ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_nl>:
  endbr64
  mov    $0x1,%eax
  xor    %ecx,%ecx
L12:
  cmpb   $0xa,-0x1(%rdi,%rax,1)
  je     L33
L38:
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L12
  xor    %eax,%eax
  cmp    $0x4,%ecx
  sete   %al
  ret
  nopl   (%rax)
L33:
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  jbe    L10
  xor    %eax,%eax
  ret
L10:
  add    $0x1,%ecx
  jmp    L38
```

assistant: ```c
int check_nl(char *str) {
  int n_l;
  int i;
  n_l = 0;
  i = 0;
  while (i < 20) {
    if (str[i] == '\n') {
      if (!((i + 1) % 5))
        n_l++;
      else
        return (0);
    }
    i++;
  }
  if (n_l == 4)
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x1c(%rbp)
  lea    -0x18(%rbp),%rax
  mov    $0x200,%edx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <posix_memalign@plt>
  test   %rax,%rax
  je     L4
  mov    $0x0,%eax
  jmp    L0
L4:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x1c(%rbp),%xmm1
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int foo(float *p) {
  int res = *p;
  int *q;
  void *tem;
  if (posix_memalign(&tem, 128, 128 * sizeof(int)) != 0)
    return 0;
  q = (int *)tem;
  *q = 1;
  return res + *p;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%ebp
  mov    %rsp,%rdi
  mov    $0x200,%edx
  mov    $0x80,%esi
  call   <posix_memalign@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L19
  mov    (%rsp),%rax
  movl   $0x1,(%rax)
  movd   %ebp,%xmm1
  cvttss2si %xmm1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  (%rbx),%xmm0
  cvttss2si %xmm0,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(float *p) {
  int res = *p;
  int *q;
  void *tem;
  if (posix_memalign(&tem, 128, 128 * sizeof(int)) != 0)
    return 0;
  q = (int *)tem;
  *q = 1;
  return res + *p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    $0x200,%edx
  mov    %rdi,%rbx
  mov    $0x80,%esi
  sub    $0x20,%rsp
  movss  (%rdi),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movss  %xmm1,0xc(%rsp)
  call   <posix_memalign@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L13
  mov    0x10(%rsp),%rax
  pxor   %xmm0,%xmm0
  movl   $0x1,(%rax)
  cvttss2si 0xc(%rsp),%eax
  cvtsi2ss %eax,%xmm0
  addss  (%rbx),%xmm0
  cvttss2si %xmm0,%eax
L13:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(float *p) {
  int res = *p;
  int *q;
  void *tem;
  if (posix_memalign(&tem, 128, 128 * sizeof(int)) != 0)
    return 0;
  q = (int *)tem;
  *q = 1;
  return res + *p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    $0x200,%edx
  mov    %rdi,%rbx
  mov    $0x80,%esi
  sub    $0x20,%rsp
  movss  (%rdi),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movss  %xmm1,0xc(%rsp)
  call   <posix_memalign@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L4
  mov    0x10(%rsp),%rax
  pxor   %xmm0,%xmm0
  movl   $0x1,(%rax)
  cvttss2si 0xc(%rsp),%eax
  cvtsi2ss %eax,%xmm0
  addss  (%rbx),%xmm0
  cvttss2si %xmm0,%eax
L4:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(float *p) {
  int res = *p;
  int *q;
  void *tem;
  if (posix_memalign(&tem, 128, 128 * sizeof(int)) != 0)
    return 0;
  q = (int *)tem;
  *q = 1;
  return res + *p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<num_ending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  add    $0x2,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x50(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L52:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L52
L21:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L16
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L16:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x54(%rbp),%eax
  add    $0x1,%eax
  mov    -0x48(%rbp),%rdx
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x78(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x78(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x68(%rbp),%rax
  mov    -0x40(%rbp),%rcx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   *%rcx
  mov    -0x68(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L40
L1:
  mov    -0x58(%rbp),%eax
  or     $0x30,%eax
  mov    %eax,%ecx
  mov    -0x48(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  mov    -0x78(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x48(%rbp),%rax
  mov    -0x40(%rbp),%rcx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   *%rcx
  addl   $0x1,-0x58(%rbp)
L40:
  cmpl   $0x9,-0x58(%rbp)
  jle    L1
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void num_ending(char *pass, int cnt, void **nxt_f) {
  int lpass = strlen(pass);
  char pass_new[lpass + 2];
  pass_new[lpass] = 0x00;
  pass_new[lpass + 1] = 0x00;
  void (*func)(char *pass, int cnt, void **nxt_f) = *nxt_f;
  func(pass, 0, nxt_f + 1);
  strcpy(pass_new, pass);
  int i;
  for (i = 0; i < 10; i++) {
    pass_new[lpass] = (unsigned char)(i | 0x30);
    func(pass_new, 0, nxt_f + 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_ending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    0x2(%rax),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L34:
  cmp    %rdx,%rsp
  je     L44
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L34
L44:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L18
  orq    $0x0,-0x8(%rsp,%rax,1)
L18:
  mov    %rsp,%r12
  movslq %r13d,%rax
  movb   $0x0,(%rsp,%rax,1)
  lea    0x1(%r13),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    (%r14),%r15
