ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <adainit@plt>
  mov    $0x0,%eax
  call   <greetings@plt>
  mov    %eax,-0xc(%rbp)
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L47
  mov    $0x0,%eax
  call   <standard_scaler@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L5
L47:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L19
  mov    $0x0,%eax
  call   <dobldobl_scaler@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L5
L19:
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jne    L5
  mov    $0x0,%eax
  call   <quaddobl_scaler@plt>
  mov    %eax,-0xc(%rbp)
L5:
  mov    $0x0,%eax
  call   <adafinal@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D40
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string
name: unpack_data
arguments: tag: D44
data_type: string
name: unpack_data
arguments: tag: D48
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D8
data_type: string

tool: D40: 
MENU for the precision of the scalers :


tool: D26:   0. use standard double precision arithmetic; or


tool: D44:   1. use double double precision arithmetic; or


tool: D48:   2. use quad double precision arithmetic.


tool: D19: Type 0, 1, or 2 to make your choice : 

tool: D8: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int fail, choice;
  adainit();
  fail = greetings();
  printf("\nMENU for the precision of the scalers :\n");
  printf("  0. use standard double precision arithmetic; or\n");
  printf("  1. use double double precision arithmetic; or\n");
  printf("  2. use quad double precision arithmetic.\n");
  printf("Type 0, 1, or 2 to make your choice : ");
  scanf("%d", &choice);
  if (choice == 0)
    fail = standard_scaler();
  else if (choice == 1)
    fail = dobldobl_scaler();
  else if (choice == 2)
    fail = quaddobl_scaler();
  adafinal();
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <adainit@plt>
  mov    $0x0,%eax
  call   <greetings@plt>
  mov    %eax,%ebx
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L41
  cmp    $0x1,%eax
  je     L21
  cmp    $0x2,%eax
  je     L25
L2:
  mov    $0x0,%eax
  call   <adafinal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L41:
  call   <standard_scaler@plt>
  mov    %eax,%ebx
  jmp    L2
L21:
  mov    $0x0,%eax
  call   <dobldobl_scaler@plt>
  mov    %eax,%ebx
  jmp    L2
L25:
  mov    $0x0,%eax
  call   <quaddobl_scaler@plt>
  mov    %eax,%ebx
  jmp    L2
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D23
type_guessed: string
name: read_data
arguments: data_label: D49
type_guessed: string
name: read_data
arguments: data_label: D29
type_guessed: string
name: read_data
arguments: data_label: D58
type_guessed: string
name: read_data
arguments: data_label: D40
type_guessed: string
name: read_data
arguments: data_label: D17
type_guessed: string

tool: D23: 
MENU for the precision of the scalers :


tool: D49:   0. use standard double precision arithmetic; or


tool: D29:   1. use double double precision arithmetic; or


tool: D58:   2. use quad double precision arithmetic.


tool: D40: Type 0, 1, or 2 to make your choice : 

tool: D17: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int fail, choice;
  adainit();
  fail = greetings();
  printf("\nMENU for the precision of the scalers :\n");
  printf("  0. use standard double precision arithmetic; or\n");
  printf("  1. use double double precision arithmetic; or\n");
  printf("  2. use quad double precision arithmetic.\n");
  printf("Type 0, 1, or 2 to make your choice : ");
  scanf("%d", &choice);
  if (choice == 0)
    fail = standard_scaler();
  else if (choice == 1)
    fail = dobldobl_scaler();
  else if (choice == 2)
    fail = quaddobl_scaler();
  adafinal();
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <adainit@plt>
  xor    %eax,%eax
  call   <greetings@plt>
  lea    D52(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L65
  cmp    $0x1,%eax
  je     L30
  cmp    $0x2,%eax
  je     L34
L55:
  xor    %eax,%eax
  call   <adafinal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L65:
  call   <standard_scaler@plt>
  mov    %eax,%r12d
  jmp    L55
L34:
  xor    %eax,%eax
  call   <quaddobl_scaler@plt>
  mov    %eax,%r12d
  jmp    L55
L30:
  xor    %eax,%eax
  call   <dobldobl_scaler@plt>
  mov    %eax,%r12d
  jmp    L55
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D52
type_infered: string
name: extract_symbolic_data
arguments: label: D59
type_infered: string
name: extract_symbolic_data
arguments: label: D25
type_infered: string
name: extract_symbolic_data
arguments: label: D57
type_infered: string
name: extract_symbolic_data
arguments: label: D47
type_infered: string
name: extract_symbolic_data
arguments: label: D34
type_infered: string

