ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lsqe>:
  endbr64
  mov    %edx,%r9d
  test   %edx,%edx
  jle    L13
  cmp    $0x1,%edx
  je     L8
  pxor   %xmm3,%xmm3
  shr    %edx
  xor    %eax,%eax
  movapd %xmm3,%xmm5
  shl    $0x4,%rdx
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm2
L44:
  movupd (%rdi,%rax,1),%xmm0
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm7
  addsd  %xmm2,%xmm4
  unpckhpd %xmm7,%xmm7
  movapd %xmm7,%xmm2
  movupd (%rsi,%rax,1),%xmm7
  addsd  %xmm4,%xmm2
  movsd  (%rsi,%rax,1),%xmm4
  addsd  %xmm1,%xmm4
  movsd  0x8(%rsi,%rax,1),%xmm1
  add    $0x10,%rax
  addsd  %xmm4,%xmm1
  movapd %xmm0,%xmm4
  mulpd  %xmm0,%xmm4
  mulpd  %xmm7,%xmm0
  addsd  %xmm4,%xmm5
  unpckhpd %xmm4,%xmm4
  addsd  %xmm0,%xmm3
  unpckhpd %xmm0,%xmm0
  addsd  %xmm4,%xmm5
  addsd  %xmm0,%xmm3
  cmp    %rdx,%rax
  jne    L44
  mov    %r9d,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%r9b
  je     L46
L5:
  cltq
  movsd  (%rdi,%rax,8),%xmm4
  movsd  (%rsi,%rax,8),%xmm0
  movapd %xmm4,%xmm6
  addsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm6
  mulsd  %xmm4,%xmm0
  addsd  %xmm6,%xmm5
  addsd  %xmm0,%xmm3
L46:
  movapd %xmm1,%xmm6
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm6
  mulsd  %xmm2,%xmm0
L15:
  pxor   %xmm4,%xmm4
  cvtsi2sd %r9d,%xmm4
  divsd  %xmm4,%xmm6
  divsd  %xmm4,%xmm0
  subsd  %xmm6,%xmm3
  subsd  %xmm0,%xmm5
  divsd  %xmm5,%xmm3
  movsd  %xmm3,(%rcx)
  mulsd  %xmm2,%xmm3
  subsd  %xmm3,%xmm1
  divsd  %xmm4,%xmm1
  movsd  %xmm1,(%r8)
  ret
  nopl   0x0(%rax)
L13:
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm6
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm5
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  jmp    L15
L8:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm5
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm2
  jmp    L5
```

assistant: ```c
void lsqe(const double *x, const double *y, int n, double *b1, double *b0) {
  double sumx, sumy, sumx2, sumxy;
  int i;
  sumx = 0.0;
  sumy = 0.0;
  sumx2 = 0.0;
  sumxy = 0.0;
  for (i = 0; i < n; ++i) {
    sumx += x[i];
    sumy += y[i];
    sumx2 += pow(x[i], 2.0);
    sumxy += (x[i] * y[i]);
  }
  *b1 = (sumxy - sumx * sumy / (double)n) / (sumx2 - pow(sumx, 2.0) / (double)n);
  *b0 = (sumy - (*b1 * sumx)) / (double)n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double divide(a, b)
double a;
double b;
{ return a / b; }
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<divide>:
  endbr64
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double divide(a, b)
double a;
double b;
{ return a / b; }
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<divide>:
  endbr64
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double divide(a, b)
double a;
double b;
{ return a / b; }
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<divide>:
  endbr64
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double divide(a, b)
double a;
double b;
{ return a / b; }
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<skiptospace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L3
L39:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L29
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L29
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
L29:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void skiptospace(p) char **p;
{
  while (((int)**p != ' ') && ((int)**p != 9) && (int)**p != '\0')
    *p = *p + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skiptospace>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L29
  cmp    $0x9,%dl
  je     L29
  add    $0x1,%rax
L23:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  je     L29
  cmp    $0x9,%dl
  jne    L23
L29:
  ret
```

assistant: ```c
void skiptospace(p) char **p;
{
  while (((int)**p != ' ') && ((int)**p != 9) && (int)**p != '\0')
    *p = *p + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skiptospace>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L32
  cmp    $0x9,%dl
  je     L32
  add    $0x1,%rax
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L42:
  cmp    $0x9,%dl
  je     L32
L34:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  jne    L42
L32:
  ret
```

assistant: ```c
void skiptospace(p) char **p;
{
  while (((int)**p != ' ') && ((int)**p != 9) && (int)**p != '\0')
    *p = *p + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skiptospace>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L31
  cmp    $0x9,%dl
  je     L31
  add    $0x1,%rax
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L14:
  cmp    $0x9,%dl
  je     L31
L27:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  jne    L14
L31:
  ret
```

assistant: ```c
void skiptospace(p) char **p;
{
  while (((int)**p != ' ') && ((int)**p != 9) && (int)**p != '\0')
    *p = *p + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D17
type_infered: string
name: disassemble_data
arguments: tag: D37
type_infered: string
name: disassemble_data
arguments: tag: D28
type_infered: string
name: disassemble_data
arguments: tag: D33
type_infered: string
name: disassemble_data
arguments: tag: D19
type_infered: string

