ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<move>:
  endbr64
  mov    %esi,%eax
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  cltd
  idiv   %ebx
  sub    $0x18,%rsp
  mov    %ecx,0x4(%rsp)
  lea    0x0(,%rax,4),%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  xor    %r8d,%r8d
  mov    %rax,0x8(%rsp)
  test   %ebp,%ebp
  jg     L22
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L2:
  movl   $0x0,(%rax)
  mov    %r15d,%eax
  mov    0x4(%rsp),%ecx
  mov    %r12d,%esi
  cltd
  mov    %r13,%rdi
  idiv   %ebx
  mov    %edx,%r15d
  mov    %r8d,%edx
  call   <next_index@plt>
  mov    %eax,%r8d
  cmp    %r14d,%ebp
  jle    L41
L22:
  movslq %r8d,%rax
  lea    0x0(%r13,%rax,4),%rax
  cmp    %r15d,%ebx
  jne    L2
  mov    (%rax),%edx
  mov    0x8(%rsp),%rcx
  movslq %r14d,%r9
  lea    0x1(%r14),%r15d
  mov    %edx,(%rcx,%r9,4)
  movl   $0x0,(%rax)
  cmp    %r15d,%ebp
  jg     L30
L41:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  mov    0x4(%rsp),%ecx
  mov    %r8d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %r15d,%r14d
  xor    %r15d,%r15d
  call   <next_index@plt>
  mov    %eax,%r8d
  jmp    L22
```

assistant: ```c
int *move(int *cards, int card_num, int player_num, int skip) {
  int cards_per_player = card_num / player_num;
  int *cand = malloc(sizeof(int) * cards_per_player);
  int i = 0, index = 0;
  int count = 1;
  while (i < cards_per_player) {
    if (count == player_num) {
      cand[i++] = cards[index];
    }
    cards[index] = 0;
    count = (count++) % player_num;
    if (i < cards_per_player)
      index = next_index(cards, card_num, index, skip);
  }
  return cand;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_quaddobl_witness_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x295,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int read_quaddobl_witness_set(int *n, int *dim, int *deg) {
  int fail, m;
  double *c;
  int d[2];
  fail = _ada_use_c2phc4c(661, n, d, c, 0);
  *dim = d[0];
  *deg = d[1];
  if (0 > 0)
    printf("The ambient dimension is %d.\n", *n);
  if (0 > 0)
    printf("The dimension of the solution set is %d.\n", d[0]);
  if (0 > 0)
    printf("The degree of the solution set is %d.\n", d[1]);
  if (0 > 1) {
    printf("The embedded system :\n");
    fail = syscon_write_quaddobl_system();
  }
  if (0 > 1) {
    printf("The following solutions are in container :\n");
    fail = solcon_write_quaddobl_solutions();
  }
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_quaddobl_witness_set>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rsi
  mov    $0x295,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    (%rsp),%edx
  mov    %edx,0x0(%rbp)
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_quaddobl_witness_set(int *n, int *dim, int *deg) {
  int fail, m;
  double *c;
  int d[2];
  fail = _ada_use_c2phc4c(661, n, d, c, 0);
  *dim = d[0];
  *deg = d[1];
  if (0 > 0)
    printf("The ambient dimension is %d.\n", *n);
  if (0 > 0)
    printf("The dimension of the solution set is %d.\n", d[0]);
  if (0 > 0)
    printf("The degree of the solution set is %d.\n", d[1]);
  if (0 > 1) {
    printf("The embedded system :\n");
    fail = syscon_write_quaddobl_system();
  }
  if (0 > 1) {
    printf("The following solutions are in container :\n");
    fail = solcon_write_quaddobl_solutions();
  }
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_quaddobl_witness_set>:
  endbr64
  push   %rbp
  xor    %r8d,%r8d
  mov    %rsi,%rbp
  xor    %ecx,%ecx
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdx,%rbx
  mov    $0x295,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <_ada_use_c2phc4c@plt>
  mov    (%rsp),%edx
  mov    %edx,0x0(%rbp)
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_quaddobl_witness_set(int *n, int *dim, int *deg) {
  int fail, m;
  double *c;
  int d[2];
  fail = _ada_use_c2phc4c(661, n, d, c, 0);
  *dim = d[0];
  *deg = d[1];
  if (0 > 0)
    printf("The ambient dimension is %d.\n", *n);
  if (0 > 0)
    printf("The dimension of the solution set is %d.\n", d[0]);
  if (0 > 0)
    printf("The degree of the solution set is %d.\n", d[1]);
  if (0 > 1) {
    printf("The embedded system :\n");
    fail = syscon_write_quaddobl_system();
  }
  if (0 > 1) {
    printf("The following solutions are in container :\n");
    fail = solcon_write_quaddobl_solutions();
  }
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_quaddobl_witness_set>:
  endbr64
  push   %rbp
  xor    %r8d,%r8d
  mov    %rsi,%rbp
