ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip_char>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  movsbl %sil,%r14d
  jmp    L25
L37:
  add    $0x1,%rbx
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L9
  lea    0x0(%rbp,%rbx,1),%r13
  cmp    %r12b,0x0(%rbp,%rbx,1)
  jne    L37
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <last_token@plt>
  mov    %rax,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  jmp    L37
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void strip_char(char *string, char char_to_strip) {
  int i;
  char *p;
  for (i = 0; i < strlen(string); i++) {
    if (string[i] == char_to_strip) {
      p = last_token(&string[i], char_to_strip);
      strcpy(&string[i], p);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strip_char>:
  endbr64
  push   %r14
  movsbl %sil,%r14d
  push   %r13
  push   %r12
  mov    %r14d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rbx
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L23
  lea    0x0(%rbp,%rbx,1),%r13
  cmp    %r12b,0x0(%rbp,%rbx,1)
  jne    L35
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <last_token@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
  jmp    L35
  nopl   0x0(%rax)
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void strip_char(char *string, char char_to_strip) {
  int i;
  char *p;
  for (i = 0; i < strlen(string); i++) {
    if (string[i] == char_to_strip) {
      p = last_token(&string[i], char_to_strip);
      strcpy(&string[i], p);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strip_char>:
  endbr64
  push   %r14
  movsbl %sil,%r14d
  push   %r13
  push   %r12
  mov    %r14d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rbx
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L5
  lea    0x0(%rbp,%rbx,1),%r13
  cmp    %r12b,0x0(%rbp,%rbx,1)
  jne    L4
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <last_token@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
  jmp    L4
  nopl   0x0(%rax)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void strip_char(char *string, char char_to_strip) {
  int i;
  char *p;
  for (i = 0; i < strlen(string); i++) {
    if (string[i] == char_to_strip) {
      p = last_token(&string[i], char_to_strip);
      strcpy(&string[i], p);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fastHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L60
L43:
  cmpq   $0xf,-0x38(%rbp)
  jbe    L0
  mov    -0x40(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x40,-0x40(%rbp)
  subq   $0x10,-0x38(%rbp)
  jmp    L57
L0:
  mov    -0x38(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movq   $0x0,-0x38(%rbp)
L57:
  movl   $0x0,-0x44(%rbp)
  jmp    L34
L51:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%ecx
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%esi
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  imul   %edx,%eax
  add    %eax,%eax
  add    %esi,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  xor    %eax,%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x44(%rbp)
L34:
  cmpl   $0x3,-0x44(%rbp)
  jle    L51
L60:
  cmpq   $0x0,-0x38(%rbp)
  jne    L43
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  xor    %eax,%edx
  mov    -0x28(%rbp),%eax
  xor    %eax,%edx
  mov    -0x24(%rbp),%eax
  xor    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
uint64_t fastHash(uint64_t nonce, const uint8_t *message, size_t message_len) {
  uint64_t hash[4] = {nonce, nonce, nonce, nonce};
  uint64_t value[4] = {0, 0, 0, 0};
  const uint8_t *p = message;
  size_t length = message_len;
  while (length != 0) {
    if (length >= 4 * sizeof(uint64_t)) {
      memcpy(&value, p, 4 * sizeof(uint64_t));
      p += 4 * sizeof(uint64_t);
      length -= 4 * sizeof(uint64_t);
