ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<grep_equal>:
  endbr64
  mov    %rsi,%rax
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L26
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x8(%rax),%rbx
L13:
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  je     L29
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rsi
  test   %rsi,%rsi
  jne    L13
  mov    $0x0,%eax
  jmp    L14
L26:
  mov    $0x0,%eax
  ret
L29:
  mov    $0x1,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int grep_equal(char *input, char *compare[]) {
  int i;
  for (i = 0; compare[i]; i++) {
    if (!strcasecmp(input, compare[i])) {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<grep_equal>:
  endbr64
  mov    %rsi,%rax
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L9
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x8(%rax),%rbx
  sub    $0x8,%rsp
  jmp    L12
  xchg   %ax,%ax
L10:
  mov    (%rbx),%rsi
  add    $0x8,%rbx
  test   %rsi,%rsi
  je     L39
L12:
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  jne    L10
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L39:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int grep_equal(char *input, char *compare[]) {
  int i;
  for (i = 0; compare[i]; i++) {
    if (!strcasecmp(input, compare[i])) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<grep_equal>:
  endbr64
  mov    %rsi,%rax
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x8(%rax),%rbx
  sub    $0x8,%rsp
  jmp    L13
  xchg   %ax,%ax
L22:
  mov    (%rbx),%rsi
  add    $0x8,%rbx
  test   %rsi,%rsi
  je     L29
L13:
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  jne    L22
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int grep_equal(char *input, char *compare[]) {
  int i;
  for (i = 0; compare[i]; i++) {
    if (!strcasecmp(input, compare[i])) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L2
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x18(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    -0x28(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rax,%rdi
  call   <xml_utf8_decode@plt>
  mov    %rax,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D9: ISO-8859-1

assistant: ```c
char *utf8_decode(const char *str) {
  char *out;
  if (strlen(str)) {
    int alen, len;
    alen = strlen(str);
    out = xml_utf8_decode(str, alen, &len, "ISO-8859-1");
  }
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utf8_decode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jne    L19
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    0x4(%rsp),%rdx
  lea    D4(%rip),%rcx
  mov    %rbx,%rdi
  call   <xml_utf8_decode@plt>
  mov    %rax,%rbp
  jmp    L20
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: ISO-8859-1

assistant: ```c
char *utf8_decode(const char *str) {
  char *out;
  if (strlen(str)) {
    int alen, len;
    alen = strlen(str);
    out = xml_utf8_decode(str, alen, &len, "ISO-8859-1");
  }
  return out;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<utf8_decode>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jne    L19
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x4(%rsp),%rdx
  lea    D0(%rip),%rcx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <xml_utf8_decode@plt>
  mov    %rax,%r12
  jmp    L17
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: ISO-8859-1

assistant: ```c
char *utf8_decode(const char *str) {
  char *out;
  if (strlen(str)) {
    int alen, len;
    alen = strlen(str);
    out = xml_utf8_decode(str, alen, &len, "ISO-8859-1");
  }
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<utf8_decode>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jne    L28
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x4(%rsp),%rdx
  lea    D5(%rip),%rcx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <xml_utf8_decode@plt>
  mov    %rax,%r12
  jmp    L4
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string

tool: D5: ISO-8859-1

assistant: ```c
char *utf8_decode(const char *str) {
  char *out;
  if (strlen(str)) {
    int alen, len;
    alen = strlen(str);
    out = xml_utf8_decode(str, alen, &len, "ISO-8859-1");
  }
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<all_leds_off>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7f008824,%eax
  mov    (%rax),%eax
  mov    $0x7f008824,%edx
  or     $0xf,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void all_leds_off(void) {
  (*(volatile unsigned int *)(0x7F008824)) |= 0xF;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<all_leds_off>:
  endbr64
  mov    0x7f008824,%eax
  or     $0xf,%eax
  mov    %eax,0x7f008824
  ret
```

assistant: ```c
void all_leds_off(void) {
  (*(volatile unsigned int *)(0x7F008824)) |= 0xF;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<all_leds_off>:
  endbr64
  mov    0x7f008824,%eax
  or     $0xf,%eax
  mov    %eax,0x7f008824
  ret
```

