ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebp
  lea    D12(%rip),%r12
  lea    D26(%rip),%r13
  mov    $0x0,%ebx
  jmp    L37
L93:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  lea    (%rdi,%rcx,1),%edx
  cmp    %esi,%eax
  cmove  %edx,%edi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L93
  cmp    %edi,%r11d
  cmove  %esi,%r9d
L83:
  add    $0x1,%esi
  add    $0x1,%r8d
  cmp    %r14d,%esi
  je     L89
L43:
  mov    %r10d,%ecx
  mov    %ebx,%edi
  test   %esi,%esi
  jg     L93
  jmp    L83
L89:
  test   %r9d,%r9d
  je     L116
  mov    %r9d,%edx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L95:
  add    $0x1,%ebp
L37:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %eax,%r10d
  cmp    $0x1,%eax
  jne    L67
  mov    0x4(%rsp),%r11d
  test   %r11d,%r11d
  je     L67
  jle    L116
  lea    0x1(%r11),%r14d
  mov    %r10d,%esi
  mov    $0x2,%r8d
  mov    $0x0,%r9d
  jmp    L43
L116:
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L95
L67:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
data_type: string
name: extract_symbolic_data
arguments: data_label: D26
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D12: %d

tool: D26: Case %d: -1


tool: D4: Case %d: %d


assistant: ```c
int main() {
  int n, i, sum, temp, k = 1, j;
  while (scanf("%d", &n) == 1) {
    temp = 0;
    if (n == 0)
      break;
    for (i = 1; i <= n; i++) {
      sum = 0;
      for (j = 1; j <= i; j++) {
        if ((i / j) * j == i) {
          sum += j;
        }
      }
      if (sum == n) {
        temp = i;
      }
    }
    if (temp != 0)
      printf("Case %d: %d\n", k, temp);
    else
      printf("Case %d: -1\n", k);
    k++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L21
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x4(%rsp),%r10d
  test   %r10d,%r10d
  je     L21
  jle    L26
  lea    0x1(%r10),%r11d
  mov    $0x1,%esi
  mov    $0x2,%r8d
  xor    %r9d,%r9d
  xchg   %ax,%ax
L31:
  mov    $0x1,%ecx
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  lea    (%rdi,%rcx,1),%edx
  imul   %ecx,%eax
  cmp    %esi,%eax
  cmove  %edx,%edi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L23
  cmp    %edi,%r10d
  lea    0x1(%rcx),%r8d
  cmove  %esi,%r9d
  add    $0x1,%esi
  cmp    %r11d,%esi
  jne    L31
  test   %r9d,%r9d
  je     L26
  mov    %r9d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L5:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L27
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L5
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D29
datatype: string

tool: D22: Case %d: -1


tool: D2: Case %d: %d


tool: D29: %d

assistant: ```c
int main() {
  int n, i, sum, temp, k = 1, j;
  while (scanf("%d", &n) == 1) {
    temp = 0;
    if (n == 0)
      break;
    for (i = 1; i <= n; i++) {
      sum = 0;
      for (j = 1; j <= i; j++) {
        if ((i / j) * j == i) {
          sum += j;
        }
      }
      if (sum == n) {
        temp = i;
      }
    }
    if (temp != 0)
      printf("Case %d: %d\n", k, temp);
    else
      printf("Case %d: -1\n", k);
    k++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L56
  nopl   0x0(%rax,%rax,1)
L62:
  mov    0x4(%rsp),%r10d
  test   %r10d,%r10d
  je     L56
  jle    L58
  lea    0x1(%r10),%r11d
  mov    $0x1,%esi
  mov    $0x2,%r8d
  xor    %r9d,%r9d
  xchg   %ax,%ax
L67:
  mov    $0x1,%ecx
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  lea    (%rdi,%rcx,1),%edx
  imul   %ecx,%eax
  cmp    %esi,%eax
  cmove  %edx,%edi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L52
  cmp    %edi,%r10d
  cmove  %esi,%r9d
  add    $0x1,%esi
  add    $0x1,%r8d
  cmp    %r11d,%esi
  jne    L67
  test   %r9d,%r9d
  je     L58
  mov    %r9d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L43:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L62
L56:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D20
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string

tool: D20: Case %d: -1


tool: D13: Case %d: %d


tool: D3: %d

assistant: ```c
int main() {
  int n, i, sum, temp, k = 1, j;
  while (scanf("%d", &n) == 1) {
    temp = 0;
    if (n == 0)
      break;
    for (i = 1; i <= n; i++) {
      sum = 0;
      for (j = 1; j <= i; j++) {
        if ((i / j) * j == i) {
          sum += j;
        }
      }
      if (sum == n) {
        temp = i;
      }
    }
    if (temp != 0)
      printf("Case %d: %d\n", k, temp);
    else
      printf("Case %d: -1\n", k);
    k++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<pptcapi_temp_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x88(%rbp)
  cmpq   $0x0,-0x88(%rbp)
  je     L15
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ecx
  lea    -0x80(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <pptcapi_ltoa@plt>
  mov    $0x0,%edi
  call   <time@plt>
  sub    $0x3b9aca00,%eax
  mov    %eax,-0x8c(%rbp)
  lea    -0x40(%rbp),%rcx
  mov    -0x8c(%rbp),%eax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <pptcapi_ltoa@plt>
  lea    -0x40(%rbp),%rcx
  lea    -0x80(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D9(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
L15:
  mov    -0x88(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: %s_%s

