ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D65(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    $0x0,%eax
  cmp    $0x186a0,%esi
  jle    L19
  lea    -0x186a1(%rsi),%eax
  cmp    $0xc34f,%eax
  ja     L27
  lea    -0x186a0(%rsi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D6(%rip),%xmm0
  addsd  D4(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L19:
  sub    %eax,%esi
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L27:
  lea    -0x249f0(%rsi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D51(%rip),%xmm0
  addsd  D32(%rip),%xmm0
  addsd  D4(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L19
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D65
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: f64
name: retrieve_data
arguments: data_tag: D4
type_guessed: byte[8]
name: retrieve_data
arguments: data_tag: D56
type_guessed: string
name: retrieve_data
arguments: data_tag: D51
type_guessed: f64
name: retrieve_data
arguments: data_tag: D32
type_guessed: byte[8]

tool: D17: Enter your salary: 

tool: D65: %d

tool: D6: 0.15

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D56: 
The net salary is %d

tool: D51: 0.25

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x4c,0xbd,0x40]}

assistant: ```c
int main(void) {
  int salary, tax;
  printf("Enter your salary: ");
  scanf("%d", &salary);
  if (salary <= 100000)
    tax = salary * 0;
  else if (salary > 100000 && salary <= 150000)
    tax = (salary - 100000) * 0.15 + 100000 * 0;
  else
    tax = (salary - 150000) * 0.25 + (150000 - 100000) * 0.15 + 100000 * 0;
  printf("\nThe net salary is %d", salary - tax);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  cmp    $0x186a0,%esi
  jle    L26
  lea    -0x186a1(%rsi),%eax
  cmp    $0xc34f,%eax
  ja     L6
  lea    -0x186a0(%rsi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D48(%rip),%xmm0
  addsd  D45(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L26:
  sub    %eax,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  lea    -0x249f0(%rsi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D22(%rip),%xmm0
  addsd  D53(%rip),%xmm0
  addsd  D45(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L26
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D48
data_type: f64
name: parse_data
arguments: data_label: D45
data_type: byte[8]
name: parse_data
arguments: data_label: D6
data_type: string
name: parse_data
arguments: data_label: D22
data_type: f64
name: parse_data
arguments: data_label: D53
data_type: byte[8]

tool: D19: Enter your salary: 

tool: D12: %d

tool: D48: 0.15

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D6: 
The net salary is %d

tool: D22: 0.25

tool: {"D53": [0x00,0x00,0x00,0x00,0x00,0x4c,0xbd,0x40]}

assistant: ```c
int main(void) {
  int salary, tax;
  printf("Enter your salary: ");
  scanf("%d", &salary);
  if (salary <= 100000)
    tax = salary * 0;
  else if (salary > 100000 && salary <= 150000)
    tax = (salary - 100000) * 0.15 + 100000 * 0;
  else
    tax = (salary - 150000) * 0.25 + (150000 - 100000) * 0.15 + 100000 * 0;
  printf("\nThe net salary is %d", salary - tax);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  cmp    $0x186a0,%esi
  jle    L24
  lea    -0x186a1(%rsi),%eax
  cmp    $0xc34f,%eax
  ja     L35
  lea    -0x186a0(%rsi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D28(%rip),%xmm0
  addsd  D68(%rip),%xmm0
  cvttsd2si %xmm0,%eax
L24:
  sub    %eax,%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L35:
  lea    -0x249f0(%rsi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D36(%rip),%xmm0
  addsd  D10(%rip),%xmm0
  addsd  D68(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L24
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
data_type: string
name: extract_symbolic_data
arguments: data_label: D41
data_type: string
name: extract_symbolic_data
arguments: data_label: D28
data_type: f64
name: extract_symbolic_data
arguments: data_label: D68
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D25
data_type: string
name: extract_symbolic_data
arguments: data_label: D36
data_type: f64
name: extract_symbolic_data
arguments: data_label: D10
data_type: byte[8]

tool: D27: Enter your salary: 

tool: D41: %d

tool: D28: 0.15

tool: {"D68": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D25: 
The net salary is %d

