ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L16
  cmp    $0x10000000,%edi
  ja     L16
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    $0x11c,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/tctyp.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/tctyp.c", 284));
  return word_ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x61000(%rsp),%r11
L85:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L85
  sub    $0xaa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L6
L99:
  movl   $0x0,-0x61a94(%rbp)
  mov    -0x61aa0(%rbp),%eax
  test   %eax,%eax
  je     L33
  mov    -0x61aa0(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x61a90(%rbp)
  movl   $0x1,-0x61a9c(%rbp)
  jmp    L49
L48:
  mov    -0x61aa0(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x61aa0(%rbp)
  mov    -0x61aa0(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x61a9c(%rbp),%eax
  cltq
  mov    %edx,-0x61a90(%rbp,%rax,4)
  addl   $0x1,-0x61a9c(%rbp)
L49:
  mov    -0x61aa0(%rbp),%eax
  cmp    $0x1,%eax
  jg     L48
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x61a9c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x61a98(%rbp)
  jmp    L72
L25:
  mov    -0x61a98(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L78
  addl   $0x1,-0x61a94(%rbp)
L78:
  mov    -0x61a98(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x61a98(%rbp)
L72:
  cmpl   $0x0,-0x61a98(%rbp)
  jns    L25
  mov    -0x61a94(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  lea    -0x61aa0(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L99
  jmp    L22
L33:
  nop
L22:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L109
  call   <__stack_chk_fail@plt>
L109:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D27
data_type: string
name: disassemble_data
arguments: label: D1
data_type: string
name: disassemble_data
arguments: label: D34
data_type: string

tool: D27: The parity of 

tool: D1: %d

tool: D34:  is %d (mod 2).


assistant: ```c
int main() {
  int bin[100000];
  int i, j, n, count;
  while (scanf("%d", &n) == 1) {
    count = 0;
    if (n == 0)
      break;
    bin[0] = n % 2;
    for (i = 1; n / 2 > 0; i++) {
      n = n / 2;
      bin[i] = n % 2;
    }
    printf("The parity of ");
    for (j = i - 1; j >= 0; j--) {
      if (bin[j] == 1)
        count++;
      printf("%d", bin[j]);
    }
    printf(" is %d (mod 2).\n", count);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L39:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L39
  sub    $0xaa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    D26(%rip),%rbp
  lea    D4(%rip),%r14
  lea    D5(%rip),%r13
  jmp    L55
L36:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x61aa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
L50:
  movslq %ebx,%rbx
  mov    $0x0,%r15d
L1:
  mov    0x10(%rsp,%rbx,4),%esi
  cmp    $0x1,%esi
  sete   %al
  movzbl %al,%eax
  add    %eax,%r15d
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L1
L95:
  mov    %r15d,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L55:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L36
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  je     L36
  mov    %ecx,%edx
  shr    $0x1f,%edx
  lea    (%rcx,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,0x10(%rsp)
  cmp    $0x1,%ecx
  jle    L25
  mov    $0x1,%esi
L65:
  mov    %esi,%ebx
  mov    %ecx,%edi
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,0x10(%rsp,%rsi,4)
  add    $0x1,%rsi
  cmp    $0x3,%edi
  jg     L65
  mov    %ecx,0xc(%rsp)
  movslq %ebx,%rdx
  mov    %eax,0x10(%rsp,%rdx,4)
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jns    L50
  mov    $0x0,%r15d
  jmp    L95
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D4
type: string
name: read_data
arguments: data_tag: D5
type: string

tool: D26: %d

tool: D4: The parity of 

tool: D5:  is %d (mod 2).


assistant: ```c
int main() {
  int bin[100000];
  int i, j, n, count;
  while (scanf("%d", &n) == 1) {
    count = 0;
    if (n == 0)
      break;
    bin[0] = n % 2;
    for (i = 1; n / 2 > 0; i++) {
      n = n / 2;
      bin[i] = n % 2;
    }
    printf("The parity of ");
    for (j = i - 1; j >= 0; j--) {
      if (bin[j] == 1)
        count++;
      printf("%d", bin[j]);
    }
    printf(" is %d (mod 2).\n", count);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L75:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L75
  sub    $0xaa8,%rsp
  lea    D19(%rip),%rbp
  lea    D15(%rip),%r14
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%r13
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L48
  nopl   (%rax)
L2:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L48
  mov    %eax,%esi
  shr    $0x1f,%esi
  lea    (%rax,%rsi,1),%edx
  and    $0x1,%edx
  sub    %esi,%edx
  mov    %edx,0x10(%rsp)
  cmp    $0x1,%eax
  jle    L70
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L74:
  sar    %eax
  movslq %edx,%rbx
  mov    %eax,%esi
  and    $0x1,%esi
  mov    %esi,0x0(%r13,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x1,%eax
  jne    L74
  movl   $0x1,0xc(%rsp)
L7:
  mov    %r14,%rdi
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <printf@plt>
  nopl   (%rax)
L8:
  mov    0x0(%r13,%rbx,4),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  cmp    $0x1,%esi
  sete   %al
  sub    $0x1,%rbx
  add    %eax,%r15d
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xffffffff,%ebx
  jne    L8
  mov    %r15d,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L2
L48:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x61aa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L70:
  xor    %ebx,%ebx
  jmp    L7
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D21
type_infered: string

tool: D19: %d

tool: D15: The parity of 

tool: D21:  is %d (mod 2).


