ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<I2CMasterDataGet>:
  endbr64
  mov    0x9c(%edi),%eax
  ret
```

assistant: ```c
unsigned char I2CMasterDataGet(unsigned int baseAdd) {
  unsigned char rData;
  rData = (unsigned char)(*((volatile unsigned int *)(baseAdd + (0x9C))));
  return rData;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<I2CMasterDataGet>:
  endbr64
  mov    0x9c(%edi),%eax
  ret
```

assistant: ```c
unsigned char I2CMasterDataGet(unsigned int baseAdd) {
  unsigned char rData;
  rData = (unsigned char)(*((volatile unsigned int *)(baseAdd + (0x9C))));
  return rData;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getXY>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%ecx
  sbb    %esi,%esi
  and    $0xe,%esi
  add    $0x1,%esi
  cmp    $0x8,%edx
  mov    $0x50,%r10d
  mov    $0x1e,%eax
  cmovne %eax,%r10d
  mov    %r10d,%r13d
  sub    %ecx,%r13d
  imul   %edx,%r13d
  movswl 0x0(%rbp),%r8d
  mov    %r8d,%eax
  cltd
  idiv   %ebx
  add    %ecx,%eax
  test   %edx,%edx
  lea    D31(%rip),%rdx
  lea    D6(%rip),%rcx
  cmove  %rcx,%rdx
  push   %r8
  push   %rdx
  push   %rax
  mov    %r13d,%r9d
  mov    %esi,%r8d
  imul   %ebx,%r8d
  mov    %r10d,%ecx
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x0,%eax
  call   <getLine@plt>
  movslq %eax,%r12
  cmpb   $0x0,(%r12)
  jne    L6
  movswl 0x0(%rbp),%r14d
L25:
  mov    %r14w,0x0(%rbp)
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <strtol@plt>
  mov    %eax,%r14d
  mov    (%rsp),%rax
  cmp    %r12,%rax
  je     L31
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L11
  movsbl %dil,%edi
  call   <toupper@plt>
  cmp    $0x50,%eax
  je     L64
L31:
  movswl 0x0(%rbp),%r14d
  lea    D32(%rip),%rdi
  call   <puts@plt>
L11:
  mov    (%rsp),%rax
  movsbl (%rax),%edi
  call   <toupper@plt>
  cmp    $0x50,%eax
  je     L64
  sub    $0x1,%r14d
  imul   %ebx,%r14d
L64:
  cmp    %r13d,%r14d
  jle    L25
  movswl 0x0(%rbp),%r14d
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L25
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D31
datatype: string
name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D32
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string

tool: D31: +

tool: 

tool: D3: %s (%d..%d) or (%dp..%dp) [%d%s or %dp]: 

