ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<correl>:
  endbr64
  push   %rbx
  mov    %edx,%r10d
  mov    %rcx,%rdx
  pxor   %xmm3,%xmm3
  sub    $0x10,%rsp
  mov    0x20(%rsp),%r11
  mov    0x28(%rsp),%rcx
  movq   $0x0,(%rcx)
  movq   $0x0,(%r11)
  movq   $0x0,(%r9)
  movq   $0x0,(%r8)
  movq   $0x0,(%rdx)
  test   %r10d,%r10d
  jle    L66
  movsd  D9(%rip),%xmm2
  movslq %r10d,%rbx
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L14
  nopl   0x0(%rax)
L70:
  movsd  (%rdx),%xmm0
L14:
  movsd  (%rdi,%rax,8),%xmm1
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm1
  movapd %xmm0,%xmm4
  addsd  %xmm2,%xmm4
  mulsd  %xmm0,%xmm1
  divsd  %xmm4,%xmm1
  addsd  (%r9),%xmm1
  movsd  %xmm1,(%r9)
  movsd  (%rsi,%rax,8),%xmm1
  subsd  (%r8),%xmm1
  mulsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm1
  divsd  %xmm4,%xmm1
  addsd  (%rcx),%xmm1
  movsd  %xmm1,(%rcx)
  movsd  (%rdi,%rax,8),%xmm1
  movsd  (%rsi,%rax,8),%xmm5
  subsd  (%rdx),%xmm1
  subsd  (%r8),%xmm5
  mulsd  %xmm5,%xmm1
  mulsd  %xmm0,%xmm1
  divsd  %xmm4,%xmm1
  addsd  (%r11),%xmm1
  movsd  %xmm1,(%r11)
  movsd  (%rdx),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rdi,%rax,8),%xmm1
  divsd  %xmm4,%xmm1
  movsd  %xmm1,(%rdx)
  mulsd  (%r8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  divsd  %xmm4,%xmm0
  movsd  %xmm0,(%r8)
  cmp    %rbx,%rax
  jne    L70
L66:
  pxor   %xmm0,%xmm0
  movsd  (%r9),%xmm1
  cvtsi2sd %r10d,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%r9)
  movsd  (%rcx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  movsd  (%r11),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%r11)
  movsd  (%r9),%xmm0
  comisd %xmm3,%xmm0
  jbe    L61
  movsd  (%rcx),%xmm2
  comisd %xmm3,%xmm2
  ja     L71
L61:
  movsd  D16(%rip),%xmm1
L16:
  mov    0x30(%rsp),%rax
  movsd  %xmm1,(%rax)
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L71:
  mulsd  %xmm2,%xmm0
  ucomisd %xmm0,%xmm3
  ja     L6
  sqrtsd %xmm0,%xmm0
L4:
  divsd  %xmm0,%xmm1
  jmp    L16
L6:
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  jmp    L4
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: f64
name: read_data
arguments: data_tag: D16
type_guessed: f32[2]

tool: D9: 1

tool: {"D16": [0.0,-2.53125]}

assistant: ```c
int correl(double x[], double y[], int n, double *mx, double *my, double *v11, double *v12, double *v22, double *r) {
  int i;
  *mx = *my = *v11 = *v12 = *v22 = 0.0;
  for (i = 0; i < n; i++) {
    *v11 += ((x[i] - *mx) * (x[i] - *mx)) * i / (i + 1.);
    *v22 += ((y[i] - *my) * (y[i] - *my)) * i / (i + 1.);
    *v12 += (x[i] - *mx) * (y[i] - *my) * i / (i + 1.);
    *mx = (*mx * i + x[i]) / (i + 1.);
    *my = (*my * i + y[i]) / (i + 1.);
  }
  *v11 /= n;
  *v22 /= n;
  *v12 /= n;
  if (*v11 > 0.0 && *v22 > 0.0)
    *r = *v12 / sqrt(*v11 * *v22);
  else
    *r = -9;
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tube_WriteS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  mov    (%rax),%eax
  mov    %eax,%eax
  mov    %rax,%rdi
  call   <write_string@plt>
  mov    -0x8(%rbp),%rdx
  add    $0x34,%rdx
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  add    $0x3,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  and    $0xfffffffc,%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void tube_WriteS(unsigned int *reg) {
  reg[13] = (unsigned int)write_string((char *)reg[13]);
  reg[13] += 3;
  reg[13] &= ~3;
}
```
user: What is the c source code of the assembly code below?

