ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xfa0,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    $0x0,%eax
L12:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0x3e8,%eax
  jne    L12
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L4:
  mov    %eax,(%rbx)
  sub    $0x1,%eax
  add    $0x4,%rbx
  cmp    $0xfffffc18,%eax
  jne    L4
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D11: finish setting H label!


tool: D16: finish setting L label!


assistant: ```c
int main() {
  int i;
  int *buffer;
  buffer = (int *)malloc(sizeof(int) * 1000);
  int *set_label_l = (int *)0x80000000;
  int *set_label_h = (int *)0x80000001;
  i = *set_label_h;
  for (i = 0; i < 1000; i++)
    buffer[i] = i;
  printf("finish setting H label!\n");
  i = *set_label_l;
  for (i = 0; i < 1000; i++)
    buffer[i] = -i;
  printf("finish setting L label!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xfa0,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0x3e8,%eax
  jne    L2
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  xchg   %ax,%ax
L16:
  mov    %eax,(%rbx)
  sub    $0x1,%eax
  add    $0x4,%rbx
  cmp    $0xfffffc18,%eax
  jne    L16
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string

tool: D6: finish setting H label!


tool: D12: finish setting L label!


assistant: ```c
int main() {
  int i;
  int *buffer;
  buffer = (int *)malloc(sizeof(int) * 1000);
  int *set_label_l = (int *)0x80000000;
  int *set_label_h = (int *)0x80000001;
  i = *set_label_h;
  for (i = 0; i < 1000; i++)
    buffer[i] = i;
  printf("finish setting H label!\n");
  i = *set_label_l;
  for (i = 0; i < 1000; i++)
    buffer[i] = -i;
  printf("finish setting L label!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xfa0,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  movdqa D13(%rip),%xmm0
  movdqa D48(%rip),%xmm2
  mov    %rax,%rbx
  lea    0xfa0(%rax),%rbp
  movdqa %xmm0,%xmm1
  nopw   0x0(%rax,%rax,1)
L11:
  movdqa %xmm1,%xmm3
  add    $0x10,%rax
  paddd  %xmm2,%xmm1
  movups %xmm3,-0x10(%rax)
  cmp    %rbp,%rax
  jne    L11
  lea    D26(%rip),%rdi
  call   <printf@plt>
  movdqa D13(%rip),%xmm0
  pxor   %xmm4,%xmm4
  movdqa D48(%rip),%xmm2
  nopl   (%rax)
L9:
  movdqa %xmm0,%xmm3
  movdqa %xmm4,%xmm1
  paddd  %xmm2,%xmm0
  add    $0x10,%rbx
  psubd  %xmm3,%xmm1
  movups %xmm1,-0x10(%rbx)
  cmp    %rbp,%rbx
  jne    L9
  lea    D22(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: byte[16]
name: unpack_data
arguments: tag: D48
type_guessed: byte[16]
name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D22
type_guessed: string

tool: {"D13": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D48": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D26: finish setting H label!


tool: D22: finish setting L label!


assistant: ```c
int main() {
  int i;
  int *buffer;
  buffer = (int *)malloc(sizeof(int) * 1000);
  int *set_label_l = (int *)0x80000000;
  int *set_label_h = (int *)0x80000001;
  i = *set_label_h;
  for (i = 0; i < 1000; i++)
    buffer[i] = i;
  printf("finish setting H label!\n");
  i = *set_label_l;
  for (i = 0; i < 1000; i++)
    buffer[i] = -i;
  printf("finish setting L label!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D35
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D60
type: string
name: extract_symbolic_data
arguments: data_label: D59
type: string
name: extract_symbolic_data
arguments: data_label: D30
type: string
name: extract_symbolic_data
arguments: data_label: D52
type: string
name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D35: Hello world!

tool: D0: Now reading uninitialized memory

tool: D60: Did you notice? (value was %i)


tool: D59: (No memory leak here)

tool: D30: Now writing to uninitialized pointer

tool: D52: Did you notice?

