ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2,0x10(%rsp)
  mov    %rsp,%r14
  movaps %xmm0,(%rsp)
L15:
  mov    (%r14,%rbx,4),%ebp
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  mov    %ebp,%edx
  add    %ebp,%r12d
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L15
  mov    %r12d,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  cvtsi2sd %r12d,%xmm0
  divsd  D5(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type: string
name: disassemble_data
arguments: data_label: D8
type: byte[16]
name: disassemble_data
arguments: data_label: D2
type: string
name: disassemble_data
arguments: data_label: D33
type: string
name: disassemble_data
arguments: data_label: D5
type: f64

tool: D26: Vetor[%d] = %d


tool: {"D8": [0x08,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D2: Total = %d


tool: D33: Media = %.2f


tool: D5: 5

assistant: ```c
int main(int argc, char *argv[]) {
  int vetor[5];
  int i, c = 0;
  vetor[0] = 8;
  vetor[1] = 5;
  vetor[2] = 4;
  vetor[3] = 3;
  vetor[4] = 2;
  for (i = 0; i < 5; i++) {
    printf("Vetor[%d] = %d\n", i, vetor[i]);
    c += vetor[i];
  }
  printf("Total = %d\n", c);
  printf("Media = %.2f\n", c / 5.0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<jogada_correta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L23:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L3
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L49
L3:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L49:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x9,%eax
  jg     L23
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L23
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <jogada_valida@plt>
  test   %eax,%eax
  je     L23
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D20
datatype: string
name: disassemble_data
arguments: data_tag: D19
datatype: string

tool: D5: Digite a jogada jogador 2


tool: D20: Digite a jogada jogador 1


tool: D19: %d

assistant: ```c
int jogada_correta(int vetor_posicao[9], int i) {
  int jogada;
  do {
    if (i % 2 == 0) {
      printf("Digite a jogada jogador 2\n");
    } else {
      printf("Digite a jogada jogador 1\n");
    }
    scanf("%d", &jogada);
  } while ((jogada > 9 || jogada < 1) || !jogada_valida(vetor_posicao, jogada));
  return jogada;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jogada_correta>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%r13
  lea    D24(%rip),%r12
  lea    D27(%rip),%rbp
  jmp    L47
L1:
  mov    %r13,%rdi
  call   <printf@plt>
L46:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x8,%eax
  jbe    L23
L28:
  test   %ebx,%ebx
  jne    L1
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L46
L23:
  mov    %r15,%rdi
  call   <jogada_valida@plt>
  test   %eax,%eax
  jne    L0
L47:
  mov    %r14d,%ebx
  and    $0x1,%ebx
  jmp    L28
L0:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D27
type_infered: string

tool: D18: Digite a jogada jogador 1


tool: D24: Digite a jogada jogador 2


tool: D27: %d

assistant: ```c
int jogada_correta(int vetor_posicao[9], int i) {
  int jogada;
  do {
    if (i % 2 == 0) {
      printf("Digite a jogada jogador 2\n");
    } else {
      printf("Digite a jogada jogador 1\n");
    }
    scanf("%d", &jogada);
  } while ((jogada > 9 || jogada < 1) || !jogada_valida(vetor_posicao, jogada));
  return jogada;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<jogada_correta>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  mov    %esi,%ebx
  and    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    %r13,%rdi
  call   <printf@plt>
L39:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x8,%eax
  jbe    L54
L48:
  test   %ebx,%ebx
  je     L36
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L39
  nopl   (%rax)
L54:
  mov    %r15,%rdi
  call   <jogada_valida@plt>
  test   %eax,%eax
  je     L48
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D22
type: string

tool: D29: Digite a jogada jogador 1


tool: D11: Digite a jogada jogador 2


tool: D22: %d

assistant: ```c
int jogada_correta(int vetor_posicao[9], int i) {
  int jogada;
  do {
    if (i % 2 == 0) {
      printf("Digite a jogada jogador 2\n");
    } else {
      printf("Digite a jogada jogador 1\n");
    }
    scanf("%d", &jogada);
  } while ((jogada > 9 || jogada < 1) || !jogada_valida(vetor_posicao, jogada));
  return jogada;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<jogada_correta>:
  endbr64
  push   %r15
  and    $0x1,%esi
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   (%rax)
L49:
  test   %r14d,%r14d
  je     L43
  nopl   (%rax)
L14:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x8,%eax
  ja     L14
L26:
  mov    %r15,%rdi
  call   <jogada_valida@plt>
  test   %eax,%eax
  je     L49
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L43:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x8,%eax
  ja     L43
  jmp    L26
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: string
name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D10: Digite a jogada jogador 2


