ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<assemble_msg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%r8d
  jge    L26
  sub    $0x1,%edx
  movslq %r8d,%rax
  mov    %esi,%r12d
  xor    %r14d,%r14d
  sub    %r8d,%edx
  lea    (%rcx,%rax,8),%r15
  add    %rax,%rdx
  lea    0x8(%rcx,%rdx,8),%r13
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    %edx,%eax
  mov    %edx,%ebx
  mov    (%r15),%rsi
  cmovle %eax,%ebx
  add    $0x8,%r15
  mov    %ebx,%edx
  call   <strncpy@plt>
  lea    (%rbx,%r14,1),%eax
  lea    0x1(%rbx,%r14,1),%r14d
  cltq
  movb   $0x20,0x0(%rbp,%rax,1)
  cmp    %r13,%r15
  je     L10
L2:
  mov    (%r15),%rdi
  call   <strlen@plt>
  mov    %r12d,%edx
  movslq %r14d,%rcx
  sub    %r14d,%edx
  lea    0x0(%rbp,%rcx,1),%rdi
  sub    $0x2,%edx
  jne    L0
  sub    $0x1,%rcx
L37:
  movb   $0xa,0x0(%rbp,%rcx,1)
  movb   $0x0,(%rdi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  movslq %r14d,%r14
  lea    -0x1(%r14),%rcx
  lea    0x0(%rbp,%r14,1),%rdi
  jmp    L37
L26:
  mov    $0xffffffffffffffff,%rcx
  jmp    L37
```

assistant: ```c
void assemble_msg(char *msgbuf, int bufsz, int argc, char *argv[], int ind) {
  int n = 0;
  while (ind < argc) {
    int sl = strlen(argv[ind]);
    int wl = bufsz - n - 2;
    if (wl == 0)
      break;
    else if (wl > sl)
      wl = sl;
    strncpy(&(msgbuf[n]), argv[ind], wl);
    msgbuf[n + wl] = ' ';
    n += wl + 1;
    ind++;
  }
  msgbuf[n - 1] = '\n';
  msgbuf[n] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2a,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  imul   %edx,%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L11
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long hash(char *word) {
  int i;
  long hashed = 42;
  for (i = 0; i < strlen(word); i++) {
    hashed += word[i] * (i + 1);
  }
  return hashed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x2a,%r12d
  jmp    L15
L16:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
  add    $0x1,%rbx
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  int i;
  long hashed = 42;
  for (i = 0; i < strlen(word); i++) {
    hashed += word[i] * (i + 1);
  }
  return hashed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash>:
  endbr64
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L17
  nopl   (%rax)
L16:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  add    $0x1,%rbx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  int i;
  long hashed = 42;
  for (i = 0; i < strlen(word); i++) {
    hashed += word[i] * (i + 1);
  }
  return hashed;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hash>:
  endbr64
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L3
  nopl   (%rax)
L0:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  add    $0x1,%rbx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  int i;
  long hashed = 42;
  for (i = 0; i < strlen(word); i++) {
    hashed += word[i] * (i + 1);
  }
  return hashed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<initDaemon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L7
  mov    $0x0,%edi
  call   <exit@plt>
L7:
  mov    $0x0,%eax
  call   <setsid@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D88(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D73(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D114(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D70(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D62(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D107(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D155(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L8
  mov    $0x0,%edi
  call   <exit@plt>
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void initDaemon() {
  if (fork() != 0) {
    exit(0);
  }
  setsid();
  signal(SIGINT, SIG_IGN);
  signal(SIGHUP, SIG_IGN);
  signal(SIGQUIT, SIG_IGN);
  signal(SIGPIPE, SIG_IGN);
  signal(SIGCHLD, SIG_IGN);
  signal(SIGTTOU, SIG_IGN);
  signal(SIGTTIN, SIG_IGN);
  signal(SIGTERM, SIG_IGN);
  signal(SIGKILL, SIG_IGN);
  if (fork() != 0) {
    exit(0);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<initDaemon>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L9
L16:
  mov    $0x0,%eax
