ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D38(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D21(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  mov    -0x38(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L9
L8:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x34(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x34(%rbp)
L9:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L8
  mov    -0x38(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <intCompSimp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D38
data_type: f64
name: parse_data
arguments: label: D21
data_type: f64
name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D41
data_type: string
name: parse_data
arguments: label: D40
data_type: string
name: parse_data
arguments: label: D16
data_type: string

tool: D38: 2

tool: D21: 7

tool: D18: dame el numero de partes a dividir el intervalo:

tool: D41: %d

tool: D40: estimacion de la integral--> %lf


tool: D16: PAUSE

assistant: ```c
int main() {
  int n;
  int i;
  double a = 2;
  double b = 7;
  double *X;
  double h;
  double integral;
  printf("dame el numero de partes a dividir el intervalo:");
  scanf("%d", &n);
  X = (double *)malloc((n + 1) * sizeof(double));
  h = (b - a) / n;
  for (i = 0; i < n + 1; i++)
    X[i] = a + h * i;
  integral = intCompSimp(X, h, n);
  printf("estimacion de la integral--> %lf\n", integral);
  system("PAUSE");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    0x4(%rsp),%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  movsd  D14(%rip),%xmm0
  divsd  %xmm1,%xmm0
  test   %esi,%esi
  js     L12
  mov    %rax,%rcx
  mov    $0x0,%edx
  movsd  D58(%rip),%xmm2
L23:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rcx)
  add    $0x1,%edx
  mov    0x4(%rsp),%esi
  add    $0x8,%rcx
  cmp    %edx,%esi
  jge    L23
L12:
  call   <intCompSimp@plt>
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D38
type: string
name: disassemble_data
arguments: tag: D10
type: string
name: disassemble_data
arguments: tag: D14
type: byte[8]
name: disassemble_data
arguments: tag: D58
type: f64
name: disassemble_data
arguments: tag: D55
type: string
name: disassemble_data
arguments: tag: D6
type: string

tool: D38: dame el numero de partes a dividir el intervalo:

tool: D10: %d

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D58: 2

tool: D55: estimacion de la integral--> %lf


tool: D6: PAUSE

assistant: ```c
int main() {
  int n;
  int i;
  double a = 2;
  double b = 7;
  double *X;
  double h;
  double integral;
  printf("dame el numero de partes a dividir el intervalo:");
  scanf("%d", &n);
  X = (double *)malloc((n + 1) * sizeof(double));
  h = (b - a) / n;
  for (i = 0; i < n + 1; i++)
    X[i] = a + h * i;
  integral = intCompSimp(X, h, n);
  printf("estimacion de la integral--> %lf\n", integral);
  system("PAUSE");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D42(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%r8d
  pxor   %xmm1,%xmm1
  movsd  D21(%rip),%xmm0
  mov    %rax,%rdi
  cvtsi2sd %r8d,%xmm1
  divsd  %xmm1,%xmm0
  test   %r8d,%r8d
  js     L0
  movsd  D28(%rip),%xmm2
  mov    %rax,%rcx
  lea    0x1(%r8),%esi
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L24:
  pxor   %xmm1,%xmm1
  add    $0x8,%rcx
  cvtsi2sd %edx,%xmm1
  add    $0x1,%edx
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,-0x8(%rcx)
  cmp    %edx,%esi
  jne    L24
L0:
  mov    %r8d,%esi
  call   <intCompSimp@plt>
  lea    D8(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D42
type: string
name: read_data
arguments: label: D20
type: string
name: read_data
arguments: label: D21
type: byte[8]
name: read_data
arguments: label: D28
type: f64
name: read_data
arguments: label: D8
type: string
name: read_data
arguments: label: D51
type: string

tool: D42: dame el numero de partes a dividir el intervalo:

tool: D20: %d

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D28: 2

tool: D8: estimacion de la integral--> %lf


tool: D51: PAUSE

assistant: ```c
int main() {
  int n;
  int i;
  double a = 2;
  double b = 7;
  double *X;
  double h;
  double integral;
  printf("dame el numero de partes a dividir el intervalo:");
  scanf("%d", &n);
  X = (double *)malloc((n + 1) * sizeof(double));
  h = (b - a) / n;
  for (i = 0; i < n + 1; i++)
    X[i] = a + h * i;
  integral = intCompSimp(X, h, n);
  printf("estimacion de la integral--> %lf\n", integral);
  system("PAUSE");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x1,-0x10(%rbp)
  movl   $0x3,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x6,-0x10(%rbp)
  jne    L12
  cmpq   $0x6,-0x8(%rbp)
  je     L18
L12:
  call   <abort@plt>
L18:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  long long a;
  long long b = 1LL;
  int c = 3;
#pragma omp atomic capture
  a = b = c << b;
  if (b != 6LL || a != 6LL)
    __builtin_abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  long long a;
  long long b = 1LL;
  int c = 3;
#pragma omp atomic capture
  a = b = c << b;
  if (b != 6LL || a != 6LL)
    __builtin_abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  long long a;
  long long b = 1LL;
  int c = 3;
#pragma omp atomic capture
  a = b = c << b;
  if (b != 6LL || a != 6LL)
    __builtin_abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  long long a;
  long long b = 1LL;
  int c = 3;
#pragma omp atomic capture
  a = b = c << b;
  if (b != 6LL || a != 6LL)
    __builtin_abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hashlet_teardown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sleep_device@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void hashlet_teardown(int fd) {
  sleep_device(fd);
  close(fd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hashlet_teardown>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <sleep_device@plt>
  mov    %ebx,%edi
  call   <close@plt>
  pop    %rbx
  ret
```

assistant: ```c
void hashlet_teardown(int fd) {
  sleep_device(fd);
  close(fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hashlet_teardown>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <sleep_device@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <close@plt>
```

assistant: ```c
void hashlet_teardown(int fd) {
  sleep_device(fd);
  close(fd);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hashlet_teardown>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <sleep_device@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <close@plt>
```

assistant: ```c
void hashlet_teardown(int fd) {
  sleep_device(fd);
  close(fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<oauth_b64_is_base64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L60
  cmpb   $0x5a,-0x4(%rbp)
  jle    L64
L60:
  cmpb   $0x60,-0x4(%rbp)
  jle    L24
  cmpb   $0x7a,-0x4(%rbp)
  jle    L64
L24:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L16
  cmpb   $0x39,-0x4(%rbp)
  jle    L64
L16:
  cmpb   $0x2b,-0x4(%rbp)
  je     L64
  cmpb   $0x2f,-0x4(%rbp)
  je     L64
  cmpb   $0x3d,-0x4(%rbp)
  jne    L79
L64:
  mov    $0x1,%eax
  jmp    L7
L79:
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int oauth_b64_is_base64(char c) {
  if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || (c >= '0' && c <= '9') || (c == '+') || (c == '/') || (c == '=')) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<oauth_b64_is_base64>:
  endbr64
  mov    %edi,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  mov    $0x1,%eax
  cmp    $0x19,%dl
  jbe    L5
  cmp    $0x3d,%dil
  ja     L4
  movabs $0x23ff880000000000,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L4:
  mov    $0x0,%eax
L5:
  ret
```

assistant: ```c
int oauth_b64_is_base64(char c) {
  if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || (c >= '0' && c <= '9') || (c == '+') || (c == '/') || (c == '=')) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<oauth_b64_is_base64>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L10
  cmp    $0x3d,%dil
  ja     L9
  movabs $0x23ff880000000000,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nop
L9:
  xor    %eax,%eax
L10:
  ret
```

assistant: ```c
int oauth_b64_is_base64(char c) {
  if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || (c >= '0' && c <= '9') || (c == '+') || (c == '/') || (c == '=')) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<oauth_b64_is_base64>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L14
  cmp    $0x3d,%dil
  ja     L19
  movabs $0x23ff880000000000,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nop
L19:
  xor    %eax,%eax
L14:
  ret
```

assistant: ```c
int oauth_b64_is_base64(char c) {
  if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || (c >= '0' && c <= '9') || (c == '+') || (c == '/') || (c == '=')) {
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<end_dependency>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L8
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
L8:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: #endif // %s


