ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <vectInit@plt>
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  jg     L26
  nopl   0x0(%rax)
L13:
  mov    %rbx,%rdi
  call   <show@plt>
  mov    %rbx,%rdi
  call   <increment@plt>
  mov    0x24(%rsp),%eax
  test   %eax,%eax
  jle    L13
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int V[10];
  int j;
  vectInit(V);
  for (; V[9] < 1;) {
    show(V);
    increment(V);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <vectInit@plt>
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  jg     L18
  nopl   0x0(%rax)
L22:
  mov    %rbx,%rdi
  call   <show@plt>
  mov    %rbx,%rdi
  call   <increment@plt>
  mov    0x24(%rsp),%eax
  test   %eax,%eax
  jle    L22
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int V[10];
  int j;
  vectInit(V);
  for (; V[9] < 1;) {
    show(V);
    increment(V);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<form_volume>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double form_volume(double length_a, double b2a_ratio, double c2a_ratio, double thickness) {
  const double length_b = length_a * b2a_ratio;
  const double length_c = length_a * c2a_ratio;
  const double form_volume = length_a * length_b * length_c;
  return form_volume;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<form_volume>:
  endbr64
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double form_volume(double length_a, double b2a_ratio, double c2a_ratio, double thickness) {
  const double length_b = length_a * b2a_ratio;
  const double length_c = length_a * c2a_ratio;
  const double form_volume = length_a * length_b * length_c;
  return form_volume;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<form_volume>:
  endbr64
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double form_volume(double length_a, double b2a_ratio, double c2a_ratio, double thickness) {
  const double length_b = length_a * b2a_ratio;
  const double length_c = length_a * c2a_ratio;
  const double form_volume = length_a * length_b * length_c;
  return form_volume;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<form_volume>:
  endbr64
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double form_volume(double length_a, double b2a_ratio, double c2a_ratio, double thickness) {
  const double length_b = length_a * b2a_ratio;
  const double length_c = length_a * c2a_ratio;
  const double form_volume = length_a * length_b * length_c;
  return form_volume;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L24
  cmpq   $0x0,-0x30(%rbp)
  jne    L39
L24:
  mov    $0x0,%eax
  jmp    L16
L39:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L16
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
L16:
  leave
  ret
```

assistant: ```c
char *strcdup(const char *s1, const char *s2) {
  if (!s1 || !s2) {
    return NULL;
  }
  size_t slen = strlen(s1);
  size_t s2len = strlen(s2);
  size_t nlen = slen + s2len + 1;
  char *dst = malloc(nlen);
  if (dst == NULL) {
    return NULL;
  }
  memcpy(dst, s1, slen);
  strncpy(dst + slen, s2, s2len + 1);
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcdup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L17
  mov    %rdi,%r13
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L17
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L25
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%rbp),%rdx
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rsi
  call   <strncpy@plt>
L25:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    $0x0,%r12d
  jmp    L25
```

assistant: ```c
char *strcdup(const char *s1, const char *s2) {
  if (!s1 || !s2) {
    return NULL;
  }
  size_t slen = strlen(s1);
  size_t s2len = strlen(s2);
  size_t nlen = slen + s2len + 1;
  char *dst = malloc(nlen);
  if (dst == NULL) {
    return NULL;
  }
  memcpy(dst, s1, slen);
  strncpy(dst + slen, s2, s2len + 1);
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcdup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L24
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L24
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L21
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%r14),%rdx
  lea    (%r12,%rbx,1),%rdi
  mov    %r13,%rsi
  call   <strncpy@plt>
L21:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strcdup(const char *s1, const char *s2) {
  if (!s1 || !s2) {
    return NULL;
  }
  size_t slen = strlen(s1);
  size_t s2len = strlen(s2);
  size_t nlen = slen + s2len + 1;
  char *dst = malloc(nlen);
  if (dst == NULL) {
    return NULL;
  }
  memcpy(dst, s1, slen);
  strncpy(dst + slen, s2, s2len + 1);
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcdup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L18
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%r14),%rdx
  lea    (%r12,%rbx,1),%rdi
  mov    %r13,%rsi
  call   <strncpy@plt>
L6:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strcdup(const char *s1, const char *s2) {
  if (!s1 || !s2) {
    return NULL;
  }
  size_t slen = strlen(s1);
  size_t s2len = strlen(s2);
  size_t nlen = slen + s2len + 1;
  char *dst = malloc(nlen);
  if (dst == NULL) {
    return NULL;
  }
  memcpy(dst, s1, slen);
  strncpy(dst + slen, s2, s2len + 1);
  return dst;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<retro_get_memory_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *retro_get_memory_data(unsigned id) {
  (void)id;
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<retro_get_memory_data>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *retro_get_memory_data(unsigned id) {
  (void)id;
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<retro_get_memory_data>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
void *retro_get_memory_data(unsigned id) {
  (void)id;
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bin_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %esi,-0x12c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x12c(%rbp)
  jle    L36
  cmpl   $0x100,-0x12c(%rbp)
  jle    L1
L36:
  mov    $0x0,%eax
  jmp    L47
L1:
  mov    -0x12c(%rbp),%edx
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x114(%rbp)
  jmp    L8
L34:
  mov    -0x114(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    -0x114(%rbp),%edx
  add    %edx,%edx
  movslq %edx,%rcx
  mov    -0x128(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sprintf@plt>
  addl   $0x1,-0x114(%rbp)
L8:
  mov    -0x114(%rbp),%eax
  cmp    -0x12c(%rbp),%eax
  jl     L34
  mov    -0x114(%rbp),%eax
  add    %eax,%eax
L47:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D7: %02x