    } else {
      memcpy(&value, p, length);
      length = 0;
    }
    int i;
    for (i = 0; i < 4; i++) {
      hash[i] += value[i] + 2 * hash[i] * value[i];
      hash[i] ^= hash[i] >> 32;
    }
  }
  return hash[0] ^ hash[1] ^ hash[2] ^ hash[3];
}
```
user: Translate the below assembly code into C programming language:

```asm
<fastHash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %edi,0x4(%rsp)
  mov    %edi,0x8(%rsp)
  mov    %edi,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  test   %rdx,%rdx
  je     L48
  mov    %rsi,%r12
  mov    %rdx,%rbp
  lea    0x10(%rsp),%rbx
  jmp    L24
L10:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    $0x0,%ebp
L42:
  mov    %rsp,%rax
  lea    0x10(%rsp),%rsi
L35:
  mov    (%rax),%ecx
  mov    (%rsi),%edx
  mov    %ecx,%edi
  imul   %edx,%edi
  lea    (%rdx,%rdi,2),%edx
  add    %ecx,%edx
  mov    %edx,%edi
  mov    $0x20,%ecx
  sar    %cl,%edi
  xor    %edi,%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    $0x4,%rsi
  cmp    %rbx,%rax
  jne    L35
  test   %rbp,%rbp
  je     L48
L24:
  cmp    $0xf,%rbp
  jbe    L10
  mov    $0x10,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x40,%r12
  sub    $0x10,%rbp
  jmp    L42
L48:
  mov    (%rsp),%eax
  xor    0x4(%rsp),%eax
  xor    0x8(%rsp),%eax
  xor    0xc(%rsp),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t fastHash(uint64_t nonce, const uint8_t *message, size_t message_len) {
  uint64_t hash[4] = {nonce, nonce, nonce, nonce};
  uint64_t value[4] = {0, 0, 0, 0};
  const uint8_t *p = message;
  size_t length = message_len;
  while (length != 0) {
    if (length >= 4 * sizeof(uint64_t)) {
      memcpy(&value, p, 4 * sizeof(uint64_t));
      p += 4 * sizeof(uint64_t);
      length -= 4 * sizeof(uint64_t);
    } else {
      memcpy(&value, p, length);
      length = 0;
    }
    int i;
    for (i = 0; i < 4; i++) {
      hash[i] += value[i] + 2 * hash[i] * value[i];
      hash[i] ^= hash[i] >> 32;
    }
  }
  return hash[0] ^ hash[1] ^ hash[2] ^ hash[3];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fastHash>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %edi,0x4(%rsp)
  mov    %edi,0x8(%rsp)
  mov    %edi,0xc(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  test   %rdx,%rdx
  je     L39
  mov    %rsi,%r13
  mov    %rdx,%r12
  lea    0x10(%rsp),%rbp
  mov    %rsp,%rbx
  cs nopw 0x0(%rax,%rax,1)
L1:
  cmp    $0xf,%r12
  jbe    L27
  mov    %r13,%rsi
  mov    $0x10,%edx
  mov    %rbp,%rdi
  add    $0x40,%r13
  call   <memcpy@plt>
  sub    $0x10,%r12
L38:
  mov    %rbx,%rax
  mov    %rbp,%rsi
L4:
  mov    (%rax),%ecx
  mov    (%rsi),%edx
  add    $0x4,%rax
  add    $0x4,%rsi
  mov    %ecx,%edi
  imul   %edx,%edi
  lea    (%rdx,%rdi,2),%edx
  add    %ecx,%edx
  mov    $0x20,%ecx
  mov    %edx,%edi
  sar    %cl,%edi
  xor    %edi,%edx
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rbp
  jne    L4
  test   %r12,%r12
  jne    L1
  mov    (%rsp),%eax
  xor    0x4(%rsp),%eax
  xor    0x8(%rsp),%eax
  xor    0xc(%rsp),%eax
L46:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L27:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %r12d,%r12d
  call   <memcpy@plt>
  jmp    L38
L39:
  xor    %eax,%eax
  jmp    L46
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t fastHash(uint64_t nonce, const uint8_t *message, size_t message_len) {
  uint64_t hash[4] = {nonce, nonce, nonce, nonce};
  uint64_t value[4] = {0, 0, 0, 0};
  const uint8_t *p = message;
  size_t length = message_len;
  while (length != 0) {
    if (length >= 4 * sizeof(uint64_t)) {
      memcpy(&value, p, 4 * sizeof(uint64_t));
      p += 4 * sizeof(uint64_t);
      length -= 4 * sizeof(uint64_t);
    } else {
      memcpy(&value, p, length);
      length = 0;
    }
    int i;
