user: 下面的汇编指令对应的C源代码是什么:

```asm
<threeSum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %esi,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  call   <bubblesort@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L143
  mov    %rbx,%rdx
  lea    -0x2(%rbp),%ecx
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  add    $0x8,%rdx
  movl   $0x0,0x24(%rsp)
  mov    %rbx,%r12
  mov    %ecx,0x34(%rsp)
  mov    %rdx,0x18(%rsp)
  mov    %r15,%rdx
  mov    %r14d,%r15d
  mov    %rdx,%r14
  nopl   0x0(%rax)
L42:
  addl   $0x1,0x24(%rsp)
  mov    0x24(%rsp),%edx
  cmp    $0x1,%edx
  je     L52
  cmp    %eax,-0x4(%r12)
  je     L32
L52:
  mov    0x24(%rsp),%eax
  cmp    %eax,0x30(%rsp)
  jle    L32
  mov    0x28(%rsp),%rcx
  movslq %eax,%rdx
  mov    (%r12),%esi
  mov    %rdx,0x10(%rsp)
  lea    0x4(%rcx,%rdx,4),%rbx
  mov    0x34(%rsp),%edx
  mov    -0x4(%rbx),%edi
  sub    %eax,%edx
  mov    %r14,%rax
  mov    %r15d,%r14d
  mov    %rax,%r15
  lea    (%rdi,%rsi,1),%eax
  mov    %edx,0x20(%rsp)
  test   %eax,%eax
  jg     L105
  cs nopw 0x0(%rax,%rax,1)
L139:
  mov    0x20(%rsp),%ecx
  cmp    $0xffffffff,%ecx
  je     L105
  mov    %ecx,%edx
  mov    0x18(%rsp),%rcx
  add    0x10(%rsp),%rdx
  mov    %r15,%rbp
  mov    %rbx,%r13
  mov    %r14d,%r15d
  lea    (%rcx,%rdx,4),%rdx
  mov    %rdx,0x8(%rsp)
  jmp    L160
  nopl   (%rax)
L116:
  mov    $0x3,%edi
  add    $0x1,%r15d
  call   <malloc@plt>
  mov    %rbp,%rdi
  lea    0x0(,%r15,8),%esi
  mov    %rax,%r14
  mov    (%r12),%eax
  mov    %eax,(%r14)
  mov    -0x4(%rbx),%eax
  mov    %eax,0x4(%r14)
  mov    0x0(%r13),%eax
  mov    %eax,0x8(%r14)
  call   <realloc@plt>
  mov    (%r12),%esi
  mov    -0x4(%rbx),%edi
  mov    %rax,%rbp
  movslq %r15d,%rax
  mov    %r14,-0x8(%rbp,%rax,8)
  lea    (%rsi,%rdi,1),%eax
  add    0x0(%r13),%eax
L75:
  test   %eax,%eax
  jg     L95
  add    $0x4,%r13
  cmp    0x8(%rsp),%r13
  je     L95
L1:
  lea    (%rdi,%rsi,1),%eax
L160:
  add    0x0(%r13),%eax
  jne    L75
  test   %r15d,%r15d
  je     L116
  movslq %r15d,%rax
  mov    -0x8(%rbp,%rax,8),%rax
  cmp    %esi,(%rax)
  jne    L116
  cmp    %edi,0x4(%rax)
  jne    L116
  add    $0x4,%r13
  cmp    0x8(%rsp),%r13
  jne    L1
  nopl   0x0(%rax)
L95:
  mov    (%rbx),%edi
  mov    %r15d,%r14d
  add    $0x4,%rbx
  addq   $0x1,0x10(%rsp)
  subl   $0x1,0x20(%rsp)
  mov    %rbp,%r15
  lea    (%rdi,%rsi,1),%eax
  test   %eax,%eax
  jle    L139
L105:
  mov    %r15,%rax
  mov    %r14d,%r15d
  mov    %rax,%r14
L32:
  mov    0x4(%r12),%eax
  add    $0x4,%r12
  test   %eax,%eax
  jle    L42
  mov    %r14,%rax
  mov    %r15d,%r14d
  mov    %rax,%r15
L122:
  mov    0x38(%rsp),%rax
  mov    %r14d,(%rax)
  add    $0x48,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L143:
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  jmp    L122
```

assistant: ```c
int **threeSum(int *A, int n, int *returnSize) {
  int i = 0, j = 0, k = 0;
  bubblesort(A, n);
  int **result = NULL;
  int num = 0;
  for (i = 0; A[i] <= 0; i++) {
    if (i > 0 && A[i] == A[i - 1])
      continue;
    for (j = i + 1; j < n; j++) {
      if (A[i] + A[j] > 0)
        break;
      for (k = j + 1; k < n; k++) {
        if (A[i] + A[j] + A[k] == 0) {
          if (num > 0 && A[i] == result[num - 1][0] && A[j] == result[num - 1][1])
            continue;
          int *tmp = malloc(3);
          tmp[0] = A[i];
          tmp[1] = A[j];
          tmp[2] = A[k];
          num++;
          result = realloc(result, num * sizeof(int *));
          result[num - 1] = tmp;
        }
        if (A[i] + A[j] + A[k] > 0)
          break;
      }
    }
  }
  *returnSize = num;
  return result;
}
```