ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<phi>:
  endbr64
  pxor   %xmm3,%xmm3
  movapd %xmm0,%xmm2
  ucomisd %xmm3,%xmm0
  jp     L36
  jne    L36
  comisd %xmm3,%xmm1
  movsd  D11(%rip),%xmm0
  jbe    L28
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  divsd  %xmm2,%xmm1
  sub    $0x18,%rsp
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <atan@plt>
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm5,%xmm5
  comisd %xmm5,%xmm2
  jbe    L1
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L28:
  movsd  D28(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L1:
  addsd  D27(%rip),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D28
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D27
datatype: f64

tool: {"D11": [0x4a,0xd8,0x12,0x4d,0xfb,0x21,0xf9,0x3f]}

tool: {"D28": [0x4a,0xd8,0x12,0x4d,0xfb,0x21,0xf9,0xbf]}

tool: D27: 3.1415926

assistant: ```c
double phi(re, im)
double re, im;
{
  if (re == 0)
    if (im > 0)
      return (3.1415926 / 2);
    else
      return (-3.1415926 / 2);
  if (re > 0)
    return (atan(im / re));
  else
    return (atan(im / re) + 3.1415926);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<phi>:
  endbr64
  pxor   %xmm3,%xmm3
  movapd %xmm0,%xmm2
  ucomisd %xmm3,%xmm0
  jp     L32
  jne    L32
  comisd %xmm3,%xmm1
  movsd  D9(%rip),%xmm0
  jbe    L25
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  divsd  %xmm2,%xmm1
  sub    $0x18,%rsp
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <atan@plt>
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm5,%xmm5
  comisd %xmm5,%xmm2
  jbe    L34
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L25:
  movsd  D24(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L34:
  addsd  D22(%rip),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: byte[8]
name: parse_data
arguments: label: D24
type_infered: byte[8]
name: parse_data
arguments: label: D22
type_infered: f64

tool: {"D9": [0x4a,0xd8,0x12,0x4d,0xfb,0x21,0xf9,0x3f]}

tool: {"D24": [0x4a,0xd8,0x12,0x4d,0xfb,0x21,0xf9,0xbf]}

tool: D22: 3.1415926

assistant: ```c
double phi(re, im)
double re, im;
{
  if (re == 0)
    if (im > 0)
      return (3.1415926 / 2);
    else
      return (-3.1415926 / 2);
  if (re > 0)
    return (atan(im / re));
  else
    return (atan(im / re) + 3.1415926);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
L4:
  addl   $0x1,-0x4(%rbp)
  jmp    L4
```

assistant: ```c
int main() {
  int i = 0;
  for (;;)
    i++;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
L4:
  jmp    L4
```

assistant: ```c
int main() {
  int i = 0;
  for (;;)
    i++;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
int main() {
  int i = 0;
  for (;;)
    i++;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
int main() {
  int i = 0;
  for (;;)
    i++;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<PWMDutyGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <PWMARRGet@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  add    $0x34,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long PWMDutyGet(unsigned long ulBase, unsigned long ulChannel) {
  unsigned long ulCMRData;
  unsigned long ulCNRData;
  ;
  ;
  ulCNRData = PWMARRGet(ulBase);
  ulCMRData = (*((volatile unsigned long *)(ulBase + 0x00000034 + ulChannel * 4)));
  ulChannel = (ulCMRData + 1) * 100 / (ulCNRData + 1);
  return ulChannel;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PWMDutyGet>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <PWMARRGet@plt>
  mov    %rax,%rcx
  lea    (%rbx,%rbp,4),%rax
  mov    0x34(%rax),%rax
  lea    0x5(%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  add    $0x1,%rcx
  mov    $0x0,%edx
  div    %rcx
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long PWMDutyGet(unsigned long ulBase, unsigned long ulChannel) {
  unsigned long ulCMRData;
  unsigned long ulCNRData;
  ;
  ;
  ulCNRData = PWMARRGet(ulBase);
  ulCMRData = (*((volatile unsigned long *)(ulBase + 0x00000034 + ulChannel * 4)));
  ulChannel = (ulCMRData + 1) * 100 / (ulCNRData + 1);
  return ulChannel;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PWMDutyGet>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <PWMARRGet@plt>
  xor    %edx,%edx
  mov    %rax,%r8
  lea    (%rbx,%rbp,4),%rax
  mov    0x34(%rax),%rax
  lea    0x1(%r8),%rcx
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  lea    0x5(%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  div    %rcx
  ret
```

assistant: ```c
unsigned long PWMDutyGet(unsigned long ulBase, unsigned long ulChannel) {
  unsigned long ulCMRData;
  unsigned long ulCNRData;
  ;
  ;
  ulCNRData = PWMARRGet(ulBase);
  ulCMRData = (*((volatile unsigned long *)(ulBase + 0x00000034 + ulChannel * 4)));
  ulChannel = (ulCMRData + 1) * 100 / (ulCNRData + 1);
  return ulChannel;
}
```
user: Translate the below assembly code into C programming language:

```asm
<PWMDutyGet>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <PWMARRGet@plt>
  xor    %edx,%edx
  mov    %rax,%r8
  lea    (%rbx,%rbp,4),%rax
  mov    0x34(%rax),%rax
  lea    0x1(%r8),%rcx
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  lea    0x5(%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  div    %rcx
  ret
```

