ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<efm>:
  endbr64
  push   %rbx
  movsd  D9(%rip),%xmm0
  mov    %rsi,%rbx
  mov    $0x32,%ecx
  movsd  0x18(%rdi),%xmm4
  movsd  (%rdi),%xmm3
  mov    $0xc8,%edx
  mov    $0x64,%esi
  movsd  0x10(%rdi),%xmm2
  movsd  0x8(%rdi),%xmm1
  mov    $0x64,%edi
  call   <onerun@plt>
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: byte[8]

tool: {"D9": [0x9a,0x99,0x99,0x99,0x99,0x99,0xa9,0x3f]}

assistant: ```c
efm(double *in, double *out, int nin, int nout, double *var, double *con) {
  double S = in[0], ibar = in[1], isig = in[2], tau = in[3];
  double dt = .05;
  int ntrials = 100, niter = 200, nstart = 50, n = 100;
  out[0] = onerun(dt, n, ntrials, niter, nstart, ibar, isig, S, tau);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L0:
  mov    $0x1f4,%edi
  call   <oosmos_DelayMS@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x5,-0x4(%rbp)
  jle    L0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D0: Work...


tool: D13: SUCCESS


assistant: ```c
extern int main(void) {
  for (int LoopCount = 1; LoopCount <= 5; LoopCount++) {
    oosmos_DelayMS(500);
    printf("Work...\n");
  }
  printf("SUCCESS\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x5,%ebx
  lea    D10(%rip),%rbp
L4:
  mov    $0x1f4,%edi
  call   <oosmos_DelayMS@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L4
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D12
datatype: string

tool: D10: Work...


tool: D12: SUCCESS


assistant: ```c
extern int main(void) {
  for (int LoopCount = 1; LoopCount <= 5; LoopCount++) {
    oosmos_DelayMS(500);
    printf("Work...\n");
  }
  printf("SUCCESS\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x8,%rsp
L4:
  mov    $0x1f4,%edi
  call   <oosmos_DelayMS@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L4
  lea    D19(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D2: Work...


tool: D19: SUCCESS


assistant: ```c
extern int main(void) {
  for (int LoopCount = 1; LoopCount <= 5; LoopCount++) {
    oosmos_DelayMS(500);
    printf("Work...\n");
  }
  printf("SUCCESS\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x8,%rsp
L6:
  mov    $0x1f4,%edi
  call   <oosmos_DelayMS@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  lea    D19(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string
name: read_data
arguments: tag: D19
datatype: string

tool: D1: Work...


tool: D19: SUCCESS


assistant: ```c
extern int main(void) {
  for (int LoopCount = 1; LoopCount <= 5; LoopCount++) {
    oosmos_DelayMS(500);
    printf("Work...\n");
  }
  printf("SUCCESS\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetInt32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x18,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int GetInt32(const char *ptr) {
  int val;
  val = (ptr[0] << 0) | (ptr[1] << 8) | (ptr[2] << 16) | (ptr[3] << 24);
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GetInt32>:
  endbr64
  movsbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movsbl 0x2(%rdi),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  movsbl (%rdi),%edx
  or     %edx,%eax
  movsbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int GetInt32(const char *ptr) {
  int val;
  val = (ptr[0] << 0) | (ptr[1] << 8) | (ptr[2] << 16) | (ptr[3] << 24);
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetInt32>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  movsbl (%rdi),%edx
  or     %edx,%eax
  movsbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int GetInt32(const char *ptr) {
  int val;
  val = (ptr[0] << 0) | (ptr[1] << 8) | (ptr[2] << 16) | (ptr[3] << 24);
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetInt32>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  movsbl (%rdi),%edx
  or     %edx,%eax
  movsbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int GetInt32(const char *ptr) {
  int val;
  val = (ptr[0] << 0) | (ptr[1] << 8) | (ptr[2] << 16) | (ptr[3] << 24);
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_four>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L7:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L7
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_four(int x, int y) {
#pragma omp target teams distribute simd collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_four>:
  endbr64
  mov    $0x0,%edx
  test   %edi,%edi
  jg     L3
  ret
L21:
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L21
L7:
  add    $0x1,%edx
  cmp    %edx,%edi
  je     L2
L3:
  mov    $0x0,%eax
  test   %esi,%esi
  jg     L21
  jmp    L7
L2:
  ret
```

assistant: ```c
void test_four(int x, int y) {
#pragma omp target teams distribute simd collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_four>:
  endbr64
  ret
```

