ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<save_cmd_status>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%esi
  mov    $0x4,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  call   <uitoa@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <save_var@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: ?

assistant: ```c
void save_cmd_status(int status) {
  char str_status[4] = {0};
  save_var("?", uitoa((uint)status, 10, str_status, 4));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sd_array_insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L4
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sd_array_push@plt>
  jmp    L15
L4:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <memmove@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L15:
  nop
  leave
  ret
```

assistant: ```c
void sd_array_insert(void *mem, size_t item_size, int *num_size, int index, void *new_item) {
  if (index == *num_size) {
    sd_array_push(mem, item_size, num_size, new_item);
  } else {
    size_t off = item_size * index;
    size_t size = item_size * (*num_size - index);
    memmove((char *)mem + off + item_size, (char *)mem + off, size);
    memcpy((char *)mem + off, new_item, item_size);
    (*num_size)++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sd_array_insert>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %r8,%r12
  mov    (%rdx),%edx
  cmp    %ecx,%edx
  je     L0
  movslq %ecx,%rax
  imul   %rsi,%rax
  lea    (%rdi,%rax,1),%r13
  sub    %ecx,%edx
  movslq %edx,%rdx
  imul   %rsi,%rdx
  add    %rsi,%rax
  add    %rax,%rdi
  mov    %r13,%rsi
  call   <memmove@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  addl   $0x1,0x0(%rbp)
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %r8,%rcx
  mov    %rbp,%rdx
  call   <sd_array_push@plt>
  jmp    L4
```

assistant: ```c
void sd_array_insert(void *mem, size_t item_size, int *num_size, int index, void *new_item) {
  if (index == *num_size) {
    sd_array_push(mem, item_size, num_size, new_item);
  } else {
    size_t off = item_size * index;
    size_t size = item_size * (*num_size - index);
    memmove((char *)mem + off + item_size, (char *)mem + off, size);
    memcpy((char *)mem + off, new_item, item_size);
    (*num_size)++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sd_array_insert>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %r8,%rbp
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  cmp    %ecx,%edx
  je     L1
  movslq %ecx,%rax
  sub    %ecx,%edx
  imul   %rsi,%rax
  movslq %edx,%rdx
  imul   %rsi,%rdx
  lea    (%rdi,%rax,1),%r14
  add    %rsi,%rax
  add    %rax,%rdi
  mov    %r14,%rsi
  call   <memmove@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  addl   $0x1,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L1:
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r8,%rcx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <sd_array_push@plt>
```

assistant: ```c
void sd_array_insert(void *mem, size_t item_size, int *num_size, int index, void *new_item) {
  if (index == *num_size) {
    sd_array_push(mem, item_size, num_size, new_item);
  } else {
    size_t off = item_size * index;
    size_t size = item_size * (*num_size - index);
    memmove((char *)mem + off + item_size, (char *)mem + off, size);
    memcpy((char *)mem + off, new_item, item_size);
    (*num_size)++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sd_array_insert>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %r8,%rbp
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  cmp    %ecx,%edx
  je     L8
  movslq %ecx,%rax
  sub    %ecx,%edx
  imul   %rsi,%rax
  movslq %edx,%rdx
  imul   %rsi,%rdx
  lea    (%rdi,%rax,1),%r14
  add    %rsi,%rax
  add    %rax,%rdi
  mov    %r14,%rsi
  call   <memmove@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  addl   $0x1,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L8:
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r8,%rcx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <sd_array_push@plt>
```