```asm
<tube_WriteS>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x34(%rdi),%edi
  call   <write_string@plt>
  add    $0x3,%eax
  and    $0xfffffffc,%eax
  mov    %eax,0x34(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void tube_WriteS(unsigned int *reg) {
  reg[13] = (unsigned int)write_string((char *)reg[13]);
  reg[13] += 3;
  reg[13] &= ~3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tube_WriteS>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x34(%rdi),%edi
  call   <write_string@plt>
  add    $0x3,%eax
  and    $0xfffffffc,%eax
  mov    %eax,0x34(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void tube_WriteS(unsigned int *reg) {
  reg[13] = (unsigned int)write_string((char *)reg[13]);
  reg[13] += 3;
  reg[13] &= ~3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tube_WriteS>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x34(%rdi),%edi
  call   <write_string@plt>
  add    $0x3,%eax
  and    $0xfffffffc,%eax
  mov    %eax,0x34(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void tube_WriteS(unsigned int *reg) {
  reg[13] = (unsigned int)write_string((char *)reg[13]);
  reg[13] += 3;
  reg[13] &= ~3;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_circular_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L36
  mov    $0x0,%eax
  jmp    L44
L36:
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L58:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
L3:
  cmpl   $0x0,-0x4(%rbp)
  jg     L58
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L53:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L16
  mov    $0x0,%eax
  jmp    L44
L16:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L53
  mov    $0x1,%eax
L44:
  leave
  ret
```

assistant: ```c
int is_circular_prime(int n) {
  if (!is_prime(n))
    return 0;
  int order = -1, power = 1, n2 = n;
  while (n2 > 0) {
    n2 /= 10;
    ++order;
    power *= 10;
  }
  power /= 10;
  for (n2 = 0; n2 < order; ++n2) {
    n = n / power + (n % power) * 10;
    if (!is_prime(n))
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_circular_prime>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  call   <is_prime@plt>
  test   %eax,%eax
  je     L53
  test   %ebx,%ebx
  jle    L66
  mov    %ebx,%ecx
  mov    $0x1,%eax
  mov    $0xffffffff,%esi
L43:
  mov    %ecx,%edi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%ecx
  mov    %ecx,%r8d
  mov    %edx,%ecx
  sub    %r8d,%ecx
  mov    %esi,%r12d
  add    $0x1,%esi
  mov    %eax,%ebp
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    $0x9,%edi
  jg     L43
  test   %esi,%esi
  jle    L3
  mov    $0x0,%r13d
  jmp    L40
L9:
  mov    %eax,%r13d
L40:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%ebx
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L53
  lea    0x1(%r13),%eax
  cmp    %r13d,%r12d
  jg     L9
  mov    $0x1,%eax
L53:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  mov    $0x1,%eax
  jmp    L53
L3:
  mov    $0x1,%eax
  jmp    L53
```

