ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ce_parse_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L73
L66:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
L73:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cmp    $0x3b,%eax
  jg     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L91
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L66
L91:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  cmpl   $0x3b,-0xc(%rbp)
  jle    L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4: Warning: module name truncated to:%s


assistant: ```c
void ce_parse_name(char *cpSrc, char *cpDest) {
  int i = 1;
  char *cpDest2 = cpDest;
  for (; i++ < 60 && *cpSrc != '>' && *cpSrc != '+' && *cpSrc != '-' && *cpSrc != '(' && *cpSrc != '\"' && *cpSrc != ' ' && *cpSrc != '\0' && *cpSrc != '\n' && *cpSrc != '.'; cpSrc++)
    *cpDest++ = *cpSrc;
  *cpDest = '\0';
  if (i >= 60)
    printf("Warning: module name truncated to:%s\n", cpDest2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ce_parse_name>:
  endbr64
  mov    %rsi,%rdx
  mov    $0x2,%ecx
  movabs $0x400000000401,%r9
  movabs $0x290500000000,%r8
  jmp    L76
L54:
  cmp    $0x2e,%al
  jbe    L36
L35:
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  add    $0x1,%rdi
  add    $0x1,%ecx
  cmp    $0x3d,%ecx
  je     L66
L76:
  movzbl (%rdi),%eax
  cmp    $0x3e,%al
  je     L50
  cmp    $0x2d,%al
  ja     L54
  bt     %rax,%r8
  jb     L50
L36:
  bt     %rax,%r9
  jae    L35
L50:
  movb   $0x0,(%rdx)
  cmp    $0x3b,%ecx
  jg     L12
  ret
L66:
  movb   $0x0,(%rdx)
L12:
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: Warning: module name truncated to:%s


assistant: ```c
void ce_parse_name(char *cpSrc, char *cpDest) {
  int i = 1;
  char *cpDest2 = cpDest;
  for (; i++ < 60 && *cpSrc != '>' && *cpSrc != '+' && *cpSrc != '-' && *cpSrc != '(' && *cpSrc != '\"' && *cpSrc != ' ' && *cpSrc != '\0' && *cpSrc != '\n' && *cpSrc != '.'; cpSrc++)
    *cpDest++ = *cpSrc;
  *cpDest = '\0';
  if (i >= 60)
    printf("Warning: module name truncated to:%s\n", cpDest2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ce_parse_name>:
  endbr64
  mov    $0x2,%ecx
  lea    0x3b(%rsi),%r9
  mov    %rsi,%rdx
  movabs $0xffffbffffffffbfe,%r11
  movabs $0x290500000000,%r10
  sub    %esi,%ecx
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L50:
  bt     %rax,%r11
  jae    L18
  add    $0x1,%rdx
  add    $0x1,%rdi
  mov    %al,-0x1(%rdx)
  cmp    %r9,%rdx
  je     L75
L88:
  movzbl (%rdi),%eax
  lea    (%rcx,%rdx,1),%r8d
  cmp    $0x3e,%al
  je     L18
  cmp    $0x2d,%al
  ja     L43
  bt     %rax,%r10
  jae    L50
L18:
  movb   $0x0,(%rdx)
  cmp    $0x3b,%r8d
  jg     L53
  ret
  nopl   (%rax)
L43:
  cmp    $0x2e,%al
  je     L50
  add    $0x1,%rdx
  add    $0x1,%rdi
  mov    %al,-0x1(%rdx)
  cmp    %r9,%rdx
  jne    L88
L75:
  movb   $0x0,(%rdx)
L53:
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: Warning: module name truncated to:%s


