ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<iposix_path_splitext>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,(%rsp)
  mov    %edx,%r14d
  mov    %rcx,0x8(%rsp)
  mov    %r8d,%r13d
  call   <strlen@plt>
  mov    %rax,%rbx
  sub    $0x1,%eax
  js     L52
  cltq
L129:
  mov    %eax,%r12d
  movzbl 0x0(%rbp,%rax,1),%edx
  cmp    $0x2e,%dl
  je     L0
  cmp    $0x2f,%dl
  je     L123
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L129
  mov    %ebx,%r12d
  jmp    L0
L52:
  mov    %ebx,%r12d
  jmp    L0
L123:
  mov    %ebx,%r12d
L0:
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L138
  cmp    %r14d,%r12d
  mov    %r14d,%r15d
  cmovle %r12d,%r15d
  test   %r15d,%r15d
  jg     L23
L137:
  cmp    %r15d,%r14d
  jle    L138
  movslq %r15d,%r15
  mov    (%rsp),%rax
  movb   $0x0,(%rax,%r15,1)
L138:
  mov    0x8(%rsp),%rdi
  test   %rdi,%rdi
  je     L2
  sub    %r12d,%ebx
  sub    $0x1,%ebx
  mov    $0x0,%eax
  cmovs  %eax,%ebx
  cmp    %r13d,%ebx
  cmovg  %r13d,%ebx
  test   %ebx,%ebx
  jg     L55
L109:
  cmp    %ebx,%r13d
  jle    L2
  movslq %ebx,%rbx
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax,%rbx,1)
L2:
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    %r15d,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  jmp    L137
L55:
  movslq %r12d,%r12
  lea    0x1(%rbp,%r12,1),%rsi
  mov    %ebx,%edx
  call   <memcpy@plt>
  jmp    L109
```

assistant: ```c
int iposix_path_splitext(const char *path, char *p1, int l1, char *p2, int l2) {
  int length, i, k, size;
  length = (int)strlen(path);
  for (i = length - 1, k = length; i >= 0; i--) {
    if (path[i] == '.') {
      k = i;
      break;
    } else if ('/' == '/') {
      if (path[i] == '/')
        break;
    } else {
      if (path[i] == '/' || path[i] == '\\')
        break;
    }
  }
  if (p1) {
    size = k < l1 ? k : l1;
    if (size > 0)
      memcpy(p1, path, size);
    if (size < l1)
      p1[size] = 0;
  }
  size = length - k - 1;
  if (size < 0)
    size = 0;
  size = size < l2 ? size : l2;
  if (p2) {
    if (size > 0)
      memcpy(p2, path + k + 1, size);
    if (size < l2)
      p2[size] = 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iposix_path_splitext>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  movslq %eax,%r8
  sub    $0x1,%edx
  js     L113
  movslq %edx,%rdx
  jmp    L73
  nopl   (%rax)
L162:
  cmp    $0x2f,%cl
  je     L113
  sub    $0x1,%rdx
  test   %edx,%edx
  js     L113
L73:
  movzbl (%r12,%rdx,1),%ecx
  cmp    $0x2e,%cl
  jne    L162
  sub    %edx,%eax
  movslq %edx,%r8
  lea    -0x1(%rax),%r15d
  xor    %eax,%eax
  test   %r15d,%r15d
  cmovs  %eax,%r15d
  test   %r14,%r14
  jne    L168
  cs nopw 0x0(%rax,%rax,1)
L56:
  test   %rbp,%rbp
  je     L153
  cmp    %r15d,%ebx
  cmovle %ebx,%r15d
  test   %r15d,%r15d
  jg     L67
  cmp    %r15d,%ebx
  jle    L153
L8:
  movslq %r15d,%r15
  movb   $0x0,0x0(%rbp,%r15,1)
L153:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L113:
  xor    %r15d,%r15d
  test   %r14,%r14
  je     L56
L168:
  cmp    %r13d,%r8d
  movslq %r13d,%rdx
  cmovle %r8,%rdx
  test   %edx,%edx
  jg     L92
  cmp    %edx,%r13d
  jle    L56
L74:
  movb   $0x0,(%r14,%rdx,1)
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L67:
  lea    0x1(%r12,%r8,1),%rsi
  mov    %r15d,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  cmp    %r15d,%ebx
  jle    L153
  jmp    L8
  nop
L92:
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %r8d,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  call   <memcpy@plt>
  movslq 0x8(%rsp),%rdx
  movslq 0xc(%rsp),%r8
  cmp    %edx,%r13d
  jle    L56
  jmp    L74
```

assistant: ```c
int iposix_path_splitext(const char *path, char *p1, int l1, char *p2, int l2) {
  int length, i, k, size;
  length = (int)strlen(path);
