ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xd,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <modify@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: %d
%d


assistant: ```c
void main(void) {
  const int a = 13;
  int b = 1;
  modify(&a, &b);
  printf("%d\n%d\n", a, b);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xd,(%rsp)
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <modify@plt>
  mov    0x4(%rsp),%edx
  mov    $0xd,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D9: %d
%d


assistant: ```c
void main(void) {
  const int a = 13;
  int b = 1;
  modify(&a, &b);
  printf("%d\n%d\n", a, b);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0xd,(%rsp)
  movl   $0x1,0x4(%rsp)
  call   <modify@plt>
  mov    0x4(%rsp),%edx
  mov    $0xd,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: %d
%d


assistant: ```c
void main(void) {
  const int a = 13;
  int b = 1;
  modify(&a, &b);
  printf("%d\n%d\n", a, b);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0xd,(%rsp)
  movl   $0x1,0x4(%rsp)
  call   <modify@plt>
  mov    0x4(%rsp),%edx
  mov    $0xd,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: %d
%d


assistant: ```c
void main(void) {
  const int a = 13;
  int b = 1;
  modify(&a, &b);
  printf("%d\n%d\n", a, b);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64726f49,-0x52(%rbp)
  movw   $0x6e61,-0x4e(%rbp)
  movb   $0x0,-0x4c(%rbp)
  movabs $0x766f6e6164726f49,%rax
  mov    %rax,-0x4b(%rbp)
  movb   $0x0,-0x43(%rbp)
  mov    %rax,-0x42(%rbp)
  movb   $0x0,-0x3a(%rbp)
  fldt   0xee8(%rip)        # 2070 <_fini+0xdcc>
  fstpt  -0x70(%rbp)
  movabs $0x6b6e6142204b5344,%rax
  mov    %rax,-0x39(%rbp)
  movb   $0x0,-0x31(%rbp)
  movabs $0x424e422030384742,%rax
  movabs $0x3720383838392047,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x3635343320303234,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x20383720,-0x18(%rbp)
  movb   $0x0,-0x14(%rbp)
  movabs $0x2dea78582,%rax
  mov    %rax,-0x88(%rbp)
  movabs $0x14d79ba858,%rax
  mov    %rax,-0x80(%rbp)
  movabs $0xd44b792d7,%rax
  mov    %rax,-0x78(%rbp)
  lea    -0x39(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rsi
  lea    -0x42(%rbp),%rcx
  lea    -0x4b(%rbp),%rdx
  lea    -0x52(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  push   -0x68(%rbp)
  push   -0x70(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  mov    -0x78(%rbp),%rcx
  mov    -0x80(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string
name: unpack_data
arguments: data_label: D30
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string

tool: D14: Bank: %s


tool: D16: Account holder name: %s %s %s
IBAN: %s


tool: D30: Balance: %.5Lf


tool: D9: Credit card numbers: %Ld, %Ld, %ld


assistant: ```c
int main() {
  char firstName[] = "Iordan";
  char middleName[] = "Iordanov";
  char lastName[] = "Iordanov";
  long double balance = 123.8965;
  char bankName[] = "DSK Bank";
  char IBAN[] = "BG80 BNBG 9888 7420 3456 78 ";
  unsigned long firstCardNum = 12325455234;
  unsigned long secondCardNum = 89516648536;
  unsigned long thirdCardNum = 56987456215;
  printf("Bank: %s\n", bankName);
  printf("Account holder name: %s %s %s\nIBAN: %s\n", firstName, middleName, lastName, IBAN);
  printf("Balance: %.5Lf\n", balance);
  printf("Credit card numbers: %Ld, %Ld, %ld\n", firstCardNum, secondCardNum, thirdCardNum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x64726f49,0x1e(%rsp)
  movw   $0x6e61,0x22(%rsp)
  movb   $0x0,0x24(%rsp)
  movabs $0x766f6e6164726f49,%rax
  mov    %rax,0x25(%rsp)
  movb   $0x0,0x2d(%rsp)
  mov    %rax,0x2e(%rsp)
  movb   $0x0,0x36(%rsp)
  movabs $0x6b6e6142204b5344,%rax
  mov    %rax,0x37(%rsp)
  movb   $0x0,0x3f(%rsp)
  movabs $0x424e422030384742,%rax
  movabs $0x3720383838392047,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x3635343320303234,%rax
  mov    %rax,0x50(%rsp)
  movl   $0x20383720,0x58(%rsp)
  movb   $0x0,0x5c(%rsp)
  lea    0x37(%rsp),%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x2e(%rsp),%rcx
  lea    0x25(%rsp),%rdx
  lea    0x1e(%rsp),%rsi
  lea    0x40(%rsp),%r8
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  fldl   0xe5e(%rip)        # 2070 <_fini+0xdec>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movabs $0xd44b792d7,%rcx
  movabs $0x14d79ba858,%rdx
  movabs $0x2dea78582,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string

