ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_result>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  movsbl (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1e(%rsp),%r12
  cmp    $0x3d,%dil
  je     L10
  lea    0xa(%rsp),%r13
  nopl   0x0(%rax)
L129:
  call   <isdigit@plt>
  test   %rax,%rax
  je     L77
  movzbl (%rbx),%edx
  movsbl 0x1(%rbx),%edi
  movslq %r14d,%rax
  add    $0x1,%rbx
  add    $0x1,%r14d
  mov    %dl,0x1e(%rsp,%rax,1)
  cmp    $0x3d,%dil
  jne    L129
L10:
  lea    0x14(%rsp),%r13
  movslq %r14d,%r14
  mov    %r12,%rsi
  mov    %r13,%rdi
  movb   $0x0,0x1e(%rsp,%r14,1)
  call   <strcpy@plt>
  cmp    $0x2d,%bpl
  je     L41
  jg     L117
  cmp    $0x2a,%bpl
  je     L0
  cmp    $0x2b,%bpl
  jne    L134
  lea    0xa(%rsp),%rdi
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <atoi@plt>
  add    %ebx,%eax
  nopl   0x0(%rax)
L134:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L94
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L77:
  movslq %r14d,%r14
  mov    %r13,%rdi
  mov    %r12,%rsi
  add    $0x1,%rbx
  movb   $0x0,0x1e(%rsp,%r14,1)
  xor    %r14d,%r14d
  call   <strcpy@plt>
  movzbl -0x1(%rbx),%ebp
  movsbl (%rbx),%edi
  cmp    $0x3d,%dil
  jne    L129
  jmp    L10
  nopl   0x0(%rax)
L117:
  cmp    $0x2f,%bpl
  jne    L134
  lea    0xa(%rsp),%rdi
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <atoi@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  jmp    L134
  nopl   0x0(%rax,%rax,1)
L41:
  lea    0xa(%rsp),%rdi
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <atoi@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  sub    %r8d,%eax
  jmp    L134
  nopl   0x0(%rax)
L0:
  lea    0xa(%rsp),%rdi
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <atoi@plt>
  imul   %ebx,%eax
  jmp    L134
L94:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_result(char buffer[2000]) {
  char left[10];
  char right[10];
  char temp[10];
  int index = 0;
  char operator;
  for (int x = 0; buffer[x] != '='; x++) {
    if (isdigit(buffer[x])) {
      temp[index] = buffer[x];
      index++;
    } else {
      temp[index] = '\0';
      index = 0;
      strcpy(left, temp);
      operator= buffer[x];
    }
  }
  temp[index] = '\0';
  strcpy(right, temp);
  switch (operator) {
  case '+':
    return atoi(left) + atoi(right);
  case '-':
    return atoi(left) - atoi(right);
  case '*':
    return atoi(left) * atoi(right);
  case '/':
    return atoi(left) / atoi(right);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fact_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L7:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L6:
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fact_2(int a) {
  unsigned i = 1;
  while (a)
    i *= a--;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fact_2>:
  endbr64
  test   %edi,%edi
  je     L18
  mov    $0x1,%eax
L1:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L1
  ret
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fact_2(int a) {
  unsigned i = 1;
  while (a)
    i *= a--;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fact_2>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L15
  nopl   (%rax)
L7:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L7
  ret
  nopl   0x0(%rax)
L15:
  ret
```

assistant: ```c
int fact_2(int a) {
  unsigned i = 1;
  while (a)
    i *= a--;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fact_2>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L6
  nopl   (%rax)
L18:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L18
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
int fact_2(int a) {
  unsigned i = 1;
  while (a)
    i *= a--;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  orq    $0x1,-0x8(%rbp)
  jmp    L18
L5:
  addq   $0x2,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L5
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t next_prime(size_t seed) {
  seed |= 1;
  while (!is_prime(seed))
    seed += 2;
  return seed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<next_prime>:
  endbr64
  push   %rbx
  or     $0x1,%rdi
  mov    %rdi,%rbx
  jmp    L6
L9:
  add    $0x2,%rbx
L6:
  mov    %rbx,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L9
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t next_prime(size_t seed) {
  seed |= 1;
  while (!is_prime(seed))
    seed += 2;
