ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<writeFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L12
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L12:
  movabs $0x7257206f6c6c6548,%rax
  mov    %rax,-0x17(%rbp)
  movl   $0x72657469,-0xf(%rbp)
  movw   $0xa21,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x17(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D24
type_infered: string
name: parse_data
arguments: label: D26
type_infered: string

tool: D0: a

tool: D24: File opening error.


tool: D26: %s

assistant: ```c
void writeFile(char *fileName) {
  FILE *log;
  log = fopen(fileName, "a");
  if (!log) {
    printf("File opening error.\n");
    exit(1);
  }
  char hello[] = "Hello Writer!\n";
  fprintf(log, "%s", hello);
  fclose(log);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<writeFile>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
L14:
  movabs $0x7257206f6c6c6548,%rax
  mov    %rax,0x9(%rsp)
  movl   $0x72657469,0x11(%rsp)
  movw   $0xa21,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0x9(%rsp),%rdx
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L14
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: string
name: disassemble_data
arguments: tag: D24
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D18: a

tool: D24: %s

tool: D4: File opening error.


assistant: ```c
void writeFile(char *fileName) {
  FILE *log;
  log = fopen(fileName, "a");
  if (!log) {
    printf("File opening error.\n");
    exit(1);
  }
  char hello[] = "Hello Writer!\n";
  fprintf(log, "%s", hello);
  fclose(log);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writeFile>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
L16:
  mov    %rbp,%rdi
  lea    0x9(%rsp),%rdx
  movabs $0x7257206f6c6c6548,%rax
  movl   $0x72657469,0x11(%rsp)
  mov    %rax,0x9(%rsp)
  lea    D17(%rip),%rsi
  mov    $0xa21,%eax
  mov    %ax,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L6:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L16
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D0
datatype: string

tool: D10: a

tool: D17: %s

tool: D0: File opening error.


assistant: ```c
void writeFile(char *fileName) {
  FILE *log;
  log = fopen(fileName, "a");
  if (!log) {
    printf("File opening error.\n");
    exit(1);
  }
  char hello[] = "Hello Writer!\n";
  fprintf(log, "%s", hello);
  fclose(log);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writeFile>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L22
L14:
  mov    %rbp,%rdi
  lea    0x9(%rsp),%rdx
  movabs $0x7257206f6c6c6548,%rax
  movl   $0x72657469,0x11(%rsp)
  mov    %rax,0x9(%rsp)
  lea    D25(%rip),%rsi
  mov    $0xa21,%eax
  mov    %ax,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L22:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L14
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string

tool: D18: a

tool: D25: %s

tool: D23: File opening error.


assistant: ```c
void writeFile(char *fileName) {
  FILE *log;
  log = fopen(fileName, "a");
  if (!log) {
    printf("File opening error.\n");
    exit(1);
  }
  char hello[] = "Hello Writer!\n";
  fprintf(log, "%s", hello);
  fclose(log);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<linux_at_least>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <uname@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x14(%rbp),%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    D5(%rip),%rsi
  mov    %eax,%edi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L58
L3:
  mov    $0x0,%eax
  jmp    L66
L58:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jb     L93
  cmpl   $0x0,-0x24(%rbp)
  je     L24
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  ja     L24
  mov    $0x1,%eax
  jmp    L91
L24:
  mov    $0x0,%eax
L91:
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L99
L93:
  mov    $0x1,%eax
  jmp    L66
L99:
  mov    $0x0,%eax
L66:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L96
  call   <__stack_chk_fail@plt>
L96:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D5: %u.%u.

assistant: ```c
bool linux_at_least(unsigned version_first, unsigned version_second) {
  struct utsname info;
  unsigned first, second;
  if (uname(&info) != 0 || sscanf(info.release, "%u.%u.", &first, &second) != 2) {
    return false;
  } else {
    return first > version_first || (first = version_first && second >= version_second);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<linux_at_least>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <uname@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L34
L47:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L34:
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D4(%rip),%rsi
  mov    0xc(%rsp),%edi
  call   <sscanf@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x2,%edx
  jne    L47
  mov    $0x1,%eax
  cmp    %ebx,0x10(%rsp)
  ja     L47
  mov    $0x0,%eax
  test   %ebx,%ebx
  je     L47
  cmp    %ebp,0x14(%rsp)
  setae  %al
  movzbl %al,%eax
  jmp    L47
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: %u.%u.