assistant: ```c
void ce_parse_name(char *cpSrc, char *cpDest) {
  int i = 1;
  char *cpDest2 = cpDest;
  for (; i++ < 60 && *cpSrc != '>' && *cpSrc != '+' && *cpSrc != '-' && *cpSrc != '(' && *cpSrc != '\"' && *cpSrc != ' ' && *cpSrc != '\0' && *cpSrc != '\n' && *cpSrc != '.'; cpSrc++)
    *cpDest++ = *cpSrc;
  *cpDest = '\0';
  if (i >= 60)
    printf("Warning: module name truncated to:%s\n", cpDest2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ce_parse_name>:
  endbr64
  mov    $0x2,%ecx
  lea    0x3b(%rsi),%r9
  mov    %rsi,%rdx
  movabs $0xffffbffffffffbfe,%r11
  movabs $0x290500000000,%r10
  sub    %esi,%ecx
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L62:
  bt     %rax,%r11
  jae    L29
  add    $0x1,%rdx
  add    $0x1,%rdi
  mov    %al,-0x1(%rdx)
  cmp    %r9,%rdx
  je     L39
L0:
  movzbl (%rdi),%eax
  lea    (%rcx,%rdx,1),%r8d
  cmp    $0x3e,%al
  je     L29
  cmp    $0x2d,%al
  ja     L49
  bt     %rax,%r10
  jae    L62
L29:
  movb   $0x0,(%rdx)
  cmp    $0x3b,%r8d
  jg     L70
  ret
  nopl   (%rax)
L49:
  cmp    $0x2e,%al
  je     L62
  add    $0x1,%rdx
  add    $0x1,%rdi
  mov    %al,-0x1(%rdx)
  cmp    %r9,%rdx
  jne    L0
L39:
  movb   $0x0,(%rdx)
L70:
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: Warning: module name truncated to:%s


assistant: ```c
void ce_parse_name(char *cpSrc, char *cpDest) {
  int i = 1;
  char *cpDest2 = cpDest;
  for (; i++ < 60 && *cpSrc != '>' && *cpSrc != '+' && *cpSrc != '-' && *cpSrc != '(' && *cpSrc != '\"' && *cpSrc != ' ' && *cpSrc != '\0' && *cpSrc != '\n' && *cpSrc != '.'; cpSrc++)
    *cpDest++ = *cpSrc;
  *cpDest = '\0';
  if (i >= 60)
    printf("Warning: module name truncated to:%s\n", cpDest2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4f0,%rsp
  mov    %rdi,-0x4d8(%rbp)
  mov    %esi,-0x4dc(%rbp)
  mov    %rdx,-0x4e8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L17
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L17:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4c8(%rbp)
  mov    -0x4e8(%rbp),%rdx
  mov    -0x4c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x4c4(%rbp),%ecx
  mov    -0x4e8(%rbp),%rdx
  lea    -0x4c0(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0x4c8(%rbp)
  cmpl   $0x0,-0x4c8(%rbp)
  js     L3
  cmpl   $0x400,-0x4c8(%rbp)
  jle    L2
L3:
  movb   $0x0,-0xc1(%rbp)
L2:
  mov    -0x4c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void _error(char *file, int line, char *msg, ...) {
  va_list ap;
  char buf[1024];
  int len = 0;
  va_start(ap, msg);
  len = vsnprintf(buf, 1024, msg, ap);
  if ((len < 0) || (len > 1024))
    buf[1023] = '\0';
  ;
  va_end(ap);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rsi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    $0x400,%esi
  call   <vsnprintf@plt>
  cmp    $0x400,%eax
  jbe    L5
  movb   $0x0,0x3ff(%rsp)
L5:
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_end@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _error(char *file, int line, char *msg, ...) {
  va_list ap;
  char buf[1024];
  int len = 0;
  va_start(ap, msg);
  len = vsnprintf(buf, 1024, msg, ap);
  if ((len < 0) || (len > 1024))
    buf[1023] = '\0';
  ;
  va_end(ap);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_error>:
  endbr64
  push   %r13
  mov    %rdx,%rsi
  mov    %rdx,%r13
  push   %r12
  xor    %r12d,%r12d
  mov    %r12d,%edi
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    $0x400,%esi
  call   <vsnprintf@plt>
  cmp    $0x400,%eax
  jbe    L11
  movb   $0x0,0x3ff(%rsp)
L11:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x418,%rsp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _error(char *file, int line, char *msg, ...) {
  va_list ap;
  char buf[1024];
  int len = 0;
  va_start(ap, msg);
  len = vsnprintf(buf, 1024, msg, ap);
  if ((len < 0) || (len > 1024))
    buf[1023] = '\0';
  ;
  va_end(ap);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_error>:
  endbr64
  push   %r13
  mov    %rdx,%rsi
  mov    %rdx,%r13
  push   %r12
  xor    %r12d,%r12d
  mov    %r12d,%edi
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    $0x400,%esi
  call   <vsnprintf@plt>
  cmp    $0x400,%eax
  jbe    L13
  movb   $0x0,0x3ff(%rsp)
L13:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x418,%rsp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _error(char *file, int line, char *msg, ...) {
  va_list ap;
  char buf[1024];
  int len = 0;
  va_start(ap, msg);
  len = vsnprintf(buf, 1024, msg, ap);
  if ((len < 0) || (len > 1024))
    buf[1023] = '\0';
  ;
  va_end(ap);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<ui24_to_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t *ui24_to_bytes(uint8_t *buf, uint32_t val) {
  buf[0] = (val >> 16) & 0xff;
  buf[1] = (val >> 8) & 0xff;
  buf[2] = (val)&0xff;
  return buf + 3;
}
```
user: What is the c source code of the assembly code below?

