ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fd_block>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    D47(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  js     L5
  mov    D25(%rip),%rdx
  mov    (%rdx),%edx
  mov    $0x0,%ecx
  test   %eax,%edx
  jne    L43
L9:
  mov    %rcx,%rax
  pop    %rbx
  ret
L5:
  mov    D0(%rip),%rax
  mov    (%rax),%rcx
  neg    %rcx
  jmp    L9
L43:
  not    %edx
  and    %eax,%edx
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <fcntl@plt>
  mov    $0x0,%ecx
  test   %eax,%eax
  jns    L9
  mov    D0(%rip),%rax
  mov    (%rax),%rcx
  neg    %rcx
  jmp    L9
```

assistant: ```c
long fd_block(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFL, 0);
  if (flags < 0)
    return -errno;
  if ((flags & O_NONBLOCK) == 0)
    return 0;
  if (fcntl(fd, F_SETFL, flags & ~O_NONBLOCK) < 0)
    return -errno;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<fd_block>:
  endbr64
  mov    D11(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  js     L23
  mov    D6(%rip),%rdx
  mov    (%rdx),%edx
  test   %eax,%edx
  jne    L19
L7:
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L19:
  not    %edx
  mov    %ebp,%edi
  and    %eax,%edx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L7
L23:
  mov    D16(%rip),%rax
  pop    %rbp
  mov    (%rax),%rax
  neg    %rax
  ret
```

assistant: ```c
long fd_block(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFL, 0);
  if (flags < 0)
    return -errno;
  if ((flags & O_NONBLOCK) == 0)
    return 0;
  if (fcntl(fd, F_SETFL, flags & ~O_NONBLOCK) < 0)
    return -errno;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fd_block>:
  endbr64
  mov    D15(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  js     L1
  mov    D19(%rip),%rdx
  mov    (%rdx),%edx
  test   %eax,%edx
  jne    L22
L4:
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L22:
  not    %edx
  mov    %ebp,%edi
  and    %eax,%edx
  mov    D31(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L4
L1:
  mov    D25(%rip),%rax
  pop    %rbp
  mov    (%rax),%rax
  neg    %rax
  ret
```

assistant: ```c
long fd_block(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFL, 0);
  if (flags < 0)
    return -errno;
  if ((flags & O_NONBLOCK) == 0)
    return 0;
  if (fcntl(fd, F_SETFL, flags & ~O_NONBLOCK) < 0)
    return -errno;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<flag_ij>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L17
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x7,(%rax)
  jmp    L4
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
L4:
  pop    %rbp
  ret
```

assistant: ```c
void flag_ij(const int id, int *i, int *j) {
  if (id % 7 == 0) {
    *i = (id / 7) - 1;
    *j = 7;
  } else {
    *i = id / 7;
    *j = id % 7;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<flag_ij>:
  endbr64
  mov    %edi,%ecx
  mov    %rdx,%rdi
  movslq %ecx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x2,%eax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  jne    L17
  movslq %ecx,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x2,%edx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  sub    $0x1,%edx
  mov    $0x7,%eax
L14:
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  ret
L17:
  movslq %ecx,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ecx,%edx
  sar    $0x2,%edx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  jmp    L14
```

assistant: ```c
void flag_ij(const int id, int *i, int *j) {
  if (id % 7 == 0) {
    *i = (id / 7) - 1;
    *j = 7;
  } else {
    *i = id / 7;
    *j = id % 7;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flag_ij>:
  endbr64
  movslq %edi,%rax
  mov    %rax,%rcx
  imul   $0xffffffff92492493,%rax,%rax
  mov    %ecx,%r9d
  sar    $0x1f,%r9d
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x2,%eax
  mov    %eax,%edi
  sub    %r9d,%edi
  lea    0x0(,%rdi,8),%r8d
  mov    %edi,%eax
  sub    %edi,%r8d
  sub    %r8d,%ecx
  mov    %ecx,%edi
  jne    L5
  sub    $0x1,%eax
  mov    $0x7,%edi
L5:
  mov    %eax,(%rsi)
  mov    %edi,(%rdx)
  ret
```

