ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compose_final_consonants>:
  endbr64
  cmp    $0x13,%esi
  sete   %dl
  cmp    $0x1,%edi
  jne    L200
  mov    $0x3,%eax
  test   %dl,%dl
  jne    L183
L200:
  cmp    $0x4,%edi
  sete   %cl
  cmp    $0x16,%esi
  jne    L65
  mov    $0x5,%eax
  test   %cl,%cl
  jne    L183
L65:
  cmp    $0x1b,%esi
  sete   %r8b
  test   %cl,%cl
  je     L58
  mov    $0x6,%eax
  test   %r8b,%r8b
  jne    L183
L58:
  cmp    $0x8,%edi
  sete   %cl
  cmp    $0x1,%esi
  jne    L142
  mov    $0x9,%eax
  test   %cl,%cl
  jne    L183
L142:
  cmp    $0x10,%esi
  jne    L217
  mov    $0xa,%eax
  test   %cl,%cl
  jne    L183
L217:
  cmp    $0x11,%esi
  jne    L31
  mov    $0xb,%eax
  test   %cl,%cl
  jne    L183
L31:
  test   %dl,%dl
  je     L119
  mov    $0xc,%eax
  test   %cl,%cl
  jne    L183
L119:
  cmp    $0x19,%esi
  jne    L190
  mov    $0xd,%eax
  test   %cl,%cl
  jne    L183
L190:
  cmp    $0x1a,%esi
  jne    L171
  mov    $0xe,%eax
  test   %cl,%cl
  jne    L183
L171:
  test   %r8b,%r8b
  je     L113
  mov    $0xf,%eax
  test   %cl,%cl
  jne    L183
L113:
  cmp    $0x11,%edi
  jne    L184
  test   %dl,%dl
  je     L184
  mov    $0x12,%eax
  ret
L184:
  mov    $0xffffffff,%eax
L183:
  ret
```

assistant: ```c
int compose_final_consonants(int c1, int c2) {
  if (c1 == 1 && c2 == 19)
    return 3;
  if (c1 == 4 && c2 == 22)
    return 5;
  if (c1 == 4 && c2 == 27)
    return 6;
  if (c1 == 8 && c2 == 1)
    return 9;
  if (c1 == 8 && c2 == 16)
    return 10;
  if (c1 == 8 && c2 == 17)
    return 11;
  if (c1 == 8 && c2 == 19)
    return 12;
  if (c1 == 8 && c2 == 25)
    return 13;
  if (c1 == 8 && c2 == 26)
    return 14;
  if (c1 == 8 && c2 == 27)
    return 15;
  if (c1 == 17 && c2 == 19)
    return 18;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compose_final_consonants>:
  endbr64
  cmp    $0x13,%esi
  sete   %dl
  cmp    $0x1,%edi
  jne    L125
  mov    $0x3,%eax
  test   %dl,%dl
  jne    L215
L125:
  cmp    $0x4,%edi
  sete   %cl
  cmp    $0x16,%esi
  jne    L68
  mov    $0x5,%eax
  test   %cl,%cl
  jne    L215
L68:
  cmp    $0x1b,%esi
  sete   %r8b
  test   %cl,%cl
  je     L132
  mov    $0x6,%eax
  test   %r8b,%r8b
  jne    L215
L132:
  cmp    $0x8,%edi
  sete   %cl
  cmp    $0x1,%esi
  jne    L178
  mov    $0x9,%eax
  test   %cl,%cl
  jne    L215
L178:
  cmp    $0x10,%esi
  jne    L165
  mov    $0xa,%eax
  test   %cl,%cl
  jne    L215
L165:
  cmp    $0x11,%esi
  jne    L18
  mov    $0xb,%eax
  test   %cl,%cl
  jne    L215
L18:
  test   %dl,%dl
  je     L211
  mov    $0xc,%eax
  test   %cl,%cl
  jne    L215
L211:
  cmp    $0x19,%esi
  jne    L187
  mov    $0xd,%eax
  test   %cl,%cl
  jne    L215
L187:
  cmp    $0x1a,%esi
  jne    L149
  mov    $0xe,%eax
  test   %cl,%cl
  jne    L215
L149:
  test   %r8b,%r8b
  je     L186
  mov    $0xf,%eax
  test   %cl,%cl
  jne    L215
L186:
  cmp    $0x11,%edi
  jne    L192
  test   %dl,%dl
  je     L192
  mov    $0x12,%eax
  ret
L192:
  mov    $0xffffffff,%eax
L215:
  ret
```

assistant: ```c
int compose_final_consonants(int c1, int c2) {
  if (c1 == 1 && c2 == 19)
    return 3;
  if (c1 == 4 && c2 == 22)
    return 5;
  if (c1 == 4 && c2 == 27)
    return 6;
  if (c1 == 8 && c2 == 1)
    return 9;
  if (c1 == 8 && c2 == 16)
    return 10;
  if (c1 == 8 && c2 == 17)
