ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_region_name_RW>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xf,-0x4(%rbp)
  ja     L91
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D103(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D103(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D45(%rip),%rax
  jmp    L90
  lea    D6(%rip),%rax
  jmp    L90
  lea    D100(%rip),%rax
  jmp    L90
  lea    D39(%rip),%rax
  jmp    L90
  lea    D23(%rip),%rax
  jmp    L90
  lea    D39(%rip),%rax
  jmp    L90
  lea    D107(%rip),%rax
  jmp    L90
  lea    D68(%rip),%rax
  jmp    L90
  lea    D67(%rip),%rax
  jmp    L90
L91:
  mov    $0x0,%eax
L90:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D45
datatype: string
name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D100
datatype: string
name: read_data
arguments: tag: D39
datatype: string
name: read_data
arguments: tag: D23
datatype: string
name: read_data
arguments: tag: D107
datatype: string
name: read_data
arguments: tag: D68
datatype: string
name: read_data
arguments: tag: D67
datatype: string

tool: D45: Butare

tool: D6: Gitarama

tool: D100: Kibungo

tool: D39: Kigali

tool: D23: Est

tool: D107: Nord

tool: D68: Ouest

tool: D67: Sud

assistant: ```c
const char *get_region_name_RW(int region_code) {
  switch (region_code) {
  case 1:
    return "Butare";
  case 6:
    return "Gitarama";
  case 7:
    return "Kibungo";
  case 9:
    return "Kigali";
  case 11:
    return "Est";
  case 12:
    return "Kigali";
  case 13:
    return "Nord";
  case 14:
    return "Ouest";
  case 15:
    return "Sud";
  default:
    return NULL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_region_name_RW>:
  endbr64
  cmp    $0xf,%edi
  ja     L4
  mov    %edi,%edi
  lea    D11(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D26(%rip),%rax
  ret
  lea    D35(%rip),%rax
  ret
  lea    D81(%rip),%rax
  ret
  lea    D54(%rip),%rax
  ret
  lea    D81(%rip),%rax
  ret
  lea    D27(%rip),%rax
  ret
  lea    D82(%rip),%rax
  ret
  lea    D72(%rip),%rax
  ret
L4:
  mov    $0x0,%eax
  ret
  lea    D70(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D35
data_type: string
name: extract_symbolic_data
arguments: tag: D81
data_type: string
name: extract_symbolic_data
arguments: tag: D54
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D82
data_type: string
name: extract_symbolic_data
arguments: tag: D72
data_type: string
name: extract_symbolic_data
arguments: tag: D70
data_type: string

tool: D26: Gitarama

tool: D35: Kibungo

tool: D81: Kigali

tool: D54: Est

tool: D27: Nord

tool: D82: Ouest

tool: D72: Sud

tool: D70: Butare

assistant: ```c
const char *get_region_name_RW(int region_code) {
  switch (region_code) {
  case 1:
    return "Butare";
  case 6:
    return "Gitarama";
  case 7:
    return "Kibungo";
  case 9:
    return "Kigali";
  case 11:
    return "Est";
  case 12:
    return "Kigali";
  case 13:
    return "Nord";
  case 14:
    return "Ouest";
  case 15:
    return "Sud";
  default:
    return NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_region_name_RW>:
  endbr64
  cmp    $0xf,%edi
  ja     L5
  lea    D4(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D36(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D66(%rip),%rax
  ret
  lea    D75(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D3(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D8(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D5(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D89(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D67(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D36
type_guessed: string
name: unpack_data
arguments: label: D66
type_guessed: string
name: unpack_data
arguments: label: D75
type_guessed: string
name: unpack_data
arguments: label: D3
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string
name: unpack_data
arguments: label: D89
type_guessed: string
name: unpack_data
arguments: label: D67
type_guessed: string

