ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<tplt_xfer>:
  endbr64
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L14:
  cmpb   $0x25,(%rsp)
  jne    L7
  cmpb   $0x25,0x1(%rsp)
  je     L21
L7:
  addl   $0x1,(%rbx)
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fprintf@plt>
L36:
  mov    %r12,%rdx
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L14
L21:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x3f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: %s

assistant: ```c
void tplt_xfer(FILE *in, FILE *out, int *lineno) {
  int iStart;
  char line[1000];
  while (fgets(line, 1000, in) && (line[0] != '%' || line[1] != '%')) {
    (*lineno)++;
    iStart = 0;
    fprintf(out, "%s", &line[iStart]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<esum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L15
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L73
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,D63(%rip)
  movsd  D63(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L13
  mov    D63(%rip),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,D47(%rip)
  movsd  D47(%rip),%xmm0
  jmp    L87
L15:
  nop
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jg     L53
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,D71(%rip)
  movsd  D71(%rip),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L76
  mov    D71(%rip),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,D71(%rip)
  movsd  D71(%rip),%xmm0
  jmp    L87
L73:
  nop
  jmp    L6
L13:
  nop
  jmp    L6
L53:
  nop
  jmp    L6
L76:
  nop
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,D71(%rip)
  mov    D71(%rip),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,D71(%rip)
  movsd  D71(%rip),%xmm0
L87:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double esum(int *mu, double *x) {
  static double esum, w;
  if (*x > 0.0e0)
    goto S10;
  if (*mu < 0)
    goto S20;
  w = (double)*mu + *x;
  if (w > 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S10:
  if (*mu > 0)
    goto S20;
  w = (double)*mu + *x;
  if (w < 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S20:
  w = *mu;
  esum = exp(w) * exp(*x);
  return esum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<esum>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rbx
  movq   %rbx,%xmm2
  comisd D7(%rip),%xmm2
  ja     L16
  mov    (%rdi),%eax
  test   %eax,%eax
  js     L35
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm2,%xmm0
  comisd D7(%rip),%xmm0
  jbe    L49
L35:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi),%xmm0
  call   <exp@plt>
  movq   %xmm0,%r14
  movq   %rbx,%xmm0
  call   <exp@plt>
  movq   %r14,%xmm3
  mulsd  %xmm3,%xmm0
L58:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
L16:
  mov    (%rdi),%eax
  test   %eax,%eax
  jg     L35
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L35
  call   <exp@plt>
  jmp    L58
L49:
  call   <exp@plt>
  jmp    L58
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: f64

tool: D7: 0

assistant: ```c
double esum(int *mu, double *x) {
  static double esum, w;
  if (*x > 0.0e0)
    goto S10;
  if (*mu < 0)
    goto S20;
  w = (double)*mu + *x;
  if (w > 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S10:
  if (*mu > 0)
    goto S20;
  w = (double)*mu + *x;
  if (w < 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S20:
  w = *mu;
  esum = exp(w) * exp(*x);
  return esum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<esum>:
  endbr64
  movsd  (%rsi),%xmm1
  pxor   %xmm0,%xmm0
  mov    (%rdi),%eax
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm1
  cvtsi2sd %eax,%xmm2
  ja     L21
  test   %eax,%eax
  js     L26
  movapd %xmm1,%xmm3
  addsd  %xmm2,%xmm3
  comisd %xmm0,%xmm3
  jbe    L9
L26:
  sub    $0x18,%rsp
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  mulsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
  nop
L21:
  test   %eax,%eax
  jg     L26
  movapd %xmm1,%xmm3
  addsd  %xmm2,%xmm3
  comisd %xmm3,%xmm0
  ja     L26
L9:
  movapd %xmm3,%xmm0
  jmp    1050 <exp@plt>
```

assistant: ```c
double esum(int *mu, double *x) {
  static double esum, w;
  if (*x > 0.0e0)
    goto S10;
  if (*mu < 0)
    goto S20;
  w = (double)*mu + *x;
  if (w > 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S10:
  if (*mu > 0)
    goto S20;
  w = (double)*mu + *x;
  if (w < 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S20:
  w = *mu;
  esum = exp(w) * exp(*x);
  return esum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<esum>:
  endbr64
  movsd  (%rsi),%xmm1
  pxor   %xmm0,%xmm0
  mov    (%rdi),%eax
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm1
  cvtsi2sd %eax,%xmm2
  ja     L9
  test   %eax,%eax
  js     L7
  movapd %xmm1,%xmm3
  addsd  %xmm2,%xmm3
  comisd %xmm0,%xmm3
  jbe    L33
L7:
  sub    $0x18,%rsp
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  mulsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
  nop
L9:
  test   %eax,%eax
  jg     L7
  movapd %xmm1,%xmm3
  addsd  %xmm2,%xmm3
  comisd %xmm3,%xmm0
  ja     L7
L33:
  movapd %xmm3,%xmm0
  jmp    1050 <exp@plt>
```

