ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ASN1_item_digest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ASN1_item_i2d@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L41
  mov    $0x0,%eax
  jmp    L6
L41:
  mov    -0x10(%rbp),%rax
  mov    -0x30(%rbp),%rdi
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    $0x0,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <EVP_Digest@plt>
  test   %eax,%eax
  jne    L20
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L6
L20:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

assistant: ```c
int ASN1_item_digest(const ASN1_ITEM *it, const EVP_MD *type, void *asn, unsigned char *md, unsigned int *len) {
  int i;
  unsigned char *str = NULL;
  i = ASN1_item_i2d(asn, &str, it);
  if (!str)
    return (0);
  if (!EVP_Digest(str, i, md, len, type, NULL)) {
    free(str);
    return (0);
  }
  free(str);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ASN1_item_digest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rax
  mov    %rsi,%r12
  mov    %rdx,%rdi
  mov    %rcx,%rbp
  mov    %r8,%r13
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  mov    %rax,%rdx
  call   <ASN1_item_i2d@plt>
  mov    (%rsp),%rdi
  mov    $0x0,%ebx
  test   %rdi,%rdi
  je     L20
  mov    %eax,%esi
  mov    $0x0,%r9d
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    %rbp,%rdx
  call   <EVP_Digest@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L32
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    $0x1,%ebx
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    (%rsp),%rdi
  call   <free@plt>
  jmp    L20
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ASN1_item_digest(const ASN1_ITEM *it, const EVP_MD *type, void *asn, unsigned char *md, unsigned int *len) {
  int i;
  unsigned char *str = NULL;
  i = ASN1_item_i2d(asn, &str, it);
  if (!str)
    return (0);
  if (!EVP_Digest(str, i, md, len, type, NULL)) {
    free(str);
    return (0);
  }
  free(str);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ASN1_item_digest>:
  endbr64
  push   %r14
  mov    %rdi,%r9
  mov    %rdx,%rdi
  mov    %r8,%r14
  push   %r13
  mov    %r9,%rdx
  mov    %rcx,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <ASN1_item_i2d@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L4
  mov    %eax,%esi
  xor    %r9d,%r9d
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <EVP_Digest@plt>
  mov    (%rsp),%rdi
  mov    %eax,%r12d
  test   %eax,%eax
  je     L20
  call   <free@plt>
  mov    $0x1,%r12d
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L20:
  call   <free@plt>
  jmp    L4
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ASN1_item_digest(const ASN1_ITEM *it, const EVP_MD *type, void *asn, unsigned char *md, unsigned int *len) {
  int i;
  unsigned char *str = NULL;
  i = ASN1_item_i2d(asn, &str, it);
  if (!str)
    return (0);
  if (!EVP_Digest(str, i, md, len, type, NULL)) {
    free(str);
    return (0);
  }
  free(str);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ASN1_item_digest>:
  endbr64
  push   %r14
  mov    %rdi,%r9
  mov    %rdx,%rdi
  mov    %r8,%r14
  push   %r13
  mov    %r9,%rdx
  mov    %rcx,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <ASN1_item_i2d@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L30
  mov    %eax,%esi
  xor    %r9d,%r9d
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <EVP_Digest@plt>
  mov    (%rsp),%rdi
  mov    %eax,%r12d
  test   %eax,%eax
  je     L36
  call   <free@plt>
  mov    $0x1,%r12d
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L36:
  call   <free@plt>
  jmp    L30
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ASN1_item_digest(const ASN1_ITEM *it, const EVP_MD *type, void *asn, unsigned char *md, unsigned int *len) {
  int i;
  unsigned char *str = NULL;
  i = ASN1_item_i2d(asn, &str, it);
  if (!str)
    return (0);
  if (!EVP_Digest(str, i, md, len, type, NULL)) {
    free(str);
    return (0);
  }
  free(str);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Alloc_Fault>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L6:
  jmp    L6
```

assistant: ```c
void Alloc_Fault(void) {
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Alloc_Fault>:
  endbr64
L8:
  jmp    L8
```

