ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: Count = %d



assistant: ```c
int main() {
  int i, j, k, n = 3, count = 0, breakIt = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      for (k = 0; k < n; k++) {
        if (i == 1 && j == 1 && k == 1) {
          breakIt = 1;
          break;
        }
        count++;
      }
      if (breakIt)
        break;
    }
    if (breakIt)
      break;
  }
  printf("Count = %d\n\n", count);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<constructRectangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x2,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L2
L38:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L32
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L32
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L13
L32:
  subl   $0x1,-0x14(%rbp)
L2:
  cmpl   $0x0,-0x14(%rbp)
  jg     L38
L13:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *constructRectangle(int area, int *returnSize) {
  *returnSize = 2;
  int *res = (int *)malloc((*returnSize) * sizeof(int));
  for (int i = area; i > 0; i--) {
    if (area % i == 0) {
      int w = i;
      int l = area / i;
      if (w <= l) {
        res[0] = l;
        res[1] = w;
        break;
      }
    }
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<constructRectangle>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movl   $0x2,(%rsi)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  test   %ebx,%ebx
  jle    L1
  mov    %ebx,%ecx
  jmp    L8
L3:
  sub    $0x1,%ecx
  je     L1
L8:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L3
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cmp    %ecx,%eax
  jl     L3
  mov    %eax,(%rsi)
  mov    %ecx,0x4(%rsi)
L1:
  mov    %rsi,%rax
  pop    %rbx
  ret
```

assistant: ```c
int *constructRectangle(int area, int *returnSize) {
  *returnSize = 2;
  int *res = (int *)malloc((*returnSize) * sizeof(int));
  for (int i = area; i > 0; i--) {
    if (area % i == 0) {
      int w = i;
      int l = area / i;
      if (w <= l) {
        res[0] = l;
        res[1] = w;
        break;
      }
    }
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<constructRectangle>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  movl   $0x2,(%rsi)
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L9
  mov    %ebx,%ecx
L12:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L18
  cmp    %eax,%ecx
  jle    L39
L18:
  sub    $0x1,%ecx
  jne    L12
L9:
  mov    %r8,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %eax,(%r8)
  mov    %r8,%rax
  mov    %ecx,0x4(%r8)
  pop    %rbx
  ret
```

assistant: ```c
int *constructRectangle(int area, int *returnSize) {
  *returnSize = 2;
  int *res = (int *)malloc((*returnSize) * sizeof(int));
  for (int i = area; i > 0; i--) {
    if (area % i == 0) {
      int w = i;
      int l = area / i;
      if (w <= l) {
        res[0] = l;
        res[1] = w;
        break;
      }
    }
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<constructRectangle>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  movl   $0x2,(%rsi)
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L32
  mov    %ebx,%ecx
L35:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L19
  cmp    %eax,%ecx
  jle    L22
L19:
  sub    $0x1,%ecx
  jne    L35
L32:
  mov    %r8,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  movd   %eax,%xmm0
  movd   %ecx,%xmm1
  mov    %r8,%rax
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%r8)
  pop    %rbx
  ret
```

assistant: ```c
int *constructRectangle(int area, int *returnSize) {
  *returnSize = 2;
  int *res = (int *)malloc((*returnSize) * sizeof(int));
  for (int i = area; i > 0; i--) {
    if (area % i == 0) {
      int w = i;
      int l = area / i;
      if (w <= l) {
        res[0] = l;
        res[1] = w;
        break;
      }
    }
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,%rcx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: D7: %s: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  printf("%s: %d\n", basename(argv[0]), i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <basename@plt>
  mov    %rax,%rsi
  mov    $0x0,%edx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string

tool: D1: %s: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  printf("%s: %d\n", basename(argv[0]), i);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <basename@plt>
  xor    %edx,%edx
  lea    D1(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string

tool: D1: %s: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  printf("%s: %d\n", basename(argv[0]), i);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <basename@plt>
  xor    %edx,%edx
  lea    D4(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: %s: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  printf("%s: %d\n", basename(argv[0]), i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipwhite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L41
L6:
  addq   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L6
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x8(%rbp),%rax
  jmp    L14
L34:
  mov    $0x0,%eax
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2:  	


assistant: ```c
char *skipwhite(const char *s) {
  char *t = (char *)s;
  for (; *t && strchr(" \t\n\r", *t); ++t)
    ;
  return *t ? t : NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<skipwhite>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%esi
  lea    D6(%rip),%rbp
  test   %sil,%sil
  je     L38
L10:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L17
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L10
L38:
  mov    $0x0,%eax
  jmp    L6
L17:
  cmpb   $0x0,(%rbx)
  cmovne %rbx,%rax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6:  	


assistant: ```c
char *skipwhite(const char *s) {
  char *t = (char *)s;
  for (; *t && strchr(" \t\n\r", *t); ++t)
    ;
  return *t ? t : NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<skipwhite>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  jne    L6
  jmp    L37
  nop
L17:
  movsbl 0x1(%r12),%esi
  add    $0x1,%r12
  test   %sil,%sil
  je     L37
L6:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L17
  cmpb   $0x0,(%r12)
  je     L37
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L37:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7:  	


assistant: ```c
char *skipwhite(const char *s) {
  char *t = (char *)s;
  for (; *t && strchr(" \t\n\r", *t); ++t)
    ;
  return *t ? t : NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skipwhite>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  jne    L16
  jmp    L14
  nop
L18:
  movsbl 0x1(%r12),%esi
  add    $0x1,%r12
  test   %sil,%sil
  je     L14
L16:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L18
  cmpb   $0x0,(%r12)
  je     L14
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L14:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4:  	


assistant: ```c
char *skipwhite(const char *s) {
  char *t = (char *)s;
  for (; *t && strchr(" \t\n\r", *t); ++t)
    ;
  return *t ? t : NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<USBDevLPMDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x362,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x362,%rdx
  and    $0xfffffffe,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBDevLPMDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000362))) &= ~0x00000001;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBDevLPMDisable>:
  endbr64
  mov    0x362(%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x362(%rdi)
  ret
```

