ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strtoi_base>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  cmpb   $0x0,(%rax)
  jne    L8
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    D27(%rip),%r12
  movl   $0x0,(%r12)
  mov    %rsp,%rsi
  mov    (%rdi),%rdi
  call   <strtol@plt>
  mov    %eax,%edx
  mov    (%r12),%eax
  test   %eax,%eax
  jne    L55
  mov    (%rsp),%rax
  cmp    %rax,(%rbx)
  je     L57
  mov    %edx,0x0(%rbp)
  mov    %rax,(%rbx)
  cmpb   $0x1,(%rax)
  mov    $0x1,%eax
  adc    $0x0,%eax
  jmp    L26
L55:
  neg    %eax
  jmp    L26
L57:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L26
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strtoi_base(char **str, int *dest, int base) {
  ((void)0);
  if (**str == '\0')
    return -EINVAL;
  char *endptr;
  errno = 0;
  int num = strtol(*str, &endptr, base);
  if (errno != 0)
    return -errno;
  if (*str == endptr)
    return -EINVAL;
  *dest = num;
  *str = endptr;
  if (*endptr == 0)
    return 2;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strtoi_base>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L15
L16:
  mov    D17(%rip),%rax
  mov    (%rax),%eax
L4:
  neg    %eax
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    D5(%rip),%r12
  mov    %rsi,%rbp
  mov    %rsp,%rsi
  movl   $0x0,(%r12)
  call   <strtol@plt>
  mov    %eax,%edx
  mov    (%r12),%eax
  test   %eax,%eax
  jne    L4
  mov    (%rsp),%rax
  cmp    %rax,(%rbx)
  je     L16
  mov    %edx,0x0(%rbp)
  mov    %rax,(%rbx)
  cmpb   $0x1,(%rax)
  mov    $0x1,%eax
  adc    $0x0,%eax
  jmp    L48
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strtoi_base(char **str, int *dest, int base) {
  ((void)0);
  if (**str == '\0')
    return -EINVAL;
  char *endptr;
  errno = 0;
  int num = strtol(*str, &endptr, base);
  if (errno != 0)
    return -errno;
  if (*str == endptr)
    return -EINVAL;
  *dest = num;
  *str = endptr;
  if (*endptr == 0)
    return 2;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strtoi_base>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L13
L36:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
L26:
  neg    %eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    D15(%rip),%r12
  mov    %rsi,%rbp
  mov    %rsp,%rsi
  movl   $0x0,(%r12)
  call   <strtol@plt>
  mov    %eax,%edx
  mov    (%r12),%eax
  test   %eax,%eax
  jne    L26
  mov    (%rsp),%rax
  cmp    %rax,(%rbx)
  je     L36
  mov    %edx,0x0(%rbp)
  mov    %rax,(%rbx)
  cmpb   $0x1,(%rax)
  mov    $0x1,%eax
  adc    $0x0,%eax
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strtoi_base(char **str, int *dest, int base) {
  ((void)0);
  if (**str == '\0')
    return -EINVAL;
  char *endptr;
  errno = 0;
  int num = strtol(*str, &endptr, base);
  if (errno != 0)
    return -errno;
  if (*str == endptr)
    return -EINVAL;
  *dest = num;
  *str = endptr;
  if (*endptr == 0)
    return 2;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_max_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L13
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L13:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_max_int(int array[], int num_members) {
  int max = array[0];
  int a;
  for (a = 1; a < num_members; a++) {
    if (array[a] > max) {
      max = array[a];
    }
  }
  return max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_max_int>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x1,%esi
  jle    L8
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%ecx
  lea    0x8(%rdi,%rcx,4),%rsi
L18:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L18
L8:
  mov    %edx,%eax
  ret
```

assistant: ```c
int find_max_int(int array[], int num_members) {
  int max = array[0];
  int a;
  for (a = 1; a < num_members; a++) {
    if (array[a] > max) {
      max = array[a];
    }
  }
  return max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_max_int>:
  endbr64
  mov    (%rdi),%r8d
  cmp    $0x1,%esi
  jle    L7
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L13
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_max_int(int array[], int num_members) {
  int max = array[0];
  int a;
  for (a = 1; a < num_members; a++) {
    if (array[a] > max) {
      max = array[a];
    }
  }
  return max;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_max_int>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rdx
  mov    %esi,%ecx
  cmp    $0x1,%esi
  jle    L47
  lea    -0x1(%rsi),%edi
  lea    -0x2(%rsi),%esi
  cmp    $0x2,%esi
  jbe    L61
  mov    %edi,%esi
  movd   %eax,%xmm3
  lea    0x4(%rdx),%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm3,%xmm0
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x14(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax)
L60:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm2
  pcmpgtd %xmm0,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  por    %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L60
  movdqa %xmm0,%xmm2
  mov    %edi,%r8d
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%r8d
  movdqa %xmm2,%xmm1
  lea    0x1(%r8),%esi
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    %r8d,%edi
  je     L5
L66:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r8
  mov    (%rdx,%rdi,4),%edi
  cmp    %edi,%eax
  cmovl  %edi,%eax
  lea    0x1(%rsi),%edi
  cmp    %edi,%ecx
  jle    L47
  mov    0x4(%rdx,%r8,1),%edi
  cmp    %edi,%eax
  cmovl  %edi,%eax
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L47
  mov    0x8(%rdx,%r8,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
L47:
  ret
  nopl   0x0(%rax)
L5:
  ret
L61:
  mov    $0x1,%esi
  jmp    L66
```

