ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<isEqual>:
  endbr64
  test   %edx,%edx
  jle    L28
  lea    -0x1(%rdx),%eax
  sub    %edi,%esi
  and    $0xfffffffc,%eax
  lea    0x4(%rdi,%rax,1),%r8d
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%edi),%ecx
  cmp    %ecx,(%esi,%edi,1)
  setne  %cl
  add    $0x4,%edi
  movzbl %cl,%ecx
  add    %ecx,%eax
  cmp    %edi,%r8d
  jne    L17
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
L22:
  test   %edx,%edx
  lea    0x3(%rdx),%eax
  pxor   %xmm1,%xmm1
  cmovns %edx,%eax
  sar    $0x2,%eax
  cvtsi2ss %eax,%xmm1
  xor    %eax,%eax
  divss  %xmm1,%xmm0
  movsd  D1(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  comisd %xmm0,%xmm1
  setae  %al
  ret
  nopl   0x0(%rax)
L28:
  pxor   %xmm0,%xmm0
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: label: D1
type: f64

tool: D1: 0.01

assistant: ```c
bool isEqual(unsigned ptr1, unsigned ptr2, int length) {
  int noMatchCount = 0;
  int i;
  for (i = 0; i < length; i = i + 4) {
    unsigned value1 = *(unsigned *)(ptr1 + i);
    unsigned value2 = *(unsigned *)(ptr2 + i);
    if (value1 != value2) {
      noMatchCount++;
    }
  }
  float nomatch_rate = (float)noMatchCount / (float)(length / 4);
  if (nomatch_rate <= 0.01) {
    return true;
  } else
    return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<jb_execvp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L9
  mov    D4(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execvp@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L17
L9:
  mov    $0x0,%eax
  call   <init_wait_cb@plt>
L17:
  nop
  leave
  ret
```

assistant: ```c
void jb_execvp(const char *command, char *const argv[]) {
  if (fork() == 0) {
    errno = 0;
    execvp(command, argv);
    exit(1);
  } else
    init_wait_cb();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jb_execvp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L13
  mov    D9(%rip),%rax
  movq   $0x0,(%rax)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <execvp@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    $0x0,%eax
  call   <init_wait_cb@plt>
  jmp    L9
```

assistant: ```c
void jb_execvp(const char *command, char *const argv[]) {
  if (fork() == 0) {
    errno = 0;
    execvp(command, argv);
    exit(1);
  } else
    init_wait_cb();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jb_execvp>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fork@plt>
  test   %rax,%rax
  jne    L9
  mov    D4(%rip),%rax
  mov    %rbp,%rdi
  mov    %r12,%rsi
  movq   $0x0,(%rax)
  call   <execvp@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    10a0 <exit@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <init_wait_cb@plt>
```

assistant: ```c
void jb_execvp(const char *command, char *const argv[]) {
  if (fork() == 0) {
    errno = 0;
    execvp(command, argv);
    exit(1);
  } else
    init_wait_cb();
}
```
user: Translate the below assembly code into C programming language:

```asm
<jb_execvp>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fork@plt>
  test   %rax,%rax
  jne    L2
  mov    D6(%rip),%rax
  mov    %rbp,%rdi
  mov    %r12,%rsi
  movq   $0x0,(%rax)
  call   <execvp@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    10a0 <exit@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <init_wait_cb@plt>
```

assistant: ```c
void jb_execvp(const char *command, char *const argv[]) {
  if (fork() == 0) {
    errno = 0;
    execvp(command, argv);
    exit(1);
  } else
    init_wait_cb();
}
```
user: Translate the below assembly code into C programming language:

```asm
<Merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L23
L73:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L73
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L30
L87:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L21
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L30
L21:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L30:
  mov    -0xc(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jg     L70
  mov    -0x8(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L87
L70:
  mov    -0x38(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L80
L27:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L80:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Merge(int array[], int tmp[], int start, int middle, int end) {
  int k;
  int current, left, right;
  int remaining;
  for (k = start; k <= end; k++)
    tmp[k] = array[k];
  current = start;
  left = start;
  right = middle + 1;
  while (left <= middle && right <= end)
    if (tmp[left] <= tmp[right])
      array[current++] = tmp[left++];
    else
      array[current++] = tmp[right++];
  remaining = middle - left;
  for (k = 0; k <= remaining; k++)
    array[current + k] = tmp[left + k];
}
```
user: What is the c source code of the assembly code below:

```asm
<Merge>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %ecx,%ebx
  cmp    %r8d,%edx
  jg     L3
  movslq %edx,%rax
L30:
  mov    (%r11,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L30
L3:
  lea    0x1(%rbx),%eax
  cmp    %ebx,%edx
  jg     L9
  cmp    %eax,%r8d
  jl     L9
  lea    0x1(%rdx),%edi
  movslq %edx,%rcx
  lea    (%r11,%rcx,4),%rcx
  jmp    L106
L58:
  add    $0x1,%eax
  mov    %edi,%ebp
  mov    %r9d,(%rcx)
L36:
  add    $0x1,%edi
  add    $0x4,%rcx
  cmp    %ebx,%edx
  jg     L100
  cmp    %r8d,%eax
  jg     L100
L106:
  movslq %edx,%r9
  mov    (%rsi,%r9,4),%r10d
  movslq %eax,%r9
  mov    (%rsi,%r9,4),%r9d
  cmp    %r9d,%r10d
  jg     L58
  add    $0x1,%edx
  mov    %edi,%ebp
  mov    %r10d,(%rcx)
  jmp    L36
L9:
  mov    %edx,%ebp
L100:
  sub    %edx,%ebx
  js     L69
  lea    0x1(%rbx),%ecx
  shl    $0x2,%rcx
  movslq %edx,%rdx
  lea    (%rsi,%rdx,4),%rdi
  movslq %ebp,%rbp
  lea    (%r11,%rbp,4),%rsi
  mov    $0x0,%eax
L33:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L33
L69:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Merge(int array[], int tmp[], int start, int middle, int end) {
  int k;
  int current, left, right;
  int remaining;
  for (k = start; k <= end; k++)
    tmp[k] = array[k];
  current = start;
  left = start;
  right = middle + 1;
  while (left <= middle && right <= end)
    if (tmp[left] <= tmp[right])
      array[current++] = tmp[left++];
    else
      array[current++] = tmp[right++];
  remaining = middle - left;
  for (k = 0; k <= remaining; k++)
    array[current + k] = tmp[left + k];
}
```
user: Translate the below assembly code into C programming language:

```asm
<Merge>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  mov    %ecx,%r11d
  movslq %edx,%rax
  cmp    %r8d,%edx
  jg     L91
  nopl   0x0(%rax,%rax,1)
L56:
  mov    (%r10,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L56
L91:
  lea    0x1(%r11),%edi
  cmp    %r11d,%edx
  jg     L35
  cmp    %edi,%r8d
  lea    0x1(%rdx),%eax
  setge  %cl
  cltq
  test   %cl,%cl
  jne    L44
  jmp    L35
  nopl   0x0(%rax)
L69:
  add    $0x1,%edx
  mov    %ecx,-0x4(%r10,%rax,4)
  add    $0x1,%rax
  cmp    %r11d,%edx
  jg     L19
L3:
  cmp    %r8d,%edi
  jg     L19
L44:
  movslq %edx,%rcx
  movslq %edi,%r9
  movslq %eax,%rbx
  mov    (%rsi,%rcx,4),%ecx
  mov    (%rsi,%r9,4),%r9d
  cmp    %r9d,%ecx
  jle    L69
  mov    %r9d,%ecx
  add    $0x1,%edi
  mov    %ecx,-0x4(%r10,%rax,4)
  add    $0x1,%rax
  cmp    %r11d,%edx
  jle    L3
L19:
  sub    %edx,%r11d
  js     L20
  movslq %r11d,%r11
  movslq %edx,%rdx
  lea    (%r10,%rbx,4),%rcx
  xor    %eax,%eax
  lea    0x4(,%r11,4),%rdi
  lea    (%rsi,%rdx,4),%rsi
  nopl   0x0(%rax)
L0:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L0
L20:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L35:
  movslq %edx,%rbx
  jmp    L19
```

assistant: ```c
void Merge(int array[], int tmp[], int start, int middle, int end) {
  int k;
  int current, left, right;
  int remaining;
  for (k = start; k <= end; k++)
    tmp[k] = array[k];
  current = start;
  left = start;
  right = middle + 1;
  while (left <= middle && right <= end)
    if (tmp[left] <= tmp[right])
      array[current++] = tmp[left++];
    else
      array[current++] = tmp[right++];
  remaining = middle - left;
  for (k = 0; k <= remaining; k++)
    array[current + k] = tmp[left + k];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nsc_enc_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x2c(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  xor    -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L3
L2:
  mov    -0x18(%rbp),%eax
  lea    (%rax,%rax,1),%ebx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  mov    -0x3c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <parity_counter@plt>
  add    %ebx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L2
  mov    -0x14(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int nsc_enc_bit(int state_out_p[], int input, int state_in, int g[], int KK, int nn) {
  int state, i;
  int out_ = 0;
  state = (input << (KK - 1)) ^ state_in;
  for (i = 0; i < nn; i++) {
    out_ = (out_ << 1) + parity_counter(state & g[i], KK);
  }
  state_out_p[0] = state >> 1;
  return (out_);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nsc_enc_bit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rcx,%rax
  lea    -0x1(%r8),%ecx
  shl    %cl,%esi
  xor    %edx,%esi
  mov    %esi,%ebp
  test   %r9d,%r9d
  jle    L14
  mov    %r8d,%r12d
  mov    %rax,%rbx
  lea    -0x1(%r9),%edx
  lea    0x4(%rax,%rdx,4),%r13
  mov    $0x0,%eax
L8:
  lea    (%rax,%rax,1),%r15d
  mov    %ebp,%edi
  and    (%rbx),%edi
  mov    %r12d,%esi
  call   <parity_counter@plt>
  add    %r15d,%eax
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L8
L6:
  sar    %ebp
  mov    %ebp,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  mov    $0x0,%eax
  jmp    L6
```

