ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_to>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D9(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rbp
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <fputs@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  call   <warn@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D9: w

tool: D2: failed to open %s

assistant: ```c
int write_to(const char *msg, const char *path) {
  FILE *fp = fopen(path, "w");
  if (!fp) {
    warn("failed to open %s", path);
    return 1;
  }
  fputs(msg, fp);
  fclose(fp);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_to>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D14(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbp
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <fputs@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %r12,%rsi
  lea    D18(%rip),%rdi
  call   <warn@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
data_type: string
name: disassemble_data
arguments: data_label: D18
data_type: string

tool: D14: w

tool: D18: failed to open %s

assistant: ```c
int write_to(const char *msg, const char *path) {
  FILE *fp = fopen(path, "w");
  if (!fp) {
    warn("failed to open %s", path);
    return 1;
  }
  fputs(msg, fp);
  fclose(fp);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<__divsi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x4(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <__udivsi3@plt>
  xor    -0x8(%rbp),%eax
  sub    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __divsi3(int a, int b) {
  int s_a = a >> 31;
  int s_b = b >> 31;
  a = (a ^ s_a) - s_a;
  b = (b ^ s_b) - s_b;
  s_a ^= s_b;
  return (__udivsi3(a, b) ^ s_a) - s_a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__divsi3>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  mov    %esi,%edx
  sar    $0x1f,%edx
  xor    %eax,%edi
  xor    %edx,%esi
  mov    %eax,%ebx
  xor    %edx,%ebx
  sub    %edx,%esi
  sub    %eax,%edi
  call   <__udivsi3@plt>
  xor    %ebx,%eax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int __divsi3(int a, int b) {
  int s_a = a >> 31;
  int s_b = b >> 31;
  a = (a ^ s_a) - s_a;
  b = (b ^ s_b) - s_b;
  s_a ^= s_b;
  return (__udivsi3(a, b) ^ s_a) - s_a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__divsi3>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  push   %rbx
  sar    $0x1f,%eax
  sar    $0x1f,%edx
  xor    %eax,%edi
  xor    %edx,%esi
  mov    %eax,%ebx
  sub    %edx,%esi
  sub    %eax,%edi
  xor    %edx,%ebx
  call   <__udivsi3@plt>
  xor    %ebx,%eax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int __divsi3(int a, int b) {
  int s_a = a >> 31;
  int s_b = b >> 31;
  a = (a ^ s_a) - s_a;
  b = (b ^ s_b) - s_b;
  s_a ^= s_b;
  return (__udivsi3(a, b) ^ s_a) - s_a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__divsi3>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  push   %rbx
  sar    $0x1f,%eax
  sar    $0x1f,%edx
  xor    %eax,%edi
  xor    %edx,%esi
  mov    %eax,%ebx
  sub    %edx,%esi
  sub    %eax,%edi
  xor    %edx,%ebx
  call   <__udivsi3@plt>
  xor    %ebx,%eax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int __divsi3(int a, int b) {
  int s_a = a >> 31;
  int s_b = b >> 31;
  a = (a ^ s_a) - s_a;
  b = (b ^ s_b) - s_b;
  s_a ^= s_b;
  return (__udivsi3(a, b) ^ s_a) - s_a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    $0x0,%edi
  call   <wait@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L18:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L5:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D40
type: string
name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D25
type: string
name: retrieve_data
arguments: data_label: D43
type: string
name: retrieve_data
arguments: data_label: D66
type: string
name: retrieve_data
arguments: data_label: D62
type: string

tool: D40: 
This is PARENT BLOCK

tool: D18: 
	* MY PID          = %d

tool: D15: 
	* MY CHILD'S PID  = %d

tool: D25: 
	* MY OWNER'S PID  = %d



tool: D43: 
THIS IS CHILD'S BLOCK

tool: D66: 
	* MY PARENT'S PID = %d

tool: D62: 
	* MY PID          = %d


assistant: ```c
void main() {
  pid_t pid = fork();
  if (pid != 0) {
    wait(0);
    printf("\nThis is PARENT BLOCK");
    printf("\n\t* MY PID          = %d", getpid());
    printf("\n\t* MY CHILD'S PID  = %d", pid);
    printf("\n\t* MY OWNER'S PID  = %d\n\n", getppid());
  } else {
    printf("\nTHIS IS CHILD'S BLOCK");
    printf("\n\t* MY PARENT'S PID = %d", getppid());
    printf("\n\t* MY PID          = %d\n", getpid());
    exit(0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbx
  mov    $0x0,%edi
  call   <wait@plt>
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%esi
  lea    D65(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L1:
  pop    %rbx
  ret
L12:
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%esi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D50
type: string
name: read_data
arguments: label: D20
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D65
type: string
name: read_data
arguments: label: D54
type: string
name: read_data
arguments: label: D47
type: string
name: read_data
arguments: label: D40
type: string

