ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_char>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <luaL_resetbuffer@plt>
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %ebp,%edi
  call   <luaL_addchar@plt>
L36:
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <lua_lua2C@plt>
  test   %rax,%rax
  je     L0
  mov    %ebx,%edi
  call   <luaL_check_number@plt>
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%ebp
  movzbl %bpl,%ebp
  cvtsi2sd %ebp,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L20
  je     L24
L20:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <luaL_argerror@plt>
  jmp    L24
  nopl   0x0(%rax)
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10b0 <closeandpush@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0: invalid value

assistant: ```c
void str_char(void) {
  int i = 0;
  luaL_resetbuffer();
  while (lua_lua2C(++i) != 0) {
    double c = luaL_check_number(i);
    if (!((unsigned char)c == c))
      luaL_argerror(i, "invalid value");
    luaL_addchar((unsigned char)c);
  }
  closeandpush();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_mtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  mov    $0x0,%eax
  jmp    L29
L8:
  mov    -0xc(%rbp),%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
time_t get_mtime(const char *path) {
  struct stat statbuf;
  if (stat(path, &statbuf) == -1) {
    return 0;
  }
  return statbuf.st_mtime;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_mtime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  cmovne 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t get_mtime(const char *path) {
  struct stat statbuf;
  if (stat(path, &statbuf) == -1) {
    return 0;
  }
  return statbuf.st_mtime;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_mtime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  cmovne 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t get_mtime(const char *path) {
  struct stat statbuf;
  if (stat(path, &statbuf) == -1) {
    return 0;
  }
  return statbuf.st_mtime;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_mtime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  cmovne 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t get_mtime(const char *path) {
  struct stat statbuf;
  if (stat(path, &statbuf) == -1) {
    return 0;
  }
  return statbuf.st_mtime;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timespec_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  mov    %eax,%eax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L49
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L8
L49:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L8:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L45
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  jmp    L65
L45:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdx,%xmm1
  addsd  %xmm1,%xmm1
L65:
  movsd  D10(%rip),%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x3b9ac9ff,%eax
  jbe    L48
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L11
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L35
L11:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L35:
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
L48:
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: f64
name: parse_data
arguments: tag: D9
type_infered: f64

tool: D10: 1000000

tool: D9: 1000000000

assistant: ```c
void timespec_add(struct timespec *tp, unsigned int ms) {
  tp->tv_sec += ms / 1000;
  tp->tv_nsec += (ms % 1000) * 1e6;
  if (tp->tv_nsec >= 1e9) {
    tp->tv_nsec -= 1e9;
    tp->tv_sec++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<timespec_add>:
  endbr64
  mov    %esi,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,%ecx
  add    0x8(%rdi),%rcx
  mov    %rcx,0x8(%rdi)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D15(%rip),%xmm0
  mov    (%rdi),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  cmp    $0x3b9ac9ff,%eax
  ja     L6
  mov    %eax,(%rdi)
  ret
L6:
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  subsd  D5(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,(%rdi)
  add    $0x1,%rcx
  mov    %rcx,0x8(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
data_type: f64
name: extract_symbolic_data
arguments: tag: D5
data_type: f64

tool: D15: 1000000

tool: D5: 1000000000

assistant: ```c
void timespec_add(struct timespec *tp, unsigned int ms) {
  tp->tv_sec += ms / 1000;
  tp->tv_nsec += (ms % 1000) * 1e6;
  if (tp->tv_nsec >= 1e9) {
    tp->tv_nsec -= 1e9;
    tp->tv_sec++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<timespec_add>:
  endbr64
  mov    %esi,%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,%ecx
  imul   $0x3e8,%eax,%eax
  add    0x8(%rdi),%rcx
  mov    %rcx,0x8(%rdi)
  sub    %eax,%esi
  mov    (%rdi),%eax
  cvtsi2sd %esi,%xmm0
  mulsd  D15(%rip),%xmm0
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  cmp    $0x3b9ac9ff,%eax
  ja     L4
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L4:
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  add    $0x1,%rcx
  cvtsi2sd %rax,%xmm0
  subsd  D13(%rip),%xmm0
  mov    %rcx,0x8(%rdi)
  cvttsd2si %xmm0,%rax
  mov    %eax,(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_infered: f64
name: extract_symbolic_data
arguments: label: D13
type_infered: f64

