user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D81(%rip),%rdi
  lea    D10(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D84(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D80(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D93(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%esi
  lea    D98(%rip),%rdi
  xor    %eax,%eax
  add    0xc(%rsp),%esi
  add    0x14(%rsp),%esi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  sub    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D82(%rip),%rdi
  xor    %eax,%eax
  sub    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  imul   0x14(%rsp),%esi
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  xor    %eax,%eax
  imul   0x14(%rsp),%esi
  lea    D92(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  lea    D122(%rip),%rdi
  mov    %edx,%ecx
  imul   %eax,%ecx
  lea    (%rdx,%rcx,2),%esi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%eax
  lea    D68(%rip),%rdi
  lea    0xa(%rax,%rdx,1),%esi
  imul   %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  lea    D132(%rip),%rdi
  mov    %eax,%esi
  add    %edx,%eax
  imul   %edx,%esi
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  lea    D49(%rip),%rdi
  lea    (%rax,%rdx,1),%esi
  imul   %edx,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  add    %esi,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D81
type: string
name: parse_data
arguments: data_tag: D10
type: string
name: parse_data
arguments: data_tag: D34
type: string
name: parse_data
arguments: data_tag: D84
type: string
name: parse_data
arguments: data_tag: D80
type: string
name: parse_data
arguments: data_tag: D93
type: string
name: parse_data
arguments: data_tag: D98
type: string
name: parse_data
arguments: data_tag: D35
type: string
name: parse_data
arguments: data_tag: D82
type: string
name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D92
type: string
name: parse_data
arguments: data_tag: D122
type: string
name: parse_data
arguments: data_tag: D68
type: string
name: parse_data
arguments: data_tag: D132
type: string
name: parse_data
arguments: data_tag: D49
type: string

tool: D81: This program needs 3 initial digit(s) to provide different calculations:


tool: D10: %d

tool: D34: Please enter 1st number: 

tool: D84: Please enter 2nd number: 

tool: D80: Please enter 3rd number: 

tool: D93: 
Pay attention to below results:

tool: D98: Summation of these 3 numbers result is: %d


tool: D35: Differences between 1st and 2nd is: %d


tool: D82: Differences between 1st and 3rd is: %d


tool: D9: 2nd number multiply by 3rd number result is: %d


tool: D92: Product of these 3 numbers is: %d


tool: D122: E= 2AB+A-B %d


tool: D68: F= A+B+10-4AB %d


tool: D132: G= AB-2(A+B) %d


tool: D49: H= 2A+2B-2AB %d


assistant: ```c
int main() {
  printf("This program needs 3 initial digit(s) to provide different calculations:\n\n");
  int a, b, c;
  printf("Please enter 1st number: ");
  scanf("%d", &a);
  printf("Please enter 2nd number: ");
  scanf("%d", &b);
  printf("Please enter 3rd number: ");
  scanf("%d", &c);
  printf("\nPay attention to below results:\n");
  printf("Summation of these 3 numbers result is: %d\n", a + b + c);
  printf("Differences between 1st and 2nd is: %d\n", b - a);
  printf("Differences between 1st and 3rd is: %d\n", c - a);
  printf("2nd number multiply by 3rd number result is: %d\n", b * c);
  printf("Product of these 3 numbers is: %d\n", a * b * c);
  printf("E= 2AB+A-B %d\n", 2 * a * b + a - b);
  printf("F= A+B+10-4AB %d\n", a + b + 10 - (4 * a * b));
  printf("G= AB-2(A+B) %d\n", a * b - 2 * (a + b));
  printf("H= 2A+2B-2AB %d\n", 2 * a + 2 * b - (2 * a * b));
  return 0;
}
```