ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hashtable_hash_key_djb2>:
  endbr64
  movsbq (%rdi),%rdx
  mov    $0x1505,%r8d
  test   %dl,%dl
  je     L6
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %r8,%rax
  mov    %r8,%rcx
  add    $0x1,%rdi
  shl    $0x5,%rax
  shr    $0x2,%rcx
  add    %rcx,%rax
  add    %rdx,%rax
  movsbq (%rdi),%rdx
  xor    %rax,%r8
  test   %dl,%dl
  jne    L11
L6:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long hashtable_hash_key_djb2(const char *string) {
  unsigned long hash;
  const char *ptr_string;
  hash = 5381;
  for (ptr_string = string; ptr_string[0]; ptr_string++) {
    hash ^= (hash << 5) + (hash >> 2) + (int)(ptr_string[0]);
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<socket_connect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0x10(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <inet_pton@plt>
  mov    D36(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x18(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int socket_connect(char *ip, int port) {
  int fd_socket;
  struct sockaddr_in server_addr;
  memset(&server_addr, 0, sizeof(server_addr));
  server_addr.sin_family = AF_INET;
  server_addr.sin_port = htons(port);
  inet_pton(AF_INET, ip, &(server_addr.sin_addr));
  fd_socket = socket(AF_INET, SOCK_STREAM | SOCK_NONBLOCK, 0);
  connect(fd_socket, (struct sockaddr *)&server_addr, sizeof(server_addr));
  return fd_socket;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<socket_connect>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D15(%rip),%rbx
  mov    (%rbx),%eax
  mov    %eax,0x14(%rsp)
  mov    %r13d,%edi
  call   <htons@plt>
  mov    %eax,0x10(%rsp)
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    (%rbx),%edi
  call   <inet_pton@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    D17(%rip),%rax
  or     (%rax),%esi
  mov    $0x0,%edx
  mov    (%rbx),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %ebx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int socket_connect(char *ip, int port) {
  int fd_socket;
  struct sockaddr_in server_addr;
  memset(&server_addr, 0, sizeof(server_addr));
  server_addr.sin_family = AF_INET;
  server_addr.sin_port = htons(port);
  inet_pton(AF_INET, ip, &(server_addr.sin_addr));
  fd_socket = socket(AF_INET, SOCK_STREAM | SOCK_NONBLOCK, 0);
  connect(fd_socket, (struct sockaddr *)&server_addr, sizeof(server_addr));
  return fd_socket;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<socket_connect>:
  endbr64
  push   %r14
  mov    $0xc,%edx
  mov    %esi,%r14d
  xor    %esi,%esi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D17(%rip),%r12
  mov    %r14d,%edi
  mov    (%r12),%eax
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    (%r12),%edi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %eax,0x10(%rsp)
  call   <inet_pton@plt>
  mov    D28(%rip),%rax
  mov    (%r12),%edi
  xor    %edx,%edx
  mov    (%rax),%esi
  mov    D22(%rip),%rax
  or     (%rax),%esi
  call   <socket@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <connect@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int socket_connect(char *ip, int port) {
  int fd_socket;
  struct sockaddr_in server_addr;
  memset(&server_addr, 0, sizeof(server_addr));
  server_addr.sin_family = AF_INET;
  server_addr.sin_port = htons(port);
  inet_pton(AF_INET, ip, &(server_addr.sin_addr));
  fd_socket = socket(AF_INET, SOCK_STREAM | SOCK_NONBLOCK, 0);
  connect(fd_socket, (struct sockaddr *)&server_addr, sizeof(server_addr));
  return fd_socket;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<socket_connect>:
  endbr64
  push   %r14
  mov    $0xc,%edx
  mov    %esi,%r14d