assistant: ```c
void test_four(int x, int y) {
#pragma omp target teams distribute simd collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<array_contains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jne    L28
  mov    $0x1,%eax
  jmp    L6
L28:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int array_contains(int len, unsigned int *array, unsigned int elt) {
  for (int i = 0; i < len; i++) {
    if (array[i] == elt)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<array_contains>:
  endbr64
  test   %edi,%edi
  jle    L28
  mov    %rsi,%rax
  lea    -0x1(%rdi),%ecx
  lea    0x4(%rsi,%rcx,4),%rcx
L13:
  cmp    %edx,(%rax)
  je     L21
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L13
  mov    $0x0,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int array_contains(int len, unsigned int *array, unsigned int elt) {
  for (int i = 0; i < len; i++) {
    if (array[i] == elt)
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<array_contains>:
  endbr64
  test   %edi,%edi
  jle    L38
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rax
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x4,%rsi
  cmp    %rax,%rsi
  je     L38
L23:
  cmp    %edx,(%rsi)
  jne    L22
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int array_contains(int len, unsigned int *array, unsigned int elt) {
  for (int i = 0; i < len; i++) {
    if (array[i] == elt)
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<array_contains>:
  endbr64
  test   %edi,%edi
  jle    L34
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rax
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x4,%rsi
  cmp    %rax,%rsi
  je     L34
L18:
  cmp    %edx,(%rsi)
  jne    L38
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int array_contains(int len, unsigned int *array, unsigned int elt) {
  for (int i = 0; i < len; i++) {
    if (array[i] == elt)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jbe    L49
  mov    -0x1c(%rbp),%eax
  shr    %eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L21
L12:
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L12
  jmp    L39
L59:
  subl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L59
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L15
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
  jmp    L21
L15:
  nop
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quickSort>
  mov    -0x10(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quickSort>
L49:
  nop
  leave
  ret
```

assistant: ```c
void quickSort(int Array[], unsigned int arraySize) {
  if (arraySize >= 2) {
    int pivot = Array[arraySize / 2];
    int i, j, temp;
    for (i = 0, j = arraySize - 1;; i++, j--) {
      while (Array[i] < pivot)
        i++;
      while (Array[j] > pivot)
        j--;
      if (i >= j)
        break;
      temp = Array[i];
      Array[i] = Array[j];
      Array[j] = temp;
    }
    quickSort(Array, i);
    quickSort(Array + i, arraySize - i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quickSort>:
  endbr64
  cmp    $0x1,%esi
  jbe    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %esi,%r12d
  mov    %esi,%eax
  shr    %eax
  mov    %eax,%eax
  mov    (%rdi,%rax,4),%esi
  lea    -0x1(%r12),%edx
  mov    %rdi,%r8
  mov    $0x0,%ebx
  jmp    L7
L3:
  add    $0x1,%rbx
  add    $0x4,%r8
L7:
  mov    %r8,%rbp
  mov    (%r8),%r9d
  cmp    %esi,%r9d
  jl     L3
  movslq %edx,%rax
  lea    (%r10,%rax,4),%rdi
  mov    (%rdi),%ecx
  cmp    %ecx,%esi
  jge    L63
  lea    -0x4(%r10,%rax,4),%rax
L11:
  sub    $0x1,%edx
  mov    %rax,%rdi
  sub    $0x4,%rax
  mov    0x4(%rax),%ecx
  cmp    %esi,%ecx
  jg     L11
L63:
  cmp    %ebx,%edx
  jle    L8
  mov    %ecx,0x0(%rbp)
  mov    %r9d,(%rdi)
  sub    $0x1,%edx
  jmp    L3
L8:
  mov    %ebx,%esi
  mov    %r10,%rdi
  call   <quickSort>
  mov    %r12d,%esi
  sub    %ebx,%esi
  mov    %rbp,%rdi
  call   <quickSort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

assistant: ```c
void quickSort(int Array[], unsigned int arraySize) {
  if (arraySize >= 2) {
    int pivot = Array[arraySize / 2];
    int i, j, temp;
    for (i = 0, j = arraySize - 1;; i++, j--) {
      while (Array[i] < pivot)
        i++;
      while (Array[j] > pivot)
        j--;
      if (i >= j)
        break;
      temp = Array[i];
      Array[i] = Array[j];
      Array[j] = temp;
    }
    quickSort(Array, i);
    quickSort(Array + i, arraySize - i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quickSort>:
  endbr64
  cmp    $0x1,%esi
  jbe    L72
  push   %r12
  mov    %rdi,%r10
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
L73:
  mov    %r12d,%eax
  lea    -0x1(%r12),%ecx
  mov    %r10,%rbx
  xor    %r8d,%r8d
  shr    %eax
  mov    (%r10,%rax,4),%edi
  movslq %ecx,%rax
  xchg   %ax,%ax
L69:
  mov    (%rbx),%r9d
  lea    (%r10,%rax,4),%rsi
  mov    %r8d,%ebp
  mov    (%rsi),%edx
  cmp    %edi,%r9d
  jl     L60
  cmp    %edx,%edi
  jge    L57
  lea    -0x4(%r10,%rax,4),%rax
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rax,%rsi
  mov    (%rax),%edx
  sub    $0x4,%rax
  sub    $0x1,%ecx
  cmp    %edi,%edx
  jg     L20
L57:
  cmp    %r8d,%ecx
  jle    L77
  mov    %edx,(%rbx)
  sub    $0x1,%ecx
  mov    %r9d,(%rsi)
  movslq %ecx,%rax
L60:
  add    $0x1,%r8
  add    $0x4,%rbx
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L77:
  mov    %ebp,%esi
  mov    %r10,%rdi
  sub    %ebp,%r12d
  call   <quickSort>
  cmp    $0x1,%r12d
  jbe    L1
  mov    %rbx,%r10
  jmp    L73
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L72:
  ret
```

