ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<cross>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross(const double *x, const double *y, double *z) {
  z[0] = x[1] * y[2] - x[2] * y[1];
  z[1] = x[2] * y[0] - x[0] * y[2];
  z[2] = x[0] * y[1] - x[1] * y[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mymemcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L0
L14:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mymemcpy(void *dst, const void *src, size_t n) {
  size_t i;
  unsigned char *d = (unsigned char *)dst;
  unsigned char *s = (unsigned char *)src;
  for (i = 0; i < n; ++i) {
    *d++ = *s++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mymemcpy>:
  endbr64
  test   %rdx,%rdx
  je     L7
  mov    $0x0,%eax
L6:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L6
L7:
  ret
```

assistant: ```c
void mymemcpy(void *dst, const void *src, size_t n) {
  size_t i;
  unsigned char *d = (unsigned char *)dst;
  unsigned char *s = (unsigned char *)src;
  for (i = 0; i < n; ++i) {
    *d++ = *s++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mymemcpy>:
  endbr64
  test   %rdx,%rdx
  je     L16
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L4
L16:
  ret
```

assistant: ```c
void mymemcpy(void *dst, const void *src, size_t n) {
  size_t i;
  unsigned char *d = (unsigned char *)dst;
  unsigned char *s = (unsigned char *)src;
  for (i = 0; i < n; ++i) {
    *d++ = *s++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mymemcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %rdx,%rdx
  je     L28
  lea    0x1(%rsi),%r8
  lea    -0x1(%rdx),%rax
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L81
  cmp    $0x6,%rax
  jbe    L81
  cmp    $0xe,%rax
  jbe    L59
  mov    %rdx,%rdi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rdi
  nopw   0x0(%rax,%rax,1)
L75:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L75
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  lea    (%rcx,%rax,1),%rdi
  lea    (%rsi,%rax,1),%r8
  cmp    %rax,%rdx
  je     L28
  mov    %rdx,%r9
  sub    %rax,%r9
  lea    -0x1(%r9),%r10
  cmp    $0x6,%r10
  jbe    L33
L0:
  mov    (%rsi,%rax,1),%rsi
  mov    %rsi,(%rcx,%rax,1)
  mov    %r9,%rcx
  and    $0xfffffffffffffff8,%rcx
  add    %rcx,%rax
  add    %rcx,%rdi
  add    %rcx,%r8
  cmp    %rcx,%r9
  je     L28
L33:
  movzbl (%r8),%ecx
  mov    %cl,(%rdi)
  lea    0x1(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L28
  movzbl 0x1(%r8),%ecx
  mov    %cl,0x1(%rdi)
  lea    0x2(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L28
  movzbl 0x2(%r8),%ecx
  mov    %cl,0x2(%rdi)
  lea    0x3(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L28
  movzbl 0x3(%r8),%ecx
  mov    %cl,0x3(%rdi)
  lea    0x4(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L28
  movzbl 0x4(%r8),%ecx
  mov    %cl,0x4(%rdi)
  lea    0x5(%rax),%rcx
  cmp    %rcx,%rdx
  jbe    L28
  movzbl 0x5(%r8),%ecx
  add    $0x6,%rax
  mov    %cl,0x5(%rdi)
  cmp    %rax,%rdx
  jbe    L28
  movzbl 0x6(%r8),%eax
  mov    %al,0x6(%rdi)
  ret
L81:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L46:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L46
L28:
  ret
L59:
  mov    %rdx,%r9
  mov    %rsi,%r8
  mov    %rcx,%rdi
  xor    %eax,%eax
  jmp    L0
```

assistant: ```c
void mymemcpy(void *dst, const void *src, size_t n) {
  size_t i;
  unsigned char *d = (unsigned char *)dst;
  unsigned char *s = (unsigned char *)src;
  for (i = 0; i < n; ++i) {
    *d++ = *s++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <udpsock_create@plt>
  mov    %eax,-0x7c(%rbp)
  movabs $0x756d206f6c6c6568,%rax
  movabs $0x217473616369746c,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rdx
  lea    -0x70(%rbp),%rsi
  mov    -0x7c(%rbp),%eax
  mov    $0xd05,%r8d
  lea    D0(%rip),%rcx
  mov    %eax,%edi
  call   <sock_sendto@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: 224.25.25.25

assistant: ```c
int main(int argc, char *argv[]) {
  int sfd;
  size_t buf_len;
  sfd = udpsock_create();
  char buf[100] = "hello multicast!";
  buf_len = strlen(buf);
  sock_sendto(sfd, buf, buf_len, "224.25.25.25", 3333);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <udpsock_create@plt>
  mov    %eax,%ebx
  movabs $0x756d206f6c6c6568,%rax
  movabs $0x217473616369746c,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0xd05,%r8d
  lea    D4(%rip),%rcx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <sock_sendto@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string

tool: D4: 224.25.25.25

assistant: ```c
int main(int argc, char *argv[]) {
  int sfd;
  size_t buf_len;
  sfd = udpsock_create();
  char buf[100] = "hello multicast!";
  buf_len = strlen(buf);
  sock_sendto(sfd, buf, buf_len, "224.25.25.25", 3333);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <udpsock_create@plt>
  movdqa D12(%rip),%xmm0
  mov    %rsp,%rsi
  mov    $0xd05,%r8d
  mov    %eax,%edi
  lea    D19(%rip),%rcx
  mov    $0x10,%edx
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <sock_sendto@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_infered: byte[16]
name: extract_symbolic_data
arguments: label: D19
type_infered: string

tool: {"D12": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x6d,0x75,0x6c,0x74,0x69,0x63,0x61,0x73,0x74,0x21]}

tool: D19: 224.25.25.25

assistant: ```c
int main(int argc, char *argv[]) {
  int sfd;
  size_t buf_len;
  sfd = udpsock_create();
  char buf[100] = "hello multicast!";
  buf_len = strlen(buf);
  sock_sendto(sfd, buf, buf_len, "224.25.25.25", 3333);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <udpsock_create@plt>
  movdqa D6(%rip),%xmm0
  mov    %rsp,%rsi
  mov    $0xd05,%r8d
  mov    %eax,%edi
  lea    D1(%rip),%rcx
  mov    $0x10,%edx
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <sock_sendto@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: byte[16]
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: {"D6": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x6d,0x75,0x6c,0x74,0x69,0x63,0x61,0x73,0x74,0x21]}

tool: D1: 224.25.25.25

assistant: ```c
int main(int argc, char *argv[]) {
  int sfd;
  size_t buf_len;
  sfd = udpsock_create();
  char buf[100] = "hello multicast!";
  buf_len = strlen(buf);
  sock_sendto(sfd, buf, buf_len, "224.25.25.25", 3333);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<eb_trim_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <evbuffer_get_length@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jbe    L18
L14:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <evbuffer_readln@plt>
  mov    %eax,%edi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <evbuffer_get_length@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jbe    L10
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L14
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jbe    L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <evbuffer_get_contiguous_space@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x20,%edx
  cmp    %edx,%eax
  cmovge %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <evbuffer_drain@plt>
  jmp    L18
L17:
  nop
L18:
  leave
  ret
```

