ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edi,%r15d
  mov    $0x4,%edi
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <alloca@plt>
  mov    -0x44(%rbp),%esi
  mov    %r15d,(%r12)
  mov    %esi,(%rbx)
  mov    %r14d,0x0(%r13)
  movl   $0x0,(%rax)
  mov    (%r12),%ecx
  cmp    %ecx,(%rbx)
  jne    L68
  nopl   0x0(%rax)
L41:
  mov    0x0(%r13),%esi
  cmp    %ecx,%esi
  jge    L17
  mov    (%rbx),%edx
  cmp    %edx,%esi
  jge    L26
  xchg   %ax,%ax
L23:
  subl   $0x1,(%r12)
  subl   $0x1,(%rbx)
  addl   $0x1,(%rax)
  mov    (%rbx),%edx
  cmp    0x0(%r13),%edx
  jg     L23
  mov    (%r12),%ecx
L26:
  cmp    %edx,%ecx
  je     L41
L17:
  mov    (%rax),%eax
L46:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L68:
  xor    %eax,%eax
  jmp    L46
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_fun(int x, int y, int z) {
  int *x_ref = alloca(sizeof(int));
  int *y_ref = alloca(sizeof(int));
  int *z_ref = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *x_ref = x;
  *y_ref = y;
  *z_ref = z;
  *c = 0;
  while ((*x_ref == *y_ref) && (*x_ref > *z_ref)) {
    while (*y_ref > *z_ref) {
      *x_ref = *x_ref - 1;
      *y_ref = *y_ref - 1;
      *c = *c + 1;
    }
  }
  return *c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    $0x4,%edi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <alloca@plt>
  mov    -0x44(%rbp),%ecx
  mov    %ecx,(%r12)
  mov    %r15d,(%rbx)
  mov    %r14d,0x0(%r13)
  movl   $0x0,(%rax)
  mov    (%r12),%esi
  mov    (%rbx),%edx
  cmp    %esi,%edx
  jne    L34
  mov    0x0(%r13),%ecx
L65:
  cmp    %ecx,%esi
  jle    L70
  cmp    %ecx,%edx
  jle    L64
  sub    $0x1,%esi
  mov    %esi,(%r12)
  jmp    L26
  nopl   0x0(%rax)
L50:
  subl   $0x1,(%r12)
L26:
  subl   $0x1,(%rbx)
  addl   $0x1,(%rax)
  mov    (%rbx),%edx
  mov    0x0(%r13),%ecx
  cmp    %ecx,%edx
  jg     L50
  mov    (%r12),%esi
L64:
  cmp    %edx,%esi
  je     L65
L70:
  mov    (%rax),%eax
L40:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L34:
  xor    %eax,%eax
  jmp    L40
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_fun(int x, int y, int z) {
  int *x_ref = alloca(sizeof(int));
  int *y_ref = alloca(sizeof(int));
  int *z_ref = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *x_ref = x;
  *y_ref = y;
  *z_ref = z;
  *c = 0;
  while ((*x_ref == *y_ref) && (*x_ref > *z_ref)) {
    while (*y_ref > *z_ref) {
      *x_ref = *x_ref - 1;
      *y_ref = *y_ref - 1;
      *c = *c + 1;
    }
  }
  return *c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3f4(%rbp)
L69:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x3f0(%rbp),%eax
  cmp    $0x53,%al
  jne    L41
  movzbl -0x3ef(%rbp),%eax
  cmp    $0x54,%al
  jne    L41
  movzbl -0x3ee(%rbp),%eax
  cmp    $0x4f,%al
  jne    L41
  movzbl -0x3ed(%rbp),%eax
  cmp    $0x50,%al
  je     L61
L41:
  movl   $0x0,-0x3f8(%rbp)
  jmp    L91
L23:
  mov    -0x3f8(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  jle    L80
  mov    -0x3f8(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L80
  mov    -0x3f8(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  mov    -0x3f8(%rbp),%eax
  cltq
  mov    %dl,-0x3f0(%rbp,%rax,1)
L80:
  addl   $0x1,-0x3f8(%rbp)
L91:
  cmpl   $0x63,-0x3f8(%rbp)
  jle    L23
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L69
L61:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
datatype: string

tool: D14: 
%s

assistant: ```c
int main() {
  char n[1000];
  int i = 0;
  do {
    scanf("\n%s", n);
    if (n[0] == 'S' && n[1] == 'T' && n[2] == 'O' && n[3] == 'P')
      break;
    else {
      for (int f = 0; f < 100; f++) {
        if (n[f] >= 'a' && n[f] <= 'z') {
          n[f] -= 32;
        }
      }
      printf("\n%s", n);
    }
  } while (1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rbx
  jmp    L91
L45:
  cmpb   $0x54,0x1(%rsp)
  jne    L23
  cmpb   $0x4f,0x2(%rsp)
  jne    L23
  cmpb   $0x50,0x3(%rsp)
  jne    L23
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L25:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L48
L59:
  movzbl (%rax),%edx