assistant: ```c
void quickSort(int Array[], unsigned int arraySize) {
  if (arraySize >= 2) {
    int pivot = Array[arraySize / 2];
    int i, j, temp;
    for (i = 0, j = arraySize - 1;; i++, j--) {
      while (Array[i] < pivot)
        i++;
      while (Array[j] > pivot)
        j--;
      if (i >= j)
        break;
      temp = Array[i];
      Array[i] = Array[j];
      Array[j] = temp;
    }
    quickSort(Array, i);
    quickSort(Array + i, arraySize - i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L43
L4:
  addq   $0x1,-0x8(%rbp)
L43:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L10
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L10
L6:
  subl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L6
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strip(char *string) {
  char *start = string;
  while (isblank(*start))
    start++;
  int end = strlen(start);
  if (start != string) {
    memmove(string, start, end);
    string[end] = '\0';
  }
  while (isblank(*(string + end - 1)))
    end--;
  string[end] = '\0';
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strip>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdi,%rbp
  jmp    L39
L30:
  add    $0x1,%rbp
L39:
  movsbl 0x0(%rbp),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L30
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    %r12,%rbp
  je     L13
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
L13:
  movslq %ebx,%rbx
L23:
  movsbl -0x1(%r12,%rbx,1),%edi
  call   <isblank@plt>
  mov    %rbx,%rdx
  sub    $0x1,%rbx
  test   %rax,%rax
  jne    L23
  movb   $0x0,(%r12,%rdx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strip(char *string) {
  char *start = string;
  while (isblank(*start))
    start++;
  int end = strlen(start);
  if (start != string) {
    memmove(string, start, end);
    string[end] = '\0';
  }
  while (isblank(*(string + end - 1)))
    end--;
  string[end] = '\0';
  return string;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L12
L8:
  add    $0x1,%rbp
L12:
  movsbl 0x0(%rbp),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  mov    %rbx,%rdx
  cmp    %r12,%rbp
  je     L36
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbx,1)
  nopl   (%rax)
L36:
  movsbl -0x1(%r12,%rbx,1),%edi
  call   <isblank@plt>
  mov    %rbx,%rdx
  sub    $0x1,%rbx
  test   %rax,%rax
  jne    L36
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12,%rdx,1)
  pop    %r12
  ret
```

assistant: ```c
char *strip(char *string) {
  char *start = string;
  while (isblank(*start))
    start++;
  int end = strlen(start);
  if (start != string) {
    memmove(string, start, end);
    string[end] = '\0';
  }
  while (isblank(*(string + end - 1)))
    end--;
  string[end] = '\0';
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L23
L22:
  add    $0x1,%rbp
L23:
  movsbl 0x0(%rbp),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L22
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  mov    %rbx,%rdx
  cmp    %r12,%rbp
  je     L11
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbx,1)
  nopl   (%rax)
L11:
  movsbl -0x1(%r12,%rbx,1),%edi
  call   <isblank@plt>
  mov    %rbx,%rdx
  sub    $0x1,%rbx
  test   %rax,%rax
  jne    L11
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12,%rdx,1)
  pop    %r12
  ret
```

