ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<merge_version1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %edx,%r13d
  mov    %ecx,%ebx
  mov    %ecx,%r15d
  sub    %esi,%r15d
  lea    0x1(%r15),%eax
  mov    %eax,0xc(%rsp)
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  cmp    %r13d,%r14d
  setle  0x8(%rsp)
  cmp    %r13d,%ebx
  setg   %dil
  movzbl %dil,%edi
  and    0x8(%rsp),%edi
  call   <assert@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L165
  lea    0x1(%r13),%edx
  cmp    %edx,%ebx
  jl     L161
  cmpb   $0x0,0x8(%rsp)
  je     L161
  mov    %r12,%rsi
  lea    0x1(%r15),%r9d
  mov    %r14d,%ecx
  mov    $0x0,%r8d
  jmp    L71
L156:
  mov    %eax,(%rsi)
  add    $0x1,%edx
L77:
  lea    0x1(%r8),%eax
  cmp    %r9d,%eax
  je     L165
  add    $0x4,%rsi
  cmp    %r13d,%ecx
  jg     L62
  cmp    %ebx,%edx
  jg     L62
  mov    %eax,%r8d
L71:
  movslq %ecx,%rax
  mov    0x0(%rbp,%rax,4),%edi
  movslq %edx,%rax
  mov    0x0(%rbp,%rax,4),%eax
  cmp    %eax,%edi
  jg     L156
  mov    %edi,(%rsi)
  add    $0x1,%ecx
  jmp    L77
L178:
  mov    $0x0,%eax
L159:
  cltq
  movslq %edx,%rdx
  sub    %rax,%rdx
  lea    0x0(%rbp,%rdx,4),%rcx
L66:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  lea    -0x1(%rax),%edx
  cmp    %edx,%r15d
  jg     L66
L165:
  cmp    %r14d,%ebx
  jl     L164
  sub    %r14d,%ebx
  movslq %r14d,%r14
  lea    0x0(%rbp,%r14,4),%rcx
  mov    $0x0,%eax
L60:
  mov    (%r12,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rbx,%rdx
  jne    L60
L164:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  cmp    %r13d,%ecx
  jg     L159
  cmp    %r8d,%r15d
  jle    L165
L69:
  cltq
  movslq %ecx,%rcx
  sub    %rax,%rcx
  lea    0x0(%rbp,%rcx,4),%rcx
L104:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  lea    -0x1(%rax),%edx
  cmp    %edx,%r15d
  jg     L104
  jmp    L165
L161:
  cmp    %r13d,%r14d
  jg     L178
  mov    %r14d,%ecx
  mov    $0x0,%eax
  jmp    L69
```

assistant: ```c
void merge_version1(int *arr, int begin, int m, int end) {
  int *t = malloc((end - begin + 1) * sizeof(int));
  int length = end - begin + 1;
  int i, j, k;
  assert(begin <= m && m < end);
  j = begin;
  k = m + 1;
  for (i = 0; i < length; i++) {
    if (j <= m && k <= end) {
      if (arr[j] <= arr[k]) {
        t[i] = arr[j];
        j++;
      } else {
        t[i] = arr[k];
        k++;
      }
    } else {
      int l;
      if (j > m)
        for (l = i; l < length; l++)
          t[l] = arr[k++];
      else
        for (l = i; l < length; l++)
          t[l] = arr[j++];
      break;
    }
  }
  j = 0;
  for (i = begin; i <= end; i++, j++) {
    arr[i] = t[j];
  }
  free(t);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<merge_version1>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  movslq %esi,%r13
  push   %r12
  sub    %r13d,%r14d
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%r14),%edx
  push   %rbx
  lea    0x0(,%rdx,4),%edi
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  call   <malloc@plt>
  cmp    %r15d,%r13d
  setle  %sil
  xor    %edi,%edi
  cmp    %r15d,%ebx
  mov    %rax,%rbp
  setg   %dil
  mov    %sil,0xb(%rsp)
  and    %esi,%edi
  call   <assert@plt>
  mov    0xc(%rsp),%edx
  movzbl 0xb(%rsp),%esi
  test   %edx,%edx
  jle    L110
  lea    0x1(%r15),%ecx
  cmp    %ecx,%ebx
  jl     L26
  test   %sil,%sil
  je     L26
  mov    %r14d,%r8d
  mov    %r13d,%esi
  mov    $0x1,%eax
  add    $0x1,%r8
  jmp    L3
  nopl   0x0(%rax)
L175:
  mov    %edi,%edx
  add    $0x1,%esi
  mov    %edx,-0x4(%rbp,%rax,4)
  mov    %eax,%edx
  cmp    %r8,%rax
  je     L110
L5:
  add    $0x1,%rax
  cmp    %r15d,%esi
  jg     L56
  cmp    %ebx,%ecx
  jg     L52
L3:
  movslq %esi,%rdx
  mov    (%r12,%rdx,4),%edi
  movslq %ecx,%rdx
  mov    (%r12,%rdx,4),%edx
  cmp    %edx,%edi
  jle    L175
  mov    %edx,-0x4(%rbp,%rax,4)
  add    $0x1,%ecx
  mov    %eax,%edx
  cmp    %r8,%rax
  jne    L5
L110:
  cmp    %r13d,%ebx
  jl     L106
  sub    %r13d,%ebx
  lea    (%r12,%r13,4),%rcx
  xor    %eax,%eax
  nop
L154:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rbx
  jne    L154
L106:
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
  nopl   0x0(%rax)
L52:
  cmp    %r15d,%esi
  jg     L56
L157:
  movslq %edx,%rax
  movslq %esi,%rsi
  sub    %rax,%rsi
  lea    (%r12,%rsi,4),%rcx
  nopw   0x0(%rax,%rax,1)
L99:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  lea    -0x1(%rax),%edx
  cmp    %edx,%r14d
  jg     L99
  jmp    L110
L105:
  xor    %edx,%edx
  nop
L56:
  movslq %edx,%rax
  movslq %ecx,%rcx
  sub    %rax,%rcx
  lea    (%r12,%rcx,4),%rcx
  nopl   (%rax)
L1:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  lea    -0x1(%rax),%edx
  cmp    %edx,%r14d
  jg     L1
  jmp    L110
L26:
  cmp    %r15d,%r13d
  jg     L105
  mov    %r13d,%esi
  xor    %edx,%edx
  jmp    L157
```

