ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gf8mul_00010000>:
  endbr64
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm1
  pxor   %xmm6,%xmm1
  pxor   %xmm6,%xmm0
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm3
  pxor   %xmm5,%xmm0
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm6
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm2
  pxor   %xmm3,%xmm7
  pxor   %xmm7,%xmm3
  pxor   %xmm2,%xmm6
  pxor   %xmm6,%xmm2
  pxor   %xmm1,%xmm5
  pxor   %xmm5,%xmm1
  pxor   %xmm0,%xmm4
  pxor   %xmm4,%xmm0
  ret
```

assistant: ```c
void gf8mul_00010000(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm6, %xmm1\n"
                       "\tpxor    %xmm6, %xmm0\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm3\n"
                       "\tpxor    %xmm5, %xmm0\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm6\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm2\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm4, %xmm0\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calculate_attrib_modifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x4,%edi
  call   <number_bits@plt>
  lea    -0x6(%rax),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  movl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int calculate_attrib_modifier(int bonus) {
  int mod;
  mod = number_bits(4) - 6 + bonus;
  if (mod == 0)
    mod = 1;
  return mod;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calculate_attrib_modifier>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <number_bits@plt>
  lea    -0x6(%rbx,%rax,1),%eax
  test   %eax,%eax
  mov    $0x1,%edx
  cmove  %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int calculate_attrib_modifier(int bonus) {
  int mod;
  mod = number_bits(4) - 6 + bonus;
  if (mod == 0)
    mod = 1;
  return mod;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculate_attrib_modifier>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <number_bits@plt>
  mov    $0x1,%edx
  lea    -0x6(%rbx,%rax,1),%eax
  pop    %rbx
  test   %eax,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int calculate_attrib_modifier(int bonus) {
  int mod;
  mod = number_bits(4) - 6 + bonus;
  if (mod == 0)
    mod = 1;
  return mod;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calculate_attrib_modifier>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <number_bits@plt>
  mov    $0x1,%edx
  lea    -0x6(%rbx,%rax,1),%eax
  pop    %rbx
  test   %eax,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int calculate_attrib_modifier(int bonus) {
  int mod;
  mod = number_bits(4) - 6 + bonus;
  if (mod == 0)
    mod = 1;
  return mod;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  mov    $0x800000,%esi
  mov    %rax,%rdi
  call   <munmap@plt>
L13:
  mov    D20(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%esi
  mov    -0xc(%rbp),%ecx
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x800000,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,-0x8(%rbp)
  mov    D32(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L29
L21:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x800000,%esi
  mov    %rax,%rdi
  call   <madvise@plt>
  mov    -0x8(%rbp),%rax
L29:
  leave
  ret
```

assistant: ```c
u_char *remmap(u_char *mem, int fd, off_t offset) {
  if (mem != NULL)
    munmap(mem, (8 * 1024 * 1024));
  mem = mmap(NULL, (8 * 1024 * 1024), PROT_READ, MAP_SHARED, fd, offset);
  if (mem == MAP_FAILED)
    return (NULL);
  madvise(mem, (8 * 1024 * 1024), MADV_SEQUENTIAL);
  return (mem);
}
```
user: Translate the below assembly code into C programming language:

```asm
<remmap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %edx,%ebp
  test   %rdi,%rdi
  je     L2
  mov    $0x800000,%esi
  call   <munmap@plt>
L2:
  mov    %ebp,%r9d
  mov    %ebx,%r8d
  mov    D20(%rip),%rax
  mov    (%rax),%ecx
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    $0x800000,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,%rbx
  mov    D1(%rip),%rax
  cmp    %rbx,(%rax)
  je     L7
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    $0x800000,%esi
  mov    %rbx,%rdi
  call   <madvise@plt>
L11:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    $0x0,%ebx