assistant: ```c
void sd_array_insert(void *mem, size_t item_size, int *num_size, int index, void *new_item) {
  if (index == *num_size) {
    sd_array_push(mem, item_size, num_size, new_item);
  } else {
    size_t off = item_size * index;
    size_t size = item_size * (*num_size - index);
    memmove((char *)mem + off + item_size, (char *)mem + off, size);
    memcpy((char *)mem + off, new_item, item_size);
    (*num_size)++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap_pointers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_pointers(char **x, char **y) {
  char *tmp;
  tmp = *x;
  *x = *y;
  *y = tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap_pointers>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap_pointers(char **x, char **y) {
  char *tmp;
  tmp = *x;
  *x = *y;
  *y = tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap_pointers>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap_pointers(char **x, char **y) {
  char *tmp;
  tmp = *x;
  *x = *y;
  *y = tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_pointers>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap_pointers(char **x, char **y) {
  char *tmp;
  tmp = *x;
  *x = *y;
  *y = tmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<cel_fnv_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    $0x811c9dc5,%ebx
  movl   $0x1000193,-0xc(%rbp)
  jmp    L3
L12:
  imul   -0xc(%rbp),%ebx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,%ebx
L3:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    %ebx,%eax
  and    $0x7fffffff,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
extern uint32_t cel_fnv_hash(const char *str) {
  register uint32_t h = 2166136261UL;
  uint32_t prime = 16777619;
  while (*str != '\0') {
    h *= prime;
    h ^= *str++;
  }
  return (h & 0x7FFFFFFF);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cel_fnv_hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L26
  mov    $0x811c9dc5,%eax
L24:
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdi
  movsbl %dl,%edx
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L24
L14:
  and    $0x7fffffff,%eax
  ret
L26:
  mov    $0x811c9dc5,%eax
  jmp    L14
```

assistant: ```c
extern uint32_t cel_fnv_hash(const char *str) {
  register uint32_t h = 2166136261UL;
  uint32_t prime = 16777619;
  while (*str != '\0') {
    h *= prime;
    h ^= *str++;
  }
  return (h & 0x7FFFFFFF);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cel_fnv_hash>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L1
  mov    $0x811c9dc5,%eax
L8:
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L8
  and    $0x7fffffff,%eax
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x11c9dc5,%eax
  ret
```

assistant: ```c
extern uint32_t cel_fnv_hash(const char *str) {
  register uint32_t h = 2166136261UL;
  uint32_t prime = 16777619;
  while (*str != '\0') {
    h *= prime;
    h ^= *str++;
  }
  return (h & 0x7FFFFFFF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cel_fnv_hash>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L18
  mov    $0x811c9dc5,%eax
L5:
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L5
  and    $0x7fffffff,%eax
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x11c9dc5,%eax
  ret
```

assistant: ```c
extern uint32_t cel_fnv_hash(const char *str) {
  register uint32_t h = 2166136261UL;
  uint32_t prime = 16777619;
  while (*str != '\0') {
    h *= prime;
    h ^= *str++;
  }
  return (h & 0x7FFFFFFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f1@plt>
  mov    $0x0,%eax
  call   <f2@plt>
  mov    $0x0,%eax
  call   <g1@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <g2@plt>
  cmp    %rax,%rbx
  je     L9
  mov    $0x0,%eax
  call   <abort@plt>
L9:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main() {
  f1();
  f2();
  if (g1() != g2())
    abort();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <f1@plt>
  mov    $0x0,%eax
  call   <f2@plt>
  mov    $0x0,%eax
  call   <g1@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <g2@plt>
  cmp    %rax,%rbx
  jne    L4
L14:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L4:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L14
```

assistant: ```c
int main() {
  f1();
  f2();
  if (g1() != g2())
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <f1@plt>
  xor    %eax,%eax
  call   <f2@plt>
  xor    %eax,%eax
  call   <g1@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <g2@plt>
  cmp    %rax,%rbx
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  f1();
  f2();
  if (g1() != g2())
    abort();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <f1@plt>
  xor    %eax,%eax
  call   <f2@plt>
  xor    %eax,%eax
  call   <g1@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <g2@plt>
  cmp    %rax,%rbx
  je     L2
  xor    %eax,%eax
  call   <abort@plt>
L2:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  f1();
  f2();
  if (g1() != g2())
    abort();
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mlr_try_double_from_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L3
  mov    $0x0,%eax
  jmp    L44
L3:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  mov    $0x0,%eax
  jmp    L44
L32:
  mov    $0x1,%eax
L44:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %lf%n

assistant: ```c
int mlr_try_double_from_string(char *string, double *pval) {
  int num_bytes_scanned;
  int rc = sscanf(string, "%lf%n", pval, &num_bytes_scanned);
  if (rc != 1)
    return 0;
  if (string[num_bytes_scanned] != 0)
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mlr_try_double_from_string>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  lea    D6(%rip),%rsi
  call   <sscanf@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  jne    L10
  movslq 0x4(%rsp),%rax
  cmpb   $0x0,(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: %lf%n

