ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<done>:
  endbr64
  push   %r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x3,%ebx
  call   <strrchr@plt>
  test   %rax,%rax
  lea    0x1(%rax),%r12
  cmove  %rbp,%r12
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <setuid@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <close@plt>
  cmp    $0xf,%ebx
  jne    L3
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <execl@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10f0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: No shell!


assistant: ```c
void done(const char *shell) {
  register int i;
  const char *sp = strrchr(shell, '/');
  if (sp)
    sp++;
  else
    sp = shell;
  setuid(getuid());
  for (i = 3; i < 15; i++)
    close(i);
  execl(shell, sp, 0);
  printf("No shell!\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <Exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: Usage: MTE filename rules codesize minsize maxsize number total output

filename ... text file to analyze
rules ...... rules table file
codesize ... MTE code size
minsize .... minimum MTE string length
maxsize .... maximum MTE string length
number ..... minimum number of occurrences
control .... add the MTE size in the operations (0/1)
total ...... number of MTE to search
output ..... output file name


assistant: ```c
void Usage(void) {
  Exit("Usage: MTE filename rules codesize minsize maxsize number total output\n"
       "\n"
       "filename ... text file to analyze\n"
       "rules ...... rules table file\n"
       "codesize ... MTE code size\n"
       "minsize .... minimum MTE string length\n"
       "maxsize .... maximum MTE string length\n"
       "number ..... minimum number of occurrences\n"
       "control .... add the MTE size in the operations (0/1)\n"
       "total ...... number of MTE to search\n"
       "output ..... output file name\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <Exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: Usage: MTE filename rules codesize minsize maxsize number total output

filename ... text file to analyze
rules ...... rules table file
codesize ... MTE code size
minsize .... minimum MTE string length
maxsize .... maximum MTE string length
number ..... minimum number of occurrences
control .... add the MTE size in the operations (0/1)
total ...... number of MTE to search
output ..... output file name


assistant: ```c
void Usage(void) {
  Exit("Usage: MTE filename rules codesize minsize maxsize number total output\n"
       "\n"
       "filename ... text file to analyze\n"
       "rules ...... rules table file\n"
       "codesize ... MTE code size\n"
       "minsize .... minimum MTE string length\n"
       "maxsize .... maximum MTE string length\n"
       "number ..... minimum number of occurrences\n"
       "control .... add the MTE size in the operations (0/1)\n"
       "total ...... number of MTE to search\n"
       "output ..... output file name\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Usage>:
  endbr64
  lea    D1(%rip),%rdi
  jmp    1050 <Exit@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: Usage: MTE filename rules codesize minsize maxsize number total output

filename ... text file to analyze
rules ...... rules table file
codesize ... MTE code size
minsize .... minimum MTE string length
maxsize .... maximum MTE string length
number ..... minimum number of occurrences
control .... add the MTE size in the operations (0/1)
total ...... number of MTE to search
output ..... output file name


assistant: ```c
void Usage(void) {
  Exit("Usage: MTE filename rules codesize minsize maxsize number total output\n"
       "\n"
       "filename ... text file to analyze\n"
       "rules ...... rules table file\n"
       "codesize ... MTE code size\n"
       "minsize .... minimum MTE string length\n"
       "maxsize .... maximum MTE string length\n"
       "number ..... minimum number of occurrences\n"
       "control .... add the MTE size in the operations (0/1)\n"
       "total ...... number of MTE to search\n"
       "output ..... output file name\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<Usage>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <Exit@plt>
```

tool_calls: name: read_data
arguments: label: D9
datatype: string

tool: D9: Usage: MTE filename rules codesize minsize maxsize number total output

filename ... text file to analyze
rules ...... rules table file
codesize ... MTE code size
minsize .... minimum MTE string length
maxsize .... maximum MTE string length
number ..... minimum number of occurrences
control .... add the MTE size in the operations (0/1)
total ...... number of MTE to search
output ..... output file name


assistant: ```c
void Usage(void) {
  Exit("Usage: MTE filename rules codesize minsize maxsize number total output\n"
       "\n"
       "filename ... text file to analyze\n"
       "rules ...... rules table file\n"
       "codesize ... MTE code size\n"
       "minsize .... minimum MTE string length\n"
       "maxsize .... maximum MTE string length\n"
       "number ..... minimum number of occurrences\n"
       "control .... add the MTE size in the operations (0/1)\n"
       "total ...... number of MTE to search\n"
       "output ..... output file name\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<numberOfStrings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L2
L8:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L8
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long numberOfStrings(const int alphLength, const int stringMinLength, const int stringMaxLength) {
  unsigned long res = 0;
  int i;
  for (i = stringMinLength; i <= stringMaxLength; i++) {
    res += pow(alphLength, i);
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<numberOfStrings>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jg     L16
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0x0,%ebp
L2:
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <pow@plt>
  add    %rax,%rbp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L2
L14:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    $0x0,%ebp
  jmp    L14
```

