ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L12
L5:
  mov    0x8(%rbx),%rdi
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
L27:
  mov    %rsp,%rbx
  lea    D0(%rip),%r12
  jmp    L14
  xchg   %ax,%ax
L55:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  mov    %rbp,%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L55
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
L4:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L27
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D4
data_type: string

tool: D13: r

tool: D0: %s

tool: D22: Filename is missing

tool: D4: Could not open file

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char buf[128];
  if (argc < 2) {
    printf("Filename is missing\n");
    exit(1);
  }
  fp = fopen(argv[1], "r");
  if (fp == 0) {
    printf("Could not open file\n");
    exit(2);
  }
  while (fgets(buf, 128, fp)) {
    printf("%s", buf);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L12
L28:
  mov    0x8(%rbx),%rdi
  lea    D24(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L30
L62:
  mov    %rsp,%rbx
  lea    D38(%rip),%r12
  jmp    L66
  xchg   %ax,%ax
L51:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L66:
  mov    %rbp,%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L51
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L28
L30:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L62
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
type_guessed: string
name: unpack_data
arguments: tag: D38
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D11
type_guessed: string

tool: D24: r

tool: D38: %s

tool: D17: Filename is missing

tool: D11: Could not open file

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char buf[128];
  if (argc < 2) {
    printf("Filename is missing\n");
    exit(1);
  }
  fp = fopen(argv[1], "r");
  if (fp == 0) {
    printf("Could not open file\n");
    exit(2);
  }
  while (fgets(buf, 128, fp)) {
    printf("%s", buf);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D60(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D146(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D91(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D102(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rsi
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D60
datatype: string
name: extract_symbolic_data
arguments: data_tag: D134
datatype: string
name: extract_symbolic_data
arguments: data_tag: D146
datatype: string
name: extract_symbolic_data
arguments: data_tag: D91
datatype: string
name: extract_symbolic_data
arguments: data_tag: D46
datatype: string
name: extract_symbolic_data
arguments: data_tag: D54
datatype: string
name: extract_symbolic_data
arguments: data_tag: D33
datatype: string
name: extract_symbolic_data
arguments: data_tag: D102
datatype: string

tool: D60: *********		   ***   		   *   		    *    


tool: D134: %s

tool: D146: *       *		  *   *  		  ***  		   * *   


tool: D91: *       *		 *     * 		 ***** 		  *   *  


tool: D46: *       *		 *     * 		   *   		 *     * 


tool: D54: *       *		 *     * 		   *   		*       *


tool: D33: *       *		 *     * 		   *   		  *   *  


tool: D102: *       *		  *   *  		   *   		   * *   


assistant: ```c
int main(void) {
  printf("%s", "*********\t\t   ***   \t\t   *   \t\t    *    \n");
  printf("%s", "*       *\t\t  *   *  \t\t  ***  \t\t   * *   \n");
  printf("%s", "*       *\t\t *     * \t\t ***** \t\t  *   *  \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t *     * \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t*       *\n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t *     * \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t  *   *  \n");
  printf("%s", "*       *\t\t  *   *  \t\t   *   \t\t   * *   \n");
  printf("%s", "*********\t\t   ***   \t\t   *   \t\t    *    \n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbp
  mov    %rbp,%rsi
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D75(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D15(%rip),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D12
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string
name: read_data
arguments: label: D1
type_guessed: string
name: read_data
arguments: label: D75
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D44
type_guessed: string
name: read_data
arguments: label: D0
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string

