ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%rdi
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x70(%rsp),%rbx
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L37:
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <getline_my@plt>
  test   %eax,%eax
  jle    L21
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <detab@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x70(%rsp),%edx
  test   %dl,%dl
  je     L37
  xor    %r14d,%r14d
  nopl   (%rax)
L31:
  mov    %edx,%ecx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%r14
  movsbl (%rbx,%r14,1),%edx
  test   %dl,%dl
  jne    L31
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D23
datatype: string

tool: D9: Input, please, lines to detab:

tool: D22: %s;


tool: D23: newline [ %d ] = '%c' and %d;


assistant: ```c
int main() {
  int len = 0;
  char line[100];
  char newline[100];
  int i = 0;
  printf("Input, please, lines to detab:\n");
  while ((len = getline_my(line, 100)) > 0) {
    detab(newline, line);
    printf("%s;\n", newline);
    i = 0;
    while (newline[i] != '\0') {
      printf("newline [ %d ] = '%c' and %d;\n", i, newline[i], newline[i]);
      i++;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D8(%rip),%rdi
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x70(%rsp),%rbx
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <getline_my@plt>
  test   %eax,%eax
  jle    L1
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <detab@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x70(%rsp),%edx
  test   %dl,%dl
  je     L2
  xor    %r14d,%r14d
  nopl   (%rax)
L23:
  mov    %edx,%ecx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%r14
  movsbl (%rbx,%r14,1),%edx
  test   %dl,%dl
  jne    L23
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D10
datatype: string

tool: D8: Input, please, lines to detab:

tool: D16: %s;


tool: D10: newline [ %d ] = '%c' and %d;


assistant: ```c
int main() {
  int len = 0;
  char line[100];
  char newline[100];
  int i = 0;
  printf("Input, please, lines to detab:\n");
  while ((len = getline_my(line, 100)) > 0) {
    detab(newline, line);
    printf("%s;\n", newline);
    i = 0;
    while (newline[i] != '\0') {
      printf("newline [ %d ] = '%c' and %d;\n", i, newline[i], newline[i]);
      i++;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cond_dummy_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cond_dummy_copy(const struct XCSF *xcsf, struct Cl *dest, const struct Cl *src) {
  (void)xcsf;
  (void)dest;
  (void)src;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cond_dummy_copy>:
  endbr64
  ret
```

assistant: ```c
void cond_dummy_copy(const struct XCSF *xcsf, struct Cl *dest, const struct Cl *src) {
  (void)xcsf;
  (void)dest;
  (void)src;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cond_dummy_copy>:
  endbr64
  ret
```

assistant: ```c
void cond_dummy_copy(const struct XCSF *xcsf, struct Cl *dest, const struct Cl *src) {
  (void)xcsf;
  (void)dest;
  (void)src;
}
```
user: What is the c source code of the assembly code below:

```asm
<cond_dummy_copy>:
  endbr64
  ret
```

assistant: ```c
void cond_dummy_copy(const struct XCSF *xcsf, struct Cl *dest, const struct Cl *src) {
  (void)xcsf;
  (void)dest;
  (void)src;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_link@plt>
  mov    $0x0,%eax
  call   <test_unlink@plt>
  mov    $0x0,%eax
  call   <test_detach@plt>
  mov    $0x0,%eax
  call   <test_move@plt>
  mov    $0x0,%eax
  call   <test_parent_count@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_link();
  test_unlink();
  test_detach();
  test_move();
  test_parent_count();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_link@plt>
  mov    $0x0,%eax
  call   <test_unlink@plt>
  mov    $0x0,%eax
  call   <test_detach@plt>
  mov    $0x0,%eax
  call   <test_move@plt>
  mov    $0x0,%eax
  call   <test_parent_count@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_link();
  test_unlink();
  test_detach();
  test_move();
  test_parent_count();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_link@plt>
  xor    %eax,%eax
  call   <test_unlink@plt>
  xor    %eax,%eax
  call   <test_detach@plt>
  xor    %eax,%eax
  call   <test_move@plt>
  xor    %eax,%eax
  call   <test_parent_count@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_link();
  test_unlink();
  test_detach();
  test_move();
  test_parent_count();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_link@plt>
  xor    %eax,%eax
  call   <test_unlink@plt>
  xor    %eax,%eax
  call   <test_detach@plt>
  xor    %eax,%eax
  call   <test_move@plt>
  xor    %eax,%eax
  call   <test_parent_count@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_link();
  test_unlink();
  test_detach();
  test_move();
  test_parent_count();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn_19_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  nop
  mov    $0xf1,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t fn_19_c(uint64_t a1, uint8_t a2) {
  if (!(a1 == 158887773995008)) {
    goto bad;
  }
  if (!(a2 == 186)) {
    goto bad;
  }
  return 113;
bad:
  return 241;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fn_19_c>:
  endbr64
  mov    $0xf1,%eax
  ret
```

