ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<test_array_set_overwrites_old_values>:
  endbr64
  push   %r12
  mov    $0x96,%esi
  mov    $0x4,%edi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x29a,(%rsp)
  movl   $0x400,0x4(%rsp)
  call   <sparse_array_init@plt>
  test   %rax,%rax
  je     L1
  mov    %rsp,%rdx
  mov    $0x4,%ecx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <sparse_array_set@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L77
  lea    0x4(%rsp),%rdx
  mov    $0x4,%ecx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <sparse_array_set@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L51
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <sparse_array_get@plt>
  cmpl   $0x400,(%rax)
  jne    L105
  mov    %rbp,%rdi
  call   <sparse_array_free@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L52
  mov    $0x1,%r12d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L77:
  mov    $0x9e,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L51:
  mov    $0x9f,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L105:
  mov    $0xa1,%esi
  lea    D20(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L49
  xchg   %ax,%ax
L1:
  mov    $0x9c,%esi
  lea    D20(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    $0xa3,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L49
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D20
type_guessed: string

tool: D20: %i: 

assistant: ```c
int test_array_set_overwrites_old_values() {
  struct sparse_array *arr = NULL;
  const int test_num = 666;
  const int test_num2 = 1024;
  arr = sparse_array_init(sizeof(int), 150);
  if (!(arr)) {
    printf("%i: ", 156);
    return 0;
  };
  if (!(sparse_array_set(arr, 0, &test_num, sizeof(test_num)))) {
    printf("%i: ", 158);
    return 0;
  };
  if (!(sparse_array_set(arr, 0, &test_num2, sizeof(test_num2)))) {
    printf("%i: ", 159);
    return 0;
  };
  if (!(*(const int *)sparse_array_get(arr, 0, NULL) == 1024)) {
    printf("%i: ", 161);
    return 0;
  };
  if (!(sparse_array_free(arr))) {
    printf("%i: ", 163);
    return 0;
  };
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L22:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L22
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x10(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string

tool: D5: %d

tool: D14: Sum: %d
Avg: %.2f

assistant: ```c
int main() {
  int n, i, a;
  int sum = 0;
  float avr;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a);
    sum += a;
  }
  printf("Sum: %d\nAvg: %.2f", sum, avr = ((float)sum) / n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L36
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D16(%rip),%r12
L9:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jg     L9
L22:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    $0x0,%ebp
  jmp    L22
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type: string
name: disassemble_data
arguments: data_label: D0
type: string

tool: D16: %d

tool: D0: Sum: %d
Avg: %.2f

assistant: ```c
int main() {
  int n, i, a;
  int sum = 0;
  float avr;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a);
    sum += a;
  }
  printf("Sum: %d\nAvg: %.2f", sum, avr = ((float)sum) / n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L16
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r13
L24:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%ebp
  cmp    %ebx,%eax
  jg     L24
L16:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %ebp,%esi
  cvtsi2ss %ebp,%xmm0
  lea    D18(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D6: %d

tool: D18: Sum: %d
Avg: %.2f

assistant: ```c
int main() {
  int n, i, a;
  int sum = 0;
  float avr;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a);
    sum += a;
  }
  printf("Sum: %d\nAvg: %.2f", sum, avr = ((float)sum) / n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L18
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r13
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%ebp
  cmp    %ebx,%eax
  jg     L9
L18:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %ebp,%esi
  cvtsi2ss %ebp,%xmm0
  lea    D3(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D9: %d

tool: D3: Sum: %d
Avg: %.2f

assistant: ```c
int main() {
  int n, i, a;
  int sum = 0;
  float avr;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a);
    sum += a;
  }
  printf("Sum: %d\nAvg: %.2f", sum, avr = ((float)sum) / n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sun_RA_dec>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movq   %xmm0,%rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    %rdx,%rsi
  mov    $0x1,%eax
  call   <sunpos@plt>
  mov    0x0(%r13),%r15
  lea    0x18(%rsp),%r13
  lea    0x10(%rsp),%r14
  movsd  D6(%rip),%xmm0
  mulsd  0x20(%rsp),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  movq   %r15,%xmm1
  mulsd  0x10(%rsp),%xmm1
  movsd  %xmm1,(%rsp)
  movq   %r15,%xmm3
  mulsd  0x18(%rsp),%xmm3
  movq   %xmm3,%r15
  movq   %rbx,%xmm4
  mulsd  D54(%rip),%xmm4
  movsd  D13(%rip),%xmm0
  subsd  %xmm4,%xmm0
  mulsd  D6(%rip),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  movq   %r15,%xmm2
  mulsd  0x10(%rsp),%xmm2
  movq   %r15,%xmm5
  mulsd  0x18(%rsp),%xmm5
  movq   %xmm5,%rbx
  movsd  (%rsp),%xmm1
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <atan2@plt>
  mulsd  D59(%rip),%xmm0
  movsd  %xmm0,(%r12)
  movsd  (%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L7
  sqrtsd %xmm1,%xmm1
L2:
  movq   %rbx,%xmm0
  call   <atan2@plt>
  mulsd  D59(%rip),%xmm0
  movsd  %xmm0,0x0(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L2
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: byte[8]
name: retrieve_data
arguments: label: D54
data_type: byte[8]
name: retrieve_data
arguments: label: D13
data_type: f64
name: retrieve_data
arguments: label: D59
data_type: byte[8]

