ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  mov    %edx,%edi
  cmp    %dl,%cl
  je     L1
  test   %cl,%cl
  je     L1
  xor    %edx,%edx
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L30:
  test   %cl,%cl
  je     L38
L17:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  cmp    %dil,%cl
  jne    L30
L38:
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *my_strcpy(char *dest, const char *src, char c) {
  int i;
  i = 0;
  while (src[i] && (src[i] != c)) {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CopyTileBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L6
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%esi
  mov    %esi,%eax
  shl    $0x2,%eax
  add    %esi,%eax
  shl    $0x2,%eax
  mov    %ecx,%esi
  sub    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L12
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x18(%rbp)
  negl   -0xc(%rbp)
L12:
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L28:
  mov    -0x8(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  cmp    %edx,-0xc(%rbp)
  jl     L18
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  add    %ecx,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CopyTile@plt>
L18:
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L28
  nop
  nop
  leave
  ret
```

assistant: ```c
void CopyTileBlock(int sourcefirst, int sourcelast, int destfirst) {
  if (sourcelast < sourcefirst) {
    int swap = sourcefirst;
    sourcefirst = sourcelast;
    sourcelast = swap;
  }
  int w = sourcelast % 20 - sourcefirst % 20;
  if (w < 0) {
    sourcefirst -= w;
    sourcelast += w;
    w = -w;
  }
  for (int i = 0; i <= sourcelast - sourcefirst; i++)
    if (i % 20 <= w)
      CopyTile(sourcefirst + i, destfirst + i);
}
```
user: What is the c source code of the assembly code below:

```asm
<CopyTileBlock>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%r14d
  cmp    %edi,%esi
  jge    L52
  mov    %esi,%r12d
  mov    %edi,%ebp
L52:
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  shl    $0x2,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  movslq %r12d,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %r12d,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  shl    $0x2,%ecx
  mov    %r12d,%edx
  sub    %ecx,%edx
  mov    %eax,%r13d
  sub    %edx,%r13d
  js     L38
L49:
  sub    %r12d,%ebp
  js     L10
  mov    $0x0,%ebx
  jmp    L75
L38:
  sub    %r13d,%r12d
  add    %r13d,%ebp
  sub    %eax,%edx
  mov    %edx,%r13d
  jmp    L49
L64:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jg     L10
L75:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  mov    %ebx,%edx
  sub    %eax,%edx
  cmp    %r13d,%edx
  jg     L64
  lea    (%r14,%rbx,1),%esi
  lea    (%r12,%rbx,1),%edi
  call   <CopyTile@plt>
  jmp    L64
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void CopyTileBlock(int sourcefirst, int sourcelast, int destfirst) {
  if (sourcelast < sourcefirst) {
    int swap = sourcefirst;
    sourcefirst = sourcelast;
    sourcelast = swap;
  }
  int w = sourcelast % 20 - sourcefirst % 20;
  if (w < 0) {
    sourcefirst -= w;
    sourcelast += w;
    w = -w;
  }
  for (int i = 0; i <= sourcelast - sourcefirst; i++)
    if (i % 20 <= w)
      CopyTile(sourcefirst + i, destfirst + i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CopyTileBlock>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edi,%esi
  jge    L17
  mov    %esi,%r13d
  mov    %edi,%r12d
L17:
  movslq %r12d,%rax
  mov    %r12d,%edx
  mov    %r13d,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x1f,%ecx
  sar    $0x23,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %r12d,%eax
  shl    $0x2,%edx
  sub    %edx,%eax
  movslq %r13d,%rdx
  imul   $0x66666667,%rdx,%rdx
  mov    %eax,%r14d
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  mov    %r13d,%edx
  shl    $0x2,%ecx
  sub    %ecx,%edx
  sub    %edx,%r14d
  jns    L18
  sub    %eax,%edx
  sub    %r14d,%r13d
  add    %r14d,%r12d
  mov    %edx,%r14d
L18:
  sub    %r13d,%r12d
  js     L46
  xor    %ebx,%ebx
  mov    $0xcccccccd,%r15d
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jg     L46
L2:
  mov    %ebx,%eax
  mov    %ebx,%edx
  imul   %r15,%rax
  shr    $0x24,%rax
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  cmp    %r14d,%edx
  jg     L42
  lea    0x0(%rbp,%rbx,1),%esi
  lea    0x0(%r13,%rbx,1),%edi
  add    $0x1,%ebx
  call   <CopyTile@plt>
  cmp    %r12d,%ebx
  jle    L2
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void CopyTileBlock(int sourcefirst, int sourcelast, int destfirst) {
  if (sourcelast < sourcefirst) {
    int swap = sourcefirst;
    sourcefirst = sourcelast;
    sourcelast = swap;
  }
  int w = sourcelast % 20 - sourcefirst % 20;
  if (w < 0) {
    sourcefirst -= w;
    sourcelast += w;
    w = -w;
  }
  for (int i = 0; i <= sourcelast - sourcefirst; i++)
    if (i % 20 <= w)
      CopyTile(sourcefirst + i, destfirst + i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<CopyTileBlock>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edi,%esi
  jge    L60
  mov    %esi,%r13d
  mov    %edi,%r12d
L60:
  movslq %r12d,%rax
  mov    %r12d,%edx
