ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  movdqa D27(%rip),%xmm0
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  lea    0x8(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D20(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <doublePtr@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D27
type_infered: byte[16]
name: unpack_data
arguments: tag: D0
type_infered: byte[8]
name: unpack_data
arguments: tag: D20
type_infered: byte[16]

tool: {"D27": [0x0a,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D0": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D20": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int tab[10] = {10, 1, 2, 3, 4, 5, 6, 7, 8, 9};
  int *ptr = tab;
  return doublePtr(&ptr, 10);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bin_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L52
L36:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L95
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x76,%al
  je     L21
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  je     L21
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L95
L21:
  mov    -0x4(%rbp),%eax
  jmp    L2
L95:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  jne    L37
  addl   $0x1,-0xc(%rbp)
  jmp    L90
L37:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L90
  addl   $0x1,-0x8(%rbp)
L90:
  addl   $0x1,-0x4(%rbp)
L52:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L36
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int bin_pos(char *str) {
  int left_brac = 0, right_brac = 0;
  for (int i = 0; i < strlen(str); i++) {
    if (left_brac == right_brac + 1) {
      if ((str[i] == 'v') || (str[i] == '^') || (str[i] == '>')) {
        return i;
      }
    }
    if (str[i] == '(') {
      left_brac++;
    } else if (str[i] == ')') {
      right_brac++;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bin_pos>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L57
L48:
  movzbl 0x0(%rbp,%rbx,1),%edx
  lea    -0x3e(%rdx),%ecx
  test   $0xdf,%cl
  je     L66
  cmp    $0x76,%dl
  jne    L25
  jmp    L66
L6:
  add    $0x1,%r13d
L47:
  add    $0x1,%rbx
L57:
  mov    %ebx,%r14d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L68
  lea    0x1(%r12),%eax
  cmp    %r13d,%eax
  je     L48
L25:
  movzbl 0x0(%rbp,%rbx,1),%edx
  cmp    $0x28,%dl
  je     L6
  cmp    $0x29,%dl
  cmove  %eax,%r12d
  jmp    L47
L68:
  mov    $0x0,%r14d
L66:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin_pos(char *str) {
  int left_brac = 0, right_brac = 0;
  for (int i = 0; i < strlen(str); i++) {
    if (left_brac == right_brac + 1) {
      if ((str[i] == 'v') || (str[i] == '^') || (str[i] == '>')) {
        return i;
      }
    }
    if (str[i] == '(') {
      left_brac++;
    } else if (str[i] == ')') {
      right_brac++;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bin_pos>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L64:
  cmp    $0x28,%al
  je     L5
  cmp    $0x29,%al
  cmove  %edx,%ebp
L40:
  add    $0x1,%rbx
L33:
  mov    %r14,%rdi
  mov    %ebx,%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L30
  lea    0x1(%rbp),%edx
  movzbl (%r14,%rbx,1),%eax
  cmp    %r12d,%edx
  jne    L64
  lea    -0x3e(%rax),%ecx
  and    $0xdf,%ecx
  je     L65
  cmp    $0x76,%al
  jne    L64
L65:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L5:
  add    $0x1,%r12d
  jmp    L40
  xchg   %ax,%ax
L30:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin_pos(char *str) {
  int left_brac = 0, right_brac = 0;
  for (int i = 0; i < strlen(str); i++) {
    if (left_brac == right_brac + 1) {
      if ((str[i] == 'v') || (str[i] == '^') || (str[i] == '>')) {
        return i;
      }
    }
    if (str[i] == '(') {
      left_brac++;
    } else if (str[i] == ')') {
      right_brac++;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bin_pos>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L62:
  cmp    $0x28,%al
  je     L67
  cmp    $0x29,%al
  cmove  %edx,%ebp
L17:
  add    $0x1,%rbx
L55:
  mov    %r14,%rdi
  mov    %ebx,%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L42
  lea    0x1(%rbp),%edx
  movzbl (%r14,%rbx,1),%eax
  cmp    %r12d,%edx
  jne    L62
  lea    -0x3e(%rax),%ecx
  and    $0xdf,%ecx
  je     L4
  cmp    $0x76,%al
  jne    L62
L4:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L67:
  add    $0x1,%r12d
  jmp    L17
  xchg   %ax,%ax
L42:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin_pos(char *str) {
  int left_brac = 0, right_brac = 0;
  for (int i = 0; i < strlen(str); i++) {
    if (left_brac == right_brac + 1) {
      if ((str[i] == 'v') || (str[i] == '^') || (str[i] == '>')) {
        return i;
      }
    }
    if (str[i] == '(') {
      left_brac++;
    } else if (str[i] == ')') {
      right_brac++;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cofact>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebp
  mov    %rdx,0x28(%rsp)
  lea    -0x1(%rsi),%edi
  mov    %edi,0x4(%rsp)
  imul   %edi,%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r15
  mov    %ebp,%edi
  imul   %ebp,%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %ebp,%ebp
  jle    L122
  movl   $0x0,0x24(%rsp)
  mov    $0x0,%r12d
  lea    -0x2(%rbp),%eax
  mov    %eax,0x20(%rsp)
  jmp    L89
L43:
  add    $0x1,%esi
  mov    $0x0,%edx
L74:
  lea    0x1(%rbx),%eax
  cmp    %eax,%ebp
  je     L1
  mov    %eax,%ebx
L88:
  cmp    %ecx,%r12d
  je     L74
  cmp    %ebx,%r13d
  je     L74
  lea    (%rbx,%rdi,1),%eax
  cltq
  movsd  (%r14,%rax,8),%xmm0
  mov    %r8d,%eax
  imul   %esi,%eax
  add    %edx,%eax
  cltq
  movsd  %xmm0,(%r15,%rax,8)
  cmp    %edx,%r9d
  jle    L43
  add    $0x1,%edx
  jmp    L74
L1:
  lea    0x1(%rcx),%eax
  add    %ebp,%edi
  cmp    %ebx,%ecx
  je     L60
  mov    %eax,%ecx
L105:
  mov    $0x0,%ebx
  jmp    L88
L60:
  lea    (%r12,%r13,1),%esi
  mov    $0xffffffff,%edi
  call   <pow@plt>
  movsd  %xmm0,0x10(%rsp)
  mov    0x4(%rsp),%esi
  mov    %r15,%rdi
  call   <detrm@plt>
  mulsd  0x10(%rsp),%xmm0
  mov    0x8(%rsp),%rdi
  movsd  %xmm0,(%rdi)
  lea    0x1(%r13),%eax
  add    $0x8,%rdi
  mov    %rdi,0x8(%rsp)
  cmp    %ebx,%r13d
  je     L68
  mov    %eax,%r13d
L107:
  mov    $0x0,%edi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    0x4(%rsp),%r8d
  mov    0x20(%rsp),%r9d
  jmp    L105
L68:
  lea    0x1(%r12),%eax
  add    %ebp,0x24(%rsp)
  cmp    %ebx,%r12d
  je     L122
  mov    %eax,%r12d
L89:
  movslq 0x24(%rsp),%rax
  mov    0x18(%rsp),%rdi
  lea    (%rdi,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r13d
  jmp    L107
L122:
  mov    0x28(%rsp),%rcx
  mov    %ebp,%edx
  mov    0x18(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <trans@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void cofact(double *num, int f, double *inv) {
  double *b = (double *)calloc((f - 1) * (f - 1), sizeof(double));
  double *fac = (double *)calloc(f * f, sizeof(double));
  int p, q, m, n, i, j;
  for (q = 0; q < f; q++) {
    for (p = 0; p < f; p++) {
      m = 0;
      n = 0;
      for (i = 0; i < f; i++) {
        for (j = 0; j < f; j++) {
          if (i != q && j != p) {
            b[m * (f - 1) + n] = num[i * f + j];
            if (n < (f - 2))
              n++;
            else {
              n = 0;
              m++;
            }
          }
        }
      }
      fac[q * f + p] = pow(-1, q + p) * detrm(b, f - 1);
    }
  }
  trans(num, fac, f, inv);
  free(b);
  free(fac);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cofact>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %r13d,%edi
  mov    %esi,%r12d
  mov    $0x8,%esi
  push   %rbp
  imul   %r13d,%edi
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdx,0x28(%rsp)
  call   <calloc@plt>
  mov    %r12d,%edi
  mov    $0x8,%esi
  imul   %r12d,%edi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %r12d,%r12d
  jle    L117
  movl   $0x0,0x24(%rsp)
  xor    %r9d,%r9d
  lea    -0x2(%r12),%r8d
L82:
  movslq 0x24(%rsp),%rax
  mov    0x18(%rsp),%rdi
  xor    %ebx,%ebx
  lea    (%rdi,%rax,8),%r10
