ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<printbinary>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    $0x0,%eax
  call   <size_t_unit@plt>
  movslq %eax,%r12
  shl    $0x2,%r12
  lea    -0x1(%r12),%ecx
  mov    $0x1,%ebx
  shl    %cl,%ebx
  test   %r12,%r12
  je     L18
  mov    $0x0,%ebp
  lea    D4(%rip),%r14
L5:
  test   %ebx,%r13d
  setne  %sil
  movzbl %sil,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  shr    %ebx
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L5
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D4: %d

assistant: ```c
void printbinary(int n) {
  int i;
  size_t bits = sizeof(int) * size_t_unit();
  unsigned int j = 1 << (bits - 1);
  for (i = 0; i < bits; i++, j >>= 1) {
    printf("%d", (j & n ? 1 : 0));
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printbinary>:
  endbr64
  push   %r14
  xor    %eax,%eax
  lea    D8(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  call   <size_t_unit@plt>
  movslq %eax,%r12
  shl    $0x2,%r12
  lea    -0x1(%r12),%ecx
  shl    %cl,%ebx
  test   %r12,%r12
  je     L1
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %esi,%esi
  test   %ebx,%r13d
  mov    %r14,%rdi
  setne  %sil
  xor    %eax,%eax
  add    $0x1,%rbp
  shr    %ebx
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L17
L1:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: %d

assistant: ```c
void printbinary(int n) {
  int i;
  size_t bits = sizeof(int) * size_t_unit();
  unsigned int j = 1 << (bits - 1);
  for (i = 0; i < bits; i++, j >>= 1) {
    printf("%d", (j & n ? 1 : 0));
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printbinary>:
  endbr64
  push   %r14
  xor    %eax,%eax
  lea    D8(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  call   <size_t_unit@plt>
  movslq %eax,%r12
  shl    $0x2,%r12
  lea    -0x1(%r12),%ecx
  shl    %cl,%ebx
  test   %r12,%r12
  je     L9
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %esi,%esi
  test   %ebx,%r13d
  mov    %r14,%rdi
  setne  %sil
  xor    %eax,%eax
  add    $0x1,%rbp
  shr    %ebx
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L16
L9:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: %d

assistant: ```c
void printbinary(int n) {
  int i;
  size_t bits = sizeof(int) * size_t_unit();
  unsigned int j = 1 << (bits - 1);
  for (i = 0; i < bits; i++, j >>= 1) {
    printf("%d", (j & n ? 1 : 0));
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fileNameInPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x18(%rbp),%rax
  jmp    L17
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L58
L57:
  subl   $0x1,-0x4(%rbp)
L58:
  cmpl   $0x0,-0x4(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L57
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
L17:
  leave
  ret
```

assistant: ```c
const char *fileNameInPath(const char *path) {
  if (!path[0])
    return path;
  int i = strlen(path) - 1;
  while (i > 0 && path[i - 1] != '/' && path[i - 1] != '\\')
    i--;
  return path + i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fileNameInPath>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  jne    L56
L54:
  mov    %rbx,%rax
  pop    %rbx
  ret
L56:
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L49
  movslq %eax,%rdx
  add    %rbx,%rdx
L27:
  movzbl -0x1(%rdx),%ecx
  cmp    $0x5c,%cl
  je     L49
  cmp    $0x2f,%cl
  je     L49
  sub    $0x1,%rdx
  sub    $0x1,%eax
  jne    L27
L49:
  cltq
  add    %rax,%rbx
  jmp    L54
```

assistant: ```c
const char *fileNameInPath(const char *path) {
  if (!path[0])
    return path;
  int i = strlen(path) - 1;
  while (i > 0 && path[i - 1] != '/' && path[i - 1] != '\\')
    i--;
  return path + i;
}
```
user: What is the c source code of the assembly code below?

