ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<shiftleft>:
  endbr64
  movsbl 0x13(%rdi),%edx
  mov    %rdi,%r10
  mov    %esi,%r9d
  lea    (%rdx,%rdx,1),%eax
  test   %esi,%esi
  jne    L40
  mov    %al,0x13(%rdi)
  test   %dl,%dl
  jns    L45
L6:
  add    $0x1,%r9d
  mov    $0x13,%eax
  sub    %r9d,%eax
  cltq
  movb   $0x1,(%r10,%rax,1)
L45:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %al,0x13(%rdi)
  mov    $0x13,%eax
  shr    $0x1f,%edx
  sub    %esi,%eax
  cmp    $0x12,%eax
  jg     L6
  lea    0x11(%rdi),%r8
  lea    -0x1(%rsi),%ecx
  lea    0x12(%rdi),%rax
  sub    %rcx,%r8
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl (%rax),%esi
  mov    %edx,%edi
  sub    $0x1,%rax
  lea    (%rsi,%rsi,1),%ecx
  movsbl %sil,%edx
  or     %edi,%ecx
  shr    $0x1f,%edx
  mov    %cl,0x1(%rax)
  cmp    %rax,%r8
  jne    L18
  test   %sil,%sil
  js     L6
  mov    %r9d,%eax
  ret
```

assistant: ```c
int shiftleft(unsigned char *a, int a_len) {
  int i, j, front, lastfront;
  if ((a_len == 0) && ((a[20 - 1] & 0x80) != 0x80)) {
    a[20 - 1] <<= 1;
    return 0;
  }
  if (a[20 - 1] & 0x80) {
    lastfront = 1;
    front = 1;
  } else
    lastfront = 0;
  a[20 - 1] <<= 1;
  for (i = 20 - 1 - 1; i >= 20 - 1 - a_len; i--) {
    if (a[i] & 0x80)
      front = 1;
    else
      front = 0;
    a[i] <<= 1;
    if (lastfront)
      a[i] |= 0x1;
    lastfront = front;
  }
  if (front) {
    a_len++;
    a[20 - 1 - a_len] = 1;
  }
  return a_len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<shiftleft>:
  endbr64
  movsbl 0x13(%rdi),%edx
  mov    %rdi,%r10
  mov    %esi,%r9d
  lea    (%rdx,%rdx,1),%eax
  test   %esi,%esi
  jne    L16
  mov    %al,0x13(%rdi)
  test   %dl,%dl
  jns    L22
L47:
  add    $0x1,%r9d
  mov    $0x13,%eax
  sub    %r9d,%eax
  cltq
  movb   $0x1,(%r10,%rax,1)
L22:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %al,0x13(%rdi)
  mov    $0x13,%eax
  shr    $0x1f,%edx
  sub    %esi,%eax
  cmp    $0x12,%eax
  jg     L47
  lea    0x11(%rdi),%r8
  lea    -0x1(%rsi),%ecx
  lea    0x12(%rdi),%rax
  sub    %rcx,%r8
  nopl   0x0(%rax,%rax,1)
L36:
  movzbl (%rax),%esi
  mov    %edx,%edi
  sub    $0x1,%rax
  lea    (%rsi,%rsi,1),%ecx
  movsbl %sil,%edx
  or     %edi,%ecx
  shr    $0x1f,%edx
  mov    %cl,0x1(%rax)
  cmp    %r8,%rax
  jne    L36
  test   %sil,%sil
  js     L47
  mov    %r9d,%eax
  ret
```

assistant: ```c
int shiftleft(unsigned char *a, int a_len) {
  int i, j, front, lastfront;
  if ((a_len == 0) && ((a[20 - 1] & 0x80) != 0x80)) {
    a[20 - 1] <<= 1;
    return 0;
  }
  if (a[20 - 1] & 0x80) {
    lastfront = 1;
    front = 1;
  } else
    lastfront = 0;
  a[20 - 1] <<= 1;
  for (i = 20 - 1 - 1; i >= 20 - 1 - a_len; i--) {
    if (a[i] & 0x80)
      front = 1;
    else
      front = 0;
    a[i] <<= 1;
    if (lastfront)
      a[i] |= 0x1;
    lastfront = front;
  }
  if (front) {
    a_len++;
    a[20 - 1 - a_len] = 1;
  }
  return a_len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x50(%rbp)
  movl   $0x2,-0x4c(%rbp)
  movl   $0x8,-0x48(%rbp)
  movl   $0x9,-0x44(%rbp)
  movl   $0x2,-0x40(%rbp)
  movl   $0x4,-0x3c(%rbp)
  movl   $0x9,-0x38(%rbp)
  movl   $0xc,-0x34(%rbp)
  movl   $0x4,-0x30(%rbp)
  movl   $0x7,-0x2c(%rbp)
  movl   $0xa,-0x28(%rbp)
  movl   $0xd,-0x24(%rbp)
  movl   $0x6,-0x20(%rbp)
  movl   $0x8,-0x1c(%rbp)
  movl   $0xb,-0x18(%rbp)
  movl   $0xf,-0x14(%rbp)
  lea    -0x50(%rbp),%rax
  mov    $0x5,%ecx
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <young_tableau_find@plt>
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpq   $0x0,-0x58(%rbp)
  je     L4
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L4:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D14: %p %p


tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int matrix[4][4] = {
      {
          1,
          2,
          8,
          9,
      },
      {
          2,
          4,
          9,
          12,
      },
      {
          4,
          7,
          10,
          13,
      },
      {
          6,
          8,
          11,
          15,
      },
  };
  int *value = young_tableau_find(matrix, 4, 4, 5);
  printf("%p %p\n", matrix, value);
  if (value) {
    printf("%d\n", *value);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x9,0x18(%rsp)
  movl   $0xc,0x1c(%rsp)
  movl   $0x4,0x20(%rsp)
  movl   $0x7,0x24(%rsp)
  movl   $0xa,0x28(%rsp)
  movl   $0xd,0x2c(%rsp)
  movl   $0x6,0x30(%rsp)
  movl   $0x8,0x34(%rsp)
  movl   $0xb,0x38(%rsp)
  movl   $0xf,0x3c(%rsp)
  mov    %rsp,%rbp
  mov    $0x5,%ecx
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <young_tableau_find@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %rbx,%rbx
  je     L6
  mov    (%rbx),%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string
name: parse_data
arguments: data_tag: D8
type: string

tool: D6: %p %p


tool: D8: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int matrix[4][4] = {
      {
          1,
          2,
          8,
          9,
      },
      {
          2,
          4,
          9,
          12,
      },
      {
          4,
          7,
          10,
          13,
      },
      {
          6,
          8,
          11,
          15,
      },
  };
  int *value = young_tableau_find(matrix, 4, 4, 5);
  printf("%p %p\n", matrix, value);
  if (value) {
    printf("%d\n", *value);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    $0x5,%ecx
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x900000008,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x400000002,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xc00000009,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x700000004,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xd0000000a,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x800000006,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xf0000000b,%rax
  mov    %rax,0x38(%rsp)
  call   <young_tableau_find@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  mov    %rax,%rbx
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  test   %rbx,%rbx
  je     L1
  mov    (%rbx),%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L1:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string

tool: D6: %p %p


tool: D13: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int matrix[4][4] = {
      {
          1,
          2,
          8,
          9,
      },
      {
          2,
          4,
          9,
          12,
      },
      {
          4,
          7,
          10,
          13,
      },
      {
          6,
          8,
          11,
          15,
      },
  };
  int *value = young_tableau_find(matrix, 4, 4, 5);
  printf("%p %p\n", matrix, value);
  if (value) {
    printf("%d\n", *value);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    $0x5,%ecx
  push   %rbx
  sub    $0x58,%rsp
  movdqa D57(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movdqa D21(%rip),%xmm0
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D59(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D46(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <young_tableau_find@plt>
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  mov    %rax,%rbx
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  test   %rbx,%rbx
  je     L18
  mov    (%rbx),%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D57
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D21
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D59
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D46
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D29
type_guessed: string
name: disassemble_data
arguments: data_label: D30
type_guessed: string

tool: {"D57": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D21": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: {"D59": [0x04,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

tool: {"D46": [0x06,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

tool: D29: %p %p


tool: D30: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int matrix[4][4] = {
      {
          1,
          2,
          8,
          9,
      },
      {
          2,
          4,
          9,
          12,
      },
      {
          4,
          7,
          10,
          13,
      },
      {
          6,
          8,
          11,
          15,
      },
  };
  int *value = young_tableau_find(matrix, 4, 4, 5);
  printf("%p %p\n", matrix, value);
  if (value) {
    printf("%d\n", *value);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  je     L12
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  je     L12
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L136
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jl     L12
L136:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L34
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L34
L12:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L93
L34:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  je     L15
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L109
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jl     L15
L109:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L88
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L88
L15:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L93
L88:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jge    L93
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L93
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L93:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D48
type: string
name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D22
type: string