tool: D7: There should be 2 errors in this run

assistant: ```c
int main() {
  printf("Hello world!\n");
  int *pI = (int *)malloc(sizeof(int));
  int j;
  printf("Now reading uninitialized memory\n");
  j = *pI + 2;
  printf("Did you notice? (value was %i)\n", j);
  free(pI);
  printf("(No memory leak here)\n");
  int *pJ;
  printf("Now writing to uninitialized pointer\n");
  *pJ = j;
  printf("Did you notice?\n");
  printf("There should be 2 errors in this run\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D68(%rip),%rdi
  call   <puts@plt>
  mov    0x0(%rbp),%eax
  lea    0x2(%rax),%ebx
  mov    %ebx,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,0x0
  lea    D53(%rip),%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D37
data_type: string
name: unpack_data
arguments: data_tag: D68
data_type: string
name: unpack_data
arguments: data_tag: D59
data_type: string
name: unpack_data
arguments: data_tag: D34
data_type: string
name: unpack_data
arguments: data_tag: D19
data_type: string
name: unpack_data
arguments: data_tag: D53
data_type: string
name: unpack_data
arguments: data_tag: D25
data_type: string

tool: D37: Hello world!

tool: D68: Now reading uninitialized memory

tool: D59: Did you notice? (value was %i)


tool: D34: (No memory leak here)

tool: D19: Now writing to uninitialized pointer

tool: D53: Did you notice?

tool: D25: There should be 2 errors in this run

assistant: ```c
int main() {
  printf("Hello world!\n");
  int *pI = (int *)malloc(sizeof(int));
  int j;
  printf("Now reading uninitialized memory\n");
  j = *pI + 2;
  printf("Did you notice? (value was %i)\n", j);
  free(pI);
  printf("(No memory leak here)\n");
  int *pJ;
  printf("Now writing to uninitialized pointer\n");
  *pJ = j;
  printf("Did you notice?\n");
  printf("There should be 2 errors in this run\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D50(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    D41(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  mov    0x0(%rbp),%eax
  lea    D65(%rip),%rdi
  lea    0x2(%rax),%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,0x0
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D50
datatype: string
name: extract_symbolic_data
arguments: tag: D41
datatype: string
name: extract_symbolic_data
arguments: tag: D65
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D39
datatype: string
name: extract_symbolic_data
arguments: tag: D40
datatype: string
name: extract_symbolic_data
arguments: tag: D16
datatype: string

tool: D50: Hello world!

tool: D41: Now reading uninitialized memory

tool: D65: Did you notice? (value was %i)


tool: D19: (No memory leak here)

tool: D39: Now writing to uninitialized pointer

tool: D40: Did you notice?

tool: D16: There should be 2 errors in this run

assistant: ```c
int main() {
  printf("Hello world!\n");
  int *pI = (int *)malloc(sizeof(int));
  int j;
  printf("Now reading uninitialized memory\n");
  j = *pI + 2;
  printf("Did you notice? (value was %i)\n", j);
  free(pI);
  printf("(No memory leak here)\n");
  int *pJ;
  printf("Now writing to uninitialized pointer\n");
  *pJ = j;
  printf("Did you notice?\n");
  printf("There should be 2 errors in this run\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D37(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  mov    0x0(%rbp),%eax
  lea    D19(%rip),%rdi
  lea    0x2(%rax),%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,0x0
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D37
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D19
datatype: string
name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D56
datatype: string
name: parse_data
arguments: data_label: D35
datatype: string
name: parse_data
arguments: data_label: D27
datatype: string

tool: D37: Hello world!

tool: D10: Now reading uninitialized memory

tool: D19: Did you notice? (value was %i)


tool: D13: (No memory leak here)

tool: D56: Now writing to uninitialized pointer

tool: D35: Did you notice?

