ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dotstrcmp>:
  endbr64
  jmp    L13
L90:
  add    $0x1,%rdi
  jmp    L13
L48:
  movzbl (%rdi),%eax
  cmp    %r8b,%al
  jg     L22
  jl     L33
  add    $0x1,%rdi
  add    $0x1,%rdx
L13:
  cmp    %rsi,%rdi
  je     L67
  cmpb   $0x2e,(%rdi)
  je     L90
  cmp    %rcx,%rdx
  je     L24
  movzbl (%rdx),%r8d
  cmp    $0x2e,%r8b
  jne    L48
  jmp    L95
L22:
  mov    $0x1,%eax
  ret
L33:
  mov    $0xffffffff,%eax
  ret
L24:
  mov    $0x1,%eax
  ret
L67:
  cmp    %rcx,%rdx
  je     L115
  cmpb   $0x2e,(%rdx)
  jne    L56
L95:
  add    $0x1,%rdx
  jmp    L13
L115:
  mov    $0x0,%eax
  ret
L56:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dotstrcmp(const char *a_s, const char *a_e, const char *b_s, const char *b_e) {
  do {
    if ((a_s != a_e) && (*a_s == '.')) {
      a_s++;
      continue;
    }
    if ((b_s != b_e) && (*b_s == '.')) {
      b_s++;
      continue;
    }
    if ((a_s == a_e) && (b_s == b_e))
      return 0;
    if (a_s == a_e)
      return -1;
    if (b_s == b_e)
      return 1;
    if (*a_s > *b_s)
      return 1;
    if (*b_s > *a_s)
      return -1;
    a_s++;
    b_s++;
  } while (true);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dotstrcmp>:
  endbr64
L69:
  cmp    %rsi,%rdi
  je     L96
L29:
  cmpb   $0x2e,(%rdi)
  je     L10
  cmp    %rcx,%rdx
  je     L54
  movzbl (%rdx),%eax
  cmp    $0x2e,%al
  je     L61
  cmp    (%rdi),%al
  jl     L54
  jg     L58
  add    $0x1,%rdi
  add    $0x1,%rdx
  cmp    %rsi,%rdi
  jne    L29
L96:
  cmp    %rcx,%rdx
  je     L70
  cmpb   $0x2e,(%rdx)
  jne    L58
L61:
  add    $0x1,%rdx
  jmp    L69
  nopl   (%rax)
L54:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x1,%rdi
  jmp    L69
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L70:
  xor    %eax,%eax
  ret
```

assistant: ```c
int dotstrcmp(const char *a_s, const char *a_e, const char *b_s, const char *b_e) {
  do {
    if ((a_s != a_e) && (*a_s == '.')) {
      a_s++;
      continue;
    }
    if ((b_s != b_e) && (*b_s == '.')) {
      b_s++;
      continue;
    }
    if ((a_s == a_e) && (b_s == b_e))
      return 0;
    if (a_s == a_e)
      return -1;
    if (b_s == b_e)
      return 1;
    if (*a_s > *b_s)
      return 1;
    if (*b_s > *a_s)
      return -1;
    a_s++;
    b_s++;
  } while (true);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dotstrcmp>:
  endbr64
L5:
  cmp    %rsi,%rdi
  je     L58
L43:
  cmpb   $0x2e,(%rdi)
  je     L13
  cmp    %rcx,%rdx
  je     L89
  movzbl (%rdx),%eax
  cmp    $0x2e,%al
  je     L83
  cmp    (%rdi),%al
  jl     L89
  jg     L63
  add    $0x1,%rdi
  add    $0x1,%rdx
  cmp    %rsi,%rdi
  jne    L43
L58:
  cmp    %rcx,%rdx
  je     L30
  cmpb   $0x2e,(%rdx)
  jne    L63
L83:
  add    $0x1,%rdx
  jmp    L5
  nopl   (%rax)
L89:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  add    $0x1,%rdi
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L63:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  ret
```