  for (i = length - 1, k = length; i >= 0; i--) {
    if (path[i] == '.') {
      k = i;
      break;
    } else if ('/' == '/') {
      if (path[i] == '/')
        break;
    } else {
      if (path[i] == '/' || path[i] == '\\')
        break;
    }
  }
  if (p1) {
    size = k < l1 ? k : l1;
    if (size > 0)
      memcpy(p1, path, size);
    if (size < l1)
      p1[size] = 0;
  }
  size = length - k - 1;
  if (size < 0)
    size = 0;
  size = size < l2 ? size : l2;
  if (p2) {
    if (size > 0)
      memcpy(p2, path + k + 1, size);
    if (size < l2)
      p2[size] = 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<iposix_path_splitext>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  movslq %eax,%r8
  sub    $0x1,%edx
  js     L50
  movslq %edx,%rdx
  jmp    L27
  nopl   (%rax)
L107:
  cmp    $0x2f,%cl
  je     L50
  sub    $0x1,%rdx
  test   %edx,%edx
  js     L50
L27:
  movzbl (%r12,%rdx,1),%ecx
  cmp    $0x2e,%cl
  jne    L107
  sub    %edx,%eax
  movslq %edx,%r8
  lea    -0x1(%rax),%r15d
  xor    %eax,%eax
  test   %r15d,%r15d
  cmovs  %eax,%r15d
  test   %r14,%r14
  jne    L169
  cs nopw 0x0(%rax,%rax,1)
L4:
  test   %rbp,%rbp
  je     L128
  cmp    %r15d,%ebx
  cmovle %ebx,%r15d
  test   %r15d,%r15d
  jg     L46
  cmp    %r15d,%ebx
  jle    L128
L85:
  movslq %r15d,%r15
  movb   $0x0,0x0(%rbp,%r15,1)
L128:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  xor    %r15d,%r15d
  test   %r14,%r14
  je     L4
L169:
  cmp    %r13d,%r8d
  movslq %r13d,%rdx
  cmovle %r8,%rdx
  test   %edx,%edx
  jg     L67
  cmp    %edx,%r13d
  jle    L4
L56:
  movb   $0x0,(%r14,%rdx,1)
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L46:
  lea    0x1(%r12,%r8,1),%rsi
  mov    %r15d,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  cmp    %r15d,%ebx
  jle    L128
  jmp    L85
  nop
L67:
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %r8d,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  call   <memcpy@plt>
  movslq 0x8(%rsp),%rdx
  movslq 0xc(%rsp),%r8
  cmp    %edx,%r13d
  jle    L4
  jmp    L56
```

assistant: ```c
int iposix_path_splitext(const char *path, char *p1, int l1, char *p2, int l2) {
  int length, i, k, size;
  length = (int)strlen(path);
  for (i = length - 1, k = length; i >= 0; i--) {
    if (path[i] == '.') {
      k = i;
      break;
    } else if ('/' == '/') {
      if (path[i] == '/')
        break;
    } else {
      if (path[i] == '/' || path[i] == '\\')
        break;
    }
  }
  if (p1) {
    size = k < l1 ? k : l1;
    if (size > 0)
      memcpy(p1, path, size);
    if (size < l1)
      p1[size] = 0;
  }
  size = length - k - 1;
  if (size < 0)
    size = 0;
  size = size < l2 ? size : l2;
  if (p2) {
    if (size > 0)
      memcpy(p2, path + k + 1, size);
    if (size < l2)
      p2[size] = 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<compute_energy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L37
L16:
  movl   $0x0,-0x20(%rbp)
  jmp    L32
L1:
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltd
  idivl  -0x3c(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltd
  idivl  -0x3c(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x3c(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x20(%rbp)
L32:
  mov    -0x20(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L1
  addl   $0x1,-0x24(%rbp)
L37:
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L16
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double compute_energy(int *lattice, int n_side) {
  double E;
  int i, j, down, right;
  int index, index_down, index_right;
  E = 0.0;
  for (i = 0; i < n_side; i++) {
    for (j = 0; j < n_side; j++) {
      down = (i + 1) % n_side;
      right = (j + 1) % n_side;
      index = j + (n_side * i);
      index_down = j + (n_side * down);
