ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  jne    L69
L85:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  jne    L142
L154:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  jne    L81
L100:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  jne    L38
L129:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <zero@plt>
  mov    $0x1,%esi
  test   %rax,%rax
  je     L87
L5:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <zero@plt>
  mov    $0x1,%esi
  test   %rax,%rax
  je     L146
L124:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <one@plt>
  mov    $0x1,%esi
  test   %rax,%rax
  je     L23
L137:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <one@plt>
  mov    $0x1,%esi
  test   %rax,%rax
  je     L135
L9:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L69:
  xor    %eax,%eax
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L85
L135:
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L9
L23:
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L137
L146:
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L124
L87:
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L5
L38:
  xor    %eax,%eax
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L129
L81:
  xor    %eax,%eax
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L100
L142:
  xor    %eax,%eax
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L154
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main() {
  printf("%d\n", 0 && 0);
  printf("%d\n", 0 && 1);
  printf("%d\n", 1 && 0);
  printf("%d\n", 1 && 1);
  printf("%d\n", 0 || 0);
  printf("%d\n", 0 || 1);
  printf("%d\n", 1 || 0);
  printf("%d\n", 1 || 1);
  printf("%d\n", zero() && zero());
  printf("%d\n", zero() && one());
  printf("%d\n", one() && zero());
  printf("%d\n", one() && one());
  printf("%d\n", zero() || zero());
  printf("%d\n", zero() || one());
  printf("%d\n", one() || zero());
  printf("%d\n", one() || one());
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  jne    L159
L137:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  jne    L133
L146:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  jne    L112
L87:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  jne    L15
L155:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <zero@plt>
  mov    $0x1,%esi
  test   %rax,%rax
  je     L84
L96:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <zero@plt>
  mov    $0x1,%esi
  test   %rax,%rax
  je     L85
L46:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <one@plt>
  mov    $0x1,%esi
  test   %rax,%rax
  je     L105
L58:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <one@plt>
  mov    $0x1,%esi
  test   %rax,%rax
  je     L125
L158:
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L159:
  xor    %eax,%eax
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L137
L125:
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L158
L105:
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L58
L85:
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L46
L84:
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L96
L15:
  xor    %eax,%eax
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L155
L112:
  xor    %eax,%eax
  call   <zero@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L87
L133:
  xor    %eax,%eax
  call   <one@plt>
  xor    %esi,%esi
  test   %rax,%rax
  setne  %sil
  jmp    L146
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d


assistant: ```c
int main() {
  printf("%d\n", 0 && 0);
  printf("%d\n", 0 && 1);
  printf("%d\n", 1 && 0);
  printf("%d\n", 1 && 1);
  printf("%d\n", 0 || 0);
  printf("%d\n", 0 || 1);
  printf("%d\n", 1 || 0);
  printf("%d\n", 1 || 1);
  printf("%d\n", zero() && zero());
  printf("%d\n", zero() && one());
  printf("%d\n", one() && zero());
  printf("%d\n", one() && one());
  printf("%d\n", zero() || zero());
  printf("%d\n", zero() || one());
  printf("%d\n", one() || zero());
  printf("%d\n", one() || one());
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <hello@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D9: in app , call hello 


tool: D8: luorongwei

assistant: ```c
int main(int argc, char **argv) {
  printf("in app , call hello \n");
  hello("luorongwei", 11);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D7(%rip),%rdi
  call   <hello@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type_infered: string
name: disassemble_data
arguments: label: D7
type_infered: string

tool: D12: in app , call hello 


tool: D7: luorongwei

assistant: ```c
int main(int argc, char **argv) {
  printf("in app , call hello \n");
  hello("luorongwei", 11);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D9(%rip),%rdi
  call   <hello@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D9
data_type: string

tool: D0: in app , call hello 


tool: D9: luorongwei

assistant: ```c
int main(int argc, char **argv) {
  printf("in app , call hello \n");
  hello("luorongwei", 11);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D2(%rip),%rdi
  call   <hello@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D2
type: string