  xor    %ecx,%ecx
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdx,%rbx
  mov    $0x295,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <_ada_use_c2phc4c@plt>
  mov    (%rsp),%edx
  mov    %edx,0x0(%rbp)
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_quaddobl_witness_set(int *n, int *dim, int *deg) {
  int fail, m;
  double *c;
  int d[2];
  fail = _ada_use_c2phc4c(661, n, d, c, 0);
  *dim = d[0];
  *deg = d[1];
  if (0 > 0)
    printf("The ambient dimension is %d.\n", *n);
  if (0 > 0)
    printf("The dimension of the solution set is %d.\n", d[0]);
  if (0 > 0)
    printf("The degree of the solution set is %d.\n", d[1]);
  if (0 > 1) {
    printf("The embedded system :\n");
    fail = syscon_write_quaddobl_system();
  }
  if (0 > 1) {
    printf("The following solutions are in container :\n");
    fail = solcon_write_quaddobl_solutions();
  }
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %edi,-0x434(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x434(%rbp)
  jg     L26
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L44
L26:
  mov    -0x440(%rbp),%rdx
  mov    -0x434(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <get_expression@plt>
  mov    %rax,-0x428(%rbp)
  mov    -0x428(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <get_exec_cmd@plt>
  mov    %rax,-0x420(%rbp)
  mov    -0x420(%rbp),%rax
  lea    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L2
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L44
L58:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x3ff,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L58
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  mov    $0x0,%eax
L44:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D35
type_guessed: string
name: disassemble_data
arguments: label: D25
type_guessed: string
name: disassemble_data
arguments: label: D23
type_guessed: string
name: disassemble_data
arguments: label: D37
type_guessed: string

tool: D6: Usage - `hexcalc {expression}`

tool: D35: evaling: %s


tool: D25: r

tool: D23: Failed to run command

tool: D37: result : %s

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage - `hexcalc {expression}`\n");
    return 0;
  }
  FILE *fp;
  int status;
  char path[1024];
  char *expression = get_expression(argc, argv);
  printf("evaling: %s\n", expression);
  char *exec_cmd = get_exec_cmd(expression);
  fp = popen(exec_cmd, "r");
  if (fp == NULL) {
    printf("Failed to run command\n");
    return 1;
  }
  while (fgets(path, sizeof(path) - 1, fp) != NULL) {
    printf("result : %s", path);
  }
  free(expression);
  free(exec_cmd);
  pclose(fp);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L24
  call   <get_expression@plt>
  mov    %rax,%r12
  mov    %rax,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <get_exec_cmd@plt>
  mov    %rax,%r13
  lea    D31(%rip),%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,%rbx
  lea    D46(%rip),%rbp
  test   %rax,%rax
  jne    L48
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L50
L24:
  lea    D48(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L50
L34:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L48:
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  mov    $0x3ff,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L34
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <pclose@plt>
  mov    $0x0,%eax
L50:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D31
data_type: string
name: disassemble_data
arguments: label: D46
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string
name: disassemble_data
arguments: label: D48
data_type: string

tool: D4: evaling: %s


tool: D31: r

tool: D46: result : %s

tool: D19: Failed to run command

tool: D48: Usage - `hexcalc {expression}`

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage - `hexcalc {expression}`\n");
    return 0;
  }
  FILE *fp;
  int status;
  char path[1024];
  char *expression = get_expression(argc, argv);
  printf("evaling: %s\n", expression);
  char *exec_cmd = get_exec_cmd(expression);
  fp = popen(exec_cmd, "r");
  if (fp == NULL) {
    printf("Failed to run command\n");
    return 1;
  }
  while (fgets(path, sizeof(path) - 1, fp) != NULL) {
    printf("result : %s", path);
  }
  free(expression);
  free(exec_cmd);
  pclose(fp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L40
  call   <get_expression@plt>
  lea    D47(%rip),%rdi
  mov    %rsp,%rbx
  lea    D7(%rip),%r14
  mov    %rax,%rsi
  mov    %rax,%r12