assistant: ```c
uint8_t fn_19_c(uint64_t a1, uint8_t a2) {
  if (!(a1 == 158887773995008)) {
    goto bad;
  }
  if (!(a2 == 186)) {
    goto bad;
  }
  return 113;
bad:
  return 241;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn_19_c>:
  endbr64
  mov    $0xf1,%eax
  ret
```

assistant: ```c
uint8_t fn_19_c(uint64_t a1, uint8_t a2) {
  if (!(a1 == 158887773995008)) {
    goto bad;
  }
  if (!(a2 == 186)) {
    goto bad;
  }
  return 113;
bad:
  return 241;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn_19_c>:
  endbr64
  mov    $0xf1,%eax
  ret
```

assistant: ```c
uint8_t fn_19_c(uint64_t a1, uint8_t a2) {
  if (!(a1 == 158887773995008)) {
    goto bad;
  }
  if (!(a2 == 186)) {
    goto bad;
  }
  return 113;
bad:
  return 241;
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D32(%rip),%rax
  mov    (%rax),%ecx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L46
  mov    $0xffffffff,%eax
  jmp    L26
L46:
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L26
L7:
  mov    -0x1c(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <listen@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L26
L2:
  mov    -0x1c(%rbp),%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
int create_socket(int port) {
  int ret_val;
  struct sockaddr_in sock_addr;
  int fd = socket(AF_INET, SOCK_STREAM, 0);
  if (fd == -1)
    return -1;
  memset(&sock_addr, 0, sizeof(sock_addr));
  sock_addr.sin_family = AF_INET;
  sock_addr.sin_addr.s_addr = INADDR_ANY;
  sock_addr.sin_port = htons(port);
  ret_val = bind(fd, (struct sockaddr *)&sock_addr, sizeof(sock_addr));
  if (ret_val == -1)
    return -1;
  ret_val = listen(fd, 2);
  if (ret_val == -1)
    return -1;
  return fd;
}
```
user: What is the c source code of the assembly code below?