tool: D15: 1000000

tool: D13: 1000000000

assistant: ```c
void timespec_add(struct timespec *tp, unsigned int ms) {
  tp->tv_sec += ms / 1000;
  tp->tv_nsec += (ms % 1000) * 1e6;
  if (tp->tv_nsec >= 1e9) {
    tp->tv_nsec -= 1e9;
    tp->tv_sec++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timespec_add>:
  endbr64
  mov    %esi,%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,%ecx
  imul   $0x3e8,%eax,%eax
  add    0x8(%rdi),%rcx
  mov    %rcx,0x8(%rdi)
  sub    %eax,%esi
  mov    (%rdi),%eax
  cvtsi2sd %esi,%xmm0
  mulsd  D3(%rip),%xmm0
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  cmp    $0x3b9ac9ff,%eax
  ja     L5
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L5:
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  add    $0x1,%rcx
  cvtsi2sd %rax,%xmm0
  subsd  D4(%rip),%xmm0
  mov    %rcx,0x8(%rdi)
  cvttsd2si %xmm0,%rax
  mov    %eax,(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: f64
name: parse_data
arguments: data_label: D4
type: f64

tool: D3: 1000000

tool: D4: 1000000000

assistant: ```c
void timespec_add(struct timespec *tp, unsigned int ms) {
  tp->tv_sec += ms / 1000;
  tp->tv_nsec += (ms % 1000) * 1e6;
  if (tp->tv_nsec >= 1e9) {
    tp->tv_nsec -= 1e9;
    tp->tv_sec++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L12
L7:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ltrim(const char *str) {
  while (isspace(*str))
    str++;
  return (char *)str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ltrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L7
L15:
  add    $0x1,%rbx
L7:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ltrim(const char *str) {
  while (isspace(*str))
    str++;
  return (char *)str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x1,%r12
L6:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(const char *str) {
  while (isspace(*str))
    str++;
  return (char *)str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%r12
L1:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(const char *str) {
  while (isspace(*str))
    str++;
  return (char *)str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rend_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
L23:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L23
  jmp    L2
L38:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L16
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L16:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
L2:
  cmpl   $0xa,-0x8(%rbp)
  je     L27
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L38
L27:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rend_line(char str[], int n) {
  int ch, i = 0;
  while (isspace(ch = getchar()))
    ;
  while (ch != '\n' && ch != EOF) {
    if (i < n) {
      str[i++] = ch;
    }
    ch = getchar();
  }
  str[i] = '\0';
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rend_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%r12d
L12:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
  mov    $0x0,%ebp
  cmp    $0xa,%ebx
  je     L3
  mov    D0(%rip),%r14
  jmp    L26
L3:
  mov    $0x0,%ebp
L48:
  movslq %ebp,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L48
L26:
  cmp    %ebx,(%r14)
  je     L48
  cmp    %ebp,%r12d
  jle    L15
  movslq %ebp,%rax
  mov    %bl,0x0(%r13,%rax,1)
  lea    0x1(%rbp),%ebp
  jmp    L15
```

assistant: ```c
int rend_line(char str[], int n) {
  int ch, i = 0;
  while (isspace(ch = getchar()))
    ;
  while (ch != '\n' && ch != EOF) {
    if (i < n) {
      str[i++] = ch;
    }
    ch = getchar();
  }
  str[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rend_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L47:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L47
  mov    %r12,%rax
  xor    %r15d,%r15d
  cmp    $0xa,%ebx
  je     L53
  mov    D5(%rip),%r14
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  jmp    L39
  xchg   %ax,%ax
L12:
  cmp    %r15d,%r13d
  jle    L20
  mov    %bl,(%rax)
  add    $0x1,%r15d
  movslq %r15d,%rbp
L20:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L1
L39:
  lea    (%r12,%rbp,1),%rax
  cmp    %ebx,(%r14)
  jne    L12
L53:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    (%r12,%rbp,1),%rax
  jmp    L53
```