assistant: ```c
unsigned long numberOfStrings(const int alphLength, const int stringMinLength, const int stringMaxLength) {
  unsigned long res = 0;
  int i;
  for (i = stringMinLength; i <= stringMaxLength; i++) {
    res += pow(alphLength, i);
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<numberOfStrings>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jg     L7
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    %edx,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L19:
  mov    %ebx,%esi
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <pow@plt>
  add    %rax,%r12
  cmp    %ebx,%ebp
  jge    L19
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long numberOfStrings(const int alphLength, const int stringMinLength, const int stringMaxLength) {
  unsigned long res = 0;
  int i;
  for (i = stringMinLength; i <= stringMaxLength; i++) {
    res += pow(alphLength, i);
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<numberOfStrings>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jg     L11
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    %edx,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L5:
  mov    %ebx,%esi
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <pow@plt>
  add    %rax,%r12
  cmp    %ebx,%ebp
  jge    L5
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long numberOfStrings(const int alphLength, const int stringMinLength, const int stringMaxLength) {
  unsigned long res = 0;
  int i;
  for (i = stringMinLength; i <= stringMaxLength; i++) {
    res += pow(alphLength, i);
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x3(%rax),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D49
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string
name: retrieve_data
arguments: data_tag: D43
datatype: string
name: retrieve_data
arguments: data_tag: D46
datatype: string
name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D23
datatype: string

tool: D49: What's your first name?

tool: D14: %s

tool: D43: "%s"


tool: D46: "%20s"


tool: D12: "%-20s"


tool: D23: "%*s"


assistant: ```c
int main() {
  char name[40];
  printf("What's your first name?\n");
  scanf("%s", name);
  printf("\"%s\"\n", name);
  printf("\"%20s\"\n", name);
  printf("\"%-20s\"\n", name);
  printf("\"%*s\"\n", strlen(name) + 3, name);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x3(%rax),%rsi
  mov    %rbx,%rdx
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
datatype: string
name: extract_symbolic_data
arguments: data_tag: D56
datatype: string
name: extract_symbolic_data
arguments: data_tag: D17
datatype: string
name: extract_symbolic_data
arguments: data_tag: D25
datatype: string
name: extract_symbolic_data
arguments: data_tag: D53
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D26: What's your first name?

tool: D56: %s

tool: D17: "%s"


tool: D25: "%20s"


tool: D53: "%-20s"


tool: D8: "%*s"


assistant: ```c
int main() {
  char name[40];
  printf("What's your first name?\n");
  scanf("%s", name);
  printf("\"%s\"\n", name);
  printf("\"%20s\"\n", name);
  printf("\"%-20s\"\n", name);
  printf("\"%*s\"\n", strlen(name) + 3, name);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  lea    D45(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <puts@plt>
  mov    %r12,%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  lea    D25(%rip),%rdi
  lea    0x3(%rax),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D45
type_guessed: string
name: unpack_data
arguments: tag: D56
type_guessed: string
name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D44
type_guessed: string
name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D25
type_guessed: string

tool: D45: What's your first name?

tool: D56: %s

tool: D26: "%s"


tool: D44: "%20s"


tool: D30: "%-20s"


tool: D25: "%*s"


assistant: ```c
int main() {
  char name[40];
  printf("What's your first name?\n");
  scanf("%s", name);
  printf("\"%s\"\n", name);
  printf("\"%20s\"\n", name);
  printf("\"%-20s\"\n", name);
  printf("\"%*s\"\n", strlen(name) + 3, name);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D34(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <puts@plt>
  mov    %r12,%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  lea    D50(%rip),%rdi
  lea    0x3(%rax),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D34
type_guessed: string
name: retrieve_data
arguments: data_label: D29
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string
name: retrieve_data
arguments: data_label: D57
type_guessed: string
name: retrieve_data
arguments: data_label: D58
type_guessed: string
name: retrieve_data
arguments: data_label: D50
type_guessed: string

tool: D34: What's your first name?

tool: D29: %s

tool: D3: "%s"


tool: D57: "%20s"


tool: D58: "%-20s"


tool: D50: "%*s"


