user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Getop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopl   (%rax)
L143:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x20,%al
  je     L143
  cmp    $0x9,%eax
  je     L143
  movb   $0x0,0x1(%rbx)
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L0
  mov    %rbx,%rbp
  jmp    L156
  nopl   (%rax)
L221:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
L156:
  mov    %r12b,0x0(%rbp)
  movsbl %r12b,%edi
  mov    %rbp,%rbx
  add    $0x1,%rbp
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L221
  mov    D16(%rip),%rax
  movb   $0x0,(%rbx)
  cmp    %r12d,(%rax)
  jne    L168
  mov    $0x1,%r12d
L130:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L168:
  mov    %r12d,%edi
  mov    $0x1,%r12d
  call   <unGetch@plt>
  jmp    L130
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L99
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%eax
  jbe    L99
  cmp    $0x3d,%r12d
  je     L1
  test   %r12d,%r12d
  mov    $0x2,%eax
  cmove  %eax,%r12d
  jmp    L130
  xchg   %ax,%ax
L99:
  xor    %eax,%eax
  cmp    $0x2d,%r12d
  je     L146
  call   <getch@plt>
  mov    %eax,%ebp
  movsbl %al,%edi
L120:
  mov    %ebx,%r15d
  lea    0x1(%rbx),%r12
  neg    %r15d
  jmp    L238
  xchg   %ax,%ax
L230:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebp
  movsbl %al,%edi
L238:
  mov    %bpl,(%r12)
  lea    (%r15,%r12,1),%r14d
  mov    %r12,%r13
  add    $0x1,%r12
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L230
  cmp    $0x2e,%ebp
  je     L234
L202:
  mov    D16(%rip),%rax
  movb   $0x0,0x0(%r13)
  xor    %r12d,%r12d
  cmp    %ebp,(%rax)
  je     L130
  mov    %ebp,%edi
  call   <unGetch@plt>
  jmp    L130
L146:
  call   <getch@plt>
  movsbl %al,%edi
  mov    %eax,%ebp
  mov    %edi,0xc(%rsp)
  call   <isdigit@plt>
  mov    0xc(%rsp),%edi
  test   %rax,%rax
  jne    L120
  cmp    $0x2e,%ebp
  je     L120
  jmp    L130
L234:
  movslq %r14d,%r14
  lea    0x1(%rbx,%r14,1),%rbx
  nopl   0x0(%rax,%rax,1)
L195:
  xor    %eax,%eax
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%ebp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L195
  jmp    L202
L1:
  xor    %eax,%eax
  call   <getch@plt>
  cmp    $0xa,%eax
  jne    L130
  xor    %edi,%edi
  call   <unGetch@plt>
  jmp    L130
```

assistant: ```c
int Getop(char s[]) {
  int i = 0;
  int c;
  int next;
  while ((s[0] = c = getch()) == ' ' || c == '\t') {
    ;
  }
  s[1] = '\0';
  if (isalpha(c)) {
    i = 0;
    while (isalpha(s[i++] = c)) {
      c = getch();
    }
    s[i - 1] = '\0';
    if (c != EOF)
      unGetch(c);
    return 1;
  }
  if (!isdigit(c) && c != '.' && c != '-') {
    if ('=' == c && '\n' == (next = getch())) {
      unGetch('\0');
      return c;
    }
    if ('\0' == c)
      return 2;
    return c;
  }
  if (c == '-') {
    next = getch();
    if (!isdigit(next) && next != '.') {
      return c;
    }
    c = next;
  } else {
    c = getch();
  }
  while (isdigit(s[++i] = c)) {
    c = getch();
  }
  if (c == '.') {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  s[i] = '\0';
  if (c != EOF)
    unGetch(c);
  return 0;
}
```