ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<checkDrawCard>:
  endbr64
  sub    $0x8,%rsp
  call   <drawCard@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int checkDrawCard(int p, struct gameState *post) {
  int r;
  r = drawCard(p, post);
  assert(r == 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checkDrawCard>:
  endbr64
  sub    $0x8,%rsp
  call   <drawCard@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

assistant: ```c
int checkDrawCard(int p, struct gameState *post) {
  int r;
  r = drawCard(p, post);
  assert(r == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checkDrawCard>:
  endbr64
  sub    $0x8,%rsp
  call   <drawCard@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

assistant: ```c
int checkDrawCard(int p, struct gameState *post) {
  int r;
  r = drawCard(p, post);
  assert(r == 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int error = 0;
  if (error)
    abort();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int error = 0;
  if (error)
    abort();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int error = 0;
  if (error)
    abort();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int error = 0;
  if (error)
    abort();
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L20:
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L20
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: %f 

assistant: ```c
void print_data(float *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M; j++) {
      printf("%f ", dat[i * M + j]);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jle    L39
  mov    %edx,%r13d
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  lea    D0(%rip),%r12
  jmp    L41
L48:
  movslq %r15d,%rdx
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rdx,4),%rbx
  lea    -0x1(%r13),%eax
  add    %rdx,%rax
  lea    0x4(%rcx,%rax,4),%rbp
L36:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L36
L50:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r14d
  add    %r13d,%r15d
  cmp    %r14d,0x4(%rsp)
  je     L39
L41:
  test   %r13d,%r13d
  jg     L48
  jmp    L50
L39:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: %f 

assistant: ```c
void print_data(float *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M; j++) {
      printf("%f ", dat[i * M + j]);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jle    L6
  mov    %edx,%r12d
  xor    %r14d,%r14d
  lea    D6(%rip),%rbp
  xor    %r13d,%r13d
  nop
L2:
  test   %r12d,%r12d
  jle    L12
  mov    0x8(%rsp),%rdx
  movslq %r14d,%rcx
  lea    -0x1(%r12),%eax
  add    %rcx,%rax
  lea    (%rdx,%rcx,4),%r15
  lea    0x4(%rdx,%rax,4),%rbx
  xchg   %ax,%ax
L22:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x4,%r15
  cvtss2sd -0x4(%r15),%xmm0
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L22
L12:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    %r12d,%r14d
  call   <putchar@plt>
  cmp    %r13d,0x4(%rsp)
  jne    L2
L6:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string

tool: D6: %f 

assistant: ```c
void print_data(float *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M; j++) {
      printf("%f ", dat[i * M + j]);
    }
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jle    L8
  mov    %edx,%r12d
  xor    %r14d,%r14d
  lea    D8(%rip),%rbp
  xor    %r13d,%r13d
  nop
L38:
  test   %r12d,%r12d
  jle    L23
  mov    0x8(%rsp),%rdx
  movslq %r14d,%rcx
  lea    -0x1(%r12),%eax
  add    %rcx,%rax
  lea    (%rdx,%rcx,4),%r15
  lea    0x4(%rdx,%rax,4),%rbx
  xchg   %ax,%ax
L39:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x4,%r15
  cvtss2sd -0x4(%r15),%xmm0
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L39
L23:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    %r12d,%r14d
  call   <putchar@plt>
  cmp    %r13d,0x4(%rsp)
  jne    L38
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: %f 

