ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x58(%rbp)
  jmp    L34
L47:
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%edx
  mov    -0x58(%rbp),%eax
  cltq
  mov    %dl,-0x50(%rbp,%rax,1)
  addl   $0x1,-0x58(%rbp)
L34:
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L47
  mov    -0x58(%rbp),%eax
  cltq
  movb   $0x0,-0x50(%rbp,%rax,1)
  jmp    L58
L88:
  mov    -0x58(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%edx
  mov    -0x54(%rbp),%eax
  cltq
  mov    %dl,-0x40(%rbp,%rax,1)
  addl   $0x1,-0x54(%rbp)
  addl   $0x1,-0x58(%rbp)
L58:
  mov    -0x58(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L88
  movl   $0x0,-0x58(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  movb   $0x0,-0x40(%rbp,%rax,1)
  jmp    L48
L1:
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  jle    L81
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L81
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  mov    -0x58(%rbp),%eax
  cltq
  mov    %dl,-0x40(%rbp,%rax,1)
L81:
  addl   $0x1,-0x58(%rbp)
L48:
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L1
  lea    -0x50(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D11: Entre com um nome e sobrenome: 

tool: D9: 
%s, %s

assistant: ```c
main() {
  char todo[32], nome[16], sobre[16];
  int i, j;
  printf("Entre com um nome e sobrenome: ");
  gets(todo);
  i = j = 0;
  while (todo[i] != ' ') {
    nome[i] = todo[i];
    i++;
  }
  nome[i] = '\0';
  while (todo[i + 1] != '\0') {
    sobre[j] = todo[i + 1];
    j++;
    i++;
  }
  i = 0;
  sobre[j] = '\0';
  while (sobre[i] != '\0') {
    if ((sobre[i] >= 97) && (sobre[i] <= 122))
      sobre[i] = sobre[i] - 32;
    i++;
  }
  printf("\n%s, %s", sobre, nome);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rdi
  call   <gets@plt>
  movzbl 0x20(%rsp),%edx
  cmp    $0x20,%dl
  je     L107
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdi
  lea    0x1f(%rsp),%rsi
L3:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  cmp    $0x20,%dl
  jne    L3
L94:
  movslq %ecx,%rax
  movb   $0x0,(%rsp,%rax,1)
  lea    0x1(%rcx),%eax
  cltq
  movzbl 0x20(%rsp,%rax,1),%edx
  test   %dl,%dl
  je     L12
  mov    $0x1,%eax
  lea    0xf(%rsp),%rdi
  movslq %ecx,%rcx
  lea    0x20(%rsp,%rcx,1),%rsi
L68:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L68
L20:
  movslq %ecx,%rcx
  movb   $0x0,0x10(%rsp,%rcx,1)
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L104
  lea    0x10(%rsp),%rdx
  jmp    L11
L107:
  mov    $0x0,%ecx
  jmp    L94
L12:
  mov    $0x0,%ecx
  jmp    L20
L119:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L104
L11:
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  ja     L119
  sub    $0x20,%eax
  mov    %al,(%rdx)
  jmp    L119
L104:
  mov    %rsp,%rdx
  lea    0x10(%rsp),%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D8: Entre com um nome e sobrenome: 

tool: D6: 
%s, %s

assistant: ```c
main() {
  char todo[32], nome[16], sobre[16];
  int i, j;
  printf("Entre com um nome e sobrenome: ");
  gets(todo);
  i = j = 0;
  while (todo[i] != ' ') {
    nome[i] = todo[i];
    i++;
  }
  nome[i] = '\0';
  while (todo[i + 1] != '\0') {
    sobre[j] = todo[i + 1];
    j++;
    i++;
  }
  i = 0;
  sobre[j] = '\0';
  while (sobre[i] != '\0') {
    if ((sobre[i] >= 97) && (sobre[i] <= 122))
      sobre[i] = sobre[i] - 32;
    i++;
  }
  printf("\n%s, %s", sobre, nome);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D14(%rip),%rdi
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  movzbl 0x20(%rsp),%edx
  cmp    $0x20,%dl
  je     L85
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdi
  lea    0x1f(%rsp),%rsi
  nop
L88:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  cmp    $0x20,%dl
  jne    L88
L4:
  movslq %ecx,%rsi
  add    $0x1,%ecx
  movslq %ecx,%rcx
  movb   $0x0,(%rsp,%rsi,1)
  movzbl 0x20(%rsp,%rcx,1),%edx
  test   %dl,%dl
  je     L93
  mov    $0x1,%eax
  lea    0xf(%rsp),%rdi
  lea    (%rbx,%rsi,1),%rcx
  nopw   0x0(%rax,%rax,1)
L87:
  mov    %dl,(%rdi,%rax,1)
  movslq %eax,%rsi
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  test   %dl,%dl
  jne    L87
L11:
  movb   $0x0,0x10(%rsp,%rsi,1)
  movzbl 0x10(%rsp),%eax
  lea    0x10(%rsp),%rsi
  mov    %rsi,%rdx
  test   %al,%al
  je     L77
  nopl   0x0(%rax,%rax,1)
L21:
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  ja     L13
  sub    $0x20,%eax
  mov    %al,(%rdx)
L13:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L21
L77:
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L85:
  xor    %ecx,%ecx
  jmp    L4
L93:
  xor    %esi,%esi
  jmp    L11
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type_infered: string
name: disassemble_data
arguments: data_label: D15
type_infered: string

