ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<iget_t4_scale>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x910,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x908(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,(%rsi)
  lea    D12(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L74
  mov    %rax,%rbp
  mov    %rbx,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%r14d
  lea    D3(%rip),%r12
L77:
  lea    0x800(%rsp),%rdi
  mov    %rbp,%rdx
  mov    $0x100,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L67
  mov    %rsp,%rsi
  lea    0x800(%rsp),%rdi
  mov    $0x100,%edx
  call   <split@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L77
  mov    %r12,%rsi
  mov    (%rsp),%rdi
  call   <strcmp@plt>
  cmp    $0x1,%ebx
  jle    L77
  test   %eax,%eax
  jne    L77
  mov    0x8(%rsp),%rdi
  call   <atof@plt>
  movss  %xmm0,0x0(%r13)
  mov    $0x0,%r14d
  jmp    L77
L67:
  mov    %rbp,%rdi
  call   <fclose@plt>
L75:
  mov    0x908(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    %r14d,%eax
  add    $0x910,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L74:
  mov    $0xffffffff,%r14d
  jmp    L75
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D24
data_type: string
name: disassemble_data
arguments: label: D3
data_type: string

tool: D12: r

tool: D24: Reading: %s


tool: D3: scale:

assistant: ```c
int iget_t4_scale(char *t4file, float *scale) {
  FILE *fp;
  char string[256], *srgv[256];
  int m, err;
  *scale = 1.;
  err = 1;
  if (!(fp = fopen(t4file, "r")))
    return -1;
  printf("Reading: %s\n", t4file);
  while (fgets(string, 256, fp)) {
    if (!(m = split(string, srgv, 256)))
      continue;
    if (!strcmp(srgv[0], "scale:") && m > 1) {
      *scale = atof(srgv[1]);
      err = 0;
    }
  }
  fclose(fp);
  return err;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<iget_t4_scale>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x918,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x908(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,(%rsi)
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L28
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  mov    %rax,%r12
  mov    $0x1,%r15d
  call   <printf@plt>
  lea    0x800(%rsp),%rbp
  lea    D7(%rip),%r13
L46:
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L16
  mov    %rsp,%rsi
  mov    $0x100,%edx
  mov    %rbp,%rdi
  call   <split@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L46
  mov    (%rsp),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  cmp    $0x1,%ebx
  jle    L46
  test   %eax,%eax
  jne    L46
  mov    0x8(%rsp),%rdi
  xor    %r15d,%r15d
  call   <atof@plt>
  movss  %xmm0,(%r14)
  jmp    L46
  nopl   0x0(%rax)
L16:
  mov    %r12,%rdi
  call   <fclose@plt>
L47:
  mov    0x908(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x918,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    $0xffffffff,%r15d
  jmp    L47
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D7
type_infered: string

tool: D0: r

tool: D1: Reading: %s


tool: D7: scale:

assistant: ```c
int iget_t4_scale(char *t4file, float *scale) {
  FILE *fp;
  char string[256], *srgv[256];
  int m, err;
  *scale = 1.;
  err = 1;
  if (!(fp = fopen(t4file, "r")))
    return -1;
  printf("Reading: %s\n", t4file);
  while (fgets(string, 256, fp)) {
    if (!(m = split(string, srgv, 256)))
      continue;
    if (!strcmp(srgv[0], "scale:") && m > 1) {
      *scale = atof(srgv[1]);
      err = 0;
    }
  }
  fclose(fp);
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iget_t4_scale>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x918,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x908(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,(%rsi)
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L56
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  mov    %rax,%r12
  mov    $0x1,%r15d
  call   <printf@plt>
  lea    0x800(%rsp),%rbp
  lea    D21(%rip),%r13
L26:
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L20
  mov    %rsp,%rsi
  mov    $0x100,%edx
  mov    %rbp,%rdi
  call   <split@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L26
  mov    (%rsp),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  cmp    $0x1,%ebx
  jle    L26
  test   %eax,%eax
  jne    L26
  mov    0x8(%rsp),%rdi
  xor    %r15d,%r15d
  call   <atof@plt>
  movss  %xmm0,(%r14)
  jmp    L26
  nopl   0x0(%rax)
L20:
  mov    %r12,%rdi
  call   <fclose@plt>
L8:
  mov    0x908(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x918,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  mov    $0xffffffff,%r15d
  jmp    L8
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D21
datatype: string

tool: D13: r

tool: D17: Reading: %s


tool: D21: scale:

assistant: ```c
int iget_t4_scale(char *t4file, float *scale) {
  FILE *fp;
  char string[256], *srgv[256];
  int m, err;
  *scale = 1.;
  err = 1;
  if (!(fp = fopen(t4file, "r")))
    return -1;
  printf("Reading: %s\n", t4file);
  while (fgets(string, 256, fp)) {
    if (!(m = split(string, srgv, 256)))
      continue;
    if (!strcmp(srgv[0], "scale:") && m > 1) {
      *scale = atof(srgv[1]);
      err = 0;
    }
  }
  fclose(fp);
  return err;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  and    $0xffffffb2,%eax
  xor    $0xffffffeb,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned char)1) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned char)4) & (unsigned char)7) | 1UL);
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 105482674UL) ^ (unsigned char)235;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movb   $0xeb,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned char)1) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned char)4) & (unsigned char)7) | 1UL);
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 105482674UL) ^ (unsigned char)235;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movb   $0xeb,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned char)1) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned char)4) & (unsigned char)7) | 1UL);
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 105482674UL) ^ (unsigned char)235;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movb   $0xeb,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned char)1) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned char)4) & (unsigned char)7) | 1UL);
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 105482674UL) ^ (unsigned char)235;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_u64_be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x38,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x30,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    $0x28,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    $0x20,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void write_u64_be(unsigned char *buf, uint64_t n) {
  buf[0] = n >> 56 & 0xff;
  buf[1] = n >> 48 & 0xff;
  buf[2] = n >> 40 & 0xff;
  buf[3] = n >> 32 & 0xff;
  buf[4] = n >> 24 & 0xff;
  buf[5] = n >> 16 & 0xff;
  buf[6] = n >> 8 & 0xff;
  buf[7] = n & 0xff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_u64_be>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  mov    $0x38,%ecx
  sar    %cl,%edx
  mov    %dl,(%rdi)
  mov    %esi,%edx
  mov    $0x30,%ecx
  sar    %cl,%edx
  mov    %dl,0x1(%rdi)
  mov    %esi,%edx
  mov    $0x28,%ecx
  sar    %cl,%edx
  mov    %dl,0x2(%rdi)
  mov    %esi,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  mov    %dl,0x3(%rdi)
  mov    %esi,%edx
  shr    $0x18,%edx
  mov    %dl,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %dl,0x5(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x6(%rdi)
  mov    %sil,0x7(%rdi)
  ret
```

assistant: ```c
void write_u64_be(unsigned char *buf, uint64_t n) {
  buf[0] = n >> 56 & 0xff;
  buf[1] = n >> 48 & 0xff;
  buf[2] = n >> 40 & 0xff;
  buf[3] = n >> 32 & 0xff;
  buf[4] = n >> 24 & 0xff;
  buf[5] = n >> 16 & 0xff;
  buf[6] = n >> 8 & 0xff;
  buf[7] = n & 0xff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_u64_be>:
  endbr64
  mov    %esi,%eax
  mov    $0x38,%ecx
  sar    %cl,%eax
  mov    $0x30,%ecx
  mov    %al,(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x28,%ecx
  mov    %al,0x1(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x20,%ecx
  mov    %al,0x2(%rdi)
  mov    %esi,%eax
  bswap  %esi
  sar    %cl,%eax
  mov    %esi,0x4(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void write_u64_be(unsigned char *buf, uint64_t n) {
  buf[0] = n >> 56 & 0xff;
  buf[1] = n >> 48 & 0xff;
  buf[2] = n >> 40 & 0xff;
  buf[3] = n >> 32 & 0xff;
  buf[4] = n >> 24 & 0xff;
  buf[5] = n >> 16 & 0xff;
  buf[6] = n >> 8 & 0xff;
  buf[7] = n & 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<write_u64_be>:
  endbr64
  mov    %esi,%edx
  mov    $0x38,%ecx
  mov    %esi,%eax
  push   %r14
  sar    %cl,%edx
  mov    $0x30,%ecx
  push   %rbx
  mov    %esi,%ebx
  sar    %cl,%eax
  sar    $0x8,%ebx
  mov    %esi,%r8d
  mov    %esi,%r9d
  mov    %eax,%r14d
  movzbl %sil,%eax
  mov    %esi,%r10d
  mov    %esi,%r11d
  shl    $0x8,%rax
  movzbl %bl,%esi
  sar    $0x10,%r11d
  mov    $0x28,%ecx
  or     %rsi,%rax
  movzbl %r11b,%esi
  shr    $0x18,%r10d
  movzbl %dl,%edx
  shl    $0x8,%rax
  sar    %cl,%r8d
  mov    $0x20,%ecx
  pop    %rbx
  or     %rsi,%rax
  movzbl %r10b,%esi
  sar    %cl,%r9d
  movzbl %r14b,%ecx
  shl    $0x8,%rax
  pop    %r14
  or     %rsi,%rax
  movzbl %r9b,%esi
  shl    $0x8,%rax
  or     %rsi,%rax
  movzbl %r8b,%esi
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void write_u64_be(unsigned char *buf, uint64_t n) {
  buf[0] = n >> 56 & 0xff;
  buf[1] = n >> 48 & 0xff;
  buf[2] = n >> 40 & 0xff;
  buf[3] = n >> 32 & 0xff;
  buf[4] = n >> 24 & 0xff;
  buf[5] = n >> 16 & 0xff;
  buf[6] = n >> 8 & 0xff;
  buf[7] = n & 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L30
L43:
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L0
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <nonblocking_cat@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  jmp    L35
L0:
  nop
L35:
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L43
  cmpl   $0x1,-0x14(%rbp)
  jne    L37
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <nonblocking_cat@plt>
L37:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int fd;
  for (i = 1; i < argc; i++) {
    fd = open(argv[i], O_RDONLY, 0);
    if (fd < 0)
      continue;
    nonblocking_cat(fd);
    close(fd);
  }
  if (argc == 1)
    nonblocking_cat(STDIN_FILENO);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L44
  lea    0x8(%rsi),%rbp
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r13
  mov    D16(%rip),%r12
  jmp    L48
L30:
  mov    %eax,%edi
  call   <nonblocking_cat@plt>
  mov    %ebx,%edi
  call   <close@plt>
L42:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L39
L48:
  mov    $0x0,%edx
  mov    (%r12),%esi
  mov    0x0(%rbp),%rdi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L30
  jmp    L42
L44:
  jne    L39
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <nonblocking_cat@plt>
L39:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int fd;
  for (i = 1; i < argc; i++) {
    fd = open(argv[i], O_RDONLY, 0);
    if (fd < 0)
      continue;
    nonblocking_cat(fd);
    close(fd);
  }
  if (argc == 1)
    nonblocking_cat(STDIN_FILENO);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L3
  lea    -0x2(%rdi),%eax
  mov    D14(%rip),%r12
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r13
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    (%r12),%esi
  mov    (%rbx),%rdi
  xor    %edx,%edx
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L0
  mov    %eax,%edi
  call   <nonblocking_cat@plt>
  mov    %ebp,%edi
  call   <close@plt>
L0:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L39
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  jne    L18
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <nonblocking_cat@plt>
  jmp    L18
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int fd;
  for (i = 1; i < argc; i++) {
    fd = open(argv[i], O_RDONLY, 0);
    if (fd < 0)
      continue;
    nonblocking_cat(fd);
    close(fd);
  }
  if (argc == 1)
    nonblocking_cat(STDIN_FILENO);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L36
  lea    -0x2(%rdi),%eax
  mov    D11(%rip),%r12
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r13
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    (%r12),%esi
  mov    (%rbx),%rdi
  xor    %edx,%edx
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L31
  mov    %eax,%edi
  call   <nonblocking_cat@plt>
  mov    %ebp,%edi
  call   <close@plt>
L31:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L29
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  jne    L2
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <nonblocking_cat@plt>
  jmp    L2
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int fd;
  for (i = 1; i < argc; i++) {
    fd = open(argv[i], O_RDONLY, 0);
    if (fd < 0)
      continue;
    nonblocking_cat(fd);
    close(fd);
  }
  if (argc == 1)
    nonblocking_cat(STDIN_FILENO);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2a,-0xc(%rbp)
  movl   $0x8,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 42;
  int b = 8;
  int c = a - -b;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x32,%eax
  ret
```

