ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<get_ppm_drift>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <get_monotonic_and_raw@plt>
  mov    $0xf,%edi
  call   <sleep@plt>
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <get_monotonic_and_raw@plt>
  mov    0x10(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <diff_timespec@plt>
  mov    %rax,%rbx
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <diff_timespec@plt>
  mov    %rax,%rcx
  imul   $0xf4240,%rbx,%rax
  cqto
  idiv   %rcx
  sub    $0xf4240,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_ppm_drift(void) {
  struct timespec mon_start, raw_start, mon_end, raw_end;
  long long delta1, delta2, eppm;
  get_monotonic_and_raw(&mon_start, &raw_start);
  sleep(15);
  get_monotonic_and_raw(&mon_end, &raw_end);
  delta1 = diff_timespec(mon_start, mon_end);
  delta2 = diff_timespec(raw_start, raw_end);
  eppm = (delta1 * 1000000) / delta2 - 1000000;
  return eppm;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_ppm_drift>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <get_monotonic_and_raw@plt>
  mov    $0xf,%edi
  call   <sleep@plt>
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <get_monotonic_and_raw@plt>
  mov    0x10(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <diff_timespec@plt>
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %rax,%rbx
  call   <diff_timespec@plt>
  mov    %rax,%r8
  imul   $0xf4240,%rbx,%rax
  cqto
  idiv   %r8
  sub    $0xf4240,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_ppm_drift(void) {
  struct timespec mon_start, raw_start, mon_end, raw_end;
  long long delta1, delta2, eppm;
  get_monotonic_and_raw(&mon_start, &raw_start);
  sleep(15);
  get_monotonic_and_raw(&mon_end, &raw_end);
  delta1 = diff_timespec(mon_start, mon_end);
  delta2 = diff_timespec(raw_start, raw_end);
  eppm = (delta1 * 1000000) / delta2 - 1000000;
  return eppm;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_ppm_drift>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <get_monotonic_and_raw@plt>
  mov    $0xf,%edi
  call   <sleep@plt>
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <get_monotonic_and_raw@plt>
  mov    0x10(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <diff_timespec@plt>
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %rax,%rbx
  call   <diff_timespec@plt>
  mov    %rax,%r8
  imul   $0xf4240,%rbx,%rax
  cqto
  idiv   %r8
  sub    $0xf4240,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_ppm_drift(void) {
  struct timespec mon_start, raw_start, mon_end, raw_end;
  long long delta1, delta2, eppm;
  get_monotonic_and_raw(&mon_start, &raw_start);
  sleep(15);
  get_monotonic_and_raw(&mon_end, &raw_end);
  delta1 = diff_timespec(mon_start, mon_end);
  delta2 = diff_timespec(raw_start, raw_end);
  eppm = (delta1 * 1000000) / delta2 - 1000000;
  return eppm;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<round2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x3fffffff,%eax
  jle    L5
  mov    -0x4(%rbp),%eax
  lea    0x3f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x6,%eax
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%esi
  mov    -0x4(%rbp),%edx
  and    $0x3f,%edx
  mov    $0x1,%edi
  mov    %edx,%ecx
  shl    %cl,%edi
  mov    %edi,%edx
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  or     %esi,%edx
  mov    %edx,(%rax)
L5:
  addl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void round2(uint64_t *out, const uint32_t *in) {
  int i;
  memset(out, 0, 128);
  for (i = 0; i < 1024; i++) {
    if (in[i] >= 1073741824 && in[i] <= 3221225471) {
      ((out)[(i) / 64] |= (((uint64_t)1) << (uint64_t)((i) % 64)));
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<round2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x80,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x0,%ecx
  mov    $0x1,%esi
  jmp    L17
L8:
  add    $0x1,%rcx
  cmp    $0x400,%rcx
  je     L34
L17:
  cmpl   $0x3fffffff,0x0(%rbp,%rcx,4)
  jle    L8
  lea    0x3f(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x6,%eax
  cltq
  mov    %esi,%edx
  shl    %cl,%edx
  or     %edx,(%rbx,%rax,4)
  jmp    L8
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void round2(uint64_t *out, const uint32_t *in) {
  int i;
  memset(out, 0, 128);
  for (i = 0; i < 1024; i++) {
    if (in[i] >= 1073741824 && in[i] <= 3221225471) {
      ((out)[(i) / 64] |= (((uint64_t)1) << (uint64_t)((i) % 64)));
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<round2>:
  endbr64
  push   %rbp
  mov    $0x80,%edx
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  xor    %ecx,%ecx
  mov    $0x1,%esi
  nopl   0x0(%rax,%rax,1)
L16:
  cmpl   $0x3fffffff,0x0(%rbp,%rcx,4)
  jle    L11
  mov    %ecx,%eax
  mov    %esi,%edx
