ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trans_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  movslq (%rdi),%rax
  movl   $0x1,D8(%rip)
  mov    %rcx,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %eax,0x2c(%rsp)
  test   %eax,%eax
  jle    L9
  mov    %rax,0x20(%rsp)
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %r9,%r15
  xor    %r13d,%r13d
  lea    0x38(%rsp),%rbp
  lea    0x30(%rsp),%rbx
L1:
  movsd  (%r14,%r13,8),%xmm0
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <sincos@plt>
  movsd  0x30(%rsp),%xmm1
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movsd  0x38(%rsp),%xmm2
  movsd  (%r12,%r13,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <sincos@plt>
  movsd  0x30(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  mov    0x10(%rsp),%rax
  movsd  (%rsp),%xmm2
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax,%r13,8)
  mulsd  0x38(%rsp),%xmm1
  mov    0x18(%rsp),%rax
  movsd  %xmm1,(%rax,%r13,8)
  movsd  %xmm2,(%r15,%r13,8)
  add    $0x1,%r13
  cmp    %r13,0x20(%rsp)
  jne    L1
  mov    0x2c(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,D2(%rip)
L9:
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int trans_(int *n, double *rlat, double *rlon, double *x, double *y, double *z__) {
  int i__1;
  static int i__, nn;
  static double phi, theta, cosphi;
  --z__;
  --y;
  --x;
  --rlon;
  --rlat;
  nn = *n;
  i__1 = nn;
  for (i__ = 1; i__ <= i__1; ++i__) {
    phi = rlat[i__];
    theta = rlon[i__];
    cosphi = cos(phi);
    x[i__] = cosphi * cos(theta);
    y[i__] = cosphi * sin(theta);
    z__[i__] = sin(phi);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rQueryObject>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <jsonObjectVal@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L7
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <hashFindVal@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x40(%rbp),%rdi
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <rQueryElement@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void rQueryObject(struct jsonElement *el, char *name, char *id, char *path, struct slRef **pResultList, struct lm *lm) {
  struct hash *hash = jsonObjectVal(el, name);
  if (hash) {
    struct jsonElement *child = hashFindVal(hash, id);
    if (child)
      rQueryElement(child, name, path, pResultList, lm);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rQueryObject>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9,%r14
  call   <jsonObjectVal@plt>
  test   %rax,%rax
  je     L10
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <hashFindVal@plt>
  test   %rax,%rax
  je     L10
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <rQueryElement@plt>
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rQueryObject(struct jsonElement *el, char *name, char *id, char *path, struct slRef **pResultList, struct lm *lm) {
  struct hash *hash = jsonObjectVal(el, name);
  if (hash) {
    struct jsonElement *child = hashFindVal(hash, id);
    if (child)
      rQueryElement(child, name, path, pResultList, lm);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rQueryObject>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %r9,%rbx
  call   <jsonObjectVal@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  mov    %rbp,%rsi
  call   <hashFindVal@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L14
  mov    %rbx,%r8
  mov    %r13,%rcx
  pop    %rbx
  mov    %r12,%rdx
  pop    %rbp
  mov    %r14,%rsi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <rQueryElement@plt>
  nopl   0x0(%rax)
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rQueryObject(struct jsonElement *el, char *name, char *id, char *path, struct slRef **pResultList, struct lm *lm) {
