ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<output_readable_char>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  cmp    $0x20,%rdi
  jle    L6
  cmp    $0x5c,%rdi
  je     L29
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <output_char@plt>
  nopl   (%rax)
L6:
  mov    $0x5c,%edi
  call   <output_char@plt>
  cmp    $0x9,%rbp
  jle    L15
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <output_q@plt>
  nopl   0x0(%rax)
L29:
  mov    $0x5c,%edi
  call   <output_char@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <output_char@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x30,%edi
  call   <output_char@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <output_q@plt>
```

assistant: ```c
void output_readable_char(long c) {
  if (c > 32) {
    if (c == (long)'\\') {
      output_char('\\');
    }
    output_char(c);
  } else {
    output_char((long)'\\');
    if (c < 10) {
      output_char((long)'0');
    }
    output_q(c);
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<output_readable_char>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  cmp    $0x20,%rdi
  jle    L12
  cmp    $0x5c,%rdi
  je     L8
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <output_char@plt>
  nopl   (%rax)
L12:
  mov    $0x5c,%edi
  call   <output_char@plt>
  cmp    $0x9,%rbp
  jle    L20
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <output_q@plt>
  nopl   0x0(%rax)
L8:
  mov    $0x5c,%edi
  call   <output_char@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <output_char@plt>
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0x30,%edi
  call   <output_char@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <output_q@plt>
```

assistant: ```c
void output_readable_char(long c) {
  if (c > 32) {
    if (c == (long)'\\') {
      output_char('\\');
    }
    output_char(c);
  } else {
    output_char((long)'\\');
    if (c < 10) {
      output_char((long)'0');
    }
    output_q(c);
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x409,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L17
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(const void *vdata, int n) {
  unsigned int multiplier = 1033;
  unsigned int value = 0;
  const unsigned char *data = vdata;
  while (n--)
    value = *data++ + multiplier * value;
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  test   %esi,%esi
  je     L12
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rcx
  mov    $0x0,%eax
L3:
  add    $0x1,%rdi
  imul   $0x409,%eax,%eax
  movzbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L3
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int hash(const void *vdata, int n) {
  unsigned int multiplier = 1033;
  unsigned int value = 0;
  const unsigned char *data = vdata;
  while (n--)
    value = *data++ + multiplier * value;
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  test   %esi,%esi
  je     L15
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L11:
  imul   $0x409,%eax,%eax
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L11
  ret
  nopl   (%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash(const void *vdata, int n) {
  unsigned int multiplier = 1033;
  unsigned int value = 0;
  const unsigned char *data = vdata;
  while (n--)
    value = *data++ + multiplier * value;
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  test   %esi,%esi
  je     L8
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L14:
  imul   $0x409,%eax,%eax
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L14
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash(const void *vdata, int n) {
  unsigned int multiplier = 1033;
  unsigned int value = 0;
  const unsigned char *data = vdata;
  while (n--)
    value = *data++ + multiplier * value;
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x414(%rbp)
  mov    %rsi,-0x420(%rbp)
  mov    %rdx,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string

tool: D0: %s

tool: D15: scan:: read from pipe: %s 


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  char s[1024];
  scanf("%s", s);
  printf("scan:: read from pipe: %s \n", s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D12: %s

tool: D10: scan:: read from pipe: %s 


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  char s[1024];
  scanf("%s", s);
  printf("scan:: read from pipe: %s \n", s);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type_infered: string
name: disassemble_data
arguments: data_label: D16
type_infered: string

tool: D14: %s

tool: D16: scan:: read from pipe: %s 


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  char s[1024];
  scanf("%s", s);
  printf("scan:: read from pipe: %s \n", s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string
name: read_data
arguments: data_label: D19
datatype: string

tool: D6: %s

tool: D19: scan:: read from pipe: %s 


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  char s[1024];
  scanf("%s", s);
  printf("scan:: read from pipe: %s \n", s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L71
L94:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L64
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L92
L64:
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jne    L7
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L92
L7:
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  jne    L72
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L92
L72:
  mov    -0x10(%rbp),%eax
  cmp    $0x4,%eax
  jne    L75
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L92
L75:
  mov    -0x10(%rbp),%eax
  cmp    $0x5,%eax
  jne    L92
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L92:
  addl   $0x1,-0xc(%rbp)
L71:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L94
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: string
name: read_data
arguments: data_label: D42
data_type: string
name: read_data
arguments: data_label: D25
data_type: string
name: read_data
arguments: data_label: D32
data_type: string
name: read_data
arguments: data_label: D8
data_type: string
name: read_data
arguments: data_label: D26
data_type: string