assistant: ```c
int main() {
  int bin[100000];
  int i, j, n, count;
  while (scanf("%d", &n) == 1) {
    count = 0;
    if (n == 0)
      break;
    bin[0] = n % 2;
    for (i = 1; n / 2 > 0; i++) {
      n = n / 2;
      bin[i] = n % 2;
    }
    printf("The parity of ");
    for (j = i - 1; j >= 0; j--) {
      if (bin[j] == 1)
        count++;
      printf("%d", bin[j]);
    }
    printf(" is %d (mod 2).\n", count);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0xaa8,%rsp
  lea    D22(%rip),%rbp
  lea    D15(%rip),%r14
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%r13
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L42
  nopl   (%rax)
L38:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L42
  mov    %eax,%esi
  shr    $0x1f,%esi
  lea    (%rax,%rsi,1),%edx
  and    $0x1,%edx
  sub    %esi,%edx
  mov    %edx,0x10(%rsp)
  cmp    $0x1,%eax
  jle    L88
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L8:
  sar    %eax
  movslq %edx,%rbx
  mov    %eax,%esi
  and    $0x1,%esi
  mov    %esi,0x0(%r13,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x1,%eax
  jne    L8
  movl   $0x1,0xc(%rsp)
L70:
  mov    %r14,%rdi
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <printf@plt>
  nopl   (%rax)
L45:
  mov    0x0(%r13,%rbx,4),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  cmp    $0x1,%esi
  sete   %al
  sub    $0x1,%rbx
  add    %eax,%r15d
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xffffffff,%ebx
  jne    L45
  mov    %r15d,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L38
L42:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x61aa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L88:
  xor    %ebx,%ebx
  jmp    L70
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D22: %d

tool: D15: The parity of 

tool: D12:  is %d (mod 2).