  struct hash *hash = jsonObjectVal(el, name);
  if (hash) {
    struct jsonElement *child = hashFindVal(hash, id);
    if (child)
      rQueryElement(child, name, path, pResultList, lm);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rQueryObject>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %r9,%rbx
  call   <jsonObjectVal@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rdi
  mov    %rbp,%rsi
  call   <hashFindVal@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L15
  mov    %rbx,%r8
  mov    %r13,%rcx
  pop    %rbx
  mov    %r12,%rdx
  pop    %rbp
  mov    %r14,%rsi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <rQueryElement@plt>
  nopl   0x0(%rax)
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rQueryObject(struct jsonElement *el, char *name, char *id, char *path, struct slRef **pResultList, struct lm *lm) {
  struct hash *hash = jsonObjectVal(el, name);
  if (hash) {
    struct jsonElement *child = hashFindVal(hash, id);
    if (child)
      rQueryElement(child, name, path, pResultList, lm);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_startsWith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L22
L5:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L19
  mov    $0x0,%eax
  jmp    L15
L19:
  addl   $0x1,-0x10(%rbp)
L22:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L5
  mov    $0x1,%eax
L15:
  leave
  ret
```

assistant: ```c
int string_startsWith(char *line, char *start) {
  int line_len = strlen(line);
  int start_len = strlen(start);
  int lowest = (line_len < start_len) ? line_len : start_len;
  int i;
  for (i = 0; i < lowest; i++) {
    if (line[i] != start[i])
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_startsWith>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  test   %eax,%eax
  jle    L48
  mov    %eax,%edx
  mov    $0x0,%eax
L4:
  movzbl (%r12,%rax,1),%ecx
  cmp    %cl,0x0(%rbp,%rax,1)
  jne    L11
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
  mov    $0x1,%eax
  jmp    L45
L48:
  mov    $0x1,%eax
  jmp    L45
L11:
  mov    $0x0,%eax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int string_startsWith(char *line, char *start) {
  int line_len = strlen(line);
  int start_len = strlen(start);
  int lowest = (line_len < start_len) ? line_len : start_len;
  int i;
  for (i = 0; i < lowest; i++) {
    if (line[i] != start[i])
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<string_startsWith>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  movslq %eax,%rdx
  test   %edx,%edx
  jle    L9
  xor    %eax,%eax
  jmp    L3
  nopl   (%rax)
L8:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L9
L3:
  movzbl (%r12,%rax,1),%ecx
  cmp    %cl,0x0(%rbp,%rax,1)
  je     L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int string_startsWith(char *line, char *start) {
  int line_len = strlen(line);
  int start_len = strlen(start);
  int lowest = (line_len < start_len) ? line_len : start_len;
  int i;
  for (i = 0; i < lowest; i++) {
    if (line[i] != start[i])
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_startsWith>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  movslq %eax,%rdx
  test   %edx,%edx
  jle    L26
  xor    %eax,%eax
  jmp    L0
  nopl   (%rax)
L12:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L26
L0:
  movzbl (%r12,%rax,1),%ecx
  cmp    %cl,0x0(%rbp,%rax,1)
  je     L12
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int string_startsWith(char *line, char *start) {
  int line_len = strlen(line);
  int start_len = strlen(start);
  int lowest = (line_len < start_len) ? line_len : start_len;
  int i;