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L25
  sub    $0x20,%edx
  mov    %dl,(%rax)
  jmp    L25
L48:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
L91:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpb   $0x53,(%rsp)
  je     L45
L23:
  mov    %rsp,%rax
  lea    0x64(%rsp),%rsi
  jmp    L59
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6: 
%s

assistant: ```c
int main() {
  char n[1000];
  int i = 0;
  do {
    scanf("\n%s", n);
    if (n[0] == 'S' && n[1] == 'T' && n[2] == 'O' && n[3] == 'P')
      break;
    else {
      for (int f = 0; f < 100; f++) {
        if (n[f] >= 'a' && n[f] <= 'z') {
          n[f] -= 32;
        }
      }
      printf("\n%s", n);
    }
  } while (1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x64(%rsp),%rbx
  nopl   0x0(%rax)
L87:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl (%rsp),%edx
  cmp    $0x53,%dl
  je     L44
L39:
  mov    %r12,%rax
  jmp    L88
  nopl   0x0(%rax)
L15:
  movzbl (%rax),%edx
L88:
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L66
  sub    $0x20,%edx
  mov    %dl,(%rax)
L66:
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L15
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L87
L44:
  cmpb   $0x54,0x1(%rsp)
  jne    L39
  cmpb   $0x4f,0x2(%rsp)
  jne    L39
  cmpb   $0x50,0x3(%rsp)
  jne    L39
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: 
%s

assistant: ```c
int main() {
  char n[1000];
  int i = 0;
  do {
    scanf("\n%s", n);
    if (n[0] == 'S' && n[1] == 'T' && n[2] == 'O' && n[3] == 'P')
      break;
    else {
      for (int f = 0; f < 100; f++) {
        if (n[f] >= 'a' && n[f] <= 'z') {
          n[f] -= 32;
        }
      }
      printf("\n%s", n);
    }
  } while (1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x64(%rsp),%rbx
  nopl   0x0(%rax)
L74:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpb   $0x53,(%rsp)
  je     L42
L11:
  mov    %r12,%rax
  nopl   0x0(%rax)
L2:
  movzbl (%rax),%edx
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L46
  sub    $0x20,%edx
  mov    %dl,(%rax)
L46:
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L2
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L74
L42:
  cmpb   $0x54,0x1(%rsp)
  jne    L11
  cmpb   $0x4f,0x2(%rsp)
  jne    L11
  cmpb   $0x50,0x3(%rsp)
  jne    L11
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: 
%s

assistant: ```c
int main() {
  char n[1000];
  int i = 0;
  do {
    scanf("\n%s", n);
    if (n[0] == 'S' && n[1] == 'T' && n[2] == 'O' && n[3] == 'P')
      break;
    else {
      for (int f = 0; f < 100; f++) {
        if (n[f] >= 'a' && n[f] <= 'z') {
          n[f] -= 32;
        }
      }
      printf("\n%s", n);
    }
  } while (1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mm_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void mm_destroy(int n, double **m) {
  int i;
  for (i = 0; i < n; ++i)
    free(m[i]);
  free(m);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mm_destroy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  test   %edi,%edi
  jle    L18
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
L12:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L12
L18:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mm_destroy(int n, double **m) {
  int i;
  for (i = 0; i < n; ++i)
    free(m[i]);
  free(m);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mm_destroy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L15
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x8(%rsi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L12
L15:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void mm_destroy(int n, double **m) {
  int i;
  for (i = 0; i < n; ++i)
    free(m[i]);
  free(m);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mm_destroy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L14
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x8(%rsi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L5
L14:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void mm_destroy(int n, double **m) {
  int i;
  for (i = 0; i < n; ++i)
    free(m[i]);
