ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L31
L26:
  movzbl -0xd(%rbp),%eax
  cmp    $0x63,%al
  jne    L49
  mov    $0x0,%eax
  call   <code@plt>
L49:
  movzbl -0xd(%rbp),%eax
  cmp    $0x64,%al
  jne    L45
  mov    $0x0,%eax
  call   <code@plt>
L45:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L31:
  movzbl -0xd(%rbp),%eax
  cmp    $0x71,%al
  jne    L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D16
datatype: string
name: parse_data
arguments: label: D35
datatype: string

tool: D18: Enter option(c for code,d for decode and q for quit): 

tool: D16: %c

tool: D35: 
Enter option(c for code,d for decode and q for quit): 

assistant: ```c
int main() {
  int b = 1;
  char d;
  printf("Enter option(c for code,d for decode and q for quit): ");
  scanf("%c", &d);
  while (d != 'q') {
    if (d == 'c') {
      code();
    }
    if (d == 'd') {
      code();
    }
    printf("\nEnter option(c for code,d for decode and q for quit): ");
    scanf("%c", &d);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x71,%al
  je     L24
  lea    D22(%rip),%r12
  lea    0x7(%rsp),%rbp
  lea    D39(%rip),%rbx
  jmp    L75
L49:
  cmpb   $0x64,0x7(%rsp)
  je     L27
L44:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x71,%al
  je     L24
L75:
  cmp    $0x63,%al
  jne    L49
  mov    $0x0,%eax
  call   <code@plt>
  jmp    L49
L27:
  mov    $0x0,%eax
  call   <code@plt>
  jmp    L44
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
datatype: string
name: read_data
arguments: data_label: D39
datatype: string
name: read_data
arguments: data_label: D22
datatype: string

tool: D14: Enter option(c for code,d for decode and q for quit): 

tool: D39: %c

tool: D22: 
Enter option(c for code,d for decode and q for quit): 

assistant: ```c
int main() {
  int b = 1;
  char d;
  printf("Enter option(c for code,d for decode and q for quit): ");
  scanf("%c", &d);
  while (d != 'q') {
    if (d == 'c') {
      code();
    }
    if (d == 'd') {
      code();
    }
    printf("\nEnter option(c for code,d for decode and q for quit): ");
    scanf("%c", &d);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D23(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x71,%al
  je     L25
  lea    D28(%rip),%r12
  jmp    L5
  nopl   0x0(%rax)
L15:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x71,%al
  je     L25
L5:
  cmp    $0x63,%al
  je     L24
L56:
  cmpb   $0x64,0x7(%rsp)
  jne    L15
  xor    %eax,%eax
  call   <code@plt>
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  call   <code@plt>
  jmp    L56
  nopl   0x0(%rax)
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string

tool: D19: Enter option(c for code,d for decode and q for quit): 

tool: D23: %c

tool: D28: 
Enter option(c for code,d for decode and q for quit): 

assistant: ```c
int main() {
  int b = 1;
  char d;
  printf("Enter option(c for code,d for decode and q for quit): ");
  scanf("%c", &d);
  while (d != 'q') {
    if (d == 'c') {
      code();
    }
    if (d == 'd') {
      code();
    }
    printf("\nEnter option(c for code,d for decode and q for quit): ");
    scanf("%c", &d);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  lea    D20(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x71,%al
  jne    L41
  jmp    L63
  nopl   0x0(%rax)
L27:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x71,%al
  je     L63
L41:
  cmp    $0x63,%al
  je     L19
L45:
  cmp    $0x64,%al
  jne    L27
  xor    %eax,%eax
  call   <code@plt>
  jmp    L27
  nopl   (%rax)
L19:
  xor    %eax,%eax
  call   <code@plt>
  movzbl 0x7(%rsp),%eax
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L63:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D13
type: string

tool: D23: Enter option(c for code,d for decode and q for quit): 

tool: D20: 
Enter option(c for code,d for decode and q for quit): 

tool: D13: %c

assistant: ```c
int main() {
  int b = 1;
  char d;
  printf("Enter option(c for code,d for decode and q for quit): ");
  scanf("%c", &d);
  while (d != 'q') {
    if (d == 'c') {
      code();
    }
    if (d == 'd') {
      code();
    }
    printf("\nEnter option(c for code,d for decode and q for quit): ");
    scanf("%c", &d);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Optition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %r8d,0xc(%rsp)
  mov    %r9d,0x8(%rsp)
  mov    %edi,%esi
  mov    %edx,%edi
  call   <Goto@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%ebx
  lea    D30(%rip),%r15
  jmp    L72
L18:
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <Goto@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  sub    0x8(%rsp),%ebx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <Goto@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L25:
  cmp    $0x1b,%al
  je     L62
L72:
  mov    $0x0,%eax
  call   <getch@plt>
  cmp    $0xd,%al
  je     L7
  cmp    %ebp,%ebx
  je     L16
  cmp    $0x48,%al
  je     L18
L16:
  cmp    %r12d,%ebx
  je     L25
  cmp    $0x50,%al
  jne    L25
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <Goto@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  add    0x8(%rsp),%ebx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <Goto@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L62:
  mov    0xc(%rsp),%ebx
L7:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
data_type: string
name: extract_symbolic_data
arguments: label: D29
data_type: string
name: extract_symbolic_data
arguments: label: D30
data_type: string

