ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strnappend>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rax
  or     %rsi,%rax
  je     L12
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  test   %rdi,%rdi
  je     L40
  test   %rsi,%rsi
  je     L53
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    $0x0,%r14d
  add    %r12,%rax
  jb     L10
  lea    0x1(%r12,%r13,1),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L10
  mov    %rax,%r14
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  add    %r13,%r15
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r15,%r12,1)
L10:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  lea    D2(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%r14
  jmp    L10
L40:
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  call   <strndup@plt>
  mov    %rax,%r14
  jmp    L10
L53:
  call   <strdup@plt>
  mov    %rax,%r14
  jmp    L10
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: 

assistant: ```c
char *strnappend(const char *s, const char *suffix, size_t b) {
  size_t a;
  char *r;
  if (!s && !suffix)
    return strdup("");
  if (!s)
    return strndup(suffix, b);
  if (!suffix)
    return strdup(s);
  assert(s);
  assert(suffix);
  a = strlen(s);
  if (b > ((size_t)-1) - a)
    return NULL;
  r = ((char *)malloc(sizeof(char) * (a + b + 1)));
  if (!r)
    return NULL;
  memcpy(r, s, a);
  memcpy(r + a, suffix, b);
  r[a + b] = 0;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strnappend>:
  endbr64
  mov    %rdi,%rax
  or     %rsi,%rax
  je     L33
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %rdi,%rdi
  je     L28
  test   %rsi,%rsi
  je     L36
  call   <assert@plt>
  mov    %r14,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  add    %r12,%rax
  jb     L8
  lea    0x1(%r12,%rbx,1),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L8
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  add    %r13,%rbx
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  lea    D6(%rip),%rdi
  jmp    10f0 <strdup@plt>
  nopl   0x0(%rax)
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10f0 <strdup@plt>
  nopl   (%rax)
L28:
  pop    %rbx
  mov    %r14,%rdi
  pop    %rbp
  mov    %rdx,%rsi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <strndup@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: 

assistant: ```c
char *strnappend(const char *s, const char *suffix, size_t b) {
  size_t a;
  char *r;
  if (!s && !suffix)
    return strdup("");
  if (!s)
    return strndup(suffix, b);
  if (!suffix)
    return strdup(s);
  assert(s);
  assert(suffix);
  a = strlen(s);
  if (b > ((size_t)-1) - a)
    return NULL;
  r = ((char *)malloc(sizeof(char) * (a + b + 1)));
  if (!r)
    return NULL;
  memcpy(r, s, a);
  memcpy(r + a, suffix, b);
  r[a + b] = 0;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strnappend>:
  endbr64
  mov    %rdi,%rax
  or     %rsi,%rax
  je     L16
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %rdi,%rdi
  je     L18
  test   %rsi,%rsi
  je     L15
  call   <assert@plt>
  mov    %r14,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  add    %r12,%rax
  jb     L26
  lea    0x1(%r12,%rbx,1),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L26
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  add    %r13,%rbx
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  lea    D1(%rip),%rdi
  jmp    10f0 <strdup@plt>
  nopl   0x0(%rax)
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10f0 <strdup@plt>
  nopl   (%rax)
L18:
  pop    %rbx
  mov    %r14,%rdi
  pop    %rbp
  mov    %rdx,%rsi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <strndup@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: 

assistant: ```c
char *strnappend(const char *s, const char *suffix, size_t b) {
  size_t a;
  char *r;
  if (!s && !suffix)
    return strdup("");
  if (!s)
    return strndup(suffix, b);
  if (!suffix)
    return strdup(s);
  assert(s);
  assert(suffix);
  a = strlen(s);
  if (b > ((size_t)-1) - a)
    return NULL;
  r = ((char *)malloc(sizeof(char) * (a + b + 1)));
  if (!r)
    return NULL;
  memcpy(r, s, a);