assistant: ```c
double esum(int *mu, double *x) {
  static double esum, w;
  if (*x > 0.0e0)
    goto S10;
  if (*mu < 0)
    goto S20;
  w = (double)*mu + *x;
  if (w > 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S10:
  if (*mu > 0)
    goto S20;
  w = (double)*mu + *x;
  if (w < 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S20:
  w = *mu;
  esum = exp(w) * exp(*x);
  return esum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L24:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L14:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  movl   $0x0,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
  mov    $0xa,%edi
  call   <ft_putchar@plt>
L6:
  cmpl   $0x0,-0x8(%rbp)
  jg     L14
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  int j;
  i = argc - 1;
  j = 0;
  while (i > 0) {
    while (argv[i][j])
      ft_putchar(argv[i][j++]);
    j = 0;
    i--;
    ft_putchar('\n');
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %eax,%eax
  jle    L11
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cltq
  shl    $0x3,%rax
  lea    (%rsi,%rax,1),%r12
  lea    -0x8(%rsi,%rax,1),%r13
  lea    -0x2(%rdi),%eax
  shl    $0x3,%rax
  sub    %rax,%r13
  jmp    L1
L17:
  movsbl %dil,%edi
  call   <ft_putchar@plt>
  mov    0x0(%rbp),%rax
  movzbl (%rax,%rbx,1),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L17
L56:
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  sub    $0x8,%r12
  cmp    %r13,%r12
  je     L40
L1:
  mov    %r12,%rbp
  mov    (%r12),%rax
  movzbl (%rax),%edi
  mov    $0x1,%ebx
  test   %dil,%dil
  jne    L17
  jmp    L56
L40:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  int j;
  i = argc - 1;
  j = 0;
  while (i > 0) {
    while (argv[i][j])
      ft_putchar(argv[i][j++]);
    j = 0;
    i--;
    ft_putchar('\n');
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %eax,%eax
  jle    L26
  cltq
  push   %r12
  shl    $0x3,%rax
  push   %rbp
  lea    -0x8(%rsi,%rax,1),%r12
  lea    (%rsi,%rax,1),%rbp
  push   %rbx
  lea    -0x2(%rdi),%eax
  shl    $0x3,%rax
  sub    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L33:
  mov    0x0(%rbp),%rax
  mov    $0x1,%ebx
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L0
  nopl   0x0(%rax)
L3:
  call   <ft_putchar@plt>
  mov    0x0(%rbp),%rax
  movsbl (%rax,%rbx,1),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
L0:
  mov    $0xa,%edi
  sub    $0x8,%rbp
  call   <ft_putchar@plt>
  cmp    %r12,%rbp
  jne    L33
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  int j;
  i = argc - 1;
  j = 0;
  while (i > 0) {
    while (argv[i][j])
      ft_putchar(argv[i][j++]);
    j = 0;
    i--;
    ft_putchar('\n');
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %eax,%eax
  jle    L20
  cltq
  push   %r12
  shl    $0x3,%rax
  push   %rbp
  lea    -0x8(%rsi,%rax,1),%r12
  lea    (%rsi,%rax,1),%rbp
  push   %rbx
  lea    -0x2(%rdi),%eax
  shl    $0x3,%rax
  sub    %rax,%r12
  nopl   0x0(%rax,%rax,1)
L6:
  mov    0x0(%rbp),%rax
  mov    $0x1,%ebx
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L13
  nopl   0x0(%rax)
L1:
  call   <ft_putchar@plt>
  mov    0x0(%rbp),%rax
  movsbl (%rax,%rbx,1),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
L13:
  mov    $0xa,%edi
  sub    $0x8,%rbp
  call   <ft_putchar@plt>
  cmp    %r12,%rbp
  jne    L6
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  int j;
  i = argc - 1;
  j = 0;
  while (i > 0) {
    while (argv[i][j])
      ft_putchar(argv[i][j++]);
    j = 0;
    i--;
    ft_putchar('\n');
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SelectionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L23
L10:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L11
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L18
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L18:
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L12
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <PrintVet@plt>
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void SelectionSort(int *vet, int ini, int fim) {
  int i, j, small, small_ind;
  for (i = ini; i < fim; i++) {
    small = vet[i];
    small_ind = i;
    for (j = i; j < fim; j++) {
      if (vet[j] < small) {
        small = vet[j];
        small_ind = j;
      }
    }
    vet[small_ind] = vet[i];
    vet[i] = small;
    PrintVet(vet, ini, fim);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SelectionSort>:
  endbr64
  cmp    %edx,%esi
  jge    L54
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %edx,%ebp
  movslq %esi,%r12
  lea    -0x1(%rdx),%eax
  sub    %esi,%eax
  lea    0x1(%r12,%rax,1),%r14
  jmp    L10
L25:
  add    $0x1,%rax
L71:
  mov    %eax,%esi
  cmp    %eax,%ebp
  jle    L79
  mov    (%rbx,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L25
  mov    %esi,%edi
  mov    %edx,%ecx
  jmp    L25
L48:
  mov    %r8d,%ecx
L79:
  movslq %edi,%rdi
  mov    %r8d,(%rbx,%rdi,4)
  mov    %ecx,(%rbx,%r12,4)
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <PrintVet@plt>
  add    $0x1,%r12
  cmp    %r14,%r12
  je     L76
L10:
  mov    %r12d,%edi
  mov    (%rbx,%r12,4),%r8d
  cmp    %r12d,%ebp
  jle    L48
  lea    0x1(%r12),%eax
  cltq
  mov    %r8d,%ecx
  jmp    L71
L76:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L54:
  ret
```

assistant: ```c
void SelectionSort(int *vet, int ini, int fim) {
  int i, j, small, small_ind;
  for (i = ini; i < fim; i++) {
    small = vet[i];
    small_ind = i;
    for (j = i; j < fim; j++) {
      if (vet[j] < small) {
        small = vet[j];
        small_ind = j;
      }
    }
    vet[small_ind] = vet[i];
    vet[i] = small;
    PrintVet(vet, ini, fim);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SelectionSort>:
  endbr64
  cmp    %edx,%esi
  jge    L59
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  sub    %esi,%r12d
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  movslq %esi,%rdi
  lea    0x1(%rdi),%r13
  add    %r13,%r12
  nopl   (%rax)
L32:
  mov    (%rbx,%rdi,4),%r8d
  movslq %edi,%rsi
  mov    %rdi,%rax
  mov    %r8d,%edx
  mov    %r8d,%ecx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L30:
  mov    (%rbx,%rax,4),%edx
L27:
  cmp    %ecx,%edx
  jge    L22
  movslq %eax,%rsi
  mov    %edx,%ecx
L22:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L30
  mov    %r8d,(%rbx,%rsi,4)
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %ecx,(%rbx,%rdi,4)
  mov    %rbx,%rdi
  call   <PrintVet@plt>
  mov    %r13,%rdi
  cmp    %r12,%r13
  je     L49
  add    $0x1,%r13
  jmp    L32
  xchg   %ax,%ax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  ret
```