assistant: ```c
void flag_ij(const int id, int *i, int *j) {
  if (id % 7 == 0) {
    *i = (id / 7) - 1;
    *j = 7;
  } else {
    *i = id / 7;
    *j = id % 7;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<flag_ij>:
  endbr64
  movslq %edi,%rax
  mov    %rax,%rcx
  imul   $0xffffffff92492493,%rax,%rax
  mov    %ecx,%r9d
  sar    $0x1f,%r9d
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x2,%eax
  mov    %eax,%edi
  sub    %r9d,%edi
  lea    0x0(,%rdi,8),%r8d
  mov    %edi,%eax
  sub    %edi,%r8d
  sub    %r8d,%ecx
  mov    %ecx,%edi
  jne    L8
  sub    $0x1,%eax
  mov    $0x7,%edi
L8:
  mov    %eax,(%rsi)
  mov    %edi,(%rdx)
  ret
```

assistant: ```c
void flag_ij(const int id, int *i, int *j) {
  if (id % 7 == 0) {
    *i = (id / 7) - 1;
    *j = 7;
  } else {
    *i = id / 7;
    *j = id % 7;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<save_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9d,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x14(%rax),%rdx
  mov    0x10(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void save_state(vec, a, b, c, d, e, f) int vec[6];
int a, b, c, d, e, f;
{
  vec[0] = a;
  vec[1] = b;
  vec[2] = c;
  vec[3] = d;
  vec[4] = e;
  vec[5] = f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<save_state>:
  endbr64
  mov    %esi,(%rdi)
  mov    %edx,0x4(%rdi)
  mov    %ecx,0x8(%rdi)
  mov    %r8d,0xc(%rdi)
  mov    %r9d,0x10(%rdi)
  mov    0x8(%rsp),%eax
  mov    %eax,0x14(%rdi)
  ret
```

assistant: ```c
void save_state(vec, a, b, c, d, e, f) int vec[6];
int a, b, c, d, e, f;
{
  vec[0] = a;
  vec[1] = b;
  vec[2] = c;
  vec[3] = d;
  vec[4] = e;
  vec[5] = f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<save_state>:
  endbr64
  mov    0x8(%rsp),%eax
  mov    %esi,(%rdi)
  mov    %edx,0x4(%rdi)
  mov    %ecx,0x8(%rdi)
  mov    %r8d,0xc(%rdi)
  mov    %r9d,0x10(%rdi)
  mov    %eax,0x14(%rdi)
  ret
```

assistant: ```c
void save_state(vec, a, b, c, d, e, f) int vec[6];
int a, b, c, d, e, f;
{
  vec[0] = a;
  vec[1] = b;
  vec[2] = c;
  vec[3] = d;
  vec[4] = e;
  vec[5] = f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<save_state>:
  endbr64
  movd   %ecx,%xmm1
  movd   %r8d,%xmm2
  movd   %esi,%xmm0
  movd   0x8(%rsp),%xmm4
  movd   %edx,%xmm3
  punpckldq %xmm2,%xmm1
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  movd   %r9d,%xmm0
  punpckldq %xmm4,%xmm0
  movq   %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void save_state(vec, a, b, c, d, e, f) int vec[6];
int a, b, c, d, e, f;
{
  vec[0] = a;
  vec[1] = b;
  vec[2] = c;
  vec[3] = d;
  vec[4] = e;
  vec[5] = f;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inc_dec_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  inc    %eax
  inc    %ecx
  inc    %edx
  inc    %ebx
  inc    %esp
  inc    %ebp
  inc    %esi
  inc    %edi
  dec    %eax
  dec    %ecx
  dec    %edx
  dec    %ebx
  dec    %esp
  dec    %ebp
  dec    %esi
  dec    %edi
  nop
  pop    %rbp
  ret
```

assistant: ```c
void inc_dec_tests(void) {
  asm("inc %eax");
  asm("inc %ecx");
  asm("inc %edx");
  asm("inc %ebx");
  asm("inc %esp");
  asm("inc %ebp");
  asm("inc %esi");
  asm("inc %edi");
  asm("dec %eax");
  asm("dec %ecx");
  asm("dec %edx");
  asm("dec %ebx");
  asm("dec %esp");
  asm("dec %ebp");
  asm("dec %esi");
  asm("dec %edi");
}
```
user: What is the c source code of the assembly code below?

```asm
<inc_dec_tests>:
  endbr64
  inc    %eax
  inc    %ecx
  inc    %edx
  inc    %ebx
  inc    %esp
  inc    %ebp
  inc    %esi
  inc    %edi
  dec    %eax
  dec    %ecx
  dec    %edx
  dec    %ebx
  dec    %esp
  dec    %ebp
  dec    %esi
  dec    %edi
  ret
```

assistant: ```c
void inc_dec_tests(void) {
  asm("inc %eax");
  asm("inc %ecx");
  asm("inc %edx");
  asm("inc %ebx");
  asm("inc %esp");
  asm("inc %ebp");
  asm("inc %esi");
  asm("inc %edi");
  asm("dec %eax");
  asm("dec %ecx");
  asm("dec %edx");
  asm("dec %ebx");
  asm("dec %esp");
  asm("dec %ebp");
  asm("dec %esi");
  asm("dec %edi");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<inc_dec_tests>:
  endbr64
  inc    %eax
  inc    %ecx
  inc    %edx
  inc    %ebx
  inc    %esp
  inc    %ebp
  inc    %esi
  inc    %edi
  dec    %eax
  dec    %ecx
  dec    %edx
  dec    %ebx
  dec    %esp
  dec    %ebp
  dec    %esi
  dec    %edi
  ret
```

