ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strchr>:
  endbr64
  mov    %esi,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
  cmp    %sil,%al
  je     L33
L0:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
  cmp    %dl,%al
  jne    L0
L33:
  cmp    %sil,%al
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  char tmp = (char)c;
  while ((*s != tmp) && (*s != '\0'))
    s++;
  return (*s == tmp) ? (char *)s : NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%edx
  cmp    %sil,%al
  jne    L19
  jmp    L2
L23:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    %dl,%al
  je     L2
L19:
  test   %al,%al
  jne    L23
  xor    %eax,%eax
  test   %sil,%sil
  cmove  %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  char tmp = (char)c;
  while ((*s != tmp) && (*s != '\0'))
    s++;
  return (*s == tmp) ? (char *)s : NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%edx
  cmp    %sil,%al
  jne    L25
  jmp    L21
L0:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    %dl,%al
  je     L21
L25:
  test   %al,%al
  jne    L0
  xor    %eax,%eax
  test   %sil,%sil
  cmove  %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  char tmp = (char)c;
  while ((*s != tmp) && (*s != '\0'))
    s++;
  return (*s == tmp) ? (char *)s : NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<NetBucket_quick_send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <NetMes_set_flags@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <NetBucket_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void NetBucket_quick_send(struct NetBucket *nbucket, struct NetMes *nmes) {
  NetMes_set_flags(nmes, 0X0);
  NetBucket_write(nbucket, nmes);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NetBucket_quick_send>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <NetMes_set_flags@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <NetBucket_write@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void NetBucket_quick_send(struct NetBucket *nbucket, struct NetMes *nmes) {
  NetMes_set_flags(nmes, 0X0);
  NetBucket_write(nbucket, nmes);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<NetBucket_quick_send>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <NetMes_set_flags@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <NetBucket_write@plt>
```

assistant: ```c
void NetBucket_quick_send(struct NetBucket *nbucket, struct NetMes *nmes) {
  NetMes_set_flags(nmes, 0X0);
  NetBucket_write(nbucket, nmes);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<NetBucket_quick_send>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <NetMes_set_flags@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <NetBucket_write@plt>
```