  for (i = 0; i < lowest; i++) {
    if (line[i] != start[i])
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dec2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    $0x21,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x21,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L38
  mov    -0x8(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L67
L33:
  mov    -0x24(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x24(%rbp)
L38:
  cmpl   $0x0,-0x24(%rbp)
  jg     L33
  jmp    L31
L40:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  addl   $0x1,-0x18(%rbp)
L31:
  cmpl   $0x7,-0x18(%rbp)
  jle    L40
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L28
L2:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L28:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L2
  mov    -0x8(%rbp),%rax
L67:
  leave
  ret
```

assistant: ```c
char *dec2bin(int a) {
  char *aout;
  char *bout;
  aout = (char *)malloc(sizeof(char) * 33);
  bout = (char *)malloc(sizeof(char) * 33);
  int i = 0;
  if (a == 0) {
    bout[0] = '0';
    bout[1] = '0';
    bout[2] = '0';
    bout[3] = '0';
    bout[4] = '0';
    bout[5] = '0';
    bout[6] = '0';
    bout[7] = '0';
    return bout;
  }
  while (a > 0) {
    aout[i] = (char)(a % 2 + 48);
    i++;
    a = (a - a % 2) / 2;
  }
  for (; i < 8; i++) {
    aout[i] = '0';
  }
  int j = 0;
  for (j = 0; j < i; j++) {
    bout[j] = aout[i - j - 1];
  }
  return bout;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dec2bin>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x21,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x21,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %ebx,%ebx
  je     L55
  mov    %rbp,%rdx
  mov    $0x1,%r8d
  sub    %ebp,%r8d
  mov    $0x0,%esi
  test   %ebx,%ebx
  jle    L19
L71:
  mov    %ebx,%ecx
  shr    $0x1f,%ecx
  lea    (%rbx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    %cl,(%rdx)
  lea    (%r8,%rdx,1),%esi
  sub    %eax,%ebx
  mov    %ebx,%ecx
  shr    $0x1f,%ebx
  add    %ecx,%ebx
  sar    %ebx
  add    $0x1,%rdx
  cmp    $0x1,%ecx
  jg     L71
  cmp    $0x7,%esi
  jg     L3
L19:
  movslq %esi,%rax
L69:
  movb   $0x30,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    $0x7,%eax
  jle    L69
  mov    $0x7,%eax
  sub    %esi,%eax
  cmp    $0x7,%esi
  mov    $0x0,%edx
  cmovg  %edx,%eax
  lea    0x1(%rsi,%rax,1),%esi
L3:
  test   %esi,%esi
  jle    L26
  movslq %esi,%rcx
  lea    -0x1(%rbp,%rcx,1),%rax
  lea    -0x2(%rbp,%rcx,1),%rdx
  lea    -0x1(%rsi),%r8d
  mov    %rdx,%rsi
  sub    %r8,%rsi
  add    %rdi,%rcx
  lea    -0x1(%rbp,%rcx,1),%r8
L10:
  movzbl (%rax),%ecx
  mov    %r8,%rdx
  sub    %rax,%rdx
  mov    %cl,(%rdx)
  sub    $0x1,%rax
  cmp    %rsi,%rax
  jne    L10
L26:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  movb   $0x30,(%rax)
  movb   $0x30,0x1(%rax)
  movb   $0x30,0x2(%rax)
  movb   $0x30,0x3(%rax)
  movb   $0x30,0x4(%rax)
  movb   $0x30,0x5(%rax)
  movb   $0x30,0x6(%rax)
  movb   $0x30,0x7(%rax)
  jmp    L26
```

assistant: ```c
char *dec2bin(int a) {
  char *aout;
  char *bout;
  aout = (char *)malloc(sizeof(char) * 33);
  bout = (char *)malloc(sizeof(char) * 33);
  int i = 0;
  if (a == 0) {
    bout[0] = '0';
    bout[1] = '0';
    bout[2] = '0';
    bout[3] = '0';
    bout[4] = '0';
    bout[5] = '0';
    bout[6] = '0';
    bout[7] = '0';
    return bout;
  }
  while (a > 0) {
    aout[i] = (char)(a % 2 + 48);
    i++;
    a = (a - a % 2) / 2;
  }
  for (; i < 8; i++) {
    aout[i] = '0';
  }
  int j = 0;
  for (j = 0; j < i; j++) {
    bout[j] = aout[i - j - 1];
  }