  mov    %r13d,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x1f,%ecx
  sar    $0x23,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %r12d,%eax
  shl    $0x2,%edx
  sub    %edx,%eax
  movslq %r13d,%rdx
  imul   $0x66666667,%rdx,%rdx
  mov    %eax,%r14d
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  mov    %r13d,%edx
  shl    $0x2,%ecx
  sub    %ecx,%edx
  sub    %edx,%r14d
  jns    L17
  sub    %eax,%edx
  sub    %r14d,%r13d
  add    %r14d,%r12d
  mov    %edx,%r14d
L17:
  sub    %r13d,%r12d
  js     L25
  xor    %ebx,%ebx
  mov    $0xcccccccd,%r15d
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jg     L25
L55:
  mov    %ebx,%eax
  mov    %ebx,%edx
  imul   %r15,%rax
  shr    $0x24,%rax
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  cmp    %r14d,%edx
  jg     L14
  lea    0x0(%rbp,%rbx,1),%esi
  lea    0x0(%r13,%rbx,1),%edi
  add    $0x1,%ebx
  call   <CopyTile@plt>
  cmp    %r12d,%ebx
  jle    L55
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void CopyTileBlock(int sourcefirst, int sourcelast, int destfirst) {
  if (sourcelast < sourcefirst) {
    int swap = sourcefirst;
    sourcefirst = sourcelast;
    sourcelast = swap;
  }
  int w = sourcelast % 20 - sourcefirst % 20;
  if (w < 0) {
    sourcefirst -= w;
    sourcelast += w;
    w = -w;
  }
  for (int i = 0; i <= sourcelast - sourcefirst; i++)
    if (i % 20 <= w)
      CopyTile(sourcefirst + i, destfirst + i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_signature>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <readb@plt>
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  cmp    %dl,%al
  jne    L20
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L14
  movl   $0x1,-0x4(%rbp)
  jmp    L17
L20:
  nop
L17:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int check_signature(volatile void *io_addr, const unsigned char *signature, int length) {
  int retval = 0;
  do {
    if (readb(io_addr) != *signature)
      goto out;
    io_addr++;
    signature++;
    length--;
  } while (length);
  retval = 1;
out:
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_signature>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%r12
L27:
  mov    %rbx,%rdi
  call   <readb@plt>
  cmp    0x0(%rbp),%al
  jne    L8
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  jne    L27
  mov    $0x1,%eax
  jmp    L0
L8:
  mov    $0x0,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int check_signature(volatile void *io_addr, const unsigned char *signature, int length) {
  int retval = 0;
  do {
    if (readb(io_addr) != *signature)
      goto out;
    io_addr++;
    signature++;
    length--;
  } while (length);
  retval = 1;
out:
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_signature>:
  endbr64
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  je     L15
L2:
  mov    %rbx,%rdi
  call   <readb@plt>
  cmp    0x0(%rbp),%al
  je     L17
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int check_signature(volatile void *io_addr, const unsigned char *signature, int length) {
  int retval = 0;
  do {
    if (readb(io_addr) != *signature)
      goto out;
    io_addr++;
    signature++;
    length--;
  } while (length);
  retval = 1;
out:
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_signature>:
  endbr64
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  je     L5
L2:
  mov    %rbx,%rdi
  call   <readb@plt>
  cmp    0x0(%rbp),%al
  je     L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int check_signature(volatile void *io_addr, const unsigned char *signature, int length) {
  int retval = 0;
  do {
    if (readb(io_addr) != *signature)
      goto out;
    io_addr++;
    signature++;
    length--;
  } while (length);
  retval = 1;
out:
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CriticalPart3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  movq   %xmm0,%r12
  movsd  %xmm3,0x8(%rsp)
  subsd  %xmm1,%xmm2
  movsd  %xmm2,(%rsp)
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L34
  movapd %xmm2,%xmm4
  sqrtsd %xmm4,%xmm4
  movapd %xmm4,%xmm0
L9:
  movsd  0x8(%rsp),%xmm5
  mulsd  %xmm5,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm5,%xmm5
  movq   %xmm5,%rbp
  movq   %r12,%xmm0
  call   <log@plt>
  cmp    $0x1,%ebx
  je     L47
  cmp    $0x2,%ebx
  jne    L22
  movq   %rbp,%xmm1
  mulsd  D6(%rip),%xmm1
  mulsd  (%rsp),%xmm1
  movapd %xmm0,%xmm2
  xorpd  D11(%rip),%xmm2
  subsd  %xmm1,%xmm2
  movsd  0x8(%rsp),%xmm6
  divsd  %xmm6,%xmm2
  movq   %xmm2,%rbx
  subsd  %xmm0,%xmm1
  divsd  %xmm6,%xmm1
  movapd %xmm1,%xmm0
  mov    $0x1,%eax
  call   <cnd@plt>
  mov    %eax,%ebp
  movq   %rbx,%xmm0
  mov    $0x1,%eax
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movq   %r12,%xmm7
  mulsd  %xmm7,%xmm1
  subsd  %xmm1,%xmm0
L14:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  movsd  (%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L9
L47:
  movq   %rbp,%xmm1
  mulsd  D6(%rip),%xmm1
  mulsd  (%rsp),%xmm1
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  movsd  0x8(%rsp),%xmm3
  divsd  %xmm3,%xmm2
  movq   %xmm2,%rbp
  addsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  mov    $0x1,%eax
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %r12,%xmm7