assistant: ```c
void merge_version1(int *arr, int begin, int m, int end) {
  int *t = malloc((end - begin + 1) * sizeof(int));
  int length = end - begin + 1;
  int i, j, k;
  assert(begin <= m && m < end);
  j = begin;
  k = m + 1;
  for (i = 0; i < length; i++) {
    if (j <= m && k <= end) {
      if (arr[j] <= arr[k]) {
        t[i] = arr[j];
        j++;
      } else {
        t[i] = arr[k];
        k++;
      }
    } else {
      int l;
      if (j > m)
        for (l = i; l < length; l++)
          t[l] = arr[k++];
      else
        for (l = i; l < length; l++)
          t[l] = arr[j++];
      break;
    }
  }
  j = 0;
  for (i = begin; i <= end; i++, j++) {
    arr[i] = t[j];
  }
  free(t);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unicode_parse_base64_to_code_points>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <base64_decode@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <unicode_read_string_utf16be@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x40(%rbp),%rax
  add    %rax,%rcx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void unicode_parse_base64_to_code_points(char *string, uint32_t *code_points, size_t *code_points_length_ptr) {
  size_t data_length, utf16_code_points_length;
  uint32_t *utf16_code_points;
  char *data;
  data = base64_decode(string, &data_length);
  utf16_code_points = unicode_read_string_utf16be((char *)data, data_length, &utf16_code_points_length);
  memcpy(&code_points[*code_points_length_ptr], utf16_code_points, sizeof(uint32_t) * utf16_code_points_length);
  *code_points_length_ptr += utf16_code_points_length;
  free(utf16_code_points);
  free(data);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<unicode_parse_base64_to_code_points>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <base64_decode@plt>
  mov    %rax,%r13
  lea    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rax,%rdi
  call   <unicode_read_string_utf16be@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  add    (%rbx),%rdi
  mov    0x10(%rsp),%edx
  mov    %rax,%rsi
  call   <memcpy@plt>
  mov    0x10(%rsp),%rax
  add    %rax,(%rbx)
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unicode_parse_base64_to_code_points(char *string, uint32_t *code_points, size_t *code_points_length_ptr) {
  size_t data_length, utf16_code_points_length;
  uint32_t *utf16_code_points;
  char *data;
  data = base64_decode(string, &data_length);
  utf16_code_points = unicode_read_string_utf16be((char *)data, data_length, &utf16_code_points_length);
  memcpy(&code_points[*code_points_length_ptr], utf16_code_points, sizeof(uint32_t) * utf16_code_points_length);
  *code_points_length_ptr += utf16_code_points_length;
  free(utf16_code_points);
  free(data);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unicode_parse_base64_to_code_points>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <base64_decode@plt>
  mov    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <unicode_read_string_utf16be@plt>
  mov    (%rbx),%rdi
  mov    0x10(%rsp),%edx
  mov    %rax,%rsi
  mov    %rax,%r13
  add    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x10(%rsp),%rax
  add    %rax,(%rbx)
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unicode_parse_base64_to_code_points(char *string, uint32_t *code_points, size_t *code_points_length_ptr) {
  size_t data_length, utf16_code_points_length;
  uint32_t *utf16_code_points;
  char *data;
  data = base64_decode(string, &data_length);
  utf16_code_points = unicode_read_string_utf16be((char *)data, data_length, &utf16_code_points_length);
  memcpy(&code_points[*code_points_length_ptr], utf16_code_points, sizeof(uint32_t) * utf16_code_points_length);
  *code_points_length_ptr += utf16_code_points_length;
  free(utf16_code_points);
  free(data);
}
```
user: What is the c source code of the assembly code below?