assistant: ```c
bool linux_at_least(unsigned version_first, unsigned version_second) {
  struct utsname info;
  unsigned first, second;
  if (uname(&info) != 0 || sscanf(info.release, "%u.%u.", &first, &second) != 2) {
    return false;
  } else {
    return first > version_first || (first = version_first && second >= version_second);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<linux_at_least>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <uname@plt>
  test   %rax,%rax
  je     L10
L1:
  xor    %eax,%eax
L4:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    0xc(%rsp),%edi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D4(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L1
  mov    $0x1,%eax
  cmp    %ebp,0x10(%rsp)
  ja     L4
  test   %ebp,%ebp
  je     L1
  cmp    %ebx,0x14(%rsp)
  jae    L4
  jmp    L1
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string

tool: D4: %u.%u.

assistant: ```c
bool linux_at_least(unsigned version_first, unsigned version_second) {
  struct utsname info;
  unsigned first, second;
  if (uname(&info) != 0 || sscanf(info.release, "%u.%u.", &first, &second) != 2) {
    return false;
  } else {
    return first > version_first || (first = version_first && second >= version_second);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<linux_at_least>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <uname@plt>
  test   %rax,%rax
  je     L56
L14:
  xor    %eax,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    0xc(%rsp),%edi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L14
  mov    $0x1,%eax
  cmp    %ebp,0x10(%rsp)
  ja     L6
  test   %ebp,%ebp
  je     L14
  cmp    %ebx,0x14(%rsp)
  jae    L6
  jmp    L14
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: %u.%u.