assistant: ```c
int main() {
  int bin[100000];
  int i, j, n, count;
  while (scanf("%d", &n) == 1) {
    count = 0;
    if (n == 0)
      break;
    bin[0] = n % 2;
    for (i = 1; n / 2 > 0; i++) {
      n = n / 2;
      bin[i] = n % 2;
    }
    printf("The parity of ");
    for (j = i - 1; j >= 0; j--) {
      if (bin[j] == 1)
        count++;
      printf("%d", bin[j]);
    }
    printf(" is %d (mod 2).\n", count);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<autohelperowl_attackpat49>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jle    L8
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%esi
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  sub    $0x8,%rsp
  mov    -0x20(%rbp),%ecx
  push   %rcx
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %edx,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <play_attack_defend_n@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  jne    L8
  mov    $0x1,%eax
  jmp    L1
L8:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat49(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  b = offset(1, 0, move, transformation);
  return owl_escape_value(a) > 0 && !play_attack_defend_n(color, 1, 3, move, a, b, move);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<autohelperowl_attackpat49>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %esi,%ecx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%r12d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%ebp
  mov    %r12d,%edi
  call   <owl_escape_value@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jg     L15
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  sub    $0x8,%rsp
  push   %rbx
  mov    %ebp,%r9d
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r13d,%edi
  call   <play_attack_defend_n@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L0
```

assistant: ```c
int autohelperowl_attackpat49(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  b = offset(1, 0, move, transformation);
  return owl_escape_value(a) > 0 && !play_attack_defend_n(color, 1, 3, move, a, b, move);
}
```
user: What is the c source code of the assembly code below:

```asm
<autohelperowl_attackpat49>:
  endbr64
  push   %r13
  xor    %edi,%edi
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %ebx,%edi
  mov    %eax,%r13d
  call   <owl_escape_value@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jle    L9
  sub    $0x8,%rsp
  mov    %r12d,%ecx
  mov    $0x3,%edx
  mov    %r13d,%r9d
  push   %r12
  mov    %ebx,%r8d
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <play_attack_defend_n@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int autohelperowl_attackpat49(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  b = offset(1, 0, move, transformation);
  return owl_escape_value(a) > 0 && !play_attack_defend_n(color, 1, 3, move, a, b, move);
}
```
user: What is the c source code of the assembly code below:

```asm
<autohelperowl_attackpat49>:
  endbr64
  push   %r13
  xor    %edi,%edi
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %ebx,%edi
  mov    %eax,%r13d
  call   <owl_escape_value@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jle    L6
  sub    $0x8,%rsp
  mov    %r12d,%ecx
  mov    $0x3,%edx
  mov    %r13d,%r9d
  push   %r12
  mov    %ebx,%r8d
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <play_attack_defend_n@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int autohelperowl_attackpat49(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  b = offset(1, 0, move, transformation);
  return owl_escape_value(a) > 0 && !play_attack_defend_n(color, 1, 3, move, a, b, move);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D24(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D17(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  D6(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D24
type_infered: byte[4]
name: read_data
arguments: label: D17
type_infered: byte[4]
name: read_data
arguments: label: D6
type_infered: f32
name: read_data
arguments: label: D37
type_infered: string

tool: {"D24": [0x00,0x00,0xa0,0x40]}

tool: {"D17": [0x00,0x00,0x90,0xc0]}

tool: D6: 11.25

tool: D37: v1 = %1.1f, v2 = %2.1f, v3 = %2.2f

assistant: ```c
main() {
  float v1;
  float v2;
  float v3;
  v1 = 5;
  v2 = -4.5;
  v3 = 11.25;
  printf("v1 = %1.1f, v2 = %2.1f, v3 = %2.2f", v1, v2, v3);
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D4(%rip),%xmm2
  movss  D29(%rip),%xmm1
  movss  D25(%rip),%xmm0
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: f32
name: extract_symbolic_data
arguments: tag: D29
type: byte[4]
name: extract_symbolic_data
arguments: tag: D25
type: byte[4]
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D4: 11.25

tool: {"D29": [0x00,0x00,0x90,0xc0]}

tool: {"D25": [0x00,0x00,0xa0,0x40]}

tool: D5: v1 = %1.1f, v2 = %2.1f, v3 = %2.2f

assistant: ```c
main() {
  float v1;
  float v2;
  float v3;
  v1 = 5;
  v2 = -4.5;
  v3 = 11.25;
  printf("v1 = %1.1f, v2 = %2.1f, v3 = %2.2f", v1, v2, v3);
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D37(%rip),%xmm2
  movss  D3(%rip),%xmm1
  lea    D38(%rip),%rdi
  movss  D12(%rip),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D37
type_infered: f32
name: parse_data
arguments: label: D3
type_infered: byte[4]
name: parse_data
arguments: label: D38
type_infered: string
name: parse_data
arguments: label: D12
type_infered: byte[4]

tool: D37: 11.25

tool: {"D3": [0x00,0x00,0x90,0xc0]}

tool: D38: v1 = %1.1f, v2 = %2.1f, v3 = %2.2f

tool: {"D12": [0x00,0x00,0xa0,0x40]}

assistant: ```c
main() {
  float v1;
  float v2;
  float v3;
  v1 = 5;
  v2 = -4.5;
  v3 = 11.25;
  printf("v1 = %1.1f, v2 = %2.1f, v3 = %2.2f", v1, v2, v3);
  getchar();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D6(%rip),%xmm2
  movss  D25(%rip),%xmm1
  lea    D34(%rip),%rdi
  movss  D35(%rip),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: f32
name: disassemble_data
arguments: label: D25
data_type: byte[4]
name: disassemble_data
arguments: label: D34
data_type: string
name: disassemble_data
arguments: label: D35
data_type: byte[4]

tool: D6: 11.25

tool: {"D25": [0x00,0x00,0x90,0xc0]}

tool: D34: v1 = %1.1f, v2 = %2.1f, v3 = %2.2f

tool: {"D35": [0x00,0x00,0xa0,0x40]}

assistant: ```c
main() {
  float v1;
  float v2;
  float v3;
  v1 = 5;
  v2 = -4.5;
  v3 = 11.25;
  printf("v1 = %1.1f, v2 = %2.1f, v3 = %2.2f", v1, v2, v3);
  getchar();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x17(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%rdx
  lea    -0x17(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <digits@plt>
  test   %rax,%rax
  je     L9
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
datatype: string
name: parse_data
arguments: data_tag: D11
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string

tool: D23: %s

tool: D11: %ld

tool: D28: -1

assistant: ```c
int main() {
  char numbers[15];
  long answer;
  scanf("%s", numbers);
  scanf("%ld", &answer);
  if (digits(numbers, answer))
    printf("-1");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  call   <digits@plt>
  test   %rax,%rax
  jne    L7
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D20
type: string
name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D18
type: string

tool: D20: %s

tool: D6: %ld

tool: D18: -1

assistant: ```c
int main() {
  char numbers[15];
  long answer;
  scanf("%s", numbers);
  scanf("%ld", &answer);
  if (digits(numbers, answer))
    printf("-1");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <digits@plt>
  test   %rax,%rax
  jne    L19
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L19:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D23: %s

tool: D14: %ld

tool: D6: -1

assistant: ```c
int main() {
  char numbers[15];
  long answer;
  scanf("%s", numbers);
  scanf("%ld", &answer);
  if (digits(numbers, answer))
    printf("-1");
  return 0;
}
```