assistant: ```c
void Alloc_Fault(void) {
  while (1)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Alloc_Fault>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
void Alloc_Fault(void) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Alloc_Fault>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
void Alloc_Fault(void) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L94:
  cmp    %rcx,%rsp
  je     L83
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L94
L83:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L120
  orq    $0x0,-0x8(%rsp,%rax,1)
L120:
  mov    %rsp,%r12
  test   %edx,%edx
  jle    L59
  mov    %r12,%r13
  mov    $0x0,%ebx
  lea    D17(%rip),%r14
L87:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%edx
  add    $0x4,%r13
  cmp    %ebx,%edx
  jg     L87
L59:
  sub    $0x1,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <quicksort@plt>
  mov    -0x2c(%rbp),%edx
  test   %edx,%edx
  jle    L24
  mov    $0x0,%ebx
  lea    D26(%rip),%r13
  jmp    L82
L123:
  cmpl   $0x0,(%rdx)
  setg   %dil
  movzbl %dil,%edi
  add    %edi,%esi
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L123
L132:
  sub    %r8d,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L132
L95:
  mov    %r13,%rdi
  call   <printf@plt>
L39:
  mov    -0x2c(%rbp),%edx
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jle    L24
L82:
  mov    (%r12,%rbx,4),%r8d
  test   %r8d,%r8d
  jle    L39
  test   %edx,%edx
  jle    L134
  mov    %r12,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%r12,%rdx,4),%rcx
  mov    %r12,%rdx
  mov    $0x0,%esi
  jmp    L123
L134:
  mov    $0x0,%esi
  jmp    L95
L24:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D17
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string

tool: D17: %d

tool: D26: %d


assistant: ```c
int main() {
  int n, i, j, max, t, count = 0;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  quicksort(a, 0, n - 1);
  for (i = 0; i < n; i++) {
    if (a[i] > 0) {
      t = a[i];
    } else
      continue;
    for (j = 0; j < n; j++) {
      if (a[j] > 0) {
        count++;
      }
    }
    for (j = 0; j < n; j++) {
      a[j] = a[j] - t;
    }
    printf("%d\n", count);
    count = 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L10
L117:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L117
L10:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L122
L62:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L69
  mov    %rbx,%r13
  xor    %r12d,%r12d
L106:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  cmp    %r12d,%edx
  jg     L106
L69:
  sub    $0x1,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <quicksort@plt>
  mov    -0x2c(%rbp),%edx
  test   %edx,%edx
  jle    L48
  xor    %r13d,%r13d
  lea    D11(%rip),%r12
  nopl   0x0(%rax)
L9:
  mov    (%rbx,%r13,4),%ecx
  test   %ecx,%ecx
  jle    L37
  xor    %eax,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L26:
  mov    (%rbx,%rax,4),%edi
  test   %edi,%edi
  jle    L126
  add    $0x1,%esi
L126:
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L26
  xor    %eax,%eax
  nopl   0x0(%rax)
L76:
  sub    %ecx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L76
  mov    %r12,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
L37:
  add    $0x1,%r13
  cmp    %r13d,%edx
  jg     L9
L48:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L122:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L62
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string
name: disassemble_data
arguments: data_tag: D11
type_infered: string

tool: D0: %d

tool: D11: %d


assistant: ```c
int main() {
  int n, i, j, max, t, count = 0;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  quicksort(a, 0, n - 1);
  for (i = 0; i < n; i++) {
    if (a[i] > 0) {
      t = a[i];
    } else
      continue;
    for (j = 0; j < n; j++) {
      if (a[j] > 0) {
        count++;
      }
    }
    for (j = 0; j < n; j++) {
      a[j] = a[j] - t;
    }
    printf("%d\n", count);
    count = 0;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MUSIC_SetVolume>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void MUSIC_SetVolume(int volume) {
  volume = ((0) > (volume) ? (0) : (volume));
  volume = ((volume) < (255) ? (volume) : (255));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<MUSIC_SetVolume>:
  endbr64
  ret
```

assistant: ```c
void MUSIC_SetVolume(int volume) {
  volume = ((0) > (volume) ? (0) : (volume));
  volume = ((volume) < (255) ? (volume) : (255));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MUSIC_SetVolume>:
  endbr64
  ret
```

assistant: ```c
void MUSIC_SetVolume(int volume) {
  volume = ((0) > (volume) ? (0) : (volume));
  volume = ((volume) < (255) ? (volume) : (255));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MUSIC_SetVolume>:
  endbr64
  ret
```

assistant: ```c
void MUSIC_SetVolume(int volume) {
  volume = ((0) > (volume) ? (0) : (volume));
  volume = ((volume) < (255) ? (volume) : (255));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_shader_limits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void print_shader_limits(GLenum target) {
  struct token_name {
    GLenum token;
    const char *name;
  };
  GLint max[1];
  int i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_shader_limits>:
  endbr64
  ret
```

