ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Controls_Cache>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D27
type: string
name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D14
type: string

tool: D17: menu/art_blueish/back_0

tool: D27: menu/art_blueish/back_1

tool: D11: menu/art_blueish/frame2_l

tool: D14: menu/art_blueish/frame1_r

assistant: ```c
void Controls_Cache(void) {
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/back_0");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/back_1");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/frame2_l");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/frame1_r");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Controls_Cache>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D28(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D27(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D10(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
datatype: string
name: read_data
arguments: data_label: D28
datatype: string
name: read_data
arguments: data_label: D27
datatype: string
name: read_data
arguments: data_label: D10
datatype: string

tool: D13: menu/art_blueish/back_0

tool: D28: menu/art_blueish/back_1

tool: D27: menu/art_blueish/frame2_l

tool: D10: menu/art_blueish/frame1_r

assistant: ```c
void Controls_Cache(void) {
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/back_0");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/back_1");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/frame2_l");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/frame1_r");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Controls_Cache>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D27(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D1(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <trap_R_RegisterShaderNoMip@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
type_guessed: string
name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D21: menu/art_blueish/back_0

tool: D27: menu/art_blueish/back_1

tool: D1: menu/art_blueish/frame2_l

tool: D5: menu/art_blueish/frame1_r

assistant: ```c
void Controls_Cache(void) {
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/back_0");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/back_1");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/frame2_l");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/frame1_r");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Controls_Cache>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D8(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D33(%rip),%rdi
  call   <trap_R_RegisterShaderNoMip@plt>
  lea    D30(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <trap_R_RegisterShaderNoMip@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
type_infered: string
name: disassemble_data
arguments: label: D8
type_infered: string
name: disassemble_data
arguments: label: D33
type_infered: string
name: disassemble_data
arguments: label: D30
type_infered: string

tool: D14: menu/art_blueish/back_0

tool: D8: menu/art_blueish/back_1

tool: D33: menu/art_blueish/frame2_l

tool: D30: menu/art_blueish/frame1_r

assistant: ```c
void Controls_Cache(void) {
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/back_0");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/back_1");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/frame2_l");
  trap_R_RegisterShaderNoMip("menu/"
                             "art_blueish"
                             "/frame1_r");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reset_scs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sane_cs@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <do_scs@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int reset_scs(int g) {
  int n = sane_cs(g);
  do_scs(n);
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reset_scs>:
  endbr64
  push   %rbx
  call   <sane_cs@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <do_scs@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int reset_scs(int g) {
  int n = sane_cs(g);
  do_scs(n);
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reset_scs>:
  endbr64
  push   %r12
  call   <sane_cs@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <do_scs@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int reset_scs(int g) {
  int n = sane_cs(g);
  do_scs(n);
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reset_scs>:
  endbr64
  push   %r12
  call   <sane_cs@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <do_scs@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int reset_scs(int g) {
  int n = sane_cs(g);
  do_scs(n);
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<caesar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L2
L1:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *caesar(char *inString, int n) {
  int i = 0;
  char *outString = (char *)malloc(strlen(inString) + 1);
  while (inString[i] != '\0') {
    outString[i] = inString[i] + n;
    i++;
  }
  outString[i] = '\0';
  return outString;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<caesar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L24
  mov    $0x1,%ecx
L20:
  add    %ebp,%edx
  mov    %dl,-0x1(%rax,%rcx,1)
  mov    %rcx,%rsi
  add    $0x1,%rcx
  movzbl -0x1(%rbx,%rcx,1),%edx
  test   %dl,%dl
  jne    L20
L4:
  movb   $0x0,(%rax,%rsi,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    $0x0,%esi
  jmp    L4
```

assistant: ```c
char *caesar(char *inString, int n) {
  int i = 0;
  char *outString = (char *)malloc(strlen(inString) + 1);
  while (inString[i] != '\0') {
    outString[i] = inString[i] + n;
    i++;
  }
  outString[i] = '\0';
  return outString;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<caesar>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L4
  mov    %ebp,%edi
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L2:
  add    %edi,%edx
  mov    %rcx,%rsi
  mov    %dl,-0x1(%rax,%rcx,1)
  add    $0x1,%rcx
  movzbl -0x1(%rbx,%rcx,1),%edx
  test   %dl,%dl
  jne    L2
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *caesar(char *inString, int n) {
  int i = 0;
  char *outString = (char *)malloc(strlen(inString) + 1);
  while (inString[i] != '\0') {
    outString[i] = inString[i] + n;
    i++;
  }
  outString[i] = '\0';
  return outString;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<caesar>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L17
  mov    %ebp,%edi
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L12:
  add    %edi,%edx
  mov    %rcx,%rsi
  mov    %dl,-0x1(%rax,%rcx,1)
  add    $0x1,%rcx
  movzbl -0x1(%rbx,%rcx,1),%edx
  test   %dl,%dl
  jne    L12
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *caesar(char *inString, int n) {
  int i = 0;
  char *outString = (char *)malloc(strlen(inString) + 1);
  while (inString[i] != '\0') {
    outString[i] = inString[i] + n;
    i++;
  }
  outString[i] = '\0';
  return outString;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getBytesInt64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x7,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getBytesInt64(unsigned long i, char *out) {
  unsigned char *ia = (unsigned char *)&i;
  out[0] = ia[0];
  out[1] = ia[1];
  out[2] = ia[2];
  out[3] = ia[3];
  out[4] = ia[4];
  out[5] = ia[5];
  out[6] = ia[6];
  out[7] = ia[7];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getBytesInt64>:
  endbr64
  mov    %rdi,%rax
  mov    %dil,(%rsi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rsi)
  mov    %rdi,%rdx
  shr    $0x10,%rdx
  mov    %dl,0x2(%rsi)
  mov    %rdi,%rdx
  shr    $0x18,%rdx
  mov    %dl,0x3(%rsi)
  mov    %rdi,%rdx
  shr    $0x20,%rdx
  mov    %dl,0x4(%rsi)
  mov    %rdi,%rdx
  shr    $0x28,%rdx
  mov    %dl,0x5(%rsi)
  mov    %rdi,%rdx
  shr    $0x30,%rdx
  mov    %dl,0x6(%rsi)
  shr    $0x38,%rax
  mov    %al,0x7(%rsi)
  ret
```

