ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dstStartDayOfYear>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x8,%rsp
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%ebx
L17:
  mov    %ebp,%edx
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <dayOfWeek@plt>
  mov    $0x3,%esi
  mov    %ebx,%edi
  mov    %rax,%rdx
  call   <isDst@plt>
  test   %eax,%eax
  je     L35
  mov    %ebp,%edx
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <dayOfWeek@plt>
  test   %rax,%rax
  jne    L1
L22:
  and    $0x3,%ebp
  mov    %ebx,%eax
  cmp    $0x1,%ebp
  adc    $0x3a,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L22
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: !!! BST START SHOULD BE A SUNDAY (%d) !!!


assistant: ```c
int dstStartDayOfYear(int year) {
  int daysToMarch = 31 + 28;
  int dayOfMarch;
  for (dayOfMarch = 20; !isDst(dayOfMarch, 3, dayOfWeek(dayOfMarch, 2, year)); dayOfMarch++)
    ;
  ;
  if (dayOfWeek(dayOfMarch, 2, year) != 0)
    printf("!!! BST START SHOULD BE A SUNDAY (%d) !!!\n", year);
  if (year % 4 == 0)
    daysToMarch++;
  return daysToMarch + dayOfMarch - 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dstStartDayOfYear>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x8,%rsp
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x1,%ebx
L35:
  mov    %ebp,%edx
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <dayOfWeek@plt>
  mov    $0x3,%esi
  mov    %ebx,%edi
  mov    %rax,%rdx
  call   <isDst@plt>
  test   %eax,%eax
  je     L31
  mov    %ebp,%edx
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <dayOfWeek@plt>
  test   %rax,%rax
  jne    L23
L2:
  and    $0x3,%ebp
  mov    %ebx,%eax
  cmp    $0x1,%ebp
  adc    $0x3a,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L23:
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: !!! BST START SHOULD BE A SUNDAY (%d) !!!


assistant: ```c
int dstStartDayOfYear(int year) {
  int daysToMarch = 31 + 28;
  int dayOfMarch;
  for (dayOfMarch = 20; !isDst(dayOfMarch, 3, dayOfWeek(dayOfMarch, 2, year)); dayOfMarch++)
    ;
  ;
  if (dayOfWeek(dayOfMarch, 2, year) != 0)
    printf("!!! BST START SHOULD BE A SUNDAY (%d) !!!\n", year);
  if (year % 4 == 0)
    daysToMarch++;
  return daysToMarch + dayOfMarch - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_laptop_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  jmp    L12
L13:
  nop
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D21
type: string

tool: D10: w

tool: D9: /proc/sys/vm/laptop_mode

tool: D21: 5


assistant: ```c
void set_laptop_mode(void) {
  FILE *file;
  file = fopen("/proc/sys/vm/laptop_mode", "w");
  if (!file)
    return;
  fprintf(file, "5\n");
  fclose(file);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_laptop_mode>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L7:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D9
type_infered: string
name: retrieve_data
arguments: data_label: D13
type_infered: string

tool: D3: w

tool: D9: /proc/sys/vm/laptop_mode

tool: D13: 5


assistant: ```c
void set_laptop_mode(void) {
  FILE *file;
  file = fopen("/proc/sys/vm/laptop_mode", "w");
  if (!file)
    return;
  fprintf(file, "5\n");
  fclose(file);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<set_laptop_mode>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rsi
  lea    D19(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbp
  mov    %rax,%rdi
  lea    D16(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string

tool: D13: w

tool: D19: /proc/sys/vm/laptop_mode

tool: D16: 5


assistant: ```c
void set_laptop_mode(void) {
  FILE *file;
  file = fopen("/proc/sys/vm/laptop_mode", "w");
  if (!file)
    return;
  fprintf(file, "5\n");
  fclose(file);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_laptop_mode>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rsi
  lea    D29(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  mov    %rax,%rdi
  lea    D15(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D15
type_guessed: string

tool: D28: w

tool: D29: /proc/sys/vm/laptop_mode

tool: D15: 5


assistant: ```c
void set_laptop_mode(void) {
  FILE *file;
  file = fopen("/proc/sys/vm/laptop_mode", "w");
  if (!file)
    return;
  fprintf(file, "5\n");
  fclose(file);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L11
L9:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L11:
  cmpl   $0x64,-0xc(%rbp)
  jle    L9
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string

