ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L70
L6:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L22
L81:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L22:
  cmpl   $0xf,-0x10(%rbp)
  jle    L81
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L30:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x2c(%rbp)
  jg     L38
  movl   $0x5a,-0xc(%rbp)
L38:
  cmpl   $0x1f,-0xc(%rbp)
  jle    L10
  cmpl   $0x7a,-0xc(%rbp)
  jg     L10
  mov    -0xc(%rbp),%eax
  jmp    L18
L10:
  mov    $0x2e,%eax
L18:
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L27:
  cmpl   $0xf,-0x10(%rbp)
  jle    L30
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x10,-0x14(%rbp)
L70:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string
name: retrieve_data
arguments: data_label: D18
type_guessed: string

tool: D9: %.5x 

tool: D3: %.2x 

tool: D18:   

assistant: ```c
void dump(const void *buf, int len) {
  int i, j, c;
  const uint8_t *pb = buf;
  for (i = 0; i < len; i += 16) {
    printf("%.5x ", i);
    for (j = 0; j < 16; j++) {
      printf("%.2x ", pb[i + j]);
    }
    printf("  ");
    for (j = 0; j < 16; j++) {
      c = pb[i + j];
      if (i + j >= len)
        c = 'Z';
      printf("%c", (c < ' ' || c > 'z') ? '.' : c);
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dump>:
  endbr64
  test   %esi,%esi
  jle    L39
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%r13d
  lea    0x40(%rdi),%r12
  lea    -0x1(%rsi),%eax
  and    $0xfffffff0,%eax
  add    $0x10,%eax
  mov    %eax,0xc(%rsp)
  movl   $0x0,0x8(%rsp)
  lea    D28(%rip),%r14
  mov    $0x2e,%r15d
  jmp    L57
L2:
  mov    $0x5a,%edi
L29:
  call   <putchar@plt>
  add    $0x4,%rbx
  add    $0x1,%ebp
  cmp    %r12,%rbx
  je     L43
L7:
  mov    (%rbx),%edi
  cmp    %ebp,%r13d
  jle    L2
  lea    -0x20(%rdi),%eax
  cmp    $0x5b,%eax
  cmovae %r15d,%edi
  jmp    L29
L43:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x10,0x8(%rsp)
  mov    0x8(%rsp),%eax
  add    $0x40,%r12
  cmp    0xc(%rsp),%eax
  je     L69
L57:
  mov    0x8(%rsp),%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%r12),%rbx
  mov    %rbx,%rbp
L33:
  mov    0x0(%rbp),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L33
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%ebp
  jmp    L7
L69:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
type_guessed: string
name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D7
type_guessed: string

tool: D28: %.2x 

tool: D10: %.5x 

tool: D7:   

assistant: ```c
void dump(const void *buf, int len) {
  int i, j, c;
  const uint8_t *pb = buf;
  for (i = 0; i < len; i += 16) {
    printf("%.5x ", i);
    for (j = 0; j < 16; j++) {
      printf("%.2x ", pb[i + j]);
    }
    printf("  ");
    for (j = 0; j < 16; j++) {
      c = pb[i + j];
      if (i + j >= len)
        c = 'Z';
      printf("%c", (c < ' ' || c > 'z') ? '.' : c);
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dump>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  and    $0xfffffff0,%eax
  mov    $0x2e,%r14d
  push   %r13
  add    $0x10,%eax
  lea    D12(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    0x40(%rdi),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  movl   $0x0,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L6:
  mov    0x8(%rsp),%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  lea    -0x40(%rbp),%rbx
  mov    %rbx,%r15
  call   <printf@plt>
  nopl   0x0(%rax)
L12:
  mov    (%r15),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbp,%r15
  jne    L12
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r15d
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L4:
  lea    -0x20(%rdi),%eax
  cmp    $0x5b,%eax
  cmovae %r14d,%edi
L63:
  call   <putchar@plt>
  add    $0x4,%rbx
  add    $0x1,%r15d
  cmp    %rbp,%rbx
  je     L19
L59:
  mov    (%rbx),%edi
  cmp    %r15d,%r12d
  jg     L4
  mov    $0x5a,%edi
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0xa,%edi
  add    $0x40,%rbp
  call   <putchar@plt>
  addl   $0x10,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    0xc(%rsp),%eax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D12: %.2x 

tool: D28: %.5x 

tool: D7:   

