ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<v_EepromWaitBusy>:
  endbr64
  push   %rbx
  lea    0x3f(%rdi),%ebx
  movzwl %bx,%ebx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  call   <inb@plt>
  test   %al,%al
  js     L2
  pop    %rbx
  ret
```

assistant: ```c
void v_EepromWaitBusy(unsigned short w_PCIBoardEepromAddress) {
  unsigned char b_EepromBusy = 0;
  do {
    b_EepromBusy = inb(w_PCIBoardEepromAddress + 0x3F);
    b_EepromBusy = b_EepromBusy & 0x80;
  } while (b_EepromBusy == 0x80);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stFreeTokens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <stCountTokens@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L12:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void stFreeTokens(char *inputString, char *delimiter, char ***tokenString) {
  int i;
  int count = stCountTokens(inputString, delimiter);
  for (i = 0; i < count; i++)
    free((*tokenString)[i]);
  free(*tokenString);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stFreeTokens>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  mov    $0x0,%eax
  call   <stCountTokens@plt>
  test   %eax,%eax
  jle    L5
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rbp
  mov    $0x0,%ebx
L6:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L6
L5:
  mov    (%r12),%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void stFreeTokens(char *inputString, char *delimiter, char ***tokenString) {
  int i;
  int count = stCountTokens(inputString, delimiter);
  for (i = 0; i < count; i++)
    free((*tokenString)[i]);
  free(*tokenString);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stFreeTokens>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  call   <stCountTokens@plt>
  test   %eax,%eax
  jle    L0
  cltq
  xor    %ebx,%ebx
  lea    0x0(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L1
L0:
  mov    (%r12),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <free@plt>
```

assistant: ```c
void stFreeTokens(char *inputString, char *delimiter, char ***tokenString) {
  int i;
  int count = stCountTokens(inputString, delimiter);
  for (i = 0; i < count; i++)
    free((*tokenString)[i]);
  free(*tokenString);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stFreeTokens>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  call   <stCountTokens@plt>
  test   %eax,%eax
  jle    L6
  cltq
  xor    %ebx,%ebx
  lea    0x0(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L17
L6:
  mov    (%r12),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <free@plt>
```

assistant: ```c
void stFreeTokens(char *inputString, char *delimiter, char ***tokenString) {
  int i;
  int count = stCountTokens(inputString, delimiter);
  for (i = 0; i < count; i++)
    free((*tokenString)[i]);
  free(*tokenString);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jul_check_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L31
  cmpl   $0xc,-0x8(%rbp)
  jle    L22
L31:
  mov    $0x0,%eax
  jmp    L6
L22:
  cmpl   $0x0,-0xc(%rbp)
  jle    L26
  cmpl   $0x1c,-0xc(%rbp)
  jle    L8
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <jul_month_length@plt>
  cmp    %eax,-0xc(%rbp)
  jle    L8
L26:
  mov    $0x0,%eax
  jmp    L6
L8:
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int jul_check_date(const int year, const int month, const int day) {
  if (month < 1 || month > 12)
    return 0;
  if (day < 1 || (day > 28 && (day > jul_month_length(year, month))))
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jul_check_date>:
  endbr64
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L13
  push   %rbx
  mov    %edx,%ebx
  mov    $0x0,%eax
  test   %edx,%edx
  jle    L31
  mov    $0x1,%eax
  cmp    $0x1c,%edx
  jg     L21
L31:
  pop    %rbx
  ret
L21:
  call   <jul_month_length@plt>
  cmp    %ebx,%eax
  setge  %al
  movzbl %al,%eax
  jmp    L31
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int jul_check_date(const int year, const int month, const int day) {
  if (month < 1 || month > 12)
    return 0;
  if (day < 1 || (day > 28 && (day > jul_month_length(year, month))))
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<jul_check_date>:
  endbr64
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L4
  test   %edx,%edx
  jle    L4
  mov    $0x1,%eax
  cmp    $0x1c,%edx
  jg     L0
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  call   <jul_month_length@plt>
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  setge  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int jul_check_date(const int year, const int month, const int day) {
  if (month < 1 || month > 12)
    return 0;
  if (day < 1 || (day > 28 && (day > jul_month_length(year, month))))
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jul_check_date>:
  endbr64
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L18
  test   %edx,%edx
  jle    L18
  mov    $0x1,%eax
  cmp    $0x1c,%edx
  jg     L25
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  call   <jul_month_length@plt>
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  setge  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int jul_check_date(const int year, const int month, const int day) {
  if (month < 1 || month > 12)
    return 0;
  if (day < 1 || (day > 28 && (day > jul_month_length(year, month))))
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<timeout_to_timespec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0xf4240,%edx,%eax
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L12
  mov    $0x1,%eax
  jmp    L0
L12:
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x20(%rbp),%eax
  imul   $0x3e8,%eax,%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    0x8(%rax),%rcx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x44b82fa1,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1c,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  lea    (%rcx,%rax,1),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  movslq %edx,%rax