tool: D52: 
MENU for the precision of the scalers :


tool: D59:   0. use standard double precision arithmetic; or


tool: D25:   1. use double double precision arithmetic; or


tool: D57:   2. use quad double precision arithmetic.


tool: D47: Type 0, 1, or 2 to make your choice : 

tool: D34: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int fail, choice;
  adainit();
  fail = greetings();
  printf("\nMENU for the precision of the scalers :\n");
  printf("  0. use standard double precision arithmetic; or\n");
  printf("  1. use double double precision arithmetic; or\n");
  printf("  2. use quad double precision arithmetic.\n");
  printf("Type 0, 1, or 2 to make your choice : ");
  scanf("%d", &choice);
  if (choice == 0)
    fail = standard_scaler();
  else if (choice == 1)
    fail = dobldobl_scaler();
  else if (choice == 2)
    fail = quaddobl_scaler();
  adafinal();
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <adainit@plt>
  xor    %eax,%eax
  call   <greetings@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L17
  cmp    $0x1,%eax
  je     L28
  cmp    $0x2,%eax
  je     L19
L58:
  xor    %eax,%eax
  call   <adafinal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L17:
  call   <standard_scaler@plt>
  mov    %eax,%r12d
  jmp    L58
L19:
  xor    %eax,%eax
  call   <quaddobl_scaler@plt>
  mov    %eax,%r12d
  jmp    L58
L28:
  xor    %eax,%eax
  call   <dobldobl_scaler@plt>
  mov    %eax,%r12d
  jmp    L58
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_infered: string
name: retrieve_data
arguments: data_label: D24
type_infered: string
name: retrieve_data
arguments: data_label: D18
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D34
type_infered: string
name: retrieve_data
arguments: data_label: D30
type_infered: string

tool: D11: 
MENU for the precision of the scalers :


tool: D24:   0. use standard double precision arithmetic; or


tool: D18:   1. use double double precision arithmetic; or


tool: D12:   2. use quad double precision arithmetic.


tool: D34: Type 0, 1, or 2 to make your choice : 

