ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  lea    D5(%rip),%rdi
  mov    $0x2,%r15d
  push   %r14
  push   %r13
  push   %r12
  lea    D48(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x1c(%rsp),%rbx
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r13d
  mov    %eax,%r14d
  and    $0x80000000,%r13d
  cmpl   $0x2,0xc(%rsp)
  jg     L10
  jmp    L42
  nop
L21:
  add    $0x1,%r15d
  cmp    %r15d,0xc(%rsp)
  jle    L42
L10:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  and    $0x80000000,%eax
  cmp    %r13d,%eax
  je     L21
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L42:
  test   %r14d,%r14d
  lea    D45(%rip),%rdi
  lea    D8(%rip),%rax
  cmovs  %rax,%rdi
  call   <printf@plt>
L35:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D48
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D46
data_type: string
name: extract_symbolic_data
arguments: tag: D45
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D5: %d

tool: D48: %s

tool: D27: %s %s

tool: D46: NEITHER

tool: D45: DECREASING

tool: D8: INCREASING

assistant: ```c
int main() {
  int n, delta, result;
  char name1[12], name2[12];
  scanf("%d", &n);
  scanf("%s %s", name1, name2);
  delta = strcmp(name1, name2) & 0x80000000;
  for (int i = 2; i < n; i++) {
    strcpy(name1, name2);
    scanf("%s", name2);
    if ((strcmp(name1, name2) & 0x80000000) != delta) {
      printf("NEITHER");
      return 0;
    }
  }
  printf(delta == 0 ? "DECREASING" : "INCREASING");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tinyrl_key_default>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <tinyrl_insert_text@plt>
  leave
  ret
```

assistant: ```c
bool tinyrl_key_default(void *context, char *key) {
  struct tinyrl *this = context;
  return tinyrl_insert_text(this, key);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tinyrl_key_default>:
  endbr64
  sub    $0x8,%rsp
  call   <tinyrl_insert_text@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool tinyrl_key_default(void *context, char *key) {
  struct tinyrl *this = context;
  return tinyrl_insert_text(this, key);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tinyrl_key_default>:
  endbr64
  jmp    1050 <tinyrl_insert_text@plt>
```