tool: D29: Bank: %s


tool: D20: Account holder name: %s %s %s
IBAN: %s


tool: D0: Balance: %.5Lf


tool: D10: Credit card numbers: %Ld, %Ld, %ld


assistant: ```c
int main() {
  char firstName[] = "Iordan";
  char middleName[] = "Iordanov";
  char lastName[] = "Iordanov";
  long double balance = 123.8965;
  char bankName[] = "DSK Bank";
  char IBAN[] = "BG80 BNBG 9888 7420 3456 78 ";
  unsigned long firstCardNum = 12325455234;
  unsigned long secondCardNum = 89516648536;
  unsigned long thirdCardNum = 56987456215;
  printf("Bank: %s\n", bankName);
  printf("Account holder name: %s %s %s\nIBAN: %s\n", firstName, middleName, lastName, IBAN);
  printf("Balance: %.5Lf\n", balance);
  printf("Credit card numbers: %Ld, %Ld, %ld\n", firstCardNum, secondCardNum, thirdCardNum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  movdqa D19(%rip),%xmm0
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x6e61,%eax
  lea    0x37(%rsp),%rsi
  movl   $0x64726f49,0x1e(%rsp)
  mov    %ax,0x22(%rsp)
  movabs $0x766f6e6164726f49,%rax
  mov    %rax,0x25(%rsp)
  mov    %rax,0x2e(%rsp)
  movabs $0x6b6e6142204b5344,%rax
  mov    %rax,0x37(%rsp)
  movabs $0x3635343320303234,%rax
  mov    %rax,0x50(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x40(%rsp)
  movb   $0x0,0x24(%rsp)
  movb   $0x0,0x2d(%rsp)
  movb   $0x0,0x36(%rsp)
  movb   $0x0,0x3f(%rsp)
  movl   $0x20383720,0x58(%rsp)
  movb   $0x0,0x5c(%rsp)
  call   <printf@plt>
  lea    0x2e(%rsp),%rcx
  lea    0x1e(%rsp),%rsi
  xor    %eax,%eax
  lea    0x40(%rsp),%r8
  lea    0x25(%rsp),%rdx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  fldl   0xf2b(%rip)        # 2070 <_fini+0xe04>
  lea    D43(%rip),%rdi
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  xor    %eax,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  movabs $0xd44b792d7,%rcx
  movabs $0x14d79ba858,%rdx
  movabs $0x2dea78582,%rsi
  call   <printf@plt>
  pop    %rdx
  pop    %rcx
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
datatype: byte[16]
name: read_data
arguments: data_tag: D10
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D43
datatype: string
name: read_data
arguments: data_tag: D31
datatype: string

tool: {"D19": [0x42,0x47,0x38,0x30,0x20,0x42,0x4e,0x42,0x47,0x20,0x39,0x38,0x38,0x38,0x20,0x37]}

tool: D10: Bank: %s


tool: D9: Account holder name: %s %s %s
IBAN: %s


tool: D43: Balance: %.5Lf


tool: D31: Credit card numbers: %Ld, %Ld, %ld


assistant: ```c
int main() {
  char firstName[] = "Iordan";
  char middleName[] = "Iordanov";
  char lastName[] = "Iordanov";
  long double balance = 123.8965;
  char bankName[] = "DSK Bank";
  char IBAN[] = "BG80 BNBG 9888 7420 3456 78 ";
  unsigned long firstCardNum = 12325455234;
  unsigned long secondCardNum = 89516648536;
  unsigned long thirdCardNum = 56987456215;
  printf("Bank: %s\n", bankName);
  printf("Account holder name: %s %s %s\nIBAN: %s\n", firstName, middleName, lastName, IBAN);
  printf("Balance: %.5Lf\n", balance);
  printf("Credit card numbers: %Ld, %Ld, %ld\n", firstCardNum, secondCardNum, thirdCardNum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  movdqa D4(%rip),%xmm0
  lea    D49(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x6e61,%eax
  lea    0x37(%rsp),%rsi
  movl   $0x64726f49,0x1e(%rsp)
  mov    %ax,0x22(%rsp)
  movabs $0x766f6e6164726f49,%rax
  mov    %rax,0x25(%rsp)
  mov    %rax,0x2e(%rsp)
  movabs $0x6b6e6142204b5344,%rax
  mov    %rax,0x37(%rsp)
  movabs $0x3635343320303234,%rax
  mov    %rax,0x50(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x40(%rsp)
  movb   $0x0,0x24(%rsp)
  movb   $0x0,0x2d(%rsp)
  movb   $0x0,0x36(%rsp)
  movb   $0x0,0x3f(%rsp)
  movl   $0x20383720,0x58(%rsp)
  movb   $0x0,0x5c(%rsp)
  call   <printf@plt>
  lea    0x2e(%rsp),%rcx
  lea    0x1e(%rsp),%rsi
  xor    %eax,%eax
  lea    0x40(%rsp),%r8
  lea    0x25(%rsp),%rdx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  fldl   0xf2b(%rip)        # 2070 <_fini+0xe04>
  lea    D36(%rip),%rdi
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  xor    %eax,%eax
  call   <printf@plt>
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  movabs $0xd44b792d7,%rcx
  movabs $0x14d79ba858,%rdx
  movabs $0x2dea78582,%rsi
  call   <printf@plt>
  pop    %rdx
  pop    %rcx
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D49
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string
name: unpack_data
arguments: data_tag: D36
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string

