ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x44(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D25(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  lea    -0x40(%rbp),%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x44(%rbp),%eax
  mov    %rsp,%rsi
  imul   %eax,%eax
  movslq %eax,%rdx
  lea    0xf(,%rdx,8),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L93
L29:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L29
L93:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L67
L7:
  lea    0x7(%rsp),%rbx
  mov    %rbx,%r13
  and    $0xfffffffffffffff8,%rbx
  shr    $0x3,%r13
  test   %eax,%eax
  je     L45
  mov    %rbx,%r15
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %r15,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <scanf@plt>
  mov    -0x44(%rbp),%eax
  add    $0x8,%r15
  imul   %eax,%eax
  cltq
  cmp    %r14,%rax
  jg     L51
L105:
  mov    0x0(,%r13,8),%rdx
  mov    -0x40(%rbp),%rcx
  cmp    %rdx,%rcx
  jl     L37
  add    $0x8,%rbx
  lea    (%rbx,%rax,8),%rax
  jmp    L104
  nopl   (%rax)
L75:
  cmp    %rax,%rbx
  je     L37
  mov    (%rbx),%rdx
  add    $0x8,%rbx
  cmp    %rcx,%rdx
  jg     L37
L104:
  cmp    %rdx,%rcx
  jne    L75
  lea    D4(%rip),%rdi
  call   <printf@plt>
L77:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L77
L67:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L7
L45:
  xor    %eax,%eax
  jmp    L105
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D14
type_guessed: string

tool: D25: %d

tool: D5: %ld

tool: D4: YES

tool: D14: NO

assistant: ```c
main() {
  long int i, j = 0, n, l = 0;
  int m;
  scanf("%d", &m);
  scanf("%ld", &n);
  long int a[m * m];
  for (i = 0; i < (m * m); i++)
    scanf("%d", &a[i]);
  for (i = 0; a[i] <= n; i++) {
    if (a[i] == n) {
      printf("YES");
      l = 1;
      break;
    }
    if (i == m * m)
      break;
  }
  if (l != 1)
    printf("NO");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<two_loops_symb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0xa,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L28:
  mov    $0x0,%eax
  call   <nop@plt>
  addl   $0x1,-0xc(%rbp)
L36:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L28
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L15:
  mov    $0x0,%eax
  call   <nop@plt>
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int two_loops_symb(int m) {
  int p = 10;
  for (int i = 0; i < m; i++) {
    nop();
  }
  for (int j = 0; j < m; j++) {
    nop();
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<two_loops_symb>:
  endbr64
  test   %edi,%edi
  jle    L27
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x0,%ebx
L2:
  mov    $0x0,%eax
  call   <nop@plt>
  mov    %ebx,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L2
  mov    $0x0,%ebx
L28:
  mov    $0x0,%eax
  call   <nop@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L28
  mov    $0xa,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  mov    $0xa,%eax
  ret
```

assistant: ```c
int two_loops_symb(int m) {
  int p = 10;
  for (int i = 0; i < m; i++) {
    nop();
  }
  for (int j = 0; j < m; j++) {
    nop();
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<two_loops_symb>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  mov    %ebx,%ebp
  lea    0x1(%rbx),%ebx
  call   <nop@plt>
  cmp    %ebx,%r12d
  jne    L1
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <nop@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L5
  pop    %rbx
  mov    $0xa,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0xa,%eax
  ret
```

