ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L0
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L2
L0:
  nop
L2:
  pop    %rbp
  ret
```

assistant: ```c
void swap(char *perm, int i, int j) {
  if (i == j) {
    return;
  }
  char tmp = perm[i];
  perm[i] = perm[j];
  perm[j] = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap>:
  endbr64
  cmp    %edx,%esi
  je     L2
  movslq %esi,%rsi
  add    %rdi,%rsi
  movzbl (%rsi),%eax
  movslq %edx,%rdx
  add    %rdx,%rdi
  movzbl (%rdi),%edx
  mov    %dl,(%rsi)
  mov    %al,(%rdi)
L2:
  ret
```

assistant: ```c
void swap(char *perm, int i, int j) {
  if (i == j) {
    return;
  }
  char tmp = perm[i];
  perm[i] = perm[j];
  perm[j] = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  cmp    %edx,%esi
  je     L3
  movslq %edx,%rdx
  movslq %esi,%rsi
  add    %rdi,%rsi
  add    %rdx,%rdi
  movzbl (%rsi),%eax
  movzbl (%rdi),%edx
  mov    %dl,(%rsi)
  mov    %al,(%rdi)
L3:
  ret
```

assistant: ```c
void swap(char *perm, int i, int j) {
  if (i == j) {
    return;
  }
  char tmp = perm[i];
  perm[i] = perm[j];
  perm[j] = tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap>:
  endbr64
  cmp    %edx,%esi
  je     L5
  movslq %edx,%rdx
  movslq %esi,%rsi
  add    %rdi,%rsi
  add    %rdx,%rdi
  movzbl (%rsi),%eax
  movzbl (%rdi),%edx
  mov    %dl,(%rsi)
  mov    %al,(%rdi)
L5:
  ret
```

assistant: ```c
void swap(char *perm, int i, int j) {
  if (i == j) {
    return;
  }
  char tmp = perm[i];
  perm[i] = perm[j];
  perm[j] = tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crash_vfprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D21
type: string
name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D21: r

tool: D3: this_file_doesnt_exist

tool: D11: blablabla


assistant: ```c
void crash_vfprintf() {
  FILE *f;
  va_list arg;
  f = fopen("this_file_doesnt_exist", "r");
  vfprintf(f, "blablabla\n", arg);
  fclose(f);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crash_vfprintf>:
  endbr64
  push   %rbx
  lea    D16(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type_guessed: string
name: retrieve_data
arguments: data_label: D6
type_guessed: string
name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D16: r

