ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jg     L4
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L6
L4:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <estimateE@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <calculateEX@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D41
type_infered: string
name: read_data
arguments: label: D76
type_infered: string
name: read_data
arguments: label: D49
type_infered: string
name: read_data
arguments: label: D77
type_infered: string
name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D69
type_infered: string
name: read_data
arguments: label: D7
type_infered: string

tool: D25: Enter a number and I will tell you its factorial

tool: D41: and use it to estimate e, and calculate

tool: D76: the value of e to the power of x: 

tool: D49: %d

tool: D77: Error - number must be 1 or greater

tool: D24: Factorial       =  %d


tool: D69: Estimation of e =  %f


tool: D7: Value of e to the power of x = %f


assistant: ```c
int main() {
  int num;
  printf("Enter a number and I will tell you its factorial\n");
  printf("and use it to estimate e, and calculate\n");
  printf("the value of e to the power of x: ");
  scanf("%d", &num);
  if (num < 1) {
    printf("Error - number must be 1 or greater\n");
    return 0;
  }
  printf("Factorial       =  %d\n", factorial(num));
  printf("Estimation of e =  %f\n", estimateE(num));
  printf("Value of e to the power of x = %f\n", calculateEX(num));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L29
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D76(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <estimateE@plt>
  lea    D52(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <calculateEX@plt>
  lea    D59(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L29:
  lea    D60(%rip),%rdi
  call   <puts@plt>
  jmp    L9
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D44
type_guessed: string
name: parse_data
arguments: data_label: D36
type_guessed: string
name: parse_data
arguments: data_label: D76
type_guessed: string
name: parse_data
arguments: data_label: D52
type_guessed: string
name: parse_data
arguments: data_label: D59
type_guessed: string
name: parse_data
arguments: data_label: D60
type_guessed: string

tool: D14: Enter a number and I will tell you its factorial

tool: D25: and use it to estimate e, and calculate

tool: D44: the value of e to the power of x: 

tool: D36: %d

tool: D76: Factorial       =  %d


tool: D52: Estimation of e =  %f


tool: D59: Value of e to the power of x = %f


tool: D60: Error - number must be 1 or greater

assistant: ```c
int main() {
  int num;
  printf("Enter a number and I will tell you its factorial\n");
  printf("and use it to estimate e, and calculate\n");
  printf("the value of e to the power of x: ");
  scanf("%d", &num);
  if (num < 1) {
    printf("Error - number must be 1 or greater\n");
    return 0;
  }
  printf("Factorial       =  %d\n", factorial(num));
  printf("Estimation of e =  %f\n", estimateE(num));
  printf("Value of e to the power of x = %f\n", calculateEX(num));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D48(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L9
  call   <factorial@plt>
  lea    D72(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <estimateE@plt>
  lea    D43(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <calculateEX@plt>
  lea    D33(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  lea    D69(%rip),%rdi
  call   <puts@plt>
  jmp    L26
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D28
data_type: string
name: unpack_data
arguments: data_label: D45
data_type: string
name: unpack_data
arguments: data_label: D37
data_type: string
name: unpack_data
arguments: data_label: D48
data_type: string
name: unpack_data
arguments: data_label: D72
data_type: string
name: unpack_data
arguments: data_label: D43
data_type: string
name: unpack_data
arguments: data_label: D33
data_type: string
name: unpack_data
arguments: data_label: D69
data_type: string

tool: D28: Enter a number and I will tell you its factorial

tool: D45: and use it to estimate e, and calculate

tool: D37: the value of e to the power of x: 

