ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  movdqa D50(%rip),%xmm0
  lea    D52(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movdqa D15(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D5(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D20(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <dump_array@plt>
  movdqa (%rsp),%xmm0
  movdqa 0x20(%rsp),%xmm1
  lea    D24(%rip),%rdi
  movdqa %xmm0,%xmm2
  shufps $0x88,0x10(%rsp),%xmm2
  movdqa %xmm2,%xmm4
  shufps $0xdd,0x10(%rsp),%xmm0
  movdqa %xmm1,%xmm3
  shufps $0x88,0x30(%rsp),%xmm3
  shufps $0x88,%xmm3,%xmm4
  movaps %xmm4,0x40(%rsp)
  movdqa %xmm0,%xmm4
  shufps $0xdd,0x30(%rsp),%xmm1
  shufps $0xdd,%xmm3,%xmm2
  shufps $0xdd,%xmm1,%xmm0
  shufps $0x88,%xmm1,%xmm4
  movaps %xmm2,0x60(%rsp)
  movaps %xmm4,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <printf@plt>
  lea    0x40(%rsp),%rdi
  call   <dump_array@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x98,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D50
data_type: byte[16]
name: parse_data
arguments: data_label: D52
data_type: string
name: parse_data
arguments: data_label: D15
data_type: byte[16]
name: parse_data
arguments: data_label: D5
data_type: byte[16]
name: parse_data
arguments: data_label: D20
data_type: byte[16]
name: parse_data
arguments: data_label: D24
data_type: string

tool: {"D50": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D52: Contents of nums:


tool: {"D15": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D5": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D20": [0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

tool: D24: 
Transposed array:


assistant: ```c
int main() {
  int nums[4][4], another[4][4];
  unsigned i, j;
  for (i = 0; i < 4; ++i)
    for (j = 0; j < 4; ++j)
      nums[i][j] = i * 4 + j;
  printf("Contents of nums:\n");
  dump_array(nums);
  for (i = 0; i < 4; ++i)
    for (j = 0; j < 4; ++j)
      another[j][i] = nums[i][j];
  printf("\nTransposed array:\n");
  dump_array(another);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L15
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x1,%eax
  je     L17
L15:
  mov    $0x0,%eax
  call   <abort@plt>
L17:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (foo(0) != 0 || foo(1) != 1)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x1,%eax
  je     L18
L6:
  mov    $0x0,%eax
  call   <abort@plt>
L18:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(0) != 0 || foo(1) != 1)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L14
  mov    $0x1,%edi
  call   <foo@plt>
  sub    $0x1,%eax
  je     L12
L14:
  xor    %eax,%eax
  call   <abort@plt>
L12:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(0) != 0 || foo(1) != 1)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L0
  mov    $0x1,%edi
  call   <foo@plt>
  sub    $0x1,%eax
  je     L11
L0:
  xor    %eax,%eax
  call   <abort@plt>
L11:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(0) != 0 || foo(1) != 1)
    abort();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xc3000(%rsp),%r11
L57:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L57
  sub    $0x530,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xc3520(%rbp)
  movq   $0x1,-0xc3518(%rbp)
  lea    -0xc352c(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L0
L97:
  lea    -0xc3528(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   $0x0,-0xc3520(%rbp)
  movq   $0x1,-0xc3518(%rbp)
  movl   $0x0,-0xc3524(%rbp)
  jmp    L96
L62:
  lea    -0xc3510(%rbp),%rdx
  mov    -0xc3524(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0xc3524(%rbp)
L96:
  mov    -0xc3528(%rbp),%eax
  cmp    %eax,-0xc3524(%rbp)
  jl     L62
  movl   $0x0,-0xc3524(%rbp)
  jmp    L23
L81:
  mov    -0xc3524(%rbp),%eax
  cltq
  mov    -0xc3510(%rbp,%rax,8),%rdx
  mov    -0xc3524(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xc3510(%rbp,%rax,8),%rax
  cmp    %rax,%rdx
  jg     L78
  addq   $0x1,-0xc3518(%rbp)
  jmp    L70
L78:
  mov    -0xc3518(%rbp),%rax
  add    $0x1,%rax
  imul   -0xc3518(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  add    %rax,-0xc3520(%rbp)
  movq   $0x1,-0xc3518(%rbp)
L70:
  addl   $0x1,-0xc3524(%rbp)
L23:
  mov    -0xc3528(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc3524(%rbp)
  jl     L81
  mov    -0xc3518(%rbp),%rax
  add    $0x1,%rax
  imul   -0xc3518(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  add    %rax,-0xc3520(%rbp)
  mov    -0xc3520(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    -0xc352c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc352c(%rbp)
  test   %eax,%eax
  jne    L97
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string
name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D3
type_infered: string