tool: D5: Digite a jogada jogador 1


tool: D4: %d

assistant: ```c
int jogada_correta(int vetor_posicao[9], int i) {
  int jogada;
  do {
    if (i % 2 == 0) {
      printf("Digite a jogada jogador 2\n");
    } else {
      printf("Digite a jogada jogador 1\n");
    }
    scanf("%d", &jogada);
  } while ((jogada > 9 || jogada < 1) || !jogada_valida(vetor_posicao, jogada));
  return jogada;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_subpolygon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x35,%edi
  call   <free_object@plt>
  mov    $0x0,%eax
  call   <error@plt>
  test   %rax,%rax
  leave
  ret
```

assistant: ```c
void free_subpolygon(struct subpolygon *spg) {
  free_object(53, (short *)spg);
  if (error())
    return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<free_subpolygon>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x35,%edi
  call   <free_object@plt>
  mov    $0x0,%eax
  call   <error@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void free_subpolygon(struct subpolygon *spg) {
  free_object(53, (short *)spg);
  if (error())
    return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_subpolygon>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x35,%edi
  call   <free_object@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <error@plt>
```

assistant: ```c
void free_subpolygon(struct subpolygon *spg) {
  free_object(53, (short *)spg);
  if (error())
    return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_subpolygon>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x35,%edi
  call   <free_object@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <error@plt>
```

assistant: ```c
void free_subpolygon(struct subpolygon *spg) {
  free_object(53, (short *)spg);
  if (error())
    return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x0,%eax
  call   <g@plt>
  mov    $0x0,%eax
  call   <h@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo() {
  f();
  g();
  h();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x0,%eax
  call   <g@plt>
  mov    $0x0,%eax
  call   <h@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo() {
  f();
  g();
  h();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <h@plt>
```

assistant: ```c
void foo() {
  f();
  g();
  h();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <h@plt>
```

assistant: ```c
void foo() {
  f();
  g();
  h();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<proc_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D4(%rip),%eax
  test   %eax,%eax
  jne    L0
  mov    $0x0,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movl   $0x1,D4(%rip)
L0:
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  mov    D28(%rip),%edx
  sub    %edx,%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  mov    D44(%rip),%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
long proc_ms(void) {
  struct timeval t;
  static int init = 0;
  static struct timeval s;
  if (!init) {
    gettimeofday(&s, 0);
    init = 1;
  }
  gettimeofday(&t, 0);
  return (t.tv_sec - s.tv_sec) * 1000 + (t.tv_usec - s.tv_usec) / 1000;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<proc_ms>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpl   $0x0,D3(%rip)
  je     L3
L28:
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    (%rsp),%eax
  sub    D16(%rip),%eax
  imul   $0x3e8,%eax,%eax
  mov    0x4(%rsp),%ecx
  sub    D48(%rip),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  cltq
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
L3:
  mov    $0x0,%esi
  lea    D16(%rip),%rdi
  call   <gettimeofday@plt>
  movl   $0x1,D3(%rip)
  jmp    L28
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long proc_ms(void) {
  struct timeval t;
  static int init = 0;
  static struct timeval s;
  if (!init) {
    gettimeofday(&s, 0);
    init = 1;
  }
  gettimeofday(&t, 0);
  return (t.tv_sec - s.tv_sec) * 1000 + (t.tv_usec - s.tv_usec) / 1000;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<proc_ms>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D20(%rip),%eax
  test   %eax,%eax
  je     L8
L2:
  mov    %rsp,%rdi
  xor    %esi,%esi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%ecx
  sub    D3(%rip),%ecx
  movslq %ecx,%rdx
  mov    (%rsp),%eax
  sub    D47(%rip),%eax
  sar    $0x1f,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  imul   $0x3e8,%eax,%eax
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  cltq
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L8:
  xor    %esi,%esi
  lea    D47(%rip),%rdi
  call   <gettimeofday@plt>
  movl   $0x1,D20(%rip)
  jmp    L2
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long proc_ms(void) {
  struct timeval t;
  static int init = 0;
  static struct timeval s;
  if (!init) {
    gettimeofday(&s, 0);
    init = 1;
  }
  gettimeofday(&t, 0);
  return (t.tv_sec - s.tv_sec) * 1000 + (t.tv_usec - s.tv_usec) / 1000;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<proc_ms>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D46(%rip),%eax
  test   %eax,%eax
  je     L0
L21:
  mov    %rsp,%rdi
  xor    %esi,%esi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%ecx
  sub    D18(%rip),%ecx
  movslq %ecx,%rdx
  mov    (%rsp),%eax
  sub    D8(%rip),%eax
  sar    $0x1f,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  imul   $0x3e8,%eax,%eax
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  cltq
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L0:
  xor    %esi,%esi
  lea    D8(%rip),%rdi
  call   <gettimeofday@plt>
  movl   $0x1,D46(%rip)
  jmp    L21
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long proc_ms(void) {
  struct timeval t;
  static int init = 0;
  static struct timeval s;
  if (!init) {
    gettimeofday(&s, 0);
    init = 1;
  }
  gettimeofday(&t, 0);
  return (t.tv_sec - s.tv_sec) * 1000 + (t.tv_usec - s.tv_usec) / 1000;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<om_gsm_flowcontrol_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <om_gsm_flowcontrol_path@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L35
  mov    $0xffffffff,%eax
  jmp    L25
L35:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <om_sysfs_readfile@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0xffffffff,%eax
  jmp    L25
L0:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L25:
  leave
  ret
```