  free(m);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stampa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void stampa(const char *dato, int len) {
  int i;
  for (i = 0; i < len; ++i) {
    printf("%c", dato[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stampa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L7:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L7
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void stampa(const char *dato, int len) {
  int i;
  for (i = 0; i < len; ++i) {
    printf("%c", dato[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<stampa>:
  endbr64
  test   %esi,%esi
  jle    L8
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax)
L8:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void stampa(const char *dato, int len) {
  int i;
  for (i = 0; i < len; ++i) {
    printf("%c", dato[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stampa>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L19:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax)
L9:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void stampa(const char *dato, int len) {
  int i;
  for (i = 0; i < len; ++i) {
    printf("%c", dato[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<relabel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    0x18(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x10(%rbp)
  mov    0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L42
L20:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,0x10(%rbp)
  jne    L27
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L35
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <u_min@plt>
  mov    %eax,-0x10(%rbp)
  jmp    L35
L27:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L35
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <u_min@plt>
  mov    %eax,-0x10(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
L42:
  mov    -0xc(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jne    L20
  mov    0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void relabel(int *iv, int *ie, int *oe, int *wgt, int *flow, int *H, int u, int n, int *next) {
  int min_height = 2 * n;
  int v = next[u];
  while (v != u) {
    if (ie[v] == u) {
      int j = ie[v];
      if (wgt[j] > flow[j]) {
        min_height = u_min(min_height, H[v]);
      }
    } else {
      int j = oe[v];
      if (flow[j] > 0) {
        min_height = u_min(min_height, H[v]);
      }
    }
    v = next[v];
  }
  H[u] = min_height + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<relabel>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%r12
  mov    %rdx,(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %r8,%r13
  mov    %r9,%r15
  mov    0x60(%rsp),%ebp
  mov    0x70(%rsp),%r14
  mov    0x68(%rsp),%eax
  lea    (%rax,%rax,1),%edi
  movslq %ebp,%rax
  mov    %rax,0x18(%rsp)
  lea    0x0(,%rax,4),%rdx
  mov    %rdx,0x8(%rsp)
  mov    (%r14,%rax,4),%ebx
  cmp    %ebx,%ebp
  jne    L55
L41:
  add    $0x1,%edi
  mov    0x18(%rsp),%rax
  mov    %edi,(%r15,%rax,4)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rax
  mov    0x0(%r13,%rax,1),%ecx
  cmp    %ecx,(%rdx,%rax,1)
  jg     L59
L50:
  mov    (%r14,%rbx,4),%ebx
  cmp    %ebx,%ebp
  je     L41
L55:
  movslq %ebx,%rbx
  cmp    %ebp,(%r12,%rbx,4)
  je     L31
  mov    (%rsp),%rax
  movslq (%rax,%rbx,4),%rax
  cmpl   $0x0,0x0(%r13,%rax,4)
  jle    L50
  mov    (%r15,%rbx,4),%esi
  call   <u_min@plt>
  mov    %eax,%edi
  jmp    L50
L59:
  mov    (%r15,%rbx,4),%esi
  call   <u_min@plt>
  mov    %eax,%edi
  jmp    L50
```

assistant: ```c
void relabel(int *iv, int *ie, int *oe, int *wgt, int *flow, int *H, int u, int n, int *next) {
  int min_height = 2 * n;
  int v = next[u];
  while (v != u) {
    if (ie[v] == u) {
      int j = ie[v];
      if (wgt[j] > flow[j]) {
        min_height = u_min(min_height, H[v]);
      }
    } else {
      int j = oe[v];
      if (flow[j] > 0) {
        min_height = u_min(min_height, H[v]);
      }
    }
    v = next[v];
  }
