ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x150,%edx
  mov    $0x150,%esi
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffeb0,%edx
  mov    $0xfffffeb0,%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x150,%edx
  mov    $0x150,%esi
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0x10052,%ecx
  xor    %eax,%eax
  mov    $0x10052,%edx
  mov    $0x10052,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D33
type: string
name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D36
type: string
name: retrieve_data
arguments: tag: D4
type: string

tool: D33: num as short and unsigned short: %hd %hu


tool: D13: -num as short and unsigned short: %hd %hu


tool: D36: num as int and char: %d %c


tool: D4: WORDS as int, short, and char: %d %hd %c


assistant: ```c
int main(void) {
  short num = 336;
  short mnum = -336;
  printf("num as short and unsigned short: %hd %hu\n", num, num);
  printf("-num as short and unsigned short: %hd %hu\n", mnum, mnum);
  printf("num as int and char: %d %c\n", num, num);
  printf("WORDS as int, short, and char: %d %hd %c\n", 65618, 65618, 65618);
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<toone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *toone(int *x) {
  x[0] = 1;
  x[1] = 1;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toone>:
  endbr64
  mov    %rdi,%rax
  movl   $0x1,(%rdi)
  movl   $0x1,0x4(%rdi)
  ret
```

assistant: ```c
int *toone(int *x) {
  x[0] = 1;
  x[1] = 1;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<toone>:
  endbr64
  movabs $0x100000001,%rdx
  mov    %rdi,%rax
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
int *toone(int *x) {
  x[0] = 1;
  x[1] = 1;
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<toone>:
  endbr64
  mov    D2(%rip),%rdx
  mov    %rdi,%rax
  mov    %rdx,(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: byte[8]

tool: {"D2": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int *toone(int *x) {
  x[0] = 1;
  x[1] = 1;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utilStrInsertChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x1c(%rbp),%eax
  mov    %al,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xa(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <utilStrInsertChars@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void utilStrInsertChar(char *str, char c) {
  char chars[2];
  chars[0] = c;
  chars[1] = '\0';
  utilStrInsertChars(str, chars);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utilStrInsertChar>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%rsi
  call   <utilStrInsertChars@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void utilStrInsertChar(char *str, char c) {
  char chars[2];
  chars[0] = c;
  chars[1] = '\0';
  utilStrInsertChars(str, chars);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utilStrInsertChar>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <utilStrInsertChars@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void utilStrInsertChar(char *str, char c) {
  char chars[2];
  chars[0] = c;
  chars[1] = '\0';
  utilStrInsertChars(str, chars);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utilStrInsertChar>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <utilStrInsertChars@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void utilStrInsertChar(char *str, char c) {
  char chars[2];
  chars[0] = c;
  chars[1] = '\0';
  utilStrInsertChars(str, chars);
}
```
user: What is the c source code of the assembly code below?

```asm
<exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x8c004004,%eax
  mov    (%rax),%eax
  cmp    $0xdeadbeef,%eax
  jne    L2
  mov    $0xf,%edi
  call   <dcloadsyscall@plt>
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void exit(int status) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    dcloadsyscall(15);
  __exit(status);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8c004004,%eax
  cmpl   $0xdeadbeef,(%rax)
  je     L5
L19:
  mov    %ebx,%edi
  call   <__exit@plt>
L5:
  mov    $0xf,%edi
  call   <dcloadsyscall@plt>
  jmp    L19
```

assistant: ```c
void exit(int status) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    dcloadsyscall(15);
  __exit(status);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<exit>:
  endbr64
  mov    $0x8c004004,%eax
  push   %rbp
  mov    %edi,%ebp
  cmpl   $0xdeadbeef,(%rax)
  je     L19
L10:
  mov    %ebp,%edi
  call   <__exit@plt>
L19:
  mov    $0xf,%edi
  call   <dcloadsyscall@plt>
  jmp    L10
```

assistant: ```c
void exit(int status) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    dcloadsyscall(15);
  __exit(status);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<exit>:
  endbr64
  mov    $0x8c004004,%eax
  push   %rbp
  mov    %edi,%ebp
  cmpl   $0xdeadbeef,(%rax)
  je     L16
L11:
  mov    %ebp,%edi
  call   <__exit@plt>
L16:
  mov    $0xf,%edi
  call   <dcloadsyscall@plt>
  jmp    L11
```