assistant: ```c
void NetBucket_quick_send(struct NetBucket *nbucket, struct NetMes *nmes) {
  NetMes_set_flags(nmes, 0X0);
  NetBucket_write(nbucket, nmes);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L23
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x24(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <solute@plt>
  mov    %rax,(%rbx)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L48
L23:
  movl   $0x0,-0x14(%rbp)
  jmp    L34
L6:
  cmpl   $0x0,-0x28(%rbp)
  je     L15
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <conflict@plt>
  test   %eax,%eax
  jne    L0
L15:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x48(%rbp),%r8
  mov    -0x40(%rbp),%rdi
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <dfs>
L0:
  addl   $0x1,-0x14(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L6
L48:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void dfs(int n, int row, int *stack, char ***solutions, int *count, int *col_sizes) {
  int col;
  if (row == n) {
    solutions[*count] = solute(stack, n);
    col_sizes[*count] = n;
    (*count)++;
  } else {
    for (col = 0; col < n; col++) {
      if (row == 0 || !conflict(stack, row, col)) {
        stack[row] = col;
        dfs(n, row + 1, stack, solutions, count, col_sizes);
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<dfs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r12d
  mov    %rdx,%r13
  mov    %rcx,0x8(%rsp)
  mov    %r8,%r14
  mov    %r9,0x10(%rsp)
  cmp    %edi,%esi
  je     L45
  mov    %esi,%ebp
  test   %edi,%edi
  jle    L3
  movslq %esi,%rax
  lea    (%rdx,%rax,4),%r15
  mov    $0x0,%ebx
  lea    0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
  jmp    L20
L45:
  movslq (%r8),%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,8),%rbx
  mov    %edi,%esi
  mov    %rdx,%rdi
  call   <solute@plt>
  mov    %rax,(%rbx)
  movslq (%r14),%rax
  mov    0x10(%rsp),%rcx
  mov    %r12d,(%rcx,%rax,4)
  addl   $0x1,(%r14)
L3:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %ebx,(%r15)
  mov    0x10(%rsp),%r9
  mov    %r14,%r8
  mov    0x8(%rsp),%rcx
  mov    %r13,%rdx
  mov    0x1c(%rsp),%esi
  mov    %r12d,%edi
  call   <dfs>
L27:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L3
L20:
  test   %ebp,%ebp
  je     L4
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <conflict@plt>
  test   %eax,%eax
  jne    L27
  jmp    L4
```

assistant: ```c
void dfs(int n, int row, int *stack, char ***solutions, int *count, int *col_sizes) {
  int col;
  if (row == n) {
    solutions[*count] = solute(stack, n);
    col_sizes[*count] = n;
    (*count)++;
  } else {
    for (col = 0; col < n; col++) {
      if (row == 0 || !conflict(stack, row, col)) {
        stack[row] = col;
        dfs(n, row + 1, stack, solutions, count, col_sizes);
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<dfs>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %r9,%r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  cmp    %edi,%esi
  je     L18
  mov    %edi,%r13d
  test   %edi,%edi
  jle    L35
  movslq %esi,%rax
  xor    %ebx,%ebx
  lea    (%rdx,%rax,4),%rax
  mov    %rax,0x10(%rsp)
  lea    0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
L2:
  test   %ebp,%ebp
  je     L9
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <conflict@plt>
  test   %eax,%eax
  jne    L7
L9:
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rcx
  mov    %r14,%r9
  mov    %r12,%r8
  mov    0x1c(%rsp),%esi
  mov    %r15,%rdx
  mov    %r13d,%edi
  mov    %ebx,(%rax)
  call   <dfs>
L7:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L2
L35:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L18:
  mov    0x8(%rsp),%rcx
  movslq (%r8),%rax
  mov    %rdx,%rdi
  lea    (%rcx,%rax,8),%rbx
  call   <solute@plt>
  mov    %rax,(%rbx)
  movslq (%r12),%rax
  mov    %ebp,(%r14,%rax,4)
  addl   $0x1,(%r12)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void dfs(int n, int row, int *stack, char ***solutions, int *count, int *col_sizes) {
  int col;
  if (row == n) {
    solutions[*count] = solute(stack, n);
    col_sizes[*count] = n;
    (*count)++;
  } else {
    for (col = 0; col < n; col++) {
      if (row == 0 || !conflict(stack, row, col)) {
        stack[row] = col;
        dfs(n, row + 1, stack, solutions, count, col_sizes);
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dfs>:
  endbr64
  push   %r15
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  cmp    %edi,%esi
  je     L0
  mov    %edi,%ebp
  test   %edi,%edi
  jle    L29
  movslq %esi,%rax
  lea    (%rdx,%rax,4),%rax
  mov    %rax,0x10(%rsp)
  test   %esi,%esi
  je     L21
  lea    0x1(%rsi),%eax
  xor    %r15d,%r15d
  mov    %eax,0x1c(%rsp)
L62:
  mov    %r15d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <conflict@plt>
  test   %eax,%eax
  jne    L46
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rcx
  mov    %r14,%r9
  mov    %r12,%r8
  mov    0x1c(%rsp),%esi
  mov    %r13,%rdx
  mov    %ebp,%edi
  mov    %r15d,(%rax)
  call   <dfs>
L46:
  add    $0x1,%r15d
  cmp    %r15d,%ebp
  jne    L62
L29:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rcx
  mov    %r14,%r9
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x1,%esi
  mov    %ebp,%edi