  jmp    L11
```

assistant: ```c
u_char *remmap(u_char *mem, int fd, off_t offset) {
  if (mem != NULL)
    munmap(mem, (8 * 1024 * 1024));
  mem = mmap(NULL, (8 * 1024 * 1024), PROT_READ, MAP_SHARED, fd, offset);
  if (mem == MAP_FAILED)
    return (NULL);
  madvise(mem, (8 * 1024 * 1024), MADV_SEQUENTIAL);
  return (mem);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<remmap>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L8
  mov    $0x800000,%esi
  call   <munmap@plt>
L8:
  mov    D7(%rip),%rax
  mov    %r12d,%r8d
  mov    %ebx,%r9d
  xor    %edi,%edi
  mov    $0x800000,%esi
  mov    (%rax),%ecx
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  call   <mmap@plt>
  mov    %rax,%r12
  mov    D15(%rip),%rax
  cmp    %r12,(%rax)
  je     L7
  mov    D12(%rip),%rax
  mov    %r12,%rdi
  mov    $0x800000,%esi
  mov    (%rax),%edx
  call   <madvise@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
u_char *remmap(u_char *mem, int fd, off_t offset) {
  if (mem != NULL)
    munmap(mem, (8 * 1024 * 1024));
  mem = mmap(NULL, (8 * 1024 * 1024), PROT_READ, MAP_SHARED, fd, offset);
  if (mem == MAP_FAILED)
    return (NULL);
  madvise(mem, (8 * 1024 * 1024), MADV_SEQUENTIAL);
  return (mem);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<remmap>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L19
  mov    $0x800000,%esi
  call   <munmap@plt>
L19:
  mov    D36(%rip),%rax
  mov    %r12d,%r8d
  mov    %ebx,%r9d
  xor    %edi,%edi
  mov    $0x800000,%esi
  mov    (%rax),%ecx
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  call   <mmap@plt>
  mov    %rax,%r12
  mov    D19(%rip),%rax
  cmp    %r12,(%rax)
  je     L5
  mov    D20(%rip),%rax
  mov    %r12,%rdi
  mov    $0x800000,%esi
  mov    (%rax),%edx
  call   <madvise@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
u_char *remmap(u_char *mem, int fd, off_t offset) {
  if (mem != NULL)
    munmap(mem, (8 * 1024 * 1024));
  mem = mmap(NULL, (8 * 1024 * 1024), PROT_READ, MAP_SHARED, fd, offset);
  if (mem == MAP_FAILED)
    return (NULL);
  madvise(mem, (8 * 1024 * 1024), MADV_SEQUENTIAL);
  return (mem);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<comm_connect_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D33(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  mov    %eax,-0x4(%rbp)
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L34
  mov    D33(%rip),%rax
  mov    (%rax),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L22
L34:
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L22:
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ignoreErrno@plt>
  test   %rax,%rax
  je     L4
  movl   $0xfffffffa,-0x8(%rbp)
  jmp    L57
L4:
  mov    $0xffffffff,%eax
  jmp    L52
L57:
  mov    -0x8(%rbp),%eax
L52:
  leave
  ret
```

assistant: ```c
int comm_connect_addr(int sock, const struct sockaddr_in *address) {
  int status = (0);
  int x;
  assert(ntohs(address->sin_port) != 0);
  errno = 0;
  x = connect(sock, (struct sockaddr *)address, sizeof(*address));
  if (errno == 0 || errno == EISCONN)
    status = (0);
  else if (ignoreErrno(errno))
    status = (-6);
  else
    return (-1);
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<comm_connect_addr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    (%rsi),%edi
  call   <ntohs@plt>
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D19(%rip),%r12
  movq   $0x0,(%r12)
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <connect@plt>
  mov    (%r12),%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L23
  mov    D11(%rip),%rdx
  cmp    (%rdx),%rdi
  jne    L20
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <ignoreErrno@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  or     $0xfffffffa,%eax
  jmp    L23
```

assistant: ```c
int comm_connect_addr(int sock, const struct sockaddr_in *address) {
  int status = (0);
  int x;
  assert(ntohs(address->sin_port) != 0);
  errno = 0;
  x = connect(sock, (struct sockaddr *)address, sizeof(*address));
  if (errno == 0 || errno == EISCONN)
    status = (0);
  else if (ignoreErrno(errno))
    status = (-6);
  else
    return (-1);