  nopl   0x0(%rax)
L22:
  xor    %r11d,%r11d
  xor    %r14d,%r14d
  xor    %ecx,%ecx
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L7:
  cmp    %r14d,%r9d
  setne  %dil
  xor    %eax,%eax
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L64:
  add    $0x1,%ecx
L95:
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  je     L16
L50:
  mov    %edx,%eax
L65:
  cmp    %eax,%ebx
  je     L95
  test   %dil,%dil
  je     L95
  lea    (%rax,%r11,1),%edx
  movslq %edx,%rdx
  movsd  (%r15,%rdx,8),%xmm0
  mov    %r13d,%edx
  imul   %esi,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  movsd  %xmm0,0x0(%rbp,%rdx,8)
  cmp    %ecx,%r8d
  jg     L64
  lea    0x1(%rax),%edx
  add    $0x1,%esi
  xor    %ecx,%ecx
  cmp    %edx,%r12d
  jne    L50
L16:
  lea    0x1(%r14),%edx
  add    %r12d,%r11d
  cmp    %eax,%r14d
  je     L92
  mov    %edx,%r14d
  jmp    L7
  nop
L92:
  lea    (%r9,%rbx,1),%esi
  mov    $0xffffffff,%edi
  mov    %r10,0x10(%rsp)
  mov    %r8d,0x20(%rsp)
  mov    %r9d,0xc(%rsp)
  call   <pow@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,(%rsp)
  call   <detrm@plt>
  mulsd  (%rsp),%xmm0
  mov    0x10(%rsp),%r10
  lea    0x1(%rbx),%eax
  mov    0xc(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  add    $0x8,%r10
  movsd  %xmm0,-0x8(%r10)
  cmp    %r14d,%ebx
  je     L44
  mov    %eax,%ebx
  jmp    L22
L44:
  add    %r12d,0x24(%rsp)
  lea    0x1(%r9),%eax
  cmp    %ebx,%r9d
  je     L117
  mov    %eax,%r9d
  jmp    L82
L117:
  mov    0x18(%rsp),%rbx
  mov    0x28(%rsp),%rcx
  mov    %r12d,%edx
  mov    %r15,%rdi
  mov    %rbx,%rsi
  call   <trans@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x38,%rsp
  mov    %rbx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <free@plt>
```

assistant: ```c
void cofact(double *num, int f, double *inv) {
  double *b = (double *)calloc((f - 1) * (f - 1), sizeof(double));
  double *fac = (double *)calloc(f * f, sizeof(double));
  int p, q, m, n, i, j;
  for (q = 0; q < f; q++) {
    for (p = 0; p < f; p++) {
      m = 0;
      n = 0;
      for (i = 0; i < f; i++) {
        for (j = 0; j < f; j++) {
          if (i != q && j != p) {
            b[m * (f - 1) + n] = num[i * f + j];
            if (n < (f - 2))
              n++;
            else {
              n = 0;
              m++;
            }
          }
        }
      }
      fac[q * f + p] = pow(-1, q + p) * detrm(b, f - 1);
    }
  }
  trans(num, fac, f, inv);
  free(b);
  free(fac);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cofact>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %r13d,%edi
  mov    %esi,%r12d
  mov    $0x8,%esi
  push   %rbp
  imul   %r13d,%edi
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdx,0x28(%rsp)
  call   <calloc@plt>
  mov    %r12d,%edi
  mov    $0x8,%esi
  imul   %r12d,%edi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %r12d,%r12d
  jle    L53
  movl   $0x0,0x24(%rsp)
  xor    %r9d,%r9d
  lea    -0x2(%r12),%r8d
L58:
  movslq 0x24(%rsp),%rax
  mov    0x18(%rsp),%rdi
  xor    %ebx,%ebx
  lea    (%rdi,%rax,8),%r10
  nopl   0x0(%rax)
L29:
  xor    %r11d,%r11d
  xor    %r14d,%r14d
  xor    %ecx,%ecx
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L83:
  cmp    %r14d,%r9d
  setne  %dil
  xor    %eax,%eax
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L24:
  add    $0x1,%ecx
L103:
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  je     L100
L92:
  mov    %edx,%eax
L67:
  cmp    %eax,%ebx
  je     L103
  test   %dil,%dil
  je     L103
  lea    (%rax,%r11,1),%edx
  movslq %edx,%rdx
  movsd  (%r15,%rdx,8),%xmm0
  mov    %r13d,%edx
  imul   %esi,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  movsd  %xmm0,0x0(%rbp,%rdx,8)
  cmp    %ecx,%r8d
  jg     L24
  lea    0x1(%rax),%edx
  add    $0x1,%esi
  xor    %ecx,%ecx
  cmp    %edx,%r12d
  jne    L92
L100:
  lea    0x1(%r14),%edx
  add    %r12d,%r11d
  cmp    %eax,%r14d
  je     L79
  mov    %edx,%r14d
  jmp    L83
  nop
L79:
  lea    (%r9,%rbx,1),%esi
  mov    $0xffffffff,%edi
  mov    %r10,0x10(%rsp)
