ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<waitinput>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L21
  imul   $0x3e8,%esi,%r12d
  mov    %edi,%ebp
  lea    0x1(%rdi),%r14d
  lea    0xc(%rsp),%rbx
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r14d,%edi
  movq   $0x0,0x18(%rsp)
  mov    %r12d,0x10(%rsp)
  call   <inpselect@plt>
  cmp    $0xffffffff,%eax
  je     L0
L21:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int waitinput(int fd, unsigned ms) {
  fd_set set;
  struct timeval tmv;
  int ret;
  if (fd < 0)
    return 0;
  do {
    FD_ZERO(&set);
    FD_SET(fd, &set);
    tmv.tv_sec = 0;
    tmv.tv_usec = 1000 * ms;
    ret = inpselect(fd + 1, &set, &tmv);
  } while (ret == -1);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<dispversion>:
  endbr64
  push   %rbx
  lea    D105(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D70(%rip),%rdi
  call   <printf@plt>
  lea    D87(%rip),%rdi
  call   <printf@plt>
  lea    D76(%rip),%rdi
  call   <printf@plt>
  lea    D82(%rip),%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    D94(%rip),%rdi
  call   <printf@plt>
  lea    D55(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D105
type_guessed: string
name: disassemble_data
arguments: data_tag: D33
type_guessed: string
name: disassemble_data
arguments: data_tag: D63
type_guessed: string
name: disassemble_data
arguments: data_tag: D68
type_guessed: string
name: disassemble_data
arguments: data_tag: D47
type_guessed: string
name: disassemble_data
arguments: data_tag: D70
type_guessed: string
name: disassemble_data
arguments: data_tag: D87
type_guessed: string
name: disassemble_data
arguments: data_tag: D76
type_guessed: string
name: disassemble_data
arguments: data_tag: D82
type_guessed: string
name: disassemble_data
arguments: data_tag: D61
type_guessed: string
name: disassemble_data
arguments: data_tag: D94
type_guessed: string
name: disassemble_data
arguments: data_tag: D55
type_guessed: string

tool: D105: prettytt: 2001/12/29

tool: D33: 


tool: D63: This program converts a LifeLines binary translation table


tool: D68: to an ascii version (safe for transmittal in email or


tool: D47: display on the web).


tool: D70: With no arguments, it will read from stdin and write to


tool: D87: stdout. With one argument, it will treat it as the input


tool: D76: filename. With two arguments, it will treat the first as


tool: D82: the input filename, and the second as the output filename.


tool: D61: If an argument is -w, it will ignore leading whitespace.


tool: D94: This is oriented towards use with files from konwert:


tool: D55: http://kki.net.pl/qrczak/programy/dos/konwert/index.html

assistant: ```c
void dispversion(void) {
  printf("prettytt: 2001/12/29");
  printf("\n");
  printf("\n");
  printf("This program converts a LifeLines binary translation table\n");
  printf("to an ascii version (safe for transmittal in email or\n");
  printf("display on the web).\n");
  printf("With no arguments, it will read from stdin and write to\n");
  printf("stdout. With one argument, it will treat it as the input\n");
  printf("filename. With two arguments, it will treat the first as\n");
  printf("the input filename, and the second as the output filename.\n");
  printf("If an argument is -w, it will ignore leading whitespace.\n");
  printf("This is oriented towards use with files from konwert:\n");
  printf("http://kki.net.pl/qrczak/programy/dos/konwert/index.html");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dispversion>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  lea    D21(%rip),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D115(%rip),%rdi
  call   <printf@plt>
  lea    D113(%rip),%rdi
  call   <printf@plt>
  lea    D112(%rip),%rdi
  call   <printf@plt>
  lea    D103(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D117(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D104(%rip),%rdi
  call   <printf@plt>
  lea    D107(%rip),%rdi
  call   <printf@plt>
  lea    D90(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D115
type: string
name: parse_data
arguments: data_tag: D113
type: string
name: parse_data
arguments: data_tag: D112
type: string
name: parse_data
arguments: data_tag: D103
type: string
name: parse_data
arguments: data_tag: D28
type: string
name: parse_data
arguments: data_tag: D117
type: string
name: parse_data
arguments: data_tag: D25
type: string
name: parse_data
arguments: data_tag: D104
type: string
name: parse_data
arguments: data_tag: D107
type: string
name: parse_data
arguments: data_tag: D90
type: string

tool: D27: prettytt: 2001/12/29

tool: D21: 


tool: D115: This program converts a LifeLines binary translation table


tool: D113: to an ascii version (safe for transmittal in email or


tool: D112: display on the web).


tool: D103: With no arguments, it will read from stdin and write to


tool: D28: stdout. With one argument, it will treat it as the input


tool: D117: filename. With two arguments, it will treat the first as


tool: D25: the input filename, and the second as the output filename.