      index_right = right + (n_side * i);
      E += -lattice[index] * lattice[index_down];
      E += -lattice[index] * lattice[index_right];
    }
  }
  return E;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compute_energy>:
  endbr64
  test   %esi,%esi
  jle    L34
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %esi,%edi
  movslq %esi,%r13
  shl    $0x2,%r13
  mov    %r9,%r8
  mov    $0x0,%r12d
  mov    $0x1,%ebp
  pxor   %xmm0,%xmm0
  lea    0x1(%rsi),%ebx
L35:
  mov    %r12d,%r11d
  mov    %ebp,%eax
  cltd
  idiv   %edi
  imul   %edi,%edx
  movslq %edx,%rdx
  lea    (%r9,%rdx,4),%r10
  mov    $0x1,%ecx
L25:
  mov    -0x4(%r8,%rcx,4),%esi
  neg    %esi
  mov    %esi,%eax
  imul   -0x4(%r10,%rcx,4),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  mov    %ecx,%eax
  cltd
  idiv   %edi
  add    %r11d,%edx
  movslq %edx,%rdx
  imul   (%r9,%rdx,4),%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%rcx
  cmp    %rbx,%rcx
  jne    L25
  lea    0x1(%rbp),%eax
  add    %edi,%r12d
  add    %r13,%r8
  cmp    %edi,%ebp
  je     L10
  mov    %eax,%ebp
  jmp    L35
L34:
  pxor   %xmm0,%xmm0
  ret
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double compute_energy(int *lattice, int n_side) {
  double E;
  int i, j, down, right;
  int index, index_down, index_right;
  E = 0.0;
  for (i = 0; i < n_side; i++) {
    for (j = 0; j < n_side; j++) {
      down = (i + 1) % n_side;
      right = (j + 1) % n_side;
      index = j + (n_side * i);
      index_down = j + (n_side * down);
      index_right = right + (n_side * i);
      E += -lattice[index] * lattice[index_down];
      E += -lattice[index] * lattice[index_right];
    }
  }
  return E;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compute_energy>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %r12
  mov    %rdi,%r10
  movslq %esi,%r12
  mov    %esi,%edi
  push   %rbp
  shl    $0x2,%r12
  mov    %r10,%r9
  xor    %r8d,%r8d
  push   %rbx
  xor    %ebp,%ebp
  pxor   %xmm0,%xmm0
  lea    0x1(%rsi),%ebx
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%ebp
  mov    $0x1,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %edi
  imul   %edi,%edx
  movslq %edx,%rdx
  lea    (%r10,%rdx,4),%r11
  nopw   0x0(%rax,%rax,1)
L9:
  mov    -0x4(%r9,%rcx,4),%esi
  mov    -0x4(%r11,%rcx,4),%eax
  pxor   %xmm1,%xmm1
  neg    %esi
  imul   %esi,%eax
  cvtsi2sd %eax,%xmm1
  mov    %ecx,%eax
  add    $0x1,%rcx
  cltd
  idiv   %edi
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  add    %r8d,%edx
  movslq %edx,%rdx
  imul   (%r10,%rdx,4),%esi
  cvtsi2sd %esi,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rcx,%rbx
  jne    L9
  add    %edi,%r8d
  add    %r12,%r9
  cmp    %edi,%ebp
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double compute_energy(int *lattice, int n_side) {
  double E;
  int i, j, down, right;
  int index, index_down, index_right;
  E = 0.0;
  for (i = 0; i < n_side; i++) {
    for (j = 0; j < n_side; j++) {
      down = (i + 1) % n_side;
      right = (j + 1) % n_side;
      index = j + (n_side * i);
      index_down = j + (n_side * down);
      index_right = right + (n_side * i);
      E += -lattice[index] * lattice[index_down];
      E += -lattice[index] * lattice[index_right];
    }
  }
  return E;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute_energy>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r12
  mov    %rdi,%r10
  movslq %esi,%r12
  mov    %esi,%edi
  push   %rbp
  shl    $0x2,%r12
  mov    %r10,%r9
  xor    %r8d,%r8d
  push   %rbx
  xor    %ebp,%ebp
  pxor   %xmm0,%xmm0
  lea    0x1(%rsi),%ebx
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x1,%ebp
  mov    $0x1,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %edi
  imul   %edi,%edx
  movslq %edx,%rdx
  lea    (%r10,%rdx,4),%r11