tool: D6: this_file_doesnt_exist

tool: D9: blablabla


assistant: ```c
void crash_vfprintf() {
  FILE *f;
  va_list arg;
  f = fopen("this_file_doesnt_exist", "r");
  vfprintf(f, "blablabla\n", arg);
  fclose(f);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crash_vfprintf>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <fopen@plt>
  xor    %edx,%edx
  lea    D25(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose@plt>
```

tool_calls: name: parse_data
arguments: label: D26
type: string
name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D25
type: string

tool: D26: r

tool: D1: this_file_doesnt_exist

tool: D25: blablabla


assistant: ```c
void crash_vfprintf() {
  FILE *f;
  va_list arg;
  f = fopen("this_file_doesnt_exist", "r");
  vfprintf(f, "blablabla\n", arg);
  fclose(f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<crash_vfprintf>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <fopen@plt>
  xor    %edx,%edx
  lea    D22(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string
name: disassemble_data
arguments: label: D10
type_infered: string
name: disassemble_data
arguments: label: D22
type_infered: string

tool: D1: r

tool: D10: this_file_doesnt_exist

tool: D22: blablabla


assistant: ```c
void crash_vfprintf() {
  FILE *f;
  va_list arg;
  f = fopen("this_file_doesnt_exist", "r");
  vfprintf(f, "blablabla\n", arg);
  fclose(f);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_minus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <str2cstr@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <str2cstr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  jmp    L13
L28:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x20(%rbp)
L1:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
L13:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <string_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long int string_minus(unsigned long int self, unsigned long int subobj) {
  char *buf, *ptr, *sub;
  int sublen;
  unsigned long int ret;
  buf = strdup(str2cstr(self));
  sub = str2cstr(subobj);
  sublen = strlen(sub);
  while ((ptr = strstr(buf, sub))) {
    while ((*ptr = ptr[sublen]))
      ptr[sublen] = '\0', ptr++;
  }
  ret = string_new(buf);
  free(buf);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<string_minus>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  call   <str2cstr@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <str2cstr@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%r12
  jmp    L1
L47:
  movb   $0x0,(%rsi,%rdx,1)
  movzbl 0x1(%rsi,%rdx,1),%ecx
  mov    %cl,0x1(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L47
L1:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L16
  lea    (%rax,%r12,1),%rsi
  movzbl (%rsi),%ecx
  mov    %cl,(%rax)
  mov    $0x0,%edx
  test   %cl,%cl
  jne    L47
  jmp    L1
L16:
  mov    %rbx,%rdi
  call   <string_new@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long int string_minus(unsigned long int self, unsigned long int subobj) {
  char *buf, *ptr, *sub;
  int sublen;
  unsigned long int ret;
  buf = strdup(str2cstr(self));
  sub = str2cstr(subobj);
  sublen = strlen(sub);
  while ((ptr = strstr(buf, sub))) {
    while ((*ptr = ptr[sublen]))
      ptr[sublen] = '\0', ptr++;
  }
  ret = string_new(buf);
  free(buf);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_minus>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <str2cstr@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <str2cstr@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  movslq %eax,%rbp
L18:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L29
L21:
  lea    (%rax,%rbp,1),%rsi
  xor    %edx,%edx
  movzbl (%rsi),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  je     L18
  cs nopw 0x0(%rax,%rax,1)
L1:
  movzbl 0x1(%rsi,%rdx,1),%ecx
  movb   $0x0,(%rsi,%rdx,1)
  mov    %cl,0x1(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L1
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L21
L29:
  mov    %r12,%rdi
  call   <string_new@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long int string_minus(unsigned long int self, unsigned long int subobj) {
  char *buf, *ptr, *sub;
  int sublen;
  unsigned long int ret;
  buf = strdup(str2cstr(self));
  sub = str2cstr(subobj);
  sublen = strlen(sub);
  while ((ptr = strstr(buf, sub))) {
    while ((*ptr = ptr[sublen]))
      ptr[sublen] = '\0', ptr++;
  }
  ret = string_new(buf);
  free(buf);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_minus>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <str2cstr@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <str2cstr@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  movslq %eax,%rbp
L15:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L3
L20:
  lea    (%rax,%rbp,1),%rsi
  xor    %edx,%edx
  movzbl (%rsi),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  je     L15
  cs nopw 0x0(%rax,%rax,1)
L0:
  movzbl 0x1(%rsi,%rdx,1),%ecx
  movb   $0x0,(%rsi,%rdx,1)
  mov    %cl,0x1(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L0
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L20
L3:
  mov    %r12,%rdi
  call   <string_new@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long int string_minus(unsigned long int self, unsigned long int subobj) {
  char *buf, *ptr, *sub;
  int sublen;
  unsigned long int ret;
  buf = strdup(str2cstr(self));
  sub = str2cstr(subobj);
  sublen = strlen(sub);
  while ((ptr = strstr(buf, sub))) {
    while ((*ptr = ptr[sublen]))
      ptr[sublen] = '\0', ptr++;
  }
  ret = string_new(buf);
  free(buf);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pow10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xffffff9d,-0x4(%rbp)
  jl     L11
  cmpl   $0x63,-0x4(%rbp)
  jg     L11
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L4
L11:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movq   %xmm0,%rax
L4:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double pow10(int i) {
  extern const double *const pow10_table99;
  return -100 < i && i < 100 ? pow10_table99[i] : pow(10, i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pow10>:
  endbr64
  lea    0x63(%rdi),%eax
  cmp    $0xc6,%eax
  ja     L6
  movslq %edi,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  movsd  (%rax,%rsi,8),%xmm0
  ret
L6:
  sub    $0x8,%rsp
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double pow10(int i) {
  extern const double *const pow10_table99;
  return -100 < i && i < 100 ? pow10_table99[i] : pow(10, i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pow10>:
  endbr64
  lea    0x63(%rdi),%eax
  cmp    $0xc6,%eax
  ja     L9
  mov    D0(%rip),%rax
  movslq %edi,%rsi
  mov    (%rax),%rax
  movsd  (%rax,%rsi,8),%xmm0
  ret
  nopl   0x0(%rax)
L9:
  mov    %edi,%esi
  mov    $0xa,%edi
  jmp    1050 <pow@plt>
```

