ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x200000(%rsp),%r11
L69:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L69
  sub    $0x140,%rsp
  mov    %edi,-0x200134(%rbp)
  mov    %rsi,-0x200140(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x200130(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x20012c(%rbp)
  jmp    L28
L6:
  lea    -0x110(%rbp),%rdx
  lea    -0x112(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x200128(%rbp)
  movl   $0x0,-0x200124(%rbp)
  movl   $0x0,-0x200124(%rbp)
  jmp    L58
L1:
  mov    -0x200124(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  mov    %eax,%edx
  sar    $0x7,%dl
  shr    $0x7,%dl
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%al
  jne    L64
  mov    -0x200128(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x200128(%rbp)
  jmp    L80
L64:
  shll   -0x200128(%rbp)
L80:
  addl   $0x1,-0x200124(%rbp)
L58:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x200124(%rbp)
  jl     L1
  movzbl -0x112(%rbp),%eax
  cmp    $0x2b,%al
  jne    L89
  mov    -0x200128(%rbp),%eax
  cltq
  mov    -0x200120(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x200128(%rbp),%eax
  cltq
  mov    %edx,-0x200120(%rbp,%rax,4)
  jmp    L86
L89:
  movzbl -0x112(%rbp),%eax
  cmp    $0x2d,%al
  jne    L104
  mov    -0x200128(%rbp),%eax
  cltq
  mov    -0x200120(%rbp,%rax,4),%eax
  lea    -0x1(%rax),%edx
  mov    -0x200128(%rbp),%eax
  cltq
  mov    %edx,-0x200120(%rbp,%rax,4)
  jmp    L86
L104:
  mov    -0x200128(%rbp),%eax
  cltq
  mov    -0x200120(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L86:
  addl   $0x1,-0x20012c(%rbp)
L28:
  mov    -0x200130(%rbp),%eax
  cmp    %eax,-0x20012c(%rbp)
  jl     L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D21
datatype: string
name: disassemble_data
arguments: label: D20
datatype: string

tool: D27: %d

tool: D21: %s %s

tool: D20: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int t;
  int c[1 << 19];
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    char op[2];
    char x[255];
    scanf("%s %s", op, x);
    int n = 0;
    int j = 0;
    for (j = 0; j < strlen(x); j++) {
      if (x[j] % 2 == 1) {
        n = (n << 1) + 1;
      } else {
        n = (n << 1);
      }
    }
    if (*op == '+') {
      c[n]++;
    } else if (*op == '-') {
      c[n]--;
    } else {
      printf("%d\n", c[n]);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x200000(%rsp),%r11
L97:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L97
  sub    $0x138,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x200128(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L19
  mov    $0x0,%r13d
  lea    0x200020(%rsp),%r12
  lea    0x20001e(%rsp),%r15
  lea    D19(%rip),%r14
  jmp    L15
L43:
  movzbl 0x0(%rbp,%r12,1),%eax
  mov    %eax,%edx
  shr    $0x7,%dl
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    0x1(%rbx,%rbx,1),%edx
  add    %ebx,%ebx
  cmp    $0x1,%al
  cmove  %edx,%ebx
  add    $0x1,%rbp
L21:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L43
  movzbl 0x20001e(%rsp),%eax
  cmp    $0x2b,%al
  je     L46
  cmp    $0x2d,%al
  jne    L68
  movslq %ebx,%rbx
  subl   $0x1,0x10(%rsp,%rbx,4)
  jmp    L74
L46:
  movslq %ebx,%rbx
  addl   $0x1,0x10(%rsp,%rbx,4)
L74:
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  jle    L19
L15:
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L21
L68:
  movslq %ebx,%rbx
  mov    0x10(%rsp,%rbx,4),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L74
L19:
  mov    0x200128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x200138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D29
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string

