ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<i2c_smbus_access>:
  endbr64
  sub    $0x28,%rsp
  movd   %edx,%xmm0
  movd   %ecx,%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %sil,(%rsp)
  mov    %rsp,%rdx
  punpckldq %xmm1,%xmm0
  mov    %r8,0x10(%rsp)
  mov    (%rax),%esi
  movq   %xmm0,0x4(%rsp)
  call   <ioctl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_access(int fd, char rw, int cmd, int size, union i2c_smbus_data *data) {
  struct i2c_smbus_ioctl_data args;
  args.read_write = rw;
  args.command = cmd;
  args.size = size;
  args.data = data;
  return ioctl(fd, I2C_SMBUS, &args);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L16
  mov    $0xffffffff,%eax
  jmp    L0
L16:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int gen(int n) {
  int r = 0;
  if (n <= 0)
    return -1;
  do {
    r += n % 10;
  } while (n /= 10);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gen>:
  endbr64
  test   %edi,%edi
  jle    L6
  mov    $0x0,%ecx
L5:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%ecx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L5
L20:
  mov    %ecx,%eax
  ret
L6:
  mov    $0xffffffff,%ecx
  jmp    L20
```

assistant: ```c
int gen(int n) {
  int r = 0;
  if (n <= 0)
    return -1;
  do {
    r += n % 10;
  } while (n /= 10);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen>:
  endbr64
  test   %edi,%edi
  jle    L9
  xor    %r8d,%r8d
  mov    $0xcccccccd,%ecx
L5:
  mov    %edi,%eax
  imul   %rcx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L5
L0:
  mov    %r8d,%eax
  ret
L9:
  mov    $0xffffffff,%r8d
  jmp    L0
```

assistant: ```c
int gen(int n) {
  int r = 0;
  if (n <= 0)
    return -1;
  do {
    r += n % 10;
  } while (n /= 10);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen>:
  endbr64
  test   %edi,%edi
  jle    L15
  xor    %r8d,%r8d
  mov    $0xcccccccd,%ecx
L24:
  mov    %edi,%eax
  imul   %rcx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    %edi,%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L24
L19:
  mov    %r8d,%eax
  ret
L15:
  mov    $0xffffffff,%r8d
  jmp    L19
```

assistant: ```c
int gen(int n) {
  int r = 0;
  if (n <= 0)
    return -1;
  do {
    r += n % 10;
  } while (n /= 10);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FindChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L35
  mov    $0xffffffff,%eax
  jmp    L11
L35:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L59
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L20
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L11
L20:
  addq   $0x1,-0x8(%rbp)
L59:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    $0xffffffff,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int FindChar(const char *_str, char c) {
  if (!_str) {
    return -1;
  }
  for (const char *str = _str; *str; str++) {
    if (*str == c) {
      return str - _str;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FindChar>:
  endbr64
  test   %rdi,%rdi
  je     L11
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L38
  mov    %rdi,%rax
L8:
  cmp    %dl,%sil
  je     L39
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L8
  mov    $0xffffffff,%eax
  ret
L39:
  sub    %edi,%eax
  ret
L11:
  mov    $0xffffffff,%eax
  ret
L38:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int FindChar(const char *_str, char c) {
  if (!_str) {
    return -1;
  }
  for (const char *str = _str; *str; str++) {
    if (*str == c) {
      return str - _str;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<FindChar>:
  endbr64
  test   %rdi,%rdi
  je     L18