assistant: ```c
double pow10(int i) {
  extern const double *const pow10_table99;
  return -100 < i && i < 100 ? pow10_table99[i] : pow(10, i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pow10>:
  endbr64
  lea    0x63(%rdi),%eax
  cmp    $0xc6,%eax
  ja     L7
  mov    D3(%rip),%rax
  movslq %edi,%rsi
  mov    (%rax),%rax
  movsd  (%rax,%rsi,8),%xmm0
  ret
  nopl   0x0(%rax)
L7:
  mov    %edi,%esi
  mov    $0xa,%edi
  jmp    1050 <pow@plt>
```

assistant: ```c
double pow10(int i) {
  extern const double *const pow10_table99;
  return -100 < i && i < 100 ? pow10_table99[i] : pow(10, i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xdrmem_getlong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x4(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L17
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  jmp    L3
L17:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ntohl@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    D12(%rip),%rax
  mov    (%rax),%eax
L3:
  leave
  ret
```

assistant: ```c
bool_t xdrmem_getlong(XDR *xdrs, long *lp) {
  if ((xdrs->x_handy -= 4) < 0)
    return FALSE;
  *lp = (int32_t)ntohl((*((int32_t *)(xdrs->x_private))));
  xdrs->x_private += 4;
  return TRUE;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdrmem_getlong>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x4,%eax
  mov    %eax,(%rdi)
  js     L0
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    0x8(%rdi),%rax
  mov    (%rax),%rdi
  call   <ntohl@plt>
  mov    %rax,0x0(%rbp)
  addq   $0x4,0x8(%rbx)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
bool_t xdrmem_getlong(XDR *xdrs, long *lp) {
  if ((xdrs->x_handy -= 4) < 0)
    return FALSE;
  *lp = (int32_t)ntohl((*((int32_t *)(xdrs->x_private))));
  xdrs->x_private += 4;
  return TRUE;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xdrmem_getlong>:
  endbr64
  subl   $0x4,(%rdi)
  js     L9
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rax
  mov    (%rax),%rdi
  call   <ntohl@plt>
  mov    %rax,0x0(%rbp)
  mov    D2(%rip),%rax
  addq   $0x4,0x8(%rbx)
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
bool_t xdrmem_getlong(XDR *xdrs, long *lp) {
  if ((xdrs->x_handy -= 4) < 0)
    return FALSE;
  *lp = (int32_t)ntohl((*((int32_t *)(xdrs->x_private))));
  xdrs->x_private += 4;
  return TRUE;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xdrmem_getlong>:
  endbr64
  subl   $0x4,(%rdi)
  js     L4
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rax
  mov    (%rax),%rdi
  call   <ntohl@plt>
  mov    %rax,0x0(%rbp)
  mov    D12(%rip),%rax
  addq   $0x4,0x8(%rbx)
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
bool_t xdrmem_getlong(XDR *xdrs, long *lp) {
  if ((xdrs->x_handy -= 4) < 0)
    return FALSE;
  *lp = (int32_t)ntohl((*((int32_t *)(xdrs->x_private))));
  xdrs->x_private += 4;
  return TRUE;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <pabc@plt>
  mov    $0x3,%edi
  call   <set_a@plt>
  mov    $0x0,%edi
  call   <pabc@plt>
  mov    $0x4,%edi
  call   <set_b@plt>
  mov    $0x0,%edi
  call   <pabc@plt>
  mov    $0x0,%edi
  call   <add_ab@plt>
  mov    $0x0,%edi
  call   <pabc@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  pabc(0);
  set_a(3);
  pabc(0);
  set_b(4);
  pabc(0);
  add_ab(0);
  pabc(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <pabc@plt>
  mov    $0x3,%edi
  call   <set_a@plt>
  mov    $0x0,%edi
  call   <pabc@plt>
  mov    $0x4,%edi
  call   <set_b@plt>
  mov    $0x0,%edi
  call   <pabc@plt>
  mov    $0x0,%edi
  call   <add_ab@plt>
  mov    $0x0,%edi
  call   <pabc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  pabc(0);
  set_a(3);
  pabc(0);
  set_b(4);
  pabc(0);
  add_ab(0);
  pabc(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <pabc@plt>
  mov    $0x3,%edi
  call   <set_a@plt>
  xor    %edi,%edi
  call   <pabc@plt>
  mov    $0x4,%edi
  call   <set_b@plt>
  xor    %edi,%edi
  call   <pabc@plt>
  xor    %edi,%edi
  call   <add_ab@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10b0 <pabc@plt>
```

assistant: ```c
void main() {
  pabc(0);
  set_a(3);
  pabc(0);
  set_b(4);
  pabc(0);
  add_ab(0);
  pabc(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <pabc@plt>
  mov    $0x3,%edi
  call   <set_a@plt>
  xor    %edi,%edi
  call   <pabc@plt>
  mov    $0x4,%edi
  call   <set_b@plt>
  xor    %edi,%edi
  call   <pabc@plt>
  xor    %edi,%edi
  call   <add_ab@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10b0 <pabc@plt>
```

assistant: ```c
void main() {
  pabc(0);
  set_a(3);
  pabc(0);
  set_b(4);
  pabc(0);
  add_ab(0);
  pabc(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x9,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: Result is %i.