assistant: ```c
unsigned long PWMDutyGet(unsigned long ulBase, unsigned long ulChannel) {
  unsigned long ulCMRData;
  unsigned long ulCNRData;
  ;
  ;
  ulCNRData = PWMARRGet(ulBase);
  ulCMRData = (*((volatile unsigned long *)(ulBase + 0x00000034 + ulChannel * 4)));
  ulChannel = (ulCMRData + 1) * 100 / (ulCNRData + 1);
  return ulChannel;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L9:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  nop
L59:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  subq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
  jmp    L7
L30:
  subq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L34
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  ja     L30
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L6
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L6
  mov    $0x1,%eax
  jmp    L5
L6:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int strend(char *source, char *target) {
  char *placeholder = target;
  while (*target++ != '\0')
    ;
  while (*source++ != '\0')
    ;
  for (--source, --target; *source == *target && target > placeholder; --source, --target)
    ;
  return (*source == *target && target == placeholder) ? 1 : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strend>:
  endbr64
  mov    %rsi,%rdx
L41:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L41
L18:
  mov    %rdi,%rcx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L18
  cmp    %rsi,%rax
  jbe    L17
L48:
  sub    $0x1,%rcx
  sub    $0x1,%rax
  movzbl (%rcx),%edx
  movzbl (%rax),%edi
  cmp    %rax,%rsi
  jae    L43
  cmp    %dil,%dl
  je     L48
L43:
  cmp    %rax,%rsi
  sete   %cl
  cmp    %dil,%dl
  sete   %al
  movzbl %al,%eax
  and    %ecx,%eax
  ret
L17:
  mov    %edx,%edi
  jmp    L43
```

assistant: ```c
int strend(char *source, char *target) {
  char *placeholder = target;
  while (*target++ != '\0')
    ;
  while (*source++ != '\0')
    ;
  for (--source, --target; *source == *target && target > placeholder; --source, --target)
    ;
  return (*source == *target && target == placeholder) ? 1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strend>:
  endbr64
  mov    %rsi,%rax
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L48
  nopl   (%rax)
L2:
  mov    %rdi,%rax
  lea    0x1(%rdi),%rdi
  cmpb   $0x0,(%rax)
  jne    L2
  cmp    %rsi,%rdx
  ja     L35
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L14:
  cmp    %rdx,%rsi
  je     L34
L35:
  sub    $0x1,%rax
  sub    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    %cl,(%rax)
  je     L14
  xor    %eax,%eax
  ret
  nop
L34:
  xor    %eax,%eax
  cmp    %rdx,%rsi
  sete   %al
  ret
```