  mov    %r8d,0x20(%rsp)
  mov    %r9d,0xc(%rsp)
  call   <pow@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,(%rsp)
  call   <detrm@plt>
  mulsd  (%rsp),%xmm0
  mov    0x10(%rsp),%r10
  lea    0x1(%rbx),%eax
  mov    0xc(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  add    $0x8,%r10
  movsd  %xmm0,-0x8(%r10)
  cmp    %r14d,%ebx
  je     L90
  mov    %eax,%ebx
  jmp    L29
L90:
  add    %r12d,0x24(%rsp)
  lea    0x1(%r9),%eax
  cmp    %ebx,%r9d
  je     L53
  mov    %eax,%r9d
  jmp    L58
L53:
  mov    0x18(%rsp),%rbx
  mov    0x28(%rsp),%rcx
  mov    %r12d,%edx
  mov    %r15,%rdi
  mov    %rbx,%rsi
  call   <trans@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x38,%rsp
  mov    %rbx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <free@plt>
```

assistant: ```c
void cofact(double *num, int f, double *inv) {
  double *b = (double *)calloc((f - 1) * (f - 1), sizeof(double));
  double *fac = (double *)calloc(f * f, sizeof(double));
  int p, q, m, n, i, j;
  for (q = 0; q < f; q++) {
    for (p = 0; p < f; p++) {
      m = 0;
      n = 0;
      for (i = 0; i < f; i++) {
        for (j = 0; j < f; j++) {
          if (i != q && j != p) {
            b[m * (f - 1) + n] = num[i * f + j];
            if (n < (f - 2))
              n++;
            else {
              n = 0;
              m++;
            }
          }
        }
      }
      fac[q * f + p] = pow(-1, q + p) * detrm(b, f - 1);
    }
  }
  trans(num, fac, f, inv);
  free(b);
  free(fac);
}
```
user: What is the c source code of the assembly code below:

```asm
<b_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <b_len@plt>
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L12:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  or     %eax,-0xc(%rbp)
  sarl   -0x14(%rbp)
L10:
  cmpl   $0x0,-0x14(%rbp)
  jg     L12
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t b_reverse(uint64_t n) {
  int32_t len = b_len(n) - 1;
  uint64_t retVal = 0;
  while (n > 0) {
    retVal |= ((n & 1) << len--);
    n >>= 1;
  }
  return retVal;
}
```
user: Translate the below assembly code into C programming language:

```asm
<b_reverse>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <b_len@plt>
  test   %ebx,%ebx
  jle    L14
  lea    -0x1(%rax),%rcx
  mov    $0x0,%eax
L28:
  mov    %ebx,%edx
  and    $0x1,%edx
  shl    %cl,%edx
  or     %edx,%eax
  sar    %ebx
  sub    $0x1,%rcx
  test   %ebx,%ebx
  jg     L28
L2:
  pop    %rbx
  ret
L14:
  mov    $0x0,%eax
  jmp    L2
```

assistant: ```c
uint64_t b_reverse(uint64_t n) {
  int32_t len = b_len(n) - 1;
  uint64_t retVal = 0;
  while (n > 0) {
    retVal |= ((n & 1) << len--);
    n >>= 1;
  }
  return retVal;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<b_reverse>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <b_len@plt>
  test   %ebx,%ebx
  jle    L2
  lea    -0x1(%rax),%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %ebx,%edx
  and    $0x1,%edx
  shl    %cl,%edx
  sub    $0x1,%rcx
  or     %edx,%eax
  sar    %ebx
  jne    L19
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint64_t b_reverse(uint64_t n) {
  int32_t len = b_len(n) - 1;
  uint64_t retVal = 0;
  while (n > 0) {
    retVal |= ((n & 1) << len--);
    n >>= 1;
  }
  return retVal;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<b_reverse>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <b_len@plt>
  test   %ebx,%ebx
  jle    L9
  lea    -0x1(%rax),%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %ebx,%edx
  and    $0x1,%edx
  shl    %cl,%edx
  sub    $0x1,%rcx
  or     %edx,%eax
  sar    %ebx
  jne    L19
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint64_t b_reverse(uint64_t n) {
  int32_t len = b_len(n) - 1;
  uint64_t retVal = 0;
  while (n > 0) {
    retVal |= ((n & 1) << len--);
    n >>= 1;
  }
  return retVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x4a,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  movss  D3(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: f32
name: unpack_data