tool: D104: If an argument is -w, it will ignore leading whitespace.


tool: D107: This is oriented towards use with files from konwert:


tool: D90: http://kki.net.pl/qrczak/programy/dos/konwert/index.html

assistant: ```c
void dispversion(void) {
  printf("prettytt: 2001/12/29");
  printf("\n");
  printf("\n");
  printf("This program converts a LifeLines binary translation table\n");
  printf("to an ascii version (safe for transmittal in email or\n");
  printf("display on the web).\n");
  printf("With no arguments, it will read from stdin and write to\n");
  printf("stdout. With one argument, it will treat it as the input\n");
  printf("filename. With two arguments, it will treat the first as\n");
  printf("the input filename, and the second as the output filename.\n");
  printf("If an argument is -w, it will ignore leading whitespace.\n");
  printf("This is oriented towards use with files from konwert:\n");
  printf("http://kki.net.pl/qrczak/programy/dos/konwert/index.html");
}
```
user: What is the c source code of the assembly code below:

```asm
<dispversion>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rdi
  lea    D32(%rip),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D82(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D84(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
type_guessed: string
name: retrieve_data
arguments: data_tag: D32
type_guessed: string
name: retrieve_data
arguments: data_tag: D48
type_guessed: string
name: retrieve_data
arguments: data_tag: D37
type_guessed: string
name: retrieve_data
arguments: data_tag: D82
type_guessed: string
name: retrieve_data
arguments: data_tag: D29
type_guessed: string
name: retrieve_data
arguments: data_tag: D49
type_guessed: string
name: retrieve_data
arguments: data_tag: D31
type_guessed: string
name: retrieve_data
arguments: data_tag: D84
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D52
type_guessed: string
name: retrieve_data
arguments: data_tag: D21
type_guessed: string

tool: D20: prettytt: 2001/12/29

tool: D32: 


tool: D48: This program converts a LifeLines binary translation table


tool: D37: to an ascii version (safe for transmittal in email or


tool: D82: display on the web).


tool: D29: With no arguments, it will read from stdin and write to


tool: D49: stdout. With one argument, it will treat it as the input


tool: D31: filename. With two arguments, it will treat the first as


tool: D84: the input filename, and the second as the output filename.


tool: D13: If an argument is -w, it will ignore leading whitespace.


tool: D52: This is oriented towards use with files from konwert:


tool: D21: http://kki.net.pl/qrczak/programy/dos/konwert/index.html

assistant: ```c
void dispversion(void) {
  printf("prettytt: 2001/12/29");
  printf("\n");
  printf("\n");
  printf("This program converts a LifeLines binary translation table\n");
  printf("to an ascii version (safe for transmittal in email or\n");
  printf("display on the web).\n");
  printf("With no arguments, it will read from stdin and write to\n");
  printf("stdout. With one argument, it will treat it as the input\n");
  printf("filename. With two arguments, it will treat the first as\n");
  printf("the input filename, and the second as the output filename.\n");
  printf("If an argument is -w, it will ignore leading whitespace.\n");
  printf("This is oriented towards use with files from konwert:\n");
  printf("http://kki.net.pl/qrczak/programy/dos/konwert/index.html");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x9000(%rsp),%r11
L8:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L8
  sub    $0xc78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x9c84(%rbp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x9c84(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L11:
  cmp    %rcx,%rsp
  je     L7
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L11
L7:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L5
  orq    $0x0,-0x8(%rsp,%rax,1)
L5:
  mov    %rsp,%r14
  test   %edx,%edx
  jle    L27
  mov    $0x0,%r15d
  lea    D14(%rip),%r13
  jmp    L103
L115:
  sub    $0x20,%rsp
  orq    $0x0,0x18(%rsp)
  lea    0x3(%rsp),%rdi
  mov    %rdi,%rax
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%rdi
  mov    -0x9c7c(%rbp),%edx
  mov    %edx,%ecx
  sub    -0x9c80(%rbp),%ecx
  mov    %ecx,0x0(,%rax,4)
  mov    -0x9c78(%rbp),%ecx
  mov    %ecx,%esi
  sub    %edx,%esi
  mov    %esi,0x4(,%rax,4)
  mov    -0x9c74(%rbp),%edx
  sub    %ecx,%edx
  mov    %edx,0x8(,%rax,4)
  mov    $0x5,%esi
  call   <lonlen@plt>
  mov    %eax,(%r14,%r15,4)
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x9c98(%rbp),%rsp
  mov    -0x9c84(%rbp),%eax
  add    $0x1,%r15
  cmp    %r15d,%eax
  jle    L41
L103:
  mov    %rsp,-0x9c98(%rbp)
  lea    -0x9c80(%rbp),%rbx
  lea    -0x9c6c(%rbp),%r12
L129:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L129
  mov    %rsp,%rax
L37:
  cmp    %rax,%rsp
  je     L115
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L37
L41:
  test   %eax,%eax
  jle    L27
  mov    $0x0,%ebx
  lea    D29(%rip),%r12
L122:
  mov    (%r14,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,-0x9c84(%rbp)
  jg     L122
L27:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D29
type_infered: string