assistant: ```c
void exit(int status) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    dcloadsyscall(15);
  __exit(status);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BrzBinaryFuncConstRPush_ackup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x1,%edi
  call   <SEND_ACKUP@plt>
  nop
  leave
  ret
```

assistant: ```c
void BrzBinaryFuncConstRPush_ackup(struct comp *comp, int port) {
  struct BrzBinaryFuncConstR_ *c = (struct BrzBinaryFuncConstR_ *)comp;
  SEND_ACKUP(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BrzBinaryFuncConstRPush_ackup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <SEND_ACKUP@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BrzBinaryFuncConstRPush_ackup(struct comp *comp, int port) {
  struct BrzBinaryFuncConstR_ *c = (struct BrzBinaryFuncConstR_ *)comp;
  SEND_ACKUP(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BrzBinaryFuncConstRPush_ackup>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <SEND_ACKUP@plt>
```

assistant: ```c
void BrzBinaryFuncConstRPush_ackup(struct comp *comp, int port) {
  struct BrzBinaryFuncConstR_ *c = (struct BrzBinaryFuncConstR_ *)comp;
  SEND_ACKUP(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<BrzBinaryFuncConstRPush_ackup>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <SEND_ACKUP@plt>
```

assistant: ```c
void BrzBinaryFuncConstRPush_ackup(struct comp *comp, int port) {
  struct BrzBinaryFuncConstR_ *c = (struct BrzBinaryFuncConstR_ *)comp;
  SEND_ACKUP(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L41:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L3
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L37
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L37:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L25
L3:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L41
  mov    -0x8(%rbp),%eax
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D3
type_infered: string

tool: D14: read

tool: D3: read_bytes(): error reading data

assistant: ```c
int read_bytes(int fd, int n, unsigned char *b) {
  int t = 0, l;
  while (t < n) {
    l = read(fd, b + t, n - t);
    if (l <= 0) {
      if (l == -1)
        perror("read");
      puts("read_bytes(): error reading data");
      return -1;
    }
    t += l;
  }
  return t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_bytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L48
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    $0x0,%ebx
L43:
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L23
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jg     L43
  jmp    L17
L23:
  cmp    $0xffffffff,%eax
  je     L14
L29:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%ebx
L17:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  jmp    L29
L48:
  mov    $0x0,%ebx
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_infered: string
name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D15: read_bytes(): error reading data

tool: D7: read

assistant: ```c
int read_bytes(int fd, int n, unsigned char *b) {
  int t = 0, l;
  while (t < n) {
    l = read(fd, b + t, n - t);
    if (l <= 0) {
      if (l == -1)
        perror("read");
      puts("read_bytes(): error reading data");
      return -1;
    }
    t += l;
  }
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_bytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L60
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rdx,%r13
  xor    %r12d,%r12d
  jmp    L13
  xchg   %ax,%ax
L34:
  add    %eax,%r12d
  cmp    %r12d,%ebx
  jle    L43
L13:
  mov    %ebx,%edx
  movslq %r12d,%rsi
  mov    %ebp,%edi
  sub    %r12d,%edx
  add    %r13,%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L34
  cmp    $0xffffffff,%eax
  je     L9
L3:
  lea    D3(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
L43:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  lea    D13(%rip),%rdi
  call   <perror@plt>
  jmp    L3
L60:
  xor    %r12d,%r12d
  jmp    L43
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string

tool: D3: read_bytes(): error reading data

tool: D13: read

assistant: ```c
int read_bytes(int fd, int n, unsigned char *b) {
  int t = 0, l;
  while (t < n) {
    l = read(fd, b + t, n - t);
    if (l <= 0) {
      if (l == -1)
        perror("read");
      puts("read_bytes(): error reading data");
      return -1;
    }
    t += l;
  }
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_bytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L56
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rdx,%r13