tool: D36: Kigali

tool: D66: Est

tool: D75: Nord

tool: D3: Ouest

tool: D8: Sud

tool: D5: Kibungo

tool: D89: Butare

tool: D67: Gitarama

assistant: ```c
const char *get_region_name_RW(int region_code) {
  switch (region_code) {
  case 1:
    return "Butare";
  case 6:
    return "Gitarama";
  case 7:
    return "Kibungo";
  case 9:
    return "Kigali";
  case 11:
    return "Est";
  case 12:
    return "Kigali";
  case 13:
    return "Nord";
  case 14:
    return "Ouest";
  case 15:
    return "Sud";
  default:
    return NULL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_region_name_RW>:
  endbr64
  cmp    $0xf,%edi
  ja     L0
  lea    D27(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D37(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D17(%rip),%rax
  ret
  lea    D55(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D28(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D9(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D52(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D62(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D26(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: label: D37
type: string
name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D55
type: string
name: read_data
arguments: label: D28
type: string
name: read_data
arguments: label: D9
type: string
name: read_data
arguments: label: D52
type: string
name: read_data
arguments: label: D62
type: string
name: read_data
arguments: label: D26
type: string

tool: D37: Kigali

tool: D17: Est

tool: D55: Nord

tool: D28: Ouest

tool: D9: Sud

tool: D52: Kibungo

tool: D62: Butare

tool: D26: Gitarama

assistant: ```c
const char *get_region_name_RW(int region_code) {
  switch (region_code) {
  case 1:
    return "Butare";
  case 6:
    return "Gitarama";
  case 7:
    return "Kibungo";
  case 9:
    return "Kigali";
  case 11:
    return "Est";
  case 12:
    return "Kigali";
  case 13:
    return "Nord";
  case 14:
    return "Ouest";
  case 15:
    return "Sud";
  default:
    return NULL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<combinationSum3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %esi,-0x58(%rbp)
  mov    %rdx,-0x60(%rbp)
  mov    %rcx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0x9,-0x48(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x68(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x60(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  movl   $0xffffffff,-0x44(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L11
L0:
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,-0x58(%rbp)
  jl     L4
  mov    -0x44(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  mov    -0x44(%rbp),%eax
  lea    0x1(%rax),%r8d
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x58(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%r10d
  mov    -0x4c(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x38(%rbp),%r9
  mov    -0x54(%rbp),%edx
  mov    -0x48(%rbp),%esi
  lea    -0x30(%rbp),%rax
  push   -0x68(%rbp)
  push   -0x60(%rbp)
  lea    -0x40(%rbp),%rcx
  push   %rcx
  push   %r8
  mov    %r10d,%r8d
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <traverse@plt>
  add    $0x20,%rsp
  addl   $0x1,-0x4c(%rbp)
L11:
  mov    -0x4c(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L0
  jmp    L12
L4:
  nop
L12:
  mov    -0x40(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int **combinationSum3(int k, int target, int **colSizes, int *returnSize) {
  int nums[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  int size = sizeof(nums) / sizeof(int);
  int **arr = (int **)malloc(sizeof(int *));
  *returnSize = 0;
  *colSizes = (int *)malloc(sizeof(int));
  int *stack = (int *)malloc(sizeof(int) * k);
  int top = -1;
  for (int i = 0; i < size; i++) {
    if (nums[i] > target)
      break;
    stack[top + 1] = nums[i];
    traverse(nums, size, i + 1, k, target - nums[i], stack, top + 1, &arr, colSizes, returnSize);
  }
  return arr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<combinationSum3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%ebx
  mov    %edi,0xc(%rsp)
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x20(%rsp)
  movl   $0x2,0x24(%rsp)
  movl   $0x3,0x28(%rsp)
  movl   $0x4,0x2c(%rsp)
  movl   $0x5,0x30(%rsp)