assistant: ```c
void USBDevLPMDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000362))) &= ~0x00000001;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<USBDevLPMDisable>:
  endbr64
  mov    0x362(%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x362(%rdi)
  ret
```

assistant: ```c
void USBDevLPMDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000362))) &= ~0x00000001;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<st_find_next_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L17
L15:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L15
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint st_find_next_word(char *text) {
  uint i;
  for (i = 1; text[i] > 32; i++)
    ;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<st_find_next_word>:
  endbr64
  cmpb   $0x20,0x1(%rdi)
  jle    L0
  mov    $0x1,%eax
L13:
  add    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  jg     L13
  ret
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
uint st_find_next_word(char *text) {
  uint i;
  for (i = 1; text[i] > 32; i++)
    ;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<st_find_next_word>:
  endbr64
  cmpb   $0x20,0x1(%rdi)
  mov    $0x1,%eax
  jle    L7
  nop
L9:
  add    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  jg     L9
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
uint st_find_next_word(char *text) {
  uint i;
  for (i = 1; text[i] > 32; i++)
    ;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<st_find_next_word>:
  endbr64
  cmpb   $0x20,0x1(%rdi)
  mov    $0x1,%eax
  jle    L10
  nop
L1:
  add    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  jg     L1
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
uint st_find_next_word(char *text) {
  uint i;
  for (i = 1; text[i] > 32; i++)
    ;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SASL_L>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L18
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  jmp    L6
L18:
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  neg    %eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int32_t SASL_L(int32_t x, int16_t by) {
  if (x >= 0)
    return x << by;
  return -((-x) << by);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SASL_L>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  ret
```

assistant: ```c
int32_t SASL_L(int32_t x, int16_t by) {
  if (x >= 0)
    return x << by;
  return -((-x) << by);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SASL_L>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  ret
```

assistant: ```c
int32_t SASL_L(int32_t x, int16_t by) {
  if (x >= 0)
    return x << by;
  return -((-x) << by);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SASL_L>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  ret
```

