ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<div_trunc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%eax
  mov    %rcx,%rbp
  mov    %edi,%ebx
  mov    $0x3f,%ecx
  sar    %cl,%ebx
  mov    %edx,%edi
  sar    %cl,%edi
  mov    %ebx,%r12d
  xor    %edi,%r12d
  xor    %ebx,%esi
  xor    %edi,%edx
  sub    %edi,%edx
  sub    %ebx,%esi
  sete   %dil
  movzbl %dil,%edi
  and    %ebx,%edi
  xor    %ebx,%eax
  add    %eax,%edi
  mov    %rbp,%rcx
  call   <divu@plt>
  cmp    $0xffffffff,%eax
  je     L21
  mov    %r12d,%edx
  xor    0x0(%rbp),%edx
  sub    %r12d,%edx
  mov    %edx,0x0(%rbp)
  xor    %edx,%r12d
  jns    L12
  test   %edx,%edx
  jne    L22
L12:
  xor    %ebx,%eax
  sub    %ebx,%eax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jmp    L34
L22:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jmp    L34
```

assistant: ```c
int64_t div_trunc(int64_t nhi, int64_t nlo, int64_t m, int64_t *q) {
  int64_t n_neg = nhi >> 63;
  int64_t m_neg = m >> 63;
  int64_t diff = n_neg ^ m_neg;
  uint64_t ulo = (uint64_t)((nlo ^ n_neg) - n_neg);
  uint64_t uhi = (uint64_t)((nhi ^ n_neg) + (n_neg & !ulo));
  uint64_t v = (uint64_t)((m ^ m_neg) - m_neg);
  int64_t r = (int64_t)divu(uhi, ulo, v, (uint64_t *)q);
  if (r == -1)
    return INT64_MIN;
  *q = (*q ^ diff) - diff;
  if ((*q ^ diff) < 0 && *q)
    return INT64_MIN;
  r = (r ^ n_neg) - n_neg;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<div_trunc>:
  endbr64
  push   %r12
  mov    %edi,%eax
  mov    %rcx,%r12
  mov    $0x3f,%ecx
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %edx,%edi
  sar    %cl,%ebx
  sar    %cl,%edi
  mov    %r12,%rcx
  xor    %edi,%edx
  mov    %ebx,%ebp
  xor    %ebx,%esi
  xor    %edi,%ebp
  sub    %edi,%edx
  xor    %edi,%edi
  sub    %ebx,%esi
  sete   %dil
  xor    %ebx,%eax
  and    %ebx,%edi
  add    %eax,%edi
  call   <divu@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    (%r12),%edx
  xor    %ebp,%edx
  sub    %ebp,%edx
  xor    %edx,%ebp
  mov    %edx,(%r12)
  jns    L17
  test   %edx,%edx
  jne    L5
L17:
  xor    %ebx,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    D7(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
```

assistant: ```c
int64_t div_trunc(int64_t nhi, int64_t nlo, int64_t m, int64_t *q) {
  int64_t n_neg = nhi >> 63;
  int64_t m_neg = m >> 63;
  int64_t diff = n_neg ^ m_neg;
  uint64_t ulo = (uint64_t)((nlo ^ n_neg) - n_neg);
  uint64_t uhi = (uint64_t)((nhi ^ n_neg) + (n_neg & !ulo));
  uint64_t v = (uint64_t)((m ^ m_neg) - m_neg);
  int64_t r = (int64_t)divu(uhi, ulo, v, (uint64_t *)q);
  if (r == -1)
    return INT64_MIN;
  *q = (*q ^ diff) - diff;
  if ((*q ^ diff) < 0 && *q)
    return INT64_MIN;
  r = (r ^ n_neg) - n_neg;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<div_trunc>:
  endbr64
  push   %r12
  mov    %edi,%eax
  mov    %rcx,%r12
  mov    $0x3f,%ecx
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %edx,%edi
  sar    %cl,%ebx
  sar    %cl,%edi
  mov    %r12,%rcx
  xor    %edi,%edx
  mov    %ebx,%ebp
  xor    %ebx,%esi
  xor    %edi,%ebp
  sub    %edi,%edx
  xor    %edi,%edi
  sub    %ebx,%esi
  sete   %dil
  xor    %ebx,%eax
  and    %ebx,%edi
  add    %eax,%edi
  call   <divu@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    (%r12),%edx
  xor    %ebp,%edx
  sub    %ebp,%edx
  xor    %edx,%ebp
  mov    %edx,(%r12)
  jns    L2
  test   %edx,%edx
  jne    L3
L2:
  xor    %ebx,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  mov    D2(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
```

assistant: ```c
int64_t div_trunc(int64_t nhi, int64_t nlo, int64_t m, int64_t *q) {
  int64_t n_neg = nhi >> 63;
  int64_t m_neg = m >> 63;
  int64_t diff = n_neg ^ m_neg;
  uint64_t ulo = (uint64_t)((nlo ^ n_neg) - n_neg);