assistant: ```c
void all_leds_off(void) {
  (*(volatile unsigned int *)(0x7F008824)) |= 0xF;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<all_leds_off>:
  endbr64
  mov    0x7f008824,%eax
  or     $0xf,%eax
  mov    %eax,0x7f008824
  ret
```

assistant: ```c
void all_leds_off(void) {
  (*(volatile unsigned int *)(0x7F008824)) |= 0xF;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<srcu_read_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__srcu_read_unlock@plt>
  nop
  leave
  ret
```

assistant: ```c
void srcu_read_unlock(struct srcu_struct *sp, int idx) {
  do {
  } while (0);
  __srcu_read_unlock(sp, idx);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<srcu_read_unlock>:
  endbr64
  sub    $0x8,%rsp
  call   <__srcu_read_unlock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void srcu_read_unlock(struct srcu_struct *sp, int idx) {
  do {
  } while (0);
  __srcu_read_unlock(sp, idx);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<srcu_read_unlock>:
  endbr64
  jmp    1050 <__srcu_read_unlock@plt>
```

assistant: ```c
void srcu_read_unlock(struct srcu_struct *sp, int idx) {
  do {
  } while (0);
  __srcu_read_unlock(sp, idx);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<srcu_read_unlock>:
  endbr64
  jmp    1050 <__srcu_read_unlock@plt>
```

assistant: ```c
void srcu_read_unlock(struct srcu_struct *sp, int idx) {
  do {
  } while (0);
  __srcu_read_unlock(sp, idx);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <error_init@plt>
  mov    $0x0,%eax
  call   <__streams_init@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <main@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void _start(int argc, char *argv[], char *envp[]) {
  int ret;
  error_init();
  __streams_init();
  ret = main(argc, argv, envp);
  _exit(ret);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_start>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x0,%eax
  call   <error_init@plt>
  mov    $0x0,%eax
  call   <__streams_init@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <main@plt>
  mov    %eax,%edi
  call   <_exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _start(int argc, char *argv[], char *envp[]) {
  int ret;
  error_init();
  __streams_init();
  ret = main(argc, argv, envp);
  _exit(ret);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_start>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  call   <error_init@plt>
  xor    %eax,%eax
  call   <__streams_init@plt>
  mov    %ebp,%edi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <main@plt>
  pop    %rbp
  pop    %r12
  mov    %eax,%edi
  pop    %r13
  jmp    1080 <_exit@plt>
```

assistant: ```c
void _start(int argc, char *argv[], char *envp[]) {
  int ret;
  error_init();
  __streams_init();
  ret = main(argc, argv, envp);
  _exit(ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_start>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  call   <error_init@plt>
  xor    %eax,%eax
  call   <__streams_init@plt>
  mov    %ebp,%edi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <main@plt>
  pop    %rbp
  pop    %r12
  mov    %eax,%edi
  pop    %r13
  jmp    1080 <_exit@plt>
```

assistant: ```c
void _start(int argc, char *argv[], char *envp[]) {
  int ret;
  error_init();
  __streams_init();
  ret = main(argc, argv, envp);
  _exit(ret);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<init_adaptor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1e0,%esi
  mov    $0x2a0,%edi
  call   <simgraph_init@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: Preparing display ...


assistant: ```c
int init_adaptor() {
  printf("Preparing display ...\n");
  simgraph_init(672, 480);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<init_adaptor>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e0,%esi
  mov    $0x2a0,%edi
  call   <simgraph_init@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Preparing display ...


assistant: ```c
int init_adaptor() {
  printf("Preparing display ...\n");
  simgraph_init(672, 480);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<init_adaptor>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e0,%esi
  mov    $0x2a0,%edi
  call   <simgraph_init@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: Preparing display ...


assistant: ```c
int init_adaptor() {
  printf("Preparing display ...\n");
  simgraph_init(672, 480);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<init_adaptor>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e0,%esi
  mov    $0x2a0,%edi
  call   <simgraph_init@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: Preparing display ...


