ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<to_hex>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D0(%rip),%r14
  lea    D26(%rip),%r13
L3:
  mov    (%r12,%rbx,4),%edx
  lea    (%r14,%rbx,2),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L3
  add    $0x1,%eax
L11:
  lea    D0(%rip),%rdx
  add    %eax,%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    $0x0,%eax
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
type: string

tool: D26: %02x

assistant: ```c
const char *to_hex(const uint8_t *text, size_t size) {
  static char hex[1024];
  int i;
  for (i = 0; i < size; i++) {
    sprintf(hex + 2 * i, "%02x", text[i]);
  }
  hex[2 * i] = 0;
  return hex;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<to_hex>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L28
  mov    %rdi,%r14
  mov    %rsi,%rbp
  lea    D29(%rip),%r12
  xor    %ebx,%ebx
  lea    D0(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%r14,%rbx,4),%edx
  lea    (%r12,%rbx,2),%rdi
  mov    %r13,%rsi
  add    $0x1,%rbx
  call   <sprintf@plt>
  cmp    %rbp,%rbx
  jne    L3
  add    %ebx,%ebx
L6:
  movslq %ebx,%rbx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L28:
  xor    %ebx,%ebx
  lea    D29(%rip),%r12
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: %02x

assistant: ```c
const char *to_hex(const uint8_t *text, size_t size) {
  static char hex[1024];
  int i;
  for (i = 0; i < size; i++) {
    sprintf(hex + 2 * i, "%02x", text[i]);
  }
  hex[2 * i] = 0;
  return hex;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_hex>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L21
  mov    %rdi,%r14
  mov    %rsi,%rbp
  lea    D27(%rip),%r12
  xor    %ebx,%ebx
  lea    D10(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%r14,%rbx,4),%edx
  lea    (%r12,%rbx,2),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L5
  lea    0x2(%rax,%rax,1),%eax
L29:
  cltq
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  lea    D27(%rip),%r12
  jmp    L29
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: string

tool: D10: %02x

assistant: ```c
const char *to_hex(const uint8_t *text, size_t size) {
  static char hex[1024];
  int i;
  for (i = 0; i < size; i++) {
    sprintf(hex + 2 * i, "%02x", text[i]);
  }
  hex[2 * i] = 0;
  return hex;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<zip_entry_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  mov    %rax,%rdi
  call   <readu2@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x2e,%rax
  leave
  ret
```

assistant: ```c
char *zip_entry_name(unsigned char *entry, int *lenp) {
  *lenp = readu2(entry + 28);
  return (char *)(entry + 46);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zip_entry_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x1c(%rdi),%rdi
  call   <readu2@plt>
  mov    %eax,0x0(%rbp)
  lea    0x2e(%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *zip_entry_name(unsigned char *entry, int *lenp) {
  *lenp = readu2(entry + 28);
  return (char *)(entry + 46);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zip_entry_name>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1c(%rdi),%rdi
  sub    $0x8,%rsp
  call   <readu2@plt>
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  lea    0x2e(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *zip_entry_name(unsigned char *entry, int *lenp) {
  *lenp = readu2(entry + 28);
  return (char *)(entry + 46);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zip_entry_name>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1c(%rdi),%rdi
  sub    $0x8,%rsp
  call   <readu2@plt>
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  lea    0x2e(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *zip_entry_name(unsigned char *entry, int *lenp) {
  *lenp = readu2(entry + 28);
  return (char *)(entry + 46);
}
```
user: Translate the below assembly code into C programming language:

```asm
<numeric_ready>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3a,%edi
  call   <strip_char_from_end@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xd,%edi
  call   <strip_char_from_end@plt>
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0xb,%edi
  call   <botevent@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string
name: disassemble_data
arguments: data_label: D29
type: string

tool: D7:  

tool: 

assistant: ```c
void numeric_ready(struct socket_info *sinfo, char *params) {
  char *channel, *info;
  strtok(params, " ");
  channel = strtok(NULL, " ");
  info = strtok(NULL, "");
  strip_char_from_end(':', info);
  strip_char_from_end('\r', info);
  botevent(11, sinfo, NULL, channel, info);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<numeric_ready>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  lea    D5(%rip),%rbx
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%r12
  lea    D0(%rip),%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    $0x3a,%edi
  call   <strip_char_from_end@plt>
  mov    %rbx,%rsi
  mov    $0xd,%edi
  call   <strip_char_from_end@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    $0xb,%edi
  call   <botevent@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string

tool: D5:  

tool: 

assistant: ```c
void numeric_ready(struct socket_info *sinfo, char *params) {
  char *channel, *info;
  strtok(params, " ");
  channel = strtok(NULL, " ");
  info = strtok(NULL, "");
  strip_char_from_end(':', info);
  strip_char_from_end('\r', info);
  botevent(11, sinfo, NULL, channel, info);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<numeric_ready>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %r12,%rsi
  push   %rbx
  call   <strtok@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  lea    D12(%rip),%rsi
  xor    %edi,%edi
  mov    %rax,%r12
  call   <strtok@plt>
  mov    $0x3a,%edi
  mov    %rax,%rbx
  mov    %rax,%rsi
  call   <strip_char_from_end@plt>
  mov    %rbx,%rsi
  mov    $0xd,%edi
  call   <strip_char_from_end@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  pop    %rbx
  mov    %rbp,%rsi
  xor    %edx,%edx
  pop    %rbp
  mov    $0xb,%edi
  pop    %r12
  jmp    1090 <botevent@plt>
```

