ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sock_ntop_host>:
  endbr64
  push   %rbx
  mov    (%rdi),%ecx
  cmp    $0x80,%ecx
  je     L10
  cmp    $0x81,%ecx
  jne    L21
  lea    D65(%rip),%rbx
  mov    %rdi,%rsi
  mov    $0x80,%ecx
  mov    $0x81,%edi
  mov    %rbx,%rdx
  call   <inet_ntop@plt>
  test   %rax,%rax
  cmovne %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L10:
  mov    (%rdi),%rcx
  cmpb   $0x0,(%rcx)
  jne    L0
  lea    D65(%rip),%rbx
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  lea    D65(%rip),%rbx
  mov    %esi,%r8d
  lea    D20(%rip),%rdx
  xor    %eax,%eax
  mov    %rbx,%rdi
  mov    $0x80,%esi
  call   <snprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L0:
  lea    D65(%rip),%rbx
  lea    D42(%rip),%rdx
  mov    $0x80,%esi
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D42
type_guessed: string

tool: D18: (no pathname bound)

tool: D20: sock_ntop_host: unknown AF_xxx: %d, len %d

tool: D42: %s

assistant: ```c
char *sock_ntop_host(const struct sockaddr *sa, socklen_t salen) {
  static char str[128];
  switch (sa->sa_family) {
  case AF_INET: {
    struct sockaddr_in *sin = (struct sockaddr_in *)sa;
    if (inet_ntop(AF_INET, &sin->sin_addr, str, sizeof(str)) == NULL) {
      return NULL;
    } else {
      return str;
    }
  }
  case AF_UNIX: {
    struct sockaddr_un *unp = (struct sockaddr_un *)sa;
    if (unp->sun_path[0] == 0)
      strcpy(str, "(no pathname bound)");
    else
      snprintf(str, sizeof(str), "%s", unp->sun_path);
    return str;
  }
  default:
    snprintf(str, sizeof(str), "sock_ntop_host: unknown AF_xxx: %d, len %d", sa->sa_family, salen);
    return str;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sock_ntop_host>:
  endbr64
  push   %rbx
  mov    (%rdi),%ecx
  cmp    $0x80,%ecx
  je     L21
  cmp    $0x81,%ecx
  jne    L3
  lea    D22(%rip),%rbx
  mov    %rdi,%rsi
  mov    $0x80,%ecx
  mov    $0x81,%edi
  mov    %rbx,%rdx
  call   <inet_ntop@plt>
  test   %rax,%rax
  cmovne %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L21:
  mov    (%rdi),%rcx
  cmpb   $0x0,(%rcx)
  jne    L24
  lea    D22(%rip),%rbx
  lea    D53(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  lea    D22(%rip),%rbx
  mov    %esi,%r8d
  lea    D58(%rip),%rdx
  xor    %eax,%eax
  mov    %rbx,%rdi
  mov    $0x80,%esi
  call   <snprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L24:
  lea    D22(%rip),%rbx
  lea    D26(%rip),%rdx
  mov    $0x80,%esi
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D53
data_type: string
name: parse_data
arguments: label: D58
data_type: string
name: parse_data
arguments: label: D26
data_type: string

tool: D53: (no pathname bound)

