user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rsi
  lea    D113(%rip),%rdi
  sub    $0xb0,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movdqa D45(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D93(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D22(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movdqa D112(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D90(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D0(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x80(%rsp)
  movdqa D19(%rip),%xmm0
  movaps %xmm0,0x90(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rbp
  mov    %rsp,%rdi
  mov    %rax,%rcx
  mov    $0x28,%edx
  mov    $0x4,%esi
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L29:
  mov    0xa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0xb0,%rsp
  pop    %rbp
  ret
L15:
  lea    D119(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L29
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D49
type_infered: string
name: read_data
arguments: label: D113
type_infered: string
name: read_data
arguments: label: D9
type_infered: byte[16]
name: read_data
arguments: label: D45
type_infered: byte[16]
name: read_data
arguments: label: D93
type_infered: byte[16]
name: read_data
arguments: label: D22
type_infered: byte[16]
name: read_data
arguments: label: D112
type_infered: byte[16]
name: read_data
arguments: label: D90
type_infered: byte[16]
name: read_data
arguments: label: D0
type_infered: byte[16]
name: read_data
arguments: label: D7
type_infered: byte[16]
name: read_data
arguments: label: D19
type_infered: byte[16]
name: read_data
arguments: label: D119
type_infered: string

tool: D49: wb

tool: D113: ./5.lvl

tool: {"D9": [0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D45": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D93": [0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D22": [0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D112": [0x06,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D90": [0x06,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D0": [0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D7": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D19": [0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D119: Unable to open file!

assistant: ```c
int main() {
  int resist_array[8 * 5] = {
      5, 5, 5, 4, 4, 5, 5, 4, 4, 3, 5, 4, 4, 3, 3, 6, 4, 3, 3, 6, 6, 4, 3, 3, 6, 5, 4, 4, 3, 3, 5, 5, 4, 4, 3, 5, 5, 5, 4, 4,
  };
  FILE *pFile;
  pFile = fopen("./5.lvl", "wb");
  if (!pFile) {
    printf("Unable to open file!");
    return 1;
  }
  fwrite(resist_array, sizeof(int), 8 * 5, pFile);
  fclose(pFile);
  return 0;
}
```