ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strchr>:
  endbr64
  nopl   0x0(%rax)
L13:
  movsbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  je     L15
  add    $0x1,%rdi
  cmp    %esi,%eax
  jne    L13
L15:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strchr(char *str, int c) {
  int i;
  i = -1;
  while (*(str + (++i)) && *(str + i) != c) {
  }
  return (str + i);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strchr>:
  endbr64
  nopl   0x0(%rax)
L4:
  movsbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  je     L18
  add    $0x1,%rdi
  cmp    %esi,%eax
  jne    L4
L18:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strchr(char *str, int c) {
  int i;
  i = -1;
  while (*(str + (++i)) && *(str + i) != c) {
  }
  return (str + i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<interpolateLinear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  movsd  -0x20(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x8(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  movss  D5(%rip),%xmm0
  subss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0xc(%rbp),%xmm0
  addss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: byte[4]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float interpolateLinear(float *data, double address, long arraysize) {
  long pos = (long)address;
  float posFract = (float)(address - (double)pos);
  return (data[pos] * (1.0f - posFract)) + (data[(pos + 1) % arraysize] * posFract);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interpolateLinear>:
  endbr64
  movapd %xmm0,%xmm1
  cvttsd2si %xmm0,%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rcx,%xmm0
  subsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  lea    0x1(%rcx),%rax
  cqto
  idiv   %rsi
  movaps %xmm1,%xmm0
  mulss  (%rdi,%rdx,4),%xmm0
  movss  D2(%rip),%xmm2
  subss  %xmm1,%xmm2
  mulss  (%rdi,%rcx,4),%xmm2
  addss  %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: byte[4]

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float interpolateLinear(float *data, double address, long arraysize) {
  long pos = (long)address;
  float posFract = (float)(address - (double)pos);
  return (data[pos] * (1.0f - posFract)) + (data[(pos + 1) % arraysize] * posFract);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interpolateLinear>:
  endbr64
  cvttsd2si %xmm0,%rcx
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  movss  D4(%rip),%xmm2
  cvtsi2sd %rcx,%xmm0
  lea    0x1(%rcx),%rax
  cqto
  idiv   %rsi
  subsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  subss  %xmm1,%xmm2
  mulss  (%rdi,%rcx,4),%xmm2
  movss  (%rdi,%rdx,4),%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float interpolateLinear(float *data, double address, long arraysize) {
  long pos = (long)address;
  float posFract = (float)(address - (double)pos);
  return (data[pos] * (1.0f - posFract)) + (data[(pos + 1) % arraysize] * posFract);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<interpolateLinear>:
  endbr64
  cvttsd2si %xmm0,%rcx
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  movss  D5(%rip),%xmm2
  cvtsi2sd %rcx,%xmm0
  lea    0x1(%rcx),%rax
  cqto
  idiv   %rsi
  subsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  subss  %xmm1,%xmm2
  mulss  (%rdi,%rcx,4),%xmm2
  movss  (%rdi,%rdx,4),%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: byte[4]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float interpolateLinear(float *data, double address, long arraysize) {
  long pos = (long)address;
  float posFract = (float)(address - (double)pos);
  return (data[pos] * (1.0f - posFract)) + (data[(pos + 1) % arraysize] * posFract);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_efene_path_from_env>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L4:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string

tool: D5: FNPATH

assistant: ```c
char *get_efene_path_from_env() {
  char *fnpath, *result;
  result = NULL;
  fnpath = getenv("FNPATH");
  if (fnpath != NULL) {
    result = strdup(fnpath);
    assert(result != NULL);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_efene_path_from_env>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
L3:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D3: FNPATH

assistant: ```c
char *get_efene_path_from_env() {
  char *fnpath, *result;
  result = NULL;
  fnpath = getenv("FNPATH");
  if (fnpath != NULL) {
    result = strdup(fnpath);
    assert(result != NULL);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_efene_path_from_env>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <strdup@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
L0:
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: FNPATH

assistant: ```c
char *get_efene_path_from_env() {
  char *fnpath, *result;
  result = NULL;
  fnpath = getenv("FNPATH");
  if (fnpath != NULL) {
    result = strdup(fnpath);
    assert(result != NULL);
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_efene_path_from_env>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  call   <strdup@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
L8:
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: FNPATH

