ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_etype>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  and    $0x1,%edi
  lea    D5(%rip),%rsi
  jne    L23
L1:
  test   $0x2,%bl
  jne    L44
  and    $0x4,%ebx
  jne    L11
L49:
  pop    %rbx
  ret
  nop
L44:
  lea    D1(%rip),%rdi
  call   <lprintf@plt>
  and    $0x4,%ebx
  lea    D57(%rip),%rsi
  je     L49
L11:
  lea    D40(%rip),%rdi
  pop    %rbx
  jmp    1050 <lprintf@plt>
  nopl   (%rax)
L23:
  lea    D2(%rip),%rdi
  call   <lprintf@plt>
  lea    D57(%rip),%rsi
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string
name: unpack_data
arguments: data_label: D57
type_guessed: string
name: unpack_data
arguments: data_label: D40
type_guessed: string
name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: 

tool: D1: %srep

tool: D57: ,

tool: D40: %srel

tool: D2: %skey

assistant: ```c
void print_etype(int type) {
  char *sep = "";
  if ((type & (1 << 0)) > 0) {
    lprintf("%skey", sep);
    sep = ",";
  }
  if ((type & (1 << 1)) > 0) {
    lprintf("%srep", sep);
    sep = ",";
  }
  if ((type & (1 << 2)) > 0) {
    lprintf("%srel", sep);
    sep = ",";
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_etype>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  and    $0x1,%edi
  lea    D39(%rip),%rsi
  jne    L24
L4:
  test   $0x2,%bl
  jne    L7
  and    $0x4,%ebx
  jne    L29
L12:
  pop    %rbx
  ret
  nop
L7:
  lea    D43(%rip),%rdi
  call   <lprintf@plt>
  and    $0x4,%ebx
  lea    D3(%rip),%rsi
  je     L12
L29:
  lea    D12(%rip),%rdi
  pop    %rbx
  jmp    1050 <lprintf@plt>
  nopl   (%rax)
L24:
  lea    D38(%rip),%rdi
  call   <lprintf@plt>
  lea    D3(%rip),%rsi
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
type_guessed: string
name: retrieve_data
arguments: data_tag: D43
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D38
type_guessed: string

tool: 

tool: D43: %srep

tool: D3: ,

tool: D12: %srel

tool: D38: %skey

assistant: ```c
void print_etype(int type) {
  char *sep = "";
  if ((type & (1 << 0)) > 0) {
    lprintf("%skey", sep);
    sep = ",";
  }
  if ((type & (1 << 1)) > 0) {
    lprintf("%srep", sep);
    sep = ",";
  }
  if ((type & (1 << 2)) > 0) {
    lprintf("%srel", sep);
    sep = ",";
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pathconN_nm3_name_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  lea    D7(%rip),%rax
  jmp    L10
L7:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string

tool: D7: i0

assistant: ```c
const char *pathconN_nm3_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<pathconN_nm3_name_in>:
  endbr64
  test   %edi,%edi
  lea    D1(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: i0

assistant: ```c
const char *pathconN_nm3_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<pathconN_nm3_name_in>:
  endbr64
  test   %edi,%edi
  mov    $0x0,%edx
  lea    D1(%rip),%rax
  cmovne %rdx,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: i0

assistant: ```c
const char *pathconN_nm3_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pathconN_nm3_name_in>:
  endbr64
  test   %edi,%edi
  mov    $0x0,%edx
  lea    D6(%rip),%rax
  cmovne %rdx,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: i0

