ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0xffffffff,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  movl   $0x8,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <isSorted@plt>
  test   %rax,%rax
  je     L25
  lea    D3(%rip),%rax
  jmp    L6
L25:
  lea    D0(%rip),%rax
L6:
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string

tool: D3: Yes

tool: D0: No

tool: D8: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int a[] = {0, -1, 2, 3, 4, 5, 6, 7};
  int nArray = sizeof(a) / sizeof(*a);
  printf("%s\n", isSorted(a, nArray) ? "Yes" : "No");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  mov    %rsp,%rdi
  mov    $0x8,%esi
  call   <isSorted@plt>
  test   %rax,%rax
  lea    D7(%rip),%rsi
  lea    D20(%rip),%rax
  cmove  %rax,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D7: Yes

tool: D20: No

tool: D4: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int a[] = {0, -1, 2, 3, 4, 5, 6, 7};
  int nArray = sizeof(a) / sizeof(*a);
  printf("%s\n", isSorted(a, nArray) ? "Yes" : "No");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x8,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xffffffff00000000,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x18(%rsp)
  call   <isSorted@plt>
  lea    D14(%rip),%rsi
  lea    D8(%rip),%rdi
  test   %rax,%rax
  lea    D26(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
datatype: string
name: extract_symbolic_data
arguments: tag: D8
datatype: string
name: extract_symbolic_data
arguments: tag: D26
datatype: string

tool: D14: Yes

tool: D8: %s


tool: D26: No

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[] = {0, -1, 2, 3, 4, 5, 6, 7};
  int nArray = sizeof(a) / sizeof(*a);
  printf("%s\n", isSorted(a, nArray) ? "Yes" : "No");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D9(%rip),%xmm0
  mov    $0x8,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <isSorted@plt>
  lea    D41(%rip),%rsi
  lea    D24(%rip),%rdi
  test   %rax,%rax
  lea    D42(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type: byte[16]
name: parse_data
arguments: data_label: D7
type: byte[16]
name: parse_data
arguments: data_label: D41
type: string
name: parse_data
arguments: data_label: D24
type: string
name: parse_data
arguments: data_label: D42
type: string

tool: {"D9": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D7": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: D41: Yes

tool: D24: %s


tool: D42: No

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[] = {0, -1, 2, 3, 4, 5, 6, 7};
  int nArray = sizeof(a) / sizeof(*a);
  printf("%s\n", isSorted(a, nArray) ? "Yes" : "No");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quadError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L15
L16:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L16
  movsd  -0x10(%rbp),%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: f64

tool: D6: 2

assistant: ```c
double quadError(double *values, double *true_values, int num_values) {
  int i;
  double result = 0., temp;
  for (i = 1; i < num_values; i++) {
    temp = true_values[i] - values[i];
    result += temp * temp;
  }
  return result / 2.;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quadError>:
  endbr64
  cmp    $0x1,%edx
  jle    L20
  mov    %edx,%edx
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
L16:
  movsd  (%rsi,%rax,8),%xmm1
  subsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
L1:
  mulsd  D2(%rip),%xmm0
  ret
L20:
  pxor   %xmm0,%xmm0
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: f32[2]

tool: {"D2": [0.0,1.75]}

assistant: ```c
double quadError(double *values, double *true_values, int num_values) {
  int i;
  double result = 0., temp;
  for (i = 1; i < num_values; i++) {
    temp = true_values[i] - values[i];
    result += temp * temp;
  }
  return result / 2.;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quadError>:
  endbr64
  cmp    $0x1,%edx
  jle    L11
  movslq %edx,%rdx
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
  nopl   (%rax)
L15:
  movsd  (%rsi,%rax,8),%xmm1
  subsd  (%rdi,%rax,8),%xmm1
  add    $0x1,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L15
  mulsd  D7(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L11:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: f32[2]