assistant: ```c
int two_loops_symb(int m) {
  int p = 10;
  for (int i = 0; i < m; i++) {
    nop();
  }
  for (int j = 0; j < m; j++) {
    nop();
  }
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<two_loops_symb>:
  endbr64
  test   %edi,%edi
  jle    L21
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  mov    %ebx,%ebp
  lea    0x1(%rbx),%ebx
  call   <nop@plt>
  cmp    %ebx,%r12d
  jne    L8
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  call   <nop@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L26
  pop    %rbx
  mov    $0xa,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    $0xa,%eax
  ret
```

assistant: ```c
int two_loops_symb(int m) {
  int p = 10;
  for (int i = 0; i < m; i++) {
    nop();
  }
  for (int j = 0; j < m; j++) {
    nop();
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<delete_cmdline_parser_required>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int delete_cmdline_parser_required(struct delete_args_info *args_info, const char *prog_name) {
  (void)(args_info);
  (void)(prog_name);
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delete_cmdline_parser_required>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int delete_cmdline_parser_required(struct delete_args_info *args_info, const char *prog_name) {
  (void)(args_info);
  (void)(prog_name);
  return EXIT_SUCCESS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delete_cmdline_parser_required>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int delete_cmdline_parser_required(struct delete_args_info *args_info, const char *prog_name) {
  (void)(args_info);
  (void)(prog_name);
  return EXIT_SUCCESS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<delete_cmdline_parser_required>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int delete_cmdline_parser_required(struct delete_args_info *args_info, const char *prog_name) {
  (void)(args_info);
  (void)(prog_name);
  return EXIT_SUCCESS;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<base26toInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L47:
  cmpb   $0x40,-0x5(%rbp)
  jle    L6
  cmpb   $0x5a,-0x5(%rbp)
  jle    L37
L6:
  mov    $0xffffffff,%eax
  jmp    L9
L37:
  mov    -0x4(%rbp),%eax
  imul   $0x1a,%eax,%edx
  movsbl -0x5(%rbp),%eax
  sub    $0x41,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jg     L47
  mov    -0x4(%rbp),%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int base26toInt(char *buffer) {
  char c;
  int result = 0;
  while ((c = *buffer++) > 0) {
    if (c < 'A' || 'Z' < c)
      return -1;
    result = result * 26 + (c - 'A');
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<base26toInt>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  jle    L5
  mov    $0x0,%eax
L28:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L3
  imul   $0x1a,%eax,%eax
  movsbl %dl,%edx
  lea    -0x41(%rax,%rdx,1),%eax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jg     L28
  ret
L5:
  mov    $0x0,%eax
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int base26toInt(char *buffer) {
  char c;
  int result = 0;
  while ((c = *buffer++) > 0) {
    if (c < 'A' || 'Z' < c)
      return -1;
    result = result * 26 + (c - 'A');
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<base26toInt>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  xor    %eax,%eax
  test   %dl,%dl
  jg     L39
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L34:
  imul   $0x1a,%eax,%eax
  movsbl %dl,%edx
  add    $0x1,%rcx
  add    %edx,%eax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jle    L8
L39:
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L34
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  ret
L28:
  ret
```

