ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<overlap_labels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x61000(%rsp),%r11
L1:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L1
  sub    $0xad0,%rsp
  mov    %rdi,-0x61ac8(%rbp)
  mov    %rsi,-0x61ad0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x61aac(%rbp)
  mov    -0x61ac8(%rbp),%rax
  mov    %rax,%rdi
  call   <get_ordered_pattern_tree@plt>
  mov    %rax,-0x61aa0(%rbp)
  mov    -0x61ad0(%rbp),%rax
  mov    %rax,%rdi
  call   <get_ordered_pattern_tree@plt>
  mov    %rax,-0x61a98(%rbp)
  lea    -0x61a90(%rbp),%rdx
  mov    -0x61aa0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_labels@plt>
  mov    %eax,-0x61aa8(%rbp)
  lea    -0x30d50(%rbp),%rdx
  mov    -0x61a98(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_labels@plt>
  mov    %eax,-0x61aa4(%rbp)
  movl   $0x0,-0x61ab4(%rbp)
  jmp    L59
L33:
  movl   $0x0,-0x61ab0(%rbp)
  jmp    L52
L55:
  lea    -0x30d50(%rbp),%rcx
  mov    -0x61ab0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  lea    (%rcx,%rax,1),%rdx
  lea    -0x61a90(%rbp),%rsi
  mov    -0x61ab4(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  add    %rcx,%rax
  shl    $0x3,%rax
  add    %rsi,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L60
  addl   $0x1,-0x61aac(%rbp)
  jmp    L71
L60:
  addl   $0x1,-0x61ab0(%rbp)
L52:
  mov    -0x61ab0(%rbp),%eax
  cmp    -0x61aa4(%rbp),%eax
  jl     L55
L71:
  addl   $0x1,-0x61ab4(%rbp)
L59:
  mov    -0x61ab4(%rbp),%eax
  cmp    -0x61aa8(%rbp),%eax
  jl     L33
  mov    -0x61aa0(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <destroy_tree_cb_2@plt>
  mov    -0x61a98(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <destroy_tree_cb_2@plt>
  mov    -0x61aac(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
int overlap_labels(char *seed1, char *seed2) {
  int i, j, overlap = 0;
  char label_set1[1000][200];
  char label_set2[1000][200];
  int lc1, lc2;
  struct rooted_tree *seed1_tree = get_ordered_pattern_tree(seed1);
  struct rooted_tree *seed2_tree = get_ordered_pattern_tree(seed2);
  lc1 = parse_labels(seed1_tree, label_set1);
  lc2 = parse_labels(seed2_tree, label_set2);
  for (i = 0; i < lc1; i++) {
    for (j = 0; j < lc2; j++) {
      if (strcmp(label_set1[i], label_set2[j]) == 0) {
        overlap++;
        break;
      }
    }
  }
  destroy_tree_cb_2(seed1_tree, NULL);
  destroy_tree_cb_2(seed2_tree, NULL);
  return overlap;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<overlap_labels>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L47:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L47
  sub    $0xab8,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x61aa8(%rsp)
  xor    %eax,%eax
  call   <get_ordered_pattern_tree@plt>
  mov    %rax,%r14
  mov    %rax,0x10(%rsp)
  mov    %rbx,%rdi
  call   <get_ordered_pattern_tree@plt>
  mov    %rax,%r15
  mov    %rax,0x18(%rsp)
  lea    0x20(%rsp),%rsi
  mov    %r14,%rdi
  call   <parse_labels@plt>
  mov    %eax,%ebx
  lea    0x30d60(%rsp),%rsi
  mov    %r15,%rdi
  call   <parse_labels@plt>
  test   %ebx,%ebx
  jle    L38
  mov    %eax,%r14d
  lea    0x20(%rsp),%r13
  lea    -0x1(%rbx),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xe8(%rsp,%rax,8),%r15
  lea    0x30d60(%rsp),%rax
  mov    %rax,(%rsp)
  lea    -0x1(%r14),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x30e28(%rsp,%rax,8),%r12
  movl   $0x0,0xc(%rsp)
  jmp    L41
L10:
  addl   $0x1,0xc(%rsp)
L63:
  add    $0xc8,%r13
  cmp    %r15,%r13
  je     L74
L41:
  mov    %r13,%rbp
  mov    (%rsp),%rbx
  test   %r14d,%r14d
  jle    L63
L26:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L10
  add    $0xc8,%rbx
  cmp    %r12,%rbx
  jne    L26
  jmp    L63
L38:
  movl   $0x0,0xc(%rsp)
