ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<execute_bind>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D23(%rip),%r12
  mov    $0x0,%edx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    (%r12),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  lea    0xc(%rsp),%rbp
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%r12),%eax
  mov    %eax,0x14(%rsp)
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %eax,0x10(%rsp)
  mov    $0x63f4,%edi
  call   <htons@plt>
  mov    %eax,0xc(%rsp)
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int execute_bind() {
  int sfd = socket(AF_INET, SOCK_STREAM, 0);
  struct sockaddr_in sin;
  memset((void *)&sin, 0, sizeof(sin));
  sin.sin_family = AF_INET;
  sin.sin_addr.s_addr = htonl(INADDR_LOOPBACK);
  sin.sin_port = htons(25588);
  bind(sfd, (struct sockaddr *)&sin, sizeof(sin));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<execute_bind>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    D2(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  lea    0xc(%rsp),%r12
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %eax,0x14(%rsp)
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0x63f4,%edi
  mov    %eax,0x10(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int execute_bind() {
  int sfd = socket(AF_INET, SOCK_STREAM, 0);
  struct sockaddr_in sin;
  memset((void *)&sin, 0, sizeof(sin));
  sin.sin_family = AF_INET;
  sin.sin_addr.s_addr = htonl(INADDR_LOOPBACK);
  sin.sin_port = htons(25588);
  bind(sfd, (struct sockaddr *)&sin, sizeof(sin));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<execute_bind>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    D13(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0xc(%rsp),%r12
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %eax,0x14(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0x63f4,%edi
  mov    %eax,0x10(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int execute_bind() {
  int sfd = socket(AF_INET, SOCK_STREAM, 0);
  struct sockaddr_in sin;
  memset((void *)&sin, 0, sizeof(sin));
  sin.sin_family = AF_INET;
  sin.sin_addr.s_addr = htonl(INADDR_LOOPBACK);
  sin.sin_port = htons(25588);
  bind(sfd, (struct sockaddr *)&sin, sizeof(sin));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L38
L4:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x14(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  movl   $0x0,-0x1c(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L11
L37:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  add    %eax,-0x18(%rbp)
  subl   $0x1,-0x10(%rbp)
L11:
  cmpl   $0x0,-0x10(%rbp)
  jns    L37
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int trap(int *height, int heightSize) {
  int *water = (int *)malloc(heightSize * sizeof(int));
  int max = 0;
  int sum = 0;
  for (int i = 0; i < heightSize; i++) {
    max = max > height[i] ? max : height[i];
    water[i] = max - height[i];
  }
  max = 0;
  for (int i = heightSize - 1; i >= 0; i--) {
    max = max > height[i] ? max : height[i];
    int h = max - height[i];
    sum += water[i] < h ? water[i] : h;
  }
  free(water);
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L22
  mov    %ebx,%eax
  lea    (%r8,%rax,4),%r9
  mov    %r8,%rax
  mov    $0x0,%edx
  mov    %rbp,%rdi
  sub    %r8,%rdi
L18:
  mov    (%rdi,%rax,1),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,%esi
  sub    %ecx,%esi
  mov    %esi,(%rax)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L18
  lea    -0x1(%rbx),%edi
  movslq %edi,%rax
  lea    (%r8,%rax,4),%rcx
  mov    $0x0,%ebx
  mov    $0x0,%edx
  sub    %r8,%rbp
L3:
  mov    0x0(%rbp,%rcx,1),%esi
  cmp    %esi,%edx
  cmovl  %esi,%edx
  mov    %edx,%eax
  sub    %esi,%eax
  mov    (%rcx),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  add    %eax,%ebx
  sub    $0x4,%rcx
  sub    $0x1,%edi
  jns    L3
L0:
  mov    %r8,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    $0x0,%ebx
  jmp    L0
```

assistant: ```c
int trap(int *height, int heightSize) {
  int *water = (int *)malloc(heightSize * sizeof(int));
  int max = 0;
  int sum = 0;
