ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<append_string_katcl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <before_append_katcl@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L12
L8:
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <add_string_parse_katcl@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <after_append_katcl@plt>
L12:
  leave
  ret
```

assistant: ```c
int append_string_katcl(struct katcl_line *l, int flags, char *buffer) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_string_parse_katcl(p, flags, buffer);
  return after_append_katcl(l, flags, result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<append_string_katcl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L16
  mov    %rax,%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <add_string_parse_katcl@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <after_append_katcl@plt>
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int append_string_katcl(struct katcl_line *l, int flags, char *buffer) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_string_parse_katcl(p, flags, buffer);
  return after_append_katcl(l, flags, result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<append_string_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L8
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <add_string_parse_katcl@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <after_append_katcl@plt>
L8:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int append_string_katcl(struct katcl_line *l, int flags, char *buffer) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_string_parse_katcl(p, flags, buffer);
  return after_append_katcl(l, flags, result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_string_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L6
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <add_string_parse_katcl@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <after_append_katcl@plt>
L6:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int append_string_katcl(struct katcl_line *l, int flags, char *buffer) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_string_parse_katcl(p, flags, buffer);
  return after_append_katcl(l, flags, result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<v3copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L16
L3:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  add    $0x1,%ebx
L16:
  cmp    $0x2,%ebx
  jle    L3
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void v3copy(const float *v1, float *v2) {
  register int i;
  for (i = 0; i < 3; i++)
    v2[i] = v1[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<v3copy>:
  endbr64
  movss  (%rdi),%xmm0
  movss  %xmm0,(%rsi)
  movss  0x4(%rdi),%xmm0
  movss  %xmm0,0x4(%rsi)
  movss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rsi)
  ret
```

assistant: ```c
void v3copy(const float *v1, float *v2) {
  register int i;
  for (i = 0; i < 3; i++)
    v2[i] = v1[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<v3copy>:
  endbr64
  movss  (%rdi),%xmm0
  movss  %xmm0,(%rsi)
  movss  0x4(%rdi),%xmm0
  movss  %xmm0,0x4(%rsi)
  movss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rsi)
  ret
```

assistant: ```c
void v3copy(const float *v1, float *v2) {
  register int i;
  for (i = 0; i < 3; i++)
    v2[i] = v1[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<v3copy>:
  endbr64
  movss  (%rdi),%xmm0
  movss  %xmm0,(%rsi)
  movss  0x4(%rdi),%xmm0
  movss  %xmm0,0x4(%rsi)
  movss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rsi)
  ret
```

assistant: ```c
void v3copy(const float *v1, float *v2) {
  register int i;
  for (i = 0; i < 3; i++)
    v2[i] = v1[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<loadstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L32
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L28
L32:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L55
L5:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L55
L8:
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  neg    %eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x8(%rbp),%rax
L55:
  leave
  ret
```

assistant: ```c
char *loadstr(FILE *file) {
  int n, size = 0;
  char *buf;
  do {
    n = getc(file);
    size++;
  } while ((n != (int)'\0') && (n != EOF));
  if (n == EOF)
    return NULL;
  if ((buf = (char *)malloc(size)) == NULL)
    return NULL;
  fseek(file, -size, SEEK_CUR);
  fread(buf, 1, size, file);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<loadstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L34:
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %ebx,%r12d
  add    $0x1,%ebx
  test   %eax,%eax
  je     L7
  mov    D19(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L34
  mov    $0x0,%r14d
  jmp    L48
L7:
  mov    D19(%rip),%rax
  cmpl   $0x0,(%rax)
  je     L55
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%r14d
  test   %rax,%rax
  je     L48
  mov    %rax,%r14
  mov    %r12d,%esi
  not    %esi
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    %rbp,%rdi
  call   <fseek@plt>
  mov    %rbp,%rcx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
L48:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L55:
  mov    $0x0,%r14d
  jmp    L48
```

assistant: ```c
char *loadstr(FILE *file) {
  int n, size = 0;
  char *buf;
  do {
    n = getc(file);
    size++;
  } while ((n != (int)'\0') && (n != EOF));
  if (n == EOF)
    return NULL;
  if ((buf = (char *)malloc(size)) == NULL)
    return NULL;
  fseek(file, -size, SEEK_CUR);
  fread(buf, 1, size, file);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<loadstr>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D4(%rip),%rbp
  push   %rbx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L30:
  cmp    %eax,0x0(%rbp)
  je     L11
L15:
  mov    %r13,%rdi
  mov    %r12d,%ebx
  add    $0x1,%r12d
  call   <getc@plt>
  test   %eax,%eax
  jne    L30
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  je     L11
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L11
  mov    D19(%rip),%rax
  mov    %ebx,%esi
  mov    %r13,%rdi
  not    %esi
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %r14,%rdi
  mov    $0x1,%esi
  call   <fread@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *loadstr(FILE *file) {
  int n, size = 0;
  char *buf;
  do {
    n = getc(file);
    size++;
  } while ((n != (int)'\0') && (n != EOF));
  if (n == EOF)
    return NULL;
  if ((buf = (char *)malloc(size)) == NULL)
    return NULL;
  fseek(file, -size, SEEK_CUR);
  fread(buf, 1, size, file);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<loadstr>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D11(%rip),%rbp
  push   %rbx
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L5:
  cmp    %eax,0x0(%rbp)
  je     L20
L49:
  mov    %r13,%rdi
  mov    %r12d,%ebx
  add    $0x1,%r12d
  call   <getc@plt>
  test   %eax,%eax
  jne    L5
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  je     L20
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L20
  mov    D9(%rip),%rax
  mov    %ebx,%esi
  mov    %r13,%rdi
  not    %esi
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %r14,%rdi
  mov    $0x1,%esi
  call   <fread@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *loadstr(FILE *file) {
  int n, size = 0;
  char *buf;
  do {
    n = getc(file);
    size++;
  } while ((n != (int)'\0') && (n != EOF));
  if (n == EOF)
    return NULL;
  if ((buf = (char *)malloc(size)) == NULL)
    return NULL;
  fseek(file, -size, SEEK_CUR);
  fread(buf, 1, size, file);
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L12:
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  cmp    %rax,-0x18(%rbp)
  jb     L12
  movss  -0xc(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float sum(const float *const __restrict v, const unsigned n) {
  float s = 0.0f;
  const float *c = v + n;
  while (c-- > v)
    s += *c;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sum>:
  endbr64
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdi
  jae    L14
  pxor   %xmm0,%xmm0
L12:
  addss  -0x4(%rax),%xmm0
  sub    $0x4,%rax
  cmp    %rax,%rdi
  jb     L12
  ret
L14:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float sum(const float *const __restrict v, const unsigned n) {
  float s = 0.0f;
  const float *c = v + n;
  while (c-- > v)
    s += *c;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sum>:
  endbr64
  mov    %esi,%esi
  pxor   %xmm0,%xmm0
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdi
  jae    L3
  nopl   0x0(%rax,%rax,1)
L16:
  addss  -0x4(%rax),%xmm0
  sub    $0x4,%rax
  cmp    %rax,%rdi
  jb     L16
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
float sum(const float *const __restrict v, const unsigned n) {
  float s = 0.0f;
  const float *c = v + n;
  while (c-- > v)
    s += *c;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sum>:
  endbr64
  mov    %esi,%esi
  mov    %rdi,%rdx
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%rax
  lea    -0x4(%rax),%rcx
  cmp    %rax,%rdi
  jae    L22
  lea    -0x1(%rsi),%rax
  mov    %rax,%rdi