tool: {"D4": [0x42,0x47,0x38,0x30,0x20,0x42,0x4e,0x42,0x47,0x20,0x39,0x38,0x38,0x38,0x20,0x37]}

tool: D49: Bank: %s


tool: D7: Account holder name: %s %s %s
IBAN: %s


tool: D36: Balance: %.5Lf


tool: D22: Credit card numbers: %Ld, %Ld, %ld


assistant: ```c
int main() {
  char firstName[] = "Iordan";
  char middleName[] = "Iordanov";
  char lastName[] = "Iordanov";
  long double balance = 123.8965;
  char bankName[] = "DSK Bank";
  char IBAN[] = "BG80 BNBG 9888 7420 3456 78 ";
  unsigned long firstCardNum = 12325455234;
  unsigned long secondCardNum = 89516648536;
  unsigned long thirdCardNum = 56987456215;
  printf("Bank: %s\n", bankName);
  printf("Account holder name: %s %s %s\nIBAN: %s\n", firstName, middleName, lastName, IBAN);
  printf("Balance: %.5Lf\n", balance);
  printf("Credit card numbers: %Ld, %Ld, %ld\n", firstCardNum, secondCardNum, thirdCardNum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<p_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %edi,-0xf4(%rbp)
  mov    %rsi,-0x100(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xec(%rbp)
  movl   $0x0,-0xe8(%rbp)
  mov    -0x100(%rbp),%rdx
  mov    -0xe4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <flag_funct@plt>
  cmpq   $0x0,-0x100(%rbp)
  jne    L23
  mov    $0xffffffff,%eax
  jmp    L70
L3:
  mov    -0xec(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x100(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L15
  mov    -0xec(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x100(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <flag_match@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L15
  mov    -0xec(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x100(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <flag_match@plt>
  mov    -0xe0(%rbp,%rax,8),%rcx
  mov    -0xf4(%rbp),%edx
  mov    -0xe4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%rcx
  movsbl %al,%eax
  mov    %eax,%edi
  call   <flag_match@plt>
  mov    %eax,-0xe8(%rbp)
  addl   $0x1,-0xec(%rbp)
  jmp    L6
L15:
  mov    -0xec(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x100(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xf4(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
L6:
  addl   $0x1,-0xec(%rbp)
L23:
  mov    -0xec(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x100(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0xe4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xe8(%rbp),%eax
L70:
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

assistant: ```c
int p_printf(int fd, const char *format, ...) {
  va_list list;
  int (*ptr[4])(va_list list, int fd);
  int i;
  int run;
  i = 0;
  run = 0;
  va_start(list, format);
  flag_funct(ptr);
  if (!(format))
    return (-1);
  while ((format[i])) {
    if (format[i] == '%' && (flag_match(format[i + 1]) != -1)) {
      run = flag_match(ptr[flag_match(format[i + 1])](list, fd));
      i++;
    } else
      write(fd, &format[i], 1);
    i++;
  }
  va_end(list);
  return (run);
}
```
user: What is the c source code of the assembly code below:

```asm
<p_printf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  call   <flag_funct@plt>
  test   %r12,%r12
  je     L49
  movzbl (%r12),%eax
  test   %al,%al
  je     L75
  mov    %r12,%rbp
  mov    $0x0,%r14d
  mov    $0x0,%ebx
  mov    $0x0,%edx
  jmp    L28
L89:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
L8:
  add    $0x1,%ebx
  movslq %ebx,%rdx
  lea    (%r12,%rdx,1),%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L13
L28:
  cmp    $0x25,%al
  jne    L89
  lea    0x1(%r12,%rdx,1),%r15
  movsbl (%r15),%edi
  call   <flag_match@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L89
  movsbl (%r15),%edi
  call   <flag_match@plt>
  mov    %r13d,%esi
  mov    $0x0,%edi
  call   *(%rsp,%rax,8)
  movsbl %al,%edi
  call   <flag_match@plt>
  mov    %eax,%r14d
  add    $0x1,%ebx
  jmp    L8
L75:
  mov    $0x0,%r14d
L13:
  mov    $0x0,%edi
  call   <va_end@plt>
L14:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    %r14d,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  mov    $0xffffffff,%r14d
  jmp    L14
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int p_printf(int fd, const char *format, ...) {
  va_list list;
  int (*ptr[4])(va_list list, int fd);
  int i;
  int run;
  i = 0;
  run = 0;
  va_start(list, format);
  flag_funct(ptr);
  if (!(format))
    return (-1);
  while ((format[i])) {
    if (format[i] == '%' && (flag_match(format[i + 1]) != -1)) {
      run = flag_match(ptr[flag_match(format[i + 1])](list, fd));
      i++;
    } else
      write(fd, &format[i], 1);
    i++;
  }
  va_end(list);
  return (run);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<p_printf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  xor    %edi,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <va_start@plt>
  mov    %rsp,%rdi
  call   <flag_funct@plt>
  test   %r12,%r12
  je     L36
  movzbl (%r12),%eax
  test   %al,%al
  je     L59
  mov    %r12,%rbp
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  xor    %edx,%edx
  jmp    L80
  nopl   (%rax)
L55:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
L67:
  add    $0x1,%ebx
  movslq %ebx,%rdx
  lea    (%r12,%rdx,1),%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L43
L80:
  cmp    $0x25,%al
  jne    L55
  lea    0x1(%r12,%rdx,1),%r15
  movsbl (%r15),%edi
  call   <flag_match@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L55
  movsbl (%r15),%edi
  add    $0x1,%ebx
  call   <flag_match@plt>
  mov    %r13d,%esi
  xor    %edi,%edi
  call   *(%rsp,%rax,8)
  movsbl %al,%edi
  call   <flag_match@plt>
  mov    %eax,%r14d
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L59:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L43:
  xor    %edi,%edi
  call   <va_end@plt>
L60:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x38,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    $0xffffffff,%r14d
  jmp    L60
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int p_printf(int fd, const char *format, ...) {
  va_list list;
  int (*ptr[4])(va_list list, int fd);
  int i;
  int run;
  i = 0;
  run = 0;
  va_start(list, format);
  flag_funct(ptr);
  if (!(format))
    return (-1);
  while ((format[i])) {
    if (format[i] == '%' && (flag_match(format[i + 1]) != -1)) {
      run = flag_match(ptr[flag_match(format[i + 1])](list, fd));
      i++;
    } else
      write(fd, &format[i], 1);
    i++;
  }
  va_end(list);
  return (run);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<p_printf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  xor    %edi,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <va_start@plt>
  mov    %rsp,%rdi
  call   <flag_funct@plt>
  test   %r12,%r12
  je     L79
  movzbl (%r12),%eax
  test   %al,%al
  je     L25
  mov    %r12,%rbp
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  xor    %edx,%edx
  jmp    L74
  nopl   (%rax)
L70:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
L23:
  add    $0x1,%ebx
  movslq %ebx,%rdx
  lea    (%r12,%rdx,1),%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L77
L74:
  cmp    $0x25,%al
  jne    L70
  lea    0x1(%r12,%rdx,1),%r15
  movsbl (%r15),%edi
  call   <flag_match@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L70
  movsbl (%r15),%edi
  add    $0x1,%ebx
  call   <flag_match@plt>
  mov    %r13d,%esi
  xor    %edi,%edi
  call   *(%rsp,%rax,8)
  movsbl %al,%edi
  call   <flag_match@plt>
  mov    %eax,%r14d
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L77:
  xor    %edi,%edi
  call   <va_end@plt>
L47:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x38,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  mov    $0xffffffff,%r14d
  jmp    L47
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int p_printf(int fd, const char *format, ...) {
  va_list list;
  int (*ptr[4])(va_list list, int fd);
  int i;
  int run;
  i = 0;
  run = 0;
  va_start(list, format);
  flag_funct(ptr);
  if (!(format))
    return (-1);
  while ((format[i])) {
    if (format[i] == '%' && (flag_match(format[i + 1]) != -1)) {
      run = flag_match(ptr[flag_match(format[i + 1])](list, fd));
      i++;
    } else
      write(fd, &format[i], 1);
    i++;
  }
  va_end(list);
  return (run);
}
```
user: Translate the below assembly code into C programming language:

```asm
<squareIntegerMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    %esi,%eax
  imul   %ecx,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void squareIntegerMatrix(int *inputMatrix, int nbRow, int nbCol, int **resultMatrix, int *nbRowRes, int *nbColRes) {
  int i;
  int size = nbRow * nbCol;
  *nbRowRes = nbRow;
  *nbColRes = nbCol;
  *resultMatrix = (int *)malloc(size * sizeof(int));
  for (i = 0; i < size; i++) {
    (*resultMatrix)[i] = inputMatrix[i] * inputMatrix[i];
  }
}
```