tool: D12: *********		   ***   		   *   		    *    


tool: D26: %s

tool: D1: *       *		  *   *  		  ***  		   * *   


tool: D75: *       *		 *     * 		 ***** 		  *   *  


tool: D15: *       *		 *     * 		   *   		 *     * 


tool: D44: *       *		 *     * 		   *   		*       *


tool: D0: *       *		 *     * 		   *   		  *   *  


tool: D14: *       *		  *   *  		   *   		   * *   


assistant: ```c
int main(void) {
  printf("%s", "*********\t\t   ***   \t\t   *   \t\t    *    \n");
  printf("%s", "*       *\t\t  *   *  \t\t  ***  \t\t   * *   \n");
  printf("%s", "*       *\t\t *     * \t\t ***** \t\t  *   *  \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t *     * \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t*       *\n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t *     * \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t  *   *  \n");
  printf("%s", "*       *\t\t  *   *  \t\t   *   \t\t   * *   \n");
  printf("%s", "*********\t\t   ***   \t\t   *   \t\t    *    \n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  lea    D40(%rip),%r12
  push   %rbp
  lea    D72(%rip),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D61(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D50(%rip),%rsi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D6(%rip),%rsi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D60(%rip),%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D24
data_type: string
name: retrieve_data
arguments: data_label: D40
data_type: string
name: retrieve_data
arguments: data_label: D72
data_type: string
name: retrieve_data
arguments: data_label: D61
data_type: string
name: retrieve_data
arguments: data_label: D50
data_type: string
name: retrieve_data
arguments: data_label: D6
data_type: string
name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D60
data_type: string

tool: D24: *       *		 *     * 		   *   		 *     * 


tool: D40: *********		   ***   		   *   		    *    


tool: D72: %s

tool: D61: *       *		  *   *  		  ***  		   * *   


tool: D50: *       *		 *     * 		 ***** 		  *   *  


tool: D6: *       *		 *     * 		   *   		*       *


tool: D7: *       *		 *     * 		   *   		  *   *  


tool: D60: *       *		  *   *  		   *   		   * *   


assistant: ```c
int main(void) {
  printf("%s", "*********\t\t   ***   \t\t   *   \t\t    *    \n");
  printf("%s", "*       *\t\t  *   *  \t\t  ***  \t\t   * *   \n");
  printf("%s", "*       *\t\t *     * \t\t ***** \t\t  *   *  \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t *     * \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t*       *\n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t *     * \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t  *   *  \n");
  printf("%s", "*       *\t\t  *   *  \t\t   *   \t\t   * *   \n");
  printf("%s", "*********\t\t   ***   \t\t   *   \t\t    *    \n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D37(%rip),%r13
  push   %r12
  lea    D54(%rip),%r12
  push   %rbp
  lea    D65(%rip),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D57(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D28(%rip),%rsi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D68(%rip),%rsi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D73(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D39(%rip),%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D37
type_guessed: string
name: parse_data
arguments: tag: D54
type_guessed: string
name: parse_data
arguments: tag: D65
type_guessed: string
name: parse_data
arguments: tag: D57
type_guessed: string
name: parse_data
arguments: tag: D28
type_guessed: string
name: parse_data
arguments: tag: D68
type_guessed: string
name: parse_data
arguments: tag: D73
type_guessed: string
name: parse_data
arguments: tag: D39
type_guessed: string

tool: D37: *       *		 *     * 		   *   		 *     * 


tool: D54: *********		   ***   		   *   		    *    


tool: D65: %s

tool: D57: *       *		  *   *  		  ***  		   * *   


tool: D28: *       *		 *     * 		 ***** 		  *   *  


tool: D68: *       *		 *     * 		   *   		*       *


tool: D73: *       *		 *     * 		   *   		  *   *  


tool: D39: *       *		  *   *  		   *   		   * *   


assistant: ```c
int main(void) {
  printf("%s", "*********\t\t   ***   \t\t   *   \t\t    *    \n");
  printf("%s", "*       *\t\t  *   *  \t\t  ***  \t\t   * *   \n");
  printf("%s", "*       *\t\t *     * \t\t ***** \t\t  *   *  \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t *     * \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t*       *\n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t *     * \n");
  printf("%s", "*       *\t\t *     * \t\t   *   \t\t  *   *  \n");
  printf("%s", "*       *\t\t  *   *  \t\t   *   \t\t   * *   \n");
  printf("%s", "*********\t\t   ***   \t\t   *   \t\t    *    \n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L0:
  mov    $0x0,%eax
  call   <bink@plt>
  jmp    L0
```

assistant: ```c
int main(void) {
  while (1) {
    bink();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L8:
  mov    $0x0,%eax
  call   <bink@plt>
  jmp    L8
```

