ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  ret
```

assistant: ```c
void test(int x) {
  int r = x < 0 ? -x : x;
  if (r == 0)
    (void)0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  ret
```

assistant: ```c
void test(int x) {
  int r = x < 0 ? -x : x;
  if (r == 0)
    (void)0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x80000000,%edi
  call   <foo@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    $0x0,%eax
  call   <abort@plt>
L9:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (foo(-0x7fffffff - 1) != -1)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000000,%edi
  call   <foo@plt>
  cmp    $0xffffffff,%eax
  jne    L8
L18:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L18
```

assistant: ```c
int main() {
  if (foo(-0x7fffffff - 1) != -1)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000000,%edi
  call   <foo@plt>
  cmp    $0xffffffff,%eax
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(-0x7fffffff - 1) != -1)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000000,%edi
  call   <foo@plt>
  cmp    $0xffffffff,%eax
  je     L4
  xor    %eax,%eax
  call   <abort@plt>
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(-0x7fffffff - 1) != -1)
    abort();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mygetline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L26
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L26
  cmpl   $0xa,-0x8(%rbp)
  jne    L35
L26:
  cmpl   $0xa,-0x8(%rbp)
  jne    L39
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L53
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L53:
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim && (c = getchar()) != EOF && c != '\n'; ++i) {
    s[i] = c;
  }
  if (c == '\n') {
    if (i < lim - 1) {
      s[lim - 1] = c;
    }
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mygetline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L32:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L75
  cmp    $0xa,%eax
  je     L75
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %ebx,%r12d
  jne    L32
  mov    %r12d,%ebx
  jmp    L4
L16:
  mov    $0x0,%ebx
L75:
  cmp    $0xa,%eax
  je     L3
L4:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  lea    -0x1(%r12),%eax
  cmp    %ebx,%eax
  jle    L22
  movslq %r12d,%r12
  movb   $0xa,-0x1(%r13,%r12,1)
L22:
  add    $0x1,%ebx
  jmp    L4
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim && (c = getchar()) != EOF && c != '\n'; ++i) {
    s[i] = c;
  }
  if (c == '\n') {
    if (i < lim - 1) {
      s[lim - 1] = c;
    }
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<mygetline>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L64
  mov    D6(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L0:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L76
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %edx,%ebp
  je     L71
  mov    %edx,%r14d
L27:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%r12)
  jne    L0
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L76
  movslq %r14d,%rax
  add    %rax,%r13
L64:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  movb   $0x0,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  lea    -0x1(%rbp),%eax
  cmp    %r14d,%eax
  jle    L80
  movb   $0xa,-0x1(%r13,%rbp,1)
L80:
  movslq %edx,%rax
  mov    %rax,%r14
  add    %rax,%r13
  jmp    L64
  nopl   0x0(%rax)
L71:
  movslq %ebp,%rax
  mov    %ebp,%r14d
  add    %rax,%r13
  jmp    L64
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim && (c = getchar()) != EOF && c != '\n'; ++i) {
    s[i] = c;
  }
  if (c == '\n') {
    if (i < lim - 1) {
      s[lim - 1] = c;
    }
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<mygetline>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L18
  mov    D7(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L43:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L6
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %edx,%ebp
  je     L4
  mov    %edx,%r14d
L37:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%r12)
  jne    L43
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L6
  movslq %r14d,%rax
  add    %rax,%r13
L18:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  movb   $0x0,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x1(%rbp),%eax
  cmp    %r14d,%eax
  jle    L44
  movb   $0xa,-0x1(%r13,%rbp,1)
L44:
  movslq %edx,%rax
  mov    %rax,%r14
  add    %rax,%r13
  jmp    L18
  nopl   0x0(%rax)
L4:
  movslq %ebp,%rax
  mov    %ebp,%r14d
  add    %rax,%r13
  jmp    L18
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim && (c = getchar()) != EOF && c != '\n'; ++i) {
    s[i] = c;
  }
  if (c == '\n') {
    if (i < lim - 1) {
      s[lim - 1] = c;
    }
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L50
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L53
  mov    $0xffffffff,%eax
  jmp    L20
L53:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L57
  mov    $0x1,%eax
  jmp    L20
L57:
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L10
  mov    $0x0,%eax
L20:
  leave
  ret
```