    return 11;
  if (c1 == 8 && c2 == 19)
    return 12;
  if (c1 == 8 && c2 == 25)
    return 13;
  if (c1 == 8 && c2 == 26)
    return 14;
  if (c1 == 8 && c2 == 27)
    return 15;
  if (c1 == 17 && c2 == 19)
    return 18;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<config_change_hotlist_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <gui_hotlist_resort@plt>
  nop
  leave
  ret
```

assistant: ```c
void config_change_hotlist_sort(void *data, struct t_config_option *option) {
  (void)data;
  (void)option;
  gui_hotlist_resort();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<config_change_hotlist_sort>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gui_hotlist_resort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void config_change_hotlist_sort(void *data, struct t_config_option *option) {
  (void)data;
  (void)option;
  gui_hotlist_resort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<config_change_hotlist_sort>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <gui_hotlist_resort@plt>
```

assistant: ```c
void config_change_hotlist_sort(void *data, struct t_config_option *option) {
  (void)data;
  (void)option;
  gui_hotlist_resort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<config_change_hotlist_sort>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <gui_hotlist_resort@plt>
```

assistant: ```c
void config_change_hotlist_sort(void *data, struct t_config_option *option) {
  (void)data;
  (void)option;
  gui_hotlist_resort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc4(%rbp),%edx
  mov    -0xb4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <printList@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void print(int num, ...) {
  va_list valist;
  va_start(valist, num);
  printList(num, valist);
  va_end(valist);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%esi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <printList@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void print(int num, ...) {
  va_list valist;
  va_start(valist, num);
  printList(num, valist);
  va_end(valist);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <printList@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void print(int num, ...) {
  va_list valist;
  va_start(valist, num);
  printList(num, valist);
  va_end(valist);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <printList@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void print(int num, ...) {
  va_list valist;
  va_start(valist, num);
  printList(num, valist);
  va_end(valist);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<smbus_read_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <smbus_wait_until_ready@plt>
  test   %rax,%rax
  jns    L8
  mov    $0xfffffffe,%eax
  jmp    L42
L8:
  mov    $0xfe2,%edi
  call   <inw@plt>
  and    $0xfffff8ef,%eax
  mov    $0xfe2,%esi
  mov    %eax,%edi
  call   <outw@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  movzbl %al,%eax
  or     $0x1,%eax
  mov    $0xfe4,%esi
  mov    %eax,%edi
  call   <outw@plt>
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    $0xfe8,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    $0xfe2,%edi
  call   <inw@plt>
  and    $0xfffffff8,%eax
  or     $0x2,%eax
  mov    $0xfe2,%esi
  mov    %eax,%edi
  call   <outw@plt>
