ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<binary>:
  endbr64
  mov    %edi,%ecx
  mov    %rsi,%rdx
  mov    (%rsi),%rsi
  mov    %edi,%eax
  sar    $0x7,%ecx
  and    $0x1,%eax
  and    $0x1,%ecx
  add    $0x30,%eax
  add    $0x30,%ecx
  mov    %cl,(%rsi)
  mov    %edi,%ecx
  mov    (%rdx),%rsi
  sar    $0x6,%ecx
  and    $0x1,%ecx
  add    $0x30,%ecx
  mov    %cl,0x1(%rsi)
  mov    %edi,%ecx
  mov    (%rdx),%rsi
  sar    $0x5,%ecx
  and    $0x1,%ecx
  add    $0x30,%ecx
  mov    %cl,0x2(%rsi)
  mov    %edi,%ecx
  mov    (%rdx),%rsi
  sar    $0x4,%ecx
  and    $0x1,%ecx
  add    $0x30,%ecx
  mov    %cl,0x3(%rsi)
  mov    %edi,%ecx
  mov    (%rdx),%rsi
  sar    $0x3,%ecx
  and    $0x1,%ecx
  add    $0x30,%ecx
  mov    %cl,0x4(%rsi)
  mov    %edi,%ecx
  mov    (%rdx),%rsi
  sar    $0x2,%ecx
  and    $0x1,%ecx
  add    $0x30,%ecx
  mov    %cl,0x5(%rsi)
  mov    %edi,%ecx
  mov    (%rdx),%rsi
  sar    %ecx
  and    $0x1,%ecx
  add    $0x30,%ecx
  mov    %cl,0x6(%rsi)
  mov    (%rdx),%rdx
  mov    %al,0x7(%rdx)
  ret
```

assistant: ```c
void binary(uint8_t value, char **result) {
  uint8_t pos = 0;
  for (int i = 7; i >= 0; i--) {
    (*result)[pos++] = (value & (1 << i)) ? '1' : '0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sigma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  movsd  %xmm0,-0x60(%rbp)
  movsd  %xmm1,-0x68(%rbp)
  mov    %r9,-0x70(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x48(%rbp),%rdx
  mov    %rdx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x18(%rbp)
  mov    %rdx,%r10
  mov    $0x0,%r11d
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movq   $0x0,-0x30(%rbp)
  jmp    L37
L17:
  mov    %rax,%rcx
  imul   -0x30(%rbp),%rcx
  lea    0x0(,%rcx,8),%rsi
  mov    -0x50(%rbp),%rcx
  add    %rcx,%rsi
  mov    -0x70(%rbp),%rcx
  movsd  (%rsi,%rcx,8),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x60(%rbp),%xmm1
  mov    %rdx,%rcx
  imul   -0x30(%rbp),%rcx
  lea    0x0(,%rcx,8),%rsi
  mov    -0x58(%rbp),%rcx
  add    %rcx,%rsi
  mov    0x10(%rbp),%rcx
  movsd  (%rsi,%rcx,8),%xmm0
  subsd  -0x68(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
L37:
  mov    -0x30(%rbp),%rcx
  cmp    -0x38(%rbp),%rcx
  jb     L17
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  test   %rax,%rax
  js     L5
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L16
L5:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L16:
  movsd  -0x28(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
double sigma(size_t r, size_t xc, size_t yc, double X[r][xc], double Y[r][yc], double xm, double ym, size_t xi, size_t yi) {
  size_t i;
  double s;
  s = 0.0;
  for (i = 0; i < r; i++)
    s += (X[i][xi] - xm) * (Y[i][yi] - ym);
  return s / (r - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sigma>:
  endbr64
  mov    %rsi,%r10
  mov    %rdx,%rsi
  movapd %xmm0,%xmm4
  test   %rdi,%rdi
  je     L43
  shl    $0x3,%r10
  lea    (%rcx,%r9,8),%rcx
  shl    $0x3,%rsi
  mov    0x8(%rsp),%rax
  lea    (%r8,%rax,8),%rdx
  pxor   %xmm0,%xmm0
  mov    $0x0,%eax
L11:
  movsd  (%rcx),%xmm2
  subsd  %xmm4,%xmm2
  movsd  (%rdx),%xmm3
  subsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  add    $0x1,%rax
  add    %r10,%rcx
  add    %rsi,%rdx
  cmp    %rax,%rdi
  jne    L11
L24:
  sub    $0x1,%rdi
  js     L45
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdi,%xmm1
L38:
  divsd  %xmm1,%xmm0
  ret
L43:
  pxor   %xmm0,%xmm0
  jmp    L24
L45:
  mov    %rdi,%rax
  shr    %rax
  and    $0x1,%edi
  or     %rdi,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L38
```