assistant: ```c
char *get_efene_path_from_env() {
  char *fnpath, *result;
  result = NULL;
  fnpath = getenv("FNPATH");
  if (fnpath != NULL) {
    result = strdup(fnpath);
    assert(result != NULL);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <main_sub@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  struct class *model;
  model = main_sub();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <main_sub@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct class *model;
  model = main_sub();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <main_sub@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct class *model;
  model = main_sub();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <main_sub@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct class *model;
  model = main_sub();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sendFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x100,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L9:
  cmp    %rdx,%rsp
  je     L0
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L9
L0:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L35
L47:
  mov    -0x48(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x4c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <writeToClient@plt>
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L35:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  je     L47
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int sendFile(FILE *fp, int clientsd) {
  int buffSize = 256;
  int counter;
  char buff[buffSize + 1];
  int r;
  memset(buff, '\0', (buffSize + 1) * sizeof(char));
  r = buffSize;
  counter = 0;
  while (r == buffSize) {
    r = fread(buff, sizeof(char), buffSize, fp);
    counter += writeToClient(clientsd, buff);
    memset(buff, '\0', buffSize * sizeof(char));
  }
  return counter;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sendFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
L33:
  cmp    %rax,%rsp
  je     L36
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L33
L36:
  sub    $0x110,%rsp
  orq    $0x0,0x108(%rsp)
  mov    %rsp,%r12
  mov    $0x101,%edx
  mov    $0x0,%esi
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    $0x0,%r13d
L32:
  mov    %r14,%rcx
  mov    $0x100,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %eax,%ebx
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <writeToClient@plt>
  add    %eax,%r13d
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  cmp    $0x100,%ebx
  je     L32
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %r13d,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sendFile(FILE *fp, int clientsd) {
  int buffSize = 256;
  int counter;
  char buff[buffSize + 1];
  int r;
  memset(buff, '\0', (buffSize + 1) * sizeof(char));
  r = buffSize;
  counter = 0;
  while (r == buffSize) {
    r = fread(buff, sizeof(char), buffSize, fp);
    counter += writeToClient(clientsd, buff);
    memset(buff, '\0', buffSize * sizeof(char));
  }
  return counter;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sendFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L38
L31:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L31
L38:
  sub    $0x110,%rsp
  orq    $0x0,0x108(%rsp)
  mov    $0x101,%edx
  xor    %esi,%esi
  xor    %r13d,%r13d
  mov    %rsp,%rdi
  mov    %rsp,%r12
  call   <memset@plt>
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0x100,%edx
  mov    %r14,%rcx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %r12,%rsi
  mov    %r15d,%edi
  mov    %eax,%ebx
  call   <writeToClient@plt>
  xor    %esi,%esi
  mov    $0x100,%edx
  mov    %r12,%rdi
  add    %eax,%r13d
  call   <memset@plt>
  cmp    $0x100,%ebx
  je     L23
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  lea    -0x28(%rbp),%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sendFile(FILE *fp, int clientsd) {
  int buffSize = 256;
  int counter;
  char buff[buffSize + 1];
  int r;
  memset(buff, '\0', (buffSize + 1) * sizeof(char));
  r = buffSize;
  counter = 0;
  while (r == buffSize) {
    r = fread(buff, sizeof(char), buffSize, fp);
    counter += writeToClient(clientsd, buff);
    memset(buff, '\0', buffSize * sizeof(char));
  }
  return counter;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sendFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L16
L17:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L17
L16:
  sub    $0x110,%rsp
  orq    $0x0,0x108(%rsp)
  mov    $0x101,%edx
  xor    %esi,%esi
  xor    %r13d,%r13d
  mov    %rsp,%rdi
  mov    %rsp,%r12
  call   <memset@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0x100,%edx
  mov    %r14,%rcx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %r12,%rsi
  mov    %r15d,%edi
  mov    %eax,%ebx
  call   <writeToClient@plt>
  xor    %esi,%esi
  mov    $0x100,%edx
  mov    %r12,%rdi
  add    %eax,%r13d
  call   <memset@plt>
  cmp    $0x100,%ebx
  je     L26
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  lea    -0x28(%rbp),%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sendFile(FILE *fp, int clientsd) {
  int buffSize = 256;
  int counter;
  char buff[buffSize + 1];
  int r;
  memset(buff, '\0', (buffSize + 1) * sizeof(char));
  r = buffSize;
  counter = 0;
  while (r == buffSize) {
    r = fread(buff, sizeof(char), buffSize, fp);
    counter += writeToClient(clientsd, buff);
    memset(buff, '\0', buffSize * sizeof(char));
  }
  return counter;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stub_read_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stub_state_pre_print@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stub_state_post_print@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: %lld