tool: D14: Entre com um nome e sobrenome: 

tool: D15: 
%s, %s

assistant: ```c
main() {
  char todo[32], nome[16], sobre[16];
  int i, j;
  printf("Entre com um nome e sobrenome: ");
  gets(todo);
  i = j = 0;
  while (todo[i] != ' ') {
    nome[i] = todo[i];
    i++;
  }
  nome[i] = '\0';
  while (todo[i + 1] != '\0') {
    sobre[j] = todo[i + 1];
    j++;
    i++;
  }
  i = 0;
  sobre[j] = '\0';
  while (sobre[i] != '\0') {
    if ((sobre[i] >= 97) && (sobre[i] <= 122))
      sobre[i] = sobre[i] - 32;
    i++;
  }
  printf("\n%s, %s", sobre, nome);
}
```
user: What is the c source code of the assembly code below?

```asm
<wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L34:
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L26:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x3e0f83e1,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L26
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wait(int t) {
  int i = 0;
  int j = 0;
  int z = 0;
  for (i = 0; i < t; i++) {
    for (j = 0; j < t; j++) {
      z = i / 33;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wait>:
  endbr64
  mov    $0x0,%ecx
  test   %edi,%edi
  jle    L35
L24:
  mov    $0x0,%eax
L11:
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L11
  lea    0x1(%rcx),%eax
  cmp    %edx,%ecx
  je     L25
  mov    %eax,%ecx
  jmp    L24
L35:
  ret
L25:
  ret
```

assistant: ```c
void wait(int t) {
  int i = 0;
  int j = 0;
  int z = 0;
  for (i = 0; i < t; i++) {
    for (j = 0; j < t; j++) {
      z = i / 33;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wait>:
  endbr64
  ret
```