assistant: ```c
int str_cmp(char *str1, char *str2) {
  for (int i = 0; i < strlen(str1); i++) {
    if (str1[i] < str2[i]) {
      return -1;
    } else if (str1[i] > str2[i]) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<str_cmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
L44:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L28
  movzbl 0x0(%rbp,%rbx,1),%edx
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,%dl
  jl     L17
  add    $0x1,%rbx
  cmp    %al,%dl
  jle    L44
  mov    $0x1,%eax
  jmp    L39
L28:
  mov    $0x0,%eax
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L39
```

assistant: ```c
int str_cmp(char *str1, char *str2) {
  for (int i = 0; i < strlen(str1); i++) {
    if (str1[i] < str2[i]) {
      return -1;
    } else if (str1[i] > str2[i]) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_cmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L1:
  movzbl 0x0(%rbp,%rbx,1),%edx
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,%dl
  jl     L20
  add    $0x1,%rbx
  cmp    %al,%dl
  jg     L23
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L20:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_cmp(char *str1, char *str2) {
  for (int i = 0; i < strlen(str1); i++) {
    if (str1[i] < str2[i]) {
      return -1;
    } else if (str1[i] > str2[i]) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<str_cmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl 0x0(%rbp,%rbx,1),%edx
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,%dl
  jl     L3
  add    $0x1,%rbx
  cmp    %al,%dl
  jg     L32
L27:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_cmp(char *str1, char *str2) {
  for (int i = 0; i < strlen(str1); i++) {
    if (str1[i] < str2[i]) {
      return -1;
    } else if (str1[i] > str2[i]) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fluff_random_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fluff_random_random@plt>
  mov    -0x8(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int fluff_random_range(struct FluffRandom *self, int min, int max) {
  int diff = max - min;
  int choice;
  choice = (int)(fluff_random_random(self) * diff);
  return choice + min;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fluff_random_range>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  sub    %esi,%edx
  mov    %edx,%ebp
  call   <fluff_random_random@plt>
  imul   %ebp,%eax
  add    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fluff_random_range(struct FluffRandom *self, int min, int max) {
  int diff = max - min;
  int choice;
  choice = (int)(fluff_random_random(self) * diff);
  return choice + min;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fluff_random_range>:
  endbr64
  push   %rbp
  sub    %esi,%edx
  push   %rbx
  mov    %edx,%ebp
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <fluff_random_random@plt>
  add    $0x8,%rsp
  imul   %ebp,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fluff_random_range(struct FluffRandom *self, int min, int max) {
  int diff = max - min;
  int choice;
  choice = (int)(fluff_random_random(self) * diff);
  return choice + min;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fluff_random_range>:
  endbr64
  push   %rbp
  sub    %esi,%edx
  push   %rbx
  mov    %edx,%ebp
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <fluff_random_random@plt>
  add    $0x8,%rsp
  imul   %ebp,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fluff_random_range(struct FluffRandom *self, int min, int max) {
  int diff = max - min;
  int choice;
  choice = (int)(fluff_random_random(self) * diff);
  return choice + min;
}
```
user: What is the c source code of the assembly code below?

```asm
<_CRI2IEG_64R64_ONCRI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L6
L19:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x1,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
L6:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _CRI2IEG_64R64_ONCRI(unsigned long *iptr, unsigned long *optr, int *numadd, int *strideadd) {
  long i;
  for (i = 0; i < *numadd; i++, optr += *strideadd) {
    *optr = iptr[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_CRI2IEG_64R64_ONCRI>:
  endbr64
  cmpl   $0x0,(%rdx)
  jle    L2
  mov    $0x0,%eax
L9:
  mov    (%rdi,%rax,8),%r8
  mov    %r8,(%rsi)
  add    $0x1,%rax
  movslq (%rcx),%r8
  lea    (%rsi,%r8,8),%rsi
  movslq (%rdx),%r8
  cmp    %rax,%r8
  jg     L9
L2:
  ret
```

assistant: ```c
void _CRI2IEG_64R64_ONCRI(unsigned long *iptr, unsigned long *optr, int *numadd, int *strideadd) {
  long i;
  for (i = 0; i < *numadd; i++, optr += *strideadd) {
    *optr = iptr[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_CRI2IEG_64R64_ONCRI>:
  endbr64
  movslq (%rdx),%rax
  test   %eax,%eax
  jle    L11
  movslq (%rcx),%rdx
  lea    (%rdi,%rax,8),%rcx
  shl    $0x3,%rdx
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    (%rdi),%rax
  add    $0x8,%rdi
  mov    %rax,(%rsi)
  add    %rdx,%rsi
  cmp    %rcx,%rdi
  jne    L16
L11:
  ret
```

assistant: ```c
void _CRI2IEG_64R64_ONCRI(unsigned long *iptr, unsigned long *optr, int *numadd, int *strideadd) {
  long i;
  for (i = 0; i < *numadd; i++, optr += *strideadd) {
    *optr = iptr[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_CRI2IEG_64R64_ONCRI>:
  endbr64
  movslq (%rdx),%rdx
  mov    %rsi,%rax
  test   %edx,%edx
  jle    L5
  movslq (%rcx),%rcx
  mov    %rcx,%rsi
  shl    $0x3,%rcx
  cmp    $0x1,%esi
  lea    (%rdi,%rdx,8),%rsi
  jne    L6
  nopl   0x0(%rax)
L14:
  mov    (%rdi),%rdx
  add    $0x8,%rdi
  mov    %rdx,(%rax)
  add    %rcx,%rax
  cmp    %rsi,%rdi
  jne    L14
L5:
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rdi),%rdx
  add    $0x8,%rdi
  mov    %rdx,(%rax)
  add    %rcx,%rax
  cmp    %rsi,%rdi
  jne    L6
  ret
```

