ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <example1@plt>
  mov    $0x0,%eax
  call   <example2@plt>
  mov    $0x0,%eax
  call   <example3@plt>
  mov    $0x0,%eax
  call   <example4@plt>
  mov    $0x0,%eax
  call   <example5@plt>
  mov    $0x0,%eax
  call   <example6@plt>
  mov    $0x0,%eax
  call   <example7@plt>
  mov    $0x0,%eax
  call   <example8@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  example1();
  example2();
  example3();
  example4();
  example5();
  example6();
  example7();
  example8();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <example1@plt>
  mov    $0x0,%eax
  call   <example2@plt>
  mov    $0x0,%eax
  call   <example3@plt>
  mov    $0x0,%eax
  call   <example4@plt>
  mov    $0x0,%eax
  call   <example5@plt>
  mov    $0x0,%eax
  call   <example6@plt>
  mov    $0x0,%eax
  call   <example7@plt>
  mov    $0x0,%eax
  call   <example8@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  example1();
  example2();
  example3();
  example4();
  example5();
  example6();
  example7();
  example8();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <example1@plt>
  xor    %eax,%eax
  call   <example2@plt>
  xor    %eax,%eax
  call   <example3@plt>
  xor    %eax,%eax
  call   <example4@plt>
  xor    %eax,%eax
  call   <example5@plt>
  xor    %eax,%eax
  call   <example6@plt>
  xor    %eax,%eax
  call   <example7@plt>
  xor    %eax,%eax
  call   <example8@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  example1();
  example2();
  example3();
  example4();
  example5();
  example6();
  example7();
  example8();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <example1@plt>
  xor    %eax,%eax
  call   <example2@plt>
  xor    %eax,%eax
  call   <example3@plt>
  xor    %eax,%eax
  call   <example4@plt>
  xor    %eax,%eax
  call   <example5@plt>
  xor    %eax,%eax
  call   <example6@plt>
  xor    %eax,%eax
  call   <example7@plt>
  xor    %eax,%eax
  call   <example8@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  example1();
  example2();
  example3();
  example4();
  example5();
  example6();
  example7();
  example8();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D16: Hello, World!

tool: D2: %s


assistant: ```c
int main(void) {
  printf("%s\n", "Hello, World!");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string

tool: D2: Hello, World!

tool: D8: %s


assistant: ```c
int main(void) {
  printf("%s\n", "Hello, World!");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string
name: unpack_data
arguments: label: D19
datatype: string

tool: D9: Hello, World!

tool: D19: %s


assistant: ```c
int main(void) {
  printf("%s\n", "Hello, World!");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string

tool: D2: Hello, World!

tool: D19: %s


assistant: ```c
int main(void) {
  printf("%s\n", "Hello, World!");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mallocDoubleArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L1:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L1
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **mallocDoubleArray(int rows, int columns) {
  int i;
  double **someArray;
  someArray = (double **)malloc(rows * sizeof(double *));
  for (i = 0; i < rows; i++) {
    someArray[i] = (double *)malloc(columns * sizeof(double));
  }
  return someArray;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mallocDoubleArray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L11
  shl    $0x3,%ebp
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r12
L16:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L16
L11:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **mallocDoubleArray(int rows, int columns) {
  int i;
  double **someArray;
  someArray = (double **)malloc(rows * sizeof(double *));
  for (i = 0; i < rows; i++) {
    someArray[i] = (double *)malloc(columns * sizeof(double));
  }
  return someArray;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mallocDoubleArray>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L11
  shl    $0x3,%ebp
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L12
L11:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **mallocDoubleArray(int rows, int columns) {
  int i;
  double **someArray;
  someArray = (double **)malloc(rows * sizeof(double *));
  for (i = 0; i < rows; i++) {
    someArray[i] = (double *)malloc(columns * sizeof(double));
  }
  return someArray;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mallocDoubleArray>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L17
  shl    $0x3,%ebp
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L7
L17:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **mallocDoubleArray(int rows, int columns) {
  int i;
  double **someArray;
  someArray = (double **)malloc(rows * sizeof(double *));
  for (i = 0; i < rows; i++) {
    someArray[i] = (double *)malloc(columns * sizeof(double));
  }
  return someArray;
}
```
user: What is the c source code of the assembly code below:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L24
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L49
L44:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L45
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L45:
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L44
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  jmp    L32
L24:
  nop
L32:
  leave
  ret
```