  shr    $0x2,%rdi
  add    $0x1,%rdi
  cmp    $0xb,%rax
  jbe    L33
  mov    %rdi,%r8
  lea    -0x10(%rdx,%rsi,1),%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%r8
  mov    %rax,%rsi
  shl    $0x4,%r8
  sub    %r8,%rsi
  nopl   0x0(%rax)
L2:
  movss  0xc(%rax),%xmm1
  sub    $0x10,%rax
  addss  %xmm1,%xmm0
  movss  0x18(%rax),%xmm1
  addss  %xmm1,%xmm0
  movss  0x14(%rax),%xmm1
  addss  %xmm1,%xmm0
  movss  0x10(%rax),%xmm1
  addss  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L2
  mov    %rdi,%rax
  and    $0xfffffffffffffffc,%rax
  mov    %rax,%rsi
  neg    %rsi
  lea    (%rcx,%rsi,4),%rcx
  cmp    %rax,%rdi
  je     L3
L60:
  addss  (%rcx),%xmm0
  lea    -0x4(%rcx),%rax
  cmp    %rcx,%rdx
  jae    L46
  addss  -0x4(%rcx),%xmm0
  cmp    %rax,%rdx
  jae    L46
  addss  -0x8(%rcx),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  pxor   %xmm0,%xmm0
L46:
  ret
  nopl   (%rax)
L3:
  ret
L33:
  pxor   %xmm0,%xmm0
  jmp    L60
```

assistant: ```c
float sum(const float *const __restrict v, const unsigned n) {
  float s = 0.0f;
  const float *c = v + n;
  while (c-- > v)
    s += *c;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alaw_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L19
L3:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <alaw_to_s16@plt>
  mov    %ax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L3
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void alaw_dec(char *alaw_data, char *s16_data, int limit) {
  int i;
  for (i = 0; i < limit; i++) {
    ((signed short *)s16_data)[i] = alaw_to_s16((unsigned char)alaw_data[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<alaw_dec>:
  endbr64
  test   %edx,%edx
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
L13:
  movzbl (%r12,%rbx,1),%edi
  call   <alaw_to_s16@plt>
  mov    %ax,0x0(%r13,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  ret
```

assistant: ```c
void alaw_dec(char *alaw_data, char *s16_data, int limit) {
  int i;
  for (i = 0; i < limit; i++) {
    ((signed short *)s16_data)[i] = alaw_to_s16((unsigned char)alaw_data[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<alaw_dec>:
  endbr64
  test   %edx,%edx
  jle    L2
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L5:
  movzbl (%r12,%rbx,1),%edi
  call   <alaw_to_s16@plt>
  mov    %ax,0x0(%r13,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void alaw_dec(char *alaw_data, char *s16_data, int limit) {
  int i;
  for (i = 0; i < limit; i++) {
    ((signed short *)s16_data)[i] = alaw_to_s16((unsigned char)alaw_data[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alaw_dec>:
  endbr64
  test   %edx,%edx
  jle    L5
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L14:
  movzbl (%r12,%rbx,1),%edi
  call   <alaw_to_s16@plt>
  mov    %ax,0x0(%r13,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
void alaw_dec(char *alaw_data, char *s16_data, int limit) {
  int i;
  for (i = 0; i < limit; i++) {
    ((signed short *)s16_data)[i] = alaw_to_s16((unsigned char)alaw_data[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Simple_ReportScanHit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D35(%rip),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L15
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L3
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L3
L15:
  mov    D36(%rip),%eax
  cmp    $0xffffffff,%eax
  je     L58
  mov    D35(%rip),%eax
  cmp    $0xffffffff,%eax
  je     L58
  mov    D87(%rip),%rcx
  mov    D36(%rip),%edx
  mov    D35(%rip),%eax
  mov    -0x18(%rbp),%r8
  movq   %rcx,%xmm0
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%r8
L58:
  mov    -0x8(%rbp),%eax
  mov    %eax,D37(%rip)
  mov    -0x4(%rbp),%eax
  mov    %eax,D37(%rip)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,D37(%rip)
  jmp    L69
L3:
  movsd  D37(%rip),%xmm1
  movsd  -0x10(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L69
  mov    -0x8(%rbp),%eax
  mov    %eax,D37(%rip)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,D37(%rip)
L69:
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int Simple_ReportScanHit(int left, int right, double score, int (*print_hit)(int, int, double)) {
  static int oldleft = -1;
  static int oldright = -1;
  static double oldscore = -999999.0;
  if (left != oldleft || (left == -1 && right == -1)) {
    if (oldright != -1 && oldleft != -1)
      (*print_hit)(oldleft, oldright, oldscore);
    oldright = right;
    oldleft = left;
    oldscore = score;
  } else if (score > oldscore) {
    oldright = right;
