ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<printnum>:
  endbr64
  push   %r14
  mov    %edi,%esi
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  cmp    $0x8,%ebp
  jle    L22
L8:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L22:
  lea    0x1(%rbp),%r13d
  mov    %r12,%rdi
  mov    %r13d,%esi
  call   <printf@plt>
  cmp    $0x9,%r13d
  jne    L20
L55:
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L20:
  lea    0x2(%rbp),%r14d
  mov    %r12,%rdi
  mov    %r14d,%esi
  call   <printf@plt>
  cmp    $0x9,%r14d
  jne    L2
L59:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L2:
  lea    0x3(%rbp),%edi
  call   <printnum>
  jmp    L59
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: %d

assistant: ```c
void printnum(int begin) {
  printf("%d", begin);
  if (begin < 9) {
    printnum(begin + 1);
  }
  printf("%d", begin);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L15
L13:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L7
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L13
L7:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L26
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L26:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strip(ptr) char **ptr;
{
  while (('0' <= **ptr) && (**ptr <= '9')) {
    (*ptr)++;
  }
  if (**ptr == '*') {
    (*ptr)++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strip>:
  endbr64
  mov    (%rdi),%rsi
  movzbl (%rsi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L20
  lea    0x1(%rsi),%rax
L19:
  mov    %rax,%rsi
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L19
L20:
  cmp    $0x2a,%dl
  je     L21
L3:
  ret
L21:
  add    $0x1,%rsi
  mov    %rsi,(%rdi)
  jmp    L3
```

assistant: ```c
void strip(ptr) char **ptr;
{
  while (('0' <= **ptr) && (**ptr <= '9')) {
    (*ptr)++;
  }
  if (**ptr == '*') {
    (*ptr)++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strip>:
  endbr64
  mov    (%rdi),%rsi
  movzbl (%rsi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L18
  lea    0x1(%rsi),%rax
  nopl   (%rax)
L7:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  mov    %rax,%rsi
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L7
L18:
  cmp    $0x2a,%dl
  je     L5
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void strip(ptr) char **ptr;
{
  while (('0' <= **ptr) && (**ptr <= '9')) {
    (*ptr)++;
  }
  if (**ptr == '*') {
    (*ptr)++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strip>:
  endbr64
  mov    (%rdi),%rsi
  movzbl (%rsi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L3
  lea    0x1(%rsi),%rax
  nopl   (%rax)
L11:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  mov    %rax,%rsi
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L11
L3:
  cmp    $0x2a,%dl
  je     L16
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void strip(ptr) char **ptr;
{
  while (('0' <= **ptr) && (**ptr <= '9')) {
    (*ptr)++;
  }
  if (**ptr == '*') {
    (*ptr)++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L2
L32:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L19
L24:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L19:
  cmpl   $0x2,-0x14(%rbp)
  jle    L24
  addl   $0x1,-0x18(%rbp)
L2:
  cmpl   $0x6,-0x18(%rbp)
  jle    L32
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D28
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D13: dsmean

tool: D28: # c::%s:len=%d


tool: D12: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsmean", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D7(%rip),%r15
  jmp    L27
L19:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L38
L27:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L25:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L25
  jmp    L19
L38:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string
name: retrieve_data
arguments: label: D4
type_infered: string

tool: D7: dsmean

tool: D29: # c::%s:len=%d


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsmean", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D3(%rip),%r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L3:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L5:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L5
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L3
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D24
type_infered: string

tool: D3: dsmean

tool: D1: # c::%s:len=%d


tool: D24: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsmean", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D29(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L2:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L4:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L4
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L2
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D29
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D29: dsmean

tool: D15: # c::%s:len=%d


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsmean", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  D33(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D33
type_infered: f64
name: retrieve_data
arguments: data_label: D62
type_infered: string
name: retrieve_data
arguments: data_label: D64
type_infered: string
name: retrieve_data
arguments: data_label: D85
type_infered: string
name: retrieve_data
arguments: data_label: D59
type_infered: string
name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D66
type_infered: string
name: retrieve_data
arguments: data_label: D84
type_infered: string
name: retrieve_data
arguments: data_label: D65
type_infered: string

tool: D33: 3852.99

tool: D62: %f


tool: D64: %e


tool: D85: %4.2f


tool: D59: %3.1f


tool: D13: %10.3f


tool: D66: %10.3E


tool: D84: %+4.2f


tool: D65: %010.2f


assistant: ```c
int main() {
  const double RENT = 3852.99;
  printf("%f\n", RENT);
  printf("%e\n", RENT);
  printf("%4.2f\n", RENT);
  printf("%3.1f\n", RENT);
  printf("%10.3f\n", RENT);
  printf("%10.3E\n", RENT);
  printf("%+4.2f\n", RENT);
  printf("%010.2f\n", RENT);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D58(%rip),%rax
  movq   %rax,%xmm0
  lea    D155(%rip),%rdi
  call   <printf@plt>
  mov    D58(%rip),%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    D58(%rip),%rax
  movq   %rax,%xmm0