L74:
  mov    $0x0,%esi
  mov    0x10(%rsp),%rdi
  call   <destroy_tree_cb_2@plt>
  mov    $0x0,%esi
  mov    0x18(%rsp),%rdi
  call   <destroy_tree_cb_2@plt>
  mov    0x61aa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    0xc(%rsp),%eax
  add    $0x61ab8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int overlap_labels(char *seed1, char *seed2) {
  int i, j, overlap = 0;
  char label_set1[1000][200];
  char label_set2[1000][200];
  int lc1, lc2;
  struct rooted_tree *seed1_tree = get_ordered_pattern_tree(seed1);
  struct rooted_tree *seed2_tree = get_ordered_pattern_tree(seed2);
  lc1 = parse_labels(seed1_tree, label_set1);
  lc2 = parse_labels(seed2_tree, label_set2);
  for (i = 0; i < lc1; i++) {
    for (j = 0; j < lc2; j++) {
      if (strcmp(label_set1[i], label_set2[j]) == 0) {
        overlap++;
        break;
      }
    }
  }
  destroy_tree_cb_2(seed1_tree, NULL);
  destroy_tree_cb_2(seed2_tree, NULL);
  return overlap;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<overlap_labels>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L70:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L70
  sub    $0xab8,%rsp
  mov    %rsi,%rbp
  lea    0x20(%rsp),%rbx
  lea    0x30d60(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x61aa8(%rsp)
  xor    %eax,%eax
  call   <get_ordered_pattern_tree@plt>
  mov    %rbp,%rdi
  mov    %rax,%r15
  mov    %rax,0x10(%rsp)
  call   <get_ordered_pattern_tree@plt>
  mov    %rbx,%rsi
  mov    %r15,%rdi
  mov    %rax,%r14
  mov    %rax,0x18(%rsp)
  call   <parse_labels@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <parse_labels@plt>
  test   %ebp,%ebp
  jle    L48
  mov    %eax,%r12d
  lea    -0x1(%rbp),%eax
  xor    %r14d,%r14d
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xe8(%rsp,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r12),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x30e28(%rsp,%rax,8),%rbp
  nopl   0x0(%rax)
L18:
  mov    %r13,%r15
  test   %r12d,%r12d
  jg     L86
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0xc8,%r15
  cmp    %rbp,%r15
  je     L3
L86:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  add    $0x1,%r14d
L3:
  add    $0xc8,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L18
L78:
  mov    0x10(%rsp),%rdi
  xor    %esi,%esi
  call   <destroy_tree_cb_2@plt>
  mov    0x18(%rsp),%rdi
  xor    %esi,%esi
  call   <destroy_tree_cb_2@plt>
  mov    0x61aa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x61ab8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L48:
  xor    %r14d,%r14d
  jmp    L78
L72:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int overlap_labels(char *seed1, char *seed2) {
  int i, j, overlap = 0;
  char label_set1[1000][200];
  char label_set2[1000][200];
  int lc1, lc2;
  struct rooted_tree *seed1_tree = get_ordered_pattern_tree(seed1);
  struct rooted_tree *seed2_tree = get_ordered_pattern_tree(seed2);
  lc1 = parse_labels(seed1_tree, label_set1);
  lc2 = parse_labels(seed2_tree, label_set2);
  for (i = 0; i < lc1; i++) {
    for (j = 0; j < lc2; j++) {
      if (strcmp(label_set1[i], label_set2[j]) == 0) {
        overlap++;
        break;
      }
    }
  }
  destroy_tree_cb_2(seed1_tree, NULL);
  destroy_tree_cb_2(seed2_tree, NULL);
  return overlap;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<overlap_labels>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L44:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L44
  sub    $0xab8,%rsp
  mov    %rsi,%rbp
  lea    0x20(%rsp),%rbx
  lea    0x30d60(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x61aa8(%rsp)
  xor    %eax,%eax
  call   <get_ordered_pattern_tree@plt>
  mov    %rbp,%rdi
  mov    %rax,%r15
  mov    %rax,0x10(%rsp)
  call   <get_ordered_pattern_tree@plt>