  H[u] = min_height + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<relabel>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x68(%rsp),%eax
  mov    0x60(%rsp),%ebp
  mov    %rcx,0x10(%rsp)
  mov    0x70(%rsp),%r13
  lea    (%rax,%rax,1),%edi
  movslq %ebp,%rax
  movslq 0x0(%r13,%rax,4),%rbx
  mov    %rax,0x18(%rsp)
  cmp    %ebx,%ebp
  je     L38
  mov    %r8,%r15
  mov    %rsi,%r14
  lea    0x0(,%rax,4),%r8
  jmp    L30
  nop
L61:
  movslq (%rdx,%rbx,4),%rax
  mov    (%r15,%rax,4),%eax
  test   %eax,%eax
  jle    L47
  mov    (%r12,%rbx,4),%esi
  mov    %rdx,0x8(%rsp)
  mov    %r8,(%rsp)
  call   <u_min@plt>
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%r8
  mov    %eax,%edi
L47:
  movslq 0x0(%r13,%rbx,4),%rbx
  cmp    %ebx,%ebp
  je     L38
L30:
  cmp    %ebp,(%r14,%rbx,4)
  jne    L61
  mov    0x10(%rsp),%rax
  mov    (%r15,%r8,1),%ecx
  cmp    %ecx,(%rax,%r8,1)
  jle    L47
  mov    (%r12,%rbx,4),%esi
  mov    %rdx,0x8(%rsp)
  mov    %r8,(%rsp)
  call   <u_min@plt>
  movslq 0x0(%r13,%rbx,4),%rbx
  mov    (%rsp),%r8
  mov    0x8(%rsp),%rdx
  mov    %eax,%edi
  cmp    %ebx,%ebp
  jne    L30
L38:
  mov    0x18(%rsp),%rax
  add    $0x1,%edi
  mov    %edi,(%r12,%rax,4)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void relabel(int *iv, int *ie, int *oe, int *wgt, int *flow, int *H, int u, int n, int *next) {
  int min_height = 2 * n;
  int v = next[u];
  while (v != u) {
    if (ie[v] == u) {
      int j = ie[v];
      if (wgt[j] > flow[j]) {
        min_height = u_min(min_height, H[v]);
      }
    } else {
      int j = oe[v];
      if (flow[j] > 0) {
        min_height = u_min(min_height, H[v]);
      }
    }
    v = next[v];
  }
  H[u] = min_height + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<relabel>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x68(%rsp),%eax
  mov    0x60(%rsp),%ebp
  mov    %rcx,0x10(%rsp)
  mov    0x70(%rsp),%r13
  lea    (%rax,%rax,1),%edi
  movslq %ebp,%rax
  movslq 0x0(%r13,%rax,4),%rbx
  mov    %rax,0x18(%rsp)
  cmp    %ebx,%ebp
  je     L5
  mov    %r8,%r15
  mov    %rsi,%r14
  lea    0x0(,%rax,4),%r8
  jmp    L62
  nop
L13:
  movslq (%rdx,%rbx,4),%rax
  mov    (%r15,%rax,4),%eax
  test   %eax,%eax
  jle    L9
  mov    (%r12,%rbx,4),%esi
  mov    %rdx,0x8(%rsp)
  mov    %r8,(%rsp)
  call   <u_min@plt>
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%r8
  mov    %eax,%edi
L9:
  movslq 0x0(%r13,%rbx,4),%rbx
  cmp    %ebx,%ebp
  je     L5
L62:
  cmp    %ebp,(%r14,%rbx,4)
  jne    L13
  mov    0x10(%rsp),%rax
  mov    (%r15,%r8,1),%ecx
  cmp    %ecx,(%rax,%r8,1)
  jle    L9
  mov    (%r12,%rbx,4),%esi
  mov    %rdx,0x8(%rsp)
  mov    %r8,(%rsp)
  call   <u_min@plt>
  movslq 0x0(%r13,%rbx,4),%rbx
  mov    (%rsp),%r8
  mov    0x8(%rsp),%rdx
  mov    %eax,%edi
  cmp    %ebx,%ebp
  jne    L62
L5:
  mov    0x18(%rsp),%rax
  add    $0x1,%edi
  mov    %edi,(%r12,%rax,4)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void relabel(int *iv, int *ie, int *oe, int *wgt, int *flow, int *H, int u, int n, int *next) {
  int min_height = 2 * n;
  int v = next[u];
  while (v != u) {
    if (ie[v] == u) {
      int j = ie[v];
      if (wgt[j] > flow[j]) {
        min_height = u_min(min_height, H[v]);
      }
    } else {
      int j = oe[v];
      if (flow[j] > 0) {
        min_height = u_min(min_height, H[v]);
      }
    }
    v = next[v];
  }
  H[u] = min_height + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L7:
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L15:
  movl   $0xffffffef,-0x4(%rbp)
  jmp    L29
L45:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <test@plt>
  mov    -0xc(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <test@plt>
  addl   $0x1,-0x4(%rbp)
L29:
  cmpl   $0x11,-0x4(%rbp)
  jle    L45
  addl   $0x1,-0x8(%rbp)
L28:
  cmpl   $0x9,-0x8(%rbp)
  jle    L15
  addl   $0x1,-0xc(%rbp)
L37:
  cmpl   $0x9,-0xc(%rbp)
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  for (int n = 0; n < 10; ++n)
    for (int m = 0; m < 10; ++m)
      for (int offset = -17; offset <= 17; ++offset) {
        test(n, m, offset);
        test(n, m, offset + n * (257 - 1));
      }
  return 0;
}
```