assistant: ```c
int bin_to_str(unsigned char *bin_buffer, int bin_buffer_len) {
  if (bin_buffer_len <= 0 || bin_buffer_len > 256)
    return 0;
  unsigned char temp_bin_buffer[256];
  memcpy(temp_bin_buffer, bin_buffer, bin_buffer_len);
  int i;
  for (i = 0; i < bin_buffer_len; i++) {
    sprintf(&bin_buffer[i * 2], "%02x", temp_bin_buffer[i]);
  }
  return (i * 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bin_to_str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rsi),%r14d
  cmp    $0xff,%r14d
  jbe    L13
L10:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rsp,%rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %r13,%rbx
  mov    %r14d,%r14d
  lea    0x2(%r13,%r14,2),%r14
  lea    D1(%rip),%r13
L5:
  movzbl 0x0(%rbp),%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x1,%rbp
  add    $0x2,%rbx
  cmp    %r14,%rbx
  jne    L5
  lea    (%r12,%r12,1),%eax
  jmp    L10
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %02x

assistant: ```c
int bin_to_str(unsigned char *bin_buffer, int bin_buffer_len) {
  if (bin_buffer_len <= 0 || bin_buffer_len > 256)
    return 0;
  unsigned char temp_bin_buffer[256];
  memcpy(temp_bin_buffer, bin_buffer, bin_buffer_len);
  int i;
  for (i = 0; i < bin_buffer_len; i++) {
    sprintf(&bin_buffer[i * 2], "%02x", temp_bin_buffer[i]);
  }
  return (i * 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bin_to_str>:
  endbr64
  push   %r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0xff,%r13d
  jbe    L19
L37:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %rsp,%rbp
  mov    %rdi,%rbx
  mov    %esi,%edx
  mov    %esi,%r12d
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  lea    0x2(%rbx,%r13,2),%r14
  call   <memcpy@plt>
  lea    D5(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L27:
  movzbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r13,%rsi
  add    $0x2,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r14,%rbx
  jne    L27
  lea    (%r12,%r12,1),%eax
  jmp    L37
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: %02x

assistant: ```c
int bin_to_str(unsigned char *bin_buffer, int bin_buffer_len) {
  if (bin_buffer_len <= 0 || bin_buffer_len > 256)
    return 0;
  unsigned char temp_bin_buffer[256];
  memcpy(temp_bin_buffer, bin_buffer, bin_buffer_len);
  int i;
  for (i = 0; i < bin_buffer_len; i++) {
    sprintf(&bin_buffer[i * 2], "%02x", temp_bin_buffer[i]);
  }
  return (i * 2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bin_to_str>:
  endbr64
  push   %r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0xff,%r13d
  jbe    L31
L30:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    %rsp,%rbp
  mov    %rdi,%rbx
  mov    %esi,%edx
  mov    %esi,%r12d
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  lea    0x2(%rbx,%r13,2),%r14
  call   <memcpy@plt>
  lea    D5(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r13,%rsi
  add    $0x2,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r14,%rbx
  jne    L8
  lea    (%r12,%r12,1),%eax
  jmp    L30
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: %02x