  return seed;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<next_prime>:
  endbr64
  or     $0x1,%rdi
  push   %r12
  mov    %rdi,%r12
  jmp    L17
  nop
L1:
  add    $0x2,%r12
L17:
  mov    %r12,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L1
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t next_prime(size_t seed) {
  seed |= 1;
  while (!is_prime(seed))
    seed += 2;
  return seed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_prime>:
  endbr64
  or     $0x1,%rdi
  push   %r12
  mov    %rdi,%r12
  jmp    L17
  nop
L3:
  add    $0x2,%r12
L17:
  mov    %r12,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L3
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t next_prime(size_t seed) {
  seed |= 1;
  while (!is_prime(seed))
    seed += 2;
  return seed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Xchomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <Xstrlen@plt>
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L129
  mov    -0x10(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  jmp    L104
L129:
  movl   $0x0,-0x18(%rbp)
  jmp    L116
L113:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <XchompConvert@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x20,-0x8(%rbp)
  jne    L18
  cmpl   $0x0,-0x1c(%rbp)
  jne    L121
L18:
  cmpq   $0x20,-0x8(%rbp)
  je     L45
  cmpq   $0xa,-0x8(%rbp)
  jne    L11
L45:
  movl   $0x1,-0x1c(%rbp)
  jmp    L71
L11:
  movl   $0x0,-0x1c(%rbp)
L71:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L12
L121:
  nop
L12:
  addl   $0x1,-0x18(%rbp)
L116:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L113
  jmp    L61
L51:
  subl   $0x1,-0x14(%rbp)
L61:
  cmpl   $0x0,-0x14(%rbp)
  jle    L37
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    $0x20,%rax
  je     L51
L37:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
L104:
  leave
  ret
```

assistant: ```c
XML_Char *Xchomp(const XML_Char *a) {
  XML_Char *result = malloc(sizeof(XML_Char) * (Xstrlen(a) + 1));
  int ignoreSpaces = 1;
  int x;
  int pos = 0;
  if (a == NULL) {
    result[0] = 0;
    return result;
  }
  for (x = 0; a[x] != 0; x++) {
    XML_Char c = XchompConvert(a[x]);
    if (c == ' ' && ignoreSpaces)
      continue;
    if (c == ' ' || c == '\n')
      ignoreSpaces = 1;
    else
      ignoreSpaces = 0;
    result[pos++] = c;
  }
  while (pos > 0 && result[pos - 1] == ' ')
    pos--;
  result[pos] = 0;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Xchomp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  call   <Xstrlen@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13,%r13
  je     L74
  mov    0x0(%r13),%rdi
  add    $0x8,%r13
  mov    $0x0,%ebx
  mov    $0x1,%ebp
  test   %rdi,%rdi
  jne    L19
  jmp    L103
L74:
  movq   $0x0,(%rax)
  jmp    L39
L65:
  cmp    $0xa,%rax
  sete   %bpl
  or     %edx,%ebp
  movzbl %bpl,%ebp
  movslq %ebx,%rdx
  mov    %rax,(%r12,%rdx,8)
  lea    0x1(%rbx),%ebx
L76:
  add    $0x8,%r13
  mov    -0x8(%r13),%rdi
  test   %rdi,%rdi
  je     L28
L19:
  call   <XchompConvert@plt>
  cmp    $0x20,%rax
  sete   %dl
  test   %ebp,%ebp
  je     L65
  test   %dl,%dl
  je     L65
  jmp    L76
L28:
  test   %ebx,%ebx
  jle    L103
  movslq %ebx,%rax
  lea    (%r12,%rax,8),%rax
L10:
  cmpq   $0x20,-0x8(%rax)
  jne    L103
  sub    $0x8,%rax
  sub    $0x1,%ebx
  jne    L10
L103:
  movslq %ebx,%rbx
  movq   $0x0,(%r12,%rbx,8)
L39:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
XML_Char *Xchomp(const XML_Char *a) {
  XML_Char *result = malloc(sizeof(XML_Char) * (Xstrlen(a) + 1));
  int ignoreSpaces = 1;
  int x;
  int pos = 0;
  if (a == NULL) {
    result[0] = 0;
    return result;
  }
  for (x = 0; a[x] != 0; x++) {
    XML_Char c = XchompConvert(a[x]);
    if (c == ' ' && ignoreSpaces)
      continue;
    if (c == ' ' || c == '\n')
      ignoreSpaces = 1;
    else
      ignoreSpaces = 0;
    result[pos++] = c;
  }
  while (pos > 0 && result[pos - 1] == ' ')
    pos--;
  result[pos] = 0;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Xchomp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <Xstrlen@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L41
  mov    0x0(%rbp),%rdi
  xor    %r13d,%r13d
  add    $0x8,%rbp
  mov    $0x1,%ebx
  test   %rdi,%rdi
  je     L15
  nopw   0x0(%rax,%rax,1)
L48:
  call   <XchompConvert@plt>
  cmp    $0x20,%rax
  sete   %dl
  test   %ebx,%ebx
  je     L23