  xor    %esi,%esi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D26(%rip),%r12
  mov    %r14d,%edi
  mov    (%r12),%eax
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    (%r12),%edi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %eax,0x10(%rsp)
  call   <inet_pton@plt>
  mov    D6(%rip),%rax
  mov    (%r12),%edi
  xor    %edx,%edx
  mov    (%rax),%esi
  mov    D14(%rip),%rax
  or     (%rax),%esi
  call   <socket@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <connect@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int socket_connect(char *ip, int port) {
  int fd_socket;
  struct sockaddr_in server_addr;
  memset(&server_addr, 0, sizeof(server_addr));
  server_addr.sin_family = AF_INET;
  server_addr.sin_port = htons(port);
  inet_pton(AF_INET, ip, &(server_addr.sin_addr));
  fd_socket = socket(AF_INET, SOCK_STREAM | SOCK_NONBLOCK, 0);
  connect(fd_socket, (struct sockaddr *)&server_addr, sizeof(server_addr));
  return fd_socket;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<encode_xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    $0x0,%ebx
  jmp    L19
L6:
  movslq %ebx,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    %ebx,%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movslq %ebx,%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  mov    %ebx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L29
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%edx
  movslq %ebx,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L30
L29:
  mov    0x10(%rbp),%rax
  movzbl (%rax),%edx
  movslq %ebx,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    0x10(%rbp),%rax
  mov    %dl,(%rax)
L30:
  add    $0x1,%ebx
L19:
  cmp    -0x18(%rbp),%ebx
  jl     L6
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void encode_xor(unsigned char *key, int key_size, unsigned char *src, int src_size, unsigned char *dst, unsigned char *first, unsigned char *second) {
  register int i = 0;
  for (; i < src_size; ++i) {
    dst[i] = src[i] ^ key[i % key_size];
    if ((i & 0x0001))
      *first = *first ^ src[i];
    else
      *second = *second ^ src[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<encode_xor>:
  endbr64
  push   %rbx
  mov    0x10(%rsp),%rbx
  test   %ecx,%ecx
  jle    L13
  mov    %rdi,%r11
  mov    %rdx,%rdi
  mov    %ecx,%r10d
  mov    $0x0,%ecx
  jmp    L38
L4:
  movzbl (%rdi,%rcx,1),%eax
  xor    %al,(%rbx)
L36:
  add    $0x1,%rcx
  cmp    %r10,%rcx
  je     L13
L38:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  movzbl (%r11,%rdx,1),%eax
  xor    (%rdi,%rcx,1),%al
  mov    %al,(%r8,%rcx,1)
  test   $0x1,%cl
  je     L4
  movzbl (%rdi,%rcx,1),%eax
  xor    %al,(%r9)
  jmp    L36
L13:
  pop    %rbx
  ret
```

assistant: ```c
void encode_xor(unsigned char *key, int key_size, unsigned char *src, int src_size, unsigned char *dst, unsigned char *first, unsigned char *second) {
  register int i = 0;
  for (; i < src_size; ++i) {
    dst[i] = src[i] ^ key[i % key_size];
    if ((i & 0x0001))
      *first = *first ^ src[i];
    else
      *second = *second ^ src[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encode_xor>:
  endbr64
  push   %rbx
  mov    0x10(%rsp),%rbx
  test   %ecx,%ecx
  jle    L18
  mov    %rdi,%r11
  movslq %ecx,%r10
  mov    %rdx,%rdi
  xor    %ecx,%ecx
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%rcx
  xor    %al,(%r9)
  cmp    %rcx,%r10
  je     L18
L37:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  movzbl (%r11,%rdx,1),%eax
  xor    (%rdi,%rcx,1),%al
  mov    %al,(%r8,%rcx,1)
  movzbl (%rdi,%rcx,1),%eax
  test   $0x1,%cl
  jne    L34
  add    $0x1,%rcx
  xor    %al,(%rbx)
