ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L91:
  mov    %ebp,%ebx
  add    $0x1,%ebp
  nopl   (%rax)
L17:
  mov    %r12d,%eax
  add    $0x1,%r12d
  lea    0x3(%rax),%r8d
  sub    $0x2,%eax
  and    $0xfffffffd,%eax
  je     L175
  test   $0x1,%r12b
  je     L41
  imul   $0xaaaaaaab,%r12d,%eax
  cmp    $0x55555555,%eax
  jbe    L41
  test   $0x3,%r12b
  je     L41
  imul   $0xcccccccd,%r12d,%edx
  cmp    $0x33333333,%edx
  jbe    L41
  ror    %eax
  cmp    $0x2aaaaaaa,%eax
  jbe    L41
  imul   $0xb6db6db7,%r12d,%eax
  cmp    $0x24924924,%eax
  jbe    L41
  test   $0x7,%r12b
  je     L41
  mov    %r12d,%eax
  mov    $0x9,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L41
  mov    %r8d,%eax
  mov    $0x3,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L41
  test   $0x3,%r8b
  je     L41
  mov    %r8d,%eax
  mov    $0x5,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L41
  mov    %r8d,%eax
  mov    $0x6,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L41
  mov    %r8d,%eax
  mov    $0x7,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L41
  test   $0x7,%r8b
  je     L41
  mov    %r8d,%eax
  mov    $0x9,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L175
  nopl   0x0(%rax,%rax,1)
L41:
  cmp    %ebp,%ebx
  jne    L17
L172:
  cmp    $0xa,%ebx
  jne    L91
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L175:
  add    $0x1,%ebx
  mov    %r8d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L17
  jmp    L172
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: (%d, %d)


assistant: ```c
int main() {
  int a, b, c, d;
  a = 1;
  b = 1;
  c = 0;
  d = 0;
  while (c < 10) {
    d++;
    while (c != d) {
      a++;
      b = a + 2;
      if (a == 3 || a == 5) {
        c++;
        printf("(%d, %d)\n", a, b);
      } else {
        if (a % 2 != 0 && a % 3 != 0 && a % 4 != 0 && a % 5 != 0 && a % 6 != 0 && a % 7 != 0 && a % 8 != 0 && a % 9 != 0 && b % 2 != 0 && b % 3 != 0 && b % 4 != 0 && b % 5 != 0 && b % 6 != 0 && b % 7 != 0 && b % 8 != 0 && b % 9 != 0) {
          c++;
          printf("(%d, %d)\n", a, b);
        }
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L105:
  mov    %ebp,%ebx
  add    $0x1,%ebp
  nopl   (%rax)
L116:
  mov    %r12d,%eax
  add    $0x1,%r12d
  lea    0x3(%rax),%r8d
  sub    $0x2,%eax
  and    $0xfffffffd,%eax
  je     L130
  test   $0x1,%r12b
  je     L132
  imul   $0xaaaaaaab,%r12d,%eax
  cmp    $0x55555555,%eax
  jbe    L132
  test   $0x3,%r12b
  je     L132
  imul   $0xcccccccd,%r12d,%edx
  cmp    $0x33333333,%edx
  jbe    L132
  ror    %eax
  cmp    $0x2aaaaaaa,%eax
  jbe    L132
  imul   $0xb6db6db7,%r12d,%eax
  cmp    $0x24924924,%eax
  jbe    L132
  test   $0x7,%r12b
  je     L132
  mov    %r12d,%eax
  mov    $0x9,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L132
  mov    %r8d,%eax
  mov    $0x3,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L132
  test   $0x3,%r8b
  je     L132
  mov    %r8d,%eax
  mov    $0x5,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L132
  mov    %r8d,%eax
  mov    $0x6,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L132
  mov    %r8d,%eax
  mov    $0x7,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L132
  test   $0x7,%r8b
  je     L132
  mov    %r8d,%eax
  mov    $0x9,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L130
  nopl   0x0(%rax,%rax,1)
L132:
  cmp    %ebp,%ebx
  jne    L116
L169:
  cmp    $0xa,%ebx
  jne    L105
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L130:
  add    $0x1,%ebx
  mov    %r8d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L116
  jmp    L169
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: (%d, %d)


assistant: ```c
int main() {
  int a, b, c, d;
  a = 1;
  b = 1;
  c = 0;
  d = 0;
  while (c < 10) {
    d++;
    while (c != d) {
      a++;
      b = a + 2;
      if (a == 3 || a == 5) {
        c++;
        printf("(%d, %d)\n", a, b);
      } else {
        if (a % 2 != 0 && a % 3 != 0 && a % 4 != 0 && a % 5 != 0 && a % 6 != 0 && a % 7 != 0 && a % 8 != 0 && a % 9 != 0 && b % 2 != 0 && b % 3 != 0 && b % 4 != 0 && b % 5 != 0 && b % 6 != 0 && b % 7 != 0 && b % 8 != 0 && b % 9 != 0) {
          c++;
          printf("(%d, %d)\n", a, b);
        }
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ebur128_get_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x3,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ebur128_get_version(int *major, int *minor, int *patch) {
  *major = 1;
  *minor = 0;
  *patch = 3;
}
```
user: What is the c source code of the assembly code below?

