ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<gib_durchschnittsverbrauch_l_pro_100km>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0xf4240,%esi
  mov    $0x0,%edi
  call   <erfasse_gleitkomma_zahl@plt>
  movss  %xmm0,0xc(%rsp)
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x186a0,%esi
  mov    $0x0,%edi
  call   <erfasse_gleitkomma_zahl@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  call   <berechne_durchschnittsverbrauch_l_pro_100km@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string

tool: D15: 
Wie viel Kilometer sind Sie mit Ihrem PKW gefahren?	

tool: D10: Wie viel Liter Benzin haben Sie dabei verbraucht?	

assistant: ```c
float gib_durchschnittsverbrauch_l_pro_100km(void) {
  float strecke = 0.0;
  float verbrauch = 0.0;
  float durchschnittsverbrauch = 0.0;
  printf("\nWie viel Kilometer sind Sie mit Ihrem PKW gefahren?\t");
  strecke = erfasse_gleitkomma_zahl(0, 1000000);
  printf("Wie viel Liter Benzin haben Sie dabei verbraucht?\t");
  verbrauch = erfasse_gleitkomma_zahl(0, 100000);
  durchschnittsverbrauch = berechne_durchschnittsverbrauch_l_pro_100km(strecke, verbrauch);
  return durchschnittsverbrauch;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gib_durchschnittsverbrauch_l_pro_100km>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0xf4240,%esi
  xor    %edi,%edi
  call   <erfasse_gleitkomma_zahl@plt>
  lea    D2(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  mov    $0x186a0,%esi
  xor    %edi,%edi
  call   <erfasse_gleitkomma_zahl@plt>
  movss  0xc(%rsp),%xmm2
  add    $0x18,%rsp
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm0
  jmp    1090 <berechne_durchschnittsverbrauch_l_pro_100km@plt>
```

tool_calls: name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D14: 
Wie viel Kilometer sind Sie mit Ihrem PKW gefahren?	

tool: D2: Wie viel Liter Benzin haben Sie dabei verbraucht?	

assistant: ```c
float gib_durchschnittsverbrauch_l_pro_100km(void) {
  float strecke = 0.0;
  float verbrauch = 0.0;
  float durchschnittsverbrauch = 0.0;
  printf("\nWie viel Kilometer sind Sie mit Ihrem PKW gefahren?\t");
  strecke = erfasse_gleitkomma_zahl(0, 1000000);
  printf("Wie viel Liter Benzin haben Sie dabei verbraucht?\t");
  verbrauch = erfasse_gleitkomma_zahl(0, 100000);
  durchschnittsverbrauch = berechne_durchschnittsverbrauch_l_pro_100km(strecke, verbrauch);
  return durchschnittsverbrauch;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gib_durchschnittsverbrauch_l_pro_100km>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0xf4240,%esi
  xor    %edi,%edi
  call   <erfasse_gleitkomma_zahl@plt>
  lea    D9(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  mov    $0x186a0,%esi
  xor    %edi,%edi
  call   <erfasse_gleitkomma_zahl@plt>
  movss  0xc(%rsp),%xmm2
  add    $0x18,%rsp
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm0
  jmp    1090 <berechne_durchschnittsverbrauch_l_pro_100km@plt>
```

tool_calls: name: parse_data
arguments: label: D12
type_guessed: string
name: parse_data
arguments: label: D9
type_guessed: string

tool: D12: 
Wie viel Kilometer sind Sie mit Ihrem PKW gefahren?	

tool: D9: Wie viel Liter Benzin haben Sie dabei verbraucht?	

assistant: ```c
float gib_durchschnittsverbrauch_l_pro_100km(void) {
  float strecke = 0.0;
  float verbrauch = 0.0;
  float durchschnittsverbrauch = 0.0;
  printf("\nWie viel Kilometer sind Sie mit Ihrem PKW gefahren?\t");
  strecke = erfasse_gleitkomma_zahl(0, 1000000);
  printf("Wie viel Liter Benzin haben Sie dabei verbraucht?\t");
  verbrauch = erfasse_gleitkomma_zahl(0, 100000);
  durchschnittsverbrauch = berechne_durchschnittsverbrauch_l_pro_100km(strecke, verbrauch);
  return durchschnittsverbrauch;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  cmp    $0x3,%edi
  jne    L4
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rsi
  lea    0x10(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x10(%rbx),%rsi
  lea    0x80(%rsp),%rdi
  call   <strcpy@plt>
  jmp    L24
L4:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rsi
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L24:
  lea    0x10(%rsp),%rdi
  lea    D32(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L63
L82:
  lea    0x80(%rsp),%rdi
  lea    D20(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L88
L78:
  cmpl   $0x0,0xc(%rsp)
  jne    L83
  lea    0xc(%rsp),%rbp
L18:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <read_a_paragraph@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <write_a_paragraph@plt>
  cmpl   $0x0,0xc(%rsp)
  je     L18
L83:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0xf0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L63:
  lea    0x10(%rsp),%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L82
L88:
  lea    0x80(%rsp),%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L78
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
type_guessed: string
name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D56
type_guessed: string
name: unpack_data
arguments: tag: D32
type_guessed: string
name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D38
type_guessed: string