  mov    $0x1,%ebx
  test   %dl,%dl
  jne    L19
L23:
  cmp    $0xa,%rax
  sete   %bl
  or     %edx,%ebx
  movslq %r13d,%rdx
  add    $0x1,%r13d
  mov    %rax,(%r12,%rdx,8)
  movzbl %bl,%ebx
L19:
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  test   %rdi,%rdi
  jne    L48
  test   %r13d,%r13d
  je     L15
  movslq %r13d,%rcx
  lea    -0x1(%r13),%edx
  lea    0x0(,%rcx,8),%rax
  sub    %rdx,%rcx
  shl    $0x3,%rcx
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L84:
  lea    -0x8(%rax),%rdx
  cmp    %rax,%rcx
  je     L15
  mov    %rdx,%rax
L60:
  cmpq   $0x20,-0x8(%r12,%rax,1)
  je     L84
  add    %r12,%rax
L86:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  mov    %r12,%rax
  jmp    L86
  nopl   (%rax)
L41:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
XML_Char *Xchomp(const XML_Char *a) {
  XML_Char *result = malloc(sizeof(XML_Char) * (Xstrlen(a) + 1));
  int ignoreSpaces = 1;
  int x;
  int pos = 0;
  if (a == NULL) {
    result[0] = 0;
    return result;
  }
  for (x = 0; a[x] != 0; x++) {
    XML_Char c = XchompConvert(a[x]);
    if (c == ' ' && ignoreSpaces)
      continue;
    if (c == ' ' || c == '\n')
      ignoreSpaces = 1;
    else
      ignoreSpaces = 0;
    result[pos++] = c;
  }
  while (pos > 0 && result[pos - 1] == ' ')
    pos--;
  result[pos] = 0;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Xchomp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <Xstrlen@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L119
  mov    0x0(%rbp),%rdi
  xor    %r12d,%r12d
  add    $0x8,%rbp
  mov    $0x1,%ebx
  test   %rdi,%rdi
  je     L65
  nopw   0x0(%rax,%rax,1)
L56:
  call   <XchompConvert@plt>
  cmp    $0x20,%rax
  sete   %dl
  test   %ebx,%ebx
  je     L94
L99:
  test   %dl,%dl
  je     L94
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  test   %rdi,%rdi
  je     L93
  call   <XchompConvert@plt>
  mov    $0x1,%ebx
  cmp    $0x20,%rax
  sete   %dl
  test   %ebx,%ebx
  jne    L99
  cs nopw 0x0(%rax,%rax,1)
L94:
  cmp    $0xa,%rax
  mov    %rax,0x0(%r13,%r12,8)
  sete   %bl
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  or     %edx,%ebx
  lea    0x1(%r12),%edx
  movzbl %bl,%ebx
  test   %rdi,%rdi
  je     L102
  movslq %edx,%r12
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L93:
  test   %r12d,%r12d
  je     L65
  mov    %r12d,%edx
L102:
  movslq %edx,%rcx
  sub    $0x1,%edx
  lea    0x0(,%rcx,8),%rax
  sub    %rdx,%rcx
  shl    $0x3,%rcx
  jmp    L37
  nop
L92:
  lea    -0x8(%rax),%rdx
  cmp    %rax,%rcx
  je     L65
  mov    %rdx,%rax
L37:
  cmpq   $0x20,-0x8(%r13,%rax,1)
  je     L92
  add    %r13,%rax
L96:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L65:
  mov    %r13,%rax
  jmp    L96
  nopl   (%rax)
L119:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
XML_Char *Xchomp(const XML_Char *a) {
  XML_Char *result = malloc(sizeof(XML_Char) * (Xstrlen(a) + 1));
  int ignoreSpaces = 1;
  int x;
  int pos = 0;
  if (a == NULL) {
    result[0] = 0;
    return result;
  }
  for (x = 0; a[x] != 0; x++) {
    XML_Char c = XchompConvert(a[x]);
    if (c == ' ' && ignoreSpaces)
      continue;
    if (c == ' ' || c == '\n')
      ignoreSpaces = 1;
    else
      ignoreSpaces = 0;
    result[pos++] = c;
  }
  while (pos > 0 && result[pos - 1] == ' ')
    pos--;
  result[pos] = 0;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_last_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L35
L10:
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L37
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L35
L37:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <strdup@plt>
L35:
  leave
  ret
```

assistant: ```c
unsigned char *get_last_name(const unsigned char *str) {
  if (!str)
    return 0;
  char *p = strrchr(str, '/');
  if (!p)
    return strdup(str);
  return strdup(p + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_last_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L12
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L19
  lea    0x1(%rax),%rdi
  call   <strdup@plt>
L14:
  pop    %rbx
  ret
L19:
  mov    %rbx,%rdi
  call   <strdup@plt>
  jmp    L14
L12:
  mov    %rdi,%rax
  jmp    L14
```

assistant: ```c
unsigned char *get_last_name(const unsigned char *str) {
  if (!str)
    return 0;
  char *p = strrchr(str, '/');
  if (!p)
    return strdup(str);