  memcpy(r + a, suffix, b);
  r[a + b] = 0;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_ktime_ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x20(%rbp),%rax
  imul   $0x3b9aca00,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned long long get_ktime_ns(void) {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000000ULL + ts.tv_nsec;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_ktime_ns>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long get_ktime_ns(void) {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000000ULL + ts.tv_nsec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_ktime_ns>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long get_ktime_ns(void) {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000000ULL + ts.tv_nsec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ktime_ns>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long get_ktime_ns(void) {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return ts.tv_sec * 1000000000ULL + ts.tv_nsec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L26:
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  add    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  and    $0xf0000000,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L24
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  xor    %eax,-0x10(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  not    %eax
  and    %eax,-0x10(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t strhash(const char *name) {
  const uint8_t *p = (uint8_t *)name;
  uint32_t h = 0, g;
  while (*p) {
    h = (h << 4) + *p++;
    if ((g = (h & 0xf0000000)) != 0)
      h ^= (g >> 24);
    h &= ~g;
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strhash>:
  endbr64
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  je     L5
  mov    $0x0,%eax
L6:
  add    $0x8,%rdi
  shl    $0x4,%eax
  add    %eax,%edx
  mov    %edx,%eax
  and    $0xf0000000,%eax
  mov    %eax,%ecx
  sar    $0x18,%ecx
  xor    %edx,%ecx
  test   %eax,%eax
  cmovne %ecx,%edx
  not    %eax
  and    %edx,%eax
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  jne    L6
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint32_t strhash(const char *name) {
  const uint8_t *p = (uint8_t *)name;
  uint32_t h = 0, g;
  while (*p) {
    h = (h << 4) + *p++;
    if ((g = (h & 0xf0000000)) != 0)
      h ^= (g >> 24);
    h &= ~g;
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strhash>:
  endbr64
  mov    (%rdi),%rdx
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L13
  xchg   %ax,%ax
L16:
  shl    $0x4,%eax
  add    $0x8,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  and    $0xf0000000,%eax
  mov    %eax,%ecx
  sar    $0x18,%ecx
  xor    %edx,%ecx
  test   %eax,%eax
  not    %eax
  cmovne %ecx,%edx
  and    %edx,%eax
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  jne    L16
  ret
  nopl   0x0(%rax)
L13:
  ret
```

assistant: ```c
uint32_t strhash(const char *name) {
  const uint8_t *p = (uint8_t *)name;
  uint32_t h = 0, g;
  while (*p) {
    h = (h << 4) + *p++;
    if ((g = (h & 0xf0000000)) != 0)
      h ^= (g >> 24);
    h &= ~g;
  }
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strhash>:
  endbr64
  mov    (%rdi),%rdx
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L14
  xchg   %ax,%ax
L39:
  shl    $0x4,%eax
  add    $0x8,%rdi
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L20
  mov    %edx,%ecx
  not    %edx
  sar    $0x18,%ecx
  xor    %ecx,%eax
  and    %edx,%eax
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  jne    L39
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  jne    L39
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
uint32_t strhash(const char *name) {
  const uint8_t *p = (uint8_t *)name;
  uint32_t h = 0, g;
  while (*p) {
    h = (h << 4) + *p++;
    if ((g = (h & 0xf0000000)) != 0)
      h ^= (g >> 24);
    h &= ~g;
  }
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bubblesort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L49:
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L35:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L41
