ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<ps_summary_unregister>:
  endbr64
  jmp    1050 <obus_server_unregister_object@plt>
```

assistant: ```c
int ps_summary_unregister(struct obus_server *server, struct ps_summary *object) {
  struct obus_object *obj = (struct obus_object *)object;
  return obus_server_unregister_object(server, obj);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rndu64_ranged>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <rndu64@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L24
  mov    -0x8(%rbp),%eax
  jmp    L12
L24:
  mov    -0x14(%rbp),%eax
  neg    %eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L47
  jmp    L22
L19:
  mov    $0x0,%eax
  call   <rndu64@plt>
  mov    %eax,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L19
L47:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
L12:
  leave
  ret
```

assistant: ```c
uint64_t rndu64_ranged(uint64_t range) {
  uint64_t max, r;
  r = rndu64();
  if (range == 0) {
    return r;
  }
  max = -(((uint64_t)-range) % range);
  if (max) {
    while (r >= max) {
      r = rndu64();
    }
  }
  return r % range;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rndu64_ranged>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <rndu64@plt>
  mov    %eax,%ecx
  test   %ebx,%ebx
  je     L30
  mov    %ebx,%eax
  neg    %eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L9
  neg    %edx
  mov    %edx,%ebp
  cmp    %edx,%ecx
  jl     L9
L14:
  mov    $0x0,%eax
  call   <rndu64@plt>
  mov    %eax,%ecx
  cmp    %eax,%ebp
  jle    L14
L9:
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  mov    %edx,%ecx
L30:
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t rndu64_ranged(uint64_t range) {
  uint64_t max, r;
  r = rndu64();
  if (range == 0) {
    return r;
  }
  max = -(((uint64_t)-range) % range);
  if (max) {
    while (r >= max) {
      r = rndu64();
    }
  }
  return r % range;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rndu64_ranged>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <rndu64@plt>
  mov    %eax,%r8d
  test   %ebx,%ebx
  je     L1
  mov    %ebx,%eax
  neg    %eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L30
  neg    %edx
  mov    %edx,%ebp
  cmp    %edx,%r8d
  jl     L30
  xchg   %ax,%ax
L10:
  xor    %eax,%eax
  call   <rndu64@plt>
  mov    %eax,%r8d
  cmp    %eax,%ebp
  jle    L10
L30:
  mov    %r8d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r8d
L1:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t rndu64_ranged(uint64_t range) {
  uint64_t max, r;
  r = rndu64();
  if (range == 0) {
    return r;
  }
  max = -(((uint64_t)-range) % range);
  if (max) {
    while (r >= max) {
      r = rndu64();
    }
  }
  return r % range;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rndu64_ranged>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <rndu64@plt>
  mov    %eax,%r8d
  test   %ebx,%ebx
  je     L39
  mov    %ebx,%eax
  neg    %eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L27
  neg    %edx
  mov    %edx,%ebp
  cmp    %edx,%r8d
  jl     L27
  xchg   %ax,%ax
L37:
  xor    %eax,%eax
  call   <rndu64@plt>
  mov    %eax,%r8d
  cmp    %eax,%ebp
  jle    L37
L27:
  mov    %r8d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r8d
L39:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t rndu64_ranged(uint64_t range) {
  uint64_t max, r;
  r = rndu64();
  if (range == 0) {
    return r;
  }
  max = -(((uint64_t)-range) % range);
  if (max) {
    while (r >= max) {
      r = rndu64();
    }
  }
  return r % range;
}
```
user: Translate the below assembly code into C programming language:

```asm
<build_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <pthread_rwlock_init@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_rwlock_rdlock@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_rwlock_unlock@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_rwlock_destroy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void build_check(void) {
  pthread_rwlock_t lock;
  pthread_rwlock_init(&lock, NULL);
  pthread_rwlock_rdlock(&lock);
  pthread_rwlock_unlock(&lock);
  pthread_rwlock_destroy(&lock);
}
```
user: What is the c source code of the assembly code below?

