user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  xor    %esi,%esi
  lea    D83(%rip),%rdi
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <printf@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L63
L64:
  mov    %r12,%rsi
  lea    D76(%rip),%rdi
  xor    %eax,%eax
  mov    %r12,%rbp
  call   <printf@plt>
  xor    %ebx,%ebx
  lea    D67(%rip),%r13
  nop
L24:
  mov    0x0(%rbp),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L24
  xor    %esi,%esi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L31
L29:
  mov    %r14,%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  mov    %r14,%rbp
  call   <printf@plt>
  xor    %ebx,%ebx
  lea    D50(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %rbp,%rax
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  mov    (%rax),%edx
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L59
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  mov    $0x50,%esi
  call   <realloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L5
L37:
  mov    %r14,%rsi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  mov    %r14,%rbp
  call   <printf@plt>
  xor    %ebx,%ebx
  lea    D19(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L70:
  mov    %rbp,%rax
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  mov    (%rax),%edx
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0x14,%ebx
  jne    L70
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L64
L5:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L37
L31:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L29
```

tool_calls: name: retrieve_data
arguments: tag: D83
type: string
name: retrieve_data
arguments: tag: D76
type: string
name: retrieve_data
arguments: tag: D67
type: string
name: retrieve_data
arguments: tag: D61
type: string
name: retrieve_data
arguments: tag: D30
type: string
name: retrieve_data
arguments: tag: D50
type: string
name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D52
type: string
name: retrieve_data
arguments: tag: D19
type: string

tool: D83: [ANTES] endereco de buffer1 = %p


tool: D76: [DEPOIS] endereco de buffer1 = %p


tool: D67: buffer1[%d] = %d


tool: D61: [ANTES] endereco de buffer2 = %p


tool: D30: [DEPOIS] endereco de buffer2 = %p


tool: D50: buffer2[%d] = %d


tool: D11: [ANTES] endereco de buffer3 = %p


tool: D52: [DEPOIS] endereco de buffer3 = %p


tool: D19: buffer3[%d] = %d


assistant: ```c
int main() {
  int *buffer1 = NULL, *buffer2 = NULL, *buffer3 = NULL;
  int i;
  printf("[ANTES] endereco de buffer1 = %p\n", buffer1);
  buffer1 = (int *)malloc(10 * sizeof(int));
  if (buffer1 == NULL)
    exit(-1);
  printf("[DEPOIS] endereco de buffer1 = %p\n", buffer1);
  for (i = 0; i < 10; i++)
    printf("buffer1[%d] = %d\n", i, buffer1[i]);
  printf("[ANTES] endereco de buffer2 = %p\n", buffer2);
  buffer2 = (int *)calloc(10, sizeof(int));
  if (!buffer2)
    exit(-1);
  int *temp = buffer2;
  printf("[DEPOIS] endereco de buffer2 = %p\n", buffer2);
  for (i = 0; i < 10; i++)
    printf("buffer2[%d] = %d\n", i, *(temp++));
  printf("[ANTES] endereco de buffer3 = %p\n", buffer3);
  buffer3 = (int *)realloc(buffer2, 2 * 10 * sizeof(int));
  if (!buffer3)
    exit(-1);
  temp = buffer3;
  printf("[DEPOIS] endereco de buffer3 = %p\n", buffer3);
  for (i = 0; i < 2 * 10; i++)
    printf("buffer3[%d] = %d\n", i, *(temp++));
  free(buffer1);
  free(buffer3);
  return 0;
}
```