assistant: ```c
double sigma(size_t r, size_t xc, size_t yc, double X[r][xc], double Y[r][yc], double xm, double ym, size_t xi, size_t yi) {
  size_t i;
  double s;
  s = 0.0;
  for (i = 0; i < r; i++)
    s += (X[i][xi] - xm) * (Y[i][yi] - ym);
  return s / (r - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sigma>:
  endbr64
  mov    %rsi,%r10
  movapd %xmm0,%xmm4
  mov    %rdx,%rsi
  test   %rdi,%rdi
  je     L35
  shl    $0x3,%r10
  lea    (%rcx,%r9,8),%rcx
  shl    $0x3,%rsi
  pxor   %xmm0,%xmm0
  mov    0x8(%rsp),%rax
  lea    (%r8,%rax,8),%rdx
  xor    %eax,%eax
  xchg   %ax,%ax
L11:
  movsd  (%rcx),%xmm2
  movsd  (%rdx),%xmm3
  add    $0x1,%rax
  add    %r10,%rcx
  add    %rsi,%rdx
  subsd  %xmm4,%xmm2
  subsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %rax,%rdi
  jne    L11
L22:
  sub    $0x1,%rdi
  js     L13
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm1,%xmm1
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  divsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L35:
  pxor   %xmm0,%xmm0
  jmp    L22
```

assistant: ```c
double sigma(size_t r, size_t xc, size_t yc, double X[r][xc], double Y[r][yc], double xm, double ym, size_t xi, size_t yi) {
  size_t i;
  double s;
  s = 0.0;
  for (i = 0; i < r; i++)
    s += (X[i][xi] - xm) * (Y[i][yi] - ym);
  return s / (r - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sigma>:
  endbr64
  mov    %rsi,%r10
  movapd %xmm0,%xmm4
  mov    %rdx,%rsi
  test   %rdi,%rdi
  je     L3
  shl    $0x3,%r10
  lea    (%rcx,%r9,8),%rcx
  shl    $0x3,%rsi
  pxor   %xmm0,%xmm0
  mov    0x8(%rsp),%rax
  lea    (%r8,%rax,8),%rdx
  xor    %eax,%eax
  xchg   %ax,%ax
L22:
  movsd  (%rcx),%xmm2
  movsd  (%rdx),%xmm3
  add    $0x1,%rax
  add    %r10,%rcx
  add    %rsi,%rdx
  subsd  %xmm4,%xmm2
  subsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %rax,%rdi
  jne    L22
L28:
  sub    $0x1,%rdi
  js     L19
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm1,%xmm1
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  divsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L3:
  pxor   %xmm0,%xmm0
  jmp    L28
```

assistant: ```c
double sigma(size_t r, size_t xc, size_t yc, double X[r][xc], double Y[r][yc], double xm, double ym, size_t xi, size_t yi) {
  size_t i;
  double s;
  s = 0.0;
  for (i = 0; i < r; i++)
    s += (X[i][xi] - xm) * (Y[i][yi] - ym);
  return s / (r - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<beta_rndc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <genbet@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L6
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void beta_rndc(int n, double a, double b, double *array) {
  int i;
  for (i = 0; i < n; i++)
    *(array + i) = genbet(a, b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<beta_rndc>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  movq   %xmm1,%r12
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r13
L18:
  movq   %r12,%xmm1
  movq   %rbp,%xmm0
  call   <genbet@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  ret
```

assistant: ```c
void beta_rndc(int n, double a, double b, double *array) {
  int i;
  for (i = 0; i < n; i++)
    *(array + i) = genbet(a, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<beta_rndc>:
  endbr64
  test   %edi,%edi
  jle    L15
  push   %r14
  lea    -0x1(%rdi),%eax
  movq   %xmm0,%r14
  push   %rbp
  lea    0x8(%rsi,%rax,8),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
L5:
  movq   %r14,%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <genbet@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  nopl   (%rax)
L15:
  ret
```

assistant: ```c
void beta_rndc(int n, double a, double b, double *array) {
  int i;
  for (i = 0; i < n; i++)
    *(array + i) = genbet(a, b);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<beta_rndc>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r14
  lea    -0x1(%rdi),%eax
  movq   %xmm0,%r14
  push   %rbp
  lea    0x8(%rsi,%rax,8),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
L0:
  movq   %r14,%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <genbet@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  nopl   (%rax)
L5:
  ret
```

assistant: ```c
void beta_rndc(int n, double a, double b, double *array) {
  int i;
  for (i = 0; i < n; i++)
    *(array + i) = genbet(a, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <rindex@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L2
L4:
  mov    -0x18(%rbp),%rax
L2:
  leave
  ret
```