tool: D9: %d

tool: D21: %lld

tool: D3: %lld


assistant: ```c
int main(void) {
  int t, i, n;
  long long c = 0, a = 1;
  long long int ar[100001];
  scanf("%d", &t);
  while (t-- != 0) {
    scanf("%d", &n);
    c = 0;
    a = 1;
    for (i = 0; i < n; i++) {
      scanf("%lld", &ar[i]);
    }
    for (i = 0; i < n - 1; i++) {
      if (ar[i] <= ar[i + 1])
        a++;
      else {
        c += (a * (a + 1)) / 2;
        a = 1;
      }
    }
    c += (a * (a + 1)) / 2;
    printf("%lld\n", c);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L75:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L75
  sub    $0x528,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc3518(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L107
  lea    0xc(%rsp),%r14
  lea    D20(%rip),%r13
  lea    D3(%rip),%rbp
  lea    D31(%rip),%r12
  jmp    L57
L77:
  lea    0x1(%rdx),%rcx
  imul   %rdx,%rcx
  mov    %rcx,%rdx
  shr    $0x3f,%rdx
  add    %rcx,%rdx
  sar    %rdx
  add    %rdx,%rdi
  mov    $0x1,%edx
L3:
  add    $0x8,%rax
  cmp    %rsi,%rax
  je     L34
L95:
  mov    0x8(%rax),%rbx
  cmp    %rbx,(%rax)
  jg     L77
  add    $0x1,%rdx
  jmp    L3
L10:
  mov    $0x1,%edx
  mov    $0x0,%edi
L34:
  lea    0x1(%rdx),%rax
  imul   %rdx,%rax
  mov    %rax,%rsi
  shr    $0x3f,%rsi
  add    %rax,%rsi
  sar    %rsi
  add    %rdi,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L107
L57:
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L15
  lea    0x10(%rsp),%r15
  mov    $0x0,%ebx
L99:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%edx
  add    $0x8,%r15
  cmp    %ebx,%edx
  jg     L99
L15:
  cmp    $0x1,%edx
  jle    L10
  lea    0x10(%rsp),%rax
  lea    -0x2(%rdx),%edx
  lea    0x18(%rsp,%rdx,8),%rsi
  mov    $0x1,%edx
  mov    $0x0,%edi
  jmp    L95
L107:
  mov    0xc3518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0xc3528,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D31
datatype: string

tool: D20: %d

tool: D3: %lld

tool: D31: %lld


assistant: ```c
int main(void) {
  int t, i, n;
  long long c = 0, a = 1;
  long long int ar[100001];
  scanf("%d", &t);
  while (t-- != 0) {
    scanf("%d", &n);
    c = 0;
    a = 1;
    for (i = 0; i < n; i++) {
      scanf("%lld", &ar[i]);
    }
    for (i = 0; i < n - 1; i++) {
      if (ar[i] <= ar[i + 1])
        a++;
      else {
        c += (a * (a + 1)) / 2;
        a = 1;
      }
    }
    c += (a * (a + 1)) / 2;
    printf("%lld\n", c);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L72:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L72
  sub    $0x528,%rsp
  lea    D11(%rip),%rbp
  lea    D21(%rip),%r12
  mov    %rbp,%rdi
  lea    D14(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0xc3518(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r13
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L60
  nopl   0x0(%rax,%rax,1)
L114:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L44
  lea    0x10(%rsp),%r15
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L19:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  add    $0x8,%r15
  cmp    %r14d,%ecx
  jg     L19
  cmp    $0x1,%ecx
  jle    L44
  sub    $0x2,%ecx
  mov    0x10(%rsp),%rdx
  lea    0x18(%rsp),%rax
  xor    %r8d,%r8d
  lea    0x20(%rsp,%rcx,8),%r9
  mov    $0x1,%esi
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L67:
  add    $0x8,%rax
  lea    0x2(%rsi),%rdi
  mov    %rcx,%rsi
  cmp    %r9,%rax
  je     L109
L30:
  mov    %rdx,%rdi
  mov    (%rax),%rdx
  lea    0x1(%rsi),%rcx
  cmp    %rdi,%rdx
  jge    L67
  imul   %rcx,%rsi
  add    $0x8,%rax
  mov    $0x2,%edi
  sar    %rsi
  add    %rsi,%r8
  mov    $0x1,%esi
  cmp    %r9,%rax
  jne    L30
L109:
  imul   %rdi,%rsi
  sar    %rsi
  add    %r8,%rsi
L116:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L114
L60:
  mov    0xc3518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0xc3528,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  mov    $0x1,%esi
  jmp    L116
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D21
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string

