ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(char *message) {
  perror(message);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void error(char *message) {
  perror(message);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void error(char *message) {
  perror(message);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void error(char *message) {
  perror(message);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<syscall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rsi,%rbx
  int    $0x80
  mov    %rbx,%rsi
  mov    -0x30(%rbp),%rdi
  mov    %rax,(%rdi)
  mov    -0x38(%rbp),%rax
  mov    %rsi,(%rax)
  mov    0x10(%rbp),%rax
  mov    %rcx,(%rax)
  mov    0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L9
  mov    0x10(%rbp),%rax
  mov    (%rax),%rax
  jmp    L17
L9:
  mov    $0x0,%eax
L17:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int syscall(unsigned long rcv, unsigned long flags, unsigned long msg0, unsigned long msg1, unsigned long *reply_rcv, unsigned long *reply_flags, unsigned long *reply_msg0, unsigned long *reply_msg1) {
  __asm__ volatile("int $0x80\n\t" : "=a"(*reply_rcv), "=b"(*reply_flags), "=c"(*reply_msg0), "=d"(*reply_msg1) : "0"(rcv), "1"(flags), "2"(msg0), "3"(msg1));
  return *reply_flags & 0x1 ? (int)*reply_msg0 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<syscall>:
  endbr64
  push   %rbx
  mov    %rdx,%r10
  mov    %rcx,%rdx
  mov    0x10(%rsp),%r11
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %r10,%rcx
  int    $0x80
  mov    %rax,(%r8)
  mov    %rbx,(%r9)
  mov    %rcx,(%r11)
  mov    0x18(%rsp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  testb  $0x1,(%r9)
  je     L5
  mov    (%r11),%eax
L5:
  pop    %rbx
  ret
```

assistant: ```c
int syscall(unsigned long rcv, unsigned long flags, unsigned long msg0, unsigned long msg1, unsigned long *reply_rcv, unsigned long *reply_flags, unsigned long *reply_msg0, unsigned long *reply_msg1) {
  __asm__ volatile("int $0x80\n\t" : "=a"(*reply_rcv), "=b"(*reply_flags), "=c"(*reply_msg0), "=d"(*reply_msg1) : "0"(rcv), "1"(flags), "2"(msg0), "3"(msg1));
  return *reply_flags & 0x1 ? (int)*reply_msg0 : 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<syscall>:
  endbr64
  mov    %rdx,%r10
  push   %rbx
  mov    %rcx,%rdx
  mov    0x10(%rsp),%r11
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %r10,%rcx
  int    $0x80
  mov    %rax,(%r8)
  mov    0x18(%rsp),%rax
  mov    %rbx,(%r9)
  mov    %rcx,(%r11)
  mov    %rdx,(%rax)
  xor    %eax,%eax
  testb  $0x1,(%r9)
  je     L9
  mov    (%r11),%eax
L9:
  pop    %rbx
  ret
```