assistant: ```c
void quick_sort(int v[], int left, int right) {
  int i, last;
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (v[i] < v[left])
      swap(v, ++last, i);
  swap(v, left, last);
  quick_sort(v, left, last - 1);
  quick_sort(v, last + 1, right);
}
```
user: Translate the below assembly code into C programming language:

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L39
  ret
L39:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  lea    0x1(%r13),%ebx
  cmp    %ebx,%r12d
  jl     L31
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%r15
  movslq %ebx,%rbx
  mov    %r13d,%r14d
  jmp    L9
L30:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L21
L9:
  mov    %ebx,%edx
  mov    (%r15),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L30
  add    $0x1,%r14d
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L30
L31:
  mov    %r13d,%r14d
L21:
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    -0x1(%r14),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%r14),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quick_sort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quick_sort(int v[], int left, int right) {
  int i, last;
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (v[i] < v[left])
      swap(v, ++last, i);
  swap(v, left, last);
  quick_sort(v, left, last - 1);
  quick_sort(v, last + 1, right);
}
```
user: What is the c source code of the assembly code below:

```asm
<quick_sort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L76:
  cmp    %r14d,%r12d
  jle    L34
L50:
  lea    (%r12,%r14,1),%eax
  mov    %r14d,%esi
  lea    0x1(%r14),%ebx
  mov    %rbp,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  cmp    %ebx,%r12d
  jl     L44
  movslq %r14d,%rax
  movslq %ebx,%rbx
  mov    %r14d,%r13d
  lea    0x0(%rbp,%rax,4),%r15
  jmp    L74
  nopl   (%rax)
L57:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L13
L74:
  mov    (%r15),%eax
  mov    %ebx,%edx
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L57
  add    $0x1,%r13d
  mov    %rbp,%rdi
  add    $0x1,%rbx
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %ebx,%r12d
  jge    L74
L13:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%r13),%r14d
  cmp    %r12d,%r14d
  jl     L50
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L44:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%r12d
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L76
```

assistant: ```c
void quick_sort(int v[], int left, int right) {
  int i, last;
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (v[i] < v[left])
      swap(v, ++last, i);
  swap(v, left, last);
  quick_sort(v, left, last - 1);
  quick_sort(v, last + 1, right);
}
```
user: What is the c source code of the assembly code below?