assistant: ```c
int dotstrcmp(const char *a_s, const char *a_e, const char *b_s, const char *b_e) {
  do {
    if ((a_s != a_e) && (*a_s == '.')) {
      a_s++;
      continue;
    }
    if ((b_s != b_e) && (*b_s == '.')) {
      b_s++;
      continue;
    }
    if ((a_s == a_e) && (b_s == b_e))
      return 0;
    if (a_s == a_e)
      return -1;
    if (b_s == b_e)
      return 1;
    if (*a_s > *b_s)
      return 1;
    if (*b_s > *a_s)
      return -1;
    a_s++;
    b_s++;
  } while (true);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_guessed: string
name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D12: input : 

tool: D4: output : 

assistant: ```c
int main() {
  char str[100] = {
      0,
  };
  printf("input : ");
  gets(str);
  printf("output : ");
  puts(str);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D3
type_infered: string

tool: D12: input : 

tool: D3: output : 

assistant: ```c
int main() {
  char str[100] = {
      0,
  };
  printf("input : ");
  gets(str);
  printf("output : ");
  puts(str);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  lea    D12(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D18
datatype: string

tool: D12: input : 

tool: D18: output : 

assistant: ```c
int main() {
  char str[100] = {
      0,
  };
  printf("input : ");
  gets(str);
  printf("output : ");
  puts(str);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  lea    D16(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string

tool: D16: input : 

tool: D19: output : 

assistant: ```c
int main() {
  char str[100] = {
      0,
  };
  printf("input : ");
  gets(str);
  printf("output : ");
  puts(str);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__wrap_xmlStrncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L6
  mov    $0x0,%eax
  jmp    L47
L6:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L38
  mov    $0x0,%eax
  jmp    L47
L38:
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    $0xffffffff,%eax
  jmp    L47
L14:
  cmpq   $0x0,-0x10(%rbp)
  jne    L43
  mov    $0x1,%eax
  jmp    L47
L43:
  mov    $0x0,%edi
  call   <__builtin_return_address@plt>
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_strncasecmp@plt>
L47:
  leave
  ret
```

assistant: ```c
int __wrap_xmlStrncasecmp(const char *s1, const char *s2, int len) {
  if (len <= 0) {
    return 0;
  }
  if (s1 == s2) {
    return 0;
  }
  if (s1 == NULL) {
    return -1;
  }
  if (s2 == NULL) {
    return 1;
  }
  return _strncasecmp(s1, s2, (size_t)len, __builtin_return_address(0));
}
```
user: What is the c source code of the assembly code below:

```asm
<__wrap_xmlStrncasecmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L49
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    $0x0,%eax
  test   %edx,%edx
  jle    L8
  test   %rdi,%rdi
  je     L11
  mov    $0x1,%eax
  test   %rsi,%rsi
  je     L8
  mov    $0x0,%edi
  call   <__builtin_return_address@plt>
  mov    %eax,%ecx
  movslq %ebx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <_strncasecmp@plt>
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L8
L49:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int __wrap_xmlStrncasecmp(const char *s1, const char *s2, int len) {
  if (len <= 0) {
    return 0;
  }
  if (s1 == s2) {
    return 0;
  }
  if (s1 == NULL) {
    return -1;
  }
  if (s2 == NULL) {
    return 1;
  }
  return _strncasecmp(s1, s2, (size_t)len, __builtin_return_address(0));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__wrap_xmlStrncasecmp>:
  endbr64
  test   %edx,%edx
  jle    L44
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmp    %rsi,%rdi
  je     L20
  test   %rdi,%rdi
  je     L23
  test   %rsi,%rsi
  je     L21
  xor    %edi,%edi
  mov    %edx,%ebx
  call   <__builtin_return_address@plt>
  movslq %ebx,%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  pop    %r12
  jmp    1070 <_strncasecmp@plt>
  xchg   %ax,%ax
L20:
  xor    %eax,%eax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L34
```