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    D58(%rip),%rax
  movq   %rax,%xmm0
  lea    D90(%rip),%rdi
  call   <printf@plt>
  mov    D58(%rip),%rax
  movq   %rax,%xmm0
  lea    D156(%rip),%rdi
  call   <printf@plt>
  mov    D58(%rip),%rax
  movq   %rax,%xmm0
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    D58(%rip),%rax
  movq   %rax,%xmm0
  lea    D110(%rip),%rdi
  call   <printf@plt>
  mov    D58(%rip),%rax
  movq   %rax,%xmm0
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D58
type: f64
name: disassemble_data
arguments: data_label: D155
type: string
name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D22
type: string
name: disassemble_data
arguments: data_label: D90
type: string
name: disassemble_data
arguments: data_label: D156
type: string
name: disassemble_data
arguments: data_label: D37
type: string
name: disassemble_data
arguments: data_label: D110
type: string
name: disassemble_data
arguments: data_label: D14
type: string

tool: D58: 3852.99

tool: D155: %f


tool: D19: %e


tool: D22: %4.2f


tool: D90: %3.1f


tool: D156: %10.3f


tool: D37: %10.3E


tool: D110: %+4.2f


tool: D14: %010.2f


assistant: ```c
int main() {
  const double RENT = 3852.99;
  printf("%f\n", RENT);
  printf("%e\n", RENT);
  printf("%4.2f\n", RENT);
  printf("%3.1f\n", RENT);
  printf("%10.3f\n", RENT);
  printf("%10.3E\n", RENT);
  printf("%+4.2f\n", RENT);
  printf("%010.2f\n", RENT);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D30(%rip),%rax
  lea    D59(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D30(%rip),%rax
  lea    D124(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D30(%rip),%rax
  lea    D127(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D30(%rip),%rax
  lea    D18(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D30(%rip),%rax
  lea    D60(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D30(%rip),%rax
  lea    D139(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D30(%rip),%rax
  lea    D118(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D30(%rip),%rax
  lea    D99(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D30
type_infered: f64
name: unpack_data
arguments: tag: D59
type_infered: string
name: unpack_data
arguments: tag: D124
type_infered: string
name: unpack_data
arguments: tag: D127
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D60
type_infered: string
name: unpack_data
arguments: tag: D139
type_infered: string
name: unpack_data
arguments: tag: D118
type_infered: string
name: unpack_data
arguments: tag: D99
type_infered: string

tool: D30: 3852.99

tool: D59: %f


tool: D124: %e


tool: D127: %4.2f


tool: D18: %3.1f


tool: D60: %10.3f


tool: D139: %10.3E


tool: D118: %+4.2f


tool: D99: %010.2f


assistant: ```c
int main() {
  const double RENT = 3852.99;
  printf("%f\n", RENT);
  printf("%e\n", RENT);
  printf("%4.2f\n", RENT);
  printf("%3.1f\n", RENT);
  printf("%10.3f\n", RENT);
  printf("%10.3E\n", RENT);
  printf("%+4.2f\n", RENT);
  printf("%010.2f\n", RENT);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D57(%rip),%rax
  lea    D72(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D57(%rip),%rax
  lea    D29(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D57(%rip),%rax
  lea    D95(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D57(%rip),%rax
  lea    D28(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D57(%rip),%rax
  lea    D41(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D57(%rip),%rax
  lea    D0(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D57(%rip),%rax
  lea    D122(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    D57(%rip),%rax
  lea    D116(%rip),%rdi
  movq   %rax,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D57
type: f64
name: parse_data
arguments: tag: D72
type: string
name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D95
type: string
name: parse_data
arguments: tag: D28
type: string
name: parse_data
arguments: tag: D41
type: string
name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D122
type: string
name: parse_data
arguments: tag: D116
type: string

tool: D57: 3852.99

tool: D72: %f


tool: D29: %e


tool: D95: %4.2f


tool: D28: %3.1f


tool: D41: %10.3f


tool: D0: %10.3E


tool: D122: %+4.2f


tool: D116: %010.2f


assistant: ```c
int main() {
  const double RENT = 3852.99;
  printf("%f\n", RENT);
  printf("%e\n", RENT);
  printf("%4.2f\n", RENT);
  printf("%3.1f\n", RENT);
  printf("%10.3f\n", RENT);
  printf("%10.3E\n", RENT);
  printf("%+4.2f\n", RENT);
  printf("%010.2f\n", RENT);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L40
L58:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x1,-0x10(%rbp)
  je     L33
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L33
L30:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L37
  movl   $0x5f,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L33:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  addl   $0x1,-0x10(%rbp)
L40:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L58
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  char *p;
  int c;
  for (i = 1; i < argc; i++) {
    p = argv[i];
    if (i != 1)
      putchar(' ');
    while (*p) {
      c = (unsigned char)*p++;
      if (!isalnum(c))
        c = '_';
      putchar(c);
    }
  }
  putchar('\n');
  return EXIT_SUCCESS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L36
  mov    %rsi,%r15
  mov    0x8(%rsi),%rbp
  mov    %edi,%r14d
  mov    $0x2,%r13d
  mov    $0x5f,%r12d
  jmp    L56
L50:
  add    $0x1,%r13
L56:
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  je     L33
L69:
  add    $0x1,%rbp
  movzbl %bl,%edi
  call   <isalnum@plt>
  movzbl %bl,%edi
  test   %eax,%eax
  cmove  %r12d,%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  jne    L69
L33:
  cmp    %r14,%r13
  je     L36
  mov    (%r15,%r13,8),%rbp
  cmp    $0x1,%r13d
  je     L50
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L50
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  char *p;
  int c;
  for (i = 1; i < argc; i++) {
    p = argv[i];
    if (i != 1)
      putchar(' ');
    while (*p) {
      c = (unsigned char)*p++;
      if (!isalnum(c))
        c = '_';
      putchar(c);
    }
  }
  putchar('\n');
  return EXIT_SUCCESS;
}
```