  mov    $0xfe0,%edi
  call   <inw@plt>
  mov    $0xfe0,%esi
  mov    %eax,%edi
  call   <outw@plt>
  mov    $0xfe6,%esi
  mov    $0x0,%edi
  call   <outw@plt>
  mov    $0xfe2,%edi
  call   <inw@plt>
  or     $0x8,%eax
  mov    $0xfe2,%esi
  mov    %eax,%edi
  call   <outw@plt>
  mov    $0x0,%eax
  call   <smbus_wait_until_done@plt>
  test   %rax,%rax
  jns    L37
  mov    $0xfffffffd,%eax
  jmp    L42
L37:
  mov    $0xfe0,%edi
  call   <inw@plt>
  mov    %al,-0x2(%rbp)
  mov    $0xfe6,%edi
  call   <inw@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x10,-0x2(%rbp)
  je     L51
  mov    $0xffffffff,%eax
  jmp    L42
L51:
  movzbl -0x1(%rbp),%eax
L42:
  leave
  ret
```

assistant: ```c
int smbus_read_byte(unsigned device, unsigned address) {
  unsigned char global_control_register;
  unsigned char global_status_register;
  unsigned char byte;
  if (smbus_wait_until_ready() < 0) {
    return -2;
  }
  outw(inw(0x0f00 + 0xe2) & ~((1 << 10) | (1 << 9) | (1 << 8) | (1 << 4)), 0x0f00 + 0xe2);
  outw(((device & 0x7f) << 1) | 1, 0x0f00 + 0xe4);
  outb(address & 0xFF, 0x0f00 + 0xe8);
  outw((inw(0x0f00 + 0xe2) & ~7) | (0x2), 0x0f00 + 0xe2);
  outw(inw(0x0f00 + 0xe0), 0x0f00 + 0xe0);
  outw(0, 0x0f00 + 0xe6);
  outw((inw(0x0f00 + 0xe2) | (1 << 3)), 0x0f00 + 0xe2);
  if (smbus_wait_until_done() < 0) {
    return -3;
  }
  global_status_register = inw(0x0f00 + 0xe0);
  byte = inw(0x0f00 + 0xe6) & 0xff;
  if (global_status_register != (1 << 4)) {
    return -1;
  }
  return byte;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<smbus_read_byte>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <smbus_wait_until_ready@plt>
  test   %rax,%rax
  js     L30
  mov    $0xfe2,%edi
  call   <inw@plt>
  and    $0xfffff8ef,%eax
  mov    %eax,%edi
  mov    $0xfe2,%esi
  call   <outw@plt>
  lea    (%rbx,%rbx,1),%edi
  movzbl %dil,%edi
  or     $0x1,%edi
  mov    $0xfe4,%esi
  call   <outw@plt>
  movzbl %bpl,%edi
  mov    $0xfe8,%esi
  call   <outb@plt>
  mov    $0xfe2,%edi
  call   <inw@plt>
  and    $0xfffffff8,%eax
  mov    %eax,%edi
  or     $0x2,%edi
  mov    $0xfe2,%esi
  call   <outw@plt>
  mov    $0xfe0,%edi
  call   <inw@plt>
  mov    %eax,%edi
  mov    $0xfe0,%esi
  call   <outw@plt>
  mov    $0xfe6,%esi
  mov    $0x0,%edi
  call   <outw@plt>
  mov    $0xfe2,%edi
  call   <inw@plt>
  or     $0x8,%eax
  mov    %eax,%edi
  mov    $0xfe2,%esi
  call   <outw@plt>
  mov    $0x0,%eax
  call   <smbus_wait_until_done@plt>
  test   %rax,%rax
  js     L58
  mov    $0xfe0,%edi
  call   <inw@plt>
  mov    %eax,%ebx
  mov    $0xfe6,%edi
  call   <inw@plt>
  cmp    $0x10,%bl
  jne    L17
  movzbl %al,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  mov    $0xfffffffe,%eax
  jmp    L7
L58:
  mov    $0xfffffffd,%eax
  jmp    L7
L17:
  mov    $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int smbus_read_byte(unsigned device, unsigned address) {
  unsigned char global_control_register;
  unsigned char global_status_register;
  unsigned char byte;
  if (smbus_wait_until_ready() < 0) {
    return -2;
  }
  outw(inw(0x0f00 + 0xe2) & ~((1 << 10) | (1 << 9) | (1 << 8) | (1 << 4)), 0x0f00 + 0xe2);
  outw(((device & 0x7f) << 1) | 1, 0x0f00 + 0xe4);
  outb(address & 0xFF, 0x0f00 + 0xe8);
  outw((inw(0x0f00 + 0xe2) & ~7) | (0x2), 0x0f00 + 0xe2);
  outw(inw(0x0f00 + 0xe0), 0x0f00 + 0xe0);