    for (i = 0; i < 4; i++) {
      hash[i] += value[i] + 2 * hash[i] * value[i];
      hash[i] ^= hash[i] >> 32;
    }
  }
  return hash[0] ^ hash[1] ^ hash[2] ^ hash[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fastHash>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  test   %rdx,%rdx
  je     L4
  lea    0x10(%rsp),%rax
  mov    %edi,%ebx
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    %rax,0x8(%rsp)
  mov    %edi,%ebp
  mov    %edi,%r12d
  mov    %edi,%r13d
  jmp    L48
L22:
  mov    0x8(%rsp),%rdi
  mov    %r14,%rsi
  mov    $0x10,%edx
  add    $0x40,%r14
  sub    $0x10,%r15
  call   <memcpy@plt>
L14:
  mov    0x10(%rsp),%eax
  mov    %ebx,%edx
  mov    $0x20,%ecx
  imul   %eax,%edx
  lea    (%rax,%rdx,2),%eax
  mov    %r13d,%edx
  add    %ebx,%eax
  mov    %eax,%ebx
  sar    %cl,%ebx
  xor    %eax,%ebx
  mov    0x14(%rsp),%eax
  imul   %eax,%edx
  lea    (%rax,%rdx,2),%eax
  add    %r13d,%eax
  mov    %eax,%r13d
  sar    %cl,%r13d
  xor    %eax,%r13d
  mov    0x18(%rsp),%eax
  mov    %eax,%edx
  imul   %r12d,%edx
  lea    (%rax,%rdx,2),%eax
  mov    %ebp,%edx
  add    %r12d,%eax
  mov    %eax,%r12d
  sar    %cl,%r12d
  xor    %eax,%r12d
  mov    0x1c(%rsp),%eax
  imul   %eax,%edx
  lea    (%rax,%rdx,2),%eax
  add    %ebp,%eax
  mov    %eax,%ebp
  sar    %cl,%ebp
  xor    %eax,%ebp
  test   %r15,%r15
  je     L38
L48:
  cmp    $0xf,%r15
  ja     L22
  mov    0x8(%rsp),%rdi
  mov    %r15,%rdx
  mov    %r14,%rsi
  xor    %r15d,%r15d
  call   <memcpy@plt>
  jmp    L14
L38:
  mov    %ebx,%eax
  xor    %r13d,%eax
  xor    %r12d,%eax
  xor    %ebp,%eax
L49:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  xor    %eax,%eax
  jmp    L49
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t fastHash(uint64_t nonce, const uint8_t *message, size_t message_len) {
  uint64_t hash[4] = {nonce, nonce, nonce, nonce};
  uint64_t value[4] = {0, 0, 0, 0};
  const uint8_t *p = message;
  size_t length = message_len;
  while (length != 0) {
    if (length >= 4 * sizeof(uint64_t)) {
      memcpy(&value, p, 4 * sizeof(uint64_t));
      p += 4 * sizeof(uint64_t);
      length -= 4 * sizeof(uint64_t);
    } else {
      memcpy(&value, p, length);
      length = 0;
    }
    int i;
    for (i = 0; i < 4; i++) {
      hash[i] += value[i] + 2 * hash[i] * value[i];
      hash[i] ^= hash[i] >> 32;
    }
  }
  return hash[0] ^ hash[1] ^ hash[2] ^ hash[3];
}
```
user: What is the c source code of the assembly code below:

```asm
<gets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L15:
  mov    $0x0,%eax
  call   <getc@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0xa,-0x5(%rbp)
  jne    L12
  movb   $0x0,-0x5(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  cmpb   $0x0,-0x5(%rbp)
  jne    L15
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  leave
  ret
```

assistant: ```c
int gets(unsigned char *buf) {
  int i = 0;
  unsigned char c;
  do {
    c = getc();
    if (c == '\n')
      c = '\0';
    buf[i++] = c;
  } while (c);
  return i - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gets>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L8:
  mov    %ebx,%r12d
  mov    $0x0,%eax
  call   <getc@plt>
  cmp    $0xa,%al
  je     L27
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  test   %al,%al
  jne    L8
  jmp    L4
L27:
  movslq %ebx,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
L4:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int gets(unsigned char *buf) {
  int i = 0;
  unsigned char c;
  do {
    c = getc();
    if (c == '\n')
      c = '\0';
    buf[i++] = c;
  } while (c);
  return i - 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gets>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  cmp    $0xa,%al
  je     L23
L3:
  mov    %al,(%rbx)
  lea    0x1(%r12),%edx
  add    $0x1,%rbx
  test   %al,%al
  je     L14
  xor    %eax,%eax
  mov    %edx,%r12d
  call   <getc@plt>
  cmp    $0xa,%al
  jne    L3
L23:
  movb   $0x0,(%rbx)
L14:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int gets(unsigned char *buf) {
  int i = 0;
  unsigned char c;
  do {
    c = getc();
    if (c == '\n')
      c = '\0';
    buf[i++] = c;
  } while (c);
  return i - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gets>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  cmp    $0xa,%al
  je     L0
L19:
  mov    %al,(%rbx)
  lea    0x1(%r12),%edx
  add    $0x1,%rbx
  test   %al,%al
  je     L13
  xor    %eax,%eax
  mov    %edx,%r12d
  call   <getc@plt>
  cmp    $0xa,%al
  jne    L19
L0:
  movb   $0x0,(%rbx)
L13:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int gets(unsigned char *buf) {
  int i = 0;
  unsigned char c;
  do {
    c = getc();
    if (c == '\n')
      c = '\0';
    buf[i++] = c;
  } while (c);
  return i - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x3,-0x28(%rbp)
  jmp    L62
L40:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L14
L48:
  mov    -0x20(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    %rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x20(%rbp)
L14:
  mov    -0x20(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    %rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x2,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  je     L48
  jmp    L1
L6:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x20(%rbp)
L1:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L6
  mov    -0x20(%rbp),%rax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <MultOrd@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jle    L43
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L43:
  addq   $0x1,-0x28(%rbp)
L62:
  cmpq   $0x3e7,-0x28(%rbp)
  jle    L40
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3dd,%esi
  mov    $0xa,%edi
  call   <MultOrd@plt>
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D28
type_infered: string

tool: D9: %ld	%ld


tool: D28: %ld


assistant: ```c
int main() {
  long int i, j, currlen, currid, templen;
  currlen = 0;
  currid = 0;
  for (i = 3; i < 1000; i++) {
    j = i;
    while (!(j % 5))
      j /= 5;
    while (!(j % 2))
      j /= 2;
    templen = MultOrd(10, j);
    if (templen > currlen) {
      currlen = templen;
      currid = i;
      printf("%ld\t%ld\n", currlen, currid);
    }
  }
  printf("%ld\n", currid);
  printf("%ld\n", MultOrd(10, 989));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x3,%ebp
  mov    $0x3,%esi
  lea    D12(%rip),%r14
  movabs $0x6666666666666667,%rbx
  jmp    L2
L71:
  add    $0x1,%rbp
  cmp    $0x3e8,%rbp
  je     L37
  mov    %rbp,%rax
  imul   %rbx
  sar    %rdx
  mov    %rbp,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rbp,%rsi
  cmp    %rax,%rbp
  jne    L2
L73:
  mov    %rsi,%rax
  imul   %rbx
  sar    %rdx
  sar    $0x3f,%rsi
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  mov    %rcx,%rsi
  mov    %rcx,%rax
  imul   %rbx
  sar    %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  cmp    %rax,%rcx
  je     L73
L2:
  test   $0x1,%sil
  jne    L58
L77:
  mov    %rsi,%rdx
  shr    $0x3f,%rdx
  add    %rsi,%rdx
  sar    %rdx
  mov    %rdx,%rsi
  test   $0x1,%dl
  je     L77
L58:
  mov    $0xa,%edi
  call   <MultOrd@plt>
  mov    %rax,%r15
  cmp    %rax,%r12
  jge    L71
  mov    %rbp,%rdx
  mov    %rax,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%r13
  mov    %r15,%r12
  jmp    L71
L37:
  mov    %r13,%rsi
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3dd,%esi
  mov    $0xa,%edi
  call   <MultOrd@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D10