assistant: ```c
int bin_to_str(unsigned char *bin_buffer, int bin_buffer_len) {
  if (bin_buffer_len <= 0 || bin_buffer_len > 256)
    return 0;
  unsigned char temp_bin_buffer[256];
  memcpy(temp_bin_buffer, bin_buffer, bin_buffer_len);
  int i;
  for (i = 0; i < bin_buffer_len; i++) {
    sprintf(&bin_buffer[i * 2], "%02x", temp_bin_buffer[i]);
  }
  return (i * 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delta_x2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movsd  %xmm3,-0x50(%rbp)
  movsd  %xmm4,-0x58(%rbp)
  movsd  -0x38(%rbp),%xmm0
  addsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D5(%rip),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <w_bar_1@plt>
  movq   %xmm0,%rbx
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <w_bar@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x40(%rbp),%xmm2
  movsd  -0x58(%rbp),%xmm1
  movsd  D14(%rip),%xmm0
  movapd %xmm1,%xmm3
  mulsd  %xmm0,%xmm3
  movsd  -0x38(%rbp),%xmm0
  mulsd  -0x50(%rbp),%xmm0
  movsd  -0x40(%rbp),%xmm1
  mulsd  -0x48(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <w_bar@plt>
  movsd  -0x18(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: f64
name: disassemble_data
arguments: data_tag: D14
datatype: byte[8]

tool: D5: 1

tool: {"D14": [0x66,0x66,0x66,0x66,0x66,0x66,0xee,0x3f]}

assistant: ```c
double delta_x2(double x1, double x2, double x3, double x4, double r) {
  double p = x1 + x2;
  double q = 1 - p;
  double num;
  num = x2 * (w_bar_1(p) - w_bar(p)) + r * (1 - (0.5) * (0.1)) * (x1 * x4 - x2 * x3);
  return num / w_bar(p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<delta_x2>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm2,%r12
  movq   %xmm3,%r15
  movq   %xmm4,%rbp
  movsd  %xmm0,(%rsp)
  movapd %xmm0,%xmm5
  movsd  %xmm1,0x8(%rsp)
  addsd  %xmm1,%xmm5
  movapd %xmm5,%xmm0
  movq   %xmm5,%r14
  call   <w_bar_1@plt>
  movq   %xmm0,%rbx
  movq   %r14,%xmm0
  call   <w_bar@plt>
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm4
  movq   %r15,%xmm7
  mulsd  %xmm7,%xmm4
  movq   %r12,%xmm0
  movsd  0x8(%rsp),%xmm6
  mulsd  %xmm6,%xmm0
  subsd  %xmm0,%xmm4
  movq   %rbp,%xmm0
  mulsd  D2(%rip),%xmm0
  mulsd  %xmm0,%xmm4
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  mulsd  %xmm6,%xmm0
  addsd  %xmm0,%xmm4
  movsd  %xmm4,(%rsp)
  movq   %r14,%xmm0
  call   <w_bar@plt>
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: byte[8]

tool: {"D2": [0x66,0x66,0x66,0x66,0x66,0x66,0xee,0x3f]}

assistant: ```c
double delta_x2(double x1, double x2, double x3, double x4, double r) {
  double p = x1 + x2;
  double q = 1 - p;
  double num;
  num = x2 * (w_bar_1(p) - w_bar(p)) + r * (1 - (0.5) * (0.1)) * (x1 * x4 - x2 * x3);
  return num / w_bar(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<delta_x2>:
  endbr64
  movapd %xmm0,%xmm6
  sub    $0x48,%rsp
  addsd  %xmm1,%xmm6
  movsd  %xmm0,0x28(%rsp)
  movsd  %xmm2,0x38(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm6,%xmm0
  movsd  %xmm4,0x30(%rsp)
  movsd  %xmm1,0x20(%rsp)
  movsd  %xmm6,0x10(%rsp)
  call   <w_bar_1@plt>
  movsd  0x10(%rsp),%xmm6
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm6,%xmm0
  call   <w_bar@plt>
  movsd  0x20(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm5
  mulsd  0x8(%rsp),%xmm5
  mulsd  %xmm1,%xmm2
  movsd  0x18(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm4
  mulsd  D5(%rip),%xmm4
  movsd  0x10(%rsp),%xmm6
  subsd  %xmm0,%xmm3
  subsd  %xmm2,%xmm5
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm5
  addsd  %xmm0,%xmm5
  movapd %xmm6,%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <w_bar@plt>
  movsd  0x8(%rsp),%xmm5
  add    $0x48,%rsp
  divsd  %xmm0,%xmm5
  movapd %xmm5,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: byte[8]