tool: D14: %d

tool: D42: GOOD LUCK


tool: D25: BUENA SUERTE


tool: D32: BONNE CHANCE


tool: D8: BUONA FORTUNA


tool: D26: VIEL GLUECK


assistant: ```c
main() {
  int n1, n2, i;
  scanf("%d", &n1);
  scanf("%d", &n2);
  for (i = 0; i < n1; i++) {
    if (n2 == 1)
      printf("GOOD LUCK\n");
    else if (n2 == 2)
      printf("BUENA SUERTE\n");
    else if (n2 == 3)
      printf("BONNE CHANCE\n");
    else if (n2 == 4)
      printf("BUONA FORTUNA\n");
    else if (n2 == 5)
      printf("VIEL GLUECK\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D52(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L104
  mov    $0x0,%ebx
  lea    D6(%rip),%r14
  lea    D32(%rip),%r13
  lea    D57(%rip),%r12
  lea    D14(%rip),%rbp
  jmp    L87
L108:
  lea    D26(%rip),%rdi
  call   <printf@plt>
L102:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jle    L104
L87:
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L108
  cmp    $0x2,%eax
  je     L126
  cmp    $0x3,%eax
  je     L14
  cmp    $0x4,%eax
  je     L41
  cmp    $0x5,%eax
  jne    L102
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L102
L126:
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L102
L14:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L102
L41:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L102
L104:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D52
data_type: string
name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D32
data_type: string
name: read_data
arguments: label: D57
data_type: string
name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D26
data_type: string

tool: D52: %d

tool: D6: VIEL GLUECK


tool: D32: BUONA FORTUNA


tool: D57: BONNE CHANCE


tool: D14: BUENA SUERTE


tool: D26: GOOD LUCK


assistant: ```c
main() {
  int n1, n2, i;
  scanf("%d", &n1);
  scanf("%d", &n2);
  for (i = 0; i < n1; i++) {
    if (n2 == 1)
      printf("GOOD LUCK\n");
    else if (n2 == 2)
      printf("BUENA SUERTE\n");
    else if (n2 == 3)
      printf("BONNE CHANCE\n");
    else if (n2 == 4)
      printf("BUONA FORTUNA\n");
    else if (n2 == 5)
      printf("VIEL GLUECK\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L46
  xor    %ebx,%ebx
  lea    D34(%rip),%r14
  lea    D42(%rip),%r13
  lea    D49(%rip),%r12
  lea    D30(%rip),%rbp
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L88:
  cmp    $0x2,%eax
  je     L25
  cmp    $0x3,%eax
  je     L49
  cmp    $0x4,%eax
  je     L86
  cmp    $0x5,%eax
  je     L22
L23:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jle    L46
L45:
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jne    L88
  lea    D29(%rip),%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jg     L45
  nopl   0x0(%rax)
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L25:
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L86:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L23
L22:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L23
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D42
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D49
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D30
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D29
type_guessed: string

tool: D7: %d

tool: D34: VIEL GLUECK


tool: D42: BUONA FORTUNA


tool: D49: BONNE CHANCE


tool: D30: BUENA SUERTE


tool: D29: GOOD LUCK


assistant: ```c
main() {
  int n1, n2, i;
  scanf("%d", &n1);
  scanf("%d", &n2);
  for (i = 0; i < n1; i++) {
    if (n2 == 1)
      printf("GOOD LUCK\n");
    else if (n2 == 2)
      printf("BUENA SUERTE\n");
    else if (n2 == 3)
      printf("BONNE CHANCE\n");
    else if (n2 == 4)
      printf("BUONA FORTUNA\n");
    else if (n2 == 5)
      printf("VIEL GLUECK\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D45(%rip),%r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  lea    D37(%rip),%r12
  push   %rbp
  lea    D53(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rbp
  call   <scanf@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jg     L14
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L75:
  cmp    $0x2,%eax
  je     L31
  cmp    $0x3,%eax
  je     L122
  cmp    $0x4,%eax
  je     L38
  cmp    $0x5,%eax
  je     L49
L69:
  add    $0x1,%ebx
  cmp    %edx,%ebx
  jge    L1
L14:
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jne    L75
  lea    D23(%rip),%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    (%rsp),%edx
  cmp    %edx,%ebx
  jl     L14
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L31:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%edx
  jmp    L69
  nopl   (%rax)
L122:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    (%rsp),%edx
  jmp    L69
  nopl   (%rax)
L38:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    (%rsp),%edx
  jmp    L69
L49:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    (%rsp),%edx
  jmp    L69
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D45
type_infered: string
name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D53
type_infered: string
name: read_data
arguments: data_label: D16
type_infered: string
name: read_data
arguments: data_label: D23
type_infered: string

tool: D45: VIEL GLUECK


tool: D21: BUONA FORTUNA


tool: D37: BONNE CHANCE


tool: D53: %d

tool: D16: BUENA SUERTE


tool: D23: GOOD LUCK


assistant: ```c
main() {
  int n1, n2, i;
  scanf("%d", &n1);
  scanf("%d", &n2);
  for (i = 0; i < n1; i++) {
    if (n2 == 1)
      printf("GOOD LUCK\n");
    else if (n2 == 2)
      printf("BUENA SUERTE\n");
    else if (n2 == 3)
      printf("BONNE CHANCE\n");
    else if (n2 == 4)
      printf("BUONA FORTUNA\n");
    else if (n2 == 5)
      printf("VIEL GLUECK\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2025736f6863616e,%rax
  mov    %rax,-0x59(%rbp)
  movb   $0x0,-0x51(%rbp)
L3:
  lea    -0x59(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <readline@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <runline@plt>
  jmp    L3
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: %s

