ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buildConstantMatrix>:
  endbr64
  push   %rbx
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  mov    (%rbx),%rax
  movq   $0x0,(%rax)
  mov    (%rbx),%rax
  movq   $0x1,0x8(%rax)
  mov    0x8(%rbx),%rax
  movq   $0x1,(%rax)
  mov    0x8(%rbx),%rax
  movq   $0x1,0x8(%rax)
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long long int **buildConstantMatrix() {
  int i, j;
  long long int **ct = (long long int **)malloc(2);
  for (i = 0; i < 2; i++) {
    ct[i] = (long long int *)malloc(2);
  }
  ct[0][0] = 0;
  ct[0][1] = 1;
  ct[1][0] = 1;
  ct[1][1] = 1;
  return ct;
}
```
user: Translate the below assembly code into C programming language:

```asm
<buildConstantMatrix>:
  endbr64
  push   %r12
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    $0x2,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x2,%edi
  mov    %rax,(%r12)
  call   <malloc@plt>
  mov    (%r12),%rdx
  mov    %rax,0x8(%r12)
  movq   $0x0,(%rdx)
  movq   $0x1,0x8(%rdx)
  movq   $0x1,(%rax)
  movq   $0x1,0x8(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long long int **buildConstantMatrix() {
  int i, j;
  long long int **ct = (long long int **)malloc(2);
  for (i = 0; i < 2; i++) {
    ct[i] = (long long int *)malloc(2);
  }
  ct[0][0] = 0;
  ct[0][1] = 1;
  ct[1][0] = 1;
  ct[1][1] = 1;
  return ct;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<buildConstantMatrix>:
  endbr64
  push   %r12
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    $0x2,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x2,%edi
  mov    %rax,(%r12)
  call   <malloc@plt>
  mov    (%r12),%rdx
  movdqa D12(%rip),%xmm0
  mov    %rax,0x8(%r12)
  movups %xmm0,(%rdx)
  movdqa D15(%rip),%xmm0
  movups %xmm0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D12
type: byte[16]
name: read_data
arguments: label: D15
type: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D15": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
long long int **buildConstantMatrix() {
  int i, j;
  long long int **ct = (long long int **)malloc(2);
  for (i = 0; i < 2; i++) {
    ct[i] = (long long int *)malloc(2);
  }
  ct[0][0] = 0;
  ct[0][1] = 1;
  ct[1][0] = 1;
  ct[1][1] = 1;
  return ct;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stpncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L6:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  mov    -0xc(%rbp),%eax
  cmp    %rax,-0x28(%rbp)
  ja     L6
L11:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L9:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    %rax,-0x28(%rbp)
  ja     L9
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *stpncpy(char *dest, const char *src, size_t n) {
  unsigned i = 0;
  for (; src[i] && i < n; ++i)
    dest[i] = src[i];
  char *retval = dest + i;
  for (; i < n; ++i)
    dest[i] = 0;
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stpncpy>:
  endbr64
  movzbl (%rsi),%r8d
  test   %rdx,%rdx
  je     L28
  test   %r8b,%r8b
  je     L28
  mov    $0x0,%ecx
  mov    $0x0,%eax
L50:
  mov    %r8b,(%rdi,%rax,1)
  add    $0x1,%ecx
  mov    %ecx,%eax
  movzbl (%rsi,%rax,1),%r8d
  cmp    %rdx,%rax
  jae    L8
  test   %r8b,%r8b
  jne    L50
L8:
  add    %rdi,%rax
  mov    %ecx,%esi
  cmp    %rsi,%rdx
  jbe    L33
L51:
  movb   $0x0,(%rdi,%rsi,1)
  add    $0x1,%ecx
  mov    %ecx,%esi
  cmp    %rdx,%rsi
  jb     L51
L33:
  ret
L28:
  mov    $0x0,%ecx
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
char *stpncpy(char *dest, const char *src, size_t n) {
  unsigned i = 0;
  for (; src[i] && i < n; ++i)
    dest[i] = src[i];
  char *retval = dest + i;
  for (; i < n; ++i)
    dest[i] = 0;
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stpncpy>:
  endbr64
  movzbl (%rsi),%r8d
  test   %rdx,%rdx
  je     L18
  test   %r8b,%r8b
  je     L18