tool: D29: %d

tool: D19: %s %s

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int t;
  int c[1 << 19];
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    char op[2];
    char x[255];
    scanf("%s %s", op, x);
    int n = 0;
    int j = 0;
    for (j = 0; j < strlen(x); j++) {
      if (x[j] % 2 == 1) {
        n = (n << 1) + 1;
      } else {
        n = (n << 1);
      }
    }
    if (*op == '+') {
      c[n]++;
    } else if (*op == '-') {
      c[n]--;
    } else {
      printf("%d\n", c[n]);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x200000(%rsp),%r11
L51:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L51
  sub    $0x138,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x200128(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L48
  xor    %ebp,%ebp
  lea    0x200020(%rsp),%r14
  lea    0x20001e(%rsp),%r13
  lea    D3(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L97:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %r15d,%r15d
  xor    %ebx,%ebx
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L83:
  movzbl (%r14,%r15,1),%eax
  mov    %eax,%edx
  shr    $0x7,%dl
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%al
  sete   %al
  add    $0x1,%r15
  movzbl %al,%eax
  lea    (%rax,%rbx,2),%ebx
L88:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  jg     L83
  movzbl 0x20001e(%rsp),%eax
  movslq %ebx,%rbx
  mov    0x10(%rsp,%rbx,4),%esi
  cmp    $0x2b,%al
  je     L87
  cmp    $0x2d,%al
  jne    L59
  sub    $0x1,%esi
  mov    %esi,0x10(%rsp,%rbx,4)
L6:
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jg     L97
L48:
  mov    0x200128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  add    $0x200138,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L87:
  add    $0x1,%esi
  mov    %esi,0x10(%rsp,%rbx,4)
  jmp    L6
  nopl   0x0(%rax)
L59:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string

tool: D28: %d

tool: D3: %s %s

tool: D9: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int t;
  int c[1 << 19];
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    char op[2];
    char x[255];
    scanf("%s %s", op, x);
    int n = 0;
    int j = 0;
    for (j = 0; j < strlen(x); j++) {
      if (x[j] % 2 == 1) {
        n = (n << 1) + 1;
      } else {
        n = (n << 1);
      }
    }
    if (*op == '+') {
      c[n]++;
    } else if (*op == '-') {
      c[n]--;
    } else {
      printf("%d\n", c[n]);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x200000(%rsp),%r11
L23:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L23
  sub    $0x138,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x200128(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L48
  xor    %ebp,%ebp
  lea    0x200020(%rsp),%r14
  lea    0x20001e(%rsp),%r13
  lea    D20(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L83:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %r15d,%r15d
  xor    %ebx,%ebx
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L90:
  movzbl (%r14,%r15,1),%eax
  mov    %eax,%edx
  shr    $0x7,%dl
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%al
  sete   %al
  add    $0x1,%r15
  movzbl %al,%eax
  lea    (%rax,%rbx,2),%ebx
L69:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  jg     L90
  movzbl 0x20001e(%rsp),%eax
  movslq %ebx,%rbx
  mov    0x10(%rsp,%rbx,4),%esi
  cmp    $0x2b,%al
  je     L59
  cmp    $0x2d,%al
  jne    L11
  sub    $0x1,%esi
  mov    %esi,0x10(%rsp,%rbx,4)
L34:
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jg     L83
L48:
  mov    0x200128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x200138,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  add    $0x1,%esi
  mov    %esi,0x10(%rsp,%rbx,4)
  jmp    L34
  nopl   0x0(%rax)
L11:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L34
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D20
data_type: string
name: read_data
arguments: data_tag: D3
data_type: string

tool: D12: %d

tool: D20: %s %s

tool: D3: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int t;
  int c[1 << 19];
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    char op[2];
    char x[255];
    scanf("%s %s", op, x);
    int n = 0;
    int j = 0;
    for (j = 0; j < strlen(x); j++) {
      if (x[j] % 2 == 1) {
        n = (n << 1) + 1;
      } else {
        n = (n << 1);
      }
    }
    if (*op == '+') {
      c[n]++;
    } else if (*op == '-') {
      c[n]--;
    } else {
      printf("%d\n", c[n]);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <cls@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <kprintf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L18:
  movl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x4(%rbp)
  je     L18
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D2: BADGER OS 0.1 Booting...

assistant: ```c
void init(void) {
  cls();
  kprintf("BADGER OS 0.1 Booting...");
  int terminate = 0;
  while (terminate == 0) {
    terminate = 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cls@plt>
  lea    D1(%rip),%rdi
  call   <kprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string

tool: D1: BADGER OS 0.1 Booting...

assistant: ```c
void init(void) {
  cls();
  kprintf("BADGER OS 0.1 Booting...");
  int terminate = 0;
  while (terminate == 0) {
    terminate = 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cls@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <kprintf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8: BADGER OS 0.1 Booting...

assistant: ```c
void init(void) {
  cls();
  kprintf("BADGER OS 0.1 Booting...");
  int terminate = 0;
  while (terminate == 0) {
    terminate = 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cls@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <kprintf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: BADGER OS 0.1 Booting...

