ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<strnicmp>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %edx,%edx
  je     L34
  mov    %rdi,%r13
  mov    %edx,%r14d
  mov    %rsi,%r12
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L51:
  test   %bl,%bl
  je     L37
  mov    0x8(%rsp),%eax
  sub    %r12d,%eax
  add    %r14d,%eax
  test   %eax,%eax
  jle    L76
L65:
  movsbl 0x0(%r13),%ebp
  add    $0x1,%r13
  mov    %ebp,%edi
  mov    %ebp,%ebx
  call   <islower@plt>
  test   %eax,%eax
  je     L99
  mov    %ebp,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
L99:
  movsbl (%r12),%r15d
  add    $0x1,%r12
  mov    %r15d,%edi
  mov    %r15d,%ebp
  call   <islower@plt>
  test   %eax,%eax
  je     L98
  mov    %r15d,%edi
  call   <toupper@plt>
  mov    %eax,%ebp
L98:
  cmp    %bpl,%bl
  je     L51
L55:
  test   %bl,%bl
  je     L40
  mov    $0xffffffff,%eax
  cmp    %bpl,%bl
  jl     L40
L34:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L37:
  cmp    %bpl,%bl
  jne    L55
L76:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L40:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strnicmp(s1, s2, n)
char *s1;
char *s2;
int n;
{
  char c1, c2;
  if (n == 0)
    return 0;
  do {
    c1 = *s1++;
    if (islower(c1))
      c1 = toupper(c1);
    c2 = *s2++;
    if (islower(c2))
      c2 = toupper(c2);
  } while (c1 == c2 && c1 && c2 && --n > 0);
  if (n == 0 || c1 == c2)
    return 0;
  if (c1 == '\0' || c1 < c2)
    return 1;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<OF_convert_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L14
  mov    -0x8(%rbp),%rax
  movb   $0x2f,(%rax)
L14:
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L45
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L45
  addq   $0x2,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L45:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void OF_convert_path(unsigned char **path) {
  unsigned char *pos;
  do {
  } while (0);
  for (pos = *path; *pos != '\0'; pos++) {
    if (*pos == '\\')
      *pos = '/';
  }
  do {
  } while (0);
  pos = *path;
  if (pos[0] == '/' && pos[1] == '/') {
    pos += 2;
    *path = pos;
  }
  do {
  } while (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<OF_convert_path>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L62
  jmp    L77
L72:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L7
L62:
  cmp    $0x5c,%dl
  jne    L72
  movb   $0x2f,(%rax)
  jmp    L72
L7:
  mov    (%rdi),%rax
  cmpb   $0x2f,(%rax)
  je     L45
L77:
  ret
L45:
  cmpb   $0x2f,0x1(%rax)
  jne    L77
  add    $0x2,%rax
  mov    %rax,(%rdi)
  jmp    L77
```

assistant: ```c
void OF_convert_path(unsigned char **path) {
  unsigned char *pos;
  do {
  } while (0);
  for (pos = *path; *pos != '\0'; pos++) {
    if (*pos == '\\')
      *pos = '/';
  }
  do {
  } while (0);
  pos = *path;
  if (pos[0] == '/' && pos[1] == '/') {
    pos += 2;
    *path = pos;
  }
  do {
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OF_convert_path>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L49
  xchg   %ax,%ax
L31:
  cmp    $0x5c,%dl
  jne    L9
  movb   $0x2f,(%rax)
L9:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L31
  mov    (%rdi),%rax
  cmpb   $0x2f,(%rax)
  je     L47
L49:
  ret
  nopl   (%rax)
L47:
  cmpb   $0x2f,0x1(%rax)
  jne    L49
  add    $0x2,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void OF_convert_path(unsigned char **path) {
  unsigned char *pos;
  do {
  } while (0);
  for (pos = *path; *pos != '\0'; pos++) {
    if (*pos == '\\')
      *pos = '/';
  }
  do {
  } while (0);
  pos = *path;
  if (pos[0] == '/' && pos[1] == '/') {
    pos += 2;
    *path = pos;
  }
  do {
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<OF_convert_path>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L57
  xchg   %ax,%ax
L59:
  cmp    $0x5c,%dl
  je     L67
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L59