tool: D48: %d

tool: D72: Factorial       =  %d


tool: D43: Estimation of e =  %f


tool: D33: Value of e to the power of x = %f


tool: D69: Error - number must be 1 or greater

assistant: ```c
int main() {
  int num;
  printf("Enter a number and I will tell you its factorial\n");
  printf("and use it to estimate e, and calculate\n");
  printf("the value of e to the power of x: ");
  scanf("%d", &num);
  if (num < 1) {
    printf("Error - number must be 1 or greater\n");
    return 0;
  }
  printf("Factorial       =  %d\n", factorial(num));
  printf("Estimation of e =  %f\n", estimateE(num));
  printf("Value of e to the power of x = %f\n", calculateEX(num));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D76(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D72(%rip),%rdi
  call   <puts@plt>
  lea    D78(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D79(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L12
  call   <factorial@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <estimateE@plt>
  lea    D62(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <calculateEX@plt>
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  lea    D54(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D76
type_guessed: string
name: disassemble_data
arguments: tag: D72
type_guessed: string
name: disassemble_data
arguments: tag: D78
type_guessed: string
name: disassemble_data
arguments: tag: D79
type_guessed: string
name: disassemble_data
arguments: tag: D23
type_guessed: string
name: disassemble_data
arguments: tag: D62
type_guessed: string
name: disassemble_data
arguments: tag: D55
type_guessed: string
name: disassemble_data
arguments: tag: D54
type_guessed: string

tool: D76: Enter a number and I will tell you its factorial

tool: D72: and use it to estimate e, and calculate

tool: D78: the value of e to the power of x: 

tool: D79: %d

tool: D23: Factorial       =  %d


tool: D62: Estimation of e =  %f


tool: D55: Value of e to the power of x = %f


tool: D54: Error - number must be 1 or greater

assistant: ```c
int main() {
  int num;
  printf("Enter a number and I will tell you its factorial\n");
  printf("and use it to estimate e, and calculate\n");
  printf("the value of e to the power of x: ");
  scanf("%d", &num);
  if (num < 1) {
    printf("Error - number must be 1 or greater\n");
    return 0;
  }
  printf("Factorial       =  %d\n", factorial(num));
  printf("Estimation of e =  %f\n", estimateE(num));
  printf("Value of e to the power of x = %f\n", calculateEX(num));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<NoteTableAdjust>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L5:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L13:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  sarl   -0x14(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  add    %esi,%edx
  mov    %dx,(%rax)
  addl   $0xc,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L32:
  cmpl   $0x7,-0xc(%rbp)
  jle    L13
  addl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0xb,-0x8(%rbp)
  jle    L5
  nop
  pop    %rbp
  ret
```

assistant: ```c
void NoteTableAdjust(unsigned char *adjust_table, unsigned short *Tone) {
  int blah, extra;
  int offset = 0;
  int x, y;
  for (y = 0; y < 12; y++) {
    offset = y;
    blah = adjust_table[y];
    for (x = 0; x < 8; x++) {
      extra = blah & 1;
      blah >>= 1;
      Tone[offset] += extra;
      offset += 12;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NoteTableAdjust>:
  endbr64
  add    $0xc0,%rsi
  mov    $0x0,%r8d
  jmp    L31
L21:
  add    $0x1,%r8
  add    $0x2,%rsi
  cmp    $0xc,%r8
  je     L16
L31:
  movzbl (%rdi,%r8,1),%edx
  lea    -0xc0(%rsi),%rax
L10:
  mov    %edx,%ecx
  and    $0x1,%ecx
  sar    %edx
  add    %cx,(%rax)
  add    $0x18,%rax
  cmp    %rsi,%rax
  jne    L10
  jmp    L21
L16:
  ret
```

