ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<print_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0xa,-0x1c(%rbp)
  jne    L44
  mov    $0x3b9aca00,%eax
  jmp    L33
L44:
  mov    $0x10000000,%eax
L33:
  mov    %rax,-0x8(%rbp)
  jmp    L27
L13:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L5
  cmpq   $0x1,-0x8(%rbp)
  jne    L57
L5:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x8(%rbp)
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    %rdx,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  mov    %al,-0x9(%rbp)
  cmpb   $0x9,-0x9(%rbp)
  jg     L28
  mov    $0x30,%edx
  jmp    L17
L28:
  mov    $0x57,%edx
L17:
  movzbl -0x9(%rbp),%eax
  add    %edx,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <print_char@plt>
L57:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x8(%rbp)
L27:
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_long(unsigned long value, int base) {
  unsigned long i;
  char c;
  for (i = (base == 10 ? 1000000000 : 0x10000000); i != 0; i /= base)
    if (value >= i || i == 1) {
      c = (value / i) % base;
      print_char(c + (c <= 9 ? '0' : 'a' - 10));
    }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_long>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  cmp    $0xa,%esi
  mov    $0x3b9aca00,%ebx
  mov    $0x10000000,%eax
  cmovne %rax,%rbx
  movslq %esi,%rbp
  jmp    L2
L26:
  mov    %r12,%rax
  mov    $0x0,%edx
  div    %rbx
  mov    $0x0,%edx
  div    %rbp
  cmp    $0xa,%dl
  mov    $0x30,%edi
  mov    $0x57,%eax
  cmovge %eax,%edi
  add    %edx,%edi
  movsbl %dil,%edi
  call   <print_char@plt>
L12:
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rbp
  cmp    %rbx,%rbp
  ja     L11
  mov    %rax,%rbx
L2:
  cmp    %rbx,%r12
  jae    L26
  cmp    $0x1,%rbx
  jne    L12
  jmp    L26
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void print_long(unsigned long value, int base) {
  unsigned long i;
  char c;
  for (i = (base == 10 ? 1000000000 : 0x10000000); i != 0; i /= base)
    if (value >= i || i == 1) {
      c = (value / i) % base;
      print_char(c + (c <= 9 ? '0' : 'a' - 10));
    }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_long>:
  endbr64
  push   %r13
  mov    $0x10000000,%eax
  mov    %rdi,%r13
  push   %r12
  mov    $0x30,%r12d
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    $0x3b9aca00,%ebx
  sub    $0x8,%rsp
  cmp    $0xa,%esi
  cmovne %rax,%rbx
  jmp    L37
  nopl   (%rax)
L5:
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  cmp    %rbx,%rbp
  ja     L4
L43:
  mov    %rax,%rbx
L37:
  cmp    %rbx,%r13
  jae    L18
  cmp    $0x1,%rbx
  jne    L5
L18:
  xor    %edx,%edx
  mov    %r13,%rax
  mov    $0x57,%edi
  div    %rbx
  xor    %edx,%edx
  div    %rbp
  cmp    $0xa,%dl
  cmovl  %r12d,%edi
  add    %edx,%edi
  movsbl %dil,%edi
  call   <print_char@plt>
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  cmp    %rbx,%rbp
  jbe    L43
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void print_long(unsigned long value, int base) {
  unsigned long i;
  char c;
  for (i = (base == 10 ? 1000000000 : 0x10000000); i != 0; i /= base)
    if (value >= i || i == 1) {
      c = (value / i) % base;
      print_char(c + (c <= 9 ? '0' : 'a' - 10));
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_long>:
  endbr64
  push   %r13
  mov    $0x10000000,%eax
  mov    %rdi,%r13
  push   %r12
  mov    $0x30,%r12d
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    $0x3b9aca00,%ebx
  sub    $0x8,%rsp
  cmp    $0xa,%esi
  cmovne %rax,%rbx
  jmp    L5
  nopl   (%rax)
L45:
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  cmp    %rbx,%rbp
  ja     L24
L38:
  mov    %rax,%rbx
L5:
  cmp    %rbx,%r13
  jae    L34
  cmp    $0x1,%rbx
  jne    L45
L34:
  xor    %edx,%edx
  mov    %r13,%rax
  mov    $0x57,%edi
  div    %rbx
  xor    %edx,%edx
  div    %rbp
  cmp    $0xa,%dl
  cmovl  %r12d,%edi
  add    %edx,%edi
  movsbl %dil,%edi
  call   <print_char@plt>
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  cmp    %rbx,%rbp
  jbe    L38
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void print_long(unsigned long value, int base) {
  unsigned long i;
  char c;
  for (i = (base == 10 ? 1000000000 : 0x10000000); i != 0; i /= base)
    if (value >= i || i == 1) {
      c = (value / i) % base;
      print_char(c + (c <= 9 ? '0' : 'a' - 10));
    }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dmatrix3d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,0x10(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0x20(%rsp)
  mov    %ecx,%r14d
  mov    %r8d,0x24(%rsp)
  mov    %r9d,0x2c(%rsp)
  sub    %edi,%esi
  mov    %esi,%edi
  add    $0x1,%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L46
L70:
  mov    0x10(%rsp),%esi
  movslq %esi,%rax
  shl    $0x3,%rax
  mov    %rbx,%rcx
  sub    %rax,%rcx
  mov    %rcx,0x38(%rsp)
  cmp    %esi,0x14(%rsp)
  jl     L68
  mov    0x20(%rsp),%ecx
  movslq %ecx,%rax
  shl    $0x3,%rax
  mov    %rax,0x30(%rsp)
  neg    %rax
  mov    %rax,0x18(%rsp)
  movslq 0x24(%rsp),%r15
  shl    $0x3,%r15
  neg    %r15
  mov    %rbx,0x8(%rsp)
  mov    %r14d,%eax
  sub    %ecx,%eax
  add    $0x1,%eax
  mov    %eax,0x28(%rsp)
  jmp    L33
L46:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L70
L101:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L47:
  mov    %rbx,%rax
  add    0x0(%rbp),%rax
  add    %r15,(%rax)
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,%r14d
  jl     L110
L90:
  mov    $0x8,%esi
  mov    %r13d,%edi
  call   <calloc@plt>
  mov    0x0(%rbp),%rdx
  mov    %rax,(%rdx,%rbx,1)
  mov    0x0(%rbp),%rax
  cmpq   $0x0,(%rax,%rbx,1)
  jne    L47
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L47
L110:
  addl   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%eax
  addq   $0x8,0x8(%rsp)
  cmp    %eax,0x14(%rsp)
  jl     L68
L33:
  mov    $0x8,%esi
  mov    0x28(%rsp),%edi
  call   <calloc@plt>
  mov    0x8(%rsp),%rcx
  mov    %rcx,%rbp
  mov    %rax,(%rcx)
  test   %rax,%rax
  je     L101
L12:
  mov    0x18(%rsp),%rax
  add    %rax,0x0(%rbp)
  mov    0x20(%rsp),%r12d
  cmp    %r12d,%r14d
  jl     L110
  mov    0x30(%rsp),%rbx
  mov    0x2c(%rsp),%r13d
  sub    0x24(%rsp),%r13d
  add    $0x1,%r13d
  jmp    L90
L68:
  mov    0x38(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D23
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string