assistant: ```c
void wait(int t) {
  int i = 0;
  int j = 0;
  int z = 0;
  for (i = 0; i < t; i++) {
    for (j = 0; j < t; j++) {
      z = i / 33;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wait>:
  endbr64
  ret
```

assistant: ```c
void wait(int t) {
  int i = 0;
  int j = 0;
  int z = 0;
  for (i = 0; i < t; i++) {
    for (j = 0; j < t; j++) {
      z = i / 33;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kdf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x24(%rbp)
  mov    -0x40(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x2c,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L14
L8:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <__be32_to_cpu@plt>
  mov    %eax,-0x28(%rbp)
  lea    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x24,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <__be32_to_cpu@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x28(%rax),%rcx
  lea    -0x28(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%r8
  mov    $0x2c,%ecx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <hmac_sha256@plt>
  addl   $0x20,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L14:
  cmpl   $0x3,-0x24(%rbp)
  jle    L8
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: Wi-Fi Easy and Secure Key Derivation

assistant: ```c
void kdf(unsigned char *key, size_t key_len, unsigned char *res) {
  uint32_t i = 1;
  uint32_t kdk_len = key_len * 8;
  int j = 0;
  char *salt = "\x57\x69\x2d\x46\x69\x20\x45\x61\x73\x79\x20\x61\x6e\x64\x20\x53\x65\x63\x75\x72\x65\x20\x4b\x65\x79\x20\x44\x65\x72\x69\x76\x61\x74\x69\x6f\x6e";
  unsigned char *buffer = malloc(36 + 4 * 2);
  for (i = 1; i < 4; i++) {
    uint32_t be = __be32_to_cpu(i);
    memcpy(buffer, &be, 4);
    memcpy(buffer + 4, salt, 36);
    be = __be32_to_cpu(kdk_len);
    memcpy(buffer + 4 + 36, &be, 4);
    hmac_sha256(key, 32, buffer, 36 + 4 * 2, res + j);
    j += 32;
  }
  free(buffer);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kdf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rsi,8),%r14d
  mov    $0x2c,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x1,%r12d
  lea    D1(%rip),%r15
L19:
  mov    %r12d,%edi
  call   <__be32_to_cpu@plt>
  mov    %eax,0x14(%rsp)
  lea    0x14(%rsp),%r13
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  lea    0x4(%rbx),%rdi
  mov    $0x24,%edx
  mov    %r15,%rsi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    %r14d,%edi
  call   <__be32_to_cpu@plt>
  mov    %eax,0x14(%rsp)
  lea    0x28(%rbx),%rdi
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    %rbp,%r8
  mov    $0x2c,%ecx
  mov    %rbx,%rdx
  mov    $0x20,%esi
  mov    0x8(%rsp),%rdi
  call   <hmac_sha256@plt>
  add    $0x1,%r12d
  add    $0x20,%rbp
  cmp    $0x4,%r12d
  jne    L19
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: Wi-Fi Easy and Secure Key Derivation

assistant: ```c
void kdf(unsigned char *key, size_t key_len, unsigned char *res) {
  uint32_t i = 1;
  uint32_t kdk_len = key_len * 8;
  int j = 0;
  char *salt = "\x57\x69\x2d\x46\x69\x20\x45\x61\x73\x79\x20\x61\x6e\x64\x20\x53\x65\x63\x75\x72\x65\x20\x4b\x65\x79\x20\x44\x65\x72\x69\x76\x61\x74\x69\x6f\x6e";
  unsigned char *buffer = malloc(36 + 4 * 2);
  for (i = 1; i < 4; i++) {
    uint32_t be = __be32_to_cpu(i);
    memcpy(buffer, &be, 4);
    memcpy(buffer + 4, salt, 36);
    be = __be32_to_cpu(kdk_len);
    memcpy(buffer + 4 + 36, &be, 4);
    hmac_sha256(key, 32, buffer, 36 + 4 * 2, res + j);
    j += 32;
  }
  free(buffer);
}
```
user: What is the c source code of the assembly code below?

```asm
<kdf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x2c,%edi
  lea    0x14(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rsi,8),%eax
  mov    %eax,0x4(%rsp)
  call   <malloc@plt>
  mov    $0x1,%r9d
  mov    %rax,%rbp
  lea    0x4(%rax),%r15
  lea    0x28(%rax),%r14
L8:
  mov    %r9d,%edi
  mov    %r9d,(%rsp)
  call   <__be32_to_cpu@plt>
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x14(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    $0x24,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <__be32_to_cpu@plt>
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    %eax,0x14(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12,%r8
  mov    %rbp,%rdx
  mov    $0x2c,%ecx
  mov    $0x20,%esi
  add    $0x20,%r12
  call   <hmac_sha256@plt>
  mov    (%rsp),%r9d
  add    $0x1,%r9d
  cmp    $0x4,%r9d
  jne    L8
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D9: Wi-Fi Easy and Secure Key Derivation

assistant: ```c
void kdf(unsigned char *key, size_t key_len, unsigned char *res) {
  uint32_t i = 1;
  uint32_t kdk_len = key_len * 8;
  int j = 0;
  char *salt = "\x57\x69\x2d\x46\x69\x20\x45\x61\x73\x79\x20\x61\x6e\x64\x20\x53\x65\x63\x75\x72\x65\x20\x4b\x65\x79\x20\x44\x65\x72\x69\x76\x61\x74\x69\x6f\x6e";
  unsigned char *buffer = malloc(36 + 4 * 2);
  for (i = 1; i < 4; i++) {
    uint32_t be = __be32_to_cpu(i);
    memcpy(buffer, &be, 4);
    memcpy(buffer + 4, salt, 36);
    be = __be32_to_cpu(kdk_len);
    memcpy(buffer + 4 + 36, &be, 4);
    hmac_sha256(key, 32, buffer, 36 + 4 * 2, res + j);
    j += 32;
  }
  free(buffer);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kdf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x2c,%edi
  lea    0x14(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rsi,8),%eax
  mov    %eax,0x4(%rsp)
  call   <malloc@plt>
  mov    $0x1,%r9d
  mov    %rax,%rbp
  lea    0x4(%rax),%r15
  lea    0x28(%rax),%r14
L7:
  mov    %r9d,%edi
  mov    %r9d,(%rsp)
  call   <__be32_to_cpu@plt>
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x14(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    $0x24,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <__be32_to_cpu@plt>
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    %eax,0x14(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12,%r8
  mov    %rbp,%rdx
  mov    $0x2c,%ecx
  mov    $0x20,%esi
  add    $0x20,%r12
  call   <hmac_sha256@plt>
  mov    (%rsp),%r9d
  add    $0x1,%r9d
  cmp    $0x4,%r9d
  jne    L7
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: Wi-Fi Easy and Secure Key Derivation

assistant: ```c
void kdf(unsigned char *key, size_t key_len, unsigned char *res) {
  uint32_t i = 1;
  uint32_t kdk_len = key_len * 8;
  int j = 0;
  char *salt = "\x57\x69\x2d\x46\x69\x20\x45\x61\x73\x79\x20\x61\x6e\x64\x20\x53\x65\x63\x75\x72\x65\x20\x4b\x65\x79\x20\x44\x65\x72\x69\x76\x61\x74\x69\x6f\x6e";
  unsigned char *buffer = malloc(36 + 4 * 2);
  for (i = 1; i < 4; i++) {
    uint32_t be = __be32_to_cpu(i);
    memcpy(buffer, &be, 4);
    memcpy(buffer + 4, salt, 36);
    be = __be32_to_cpu(kdk_len);
    memcpy(buffer + 4 + 36, &be, 4);
    hmac_sha256(key, 32, buffer, 36 + 4 * 2, res + j);
    j += 32;
  }
  free(buffer);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<listxattr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fsfr_base_listxattr@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L13
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fsfr_filter_xattr@plt>
  jmp    L0
L13:
  mov    -0x4(%rbp),%eax
L0:
  leave
  ret
```