assistant: ```c
int32_t SASL_L(int32_t x, int16_t by) {
  if (x >= 0)
    return x << by;
  return -((-x) << by);
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L3:
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L49:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L4:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L49
L26:
  nop
  leave
  ret
```

assistant: ```c
void trim_line(char *line) {
  int len;
  char *fnw = line;
  while (isspace((unsigned char)*fnw))
    ++fnw;
  len = strlen(fnw);
  memmove(line, fnw, len);
  fnw = line + len - 1;
  while (fnw >= line && isspace((unsigned char)*fnw))
    *fnw-- = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  jmp    L34
L29:
  add    $0x1,%rbx
L34:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  movslq %r12d,%r12
  lea    -0x1(%rbp,%r12,1),%rbx
  cmp    %rbx,%rbp
  ja     L24
L23:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L24
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  jbe    L23
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trim_line(char *line) {
  int len;
  char *fnw = line;
  while (isspace((unsigned char)*fnw))
    ++fnw;
  len = strlen(fnw);
  memmove(line, fnw, len);
  fnw = line + len - 1;
  while (fnw >= line && isspace((unsigned char)*fnw))
    *fnw-- = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim_line>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L21
L42:
  add    $0x1,%rbp
L21:
  movzbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L42
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movslq %eax,%rbx
  mov    %ebx,%edx
  lea    -0x1(%r12,%rbx,1),%rbx
  call   <memmove@plt>
  cmp    %rbx,%r12
  jbe    L29
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L49:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%r12
  ja     L13
L29:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L49
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trim_line(char *line) {
  int len;
  char *fnw = line;
  while (isspace((unsigned char)*fnw))
    ++fnw;
  len = strlen(fnw);
  memmove(line, fnw, len);
  fnw = line + len - 1;
  while (fnw >= line && isspace((unsigned char)*fnw))
    *fnw-- = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trim_line>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L55
L32:
  add    $0x1,%rbp
L55:
  movzbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movslq %eax,%rbx
  mov    %ebx,%edx
  lea    -0x1(%r12,%rbx,1),%rbx
  call   <memmove@plt>
  cmp    %rbx,%r12
  jbe    L25
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L37:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%r12
  ja     L38
L25:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trim_line(char *line) {
  int len;
  char *fnw = line;
  while (isspace((unsigned char)*fnw))
    ++fnw;
  len = strlen(fnw);
  memmove(line, fnw, len);
  fnw = line + len - 1;
  while (fnw >= line && isspace((unsigned char)*fnw))
    *fnw-- = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp_ulong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jb     L4
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  seta   %al
  movzbl %al,%eax
  jmp    L15
L4:
  mov    $0xffffffff,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_ulong(const void *aa, const void *bb) {
  const unsigned long *a = aa, *b = bb;
  return (*a < *b) ? -1 : (*a > *b);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmp_ulong>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jb     L2
  seta   %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
int cmp_ulong(const void *aa, const void *bb) {
  const unsigned long *a = aa, *b = bb;
  return (*a < *b) ? -1 : (*a > *b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmp_ulong>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int cmp_ulong(const void *aa, const void *bb) {
  const unsigned long *a = aa, *b = bb;
  return (*a < *b) ? -1 : (*a > *b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmp_ulong>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int cmp_ulong(const void *aa, const void *bb) {
  const unsigned long *a = aa, *b = bb;
  return (*a < *b) ? -1 : (*a > *b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_8_1_t32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L5:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <print_one_line_t32@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x1,-0x4(%rbp)
  jle    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_8_1_t32(int k) {
  for (int loop = 0; loop < 2; ++loop) {
    print_one_line_t32(k, 0, 1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_8_1_t32>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <print_one_line_t32@plt>
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <print_one_line_t32@plt>
  pop    %rbx
  ret
```

assistant: ```c
void print_8_1_t32(int k) {
  for (int loop = 0; loop < 2; ++loop) {
    print_one_line_t32(k, 0, 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_8_1_t32>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  mov    %edi,%ebp
  xor    %esi,%esi
  call   <print_one_line_t32@plt>
  mov    %ebp,%edi
  mov    $0x1,%edx
  xor    %esi,%esi
  pop    %rbp
  jmp    1050 <print_one_line_t32@plt>
```

assistant: ```c
void print_8_1_t32(int k) {
  for (int loop = 0; loop < 2; ++loop) {
    print_one_line_t32(k, 0, 1);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_8_1_t32>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  mov    %edi,%ebp
  xor    %esi,%esi
  call   <print_one_line_t32@plt>
  mov    %ebp,%edi
  mov    $0x1,%edx
  xor    %esi,%esi
  pop    %rbp
  jmp    1050 <print_one_line_t32@plt>
```

assistant: ```c
void print_8_1_t32(int k) {
  for (int loop = 0; loop < 2; ++loop) {
    print_one_line_t32(k, 0, 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    $0x0,%ebx
  jmp    L29
L38:
  mov    $0x0,%r12d
  jmp    L35
L17:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  movslq %r12d,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L0
  cmp    %r12d,%ebx
  jne    L24
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L0
L24:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L0:
  add    $0x1,%r12d
L35:
  cmp    $0x3,%r12d
  jle    L17
  add    $0x1,%ebx
L29:
  cmp    $0x3,%ebx
  jle    L38
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void compare(const int *in_digits, const int *ans_digits, int *a, int *b) {
  for (register int i = 0; i < 4; i++)
    for (register int j = 0; j < 4; j++)
      if (in_digits[i] == ans_digits[j])
        (i == j) ? (*a)++ : (*b)++;
}
```