ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<get_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L45
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L67:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L18
  cmp    $0xa,%eax
  je     L18
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L67
  mov    %r12d,%ebx
  jmp    L33
L45:
  mov    $0x0,%ebx
L18:
  cmp    $0xa,%eax
  je     L32
L33:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  add    $0x1,%ebx
  jmp    L33
```

assistant: ```c
int get_line(char str[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    str[i] = c;
  if (c == '\n') {
    str[i] = c;
    ++i;
  }
  str[i] = '\0';
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_line>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L51
  mov    D0(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L38:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L42
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L45
  mov    %edx,%r14d
L7:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L38
  cmp    $0xa,%eax
  je     L29
L51:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  lea    0x1(%r14),%edx
L42:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L45:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_line(char str[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    str[i] = c;
  if (c == '\n') {
    str[i] = c;
    ++i;
  }
  str[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_line>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L44
  mov    D0(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L38:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L10
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L57
  mov    %edx,%r14d
L56:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L38
  cmp    $0xa,%eax
  je     L42
L44:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  lea    0x1(%r14),%edx
L10:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L57:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_line(char str[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    str[i] = c;
  if (c == '\n') {
    str[i] = c;
    ++i;
  }
  str[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_machine_little_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  movzbl -0xc(%rbp),%eax
  cmp    $0x1,%al
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int is_machine_little_endian() {
  union {
    int i;
    char c[sizeof(int)];
  } u;
  u.i = 1;
  return (u.c[0] == 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_machine_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_machine_little_endian() {
  union {
    int i;
    char c[sizeof(int)];
  } u;
  u.i = 1;
  return (u.c[0] == 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_machine_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_machine_little_endian() {
  union {
    int i;
    char c[sizeof(int)];
  } u;
  u.i = 1;
  return (u.c[0] == 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_machine_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_machine_little_endian() {
  union {
    int i;
    char c[sizeof(int)];
  } u;
  u.i = 1;
  return (u.c[0] == 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D71(%rip),%rax
  mov    %rax,-0x60(%rbp)
  lea    D77(%rip),%rax
  mov    %rax,-0x58(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D67(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D83(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D59(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D65(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D73(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D45(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x64(%rbp)
  jmp    L6
L23:
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x64(%rbp)
L6:
  cmpl   $0x9,-0x64(%rbp)
  jle    L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D71
data_type: string
name: read_data
arguments: tag: D77
data_type: string
name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D67
data_type: string
name: read_data
arguments: tag: D83
data_type: string
name: read_data
arguments: tag: D59
data_type: string
name: read_data
arguments: tag: D65
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D73
data_type: string
name: read_data
arguments: tag: D45
data_type: string
name: read_data
arguments: tag: D98
data_type: string

tool: D71: 123

tool: D77:  0.1 

tool: D22: bc

tool: D67: 1 a

tool: D83: 2e10

tool: D59: 2e10.

tool: D65: .4

tool: D26: 43.e4

tool: D73: .2e81

tool: D45: 3.  

tool: D98: %d


assistant: ```c
int main() {
  char *s[10];
  s[0] = "123";
  s[1] = " 0.1 ";
  s[2] = "bc";
  s[3] = "1 a";
  s[4] = "2e10";
  s[5] = "2e10.";
  s[6] = ".4";
  s[7] = "43.e4";
  s[8] = ".2e81";
  s[9] = "3.  ";
  for (int i = 0; i < 10; i++)
    printf("%d\n", isNumber(s[i]));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D53(%rip),%rax
  mov    %rax,(%rsp)
  lea    D23(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D98(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D42(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D71(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D84(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D73(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D14(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D70(%rip),%rax
  mov    %rax,0x40(%rsp)
  lea    D61(%rip),%rax
  mov    %rax,0x48(%rsp)
  mov    %rsp,%rbx
  lea    0x50(%rsp),%r12
  lea    D58(%rip),%rbp
L8:
  mov    (%rbx),%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L8
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D53
type_infered: string
name: retrieve_data
arguments: data_tag: D23
type_infered: string
name: retrieve_data
arguments: data_tag: D98
type_infered: string
name: retrieve_data
arguments: data_tag: D42
type_infered: string
name: retrieve_data
arguments: data_tag: D71
type_infered: string
name: retrieve_data
arguments: data_tag: D84
type_infered: string
name: retrieve_data
arguments: data_tag: D73
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string
name: retrieve_data
arguments: data_tag: D70
type_infered: string
name: retrieve_data
arguments: data_tag: D61
type_infered: string
name: retrieve_data
arguments: data_tag: D58
type_infered: string

tool: D53: 123

tool: D23:  0.1 

tool: D98: bc

tool: D42: 1 a

tool: D71: 2e10

tool: D84: 2e10.

