ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D23(%rip),%r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L17:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L10:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L10
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L17
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
type_infered: string
name: disassemble_data
arguments: label: D3
type_infered: string
name: disassemble_data
arguments: label: D1
type_infered: string

tool: D23: dsumkbn

tool: D3: # c::%s:len=%d


tool: D1: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsumkbn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L23:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L42
  cmpl   $0x5f,-0x4(%rbp)
  je     L42
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L28
L42:
  cmpl   $0x13,-0x8(%rbp)
  jle    L23
L28:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *readname(char *arg, char name[]) {
  int i = 0;
  int c;
  while ((isalpha(c = *arg) || c == '_' || isdigit(c)) && i < 20) {
    name[i++] = c;
    arg++;
  }
  name[i] = '\0';
  return arg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readname>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    $0x0,%ebx
  jmp    L14
L12:
  cmp    $0x14,%rbx
  je     L41
  mov    %r13b,(%r15,%rbx,1)
  add    $0x1,%r12
  add    $0x1,%rbx
L14:
  mov    %ebx,%r14d
  movzbl (%r12),%r13d
  movsbl %r13b,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  cmp    $0x5f,%ebp
  je     L12
  test   %rax,%rax
  jne    L12
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L12
L41:
  movslq %r14d,%r14
  movb   $0x0,(%r15,%r14,1)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *readname(char *arg, char name[]) {
  int i = 0;
  int c;
  while ((isalpha(c = *arg) || c == '_' || isdigit(c)) && i < 20) {
    name[i++] = c;
    arg++;
  }
  name[i] = '\0';
  return arg;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readname>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L20
  nopl   0x0(%rax)
L19:
  cmp    $0x14,%rbx
  je     L26
  mov    %r15b,(%r12,%rbx,1)
  add    $0x1,%r14
  add    $0x1,%rbx
L20:
  movsbl (%r14),%ebp
  mov    %ebp,%edi
  mov    %ebp,%r15d
  call   <isalpha@plt>
  cmp    $0x5f,%ebp
  je     L19
  test   %rax,%rax
  jne    L19
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L19
  movslq %ebx,%rbx
L26:
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *readname(char *arg, char name[]) {
  int i = 0;
  int c;
  while ((isalpha(c = *arg) || c == '_' || isdigit(c)) && i < 20) {
    name[i++] = c;
    arg++;
  }
  name[i] = '\0';
  return arg;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readname>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L41
  nopl   0x0(%rax)
L29:
  cmp    $0x14,%rbx
  je     L44
  mov    %r15b,(%r12,%rbx,1)
  add    $0x1,%r14
  add    $0x1,%rbx
L41:
  movsbl (%r14),%ebp
  mov    %ebp,%edi
  mov    %ebp,%r15d
  call   <isalpha@plt>
  cmp    $0x5f,%ebp
  je     L29
  test   %rax,%rax
  jne    L29
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L29
  movslq %ebx,%rbx
L44:
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *readname(char *arg, char name[]) {
  int i = 0;
  int c;
  while ((isalpha(c = *arg) || c == '_' || isdigit(c)) && i < 20) {
    name[i++] = c;
    arg++;
  }
  name[i] = '\0';
  return arg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calc_tcp_csum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x18(%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  cltq
  sub    $0x20,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L5
  lea    D7(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <error@plt>
L5:
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <htons@plt>
  add    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <htons@plt>
  add    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  shr    %rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <calc_csum@plt>
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string

tool: D7: odd length: csum needs padding

assistant: ```c
uint16_t calc_tcp_csum(struct iphdr *iph, struct tcphdr *tcph) {
  unsigned long sum = 0, tcplen;
  tcplen = ntohs(iph->tot_len) - sizeof(*iph);
  if (tcplen & 1)
    error(1, 0, "odd length: csum needs padding");
  sum += iph->daddr;
  sum += iph->saddr;
  sum += htons(iph->protocol);
  sum += htons(tcplen);
  return calc_csum(sum, (void *)tcph, tcplen >> 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<calc_tcp_csum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    0x18(%rdi),%edi
  call   <ntohs@plt>
  cltq
  lea    -0x20(%rax),%rbp
  test   $0x1,%al
  jne    L11
L1:
  mov    0x8(%rbx),%r13
  add    0x10(%rbx),%r13
  mov    (%rbx),%rdi
  call   <htons@plt>
  add    %rax,%r13
  mov    %rbp,%rdi
  call   <htons@plt>
  mov    %rbp,%rdx
  shr    %rdx
  lea    (%rax,%r13,1),%rdi
  mov    %r12,%rsi
  call   <calc_csum@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  lea    D1(%rip),%rdx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <error@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: odd length: csum needs padding

