ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_socket_base_path>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  mov    $0x6,%edx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  mov    $0x80,%edi
  call   <my_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L57
  mov    %rbp,%rdx
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L57:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %rbx,%rax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  sub    %rax,%rdx
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <strncpy@plt>
  mov    $0x80,%edi
  call   <my_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L57
  mov    %rsp,%rsi
  mov    $0x5,%edx
  mov    $0x2f,%edi
  call   <my_nstrchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L39
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    %rax,%rbp
  lea    0x1(%rbp),%rsi
  mov    %r12,%rcx
  lea    D14(%rip),%rdx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  jmp    L57
L39:
  mov    %rsp,%rdx
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  jmp    L57
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string
name: read_data
arguments: data_label: D14
datatype: string

tool: D1: rmroot

tool: D14: %s

assistant: ```c
char *get_socket_base_path(char *cmd) {
  char *temp = NULL;
  char *temp1 = NULL;
  char path[1024] = {0};
  char *root_path = NULL;
  if (!strncmp(cmd, "rmroot", 6)) {
    temp = strchr(cmd, '/');
    root_path = my_malloc(128);
    if (root_path == NULL)
      return NULL;
    sprintf(root_path, "%s", temp);
  } else {
    temp = strchr(cmd, '/');
    temp1 = strchr(temp, '\n');
    strncpy(path, temp, strlen(temp) - strlen(temp1));
    root_path = my_malloc(128);
    if (root_path == NULL)
      return NULL;
    temp = my_nstrchr('/', path, 5);
    if (temp == NULL) {
      sprintf(root_path, "%s", path);
    } else {
      snprintf(root_path, strlen(path) - strlen(temp) + 1, "%s", path);
    }
  }
  return root_path;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_socket_base_path>:
  endbr64
  push   %r13
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  mov    $0x6,%edx
  push   %r12
  mov    %rdi,%r12
  lea    D3(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    $0x2f,%esi
  mov    %r12,%rdi
  test   %eax,%eax
  jne    L3
  call   <strchr@plt>
  mov    $0x80,%edi
  mov    %rax,%r13
  call   <my_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
L0:
  mov    %r13,%rdx
  lea    D13(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
L5:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x418,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <strchr@plt>
  mov    $0xa,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strchr@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rsp,%r13
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  sub    %rax,%rbx
  mov    %rbx,%rdx
  call   <strncpy@plt>
  mov    $0x80,%edi
  call   <my_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    $0x2f,%edi
  call   <my_nstrchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L0
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r13,%rcx
  lea    D13(%rip),%rdx
  mov    %r12,%rdi
  sub    %rax,%rbx
  lea    0x1(%rbx),%rsi
  call   <snprintf@plt>
  jmp    L5
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D13
type_guessed: string

tool: D3: rmroot

tool: D13: %s

assistant: ```c
char *get_socket_base_path(char *cmd) {
  char *temp = NULL;
  char *temp1 = NULL;
  char path[1024] = {0};
  char *root_path = NULL;
  if (!strncmp(cmd, "rmroot", 6)) {
    temp = strchr(cmd, '/');
    root_path = my_malloc(128);
    if (root_path == NULL)
      return NULL;
    sprintf(root_path, "%s", temp);
  } else {
    temp = strchr(cmd, '/');
    temp1 = strchr(temp, '\n');
    strncpy(path, temp, strlen(temp) - strlen(temp1));
    root_path = my_malloc(128);
    if (root_path == NULL)
      return NULL;
    temp = my_nstrchr('/', path, 5);
    if (temp == NULL) {
      sprintf(root_path, "%s", path);
    } else {
      snprintf(root_path, strlen(path) - strlen(temp) + 1, "%s", path);
    }
  }
  return root_path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_socket_base_path>:
  endbr64
  push   %r13
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  mov    $0x6,%edx
  push   %r12
  mov    %rdi,%r12
  lea    D1(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    $0x2f,%esi
  mov    %r12,%rdi
  test   %eax,%eax
  jne    L37
  call   <strchr@plt>
  mov    $0x80,%edi
  mov    %rax,%r13
  call   <my_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L51
L6:
  mov    %r13,%rdx
  lea    D25(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
L51:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x418,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  call   <strchr@plt>
  mov    $0xa,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strchr@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rsp,%r13
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  sub    %rax,%rbx
  mov    %rbx,%rdx
  call   <strncpy@plt>
  mov    $0x80,%edi
  call   <my_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L51
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    $0x2f,%edi
  call   <my_nstrchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r13,%rcx
  lea    D25(%rip),%rdx
  mov    %r12,%rdi
  sub    %rax,%rbx
  lea    0x1(%rbx),%rsi
  call   <snprintf@plt>
  jmp    L51
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type: string
name: parse_data
arguments: tag: D25
type: string

