ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<maxXor>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  setg   %dil
  xor    %eax,%eax
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  setle  %dil
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x3e8,%ebp
  setle  %dil
  xor    %eax,%eax
  call   <assert@plt>
  cmp    %ebp,%ebx
  jg     L22
  lea    0x1(%rbp),%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %ebx,%eax
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %ebx,%edx
  xor    %eax,%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x1,%eax
  cmp    %eax,%ebp
  jge    L21
  add    $0x1,%ebx
  cmp    %ebx,%ecx
  jne    L29
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int maxXor(int l, int r) {
  assert(1 <= l);
  assert(l <= r);
  assert(r <= pow(10, 3));
  int max = 0;
  int inner_r;
  int xor ;
  for (l; l <= r; l++) {
    for (inner_r = l; inner_r <= r; inner_r++) {
      xor = l ^ inner_r;
      if (xor > max) {
        max = xor;
      }
    }
  }
  return max;
}
```
user: What is the c source code of the assembly code below?

```asm
<maxXor>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  setg   %dil
  xor    %eax,%eax
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  setle  %dil
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x3e8,%ebp
  setle  %dil
  xor    %eax,%eax
  call   <assert@plt>
  cmp    %ebp,%ebx
  jg     L12
  movdqa D4(%rip),%xmm5
  lea    0x1(%rbp),%edi
  xor    %eax,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L31:
  mov    %edi,%ecx
  mov    %ebp,%edx
  sub    %ebx,%ecx
  cmp    %ebx,%ebp
  cmovl  %r8d,%ecx
  sub    %ebx,%edx
  cmp    $0x2,%edx
  jbe    L8
  cmp    %ebx,%ebp
  jl     L8
  movd   %eax,%xmm6
  lea    0x2(%rbx),%eax
  lea    0x1(%rbx),%esi
  mov    %ecx,%edx
  movd   %eax,%xmm0
  lea    0x3(%rbx),%eax
  pshufd $0x0,%xmm6,%xmm2
  shr    $0x2,%edx
  movd   %eax,%xmm7
  movd   %ebx,%xmm3
  movd   %esi,%xmm6
  xor    %eax,%eax
  punpckldq %xmm7,%xmm0
  punpckldq %xmm6,%xmm3
  movd   %ebx,%xmm7
  punpcklqdq %xmm0,%xmm3
  pshufd $0x0,%xmm7,%xmm4
  nopl   (%rax)
L22:
  movdqa %xmm3,%xmm0
  add    $0x1,%eax
  paddd  %xmm5,%xmm3
  pxor   %xmm4,%xmm0
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %edx,%eax
  jne    L22
  movdqa %xmm2,%xmm1
  mov    %ecx,%r9d
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%r9d
  movdqa %xmm1,%xmm0
  lea    (%r9,%rbx,1),%edx
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movd   %xmm1,%eax
  cmp    %r9d,%ecx
  je     L40
L66:
  mov    %ebx,%ecx
  xor    %edx,%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%ebp
  jl     L40
  xor    %ebx,%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  add    $0x2,%edx
  xor    %edx,%ebx
  cmp    %ebx,%eax
  cmovge %eax,%ebx
  cmp    %edx,%ebp
  cmovge %ebx,%eax
L40:
  mov    %esi,%ebx
  cmp    %edi,%esi
  jne    L31
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    %ebx,%edx
  lea    0x1(%rbx),%esi
  jmp    L66
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: byte[16]

tool: {"D4": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int maxXor(int l, int r) {
  assert(1 <= l);
  assert(l <= r);
  assert(r <= pow(10, 3));
  int max = 0;
  int inner_r;
  int xor ;
  for (l; l <= r; l++) {
    for (inner_r = l; inner_r <= r; inner_r++) {
      xor = l ^ inner_r;
      if (xor > max) {
        max = xor;
      }
    }
  }
  return max;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<modos_jogo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
L33:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <nome_decorado@plt>
  mov    $0xc6,%r8d
  mov    $0x87,%ecx
  mov    $0xa3,%edx
  mov    $0x10,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  je     L21
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  je     L21
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  je     L21
  mov    -0x10(%rbp),%eax
  cmp    $0x4,%eax
  jne    L33
L21:
  cmpl   $0x1,-0x14(%rbp)
  jne    L61
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <auto_MK_engine@plt>
  jmp    L11
L61:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <manual_MK_engine@plt>
L11:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type_guessed: string
name: disassemble_data
arguments: data_label: D29
type_guessed: string
name: disassemble_data
arguments: data_label: D40
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: string
name: disassemble_data
arguments: data_label: D58
type_guessed: string
name: disassemble_data
arguments: data_label: D6
type_guessed: string
name: disassemble_data
arguments: data_label: D62
type_guessed: string