  uint64_t uhi = (uint64_t)((nhi ^ n_neg) + (n_neg & !ulo));
  uint64_t v = (uint64_t)((m ^ m_neg) - m_neg);
  int64_t r = (int64_t)divu(uhi, ulo, v, (uint64_t *)q);
  if (r == -1)
    return INT64_MIN;
  *q = (*q ^ diff) - diff;
  if ((*q ^ diff) < 0 && *q)
    return INT64_MIN;
  r = (r ^ n_neg) - n_neg;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6: concrete contains gravel and cement.


assistant: ```c
int main(void) {
  printf("concrete contains gravel and cement.\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: concrete contains gravel and cement.


assistant: ```c
int main(void) {
  printf("concrete contains gravel and cement.\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: concrete contains gravel and cement.


assistant: ```c
int main(void) {
  printf("concrete contains gravel and cement.\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: concrete contains gravel and cement.


assistant: ```c
int main(void) {
  printf("concrete contains gravel and cement.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<joe_closelog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <closelog@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void joe_closelog(void) {
  closelog();
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<joe_closelog>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <closelog@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void joe_closelog(void) {
  closelog();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<joe_closelog>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <closelog@plt>
```

assistant: ```c
void joe_closelog(void) {
  closelog();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<joe_closelog>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <closelog@plt>
```

assistant: ```c
void joe_closelog(void) {
  closelog();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<s_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  je     L0
  mov    $0x0,%eax
  jmp    L12
L0:
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
L12:
  leave
  ret
```

assistant: ```c
int s_read(void *user, int offset, void *buf, int size) {
  FILE *f = user;
  if (fseek(f, offset, SEEK_SET) != 0)
    return 0;
  return fread(buf, 1, size, f);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<s_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L12
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %rbx,%rcx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  jmp    L10
```

assistant: ```c
int s_read(void *user, int offset, void *buf, int size) {
  FILE *f = user;
  if (fseek(f, offset, SEEK_SET) != 0)
    return 0;
  return fread(buf, 1, size, f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<s_read>:
  endbr64
  mov    D7(%rip),%rax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    (%rax),%edx
  call   <fseek@plt>
  test   %rax,%rax
  je     L2
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L2:
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <fread@plt>
```

assistant: ```c
int s_read(void *user, int offset, void *buf, int size) {
  FILE *f = user;
  if (fseek(f, offset, SEEK_SET) != 0)
    return 0;
  return fread(buf, 1, size, f);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<s_read>:
  endbr64
  mov    D5(%rip),%rax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    (%rax),%edx
  call   <fseek@plt>
  test   %rax,%rax
  je     L9
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L9:
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <fread@plt>
```

assistant: ```c
int s_read(void *user, int offset, void *buf, int size) {
  FILE *f = user;
  if (fseek(f, offset, SEEK_SET) != 0)
    return 0;
  return fread(buf, 1, size, f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_data_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L12