  outw(0, 0x0f00 + 0xe6);
  outw((inw(0x0f00 + 0xe2) | (1 << 3)), 0x0f00 + 0xe2);
  if (smbus_wait_until_done() < 0) {
    return -3;
  }
  global_status_register = inw(0x0f00 + 0xe0);
  byte = inw(0x0f00 + 0xe6) & 0xff;
  if (global_status_register != (1 << 4)) {
    return -1;
  }
  return byte;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<smbus_read_byte>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <smbus_wait_until_ready@plt>
  test   %rax,%rax
  js     L38
  mov    $0xfe2,%edi
  call   <inw@plt>
  mov    $0xfe2,%esi
  and    $0xfffff8ef,%eax
  mov    %eax,%edi
  call   <outw@plt>
  lea    (%rbx,%rbx,1),%edi
  mov    $0xfe4,%esi
  movzbl %dil,%edi
  or     $0x1,%edi
  call   <outw@plt>
  mov    $0xfe8,%esi
  movzbl %bpl,%edi
  call   <outb@plt>
  mov    $0xfe2,%edi
  call   <inw@plt>
  mov    $0xfe2,%esi
  and    $0xfffffff8,%eax
  mov    %eax,%edi
  or     $0x2,%edi
  call   <outw@plt>
  mov    $0xfe0,%edi
  call   <inw@plt>
  mov    $0xfe0,%esi
  mov    %eax,%edi
  call   <outw@plt>
  mov    $0xfe6,%esi
  xor    %edi,%edi
  call   <outw@plt>
  mov    $0xfe2,%edi
  call   <inw@plt>
  mov    $0xfe2,%esi
  or     $0x8,%eax
  mov    %eax,%edi
  call   <outw@plt>
  xor    %eax,%eax
  call   <smbus_wait_until_done@plt>
  test   %rax,%rax
  js     L46
  mov    $0xfe0,%edi
  call   <inw@plt>
  mov    $0xfe6,%edi
  mov    %eax,%ebx
  call   <inw@plt>
  cmp    $0x10,%bl
  jne    L15
  movzbl %al,%eax
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xffffffff,%eax
  jmp    L50
  nop
L38:
  mov    $0xfffffffe,%eax
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L46:
  mov    $0xfffffffd,%eax
  jmp    L50
```

assistant: ```c
int smbus_read_byte(unsigned device, unsigned address) {
  unsigned char global_control_register;
  unsigned char global_status_register;
  unsigned char byte;
  if (smbus_wait_until_ready() < 0) {
    return -2;
  }
  outw(inw(0x0f00 + 0xe2) & ~((1 << 10) | (1 << 9) | (1 << 8) | (1 << 4)), 0x0f00 + 0xe2);
  outw(((device & 0x7f) << 1) | 1, 0x0f00 + 0xe4);
  outb(address & 0xFF, 0x0f00 + 0xe8);
  outw((inw(0x0f00 + 0xe2) & ~7) | (0x2), 0x0f00 + 0xe2);
  outw(inw(0x0f00 + 0xe0), 0x0f00 + 0xe0);
  outw(0, 0x0f00 + 0xe6);
  outw((inw(0x0f00 + 0xe2) | (1 << 3)), 0x0f00 + 0xe2);
  if (smbus_wait_until_done() < 0) {
    return -3;
  }
  global_status_register = inw(0x0f00 + 0xe0);
  byte = inw(0x0f00 + 0xe6) & 0xff;
  if (global_status_register != (1 << 4)) {
    return -1;
  }
  return byte;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smbus_read_byte>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <smbus_wait_until_ready@plt>
  test   %rax,%rax
  js     L4
  mov    $0xfe2,%edi
  call   <inw@plt>
  mov    $0xfe2,%esi
  and    $0xfffff8ef,%eax
  mov    %eax,%edi
  call   <outw@plt>
  lea    (%rbx,%rbx,1),%edi
  mov    $0xfe4,%esi
  movzbl %dil,%edi
  or     $0x1,%edi
  call   <outw@plt>
  mov    $0xfe8,%esi
  movzbl %bpl,%edi
  call   <outb@plt>
  mov    $0xfe2,%edi
  call   <inw@plt>
  mov    $0xfe2,%esi
  and    $0xfffffff8,%eax
  mov    %eax,%edi
  or     $0x2,%edi
  call   <outw@plt>
  mov    $0xfe0,%edi
  call   <inw@plt>
  mov    $0xfe0,%esi
  mov    %eax,%edi
  call   <outw@plt>
  mov    $0xfe6,%esi
  xor    %edi,%edi
  call   <outw@plt>
  mov    $0xfe2,%edi
  call   <inw@plt>
  mov    $0xfe2,%esi