tool: D18: in app , call hello 


tool: D2: luorongwei

assistant: ```c
int main(int argc, char **argv) {
  printf("in app , call hello \n");
  hello("luorongwei", 11);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L28
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x28(%rbp)
  jbe    L9
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  jmp    L28
L9:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L28:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t siz) {
  size_t slen = strlen(src);
  size_t dlen = strlen(dst);
  if (siz != 0) {
    if (dlen + slen < siz)
      memcpy(dst + dlen, src, slen + 1);
    else {
      memcpy(dst + dlen, src, siz - dlen - 1);
      dst[siz - 1] = '\0';
    }
  }
  return dlen + slen;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlcat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  test   %r13,%r13
  je     L15
  lea    (%rbx,%rax,1),%rax
  cmp    %r13,%rax
  jae    L25
  lea    0x1(%rbx),%rdx
  lea    (%r12,%rbp,1),%rdi
  mov    %r14,%rsi
  call   <memcpy@plt>
L15:
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  lea    -0x1(%r13),%rdx
  sub    %rbp,%rdx
  lea    (%r12,%rbp,1),%rdi
  mov    %r14,%rsi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%r13,1)
  jmp    L15
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t siz) {
  size_t slen = strlen(src);
  size_t dlen = strlen(dst);
  if (siz != 0) {
    if (dlen + slen < siz)
      memcpy(dst + dlen, src, slen + 1);
    else {
      memcpy(dst + dlen, src, siz - dlen - 1);
      dst[siz - 1] = '\0';
    }
  }
  return dlen + slen;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlcat>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    (%r12,%rax,1),%r14
  test   %rbx,%rbx
  je     L8
  lea    0x0(%rbp,%rax,1),%rdi
  cmp    %r14,%rbx
  jbe    L11
  lea    0x1(%r12),%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
L8:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  lea    -0x1(%rbx),%rdx
  mov    %r13,%rsi
  sub    %rax,%rdx
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t siz) {
  size_t slen = strlen(src);
  size_t dlen = strlen(dst);
  if (siz != 0) {
    if (dlen + slen < siz)
      memcpy(dst + dlen, src, slen + 1);
    else {
      memcpy(dst + dlen, src, siz - dlen - 1);
      dst[siz - 1] = '\0';
    }
  }
  return dlen + slen;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlcat>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    (%r12,%rax,1),%r14
  test   %rbx,%rbx
  je     L19
  lea    0x0(%rbp,%rax,1),%rdi
  cmp    %r14,%rbx
  jbe    L12
  lea    0x1(%r12),%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
L19:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L12:
  lea    -0x1(%rbx),%rdx
  mov    %r13,%rsi
  sub    %rax,%rdx
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t siz) {
  size_t slen = strlen(src);
  size_t dlen = strlen(dst);
  if (siz != 0) {
    if (dlen + slen < siz)
      memcpy(dst + dlen, src, slen + 1);
    else {
      memcpy(dst + dlen, src, siz - dlen - 1);
      dst[siz - 1] = '\0';
    }
  }
  return dlen + slen;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strStr0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L56
  mov    $0xffffffff,%eax
  jmp    L23
L56:
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L1:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L33
  mov    -0xc(%rbp),%eax
  jmp    L23
L33:
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L1
  mov    $0xffffffff,%eax
L23:
  leave
  ret
```

assistant: ```c
int strStr0(char *haystack, char *needle) {
  int needleSize = strlen(needle);
  int haySize = strlen(haystack);
  if (haySize < needleSize)
    return -1;
  for (int i = 0; i <= haySize - needleSize; i++)
    if (strncmp(haystack + i, needle, needleSize) == 0)
      return i;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strStr0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %eax,%r12d
  jg     L22
  mov    %eax,%ebp
  sub    %r12d,%ebp
  mov    $0x0,%ebx
L5:
  mov    %ebx,%r15d
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L16
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L5
  mov    $0xffffffff,%r15d
L16:
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    $0xffffffff,%r15d
  jmp    L16
```

assistant: ```c
int strStr0(char *haystack, char *needle) {
  int needleSize = strlen(needle);
  int haySize = strlen(haystack);
  if (haySize < needleSize)
    return -1;
  for (int i = 0; i <= haySize - needleSize; i++)
    if (strncmp(haystack + i, needle, needleSize) == 0)
      return i;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strStr0>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jg     L1
  mov    %eax,%ebp
  xor    %ebx,%ebx
  sub    %r12d,%ebp
  jmp    L22
  nopl   0x0(%rax)
L7:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jl     L1
L22:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %ebx,%r15d
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L7
L29:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0xffffffff,%r15d
  jmp    L29
```

assistant: ```c
int strStr0(char *haystack, char *needle) {
  int needleSize = strlen(needle);
  int haySize = strlen(haystack);
  if (haySize < needleSize)
    return -1;
  for (int i = 0; i <= haySize - needleSize; i++)
    if (strncmp(haystack + i, needle, needleSize) == 0)
      return i;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strStr0>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jg     L33
  mov    %eax,%ebp
  xor    %ebx,%ebx
  sub    %r12d,%ebp
  jmp    L40
  nopl   0x0(%rax)
L9:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jl     L33
L40:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %ebx,%r15d
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L9
L3:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  mov    $0xffffffff,%r15d
  jmp    L3
```

