ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<pathcon_nm5_name_out>:
  endbr64
  lea    D11(%rip),%rax
  test   %edi,%edi
  je     L4
  cmp    $0x1,%edi
  lea    D3(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_infered: string
name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D11: o0

tool: D3: o1

assistant: ```c
const char *pathcon_nm5_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<decode_int16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x1c(%rbp)
  jg     L37
  mov    $0x0,%eax
  jmp    L50
L37:
  cmpq   $0x0,-0x18(%rbp)
  je     L2
  cmpq   $0x0,-0x28(%rbp)
  je     L2
  cmpl   $0x0,-0x20(%rbp)
  jg     L108
L2:
  mov    $0xffffffff,%eax
  jmp    L50
L108:
  movl   $0x0,-0xc(%rbp)
  jmp    L102
L70:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L53
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sl_gswap2a@plt>
L53:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,-0x20(%rbp)
  addl   $0x1,-0xc(%rbp)
L102:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L9
  cmpl   $0x7,-0x20(%rbp)
  jg     L70
L9:
  mov    -0xc(%rbp),%eax
L50:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int decode_int16(int16_t *input, int samplecount, int32_t *output, int outputlength, int swapflag) {
  int16_t sample;
  int idx;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  for (idx = 0; idx < samplecount && outputlength >= (int)sizeof(int32_t); idx++) {
    sample = input[idx];
    if (swapflag)
      sl_gswap2a(&sample);
    output[idx] = (int32_t)sample;
    outputlength -= sizeof(int32_t);
  }
  return idx;
}
```
user: What is the c source code of the assembly code below:

```asm
<decode_int16>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %ecx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ecx
  test   %esi,%esi
  jle    L22
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    %r8d,%r15d
  test   %rdx,%rdx
  sete   %al
  test   %ebp,%ebp
  setle  %dl
  or     %dl,%al
  jne    L25
  test   %rdi,%rdi
  je     L25
  cmp    $0x7,%ebp
  jle    L33
  mov    $0x1,%ebx
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L44
L71:
  movslq 0x14(%rsp),%rax
  mov    %rax,-0x8(%r13,%rbx,8)
  sub    $0x8,%ebp
  mov    %ebx,%ecx
  cmp    %ebx,%r12d
  setg   %dl
  cmp    $0x7,%ebp
  setg   %al
  add    $0x1,%rbx
  test   %al,%dl
  je     L22
L44:
  mov    -0x4(%r14,%rbx,4),%eax
  mov    %eax,0x14(%rsp)
  test   %r15d,%r15d
  je     L71
  mov    0x8(%rsp),%rdi
  call   <sl_gswap2a@plt>
  jmp    L71
L25:
  mov    $0xffffffff,%ecx
  jmp    L22
L33:
  mov    $0x0,%ecx
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  mov    %ecx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L82:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_int16(int16_t *input, int samplecount, int32_t *output, int outputlength, int swapflag) {
  int16_t sample;
  int idx;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  for (idx = 0; idx < samplecount && outputlength >= (int)sizeof(int32_t); idx++) {
    sample = input[idx];
    if (swapflag)
      sl_gswap2a(&sample);
    output[idx] = (int32_t)sample;
    outputlength -= sizeof(int32_t);
  }
  return idx;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decode_int16>:
  endbr64
  push   %r15
  xor    %r9d,%r9d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L68
  test   %rdx,%rdx
  mov    %rdx,%r15
  mov    %ecx,%ebp
  sete   %al
  test   %ecx,%ecx
  setle  %dl
  or     %dl,%al
  jne    L37
  mov    %rdi,%r14
  test   %rdi,%rdi
  je     L37
  cmp    $0x7,%ecx
  jle    L68
  mov    %esi,%r13d
  mov    $0x1,%ebx
  lea    0x14(%rsp),%r12
  jmp    L12
  nopl   (%rax)
L24:
  sub    $0x8,%ebp
  cmp    %ebx,%r13d
  mov    %rax,-0x8(%r15,%rbx,8)
  mov    %ebx,%r9d
  setg   %dl
  cmp    $0x7,%ebp
  setg   %al
  add    $0x1,%rbx
  test   %al,%dl
  je     L68
L12:
  movslq -0x4(%r14,%rbx,4),%rax
  mov    %eax,0x14(%rsp)
  test   %r8d,%r8d
  je     L24
  mov    %r12,%rdi
  mov    %r8d,0xc(%rsp)
  call   <sl_gswap2a@plt>
  movslq 0x14(%rsp),%rax
  mov    0xc(%rsp),%r8d
  jmp    L24
L37:
  mov    $0xffffffff,%r9d
  nopl   0x0(%rax)
L68:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0x28,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L84:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_int16(int16_t *input, int samplecount, int32_t *output, int outputlength, int swapflag) {
  int16_t sample;
  int idx;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  for (idx = 0; idx < samplecount && outputlength >= (int)sizeof(int32_t); idx++) {
    sample = input[idx];
    if (swapflag)
      sl_gswap2a(&sample);
    output[idx] = (int32_t)sample;
    outputlength -= sizeof(int32_t);
  }
  return idx;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<decode_int16>:
  endbr64
  push   %r15
  xor    %r9d,%r9d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L38
  test   %rdx,%rdx
  mov    %rdx,%r13
  mov    %ecx,%ebx
  sete   %al
  test   %ecx,%ecx
  setle  %dl
  or     %dl,%al
  jne    L31
  mov    %rdi,%r14
  test   %rdi,%rdi
  je     L31
  cmp    $0x7,%ecx
  jle    L38
  mov    %esi,%r12d
  test   %r8d,%r8d
  jne    L40
  mov    $0x1,%eax
  nop
L24:
  movslq -0x4(%r14,%rax,4),%rdx
  sub    $0x8,%ebx
  cmp    %eax,%r12d
  mov    %eax,%r9d
  setg   %cl
  cmp    $0x7,%ebx
  mov    %rdx,-0x8(%r13,%rax,8)
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L24
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x18,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L40:
  mov    $0x1,%ebp
  lea    0x4(%rsp),%r15
  nopw   0x0(%rax,%rax,1)
L1:
  mov    -0x4(%r14,%rbp,4),%eax
  mov    %r15,%rdi
  sub    $0x8,%ebx
  mov    %eax,0x4(%rsp)
  call   <sl_gswap2a@plt>
  cmp    %ebp,%r12d
  movslq 0x4(%rsp),%rax
  mov    %ebp,%r9d
  setg   %dl
  cmp    $0x7,%ebx
  mov    %rax,-0x8(%r13,%rbp,8)
  setg   %al
  add    $0x1,%rbp
  test   %al,%dl
  jne    L1
  jmp    L38
L31:
  mov    $0xffffffff,%r9d
  jmp    L38
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_int16(int16_t *input, int samplecount, int32_t *output, int outputlength, int swapflag) {
  int16_t sample;
  int idx;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  for (idx = 0; idx < samplecount && outputlength >= (int)sizeof(int32_t); idx++) {
    sample = input[idx];
    if (swapflag)
      sl_gswap2a(&sample);
    output[idx] = (int32_t)sample;
    outputlength -= sizeof(int32_t);
  }
  return idx;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pow64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L67
  mov    $0x1,%eax
  jmp    L55
L67:
  cmpl   $0x1,-0x18(%rbp)
  jne    L29
  mov    -0x14(%rbp),%eax
  jmp    L55
L29:
  cmpl   $0x2,-0x18(%rbp)
  jne    L32
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  jmp    L55
L32:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow64>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L10
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
L55:
  leave
  ret
```

assistant: ```c
uint64_t pow64(uint64_t a, uint64_t n) {
  uint64_t t;
  if (n == 0) {
    return 1;
  }
  if (n == 1) {
    return a;
  }
  if (n == 2) {
    return a * a;
  }
  t = pow64(a, n / 2);
  t *= t;
  if (n & 1) {
    t *= a;
  }
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pow64>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L9
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edi,%eax
  cmp    $0x1,%esi
  je     L30
  cmp    $0x2,%esi
  je     L33
  shr    $0x1f,%esi
  add    %ebx,%esi
  sar    %esi
  call   <pow64>
  imul   %eax,%eax
  test   $0x1,%bl
  je     L30
  imul   %ebp,%eax
  jmp    L30
L33:
  imul   %edi,%eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  ret
```