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L18
  mov    %rdi,%rax
  jmp    L24
  nopl   (%rax)
L31:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L18
L24:
  cmp    %dl,%sil
  jne    L31
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L18:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int FindChar(const char *_str, char c) {
  if (!_str) {
    return -1;
  }
  for (const char *str = _str; *str; str++) {
    if (*str == c) {
      return str - _str;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FindChar>:
  endbr64
  test   %rdi,%rdi
  je     L29
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L29
  mov    %rdi,%rax
  jmp    L40
  nopl   (%rax)
L4:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L29
L40:
  cmp    %dl,%sil
  jne    L4
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L29:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int FindChar(const char *_str, char c) {
  if (!_str) {
    return -1;
  }
  for (const char *str = _str; *str; str++) {
    if (*str == c) {
      return str - _str;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EPINonBlockingReadGet32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L0
L13:
  mov    -0x18(%rbp),%rax
  add    $0x70,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x8,-0x28(%rbp)
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  add    $0x6c,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L16
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L13
L16:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadGet32(uint32_t ui32Base, uint32_t ui32Count, uint32_t *pui32Buf) {
  uint32_t ui32CountRead = 0;
  ;
  ;
  ;
  while ((*((volatile uint32_t *)(ui32Base + 0x0000006C))) && ui32Count--) {
    *pui32Buf = (*((volatile uint32_t *)(ui32Base + 0x00000070)));
    pui32Buf++;
    ui32CountRead++;
  }
  return (ui32CountRead);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EPINonBlockingReadGet32>:
  endbr64
  lea    0x6c(%rdi),%r8
  mov    0x6c(%rdi),%rax
  test   %rax,%rax
  je     L8
  test   %rsi,%rsi
  je     L28
  mov    $0x0,%eax
L11:
  mov    0x70(%rdi),%rcx
  mov    %rcx,(%rdx,%rax,8)
  add    $0x1,%rax
  mov    (%r8),%rcx
  test   %rcx,%rcx
  je     L8
  cmp    %rax,%rsi
  jne    L11
  ret
L28:
  mov    %rsi,%rax
L8:
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadGet32(uint32_t ui32Base, uint32_t ui32Count, uint32_t *pui32Buf) {
  uint32_t ui32CountRead = 0;
  ;
  ;
  ;
  while ((*((volatile uint32_t *)(ui32Base + 0x0000006C))) && ui32Count--) {
    *pui32Buf = (*((volatile uint32_t *)(ui32Base + 0x00000070)));
    pui32Buf++;
    ui32CountRead++;
  }
  return (ui32CountRead);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EPINonBlockingReadGet32>:
  endbr64
  mov    0x6c(%rdi),%rax
  lea    0x6c(%rdi),%r8
  test   %rax,%rax
  je     L20
  test   %rsi,%rsi
  je     L6
  add    $0x70,%rdi
  xor    %eax,%eax
  jmp    L30
  xchg   %ax,%ax
L34:
  cmp    %rax,%rsi
  je     L35
L30:
  mov    (%rdi),%rcx
  mov    %rcx,(%rdx,%rax,8)
  mov    (%r8),%rcx
  add    $0x1,%rax
  test   %rcx,%rcx
  jne    L34
L20:
  ret
  nopl   0x0(%rax)
L35:
  ret
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadGet32(uint32_t ui32Base, uint32_t ui32Count, uint32_t *pui32Buf) {
  uint32_t ui32CountRead = 0;
  ;
  ;
  ;
  while ((*((volatile uint32_t *)(ui32Base + 0x0000006C))) && ui32Count--) {
    *pui32Buf = (*((volatile uint32_t *)(ui32Base + 0x00000070)));
    pui32Buf++;
    ui32CountRead++;
  }
  return (ui32CountRead);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<EPINonBlockingReadGet32>:
  endbr64