```asm
<ebur128_get_version>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0x0,(%rsi)
  movl   $0x3,(%rdx)
  ret
```

assistant: ```c
void ebur128_get_version(int *major, int *minor, int *patch) {
  *major = 1;
  *minor = 0;
  *patch = 3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ebur128_get_version>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0x0,(%rsi)
  movl   $0x3,(%rdx)
  ret
```

assistant: ```c
void ebur128_get_version(int *major, int *minor, int *patch) {
  *major = 1;
  *minor = 0;
  *patch = 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ebur128_get_version>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0x0,(%rsi)
  movl   $0x3,(%rdx)
  ret
```

assistant: ```c
void ebur128_get_version(int *major, int *minor, int *patch) {
  *major = 1;
  *minor = 0;
  *patch = 3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ho2ro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x54(%rbp),%edx
  lea    -0x30(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ho2ax@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x54(%rbp),%edx
  mov    -0x50(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ax2ro@plt>
  mov    %eax,-0x34(%rbp)
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int ho2ro(double *ho, double *ro, int p) {
  double ax[4];
  int trash;
  trash = ho2ax(ho, ax, p);
  trash = ax2ro(ax, ro, p);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ho2ro>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <ho2ax@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ax2ro@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x1,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ho2ro(double *ho, double *ro, int p) {
  double ax[4];
  int trash;
  trash = ho2ax(ho, ax, p);
  trash = ax2ro(ax, ro, p);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ho2ro>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <ho2ax@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ax2ro@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ho2ro(double *ho, double *ro, int p) {
  double ax[4];
  int trash;
  trash = ho2ax(ho, ax, p);
  trash = ax2ro(ax, ro, p);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ho2ro>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <ho2ax@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ax2ro@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ho2ro(double *ho, double *ro, int p) {
  double ax[4];
  int trash;
  trash = ho2ax(ho, ax, p);
  trash = ax2ro(ax, ro, p);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x2(%rbp)
  jmp    L22
L15:
  movb   $0x0,-0x1(%rbp)
  jmp    L20
L1:
  movsbq -0x2(%rbp),%rax
  imul   $0x5a,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movsbl -0x1(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L20:
  cmpb   $0x8,-0x1(%rbp)
  jle    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
L22:
  cmpb   $0x8,-0x2(%rbp)
  jle    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void output(char grid[9][9][10]) {
  char i, j;
  for (i = 0; i < 9; ++i) {
    for (j = 0; j < 9; ++j)
      putchar('0' + grid[i][j][0]);
    putchar('\n');
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<output>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x5a(%rdi),%rbp
  lea    0x384(%rdi),%r12
L16:
  lea    -0x5a(%rbp),%rbx
L11:
  movzbl (%rbx),%eax
  lea    0x30(%rax),%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0xa,%rbx
  cmp    %rbp,%rbx
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x5a,%rbp
  cmp    %r12,%rbp
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void output(char grid[9][9][10]) {
  char i, j;
  for (i = 0; i < 9; ++i) {
    for (j = 0; j < 9; ++j)
      putchar('0' + grid[i][j][0]);
    putchar('\n');
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<output>:
  endbr64
  push   %r12
  lea    0x384(%rdi),%r12
  push   %rbp
  lea    0x5a(%rdi),%rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L5:
  lea    -0x5a(%rbp),%rbx
  nopl   0x0(%rax)
L9:
  movzbl (%rbx),%eax
  add    $0xa,%rbx
  lea    0x30(%rax),%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L9
  mov    $0xa,%edi
  add    $0x5a,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r12
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void output(char grid[9][9][10]) {
  char i, j;
  for (i = 0; i < 9; ++i) {
    for (j = 0; j < 9; ++j)
      putchar('0' + grid[i][j][0]);
    putchar('\n');
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<output>:
  endbr64
  push   %r12
  lea    0x384(%rdi),%r12
  push   %rbp
  lea    0x5a(%rdi),%rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L4:
  lea    -0x5a(%rbp),%rbx
  nopl   0x0(%rax)
L6:
  movzbl (%rbx),%eax
  add    $0xa,%rbx
  lea    0x30(%rax),%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L6
  mov    $0xa,%edi
  add    $0x5a,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r12
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void output(char grid[9][9][10]) {
  char i, j;
  for (i = 0; i < 9; ++i) {
    for (j = 0; j < 9; ++j)
      putchar('0' + grid[i][j][0]);
    putchar('\n');
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<l6480_cmd_hardhiz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0xa8,%edi
  call   <l6480_send_cmd@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void l6480_cmd_hardhiz(void) {
  l6480_send_cmd(0xA8, 1, 0, 0);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<l6480_cmd_hardhiz>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0xa8,%edi
  call   <l6480_send_cmd@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void l6480_cmd_hardhiz(void) {
  l6480_send_cmd(0xA8, 1, 0, 0);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<l6480_cmd_hardhiz>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0xa8,%edi
  jmp    1050 <l6480_send_cmd@plt>
```

assistant: ```c
void l6480_cmd_hardhiz(void) {
  l6480_send_cmd(0xA8, 1, 0, 0);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<l6480_cmd_hardhiz>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0xa8,%edi
  jmp    1050 <l6480_send_cmd@plt>
```

assistant: ```c
void l6480_cmd_hardhiz(void) {
  l6480_send_cmd(0xA8, 1, 0, 0);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<server_accept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x4,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <accept@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int server_accept(int server) {
  struct sockaddr_in cin;
  memset(&cin, 0, sizeof(cin));
  socklen_t sin_size = sizeof(cin);
  return accept(server, (struct sockaddr *)&cin, &sin_size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<server_accept>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  movl   $0x4,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <accept@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int server_accept(int server) {
  struct sockaddr_in cin;
  memset(&cin, 0, sizeof(cin));
  socklen_t sin_size = sizeof(cin);
  return accept(server, (struct sockaddr *)&cin, &sin_size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<server_accept>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0x4(%rsp),%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  movl   $0x4,0x4(%rsp)
  call   <accept@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int server_accept(int server) {
  struct sockaddr_in cin;
  memset(&cin, 0, sizeof(cin));
  socklen_t sin_size = sizeof(cin);
  return accept(server, (struct sockaddr *)&cin, &sin_size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<server_accept>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0x4(%rsp),%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  movl   $0x4,0x4(%rsp)
  call   <accept@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int server_accept(int server) {
  struct sockaddr_in cin;
  memset(&cin, 0, sizeof(cin));
  socklen_t sin_size = sizeof(cin);
  return accept(server, (struct sockaddr *)&cin, &sin_size);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<redirect_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mg_printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: HTTP/1.1 302 Found
Expires: Thu, 01-Jan-1970 00:00:01 GMT
Cache: no-cache
max-age: 0
s-maxage: 0
Cache-Control: no-cache, no-store, must-revalidate
Location: /%s



assistant: ```c
void redirect_to(struct mg_connection *conn, const char *dest) {
  mg_printf(conn,
            "HTTP/1.1 302 Found\r\n"
            "Expires: Thu, 01-Jan-1970 00:00:01 GMT\r\n"
            "Cache: no-cache\r\n"
            "max-age: 0\r\n"
            "s-maxage: 0\r\n"
            "Cache-Control: no-cache, no-store, must-revalidate\r\n"
            "Location: "
            "/"
            "%s\r\n\r\n",
            dest);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<redirect_to>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D3(%rip),%rsi
  call   <mg_printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: HTTP/1.1 302 Found