assistant: ```c
int base26toInt(char *buffer) {
  char c;
  int result = 0;
  while ((c = *buffer++) > 0) {
    if (c < 'A' || 'Z' < c)
      return -1;
    result = result * 26 + (c - 'A');
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<base26toInt>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  xor    %eax,%eax
  test   %dl,%dl
  jg     L12
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L26:
  imul   $0x1a,%eax,%eax
  movsbl %dl,%edx
  add    $0x1,%rcx
  add    %edx,%eax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jle    L37
L12:
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L26
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  ret
L25:
  ret
```

assistant: ```c
int base26toInt(char *buffer) {
  char c;
  int result = 0;
  while ((c = *buffer++) > 0) {
    if (c < 'A' || 'Z' < c)
      return -1;
    result = result * 26 + (c - 'A');
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initmask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %r8,-0x38(%rbp)
  mov    $0x80000000,%r14d
  lea    0x1(%rdx),%r12d
  mov    -0x38(%rbp),%rdx
  movl   $0x0,(%rdx)
  mov    $0x0,%ebx
  jmp    L91
L84:
  mov    -0x38(%rbp),%rdx
  mov    (%rdx),%edx
  mov    %r14d,%edi
  mov    %ebx,%ecx
  shr    %cl,%edi
  mov    %edi,%ecx
  or     %edx,%ecx
  mov    -0x38(%rbp),%rdx
  mov    %ecx,(%rdx)
  add    $0x1,%ebx
L91:
  cmp    %r12d,%ebx
  jl     L84
  mov    -0x38(%rbp),%rdx
  mov    (%rdx),%esi
  mov    %eax,%edx
  sub    %r12d,%edx
  mov    %edx,%ecx
  shr    %cl,%esi
  mov    %esi,%ecx
  mov    -0x38(%rbp),%rdx
  mov    %ecx,(%rdx)
  mov    $0x0,%ebx
  jmp    L56
L7:
  movslq %ebx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  cmp    $0x5e,%dl
  je     L83
  movslq %ebx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  cmp    $0x24,%dl
  jne    L49
L83:
  movslq %ebx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movb   $0xa,(%rdx)
L49:
  add    $0x1,%ebx
L56:
  cmp    %eax,%ebx
  jl     L7
  mov    $0x0,%ebx
  jmp    L32
L51:
  movslq %ebx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movl   $0xffffffff,(%rdx)
  add    $0x1,%ebx
L32:
  cmp    $0xff,%ebx
  jle    L51
  mov    $0x0,%ebx
  jmp    L50
L65:
  movslq %ebx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%r13d
  mov    $0x0,%r12d
  jmp    L33
L18:
  movslq %r12d,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  cmp    %edx,%r13d
  jne    L117
  mov    %r13d,%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%esi
  mov    %r14d,%edx
  mov    %r12d,%ecx
  shr    %cl,%edx
  mov    %edx,%ecx
  not    %ecx
  mov    %r13d,%edx
  lea    0x0(,%rdx,4),%rdi
  mov    -0x30(%rbp),%rdx
  add    %rdi,%rdx
  and    %esi,%ecx
  mov    %ecx,(%rdx)
L117:
  add    $0x1,%r12d
L33:
  cmp    %eax,%r12d
  jl     L18
  add    $0x1,%ebx
L50:
  cmp    %eax,%ebx
  jl     L65
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
void initmask(pattern, Mask, m, D, endposition) unsigned char *pattern;
unsigned *Mask;
register int m, D;
unsigned *endposition;
{
  register unsigned Bit1, c;
  register int i, j, frag_num;
  Bit1 = (unsigned)0x80000000;
  frag_num = D + 1;
  *endposition = 0;
  for (i = 0; i < frag_num; i++)
    *endposition = *endposition | (Bit1 >> i);
  *endposition = *endposition >> (m - frag_num);
  for (i = 0; i < m; i++)
    if (pattern[i] == '^' || pattern[i] == '$') {
      pattern[i] = '\n';
    }
  for (i = 0; i < 256; i++)
    Mask[i] = ~0;
  for (i = 0; i < m; i++) {
    c = pattern[i];
    for (j = 0; j < m; j++)
      if (c == pattern[j])
        Mask[c] = Mask[c] & ~(Bit1 >> j);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<initmask>:
  endbr64
  push   %rbx
  mov    %rsi,%r9
  mov    %edx,%esi
  lea    0x1(%rcx),%ebx
  movl   $0x0,(%r8)
  test   %ebx,%ebx
  jle    L82
  mov    %ebx,%r10d
  mov    $0x0,%eax
  mov    $0x0,%ecx
  mov    $0x80000000,%r11d
L4:
  mov    %r11d,%edx
  shr    %cl,%edx
  or     %edx,%eax
  add    $0x1,%ecx
  cmp    %r10d,%ecx
  jne    L4
  mov    %eax,(%r8)
L82:
  mov    %esi,%ecx
  sub    %ebx,%ecx
  shrl   %cl,(%r8)
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%r8
  jmp    L85
L153:
  movb   $0xa,(%rcx)
L43:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L17
L85:
  mov    %rax,%rcx
  movzbl (%rax),%edx
  cmp    $0x5e,%dl
  je     L153
  cmp    $0x24,%dl
  jne    L43
  jmp    L153
L17:
  mov    %r9,%rax
  lea    0x400(%r9),%rdx
L136:
  movl   $0xffffffff,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L136
  test   %esi,%esi
  jle    L66
  mov    %rdi,%r10
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbx
  mov    %esi,%esi
  mov    $0x80000000,%r11d
  jmp    L54
L81:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  je     L156
L119:
  cmp    (%rdi,%rcx,1),%dl
  jne    L81
  mov    %r11d,%eax
  shr    %cl,%eax
  not    %eax
  and    %eax,(%r8)
  jmp    L81
L156:
  add    $0x1,%r10
  cmp    %rbx,%r10
  je     L66
L54:
  movzbl (%r10),%edx
  movzbl %dl,%eax
  lea    (%r9,%rax,4),%r8
  mov    $0x0,%ecx
  jmp    L119
L66:
  pop    %rbx
  ret
```