  mov    0x6c(%rdi),%rax
  lea    0x6c(%rdi),%r8
  test   %rax,%rax
  je     L12
  test   %rsi,%rsi
  je     L27
  add    $0x70,%rdi
  xor    %eax,%eax
  jmp    L32
  xchg   %ax,%ax
L47:
  cmp    %rax,%rsi
  je     L24
L32:
  mov    (%rdi),%rcx
  mov    %rcx,(%rdx,%rax,8)
  mov    (%r8),%rcx
  add    $0x1,%rax
  test   %rcx,%rcx
  jne    L47
L12:
  ret
  nopl   0x0(%rax)
L24:
  ret
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadGet32(uint32_t ui32Base, uint32_t ui32Count, uint32_t *pui32Buf) {
  uint32_t ui32CountRead = 0;
  ;
  ;
  ;
  while ((*((volatile uint32_t *)(ui32Base + 0x0000006C))) && ui32Count--) {
    *pui32Buf = (*((volatile uint32_t *)(ui32Base + 0x00000070)));
    pui32Buf++;
    ui32CountRead++;
  }
  return (ui32CountRead);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movabs $0x5555555555555555,%rax
  mov    %rax,-0x8(%rbp)
  movabs $0xaaaaaaaaaaaaaaaa,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0xffffffffffffffff,-0x8(%rbp)
  movabs $0x8000000000000000,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x1,-0x8(%rbp)
  movabs $0x7fffffffffffffff,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0xfffffffffffffffe,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  signed long long int li;
  li = 0x5555555555555555LL;
  li = 0xAAAAAAAAAAAAAAAALL;
  li = 0x0000000000000000LL;
  li = 0xFFFFFFFFFFFFFFFFLL;
  li = 0x8000000000000000LL;
  li = 0x0000000000000001LL;
  li = 0x7FFFFFFFFFFFFFFFLL;
  li = 0xFFFFFFFFFFFFFFFELL;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  signed long long int li;
  li = 0x5555555555555555LL;
  li = 0xAAAAAAAAAAAAAAAALL;
  li = 0x0000000000000000LL;
  li = 0xFFFFFFFFFFFFFFFFLL;
  li = 0x8000000000000000LL;
  li = 0x0000000000000001LL;
  li = 0x7FFFFFFFFFFFFFFFLL;
  li = 0xFFFFFFFFFFFFFFFELL;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  signed long long int li;
  li = 0x5555555555555555LL;
  li = 0xAAAAAAAAAAAAAAAALL;
  li = 0x0000000000000000LL;
  li = 0xFFFFFFFFFFFFFFFFLL;
  li = 0x8000000000000000LL;
  li = 0x0000000000000001LL;
  li = 0x7FFFFFFFFFFFFFFFLL;
  li = 0xFFFFFFFFFFFFFFFELL;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  signed long long int li;
  li = 0x5555555555555555LL;
  li = 0xAAAAAAAAAAAAAAAALL;
  li = 0x0000000000000000LL;
  li = 0xFFFFFFFFFFFFFFFFLL;
  li = 0x8000000000000000LL;
  li = 0x0000000000000001LL;
  li = 0x7FFFFFFFFFFFFFFFLL;
  li = 0xFFFFFFFFFFFFFFFELL;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x10,%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *f(char *p) {
  short x = *p++ << 16;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *f(char *p) {
  short x = *p++ << 16;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *f(char *p) {
  short x = *p++ << 16;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *f(char *p) {
  short x = *p++ << 16;
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x61,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: %c

assistant: ```c
int main() {
  char a = 'a';
  printf("%c", a -= 32);
  getchar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: %c

assistant: ```c
int main() {
  char a = 'a';
  printf("%c", a -= 32);
  getchar();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: %c

assistant: ```c
int main() {
  char a = 'a';
  printf("%c", a -= 32);
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: %c

assistant: ```c
int main() {
  char a = 'a';
  printf("%c", a -= 32);
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L81
L108:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    $0x4f,%al
  je     L92
