ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<djb2>:
  endbr64
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L14
  mov    $0x1505,%eax
L19:
  mov    %rax,%rdx
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq (%rdi),%rdx
  xor    %rdx,%rax
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L19
  ret
L14:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned long djb2(void *key, size_t keysize) {
  char *s, *sp;
  unsigned long hash;
  s = (char *)key;
  hash = 5381;
  for (sp = s; sp < s + keysize; sp++)
    hash = ((hash << 5) + hash) ^ *sp;
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<djb2>:
  endbr64
  add    %rdi,%rsi
  mov    $0x1505,%eax
  cmp    %rsi,%rdi
  jae    L19
  nopl   0x0(%rax)
L1:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  xor    %rdx,%rax
  cmp    %rsi,%rdi
  jne    L1
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
unsigned long djb2(void *key, size_t keysize) {
  char *s, *sp;
  unsigned long hash;
  s = (char *)key;
  hash = 5381;
  for (sp = s; sp < s + keysize; sp++)
    hash = ((hash << 5) + hash) ^ *sp;
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<djb2>:
  endbr64
  add    %rdi,%rsi
  mov    $0x1505,%eax
  cmp    %rsi,%rdi
  jae    L8
  nopl   0x0(%rax)
L0:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  xor    %rdx,%rax
  cmp    %rsi,%rdi
  jne    L0
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
unsigned long djb2(void *key, size_t keysize) {
  char *s, *sp;
  unsigned long hash;
  s = (char *)key;
  hash = 5381;
  for (sp = s; sp < s + keysize; sp++)
    hash = ((hash << 5) + hash) ^ *sp;
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_printf@plt>
  mov    $0x0,%eax
  call   <test_alloc@plt>
  mov    $0x0,%eax
  call   <test_list@plt>
  mov    $0x0,%eax
  call   <test_vector@plt>
  mov    $0x0,%eax
  call   <test_hashtable@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_printf();
  test_alloc();
  test_list();
  test_vector();
  test_hashtable();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_printf@plt>
  mov    $0x0,%eax
  call   <test_alloc@plt>
  mov    $0x0,%eax
  call   <test_list@plt>
  mov    $0x0,%eax
  call   <test_vector@plt>
  mov    $0x0,%eax
  call   <test_hashtable@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_printf();
  test_alloc();
  test_list();
  test_vector();
  test_hashtable();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_printf@plt>
  xor    %eax,%eax
  call   <test_alloc@plt>
  xor    %eax,%eax
  call   <test_list@plt>
  xor    %eax,%eax
  call   <test_vector@plt>
  xor    %eax,%eax
  call   <test_hashtable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_printf();
  test_alloc();
  test_list();
  test_vector();
  test_hashtable();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_printf@plt>
  xor    %eax,%eax
  call   <test_alloc@plt>
  xor    %eax,%eax
  call   <test_list@plt>
  xor    %eax,%eax
  call   <test_vector@plt>
  xor    %eax,%eax
  call   <test_hashtable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_printf();
  test_alloc();
  test_list();
  test_vector();
  test_hashtable();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shellsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  jmp    L44
L18:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L31
L0:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L59
L11:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L59:
  cmpl   $0x0,-0x8(%rbp)
  js     L39
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L11
L39:
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
L44:
  cmpl   $0x0,-0x10(%rbp)
  jg     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  for (gap = n / 2; gap > 0; gap /= 2) {
    for (i = gap; i < n; i++) {
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<shellsort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %esi,%r11d
  shr    $0x1f,%r11d
  add    %esi,%r11d
  sar    %r11d
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebp
  cmp    $0x1,%esi
  jg     L32
L82:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  lea    0x1(%r9),%rax
  cmp    %r10,%r9
  je     L49
  mov    %rax,%r9
L70:
  test   %r9d,%r9d
  js     L16
  mov    %r9,%rax
L3:
  mov    (%rdi,%rax,4),%ecx
  mov    (%rsi,%rax,4),%edx