tool: D14: %d

tool: D29: %d 


assistant: ```c
int main(void) {
  int N;
  int ar[10000];
  scanf("%d", &N);
  printf("\n");
  int i, l = 0, j, k = 0, count = 0;
  int len[N];
  for (i = 0; i < N; i++) {
    count = 0;
    for (j = 0; j < 5; j++) {
      scanf("%d", &ar[j]);
      count++;
    }
    int r[count];
    k = 0;
    for (j = 0; j < (count - 2); j++) {
      r[k++] = ar[j + 1] - ar[j];
    }
    len[l++] = lonlen(r, count);
    printf("\n");
  }
  for (i = 0; i < N; i++)
    printf("%d \n", len[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x9000(%rsp),%r11
L41:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L41
  sub    $0xca8,%rsp
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x9ca4(%rbp),%rsi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movslq -0x9ca4(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L39
L71:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L71
L39:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L82
L13:
  mov    %rsp,-0x9cb8(%rbp)
  test   %ecx,%ecx
  jle    L70
  lea    -0x9c80(%rbp),%rax
  xor    %r13d,%r13d
  lea    -0x9c6c(%rbp),%r12
  mov    %rax,-0x9cc0(%rbp)
  lea    -0x9ca0(%rbp),%rax
  mov    %rax,-0x9cc8(%rbp)
  cs nopw 0x0(%rax,%rax,1)
L89:
  mov    -0x9cc0(%rbp),%r14
  mov    %rsp,%r15
L23:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r14
  call   <scanf@plt>
  cmp    %r12,%r14
  jne    L23
  mov    -0x9c7c(%rbp),%eax
  mov    -0x9cc8(%rbp),%rdi
  mov    $0x5,%esi
  mov    %eax,%edx
  sub    -0x9c80(%rbp),%edx
  mov    %edx,-0x9ca0(%rbp)
  mov    -0x9c78(%rbp),%edx
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x9c74(%rbp),%eax
  mov    %ecx,-0x9c9c(%rbp)
  sub    %edx,%eax
  mov    %eax,-0x9c98(%rbp)
  call   <lonlen@plt>
  mov    -0x9cb8(%rbp),%rcx
  mov    $0xa,%edi
  mov    %eax,(%rcx,%r13,4)
  add    $0x1,%r13
  call   <putchar@plt>
  mov    -0x9ca4(%rbp),%eax
  mov    %r15,%rsp
  cmp    %r13d,%eax
  jg     L89
  test   %eax,%eax
  jle    L70
  xor    %ebx,%ebx
  lea    D1(%rip),%r12
  nopl   0x0(%rax)
L17:
  mov    -0x9cb8(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,4),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x9ca4(%rbp)
  jg     L17
L70:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L82:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L13
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string

tool: D15: %d

tool: D1: %d 


assistant: ```c
int main(void) {
  int N;
  int ar[10000];
  scanf("%d", &N);
  printf("\n");
  int i, l = 0, j, k = 0, count = 0;
  int len[N];
  for (i = 0; i < N; i++) {
    count = 0;
    for (j = 0; j < 5; j++) {
      scanf("%d", &ar[j]);
      count++;
    }
    int r[count];
    k = 0;
    for (j = 0; j < (count - 2); j++) {
      r[k++] = ar[j + 1] - ar[j];
    }
    len[l++] = lonlen(r, count);
    printf("\n");
  }
  for (i = 0; i < N; i++)
    printf("%d \n", len[i]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x9000(%rsp),%r11
L69:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L69
  sub    $0xca8,%rsp
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x9ca4(%rbp),%rsi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movslq -0x9ca4(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L85
L74:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L74
L85:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L70
L94:
  mov    %rsp,-0x9cb8(%rbp)
  test   %ecx,%ecx
  jle    L50
  lea    -0x9c80(%rbp),%rax
  xor    %r13d,%r13d
  lea    -0x9c6c(%rbp),%r12
  mov    %rax,-0x9cc0(%rbp)
  lea    -0x9ca0(%rbp),%rax
  mov    %rax,-0x9cc8(%rbp)
  cs nopw 0x0(%rax,%rax,1)
L40:
  mov    -0x9cc0(%rbp),%r14
  mov    %rsp,%r15
L3:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r14
  call   <scanf@plt>
  cmp    %r12,%r14
  jne    L3
  movq   -0x9c7c(%rbp),%xmm0
  mov    -0x9c74(%rbp),%edx
  mov    $0x5,%esi
  movq   -0x9c80(%rbp),%xmm2
  mov    -0x9cc8(%rbp),%rdi
  movdqa %xmm0,%xmm1
  pshufd $0xe5,%xmm0,%xmm3
  movd   %xmm3,%eax
  psubd  %xmm2,%xmm1
  sub    %eax,%edx
  mov    %edx,-0x9c98(%rbp)
  movq   %xmm1,-0x9ca0(%rbp)
  call   <lonlen@plt>
  mov    -0x9cb8(%rbp),%rcx
  mov    $0xa,%edi
  mov    %eax,(%rcx,%r13,4)
  add    $0x1,%r13
  call   <putchar@plt>
  mov    -0x9ca4(%rbp),%eax
  mov    %r15,%rsp
  cmp    %r13d,%eax
  jg     L40
  test   %eax,%eax
  jle    L50
  xor    %ebx,%ebx
  lea    D3(%rip),%r12
  xchg   %ax,%ax
L96:
  mov    -0x9cb8(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,4),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x9ca4(%rbp)
  jg     L96
L50:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L70:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L94
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: string