```asm
<ui24_to_bytes>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  mov    %edx,0x4(%rdi)
  and    $0xff,%eax
  mov    %eax,0x8(%rdi)
  lea    0xc(%rdi),%rax
  ret
```

assistant: ```c
uint8_t *ui24_to_bytes(uint8_t *buf, uint32_t val) {
  buf[0] = (val >> 16) & 0xff;
  buf[1] = (val >> 8) & 0xff;
  buf[2] = (val)&0xff;
  return buf + 3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ui24_to_bytes>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %eax,0x8(%rdi)
  lea    0xc(%rdi),%rax
  mov    %edx,0x4(%rdi)
  ret
```

assistant: ```c
uint8_t *ui24_to_bytes(uint8_t *buf, uint32_t val) {
  buf[0] = (val >> 16) & 0xff;
  buf[1] = (val >> 8) & 0xff;
  buf[2] = (val)&0xff;
  return buf + 3;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ui24_to_bytes>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %eax,0x8(%rdi)
  lea    0xc(%rdi),%rax
  mov    %edx,0x4(%rdi)
  ret
```

assistant: ```c
uint8_t *ui24_to_bytes(uint8_t *buf, uint32_t val) {
  buf[0] = (val >> 16) & 0xff;
  buf[1] = (val >> 8) & 0xff;
  buf[2] = (val)&0xff;
  return buf + 3;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L27
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  jmp    L1
L27:
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int is_directory(const char *filename) {
  struct stat buffer;
  int status;
  status = stat(filename, &buffer);
  if (status == 0) {
    return S_ISDIR(buffer.st_mode);
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_directory>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L2
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L2:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  jmp    L4
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *filename) {
  struct stat buffer;
  int status;
  status = stat(filename, &buffer);
  if (status == 0) {
    return S_ISDIR(buffer.st_mode);
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_directory>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L24
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L24:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  jmp    L0
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *filename) {
  struct stat buffer;
  int status;
  status = stat(filename, &buffer);
  if (status == 0) {
    return S_ISDIR(buffer.st_mode);
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_directory>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L8
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L8:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  jmp    L3
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *filename) {
  struct stat buffer;
  int status;
  status = stat(filename, &buffer);
  if (status == 0) {
    return S_ISDIR(buffer.st_mode);
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SDBMHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x6,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L19
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int SDBMHash(unsigned char *str, unsigned int len) {
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (*str) + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SDBMHash>:
  endbr64
  test   %esi,%esi
  je     L15
  mov    %esi,%eax
  lea    (%rdi,%rax,1),%rcx
  mov    $0x0,%eax
L11:
  imul   $0x1003f,%eax,%eax
  movzbl (%rdi),%edx
  add    %edx,%eax
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L11
  ret
L15:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int SDBMHash(unsigned char *str, unsigned int len) {
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (*str) + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SDBMHash>:
  endbr64
  test   %esi,%esi
  je     L18
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L10:
  imul   $0x1003f,%eax,%eax
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L10
  ret
  nopl   (%rax)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int SDBMHash(unsigned char *str, unsigned int len) {
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (*str) + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SDBMHash>:
  endbr64
  test   %esi,%esi
  je     L2
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L13:
  imul   $0x1003f,%eax,%eax
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L13
  ret
  nopl   (%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int SDBMHash(unsigned char *str, unsigned int len) {
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (*str) + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlen16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L12:
  addq   $0x2,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  jne    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen16(unsigned short *s) {
  int len = 0;
  while (*s) {
    s++;
    len++;
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlen16>:
  endbr64
  cmpw   $0x0,(%rdi)
  je     L9
  mov    $0x0,%eax
L7:
  add    $0x2,%rdi
  add    $0x1,%eax
  cmpw   $0x0,(%rdi)
  jne    L7
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strlen16(unsigned short *s) {
  int len = 0;
  while (*s) {
    s++;
    len++;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen16>:
  endbr64
  xor    %eax,%eax
  cmpw   $0x0,(%rdi)
  je     L16
  nopl   0x0(%rax)
L7:
  add    $0x2,%rdi
  add    $0x1,%eax
  cmpw   $0x0,(%rdi)
  jne    L7
  ret
  xchg   %ax,%ax
L16:
  ret
```