assistant: ```c
void print_data(float *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M; j++) {
      printf("%f ", dat[i * M + j]);
    }
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<dqag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  movsd  %xmm2,-0x40(%rbp)
  movsd  %xmm3,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %r8,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%r9
  mov    -0x68(%rbp),%r8
  mov    -0x60(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  mov    -0x4c(%rbp),%esi
  movsd  -0x48(%rbp),%xmm2
  movsd  -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <dqage@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double dqag(double f(double), double a, double b, double epsabs, double epsrel, int irule, double *abserr, int *neval, int *ier) {
  double result;
  int last;
  result = dqage(f, a, b, epsabs, epsrel, irule, abserr, neval, ier, &last);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dqag>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r9
  call   <dqage@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double dqag(double f(double), double a, double b, double epsabs, double epsrel, int irule, double *abserr, int *neval, int *ier) {
  double result;
  int last;
  result = dqage(f, a, b, epsabs, epsrel, irule, abserr, neval, ier, &last);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dqag>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r9
  call   <dqage@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double dqag(double f(double), double a, double b, double epsabs, double epsrel, int irule, double *abserr, int *neval, int *ier) {
  double result;
  int last;
  result = dqage(f, a, b, epsabs, epsrel, irule, abserr, neval, ier, &last);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dqag>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r9
  call   <dqage@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double dqag(double f(double), double a, double b, double epsabs, double epsrel, int irule, double *abserr, int *neval, int *ier) {
  double result;
  int last;
  result = dqage(f, a, b, epsabs, epsrel, irule, abserr, neval, ier, &last);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<existence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <calc_fx@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <calc_fx@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L3
  mov    $0x1,%eax
  jmp    L4
L3:
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
int existence(double a, double b) {
  double fa = calc_fx(a);
  double fb = calc_fx(b);
  if (fa * fb < 0)
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<existence>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm1,%rbx
  call   <calc_fx@plt>
  movq   %xmm0,%r14
  movq   %rbx,%xmm0
  call   <calc_fx@plt>
  movq   %r14,%xmm2
  mulsd  %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
int existence(double a, double b) {
  double fa = calc_fx(a);
  double fb = calc_fx(b);
  if (fa * fb < 0)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<existence>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <calc_fx@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   <calc_fx@plt>
  mulsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  add    $0x18,%rsp
  ret
```

assistant: ```c
int existence(double a, double b) {
  double fa = calc_fx(a);
  double fb = calc_fx(b);
  if (fa * fb < 0)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<existence>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <calc_fx@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   <calc_fx@plt>
  mulsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  add    $0x18,%rsp
  ret
```