tool: D58: sock_ntop_host: unknown AF_xxx: %d, len %d

tool: D26: %s

assistant: ```c
char *sock_ntop_host(const struct sockaddr *sa, socklen_t salen) {
  static char str[128];
  switch (sa->sa_family) {
  case AF_INET: {
    struct sockaddr_in *sin = (struct sockaddr_in *)sa;
    if (inet_ntop(AF_INET, &sin->sin_addr, str, sizeof(str)) == NULL) {
      return NULL;
    } else {
      return str;
    }
  }
  case AF_UNIX: {
    struct sockaddr_un *unp = (struct sockaddr_un *)sa;
    if (unp->sun_path[0] == 0)
      strcpy(str, "(no pathname bound)");
    else
      snprintf(str, sizeof(str), "%s", unp->sun_path);
    return str;
  }
  default:
    snprintf(str, sizeof(str), "sock_ntop_host: unknown AF_xxx: %d, len %d", sa->sa_family, salen);
    return str;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap_32_bit_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl 0x3(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_32_bit_val(void *ptr) {
  char *tptr = (char *)ptr, tchar;
  {
    tchar = tptr[0];
    tptr[0] = tptr[3];
    tptr[3] = tchar;
  };
  {
    tchar = tptr[1];
    tptr[1] = tptr[2];
    tptr[2] = tchar;
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_32_bit_val>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  mov    %dl,0x1(%rdi)
  mov    %al,0x2(%rdi)
  ret
```

assistant: ```c
void swap_32_bit_val(void *ptr) {
  char *tptr = (char *)ptr, tchar;
  {
    tchar = tptr[0];
    tptr[0] = tptr[3];
    tptr[3] = tchar;
  };
  {
    tchar = tptr[1];
    tptr[1] = tptr[2];
    tptr[2] = tchar;
  };
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<swap_32_bit_val>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  rolw   $0x8,0x1(%rdi)
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void swap_32_bit_val(void *ptr) {
  char *tptr = (char *)ptr, tchar;
  {
    tchar = tptr[0];
    tptr[0] = tptr[3];
    tptr[3] = tchar;
  };
  {
    tchar = tptr[1];
    tptr[1] = tptr[2];
    tptr[2] = tchar;
  };
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap_32_bit_val>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  rolw   $0x8,0x1(%rdi)
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void swap_32_bit_val(void *ptr) {
  char *tptr = (char *)ptr, tchar;
  {
    tchar = tptr[0];
    tptr[0] = tptr[3];
    tptr[3] = tchar;
  };
  {
    tchar = tptr[1];
    tptr[1] = tptr[2];
    tptr[2] = tchar;
  };
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%r15d
  cmp    $0x2,%edi
  jg     L83
L136:
  mov    %r15d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L83:
  mov    %rsi,%r14
  mov    0x10(%rsi),%rdi
  lea    D6(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L121
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%r13
L4:
  mov    0x8(%rsp),%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L62
  mov    0x8(%rsp),%rdx
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L62
  add    $0x1,%r15d
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  movslq %ebp,%rax
  movb   $0x0,(%r12,%rax,1)
  test   %ebp,%ebp
  js     L4
  mov    $0x0,%eax
  mov    $0x0,%ebx
  jmp    L61
L54:
  cltq
  movb   $0x0,0x0(%r13,%rax,1)
  mov    0x8(%r14),%rdi
  mov    %r13,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L4
  cmp    %ebx,%ebp
  je     L136
  add    $0x1,%ebx
  mov    $0x0,%eax
L134:
  movslq %ebx,%rdx
  movzbl (%r12,%rdx,1),%ecx
  movslq %eax,%rdx
  mov    %cl,0x0(%r13,%rdx,1)
  add    $0x1,%ebx
  add    $0x1,%eax
  cmp    %ebx,%ebp
  jl     L4
L61:
  movslq %ebx,%rdx
  cmpb   $0x2c,(%r12,%rdx,1)
  je     L54
  cmp    %ebx,%ebp
  jne    L134
  jmp    L54
L62:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%r15d
  jmp    L136
L121:
  mov    $0x0,%r15d
  jmp    L136
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: r

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    return 0;
  }
  FILE *qfile = fopen(argv[2], "r");
  if (qfile == NULL) {
    return 0;
  }
  char *ques = (char *)malloc(100);
  int line = 0;
  int siz, i, k;
  char *voc = (char *)malloc(2 * 5);
  while (feof(qfile) == 0) {
    ques = fgets(ques, 100, qfile);
    if (ques == NULL)
      break;
    line++;
    siz = strlen(ques) - 1;
    ques[siz] = '\0';
    for (i = 0, k = 0; i <= siz; i++, k++) {
      if (ques[i] == ',' || i == siz) {
        voc[k] = '\0';
        if (strstr(argv[1], voc) == NULL)
          break;
        else if (i == siz)
          return line;
        k = 0;
        i++;
      }
      voc[k] = ques[i];
    }
  }
  free(ques);