  return bout;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dec2bin>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x21,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x21,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  je     L117
  mov    %rbp,%rax
  jle    L115
  mov    $0x1,%esi
  sub    %ebp,%esi
  xchg   %ax,%ax
L23:
  mov    %ebx,%edx
  and    $0x1,%edx
  lea    0x30(%rdx),%ecx
  sub    %edx,%ebx
  mov    %cl,(%rax)
  lea    (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  sar    %ebx
  jne    L23
  cmp    $0x7,%ecx
  jg     L17
L53:
  mov    $0x8,%eax
  mov    $0x1,%edx
  movabs $0x3030303030303030,%r9
  sub    %ecx,%eax
  cmp    $0x7,%ecx
  cmovg  %rdx,%rax
  movslq %ecx,%rdx
  add    %rbp,%rdx
  mov    %eax,%esi
  cmp    $0x8,%eax
  jb     L45
  lea    0x8(%rdx),%rdi
  mov    %r9,(%rdx)
  and    $0xfffffffffffffff8,%rdi
  mov    %r9,-0x8(%rax,%rdx,1)
  sub    %rdi,%rdx
  lea    (%rax,%rdx,1),%esi
  and    $0xfffffff8,%esi
  cmp    $0x8,%esi
  jb     L18
  and    $0xfffffff8,%esi
  xor    %eax,%eax
L81:
  mov    %eax,%edx
  add    $0x8,%eax
  mov    %r9,(%rdi,%rdx,1)
  cmp    %esi,%eax
  jb     L81
L18:
  mov    $0x7,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  cmp    $0x7,%ecx
  cmovg  %edx,%eax
  lea    0x1(%rcx,%rax,1),%ecx
L17:
  movslq %ecx,%rdx
  sub    $0x1,%ecx
  lea    -0x2(%rbp,%rdx,1),%rsi
  lea    -0x1(%rbp,%rdx,1),%rax
  add    %r8,%rdx
  sub    %rcx,%rsi
  lea    -0x1(%rbp,%rdx,1),%rdi
  nopl   0x0(%rax,%rax,1)
L85:
  movzbl (%rax),%ecx
  mov    %rdi,%rdx
  sub    %rax,%rdx
  sub    $0x1,%rax
  mov    %cl,(%rdx)
  cmp    %rax,%rsi
  jne    L85
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L45:
  test   $0x4,%al
  jne    L127
  test   %esi,%esi
  je     L18
  movb   $0x30,(%rdx)
  test   $0x2,%sil
  je     L18
  mov    $0x3030,%eax
  mov    %ax,-0x2(%rdx,%rsi,1)
  jmp    L18
  nopl   (%rax)
L117:
  movabs $0x3030303030303030,%rax
  mov    %rax,(%r8)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L115:
  xor    %ecx,%ecx
  jmp    L53
L127:
  movl   $0x30303030,(%rdx)
  movl   $0x30303030,-0x4(%rdx,%rsi,1)
  jmp    L18
```

assistant: ```c
char *dec2bin(int a) {
  char *aout;
  char *bout;
  aout = (char *)malloc(sizeof(char) * 33);
  bout = (char *)malloc(sizeof(char) * 33);
  int i = 0;
  if (a == 0) {
    bout[0] = '0';
    bout[1] = '0';
    bout[2] = '0';
    bout[3] = '0';
    bout[4] = '0';
    bout[5] = '0';
    bout[6] = '0';
    bout[7] = '0';
    return bout;
  }
  while (a > 0) {
    aout[i] = (char)(a % 2 + 48);
    i++;
    a = (a - a % 2) / 2;
  }
  for (; i < 8; i++) {
    aout[i] = '0';
  }
  int j = 0;
  for (j = 0; j < i; j++) {
    bout[j] = aout[i - j - 1];
  }
  return bout;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dec2bin>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x21,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x21,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  je     L65
  mov    %rbp,%rax
  jle    L106
  mov    $0x1,%esi
  sub    %ebp,%esi
  xchg   %ax,%ax
L126:
  mov    %ebx,%edx
  and    $0x1,%edx
  lea    0x30(%rdx),%ecx
  sub    %edx,%ebx
  mov    %cl,(%rax)
  lea    (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  sar    %ebx
  jne    L126
  cmp    $0x7,%ecx
  jg     L124
L24:
  mov    $0x8,%eax
  mov    $0x1,%edx
  movabs $0x3030303030303030,%r9
  sub    %ecx,%eax
  cmp    $0x7,%ecx
  cmovg  %rdx,%rax
  movslq %ecx,%rdx
  add    %rbp,%rdx
  mov    %eax,%esi
  cmp    $0x8,%eax
  jb     L5
  lea    0x8(%rdx),%rdi
  mov    %r9,(%rdx)
  and    $0xfffffffffffffff8,%rdi
  mov    %r9,-0x8(%rax,%rdx,1)
  sub    %rdi,%rdx
  lea    (%rax,%rdx,1),%esi
  and    $0xfffffff8,%esi
  cmp    $0x8,%esi
  jb     L10
  and    $0xfffffff8,%esi
  xor    %eax,%eax
L121:
  mov    %eax,%edx