assistant: ```c
uint64_t pow64(uint64_t a, uint64_t n) {
  uint64_t t;
  if (n == 0) {
    return 1;
  }
  if (n == 1) {
    return a;
  }
  if (n == 2) {
    return a * a;
  }
  t = pow64(a, n / 2);
  t *= t;
  if (n & 1) {
    t *= a;
  }
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pow64>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L156
  push   %r12
  mov    %edi,%eax
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  cmp    $0x1,%esi
  je     L130
  cmp    $0x2,%esi
  je     L139
  mov    %esi,%edx
  mov    $0x1,%eax
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  je     L131
  cmp    $0x1,%edx
  je     L48
  cmp    $0x2,%edx
  je     L91
  test   %esi,%esi
  lea    0x3(%rsi),%ecx
  mov    $0x1,%eax
  cmovns %esi,%ecx
  sar    $0x2,%ecx
  mov    %ecx,%r12d
  je     L50
  cmp    $0x1,%ecx
  je     L94
  cmp    $0x2,%ecx
  je     L64
  test   %ebx,%ebx
  lea    0x7(%rsi),%esi
  mov    %edx,0xc(%rsp)
  cmovns %ebx,%esi
  mov    %edi,0x8(%rsp)
  sar    $0x3,%esi
  call   <pow64>
  mov    0x8(%rsp),%edi
  mov    0xc(%rsp),%edx
  imul   %eax,%eax
  and    $0x1,%r12d
  je     L114
  imul   %edi,%eax
L114:
  imul   %eax,%eax
L50:
  and    $0x1,%edx
  je     L97
  imul   %edi,%eax
L97:
  imul   %eax,%eax
L131:
  and    $0x1,%ebx
  je     L130
  imul   %edi,%eax
L130:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L156:
  ret
  nopl   0x0(%rax)
L139:
  add    $0x18,%rsp
  imul   %edi,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L91:
  mov    %edi,%eax
  imul   %edi,%eax
  imul   %eax,%eax
  jmp    L131
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %edi,%eax
  imul   %edi,%eax
  jmp    L131
  nop
L64:
  mov    %edi,%eax
  imul   %edi,%eax
  imul   %eax,%eax
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L94:
  mov    %edi,%eax
  imul   %edi,%eax
  jmp    L50
```

assistant: ```c
uint64_t pow64(uint64_t a, uint64_t n) {
  uint64_t t;
  if (n == 0) {
    return 1;
  }
  if (n == 1) {
    return a;
  }
  if (n == 2) {
    return a * a;
  }
  t = pow64(a, n / 2);
  t *= t;
  if (n & 1) {
    t *= a;
  }
  return t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pow64>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L17
  push   %r12
  mov    %edi,%eax
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  cmp    $0x1,%esi
  je     L2
  cmp    $0x2,%esi
  je     L53
  mov    %esi,%edx
  mov    $0x1,%eax
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  je     L20
  cmp    $0x1,%edx
  je     L23
  cmp    $0x2,%edx
  je     L58
  test   %esi,%esi
  lea    0x3(%rsi),%ecx
  mov    $0x1,%eax
  cmovns %esi,%ecx
  sar    $0x2,%ecx
  mov    %ecx,%r12d
  je     L88
  cmp    $0x1,%ecx
  je     L74
  cmp    $0x2,%ecx
  je     L102
  test   %ebx,%ebx
  lea    0x7(%rsi),%esi
  mov    %edx,0xc(%rsp)
  cmovns %ebx,%esi
  mov    %edi,0x8(%rsp)
  sar    $0x3,%esi
  call   <pow64>
  mov    0x8(%rsp),%edi
  mov    0xc(%rsp),%edx
  imul   %eax,%eax
  and    $0x1,%r12d
  je     L67
  imul   %edi,%eax
L67:
  imul   %eax,%eax
L88:
  and    $0x1,%edx
  je     L104
  imul   %edi,%eax
L104:
  imul   %eax,%eax
L20:
  and    $0x1,%ebx
  je     L2
  imul   %edi,%eax
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L17:
  ret
  nopl   0x0(%rax)
L53:
  add    $0x18,%rsp
  imul   %edi,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %edi,%eax
  imul   %edi,%eax
  imul   %eax,%eax
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %edi,%eax
  imul   %edi,%eax
  jmp    L20
  nop
L102:
  mov    %edi,%eax
  imul   %edi,%eax
  imul   %eax,%eax
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %edi,%eax
  imul   %edi,%eax
  jmp    L88
```