assistant: ```c
bool tinyrl_key_default(void *context, char *key) {
  struct tinyrl *this = context;
  return tinyrl_insert_text(this, key);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tinyrl_key_default>:
  endbr64
  jmp    1050 <tinyrl_insert_text@plt>
```

assistant: ```c
bool tinyrl_key_default(void *context, char *key) {
  struct tinyrl *this = context;
  return tinyrl_insert_text(this, key);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f() {
  struct S {
    int i;
  };
  struct S;
  struct S s;
  return s.i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int f() {
  struct S {
    int i;
  };
  struct S;
  struct S s;
  return s.i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int f() {
  struct S {
    int i;
  };
  struct S;
  struct S s;
  return s.i;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int f() {
  struct S {
    int i;
  };
  struct S;
  struct S s;
  return s.i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__SSAT16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x10,%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <__SSAT@plt>
  and    $0xffff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <__SSAT@plt>
  and    $0xffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  or     -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SSAT16(int32_t x, const uint32_t y) {
  int32_t r = 0, s = 0;
  r = __SSAT((((int32_t)x << 16) >> 16), y) & (int32_t)0x0000FFFF;
  s = __SSAT((((int32_t)x) >> 16), y) & (int32_t)0x0000FFFF;
  return ((uint32_t)((s << 16) | (r)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__SSAT16>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  movswl %di,%edi
  call   <__SSAT@plt>
  mov    %eax,%ebp
  sar    $0x10,%ebx
  mov    %ebx,%edi
  mov    %r12d,%esi
  call   <__SSAT@plt>
  shl    $0x10,%eax
  movzwl %bp,%ebp
  or     %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SSAT16(int32_t x, const uint32_t y) {
  int32_t r = 0, s = 0;
  r = __SSAT((((int32_t)x << 16) >> 16), y) & (int32_t)0x0000FFFF;
  s = __SSAT((((int32_t)x) >> 16), y) & (int32_t)0x0000FFFF;
  return ((uint32_t)((s << 16) | (r)));
}
```
user: What is the c source code of the assembly code below:

```asm
<__SSAT16>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movswl %di,%edi
  sar    $0x10,%ebx
  call   <__SSAT@plt>
  mov    %ebx,%edi
  mov    %r12d,%esi
  mov    %eax,%ebp
  call   <__SSAT@plt>
  movzwl %bp,%ebp
  pop    %rbx
  shl    $0x10,%eax
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SSAT16(int32_t x, const uint32_t y) {
  int32_t r = 0, s = 0;
  r = __SSAT((((int32_t)x << 16) >> 16), y) & (int32_t)0x0000FFFF;
  s = __SSAT((((int32_t)x) >> 16), y) & (int32_t)0x0000FFFF;
  return ((uint32_t)((s << 16) | (r)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__SSAT16>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movswl %di,%edi
  sar    $0x10,%ebx
  call   <__SSAT@plt>
  mov    %ebx,%edi
  mov    %r12d,%esi
  mov    %eax,%ebp
  call   <__SSAT@plt>
  movzwl %bp,%ebp
  pop    %rbx
  shl    $0x10,%eax
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SSAT16(int32_t x, const uint32_t y) {
  int32_t r = 0, s = 0;
  r = __SSAT((((int32_t)x << 16) >> 16), y) & (int32_t)0x0000FFFF;
  s = __SSAT((((int32_t)x) >> 16), y) & (int32_t)0x0000FFFF;
  return ((uint32_t)((s << 16) | (r)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <write@plt>
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int putchar(int c) {
  char cc = c;
  write(0, &c, 1);
  return (unsigned char)c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putchar>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%edi
  call   <write@plt>
  movzbl 0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int putchar(int c) {
  char cc = c;
  write(0, &c, 1);
  return (unsigned char)c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putchar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  xor    %edi,%edi
  call   <write@plt>
  movzbl 0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int putchar(int c) {
  char cc = c;
  write(0, &c, 1);
  return (unsigned char)c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<putchar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  xor    %edi,%edi
  call   <write@plt>
  movzbl 0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int putchar(int c) {
  char cc = c;
  write(0, &c, 1);
  return (unsigned char)c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xyz_event_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
L3:
  nop
  leave
  ret
```

assistant: ```c
void xyz_event_destroy(struct xyz_event_t *ev) {
  if (ev) {
    free(ev);
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<xyz_event_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
void xyz_event_destroy(struct xyz_event_t *ev) {
  if (ev) {
    free(ev);
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xyz_event_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L8
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void xyz_event_destroy(struct xyz_event_t *ev) {
  if (ev) {
    free(ev);
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xyz_event_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void xyz_event_destroy(struct xyz_event_t *ev) {
  if (ev) {
    free(ev);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getrandom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L0:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x0,-0x4(%rbp)
  jg     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void getrandom(int n, int *d) {
  int i;
  d[0] = n;
  d[n] = 1;
  for (i = n - 1; i >= 1; i--)
    d[i] = rand() % 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getrandom>:
  endbr64
  mov    %edi,(%rsi)
  movslq %edi,%rax
  movl   $0x1,(%rsi,%rax,4)
  sub    $0x1,%edi
  test   %edi,%edi
  jle    L3
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  movslq %edi,%rbx
L15:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  ret
```

assistant: ```c
void getrandom(int n, int *d) {
  int i;
  d[0] = n;
  d[n] = 1;
  for (i = n - 1; i >= 1; i--)
    d[i] = rand() % 2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getrandom>:
  endbr64
  mov    %edi,(%rsi)
  movslq %edi,%rax
  sub    $0x1,%edi
  movl   $0x1,(%rsi,%rax,4)
  test   %edi,%edi
  jle    L3
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,(%rbx,%rbp,4)
  sub    $0x1,%rbp
  test   %ebp,%ebp
  jg     L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  ret
```

