user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x8(%rsi),%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %eax,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <d3arr@plt>
  mov    %eax,0x1c(%rsp)
  movslq %eax,%rsi
  mov    %rsi,0x10(%rsp)
  test   %ebx,%ebx
  jle    L41
  mov    %rsi,%rbp
  lea    -0x1(%rbx),%eax
  lea    0x8(%rsi,%rax,8),%r14
  mov    %ebx,%r11d
  shl    $0x3,%r11
  mov    %ebx,%r13d
  imul   %ebx,%r13d
  mov    $0x0,%r10d
L102:
  mov    %rbp,%r9
  mov    %r10d,%r12d
  lea    (%rbx,%r10,1),%r8d
  mov    $0x0,%edi
L54:
  mov    %r10d,%eax
  mov    $0x0,%edx
L139:
  mov    %eax,%esi
  add    $0x1,%eax
  mov    (%r9),%rcx
  mov    (%rcx,%rdi,1),%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,(%rcx,%rdx,1)
  add    $0x8,%rdx
  cmp    %r8d,%eax
  jne    L139
  add    %ebx,%r10d
  add    %ebx,%r8d
  add    $0x8,%rdi
  cmp    %r11,%rdi
  jne    L54
  lea    (%r12,%r13,1),%r10d
  add    $0x8,%rbp
  cmp    %r14,%rbp
  jne    L102
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%r13d
  imul   %ebx,%r13d
  mov    %ebx,%r15d
  imul   %r13d,%r15d
  mov    $0x0,%r12d
  lea    D26(%rip),%r14
  mov    %ebx,0x8(%rsp)
  mov    0x10(%rsp),%rbp
  jmp    L121
L41:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L96
L67:
  add    $0x1,%r12
  cmp    %r12d,%r15d
  jle    L79
L121:
  mov    0x0(%rbp),%rax
  mov    (%rax),%rax
  movsd  (%rax,%r12,8),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%r12),%ebx
  mov    %ebx,%eax
  cltd
  idivl  0x8(%rsp)
  test   %edx,%edx
  je     L36
L96:
  mov    %ebx,%eax
  cltd
  idiv   %r13d
  test   %edx,%edx
  jne    L67
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L67
L79:
  mov    0x8(%rsp),%ebx
L7:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L133
  movslq 0x1c(%rsp),%r15
  lea    -0x1(%rbx),%eax
  lea    0x8(%r15,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  mov    %ebx,%ebx
  lea    0x0(,%rbx,8),%rbp
  lea    D26(%rip),%r14
L143:
  mov    %r15,%r13
  mov    $0x0,%r12d
L48:
  mov    $0x0,%ebx
L77:
  mov    0x0(%r13),%rax
  mov    (%rax,%r12,1),%rax
  movsd  (%rax,%rbx,1),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L77
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%r12
  cmp    %r12,%rbp
  jne    L48
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%r15
  cmp    0x8(%rsp),%r15
  jne    L143
L133:
  mov    0x10(%rsp),%rbx
  mov    (%rbx),%rax
  mov    (%rax),%rdi
  call   <free@plt>
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D26
type_infered: string
name: unpack_data
arguments: label: D27
type_infered: string

tool: D9: Matrix with 1D indexing:

tool: D26: %.1f 

tool: D27: Matrix with 3D indexing:

assistant: ```c
int main(int argc, char *argv[]) {
  int n = atoi(argv[1]);
  double ***mat3 = d3arr(n, n, n);
  int cnt = 0;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      for (int k = 0; k < n; k++) {
        mat3[i][j][k] = cnt++;
      }
    }
  }
  printf("Matrix with 1D indexing:\n");
  for (int i = 0; i < n * n * n; i++) {
    printf("%.1f ", mat3[0][0][i]);
    if ((i + 1) % n == 0) {
      printf("\n");
    }
    if ((i + 1) % (n * n) == 0) {
      printf("\n");
    }
  }
  printf("Matrix with 3D indexing:\n");
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      for (int k = 0; k < n; k++) {
        printf("%.1f ", mat3[i][j][k]);
      }
      printf("\n");
    }
    printf("\n");
  }
  free(mat3[0][0]);
  free(mat3[0]);
  free(mat3);
  return 0;
}
```