assistant: ```c
void SelectionSort(int *vet, int ini, int fim) {
  int i, j, small, small_ind;
  for (i = ini; i < fim; i++) {
    small = vet[i];
    small_ind = i;
    for (j = i; j < fim; j++) {
      if (vet[j] < small) {
        small = vet[j];
        small_ind = j;
      }
    }
    vet[small_ind] = vet[i];
    vet[i] = small;
    PrintVet(vet, ini, fim);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SelectionSort>:
  endbr64
  cmp    %edx,%esi
  jge    L37
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  sub    %esi,%r12d
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  movslq %esi,%rdi
  lea    0x1(%rdi),%r13
  add    %r13,%r12
  nopl   (%rax)
L25:
  mov    (%rbx,%rdi,4),%r8d
  movslq %edi,%rsi
  mov    %rdi,%rax
  mov    %r8d,%ecx
  nopl   (%rax)
L2:
  mov    (%rbx,%rax,4),%edx
  cmp    %edx,%ecx
  jle    L8
  movslq %eax,%rsi
  mov    %edx,%ecx
L8:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L2
  mov    %r8d,(%rbx,%rsi,4)
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %ecx,(%rbx,%rdi,4)
  mov    %rbx,%rdi
  call   <PrintVet@plt>
  mov    %r13,%rdi
  cmp    %r12,%r13
  je     L49
  add    $0x1,%r13
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  ret
```

assistant: ```c
void SelectionSort(int *vet, int ini, int fim) {
  int i, j, small, small_ind;
  for (i = ini; i < fim; i++) {
    small = vet[i];
    small_ind = i;
    for (j = i; j < fim; j++) {
      if (vet[j] < small) {
        small = vet[j];
        small_ind = j;
      }
    }
    vet[small_ind] = vet[i];
    vet[i] = small;
    PrintVet(vet, ini, fim);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L4:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
L5:
  cmpl   $0x9,-0x8(%rbp)
  jle    L4
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  i = 0;
  j = 0;
  while (i < 10) {
    j += ++i;
  }
  return i + j;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x41,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  i = 0;
  j = 0;
  while (i < 10) {
    j += ++i;
  }
  return i + j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x41,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  i = 0;
  j = 0;
  while (i < 10) {
    j += ++i;
  }
  return i + j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x41,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  i = 0;
  j = 0;
  while (i < 10) {
    j += ++i;
  }
  return i + j;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<msr_encode_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L10
  mov    $0x0,%eax
  jmp    L42
L10:
  cmpq   $0x0,-0x18(%rbp)
  je     L23
  cmpq   $0x0,-0x28(%rbp)
  je     L23
  cmpl   $0x0,-0x20(%rbp)
  jg     L7
L23:
  mov    $0xffffffff,%eax
  jmp    L42
L7:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jle    L32
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
L32:
  mov    -0x4(%rbp),%eax
L42:
  leave
  ret
```

