ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<slurm_strcasestr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L38
L16:
  movl   $0x0,-0x24(%rbp)
  jmp    L49
L44:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L15
  addl   $0x1,-0x24(%rbp)
L49:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L44
  jmp    L47
L15:
  nop
L47:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L67
  mov    -0x18(%rbp),%rax
  jmp    L52
L67:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x28(%rbp)
L38:
  mov    -0x28(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L16
  mov    $0x0,%eax
L52:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *slurm_strcasestr(char *haystack, char *needle) {
  int hay_inx, hay_size = strlen(haystack);
  int need_inx, need_size = strlen(needle);
  char *hay_ptr = haystack;
  for (hay_inx = 0; hay_inx < hay_size; hay_inx++) {
    for (need_inx = 0; need_inx < need_size; need_inx++) {
      if (tolower((int)hay_ptr[need_inx]) != tolower((int)needle[need_inx]))
        break;
    }
    if (need_inx == need_size)
      return hay_ptr;
    else
      hay_ptr++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<slurm_strcasestr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r15
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,0x4(%rsp)
  test   %ebx,%ebx
  jle    L26
  mov    %ebx,%ebx
  lea    0x0(%r13,%rbx,1),%rax
  mov    %rax,0x8(%rsp)
  jmp    L63
L22:
  cmp    %r12d,0x4(%rsp)
  je     L79
  add    $0x1,%r13
  cmp    0x8(%rsp),%r13
  je     L46
L63:
  mov    0x4(%rsp),%eax
  mov    %eax,%r14d
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  test   %eax,%eax
  jle    L22
L65:
  mov    %ebx,%r12d
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <tolower@plt>
  mov    %rax,%rbp
  movsbl (%r15,%rbx,1),%edi
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L22
  lea    0x1(%rbx),%r12d
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L65
  jmp    L22
L26:
  mov    $0x0,%r13d
  jmp    L79
L46:
  mov    $0x0,%r13d
L79:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *slurm_strcasestr(char *haystack, char *needle) {
  int hay_inx, hay_size = strlen(haystack);
  int need_inx, need_size = strlen(needle);
  char *hay_ptr = haystack;
  for (hay_inx = 0; hay_inx < hay_size; hay_inx++) {
    for (need_inx = 0; need_inx < need_size; need_inx++) {
      if (tolower((int)hay_ptr[need_inx]) != tolower((int)needle[need_inx]))
        break;
    }
    if (need_inx == need_size)
      return hay_ptr;
    else
      hay_ptr++;
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<slurm_strcasestr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r15
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    (%r12,%r15,1),%rax
  mov    %rax,0x8(%rsp)
  lea    0x1(%r14),%r13d
  test   %r15d,%r15d
  jle    L70
  nopl   (%rax)
L22:
  mov    $0x1,%r15d
  xor    %eax,%eax
  test   %r14d,%r14d
  jg     L27
  jmp    L63
  nop
L54:
  mov    %r15d,%eax
  add    $0x1,%r15
  cmp    %r13,%r15
  je     L63
L27:
  movsbl -0x1(%r12,%r15,1),%edi
  call   <tolower@plt>
  movsbl -0x1(%rbp,%r15,1),%edi
  mov    %rax,%rbx
  call   <tolower@plt>
  cmp    %rax,%rbx
  je     L54
  add    $0x1,%r12
  cmp    0x8(%rsp),%r12
  jne    L22
L70:
  xor    %r12d,%r12d
L52:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  cmp    %eax,%r14d
  je     L52
  add    $0x1,%r12
  cmp    0x8(%rsp),%r12
  jne    L22
  jmp    L70
```

assistant: ```c
char *slurm_strcasestr(char *haystack, char *needle) {
  int hay_inx, hay_size = strlen(haystack);
  int need_inx, need_size = strlen(needle);
  char *hay_ptr = haystack;
  for (hay_inx = 0; hay_inx < hay_size; hay_inx++) {
    for (need_inx = 0; need_inx < need_size; need_inx++) {
      if (tolower((int)hay_ptr[need_inx]) != tolower((int)needle[need_inx]))
        break;
    }
    if (need_inx == need_size)
      return hay_ptr;
    else
      hay_ptr++;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<slurm_strcasestr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r15
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    (%r12,%r15,1),%rax
  mov    %rax,0x8(%rsp)
  lea    0x1(%r14),%r13d
  test   %r15d,%r15d
  jle    L11
  nopl   (%rax)
L41:
  mov    $0x1,%r15d
  xor    %eax,%eax
  test   %r14d,%r14d
  jg     L69
  jmp    L19
  nop
L61:
  mov    %r15d,%eax
  add    $0x1,%r15
  cmp    %r15,%r13
  je     L19
L69:
  movsbl -0x1(%r12,%r15,1),%edi
  call   <tolower@plt>
  movsbl -0x1(%rbp,%r15,1),%edi
  mov    %rax,%rbx
  call   <tolower@plt>
  cmp    %rax,%rbx
  je     L61
  add    $0x1,%r12
  cmp    0x8(%rsp),%r12