arguments: label: D0
data_type: string

tool: D3: 7.5

tool: D0: La edad es %d


assistant: ```c
int main() {
  struct datos_persona {
    char inicial;
    int edad;
    float nota;
  };
  struct datos_persona persona;
  persona.inicial = 'J';
  persona.edad = 20;
  persona.nota = 7.5;
  printf("La edad es %d\n", persona.edad);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: La edad es %d


assistant: ```c
int main() {
  struct datos_persona {
    char inicial;
    int edad;
    float nota;
  };
  struct datos_persona persona;
  persona.inicial = 'J';
  persona.edad = 20;
  persona.nota = 7.5;
  printf("La edad es %d\n", persona.edad);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D5: La edad es %d


assistant: ```c
int main() {
  struct datos_persona {
    char inicial;
    int edad;
    float nota;
  };
  struct datos_persona persona;
  persona.inicial = 'J';
  persona.edad = 20;
  persona.nota = 7.5;
  printf("La edad es %d\n", persona.edad);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: La edad es %d


assistant: ```c
int main() {
  struct datos_persona {
    char inicial;
    int edad;
    float nota;
  };
  struct datos_persona persona;
  persona.inicial = 'J';
  persona.edad = 20;
  persona.nota = 7.5;
  printf("La edad es %d\n", persona.edad);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testterm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <cgetc@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L50
  mov    $0x1,%eax
  jmp    L1
L50:
  cmpb   $0x2e,-0x1(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L1
L53:
  cmpb   $0xa,-0x1(%rbp)
  je     L48
  cmpb   $0x3b,-0x1(%rbp)
  jne    L17
L48:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  movsbl -0x1(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ungetc@plt>
L17:
  mov    $0x1,%eax
L1:
  leave
  ret
```

assistant: ```c
int testterm() {
  char c;
  if (!(c = cgetc(0)))
    return (1);
  if (c == '.')
    return (0);
  if (c == '\n' || c == ';')
    ungetc(c, stdin);
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<testterm>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <cgetc@plt>
  mov    $0x1,%edx
  test   %al,%al
  je     L6
  mov    $0x0,%edx
  cmp    $0x2e,%al
  je     L6
  cmp    $0xa,%al
  je     L17
  mov    $0x1,%edx
  cmp    $0x3b,%al
  je     L17
L6:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L17:
  movsbl %al,%edi
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <ungetc@plt>
  mov    $0x1,%edx
  jmp    L6
```

assistant: ```c
int testterm() {
  char c;
  if (!(c = cgetc(0)))
    return (1);
  if (c == '.')
    return (0);
  if (c == '\n' || c == ';')
    ungetc(c, stdin);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<testterm>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <cgetc@plt>
  mov    $0x1,%r8d
  test   %al,%al
  je     L27
  xor    %r8d,%r8d
  cmp    $0x2e,%al
  je     L27
  cmp    $0xa,%al
  je     L19
  mov    $0x1,%r8d
  cmp    $0x3b,%al
  je     L19
L27:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  movsbl %al,%edi
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <ungetc@plt>
  mov    $0x1,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int testterm() {
  char c;
  if (!(c = cgetc(0)))
    return (1);
  if (c == '.')
    return (0);
  if (c == '\n' || c == ';')
    ungetc(c, stdin);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<testterm>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <cgetc@plt>
  mov    $0x1,%r8d
  test   %al,%al
  je     L12
  xor    %r8d,%r8d
  cmp    $0x2e,%al
  je     L12
  cmp    $0xa,%al
  je     L30
  mov    $0x1,%r8d
  cmp    $0x3b,%al
  je     L30
L12:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  movsbl %al,%edi
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <ungetc@plt>
  mov    $0x1,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int testterm() {
  char c;
  if (!(c = cgetc(0)))
    return (1);
  if (c == '.')
    return (0);
  if (c == '\n' || c == ';')
    ungetc(c, stdin);
  return (1);
}
```