assistant: ```c
void print_shader_limits(GLenum target) {
  struct token_name {
    GLenum token;
    const char *name;
  };
  GLint max[1];
  int i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_shader_limits>:
  endbr64
  ret
```

assistant: ```c
void print_shader_limits(GLenum target) {
  struct token_name {
    GLenum token;
    const char *name;
  };
  GLint max[1];
  int i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_shader_limits>:
  endbr64
  ret
```

assistant: ```c
void print_shader_limits(GLenum target) {
  struct token_name {
    GLenum token;
    const char *name;
  };
  GLint max[1];
  int i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x7a,-0x4(%rbp)
  jg     L58
  cmpb   $0x60,-0x4(%rbp)
  jle    L58
  mov    $0x1,%eax
  jmp    L42
L58:
  cmpb   $0x5a,-0x4(%rbp)
  jg     L60
  cmpb   $0x40,-0x4(%rbp)
  jle    L60
  mov    $0x1,%eax
  jmp    L42
L60:
  cmpb   $0x5f,-0x4(%rbp)
  jne    L68
  mov    $0x1,%eax
  jmp    L42
L68:
  cmpb   $0x2e,-0x4(%rbp)
  jne    L95
  mov    $0x1,%eax
  jmp    L42
L95:
  mov    $0x0,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int alpha(char c) {
  if (c <= 'z' && c >= 'a')
    return (1);
  if (c <= 'Z' && c >= 'A')
    return (1);
  if (c == '_')
    return (1);
  if (c == '.')
    return (1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<alpha>:
  endbr64
  cmp    $0x5f,%dil
  sete   %al
  cmp    $0x2e,%dil
  sete   %dl
  or     %edx,%eax
  and    $0xffffffdf,%edi
  sub    $0x41,%edi
  cmp    $0x19,%dil
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int alpha(char c) {
  if (c <= 'z' && c >= 'a')
    return (1);
  if (c <= 'Z' && c >= 'A')
    return (1);
  if (c == '_')
    return (1);
  if (c == '.')
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<alpha>:
  endbr64
  cmp    $0x2e,%dil
  sete   %al
  cmp    $0x5f,%dil
  sete   %dl
  and    $0xffffffdf,%edi
  sub    $0x41,%edi
  or     %edx,%eax
  cmp    $0x19,%dil
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int alpha(char c) {
  if (c <= 'z' && c >= 'a')
    return (1);
  if (c <= 'Z' && c >= 'A')
    return (1);
  if (c == '_')
    return (1);
  if (c == '.')
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<alpha>:
  endbr64
  cmp    $0x2e,%dil
  sete   %al
  cmp    $0x5f,%dil
  sete   %dl
  and    $0xffffffdf,%edi
  sub    $0x41,%edi
  or     %edx,%eax
  cmp    $0x19,%dil
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int alpha(char c) {
  if (c <= 'z' && c >= 'a')
    return (1);
  if (c <= 'Z' && c >= 'A')
    return (1);
  if (c == '_')
    return (1);
  if (c == '.')
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x334(%rbp)
  jmp    L17
L18:
  mov    -0x334(%rbp),%eax
  cltq
  mov    -0x334(%rbp),%edx
  mov    %edx,-0x330(%rbp,%rax,4)
  mov    -0x334(%rbp),%eax
  cltq
  movl   $0x0,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x334(%rbp)
L17:
  cmpl   $0x63,-0x334(%rbp)
  jle    L18
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void f(void) {
  int a[100], b[100];
#pragma hlt distribute
  for (int i = 0; i < 100; i++) {
    {
      a[i] = i * 1;
      b[i] = 0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f>:
  endbr64
  mov    $0x64,%eax
L5:
  sub    $0x1,%eax
  jne    L5
  ret
```

assistant: ```c
void f(void) {
  int a[100], b[100];
#pragma hlt distribute
  for (int i = 0; i < 100; i++) {
    {
      a[i] = i * 1;
      b[i] = 0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int a[100], b[100];
#pragma hlt distribute
  for (int i = 0; i < 100; i++) {
    {
      a[i] = i * 1;
      b[i] = 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int a[100], b[100];
#pragma hlt distribute
  for (int i = 0; i < 100; i++) {
    {
      a[i] = i * 1;
      b[i] = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t2p_posix2time_timeval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <t2p_posix2time@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,0x4(%rdx)
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L19