  free(voc);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x2,%edi
  jg     L120
L22:
  movl   $0x0,0xc(%rsp)
L57:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L120:
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbp
  lea    D9(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L22
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    $0xa,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  movl   $0x0,0xc(%rsp)
  mov    %rax,%r15
L49:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L109
  mov    %r12,%rdi
  mov    %r13,%rdx
  mov    $0x64,%esi
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L109
  mov    %rax,%rdi
  addl   $0x1,0xc(%rsp)
  xor    %ebx,%ebx
  call   <strlen@plt>
  xor    %ecx,%ecx
  lea    -0x1(%rax),%r14d
  movslq %r14d,%rax
  movb   $0x0,(%r12,%rax,1)
  test   %r14d,%r14d
  jns    L89
  jmp    L49
L14:
  add    $0x1,%ecx
  cmp    $0x2c,%dl
  je     L66
L91:
  add    $0x1,%ebx
  mov    %dl,(%rax)
  cmp    %ebx,%r14d
  jl     L49
L89:
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%edx
  movslq %ecx,%rax
  add    %r15,%rax
  cmp    %ebx,%r14d
  jne    L14
L66:
  movb   $0x0,(%rax)
  mov    0x8(%rbp),%rdi
  mov    %r15,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L49
  cmp    %ebx,%r14d
  je     L57
  add    $0x1,%ebx
  mov    $0x1,%ecx
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%edx
  mov    %r15,%rax
  jmp    L91
L109:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  jmp    L22
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: r

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    return 0;
  }
  FILE *qfile = fopen(argv[2], "r");
  if (qfile == NULL) {
    return 0;
  }
  char *ques = (char *)malloc(100);
  int line = 0;
  int siz, i, k;
  char *voc = (char *)malloc(2 * 5);
  while (feof(qfile) == 0) {
    ques = fgets(ques, 100, qfile);
    if (ques == NULL)
      break;
    line++;
    siz = strlen(ques) - 1;
    ques[siz] = '\0';
    for (i = 0, k = 0; i <= siz; i++, k++) {
      if (ques[i] == ',' || i == siz) {
        voc[k] = '\0';
        if (strstr(argv[1], voc) == NULL)
          break;
        else if (i == siz)
          return line;
        k = 0;
        i++;
      }
      voc[k] = ques[i];
    }
  }
  free(ques);
  free(voc);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x2,%edi
  jg     L123
L97:
  movl   $0x0,0xc(%rsp)
L98:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L123:
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbp
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L97
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    $0xa,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  movl   $0x0,0xc(%rsp)
  mov    %rax,%r15
L57:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L93
  mov    %r12,%rdi
  mov    %r13,%rdx
  mov    $0x64,%esi
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L93
  mov    %rax,%rdi
  addl   $0x1,0xc(%rsp)
  xor    %ebx,%ebx
  call   <strlen@plt>
  xor    %ecx,%ecx
  lea    -0x1(%rax),%r14d
  movslq %r14d,%rax
  movb   $0x0,(%r12,%rax,1)
  test   %r14d,%r14d
  jns    L20
  jmp    L57
L33:
  add    $0x1,%ecx
  cmp    $0x2c,%dl
  je     L18
L6:
  add    $0x1,%ebx
  mov    %dl,(%rax)
  cmp    %ebx,%r14d
  jl     L57
L20:
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%edx
  movslq %ecx,%rax
  add    %r15,%rax
  cmp    %ebx,%r14d
  jne    L33
L18:
  movb   $0x0,(%rax)
  mov    0x8(%rbp),%rdi
  mov    %r15,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L57
  cmp    %ebx,%r14d
  je     L98
  add    $0x1,%ebx
  mov    $0x1,%ecx
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%edx
  mov    %r15,%rax
  jmp    L6
L93:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  jmp    L97
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: r

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    return 0;
  }
  FILE *qfile = fopen(argv[2], "r");
  if (qfile == NULL) {
    return 0;
  }
  char *ques = (char *)malloc(100);
  int line = 0;
  int siz, i, k;
  char *voc = (char *)malloc(2 * 5);
  while (feof(qfile) == 0) {
    ques = fgets(ques, 100, qfile);
    if (ques == NULL)
      break;
    line++;
    siz = strlen(ques) - 1;
    ques[siz] = '\0';
    for (i = 0, k = 0; i <= siz; i++, k++) {
      if (ques[i] == ',' || i == siz) {
        voc[k] = '\0';
        if (strstr(argv[1], voc) == NULL)
          break;
        else if (i == siz)
          return line;
        k = 0;
        i++;
      }
      voc[k] = ques[i];
    }
  }
  free(ques);