assistant: ```c
void initmask(pattern, Mask, m, D, endposition) unsigned char *pattern;
unsigned *Mask;
register int m, D;
unsigned *endposition;
{
  register unsigned Bit1, c;
  register int i, j, frag_num;
  Bit1 = (unsigned)0x80000000;
  frag_num = D + 1;
  *endposition = 0;
  for (i = 0; i < frag_num; i++)
    *endposition = *endposition | (Bit1 >> i);
  *endposition = *endposition >> (m - frag_num);
  for (i = 0; i < m; i++)
    if (pattern[i] == '^' || pattern[i] == '$') {
      pattern[i] = '\n';
    }
  for (i = 0; i < 256; i++)
    Mask[i] = ~0;
  for (i = 0; i < m; i++) {
    c = pattern[i];
    for (j = 0; j < m; j++)
      if (c == pattern[j])
        Mask[c] = Mask[c] & ~(Bit1 >> j);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initmask>:
  endbr64
  mov    %rsi,%r10
  mov    %edx,%esi
  push   %rbx
  lea    0x1(%rcx),%eax
  mov    %esi,%ebx
  mov    %rdi,%r9
  sub    %eax,%ebx
  test   %eax,%eax
  jle    L47
  mov    %ecx,%edi
  xor    %eax,%eax
  xor    %ecx,%ecx
  mov    $0x80000000,%r11d
  nopl   0x0(%rax,%rax,1)
L35:
  mov    %r11d,%edx
  shr    %cl,%edx
  or     %edx,%eax
  mov    %ecx,%edx
  add    $0x1,%ecx
  cmp    %edx,%edi
  jne    L35
  mov    %ebx,%ecx
  shr    %cl,%eax
  mov    %eax,(%r8)
  test   %esi,%esi
  jle    L63
L3:
  lea    -0x1(%rsi),%ecx
  lea    0x1(%r9),%rbx
  mov    %r9,%rax
  mov    %rcx,%r11
  add    %rbx,%rcx
  jmp    L90
  nopl   0x0(%rax)
L98:
  cmp    $0x24,%dl
  je     L45
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L103
L90:
  movzbl (%rax),%edx
  cmp    $0x5e,%dl
  jne    L98
L45:
  movb   $0xa,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L90
L103:
  lea    0x8(%r10),%rdi
  mov    %r10,%rcx
  add    %r11,%rbx
  mov    %r9,%r8
  and    $0xfffffffffffffff8,%rdi
  mov    $0xffffffffffffffff,%rax
  movq   $0xffffffffffffffff,(%r10)
  mov    $0x80000000,%r11d
  movq   $0xffffffffffffffff,0x3f8(%r10)
  sub    %rdi,%rcx
  add    $0x400,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L59:
  movzbl (%r8),%eax
  xor    %ecx,%ecx
  mov    %rax,%rdx
  lea    (%r10,%rax,4),%rdi
  nopl   (%rax)
L82:
  cmp    (%r9,%rcx,1),%dl
  jne    L85
  mov    %r11d,%eax
  shr    %cl,%eax
  not    %eax
  and    %eax,(%rdi)
L85:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L82
  add    $0x1,%r8
  cmp    %r8,%rbx
  jne    L59
  pop    %rbx
  ret
L47:
  xor    %eax,%eax
  mov    %eax,(%r8)
  test   %esi,%esi
  jg     L3
L63:
  lea    0x8(%r10),%rdi
  mov    %r10,%rcx
  mov    $0xffffffffffffffff,%rax
  movq   $0xffffffffffffffff,(%r10)
  movq   $0xffffffffffffffff,0x3f8(%r10)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0x400,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  pop    %rbx
  ret
```

assistant: ```c
void initmask(pattern, Mask, m, D, endposition) unsigned char *pattern;
unsigned *Mask;
register int m, D;
unsigned *endposition;
{
  register unsigned Bit1, c;
  register int i, j, frag_num;
  Bit1 = (unsigned)0x80000000;
  frag_num = D + 1;
  *endposition = 0;
  for (i = 0; i < frag_num; i++)
    *endposition = *endposition | (Bit1 >> i);
  *endposition = *endposition >> (m - frag_num);
  for (i = 0; i < m; i++)
    if (pattern[i] == '^' || pattern[i] == '$') {
      pattern[i] = '\n';
    }
  for (i = 0; i < 256; i++)
    Mask[i] = ~0;
  for (i = 0; i < m; i++) {
    c = pattern[i];
    for (j = 0; j < m; j++)
      if (c == pattern[j])
        Mask[c] = Mask[c] & ~(Bit1 >> j);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<initmask>:
  endbr64
  mov    %rsi,%r10
  mov    %edx,%esi
  push   %rbx
  lea    0x1(%rcx),%eax
  mov    %esi,%ebx
  mov    %rdi,%r9
  sub    %eax,%ebx
  test   %eax,%eax
  jle    L78
  mov    %ecx,%edi
  xor    %eax,%eax
  xor    %ecx,%ecx
  mov    $0x80000000,%r11d
  nopl   0x0(%rax,%rax,1)
L50:
  mov    %r11d,%edx
  shr    %cl,%edx
  or     %edx,%eax
  mov    %ecx,%edx
  add    $0x1,%ecx
  cmp    %edx,%edi
  jne    L50
  mov    %ebx,%ecx
  shr    %cl,%eax
  mov    %eax,(%r8)
  test   %esi,%esi
  jle    L3
L6:
  lea    -0x1(%rsi),%ecx
  lea    0x1(%r9),%rbx
  mov    %r9,%rax
  mov    %rcx,%r11
  add    %rbx,%rcx
  jmp    L23
  nopl   0x0(%rax)
L82:
  cmp    $0x24,%dl
  je     L71
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L117
L23:
  movzbl (%rax),%edx
  cmp    $0x5e,%dl
  jne    L82
L71:
  movb   $0xa,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L23
L117:
  lea    0x8(%r10),%rdi
  mov    %r10,%rcx
  add    %r11,%rbx
  mov    %r9,%r8
  and    $0xfffffffffffffff8,%rdi
  mov    $0xffffffffffffffff,%rax
  movq   $0xffffffffffffffff,(%r10)
  mov    $0x80000000,%r11d
  movq   $0xffffffffffffffff,0x3f8(%r10)
  sub    %rdi,%rcx
  add    $0x400,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L42:
  movzbl (%r8),%eax
  xor    %ecx,%ecx
  mov    %rax,%rdx
  lea    (%r10,%rax,4),%rdi
  nopl   (%rax)
L103:
  cmp    (%r9,%rcx,1),%dl
  jne    L101
  mov    %r11d,%eax
  shr    %cl,%eax
  not    %eax
  and    %eax,(%rdi)
L101:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L103
  add    $0x1,%r8
  cmp    %r8,%rbx
  jne    L42
  pop    %rbx
  ret
L78:
  xor    %eax,%eax
  mov    %eax,(%r8)
  test   %esi,%esi
  jg     L6
L3:
  lea    0x8(%r10),%rdi
  mov    %r10,%rcx
  mov    $0xffffffffffffffff,%rax
  movq   $0xffffffffffffffff,(%r10)
  movq   $0xffffffffffffffff,0x3f8(%r10)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0x400,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  pop    %rbx
  ret
```