assistant: ```c
const char *pathconN_nm3_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  default:
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x14,%edi
  call   <f1@plt>
  mov    $0x14,%edi
  call   <f2@plt>
  mov    $0x14,%edi
  call   <f3@plt>
  mov    $0x0,%eax
  call   <f4@plt>
  mov    $0x4,%esi
  mov    $0x14,%edi
  call   <__builtin_calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <f5@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  f1(20);
  f2(20);
  f3(20);
  f4();
  int *p = (int *)__builtin_calloc(20, sizeof(*p));
  f5(p);
  __builtin_free(p);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x14,%edi
  call   <f1@plt>
  mov    $0x14,%edi
  call   <f2@plt>
  mov    $0x14,%edi
  call   <f3@plt>
  mov    $0x0,%eax
  call   <f4@plt>
  mov    $0x4,%esi
  mov    $0x14,%edi
  call   <__builtin_calloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <f5@plt>
  mov    %rbx,%rdi
  call   <__builtin_free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  f1(20);
  f2(20);
  f3(20);
  f4();
  int *p = (int *)__builtin_calloc(20, sizeof(*p));
  f5(p);
  __builtin_free(p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x14,%edi
  call   <f1@plt>
  mov    $0x14,%edi
  call   <f2@plt>
  mov    $0x14,%edi
  call   <f3@plt>
  xor    %eax,%eax
  call   <f4@plt>
  mov    $0x4,%esi
  mov    $0x14,%edi
  call   <__builtin_calloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <f5@plt>
  mov    %rbp,%rdi
  call   <__builtin_free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  f1(20);
  f2(20);
  f3(20);
  f4();
  int *p = (int *)__builtin_calloc(20, sizeof(*p));
  f5(p);
  __builtin_free(p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x14,%edi
  call   <f1@plt>
  mov    $0x14,%edi
  call   <f2@plt>
  mov    $0x14,%edi
  call   <f3@plt>
  xor    %eax,%eax
  call   <f4@plt>
  mov    $0x4,%esi
  mov    $0x14,%edi
  call   <__builtin_calloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <f5@plt>
  mov    %rbp,%rdi
  call   <__builtin_free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  f1(20);
  f2(20);
  f3(20);
  f4();
  int *p = (int *)__builtin_calloc(20, sizeof(*p));
  f5(p);
  __builtin_free(p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Thread_unlock_mutex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_unlock@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  movl   $0x0,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Thread_unlock_mutex(pthread_mutex_t *mutex) {
  int rc = -1;
  if ((rc = pthread_mutex_unlock(mutex)) == 0)
    rc = 0;
  return rc;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Thread_unlock_mutex>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutex_unlock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Thread_unlock_mutex(pthread_mutex_t *mutex) {
  int rc = -1;
  if ((rc = pthread_mutex_unlock(mutex)) == 0)
    rc = 0;
  return rc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Thread_unlock_mutex>:
  endbr64
  jmp    1050 <pthread_mutex_unlock@plt>
```

assistant: ```c
int Thread_unlock_mutex(pthread_mutex_t *mutex) {
  int rc = -1;
  if ((rc = pthread_mutex_unlock(mutex)) == 0)
    rc = 0;
  return rc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Thread_unlock_mutex>:
  endbr64
  jmp    1050 <pthread_mutex_unlock@plt>
```

