ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hd44780_ll_data_write>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <hd44780_ll_register_write@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int8_t hd44780_ll_data_write(uint8_t data) {
  if (hd44780_ll_register_write(data, 1)) {
    return (-1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hd44780_ll_data_write>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <hd44780_ll_register_write@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int8_t hd44780_ll_data_write(uint8_t data) {
  if (hd44780_ll_register_write(data, 1)) {
    return (-1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fb_ctor__astznodezconv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((constructor)) void fb_ctor__astznodezconv(void) {
label$0:;
label$1:;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fb_ctor__astznodezconv>:
  endbr64
  ret
```

assistant: ```c
__attribute__((constructor)) void fb_ctor__astznodezconv(void) {
label$0:;
label$1:;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fb_ctor__astznodezconv>:
  endbr64
  ret
```

assistant: ```c
__attribute__((constructor)) void fb_ctor__astznodezconv(void) {
label$0:;
label$1:;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fb_ctor__astznodezconv>:
  endbr64
  ret
```

assistant: ```c
__attribute__((constructor)) void fb_ctor__astznodezconv(void) {
label$0:;
label$1:;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xdr_pmaplist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    D35(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%ebx
  mov    $0x0,%r12d
  jmp    L39
L75:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xdr_bool@plt>
  test   %eax,%eax
  jne    L29
  mov    D53(%rip),%rax
  mov    (%rax),%rax
  jmp    L4
L29:
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L15
  mov    D21(%rip),%rax
  mov    (%rax),%rax
  jmp    L4
L15:
  test   %ebx,%ebx
  je     L61
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%r12
L61:
  mov    D39(%rip),%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x8,%edx
  mov    %rax,%rdi
  call   <xdr_reference@plt>
  test   %eax,%eax
  jne    L108
  mov    D53(%rip),%rax
  mov    (%rax),%rax
  jmp    L4
L108:
  test   %ebx,%ebx
  jne    L45
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  jmp    L32
L45:
  mov    %r12,%rax
L32:
  mov    %rax,-0x30(%rbp)
L39:
  mov    D21(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L75
L4:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
bool_t xdr_pmaplist(XDR *xdrs, struct pmaplist **rp) {
  bool_t more_elements;
  register int freeing = (xdrs->x_op == XDR_FREE);
  register struct pmaplist **next = NULL;
  while (TRUE) {
    more_elements = (bool_t)(*rp != NULL);
    if (!xdr_bool(xdrs, &more_elements))
      return (FALSE);
    if (!more_elements)
      return (TRUE);
    if (freeing)
      next = &((*rp)->pml_next);
    if (!xdr_reference(xdrs, (caddr_t *)rp, (u_int)sizeof(struct pmaplist), (xdrproc_t)xdr_pmap))
      return (FALSE);
    rp = (freeing) ? next : &((*rp)->pml_next);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<xdr_pmaplist>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%r13
  mov    D17(%rip),%rax
  mov    (%rax),%r14
  mov    D5(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L84
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsp,%r12
  jmp    L92
L67:
  mov    D32(%rip),%rax
  mov    (%rax),%rax
L84:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L78:
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  jmp    L84
L87:
  mov    (%rbx),%r15
  mov    D41(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x8,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <xdr_reference@plt>
  test   %eax,%eax
  je     L95
  mov    %r15,%rbx
  jmp    L60
L46:
  mov    (%rbx),%rbx
L60:
  mov    D5(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L84
L92:
  cmpq   $0x0,(%rbx)
  setne  %al
  movzbl %al,%eax
  mov    %rax,(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <xdr_bool@plt>
  test   %eax,%eax
  je     L67
  cmpq   $0x0,(%rsp)
  je     L78
  cmp    %r14,%r13
  je     L87
  mov    D41(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x8,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <xdr_reference@plt>
  test   %eax,%eax
  jne    L46
L95:
  mov    D32(%rip),%rax
  mov    (%rax),%rax
  jmp    L84
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_pmaplist(XDR *xdrs, struct pmaplist **rp) {
  bool_t more_elements;
  register int freeing = (xdrs->x_op == XDR_FREE);
  register struct pmaplist **next = NULL;
  while (TRUE) {
    more_elements = (bool_t)(*rp != NULL);