tool: D32: ???1

tool: D0: ???2

assistant: ```c
void getXY(char *what, short *locp, int scale, int abs) {
  char *line, *end;
  int val;
  int min = abs ? 1 : 15;
  int minp = min * scale;
  int max = scale == 8 ? 80 : 30;
  int maxp = (max - abs) * scale;
  int loc = *locp / scale + abs;
  char *plus = *locp % scale ? "+" : "";
  printf("%s (%d..%d) or (%dp..%dp) [%d%s or %dp]: ", what, min, max, minp, maxp, loc, plus, (int)*locp);
  line = getLine();
  if (!*line)
    val = *locp;
  else {
    val = strtol(line, &end, 0);
    if (line == end || (*end && toupper(*end) != 'P')) {
      val = *locp;
      printf("???1\n");
    }
    if (toupper(*end) != 'P')
      val = (val - 1) * scale;
    if (val > maxp) {
      val = *locp;
      printf("???2\n");
    }
  }
  *locp = val;
  free(line);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int(strcmp)(char const *cs, char const *ct) {
  int __res;
  {
    ;
    return (__res);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int(strcmp)(char const *cs, char const *ct) {
  int __res;
  {
    ;
    return (__res);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int(strcmp)(char const *cs, char const *ct) {
  int __res;
  {
    ;
    return (__res);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int(strcmp)(char const *cs, char const *ct) {
  int __res;
  {
    ;
    return (__res);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x32,%eax
  cmp    $0x22,%eax
  ja     L107
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D5(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
  jmp    L55
  mov    $0x3,%eax
  jmp    L55
  mov    $0x4,%eax
  jmp    L55
  mov    $0x5,%eax
  jmp    L55
  mov    $0x6,%eax
  jmp    L55
  mov    $0x7,%eax
  jmp    L55
  mov    $0x8,%eax
  jmp    L55
  mov    $0x9,%eax
  jmp    L55
  mov    $0xa,%eax
  jmp    L55
  mov    $0xb,%eax
  jmp    L55
  mov    $0xc,%eax
  jmp    L55
  mov    $0xd,%eax
  jmp    L55
  mov    $0xe,%eax
  jmp    L55
L107:
  mov    $0x1,%eax
L55:
  pop    %rbp
  ret
```

assistant: ```c
int Sort(char c) {
  switch (c) {
  case '2':
    return 2;
  case '3':
    return 3;
  case '4':
    return 4;
  case '5':
    return 5;
  case '6':
    return 6;
  case '7':
    return 7;
  case '8':
    return 8;
  case '9':
    return 9;
  case 'T':
    return 10;
  case 'J':
    return 11;
  case 'Q':
    return 12;
  case 'K':
    return 13;
  case 'A':
    return 14;
  default:
    return 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Sort>:
  endbr64
  sub    $0x32,%edi
  cmp    $0x22,%dil
  ja     L4
  movzbl %dil,%edi
  lea    D1(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0xd,%eax
  ret
  mov    $0xe,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
```

assistant: ```c
int Sort(char c) {
  switch (c) {
  case '2':
    return 2;
  case '3':
    return 3;
  case '4':
    return 4;
  case '5':
    return 5;
  case '6':
    return 6;
  case '7':
    return 7;
  case '8':
    return 8;
  case '9':
    return 9;
  case 'T':
    return 10;
  case 'J':
    return 11;
  case 'Q':
    return 12;
  case 'K':
    return 13;
  case 'A':
    return 14;
  default:
    return 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Sort>:
  endbr64
  sub    $0x32,%edi
  mov    $0x1,%eax
  cmp    $0x22,%dil
  ja     L1
  movzbl %dil,%edi
  lea    D8(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L1:
  ret
```

assistant: ```c
int Sort(char c) {
  switch (c) {
  case '2':
    return 2;
  case '3':
    return 3;
  case '4':
    return 4;
  case '5':
    return 5;
  case '6':
    return 6;
  case '7':
    return 7;
  case '8':
    return 8;
  case '9':
    return 9;
  case 'T':
    return 10;
  case 'J':
    return 11;
  case 'Q':
    return 12;
  case 'K':
    return 13;
  case 'A':
    return 14;
  default:
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Sort>:
  endbr64
  sub    $0x32,%edi
  mov    $0x1,%eax
  cmp    $0x22,%dil
  ja     L7
  movzbl %dil,%edi
  lea    D2(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L7:
  ret
```

assistant: ```c
int Sort(char c) {
  switch (c) {
  case '2':
    return 2;
  case '3':
    return 3;
  case '4':
    return 4;
  case '5':
    return 5;
  case '6':
    return 6;
  case '7':
    return 7;
  case '8':
    return 8;
  case '9':
    return 9;
  case 'T':
    return 10;
  case 'J':
    return 11;
  case 'Q':
    return 12;
  case 'K':
    return 13;
  case 'A':
    return 14;
  default:
    return 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <SystemInit@plt>
L2:
  jmp    L2
```

assistant: ```c
int main(void) {
  SystemInit();
  while (1) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <SystemInit@plt>
L6:
  jmp    L6
```

assistant: ```c
int main(void) {
  SystemInit();
  while (1) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SystemInit@plt>
L7:
  jmp    L7
```

assistant: ```c
int main(void) {
  SystemInit();
  while (1) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SystemInit@plt>
L0:
  jmp    L0
```

