ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<NeubotPoller_sigint>:
  endbr64
  mov    %rdx,%rdi
  jmp    1050 <NeubotPoller_break_loop@plt>
```

assistant: ```c
void NeubotPoller_sigint(int signo, short event, void *opaque) {
  struct NeubotPoller *self;
  (void)signo;
  (void)event;
  self = (struct NeubotPoller *)opaque;
  NeubotPoller_break_loop(self);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x90(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x90(%rbp),%edx
  mov    -0x8c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x5c(%rbp)
  mov    -0x5c(%rbp),%ecx
  mov    -0x8c(%rbp),%edx
  mov    -0x90(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x90(%rbp),%eax
  mov    -0x8c(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%ecx
  mov    -0x8c(%rbp),%edx
  mov    -0x90(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D33
type: string
name: unpack_data
arguments: tag: D38
type: string
name: unpack_data
arguments: tag: D58
type: string
name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D28
type: string

tool: D33: Enter 1st number you want to add and subtract:

tool: D38: %9d

tool: D58: Enter 2nd number you want to add and subtract:

tool: D3: %9d + %9d = %9d


tool: D28: %9d - %9d = %9d


assistant: ```c
int main(void) {
  int numbers[10], sum1[10], sub1[10];
  printf("Enter 1st number you want to add and subtract:\n");
  scanf("%9d", &numbers[0]);
  printf("Enter 2nd number you want to add and subtract:\n");
  scanf("%9d", &numbers[1]);
  sum1[1] = numbers[0] + numbers[1];
  printf("%9d + %9d = %9d\n", numbers[0], numbers[1], sum1[1]);
  sub1[1] = numbers[0] - numbers[1];
  printf("%9d - %9d = %9d\n", numbers[0], numbers[1], sub1[1]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D37(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  lea    (%rsi,%rdx,1),%ecx
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  mov    %esi,%ecx
  sub    %edx,%ecx
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D37
type_guessed: string
name: retrieve_data
arguments: data_label: D18
type_guessed: string
name: retrieve_data
arguments: data_label: D29
type_guessed: string
name: retrieve_data
arguments: data_label: D48
type_guessed: string

tool: D9: Enter 1st number you want to add and subtract:

tool: D37: %9d

tool: D18: Enter 2nd number you want to add and subtract:

tool: D29: %9d + %9d = %9d


tool: D48: %9d - %9d = %9d


assistant: ```c
int main(void) {
  int numbers[10], sum1[10], sub1[10];
  printf("Enter 1st number you want to add and subtract:\n");
  scanf("%9d", &numbers[0]);
  printf("Enter 2nd number you want to add and subtract:\n");
  scanf("%9d", &numbers[1]);
  sum1[1] = numbers[0] + numbers[1];
  printf("%9d + %9d = %9d\n", numbers[0], numbers[1], sum1[1]);
  sub1[1] = numbers[0] - numbers[1];
  printf("%9d - %9d = %9d\n", numbers[0], numbers[1], sub1[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D37(%rip),%rdi
  lea    D45(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  lea    (%rsi,%rdx,1),%ecx
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  mov    %esi,%ecx
  sub    %edx,%ecx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D37
type_guessed: string
name: unpack_data
arguments: tag: D45
type_guessed: string
name: unpack_data
arguments: tag: D40
type_guessed: string
name: unpack_data
arguments: tag: D33
type_guessed: string
name: unpack_data
arguments: tag: D36
type_guessed: string

tool: D37: Enter 1st number you want to add and subtract:

tool: D45: %9d

tool: D40: Enter 2nd number you want to add and subtract:

tool: D33: %9d + %9d = %9d


tool: D36: %9d - %9d = %9d


assistant: ```c
int main(void) {
  int numbers[10], sum1[10], sub1[10];
  printf("Enter 1st number you want to add and subtract:\n");
  scanf("%9d", &numbers[0]);
  printf("Enter 2nd number you want to add and subtract:\n");
  scanf("%9d", &numbers[1]);
  sum1[1] = numbers[0] + numbers[1];
  printf("%9d + %9d = %9d\n", numbers[0], numbers[1], sum1[1]);
  sub1[1] = numbers[0] - numbers[1];
  printf("%9d - %9d = %9d\n", numbers[0], numbers[1], sub1[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  lea    D33(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  lea    (%rsi,%rdx,1),%ecx
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  mov    %esi,%ecx
  sub    %edx,%ecx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D46
type_infered: string
name: read_data
arguments: label: D33
type_infered: string
name: read_data
arguments: label: D9
type_infered: string
name: read_data
arguments: label: D18
type_infered: string
name: read_data
arguments: label: D25
type_infered: string

tool: D46: Enter 1st number you want to add and subtract:

tool: D33: %9d

tool: D9: Enter 2nd number you want to add and subtract:

tool: D18: %9d + %9d = %9d


tool: D25: %9d - %9d = %9d