assistant: ```c
int syscall(unsigned long rcv, unsigned long flags, unsigned long msg0, unsigned long msg1, unsigned long *reply_rcv, unsigned long *reply_flags, unsigned long *reply_msg0, unsigned long *reply_msg1) {
  __asm__ volatile("int $0x80\n\t" : "=a"(*reply_rcv), "=b"(*reply_flags), "=c"(*reply_msg0), "=d"(*reply_msg1) : "0"(rcv), "1"(flags), "2"(msg0), "3"(msg1));
  return *reply_flags & 0x1 ? (int)*reply_msg0 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<syscall>:
  endbr64
  mov    %rdx,%r10
  push   %rbx
  mov    %rcx,%rdx
  mov    0x10(%rsp),%r11
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %r10,%rcx
  int    $0x80
  mov    %rax,(%r8)
  mov    0x18(%rsp),%rax
  mov    %rbx,(%r9)
  mov    %rcx,(%r11)
  mov    %rdx,(%rax)
  xor    %eax,%eax
  testb  $0x1,(%r9)
  je     L2
  mov    (%r11),%eax
L2:
  pop    %rbx
  ret
```

assistant: ```c
int syscall(unsigned long rcv, unsigned long flags, unsigned long msg0, unsigned long msg1, unsigned long *reply_rcv, unsigned long *reply_flags, unsigned long *reply_msg0, unsigned long *reply_msg1) {
  __asm__ volatile("int $0x80\n\t" : "=a"(*reply_rcv), "=b"(*reply_flags), "=c"(*reply_msg0), "=d"(*reply_msg1) : "0"(rcv), "1"(flags), "2"(msg0), "3"(msg1));
  return *reply_flags & 0x1 ? (int)*reply_msg0 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nlmsg_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x4000,%edi
  call   <nlmsg_alloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L35
  mov    $0x0,%eax
  jmp    L42
L35:
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <nlmsg_put@plt>
  test   %rax,%rax
  je     L32
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <nlmsg_free@plt>
  mov    $0x0,%eax
  jmp    L42
L32:
  mov    -0x18(%rbp),%rax
L42:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
struct nlmsg *nlmsg_new(int type, int flags) {
  struct nlmsghdr hdr = {.nlmsg_type = type, .nlmsg_flags = flags};
  struct nlmsg *msg;
  hdr.nlmsg_flags |= NLM_F_REQUEST;
  msg = nlmsg_alloc(16384);
  if (!msg)
    return NULL;
  if (nlmsg_put(msg, &hdr, sizeof(hdr))) {
    nlmsg_free(msg);
    return NULL;
  }
  return msg;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nlmsg_new>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    D1(%rip),%rax
  or     (%rax),%esi
  mov    %esi,0x4(%rsp)
  mov    $0x4000,%edi
  call   <nlmsg_alloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L19
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,%rdi
  call   <nlmsg_put@plt>
  test   %rax,%rax
  jne    L27
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L27:
  mov    %rbx,%rdi
  call   <nlmsg_free@plt>
  mov    $0x0,%ebx
  jmp    L19
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct nlmsg *nlmsg_new(int type, int flags) {
  struct nlmsghdr hdr = {.nlmsg_type = type, .nlmsg_flags = flags};
  struct nlmsg *msg;
  hdr.nlmsg_flags |= NLM_F_REQUEST;
  msg = nlmsg_alloc(16384);
  if (!msg)
    return NULL;
  if (nlmsg_put(msg, &hdr, sizeof(hdr))) {
    nlmsg_free(msg);
    return NULL;
  }
  return msg;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nlmsg_new>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %edi,(%rsp)
  mov    $0x4000,%edi
  or     (%rax),%esi
  mov    %esi,0x4(%rsp)
  call   <nlmsg_alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,%rdi
  call   <nlmsg_put@plt>
  test   %rax,%rax
  jne    L39
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <nlmsg_free@plt>
  jmp    L27
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct nlmsg *nlmsg_new(int type, int flags) {
  struct nlmsghdr hdr = {.nlmsg_type = type, .nlmsg_flags = flags};
  struct nlmsg *msg;
  hdr.nlmsg_flags |= NLM_F_REQUEST;
  msg = nlmsg_alloc(16384);
  if (!msg)
    return NULL;
  if (nlmsg_put(msg, &hdr, sizeof(hdr))) {
    nlmsg_free(msg);
    return NULL;
  }
  return msg;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nlmsg_new>:
  endbr64
  push   %r12
  movd   %edi,%xmm0
  mov    $0x4000,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D1(%rip),%rax
  or     (%rax),%esi
  movd   %esi,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  call   <nlmsg_alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L29
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,%rdi
  call   <nlmsg_put@plt>
  test   %rax,%rax
  jne    L37
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <nlmsg_free@plt>
  jmp    L29
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct nlmsg *nlmsg_new(int type, int flags) {
  struct nlmsghdr hdr = {.nlmsg_type = type, .nlmsg_flags = flags};
  struct nlmsg *msg;
  hdr.nlmsg_flags |= NLM_F_REQUEST;
  msg = nlmsg_alloc(16384);
  if (!msg)
    return NULL;
  if (nlmsg_put(msg, &hdr, sizeof(hdr))) {
    nlmsg_free(msg);
    return NULL;
  }
  return msg;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm2
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm0
  call   <glClearColor@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  mov    $0xf,%r9d
  mov    $0x5,%r8d
  mov    $0x5,%ecx
  mov    $0xfffffffb,%edx
  mov    $0x5,%esi
  mov    $0xfffffffb,%edi
  call   <glOrtho@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  sub    $0x8,%rsp
  push   $0x0
  push   $0x1
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <gluLookAt@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void init(void) {
  glClearColor(0.0, 0.0, 0.0, 0.0);
  glMatrixMode(GL_PROJECTION);
  glOrtho(-5, 5, -5, 5, 5, 15);
  glMatrixMode(GL_MODELVIEW);
  gluLookAt(0, 0, 10, 0, 0, 0, 0, 1, 0);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<init>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x8,%rsp
  movapd %xmm3,%xmm2
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm0
  call   <glClearColor@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  mov    $0xf,%r9d
  mov    $0x5,%r8d
  mov    $0x5,%ecx
  mov    $0xfffffffb,%edx
  mov    $0x5,%esi
  mov    $0xfffffffb,%edi
  call   <glOrtho@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  push   $0x0
  xor    %ecx,%ecx
  mov    $0xa,%edx
  xor    %esi,%esi
  push   $0x1
  xor    %edi,%edi
  push   $0x0
  call   <gluLookAt@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void init(void) {
  glClearColor(0.0, 0.0, 0.0, 0.0);
  glMatrixMode(GL_PROJECTION);
  glOrtho(-5, 5, -5, 5, 5, 15);
  glMatrixMode(GL_MODELVIEW);
  gluLookAt(0, 0, 10, 0, 0, 0, 0, 1, 0);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x8,%rsp
  movapd %xmm3,%xmm2
  movapd %xmm3,%xmm1
  movapd %xmm3,%xmm0
  call   <glClearColor@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  mov    $0xf,%r9d
  mov    $0x5,%r8d
  mov    $0x5,%ecx
  mov    $0xfffffffb,%edx
  mov    $0x5,%esi
  mov    $0xfffffffb,%edi
  call   <glOrtho@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  push   $0x0
  xor    %ecx,%ecx
  mov    $0xa,%edx
  xor    %esi,%esi
  push   $0x1
  xor    %edi,%edi
  push   $0x0
  call   <gluLookAt@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void init(void) {
  glClearColor(0.0, 0.0, 0.0, 0.0);
  glMatrixMode(GL_PROJECTION);
  glOrtho(-5, 5, -5, 5, 5, 15);
  glMatrixMode(GL_MODELVIEW);
  gluLookAt(0, 0, 10, 0, 0, 0, 0, 1, 0);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<absolutize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x18(%rbp),%rax
  jmp    L28
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L67
  mov    -0x18(%rbp),%rax
  jmp    L28
L67:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L11
L27:
  subl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L27
L7:
  cmpl   $0x0,-0x4(%rbp)
  je     L44
  mov    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <do_path_append@plt>
  jmp    L28
L44:
  mov    -0x18(%rbp),%rax
L28:
  leave
  ret
```