tool_calls: name: retrieve_data
arguments: label: D13
datatype: string
name: retrieve_data
arguments: label: D12
datatype: string

tool: D13:  

tool: 

assistant: ```c
void numeric_ready(struct socket_info *sinfo, char *params) {
  char *channel, *info;
  strtok(params, " ");
  channel = strtok(NULL, " ");
  info = strtok(NULL, "");
  strip_char_from_end(':', info);
  strip_char_from_end('\r', info);
  botevent(11, sinfo, NULL, channel, info);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<numeric_ready>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %r12,%rsi
  push   %rbx
  call   <strtok@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  lea    D17(%rip),%rsi
  xor    %edi,%edi
  mov    %rax,%r12
  call   <strtok@plt>
  mov    $0x3a,%edi
  mov    %rax,%rbx
  mov    %rax,%rsi
  call   <strip_char_from_end@plt>
  mov    %rbx,%rsi
  mov    $0xd,%edi
  call   <strip_char_from_end@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  pop    %rbx
  mov    %rbp,%rsi
  xor    %edx,%edx
  pop    %rbp
  mov    $0xb,%edi
  pop    %r12
  jmp    1090 <botevent@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type: string
name: parse_data
arguments: tag: D17
type: string

tool: D4:  

tool: 

assistant: ```c
void numeric_ready(struct socket_info *sinfo, char *params) {
  char *channel, *info;
  strtok(params, " ");
  channel = strtok(NULL, " ");
  info = strtok(NULL, "");
  strip_char_from_end(':', info);
  strip_char_from_end('\r', info);
  botevent(11, sinfo, NULL, channel, info);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L11:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L39
L16:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L15
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jae    L15
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L15:
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(int num, unsigned int data[]) {
  int tmpSwap;
  for (int i = 0; i < num - 1; i++) {
    for (int j = i + 1; j < num; j++) {
      if (data[i] != 0 && data[i] < data[j]) {
        tmpSwap = data[i];
        data[i] = data[j];
        data[j] = tmpSwap;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  cmp    $0x1,%edi
  jle    L22
  push   %rbp
  push   %rbx
  mov    %edi,%r10d
  lea    0x4(%rsi),%rcx
  lea    -0x2(%rdi),%ebx
  add    $0x2,%rbx
  mov    $0x1,%r9d
  lea    -0x1(%rdi),%ebp
  lea    0x8(%rsi),%r11
  jmp    L57
L46:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L24
L40:
  mov    -0x4(%rcx),%edx
  test   %edx,%edx
  je     L46
  mov    (%rax),%edi
  cmp    %edi,%edx
  jae    L46
  mov    %edi,-0x4(%rcx)
  mov    %edx,(%rax)
  jmp    L46
L24:
  add    $0x1,%r9
  add    $0x4,%rcx
  cmp    %rbx,%r9
  je     L45
L57:
  cmp    %r9d,%r10d
  jle    L24
  mov    %ebp,%eax
  sub    %r9d,%eax
  lea    -0x1(%r9,%rax,1),%rax
  lea    (%r11,%rax,4),%r8
  mov    %rcx,%rax
  jmp    L40
L45:
  pop    %rbx
  pop    %rbp
  ret
L22:
  ret
```

assistant: ```c
void sort(int num, unsigned int data[]) {
  int tmpSwap;
  for (int i = 0; i < num - 1; i++) {
    for (int j = i + 1; j < num; j++) {
      if (data[i] != 0 && data[i] < data[j]) {
        tmpSwap = data[i];
        data[i] = data[j];
        data[j] = tmpSwap;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  cmp    $0x1,%edi
  jle    L45
  lea    -0x2(%rdi),%r11d
  push   %rbx
  mov    %edi,%r9d
  lea    0x4(%rsi),%rcx
  add    $0x2,%r11
  mov    $0x1,%r8d
  lea    -0x1(%rdi),%ebx
  lea    0x8(%rsi),%r10
  cs nopw 0x0(%rax,%rax,1)
L9:
  cmp    %r8d,%r9d
  jle    L15
  mov    %ebx,%eax
  sub    %r8d,%eax
  lea    -0x1(%r8,%rax,1),%rax
  lea    (%r10,%rax,4),%rdi
  mov    %rcx,%rax
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    -0x4(%rcx),%edx
  test   %edx,%edx
  je     L19
  mov    (%rax),%esi
  cmp    %esi,%edx
  jae    L19
  mov    %esi,-0x4(%rcx)
  mov    %edx,(%rax)
L19:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L36
L15:
  add    $0x1,%r8
  add    $0x4,%rcx
  cmp    %r11,%r8
  jne    L9
  pop    %rbx
  ret
L45:
  ret
```