  add    $0x8,%eax
  mov    %r9,(%rdi,%rdx,1)
  cmp    %esi,%eax
  jb     L121
L10:
  mov    $0x7,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  cmp    $0x7,%ecx
  cmovg  %edx,%eax
  lea    0x1(%rcx,%rax,1),%ecx
L124:
  movslq %ecx,%rdx
  sub    $0x1,%ecx
  lea    -0x2(%rbp,%rdx,1),%rsi
  lea    -0x1(%rbp,%rdx,1),%rax
  sub    %rcx,%rsi
  lea    (%r8,%rbp,1),%rcx
  lea    -0x1(%rdx,%rcx,1),%rdi
  nopl   0x0(%rax)
L100:
  movzbl (%rax),%ecx
  mov    %rdi,%rdx
  sub    %rax,%rdx
  sub    $0x1,%rax
  mov    %cl,(%rdx)
  cmp    %rsi,%rax
  jne    L100
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L5:
  test   $0x4,%al
  jne    L48
  test   %esi,%esi
  je     L10
  movb   $0x30,(%rdx)
  test   $0x2,%sil
  je     L10
  mov    $0x3030,%eax
  mov    %ax,-0x2(%rdx,%rsi,1)
  jmp    L10
  nopl   (%rax)
L65:
  mov    D2(%rip),%rax
  mov    %rax,(%r8)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L106:
  xor    %ecx,%ecx
  jmp    L24
L48:
  movl   $0x30303030,(%rdx)
  movl   $0x30303030,-0x4(%rdx,%rsi,1)
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: byte[8]

tool: {"D2": [0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30]}

assistant: ```c
char *dec2bin(int a) {
  char *aout;
  char *bout;
  aout = (char *)malloc(sizeof(char) * 33);
  bout = (char *)malloc(sizeof(char) * 33);
  int i = 0;
  if (a == 0) {
    bout[0] = '0';
    bout[1] = '0';
    bout[2] = '0';
    bout[3] = '0';
    bout[4] = '0';
    bout[5] = '0';
    bout[6] = '0';
    bout[7] = '0';
    return bout;
  }
  while (a > 0) {
    aout[i] = (char)(a % 2 + 48);
    i++;
    a = (a - a % 2) / 2;
  }
  for (; i < 8; i++) {
    aout[i] = '0';
  }
  int j = 0;
  for (j = 0; j < i; j++) {
    bout[j] = aout[i - j - 1];
  }
  return bout;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2,-0x8(%rbp)
  jmp    L8
L3:
  subl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0x1,-0x8(%rbp)
  jg     L3
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int n = 2;
  int m;
  while (n > 1) {
    n--;
  }
  m = 0;
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  int n = 2;
  int m;
  while (n > 1) {
    n--;
  }
  m = 0;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  int n = 2;
  int m;
  while (n > 1) {
    n--;
  }
  m = 0;
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  int n = 2;
  int m;
  while (n > 1) {
    n--;
  }
  m = 0;
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <dash@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dash@plt>
  mov    $0x0,%eax
  call   <cBreak@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sX() {
  dash();
  dot();
  dot();
  dash();
  cBreak();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sX>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dash@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dot@plt>
  mov    $0x0,%eax
  call   <dash@plt>
  mov    $0x0,%eax
  call   <cBreak@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sX() {
  dash();
  dot();
  dot();
  dash();
  cBreak();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sX>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dash@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dash@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <cBreak@plt>
```

assistant: ```c
void sX() {
  dash();
  dot();
  dot();
  dash();
  cBreak();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sX>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dash@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dot@plt>
  xor    %eax,%eax
  call   <dash@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <cBreak@plt>
```

assistant: ```c
void sX() {
  dash();
  dot();
  dot();
  dash();
  cBreak();
}
```