tool: {"D7": [0.0,1.75]}

assistant: ```c
double quadError(double *values, double *true_values, int num_values) {
  int i;
  double result = 0., temp;
  for (i = 1; i < num_values; i++) {
    temp = true_values[i] - values[i];
    result += temp * temp;
  }
  return result / 2.;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quadError>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x1,%edx
  jle    L34
  lea    -0x1(%rdx),%edi
  cmp    $0x2,%edx
  je     L30
  mov    %edi,%eax
  pxor   %xmm0,%xmm0
  shr    %eax
  lea    -0x1(%rax),%edx
  mov    $0x8,%eax
  shl    $0x4,%rdx
  add    $0x18,%rdx
  nopl   0x0(%rax)
L18:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm3
  add    $0x10,%rax
  subpd  %xmm3,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L18
  mov    %edi,%eax
  or     $0x1,%eax
  and    $0x1,%edi
  je     L6
L28:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  subsd  (%rcx,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L6:
  mulsd  D5(%rip),%xmm0
  ret
  xchg   %ax,%ax
L34:
  pxor   %xmm0,%xmm0
  ret
L30:
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  jmp    L28
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: f32[2]

tool: {"D5": [0.0,1.75]}

assistant: ```c
double quadError(double *values, double *true_values, int num_values) {
  int i;
  double result = 0., temp;
  for (i = 1; i < num_values; i++) {
    temp = true_values[i] - values[i];
    result += temp * temp;
  }
  return result / 2.;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    -0x18(%rbp),%rax
  jmp    L56
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L4:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L4
  jmp    L71
L25:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
L71:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L25
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L25
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L25
  mov    -0x18(%rbp),%rax
L56:
  leave
  ret
```

assistant: ```c
char *trim(char *text) {
  if (!*text)
    return text;
  for (char *ch = text + strlen(text) - 1; isspace((int)*ch) || *ch == '\'' || *ch == '\"'; *ch-- = '\0')
    ;
  for (; isspace((int)*text) || *text == '\'' || *text == '\"'; *text++ = '\0')
    ;
  return text;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  jne    L14
L28:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  jmp    L74
L15:
  sub    $0x1,%rbp
  movb   $0x0,0x1(%rbp)
L74:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  movzbl 0x0(%rbp),%eax
  cmp    $0x22,%al
  je     L15
  cmp    $0x27,%al
  je     L15
  jmp    L88
L56:
  add    $0x1,%rbx
  movb   $0x0,-0x1(%rbx)
L88:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L56
  movzbl (%rbx),%eax
  cmp    $0x22,%al
  je     L56
  cmp    $0x27,%al
  je     L56
  jmp    L28
```