assistant: ```c
int main(void) {
  SystemInit();
  while (1) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<netplot_replot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %edi,-0x114(%rbp)
  mov    %esi,-0x118(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x118(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    %edx,%ecx
  lea    D3(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x110(%rbp),%rdx
  mov    -0x114(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <send_command_expect_ok@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: replot %d


assistant: ```c
int netplot_replot(int server_connection_index, int plot_index) {
  char buffer[256];
  memset(buffer, 0, 256);
  snprintf(buffer, 256, "replot %d\n", plot_index);
  return send_command_expect_ok(server_connection_index, buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<netplot_replot>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%ecx
  lea    D3(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <send_command_expect_ok@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: string

tool: D3: replot %d


assistant: ```c
int netplot_replot(int server_connection_index, int plot_index) {
  char buffer[256];
  memset(buffer, 0, 256);
  snprintf(buffer, 256, "replot %d\n", plot_index);
  return send_command_expect_ok(server_connection_index, buffer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<netplot_replot>:
  endbr64
  push   %r13
  mov    $0x100,%edx
  mov    %esi,%r13d
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x100,%esi
  mov    %r12,%rdi
  mov    %r13d,%ecx
  lea    D5(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <send_command_expect_ok@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: replot %d


assistant: ```c
int netplot_replot(int server_connection_index, int plot_index) {
  char buffer[256];
  memset(buffer, 0, 256);
  snprintf(buffer, 256, "replot %d\n", plot_index);
  return send_command_expect_ok(server_connection_index, buffer);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<netplot_replot>:
  endbr64
  push   %r13
  mov    $0x100,%edx
  mov    %esi,%r13d
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x100,%esi
  mov    %r12,%rdi
  mov    %r13d,%ecx
  lea    D2(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <send_command_expect_ok@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D2: replot %d


assistant: ```c
int netplot_replot(int server_connection_index, int plot_index) {
  char buffer[256];
  memset(buffer, 0, 256);
  snprintf(buffer, 256, "replot %d\n", plot_index);
  return send_command_expect_ok(server_connection_index, buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cgexit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <gen@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <gen@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D0: popl	%ebp

tool: D2: ret

assistant: ```c
void cgexit(void) {
  gen("popl\t%ebp");
  gen("ret");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cgexit>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <gen@plt>
  lea    D19(%rip),%rdi
  call   <gen@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string

tool: D3: popl	%ebp

tool: D19: ret

assistant: ```c
void cgexit(void) {
  gen("popl\t%ebp");
  gen("ret");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cgexit>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <gen@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <gen@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string
name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D1: popl	%ebp

tool: D7: ret

assistant: ```c
void cgexit(void) {
  gen("popl\t%ebp");
  gen("ret");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cgexit>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <gen@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <gen@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string

tool: D18: popl	%ebp

tool: D1: ret

assistant: ```c
void cgexit(void) {
  gen("popl\t%ebp");
  gen("ret");
}
```
user: What is the c source code of the assembly code below?

```asm
<comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int comp(const void *a, const void *b) {
  int *x = (int *)a;
  int *y = (int *)b;
  return x[1] - y[1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comp>:
  endbr64
  mov    0x4(%rdi),%eax
  sub    0x4(%rsi),%eax
  ret
```

assistant: ```c
int comp(const void *a, const void *b) {
  int *x = (int *)a;
  int *y = (int *)b;
  return x[1] - y[1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<comp>:
  endbr64
  mov    0x4(%rdi),%eax
  sub    0x4(%rsi),%eax
  ret
```