assistant: ```c
int strStr0(char *haystack, char *needle) {
  int needleSize = strlen(needle);
  int haySize = strlen(haystack);
  if (haySize < needleSize)
    return -1;
  for (int i = 0; i <= haySize - needleSize; i++)
    if (strncmp(haystack + i, needle, needleSize) == 0)
      return i;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_result>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L17
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  mov    %rdx,%rcx
  shl    $0x8,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
L17:
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L23
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int write_result(void *result_pointer, int number_columns, char **fields, char **column_names) {
  int i;
  char(*result)[256] = (char(*)[256])result_pointer;
  for (i = 0; i != number_columns; i++) {
    if (fields[i] != NULL) {
      strcpy(result[i], fields[i]);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_result>:
  endbr64
  test   %esi,%esi
  je     L41
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  shl    $0x8,%rax
  lea    0x100(%rdi,%rax,1),%r12
  jmp    L2
L22:
  add    $0x8,%rbp
  add    $0x100,%rbx
  cmp    %r12,%rbx
  je     L33
L2:
  mov    0x0(%rbp),%rsi
  test   %rsi,%rsi
  je     L22
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L22
L33:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int write_result(void *result_pointer, int number_columns, char **fields, char **column_names) {
  int i;
  char(*result)[256] = (char(*)[256])result_pointer;
  for (i = 0; i != number_columns; i++) {
    if (fields[i] != NULL) {
      strcpy(result[i], fields[i]);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_result>:
  endbr64
  test   %esi,%esi
  je     L15
  lea    -0x1(%rsi),%eax
  push   %r12
  shl    $0x8,%rax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    0x100(%rdi,%rax,1),%r12
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L0:
  mov    0x0(%rbp),%rsi
  test   %rsi,%rsi
  je     L23
  mov    %rbx,%rdi
  call   <strcpy@plt>
L23:
  add    $0x100,%rbx
  add    $0x8,%rbp
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int write_result(void *result_pointer, int number_columns, char **fields, char **column_names) {
  int i;
  char(*result)[256] = (char(*)[256])result_pointer;
  for (i = 0; i != number_columns; i++) {
    if (fields[i] != NULL) {
      strcpy(result[i], fields[i]);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_result>:
  endbr64
  test   %esi,%esi
  je     L11
  lea    -0x1(%rsi),%eax
  push   %r12
  shl    $0x8,%rax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    0x100(%rdi,%rax,1),%r12
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L1:
  mov    0x0(%rbp),%rsi
  test   %rsi,%rsi
  je     L27
  mov    %rbx,%rdi
  call   <strcpy@plt>
L27:
  add    $0x100,%rbx
  add    $0x8,%rbp
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int write_result(void *result_pointer, int number_columns, char **fields, char **column_names) {
  int i;
  char(*result)[256] = (char(*)[256])result_pointer;
  for (i = 0; i != number_columns; i++) {
    if (fields[i] != NULL) {
      strcpy(result[i], fields[i]);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<array_push>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L16
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x1,%eax
  jmp    L38
L16:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  mov    $0x0,%eax
L38:
  leave
  ret
```

assistant: ```c
int array_push(char *v, char **array, int count) {
  for (int i = 0; i < count; ++i) {
    if (!strlen(array[i])) {
      array[i] = v;
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<array_push>:
  endbr64
  test   %edx,%edx
  jle    L12
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rsi,%rax,8),%r12
L18:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L25
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L18
  mov    $0x0,%eax
  jmp    L10
L25:
  mov    %r13,(%rbx)
  mov    $0x1,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int array_push(char *v, char **array, int count) {
  for (int i = 0; i < count; ++i) {
    if (!strlen(array[i])) {
      array[i] = v;
      return 1;
    }
  }
  return 0;
}
```