```asm
<fileNameInPath>:
  endbr64
  cmpb   $0x0,(%rdi)
  push   %r12
  mov    %rdi,%r12
  jne    L44
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L44:
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  test   %eax,%eax
  jg     L39
  jmp    L62
  nopl   0x0(%rax)
L17:
  cmp    $0x2f,%al
  je     L62
  lea    -0x1(%rdx),%eax
  sub    $0x1,%rdx
  je     L40
L39:
  movzbl -0x1(%r12,%rdx,1),%eax
  cmp    $0x5c,%al
  jne    L17
L62:
  add    %rdx,%r12
L31:
  mov    %r12,%rax
  pop    %r12
  ret
L40:
  movslq %eax,%rdx
  add    %rdx,%r12
  jmp    L31
```

assistant: ```c
const char *fileNameInPath(const char *path) {
  if (!path[0])
    return path;
  int i = strlen(path) - 1;
  while (i > 0 && path[i - 1] != '/' && path[i - 1] != '\\')
    i--;
  return path + i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fileNameInPath>:
  endbr64
  cmpb   $0x0,(%rdi)
  push   %r12
  mov    %rdi,%r12
  jne    L65
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L65:
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  test   %eax,%eax
  jg     L59
  jmp    L35
  nopl   0x0(%rax)
L18:
  cmp    $0x2f,%al
  je     L35
  lea    -0x1(%rdx),%eax
  sub    $0x1,%rdx
  je     L22
L59:
  movzbl -0x1(%r12,%rdx,1),%eax
  cmp    $0x5c,%al
  jne    L18
L35:
  add    %rdx,%r12
L4:
  mov    %r12,%rax
  pop    %r12
  ret
L22:
  movslq %eax,%rdx
  add    %rdx,%r12
  jmp    L4
```