assistant: ```c
uint16_t calc_tcp_csum(struct iphdr *iph, struct tcphdr *tcph) {
  unsigned long sum = 0, tcplen;
  tcplen = ntohs(iph->tot_len) - sizeof(*iph);
  if (tcplen & 1)
    error(1, 0, "odd length: csum needs padding");
  sum += iph->daddr;
  sum += iph->saddr;
  sum += htons(iph->protocol);
  sum += htons(tcplen);
  return calc_csum(sum, (void *)tcph, tcplen >> 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calc_tcp_csum>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x18(%rdi),%edi
  call   <ntohs@plt>
  cltq
  lea    -0x20(%rax),%rbp
  test   $0x1,%al
  jne    L9
L14:
  mov    (%rbx),%rdi
  mov    0x8(%rbx),%r13
  add    0x10(%rbx),%r13
  call   <htons@plt>
  mov    %rbp,%rdi
  add    %rax,%r13
  call   <htons@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdx
  mov    %r12,%rsi
  pop    %rbx
  lea    (%rax,%r13,1),%rdi
  pop    %rbp
  shr    %rdx
  pop    %r12
  pop    %r13
  jmp    1080 <calc_csum@plt>
  nopl   (%rax)
L9:
  lea    D7(%rip),%rdx
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <error@plt>
  jmp    L14
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: odd length: csum needs padding

assistant: ```c
uint16_t calc_tcp_csum(struct iphdr *iph, struct tcphdr *tcph) {
  unsigned long sum = 0, tcplen;
  tcplen = ntohs(iph->tot_len) - sizeof(*iph);
  if (tcplen & 1)
    error(1, 0, "odd length: csum needs padding");
  sum += iph->daddr;
  sum += iph->saddr;
  sum += htons(iph->protocol);
  sum += htons(tcplen);
  return calc_csum(sum, (void *)tcph, tcplen >> 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calc_tcp_csum>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x18(%rdi),%edi
  call   <ntohs@plt>
  cltq
  lea    -0x20(%rax),%rbp
  test   $0x1,%al
  jne    L8
L5:
  mov    (%rbx),%rdi
  mov    0x8(%rbx),%r13
  add    0x10(%rbx),%r13
  call   <htons@plt>
  mov    %rbp,%rdi
  add    %rax,%r13
  call   <htons@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdx
  mov    %r12,%rsi
  pop    %rbx
  lea    (%rax,%r13,1),%rdi
  pop    %rbp
  shr    %rdx
  pop    %r12
  pop    %r13
  jmp    1080 <calc_csum@plt>
  nopl   (%rax)
L8:
  lea    D5(%rip),%rdx
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <error@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: odd length: csum needs padding