assistant: ```c
uint64_t pow64(uint64_t a, uint64_t n) {
  uint64_t t;
  if (n == 0) {
    return 1;
  }
  if (n == 1) {
    return a;
  }
  if (n == 2) {
    return a * a;
  }
  t = pow64(a, n / 2);
  t *= t;
  if (n & 1) {
    t *= a;
  }
  return t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L5:
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  movss  D63(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L16
  movss  D63(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  je     L38
L16:
  movss  -0xc(%rbp),%xmm1
  movss  D5(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  D35(%rip),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  D54(%rip),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L5
L38:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D61
data_type: string
name: retrieve_data
arguments: data_label: D33
data_type: string
name: retrieve_data
arguments: data_label: D63
data_type: byte[4]
name: retrieve_data
arguments: data_label: D5
data_type: byte[4]
name: retrieve_data
arguments: data_label: D35
data_type: byte[4]
name: retrieve_data
arguments: data_label: D54
data_type: byte[4]
name: retrieve_data
arguments: data_label: D59
data_type: string

tool: D61: 
Enter the amount of sales (-1, to end): 

tool: D33: %f

tool: {"D63": [0x00,0x00,0x80,0xbf]}

tool: {"D5": [0x00,0x00,0x10,0x41]}

tool: {"D35": [0x00,0x00,0xc8,0x42]}

tool: {"D54": [0x00,0x00,0x48,0x43]}

tool: D59: Salary: $%.2f

assistant: ```c
main() {
  float aSales;
  while (1) {
    printf("\nEnter the amount of sales (-1, to end): ");
    scanf("%f", &aSales);
    if (aSales == -1)
      break;
    printf("Salary: $%.2f", aSales * 9 / 100 + 200);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rbp
  lea    D61(%rip),%rbx
  jmp    L15
L6:
  mulss  D42(%rip),%xmm0
  divss  D19(%rip),%xmm0
  addss  D8(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D40(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L15:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  ucomiss D14(%rip),%xmm0
  jp     L6
  jne    L6
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D55
type: string
name: parse_data
arguments: data_label: D61
type: string
name: parse_data
arguments: data_label: D42
type: byte[4]
name: parse_data
arguments: data_label: D19
type: byte[4]
name: parse_data
arguments: data_label: D8
type: byte[4]
name: parse_data
arguments: data_label: D40
type: string
name: parse_data
arguments: data_label: D14
type: byte[4]

tool: D55: 
Enter the amount of sales (-1, to end): 

tool: D61: %f

tool: {"D42": [0x00,0x00,0x10,0x41]}

tool: {"D19": [0x00,0x00,0xc8,0x42]}

tool: {"D8": [0x00,0x00,0x48,0x43]}

tool: D40: Salary: $%.2f

tool: {"D14": [0x00,0x00,0x80,0xbf]}

assistant: ```c
main() {
  float aSales;
  while (1) {
    printf("\nEnter the amount of sales (-1, to end): ");
    scanf("%f", &aSales);
    if (aSales == -1)
      break;
    printf("Salary: $%.2f", aSales * 9 / 100 + 200);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  lea    D55(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L8:
  mulss  D14(%rip),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  divss  D65(%rip),%xmm0
  addss  D27(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L23:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  ucomiss D25(%rip),%xmm0
  jp     L8
  jne    L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D55
type: string
name: unpack_data
arguments: tag: D18
type: string
name: unpack_data
arguments: tag: D14
type: byte[4]
name: unpack_data
arguments: tag: D65
type: byte[4]
name: unpack_data
arguments: tag: D27
type: byte[4]
name: unpack_data
arguments: tag: D25
type: byte[4]