  xor    %r12d,%r12d
  jmp    L17
  xchg   %ax,%ax
L4:
  add    %eax,%r12d
  cmp    %r12d,%ebx
  jle    L60
L17:
  mov    %ebx,%edx
  movslq %r12d,%rsi
  mov    %ebp,%edi
  sub    %r12d,%edx
  add    %r13,%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L4
  cmp    $0xffffffff,%eax
  je     L43
L54:
  lea    D5(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
L60:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  lea    D12(%rip),%rdi
  call   <perror@plt>
  jmp    L54
L56:
  xor    %r12d,%r12d
  jmp    L60
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string
name: read_data
arguments: label: D12
type_guessed: string

tool: D5: read_bytes(): error reading data

tool: D12: read

assistant: ```c
int read_bytes(int fd, int n, unsigned char *b) {
  int t = 0, l;
  while (t < n) {
    l = read(fd, b + t, n - t);
    if (l <= 0) {
      if (l == -1)
        perror("read");
      puts("read_bytes(): error reading data");
      return -1;
    }
    t += l;
  }
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sqrt_newton2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L35
L28:
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  comisd -0x28(%rbp),%xmm2
  jbe    L1
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L23
L1:
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L23:
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L35:
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <abs@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm3
  comisd -0x30(%rbp),%xmm3
  ja     L28
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: f64

tool: D7: 2

assistant: ```c
double sqrt_newton2(double num, double precision) {
  double lo = 0.0;
  double hi = num;
  double prev = 0.0;
  double mid = (lo + hi) / 2.0;
  while (abs(mid - prev) > precision) {
    if (pow(mid, 2) > num)
      hi = mid;
    else
      lo = mid;
    prev = mid;
    mid = (lo + hi) / 2.0;
  }
  return mid;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sqrt_newton2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movq   %xmm0,%rbp
  movsd  %xmm1,0x18(%rsp)
  pxor   %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D0(%rip),%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,0x10(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  jmp    L7
L6:
  mov    $0x2,%edi
  movq   %rbx,%xmm0
  call   <pow@plt>
  movq   %rbp,%xmm1
  cmpltsd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm2
  andpd  %xmm1,%xmm2
  movq   %rbx,%xmm6
  andnpd %xmm6,%xmm1
  movapd %xmm1,%xmm3
  orpd   %xmm2,%xmm3
  movsd  %xmm3,0x8(%rsp)
  movq   %rbp,%xmm1
  cmpltsd %xmm0,%xmm1
  movq   %rbx,%xmm0
  andpd  %xmm1,%xmm0
  movsd  0x10(%rsp),%xmm7
  andnpd %xmm7,%xmm1
  movapd %xmm1,%xmm4
  orpd   %xmm0,%xmm4
  movsd  %xmm4,0x10(%rsp)
  addsd  %xmm4,%xmm3
  movapd %xmm3,%xmm1
  movq   %rbx,%xmm0
  mulsd  D0(%rip),%xmm1
  movq   %xmm1,%rbx
L7:
  movq   %rbx,%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <abs@plt>
  comisd 0x18(%rsp),%xmm0
  ja     L6
  movq   %rbx,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: f32[2]

tool: {"D0": [0.0,1.75]}

assistant: ```c
double sqrt_newton2(double num, double precision) {
  double lo = 0.0;
  double hi = num;
  double prev = 0.0;
  double mid = (lo + hi) / 2.0;
  while (abs(mid - prev) > precision) {
    if (pow(mid, 2) > num)
      hi = mid;
    else
      lo = mid;
    prev = mid;
    mid = (lo + hi) / 2.0;
  }
  return mid;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sqrt_newton2>:
  endbr64
  sub    $0x38,%rsp
  movapd %xmm0,%xmm7
  movsd  %xmm0,0x28(%rsp)
  pxor   %xmm0,%xmm0
  movsd  %xmm1,0x20(%rsp)
  movapd %xmm7,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm7,0x18(%rsp)
  mulsd  D14(%rip),%xmm1
  movsd  %xmm0,0x10(%rsp)
  jmp    L15
  nopl   (%rax)
L4:
  movapd %xmm1,%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm7
  movapd %xmm0,%xmm2
  movsd  0x28(%rsp),%xmm0
  cmpltsd %xmm2,%xmm0
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm3
  andpd  %xmm0,%xmm2
  andnpd %xmm1,%xmm3
  orpd   %xmm2,%xmm3
  movapd %xmm1,%xmm2
  andpd  %xmm0,%xmm2
  andnpd %xmm7,%xmm0
  movapd %xmm3,%xmm4
  movsd  %xmm3,0x10(%rsp)
  movapd %xmm0,%xmm5
  movapd %xmm1,%xmm0
  movsd  D14(%rip),%xmm1
  orpd   %xmm2,%xmm5
  addsd  %xmm5,%xmm4
  movsd  %xmm5,0x18(%rsp)
  mulsd  %xmm4,%xmm1
L15:
  movapd %xmm1,%xmm2
  movsd  %xmm1,0x8(%rsp)
  subsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  call   <abs@plt>
  comisd 0x20(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  ja     L4
  movapd %xmm1,%xmm0