  return strdup(p + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_last_name>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L17
  lea    0x1(%rax),%rdi
  pop    %rbp
  jmp    1070 <strdup@plt>
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <strdup@plt>
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *get_last_name(const unsigned char *str) {
  if (!str)
    return 0;
  char *p = strrchr(str, '/');
  if (!p)
    return strdup(str);
  return strdup(p + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_last_name>:
  endbr64
  test   %rdi,%rdi
  je     L17
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L15
  lea    0x1(%rax),%rdi
  pop    %rbp
  jmp    1070 <strdup@plt>
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <strdup@plt>
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *get_last_name(const unsigned char *str) {
  if (!str)
    return 0;
  char *p = strrchr(str, '/');
  if (!p)
    return strdup(str);
  return strdup(p + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x3,%rax
  or     $0x61bab5,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L18
L11:
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shr    $0x3,%rax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x1a(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  add    $0x4,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,%rdx
  movzwl -0x1a(%rbp),%eax
  mov    %ax,(%rdx)
  addq   $0x2,-0x18(%rbp)
L18:
  cmpq   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x10(%rbp),%rax
  or     $0x369937ec,%rax
  xor    $0x1c3473e5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] <<= ((state[0UL] >> 3UL) & 7UL) | 1UL;
      copy11 = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 916010988UL) ^ 473199589UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  shr    $0x3,%rax
  or     $0x61bab5,%rax
  shl    $0x7,%rax
  mov    %rax,%rcx
  shr    $0x20,%rcx
  movzwl %ax,%edx
  shl    $0x20,%rdx
  movabs $0xffff0000ffffffff,%rdi
  and    %rdi,%rax
  or     %rdx,%rax
  mov    %cx,%ax
  or     $0x369937ec,%rax
  xor    $0x1c3473e5,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] <<= ((state[0UL] >> 3UL) & 7UL) | 1UL;
      copy11 = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 916010988UL) ^ 473199589UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movabs $0xffff0000ffffffff,%rdx
  mov    (%rdi),%rax
  shr    $0x3,%rax
  shl    $0x7,%rax
  or     $0x30dd5a80,%rax
  movzwl %ax,%ecx
  and    %rax,%rdx
  shr    $0x20,%rax
  shl    $0x20,%rcx
  or     %rcx,%rdx
  mov    %ax,%dx
  or     $0x369937ec,%rdx
  xor    $0x1c3473e5,%rdx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] <<= ((state[0UL] >> 3UL) & 7UL) | 1UL;
      copy11 = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 916010988UL) ^ 473199589UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movabs $0xffff0000ffffffff,%rdx
  mov    (%rdi),%rax
  shr    $0x3,%rax
  shl    $0x7,%rax
  or     $0x30dd5a80,%rax
  movzwl %ax,%ecx
  and    %rax,%rdx
  shr    $0x20,%rax
  shl    $0x20,%rcx
  or     %rcx,%rdx
  mov    %ax,%dx
  or     $0x369937ec,%rdx
  xor    $0x1c3473e5,%rdx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] <<= ((state[0UL] >> 3UL) & 7UL) | 1UL;
      copy11 = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = copy11;
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 916010988UL) ^ 473199589UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<xwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L9
  mov    -0xc(%rbp),%eax
  jmp    L25
L9:
  mov    -0xc(%rbp),%eax
  cltq
  sub    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L26
  mov    -0x28(%rbp),%rax
L25:
  leave
  ret
```

assistant: ```c
ssize_t xwrite(int fd, const char *s, size_t nmemb) {
  ssize_t r;
  size_t n;
  n = nmemb;
  do {
    r = write(fd, s, n);
    if (r == -1)
      return r;
    n -= r;
    s += r;
  } while (n);
  return nmemb;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xwrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rdx,%rbx
L5:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L2
  cltq
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L5
  mov    %r13d,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t xwrite(int fd, const char *s, size_t nmemb) {
  ssize_t r;
  size_t n;
  n = nmemb;
  do {
    r = write(fd, s, n);
    if (r == -1)
      return r;
    n -= r;
    s += r;
  } while (n);
  return nmemb;
}
```