assistant: ```c
void inc_dec_tests(void) {
  asm("inc %eax");
  asm("inc %ecx");
  asm("inc %edx");
  asm("inc %ebx");
  asm("inc %esp");
  asm("inc %ebp");
  asm("inc %esi");
  asm("inc %edi");
  asm("dec %eax");
  asm("dec %ecx");
  asm("dec %edx");
  asm("dec %ebx");
  asm("dec %esp");
  asm("dec %ebp");
  asm("dec %esi");
  asm("dec %edi");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inc_dec_tests>:
  endbr64
  inc    %eax
  inc    %ecx
  inc    %edx
  inc    %ebx
  inc    %esp
  inc    %ebp
  inc    %esi
  inc    %edi
  dec    %eax
  dec    %ecx
  dec    %edx
  dec    %ebx
  dec    %esp
  dec    %ebp
  dec    %esi
  dec    %edi
  ret
```

assistant: ```c
void inc_dec_tests(void) {
  asm("inc %eax");
  asm("inc %ecx");
  asm("inc %edx");
  asm("inc %ebx");
  asm("inc %esp");
  asm("inc %ebp");
  asm("inc %esi");
  asm("inc %edi");
  asm("dec %eax");
  asm("dec %ecx");
  asm("dec %edx");
  asm("dec %ebx");
  asm("dec %esp");
  asm("dec %ebp");
  asm("dec %esi");
  asm("dec %edi");
}
```
user: What is the c source code of the assembly code below?

```asm
<crn_err_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <crn_err_internal@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void crn_err_exit(int error, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  crn_err_internal(1, error, fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<crn_err_exit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    $0x1,%edi
  call   <crn_err_internal@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void crn_err_exit(int error, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  crn_err_internal(1, error, fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<crn_err_exit>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    $0x1,%edi
  call   <crn_err_internal@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void crn_err_exit(int error, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  crn_err_internal(1, error, fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crn_err_exit>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    $0x1,%edi
  call   <crn_err_internal@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void crn_err_exit(int error, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  crn_err_internal(1, error, fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<irecv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdi
  lea    -0x10(%rbp),%rcx
  lea    -0x19(%rbp),%rdx
  lea    -0x17(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <alpar_recv@plt>
  mov    %ax,-0x16(%rbp)
  cmpw   $0xffff,-0x16(%rbp)
  jne    L39
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L54
L39:
  movswl -0x16(%rbp),%edx
  movzbl -0x19(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpw   $0x0,-0x16(%rbp)
  je     L52
  movl   $0x0,-0x14(%rbp)
  jmp    L46
L50:
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L46:
  movswl -0x16(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L50
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L52:
  movzbl -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L54:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string
name: read_data
arguments: data_label: D23
data_type: string
name: read_data
arguments: data_label: D31
data_type: string
name: read_data
arguments: data_label: D12
data_type: string

tool: D7: receieve failure

tool: D23: command=%x,length=%hx


tool: D31: data[%d]=%u(0x%x)('%c')


tool: D12: lrc=%u


assistant: ```c
void irecv(int fd) {
  unsigned char command;
  unsigned char *data;
  short int length;
  unsigned char lrc;
  unsigned char ack;
  length = alpar_recv(fd, &ack, &command, &data, &lrc);
  if (length == -1) {
    perror("receieve failure");
    return;
  }
  printf("command=%x,length=%hx\n", command, length);
  if (length) {
    int i;
    for (i = 0; i < length; i++)
      printf("data[%d]=%u(0x%x)(\'%c\')\n", i, (unsigned char)data[i], (unsigned char)data[i], (unsigned char)data[i]);
    free(data);
  }
  printf("lrc=%u\n", lrc);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<irecv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xd(%rsp),%rdx
  lea    0xf(%rsp),%rsi
  lea    0xe(%rsp),%r8
  call   <alpar_recv@plt>
  cmp    $0xffff,%ax
  je     L35
  mov    %eax,%ebx
  movswl %ax,%ebp
  movzbl 0xd(%rsp),%esi
  mov    %ebp,%edx
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %bx,%bx
  je     L50
  test   %ebp,%ebp
  jle    L29
  mov    $0x0,%ebx
  lea    D1(%rip),%r12
L21:
  mov    0x10(%rsp),%rax
  movzbl (%rax,%rbx,1),%edx
  movzbl %bl,%esi
  mov    %edx,%r8d
  mov    %edx,%ecx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L21
L29:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
L50:
  movzbl 0xe(%rsp),%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  lea    D32(%rip),%rdi
  call   <perror@plt>