  mov    %ebx,(%rax)
  add    $0x1,%ebx
  call   <dfs>
  cmp    %ebx,%ebp
  jne    L21
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L0:
  movslq (%r8),%rax
  mov    %rdx,%rdi
  lea    (%rcx,%rax,8),%rbp
  call   <solute@plt>
  mov    %rax,0x0(%rbp)
  movslq (%r12),%rax
  mov    %ebx,(%r14,%rax,4)
  addl   $0x1,(%r12)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void dfs(int n, int row, int *stack, char ***solutions, int *count, int *col_sizes) {
  int col;
  if (row == n) {
    solutions[*count] = solute(stack, n);
    col_sizes[*count] = n;
    (*count)++;
  } else {
    for (col = 0; col < n; col++) {
      if (row == 0 || !conflict(stack, row, col)) {
        stack[row] = col;
        dfs(n, row + 1, stack, solutions, count, col_sizes);
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sumOfDigits@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D20
data_type: string
name: parse_data
arguments: tag: D17
data_type: string
name: parse_data
arguments: tag: D21
data_type: string

tool: D20: Enter number to be summed: 

tool: D17: %d

tool: D21: 
The sum of digits is %d 


assistant: ```c
int main() {
  int num;
  printf("Enter number to be summed: ");
  scanf("%d", &num);
  printf("\nThe sum of digits is %d \n", sumOfDigits(num));
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <sumOfDigits@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type_infered: string
name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D22: Enter number to be summed: 

tool: D25: %d

tool: D0: 
The sum of digits is %d 


assistant: ```c
int main() {
  int num;
  printf("Enter number to be summed: ");
  scanf("%d", &num);
  printf("\nThe sum of digits is %d \n", sumOfDigits(num));
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <sumOfDigits@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string
name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D16: Enter number to be summed: 

tool: D3: %d

tool: D6: 
The sum of digits is %d 


assistant: ```c
int main() {
  int num;
  printf("Enter number to be summed: ");
  scanf("%d", &num);
  printf("\nThe sum of digits is %d \n", sumOfDigits(num));
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <sumOfDigits@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D24
type_infered: string

tool: D1: Enter number to be summed: 

tool: D20: %d

tool: D24: 
The sum of digits is %d 


assistant: ```c
int main() {
  int num;
  printf("Enter number to be summed: ");
  scanf("%d", &num);
  printf("\nThe sum of digits is %d \n", sumOfDigits(num));
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_piece_css>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  cmp    $0x1,%eax
  jne    L7
  mov    -0x10(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L14
L7:
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  cmp    $0x2,%eax
  jne    L82
  mov    -0x10(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L14
L82:
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  cmp    $0x3,%eax
  jne    L23
  mov    -0x10(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L14
L23:
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  cmp    $0x4,%eax
  jne    L75
  mov    -0x10(%rbp),%rax
  lea    D57(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L14
L75:
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  cmp    $0x5,%eax
  jne    L94
  mov    -0x10(%rbp),%rax
  lea    D51(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L14
L94:
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  cmp    $0x6,%eax
  jne    L14
  mov    -0x10(%rbp),%rax
  lea    D55(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L14:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D31
data_type: string
name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D57
data_type: string
name: retrieve_data
arguments: label: D51
data_type: string
name: retrieve_data
arguments: label: D55
data_type: string

tool: D11: pawn

tool: D31: tower

tool: D17: horse

tool: D57: bishop

tool: D51: queen

tool: D55: king

assistant: ```c
void print_piece_css(unsigned int piece, char *text) {
  if (0) {
  } else if ((piece & 7) == 1)
    sprintf(text, "pawn");
  else if ((piece & 7) == 2)
    sprintf(text, "tower");
  else if ((piece & 7) == 3)
    sprintf(text, "horse");
  else if ((piece & 7) == 4)
    sprintf(text, "bishop");
  else if ((piece & 7) == 5)
    sprintf(text, "queen");
  else if ((piece & 7) == 6)
    sprintf(text, "king");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_piece_css>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rax
  and    $0x7,%edi
  cmp    $0x1,%edi
  je     L25
  cmp    $0x6,%edi
  ja     L52
  mov    %edi,%edi
  lea    D28(%rip),%rcx
  movslq (%rcx,%rdi,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
L25:
  lea    D56(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L52:
  add    $0x8,%rsp
  ret
  lea    D64(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L52
  lea    D31(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L52
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L52
  lea    D17(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L52
  lea    D49(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L52
```