tool: D28: Square is: %d


tool: D1: Sum is: %d


tool: D29: Difference is: %d


assistant: ```c
int main() {
  int i;
  int sum = 0;
  int square = 0;
  for (i = 1; i < 100 + 1; i++) {
    sum += i * i;
    square += i;
  }
  square *= square;
  printf("Square is: %d\n", square);
  printf("Sum is: %d\n", sum);
  printf("Difference is: %d\n", square - sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  mov    $0x1852324,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x529ae,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x17ff976,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D16: Square is: %d


tool: D14: Sum is: %d


tool: D7: Difference is: %d


assistant: ```c
int main() {
  int i;
  int sum = 0;
  int square = 0;
  for (i = 1; i < 100 + 1; i++) {
    sum += i * i;
    square += i;
  }
  square *= square;
  printf("Square is: %d\n", square);
  printf("Sum is: %d\n", sum);
  printf("Difference is: %d\n", square - sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1852324,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x529ae,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x17ff976,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D24
type_guessed: string
name: retrieve_data
arguments: tag: D11
type_guessed: string

tool: D4: Square is: %d


tool: D24: Sum is: %d


tool: D11: Difference is: %d


assistant: ```c
int main() {
  int i;
  int sum = 0;
  int square = 0;
  for (i = 1; i < 100 + 1; i++) {
    sum += i * i;
    square += i;
  }
  square *= square;
  printf("Square is: %d\n", square);
  printf("Sum is: %d\n", sum);
  printf("Difference is: %d\n", square - sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1852324,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x529ae,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x17ff976,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D29: Square is: %d


tool: D1: Sum is: %d


tool: D19: Difference is: %d


assistant: ```c
int main() {
  int i;
  int sum = 0;
  int square = 0;
  for (i = 1; i < 100 + 1; i++) {
    sum += i * i;
    square += i;
  }
  square *= square;
  printf("Square is: %d\n", square);
  printf("Sum is: %d\n", sum);
  printf("Difference is: %d\n", square - sum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<rgb24to15_C>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x44(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L0:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  shl    $0x2,%eax
  and    $0x3e0,%eax
  mov    %edx,%esi
  or     %eax,%esi
  mov    -0x1c(%rbp),%eax
  shl    $0x7,%eax
  and    $0x7c00,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %edx,(%rax)
L4:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rgb24to15_C(const uint8_t *src, uint8_t *dst, unsigned src_size) {
  const uint8_t *s = src;
  const uint8_t *end;
  uint16_t *d = (uint16_t *)dst;
  end = s + src_size;
  while (s < end) {
    const int b = *s++;
    const int g = *s++;
    const int r = *s++;
    *d++ = (b >> 3) | ((g & 0xF8) << 2) | ((r & 0xF8) << 7);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rgb24to15_C>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %rdi,%rcx
  jae    L16
L10:
  mov    (%rcx),%edx
  mov    0x4(%rcx),%eax
  add    $0xc,%rcx
  add    $0x4,%rsi
  shl    $0x2,%eax
  and    $0x3e0,%eax
  sar    $0x3,%edx
  or     %edx,%eax
  mov    -0x4(%rcx),%edx
  shl    $0x7,%edx
  and    $0x7c00,%edx
  or     %edx,%eax
  mov    %eax,-0x4(%rsi)
  cmp    %rdi,%rcx
  jb     L10
L16:
  ret
```

assistant: ```c
void rgb24to15_C(const uint8_t *src, uint8_t *dst, unsigned src_size) {
  const uint8_t *s = src;
  const uint8_t *end;
  uint16_t *d = (uint16_t *)dst;
  end = s + src_size;
  while (s < end) {
    const int b = *s++;
    const int g = *s++;
    const int r = *s++;
    *d++ = (b >> 3) | ((g & 0xF8) << 2) | ((r & 0xF8) << 7);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rgb24to15_C>:
  endbr64
  mov    %edx,%edx
  mov    %rdi,%rcx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %rdi,%rcx
  jae    L13
  nopw   0x0(%rax,%rax,1)
L17:
  mov    0x4(%rcx),%eax
  mov    (%rcx),%edx
  add    $0xc,%rcx
  add    $0x4,%rsi
  shl    $0x2,%eax
  sar    $0x3,%edx
  and    $0x3e0,%eax
  or     %edx,%eax
  mov    -0x4(%rcx),%edx
  shl    $0x7,%edx
  and    $0x7c00,%edx
  or     %edx,%eax
  mov    %eax,-0x4(%rsi)
  cmp    %rcx,%rdi
  ja     L17
L13:
  ret
```