assistant: ```c
ssize_t listxattr(const char *path, char *list, size_t size) {
  int rtn = fsfr_base_listxattr(path, list, size);
  if (rtn > 0)
    return fsfr_filter_xattr(list, rtn);
  return rtn;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<listxattr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <fsfr_base_listxattr@plt>
  test   %eax,%eax
  jg     L13
L2:
  pop    %rbx
  ret
L13:
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <fsfr_filter_xattr@plt>
  jmp    L2
```

assistant: ```c
ssize_t listxattr(const char *path, char *list, size_t size) {
  int rtn = fsfr_base_listxattr(path, list, size);
  if (rtn > 0)
    return fsfr_filter_xattr(list, rtn);
  return rtn;
}
```
user: What is the c source code of the assembly code below?

```asm
<listxattr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <fsfr_base_listxattr@plt>
  test   %eax,%eax
  jg     L4
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  jmp    1060 <fsfr_filter_xattr@plt>
```

assistant: ```c
ssize_t listxattr(const char *path, char *list, size_t size) {
  int rtn = fsfr_base_listxattr(path, list, size);
  if (rtn > 0)
    return fsfr_filter_xattr(list, rtn);
  return rtn;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<listxattr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <fsfr_base_listxattr@plt>
  test   %eax,%eax
  jg     L9
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  jmp    1060 <fsfr_filter_xattr@plt>
```

assistant: ```c
ssize_t listxattr(const char *path, char *list, size_t size) {
  int rtn = fsfr_base_listxattr(path, list, size);
  if (rtn > 0)
    return fsfr_filter_xattr(list, rtn);
  return rtn;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec_isempty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vec_len@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int vec_isempty(const struct vector *v) {
  assert(v != NULL);
  return (vec_len(v) == 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec_isempty>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <vec_len@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int vec_isempty(const struct vector *v) {
  assert(v != NULL);
  return (vec_len(v) == 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vec_isempty>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <vec_len@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int vec_isempty(const struct vector *v) {
  assert(v != NULL);
  return (vec_len(v) == 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vec_isempty>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <vec_len@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int vec_isempty(const struct vector *v) {
  assert(v != NULL);
  return (vec_len(v) == 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<free_string_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L2
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L13:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addq   $0x8,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L34
L2:
  nop
L34:
  leave
  ret
```

assistant: ```c
void free_string_array(char **arr) {
  if (!arr)
    return;
  for (char **current = arr; *current; current++) {
    free(*current);
  }
  free(arr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_string_array>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L20
  mov    %rbp,%rbx
L23:
  call   <free@plt>
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L23
L20:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  ret
```

assistant: ```c
void free_string_array(char **arr) {
  if (!arr)
    return;
  for (char **current = arr; *current; current++) {
    free(*current);
  }
  free(arr);
}
```