  add    $0x38,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
data_type: f32[2]

tool: {"D14": [0.0,1.75]}

assistant: ```c
double sqrt_newton2(double num, double precision) {
  double lo = 0.0;
  double hi = num;
  double prev = 0.0;
  double mid = (lo + hi) / 2.0;
  while (abs(mid - prev) > precision) {
    if (pow(mid, 2) > num)
      hi = mid;
    else
      lo = mid;
    prev = mid;
    mid = (lo + hi) / 2.0;
  }
  return mid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqrt_newton2>:
  endbr64
  sub    $0x38,%rsp
  movapd %xmm0,%xmm7
  movsd  %xmm0,0x28(%rsp)
  pxor   %xmm0,%xmm0
  movsd  %xmm1,0x20(%rsp)
  movapd %xmm7,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm7,0x18(%rsp)
  mulsd  D10(%rip),%xmm1
  movsd  %xmm0,0x10(%rsp)
  jmp    L18
  nopl   (%rax)
L14:
  movapd %xmm1,%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm7
  movapd %xmm0,%xmm2
  movsd  0x28(%rsp),%xmm0
  cmpltsd %xmm2,%xmm0
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm3
  andpd  %xmm0,%xmm2
  andnpd %xmm1,%xmm3
  orpd   %xmm2,%xmm3
  movapd %xmm1,%xmm2
  andpd  %xmm0,%xmm2
  andnpd %xmm7,%xmm0
  movapd %xmm3,%xmm4
  movsd  %xmm3,0x10(%rsp)
  movapd %xmm0,%xmm5
  movapd %xmm1,%xmm0
  movsd  D10(%rip),%xmm1
  orpd   %xmm2,%xmm5
  addsd  %xmm5,%xmm4
  movsd  %xmm5,0x18(%rsp)
  mulsd  %xmm4,%xmm1
L18:
  movapd %xmm1,%xmm2
  movsd  %xmm1,0x8(%rsp)
  subsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  call   <abs@plt>
  comisd 0x20(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  ja     L14
  movapd %xmm1,%xmm0
  add    $0x38,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: f32[2]

tool: {"D10": [0.0,1.75]}

assistant: ```c
double sqrt_newton2(double num, double precision) {
  double lo = 0.0;
  double hi = num;
  double prev = 0.0;
  double mid = (lo + hi) / 2.0;
  while (abs(mid - prev) > precision) {
    if (pow(mid, 2) > num)
      hi = mid;
    else
      lo = mid;
    prev = mid;
    mid = (lo + hi) / 2.0;
  }
  return mid;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x7000(%rsp),%r11
L34:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L34
  sub    $0x4e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x83fe65,%edi
  call   <srand48@plt>
  lea    -0x3420(%rbp),%rax
  mov    %rax,%rdi
  call   <fillVal@plt>
  lea    -0x6d10(%rbp),%rax
  mov    %rax,%rdi
  call   <fill@plt>
  lea    -0x74d0(%rbp),%rdx
  lea    -0x4e30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <initMat@plt>
  lea    -0x5da0(%rbp),%rax
  mov    %rax,%rdi
  call   <initOut@plt>
  lea    -0x5da0(%rbp),%rdi
  lea    -0x6d10(%rbp),%rcx
  lea    -0x74d0(%rbp),%rdx
  lea    -0x4e30(%rbp),%rsi
  lea    -0x3420(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <spmv@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x74d4(%rbp)
  jmp    L7
L13:
  mov    -0x74d4(%rbp),%eax
  cltq
  mov    -0x5da0(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x74d4(%rbp)
L7:
  cmpl   $0x1ed,-0x74d4(%rbp)
  jle    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: %d 

assistant: ```c
int main() {
  double nzval[1666];
  double x[494];
  double y[494];
  int colind[1666];
  int rowptr[494 + 1];
  int i;
  srand48(8650341L);
  fillVal(nzval);
  fill(x);
  initMat(colind, rowptr);
  initOut(y);
  spmv(nzval, colind, rowptr, x, y);
  printf("\n");
  for (i = 0; i < 494; i++) {
    printf("%d ", y[i]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x4d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x74c8(%rsp)
  xor    %eax,%eax
  mov    $0x83fe65,%edi
  call   <srand48@plt>
  lea    0x40b0(%rsp),%rbp
  mov    %rbp,%rdi
  call   <fillVal@plt>
  lea    0x7c0(%rsp),%r14
  mov    %r14,%rdi
  call   <fill@plt>
  mov    %rsp,%r13
  lea    0x26a0(%rsp),%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <initMat@plt>
  lea    0x1730(%rsp),%rbx
  mov    %rbx,%rdi
  call   <initOut@plt>
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <spmv@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D7(%rip),%rbp
L21:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x74c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x74d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d 

assistant: ```c
int main() {
  double nzval[1666];
  double x[494];
  double y[494];
  int colind[1666];
  int rowptr[494 + 1];
  int i;
  srand48(8650341L);
  fillVal(nzval);
  fill(x);
  initMat(colind, rowptr);
  initOut(y);
  spmv(nzval, colind, rowptr, x, y);
  printf("\n");
  for (i = 0; i < 494; i++) {
    printf("%d ", y[i]);
  }
  printf("\n");
  return 0;
}
```