```asm
<quick_sort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L11:
  cmp    %r14d,%r12d
  jle    L16
L10:
  lea    (%r12,%r14,1),%eax
  mov    %r14d,%esi
  lea    0x1(%r14),%ebx
  mov    %rbp,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  cmp    %ebx,%r12d
  jl     L3
  movslq %r14d,%rax
  movslq %ebx,%rbx
  mov    %r14d,%r13d
  lea    0x0(%rbp,%rax,4),%r15
  jmp    L19
  nopl   (%rax)
L56:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L4
L19:
  mov    (%r15),%eax
  mov    %ebx,%edx
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L56
  add    $0x1,%r13d
  mov    %rbp,%rdi
  add    $0x1,%rbx
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %ebx,%r12d
  jge    L19
L4:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%r13),%r14d
  cmp    %r12d,%r14d
  jl     L10
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L3:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%r12d
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L11
```

assistant: ```c
void quick_sort(int v[], int left, int right) {
  int i, last;
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (v[i] < v[left])
      swap(v, ++last, i);
  swap(v, left, last);
  quick_sort(v, left, last - 1);
  quick_sort(v, last + 1, right);
}
```
user: What is the c source code of the assembly code below:

```asm
<test_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <abs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <labs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <llabs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabsf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabsl@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <cabsf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <cabs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <cabsl@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_abs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_labs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_llabs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_fabsf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_fabs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_fabsl@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_cabsf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_cabs@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <__builtin_cabsl@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_double(double x) {
  (void)abs(x);
  (void)labs(x);
  (void)llabs(x);
  (void)fabsf(x);
  (void)fabs(x);
  (void)fabsl(x);
  (void)cabsf(x);
  (void)cabs(x);
  (void)cabsl(x);
  (void)__builtin_abs(x);
  (void)__builtin_labs(x);
  (void)__builtin_llabs(x);
  (void)__builtin_fabsf(x);
  (void)__builtin_fabs(x);
  (void)__builtin_fabsl(x);
  (void)__builtin_cabsf(x);
  (void)__builtin_cabs(x);
  (void)__builtin_cabsl(x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_double>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <abs@plt>
  movq   %rbx,%xmm0
  call   <labs@plt>
  movq   %rbx,%xmm0
  call   <llabs@plt>
  movq   %rbx,%xmm0
  call   <fabsf@plt>
  movq   %rbx,%xmm0
  call   <fabs@plt>
  movq   %rbx,%xmm0
  call   <fabsl@plt>
  movq   %rbx,%xmm0
  call   <cabsf@plt>
  movq   %rbx,%xmm0
  call   <cabs@plt>
  movq   %rbx,%xmm0
  call   <cabsl@plt>
  movq   %rbx,%xmm0
  call   <__builtin_abs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_labs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_llabs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabsf@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabsl@plt>
  movq   %rbx,%xmm0
  call   <__builtin_cabsf@plt>
  movq   %rbx,%xmm0
  call   <__builtin_cabs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_cabsl@plt>
  pop    %rbx
  ret
```

assistant: ```c
void test_double(double x) {
  (void)abs(x);
  (void)labs(x);
  (void)llabs(x);
  (void)fabsf(x);
  (void)fabs(x);
  (void)fabsl(x);
  (void)cabsf(x);
  (void)cabs(x);
  (void)cabsl(x);
  (void)__builtin_abs(x);
  (void)__builtin_labs(x);
  (void)__builtin_llabs(x);
  (void)__builtin_fabsf(x);
  (void)__builtin_fabs(x);
  (void)__builtin_fabsl(x);
  (void)__builtin_cabsf(x);
  (void)__builtin_cabs(x);
  (void)__builtin_cabsl(x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_double>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <abs@plt>
  movq   %rbx,%xmm0
  call   <labs@plt>
  movq   %rbx,%xmm0
  call   <llabs@plt>
  movq   %rbx,%xmm0
  call   <fabsf@plt>
  movq   %rbx,%xmm0
  call   <fabs@plt>
  movq   %rbx,%xmm0
  call   <fabsl@plt>
  movq   %rbx,%xmm0
  call   <cabsf@plt>
  movq   %rbx,%xmm0
  call   <cabs@plt>
  movq   %rbx,%xmm0
  call   <cabsl@plt>
  movq   %rbx,%xmm0
  call   <__builtin_abs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_labs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_llabs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabsf@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabsl@plt>
  movq   %rbx,%xmm0
  call   <__builtin_cabsf@plt>
  movq   %rbx,%xmm0
  call   <__builtin_cabs@plt>
  movq   %rbx,%xmm0
  pop    %rbx
  jmp    1260 <__builtin_cabsl@plt>
```

assistant: ```c
void test_double(double x) {
  (void)abs(x);
  (void)labs(x);
  (void)llabs(x);
  (void)fabsf(x);
  (void)fabs(x);
  (void)fabsl(x);
  (void)cabsf(x);
  (void)cabs(x);
  (void)cabsl(x);
  (void)__builtin_abs(x);
  (void)__builtin_labs(x);
  (void)__builtin_llabs(x);
  (void)__builtin_fabsf(x);
  (void)__builtin_fabs(x);
  (void)__builtin_fabsl(x);
  (void)__builtin_cabsf(x);
  (void)__builtin_cabs(x);
  (void)__builtin_cabsl(x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_double>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <abs@plt>
  movq   %rbx,%xmm0
  call   <labs@plt>
  movq   %rbx,%xmm0
  call   <llabs@plt>
  movq   %rbx,%xmm0
  call   <fabsf@plt>
  movq   %rbx,%xmm0
  call   <fabs@plt>
  movq   %rbx,%xmm0
  call   <fabsl@plt>
  movq   %rbx,%xmm0
  call   <cabsf@plt>
  movq   %rbx,%xmm0
  call   <cabs@plt>
  movq   %rbx,%xmm0
  call   <cabsl@plt>
  movq   %rbx,%xmm0
  call   <__builtin_abs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_labs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_llabs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabsf@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabs@plt>
  movq   %rbx,%xmm0
  call   <__builtin_fabsl@plt>
  movq   %rbx,%xmm0
  call   <__builtin_cabsf@plt>
  movq   %rbx,%xmm0
  call   <__builtin_cabs@plt>
  movq   %rbx,%xmm0
  pop    %rbx
  jmp    1260 <__builtin_cabsl@plt>
```