assistant: ```c
void NoteTableAdjust(unsigned char *adjust_table, unsigned short *Tone) {
  int blah, extra;
  int offset = 0;
  int x, y;
  for (y = 0; y < 12; y++) {
    offset = y;
    blah = adjust_table[y];
    for (x = 0; x < 8; x++) {
      extra = blah & 1;
      blah >>= 1;
      Tone[offset] += extra;
      offset += 12;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<NoteTableAdjust>:
  endbr64
  add    $0xc0,%rsi
  xor    %r8d,%r8d
  xchg   %ax,%ax
L13:
  movzbl (%rdi,%r8,1),%edx
  lea    -0xc0(%rsi),%rax
  nopl   0x0(%rax)
L14:
  mov    %edx,%ecx
  sar    %edx
  and    $0x1,%ecx
  add    %cx,(%rax)
  add    $0x18,%rax
  cmp    %rax,%rsi
  jne    L14
  add    $0x1,%r8
  add    $0x2,%rsi
  cmp    $0xc,%r8
  jne    L13
  ret
```

assistant: ```c
void NoteTableAdjust(unsigned char *adjust_table, unsigned short *Tone) {
  int blah, extra;
  int offset = 0;
  int x, y;
  for (y = 0; y < 12; y++) {
    offset = y;
    blah = adjust_table[y];
    for (x = 0; x < 8; x++) {
      extra = blah & 1;
      blah >>= 1;
      Tone[offset] += extra;
      offset += 12;
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<NoteTableAdjust>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rsi
  lea    0x18(%rax),%rdi
  xchg   %ax,%ax
L6:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  mov    %edx,%ecx
  and    $0x1,%ecx
  add    %cx,(%rax)
  mov    %edx,%ecx
  sar    %ecx
  and    $0x1,%ecx
  add    %cx,0x18(%rax)
  mov    %edx,%ecx
  sar    $0x2,%ecx
  and    $0x1,%ecx
  add    %cx,0x30(%rax)
  mov    %edx,%ecx
  sar    $0x3,%ecx
  and    $0x1,%ecx
  add    %cx,0x48(%rax)
  mov    %edx,%ecx
  sar    $0x4,%ecx
  and    $0x1,%ecx
  add    %cx,0x60(%rax)
  mov    %edx,%ecx
  sar    $0x5,%ecx
  and    $0x1,%ecx
  add    %cx,0x78(%rax)
  mov    %edx,%ecx
  sar    $0x7,%edx
  sar    $0x6,%ecx
  add    %dx,0xa8(%rax)
  and    $0x1,%ecx
  add    %cx,0x90(%rax)
  add    $0x2,%rax
  cmp    %rax,%rdi
  jne    L6
  ret
```

assistant: ```c
void NoteTableAdjust(unsigned char *adjust_table, unsigned short *Tone) {
  int blah, extra;
  int offset = 0;
  int x, y;
  for (y = 0; y < 12; y++) {
    offset = y;
    blah = adjust_table[y];
    for (x = 0; x < 8; x++) {
      extra = blah & 1;
      blah >>= 1;
      Tone[offset] += extra;
      offset += 12;
    }
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L3
  mov    $0x0,%eax
  call   <usage@plt>
L3:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x121,%edi
  call   <syscall@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L15
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L15:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D4
type: string

tool: D12: Zombify: An error occured.


tool: D4: Zombify sucessful.


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    usage();
  }
  pid_t target = atol(argv[1]);
  long ret_val = syscall(289, target);
  if (ret_val == -1) {
    printf("Zombify: An error occured.\n");
    exit(-1);
  }
  printf("Zombify sucessful.\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L7
L8:
  mov    0x8(%rbx),%rdi
  call   <atol@plt>
  mov    %eax,%esi
  mov    $0x121,%edi
  call   <syscall@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L13
L36:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L7:
  mov    $0x0,%eax
  call   <usage@plt>
  jmp    L8
L13:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L36
```

tool_calls: name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string

tool: D14: Zombify sucessful.


tool: D18: Zombify: An error occured.


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    usage();
  }
  pid_t target = atol(argv[1]);
  long ret_val = syscall(289, target);
  if (ret_val == -1) {
    printf("Zombify: An error occured.\n");
    exit(-1);
  }
  printf("Zombify sucessful.\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L3
L36:
  mov    0x8(%rbx),%rdi
  call   <atol@plt>
  mov    $0x121,%edi
  mov    %eax,%esi
  call   <syscall@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L38
L18:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  xor    %eax,%eax
  call   <usage@plt>
  jmp    L36
L38:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D2
datatype: string

tool: D17: Zombify sucessful.


tool: D2: Zombify: An error occured.


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    usage();
  }
  pid_t target = atol(argv[1]);
  long ret_val = syscall(289, target);
  if (ret_val == -1) {
    printf("Zombify: An error occured.\n");
    exit(-1);
  }
  printf("Zombify sucessful.\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L7
L24:
  mov    0x8(%rbx),%rdi
  call   <atol@plt>
  mov    $0x121,%edi
  mov    %eax,%esi
  call   <syscall@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L11
L29:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  xor    %eax,%eax
  call   <usage@plt>
  jmp    L24
L11:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L29
```

tool_calls: name: retrieve_data
arguments: label: D19
type: string
name: retrieve_data
arguments: label: D0
type: string

tool: D19: Zombify sucessful.


tool: D0: Zombify: An error occured.