assistant: ```c
int strend(char *source, char *target) {
  char *placeholder = target;
  while (*target++ != '\0')
    ;
  while (*source++ != '\0')
    ;
  for (--source, --target; *source == *target && target > placeholder; --source, --target)
    ;
  return (*source == *target && target == placeholder) ? 1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strend>:
  endbr64
  mov    %rsi,%rax
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L9
  nopl   (%rax)
L50:
  mov    %rdi,%rax
  lea    0x1(%rdi),%rdi
  cmpb   $0x0,(%rax)
  jne    L50
  cmp    %rsi,%rdx
  ja     L16
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L19:
  cmp    %rdx,%rsi
  je     L46
L16:
  sub    $0x1,%rax
  sub    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    %cl,(%rax)
  je     L19
  xor    %eax,%eax
  ret
  nop
L46:
  xor    %eax,%eax
  cmp    %rdx,%rsi
  sete   %al
  ret
```

assistant: ```c
int strend(char *source, char *target) {
  char *placeholder = target;
  while (*target++ != '\0')
    ;
  while (*source++ != '\0')
    ;
  for (--source, --target; *source == *target && target > placeholder; --source, --target)
    ;
  return (*source == *target && target == placeholder) ? 1 : 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <b@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: b=%d


assistant: ```c
int main() {
  printf("b=%d\n", b());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <b@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: b=%d


assistant: ```c
int main() {
  printf("b=%d\n", b());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <b@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: b=%d


assistant: ```c
int main() {
  printf("b=%d\n", b());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <b@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: b=%d


assistant: ```c
int main() {
  printf("b=%d\n", b());
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L5:
  mov    $0x0,%eax
  call   <AltKeyDown@plt>
  test   %eax,%eax
  je     L5
  nop
L9:
  mov    $0x0,%eax
  call   <KeyPressed@plt>
  test   %eax,%eax
  je     L9
  mov    $0x0,%eax
  call   <ReadKey@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
int main() {
  while (!AltKeyDown())
    ;
  while (!KeyPressed())
    ;
  printf("%d", ReadKey());
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L19:
  mov    $0x0,%eax
  call   <AltKeyDown@plt>
  test   %eax,%eax
  je     L19
L17:
  mov    $0x0,%eax
  call   <KeyPressed@plt>
  test   %eax,%eax
  je     L17
  mov    $0x0,%eax
  call   <ReadKey@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: %d

assistant: ```c
int main() {
  while (!AltKeyDown())
    ;
  while (!KeyPressed())
    ;
  printf("%d", ReadKey());
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <AltKeyDown@plt>
  test   %eax,%eax
  je     L4
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  call   <KeyPressed@plt>
  test   %eax,%eax
  je     L16
  xor    %eax,%eax
  call   <ReadKey@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main() {
  while (!AltKeyDown())
    ;
  while (!KeyPressed())
    ;
  printf("%d", ReadKey());
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  call   <AltKeyDown@plt>
  test   %eax,%eax
  je     L11
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <KeyPressed@plt>
  test   %eax,%eax
  je     L3
  xor    %eax,%eax
  call   <ReadKey@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: %d

assistant: ```c
int main() {
  while (!AltKeyDown())
    ;
  while (!KeyPressed())
    ;
  printf("%d", ReadKey());
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GetPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  0x3d0958(%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L8
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L0
L8:
  pxor   %xmm0,%xmm0
L0:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double GetPath(double *sln, int yardage) {
  double size = sln[50001 * 10 + 1];
  if (yardage < size) {
    return sln[10 * yardage + 1];
  } else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GetPath>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  movsd  0x3d0958(%rdi),%xmm1
  comisd %xmm0,%xmm1
  jbe    L2
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  cltq
  movsd  0x8(%rdi,%rax,8),%xmm0
  ret
L2:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double GetPath(double *sln, int yardage) {
  double size = sln[50001 * 10 + 1];
  if (yardage < size) {
    return sln[10 * yardage + 1];
  } else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GetPath>:
  endbr64
  pxor   %xmm0,%xmm0
  movsd  0x3d0958(%rdi),%xmm1
  cvtsi2sd %esi,%xmm0
  comisd %xmm0,%xmm1
  jbe    L0
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  cltq
  movsd  0x8(%rdi,%rax,8),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double GetPath(double *sln, int yardage) {
  double size = sln[50001 * 10 + 1];
  if (yardage < size) {
    return sln[10 * yardage + 1];
  } else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetPath>:
  endbr64
  pxor   %xmm0,%xmm0
  movsd  0x3d0958(%rdi),%xmm1
  cvtsi2sd %esi,%xmm0
  comisd %xmm0,%xmm1
  jbe    L2
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  cltq
  movsd  0x8(%rdi,%rax,8),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double GetPath(double *sln, int yardage) {
  double size = sln[50001 * 10 + 1];
  if (yardage < size) {
    return sln[10 * yardage + 1];
  } else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x5,-0x8(%rbp)
  movl   $0x5,-0x8(%rbp)
  movl   $0x5,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo() {
  int y;
  volatile int x;
  x = 5;
  x = 5;
  x = 5;
  y = 3;
  return x + y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  movl   $0x5,-0x4(%rsp)
  movl   $0x5,-0x4(%rsp)
  movl   $0x5,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  add    $0x3,%eax
  ret
```

