user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x3,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L22
L7:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L22:
  cmpl   $0x2,-0x14(%rbp)
  jle    L7
  mov    $0x0,%eax
  call   <getchar@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L76
L4:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L76:
  cmpl   $0x2,-0x14(%rbp)
  jle    L4
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L30
L20:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  mov    -0x14(%rbp),%edx
  add    $0x1,%edx
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L30:
  cmpl   $0x2,-0x14(%rbp)
  jle    L20
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L44
L43:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  mov    -0x14(%rbp),%edx
  add    $0x1,%edx
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L44:
  cmpl   $0x2,-0x14(%rbp)
  jle    L43
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type_guessed: string
name: extract_symbolic_data
arguments: label: D33
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string
name: extract_symbolic_data
arguments: label: D56
type_guessed: string
name: extract_symbolic_data
arguments: label: D42
type_guessed: string

tool: D24: Please input %d floats for 'arr1':


tool: D33: %f

tool: D8: Arr1:

tool: D56: pos %d: %.3f


tool: D42: Arr2:

assistant: ```c
int main() {
  int i;
  float *arr1, *arr2;
  arr1 = (float *)malloc(3 * sizeof(float));
  arr2 = (float *)malloc(3 * sizeof(float));
  printf("Please input %d floats for 'arr1':\n", 3);
  for (i = 0; i < 3; i++) {
    scanf("%f", arr1 + i);
  }
  getchar();
  for (i = 0; i < 3; i++) {
    *(arr2 + i) = *(arr1 + i);
  }
  printf("Arr1:\n");
  for (i = 0; i < 3; i++) {
    printf("pos %d: %.3f\n", i + 1, arr1[i]);
  }
  printf("Arr2:\n");
  for (i = 0; i < 3; i++) {
    printf("pos %d: %.3f\n", i + 1, arr2[i]);
  }
  free(arr1);
  free(arr2);
  return 0;
}
```