assistant: ```c
uint16_t calc_tcp_csum(struct iphdr *iph, struct tcphdr *tcph) {
  unsigned long sum = 0, tcplen;
  tcplen = ntohs(iph->tot_len) - sizeof(*iph);
  if (tcplen & 1)
    error(1, 0, "odd length: csum needs padding");
  sum += iph->daddr;
  sum += iph->saddr;
  sum += htons(iph->protocol);
  sum += htons(tcplen);
  return calc_csum(sum, (void *)tcph, tcplen >> 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readlinka>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L27
L17:
  mov    -0x20(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  shlq   -0x20(%rbp)
L27:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <readlink@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jae    L17
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L8
L7:
  nop
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
char *readlinka(char const *path) {
  size_t buflen = BUFSIZ;
  char *buf = malloc(buflen);
  ssize_t read;
  while ((read = readlink(path, buf, buflen - 1)) >= buflen - 1) {
    char *newbuf = realloc(buf, buflen * 2);
    if (newbuf == NULL) {
      goto failure;
    }
    buf = newbuf;
    buflen = buflen * 2;
  }
  buf[read] = '\0';
  return buf;
failure:
  free(buf);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<readlinka>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    D0(%rip),%rax
  mov    (%rax),%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
L1:
  lea    -0x1(%rbp),%rbx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <readlink@plt>
  cmp    %rax,%rbx
  ja     L5
  add    %rbp,%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L31
  mov    %rax,%r12
  jmp    L1
L31:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbx,%r12
  jmp    L7
L5:
  movb   $0x0,(%r12,%rax,1)
L7:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *readlinka(char const *path) {
  size_t buflen = BUFSIZ;
  char *buf = malloc(buflen);
  ssize_t read;
  while ((read = readlink(path, buf, buflen - 1)) >= buflen - 1) {
    char *newbuf = realloc(buf, buflen * 2);
    if (newbuf == NULL) {
      goto failure;
    }
    buf = newbuf;
    buflen = buflen * 2;
  }
  buf[read] = '\0';
  return buf;
failure:
  free(buf);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<readlinka>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L20:
  add    %rbx,%rbx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L24
  mov    %rax,%r12
L15:
  lea    -0x1(%rbx),%r13
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %r13,%rdx
  call   <readlink@plt>
  cmp    %rax,%r13
  jbe    L20
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *readlinka(char const *path) {
  size_t buflen = BUFSIZ;
  char *buf = malloc(buflen);
  ssize_t read;
  while ((read = readlink(path, buf, buflen - 1)) >= buflen - 1) {
    char *newbuf = realloc(buf, buflen * 2);
    if (newbuf == NULL) {
      goto failure;
    }
    buf = newbuf;
    buflen = buflen * 2;
  }
  buf[read] = '\0';
  return buf;
failure:
  free(buf);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readlinka>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L27:
  add    %rbx,%rbx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%r12
L4:
  lea    -0x1(%rbx),%r13
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %r13,%rdx
  call   <readlink@plt>
  cmp    %rax,%r13
  jbe    L27
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *readlinka(char const *path) {
  size_t buflen = BUFSIZ;
  char *buf = malloc(buflen);
  ssize_t read;
  while ((read = readlink(path, buf, buflen - 1)) >= buflen - 1) {
    char *newbuf = realloc(buf, buflen * 2);
    if (newbuf == NULL) {
      goto failure;
    }
    buf = newbuf;
    buflen = buflen * 2;
  }
  buf[read] = '\0';
  return buf;
failure:
  free(buf);
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<fibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L32
  mov    $0x1,%eax
  jmp    L4
L32:
  cmpl   $0x1,-0x14(%rbp)
  jne    L26
  mov    $0x1,%eax
  jmp    L4
L26:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibonacci>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibonacci>
  add    %ebx,%eax
L4:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibonacci(int n) {
  if (n == 0) {
    return 1;
  } else if (n == 1) {
    return 1;
  } else {
    return fibonacci(n - 1) + fibonacci(n - 2);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fibonacci>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  ja     L9
  ret
L9:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fibonacci>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fibonacci>
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fibonacci(int n) {
  if (n == 0) {
    return 1;
  } else if (n == 1) {
    return 1;
  } else {
    return fibonacci(n - 1) + fibonacci(n - 2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L20:
  addl   $0x1,-0x4(%rbp)
L1:
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
L18:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ft_strlen(char *str) {
  int i;
  i = 0;
  while (str && str[i])
    i++;
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strlen>:
  endbr64
  test   %rdi,%rdi
  je     L18
  mov    $0x0,%eax
L24:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L24
L5:
  mov    %edx,%eax
  ret
L18:
  mov    $0x0,%edx
  jmp    L5
```

assistant: ```c
unsigned int ft_strlen(char *str) {
  int i;
  i = 0;
  while (str && str[i])
    i++;
  return (i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strlen>:
  endbr64
  test   %rdi,%rdi
  je     L26
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L11
L9:
  mov    %r8d,%eax
  ret
L26:
  xor    %r8d,%r8d
  jmp    L9
```