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L36:
  cmp    %rdx,%rax
  jae    L35
L66:
  mov    %r8b,(%rdi,%rax,1)
  lea    0x1(%rcx),%eax
  movzbl (%rsi,%rax,1),%r8d
  mov    %rax,%rcx
  test   %r8b,%r8b
  jne    L36
L35:
  lea    (%rdi,%rax,1),%r8
L6:
  cmp    %rax,%rdx
  jbe    L47
  nopw   0x0(%rax,%rax,1)
L71:
  movb   $0x0,(%rdi,%rax,1)
  lea    0x1(%rcx),%eax
  mov    %rax,%rcx
  cmp    %rdx,%rax
  jb     L71
L47:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rdi,%r8
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L6
```

assistant: ```c
char *stpncpy(char *dest, const char *src, size_t n) {
  unsigned i = 0;
  for (; src[i] && i < n; ++i)
    dest[i] = src[i];
  char *retval = dest + i;
  for (; i < n; ++i)
    dest[i] = 0;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stpncpy>:
  endbr64
  movzbl (%rsi),%r8d
  test   %rdx,%rdx
  je     L3
  test   %r8b,%r8b
  je     L3
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    %rdx,%rax
  jae    L18
L1:
  mov    %r8b,(%rdi,%rax,1)
  lea    0x1(%rcx),%eax
  movzbl (%rsi,%rax,1),%r8d
  mov    %rax,%rcx
  test   %r8b,%r8b
  jne    L8
L18:
  lea    (%rdi,%rax,1),%r8
L44:
  cmp    %rax,%rdx
  jbe    L48
  nopw   0x0(%rax,%rax,1)
L67:
  movb   $0x0,(%rdi,%rax,1)
  lea    0x1(%rcx),%eax
  mov    %rax,%rcx
  cmp    %rdx,%rax
  jb     L67
L48:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rdi,%r8
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L44
```

assistant: ```c
char *stpncpy(char *dest, const char *src, size_t n) {
  unsigned i = 0;
  for (; src[i] && i < n; ++i)
    dest[i] = src[i];
  char *retval = dest + i;
  for (; i < n; ++i)
    dest[i] = 0;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dohuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x2c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bihuf@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L28
  movl   $0x0,-0x20(%rbp)
  jmp    L48
L4:
  mov    -0x20(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L50
  movl   $0x80,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,-0x1c(%rbp)
L50:
  mov    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    %edx,%eax
  movzbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fputbit@plt>
  sarl   -0x18(%rbp)
  addl   $0x1,-0x20(%rbp)
L48:
  mov    -0x20(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L4
  mov    $0x0,%eax
  jmp    L55
L28:
  mov    $0xffffffff,%eax
L55:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int dohuf(FILE *f, int simb, unsigned char *curhuf) {
  int i, j, m, bits;
  unsigned char *pb;
  bits = bihuf(simb, curhuf, &pb);
  if (bits > 0) {
    for (i = 0; i < bits; i++) {
      if (!(i & 7)) {
        m = 0x80;
        j = i >> 3;
      }
      fputbit(f, pb[j] & m);
      m >>= 1;
    }
    return 0;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dohuf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r14
  mov    %esi,%edi
  mov    %rdx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <bihuf@plt>
  test   %eax,%eax
  jle    L63
  mov    %eax,%r12d
  mov    $0x0,%ebx
  jmp    L13
L57:
  movslq %r13d,%rax
  mov    (%rsp),%rdx
  mov    %ebp,%esi
  and    (%rdx,%rax,1),%sil
  movzbl %sil,%esi
  mov    %r14,%rdi
  call   <fputbit@plt>
  sar    %ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L48
L13:
  test   $0x7,%bl
  jne    L57
  mov    %ebx,%r13d
  sar    $0x3,%r13d
  mov    $0x80,%ebp
  jmp    L57
L48:
  mov    $0x0,%eax
L32:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  mov    $0xffffffff,%eax
  jmp    L32
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dohuf(FILE *f, int simb, unsigned char *curhuf) {
  int i, j, m, bits;
  unsigned char *pb;
  bits = bihuf(simb, curhuf, &pb);
  if (bits > 0) {
    for (i = 0; i < bits; i++) {
      if (!(i & 7)) {
        m = 0x80;
        j = i >> 3;
      }
      fputbit(f, pb[j] & m);
