx,1),%r9d
  cmovl  %esi,%edx
  add    $0x4,%rcx
  cmp    %rcx,%r10
  jne    L11
  cmp    %r9d,%eax
  cmovge %eax,%r9d
  mov    %r9d,%r8d
L36:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L34:
  xor    %r8d,%r8d
  jmp    L36
```

assistant: ```c
int rob(int *nums, int size) {
  if (size == 1)
    return nums[0];
  int inFirst = nums[0], exFirst = 0;
  int inNoFirst = 0, exNoFirst = 0;
  for (int i = 1; i < size; i++) {
    int preInFirst = inFirst;
    inFirst = exFirst + nums[i];
    exFirst = preInFirst > exFirst ? preInFirst : exFirst;
    int preInNoFirst = inNoFirst;
    inNoFirst = exNoFirst + nums[i];
    exNoFirst = preInNoFirst > exNoFirst ? preInNoFirst : exNoFirst;
  }
  return inNoFirst > exFirst ? inNoFirst : exFirst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L75
L50:
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L26
L5:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L40
L14:
  mov    -0x24(%rbp),%eax
  cltq
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%eax
  cltq
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0x24(%rbp),%eax
  cltq
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%eax
  cltq
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L40:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x58(%rbp)
  ja     L14
  movsd  -0x10(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L18
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L18:
  addl   $0x1,-0x20(%rbp)
L26:
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,-0x50(%rbp)
  ja     L5
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x24(%rbp)
L75:
  mov    -0x24(%rbp),%eax
  cltq
  cmp    %rax,-0x48(%rbp)
  ja     L50
  mov    -0x48(%rbp),%rax
  test   %rax,%rax
  js     L59
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L7
L59:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L7:
  movsd  -0x8(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: f64

tool: D7: 1e+200

assistant: ```c
double gd(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  int i, j, k;
  double d, min, dis;
  dis = 0.0;
  for (i = 0; i < numelA; i++) {
    min = 1.0E200;
    for (j = 0; j < numelB; j++) {
      d = 0.0;
      for (k = 0; k < nObjs; k++)
        d += (A[i * nObjs + k] - B[j * nObjs + k]) * (A[i * nObjs + k] - B[j * nObjs + k]);
      if (d < min)
        min = d;
    }
    dis += sqrt(min);
  }
  return dis / (double)(numelA);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rdx,%r15
  mov    %rcx,0x10(%rsp)
  test   %rdx,%rdx
  je     L46
  mov    %rdi,%rbp
  mov    %r8,%r12
  lea    0x0(,%r8,8),%rbx
  mov    $0x0,%r14d
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  mov    %ecx,%r13d
  jmp    L56
L51:
  movsd  0x0(%rbp,%rax,1),%xmm0
  subsd  (%rdx,%rax,1),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %rbx,%rax
  jne    L51
L7:
  minsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  add    $0x1,%ecx
  add    %rbx,%rdx
  cmp    %r13d,%ecx
  je     L83
L31:
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  test   %r12,%r12
  jne    L51
  jmp    L7
L36:
  movsd  D13(%rip),%xmm2
L83:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%r14
  add    %rbx,%rbp
  cmp    %r14,%r15
  je     L0
L56:
  cmpq   $0x0,0x10(%rsp)
  je     L36
  mov    0x18(%rsp),%rdx
  movsd  D13(%rip),%xmm2
  mov    $0x0,%ecx
  jmp    L31
L46:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L0:
  test   %r15,%r15
  js     L89
  pxor   %xmm1,%xmm1
  cvtsi2sd %r15,%xmm1
L8:
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L89:
  mov    %r15,%rax
  shr    %rax
  and    $0x1,%r15d
  or     %r15,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_infered: f64

tool: D13: 1e+200

assistant: ```c
double gd(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  int i, j, k;
  double d, min, dis;
  dis = 0.0;
  for (i = 0; i < numelA; i++) {
    min = 1.0E200;
    for (j = 0; j < numelB; j++) {
      d = 0.0;
      for (k = 0; k < nObjs; k++)
        d += (A[i * nObjs + k] - B[j * nObjs + k]) * (A[i * nObjs + k] - B[j * nObjs + k]);
      if (d < min)
        min = d;
    }
    dis += sqrt(min);
  }
  return dis / (double)(numelA);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rdx,0x10(%rsp)
  test   %rdx,%rdx
  je     L44
  pxor   %xmm3,%xmm3
  mov    %rdi,%r14
  mov    %rcx,%r12
  mov    %r8,%r15
  lea    0x0(,%r8,8),%rbx
  xor    %ebp,%ebp
  movapd %xmm3,%xmm4
  mov    %ecx,%r13d
  nopl   0x0(%rax,%rax,1)
L75:
  test   %r12,%r12
  je     L17
  mov    D10(%rip),%rax
  mov    0x18(%rsp),%rdx
  xor    %ecx,%ecx
  movq   %rax,%xmm2
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  movapd %xmm3,%xmm1
  test   %r15,%r15
  je     L50
  nopl   0x0(%rax,%rax,1)
L40:
  movsd  (%r14,%rax,1),%xmm0
  subsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rax
  jne    L40
L50:
  minsd  %xmm2,%xmm1
  add    $0x1,%ecx
  add    %rbx,%rdx
  movapd %xmm1,%xmm2
  cmp    %ecx,%r13d
  jne    L25
L78:
  movapd %xmm2,%xmm0
  movsd  %xmm4,0x8(%rsp)
  add    $0x1,%rbp
  add    %rbx,%r14
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm4
  cmp    0x10(%rsp),%rbp
  cvtsi2sd %rax,%xmm0
  pxor   %xmm3,%xmm3
  addsd  %xmm0,%xmm4
  jne    L75
L20:
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x10(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm0,%xmm4
  movapd %xmm4,%xmm0
  ret
L17:
  mov    D10(%rip),%rax
  movq   %rax,%xmm2
  jmp    L78
L44:
  pxor   %xmm4,%xmm4
  jmp    L20
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
data_type: f64

tool: D10: 1e+200

assistant: ```c
double gd(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  int i, j, k;
  double d, min, dis;
  dis = 0.0;
  for (i = 0; i < numelA; i++) {
    min = 1.0E200;
    for (j = 0; j < numelB; j++) {
      d = 0.0;
      for (k = 0; k < nObjs; k++)
        d += (A[i * nObjs + k] - B[j * nObjs + k]) * (A[i * nObjs + k] - B[j * nObjs + k]);
      if (d < min)
        min = d;
    }
    dis += sqrt(min);
  }
  return dis / (double)(numelA);
}
```