tool: D48: Please eneter 3 numbers separated by spaces > 

tool: D16: %d%d%d

tool: D22: %d is the median


assistant: ```c
int main(void) {
  int n1, n2, n3;
  printf("Please eneter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &n1, &n2, &n3);
  if (n1 == n2 || n1 == n3 || (n2 < n1 && n1 < n3) || (n3 < n1 && n1 < n2))
    printf("%d is the median\n", n1);
  else if (n2 == n3 || (n1 < n2 && n2 < n3) || (n3 < n2 && n2 < n1))
    printf("%d is the median\n", n2);
  else if (n1 < n3 && n3 < n2)
    printf("%d is the median\n", n3);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  je     L110
  mov    0x14(%rsp),%edx
  cmp    %edx,%esi
  je     L110
  setl   %cl
  cmp    %eax,%esi
  setg   %dil
  test   %cl,%cl
  je     L56
  test   %dil,%dil
  jne    L110
L56:
  cmp    %eax,%esi
  setl   %r8b
  cmp    %edx,%esi
  jle    L34
  test   %r8b,%r8b
  jne    L110
L34:
  cmp    %edx,%eax
  je     L47
  jge    L108
  test   %r8b,%r8b
  jne    L47
L108:
  cmp    %edx,%eax
  setg   %sil
  test   %dil,%dil
  je     L90
  test   %sil,%sil
  jne    L47
L90:
  test   %cl,%cl
  je     L75
  test   %sil,%sil
  je     L75
  mov    %edx,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L75
L110:
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L75:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L47:
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L75
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D45
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D28: Please eneter 3 numbers separated by spaces > 

tool: D45: %d%d%d

tool: D3: %d is the median


assistant: ```c
int main(void) {
  int n1, n2, n3;
  printf("Please eneter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &n1, &n2, &n3);
  if (n1 == n2 || n1 == n3 || (n2 < n1 && n1 < n3) || (n3 < n1 && n1 < n2))
    printf("%d is the median\n", n1);
  else if (n2 == n3 || (n1 < n2 && n2 < n3) || (n3 < n2 && n2 < n1))
    printf("%d is the median\n", n2);
  else if (n1 < n3 && n3 < n2)
    printf("%d is the median\n", n3);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r8d
  cmp    %r8d,%esi
  je     L25
  mov    0x14(%rsp),%r9d
  cmp    %r9d,%esi
  je     L25
  setl   %al
  cmp    %r8d,%esi
  setg   %cl
  jle    L17
  test   %al,%al
  jne    L25
L17:
  cmp    %r8d,%esi
  setl   %dl
  cmp    %r9d,%esi
  jle    L2
  test   %dl,%dl
  jne    L25
L2:
  cmp    %r9d,%r8d
  je     L59
  jge    L77
  test   %dl,%dl
  jne    L59
L77:
  cmp    %r9d,%r8d
  jle    L137
  test   %cl,%cl
  jne    L59
  test   %al,%al
  je     L137
  mov    %r9d,%esi
L25:
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L137:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L107
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L59:
  mov    %r8d,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L137
L107:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
data_type: string
name: unpack_data
arguments: data_tag: D6
data_type: string
name: unpack_data
arguments: data_tag: D21
data_type: string

tool: D18: Please eneter 3 numbers separated by spaces > 

tool: D6: %d%d%d

tool: D21: %d is the median


assistant: ```c
int main(void) {
  int n1, n2, n3;
  printf("Please eneter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &n1, &n2, &n3);
  if (n1 == n2 || n1 == n3 || (n2 < n1 && n1 < n3) || (n3 < n1 && n1 < n2))
    printf("%d is the median\n", n1);
  else if (n2 == n3 || (n1 < n2 && n2 < n3) || (n3 < n2 && n2 < n1))
    printf("%d is the median\n", n2);
  else if (n1 < n3 && n3 < n2)
    printf("%d is the median\n", n3);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r8d
  cmp    %r8d,%esi
  je     L46
  mov    0x14(%rsp),%r9d
  cmp    %r9d,%esi
  je     L46
  setl   %al
  cmp    %r8d,%esi
  setg   %cl
  jle    L16
  test   %al,%al
  jne    L46
L16:
  cmp    %r8d,%esi
  setl   %dl
  cmp    %r9d,%esi
  jle    L52
  test   %dl,%dl
  jne    L46
L52:
  cmp    %r9d,%r8d
  je     L51
  jge    L4
  test   %dl,%dl
  jne    L51
L4:
  cmp    %r9d,%r8d
  jle    L23
  test   %cl,%cl
  jne    L51
  test   %al,%al
  je     L23
  mov    %r9d,%esi
L46:
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L51:
  mov    %r8d,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
type: string
name: extract_symbolic_data
arguments: tag: D34
type: string
name: extract_symbolic_data
arguments: tag: D18
type: string

