ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<quaddobl_deflate>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xfa,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int quaddobl_deflate(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(250, a, b, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movw   $0x2,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  and    $0xfff80000,%eax
  or     $0x3,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  je     L38
  mov    $0x1,%eax
  jmp    L1
L38:
  lea    -0x14(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    $0x3,%eax
  je     L16
  mov    $0x2,%eax
  jmp    L1
L16:
  lea    -0x14(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    $0x4,%eax
  je     L66
  mov    $0x3,%eax
  jmp    L1
L66:
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
main() {
  struct {
    int a : 16;
    int b : 19;
    int c;
  } s;
  memset(&s, 0, sizeof s);
  s.a = 2;
  s.b = 3;
  s.c = 4;
  if (sizeof(s) != 3 * sizeof(int))
    return 4;
  if (0 [(int *)&s] != 2)
    return 1;
  if (1 [(int *)&s] != 3)
    return 2;
  if (2 [(int *)&s] != 4)
    return 3;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  struct {
    int a : 16;
    int b : 19;
    int c;
  } s;
  memset(&s, 0, sizeof s);
  s.a = 2;
  s.b = 3;
  s.c = 4;
  if (sizeof(s) != 3 * sizeof(int))
    return 4;
  if (0 [(int *)&s] != 2)
    return 1;
  if (1 [(int *)&s] != 3)
    return 2;
  if (2 [(int *)&s] != 4)
    return 3;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  struct {
    int a : 16;
    int b : 19;
    int c;
  } s;
  memset(&s, 0, sizeof s);
  s.a = 2;
  s.b = 3;
  s.c = 4;
  if (sizeof(s) != 3 * sizeof(int))
    return 4;
  if (0 [(int *)&s] != 2)
    return 1;
  if (1 [(int *)&s] != 3)
    return 2;
  if (2 [(int *)&s] != 4)
    return 3;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  struct {
    int a : 16;
    int b : 19;
    int c;
  } s;
  memset(&s, 0, sizeof s);
  s.a = 2;
  s.b = 3;
  s.c = 4;
  if (sizeof(s) != 3 * sizeof(int))
    return 4;
  if (0 [(int *)&s] != 2)
    return 1;
  if (1 [(int *)&s] != 3)
    return 2;
  if (2 [(int *)&s] != 4)
    return 3;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x64,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L0:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  sub    $0x4,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L1
  mov    $0x0,%eax
  call   <remove_me@plt>
L1:
  addl   $0x1,-0xc(%rbp)
  addl   $0x5,-0x8(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L0
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int a, b;
  int N = 100;
  a = 0;
  b = 0;
  while (a < N) {
    if (b >= 5 * N - 4)
      remove_me();
    a++;
    b += 5;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L16:
  add    $0x5,%ebx
  cmp    $0x1f4,%ebx
  je     L24
  cmp    $0x1ef,%ebx
  jle    L16
  mov    $0x0,%eax
  call   <remove_me@plt>
  jmp    L16
L24:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int a, b;
  int N = 100;
  a = 0;
  b = 0;
  while (a < N) {
    if (b >= 5 * N - 4)
      remove_me();
    a++;
    b += 5;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  jmp    L14
  nopl   0x0(%rax)
L25:
  cmp    $0x1ef,%ebx
  jg     L2
L14:
  add    $0x5,%ebx
  cmp    $0x1f4,%ebx
  jne    L25
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  xor    %eax,%eax
  call   <remove_me@plt>
  jmp    L14
```

assistant: ```c
int main(void) {
  int a, b;
  int N = 100;
  a = 0;
  b = 0;
  while (a < N) {
    if (b >= 5 * N - 4)
      remove_me();
    a++;
    b += 5;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a, b;
  int N = 100;
  a = 0;
  b = 0;
  while (a < N) {
    if (b >= 5 * N - 4)
      remove_me();
    a++;
    b += 5;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n << m;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n << m;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n << m;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n << m;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_max>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%esi
  je     L52
  mov    %esi,%r13d
  cmp    $0x3,%esi
  je     L33
  movl   $0x0,0x18(%rsp)
  test   %esi,%esi
  jle    L49
  mov    0x8(%rsp),%r15
  mov    $0x0,%r12d
  lea    0x20(%rsp),%rax
  mov    %rax,0x10(%rsp)
  jmp    L11
L52:
  mov    0x4(%rdi),%eax
  mov    %eax,0x18(%rsp)
L49:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  mov    0x18(%rsp),%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  mov    0x8(%rsp),%rdi
  mov    0x8(%rdi),%eax
  mov    0x4(%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  mov    0x34(%rdi),%edx
  cmp    %edx,%eax
  cmovge %eax,%edx
  mov    %edx,0x18(%rsp)
  jmp    L49
L41:
  add    $0x1,%rbx
L89:
  mov    %ebx,%esi
  cmp    %rbx,%r14
  je     L75
  cmp    %ebx,%ebp
  jge    L41
  mov    0x10(%rsp),%r8
  mov    0x8(%rsp),%rcx
  mov    %r13d,%edx
  mov    %r12d,%edi
  call   <delete_com@plt>
  mov    (%rsp),%rax
  mov    (%rax,%rbx,4),%eax
  mov    %eax,0x1c(%rsp)
  lea    -0x2(%r13),%esi
  mov    0x10(%rsp),%rdi
  call   <get_max>
  add    0x1c(%rsp),%eax
  mov    0x18(%rsp),%ecx
  cmp    %eax,%ecx
  cmovge %ecx,%eax
  mov    %eax,0x18(%rsp)
  jmp    L41
L75:
  add    $0x1,%r12d
  add    $0x2c,%r15
  cmp    %r12d,%r13d
  je     L49
L11:
  mov    %r15,(%rsp)
  mov    %r13d,%r14d
  mov    $0x1,%ebx
  test   %r12d,%r12d
  mov    $0x0,%ebp
  cmovns %r12d,%ebp
  jmp    L89
L83:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_max(int comb[11][11], int goods_num) {
  int i = 0;
  int j = 0;
  int x = 0;
  int y = 0;
  int temp_comb[11][11];
  int temp_max = 0;
  int max_price = 0;
  if (goods_num == 2)
    return comb[0][1];
  if (goods_num == 3) {
    temp_max = comb[0][1];
    if (temp_max < comb[0][2])
      temp_max = comb[0][2];
    if (temp_max < comb[1][2])
      temp_max = comb[1][2];
    return temp_max;
  }
  for (i = 0; i < goods_num; i++) {
    for (j = 0; j < goods_num; j++) {
      if ((j > 0) && (i != j) && (i < j)) {
        delete_com(i, j, goods_num, comb, temp_comb);
        temp_max = comb[i][j] + get_max(temp_comb, goods_num - 2);
        max_price = max_price > temp_max ? max_price : temp_max;
      }
    }
  }
  return max_price;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_max>:
  endbr64
  push   %r15
  mov    %rdi,%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%esi
  je     L9
  mov    %esi,%r12d
  cmp    $0x3,%esi
  je     L38
  xor    %r10d,%r10d
  test   %esi,%esi
  jle    L41
  mov    %rdi,%r15
  xor    %ebp,%ebp
  lea    0x20(%rsp),%r8
  movslq %esi,%r13
L106:
  mov    $0x1,%ebx
  mov    %ebx,%esi
  cmp    %rbx,%r13