  return status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<comm_connect_addr>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%edi
  call   <ntohs@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
  call   <assert@plt>
  mov    %r12d,%edi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    D8(%rip),%rbx
  movq   $0x0,(%rbx)
  call   <connect@plt>
  mov    (%rbx),%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L8
  mov    D17(%rip),%rdx
  cmp    (%rdx),%rdi
  jne    L19
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  call   <ignoreErrno@plt>
  pop    %rbx
  pop    %rbp
  cmp    $0x1,%rax
  pop    %r12
  sbb    %eax,%eax
  or     $0xfffffffa,%eax
  ret
```

assistant: ```c
int comm_connect_addr(int sock, const struct sockaddr_in *address) {
  int status = (0);
  int x;
  assert(ntohs(address->sin_port) != 0);
  errno = 0;
  x = connect(sock, (struct sockaddr *)address, sizeof(*address));
  if (errno == 0 || errno == EISCONN)
    status = (0);
  else if (ignoreErrno(errno))
    status = (-6);
  else
    return (-1);
  return status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<comm_connect_addr>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%edi
  call   <ntohs@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
  call   <assert@plt>
  mov    %r12d,%edi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    D14(%rip),%rbx
  movq   $0x0,(%rbx)
  call   <connect@plt>
  mov    (%rbx),%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L17
  mov    D10(%rip),%rdx
  cmp    (%rdx),%rdi
  jne    L14
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  call   <ignoreErrno@plt>
  pop    %rbx
  pop    %rbp
  cmp    $0x1,%rax
  pop    %r12
  sbb    %eax,%eax
  or     $0xfffffffa,%eax
  ret
```

assistant: ```c
int comm_connect_addr(int sock, const struct sockaddr_in *address) {
  int status = (0);
  int x;
  assert(ntohs(address->sin_port) != 0);
  errno = 0;
  x = connect(sock, (struct sockaddr *)address, sizeof(*address));
  if (errno == 0 || errno == EISCONN)
    status = (0);
  else if (ignoreErrno(errno))
    status = (-6);
  else
    return (-1);
  return status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strdoubler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L7:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdoubler(char *str) {
  int string_size = strlen(str);
  char *doubled_string = (char *)malloc(sizeof(char) * string_size);
  int doubler_size = string_size * 2 - 1;
  int str_index = 0;
  for (int ii = 0; ii < doubler_size; ++ii) {
    doubled_string[ii++] = str[str_index];
    doubled_string[ii] = str[str_index++];
  }
  return doubled_string;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strdoubler>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  add    %ebp,%ebp
  cmp    $0x1,%ebp
  jle    L0
  mov    %rbx,%rdi
  mov    %rax,%rdx
  sub    $0x2,%ebp
  shr    %ebp
  mov    %ebp,%ebp
  lea    0x2(%rax,%rbp,2),%rsi
L18:
  movzbl (%rdi),%ecx
  mov    %cl,(%rdx)
  mov    %cl,0x1(%rdx)
  add    $0x1,%rdi
  add    $0x2,%rdx
  cmp    %rsi,%rdx
  jne    L18
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strdoubler(char *str) {
  int string_size = strlen(str);
  char *doubled_string = (char *)malloc(sizeof(char) * string_size);
  int doubler_size = string_size * 2 - 1;
  int str_index = 0;
  for (int ii = 0; ii < doubler_size; ++ii) {
    doubled_string[ii++] = str[str_index];
    doubled_string[ii] = str[str_index++];
  }
  return doubled_string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strdoubler>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  add    %ebp,%ebp
  cmp    $0x1,%ebp
  jle    L6
  sub    $0x2,%ebp
  mov    %rbx,%rdi
  mov    %rax,%rdx
  shr    %ebp
  lea    0x2(%rax,%rbp,2),%rsi
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl (%rdi),%ecx
  add    $0x2,%rdx
  add    $0x1,%rdi
  mov    %cl,-0x2(%rdx)
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L18
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strdoubler(char *str) {
  int string_size = strlen(str);
  char *doubled_string = (char *)malloc(sizeof(char) * string_size);
  int doubler_size = string_size * 2 - 1;
  int str_index = 0;
  for (int ii = 0; ii < doubler_size; ++ii) {
    doubled_string[ii++] = str[str_index];