assistant: ```c
char *basename(char *name) {
  char *base;
  base = rindex(name, '/');
  return base ? base + 1 : name;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <rindex@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *basename(char *name) {
  char *base;
  base = rindex(name, '/');
  return base ? base + 1 : name;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <rindex@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *basename(char *name) {
  char *base;
  base = rindex(name, '/');
  return base ? base + 1 : name;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <rindex@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *basename(char *name) {
  char *base;
  base = rindex(name, '/');
  return base ? base + 1 : name;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
L9:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L24
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L24:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L9
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string
name: retrieve_data
arguments: tag: D22
type: string
name: retrieve_data
arguments: tag: D2
type: string

tool: D5: Enter a number: 

tool: D22: %d

tool: D2: 
The largest number entered was %d


assistant: ```c
int main(void) {
  int n, largest = 0;
  do {
    printf("Enter a number: ");
    scanf("%d", &n);
    if (n > largest)
      largest = n;
  } while (n != 0);
  printf("\nThe largest number entered was %d\n", largest);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D4(%rip),%r13
  lea    0x4(%rsp),%r12
  lea    D0(%rip),%rbp
L9:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  test   %eax,%eax
  jne    L9
  mov    %ebx,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D10
type: string

tool: D4: Enter a number: 

tool: D0: %d

tool: D10: 
The largest number entered was %d


assistant: ```c
int main(void) {
  int n, largest = 0;
  do {
    printf("Enter a number: ");
    scanf("%d", &n);
    if (n > largest)
      largest = n;
  } while (n != 0);
  printf("\nThe largest number entered was %d\n", largest);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  test   %eax,%eax
  jne    L3
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
data_type: string
name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D18
data_type: string

tool: D10: Enter a number: 

tool: D14: %d

tool: D18: 
The largest number entered was %d


assistant: ```c
int main(void) {
  int n, largest = 0;
  do {
    printf("Enter a number: ");
    scanf("%d", &n);
    if (n > largest)
      largest = n;
  } while (n != 0);
  printf("\nThe largest number entered was %d\n", largest);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D25(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  test   %eax,%eax
  jne    L5
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string
name: disassemble_data
arguments: data_label: D25
data_type: string
name: disassemble_data
arguments: data_label: D14
data_type: string

tool: D9: Enter a number: 

tool: D25: %d

tool: D14: 
The largest number entered was %d


assistant: ```c
int main(void) {
  int n, largest = 0;
  do {
    printf("Enter a number: ");
    scanf("%d", &n);
    if (n > largest)
      largest = n;
  } while (n != 0);
  printf("\nThe largest number entered was %d\n", largest);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L1:
  movl   $0x0,-0x8(%rbp)
  jmp    L44
L25:
  movl   $0x0,-0x4(%rbp)
  jmp    L54
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L54:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L23
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L25
  addl   $0x1,-0xc(%rbp)
L36:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(float **a, float **b, float *c, int n, int m, int l) {
  int i, j, k;
  float s;
  for (i = 0; i < l; i++)
    for (j = 0; j < n; j++)
      for (k = 0; k < m; k++)
        c[i] += a[i][k] * b[k][j];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  test   %r9d,%r9d
  jle    L54
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    %ecx,%ebx
  mov    %r8d,%r11d
  mov    %rdi,%r8
  lea    -0x1(%r9),%ecx
  lea    0x4(%rdx,%rcx,4),%r12
  lea    -0x1(%rbx),%eax
  lea    0x4(,%rax,4),%rbp
  lea    -0x1(%r11),%eax
  lea    0x4(,%rax,4),%r9
  jmp    L21
L26:
  mov    (%r8),%rsi
  mov    (%r10,%rax,2),%rcx
  movss  (%rsi,%rax,1),%xmm0
  mulss  (%rcx,%rdi,1),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  add    $0x4,%rax
  cmp    %rax,%r9
  jne    L26
L33:
  add    $0x4,%rdi
  cmp    %rbp,%rdi
  je     L45
L18:
  mov    $0x0,%eax
  test   %r11d,%r11d
  jg     L26
  jmp    L33
L45:
  add    $0x4,%rdx
  add    $0x8,%r8
  cmp    %r12,%rdx
  je     L89
L21:
  mov    $0x0,%edi
  test   %ebx,%ebx
  jg     L18
  jmp    L45
L89:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  ret
```

assistant: ```c
void foo(float **a, float **b, float *c, int n, int m, int l) {
  int i, j, k;
  float s;
  for (i = 0; i < l; i++)
    for (j = 0; j < n; j++)
      for (k = 0; k < m; k++)
        c[i] += a[i][k] * b[k][j];
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  test   %r9d,%r9d
  jle    L34
  mov    %r9d,%eax
  push   %r12
  mov    %rsi,%r10
  mov    %r8d,%r11d
  sub    $0x1,%eax
  push   %rbp
  mov    %rdx,%rsi
  mov    %ecx,%ebp
  lea    0x4(%rdx,%rax,4),%r12
  lea    -0x1(%rcx),%eax
  push   %rbx
  mov    %rdi,%r9
  lea    0x4(,%rax,4),%rbx
  movslq %r8d,%r8
  nopl   0x0(%rax,%rax,1)
L47:
  xor    %ecx,%ecx
  test   %ebp,%ebp
  jle    L28
  cs nopw 0x0(%rax,%rax,1)
L4:
  test   %r11d,%r11d
  jle    L37
  mov    (%r9),%rdi
  movss  (%rsi),%xmm1
  xor    %eax,%eax
  xchg   %ax,%ax
L41:
  mov    (%r10,%rax,8),%rdx
  movss  (%rdx,%rcx,1),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rsi)
  cmp    %r8,%rax
  jne    L41
L37:
  add    $0x4,%rcx
  cmp    %rcx,%rbx
  jne    L4
L28:
  add    $0x4,%rsi
  add    $0x8,%r9
  cmp    %r12,%rsi
  jne    L47
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  ret
```