```asm
<unicode_parse_base64_to_code_points>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <base64_decode@plt>
  mov    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <unicode_read_string_utf16be@plt>
  mov    (%rbx),%rdi
  mov    0x10(%rsp),%edx
  mov    %rax,%rsi
  mov    %rax,%r13
  add    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x10(%rsp),%rax
  add    %rax,(%rbx)
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unicode_parse_base64_to_code_points(char *string, uint32_t *code_points, size_t *code_points_length_ptr) {
  size_t data_length, utf16_code_points_length;
  uint32_t *utf16_code_points;
  char *data;
  data = base64_decode(string, &data_length);
  utf16_code_points = unicode_read_string_utf16be((char *)data, data_length, &utf16_code_points_length);
  memcpy(&code_points[*code_points_length_ptr], utf16_code_points, sizeof(uint32_t) * utf16_code_points_length);
  *code_points_length_ptr += utf16_code_points_length;
  free(utf16_code_points);
  free(data);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sig_segment_fault>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D0: sig number is %d


assistant: ```c
void sig_segment_fault(int signo) {
  printf("sig number is %d\n", signo);
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<sig_segment_fault>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: sig number is %d


assistant: ```c
void sig_segment_fault(int signo) {
  printf("sig number is %d\n", signo);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sig_segment_fault>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: sig number is %d


assistant: ```c
void sig_segment_fault(int signo) {
  printf("sig number is %d\n", signo);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sig_segment_fault>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string

