ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<mods3600>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D15(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movsd  D15(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
data_type: f64

tool: D15: 1296000

assistant: ```c
double mods3600(double x) {
  double y;
  y = x - 1.296e6 * floor(x / 1.296e6);
  return y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mods3600>:
  endbr64
  movapd %xmm0,%xmm3
  divsd  D17(%rip),%xmm3
  movapd %xmm3,%xmm1
  movsd  D2(%rip),%xmm4
  movapd %xmm3,%xmm2
  andpd  %xmm4,%xmm2
  movsd  D36(%rip),%xmm5
  ucomisd %xmm2,%xmm5
  jbe    L1
  cvttsd2si %xmm3,%rax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movapd %xmm2,%xmm1
  cmpnlesd %xmm3,%xmm1
  movsd  D12(%rip),%xmm5
  andpd  %xmm5,%xmm1
  subsd  %xmm1,%xmm2
  andnpd %xmm3,%xmm4
  movapd %xmm2,%xmm1
  orpd   %xmm4,%xmm1
L1:
  mulsd  D17(%rip),%xmm1
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_infered: f64
name: disassemble_data
arguments: data_tag: D2
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D36
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D12
type_infered: byte[8]

tool: D17: 1296000

tool: {"D2": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double mods3600(double x) {
  double y;
  y = x - 1.296e6 * floor(x / 1.296e6);
  return y;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mods3600>:
  endbr64
  movsd  D30(%rip),%xmm4
  movapd %xmm0,%xmm1
  movsd  D9(%rip),%xmm3
  movsd  D6(%rip),%xmm5
  divsd  %xmm4,%xmm1
  movapd %xmm1,%xmm2
  andpd  %xmm3,%xmm2
  ucomisd %xmm2,%xmm5
  jbe    L2
  cvttsd2si %xmm1,%rax
  pxor   %xmm2,%xmm2
  movsd  D39(%rip),%xmm6
  andnpd %xmm1,%xmm3
  cvtsi2sd %rax,%xmm2
  movapd %xmm2,%xmm5
  cmpnlesd %xmm1,%xmm5
  andpd  %xmm6,%xmm5
  subsd  %xmm5,%xmm2
  orpd   %xmm3,%xmm2
  movapd %xmm2,%xmm1
L2:
  mulsd  %xmm4,%xmm1
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
data_type: f64
name: extract_symbolic_data
arguments: data_label: D9
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D6
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D39
data_type: byte[8]

tool: D30: 1296000

tool: {"D9": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double mods3600(double x) {
  double y;
  y = x - 1.296e6 * floor(x / 1.296e6);
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mods3600>:
  endbr64
  movsd  D25(%rip),%xmm4
  movapd %xmm0,%xmm1
  movsd  D5(%rip),%xmm3
  movsd  D17(%rip),%xmm5
  divsd  %xmm4,%xmm1
  movapd %xmm1,%xmm2
  andpd  %xmm3,%xmm2
  ucomisd %xmm2,%xmm5
  jbe    L8
  cvttsd2si %xmm1,%rax
  pxor   %xmm2,%xmm2
  movsd  D33(%rip),%xmm6
  andnpd %xmm1,%xmm3
  cvtsi2sd %rax,%xmm2
  movapd %xmm2,%xmm5
  cmpnlesd %xmm1,%xmm5
  andpd  %xmm6,%xmm5
  subsd  %xmm5,%xmm2
  orpd   %xmm3,%xmm2
  movapd %xmm2,%xmm1
L8:
  mulsd  %xmm4,%xmm1
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D25
type: f64
name: retrieve_data
arguments: label: D5
type: byte[8]
name: retrieve_data
arguments: label: D17
type: byte[8]
name: retrieve_data
arguments: label: D33
type: byte[8]