tool: D30: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int fail, choice;
  adainit();
  fail = greetings();
  printf("\nMENU for the precision of the scalers :\n");
  printf("  0. use standard double precision arithmetic; or\n");
  printf("  1. use double double precision arithmetic; or\n");
  printf("  2. use quad double precision arithmetic.\n");
  printf("Type 0, 1, or 2 to make your choice : ");
  scanf("%d", &choice);
  if (choice == 0)
    fail = standard_scaler();
  else if (choice == 1)
    fail = dobldobl_scaler();
  else if (choice == 2)
    fail = quaddobl_scaler();
  adafinal();
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<backcol>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rdx,%rbx
  test   %ecx,%ecx
  jne    L122
  mov    %ecx,%r12d
  mov    %edi,%eax
  sub    $0x1,%eax
  js     L40
  sub    $0x2,%ebp
  movslq %ebp,%rbp
  cltq
  imul   $0x1908,%rax,%rax
  lea    -0x1900(%rsi,%rax,1),%r13
L123:
  movsd  0x1900(%r13),%xmm0
  call   <is_zero@plt>
  test   %rax,%rax
  jne    L166
  movsd  0x8(%rbx,%rbp,8),%xmm0
  divsd  0x1900(%r13),%xmm0
  movsd  %xmm0,0x8(%rbx,%rbp,8)
  test   %ebp,%ebp
  js     L66
  mov    %r13,%rdx
  mov    %rbp,%rax
L30:
  movsd  (%rdx),%xmm1
  mulsd  0x8(%rbx,%rbp,8),%xmm1
  movsd  (%rbx,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  sub    $0x1,%rax
  sub    $0x1900,%rdx
  test   %eax,%eax
  jns    L30
  sub    $0x1,%rbp
  sub    $0x1908,%r13
  jmp    L123
L122:
  mov    %edi,%eax
  sub    $0x1,%eax
  js     L96
  mov    %edi,%r14d
  cltq
  lea    (%rdx,%rax,8),%r12
  imul   $0x1908,%rax,%rax
  lea    0x1900(%rsi,%rax,1),%r13
  jmp    L55
L36:
  movsd  -0x1900(%r13),%xmm0
  call   <is_zero@plt>
  test   %rax,%rax
  jne    L83
  movsd  (%r12),%xmm0
  divsd  -0x1900(%r13),%xmm0
  movsd  %xmm0,(%r12)
  sub    $0x8,%r12
  sub    $0x1908,%r13
  sub    $0x1,%r14d
  je     L46
L55:
  cmp    %r14d,%ebp
  jle    L36
  movslq %r14d,%rax
  mov    %r13,%rdx
L79:
  movsd  (%rdx),%xmm1
  mulsd  (%rbx,%rax,8),%xmm1
  movsd  (%r12),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%r12)
  add    $0x1,%rax
  add    $0x1900,%rdx
  cmp    %eax,%ebp
  jg     L79
  jmp    L36
L40:
  mov    %ecx,%eax
  jmp    L46
L166:
  mov    $0xffffffff,%eax
  jmp    L46
L66:
  mov    %r12d,%eax
L46:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L96:
  mov    $0x0,%eax
  jmp    L46
L83:
  mov    $0xffffffff,%eax
  jmp    L46
```

assistant: ```c
int backcol(int n, double A[][800], double b[], int trans) {
  int i, j;
  if (trans == 0) {
    for (j = n - 1; j >= 0; j--) {
      if (is_zero(A[j][j]))
        return -1;
      b[j] /= A[j][j];
      for (i = j - 1; i >= 0; i--) {
        b[i] -= A[i][j] * b[j];
      }
    }
  } else {
    for (j = n - 1; j >= 0; j--) {
      for (i = j + 1; i < n; i++) {
        b[j] -= A[i][j] * b[i];
      }
      if (is_zero(A[j][j]))
        return -1;
      b[j] /= A[j][j];
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<backcol>:
  endbr64
  push   %r14
  lea    -0x1(%rdi),%eax
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %ecx,%ecx
  jne    L38
  test   %eax,%eax
  js     L75
  cltq
  lea    -0x2(%rdi),%ebp
  imul   $0x1908,%rax,%rax
  movslq %ebp,%rbp
  lea    -0x1900(%rsi,%rax,1),%r12
  nopl   0x0(%rax)
L99:
  movsd  0x1900(%r12),%xmm0
  call   <is_zero@plt>
  test   %rax,%rax
  jne    L53
  movsd  0x8(%rbx,%rbp,8),%xmm0
  divsd  0x1900(%r12),%xmm0
  movsd  %xmm0,0x8(%rbx,%rbp,8)
  cmp    $0xffffffff,%ebp
  je     L75
  mov    %r12,%rdx
  mov    %rbp,%rax
  jmp    L93
  nop
L117:
  movsd  0x8(%rbx,%rbp,8),%xmm0
L93:
  mulsd  (%rdx),%xmm0
  movsd  (%rbx,%rax,8),%xmm1
  sub    $0x1900,%rdx
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx,%rax,8)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L117
  sub    $0x1,%rbp
  sub    $0x1908,%r12
  jmp    L99
  nopl   (%rax)
L38:
  test   %eax,%eax
  js     L75
  cltq
  mov    %edi,%r14d
  lea    (%rdx,%rax,8),%rbp
  imul   $0x1908,%rax,%rax
  lea    0x1900(%rsi,%rax,1),%r13
  nopl   0x0(%rax,%rax,1)
L11:
  cmp    %r14d,%r12d
  jle    L107
  movsd  0x0(%rbp),%xmm1
  movslq %r14d,%rax
  mov    %r13,%rdx
L45:
  movsd  (%rdx),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  add    $0x1,%rax
  add    $0x1900,%rdx
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  cmp    %eax,%r12d
  jg     L45
L107:
  movsd  -0x1900(%r13),%xmm0
  call   <is_zero@plt>
  test   %rax,%rax
  jne    L53
  movsd  0x0(%rbp),%xmm0
  sub    $0x1908,%r13
  sub    $0x8,%rbp
  divsd  0x8(%r13),%xmm0
  movsd  %xmm0,0x8(%rbp)
  sub    $0x1,%r14d
  jne    L11
L75:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L53:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int backcol(int n, double A[][800], double b[], int trans) {
  int i, j;
  if (trans == 0) {
    for (j = n - 1; j >= 0; j--) {
      if (is_zero(A[j][j]))
        return -1;
      b[j] /= A[j][j];
      for (i = j - 1; i >= 0; i--) {
        b[i] -= A[i][j] * b[j];
      }
    }
  } else {
    for (j = n - 1; j >= 0; j--) {
      for (i = j + 1; i < n; i++) {
        b[j] -= A[i][j] * b[i];
      }
      if (is_zero(A[j][j]))
        return -1;
      b[j] /= A[j][j];
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<queue_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L4