assistant: ```c
void dump(const void *buf, int len) {
  int i, j, c;
  const uint8_t *pb = buf;
  for (i = 0; i < len; i += 16) {
    printf("%.5x ", i);
    for (j = 0; j < 16; j++) {
      printf("%.2x ", pb[i + j]);
    }
    printf("  ");
    for (j = 0; j < 16; j++) {
      c = pb[i + j];
      if (i + j >= len)
        c = 'Z';
      printf("%c", (c < ' ' || c > 'z') ? '.' : c);
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dump>:
  endbr64
  test   %esi,%esi
  jle    L13
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  and    $0xfffffff0,%eax
  mov    $0x2e,%r14d
  push   %r13
  add    $0x10,%eax
  lea    D22(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    0x40(%rdi),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  movl   $0x0,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L16:
  mov    0x8(%rsp),%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  lea    -0x40(%rbp),%rbx
  mov    %rbx,%r15
  call   <printf@plt>
  nopl   0x0(%rax)
L68:
  mov    (%r15),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbp,%r15
  jne    L68
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r15d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L31:
  lea    -0x20(%rdi),%eax
  cmp    $0x5b,%eax
  cmovae %r14d,%edi
L11:
  call   <putchar@plt>
  add    $0x4,%rbx
  add    $0x1,%r15d
  cmp    %rbp,%rbx
  je     L15
L49:
  mov    (%rbx),%edi
  cmp    %r12d,%r15d
  jl     L31
  mov    $0x5a,%edi
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0xa,%edi
  add    $0x40,%rbp
  call   <putchar@plt>
  addl   $0x10,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    0xc(%rsp),%eax
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D10
data_type: string

tool: D22: %.2x 

tool: D1: %.5x 

tool: D10:   

assistant: ```c
void dump(const void *buf, int len) {
  int i, j, c;
  const uint8_t *pb = buf;
  for (i = 0; i < len; i += 16) {
    printf("%.5x ", i);
    for (j = 0; j < 16; j++) {
      printf("%.2x ", pb[i + j]);
    }
    printf("  ");
    for (j = 0; j < 16; j++) {
      c = pb[i + j];
      if (i + j >= len)
        c = 'Z';
      printf("%c", (c < ' ' || c > 'z') ? '.' : c);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rax
  mov    $0x0,%ebx
  mov    $0x40000000,%r12d
L5:
  lea    (%rbx,%r12,1),%r13
  cmp    %rax,%r13
  ja     L25
  sub    %r13,%rax
  lea    0x0(%r13,%r12,1),%rbx
L25:
  shr    %rbx
  shr    $0x2,%r12
  test   %r12,%r12
  jne    L5
  cmp    %rbx,%rax
  jbe    L16
  add    $0x1,%rbx
L16:
  mov    %rbx,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
long isqrt(register unsigned long x) {
  register unsigned long r, nr, m;
  r = 0;
  m = 0x40000000;
  do {
    nr = r + m;
    if (nr <= x) {
      x -= nr;
      r = nr + m;
    }
    r >>= 1;
    m >>= 2;
  } while (m != 0);
  if (x > r)
    r += 1;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isqrt>:
  endbr64
  mov    $0x10,%ecx
  mov    $0x40000000,%edx
  mov    $0x0,%eax
  jmp    L28
L38:
  sub    %rsi,%rdi
  lea    (%rdx,%rsi,1),%rax
L31:
  shr    %rax
  shr    $0x2,%rdx
  sub    $0x1,%ecx
  je     L4
L28:
  lea    (%rax,%rdx,1),%rsi
  cmp    %rsi,%rdi
  jb     L31
  jmp    L38
L4:
  cmp    %rdi,%rax
  adc    $0x0,%rax
  ret
```

assistant: ```c
long isqrt(register unsigned long x) {
  register unsigned long r, nr, m;
  r = 0;
  m = 0x40000000;
  do {
    nr = r + m;
    if (nr <= x) {
      x -= nr;
      r = nr + m;
    }
    r >>= 1;
    m >>= 2;
  } while (m != 0);
  if (x > r)
    r += 1;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isqrt>:
  endbr64
  mov    $0x10,%ecx
  mov    $0x40000000,%edx
  xor    %eax,%eax
L18:
  lea    (%rax,%rdx,1),%rsi
  cmp    %rsi,%rdi
  jb     L11
  sub    %rsi,%rdi
  lea    (%rdx,%rsi,1),%rax
L11:
  shr    %rax
  shr    $0x2,%rdx
  sub    $0x1,%ecx
  jne    L18
  cmp    %rdi,%rax
  adc    $0x0,%rax
  ret
```