assistant: ```c
void getrandom(int n, int *d) {
  int i;
  d[0] = n;
  d[n] = 1;
  for (i = n - 1; i >= 1; i--)
    d[i] = rand() % 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<getrandom>:
  endbr64
  mov    %edi,(%rsi)
  movslq %edi,%rax
  sub    $0x1,%edi
  movl   $0x1,(%rsi,%rax,4)
  test   %edi,%edi
  jle    L15
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,(%rbx,%rbp,4)
  sub    $0x1,%rbp
  test   %ebp,%ebp
  jg     L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L15:
  ret
```

assistant: ```c
void getrandom(int n, int *d) {
  int i;
  d[0] = n;
  d[n] = 1;
  for (i = n - 1; i >= 1; i--)
    d[i] = rand() % 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<maxArea1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L4:
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L19
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
  jmp    L29
L19:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0x10(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L4
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int maxArea1(int *heights, int size) {
  int l = 0;
  int r = size - 1;
  int max = 0;
  while (l < r) {
    int len = r - l;
    int area = 0;
    if (heights[l] < heights[r]) {
      area = len * heights[l];
      max = max > area ? max : area;
      l++;
    } else {
      area = len * heights[r];
      max = max > area ? max : area;
      r--;
    }
  }
  return max;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<maxArea1>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L1
  mov    $0x0,%r8d
  mov    $0x0,%eax
  jmp    L5
L26:
  imul   %r9d,%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  sub    $0x1,%esi
L4:
  cmp    %esi,%eax
  jge    L24
L5:
  mov    %esi,%r9d
  sub    %eax,%r9d
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%ecx
  movslq %esi,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %edx,%ecx
  jge    L26
  imul   %r9d,%ecx
  cmp    %ecx,%r8d
  cmovl  %ecx,%r8d
  add    $0x1,%eax
  jmp    L4
L1:
  mov    $0x0,%r8d
L24:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxArea1(int *heights, int size) {
  int l = 0;
  int r = size - 1;
  int max = 0;
  while (l < r) {
    int len = r - l;
    int area = 0;
    if (heights[l] < heights[r]) {
      area = len * heights[l];
      max = max > area ? max : area;
      l++;
    } else {
      area = len * heights[r];
      max = max > area ? max : area;
      r--;
    }
  }
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<maxArea1>:
  endbr64
  sub    $0x1,%esi
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L14
  xor    %eax,%eax
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L16:
  imul   %r9d,%ecx
  cmp    %ecx,%r8d
  cmovl  %ecx,%r8d
  add    $0x1,%eax
  cmp    %eax,%esi
  jle    L14
L1:
  movslq %eax,%rdx
  mov    %esi,%r9d
  mov    (%rdi,%rdx,4),%ecx
  movslq %esi,%rdx
  sub    %eax,%r9d
  mov    (%rdi,%rdx,4),%edx
  cmp    %edx,%ecx
  jl     L16
  imul   %r9d,%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  sub    $0x1,%esi
  cmp    %eax,%esi
  jg     L1
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxArea1(int *heights, int size) {
  int l = 0;
  int r = size - 1;
  int max = 0;
  while (l < r) {
    int len = r - l;
    int area = 0;
    if (heights[l] < heights[r]) {
      area = len * heights[l];
      max = max > area ? max : area;
      l++;
    } else {
      area = len * heights[r];
      max = max > area ? max : area;
      r--;
    }
  }
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<maxArea1>:
  endbr64
  sub    $0x1,%esi
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L12
  xor    %ecx,%ecx
  xor    %r11d,%r11d
  nopl   0x0(%rax,%rax,1)
L30:
  movslq %esi,%r10
L27:
  mov    (%rdi,%r11,4),%edx
  mov    (%rdi,%r10,4),%eax
  mov    %esi,%r9d
  sub    %ecx,%r9d
  cmp    %edx,%eax
  jle    L29
  imul   %r9d,%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jge    L12
  movslq %ecx,%r11
  jmp    L27
  nopl   0x0(%rax)
L29:
  imul   %r9d,%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  sub    $0x1,%esi
  cmp    %ecx,%esi
  jg     L30
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxArea1(int *heights, int size) {
  int l = 0;
  int r = size - 1;
  int max = 0;