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_pop@plt>
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_len@plt>
  test   %rax,%rax
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void queue_clear(struct queue *queue) {
  assert(queue != NULL);
  while (queue_len(queue) != 0)
    queue_pop(queue);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<queue_clear>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  jmp    L12
L0:
  mov    %rbx,%rdi
  call   <queue_pop@plt>
L12:
  mov    %rbx,%rdi
  call   <queue_len@plt>
  test   %rax,%rax
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void queue_clear(struct queue *queue) {
  assert(queue != NULL);
  while (queue_len(queue) != 0)
    queue_pop(queue);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<queue_clear>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  call   <queue_pop@plt>
L6:
  mov    %rbx,%rdi
  call   <queue_len@plt>
  test   %rax,%rax
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void queue_clear(struct queue *queue) {
  assert(queue != NULL);
  while (queue_len(queue) != 0)
    queue_pop(queue);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<queue_clear>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  call   <queue_pop@plt>
L11:
  mov    %rbx,%rdi
  call   <queue_len@plt>
  test   %rax,%rax
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
void queue_clear(struct queue *queue) {
  assert(queue != NULL);
  while (queue_len(queue) != 0)
    queue_pop(queue);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ignoreretrn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6330362031303032,%rax
  movabs $0x3031312d20306330,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x3130303130313131,%rax
  movabs $0x3030313030313031,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6636783020303030,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x66666666,-0x18(%rbp)
  movb   $0x0,-0x14(%rbp)
  lea    -0x48(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void ignoreretrn(void) {
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char *pEnd;
  strtol(szNumbers, &pEnd, 10);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ignoreretrn>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x6330362031303032,%rax
  movabs $0x3031312d20306330,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x3130303130313131,%rax
  movabs $0x3030313030313031,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6636783020303030,%rax
  mov    %rax,0x30(%rsp)
  movl   $0x66666666,0x38(%rsp)
  movb   $0x0,0x3c(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x58,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ignoreretrn(void) {
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char *pEnd;
  strtol(szNumbers, &pEnd, 10);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ignoreretrn>:
  endbr64
  sub    $0x58,%rsp
  movdqa D17(%rip),%xmm0
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movabs $0x6636783020303030,%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D3(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movl   $0x66666666,0x38(%rsp)
  movb   $0x0,0x3c(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <strtol@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x58,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type_infered: byte[16]
name: extract_symbolic_data
arguments: tag: D3
type_infered: byte[16]

tool: {"D17": [0x32,0x30,0x30,0x31,0x20,0x36,0x30,0x63,0x30,0x63,0x30,0x20,0x2d,0x31,0x31,0x30]}

tool: {"D3": [0x31,0x31,0x31,0x30,0x31,0x30,0x30,0x31,0x31,0x30,0x31,0x30,0x30,0x31,0x30,0x30]}

assistant: ```c
void ignoreretrn(void) {
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char *pEnd;
  strtol(szNumbers, &pEnd, 10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ignoreretrn>:
  endbr64
  sub    $0x58,%rsp
  movdqa D5(%rip),%xmm0
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movabs $0x6636783020303030,%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D11(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movl   $0x66666666,0x38(%rsp)
  movb   $0x0,0x3c(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <strtol@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: byte[16]
name: unpack_data
arguments: data_tag: D11
data_type: byte[16]

tool: {"D5": [0x32,0x30,0x30,0x31,0x20,0x36,0x30,0x63,0x30,0x63,0x30,0x20,0x2d,0x31,0x31,0x30]}

tool: {"D11": [0x31,0x31,0x31,0x30,0x31,0x30,0x30,0x31,0x31,0x30,0x31,0x30,0x30,0x31,0x30,0x30]}

assistant: ```c
void ignoreretrn(void) {
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char *pEnd;
  strtol(szNumbers, &pEnd, 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Toeplitz_mat4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <_mm_setzero_ps@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    $0x3,%eax
  sub    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <_mm_loadu_ps@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <_mm_load_ps1@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  cmpl   $0x3,-0xc(%rbp)
  jle    L2
  mov    -0x10(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_mm_storeu_ps@plt>
  nop
  leave
  ret
```