assistant: ```c
int main(void) {
  while (1) {
    bink();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <bink@plt>
  jmp    L4
```

assistant: ```c
int main(void) {
  while (1) {
    bink();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <bink@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  while (1) {
    bink();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_reversible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L0
L3:
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L16
  mov    $0x0,%eax
  jmp    L33
L16:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L0:
  cmpq   $0x0,-0x8(%rbp)
  jg     L3
  mov    $0x1,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
bool is_reversible(long num) {
  while (num > 0) {
    if (num % 2 == 0)
      return false;
    num /= 10;
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_reversible>:
  endbr64
  test   %rdi,%rdi
  jle    L6
  movabs $0x6666666666666667,%rsi
  test   $0x1,%dil
  je     L15
L8:
  mov    %rdi,%rcx
  mov    %rdi,%rax
  imul   %rsi
  sar    $0x2,%rdx
  sar    $0x3f,%rdi
  sub    %rdi,%rdx
  mov    %rdx,%rdi
  cmp    $0x9,%rcx
  jle    L0
  test   $0x1,%dl
  jne    L8
  mov    $0x0,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
L6:
  mov    $0x1,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool is_reversible(long num) {
  while (num > 0) {
    if (num % 2 == 0)
      return false;
    num /= 10;
  }
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_reversible>:
  endbr64
  mov    %rdi,%rdx
  test   %rdi,%rdi
  jle    L24
  movabs $0xcccccccccccccccd,%rsi
  test   $0x1,%dil
  jne    L42
  jmp    L5
  xchg   %ax,%ax
L38:
  test   $0x1,%dl
  je     L5
L42:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  jg     L38
L24:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool is_reversible(long num) {
  while (num > 0) {
    if (num % 2 == 0)
      return false;
    num /= 10;
  }
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_reversible>:
  endbr64
  mov    %rdi,%rdx
  test   %rdi,%rdi
  jle    L5
  movabs $0xcccccccccccccccd,%rsi
  test   $0x1,%dil
  jne    L49
  jmp    L7
  xchg   %ax,%ax
L37:
  test   $0x1,%dl
  je     L7
L49:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  jg     L37
L5:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool is_reversible(long num) {
  while (num > 0) {
    if (num % 2 == 0)
      return false;
    num /= 10;
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<send_mail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x7d0(%rax),%r8
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <smtp_start_mail@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L39
  mov    $0x0,%eax
  call   <smtp_error@plt>
  mov    %eax,%edi
  call   <fatal@plt>
L39:
  cmpq   $0x0,-0x38(%rbp)
  je     L2
  mov    $0x0,%eax
  call   <lp_from_address@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <smtp_write@plt>
  mov    -0x4(%rbp),%eax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <smtp_write@plt>
L2:
  mov    -0x40(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <smtp_write_data@plt>
  cmpq   $0x0,0x10(%rbp)
  je     L4
  mov    -0x4(%rbp),%eax
  mov    0x10(%rbp),%rsi
  mov    %eax,%edi
  call   <smtp_write_data@plt>
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <smtp_end_mail@plt>
  cmp    $0xffffffff,%eax
  jne    L35
  mov    $0x0,%eax
  call   <smtp_error@plt>
  mov    %eax,%edi
  call   <fatal@plt>
L35:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D19
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D19: X-Loop: %s


tool: D16: 


assistant: ```c
void send_mail(char *from, char *to, char *cc, char *bcc, char *subject, char *body, char *sig) {
  int fd;
  fd = smtp_start_mail(from, to, cc, bcc, subject, strlen(body) + 2000);
  if (fd == -1)
    fatal(smtp_error());
  if (subject) {
    smtp_write(fd, "X-Loop: %s\n", lp_from_address());
    smtp_write(fd, "\n");
  }
  smtp_write_data(fd, body);
  if (sig)
    smtp_write_data(fd, sig);
  if (smtp_end_mail(fd) == -1)
    fatal(smtp_error());
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_mail>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%r15
  mov    %r8,%rbp
  mov    %r9,%rbx
  mov    %r9,%rdi
  call   <strlen@plt>
  lea    0x7d0(%rax),%r9
  mov    %rbp,%r8
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <smtp_start_mail@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L7
L19:
  test   %rbp,%rbp
  je     L48
  mov    $0x0,%eax
  call   <lp_from_address@plt>
  mov    %eax,%edx
  lea    D14(%rip),%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <smtp_write@plt>
  lea    D8(%rip),%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <smtp_write@plt>
L48:
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <smtp_write_data@plt>
  cmpq   $0x0,0x40(%rsp)
  je     L16
  mov    0x40(%rsp),%rsi
  mov    %r12d,%edi
  call   <smtp_write_data@plt>
L16:
  mov    %r12d,%edi
  call   <smtp_end_mail@plt>
  cmp    $0xffffffff,%eax
  je     L0
L52:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    $0x0,%eax
  call   <smtp_error@plt>
  mov    %eax,%edi
  call   <fatal@plt>
  jmp    L19
L0:
  mov    $0x0,%eax
  call   <smtp_error@plt>
  mov    %eax,%edi
  call   <fatal@plt>
  jmp    L52
```

