ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bill>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x32,%edi
  ja     L41
  mov    %edi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  mulsd  D63(%rip),%xmm0
L20:
  mulsd  D44(%rip),%xmm0
  lea    D71(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L41:
  cmp    $0x96,%edi
  ja     L30
  lea    -0x32(%rdi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D10(%rip),%xmm0
  addsd  D69(%rip),%xmm0
  jmp    L20
L30:
  cmp    $0xfa,%edi
  ja     L46
  lea    -0x96(%rdi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D9(%rip),%xmm0
  addsd  D79(%rip),%xmm0
  jmp    L20
L46:
  lea    -0xfa(%rdi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D59(%rip),%xmm0
  addsd  D53(%rip),%xmm0
  jmp    L20
```

tool_calls: name: unpack_data
arguments: tag: D63
data_type: f64
name: unpack_data
arguments: tag: D44
data_type: f64
name: unpack_data
arguments: tag: D71
data_type: string
name: unpack_data
arguments: tag: D10
data_type: f64
name: unpack_data
arguments: tag: D69
data_type: byte[8]
name: unpack_data
arguments: tag: D9
data_type: f64
name: unpack_data
arguments: tag: D79
data_type: byte[8]
name: unpack_data
arguments: tag: D59
data_type: f64
name: unpack_data
arguments: tag: D53
data_type: byte[8]

tool: D63: 0.5

tool: D44: 1.3

tool: D71: Bill: %.2lf


tool: D10: 0.75

tool: {"D69": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D9: 1.2

tool: {"D79": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D59: 1.5

tool: {"D53": [0x00,0x00,0x00,0x00,0x00,0x80,0x6b,0x40]}

assistant: ```c
void bill(unsigned units) {
  double bill;
  if (units <= 50)
    bill = 0.5 * units;
  else if (units <= 150)
    bill = 0.5 * 50 + 0.75 * (units - 50);
  else if (units <= 250)
    bill = 0.5 * 50 + 0.75 * 100 + 1.2 * (units - 150);
  else
    bill = 0.5 * 50 + 0.75 * 100 + 1.2 * 100 + 1.5 * (units - 250);
  bill *= 1.3;
  printf("Bill: %.2lf\n", bill);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bill>:
  endbr64
  cmp    $0x32,%edi
  ja     L35
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D64(%rip),%xmm0
L3:
  mulsd  D58(%rip),%xmm0
  lea    D78(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L35:
  cmp    $0x96,%edi
  ja     L52
  sub    $0x32,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D21(%rip),%xmm0
  addsd  D70(%rip),%xmm0
  jmp    L3
  nopl   (%rax)
L52:
  cmp    $0xfa,%edi
  ja     L1
  sub    $0x96,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D26(%rip),%xmm0
  addsd  D11(%rip),%xmm0
  jmp    L3
L1:
  lea    -0xfa(%rdi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D79(%rip),%xmm0
  addsd  D31(%rip),%xmm0
  jmp    L3
```

tool_calls: name: read_data
arguments: label: D64
datatype: f64
name: read_data
arguments: label: D58
datatype: f64
name: read_data
arguments: label: D78
datatype: string
name: read_data
arguments: label: D21
datatype: f64
name: read_data
arguments: label: D70
datatype: byte[8]
name: read_data
arguments: label: D26
datatype: f64
name: read_data
arguments: label: D11
datatype: byte[8]
name: read_data
arguments: label: D79
datatype: f64
name: read_data
arguments: label: D31
datatype: byte[8]