  imul   $0x44b82fa1,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1c,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x3b9aca00,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x40(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int timeout_to_timespec(int timeout, struct timespec *ts) {
  int sc = timeout / 1000;
  int ns = (timeout % 1000) * 1000 * 1000;
  int ret;
  if (timeout < 0)
    return 1;
  struct timeval now;
  ret = gettimeofday(&now, 0);
  ts->tv_sec = now.tv_sec + sc;
  ts->tv_nsec = now.tv_usec * 1000 + ns;
  ts->tv_sec += ts->tv_nsec / 1000000000L;
  ts->tv_nsec %= 1000000000L;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<timeout_to_timespec>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  test   %edi,%edi
  js     L10
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%ecx
  movslq %ebp,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  sub    %edx,%ebp
  imul   $0xf4240,%ebp,%ebp
  add    %ebp,%ecx
  cltq
  add    0x8(%rsp),%rax
  movslq %ecx,%rdx
  imul   $0x44b82fa1,%rdx,%rdx
  sar    $0x3c,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  movslq %edx,%rsi
  add    %rsi,%rax
  mov    %rax,0x8(%rbx)
  imul   $0x3b9aca00,%edx,%edx
  sub    %edx,%ecx
  mov    %ecx,(%rbx)
  mov    $0x0,%eax
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int timeout_to_timespec(int timeout, struct timespec *ts) {
  int sc = timeout / 1000;
  int ns = (timeout % 1000) * 1000 * 1000;
  int ret;
  if (timeout < 0)
    return 1;
  struct timeval now;
  ret = gettimeofday(&now, 0);
  ts->tv_sec = now.tv_sec + sc;
  ts->tv_nsec = now.tv_usec * 1000 + ns;
  ts->tv_sec += ts->tv_nsec / 1000000000L;
  ts->tv_nsec %= 1000000000L;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<timeout_to_timespec>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  test   %edi,%edi
  js     L11
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rsp,%rdi
  xor    %esi,%esi
  call   <gettimeofday@plt>
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  imul   $0x3e8,(%rsp),%ecx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  cltq
  add    0x8(%rsp),%rax
  sub    %edx,%ebx
  imul   $0xf4240,%ebx,%ebx
  add    %ebx,%ecx
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x44b82fa1,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x3c,%rdx
  sub    %esi,%edx
  movslq %edx,%rsi
  imul   $0x3b9aca00,%edx,%edx
  add    %rsi,%rax
  mov    %rax,0x8(%rbp)
  xor    %eax,%eax
  sub    %edx,%ecx
  mov    %ecx,0x0(%rbp)
L11:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int timeout_to_timespec(int timeout, struct timespec *ts) {
  int sc = timeout / 1000;
  int ns = (timeout % 1000) * 1000 * 1000;
  int ret;
  if (timeout < 0)
    return 1;
  struct timeval now;
  ret = gettimeofday(&now, 0);
  ts->tv_sec = now.tv_sec + sc;
  ts->tv_nsec = now.tv_usec * 1000 + ns;
  ts->tv_sec += ts->tv_nsec / 1000000000L;
  ts->tv_nsec %= 1000000000L;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timeout_to_timespec>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  test   %edi,%edi
  js     L14
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rsp,%rdi
  xor    %esi,%esi
  call   <gettimeofday@plt>
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  imul   $0x3e8,(%rsp),%ecx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  cltq
  add    0x8(%rsp),%rax
  sub    %edx,%ebx
  imul   $0xf4240,%ebx,%ebx
  add    %ebx,%ecx
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x44b82fa1,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x3c,%rdx
  sub    %esi,%edx
  movslq %edx,%rsi
  imul   $0x3b9aca00,%edx,%edx
  add    %rsi,%rax
  mov    %rax,0x8(%rbp)
  xor    %eax,%eax
  sub    %edx,%ecx
  mov    %ecx,0x0(%rbp)
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int timeout_to_timespec(int timeout, struct timespec *ts) {
  int sc = timeout / 1000;
  int ns = (timeout % 1000) * 1000 * 1000;
  int ret;
  if (timeout < 0)
    return 1;
  struct timeval now;
  ret = gettimeofday(&now, 0);
  ts->tv_sec = now.tv_sec + sc;
  ts->tv_nsec = now.tv_usec * 1000 + ns;
  ts->tv_sec += ts->tv_nsec / 1000000000L;
  ts->tv_nsec %= 1000000000L;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  __asm__ __volatile__("nop;");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  nop
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  __asm__ __volatile__("nop;");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  nop
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  __asm__ __volatile__("nop;");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  nop
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  __asm__ __volatile__("nop;");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sieve_eratosthene>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L39
L31:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L23
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L31
  nop
  nop
  leave
  ret
```

assistant: ```c
void sieve_eratosthene(int prime[], int length) {
  int i, j;
  for (i = 2; i < sqrt(length); i++) {
    for (j = i * i; j < length; j += i) {
      prime[j] = 0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sieve_eratosthene>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x2,%ebx
  jmp    L43
L14:
  add    $0x1,%rbx
L43:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jle    L25
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %eax,%ebp
  jle    L14
  cltq
L41:
  movl   $0x0,(%r12,%rax,4)
  add    %rbx,%rax
  cmp    %eax,%ebp
  jg     L41
  jmp    L14
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sieve_eratosthene(int prime[], int length) {
  int i, j;
  for (i = 2; i < sqrt(length); i++) {