  free(voc);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rysuj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: %s

assistant: ```c
void rysuj(char element[], int k) {
  int i = 0;
  while (i < k) {
    printf("%s", element);
    ++i;
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rysuj>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L13
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
L2:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L2
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D5: %s

assistant: ```c
void rysuj(char element[], int k) {
  int i = 0;
  while (i < k) {
    printf("%s", element);
    ++i;
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rysuj>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L17:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L17
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D8: %s

assistant: ```c
void rysuj(char element[], int k) {
  int i = 0;
  while (i < k) {
    printf("%s", element);
    ++i;
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rysuj>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L7:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L7
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: %s

assistant: ```c
void rysuj(char element[], int k) {
  int i = 0;
  while (i < k) {
    printf("%s", element);
    ++i;
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <printAscii@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D49
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D38
data_type: string

tool: D49: 


tool: D14: *************************************


tool: D38: *** EXTENDED ASCII TABLE EXAMPLE


assistant: ```c
int main() {
  printf("\n");
  printf("*************************************\n");
  printf("*** EXTENDED ASCII TABLE EXAMPLE\n");
  printf("*************************************\n");
  printf("\n");
  printAscii();
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <printAscii@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type: string
name: retrieve_data
arguments: data_label: D1
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D13: 


tool: D1: *************************************


tool: D15: *** EXTENDED ASCII TABLE EXAMPLE


assistant: ```c
int main() {
  printf("\n");
  printf("*************************************\n");
  printf("*** EXTENDED ASCII TABLE EXAMPLE\n");
  printf("*************************************\n");
  printf("\n");
  printAscii();
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <printAscii@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D29
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D11
type_guessed: string

tool: D29: *************************************


tool: D4: 


tool: D11: *** EXTENDED ASCII TABLE EXAMPLE


assistant: ```c
int main() {
  printf("\n");
  printf("*************************************\n");
  printf("*** EXTENDED ASCII TABLE EXAMPLE\n");
  printf("*************************************\n");
  printf("\n");
  printAscii();
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  lea    D27(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <printAscii@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D27
type: string
name: unpack_data
arguments: label: D8
type: string

tool: D19: *************************************


tool: D27: 


tool: D8: *** EXTENDED ASCII TABLE EXAMPLE


assistant: ```c
int main() {
  printf("\n");
  printf("*************************************\n");
  printf("*** EXTENDED ASCII TABLE EXAMPLE\n");
  printf("*************************************\n");
  printf("\n");
  printAscii();
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fill_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
char *fill_str(char *from) {
  char *ptr = malloc(sizeof(char) * 10);
  strcpy(ptr, from);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill_str>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *fill_str(char *from) {
  char *ptr = malloc(sizeof(char) * 10);
  strcpy(ptr, from);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fill_str>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  pop    %rbp
  ret
```

assistant: ```c
char *fill_str(char *from) {
  char *ptr = malloc(sizeof(char) * 10);
  strcpy(ptr, from);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fill_str>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  pop    %rbp
  ret
```

assistant: ```c
char *fill_str(char *from) {
  char *ptr = malloc(sizeof(char) * 10);
  strcpy(ptr, from);
}
```