ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fk10>:
  endbr64
  test   %esi,%esi
  jle    L6
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x10,%rsp
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %ebp,%eax
  pxor   %xmm0,%xmm0
  add    $0x1,%ebp
  add    $0x8,%r14
  cvtsi2sd %eax,%xmm0
  lea    0x0(%rbp,%rbp,1),%ebx
  movapd %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  mulsd  (%r12),%xmm1
  cvttsd2si %xmm1,%edi
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm0
  mulsd  0x8(%r12),%xmm0
  sub    %eax,%ebx
  cvttsd2si %xmm0,%edi
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  sub    %eax,%ebx
  cvtsi2sd %ebx,%xmm0
  movsd  %xmm0,-0x8(%r14)
  cmp    %r13d,%ebp
  jle    L14
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void fk10(double *x, int M, int N, double *f, void *params) {
  int i;
  for (i = 1; i <= M; ++i) {
    f[i - 1] = 2 + 2 * i - exp(i * x[0]) - exp(i * x[1]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getIP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    (%rax),%ecx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x14(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    D27(%rip),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <strncpy@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  je     L25
  mov    $0xffffffff,%eax
  jmp    L22
L25:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  lea    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <inet_ntoa@plt>
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int getIP(const char *interface, char *ip) {
  int fd;
  struct ifreq ifr;
  fd = socket(AF_INET, SOCK_DGRAM, 0);
  ifr.ifr_addr.sa_family = AF_INET;
  strncpy(ifr.ifr_name, interface, IFNAMSIZ - 1);
  if (ioctl(fd, SIOCGIFADDR, &ifr) != 0) {
    return -1;
  }
  close(fd);
  strcpy(ip, inet_ntoa(((struct sockaddr_in *)&ifr.ifr_addr)->sin_addr));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getIP>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D10(%rip),%r13
  mov    $0x0,%edx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    0x0(%r13),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  mov    0x0(%r13),%eax
  mov    %eax,(%rsp)
  mov    D0(%rip),%rax
  mov    (%rax),%rdx
  sub    $0x1,%rdx
  mov    %rbp,%rsi
  mov    0x4(%rsp),%edi
  call   <strncpy@plt>
  mov    %rsp,%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  jne    L11
  mov    %ebx,%edi
  call   <close@plt>
  mov    (%rsp),%edi
  call   <inet_ntoa@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L18
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getIP(const char *interface, char *ip) {
  int fd;
  struct ifreq ifr;
  fd = socket(AF_INET, SOCK_DGRAM, 0);
  ifr.ifr_addr.sa_family = AF_INET;
  strncpy(ifr.ifr_name, interface, IFNAMSIZ - 1);
  if (ioctl(fd, SIOCGIFADDR, &ifr) != 0) {
    return -1;
  }
  close(fd);
  strcpy(ip, inet_ntoa(((struct sockaddr_in *)&ifr.ifr_addr)->sin_addr));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getIP>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  xor    %edx,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D21(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D32(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    0x4(%rsp),%edi
  mov    %r12,%rsi
  mov    %eax,%ebp
  mov    (%rbx),%eax
  mov    %eax,(%rsp)
  mov    D31(%rip),%rax
  mov    (%rax),%rdx
  sub    $0x1,%rdx
  call   <strncpy@plt>
  mov    D14(%rip),%rax
  mov    %rsp,%rdx
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  jne    L21
  mov    %ebp,%edi
  call   <close@plt>
  mov    (%rsp),%edi
  call   <inet_ntoa@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  xor    %eax,%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L21:
  mov    $0xffffffff,%eax
  jmp    L14
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getIP(const char *interface, char *ip) {
  int fd;
  struct ifreq ifr;
  fd = socket(AF_INET, SOCK_DGRAM, 0);
  ifr.ifr_addr.sa_family = AF_INET;
  strncpy(ifr.ifr_name, interface, IFNAMSIZ - 1);
  if (ioctl(fd, SIOCGIFADDR, &ifr) != 0) {
    return -1;
  }
  close(fd);
  strcpy(ip, inet_ntoa(((struct sockaddr_in *)&ifr.ifr_addr)->sin_addr));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getIP>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  xor    %edx,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D24(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D29(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    0x4(%rsp),%edi
  mov    %r12,%rsi
  mov    %eax,%ebp
  mov    (%rbx),%eax
  mov    %eax,(%rsp)
  mov    D38(%rip),%rax
  mov    (%rax),%rdx
  sub    $0x1,%rdx
  call   <strncpy@plt>
  mov    D31(%rip),%rax
  mov    %rsp,%rdx
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  jne    L24
  mov    %ebp,%edi
  call   <close@plt>
  mov    (%rsp),%edi
  call   <inet_ntoa@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  xor    %eax,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L24:
  mov    $0xffffffff,%eax
  jmp    L2
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getIP(const char *interface, char *ip) {
  int fd;
  struct ifreq ifr;
  fd = socket(AF_INET, SOCK_DGRAM, 0);
  ifr.ifr_addr.sa_family = AF_INET;
  strncpy(ifr.ifr_name, interface, IFNAMSIZ - 1);
  if (ioctl(fd, SIOCGIFADDR, &ifr) != 0) {
    return -1;
  }
  close(fd);
  strcpy(ip, inet_ntoa(((struct sockaddr_in *)&ifr.ifr_addr)->sin_addr));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rop3_129_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x20(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x1c(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  or     %al,-0x2(%rbp)
  notb   -0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x2(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_129_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk1 = S ^ T;
  stk2 = *D ^ S;
  stk1 = stk1 | stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_129_0_0>:
  endbr64
  xor    %esi,%edx
  xor    (%rdi),%sil
  or     %edx,%esi
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_129_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk1 = S ^ T;
  stk2 = *D ^ S;
  stk1 = stk1 | stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rop3_129_0_0>:
  endbr64
  xor    %esi,%edx
  xor    (%rdi),%sil
  or     %edx,%esi
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_129_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk1 = S ^ T;
  stk2 = *D ^ S;
  stk1 = stk1 | stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rop3_129_0_0>:
  endbr64
  xor    %esi,%edx
  xor    (%rdi),%sil
  or     %edx,%esi
  not    %esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_129_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk1 = S ^ T;
  stk2 = *D ^ S;
  stk1 = stk1 | stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  je     L16
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__tokencap_dump@plt>
L16:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  je     L96
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__tokencap_dump@plt>
  jmp    L96
L50:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x2(%rbp)