assistant: ```c
void getBytesInt64(unsigned long i, char *out) {
  unsigned char *ia = (unsigned char *)&i;
  out[0] = ia[0];
  out[1] = ia[1];
  out[2] = ia[2];
  out[3] = ia[3];
  out[4] = ia[4];
  out[5] = ia[5];
  out[6] = ia[6];
  out[7] = ia[7];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getBytesInt64>:
  endbr64
  mov    %rdi,(%rsi)
  ret
```

assistant: ```c
void getBytesInt64(unsigned long i, char *out) {
  unsigned char *ia = (unsigned char *)&i;
  out[0] = ia[0];
  out[1] = ia[1];
  out[2] = ia[2];
  out[3] = ia[3];
  out[4] = ia[4];
  out[5] = ia[5];
  out[6] = ia[6];
  out[7] = ia[7];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getBytesInt64>:
  endbr64
  mov    %rdi,(%rsi)
  ret
```

assistant: ```c
void getBytesInt64(unsigned long i, char *out) {
  unsigned char *ia = (unsigned char *)&i;
  out[0] = ia[0];
  out[1] = ia[1];
  out[2] = ia[2];
  out[3] = ia[3];
  out[4] = ia[4];
  out[5] = ia[5];
  out[6] = ia[6];
  out[7] = ia[7];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PopCharPixel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *PopCharPixel(const unsigned char pixel, unsigned char *pixels) {
  *pixels++ = (unsigned char)(pixel);
  return (pixels);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PopCharPixel>:
  endbr64
  mov    %dil,(%rsi)
  lea    0x1(%rsi),%rax
  ret
```

assistant: ```c
unsigned char *PopCharPixel(const unsigned char pixel, unsigned char *pixels) {
  *pixels++ = (unsigned char)(pixel);
  return (pixels);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PopCharPixel>:
  endbr64
  mov    %dil,(%rsi)
  lea    0x1(%rsi),%rax
  ret
```

assistant: ```c
unsigned char *PopCharPixel(const unsigned char pixel, unsigned char *pixels) {
  *pixels++ = (unsigned char)(pixel);
  return (pixels);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PopCharPixel>:
  endbr64
  mov    %dil,(%rsi)
  lea    0x1(%rsi),%rax
  ret
```

assistant: ```c
unsigned char *PopCharPixel(const unsigned char pixel, unsigned char *pixels) {
  *pixels++ = (unsigned char)(pixel);
  return (pixels);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_rev_or_not>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <str_rev@plt>
  jmp    L18
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <str_rev@plt>
L18:
  nop
  leave
  ret
```

assistant: ```c
void _rev_or_not(char *s) {
  if (s[0] == '-') {
    str_rev(&s[1]);
  } else {
    str_rev(s);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_rev_or_not>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x2d,(%rdi)
  je     L6
  call   <str_rev@plt>
L5:
  add    $0x8,%rsp
  ret
L6:
  add    $0x1,%rdi
  call   <str_rev@plt>
  jmp    L5
```

assistant: ```c
void _rev_or_not(char *s) {
  if (s[0] == '-') {
    str_rev(&s[1]);
  } else {
    str_rev(s);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_rev_or_not>:
  endbr64
  cmpb   $0x2d,(%rdi)
  je     L9
  jmp    1050 <str_rev@plt>
  xchg   %ax,%ax
L9:
  add    $0x1,%rdi
  jmp    1050 <str_rev@plt>
```