assistant: ```c
void eb_trim_cb(struct evbuffer *b, const struct evbuffer_cb_info *i, void *_ts) {
  if (i->n_added == 0)
    return;
  int len = evbuffer_get_length(b);
  if (len > ((size_t)_ts)) {
    int len2;
    do {
      free(evbuffer_readln(b, NULL, EVBUFFER_EOL_CRLF));
      len2 = evbuffer_get_length(b);
    } while ((len2 > ((size_t)_ts)) && (len != len2));
    if (len2 > ((size_t)_ts)) {
      int firstchunk = evbuffer_get_contiguous_space(b);
      evbuffer_drain(b, firstchunk < 32 ? 32 : firstchunk);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eb_trim_cb>:
  endbr64
  cmpq   $0x0,(%rsi)
  jne    L2
  ret
L2:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  call   <evbuffer_get_length@plt>
  mov    %eax,%r12d
  cltq
  cmp    %rbp,%rax
  jbe    L28
  mov    D8(%rip),%r13
L18:
  mov    0x0(%r13),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <evbuffer_readln@plt>
  mov    %eax,%edi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <evbuffer_get_length@plt>
  movslq %eax,%rdx
  cmp    %eax,%r12d
  je     L50
  cmp    %rdx,%rbp
  jb     L18
L50:
  cmp    %rdx,%rbp
  jb     L23
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  mov    %rbx,%rdi
  call   <evbuffer_get_contiguous_space@plt>
  mov    $0x20,%edx
  cmp    %edx,%eax
  mov    %edx,%esi
  cmovge %eax,%esi
  mov    %rbx,%rdi
  call   <evbuffer_drain@plt>
  jmp    L28
```

assistant: ```c
void eb_trim_cb(struct evbuffer *b, const struct evbuffer_cb_info *i, void *_ts) {
  if (i->n_added == 0)
    return;
  int len = evbuffer_get_length(b);
  if (len > ((size_t)_ts)) {
    int len2;
    do {
      free(evbuffer_readln(b, NULL, EVBUFFER_EOL_CRLF));
      len2 = evbuffer_get_length(b);
    } while ((len2 > ((size_t)_ts)) && (len != len2));
    if (len2 > ((size_t)_ts)) {
      int firstchunk = evbuffer_get_contiguous_space(b);
      evbuffer_drain(b, firstchunk < 32 ? 32 : firstchunk);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<eb_trim_cb>:
  endbr64
  cmpq   $0x0,(%rsi)
  jne    L40
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <evbuffer_get_length@plt>
  mov    %eax,%ebp
  cltq
  cmp    %rbx,%rax
  jbe    L42
  mov    D7(%rip),%r12
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L8:
  cmp    %rdx,%rbx
  jae    L42
L30:
  mov    (%r12),%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <evbuffer_readln@plt>
  mov    %eax,%edi
  call   <free@plt>
  mov    %r13,%rdi
  call   <evbuffer_get_length@plt>
  movslq %eax,%rdx
  cmp    %eax,%ebp
  jne    L8
  cmp    %rdx,%rbx
  jae    L42
  mov    %r13,%rdi
  call   <evbuffer_get_contiguous_space@plt>
  mov    $0x20,%edx
  mov    %r13,%rdi
  cmp    %edx,%eax
  mov    %edx,%esi
  cmovge %eax,%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <evbuffer_drain@plt>
  nopl   0x0(%rax)
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void eb_trim_cb(struct evbuffer *b, const struct evbuffer_cb_info *i, void *_ts) {
  if (i->n_added == 0)
    return;
  int len = evbuffer_get_length(b);
  if (len > ((size_t)_ts)) {
    int len2;
    do {
      free(evbuffer_readln(b, NULL, EVBUFFER_EOL_CRLF));
      len2 = evbuffer_get_length(b);
    } while ((len2 > ((size_t)_ts)) && (len != len2));
    if (len2 > ((size_t)_ts)) {
      int firstchunk = evbuffer_get_contiguous_space(b);
      evbuffer_drain(b, firstchunk < 32 ? 32 : firstchunk);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eb_trim_cb>:
  endbr64
  cmpq   $0x0,(%rsi)
  jne    L41
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <evbuffer_get_length@plt>
  mov    %eax,%ebp
  cltq
  cmp    %rbx,%rax
  jbe    L36
  mov    D6(%rip),%r12
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L38:
  cmp    %rdx,%rbx
  jae    L36
L40:
  mov    (%r12),%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <evbuffer_readln@plt>
  mov    %eax,%edi
  call   <free@plt>
  mov    %r13,%rdi
  call   <evbuffer_get_length@plt>
  movslq %eax,%rdx
  cmp    %eax,%ebp
  jne    L38
  cmp    %rdx,%rbx
  jae    L36
  mov    %r13,%rdi
  call   <evbuffer_get_contiguous_space@plt>
  mov    $0x20,%edx
  mov    %r13,%rdi
  cmp    %edx,%eax
  mov    %edx,%esi
  cmovge %eax,%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <evbuffer_drain@plt>
  nopl   0x0(%rax)
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void eb_trim_cb(struct evbuffer *b, const struct evbuffer_cb_info *i, void *_ts) {
  if (i->n_added == 0)
    return;
  int len = evbuffer_get_length(b);
  if (len > ((size_t)_ts)) {
    int len2;
    do {
      free(evbuffer_readln(b, NULL, EVBUFFER_EOL_CRLF));
      len2 = evbuffer_get_length(b);
    } while ((len2 > ((size_t)_ts)) && (len != len2));
    if (len2 > ((size_t)_ts)) {
      int firstchunk = evbuffer_get_contiguous_space(b);
      evbuffer_drain(b, firstchunk < 32 ? 32 : firstchunk);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<devideByFive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L18
L1:
  mov    -0xc(%rbp),%edx
  mov    %edx,%ecx
  mov    $0xcccccccd,%eax
  imul   %rcx,%rax
  shr    $0x20,%rax
  mov    %eax,%ecx
  shr    $0x2,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x5,%eax
  cmp    %eax,-0xc(%rbp)
  ja     L4
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L4:
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jbe    L1
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D23
type: string

tool: D6: %u

tool: D0: , 

tool: D23: 
There is only %u numbers.

assistant: ```c
void devideByFive(int A, int B) {
  unsigned int i, remainder, p = 0;
  for (i = A; i <= B; i++) {
    if ((remainder = i % 5) == 0) {
      printf("%u", i);
      ++p;
      if (i <= B - 5) {
        printf(", ");
      }
    }
  }
  printf("\nThere is only %u numbers.", p);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<devideByFive>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  ja     L2
  mov    %esi,%ebp
  mov    %edi,%ebx
  mov    $0x0,%r13d
  mov    $0xcccccccd,%r12d
  lea    D29(%rip),%r15
  lea    -0x5(%rsi),%r14d
  jmp    L47
L20:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  ja     L35
L47:
  mov    %ebx,%eax
  imul   %r12,%rax
  shr    $0x22,%rax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  jne    L20
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r13d
  cmp    %ebx,%r14d
  jb     L20
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L2:
  mov    $0x0,%r13d
L35:
  mov    %r13d,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D28
type_guessed: string

tool: D29: %u

tool: D14: , 

tool: D28: 
There is only %u numbers.

assistant: ```c
void devideByFive(int A, int B) {
  unsigned int i, remainder, p = 0;
  for (i = A; i <= B; i++) {
    if ((remainder = i % 5) == 0) {
      printf("%u", i);
      ++p;
      if (i <= B - 5) {
        printf(", ");
      }
    }
  }
  printf("\nThere is only %u numbers.", p);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<devideByFive>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  ja     L3
  mov    %esi,%ebp
  mov    %edi,%ebx
  lea    D21(%rip),%r13
  xor    %r15d,%r15d
  lea    -0x5(%rsi),%r12d
  lea    D27(%rip),%r14
  jmp    L69
  nopl   (%rax)
L12:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  ja     L62
L69:
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L12
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebx,%r12d
  jb     L12
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jbe    L69
L62:
  add    $0x8,%rsp
  mov    %r15d,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L3:
  xor    %r15d,%r15d
  jmp    L62
```