  je     L15
L19:
  cmp    %ebx,%ebp
  jl     L54
L25:
  add    $0x1,%rbx
  mov    %ebx,%esi
  cmp    %rbx,%r13
  jne    L19
L15:
  add    $0x1,%ebp
  add    $0x2c,%r15
  cmp    %ebp,%r12d
  jne    L106
L41:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x218,%rsp
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    %r10d,0x1c(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %rcx,0x10(%rsp)
  call   <delete_com@plt>
  mov    0x8(%rsp),%rdi
  mov    (%r15,%rbx,4),%r14d
  lea    -0x2(%r12),%esi
  call   <get_max>
  mov    0x1c(%rsp),%r10d
  mov    0x10(%rsp),%rcx
  add    %eax,%r14d
  mov    0x8(%rsp),%r8
  cmp    %r14d,%r10d
  cmovl  %r14d,%r10d
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x4(%rdi),%r10d
  jmp    L41
  nopl   0x0(%rax)
L38:
  mov    0x4(%rdi),%eax
  mov    0x8(%rdi),%r10d
  cmp    %eax,%r10d
  cmovl  %eax,%r10d
  mov    0x34(%rdi),%eax
  cmp    %eax,%r10d
  cmovl  %eax,%r10d
  jmp    L41
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_max(int comb[11][11], int goods_num) {
  int i = 0;
  int j = 0;
  int x = 0;
  int y = 0;
  int temp_comb[11][11];
  int temp_max = 0;
  int max_price = 0;
  if (goods_num == 2)
    return comb[0][1];
  if (goods_num == 3) {
    temp_max = comb[0][1];
    if (temp_max < comb[0][2])
      temp_max = comb[0][2];
    if (temp_max < comb[1][2])
      temp_max = comb[1][2];
    return temp_max;
  }
  for (i = 0; i < goods_num; i++) {
    for (j = 0; j < goods_num; j++) {
      if ((j > 0) && (i != j) && (i < j)) {
        delete_com(i, j, goods_num, comb, temp_comb);
        temp_max = comb[i][j] + get_max(temp_comb, goods_num - 2);
        max_price = max_price > temp_max ? max_price : temp_max;
      }
    }
  }
  return max_price;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_max>:
  endbr64
  push   %r15
  mov    %rdi,%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%esi
  je     L0
  mov    %esi,%r12d
  cmp    $0x3,%esi
  je     L67
  xor    %r10d,%r10d
  test   %esi,%esi
  jle    L41
  lea    -0x2(%rsi),%eax
  mov    %rdi,%r15
  xor    %ebp,%ebp
  movslq %esi,%r13
  mov    %eax,0x1c(%rsp)
  lea    0x20(%rsp),%r8
L98:
  mov    $0x1,%ebx
  cmp    $0x1,%r12d
  je     L105
L50:
  mov    %ebx,%esi
  cmp    %ebx,%ebp
  jl     L15
L4:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L50
L105:
  add    $0x1,%ebp
  add    $0x2c,%r15
  cmp    %ebp,%r12d
  jne    L98
L41:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  add    $0x218,%rsp
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L15:
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    %r10d,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %rcx,0x10(%rsp)
  call   <delete_com@plt>
  mov    0x1c(%rsp),%esi
  mov    0x8(%rsp),%rdi
  mov    (%r15,%rbx,4),%r14d
  call   <get_max>
  mov    0x18(%rsp),%r10d
  mov    0x10(%rsp),%rcx
  add    %eax,%r14d
  mov    0x8(%rsp),%r8
  cmp    %r14d,%r10d
  cmovl  %r14d,%r10d
  jmp    L4
  nopl   0x0(%rax)
L0:
  mov    0x4(%rdi),%r10d
  jmp    L41
  nopl   0x0(%rax)
L67:
  mov    0x4(%rdi),%eax
  mov    0x8(%rdi),%r10d
  cmp    %eax,%r10d
  cmovl  %eax,%r10d
  mov    0x34(%rdi),%eax
  cmp    %eax,%r10d
  cmovl  %eax,%r10d
  jmp    L41
L97:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_max(int comb[11][11], int goods_num) {
  int i = 0;
  int j = 0;
  int x = 0;
  int y = 0;
  int temp_comb[11][11];
  int temp_max = 0;
  int max_price = 0;
  if (goods_num == 2)
    return comb[0][1];
  if (goods_num == 3) {
    temp_max = comb[0][1];
    if (temp_max < comb[0][2])
      temp_max = comb[0][2];
    if (temp_max < comb[1][2])
      temp_max = comb[1][2];
    return temp_max;
  }
  for (i = 0; i < goods_num; i++) {
    for (j = 0; j < goods_num; j++) {
      if ((j > 0) && (i != j) && (i < j)) {
        delete_com(i, j, goods_num, comb, temp_comb);
        temp_max = comb[i][j] + get_max(temp_comb, goods_num - 2);
        max_price = max_price > temp_max ? max_price : temp_max;
      }
    }
  }
  return max_price;
}
```
user: What is the c source code of the assembly code below?

```asm
<hashes_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L28
  mov    $0x0,%eax
  jmp    L2
L28:
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L29
  mov    $0x1,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
bool hashes_equal(unsigned char *h1, unsigned char *h2, int length) {
  int i;
  for (i = 0; i < length; ++i) {
    if (h1[i] != h2[i]) {
      return false;
    }
  }
  return true;
}
```
user: What is the c source code of the assembly code below:

```asm
<hashes_equal>:
  endbr64
  test   %edx,%edx
  jle    L12
  mov    %edx,%edx
  mov    $0x0,%eax
L4:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jne    L11
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
  mov    $0x1,%eax
  ret
L12:
  mov    $0x1,%eax
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool hashes_equal(unsigned char *h1, unsigned char *h2, int length) {
  int i;
  for (i = 0; i < length; ++i) {
    if (h1[i] != h2[i]) {
      return false;
    }
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashes_equal>:
  endbr64
  test   %edx,%edx
  jle    L31
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L15
  nop
L20:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L31
L15:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L20
  xor    %eax,%eax
  ret
  nopl   (%rax)
L31:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool hashes_equal(unsigned char *h1, unsigned char *h2, int length) {
  int i;
  for (i = 0; i < length; ++i) {
    if (h1[i] != h2[i]) {
      return false;
    }
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hashes_equal>:
  endbr64
  test   %edx,%edx
  jle    L37
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L5
  nop
L33:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L37
L5:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L33
  xor    %eax,%eax
  ret
  nopl   (%rax)
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool hashes_equal(unsigned char *h1, unsigned char *h2, int length) {
  int i;
  for (i = 0; i < length; ++i) {
    if (h1[i] != h2[i]) {
      return false;
    }
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L44:
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L57
L70:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L57:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L59
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L70
L59:
  cmpl   $0x0,-0x4(%rbp)
  jle    L68
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
  mov    -0xc(%rbp),%eax
  jmp    L72
L68:
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    $0xffffffff,%eax
L72:
  pop    %rbp
  ret
```