  movl   $0x6,0x34(%rsp)
  movl   $0x7,0x38(%rsp)
  movl   $0x8,0x3c(%rsp)
  movl   $0x9,0x40(%rsp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  movl   $0x0,(%r14)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x1,%ebx
  lea    0x18(%rsp),%r15
L11:
  mov    0x1c(%rsp,%rbx,4),%eax
  cmp    %ebp,%eax
  jg     L4
  mov    %eax,(%r12)
  lea    0x20(%rsp),%rdi
  push   %r14
  push   %r13
  push   %r15
  push   $0x0
  mov    %r12,%r9
  mov    %ebp,%r8d
  sub    %eax,%r8d
  mov    0x2c(%rsp),%ecx
  mov    %ebx,%edx
  mov    $0x9,%esi
  call   <traverse@plt>
  add    $0x1,%rbx
  add    $0x20,%rsp
  cmp    $0xa,%rbx
  jne    L11
L4:
  mov    0x18(%rsp),%rax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int **combinationSum3(int k, int target, int **colSizes, int *returnSize) {
  int nums[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  int size = sizeof(nums) / sizeof(int);
  int **arr = (int **)malloc(sizeof(int *));
  *returnSize = 0;
  *colSizes = (int *)malloc(sizeof(int));
  int *stack = (int *)malloc(sizeof(int) * k);
  int top = -1;
  for (int i = 0; i < size; i++) {
    if (nums[i] > target)
      break;
    stack[top + 1] = nums[i];
    traverse(nums, size, i + 1, k, target - nums[i], stack, top + 1, &arr, colSizes, returnSize);
  }
  return arr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<combinationSum3>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    $0x8,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x58,%rsp
  mov    %rdx,(%rsp)
  lea    0x20(%rsp),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x200000001,%rax
  movl   $0x9,0x40(%rsp)
  mov    %rax,0x20(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x38(%rsp)
  call   <malloc@plt>
  movl   $0x0,(%r14)
  mov    $0x4,%edi
  mov    %rax,0x18(%rsp)
  call   <malloc@plt>
  lea    0x0(,%r12,4),%edi
  mov    %rax,(%rbx)
  mov    $0x1,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  lea    0x18(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L19:
  mov    -0x4(%r15,%rbx,4),%eax
  cmp    %ebp,%eax
  jg     L3
  mov    %eax,0x0(%r13)
  mov    %ebp,%r8d
  mov    %ebx,%edx
  mov    %r13,%r9
  push   %r14
  sub    %eax,%r8d
  mov    %r12d,%ecx
  mov    $0x9,%esi
  push   0x8(%rsp)
  mov    %r15,%rdi
  add    $0x1,%rbx
  push   0x18(%rsp)
  push   $0x0
  call   <traverse@plt>
  add    $0x20,%rsp
  cmp    $0xa,%rbx
  jne    L19
L3:
  mov    0x18(%rsp),%rax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int **combinationSum3(int k, int target, int **colSizes, int *returnSize) {
  int nums[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  int size = sizeof(nums) / sizeof(int);
  int **arr = (int **)malloc(sizeof(int *));
  *returnSize = 0;
  *colSizes = (int *)malloc(sizeof(int));
  int *stack = (int *)malloc(sizeof(int) * k);
  int top = -1;
  for (int i = 0; i < size; i++) {
    if (nums[i] > target)
      break;
    stack[top + 1] = nums[i];
    traverse(nums, size, i + 1, k, target - nums[i], stack, top + 1, &arr, colSizes, returnSize);
  }
  return arr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<combinationSum3>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    $0x8,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x58,%rsp
  movdqa D17(%rip),%xmm0
  mov    %rdx,(%rsp)
  lea    0x20(%rsp),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x20(%rsp)
  movdqa D14(%rip),%xmm0
  movl   $0x9,0x40(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <malloc@plt>
  movl   $0x0,(%r14)
  mov    $0x4,%edi
  mov    %rax,0x18(%rsp)
  call   <malloc@plt>
  lea    0x0(,%r12,4),%edi
  mov    %rax,(%rbx)
  mov    $0x1,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  lea    0x18(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L20:
  mov    -0x4(%r15,%rbx,4),%eax
  cmp    %ebp,%eax
  jg     L29
  mov    %eax,0x0(%r13)
  mov    %ebp,%r8d
  mov    %ebx,%edx
  mov    %r13,%r9
  push   %r14
  sub    %eax,%r8d
  mov    %r12d,%ecx
  mov    $0x9,%esi
  push   0x8(%rsp)
  mov    %r15,%rdi
  add    $0x1,%rbx
  push   0x18(%rsp)
  push   $0x0
  call   <traverse@plt>
  add    $0x20,%rsp
  cmp    $0xa,%rbx
  jne    L20
L29:
  mov    0x18(%rsp),%rax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D17
datatype: byte[16]
name: retrieve_data
arguments: data_label: D14
datatype: byte[16]

