ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<column_prod>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  cmp    $0x10,%ebx
  jg     L5
  movslq %edx,%rbp
  mov    %rdi,%r12
  lea    0x3(%rbx),%ecx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %ebp,%r8d
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%rax
  shl    $0x4,%rax
  add    %rax,%r12
  lea    (%r12,%rbp,4),%rdx
  mov    0x50(%rdx),%eax
  imul   (%rdx),%eax
  imul   0xa0(%rdx),%eax
  imul   0xf0(%rdx),%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    $0xffffffff,%eax
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: %d:%d->%d:%d

assistant: ```c
int column_prod(int num[20][20], int i, int j) {
  if (i > 16)
    return -1;
  printf("%d:%d->%d:%d", i, j, i + 3, j);
  return num[i][j] * num[i + 1][j] * num[i + 2][j] * num[i + 3][j];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<column_prod>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  cmp    $0x10,%ebx
  jg     L2
  movslq %edx,%rbp
  mov    %rdi,%r12
  lea    0x3(%rbx),%ecx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %ebp,%r8d
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%rax
  shl    $0x4,%rax
  add    %rax,%r12
  lea    (%r12,%rbp,4),%rdx
  mov    0x50(%rdx),%eax
  imul   (%rdx),%eax
  imul   0xa0(%rdx),%eax
  imul   0xf0(%rdx),%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  mov    $0xffffffff,%eax
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: %d:%d->%d:%d

assistant: ```c
int column_prod(int num[20][20], int i, int j) {
  if (i > 16)
    return -1;
  printf("%d:%d->%d:%d", i, j, i + 3, j);
  return num[i][j] * num[i + 1][j] * num[i + 2][j] * num[i + 3][j];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L48
L59:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L12
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L12
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L12:
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jg     L8
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L59
L8:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D24
datatype: string

tool: D0: Enter two numbers: 

tool: D9: %d %d

tool: D24: GCD for numbers %d and %d is %d

assistant: ```c
int main() {
  int a, b, gcd;
  printf("Enter two numbers: \n");
  scanf("%d %d", &a, &b);
  int i;
  gcd = 1;
  for (i = 1; i <= a && i <= b; i++)
    if (a % i == 0 && b % i == 0)
      gcd = i;
  printf("GCD for numbers %d and %d is %d", a, b, gcd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  test   %esi,%esi
  jle    L23
  mov    0x4(%rsp),%edi
  mov    $0x1,%ecx
  mov    $0x1,%r8d
  jmp    L34
L28:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L43
L34:
  cmp    %ecx,%edi
  jl     L43
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L28
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%r8d
  jmp    L28
L23:
  mov    $0x1,%r8d
L43:
  mov    %r8d,%ecx
  mov    0x4(%rsp),%edx
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D11
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string

tool: D0: Enter two numbers: 

tool: D11: %d %d

tool: D8: GCD for numbers %d and %d is %d

assistant: ```c
int main() {
  int a, b, gcd;
  printf("Enter two numbers: \n");
  scanf("%d %d", &a, &b);
  int i;
  gcd = 1;
  for (i = 1; i <= a && i <= b; i++)
    if (a % i == 0 && b % i == 0)
      gcd = i;
  printf("GCD for numbers %d and %d is %d", a, b, gcd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  test   %esi,%esi
  jle    L7
  mov    0x4(%rsp),%r8d
  mov    $0x1,%ecx
  mov    $0x1,%r9d
  jmp    L53
  nopl   0x0(%rax)
L57:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L15
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%r9d
L15:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L6
L53:
  cmp    %ecx,%r8d
  jge    L57
L6:
  xor    %eax,%eax
  mov    %r9d,%ecx
  lea    D15(%rip),%rdi
  mov    %r8d,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  mov    0x4(%rsp),%r8d
  mov    $0x1,%r9d
  jmp    L6
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
type_infered: string
name: unpack_data
arguments: tag: D24
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string

tool: D29: Enter two numbers: 