  mov    (%rdi),%rax
  cmpb   $0x2f,(%rax)
  je     L21
L57:
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  movb   $0x2f,(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L59
  mov    (%rdi),%rax
  cmpb   $0x2f,(%rax)
  jne    L57
L21:
  cmpb   $0x2f,0x1(%rax)
  jne    L57
  add    $0x2,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void OF_convert_path(unsigned char **path) {
  unsigned char *pos;
  do {
  } while (0);
  for (pos = *path; *pos != '\0'; pos++) {
    if (*pos == '\\')
      *pos = '/';
  }
  do {
  } while (0);
  pos = *path;
  if (pos[0] == '/' && pos[1] == '/') {
    pos += 2;
    *path = pos;
  }
  do {
  } while (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<recv_fd>:
  endbr64
  push   %rbx
  sub    $0x180,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x5c(%rsp)
  movw   $0x0,0x64(%rsp)
  movq   $0x0,0x66(%rsp)
  movw   $0x0,0x6e(%rsp)
  lea    0x5c(%rsp),%rax
  mov    %rax,0x30(%rsp)
  movl   $0x3,0x38(%rsp)
  lea    0x66(%rsp),%rax
  mov    %rax,0x40(%rsp)
  movl   $0x3,0x58(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x18(%rsp)
  movl   $0x2,(%rsp)
  lea    0x70(%rsp),%rax
  mov    %rax,0x8(%rsp)
  movl   $0x100,0x10(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edx
  call   <recvmsg@plt>
  test   %rax,%rax
  js     L16
L11:
  mov    %rsp,%rdi
  call   <CMSG_FIRSTHDR@plt>
  mov    %rax,%rdi
  call   <CMSG_DATA@plt>
  mov    %rax,%rbx
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <err_remark@plt>
  mov    (%rbx),%ebx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <err_remark@plt>
  lea    0x5c(%rsp),%rsi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <err_remark@plt>
  lea    0x66(%rsp),%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <err_remark@plt>
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    %ebx,%eax
  add    $0x180,%rsp
  pop    %rbx
  ret
L16:
  lea    D24(%rip),%rdi
  call   <err_syserr@plt>
  jmp    L11
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
type_infered: string
name: parse_data
arguments: tag: D7
type_infered: string
name: parse_data
arguments: tag: D49
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string

tool: D14: About to extract fd


tool: D7: Extracted fd %d


tool: D49: Extracted buf1 %s


tool: D23: Extracted buf2 %s


tool: D24: Failed to receive message


assistant: ```c
int recv_fd(int socket) {
  struct msghdr msg = {0};
  char m_buffer[256];
  char buf1[10] = {0};
  char buf2[10] = {0};
  struct iovec io[2];
  io[0].iov_base = buf1;
  io[0].iov_len = 3;
  io[1].iov_base = buf2;
  io[2].iov_len = 3;
  msg.msg_iov = io;
  msg.msg_iovlen = 2;
  char c_buffer[256];
  msg.msg_control = c_buffer;
  msg.msg_controllen = sizeof(c_buffer);
  if (recvmsg(socket, &msg, 0) < 0)
    err_syserr("Failed to receive message\n");
  struct cmsghdr *cmsg = CMSG_FIRSTHDR(&msg);
  void *data = CMSG_DATA(cmsg);
  err_remark("About to extract fd\n");
  int fd = *((int *)data);
  err_remark("Extracted fd %d\n", fd);
  err_remark("Extracted buf1 %s\n", buf1);
  err_remark("Extracted buf2 %s\n", buf2);
  return fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<recv_fd>:
  endbr64
  push   %r13
  xor    %edx,%edx
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x188,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  mov    %rsp,%r13
  movaps %xmm0,0x10(%rsp)
  mov    %ax,0x64(%rsp)
  lea    0x30(%rsp),%rax
  lea    0x5c(%rsp),%r12
  mov    %r13,%rsi
  mov    %dx,0x6e(%rsp)
  lea    0x66(%rsp),%rbp
  xor    %edx,%edx
  mov    %rax,0x18(%rsp)
  lea    0x70(%rsp),%rax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x5c(%rsp)
  movq   $0x0,0x66(%rsp)
  mov    %r12,0x30(%rsp)
  movl   $0x3,0x38(%rsp)
  mov    %rbp,0x40(%rsp)
  movl   $0x3,0x58(%rsp)
  movl   $0x2,(%rsp)
  mov    %rax,0x8(%rsp)
  movl   $0x100,0x10(%rsp)
  call   <recvmsg@plt>
  test   %rax,%rax
  js     L2
L1:
  mov    %r13,%rdi
  call   <CMSG_FIRSTHDR@plt>
  mov    %rax,%rdi