tool: D1: rmroot

tool: D25: %s

assistant: ```c
char *get_socket_base_path(char *cmd) {
  char *temp = NULL;
  char *temp1 = NULL;
  char path[1024] = {0};
  char *root_path = NULL;
  if (!strncmp(cmd, "rmroot", 6)) {
    temp = strchr(cmd, '/');
    root_path = my_malloc(128);
    if (root_path == NULL)
      return NULL;
    sprintf(root_path, "%s", temp);
  } else {
    temp = strchr(cmd, '/');
    temp1 = strchr(temp, '\n');
    strncpy(path, temp, strlen(temp) - strlen(temp1));
    root_path = my_malloc(128);
    if (root_path == NULL)
      return NULL;
    temp = my_nstrchr('/', path, 5);
    if (temp == NULL) {
      sprintf(root_path, "%s", path);
    } else {
      snprintf(root_path, strlen(path) - strlen(temp) + 1, "%s", path);
    }
  }
  return root_path;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<japi_deactivate_grammar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <do_send@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <send_idlist@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: DEACTIVATEGRAM


assistant: ```c
void japi_deactivate_grammar(int sd, char *idlist) {
  do_send(sd, "DEACTIVATEGRAM\n");
  send_idlist(sd, idlist);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<japi_deactivate_grammar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    D6(%rip),%rsi
  call   <do_send@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <send_idlist@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D6: DEACTIVATEGRAM


assistant: ```c
void japi_deactivate_grammar(int sd, char *idlist) {
  do_send(sd, "DEACTIVATEGRAM\n");
  send_idlist(sd, idlist);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<japi_deactivate_grammar>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <do_send@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <send_idlist@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: DEACTIVATEGRAM


assistant: ```c
void japi_deactivate_grammar(int sd, char *idlist) {
  do_send(sd, "DEACTIVATEGRAM\n");
  send_idlist(sd, idlist);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<japi_deactivate_grammar>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D3(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <do_send@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <send_idlist@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: DEACTIVATEGRAM


assistant: ```c
void japi_deactivate_grammar(int sd, char *idlist) {
  do_send(sd, "DEACTIVATEGRAM\n");
  send_idlist(sd, idlist);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <testFile@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L21
  mov    $0x0,%eax
  jmp    L8
L21:
  cmpl   $0x0,-0x4(%rbp)
  jg     L38
  mov    $0x1,%eax
  jmp    L8
L38:
  mov    -0x4(%rbp),%eax
L8:
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int resultCode = testFile(argv[1]);
  if (resultCode > 0)
    return 0;
  if (resultCode <= 0)
    return 1;
  return resultCode;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <testFile@plt>
  test   %eax,%eax
  setle  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int resultCode = testFile(argv[1]);
  if (resultCode > 0)
    return 0;
  if (resultCode <= 0)
    return 1;
  return resultCode;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <testFile@plt>
  test   %eax,%eax
  setle  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int resultCode = testFile(argv[1]);
  if (resultCode > 0)
    return 0;
  if (resultCode <= 0)
    return 1;
  return resultCode;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <testFile@plt>
  test   %eax,%eax
  setle  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int resultCode = testFile(argv[1]);
  if (resultCode > 0)
    return 0;
  if (resultCode <= 0)
    return 1;
  return resultCode;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L1:
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *psz, int cch) {
  int ich;
  char chTemp;
  for (ich = 0; ich < --cch; ich++) {
    chTemp = psz[ich];
    psz[ich] = psz[cch];
    psz[cch] = chTemp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L17
  movslq %esi,%rsi
  mov    $0x0,%eax
L19:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dl,(%rdi,%rsi,1)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L19
L17:
  ret
```

assistant: ```c
void reverse(char *psz, int cch) {
  int ich;
  char chTemp;
  for (ich = 0; ich < --cch; ich++) {
    chTemp = psz[ich];
    psz[ich] = psz[cch];
    psz[cch] = chTemp;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L16
  movslq %esi,%rsi
  xor    %eax,%eax
L12:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L12
L16:
  ret
```