assistant: ```c
int Thread_unlock_mutex(pthread_mutex_t *mutex) {
  int rc = -1;
  if ((rc = pthread_mutex_unlock(mutex)) == 0)
    rc = 0;
  return rc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<exit_with_diagnostic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fprintf@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void exit_with_diagnostic(char *diagnostic_message) {
  fprintf(stderr, diagnostic_message);
  exit(EXIT_FAILURE);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<exit_with_diagnostic>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fprintf@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void exit_with_diagnostic(char *diagnostic_message) {
  fprintf(stderr, diagnostic_message);
  exit(EXIT_FAILURE);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<exit_with_diagnostic>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    %rdi,%rsi
  mov    (%rax),%edi
  call   <fprintf@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void exit_with_diagnostic(char *diagnostic_message) {
  fprintf(stderr, diagnostic_message);
  exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<exit_with_diagnostic>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    %rdi,%rsi
  mov    (%rax),%edi
  call   <fprintf@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void exit_with_diagnostic(char *diagnostic_message) {
  fprintf(stderr, diagnostic_message);
  exit(EXIT_FAILURE);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<base64url_to_base64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L46:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L13
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2b,(%rax)
  jmp    L78
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  jne    L2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  jmp    L78
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L78:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L46
L42:
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  and    $0xfffffffc,%eax
  cmp    %eax,-0x24(%rbp)
  jg     L9
  mov    $0xffffffff,%eax
  jmp    L92
L79:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3d,(%rax)
L9:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L79
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
L92:
  leave
  ret
```

assistant: ```c
int base64url_to_base64(const char *const input, char *output, int olen) {
  int i = 0;
  while (input[i] && i < olen) {
    if (input[i] == '-') {
      output[i] = '+';
    } else if (input[i] == '_') {
      output[i] = '/';
    } else {
      output[i] = input[i];
    }
    i++;
  }
  if (((i + 3) & -4) >= olen) {
    return -1;
  }
  while (i & 3) {
    output[i++] = '=';
  }
  output[i] = 0;
  assert(i < olen);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<base64url_to_base64>:
  endbr64
  mov    %rsi,%r9
  movzbl (%rdi),%esi
  test   %edx,%edx
  jle    L78
  test   %sil,%sil
  je     L78
  mov    $0x0,%eax
  mov    $0x2f,%r11d
  jmp    L7
L68:
  movb   $0x2b,(%r9,%rax,1)
L6:
  lea    0x1(%rcx),%r8d
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%esi
  cmp    %eax,%edx
  jle    L31
  test   %sil,%sil
  je     L31
L7:
  mov    %eax,%ecx
  mov    %eax,%r10d
  cmp    $0x2d,%sil
  je     L68
  cmp    $0x5f,%sil
  cmove  %r11d,%esi
  mov    %sil,(%r9,%rax,1)
  jmp    L6
L31:
  add    $0x4,%r10d
  and    $0xfffffffc,%r10d
  cmp    %edx,%r10d
  jge    L16
  test   $0x3,%r8b
  je     L98
  lea    0x2(%rcx),%eax
  cltq
L69:
  mov    %eax,%r8d
  movb   $0x3d,-0x1(%r9,%rax,1)
  add    $0x1,%rax
  test   $0x3,%r8b
  jne    L69
L98:
  sub    $0x8,%rsp
  movslq %r8d,%rax
  movb   $0x0,(%r9,%rax,1)
  cmp    %r8d,%edx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L16:
  mov    $0xffffffff,%eax
  ret
L94:
  mov    $0xffffffff,%eax
  ret
L78:
  test   %edx,%edx
  jle    L94
  mov    $0x0,%r8d
  jmp    L98
```

