ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L18
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L10
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L10:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L1
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L1:
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D5
type_infered: string

tool: D12: %d%d%d

tool: D5: %d %d %d

assistant: ```c
main() {
  int a, b, c, temp;
  scanf("%d%d%d", &a, &b, &c);
  if (a > b) {
    temp = a;
    a = b;
    b = temp;
  }
  if (b > c) {
    temp = b;
    b = c;
    c = temp;
  }
  if (a > b) {
    temp = a;
    a = b;
    b = temp;
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  cmp    %edx,%eax
  jle    L13
  mov    %edx,0xc(%rsp)
  mov    %eax,0x10(%rsp)
L13:
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%eax
  cmp    %eax,%edx
  jle    L19
  mov    %eax,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  mov    0xc(%rsp),%edx
  cmp    %eax,%edx
  jle    L19
  mov    %eax,0xc(%rsp)
  mov    %edx,0x10(%rsp)
L19:
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D13
type_infered: string

tool: D5: %d%d%d

tool: D13: %d %d %d

assistant: ```c
main() {
  int a, b, c, temp;
  scanf("%d%d%d", &a, &b, &c);
  if (a > b) {
    temp = a;
    a = b;
    b = temp;
  }
  if (b > c) {
    temp = b;
    b = c;
    c = temp;
  }
  if (a > b) {
    temp = a;
    a = b;
    b = temp;
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%edx
  cmp    %edx,%esi
  jle    L11
  mov    %esi,%eax
  mov    %edx,0xc(%rsp)
  mov    %esi,0x10(%rsp)
  mov    %edx,%esi
  mov    %eax,%edx
L11:
  mov    0x14(%rsp),%ecx
  cmp    %edx,%ecx
  jge    L1
  mov    %ecx,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  cmp    %esi,%ecx
  jge    L30
  mov    %ecx,0xc(%rsp)
  mov    %esi,%edx
  mov    %esi,0x10(%rsp)
  mov    %ecx,%esi
  mov    0x14(%rsp),%ecx
L1:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L41:
  call   <__stack_chk_fail@plt>
L30:
  mov    %ecx,%edx
  mov    0x14(%rsp),%ecx
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D15
type: string
name: read_data
arguments: label: D18
type: string