tool: D64: 0.5

tool: D58: 1.3

tool: D78: Bill: %.2lf


tool: D21: 0.75

tool: {"D70": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D26: 1.2

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D79: 1.5

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x80,0x6b,0x40]}

assistant: ```c
void bill(unsigned units) {
  double bill;
  if (units <= 50)
    bill = 0.5 * units;
  else if (units <= 150)
    bill = 0.5 * 50 + 0.75 * (units - 50);
  else if (units <= 250)
    bill = 0.5 * 50 + 0.75 * 100 + 1.2 * (units - 150);
  else
    bill = 0.5 * 50 + 0.75 * 100 + 1.2 * 100 + 1.5 * (units - 250);
  bill *= 1.3;
  printf("Bill: %.2lf\n", bill);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bill>:
  endbr64
  cmp    $0x32,%edi
  ja     L30
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D10(%rip),%xmm0
L57:
  mulsd  D5(%rip),%xmm0
  lea    D67(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   (%rax)
L30:
  cmp    $0x96,%edi
  ja     L2
  sub    $0x32,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D32(%rip),%xmm0
  addsd  D61(%rip),%xmm0
  jmp    L57
  nopl   (%rax)
L2:
  cmp    $0xfa,%edi
  ja     L15
  sub    $0x96,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D75(%rip),%xmm0
  addsd  D65(%rip),%xmm0
  jmp    L57
L15:
  lea    -0xfa(%rdi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D49(%rip),%xmm0
  addsd  D79(%rip),%xmm0
  jmp    L57
```

tool_calls: name: read_data
arguments: tag: D10
type_infered: f64
name: read_data
arguments: tag: D5
type_infered: f64
name: read_data
arguments: tag: D67
type_infered: string
name: read_data
arguments: tag: D32
type_infered: f64
name: read_data
arguments: tag: D61
type_infered: byte[8]
name: read_data
arguments: tag: D75
type_infered: f64
name: read_data
arguments: tag: D65
type_infered: byte[8]
name: read_data
arguments: tag: D49
type_infered: f64
name: read_data
arguments: tag: D79
type_infered: byte[8]

tool: D10: 0.5

tool: D5: 1.3

tool: D67: Bill: %.2lf


tool: D32: 0.75

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D75: 1.2

tool: {"D65": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D49: 1.5

tool: {"D79": [0x00,0x00,0x00,0x00,0x00,0x80,0x6b,0x40]}

assistant: ```c
void bill(unsigned units) {
  double bill;
  if (units <= 50)
    bill = 0.5 * units;
  else if (units <= 150)
    bill = 0.5 * 50 + 0.75 * (units - 50);
  else if (units <= 250)
    bill = 0.5 * 50 + 0.75 * 100 + 1.2 * (units - 150);
  else
    bill = 0.5 * 50 + 0.75 * 100 + 1.2 * 100 + 1.5 * (units - 250);
  bill *= 1.3;
  printf("Bill: %.2lf\n", bill);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_paragraph_save_amount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <get_configuration_value@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    $0xffffffff,%eax
  jmp    L3
L19:
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: save-text-history-paragraphs

assistant: ```c
int get_paragraph_save_amount() {
  char *nof_paragraphs_as_string = get_configuration_value("save-text-history-paragraphs");
  if (nof_paragraphs_as_string == NULL)
    return -1;
  else
    return strtol(nof_paragraphs_as_string, NULL, 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_paragraph_save_amount>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <get_configuration_value@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
L3:
  add    $0x8,%rsp
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L3
```

tool_calls: name: read_data
arguments: tag: D2
type: string

tool: D2: save-text-history-paragraphs

assistant: ```c
int get_paragraph_save_amount() {
  char *nof_paragraphs_as_string = get_configuration_value("save-text-history-paragraphs");
  if (nof_paragraphs_as_string == NULL)
    return -1;
  else
    return strtol(nof_paragraphs_as_string, NULL, 10);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_paragraph_save_amount>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <get_configuration_value@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  add    $0x8,%rsp
  jmp    1060 <strtol@plt>
  nopl   0x0(%rax)
L1:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: save-text-history-paragraphs

assistant: ```c
int get_paragraph_save_amount() {
  char *nof_paragraphs_as_string = get_configuration_value("save-text-history-paragraphs");
  if (nof_paragraphs_as_string == NULL)
    return -1;
  else
    return strtol(nof_paragraphs_as_string, NULL, 10);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_paragraph_save_amount>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <get_configuration_value@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  add    $0x8,%rsp
  jmp    1060 <strtol@plt>
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string

tool: D5: save-text-history-paragraphs

assistant: ```c
int get_paragraph_save_amount() {
  char *nof_paragraphs_as_string = get_configuration_value("save-text-history-paragraphs");
  if (nof_paragraphs_as_string == NULL)
    return -1;
  else
    return strtol(nof_paragraphs_as_string, NULL, 10);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<iRcTSFID_RUDLL_GetFinger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1008,%edx
  lea    D14(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  addl   $0x3,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  add    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x3d,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <iDoRemoteFunc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L22
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <vWriteLogTxt@plt>
  mov    $0x63,%eax
  jmp    L29
L22:
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <iGetParaInt@plt>
  test   %eax,%eax
  jne    L20
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <psGetParaBuf@plt>
  cltq
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    $0xc8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <psGetParaBuf@plt>
  cltq
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x64,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L20:
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <iGetParaInt@plt>
L29:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D23
type_guessed: string
name: unpack_data
arguments: data_label: D20
type_guessed: string

tool: D14: %u(b003

tool: D23: ,b000,b000)