    for (j = i * i; j < length; j += i) {
      prime[j] = 0;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sieve_eratosthene>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    $0x2,%ebx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jle    L35
  nopl   (%rax)
L31:
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %eax,%ebp
  jle    L3
  cltq
  nopl   0x0(%rax,%rax,1)
L37:
  movl   $0x0,(%r12,%rax,4)
  add    %rbx,%rax
  cmp    %eax,%ebp
  jg     L37
L3:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jg     L31
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sieve_eratosthene(int prime[], int length) {
  int i, j;
  for (i = 2; i < sqrt(length); i++) {
    for (j = i * i; j < length; j += i) {
      prime[j] = 0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sieve_eratosthene>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    $0x2,%ebx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jle    L1
  nopl   (%rax)
L21:
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %eax,%ebp
  jle    L19
  cltq
  nopl   0x0(%rax,%rax,1)
L17:
  movl   $0x0,(%r12,%rax,4)
  add    %rbx,%rax
  cmp    %eax,%ebp
  jg     L17
L19:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jg     L21
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sieve_eratosthene(int prime[], int length) {
  int i, j;
  for (i = 2; i < sqrt(length); i++) {
    for (j = i * i; j < length; j += i) {
      prime[j] = 0;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bottom_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  xor    %eax,%eax
  dec    %eax
  bsf    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bottom_bit(unsigned int bits) {
  int res;
  __asm__(" xorl %[res],%[res];\n"
          " decl %[res];\n"
          " bsfl %[bits],%[res]\n"
          : [res] "=&r"(res)
          : [bits] "rm"(bits));
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bottom_bit>:
  endbr64
  xor    %eax,%eax
  dec    %eax
  bsf    %edi,%eax
  ret
```

assistant: ```c
int bottom_bit(unsigned int bits) {
  int res;
  __asm__(" xorl %[res],%[res];\n"
          " decl %[res];\n"
          " bsfl %[bits],%[res]\n"
          : [res] "=&r"(res)
          : [bits] "rm"(bits));
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bottom_bit>:
  endbr64
  xor    %eax,%eax
  dec    %eax
  bsf    %edi,%eax
  ret
```

assistant: ```c
int bottom_bit(unsigned int bits) {
  int res;
  __asm__(" xorl %[res],%[res];\n"
          " decl %[res];\n"
          " bsfl %[bits],%[res]\n"
          : [res] "=&r"(res)
          : [bits] "rm"(bits));
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bottom_bit>:
  endbr64
  xor    %eax,%eax
  dec    %eax
  bsf    %edi,%eax
  ret
```

assistant: ```c
int bottom_bit(unsigned int bits) {
  int res;
  __asm__(" xorl %[res],%[res];\n"
          " decl %[res];\n"
          " bsfl %[bits],%[res]\n"
          : [res] "=&r"(res)
          : [bits] "rm"(bits));
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<osal_search_dir_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0x104,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstombs@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) void *osal_search_dir_open(const wchar_t *_pathname) {
  char pathname[260];
  wcstombs(pathname, _pathname, 260);
  DIR *dir;
  dir = opendir(pathname);
  return dir;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<osal_search_dir_open>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x104,%edx
  mov    %rbx,%rdi
  call   <wcstombs@plt>
  mov    %rbx,%rdi
  call   <opendir@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x110,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) void *osal_search_dir_open(const wchar_t *_pathname) {
  char pathname[260];
  wcstombs(pathname, _pathname, 260);
  DIR *dir;
  dir = opendir(pathname);
  return dir;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<osal_search_dir_open>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x104,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <wcstombs@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x110,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) void *osal_search_dir_open(const wchar_t *_pathname) {
  char pathname[260];
  wcstombs(pathname, _pathname, 260);
  DIR *dir;
  dir = opendir(pathname);
  return dir;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<osal_search_dir_open>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x104,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <wcstombs@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x110,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) void *osal_search_dir_open(const wchar_t *_pathname) {
  char pathname[260];
  wcstombs(pathname, _pathname, 260);
  DIR *dir;
  dir = opendir(pathname);
  return dir;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<statfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__get_array_size@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  cmpl   $0x0,-0x8(%rbp)
  jle    L4
  mov    $0x0,%eax
  jmp    L7
L4:
  mov    $0xffffffff,%eax
L7:
  leave
  ret
```

assistant: ```c
int statfs(const char *path, struct statfs *buf) {
  int success;
  int size_path;
  success = __infer_nondet_int();
  size_path = __get_array_size(path);
  struct statfs s;
  *buf = s;
  return (success > 0) ? 0 : -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<statfs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <__get_array_size@plt>
  movl   $0x0,0x0(%rbp)
  test   %ebx,%ebx
  setle  %al
  movzbl %al,%eax
  neg    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int statfs(const char *path, struct statfs *buf) {
  int success;
  int size_path;
  success = __infer_nondet_int();
  size_path = __get_array_size(path);
  struct statfs s;
  *buf = s;
  return (success > 0) ? 0 : -1;
}
```