user: What would the C source look like for the assembly code provided here?

```asm
<compute_gold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L18:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L96
L66:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L40
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jne    L40
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L16
L40:
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L96:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L66
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  D11(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L70
L13:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L21
L39:
  mov    -0x1c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x1c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L39
  mov    -0x1c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L70:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L13
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L18
  mov    $0x1,%eax
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D19
type: string
name: parse_data
arguments: tag: D11
type: byte[4]

tool: D19: Numerical instability detected. The principal diagonal element is zero. 


tool: {"D11": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int compute_gold(float *U, unsigned int num_elements) {
  unsigned int i, j, k;
  for (k = 0; k < num_elements; k++) {
    for (j = (k + 1); j < num_elements; j++) {
      if (U[num_elements * k + k] == 0) {
        printf("Numerical instability detected. The principal diagonal element is zero. \n");
        return 0;
      }
      U[num_elements * k + j] = (float)(U[num_elements * k + j] / U[num_elements * k + k]);
    }
    U[num_elements * k + k] = 1;
    for (i = (k + 1); i < num_elements; i++) {
      for (j = (k + 1); j < num_elements; j++)
        U[num_elements * i + j] = U[num_elements * i + j] - (U[num_elements * i + k] * U[num_elements * k + j]);
      U[num_elements * i + k] = 0;
    }
  }
  return 1;
}
```