user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<imparreglos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x54(%rbp)
  jne    L26
  movl   $0xffffffff,-0x30(%rbp)
  movl   $0xfffffffe,-0x2c(%rbp)
  movl   $0xfffffffd,-0x28(%rbp)
  movl   $0xfffffffc,-0x24(%rbp)
  movl   $0xfffffffb,-0x20(%rbp)
  movl   $0xfffffffa,-0x1c(%rbp)
  movl   $0xfffffff9,-0x18(%rbp)
  movl   $0xfffffff8,-0x14(%rbp)
  movl   $0xfffffff7,-0x10(%rbp)
  movl   $0xfffffff6,-0xc(%rbp)
  movl   $0xa,-0x38(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L40
L17:
  mov    -0x44(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L21
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  addl   $0x1,-0x44(%rbp)
L40:
  mov    -0x44(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L17
  jmp    L93
L26:
  movl   $0xffffffff,-0x30(%rbp)
  movl   $0xfffffffe,-0x2c(%rbp)
  movl   $0xfffffffd,-0x28(%rbp)
  movl   $0xfffffffc,-0x24(%rbp)
  movl   $0xfffffffb,-0x20(%rbp)
  movl   $0xfffffffa,-0x1c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x3,-0x34(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L3
L63:
  movl   $0x0,-0x40(%rbp)
  jmp    L88
L55:
  mov    -0x44(%rbp),%edx
  mov    -0x40(%rbp),%eax
  add    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L84
  mov    -0x40(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L84:
  addl   $0x1,-0x3c(%rbp)
  addl   $0x1,-0x40(%rbp)
L88:
  mov    -0x40(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L55
  addl   $0x1,-0x44(%rbp)
L3:
  mov    -0x44(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L63
L93:
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L83
  call   <__stack_chk_fail@plt>
L83:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D14
type_infered: string
name: read_data
arguments: tag: D33
type_infered: string

tool: D14: 
Las entradas impares del vector, son:

tool: D33: p[%d] = %d


assistant: ```c
int imparreglos(int dimen) {
  int i, j, filas, columnas;
  if (dimen == 1) {
    int vector[] = {-1, -2, -3, -4, -5, -6, -7, -8, -9, -10};
    int *p;
    filas = sizeof(vector) / sizeof(vector[0]);
    printf("\nLas entradas impares del vector, son:\n");
    for (i = 0; i < filas; i++) {
      if (i % 2 != 0)
        printf("p[%d] = %d\n", i, vector[i]);
    }
  } else {
    int vector[][3] = {{-1, -2, -3}, {-4, -5, -6}};
    int(*p)[][3];
    filas = sizeof(vector) / sizeof(vector[0]);
    columnas = sizeof(vector[0]) / sizeof(vector[0][0]);
    printf("\nLas entradas impares del vector, son:\n");
    int k = 0;
    for (i = 0; i < filas; i++) {
      for (j = 0; j < columnas; j++) {
        if ((i + j) % 2 != 0)
          printf("p[%d] = %d\n", k, vector[i][j]);
        k++;
      }
    }
  }
}
```