assistant: ```c
int __wrap_xmlStrncasecmp(const char *s1, const char *s2, int len) {
  if (len <= 0) {
    return 0;
  }
  if (s1 == s2) {
    return 0;
  }
  if (s1 == NULL) {
    return -1;
  }
  if (s2 == NULL) {
    return 1;
  }
  return _strncasecmp(s1, s2, (size_t)len, __builtin_return_address(0));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__wrap_xmlStrncasecmp>:
  endbr64
  test   %edx,%edx
  jle    L16
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmp    %rsi,%rdi
  je     L6
  test   %rdi,%rdi
  je     L15
  test   %rsi,%rsi
  je     L18
  xor    %edi,%edi
  mov    %edx,%ebx
  call   <__builtin_return_address@plt>
  movslq %ebx,%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  pop    %r12
  jmp    1070 <_strncasecmp@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L40
```

assistant: ```c
int __wrap_xmlStrncasecmp(const char *s1, const char *s2, int len) {
  if (len <= 0) {
    return 0;
  }
  if (s1 == s2) {
    return 0;
  }
  if (s1 == NULL) {
    return -1;
  }
  if (s2 == NULL) {
    return 1;
  }
  return _strncasecmp(s1, s2, (size_t)len, __builtin_return_address(0));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <LOOP@plt>
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int i = 0;
  return (i + (i + 1 + LOOP(i + 1 + 1)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <LOOP@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  int i = 0;
  return (i + (i + 1 + LOOP(i + 1 + 1)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x2,%edi
  xor    %eax,%eax
  jmp    1050 <LOOP@plt>
```

assistant: ```c
void main() {
  int i = 0;
  return (i + (i + 1 + LOOP(i + 1 + 1)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x2,%edi
  xor    %eax,%eax
  jmp    1050 <LOOP@plt>
```

assistant: ```c
void main() {
  int i = 0;
  return (i + (i + 1 + LOOP(i + 1 + 1)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tty_getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <tty_getc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1b,-0x4(%rbp)
  jne    L96
  mov    $0x0,%eax
  call   <tty_getc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x5b,-0x4(%rbp)
  je     L60
  cmpl   $0x4f,-0x4(%rbp)
  jne    L96
L60:
  mov    $0x0,%eax
  call   <tty_getc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x41,-0x4(%rbp)
  jne    L49
  mov    $0x103,%eax
  jmp    L70
L49:
  cmpl   $0x42,-0x4(%rbp)
  jne    L80
  mov    $0x102,%eax
  jmp    L70
L80:
  cmpl   $0x43,-0x4(%rbp)
  jne    L1
  mov    $0x105,%eax
  jmp    L70
L1:
  cmpl   $0x44,-0x4(%rbp)
  jne    L96
  mov    $0x104,%eax
  jmp    L70
L96:
  mov    -0x4(%rbp),%eax
L70:
  leave
  ret
```

assistant: ```c
int tty_getch() {
  int ch;
  ch = tty_getc();
  if (ch == 27) {
    ch = tty_getc();
    if (ch == '[' || ch == 'O') {
      ch = tty_getc();
      if (ch == 'A') {
        return 259;
      }
      if (ch == 'B') {
        return 258;
      }
      if (ch == 'C') {
        return 261;
      }
      if (ch == 'D') {
        return 260;
      }
    }
  }
  return ch;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tty_getch>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tty_getc@plt>
  cmp    $0x1b,%eax
  je     L61
L83:
  add    $0x8,%rsp
  ret
L61:
  mov    $0x0,%eax
  call   <tty_getc@plt>
  cmp    $0x5b,%eax
  je     L90
  cmp    $0x4f,%eax
  jne    L83
L90:
  mov    $0x0,%eax
  call   <tty_getc@plt>
  cmp    $0x41,%eax
  je     L80
  cmp    $0x42,%eax
  je     L29
  cmp    $0x43,%eax
  je     L88
  cmp    $0x44,%eax
  mov    $0x104,%edx
  cmove  %edx,%eax
  jmp    L83
L80:
  mov    $0x103,%eax
  jmp    L83
L29:
  mov    $0x102,%eax
  jmp    L83
L88:
  mov    $0x105,%eax
  jmp    L83
```

assistant: ```c
int tty_getch() {
  int ch;
  ch = tty_getc();
  if (ch == 27) {
    ch = tty_getc();
    if (ch == '[' || ch == 'O') {
      ch = tty_getc();
      if (ch == 'A') {
        return 259;
      }
      if (ch == 'B') {
        return 258;
      }
      if (ch == 'C') {
        return 261;
      }
      if (ch == 'D') {
        return 260;
      }
    }
  }
  return ch;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tty_getch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tty_getc@plt>
  cmp    $0x1b,%eax
  je     L25
L69:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  call   <tty_getc@plt>
  cmp    $0x5b,%eax
  je     L56
  cmp    $0x4f,%eax
  jne    L69
L56:
  xor    %eax,%eax
  call   <tty_getc@plt>
  cmp    $0x41,%eax
  je     L41
  cmp    $0x42,%eax
  je     L57
  cmp    $0x43,%eax
  je     L44
  cmp    $0x44,%eax
  mov    $0x104,%edx
  cmove  %edx,%eax
  jmp    L69
L44:
  mov    $0x105,%eax
  jmp    L69
L41:
  mov    $0x103,%eax
  jmp    L69
L57:
  mov    $0x102,%eax
  jmp    L69
```