tool: D73: .4

tool: D14: 43.e4

tool: D70: .2e81

tool: D61: 3.  

tool: D58: %d


assistant: ```c
int main() {
  char *s[10];
  s[0] = "123";
  s[1] = " 0.1 ";
  s[2] = "bc";
  s[3] = "1 a";
  s[4] = "2e10";
  s[5] = "2e10.";
  s[6] = ".4";
  s[7] = "43.e4";
  s[8] = ".2e81";
  s[9] = "3.  ";
  for (int i = 0; i < 10; i++)
    printf("%d\n", isNumber(s[i]));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D36(%rip),%rdi
  push   %rbp
  lea    D91(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  lea    D27(%rip),%rax
  lea    0x8(%rsp),%rbx
  lea    0x50(%rsp),%r12
  mov    %rax,0x8(%rsp)
  lea    D105(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D68(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D7(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D95(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D80(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D61(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D51(%rip),%rax
  mov    %rax,0x40(%rsp)
  lea    D48(%rip),%rax
  mov    %rax,0x48(%rsp)
  jmp    L13
L11:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
L13:
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D36
type_guessed: string
name: unpack_data
arguments: tag: D91
type_guessed: string
name: unpack_data
arguments: tag: D27
type_guessed: string
name: unpack_data
arguments: tag: D105
type_guessed: string
name: unpack_data
arguments: tag: D68
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D95
type_guessed: string
name: unpack_data
arguments: tag: D80
type_guessed: string
name: unpack_data
arguments: tag: D61
type_guessed: string
name: unpack_data
arguments: tag: D51
type_guessed: string
name: unpack_data
arguments: tag: D48
type_guessed: string

tool: D36: 123

tool: D91: %d


tool: D27:  0.1 

tool: D105: bc

tool: D68: 1 a

tool: D7: 2e10

tool: D95: 2e10.

tool: D80: .4

tool: D61: 43.e4

tool: D51: .2e81

tool: D48: 3.  

assistant: ```c
int main() {
  char *s[10];
  s[0] = "123";
  s[1] = " 0.1 ";
  s[2] = "bc";
  s[3] = "1 a";
  s[4] = "2e10";
  s[5] = "2e10.";
  s[6] = ".4";
  s[7] = "43.e4";
  s[8] = ".2e81";
  s[9] = "3.  ";
  for (int i = 0; i < 10; i++)
    printf("%d\n", isNumber(s[i]));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdx
  lea    D53(%rip),%rcx
  push   %rbp
  movq   %rdx,%xmm0
  lea    D0(%rip),%rdx
  lea    D30(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  lea    D90(%rip),%rax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%r12
  movq   %rax,%xmm1
  lea    D62(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  lea    D96(%rip),%rax
  movaps %xmm0,(%rsp)
  movq   %rcx,%xmm0
  movq   %rax,%xmm3
  lea    D101(%rip),%rcx
  punpcklqdq %xmm2,%xmm0
  lea    D6(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  movq   %rdx,%xmm0
  movq   %rax,%xmm4
  lea    D67(%rip),%rdx
  punpcklqdq %xmm3,%xmm0
  lea    D29(%rip),%rax
  movaps %xmm0,0x20(%rsp)
  movq   %rcx,%xmm0
  movq   %rax,%xmm5
  punpcklqdq %xmm4,%xmm0
  movaps %xmm0,0x30(%rsp)
  movq   %rdx,%xmm0
  punpcklqdq %xmm5,%xmm0
  movaps %xmm0,0x40(%rsp)
  nopl   (%rax)
L9:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L9
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
data_type: string
name: disassemble_data
arguments: data_label: D53
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D30
data_type: string
name: disassemble_data
arguments: data_label: D90
data_type: string
name: disassemble_data
arguments: data_label: D62
data_type: string
name: disassemble_data
arguments: data_label: D96
data_type: string
name: disassemble_data
arguments: data_label: D101
data_type: string
name: disassemble_data
arguments: data_label: D6
data_type: string
name: disassemble_data
arguments: data_label: D67
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string

tool: D28: 123

tool: D53: bc

tool: D0: 2e10

tool: D30: %d


tool: D90:  0.1 

tool: D62: 1 a

tool: D96: 2e10.