  add    $0x8,%r14
  mov    %r14,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   *%r15
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    $0x0,%ebx
  movslq %r13d,%r13
L5:
  mov    %ebx,%eax
  or     $0x30,%eax
  mov    %al,(%r12,%r13,1)
  mov    %r14,%rdx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   *%r15
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L5
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void num_ending(char *pass, int cnt, void **nxt_f) {
  int lpass = strlen(pass);
  char pass_new[lpass + 2];
  pass_new[lpass] = 0x00;
  pass_new[lpass + 1] = 0x00;
  void (*func)(char *pass, int cnt, void **nxt_f) = *nxt_f;
  func(pass, 0, nxt_f + 1);
  strcpy(pass_new, pass);
  int i;
  for (i = 0; i < 10; i++) {
    pass_new[lpass] = (unsigned char)(i | 0x30);
    func(pass_new, 0, nxt_f + 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_ending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    0x2(%rax),%edx
  movslq %edx,%rdx
  add    $0xf,%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L57
L51:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L51
L57:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L59
L52:
  movslq %eax,%r15
  add    $0x1,%eax
  mov    0x0(%r13),%r14
  add    $0x8,%r13
  cltq
  mov    %rbx,%rdi
  movb   $0x0,(%rsp,%r15,1)
  mov    %r13,%rdx
  movb   $0x0,(%rsp,%rax,1)
  xor    %esi,%esi
  mov    %rsp,%r12
  call   *%r14
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  xor    %ebx,%ebx
  call   <strcpy@plt>
  nopl   0x0(%rax)
L7:
  mov    %ebx,%eax
  add    $0x1,%ebx
  mov    %r13,%rdx
  xor    %esi,%esi
  or     $0x30,%eax
  mov    %r12,%rdi
  mov    %al,(%r12,%r15,1)
  call   *%r14
  cmp    $0xa,%ebx
  jne    L7
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L52
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void num_ending(char *pass, int cnt, void **nxt_f) {
  int lpass = strlen(pass);
  char pass_new[lpass + 2];
  pass_new[lpass] = 0x00;
  pass_new[lpass + 1] = 0x00;
  void (*func)(char *pass, int cnt, void **nxt_f) = *nxt_f;
  func(pass, 0, nxt_f + 1);
  strcpy(pass_new, pass);
  int i;
  for (i = 0; i < 10; i++) {
    pass_new[lpass] = (unsigned char)(i | 0x30);
    func(pass_new, 0, nxt_f + 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<num_ending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    0x2(%rax),%edx
  movslq %edx,%rdx
  add    $0xf,%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L57
L35:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L35
L57:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L26
L7:
  movslq %eax,%r15
  add    $0x1,%eax
  mov    0x0(%r13),%r14
  add    $0x8,%r13
  cltq
  mov    %rbx,%rdi
  movb   $0x0,(%rsp,%r15,1)
  mov    %r13,%rdx
  movb   $0x0,(%rsp,%rax,1)
  xor    %esi,%esi
  mov    %rsp,%r12
  call   *%r14
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  xor    %ebx,%ebx
  call   <strcpy@plt>
  nopl   0x0(%rax)
L32:
  mov    %ebx,%eax
  add    $0x1,%ebx
  mov    %r13,%rdx
  xor    %esi,%esi
  or     $0x30,%eax
  mov    %r12,%rdi
  mov    %al,(%r12,%r15,1)
  call   *%r14
  cmp    $0xa,%ebx
  jne    L32
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L7
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void num_ending(char *pass, int cnt, void **nxt_f) {
  int lpass = strlen(pass);
  char pass_new[lpass + 2];
  pass_new[lpass] = 0x00;
  pass_new[lpass + 1] = 0x00;
  void (*func)(char *pass, int cnt, void **nxt_f) = *nxt_f;
  func(pass, 0, nxt_f + 1);
  strcpy(pass_new, pass);
  int i;
  for (i = 0; i < 10; i++) {
    pass_new[lpass] = (unsigned char)(i | 0x30);
    func(pass_new, 0, nxt_f + 1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D53(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L59:
  cmp    %rcx,%rsp
  je     L81
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L59
L81:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L92
  orq    $0x0,-0x8(%rsp,%rax,1)
L92:
  mov    %rsp,%r13
  test   %edx,%edx
  jle    L86
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D53(%rip),%r14
L54:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x2c(%rbp)
  jg     L54
L86:
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  test   %edx,%edx
  jle    L93
  mov    $0x0,%ebx
  lea    D40(%rip),%r12
L3:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jg     L3
L93:
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <mergesort@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x2c(%rbp)
  jle    L89
  mov    $0x0,%ebx
  lea    D40(%rip),%r12
L31:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,-0x2c(%rbp)
  jg     L31
L89:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D53
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string
name: disassemble_data
arguments: data_tag: D40
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D53: %d

tool: D16: 
 Unsorted Array

tool: D40:   %d,

tool: D5: 
 Sorted Array:

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int arr[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("\n Unsorted Array");
  for (int i = 0; i < n; i++) {
    printf("  %d,", arr[i]);
  }
  mergesort(arr, 0, n);
  printf("\n Sorted Array:");
  for (int i = 0; i < n; i++) {
    printf("  %d,", arr[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D36(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L18