  for (int i = 0; i < heightSize; i++) {
    max = max > height[i] ? max : height[i];
    water[i] = max - height[i];
  }
  max = 0;
  for (int i = heightSize - 1; i >= 0; i--) {
    max = max > height[i] ? max : height[i];
    int h = max - height[i];
    sum += water[i] < h ? water[i] : h;
  }
  free(water);
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<trap>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%r12,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    -0x1(%r12),%edi
  mov    %rax,%r9
  test   %r12d,%r12d
  jle    L10
  mov    %rbx,%r8
  lea    (%rax,%r12,4),%r10
  xor    %edx,%edx
  sub    %rax,%r8
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%r8,%rax,1),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  mov    %edx,%esi
  sub    %ecx,%esi
  mov    %esi,-0x4(%rax)
  cmp    %rax,%r10
  jne    L8
L35:
  movslq %edi,%rax
  sub    %r9,%rbx
  xor    %r12d,%r12d
  xor    %edx,%edx
  lea    (%r9,%rax,4),%rcx
  mov    %rbx,%r8
  nopl   0x0(%rax,%rax,1)
L37:
  mov    (%r8,%rcx,1),%esi
  cmp    %esi,%edx
  cmovl  %esi,%edx
  mov    %edx,%eax
  sub    %esi,%eax
  mov    (%rcx),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  sub    $0x1,%edi
  sub    $0x4,%rcx
  add    %eax,%r12d
  cmp    $0xffffffff,%edi
  jne    L37
L20:
  mov    %r9,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  test   %edi,%edi
  jns    L35
  xor    %r12d,%r12d
  jmp    L20
```

assistant: ```c
int trap(int *height, int heightSize) {
  int *water = (int *)malloc(heightSize * sizeof(int));
  int max = 0;
  int sum = 0;
  for (int i = 0; i < heightSize; i++) {
    max = max > height[i] ? max : height[i];
    water[i] = max - height[i];
  }
  max = 0;
  for (int i = heightSize - 1; i >= 0; i--) {
    max = max > height[i] ? max : height[i];
    int h = max - height[i];
    sum += water[i] < h ? water[i] : h;
  }
  free(water);
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trap>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%r12,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    -0x1(%r12),%edi
  mov    %rax,%r9
  test   %r12d,%r12d
  jle    L47
  mov    %rbx,%r8
  lea    (%rax,%r12,4),%r10
  xor    %edx,%edx
  sub    %rax,%r8
  nopl   0x0(%rax,%rax,1)
L48:
  mov    (%r8,%rax,1),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  mov    %edx,%esi
  sub    %ecx,%esi
  mov    %esi,-0x4(%rax)
  cmp    %rax,%r10
  jne    L48
L41:
  movslq %edi,%rax
  sub    %r9,%rbx
  xor    %r12d,%r12d
  xor    %edx,%edx
  lea    (%r9,%rax,4),%rcx
  mov    %rbx,%r8
  nopl   0x0(%rax,%rax,1)
L20:
  mov    (%r8,%rcx,1),%esi
  cmp    %esi,%edx
  cmovl  %esi,%edx
  mov    %edx,%eax
  sub    %esi,%eax
  mov    (%rcx),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  sub    $0x1,%edi
  sub    $0x4,%rcx
  add    %eax,%r12d
  cmp    $0xffffffff,%edi
  jne    L20
L25:
  mov    %r9,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L47:
  test   %edi,%edi
  jns    L41
  xor    %r12d,%r12d
  jmp    L25
```

assistant: ```c
int trap(int *height, int heightSize) {
  int *water = (int *)malloc(heightSize * sizeof(int));
  int max = 0;
  int sum = 0;
  for (int i = 0; i < heightSize; i++) {
    max = max > height[i] ? max : height[i];
    water[i] = max - height[i];
  }
  max = 0;
  for (int i = heightSize - 1; i >= 0; i--) {
    max = max > height[i] ? max : height[i];
    int h = max - height[i];
    sum += water[i] < h ? water[i] : h;
  }
  free(water);
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tglt_secure_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jg     L1
  mov    $0x0,%edi
  call   <assert@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void tglt_secure_random(void *s, int l) {
  if (RAND_bytes(s, l) <= 0) {
    assert(0 && "End of random. If you want, you can start with -w");
  } else {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tglt_secure_random>:
  endbr64
  sub    $0x8,%rsp
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jle    L4
L6:
  add    $0x8,%rsp
  ret
L4:
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L6
```

assistant: ```c
void tglt_secure_random(void *s, int l) {
  if (RAND_bytes(s, l) <= 0) {