tool: D24: 

usage: para in-file out-file 

tool: D30: Para Version 1 - January 1999

tool: D56: 
%s


tool: D32: rt

tool: D20: wt

tool: D38: 
ERROR Could not open file %s

assistant: ```c
int main(int argc, char *argv[]) {
  char in_file_name[100], out_file_name[100], title[100];
  FILE *in_file, *out_file;
  int double_space = 0, file_done = 0, i, line_counter = 0, lines = 66, page_counter = 1, print_date = 0, print_page = 0, print_title = 0;
  struct word_list_struct *word_list, *temp;
  if (argc != 3) {
    printf("\n\nusage: para in-file out-file ");
    printf("\n%s\n", "Para Version 1 - January 1999");
    exit(1);
  }
  if (argc == 3) {
    strcpy(in_file_name, argv[1]);
    strcpy(out_file_name, argv[2]);
  }
  if ((in_file = fopen(in_file_name, "rt")) == NULL) {
    printf("\nERROR Could not open file %s", in_file_name);
    exit(2);
  }
  if ((out_file = fopen(out_file_name, "wt")) == NULL) {
    printf("\nERROR Could not open file %s", out_file_name);
    exit(2);
  }
  while (file_done == 0) {
    word_list = read_a_paragraph(in_file, &file_done);
    write_a_paragraph(word_list, out_file);
  }
  fclose(in_file);
  fclose(out_file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xff00,-0x8(%rbp)
  movl   $0x8000,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <leftmost_one@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L11
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  test   %rax,%rax
L11:
  movl   $0x6600,-0x8(%rbp)
  movl   $0x4000,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <leftmost_one@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L9
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  test   %rax,%rax
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D6: First example test pass!


tool: D3: Second example test pass!


assistant: ```c
int main(void) {
  int test_hex_0;
  int assert_ret;
  test_hex_0 = 0XFF00;
  assert_ret = 0x8000;
  !(assert_ret ^ leftmost_one(test_hex_0)) && printf("First example test pass!\n");
  test_hex_0 = 0x6600;
  assert_ret = 0x4000;
  !(assert_ret ^ leftmost_one(test_hex_0)) && printf("Second example test pass!\n");
  getchar();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff00,%edi
  call   <leftmost_one@plt>
  cmp    $0x8000,%eax
  je     L35
L27:
  mov    $0x6600,%edi
  call   <leftmost_one@plt>
  cmp    $0x4000,%eax
  je     L14
L20:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L35:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L14:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L20
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D17: First example test pass!


tool: D4: Second example test pass!