L6:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xfe,%al
  jne    L6
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
const volatile unsigned char *find_data_start(const volatile unsigned char *r1ptr) {
  ++r1ptr;
  while (*r1ptr != 0xfe)
    ++r1ptr;
  return r1ptr + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find_data_start>:
  endbr64
  lea    0x1(%rdi),%rax
  movzbl 0x1(%rdi),%edx
  cmp    $0xfe,%dl
  je     L1
L6:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0xfe,%dl
  jne    L6
L1:
  add    $0x1,%rax
  ret
```

assistant: ```c
const volatile unsigned char *find_data_start(const volatile unsigned char *r1ptr) {
  ++r1ptr;
  while (*r1ptr != 0xfe)
    ++r1ptr;
  return r1ptr + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_data_start>:
  endbr64
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rax
  cmp    $0xfe,%dl
  je     L14
  nopl   0x0(%rax)
L17:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0xfe,%dl
  jne    L17
L14:
  add    $0x1,%rax
  ret
```

assistant: ```c
const volatile unsigned char *find_data_start(const volatile unsigned char *r1ptr) {
  ++r1ptr;
  while (*r1ptr != 0xfe)
    ++r1ptr;
  return r1ptr + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_data_start>:
  endbr64
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rax
  cmp    $0xfe,%dl
  je     L1
  nopl   0x0(%rax)
L18:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0xfe,%dl
  jne    L18
L1:
  add    $0x1,%rax
  ret
```

assistant: ```c
const volatile unsigned char *find_data_start(const volatile unsigned char *r1ptr) {
  ++r1ptr;
  while (*r1ptr != 0xfe)
    ++r1ptr;
  return r1ptr + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x2710,-0x20(%rbp)
  mov    $0x2710,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L11
L4:
  addl   $0x1,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <process_line@plt>
  mov    %rax,-0x10(%rbp)
L11:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  lea    -0x20(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  jne    L4
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <treeprint_lines@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main() {
  size_t n = 10000;
  char *line = malloc(10000);
  struct tnode *root = NULL;
  int linecounter = 0;
  while (getline(&line, &n, stdin) != -1) {
    linecounter++;
    root = process_line(line, linecounter, root);
  }
  treeprint_lines(root);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x2710,0x8(%rsp)
  mov    $0x2710,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  mov    D3(%rip),%r12
  jmp    L12
L25:
  add    $0x1,%ebp
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    0x10(%rsp),%rdi
  call   <process_line@plt>
  mov    %rax,%rbx
L12:
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    (%r12),%edx
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  jne    L25
  mov    %rbx,%rdi
  call   <treeprint_lines@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  size_t n = 10000;
  char *line = malloc(10000);
  struct tnode *root = NULL;
  int linecounter = 0;
  while (getline(&line, &n, stdin) != -1) {
    linecounter++;
    root = process_line(line, linecounter, root);
  }
  treeprint_lines(root);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x2710,%edi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%rbp
  movq   $0x2710,0x8(%rsp)
  call   <malloc@plt>
  mov    D0(%rip),%r14
  mov    %rax,0x10(%rsp)
  jmp    L26
L18:
  mov    0x10(%rsp),%rdi
  add    $0x1,%ebx
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <process_line@plt>
  mov    %rax,%r12
L26:
  mov    (%r14),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  jne    L18
  mov    %r12,%rdi
  call   <treeprint_lines@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  size_t n = 10000;
