ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bytes_to_int32>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  lea    0x4(%rsp),%rdi
  mov    %r8,%rsi
  je     L17
  call   <reverse_memcpy@plt>
L10:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  call   <memcpy@plt>
  jmp    L10
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t bytes_to_int32(const unsigned char bytes[4], int switch_endian) {
  int32_t dest_num;
  void *dest_ptr = (void *)&dest_num;
  if (switch_endian) {
    reverse_memcpy(dest_ptr, (void *)bytes, 4);
  } else {
    memcpy(dest_ptr, (void *)bytes, 4);
  }
  return dest_num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x80,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shr    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D48
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D40
datatype: string
name: extract_symbolic_data
arguments: label: D64
datatype: string

tool: D48: j:%u


tool: D13: k:%u


tool: D40: a:%u


tool: D64: %u


assistant: ```c
int main(void) {
  unsigned int a = 128;
  unsigned int j = a << 1;
  unsigned int k = a >> 1;
  printf("j:%u\n", j);
  printf("k:%u\n", k);
  printf("a:%u\n", a);
  printf("%u\n", a << 2 + 1);
  printf("%u\n", (a << 2) + 1);
  printf("%u\n", j & k);
  printf("%u\n", j | k);
  printf("%u\n", ~a);
  printf("%u\n", j ^ k);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x100,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x40,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x80,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    $0x400,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x201,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x140,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xffffff7f,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x140,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D21
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D31
type_infered: string
name: retrieve_data
arguments: label: D2
type_infered: string

tool: D21: j:%u


tool: D3: k:%u


tool: D31: a:%u


tool: D2: %u


assistant: ```c
int main(void) {
  unsigned int a = 128;
  unsigned int j = a << 1;
  unsigned int k = a >> 1;
  printf("j:%u\n", j);
  printf("k:%u\n", k);
  printf("a:%u\n", a);
  printf("%u\n", a << 2 + 1);
  printf("%u\n", (a << 2) + 1);
  printf("%u\n", j & k);
  printf("%u\n", j | k);
  printf("%u\n", ~a);
  printf("%u\n", j ^ k);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x100,%esi
  lea    D0(%rip),%rdi
  lea    D11(%rip),%rbp
  call   <printf@plt>
  mov    $0x40,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x80,%esi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x400,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x201,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x140,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffff7f,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x140,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D11
datatype: string
name: retrieve_data
arguments: data_tag: D32
datatype: string
name: retrieve_data
arguments: data_tag: D34
datatype: string

tool: D0: j:%u


tool: D11: %u


tool: D32: k:%u


tool: D34: a:%u


assistant: ```c
int main(void) {
  unsigned int a = 128;
  unsigned int j = a << 1;
  unsigned int k = a >> 1;
  printf("j:%u\n", j);
  printf("k:%u\n", k);
  printf("a:%u\n", a);
  printf("%u\n", a << 2 + 1);
  printf("%u\n", (a << 2) + 1);
  printf("%u\n", j & k);
  printf("%u\n", j | k);
  printf("%u\n", ~a);
  printf("%u\n", j ^ k);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x100,%esi
  lea    D31(%rip),%rdi
  lea    D15(%rip),%rbp
  call   <printf@plt>
  mov    $0x40,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x80,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x400,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x201,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x140,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffff7f,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x140,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D31
data_type: string
name: unpack_data
arguments: data_label: D15
data_type: string
name: unpack_data
arguments: data_label: D6
data_type: string
name: unpack_data
arguments: data_label: D17
data_type: string

