ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotate_180>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <rotate_90@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <rotate_90@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotate_180(char before[][10], char trans[][10], int n) {
  char tmp[10][10];
  memset(tmp, 0, sizeof(tmp));
  rotate_90(before, tmp, n);
  rotate_90(tmp, trans, n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotate_180>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %edx,%r12d
  mov    $0x64,%edx
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <rotate_90@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <rotate_90@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotate_180(char before[][10], char trans[][10], int n) {
  char tmp[10][10];
  memset(tmp, 0, sizeof(tmp));
  rotate_90(before, tmp, n);
  rotate_90(tmp, trans, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotate_180>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %edx,%r12d
  mov    $0x64,%edx
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <rotate_90@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <rotate_90@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotate_180(char before[][10], char trans[][10], int n) {
  char tmp[10][10];
  memset(tmp, 0, sizeof(tmp));
  rotate_90(before, tmp, n);
  rotate_90(tmp, trans, n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aa_hadec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  movsd  -0x10(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <aaha_aux@plt>
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd D8(%rip),%xmm0
  ja     L18
  jmp    L15
L18:
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  D11(%rip),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
L15:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: f64[2]
name: read_data
arguments: data_label: D11
type_guessed: byte[8]

tool: {"D8": [3.141592653589793,6.283185307179586]}

tool: {"D11": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void aa_hadec(double lt, double alt, double az, double *ha, double *dec) {
  aaha_aux(lt, az, alt, ha, dec);
  if (*ha > 3.141592653589793)
    *ha -= 2 * 3.141592653589793;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aa_hadec>:
  endbr64
  push   %rbx
  movapd %xmm1,%xmm3
  movapd %xmm2,%xmm1
  mov    %rdi,%rbx
  movapd %xmm3,%xmm2
  call   <aaha_aux@plt>
  movsd  (%rbx),%xmm0
  comisd D2(%rip),%xmm0
  jbe    L9
  subsd  D17(%rip),%xmm0
  movsd  %xmm0,(%rbx)
L9:
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: f64[2]
name: parse_data
arguments: label: D17
type_infered: byte[8]

tool: {"D2": [3.141592653589793,6.283185307179586]}

tool: {"D17": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void aa_hadec(double lt, double alt, double az, double *ha, double *dec) {
  aaha_aux(lt, az, alt, ha, dec);
  if (*ha > 3.141592653589793)
    *ha -= 2 * 3.141592653589793;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aa_hadec>:
  endbr64
  push   %rbx
  movapd %xmm1,%xmm3
  mov    %rdi,%rbx
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  call   <aaha_aux@plt>
  movsd  (%rbx),%xmm0
  comisd D18(%rip),%xmm0
  jbe    L2
  subsd  D12(%rip),%xmm0
  movsd  %xmm0,(%rbx)
L2:
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: f64[2]
name: extract_symbolic_data
arguments: label: D12
type_guessed: byte[8]