  call   <setsid@plt>
  mov    D76(%rip),%rbx
  mov    (%rbx),%esi
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D50(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D37(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D72(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D25(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D67(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D63(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L28
L18:
  pop    %rbx
  ret
L9:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L16
L28:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L18
```

assistant: ```c
void initDaemon() {
  if (fork() != 0) {
    exit(0);
  }
  setsid();
  signal(SIGINT, SIG_IGN);
  signal(SIGHUP, SIG_IGN);
  signal(SIGQUIT, SIG_IGN);
  signal(SIGPIPE, SIG_IGN);
  signal(SIGCHLD, SIG_IGN);
  signal(SIGTTOU, SIG_IGN);
  signal(SIGTTIN, SIG_IGN);
  signal(SIGTERM, SIG_IGN);
  signal(SIGKILL, SIG_IGN);
  if (fork() != 0) {
    exit(0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<initDaemon>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L24
L1:
  xor    %eax,%eax
  call   <setsid@plt>
  mov    D29(%rip),%rbx
  mov    D84(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D20(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D25(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D32(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D12(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D27(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D6(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D39(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D40(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L6
  pop    %rbx
  ret
  nopl   0x0(%rax)
L24:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L1
  nopl   0x0(%rax)
L6:
  xor    %edi,%edi
  pop    %rbx
  jmp    10a0 <exit@plt>
```

assistant: ```c
void initDaemon() {
  if (fork() != 0) {
    exit(0);
  }
  setsid();
  signal(SIGINT, SIG_IGN);
  signal(SIGHUP, SIG_IGN);
  signal(SIGQUIT, SIG_IGN);
  signal(SIGPIPE, SIG_IGN);
  signal(SIGCHLD, SIG_IGN);
  signal(SIGTTOU, SIG_IGN);
  signal(SIGTTIN, SIG_IGN);
  signal(SIGTERM, SIG_IGN);
  signal(SIGKILL, SIG_IGN);
  if (fork() != 0) {
    exit(0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<initDaemon>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L4
L22:
  xor    %eax,%eax
  call   <setsid@plt>
  mov    D64(%rip),%rbx
  mov    D95(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D99(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D71(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D56(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D82(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D2(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D26(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D41(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  mov    D83(%rip),%rax
  mov    (%rbx),%esi
  mov    (%rax),%edi
  call   <signal@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L21
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L22
  nopl   0x0(%rax)
L21:
  xor    %edi,%edi
  pop    %rbx
  jmp    10a0 <exit@plt>
```

assistant: ```c
void initDaemon() {
  if (fork() != 0) {
    exit(0);
  }
  setsid();
  signal(SIGINT, SIG_IGN);
  signal(SIGHUP, SIG_IGN);
  signal(SIGQUIT, SIG_IGN);
  signal(SIGPIPE, SIG_IGN);
  signal(SIGCHLD, SIG_IGN);
  signal(SIGTTOU, SIG_IGN);
  signal(SIGTTIN, SIG_IGN);
  signal(SIGTERM, SIG_IGN);
  signal(SIGKILL, SIG_IGN);
  if (fork() != 0) {
    exit(0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rq_hashtable_calc_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x8,-0x4(%rbp)
  jmp    L21
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L13
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  jmp    L39
L13:
  addl   $0x1,-0x8(%rbp)
  shll   -0x4(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    $0x1c,%eax
  jbe    L8
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int rq_hashtable_calc_size(int size) {