tool: D20: iRcTSFID_RUDLL_GetFinger iDoRemoteFunc ret = %d

assistant: ```c
int iRcTSFID_RUDLL_GetFinger(char fpflag[3], unsigned char fpminu1[200], unsigned char fpminu2[100]) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(b003", 4104);
  memcpy(psFunCall + uiDataLen, fpflag, 3);
  uiDataLen += 3;
  uiDataLen += sprintf(psFunCall + uiDataLen, ",b000,b000)");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 61);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("iRcTSFID_RUDLL_GetFinger iDoRemoteFunc ret = %d", uiRet);
    return 99;
  }
  if (iGetParaInt(0) == 0) {
    memcpy(fpminu1, psGetParaBuf(3), 200);
    memcpy(fpminu2, psGetParaBuf(4), 100);
  }
  return iGetParaInt(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shl_array_pow2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    $0x4,%eax
  jmp    L33
L2:
  subq   $0x1,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L4
L17:
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  or     %rax,-0x18(%rbp)
  shlq   -0x8(%rbp)
L4:
  cmpq   $0x3f,-0x8(%rbp)
  jbe    L17
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
L33:
  pop    %rbp
  ret
```

assistant: ```c
size_t shl_array_pow2(size_t v) {
  size_t i;
  if (!v)
    return 4;
  --v;
  for (i = 1; i < 8 * sizeof(size_t); i *= 2)
    v |= v >> i;
  return ++v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shl_array_pow2>:
  endbr64
  mov    $0x4,%eax
  test   %rdi,%rdi
  je     L14
  lea    -0x1(%rdi),%rax
  mov    $0x6,%edx
  mov    $0x1,%ecx
L0:
  mov    %rax,%rsi
  shr    %cl,%rsi
  or     %rsi,%rax
  add    %rcx,%rcx
  sub    $0x1,%edx
  jne    L0
  add    $0x1,%rax
L14:
  ret
```

assistant: ```c
size_t shl_array_pow2(size_t v) {
  size_t i;
  if (!v)
    return 4;
  --v;
  for (i = 1; i < 8 * sizeof(size_t); i *= 2)
    v |= v >> i;
  return ++v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<shl_array_pow2>:
  endbr64
  mov    $0x4,%eax
  test   %rdi,%rdi
  je     L19
  lea    -0x1(%rdi),%rax
  mov    $0x6,%edx
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L1:
  mov    %rax,%rsi
  shr    %cl,%rsi
  add    %rcx,%rcx
  or     %rsi,%rax
  sub    $0x1,%edx
  jne    L1
  add    $0x1,%rax
L19:
  ret
```

assistant: ```c
size_t shl_array_pow2(size_t v) {
  size_t i;
  if (!v)
    return 4;
  --v;
  for (i = 1; i < 8 * sizeof(size_t); i *= 2)
    v |= v >> i;
  return ++v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shl_array_pow2>:
  endbr64
  mov    $0x4,%eax
  test   %rdi,%rdi
  je     L5
  sub    $0x1,%rdi
  mov    %rdi,%rdx
  shr    %rdx
  or     %rdi,%rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x8,%rax
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x20,%rax
  or     %rdx,%rax
  add    $0x1,%rax
L5:
  ret
```