  call   <CMSG_DATA@plt>
  lea    D40(%rip),%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <err_remark@plt>
  mov    (%rbx),%r13d
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  mov    %r13d,%esi
  call   <err_remark@plt>
  mov    %r12,%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <err_remark@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <err_remark@plt>
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x188,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L2:
  lea    D5(%rip),%rdi
  call   <err_syserr@plt>
  jmp    L1
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D40
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D30
datatype: string
name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D40: About to extract fd


tool: D27: Extracted fd %d


tool: D30: Extracted buf1 %s


tool: D17: Extracted buf2 %s


tool: D5: Failed to receive message


assistant: ```c
int recv_fd(int socket) {
  struct msghdr msg = {0};
  char m_buffer[256];
  char buf1[10] = {0};
  char buf2[10] = {0};
  struct iovec io[2];
  io[0].iov_base = buf1;
  io[0].iov_len = 3;
  io[1].iov_base = buf2;
  io[2].iov_len = 3;
  msg.msg_iov = io;
  msg.msg_iovlen = 2;
  char c_buffer[256];
  msg.msg_control = c_buffer;
  msg.msg_controllen = sizeof(c_buffer);
  if (recvmsg(socket, &msg, 0) < 0)
    err_syserr("Failed to receive message\n");
  struct cmsghdr *cmsg = CMSG_FIRSTHDR(&msg);
  void *data = CMSG_DATA(cmsg);
  err_remark("About to extract fd\n");
  int fd = *((int *)data);
  err_remark("Extracted fd %d\n", fd);
  err_remark("Extracted buf1 %s\n", buf1);
  err_remark("Extracted buf2 %s\n", buf2);
  return fd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<recv_fd>:
  endbr64
  push   %r13
  xor    %edx,%edx
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x188,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  mov    %rsp,%r13
  movaps %xmm0,0x10(%rsp)
  mov    %ax,0x64(%rsp)
  lea    0x30(%rsp),%rax
  lea    0x5c(%rsp),%r12
  mov    %r13,%rsi
  mov    %dx,0x6e(%rsp)
  lea    0x66(%rsp),%rbp
  xor    %edx,%edx
  mov    %rax,0x18(%rsp)
  lea    0x70(%rsp),%rax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x5c(%rsp)
  movq   $0x0,0x66(%rsp)
  mov    %r12,0x30(%rsp)
  movl   $0x3,0x38(%rsp)
  mov    %rbp,0x40(%rsp)
  movl   $0x3,0x58(%rsp)
  movl   $0x2,(%rsp)
  mov    %rax,0x8(%rsp)
  movl   $0x100,0x10(%rsp)
  call   <recvmsg@plt>
  test   %rax,%rax
  js     L14
L12:
  mov    %r13,%rdi
  call   <CMSG_FIRSTHDR@plt>
  mov    %rax,%rdi
  call   <CMSG_DATA@plt>
  lea    D35(%rip),%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <err_remark@plt>
  mov    (%rbx),%r13d
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  mov    %r13d,%esi
  call   <err_remark@plt>
  mov    %r12,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <err_remark@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D36(%rip),%rdi
  call   <err_remark@plt>
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x188,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L14:
  lea    D26(%rip),%rdi
  call   <err_syserr@plt>
  jmp    L12
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D35
type_infered: string
name: read_data
arguments: tag: D37
type_infered: string
name: read_data
arguments: tag: D14
type_infered: string
name: read_data
arguments: tag: D36
type_infered: string
name: read_data
arguments: tag: D26
type_infered: string

tool: D35: About to extract fd


tool: D37: Extracted fd %d


tool: D14: Extracted buf1 %s


tool: D36: Extracted buf2 %s


tool: D26: Failed to receive message


assistant: ```c
int recv_fd(int socket) {
  struct msghdr msg = {0};
  char m_buffer[256];
  char buf1[10] = {0};
  char buf2[10] = {0};
  struct iovec io[2];
  io[0].iov_base = buf1;
  io[0].iov_len = 3;
  io[1].iov_base = buf2;
  io[2].iov_len = 3;
  msg.msg_iov = io;
  msg.msg_iovlen = 2;
  char c_buffer[256];
  msg.msg_control = c_buffer;