tool: D50: 
This is PARENT BLOCK

tool: D20: 
	* MY PID          = %d

tool: D14: 
	* MY CHILD'S PID  = %d

tool: D65: 
	* MY OWNER'S PID  = %d



tool: D54: 
THIS IS CHILD'S BLOCK

tool: D47: 
	* MY PARENT'S PID = %d

tool: D40: 
	* MY PID          = %d


assistant: ```c
void main() {
  pid_t pid = fork();
  if (pid != 0) {
    wait(0);
    printf("\nThis is PARENT BLOCK");
    printf("\n\t* MY PID          = %d", getpid());
    printf("\n\t* MY CHILD'S PID  = %d", pid);
    printf("\n\t* MY OWNER'S PID  = %d\n\n", getppid());
  } else {
    printf("\nTHIS IS CHILD'S BLOCK");
    printf("\n\t* MY PARENT'S PID = %d", getppid());
    printf("\n\t* MY PID          = %d\n", getpid());
    exit(0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L5
  xor    %edi,%edi
  mov    %rax,%rbp
  call   <wait@plt>
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  lea    D39(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
L5:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D38(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    10d0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D51
datatype: string
name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D41
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string
name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D38
datatype: string

tool: D51: 
This is PARENT BLOCK

tool: D11: 
	* MY PID          = %d

tool: D41: 
	* MY CHILD'S PID  = %d

tool: D39: 
	* MY OWNER'S PID  = %d



tool: D0: 
THIS IS CHILD'S BLOCK

tool: D18: 
	* MY PARENT'S PID = %d

tool: D38: 
	* MY PID          = %d


assistant: ```c
void main() {
  pid_t pid = fork();
  if (pid != 0) {
    wait(0);
    printf("\nThis is PARENT BLOCK");
    printf("\n\t* MY PID          = %d", getpid());
    printf("\n\t* MY CHILD'S PID  = %d", pid);
    printf("\n\t* MY OWNER'S PID  = %d\n\n", getppid());
  } else {
    printf("\nTHIS IS CHILD'S BLOCK");
    printf("\n\t* MY PARENT'S PID = %d", getppid());
    printf("\n\t* MY PID          = %d\n", getpid());
    exit(0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L7
  xor    %edi,%edi
  mov    %rax,%rbp
  call   <wait@plt>
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  lea    D50(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
L7:
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D48(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    10d0 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D53
type_guessed: string
name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D50
type_guessed: string
name: unpack_data
arguments: data_tag: D32
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D48
type_guessed: string