tool_calls: name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D27
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string

tool: D21: %u

tool: D27: , 

tool: D18: 
There is only %u numbers.

assistant: ```c
void devideByFive(int A, int B) {
  unsigned int i, remainder, p = 0;
  for (i = A; i <= B; i++) {
    if ((remainder = i % 5) == 0) {
      printf("%u", i);
      ++p;
      if (i <= B - 5) {
        printf(", ");
      }
    }
  }
  printf("\nThere is only %u numbers.", p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<devideByFive>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  ja     L53
  mov    %esi,%ebp
  mov    %edi,%ebx
  lea    D7(%rip),%r13
  xor    %r15d,%r15d
  lea    -0x5(%rsi),%r12d
  lea    D6(%rip),%r14
  jmp    L64
  nopl   (%rax)
L63:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  ja     L6
L64:
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L63
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebx,%r12d
  jb     L63
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jbe    L64
L6:
  add    $0x8,%rsp
  mov    %r15d,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L53:
  xor    %r15d,%r15d
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D6
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D7: %u

tool: D6: , 

tool: D4: 
There is only %u numbers.

assistant: ```c
void devideByFive(int A, int B) {
  unsigned int i, remainder, p = 0;
  for (i = A; i <= B; i++) {
    if ((remainder = i % 5) == 0) {
      printf("%u", i);
      ++p;
      if (i <= B - 5) {
        printf(", ");
      }
    }
  }
  printf("\nThere is only %u numbers.", p);
}
```