assistant: ```c
int comp(const void *a, const void *b) {
  int *x = (int *)a;
  int *y = (int *)b;
  return x[1] - y[1];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<comp>:
  endbr64
  mov    0x4(%rdi),%eax
  sub    0x4(%rsi),%eax
  ret
```

assistant: ```c
int comp(const void *a, const void *b) {
  int *x = (int *)a;
  int *y = (int *)b;
  return x[1] - y[1];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movss  -0x14(%rbp),%xmm2
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm3
  movq   %xmm3,%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string
name: extract_symbolic_data
arguments: label: D12
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D5: Please insert three float numbers:

tool: D12: %f %f %f

tool: D9: Your numbers are:
%.4f
%.3f
%.0f


assistant: ```c
main() {
  float f1, f2, f3;
  printf("Please insert three float numbers:\n");
  scanf("%f %f %f", &f1, &f2, &f3);
  printf("Your numbers are:\n%.4f\n%.3f\n%.0f\n", f1, f2, f3);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd 0x14(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd 0x10(%rsp),%xmm1
  lea    D3(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D21
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string
name: disassemble_data
arguments: label: D3
data_type: string

tool: D21: Please insert three float numbers:

tool: D19: %f %f %f

tool: D3: Your numbers are:
%.4f
%.3f
%.0f


assistant: ```c
main() {
  float f1, f2, f3;
  printf("Please insert three float numbers:\n");
  scanf("%f %f %f", &f1, &f2, &f3);
  printf("Your numbers are:\n%.4f\n%.3f\n%.0f\n", f1, f2, f3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D23(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  lea    D1(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd 0x14(%rsp),%xmm2
  cvtss2sd 0x10(%rsp),%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
datatype: string
name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D1
datatype: string

tool: D10: Please insert three float numbers:

tool: D23: %f %f %f

tool: D1: Your numbers are:
%.4f
%.3f
%.0f


assistant: ```c
main() {
  float f1, f2, f3;
  printf("Please insert three float numbers:\n");
  scanf("%f %f %f", &f1, &f2, &f3);
  printf("Your numbers are:\n%.4f\n%.3f\n%.0f\n", f1, f2, f3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D8(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  lea    D21(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd 0x14(%rsp),%xmm2
  cvtss2sd 0x10(%rsp),%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
data_type: string
name: retrieve_data
arguments: tag: D8
data_type: string
name: retrieve_data
arguments: tag: D21
data_type: string

tool: D16: Please insert three float numbers:

tool: D8: %f %f %f

tool: D21: Your numbers are:
%.4f
%.3f
%.0f


assistant: ```c
main() {
  float f1, f2, f3;
  printf("Please insert three float numbers:\n");
  scanf("%f %f %f", &f1, &f2, &f3);
  printf("Your numbers are:\n%.4f\n%.3f\n%.0f\n", f1, f2, f3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inet6_srcrt_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <CMSG_DATA@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rsi
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x8(%rbp),%rdx
  mov    %ecx,0x4(%rdx)
  cltq
  shl    $0x2,%rax
  lea    (%rsi,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int inet6_srcrt_add(struct cmsghdr *cmsg, const struct in6_addr *addr) {
  struct ip6_rthdr0 *hdr;
  hdr = (struct ip6_rthdr0 *)CMSG_DATA(cmsg);
  cmsg->cmsg_len += sizeof(struct in6_addr);
  hdr->ip6r0_len += sizeof(struct in6_addr) / 8;
  memcpy(&hdr->ip6r0_addr[hdr->ip6r0_segleft++], addr, sizeof(struct in6_addr));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<inet6_srcrt_add>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <CMSG_DATA@plt>
  addl   $0x4,0x0(%rbp)
  mov    0x4(%rax),%edi
  lea    0x1(%rdi),%edx
  mov    %edx,0x4(%rax)
  movslq %edi,%rdi
  shl    $0x2,%rdi
  add    0x8(%rax),%rdi
  mov    $0x4,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int inet6_srcrt_add(struct cmsghdr *cmsg, const struct in6_addr *addr) {
  struct ip6_rthdr0 *hdr;
  hdr = (struct ip6_rthdr0 *)CMSG_DATA(cmsg);
  cmsg->cmsg_len += sizeof(struct in6_addr);
  hdr->ip6r0_len += sizeof(struct in6_addr) / 8;
  memcpy(&hdr->ip6r0_addr[hdr->ip6r0_segleft++], addr, sizeof(struct in6_addr));
  return 0;
}
```