  char *line = malloc(10000);
  struct tnode *root = NULL;
  int linecounter = 0;
  while (getline(&line, &n, stdin) != -1) {
    linecounter++;
    root = process_line(line, linecounter, root);
  }
  treeprint_lines(root);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x2710,%edi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%rbp
  movq   $0x2710,0x8(%rsp)
  call   <malloc@plt>
  mov    D4(%rip),%r14
  mov    %rax,0x10(%rsp)
  jmp    L29
L7:
  mov    0x10(%rsp),%rdi
  add    $0x1,%ebx
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <process_line@plt>
  mov    %rax,%r12
L29:
  mov    (%r14),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  jne    L7
  mov    %r12,%rdi
  call   <treeprint_lines@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  size_t n = 10000;
  char *line = malloc(10000);
  struct tnode *root = NULL;
  int linecounter = 0;
  while (getline(&line, &n, stdin) != -1) {
    linecounter++;
    root = process_line(line, linecounter, root);
  }
  treeprint_lines(root);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shell_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L59
L37:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
L3:
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L27
L56:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L50
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap_elem@plt>
  movl   $0x1,-0x8(%rbp)
L50:
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L56
  cmpl   $0x1,-0x8(%rbp)
  je     L3
L59:
  cmpl   $0x0,-0xc(%rbp)
  jg     L37
  nop
  nop
  leave
  ret
```

assistant: ```c
void shell_sort(int *pdata, int count) {
  int i, jump, change, temp, m;
  jump = count;
  while (jump > 0) {
    jump = jump / 2;
    do {
      change = 0;
      for (i = 1; i < (count - jump); i++) {
        m = i + jump;
        if (*(pdata + i) > *(pdata + m)) {
          swap_elem((pdata + m), (pdata + i));
          change = 1;
        }
      }
    } while (change == 1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<shell_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  test   %esi,%esi
  jg     L25
L48:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    %esi,%r13d
  mov    %esi,0x18(%rsp)
  mov    %rdi,%rax
  add    $0x8,%rax
  mov    %rax,0x10(%rsp)
  mov    $0x1,%r14d
L5:
  mov    0x18(%rsp),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,0x1c(%rsp)
  mov    %r13d,%r15d
  sub    %eax,%r15d
  add    $0x1,%eax
  cltq
  mov    (%rsp),%rcx
  lea    (%rcx,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  lea    -0x2(%r15),%eax
  mov    0x10(%rsp),%rcx
  lea    (%rcx,%rax,4),%r12
L21:
  cmp    $0x1,%r15d
  jle    L27
  mov    (%rsp),%rax
  lea    0x4(%rax),%rbx
  mov    0x8(%rsp),%rbp
  mov    $0x0,%eax
  jmp    L40
L54:
  add    $0x4,%rbx
  add    $0x4,%rbp
  cmp    %r12,%rbx
  je     L11
L40:
  mov    0x0(%rbp),%edx
  cmp    %edx,(%rbx)
  jle    L54
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap_elem@plt>
  mov    %r14d,%eax
  jmp    L54
L11:
  cmp    $0x1,%eax
  je     L21
L27:
  cmpl   $0x1,0x18(%rsp)
  jle    L48
  mov    0x1c(%rsp),%eax
  mov    %eax,0x18(%rsp)
  jmp    L5
```

assistant: ```c
void shell_sort(int *pdata, int count) {
  int i, jump, change, temp, m;
  jump = count;
  while (jump > 0) {
    jump = jump / 2;
    do {
      change = 0;
      for (i = 1; i < (count - jump); i++) {
        m = i + jump;
        if (*(pdata + i) > *(pdata + m)) {
          swap_elem((pdata + m), (pdata + i));
          change = 1;
        }
      }
    } while (change == 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shell_sort>:
  endbr64
  push   %r15
  lea    0x8(%rdi),%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %esi,(%rsp)
  mov    %rcx,0x8(%rsp)
  test   %esi,%esi
  jle    L20
  mov    %rdi,%rbp
  nopl   (%rax)
L29:
  mov    0x4(%rsp),%ebx
  mov    0x8(%rsp),%rcx
  sarl   (%rsp)
  mov    (%rsp),%eax
  sub    %eax,%ebx
  add    $0x1,%eax
  cltq
  lea    0x0(%rbp,%rax,4),%r12
  lea    -0x2(%rbx),%eax
  lea    (%rcx,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L39:
  cmp    $0x1,%ebx
  jle    L21
  lea    0x4(%rbp),%r13
  mov    %r12,%r15
  xor    %eax,%eax
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L33:
  add    $0x4,%r13
  add    $0x4,%r15
  cmp    %r14,%r13
  je     L78
L56:
  mov    (%r15),%edx
  cmp    %edx,0x0(%r13)
  jle    L33
  mov    %r13,%rsi
  mov    %r15,%rdi
  add    $0x4,%r13
  add    $0x4,%r15
  call   <swap_elem@plt>
  mov    $0x1,%eax
  cmp    %r14,%r13
  jne    L56
L78:
  cmp    $0x1,%eax
  je     L39
  nopl   0x0(%rax,%rax,1)
L21:
  mov    (%rsp),%eax
  test   %eax,%eax
  jne    L29
L20:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shell_sort(int *pdata, int count) {
  int i, jump, change, temp, m;
  jump = count;
  while (jump > 0) {
    jump = jump / 2;
    do {
      change = 0;
      for (i = 1; i < (count - jump); i++) {
        m = i + jump;
        if (*(pdata + i) > *(pdata + m)) {
          swap_elem((pdata + m), (pdata + i));
          change = 1;
        }
      }
    } while (change == 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shell_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jle    L57
  lea    0x8(%rdi),%rax
  mov    %esi,(%rsp)
  mov    %rdi,%rbp
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L51:
  mov    0x4(%rsp),%ebx
  mov    0x8(%rsp),%rcx
  sarl   (%rsp)
  mov    (%rsp),%eax
  sub    %eax,%ebx
  add    $0x1,%eax
  cltq
  lea    0x0(%rbp,%rax,4),%r12
  lea    -0x2(%rbx),%eax
  lea    (%rcx,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L42:
  cmp    $0x1,%ebx
  jle    L58
  lea    0x4(%rbp),%r13
  mov    %r12,%r15
  xor    %eax,%eax
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L69:
  add    $0x4,%r13
  add    $0x4,%r15
  cmp    %r14,%r13
  je     L5
L30:
  mov    (%r15),%edx
  cmp    %edx,0x0(%r13)
  jle    L69
  mov    %r13,%rsi
  mov    %r15,%rdi
  add    $0x4,%r13
  add    $0x4,%r15
  call   <swap_elem@plt>
  mov    $0x1,%eax
  cmp    %r14,%r13
  jne    L30
L5:
  cmp    $0x1,%eax
  je     L42
  nopl   0x0(%rax,%rax,1)
L58:
  mov    (%rsp),%eax
  test   %eax,%eax
  jne    L51
L57:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shell_sort(int *pdata, int count) {
  int i, jump, change, temp, m;
  jump = count;
  while (jump > 0) {
    jump = jump / 2;
    do {
      change = 0;
      for (i = 1; i < (count - jump); i++) {
        m = i + jump;
        if (*(pdata + i) > *(pdata + m)) {
          swap_elem((pdata + m), (pdata + i));
          change = 1;
        }
      }
    } while (change == 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<computeUniformColorLUT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <computeUniformColorLUTI@plt>
  mov    $0x0,%eax
  call   <computeUniformColorLUTD@plt>
  mov    $0x0,%eax
  call   <computeUniformColorLUTT@plt>
  mov    $0x0,%eax
  call   <computeUniformColorLUTP@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void computeUniformColorLUT() {
  computeUniformColorLUTI();
  computeUniformColorLUTD();
  computeUniformColorLUTT();
  computeUniformColorLUTP();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<computeUniformColorLUT>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <computeUniformColorLUTI@plt>
  mov    $0x0,%eax
  call   <computeUniformColorLUTD@plt>
  mov    $0x0,%eax
  call   <computeUniformColorLUTT@plt>
  mov    $0x0,%eax
  call   <computeUniformColorLUTP@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void computeUniformColorLUT() {
  computeUniformColorLUTI();
  computeUniformColorLUTD();
  computeUniformColorLUTT();
  computeUniformColorLUTP();
}
```