assistant: ```c
int main(int argc, char **argv) {
  int i;
  int k;
  int result;
  i = 2;
  k = 9;
  result = i + k;
  printf("Result is %i.\n", result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: Result is %i.


assistant: ```c
int main(int argc, char **argv) {
  int i;
  int k;
  int result;
  i = 2;
  k = 9;
  result = i + k;
  printf("Result is %i.\n", result);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: Result is %i.


assistant: ```c
int main(int argc, char **argv) {
  int i;
  int k;
  int result;
  i = 2;
  k = 9;
  result = i + k;
  printf("Result is %i.\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Result is %i.


assistant: ```c
int main(int argc, char **argv) {
  int i;
  int k;
  int result;
  i = 2;
  k = 9;
  result = i + k;
  printf("Result is %i.\n", result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L11
  movl   $0x1,-0xc(%rbp)
  jmp    L41
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf0,%eax
  cmp    $0xf0,%eax
  jne    L13
  movl   $0x4,-0xc(%rbp)
  jmp    L41
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xe0,%eax
  cmp    $0xe0,%eax
  jne    L21
  movl   $0x3,-0xc(%rbp)
  jmp    L41
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xc0,%eax
  cmp    $0xc0,%eax
  jne    L51
  movl   $0x2,-0xc(%rbp)
  jmp    L41
L51:
  movl   $0x5,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int utf8_len(char *buf, int len) {
  unsigned char *ptr;
  int ret;
  ptr = (unsigned char *)buf;
  if (((*ptr) <= 0x7F)) {
    ret = 1;
  } else if (((*ptr) & 0xF0) == 0xF0) {
    ret = 4;
  } else if (((*ptr) & 0xE0) == 0xE0) {
    ret = 3;
  } else if (((*ptr) & 0xC0) == 0xC0) {
    ret = 2;
  } else {
    ret = 5;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_len>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  test   %dl,%dl
  js     L1
L19:
  ret
L1:
  mov    %edx,%ecx
  and    $0xfffffff0,%ecx
  mov    $0x4,%eax
  cmp    $0xf0,%cl
  je     L19
  mov    %edx,%ecx
  and    $0xffffffe0,%ecx
  mov    $0x3,%eax
  cmp    $0xe0,%cl
  je     L19
  and    $0xffffffc0,%edx
  cmp    $0xc0,%dl
  setne  %al
  movzbl %al,%eax
  lea    0x2(%rax,%rax,2),%eax
  jmp    L19
```

assistant: ```c
__attribute__((always_)) int utf8_len(char *buf, int len) {
  unsigned char *ptr;
  int ret;
  ptr = (unsigned char *)buf;
  if (((*ptr) <= 0x7F)) {
    ret = 1;
  } else if (((*ptr) & 0xF0) == 0xF0) {
    ret = 4;
  } else if (((*ptr) & 0xE0) == 0xE0) {
    ret = 3;
  } else if (((*ptr) & 0xC0) == 0xC0) {
    ret = 2;
  } else {
    ret = 5;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8_len>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  test   %dl,%dl
  js     L6
L1:
  ret
  nopl   0x0(%rax)
L6:
  mov    %edx,%ecx
  mov    $0x4,%eax
  and    $0xfffffff0,%ecx
  cmp    $0xf0,%cl
  je     L1
  mov    %edx,%ecx
  mov    $0x3,%eax
  and    $0xffffffe0,%ecx
  cmp    $0xe0,%cl
  je     L1
  and    $0xffffffc0,%edx
  xor    %eax,%eax
  cmp    $0xc0,%dl
  setne  %al
  lea    0x2(%rax,%rax,2),%eax
  ret
```

assistant: ```c
__attribute__((always_)) int utf8_len(char *buf, int len) {
  unsigned char *ptr;
  int ret;
  ptr = (unsigned char *)buf;
  if (((*ptr) <= 0x7F)) {
    ret = 1;
  } else if (((*ptr) & 0xF0) == 0xF0) {
    ret = 4;
  } else if (((*ptr) & 0xE0) == 0xE0) {
    ret = 3;
  } else if (((*ptr) & 0xC0) == 0xC0) {
    ret = 2;
  } else {
    ret = 5;
  }
  return ret;
}
```