  mov    %rbx,%rsi
  mov    %r15,%rdi
  mov    %rax,%r14
  mov    %rax,0x18(%rsp)
  call   <parse_labels@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <parse_labels@plt>
  test   %ebp,%ebp
  jle    L80
  mov    %eax,%r12d
  lea    -0x1(%rbp),%eax
  xor    %r14d,%r14d
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xe8(%rsp,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r12),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x30e28(%rsp,%rax,8),%rbp
  nopl   0x0(%rax)
L51:
  mov    %r13,%r15
  test   %r12d,%r12d
  jg     L10
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L75:
  add    $0xc8,%r15
  cmp    %rbp,%r15
  je     L43
L10:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L75
  add    $0x1,%r14d
L43:
  add    $0xc8,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L51
L39:
  mov    0x10(%rsp),%rdi
  xor    %esi,%esi
  call   <destroy_tree_cb_2@plt>
  mov    0x18(%rsp),%rdi
  xor    %esi,%esi
  call   <destroy_tree_cb_2@plt>
  mov    0x61aa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x61ab8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L80:
  xor    %r14d,%r14d
  jmp    L39
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int overlap_labels(char *seed1, char *seed2) {
  int i, j, overlap = 0;
  char label_set1[1000][200];
  char label_set2[1000][200];
  int lc1, lc2;
  struct rooted_tree *seed1_tree = get_ordered_pattern_tree(seed1);
  struct rooted_tree *seed2_tree = get_ordered_pattern_tree(seed2);
  lc1 = parse_labels(seed1_tree, label_set1);
  lc2 = parse_labels(seed2_tree, label_set2);
  for (i = 0; i < lc1; i++) {
    for (j = 0; j < lc2; j++) {
      if (strcmp(label_set1[i], label_set2[j]) == 0) {
        overlap++;
        break;
      }
    }
  }
  destroy_tree_cb_2(seed1_tree, NULL);
  destroy_tree_cb_2(seed2_tree, NULL);
  return overlap;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BinIOCountBytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0xffffffff,-0x24(%rbp)
  jne    L24
  movl   $0x1,-0x24(%rbp)
L24:
  mov    -0x1c(%rbp),%eax
  sub    $0x62,%eax
  cmp    $0x16,%eax
  ja     L67
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D4(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movq   $0x1,-0x8(%rbp)
  jmp    L67
  movq   $0x1,-0x8(%rbp)
  jmp    L67
  movq   $0x2,-0x8(%rbp)
  jmp    L67
  movq   $0x4,-0x8(%rbp)
  jmp    L67
  movq   $0x8,-0x8(%rbp)
  jmp    L67
  movq   $0x4,-0x8(%rbp)
  jmp    L67
  movq   $0x8,-0x8(%rbp)
  nop
L67:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  imul   -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
extern void BinIOCountBytes(void *context, int type, int byte_order, int count) {
  size_t type_size = 0;
  if (count == -1) {
    count = 1;
  }
  switch (type) {
  case 'x':
    type_size = 1;
    break;
  case 'b':
    type_size = 1;
    break;
  case 's':
    type_size = 2;
    break;
  case 'i':
    type_size = 4;
    break;
  case 'l':
    type_size = 8;
    break;
  case 'f':
    type_size = 4;
    break;
  case 'd':
    type_size = 8;
    break;
  }
  *(size_t *)context += type_size * count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<BinIOCountBytes>:
  endbr64
  cmp    $0xffffffff,%ecx
  mov    $0x1,%eax
  cmove  %eax,%ecx
  sub    $0x62,%esi
  cmp    $0x16,%esi
  ja     L8
  mov    %esi,%esi
  lea    D5(%rip),%rdx
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  jmp    L42
  mov    $0x2,%eax
  jmp    L42
  mov    $0x4,%eax
  jmp    L42
  mov    $0x8,%eax
  jmp    L42
  mov    $0x4,%eax
  jmp    L42
  mov    $0x8,%eax
  jmp    L42
L8:
  mov    $0x0,%eax
L42:
  movslq %ecx,%rcx
  imul   %rax,%rcx
  add    %rcx,(%rdi)
  ret
```

assistant: ```c
extern void BinIOCountBytes(void *context, int type, int byte_order, int count) {