assistant: ```c
int main() {
  int a = 42;
  int b = 8;
  int c = a - -b;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x32,%eax
  ret
```

assistant: ```c
int main() {
  int a = 42;
  int b = 8;
  int c = a - -b;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x32,%eax
  ret
```

assistant: ```c
int main() {
  int a = 42;
  int b = 8;
  int c = a - -b;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mutilsStrLower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L25
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L25:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mutilsStrLower(char *str) {
  char *s;
  if (str) {
    for (s = str; *s; ++s)
      *s = tolower(*s);
  }
  return (str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mutilsStrLower>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L12
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L12
  mov    %rbp,%rbx
L22:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L22
L12:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mutilsStrLower(char *str) {
  char *s;
  if (str) {
    for (s = str; *s; ++s)
      *s = tolower(*s);
  }
  return (str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mutilsStrLower>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L4
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  mov    %r12,%rbx
  xchg   %ax,%ax
L19:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *mutilsStrLower(char *str) {
  char *s;
  if (str) {
    for (s = str; *s; ++s)
      *s = tolower(*s);
  }
  return (str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mutilsStrLower>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L19
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L19
  mov    %r12,%rbx
  xchg   %ax,%ax
L17:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L17
L19:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *mutilsStrLower(char *str) {
  char *s;
  if (str) {
    for (s = str; *s; ++s)
      *s = tolower(*s);
  }
  return (str);
}
```