tool: D25: 1296000

tool: {"D5": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double mods3600(double x) {
  double y;
  y = x - 1.296e6 * floor(x / 1.296e6);
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0xa,%esi
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  lea    0x38(%rsp),%r12
  mov    %rbx,%rbp
  lea    D30(%rip),%r13
L30:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L30
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rbp
  lea    D17(%rip),%r13
L31:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L31
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%esi
L15:
  add    (%rbx),%esi
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L15
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  divss  D34(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  lea    D37(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  subss  D9(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D56(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D64
type_infered: string
name: disassemble_data
arguments: tag: D30
type_infered: string
name: disassemble_data
arguments: tag: D46
type_infered: string
name: disassemble_data
arguments: tag: D17
type_infered: string
name: disassemble_data
arguments: tag: D34
type_infered: byte[4]
name: disassemble_data
arguments: tag: D37
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: byte[4]
name: disassemble_data
arguments: tag: D56
type_infered: string

tool: D64: Enter %d golf socres:


tool: D30: %d

tool: D46: The scores read in are as follows:

tool: D17: %5d

tool: {"D34": [0x00,0x00,0x20,0x41]}

tool: D37: Sum of scores = %d, average = %.2f


tool: {"D9": [0x00,0x00,0x90,0x42]}

tool: D56: That's a handicap of %.0f.


assistant: ```c
int main(void) {
  int index, score[10];
  int sum = 0;
  float average;
  printf("Enter %d golf socres:\n", 10);
  for (index = 0; index < 10; index++)
    scanf("%d", &score[index]);
  printf("The scores read in are as follows:\n");
  for (index = 0; index < 10; index++)
    printf("%5d", score[index]);
  printf("\n");
  for (index = 0; index < 10; index++)
    sum += score[index];
  average = (float)sum / 10;
  printf("Sum of scores = %d, average = %.2f\n", sum, average);
  printf("That's a handicap of %.0f.\n", average - 72);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%esi
  lea    D49(%rip),%rdi
  lea    D28(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x38(%rsp),%r12
  mov    %rbx,%rbp
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L18
  lea    D37(%rip),%rdi
  mov    %rbx,%rbp
  lea    D61(%rip),%r13
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L25:
  add    (%rbx),%esi
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L25
  lea    D19(%rip),%rdi
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtsi2ss %esi,%xmm1
  divss  D50(%rip),%xmm1
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  subss  D14(%rip),%xmm1
  lea    D38(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D49
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D37
data_type: string
name: retrieve_data
arguments: tag: D61
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D50
data_type: byte[4]
name: retrieve_data
arguments: tag: D14
data_type: byte[4]
name: retrieve_data
arguments: tag: D38
data_type: string

tool: D49: Enter %d golf socres:


tool: D28: %d

tool: D37: The scores read in are as follows:

tool: D61: %5d

tool: D19: Sum of scores = %d, average = %.2f


tool: {"D50": [0x00,0x00,0x20,0x41]}

tool: {"D14": [0x00,0x00,0x90,0x42]}

tool: D38: That's a handicap of %.0f.


assistant: ```c
int main(void) {
  int index, score[10];
  int sum = 0;
  float average;
  printf("Enter %d golf socres:\n", 10);
  for (index = 0; index < 10; index++)
    scanf("%d", &score[index]);
  printf("The scores read in are as follows:\n");
  for (index = 0; index < 10; index++)
    printf("%5d", score[index]);
  printf("\n");
  for (index = 0; index < 10; index++)
    sum += score[index];
  average = (float)sum / 10;
  printf("Sum of scores = %d, average = %.2f\n", sum, average);
  printf("That's a handicap of %.0f.\n", average - 72);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%esi
  lea    D2(%rip),%rdi
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x38(%rsp),%r12
  mov    %rbx,%rbp
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L6
  lea    D65(%rip),%rdi
  lea    D29(%rip),%rbp
  call   <puts@plt>
  nop
L20:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  movdqa 0x10(%rsp),%xmm0
  mov    0x30(%rsp),%edx
  lea    D22(%rip),%rdi
  paddd  0x20(%rsp),%xmm0
  mov    0x34(%rsp),%eax
  movdqa %xmm0,%xmm1
  add    %edx,%eax
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  movd   %xmm0,%esi
  pxor   %xmm0,%xmm0
  add    %eax,%esi
  mov    $0x1,%eax
  cvtsi2ss %esi,%xmm1
  divss  D76(%rip),%xmm1
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  subss  D24(%rip),%xmm1
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string
name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D65
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D22
datatype: string
name: extract_symbolic_data
arguments: data_tag: D76
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D24
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D36
datatype: string

tool: D2: Enter %d golf socres:


tool: D11: %d

tool: D65: The scores read in are as follows:

tool: D29: %5d

tool: D22: Sum of scores = %d, average = %.2f


tool: {"D76": [0x00,0x00,0x20,0x41]}

tool: {"D24": [0x00,0x00,0x90,0x42]}

tool: D36: That's a handicap of %.0f.