assistant: ```c
int tty_getch() {
  int ch;
  ch = tty_getc();
  if (ch == 27) {
    ch = tty_getc();
    if (ch == '[' || ch == 'O') {
      ch = tty_getc();
      if (ch == 'A') {
        return 259;
      }
      if (ch == 'B') {
        return 258;
      }
      if (ch == 'C') {
        return 261;
      }
      if (ch == 'D') {
        return 260;
      }
    }
  }
  return ch;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tty_getch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tty_getc@plt>
  cmp    $0x1b,%eax
  je     L67
L12:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L67:
  xor    %eax,%eax
  call   <tty_getc@plt>
  cmp    $0x5b,%eax
  je     L30
  cmp    $0x4f,%eax
  jne    L12
L30:
  xor    %eax,%eax
  call   <tty_getc@plt>
  cmp    $0x41,%eax
  je     L38
  cmp    $0x42,%eax
  je     L9
  cmp    $0x43,%eax
  je     L79
  cmp    $0x44,%eax
  mov    $0x104,%edx
  cmove  %edx,%eax
  jmp    L12
L79:
  mov    $0x105,%eax
  jmp    L12
L38:
  mov    $0x103,%eax
  jmp    L12
L9:
  mov    $0x102,%eax
  jmp    L12
```

assistant: ```c
int tty_getch() {
  int ch;
  ch = tty_getc();
  if (ch == 27) {
    ch = tty_getc();
    if (ch == '[' || ch == 'O') {
      ch = tty_getc();
      if (ch == 'A') {
        return 259;
      }
      if (ch == 'B') {
        return 258;
      }
      if (ch == 'C') {
        return 261;
      }
      if (ch == 'D') {
        return 260;
      }
    }
  }
  return ch;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bic(int x, int m) {
  int z = m ^ (x | m);
  return z;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bic>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    %edi,%eax
  ret
```

assistant: ```c
int bic(int x, int m) {
  int z = m ^ (x | m);
  return z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bic>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    %edi,%eax
  ret
```

assistant: ```c
int bic(int x, int m) {
  int z = m ^ (x | m);
  return z;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bic>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    %edi,%eax
  ret
```