assistant: ```c
char *absolutize(char *p, char *d) {
  int l1;
  if (!p[0])
    return p;
  if (p[0] == '/')
    return p;
  l1 = strlen(d);
  while (l1 && (d[l1 - 1] != '/')) {
    l1--;
  }
  if (l1)
    return do_path_append(d, l1, p);
  else
    return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<absolutize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%eax
  cmp    $0x2f,%al
  je     L43
  mov    %rsi,%rbx
  test   %al,%al
  je     L43
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L43
  cltq
L59:
  mov    %eax,%esi
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  je     L26
  sub    $0x1,%rax
  test   %eax,%eax
  jne    L59
L43:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  test   %eax,%eax
  je     L43
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <do_path_append@plt>
  mov    %rax,%rbp
  jmp    L43
```

assistant: ```c
char *absolutize(char *p, char *d) {
  int l1;
  if (!p[0])
    return p;
  if (p[0] == '/')
    return p;
  l1 = strlen(d);
  while (l1 && (d[l1 - 1] != '/')) {
    l1--;
  }
  if (l1)
    return do_path_append(d, l1, p);
  else
    return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<absolutize>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  cmp    $0x2f,%al
  je     L53
  test   %al,%al
  je     L53
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  je     L53
  cltq
  jmp    L52
  nopl   0x0(%rax)
L14:
  sub    $0x1,%rax
  test   %eax,%eax
  je     L53
L52:
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  mov    %eax,%esi
  jne    L14
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <do_path_append@plt>
  nopl   0x0(%rax,%rax,1)
L53:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *absolutize(char *p, char *d) {
  int l1;
  if (!p[0])
    return p;
  if (p[0] == '/')
    return p;
  l1 = strlen(d);
  while (l1 && (d[l1 - 1] != '/')) {
    l1--;
  }
  if (l1)
    return do_path_append(d, l1, p);
  else
    return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<absolutize>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  cmp    $0x2f,%al
  je     L52
  test   %al,%al
  je     L52
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  je     L52
  cltq
  jmp    L43
  nopl   0x0(%rax)
L51:
  sub    $0x1,%rax
  test   %eax,%eax
  je     L52
L43:
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  mov    %eax,%esi
  jne    L51
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <do_path_append@plt>
  nopl   0x0(%rax,%rax,1)
L52:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *absolutize(char *p, char *d) {
  int l1;
  if (!p[0])
    return p;
  if (p[0] == '/')
    return p;
  l1 = strlen(d);
  while (l1 && (d[l1 - 1] != '/')) {
    l1--;
  }
  if (l1)
    return do_path_append(d, l1, p);
  else
    return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xcalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L21
  cmpq   $0x0,-0x18(%rbp)
  je     L21
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  mov    $0x0,%eax
  call   <xalloc_die@plt>
L21:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xcalloc(size_t count, size_t size) {
  void *res = calloc(count, size);
  if (size && count && !res) {
    xalloc_die();
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xcalloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  setne  %dl
  test   %rbx,%rbx
  setne  %al
  test   %al,%dl
  je     L26
  test   %r12,%r12
  je     L4
L26:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x0,%eax
  call   <xalloc_die@plt>
  jmp    L26
```