assistant: ```c
int strindex(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = 1, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0') {
      return i;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L77
  movzbl (%rsi),%r9d
  mov    $0x0,%r8d
  jmp    L11
L21:
  add    $0x1,%r8
  cmpb   $0x0,(%rdi,%r8,1)
  je     L47
L11:
  mov    %r8d,%r10d
  mov    %r9d,%edx
  mov    $0x1,%eax
  test   %r9b,%r9b
  je     L21
L12:
  lea    -0x1(%rax),%ecx
  cmp    %dl,(%rdi,%rax,1)
  jne    L68
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L12
L68:
  test   %dl,%dl
  jne    L21
  test   %ecx,%ecx
  jle    L21
  jmp    L42
L77:
  mov    $0xffffffff,%r10d
  jmp    L42
L47:
  mov    $0xffffffff,%r10d
L42:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int strindex(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = 1, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0') {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  nop
L14:
  mov    %ecx,%r9d
  mov    %r8d,%edx
  mov    $0x1,%eax
  test   %r8b,%r8b
  jne    L20
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L33
L20:
  cmp    %dl,(%rdi,%rax,1)
  je     L3
L25:
  add    $0x1,%rcx
  cmpb   $0x0,(%rdi,%rcx,1)
  jne    L14
L19:
  mov    $0xffffffff,%r9d
L33:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int strindex(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = 1, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0') {
      return i;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L43
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  nop
L8:
  mov    %ecx,%r9d
  mov    %r8d,%edx
  mov    $0x1,%eax
  test   %r8b,%r8b
  jne    L0
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L59
L0:
  cmp    %dl,(%rdi,%rax,1)
  je     L39
L16:
  add    $0x1,%rcx
  cmpb   $0x0,(%rdi,%rcx,1)
  jne    L8
L43:
  mov    $0xffffffff,%r9d
L59:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int strindex(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = 1, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0') {
      return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<PrintUsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D31
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D42
datatype: string
name: unpack_data
arguments: tag: D40
datatype: string