assistant: ```c
bool linux_at_least(unsigned version_first, unsigned version_second) {
  struct utsname info;
  unsigned first, second;
  if (uname(&info) != 0 || sscanf(info.release, "%u.%u.", &first, &second) != 2) {
    return false;
  } else {
    return first > version_first || (first = version_first && second >= version_second);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<searchRange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x2,(%rax)
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L44:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jg     L71
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jne    L0
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L0
L71:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L44
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L82
L56:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jl     L36
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jne    L82
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L82
L36:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L82:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L56
  mov    -0x8(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *searchRange(int *nums, int numsSize, int target, int *returnSize) {
  int l = -1, r = -1;
  int *indexes = (int *)malloc(sizeof(int) * 2);
  *returnSize = 2;
  int low = 0, high = numsSize - 1;
  int mid = 0;
  while (low <= high) {
    mid = (low + high) / 2;
    if (nums[mid] >= target) {
      high = mid - 1;
      if (nums[mid] == target)
        l = mid;
    } else
      low = mid + 1;
  }
  low = 0, high = numsSize - 1;
  while (low <= high) {
    mid = (low + high) / 2;
    if (nums[mid] <= target) {
      low = mid + 1;
      if (nums[mid] == target)
        r = mid;
    } else
      high = mid - 1;
  }
  indexes[0] = l;
  indexes[1] = r;
  return indexes;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<searchRange>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    %rcx,%r13
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  movl   $0x2,0x0(%r13)
  mov    %r12d,%edx
  sub    $0x1,%edx
  js     L25
  mov    %edx,%r9d
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  jmp    L61
L7:
  lea    0x1(%rax),%esi
L64:
  cmp    %esi,%r9d
  jl     L85
L61:
  lea    (%rsi,%r9,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ebx,%ecx
  jl     L7
  lea    -0x1(%rax),%r9d
  cmove  %eax,%edi
  jmp    L64
L85:
  mov    $0x0,%esi
  mov    $0xffffffff,%r9d
  jmp    L41
L17:
  lea    -0x1(%rax),%edx
L6:
  cmp    %edx,%esi
  jg     L48
L41:
  lea    (%rsi,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ebx,%ecx
  jg     L17
  lea    0x1(%rax),%esi
  cmove  %eax,%r9d
  jmp    L6
L25:
  mov    $0xffffffff,%edi
  mov    $0xffffffff,%r9d
L48:
  mov    %edi,(%r8)
  mov    %r9d,0x4(%r8)
  mov    %r8,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *searchRange(int *nums, int numsSize, int target, int *returnSize) {
  int l = -1, r = -1;
  int *indexes = (int *)malloc(sizeof(int) * 2);
  *returnSize = 2;
  int low = 0, high = numsSize - 1;
  int mid = 0;
  while (low <= high) {
    mid = (low + high) / 2;
    if (nums[mid] >= target) {
      high = mid - 1;
      if (nums[mid] == target)
        l = mid;
    } else
      low = mid + 1;
  }
  low = 0, high = numsSize - 1;
  while (low <= high) {
    mid = (low + high) / 2;
    if (nums[mid] <= target) {
      low = mid + 1;
      if (nums[mid] == target)
        r = mid;
    } else
      high = mid - 1;
  }
  indexes[0] = l;
  indexes[1] = r;
  return indexes;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<searchRange>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r12d,%edx
  movl   $0x2,0x0(%r13)
  mov    %rax,%r9
  sub    $0x1,%edx
  js     L77
  mov    %edx,%esi
  xor    %ecx,%ecx
  mov    $0xffffffff,%r8d
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L56:
  lea    -0x1(%rax),%esi
  cmove  %eax,%r8d
  cmp    %esi,%ecx
  jg     L97
L62:
  lea    (%rcx,%rsi,1),%eax
  sar    %eax
  movslq %eax,%rdi
  mov    0x0(%rbp,%rdi,4),%edi
  cmp    %ebx,%edi
  jge    L56
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L62
L97:
  xor    %ecx,%ecx
  mov    $0xffffffff,%edi
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L16:
  lea    0x1(%rax),%ecx
  cmove  %eax,%edi
  cmp    %ecx,%edx
  jl     L7
L49:
  lea    (%rcx,%rdx,1),%eax
  sar    %eax
  movslq %eax,%rsi
  mov    0x0(%rbp,%rsi,4),%esi
  cmp    %ebx,%esi
  jle    L16
  lea    -0x1(%rax),%edx
  cmp    %ecx,%edx
  jge    L49
L7:
  mov    %r8d,(%r9)
  mov    %r9,%rax
  mov    %edi,0x4(%r9)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L77:
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%edi
  jmp    L7
```

assistant: ```c
int *searchRange(int *nums, int numsSize, int target, int *returnSize) {
  int l = -1, r = -1;
  int *indexes = (int *)malloc(sizeof(int) * 2);
  *returnSize = 2;
  int low = 0, high = numsSize - 1;
  int mid = 0;
  while (low <= high) {
    mid = (low + high) / 2;
    if (nums[mid] >= target) {
      high = mid - 1;
      if (nums[mid] == target)
        l = mid;
    } else
      low = mid + 1;
  }
  low = 0, high = numsSize - 1;
  while (low <= high) {
    mid = (low + high) / 2;
    if (nums[mid] <= target) {
      low = mid + 1;
      if (nums[mid] == target)
        r = mid;
    } else
      high = mid - 1;
  }
  indexes[0] = l;
  indexes[1] = r;
  return indexes;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<searchRange>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r12d,%edx
  movl   $0x2,0x0(%r13)
  mov    %rax,%r9
  sub    $0x1,%edx
  js     L37
  mov    %edx,%esi
  xor    %ecx,%ecx
  mov    $0xffffffff,%r8d
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L20:
  lea    -0x1(%rax),%esi
  cmove  %eax,%r8d
  cmp    %esi,%ecx
  jg     L9
L30:
  lea    (%rcx,%rsi,1),%eax
  sar    %eax
  movslq %eax,%rdi
  mov    0x0(%rbp,%rdi,4),%edi
  cmp    %edi,%ebx
  jle    L20
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L30
L9:
  xor    %ecx,%ecx
  mov    $0xffffffff,%edi
  jmp    L71
  nopl   0x0(%rax,%rax,1)
L51:
  lea    0x1(%rax),%ecx
  cmove  %eax,%edi
  cmp    %ecx,%edx
  jl     L32
L71:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%rsi
  mov    0x0(%rbp,%rsi,4),%esi
  cmp    %esi,%ebx
  jge    L51
  lea    -0x1(%rax),%edx
  cmp    %ecx,%edx
  jge    L71
L32:
  mov    %r8d,(%r9)
  mov    %r9,%rax
  mov    %edi,0x4(%r9)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L37:
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%edi
  jmp    L32
```