tool: D53: 
This is PARENT BLOCK

tool: D8: 
	* MY PID          = %d

tool: D27: 
	* MY CHILD'S PID  = %d

tool: D50: 
	* MY OWNER'S PID  = %d



tool: D32: 
THIS IS CHILD'S BLOCK

tool: D23: 
	* MY PARENT'S PID = %d

tool: D48: 
	* MY PID          = %d


assistant: ```c
void main() {
  pid_t pid = fork();
  if (pid != 0) {
    wait(0);
    printf("\nThis is PARENT BLOCK");
    printf("\n\t* MY PID          = %d", getpid());
    printf("\n\t* MY CHILD'S PID  = %d", pid);
    printf("\n\t* MY OWNER'S PID  = %d\n\n", getppid());
  } else {
    printf("\nTHIS IS CHILD'S BLOCK");
    printf("\n\t* MY PARENT'S PID = %d", getppid());
    printf("\n\t* MY PID          = %d\n", getpid());
    exit(0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    -0x17447d68(%rdx),%eax
  test   $0x8,%dl
  jne    L2
  test   $0x1,%al
  jne    L46
  test   $0x2,%al
  je     L12
  imul   %eax,%eax
  jmp    L46
L12:
  mov    %eax,%edx
  imul   %eax,%edx
  shl    $0x4,%edx
  and    $0x3f0,%edx
  or     %edx,%eax
  jmp    L46
L2:
  test   $0x1,%al
  je     L20
  lea    0x0(,%rax,4),%edx
  and    $0x1c,%edx
  or     %edx,%eax
L46:
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
L20:
  mov    %eax,%edx
  shl    $0x4,%edx
  and    $0x1f0,%edx
  or     %edx,%eax
  jmp    L46
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        if (state[0UL] & 1U) {
          copy11 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          state[0UL] |= ((state[0UL] + state[0UL]) & 63U) << 4UL;
        }
      } else if ((state[0UL] >> 1U) & 1U) {
        state[0UL] *= state[0UL];
      } else {
        state[0UL] |= (state[0UL] * state[0UL] & 63U) << 4UL;
      }
    } else if (state[0UL] & 1U) {
      state[0UL] |= (state[0UL] & 7U) << 2UL;
    } else {
      state[0UL] |= (state[0UL] & 31U) << 4UL;
    }
    output[0UL] = state[0UL] + 1042671356UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,%ecx
  lea    -0x17447d68(%rax),%edx
  and    $0x1,%ecx
  test   $0x8,%al
  jne    L1
  mov    %edx,%eax
  test   %ecx,%ecx
  je     L19
L16:
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  test   %ecx,%ecx
  je     L2
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %edx,%eax
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
L2:
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L19:
  imul   %edx,%eax
  test   $0x2,%dl
  jne    L16
  shl    $0x4,%eax
  and    $0x3f0,%eax
  or     %edx,%eax
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        if (state[0UL] & 1U) {
          copy11 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          state[0UL] |= ((state[0UL] + state[0UL]) & 63U) << 4UL;
        }
      } else if ((state[0UL] >> 1U) & 1U) {
        state[0UL] *= state[0UL];
      } else {
        state[0UL] |= (state[0UL] * state[0UL] & 63U) << 4UL;
      }
    } else if (state[0UL] & 1U) {
      state[0UL] |= (state[0UL] & 7U) << 2UL;
    } else {
      state[0UL] |= (state[0UL] & 31U) << 4UL;
    }
    output[0UL] = state[0UL] + 1042671356UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  mov    %edx,%ecx
  lea    -0x17447d68(%rdx),%eax
  and    $0x1,%ecx
  and    $0x8,%edx
  jne    L6
  test   %ecx,%ecx
  je     L34
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  test   %ecx,%ecx
  je     L18
  lea    0x0(,%rax,4),%edx
  and    $0x1c,%edx
  or     %edx,%eax
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
L18:
  mov    %eax,%edx
  shl    $0x4,%edx
  and    $0x1f0,%edx
  or     %edx,%eax
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L34:
  mov    %eax,%edx
  imul   %eax,%edx
  test   $0x2,%al
  je     L4
  mov    %edx,%eax
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  shl    $0x4,%edx
  and    $0x3f0,%edx
  or     %edx,%eax
  add    $0x3e25e6fc,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        if (state[0UL] & 1U) {
          copy11 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        } else {
          state[0UL] |= ((state[0UL] + state[0UL]) & 63U) << 4UL;
        }
      } else if ((state[0UL] >> 1U) & 1U) {
        state[0UL] *= state[0UL];
      } else {
        state[0UL] |= (state[0UL] * state[0UL] & 63U) << 4UL;
      }
    } else if (state[0UL] & 1U) {
      state[0UL] |= (state[0UL] & 7U) << 2UL;
    } else {
      state[0UL] |= (state[0UL] & 31U) << 4UL;
    }
    output[0UL] = state[0UL] + 1042671356UL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__syscall3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rdi
  mov    -0x28(%rbp),%rsi
  mov    -0x30(%rbp),%rdx
  syscall
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long __syscall3(long n, long a1, long a2, long a3) {
  unsigned long ret;
  __asm__ __volatile__("syscall" : "=a"(ret) : "a"(n), "D"(a1), "S"(a2), "d"(a3) : "rcx", "r11", "memory");
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__syscall3>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  syscall
  ret
```

assistant: ```c
long __syscall3(long n, long a1, long a2, long a3) {
  unsigned long ret;
  __asm__ __volatile__("syscall" : "=a"(ret) : "a"(n), "D"(a1), "S"(a2), "d"(a3) : "rcx", "r11", "memory");
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__syscall3>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  syscall
  ret
```

assistant: ```c
long __syscall3(long n, long a1, long a2, long a3) {
  unsigned long ret;
  __asm__ __volatile__("syscall" : "=a"(ret) : "a"(n), "D"(a1), "S"(a2), "d"(a3) : "rcx", "r11", "memory");
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__syscall3>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  syscall
  ret
```

assistant: ```c
long __syscall3(long n, long a1, long a2, long a3) {
  unsigned long ret;
  __asm__ __volatile__("syscall" : "=a"(ret) : "a"(n), "D"(a1), "S"(a2), "d"(a3) : "rcx", "r11", "memory");
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3c,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    $0x0,%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    $0x0,%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L1
  movl   $0x1,-0x4(%rbp)
L1:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int tmp;
  int p_9 = 60;
  tmp = (p_9 + 1) % 0;
  if ((p_9 + 1) % 0) {
    tmp = 1;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int tmp;
  int p_9 = 60;
  tmp = (p_9 + 1) % 0;
  if ((p_9 + 1) % 0) {
    tmp = 1;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int tmp;
  int p_9 = 60;
  tmp = (p_9 + 1) % 0;
  if ((p_9 + 1) % 0) {
    tmp = 1;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int tmp;
  int p_9 = 60;
  tmp = (p_9 + 1) % 0;
  if ((p_9 + 1) % 0) {
    tmp = 1;
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L22
L21:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L15
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rcx
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <swap@plt>
  jmp    L22
L15:
  addl   $0x1,-0xc(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L21
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int partition(int *values, int start, int end) {
  int pivot = values[end - 1];
  int i = start;
  int j = end - 2;
  while (i <= j)
    if (values[i] > pivot)
      swap(values, i, j--);
    else
      i++;
  swap(values, i, end - 1);
  return i;
}
```