Expires: Thu, 01-Jan-1970 00:00:01 GMT
Cache: no-cache
max-age: 0
s-maxage: 0
Cache-Control: no-cache, no-store, must-revalidate
Location: /%s



assistant: ```c
void redirect_to(struct mg_connection *conn, const char *dest) {
  mg_printf(conn,
            "HTTP/1.1 302 Found\r\n"
            "Expires: Thu, 01-Jan-1970 00:00:01 GMT\r\n"
            "Cache: no-cache\r\n"
            "max-age: 0\r\n"
            "s-maxage: 0\r\n"
            "Cache-Control: no-cache, no-store, must-revalidate\r\n"
            "Location: "
            "/"
            "%s\r\n\r\n",
            dest);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<redirect_to>:
  endbr64
  mov    %rsi,%rdx
  lea    D4(%rip),%rsi
  jmp    1050 <mg_printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string

tool: D4: HTTP/1.1 302 Found
Expires: Thu, 01-Jan-1970 00:00:01 GMT
Cache: no-cache
max-age: 0
s-maxage: 0
Cache-Control: no-cache, no-store, must-revalidate
Location: /%s



assistant: ```c
void redirect_to(struct mg_connection *conn, const char *dest) {
  mg_printf(conn,
            "HTTP/1.1 302 Found\r\n"
            "Expires: Thu, 01-Jan-1970 00:00:01 GMT\r\n"
            "Cache: no-cache\r\n"
            "max-age: 0\r\n"
            "s-maxage: 0\r\n"
            "Cache-Control: no-cache, no-store, must-revalidate\r\n"
            "Location: "
            "/"
            "%s\r\n\r\n",
            dest);
}
```
user: What is the c source code of the assembly code below:

```asm
<redirect_to>:
  endbr64
  mov    %rsi,%rdx
  lea    D9(%rip),%rsi
  jmp    1050 <mg_printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: HTTP/1.1 302 Found
Expires: Thu, 01-Jan-1970 00:00:01 GMT
Cache: no-cache
max-age: 0
s-maxage: 0
Cache-Control: no-cache, no-store, must-revalidate
Location: /%s



assistant: ```c
void redirect_to(struct mg_connection *conn, const char *dest) {
  mg_printf(conn,
            "HTTP/1.1 302 Found\r\n"
            "Expires: Thu, 01-Jan-1970 00:00:01 GMT\r\n"
            "Cache: no-cache\r\n"
            "max-age: 0\r\n"
            "s-maxage: 0\r\n"
            "Cache-Control: no-cache, no-store, must-revalidate\r\n"
            "Location: "
            "/"
            "%s\r\n\r\n",
            dest);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%edi
  call   <dobro@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string

tool: D1: %d

assistant: ```c
int main() {
  printf("%d", dobro(4));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <dobro@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: %d

assistant: ```c
int main() {
  printf("%d", dobro(4));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <dobro@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: %d

assistant: ```c
int main() {
  printf("%d", dobro(4));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <dobro@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: %d

assistant: ```c
int main() {
  printf("%d", dobro(4));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rand_expo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
L1:
  mov    $0x0,%eax
  call   <rand_uni@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L13
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  je     L1
L13:
  movsd  D11(%rip),%xmm0
  subsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <log@plt>
  movq   %xmm0,%rax
  movq   D8(%rip),%xmm0
  movq   %rax,%xmm1
  xorpd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  divsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D8
type_guessed: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double rand_expo(double lambda) {
  double u;
  do {
    u = rand_uni();
  } while (u == 0);
  return (log(1 - u) / -lambda);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rand_expo>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
L11:
  mov    $0x0,%eax
  call   <rand_uni@plt>
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm0
  jp     L5
  je     L11
L5:
  movsd  D11(%rip),%xmm1
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%edi
  call   <log@plt>
  xorpd  D1(%rip),%xmm0
  movq   %rbx,%xmm3
  divsd  %xmm3,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type_infered: byte[8]
name: read_data
arguments: data_label: D1
type_infered: byte[16]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double rand_expo(double lambda) {
  double u;
  do {
    u = rand_uni();
  } while (u == 0);
  return (log(1 - u) / -lambda);
}
```