assistant: ```c
int find_max_int(int array[], int num_members) {
  int max = array[0];
  int a;
  for (a = 1; a < num_members; a++) {
    if (array[a] > max) {
      max = array[a];
    }
  }
  return max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D70
type_guessed: string
name: extract_symbolic_data
arguments: label: D44
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string
name: extract_symbolic_data
arguments: label: D69
type_guessed: string

tool: D70: * * * * * * * *


tool: D44:  * * * * * * * *


tool: D20:  * * * * * * * *



tool: D69: * * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *


assistant: ```c
int main(void) {
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n\n");
  printf("* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D29
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string
name: unpack_data
arguments: label: D16
type_guessed: string

tool: D29: * * * * * * * *


tool: D0:  * * * * * * * *


tool: D5:  * * * * * * * *



tool: D16: * * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *


assistant: ```c
int main(void) {
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n\n");
  printf("* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  lea    D33(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D34
type: string
name: disassemble_data
arguments: data_tag: D33
type: string
name: disassemble_data
arguments: data_tag: D11
type: string
name: disassemble_data
arguments: data_tag: D4
type: string

tool: D34:  * * * * * * * *


tool: D33: * * * * * * * *


tool: D11:  * * * * * * * *



tool: D4: * * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *


assistant: ```c
int main(void) {
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n\n");
  printf("* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D39
type_guessed: string

tool: D1:  * * * * * * * *


tool: D19: * * * * * * * *


tool: D13:  * * * * * * * *



tool: D39: * * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *
* * * * * * * *
 * * * * * * * *


assistant: ```c
int main(void) {
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n");
  printf("* * * * * * * *\n");
  printf(" * * * * * * * *\n\n");
  printf("* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n* * * * * * * *\n * * * * * * * *\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ilog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L18
  mov    $0x0,%eax
  jmp    L14
L12:
  addl   $0x1,-0x4(%rbp)
  sarl   -0x14(%rbp)
L18:
  cmpl   $0x0,-0x14(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int ilog2(int n) {
  int r = -1;
  if (n <= 0)
    return (0);
  while (n) {
    r++;
    n >>= 1;
  }
  return (r);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ilog2>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  jle    L2
  mov    $0xffffffff,%eax
L3:
  add    $0x1,%eax
  sar    %edi
  jne    L3
L2:
  ret
```

assistant: ```c
int ilog2(int n) {
  int r = -1;
  if (n <= 0)
    return (0);
  while (n) {
    r++;
    n >>= 1;
  }
  return (r);
}
```
user: What is the c source code of the assembly code below?

```asm
<ilog2>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L11
  mov    $0xffffffff,%eax
  nop
L5:
  add    $0x1,%eax
  sar    %edi
  jne    L5
L11:
  ret
```

assistant: ```c
int ilog2(int n) {
  int r = -1;
  if (n <= 0)
    return (0);
  while (n) {
    r++;
    n >>= 1;
  }
  return (r);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ilog2>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L18
  mov    $0xffffffff,%eax
  nop
L5:
  add    $0x1,%eax
  sar    %edi
  jne    L5
L18:
  ret
```

assistant: ```c
int ilog2(int n) {
  int r = -1;
  if (n <= 0)
    return (0);
  while (n) {
    r++;
    n >>= 1;
  }
  return (r);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<TrioIsQualifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x39,%eax
  jg     L101
  cmp    $0x20,%eax
  jge    L28
  jmp    L80
L51:
  sub    $0x40,%eax
  movabs $0x492150044041201,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L9
  jmp    L80
L28:
  mov    %eax,%edx
  movabs $0x3ff6ccb00000000,%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L9
  jmp    L80
L101:
  cmp    $0x7a,%eax
  jg     L80
  cmp    $0x40,%eax
  jge    L51
  jmp    L80
L9:
  mov    $0x1,%eax
  jmp    L71
L80:
  mov    $0x0,%eax
L71:
  pop    %rbp
  ret
```