tool: D7: Salary: $%.2f

tool: D55: 
Enter the amount of sales (-1, to end): 

tool: D18: %f

tool: {"D14": [0x00,0x00,0x10,0x41]}

tool: {"D65": [0x00,0x00,0xc8,0x42]}

tool: {"D27": [0x00,0x00,0x48,0x43]}

tool: {"D25": [0x00,0x00,0x80,0xbf]}

assistant: ```c
main() {
  float aSales;
  while (1) {
    printf("\nEnter the amount of sales (-1, to end): ");
    scanf("%f", &aSales);
    if (aSales == -1)
      break;
    printf("Salary: $%.2f", aSales * 9 / 100 + 200);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D61(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L22:
  mulss  D68(%rip),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  divss  D11(%rip),%xmm0
  addss  D43(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L11:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  ucomiss D35(%rip),%xmm0
  jp     L22
  jne    L22
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_guessed: string
name: retrieve_data
arguments: label: D61
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D68
type_guessed: byte[4]
name: retrieve_data
arguments: label: D11
type_guessed: byte[4]
name: retrieve_data
arguments: label: D43
type_guessed: byte[4]
name: retrieve_data
arguments: label: D35
type_guessed: byte[4]

tool: D16: Salary: $%.2f

tool: D61: 
Enter the amount of sales (-1, to end): 

tool: D6: %f

tool: {"D68": [0x00,0x00,0x10,0x41]}

tool: {"D11": [0x00,0x00,0xc8,0x42]}

tool: {"D43": [0x00,0x00,0x48,0x43]}

tool: {"D35": [0x00,0x00,0x80,0xbf]}

assistant: ```c
main() {
  float aSales;
  while (1) {
    printf("\nEnter the amount of sales (-1, to end): ");
    scanf("%f", &aSales);
    if (aSales == -1)
      break;
    printf("Salary: $%.2f", aSales * 9 / 100 + 200);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inversa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa0(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cofatores@plt>
  lea    -0x50(%rbp),%rdx
  lea    -0xa0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <transposta@plt>
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <determinante@plt>
  movq   %xmm0,%rax
  mov    %rax,-0xa8(%rbp)
  movl   $0x0,-0xb0(%rbp)
  jmp    L26
L35:
  movl   $0x0,-0xac(%rbp)
  jmp    L46
L25:
  mov    -0xac(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movsd  -0x50(%rbp,%rax,8),%xmm0
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0xc0(%rbp),%rax
  add    %rax,%rdx
  divsd  -0xa8(%rbp),%xmm0
  mov    -0xac(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0xac(%rbp)
L46:
  cmpl   $0x2,-0xac(%rbp)
  jle    L25
  addl   $0x1,-0xb0(%rbp)
L26:
  cmpl   $0x2,-0xb0(%rbp)
  jle    L35
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
void inversa(double mtx[3][3], double resp[3][3]) {
  int i, j;
  double coef[3][3];
  double adj[3][3];
  double determ;
  cofatores(mtx, coef);
  transposta(coef, adj);
  determ = determinante(mtx);
  for (i = 0; i < 3; i++)
    for (j = 0; j < 3; j++)
      resp[i][j] = adj[i][j] / determ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inversa>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <cofatores@plt>
  lea    0x50(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <transposta@plt>
  mov    %r12,%rdi
  call   <determinante@plt>
  mov    %rbx,%rax
  mov    %rbp,%rdx
  lea    0x98(%rsp),%rcx
L1:
  movsd  (%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  movsd  0x8(%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rdx)
  movsd  0x10(%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rdx)
  add    $0x18,%rax
  add    $0x18,%rdx
  cmp    %rax,%rcx
  jne    L1
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void inversa(double mtx[3][3], double resp[3][3]) {
  int i, j;
  double coef[3][3];
  double adj[3][3];
  double determ;
  cofatores(mtx, coef);
  transposta(coef, adj);
  determ = determinante(mtx);
  for (i = 0; i < 3; i++)
    for (j = 0; j < 3; j++)
      resp[i][j] = adj[i][j] / determ;
}
```