user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    D27(%rip),%r14
  lea    D7(%rip),%r15
  lea    D25(%rip),%r12
  jmp    L151
L18:
  movl   $0x3,0x24(%rsp)
  movl   $0x3,0x2c(%rsp)
  movl   $0x3,0x34(%rsp)
L66:
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cltq
  mov    0x24(%rsp,%rax,8),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L66
L151:
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  je     L49
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  movl   $0x0,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x34(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r13,%rbx
  lea    0x14(%rsp),%rbp
  mov    %r13,%rdx
L55:
  mov    (%rdx),%eax
  sub    $0x1,%eax
  cltq
  addl   $0x1,0x20(%rsp,%rax,8)
  add    $0x4,%rdx
  cmp    %rbp,%rdx
  jne    L55
  mov    0x20(%rsp),%eax
  test   %eax,%eax
  jle    L27
  cmpl   $0x0,0x28(%rsp)
  jle    L27
  cmpl   $0x0,0x30(%rsp)
  jg     L18
L27:
  cmp    $0x5,%eax
  je     L18
  mov    0x28(%rsp),%edx
  cmp    $0x5,%edx
  je     L18
  mov    0x30(%rsp),%ecx
  cmp    $0x5,%ecx
  je     L18
  test   %edx,%edx
  setg   %dl
  test   %eax,%eax
  setg   %al
  test   %dl,%dl
  je     L28
  test   %al,%al
  je     L28
  movl   $0x1,0x24(%rsp)
  movl   $0x2,0x2c(%rsp)
  jmp    L66
L28:
  test   %ecx,%ecx
  setg   %cl
  test   %dl,%dl
  je     L44
  test   %cl,%cl
  je     L44
  movl   $0x1,0x2c(%rsp)
  movl   $0x2,0x34(%rsp)
  jmp    L66
L44:
  test   %al,%al
  je     L66
  test   %cl,%cl
  je     L66
  movl   $0x1,0x34(%rsp)
  movl   $0x2,0x24(%rsp)
  jmp    L66
L49:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L173
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L173:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D27
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D25
datatype: string

tool: D27: %d

tool: D7: %d %d %d %d

tool: D25: %d


assistant: ```c
int main(void) {
  int hand[5], kind[3][2], i, num;
  while (1) {
    scanf("%d", &hand[0]);
    if (hand[0] == 0)
      break;
    for (i = 0; i < 3; i++)
      kind[i][0] = 0, kind[i][1] = 0;
    scanf("%d %d %d %d", &hand[1], &hand[2], &hand[3], &hand[4]);
    for (i = 0; i < 5; i++)
      kind[hand[i] - 1][0]++;
    if ((kind[0][0] > 0 && kind[1][0] > 0 && kind[2][0] > 0) || kind[0][0] == 5 || kind[1][0] == 5 || kind[2][0] == 5) {
      kind[0][1] = 3, kind[1][1] = 3, kind[2][1] = 3;
    } else if (kind[0][0] > 0 && kind[1][0] > 0) {
      kind[0][1] = 1, kind[1][1] = 2;
    } else if (kind[1][0] > 0 && kind[2][0] > 0) {
      kind[1][1] = 1, kind[2][1] = 2;
    } else if (kind[2][0] > 0 && kind[0][0] > 0) {
      kind[2][1] = 1, kind[0][1] = 2;
    }
    for (i = 0; i < 5; i++) {
      printf("%d\n", kind[hand[i] - 1][1]);
    }
  }
  return 0;
}
```