    assert(0 && "End of random. If you want, you can start with -w");
  } else {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<tglt_secure_random>:
  endbr64
  sub    $0x8,%rsp
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jle    L2
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

assistant: ```c
void tglt_secure_random(void *s, int l) {
  if (RAND_bytes(s, l) <= 0) {
    assert(0 && "End of random. If you want, you can start with -w");
  } else {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tglt_secure_random>:
  endbr64
  sub    $0x8,%rsp
  call   <RAND_bytes@plt>
  test   %rax,%rax
  jle    L8
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

assistant: ```c
void tglt_secure_random(void *s, int l) {
  if (RAND_bytes(s, l) <= 0) {
    assert(0 && "End of random. If you want, you can start with -w");
  } else {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stringcompare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x18(%rbp)
L95:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  ja     L42
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    $0x0,%eax
  jmp    L85
L38:
  mov    $0xffffffff,%eax
  jmp    L85
L42:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L110
  mov    -0x14(%rbp),%eax
  jmp    L85
L110:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L74
  mov    $0x0,%eax
  jmp    L85
L74:
  mov    $0xffffffff,%eax
  jmp    L85
L36:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L67
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L99
  mov    $0x0,%eax
  jmp    L85
L99:
  mov    $0x1,%eax
  jmp    L85
L67:
  addl   $0x1,-0x18(%rbp)
  jmp    L95
L85:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int stringcompare(const char *s1, const char *s2, size_t length) {
  int diff, i;
  for (i = 0;; i++) {
    if (i >= length) {
      if (!s2[i])
        return 0;
      return -1;
    }
    diff = tolower(s1[i]) - tolower(s2[i]);
    if (diff)
      return diff;
    if (!s1[i]) {
      if (!s2[i])
        return 0;
      else
        return -1;
    }
    if (!s2[i]) {
      if (!s1[i])
        return 0;
      else
        return 1;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stringcompare>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r15
  mov    %rsi,%r12
  mov    $0x0,%ebp
  test   %rdx,%rdx
  je     L61
L57:
  movsbl 0x0(%r13,%rbp,1),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movsbl (%r12),%edi
  call   <tolower@plt>
  sub    %eax,%ebx
  jne    L36
  cmpb   $0x0,0x0(%r13,%rbp,1)
  je     L58
  cmpb   $0x0,(%r12)
  je     L62
  add    $0x1,%rbp
  add    $0x1,%r12
  cmp    %rbp,%r15
  jne    L57
L42:
  mov    0x8(%rsp),%rax
  movzbl (%rax,%rbp,1),%eax
  neg    %al
  sbb    %ebx,%ebx
L36:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  mov    %rdx,%rbp
  jmp    L42
L58:
  movzbl (%r12),%eax
  neg    %al
  sbb    %ebx,%ebx
  jmp    L36
L62:
  mov    $0x1,%ebx
  jmp    L36
```

assistant: ```c
int stringcompare(const char *s1, const char *s2, size_t length) {
  int diff, i;
  for (i = 0;; i++) {
    if (i >= length) {
      if (!s2[i])
        return 0;
      return -1;
    }
    diff = tolower(s1[i]) - tolower(s2[i]);
    if (diff)
      return diff;
    if (!s1[i]) {
      if (!s2[i])
        return 0;
      else
        return -1;
    }
    if (!s2[i]) {
      if (!s1[i])
        return 0;
      else
        return 1;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<stringcompare>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  test   %rdx,%rdx
  jne    L9
  jmp    L6
  xchg   %ax,%ax
L5:
  cmpb   $0x0,(%r14,%rbx,1)
  movzbl (%r12,%rbx,1),%eax
  je     L24
  test   %al,%al
  je     L0
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L1
L9:
  movsbl (%r14,%rbx,1),%edi
  call   <tolower@plt>
  movsbl (%r12,%rbx,1),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  sub    %eax,%ebp
  je     L5
  pop    %rbx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L1:
  add    %r13,%r12
L6:
  movzbl (%r12),%eax
  pop    %rbx
  neg    %al
  sbb    %ebp,%ebp
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  neg    %al