assistant: ```c
void _rev_or_not(char *s) {
  if (s[0] == '-') {
    str_rev(&s[1]);
  } else {
    str_rev(s);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_rev_or_not>:
  endbr64
  cmpb   $0x2d,(%rdi)
  je     L9
  jmp    1050 <str_rev@plt>
  xchg   %ax,%ax
L9:
  add    $0x1,%rdi
  jmp    1050 <str_rev@plt>
```

assistant: ```c
void _rev_or_not(char *s) {
  if (s[0] == '-') {
    str_rev(&s[1]);
  } else {
    str_rev(s);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L3
L6:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x79(%rbp)
  mov    -0x74(%rbp),%eax
  sub    -0x78(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x74(%rbp),%eax
  sub    -0x78(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x79(%rbp),%edx
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x78(%rbp)
L3:
  mov    -0x74(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x78(%rbp)
  jl     L6
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D6
type: string

tool: D17: Enter string you want to see reversed: 

tool: D14: %99[^
]

tool: D6: Reversed String: %s


assistant: ```c
int main(void) {
  char chArr[100];
  char temp;
  int n;
  printf("Enter string you want to see reversed: ");
  scanf("%99[^\n]", chArr);
  n = strlen(chArr);
  for (int i = 0; i < n / 2; i++) {
    temp = chArr[i];
    chArr[i] = chArr[n - i - 1];
    chArr[n - i - 1] = temp;
  }
  printf("Reversed String: %s\n", chArr);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L8
  mov    %rsp,%rdx
  cltq
  add    %rbx,%rax
  mov    $0x0,%ecx
L29:
  movzbl (%rdx),%esi
  movzbl -0x1(%rax),%edi
  mov    %dil,(%rdx)
  mov    %sil,-0x1(%rax)
  add    $0x1,%ecx
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %r8d,%ecx
  jl     L29
L8:
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D11
datatype: string
name: parse_data
arguments: label: D20
datatype: string
name: parse_data
arguments: label: D14
datatype: string

tool: D11: Enter string you want to see reversed: 

tool: D20: %99[^
]

tool: D14: Reversed String: %s


assistant: ```c
int main(void) {
  char chArr[100];
  char temp;
  int n;
  printf("Enter string you want to see reversed: ");
  scanf("%99[^\n]", chArr);
  n = strlen(chArr);
  for (int i = 0; i < n / 2; i++) {
    temp = chArr[i];
    chArr[i] = chArr[n - i - 1];
    chArr[n - i - 1] = temp;
  }
  printf("Reversed String: %s\n", chArr);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L15
  cltq
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  add    %rbp,%rax
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl (%rdx),%esi
  movzbl -0x1(%rax),%edi
  add    $0x1,%ecx
  add    $0x1,%rdx
  sub    $0x1,%rax
  mov    %dil,-0x1(%rdx)
  mov    %sil,(%rax)
  cmp    %r8d,%ecx
  jl     L4
L15:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type_infered: string
name: unpack_data
arguments: data_tag: D23
type_infered: string
name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D10: Enter string you want to see reversed: 

tool: D23: %99[^
]

tool: D0: Reversed String: %s


assistant: ```c
int main(void) {
  char chArr[100];
  char temp;
  int n;
  printf("Enter string you want to see reversed: ");
  scanf("%99[^\n]", chArr);
  n = strlen(chArr);
  for (int i = 0; i < n / 2; i++) {
    temp = chArr[i];
    chArr[i] = chArr[n - i - 1];
    chArr[n - i - 1] = temp;
  }
  printf("Reversed String: %s\n", chArr);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L11
  cltq
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  add    %rbp,%rax
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl (%rdx),%esi
  movzbl -0x1(%rax),%edi
  add    $0x1,%ecx
  add    $0x1,%rdx
  sub    $0x1,%rax
  mov    %dil,-0x1(%rdx)
  mov    %sil,(%rax)
  cmp    %r8d,%ecx
  jl     L21
L11:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string

tool: D26: Enter string you want to see reversed: 

tool: D24: %99[^
]

tool: D16: Reversed String: %s


assistant: ```c
int main(void) {
  char chArr[100];
  char temp;
  int n;
  printf("Enter string you want to see reversed: ");
  scanf("%99[^\n]", chArr);
  n = strlen(chArr);
  for (int i = 0; i < n / 2; i++) {
    temp = chArr[i];
    chArr[i] = chArr[n - i - 1];
    chArr[n - i - 1] = temp;
  }
  printf("Reversed String: %s\n", chArr);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alldigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L7
L1:
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L7
  mov    $0x0,%eax
  jmp    L0
L7:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int alldigits(char *s) {
  int ch;
  while ((ch = *s++) != '\0') {
    if (!isdigit(ch)) {
      return 0;
    }
  }
  return 1;
}
```