  cmp    %edx,%ecx
  jle    L16
  mov    %edx,(%rdi,%rax,4)
  mov    %ecx,(%rsi,%rax,4)
  add    %r8,%rax
  test   %eax,%eax
  jns    L3
  jmp    L16
L49:
  mov    %r11d,%eax
  shr    $0x1f,%eax
  add    %r11d,%eax
  sar    %eax
  cmp    $0x1,%r11d
  jle    L82
  mov    %eax,%r11d
L32:
  cmp    %r11d,%ebx
  jle    L49
  mov    %r12d,%r10d
  sub    %r11d,%r10d
  movslq %r11d,%rax
  lea    (%rdi,%rax,4),%rsi
  mov    %rbp,%r9
  mov    %r11d,%r8d
  neg    %r8d
  movslq %r8d,%r8
  jmp    L70
```

assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  for (gap = n / 2; gap > 0; gap /= 2) {
    for (i = gap; i < n; i++) {
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shellsort>:
  endbr64
  mov    %esi,%r11d
  shr    $0x1f,%r11d
  add    %esi,%r11d
  sar    %r11d
  cmp    $0x1,%esi
  jle    L31
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %esi,%ebx
  nopl   (%rax)
L51:
  cmp    %r11d,%ebx
  jle    L71
  mov    %r11d,%r8d
  mov    %ebp,%r10d
  movslq %r11d,%rax
  xor    %r9d,%r9d
  neg    %r8d
  sub    %r11d,%r10d
  lea    (%rdi,%rax,4),%rsi
  movslq %r8d,%r8
  xchg   %ax,%ax
L61:
  mov    %r9,%rax
  jmp    L13
  nopl   (%rax)
L43:
  mov    %edx,(%rdi,%rax,4)
  mov    %ecx,(%rsi,%rax,4)
  add    %r8,%rax
  test   %eax,%eax
  js     L8
L13:
  mov    (%rdi,%rax,4),%ecx
  mov    (%rsi,%rax,4),%edx
  cmp    %edx,%ecx
  jg     L43
L8:
  lea    0x1(%r9),%rax
  cmp    %r10,%r9
  je     L71
  mov    %rax,%r9
  jmp    L61
  nopl   (%rax)
L71:
  sar    %r11d
  jne    L51
  pop    %rbx
  pop    %rbp
  ret
L31:
  ret
```

assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  for (gap = n / 2; gap > 0; gap /= 2) {
    for (i = gap; i < n; i++) {
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shellsort>:
  endbr64
  mov    %esi,%r11d
  shr    $0x1f,%r11d
  add    %esi,%r11d
  sar    %r11d
  cmp    $0x1,%esi
  jle    L20
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %esi,%ebx
  nopl   (%rax)
L79:
  cmp    %r11d,%ebx
  jle    L48
  mov    %r11d,%r8d
  mov    %ebp,%r10d
  movslq %r11d,%rax
  xor    %r9d,%r9d
  neg    %r8d
  sub    %r11d,%r10d
  lea    (%rdi,%rax,4),%rsi
  movslq %r8d,%r8
  xchg   %ax,%ax
L6:
  mov    %r9,%rax
  jmp    L24
  nopl   (%rax)
L33:
  mov    %edx,(%rdi,%rax,4)
  mov    %ecx,(%rsi,%rax,4)
  add    %r8,%rax
  test   %eax,%eax
  js     L78
L24:
  mov    (%rdi,%rax,4),%ecx
  mov    (%rsi,%rax,4),%edx
  cmp    %edx,%ecx
  jg     L33
L78:
  lea    0x1(%r9),%rax
  cmp    %r9,%r10
  je     L48
  mov    %rax,%r9
  jmp    L6
  nopl   (%rax)
L48:
  sar    %r11d
  jne    L79
  pop    %rbx
  pop    %rbp
  ret
L20:
  ret
```

assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  for (gap = n / 2; gap > 0; gap /= 2) {
    for (i = gap; i < n; i++) {
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cents2money>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L6
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L0
L6:
  cmpq   $0x63,-0x18(%rbp)
  jg     L79
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D30(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L0
L74:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L73
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2e,(%rax)
  jmp    L20
L73:
  cmpq   $0x0,-0x18(%rbp)
  jle    L20
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L20
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2c,(%rax)
L20:
  addl   $0x1,-0xc(%rbp)
L79:
  cmpq   $0x0,-0x18(%rbp)
  jg     L74
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
L0:
  lea    D13(%rip),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D17
datatype: string
name: read_data
arguments: label: D30
datatype: string

tool: D17: 0.00

tool: D30: 0.%2.2ld

assistant: ```c
const char *cents2money(long cents) {
  static char buff[64];
  int idx = 0;
  char *d = buff;
  if (cents == 0) {
    strcpy(buff, "0.00");
  } else if (cents < 100) {
    sprintf(buff, "0.%2.2ld", cents);
  } else {
    while (cents > 0) {
      *d++ = '0' + (cents % 10);
      cents = cents / 10;
      if (idx == 1) {
        *d++ = '.';
      } else if (cents > 0 && (idx - 1) % 3 == 0) {
        *d++ = ',';
      }
      idx++;
    }
    *d++ = 0;
    reverse(buff);
  }
  return (buff);
}
```
user: What is the c source code of the assembly code below?