  movl   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L41:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L35
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jge    L24
  cmpl   $0x1,-0x10(%rbp)
  je     L49
L24:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubblesort(int a[], int n) {
  bool flip = true;
  for (int i = 0; i < n - 1 && flip == true; i++) {
    flip = false;
    for (int j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        flip = true;
        int key = a[j];
        a[j] = a[j + 1];
        a[j + 1] = key;
      }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bubblesort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebp
  test   %ebp,%ebp
  jle    L48
  mov    %rdi,%r8
  mov    %esi,%ebx
  mov    %ebp,%r9d
  mov    $0x0,%r11d
  mov    $0x0,%edx
  mov    $0x0,%r13d
  mov    $0x1,%r10d
  mov    $0x0,%r12d
  jmp    L45
L4:
  add    $0x1,%edx
  cmp    %r9d,%edx
  jge    L40
L45:
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%r8,%rax,1),%rsi
  mov    (%rsi),%ecx
  lea    0x4(%r8,%rax,1),%rax
  mov    (%rax),%edi
  cmp    %edi,%ecx
  jle    L4
  mov    %edi,(%rsi)
  mov    %ecx,(%rax)
  mov    %r10d,%r13d
  jmp    L4
L40:
  add    $0x1,%r11d
  cmp    $0x1,%r13d
  jne    L48
  cmp    %ebp,%r11d
  jge    L48
  mov    %ebx,%r9d
  sub    %r11d,%r9d
  sub    $0x1,%r9d
  test   %r9d,%r9d
  jle    L48
  mov    $0x0,%edx
  mov    %r12d,%r13d
  jmp    L45
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bubblesort(int a[], int n) {
  bool flip = true;
  for (int i = 0; i < n - 1 && flip == true; i++) {
    flip = false;
    for (int j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        flip = true;
        int key = a[j];
        a[j] = a[j + 1];
        a[j + 1] = key;
      }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bubblesort>:
  endbr64
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L1
  mov    %esi,%ebx
  mov    %rdi,%r9
  mov    %ebp,%r10d
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %edx,%edx
  xor    %r11d,%r11d
  nopl   (%rax)
L55:
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%rdi
  lea    0x4(%r9,%rax,1),%rax
  mov    (%rdi),%ecx
  mov    (%rax),%r8d
  cmp    %r8d,%ecx
  jle    L19
  mov    %r8d,(%rdi)
  mov    $0x1,%r11d
  mov    %ecx,(%rax)
L19:
  add    $0x1,%edx
  cmp    %r10d,%edx
  jl     L55
  add    $0x1,%esi
  cmp    %esi,%ebp
  jle    L1
  test   %r11d,%r11d
  je     L1
  mov    %ebx,%r10d
  sub    %esi,%r10d
  sub    $0x1,%r10d
  test   %r10d,%r10d
  jg     L16
L1:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bubblesort(int a[], int n) {
  bool flip = true;
  for (int i = 0; i < n - 1 && flip == true; i++) {
    flip = false;
    for (int j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        flip = true;
        int key = a[j];
        a[j] = a[j + 1];
        a[j + 1] = key;
      }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bubblesort>:
  endbr64
  push   %rbx
  lea    -0x1(%rsi),%ebx
  xor    %r11d,%r11d
  mov    %ebx,%r9d
  test   %ebx,%ebx
  jle    L0
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %edx,%edx
  xor    %r10d,%r10d
  nopl   (%rax)
L45:
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rcx
  movq   (%rcx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%r8d
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%r8d
  jle    L28
  movq   %xmm1,(%rcx)
  mov    $0x1,%r10d
L28:
  add    $0x1,%edx
  cmp    %r9d,%edx
  jl     L45
  add    $0x1,%r11d
  cmp    %r11d,%ebx
  jle    L0
  test   %r10d,%r10d
  je     L0
  mov    %esi,%r9d
  sub    %r11d,%r9d
  sub    $0x1,%r9d
  test   %r9d,%r9d
  jg     L11
L0:
  pop    %rbx
  ret
```

assistant: ```c
void bubblesort(int a[], int n) {
  bool flip = true;
  for (int i = 0; i < n - 1 && flip == true; i++) {
    flip = false;
    for (int j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        flip = true;
        int key = a[j];
        a[j] = a[j + 1];
        a[j + 1] = key;
      }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pfuncFullWithSym>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <getSequenceLengthInt@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x24(%rbp),%r9d