assistant: ```c
char *pptcapi_temp_name() {
  char *retbuf = (char *)malloc(256);
  if (retbuf) {
    char tempbuf1[50];
    pptcapi_ltoa(getpid(), tempbuf1, 10);
    char tempbuf2[50];
    unsigned int t = time(NULL) - 1000000000;
    pptcapi_ltoa(t, tempbuf2, 10);
    snprintf(retbuf, 256, "%s_%s", tempbuf1, tempbuf2);
  }
  return retbuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pptcapi_temp_name>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L4
L7:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %rbx,%rax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edi
  mov    %rsp,%rbp
  mov    $0xa,%edx
  mov    %rbp,%rsi
  call   <pptcapi_ltoa@plt>
  mov    $0x0,%edi
  call   <time@plt>
  lea    0x40(%rsp),%r12
  lea    -0x3b9aca00(%rax),%edi
  mov    $0xa,%edx
  mov    %r12,%rsi
  call   <pptcapi_ltoa@plt>
  mov    %r12,%r8
  mov    %rbp,%rcx
  lea    D0(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  jmp    L7
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: %s_%s

assistant: ```c
char *pptcapi_temp_name() {
  char *retbuf = (char *)malloc(256);
  if (retbuf) {
    char tempbuf1[50];
    pptcapi_ltoa(getpid(), tempbuf1, 10);
    char tempbuf2[50];
    unsigned int t = time(NULL) - 1000000000;
    pptcapi_ltoa(t, tempbuf2, 10);
    snprintf(retbuf, 256, "%s_%s", tempbuf1, tempbuf2);
  }
  return retbuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pptcapi_temp_name>:
  endbr64
  push   %r13
  mov    $0x100,%edi
  push   %r12
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L3
L21:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  sub    $0xffffffffffffff80,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x40(%rsp),%rbx
  call   <getpid@plt>
  mov    %r13,%rsi
  mov    $0xa,%edx
  mov    %eax,%edi
  call   <pptcapi_ltoa@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edx
  lea    -0x3b9aca00(%rax),%edi
  call   <pptcapi_ltoa@plt>
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    $0x100,%esi
  lea    D5(%rip),%rdx
  mov    %r12,%rdi
  call   <snprintf@plt>
  jmp    L21
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string

tool: D5: %s_%s

assistant: ```c
char *pptcapi_temp_name() {
  char *retbuf = (char *)malloc(256);
  if (retbuf) {
    char tempbuf1[50];
    pptcapi_ltoa(getpid(), tempbuf1, 10);
    char tempbuf2[50];
    unsigned int t = time(NULL) - 1000000000;
    pptcapi_ltoa(t, tempbuf2, 10);
    snprintf(retbuf, 256, "%s_%s", tempbuf1, tempbuf2);
  }
  return retbuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pptcapi_temp_name>:
  endbr64
  push   %r13
  mov    $0x100,%edi
  push   %r12
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L3
L29:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  sub    $0xffffffffffffff80,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x40(%rsp),%rbx
  call   <getpid@plt>
  mov    %r13,%rsi
  mov    $0xa,%edx
  mov    %eax,%edi
  call   <pptcapi_ltoa@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edx
  lea    -0x3b9aca00(%rax),%edi
  call   <pptcapi_ltoa@plt>
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    $0x100,%esi
  lea    D5(%rip),%rdx
  mov    %r12,%rdi
  call   <snprintf@plt>
  jmp    L29
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D5: %s_%s