assistant: ```c
int mlr_try_double_from_string(char *string, double *pval) {
  int num_bytes_scanned;
  int rc = sscanf(string, "%lf%n", pval, &num_bytes_scanned);
  if (rc != 1)
    return 0;
  if (string[num_bytes_scanned] != 0)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mlr_try_double_from_string>:
  endbr64
  push   %rbx
  mov    %rsi,%rdx
  lea    D8(%rip),%rsi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  call   <sscanf@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jne    L16
  movslq 0x4(%rsp),%rax
  cmpb   $0x0,(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string

tool: D8: %lf%n

assistant: ```c
int mlr_try_double_from_string(char *string, double *pval) {
  int num_bytes_scanned;
  int rc = sscanf(string, "%lf%n", pval, &num_bytes_scanned);
  if (rc != 1)
    return 0;
  if (string[num_bytes_scanned] != 0)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mlr_try_double_from_string>:
  endbr64
  push   %rbx
  mov    %rsi,%rdx
  lea    D1(%rip),%rsi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  call   <sscanf@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jne    L5
  movslq 0x4(%rsp),%rax
  cmpb   $0x0,(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %lf%n

assistant: ```c
int mlr_try_double_from_string(char *string, double *pval) {
  int num_bytes_scanned;
  int rc = sscanf(string, "%lf%n", pval, &num_bytes_scanned);
  if (rc != 1)
    return 0;
  if (string[num_bytes_scanned] != 0)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<write_standard_target_Laurent_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x2fa,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int write_standard_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(762, a, b, c, 0);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_standard_target_Laurent_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x2fa,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int write_standard_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(762, a, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_standard_target_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x2fa,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int write_standard_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(762, a, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FS_Init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <FS_X_OS_Init@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    $0x0,%eax
  call   <FS__fat_block_init@plt>
L7:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int FS_Init(void) {
  int x;
  x = FS_X_OS_Init();
  if (x == 0) {
    FS__fat_block_init();
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FS_Init>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <FS_X_OS_Init@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L10
L4:
  mov    %ebx,%eax
  pop    %rbx
  ret
L10:
  mov    $0x0,%eax
  call   <FS__fat_block_init@plt>
  jmp    L4
```

assistant: ```c
int FS_Init(void) {
  int x;
  x = FS_X_OS_Init();
  if (x == 0) {
    FS__fat_block_init();
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FS_Init>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <FS_X_OS_Init@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L0
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <FS__fat_block_init@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int FS_Init(void) {
  int x;
  x = FS_X_OS_Init();
  if (x == 0) {
    FS__fat_block_init();
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FS_Init>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <FS_X_OS_Init@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L1
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <FS__fat_block_init@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int FS_Init(void) {
  int x;
  x = FS_X_OS_Init();
  if (x == 0) {
    FS__fat_block_init();
  }
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<import64>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbx
  movzbl 0x7(%rdi),%ecx
  movzbl 0x6(%rdi),%edx
  movzbl 0x5(%rdi),%r8d
  movzbl 0x4(%rdi),%r9d
  movzbl 0x3(%rdi),%r10d
  movzbl 0x2(%rdi),%r11d
  movzbl 0x1(%rdi),%ebx
  movzbl (%rdi),%edi
  test   %r12d,%r12d
  je     L24
  test   %esi,%esi
  jne    L31
L23:
  mov    %r9d,%eax
  movzbl %r10b,%r9d
  movzbl %al,%r10d
  mov    %r8d,%eax
  movzbl %r11b,%r8d
  movzbl %al,%r11d
  mov    %edx,%eax
  movzbl %bl,%edx
  mov    %eax,%ebx
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %eax,%edi
L31:
  shl    $0x10,%r11
  xor    %eax,%eax
  shl    $0x18,%r10
  movabs $0xffffffff00ffffff,%rsi
  shl    $0x20,%r9
  mov    %dil,%al
  shl    $0x28,%r8
  shl    $0x30,%rdx
  mov    %bl,%ah
  shl    $0x38,%rcx
  pop    %rbx
  and    $0xffffffffff00ffff,%rax
  pop    %r12
  or     %r11,%rax
  and    %rsi,%rax
  movabs $0xffffff00ffffffff,%rsi
  or     %r10,%rax
  and    %rsi,%rax
  movabs $0xffff00ffffffffff,%rsi
  or     %r9,%rax
  and    %rsi,%rax
  movabs $0xff00ffffffffffff,%rsi
  or     %r8,%rax
  and    %rsi,%rax
  or     %rdx,%rax
  movabs $0xffffffffffffff,%rdx
  and    %rdx,%rax
  or     %rcx,%rax
  movq   %rax,%xmm0
  ret
  xchg   %ax,%ax
L24:
  test   %esi,%esi
  je     L31
  jmp    L23
```