assistant: ```c
int bic(int x, int m) {
  int z = m ^ (x | m);
  return z;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nc_uri>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    0x8(%rsi),%r12
  mov    0x8(%rdi),%rdi
  mov    $0x3a,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L149
  cmpb   $0x2f,0x1(%rax)
  jne    L149
  cmpb   $0x2f,0x2(%rax)
  je     L71
L149:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
L130:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L71:
  lea    0x3(%rax),%rbx
  mov    $0x3a,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L86
L108:
  sub    %ebx,%eax
L38:
  test   %eax,%eax
  je     L64
  cmpb   $0x2e,(%r12)
  je     L92
  cmp    %eax,0x0(%rbp)
  je     L81
L55:
  mov    D55(%rip),%rax
  mov    (%rax),%eax
  jmp    L130
L86:
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L108
  mov    %rbx,%rdi
  call   <strlen@plt>
  jmp    L38
L64:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L130
L92:
  mov    0x0(%rbp),%edx
  cmp    %eax,%edx
  jl     L117
L27:
  mov    D55(%rip),%rax
  mov    (%rax),%eax
  jmp    L130
L117:
  cltq
  movslq %edx,%rcx
  sub    %rcx,%rax
  lea    (%rbx,%rax,1),%rdi
  mov    %r12,%rsi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L27
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  jmp    L130
L81:
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L55
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  jmp    L130
```

assistant: ```c
int nc_uri(ASN1_IA5STRING *uri, ASN1_IA5STRING *base) {
  const char *baseptr = (char *)base->data;
  const char *hostptr = (char *)uri->data;
  const char *p = strchr(hostptr, ':');
  int hostlen;
  if (!p || (p[1] != '/') || (p[2] != '/'))
    return X509_V_ERR_UNSUPPORTED_NAME_SYNTAX;
  hostptr = p + 3;
  p = strchr(hostptr, ':');
  if (!p)
    p = strchr(hostptr, '/');
  if (!p)
    hostlen = strlen(hostptr);
  else
    hostlen = p - hostptr;
  if (hostlen == 0)
    return X509_V_ERR_UNSUPPORTED_NAME_SYNTAX;
  if (*baseptr == '.') {
    if (hostlen > base->length) {
      p = hostptr + hostlen - base->length;
      if (!strncasecmp(p, baseptr, base->length))
        return X509_V_OK;
    }
    return X509_V_ERR_PERMITTED_VIOLATION;
  }
  if ((base->length != (int)hostlen) || strncasecmp(hostptr, baseptr, hostlen))
    return X509_V_ERR_PERMITTED_VIOLATION;
  return X509_V_OK;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nc_uri>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rdi),%rdi
  mov    %rsi,%rbx
  mov    0x8(%rsi),%r12
  mov    $0x3a,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L134
  cmpb   $0x2f,0x1(%rax)
  je     L66
L134:
  mov    D11(%rip),%rax
  mov    (%rax),%eax
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L66:
  cmpb   $0x2f,0x2(%rax)
  jne    L134
  lea    0x3(%rax),%rbp
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L53
L17:
  sub    %ebp,%eax
L110:
  test   %eax,%eax
  je     L134
  cmpb   $0x2e,(%r12)
  mov    (%rbx),%edx
  je     L39
  cmp    %edx,%eax
  je     L35
L19:
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L53:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L17
  mov    %rbp,%rdi
  call   <strlen@plt>
  jmp    L110
  nopl   0x0(%rax)
L35:
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L19
L119:
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L37
L39:
  cmp    %edx,%eax
  jle    L19
  cltq
  movslq %edx,%rcx
  mov    %r12,%rsi
  sub    %rcx,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L19
  jmp    L119
```

assistant: ```c
int nc_uri(ASN1_IA5STRING *uri, ASN1_IA5STRING *base) {
  const char *baseptr = (char *)base->data;
  const char *hostptr = (char *)uri->data;
  const char *p = strchr(hostptr, ':');
  int hostlen;
  if (!p || (p[1] != '/') || (p[2] != '/'))
    return X509_V_ERR_UNSUPPORTED_NAME_SYNTAX;
  hostptr = p + 3;
  p = strchr(hostptr, ':');
  if (!p)
    p = strchr(hostptr, '/');
  if (!p)
    hostlen = strlen(hostptr);
  else
    hostlen = p - hostptr;
  if (hostlen == 0)
    return X509_V_ERR_UNSUPPORTED_NAME_SYNTAX;
  if (*baseptr == '.') {
    if (hostlen > base->length) {
      p = hostptr + hostlen - base->length;
      if (!strncasecmp(p, baseptr, base->length))
        return X509_V_OK;
    }
    return X509_V_ERR_PERMITTED_VIOLATION;
  }
  if ((base->length != (int)hostlen) || strncasecmp(hostptr, baseptr, hostlen))
    return X509_V_ERR_PERMITTED_VIOLATION;
  return X509_V_OK;
}
```