ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x2a,-0x13(%rbp)
  movb   $0x23,-0x12(%rbp)
  movb   $0x20,-0x11(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x10(%rbp),%eax
  sub    $0x2,%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  movsbl -0x11(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  movsbl -0x13(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  movsbl -0x11(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L23:
  mov    -0x10(%rbp),%eax
  sub    $0x2,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  movsbl -0x11(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  movsbl -0x13(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  lea    0x1(%rax),%edx
  movsbl -0x12(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  movsbl -0x13(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  mov    -0x10(%rbp),%eax
  sub    $0x2,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  movsbl -0x11(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L23
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  lea    -0x1(%rax),%edx
  movsbl -0x13(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <repeat@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string
name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D2: %d

tool: D1: %d


assistant: ```c
int main() {
  char contour = '*';
  char body = '#';
  char background = ' ';
  int height;
  scanf("%d", &height);
  printf("%d\n", (height - 2) * (height - 2));
  repeat(background, height - 1);
  repeat(contour, 1);
  repeat(background, height - 1);
  printf("\n");
  for (int i = 0; i < height - 2; i++) {
    repeat(background, height - 2 - i);
    repeat(contour, 1);
    repeat(body, 2 * i + 1);
    repeat(contour, 1);
    repeat(background, height - 2 - i);
    printf("\n");
  }
  repeat(contour, 2 * height - 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  imul   %esi,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%esi
  mov    $0x20,%edi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%esi
  mov    $0x20,%edi
  call   <repeat@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  test   %esi,%esi
  jle    L11
  mov    $0x0,%ebx
L10:
  sub    %ebx,%esi
  mov    $0x20,%edi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  lea    0x1(%rbx,%rbx,1),%esi
  mov    $0x23,%edi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  sub    %ebx,%esi
  mov    $0x20,%edi
  call   <repeat@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  cmp    %ebx,%esi
  jg     L10
L11:
  lea    -0x1(%rax,%rax,1),%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string
name: parse_data
arguments: label: D18
data_type: string

tool: D4: %d

tool: D18: %d


assistant: ```c
int main() {
  char contour = '*';
  char body = '#';
  char background = ' ';
  int height;
  scanf("%d", &height);
  printf("%d\n", (height - 2) * (height - 2));
  repeat(background, height - 1);
  repeat(contour, 1);
  repeat(background, height - 1);
  printf("\n");
  for (int i = 0; i < height - 2; i++) {
    repeat(background, height - 2 - i);
    repeat(contour, 1);
    repeat(body, 2 * i + 1);
    repeat(contour, 1);
    repeat(background, height - 2 - i);
    printf("\n");
  }
  repeat(contour, 2 * height - 1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D16(%rip),%rdi
  lea    -0x2(%rax),%esi
  xor    %eax,%eax
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    $0x20,%edi
  lea    -0x1(%rax),%esi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x4(%rsp),%eax
  mov    $0x20,%edi
  lea    -0x1(%rax),%esi
  call   <repeat@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  test   %esi,%esi
  jle    L0
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  sub    %ebx,%esi
  mov    $0x20,%edi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  lea    0x1(%rbx,%rbx,1),%esi
  mov    $0x23,%edi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x4(%rsp),%eax
  mov    $0x20,%edi
  lea    -0x2(%rax),%esi
  sub    %ebx,%esi
  add    $0x1,%ebx
  call   <repeat@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  cmp    %ebx,%esi
  jg     L6
L0:
  lea    -0x1(%rax,%rax,1),%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D16
type_infered: string

tool: D5: %d

tool: D16: %d


assistant: ```c
int main() {
  char contour = '*';
  char body = '#';
  char background = ' ';
  int height;
  scanf("%d", &height);
  printf("%d\n", (height - 2) * (height - 2));
  repeat(background, height - 1);
  repeat(contour, 1);
  repeat(background, height - 1);
  printf("\n");
  for (int i = 0; i < height - 2; i++) {
    repeat(background, height - 2 - i);
    repeat(contour, 1);
    repeat(body, 2 * i + 1);
    repeat(contour, 1);
    repeat(background, height - 2 - i);
    printf("\n");
  }
  repeat(contour, 2 * height - 1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D5(%rip),%rdi
  lea    -0x2(%rax),%esi
  xor    %eax,%eax
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    $0x20,%edi
  lea    -0x1(%rax),%esi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x4(%rsp),%eax
  mov    $0x20,%edi
  lea    -0x1(%rax),%esi
  call   <repeat@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  test   %esi,%esi
  jle    L18
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L26:
  sub    %ebx,%esi
  mov    $0x20,%edi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  lea    0x1(%rbx,%rbx,1),%esi
  mov    $0x23,%edi
  call   <repeat@plt>
  mov    $0x1,%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x4(%rsp),%eax
  mov    $0x20,%edi
  lea    -0x2(%rax),%esi
  sub    %ebx,%esi
  add    $0x1,%ebx
  call   <repeat@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  cmp    %ebx,%esi
  jg     L26
L18:
  lea    -0x1(%rax,%rax,1),%esi
  mov    $0x2a,%edi
  call   <repeat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D10: %d