tool: D12: allocation failure 1 in dmatrix3d()

tool: D23: allocation failure 2 in dmatrix3d()

tool: D28: allocation failure 3 in dmatrix3d()

assistant: ```c
double ***dmatrix3d(int nsl, int nsh, int nrl, int nrh, int ncl, int nch) {
  int i, j;
  double ***m;
  m = (double ***)calloc((unsigned)(nsh - nsl + 1), sizeof(double **));
  if (!m)
    printf("allocation failure 1 in dmatrix3d()");
  m -= nsl;
  for (j = nsl; j <= nsh; j++) {
    m[j] = (double **)calloc((unsigned)(nrh - nrl + 1), sizeof(double *));
    if (!m[j])
      printf("allocation failure 2 in dmatrix3d()");
    m[j] -= nrl;
    for (i = nrl; i <= nrh; i++) {
      m[j][i] = (double *)calloc((unsigned)(nch - ncl + 1), sizeof(double));
      if (!m[j][i])
        printf("allocation failure 3 in dmatrix3d()");
      m[j][i] -= ncl;
    }
  }
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dmatrix3d>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0x8(%rsp)
  sub    %edi,%esi
  mov    %edi,0x4(%rsp)
  mov    %esi,%edi
  mov    $0x8,%esi
  add    $0x1,%edi
  mov    %edx,0xc(%rsp)
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
L91:
  movslq 0x4(%rsp),%rax
  mov    %rbx,%rsi
  mov    %rax,%rcx
  shl    $0x3,%rax
  sub    %rax,%rsi
  mov    %rsi,0x28(%rsp)
  cmp    %ecx,0x8(%rsp)
  jl     L61
  movslq 0xc(%rsp),%rax
  sub    %r15d,%r12d
  movslq %r15d,%r13
  mov    %r12d,0x24(%rsp)
  shl    $0x3,%r13
  mov    %rax,%rcx
  shl    $0x3,%rax
  neg    %r13
  mov    %rax,0x10(%rsp)
  neg    %rax
  mov    %rax,0x18(%rsp)
  mov    %ebp,%eax
  sub    %ecx,%eax
  add    $0x1,%eax
  mov    %eax,0x20(%rsp)
  nopw   0x0(%rax,%rax,1)
L63:
  mov    0x20(%rsp),%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L100
L108:
  add    0x18(%rsp),%rax
  mov    0x10(%rsp),%r14
  mov    %rax,(%rbx)
  mov    0x24(%rsp),%eax
  lea    0x1(%rax),%r12d
  mov    0xc(%rsp),%eax
  mov    %eax,%r15d
  cmp    %eax,%ebp
  jge    L34
  jmp    L21
  nopl   0x0(%rax)
L92:
  add    %r13,%rax
  add    $0x1,%r15d
  add    $0x8,%r14
  mov    %rax,(%rdx)
  cmp    %r15d,%ebp
  jl     L21
L34:
  mov    $0x8,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    (%rbx),%rdx
  add    %r14,%rdx
  mov    %rax,(%rdx)
  test   %rax,%rax
  jne    L92
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rdx
  add    %r14,%rdx
  mov    (%rdx),%rax
  jmp    L92
  nopl   (%rax)
L21:
  addl   $0x1,0x4(%rsp)
  add    $0x8,%rbx
  mov    0x4(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  jge    L63
L61:
  mov    0x28(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L100:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rax
  jmp    L108
L37:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L91
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string
name: read_data
arguments: tag: D18
type_infered: string
name: read_data
arguments: tag: D10
type_infered: string

