user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x58(%rbp)
  jmp    L46
L0:
  mov    -0x58(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x54(%rbp)
  jmp    L29
L84:
  mov    -0x54(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x50(%rbp),%rcx
  mov    -0x54(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x54(%rbp)
L29:
  cmpl   $0x4,-0x54(%rbp)
  jle    L84
  addl   $0x1,-0x58(%rbp)
L46:
  cmpl   $0x2,-0x58(%rbp)
  jle    L0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x54(%rbp)
  jmp    L32
L107:
  mov    -0x54(%rbp),%eax
  cltq
  movss  -0x50(%rbp,%rax,4),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x54(%rbp)
L32:
  cmpl   $0x4,-0x54(%rbp)
  jle    L107
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L82
L40:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x40,%rax
  movss  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x58(%rbp)
L82:
  cmpl   $0x2,-0x58(%rbp)
  jle    L40
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L28
L102:
  mov    -0x58(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x54(%rbp)
  jmp    L95
L104:
  mov    -0x54(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movss  -0x50(%rbp,%rax,4),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x54(%rbp)
L95:
  cmpl   $0x4,-0x54(%rbp)
  jle    L104
  addl   $0x1,-0x58(%rbp)
L28:
  cmpl   $0x2,-0x58(%rbp)
  jle    L102
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D74
type: string
name: extract_symbolic_data
arguments: tag: D63
type: string
name: extract_symbolic_data
arguments: tag: D84
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D52
type: string
name: extract_symbolic_data
arguments: tag: D47
type: string
name: extract_symbolic_data
arguments: tag: D54
type: string
name: extract_symbolic_data
arguments: tag: D53
type: string
name: extract_symbolic_data
arguments: tag: D41
type: string

tool: D74: 
 Digite as notas da AV%d

tool: D63: 
 Entre com nota %d: 

tool: D84: %f

tool: D16: 
 Notas da AV1

tool: D22: %.2f - 

tool: D52: 
 Notas do ultimo aluno

tool: D47: %f - 

tool: D54: 
 As notas digitadas foram:
 

tool: D53: 
 AV%d : 

tool: D41:  %.2f - 

assistant: ```c
int main() {
  float nota[3][5];
  int i, j;
  for (i = 0; i <= 2; i++) {
    printf("\n Digite as notas da AV%d", i + 1);
    for (j = 0; j <= 4; j++) {
      printf("\n Entre com nota %d: ", j + 1);
      scanf("%f", &nota[i][j]);
    }
  }
  printf("\n Notas da AV1\n");
  for (j = 0; j <= 4; j++) {
    printf("%.2f - ", nota[0][j]);
  }
  printf("\n Notas do ultimo aluno\n");
  for (i = 0; i <= 2; i++) {
    printf("%f - ", nota[i][4]);
  }
  printf("\n As notas digitadas foram:\n ");
  for (i = 0; i <= 2; i++) {
    printf("\n AV%d : ", i + 1);
    for (j = 0; j <= 4; j++) {
      printf(" %.2f - ", nota[i][j]);
    }
  }
  return 0;
}
```