assistant: ```c
int existence(double a, double b) {
  double fa = calc_fx(a);
  double fb = calc_fx(b);
  if (fa * fb < 0)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<num_of_conflicts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L71
L13:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L49
L85:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L81
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%esi
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  add    %esi,%eax
  cmp    %eax,%edx
  je     L81
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  cmp    %eax,%edx
  jne    L66
L81:
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x38(%rbp)
L66:
  addl   $0x1,-0x14(%rbp)
L49:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L85
  addq   $0x4,-0x38(%rbp)
  addl   $0x1,-0x18(%rbp)
L71:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L13
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L24:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L69
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
L69:
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L24
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int num_of_conflicts(int state[], int k, int column, int *conflicts) {
  int *start_of_conflicts = conflicts;
  for (int i = 0; i < k; i++) {
    for (int j = i + 1; j < k; j++) {
      if ((state[j] == state[i]) || (state[j] == state[i] + abs(i - j)) || (state[j] == state[i] - abs(i - j))) {
        *(conflicts++);
      }
    }
    conflicts++;
  }
  int lowest = INT_MAX;
  for (int i = 0; i < k; i++) {
    if (*start_of_conflicts < lowest)
      lowest = *(conflicts++);
  }
  return lowest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<num_of_conflicts>:
  endbr64
  test   %esi,%esi
  jle    L80
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %esi,%r9d
  mov    %rcx,%rbp
  lea    -0x1(%rsi),%r12d
  mov    %rcx,%r8
  mov    $0x1,%ebx
  mov    $0x0,%r11d
  jmp    L12
L61:
  add    $0x4,%r8
L60:
  add    $0x1,%rax
  cmp    %eax,%r9d
  jle    L106
L51:
  mov    (%r10,%rax,4),%edx
  cmp    %edi,%edx
  je     L61
  mov    %r11d,%esi
  sub    %eax,%esi
  mov    %esi,%ecx
  neg    %ecx
  cmovs  %esi,%ecx
  lea    (%rdi,%rcx,1),%esi
  cmp    %esi,%edx
  je     L61
  mov    %edi,%esi
  sub    %ecx,%esi
  cmp    %esi,%edx
  jne    L60
  jmp    L61
L129:
  add    $0x1,%eax
  cmp    %eax,%r9d
  je     L19
L68:
  cmp    %edx,%ecx
  jge    L129
  mov    (%r8),%edx
  lea    0x4(%r8),%r8
  jmp    L129
L80:
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  ret
L64:
  add    $0x4,%r8
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    0x0(%rbp),%ecx
  mov    $0x0,%eax
  jmp    L68
L106:
  add    $0x4,%r8
  add    $0x1,%r11
  add    $0x1,%rbx
L12:
  cmp    %r12,%r11
  je     L64
  mov    (%r10,%r11,4),%edi
  mov    %rbx,%rax
  jmp    L51
L19:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int num_of_conflicts(int state[], int k, int column, int *conflicts) {
  int *start_of_conflicts = conflicts;
  for (int i = 0; i < k; i++) {
    for (int j = i + 1; j < k; j++) {
      if ((state[j] == state[i]) || (state[j] == state[i] + abs(i - j)) || (state[j] == state[i] - abs(i - j))) {
        *(conflicts++);
      }
    }
    conflicts++;
  }
  int lowest = INT_MAX;
  for (int i = 0; i < k; i++) {
    if (*start_of_conflicts < lowest)
      lowest = *(conflicts++);
  }
  return lowest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<num_of_conflicts>:
  endbr64
  mov    D9(%rip),%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rax),%r12d
  test   %esi,%esi
  jle    L22
  lea    -0x1(%rsi),%r13d
  xor    %r11d,%r11d
  mov    %rdi,%r10
  mov    %esi,%r9d
  mov    %rcx,%rbp
  mov    %rcx,%r8
  mov    $0x1,%ebx
  cmp    %r13,%r11
  je     L50
  nopl   0x0(%rax)
L102:
  mov    (%r10,%r11,4),%edi
  mov    %rbx,%rax
  jmp    L4
  nopl   0x0(%rax)
L15:
  mov    %r11d,%esi
  sub    %eax,%esi
  mov    %esi,%ecx
  neg    %ecx
  cmovs  %esi,%ecx
  lea    (%rdi,%rcx,1),%esi
  cmp    %esi,%edx
  je     L8
  mov    %edi,%esi
  sub    %ecx,%esi
  cmp    %esi,%edx
  je     L8
  add    $0x1,%rax
  cmp    %eax,%r9d
  jle    L55
L4:
  mov    (%r10,%rax,4),%edx
  cmp    %edi,%edx
  jne    L15
L8:
  add    $0x1,%rax
  add    $0x4,%r8
  cmp    %eax,%r9d
  jg     L4
L55:
  add    $0x1,%r11
  add    $0x4,%r8
  add    $0x1,%rbx
  cmp    %r13,%r11
  jne    L102
L50:
  mov    0x0(%rbp),%edx
  add    $0x4,%r8
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L38:
  cmp    %r12d,%edx
  jge    L79
  mov    (%r8),%r12d
  add    $0x4,%r8
L79:
  add    $0x1,%eax