tool: D5: allocation failure 3 in dmatrix3d()

tool: D18: allocation failure 2 in dmatrix3d()

tool: D10: allocation failure 1 in dmatrix3d()

assistant: ```c
double ***dmatrix3d(int nsl, int nsh, int nrl, int nrh, int ncl, int nch) {
  int i, j;
  double ***m;
  m = (double ***)calloc((unsigned)(nsh - nsl + 1), sizeof(double **));
  if (!m)
    printf("allocation failure 1 in dmatrix3d()");
  m -= nsl;
  for (j = nsl; j <= nsh; j++) {
    m[j] = (double **)calloc((unsigned)(nrh - nrl + 1), sizeof(double *));
    if (!m[j])
      printf("allocation failure 2 in dmatrix3d()");
    m[j] -= nrl;
    for (i = nrl; i <= nrh; i++) {
      m[j][i] = (double *)calloc((unsigned)(nch - ncl + 1), sizeof(double));
      if (!m[j][i])
        printf("allocation failure 3 in dmatrix3d()");
      m[j][i] -= ncl;
    }
  }
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L5
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: n=%d


assistant: ```c
int power(int base, int n) {
  int i, p;
  printf("n=%d\n", n);
  p = 1;
  for (i = 1; i <= n; ++i)
    p = p * base;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<power>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L10
  lea    0x1(%rbx),%esi
  mov    $0x1,%edx
  mov    $0x1,%eax
L9:
  imul   %ebp,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L9
L2:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x1,%edx
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: n=%d


assistant: ```c
int power(int base, int n) {
  int i, p;
  printf("n=%d\n", n);
  p = 1;
  for (i = 1; i <= n; ++i)
    p = p * base;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D0(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L14
  lea    0x1(%rbx),%esi
  mov    $0x1,%r8d
  mov    $0x1,%eax
  nopl   0x0(%rax)
L17:
  add    $0x1,%eax
  imul   %ebp,%r8d
  cmp    %esi,%eax
  jne    L17
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L14:
  add    $0x8,%rsp
  mov    $0x1,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: n=%d


assistant: ```c
int power(int base, int n) {
  int i, p;
  printf("n=%d\n", n);
  p = 1;
  for (i = 1; i <= n; ++i)
    p = p * base;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<power>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D5(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L7
  lea    0x1(%rbx),%esi
  mov    $0x1,%r8d
  mov    $0x1,%eax
  nopl   0x0(%rax)
L17:
  add    $0x1,%eax
  imul   %ebp,%r8d
  cmp    %esi,%eax
  jne    L17
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  add    $0x8,%rsp
  mov    $0x1,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: n=%d


assistant: ```c
int power(int base, int n) {
  int i, p;
  printf("n=%d\n", n);
  p = 1;
  for (i = 1; i <= n; ++i)
    p = p * base;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_from_u>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <str_new@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: %lu

assistant: ```c
char *str_from_u(unsigned long v) {
  char buf[30];
  sprintf(buf, "%lu", v);
  return str_new(buf);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_from_u>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <str_new@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x30,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string