tool: D36: 0.25

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x4c,0xbd,0x40]}

assistant: ```c
int main(void) {
  int salary, tax;
  printf("Enter your salary: ");
  scanf("%d", &salary);
  if (salary <= 100000)
    tax = salary * 0;
  else if (salary > 100000 && salary <= 150000)
    tax = (salary - 100000) * 0.15 + 100000 * 0;
  else
    tax = (salary - 150000) * 0.25 + (150000 - 100000) * 0.15 + 100000 * 0;
  printf("\nThe net salary is %d", salary - tax);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x4,-0x4(%rbp)
  jle    L16
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  for (int i = 0; i < 5; i++) {
    printf(argv[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    0x28(%rsi),%rbp
L3:
  mov    (%rbx),%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L3
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  for (int i = 0; i < 5; i++) {
    printf(argv[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    0x28(%rsi),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
L9:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  for (int i = 0; i < 5; i++) {
    printf(argv[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    0x28(%rsi),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
L5:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  for (int i = 0; i < 5; i++) {
    printf(argv[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<name_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L17
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  jmp    L25
L17:
  nop
L25:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int name_in(char *name, char **a, int max) {
  int result = 0, i;
  for (i = 0; i < max; i++) {
    result = (strcmp(name, a[i]) == 0);
    if (result)
      break;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<name_in>:
  endbr64
  test   %edx,%edx
  jle    L16
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rsi,%rax,8),%r12
L13:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L14
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L13
  mov    $0x0,%eax
  jmp    L24
L16:
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int name_in(char *name, char **a, int max) {
  int result = 0, i;
  for (i = 0; i < max; i++) {
    result = (strcmp(name, a[i]) == 0);
    if (result)
      break;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<name_in>:
  endbr64
  test   %edx,%edx
  jle    L20
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L26
  nopl   0x0(%rax)
L3:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L4
L26:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L3
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int name_in(char *name, char **a, int max) {
  int result = 0, i;
  for (i = 0; i < max; i++) {
    result = (strcmp(name, a[i]) == 0);
    if (result)
      break;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<name_in>:
  endbr64
  test   %edx,%edx
  jle    L34
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L2
  nopl   0x0(%rax)
L30:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L25
L2:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L30
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int name_in(char *name, char **a, int max) {
  int result = 0, i;
  for (i = 0; i < max; i++) {
    result = (strcmp(name, a[i]) == 0);
    if (result)
      break;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x18(%rbp)
  movl   $0x80,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L22:
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L25:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  imul   $0xe,%eax,%eax
  add    %ecx,%eax
  imul   %edx,%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L25
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L22
  mov    -0x18(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string

tool: D9:  %d %d %d


assistant: ```c
int main() {
  int sum = 0;
  int a, b, A, B, N;
  N = 128;
  A = 1;
  B = 1;
  for (a = 0; a < A; a++)
    for (b = 0; b < B; b++)
      sum += (b + 1) * (N * (N - 1) / 2 + 14 * a * N);
  printf(" %d %d %d\n", A, B, sum);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1fc0,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3:  %d %d %d


assistant: ```c
int main() {
  int sum = 0;
  int a, b, A, B, N;
  N = 128;
  A = 1;
  B = 1;
  for (a = 0; a < A; a++)
    for (b = 0; b < B; b++)
      sum += (b + 1) * (N * (N - 1) / 2 + 14 * a * N);
  printf(" %d %d %d\n", A, B, sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1fc0,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2:  %d %d %d


assistant: ```c
int main() {
  int sum = 0;
  int a, b, A, B, N;
  N = 128;
  A = 1;
  B = 1;
  for (a = 0; a < A; a++)
    for (b = 0; b < B; b++)
      sum += (b + 1) * (N * (N - 1) / 2 + 14 * a * N);
  printf(" %d %d %d\n", A, B, sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1fc0,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1:  %d %d %d


assistant: ```c
int main() {
  int sum = 0;
  int a, b, A, B, N;
  N = 128;
  A = 1;
  B = 1;
  for (a = 0; a < A; a++)
    for (b = 0; b < B; b++)
      sum += (b + 1) * (N * (N - 1) / 2 + 14 * a * N);
  printf(" %d %d %d\n", A, B, sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L25
  mov    $0x1,%edi
  call   <close@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <dup@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%edx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <execlp@plt>
  jmp    L27
L25:
  mov    $0x0,%edi
  call   <close@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <dup@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <execlp@plt>
L27:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string
name: unpack_data
arguments: label: D13
datatype: string

tool: D0: ls

tool: D13: wc

assistant: ```c
int main() {
  int pd[2];
  pipe(pd);
  if (fork()) {
    close(1);
    dup(pd[1]);
    close(pd[0]);
    close(pd[1]);
    execlp("ls", "ls", (char *)NULL);
  } else {
    close(0);
    dup(pd[0]);
    close(pd[0]);
    close(pd[1]);
    execlp("wc", "wc", (char *)NULL);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <pipe@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L7
  mov    $0x1,%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <dup@plt>
  mov    (%rsp),%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <close@plt>
  mov    $0x0,%edx
  lea    D12(%rip),%rdi
  mov    %rdi,%rsi
  call   <execlp@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  mov    $0x0,%edi
  call   <close@plt>
  mov    (%rsp),%edi
  call   <dup@plt>
  mov    (%rsp),%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <close@plt>
  mov    $0x0,%edx
  lea    D13(%rip),%rdi
  mov    %rdi,%rsi
  call   <execlp@plt>
  jmp    L5
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string

tool: D12: ls

tool: D13: wc

assistant: ```c
int main() {
  int pd[2];
  pipe(pd);
  if (fork()) {
    close(1);
    dup(pd[1]);
    close(pd[0]);
    close(pd[1]);
    execlp("ls", "ls", (char *)NULL);
  } else {
    close(0);
    dup(pd[0]);
    close(pd[0]);
    close(pd[1]);
    execlp("wc", "wc", (char *)NULL);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <pipe@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L26
  mov    $0x1,%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <dup@plt>
  mov    (%rsp),%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <close@plt>
  lea    D18(%rip),%rdi
  xor    %edx,%edx
  mov    %rdi,%rsi
  call   <execlp@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L26:
  xor    %edi,%edi
  call   <close@plt>
  mov    (%rsp),%edi
  call   <dup@plt>
  mov    (%rsp),%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <close@plt>
  lea    D8(%rip),%rdi
  xor    %edx,%edx
  mov    %rdi,%rsi
  call   <execlp@plt>
  jmp    L15
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
type: string
name: read_data
arguments: data_label: D8
type: string