assistant: ```c
double import64(char *p, int little_endian, int little_endian_arch) {
  union cvt {
    unsigned char byte[8];
    double double_value;
  } convert;
  if (little_endian_arch) {
    if (!little_endian) {
      convert.byte[0] = *(p + 7);
      convert.byte[1] = *(p + 6);
      convert.byte[2] = *(p + 5);
      convert.byte[3] = *(p + 4);
      convert.byte[4] = *(p + 3);
      convert.byte[5] = *(p + 2);
      convert.byte[6] = *(p + 1);
      convert.byte[7] = *(p + 0);
    } else {
      convert.byte[0] = *(p + 0);
      convert.byte[1] = *(p + 1);
      convert.byte[2] = *(p + 2);
      convert.byte[3] = *(p + 3);
      convert.byte[4] = *(p + 4);
      convert.byte[5] = *(p + 5);
      convert.byte[6] = *(p + 6);
      convert.byte[7] = *(p + 7);
    }
  } else {
    if (!little_endian) {
      convert.byte[0] = *(p + 0);
      convert.byte[1] = *(p + 1);
      convert.byte[2] = *(p + 2);
      convert.byte[3] = *(p + 3);
      convert.byte[4] = *(p + 4);
      convert.byte[5] = *(p + 5);
      convert.byte[6] = *(p + 6);
      convert.byte[7] = *(p + 7);
    } else {
      convert.byte[0] = *(p + 7);
      convert.byte[1] = *(p + 6);
      convert.byte[2] = *(p + 5);
      convert.byte[3] = *(p + 4);
      convert.byte[4] = *(p + 3);
      convert.byte[5] = *(p + 2);
      convert.byte[6] = *(p + 1);
      convert.byte[7] = *(p + 0);
    }
  }
  return convert.double_value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<import64>:
  endbr64
  mov    (%rdi),%rax
  movq   (%rdi),%xmm0
  bswap  %rax
  test   %edx,%edx
  je     L26
  test   %esi,%esi
  jne    L8
L16:
  movq   %rax,%xmm0
L8:
  ret
  nopl   0x0(%rax)
L26:
  test   %esi,%esi
  jne    L16
  ret
```

assistant: ```c
double import64(char *p, int little_endian, int little_endian_arch) {
  union cvt {
    unsigned char byte[8];
    double double_value;
  } convert;
  if (little_endian_arch) {
    if (!little_endian) {
      convert.byte[0] = *(p + 7);
      convert.byte[1] = *(p + 6);
      convert.byte[2] = *(p + 5);
      convert.byte[3] = *(p + 4);
      convert.byte[4] = *(p + 3);
      convert.byte[5] = *(p + 2);
      convert.byte[6] = *(p + 1);
      convert.byte[7] = *(p + 0);
    } else {
      convert.byte[0] = *(p + 0);
      convert.byte[1] = *(p + 1);
      convert.byte[2] = *(p + 2);
      convert.byte[3] = *(p + 3);
      convert.byte[4] = *(p + 4);
      convert.byte[5] = *(p + 5);
      convert.byte[6] = *(p + 6);
      convert.byte[7] = *(p + 7);
    }
  } else {
    if (!little_endian) {
      convert.byte[0] = *(p + 0);
      convert.byte[1] = *(p + 1);
      convert.byte[2] = *(p + 2);
      convert.byte[3] = *(p + 3);
      convert.byte[4] = *(p + 4);
      convert.byte[5] = *(p + 5);
      convert.byte[6] = *(p + 6);
      convert.byte[7] = *(p + 7);
    } else {
      convert.byte[0] = *(p + 7);
      convert.byte[1] = *(p + 6);
      convert.byte[2] = *(p + 5);
      convert.byte[3] = *(p + 4);
      convert.byte[4] = *(p + 3);
      convert.byte[5] = *(p + 2);
      convert.byte[6] = *(p + 1);
      convert.byte[7] = *(p + 0);
    }
  }
  return convert.double_value;
}
```