ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jl     L36
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L78
L36:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jl     L76
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jg     L76
L78:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L63
L76:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jl     L83
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L74
L83:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jl     L106
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jg     L106
L74:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L63
L106:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L63:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D30
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D45
type_infered: string

tool: D30: Please enter 3 numbers separated by spaces > 

tool: D20: %i %i %i

tool: D45: %i is the median


assistant: ```c
int main(void) {
  int num1, num2, num3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%i %i %i", &num1, &num2, &num3);
  if ((((num1 >= num2) && (num1 <= num3))) || ((num1 >= num3) && (num1 <= num2))) {
    printf("%i is the median\n", num1);
    return 0;
  } else if ((((num2 >= num1) && (num2 <= num3))) || ((num2 >= num3) && (num2 <= num1))) {
    printf("%i is the median\n", num2);
    return 0;
  } else {
    printf("%i is the median\n", num3);
    return 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  jl     L99
  cmp    0x14(%rsp),%esi
  jle    L45
L99:
  mov    0x14(%rsp),%edx
  cmp    %eax,%esi
  setle  %cl
  cmp    %edx,%esi
  jl     L51
  test   %cl,%cl
  jne    L45
L51:
  cmp    %edx,%eax
  jg     L41
  test   %cl,%cl
  jne    L1
L41:
  cmp    %eax,%esi
  jl     L85
  cmp    %edx,%eax
  jl     L85
L1:
  mov    %eax,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L64:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L45:
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L64
L85:
  mov    %edx,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L64
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D25
data_type: string
name: read_data
arguments: tag: D5
data_type: string
name: read_data
arguments: tag: D27
data_type: string

tool: D25: Please enter 3 numbers separated by spaces > 

tool: D5: %i %i %i

tool: D27: %i is the median


assistant: ```c
int main(void) {
  int num1, num2, num3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%i %i %i", &num1, &num2, &num3);
  if ((((num1 >= num2) && (num1 <= num3))) || ((num1 >= num3) && (num1 <= num2))) {
    printf("%i is the median\n", num1);
    return 0;
  } else if ((((num2 >= num1) && (num2 <= num3))) || ((num2 >= num3) && (num2 <= num1))) {
    printf("%i is the median\n", num2);
    return 0;
  } else {
    printf("%i is the median\n", num3);
    return 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%r9d
  cmp    %r8d,%esi
  jl     L52
  cmp    %r9d,%esi
  jle    L63
  cmp    %r8d,%esi
  je     L63
  cmp    %r9d,%r8d
  jl     L46
L2:
  mov    %r8d,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L53
L52:
  cmp    %r9d,%esi
  jge    L63
  cmp    %r9d,%r8d
  jle    L2
L46:
  mov    %r9d,%esi
L63:
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L53:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string

tool: D0: Please enter 3 numbers separated by spaces > 

tool: D3: %i %i %i

tool: D20: %i is the median


assistant: ```c
int main(void) {
  int num1, num2, num3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%i %i %i", &num1, &num2, &num3);
  if ((((num1 >= num2) && (num1 <= num3))) || ((num1 >= num3) && (num1 <= num2))) {
    printf("%i is the median\n", num1);
    return 0;
  } else if ((((num2 >= num1) && (num2 <= num3))) || ((num2 >= num3) && (num2 <= num1))) {
    printf("%i is the median\n", num2);
    return 0;
  } else {
    printf("%i is the median\n", num3);
    return 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%r9d
  cmp    %r8d,%esi
  jl     L4
  cmp    %r9d,%esi
  jle    L39
  cmp    %r8d,%esi
  je     L39
  cmp    %r9d,%r8d
  jl     L33
L75:
  mov    %r8d,%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L73
L4:
  cmp    %r9d,%esi
  jge    L39
  cmp    %r9d,%r8d
  jle    L75
L33:
  mov    %r9d,%esi
L39:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L73:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D23
type_guessed: string

tool: D7: Please enter 3 numbers separated by spaces > 

tool: D0: %i %i %i

tool: D23: %i is the median


assistant: ```c
int main(void) {
  int num1, num2, num3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%i %i %i", &num1, &num2, &num3);
  if ((((num1 >= num2) && (num1 <= num3))) || ((num1 >= num3) && (num1 <= num2))) {
    printf("%i is the median\n", num1);
    return 0;
  } else if ((((num2 >= num1) && (num2 <= num3))) || ((num2 >= num3) && (num2 <= num1))) {
    printf("%i is the median\n", num2);
    return 0;
  } else {
    printf("%i is the median\n", num3);
    return 0;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x8,-0x4(%rbp)
  jle    L9
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy(char from[], char to[]) {
  int i;
  for (i = 0; i < 9; ++i) {
    to[i] = from[i];
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<copy>:
  endbr64
  mov    $0x0,%eax
L3:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    $0x9,%rax
  jne    L3
  ret
```

assistant: ```c
void copy(char from[], char to[]) {
  int i;
  for (i = 0; i < 9; ++i) {
    to[i] = from[i];
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<copy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L8:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    $0x9,%rax
  jne    L8
  ret
```