  jmp    L32
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type_guessed: string
name: extract_symbolic_data
arguments: label: D1
type_guessed: string
name: extract_symbolic_data
arguments: label: D6
type_guessed: string
name: extract_symbolic_data
arguments: label: D32
type_guessed: string

tool: D27: command=%x,length=%hx


tool: D1: data[%d]=%u(0x%x)('%c')


tool: D6: lrc=%u


tool: D32: receieve failure

assistant: ```c
void irecv(int fd) {
  unsigned char command;
  unsigned char *data;
  short int length;
  unsigned char lrc;
  unsigned char ack;
  length = alpar_recv(fd, &ack, &command, &data, &lrc);
  if (length == -1) {
    perror("receieve failure");
    return;
  }
  printf("command=%x,length=%hx\n", command, length);
  if (length) {
    int i;
    for (i = 0; i < length; i++)
      printf("data[%d]=%u(0x%x)(\'%c\')\n", i, (unsigned char)data[i], (unsigned char)data[i], (unsigned char)data[i]);
    free(data);
  }
  printf("lrc=%u\n", lrc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<irecv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  lea    0x10(%rsp),%rcx
  lea    0xd(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rsi
  lea    0xe(%rsp),%r8
  call   <alpar_recv@plt>
  cmp    $0xffff,%ax
  je     L37
  movswl %ax,%ebp
  movzbl 0xd(%rsp),%esi
  mov    %eax,%ebx
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%edx
  call   <printf@plt>
  test   %bx,%bx
  je     L31
  test   %ebp,%ebp
  jle    L52
  xor    %ebx,%ebx
  lea    D15(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x10(%rsp),%rax
  movzbl %bl,%esi
  mov    %r12,%rdi
  movzbl (%rax,%rbx,1),%edx
  xor    %eax,%eax
  add    $0x1,%rbx
  mov    %edx,%r8d
  mov    %edx,%ecx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jg     L0
L52:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
L31:
  movzbl 0xe(%rsp),%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L37:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  jmp    L17
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D15
type: string
name: extract_symbolic_data
arguments: data_label: D32
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D5: command=%x,length=%hx


tool: D15: data[%d]=%u(0x%x)('%c')


tool: D32: lrc=%u


tool: D9: receieve failure

assistant: ```c
void irecv(int fd) {
  unsigned char command;
  unsigned char *data;
  short int length;
  unsigned char lrc;
  unsigned char ack;
  length = alpar_recv(fd, &ack, &command, &data, &lrc);
  if (length == -1) {
    perror("receieve failure");
    return;
  }
  printf("command=%x,length=%hx\n", command, length);
  if (length) {
    int i;
    for (i = 0; i < length; i++)
      printf("data[%d]=%u(0x%x)(\'%c\')\n", i, (unsigned char)data[i], (unsigned char)data[i], (unsigned char)data[i]);
    free(data);
  }
  printf("lrc=%u\n", lrc);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<irecv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  lea    0x10(%rsp),%rcx
  lea    0xd(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rsi
  lea    0xe(%rsp),%r8
  call   <alpar_recv@plt>
  cmp    $0xffff,%ax
  je     L22
  movswl %ax,%ebp
  movzbl 0xd(%rsp),%esi
  mov    %eax,%ebx
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%edx
  call   <printf@plt>
  test   %bx,%bx
  je     L49
  test   %ebp,%ebp
  jle    L41
  xor    %ebx,%ebx
  lea    D38(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L59:
  mov    0x10(%rsp),%rax
  movzbl %bl,%esi
  mov    %r12,%rdi
  movzbl (%rax,%rbx,1),%edx
  xor    %eax,%eax
  add    $0x1,%rbx
  mov    %edx,%r8d
  mov    %edx,%ecx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jg     L59
L41:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
L49:
  movzbl 0xe(%rsp),%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L37:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L22:
  lea    D31(%rip),%rdi
  call   <perror@plt>
  jmp    L37
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
type_infered: string
name: unpack_data
arguments: tag: D38
type_infered: string
name: unpack_data
arguments: tag: D28
type_infered: string
name: unpack_data
arguments: tag: D31
type_infered: string

tool: D29: command=%x,length=%hx


tool: D38: data[%d]=%u(0x%x)('%c')


tool: D28: lrc=%u


tool: D31: receieve failure

assistant: ```c
void irecv(int fd) {
  unsigned char command;
  unsigned char *data;
  short int length;
  unsigned char lrc;
  unsigned char ack;
  length = alpar_recv(fd, &ack, &command, &data, &lrc);
  if (length == -1) {
    perror("receieve failure");
    return;
  }
  printf("command=%x,length=%hx\n", command, length);
  if (length) {
    int i;
    for (i = 0; i < length; i++)
      printf("data[%d]=%u(0x%x)(\'%c\')\n", i, (unsigned char)data[i], (unsigned char)data[i], (unsigned char)data[i]);
    free(data);
  }
  printf("lrc=%u\n", lrc);
}
```