data_type: string

tool: D12: %ld	%ld


tool: D10: %ld


assistant: ```c
int main() {
  long int i, j, currlen, currid, templen;
  currlen = 0;
  currid = 0;
  for (i = 3; i < 1000; i++) {
    j = i;
    while (!(j % 5))
      j /= 5;
    while (!(j % 2))
      j /= 2;
    templen = MultOrd(10, j);
    if (templen > currlen) {
      currlen = templen;
      currid = i;
      printf("%ld\t%ld\n", currlen, currid);
    }
  }
  printf("%ld\n", currid);
  printf("%ld\n", MultOrd(10, 989));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x3,%edx
  mov    $0x3,%r15d
  push   %r14
  movabs $0x3333333333333333,%r14
  push   %r13
  movabs $0xcccccccccccccccd,%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  movq   $0x0,0x8(%rsp)
  jmp    L3
  nopl   (%rax)
L2:
  sar    %rdx
L3:
  test   $0x1,%dl
  je     L2
  mov    %edx,%esi
  mov    $0xa,%edi
  call   <MultOrd@plt>
  mov    %rax,%rbp
  cmp    %rbx,%rax
  jg     L79
  add    $0x1,%r15
  cmp    $0x3e8,%r15
  je     L28
L16:
  mov    %r15,%rax
  mov    %r15,%rdx
  imul   %r13,%rax
  cmp    %r14,%rax
  ja     L3
L67:
  mov    %rdx,%rax
  mul    %r13
  shr    $0x2,%rdx
  mov    %rdx,%rax
  imul   %r13,%rax
  cmp    %r14,%rax
  jbe    L67
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L79:
  mov    %r15,%rdx
  mov    %rax,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15,0x8(%rsp)
  add    $0x1,%r15
  mov    %rbp,%rbx
  cmp    $0x3e8,%r15
  jne    L16
L28:
  mov    0x8(%rsp),%rsi
  lea    D13(%rip),%rbp
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x3dd,%esi
  mov    $0xa,%edi
  call   <MultOrd@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D13
datatype: string

tool: D2: %ld	%ld


tool: D13: %ld


assistant: ```c
int main() {
  long int i, j, currlen, currid, templen;
  currlen = 0;
  currid = 0;
  for (i = 3; i < 1000; i++) {
    j = i;
    while (!(j % 5))
      j /= 5;
    while (!(j % 2))
      j /= 2;
    templen = MultOrd(10, j);
    if (templen > currlen) {
      currlen = templen;
      currid = i;
      printf("%ld\t%ld\n", currlen, currid);
    }
  }
  printf("%ld\n", currid);
  printf("%ld\n", MultOrd(10, 989));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x3,%edx
  mov    $0x3,%r15d
  push   %r14
  movabs $0x3333333333333333,%r14
  push   %r13
  movabs $0xcccccccccccccccd,%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  movq   $0x0,0x8(%rsp)
  jmp    L35
  nopl   (%rax)
L29:
  sar    %rdx
L35:
  test   $0x1,%dl
  je     L29
  mov    %edx,%esi
  mov    $0xa,%edi
  call   <MultOrd@plt>
  mov    %rax,%rbp
  cmp    %rbx,%rax
  jg     L77
  add    $0x1,%r15
  cmp    $0x3e8,%r15
  je     L15
L14:
  mov    %r15,%rax
  mov    %r15,%rdx
  imul   %r13,%rax
  cmp    %r14,%rax
  ja     L35
L79:
  mov    %rdx,%rax
  mul    %r13
  shr    $0x2,%rdx
  mov    %rdx,%rax
  imul   %r13,%rax
  cmp    %r14,%rax
  jbe    L79
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %r15,%rdx
  mov    %rax,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15,0x8(%rsp)
  add    $0x1,%r15
  mov    %rbp,%rbx
  cmp    $0x3e8,%r15
  jne    L14
L15:
  mov    0x8(%rsp),%rsi
  lea    D14(%rip),%rbp
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x3dd,%esi
  mov    $0xa,%edi
  call   <MultOrd@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string

tool: D7: %ld	%ld


tool: D14: %ld


assistant: ```c
int main() {
  long int i, j, currlen, currid, templen;
  currlen = 0;
  currid = 0;
  for (i = 3; i < 1000; i++) {
    j = i;
    while (!(j % 5))
      j /= 5;
    while (!(j % 2))
      j /= 2;
    templen = MultOrd(10, j);
    if (templen > currlen) {
      currlen = templen;
      currid = i;
      printf("%ld\t%ld\n", currlen, currid);
    }
  }
  printf("%ld\n", currid);
  printf("%ld\n", MultOrd(10, 989));
  return 0;
}
```