user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  lea    D24(%rip),%rdi
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <MYstrcpy@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <MYstrlen@plt>
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <MYstrcpy@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  lea    D23(%rip),%r14
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <MYstrlen@plt>
  mov    %r12,%rsi
  lea    0x0(%rbp,%rax,1),%rdi
  call   <MYstrcpy@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <MYstrcpy@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <MYstrlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <MYstrlen@plt>
  lea    0x1(%rbx),%edi
  mov    %r12,%rsi
  movslq %edi,%rdi
  movb   $0x20,(%rsp,%rax,1)
  add    %rbp,%rdi
  call   <MYstrcpy@plt>
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D24
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string
name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D40
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string

tool: D24: Our string literal is %s, 
while the unititialized buffer is %s


tool: D19: 


tool: D4: This is a literal string

tool: D1: Our string literal is %s, 
while the now ititialized buffer is %s


tool: D40: Our string literal is %s, 
while the stringPtr is %s


tool: D23: Buffer is now %s


assistant: ```c
int main(int argc, char *argv[]) {
  int index;
  char c, buffer[80];
  char *stringPtr, *literal = "This is a literal string";
  printf("Our string literal is %s, \nwhile the unititialized buffer is %s\n", literal, buffer);
  printf("\n\n");
  MYstrcpy(buffer, literal);
  printf("Our string literal is %s, \nwhile the now ititialized buffer is %s\n", literal, buffer);
  stringPtr = (char *)malloc(MYstrlen(literal));
  MYstrcpy(stringPtr, literal);
  printf("Our string literal is %s, \nwhile the stringPtr is %s\n", literal, stringPtr);
  printf("\n\n");
  MYstrcpy(buffer + MYstrlen(buffer), literal);
  printf("Buffer is now %s\n", buffer);
  printf("\n\n");
  MYstrcpy(buffer, literal);
  printf("Buffer is now %s\n", buffer);
  printf("\n\n");
  index = MYstrlen(buffer) + 1;
  buffer[MYstrlen(buffer)] = ' ';
  MYstrcpy(buffer + index, literal);
  printf("Buffer is now %s\n", buffer);
  printf("\n\n");
}
```