  msg.msg_controllen = sizeof(c_buffer);
  if (recvmsg(socket, &msg, 0) < 0)
    err_syserr("Failed to receive message\n");
  struct cmsghdr *cmsg = CMSG_FIRSTHDR(&msg);
  void *data = CMSG_DATA(cmsg);
  err_remark("About to extract fd\n");
  int fd = *((int *)data);
  err_remark("Extracted fd %d\n", fd);
  err_remark("Extracted buf1 %s\n", buf1);
  err_remark("Extracted buf2 %s\n", buf2);
  return fd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<coord_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L89
L43:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  mov    D15(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jl     L90
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L36
  mov    $0x1,%eax
  jmp    L26
L36:
  mov    $0xffffffff,%eax
  jmp    L26
L90:
  addl   $0x1,-0xc(%rbp)
L89:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L43
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  mov    D15(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jge    L9
  mov    $0x0,%eax
  jmp    L26
L9:
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L27
  mov    $0x1,%eax
  jmp    L26
L27:
  mov    $0xffffffff,%eax
L26:
  leave
  ret
```

assistant: ```c
int coord_cmp(double *c1, double *c2, int dim) {
  int i;
  double ret = 0.0;
  for (i = 0; i < dim; i++) {
    ret = *c1++ - *c2++;
    if (fabs(ret) >= DBL_EPSILON) {
      return ret > 0 ? 1 : -1;
    }
  }
  if (fabs(ret) < DBL_EPSILON) {
    return 0;
  } else {
    return ret > 0 ? 1 : -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L27
L13:
  lea    -0x810(%rbp),%rcx
  lea    -0xc10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <DeTab@plt>
  lea    -0x810(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  lea    -0xc10(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <GetLine@plt>
  mov    %eax,-0xc14(%rbp)
  cmpl   $0x0,-0xc14(%rbp)
  jg     L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D3: %s

assistant: ```c
int main() {
  char input[1024];
  char line[1024 * 2];
  int len;
  while ((len = GetLine(input, 1024)) > 0) {
    DeTab(input, line, 8);
    printf("%s", line);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xc18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rbp
  jmp    L20
L8:
  lea    0x400(%rsp),%rbx
  mov    %rsp,%rdi
  mov    $0x8,%edx
  mov    %rbx,%rsi
  call   <DeTab@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L20:
  mov    %rsp,%rdi
  mov    $0x400,%esi
  call   <GetLine@plt>
  test   %eax,%eax
  jg     L8
  mov    0xc08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0xc18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: %s

assistant: ```c
int main() {
  char input[1024];
  char line[1024 * 2];
  int len;
  while ((len = GetLine(input, 1024)) > 0) {
    DeTab(input, line, 8);
    printf("%s", line);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L4
  xchg   %ax,%ax
L19:
  lea    0x400(%rsp),%rbp
  mov    %rbx,%rdi
  mov    $0x8,%edx
  mov    %rbp,%rsi
  call   <DeTab@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L4:
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <GetLine@plt>
  test   %eax,%eax
  jg     L19
  mov    0xc08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xc10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: %s

assistant: ```c
int main() {
  char input[1024];
  char line[1024 * 2];
  int len;
  while ((len = GetLine(input, 1024)) > 0) {
    DeTab(input, line, 8);
    printf("%s", line);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L18
  xchg   %ax,%ax
L17:
  lea    0x400(%rsp),%rbp
  mov    %rbx,%rdi
  mov    $0x8,%edx
  mov    %rbp,%rsi
  call   <DeTab@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L18:
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <GetLine@plt>
  test   %eax,%eax
  jg     L17
  mov    0xc08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xc10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: %s

assistant: ```c
int main() {
