user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rotate>:
  endbr64
  push   %r15
  push   %r14
  movslq %esi,%r14
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14d,%edi
  imul   %r12d,%edi
  sub    $0x38,%rsp
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L10
  mov    %r14,%r13
  test   %r14d,%r14d
  jle    L10
  lea    -0x1(%r14),%eax
  mov    %r12d,%r8d
  mov    %r12,%rbp
  shl    $0x2,%r14
  mov    %eax,%edx
  neg    %r8d
  shl    $0x2,%rax
  mov    $0xfffffffffffffffc,%r11
  imul   %r12d,%edx
  movslq %r8d,%r8
  lea    0x4(%rdi,%rax,1),%rsi
  xor    %r9d,%r9d
  shl    $0x2,%r8
  sub    %rax,%r11
  movslq %edx,%rdx
  lea    (%rbx,%rdx,4),%r10
  nopl   (%rax)
L65:
  lea    (%r11,%rsi,1),%rax
  mov    %r10,%rdx
  nopw   0x0(%rax,%rax,1)
L79:
  mov    (%rdx),%ecx
  add    $0x4,%rax
  add    %r8,%rdx
  mov    %ecx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L79
  add    $0x1,%r9
  add    $0x4,%r10
  lea    (%rax,%r14,1),%rsi
  cmp    %r12,%r9
  jne    L65
  mov    %ebp,%eax
  lea    0x0(,%r12,4),%r15
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  shr    $0x2,%eax
  xor    %r10d,%r10d
  lea    0x4(%rdi),%r14
  lea    -0x1(%rax),%esi
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  add    $0x1,%rsi
  mov    %eax,%ecx
  mov    %eax,0x4(%rsp)
  shl    $0x4,%rsi
  mov    %rcx,0x8(%rsp)
  lea    0x1(%rax),%ecx
  add    $0x2,%eax
  mov    %eax,0x14(%rsp)
  mov    %rax,0x20(%rsp)
  lea    -0x1(%rbp),%eax
  mov    %eax,(%rsp)
  mov    %ebp,%eax
  shl    $0x2,%rax
  mov    %ecx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %rax,0x28(%rsp)
L7:
  mov    %rbx,%rax
  lea    (%rbx,%r8,1),%rdx
  sub    %r14,%rax
  cmp    $0x8,%rax
  jbe    L93
  cmpl   $0x2,(%rsp)
  lea    (%r8,%rdi,1),%rcx
  seta   %r11b
  xor    %eax,%eax
  test   %r11b,%r11b
  je     L93
  nopl   0x0(%rax,%rax,1)
L11:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L11
  cmp    %ebp,0x4(%rsp)
  je     L72
  mov    0x8(%rsp),%rax
  add    %r9,%rax
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  cmp    0x10(%rsp),%ebp
  jle    L72
  mov    0x18(%rsp),%rax
  add    %r9,%rax
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  cmp    0x14(%rsp),%ebp
  jle    L72
  mov    0x20(%rsp),%rax
  add    %r9,%rax
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
L72:
  add    $0x1,%r10d
  add    %r15,%r8
  add    %r12,%r9
  cmp    %r10d,%r13d
  jne    L7
L10:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <free@plt>
  nopl   0x0(%rax)
L93:
  mov    0x28(%rsp),%rax
  lea    (%rax,%r8,1),%rdx
  mov    %r8,%rax
  nopl   0x0(%rax)
L121:
  mov    (%rdi,%rax,1),%ecx
  mov    %ecx,(%rbx,%rax,1)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L121
  jmp    L72
```

assistant: ```c
void rotate(int **matrix, int row, int col) {
  int *old = (int *)matrix;
  int *img = malloc(sizeof(int) * row * col);
  for (int i = 0; i < col; i++) {
    for (int j = 0; j < row; j++) {
      *(img + i * row + j) = *(old + (row - j - 1) * col + i);
    }
  }
  for (int i = 0; i < row; i++) {
    for (int j = 0; j < col; j++) {
      *(old + i * col + j) = *(img + i * col + j);
    }
  }
  free(img);
}
```