assistant: ```c
int main(void) {
  int numbers[10], sum1[10], sub1[10];
  printf("Enter 1st number you want to add and subtract:\n");
  scanf("%9d", &numbers[0]);
  printf("Enter 2nd number you want to add and subtract:\n");
  scanf("%9d", &numbers[1]);
  sum1[1] = numbers[0] + numbers[1];
  printf("%9d + %9d = %9d\n", numbers[0], numbers[1], sum1[1]);
  sub1[1] = numbers[0] - numbers[1];
  printf("%9d - %9d = %9d\n", numbers[0], numbers[1], sub1[1]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L28:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  cmpl   $0x9,-0x8(%rbp)
  jg     L2
  cmpl   $0x9,-0x4(%rbp)
  jg     L2
  jmp    L28
L2:
  cmpl   $0x9,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = 0;
  int y = 0;
  while (true) {
    x++;
    y++;
    x += y;
    y += x;
    if (x >= 10 || y >= 10)
      break;
  }
  assert(y >= 10);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%eax
L11:
  lea    0x2(%rax,%rdx,1),%eax
  lea    0x1(%rax,%rdx,1),%edx
  cmp    $0x9,%edx
  setg   %dil
  cmp    $0x9,%eax
  jg     L0
  test   %dil,%dil
  je     L11
L0:
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = 0;
  int y = 0;
  while (true) {
    x++;
    y++;
    x += y;
    y += x;
    if (x >= 10 || y >= 10)
      break;
  }
  assert(y >= 10);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L15:
  lea    0x2(%rax,%rdx,1),%eax
  lea    0x1(%rax,%rdx,1),%edx
  cmp    $0x9,%edx
  setg   %dil
  cmp    $0x9,%eax
  jg     L17
  test   %dil,%dil
  je     L15
L17:
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = 0;
  int y = 0;
  while (true) {
    x++;
    y++;
    x += y;
    y += x;
    if (x >= 10 || y >= 10)
      break;
  }
  assert(y >= 10);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  lea    0x2(%rax,%rdx,1),%eax
  lea    0x1(%rax,%rdx,1),%edx
  cmp    $0x9,%edx
  setg   %dil
  cmp    $0x9,%eax
  jg     L5
  test   %dil,%dil
  je     L8
L5:
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = 0;
  int y = 0;
  while (true) {
    x++;
    y++;
    x += y;
    y += x;
    if (x >= 10 || y >= 10)
      break;
  }
  assert(y >= 10);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rax
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movq   $0x0,-0x58(%rbp)
  jmp    L19
L12:
  mov    -0x58(%rbp),%rax
  mov    -0x50(%rbp,%rax,4),%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <test_assert@plt>
  addq   $0x1,-0x58(%rbp)
L19:
  cmpq   $0xf,-0x58(%rbp)
  jbe    L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int main() {
  int array[16];
  memset(array, 0, 16 * sizeof(int));
  for (size_t i = 0; i < 16; ++i)
    test_assert(array[i] == 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    0x40(%rsp),%rbp
L10:
  cmpl   $0x0,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <test_assert@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L10
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[16];
  memset(array, 0, 16 * sizeof(int));
  for (size_t i = 0; i < 16; ++i)
    test_assert(array[i] == 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x40,%edx
  xor    %esi,%esi
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%rbp
  mov    %rbx,%rdi
  call   <memset@plt>
  nopl   0x0(%rax)
L10:
  mov    (%rbx),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x4,%rbx
  call   <test_assert@plt>
  cmp    %rbp,%rbx
  jne    L10
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[16];
  memset(array, 0, 16 * sizeof(int));
  for (size_t i = 0; i < 16; ++i)
    test_assert(array[i] == 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x40,%edx
  xor    %esi,%esi
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%rbp
  mov    %rbx,%rdi
  call   <memset@plt>
  nopl   0x0(%rax)
L11:
  mov    (%rbx),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x4,%rbx
  call   <test_assert@plt>
  cmp    %rbp,%rbx
  jne    L11
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[16];
  memset(array, 0, 16 * sizeof(int));
  for (size_t i = 0; i < 16; ++i)
    test_assert(array[i] == 0);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<getIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  imul   -0x28(%rbp),%rax
  shr    %rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sub    $0x1,%rax
  imul   %rdx,%rax
  shr    %rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  sub    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t getIndex(const size_t x, const size_t y, const size_t n) {
  size_t k = (n * (n - 1) / 2) - ((n - x) * (n - x - 1) / 2) + y - x - 1;
  return k;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getIndex>:
  endbr64
  mov    %rdx,%rcx
  sub    %rdi,%rcx
  lea    -0x1(%rdx),%rax
  imul   %rdx,%rax
  shr    %rax
  sub    $0x1,%rsi
  sub    %rdi,%rsi
  add    %rsi,%rax
  lea    -0x1(%rcx),%rdx
  imul   %rcx,%rdx
  shr    %rdx
  sub    %rdx,%rax
  ret
```