L95:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L95
L18:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L14
L4:
  mov    %rsp,%r13
  test   %ecx,%ecx
  jle    L101
  mov    %r13,%r12
  xor    %ebx,%ebx
  nop
L17:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L17
L101:
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  test   %edx,%edx
  jle    L79
  xor    %ebx,%ebx
  lea    D16(%rip),%r12
  nopl   (%rax)
L49:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  cmp    %ebx,%edx
  jg     L49
L79:
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <mergesort@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L64
  xor    %ebx,%ebx
  lea    D16(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L27:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L27
L64:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L14:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L4
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D36
data_type: string
name: unpack_data
arguments: data_label: D42
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string
name: unpack_data
arguments: data_label: D23
data_type: string

tool: D36: %d

tool: D42: 
 Unsorted Array

tool: D16:   %d,

tool: D23: 
 Sorted Array:

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int arr[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("\n Unsorted Array");
  for (int i = 0; i < n; i++) {
    printf("  %d,", arr[i]);
  }
  mergesort(arr, 0, n);
  printf("\n Sorted Array:");
  for (int i = 0; i < n; i++) {
    printf("  %d,", arr[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D44(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L69
L85:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L85
L69:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L62
L28:
  mov    %rsp,%r13
  test   %ecx,%ecx
  jle    L14
  mov    %r13,%r12
  xor    %ebx,%ebx
  nop
L48:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L48
L14:
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  test   %edx,%edx
  jle    L61
  xor    %ebx,%ebx
  lea    D41(%rip),%r12
  nopl   (%rax)
L10:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  cmp    %ebx,%edx
  jg     L10
L61:
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <mergesort@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L96
  xor    %ebx,%ebx
  lea    D41(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L101:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L101
L96:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L62:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L28
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D44
type_infered: string
name: unpack_data
arguments: data_label: D39
type_infered: string
name: unpack_data
arguments: data_label: D41
type_infered: string
name: unpack_data
arguments: data_label: D23
type_infered: string

tool: D44: %d

tool: D39: 
 Unsorted Array

tool: D41:   %d,

tool: D23: 
 Sorted Array:

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int arr[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("\n Unsorted Array");
  for (int i = 0; i < n; i++) {
    printf("  %d,", arr[i]);
  }
  mergesort(arr, 0, n);
  printf("\n Sorted Array:");
  for (int i = 0; i < n; i++) {
    printf("  %d,", arr[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<rcu_blocking_is_gp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <might_sleep@plt>
  mov    $0x0,%eax
  call   <preempt_disable@plt>
  mov    $0x0,%eax
  call   <num_online_cpus@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <preempt_enable@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rcu_blocking_is_gp(void) {
  int ret;
  might_sleep();
  preempt_disable();
  ret = num_online_cpus() == 1;
  preempt_enable();
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rcu_blocking_is_gp>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <might_sleep@plt>
  mov    $0x0,%eax
  call   <preempt_disable@plt>
  mov    $0x0,%eax
  call   <num_online_cpus@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <preempt_enable@plt>
  cmp    $0x1,%ebx
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rcu_blocking_is_gp(void) {
  int ret;
  might_sleep();
  preempt_disable();
  ret = num_online_cpus() == 1;
  preempt_enable();
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rcu_blocking_is_gp>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <might_sleep@plt>
  xor    %eax,%eax
  call   <preempt_disable@plt>
  xor    %eax,%eax
  call   <num_online_cpus@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <preempt_enable@plt>
  xor    %eax,%eax
  cmp    $0x1,%ebx
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
int rcu_blocking_is_gp(void) {
  int ret;
  might_sleep();
  preempt_disable();
  ret = num_online_cpus() == 1;
  preempt_enable();
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rcu_blocking_is_gp>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <might_sleep@plt>
  xor    %eax,%eax
  call   <preempt_disable@plt>
  xor    %eax,%eax
  call   <num_online_cpus@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <preempt_enable@plt>
  xor    %eax,%eax
  cmp    $0x1,%ebx
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
int rcu_blocking_is_gp(void) {
  int ret;
  might_sleep();
  preempt_disable();
  ret = num_online_cpus() == 1;
  preempt_enable();
  return ret;
}
```