```asm
<build_check>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <pthread_rwlock_init@plt>
  mov    %rbx,%rdi
  call   <pthread_rwlock_rdlock@plt>
  mov    %rbx,%rdi
  call   <pthread_rwlock_unlock@plt>
  mov    %rbx,%rdi
  call   <pthread_rwlock_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void build_check(void) {
  pthread_rwlock_t lock;
  pthread_rwlock_init(&lock, NULL);
  pthread_rwlock_rdlock(&lock);
  pthread_rwlock_unlock(&lock);
  pthread_rwlock_destroy(&lock);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<build_check>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <pthread_rwlock_init@plt>
  mov    %rbp,%rdi
  call   <pthread_rwlock_rdlock@plt>
  mov    %rbp,%rdi
  call   <pthread_rwlock_unlock@plt>
  mov    %rbp,%rdi
  call   <pthread_rwlock_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void build_check(void) {
  pthread_rwlock_t lock;
  pthread_rwlock_init(&lock, NULL);
  pthread_rwlock_rdlock(&lock);
  pthread_rwlock_unlock(&lock);
  pthread_rwlock_destroy(&lock);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<build_check>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <pthread_rwlock_init@plt>
  mov    %rbp,%rdi
  call   <pthread_rwlock_rdlock@plt>
  mov    %rbp,%rdi
  call   <pthread_rwlock_unlock@plt>
  mov    %rbp,%rdi
  call   <pthread_rwlock_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void build_check(void) {
  pthread_rwlock_t lock;
  pthread_rwlock_init(&lock, NULL);
  pthread_rwlock_rdlock(&lock);
  pthread_rwlock_unlock(&lock);
  pthread_rwlock_destroy(&lock);
}
```
user: What is the c source code of the assembly code below?

```asm
<list_pop_back>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <list_back@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <list_remove@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct list_elem *list_pop_back(struct list *list) {
  struct list_elem *back = list_back(list);
  list_remove(back);
  return back;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<list_pop_back>:
  endbr64
  push   %rbx
  call   <list_back@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <list_remove@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
struct list_elem *list_pop_back(struct list *list) {
  struct list_elem *back = list_back(list);
  list_remove(back);
  return back;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_pop_back>:
  endbr64
  push   %r12
  call   <list_back@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <list_remove@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
struct list_elem *list_pop_back(struct list *list) {
  struct list_elem *back = list_back(list);
  list_remove(back);
  return back;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<list_pop_back>:
  endbr64
  push   %r12
  call   <list_back@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <list_remove@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
struct list_elem *list_pop_back(struct list *list) {
  struct list_elem *back = list_back(list);
  list_remove(back);
  return back;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<move_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rotate_clockwise@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rotate_clockwise@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <move_left@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rotate_clockwise@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rotate_clockwise@plt>
  nop
  leave
  ret
```

assistant: ```c
void move_right(struct game *game) {
  rotate_clockwise(game);
  rotate_clockwise(game);
  move_left(game);
  rotate_clockwise(game);
  rotate_clockwise(game);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<move_right>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <rotate_clockwise@plt>
  mov    %rbx,%rdi
  call   <rotate_clockwise@plt>
  mov    %rbx,%rdi
  call   <move_left@plt>
  mov    %rbx,%rdi
  call   <rotate_clockwise@plt>
  mov    %rbx,%rdi
  call   <rotate_clockwise@plt>
  pop    %rbx
  ret
```

assistant: ```c
void move_right(struct game *game) {
  rotate_clockwise(game);
  rotate_clockwise(game);
  move_left(game);
  rotate_clockwise(game);
  rotate_clockwise(game);
}
```
user: Translate the below assembly code into C programming language:

```asm
<move_right>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <rotate_clockwise@plt>
  mov    %rbp,%rdi
  call   <rotate_clockwise@plt>
  mov    %rbp,%rdi
  call   <move_left@plt>
  mov    %rbp,%rdi
  call   <rotate_clockwise@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <rotate_clockwise@plt>
```

assistant: ```c
void move_right(struct game *game) {
  rotate_clockwise(game);
  rotate_clockwise(game);
  move_left(game);
  rotate_clockwise(game);
  rotate_clockwise(game);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<move_right>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <rotate_clockwise@plt>
  mov    %rbp,%rdi
  call   <rotate_clockwise@plt>
  mov    %rbp,%rdi
  call   <move_left@plt>
  mov    %rbp,%rdi
  call   <rotate_clockwise@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <rotate_clockwise@plt>
```