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <get_exec_cmd@plt>
  lea    D44(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <popen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L23
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L23:
  mov    %rbp,%rdx
  mov    $0x3ff,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <pclose@plt>
  xor    %eax,%eax
L14:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  lea    D30(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L14
L41:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L14
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D47
type_guessed: string
name: read_data
arguments: label: D7
type_guessed: string
name: read_data
arguments: label: D44
type_guessed: string
name: read_data
arguments: label: D30
type_guessed: string
name: read_data
arguments: label: D2
type_guessed: string

tool: D47: evaling: %s


tool: D7: result : %s

tool: D44: r

tool: D30: Usage - `hexcalc {expression}`

tool: D2: Failed to run command

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage - `hexcalc {expression}`\n");
    return 0;
  }
  FILE *fp;
  int status;
  char path[1024];
  char *expression = get_expression(argc, argv);
  printf("evaling: %s\n", expression);
  char *exec_cmd = get_exec_cmd(expression);
  fp = popen(exec_cmd, "r");
  if (fp == NULL) {
    printf("Failed to run command\n");
    return 1;
  }
  while (fgets(path, sizeof(path) - 1, fp) != NULL) {
    printf("result : %s", path);
  }
  free(expression);
  free(exec_cmd);
  pclose(fp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L27
  call   <get_expression@plt>
  lea    D30(%rip),%rdi
  mov    %rsp,%rbx
  lea    D32(%rip),%r14
  mov    %rax,%rsi
  mov    %rax,%r12
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <get_exec_cmd@plt>
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <popen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L18
  jmp    L68
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    %rbp,%rdx
  mov    $0x3ff,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L55
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <pclose@plt>
  xor    %eax,%eax
L69:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  lea    D35(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L69
L68:
  lea    D41(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L69
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D30
type_infered: string
name: retrieve_data
arguments: data_label: D32
type_infered: string
name: retrieve_data
arguments: data_label: D29
type_infered: string
name: retrieve_data
arguments: data_label: D35
type_infered: string
name: retrieve_data
arguments: data_label: D41
type_infered: string

tool: D30: evaling: %s


tool: D32: result : %s

tool: D29: r

tool: D35: Usage - `hexcalc {expression}`

tool: D41: Failed to run command

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage - `hexcalc {expression}`\n");
    return 0;
  }
  FILE *fp;
  int status;
  char path[1024];
  char *expression = get_expression(argc, argv);
  printf("evaling: %s\n", expression);
  char *exec_cmd = get_exec_cmd(expression);
  fp = popen(exec_cmd, "r");
  if (fp == NULL) {
    printf("Failed to run command\n");
    return 1;
  }
  while (fgets(path, sizeof(path) - 1, fp) != NULL) {
    printf("result : %s", path);
  }
  free(expression);
  free(exec_cmd);
  pclose(fp);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_crc_16_ccitt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  shl    $0x8,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L49
L13:
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%eax
  cltq
  or     %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L38
L18:
  shlq   -0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1000000,%eax
  test   %rax,%rax
  je     L42
  mov    -0x8(%rbp),%rax
  xor    $0x1102100,%rax
  mov    %rax,-0x8(%rbp)
L42:
  addq   $0x1,-0x10(%rbp)
L38:
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jl     L18
  addq   $0x1,-0x18(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L13
  mov    -0x8(%rbp),%rax
  sar    $0x8,%rax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t calc_crc_16_ccitt(const uint8_t *src, size_t nbytes, uint16_t crc) {
  size_t ibyte;
  uint32_t ibit;
  uint32_t crcwk = crc << 8;
  for (ibyte = 0; ibyte < nbytes; ibyte++) {
    crcwk |= *src++;
    for (ibit = 0; ibit < CHAR_BIT; ibit++) {
      crcwk <<= 1;
      if (crcwk & (0x01000000)) {
        crcwk ^= (0x11021ul << 8);