tool: D22: >>

tool: D29: <<

tool: D30:   

assistant: ```c
int Optition(int up, int down, int left, int right, int backspace, int step) {
  char ch;
  int line = up;
  Goto(left, line);
  printf(">>");
  Goto(right, line);
  printf("<<");
  while ((ch = getch()) != 0x0d) {
    while (ch == 0x48) {
      if (line == up) {
        break;
      } else {
        Goto(left, line);
        printf("  ");
        Goto(right, line);
        printf("  ");
        line -= step;
        Goto(left, line);
        printf(">>");
        Goto(right, line);
        printf("<<");
        break;
      }
    }
    while (ch == 0x50) {
      if (line == down) {
        break;
      } else {
        Goto(left, line);
        printf("  ");
        Goto(right, line);
        printf("  ");
        line += step;
        Goto(left, line);
        printf(">>");
        Goto(right, line);
        printf("<<");
        break;
      }
    }
    if (ch == 0x1b) {
      line = backspace;
      break;
    }
  }
  return line;
}
```
user: What is the c source code of the assembly code below:

```asm
<Optition>:
  endbr64
  push   %r15
  lea    D27(%rip),%r15
  push   %r14
  lea    D26(%rip),%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebx,%r12d
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %edi,%esi
  mov    %edx,%edi
  mov    %r8d,0xc(%rsp)
  mov    %r9d,0x8(%rsp)
  call   <Goto@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <Goto@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  xchg   %ax,%ax
L43:
  xor    %eax,%eax
  call   <getch@plt>
  cmp    $0xd,%al
  je     L51
  cmp    $0x48,%al
  jne    L21
  cmp    %ebx,%r12d
  jne    L66
L21:
  cmp    0x4(%rsp),%r12d
  je     L47
  cmp    $0x50,%al
  je     L74
L47:
  cmp    $0x1b,%al
  jne    L43
  mov    0xc(%rsp),%r12d
L51:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L74:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <Goto@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  add    0x8(%rsp),%r12d
L10:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  mov    %r12d,%esi
  call   <Goto@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <Goto@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  sub    0x8(%rsp),%r12d
  jmp    L10
```

tool_calls: name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D36
datatype: string

tool: D27: >>

tool: D26:   

tool: D36: <<

assistant: ```c
int Optition(int up, int down, int left, int right, int backspace, int step) {
  char ch;
  int line = up;
  Goto(left, line);
  printf(">>");
  Goto(right, line);
  printf("<<");
  while ((ch = getch()) != 0x0d) {
    while (ch == 0x48) {
      if (line == up) {
        break;
      } else {
        Goto(left, line);
        printf("  ");
        Goto(right, line);
        printf("  ");
        line -= step;
        Goto(left, line);
        printf(">>");
        Goto(right, line);
        printf("<<");
        break;
      }
    }
    while (ch == 0x50) {
      if (line == down) {
        break;
      } else {
        Goto(left, line);
        printf("  ");
        Goto(right, line);
        printf("  ");
        line += step;
        Goto(left, line);
        printf(">>");
        Goto(right, line);
        printf("<<");
        break;
      }
    }
    if (ch == 0x1b) {
      line = backspace;
      break;
    }
  }
  return line;
}
```
user: What is the c source code of the assembly code below?

```asm
<Optition>:
  endbr64
  push   %r15
  lea    D17(%rip),%r15
  push   %r14
  lea    D31(%rip),%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebx,%r12d
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %edi,%esi
  mov    %edx,%edi
  mov    %r8d,0xc(%rsp)
  mov    %r9d,0x8(%rsp)
  call   <Goto@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <Goto@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xchg   %ax,%ax
L79:
  xor    %eax,%eax
  call   <getch@plt>
  cmp    $0xd,%al
  je     L15
  cmp    $0x48,%al
  jne    L33
  cmp    %ebx,%r12d
  jne    L34
L33:
  cmp    0x4(%rsp),%r12d
  je     L48
  cmp    $0x50,%al
  je     L76
L48:
  cmp    $0x1b,%al
  jne    L79
  mov    0xc(%rsp),%r12d
L15:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L76:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <Goto@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  add    0x8(%rsp),%r12d
L3:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  mov    %r12d,%esi
  call   <Goto@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <Goto@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <Goto@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  sub    0x8(%rsp),%r12d
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D31
type: string
name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D17: >>

tool: D31:   

tool: D7: <<

assistant: ```c
int Optition(int up, int down, int left, int right, int backspace, int step) {
  char ch;
  int line = up;
  Goto(left, line);
  printf(">>");
  Goto(right, line);
  printf("<<");
  while ((ch = getch()) != 0x0d) {
    while (ch == 0x48) {
      if (line == up) {
        break;
      } else {
        Goto(left, line);
        printf("  ");
        Goto(right, line);
        printf("  ");
        line -= step;
        Goto(left, line);
        printf(">>");
        Goto(right, line);
        printf("<<");
        break;
      }
    }
    while (ch == 0x50) {
      if (line == down) {
        break;
      } else {
        Goto(left, line);
        printf("  ");
        Goto(right, line);
        printf("  ");
        line += step;
        Goto(left, line);
        printf(">>");
        Goto(right, line);
        printf("<<");
        break;
      }
    }
    if (ch == 0x1b) {
      line = backspace;
      break;
    }
  }
  return line;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Msp430CounterC__0__Counter__overflow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <TransformCounterC__1__CounterFrom__overflow@plt>
  mov    $0x0,%eax
  call   <TransformCounterC__0__CounterFrom__overflow@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Msp430CounterC__0__Counter__overflow(void) {
  TransformCounterC__1__CounterFrom__overflow();
  TransformCounterC__0__CounterFrom__overflow();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Msp430CounterC__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <TransformCounterC__1__CounterFrom__overflow@plt>
  mov    $0x0,%eax
  call   <TransformCounterC__0__CounterFrom__overflow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Msp430CounterC__0__Counter__overflow(void) {
  TransformCounterC__1__CounterFrom__overflow();
  TransformCounterC__0__CounterFrom__overflow();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Msp430CounterC__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TransformCounterC__1__CounterFrom__overflow@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <TransformCounterC__0__CounterFrom__overflow@plt>
```