  char input[1024];
  char line[1024 * 2];
  int len;
  while ((len = GetLine(input, 1024)) > 0) {
    DeTab(input, line, 8);
    printf("%s", line);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<palinbase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %esi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x44(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movl   $0x0,-0x30(%rbp)
  movb   $0x0,-0x2c(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movb   $0x0,-0xc(%rbp)
  jmp    L41
L5:
  mov    -0x54(%rbp),%eax
  cltd
  idivl  -0x58(%rbp)
  mov    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x44(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x44(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x40(%rbp,%rax,1)
  mov    -0x54(%rbp),%eax
  cltd
  idivl  -0x58(%rbp)
  mov    %eax,-0x54(%rbp)
L41:
  cmpl   $0x0,-0x54(%rbp)
  jg     L5
  movl   $0x0,-0x48(%rbp)
  jmp    L27
L21:
  mov    -0x44(%rbp),%eax
  sub    -0x48(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x48(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%edx
  movslq %ecx,%rax
  mov    %dl,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x48(%rbp)
L27:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L21
  lea    -0x20(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
int palinbase(int n, int b) {
  int i, sz = 0;
  char s1[21] = {0};
  char s2[21] = {0};
  while (n > 0) {
    s1[sz++] = (n % b) + '0';
    n /= b;
  }
  for (i = 0; i < sz; i++)
    s2[sz - i - 1] = s1[i];
  return (strcmp(s1, s2) == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<palinbase>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  movb   $0x0,0x14(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  test   %edi,%edi
  jle    L19
  mov    %rsp,%r10
  mov    %r10,%r8
  mov    $0x0,%ecx
L6:
  mov    %ecx,%r9d
  add    $0x1,%ecx
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %eax,%edi
  add    $0x1,%r8
  test   %eax,%eax
  jg     L6
  test   %ecx,%ecx
  jle    L19
  movslq %ecx,%rcx
  lea    0x1f(%rsp,%rcx,1),%rcx
  mov    %r10,%rax
L40:
  movzbl (%rax),%edx
  mov    %dl,(%rcx)
  add    $0x1,%rax
  sub    $0x1,%rcx
  mov    %eax,%edx
  sub    %r10d,%edx
  sub    $0x1,%edx
  cmp    %edx,%r9d
  jg     L40
L19:
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x48,%rsp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int palinbase(int n, int b) {
  int i, sz = 0;
  char s1[21] = {0};
  char s2[21] = {0};
  while (n > 0) {
    s1[sz++] = (n % b) + '0';
    n /= b;
  }
  for (i = 0; i < sz; i++)
    s2[sz - i - 1] = s1[i];
  return (strcmp(s1, s2) == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<palinbase>:
  endbr64
  sub    $0x48,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rdx
  mov    %rdx,0x38(%rsp)
  xor    %edx,%edx
  movl   $0x0,0x10(%rsp)
  movb   $0x0,0x14(%rsp)
  movl   $0x0,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x20(%rsp)
  test   %edi,%edi
  jle    L36
  mov    %rsp,%r9
  mov    %edi,%eax
  xor    %ecx,%ecx
  mov    %r9,%rdi
  mov    %r9,%r8
L10:
  cltd
  movslq %ecx,%r10
  add    $0x1,%r8
  add    $0x1,%ecx
  idiv   %esi
  add    $0x30,%edx
  mov    %dl,-0x1(%r8)
  test   %eax,%eax
  jg     L10
  movslq %ecx,%rcx
  lea    0x20(%rsp),%rsi
  lea    (%rsi,%rcx,1),%rax
  lea    0x1f(%rsp,%rcx,1),%rcx
  sub    %r10,%rcx
  nopl   0x0(%rax)
L13:
  movzbl (%rdi),%edx
  sub    $0x1,%rax
  add    $0x1,%rdi
  mov    %dl,(%rax)
  cmp    %rcx,%rax
  jne    L13
L38:
  mov    %r9,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x48,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rsp,%r9
  lea    0x20(%rsp),%rsi
  jmp    L38
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int palinbase(int n, int b) {
  int i, sz = 0;
  char s1[21] = {0};
  char s2[21] = {0};
  while (n > 0) {
    s1[sz++] = (n % b) + '0';
    n /= b;
  }
  for (i = 0; i < sz; i++)
    s2[sz - i - 1] = s1[i];
  return (strcmp(s1, s2) == 0);
}
```