assistant: ```c
int stub_read_int(int64_t value, void *data) {
  stub_state_pre_print(data);
  printf("%lld", (signed long long)value);
  stub_state_post_print(data);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stub_read_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <stub_state_pre_print@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <stub_state_post_print@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: %lld

assistant: ```c
int stub_read_int(int64_t value, void *data) {
  stub_state_pre_print(data);
  printf("%lld", (signed long long)value);
  stub_state_post_print(data);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stub_read_int>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <stub_state_pre_print@plt>
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stub_state_post_print@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0: %lld

assistant: ```c
int stub_read_int(int64_t value, void *data) {
  stub_state_pre_print(data);
  printf("%lld", (signed long long)value);
  stub_state_post_print(data);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stub_read_int>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <stub_state_pre_print@plt>
  mov    %r12,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stub_state_post_print@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: %lld

assistant: ```c
int stub_read_int(int64_t value, void *data) {
  stub_state_pre_print(data);
  printf("%lld", (signed long long)value);
  stub_state_post_print(data);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x23,%esi
  mov    $0x96,%edi
  call   <gcd@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x195,%esi
  mov    $0x402,%edi
  call   <gcd@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x195,%edx
  mov    $0x402,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x53,-0x8(%rbp)
  movl   $0xf0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D11: The GCD of 150 and 35 is %i


tool: D2: The GCD of %i and %i is %i


assistant: ```c
int main(void) {
  int result, u, v;
  result = gcd(150, 35);
  printf("The GCD of 150 and 35 is %i\n", result);
  result = gcd(1026, 405);
  printf("The GCD of %i and %i is %i\n", 1026, 405, result);
  u = 83;
  v = 240;
  printf("The GCD of %i and %i is %i\n", u, v, gcd(u, v));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x23,%esi
  mov    $0x96,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x195,%esi
  mov    $0x402,%edi
  call   <gcd@plt>
  mov    %eax,%ecx
  mov    $0x195,%edx
  mov    $0x402,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xf0,%esi
  mov    $0x53,%edi
  call   <gcd@plt>
  mov    %eax,%ecx
  mov    $0xf0,%edx
  mov    $0x53,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D3: The GCD of 150 and 35 is %i


tool: D7: The GCD of %i and %i is %i


assistant: ```c
int main(void) {
  int result, u, v;
  result = gcd(150, 35);
  printf("The GCD of 150 and 35 is %i\n", result);
  result = gcd(1026, 405);
  printf("The GCD of %i and %i is %i\n", 1026, 405, result);
  u = 83;
  v = 240;
  printf("The GCD of %i and %i is %i\n", u, v, gcd(u, v));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x23,%esi
  mov    $0x96,%edi
  lea    D18(%rip),%rbp
  call   <gcd@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x195,%esi
  mov    $0x402,%edi
  call   <gcd@plt>
  mov    $0x195,%edx
  mov    %rbp,%rdi
  mov    $0x402,%esi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xf0,%esi
  mov    $0x53,%edi
  call   <gcd@plt>
  mov    %rbp,%rdi
  mov    $0xf0,%edx
  mov    $0x53,%esi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D18: The GCD of %i and %i is %i


tool: D0: The GCD of 150 and 35 is %i


assistant: ```c
int main(void) {
  int result, u, v;
  result = gcd(150, 35);
  printf("The GCD of 150 and 35 is %i\n", result);
  result = gcd(1026, 405);
  printf("The GCD of %i and %i is %i\n", 1026, 405, result);
  u = 83;
  v = 240;
  printf("The GCD of %i and %i is %i\n", u, v, gcd(u, v));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x23,%esi
  mov    $0x96,%edi
  lea    D4(%rip),%rbp
  call   <gcd@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x195,%esi
  mov    $0x402,%edi
  call   <gcd@plt>
  mov    $0x195,%edx
  mov    %rbp,%rdi
  mov    $0x402,%esi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xf0,%esi
  mov    $0x53,%edi
  call   <gcd@plt>
  mov    %rbp,%rdi
  mov    $0xf0,%edx
  mov    $0x53,%esi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D0
type: string

tool: D4: The GCD of %i and %i is %i


tool: D0: The GCD of 150 and 35 is %i


assistant: ```c
int main(void) {
  int result, u, v;
  result = gcd(150, 35);
  printf("The GCD of 150 and 35 is %i\n", result);
  result = gcd(1026, 405);
  printf("The GCD of %i and %i is %i\n", 1026, 405, result);
  u = 83;
  v = 240;
  printf("The GCD of %i and %i is %i\n", u, v, gcd(u, v));
  return 0;
}
```