assistant: ```c
unsigned int ft_strlen(char *str) {
  int i;
  i = 0;
  while (str && str[i])
    i++;
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strlen>:
  endbr64
  test   %rdi,%rdi
  je     L21
  cmpb   $0x0,(%rdi)
  je     L21
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %edx,%eax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdi,%rdx,1)
  jne    L17
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int ft_strlen(char *str) {
  int i;
  i = 0;
  while (str && str[i])
    i++;
  return (i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memcmp16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L13
L10:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L2
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L68
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L38
L68:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L38
L2:
  addq   $0x8,-0x20(%rbp)
  addq   $0x8,-0x18(%rbp)
  subq   $0x8,-0x38(%rbp)
L13:
  cmpq   $0x7,-0x38(%rbp)
  ja     L10
  mov    $0x0,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp16(const void *m1, const void *m2, size_t n) {
  const uint16_t *im1 = (const uint16_t *)m1;
  const uint16_t *im2 = (const uint16_t *)m2;
  const uint8_t *cm1;
  const uint8_t *cm2;
  for (; n >= sizeof(uint16_t); n -= sizeof(uint16_t)) {
    if (*im1 != *im2) {
      cm1 = (const uint8_t *)im1;
      cm2 = (const uint8_t *)im2;
      do {
        if (cm1[0] != cm2[0])
          return (cm1[0] - cm2[0]);
        if (cm1[1] != cm2[1])
          return (cm1[1] - cm2[1]);
      } while (0);
    }
    im1++;
    im2++;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memcmp16>:
  endbr64
  cmp    $0x7,%rdx
  jbe    L11
  sub    $0x8,%rdx
  shr    $0x3,%rdx
  lea    0x8(,%rdx,8),%r8
  mov    $0x0,%edx
L0:
  mov    (%rdi,%rdx,1),%rax
  mov    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rax
  jne    L1
  add    $0x8,%rdx
  cmp    %r8,%rdx
  jne    L0
  mov    $0x0,%eax
  ret
L1:
  sub    %ecx,%eax
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memcmp16(const void *m1, const void *m2, size_t n) {
  const uint16_t *im1 = (const uint16_t *)m1;
  const uint16_t *im2 = (const uint16_t *)m2;
  const uint8_t *cm1;
  const uint8_t *cm2;
  for (; n >= sizeof(uint16_t); n -= sizeof(uint16_t)) {
    if (*im1 != *im2) {
      cm1 = (const uint8_t *)im1;
      cm2 = (const uint8_t *)im2;
      do {
        if (cm1[0] != cm2[0])
          return (cm1[0] - cm2[0]);
        if (cm1[1] != cm2[1])
          return (cm1[1] - cm2[1]);
      } while (0);
    }
    im1++;
    im2++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<memcmp16>:
  endbr64
  cmp    $0x7,%rdx
  jbe    L21
  sub    $0x8,%rdx
  shr    $0x3,%rdx
  lea    0x8(,%rdx,8),%r8
  xor    %edx,%edx
  jmp    L16
  xchg   %ax,%ax
L17:
  add    $0x8,%rdx
  cmp    %rdx,%r8
  je     L21
L16:
  mov    (%rdi,%rdx,1),%rax
  mov    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rax
  je     L17
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp16(const void *m1, const void *m2, size_t n) {
  const uint16_t *im1 = (const uint16_t *)m1;
  const uint16_t *im2 = (const uint16_t *)m2;
  const uint8_t *cm1;
  const uint8_t *cm2;
  for (; n >= sizeof(uint16_t); n -= sizeof(uint16_t)) {
    if (*im1 != *im2) {
      cm1 = (const uint8_t *)im1;
      cm2 = (const uint8_t *)im2;
      do {
        if (cm1[0] != cm2[0])
          return (cm1[0] - cm2[0]);
        if (cm1[1] != cm2[1])
          return (cm1[1] - cm2[1]);
      } while (0);
    }
    im1++;
    im2++;
  }
  return (0);
}
```