assistant: ```c
int init_adaptor() {
  printf("Preparing display ...\n");
  simgraph_init(672, 480);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBIntEnableControl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  test   %eax,%eax
  je     L12
  mov    -0x4(%rbp),%eax
  add    $0xb,%eax
  cltq
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0xb,%eax
  cltq
  mov    %dl,(%rax)
L12:
  mov    -0x8(%rbp),%eax
  and    $0x100,%eax
  test   %eax,%eax
  je     L21
  mov    -0x4(%rbp),%eax
  add    $0x408,%eax
  cltq
  movq   $0x1,(%rax)
L21:
  mov    -0x8(%rbp),%eax
  and    $0x200,%eax
  test   %eax,%eax
  je     L20
  mov    $0x40050448,%eax
  movq   $0x1,(%rax)
L20:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBIntEnableControl(uint32_t ui32Base, uint32_t ui32Flags) {
  ;
  ;
  if (ui32Flags & 0x000000FF) {
    (*((volatile unsigned char *)(ui32Base + 0x0000000B))) |= ui32Flags;
  }
  if (ui32Flags & 0x00000100) {
    (*((volatile unsigned long *)(ui32Base + 0x00000408))) = 0x00000001;
  }
  if (ui32Flags & 0x00000200) {
    (*((volatile unsigned long *)(0x40050000 + 0x00000448))) = 0x00000001;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<USBIntEnableControl>:
  endbr64
  test   %sil,%sil
  je     L18
  lea    0xb(%rdi),%eax
  cltq
  movzbl (%rax),%edx
  or     %esi,%edx
  mov    %dl,(%rax)
L18:
  test   $0x100,%esi
  je     L8
  add    $0x408,%edi
  movslq %edi,%rdi
  movq   $0x1,(%rdi)
L8:
  test   $0x200,%esi
  je     L0
  movq   $0x1,0x40050448
L0:
  ret
```

assistant: ```c
void USBIntEnableControl(uint32_t ui32Base, uint32_t ui32Flags) {
  ;
  ;
  if (ui32Flags & 0x000000FF) {
    (*((volatile unsigned char *)(ui32Base + 0x0000000B))) |= ui32Flags;
  }
  if (ui32Flags & 0x00000100) {
    (*((volatile unsigned long *)(ui32Base + 0x00000408))) = 0x00000001;
  }
  if (ui32Flags & 0x00000200) {
    (*((volatile unsigned long *)(0x40050000 + 0x00000448))) = 0x00000001;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBIntEnableControl>:
  endbr64
  test   %sil,%sil
  je     L12
  lea    0xb(%rdi),%eax
  cltq
  movzbl (%rax),%edx
  or     %esi,%edx
  mov    %dl,(%rax)
L12:
  test   $0x100,%esi
  je     L26
  add    $0x408,%edi
  movslq %edi,%rdi
  movq   $0x1,(%rdi)
L26:
  and    $0x200,%esi
  je     L21
  movq   $0x1,0x40050448
L21:
  ret
```