assistant: ```c
void Toeplitz_mat4(const float *a, const float *f, float *b) {
  __m128 ax, fx, bx = _mm_setzero_ps();
  for (int x = 0; x < 4; x++) {
    ax = _mm_loadu_ps(a + 3 - x);
    fx = _mm_load_ps1(f + x);
    bx = bx + ax * fx;
  }
  _mm_storeu_ps(b, bx);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Toeplitz_mat4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%r15
  mov    $0x0,%eax
  call   <_mm_setzero_ps@plt>
  mov    %eax,%r13d
  lea    0xc(%r14),%r12
L7:
  mov    %r12,%rdi
  call   <_mm_loadu_ps@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <_mm_load_ps1@plt>
  imul   %eax,%ebx
  add    %ebx,%r13d
  mov    %r12,%rax
  sub    $0x4,%r12
  add    $0x4,%rbp
  cmp    %r14,%rax
  jne    L7
  mov    %r13d,%esi
  mov    %r15,%rdi
  call   <_mm_storeu_ps@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Toeplitz_mat4(const float *a, const float *f, float *b) {
  __m128 ax, fx, bx = _mm_setzero_ps();
  for (int x = 0; x < 4; x++) {
    ax = _mm_loadu_ps(a + 3 - x);
    fx = _mm_load_ps1(f + x);
    bx = bx + ax * fx;
  }
  _mm_storeu_ps(b, bx);
}
```
user: What is the c source code of the assembly code below:

```asm
<Toeplitz_mat4>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0xc(%r13),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <_mm_setzero_ps@plt>
  mov    %eax,%r15d
L7:
  mov    %rbp,%rdi
  call   <_mm_loadu_ps@plt>
  mov    %r12,%rdi
  add    $0x4,%r12
  mov    %eax,%ebx
  call   <_mm_load_ps1@plt>
  imul   %eax,%ebx
  mov    %rbp,%rax
  sub    $0x4,%rbp
  add    %ebx,%r15d
  cmp    %r13,%rax
  jne    L7
  add    $0x8,%rsp
  mov    %r15d,%esi
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <_mm_storeu_ps@plt>
```

assistant: ```c
void Toeplitz_mat4(const float *a, const float *f, float *b) {
  __m128 ax, fx, bx = _mm_setzero_ps();
  for (int x = 0; x < 4; x++) {
    ax = _mm_loadu_ps(a + 3 - x);
    fx = _mm_load_ps1(f + x);
    bx = bx + ax * fx;
  }
  _mm_storeu_ps(b, bx);
}
```