assistant: ```c
size_t shl_array_pow2(size_t v) {
  size_t i;
  if (!v)
    return 4;
  --v;
  for (i = 1; i < 8 * sizeof(size_t); i *= 2)
    v |= v >> i;
  return ++v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MDparseline>:
  endbr64
  movq   $0x0,(%rdx)
  mov    %rsi,%rax
  movq   $0x0,(%rcx)
  cmp    %rsi,%rdi
  jb     L316
  jmp    L92
  nopl   0x0(%rax)
L157:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  je     L92
L316:
  movzbl (%rdi),%esi
  cmp    $0x20,%sil
  je     L157
  cmp    %rdi,%rax
  jbe    L92
  cmp    $0xa,%sil
  je     L126
  cmp    $0x23,%sil
  je     L12
  mov    %rdi,(%rdx)
  jmp    L76
  nopl   0x0(%rax)
L319:
  cmp    $0x3a,%dl
  je     L346
  lea    0x1(%rdi),%rdx
  cmp    %rdx,%rax
  je     L156
  mov    %rdx,%rdi
L76:
  movzbl (%rdi),%edx
  cmp    $0xa,%dl
  jne    L319
  cmp    $0x3a,%dl
  je     L346
L92:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L12:
  mov    %rdi,%rdx
  add    $0x1,%rdi
  cmp    %rdi,%rax
  je     L92
  cmpb   $0xa,(%rdi)
  jne    L12
  lea    0x2(%rdx),%rax
  ret
  xchg   %ax,%ax
L346:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  ja     L89
  jmp    L92
  nopl   0x0(%rax,%rax,1)
L62:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  je     L92
L89:
  cmpb   $0x20,(%rdi)
  je     L62
  cmp    %rdi,%rax
  ja     L36
  jmp    L92
  nopl   (%rax)
L269:
  cmp    $0x23,%dl
  je     L290
  add    $0x1,%rdi
  cmp    %rdi,%rax
  je     L92
L36:
  movzbl (%rdi),%edx
  cmp    $0xa,%dl
  jne    L269
L290:
  cmp    %rdi,%rax
  jbe    L92
  cmp    $0xa,%dl
  je     L126
  cmpb   $0x3a,0x1(%rdi)
  jne    L92
  add    $0x2,%rdi
  cmp    %rdi,%rax
  ja     L163
  jmp    L92
  nopl   0x0(%rax)
L223:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  je     L92
L163:
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L223
  cmp    %rdi,%rax
  jbe    L92
  cmp    $0xa,%dl
  je     L126
  mov    %rdi,(%rcx)
  jmp    L134
  nopl   0x0(%rax,%rax,1)
L144:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  je     L92
L134:
  cmpb   $0xa,(%rdi)
  jne    L144
  cmp    %rdi,%rax
  jbe    L92
L126:
  lea    0x1(%rdi),%rax
  ret
L156:
  movzbl 0x1(%rdi),%edx
  mov    %rax,%rdi
  cmp    $0x3a,%dl
  jne    L92
  jmp    L346
```

assistant: ```c
char *MDparseline(char *line, char *limit, char **targ, char **tool) {
  char *next;
  *targ = 0;
  *tool = 0;
  next = line;
  while (next < limit && *next == ' ') {
    next++;
  };
  if ((next >= limit)) {
    return 0;
  }
  if ((*next == '\n')) {
    return ++next;
  }
  if (*next == '#') {
    while (next < limit && *next != '\n') {
      next++;
    };
    if ((next >= limit)) {
      return 0;
    }
    if ((*next == '\n')) {
      return ++next;
    }
  }
  *targ = next;
  while (next < limit && *next != ':' && *next != '\n') {
    next++;
  };
  if (*next != ':')
    return 0;
  next++;
  while (next < limit && *next == ' ') {
    next++;
  };
  while (next < limit && *next != '#' && *next != '\n') {
    next++;
  };
  if ((next >= limit)) {
    return 0;
  }
  if ((*next == '\n')) {
    return ++next;
  }
  if (*++next != ':')
    return 0;
  next++;
  while (next < limit && *next == ' ') {
    next++;
  };
  if ((next >= limit)) {
    return 0;
  }
  if ((*next == '\n')) {
    return ++next;
  }
  *tool = next;
  while (next < limit && *next != '\n') {
    next++;
  };
  if ((next >= limit)) {
    return 0;
  }
  return ++next;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hextoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: %llx

assistant: ```c
unsigned long long hextoll(char *str) {
  unsigned long long ret;
  sscanf(str, "%llx", &ret);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hextoll>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: %llx

assistant: ```c
unsigned long long hextoll(char *str) {
  unsigned long long ret;
  sscanf(str, "%llx", &ret);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hextoll>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <sscanf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D9: %llx

assistant: ```c
unsigned long long hextoll(char *str) {
  unsigned long long ret;
  sscanf(str, "%llx", &ret);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hextoll>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <sscanf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: %llx

assistant: ```c
unsigned long long hextoll(char *str) {
  unsigned long long ret;
  sscanf(str, "%llx", &ret);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <flockfile@plt>
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf_unlocked@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <funlockfile@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int printf(const char *restrict format, ...) {
  flockfile(stdout);
  va_list ap;
  va_start(ap, format);
  int result = vfprintf_unlocked(stdout, format, ap);
  va_end(ap);
  funlockfile(stdout);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    D7(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <flockfile@plt>
  mov    %rbx,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    0x0(%rbp),%edi
  call   <vfprintf_unlocked@plt>
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    0x0(%rbp),%edi
  call   <funlockfile@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int printf(const char *restrict format, ...) {
  flockfile(stdout);
  va_list ap;
  va_start(ap, format);
  int result = vfprintf_unlocked(stdout, format, ap);
  va_end(ap);
  funlockfile(stdout);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbx
  mov    (%rbx),%edi
  call   <flockfile@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    (%rbx),%edi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <vfprintf_unlocked@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    (%rbx),%edi
  call   <funlockfile@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int printf(const char *restrict format, ...) {
  flockfile(stdout);
  va_list ap;
  va_start(ap, format);
  int result = vfprintf_unlocked(stdout, format, ap);
  va_end(ap);
  funlockfile(stdout);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%rbx
  mov    (%rbx),%edi
  call   <flockfile@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    (%rbx),%edi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <vfprintf_unlocked@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    (%rbx),%edi
  call   <funlockfile@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int printf(const char *restrict format, ...) {
  flockfile(stdout);
  va_list ap;
  va_start(ap, format);
  int result = vfprintf_unlocked(stdout, format, ap);
  va_end(ap);
  funlockfile(stdout);
  return result;
}
```