assistant: ```c
void USBIntEnableControl(uint32_t ui32Base, uint32_t ui32Flags) {
  ;
  ;
  if (ui32Flags & 0x000000FF) {
    (*((volatile unsigned char *)(ui32Base + 0x0000000B))) |= ui32Flags;
  }
  if (ui32Flags & 0x00000100) {
    (*((volatile unsigned long *)(ui32Base + 0x00000408))) = 0x00000001;
  }
  if (ui32Flags & 0x00000200) {
    (*((volatile unsigned long *)(0x40050000 + 0x00000448))) = 0x00000001;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<USBIntEnableControl>:
  endbr64
  test   %sil,%sil
  je     L23
  lea    0xb(%rdi),%eax
  cltq
  movzbl (%rax),%edx
  or     %esi,%edx
  mov    %dl,(%rax)
L23:
  test   $0x100,%esi
  je     L9
  add    $0x408,%edi
  movslq %edi,%rdi
  movq   $0x1,(%rdi)
L9:
  and    $0x200,%esi
  je     L12
  movq   $0x1,0x40050448
L12:
  ret
```

assistant: ```c
void USBIntEnableControl(uint32_t ui32Base, uint32_t ui32Flags) {
  ;
  ;
  if (ui32Flags & 0x000000FF) {
    (*((volatile unsigned char *)(ui32Base + 0x0000000B))) |= ui32Flags;
  }
  if (ui32Flags & 0x00000100) {
    (*((volatile unsigned long *)(ui32Base + 0x00000408))) = 0x00000001;
  }
  if (ui32Flags & 0x00000200) {
    (*((volatile unsigned long *)(0x40050000 + 0x00000448))) = 0x00000001;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<libjte_decide_file_jigdo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x48(%rbp),%rdi
  lea    -0x10(%rbp),%rcx
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <list_file_in_jigdo@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L28
  mov    -0x14(%rbp),%eax
  jmp    L30
L28:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L41
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <libjte_report_no_mem@plt>
  mov    $0xffffffff,%eax
  jmp    L30
L41:
  mov    $0x1,%eax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
int libjte_decide_file_jigdo(struct libjte_env *o, char *filename, off_t size, char **mirror_name, unsigned char md5[16]) {
  int ret;
  char *md5_name;
  *mirror_name = NULL;
  ret = list_file_in_jigdo(o, filename, size, &md5_name, md5);
  if (ret <= 0)
    return ret;
  *mirror_name = strdup(md5_name);
  if (*mirror_name == NULL) {
    libjte_report_no_mem(o, strlen(md5_name) + 1, 0);
    return -1;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<libjte_decide_file_jigdo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rcx)
  mov    %rsp,%rcx
  call   <list_file_in_jigdo@plt>
  test   %eax,%eax
  jle    L39
  mov    (%rsp),%r12
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L25
  mov    $0x1,%eax
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <libjte_report_no_mem@plt>
  mov    $0xffffffff,%eax
  jmp    L39
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int libjte_decide_file_jigdo(struct libjte_env *o, char *filename, off_t size, char **mirror_name, unsigned char md5[16]) {
  int ret;
  char *md5_name;
  *mirror_name = NULL;
  ret = list_file_in_jigdo(o, filename, size, &md5_name, md5);
  if (ret <= 0)
    return ret;
  *mirror_name = strdup(md5_name);
  if (*mirror_name == NULL) {
    libjte_report_no_mem(o, strlen(md5_name) + 1, 0);
    return -1;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<libjte_decide_file_jigdo>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rcx)
  mov    %rsp,%rcx
  call   <list_file_in_jigdo@plt>
  test   %eax,%eax
  jle    L20
  mov    (%rsp),%r12
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L25
  mov    $0x1,%eax
L20:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  lea    0x1(%rax),%rsi
  call   <libjte_report_no_mem@plt>
  or     $0xffffffff,%eax
  jmp    L20
```

assistant: ```c
int libjte_decide_file_jigdo(struct libjte_env *o, char *filename, off_t size, char **mirror_name, unsigned char md5[16]) {
  int ret;
  char *md5_name;
  *mirror_name = NULL;
  ret = list_file_in_jigdo(o, filename, size, &md5_name, md5);
  if (ret <= 0)
    return ret;
  *mirror_name = strdup(md5_name);
  if (*mirror_name == NULL) {
    libjte_report_no_mem(o, strlen(md5_name) + 1, 0);
    return -1;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<libjte_decide_file_jigdo>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rcx)
  mov    %rsp,%rcx
  call   <list_file_in_jigdo@plt>
  test   %eax,%eax
  jle    L23
  mov    (%rsp),%r12
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L1
  mov    $0x1,%eax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  call   <__stack_chk_fail@plt>
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  lea    0x1(%rax),%rsi
  call   <libjte_report_no_mem@plt>
  or     $0xffffffff,%eax
  jmp    L23
```

assistant: ```c
int libjte_decide_file_jigdo(struct libjte_env *o, char *filename, off_t size, char **mirror_name, unsigned char md5[16]) {
  int ret;
  char *md5_name;
  *mirror_name = NULL;
  ret = list_file_in_jigdo(o, filename, size, &md5_name, md5);
  if (ret <= 0)
    return ret;
  *mirror_name = strdup(md5_name);
  if (*mirror_name == NULL) {
    libjte_report_no_mem(o, strlen(md5_name) + 1, 0);
    return -1;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %d %p


assistant: ```c
int main() {
  int i = 5;
  int *ip = &i;
  printf("%d %p\n", *ip, ip);
  i++;
  printf("%d %p\n", *ip, ip);
  (*ip)++;
  printf("%d %p\n", *ip, ip);
  return 0;
}
```