user: 请从给定的汇编指令推导出C源代码：

```asm
<processInput>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  cmp    $0x6,%edi
  ja     L98
  lea    D27(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <pop@plt>
  nopw   0x0(%rax,%rax,1)
L98:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
  lea    0x4(%rsp),%r12
  lea    D25(%rip),%rbp
L32:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L98
  mov    0x4(%rsp),%edi
  call   <findLast@plt>
  mov    0x4(%rsp),%esi
  lea    D85(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <wait@plt>
  jmp    L98
  nop
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L98
  mov    0x4(%rsp),%edi
  call   <push@plt>
  jmp    L98
  nopl   (%rax)
  xor    %eax,%eax
  call   <clear@plt>
  jmp    L98
  nopl   0x0(%rax)
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L98
  mov    0x4(%rsp),%edi
  call   <seek@plt>
  mov    0x4(%rsp),%esi
  lea    D81(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <wait@plt>
  jmp    L98
  nopl   0x0(%rax,%rax,1)
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  lea    D25(%rip),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L32
  mov    0x4(%rsp),%edi
  call   <find@plt>
  mov    0x4(%rsp),%esi
  lea    D67(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <wait@plt>
  jmp    L32
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D25
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D85
type_guessed: string
name: unpack_data
arguments: data_label: D59
type_guessed: string
name: unpack_data
arguments: data_label: D46
type_guessed: string
name: unpack_data
arguments: data_label: D81
type_guessed: string
name: unpack_data
arguments: data_label: D47
type_guessed: string
name: unpack_data
arguments: data_label: D67
type_guessed: string

tool: D25: %d

tool: D5: value to find: 

tool: D85: Position of last element with value %d is %i


tool: D59: Value to add: 

tool: D46: Position to seek: 

tool: D81: Value of element %d is %i


tool: D47: Value to find: 

tool: D67: Position of element with value %d is %i


assistant: ```c
void processInput(int res) {
  int arg = 0;
  switch (res) {
  case 1:
    printf("Value to add: ");
    if (scanf("%d", &arg))
      push(arg);
    break;
  case 2:
    pop();
    break;
  case 3:
    clear();
    break;
  case 4:
    printf("Position to seek: ");
    if (scanf("%d", &arg)) {
      int val = seek(arg);
      printf("Value of element %d is %i\n", arg, val);
      wait();
    }
    break;
  case 5:
    printf("Value to find: ");
    if (scanf("%d", &arg)) {
      int val = find(arg);
      printf("Position of element with value %d is %i\n", arg, val);
      wait();
    }
  case 6:
    printf("value to find: ");
    if (scanf("%d", &arg)) {
      int val = findLast(arg);
      printf("Position of last element with value %d is %i\n", arg, val);
      wait();
    }
  }
}
```