tool: D24: %d %d

tool: D15: GCD for numbers %d and %d is %d

assistant: ```c
int main() {
  int a, b, gcd;
  printf("Enter two numbers: \n");
  scanf("%d %d", &a, &b);
  int i;
  gcd = 1;
  for (i = 1; i <= a && i <= b; i++)
    if (a % i == 0 && b % i == 0)
      gcd = i;
  printf("GCD for numbers %d and %d is %d", a, b, gcd);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  test   %esi,%esi
  jle    L68
  mov    0x4(%rsp),%r8d
  mov    $0x1,%ecx
  mov    $0x1,%r9d
  jmp    L30
  nopl   0x0(%rax)
L17:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L50
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%r9d
L50:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L53
L30:
  cmp    %ecx,%r8d
  jge    L17
L53:
  xor    %eax,%eax
  mov    %r9d,%ecx
  lea    D0(%rip),%rdi
  mov    %r8d,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L68:
  mov    0x4(%rsp),%r8d
  mov    $0x1,%r9d
  jmp    L53
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
datatype: string
name: unpack_data
arguments: tag: D29
datatype: string
name: unpack_data
arguments: tag: D0
datatype: string

tool: D23: Enter two numbers: 

tool: D29: %d %d

tool: D0: GCD for numbers %d and %d is %d

assistant: ```c
int main() {
  int a, b, gcd;
  printf("Enter two numbers: \n");
  scanf("%d %d", &a, &b);
  int i;
  gcd = 1;
  for (i = 1; i <= a && i <= b; i++)
    if (a % i == 0 && b % i == 0)
      gcd = i;
  printf("GCD for numbers %d and %d is %d", a, b, gcd);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x1c,%eax
  test   %eax,%eax
  jne    L15
  mov    $0x0,%eax
  jmp    L35
L15:
  movl   $0x0,-0x4(%rbp)
  jmp    L55
L50:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  movzbl %al,%eax
  cmp    $0xa,%eax
  jne    L38
  mov    $0x0,%eax
  jmp    L35
L38:
  addl   $0x8,-0x4(%rbp)
L55:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L50
  mov    $0x1,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int check(unsigned c) {
  int i;
  if (((c >> 28) & 0xF) == 0)
    return 0;
  for (i = 0; i < 32; i += 8)
    if (((c >> i) & 0xFF) == '\n')
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check>:
  endbr64
  mov    $0x0,%edx
  mov    %edi,%eax
  shr    $0x1c,%eax
  je     L0
  cmp    $0xa,%dil
  je     L0
  mov    %edi,%eax
  movzbl %ah,%edx
  cmp    $0xa,%edx
  je     L19
  shr    $0x10,%eax
  cmp    $0xa,%al
  setne  %dl
  movzbl %dl,%edx
L0:
  mov    %edx,%eax
  ret
L19:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
int check(unsigned c) {
  int i;
  if (((c >> 28) & 0xF) == 0)
    return 0;
  for (i = 0; i < 32; i += 8)
    if (((c >> i) & 0xFF) == '\n')
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check>:
  endbr64
  mov    %edi,%edx
  xor    %eax,%eax
  shr    $0x1c,%edx
  je     L22
  xor    %ecx,%ecx
L17:
  mov    %edi,%eax
  shr    %cl,%eax
  cmp    $0xa,%al
  je     L7
  add    $0x8,%ecx
  cmp    $0x20,%ecx
  jne    L17
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L7:
  xor    %eax,%eax
L22:
  ret
```

assistant: ```c
int check(unsigned c) {
  int i;
  if (((c >> 28) & 0xF) == 0)
    return 0;
  for (i = 0; i < 32; i += 8)
    if (((c >> i) & 0xFF) == '\n')
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check>:
  endbr64
  mov    %edi,%ecx
  xor    %r8d,%r8d
  mov    %edi,%eax
  shr    $0x1c,%ecx
  je     L18
  cmp    $0xa,%dil
  je     L18
  movzbl %ah,%edx
  cmp    $0xa,%edx
  je     L18
  shr    $0x10,%eax
  xor    %r8d,%r8d
  cmp    $0xa,%al
  setne  %r8b
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check(unsigned c) {
  int i;
  if (((c >> 28) & 0xF) == 0)
    return 0;
  for (i = 0; i < 32; i += 8)
    if (((c >> i) & 0xFF) == '\n')
      return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GCMGetDiskHeaderInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L21
  cmpq   $0x0,-0x10(%rbp)
  je     L21
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x440,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x2000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x2000,%eax
  je     L25
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L25
L21:
  nop
L25:
  leave
  ret
```