assistant: ```c
char *trim(char *text) {
  if (!*text)
    return text;
  for (char *ch = text + strlen(text) - 1; isspace((int)*ch) || *ch == '\'' || *ch == '\"'; *ch-- = '\0')
    ;
  for (; isspace((int)*text) || *text == '\'' || *text == '\"'; *text++ = '\0')
    ;
  return text;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L24
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L24:
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L79
  xchg   %ax,%ax
L19:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L79:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  movzbl (%rbx),%eax
  cmp    $0x22,%al
  je     L19
  cmp    $0x27,%al
  je     L19
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L69
  xchg   %ax,%ax
L32:
  movb   $0x0,(%r12)
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
L69:
  movzbl (%r12),%eax
  cmp    $0x22,%al
  je     L32
  cmp    $0x27,%al
  je     L32
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *text) {
  if (!*text)
    return text;
  for (char *ch = text + strlen(text) - 1; isspace((int)*ch) || *ch == '\'' || *ch == '\"'; *ch-- = '\0')
    ;
  for (; isspace((int)*text) || *text == '\'' || *text == '\"'; *text++ = '\0')
    ;
  return text;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L78
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L78:
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L57
  xchg   %ax,%ax
L47:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L57:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L47
  movzbl (%rbx),%eax
  cmp    $0x22,%al
  je     L47
  cmp    $0x27,%al
  je     L47
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L82
  xchg   %ax,%ax
L0:
  movb   $0x0,(%r12)
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  call   <isspace@plt>
  test   %rax,%rax
  jne    L0
L82:
  movzbl (%r12),%eax
  cmp    $0x22,%al
  je     L0
  cmp    $0x27,%al
  je     L0
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *text) {
  if (!*text)
    return text;
  for (char *ch = text + strlen(text) - 1; isspace((int)*ch) || *ch == '\'' || *ch == '\"'; *ch-- = '\0')
    ;
  for (; isspace((int)*text) || *text == '\'' || *text == '\"'; *text++ = '\0')
    ;
  return text;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<baud_down>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <term_baud_down@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int baud_down(int baud) {
  int nb;
  nb = term_baud_down(baud);
  if (nb == 0)
    nb = baud;
  return nb;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<baud_down>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <term_baud_down@plt>
  test   %eax,%eax
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int baud_down(int baud) {
  int nb;
  nb = term_baud_down(baud);
  if (nb == 0)
    nb = baud;
  return nb;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<baud_down>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <term_baud_down@plt>
  test   %eax,%eax
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int baud_down(int baud) {
  int nb;
  nb = term_baud_down(baud);
  if (nb == 0)
    nb = baud;
  return nb;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<baud_down>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <term_baud_down@plt>
  test   %eax,%eax
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int baud_down(int baud) {
  int nb;
  nb = term_baud_down(baud);
  if (nb == 0)
    nb = baud;
  return nb;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <foo@plt>
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
int main2() {
  foo();
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main2() {
  foo();
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main2>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
int main2() {
  foo();
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main2>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
int main2() {
  foo();
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<file_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <file_header@plt>
L22:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <file_next@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x10(%rbp),%xmm0
  ja     L37
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <file_next@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0xc(%rbp),%xmm0
  ja     L38
  movss  -0xc(%rbp),%xmm0
  subss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
  movss  -0x8(%rbp),%xmm0
  subss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  -0x1c(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x8(%rbp),%xmm0
  subss  -0x1c(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x8(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L22
L37:
  nop
  jmp    L25
L38:
  nop
L25:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  pxor   %xmm3,%xmm3
  cvtss2sd -0x1c(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x18(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D32
type_guessed: string
name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D36
type_guessed: string
name: read_data
arguments: data_tag: D23
type_guessed: string

tool: D32: %f


tool: D5: 


tool: D36: Mean:     %f


tool: D23: Std. Dev: %f


assistant: ```c
void file_read(FILE *file) {
  float time1;
  float time2;
  float diff;
  float mean;
  float var;
  float delta;
  int num;
  num = 0;
  var = 0.0f;
  mean = 0.0f;
  file_header(file);
  while (1) {
    time1 = file_next(file);
    if (time1 < 0)
      break;
    time2 = file_next(file);
    if (time2 < 0)
      break;
    diff = time2 - time1;
    num++;
    delta = diff - mean;
    mean += delta / num;
    var += delta * (diff - mean);
    printf("%f\n", diff);
  }
  printf("\n\n");
  printf("Mean:     %f\n", mean);
  printf("Std. Dev: %f\n", sqrt(var / (num - 1)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  call   <file_header@plt>
  mov    $0x0,%ebx
  pxor   %xmm3,%xmm3
  movss  %xmm3,0x8(%rsp)
  movss  %xmm3,0x4(%rsp)
  lea    D31(%rip),%r12
  jmp    L23
L27:
  subss  0xc(%rsp),%xmm0
  add    $0x1,%ebx
  movaps %xmm0,%xmm2
  movss  0x4(%rsp),%xmm6
  subss  %xmm6,%xmm2
  pxor   %xmm3,%xmm3
  cvtsi2ss %ebx,%xmm3
  movaps %xmm2,%xmm1
  divss  %xmm3,%xmm1
  addss  %xmm6,%xmm1
  movaps %xmm1,%xmm4
  movss  %xmm1,0x4(%rsp)
  movaps %xmm0,%xmm1
  subss  %xmm4,%xmm1
  mulss  %xmm2,%xmm1
  addss  0x8(%rsp),%xmm1
  movss  %xmm1,0x8(%rsp)
  cvtss2sd %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L23:
  mov    %rbp,%rdi
  call   <file_next@plt>
  pxor   %xmm7,%xmm7
  movss  %xmm0,0xc(%rsp)
  comiss %xmm0,%xmm7
  ja     L0
  mov    %rbp,%rdi
  call   <file_next@plt>
  pxor   %xmm3,%xmm3
  comiss %xmm0,%xmm3
  jbe    L27
L0:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  movss  0x8(%rsp),%xmm0
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  lea    D5(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D31
type: string
name: parse_data
arguments: tag: D27
type: string
name: parse_data
arguments: tag: D36
type: string
name: parse_data
arguments: tag: D5
type: string