assistant: ```c
void init(void) {
  cls();
  kprintf("BADGER OS 0.1 Booting...");
  int terminate = 0;
  while (terminate == 0) {
    terminate = 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<PointNormal>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  movapd %xmm0,%xmm1
  movsd  D134(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L35
  movsd  D8(%rip),%xmm1
  movq   %rbx,%xmm4
  subsd  %xmm4,%xmm1
L35:
  movsd  D129(%rip),%xmm0
  movsd  D169(%rip),%xmm2
  comisd %xmm1,%xmm2
  jbe    L15
L3:
  pop    %rbx
  ret
L15:
  mulsd  %xmm1,%xmm1
  movsd  D8(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <log@plt>
  mov    %eax,%edi
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  mulsd  D165(%rip),%xmm0
  subsd  D104(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D120(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D8(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D1(%rip),%xmm0
  movapd %xmm2,%xmm1
  mulsd  D121(%rip),%xmm1
  addsd  D160(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D6(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D5(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D16(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  movsd  D134(%rip),%xmm1
  movq   %rbx,%xmm5
  comisd %xmm5,%xmm1
  jbe    L3
  xorpd  D103(%rip),%xmm0
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: label: D134
type: f64
name: retrieve_data
arguments: label: D8
type: f64
name: retrieve_data
arguments: label: D129
type: f32[2]
name: retrieve_data
arguments: label: D169
type: byte[8]
name: retrieve_data
arguments: label: D165
type: byte[8]
name: retrieve_data
arguments: label: D104
type: byte[8]
name: retrieve_data
arguments: label: D120
type: byte[8]
name: retrieve_data
arguments: label: D1
type: byte[8]
name: retrieve_data
arguments: label: D121
type: byte[8]
name: retrieve_data
arguments: label: D160
type: byte[8]
name: retrieve_data
arguments: label: D6
type: byte[8]
name: retrieve_data
arguments: label: D5
type: byte[8]
name: retrieve_data
arguments: label: D16
type: byte[8]
name: retrieve_data
arguments: label: D103
type: f32[4]

tool: D134: 0.5

tool: D8: 1

tool: {"D129": [0.0,-6.11029052734375]}

tool: {"D169": [0x23,0x42,0x92,0x0c,0xa1,0x9c,0xc7,0x3b]}

tool: {"D165": [0x62,0x1a,0xed,0xc3,0xae,0xc8,0x07,0xbf]}

tool: {"D104": [0x30,0xa8,0x87,0x73,0xcc,0xe9,0x94,0x3f]}

tool: {"D120": [0x46,0xf1,0x67,0x5c,0x4b,0xe7,0xd5,0x3f]}

tool: {"D1": [0x37,0xf2,0x4e,0xc6,0x74,0x9f,0xd4,0x3f]}

tool: {"D121": [0x88,0x45,0x07,0xda,0xc3,0x96,0x6f,0x3f]}

tool: {"D160": [0x68,0x5f,0x64,0x3e,0x73,0x81,0xba,0x3f]}

tool: {"D6": [0x54,0xf0,0x34,0xb0,0xcc,0xfe,0xe0,0x3f]}

tool: {"D5": [0x2f,0xbd,0x89,0x04,0xa9,0xd5,0xe2,0x3f]}

tool: {"D16": [0x54,0xf7,0xcc,0x9d,0xe6,0x6e,0xb9,0x3f]}

tool: {"D103": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double PointNormal(double prob) {
  double a0 = -.322232431088, a1 = -1, a2 = -.342242088547, a3 = -.0204231210245;
  double a4 = -.453642210148e-4, b0 = .0993484626060, b1 = .588581570495;
  double b2 = .531103462366, b3 = .103537752850, b4 = .0038560700634;
  double y, z = 0, p = prob, p1;
  p1 = (p < 0.5 ? p : 1 - p);
  if (p1 < 1e-20)
    return (-9999);
  y = sqrt(log(1 / (p1 * p1)));
  z = y + ((((y * a4 + a3) * y + a2) * y + a1) * y + a0) / ((((y * b4 + b3) * y + b2) * y + b1) * y + b0);
  return (p < 0.5 ? -z : z);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  sub    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L55
L18:
  mov    -0x38(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,(%rax)
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L24
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L55
L24:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L20
L39:
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x20(%rbp)
L20:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jle    L39
  mov    -0x8(%rbp),%rax
L55:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D0
type_guessed: string