      m >>= 1;
    }
    return 0;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dohuf>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  mov    %rdx,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <bihuf@plt>
  test   %eax,%eax
  jle    L57
  mov    %eax,%ebp
  xor    %r14d,%r14d
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %ebx,%esi
  sar    %ebx
L45:
  mov    (%rsp),%rdx
  movslq %r12d,%rax
  mov    %r13,%rdi
  add    $0x1,%r14d
  and    (%rdx,%rax,1),%sil
  movzbl %sil,%esi
  call   <fputbit@plt>
  cmp    %r14d,%ebp
  je     L32
L39:
  test   $0x7,%r14b
  jne    L33
  mov    %r14d,%r12d
  mov    $0x40,%ebx
  mov    $0xffffff80,%esi
  sar    $0x3,%r12d
  jmp    L45
  nopl   (%rax)
L32:
  xor    %eax,%eax
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  mov    $0xffffffff,%eax
  jmp    L36
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dohuf(FILE *f, int simb, unsigned char *curhuf) {
  int i, j, m, bits;
  unsigned char *pb;
  bits = bihuf(simb, curhuf, &pb);
  if (bits > 0) {
    for (i = 0; i < bits; i++) {
      if (!(i & 7)) {
        m = 0x80;
        j = i >> 3;
      }
      fputbit(f, pb[j] & m);
      m >>= 1;
    }
    return 0;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dohuf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  mov    %rdx,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <bihuf@plt>
  test   %eax,%eax
  jle    L25
  mov    %eax,%ebp
  xor    %ebx,%ebx
  xchg   %ax,%ax
L30:
  mov    %ebx,%r15d
  and    $0x7,%r15d
  je     L28
  mov    (%rsp),%rdx
  movslq %r12d,%rax
  mov    %r14d,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  sar    %r14d
  and    (%rdx,%rax,1),%sil
  movzbl %sil,%esi
  call   <fputbit@plt>
  cmp    %ebx,%ebp
  jne    L30
  xor    %r15d,%r15d
L56:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %ebx,%r12d
  mov    (%rsp),%rdx
  mov    %r13,%rdi
  add    $0x1,%ebx
  sar    $0x3,%r12d
  movslq %r12d,%rax
  movzbl (%rdx,%rax,1),%esi
  and    $0x80,%esi
  call   <fputbit@plt>
  cmp    %ebx,%ebp
  je     L56
  mov    $0x40,%r14d
  jmp    L30
L25:
  mov    $0xffffffff,%r15d
  jmp    L56
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dohuf(FILE *f, int simb, unsigned char *curhuf) {
  int i, j, m, bits;
  unsigned char *pb;
  bits = bihuf(simb, curhuf, &pb);
  if (bits > 0) {
    for (i = 0; i < bits; i++) {
      if (!(i & 7)) {
        m = 0x80;
        j = i >> 3;
      }
      fputbit(f, pb[j] & m);
      m >>= 1;
    }
    return 0;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L4
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ft_putchar_fd@plt>
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <ft_putchar_fd@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  while (*s)
    ft_putchar_fd(*s++, fd);
  ft_putchar_fd('\n', fd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L6
L9:
  add    $0x1,%rbx
  movsbl %dil,%edi
  mov    %ebp,%esi
  call   <ft_putchar_fd@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
L6:
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <ft_putchar_fd@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  while (*s)
    ft_putchar_fd(*s++, fd);
  ft_putchar_fd('\n', fd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rbx
  mov    %ebp,%esi
  call   <ft_putchar_fd@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L11
L10:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <ft_putchar_fd@plt>
```

assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  while (*s)
    ft_putchar_fd(*s++, fd);
  ft_putchar_fd('\n', fd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rbx
  mov    %ebp,%esi
  call   <ft_putchar_fd@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L0
L4:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <ft_putchar_fd@plt>
```

assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  while (*s)