tool: D11: %d

tool: D21: %lld


tool: D14: %lld

assistant: ```c
int main(void) {
  int t, i, n;
  long long c = 0, a = 1;
  long long int ar[100001];
  scanf("%d", &t);
  while (t-- != 0) {
    scanf("%d", &n);
    c = 0;
    a = 1;
    for (i = 0; i < n; i++) {
      scanf("%lld", &ar[i]);
    }
    for (i = 0; i < n - 1; i++) {
      if (ar[i] <= ar[i + 1])
        a++;
      else {
        c += (a * (a + 1)) / 2;
        a = 1;
      }
    }
    c += (a * (a + 1)) / 2;
    printf("%lld\n", c);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L56:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L56
  sub    $0x528,%rsp
  lea    D15(%rip),%rbp
  lea    D16(%rip),%r12
  mov    %rbp,%rdi
  lea    D28(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0xc3518(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r13
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L43
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L35
  lea    0x10(%rsp),%r15
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L83:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  add    $0x8,%r15
  cmp    %r14d,%edx
  jg     L83
  cmp    $0x1,%edx
  jle    L35
  sub    $0x2,%edx
  mov    0x10(%rsp),%rdi
  lea    0x18(%rsp),%rax
  xor    %r8d,%r8d
  lea    0x20(%rsp,%rdx,8),%r9
  mov    $0x1,%ecx
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rax
  lea    0x2(%rcx),%rsi
  mov    %rdx,%rcx
  cmp    %r9,%rax
  je     L51
L3:
  mov    %rdi,%rsi
  mov    (%rax),%rdi
  lea    0x1(%rcx),%rdx
  cmp    %rsi,%rdi
  jge    L14
  imul   %rcx,%rdx
  add    $0x8,%rax
  mov    $0x2,%esi
  mov    $0x1,%ecx
  sar    %rdx
  add    %rdx,%r8
  cmp    %r9,%rax
  jne    L3
L51:
  imul   %rcx,%rsi
  sar    %rsi
  add    %r8,%rsi
L97:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L28
L43:
  mov    0xc3518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0xc3528,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  mov    $0x1,%esi
  jmp    L97
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
data_type: string
name: extract_symbolic_data
arguments: data_label: D16
data_type: string
name: extract_symbolic_data
arguments: data_label: D28
data_type: string

tool: D15: %d

tool: D16: %lld


tool: D28: %lld

assistant: ```c
int main(void) {
  int t, i, n;
  long long c = 0, a = 1;
  long long int ar[100001];
  scanf("%d", &t);
  while (t-- != 0) {
    scanf("%d", &n);
    c = 0;
    a = 1;
    for (i = 0; i < n; i++) {
      scanf("%lld", &ar[i]);
    }
    for (i = 0; i < n - 1; i++) {
      if (ar[i] <= ar[i + 1])
        a++;
      else {
        c += (a * (a + 1)) / 2;
        a = 1;
      }
    }
    c += (a * (a + 1)) / 2;
    printf("%lld\n", c);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matrix_print_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L18:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L18
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type_infered: string
name: retrieve_data
arguments: data_tag: D3
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string

tool: D16: %s=[


tool: D3: %ld 

tool: D11: ]

assistant: ```c
void matrix_print_long(const char *name, const long *a, const unsigned int dimX, const unsigned int dimY) {
  printf("%s=[\n", name);
  for (unsigned int i = 0; i < dimX * dimY; i++) {
    printf("%ld ", a[i]);
  }
  printf("]\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_print_long>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %rdi,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  imul   %r12d,%edx
  test   %edx,%edx
  je     L14
  mov    %rbp,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rbp,%rax,8),%r12
  lea    D25(%rip),%rbp
L8:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L8
L14:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D21: %s=[


tool: D25: %ld 

tool: D15: ]