tool_calls: name: retrieve_data
arguments: data_label: D56
type_infered: string
name: retrieve_data
arguments: data_label: D64
type_infered: string
name: retrieve_data
arguments: data_label: D31
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D49
type_infered: string

tool: D56: pawn

tool: D64: tower

tool: D31: horse

tool: D8: bishop

tool: D17: queen

tool: D49: king

assistant: ```c
void print_piece_css(unsigned int piece, char *text) {
  if (0) {
  } else if ((piece & 7) == 1)
    sprintf(text, "pawn");
  else if ((piece & 7) == 2)
    sprintf(text, "tower");
  else if ((piece & 7) == 3)
    sprintf(text, "horse");
  else if ((piece & 7) == 4)
    sprintf(text, "bishop");
  else if ((piece & 7) == 5)
    sprintf(text, "queen");
  else if ((piece & 7) == 6)
    sprintf(text, "king");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_piece_css>:
  endbr64
  and    $0x7,%edi
  mov    %rsi,%r8
  cmp    $0x1,%edi
  je     L10
  cmp    $0x6,%edi
  ja     L3
  lea    D45(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L10:
  lea    D60(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nopw   0x0(%rax,%rax,1)
  lea    D49(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nop
  lea    D28(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nop
  lea    D46(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nop
  lea    D59(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nop
  lea    D51(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D60
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D49
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D46
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D59
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D51
type_guessed: string

tool: D60: pawn

tool: D49: king

tool: D28: tower

tool: D46: horse

tool: D59: bishop

tool: D51: queen

assistant: ```c
void print_piece_css(unsigned int piece, char *text) {
  if (0) {
  } else if ((piece & 7) == 1)
    sprintf(text, "pawn");
  else if ((piece & 7) == 2)
    sprintf(text, "tower");
  else if ((piece & 7) == 3)
    sprintf(text, "horse");
  else if ((piece & 7) == 4)
    sprintf(text, "bishop");
  else if ((piece & 7) == 5)
    sprintf(text, "queen");
  else if ((piece & 7) == 6)
    sprintf(text, "king");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_piece_css>:
  endbr64
  and    $0x7,%edi
  mov    %rsi,%r8
  cmp    $0x1,%edi
  je     L13
  cmp    $0x6,%edi
  ja     L18
  lea    D23(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L13:
  lea    D24(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nopw   0x0(%rax,%rax,1)
  lea    D1(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nop
  lea    D43(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nop
  lea    D51(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nop
  lea    D40(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
  nop
  lea    D22(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <sprintf@plt>
L18:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D1
data_type: string
name: parse_data
arguments: data_tag: D43
data_type: string
name: parse_data
arguments: data_tag: D51
data_type: string
name: parse_data
arguments: data_tag: D40
data_type: string
name: parse_data
arguments: data_tag: D22
data_type: string

tool: D24: pawn

tool: D1: king

tool: D43: tower

tool: D51: horse

tool: D40: bishop

tool: D22: queen

assistant: ```c
void print_piece_css(unsigned int piece, char *text) {
  if (0) {
  } else if ((piece & 7) == 1)
    sprintf(text, "pawn");
  else if ((piece & 7) == 2)
    sprintf(text, "tower");
  else if ((piece & 7) == 3)
    sprintf(text, "horse");
  else if ((piece & 7) == 4)
    sprintf(text, "bishop");
  else if ((piece & 7) == 5)
    sprintf(text, "queen");
  else if ((piece & 7) == 6)
    sprintf(text, "king");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maximum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  jmp    L11
L2:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int maximum(unsigned int n, unsigned int bound) {
  if (n == bound - 1) {
    return n;
  } else {
    return n + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<maximum>:
  endbr64
  sub    $0x1,%esi
  cmp    %edi,%esi
  setne  %al
  movzbl %al,%eax
  add    %edi,%eax
  ret
```

assistant: ```c
unsigned int maximum(unsigned int n, unsigned int bound) {
  if (n == bound - 1) {
    return n;
  } else {
    return n + 1;
  }
}
```