user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D44(%rip),%rcx
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  push   %r12
  lea    D38(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x58,%rsp
  movdqa D20(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rax
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r13
  movq   %rax,%xmm1
  movaps %xmm0,(%rsp)
  lea    D85(%rip),%rax
  movq   %r12,%xmm0
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  lea    D78(%rip),%rax
  movl   $0x2,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movq   %rcx,%xmm0
  mov    %rax,0x40(%rsp)
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x30(%rsp)
L45:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L45
  lea    D45(%rip),%r14
  xor    %ebx,%ebx
  lea    D51(%rip),%r15
  mov    %r14,%rdi
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L35:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  jne    L35
  mov    %r14,%rdi
  xor    %ebx,%ebx
  lea    D8(%rip),%r15
  call   <puts@plt>
  xchg   %ax,%ax
L42:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L42
  mov    %r14,%rdi
  mov    %rbp,%rbx
  lea    D92(%rip),%r13
  call   <puts@plt>
  nop
L23:
  mov    (%rbx),%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    %rbx,%rax
  sub    %rbp,%rax
  cmp    $0x10,%rax
  jle    L23
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D44
type_guessed: string
name: parse_data
arguments: tag: D21
type_guessed: string
name: parse_data
arguments: tag: D38
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: byte[16]
name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D85
type_guessed: string
name: parse_data
arguments: tag: D78
type_guessed: string
name: parse_data
arguments: tag: D45
type_guessed: string
name: parse_data
arguments: tag: D51
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D92
type_guessed: string

tool: D44: Mary

tool: D21: %s is %d years old


tool: D38: Alan

tool: {"D20": [0x16,0x00,0x00,0x00,0x24,0x00,0x00,0x00,0x1b,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

tool: D24: Frank

tool: D85: John

tool: D78: Lisa

tool: D45: ---

tool: D51: %s is %d years alive


tool: D8: %s has lived %d years


tool: D92: %s's age is %d


assistant: ```c
int main(int argc, char *argv[]) {
  int ages[] = {22, 36, 27, 23, 2};
  char *names[] = {"Alan", "Frank", "Mary", "John", "Lisa"};
  int count = sizeof(ages) / sizeof(int);
  int i = 0;
  for (; i < count; i++) {
    printf("%s is %d years old\n", names[i], ages[i]);
  }
  printf("---\n");
  int *cur_age = ages;
  char **cur_name = names;
  for (i = 0; i < count + 1; i++) {
    printf("%s is %d years alive\n", *(cur_name + i), *(cur_age + i));
  }
  printf("---\n");
  for (i = -1; i++, i < count;) {
    printf("%s has lived %d years\n", cur_name[i], cur_age[i]);
  }
  printf("---\n");
  for (cur_age = ages, cur_name = names; (cur_age - ages) < count; cur_age++) {
    printf("%s's age is %d\n", *cur_name, *cur_age);
  }
  return 0;
}
```