tool: {"D5": [0x66,0x66,0x66,0x66,0x66,0x66,0xee,0x3f]}

assistant: ```c
double delta_x2(double x1, double x2, double x3, double x4, double r) {
  double p = x1 + x2;
  double q = 1 - p;
  double num;
  num = x2 * (w_bar_1(p) - w_bar(p)) + r * (1 - (0.5) * (0.1)) * (x1 * x4 - x2 * x3);
  return num / w_bar(p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<delta_x2>:
  endbr64
  movapd %xmm0,%xmm6
  sub    $0x48,%rsp
  addsd  %xmm1,%xmm6
  movsd  %xmm0,0x28(%rsp)
  movsd  %xmm2,0x38(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm6,%xmm0
  movsd  %xmm4,0x30(%rsp)
  movsd  %xmm1,0x20(%rsp)
  movsd  %xmm6,0x10(%rsp)
  call   <w_bar_1@plt>
  movsd  0x10(%rsp),%xmm6
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm6,%xmm0
  call   <w_bar@plt>
  movsd  0x20(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm5
  mulsd  0x8(%rsp),%xmm5
  mulsd  %xmm1,%xmm2
  movsd  0x18(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm4
  mulsd  D5(%rip),%xmm4
  movsd  0x10(%rsp),%xmm6
  subsd  %xmm0,%xmm3
  subsd  %xmm2,%xmm5
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm5
  addsd  %xmm0,%xmm5
  movapd %xmm6,%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <w_bar@plt>
  movsd  0x8(%rsp),%xmm5
  add    $0x48,%rsp
  divsd  %xmm0,%xmm5
  movapd %xmm5,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: byte[8]

tool: {"D5": [0x66,0x66,0x66,0x66,0x66,0x66,0xee,0x3f]}

assistant: ```c
double delta_x2(double x1, double x2, double x3, double x4, double r) {
  double p = x1 + x2;
  double q = 1 - p;
  double num;
  num = x2 * (w_bar_1(p) - w_bar(p)) + r * (1 - (0.5) * (0.1)) * (x1 * x4 - x2 * x3);
  return num / w_bar(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_pipe_fetch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x10000(%rsp),%r11
L49:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L49
  sub    $0x30,%rsp
  mov    %rdi,-0x10028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1001c(%rbp)
  cmpq   $0x0,-0x10028(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L63
L53:
  movb   $0x0,-0x10010(%rbp)
  mov    -0x10028(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x10018(%rbp)
  mov    -0x10018(%rbp),%rcx
  lea    -0x10010(%rbp),%rax
  mov    $0x10000,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <string_input@plt>
  test   %eax,%eax
  jne    L18
  movl   $0x1,-0x1001c(%rbp)
L18:
  mov    -0x10018(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  cmpl   $0x0,-0x1001c(%rbp)
  je     L68
  mov    $0x0,%eax
  jmp    L63
L68:
  lea    -0x10010(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
L63:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: r

assistant: ```c
char *string_pipe_fetch(char *system_string) {
  char buffer[65536];
  FILE *p;
  int null_input = 0;
  if (!system_string)
    return (char *)0;
  *buffer = '\0';
  p = popen(system_string, "r");
  if (!string_input(buffer, p, 65536))
    null_input = 1;
  pclose(p);
  if (null_input)
    return (char *)0;
  else
    return strdup(buffer);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<string_pipe_fetch>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x10000(%rsp),%r11
L31:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L31
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L48
  movb   $0x0,(%rsp)
  lea    D6(%rip),%rsi
  call   <popen@plt>
  mov    %rax,%rbx
  mov    %rsp,%rdi
  mov    $0x10000,%edx
  mov    %rax,%rsi
  call   <string_input@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <pclose@plt>
  mov    $0x0,%eax
  test   %ebp,%ebp
  je     L0
  mov    %rsp,%rdi
  call   <strdup@plt>
L0:
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x10018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    %rdi,%rax
  jmp    L0
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: r

assistant: ```c
char *string_pipe_fetch(char *system_string) {
  char buffer[65536];
  FILE *p;
  int null_input = 0;
  if (!system_string)
    return (char *)0;
  *buffer = '\0';
  p = popen(system_string, "r");
  if (!string_input(buffer, p, 65536))
    null_input = 1;
  pclose(p);
  if (null_input)
    return (char *)0;
  else
    return strdup(buffer);
}
```