  jne    L93
  mov    $0x0,%eax
  jmp    L80
L93:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L68
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jbe    L83
  mov    $0x1,%eax
  jmp    L80
L83:
  mov    $0xffffffff,%eax
  jmp    L80
L68:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L96:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L50
  mov    $0x0,%eax
L80:
  leave
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t len) {
  if (__tokencap_is_ro(str1))
    __tokencap_dump(str1, len, 1);
  if (__tokencap_is_ro(str2))
    __tokencap_dump(str2, len, 1);
  while (len--) {
    unsigned char c1 = *str1, c2 = *str2;
    if (!c1)
      return 0;
    if (c1 != c2)
      return (c1 > c2) ? 1 : -1;
    str1++;
    str2++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  jne    L29
L42:
  mov    %rbp,%rdi
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  jne    L102
L30:
  test   %r12,%r12
  je     L44
  mov    $0x0,%eax
L65:
  movzbl (%rbx,%rax,1),%edx
  movzbl 0x0(%rbp,%rax,1),%ecx
  test   %dl,%dl
  je     L27
  cmp    %cl,%dl
  jne    L1
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L65
  mov    $0x0,%eax
  jmp    L33
L29:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <__tokencap_dump@plt>
  jmp    L42
L102:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__tokencap_dump@plt>
  jmp    L30
L1:
  cmp    %dl,%cl
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  jmp    L33
L44:
  mov    $0x0,%eax
  jmp    L33
L27:
  mov    $0x0,%eax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t len) {
  if (__tokencap_is_ro(str1))
    __tokencap_dump(str1, len, 1);
  if (__tokencap_is_ro(str2))
    __tokencap_dump(str2, len, 1);
  while (len--) {
    unsigned char c1 = *str1, c2 = *str2;
    if (!c1)
      return 0;
    if (c1 != c2)
      return (c1 > c2) ? 1 : -1;
    str1++;
    str2++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strncmp>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  jne    L16
  mov    %rbp,%rdi
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  jne    L69
L84:
  test   %r12,%r12
  je     L39
  xor    %eax,%eax
  jmp    L26
  nopl   0x0(%rax)
L38:
  cmp    %cl,%dl
  jne    L78
  add    $0x1,%rax
  cmp    %r12,%rax
  je     L39
L26:
  movzbl (%rbx,%rax,1),%edx
  movzbl 0x0(%rbp,%rax,1),%ecx
  test   %dl,%dl
  jne    L38
L39:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  mov    %rbx,%rdi
  mov    $0x1,%edx
  mov    %r12,%rsi
  call   <__tokencap_dump@plt>
  mov    %rbp,%rdi
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  je     L84
L69:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__tokencap_dump@plt>
  jmp    L84
  nop
L78:
  cmp    %dl,%cl
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t len) {
  if (__tokencap_is_ro(str1))
    __tokencap_dump(str1, len, 1);
  if (__tokencap_is_ro(str2))
    __tokencap_dump(str2, len, 1);
  while (len--) {
    unsigned char c1 = *str1, c2 = *str2;
    if (!c1)
      return 0;
    if (c1 != c2)
      return (c1 > c2) ? 1 : -1;
    str1++;
    str2++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncmp>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbp,%rdi
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  jne    L25
L3:
  test   %r12,%r12
  je     L8
  xor    %eax,%eax
  jmp    L52
  nopl   0x0(%rax)
L50:
  cmp    %cl,%dl
  jne    L5
  add    $0x1,%rax
  cmp    %rax,%r12
  je     L8
L52:
  movzbl (%rbx,%rax,1),%edx
  movzbl 0x0(%rbp,%rax,1),%ecx
  test   %dl,%dl
  jne    L50
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  mov    %rbx,%rdi
  mov    $0x1,%edx
  mov    %r12,%rsi
  call   <__tokencap_dump@plt>
  mov    %rbp,%rdi
  call   <__tokencap_is_ro@plt>
  test   %rax,%rax
  je     L3
L25:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__tokencap_dump@plt>
  jmp    L3
  nop
L5:
  cmp    %dl,%cl
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t len) {
  if (__tokencap_is_ro(str1))
    __tokencap_dump(str1, len, 1);
  if (__tokencap_is_ro(str2))
    __tokencap_dump(str2, len, 1);
  while (len--) {
    unsigned char c1 = *str1, c2 = *str2;
    if (!c1)
      return 0;
    if (c1 != c2)
      return (c1 > c2) ? 1 : -1;
    str1++;
    str2++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cstrlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L16
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L16:
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *cstrlwr(char *s) {
  for (; s; ++s)
    *s = tolower(*s);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cstrlwr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L2
L19:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  jmp    L19
L2:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *cstrlwr(char *s) {
  for (; s; ++s)
    *s = tolower(*s);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cstrlwr>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L9:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  jmp    L9
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *cstrlwr(char *s) {
  for (; s; ++s)
    *s = tolower(*s);
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cstrlwr>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L0:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  jmp    L0
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *cstrlwr(char *s) {
  for (; s; ++s)
    *s = tolower(*s);
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Operand_soffsetx4_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x4,%eax
  shr    $0x2,%eax
  and    $0x3ffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_soffsetx4_encode(unsigned int *valp) {
  unsigned offset_0, soffsetx4_0;
  soffsetx4_0 = *valp;
  offset_0 = ((soffsetx4_0 - 0x4) >> 2) & 0x3ffff;
  *valp = offset_0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Operand_soffsetx4_encode>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x4,%eax
  shr    $0x2,%eax
  and    $0x3ffff,%eax
  mov    %eax,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Operand_soffsetx4_encode(unsigned int *valp) {
  unsigned offset_0, soffsetx4_0;
  soffsetx4_0 = *valp;
  offset_0 = ((soffsetx4_0 - 0x4) >> 2) & 0x3ffff;
  *valp = offset_0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Operand_soffsetx4_encode>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x4,%eax
  shr    $0x2,%eax
  and    $0x3ffff,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_soffsetx4_encode(unsigned int *valp) {
  unsigned offset_0, soffsetx4_0;
  soffsetx4_0 = *valp;
  offset_0 = ((soffsetx4_0 - 0x4) >> 2) & 0x3ffff;
  *valp = offset_0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Operand_soffsetx4_encode>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x4,%eax
  shr    $0x2,%eax
  and    $0x3ffff,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_soffsetx4_encode(unsigned int *valp) {
  unsigned offset_0, soffsetx4_0;
  soffsetx4_0 = *valp;
  offset_0 = ((soffsetx4_0 - 0x4) >> 2) & 0x3ffff;
  *valp = offset_0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <execv@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D8
datatype: string