```asm
<create_socket>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L35
  lea    0xc(%rsp),%rbp
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  mov    %r12d,%edi
  call   <htons@plt>
  mov    %eax,0xc(%rsp)
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L15
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  cmove  %eax,%ebx
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    %eax,%ebx
  jmp    L35
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_socket(int port) {
  int ret_val;
  struct sockaddr_in sock_addr;
  int fd = socket(AF_INET, SOCK_STREAM, 0);
  if (fd == -1)
    return -1;
  memset(&sock_addr, 0, sizeof(sock_addr));
  sock_addr.sin_family = AF_INET;
  sock_addr.sin_addr.s_addr = INADDR_ANY;
  sock_addr.sin_port = htons(port);
  ret_val = bind(fd, (struct sockaddr *)&sock_addr, sizeof(sock_addr));
  if (ret_val == -1)
    return -1;
  ret_val = listen(fd, 2);
  if (ret_val == -1)
    return -1;
  return fd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<create_socket>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D18(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L46
  lea    0xc(%rsp),%rbp
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %r13d,%edi
  mov    %eax,0x14(%rsp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L46
  mov    $0x2,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  je     L46
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L46:
  mov    $0xffffffff,%r12d
  jmp    L35
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_socket(int port) {
  int ret_val;
  struct sockaddr_in sock_addr;
  int fd = socket(AF_INET, SOCK_STREAM, 0);
  if (fd == -1)
    return -1;
  memset(&sock_addr, 0, sizeof(sock_addr));
  sock_addr.sin_family = AF_INET;
  sock_addr.sin_addr.s_addr = INADDR_ANY;
  sock_addr.sin_port = htons(port);
  ret_val = bind(fd, (struct sockaddr *)&sock_addr, sizeof(sock_addr));
  if (ret_val == -1)
    return -1;
  ret_val = listen(fd, 2);
  if (ret_val == -1)
    return -1;
  return fd;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<create_socket>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D24(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D29(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L4
  lea    0x8(%rsp),%rbp
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D9(%rip),%rdx
  mov    (%rbx),%eax
  mov    %r13d,%edi
  movd   (%rdx),%xmm0
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0xc(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,0x8(%rsp)
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L4
  mov    $0x2,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  je     L4
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%r12d
  jmp    L48
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_socket(int port) {
  int ret_val;
  struct sockaddr_in sock_addr;
  int fd = socket(AF_INET, SOCK_STREAM, 0);
  if (fd == -1)
    return -1;
  memset(&sock_addr, 0, sizeof(sock_addr));
  sock_addr.sin_family = AF_INET;
  sock_addr.sin_addr.s_addr = INADDR_ANY;
  sock_addr.sin_port = htons(port);
  ret_val = bind(fd, (struct sockaddr *)&sock_addr, sizeof(sock_addr));
  if (ret_val == -1)
    return -1;
  ret_val = listen(fd, 2);
  if (ret_val == -1)
    return -1;
  return fd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <parse_args@plt>
  mov    $0x0,%eax
  call   <download@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  parse_args(argc, argv);
  download();
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <parse_args@plt>
  mov    $0x0,%eax
  call   <download@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  parse_args(argc, argv);
  download();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <parse_args@plt>
  xor    %eax,%eax
  call   <download@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  parse_args(argc, argv);
  download();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <parse_args@plt>
  xor    %eax,%eax
  call   <download@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  parse_args(argc, argv);
  download();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BN_X931_generate_Xpq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  cmpl   $0x3ff,-0x34(%rbp)
  jle    L2
  mov    -0x34(%rbp),%eax
  movzbl %al,%eax
  test   %eax,%eax
  je     L114
L2:
  mov    $0x0,%eax
  jmp    L107
L114:
  sarl   -0x34(%rbp)
  mov    -0x34(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <BN_rand@plt>
  test   %eax,%eax
  je     L38
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_CTX_start@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_CTX_get@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L148
  movl   $0x0,-0x1c(%rbp)
  jmp    L66
L40:
  mov    -0x34(%rbp),%esi
  mov    -0x30(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <BN_rand@plt>
  test   %eax,%eax