tool: {"D17": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D14": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int **combinationSum3(int k, int target, int **colSizes, int *returnSize) {
  int nums[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  int size = sizeof(nums) / sizeof(int);
  int **arr = (int **)malloc(sizeof(int *));
  *returnSize = 0;
  *colSizes = (int *)malloc(sizeof(int));
  int *stack = (int *)malloc(sizeof(int) * k);
  int top = -1;
  for (int i = 0; i < size; i++) {
    if (nums[i] > target)
      break;
    stack[top + 1] = nums[i];
    traverse(nums, size, i + 1, k, target - nums[i], stack, top + 1, &arr, colSizes, returnSize);
  }
  return arr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBFIFOConfigSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x2000,%eax
  test   %eax,%eax
  je     L0
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%r8d
  mov    %edx,%ecx
  mov    $0x62,%edx
  mov    %eax,%edi
  call   <_USBIndexWrite@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  mov    $0x2,%r8d
  mov    %edx,%ecx
  mov    $0x64,%edx
  mov    %eax,%edi
  call   <_USBIndexWrite@plt>
  jmp    L5
L0:
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%r8d
  mov    %edx,%ecx
  mov    $0x63,%edx
  mov    %eax,%edi
  call   <_USBIndexWrite@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  mov    $0x2,%r8d
  mov    %edx,%ecx
  mov    $0x66,%edx
  mov    %eax,%edi
  call   <_USBIndexWrite@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void USBFIFOConfigSet(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32FIFOAddress, uint32_t ui32FIFOSize, uint32_t ui32Flags) {
  ;

  ;
  if (ui32Flags & (0x00002000 | 0x00002000)) {
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000062, ui32FIFOSize, 1);
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000064, ui32FIFOAddress >> 3, 2);
  } else {
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000063, ui32FIFOSize, 1);
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000066, ui32FIFOAddress >> 3, 2);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<USBFIFOConfigSet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %edx,%ebp
  test   $0x2000,%r8d
  je     L3
  mov    %esi,%ebx
  sar    $0x4,%ebx
  mov    $0x1,%r8d
  mov    $0x62,%edx
  mov    %ebx,%esi
  call   <_USBIndexWrite@plt>
  mov    %ebp,%ecx
  sar    $0x3,%ecx
  mov    $0x2,%r8d
  mov    $0x64,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <_USBIndexWrite@plt>
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    %esi,%ebx
  sar    $0x4,%ebx
  mov    $0x1,%r8d
  mov    $0x63,%edx
  mov    %ebx,%esi
  call   <_USBIndexWrite@plt>
  mov    %ebp,%ecx
  sar    $0x3,%ecx
  mov    $0x2,%r8d
  mov    $0x66,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <_USBIndexWrite@plt>
  jmp    L2
```

assistant: ```c
void USBFIFOConfigSet(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32FIFOAddress, uint32_t ui32FIFOSize, uint32_t ui32Flags) {
  ;

  ;
  if (ui32Flags & (0x00002000 | 0x00002000)) {
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000062, ui32FIFOSize, 1);
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000064, ui32FIFOAddress >> 3, 2);
  } else {
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000063, ui32FIFOSize, 1);
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000066, ui32FIFOAddress >> 3, 2);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<USBFIFOConfigSet>:
  endbr64
  sar    $0x4,%esi
  sar    $0x3,%edx
  and    $0x2000,%r8d
  push   %r13
  mov    $0x1,%r8d
  push   %r12
  mov    %edx,%r13d
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  je     L4
  mov    $0x62,%edx
  call   <_USBIndexWrite@plt>
  mov    %r13d,%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x2,%r8d
  pop    %rbp
  mov    $0x64,%edx
  pop    %r12
  pop    %r13
  jmp    1050 <_USBIndexWrite@plt>
  nopl   (%rax)
L4:
  mov    $0x63,%edx
  call   <_USBIndexWrite@plt>
  mov    %r13d,%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x2,%r8d
  pop    %rbp
  mov    $0x66,%edx
  pop    %r12
  pop    %r13
  jmp    1050 <_USBIndexWrite@plt>
```