tool: {"D18": [3.141592653589793,6.283185307179586]}

tool: {"D12": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void aa_hadec(double lt, double alt, double az, double *ha, double *dec) {
  aaha_aux(lt, az, alt, ha, dec);
  if (*ha > 3.141592653589793)
    *ha -= 2 * 3.141592653589793;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aa_hadec>:
  endbr64
  push   %rbx
  movapd %xmm1,%xmm3
  mov    %rdi,%rbx
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  call   <aaha_aux@plt>
  movsd  (%rbx),%xmm0
  comisd D13(%rip),%xmm0
  jbe    L9
  subsd  D2(%rip),%xmm0
  movsd  %xmm0,(%rbx)
L9:
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
datatype: f64[2]
name: unpack_data
arguments: tag: D2
datatype: byte[8]

tool: {"D13": [3.141592653589793,6.283185307179586]}

tool: {"D2": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void aa_hadec(double lt, double alt, double az, double *ha, double *dec) {
  aaha_aux(lt, az, alt, ha, dec);
  if (*ha > 3.141592653589793)
    *ha -= 2 * 3.141592653589793;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<squares>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L10
L18:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <squares>
  add    %ebx,%eax
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int squares(int n) {
  if (n == 0)
    return 0;
  else
    return n * n + squares(n - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<squares>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jne    L4
  ret
L4:
  push   %rbx
  mov    %edi,%ebx
  imul   %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <squares>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int squares(int n) {
  if (n == 0)
    return 0;
  else
    return n * n + squares(n - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<squares>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L1
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %edi,%edx
  imul   %edi,%edx
  add    %edx,%eax
  sub    $0x1,%edi
  jne    L10
L1:
  ret
```

assistant: ```c
int squares(int n) {
  if (n == 0)
    return 0;
  else
    return n * n + squares(n - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<squares>:
  endbr64
  test   %edi,%edi
  je     L61
  lea    -0x1(%rdi),%edx
  mov    %edi,%ecx
  cmp    $0x11,%edx
  jbe    L49
  movd   %edi,%xmm5
  mov    %edi,%edx
  movdqa D17(%rip),%xmm4
  xor    %eax,%eax
  pshufd $0x0,%xmm5,%xmm3
  paddd  D16(%rip),%xmm3
  shr    $0x2,%edx
  pxor   %xmm1,%xmm1
  xchg   %ax,%ax
L66:
  movdqa %xmm3,%xmm0
  add    $0x1,%eax
  paddd  %xmm4,%xmm3
  movdqa %xmm0,%xmm2
  pmuludq %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pmuludq %xmm0,%xmm0
  pshufd $0x8,%xmm2,%xmm2
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm2
  paddd  %xmm2,%xmm1
  cmp    %edx,%eax
  jne    L66
  movdqa %xmm1,%xmm0
  mov    %edi,%edx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edx
  paddd  %xmm0,%xmm1
  sub    %edx,%edi
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %edx,%ecx
  je     L12
  lea    -0x1(%rdi),%edx
  jmp    L16
L23:
  sub    $0x1,%edx
L16:
  mov    %edi,%ecx
  imul   %edi,%ecx
  mov    %edx,%edi
  add    %ecx,%eax
  test   %edx,%edx
  jne    L23
L12:
  ret
  nopl   0x0(%rax)
L61:
  xor    %eax,%eax
  ret
L49:
  xor    %eax,%eax
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: data_label: D17
data_type: byte[16]
name: retrieve_data
arguments: data_label: D16
data_type: byte[16]