tool: D31: j:%u


tool: D15: %u


tool: D6: k:%u


tool: D17: a:%u


assistant: ```c
int main(void) {
  unsigned int a = 128;
  unsigned int j = a << 1;
  unsigned int k = a >> 1;
  printf("j:%u\n", j);
  printf("k:%u\n", k);
  printf("a:%u\n", a);
  printf("%u\n", a << 2 + 1);
  printf("%u\n", (a << 2) + 1);
  printf("%u\n", j & k);
  printf("%u\n", j | k);
  printf("%u\n", ~a);
  printf("%u\n", j ^ k);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash_djb2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1505,-0x4(%rbp)
  jmp    L3
L16:
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash_djb2(const char *p) {
  unsigned hash_val = 5381;
  while (*p) {
    hash_val = ((hash_val << 5) + hash_val) + *p;
    hash_val %= UINT_MAX;
    p++;
  }
  return hash_val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash_djb2>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L22
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    $0x1505,%edx
L17:
  mov    %edx,%eax
  shl    $0x5,%eax
  add    %eax,%edx
  movsbl %cl,%eax
  add    %edx,%eax
  mov    $0x0,%edx
  div    %esi
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L17
L12:
  mov    %edx,%eax
  ret
L22:
  mov    $0x1505,%edx
  jmp    L12
```

assistant: ```c
unsigned hash_djb2(const char *p) {
  unsigned hash_val = 5381;
  while (*p) {
    hash_val = ((hash_val << 5) + hash_val) + *p;
    hash_val %= UINT_MAX;
    p++;
  }
  return hash_val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hash_djb2>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L5
  mov    D9(%rip),%rax
  mov    $0x1505,%edx
  mov    (%rax),%esi
  nopl   0x0(%rax)
L8:
  mov    %edx,%eax
  add    $0x1,%rdi
  shl    $0x5,%eax
  add    %eax,%edx
  movsbl %cl,%eax
  movzbl (%rdi),%ecx
  add    %edx,%eax
  xor    %edx,%edx
  div    %esi
  test   %cl,%cl
  jne    L8
  mov    %edx,%eax
  ret
  xchg   %ax,%ax
L5:
  mov    $0x1505,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned hash_djb2(const char *p) {
  unsigned hash_val = 5381;
  while (*p) {
    hash_val = ((hash_val << 5) + hash_val) + *p;
    hash_val %= UINT_MAX;
    p++;
  }
  return hash_val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_djb2>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L1
  mov    D2(%rip),%rax
  mov    $0x1505,%edx
  mov    (%rax),%esi
  nopl   0x0(%rax)
L11:
  mov    %edx,%eax
  add    $0x1,%rdi
  shl    $0x5,%eax
  add    %eax,%edx
  movsbl %cl,%eax
  movzbl (%rdi),%ecx
  add    %edx,%eax
  xor    %edx,%edx
  div    %esi
  test   %cl,%cl
  jne    L11
  mov    %edx,%eax
  ret
  xchg   %ax,%ax
L1:
  mov    $0x1505,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned hash_djb2(const char *p) {
  unsigned hash_val = 5381;
  while (*p) {
    hash_val = ((hash_val << 5) + hash_val) + *p;
    hash_val %= UINT_MAX;
    p++;
  }
  return hash_val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gf8mul_01101110>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm7,%xmm6
  pxor   %xmm6,%xmm5
  pxor   %xmm5,%xmm4
  pxor   %xmm4,%xmm3
  pxor   %xmm3,%xmm2
  pxor   %xmm2,%xmm1
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm5
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm2
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm6,%xmm3
  pxor   %xmm6,%xmm2
  pxor   %xmm5,%xmm2
  pxor   %xmm5,%xmm1
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm2
  pxor   %xmm7,%xmm4
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm1
  pxor   %xmm6,%xmm3
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm0
  pxor   %xmm5,%xmm2
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gf8mul_01101110(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm5\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm2\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm2\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gf8mul_01101110>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm6,%xmm5
  pxor   %xmm5,%xmm4
  pxor   %xmm4,%xmm3
  pxor   %xmm3,%xmm2
  pxor   %xmm2,%xmm1
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm5
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm2
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm6,%xmm3
  pxor   %xmm6,%xmm2
  pxor   %xmm5,%xmm2
  pxor   %xmm5,%xmm1
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm2
  pxor   %xmm7,%xmm4
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm1
  pxor   %xmm6,%xmm3
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm0
  pxor   %xmm5,%xmm2
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  ret
```

assistant: ```c
void gf8mul_01101110(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm5\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm2\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm2\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gf8mul_01101110>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm6,%xmm5
  pxor   %xmm5,%xmm4
  pxor   %xmm4,%xmm3
  pxor   %xmm3,%xmm2
  pxor   %xmm2,%xmm1
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm5
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm2
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm6,%xmm3
  pxor   %xmm6,%xmm2
  pxor   %xmm5,%xmm2
  pxor   %xmm5,%xmm1
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm2
  pxor   %xmm7,%xmm4
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm1
  pxor   %xmm6,%xmm3
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm0
  pxor   %xmm5,%xmm2
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  ret
```

assistant: ```c
void gf8mul_01101110(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm5\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm2\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm2\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<gf8mul_01101110>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm6,%xmm5
  pxor   %xmm5,%xmm4
  pxor   %xmm4,%xmm3
  pxor   %xmm3,%xmm2
  pxor   %xmm2,%xmm1
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm5
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm2
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm6,%xmm3
  pxor   %xmm6,%xmm2
  pxor   %xmm5,%xmm2
  pxor   %xmm5,%xmm1
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm2
  pxor   %xmm7,%xmm4
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm1
  pxor   %xmm6,%xmm3
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm0
  pxor   %xmm5,%xmm2
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  ret
```

assistant: ```c
void gf8mul_01101110(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm5\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm2\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm2\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copyString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L1
L11:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L1:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copyString(char *to, char *from, int index) {
  to += index;
  while (*from) {
    *to++ = *from++;
  }
  *to = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<copyString>:
  endbr64
  movslq %edx,%rdx
  add    %rdx,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  je     L15
L19:
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L19
L15:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void copyString(char *to, char *from, int index) {
  to += index;
  while (*from) {
    *to++ = *from++;
  }
  *to = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<copyString>:
  endbr64
  movzbl (%rsi),%eax
  movslq %edx,%rdx
  add    %rdx,%rdi
  test   %al,%al
  je     L14
  nopl   0x0(%rax)
L1:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L1
L14:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void copyString(char *to, char *from, int index) {
  to += index;
  while (*from) {
    *to++ = *from++;
  }
  *to = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copyString>:
  endbr64
  movzbl (%rsi),%eax
  movslq %edx,%rdx
  add    %rdx,%rdi
  test   %al,%al
  je     L6
  nopl   0x0(%rax)
L2:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L2
L6:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void copyString(char *to, char *from, int index) {
  to += index;
  while (*from) {
    *to++ = *from++;
  }
  *to = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strSearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L4:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L7
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strSearch(char *suchen, char ch) {
  int counter = 0;
  while (*suchen != '\0') {
    if (*suchen++ == ch)
      counter++;
  }
  return counter;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strSearch>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  mov    $0x0,%edx
L11:
  add    $0x1,%rdi
  cmp    %al,%sil
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L11
L6:
  mov    %edx,%eax
  ret
L12:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int strSearch(char *suchen, char ch) {
  int counter = 0;
  while (*suchen != '\0') {
    if (*suchen++ == ch)
      counter++;
  }
  return counter;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strSearch>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L12
  xchg   %ax,%ax
L11:
  add    $0x1,%rdi
  cmp    %al,%sil
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L11
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strSearch(char *suchen, char ch) {
  int counter = 0;
  while (*suchen != '\0') {
    if (*suchen++ == ch)
      counter++;
  }
  return counter;
}
```