    ft_putchar_fd(*s++, fd);
  ft_putchar_fd('\n', fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L7
L25:
  cmpl   $0x1,-0x14(%rbp)
  jne    L28
  mov    $0x1,%eax
  jmp    L7
L28:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibonacci>
  mov    %rax,%rbx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibonacci>
  add    %rbx,%rax
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long long int fibonacci(unsigned int n) {
  if (n == 0) {
    return (0);
  } else if (n == 1) {
    return (1);
  } else {
    return (fibonacci(n - 1) + fibonacci(n - 2));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fibonacci>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  je     L14
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jne    L27
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  lea    -0x1(%rdi),%edi
  call   <fibonacci>
  mov    %rax,%rbp
  lea    -0x2(%rbx),%edi
  call   <fibonacci>
  add    %rbp,%rax
  jmp    L7
L14:
  ret
```

assistant: ```c
unsigned long long int fibonacci(unsigned int n) {
  if (n == 0) {
    return (0);
  } else if (n == 1) {
    return (1);
  } else {
    return (fibonacci(n - 1) + fibonacci(n - 2));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<elf_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L14
L22:
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0xf0000000,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  shr    $0x18,%rax
  xor    %rax,-0x10(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  not    %rax
  and    %rax,-0x10(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long elf_hash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name) {
    h = (h << 4) + *name++;
    if (g = (h & 0xf0000000))
      h ^= g >> 24;
    h &= ~g;
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<elf_hash>:
  endbr64
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  movzbl %cl,%edx
  mov    $0x0,%eax
  test   %cl,%cl
  jne    L17
  ret
L6:
  shl    $0x4,%rax
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %rax,%rdx
  mov    %rdx,%rax
  and    $0xf0000000,%eax
  mov    %rax,%rcx
  shr    $0x18,%rcx
  xor    %rdx,%rcx
  test   %rax,%rax
  cmovne %rcx,%rdx
L17:
  not    %rax
  and    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L6
  ret
```

assistant: ```c
unsigned long elf_hash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name) {
    h = (h << 4) + *name++;
    if (g = (h & 0xf0000000))
      h ^= g >> 24;
    h &= ~g;
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<elf_hash>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L21
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L1:
  shl    $0x4,%rax
  add    $0x1,%rdi
  add    %rax,%rdx
  mov    %rdx,%rax
  and    $0xf0000000,%eax
  mov    %rax,%rcx
  shr    $0x18,%rcx
  xor    %rdx,%rcx
  test   %rax,%rax
  cmovne %rcx,%rdx
L21:
  not    %rax
  and    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L1
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  ret
```

assistant: ```c
unsigned long elf_hash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name) {
    h = (h << 4) + *name++;
    if (g = (h & 0xf0000000))
      h ^= g >> 24;
    h &= ~g;
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<elf_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L42
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L33
  nopw   0x0(%rax,%rax,1)
L32:
  shl    $0x4,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L11
  mov    %rdx,%rsi
  not    %rdx
  shr    $0x18,%rsi
  xor    %rsi,%rax
  and    %rdx,%rax
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L32
  ret
  xchg   %ax,%ax
L11:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L32
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  ret
  nopl   0x0(%rax)
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long elf_hash(const unsigned char *name) {