tool: {"D17": [0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff]}

tool: {"D16": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfd,0xff,0xff,0xff]}

assistant: ```c
int squares(int n) {
  if (n == 0)
    return 0;
  else
    return n * n + squares(n - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void drop(char s1[], int place) {
  int n;
  int length = 0;
  length = strlen(s1);
  for (n = place; n < length; n++) {
    s1[n] = s1[n + 1];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<drop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L14
  movslq %ebx,%rcx
  lea    0x0(%rbp,%rcx,1),%rdx
  lea    0x1(%rbp,%rcx,1),%rcx
  sub    %ebx,%eax
  lea    -0x1(%rax),%eax
  add    %rax,%rcx
L17:
  movzbl 0x1(%rdx),%eax
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L17
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drop(char s1[], int place) {
  int n;
  int length = 0;
  length = strlen(s1);
  for (n = place; n < length; n++) {
    s1[n] = s1[n + 1];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drop>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L8
  sub    %ebp,%eax
  movslq %ebp,%rcx
  add    $0x8,%rsp
  lea    -0x1(%rax),%edx
  lea    0x1(%rbx,%rcx,1),%rsi
  lea    (%rbx,%rcx,1),%rdi
  add    $0x1,%rdx
  pop    %rbx
  pop    %rbp
  jmp    1070 <memmove@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drop(char s1[], int place) {
  int n;
  int length = 0;
  length = strlen(s1);
  for (n = place; n < length; n++) {
    s1[n] = s1[n + 1];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<drop>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L1
  sub    %ebp,%eax
  movslq %ebp,%rcx
  add    $0x8,%rsp
  lea    -0x1(%rax),%edx
  lea    0x1(%rbx,%rcx,1),%rsi
  lea    (%rbx,%rcx,1),%rdi
  add    $0x1,%rdx
  pop    %rbx
  pop    %rbp
  jmp    1070 <memmove@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drop(char s1[], int place) {
  int n;
  int length = 0;
  length = strlen(s1);
  for (n = place; n < length; n++) {
    s1[n] = s1[n + 1];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checkVowel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x61,-0x4(%rbp)
  je     L83
  cmpb   $0x41,-0x4(%rbp)
  je     L83
  cmpb   $0x65,-0x4(%rbp)
  je     L83
  cmpb   $0x45,-0x4(%rbp)
  je     L83
  cmpb   $0x69,-0x4(%rbp)
  je     L83
  cmpb   $0x49,-0x4(%rbp)
  je     L83
  cmpb   $0x6f,-0x4(%rbp)
  je     L83
  cmpb   $0x4f,-0x4(%rbp)
  je     L83
  cmpb   $0x75,-0x4(%rbp)
  je     L83
  cmpb   $0x55,-0x4(%rbp)
  jne    L87
L83:
  mov    $0x1,%eax
  jmp    L47
L87:
  mov    $0x0,%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int checkVowel(char M) {
  if (M == 'a' || M == 'A' || M == 'e' || M == 'E' || M == 'i' || M == 'I' || M == 'o' || M == 'O' || M == 'u' || M == 'U')
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checkVowel>:
  endbr64
  lea    -0x41(%rdi),%ecx
  cmp    $0x34,%cl
  ja     L9
  movabs $0x10411100104111,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int checkVowel(char M) {
  if (M == 'a' || M == 'A' || M == 'e' || M == 'E' || M == 'i' || M == 'I' || M == 'o' || M == 'O' || M == 'u' || M == 'U')
    return (1);
  else
    return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<checkVowel>:
  endbr64
  lea    -0x41(%rdi),%ecx
  cmp    $0x34,%cl
  ja     L3
  movabs $0x10411100104111,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int checkVowel(char M) {