  mulsd  %xmm0,%xmm7
  movq   %xmm7,%r12
  movq   %rbp,%xmm0
  mov    $0x1,%eax
  call   <cnd@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movq   %r12,%xmm0
  subsd  %xmm1,%xmm0
  jmp    L14
L22:
  call   <abort@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type: byte[8]
name: read_data
arguments: data_label: D11
type: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CriticalPart3(int id, double I, double t1, double T2, double v) {
  double result;
  double z1, z2;
  const double vT2_t1 = v * sqrt(T2 - t1);
  const double p2v = ((v) * (v));
  const double logI = log(I);
  if (id == 1) {
    z1 = (logI + p2v / 2.0 * (T2 - t1)) / vT2_t1;
    z2 = (logI - p2v / 2.0 * (T2 - t1)) / vT2_t1;
    result = I * cnd(z1) - cnd(z2);
  } else if (id == 2) {
    z1 = (-logI + ((v) * (v)) / 2.0 * (T2 - t1)) / vT2_t1;
    z2 = (-logI - ((v) * (v)) / 2.0 * (T2 - t1)) / vT2_t1;
    result = cnd(z1) - I * cnd(z2);
  } else
    abort();
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CriticalPart3>:
  endbr64
  push   %r14
  subsd  %xmm1,%xmm2
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L2
  movapd %xmm2,%xmm1
  sqrtsd %xmm1,%xmm1
L4:
  mulsd  %xmm3,%xmm1
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm2,0x18(%rsp)
  mulsd  %xmm3,%xmm3
  movsd  %xmm1,0x10(%rsp)
  movq   %xmm3,%r14
  call   <log@plt>
  cmp    $0x1,%ebx
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  je     L17
  cmp    $0x2,%ebx
  jne    10c0 <CriticalPart3.cold>
  movq   %r14,%xmm3
  mov    $0x1,%eax
  mulsd  D5(%rip),%xmm3
  mulsd  %xmm2,%xmm3
  movapd %xmm0,%xmm2
  xorpd  D10(%rip),%xmm2
  subsd  %xmm3,%xmm2
  subsd  %xmm0,%xmm3
  divsd  %xmm1,%xmm3
  divsd  %xmm1,%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <cnd@plt>
  movsd  0x10(%rsp),%xmm2
  mov    %eax,%ebx
  mov    $0x1,%eax
  movapd %xmm2,%xmm0
  call   <cnd@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm1
  mulsd  0x8(%rsp),%xmm1
  add    $0x28,%rsp
  cvtsi2sd %ebx,%xmm0
  pop    %rbx
  pop    %r14
  subsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movq   %r14,%xmm3
  mov    $0x1,%eax
  mulsd  D5(%rip),%xmm3
  mulsd  %xmm3,%xmm2
  movapd %xmm0,%xmm3
  subsd  %xmm2,%xmm3
  addsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm3
  divsd  %xmm1,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  movsd  0x10(%rsp),%xmm3
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  movq   %xmm0,%rbx
  movapd %xmm3,%xmm0
  call   <cnd@plt>
  pxor   %xmm1,%xmm1
  movq   %rbx,%xmm0
  add    $0x28,%rsp
  cvtsi2sd %eax,%xmm1
  pop    %rbx
  pop    %r14
  subsd  %xmm1,%xmm0
  ret
L2:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <sqrt@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: byte[8]
name: parse_data
arguments: data_label: D10
data_type: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CriticalPart3(int id, double I, double t1, double T2, double v) {
  double result;
  double z1, z2;
  const double vT2_t1 = v * sqrt(T2 - t1);
  const double p2v = ((v) * (v));
  const double logI = log(I);
  if (id == 1) {
    z1 = (logI + p2v / 2.0 * (T2 - t1)) / vT2_t1;
    z2 = (logI - p2v / 2.0 * (T2 - t1)) / vT2_t1;
    result = I * cnd(z1) - cnd(z2);
  } else if (id == 2) {
    z1 = (-logI + ((v) * (v)) / 2.0 * (T2 - t1)) / vT2_t1;
    z2 = (-logI - ((v) * (v)) / 2.0 * (T2 - t1)) / vT2_t1;
    result = cnd(z1) - I * cnd(z2);
  } else
    abort();
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CriticalPart3>:
  endbr64
  push   %r14
  subsd  %xmm1,%xmm2
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L27
  movapd %xmm2,%xmm1
  sqrtsd %xmm1,%xmm1
L23:
  mulsd  %xmm3,%xmm1
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm2,0x18(%rsp)
  mulsd  %xmm3,%xmm3
  movsd  %xmm1,0x10(%rsp)
  movq   %xmm3,%r14
  call   <log@plt>
  cmp    $0x1,%ebx
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  je     L8
  cmp    $0x2,%ebx
  jne    10c0 <CriticalPart3.cold>
  movq   %r14,%xmm3
  mov    $0x1,%eax
  mulsd  D27(%rip),%xmm3
  mulsd  %xmm2,%xmm3
  movapd %xmm0,%xmm2
  xorpd  D23(%rip),%xmm2
  subsd  %xmm3,%xmm2
  subsd  %xmm0,%xmm3
  divsd  %xmm1,%xmm3
  divsd  %xmm1,%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <cnd@plt>
  movsd  0x10(%rsp),%xmm2
  mov    %eax,%ebx
  mov    $0x1,%eax
  movapd %xmm2,%xmm0
  call   <cnd@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm1
  mulsd  0x8(%rsp),%xmm1
  add    $0x28,%rsp
  cvtsi2sd %ebx,%xmm0
  pop    %rbx
  pop    %r14
  subsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  movq   %r14,%xmm3
  mov    $0x1,%eax
  mulsd  D27(%rip),%xmm3
  mulsd  %xmm3,%xmm2
  movapd %xmm0,%xmm3
  subsd  %xmm2,%xmm3
  addsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm3
  divsd  %xmm1,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  movsd  0x10(%rsp),%xmm3
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  movq   %xmm0,%rbx
  movapd %xmm3,%xmm0
  call   <cnd@plt>
  pxor   %xmm1,%xmm1
  movq   %rbx,%xmm0
  add    $0x28,%rsp
  cvtsi2sd %eax,%xmm1
  pop    %rbx
  pop    %r14
  subsd  %xmm1,%xmm0
  ret
L27:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <sqrt@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L23
```