      }
    }
  }
  return (uint16_t)(crcwk >> 8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_crc_16_ccitt>:
  endbr64
  shl    $0x8,%edx
  movslq %edx,%rax
  test   %rsi,%rsi
  je     L6
  mov    D9(%rip),%rdx
  mov    (%rdx),%r8
  mov    $0x0,%r9d
L3:
  movslq (%rdi,%r9,4),%rdx
  or     %rdx,%rax
  test   %r8,%r8
  jle    L18
  mov    $0x0,%edx
L16:
  add    %rax,%rax
  mov    %rax,%rcx
  xor    $0x1102100,%rcx
  test   $0x1000000,%eax
  cmovne %rcx,%rax
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L16
L18:
  add    $0x1,%r9
  cmp    %r9,%rsi
  jne    L3
L6:
  sar    $0x8,%rax
  ret
```

assistant: ```c
uint16_t calc_crc_16_ccitt(const uint8_t *src, size_t nbytes, uint16_t crc) {
  size_t ibyte;
  uint32_t ibit;
  uint32_t crcwk = crc << 8;
  for (ibyte = 0; ibyte < nbytes; ibyte++) {
    crcwk |= *src++;
    for (ibit = 0; ibit < CHAR_BIT; ibit++) {
      crcwk <<= 1;
      if (crcwk & (0x01000000)) {
        crcwk ^= (0x11021ul << 8);
      }
    }
  }
  return (uint16_t)(crcwk >> 8);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calc_crc_16_ccitt>:
  endbr64
  shl    $0x8,%edx
  movslq %edx,%rax
  test   %rsi,%rsi
  je     L28
  mov    D5(%rip),%rdx
  xor    %r9d,%r9d
  mov    (%rdx),%r8
  nopl   0x0(%rax)
L4:
  movslq (%rdi,%r9,4),%rdx
  or     %rdx,%rax
  test   %r8,%r8
  jle    L12
  xor    %edx,%edx
  xchg   %ax,%ax
L13:
  add    %rax,%rax
  mov    %rax,%rcx
  xor    $0x1102100,%rcx
  test   $0x1000000,%eax
  cmovne %rcx,%rax
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L13
L12:
  add    $0x1,%r9
  cmp    %r9,%rsi
  jne    L4
L28:
  sar    $0x8,%rax
  ret
```

assistant: ```c
uint16_t calc_crc_16_ccitt(const uint8_t *src, size_t nbytes, uint16_t crc) {
  size_t ibyte;
  uint32_t ibit;
  uint32_t crcwk = crc << 8;
  for (ibyte = 0; ibyte < nbytes; ibyte++) {
    crcwk |= *src++;
    for (ibit = 0; ibit < CHAR_BIT; ibit++) {
      crcwk <<= 1;
      if (crcwk & (0x01000000)) {
        crcwk ^= (0x11021ul << 8);
      }
    }
  }
  return (uint16_t)(crcwk >> 8);
}
```
user: What is the c source code of the assembly code below?

```asm
<calc_crc_16_ccitt>:
  endbr64
  shl    $0x8,%edx
  movslq %edx,%rax
  test   %rsi,%rsi
  je     L31
  mov    D8(%rip),%rdx
  xor    %r9d,%r9d
  mov    (%rdx),%r8
  nopl   0x0(%rax)
L3:
  movslq (%rdi,%r9,4),%rdx
  or     %rdx,%rax
  test   %r8,%r8
  jle    L27
  xor    %edx,%edx
  xchg   %ax,%ax
L23:
  add    %rax,%rax
  mov    %rax,%rcx
  xor    $0x1102100,%rcx
  test   $0x1000000,%eax
  cmovne %rcx,%rax
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L23
L27:
  add    $0x1,%r9
  cmp    %r9,%rsi
  jne    L3
L31:
  sar    $0x8,%rax
  ret
```

assistant: ```c
uint16_t calc_crc_16_ccitt(const uint8_t *src, size_t nbytes, uint16_t crc) {
  size_t ibyte;
  uint32_t ibit;
  uint32_t crcwk = crc << 8;
  for (ibyte = 0; ibyte < nbytes; ibyte++) {
    crcwk |= *src++;
    for (ibit = 0; ibit < CHAR_BIT; ibit++) {
      crcwk <<= 1;
      if (crcwk & (0x01000000)) {
        crcwk ^= (0x11021ul << 8);
      }
    }
  }
  return (uint16_t)(crcwk >> 8);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uninitvar_strcat_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strcat_s@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strcat_s@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strcat_s@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strcat_s@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strcat_s@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_strcat_s(char *Ct, size_t N, char *S) {
  char *ct_1, *ct_2;
  char *s;
  size_t n1, n2;
  (void)strcat_s(ct_1, n1, s);
  (void)strcat_s(ct_2, N, S);
  (void)strcat_s(Ct, N, s);
  (void)strcat_s(Ct, n2, S);
  (void)strcat_s(Ct, N, S);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uninitvar_strcat_s>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x0,%r13d
  mov    %r13,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <strcat_s@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strcat_s@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat_s@plt>
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strcat_s@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat_s@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void uninitvar_strcat_s(char *Ct, size_t N, char *S) {
  char *ct_1, *ct_2;
  char *s;
  size_t n1, n2;
  (void)strcat_s(ct_1, n1, s);
  (void)strcat_s(ct_2, N, S);
  (void)strcat_s(Ct, N, s);
  (void)strcat_s(Ct, n2, S);
  (void)strcat_s(Ct, N, S);
}
```