  nopw   0x0(%rax,%rax,1)
L6:
  mov    -0x4(%r9,%rcx,4),%esi
  mov    -0x4(%r11,%rcx,4),%eax
  pxor   %xmm1,%xmm1
  neg    %esi
  imul   %esi,%eax
  cvtsi2sd %eax,%xmm1
  mov    %ecx,%eax
  add    $0x1,%rcx
  cltd
  idiv   %edi
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  add    %r8d,%edx
  movslq %edx,%rdx
  imul   (%r10,%rdx,4),%esi
  cvtsi2sd %esi,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rcx,%rbx
  jne    L6
  add    %edi,%r8d
  add    %r12,%r9
  cmp    %edi,%ebp
  jne    L22
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double compute_energy(int *lattice, int n_side) {
  double E;
  int i, j, down, right;
  int index, index_down, index_right;
  E = 0.0;
  for (i = 0; i < n_side; i++) {
    for (j = 0; j < n_side; j++) {
      down = (i + 1) % n_side;
      right = (j + 1) % n_side;
      index = j + (n_side * i);
      index_down = j + (n_side * down);
      index_right = right + (n_side * i);
      E += -lattice[index] * lattice[index_down];
      E += -lattice[index] * lattice[index_right];
    }
  }
  return E;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_dir_details>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x438(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x420(%rbp)
  cmpq   $0x0,-0x420(%rbp)
  je     L8
  jmp    L29
L40:
  mov    -0x418(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x438(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x424(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  js     L39
  mov    -0x418(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x424(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <print_file_details@plt>
L29:
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L40
  jmp    L8
L39:
  nop
L8:
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: %s/%s

assistant: ```c
void print_dir_details(char dir[]) {
  struct dirent *pDirent;
  DIR *pDir;
  pDir = opendir(dir);
  if (pDir != NULL) {
    while ((pDirent = readdir(pDir)) != NULL) {
      char filepath[1024];
      sprintf(filepath, "%s/%s", dir, pDirent->d_name);
      struct stat file_stats;
      if (stat(filepath, &file_stats) < 0) {
        break;
      }
      print_file_details(file_stats, pDirent->d_name);
    }
  }
  closedir(pDir);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_dir_details>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x420,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  mov    %rax,%r12
  lea    D5(%rip),%r14
  test   %rax,%rax
  je     L32
L41:
  mov    %r12,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L32
  lea    0x10(%rsp),%rbp
  mov    (%rbx),%rcx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %rax,%rax
  js     L32
  mov    (%rbx),%rsi
  mov    0xc(%rsp),%edi
  call   <print_file_details@plt>
  jmp    L41
L32:
  mov    %r12,%rdi
  call   <closedir@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x420,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: %s/%s

assistant: ```c
void print_dir_details(char dir[]) {
  struct dirent *pDirent;
  DIR *pDir;
  pDir = opendir(dir);
  if (pDir != NULL) {
    while ((pDirent = readdir(pDir)) != NULL) {
      char filepath[1024];
      sprintf(filepath, "%s/%s", dir, pDirent->d_name);
      struct stat file_stats;
      if (stat(filepath, &file_stats) < 0) {
        break;
      }
      print_file_details(file_stats, pDirent->d_name);
    }
  }
  closedir(pDir);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_dir_details>:
  endbr64
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L8
  jmp    L40
  nop
L20:
  lea    0x10(%rsp),%rbp
  mov    (%rbx),%rcx
  mov    %r14,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %rax,%rax
  js     L40
  mov    (%rbx),%rsi
  mov    0xc(%rsp),%edi