assistant: ```c
int om_gsm_flowcontrol_get() {
  const char *path = om_gsm_flowcontrol_path();
  if (path == NULL)
    return -1;
  const char *val = om_sysfs_readfile(path);
  if (val == NULL)
    return -1;
  return atoi(val);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<om_gsm_flowcontrol_get>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <om_gsm_flowcontrol_path@plt>
  test   %rax,%rax
  je     L31
  mov    %rax,%rdi
  call   <om_sysfs_readfile@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L38
  call   <atoi@plt>
L16:
  add    $0x8,%rsp
  ret
L31:
  mov    $0xffffffff,%eax
  jmp    L16
L38:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int om_gsm_flowcontrol_get() {
  const char *path = om_gsm_flowcontrol_path();
  if (path == NULL)
    return -1;
  const char *val = om_sysfs_readfile(path);
  if (val == NULL)
    return -1;
  return atoi(val);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<om_gsm_flowcontrol_get>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <om_gsm_flowcontrol_path@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  call   <om_sysfs_readfile@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  jmp    1090 <atoi@plt>
  nopl   (%rax)
L1:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int om_gsm_flowcontrol_get() {
  const char *path = om_gsm_flowcontrol_path();
  if (path == NULL)
    return -1;
  const char *val = om_sysfs_readfile(path);
  if (val == NULL)
    return -1;
  return atoi(val);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<om_gsm_flowcontrol_get>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <om_gsm_flowcontrol_path@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <om_sysfs_readfile@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  jmp    1090 <atoi@plt>
  nopl   (%rax)
L0:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int om_gsm_flowcontrol_get() {
  const char *path = om_gsm_flowcontrol_path();
  if (path == NULL)
    return -1;
  const char *val = om_sysfs_readfile(path);
  if (val == NULL)
    return -1;
  return atoi(val);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<remove_html_tags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L0
L3:
  mov    -0x18(%rbp),%rax
  mov    $0x3e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L0:
  mov    -0x18(%rbp),%rax
  mov    $0x3c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void remove_html_tags(char *buff) {
  while ((buff = strchr(buff, '<')) != NULL) {
    char *tptr = strchr(buff, '>');
    assert(tptr);
    memmove(buff, tptr + 1, strlen(tptr));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<remove_html_tags>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  jmp    L4
L6:
  mov    $0x3e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
L4:
  mov    $0x3c,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_html_tags(char *buff) {
  while ((buff = strchr(buff, '<')) != NULL) {
    char *tptr = strchr(buff, '>');
    assert(tptr);
    memmove(buff, tptr + 1, strlen(tptr));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<remove_html_tags>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L9
  nop
L10:
  mov    $0x3e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <memmove@plt>
L9:
  mov    %rbp,%rdi
  mov    $0x3c,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_html_tags(char *buff) {
  while ((buff = strchr(buff, '<')) != NULL) {
    char *tptr = strchr(buff, '>');
    assert(tptr);
    memmove(buff, tptr + 1, strlen(tptr));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<remove_html_tags>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L11
  nop
L19:
  mov    $0x3e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <memmove@plt>
L11:
  mov    %rbp,%rdi
  mov    $0x3c,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_html_tags(char *buff) {
  while ((buff = strchr(buff, '<')) != NULL) {
    char *tptr = strchr(buff, '>');
    assert(tptr);
    memmove(buff, tptr + 1, strlen(tptr));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parse_status>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  jmp    L59
L4:
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L59
L13:
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
  mov    -0x10(%rbp),%rax
  movl   $0x2,(%rax)
  mov    $0x1,%eax
  jmp    L59
L21:
  mov    $0x0,%eax
L59:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string

tool: D7: enable

tool: D9: disable

tool: D10: auto

assistant: ```c
bool parse_status(const char *param, int *status) {
  if (strcmp(param, "enable") == 0) {
    *status = 1;
    return true;
  } else if (strcmp(param, "disable") == 0) {
    *status = 0;
    return true;
  } else if (strcmp(param, "auto") == 0) {
    *status = 2;
    return true;
  }
  return false;
}
```