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    $0x44,%al
  jne    L86
L92:
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x30,-0x12(%rbp,%rax,1)
  jmp    L68
L86:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    $0x49,%al
  jne    L54
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x31,-0x12(%rbp,%rax,1)
  jmp    L68
L54:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    $0x5a,%al
  jne    L5
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x32,-0x12(%rbp,%rax,1)
  jmp    L68
L5:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    $0x53,%al
  jne    L123
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x35,-0x12(%rbp,%rax,1)
  jmp    L68
L123:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    $0x42,%al
  jne    L68
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x38,-0x12(%rbp,%rax,1)
L68:
  addl   $0x1,-0x18(%rbp)
L81:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L108
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L102
  call   <__stack_chk_fail@plt>
L102:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D13: %s

tool: D0: %s


assistant: ```c
int main(void) {
  char price[10];
  int i;
  scanf("%s", price);
  for (i = 0; price[i] != '\0'; i++) {
    if (price[i] == 'O' || price[i] == 'D') {
      price[i] = '0';
    } else if (price[i] == 'I') {
      price[i] = '1';
    } else if (price[i] == 'Z') {
      price[i] = '2';
    } else if (price[i] == 'S') {
      price[i] = '5';
    } else if (price[i] == 'B') {
      price[i] = '8';
    }
  }
  printf("%s\n", price);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  movzbl 0xe(%rsp),%eax
  test   %al,%al
  je     L16
  lea    0xe(%rsp),%rdx
  lea    D13(%rip),%rcx
  jmp    L78
  movb   $0x30,(%rdx)
L79:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L16
L78:
  sub    $0x42,%eax
  cmp    $0x18,%al
  ja     L79
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  movb   $0x31,(%rdx)
  jmp    L79
  movb   $0x32,(%rdx)
  jmp    L79
  movb   $0x35,(%rdx)
  jmp    L79
  movb   $0x38,(%rdx)
  jmp    L79
L16:
  lea    0xe(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string

tool: D8: %s

tool: D28: %s


assistant: ```c
int main(void) {
  char price[10];
  int i;
  scanf("%s", price);
  for (i = 0; price[i] != '\0'; i++) {
    if (price[i] == 'O' || price[i] == 'D') {
      price[i] = '0';
    } else if (price[i] == 'I') {
      price[i] = '1';
    } else if (price[i] == 'Z') {
      price[i] = '2';
    } else if (price[i] == 'S') {
      price[i] = '5';
    } else if (price[i] == 'B') {
      price[i] = '8';
    }
  }
  printf("%s\n", price);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movzbl 0xe(%rsp),%eax
  test   %al,%al
  je     L52
  mov    %rbp,%rdx
  lea    D5(%rip),%rcx
L97:
  sub    $0x42,%eax
  cmp    $0x18,%al
  ja     L74
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  movb   $0x30,(%rdx)
  nopl   0x0(%rax,%rax,1)
L74:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L97
L52:
  mov    %rbp,%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
  movb   $0x32,(%rdx)
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L97
  jmp    L52
  nopl   0x0(%rax)
  movb   $0x38,(%rdx)
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L97
  jmp    L52
  nopl   0x0(%rax)
  movb   $0x35,(%rdx)
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L97
  jmp    L52
  nopl   (%rax)
  movb   $0x31,(%rdx)
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L97
  jmp    L52
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string

tool: D23: %s

tool: D26: %s


assistant: ```c
int main(void) {
  char price[10];