assistant: ```c
int main(void) {
  int test_hex_0;
  int assert_ret;
  test_hex_0 = 0XFF00;
  assert_ret = 0x8000;
  !(assert_ret ^ leftmost_one(test_hex_0)) && printf("First example test pass!\n");
  test_hex_0 = 0x6600;
  assert_ret = 0x4000;
  !(assert_ret ^ leftmost_one(test_hex_0)) && printf("Second example test pass!\n");
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff00,%edi
  call   <leftmost_one@plt>
  cmp    $0x8000,%eax
  je     L28
L32:
  mov    $0x6600,%edi
  call   <leftmost_one@plt>
  cmp    $0x4000,%eax
  je     L34
L39:
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L28:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L34:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L39
```

tool_calls: name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D0
datatype: string

tool: D16: First example test pass!


tool: D0: Second example test pass!


assistant: ```c
int main(void) {
  int test_hex_0;
  int assert_ret;
  test_hex_0 = 0XFF00;
  assert_ret = 0x8000;
  !(assert_ret ^ leftmost_one(test_hex_0)) && printf("First example test pass!\n");
  test_hex_0 = 0x6600;
  assert_ret = 0x4000;
  !(assert_ret ^ leftmost_one(test_hex_0)) && printf("Second example test pass!\n");
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff00,%edi
  call   <leftmost_one@plt>
  cmp    $0x8000,%eax
  je     L16
L15:
  mov    $0x6600,%edi
  call   <leftmost_one@plt>
  cmp    $0x4000,%eax
  je     L27
L29:
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L16:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L27:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L29
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D15
type_guessed: string

tool: D1: First example test pass!


tool: D15: Second example test pass!


assistant: ```c
int main(void) {
  int test_hex_0;
  int assert_ret;
  test_hex_0 = 0XFF00;
  assert_ret = 0x8000;
  !(assert_ret ^ leftmost_one(test_hex_0)) && printf("First example test pass!\n");
  test_hex_0 = 0x6600;
  assert_ret = 0x4000;
  !(assert_ret ^ leftmost_one(test_hex_0)) && printf("Second example test pass!\n");
  getchar();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_sigwinch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    $0x0,%edi
  call   <ttyname@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    D37(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0xffffffff,-0x20(%rbp)
  je     L14
  mov    D29(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  je     L17
  mov    -0xc(%rbp),%edx
  mov    D24(%rip),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <var_init@plt>
  mov    $0x0,%eax
  call   <clear@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  jmp    L45
L5:
  nop
  jmp    L45
L14:
  nop
  jmp    L45
L17:
  nop
L45:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
void handle_sigwinch(int s) {
  char *tty = NULL;
  int fd = 0;
  int result = 0;
  struct winsize win;
  tty = ttyname(0);
  if (!tty)
    return;
  fd = open(tty, O_RDWR);
  if (fd == -1)
    return;
  result = ioctl(fd, TIOCGWINSZ, &win);
  if (result == -1)
    return;
  COLS = win.ws_col;
  LINES = win.ws_row;
  var_init();
  clear();
  refresh();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<handle_sigwinch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <ttyname@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    %rsp,%rdx
  mov    D12(%rip),%rcx
  mov    (%rcx),%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    D9(%rip),%rax
  mov    0x4(%rsp),%edx
  mov    %edx,(%rax)
  mov    D22(%rip),%rax
  mov    (%rsp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <var_init@plt>
  mov    $0x0,%eax
  call   <clear@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handle_sigwinch(int s) {
  char *tty = NULL;
  int fd = 0;
  int result = 0;
  struct winsize win;
  tty = ttyname(0);
  if (!tty)
    return;
  fd = open(tty, O_RDWR);
  if (fd == -1)
    return;
  result = ioctl(fd, TIOCGWINSZ, &win);
  if (result == -1)
    return;
  COLS = win.ws_col;
  LINES = win.ws_row;
  var_init();
  clear();
  refresh();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<handle_sigwinch>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ttyname@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%rdi
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%edi
  cmp    $0xffffffff,%eax
  je     L22
  mov    D17(%rip),%rax
  mov    %rsp,%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L22
  mov    D0(%rip),%rax
  mov    0x4(%rsp),%edx
  mov    %edx,(%rax)
  mov    D13(%rip),%rax
  mov    (%rsp),%edx
  mov    %edx,(%rax)
  xor    %eax,%eax
  call   <var_init@plt>
  xor    %eax,%eax
  call   <clear@plt>
  xor    %eax,%eax
  call   <refresh@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handle_sigwinch(int s) {
  char *tty = NULL;
  int fd = 0;
  int result = 0;
  struct winsize win;
  tty = ttyname(0);
  if (!tty)
    return;
  fd = open(tty, O_RDWR);
  if (fd == -1)
    return;
  result = ioctl(fd, TIOCGWINSZ, &win);
  if (result == -1)
    return;
  COLS = win.ws_col;
  LINES = win.ws_row;
  var_init();
  clear();
  refresh();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<handle_sigwinch>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ttyname@plt>
  test   %rax,%rax
  je     L34
  mov    %rax,%rdi
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%edi
  cmp    $0xffffffff,%eax
  je     L34
  mov    D10(%rip),%rax
  mov    %rsp,%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L34
  mov    D38(%rip),%rax
  mov    0x4(%rsp),%edx
  mov    %edx,(%rax)
  mov    D32(%rip),%rax
  mov    (%rsp),%edx
  mov    %edx,(%rax)
  xor    %eax,%eax
  call   <var_init@plt>