tool: D4: %d

tool: D3: %d 


assistant: ```c
int main(void) {
  int N;
  int ar[10000];
  scanf("%d", &N);
  printf("\n");
  int i, l = 0, j, k = 0, count = 0;
  int len[N];
  for (i = 0; i < N; i++) {
    count = 0;
    for (j = 0; j < 5; j++) {
      scanf("%d", &ar[j]);
      count++;
    }
    int r[count];
    k = 0;
    for (j = 0; j < (count - 2); j++) {
      r[k++] = ar[j + 1] - ar[j];
    }
    len[l++] = lonlen(r, count);
    printf("\n");
  }
  for (i = 0; i < N; i++)
    printf("%d \n", len[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<minimax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L16
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L16:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void minimax(int *arr, int s, int *minimum, int *maximum) {
  int j;
  for (j = 0; j < s; j++) {
    if (arr[j] > *maximum) {
      *maximum = arr[j];
    }
    if (arr[j] < *minimum) {
      *minimum = arr[j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<minimax>:
  endbr64
  test   %esi,%esi
  jle    L36
  mov    %rdi,%rax
  lea    -0x1(%rsi),%esi
  lea    0x4(%rdi,%rsi,4),%r8
  jmp    L49
L10:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L36
L49:
  mov    %rax,%rdi
  mov    (%rax),%esi
  cmp    (%rcx),%esi
  jle    L41
  mov    %esi,(%rcx)
L41:
  mov    (%rdi),%esi
  cmp    (%rdx),%esi
  jge    L10
  mov    %esi,(%rdx)
  jmp    L10
L36:
  ret
```

assistant: ```c
void minimax(int *arr, int s, int *minimum, int *maximum) {
  int j;
  for (j = 0; j < s; j++) {
    if (arr[j] > *maximum) {
      *maximum = arr[j];
    }
    if (arr[j] < *minimum) {
      *minimum = arr[j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<minimax>:
  endbr64
  test   %esi,%esi
  jle    L23
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L30:
  mov    (%rdi),%eax
  cmp    (%rcx),%eax
  jle    L12
  mov    %eax,(%rcx)
L12:
  cmp    (%rdx),%eax
  jge    L20
  mov    %eax,(%rdx)
L20:
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L30
L23:
  ret
```

assistant: ```c
void minimax(int *arr, int s, int *minimum, int *maximum) {
  int j;
  for (j = 0; j < s; j++) {
    if (arr[j] > *maximum) {
      *maximum = arr[j];
    }
    if (arr[j] < *minimum) {
      *minimum = arr[j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<minimax>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L12:
  mov    (%rdi),%eax
  cmp    (%rcx),%eax
  jle    L31
  mov    %eax,(%rcx)
L31:
  cmp    (%rdx),%eax
  jge    L26
  mov    %eax,(%rdx)
L26:
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L12
L21:
  ret
```

assistant: ```c
void minimax(int *arr, int s, int *minimum, int *maximum) {
  int j;
  for (j = 0; j < s; j++) {
    if (arr[j] > *maximum) {
      *maximum = arr[j];
    }
    if (arr[j] < *minimum) {
      *minimum = arr[j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f3(int t, int v) {
  int a = t + 1U;
  int b = a * v;
  return b - v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f3>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int f3(int t, int v) {
  int a = t + 1U;
  int b = a * v;
  return b - v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f3>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int f3(int t, int v) {
  int a = t + 1U;
  int b = a * v;
  return b - v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f3>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int f3(int t, int v) {
  int a = t + 1U;
  int b = a * v;
  return b - v;
}
```