assistant: ```c
const char *fileNameInPath(const char *path) {
  if (!path[0])
    return path;
  int i = strlen(path) - 1;
  while (i > 0 && path[i - 1] != '/' && path[i - 1] != '\\')
    i--;
  return path + i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_read>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L123
  mov    %rsi,%r12
  mov    %ecx,%ebx
  cmpb   $0x0,(%rdi)
  je     L22
  movsbl %dl,%ebp
  mov    %ebp,%esi
  call   <ft_strclen@plt>
  cmp    %ebx,%eax
  cmova  %ebx,%eax
  mov    %eax,%r14d
  mov    %ebp,%esi
  mov    (%r12),%rdi
  call   <ft_strchr@plt>
  test   %eax,%eax
  jne    L129
  mov    $0x1,%ecx
  mov    %r14d,%edx
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  mov    $0xffffffd6,%edx
  test   %rax,%rax
  je     L15
  mov    $0x1000,%edx
  mov    $0x0,%esi
  mov    (%r12),%rdi
  call   <ft_memset@plt>
  mov    $0xffffffff,%edx
  jmp    L15
L129:
  mov    (%r12),%rdi
  call   <ft_strlen@plt>
  cmp    %r14d,%eax
  je     L116
  mov    $0x1,%ecx
  mov    %r14d,%edx
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L55
  mov    (%r12),%rdi
  mov    %r14d,%r14d
  lea    0x1(%rdi,%r14,1),%rsi
  mov    %ebx,%edx
  call   <ft_memmove@plt>
  mov    $0x1000,%edx
  sub    %ebx,%edx
  mov    %ebx,%edi
  sub    %r14,%rdi
  add    (%r12),%rdi
  mov    $0x0,%esi
  call   <ft_memset@plt>
  mov    $0x1,%edx
L15:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L116:
  mov    $0x1,%ecx
  mov    %r14d,%edx
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L23
  mov    $0x1000,%edx
  mov    $0x0,%esi
  mov    (%r12),%rdi
  call   <ft_memset@plt>
  mov    $0x0,%edx
  jmp    L15
L123:
  mov    $0xffffffff,%edx
  jmp    L15
L22:
  mov    $0xffffffff,%edx
  jmp    L15
L23:
  mov    $0xffffffd6,%edx
  jmp    L15
L55:
  mov    $0xffffffd6,%edx
  jmp    L15
```

assistant: ```c
int ft_read(char **line, char **buf, char c, unsigned int max_s) {
  unsigned int size;
  if (!*buf || !**buf)
    return (-1);
  size = ft_strclen(*buf, c);
  size = (size > max_s) ? max_s : size;
  if (!ft_strchr(*buf, c)) {
    if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
      return (-42);
    ft_memset(*buf, '\0', 4096);
    return (-1);
  }
  if (size == ft_strlen(*buf)) {
    if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
      return (-42);
    ft_memset(*buf, '\0', 4096);
    return (0);
  }
  if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
    return (-42);
  ft_memmove(*buf, (*buf) + size + 1, max_s);
  ft_memset((*buf) + max_s - size, '\0', 4096 - max_s);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_read>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L22
  cmpb   $0x0,(%rdi)
  je     L22
  movsbl %dl,%ebp
  mov    %rsi,%r12
  mov    %ecx,%ebx
  mov    %ebp,%esi
  call   <ft_strclen@plt>
  mov    (%r12),%rdi
  mov    %ebp,%esi
  cmp    %ebx,%eax
  cmova  %ebx,%eax
  mov    %eax,%r14d
  call   <ft_strchr@plt>
  test   %eax,%eax
  je     L37
  mov    (%r12),%rdi
  call   <ft_strlen@plt>
  mov    $0x1,%ecx
  cmp    %r14d,%eax
  je     L43
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  mov    %r14d,%edx
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L58
  mov    (%r12),%rdi
  mov    %ebx,%edx
  lea    0x1(%rdi,%r14,1),%rsi
  call   <ft_memmove@plt>
  mov    $0x1000,%edx
  mov    %ebx,%edi
  xor    %esi,%esi
  sub    %ebx,%edx
  sub    %r14,%rdi
  add    (%r12),%rdi
  call   <ft_memset@plt>
  mov    $0x1,%eax
L77:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L37:
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  mov    $0x1,%ecx
  mov    %r14d,%edx
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L58
  mov    (%r12),%rdi
  mov    $0x1000,%edx
  xor    %esi,%esi
  call   <ft_memset@plt>
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L58:
  pop    %rbx
  mov    $0xffffffd6,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L43:
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  mov    %eax,%edx
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L58
  mov    (%r12),%rdi
  mov    $0x1000,%edx
  xor    %esi,%esi
  call   <ft_memset@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0xffffffff,%eax
  jmp    L77
```