  if (M == 'a' || M == 'A' || M == 'e' || M == 'E' || M == 'i' || M == 'I' || M == 'o' || M == 'O' || M == 'u' || M == 'U')
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<checkVowel>:
  endbr64
  lea    -0x41(%rdi),%ecx
  cmp    $0x34,%cl
  ja     L8
  movabs $0x10411100104111,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int checkVowel(char M) {
  if (M == 'a' || M == 'A' || M == 'e' || M == 'E' || M == 'i' || M == 'I' || M == 'o' || M == 'O' || M == 'u' || M == 'U')
    return (1);
  else
    return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = vfprintf(stdout, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = vfprintf(stdout, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = vfprintf(stdout, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = vfprintf(stdout, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<divmodbig>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbp
  mov    (%rsi),%ebx
  mov    (%rdi),%r8d
  sub    %ebx,%r8d
  js     L58
  mov    %rdi,%rax
  mov    %rsi,%r14
  movslq %r8d,%rcx
  lea    (%rdx,%rcx,4),%r11
  lea    -0x1(%rbx),%edx
  add    %rdx,%rcx
  lea    0x4(%rdi,%rcx,4),%rcx
  movslq %ebx,%rsi
  lea    (%r14,%rsi,4),%r13
  mov    %r8d,%edi
  not    %rdx
  lea    0x0(,%rdx,4),%rsi
  mov    %rsi,-0x8(%rsp)
  jmp    L78
L36:
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%r12
  mov    $0x0,%edx
  mov    $0x0,%esi
L15:
  mov    (%r12,%rdx,1),%r10d
  mov    0x0(%r13,%rdx,1),%r9d
  cmp    %r9d,%r10d
  jne    L248
  add    $0x1,%esi
  sub    $0x4,%rdx
  cmp    %ebx,%esi
  jl     L15
  jmp    L165
L248:
  jl     L152
  jmp    L165
L7:
  add    $0x2,%esi
  mov    %esi,0x4(%rdx)
  subl   $0x1,0x8(%rdx)
L184:
  add    $0x4,%rdx
  add    $0x4,%r9
  cmp    %rcx,%rdx
  je     L210
L123:
  mov    0x4(%rdx),%esi
  sub    (%r9),%esi
  js     L7
  mov    %esi,0x4(%rdx)
  jmp    L184
L210:
  mov    (%rax),%r9d
  cmp    $0x1,%r9d
  jle    L152
  lea    -0x1(%r9),%edx
  movslq %edx,%rdx
  movslq %r9d,%rsi
  sub    $0x2,%rsi
  lea    -0x2(%r9),%r9d
  sub    %r9,%rsi
L12:
  cmpl   $0x0,0x4(%rax,%rdx,4)
  jne    L152
  mov    %edx,(%rax)
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L12
L152:
  sub    $0x1,%edi
  sub    $0x4,%r11
  sub    $0x4,%rcx
  cmp    $0xffffffff,%edi
  je     L98
L78:
  mov    %r11,%r15
  movl   $0x0,0x4(%r11)
  mov    (%rax),%edx
  mov    %edi,%esi
  add    (%r14),%esi
  cmp    %esi,%edx
  jl     L152
  lea    (%rdi,%rbx,1),%esi
  cmp    %esi,%edx
  je     L36
L165:
  movl   $0x1,0x4(%r15)
  test   %ebx,%ebx
  jle    L210
  mov    -0x8(%rsp),%rsi
  lea    (%rsi,%rcx,1),%rdx
  lea    0x4(%r14),%r9
  jmp    L123
L58:
  add    $0x1,%r8d
  mov    %r8d,(%rdx)
  cmp    $0x1,%r8d
  jg     L57
  jmp    L240
L111:
  movl   $0x1,0x0(%rbp)
  movl   $0x0,0x4(%rbp)
  jmp    L221
L98:
  add    $0x1,%r8d
  mov    %r8d,0x0(%rbp)
  cmp    $0x1,%r8d
  jle    L221
L57:
  movslq %r8d,%rax
L237:
  mov    %eax,%r8d
  cmpl   $0x0,0x0(%rbp,%rax,4)
  jne    L240
  lea    -0x1(%rax),%r8d
  mov    %r8d,0x0(%rbp)
  sub    $0x1,%rax
  cmp    $0x1,%eax
  jg     L237
L240:
  test   %r8d,%r8d
  jle    L111
L221:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void divmodbig(int *x, int *y, int *d) {
  int a, b, n = y[0], l;
  l = x[0] - y[0];
  for (a = l; a >= 0; a--) {
    d[a + 1] = 0;
    if (x[0] < y[0] + a)
      continue;
    else if (x[0] == n + a) {
      for (b = 0; x[x[0] - b] == y[n - b] && b + 1 < n; b++)