tool: D8: sig number is %d


assistant: ```c
void sig_segment_fault(int signo) {
  printf("sig number is %d\n", signo);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ceil_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x20,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L24:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L2
  mov    -0xc(%rbp),%eax
  jmp    L5
L2:
  mov    $0x0,%eax
L5:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shrq   %cl,-0x18(%rbp)
  sarl   -0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  cmpl   $0x5,-0x8(%rbp)
  jle    L24
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: 

assistant: ```c
int ceil_log2(unsigned long long x) {
  static const unsigned long long t[6] = {0xFFFFFFFF00000000ull, 0x00000000FFFF0000ull, 0x000000000000FF00ull, 0x00000000000000F0ull, 0x000000000000000Cull, 0x0000000000000002ull};
  int y = (((x & (x - 1)) == 0) ? 0 : 1);
  int j = 32;
  int i;
  for (i = 0; i < 6; i++) {
    int k = (((x & t[i]) == 0) ? 0 : j);
    y += k;
    x >>= k;
    j >>= 1;
  }
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ceil_log2>:
  endbr64
  lea    -0x1(%rdi),%rax
  test   %rdi,%rax
  setne  %sil
  movzbl %sil,%esi
  lea    D5(%rip),%rax
  lea    0x30(%rax),%r9
  mov    $0x20,%edx
  mov    $0x0,%r8d
L0:
  mov    %rdi,%rcx
  and    (%rax),%rcx
  mov    %r8d,%ecx
  cmovne %edx,%ecx
  add    %ecx,%esi
  shr    %cl,%rdi
  sar    %edx
  add    $0x8,%rax
  cmp    %r9,%rax
  jne    L0
  mov    %esi,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: 

assistant: ```c
int ceil_log2(unsigned long long x) {
  static const unsigned long long t[6] = {0xFFFFFFFF00000000ull, 0x00000000FFFF0000ull, 0x000000000000FF00ull, 0x00000000000000F0ull, 0x000000000000000Cull, 0x0000000000000002ull};
  int y = (((x & (x - 1)) == 0) ? 0 : 1);
  int j = 32;
  int i;
  for (i = 0; i < 6; i++) {
    int k = (((x & t[i]) == 0) ? 0 : j);
    y += k;
    x >>= k;
    j >>= 1;
  }
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ceil_log2>:
  endbr64
  lea    -0x1(%rdi),%rax
  xor    %r8d,%r8d
  mov    $0x20,%ecx
  movabs $0xffffffff00000000,%rdx
  test   %rdi,%rax
  lea    D8(%rip),%rax
  setne  %r8b
  lea    0x30(%rax),%rsi
  jmp    L26
  xchg   %ax,%ax
L21:
  mov    (%rax),%rdx
L26:
  test   %rdi,%rdx
  je     L28
  add    %ecx,%r8d
  shr    %cl,%rdi
L28:
  add    $0x8,%rax
  sar    %ecx
  cmp    %rsi,%rax
  jne    L21
  mov    %r8d,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: 