assistant: ```c
void USBFIFOConfigSet(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32FIFOAddress, uint32_t ui32FIFOSize, uint32_t ui32Flags) {
  ;

  ;
  if (ui32Flags & (0x00002000 | 0x00002000)) {
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000062, ui32FIFOSize, 1);
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000064, ui32FIFOAddress >> 3, 2);
  } else {
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000063, ui32FIFOSize, 1);
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000066, ui32FIFOAddress >> 3, 2);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<USBFIFOConfigSet>:
  endbr64
  sar    $0x4,%esi
  sar    $0x3,%edx
  and    $0x2000,%r8d
  push   %r13
  mov    $0x1,%r8d
  push   %r12
  mov    %edx,%r13d
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  je     L7
  mov    $0x62,%edx
  call   <_USBIndexWrite@plt>
  mov    %r13d,%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x2,%r8d
  pop    %rbp
  mov    $0x64,%edx
  pop    %r12
  pop    %r13
  jmp    1050 <_USBIndexWrite@plt>
  nopl   (%rax)
L7:
  mov    $0x63,%edx
  call   <_USBIndexWrite@plt>
  mov    %r13d,%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x2,%r8d
  pop    %rbp
  mov    $0x66,%edx
  pop    %r12
  pop    %r13
  jmp    1050 <_USBIndexWrite@plt>
```

assistant: ```c
void USBFIFOConfigSet(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32FIFOAddress, uint32_t ui32FIFOSize, uint32_t ui32Flags) {
  ;

  ;
  if (ui32Flags & (0x00002000 | 0x00002000)) {
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000062, ui32FIFOSize, 1);
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000064, ui32FIFOAddress >> 3, 2);
  } else {
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000063, ui32FIFOSize, 1);
    _USBIndexWrite(ui32Base, ui32Endpoint >> 4, 0x00000066, ui32FIFOAddress >> 3, 2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<base64_alloc_encode_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <base64_encoded_size@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *base64_alloc_encode_buffer(size_t input_size) {
  size_t encoded_size = base64_encoded_size(input_size);
  char *buffer = malloc(encoded_size + 1);
  buffer[encoded_size] = 0;
  return buffer;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<base64_alloc_encode_buffer>:
  endbr64
  push   %rbx
  call   <base64_encoded_size@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
```

assistant: ```c
char *base64_alloc_encode_buffer(size_t input_size) {
  size_t encoded_size = base64_encoded_size(input_size);
  char *buffer = malloc(encoded_size + 1);
  buffer[encoded_size] = 0;
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<base64_alloc_encode_buffer>:
  endbr64
  push   %rbx
  call   <base64_encoded_size@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
```

assistant: ```c
char *base64_alloc_encode_buffer(size_t input_size) {
  size_t encoded_size = base64_encoded_size(input_size);
  char *buffer = malloc(encoded_size + 1);
  buffer[encoded_size] = 0;
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<base64_alloc_encode_buffer>:
  endbr64
  push   %rbx
  call   <base64_encoded_size@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
```

assistant: ```c
char *base64_alloc_encode_buffer(size_t input_size) {
  size_t encoded_size = base64_encoded_size(input_size);
  char *buffer = malloc(encoded_size + 1);
  buffer[encoded_size] = 0;
  return buffer;
}
```