  sar    $0x6,%eax
  shl    %cl,%edx
  cltq
  or     %edx,(%rbx,%rax,4)
L11:
  add    $0x1,%rcx
  cmp    $0x400,%rcx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void round2(uint64_t *out, const uint32_t *in) {
  int i;
  memset(out, 0, 128);
  for (i = 0; i < 1024; i++) {
    if (in[i] >= 1073741824 && in[i] <= 3221225471) {
      ((out)[(i) / 64] |= (((uint64_t)1) << (uint64_t)((i) % 64)));
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<round2>:
  endbr64
  push   %rbp
  mov    $0x80,%edx
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  xor    %ecx,%ecx
  mov    $0x1,%esi
  nopl   0x0(%rax,%rax,1)
L1:
  cmpl   $0x3fffffff,0x0(%rbp,%rcx,4)
  jle    L7
  mov    %ecx,%eax
  mov    %esi,%edx
  sar    $0x6,%eax
  shl    %cl,%edx
  cltq
  or     %edx,(%rbx,%rax,4)
L7:
  add    $0x1,%rcx
  cmp    $0x400,%rcx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void round2(uint64_t *out, const uint32_t *in) {
  int i;
  memset(out, 0, 128);
  for (i = 0; i < 1024; i++) {
    if (in[i] >= 1073741824 && in[i] <= 3221225471) {
      ((out)[(i) / 64] |= (((uint64_t)1) << (uint64_t)((i) % 64)));
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x77,%eax
  je     L15
  cmp    $0x77,%eax
  jg     L17
  cmp    $0x74,%eax
  je     L43
  cmp    $0x74,%eax
  jg     L17
  cmp    $0x54,%eax
  je     L43
  cmp    $0x57,%eax
  jne    L17
L15:
  movl   $0x1,-0xc(%rbp)
L43:
  movl   $0x1,-0x8(%rbp)
  nop
L17:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main(int na, char *argv[]) {
  int wflg = 0, tflg = 0;
  int dflg = 0;
  switch (argv[1][0]) {
  case 'w':
  case 'W':
    wflg = 1;
  case 't':
  case 'T':
    tflg = 1;
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main(int na, char *argv[]) {
  int wflg = 0, tflg = 0;
  int dflg = 0;
  switch (argv[1][0]) {
  case 'w':
  case 'W':
    wflg = 1;
  case 't':
  case 'T':
    tflg = 1;
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main(int na, char *argv[]) {
  int wflg = 0, tflg = 0;
  int dflg = 0;
  switch (argv[1][0]) {
  case 'w':
  case 'W':
    wflg = 1;
  case 't':
  case 'T':
    tflg = 1;
    break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main(int na, char *argv[]) {
  int wflg = 0, tflg = 0;
  int dflg = 0;
  switch (argv[1][0]) {
  case 'w':
  case 'W':
    wflg = 1;
  case 't':
  case 'T':
    tflg = 1;
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getBCC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x9(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L14
L3:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  xor    %al,-0x9(%rbp)
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L3
  movzbl -0x9(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char getBCC(const char buf[], uint size) {
  char BCC = 0;
  uint i;
  for (i = 0; i < size; ++i) {
    BCC ^= buf[i];
  }
  return BCC;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getBCC>:
  endbr64
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%rax
  add    %rsi,%rdi
  mov    $0x0,%edx
L23:
  xor    (%rax),%dl
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L23
L2:
  mov    %edx,%eax
  ret
L4:
  mov    $0x0,%edx
  jmp    L2
```

assistant: ```c
char getBCC(const char buf[], uint size) {
  char BCC = 0;
  uint i;
  for (i = 0; i < size; ++i) {
    BCC ^= buf[i];
  }
  return BCC;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getBCC>:
  endbr64
  test   %rsi,%rsi
  je     L11
  add    %rdi,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L2:
  xor    (%rdi),%al
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L2
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
char getBCC(const char buf[], uint size) {
  char BCC = 0;
  uint i;
  for (i = 0; i < size; ++i) {
    BCC ^= buf[i];
  }
  return BCC;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getBCC>:
  endbr64
  test   %rsi,%rsi
  je     L153
  lea    -0x1(%rsi),%rax
  mov    %rsi,%rcx
  cmp    $0xe,%rax
  jbe    L114
  mov    %rsi,%rdx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  and    $0xfffffffffffffff0,%rdx
  add    %rdi,%rdx
  nop
L23:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  pxor   %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L23
  movdqa %xmm0,%xmm1
  mov    %rcx,%rsi
  psrldq $0x8,%xmm1
  and    $0xfffffffffffffff0,%rsi
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x2,%xmm1
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x1,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0xf,%cl
  je     L13
L50:
  mov    %rcx,%r8
  sub    %rsi,%r8
  lea    -0x1(%r8),%rdx
  cmp    $0x6,%rdx
  jbe    L161
  push   %rbp
  push   %rbx
  mov    (%rdi,%rsi,1),%rbx
  mov    %ebx,%edx
  movzbl %bh,%ebp
  xor    %ebp,%edx
  mov    %rbx,-0x10(%rsp)
  xor    %eax,%edx
  mov    %rbx,%rax