tool: D7: %lu

assistant: ```c
char *str_from_u(unsigned long v) {
  char buf[30];
  sprintf(buf, "%lu", v);
  return str_new(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_from_u>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  lea    D2(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <str_new@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x30,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: %lu

assistant: ```c
char *str_from_u(unsigned long v) {
  char buf[30];
  sprintf(buf, "%lu", v);
  return str_new(buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_from_u>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  lea    D6(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <str_new@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x30,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: %lu

assistant: ```c
char *str_from_u(unsigned long v) {
  char buf[30];
  sprintf(buf, "%lu", v);
  return str_new(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<test_stdarg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movb   $0x1,-0x2(%rbp)
  movb   $0x2,-0x1(%rbp)
  movsbl -0x1(%rbp),%edx
  movsbl -0x2(%rbp),%esi
  lea    -0x14(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  mov    $0x76214365,%edx
  mov    %rax,%rdi
  call   <test_stdarg_va@plt>
  cmp    $0x1,%eax
  je     L16
  mov    $0x0,%eax
  jmp    L6
L16:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int test_stdarg(int r) {
  char c1 = 1, c2 = 2;
  if (test_stdarg_va(&r, c1, 0x76214365ul, c2, &r) != 1)
    return 0;
  return r & 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_stdarg>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  mov    %rdi,%r8
  mov    $0x2,%ecx
  mov    $0x76214365,%edx
  mov    $0x1,%esi
  call   <test_stdarg_va@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  jne    L7
  mov    0xc(%rsp),%eax
  and    $0x1,%eax
L7:
  add    $0x18,%rsp
  ret
```

assistant: ```c
int test_stdarg(int r) {
  char c1 = 1, c2 = 2;
  if (test_stdarg_va(&r, c1, 0x76214365ul, c2, &r) != 1)
    return 0;
  return r & 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_stdarg>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%ecx
  mov    $0x76214365,%edx
  mov    $0x1,%esi
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  mov    %rdi,%r8
  call   <test_stdarg_va@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jne    L1
  mov    0xc(%rsp),%eax
  and    $0x1,%eax
L1:
  add    $0x18,%rsp
  ret
```

assistant: ```c
int test_stdarg(int r) {
  char c1 = 1, c2 = 2;
  if (test_stdarg_va(&r, c1, 0x76214365ul, c2, &r) != 1)
    return 0;
  return r & 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_stdarg>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%ecx
  mov    $0x76214365,%edx
  mov    $0x1,%esi
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  mov    %rdi,%r8
  call   <test_stdarg_va@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jne    L3
  mov    0xc(%rsp),%eax
  and    $0x1,%eax
L3:
  add    $0x18,%rsp
  ret
```

assistant: ```c
int test_stdarg(int r) {
  char c1 = 1, c2 = 2;
  if (test_stdarg_va(&r, c1, 0x76214365ul, c2, &r) != 1)
    return 0;
  return r & 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<qd_real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void qd_real(double a, double *b) {
  b[0] = a;
  b[1] = 0.0;
  b[2] = 0.0;
  b[3] = 0.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<qd_real>:
  endbr64
  movsd  %xmm0,(%rdi)
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  ret
```

assistant: ```c
void qd_real(double a, double *b) {
  b[0] = a;
  b[1] = 0.0;
  b[2] = 0.0;
  b[3] = 0.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qd_real>:
  endbr64
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movsd  %xmm0,(%rdi)
  ret
```

assistant: ```c
void qd_real(double a, double *b) {
  b[0] = a;
  b[1] = 0.0;
  b[2] = 0.0;
  b[3] = 0.0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n -= m;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n -= m;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n -= m;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n -= m;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_params>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x20,%eax
  seta   %dl
  test   %dl,%dl
  jne    L40
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  movabs $0x100002201,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L34
  and    $0x400,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L11
  jmp    L40
L34:
  cmpl   $0x0,-0xc(%rbp)
  je     L70
  addl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L70
L11:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L32
L40:
  movl   $0x1,-0xc(%rbp)
  jmp    L32
L70:
  nop
L32:
  addl   $0x1,-0x8(%rbp)
L57:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L17
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4: read new line

assistant: ```c
int count_params(const char *cmdline) {
  int params_count = 0;
  int length = strlen(cmdline);
  int inword = 0;
  int i;
  for (i = 0; i < length - 1; i++) {
    switch (cmdline[i]) {
    case ' ':
    case '\0':
    case '\r':
    case '\t':
      if (inword) {
        params_count++;
        inword = 0;
      }
      break;
    case '\n':
      printf("read new line");
      break;
    default:
      inword = 1;
      break;
    }
  }
  params_count++;
  return params_count;
}
```