  mov    -0x20(%rbp),%r8d
  mov    -0x1c(%rbp),%ecx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  mov    0x40(%rbp),%edi
  push   %rdi
  push   0x38(%rbp)
  push   0x30(%rbp)
  push   0x28(%rbp)
  push   0x20(%rbp)
  mov    -0x2c(%rbp),%edi
  push   %rdi
  mov    -0x28(%rbp),%edi
  push   %rdi
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %rax,%rdi
  call   <pfuncFullWithSymHelper@plt>
  add    $0x50,%rsp
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
long double pfuncFullWithSym(int inputSeq[], int complexity, int naType, int dangles, long double temperature, int calcPairs, int permSymmetry, long double sodiumconc, long double magnesiumconc, int uselongsalt) {
  int nStrands;
  int seqlength = getSequenceLengthInt(inputSeq, &nStrands);
  return pfuncFullWithSymHelper(inputSeq, seqlength, nStrands, complexity, naType, dangles, temperature, calcPairs, permSymmetry, sodiumconc, magnesiumconc, uselongsalt);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pfuncFullWithSym>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  mov    %r9d,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <getSequenceLengthInt@plt>
  mov    %eax,%esi
  sub    $0x8,%rsp
  mov    0x88(%rsp),%eax
  push   %rax
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   %r15
  push   %r14
  push   0x98(%rsp)
  push   0x98(%rsp)
  mov    %r13d,%r9d
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  mov    0x54(%rsp),%edx
  mov    %rbx,%rdi
  call   <pfuncFullWithSymHelper@plt>
  add    $0x50,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double pfuncFullWithSym(int inputSeq[], int complexity, int naType, int dangles, long double temperature, int calcPairs, int permSymmetry, long double sodiumconc, long double magnesiumconc, int uselongsalt) {
  int nStrands;
  int seqlength = getSequenceLengthInt(inputSeq, &nStrands);
  return pfuncFullWithSymHelper(inputSeq, seqlength, nStrands, complexity, naType, dangles, temperature, calcPairs, permSymmetry, sodiumconc, magnesiumconc, uselongsalt);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pfuncFullWithSym>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <getSequenceLengthInt@plt>
  sub    $0x8,%rsp
  mov    %r13d,%r9d
  mov    %ebx,%r8d
  mov    %eax,%esi
  mov    0x88(%rsp),%eax
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  push   %rax
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   %r15
  push   %r14
  push   0x98(%rsp)
  push   0x98(%rsp)
  mov    0x54(%rsp),%edx
  call   <pfuncFullWithSymHelper@plt>
  add    $0x50,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double pfuncFullWithSym(int inputSeq[], int complexity, int naType, int dangles, long double temperature, int calcPairs, int permSymmetry, long double sodiumconc, long double magnesiumconc, int uselongsalt) {
  int nStrands;
  int seqlength = getSequenceLengthInt(inputSeq, &nStrands);
  return pfuncFullWithSymHelper(inputSeq, seqlength, nStrands, complexity, naType, dangles, temperature, calcPairs, permSymmetry, sodiumconc, magnesiumconc, uselongsalt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pfuncFullWithSym>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <getSequenceLengthInt@plt>
  sub    $0x8,%rsp
  mov    %r13d,%r9d
  mov    %ebx,%r8d
  mov    %eax,%esi
  mov    0x88(%rsp),%eax
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  push   %rax
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   0x88(%rsp)
  push   %r15
  push   %r14
  push   0x98(%rsp)
  push   0x98(%rsp)
  mov    0x54(%rsp),%edx
  call   <pfuncFullWithSymHelper@plt>
  add    $0x50,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double pfuncFullWithSym(int inputSeq[], int complexity, int naType, int dangles, long double temperature, int calcPairs, int permSymmetry, long double sodiumconc, long double magnesiumconc, int uselongsalt) {
  int nStrands;
  int seqlength = getSequenceLengthInt(inputSeq, &nStrands);
  return pfuncFullWithSymHelper(inputSeq, seqlength, nStrands, complexity, naType, dangles, temperature, calcPairs, permSymmetry, sodiumconc, magnesiumconc, uselongsalt);
}
```