  cmp    %rcx,%r10
  jne    L37
L18:
  pop    %rbx
  ret
```

assistant: ```c
void encode_xor(unsigned char *key, int key_size, unsigned char *src, int src_size, unsigned char *dst, unsigned char *first, unsigned char *second) {
  register int i = 0;
  for (; i < src_size; ++i) {
    dst[i] = src[i] ^ key[i % key_size];
    if ((i & 0x0001))
      *first = *first ^ src[i];
    else
      *second = *second ^ src[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<encode_xor>:
  endbr64
  push   %rbx
  mov    0x10(%rsp),%rbx
  test   %ecx,%ecx
  jle    L49
  mov    %rdi,%r11
  movslq %ecx,%r10
  mov    %rdx,%rdi
  xor    %ecx,%ecx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rcx
  xor    %al,(%r9)
  cmp    %rcx,%r10
  je     L49
L8:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  movzbl (%r11,%rdx,1),%eax
  xor    (%rdi,%rcx,1),%al
  mov    %al,(%r8,%rcx,1)
  movzbl (%rdi,%rcx,1),%eax
  test   $0x1,%cl
  jne    L15
  add    $0x1,%rcx
  xor    %al,(%rbx)
  cmp    %rcx,%r10
  jne    L8
L49:
  pop    %rbx
  ret
```

assistant: ```c
void encode_xor(unsigned char *key, int key_size, unsigned char *src, int src_size, unsigned char *dst, unsigned char *first, unsigned char *second) {
  register int i = 0;
  for (; i < src_size; ++i) {
    dst[i] = src[i] ^ key[i % key_size];
    if ((i & 0x0001))
      *first = *first ^ src[i];
    else
      *second = *second ^ src[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L8:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  addl   $0x1,-0xc(%rbp)
L2:
  cmpl   $0xf423f,-0xc(%rbp)
  jle    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int main(int ac, char **av) {
  for (int i = 0; i < 1000000; i++) {
    struct stat st;
    stat(av[1], &st);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0xf4240,%ebx
  lea    0x4(%rsp),%r12
L7:
  mov    0x8(%rbp),%rdi
  mov    %r12,%rsi
  call   <stat@plt>
  sub    $0x1,%ebx
  jne    L7
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int ac, char **av) {
  for (int i = 0; i < 1000000; i++) {
    struct stat st;
    stat(av[1], &st);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L18:
  mov    0x8(%rbp),%rdi
  mov    %r12,%rsi
  call   <stat@plt>
  sub    $0x1,%ebx
  jne    L18
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int ac, char **av) {
  for (int i = 0; i < 1000000; i++) {
    struct stat st;
    stat(av[1], &st);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L6:
  mov    0x8(%rbp),%rdi
  mov    %r12,%rsi
  call   <stat@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int ac, char **av) {
  for (int i = 0; i < 1000000; i++) {
    struct stat st;
    stat(av[1], &st);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_combination>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,%edx
  jl     L1
  mov    $0x0,%eax
  jmp    L72
L1:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L41
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%eax
  sub    %ecx,%eax
  cmp    %eax,%edx
  jl     L76
  subl   $0x1,-0xc(%rbp)
L41:
  cmpl   $0x0,-0xc(%rbp)
  jg     L3
  jmp    L11
L76:
  nop
L11:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L49
L42:
  addl   $0x1,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L42
  mov    $0x1,%eax
L72:
  pop    %rbp
  ret
```

assistant: ```c
int next_combination(int *list, int lsize, int inall) {
  int size = lsize;
  int i;
  int value;
  if (list[0] >= (inall - size)) {
    return 0;
  }
  for (i = size - 1; i > 0; --i) {
    if (list[i] < inall - (size - i)) {
      break;
    }
  }
  value = list[i];
  for (; i < size; ++i) {
    ++value;
    list[i] = value;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<next_combination>:
  endbr64
  mov    %esi,%r8d
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    $0x0,%eax
  cmp    %ecx,(%rdi)
  jge    L22
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L7
  movslq %eax,%rcx
  lea    (%rdi,%rcx,4),%rcx
  sub    %esi,%edx
L0:
  lea    (%rdx,%rax,1),%esi
  cmp    %esi,(%rcx)
  jl     L7
  sub    $0x4,%rcx
  sub    $0x1,%eax
  jne    L0
L7:
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    (%rcx),%edx
  cmp    %eax,%r8d
  jle    L36
  sub    %eax,%r8d
  lea    (%r8,%rdx,1),%eax
L29:
  add    $0x1,%edx
  mov    %edx,(%rcx)
  add    $0x4,%rcx
  cmp    %eax,%edx
  jne    L29
  mov    $0x1,%eax
  ret
L36:
  mov    $0x1,%eax
L22:
  ret
```

assistant: ```c
int next_combination(int *list, int lsize, int inall) {
  int size = lsize;
  int i;
  int value;
  if (list[0] >= (inall - size)) {
    return 0;
  }
  for (i = size - 1; i > 0; --i) {
    if (list[i] < inall - (size - i)) {
      break;
    }
  }
  value = list[i];
  for (; i < size; ++i) {
    ++value;
    list[i] = value;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<next_combination>:
  endbr64
  mov    (%rdi),%r10d
  sub    %esi,%edx
  mov    %rdi,%r9
  xor    %eax,%eax
  cmp    %edx,%r10d
  jge    L33
  lea    -0x1(%rsi),%ecx
  movslq %ecx,%rax
  lea    (%rdi,%rax,4),%rdi
  mov    (%rdi),%eax
  test   %ecx,%ecx
  jg     L39
  jmp    L31
  nopl   (%rax)
L25:
  sub    $0x4,%rdi
  sub    $0x1,%ecx
  je     L10
L39:
  mov    (%rdi),%eax
  lea    (%rdx,%rcx,1),%r8d
  cmp    %r8d,%eax
  jge    L25
L31:
  cmp    %ecx,%esi
  jle    L35
  movslq %ecx,%rdx
  add    %eax,%esi
  lea    (%r9,%rdx,4),%rdx
  sub    %ecx,%esi
  nopl   0x0(%rax,%rax,1)
L57:
  add    $0x1,%eax
  add    $0x4,%rdx
  mov    %eax,-0x4(%rdx)
  cmp    %esi,%eax
  jne    L57
L35:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L33:
  ret
  nopl   0x0(%rax)
L10:
  mov    %r10d,%eax
  jmp    L31
```

assistant: ```c
int next_combination(int *list, int lsize, int inall) {
  int size = lsize;
  int i;
  int value;
  if (list[0] >= (inall - size)) {
    return 0;
  }
  for (i = size - 1; i > 0; --i) {
    if (list[i] < inall - (size - i)) {
      break;
    }
  }
  value = list[i];
  for (; i < size; ++i) {
    ++value;
    list[i] = value;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<next_combination>:
  endbr64
  mov    (%rdi),%r10d
  sub    %esi,%edx
  mov    %rdi,%r9
  mov    %esi,%r8d
  xor    %eax,%eax
  cmp    %edx,%r10d
  jge    L116
  lea    -0x1(%rsi),%eax
  movslq %eax,%rcx
  lea    (%rdi,%rcx,4),%rcx
  mov    (%rcx),%esi
  test   %eax,%eax
  jg     L128
  jmp    L38
  nopl   0x0(%rax)
L86:
  sub    $0x4,%rcx
  sub    $0x1,%eax
  je     L34
L128:
  mov    (%rcx),%esi
  lea    (%rdx,%rax,1),%edi
  cmp    %edi,%esi
  jge    L86
L38:
  cmp    %eax,%r8d
  jle    L63
  mov    %r8d,%r10d
  sub    %eax,%r10d
  lea    -0x1(%r10),%edx
  cmp    $0x2,%edx
  jbe    L22
  movslq %eax,%rdx
  movd   %esi,%xmm4
  movdqa D8(%rip),%xmm3
  movdqa D24(%rip),%xmm2
  lea    (%r9,%rdx,4),%rcx
  mov    %r10d,%edx
  pshufd $0x0,%xmm4,%xmm1
  shr    $0x2,%edx
  paddd  D29(%rip),%xmm1
  lea    -0x1(%rdx),%edi
  lea    0x10(%rcx),%rdx
  shl    $0x4,%rdi
  add    %rdx,%rdi
  jmp    L23
  nopl   0x0(%rax)
L106:
  add    $0x10,%rdx
L23:
  movdqa %xmm1,%xmm0
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  movups %xmm0,(%rcx)
  mov    %rdx,%rcx
  cmp    %rdx,%rdi
  jne    L106
  mov    %r10d,%edx
  and    $0xfffffffc,%edx
  add    %edx,%eax
  add    %edx,%esi
  cmp    %r10d,%edx
  je     L63
L22:
  movslq %eax,%rdx
  lea    0x1(%rsi),%edi
  mov    %edi,(%r9,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r8d
  jle    L63
  lea    0x2(%rsi),%edx