tool: D5: %d


assistant: ```c
int main() {
  char contour = '*';
  char body = '#';
  char background = ' ';
  int height;
  scanf("%d", &height);
  printf("%d\n", (height - 2) * (height - 2));
  repeat(background, height - 1);
  repeat(contour, 1);
  repeat(background, height - 1);
  printf("\n");
  for (int i = 0; i < height - 2; i++) {
    repeat(background, height - 2 - i);
    repeat(contour, 1);
    repeat(body, 2 * i + 1);
    repeat(contour, 1);
    repeat(background, height - 2 - i);
    printf("\n");
  }
  repeat(contour, 2 * height - 1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clip_lf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L14:
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L19
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L14
L19:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *clip_lf(char *string, int size) {
  char *temp_ptr;
  int i = 0;
  temp_ptr = string;
  while ((*temp_ptr != 0) && (*temp_ptr != '\n') && (i < (size - 1))) {
    i++;
    temp_ptr++;
  }
  *temp_ptr = 0;
  return string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clip_lf>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L43
  cmp    $0xa,%dl
  je     L43
  cmp    $0x1,%esi
  jle    L41
  lea    -0x2(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    %rdi,%rdx
L9:
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L6
  cmp    $0xa,%cl
  je     L6
  cmp    %rsi,%rdx
  jne    L9
  mov    %rsi,%rdx
L6:
  movb   $0x0,(%rdx)
  ret
L43:
  mov    %rax,%rdx
  jmp    L6
L41:
  mov    %rdi,%rdx
  jmp    L6
```

assistant: ```c
char *clip_lf(char *string, int size) {
  char *temp_ptr;
  int i = 0;
  temp_ptr = string;
  while ((*temp_ptr != 0) && (*temp_ptr != '\n') && (i < (size - 1))) {
    i++;
    temp_ptr++;
  }
  *temp_ptr = 0;
  return string;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clip_lf>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L29
  cmp    $0xa,%dl
  je     L29
  cmp    $0x1,%esi
  jle    L29
  lea    -0x2(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L26:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  je     L53
  cmp    $0xa,%cl
  je     L53
  cmp    %rsi,%rdx
  jne    L26
L53:
  movb   $0x0,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *clip_lf(char *string, int size) {
  char *temp_ptr;
  int i = 0;
  temp_ptr = string;
  while ((*temp_ptr != 0) && (*temp_ptr != '\n') && (i < (size - 1))) {
    i++;
    temp_ptr++;
  }
  *temp_ptr = 0;
  return string;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clip_lf>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L2
  cmp    $0xa,%dl
  je     L2
  cmp    $0x1,%esi
  jle    L2
  lea    -0x2(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  je     L53
  cmp    $0xa,%cl
  je     L53
  cmp    %rsi,%rdx
  jne    L1
L53:
  movb   $0x0,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *clip_lf(char *string, int size) {
  char *temp_ptr;
  int i = 0;
  temp_ptr = string;
  while ((*temp_ptr != 0) && (*temp_ptr != '\n') && (i < (size - 1))) {
    i++;
    temp_ptr++;
  }
  *temp_ptr = 0;
  return string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GetUSP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x7fff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  test   %rax,%rax
  js     L10
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L8
L10:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L8:
  movsd  D4(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3f]}

assistant: ```c
double GetUSP(int *Ptr, int Scale) {
  unsigned Oct;
  double x;
  Oct = 077777 & *Ptr;
  x = Oct * (1.0 / 0100000) * Scale;
  return (x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GetUSP>:
  endbr64
  mov    (%rdi),%eax
  and    $0x7fff,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D4(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3f]}

assistant: ```c
double GetUSP(int *Ptr, int Scale) {
  unsigned Oct;
  double x;
  Oct = 077777 & *Ptr;
  x = Oct * (1.0 / 0100000) * Scale;
  return (x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GetUSP>:
  endbr64
  mov    (%rdi),%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  and    $0x7fff,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3f]}

assistant: ```c
double GetUSP(int *Ptr, int Scale) {
  unsigned Oct;
  double x;
  Oct = 077777 & *Ptr;
  x = Oct * (1.0 / 0100000) * Scale;
  return (x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetUSP>:
  endbr64
  mov    (%rdi),%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  and    $0x7fff,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D2(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3f]}

assistant: ```c
double GetUSP(int *Ptr, int Scale) {
  unsigned Oct;
  double x;
  Oct = 077777 & *Ptr;
  x = Oct * (1.0 / 0100000) * Scale;