assistant: ```c
long isqrt(register unsigned long x) {
  register unsigned long r, nr, m;
  r = 0;
  m = 0x40000000;
  do {
    nr = r + m;
    if (nr <= x) {
      x -= nr;
      r = nr + m;
    }
    r >>= 1;
    m >>= 2;
  } while (m != 0);
  if (x > r)
    r += 1;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isqrt>:
  endbr64
  mov    %rdi,%rdx
  xor    %eax,%eax
  cmp    $0x3fffffff,%rdi
  jbe    L124
  sub    $0x40000000,%rdx
  mov    $0x80000000,%eax
L124:
  shr    %rax
  lea    0x10000000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L12
  sub    %rcx,%rdx
  add    $0x20000000,%rax
L12:
  shr    %rax
  lea    0x4000000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L67
  sub    %rcx,%rdx
  add    $0x8000000,%rax
L67:
  shr    %rax
  lea    0x1000000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L66
  sub    %rcx,%rdx
  add    $0x2000000,%rax
L66:
  shr    %rax
  lea    0x400000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L6
  sub    %rcx,%rdx
  add    $0x800000,%rax
L6:
  shr    %rax
  lea    0x100000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L48
  sub    %rcx,%rdx
  add    $0x200000,%rax
L48:
  shr    %rax
  lea    0x40000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L125
  sub    %rcx,%rdx
  add    $0x80000,%rax
L125:
  shr    %rax
  lea    0x10000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L9
  sub    %rcx,%rdx
  add    $0x20000,%rax
L9:
  shr    %rax
  lea    0x4000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L61
  sub    %rcx,%rdx
  add    $0x8000,%rax
L61:
  shr    %rax
  lea    0x1000(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L98
  sub    %rcx,%rdx
  add    $0x2000,%rax
L98:
  shr    %rax
  lea    0x400(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L81
  sub    %rcx,%rdx
  add    $0x800,%rax
L81:
  shr    %rax
  lea    0x100(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L136
  sub    %rcx,%rdx
  add    $0x200,%rax
L136:
  shr    %rax
  lea    0x40(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L97
  sub    %rcx,%rdx
  sub    $0xffffffffffffff80,%rax
L97:
  shr    %rax
  lea    0x10(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L102
  sub    %rcx,%rdx
  add    $0x20,%rax
L102:
  shr    %rax
  lea    0x4(%rax),%rcx
  cmp    %rcx,%rdx
  jb     L90
  sub    %rcx,%rdx
  add    $0x8,%rax
L90:
  shr    %rax
  lea    0x1(%rax),%rcx
  cmp    %rdx,%rcx
  ja     L26
  sub    %rcx,%rdx
  add    $0x2,%rax
L26:
  shr    %rax
  cmp    %rdx,%rax
  adc    $0x0,%rax
  ret
```

assistant: ```c
long isqrt(register unsigned long x) {
  register unsigned long r, nr, m;
  r = 0;
  m = 0x40000000;
  do {
    nr = r + m;
    if (nr <= x) {
      x -= nr;
      r = nr + m;
    }
    r >>= 1;
    m >>= 2;
  } while (m != 0);
  if (x > r)
    r += 1;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cubew_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L17
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
char *cubew_strdup(const char *str) {
  if (str == NULL)
    return NULL;
  char *new_str = calloc(strlen(str) + 1, 1);
  strcpy(new_str, str);
  return new_str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cubew_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L11
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L9:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rdi,%rbp
  jmp    L9
```

assistant: ```c
char *cubew_strdup(const char *str) {
  if (str == NULL)
    return NULL;
  char *new_str = calloc(strlen(str) + 1, 1);
  strcpy(new_str, str);
  return new_str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cubew_strdup>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *cubew_strdup(const char *str) {
  if (str == NULL)
    return NULL;
  char *new_str = calloc(strlen(str) + 1, 1);
  strcpy(new_str, str);
  return new_str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cubew_strdup>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L4
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L4:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *cubew_strdup(const char *str) {
  if (str == NULL)
    return NULL;
  char *new_str = calloc(strlen(str) + 1, 1);
  strcpy(new_str, str);
  return new_str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<waitAnswer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rcx
  mov    -0x94(%rbp),%eax
  mov    $0x80,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <waitFrame@plt>
  mov    -0xa0(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: %u

assistant: ```c
int waitAnswer(int sock, uint32_t *pValue) {
  char str[128];
  waitFrame(sock, str, 128);
  sscanf(str, "%u", pValue);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<waitAnswer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x80,%edx
  mov    %rbp,%rsi
  call   <waitFrame@plt>
  mov    %rbx,%rdx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: %u

assistant: ```c
int waitAnswer(int sock, uint32_t *pValue) {
  char str[128];
  waitFrame(sock, str, 128);
  sscanf(str, "%u", pValue);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<waitAnswer>:
  endbr64
  push   %r12
  mov    $0x80,%edx
  mov    %rsi,%r12
  push   %rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <waitFrame@plt>
  mov    %r12,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: %u