assistant: ```c
void rgb24to15_C(const uint8_t *src, uint8_t *dst, unsigned src_size) {
  const uint8_t *s = src;
  const uint8_t *end;
  uint16_t *d = (uint16_t *)dst;
  end = s + src_size;
  while (s < end) {
    const int b = *s++;
    const int g = *s++;
    const int r = *s++;
    *d++ = (b >> 3) | ((g & 0xF8) << 2) | ((r & 0xF8) << 7);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rgb24to15_C>:
  endbr64
  mov    %edx,%edx
  mov    %rdi,%rcx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %rdi,%rcx
  jae    L4
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x4(%rcx),%eax
  mov    (%rcx),%edx
  add    $0xc,%rcx
  add    $0x4,%rsi
  shl    $0x2,%eax
  sar    $0x3,%edx
  and    $0x3e0,%eax
  or     %edx,%eax
  mov    -0x4(%rcx),%edx
  shl    $0x7,%edx
  and    $0x7c00,%edx
  or     %edx,%eax
  mov    %eax,-0x4(%rsi)
  cmp    %rcx,%rdi
  ja     L1
L4:
  ret
```

assistant: ```c
void rgb24to15_C(const uint8_t *src, uint8_t *dst, unsigned src_size) {
  const uint8_t *s = src;
  const uint8_t *end;
  uint16_t *d = (uint16_t *)dst;
  end = s + src_size;
  while (s < end) {
    const int b = *s++;
    const int g = *s++;
    const int r = *s++;
    *d++ = (b >> 3) | ((g & 0xF8) << 2) | ((r & 0xF8) << 7);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<unknown_nat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <unknown_function@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L9
  mov    -0x8(%rbp),%rax
  jmp    L18
L9:
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
uint32_t unknown_nat() {
  uint32_t x = unknown_function();
  if (x >= 0) {
    return x;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<unknown_nat>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <unknown_function@plt>
  test   %rax,%rax
  mov    $0x0,%edx
  cmovs  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t unknown_nat() {
  uint32_t x = unknown_function();
  if (x >= 0) {
    return x;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<unknown_nat>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <unknown_function@plt>
  xor    %edx,%edx
  test   %rax,%rax
  cmovs  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t unknown_nat() {
  uint32_t x = unknown_function();
  if (x >= 0) {
    return x;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<unknown_nat>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <unknown_function@plt>
  xor    %edx,%edx
  test   %rax,%rax
  cmovs  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t unknown_nat() {
  uint32_t x = unknown_function();
  if (x >= 0) {
    return x;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fBlaMka>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  shll   -0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t fBlaMka(uint64_t x, uint64_t y) {
  uint32_t lessX = (uint32_t)x;
  uint32_t lessY = (uint32_t)y;
  uint64_t lessZ = (uint64_t)lessX;
  lessZ = lessZ * lessY;
  lessZ = lessZ << 1;
  uint64_t z = lessZ + x + y;
  return z;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fBlaMka>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  lea    (%rdi,%rax,2),%eax
  add    %esi,%eax
  ret
```

assistant: ```c
uint64_t fBlaMka(uint64_t x, uint64_t y) {
  uint32_t lessX = (uint32_t)x;
  uint32_t lessY = (uint32_t)y;
  uint64_t lessZ = (uint64_t)lessX;
  lessZ = lessZ * lessY;
  lessZ = lessZ << 1;
  uint64_t z = lessZ + x + y;
  return z;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fBlaMka>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  lea    (%rdi,%rax,2),%eax
  add    %esi,%eax
  ret
```

assistant: ```c
uint64_t fBlaMka(uint64_t x, uint64_t y) {
  uint32_t lessX = (uint32_t)x;
  uint32_t lessY = (uint32_t)y;
  uint64_t lessZ = (uint64_t)lessX;
  lessZ = lessZ * lessY;
  lessZ = lessZ << 1;
  uint64_t z = lessZ + x + y;
  return z;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fBlaMka>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  lea    (%rdi,%rax,2),%eax
  add    %esi,%eax
  ret
```