assistant: ```c
int msr_encode_text(char *input, int samplecount, char *output, int outputlength) {
  int length;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  length = (samplecount < outputlength) ? samplecount : outputlength;
  memcpy(output, input, length);
  outputlength -= length;
  if (outputlength > 0)
    memset(output + length, 0, outputlength);
  return length;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<msr_encode_text>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r12d
  test   %esi,%esi
  jle    L51
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  test   %rdx,%rdx
  sete   %al
  test   %ecx,%ecx
  setle  %dl
  or     %dl,%al
  jne    L4
  test   %rdi,%rdi
  je     L4
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  mov    %esi,%r12d
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  sub    %r12d,%ebx
  test   %ebx,%ebx
  jg     L33
L51:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %ebx,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  jmp    L51
L4:
  mov    $0xffffffff,%r12d
  jmp    L51
```

assistant: ```c
int msr_encode_text(char *input, int samplecount, char *output, int outputlength) {
  int length;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  length = (samplecount < outputlength) ? samplecount : outputlength;
  memcpy(output, input, length);
  outputlength -= length;
  if (outputlength > 0)
    memset(output + length, 0, outputlength);
  return length;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<msr_encode_text>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L24
  test   %rdx,%rdx
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  sete   %al
  test   %ecx,%ecx
  setle  %dl
  or     %dl,%al
  jne    L26
  test   %rdi,%rdi
  je     L26
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  mov    %esi,%r12d
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  sub    %r12d,%ebx
  mov    %ebx,%edx
  test   %ebx,%ebx
  jg     L20
L24:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L20:
  movslq %r12d,%rax
  xor    %esi,%esi
  lea    0x0(%rbp,%rax,1),%rdi
  call   <memset@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0xffffffff,%r12d
  jmp    L24
```

assistant: ```c
int msr_encode_text(char *input, int samplecount, char *output, int outputlength) {
  int length;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  length = (samplecount < outputlength) ? samplecount : outputlength;
  memcpy(output, input, length);
  outputlength -= length;
  if (outputlength > 0)
    memset(output + length, 0, outputlength);
  return length;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<msr_encode_text>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  test   %rdx,%rdx
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  sete   %al
  test   %ecx,%ecx
  setle  %dl
  or     %dl,%al
  jne    L32
  test   %rdi,%rdi
  je     L32
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  mov    %esi,%r12d
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  sub    %r12d,%ebx
  mov    %ebx,%edx
  test   %ebx,%ebx
  jg     L49
L16:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L49:
  movslq %r12d,%rax
  xor    %esi,%esi
  lea    0x0(%rbp,%rax,1),%rdi
  call   <memset@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    $0xffffffff,%r12d
  jmp    L16
```

assistant: ```c
int msr_encode_text(char *input, int samplecount, char *output, int outputlength) {
  int length;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  length = (samplecount < outputlength) ? samplecount : outputlength;
  memcpy(output, input, length);
  outputlength -= length;
  if (outputlength > 0)
    memset(output + length, 0, outputlength);
  return length;
}
```