user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D53(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <fa_logtab_init@plt>
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <log@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <fa_fast_log2@plt>
  movsd  D45(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <log10@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <fa_fast_log2@plt>
  movsd  D28(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrtf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <fa_fast_sqrtf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D53
data_type: f32
name: read_data
arguments: label: D45
data_type: f64
name: read_data
arguments: label: D58
data_type: string
name: read_data
arguments: label: D28
data_type: byte[8]
name: read_data
arguments: label: D27
data_type: string
name: read_data
arguments: label: D44
data_type: string

tool: D53: 487324.718

tool: D45: 0.6931471805599453

tool: D58: log:  y1=%f, y2=%f, dy=%f


tool: {"D28": [0xfe,0x79,0x9f,0x50,0x13,0x44,0xd3,0x3f]}

tool: D27: log10:  y1=%f, y2=%f, dy=%f


tool: D44: sqrtf:  y1=%f, y2=%f, dy=%f


assistant: ```c
int main() {
  float x;
  float y1, y2, dy;
  float y_sin, y_cos, y_tan;
  float y_arcsin, y_arccos, y_arctan;
  float y_sin_true, y_cos_true;
  float sita_true, sita;
  float delta;
  x = 487324.718;
  fa_logtab_init();
  y1 = log(x);
  y2 = (fa_fast_log2(x) * (0.69314718055994530942));
  dy = fabs(y2 - y1);
  printf("log:  y1=%f, y2=%f, dy=%f\n", y1, y2, dy);
  y1 = log10(x);
  y2 = (fa_fast_log2(x) * ((0.69314718055994530942) / (2.30258509299404568402)));
  dy = fabs(y2 - y1);
  printf("log10:  y1=%f, y2=%f, dy=%f\n", y1, y2, dy);
  y1 = sqrtf(x);
  y2 = (fa_fast_sqrtf(x));
  dy = fabs(y2 - y1);
  printf("sqrtf:  y1=%f, y2=%f, dy=%f\n", y1, y2, dy);
}
```