    if (!xdr_bool(xdrs, &more_elements))
      return (FALSE);
    if (!more_elements)
      return (TRUE);
    if (freeing)
      next = &((*rp)->pml_next);
    if (!xdr_reference(xdrs, (caddr_t *)rp, (u_int)sizeof(struct pmaplist), (xdrproc_t)xdr_pmap))
      return (FALSE);
    rp = (freeing) ? next : &((*rp)->pml_next);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<xdr_pmaplist>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    D18(%rip),%rbp
  mov    (%rdi),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x10(%rsp),%r12
  cmpq   $0x0,0x0(%rbp)
  mov    (%rax),%r13
  jne    L55
  jmp    L115
  nopl   (%rax)
L93:
  mov    $0x8,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <xdr_reference@plt>
  test   %eax,%eax
  je     L57
  cmpq   $0x0,0x0(%rbp)
  mov    (%r15),%r15
  je     L115
L55:
  xor    %eax,%eax
  cmpq   $0x0,(%r15)
  mov    %r12,%rsi
  mov    %rbx,%rdi
  setne  %al
  mov    %rax,0x10(%rsp)
  call   <xdr_bool@plt>
  test   %eax,%eax
  je     L57
  cmpq   $0x0,0x10(%rsp)
  je     L48
  mov    D20(%rip),%rax
  mov    (%rax),%ecx
  cmp    %r13,%r14
  jne    L93
  mov    (%r15),%rax
  mov    $0x8,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    %rax,0x8(%rsp)
  call   <xdr_reference@plt>
  test   %eax,%eax
  je     L57
  cmpq   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%r15
  jne    L55
  nopl   (%rax)
L115:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L57:
  mov    D17(%rip),%rax
  mov    (%rax),%rax
  jmp    L115
  nopl   0x0(%rax)
L48:
  mov    0x0(%rbp),%rax
  jmp    L115
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_pmaplist(XDR *xdrs, struct pmaplist **rp) {
  bool_t more_elements;
  register int freeing = (xdrs->x_op == XDR_FREE);
  register struct pmaplist **next = NULL;
  while (TRUE) {
    more_elements = (bool_t)(*rp != NULL);
    if (!xdr_bool(xdrs, &more_elements))
      return (FALSE);
    if (!more_elements)
      return (TRUE);
    if (freeing)
      next = &((*rp)->pml_next);
    if (!xdr_reference(xdrs, (caddr_t *)rp, (u_int)sizeof(struct pmaplist), (xdrproc_t)xdr_pmap))
      return (FALSE);
    rp = (freeing) ? next : &((*rp)->pml_next);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xdr_pmaplist>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D20(%rip),%r12
  mov    (%rdi),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D47(%rip),%rax
  cmpq   $0x0,(%r12)
  mov    (%rax),%rax
  je     L17
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsp,%r13
  cmp    %rax,%rdx
  jne    L100
  jmp    L14
  xchg   %ax,%ax
L114:
  cmpq   $0x0,(%rsp)
  je     L42
  mov    D30(%rip),%rax
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    (%rax),%ecx
  call   <xdr_reference@plt>
  test   %eax,%eax
  je     L20
  cmpq   $0x0,(%r12)
  mov    0x0(%rbp),%rbp
  je     L17
L100:
  xor    %eax,%eax
  cmpq   $0x0,0x0(%rbp)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  setne  %al
  mov    %rax,(%rsp)
  call   <xdr_bool@plt>
  test   %eax,%eax
  jne    L114
L20:
  mov    D6(%rip),%rax
  mov    (%rax),%rax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  cmpq   $0x0,(%rsp)
  je     L42
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    0x0(%rbp),%r14
  mov    D30(%rip),%rax
  mov    (%rax),%ecx
  call   <xdr_reference@plt>
  test   %eax,%eax
  je     L20
  cmpq   $0x0,(%r12)
  je     L17
  mov    %r14,%rbp
L14:
  xor    %eax,%eax
  cmpq   $0x0,0x0(%rbp)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  setne  %al
  mov    %rax,(%rsp)
  call   <xdr_bool@plt>
  test   %eax,%eax
  jne    L63
  jmp    L20
  nopl   0x0(%rax)
L42:
  mov    (%r12),%rax
  jmp    L17
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_pmaplist(XDR *xdrs, struct pmaplist **rp) {
  bool_t more_elements;
  register int freeing = (xdrs->x_op == XDR_FREE);
  register struct pmaplist **next = NULL;
  while (TRUE) {
    more_elements = (bool_t)(*rp != NULL);
    if (!xdr_bool(xdrs, &more_elements))
      return (FALSE);
    if (!more_elements)
      return (TRUE);
    if (freeing)
      next = &((*rp)->pml_next);
    if (!xdr_reference(xdrs, (caddr_t *)rp, (u_int)sizeof(struct pmaplist), (xdrproc_t)xdr_pmap))
      return (FALSE);
    rp = (freeing) ? next : &((*rp)->pml_next);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0xa,-0x14(%rbp)
  jle    L6
  movl   $0xa,-0x4(%rbp)
  jmp    L13
L6:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bar(int n) {
  int ret;
  if (n > 10)
    ret = 10;
  else
    ret = n / 2;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bar>:
  endbr64
  mov    $0xa,%eax
  cmp    $0xa,%edi
  jg     L0
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
L0:
  ret
```