  pop    %rbx
  sbb    %ebp,%ebp
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L0:
  mov    $0x1,%ebp
  pop    %rbx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int stringcompare(const char *s1, const char *s2, size_t length) {
  int diff, i;
  for (i = 0;; i++) {
    if (i >= length) {
      if (!s2[i])
        return 0;
      return -1;
    }
    diff = tolower(s1[i]) - tolower(s2[i]);
    if (diff)
      return diff;
    if (!s1[i]) {
      if (!s2[i])
        return 0;
      else
        return -1;
    }
    if (!s2[i]) {
      if (!s1[i])
        return 0;
      else
        return 1;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stringcompare>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  test   %rdx,%rdx
  jne    L21
  jmp    L56
  xchg   %ax,%ax
L10:
  cmpb   $0x0,(%r14,%rbx,1)
  movzbl (%r12,%rbx,1),%eax
  je     L41
  test   %al,%al
  je     L26
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L19
L21:
  movsbl (%r14,%rbx,1),%edi
  call   <tolower@plt>
  movsbl (%r12,%rbx,1),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  sub    %eax,%ebp
  je     L10
  pop    %rbx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L19:
  add    %r13,%r12
L56:
  movzbl (%r12),%eax
  pop    %rbx
  neg    %al
  sbb    %ebp,%ebp
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  neg    %al
  pop    %rbx
  sbb    %ebp,%ebp
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L26:
  mov    $0x1,%ebp
  pop    %rbx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int stringcompare(const char *s1, const char *s2, size_t length) {
  int diff, i;
  for (i = 0;; i++) {
    if (i >= length) {
      if (!s2[i])
        return 0;
      return -1;
    }
    diff = tolower(s1[i]) - tolower(s2[i]);
    if (diff)
      return diff;
    if (!s1[i]) {
      if (!s2[i])
        return 0;
      else
        return -1;
    }
    if (!s2[i]) {
      if (!s1[i])
        return 0;
      else
        return 1;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<darwin_my_recvfrom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  lea    -0x10(%rbp),%r8
  lea    -0x14(%rbp),%rdi
  mov    -0x28(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <recvfrom@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L23
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <darwin_convert_addr_from_native@plt>
  test   %eax,%eax
  jne    L9
  mov    $0xffffffff,%eax
  jmp    L38
L9:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
L23:
  mov    -0xc(%rbp),%eax
L38:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
ssize_t darwin_my_recvfrom(int sockfd, void *buf, size_t len, int flags, struct android_sockaddr *addr, socklen_t *addrlen) {
  struct sockaddr_storage stor;
  socklen_t ret_size = sizeof(stor);
  int ret = recvfrom(sockfd, buf, len, flags, (struct sockaddr *)&stor, &ret_size);
  if (ret >= 0) {
    if (!darwin_convert_addr_from_native((struct sockaddr *)&stor, addr, *addrlen))
      return -1;
    *addrlen = ret_size - 1;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<darwin_my_recvfrom>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %r8,%r12
  mov    %r9,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x4(%rsp)
  lea    0x4(%rsp),%r9
  mov    %rsp,%r8
  call   <recvfrom@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L15
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    %rsp,%rdi
  mov    0x0(%rbp),%edx
  mov    %r12,%rsi
  call   <darwin_convert_addr_from_native@plt>
  test   %eax,%eax
  je     L22
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x0(%rbp)
  jmp    L33
L22:
  mov    $0xffffffff,%ebx
  jmp    L33
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t darwin_my_recvfrom(int sockfd, void *buf, size_t len, int flags, struct android_sockaddr *addr, socklen_t *addrlen) {
  struct sockaddr_storage stor;
  socklen_t ret_size = sizeof(stor);
  int ret = recvfrom(sockfd, buf, len, flags, (struct sockaddr *)&stor, &ret_size);
  if (ret >= 0) {
    if (!darwin_convert_addr_from_native((struct sockaddr *)&stor, addr, *addrlen))
      return -1;
    *addrlen = ret_size - 1;
  }
  return ret;
}
```