  mov    %rbx,-0x18(%rsp)
  shr    $0x10,%rax
  mov    %rbx,-0x20(%rsp)
  xor    %eax,%edx
  mov    %rbx,%rax
  mov    %rbx,-0x28(%rsp)
  shr    $0x18,%rax
  mov    %rbx,-0x30(%rsp)
  xor    %eax,%edx
  mov    %rbx,%rax
  mov    %rbx,-0x38(%rsp)
  shr    $0x20,%rax
  mov    %rbx,-0x40(%rsp)
  xor    %eax,%edx
  mov    %rbx,%rax
  mov    %rbx,-0x48(%rsp)
  shr    $0x28,%rax
  xor    %eax,%edx
  mov    %rbx,%rax
  shr    $0x30,%rax
  xor    %eax,%edx
  mov    %rbx,%rax
  shr    $0x38,%rax
  xor    %edx,%eax
  mov    %r8,%rdx
  and    $0xfffffffffffffff8,%rdx
  add    %rdx,%rsi
  cmp    %rdx,%r8
  je     L163
  lea    0x1(%rsi),%rdx
  xor    (%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L163
  lea    0x2(%rsi),%rdx
  xor    0x1(%rdi,%rsi,1),%al
  cmp    %rcx,%rdx
  jae    L163
  lea    0x3(%rsi),%rdx
  xor    0x2(%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L163
  lea    0x4(%rsi),%rdx
  xor    0x3(%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L163
  lea    0x5(%rsi),%rdx
  xor    0x4(%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L163
  lea    0x6(%rsi),%rdx
  xor    0x5(%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L163
  xor    0x6(%rdi,%rsi,1),%al
L163:
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L153:
  xor    %eax,%eax
  ret
L114:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L50
L161:
  lea    0x1(%rsi),%rdx
  xor    (%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L19
  lea    0x2(%rsi),%rdx
  xor    0x1(%rdi,%rsi,1),%al
  cmp    %rcx,%rdx
  jae    L19
  lea    0x3(%rsi),%rdx
  xor    0x2(%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L19
  lea    0x4(%rsi),%rdx
  xor    0x3(%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L19
  lea    0x5(%rsi),%rdx
  xor    0x4(%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L19
  lea    0x6(%rsi),%rdx
  xor    0x5(%rdi,%rsi,1),%al
  cmp    %rdx,%rcx
  jbe    L19
  xor    0x6(%rdi,%rsi,1),%al
L19:
  ret
L13:
  ret
```

assistant: ```c
char getBCC(const char buf[], uint size) {
  char BCC = 0;
  uint i;
  for (i = 0; i < size; ++i) {
    BCC ^= buf[i];
  }
  return BCC;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L29:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  jmp    L11
L32:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strcat(char *dst, const char *src) {
  unsigned int i = 0;
  while (dst[i]) {
    i++;
  }
  while (src[i]) {
    dst[i] = src[i];
    i++;
  }
  dst[i] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L48
  mov    $0x0,%eax
L19:
  add    $0x1,%eax
  mov    %eax,%edx
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L19
L25:
  mov    %eax,%edx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  je     L13
L8:
  mov    %cl,(%rdi,%rdx,1)
  add    $0x1,%eax
  mov    %eax,%edx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L8
L13:
  movb   $0x0,(%rdi,%rdx,1)
  ret
L48:
  mov    $0x0,%eax
  jmp    L25
```

assistant: ```c
void strcat(char *dst, const char *src) {
  unsigned int i = 0;
  while (dst[i]) {
    i++;
  }
  while (src[i]) {
    dst[i] = src[i];
    i++;
  }
  dst[i] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L17:
  lea    0x1(%rax),%edx
  lea    (%rdi,%rdx,1),%r8
  mov    %rdx,%rax
  cmpb   $0x0,(%r8)
  jne    L17
  lea    (%rsi,%rdx,1),%rcx
L40:
  movzbl (%rcx),%ecx
  test   %cl,%cl
  je     L13
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %cl,(%rdi,%rdx,1)
  lea    0x1(%rax),%edx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %rdx,%rax
  test   %cl,%cl
  jne    L38
  lea    (%rdi,%rdx,1),%r8
L13:
  movb   $0x0,(%r8)
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rdi,%r8
  mov    %rsi,%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L40
```

assistant: ```c
void strcat(char *dst, const char *src) {
  unsigned int i = 0;
  while (dst[i]) {
    i++;
  }
  while (src[i]) {
    dst[i] = src[i];
    i++;
  }
  dst[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  lea    0x1(%rax),%edx
  lea    (%rdi,%rdx,1),%r8
  mov    %rdx,%rax
  cmpb   $0x0,(%r8)
  jne    L5
  lea    (%rsi,%rdx,1),%rcx
L18:
  movzbl (%rcx),%ecx
  test   %cl,%cl
  je     L14
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %cl,(%rdi,%rdx,1)
  lea    0x1(%rax),%edx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %rdx,%rax
  test   %cl,%cl
  jne    L47
  lea    (%rdi,%rdx,1),%r8
L14:
  movb   $0x0,(%r8)
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rdi,%r8
  mov    %rsi,%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L18
```

assistant: ```c
void strcat(char *dst, const char *src) {
  unsigned int i = 0;
  while (dst[i]) {
    i++;
  }
  while (src[i]) {
    dst[i] = src[i];
    i++;
  }
  dst[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: Hello World!