assistant: ```c
void end_dependency(FILE *f, const char *dependency) {
  if (dependency != NULL) {
    fprintf(f, "#endif // %s\n", dependency);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<end_dependency>:
  endbr64
  test   %rsi,%rsi
  je     L4
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D3(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: #endif // %s


assistant: ```c
void end_dependency(FILE *f, const char *dependency) {
  if (dependency != NULL) {
    fprintf(f, "#endif // %s\n", dependency);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<end_dependency>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L9
  lea    D5(%rip),%rsi
  jmp    1050 <fprintf@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: #endif // %s


assistant: ```c
void end_dependency(FILE *f, const char *dependency) {
  if (dependency != NULL) {
    fprintf(f, "#endif // %s\n", dependency);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<end_dependency>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L3
  lea    D4(%rip),%rsi
  jmp    1050 <fprintf@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D4: #endif // %s


assistant: ```c
void end_dependency(FILE *f, const char *dependency) {
  if (dependency != NULL) {
    fprintf(f, "#endif // %s\n", dependency);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_fast_math>:
  endbr64
  stmxcsr -0x4(%rsp)
  orl    $0x8040,-0x4(%rsp)
  ldmxcsr -0x4(%rsp)
  ret
```

assistant: ```c
void __attribute__((constructor)) set_fast_math(void) {
  unsigned int mxcsr = __builtin_ia32_stmxcsr();
  mxcsr |= (1 << 6) | (1 << 15);
  __builtin_ia32_ldmxcsr(mxcsr);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    $0xb,%edx
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <helper_function@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    $0xd,%edx
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D39
type_guessed: string
name: read_data
arguments: data_tag: D35
type_guessed: string

tool: D39: main

tool: D35: %s(%d): a is %d


assistant: ```c
int main() {
  int a = 5;
  printf("%s(%d): a is %d\n", __func__, 11, a);
  helper_function(&a);
  printf("%s(%d): a is %d\n", __func__, 13, a);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  mov    $0x5,%ecx
  mov    $0xb,%edx
  lea    D2(%rip),%rbp
  mov    %rbp,%rsi
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  mov    $0x0,%eax
  call   <helper_function@plt>
  mov    0x4(%rsp),%ecx
  mov    $0xd,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string
name: unpack_data
arguments: label: D12
data_type: string

tool: D2: main

tool: D12: %s(%d): a is %d


assistant: ```c
int main() {
  int a = 5;
  printf("%s(%d): a is %d\n", __func__, 11, a);
  helper_function(&a);
  printf("%s(%d): a is %d\n", __func__, 13, a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  mov    $0x5,%ecx
  mov    $0xb,%edx
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  xor    %eax,%eax
  call   <helper_function@plt>
  mov    0x4(%rsp),%ecx
  xor    %eax,%eax
  mov    $0xd,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D5
type: string

tool: D1: main

tool: D5: %s(%d): a is %d


assistant: ```c
int main() {
  int a = 5;
  printf("%s(%d): a is %d\n", __func__, 11, a);
  helper_function(&a);
  printf("%s(%d): a is %d\n", __func__, 13, a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  mov    $0x5,%ecx
  mov    $0xb,%edx
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  xor    %eax,%eax
  call   <helper_function@plt>
  mov    0x4(%rsp),%ecx
  xor    %eax,%eax
  mov    $0xd,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string
name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D5: main

tool: D8: %s(%d): a is %d


assistant: ```c
int main() {
  int a = 5;
  printf("%s(%d): a is %d\n", __func__, 11, a);
  helper_function(&a);
  printf("%s(%d): a is %d\n", __func__, 13, a);
}
```
user: What is the c source code of the assembly code below:

```asm
<printAndFail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void printAndFail(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  fflush(stderr);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printAndFail>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D2(%rip),%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    (%r12),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    (%r12),%edi
  call   <fflush@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printAndFail(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  fflush(stderr);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printAndFail>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D1(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printAndFail(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
  fflush(stderr);
  exit(1);
}
```