assistant: ```c
int main(void) {
  int index, score[10];
  int sum = 0;
  float average;
  printf("Enter %d golf socres:\n", 10);
  for (index = 0; index < 10; index++)
    scanf("%d", &score[index]);
  printf("The scores read in are as follows:\n");
  for (index = 0; index < 10; index++)
    printf("%5d", score[index]);
  printf("\n");
  for (index = 0; index < 10; index++)
    sum += score[index];
  average = (float)sum / 10;
  printf("Sum of scores = %d, average = %.2f\n", sum, average);
  printf("That's a handicap of %.0f.\n", average - 72);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<multiply270>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L21
L27:
  movl   $0x0,-0x3c(%rbp)
  jmp    L18
L34:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L18:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L34
  addl   $0x1,-0x40(%rbp)
L21:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L27
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply270(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multiply270>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L21:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L1:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L1
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  ret
```

assistant: ```c
void multiply270(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<multiply270>:
  endbr64
  test   %edi,%edi
  jle    L3
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L29
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L6
  pop    %rbx
  ret
L3:
  ret
```

assistant: ```c
void multiply270(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply270>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L90
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L19:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L79
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L79
  nopl   0x0(%rax)
L45:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L45
  cmp    -0x24(%rsp),%r11d
  je     L8
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L8
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L8
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L8:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L19
L90:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L65:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L65
  mov    -0x18(%rsp),%r8
  jmp    L8
```

assistant: ```c
void multiply270(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<err_found>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <ft_putendl_fd@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void err_found(char *str) {
  ft_putendl_fd(str, 2);
  exit(3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<err_found>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  call   <ft_putendl_fd@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void err_found(char *str) {
  ft_putendl_fd(str, 2);
  exit(3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<err_found>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  call   <ft_putendl_fd@plt>
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1060 <exit@plt>
```

assistant: ```c
void err_found(char *str) {
  ft_putendl_fd(str, 2);
  exit(3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<err_found>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  call   <ft_putendl_fd@plt>
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1060 <exit@plt>
```

assistant: ```c
void err_found(char *str) {
  ft_putendl_fd(str, 2);
  exit(3);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  call   <abort@plt>
```

assistant: ```c
int main() {
  struct {
    int x;
  } *p = malloc(sizeof(*p));
  abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <abort@plt>
```

assistant: ```c
int main() {
  struct {
    int x;
  } *p = malloc(sizeof(*p));
  abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rax
  call   <abort@plt>
```

assistant: ```c
int main() {
  struct {
    int x;
  } *p = malloc(sizeof(*p));
  abort();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rax
  call   <abort@plt>
```

assistant: ```c
int main() {
  struct {
    int x;
  } *p = malloc(sizeof(*p));
  abort();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: /


assistant: ```c
int main(int argc, char *argv[]) {
  printf("/\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: /


assistant: ```c
int main(int argc, char *argv[]) {
  printf("/\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: string

tool: D0: /


assistant: ```c
int main(int argc, char *argv[]) {
  printf("/\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: /


assistant: ```c
int main(int argc, char *argv[]) {
  printf("/\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<XTL_SubVars_DecrementValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <XTL_SubVars_GetValueInt@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffd8f1,-0x4(%rbp)
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L11
L10:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <XTL_SubVars_UpdateInt@plt>
L11:
  leave
  ret
```

assistant: ```c
int XTL_SubVars_DecrementValue(char *key) {
  int retval;
  retval = XTL_SubVars_GetValueInt(key);
  if (retval == -9999)
    return -1;
  --retval;
  return XTL_SubVars_UpdateInt(key, retval);
}
```