  jne    L41
L11:
  xor    %r12d,%r12d
L53:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  cmp    %eax,%r14d
  je     L53
  add    $0x1,%r12
  cmp    0x8(%rsp),%r12
  jne    L41
  jmp    L11
```

assistant: ```c
char *slurm_strcasestr(char *haystack, char *needle) {
  int hay_inx, hay_size = strlen(haystack);
  int need_inx, need_size = strlen(needle);
  char *hay_ptr = haystack;
  for (hay_inx = 0; hay_inx < hay_size; hay_inx++) {
    for (need_inx = 0; need_inx < need_size; need_inx++) {
      if (tolower((int)hay_ptr[need_inx]) != tolower((int)needle[need_inx]))
        break;
    }
    if (need_inx == need_size)
      return hay_ptr;
    else
      hay_ptr++;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dheap_left_child_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L14
  mov    $0xffffffff,%eax
  jmp    L3
L14:
  mov    -0x4(%rbp),%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int dheap_left_child_index(int i, int n) {
  int li = 2 * i + 1;
  if (li >= n)
    return -1;
  else
    return li;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dheap_left_child_index>:
  endbr64
  lea    0x1(%rdi,%rdi,1),%eax
  cmp    %esi,%eax
  jge    L11
L14:
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int dheap_left_child_index(int i, int n) {
  int li = 2 * i + 1;
  if (li >= n)
    return -1;
  else
    return li;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dheap_left_child_index>:
  endbr64
  lea    0x1(%rdi,%rdi,1),%eax
  cmp    %esi,%eax
  jge    L9
  ret
  nopl   (%rax)
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dheap_left_child_index(int i, int n) {
  int li = 2 * i + 1;
  if (li >= n)
    return -1;
  else
    return li;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dheap_left_child_index>:
  endbr64
  lea    0x1(%rdi,%rdi,1),%eax
  cmp    %esi,%eax
  jge    L5
  ret
  nopl   (%rax)
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int dheap_left_child_index(int i, int n) {
  int li = 2 * i + 1;
  if (li >= n)
    return -1;
  else
    return li;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L12:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
L1:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum_i(const int *a, int size) {
  int s = 0;
  while (--size >= 0)
    s += a[size];
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sum_i>:
  endbr64
  sub    $0x1,%esi
  js     L18
  movslq %esi,%rsi
  mov    $0x0,%eax
L8:
  add    (%rdi,%rsi,4),%eax
  sub    $0x1,%rsi
  test   %esi,%esi
  jns    L8
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int sum_i(const int *a, int size) {
  int s = 0;
  while (--size >= 0)
    s += a[size];
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_i>:
  endbr64
  sub    $0x1,%esi
  js     L4
  movslq %esi,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L19:
  add    (%rdi,%rsi,4),%eax
  sub    $0x1,%rsi
  test   %esi,%esi
  jns    L19
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum_i(const int *a, int size) {
  int s = 0;
  while (--size >= 0)
    s += a[size];
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sum_i>:
  endbr64
  mov    %esi,%r8d
  mov    %rdi,%rcx
  sub    $0x1,%r8d
  js     L52
  cmp    $0x2,%r8d
  jbe    L23
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  lea    -0x10(%rdi,%rax,4),%rdx
  mov    %esi,%edi
  shr    $0x2,%edi
  lea    -0x10(%rdx),%rax
  lea    -0x1(%rdi),%r9d
  mov    %rax,%rdi
  shl    $0x4,%r9
  sub    %r9,%rdi
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L43:
  sub    $0x10,%rax
L48:
  movdqu (%rdx),%xmm1
  mov    %rax,%rdx
  pshufd $0x1b,%xmm1,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L43
  movdqa %xmm0,%xmm1
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  sub    %edx,%r8d
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%esi
  je     L0
L77:
  movslq %r8d,%rdx
  mov    %r8d,%edi
  add    (%rcx,%rdx,4),%eax
  sub    $0x1,%edi
  lea    0x0(,%rdx,4),%rsi
  js     L26
  add    -0x4(%rcx,%rsi,1),%eax
  cmp    $0x1,%r8d
  je     L26
  add    -0x8(%rcx,%rsi,1),%eax
  ret
L52:
  xor    %eax,%eax
L26:
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
L23:
  xor    %eax,%eax
  jmp    L77
```

assistant: ```c
int sum_i(const int *a, int size) {
  int s = 0;
  while (--size >= 0)
    s += a[size];
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eat_token_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L59
L28:
  addq   $0x1,-0x8(%rbp)
L59:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L28
L47:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *eat_token_end(const char *p, const char *pend) {