assistant: ```c
void GCMGetDiskHeaderInfo(FILE *ifile, char *buf) {
  if (!ifile || !buf)
    return;
  fseek(ifile, 0x0440, SEEK_SET);
  if (fread(buf, 1, 0x2000, ifile) != 0x2000) {
    free(buf);
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GCMGetDiskHeaderInfo>:
  endbr64
  test   %rdi,%rdi
  je     L26
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L11
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    $0x440,%esi
  call   <fseek@plt>
  mov    %rbx,%rcx
  mov    $0x2000,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  cmp    $0x2000,%eax
  jne    L14
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L11
L26:
  ret
```

assistant: ```c
void GCMGetDiskHeaderInfo(FILE *ifile, char *buf) {
  if (!ifile || !buf)
    return;
  fseek(ifile, 0x0440, SEEK_SET);
  if (fread(buf, 1, 0x2000, ifile) != 0x2000) {
    free(buf);
    return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GCMGetDiskHeaderInfo>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L8
  mov    D0(%rip),%rax
  mov    %rdi,%r12
  mov    $0x440,%esi
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r12,%rcx
  mov    $0x2000,%edx
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    $0x2000,%eax
  jne    L3
L8:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  ret
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <free@plt>
```

assistant: ```c
void GCMGetDiskHeaderInfo(FILE *ifile, char *buf) {
  if (!ifile || !buf)
    return;
  fseek(ifile, 0x0440, SEEK_SET);
  if (fread(buf, 1, 0x2000, ifile) != 0x2000) {
    free(buf);
    return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GCMGetDiskHeaderInfo>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L13
  mov    D4(%rip),%rax
  mov    %rdi,%r12
  mov    $0x440,%esi
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r12,%rcx
  mov    $0x2000,%edx
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    $0x2000,%eax
  jne    L1
L13:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  ret
  nopl   0x0(%rax)
L1:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <free@plt>
```

assistant: ```c
void GCMGetDiskHeaderInfo(FILE *ifile, char *buf) {
  if (!ifile || !buf)
    return;
  fseek(ifile, 0x0440, SEEK_SET);
  if (fread(buf, 1, 0x2000, ifile) != 0x2000) {
    free(buf);
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vp8_mse2psnr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movl   $0x64,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x28(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L5
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  divsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  movsd  D7(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L5:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L15
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L15:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: f64

tool: D7: 10

assistant: ```c
double vp8_mse2psnr(double samples, double peak, double mse) {
  const int kMaxPSNR = 100;
  double psnr = kMaxPSNR;
  if (mse > 0.0)
    psnr = 10.0 * log10(peak * peak * samples / mse);
  if (psnr > kMaxPSNR)
    psnr = kMaxPSNR;
  return psnr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vp8_mse2psnr>:
  endbr64
  comisd D29(%rip),%xmm2
  ja     L4
  movsd  D9(%rip),%xmm0
  ret
L4:
  sub    $0x8,%rsp
  mulsd  %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  call   <log10@plt>
  mulsd  D27(%rip),%xmm0
  comisd D9(%rip),%xmm0
  jbe    L14
  movsd  D9(%rip),%xmm0
L14:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D29
type_infered: f64[2]
name: unpack_data
arguments: data_label: D9
type_infered: byte[16]
name: unpack_data
arguments: data_label: D27
type_infered: f64

tool: {"D29": [0.0,10.0]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D27: 10

assistant: ```c
double vp8_mse2psnr(double samples, double peak, double mse) {
  const int kMaxPSNR = 100;
  double psnr = kMaxPSNR;
  if (mse > 0.0)
    psnr = 10.0 * log10(peak * peak * samples / mse);
  if (psnr > kMaxPSNR)
    psnr = kMaxPSNR;
  return psnr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vp8_mse2psnr>:
  endbr64
  comisd D21(%rip),%xmm2
  ja     L5
  movsd  D28(%rip),%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mulsd  %xmm1,%xmm1
  sub    $0x8,%rsp
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  call   <log10@plt>
  mulsd  D31(%rip),%xmm0