```asm
<cents2money>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L52
  mov    %rdi,%rcx
  lea    D55(%rip),%rdi
  mov    $0x0,%r8d
  movabs $0x6666666666666667,%r10
  cmp    $0x63,%rcx
  jg     L24
  mov    %rcx,%rdx
  lea    D28(%rip),%rsi
  call   <sprintf@plt>
  jmp    L13
L52:
  lea    D34(%rip),%rsi
  lea    D55(%rip),%rdi
  call   <strcpy@plt>
  jmp    L13
L78:
  lea    0x2(%rdi),%r9
  movb   $0x2e,0x1(%rdi)
  add    $0x1,%r8d
  cmp    $0x9,%rcx
  jle    L33
L57:
  mov    %r9,%rdi
  mov    %rdx,%rcx
L24:
  lea    0x1(%rdi),%r9
  mov    %rcx,%rax
  imul   %r10
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  mov    %rcx,%rax
  sub    %rsi,%rax
  add    $0x30,%eax
  mov    %al,(%rdi)
  cmp    $0x1,%r8d
  je     L78
  cmp    $0x9,%rcx
  jle    L33
  lea    -0x1(%r8),%ecx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ecx
  jne    L61
  lea    0x2(%rdi),%r9
  movb   $0x2c,0x1(%rdi)
L61:
  add    $0x1,%r8d
  jmp    L57
L33:
  movb   $0x0,(%r9)
  lea    D55(%rip),%rdi
  call   <reverse@plt>
L13:
  lea    D55(%rip),%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D28
datatype: string
name: disassemble_data
arguments: label: D34
datatype: string

tool: D28: 0.%2.2ld

tool: D34: 0.00

assistant: ```c
const char *cents2money(long cents) {
  static char buff[64];
  int idx = 0;
  char *d = buff;
  if (cents == 0) {
    strcpy(buff, "0.00");
  } else if (cents < 100) {
    sprintf(buff, "0.%2.2ld", cents);
  } else {
    while (cents > 0) {
      *d++ = '0' + (cents % 10);
      cents = cents / 10;
      if (idx == 1) {
        *d++ = '.';
      } else if (cents > 0 && (idx - 1) % 3 == 0) {
        *d++ = ',';
      }
      idx++;
    }
    *d++ = 0;
    reverse(buff);
  }
  return (buff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cents2money>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L32
  mov    %rdi,%r8
  xor    %r9d,%r9d
  lea    D24(%rip),%r12
  movabs $0x6666666666666667,%r11
  mov    %r12,%rdi
  cmp    $0x63,%r8
  jg     L5
  mov    %r8,%rdx
  lea    D35(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L38:
  cmp    $0x9,%rax
  jle    L15
  lea    -0x1(%r9),%eax
  imul   $0xaaaaaaab,%eax,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L15
  movb   $0x2c,0x1(%rdi)
  add    $0x2,%rdi
L55:
  add    $0x1,%r9d
  test   %rdx,%rdx
  je     L57
L5:
  mov    %r8,%rax
  mov    %r8,%rcx
  lea    0x1(%rdi),%r10
  imul   %r11
  mov    %r8,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  mov    %r8,%rax
  lea    (%rdx,%rdx,4),%rsi
  mov    %rdx,%r8
  add    %rsi,%rsi
  sub    %rsi,%rcx
  add    $0x30,%ecx
  mov    %cl,(%rdi)
  cmp    $0x1,%r9d
  jne    L38
  movb   $0x2e,0x1(%rdi)
  add    $0x1,%r9d
  add    $0x2,%rdi
  test   %rdx,%rdx
  jne    L5
L57:
  movb   $0x0,(%rdi)
  mov    %r12,%rdi
  call   <reverse@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  mov    %r10,%rdi
  jmp    L55
  nopl   (%rax)
L32:
  lea    D24(%rip),%r12
  lea    D23(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: string

tool: D35: 0.%2.2ld

tool: D23: 0.00

assistant: ```c
const char *cents2money(long cents) {
  static char buff[64];
  int idx = 0;
  char *d = buff;
  if (cents == 0) {
    strcpy(buff, "0.00");
  } else if (cents < 100) {
    sprintf(buff, "0.%2.2ld", cents);