  for (; (p < pend) && (*p != ' ') && (*p != '\t') && (*p != '\n') && (*p != '\r'); p++)
    ;
  return (char *)p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eat_token_end>:
  endbr64
  mov    %rdi,%rax
  movabs $0x100002600,%rcx
  cmp    %rsi,%rdi
  jb     L26
  ret
L24:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L38
L26:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  ja     L24
  bt     %rdx,%rcx
  jae    L24
  ret
L38:
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *eat_token_end(const char *p, const char *pend) {
  for (; (p < pend) && (*p != ' ') && (*p != '\t') && (*p != '\n') && (*p != '\r'); p++)
    ;
  return (char *)p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eat_token_end>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jb     L35
  jmp    L64
  xchg   %ax,%ax
L31:
  cmp    $0x8,%dl
  jg     L62
L10:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L7
L35:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L7
  cmp    $0xa,%dl
  jle    L31
  cmp    $0xd,%dl
  jne    L10
L7:
  ret
  nopl   0x0(%rax)
L62:
  ret
L64:
  ret
```

assistant: ```c
char *eat_token_end(const char *p, const char *pend) {
  for (; (p < pend) && (*p != ' ') && (*p != '\t') && (*p != '\n') && (*p != '\r'); p++)
    ;
  return (char *)p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<eat_token_end>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jb     L54
  jmp    L69
  xchg   %ax,%ax
L52:
  cmp    $0x8,%dl
  jg     L10
L7:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L65
L54:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L65
  cmp    $0xa,%dl
  jle    L52
  cmp    $0xd,%dl
  jne    L7
L65:
  ret
  nopl   0x0(%rax)
L10:
  ret
L69:
  ret
```

assistant: ```c
char *eat_token_end(const char *p, const char *pend) {
  for (; (p < pend) && (*p != ' ') && (*p != '\t') && (*p != '\n') && (*p != '\r'); p++)
    ;
  return (char *)p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mon_tfsrun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <monLock@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_tfsrun@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <monUnlock@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mon_tfsrun(char **name, int verbose) {
  int ret;
  monLock();
  ret = _tfsrun(name, verbose);
  monUnlock();
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mon_tfsrun>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <monLock@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_tfsrun@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <monUnlock@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int mon_tfsrun(char **name, int verbose) {
  int ret;
  monLock();
  ret = _tfsrun(name, verbose);
  monUnlock();
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mon_tfsrun>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <monLock@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_tfsrun@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <monUnlock@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mon_tfsrun(char **name, int verbose) {
  int ret;
  monLock();
  ret = _tfsrun(name, verbose);
  monUnlock();
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mon_tfsrun>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <monLock@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_tfsrun@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <monUnlock@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mon_tfsrun(char **name, int verbose) {
  int ret;
  monLock();
  ret = _tfsrun(name, verbose);
  monUnlock();
  return (ret);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_valid_interface>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getifaddrs@plt>
  test   %rax,%rax
  je     L9
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L68
L9:
  movl   $0x0,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L3
L48:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
  movl   $0x1,-0x1c(%rbp)
  jmp    L60
L26:
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
L3:
  cmpq   $0x0,-0x10(%rbp)
  jne    L48
L60:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <freeifaddrs@plt>
  mov    -0x1c(%rbp),%eax
L68:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2: Failed to getifaddrs()

assistant: ```c
int is_valid_interface(const char *ifname) {
  struct ifaddrs *ifa, *cur;
  if (getifaddrs(&ifa)) {
    perror("Failed to getifaddrs()");
    return 0;
  }
  int found = 0;
  for (cur = ifa; cur; cur = cur->ifa_next) {
    if (strcmp(ifname, cur->ifa_name) == 0) {
      found = 1;