assistant: ```c
int bar(int n) {
  int ret;
  if (n > 10)
    ret = 10;
  else
    ret = n / 2;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bar>:
  endbr64
  mov    $0xa,%eax
  cmp    $0xa,%edi
  jg     L1
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
L1:
  ret
```

assistant: ```c
int bar(int n) {
  int ret;
  if (n > 10)
    ret = 10;
  else
    ret = n / 2;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bar>:
  endbr64
  mov    $0xa,%eax
  cmp    $0xa,%edi
  jg     L6
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
L6:
  ret
```

assistant: ```c
int bar(int n) {
  int ret;
  if (n > 10)
    ret = 10;
  else
    ret = n / 2;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_vecs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x88(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L24
  mov    -0x88(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jg     L53
L24:
  mov    $0xffffffff,%eax
  jmp    L78
L53:
  mov    -0x88(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x7c(%rbp)
  mov    -0x88(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L2
L75:
  mov    -0x74(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x74(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x90(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L2:
  mov    -0x7c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x7c(%rbp)
  test   %eax,%eax
  jne    L75
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L68
L71:
  mov    -0x74(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x74(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L68:
  mov    -0x78(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x78(%rbp)
  test   %eax,%eax
  jne    L71
L78:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D44
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D37
type_guessed: string

tool: D44: %s %d

tool: D1: dim

tool: D13: %s

tool: D37: %lf

assistant: ```c
int read_vecs(int *one, double *two, double *three) {
  char line[100];
  scanf("%s %d", line, one);
  if (strcmp(line, "dim") != 0 || *one < 1) {
    return -1;
  }
  int count = *one, count2 = *one;
  scanf("%s", line);
  int i = 0;
  while (count-- != 0) {
    scanf("%lf", (two + i++));
  }
  scanf("%s", line);
  i = 0;
  while (count2-- != 0) {
    scanf("%lf", (three + i++));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_vecs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdi,%rdx
  mov    %r13,%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
  mov    (%rbx),%r13d
  test   %r13d,%r13d
  jle    L9
  mov    %rsp,%rsi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r12,%rbx
  lea    -0x1(%r13),%r13d
  shl    $0x3,%r13
  lea    0x8(%r12,%r13,1),%r14
  lea    D9(%rip),%r12
L40:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L40
  mov    %rsp,%rsi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbp,%rbx
  lea    0x8(%rbp,%r13,1),%r12
  lea    D9(%rip),%rbp
L17:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x8,%rbx
  cmp    %rbx,%r12
  jne    L17
  jmp    L6
L9:
  mov    $0xffffffff,%eax
L6:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D25
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D9
data_type: string