assistant: ```c
int waitAnswer(int sock, uint32_t *pValue) {
  char str[128];
  waitFrame(sock, str, 128);
  sscanf(str, "%u", pValue);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<waitAnswer>:
  endbr64
  push   %r12
  mov    $0x80,%edx
  mov    %rsi,%r12
  push   %rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <waitFrame@plt>
  mov    %r12,%rdx
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: %u

assistant: ```c
int waitAnswer(int sock, uint32_t *pValue) {
  char str[128];
  waitFrame(sock, str, 128);
  sscanf(str, "%u", pValue);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  movl   $0x1,-0x8(%rbp)
  jmp    L73
L24:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L48
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L60
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%rdx
  add    $0x1,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x4(%rbp)
L48:
  addq   $0x1,-0x20(%rbp)
L73:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  jmp    L65
L60:
  nop
L65:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L15
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L77
L58:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L77:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L58
L15:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int split(char symbol, char *line, char **lst, int lst_len) {
  int i;
  int assign = 0;
  lst[0] = line;
  for (i = 1; *line; line++) {
    if (*line == symbol) {
      *line = '\0';
      if (i >= lst_len)
        break;
      lst[i++] = line + 1;
      assign++;
    }
  }
  assign++;
  if (assign < lst_len) {
    for (i = assign; i < lst_len; i++)
      lst[i] = line;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<split>:
  endbr64
  mov    %rsi,(%rdx)
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L69
  mov    $0x0,%r9d
  mov    $0x1,%eax
  jmp    L41
L24:
  add    $0x1,%rsi
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L27
L41:
  cmp    %r8b,%dil
  jne    L24
  movb   $0x0,(%rsi)
  cmp    %eax,%ecx
  jle    L27
  movslq %eax,%r8
  lea    0x1(%rsi),%r10
  mov    %r10,(%rdx,%r8,8)
  add    $0x1,%r9d
  lea    0x1(%rax),%eax
  jmp    L24
L69:
  mov    $0x0,%r9d
  mov    $0x1,%eax
L27:
  lea    0x1(%r9),%edi
  cmp    %edi,%ecx
  jle    L19
  movslq %edi,%rax
L32:
  mov    %rsi,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L32
  lea    -0x1(%rdi,%rcx,1),%eax
  sub    %r9d,%eax
L19:
  ret
```

assistant: ```c
int split(char symbol, char *line, char **lst, int lst_len) {
  int i;
  int assign = 0;
  lst[0] = line;
  for (i = 1; *line; line++) {
    if (*line == symbol) {
      *line = '\0';
      if (i >= lst_len)
        break;
      lst[i++] = line + 1;
      assign++;
    }
  }
  assign++;
  if (assign < lst_len) {
    for (i = assign; i < lst_len; i++)
      lst[i] = line;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<split>:
  endbr64
  mov    %rsi,(%rdx)
  mov    %rdx,%r11
  movzbl (%rsi),%edx
  mov    %ecx,%r10d
  test   %dl,%dl
  je     L32
  lea    0x1(%rsi),%rax
  xor    %r9d,%r9d
  mov    $0x1,%r8d
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L27:
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L64
L36:
  lea    -0x1(%rax),%rcx
  mov    %rax,%rsi
  cmp    %dil,%dl
  jne    L27
  movb   $0x0,-0x1(%rax)
  add    $0x1,%r9d
  cmp    %r8d,%r10d
  jle    L10
  movslq %r8d,%rdx
  add    $0x1,%r8d
  mov    %rax,(%r11,%rdx,8)
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L36
L64:
  add    $0x1,%r9d
L82:
  cmp    %r9d,%r10d
  jle    L28
  lea    -0x1(%r10),%edx
  movslq %r9d,%rcx
  sub    %r9d,%edx
  lea    (%r11,%rcx,8),%rax
  add    %rcx,%rdx
  lea    0x8(%r11,%rdx,8),%rdx
  nopl   0x0(%rax)
L7:
  mov    %rsi,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L7
  mov    %r10d,%r8d
L28:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rcx,%rsi
  jmp    L82
L32:
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  jmp    L82
```

assistant: ```c
int split(char symbol, char *line, char **lst, int lst_len) {
  int i;
  int assign = 0;
  lst[0] = line;
  for (i = 1; *line; line++) {
    if (*line == symbol) {
      *line = '\0';
      if (i >= lst_len)
        break;
      lst[i++] = line + 1;
      assign++;
    }
  }
  assign++;
  if (assign < lst_len) {
    for (i = assign; i < lst_len; i++)
      lst[i] = line;
  }
  return i;
}
```