assistant: ```c
int ceil_log2(unsigned long long x) {
  static const unsigned long long t[6] = {0xFFFFFFFF00000000ull, 0x00000000FFFF0000ull, 0x000000000000FF00ull, 0x00000000000000F0ull, 0x000000000000000Cull, 0x0000000000000002ull};
  int y = (((x & (x - 1)) == 0) ? 0 : 1);
  int j = 32;
  int i;
  for (i = 0; i < 6; i++) {
    int k = (((x & t[i]) == 0) ? 0 : j);
    y += k;
    x >>= k;
    j >>= 1;
  }
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ceil_log2>:
  endbr64
  movabs $0xffffffff00000000,%rdx
  lea    -0x1(%rdi),%rax
  test   %rdi,%rax
  setne  %al
  movzbl %al,%eax
  test   %rdx,%rdi
  je     L13
  add    $0x20,%eax
  shr    $0x20,%rdi
L13:
  test   $0xffff0000,%edi
  je     L26
  add    $0x10,%eax
  shr    $0x10,%rdi
L26:
  test   $0xff00,%edi
  je     L9
  add    $0x8,%eax
  shr    $0x8,%rdi
L9:
  test   $0xf0,%dil
  je     L2
  add    $0x4,%eax
  shr    $0x4,%rdi
L2:
  test   $0xc,%dil
  je     L25
  add    $0x2,%eax
  shr    $0x2,%rdi
L25:
  and    $0x2,%edi
  cmp    $0x1,%rdi
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int ceil_log2(unsigned long long x) {
  static const unsigned long long t[6] = {0xFFFFFFFF00000000ull, 0x00000000FFFF0000ull, 0x000000000000FF00ull, 0x00000000000000F0ull, 0x000000000000000Cull, 0x0000000000000002ull};
  int y = (((x & (x - 1)) == 0) ? 0 : 1);
  int j = 32;
  int i;
  for (i = 0; i < 6; i++) {
    int k = (((x & t[i]) == 0) ? 0 : j);
    y += k;
    x >>= k;
    j >>= 1;
  }
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cset_gate_Lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    $0x1,%ecx
  jmp    1112 <cset_gate_Lock_check>
```

assistant: ```c
extern void cset_gate_Lock(volatile int *gate) {
  asm volatile("jmp cset_gate_Lock_check\n"
               "cset_gate_Lock_wait:\n"
               "pause\n"
               "cset_gate_Lock_check:\n"
               "mov %[lock], %%eax\n"
               "cmp %[gate], %%eax\n"
               "je cset_gate_Lock_wait\n"
               "lock xchg %%eax, %[gate]\n"
               "test %%eax, %%eax\n"
               "jnz cset_gate_Lock_wait\n"
               : [gate] "=m"(*gate)
               : [lock] "r"(1)
               : "eax");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cset_gate_Lock>:
  endbr64
  mov    $0x1,%edx
  jmp    1106 <cset_gate_Lock_check>
```

assistant: ```c
extern void cset_gate_Lock(volatile int *gate) {
  asm volatile("jmp cset_gate_Lock_check\n"
               "cset_gate_Lock_wait:\n"
               "pause\n"
               "cset_gate_Lock_check:\n"
               "mov %[lock], %%eax\n"
               "cmp %[gate], %%eax\n"
               "je cset_gate_Lock_wait\n"
               "lock xchg %%eax, %[gate]\n"
               "test %%eax, %%eax\n"
               "jnz cset_gate_Lock_wait\n"
               : [gate] "=m"(*gate)
               : [lock] "r"(1)
               : "eax");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cset_gate_Lock>:
  endbr64
  mov    $0x1,%edx
  jmp    110d <cset_gate_Lock_check>
```

assistant: ```c
extern void cset_gate_Lock(volatile int *gate) {
  asm volatile("jmp cset_gate_Lock_check\n"
               "cset_gate_Lock_wait:\n"
               "pause\n"
               "cset_gate_Lock_check:\n"
               "mov %[lock], %%eax\n"
               "cmp %[gate], %%eax\n"
               "je cset_gate_Lock_wait\n"
               "lock xchg %%eax, %[gate]\n"
               "test %%eax, %%eax\n"
               "jnz cset_gate_Lock_wait\n"
               : [gate] "=m"(*gate)
               : [lock] "r"(1)
               : "eax");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <hmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *hstrdup(const char *s) {
  char *p;
  p = (char *)hmalloc(strlen(s) + 1);
  strcpy(p, s);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<hstrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <hmalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *hstrdup(const char *s) {
  char *p;
  p = (char *)hmalloc(strlen(s) + 1);
  strcpy(p, s);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hstrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <hmalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *hstrdup(const char *s) {
  char *p;
  p = (char *)hmalloc(strlen(s) + 1);
  strcpy(p, s);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hstrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <hmalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *hstrdup(const char *s) {
  char *p;
  p = (char *)hmalloc(strlen(s) + 1);
  strcpy(p, s);
  return p;
}
```