assistant: ```c
int main() {
  char name[40];
  printf("What's your first name?\n");
  scanf("%s", name);
  printf("\"%s\"\n", name);
  printf("\"%20s\"\n", name);
  printf("\"%-20s\"\n", name);
  printf("\"%*s\"\n", strlen(name) + 3, name);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_div_df_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %rdi,-0x28(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <__builtin_vsx_xstdivdp_fe@plt>
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rbx
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <__builtin_vsx_xstdivdp_fg@plt>
  mov    %eax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void test_div_df_1(double a, double b, int *p) {
  p[0] = __builtin_vsx_xstdivdp_fe(a, b);
  p[1] = __builtin_vsx_xstdivdp_fg(a, b);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_div_df_1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%rbp
  movq   %xmm1,%r12
  mov    %rdi,%rbx
  call   <__builtin_vsx_xstdivdp_fe@plt>
  mov    %eax,(%rbx)
  movq   %r12,%xmm1
  movq   %rbp,%xmm0
  call   <__builtin_vsx_xstdivdp_fg@plt>
  mov    %eax,0x4(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test_div_df_1(double a, double b, int *p) {
  p[0] = __builtin_vsx_xstdivdp_fe(a, b);
  p[1] = __builtin_vsx_xstdivdp_fg(a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_div_df_1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <__builtin_vsx_xstdivdp_fe@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    %eax,(%rbx)
  call   <__builtin_vsx_xstdivdp_fg@plt>
  mov    %eax,0x4(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void test_div_df_1(double a, double b, int *p) {
  p[0] = __builtin_vsx_xstdivdp_fe(a, b);
  p[1] = __builtin_vsx_xstdivdp_fg(a, b);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_div_df_1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <__builtin_vsx_xstdivdp_fe@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    %eax,(%rbx)
  call   <__builtin_vsx_xstdivdp_fg@plt>
  mov    %eax,0x4(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void test_div_df_1(double a, double b, int *p) {
  p[0] = __builtin_vsx_xstdivdp_fe(a, b);
  p[1] = __builtin_vsx_xstdivdp_fg(a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<asciicat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  addq   $0x2,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L81
L10:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  cmpb   $0x39,-0xc(%rbp)
  jle    L83
  movsbl -0xc(%rbp),%eax
  sub    $0x37,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  jmp    L40
L83:
  movsbl -0xc(%rbp),%eax
  sub    $0x30,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
L40:
  cmpb   $0x39,-0xb(%rbp)
  jle    L0
  movzbl -0xb(%rbp),%eax
  sub    $0x37,%eax
  jmp    L91
L0:
  movzbl -0xb(%rbp),%eax
  sub    $0x30,%eax
L91:
  or     %edx,%eax
  mov    %al,-0xa(%rbp)
  movzbl -0xa(%rbp),%eax
  cmp    $0x1f,%al
  jle    L80
  movzbl -0xa(%rbp),%eax
  cmp    $0x7f,%al
  je     L80
  lea    -0xa(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L81
L80:
  mov    -0x18(%rbp),%rax
  lea    D26(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L81:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x18(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L72
  call   <__stack_chk_fail@plt>
L72:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D14
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string

tool: D14: "

tool: D26: .

assistant: ```c
void asciicat(char *pcBuffer, char *pcString) {
  char x[2];
  char cHighNibble, cLowNibble;
  x[0] = 0;
  x[1] = 0;
  pcString += 2;
  strcat(pcBuffer, "\"");
  while (*pcString != 0) {
    cHighNibble = *pcString++;
    cLowNibble = *pcString++;
    *x = (((cHighNibble) > '9') ? ((cHighNibble) - 'A' + 10) : ((cHighNibble) - '0')) << 4 | (((cLowNibble) > '9') ? ((cLowNibble) - 'A' + 10) : ((cLowNibble) - '0'));
    if (((*x) >= ' ') && ((*x) <= '~'))
      strcat(pcBuffer, x);
    else
      strcat(pcBuffer, ".");
  }
  strcat(pcBuffer, "\"");
}
```
user: What is the c source code of the assembly code below?

```asm
<asciicat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x2(%rsi),%rbx
  lea    D27(%rip),%rsi
  call   <strcat@plt>
  movzbl 0x2(%r12),%edx
  test   %dl,%dl
  je     L57
  lea    D8(%rip),%r12
  jmp    L1
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L29:
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L57
L1:
  add    $0x2,%rbx
  movzbl -0x1(%rbx),%ecx
  mov    %edx,%esi
  shl    $0x4,%esi
  sub    $0x70,%esi
  mov    %edx,%eax
  shl    $0x4,%eax
  cmp    $0x3a,%dl
  cmovge %esi,%eax
  lea    -0x37(%rcx),%esi
  lea    -0x30(%rcx),%edx
  cmp    $0x3a,%cl
  cmovge %esi,%edx
  or     %edx,%eax
  mov    %al,0x6(%rsp)
  sub    $0x20,%eax
  cmp    $0x5e,%al
  ja     L2
  lea    0x6(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L29
L57:
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D27
type: string
name: parse_data
arguments: tag: D8
type: string

tool: D27: "

tool: D8: .

assistant: ```c
void asciicat(char *pcBuffer, char *pcString) {
  char x[2];
  char cHighNibble, cLowNibble;
  x[0] = 0;
  x[1] = 0;
  pcString += 2;
  strcat(pcBuffer, "\"");
  while (*pcString != 0) {
    cHighNibble = *pcString++;
    cLowNibble = *pcString++;
    *x = (((cHighNibble) > '9') ? ((cHighNibble) - 'A' + 10) : ((cHighNibble) - '0')) << 4 | (((cLowNibble) > '9') ? ((cLowNibble) - 'A' + 10) : ((cLowNibble) - '0'));
    if (((*x) >= ' ') && ((*x) <= '~'))
      strcat(pcBuffer, x);
    else
      strcat(pcBuffer, ".");
  }
  strcat(pcBuffer, "\"");
}
```