assistant: ```c
void sort(int num, unsigned int data[]) {
  int tmpSwap;
  for (int i = 0; i < num - 1; i++) {
    for (int j = i + 1; j < num; j++) {
      if (data[i] != 0 && data[i] < data[j]) {
        tmpSwap = data[i];
        data[i] = data[j];
        data[j] = tmpSwap;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  cmp    $0x1,%edi
  jle    L8
  mov    %edi,%r9d
  lea    -0x2(%rdi),%r11d
  lea    0x4(%rsi),%r10
  push   %rbx
  mov    %r10,%rcx
  add    $0x2,%r11
  lea    -0x1(%r9),%ebx
  mov    $0x1,%edi
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rdi
  add    $0x4,%rcx
  cmp    %r11,%rdi
  je     L71
L3:
  cmp    %edi,%r9d
  jle    L1
  mov    %ebx,%eax
  mov    %rcx,%rdx
  sub    %edi,%eax
  lea    -0x1(%rdi,%rax,1),%rax
  lea    (%r10,%rax,4),%r8
L66:
  mov    -0x4(%rcx),%eax
  test   %eax,%eax
  je     L1
  mov    (%rdx),%esi
  cmp    %esi,%eax
  jae    L44
  mov    %esi,-0x4(%rcx)
  mov    %eax,(%rdx)
L44:
  cmp    %r8,%rdx
  je     L1
  add    $0x4,%rdx
  jmp    L66
  nop
L71:
  pop    %rbx
  ret
L8:
  ret
```

assistant: ```c
void sort(int num, unsigned int data[]) {
  int tmpSwap;
  for (int i = 0; i < num - 1; i++) {
    for (int j = i + 1; j < num; j++) {
      if (data[i] != 0 && data[i] < data[j]) {
        tmpSwap = data[i];
        data[i] = data[j];
        data[j] = tmpSwap;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L45
L5:
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L32:
  cmpl   $0x63,-0x4(%rbp)
  jg     L11
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L21:
  cmpl   $0x9,-0x8(%rbp)
  jle    L32
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L45:
  cmpl   $0x9,-0xc(%rbp)
  jle    L5
  jmp    L27
L11:
  nop
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: %10f 

assistant: ```c
void print_arr(double *arr) {
  int row, col, i = 0;
  printf("\n");
  for (row = 0; row < 10; row++) {
    for (col = 0; col < 10; col++) {
      if (i < 100) {
        printf("%10f ", arr[row * 10 + col]);
      } else {
        goto FINISH;
      }
      i++;
    }
    printf("\n");
  }
FINISH:
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_arr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r15,%r14
  add    $0x2d0,%r15
  mov    $0x0,%ebx
  lea    D3(%rip),%r12
L21:
  movsd  (%r14),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0xa(%rbx),%r13d
  mov    %r14,%rbp
  lea    0x1(%rbx),%ebx
L30:
  cmp    $0x63,%ebx
  jg     L11
  movsd  0x8(%rbp),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %r13d,%ebx
  jne    L30
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r15,%r14
  je     L11
  add    $0x50,%r14
  cmp    $0x63,%ebx
  jle    L21
L11:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: %10f 

assistant: ```c
void print_arr(double *arr) {
  int row, col, i = 0;
  printf("\n");
  for (row = 0; row < 10; row++) {
    for (col = 0; col < 10; col++) {
      if (i < 100) {
        printf("%10f ", arr[row * 10 + col]);
      } else {
        goto FINISH;
      }
      i++;
    }
    printf("\n");
  }
FINISH:
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_arr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    $0xa,%edi
  push   %r13
  lea    0x320(%r14),%r15
  lea    D2(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <putchar@plt>
L8:
  lea    0xa(%rbx),%r12d
  mov    %r14,%rbp
  cs nopw 0x0(%rax,%rax,1)
L5:
  cmp    $0x63,%ebx
  jg     L21
  movsd  0x0(%rbp),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%ebx
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L5