tool: D101: .4

tool: D6: 43.e4

tool: D67: .2e81

tool: D29: 3.  

assistant: ```c
int main() {
  char *s[10];
  s[0] = "123";
  s[1] = " 0.1 ";
  s[2] = "bc";
  s[3] = "1 a";
  s[4] = "2e10";
  s[5] = "2e10.";
  s[6] = ".4";
  s[7] = "43.e4";
  s[8] = ".2e81";
  s[9] = "3.  ";
  for (int i = 0; i < 10; i++)
    printf("%d\n", isNumber(s[i]));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uniq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L37
L17:
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L24
  mov    $0x0,%eax
  jmp    L26
L24:
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jb     L17
  mov    $0x1,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
bool uniq(unsigned *ib, unsigned s, unsigned i) {
  unsigned j;
  for (j = s + 1; j < i; j++)
    if (ib[s] == ib[j])
      return false;
  return true;
}
```
user: What is the c source code of the assembly code below?

```asm
<uniq>:
  endbr64
  lea    0x1(%rsi),%eax
  cmp    %edx,%eax
  jae    L11
  mov    %esi,%ecx
  mov    (%rdi,%rcx,4),%ecx
  mov    %eax,%r8d
  lea    (%rdi,%r8,4),%rax
  sub    $0x2,%edx
  sub    %esi,%edx
  add    %r8,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
L4:
  cmp    (%rax),%ecx
  je     L13
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
  mov    $0x1,%eax
  ret
L11:
  mov    $0x1,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool uniq(unsigned *ib, unsigned s, unsigned i) {
  unsigned j;
  for (j = s + 1; j < i; j++)
    if (ib[s] == ib[j])
      return false;
  return true;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uniq>:
  endbr64
  lea    0x1(%rsi),%eax
  cmp    %edx,%eax
  jae    L29
  sub    $0x2,%edx
  mov    %eax,%r8d
  mov    %esi,%ecx
  sub    %esi,%edx
  mov    (%rdi,%rcx,4),%ecx
  lea    (%rdi,%r8,4),%rax
  add    %r8,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L14:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L29
L2:
  cmp    (%rax),%ecx
  jne    L14
  xor    %eax,%eax
  ret
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool uniq(unsigned *ib, unsigned s, unsigned i) {
  unsigned j;
  for (j = s + 1; j < i; j++)
    if (ib[s] == ib[j])
      return false;
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uniq>:
  endbr64
  lea    0x1(%rsi),%eax
  cmp    %edx,%eax
  jae    L19
  sub    $0x2,%edx
  mov    %eax,%r8d
  mov    %esi,%ecx
  sub    %esi,%edx
  mov    (%rdi,%rcx,4),%ecx
  lea    (%rdi,%r8,4),%rax
  add    %r8,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L28:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L19
L4:
  cmp    (%rax),%ecx
  jne    L28
  xor    %eax,%eax
  ret
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool uniq(unsigned *ib, unsigned s, unsigned i) {
  unsigned j;
  for (j = s + 1; j < i; j++)
    if (ib[s] == ib[j])
      return false;
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <setup@plt>
L4:
  mov    $0x0,%eax
  call   <loop@plt>
  jmp    L4
```

assistant: ```c
int main(void) {
  setup();
  while (true)
    loop();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <setup@plt>
L6:
  mov    $0x0,%eax
  call   <loop@plt>
  jmp    L6
```

assistant: ```c
int main(void) {
  setup();
  while (true)
    loop();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup@plt>
  nop
L5:
  xor    %eax,%eax
  call   <loop@plt>
  jmp    L5
```

assistant: ```c
int main(void) {
  setup();
  while (true)
    loop();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup@plt>
  nop
L9:
  xor    %eax,%eax
  call   <loop@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  setup();
  while (true)
    loop();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L14
  cmpl   $0x5a,-0x4(%rbp)
  jg     L14
  mov    -0x4(%rbp),%eax
  add    $0x20,%eax
  jmp    L24
L14:
  mov    -0x4(%rbp),%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int tolower(int c) {
  if ((c >= 'A') && (c <= 'Z'))
    return (c - 'A' + 'a');
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tolower>:
  endbr64
  mov    %edi,%eax
  lea    -0x41(%rdi),%ecx
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int tolower(int c) {