assistant: ```c
void initmask(pattern, Mask, m, D, endposition) unsigned char *pattern;
unsigned *Mask;
register int m, D;
unsigned *endposition;
{
  register unsigned Bit1, c;
  register int i, j, frag_num;
  Bit1 = (unsigned)0x80000000;
  frag_num = D + 1;
  *endposition = 0;
  for (i = 0; i < frag_num; i++)
    *endposition = *endposition | (Bit1 >> i);
  *endposition = *endposition >> (m - frag_num);
  for (i = 0; i < m; i++)
    if (pattern[i] == '^' || pattern[i] == '$') {
      pattern[i] = '\n';
    }
  for (i = 0; i < 256; i++)
    Mask[i] = ~0;
  for (i = 0; i < m; i++) {
    c = pattern[i];
    for (j = 0; j < m; j++)
      if (c == pattern[j])
        Mask[c] = Mask[c] & ~(Bit1 >> j);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_list_swap_null_params>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <list_swap@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L1
  movl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
bool test_list_swap_null_params(void) {
  bool pass = false;
  unsigned int res = list_swap(0, 1, NULL);
  if (res == 1) {
    pass = true;
  }
  return pass;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_list_swap_null_params>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <list_swap@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool test_list_swap_null_params(void) {
  bool pass = false;
  unsigned int res = list_swap(0, 1, NULL);
  if (res == 1) {
    pass = true;
  }
  return pass;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_list_swap_null_params>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <list_swap@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool test_list_swap_null_params(void) {
  bool pass = false;
  unsigned int res = list_swap(0, 1, NULL);
  if (res == 1) {
    pass = true;
  }
  return pass;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_list_swap_null_params>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <list_swap@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool test_list_swap_null_params(void) {
  bool pass = false;
  unsigned int res = list_swap(0, 1, NULL);
  if (res == 1) {
    pass = true;
  }
  return pass;
}
```