assistant: ```c
void move_right(struct game *game) {
  rotate_clockwise(game);
  rotate_clockwise(game);
  move_left(game);
  rotate_clockwise(game);
  rotate_clockwise(game);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func2(void) {
  extern double *p;
  extern double *p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func2>:
  endbr64
  ret
```

assistant: ```c
void func2(void) {
  extern double *p;
  extern double *p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<func2>:
  endbr64
  ret
```

assistant: ```c
void func2(void) {
  extern double *p;
  extern double *p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<func2>:
  endbr64
  ret
```

assistant: ```c
void func2(void) {
  extern double *p;
  extern double *p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jne    L5
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <qrencode@plt>
L5:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 2) {
    qrencode(argv[1]);
  }
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L1
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  ret
L1:
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <qrencode@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 2) {
    qrencode(argv[1]);
  }
  return EXIT_SUCCESS;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L2
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  ret
L2:
  push   %rax
  mov    0x8(%rsi),%rdi
  call   <qrencode@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  pop    %rdx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 2) {
    qrencode(argv[1]);
  }
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L0
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  ret
L0:
  push   %rax
  mov    0x8(%rsi),%rdi
  call   <qrencode@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  pop    %rdx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 2) {
    qrencode(argv[1]);
  }
  return EXIT_SUCCESS;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getlogin@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L1
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int main(void) {
  char *lname = getlogin();
  if (!lname)
    return 1;
  puts(lname);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getlogin@plt>
  mov    %rax,%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L3
  call   <puts@plt>
  mov    $0x0,%eax
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *lname = getlogin();
  if (!lname)
    return 1;
  puts(lname);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getlogin@plt>
  mov    %rax,%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L8
  call   <puts@plt>
  xor    %eax,%eax
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *lname = getlogin();
  if (!lname)
    return 1;
  puts(lname);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getlogin@plt>
  mov    %rax,%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L0
  call   <puts@plt>
  xor    %eax,%eax
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *lname = getlogin();
  if (!lname)
    return 1;
  puts(lname);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setcelltype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L25
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1f,%ah
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  or     $0x10,%ah
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L23
L25:
  cmpl   $0x1,-0xc(%rbp)
  jne    L23
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    $0x2f,%ah
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  or     $0x20,%ah
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L23:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setcelltype(int *flag, int type) {
  if (type == 0) {
    *flag = *flag & (~57344);
    *flag = *flag | 4096;
  } else if (type == 1) {
    *flag = *flag & (~53248);
    *flag = *flag | 8192;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setcelltype>:
  endbr64
  test   %esi,%esi
  jne    L1
  mov    (%rdi),%eax
  and    $0x1f,%ah
  or     $0x10,%ah
  mov    %eax,(%rdi)
  ret
L1:
  cmp    $0x1,%esi
  je     L8
L19:
  ret
L8:
  mov    (%rdi),%eax
  and    $0x2f,%ah
  or     $0x20,%ah
  mov    %eax,(%rdi)
  jmp    L19
```