        ;
      if (x[x[0] - b] < y[n - b])
        continue;
    }
    d[a + 1] = 1;
    for (b = 1; b <= n; b++) {
      x[a + b] -= y[b];
      if (x[a + b] < 0) {
        x[a + b] += 2;
        x[a + b + 1]--;
      }
    }
    while (x[0] > 1 && x[x[0]] == 0)
      x[0]--;
  }
  for (d[0] = l + 1; d[0] > 1 && d[d[0]] == 0; d[0]--)
    ;
  if (d[0] < 1) {
    d[0] = 1;
    d[1] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<divmodbig>:
  endbr64
  push   %r15
  push   %r14
  mov    (%rdi),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rsi),%r10d
  mov    %rdx,%rbx
  sub    %r10d,%r14d
  js     L65
  movslq %r14d,%r8
  lea    -0x1(%r10),%r13d
  mov    %rsi,%r12
  mov    %r14d,%r9d
  lea    (%r8,%r13,1),%rax
  not    %r13
  lea    (%rdx,%r8,4),%r11
  lea    0x4(%rdi,%rax,4),%rsi
  movslq %r10d,%rax
  shl    $0x2,%r13
  lea    (%r12,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L109:
  movl   $0x0,0x4(%r11)
  mov    (%r12),%edx
  movslq (%rdi),%rax
  add    %r9d,%edx
  cmp    %edx,%eax
  jl     L190
  lea    (%r9,%r10,1),%edx
  cmp    %edx,%eax
  je     L175
L187:
  movl   $0x1,0x4(%r11)
  test   %r10d,%r10d
  jle    L99
  lea    0x0(%r13,%rsi,1),%rax
  lea    0x4(%r12),%rcx
  jmp    L55
  nop
L205:
  mov    %edx,0x4(%rax)
  add    $0x4,%rax
  add    $0x4,%rcx
  cmp    %rsi,%rax
  je     L99
L55:
  mov    0x4(%rax),%edx
  sub    (%rcx),%edx
  jns    L205
  add    $0x2,%edx
  subl   $0x1,0x8(%rax)
  add    $0x4,%rax
  add    $0x4,%rcx
  mov    %edx,(%rax)
  cmp    %rsi,%rax
  jne    L55
L99:
  mov    (%rdi),%ecx
  cmp    $0x1,%ecx
  jle    L190
  movslq %ecx,%rdx
  lea    -0x1(%rcx),%eax
  sub    $0x2,%ecx
  sub    $0x2,%rdx
  cltq
  sub    %rcx,%rdx
  jmp    L125
  nopl   0x0(%rax,%rax,1)
L114:
  mov    %eax,(%rdi)
  sub    $0x1,%rax
  cmp    %rax,%rdx
  je     L190
L125:
  mov    0x4(%rdi,%rax,4),%ecx
  test   %ecx,%ecx
  je     L114
L190:
  sub    $0x1,%r9d
  sub    $0x4,%r11
  sub    $0x4,%rsi
  cmp    $0xffffffff,%r9d
  jne    L109
  lea    0x1(%r14),%eax
  mov    %eax,(%rbx)
  cmp    $0x1,%eax
  je     L102
  lea    -0x1(%r8),%rax
  lea    -0x1(%r14),%edx
  sub    %rdx,%rax
  jmp    L199
  nopl   0x0(%rax)
L218:
  mov    %r8d,(%rbx)
  sub    $0x1,%r8
  cmp    %rax,%r8
  je     L102
L199:
  mov    0x4(%rbx,%r8,4),%edx
  test   %edx,%edx
  je     L218
L102:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L175:
  lea    (%rdi,%rax,4),%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L67:
  add    $0x1,%edx
  sub    $0x4,%rax
  cmp    %r10d,%edx
  jge    L187
L71:
  mov    0x0(%rbp,%rax,1),%r15d
  cmp    %r15d,(%rcx,%rax,1)
  je     L67
  jl     L190
  jmp    L187
  cs nopw 0x0(%rax,%rax,1)
L65:
  movq   $0x1,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void divmodbig(int *x, int *y, int *d) {
  int a, b, n = y[0], l;
  l = x[0] - y[0];
  for (a = l; a >= 0; a--) {
    d[a + 1] = 0;
    if (x[0] < y[0] + a)
      continue;
    else if (x[0] == n + a) {
      for (b = 0; x[x[0] - b] == y[n - b] && b + 1 < n; b++)
        ;
      if (x[x[0] - b] < y[n - b])
        continue;
    }
    d[a + 1] = 1;
    for (b = 1; b <= n; b++) {
      x[a + b] -= y[b];
      if (x[a + b] < 0) {
        x[a + b] += 2;
        x[a + b + 1]--;
      }
    }
    while (x[0] > 1 && x[x[0]] == 0)
      x[0]--;
  }
  for (d[0] = l + 1; d[0] > 1 && d[d[0]] == 0; d[0]--)
    ;
  if (d[0] < 1) {
    d[0] = 1;
    d[1] = 0;
  }
}
```