  call   <print_file_details@plt>
L8:
  mov    %r12,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L20
L40:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x420,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10d0 <closedir@plt>
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D8: %s/%s

assistant: ```c
void print_dir_details(char dir[]) {
  struct dirent *pDirent;
  DIR *pDir;
  pDir = opendir(dir);
  if (pDir != NULL) {
    while ((pDirent = readdir(pDir)) != NULL) {
      char filepath[1024];
      sprintf(filepath, "%s/%s", dir, pDirent->d_name);
      struct stat file_stats;
      if (stat(filepath, &file_stats) < 0) {
        break;
      }
      print_file_details(file_stats, pDirent->d_name);
    }
  }
  closedir(pDir);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_dir_details>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L43
  jmp    L14
  nop
L12:
  lea    0x10(%rsp),%rbp
  mov    (%rbx),%rcx
  mov    %r14,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %rax,%rax
  js     L14
  mov    (%rbx),%rsi
  mov    0xc(%rsp),%edi
  call   <print_file_details@plt>
L43:
  mov    %r12,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L12
L14:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x420,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10d0 <closedir@plt>
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: %s/%s

assistant: ```c
void print_dir_details(char dir[]) {
  struct dirent *pDirent;
  DIR *pDir;
  pDir = opendir(dir);
  if (pDir != NULL) {
    while ((pDirent = readdir(pDir)) != NULL) {
      char filepath[1024];
      sprintf(filepath, "%s/%s", dir, pDirent->d_name);
      struct stat file_stats;
      if (stat(filepath, &file_stats) < 0) {
        break;
      }
      print_file_details(file_stats, pDirent->d_name);
    }
  }
  closedir(pDir);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ind(const int i, const int m) {
  int ind = i % m;
  if (ind == 0)
    ind = m;
  return ind;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ind>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  mov    %esi,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
int ind(const int i, const int m) {
  int ind = i % m;
  if (ind == 0)
    ind = m;
  return ind;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ind>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %esi,%eax
  test   %edx,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int ind(const int i, const int m) {
  int ind = i % m;
  if (ind == 0)
    ind = m;
  return ind;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ind>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %esi,%eax
  test   %edx,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int ind(const int i, const int m) {
  int ind = i % m;
  if (ind == 0)
    ind = m;
  return ind;
}
```
user: What is the c source code of the assembly code below:

```asm
<vprintl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x5b,%edi
  call   <putchar@plt>
  cmpq   $0x0,-0x20(%rbp)
  je     L13
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L32:
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  je     L47
  lea    D2(%rip),%rax
  jmp    L56
L47:
  lea    D24(%rip),%rax
L56:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L32
  jmp    L41
L13:
  mov    $0x5d,%edi
  call   <putchar@plt>
L41:
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string
name: unpack_data
arguments: tag: D24
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string

tool: D2: , 

tool: D24: ]

tool: D10: %i%s

assistant: ```c
void vprintl(int *v, const size_t size) {
  printf("[");
  if (size != 0) {
    for (int i = 0; i < size; i++)
      printf("%i%s", v[i], (i != size - 1) ? ", " : "]");
  } else {
    printf("]");
  }
  printf("\n");
}
```