assistant: ```c
void copy(char from[], char to[]) {
  int i;
  for (i = 0; i < 9; ++i) {
    to[i] = from[i];
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy>:
  endbr64
  lea    0x1(%rdi),%rdx
  mov    %rsi,%rax
  sub    %rdx,%rax
  cmp    $0x6,%rax
  jbe    L2
  mov    (%rdi),%rax
  mov    %rax,(%rsi)
  movzbl 0x8(%rdi),%eax
  mov    %al,0x8(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  movzbl 0x1(%rdi),%eax
  mov    %al,0x1(%rsi)
  movzbl 0x2(%rdi),%eax
  mov    %al,0x2(%rsi)
  movzbl 0x3(%rdi),%eax
  mov    %al,0x3(%rsi)
  movzbl 0x4(%rdi),%eax
  mov    %al,0x4(%rsi)
  movzbl 0x5(%rdi),%eax
  mov    %al,0x5(%rsi)
  movzbl 0x6(%rdi),%eax
  mov    %al,0x6(%rsi)
  movzbl 0x7(%rdi),%eax
  mov    %al,0x7(%rsi)
  movzbl 0x8(%rdi),%eax
  mov    %al,0x8(%rsi)
  ret
```

assistant: ```c
void copy(char from[], char to[]) {
  int i;
  for (i = 0; i < 9; ++i) {
    to[i] = from[i];
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L59:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L48
  mov    $0x1,%eax
  jmp    L57
L48:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L23
  mov    $0xffffffff,%eax
  jmp    L57
L23:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
L65:
  mov    $0x0,%eax
L57:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp_(const char *s1, const char *s2) {
  int i = 0;
  while (s1[i] && s2[i]) {
    if (s1[i] > s2[i]) {
      return 1;
    } else if (s1[i] < s2[i]) {
      return -1;
    }
    i++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcmp_>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x0,%ecx
  test   %al,%al
  je     L31
L8:
  movzbl (%rsi,%rcx,1),%edx
  test   %dl,%dl
  je     L28
  cmp    %al,%dl
  jl     L49
  jg     L43
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  jne    L8
  mov    $0x0,%eax
  ret
L31:
  mov    $0x0,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
L49:
  mov    $0x1,%eax
  ret
L43:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strcmp_(const char *s1, const char *s2) {
  int i = 0;
  while (s1[i] && s2[i]) {
    if (s1[i] > s2[i]) {
      return 1;
    } else if (s1[i] < s2[i]) {
      return -1;
    }
    i++;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcmp_>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L47
  jmp    L17
  nop
L26:
  cmp    %dl,%cl
  jl     L40
  jg     L55
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L29
L47:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L26
L29:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L40:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    $0xffffffff,%eax
  ret
L17:
  ret
```

assistant: ```c
int strcmp_(const char *s1, const char *s2) {
  int i = 0;
  while (s1[i] && s2[i]) {
    if (s1[i] > s2[i]) {
      return 1;
    } else if (s1[i] < s2[i]) {
      return -1;
    }
    i++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp_>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L41
  jmp    L38
  nop
L36:
  cmp    %dl,%cl
  jl     L28
  jg     L11
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L46
L41:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L36
L46:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L28:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0xffffffff,%eax
  ret
L38:
  ret
```

assistant: ```c
int strcmp_(const char *s1, const char *s2) {
  int i = 0;
  while (s1[i] && s2[i]) {
    if (s1[i] > s2[i]) {
      return 1;
    } else if (s1[i] < s2[i]) {
      return -1;
    }
    i++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_compute_power_rec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L35
  mov    $0x1,%eax
  jmp    L13
L35:
  cmpl   $0x0,-0x8(%rbp)
  jns    L37
  mov    $0x0,%eax
  jmp    L13
L37:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <my_compute_power_rec>
  imul   -0x4(%rbp),%eax
L13:
  leave
  ret
```