tool: D28: clear

tool: D29: %c Digite o n%cmero da op%c%co correspondente ao tamanho do tabuleiro:



tool: D40:   1 %c 4x4


tool: D25:   2 %c 6x6


tool: D58:   3 %c 8x8


tool: D6:   4 %c 10x10

 > 

tool: D62: %d

assistant: ```c
void modos_jogo(int modo) {
  int opcao = 0, retorno;
  do {
    system("clear");
    nome_decorado();
    printf("%c Digite o n%cmero da op%c%co correspondente ao tamanho do tabuleiro:\n\n", 16, 163, 135, 198);
    printf("  1 %c 4x4\n", 175);
    printf("  2 %c 6x6\n", 175);
    printf("  3 %c 8x8\n", 175);
    printf("  4 %c 10x10\n\n > ", 175);
    scanf("%d", &opcao);
  } while (opcao != 1 && opcao != 2 && opcao != 3 && opcao != 4);
  if (modo == 1) {
    retorno = (2 * opcao + 2);
    auto_MK_engine(retorno);
  } else {
    retorno = (2 * opcao + 2);
    manual_MK_engine(retorno);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<modos_jogo>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D35(%rip),%r13
  lea    D26(%rip),%r12
  lea    D40(%rip),%rbp
  lea    D53(%rip),%rbx
L10:
  mov    %r13,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <nome_decorado@plt>
  mov    $0xc6,%r8d
  mov    $0x87,%ecx
  mov    $0xa3,%edx
  mov    $0x10,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x3,%edx
  ja     L10
  cmp    $0x1,%r14d
  je     L3
  lea    0x2(%rax,%rax,1),%edi
  call   <manual_MK_engine@plt>
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  lea    0x2(%rax,%rax,1),%edi
  call   <auto_MK_engine@plt>
  jmp    L14
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D35
data_type: string
name: retrieve_data
arguments: data_label: D26
data_type: string
name: retrieve_data
arguments: data_label: D40
data_type: string
name: retrieve_data
arguments: data_label: D53
data_type: string
name: retrieve_data
arguments: data_label: D12
data_type: string
name: retrieve_data
arguments: data_label: D55
data_type: string
name: retrieve_data
arguments: data_label: D28
data_type: string

tool: D35: clear

tool: D26: %c Digite o n%cmero da op%c%co correspondente ao tamanho do tabuleiro:



tool: D40:   1 %c 4x4


tool: D53:   2 %c 6x6


tool: D12:   3 %c 8x8


tool: D55:   4 %c 10x10

 > 

tool: D28: %d

assistant: ```c
void modos_jogo(int modo) {
  int opcao = 0, retorno;
  do {
    system("clear");
    nome_decorado();
    printf("%c Digite o n%cmero da op%c%co correspondente ao tamanho do tabuleiro:\n\n", 16, 163, 135, 198);
    printf("  1 %c 4x4\n", 175);
    printf("  2 %c 6x6\n", 175);
    printf("  3 %c 8x8\n", 175);
    printf("  4 %c 10x10\n\n > ", 175);
    scanf("%d", &opcao);
  } while (opcao != 1 && opcao != 2 && opcao != 3 && opcao != 4);
  if (modo == 1) {
    retorno = (2 * opcao + 2);
    auto_MK_engine(retorno);
  } else {
    retorno = (2 * opcao + 2);
    manual_MK_engine(retorno);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<modos_jogo>:
  endbr64
  push   %r15
  lea    D55(%rip),%r15
  push   %r14
  lea    D43(%rip),%r14
  push   %r13
  lea    D57(%rip),%r13
  push   %r12
  lea    D59(%rip),%r12
  push   %rbp
  lea    D67(%rip),%rbp
  push   %rbx
  lea    D69(%rip),%rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  movl   $0x0,0x14(%rsp)
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L13:
  mov    %r15,%rdi
  call   <system@plt>
  xor    %eax,%eax
  call   <nome_decorado@plt>
  mov    $0xa3,%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0xc6,%r8d
  mov    $0x87,%ecx
  mov    $0x10,%esi
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x3,%edx
  ja     L13
  cmpl   $0x1,0xc(%rsp)
  lea    0x2(%rax,%rax,1),%edi
  je     L0
  call   <manual_MK_engine@plt>
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L0:
  call   <auto_MK_engine@plt>
  jmp    L19
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D55
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D43
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D57
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D59
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D67
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D69
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D28
type_guessed: string

tool: D55: clear

tool: D43: %c Digite o n%cmero da op%c%co correspondente ao tamanho do tabuleiro:



tool: D57:   1 %c 4x4


tool: D59:   2 %c 6x6


tool: D67:   3 %c 8x8


tool: D69:   4 %c 10x10

 > 

tool: D28: %d

assistant: ```c
void modos_jogo(int modo) {
  int opcao = 0, retorno;
  do {
    system("clear");
    nome_decorado();
    printf("%c Digite o n%cmero da op%c%co correspondente ao tamanho do tabuleiro:\n\n", 16, 163, 135, 198);
    printf("  1 %c 4x4\n", 175);
    printf("  2 %c 6x6\n", 175);
    printf("  3 %c 8x8\n", 175);
    printf("  4 %c 10x10\n\n > ", 175);
    scanf("%d", &opcao);
  } while (opcao != 1 && opcao != 2 && opcao != 3 && opcao != 4);
  if (modo == 1) {
    retorno = (2 * opcao + 2);
    auto_MK_engine(retorno);
  } else {
    retorno = (2 * opcao + 2);
    manual_MK_engine(retorno);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<modos_jogo>:
  endbr64
  push   %r15
  lea    D13(%rip),%r15
  push   %r14
  lea    D48(%rip),%r14
  push   %r13
  lea    D33(%rip),%r13
  push   %r12
  lea    D30(%rip),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  lea    D39(%rip),%rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  movl   $0x0,0x14(%rsp)
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L34:
  mov    %r15,%rdi
  call   <system@plt>
  xor    %eax,%eax
  call   <nome_decorado@plt>
  mov    $0xa3,%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0xc6,%r8d
  mov    $0x87,%ecx
  mov    $0x10,%esi
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xaf,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rsi
  lea    D69(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x3,%edx
  ja     L34
  cmpl   $0x1,0xc(%rsp)
  lea    0x2(%rax,%rax,1),%edi
  je     L38
  call   <manual_MK_engine@plt>
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L38:
  call   <auto_MK_engine@plt>
  jmp    L3
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D48
data_type: string
name: parse_data
arguments: data_tag: D33
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string
name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D39
data_type: string
name: parse_data
arguments: data_tag: D69
data_type: string

tool: D13: clear

tool: D48: %c Digite o n%cmero da op%c%co correspondente ao tamanho do tabuleiro:



tool: D33:   1 %c 4x4


tool: D30:   2 %c 6x6


tool: D2:   3 %c 8x8


tool: D39:   4 %c 10x10

 > 

tool: D69: %d

assistant: ```c
void modos_jogo(int modo) {
  int opcao = 0, retorno;
  do {
    system("clear");
    nome_decorado();
    printf("%c Digite o n%cmero da op%c%co correspondente ao tamanho do tabuleiro:\n\n", 16, 163, 135, 198);
    printf("  1 %c 4x4\n", 175);
    printf("  2 %c 6x6\n", 175);
    printf("  3 %c 8x8\n", 175);
    printf("  4 %c 10x10\n\n > ", 175);
    scanf("%d", &opcao);
  } while (opcao != 1 && opcao != 2 && opcao != 3 && opcao != 4);
  if (modo == 1) {
    retorno = (2 * opcao + 2);
    auto_MK_engine(retorno);
  } else {
    retorno = (2 * opcao + 2);
    manual_MK_engine(retorno);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<premul_nozero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  cmpb   $0xff,-0x8(%rbp)
  jne    L14
  mov    -0x4(%rbp),%eax
  jmp    L7
L14:
  mov    -0x4(%rbp),%eax
  and    $0xff00ff,%eax
  mov    %eax,%edx
  movzbl -0x8(%rbp),%eax
  imul   %edx,%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  mov    %eax,%edx
  movzbl -0x8(%rbp),%eax
  imul   %edx,%eax
  and    $0xff00ff00,%eax
  or     %ecx,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int premul_nozero(unsigned int val, unsigned char alpha) {
  if (alpha == 0xFF)
    return val;
  else
    return ((((val & 0x00FF00FF) * alpha) >> 8) & 0x00FF00FF) | ((((val & 0xFF00FF00) >> 8) * alpha) & 0xFF00FF00);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<premul_nozero>:
  endbr64
  mov    %edi,%eax
  cmp    $0xff,%sil
  je     L7
  movzbl %sil,%esi
  and    $0xff00ff,%eax
  imul   %esi,%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  shr    $0x8,%edi
  and    $0xff00ff,%edi
  imul   %esi,%edi
  and    $0xff00ff00,%edi
  or     %edi,%eax
L7:
  ret
```

assistant: ```c
unsigned int premul_nozero(unsigned int val, unsigned char alpha) {
  if (alpha == 0xFF)
    return val;
  else
    return ((((val & 0x00FF00FF) * alpha) >> 8) & 0x00FF00FF) | ((((val & 0xFF00FF00) >> 8) * alpha) & 0xFF00FF00);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<premul_nozero>:
  endbr64
  mov    %edi,%eax
  cmp    $0xff,%sil
  je     L3
  mov    %edi,%edx
  movzbl %sil,%esi
  shr    $0x8,%eax
  and    $0xff00ff,%edx
  and    $0xff00ff,%eax
  imul   %esi,%edx
  imul   %esi,%eax
  shr    $0x8,%edx
  and    $0xff00ff,%edx
  and    $0xff00ff00,%eax
  or     %edx,%eax
L3:
  ret
```