assistant: ```c
char *pptcapi_temp_name() {
  char *retbuf = (char *)malloc(256);
  if (retbuf) {
    char tempbuf1[50];
    pptcapi_ltoa(getpid(), tempbuf1, 10);
    char tempbuf2[50];
    unsigned int t = time(NULL) - 1000000000;
    pptcapi_ltoa(t, tempbuf2, 10);
    snprintf(retbuf, 256, "%s_%s", tempbuf1, tempbuf2);
  }
  return retbuf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<simple_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L15
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L15:
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <count_arg@plt>
  mov    %eax,-0xb8(%rbp)
  movl   $0x0,-0xbc(%rbp)
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  movl   $0x0,-0xbc(%rbp)
  jmp    L25
L4:
  addl   $0x1,-0xbc(%rbp)
L25:
  mov    -0xbc(%rbp),%eax
  cmp    -0xb8(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void simple_printf(const char *format, ...) {
  va_list l;
  int count = count_arg(format);
  int i = 0;
  va_start(l, format);
  for (i = 0; i < count; ++i) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<simple_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <count_arg@plt>
  mov    %eax,%ebx
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <va_start@plt>
  test   %ebx,%ebx
  jle    L4
  mov    $0x0,%eax
L12:
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L12
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void simple_printf(const char *format, ...) {
  va_list l;
  int count = count_arg(format);
  int i = 0;
  va_start(l, format);
  for (i = 0; i < count; ++i) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<simple_printf>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <count_arg@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <va_start@plt>
  pop    %rbp
  ret
```

assistant: ```c
void simple_printf(const char *format, ...) {
  va_list l;
  int count = count_arg(format);
  int i = 0;
  va_start(l, format);
  for (i = 0; i < count; ++i) {
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<simple_printf>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <count_arg@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <va_start@plt>
  pop    %rbp
  ret
```

assistant: ```c
void simple_printf(const char *format, ...) {
  va_list l;
  int count = count_arg(format);
  int i = 0;
  va_start(l, format);
  for (i = 0; i < count; ++i) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <twrite@plt>
  nop
  leave
  ret
```

assistant: ```c
void tputs(const char *s) {
  size_t n;
  n = strlen(s);
  twrite(s, n);
}
```
user: What is the c source code of the assembly code below:

```asm
<tputs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <twrite@plt>
  pop    %rbx
  ret
```

assistant: ```c
void tputs(const char *s) {
  size_t n;
  n = strlen(s);
  twrite(s, n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tputs>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  jmp    1060 <twrite@plt>
```

assistant: ```c
void tputs(const char *s) {
  size_t n;
  n = strlen(s);
  twrite(s, n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tputs>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  jmp    1060 <twrite@plt>
```

assistant: ```c
void tputs(const char *s) {
  size_t n;
  n = strlen(s);
  twrite(s, n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vec_scalar_mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vec_scalar_mul(double z[], const double x[], double y, int n) {
  int i;
  for (i = 0; i < n; i++)
    z[i] = x[i] * y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec_scalar_mul>:
  endbr64
  test   %edx,%edx
  jle    L0
  mov    %edx,%edx
  mov    $0x0,%eax
L17:
  movapd %xmm0,%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L0:
  ret
```

assistant: ```c
void vec_scalar_mul(double z[], const double x[], double y, int n) {
  int i;
  for (i = 0; i < n; i++)
    z[i] = x[i] * y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vec_scalar_mul>:
  endbr64
  test   %edx,%edx
  jle    L6
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L13:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L13
L6:
  ret
```

assistant: ```c
void vec_scalar_mul(double z[], const double x[], double y, int n) {
  int i;
  for (i = 0; i < n; i++)
    z[i] = x[i] * y;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vec_scalar_mul>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L3
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L34
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L34
  mov    %edx,%edi
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  shr    %edi
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rdi
  xchg   %ax,%ax
L32:
  movupd (%rsi,%rax,1),%xmm1
  mulpd  %xmm2,%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L32
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L3
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L22:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L22
L3:
  ret
```

assistant: ```c
void vec_scalar_mul(double z[], const double x[], double y, int n) {
  int i;
  for (i = 0; i < n; i++)
    z[i] = x[i] * y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UnixVfs_rmdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <rmdir@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L0
L14:
  mov    $0xffffffff,%eax
L0:
  leave
  ret
```

assistant: ```c
int UnixVfs_rmdir(const char *zPath) {
  int rc;
  rc = rmdir(zPath);
  return rc == 0 ? 0 : -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UnixVfs_rmdir>:
  endbr64
  sub    $0x8,%rsp
  call   <rmdir@plt>
  neg    %eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int UnixVfs_rmdir(const char *zPath) {
  int rc;
  rc = rmdir(zPath);
  return rc == 0 ? 0 : -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UnixVfs_rmdir>:
  endbr64
  sub    $0x8,%rsp
  call   <rmdir@plt>
  neg    %eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int UnixVfs_rmdir(const char *zPath) {
  int rc;
  rc = rmdir(zPath);
  return rc == 0 ? 0 : -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UnixVfs_rmdir>:
  endbr64
  sub    $0x8,%rsp
  call   <rmdir@plt>
  neg    %eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int UnixVfs_rmdir(const char *zPath) {
  int rc;
  rc = rmdir(zPath);
  return rc == 0 ? 0 : -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: %d 

assistant: ```c
void print(int *v, int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d ", v[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L6
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D4(%rip),%rbp
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: %d 

assistant: ```c
void print(int *v, int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d ", v[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: %d 

assistant: ```c
void print(int *v, int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d ", v[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D8: %d 

assistant: ```c
void print(int *v, int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d ", v[i]);
  }
}
```