tool: D31: Options:


tool: D26:   -display <display-name>  specify X display name


tool: D24:   -t                       print in tabular format


tool: D42:   -v                       print in verbose format


tool: D40:   -help                    print this information


assistant: ```c
void PrintUsage(void) {
  printf("Options:\n");
  printf("  -display <display-name>  specify X display name\n");
  printf("  -t                       print in tabular format\n");
  printf("  -v                       print in verbose format\n");
  printf("  -help                    print this information\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PrintUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
datatype: string
name: extract_symbolic_data
arguments: tag: D33
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string
name: extract_symbolic_data
arguments: tag: D26
datatype: string
name: extract_symbolic_data
arguments: tag: D29
datatype: string

tool: D20: Options:


tool: D33:   -display <display-name>  specify X display name


tool: D4:   -t                       print in tabular format


tool: D26:   -v                       print in verbose format


tool: D29:   -help                    print this information


assistant: ```c
void PrintUsage(void) {
  printf("Options:\n");
  printf("  -display <display-name>  specify X display name\n");
  printf("  -t                       print in tabular format\n");
  printf("  -v                       print in verbose format\n");
  printf("  -help                    print this information\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PrintUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D30
type: string
name: unpack_data
arguments: label: D29
type: string
name: unpack_data
arguments: label: D49
type: string
name: unpack_data
arguments: label: D40
type: string

tool: D18: Options:


tool: D30:   -display <display-name>  specify X display name


tool: D29:   -t                       print in tabular format


tool: D49:   -v                       print in verbose format


tool: D40:   -help                    print this information


assistant: ```c
void PrintUsage(void) {
  printf("Options:\n");
  printf("  -display <display-name>  specify X display name\n");
  printf("  -t                       print in tabular format\n");
  printf("  -v                       print in verbose format\n");
  printf("  -help                    print this information\n");
}
```