tool: {"D6": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

tool: {"D54": [0xda,0xda,0xce,0xf8,0x2f,0xe9,0x97,0x3e]}

tool: D13: 23.4393

tool: {"D59": [0xf8,0xc1,0x63,0x1a,0xdc,0xa5,0x4c,0x40]}

assistant: ```c
void sun_RA_dec(double d, double *RA, double *dec, double *r) {
  double lon, obl_ecl;
  double xs, ys;
  double xe, ye, ze;
  sunpos(d, &lon, r);
  xs = *r * cos((lon) * (3.1415926535897932384 / 180.0));
  ys = *r * sin((lon) * (3.1415926535897932384 / 180.0));
  obl_ecl = 23.4393 - 3.563E-7 * d;
  xe = xs;
  ye = ys * cos((obl_ecl) * (3.1415926535897932384 / 180.0));
  ze = ys * sin((obl_ecl) * (3.1415926535897932384 / 180.0));
  *RA = ((180.0 / 3.1415926535897932384) * atan2(ye, xe));
  *dec = ((180.0 / 3.1415926535897932384) * atan2(ze, sqrt(xe * xe + ye * ye)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sun_RA_dec>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x18(%rsp)
  call   <sunpos@plt>
  lea    0x20(%rsp),%r13
  movsd  0x0(%rbp),%xmm2
  movsd  D18(%rip),%xmm0
  mulsd  0x30(%rsp),%xmm0
  lea    0x28(%rsp),%rbp
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movsd  %xmm2,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x18(%rsp),%xmm3
  mov    %r13,%rsi
  movsd  0x8(%rsp),%xmm2
  mulsd  D34(%rip),%xmm3
  movsd  0x20(%rsp),%xmm1
  mov    %rbp,%rdi
  movsd  D43(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  0x28(%rsp),%xmm2
  subsd  %xmm3,%xmm0
  mulsd  D18(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  mulsd  %xmm2,%xmm3
  mulsd  0x28(%rsp),%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <atan2@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm3
  mulsd  D44(%rip),%xmm0
  movsd  0x18(%rsp),%xmm2
  mulsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm3
  movsd  %xmm0,(%r12)
  pxor   %xmm0,%xmm0
  addsd  %xmm3,%xmm1
  ucomisd %xmm1,%xmm0
  ja     L9
  sqrtsd %xmm1,%xmm1
L28:
  movapd %xmm2,%xmm0
  call   <atan2@plt>
  mulsd  D44(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L28
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
data_type: byte[8]
name: read_data
arguments: label: D34
data_type: byte[8]
name: read_data
arguments: label: D43
data_type: f64
name: read_data
arguments: label: D44
data_type: byte[8]

tool: {"D18": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

tool: {"D34": [0xda,0xda,0xce,0xf8,0x2f,0xe9,0x97,0x3e]}

tool: D43: 23.4393

tool: {"D44": [0xf8,0xc1,0x63,0x1a,0xdc,0xa5,0x4c,0x40]}

assistant: ```c
void sun_RA_dec(double d, double *RA, double *dec, double *r) {
  double lon, obl_ecl;
  double xs, ys;
  double xe, ye, ze;
  sunpos(d, &lon, r);
  xs = *r * cos((lon) * (3.1415926535897932384 / 180.0));
  ys = *r * sin((lon) * (3.1415926535897932384 / 180.0));
  obl_ecl = 23.4393 - 3.563E-7 * d;
  xe = xs;
  ye = ys * cos((obl_ecl) * (3.1415926535897932384 / 180.0));
  ze = ys * sin((obl_ecl) * (3.1415926535897932384 / 180.0));
  *RA = ((180.0 / 3.1415926535897932384) * atan2(ye, xe));
  *dec = ((180.0 / 3.1415926535897932384) * atan2(ze, sqrt(xe * xe + ye * ye)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sun_RA_dec>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x18(%rsp)
  call   <sunpos@plt>
  lea    0x20(%rsp),%r13
  movsd  0x0(%rbp),%xmm2
  movsd  D14(%rip),%xmm0
  mulsd  0x30(%rsp),%xmm0
  lea    0x28(%rsp),%rbp
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movsd  %xmm2,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x18(%rsp),%xmm3
  mov    %r13,%rsi
  movsd  0x8(%rsp),%xmm2
  mulsd  D29(%rip),%xmm3
  movsd  0x20(%rsp),%xmm1
  mov    %rbp,%rdi
  movsd  D57(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  0x28(%rsp),%xmm2
  subsd  %xmm3,%xmm0
  mulsd  D14(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  mulsd  %xmm2,%xmm3
  mulsd  0x28(%rsp),%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <atan2@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm3
  mulsd  D20(%rip),%xmm0
  movsd  0x18(%rsp),%xmm2
  mulsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm3
  movsd  %xmm0,(%r12)
  pxor   %xmm0,%xmm0
  addsd  %xmm3,%xmm1
  ucomisd %xmm1,%xmm0
  ja     L24
  sqrtsd %xmm1,%xmm1
L9:
  movapd %xmm2,%xmm0
  call   <atan2@plt>
  mulsd  D20(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L9
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D14
data_type: byte[8]
name: retrieve_data
arguments: data_label: D29
data_type: byte[8]
name: retrieve_data
arguments: data_label: D57
data_type: f64
name: retrieve_data
arguments: data_label: D20
data_type: byte[8]