tool: D15: %d%d%d

tool: D18: %d %d %d

assistant: ```c
main() {
  int a, b, c, temp;
  scanf("%d%d%d", &a, &b, &c);
  if (a > b) {
    temp = a;
    a = b;
    b = temp;
  }
  if (b > c) {
    temp = b;
    b = c;
    c = temp;
  }
  if (a > b) {
    temp = a;
    a = b;
    b = temp;
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%edx
  cmp    %edx,%esi
  jle    L47
  mov    %esi,%eax
  mov    %edx,0xc(%rsp)
  mov    %esi,0x10(%rsp)
  mov    %edx,%esi
  mov    %eax,%edx
L47:
  mov    0x14(%rsp),%ecx
  cmp    %edx,%ecx
  jge    L23
  mov    %ecx,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  cmp    %esi,%ecx
  jge    L18
  mov    %ecx,0xc(%rsp)
  mov    %esi,%edx
  mov    %esi,0x10(%rsp)
  mov    %ecx,%esi
  mov    0x14(%rsp),%ecx
L23:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
L18:
  mov    %ecx,%edx
  mov    0x14(%rsp),%ecx
  jmp    L23
```

tool_calls: name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D3
data_type: string

tool: D16: %d%d%d

tool: D3: %d %d %d

assistant: ```c
main() {
  int a, b, c, temp;
  scanf("%d%d%d", &a, &b, &c);
  if (a > b) {
    temp = a;
    a = b;
    b = temp;
  }
  if (b > c) {
    temp = b;
    b = c;
    c = temp;
  }
  if (a > b) {
    temp = a;
    a = b;
    b = temp;
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<logger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string

tool: D0: server.log

tool: D12: %s

assistant: ```c
void logger(char *str) {
  char *file = "server.log";
  printf("%s", str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<logger>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: %s

assistant: ```c
void logger(char *str) {
  char *file = "server.log";
  printf("%s", str);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<logger>:
  endbr64
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: %s

assistant: ```c
void logger(char *str) {
  char *file = "server.log";
  printf("%s", str);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<logger>:
  endbr64
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string

tool: D6: %s

assistant: ```c
void logger(char *str) {
  char *file = "server.log";
  printf("%s", str);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xa,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  mov    %eax,%edx
  mov    %edx,-0x14(%rbp)
  mov    %ebx,%esi
  mov    %ebp,%ecx
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %esi,-0x10(%rbp)
  mov    %ecx,-0xc(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%esi
  mov    %eax,%ebx
  mov    %edx,%ebp
  mov    %ecx,%edi
  mov    %esi,%esi
  mov    -0x4(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D6: a= %d, b = %d, base = %d, r1 = %d


assistant: ```c
int main(void) {
  int a = 10, b;
  asm("movl %1, %%eax; movl %%eax, %0;" : "=r"(b) : "r"(a) : "%eax");
  int base, sp, hp, r1;
  asm("movl %%ebx, %0; movl %%ebp, %1; movl %%edi, %2; movl %%esi, %3;" : "=r"(base), "=r"(sp), "=r"(hp), "=r"(r1));
  printf("a= %d, b = %d, base = %d, r1 = %d\n", a, b, base, r1);
  asm("movl %0, %%ebx; movl %1, %%ebp; movl %2, %%edi; movl %3, %%esi;" ::"r"(base), "r"(sp), "r"(hp), "r"(r1));
  printf("a= %d, b = %d, base = %d, r1 = %d\n", a, b, base, r1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%ebx
  mov    %ebx,%eax
  mov    %eax,%ebx
  mov    %ebx,%ebp
  mov    %ebp,%r14d
  mov    %edi,%r15d
  mov    %esi,%r12d
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0xa,%esi
  lea    D2(%rip),%r13
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%ebx
  mov    %r14d,%ebp
  mov    %r15d,%edi
  mov    %r12d,%esi
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0xa,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D2: a= %d, b = %d, base = %d, r1 = %d


assistant: ```c
int main(void) {
  int a = 10, b;
  asm("movl %1, %%eax; movl %%eax, %0;" : "=r"(b) : "r"(a) : "%eax");
  int base, sp, hp, r1;
  asm("movl %%ebx, %0; movl %%ebp, %1; movl %%edi, %2; movl %%esi, %3;" : "=r"(base), "=r"(sp), "=r"(hp), "=r"(r1));
  printf("a= %d, b = %d, base = %d, r1 = %d\n", a, b, base, r1);
  asm("movl %0, %%ebx; movl %1, %%ebp; movl %2, %%edi; movl %3, %%esi;" ::"r"(base), "r"(sp), "r"(hp), "r"(r1));
  printf("a= %d, b = %d, base = %d, r1 = %d\n", a, b, base, r1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xa,%esi
  push   %r14
  push   %r13
  push   %r12
  mov    $0xa,%r12d
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    %r12d,%eax
  mov    %eax,%r12d
  mov    %ebx,%r13d
  mov    %ebp,%r14d
  mov    %edi,%r15d
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%ebx
  mov    %r14d,%ebp
  mov    %r15d,%edi
  mov    %ebx,%esi
  mov    $0xa,%esi
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: a= %d, b = %d, base = %d, r1 = %d


assistant: ```c
int main(void) {
  int a = 10, b;
  asm("movl %1, %%eax; movl %%eax, %0;" : "=r"(b) : "r"(a) : "%eax");
  int base, sp, hp, r1;
  asm("movl %%ebx, %0; movl %%ebp, %1; movl %%edi, %2; movl %%esi, %3;" : "=r"(base), "=r"(sp), "=r"(hp), "=r"(r1));
  printf("a= %d, b = %d, base = %d, r1 = %d\n", a, b, base, r1);
  asm("movl %0, %%ebx; movl %1, %%ebp; movl %2, %%edi; movl %3, %%esi;" ::"r"(base), "r"(sp), "r"(hp), "r"(r1));
  printf("a= %d, b = %d, base = %d, r1 = %d\n", a, b, base, r1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xa,%esi
  push   %r14
  push   %r13
  push   %r12
  mov    $0xa,%r12d
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    %r12d,%eax
  mov    %eax,%r12d
  mov    %ebx,%r13d
  mov    %ebp,%r14d
  mov    %edi,%r15d
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%ebx
  mov    %r14d,%ebp
  mov    %r15d,%edi
  mov    %ebx,%esi
  mov    $0xa,%esi
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string

tool: D4: a= %d, b = %d, base = %d, r1 = %d