tool: D27: There should be 2 errors in this run

assistant: ```c
int main() {
  printf("Hello world!\n");
  int *pI = (int *)malloc(sizeof(int));
  int j;
  printf("Now reading uninitialized memory\n");
  j = *pI + 2;
  printf("Did you notice? (value was %i)\n", j);
  free(pI);
  printf("(No memory leak here)\n");
  int *pJ;
  printf("Now writing to uninitialized pointer\n");
  *pJ = j;
  printf("Did you notice?\n");
  printf("There should be 2 errors in this run\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x8,-0x2c(%rbp)
  jg     L17
  mov    $0x0,%eax
  jmp    L18
L17:
  lea    -0x12(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L68
L4:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  cmp    $0x1,%al
  jg     L65
  movzbl -0x12(%rbp),%eax
  cmp    $0x1,%al
  jne    L36
L65:
  mov    $0x0,%eax
  jmp    L18
L36:
  addl   $0x1,-0x1c(%rbp)
L68:
  cmpl   $0x9,-0x1c(%rbp)
  jne    L4
  mov    $0x1,%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
bool isPand(char *xs, int len) {
  if (len < 9) {
    return false;
  }
  char d[9 + 1];
  memset(d, 0, 9 + 1);
  int i;
  for (i = 0; i != 9; i++) {
    int idx = xs[i];
    d[idx]++;
    if (d[idx] > 1 || d[0] == 1) {
      return false;
    }
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isPand>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x8,%esi
  jg     L37
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L72
  add    $0x20,%rsp
  pop    %rbx
  ret
L37:
  mov    %rdi,%rbx
  lea    0xe(%rsp),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbx,%rdx
  lea    0x9(%rbx),%rdi
L33:
  movsbq (%rdx),%rcx
  movzbl 0xe(%rsp,%rcx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rcx,1)
  cmp    $0x1,%al
  jg     L76
  cmpb   $0x1,0xe(%rsp)
  je     L74
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L33
  mov    $0x1,%eax
  jmp    L10
L76:
  mov    $0x0,%eax
  jmp    L10
L74:
  mov    $0x0,%eax
  jmp    L10
L72:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isPand(char *xs, int len) {
  if (len < 9) {
    return false;
  }
  char d[9 + 1];
  memset(d, 0, 9 + 1);
  int i;
  for (i = 0; i != 9; i++) {
    int idx = xs[i];
    d[idx]++;
    if (d[idx] > 1 || d[0] == 1) {
      return false;
    }
  }
  return true;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isPand>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x8,%esi
  jg     L35
L10:
  xor    %eax,%eax
L18:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x20,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    %rdi,%rbx
  mov    $0xa,%edx
  lea    0xe(%rsp),%rdi
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rbx,%rdi
  lea    0x9(%rbx),%rcx
  nopl   0x0(%rax,%rax,1)
L37:
  movsbq (%rdi),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L10
  cmpb   $0x1,0xe(%rsp)
  je     L10
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L37
  mov    $0x1,%eax
  jmp    L18
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isPand(char *xs, int len) {
  if (len < 9) {
    return false;
  }
  char d[9 + 1];
  memset(d, 0, 9 + 1);
  int i;
  for (i = 0; i != 9; i++) {
    int idx = xs[i];
    d[idx]++;
    if (d[idx] > 1 || d[0] == 1) {
      return false;
    }
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isPand>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x8,%esi
  jg     L134
L62:
  xor    %eax,%eax
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L134:
  mov    %rdi,%rbx
  mov    $0xa,%edx
  lea    0xe(%rsp),%rdi
  xor    %esi,%esi
  call   <memset@plt>
  movsbq (%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  je     L62
  movsbq 0x1(%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  je     L62
  movsbq 0x2(%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  je     L62
  movsbq 0x3(%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  je     L62
  movsbq 0x4(%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  je     L62
  movsbq 0x5(%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  je     L62
  movsbq 0x6(%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  je     L62
  movsbq 0x7(%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  je     L62
  movsbq 0x8(%rbx),%rdx
  movzbl 0xe(%rsp,%rdx,1),%eax
  add    $0x1,%eax
  mov    %al,0xe(%rsp,%rdx,1)
  cmp    $0x1,%al
  jg     L62
  cmpb   $0x1,0xe(%rsp)
  mov    $0x1,%eax
  jne    L9
  jmp    L62
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isPand(char *xs, int len) {
  if (len < 9) {
    return false;
  }
  char d[9 + 1];
  memset(d, 0, 9 + 1);
  int i;
  for (i = 0; i != 9; i++) {
    int idx = xs[i];
    d[idx]++;
    if (d[idx] > 1 || d[0] == 1) {
      return false;
    }
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0xa,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <insertionSort@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main() {
  int arr[] = {4, 1, 8, 10, 5, 2, 3, 6};
  printArray(arr, 8);
  insertionSort(arr, 8);
  printArray(arr, 8);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0xa,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  mov    %rsp,%rbx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <insertionSort@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int arr[] = {4, 1, 8, 10, 5, 2, 3, 6};
  printArray(arr, 8);
  insertionSort(arr, 8);
  printArray(arr, 8);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x8,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x100000004,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0xa00000008,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x200000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x18(%rsp)
  call   <printArray@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <insertionSort@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int arr[] = {4, 1, 8, 10, 5, 2, 3, 6};
  printArray(arr, 8);
  insertionSort(arr, 8);
  printArray(arr, 8);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x8,%esi
  sub    $0x30,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movdqa D11(%rip),%xmm0
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <printArray@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <insertionSort@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: byte[16]
name: extract_symbolic_data
arguments: tag: D11
type_infered: byte[16]

tool: {"D6": [0x04,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D11": [0x05,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int arr[] = {4, 1, 8, 10, 5, 2, 3, 6};
  printArray(arr, 8);
  insertionSort(arr, 8);
  printArray(arr, 8);
  return 0;
}
```