  mov    $0xa,%edi
  add    $0x50,%r14
  call   <putchar@plt>
  cmp    %r15,%r14
  jne    L8
L21:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: %10f 

assistant: ```c
void print_arr(double *arr) {
  int row, col, i = 0;
  printf("\n");
  for (row = 0; row < 10; row++) {
    for (col = 0; col < 10; col++) {
      if (i < 100) {
        printf("%10f ", arr[row * 10 + col]);
      } else {
        goto FINISH;
      }
      i++;
    }
    printf("\n");
  }
FINISH:
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_arr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    $0xa,%edi
  push   %r13
  lea    0x320(%r14),%r15
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <putchar@plt>
L0:
  lea    0xa(%rbx),%r12d
  mov    %r14,%rbp
  cs nopw 0x0(%rax,%rax,1)
L12:
  cmp    $0x63,%ebx
  jg     L7
  movsd  0x0(%rbp),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%ebx
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L12
  mov    $0xa,%edi
  add    $0x50,%r14
  call   <putchar@plt>
  cmp    %r15,%r14
  jne    L0
L7:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: %10f 

assistant: ```c
void print_arr(double *arr) {
  int row, col, i = 0;
  printf("\n");
  for (row = 0; row < 10; row++) {
    for (col = 0; col < 10; col++) {
      if (i < 100) {
        printf("%10f ", arr[row * 10 + col]);
      } else {
        goto FINISH;
      }
      i++;
    }
    printf("\n");
  }
FINISH:
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L15:
  mov    $0x0,%eax
  call   <random@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x288df0cb,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x65,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *create_vector(int length) {
  int *vec, i;
  vec = (int *)calloc(length, sizeof(int));
  for (i = 0; i < length; i++)
    vec[i] = random() % 101;
  return vec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_vector>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L1
  mov    %rax,%rbx
  mov    %ebp,%ebp
  lea    (%rax,%rbp,4),%rbp
L16:
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0x288df0cb,%rdx,%rdx
  sar    $0x24,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L16
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *create_vector(int length) {
  int *vec, i;
  vec = (int *)calloc(length, sizeof(int));
  for (i = 0; i < length; i++)
    vec[i] = random() % 101;
  return vec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_vector>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L0
  mov    %rax,%rbp
  lea    (%rax,%rbx,4),%rbx
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x288df0cb,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x24,%rdx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L16
L0:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *create_vector(int length) {
  int *vec, i;
  vec = (int *)calloc(length, sizeof(int));
  for (i = 0; i < length; i++)
    vec[i] = random() % 101;
  return vec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_vector>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L15
  mov    %rax,%rbp
  lea    (%rax,%rbx,4),%rbx
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x288df0cb,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x24,%rdx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L6
L15:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *create_vector(int length) {
  int *vec, i;
  vec = (int *)calloc(length, sizeof(int));
  for (i = 0; i < length; i++)
    vec[i] = random() % 101;
  return vec;
}
```