assistant: ```c
int base64url_to_base64(const char *const input, char *output, int olen) {
  int i = 0;
  while (input[i] && i < olen) {
    if (input[i] == '-') {
      output[i] = '+';
    } else if (input[i] == '_') {
      output[i] = '/';
    } else {
      output[i] = input[i];
    }
    i++;
  }
  if (((i + 3) & -4) >= olen) {
    return -1;
  }
  while (i & 3) {
    output[i++] = '=';
  }
  output[i] = 0;
  assert(i < olen);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<base64url_to_base64>:
  endbr64
  mov    %edx,%r9d
  push   %rbx
  movzbl (%rdi),%edx
  test   %r9d,%r9d
  setg   %al
  mov    %eax,%r8d
  test   %dl,%dl
  je     L12
  test   %al,%al
  je     L12
  xor    %eax,%eax
  mov    $0x2f,%ebx
  jmp    L45
  nopl   (%rax)
L60:
  cmp    $0x5f,%dl
  cmove  %ebx,%edx
L40:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  lea    0x1(%rcx),%r11d
  movzbl (%rdi,%rax,1),%edx
  cmp    %eax,%r9d
  setg   %r8b
  test   %dl,%dl
  je     L42
  test   %r8b,%r8b
  je     L42
L45:
  mov    %eax,%ecx
  mov    %eax,%r10d
  cmp    $0x2d,%dl
  jne    L60
  mov    $0x2b,%edx
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
L42:
  add    $0x4,%r10d
  and    $0xfffffffc,%r10d
  cmp    %r9d,%r10d
  jge    L94
  and    $0x3,%r11d
  je     L28
  lea    0x2(%rcx),%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%edx
  movb   $0x3d,-0x1(%rsi,%rax,1)
  add    $0x1,%rax
  test   $0x3,%dl
  jne    L5
  movslq %edx,%rax
  add    %rax,%rsi
  cmp    %edx,%r9d
  setg   %r8b
L109:
  movb   $0x0,(%rsi)
  movzbl %r8b,%edi
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L12:
  test   %r9d,%r9d
  jg     L109
L94:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
L28:
  add    %rax,%rsi
  jmp    L109
```

assistant: ```c
int base64url_to_base64(const char *const input, char *output, int olen) {
  int i = 0;
  while (input[i] && i < olen) {
    if (input[i] == '-') {
      output[i] = '+';
    } else if (input[i] == '_') {
      output[i] = '/';
    } else {
      output[i] = input[i];
    }
    i++;
  }
  if (((i + 3) & -4) >= olen) {
    return -1;
  }
  while (i & 3) {
    output[i++] = '=';
  }
  output[i] = 0;
  assert(i < olen);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<base64url_to_base64>:
  endbr64
  mov    %edx,%r9d
  push   %rbx
  movzbl (%rdi),%edx
  test   %r9d,%r9d
  setg   %al
  mov    %eax,%r8d
  test   %dl,%dl
  je     L117
  test   %al,%al
  je     L117
  xor    %eax,%eax
  mov    $0x2f,%ebx
  jmp    L103
  nopl   (%rax)
L112:
  cmp    $0x5f,%dl
  cmove  %ebx,%edx
L22:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  lea    0x1(%rcx),%r11d
  movzbl (%rdi,%rax,1),%edx
  cmp    %eax,%r9d
  setg   %r8b
  test   %dl,%dl
  je     L16
  test   %r8b,%r8b
  je     L16
L103:
  mov    %eax,%ecx
  mov    %eax,%r10d
  cmp    $0x2d,%dl
  jne    L112
  mov    $0x2b,%edx
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L16:
  add    $0x4,%r10d
  and    $0xfffffffc,%r10d
  cmp    %r9d,%r10d
  jge    L61
  and    $0x3,%r11d
  je     L17
  lea    0x2(%rcx),%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L81:
  mov    %eax,%edx
  movb   $0x3d,-0x1(%rsi,%rax,1)
  add    $0x1,%rax
  test   $0x3,%dl
  jne    L81
  movslq %edx,%rax
  add    %rax,%rsi
  cmp    %edx,%r9d
  setg   %r8b
L75:
  movb   $0x0,(%rsi)
  movzbl %r8b,%edi
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L117:
  test   %r9d,%r9d
  jg     L75
L61:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
L17:
  add    %rax,%rsi
  jmp    L75
```

assistant: ```c
int base64url_to_base64(const char *const input, char *output, int olen) {
  int i = 0;
  while (input[i] && i < olen) {
    if (input[i] == '-') {
      output[i] = '+';
    } else if (input[i] == '_') {
      output[i] = '/';
    } else {
      output[i] = input[i];
    }
    i++;
  }
  if (((i + 3) & -4) >= olen) {
    return -1;
  }
  while (i & 3) {
    output[i++] = '=';
  }
  output[i] = 0;
  assert(i < olen);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  jmp    L81
L79:
  cmpl   $0x3,-0x4(%rbp)
  je     L99
  cmpl   $0x3,-0x4(%rbp)
  jg     L49
  cmpl   $0x1,-0x4(%rbp)
  je     L6
  cmpl   $0x2,-0x4(%rbp)
  jmp    L49
L99:
  nop
  jmp    L49
L6:
  nop
L49:
  nop
  cmpl   $0x2,-0x4(%rbp)
L81:
  cmpl   $0x2,-0x4(%rbp)
  jle    L79
  jmp    L4
L95:
  addl   $0x1,-0x4(%rbp)
  jmp    L82
L4:
  cmpl   $0x1,-0x4(%rbp)
  jle    L95
  nop
L82:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f(int x) {
  while (x < 3) {
    switch (x) {
    case 1:
      break;
    case 2:
      break;
    case 3:
      break;
    }
    while (x > 2) {
      if (3 > 4) {
        break;
      } else {
        break;
      }
    }
  }
  while (x < 2) {
    x++;
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f>:
  endbr64
L7:
  cmp    $0x2,%edi
  jle    L7
  ret
```

assistant: ```c
void f(int x) {
  while (x < 3) {
    switch (x) {
    case 1:
      break;
    case 2:
      break;
    case 3:
      break;
    }
    while (x > 2) {
      if (3 > 4) {
        break;
      } else {
        break;
      }
    }
  }
  while (x < 2) {
    x++;
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f>:
  endbr64
  nopl   0x0(%rax)
L3:
  cmp    $0x2,%edi
  jle    L3
  ret
```