  unsigned long h = 0, g;
  while (*name) {
    h = (h << 4) + *name++;
    if (g = (h & 0xf0000000))
      h ^= g >> 24;
    h &= ~g;
  }
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_try_load_flex_struct_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  cmp    %rax,-0x30(%rbp)
  jbe    L16
  mov    $0x0,%eax
  jmp    L32
L16:
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  imul   -0x30(%rbp),%rax
  cmp    %rax,%rdx
  jae    L5
  mov    $0x0,%eax
  jmp    L32
L5:
  mov    -0x20(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  cmovb  %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
bool _try_load_flex_struct_size(size_t struct_size, size_t fam_type_size, size_t fam_offset, size_t fam_length, size_t *size_handle) {
  if (SIZE_MAX / fam_type_size < fam_length)
    return false;
  if ((SIZE_MAX - fam_offset) < (fam_type_size * fam_length))
    return false;
  const size_t fam_size = fam_type_size * fam_length;
  *size_handle = ((fam_offset + fam_size) < struct_size) ? struct_size : fam_offset + fam_size;
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_try_load_flex_struct_size>:
  endbr64
  mov    %rdi,%r10
  mov    %rdx,%r9
  mov    D0(%rip),%rax
  mov    (%rax),%rdi
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    $0x0,%edx
  cmp    %rcx,%rax
  jb     L7
  imul   %rcx,%rsi
  sub    %r9,%rdi
  cmp    %rsi,%rdi
  jb     L7
  add    %r9,%rsi
  cmp    %r10,%rsi
  cmovb  %r10,%rsi
  mov    %rsi,(%r8)
  mov    $0x1,%edx
L7:
  mov    %edx,%eax
  ret
```

assistant: ```c
bool _try_load_flex_struct_size(size_t struct_size, size_t fam_type_size, size_t fam_offset, size_t fam_length, size_t *size_handle) {
  if (SIZE_MAX / fam_type_size < fam_length)
    return false;
  if ((SIZE_MAX - fam_offset) < (fam_type_size * fam_length))
    return false;
  const size_t fam_size = fam_type_size * fam_length;
  *size_handle = ((fam_offset + fam_size) < struct_size) ? struct_size : fam_offset + fam_size;
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_try_load_flex_struct_size>:
  endbr64
  mov    D9(%rip),%rax
  mov    %rdi,%r10
  mov    %rdx,%r9
  xor    %edx,%edx
  xor    %r11d,%r11d
  mov    (%rax),%rdi
  mov    %rdi,%rax
  div    %rsi
  cmp    %rcx,%rax
  jb     L3
  imul   %rcx,%rsi
  sub    %r9,%rdi
  cmp    %rsi,%rdi
  jb     L3
  add    %r9,%rsi
  mov    $0x1,%r11d
  cmp    %r10,%rsi
  cmovb  %r10,%rsi
  mov    %rsi,(%r8)
L3:
  mov    %r11d,%eax
  ret
```

assistant: ```c
bool _try_load_flex_struct_size(size_t struct_size, size_t fam_type_size, size_t fam_offset, size_t fam_length, size_t *size_handle) {
  if (SIZE_MAX / fam_type_size < fam_length)
    return false;
  if ((SIZE_MAX - fam_offset) < (fam_type_size * fam_length))
    return false;
  const size_t fam_size = fam_type_size * fam_length;
  *size_handle = ((fam_offset + fam_size) < struct_size) ? struct_size : fam_offset + fam_size;
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_try_load_flex_struct_size>:
  endbr64
  mov    D4(%rip),%rax
  mov    %rdi,%r10
  mov    %rdx,%r9
  xor    %edx,%edx
  xor    %r11d,%r11d
  mov    (%rax),%rdi
  mov    %rdi,%rax
  div    %rsi
  cmp    %rcx,%rax
  jb     L1
  imul   %rcx,%rsi
  sub    %r9,%rdi
  cmp    %rsi,%rdi
  jb     L1
  add    %r9,%rsi
  mov    $0x1,%r11d
  cmp    %r10,%rsi
  cmovb  %r10,%rsi
  mov    %rsi,(%r8)
L1:
  mov    %r11d,%eax
  ret
```

assistant: ```c
bool _try_load_flex_struct_size(size_t struct_size, size_t fam_type_size, size_t fam_offset, size_t fam_length, size_t *size_handle) {
  if (SIZE_MAX / fam_type_size < fam_length)
    return false;
  if ((SIZE_MAX - fam_offset) < (fam_type_size * fam_length))
    return false;
  const size_t fam_size = fam_type_size * fam_length;
  *size_handle = ((fam_offset + fam_size) < struct_size) ? struct_size : fam_offset + fam_size;
  return true;
}
```