      break;
    }
  }
  freeifaddrs(ifa);
  return found;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_valid_interface>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  test   %rax,%rax
  jne    L42
  mov    (%rsp),%rbx
  test   %rbx,%rbx
  je     L57
L28:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L21
  mov    0x8(%rbx),%rbx
  test   %rbx,%rbx
  jne    L28
  jmp    L23
L42:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%ebx
  jmp    L75
L57:
  mov    $0x0,%ebx
  jmp    L23
L21:
  mov    $0x1,%ebx
L23:
  mov    (%rsp),%rdi
  call   <freeifaddrs@plt>
L75:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: Failed to getifaddrs()

assistant: ```c
int is_valid_interface(const char *ifname) {
  struct ifaddrs *ifa, *cur;
  if (getifaddrs(&ifa)) {
    perror("Failed to getifaddrs()");
    return 0;
  }
  int found = 0;
  for (cur = ifa; cur; cur = cur->ifa_next) {
    if (strcmp(ifname, cur->ifa_name) == 0) {
      found = 1;
      break;
    }
  }
  freeifaddrs(ifa);
  return found;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_valid_interface>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  test   %rax,%rax
  jne    L37
  mov    (%rsp),%rbp
  test   %rbp,%rbp
  jne    L48
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L49:
  mov    0x8(%rbp),%rbp
  test   %rbp,%rbp
  je     L57
L48:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L49
  mov    (%rsp),%rbp
  mov    $0x1,%r12d
L23:
  mov    %rbp,%rdi
  call   <freeifaddrs@plt>
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    (%rsp),%rbp
  xor    %r12d,%r12d
  jmp    L23
  nopl   0x0(%rax)
L37:
  lea    D3(%rip),%rdi
  xor    %r12d,%r12d
  call   <perror@plt>
  jmp    L45
L55:
  xor    %r12d,%r12d
  jmp    L23
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: Failed to getifaddrs()

assistant: ```c
int is_valid_interface(const char *ifname) {
  struct ifaddrs *ifa, *cur;
  if (getifaddrs(&ifa)) {
    perror("Failed to getifaddrs()");
    return 0;
  }
  int found = 0;
  for (cur = ifa; cur; cur = cur->ifa_next) {
    if (strcmp(ifname, cur->ifa_name) == 0) {
      found = 1;
      break;
    }
  }
  freeifaddrs(ifa);
  return found;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_valid_interface>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getifaddrs@plt>
  test   %rax,%rax
  jne    L4
  mov    (%rsp),%rbp
  test   %rbp,%rbp
  jne    L45
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L40:
  mov    0x8(%rbp),%rbp
  test   %rbp,%rbp
  je     L86
L45:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L40
  mov    (%rsp),%rbp
  mov    $0x1,%r12d
L25:
  mov    %rbp,%rdi
  call   <freeifaddrs@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L86:
  mov    (%rsp),%rbp
  xor    %r12d,%r12d
  jmp    L25
  nopl   0x0(%rax)
L4:
  lea    D6(%rip),%rdi
  xor    %r12d,%r12d
  call   <perror@plt>
  jmp    L5
L68:
  xor    %r12d,%r12d
  jmp    L25
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: Failed to getifaddrs()

assistant: ```c
int is_valid_interface(const char *ifname) {
  struct ifaddrs *ifa, *cur;
  if (getifaddrs(&ifa)) {
    perror("Failed to getifaddrs()");
    return 0;
  }
  int found = 0;
  for (cur = ifa; cur; cur = cur->ifa_next) {
    if (strcmp(ifname, cur->ifa_name) == 0) {
      found = 1;
      break;
    }
  }
  freeifaddrs(ifa);
  return found;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0x1e8480,%edi
  call   <sieve_and_sum@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: ANSWER: %ld


assistant: ```c
int main() {
  long sum = 0;
  sum = sieve_and_sum(2000000);
  printf("ANSWER: %ld\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <sieve_and_sum@plt>
  mov    %rax,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: ANSWER: %ld


assistant: ```c
int main() {
  long sum = 0;
  sum = sieve_and_sum(2000000);
  printf("ANSWER: %ld\n", sum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <sieve_and_sum@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: ANSWER: %ld


assistant: ```c
int main() {
  long sum = 0;
  sum = sieve_and_sum(2000000);
  printf("ANSWER: %ld\n", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <sieve_and_sum@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D5: ANSWER: %ld


assistant: ```c
int main() {
  long sum = 0;
  sum = sieve_and_sum(2000000);
  printf("ANSWER: %ld\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PendSV_Handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  jmp    L1
```

assistant: ```c
__attribute__((weak)) void PendSV_Handler(void) {
  while (1) {
  }
}
```