assistant: ```c
int my_compute_power_rec(int nb, int p) {
  if (p == 0)
    return (1);
  else if (p < 0)
    return (0);
  else
    return (nb * my_compute_power_rec(nb, p - 1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_compute_power_rec>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L23
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  jns    L22
L25:
  pop    %rbx
  ret
L22:
  sub    $0x1,%esi
  call   <my_compute_power_rec>
  imul   %ebx,%eax
  jmp    L25
L23:
  ret
```

assistant: ```c
int my_compute_power_rec(int nb, int p) {
  if (p == 0)
    return (1);
  else if (p < 0)
    return (0);
  else
    return (nb * my_compute_power_rec(nb, p - 1));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_compute_power_rec>:
  endbr64
  test   %esi,%esi
  je     L16
  js     L10
  mov    $0x1,%eax
  nop
L18:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L18
  ret
L16:
  mov    $0x1,%eax
  ret
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int my_compute_power_rec(int nb, int p) {
  if (p == 0)
    return (1);
  else if (p < 0)
    return (0);
  else
    return (nb * my_compute_power_rec(nb, p - 1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<my_compute_power_rec>:
  endbr64
  test   %esi,%esi
  je     L14
  js     L9
  mov    $0x1,%eax
  nop
L23:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L23
  ret
L14:
  mov    $0x1,%eax
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int my_compute_power_rec(int nb, int p) {
  if (p == 0)
    return (1);
  else if (p < 0)
    return (0);
  else
    return (nb * my_compute_power_rec(nb, p - 1));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<call_stdcall_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x2a,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   *%rax
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int call_stdcall_fun(int (*f)(int, int, int)) {
  int a = 42;
  f(1, 2, 3);
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<call_stdcall_fun>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   *%rax
  mov    $0x2a,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int call_stdcall_fun(int (*f)(int, int, int)) {
  int a = 42;
  f(1, 2, 3);
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<call_stdcall_fun>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   *%r8
  mov    $0x2a,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int call_stdcall_fun(int (*f)(int, int, int)) {
  int a = 42;
  f(1, 2, 3);
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<layer_mixN_forward>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L17:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void layer_mixN_forward(const int N, const int *table, const double *params, const double *input, double *output) {
  for (int i = 0; i < N; i++) {
    output[table[2 * i + 1]] += input[table[2 * i]] * params[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<layer_mixN_forward>:
  endbr64
  mov    %rdx,%r10
  test   %edi,%edi
  jle    L10
  mov    %edi,%edi
  mov    $0x0,%eax
L11:
  movslq 0x4(%rsi,%rax,8),%rdx
  lea    (%r8,%rdx,8),%rdx
  movslq (%rsi,%rax,8),%r9
  movsd  (%rcx,%r9,8),%xmm0
  mulsd  (%r10,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L11
L10:
  ret
```

assistant: ```c
void layer_mixN_forward(const int N, const int *table, const double *params, const double *input, double *output) {
  for (int i = 0; i < N; i++) {
    output[table[2 * i + 1]] += input[table[2 * i]] * params[i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<layer_mixN_forward>:
  endbr64
  mov    %rdx,%r10
  test   %edi,%edi
  jle    L0
  movslq %edi,%rdi
  xor    %eax,%eax
L15:
  movslq 0x4(%rsi,%rax,8),%rdx
  movslq (%rsi,%rax,8),%r9
  lea    (%r8,%rdx,8),%rdx
  movsd  (%rcx,%r9,8),%xmm0
  mulsd  (%r10,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rdi
  jne    L15
L0:
  ret
```

assistant: ```c
void layer_mixN_forward(const int N, const int *table, const double *params, const double *input, double *output) {
  for (int i = 0; i < N; i++) {
    output[table[2 * i + 1]] += input[table[2 * i]] * params[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<layer_mixN_forward>:
  endbr64
  mov    %rdx,%r10
  test   %edi,%edi
  jle    L13
  movslq %edi,%rdi
  xor    %eax,%eax
L3:
  movslq 0x4(%rsi,%rax,8),%rdx
  movslq (%rsi,%rax,8),%r9
  lea    (%r8,%rdx,8),%rdx
  movsd  (%rcx,%r9,8),%xmm0
  mulsd  (%r10,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rdi
  jne    L3
L13:
  ret
```

assistant: ```c
void layer_mixN_forward(const int N, const int *table, const double *params, const double *input, double *output) {
  for (int i = 0; i < N; i++) {
    output[table[2 * i + 1]] += input[table[2 * i]] * params[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<logBase10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  lea    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <getNumber@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double logBase10(double a) {
  getNumber(&a);
  return (log10(a));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<logBase10>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <getNumber@plt>
  movsd  0x8(%rsp),%xmm0
  call   <log10@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
double logBase10(double a) {
  getNumber(&a);
  return (log10(a));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<logBase10>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <getNumber@plt>
  movsd  0x8(%rsp),%xmm0
  call   <log10@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
double logBase10(double a) {
  getNumber(&a);
  return (log10(a));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<logBase10>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <getNumber@plt>
  movsd  0x8(%rsp),%xmm0
  call   <log10@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
double logBase10(double a) {
  getNumber(&a);
  return (log10(a));
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_11_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_11_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = S & stk3;
  stk1 = T | stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_11_0_1>:
  endbr64
  mov    %rdi,%rcx
  movzbl (%rdi),%edi
  mov    %edi,%eax
  not    %eax
  and    %esi,%eax
  or     %edx,%eax
  not    %esi
  and    %edx,%esi
  and    %edi,%esi
  not    %eax
  or     %esi,%eax
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void rop3_11_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = S & stk3;
  stk1 = T | stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```