assistant: ```c
void setcelltype(int *flag, int type) {
  if (type == 0) {
    *flag = *flag & (~57344);
    *flag = *flag | 4096;
  } else if (type == 1) {
    *flag = *flag & (~53248);
    *flag = *flag | 8192;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<setcelltype>:
  endbr64
  test   %esi,%esi
  jne    L14
  mov    (%rdi),%eax
  and    $0x1f,%ah
  or     $0x10,%ah
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  cmp    $0x1,%esi
  je     L15
  ret
  xchg   %ax,%ax
L15:
  mov    (%rdi),%eax
  and    $0x2f,%ah
  or     $0x20,%ah
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void setcelltype(int *flag, int type) {
  if (type == 0) {
    *flag = *flag & (~57344);
    *flag = *flag | 4096;
  } else if (type == 1) {
    *flag = *flag & (~53248);
    *flag = *flag | 8192;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setcelltype>:
  endbr64
  test   %esi,%esi
  jne    L16
  mov    (%rdi),%eax
  and    $0x1f,%ah
  or     $0x10,%ah
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  cmp    $0x1,%esi
  je     L1
  ret
  xchg   %ax,%ax
L1:
  mov    (%rdi),%eax
  and    $0x2f,%ah
  or     $0x20,%ah
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void setcelltype(int *flag, int type) {
  if (type == 0) {
    *flag = *flag & (~57344);
    *flag = *flag | 4096;
  } else if (type == 1) {
    *flag = *flag & (~53248);
    *flag = *flag | 8192;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<residuals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  -0x30(%rbp),%xmm1
  addsd  -0x38(%rbp),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void residuals(const double *x, const double *y, int n, double slope, double intcp, double *res) {
  for (int i = 0; i < n; i++) {
    res[i] = y[i] - (intcp + (slope * x[i]));
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<residuals>:
  endbr64
  test   %edx,%edx
  jle    L18
  mov    %edx,%edx
  mov    $0x0,%eax
L5:
  movapd %xmm0,%xmm3
  mulsd  (%rdi,%rax,8),%xmm3
  addsd  %xmm1,%xmm3
  movsd  (%rsi,%rax,8),%xmm2
  subsd  %xmm3,%xmm2
  movsd  %xmm2,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L18:
  ret
```

assistant: ```c
void residuals(const double *x, const double *y, int n, double slope, double intcp, double *res) {
  for (int i = 0; i < n; i++) {
    res[i] = y[i] - (intcp + (slope * x[i]));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<residuals>:
  endbr64
  test   %edx,%edx
  jle    L9
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L8:
  movsd  (%rdi,%rax,8),%xmm3
  movsd  (%rsi,%rax,8),%xmm2
  mulsd  %xmm0,%xmm3
  addsd  %xmm1,%xmm3
  subsd  %xmm3,%xmm2
  movsd  %xmm2,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L8
L9:
  ret
```

assistant: ```c
void residuals(const double *x, const double *y, int n, double slope, double intcp, double *res) {
  for (int i = 0; i < n; i++) {
    res[i] = y[i] - (intcp + (slope * x[i]));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<residuals>:
  endbr64
  mov    %edx,%r8d
  movapd %xmm1,%xmm4
  mov    %rcx,%rdx
  test   %r8d,%r8d
  jle    L57
  lea    0x8(%rdi),%rax
  cmp    %rax,%rcx
  lea    0x8(%rsi),%rax
  setne  %cl
  cmp    %rax,%rdx
  setne  %al
  test   %al,%cl
  je     L37
  lea    -0x1(%r8),%eax
  cmp    $0x1,%eax
  jbe    L37
  mov    %r8d,%ecx
  movapd %xmm0,%xmm5
  unpcklpd %xmm1,%xmm1
  xor    %eax,%eax
  shr    %ecx
  unpcklpd %xmm5,%xmm5
  shl    $0x4,%rcx
  nop
L44:
  movupd (%rdi,%rax,1),%xmm2
  movupd (%rsi,%rax,1),%xmm3
  mulpd  %xmm5,%xmm2
  addpd  %xmm1,%xmm2
  subpd  %xmm2,%xmm3
  movups %xmm3,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L44
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r8d
  je     L57
  mulsd  (%rdi,%rax,8),%xmm0
  movapd %xmm0,%xmm1
  movsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm4,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L50:
  movsd  (%rdi,%rax,8),%xmm2
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm2
  addsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L50
L57:
  ret
```

assistant: ```c
void residuals(const double *x, const double *y, int n, double slope, double intcp, double *res) {
  for (int i = 0; i < n; i++) {
    res[i] = y[i] - (intcp + (slope * x[i]));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(char *str) {
  perror(str);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die(char *str) {
  perror(str);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void die(char *str) {
  perror(str);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void die(char *str) {
  perror(str);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  jne    L29
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L24
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  jmp    L1
L24:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L1
L29:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: shell: Error

assistant: ```c
int read_line(FILE *stream, char *buf) {
  if (!fgets(buf, 1024, stream)) {
    if (feof(stream)) {
      putchar('\n');
      return 0;
    } else {
      perror("shell: Error");
      return -1;
    }
  }
  return strlen(buf);
}
```