assistant: ```c
int rend_line(char str[], int n) {
  int ch, i = 0;
  while (isspace(ch = getchar()))
    ;
  while (ch != '\n' && ch != EOF) {
    if (i < n) {
      str[i++] = ch;
    }
    ch = getchar();
  }
  str[i] = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rend_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L30
  mov    %rbp,%rax
  xor    %r14d,%r14d
  cmp    $0xa,%ebx
  je     L7
  mov    D8(%rip),%r13
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  nopl   (%rax)
L29:
  lea    0x0(%rbp,%r15,1),%rax
  cmp    %ebx,0x0(%r13)
  je     L7
  cmp    %r14d,%r12d
  jle    L47
  mov    %bl,(%rax)
  xor    %eax,%eax
  add    $0x1,%r14d
  movslq %r14d,%r15
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  jne    L29
  lea    0x0(%rbp,%r15,1),%rax
L7:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L47:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  jne    L29
  lea    0x0(%rbp,%r15,1),%rax
  jmp    L7
```

assistant: ```c
int rend_line(char str[], int n) {
  int ch, i = 0;
  while (isspace(ch = getchar()))
    ;
  while (ch != '\n' && ch != EOF) {
    if (i < n) {
      str[i++] = ch;
    }
    ch = getchar();
  }
  str[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L12
L7:
  mov    -0x10(%rbp),%eax
  sub    $0x3,%eax
  mov    %eax,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  jg     L7
  movl   $0x0,-0xc(%rbp)
  jmp    L40
L35:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  addl   $0x1,-0xc(%rbp)
L40:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L35
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D72
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D69
datatype: string
name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D50
datatype: string
name: retrieve_data
arguments: data_tag: D56
datatype: string

tool: D72:  Enter the 1st Number: 

tool: D2: %d

tool: D69:  Enter the 2nd Number: 

tool: D9:  Enter the 3rd Number: 

tool: D50:  Times of Rotation: 

tool: D56:  %d %d %d 

assistant: ```c
int main() {
  int a, b, c, n, count;
  printf(" Enter the 1st Number: \n");
  scanf("%d", &a);
  printf(" Enter the 2nd Number: \n");
  scanf("%d", &b);
  printf(" Enter the 3rd Number: \n");
  scanf("%d", &c);
  printf(" Times of Rotation: \n");
  scanf("%d", &n);
  while (n > 3)
    n = n - 3;
  for (count = 0; count < n; count++)
    rotr(&a, &b, &c);
  printf(" %d %d %d ", a, b, c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D57(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  jle    L26
L36:
  sub    $0x3,%eax
  cmp    $0x3,%eax
  jg     L36
  mov    %eax,0x14(%rsp)
L26:
  cmpl   $0x0,0x14(%rsp)
  jle    L47
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rbp
L25:
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  call   <rotr@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jg     L25
L47:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D57
datatype: string
name: read_data
arguments: tag: D1
datatype: string
name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D38
datatype: string
name: read_data
arguments: tag: D22
datatype: string

tool: D11:  Enter the 1st Number: 

tool: D57: %d

tool: D1:  Enter the 2nd Number: 

tool: D0:  Enter the 3rd Number: 

tool: D38:  Times of Rotation: 

tool: D22:  %d %d %d 

assistant: ```c
int main() {
  int a, b, c, n, count;
  printf(" Enter the 1st Number: \n");
  scanf("%d", &a);
  printf(" Enter the 2nd Number: \n");
  scanf("%d", &b);
  printf(" Enter the 3rd Number: \n");
  scanf("%d", &c);
  printf(" Times of Rotation: \n");
  scanf("%d", &n);
  while (n > 3)
    n = n - 3;
  for (count = 0; count < n; count++)
    rotr(&a, &b, &c);
  printf(" %d %d %d ", a, b, c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%rdi
  lea    D48(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0xc(%rsp),%r12
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  jle    L42
  nopl   (%rax)
L49:
  sub    $0x3,%eax
  cmp    $0x3,%eax
  jg     L49
  mov    %eax,0x14(%rsp)
L16:
  xor    %ebx,%ebx
  xchg   %ax,%ax
L28:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L28
L53:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  test   %eax,%eax
  jle    L53
  jmp    L16
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D48
type_guessed: string
name: extract_symbolic_data
arguments: label: D59
type_guessed: string
name: extract_symbolic_data
arguments: label: D10
type_guessed: string
name: extract_symbolic_data
arguments: label: D49
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D22:  Enter the 1st Number: 

tool: D48: %d

tool: D59:  Enter the 2nd Number: 

tool: D10:  Enter the 3rd Number: 

tool: D49:  Times of Rotation: 

tool: D19:  %d %d %d 

assistant: ```c
int main() {
  int a, b, c, n, count;
  printf(" Enter the 1st Number: \n");
  scanf("%d", &a);
  printf(" Enter the 2nd Number: \n");
  scanf("%d", &b);
  printf(" Enter the 3rd Number: \n");
  scanf("%d", &c);
  printf(" Times of Rotation: \n");
  scanf("%d", &n);
  while (n > 3)
    n = n - 3;
  for (count = 0; count < n; count++)
    rotr(&a, &b, &c);
  printf(" %d %d %d ", a, b, c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fb_pixel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fb_pixel(unsigned short *fbmem, int w, int x, int y, int color) {
  unsigned short *pos;
  pos = fbmem + y * w + x;
  *pos = color;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fb_pixel>:
  endbr64
  imul   %esi,%ecx
  movslq %ecx,%rcx
  movslq %edx,%rdx
  add    %rdx,%rcx
  mov    %r8w,(%rdi,%rcx,2)
  ret
```

assistant: ```c
void fb_pixel(unsigned short *fbmem, int w, int x, int y, int color) {
  unsigned short *pos;
  pos = fbmem + y * w + x;
  *pos = color;
}
```