tool: D18: ls

tool: D8: wc

assistant: ```c
int main() {
  int pd[2];
  pipe(pd);
  if (fork()) {
    close(1);
    dup(pd[1]);
    close(pd[0]);
    close(pd[1]);
    execlp("ls", "ls", (char *)NULL);
  } else {
    close(0);
    dup(pd[0]);
    close(pd[0]);
    close(pd[1]);
    execlp("wc", "wc", (char *)NULL);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <pipe@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L3
  mov    $0x1,%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <dup@plt>
  mov    (%rsp),%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <close@plt>
  lea    D10(%rip),%rdi
  xor    %edx,%edx
  mov    %rdi,%rsi
  call   <execlp@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  xor    %edi,%edi
  call   <close@plt>
  mov    (%rsp),%edi
  call   <dup@plt>
  mov    (%rsp),%edi
  call   <close@plt>
  mov    0x4(%rsp),%edi
  call   <close@plt>
  lea    D5(%rip),%rdi
  xor    %edx,%edx
  mov    %rdi,%rsi
  call   <execlp@plt>
  jmp    L24
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D10: ls

tool: D5: wc

assistant: ```c
int main() {
  int pd[2];
  pipe(pd);
  if (fork()) {
    close(1);
    dup(pd[1]);
    close(pd[0]);
    close(pd[1]);
    execlp("ls", "ls", (char *)NULL);
  } else {
    close(0);
    dup(pd[0]);
    close(pd[0]);
    close(pd[1]);
    execlp("wc", "wc", (char *)NULL);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sqfs_gen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  lea    D35(%rip),%r8
  lea    D14(%rip),%rdx
  mov    %rdx,%rcx
  lea    D64(%rip),%rdx
  lea    D43(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <abms_system@plt>
  lea    -0x110(%rbp),%rax
  sub    $0x8,%rsp
  lea    D89(%rip),%rdx
  push   %rdx
  lea    D35(%rip),%r9
  lea    D91(%rip),%r8
  lea    D8(%rip),%rdx
  mov    %rdx,%rcx
  lea    D64(%rip),%rdx
  lea    D28(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  add    $0x10,%rsp
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <abms_system@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D35
type: string
name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D64
type: string
name: retrieve_data
arguments: tag: D43
type: string
name: retrieve_data
arguments: tag: D89
type: string
name: retrieve_data
arguments: tag: D91
type: string
name: retrieve_data
arguments: tag: D8
type: string
name: retrieve_data
arguments: tag: D28
type: string

tool: D35: /app/os/images/

tool: D14: mkdir

tool: D64: /app/os/sys/bin/

tool: D43: %s%s %s

tool: D89: abms.sqfs

tool: D91: /app/os/sys/

tool: D8: mksquashfs

tool: D28: %s%s %s %s%s

assistant: ```c
void sqfs_gen(void) {
  char lcmd[255];
  sprintf(lcmd, "%s%s %s", "/app/os/sys/bin/", "mkdir", "/app/os/images/");
  abms_system(lcmd);
  sprintf(lcmd, "%s%s %s %s%s", "/app/os/sys/bin/", "mksquashfs", "/app/os/sys/", "/app/os/images/", "abms.sqfs");
  abms_system(lcmd);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sqfs_gen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D28(%rip),%r8
  lea    D17(%rip),%rcx
  lea    D22(%rip),%rbp
  mov    %rbp,%rdx
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <abms_system@plt>
  sub    $0x8,%rsp
  lea    D3(%rip),%rax
  push   %rax
  lea    D28(%rip),%r9
  lea    D70(%rip),%r8
  lea    D87(%rip),%rcx
  mov    %rbp,%rdx
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <abms_system@plt>
  mov    %rbx,%rsp
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D22
type: string
name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D70
type: string
name: unpack_data
arguments: tag: D87
type: string
name: unpack_data
arguments: tag: D11
type: string

tool: D28: /app/os/images/

tool: D17: mkdir

tool: D22: /app/os/sys/bin/

tool: D14: %s%s %s

tool: D3: abms.sqfs

tool: D70: /app/os/sys/

tool: D87: mksquashfs

tool: D11: %s%s %s %s%s

assistant: ```c
void sqfs_gen(void) {
  char lcmd[255];
  sprintf(lcmd, "%s%s %s", "/app/os/sys/bin/", "mkdir", "/app/os/images/");
  abms_system(lcmd);
  sprintf(lcmd, "%s%s %s %s%s", "/app/os/sys/bin/", "mksquashfs", "/app/os/sys/", "/app/os/images/", "abms.sqfs");
  abms_system(lcmd);
  return;
}
```