  while (l < r) {
    int len = r - l;
    int area = 0;
    if (heights[l] < heights[r]) {
      area = len * heights[l];
      max = max > area ? max : area;
      l++;
    } else {
      area = len * heights[r];
      max = max > area ? max : area;
      r--;
    }
  }
  return max;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <getPath@plt>
  test   %rax,%rax
  je     L16
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x80(%rbp)
  jmp    L18
L94:
  addq   $0x1,-0x80(%rbp)
L18:
  mov    -0x80(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L94
  jmp    L96
L61:
  mov    -0x80(%rbp),%rax
  cmp    -0x78(%rbp),%rax
  jne    L71
  mov    -0x90(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L109
L71:
  subq   $0x1,-0x80(%rbp)
L96:
  mov    -0x80(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L61
  jmp    L90
L78:
  mov    -0x80(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x90(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x80(%rbp)
  addq   $0x1,-0x90(%rbp)
L90:
  mov    -0x80(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
  mov    -0x90(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L109
L16:
  mov    -0x90(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L109:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int getType(char *header, char *result) {
  char temp[100];
  if (getPath(header, temp)) {
    char *p = temp;
    char *p2 = temp;
    while (*p2 != '\0') {
      p2++;
    }
    while (*p2 != '.') {
      if (p2 == p) {
        *result = '\0';
        return 0;
      }
      p2--;
    }
    while (*p2 != '\0') {
      *result = *p2;
      p2++;
      result++;
    }
    *result = '\0';
    return 1;
  } else {
    *result = '\0';
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getType>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <getPath@plt>
  test   %rax,%rax
  je     L38
  cmpb   $0x0,(%rsp)
  je     L72
  mov    %rsp,%rax
L10:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L10
  mov    %rsp,%rdx
  cmp    %rdx,%rax
  je     L72
L44:
  sub    $0x1,%rax
  cmpb   $0x2e,(%rax)
  je     L61
  cmp    %rdx,%rax
  jne    L44
L72:
  movb   $0x0,(%rbx)
  mov    $0x0,%eax
  jmp    L96
L38:
  movb   $0x0,(%rbx)
  mov    $0x0,%eax
L96:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L60
  add    $0x70,%rsp
  pop    %rbx
  ret
L61:
  movzbl (%rax),%edx
L22:
  mov    %dl,(%rbx)
  add    $0x1,%rax
  add    $0x1,%rbx
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L22
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
  jmp    L96
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getType(char *header, char *result) {
  char temp[100];
  if (getPath(header, temp)) {
    char *p = temp;
    char *p2 = temp;
    while (*p2 != '\0') {
      p2++;
    }
    while (*p2 != '.') {
      if (p2 == p) {
        *result = '\0';
        return 0;
      }
      p2--;
    }
    while (*p2 != '\0') {
      *result = *p2;
      p2++;
      result++;
    }
    *result = '\0';
    return 1;
  } else {
    *result = '\0';
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getType>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <getPath@plt>
  test   %rax,%rax
  je     L72
  cmpb   $0x0,(%rsp)
  je     L72
  mov    %rbp,%rax
  cs nopw 0x0(%rax,%rax,1)
L14:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L14
  nopl   0x0(%rax)
L57:
  cmp    %rbp,%rax
  je     L72
  movzbl -0x1(%rax),%edx
  sub    $0x1,%rax
  cmp    $0x2e,%dl
  jne    L57
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x1,%rax
  mov    %dl,(%rbx)
  add    $0x1,%rbx
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L36
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L72:
  movb   $0x0,(%rbx)
  xor    %eax,%eax
L62:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getType(char *header, char *result) {
  char temp[100];
  if (getPath(header, temp)) {
    char *p = temp;
    char *p2 = temp;
    while (*p2 != '\0') {
      p2++;
    }
    while (*p2 != '.') {
      if (p2 == p) {
        *result = '\0';
        return 0;
      }
      p2--;
    }
    while (*p2 != '\0') {
      *result = *p2;
      p2++;
      result++;
    }
    *result = '\0';
    return 1;
  } else {
    *result = '\0';
    return 0;
  }
}
```