assistant: ```c
size_t getIndex(const size_t x, const size_t y, const size_t n) {
  size_t k = (n * (n - 1) / 2) - ((n - x) * (n - x - 1) / 2) + y - x - 1;
  return k;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getIndex>:
  endbr64
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%rax
  sub    $0x1,%rsi
  sub    %rdi,%rcx
  imul   %rdx,%rax
  sub    %rdi,%rsi
  lea    -0x1(%rcx),%rdx
  imul   %rcx,%rdx
  shr    %rax
  add    %rsi,%rax
  shr    %rdx
  sub    %rdx,%rax
  ret
```

assistant: ```c
size_t getIndex(const size_t x, const size_t y, const size_t n) {
  size_t k = (n * (n - 1) / 2) - ((n - x) * (n - x - 1) / 2) + y - x - 1;
  return k;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getIndex>:
  endbr64
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%rax
  sub    $0x1,%rsi
  sub    %rdi,%rcx
  imul   %rdx,%rax
  sub    %rdi,%rsi
  lea    -0x1(%rcx),%rdx
  imul   %rcx,%rdx
  shr    %rax
  add    %rsi,%rax
  shr    %rdx
  sub    %rdx,%rax
  ret
```

assistant: ```c
size_t getIndex(const size_t x, const size_t y, const size_t n) {
  size_t k = (n * (n - 1) / 2) - ((n - x) * (n - x - 1) / 2) + y - x - 1;
  return k;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fts_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L6
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L6:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void fts_free(FTSENT *p) {
  if (p->fts_statp)
    free(p->fts_statp);
  free(p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fts_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L3
  call   <free@plt>
L3:
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fts_free(FTSENT *p) {
  if (p->fts_statp)
    free(p->fts_statp);
  free(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fts_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L7
  call   <free@plt>
L7:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void fts_free(FTSENT *p) {
  if (p->fts_statp)
    free(p->fts_statp);
  free(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fts_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  call   <free@plt>
L1:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void fts_free(FTSENT *p) {
  if (p->fts_statp)
    free(p->fts_statp);
  free(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
type: string
name: unpack_data
arguments: data_label: D11
type: string

tool: D17: Hello (%d)

tool: D11:  World (%d)


assistant: ```c
int main() {
#pragma omp parallel
  {
    int id = omp_get_thread_num();
    printf("Hello (%d)", id);
    printf(" World (%d)\n", id);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D12
type: string

tool: D6: Hello (%d)

tool: D12:  World (%d)


assistant: ```c
int main() {
#pragma omp parallel
  {
    int id = omp_get_thread_num();
    printf("Hello (%d)", id);
    printf(" World (%d)\n", id);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string

tool: D5: Hello (%d)

tool: D3:  World (%d)


assistant: ```c
int main() {
#pragma omp parallel
  {
    int id = omp_get_thread_num();
    printf("Hello (%d)", id);
    printf(" World (%d)\n", id);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string
name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D6: Hello (%d)

tool: D3:  World (%d)


assistant: ```c
int main() {
#pragma omp parallel
  {
    int id = omp_get_thread_num();
    printf("Hello (%d)", id);
    printf(" World (%d)\n", id);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<iso_stop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <pclog@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: iso_stop stub


assistant: ```c
void iso_stop(void) {
  pclog("iso_stop stub\n");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iso_stop>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <pclog@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: iso_stop stub


assistant: ```c
void iso_stop(void) {
  pclog("iso_stop stub\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iso_stop>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <pclog@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: iso_stop stub


assistant: ```c
void iso_stop(void) {
  pclog("iso_stop stub\n");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<iso_stop>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <pclog@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: iso_stop stub


assistant: ```c
void iso_stop(void) {
  pclog("iso_stop stub\n");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  nop
  jmp    *%rax
  endbr64
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L5
  endbr64
  mov    $0x3,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  void *p = &&x;
rejmp:
  goto *p;
x:
  p = &&y;
  goto rejmp;
y:
  return 3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  lea    D14(%rip),%rax
  lea    D15(%rip),%rdx
  jmp    L9
  endbr64
  mov    %rdx,%rax
L9:
  jmp    *%rax
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
main() {
  void *p = &&x;
rejmp:
  goto *p;
x:
  p = &&y;
  goto rejmp;
y:
  return 3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
main() {
  void *p = &&x;
rejmp:
  goto *p;
x:
  p = &&y;
  goto rejmp;
y:
  return 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
main() {
  void *p = &&x;
rejmp:
  goto *p;
x:
  p = &&y;
  goto rejmp;
y:
  return 3;
}
```