  int i;
  scanf("%s", price);
  for (i = 0; price[i] != '\0'; i++) {
    if (price[i] == 'O' || price[i] == 'D') {
      price[i] = '0';
    } else if (price[i] == 'I') {
      price[i] = '1';
    } else if (price[i] == 'Z') {
      price[i] = '2';
    } else if (price[i] == 'S') {
      price[i] = '5';
    } else if (price[i] == 'B') {
      price[i] = '8';
    }
  }
  printf("%s\n", price);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BitDeinterleave>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t BitDeinterleave(uint64_t Ai) {
  if ((0)) {
    uint32_t hi = (uint32_t)(Ai >> 32), lo = (uint32_t)Ai;
    uint32_t t0, t1;
    t0 = lo & 0x0000ffff;
    t0 |= t0 << 8;
    t0 &= 0x00ff00ff;
    t0 |= t0 << 4;
    t0 &= 0x0f0f0f0f;
    t0 |= t0 << 2;
    t0 &= 0x33333333;
    t0 |= t0 << 1;
    t0 &= 0x55555555;
    t1 = hi << 16;
    t1 |= t1 >> 8;
    t1 &= 0xff00ff00;
    t1 |= t1 >> 4;
    t1 &= 0xf0f0f0f0;
    t1 |= t1 >> 2;
    t1 &= 0xcccccccc;
    t1 |= t1 >> 1;
    t1 &= 0xaaaaaaaa;
    lo >>= 16;
    lo |= lo << 8;
    lo &= 0x00ff00ff;
    lo |= lo << 4;
    lo &= 0x0f0f0f0f;
    lo |= lo << 2;
    lo &= 0x33333333;
    lo |= lo << 1;
    lo &= 0x55555555;
    hi &= 0xffff0000;
    hi |= hi >> 8;
    hi &= 0xff00ff00;
    hi |= hi >> 4;
    hi &= 0xf0f0f0f0;
    hi |= hi >> 2;
    hi &= 0xcccccccc;
    hi |= hi >> 1;
    hi &= 0xaaaaaaaa;
    Ai = ((uint64_t)(hi | lo) << 32) | (t1 | t0);
  }
  return Ai;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BitDeinterleave>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint64_t BitDeinterleave(uint64_t Ai) {
  if ((0)) {
    uint32_t hi = (uint32_t)(Ai >> 32), lo = (uint32_t)Ai;
    uint32_t t0, t1;
    t0 = lo & 0x0000ffff;
    t0 |= t0 << 8;
    t0 &= 0x00ff00ff;
    t0 |= t0 << 4;
    t0 &= 0x0f0f0f0f;
    t0 |= t0 << 2;
    t0 &= 0x33333333;
    t0 |= t0 << 1;
    t0 &= 0x55555555;
    t1 = hi << 16;
    t1 |= t1 >> 8;
    t1 &= 0xff00ff00;
    t1 |= t1 >> 4;
    t1 &= 0xf0f0f0f0;
    t1 |= t1 >> 2;
    t1 &= 0xcccccccc;
    t1 |= t1 >> 1;
    t1 &= 0xaaaaaaaa;
    lo >>= 16;
    lo |= lo << 8;
    lo &= 0x00ff00ff;
    lo |= lo << 4;
    lo &= 0x0f0f0f0f;
    lo |= lo << 2;
    lo &= 0x33333333;
    lo |= lo << 1;
    lo &= 0x55555555;
    hi &= 0xffff0000;
    hi |= hi >> 8;
    hi &= 0xff00ff00;
    hi |= hi >> 4;
    hi &= 0xf0f0f0f0;
    hi |= hi >> 2;
    hi &= 0xcccccccc;
    hi |= hi >> 1;
    hi &= 0xaaaaaaaa;
    Ai = ((uint64_t)(hi | lo) << 32) | (t1 | t0);
  }
  return Ai;
}
```
user: What is the c source code of the assembly code below:

```asm
<BitDeinterleave>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint64_t BitDeinterleave(uint64_t Ai) {
  if ((0)) {
    uint32_t hi = (uint32_t)(Ai >> 32), lo = (uint32_t)Ai;
    uint32_t t0, t1;
    t0 = lo & 0x0000ffff;
    t0 |= t0 << 8;
    t0 &= 0x00ff00ff;
    t0 |= t0 << 4;
    t0 &= 0x0f0f0f0f;
    t0 |= t0 << 2;
    t0 &= 0x33333333;
    t0 |= t0 << 1;
    t0 &= 0x55555555;
    t1 = hi << 16;
    t1 |= t1 >> 8;
    t1 &= 0xff00ff00;
    t1 |= t1 >> 4;
    t1 &= 0xf0f0f0f0;
    t1 |= t1 >> 2;
    t1 &= 0xcccccccc;
    t1 |= t1 >> 1;
    t1 &= 0xaaaaaaaa;
    lo >>= 16;
    lo |= lo << 8;
    lo &= 0x00ff00ff;
    lo |= lo << 4;
    lo &= 0x0f0f0f0f;
    lo |= lo << 2;
    lo &= 0x33333333;
    lo |= lo << 1;
    lo &= 0x55555555;
    hi &= 0xffff0000;
    hi |= hi >> 8;
    hi &= 0xff00ff00;
    hi |= hi >> 4;
    hi &= 0xf0f0f0f0;
    hi |= hi >> 2;
    hi &= 0xcccccccc;
    hi |= hi >> 1;
    hi &= 0xaaaaaaaa;
    Ai = ((uint64_t)(hi | lo) << 32) | (t1 | t0);
  }
  return Ai;
}
```