  movsd  D28(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L14
  movapd %xmm1,%xmm0
L14:
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
type: f64[2]
name: read_data
arguments: data_label: D28
type: byte[8]
name: read_data
arguments: data_label: D31
type: f64

tool: {"D21": [0.0,10.0]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D31: 10

assistant: ```c
double vp8_mse2psnr(double samples, double peak, double mse) {
  const int kMaxPSNR = 100;
  double psnr = kMaxPSNR;
  if (mse > 0.0)
    psnr = 10.0 * log10(peak * peak * samples / mse);
  if (psnr > kMaxPSNR)
    psnr = kMaxPSNR;
  return psnr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vp8_mse2psnr>:
  endbr64
  comisd D24(%rip),%xmm2
  ja     L1
  movsd  D35(%rip),%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mulsd  %xmm1,%xmm1
  sub    $0x8,%rsp
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  call   <log10@plt>
  mulsd  D1(%rip),%xmm0
  movsd  D35(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L15
  movapd %xmm1,%xmm0
L15:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D24
data_type: f64[2]
name: parse_data
arguments: data_tag: D35
data_type: byte[8]
name: parse_data
arguments: data_tag: D1
data_type: f64

tool: {"D24": [0.0,10.0]}

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D1: 10

assistant: ```c
double vp8_mse2psnr(double samples, double peak, double mse) {
  const int kMaxPSNR = 100;
  double psnr = kMaxPSNR;
  if (mse > 0.0)
    psnr = 10.0 * log10(peak * peak * samples / mse);
  if (psnr > kMaxPSNR)
    psnr = kMaxPSNR;
  return psnr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L48
L37:
  movl   $0x1,-0xc(%rbp)
  jmp    L11
L8:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L48:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D26
datatype: string
name: read_data
arguments: data_label: D17
datatype: string
name: read_data
arguments: data_label: D27
datatype: string

tool: D26: Enter the number of rows: 

tool: D17: %d

tool: D27: %d 

assistant: ```c
int main() {
  int i, j, rows;
  printf("Enter the number of rows: ");
  scanf("%d", &rows);
  for (i = 1; i <= rows; ++i) {
    for (j = 1; j <= i; ++j) {
      printf("%d ", j);
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%ebp
  lea    D28(%rip),%r12
  cmpl   $0x0,0x4(%rsp)
  jg     L37
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L46
L57:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jl     L29
L37:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L46
  jmp    L57
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
data_type: string
name: extract_symbolic_data
arguments: data_label: D26
data_type: string
name: extract_symbolic_data
arguments: data_label: D28
data_type: string

tool: D21: Enter the number of rows: 

tool: D26: %d

tool: D28: %d 

assistant: ```c
int main() {
  int i, j, rows;
  printf("Enter the number of rows: ");
  scanf("%d", &rows);
  for (i = 1; i <= rows; ++i) {
    for (j = 1; j <= i; ++j) {
      printf("%d ", j);
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L7
  mov    $0x1,%ebp
  lea    D3(%rip),%r12
  nopl   (%rax)
L19:
  mov    $0x1,%ebx
  nopl   (%rax)
L35:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L35
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x4(%rsp)
  jge    L19
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D25
data_type: string
name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D25: Enter the number of rows: 

tool: D23: %d

tool: D3: %d 

assistant: ```c
int main() {
  int i, j, rows;
  printf("Enter the number of rows: ");
  scanf("%d", &rows);
  for (i = 1; i <= rows; ++i) {
    for (j = 1; j <= i; ++j) {
      printf("%d ", j);
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L10
  mov    $0x1,%ebp
  lea    D1(%rip),%r12
  nopl   (%rax)
L0:
  mov    $0x1,%ebx
  nopl   (%rax)
L13:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L13
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x4(%rsp)
  jge    L0
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D28
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string

tool: D3: Enter the number of rows: 

tool: D28: %d

tool: D1: %d 

assistant: ```c
int main() {
  int i, j, rows;
  printf("Enter the number of rows: ");
  scanf("%d", &rows);
  for (i = 1; i <= rows; ++i) {
    for (j = 1; j <= i; ++j) {
      printf("%d ", j);
    }
    printf("\n");
  }
  return 0;
}
```