assistant: ```c
int is_circular_prime(int n) {
  if (!is_prime(n))
    return 0;
  int order = -1, power = 1, n2 = n;
  while (n2 > 0) {
    n2 /= 10;
    ++order;
    power *= 10;
  }
  power /= 10;
  for (n2 = 0; n2 < order; ++n2) {
    n = n / power + (n % power) * 10;
    if (!is_prime(n))
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_circular_prime>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <is_prime@plt>
  test   %eax,%eax
  je     L4
  test   %r12d,%r12d
  jle    L23
  mov    %r12d,%eax
  mov    $0x1,%edx
  mov    $0xffffffff,%esi
  mov    $0xcccccccd,%edi
  nopl   0x0(%rax)
L32:
  mov    %eax,%eax
  mov    %edx,%ebp
  lea    (%rdx,%rdx,4),%edx
  mov    %esi,%r13d
  mov    %rax,%rcx
  imul   %rdi,%rax
  lea    0x1(%rsi),%esi
  add    %edx,%edx
  shr    $0x23,%rax
  cmp    $0x9,%ecx
  jg     L32
  test   %esi,%esi
  je     L23
  xor    %ebx,%ebx
  jmp    L69
  nop
L28:
  lea    0x1(%rbx),%eax
  cmp    %ebx,%r13d
  jle    L23
  mov    %eax,%ebx
L69:
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%r12d
  mov    %r12d,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L28
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int is_circular_prime(int n) {
  if (!is_prime(n))
    return 0;
  int order = -1, power = 1, n2 = n;
  while (n2 > 0) {
    n2 /= 10;
    ++order;
    power *= 10;
  }
  power /= 10;
  for (n2 = 0; n2 < order; ++n2) {
    n = n / power + (n % power) * 10;
    if (!is_prime(n))
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_circular_prime>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <is_prime@plt>
  test   %eax,%eax
  je     L42
  test   %r12d,%r12d
  jle    L4
  mov    %r12d,%eax
  mov    $0x1,%edx
  mov    $0xffffffff,%esi
  mov    $0xcccccccd,%edi
  nopl   0x0(%rax)
L37:
  mov    %eax,%eax
  mov    %edx,%ebp
  lea    (%rdx,%rdx,4),%edx
  mov    %esi,%r13d
  mov    %rax,%rcx
  imul   %rdi,%rax
  lea    0x1(%rsi),%esi
  add    %edx,%edx
  shr    $0x23,%rax
  cmp    $0x9,%ecx
  jg     L37
  test   %esi,%esi
  je     L4
  xor    %ebx,%ebx
  jmp    L44
  nop
L22:
  lea    0x1(%rbx),%eax
  cmp    %ebx,%r13d
  jle    L4
  mov    %eax,%ebx
L44:
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%r12d
  mov    %r12d,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L22
L42:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int is_circular_prime(int n) {
  if (!is_prime(n))
    return 0;
  int order = -1, power = 1, n2 = n;
  while (n2 > 0) {
    n2 /= 10;
    ++order;
    power *= 10;
  }
  power /= 10;
  for (n2 = 0; n2 < order; ++n2) {
    n = n / power + (n % power) * 10;
    if (!is_prime(n))
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_hello>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: hello

assistant: ```c
extern void print_hello(void) {
  puts("hello");
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_hello>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: hello

assistant: ```c
extern void print_hello(void) {
  puts("hello");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_hello>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2: hello

assistant: ```c
extern void print_hello(void) {
  puts("hello");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_hello>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: hello

assistant: ```c
extern void print_hello(void) {
  puts("hello");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L14
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L14:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L26
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D26
data_type: string
name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D34
data_type: string

tool: D26: %f

tool: D4: 
%f

tool: D34: %.1f

assistant: ```c
int main() {
  float num, max;
  scanf("%f", &num);
  max = num;
  scanf("\n%f", &num);
  if (num > max)
    max = num;
  scanf("\n%f", &num);
  if (num > max)
    max = num;
  printf("%.1f", max);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movd   %ebx,%xmm1
  maxss  %xmm1,%xmm0
  movd   %xmm0,%ebx
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movd   %ebx,%xmm2
  maxss  %xmm2,%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D22
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string