assistant: ```c
void reverse(char *psz, int cch) {
  int ich;
  char chTemp;
  for (ich = 0; ich < --cch; ich++) {
    chTemp = psz[ich];
    psz[ich] = psz[cch];
    psz[cch] = chTemp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L16
  movslq %esi,%rsi
  xor    %eax,%eax
L3:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L3
L16:
  ret
```

assistant: ```c
void reverse(char *psz, int cch) {
  int ich;
  char chTemp;
  for (ich = 0; ich < --cch; ich++) {
    chTemp = psz[ich];
    psz[ich] = psz[cch];
    psz[cch] = chTemp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calpriv_fbt_search_l_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  sub    $0x8,%rsp
  push   0x18(%rbp)
  mov    0x10(%rbp),%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <cal_linear_ordered_search@plt>
  add    $0x10,%rsp
  leave
  ret
```

assistant: ```c
int calpriv_fbt_search_l_search(void *ctx, const void *key, const void *ptr, size_t count, size_t size, int (*cmp)(void *, const void *, const void *), void *cmp_ctx, size_t *pos_out) {
  (void)ctx;
  return cal_linear_ordered_search(key, ptr, count, size, cmp, cmp_ctx, pos_out);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calpriv_fbt_search_l_search>:
  endbr64
  sub    $0x10,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %r8,%rcx
  mov    %r9,%r8
  push   0x20(%rsp)
  mov    0x20(%rsp),%r9
  call   <cal_linear_ordered_search@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int calpriv_fbt_search_l_search(void *ctx, const void *key, const void *ptr, size_t count, size_t size, int (*cmp)(void *, const void *, const void *), void *cmp_ctx, size_t *pos_out) {
  (void)ctx;
  return cal_linear_ordered_search(key, ptr, count, size, cmp, cmp_ctx, pos_out);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calpriv_fbt_search_l_search>:
  endbr64
  mov    0x10(%rsp),%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %r8,%rcx
  mov    %r9,%r8
  mov    0x8(%rsp),%r9
  mov    %rax,0x8(%rsp)
  jmp    1050 <cal_linear_ordered_search@plt>
```

assistant: ```c
int calpriv_fbt_search_l_search(void *ctx, const void *key, const void *ptr, size_t count, size_t size, int (*cmp)(void *, const void *, const void *), void *cmp_ctx, size_t *pos_out) {
  (void)ctx;
  return cal_linear_ordered_search(key, ptr, count, size, cmp, cmp_ctx, pos_out);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calpriv_fbt_search_l_search>:
  endbr64
  mov    0x10(%rsp),%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %r8,%rcx
  mov    %r9,%r8
  mov    0x8(%rsp),%r9
  mov    %rax,0x8(%rsp)
  jmp    1050 <cal_linear_ordered_search@plt>
```