tool: D25: %s %d

tool: D12: dim

tool: D31: %s

tool: D9: %lf

assistant: ```c
int read_vecs(int *one, double *two, double *three) {
  char line[100];
  scanf("%s %d", line, one);
  if (strcmp(line, "dim") != 0 || *one < 1) {
    return -1;
  }
  int count = *one, count2 = *one;
  scanf("%s", line);
  int i = 0;
  while (count-- != 0) {
    scanf("%lf", (two + i++));
  }
  scanf("%s", line);
  i = 0;
  while (count2-- != 0) {
    scanf("%lf", (three + i++));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_vecs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x88,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rdi,%rdx
  lea    D28(%rip),%rdi
  mov    %r12,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D29(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L49
  mov    0x0(%r13),%r13d
  test   %r13d,%r13d
  jle    L49
  lea    -0x1(%r13),%r14d
  lea    D26(%rip),%r15
  mov    %r12,%rsi
  xor    %eax,%eax
  mov    %r15,%rdi
  shl    $0x3,%r14
  lea    D22(%rip),%rbp
  call   <scanf@plt>
  lea    0x8(%rbx,%r14,1),%r13
L37:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L37
  mov    %r12,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rbx
  lea    0x8(%rbx,%r14,1),%r12
  nopl   (%rax)
L48:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <scanf@plt>
  cmp    %rbx,%r12
  jne    L48
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L49:
  mov    $0xffffffff,%eax
L6:
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D28
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D22
type_infered: string

tool: D28: %s %d

tool: D29: dim

tool: D26: %s

tool: D22: %lf

assistant: ```c
int read_vecs(int *one, double *two, double *three) {
  char line[100];
  scanf("%s %d", line, one);
  if (strcmp(line, "dim") != 0 || *one < 1) {
    return -1;
  }
  int count = *one, count2 = *one;
  scanf("%s", line);
  int i = 0;
  while (count-- != 0) {
    scanf("%lf", (two + i++));
  }
  scanf("%s", line);
  i = 0;
  while (count2-- != 0) {
    scanf("%lf", (three + i++));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_vecs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x88,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rdi,%rdx
  lea    D29(%rip),%rdi
  mov    %r12,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L58
  mov    0x0(%r13),%r13d
  test   %r13d,%r13d
  jle    L58
  lea    -0x1(%r13),%r14d
  lea    D15(%rip),%r15
  mov    %r12,%rsi
  xor    %eax,%eax
  mov    %r15,%rdi
  shl    $0x3,%r14
  lea    D38(%rip),%rbp
  call   <scanf@plt>
  lea    0x8(%rbx,%r14,1),%r13
L33:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L33
  mov    %r12,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rbx
  lea    0x8(%rbx,%r14,1),%r12
  nopl   (%rax)
L47:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <scanf@plt>
  cmp    %rbx,%r12
  jne    L47
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L58:
  mov    $0xffffffff,%eax
L36:
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D38
type: string

tool: D29: %s %d

tool: D21: dim

tool: D15: %s

tool: D38: %lf

assistant: ```c
int read_vecs(int *one, double *two, double *three) {
  char line[100];
  scanf("%s %d", line, one);
  if (strcmp(line, "dim") != 0 || *one < 1) {
    return -1;
  }
  int count = *one, count2 = *one;
  scanf("%s", line);
  int i = 0;
  while (count-- != 0) {
    scanf("%lf", (two + i++));
  }
  scanf("%s", line);
  i = 0;
  while (count2-- != 0) {
    scanf("%lf", (three + i++));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xff,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  sar    $0xc,%eax
  test   %eax,%eax
  je     L3
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L3:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D16: Right

tool: D1: Wrong

assistant: ```c
main() {
  int a = 0xff;
  if ((a << 4) >> 12)
    printf("Right");
  else
    printf("Wrong");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: Wrong

assistant: ```c
main() {
  int a = 0xff;
  if ((a << 4) >> 12)
    printf("Right");
  else
    printf("Wrong");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Wrong

assistant: ```c
main() {
  int a = 0xff;
  if ((a << 4) >> 12)
    printf("Right");
  else
    printf("Wrong");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: Wrong

assistant: ```c
main() {
  int a = 0xff;
  if ((a << 4) >> 12)
    printf("Right");
  else
    printf("Wrong");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<backtrack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <backtrack_co@plt>
  nop
  leave
  ret
```

assistant: ```c
void backtrack(const char *sequence) {
  backtrack_co(sequence, 0, 0);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<backtrack>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <backtrack_co@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void backtrack(const char *sequence) {
  backtrack_co(sequence, 0, 0);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<backtrack>:
  endbr64
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    1050 <backtrack_co@plt>
```

assistant: ```c
void backtrack(const char *sequence) {
  backtrack_co(sequence, 0, 0);
  return;
}
```