  size_t type_size = 0;
  if (count == -1) {
    count = 1;
  }
  switch (type) {
  case 'x':
    type_size = 1;
    break;
  case 'b':
    type_size = 1;
    break;
  case 's':
    type_size = 2;
    break;
  case 'i':
    type_size = 4;
    break;
  case 'l':
    type_size = 8;
    break;
  case 'f':
    type_size = 4;
    break;
  case 'd':
    type_size = 8;
    break;
  }
  *(size_t *)context += type_size * count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<BinIOCountBytes>:
  endbr64
  cmp    $0xffffffff,%ecx
  mov    $0x1,%eax
  cmove  %eax,%ecx
  sub    $0x62,%esi
  xor    %eax,%eax
  movslq %ecx,%rcx
  cmp    $0x16,%esi
  ja     L9
  lea    D3(%rip),%rax
  imul   (%rax,%rsi,8),%rcx
  mov    %rcx,%rax
L9:
  add    %rax,(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: 

assistant: ```c
extern void BinIOCountBytes(void *context, int type, int byte_order, int count) {
  size_t type_size = 0;
  if (count == -1) {
    count = 1;
  }
  switch (type) {
  case 'x':
    type_size = 1;
    break;
  case 'b':
    type_size = 1;
    break;
  case 's':
    type_size = 2;
    break;
  case 'i':
    type_size = 4;
    break;
  case 'l':
    type_size = 8;
    break;
  case 'f':
    type_size = 4;
    break;
  case 'd':
    type_size = 8;
    break;
  }
  *(size_t *)context += type_size * count;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<BinIOCountBytes>:
  endbr64
  cmp    $0xffffffff,%ecx
  mov    $0x1,%eax
  cmove  %eax,%ecx
  sub    $0x62,%esi
  xor    %eax,%eax
  movslq %ecx,%rcx
  cmp    $0x16,%esi
  ja     L1
  lea    D4(%rip),%rax
  imul   (%rax,%rsi,8),%rcx
  mov    %rcx,%rax
L1:
  add    %rax,(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: 

assistant: ```c
extern void BinIOCountBytes(void *context, int type, int byte_order, int count) {
  size_t type_size = 0;
  if (count == -1) {
    count = 1;
  }
  switch (type) {
  case 'x':
    type_size = 1;
    break;
  case 'b':
    type_size = 1;
    break;
  case 's':
    type_size = 2;
    break;
  case 'i':
    type_size = 4;
    break;
  case 'l':
    type_size = 8;
    break;
  case 'f':
    type_size = 4;
    break;
  case 'd':
    type_size = 8;
    break;
  }
  *(size_t *)context += type_size * count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_fd_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L17
  mov    -0x18(%rbp),%rax
  jmp    L25
L17:
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %rax,-0x10(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    -0x10(%rbp),%rax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
size_t get_fd_size(int fd) {
  struct stat stat;
  fstat(fd, &stat);
  if (stat.st_size)
    return stat.st_size;
  size_t ret = lseek(fd, 0, SEEK_END);
  lseek(fd, 0, SEEK_SET);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_fd_size>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  mov    (%rsp),%rbp
  test   %rbp,%rbp
  je     L17
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <lseek@plt>
  mov    %rax,%rbp
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <lseek@plt>
  jmp    L5
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t get_fd_size(int fd) {
  struct stat stat;
  fstat(fd, &stat);
  if (stat.st_size)
    return stat.st_size;
  size_t ret = lseek(fd, 0, SEEK_END);
  lseek(fd, 0, SEEK_SET);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_fd_size>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  mov    (%rsp),%r12
  test   %r12,%r12
  jne    L5
  mov    D3(%rip),%rax
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    (%rax),%edx
  call   <lseek@plt>
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    %rax,%r12
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t get_fd_size(int fd) {
  struct stat stat;
  fstat(fd, &stat);