  je     L142
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BN_sub@plt>
  mov    -0x34(%rbp),%eax
  lea    -0x63(%rax),%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_num_bits@plt>
  cmp    %eax,%ebx
  jle    L69
  addl   $0x1,-0x1c(%rbp)
L66:
  cmpl   $0x3e7,-0x1c(%rbp)
  jle    L40
  jmp    L122
L69:
  nop
L122:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_CTX_end@plt>
  cmpl   $0x3e7,-0x1c(%rbp)
  jg     L83
  mov    $0x1,%eax
  jmp    L107
L83:
  mov    $0x0,%eax
  jmp    L107
L38:
  nop
  jmp    L29
L148:
  nop
  jmp    L29
L142:
  nop
L29:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_CTX_end@plt>
  mov    $0x0,%eax
L107:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int BN_X931_generate_Xpq(BIGNUM *Xp, BIGNUM *Xq, int nbits, BN_CTX *ctx) {
  BIGNUM *t;
  int i;
  if ((nbits < 1024) || (nbits & 0xff))
    return 0;
  nbits >>= 1;
  if (!BN_rand(Xp, nbits, 1, 0))
    goto err;
  BN_CTX_start(ctx);
  t = BN_CTX_get(ctx);
  if (t == NULL)
    goto err;
  for (i = 0; i < 1000; i++) {
    if (!BN_rand(Xq, nbits, 1, 0))
      goto err;
    BN_sub(t, Xp, Xq);
    if (BN_num_bits(t) > (nbits - 100))
      break;
  }
  BN_CTX_end(ctx);
  if (i < 1000)
    return 1;
  return 0;
err:
  BN_CTX_end(ctx);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BN_X931_generate_Xpq>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    $0x0,%r14d
  cmp    $0x3ff,%edx
  jle    L39
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %rcx,%r15
  mov    %edx,%r14d
  and    $0xff,%r14d
  je     L55
  mov    $0x0,%r14d
L39:
  mov    %r14d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  sar    %ebx
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %ebx,%esi
  call   <BN_rand@plt>
  test   %eax,%eax
  jne    L6
L21:
  mov    0x8(%rsp),%rdi
  call   <BN_CTX_end@plt>
  jmp    L39
L6:
  mov    %r15,%rdi
  call   <BN_CTX_start@plt>
  mov    %r15,%rdi
  call   <BN_CTX_get@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L21
  mov    %r14d,%r12d
  lea    -0x63(%rbx),%r15d
L25:
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <BN_rand@plt>
  test   %eax,%eax
  je     L21
  mov    %rbp,%rdx
  mov    (%rsp),%rsi
  mov    %r13,%rdi
  call   <BN_sub@plt>
  mov    %r13,%rdi
  call   <BN_num_bits@plt>
  cmp    %eax,%r15d
  jle    L81
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  jne    L25
L81:
  mov    0x8(%rsp),%rdi
  call   <BN_CTX_end@plt>
  cmp    $0x3e7,%r12d
  setle  %r14b
  movzbl %r14b,%r14d
  jmp    L39
```

assistant: ```c
int BN_X931_generate_Xpq(BIGNUM *Xp, BIGNUM *Xq, int nbits, BN_CTX *ctx) {
  BIGNUM *t;
  int i;
  if ((nbits < 1024) || (nbits & 0xff))
    return 0;
  nbits >>= 1;
  if (!BN_rand(Xp, nbits, 1, 0))
    goto err;
  BN_CTX_start(ctx);
  t = BN_CTX_get(ctx);
  if (t == NULL)
    goto err;
  for (i = 0; i < 1000; i++) {
    if (!BN_rand(Xq, nbits, 1, 0))
      goto err;
    BN_sub(t, Xp, Xq);
    if (BN_num_bits(t) > (nbits - 100))
      break;
  }
  BN_CTX_end(ctx);
  if (i < 1000)
    return 1;
  return 0;
err:
  BN_CTX_end(ctx);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BN_X931_generate_Xpq>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  cmp    $0x3ff,%edx
  jle    L98
  mov    %edx,%r15d
  mov    %edx,%ebx
  and    $0xff,%r15d
  je     L64
  xor    %r15d,%r15d
L98:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L64:
  sar    %ebx
  mov    %rsi,%rbp
  mov    %rcx,%r14
  mov    $0x1,%edx
  xor    %ecx,%ecx
  mov    %ebx,%esi
  mov    %rdi,%r12
  call   <BN_rand@plt>
  test   %eax,%eax
  jne    L58
L70:
  mov    0x8(%rsp),%rdi
  call   <BN_CTX_end@plt>
  jmp    L98
  nopl   0x0(%rax)
L58:
  mov    %r14,%rdi
  call   <BN_CTX_start@plt>
  mov    %r14,%rdi
  call   <BN_CTX_get@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L70
  lea    -0x63(%rbx),%eax
  mov    $0x3e8,%r13d
  mov    %eax,0x4(%rsp)
  jmp    L25
  nop
L87:
  mov    %r14,%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <BN_sub@plt>
  mov    %r14,%rdi
  call   <BN_num_bits@plt>
  cmp    %eax,0x4(%rsp)
  jle    L19
  sub    $0x1,%r13d
  je     L70
L25:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <BN_rand@plt>
  test   %eax,%eax
  jne    L87
  jmp    L70
  nopl   0x0(%rax)
L19:
  mov    0x8(%rsp),%rdi
  mov    $0x1,%r15d
  call   <BN_CTX_end@plt>
  jmp    L98
```

assistant: ```c
int BN_X931_generate_Xpq(BIGNUM *Xp, BIGNUM *Xq, int nbits, BN_CTX *ctx) {
  BIGNUM *t;
  int i;
  if ((nbits < 1024) || (nbits & 0xff))
    return 0;
  nbits >>= 1;
  if (!BN_rand(Xp, nbits, 1, 0))
    goto err;
  BN_CTX_start(ctx);
  t = BN_CTX_get(ctx);
  if (t == NULL)
    goto err;
  for (i = 0; i < 1000; i++) {
    if (!BN_rand(Xq, nbits, 1, 0))
      goto err;
    BN_sub(t, Xp, Xq);
    if (BN_num_bits(t) > (nbits - 100))
      break;
  }
  BN_CTX_end(ctx);
  if (i < 1000)
    return 1;
  return 0;
err:
  BN_CTX_end(ctx);
  return 0;
}
```