assistant: ```c
unsigned int premul_nozero(unsigned int val, unsigned char alpha) {
  if (alpha == 0xFF)
    return val;
  else
    return ((((val & 0x00FF00FF) * alpha) >> 8) & 0x00FF00FF) | ((((val & 0xFF00FF00) >> 8) * alpha) & 0xFF00FF00);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<premul_nozero>:
  endbr64
  mov    %edi,%eax
  cmp    $0xff,%sil
  je     L6
  mov    %edi,%edx
  movzbl %sil,%esi
  shr    $0x8,%eax
  and    $0xff00ff,%edx
  and    $0xff00ff,%eax
  imul   %esi,%edx
  imul   %esi,%eax
  shr    $0x8,%edx
  and    $0xff00ff,%edx
  and    $0xff00ff00,%eax
  or     %edx,%eax
L6:
  ret
```

assistant: ```c
unsigned int premul_nozero(unsigned int val, unsigned char alpha) {
  if (alpha == 0xFF)
    return val;
  else
    return ((((val & 0x00FF00FF) * alpha) >> 8) & 0x00FF00FF) | ((((val & 0xFF00FF00) >> 8) * alpha) & 0xFF00FF00);
}
```
user: Translate the below assembly code into C programming language:

```asm
<op_smooth_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    -0x2(%rax),%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L24
  lea    D9(%rip),%rax
  mov    %rax,-0x40(%rbp)
L24:
  cmpl   $0x0,-0x14(%rbp)
  jle    L29
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D26(%rip),%r9
  mov    %esi,%r8d
  lea    D42(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L12
L29:
  mov    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L12:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x27,%edx
  mov    $0x1,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string
name: disassemble_data
arguments: data_label: D42
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string
name: disassemble_data
arguments: data_label: D39
type_guessed: string

tool: 

tool: D26:  

tool: D42: %s%s:%*s

tool: D0: %s%s: 

tool: D39: apply a smoothing filter (Hann window)


assistant: ```c
void op_smooth_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "apply a smoothing filter (Hann window)\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<op_smooth_short>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x2(%rbx),%eax
  sub    %edx,%eax
  test   %rbp,%rbp
  lea    D15(%rip),%rdx
  cmove  %rdx,%rbp
  test   %eax,%eax
  jle    L18
  lea    D8(%rip),%r9
  lea    0x1(%rax),%r8d
  mov    %r13,%rcx
  mov    %rbp,%rdx
  lea    D47(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L19:
  mov    %r12,%rcx
  mov    $0x27,%edx
  mov    $0x1,%esi
  lea    D38(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %r13,%rcx
  mov    %rbp,%rdx
  lea    D10(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string
name: extract_symbolic_data
arguments: data_label: D47
type_infered: string
name: extract_symbolic_data
arguments: data_label: D38
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string

tool: 

tool: D8:  

tool: D47: %s%s:%*s

tool: D38: apply a smoothing filter (Hann window)


tool: D10: %s%s: 

assistant: ```c
void op_smooth_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "apply a smoothing filter (Hann window)\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<op_smooth_short>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D44(%rip),%rdx
  mov    %eax,%r8d
  lea    -0x2(%rbx),%eax
  sub    %r8d,%eax
  test   %r12,%r12
  cmove  %rdx,%r12
  test   %eax,%eax
  jle    L14
  lea    0x1(%rax),%r8d
  lea    D48(%rip),%r9
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D5(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L6:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    $0x27,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D16(%rip),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <fwrite@plt>
L14:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D15(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: data_tag: D44
datatype: string
name: read_data
arguments: data_tag: D48
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string

tool: 

tool: D48:  

tool: D5: %s%s:%*s

tool: D16: apply a smoothing filter (Hann window)


tool: D15: %s%s: 

assistant: ```c
void op_smooth_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "apply a smoothing filter (Hann window)\n");
}
```