user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x6f,%edx
  lea    D78(%rip),%rdi
  push   %r13
  lea    D57(%rip),%r13
  push   %r12
  lea    D38(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D99(%rip),%rbx
  mov    %rbx,%rsi
  lea    0x6(%rbx),%r14
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  mov    %dx,0x6(%rsp)
  movl   $0x6c6c6568,0x2(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D63(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D83(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D125(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D108(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x6,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x2(%rsp),%esi
  mov    %r12,%rdi
  mov    %rbp,%rdx
  xor    %eax,%eax
  mov    %esi,%ecx
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x48,%ecx
  mov    %rbp,%rdx
  mov    $0x48,%esi
  xor    %eax,%eax
  movb   $0x48,0x2(%rsp)
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x68,%ecx
  mov    %rbx,%rdx
  mov    $0x68,%esi
  xor    %eax,%eax
  lea    D92(%rip),%r12
  call   <printf@plt>
  mov    $0x68,%ecx
  xor    %eax,%eax
  mov    $0x68,%edx
  mov    $0x68,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  nopl   (%rax)
L12:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%rbp
  cmp    %r14,%rbx
  jne    L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D78
data_type: string
name: unpack_data
arguments: tag: D57
data_type: string
name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D99
data_type: string
name: unpack_data
arguments: tag: D48
data_type: string
name: unpack_data
arguments: tag: D63
data_type: string
name: unpack_data
arguments: tag: D83
data_type: string
name: unpack_data
arguments: tag: D37
data_type: string
name: unpack_data
arguments: tag: D125
data_type: string
name: unpack_data
arguments: tag: D108
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D92
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string

tool: D78: s1=[%s]


tool: D57: s1: [%s] 


tool: D38: %c 	 %20i 	 %c 


tool: D99: hello

tool: D48: s2=[%s]


tool: D63: s3=[%s]


tool: D83: s4=[%s]


tool: D37: s5=[%s]


tool: D125: s6=[%s]


tool: D108: size of s1: %d 


tool: D18: size of s2: %d 


tool: D92: s2: [%s] 


tool: D27: %c 	 %20c 	 %c 


assistant: ```c
int main() {
  char *s1 = "hello";
  char s2[] = "hello";
  char *s3 = s2;
  char **s4 = &s3;
  char **s5 = &s1;
  char(*s6)[6] = &s2;
  printf("s1=[%s]\n", s1);
  printf("s2=[%s]\n", s2);
  printf("s3=[%s]\n", s3);
  printf("s4=[%s]\n", *s4);
  printf("s5=[%s]\n", *s5);
  printf("s6=[%s]\n", s6);
  printf("size of s1: %d \n", sizeof(s1));
  printf("size of s2: %d \n", sizeof(s2));
  printf("%c \t %20i \t %c \n", s3[0], s6[0], *(s6[0]));
  s2[0] = 'H';
  printf("%c \t %20i \t %c \n", s3[0], s6[0], (*s6)[0]);
  printf("%c \t %20i \t %c \n", s1[0], s5[0], *s5[0]);
  printf("%c \t %20c \t %c \n", s1[0], (*s5)[0], *(s5[0]));
  for (int i = 0; i < 6; i++) {
    printf("s1: [%s] \n", s1 + i);
    printf("s2: [%s] \n", s2 + i);
  }
  return 0;
}
```