    doubled_string[ii] = str[str_index++];
  }
  return doubled_string;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L53:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  je     L40
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L54
L24:
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jle    L70
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x14(%rbp)
  jmp    L84
L70:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L30
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x10(%rbp)
  jmp    L84
L30:
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,-0x10(%rbp)
L84:
  addl   $0x1,-0xc(%rbp)
L54:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L24
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L53
L40:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L86
  call   <__stack_chk_fail@plt>
L86:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string

tool: D16: %d


tool: D15: %d %d


assistant: ```c
int main(void) {
  int num, ta, tb, sca, scb, i;
  while (1) {
    scanf("%d\n", &num);
    if (num == 0)
      break;
    sca = 0, scb = 0;
    for (i = 0; i < num; i++) {
      scanf("%d %d\n", &ta, &tb);
      if (ta > tb) {
        sca += ta + tb;
      } else if (ta < tb) {
        scb += ta + tb;
      } else {
        sca += ta;
        scb += tb;
      }
    }
    printf("%d %d\n", sca, scb);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r15
  lea    D18(%rip),%r13
  lea    0x14(%rsp),%r14
  jmp    L96
L27:
  jge    L90
  add    %edx,%eax
  add    %eax,%r12d
L23:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L83
L15:
  lea    0x10(%rsp),%rsi
  mov    %r14,%rdx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  mov    0x14(%rsp),%edx
  cmp    %edx,%eax
  jle    L27
  add    %edx,%eax
  add    %eax,%ebp
  jmp    L23
L90:
  add    %eax,%ebp
  add    %edx,%r12d
  jmp    L23
L62:
  mov    $0x0,%r12d
  mov    $0x0,%ebp
L83:
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L96:
  mov    %r15,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L69
  jle    L62
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L15
L69:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: string

tool: D18: %d %d


tool: D6: %d


assistant: ```c
int main(void) {
  int num, ta, tb, sca, scb, i;
  while (1) {
    scanf("%d\n", &num);
    if (num == 0)
      break;
    sca = 0, scb = 0;
    for (i = 0; i < num; i++) {
      scanf("%d %d\n", &ta, &tb);
      if (ta > tb) {
        sca += ta + tb;
      } else if (ta < tb) {
        scb += ta + tb;
      } else {
        sca += ta;
        scb += tb;
      }
    }
    printf("%d %d\n", sca, scb);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L33:
  mov    0x8(%rsp),%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L107
  jle    L12
  xor    %r15d,%r15d
  xor    %r12d,%r12d
  lea    0x24(%rsp),%r14
  xor    %ebp,%ebp
  lea    0x20(%rsp),%r13
  jmp    L18
  nopl   (%rax)
L17:
  add    %edx,%eax
  add    %eax,%ebp
L6:
  add    $0x1,%r15d
  cmp    %r15d,0x1c(%rsp)
  jle    L74
L18:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  mov    0x24(%rsp),%edx
  cmp    %edx,%eax
  jg     L17
  jge    L5
  add    %edx,%eax
  add    $0x1,%r15d
  add    %eax,%r12d
  cmp    %r15d,0x1c(%rsp)
  jg     L18
L74:
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L33
  nop
L5:
  add    %eax,%ebp
  add    %edx,%r12d
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L107:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L12:
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  mov    %rbx,%rdi
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <printf@plt>
  jmp    L33
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D5
data_type: string

tool: D16: %d %d


tool: D5: %d


assistant: ```c
int main(void) {
  int num, ta, tb, sca, scb, i;
  while (1) {
    scanf("%d\n", &num);
    if (num == 0)
      break;
    sca = 0, scb = 0;
    for (i = 0; i < num; i++) {
      scanf("%d %d\n", &ta, &tb);
      if (ta > tb) {
        sca += ta + tb;
      } else if (ta < tb) {
        scb += ta + tb;
      } else {
        sca += ta;
        scb += tb;
      }
    }
    printf("%d %d\n", sca, scb);
  }
  return 0;
}
```