  or     $0x8,%eax
  mov    %eax,%edi
  call   <outw@plt>
  xor    %eax,%eax
  call   <smbus_wait_until_done@plt>
  test   %rax,%rax
  js     L39
  mov    $0xfe0,%edi
  call   <inw@plt>
  mov    $0xfe6,%edi
  mov    %eax,%ebx
  call   <inw@plt>
  cmp    $0x10,%bl
  jne    L1
  movzbl %al,%eax
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xffffffff,%eax
  jmp    L38
  nop
L4:
  mov    $0xfffffffe,%eax
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0xfffffffd,%eax
  jmp    L38
```

assistant: ```c
int smbus_read_byte(unsigned device, unsigned address) {
  unsigned char global_control_register;
  unsigned char global_status_register;
  unsigned char byte;
  if (smbus_wait_until_ready() < 0) {
    return -2;
  }
  outw(inw(0x0f00 + 0xe2) & ~((1 << 10) | (1 << 9) | (1 << 8) | (1 << 4)), 0x0f00 + 0xe2);
  outw(((device & 0x7f) << 1) | 1, 0x0f00 + 0xe4);
  outb(address & 0xFF, 0x0f00 + 0xe8);
  outw((inw(0x0f00 + 0xe2) & ~7) | (0x2), 0x0f00 + 0xe2);
  outw(inw(0x0f00 + 0xe0), 0x0f00 + 0xe0);
  outw(0, 0x0f00 + 0xe6);
  outw((inw(0x0f00 + 0xe2) | (1 << 3)), 0x0f00 + 0xe2);
  if (smbus_wait_until_done() < 0) {
    return -3;
  }
  global_status_register = inw(0x0f00 + 0xe0);
  byte = inw(0x0f00 + 0xe6) & 0xff;
  if (global_status_register != (1 << 4)) {
    return -1;
  }
  return byte;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x7,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bar(void) {
  int32_t result;
  const int32_t other = 7;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bar>:
  endbr64
  ret
```

assistant: ```c
void bar(void) {
  int32_t result;
  const int32_t other = 7;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bar>:
  endbr64
  ret
```

assistant: ```c
void bar(void) {
  int32_t result;
  const int32_t other = 7;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  ret
```

assistant: ```c
void bar(void) {
  int32_t result;
  const int32_t other = 7;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RmatMult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L42:
  movl   $0x0,-0x8(%rbp)
  jmp    L49
L50:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  movl   $0x0,-0xc(%rbp)
  jmp    L58
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm2
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  addl   $0x1,-0xc(%rbp)
L58:
  cmpl   $0x2,-0xc(%rbp)
  jle    L5
  addl   $0x1,-0x8(%rbp)
L49:
  cmpl   $0x2,-0x8(%rbp)
  jle    L50
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x2,-0x4(%rbp)
  jle    L42
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void RmatMult(float (*A)[3l], float (*B)[3l], float (*C)[3l]) {
  signed int i;
  signed int j;
  signed int k = 0;
  while (k < 3) {
    j = 0;
    while (j < 3) {
      A[(signed long int)k][(signed long int)j] = (float)0.000000;
      i = 0;
      while (i < 3) {
        A[(signed long int)k][(signed long int)j] = A[(signed long int)k][(signed long int)j] + B[(signed long int)k][(signed long int)i] * C[(signed long int)i][(signed long int)j];
        i = i + 1;
      }
      j = j + 1;
    }
    k = k + 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RmatMult>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%r11
  lea    0xc(%rsi),%r10
  lea    0x30(%rsi),%rbp
  lea    0xc(%rdx),%rbx
  jmp    L19
L58:
  add    $0x4,%r8