tool: D31: %f


tool: D27: 


tool: D36: Mean:     %f


tool: D5: Std. Dev: %f


assistant: ```c
void file_read(FILE *file) {
  float time1;
  float time2;
  float diff;
  float mean;
  float var;
  float delta;
  int num;
  num = 0;
  var = 0.0f;
  mean = 0.0f;
  file_header(file);
  while (1) {
    time1 = file_next(file);
    if (time1 < 0)
      break;
    time2 = file_next(file);
    if (time2 < 0)
      break;
    diff = time2 - time1;
    num++;
    delta = diff - mean;
    mean += delta / num;
    var += delta * (diff - mean);
    printf("%f\n", diff);
  }
  printf("\n\n");
  printf("Mean:     %f\n", mean);
  printf("Std. Dev: %f\n", sqrt(var / (num - 1)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<file_read>:
  endbr64
  push   %r12
  lea    D36(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  call   <file_header@plt>
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  jmp    L4
  nop
L28:
  mov    %rbp,%rdi
  call   <file_next@plt>
  pxor   %xmm7,%xmm7
  comiss %xmm0,%xmm7
  ja     L25
  movss  0xc(%rsp),%xmm1
  add    $0x1,%ebx
  pxor   %xmm3,%xmm3
  mov    %r12,%rdi
  movss  0x4(%rsp),%xmm5
  cvtsi2ss %ebx,%xmm3
  mov    $0x1,%eax
  subss  %xmm1,%xmm0
  movaps %xmm0,%xmm2
  subss  %xmm5,%xmm2
  movaps %xmm2,%xmm1
  divss  %xmm3,%xmm1
  addss  %xmm5,%xmm1
  movaps %xmm1,%xmm4
  movss  %xmm1,0x4(%rsp)
  movaps %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  subss  %xmm4,%xmm1
  mulss  %xmm2,%xmm1
  addss  0x8(%rsp),%xmm1
  movss  %xmm1,0x8(%rsp)
  call   <printf@plt>
L4:
  mov    %rbp,%rdi
  call   <file_next@plt>
  pxor   %xmm6,%xmm6
  comiss %xmm0,%xmm6
  movss  %xmm0,0xc(%rsp)
  jbe    L28
L25:
  lea    D18(%rip),%rdi
  sub    $0x1,%ebx
  call   <puts@plt>
  lea    D23(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x4(%rsp),%xmm0
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0x8(%rsp),%xmm0
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  add    $0x10,%rsp
  mov    $0x1,%eax
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10a0 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D36
type: string
name: read_data
arguments: data_label: D18
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D8
type: string

tool: D36: %f


tool: D18: 


tool: D23: Mean:     %f


tool: D8: Std. Dev: %f


assistant: ```c
void file_read(FILE *file) {
  float time1;
  float time2;
  float diff;
  float mean;
  float var;
  float delta;
  int num;
  num = 0;
  var = 0.0f;
  mean = 0.0f;
  file_header(file);
  while (1) {
    time1 = file_next(file);
    if (time1 < 0)
      break;
    time2 = file_next(file);
    if (time2 < 0)
      break;
    diff = time2 - time1;
    num++;
    delta = diff - mean;
    mean += delta / num;
    var += delta * (diff - mean);
    printf("%f\n", diff);
  }
  printf("\n\n");
  printf("Mean:     %f\n", mean);
  printf("Std. Dev: %f\n", sqrt(var / (num - 1)));
}
```