tool: D14: usage: getsram [opts] addr


tool: D17: 	-c|--chip <chip-id>


tool: D37: 	-l|--length <size to read>


tool: D28:         -n|--occ-channel <chan>


tool: D33: 	-f|--file <filename>


tool: D19:         -v|--version


assistant: ```c
void print_usage(int code) {
  printf("usage: getsram [opts] addr\n");
  printf("	-c|--chip <chip-id>\n");
  printf("	-l|--length <size to read>\n");
  printf("        -n|--occ-channel <chan>\n");
  printf("	-f|--file <filename>\n");
  printf("        -v|--version\n");
  exit(code);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D27
type_infered: string
name: disassemble_data
arguments: tag: D32
type_infered: string
name: disassemble_data
arguments: tag: D20
type_infered: string
name: disassemble_data
arguments: tag: D56
type_infered: string
name: disassemble_data
arguments: tag: D45
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string

tool: D27: usage: getsram [opts] addr


tool: D32: 	-c|--chip <chip-id>


tool: D20: 	-l|--length <size to read>


tool: D56:         -n|--occ-channel <chan>


tool: D45: 	-f|--file <filename>


tool: D13:         -v|--version


assistant: ```c
void print_usage(int code) {
  printf("usage: getsram [opts] addr\n");
  printf("	-c|--chip <chip-id>\n");
  printf("	-l|--length <size to read>\n");
  printf("        -n|--occ-channel <chan>\n");
  printf("	-f|--file <filename>\n");
  printf("        -v|--version\n");
  exit(code);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D45
type: string
name: disassemble_data
arguments: data_label: D32
type: string
name: disassemble_data
arguments: data_label: D51
type: string
name: disassemble_data
arguments: data_label: D39
type: string
name: disassemble_data
arguments: data_label: D29
type: string
name: disassemble_data
arguments: data_label: D9
type: string

tool: D45: usage: getsram [opts] addr


tool: D32: 	-c|--chip <chip-id>


tool: D51: 	-l|--length <size to read>


tool: D39:         -n|--occ-channel <chan>


tool: D29: 	-f|--file <filename>


tool: D9:         -v|--version


assistant: ```c
void print_usage(int code) {
  printf("usage: getsram [opts] addr\n");
  printf("	-c|--chip <chip-id>\n");
  printf("	-l|--length <size to read>\n");
  printf("        -n|--occ-channel <chan>\n");
  printf("	-f|--file <filename>\n");
  printf("        -v|--version\n");
  exit(code);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D7
data_type: string
name: parse_data
arguments: label: D39
data_type: string
name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D32
data_type: string
name: parse_data
arguments: label: D22
data_type: string

tool: D18: usage: getsram [opts] addr


tool: D7: 	-c|--chip <chip-id>


tool: D39: 	-l|--length <size to read>


tool: D5:         -n|--occ-channel <chan>


tool: D32: 	-f|--file <filename>


tool: D22:         -v|--version


assistant: ```c
void print_usage(int code) {
  printf("usage: getsram [opts] addr\n");
  printf("	-c|--chip <chip-id>\n");
  printf("	-l|--length <size to read>\n");
  printf("        -n|--occ-channel <chan>\n");
  printf("	-f|--file <filename>\n");
  printf("        -v|--version\n");
  exit(code);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string

tool: D8: argv[%d] = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L19:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L19
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    $0x0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: argv[%d] = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L12
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L15:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L15
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: argv[%d] = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L1
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L17
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: argv[%d] = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("argv[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ighmm_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L29
  movl   $0x1,-0x14(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  jmp    L4
L11:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x15,%edi
  call   <mes_aux@plt>
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: malloc: could not allocate %d bytes


assistant: ```c
void *ighmm_malloc(int bytes) {
  void *res;
  if (bytes <= 0)
    bytes = 1;
  res = malloc(bytes);
  if (res)
    return (res);
  else
    mes_aux((1 | 16 | 4), "malloc: could not allocate %d bytes\n", bytes);
  return (NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ighmm_malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  mov    $0x1,%eax
  cmovg  %edi,%eax
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L13
L2:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    %ebx,%edx
  lea    D8(%rip),%rsi
  mov    $0x15,%edi
  call   <mes_aux@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: malloc: could not allocate %d bytes


assistant: ```c
void *ighmm_malloc(int bytes) {
  void *res;
  if (bytes <= 0)
    bytes = 1;
  res = malloc(bytes);
  if (res)
    return (res);
  else
    mes_aux((1 | 16 | 4), "malloc: could not allocate %d bytes\n", bytes);
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ighmm_malloc>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  push   %r12
  sub    $0x8,%rsp
  test   %edi,%edi
  cmovg  %edi,%eax
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L4
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    %r12d,%edx
  lea    D4(%rip),%rsi
  mov    $0x15,%edi
  call   <mes_aux@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: malloc: could not allocate %d bytes


assistant: ```c
void *ighmm_malloc(int bytes) {
  void *res;
  if (bytes <= 0)
    bytes = 1;
  res = malloc(bytes);
  if (res)
    return (res);
  else
    mes_aux((1 | 16 | 4), "malloc: could not allocate %d bytes\n", bytes);
  return (NULL);
}
```
user: What is the c source code of the assembly code below:

```asm
<ighmm_malloc>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  push   %r12
  sub    $0x8,%rsp
  test   %edi,%edi
  cmovg  %edi,%eax
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L4
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    %r12d,%edx
  lea    D2(%rip),%rsi
  mov    $0x15,%edi
  call   <mes_aux@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: malloc: could not allocate %d bytes


assistant: ```c
void *ighmm_malloc(int bytes) {
  void *res;
  if (bytes <= 0)
    bytes = 1;
  res = malloc(bytes);
  if (res)
    return (res);
  else
    mes_aux((1 | 16 | 4), "malloc: could not allocate %d bytes\n", bytes);
  return (NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  jmp    L51
L54:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L66
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
L66:
  addl   $0x1,-0x24(%rbp)
L51:
  cmpl   $0xf,-0x24(%rbp)
  jle    L54
  movl   $0x0,-0x24(%rbp)
  jmp    L40
L9:
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  lea    0x1(%rax),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x24(%rbp)
L40:
  cmpl   $0xf,-0x24(%rbp)
  jle    L9
  movl   $0x0,-0x24(%rbp)
  jmp    L86
L0:
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  movzbl %al,%ecx
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  cmp    %eax,%ecx
  je     L27
  mov    $0x0,%eax
  call   <abort@plt>
L27:
  addl   $0x1,-0x24(%rbp)
L86:
  cmpl   $0xf,-0x24(%rbp)
  jle    L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
__attribute__((no)) int main1() {
  union {
    unsigned char a[16] __attribute__((__aligned__(16)));
    unsigned char b[16] __attribute__((__aligned__(16)));
  } s;
  int i;
  for (i = 0; i < 16; i++) {
    s.b[i] = 3 * i;
    if (i % 3 == 0)
      s.b[i] = 3 * i;
  }
  for (i = 0; i < 16; i++) {
    s.a[i] = s.b[i] + 1;
  }
  for (i = 0; i < 16; i++) {
    if (s.a[i] != 3 * i + 1)
      abort();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x10(%rsp),%rbp
  mov    %rbx,%rax
  mov    $0x0,%edx
L63:
  mov    %dl,(%rax)
  add    $0x3,%edx
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L63
  mov    %rbx,%rax
L49:
  addb   $0x1,(%rax)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L49
  mov    $0x1,%r12d
  jmp    L33
L46:
  add    $0x1,%rbx
  add    $0x3,%r12d
  cmp    %rbp,%rbx
  je     L42
L33:
  movzbl (%rbx),%eax
  cmp    %r12d,%eax
  je     L46
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L46
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no)) int main1() {
  union {
    unsigned char a[16] __attribute__((__aligned__(16)));
    unsigned char b[16] __attribute__((__aligned__(16)));
  } s;
  int i;
  for (i = 0; i < 16; i++) {
    s.b[i] = 3 * i;
    if (i % 3 == 0)
      s.b[i] = 3 * i;
  }
  for (i = 0; i < 16; i++) {
    s.a[i] = s.b[i] + 1;
  }
  for (i = 0; i < 16; i++) {
    if (s.a[i] != 3 * i + 1)
      abort();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main1>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x10(%rsp),%r12
  mov    %rbx,%rax
  nopl   0x0(%rax)
L26:
  mov    %dl,(%rax)
  add    $0x1,%rax
  add    $0x3,%edx
  cmp    %r12,%rax
  jne    L26
  mov    %rbx,%rax
  nopl   0x0(%rax)
L41:
  addb   $0x1,(%rax)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L41
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L10:
  movzbl (%rbx),%eax
  cmp    %ebp,%eax
  je     L36
  xor    %eax,%eax
  call   <abort@plt>
L36:
  add    $0x1,%rbx
  add    $0x3,%ebp
  cmp    %r12,%rbx
  jne    L10
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no)) int main1() {
  union {
    unsigned char a[16] __attribute__((__aligned__(16)));
    unsigned char b[16] __attribute__((__aligned__(16)));
  } s;
  int i;
  for (i = 0; i < 16; i++) {
    s.b[i] = 3 * i;
    if (i % 3 == 0)
      s.b[i] = 3 * i;
  }
  for (i = 0; i < 16; i++) {
    s.a[i] = s.b[i] + 1;
  }
  for (i = 0; i < 16; i++) {
    if (s.a[i] != 3 * i + 1)
      abort();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main1>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((no)) int main1() {
  union {
    unsigned char a[16] __attribute__((__aligned__(16)));
    unsigned char b[16] __attribute__((__aligned__(16)));
  } s;
  int i;
  for (i = 0; i < 16; i++) {
    s.b[i] = 3 * i;
    if (i % 3 == 0)
      s.b[i] = 3 * i;
  }
  for (i = 0; i < 16; i++) {
    s.a[i] = s.b[i] + 1;
  }
  for (i = 0; i < 16; i++) {
    if (s.a[i] != 3 * i + 1)
      abort();
  }
  return 0;
}
```