user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    D94(%rip),%r12
  lea    0x1c(%rsp),%rbp
  lea    D58(%rip),%rbx
L19:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  sub    $0x5,%eax
  cmp    $0x2d,%eax
  ja     L19
  lea    0x20(%rsp),%rbx
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D14(%rip),%r14
  lea    D58(%rip),%r13
L92:
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0x1c(%rsp),%eax
  add    $0x4,%r12
  cmp    %ebp,%eax
  jg     L92
  mov    0x20(%rsp),%ebp
  test   %eax,%eax
  jle    L53
  lea    -0x1(%rax),%eax
  lea    0x4(%rbx,%rax,4),%rsi
  mov    %ebp,%r12d
  movl   $0x0,0xc(%rsp)
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  jmp    L80
L88:
  add    $0x1,%r15d
L33:
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  cmp    %eax,%r12d
  cmovg  %eax,%r12d
  add    $0x4,%rbx
  cmp    %rsi,%rbx
  je     L87
L80:
  mov    (%rbx),%eax
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  adc    $0x0,%r14d
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  cmp    $0x1,%edx
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%r13d
  test   %eax,%eax
  jg     L88
  cmp    $0x80000000,%eax
  sbbl   $0xffffffff,0xc(%rsp)
  jmp    L33
L87:
  mov    $0x0,%ebx
L28:
  mov    0x20(%rsp,%rbx,4),%esi
  lea    D97(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x1c(%rsp)
  jg     L28
L74:
  mov    %r14d,%esi
  lea    D108(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13d,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r15d,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D62(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0xf8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  mov    %ebp,%r12d
  movl   $0x0,0xc(%rsp)
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  jmp    L74
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D94
type_infered: string
name: read_data
arguments: label: D58
type_infered: string
name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D97
type_infered: string
name: read_data
arguments: label: D108
type_infered: string
name: read_data
arguments: label: D10
type_infered: string
name: read_data
arguments: label: D59
type_infered: string
name: read_data
arguments: label: D36
type_infered: string
name: read_data
arguments: label: D54
type_infered: string
name: read_data
arguments: label: D62
type_infered: string

tool: D94: numero de elementos del vector

tool: D58: %d

tool: D14: v[%d]=


tool: D97: 
%d


tool: D108: Los numeros Pares son: %d

tool: D10: Los numeros Impares son: %d

tool: D59: Los numeros Positivos son: %d

tool: D36: Los numeros Negativos son: %d

tool: D54: El numero Mayor es: %d

tool: D62: El numero Menor es: %d

assistant: ```c
void main() {
  int vec[50];
  int x, n, par, impar, pos, neg, mayor, menor;
  do {
    printf("numero de elementos del vector");
    scanf("%d", &n);
  } while (n < 5 || n > 50);
  for (x = 0; x < n; x++) {
    printf("v[%d]=\n", x);
    scanf("%d", &vec[x]);
  }
  par = 0;
  impar = 0;
  pos = 0;
  neg = 0;
  mayor = vec[0];
  menor = vec[0];
  for (x = 0; x < n; x++) {
    if (vec[x] % 2 == 0) {
      par++;
    }
    if (vec[x] % 2 == 1) {
      impar++;
    }
    if (vec[x] > 0) {
      pos++;
    }
    if (vec[x] < 0) {
      neg++;
    }
    if (vec[x] > mayor) {
      mayor = vec[x];
    }
    if (vec[x] < menor) {
      menor = vec[x];
    }
  }
  for (x = 0; x < n; x++) {
    printf("\n%d\n", vec[x]);
  }
  printf("Los numeros Pares son: %d", par);
  printf("Los numeros Impares son: %d", impar);
  printf("Los numeros Positivos son: %d", pos);
  printf("Los numeros Negativos son: %d", neg);
  printf("El numero Mayor es: %d", mayor);
  printf("El numero Menor es: %d", menor);
}
```