assistant: ```c
int ft_read(char **line, char **buf, char c, unsigned int max_s) {
  unsigned int size;
  if (!*buf || !**buf)
    return (-1);
  size = ft_strclen(*buf, c);
  size = (size > max_s) ? max_s : size;
  if (!ft_strchr(*buf, c)) {
    if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
      return (-42);
    ft_memset(*buf, '\0', 4096);
    return (-1);
  }
  if (size == ft_strlen(*buf)) {
    if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
      return (-42);
    ft_memset(*buf, '\0', 4096);
    return (0);
  }
  if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
    return (-42);
  ft_memmove(*buf, (*buf) + size + 1, max_s);
  ft_memset((*buf) + max_s - size, '\0', 4096 - max_s);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_read>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L65
  cmpb   $0x0,(%rdi)
  je     L65
  movsbl %dl,%ebp
  mov    %rsi,%r12
  mov    %ecx,%ebx
  mov    %ebp,%esi
  call   <ft_strclen@plt>
  mov    (%r12),%rdi
  mov    %ebp,%esi
  cmp    %ebx,%eax
  cmova  %ebx,%eax
  mov    %eax,%r14d
  call   <ft_strchr@plt>
  test   %eax,%eax
  je     L67
  mov    (%r12),%rdi
  call   <ft_strlen@plt>
  mov    $0x1,%ecx
  cmp    %r14d,%eax
  je     L74
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  mov    %r14d,%edx
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L12
  mov    (%r12),%rdi
  mov    %ebx,%edx
  lea    0x1(%rdi,%r14,1),%rsi
  call   <ft_memmove@plt>
  mov    $0x1000,%edx
  mov    %ebx,%edi
  xor    %esi,%esi
  sub    %ebx,%edx
  sub    %r14,%rdi
  add    (%r12),%rdi
  call   <ft_memset@plt>
  mov    $0x1,%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L67:
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  mov    $0x1,%ecx
  mov    %r14d,%edx
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L12
  mov    (%r12),%rdi
  mov    $0x1000,%edx
  xor    %esi,%esi
  call   <ft_memset@plt>
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L12:
  pop    %rbx
  mov    $0xffffffd6,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L74:
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdi
  mov    %eax,%edx
  call   <ft_strnjoinf@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L12
  mov    (%r12),%rdi
  mov    $0x1000,%edx
  xor    %esi,%esi
  call   <ft_memset@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L65:
  mov    $0xffffffff,%eax
  jmp    L20
```

assistant: ```c
int ft_read(char **line, char **buf, char c, unsigned int max_s) {
  unsigned int size;
  if (!*buf || !**buf)
    return (-1);
  size = ft_strclen(*buf, c);
  size = (size > max_s) ? max_s : size;
  if (!ft_strchr(*buf, c)) {
    if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
      return (-42);
    ft_memset(*buf, '\0', 4096);
    return (-1);
  }
  if (size == ft_strlen(*buf)) {
    if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
      return (-42);
    ft_memset(*buf, '\0', 4096);
    return (0);
  }
  if (!(*line = ft_strnjoinf(*line, *buf, size, 1)))
    return (-42);
  ft_memmove(*buf, (*buf) + size + 1, max_s);
  ft_memset((*buf) + max_s - size, '\0', 4096 - max_s);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strstrncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strnstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L39
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  jmp    L25
L39:
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
L25:
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L18
L28:
  mov    $0x0,%eax
L18:
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x40(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strstrncpy(char *restrict whither, const char *restrict whence, const char *restrict str, size_t maxlen) {
  const char *stop = strnstr(whence, str, maxlen);
  size_t n = stop == NULL ? strnlen(whence, maxlen) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memcpy(whither, whence, n);
  memset(whither + n, 0, maxlen - n);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstrncpy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%rsi
  mov    %rcx,%rbp
  mov    %rcx,%rdx
  mov    %r14,%rdi
  call   <strnstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  sub    %r14,%r12
  mov    %r12,%r13
  lea    (%rbx,%r12,1),%r12
L8:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdx
  sub    %r13,%rdx
  lea    (%rbx,%r13,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strnlen@plt>
  mov    %rax,%r13
  jmp    L8
```

assistant: ```c
char *strstrncpy(char *restrict whither, const char *restrict whence, const char *restrict str, size_t maxlen) {
  const char *stop = strnstr(whence, str, maxlen);
  size_t n = stop == NULL ? strnlen(whence, maxlen) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memcpy(whither, whence, n);
  memset(whither + n, 0, maxlen - n);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstrncpy>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  push   %rbx
  mov    %rbp,%rdi
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strnstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  mov    %rax,%r14
  sub    %rbp,%r14
  lea    0x0(%r13,%r14,1),%r12
  mov    %r12,%r15
L3:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %r14,%rbx
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r15,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L18:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strnlen@plt>
  mov    %rax,%r14
  lea    0x0(%r13,%rax,1),%r15
  jmp    L3
```

assistant: ```c
char *strstrncpy(char *restrict whither, const char *restrict whence, const char *restrict str, size_t maxlen) {
  const char *stop = strnstr(whence, str, maxlen);
  size_t n = stop == NULL ? strnlen(whence, maxlen) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memcpy(whither, whence, n);
  memset(whither + n, 0, maxlen - n);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstrncpy>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  push   %rbx
  mov    %rbp,%rdi
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strnstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rax,%r14
  sub    %rbp,%r14
  lea    0x0(%r13,%r14,1),%r12
  mov    %r12,%r15
L8:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %r14,%rbx
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r15,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L3:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strnlen@plt>
  mov    %rax,%r14
  lea    0x0(%r13,%rax,1),%r15
  jmp    L8
```