  add    $0x2,%eax
  mov    %edx,0x4(%r9,%rcx,1)
  cmp    %eax,%r8d
  jle    L63
  add    $0x3,%esi
  mov    %esi,0x8(%r9,%rcx,1)
L63:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L116:
  ret
  nopl   0x0(%rax)
L34:
  mov    %r10d,%esi
  jmp    L38
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: byte[16]
name: read_data
arguments: data_tag: D24
type_infered: byte[16]
name: read_data
arguments: data_tag: D29
type_infered: byte[16]

tool: {"D8": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D24": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int next_combination(int *list, int lsize, int inall) {
  int size = lsize;
  int i;
  int value;
  if (list[0] >= (inall - size)) {
    return 0;
  }
  for (i = size - 1; i > 0; --i) {
    if (list[i] < inall - (size - i)) {
      break;
    }
  }
  value = list[i];
  for (; i < size; ++i) {
    ++value;
    list[i] = value;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_dedx_filename>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%r13d
  cmp    $0x1,%eax
  jle    L29
  mov    %eax,%eax
  mov    %rax,0x8(%rsp)
  mov    %r13d,%r14d
  mov    $0x1,%ebp
  lea    -0x1(%r13),%r15d
  jmp    L1
L84:
  movslq %r13d,%rax
  movzbl -0x1(%rbx,%rax,1),%edx
L90:
  movsbl %dl,%edx
  movsbl (%rbx,%rbp,1),%esi
  movsbl -0x1(%rbx,%rbp,1),%edi
  call   <camel_split@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r14d
  add    $0x1,%rbp
  cmp    %rbp,0x8(%rsp)
  je     L63
L1:
  cmp    %ebp,%r15d
  jle    L84
  movzbl 0x1(%rbx,%rbp,1),%edx
  jmp    L90
L92:
  mov    0x18(%rsp),%rax
  movzbl -0x1(%rbx,%rax,1),%edx
  jmp    L105
L31:
  movslq %r12d,%r13
  add    0x10(%rsp),%r13
  movsbl (%rbx,%rbp,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%r13)
  add    $0x1,%r12d
  add    $0x1,%rbp
  cmp    %rbp,0x8(%rsp)
  je     L47
L33:
  cmp    %ebp,%r15d
  jle    L92
  movzbl 0x1(%rbx,%rbp,1),%edx
L105:
  movsbl %dl,%edx
  movsbl (%rbx,%rbp,1),%esi
  movsbl -0x1(%rbx,%rbp,1),%edi
  call   <camel_split@plt>
  test   %rax,%rax
  je     L31
  movslq %r12d,%rax
  mov    0x10(%rsp),%rcx
  movb   $0x5f,(%rcx,%rax,1)
  add    $0x1,%r12d
  jmp    L31
L29:
  lea    0x5(%rax),%esi
  mov    (%r12),%rdi
  call   <reallocate@plt>
  mov    %rax,%r14
  mov    %rax,0x10(%rsp)
  mov    %rax,(%r12)
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%r14)
  mov    %r13d,%r14d
L47:
  movslq %r14d,%r14
  mov    0x10(%rsp),%rax
  movb   $0x2e,(%rax,%r14,1)
  movb   $0x74,0x1(%rax,%r14,1)
  movb   $0x78,0x2(%rax,%r14,1)
  movb   $0x74,0x3(%rax,%r14,1)
  movb   $0x0,0x4(%rax,%r14,1)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  lea    0x5(%r14),%esi
  mov    (%r12),%rdi
  call   <reallocate@plt>
  mov    %rax,%rbp
  mov    %rax,0x10(%rsp)
  mov    %rax,(%r12)
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp)
  mov    $0x1,%ebp
  mov    $0x1,%r12d
  movslq %r13d,%rax
  mov    %rax,0x18(%rsp)
  jmp    L33
```

assistant: ```c
void set_dedx_filename(const char *name, char **filename_ptr) {
  const int n0 = strlen(name);
  int i, n = n0;
  for (i = 1; i < n0; i++) {
    const char c = (i < n0 - 1) ? name[i + 1] : name[n0 - 1];
    if (camel_split(name[i - 1], name[i], c))
      n++;
  }
  char *filename = reallocate(*filename_ptr, n + 5);
  *filename_ptr = filename;
  filename[0] = tolower(name[0]);
  int j;
  for (i = 1, j = 1; i < n0; i++, j++) {
    const char c = (i < n0 - 1) ? name[i + 1] : name[n0 - 1];
    if (camel_split(name[i - 1], name[i], c)) {
      filename[j] = '_';
      j++;
    }
    filename[j] = tolower(name[i]);
  }
  filename[n + 0] = '.';
  filename[n + 1] = 't';
  filename[n + 2] = 'x';
  filename[n + 3] = 't';
  filename[n + 4] = 0x0;
}
```