user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  lea    D3(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  call   <scanf@plt>
  mov    0x20(%rsp),%ecx
  mov    0x24(%rsp),%eax
  cmp    %eax,%ecx
  jg     L185
  nopl   0x0(%rax,%rax,1)
L46:
  lea    0x1(%rcx),%r11d
  test   %ecx,%ecx
  jle    L135
  lea    -0x1(%rcx),%r10d
  mov    %r11d,0x18(%rsp)
  mov    %r11d,%ebp
  pxor   %xmm2,%xmm2
  mov    $0x1,%r15d
  mov    $0x1,%esi
  mov    %ecx,%r11d
  sub    %ecx,%r15d
  mov    %r15d,%eax
  mov    %r10d,%r15d
  mov    %eax,%r10d
  cs nopw 0x0(%rax,%rax,1)
L169:
  mov    %esi,%ebx
  jmp    L120
  nopl   0x0(%rax)
L38:
  add    $0x1,%ebx
  cmp    %r11d,%ebx
  jg     L49
L120:
  lea    (%rsi,%rbx,1),%eax
  cmp    %eax,%r11d
  jge    L38
  lea    (%rbx,%rbp,1),%r12d
  lea    (%rbx,%r15,1),%eax
  mov    %ebp,%edx
  imul   %r12d,%eax
  sub    %ebx,%edx
  imul   %edx,%eax
  lea    (%rbx,%r10,1),%edx
  imul   %edx,%eax
  test   $0xf,%al
  jne    L38
  test   %eax,%eax
  lea    0xf(%rax),%r13d
  pxor   %xmm1,%xmm1
  cmovns %eax,%r13d
  sar    $0x4,%r13d
  cvtsi2sd %r13d,%xmm1
  ucomisd %xmm1,%xmm2
  ja     L174
  sqrtsd %xmm1,%xmm1
  cvttsd2si %xmm1,%r14d
  mov    %r14d,%eax
  imul   %r14d,%eax
  cmp    %eax,%r13d
  jne    L38
L52:
  cmp    $0x1,%r14d
  jle    L38
  mov    %r15d,0x8(%rsp)
  mov    $0x1,%r13d
  mov    %ebp,%r15d
  mov    %ebx,%ebp
  mov    %r11d,%ebx
  nopl   0x0(%rax)
L48:
  mov    %r14d,%eax
  cltd
  idiv   %r13d
  test   %edx,%edx
  jne    L43
  lea    0x0(%r13,%rax,2),%edx
  add    %r13d,%edx
  cmp    %r12d,%edx
  je     L155
L43:
  add    $0x1,%r13d
  mov    %r13d,%eax
  imul   %r13d,%eax
  cmp    %r14d,%eax
  jl     L48
  mov    %ebx,%r11d
  mov    %ebp,%ebx
  mov    %r15d,%ebp
  mov    0x8(%rsp),%r15d
  add    $0x1,%ebx
  cmp    %r11d,%ebx
  jle    L120
  nopl   (%rax)
L49:
  add    $0x1,%esi
  add    $0x1,%ebp
  sub    $0x1,%r15d
  add    $0x1,%r10d
  cmp    %r11d,%esi
  jle    L169
  mov    0x18(%rsp),%r11d
  mov    0x24(%rsp),%eax
L135:
  mov    %r11d,%ecx
  cmp    %eax,%r11d
  jle    L46
L185:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L126
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L155:
  cmp    %r13d,%eax
  mov    %r13d,%r9d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  cmovge %eax,%r9d
  cmovg  %r13d,%eax
  lea    D8(%rip),%rdi
  mov    %esi,0x10(%rsp)
  mov    %r10d,0x14(%rsp)
  mov    %eax,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%r10d
  mov    0x10(%rsp),%esi
  pxor   %xmm2,%xmm2
  jmp    L43
L174:
  movapd %xmm1,%xmm0
  mov    %r10d,0x1c(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %r11d,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  mov    0x10(%rsp),%r11d
  pxor   %xmm2,%xmm2
  cvttsd2si %xmm0,%eax
  mov    0x14(%rsp),%esi
  mov    0x1c(%rsp),%r10d
  imul   %eax,%eax
  cmp    %eax,%r13d
  jne    L38
  movapd %xmm1,%xmm0
  mov    %r10d,0x14(%rsp)
  mov    %esi,0x10(%rsp)
  mov    %r11d,0x8(%rsp)
  call   <sqrt@plt>
  mov    0x8(%rsp),%r11d
  mov    0x10(%rsp),%esi
  pxor   %xmm2,%xmm2
  cvttsd2si %xmm0,%r14d
  mov    0x14(%rsp),%r10d
  jmp    L52
L126:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string
name: read_data
arguments: data_tag: D8
type_infered: string

tool: D3: %d %d

tool: D8: (%d, %d, %d)  (%d, %d)


assistant: ```c
main() {
  int start, stop;
  int a, b, c;
  int s, t;
  int l, w;
  int A;
  int area;
  int isSquare(n) int n;
  {
    int s;
    s = (int)sqrt((double)n);
    return (n == s * s);
  }
  scanf("%d %d", &start, &stop);
  for (c = start; c <= stop; c++)
    for (a = 1; a <= c; a++)
      for (b = a; b <= c; b++) {
        s = a + b + c;
        if ((a + b) <= c)
          continue;
        t = s * (b + c - a) * (a + c - b) * (a + b - c);
        if (!(t % 16) && (isSquare(t / 16))) {
          A = (int)sqrt(t / 16);
          for (l = 1; l * l < A; l++)
            if (!(A % l)) {
              w = A / l;
              if (s == (w + w + l + l))
                printf("(%d, %d, %d)  (%d, %d)\n", a, b, c, (w < l) ? w : l, (w < l ? l : w));
            }
        }
      }
}
```