  if ((c >= 'A') && (c <= 'Z'))
    return (c - 'A' + 'a');
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tolower>:
  endbr64
  lea    -0x41(%rdi),%ecx
  mov    %edi,%eax
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int tolower(int c) {
  if ((c >= 'A') && (c <= 'Z'))
    return (c - 'A' + 'a');
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tolower>:
  endbr64
  lea    -0x41(%rdi),%ecx
  mov    %edi,%eax
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int tolower(int c) {
  if ((c >= 'A') && (c <= 'Z'))
    return (c - 'A' + 'a');
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<removeChars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L11:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L13
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L37
  addq   $0x1,-0x10(%rbp)
L37:
  addq   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void removeChars(char *str, char *garbage) {
  char *src, *dst, *ch;
  for (ch = garbage; *ch != '\0'; ch++) {
    for (src = dst = str; *src != '\0'; src++) {
      *dst = *src;
      if (*dst != *ch)
        dst++;
    }
    *dst = '\0';
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<removeChars>:
  endbr64
  cmpb   $0x0,(%rsi)
  jne    L20
  ret
L25:
  mov    %al,(%rdx)
  cmp    %al,(%rsi)
  setne  %al
  movzbl %al,%eax
  add    %rax,%rdx
  add    $0x1,%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L25
L24:
  movb   $0x0,(%rdx)
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  je     L12
L20:
  movzbl (%rdi),%eax
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  test   %al,%al
  jne    L25
  jmp    L24
L12:
  ret
```

assistant: ```c
void removeChars(char *str, char *garbage) {
  char *src, *dst, *ch;
  for (ch = garbage; *ch != '\0'; ch++) {
    for (src = dst = str; *src != '\0'; src++) {
      *dst = *src;
      if (*dst != *ch)
        dst++;
    }
    *dst = '\0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<removeChars>:
  endbr64
  cmpb   $0x0,(%rsi)
  je     L8
  nopl   0x0(%rax)
L7:
  movzbl (%rdi),%eax
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  test   %al,%al
  je     L32
  nopl   (%rax)
L36:
  mov    %al,(%rdx)
  cmp    %al,(%rsi)
  setne  %al
  add    $0x1,%rcx
  movzbl %al,%eax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L36
L32:
  add    $0x1,%rsi
  movb   $0x0,(%rdx)
  cmpb   $0x0,(%rsi)
  jne    L7
  ret
L8:
  ret
```

assistant: ```c
void removeChars(char *str, char *garbage) {
  char *src, *dst, *ch;
  for (ch = garbage; *ch != '\0'; ch++) {
    for (src = dst = str; *src != '\0'; src++) {
      *dst = *src;
      if (*dst != *ch)
        dst++;
    }
    *dst = '\0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<removeChars>:
  endbr64
  cmpb   $0x0,(%rsi)
  je     L16
  nopl   0x0(%rax)
L10:
  movzbl (%rdi),%eax
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  test   %al,%al
  je     L2
  nopl   (%rax)
L6:
  mov    %al,(%rdx)
  cmp    (%rsi),%al
  setne  %al
  add    $0x1,%rcx
  movzbl %al,%eax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L6
L2:
  add    $0x1,%rsi
  movb   $0x0,(%rdx)
  cmpb   $0x0,(%rsi)
  jne    L10
  ret
L16:
  ret
```

assistant: ```c
void removeChars(char *str, char *garbage) {
  char *src, *dst, *ch;
  for (ch = garbage; *ch != '\0'; ch++) {
    for (src = dst = str; *src != '\0'; src++) {
      *dst = *src;
      if (*dst != *ch)
        dst++;
    }
    *dst = '\0';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getValue2@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x5,%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%edi
  call   <use@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo2() {
  int x = getValue2();
  int y = x;
  use(5 / x);
  if (y == 0) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getValue2@plt>
  mov    %eax,%ecx
  mov    $0x5,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  call   <use@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo2() {
  int x = getValue2();
  int y = x;
  use(5 / x);
  if (y == 0) {
  }
}
```