assistant: ```c
int *searchRange(int *nums, int numsSize, int target, int *returnSize) {
  int l = -1, r = -1;
  int *indexes = (int *)malloc(sizeof(int) * 2);
  *returnSize = 2;
  int low = 0, high = numsSize - 1;
  int mid = 0;
  while (low <= high) {
    mid = (low + high) / 2;
    if (nums[mid] >= target) {
      high = mid - 1;
      if (nums[mid] == target)
        l = mid;
    } else
      low = mid + 1;
  }
  low = 0, high = numsSize - 1;
  while (low <= high) {
    mid = (low + high) / 2;
    if (nums[mid] <= target) {
      low = mid + 1;
      if (nums[mid] == target)
        r = mid;
    } else
      high = mid - 1;
  }
  indexes[0] = l;
  indexes[1] = r;
  return indexes;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<LeftShift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jle    L15
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L15
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Reverse@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Reverse@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Reverse@plt>
L15:
  nop
  leave
  ret
```

assistant: ```c
void LeftShift(int R[], int n, int p) {
  if (p > 0 && p < n) {
    Reverse(R, 0, n - 1);
    Reverse(R, 0, n - 1 - p);
    Reverse(R, n - p, n - 1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LeftShift>:
  endbr64
  test   %edx,%edx
  jle    L6
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  cmp    %esi,%edx
  jl     L11
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  lea    -0x1(%rsi),%r13d
  mov    %r13d,%edx
  mov    $0x0,%esi
  call   <Reverse@plt>
  mov    %r13d,%edx
  sub    %ebx,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <Reverse@plt>
  mov    %ebp,%esi
  sub    %ebx,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <Reverse@plt>
  jmp    L17
L6:
  ret
```

assistant: ```c
void LeftShift(int R[], int n, int p) {
  if (p > 0 && p < n) {
    Reverse(R, 0, n - 1);
    Reverse(R, 0, n - 1 - p);
    Reverse(R, n - p, n - 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<LeftShift>:
  endbr64
  test   %edx,%edx
  jle    L17
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    %esi,%edx
  jl     L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  lea    -0x1(%rsi),%r13d
  xor    %esi,%esi
  mov    %rdi,%r12
  mov    %r13d,%edx
  call   <Reverse@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  xor    %esi,%esi
  sub    %ebx,%edx
  call   <Reverse@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r13d,%edx
  sub    %ebx,%esi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <Reverse@plt>
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
void LeftShift(int R[], int n, int p) {
  if (p > 0 && p < n) {
    Reverse(R, 0, n - 1);
    Reverse(R, 0, n - 1 - p);
    Reverse(R, n - p, n - 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LeftShift>:
  endbr64
  test   %edx,%edx
  jle    L10
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    %esi,%edx
  jl     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L9:
  lea    -0x1(%rsi),%r13d
  xor    %esi,%esi
  mov    %rdi,%r12
  mov    %r13d,%edx
  call   <Reverse@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  xor    %esi,%esi
  sub    %ebx,%edx
  call   <Reverse@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r13d,%edx
  sub    %ebx,%esi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <Reverse@plt>
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
void LeftShift(int R[], int n, int p) {
  if (p > 0 && p < n) {
    Reverse(R, 0, n - 1);
    Reverse(R, 0, n - 1 - p);
    Reverse(R, n - p, n - 1);
  }
}
```