assistant: ```c
void *xcalloc(size_t count, size_t size) {
  void *res = calloc(count, size);
  if (size && count && !res) {
    xalloc_die();
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xcalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <calloc@plt>
  test   %rbp,%rbp
  setne  %dl
  test   %rbx,%rbx
  mov    %rax,%r12
  setne  %al
  test   %al,%dl
  je     L10
  test   %r12,%r12
  je     L20
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  xor    %eax,%eax
  call   <xalloc_die@plt>
  jmp    L10
```

assistant: ```c
void *xcalloc(size_t count, size_t size) {
  void *res = calloc(count, size);
  if (size && count && !res) {
    xalloc_die();
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xcalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <calloc@plt>
  test   %rbp,%rbp
  setne  %dl
  test   %rbx,%rbx
  mov    %rax,%r12
  setne  %al
  test   %al,%dl
  je     L2
  test   %r12,%r12
  je     L4
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  xor    %eax,%eax
  call   <xalloc_die@plt>
  jmp    L2
```

assistant: ```c
void *xcalloc(size_t count, size_t size) {
  void *res = calloc(count, size);
  if (size && count && !res) {
    xalloc_die();
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<create_graph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L32
L33:
  movl   $0x0,-0xc(%rbp)
  jmp    L53
L56:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  addl   $0x1,-0xc(%rbp)
L53:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L56
  addl   $0x1,-0x10(%rbp)
L32:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L33
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L62
L25:
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x14(%rbp),%esi
  movslq %ecx,%rax
  mov    %esi,(%rdx,%rax,4)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rsi
  mov    %rsi,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  shl    $0x4,%rax
  mov    %rax,%rsi
  mov    -0x28(%rbp),%rax
  add    %rax,%rsi
  mov    -0x18(%rbp),%edi
  movslq %ecx,%rax
  mov    (%rdx,%rax,4),%edx
  movslq %edi,%rax
  mov    %edx,(%rsi,%rax,4)
  addl   $0x1,-0x10(%rbp)
L62:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L25
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D32
data_type: string

tool: D15: 
 Enter the number of edges

tool: D29: %d

tool: D22: Enter the edges as (v1,v2,weight)triplets


tool: D32: %d%d%d

assistant: ```c
void create_graph(int G[][20], int no_of_nodes) {
  int i, j;
  int no_of_edges;
  int v1, v2, weight;
  for (i = 0; i < no_of_nodes; i++)
    for (j = 0; j < no_of_nodes; j++)
      G[i][j] = 0;
  printf("\n Enter the number of edges");
  scanf("%d", &no_of_edges);
  printf("Enter the edges as (v1,v2,weight)triplets\n");
  for (i = 0; i < no_of_edges; i++) {
    scanf("%d%d%d", &v1, &v2, &weight);
    G[v1][v2] = G[v2][v1] = weight;
  }
}
```