  } else {
    while (cents > 0) {
      *d++ = '0' + (cents % 10);
      cents = cents / 10;
      if (idx == 1) {
        *d++ = '.';
      } else if (cents > 0 && (idx - 1) % 3 == 0) {
        *d++ = ',';
      }
      idx++;
    }
    *d++ = 0;
    reverse(buff);
  }
  return (buff);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cents2money>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L43
  mov    %rdi,%r8
  xor    %r9d,%r9d
  lea    D18(%rip),%r12
  movabs $0x6666666666666667,%r11
  mov    %r12,%rdi
  cmp    $0x63,%r8
  jg     L65
  mov    %r8,%rdx
  lea    D39(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L48:
  cmp    $0x9,%rax
  jle    L67
  lea    -0x1(%r9),%eax
  imul   $0xaaaaaaab,%eax,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L67
  movb   $0x2c,0x1(%rdi)
  add    $0x2,%rdi
L57:
  add    $0x1,%r9d
  test   %rdx,%rdx
  je     L2
L65:
  mov    %r8,%rax
  mov    %r8,%rcx
  lea    0x1(%rdi),%r10
  imul   %r11
  mov    %r8,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  mov    %r8,%rax
  lea    (%rdx,%rdx,4),%rsi
  mov    %rdx,%r8
  add    %rsi,%rsi
  sub    %rsi,%rcx
  add    $0x30,%ecx
  mov    %cl,(%rdi)
  cmp    $0x1,%r9d
  jne    L48
  movb   $0x2e,0x1(%rdi)
  add    $0x1,%r9d
  add    $0x2,%rdi
  test   %rdx,%rdx
  jne    L65
L2:
  movb   $0x0,(%rdi)
  mov    %r12,%rdi
  call   <reverse@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L67:
  mov    %r10,%rdi
  jmp    L57
  nopl   (%rax)
L43:
  lea    D18(%rip),%r12
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
data_type: string
name: retrieve_data
arguments: data_tag: D16
data_type: string

tool: D39: 0.%2.2ld

tool: D16: 0.00

assistant: ```c
const char *cents2money(long cents) {
  static char buff[64];
  int idx = 0;
  char *d = buff;
  if (cents == 0) {
    strcpy(buff, "0.00");
  } else if (cents < 100) {
    sprintf(buff, "0.%2.2ld", cents);
  } else {
    while (cents > 0) {
      *d++ = '0' + (cents % 10);
      cents = cents / 10;
      if (idx == 1) {
        *d++ = '.';
      } else if (cents > 0 && (idx - 1) % 3 == 0) {
        *d++ = ',';
      }
      idx++;
    }
    *d++ = 0;
    reverse(buff);
  }
  return (buff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vec_mult_ref>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x186000(%rsp),%r11
L28:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L28
  sub    $0xa30,%rsp
  mov    %rdi,-0x186a28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc3510(%rbp),%rdx
  lea    -0x186a10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <init@plt>
  movl   $0x0,-0x186a14(%rbp)
  jmp    L21
L36:
  mov    -0x186a14(%rbp),%eax
  cltq
  mov    -0x186a10(%rbp,%rax,8),%rcx
  mov    -0x186a14(%rbp),%eax
  cltq
  mov    -0xc3510(%rbp,%rax,8),%rax
  mov    -0x186a14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rsi
  mov    -0x186a28(%rbp),%rdx
  add    %rsi,%rdx
  imul   %rcx,%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x186a14(%rbp)
L21:
  cmpl   $0x1869f,-0x186a14(%rbp)
  jle    L36
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void vec_mult_ref(long long *p) {
  int i;
  long long v1[100000], v2[100000];
  init(v1, v2);
  for (i = 0; i < 100000; i++)
    p[i] = v1[i] * v2[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec_mult_ref>:
  endbr64
  push   %rbx
  lea    -0x186000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0xa10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x186a08(%rsp)
  xor    %eax,%eax
  lea    0xc3500(%rsp),%rsi
  mov    %rsp,%rdi
  call   <init@plt>
  mov    $0x0,%eax
  lea    0xc3500(%rsp),%rcx
L13:
  mov    (%rsp,%rax,1),%rdx
  imul   (%rax,%rcx,1),%rdx
  mov    %rdx,(%rbx,%rax,1)
  add    $0x8,%rax
  cmp    $0xc3500,%rax
  jne    L13
  mov    0x186a08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x186a10,%rsp
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vec_mult_ref(long long *p) {
  int i;
  long long v1[100000], v2[100000];
  init(v1, v2);
  for (i = 0; i < 100000; i++)
    p[i] = v1[i] * v2[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vec_mult_ref>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x186000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0xa10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a08(%rsp)
  xor    %eax,%eax
  lea    0xc3500(%rsp),%r12
  mov    %rsp,%rbp
  mov    %rdi,%rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <init@plt>
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    0x0(%rbp,%rax,1),%rdx
  imul   (%r12,%rax,1),%rdx
  mov    %rdx,(%rbx,%rax,1)
  add    $0x8,%rax
  cmp    $0xc3500,%rax
  jne    L27
  mov    0x186a08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x186a10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vec_mult_ref(long long *p) {
  int i;
  long long v1[100000], v2[100000];
  init(v1, v2);
  for (i = 0; i < 100000; i++)
    p[i] = v1[i] * v2[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vec_mult_ref>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x186000(%rsp),%r11
L13:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L13
  sub    $0xa10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a08(%rsp)
  xor    %eax,%eax
  lea    0xc3500(%rsp),%r12
  mov    %rsp,%rbp
  mov    %rdi,%rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <init@plt>
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    0x0(%rbp,%rax,1),%rdx
  imul   (%r12,%rax,1),%rdx
  mov    %rdx,(%rbx,%rax,1)
  add    $0x8,%rax
  cmp    $0xc3500,%rax
  jne    L11
  mov    0x186a08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x186a10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vec_mult_ref(long long *p) {
  int i;
  long long v1[100000], v2[100000];
  init(v1, v2);
  for (i = 0; i < 100000; i++)
    p[i] = v1[i] * v2[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_attempt_work_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   -0x20(%rbp)
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    %rax,%rcx
  mov    $0x4,%edx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <concatenate@plt>
  add    $0x10,%rsp
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D14
type: string

tool: D2: attempt_dir_path

tool: D14: %s/taskTracker/%s/jobcache/%s/%s/work

assistant: ```c
char *get_attempt_work_directory(const char *tt_root, const char *user, const char *job_id, const char *attempt_id) {
  return concatenate("%s/taskTracker/%s"
                     "/jobcache/%s"
                     "/%s/work",
                     "attempt_dir_path", 4, tt_root, user, job_id, attempt_id);
}
```