tool_calls: name: unpack_data
arguments: label: D27
type_infered: byte[8]
name: unpack_data
arguments: label: D23
type_infered: byte[16]

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CriticalPart3(int id, double I, double t1, double T2, double v) {
  double result;
  double z1, z2;
  const double vT2_t1 = v * sqrt(T2 - t1);
  const double p2v = ((v) * (v));
  const double logI = log(I);
  if (id == 1) {
    z1 = (logI + p2v / 2.0 * (T2 - t1)) / vT2_t1;
    z2 = (logI - p2v / 2.0 * (T2 - t1)) / vT2_t1;
    result = I * cnd(z1) - cnd(z2);
  } else if (id == 2) {
    z1 = (-logI + ((v) * (v)) / 2.0 * (T2 - t1)) / vT2_t1;
    z2 = (-logI - ((v) * (v)) / 2.0 * (T2 - t1)) / vT2_t1;
    result = cnd(z1) - I * cnd(z2);
  } else
    abort();
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fdatasync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <pthread_testcancel@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__libc_fdatasync@plt>
  leave
  ret
```

assistant: ```c
int fdatasync(int fd) {
  pthread_testcancel();
  return __libc_fdatasync(fd);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fdatasync>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <pthread_testcancel@plt>
  mov    %ebx,%edi
  call   <__libc_fdatasync@plt>
  pop    %rbx
  ret
```