assistant: ```c
int strlen16(unsigned short *s) {
  int len = 0;
  while (*s) {
    s++;
    len++;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen16>:
  endbr64
  xor    %eax,%eax
  cmpw   $0x0,(%rdi)
  je     L13
  nopl   0x0(%rax)
L0:
  add    $0x2,%rdi
  add    $0x1,%eax
  cmpw   $0x0,(%rdi)
  jne    L0
  ret
  xchg   %ax,%ax
L13:
  ret
```

assistant: ```c
int strlen16(unsigned short *s) {
  int len = 0;
  while (*s) {
    s++;
    len++;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buffer_append_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <buffer_append@plt>
  nop
  leave
  ret
```

assistant: ```c
void buffer_append_string(struct Buffer *buffer, const char *data) {
  int len = strlen(data);
  buffer_append(buffer, data, len);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<buffer_append_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <buffer_append@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void buffer_append_string(struct Buffer *buffer, const char *data) {
  int len = strlen(data);
  buffer_append(buffer, data, len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<buffer_append_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1070 <buffer_append@plt>
```

assistant: ```c
void buffer_append_string(struct Buffer *buffer, const char *data) {
  int len = strlen(data);
  buffer_append(buffer, data, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<buffer_append_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1070 <buffer_append@plt>
```

assistant: ```c
void buffer_append_string(struct Buffer *buffer, const char *data) {
  int len = strlen(data);
  buffer_append(buffer, data, len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2a,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L5:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  imul   %edx,%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L5
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long hash(char *word) {
  long int helper = 42;
  int i = 0;
  for (i = 0; i < strlen(word); i++) {
    helper += (word[i] * (i + 1));
  }
  return helper;
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x2a,%r12d
  jmp    L8
L9:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
  add    $0x1,%rbx
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  long int helper = 42;
  int i = 0;
  for (i = 0; i < strlen(word); i++) {
    helper += (word[i] * (i + 1));
  }
  return helper;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L17
  nopl   (%rax)
L2:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  add    $0x1,%rbx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L2
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  long int helper = 42;
  int i = 0;
  for (i = 0; i < strlen(word); i++) {
    helper += (word[i] * (i + 1));
  }
  return helper;
}
```