user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1d000(%rsp),%r11
L253:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L253
  sub    $0x4f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1d4e8(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  cmp    %eax,0x14(%rsp)
  jne    L101
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    D33(%rip),%r12
  cmpl   $0x0,0x10(%rsp)
  jg     L200
L189:
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    D33(%rip),%r12
  cmpl   $0x0,0x18(%rsp)
  jg     L104
  jmp    L42
L12:
  lea    0x20(%rsp,%r14,4),%rbp
  mov    $0x0,%ebx
L142:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x14(%rsp)
  jg     L142
L99:
  add    $0x1,%r13d
  add    $0x64,%r14
  cmp    %r13d,0x10(%rsp)
  jle    L189
L200:
  cmpl   $0x0,0x14(%rsp)
  jg     L12
  jmp    L99
L238:
  lea    0x9c60(%rsp,%r14,4),%rbp
  mov    $0x0,%ebx
L28:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x1c(%rsp)
  jg     L28
L63:
  add    $0x1,%r13d
  mov    0x18(%rsp),%eax
  add    $0x64,%r14
  cmp    %r13d,%eax
  jle    L141
L104:
  cmpl   $0x0,0x1c(%rsp)
  jg     L238
  jmp    L63
L141:
  test   %eax,%eax
  jle    L42
  mov    0x14(%rsp),%r13d
  mov    0x10(%rsp),%ebx
  lea    0x138a0(%rsp),%r12
  lea    0x20(%rsp),%r11
  lea    -0x1(%rax),%eax
  imul   $0x190,%rax,%rax
  lea    0x1b0(%rsp,%rax,1),%r15
  lea    0x9c60(%rsp),%r14
  lea    -0x1(%rbx),%eax
  imul   $0x190,%rax,%rax
  lea    0x9df0(%rsp,%rax,1),%rax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r13),%eax
  lea    0x9c64(%rsp,%rax,4),%rbp
  jmp    L125
L166:
  mov    %r8,%r10
  movl   $0x0,(%r8)
  test   %ebx,%ebx
  jle    L36
  mov    %r9,%rax
  mov    %r11,%rcx
  mov    $0x0,%esi
L239:
  mov    (%rcx),%edx
  imul   (%rax),%edx
  add    %edx,%esi
  add    $0x4,%rcx
  add    $0x190,%rax
  cmp    %rdi,%rax
  jne    L239
  mov    %esi,(%r10)
L36:
  add    $0x4,%r8
  add    $0x4,%r9
  add    $0x4,%rdi
  cmp    %rbp,%r9
  jne    L166
L17:
  add    $0x190,%r12
  add    $0x190,%r11
  cmp    %r15,%r11
  je     L234
L125:
  mov    0x8(%rsp),%rdi
  mov    %r14,%r9
  mov    %r12,%r8
  test   %r13d,%r13d
  jg     L166
  jmp    L17
L75:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x1c(%rsp)
  jg     L75
L231:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    $0x190,%rbp
  cmp    %r13d,0x18(%rsp)
  jle    L42
L155:
  mov    $0x0,%ebx
  cmpl   $0x0,0x1c(%rsp)
  jg     L75
  jmp    L231
L101:
  lea    D48(%rip),%rdi
  call   <puts@plt>
L42:
  mov    0x1d4e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L175
  mov    $0x0,%eax
  add    $0x1d4f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L234:
  lea    0x138a0(%rsp),%rbp
  mov    $0x0,%r13d
  lea    D37(%rip),%r12
  jmp    L155
L175:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D33
datatype: string
name: unpack_data
arguments: label: D48
datatype: string
name: unpack_data
arguments: label: D37
datatype: string

tool: D4: %d %d

tool: D33: %d

tool: D48: Multiplication can not be done!

tool: D37: %d	

assistant: ```c
int main() {
  int a[100][100], b[100][100], c[100][100];
  int i, j, k, tmp, m1, n1, m2, n2;
  scanf("%d %d", &m1, &n1);
  scanf("%d %d", &m2, &n2);
  if (n1 == m2) {
    for (i = 0; i < m1; i++) {
      for (j = 0; j < n1; j++) {
        scanf("%d", &a[i][j]);
      }
    }
    for (i = 0; i < m2; i++) {
      for (j = 0; j < n2; j++) {
        scanf("%d", &b[i][j]);
      }
    }
    for (i = 0; i < m2; i++) {
      for (j = 0; j < n1; j++) {
        c[i][j] = 0;
        for (k = 0; k < m1; k++) {
          c[i][j] = c[i][j] + a[i][k] * b[k][j];
        }
      }
    }
    for (i = 0; i < m2; i++) {
      for (j = 0; j < n2; j++) {
        printf("%d\t", c[i][j]);
      }
      printf("\n");
    }
  } else {
    printf("Multiplication can not be done!\n");
  }
  return 0;
}
```