user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mergeAndCount>:
  endbr64
  push   %r15
  mov    %ecx,%r10d
  push   %r14
  sub    %edx,%r10d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0x20(%rsp)
  movl   $0x0,0x18(%rsp)
  cmp    $0x1,%r10d
  jle    L87
  mov    %r10d,%r14d
  movslq %r8d,%r13
  mov    %ecx,%ebx
  mov    %r9d,0x24(%rsp)
  sar    %r14d
  mov    %r13d,%r8d
  mov    %rsi,0x10(%rsp)
  mov    %rdi,%rbp
  lea    (%r14,%rdx,1),%eax
  mov    %edx,%r15d
  mov    %eax,%ecx
  mov    %eax,0x1c(%rsp)
  call   <mergeAndCount>
  mov    0x24(%rsp),%r9d
  mov    0x1c(%rsp),%edx
  mov    %ebx,%ecx
  mov    0x10(%rsp),%rsi
  mov    %r13d,%r8d
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <mergeAndCount>
  lea    (%r12,%rax,1),%ecx
  movslq 0x20(%rsp),%rax
  mov    %ecx,0x18(%rsp)
  cmp    0x1c(%rsp),%r15d
  jge    L70
  mov    %rax,0x28(%rsp)
  lea    0x0(%rbp,%rax,8),%r11
  movslq 0x24(%rsp),%r15
  xor    %r9d,%r9d
  mov    %eax,0x8(%rsp)
  mov    0x1c(%rsp),%eax
  mov    %eax,0xc(%rsp)
  mov    %eax,%r10d
  mov    %eax,%ecx
  mov    %eax,%esi
  cs nopw 0x0(%rax,%rax,1)
L73:
  mov    (%r11),%rdx
  cmp    %esi,%ebx
  jle    L139
  movslq %esi,%rax
  lea    0x0(%rbp,%rax,8),%rdi
  jmp    L158
  nopl   0x0(%rax)
L136:
  add    $0x1,%esi
  add    $0x8,%rdi
  cmp    %esi,%ebx
  je     L139
L158:
  mov    (%rdi),%rax
  sub    %rdx,%rax
  cmp    %r13,%rax
  jl     L136
L139:
  movslq %ecx,%rax
  lea    0x0(%rbp,%rax,8),%rdi
  cmp    %ecx,%ebx
  jg     L16
  jmp    L149
  nopl   0x0(%rax)
L99:
  add    $0x1,%ecx
  add    $0x8,%rdi
  cmp    %ecx,%ebx
  je     L149
L16:
  mov    (%rdi),%rax
  sub    %rdx,%rax
  cmp    %r15,%rax
  jle    L99
L149:
  cmp    %r10d,%ebx
  jle    L102
  mov    0x10(%rsp),%r14
  movslq %r10d,%rax
  movslq %r9d,%rdi
  lea    (%rbx,%r9,1),%r12d
  sub    %rax,%rdi
  sub    %r10d,%r12d
  lea    (%r14,%rdi,8),%r14
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L91:
  mov    %r8,(%r14,%rax,8)
  lea    0x1(%rax),%r10d
  mov    (%r11),%rdx
  add    $0x1,%rax
  movslq %edi,%r9
  cmp    %edi,%r12d
  je     L102
L72:
  mov    0x0(%rbp,%rax,8),%r8
  mov    %eax,%r10d
  lea    0x1(%r9),%edi
  cmp    %rdx,%r8
  jl     L91
L66:
  mov    %ecx,%eax
  addl   $0x1,0x8(%rsp)
  sub    %esi,%eax
  add    %eax,0x18(%rsp)
  mov    0x10(%rsp),%rax
  mov    %rdx,(%rax,%r9,8)
  mov    0x8(%rsp),%eax
  movslq %edi,%r9
  cmp    %eax,0x1c(%rsp)
  je     L50
  add    $0x8,%r11
  cmp    0xc(%rsp),%ebx
  jle    1060 <mergeAndCount.cold>
  mov    %esi,0xc(%rsp)
  jmp    L73
  nopw   0x0(%rax,%rax,1)
L102:
  lea    0x1(%r9),%edi
  jmp    L66
  xchg   %ax,%ax
L50:
  mov    %r10d,%r14d
  sub    0x20(%rsp),%r14d
L82:
  mov    0x28(%rsp),%rax
  mov    0x10(%rsp),%rsi
  lea    0x0(,%r14,8),%edx
  lea    0x0(%rbp,%rax,8),%rdi
  call   <memcpy@plt>
L87:
  mov    0x18(%rsp),%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L70:
  mov    %rax,0x28(%rsp)
  jmp    L82
```

assistant: ```c
int mergeAndCount(long *sums, long *buff, int start, int end, int lower, int upper) {
  if (end - start <= 1)
    return 0;
  int mid = start + (end - start) / 2;
  int cnt = mergeAndCount(sums, buff, start, mid, lower, upper) + mergeAndCount(sums, buff, mid, end, lower, upper);
  int lowerIdx = mid, upperIdx = mid, tempIdx = mid;
  for (int i = start, bi = 0; i < mid; i++, bi++) {
    while (lowerIdx < end && sums[lowerIdx] - sums[i] < lower)
      lowerIdx++;
    while (upperIdx < end && sums[upperIdx] - sums[i] <= upper)
      upperIdx++;
    while (tempIdx < end && sums[tempIdx] < sums[i])
      buff[bi++] = sums[tempIdx++];
    cnt += upperIdx - lowerIdx;
    buff[bi] = sums[i];
  }
  memcpy(sums + start, buff, (tempIdx - start) * sizeof(long));
  return cnt;
}
```