assistant: ```c
int TrioIsQualifier(const char character) {
  switch (character) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
  case '+':
  case '-':
  case ' ':
  case '.':
  case '*':
  case '#':
  case 'h':
  case 'l':
  case '^':
  case 'L':
  case 'z':
  case 't':
  case 'j':
  case 'q':
  case 'Z':
  case 'w':
  case '\'':
  case '!':
  case '&':
  case '@':
  case 'I':
  case 'R':
    return (!(1 == 0));
  default:
    return (1 == 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TrioIsQualifier>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x39,%dil
  jle    L13
  sub    $0x40,%ecx
  movabs $0x492150044041201,%rdx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  cmp    $0x3b,%cl
  mov    $0x0,%eax
  cmovb  %edx,%eax
  ret
L13:
  cmp    $0x1f,%dil
  jg     L1
  mov    $0x0,%eax
  ret
L1:
  movabs $0x3ff6ccb00000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int TrioIsQualifier(const char character) {
  switch (character) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
  case '+':
  case '-':
  case ' ':
  case '.':
  case '*':
  case '#':
  case 'h':
  case 'l':
  case '^':
  case 'L':
  case 'z':
  case 't':
  case 'j':
  case 'q':
  case 'Z':
  case 'w':
  case '\'':
  case '!':
  case '&':
  case '@':
  case 'I':
  case 'R':
    return (!(1 == 0));
  default:
    return (1 == 0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TrioIsQualifier>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x39,%dil
  jle    L16
  movabs $0x492150044041201,%rdx
  sub    $0x40,%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x3b,%cl
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax)
L16:
  cmp    $0x1f,%dil
  jg     L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  movabs $0x3ff6ccb00000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int TrioIsQualifier(const char character) {
  switch (character) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
  case '+':
  case '-':
  case ' ':
  case '.':
  case '*':
  case '#':
  case 'h':
  case 'l':
  case '^':
  case 'L':
  case 'z':
  case 't':
  case 'j':
  case 'q':
  case 'Z':
  case 'w':
  case '\'':
  case '!':
  case '&':
  case '@':
  case 'I':
  case 'R':
    return (!(1 == 0));
  default:
    return (1 == 0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TrioIsQualifier>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x39,%dil
  jle    L19
  movabs $0x492150044041201,%rdx
  sub    $0x40,%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x3b,%cl
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax)
L19:
  cmp    $0x1f,%dil
  jg     L2
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L2:
  movabs $0x3ff6ccb00000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int TrioIsQualifier(const char character) {
  switch (character) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
  case '+':
  case '-':
  case ' ':
  case '.':
  case '*':
  case '#':
  case 'h':
  case 'l':
  case '^':
  case 'L':
  case 'z':
  case 't':
  case 'j':
  case 'q':
  case 'Z':
  case 'w':
  case '\'':
  case '!':
  case '&':
  case '@':
  case 'I':
  case 'R':
    return (!(1 == 0));
  default:
    return (1 == 0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CmdLShift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <Pop@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <Pop@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edi
  call   <Push@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int CmdLShift(void) {
  int operand2;
  operand2 = Pop();
  Push(Pop() << operand2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CmdLShift>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <Pop@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <Pop@plt>
  mov    %ebx,%ecx
  shl    %cl,%eax
  mov    %eax,%edi
  call   <Push@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int CmdLShift(void) {
  int operand2;
  operand2 = Pop();
  Push(Pop() << operand2);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<CmdLShift>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <Pop@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <Pop@plt>
  mov    %ebx,%ecx
  shl    %cl,%eax
  mov    %eax,%edi
  call   <Push@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int CmdLShift(void) {
  int operand2;
  operand2 = Pop();
  Push(Pop() << operand2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CmdLShift>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <Pop@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <Pop@plt>
  mov    %ebx,%ecx
  shl    %cl,%eax
  mov    %eax,%edi
  call   <Push@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int CmdLShift(void) {
  int operand2;
  operand2 = Pop();
  Push(Pop() << operand2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fgetpwent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L9
L17:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fileno@plt>
  mov    %eax,%edi
  call   <__getpwent@plt>
L9:
  leave
  ret
```

assistant: ```c
struct passwd *fgetpwent(FILE *file) {
  if (file == NULL) {
    errno = EINTR;
    return NULL;
  }
  return __getpwent(fileno(file));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fgetpwent>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <fileno@plt>
  mov    %eax,%edi
  call   <__getpwent@plt>
  add    $0x8,%rsp
  ret
L9:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    %rdi,%rax
  ret
```

assistant: ```c
struct passwd *fgetpwent(FILE *file) {
  if (file == NULL) {
    errno = EINTR;
    return NULL;
  }
  return __getpwent(fileno(file));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fgetpwent>:
  endbr64
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  call   <fileno@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <__getpwent@plt>
  nopl   (%rax)
L4:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
struct passwd *fgetpwent(FILE *file) {
  if (file == NULL) {
    errno = EINTR;
    return NULL;
  }
  return __getpwent(fileno(file));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fgetpwent>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <fileno@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <__getpwent@plt>
  nopl   (%rax)
L0:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
struct passwd *fgetpwent(FILE *file) {
  if (file == NULL) {
    errno = EINTR;
    return NULL;
  }
  return __getpwent(fileno(file));
}
```