assistant: ```c
int main(void) {
  int a = 10, b;
  asm("movl %1, %%eax; movl %%eax, %0;" : "=r"(b) : "r"(a) : "%eax");
  int base, sp, hp, r1;
  asm("movl %%ebx, %0; movl %%ebp, %1; movl %%edi, %2; movl %%esi, %3;" : "=r"(base), "=r"(sp), "=r"(hp), "=r"(r1));
  printf("a= %d, b = %d, base = %d, r1 = %d\n", a, b, base, r1);
  asm("movl %0, %%ebx; movl %1, %%ebp; movl %2, %%edi; movl %3, %%esi;" ::"r"(base), "r"(sp), "r"(hp), "r"(r1));
  printf("a= %d, b = %d, base = %d, r1 = %d\n", a, b, base, r1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D4(%rip),%rax
  movl   $0x0,(%rax)
  movl   $0x20,-0x8(%rbp)
  jmp    L12
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <output_char@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <change_state@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L12:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L18
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int last_char, cur_char;
  extern int state;
  state = 0;
  last_char = ' ';
  while ((cur_char = getchar()) != EOF) {
    output_char(cur_char);
    change_state(cur_char, last_char);
    last_char = cur_char;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D18(%rip),%rax
  movl   $0x0,(%rax)
  mov    $0x20,%ebp
  jmp    L6
L5:
  mov    %ebx,%edi
  call   <output_char@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <change_state@plt>
  mov    %ebx,%ebp
L6:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D17(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int last_char, cur_char;
  extern int state;
  state = 0;
  last_char = ' ';
  while ((cur_char = getchar()) != EOF) {
    output_char(cur_char);
    change_state(cur_char, last_char);
    last_char = cur_char;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    D13(%rip),%rax
  push   %r12
  mov    D8(%rip),%r12
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  movl   $0x0,(%rax)
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%edi
  call   <output_char@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    %ebx,%ebp
  call   <change_state@plt>
L15:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L14
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int last_char, cur_char;
  extern int state;
  state = 0;
  last_char = ' ';
  while ((cur_char = getchar()) != EOF) {
    output_char(cur_char);
    change_state(cur_char, last_char);
    last_char = cur_char;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    D14(%rip),%rax
  push   %r12
  mov    D2(%rip),%r12
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  movl   $0x0,(%rax)
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  call   <output_char@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    %ebx,%ebp
  call   <change_state@plt>
L10:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int last_char, cur_char;
  extern int state;
  state = 0;
  last_char = ' ';
  while ((cur_char = getchar()) != EOF) {
    output_char(cur_char);
    change_state(cur_char, last_char);
    last_char = cur_char;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x2,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string

tool: D1: a = %d, b = %d, c = %d


assistant: ```c
int main(int argc, char *argv[]) {
  enum { a, b, c };
  printf("a = %d, b = %d, c = %d\n", a, b, c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: a = %d, b = %d, c = %d


assistant: ```c
int main(int argc, char *argv[]) {
  enum { a, b, c };
  printf("a = %d, b = %d, c = %d\n", a, b, c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: a = %d, b = %d, c = %d


assistant: ```c
int main(int argc, char *argv[]) {
  enum { a, b, c };
  printf("a = %d, b = %d, c = %d\n", a, b, c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string

tool: D5: a = %d, b = %d, c = %d


assistant: ```c
int main(int argc, char *argv[]) {
  enum { a, b, c };
  printf("a = %d, b = %d, c = %d\n", a, b, c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D25
datatype: string

tool: D26: 

tool: D25: %d 

assistant: ```c
void dump(int a[], int size) {
  int i = 0;
  printf("\r\n");
  for (i = 0; i < size; i++) {
    printf("%d ", a[i]);
  }
  printf("\r\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dump>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D26(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L15
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D20(%rip),%rbp
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L8
L15:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string

tool: D26: 

tool: D20: %d 

assistant: ```c
void dump(int a[], int size) {
  int i = 0;
  printf("\r\n");
  for (i = 0; i < size; i++) {
    printf("%d ", a[i]);
  }
  printf("\r\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump>:
  endbr64
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L7
  lea    -0x1(%rbp),%eax
  lea    D9(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   (%rax)
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
L7:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D15: 

tool: D9: %d 

assistant: ```c
void dump(int a[], int size) {
  int i = 0;
  printf("\r\n");
  for (i = 0; i < size; i++) {
    printf("%d ", a[i]);
  }
  printf("\r\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dump>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L19
  lea    -0x1(%rbp),%eax
  lea    D8(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   (%rax)
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
L19:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D0: 

tool: D8: %d 

assistant: ```c
void dump(int a[], int size) {
  int i = 0;
  printf("\r\n");
  for (i = 0; i < size; i++) {
    printf("%d ", a[i]);
  }
  printf("\r\n");
}
```