tool: D5: gcc

tool: D8: /vsta/bin/gcc

assistant: ```c
int main(int argc, char **argv) {
  argv[0] = "gcc";
  execv("/vsta/bin/gcc", argv);
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rax
  mov    %rax,(%rsi)
  lea    D16(%rip),%rdi
  call   <execv@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D16
type_infered: string

tool: D0: gcc

tool: D16: /vsta/bin/gcc

assistant: ```c
int main(int argc, char **argv) {
  argv[0] = "gcc";
  execv("/vsta/bin/gcc", argv);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  lea    D5(%rip),%rax
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  mov    %rax,(%rsi)
  call   <execv@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D5: gcc

tool: D15: /vsta/bin/gcc

assistant: ```c
int main(int argc, char **argv) {
  argv[0] = "gcc";
  execv("/vsta/bin/gcc", argv);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  lea    D3(%rip),%rax
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  mov    %rax,(%rsi)
  call   <execv@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D3: gcc

tool: D6: /vsta/bin/gcc

assistant: ```c
int main(int argc, char **argv) {
  argv[0] = "gcc";
  execv("/vsta/bin/gcc", argv);
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L4
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L0
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void copy(void **a, void *b, size_t size) {
  if (size == 0) {
    size_t len = strlen(b) + 1;
    *a = realloc(*a, len);
    memcpy(*a, b, len);
  } else {
    memcpy(*a, b, size);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdx,%rdx
  jne    L19
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    (%rdi),%rdi
  call   <memcpy@plt>
  jmp    L3
```

assistant: ```c
void copy(void **a, void *b, size_t size) {
  if (size == 0) {
    size_t len = strlen(b) + 1;
    *a = realloc(*a, len);
    memcpy(*a, b, len);
  } else {
    memcpy(*a, b, size);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdx,%rdx
  jne    L7
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rsi
  call   <realloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rdi),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
```

assistant: ```c
void copy(void **a, void *b, size_t size) {
  if (size == 0) {
    size_t len = strlen(b) + 1;
    *a = realloc(*a, len);
    memcpy(*a, b, len);
  } else {
    memcpy(*a, b, size);
  }
}
```