  if (stat.st_size)
    return stat.st_size;
  size_t ret = lseek(fd, 0, SEEK_END);
  lseek(fd, 0, SEEK_SET);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_fd_size>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  mov    (%rsp),%r12
  test   %r12,%r12
  jne    L12
  mov    D3(%rip),%rax
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    (%rax),%edx
  call   <lseek@plt>
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    %rax,%r12
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t get_fd_size(int fd) {
  struct stat stat;
  fstat(fd, &stat);
  if (stat.st_size)
    return stat.st_size;
  size_t ret = lseek(fd, 0, SEEK_END);
  lseek(fd, 0, SEEK_SET);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_system_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D4: test_system_cmp...

tool: D5: Ok


assistant: ```c
void test_system_cmp() {
  printf("test_system_cmp...");
  printf("Ok\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<test_system_cmp>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string
name: read_data
arguments: tag: D14
type: string

tool: D7: test_system_cmp...

tool: D14: Ok


assistant: ```c
void test_system_cmp() {
  printf("test_system_cmp...");
  printf("Ok\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_system_cmp>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string

tool: D5: test_system_cmp...

tool: D10: Ok


assistant: ```c
void test_system_cmp() {
  printf("test_system_cmp...");
  printf("Ok\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_system_cmp>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D14
type: string

tool: D4: test_system_cmp...

tool: D14: Ok


assistant: ```c
void test_system_cmp() {
  printf("test_system_cmp...");
  printf("Ok\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xa,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L17:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L12:
  cmpl   $0x0,-0x8(%rbp)
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i = 10, n = 0;
  while (i) {
    n = n + i;
    i--;
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x37,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 10, n = 0;
  while (i) {
    n = n + i;
    i--;
  }
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x37,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 10, n = 0;
  while (i) {
    n = n + i;
    i--;
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x37,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 10, n = 0;
  while (i) {
    n = n + i;
    i--;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: 
 We are multiplying ()


assistant: ```c
int multiply(int integer1, int integer2) {
  printf("\n We are multiplying ()\n");
  return (integer1 * integer2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  imul   %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: 
 We are multiplying ()


assistant: ```c
int multiply(int integer1, int integer2) {
  printf("\n We are multiplying ()\n");
  return (integer1 * integer2);
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    D1(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  imul   %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D1: 
 We are multiplying ()


assistant: ```c
int multiply(int integer1, int integer2) {
  printf("\n We are multiplying ()\n");
  return (integer1 * integer2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiply>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    D1(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  imul   %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: 
 We are multiplying ()


assistant: ```c
int multiply(int integer1, int integer2) {
  printf("\n We are multiplying ()\n");
  return (integer1 * integer2);
}
```