    oldscore = score;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Simple_ReportScanHit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  movq   %xmm0,%r12
  mov    D33(%rip),%edi
  cmp    %ebx,%edi
  je     L13
L3:
  mov    D65(%rip),%esi
  cmp    $0xffffffff,%edi
  je     L59
  cmp    $0xffffffff,%esi
  je     L59
  movsd  D6(%rip),%xmm0
  call   *%rdx
L59:
  mov    %ebp,D7(%rip)
  mov    %ebx,D7(%rip)
  mov    %r12,D7(%rip)
L44:
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %ebx,%eax
  and    %esi,%eax
  cmp    $0xffffffff,%eax
  je     L3
  comisd D7(%rip),%xmm0
  jbe    L44
  mov    %esi,D7(%rip)
  movsd  %xmm0,D7(%rip)
  jmp    L44
```

assistant: ```c
int Simple_ReportScanHit(int left, int right, double score, int (*print_hit)(int, int, double)) {
  static int oldleft = -1;
  static int oldright = -1;
  static double oldscore = -999999.0;
  if (left != oldleft || (left == -1 && right == -1)) {
    if (oldright != -1 && oldleft != -1)
      (*print_hit)(oldleft, oldright, oldscore);
    oldright = right;
    oldleft = left;
    oldscore = score;
  } else if (score > oldscore) {
    oldright = right;
    oldscore = score;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Simple_ReportScanHit>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm1
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    D62(%rip),%edi
  cmp    %ebx,%edi
  je     L25
L0:
  mov    D73(%rip),%esi
  cmp    $0xffffffff,%edi
  je     L7
  cmp    $0xffffffff,%esi
  je     L7
  movsd  %xmm1,0x8(%rsp)
  movsd  D58(%rip),%xmm0
  call   *%rdx
  movsd  0x8(%rsp),%xmm1
L7:
  mov    %ebp,D31(%rip)
  mov    %ebx,D31(%rip)
  movsd  %xmm1,D31(%rip)
L26:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %edi,%eax
  and    %esi,%eax
  cmp    $0xffffffff,%eax
  je     L0
  comisd D31(%rip),%xmm0
  jbe    L26
  mov    %esi,D31(%rip)
  mov    $0x1,%eax
  movsd  %xmm0,D31(%rip)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int Simple_ReportScanHit(int left, int right, double score, int (*print_hit)(int, int, double)) {
  static int oldleft = -1;
  static int oldright = -1;
  static double oldscore = -999999.0;
  if (left != oldleft || (left == -1 && right == -1)) {
    if (oldright != -1 && oldleft != -1)
      (*print_hit)(oldleft, oldright, oldscore);
    oldright = right;
    oldleft = left;
    oldscore = score;
  } else if (score > oldscore) {
    oldright = right;
    oldscore = score;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Simple_ReportScanHit>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm1
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    D56(%rip),%edi
  cmp    %ebx,%edi
  je     L16
L7:
  mov    D13(%rip),%esi
  cmp    $0xffffffff,%edi
  je     L4
  cmp    $0xffffffff,%esi
  je     L4
  movsd  %xmm1,0x8(%rsp)
  movsd  D79(%rip),%xmm0
  call   *%rdx
  movsd  0x8(%rsp),%xmm1
L4:
  mov    %ebp,D64(%rip)
  mov    %ebx,D64(%rip)
  movsd  %xmm1,D64(%rip)
L49:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %edi,%eax
  and    %esi,%eax
  cmp    $0xffffffff,%eax
  je     L7
  comisd D64(%rip),%xmm0
  jbe    L49
  mov    %esi,D64(%rip)
  mov    $0x1,%eax
  movsd  %xmm0,D64(%rip)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int Simple_ReportScanHit(int left, int right, double score, int (*print_hit)(int, int, double)) {
  static int oldleft = -1;
  static int oldright = -1;
  static double oldscore = -999999.0;
  if (left != oldleft || (left == -1 && right == -1)) {
    if (oldright != -1 && oldleft != -1)
      (*print_hit)(oldleft, oldright, oldscore);
    oldright = right;
    oldleft = left;
    oldscore = score;
  } else if (score > oldscore) {
    oldright = right;
    oldscore = score;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L8:
  cmpb   $0x30,-0x1(%rbp)
  jle    L48
  cmpb   $0x79,-0x1(%rbp)
  jg     L48
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L61
L48:
  mov    $0x2e,%edi
  call   <putchar@plt>
L61:
  cmpb   $0x3e,-0x1(%rbp)
  jne    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  jmp    L50
L23:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <readchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jg     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
L50:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: response: 

assistant: ```c
int response(int fd) {
  char c;
  printf("response: ");
  while ((c = readchar(fd)) > 0) {
    if (c > 48 && c < 122)
      printf("%c", c);
    else
      printf(".");
    if (c == '>') {
      printf("\n");
      return 0;
    }
  }
  printf("\n");
  return 1;
}
```