assistant: ```c
char *strip(char *string) {
  char *start = string;
  while (isblank(*start))
    start++;
  int end = strlen(start);
  if (start != string) {
    memmove(string, start, end);
    string[end] = '\0';
  }
  while (isblank(*(string + end - 1)))
    end--;
  string[end] = '\0';
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <__builtin_strlen@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <__builtin_doesntexist@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D7: hi

assistant: ```c
void f() {
  (void)__builtin_strlen("hi");
  (void)__builtin_doesntexist(1, 2, 3);
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <__builtin_strlen@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <__builtin_doesntexist@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: hi

assistant: ```c
void f() {
  (void)__builtin_strlen("hi");
  (void)__builtin_doesntexist(1, 2, 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <__builtin_strlen@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <__builtin_doesntexist@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: hi

assistant: ```c
void f() {
  (void)__builtin_strlen("hi");
  (void)__builtin_doesntexist(1, 2, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <__builtin_strlen@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <__builtin_doesntexist@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: hi

assistant: ```c
void f() {
  (void)__builtin_strlen("hi");
  (void)__builtin_doesntexist(1, 2, 3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<djb2_hash_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1505,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L3
L15:
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L15
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int djb2_hash_str(const char *str, size_t str_len) {
  unsigned int hash;
  size_t i;
  hash = 5381;
  for (i = 0; i < str_len; ++i) {
    hash = ((hash << 5) + hash) + ((unsigned int)str[i]);
  }
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<djb2_hash_str>:
  endbr64
  test   %rsi,%rsi
  je     L10
  mov    %rdi,%rdx
  add    %rsi,%rdi
  mov    $0x1505,%eax
L16:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  add    %ecx,%eax
  movsbl (%rdx),%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L16
  ret
L10:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned int djb2_hash_str(const char *str, size_t str_len) {
  unsigned int hash;
  size_t i;
  hash = 5381;
  for (i = 0; i < str_len; ++i) {
    hash = ((hash << 5) + hash) + ((unsigned int)str[i]);
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<djb2_hash_str>:
  endbr64
  test   %rsi,%rsi
  je     L18
  add    %rdi,%rsi
  mov    $0x1505,%eax
  nopl   0x0(%rax)
L5:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rsi,%rdi
  jne    L5
  ret
  nop
L18:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned int djb2_hash_str(const char *str, size_t str_len) {
  unsigned int hash;
  size_t i;
  hash = 5381;
  for (i = 0; i < str_len; ++i) {
    hash = ((hash << 5) + hash) + ((unsigned int)str[i]);
  }
  return hash;
}
```