assistant: ```c
int fdatasync(int fd) {
  pthread_testcancel();
  return __libc_fdatasync(fd);
}
```
user: What is the c source code of the assembly code below?

```asm
<fdatasync>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <pthread_testcancel@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <__libc_fdatasync@plt>
```

assistant: ```c
int fdatasync(int fd) {
  pthread_testcancel();
  return __libc_fdatasync(fd);
}
```
user: What is the c source code of the assembly code below:

```asm
<fdatasync>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <pthread_testcancel@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <__libc_fdatasync@plt>
```

assistant: ```c
int fdatasync(int fd) {
  pthread_testcancel();
  return __libc_fdatasync(fd);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0x8(%rbp)
  movl   $0x1e,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D11
type: string

tool: D4: ticket %d


tool: D11: %d X %d = %d


assistant: ```c
int main() {
  int shuzi = 3, jiage = 30;
  printf("ticket %d\n", shuzi * jiage);
  printf("%d X %d = %d\n", shuzi, jiage, shuzi * jiage);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5a,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5a,%ecx
  mov    $0x1e,%edx
  mov    $0x3,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string

tool: D10: ticket %d


tool: D18: %d X %d = %d


assistant: ```c
int main() {
  int shuzi = 3, jiage = 30;
  printf("ticket %d\n", shuzi * jiage);
  printf("%d X %d = %d\n", shuzi, jiage, shuzi * jiage);
  return 0;
}
```