assistant: ```c
int foo() {
  int y;
  volatile int x;
  x = 5;
  x = 5;
  x = 5;
  y = 3;
  return x + y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  movl   $0x5,-0x4(%rsp)
  movl   $0x5,-0x4(%rsp)
  movl   $0x5,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  add    $0x3,%eax
  ret
```

assistant: ```c
int foo() {
  int y;
  volatile int x;
  x = 5;
  x = 5;
  x = 5;
  y = 3;
  return x + y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  movl   $0x5,-0x4(%rsp)
  movl   $0x5,-0x4(%rsp)
  movl   $0x5,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  add    $0x3,%eax
  ret
```

assistant: ```c
int foo() {
  int y;
  volatile int x;
  x = 5;
  x = 5;
  x = 5;
  y = 3;
  return x + y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utilities_null_terminated_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x0,-0x2c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    %rax,%r8
  mov    $0x0,%r9d
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L47:
  cmp    %rdx,%rsp
  je     L8
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L47
L8:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L50
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L50:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L17
L29:
  addl   $0x1,-0x2c(%rbp)
L17:
  mov    -0x2c(%rbp),%eax
  imul   -0x40(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x2c(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int utilities_null_terminated_length(void *array, size_t element_size) {
  unsigned int ret = 0;
  uint8_t comparrison[element_size];
  memset(comparrison, 0, element_size);
  while (memcmp(&((uint8_t *)array)[ret * element_size], comparrison, element_size))
    ret++;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utilities_null_terminated_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x0(,%rsi,4),%r14
  lea    0xf(%r14),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L55:
  cmp    %rdx,%rsp
  je     L41
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L55
L41:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L46
  orq    $0x0,-0x8(%rsp,%rax,1)
L46:
  mov    %rsp,%r15
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  mov    $0x0,%ebx
  jmp    L8
L58:
  add    $0x1,%ebx
L8:
  mov    %ebx,%edi
  imul   %r14,%rdi
  add    %r13,%rdi
  mov    %r12,%rdx
  mov    %r15,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L58
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    %ebx,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int utilities_null_terminated_length(void *array, size_t element_size) {
  unsigned int ret = 0;
  uint8_t comparrison[element_size];
  memset(comparrison, 0, element_size);
  while (memcmp(&((uint8_t *)array)[ret * element_size], comparrison, element_size))
    ret++;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utilities_null_terminated_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  lea    0x0(,%rsi,4),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(%r13),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L58
L53:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L53
L58:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L29
L60:
  mov    %rsp,%r14
  mov    %rbx,%rdx
  xor    %esi,%esi
  xor    %r15d,%r15d
  mov    %r14,%rdi
  call   <memset@plt>
  jmp    L55
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x1,%r15d
L55:
  mov    %r15d,%edi
  mov    %rbx,%rdx
  mov    %r14,%rsi
  imul   %r13,%rdi
  add    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L18
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  lea    -0x28(%rbp),%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nop
L29:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L60
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int utilities_null_terminated_length(void *array, size_t element_size) {
  unsigned int ret = 0;
  uint8_t comparrison[element_size];
  memset(comparrison, 0, element_size);
  while (memcmp(&((uint8_t *)array)[ret * element_size], comparrison, element_size))
    ret++;
  return ret;
}
```