assistant: ```c
int main(int argc, char *argv[]) {
  char prompt[] = "nachos% ";
  char buffer[64];
  while (1) {
    printf("%s", prompt);
    readline(buffer, 64);
    runline(buffer);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movabs $0x2025736f6863616e,%rax
  mov    %rax,0x7(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    D7(%rip),%rbp
L1:
  lea    0x7(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <readline@plt>
  mov    %rbx,%rdi
  call   <runline@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: %s

assistant: ```c
int main(int argc, char *argv[]) {
  char prompt[] = "nachos% ";
  char buffer[64];
  while (1) {
    printf("%s", prompt);
    readline(buffer, 64);
    runline(buffer);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x2025736f6863616e,%rax
  movb   $0x0,0xf(%rsp)
  lea    0x7(%rsp),%r12
  lea    0x10(%rsp),%rbx
  mov    %rax,0x7(%rsp)
  nop
L8:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    $0x40,%esi
  call   <readline@plt>
  mov    %rbx,%rdi
  call   <runline@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string

tool: D7: %s

assistant: ```c
int main(int argc, char *argv[]) {
  char prompt[] = "nachos% ";
  char buffer[64];
  while (1) {
    printf("%s", prompt);
    readline(buffer, 64);
    runline(buffer);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x2025736f6863616e,%rax
  movb   $0x0,0xf(%rsp)
  lea    0x7(%rsp),%r12
  lea    0x10(%rsp),%rbx
  mov    %rax,0x7(%rsp)
  nop
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    $0x40,%esi
  call   <readline@plt>
  mov    %rbx,%rdi
  call   <runline@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D6: %s

assistant: ```c
int main(int argc, char *argv[]) {
  char prompt[] = "nachos% ";
  char buffer[64];
  while (1) {
    printf("%s", prompt);
    readline(buffer, 64);
    runline(buffer);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xf,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movl   $0x1,-0x90(%rbp)
  movl   $0x1,-0x98(%rbp)
  jmp    L103
L88:
  mov    -0x98(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x98(%rbp),%eax
  cltq
  mov    %edx,-0x90(%rbp,%rax,4)
  addl   $0x1,-0x98(%rbp)
L103:
  cmpl   $0x1e,-0x98(%rbp)
  jle    L88
  lea    -0xa8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L31
L99:
  lea    -0x9c(%rbp),%rcx
  lea    -0xa0(%rbp),%rdx
  lea    -0xa4(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xa0(%rbp),%eax
  mov    %eax,%edi
  call   <ones@plt>
  mov    %eax,-0xa0(%rbp)
  mov    -0x9c(%rbp),%eax
  mov    %eax,%edi
  call   <ones@plt>
  mov    %eax,-0x9c(%rbp)
  movl   $0x0,-0x94(%rbp)
  mov    -0xa0(%rbp),%edx
  mov    -0x9c(%rbp),%eax
  add    %eax,%edx
  mov    -0xa4(%rbp),%eax
  cmp    %eax,%edx
  jg     L16
  mov    -0xa4(%rbp),%eax
  mov    %eax,-0x98(%rbp)
  jmp    L15
L43:
  mov    -0x98(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  xor    %eax,-0x94(%rbp)
  subl   $0x1,-0x98(%rbp)
L15:
  mov    -0xa0(%rbp),%edx
  mov    -0x98(%rbp),%eax
  add    %eax,%edx
  mov    -0x9c(%rbp),%eax
  add    %eax,%edx
  mov    -0xa4(%rbp),%eax
  cmp    %eax,%edx
  jg     L43
  jmp    L32
L16:
  mov    -0xa4(%rbp),%eax
  mov    %eax,-0x98(%rbp)
  jmp    L14
L8:
  mov    -0x98(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  xor    %eax,-0x94(%rbp)
  subl   $0x1,-0x98(%rbp)
L14:
  mov    -0xa4(%rbp),%edx
  mov    -0x98(%rbp),%eax
  add    %eax,%edx
  mov    -0xa0(%rbp),%ecx
  mov    -0x9c(%rbp),%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  jg     L8
L32:
  mov    -0x94(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  mov    -0xa8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xa8(%rbp)
  test   %eax,%eax
  jne    L99
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string
name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string

tool: D7: %d

tool: D9: %d%d%d

tool: D23: %d


assistant: ```c
int main() {
  int t, n, a, b, p[31] = {1}, i, x;
  for (i = 1; i < 31; ++i)
    p[i] = p[i - 1] << 1;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &n, &a, &b);
    a = ones(a);
    b = ones(b);
    x = 0;
    if (a + b <= n)
      for (i = n; i + a + b > n; --i)
        x ^= p[i - 1];
    else
      for (i = n; i + n > a + b; --i)
        x ^= p[i - 1];
    printf("%d\n", x);
  }
  return 0;
}
```