tool: D22: %f

tool: D9: 
%f

tool: D15: %.1f

assistant: ```c
int main() {
  float num, max;
  scanf("%f", &num);
  max = num;
  scanf("\n%f", &num);
  if (num > max)
    max = num;
  scanf("\n%f", &num);
  if (num > max)
    max = num;
  printf("%.1f", max);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  lea    D2(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  mov    %r12,%rdi
  mov    %rbp,%rsi
  movss  0x14(%rsp),%xmm1
  maxss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rsp)
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  lea    D24(%rip),%rdi
  maxss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D11
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string
name: unpack_data
arguments: data_tag: D24
data_type: string

tool: D11: %f

tool: D2: 
%f

tool: D24: %.1f

assistant: ```c
int main() {
  float num, max;
  scanf("%f", &num);
  max = num;
  scanf("\n%f", &num);
  if (num > max)
    max = num;
  scanf("\n%f", &num);
  if (num > max)
    max = num;
  printf("%.1f", max);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%rdi
  lea    D11(%rip),%r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  mov    %r12,%rdi
  mov    %rbp,%rsi
  movss  0x14(%rsp),%xmm1
  maxss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rsp)
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  lea    D26(%rip),%rdi
  maxss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D11
type_guessed: string
name: parse_data
arguments: data_label: D26
type_guessed: string

tool: D25: %f

tool: D11: 
%f

tool: D26: %.1f

assistant: ```c
int main() {
  float num, max;
  scanf("%f", &num);
  max = num;
  scanf("\n%f", &num);
  if (num > max)
    max = num;
  scanf("\n%f", &num);
  if (num > max)
    max = num;
  printf("%.1f", max);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Blue7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Bar7@plt>
  mov    %eax,-0x4(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D12:  Blue7: once


tool: D15:  Blue7: twice


assistant: ```c
extern int Blue7(int one, int two) {
  int sum = 0;
  printf(" Blue7: once\n");
  sum = Bar7(one, two, 1);
  printf(" Blue7: twice\n");
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<Blue7>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <Bar7@plt>
  mov    %eax,%ebx
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
datatype: string
name: unpack_data
arguments: label: D10
datatype: string

tool: D16:  Blue7: once


tool: D10:  Blue7: twice


assistant: ```c
extern int Blue7(int one, int two) {
  int sum = 0;
  printf(" Blue7: once\n");
  sum = Bar7(one, two, 1);
  printf(" Blue7: twice\n");
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Blue7>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D14(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    $0x1,%edx
  call   <Bar7@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D14
datatype: string
name: parse_data
arguments: label: D16
datatype: string

tool: D14:  Blue7: once


tool: D16:  Blue7: twice


assistant: ```c
extern int Blue7(int one, int two) {
  int sum = 0;
  printf(" Blue7: once\n");
  sum = Bar7(one, two, 1);
  printf(" Blue7: twice\n");
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Blue7>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D16(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    $0x1,%edx
  call   <Bar7@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D16:  Blue7: once


tool: D2:  Blue7: twice


assistant: ```c
extern int Blue7(int one, int two) {
  int sum = 0;
  printf(" Blue7: once\n");
  sum = Bar7(one, two, 1);
  printf(" Blue7: twice\n");
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xcstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xcmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xcstrdup(const char *string) {
  void *mem;
  mem = xcmalloc(strlen(string) + sizeof(char));
  strcpy(mem, string);
  return (mem);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xcstrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xcmalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *xcstrdup(const char *string) {
  void *mem;
  mem = xcmalloc(strlen(string) + sizeof(char));
  strcpy(mem, string);
  return (mem);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xcstrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xcmalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *xcstrdup(const char *string) {
  void *mem;
  mem = xcmalloc(strlen(string) + sizeof(char));
  strcpy(mem, string);
  return (mem);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xcstrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xcmalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *xcstrdup(const char *string) {
  void *mem;
  mem = xcmalloc(strlen(string) + sizeof(char));
  strcpy(mem, string);
  return (mem);
}
```