tool: D24: Please eneter 3 numbers separated by spaces > 

tool: D34: %d%d%d

tool: D18: %d is the median


assistant: ```c
int main(void) {
  int n1, n2, n3;
  printf("Please eneter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &n1, &n2, &n3);
  if (n1 == n2 || n1 == n3 || (n2 < n1 && n1 < n3) || (n3 < n1 && n1 < n2))
    printf("%d is the median\n", n1);
  else if (n2 == n3 || (n1 < n2 && n2 < n3) || (n3 < n2 && n2 < n1))
    printf("%d is the median\n", n2);
  else if (n1 < n3 && n3 < n2)
    printf("%d is the median\n", n3);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ex_int_iisort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L44
L67:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L4
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L4:
  addl   $0x1,-0x14(%rbp)
L44:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L67
  mov    -0xc(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ex_swap@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L68
L56:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L39
L10:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x10(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L10
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L68:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L56
  nop
  nop
  leave
  ret
```

assistant: ```c
void ex_int_iisort(int v[], int iv[], int N) {
  int i, j;
  int ndx = 0;
  int small;
  int tmp;
  small = v[iv[0]];
  for (i = 1; i < N; i++) {
    if (v[iv[i]] < small) {
      small = v[iv[i]];
      ndx = i;
    }
  }
  ex_swap(iv, 0, ndx);
  for (i = 1; i < N; i++) {
    tmp = iv[i];
    for (j = i; v[tmp] < v[iv[j - 1]]; j--) {
      iv[j] = iv[j - 1];
    }
    iv[j] = tmp;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ex_int_iisort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movslq (%rsi),%rax
  mov    (%rdi,%rax,4),%ecx
  cmp    $0x1,%edx
  jle    L45
  mov    %rdi,%rbp
  mov    %edx,%r12d
  mov    %edx,%esi
  mov    $0x1,%eax
  mov    $0x0,%edi
  jmp    L24
L15:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L85
L24:
  movslq (%rbx,%rax,4),%rdx
  mov    0x0(%rbp,%rdx,4),%edx
  cmp    %ecx,%edx
  jge    L15
  mov    %edx,%ecx
  mov    %eax,%edi
  jmp    L15
L23:
  mov    %rdi,%rax
  jmp    L19
L85:
  mov    %edi,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <ex_swap@plt>
  mov    $0x4,%edi
  mov    $0x1,%r8d
L42:
  mov    (%rbx,%rdi,1),%r9d
  movslq %r9d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  mov    -0x4(%rbx,%rdi,1),%edx
  movslq %edx,%rax
  mov    0x0(%rbp,%rax,4),%eax
  cmp    %eax,(%rsi)
  jge    L23
  mov    %rdi,%rax
L32:
  mov    %edx,(%rbx,%rax,1)
  sub    $0x4,%rax
  mov    -0x4(%rbx,%rax,1),%edx
  movslq %edx,%rcx
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,(%rsi)
  jl     L32
L19:
  mov    %r9d,(%rbx,%rax,1)
  add    $0x1,%r8d
  add    $0x4,%rdi
  cmp    %r8d,%r12d
  jne    L42
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <ex_swap@plt>
  jmp    L20
```

assistant: ```c
void ex_int_iisort(int v[], int iv[], int N) {
  int i, j;
  int ndx = 0;
  int small;
  int tmp;
  small = v[iv[0]];
  for (i = 1; i < N; i++) {
    if (v[iv[i]] < small) {
      small = v[iv[i]];
      ndx = i;
    }
  }
  ex_swap(iv, 0, ndx);
  for (i = 1; i < N; i++) {
    tmp = iv[i];
    for (j = i; v[tmp] < v[iv[j - 1]]; j--) {
      iv[j] = iv[j - 1];
    }
    iv[j] = tmp;
  }
}
```