  return (x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_single_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D65(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tcgetattr@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    D31(%rip),%rax
  mov    (%rax),%ecx
  mov    D68(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    D40(%rip),%rax
  mov    (%rax),%ecx
  mov    D65(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  mov    D40(%rip),%rax
  mov    (%rax),%ecx
  mov    D65(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int get_single_char() {
  struct termios oldt, newt;
  int ch;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  return ch;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_single_char>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D18(%rip),%rbx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  mov    D14(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D23(%rip),%r13
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdx
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_single_char() {
  struct termios oldt, newt;
  int ch;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  return ch;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_single_char>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D9(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    (%rbx),%edi
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    D37(%rip),%rbp
  mov    D5(%rip),%rdx
  mov    (%rbx),%edi
  mov    %eax,0x4(%rsp)
  mov    D31(%rip),%rax
  mov    0x0(%rbp),%esi
  mov    (%rax),%eax
  or     (%rdx),%eax
  lea    0x4(%rsp),%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  mov    %r13,%rdx
  mov    %eax,%r12d
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_single_char() {
  struct termios oldt, newt;
  int ch;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  return ch;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_single_char>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D12(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    (%rbx),%edi
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    D19(%rip),%rbp
  mov    D21(%rip),%rdx
  mov    (%rbx),%edi
  mov    %eax,0x4(%rsp)
  mov    D38(%rip),%rax
  mov    0x0(%rbp),%esi
  mov    (%rax),%eax
  or     (%rdx),%eax
  lea    0x4(%rsp),%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  mov    %r13,%rdx
  mov    %eax,%r12d
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_single_char() {
  struct termios oldt, newt;
  int ch;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  return ch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CPLHaveRuntimeAVX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x14(%rbp),%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <__cpuid_count@plt>
  mov    -0x18(%rbp),%eax
  and    $0x8000000,%eax
  test   %eax,%eax
  jne    L62
  mov    $0x0,%eax
  jmp    L43
L62:
  mov    -0x18(%rbp),%eax
  and    $0x10000000,%eax
  test   %eax,%eax
  jne    L9
  mov    $0x0,%eax
  jmp    L43
L9:
  mov    $0x0,%eax
  mov    %eax,%ecx
  xgetbv
  mov    %eax,-0x28(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  and    $0x6,%eax
  cmp    $0x6,%eax
  je     L68
  mov    $0x0,%eax
  jmp    L43
L68:
  mov    $0x1,%eax
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

assistant: ```c
int CPLHaveRuntimeAVX() {
  int cpuinfo[4] = {0, 0, 0, 0};
  unsigned int nXCRLow;
  unsigned int nXCRHigh;
  __cpuid_count(1, 0, cpuinfo[0], cpuinfo[1], cpuinfo[2], cpuinfo[3]);
  if ((cpuinfo[2] & (1 << 27)) == 0) {
    return 0;
  }
  if ((cpuinfo[2] & (1 << 28)) == 0) {
    return 0;
  }
  __asm__("xgetbv" : "=a"(nXCRLow), "=d"(nXCRHigh) : "c"(0));
  if ((nXCRLow & ((1 << 1) | (2 << 1))) != ((1 << 1) | (2 << 1))) {
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CPLHaveRuntimeAVX>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <__cpuid_count@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CPLHaveRuntimeAVX() {
  int cpuinfo[4] = {0, 0, 0, 0};
  unsigned int nXCRLow;
  unsigned int nXCRHigh;
  __cpuid_count(1, 0, cpuinfo[0], cpuinfo[1], cpuinfo[2], cpuinfo[3]);
  if ((cpuinfo[2] & (1 << 27)) == 0) {
    return 0;
  }
  if ((cpuinfo[2] & (1 << 28)) == 0) {
    return 0;
  }
  __asm__("xgetbv" : "=a"(nXCRLow), "=d"(nXCRHigh) : "c"(0));
  if ((nXCRLow & ((1 << 1) | (2 << 1))) != ((1 << 1) | (2 << 1))) {
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CPLHaveRuntimeAVX>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <__cpuid_count@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CPLHaveRuntimeAVX() {
  int cpuinfo[4] = {0, 0, 0, 0};
  unsigned int nXCRLow;
  unsigned int nXCRHigh;
  __cpuid_count(1, 0, cpuinfo[0], cpuinfo[1], cpuinfo[2], cpuinfo[3]);
  if ((cpuinfo[2] & (1 << 27)) == 0) {
    return 0;
  }
  if ((cpuinfo[2] & (1 << 28)) == 0) {
    return 0;
  }
  __asm__("xgetbv" : "=a"(nXCRLow), "=d"(nXCRHigh) : "c"(0));
  if ((nXCRLow & ((1 << 1) | (2 << 1))) != ((1 << 1) | (2 << 1))) {
    return 0;
  }
  return 1;
}
```