tool: {"D14": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

tool: {"D29": [0xda,0xda,0xce,0xf8,0x2f,0xe9,0x97,0x3e]}

tool: D57: 23.4393

tool: {"D20": [0xf8,0xc1,0x63,0x1a,0xdc,0xa5,0x4c,0x40]}

assistant: ```c
void sun_RA_dec(double d, double *RA, double *dec, double *r) {
  double lon, obl_ecl;
  double xs, ys;
  double xe, ye, ze;
  sunpos(d, &lon, r);
  xs = *r * cos((lon) * (3.1415926535897932384 / 180.0));
  ys = *r * sin((lon) * (3.1415926535897932384 / 180.0));
  obl_ecl = 23.4393 - 3.563E-7 * d;
  xe = xs;
  ye = ys * cos((obl_ecl) * (3.1415926535897932384 / 180.0));
  ze = ys * sin((obl_ecl) * (3.1415926535897932384 / 180.0));
  *RA = ((180.0 / 3.1415926535897932384) * atan2(ye, xe));
  *dec = ((180.0 / 3.1415926535897932384) * atan2(ze, sqrt(xe * xe + ye * ye)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <build_path@plt>
  mov    $0x0,%eax
  call   <print_queue_set@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  build_path();
  print_queue_set();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <build_path@plt>
  mov    $0x0,%eax
  call   <print_queue_set@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  build_path();
  print_queue_set();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <build_path@plt>
  xor    %eax,%eax
  call   <print_queue_set@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  build_path();
  print_queue_set();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <build_path@plt>
  xor    %eax,%eax
  call   <print_queue_set@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  build_path();
  print_queue_set();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string

tool: D10: alamat memory pnum %p 


tool: D8: nilai pnum %d 


assistant: ```c
int main() {
  int *pnum = NULL;
  printf("alamat memory pnum %p \n", pnum);
  printf("nilai pnum %d \n", *pnum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string

tool: D14: alamat memory pnum %p 


tool: D18: nilai pnum %d 


assistant: ```c
int main() {
  int *pnum = NULL;
  printf("alamat memory pnum %p \n", pnum);
  printf("nilai pnum %d \n", *pnum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0,%eax
  ud2
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: alamat memory pnum %p 


assistant: ```c
int main() {
  int *pnum = NULL;
  printf("alamat memory pnum %p \n", pnum);
  printf("nilai pnum %d \n", *pnum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0,%eax
  ud2
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D7: alamat memory pnum %p 


assistant: ```c
int main() {
  int *pnum = NULL;
  printf("alamat memory pnum %p \n", pnum);
  printf("nilai pnum %d \n", *pnum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crypto_onetimeauth_verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <crypto_onetimeauth@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypto_verify_16@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int crypto_onetimeauth_verify(const unsigned char *h, const unsigned char *in, unsigned long long inlen, const unsigned char *k) {
  unsigned char correct[16];
  crypto_onetimeauth(correct, in, inlen, k);
  return crypto_verify_16(h, correct);
}
```
user: What is the c source code of the assembly code below?

```asm
<crypto_onetimeauth_verify>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <crypto_onetimeauth@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <crypto_verify_16@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_onetimeauth_verify(const unsigned char *h, const unsigned char *in, unsigned long long inlen, const unsigned char *k) {
  unsigned char correct[16];
  crypto_onetimeauth(correct, in, inlen, k);
  return crypto_verify_16(h, correct);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crypto_onetimeauth_verify>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <crypto_onetimeauth@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crypto_verify_16@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_onetimeauth_verify(const unsigned char *h, const unsigned char *in, unsigned long long inlen, const unsigned char *k) {
  unsigned char correct[16];
  crypto_onetimeauth(correct, in, inlen, k);
  return crypto_verify_16(h, correct);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crypto_onetimeauth_verify>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <crypto_onetimeauth@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crypto_verify_16@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_onetimeauth_verify(const unsigned char *h, const unsigned char *in, unsigned long long inlen, const unsigned char *k) {
  unsigned char correct[16];
  crypto_onetimeauth(correct, in, inlen, k);
  return crypto_verify_16(h, correct);
}
```