assistant: ```c
void f(int x) {
  while (x < 3) {
    switch (x) {
    case 1:
      break;
    case 2:
      break;
    case 3:
      break;
    }
    while (x > 2) {
      if (3 > 4) {
        break;
      } else {
        break;
      }
    }
  }
  while (x < 2) {
    x++;
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  cmp    $0x2,%edi
  jg     L19
L10:
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void f(int x) {
  while (x < 3) {
    switch (x) {
    case 1:
      break;
    case 2:
      break;
    case 3:
      break;
    }
    while (x > 2) {
      if (3 > 4) {
        break;
      } else {
        break;
      }
    }
  }
  while (x < 2) {
    x++;
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<HO_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  D5(%rip),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  D9(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D5(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm3
  mulsd  -0x20(%rbp),%xmm3
  movsd  %xmm3,-0x30(%rbp)
  movsd  D26(%rip),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm4
  mulsd  -0x30(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: byte[8]
name: unpack_data
arguments: label: D9
type_infered: f64
name: unpack_data
arguments: label: D26
type_infered: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: D9: 0.7511255444

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
double HO_0(const double L, const double x) {
  double retval = 0.7511255444e0 * pow(L, -0.1e1 / 0.2e1) * exp(-0.5000000000e0 * x * x * pow(L, -0.2e1));
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<HO_0>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbp
  movsd  %xmm1,0x8(%rsp)
  mov    D25(%rip),%rax
  movq   %rax,%xmm1
  call   <pow@plt>
  movq   %xmm0,%rbx
  movsd  D26(%rip),%xmm1
  movq   %rbp,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  D25(%rip),%xmm0
  movsd  0x8(%rsp),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  mulsd  D27(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D25
type: byte[8]
name: retrieve_data
arguments: data_label: D26
type: byte[8]
name: retrieve_data
arguments: data_label: D27
type: f64

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D27: 0.7511255444

assistant: ```c
double HO_0(const double L, const double x) {
  double retval = 0.7511255444e0 * pow(L, -0.1e1 / 0.2e1) * exp(-0.5000000000e0 * x * x * pow(L, -0.2e1));
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HO_0>:
  endbr64
  sub    $0x28,%rsp
  mov    D1(%rip),%rax
  movsd  %xmm1,0x18(%rsp)
  movq   %rax,%xmm1
  movsd  %xmm0,0x10(%rsp)
  call   <pow@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  D19(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  D1(%rip),%xmm2
  mulsd  %xmm4,%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm1,%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm3
  mulsd  D34(%rip),%xmm3
  add    $0x28,%rsp
  movapd %xmm0,%xmm1
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: byte[8]
name: disassemble_data
arguments: data_tag: D19
type: byte[8]
name: disassemble_data
arguments: data_tag: D34
type: f64

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D34: 0.7511255444

assistant: ```c
double HO_0(const double L, const double x) {
  double retval = 0.7511255444e0 * pow(L, -0.1e1 / 0.2e1) * exp(-0.5000000000e0 * x * x * pow(L, -0.2e1));
  return retval;
}
```