user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x5,%ecx
  lea    D1(%rip),%r15
  push   %r14
  lea    D91(%rip),%r14
  push   %r13
  lea    D46(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x98,%rsp
  movaps D86(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rbp
  lea    0x50(%rsp),%rax
  movl   $0x3f000000,0x44(%rsp)
  movups %xmm0,0x34(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rax,%rdi
  mov    %rbp,%rdx
  movaps D52(%rip),%xmm0
  mov    %rax,0x8(%rsp)
  mov    %r12,%rsi
  xor    %eax,%eax
  movl   $0x3de38e39,0x74(%rsp)
  movups %xmm0,0x54(%rsp)
  movaps D24(%rip),%xmm0
  movups %xmm0,0x64(%rsp)
  call   <toeplz@plt>
  lea    D102(%rip),%rdi
  call   <puts@plt>
L14:
  pxor   %xmm0,%xmm0
  mov    %ebx,%edx
  mov    %r15,%rcx
  mov    %r14,%rsi
  cvtss2sd (%r12,%rbx,4),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  jne    L14
  lea    D16(%rip),%rdi
  lea    0x64(%rsp),%r13
  call   <puts@plt>
  lea    D41(%rip),%rdx
  lea    D62(%rip),%rsi
  xor    %eax,%eax
  lea    D103(%rip),%rdi
  lea    D99(%rip),%r12
  call   <printf@plt>
  mov    0x8(%rsp),%rbx
L17:
  movss  0x14(%rbx),%xmm0
  pxor   %xmm2,%xmm2
  mov    %r12,%rdi
  add    $0x4,%rbx
  mulss  0x14(%rsp),%xmm0
  movss  0xc(%rbx),%xmm1
  mov    $0x2,%eax
  add    $0x4,%rbp
  mulss  0x18(%rsp),%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  0x8(%rbx),%xmm0
  mulss  0x1c(%rsp),%xmm0
  addss  %xmm1,%xmm0
  movss  0x4(%rbx),%xmm1
  mulss  0x20(%rsp),%xmm1
  addss  %xmm0,%xmm1
  movss  (%rbx),%xmm0
  mulss  0x24(%rsp),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x0(%rbp),%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L17
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D91
datatype: string
name: extract_symbolic_data
arguments: data_label: D46
datatype: string
name: extract_symbolic_data
arguments: data_label: D86
datatype: f32[4]
name: extract_symbolic_data
arguments: data_label: D52
datatype: f32[4]
name: extract_symbolic_data
arguments: data_label: D24
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D102
datatype: string
name: extract_symbolic_data
arguments: data_label: D16
datatype: string
name: extract_symbolic_data
arguments: data_label: D41
datatype: string
name: extract_symbolic_data
arguments: data_label: D62
datatype: string
name: extract_symbolic_data
arguments: data_label: D103
datatype: string
name: extract_symbolic_data
arguments: data_label: D99
datatype: string

tool: D1: ] =

tool: D91: x[

tool: D46: %7s%1d%s %13f


tool: {"D86": [0.10000000149011612,0.20000000298023224,0.30000001192092896,0.4000000059604645]}

tool: {"D52": [1.0,0.5,0.3333333432674408,0.25]}

tool: {"D24": [0xcd,0xcc,0x4c,0x3e,0xab,0xaa,0x2a,0x3e,0x25,0x49,0x12,0x3e,0x00,0x00,0x00,0x3e]}

tool: D102: Solution vector:

tool: D16: 
Test of solution:

tool: D41: original

tool: D62: mtrx*soln

tool: D103: %13s %12s


tool: D99: %12.4f %12.4f


assistant: ```c
int main(void) {
  int i, j;
  float sum, r[(2 * 5) + 1], x[5 + 1], y[5 + 1];
  for (i = 1; i <= 5; i++)
    y[i] = 0.1 * i;
  for (i = 1; i < (2 * 5); i++)
    r[i] = 1.0 / i;
  toeplz(r, x, y, 5);
  printf("Solution vector:\n");
  for (i = 1; i <= 5; i++)
    printf("%7s%1d%s %13f\n", "x[", i, "] =", x[i]);
  printf("\nTest of solution:\n");
  printf("%13s %12s\n", "mtrx*soln", "original");
  for (i = 1; i <= 5; i++) {
    sum = 0.0;
    for (j = 1; j <= 5; j++)
      sum += (r[5 + i - j] * x[j]);
    printf("%12.4f %12.4f\n", sum, y[i]);
  }
  return 0;
}
```