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    usage();
  }
  pid_t target = atol(argv[1]);
  long ret_val = syscall(289, target);
  if (ret_val == -1) {
    printf("Zombify: An error occured.\n");
    exit(-1);
  }
  printf("Zombify sucessful.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<brk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isAlphanumeric@plt>
  test   %eax,%eax
  jne    L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L33
L25:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L32
  mov    $0x0,%eax
L33:
  leave
  ret
```

assistant: ```c
char *brk(char *s1) {
  int i;
  for (i = 0; i < strlen(s1); i++) {
    if (!isAlphanumeric(s1[i])) {
      return s1 + i;
    }
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<brk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L26:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L11
  lea    0x0(%rbp,%rbx,1),%r12
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isAlphanumeric@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  jne    L26
  jmp    L3
L11:
  mov    $0x0,%r12d
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *brk(char *s1) {
  int i;
  for (i = 0; i < strlen(s1); i++) {
    if (!isAlphanumeric(s1[i])) {
      return s1 + i;
    }
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<brk>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L0
  nop
L28:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%rbp,%rbx,1),%r12
  add    $0x1,%rbx
  call   <isAlphanumeric@plt>
  test   %eax,%eax
  je     L24
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L28
  xor    %r12d,%r12d
L24:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *brk(char *s1) {
  int i;
  for (i = 0; i < strlen(s1); i++) {
    if (!isAlphanumeric(s1[i])) {
      return s1 + i;
    }
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<brk>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L27
  nop
L9:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%rbp,%rbx,1),%r12
  add    $0x1,%rbx
  call   <isAlphanumeric@plt>
  test   %eax,%eax
  je     L0
L27:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  xor    %r12d,%r12d
L0:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *brk(char *s1) {
  int i;
  for (i = 0; i < strlen(s1); i++) {
    if (!isAlphanumeric(s1[i])) {
      return s1 + i;
    }
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ijs_strnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L36:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x4(%rbp),%eax
  jmp    L23
L33:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L36
  mov    -0x1c(%rbp),%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int ijs_strnlen(const char *s, int size) {
  int i;
  for (i = 0; i < size; i++)
    if (s[i] == 0)
      return i;
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ijs_strnlen>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L18
  mov    %esi,%r8d
  mov    $0x0,%edx
L12:
  cmpb   $0x0,(%rdi,%rdx,1)
  je     L28
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L12
  ret
L28:
  mov    %edx,%eax
L18:
  ret
```

assistant: ```c
int ijs_strnlen(const char *s, int size) {
  int i;
  for (i = 0; i < size; i++)
    if (s[i] == 0)
      return i;
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ijs_strnlen>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L28
  movslq %esi,%rcx
  xor    %edx,%edx
  jmp    L36
  nopl   0x0(%rax)
L37:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L3
L36:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L37
  mov    %edx,%eax
L28:
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
int ijs_strnlen(const char *s, int size) {
  int i;
  for (i = 0; i < size; i++)
    if (s[i] == 0)
      return i;
  return size;
}
```
user: What is the c source code of the assembly code below?

```asm
<ijs_strnlen>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L17
  movslq %esi,%rcx
  xor    %edx,%edx
  jmp    L1
  nopl   0x0(%rax)
L35:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L0
L1:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L35
  mov    %edx,%eax
L17:
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
int ijs_strnlen(const char *s, int size) {
  int i;
  for (i = 0; i < size; i++)
    if (s[i] == 0)
      return i;
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <task_name1@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <task_name2@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type: string
name: unpack_data
arguments: label: D10
type: string

tool: D9: foo

tool: D10: bar

assistant: ```c
int main(int argc, char *argv[]) {
  task_name1("foo");
  task_name2("bar");
  return 0;
}
```