user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L71:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L71
  sub    $0xe08,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x9df8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%r8d
  test   %r8d,%r8d
  jle    L134
  lea    0x20(%rsp),%rax
  movslq %r8d,%rdx
  xor    %esi,%esi
  mov    %r8d,0xc(%rsp)
  shl    $0x2,%rdx
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  mov    %rax,%r15
  call   <memset@plt>
  mov    0x1c(%rsp),%eax
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  movl   $0x0,0x8(%rsp)
  mov    0xc(%rsp),%r8d
  lea    D13(%rip),%r13
  test   %eax,%eax
  jle    L62
  nopl   0x0(%rax,%rax,1)
L172:
  lea    0x1b0(%rsp),%rbx
  xor    %r14d,%r14d
  sub    %rbp,%rbx
  xchg   %ax,%ax
L9:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <scanf@plt>
  lea    (%rbx,%rbp,1),%rax
  add    $0x4,%rbx
  mov    (%rax,%r12,1),%eax
  add    %eax,(%r15)
  mov    0x1c(%rsp),%eax
  cmp    %r14d,%eax
  jg     L9
  addl   $0x1,0x8(%rsp)
  mov    0x18(%rsp),%r8d
  mov    0x8(%rsp),%ecx
  cmp    %r8d,%ecx
  jge    L113
  add    $0x4,%r15
  sub    $0x190,%rbp
  add    $0x190,%r12
  test   %eax,%eax
  jg     L172
L62:
  mov    0x8(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r8d,%r14d
  jge    L113
  mov    0x24(%rsp),%ebp
  mov    0x20(%rsp),%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  cmp    $0x2,%r8d
  jle    L92
L63:
  lea    -0x2(%r8),%ecx
  cmp    $0x2,%r8d
  mov    $0x1,%eax
  cmovle %eax,%ecx
  cmp    $0x5,%r8d
  jle    L86
  movd   %ebp,%xmm3
  lea    0x28(%rsp),%rax
  mov    %ecx,%edx
  shr    $0x2,%edx
  pshufd $0x0,%xmm3,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x38(%rsp,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L26:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rdx,%rax
  jne    L26
  movdqa %xmm2,%xmm1
  mov    %ecx,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  movdqa %xmm1,%xmm0
  lea    0x2(%rdx),%eax
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movd   %xmm1,%ebp
  cmp    %ecx,%edx
  je     L92
L191:
  movslq %eax,%rdx
  mov    0x20(%rsp,%rdx,4),%edx
  cmp    %edx,%ebp
  cmovl  %edx,%ebp
  lea    0x1(%rax),%edx
  cmp    %r8d,%edx
  jge    L92
  movslq %edx,%rdx
  mov    0x20(%rsp,%rdx,4),%edx
  cmp    %edx,%ebp
  cmovl  %edx,%ebp
  add    $0x2,%eax
  cmp    %r8d,%eax
  jge    L92
  cltq
  mov    0x20(%rsp,%rax,4),%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
L92:
  xor    %ebx,%ebx
  lea    D12(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L216:
  mov    (%rsp),%rax
  mov    %ebx,%esi
  cmp    %ebp,(%rax,%rbx,4)
  je     L3
  add    $0x1,%rbx
  cmp    %ebx,%r8d
  jg     L216
L134:
  mov    0x9df8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x9e08,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x18(%rsp),%r8d
  cmp    %ebx,%r8d
  jg     L216
  jmp    L134
L86:
  mov    $0x2,%eax
  jmp    L191
L113:
  mov    0x20(%rsp),%ebp
  mov    0x24(%rsp),%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  cmp    $0x2,%r8d
  jg     L63
  test   %r8d,%r8d
  jle    L134
  jmp    L92
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string
name: retrieve_data
arguments: data_tag: D13
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D3: %d %d

tool: D13: %d

tool: D12: %d 

assistant: ```c
int main() {
  int M[100][100];
  int i, j, n, m, sum[100];
  scanf("%d %d", &n, &m);
  for (i = 0; i < n; i++)
    sum[i] = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      scanf("%d", &M[i][j]);
      sum[i] = sum[i] + M[i][j];
    }
  }
  int max;
  if (sum[0] >= sum[1])
    max = sum[0];
  else
    max = sum[1];
  for (i = 2; i < n; i++) {
    if (sum[i] >= max)
      max = sum[i];
  }
  for (i = 0; i < n; i++) {
    if (sum[i] == max)
      printf("%d ", i);
  }
  return 0;
}
```