assistant: ```c
void _CRI2IEG_64R64_ONCRI(unsigned long *iptr, unsigned long *optr, int *numadd, int *strideadd) {
  long i;
  for (i = 0; i < *numadd; i++, optr += *strideadd) {
    *optr = iptr[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strncasecmp_diff_length_6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D2(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  cmp    $0x1,%eax
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string
name: unpack_data
arguments: data_label: D15
datatype: string

tool: D2: aBDe

tool: D15: abc

assistant: ```c
void strncasecmp_diff_length_6() {
  char *x = "aBDe";
  char *y = "abc";
  if (strncasecmp(x, y, 3) != 1)
    (void)*(char *)0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strncasecmp_diff_length_6>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D4(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <strncasecmp@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D4: abc

tool: D9: aBDe

assistant: ```c
void strncasecmp_diff_length_6() {
  char *x = "aBDe";
  char *y = "abc";
  if (strncasecmp(x, y, 3) != 1)
    (void)*(char *)0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncasecmp_diff_length_6>:
  endbr64
  mov    $0x3,%edx
  lea    D0(%rip),%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <strncasecmp@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: string

tool: D0: abc

tool: D6: aBDe

assistant: ```c
void strncasecmp_diff_length_6() {
  char *x = "aBDe";
  char *y = "abc";
  if (strncasecmp(x, y, 3) != 1)
    (void)*(char *)0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncasecmp_diff_length_6>:
  endbr64
  mov    $0x3,%edx
  lea    D8(%rip),%rsi
  lea    D16(%rip),%rdi
  jmp    1050 <strncasecmp@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D8: abc

tool: D16: aBDe

assistant: ```c
void strncasecmp_diff_length_6() {
  char *x = "aBDe";
  char *y = "abc";
  if (strncasecmp(x, y, 3) != 1)
    (void)*(char *)0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<msync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    D5(%rip),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int msync(void *addr, size_t length, int flags) {
  errno = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<msync>:
  endbr64
  mov    D7(%rip),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int msync(void *addr, size_t length, int flags) {
  errno = 0;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msync>:
  endbr64
  mov    D7(%rip),%rax
  movq   $0x0,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int msync(void *addr, size_t length, int flags) {
  errno = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<msync>:
  endbr64
  mov    D9(%rip),%rax
  movq   $0x0,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int msync(void *addr, size_t length, int flags) {
  errno = 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<define_polynome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <_helper_get_first_param@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x25(%rbp)
  movsbl -0x25(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L26
  movl   $0x0,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L21
L32:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtod@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
L21:
  mov    $0x0,%eax
  call   <_helper_get_next_param@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L32
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  movsbl -0x25(%rbp),%eax
  mov    -0x18(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <_helper_insert_polynome_table_node@plt>
  jmp    L28
L26:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    $0x0,%eax
  call   <_helper_end_get_params@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: Syntax error!

assistant: ```c
void define_polynome(const char *params) {
  char *ptr, name;
  double *cparams;
  int pcount;
  ptr = _helper_get_first_param(params);
  if (isalpha((name = *ptr))) {
    pcount = 0;
    cparams = malloc(sizeof(*cparams) * (strlen(params)));
    while ((ptr = _helper_get_next_param())) {
      cparams[pcount++] = strtod(ptr, NULL);
    }
    _helper_insert_polynome_table_node(name, cparams, pcount - 1);
  } else
    printf("Syntax error!");
  _helper_end_get_params();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<define_polynome>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <_helper_get_first_param@plt>
  movsbl (%rax),%r12d
  mov    %r12d,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L32
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  jmp    L21
L38:
  mov    $0x0,%esi
  call   <strtod@plt>
  movsd  %xmm0,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
L21:
  mov    $0x0,%eax
  call   <_helper_get_next_param@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L38
  lea    -0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <_helper_insert_polynome_table_node@plt>
L16:
  mov    $0x0,%eax
  call   <_helper_end_get_params@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string

tool: D3: Syntax error!

assistant: ```c
void define_polynome(const char *params) {
  char *ptr, name;
  double *cparams;
  int pcount;
  ptr = _helper_get_first_param(params);
  if (isalpha((name = *ptr))) {
    pcount = 0;
    cparams = malloc(sizeof(*cparams) * (strlen(params)));
    while ((ptr = _helper_get_next_param())) {
      cparams[pcount++] = strtod(ptr, NULL);
    }
    _helper_insert_polynome_table_node(name, cparams, pcount - 1);
  } else
    printf("Syntax error!");
  _helper_end_get_params();
}
```