user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D25(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0xf(%rsp)
  lea    0xf(%rsp),%rbp
  lea    0x13(%rsp),%r12
  movl   $0x77616853,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <printf@plt>
  movsd  D0(%rip),%xmm0
  mov    $0x1,%eax
  lea    D146(%rip),%rdi
  call   <printf@plt>
  movsd  D60(%rip),%xmm0
  mov    $0x1,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D77(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D133(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D106(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rcx
  mov    $0x41,%edx
  mov    %rbp,%rsi
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  lea    D141(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D7(%rip),%xmm0
  mov    $0x1,%eax
  lea    D149(%rip),%rdi
  call   <printf@plt>
  movsd  D43(%rip),%xmm0
  mov    $0x1,%eax
  lea    D121(%rip),%rdi
  call   <printf@plt>
  mov    $0xe,%esi
  lea    D90(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x23,%esi
  lea    D82(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: byte[8]
name: read_data
arguments: data_tag: D146
type_guessed: string
name: read_data
arguments: data_tag: D60
type_guessed: f64
name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D77
type_guessed: string
name: read_data
arguments: data_tag: D133
type_guessed: string
name: read_data
arguments: data_tag: D106
type_guessed: string
name: read_data
arguments: data_tag: D50
type_guessed: string
name: read_data
arguments: data_tag: D141
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: byte[8]
name: read_data
arguments: data_tag: D149
type_guessed: string
name: read_data
arguments: data_tag: D43
type_guessed: byte[8]
name: read_data
arguments: data_tag: D121
type_guessed: string
name: read_data
arguments: data_tag: D90
type_guessed: string
name: read_data
arguments: data_tag: D82
type_guessed: string

tool: D25: You are %d miles away.


tool: {"D0": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D146: You have %f levels of power.


tool: D60: 56789.4532

tool: D1: You have %f awesome super powers.


tool: D77: I have an initial %c.


tool: D133: I have a first name %s.


tool: D106: I have a last name %s.


tool: D50: My whole name is %s %c. %s.


tool: D141: 
x1=%d

tool: {"D7": [0x00,0x00,0x00,0x20,0x7e,0x8c,0xf8,0x3f]}

tool: D149: 
x2=%f

tool: {"D43": [0x00,0x00,0x00,0x00,0x54,0x35,0x7e,0x40]}

tool: D121: 
x3=%f

tool: D90: 
x4=%d

tool: D82: 
x5=%d

assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Zed";
  char last_name[] = "Shaw";
  printf("You are %d miles away.\n", distance);
  printf("You have %f levels of power.\n", power);
  printf("You have %f awesome super powers.\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name %s.\n", first_name);
  printf("I have a last name %s.\n", last_name);
  printf("My whole name is %s %c. %s.\n", first_name, initial, last_name);
  int x1 = 12;
  float x2 = 1.5343f;
  float x3 = 483.333;
  int x4 = 016;
  int x5 = 0x23;
  printf("\nx1=%d", x1);
  printf("\nx2=%f", x2);
  printf("\nx3=%f", x3);
  printf("\nx4=%d", x4);
  printf("\nx5=%d", x5);
  return 0;
}
```