  xor    %eax,%eax
  call   <clear@plt>
  xor    %eax,%eax
  call   <refresh@plt>
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handle_sigwinch(int s) {
  char *tty = NULL;
  int fd = 0;
  int result = 0;
  struct winsize win;
  tty = ttyname(0);
  if (!tty)
    return;
  fd = open(tty, O_RDWR);
  if (fd == -1)
    return;
  result = ioctl(fd, TIOCGWINSZ, &win);
  if (result == -1)
    return;
  COLS = win.ws_col;
  LINES = win.ws_row;
  var_init();
  clear();
  refresh();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<scalar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void scalar(const double v1[3], const double v2, double result[3]) {
  result[0] = v1[0] * v2;
  result[1] = v1[1] * v2;
  result[2] = v1[2] * v2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scalar>:
  endbr64
  movapd %xmm0,%xmm1
  mulsd  (%rdi),%xmm1
  movsd  %xmm1,(%rsi)
  movapd %xmm0,%xmm1
  mulsd  0x8(%rdi),%xmm1
  movsd  %xmm1,0x8(%rsi)
  mulsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void scalar(const double v1[3], const double v2, double result[3]) {
  result[0] = v1[0] * v2;
  result[1] = v1[1] * v2;
  result[2] = v1[2] * v2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scalar>:
  endbr64
  movsd  (%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  movsd  0x8(%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsi)
  mulsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void scalar(const double v1[3], const double v2, double result[3]) {
  result[0] = v1[0] * v2;
  result[1] = v1[1] * v2;
  result[2] = v1[2] * v2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scalar>:
  endbr64
  movsd  (%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  movsd  0x8(%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsi)
  mulsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void scalar(const double v1[3], const double v2, double result[3]) {
  result[0] = v1[0] * v2;
  result[1] = v1[1] * v2;
  result[2] = v1[2] * v2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Statement_Block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1e,%edi
  call   <Match@plt>
  test   %rax,%rax
  je     L1
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Statement_Sequence@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1f,%edi
  call   <Match@plt>
  jmp    L5
L1:
  movl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Statement_Sequence@plt>
  movl   $0x0,-0x4(%rbp)
L5:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D16
data_type: string

tool: D12: {

tool: D16: }

assistant: ```c
void Statement_Block(int *nChain) {
  int oneline = 0;
  if (Match(30, "{")) {
    Statement_Sequence(*nChain, oneline);
    Match(31, "}");
  } else {
    oneline = 1;
    Statement_Sequence(*nChain, oneline);
    oneline = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Statement_Block>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rsi
  mov    $0x1e,%edi
  call   <Match@plt>
  test   %rax,%rax
  je     L11
  mov    $0x0,%esi
  mov    (%rbx),%edi
  call   <Statement_Sequence@plt>
  lea    D13(%rip),%rsi
  mov    $0x1f,%edi
  call   <Match@plt>
L3:
  pop    %rbx
  ret
L11:
  mov    $0x1,%esi
  mov    (%rbx),%edi
  call   <Statement_Sequence@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D13
datatype: string

tool: D6: {

tool: D13: }

assistant: ```c
void Statement_Block(int *nChain) {
  int oneline = 0;
  if (Match(30, "{")) {
    Statement_Sequence(*nChain, oneline);
    Match(31, "}");
  } else {
    oneline = 1;
    Statement_Sequence(*nChain, oneline);
    oneline = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Statement_Block>:
  endbr64
  push   %rbx
  lea    D14(%rip),%rsi
  mov    %rdi,%rbx
  mov    $0x1e,%edi
  call   <Match@plt>
  test   %rax,%rax
  je     L2
  mov    (%rbx),%edi
  xor    %esi,%esi
  call   <Statement_Sequence@plt>
  lea    D19(%rip),%rsi
  mov    $0x1f,%edi
  pop    %rbx
  jmp    1070 <Match@plt>
  nopl   0x0(%rax)
L2:
  mov    (%rbx),%edi
  mov    $0x1,%esi
  pop    %rbx
  jmp    1060 <Statement_Sequence@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D14: {

tool: D19: }

assistant: ```c
void Statement_Block(int *nChain) {
  int oneline = 0;
  if (Match(30, "{")) {
    Statement_Sequence(*nChain, oneline);
    Match(31, "}");
  } else {
    oneline = 1;
    Statement_Sequence(*nChain, oneline);
    oneline = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Statement_Block>:
  endbr64
  push   %rbx
  lea    D15(%rip),%rsi
  mov    %rdi,%rbx
  mov    $0x1e,%edi
  call   <Match@plt>
  test   %rax,%rax
  je     L9
  mov    (%rbx),%edi
  xor    %esi,%esi
  call   <Statement_Sequence@plt>
  lea    D2(%rip),%rsi
  mov    $0x1f,%edi
  pop    %rbx
  jmp    1070 <Match@plt>
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%edi
  mov    $0x1,%esi
  pop    %rbx
  jmp    1060 <Statement_Sequence@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D15: {

tool: D2: }

assistant: ```c
void Statement_Block(int *nChain) {
  int oneline = 0;
  if (Match(30, "{")) {
    Statement_Sequence(*nChain, oneline);
    Match(31, "}");
  } else {
    oneline = 1;
    Statement_Sequence(*nChain, oneline);
    oneline = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Util_in_range_strict>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  comisd -0x28(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L25
  cmpl   $0x0,-0x4(%rbp)
  je     L25
  mov    $0x1,%eax
  jmp    L6
L25:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int Util_in_range_strict(const double lower, const double upper, const double x) {
  int lowcond, upcond;
  lowcond = x > lower;
  upcond = x < upper;
  return lowcond && upcond;
}
```