  cmp    %eax,%r9d
  jne    L38
L22:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int num_of_conflicts(int state[], int k, int column, int *conflicts) {
  int *start_of_conflicts = conflicts;
  for (int i = 0; i < k; i++) {
    for (int j = i + 1; j < k; j++) {
      if ((state[j] == state[i]) || (state[j] == state[i] + abs(i - j)) || (state[j] == state[i] - abs(i - j))) {
        *(conflicts++);
      }
    }
    conflicts++;
  }
  int lowest = INT_MAX;
  for (int i = 0; i < k; i++) {
    if (*start_of_conflicts < lowest)
      lowest = *(conflicts++);
  }
  return lowest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<num_of_conflicts>:
  endbr64
  mov    D1(%rip),%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rax),%r12d
  test   %esi,%esi
  jle    L121
  mov    %esi,%r10d
  mov    %rcx,%rbp
  cmp    $0x1,%esi
  je     L20
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r13d
  mov    %rcx,%r8
  mov    $0x1,%ebx
  xor    %r11d,%r11d
  nopl   (%rax)
L72:
  mov    (%r9,%r11,4),%edi
  mov    %rbx,%rax
  jmp    L47
  nopl   0x0(%rax)
L74:
  mov    %r11d,%esi
  sub    %eax,%esi
  mov    %esi,%ecx
  neg    %ecx
  cmovs  %esi,%ecx
  lea    (%rdi,%rcx,1),%esi
  cmp    %esi,%edx
  je     L105
  mov    %edi,%esi
  sub    %ecx,%esi
  cmp    %esi,%edx
  je     L105
  add    $0x1,%rax
  cmp    %eax,%r10d
  jle    L29
L47:
  mov    (%r9,%rax,4),%edx
  cmp    %edx,%edi
  jne    L74
L105:
  add    $0x1,%rax
  add    $0x4,%r8
  cmp    %eax,%r10d
  jg     L47
L29:
  add    $0x1,%r11
  add    $0x4,%r8
  add    $0x1,%rbx
  cmp    %r13,%r11
  jne    L72
L63:
  mov    0x0(%rbp),%edx
  add    $0x4,%r8
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L111:
  cmp    %r12d,%edx
  jl     L19
L121:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%eax
  mov    (%r8),%r12d
  lea    0x4(%r8),%rcx
  cmp    %eax,%r10d
  je     L121
  mov    %rcx,%r8
  jmp    L111
L20:
  mov    %rcx,%r8
  jmp    L63
```

assistant: ```c
int num_of_conflicts(int state[], int k, int column, int *conflicts) {
  int *start_of_conflicts = conflicts;
  for (int i = 0; i < k; i++) {
    for (int j = i + 1; j < k; j++) {
      if ((state[j] == state[i]) || (state[j] == state[i] + abs(i - j)) || (state[j] == state[i] - abs(i - j))) {
        *(conflicts++);
      }
    }
    conflicts++;
  }
  int lowest = INT_MAX;
  for (int i = 0; i < k; i++) {
    if (*start_of_conflicts < lowest)
      lowest = *(conflicts++);
  }
  return lowest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L26
L34:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jns    L65
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L13
L65:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L50
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L13
L50:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L77
L21:
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L77:
  cmpl   $0x1,-0x14(%rbp)
  jg     L21
  mov    -0x18(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L26:
  mov    -0x18(%rbp),%eax
  cmp    $0xffffffff,%eax
  jne    L34
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L85
  call   <__stack_chk_fail@plt>
L85:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D61
data_type: string
name: unpack_data
arguments: data_label: D62
data_type: string
name: unpack_data
arguments: data_label: D23
data_type: string
name: unpack_data
arguments: data_label: D18
data_type: string
name: unpack_data
arguments: data_label: D78
data_type: string
name: unpack_data
arguments: data_label: D77
data_type: string

tool: D61: Programdan cikmak icin -1 giriniz.

tool: D62: Faktoriyeli hesaplanacak pozitif tam sayiyi giriniz:

tool: D23: %d

tool: D18: Girdiginiz sayi pozitif bir tam sayi degildir.

tool: D78: 0 sayisinin faktoriyeli 1 dir.

tool: D77: Girdiginiz %d sayisinin faktoriyeli %ld dir.


assistant: ```c
int main() {
  int sayi, ara_deger;
  long int faktoriyel;
  printf("Programdan cikmak icin -1 giriniz.\n");
  printf("Faktoriyeli hesaplanacak pozitif tam sayiyi giriniz:");
  scanf("%d", &sayi);
  while (sayi != -1) {
    if (sayi < 0) {
      printf("Girdiginiz sayi pozitif bir tam sayi degildir.\n");
    } else if (sayi == 0) {
      printf("0 sayisinin faktoriyeli 1 dir.\n");
    } else {
      ara_deger = sayi;
      faktoriyel = 1;
      while (ara_deger > 1) {
        faktoriyel = faktoriyel * ara_deger;
        ara_deger--;
      }
      printf("Girdiginiz %d sayisinin faktoriyeli %ld dir.\n", sayi, faktoriyel);
    }
    printf("Faktoriyeli hesaplanacak pozitif tam sayiyi giriniz:");
    scanf("%d", &sayi);
  }
  return 0;
}
```