assistant: ```c
int calpriv_fbt_search_l_search(void *ctx, const void *key, const void *ptr, size_t count, size_t size, int (*cmp)(void *, const void *, const void *), void *cmp_ctx, size_t *pos_out) {
  (void)ctx;
  return cal_linear_ordered_search(key, ptr, count, size, cmp, cmp_ctx, pos_out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L17
L69:
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  jmp    L11
L71:
  subl   $0x1,-0x4(%rbp)
  jmp    L64
L22:
  addl   $0x1,-0x8(%rbp)
  subl   $0x2,-0x4(%rbp)
L64:
  mov    -0x8(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L43
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L22
L43:
  subl   $0x1,-0x4(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L15
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L71
L15:
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
L17:
  cmpl   $0x1,-0x8(%rbp)
  jg     L69
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  while (x >= 2) {
    x--;
    y = y + x;
    while (y >= x + 1 && __VERIFIER_nondet_int()) {
      y--;
      while (y >= x + 3 && __VERIFIER_nondet_int()) {
        x++;
        y = y - 2;
      }
      y--;
    }
    x--;
    y = y - x;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  cmp    $0x1,%ebx
  jg     L65
L37:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L83:
  mov    %eax,%ebx
L78:
  sub    $0x1,%ebp
  cmp    %ebx,%ebp
  jle    L38
L45:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  je     L38
  sub    $0x1,%ebp
  lea    0x2(%rbx),%eax
  cmp    %eax,%ebp
  jle    L78
L56:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  je     L78
  lea    0x1(%rbx),%eax
  sub    $0x2,%ebp
  add    $0x3,%ebx
  cmp    %ebx,%ebp
  jle    L83
  mov    %eax,%ebx
  jmp    L56
L38:
  sub    $0x1,%ebx
  sub    %ebx,%ebp
  cmp    $0x1,%ebx
  jle    L37
L65:
  sub    $0x1,%ebx
  add    %ebx,%ebp
  cmp    %ebp,%ebx
  jl     L45
  jmp    L38
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  while (x >= 2) {
    x--;
    y = y + x;
    while (y >= x + 1 && __VERIFIER_nondet_int()) {
      y--;
      while (y >= x + 3 && __VERIFIER_nondet_int()) {
        x++;
        y = y - 2;
      }
      y--;
    }
    x--;
    y = y - x;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x1,%ebx
  jle    L69
  mov    %eax,%ebp
  nopl   0x0(%rax)
L83:
  sub    $0x1,%ebx
  add    %ebx,%ebp
  cmp    %ebp,%ebx
  jge    L59
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  je     L59
  sub    $0x1,%ebp
  lea    0x2(%rbx),%eax
  cmp    %eax,%ebp
  jg     L74
  jmp    L48
  nop
L34:
  lea    0x1(%rbx),%eax
  sub    $0x2,%ebp
  add    $0x3,%ebx
  cmp    %ebp,%ebx
  mov    %eax,%ebx
  jge    L48
L74:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L34
L48:
  sub    $0x1,%ebp
  cmp    %ebx,%ebp
  jg     L45
L59:
  sub    $0x1,%ebx
  sub    %ebx,%ebp
  cmp    $0x1,%ebx
  jg     L83
L69:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  while (x >= 2) {
    x--;
    y = y + x;
    while (y >= x + 1 && __VERIFIER_nondet_int()) {
      y--;
      while (y >= x + 3 && __VERIFIER_nondet_int()) {
        x++;
        y = y - 2;
      }
      y--;
    }
    x--;
    y = y - x;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x1,%ebx
  jle    L51
  mov    %eax,%ebp
  nopl   0x0(%rax)
L84:
  sub    $0x1,%ebx
  add    %ebx,%ebp
  cmp    %ebp,%ebx
  jge    L65
  nopl   0x0(%rax)
L89:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  je     L65
  sub    $0x1,%ebp
  lea    0x2(%rbx),%eax
  cmp    %eax,%ebp
  jg     L50
  jmp    L5
  nop
L71:
  lea    0x1(%rbx),%eax
  sub    $0x2,%ebp
  add    $0x3,%ebx
  cmp    %ebx,%ebp
  mov    %eax,%ebx
  jle    L5
L50:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L71
L5:
  sub    $0x1,%ebp
  cmp    %ebx,%ebp
  jg     L89
L65:
  sub    $0x1,%ebx
  sub    %ebx,%ebp
  cmp    $0x1,%ebx
  jg     L84
L51:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  while (x >= 2) {
    x--;
    y = y + x;
    while (y >= x + 1 && __VERIFIER_nondet_int()) {
      y--;
      while (y >= x + 3 && __VERIFIER_nondet_int()) {
        x++;
        y = y - 2;
      }
      y--;
    }
    x--;
    y = y - x;
  }
  return 0;
}
```