tool: D8: error imatrix: calloc error No. 1 


tool: D0: error imatrix: calloc error No. 2 


assistant: ```c
int **imatrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  int **m;
  if ((m = (int **)calloc(nrow, sizeof(int *))) == NULL) {
    printf("error imatrix: calloc error No. 1 \n");
    return (NULL);
  }
  m += 0;
  m -= ncl;
  if ((m[nrl] = (int *)calloc(nrow * ncol, sizeof(int))) == NULL) {
    printf("error imatrix: calloc error No. 2 \n");
    return (NULL);
  }
  m[nrl] += 0;
  m[nrl] -= nrl;
  for (i = nrl + 1; i <= nrh; i++) {
    m[i] = m[i - 1] + ncol;
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<imatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%r15
  mov    %rsi,%r14
  sub    %rdi,%r14
  add    $0x1,%r14
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbx
  mov    $0x8,%esi
  mov    %r14,%rdi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L32
  shl    $0x3,%r15
  sub    %r15,%rbp
  mov    %r14,%rdi
  imul   %rbx,%rdi
  mov    $0x4,%esi
  call   <calloc@plt>
  lea    0x0(%rbp,%r13,8),%rdx
  mov    %rax,(%rdx)
  test   %rax,%rax
  je     L28
  lea    0x0(,%r13,4),%rcx
  sub    %rcx,%rax
  mov    %rax,(%rdx)
  cmp    %r13,%r12
  jle    L39
  lea    0x0(,%rbx,4),%rsi
  lea    0x0(%rbp,%r12,8),%rax
L31:
  mov    %rsi,%rcx
  add    (%rdx),%rcx
  mov    %rcx,0x8(%rdx)
  add    $0x8,%rdx
  cmp    %rax,%rdx
  jne    L31
L39:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L28:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebp
  jmp    L39
```

tool_calls: name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string

tool: D16: error imatrix: calloc error No. 1 


tool: D14: error imatrix: calloc error No. 2 


assistant: ```c
int **imatrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  int **m;
  if ((m = (int **)calloc(nrow, sizeof(int *))) == NULL) {
    printf("error imatrix: calloc error No. 1 \n");
    return (NULL);
  }
  m += 0;
  m -= ncl;
  if ((m[nrl] = (int *)calloc(nrow * ncol, sizeof(int))) == NULL) {
    printf("error imatrix: calloc error No. 2 \n");
    return (NULL);
  }
  m[nrl] += 0;
  m[nrl] -= nrl;
  for (i = nrl + 1; i <= nrh; i++) {
    m[i] = m[i - 1] + ncol;
  }
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<imatrix>:
  endbr64
  push   %r15
  sub    %rdx,%rcx
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  sub    %rdi,%r13
  push   %rbp
  add    $0x1,%r13
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %r13,%rdi
  lea    0x1(%rcx),%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L24
  mov    %r13,%rdi
  shl    $0x3,%r15
  mov    $0x4,%esi
  imul   %rbx,%rdi
  sub    %r15,%r12
  call   <calloc@plt>
  lea    (%r12,%r14,8),%rdx
  mov    %rax,(%rdx)
  test   %rax,%rax
  je     L46
  lea    0x0(,%r14,4),%rcx
  sub    %rcx,%rax
  mov    %rax,(%rdx)
  cmp    %r14,%rbp
  jle    L58
  lea    0x0(,%rbx,4),%rsi
  lea    (%r12,%rbp,8),%rax
  nopl   0x0(%rax)
L51:
  mov    (%rdx),%rcx
  add    $0x8,%rdx
  add    %rsi,%rcx
  mov    %rcx,(%rdx)
  cmp    %rax,%rdx
  jne    L51
L58:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L24:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L58
L46:
  lea    D11(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L58
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string

tool: D7: error imatrix: calloc error No. 1 


tool: D11: error imatrix: calloc error No. 2 


assistant: ```c
int **imatrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  int **m;
  if ((m = (int **)calloc(nrow, sizeof(int *))) == NULL) {
    printf("error imatrix: calloc error No. 1 \n");
    return (NULL);
  }
  m += 0;
  m -= ncl;
  if ((m[nrl] = (int *)calloc(nrow * ncol, sizeof(int))) == NULL) {
    printf("error imatrix: calloc error No. 2 \n");
    return (NULL);
  }
  m[nrl] += 0;
  m[nrl] -= nrl;
  for (i = nrl + 1; i <= nrh; i++) {
    m[i] = m[i - 1] + ncol;
  }
  return m;
}
```