assistant: ```c
void foo(float **a, float **b, float *c, int n, int m, int l) {
  int i, j, k;
  float s;
  for (i = 0; i < l; i++)
    for (j = 0; j < n; j++)
      for (k = 0; k < m; k++)
        c[i] += a[i][k] * b[k][j];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  test   %r9d,%r9d
  jle    L3
  movslq %ecx,%rax
  test   %eax,%eax
  jle    L3
  test   %r8d,%r8d
  jle    L3
  mov    %rsi,%r10
  mov    %rdx,%rsi
  mov    %r9d,%edx
  push   %rbx
  sub    $0x1,%edx
  mov    %rdi,%r11
  lea    0x0(,%rax,4),%r9
  movslq %r8d,%r8
  lea    0x4(%rsi,%rdx,4),%rbx
  nopl   (%rax)
L33:
  mov    (%r11),%rdi
  xor    %ecx,%ecx
  nopl   (%rax)
L35:
  movss  (%rsi),%xmm1
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    (%r10,%rax,8),%rdx
  movss  (%rdx,%rcx,1),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rsi)
  cmp    %rax,%r8
  jne    L27
  add    $0x4,%rcx
  cmp    %rcx,%r9
  jne    L35
  add    $0x4,%rsi
  add    $0x8,%r11
  cmp    %rsi,%rbx
  jne    L33
  pop    %rbx
  ret
L3:
  ret
```

assistant: ```c
void foo(float **a, float **b, float *c, int n, int m, int l) {
  int i, j, k;
  float s;
  for (i = 0; i < l; i++)
    for (j = 0; j < n; j++)
      for (k = 0; k < m; k++)
        c[i] += a[i][k] * b[k][j];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<irc_kick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L5
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rsi,%r8
  lea    D14(%rip),%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <do_send@plt>
  jmp    L19
L5:
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  lea    D7(%rip),%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <do_send@plt>
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type: string
name: retrieve_data
arguments: data_tag: D7
type: string

tool: D14: KICK %s %s :%s

tool: D7: KICK %s %s

assistant: ```c
int irc_kick(int fd, const char *channel, const char *nick, const char *comment) {
  if (comment)
    return do_send(fd, "KICK %s %s :%s", channel, nick, comment);
  else
    return do_send(fd, "KICK %s %s", channel, nick);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<irc_kick>:
  endbr64
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L13
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D13(%rip),%rsi
  mov    $0x0,%eax
  call   <do_send@plt>
L8:
  add    $0x8,%rsp
  ret
L13:
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D2(%rip),%rsi
  mov    $0x0,%eax
  call   <do_send@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D2
type: string

tool: D13: KICK %s %s :%s

tool: D2: KICK %s %s

assistant: ```c
int irc_kick(int fd, const char *channel, const char *nick, const char *comment) {
  if (comment)
    return do_send(fd, "KICK %s %s :%s", channel, nick, comment);
  else
    return do_send(fd, "KICK %s %s", channel, nick);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<irc_kick>:
  endbr64
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  test   %r8,%r8
  je     L0
  lea    D12(%rip),%rsi
  xor    %eax,%eax
  jmp    1050 <do_send@plt>
L0:
  lea    D17(%rip),%rsi
  xor    %eax,%eax
  jmp    1050 <do_send@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
datatype: string
name: extract_symbolic_data
arguments: data_tag: D17
datatype: string

tool: D12: KICK %s %s :%s

tool: D17: KICK %s %s

assistant: ```c
int irc_kick(int fd, const char *channel, const char *nick, const char *comment) {
  if (comment)
    return do_send(fd, "KICK %s %s :%s", channel, nick, comment);
  else
    return do_send(fd, "KICK %s %s", channel, nick);
}
```