user: 请从给定的汇编指令推导出C源代码：

```asm
<toto>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L106:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L106
  sub    $0xe18,%rsp
  mov    $0xfffffffffffffe80,%rbx
  mov    $0xc,%r12d
  mov    $0x1,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x9e08(%rsp)
  xor    %eax,%eax
  lea    0x4e0(%rsp),%rax
  lea    0x1c0(%rsp),%r15
  mov    %rax,0x28(%rsp)
  mov    %rax,%r13
  sub    %r15,%rbx
  sub    %r15,%r12
  lea    0x1c4(%rsp),%rax
  lea    0x9f84(%rsp),%rbp
  mov    %r15,%r9
  mov    %rax,(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x4d4(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    0x354(%rsp),%rax
  mov    %rax,0x18(%rsp)
L115:
  lea    0x0(,%r14,4),%r15
  mov    0x20(%rsp),%rax
  mov    0x18(%rsp),%rdi
  mov    %r13,%rdx
  mov    %r15,%r10
  mov    0x28(%rsp),%rsi
  sub    %r9,%r10
  lea    0xc(%r10),%r8
  add    $0x8,%r10
L39:
  lea    (%r8,%rax,1),%r11
  lea    (%rbx,%rax,1),%rcx
  cmp    %rcx,%r11
  jle    L81
  lea    (%r10,%rax,1),%r11
  lea    (%r12,%rax,1),%rcx
  cmp    %rcx,%r11
  jl     L32
L81:
  mov    (%rdx),%r11d
  mov    %rdi,%rcx
  add    $0x2,%r11d
  movd   %r11d,%xmm0
  pshufd $0x0,%xmm0,%xmm0
  nopw   0x0(%rax,%rax,1)
L14:
  movups %xmm0,(%rcx)
  add    $0x10,%rcx
  cmp    %rax,%rcx
  jne    L14
  mov    (%rdx),%ecx
  add    $0x2,%ecx
  movd   %ecx,%xmm0
  pshufd $0xe0,%xmm0,%xmm0
  movq   %xmm0,(%rax)
  mov    (%rdx),%ecx
  add    $0x2,%ecx
  mov    %ecx,0x8(%rax)
L33:
  add    $0x190,%rax
  add    $0x190,%rdx
  add    $0x190,%rdi
  add    $0x190,%rsi
  cmp    %rbp,%rax
  jne    L39
  xor    %eax,%eax
  mov    %r9,0x8(%rsp)
  call   <bar@plt>
  mov    0x8(%rsp),%r9
  mov    %r13,%rax
  lea    0x9dcc(%r9,%r15,1),%r15
L2:
  mov    (%rax),%edi
  add    $0x190,%rax
  lea    0x2(%rdi),%edx
  mov    %edx,-0x31c(%rax)
  cmp    %r15,%rax
  jne    L2
  xor    %eax,%eax
  mov    %r9,0x8(%rsp)
  call   <bar@plt>
  mov    0x8(%rsp),%r9
  mov    %r13,%rax
L42:
  mov    (%rax),%edi
  add    $0x190,%rax
  lea    0x2(%rdi),%edx
  mov    %edx,-0x31c(%rax)
  cmp    %r15,%rax
  jne    L42
  mov    (%rsp),%rax
  mov    0x10(%rsp),%rdi
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  add    $0x2,%eax
  mov    %eax,(%rdi,%r14,4)
  mov    %r13,%rax
L29:
  mov    (%rax),%edi
  add    $0x190,%rax
  lea    0x2(%rdi),%edx
  mov    %edx,-0x31c(%rax)
  cmp    %r15,%rax
  jne    L29
  add    $0x1,%r14
  addq   $0x194,(%rsp)
  add    $0x4,%r13
  cmp    $0x64,%r14
  jne    L115
  mov    0x34(%rsp),%eax
  add    0x684(%rsp),%eax
  mov    0x9e08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x9e18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L118:
  mov    (%rdx),%r11d
  add    $0x4,%rcx
  add    $0x2,%r11d
  mov    %r11d,-0x4(%rcx)
  cmp    %rsi,%rcx
  jne    L118
  jmp    L33
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto() {
  int i, j, k;
  int a[100][100];
  int b[100];
  for (i = 1; i < 100; i++) {
    for (j = 1; j < 100; j++)
      for (k = 1; k < 100; k++)
        a[j][k] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
    bar();
    for (j = 1; j < 100; j++)
      a[j][i] = a[j + 1][i - 1] + 2;
    b[i] = b[i - 1] + 2;
    bar();
    for (j = 1; j < 100; j++)
      a[j][i] = a[j + 1][i - 1] + 2;
    b[i] = a[i - 1][i] + 2;
    for (j = 1; j < 100; j++)
      a[j][i] = a[j + 1][i - 1] + 2;
  }
  return a[3][5] + b[1];
}
```