tool_calls: name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D8
type: string

tool: D14: X-Loop: %s


tool: D8: 


assistant: ```c
void send_mail(char *from, char *to, char *cc, char *bcc, char *subject, char *body, char *sig) {
  int fd;
  fd = smtp_start_mail(from, to, cc, bcc, subject, strlen(body) + 2000);
  if (fd == -1)
    fatal(smtp_error());
  if (subject) {
    smtp_write(fd, "X-Loop: %s\n", lp_from_address());
    smtp_write(fd, "\n");
  }
  smtp_write_data(fd, body);
  if (sig)
    smtp_write_data(fd, sig);
  if (smtp_end_mail(fd) == -1)
    fatal(smtp_error());
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_mail>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r9,%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  mov    0x50(%rsp),%r13
  call   <strlen@plt>
  mov    0x8(%rsp),%rcx
  mov    %rbp,%rdi
  mov    %rbx,%r8
  lea    0x7d0(%rax),%r9
  mov    %r15,%rdx
  mov    %r14,%rsi
  call   <smtp_start_mail@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L17
L34:
  test   %rbx,%rbx
  je     L15
  xor    %eax,%eax
  call   <lp_from_address@plt>
  lea    D14(%rip),%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <smtp_write@plt>
  lea    D5(%rip),%rsi
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <smtp_write@plt>
L15:
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <smtp_write_data@plt>
  test   %r13,%r13
  je     L22
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <smtp_write_data@plt>
L22:
  mov    %ebp,%edi
  call   <smtp_end_mail@plt>
  cmp    $0xffffffff,%eax
  je     L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  call   <smtp_error@plt>
  mov    %eax,%edi
  call   <fatal@plt>
  jmp    L34
L28:
  xor    %eax,%eax
  call   <smtp_error@plt>
  add    $0x18,%rsp
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1130 <fatal@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D14: X-Loop: %s


tool: D5: 


assistant: ```c
void send_mail(char *from, char *to, char *cc, char *bcc, char *subject, char *body, char *sig) {
  int fd;
  fd = smtp_start_mail(from, to, cc, bcc, subject, strlen(body) + 2000);
  if (fd == -1)
    fatal(smtp_error());
  if (subject) {
    smtp_write(fd, "X-Loop: %s\n", lp_from_address());
    smtp_write(fd, "\n");
  }
  smtp_write_data(fd, body);
  if (sig)
    smtp_write_data(fd, sig);
  if (smtp_end_mail(fd) == -1)
    fatal(smtp_error());
}
```