assistant: ```c
char *strstrncpy(char *restrict whither, const char *restrict whence, const char *restrict str, size_t maxlen) {
  const char *stop = strnstr(whence, str, maxlen);
  size_t n = stop == NULL ? strnlen(whence, maxlen) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memcpy(whither, whence, n);
  memset(whither + n, 0, maxlen - n);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RaiseInToPower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L29
  mov    $0x1,%eax
  jmp    L34
L29:
  movl   $0x1,-0xc(%rbp)
  jmp    L24
L32:
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L32
  mov    -0x8(%rbp),%rax
L34:
  pop    %rbp
  ret
```

assistant: ```c
long RaiseInToPower(int n, int k) {
  long sum = n;
  if (k == 0)
    return 1;
  for (int i = 1; i < k; i++) {
    sum *= n;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RaiseInToPower>:
  endbr64
  mov    $0x1,%edx
  test   %esi,%esi
  je     L18
  movslq %edi,%rdi
  cmp    $0x1,%esi
  jle    L26
  mov    %rdi,%rdx
  mov    $0x1,%eax
L38:
  imul   %rdi,%rdx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L38
L18:
  mov    %rdx,%rax
  ret
L26:
  mov    %rdi,%rdx
  jmp    L18
```

assistant: ```c
long RaiseInToPower(int n, int k) {
  long sum = n;
  if (k == 0)
    return 1;
  for (int i = 1; i < k; i++) {
    sum *= n;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<RaiseInToPower>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L14
  movslq %edi,%rdi
  mov    %rdi,%r8
  cmp    $0x1,%esi
  jle    L14
  mov    $0x1,%eax
  xchg   %ax,%ax
L8:
  add    $0x1,%eax
  imul   %rdi,%r8
  cmp    %eax,%esi
  jne    L8
L14:
  mov    %r8,%rax
  ret
```

assistant: ```c
long RaiseInToPower(int n, int k) {
  long sum = n;
  if (k == 0)
    return 1;
  for (int i = 1; i < k; i++) {
    sum *= n;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RaiseInToPower>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L20
  movslq %edi,%rdi
  mov    %rdi,%r8
  cmp    $0x1,%esi
  jle    L20
  mov    $0x1,%eax
  xchg   %ax,%ax
L17:
  add    $0x1,%eax
  imul   %rdi,%r8
  cmp    %eax,%esi
  jne    L17
L20:
  mov    %r8,%rax
  ret
```

assistant: ```c
long RaiseInToPower(int n, int k) {
  long sum = n;
  if (k == 0)
    return 1;
  for (int i = 1; i < k; i++) {
    sum *= n;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TimerIntEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0x18,%rdx
  or     -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TimerIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000018))) |= ulIntFlags;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimerIntEnable>:
  endbr64
  mov    0x18(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x18(%rdi)
  ret
```

assistant: ```c
void TimerIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000018))) |= ulIntFlags;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TimerIntEnable>:
  endbr64
  mov    0x18(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x18(%rdi)
  ret
```

assistant: ```c
void TimerIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000018))) |= ulIntFlags;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TimerIntEnable>:
  endbr64
  mov    0x18(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x18(%rdi)
  ret
```

assistant: ```c
void TimerIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000018))) |= ulIntFlags;
}
```