assistant: ```c
void Msp430CounterC__0__Counter__overflow(void) {
  TransformCounterC__1__CounterFrom__overflow();
  TransformCounterC__0__CounterFrom__overflow();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Msp430CounterC__0__Counter__overflow>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TransformCounterC__1__CounterFrom__overflow@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <TransformCounterC__0__CounterFrom__overflow@plt>
```

assistant: ```c
void Msp430CounterC__0__Counter__overflow(void) {
  TransformCounterC__1__CounterFrom__overflow();
  TransformCounterC__0__CounterFrom__overflow();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_in_string_array_case>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <string_array_pos_case@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int is_in_string_array_case(char *array[], size_t len, const char item[]) {
  const int pos = string_array_pos_case(array, len, item);
  return pos >= 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_in_string_array_case>:
  endbr64
  sub    $0x8,%rsp
  call   <string_array_pos_case@plt>
  not    %eax
  shr    $0x1f,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_in_string_array_case(char *array[], size_t len, const char item[]) {
  const int pos = string_array_pos_case(array, len, item);
  return pos >= 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_in_string_array_case>:
  endbr64
  sub    $0x8,%rsp
  call   <string_array_pos_case@plt>
  add    $0x8,%rsp
  not    %eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int is_in_string_array_case(char *array[], size_t len, const char item[]) {
  const int pos = string_array_pos_case(array, len, item);
  return pos >= 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_number_of_columns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L3
  movq   $0x0,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
size_t parse_number_of_columns(const char *p) {
  size_t number_of_columns;
  char *q;
  number_of_columns = strtol(p, &q, 10);
  if (*q != '\0')
    number_of_columns = 0;
  return number_of_columns;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_number_of_columns>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  mov    $0x0,%edx
  cmovne %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t parse_number_of_columns(const char *p) {
  size_t number_of_columns;
  char *q;
  number_of_columns = strtol(p, &q, 10);
  if (*q != '\0')
    number_of_columns = 0;
  return number_of_columns;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_number_of_columns>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  mov    $0x0,%edx
  cmovne %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t parse_number_of_columns(const char *p) {
  size_t number_of_columns;
  char *q;
  number_of_columns = strtol(p, &q, 10);
  if (*q != '\0')
    number_of_columns = 0;
  return number_of_columns;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_number_of_columns>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  mov    $0x0,%edx
  cmovne %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t parse_number_of_columns(const char *p) {
  size_t number_of_columns;
  char *q;
  number_of_columns = strtol(p, &q, 10);
  if (*q != '\0')
    number_of_columns = 0;
  return number_of_columns;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L14:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x9,-0x4(%rbp)
  jle    L14
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int n = 0;
  for (int i = 0; i < 10; i = i + 1) {
    n = n + i;
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x2d,%eax
  ret
```

assistant: ```c
int main(void) {
  int n = 0;
  for (int i = 0; i < 10; i = i + 1) {
    n = n + i;
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x2d,%eax
  ret
```

assistant: ```c
int main(void) {
  int n = 0;
  for (int i = 0; i < 10; i = i + 1) {
    n = n + i;
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x2d,%eax
  ret
```

assistant: ```c
int main(void) {
  int n = 0;
  for (int i = 0; i < 10; i = i + 1) {
    n = n + i;
  }
  return n;
}
```