  static long primes[] = {8 + 3, 16 + 3, 32 + 5, 64 + 3, 128 + 3, 256 + 27, 512 + 9, 1024 + 9, 2048 + 5, 4096 + 3, 8192 + 27, 16384 + 43, 32768 + 3, 65536 + 45, 131072 + 29, 262144 + 3, 524288 + 21, 1048576 + 7, 2097152 + 17, 4194304 + 15, 8388608 + 9, 16777216 + 43, 33554432 + 35, 67108864 + 15, 134217728 + 29, 268435456 + 3, 536870912 + 11, 1073741824 + 85, 0};
  int i;
  int newsize;
  for (i = 0, newsize = 8; i < sizeof(primes) / sizeof(primes[0]); i++, newsize <<= 1) {
    if (newsize > size)
      return primes[i];
  }
  assert(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rq_hashtable_calc_size>:
  endbr64
  cmp    $0x7,%edi
  jle    L14
  mov    $0x10,%edx
  mov    $0x1,%eax
L27:
  cmp    %edx,%edi
  jl     L20
  add    $0x1,%eax
  add    %edx,%edx
  cmp    $0x1d,%eax
  jne    L27
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L14:
  mov    $0x0,%eax
L20:
  cltq
  lea    D0(%rip),%rdx
  mov    (%rdx,%rax,8),%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: 

assistant: ```c
int rq_hashtable_calc_size(int size) {
  static long primes[] = {8 + 3, 16 + 3, 32 + 5, 64 + 3, 128 + 3, 256 + 27, 512 + 9, 1024 + 9, 2048 + 5, 4096 + 3, 8192 + 27, 16384 + 43, 32768 + 3, 65536 + 45, 131072 + 29, 262144 + 3, 524288 + 21, 1048576 + 7, 2097152 + 17, 4194304 + 15, 8388608 + 9, 16777216 + 43, 33554432 + 35, 67108864 + 15, 134217728 + 29, 268435456 + 3, 536870912 + 11, 1073741824 + 85, 0};
  int i;
  int newsize;
  for (i = 0, newsize = 8; i < sizeof(primes) / sizeof(primes[0]); i++, newsize <<= 1) {
    if (newsize > size)
      return primes[i];
  }
  assert(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rq_hashtable_calc_size>:
  endbr64
  cmp    $0x7,%edi
  jle    L34
  mov    $0x10,%edx
  mov    $0x1,%eax
  jmp    L32
  nopl   (%rax)
L6:
  add    $0x1,%eax
  add    %edx,%edx
  cmp    $0x1d,%eax
  je     L4
L32:
  cmp    %edx,%edi
  jge    L6
  lea    D9(%rip),%rdx
  cltq
  mov    (%rdx,%rax,8),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L34:
  mov    $0xb,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9: 

assistant: ```c
int rq_hashtable_calc_size(int size) {
  static long primes[] = {8 + 3, 16 + 3, 32 + 5, 64 + 3, 128 + 3, 256 + 27, 512 + 9, 1024 + 9, 2048 + 5, 4096 + 3, 8192 + 27, 16384 + 43, 32768 + 3, 65536 + 45, 131072 + 29, 262144 + 3, 524288 + 21, 1048576 + 7, 2097152 + 17, 4194304 + 15, 8388608 + 9, 16777216 + 43, 33554432 + 35, 67108864 + 15, 134217728 + 29, 268435456 + 3, 536870912 + 11, 1073741824 + 85, 0};
  int i;
  int newsize;
  for (i = 0, newsize = 8; i < sizeof(primes) / sizeof(primes[0]); i++, newsize <<= 1) {
    if (newsize > size)
      return primes[i];
  }
  assert(0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rq_hashtable_calc_size>:
  endbr64
  cmp    $0x7,%edi
  jle    L11
  mov    $0x10,%edx
  mov    $0x1,%eax
  jmp    L1
  nopl   (%rax)
L36:
  add    $0x1,%eax
  add    %edx,%edx
  cmp    $0x1d,%eax
  je     L21
L1:
  cmp    %edx,%edi
  jge    L36
  lea    D5(%rip),%rdx
  cltq
  mov    (%rdx,%rax,8),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L11:
  mov    $0xb,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: 

assistant: ```c
int rq_hashtable_calc_size(int size) {
  static long primes[] = {8 + 3, 16 + 3, 32 + 5, 64 + 3, 128 + 3, 256 + 27, 512 + 9, 1024 + 9, 2048 + 5, 4096 + 3, 8192 + 27, 16384 + 43, 32768 + 3, 65536 + 45, 131072 + 29, 262144 + 3, 524288 + 21, 1048576 + 7, 2097152 + 17, 4194304 + 15, 8388608 + 9, 16777216 + 43, 33554432 + 35, 67108864 + 15, 134217728 + 29, 268435456 + 3, 536870912 + 11, 1073741824 + 85, 0};
  int i;
  int newsize;
  for (i = 0, newsize = 8; i < sizeof(primes) / sizeof(primes[0]); i++, newsize <<= 1) {
    if (newsize > size)
      return primes[i];
  }
  assert(0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getOutFileName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  jmp    L33
L19:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L28
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L20
  mov    -0x30(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %rax,%rbx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x30(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  jmp    L58
L20:
  subq   $0x1,-0x30(%rbp)
L33:
  mov    -0x30(%rbp),%rax
  sub    -0x38(%rbp),%rax
  test   %rax,%rax
  jns    L19
  jmp    L6