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <t2p_normalize_timeval@plt>
  jmp    L55
L19:
  mov    -0xc(%rbp),%eax
  cmp    $0xffffffff,%eax
  jne    L49
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L55
L49:
  mov    -0xc(%rbp),%eax
  cmp    $0xfffffffe,%eax
  jne    L55
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0xf4240,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L55:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
struct timeval *t2p_posix2time_timeval(struct timeval *tv) {
  int state;
  tv->tv_sec = t2p_posix2time(tv->tv_sec, &state);
  if (state == 1) {
    tv->tv_usec <<= 1;
    t2p_normalize_timeval(tv);
  } else if (state == -1)
    tv->tv_usec >>= 1;
  else if (state == -2)
    tv->tv_usec = (tv->tv_usec + 1000000) >> 1;
  return tv;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<t2p_posix2time_timeval>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    0x4(%rdi),%edi
  call   <t2p_posix2time@plt>
  mov    %eax,0x4(%rbx)
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L12
  cmp    $0xffffffff,%eax
  je     L27
  cmp    $0xfffffffe,%eax
  je     L57
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L12:
  shll   (%rbx)
  mov    %rbx,%rdi
  call   <t2p_normalize_timeval@plt>
  jmp    L37
L27:
  sarl   (%rbx)
  jmp    L37
L57:
  mov    (%rbx),%eax
  add    $0xf4240,%eax
  sar    %eax
  mov    %eax,(%rbx)
  jmp    L37
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timeval *t2p_posix2time_timeval(struct timeval *tv) {
  int state;
  tv->tv_sec = t2p_posix2time(tv->tv_sec, &state);
  if (state == 1) {
    tv->tv_usec <<= 1;
    t2p_normalize_timeval(tv);
  } else if (state == -1)
    tv->tv_usec >>= 1;
  else if (state == -2)
    tv->tv_usec = (tv->tv_usec + 1000000) >> 1;
  return tv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<t2p_posix2time_timeval>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    0x4(%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <t2p_posix2time@plt>
  mov    %eax,0x4(%r12)
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L33
  cmp    $0xffffffff,%eax
  je     L16
  cmp    $0xfffffffe,%eax
  je     L53
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  sarl   (%r12)
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L33:
  shll   (%r12)
  mov    %r12,%rdi
  call   <t2p_normalize_timeval@plt>
  jmp    L18
  xchg   %ax,%ax
L53:
  mov    (%r12),%eax
  add    $0xf4240,%eax
  sar    %eax
  mov    %eax,(%r12)
  jmp    L18
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timeval *t2p_posix2time_timeval(struct timeval *tv) {
  int state;
  tv->tv_sec = t2p_posix2time(tv->tv_sec, &state);
  if (state == 1) {
    tv->tv_usec <<= 1;
    t2p_normalize_timeval(tv);
  } else if (state == -1)
    tv->tv_usec >>= 1;
  else if (state == -2)
    tv->tv_usec = (tv->tv_usec + 1000000) >> 1;
  return tv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t2p_posix2time_timeval>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    0x4(%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <t2p_posix2time@plt>
  mov    %eax,0x4(%r12)
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L4
  cmp    $0xffffffff,%eax
  je     L13
  cmp    $0xfffffffe,%eax
  je     L59
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  sarl   (%r12)
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L4:
  shll   (%r12)
  mov    %r12,%rdi
  call   <t2p_normalize_timeval@plt>
  jmp    L25
  xchg   %ax,%ax
L59:
  mov    (%r12),%eax
  add    $0xf4240,%eax
  sar    %eax
  mov    %eax,(%r12)
  jmp    L25
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timeval *t2p_posix2time_timeval(struct timeval *tv) {
  int state;
  tv->tv_sec = t2p_posix2time(tv->tv_sec, &state);
  if (state == 1) {
    tv->tv_usec <<= 1;
    t2p_normalize_timeval(tv);
  } else if (state == -1)
    tv->tv_usec >>= 1;
  else if (state == -2)
    tv->tv_usec = (tv->tv_usec + 1000000) >> 1;
  return tv;
}
```