user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1cc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1c4(%rbp)
  jmp    L78
L52:
  movl   $0x0,-0x1c0(%rbp)
  jmp    L44
L80:
  mov    -0x1c4(%rbp),%edx
  mov    -0x1c0(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1b0(%rbp),%rcx
  mov    -0x1c0(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x1c4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1c0(%rbp)
L44:
  mov    -0x1cc(%rbp),%eax
  cmp    %eax,-0x1c0(%rbp)
  jl     L80
  addl   $0x1,-0x1c4(%rbp)
L78:
  mov    -0x1c8(%rbp),%eax
  cmp    %eax,-0x1c4(%rbp)
  jl     L52
  movl   $0x0,-0x1bc(%rbp)
  movl   $0x0,-0x1b8(%rbp)
  jmp    L12
L57:
  movl   $0x0,-0x1b4(%rbp)
  jmp    L37
L23:
  mov    -0x1b4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1b8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0x1b0(%rbp,%rax,4),%ebx
  mov    -0x1b4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,-0x1bc(%rbp)
  addl   $0x1,-0x1b4(%rbp)
L37:
  mov    -0x1cc(%rbp),%eax
  cmp    %eax,-0x1b4(%rbp)
  jl     L23
  mov    -0x1bc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1bc(%rbp)
  addl   $0x1,-0x1b8(%rbp)
L12:
  mov    -0x1c8(%rbp),%eax
  cmp    %eax,-0x1b8(%rbp)
  jl     L57
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D3
datatype: string
name: read_data
arguments: label: D46
datatype: string
name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D66
datatype: string

tool: D25: Numarul de linii

tool: D3: %d

tool: D46: Numarul de coloane

tool: D24: a[%d][%d]= 

tool: D21: %d 

tool: D66: 
Exit...

assistant: ```c
int main() {
  int a[10][10];
  int n, m;
  printf("Numarul de linii\n");
  scanf("%d", &m);
  printf("Numarul de coloane\n");
  scanf("%d", &n);
  for (int i = 0; i < m; ++i) {
    for (int j = 0; j < n; ++j) {
      printf("a[%d][%d]= ", j, i);
      scanf("%d", &a[i][j]);
    }
  }
  int zecimal = 0;
  for (int i = 0; i < m; ++i) {
    for (int j = 0; j < n; ++j) {
      zecimal += a[i][j] * pow(2, j);
    }
    printf("%d ", zecimal);
    zecimal = 0;
  }
  printf("\nExit...\n");
  return 0;
}
```