L28:
  nop
L6:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
L58:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *getOutFileName(char const *file, const char *ext) {
  size_t len = strlen(file);
  char const *i = file + len - 1;
  for (; i - file >= 0; --i) {
    if (*i == '/')
      break;
    if (*i == '.') {
      char *ret = (char *)malloc((i - file) + strlen(ext) + 1);
      strncpy(ret, file, i - file);
      strcpy(ret + (i - file), ext);
      return ret;
    }
  }
  char *ret = (char *)malloc(len + strlen(ext));
  strcpy(ret, file);
  strcpy(ret + len, ext);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<getOutFileName>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%r13
  lea    -0x1(%rax),%rdx
  lea    (%rbx,%rdx,1),%rax
  mov    %rdx,%rbp
  test   %rdx,%rdx
  js     L29
L33:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  je     L29
  cmp    $0x2e,%dl
  je     L39
  sub    $0x1,%rax
  mov    %rax,%rbp
  sub    %rbx,%rbp
  jns    L33
L29:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    (%rax,%r13,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    (%r14,%r13,1),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
L37:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    (%r14,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  jmp    L37
```

assistant: ```c
char *getOutFileName(char const *file, const char *ext) {
  size_t len = strlen(file);
  char const *i = file + len - 1;
  for (; i - file >= 0; --i) {
    if (*i == '/')
      break;
    if (*i == '.') {
      char *ret = (char *)malloc((i - file) + strlen(ext) + 1);
      strncpy(ret, file, i - file);
      strcpy(ret + (i - file), ext);
      return ret;
    }
  }
  char *ret = (char *)malloc(len + strlen(ext));
  strcpy(ret, file);
  strcpy(ret + len, ext);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getOutFileName>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%rbx
  mov    %rax,%r12
  lea    0x0(%rbp,%rbx,1),%rax
  cmp    $0xffffffffffffffff,%rbx
  jne    L31
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L43:
  cmp    $0x2e,%dl
  je     L24
  sub    $0x1,%rax
  mov    %rax,%rbx
  sub    %rbp,%rbx
  js     L7
L31:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  jne    L43
L7:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    (%rax,%r12,1),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    (%r14,%r12,1),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    (%r14,%rbx,1),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *getOutFileName(char const *file, const char *ext) {
  size_t len = strlen(file);
  char const *i = file + len - 1;
  for (; i - file >= 0; --i) {
    if (*i == '/')
      break;
    if (*i == '.') {
      char *ret = (char *)malloc((i - file) + strlen(ext) + 1);
      strncpy(ret, file, i - file);
      strcpy(ret + (i - file), ext);
      return ret;
    }
  }
  char *ret = (char *)malloc(len + strlen(ext));
  strcpy(ret, file);
  strcpy(ret + len, ext);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getOutFileName>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%rbx
  mov    %rax,%r12
  lea    0x0(%rbp,%rbx,1),%rax
  cmp    $0xffffffffffffffff,%rbx
  jne    L19
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L37:
  cmp    $0x2e,%dl
  je     L45
  sub    $0x1,%rax
  mov    %rax,%rbx
  sub    %rbp,%rbx
  js     L35
L19:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  jne    L37
L35:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    (%rax,%r12,1),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    (%r14,%r12,1),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    (%r14,%rbx,1),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *getOutFileName(char const *file, const char *ext) {
  size_t len = strlen(file);
  char const *i = file + len - 1;
  for (; i - file >= 0; --i) {
    if (*i == '/')
      break;
    if (*i == '.') {
      char *ret = (char *)malloc((i - file) + strlen(ext) + 1);
      strncpy(ret, file, i - file);
      strcpy(ret + (i - file), ext);
      return ret;
    }
  }
  char *ret = (char *)malloc(len + strlen(ext));
  strcpy(ret, file);
  strcpy(ret + len, ext);
  return ret;
}
```