assistant: ```c
uint64_t fBlaMka(uint64_t x, uint64_t y) {
  uint32_t lessX = (uint32_t)x;
  uint32_t lessY = (uint32_t)y;
  uint64_t lessZ = (uint64_t)lessX;
  lessZ = lessZ * lessY;
  lessZ = lessZ << 1;
  uint64_t z = lessZ + x + y;
  return z;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nodeid2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xf,%esi
  mov    %rax,%rdi
  call   <is_name@plt>
  test   %rax,%rax
  je     L35
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L20
L35:
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    %edx,%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sprintf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0xf,-0x4(%rbp)
  jle    L13
  movl   $0x1f,-0x4(%rbp)
  jmp    L26
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L5
L20:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: %02x

assistant: ```c
void nodeid2str(uint8_t *id, char *str) {
  int i;
  if (is_name((char *)id, 15)) {
    memcpy(str, id, 16);
    return;
  }
  for (i = 0; i < 16; i++)
    sprintf(&str[2 * i], "%02x", id[i]);
  for (i = 31; str[i] == '0'; i--)
    str[i] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nodeid2str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    $0xf,%esi
  call   <is_name@plt>
  mov    %r13,%rbx
  lea    0x20(%r13),%r14
  lea    D0(%rip),%r12
  test   %rax,%rax
  jne    L49
L8:
  mov    0x0(%rbp),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x4,%rbp
  add    $0x2,%rbx
  cmp    %r14,%rbx
  jne    L8
  lea    0x1f(%r13),%rax
  cmpb   $0x30,0x1f(%r13)
  jne    L10
L13:
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmpb   $0x30,(%rax)
  je     L13
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0: %02x

assistant: ```c
void nodeid2str(uint8_t *id, char *str) {
  int i;
  if (is_name((char *)id, 15)) {
    memcpy(str, id, 16);
    return;
  }
  for (i = 0; i < 16; i++)
    sprintf(&str[2 * i], "%02x", id[i]);
  for (i = 31; str[i] == '0'; i--)
    str[i] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nodeid2str>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    $0xf,%esi
  push   %r12
  lea    0x20(%r13),%r14
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r13,%rbx
  call   <is_name@plt>
  test   %rax,%rax
  jne    L23
  nop
L1:
  mov    0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x2,%rbx
  add    $0x4,%rbp
  call   <sprintf@plt>
  cmp    %r14,%rbx
  jne    L1
  cmpb   $0x30,0x1f(%r13)
  lea    0x1f(%r13),%rax
  jne    L12
  cs nopw 0x0(%rax,%rax,1)
L28:
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmpb   $0x30,(%rax)
  je     L28
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L23:
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  mov    $0x10,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <memcpy@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9: %02x

assistant: ```c
void nodeid2str(uint8_t *id, char *str) {
  int i;
  if (is_name((char *)id, 15)) {
    memcpy(str, id, 16);
    return;
  }
  for (i = 0; i < 16; i++)
    sprintf(&str[2 * i], "%02x", id[i]);
  for (i = 31; str[i] == '0'; i--)
    str[i] = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<nodeid2str>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    $0xf,%esi
  push   %r12
  lea    0x20(%r13),%r14
  lea    D2(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r13,%rbx
  call   <is_name@plt>
  test   %rax,%rax
  jne    L24
  nop
L27:
  mov    0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x2,%rbx
  add    $0x4,%rbp
  call   <sprintf@plt>
  cmp    %rbx,%r14
  jne    L27
  cmpb   $0x30,0x1f(%r13)
  lea    0x1f(%r13),%rax
  jne    L13
  cs nopw 0x0(%rax,%rax,1)
L4:
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmpb   $0x30,(%rax)
  je     L4
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L24:
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  mov    $0x10,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <memcpy@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: %02x

assistant: ```c
void nodeid2str(uint8_t *id, char *str) {
  int i;
  if (is_name((char *)id, 15)) {
    memcpy(str, id, 16);
    return;
  }
  for (i = 0; i < 16; i++)
    sprintf(&str[2 * i], "%02x", id[i]);
  for (i = 31; str[i] == '0'; i--)
    str[i] = 0;
}
```