assistant: ```c
main() {
  int i;
  printf("Hello World!");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Hello World!

assistant: ```c
main() {
  int i;
  printf("Hello World!");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: Hello World!

assistant: ```c
main() {
  int i;
  printf("Hello World!");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: Hello World!

assistant: ```c
main() {
  int i;
  printf("Hello World!");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bignum_base64_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <base64_decode@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L8
  mov    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BN_dec2bn@plt>
  mov    %eax,-0x1c(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
BIGNUM *bignum_base64_decode(const char *base64bignum) {
  BIGNUM *bn = NULL;
  int len;
  unsigned char *data = base64_decode(base64bignum, &len);
  if (len) {
    len = BN_dec2bn(&bn, data);
  }
  free(data);
  return bn;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bignum_base64_decode>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  lea    0xc(%rsp),%rsi
  call   <base64_decode@plt>
  mov    %rax,%rbx
  cmpl   $0x0,0xc(%rsp)
  jne    L6
L0:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  lea    0x10(%rsp),%rdi
  mov    %rax,%rsi
  call   <BN_dec2bn@plt>
  mov    %eax,0xc(%rsp)
  jmp    L0
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
BIGNUM *bignum_base64_decode(const char *base64bignum) {
  BIGNUM *bn = NULL;
  int len;
  unsigned char *data = base64_decode(base64bignum, &len);
  if (len) {
    len = BN_dec2bn(&bn, data);
  }
  free(data);
  return bn;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bignum_base64_decode>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  call   <base64_decode@plt>
  mov    %rax,%rbp
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L0
L12:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <BN_dec2bn@plt>
  mov    %eax,0xc(%rsp)
  jmp    L12
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
BIGNUM *bignum_base64_decode(const char *base64bignum) {
  BIGNUM *bn = NULL;
  int len;
  unsigned char *data = base64_decode(base64bignum, &len);
  if (len) {
    len = BN_dec2bn(&bn, data);
  }
  free(data);
  return bn;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bignum_base64_decode>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  call   <base64_decode@plt>
  mov    %rax,%rbp
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L19
L18:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <BN_dec2bn@plt>
  mov    %eax,0xc(%rsp)
  jmp    L18
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
BIGNUM *bignum_base64_decode(const char *base64bignum) {
  BIGNUM *bn = NULL;
  int len;
  unsigned char *data = base64_decode(base64bignum, &len);
  if (len) {
    len = BN_dec2bn(&bn, data);
  }
  free(data);
  return bn;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<greatest_among_three>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L8
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L35
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L35:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L8:
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L58
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L58:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int greatest_among_three(const int num1, const int num2, const int num3) {
  int result = 0;
  if (num1 > num2) {
    if (num1 > num3) {
      result = num1;
    } else {
      result = num3;
    }
  } else if (num2 > num3) {
    result = num2;
  } else {
    result = num3;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<greatest_among_three>:
  endbr64
  cmp    %edx,%edi
  mov    %edx,%eax
  cmovge %edi,%eax
  cmp    %edx,%esi
  cmovge %esi,%edx
  cmp    %esi,%edi
  cmovle %edx,%eax
  ret
```

assistant: ```c
int greatest_among_three(const int num1, const int num2, const int num3) {
  int result = 0;
  if (num1 > num2) {
    if (num1 > num3) {
      result = num1;
    } else {
      result = num3;
    }
  } else if (num2 > num3) {
    result = num2;
  } else {
    result = num3;
  }
  return result;
}
```