  add    $0x4,%r9
  cmp    %rbx,%r9
  je     L29
L12:
  mov    %r8,%rsi
  movl   $0x0,(%r8)
  mov    %r9,%rcx
  mov    %r11,%rax
L17:
  movss  (%rax),%xmm0
  mulss  (%rcx),%xmm0
  addss  (%rsi),%xmm0
  movss  %xmm0,(%rsi)
  add    $0x4,%rax
  add    $0xc,%rcx
  cmp    %r10,%rax
  jne    L17
  jmp    L58
L29:
  add    $0xc,%r11
  add    $0xc,%r10
  add    $0xc,%rdi
  cmp    %rbp,%r10
  je     L26
L19:
  mov    %rdx,%r9
  mov    %rdi,%r8
  jmp    L12
L26:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void RmatMult(float (*A)[3l], float (*B)[3l], float (*C)[3l]) {
  signed int i;
  signed int j;
  signed int k = 0;
  while (k < 3) {
    j = 0;
    while (j < 3) {
      A[(signed long int)k][(signed long int)j] = (float)0.000000;
      i = 0;
      while (i < 3) {
        A[(signed long int)k][(signed long int)j] = A[(signed long int)k][(signed long int)j] + B[(signed long int)k][(signed long int)i] * C[(signed long int)i][(signed long int)j];
        i = i + 1;
      }
      j = j + 1;
    }
    k = k + 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RmatMult>:
  endbr64
  push   %rbx
  lea    0xc(%rsi),%r10
  lea    0x30(%rsi),%rbx
  pxor   %xmm2,%xmm2
  lea    0xc(%rdx),%r11
L4:
  mov    %rdx,%r9
  mov    %rdi,%r8
L15:
  movl   $0x0,(%r8)
  mov    %r9,%rcx
  mov    %rsi,%rax
  movaps %xmm2,%xmm1
L28:
  movss  (%rax),%xmm0
  mulss  (%rcx),%xmm0
  add    $0x4,%rax
  add    $0xc,%rcx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%r8)
  cmp    %r10,%rax
  jne    L28
  add    $0x4,%r9
  add    $0x4,%r8
  cmp    %r11,%r9
  jne    L15
  lea    0xc(%rax),%r10
  add    $0xc,%rsi
  add    $0xc,%rdi
  cmp    %rbx,%r10
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void RmatMult(float (*A)[3l], float (*B)[3l], float (*C)[3l]) {
  signed int i;
  signed int j;
  signed int k = 0;
  while (k < 3) {
    j = 0;
    while (j < 3) {
      A[(signed long int)k][(signed long int)j] = (float)0.000000;
      i = 0;
      while (i < 3) {
        A[(signed long int)k][(signed long int)j] = A[(signed long int)k][(signed long int)j] + B[(signed long int)k][(signed long int)i] * C[(signed long int)i][(signed long int)j];
        i = i + 1;
      }
      j = j + 1;
    }
    k = k + 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_starts_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L11
  mov    $0x0,%eax
  jmp    L29
L11:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L25
  mov    -0x18(%rbp),%rax
  jmp    L29
L25:
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
const char *str_starts_with(const char *const haystack, const char *const needle) {
  const size_t stacklen = strlen(haystack);
  const size_t ndllen = strlen(needle);
  if (stacklen < ndllen)
    return NULL;
  return (memcmp(haystack, needle, ndllen) == 0) ? haystack : NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_starts_with>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%r12
  jb     L1
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %rbx,%rax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *str_starts_with(const char *const haystack, const char *const needle) {
  const size_t stacklen = strlen(haystack);
  const size_t ndllen = strlen(needle);
  if (stacklen < ndllen)
    return NULL;
  return (memcmp(haystack, needle, ndllen) == 0) ? haystack : NULL;
}
```