assistant: ```c
void matrix_print_long(const char *name, const long *a, const unsigned int dimX, const unsigned int dimY) {
  printf("%s=[\n", name);
  for (unsigned int i = 0; i < dimX * dimY; i++) {
    printf("%ld ", a[i]);
  }
  printf("]\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix_print_long>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edx
  imul   %r12d,%edx
  test   %edx,%edx
  je     L5
  lea    -0x1(%rdx),%eax
  lea    D23(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
L5:
  pop    %rbx
  lea    D28(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D23
type: string
name: disassemble_data
arguments: data_tag: D28
type: string

tool: D13: %s=[


tool: D23: %ld 

tool: D28: ]

assistant: ```c
void matrix_print_long(const char *name, const long *a, const unsigned int dimX, const unsigned int dimY) {
  printf("%s=[\n", name);
  for (unsigned int i = 0; i < dimX * dimY; i++) {
    printf("%ld ", a[i]);
  }
  printf("]\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrix_print_long>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edx
  imul   %r12d,%edx
  test   %edx,%edx
  je     L1
  lea    -0x1(%rdx),%eax
  lea    D9(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
L1:
  pop    %rbx
  lea    D25(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D25
type_guessed: string

tool: D19: %s=[


tool: D9: %ld 

tool: D25: ]

assistant: ```c
void matrix_print_long(const char *name, const long *a, const unsigned int dimX, const unsigned int dimY) {
  printf("%s=[\n", name);
  for (unsigned int i = 0; i < dimX * dimY; i++) {
    printf("%ld ", a[i]);
  }
  printf("]\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_trimat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  mov    -0x1c(%rbp),%ebx
  jmp    L13
L17:
  mov    -0x24(%rbp),%r12d
  jmp    L37
L33:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movslq %r12d,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  add    $0x1,%r12d
L37:
  cmp    -0x28(%rbp),%r12d
  jle    L33
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  add    $0x1,%ebx
L13:
  cmp    -0x20(%rbp),%ebx
  jle    L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void free_trimat(m, nrl, nrh, ncl, nch, nzl, nzh) char ***m;
int nrl, nrh, ncl, nch, nzl, nzh;
{
  register int i, j;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      free((char *)m[i][j]);
    }
    free((char *)m[i]);
  }
  free((char *)m);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<free_trimat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  cmp    %edx,%esi
  jg     L54
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%rbp
  sub    %esi,%edx
  add    %rdx,%rax
  lea    0x8(%rdi,%rax,8),%r15
  movslq %ecx,%rax
  lea    0x0(,%rax,8),%rcx
  mov    %rcx,(%rsp)
  mov    %r8d,%edx
  sub    %r13d,%edx
  lea    0x1(%rax,%rdx,1),%r12
  shl    $0x3,%r12
  jmp    L57
L52:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L52
L51:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L54
L57:
  mov    (%rsp),%rbx
  cmp    %r14d,%r13d
  jle    L52
  jmp    L51
L54:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void free_trimat(m, nrl, nrh, ncl, nch, nzl, nzh) char ***m;
int nrl, nrh, ncl, nch, nzl, nzh;
{
  register int i, j;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      free((char *)m[i][j]);
    }
    free((char *)m[i]);
  }
  free((char *)m);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_trimat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  cmp    %edx,%esi
  jg     L28
  movslq %esi,%rax
  sub    %esi,%edx
  mov    %ecx,%ebp
  mov    %r8d,%r12d
  lea    (%rdi,%rax,8),%r15
  add    %rdx,%rax
  mov    %r8d,%edx
  lea    0x8(%rdi,%rax,8),%r14
  movslq %ecx,%rax
  sub    %ebp,%edx
  lea    0x0(,%rax,8),%rcx
  lea    0x1(%rax,%rdx,1),%rbx
  mov    %rcx,(%rsp)
  shl    $0x3,%rbx
  xchg   %ax,%ax
L27:
  mov    (%rsp),%r13
  cmp    %r12d,%ebp
  jg     L6
  nopl   0x0(%rax)
L17:
  mov    (%r15),%rdx
  mov    (%rdx,%r13,1),%rdi
  add    $0x8,%r13
  call   <free@plt>
  cmp    %r13,%rbx
  jne    L17
L6:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <free@plt>
  cmp    %r14,%r15
  jne    L27
L28:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <free@plt>
```

assistant: ```c
void free_trimat(m, nrl, nrh, ncl, nch, nzl, nzh) char ***m;
int nrl, nrh, ncl, nch, nzl, nzh;
{
  register int i, j;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      free((char *)m[i][j]);
    }
    free((char *)m[i]);
  }
  free((char *)m);
}
```