assistant: ```c
void test_double(double x) {
  (void)abs(x);
  (void)labs(x);
  (void)llabs(x);
  (void)fabsf(x);
  (void)fabs(x);
  (void)fabsl(x);
  (void)cabsf(x);
  (void)cabs(x);
  (void)cabsl(x);
  (void)__builtin_abs(x);
  (void)__builtin_labs(x);
  (void)__builtin_llabs(x);
  (void)__builtin_fabsf(x);
  (void)__builtin_fabs(x);
  (void)__builtin_fabsl(x);
  (void)__builtin_cabsf(x);
  (void)__builtin_cabs(x);
  (void)__builtin_cabsl(x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_region_name_VC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  ja     L60
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D51(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D51(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D24(%rip),%rax
  jmp    L21
  lea    D70(%rip),%rax
  jmp    L21
  lea    D15(%rip),%rax
  jmp    L21
  lea    D31(%rip),%rax
  jmp    L21
  lea    D7(%rip),%rax
  jmp    L21
  lea    D57(%rip),%rax
  jmp    L21
L60:
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D24
type_guessed: string
name: parse_data
arguments: label: D70
type_guessed: string
name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D31
type_guessed: string
name: parse_data
arguments: label: D7
type_guessed: string
name: parse_data
arguments: label: D57
type_guessed: string

tool: D24: Charlotte

tool: D70: Saint Andrew

tool: D15: Saint David

tool: D31: Saint George

tool: D7: Saint Patrick

tool: D57: Grenadines

assistant: ```c
const char *get_region_name_VC(int region_code) {
  switch (region_code) {
  case 1:
    return "Charlotte";
  case 2:
    return "Saint Andrew";
  case 3:
    return "Saint David";
  case 4:
    return "Saint George";
  case 5:
    return "Saint Patrick";
  case 6:
    return "Grenadines";
  default:
    return NULL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_region_name_VC>:
  endbr64
  cmp    $0x6,%edi
  ja     L2
  mov    %edi,%edi
  lea    D62(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D17(%rip),%rax
  ret
  lea    D11(%rip),%rax
  ret
  lea    D67(%rip),%rax
  ret
  lea    D39(%rip),%rax
  ret
  lea    D41(%rip),%rax
  ret
L2:
  mov    $0x0,%eax
  ret
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string
name: disassemble_data
arguments: label: D67
type_guessed: string
name: disassemble_data
arguments: label: D39
type_guessed: string
name: disassemble_data
arguments: label: D41
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D17: Saint Andrew

tool: D11: Saint David

tool: D67: Saint George

tool: D39: Saint Patrick

tool: D41: Grenadines

tool: D1: Charlotte

assistant: ```c
const char *get_region_name_VC(int region_code) {
  switch (region_code) {
  case 1:
    return "Charlotte";
  case 2:
    return "Saint Andrew";
  case 3:
    return "Saint David";
  case 4:
    return "Saint George";
  case 5:
    return "Saint Patrick";
  case 6:
    return "Grenadines";
  default:
    return NULL;
  }
}
```