assistant: ```c
int nsc_enc_bit(int state_out_p[], int input, int state_in, int g[], int KK, int nn) {
  int state, i;
  int out_ = 0;
  state = (input << (KK - 1)) ^ state_in;
  for (i = 0; i < nn; i++) {
    out_ = (out_ << 1) + parity_counter(state & g[i], KK);
  }
  state_out_p[0] = state >> 1;
  return (out_);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nsc_enc_bit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  lea    -0x1(%r8),%ecx
  shl    %cl,%esi
  xor    %edx,%esi
  sub    $0x8,%rsp
  mov    %esi,%ebp
  test   %r9d,%r9d
  jle    L3
  lea    -0x1(%r9),%eax
  mov    %r8d,%r13d
  lea    0x4(%rbx,%rax,4),%r14
  xor    %eax,%eax
  nopl   (%rax)
L15:
  mov    (%rbx),%edi
  mov    %r13d,%esi
  lea    (%rax,%rax,1),%r15d
  add    $0x4,%rbx
  and    %ebp,%edi
  call   <parity_counter@plt>
  add    %r15d,%eax
  cmp    %r14,%rbx
  jne    L15
L28:
  sar    %ebp
  mov    %ebp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  jmp    L28
```

assistant: ```c
int nsc_enc_bit(int state_out_p[], int input, int state_in, int g[], int KK, int nn) {
  int state, i;
  int out_ = 0;
  state = (input << (KK - 1)) ^ state_in;
  for (i = 0; i < nn; i++) {
    out_ = (out_ << 1) + parity_counter(state & g[i], KK);
  }
  state_out_p[0] = state >> 1;
  return (out_);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nsc_enc_bit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  lea    -0x1(%r8),%ecx
  shl    %cl,%esi
  xor    %edx,%esi
  sub    $0x8,%rsp
  mov    %esi,%ebp
  test   %r9d,%r9d
  jle    L17
  lea    -0x1(%r9),%eax
  mov    %r8d,%r13d
  lea    0x4(%rbx,%rax,4),%r14
  xor    %eax,%eax
  nopl   (%rax)
L24:
  mov    (%rbx),%edi
  mov    %r13d,%esi
  lea    (%rax,%rax,1),%r15d
  add    $0x4,%rbx
  and    %ebp,%edi
  call   <parity_counter@plt>
  add    %r15d,%eax
  cmp    %r14,%rbx
  jne    L24
L29:
  sar    %ebp
  mov    %ebp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  jmp    L29
```

assistant: ```c
int nsc_enc_bit(int state_out_p[], int input, int state_in, int g[], int KK, int nn) {
  int state, i;
  int out_ = 0;
  state = (input << (KK - 1)) ^ state_in;
  for (i = 0; i < nn; i++) {
    out_ = (out_ << 1) + parity_counter(state & g[i], KK);
  }
  state_out_p[0] = state >> 1;
  return (out_);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L1
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edi
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <mergeSortedArray@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void mergeSort(int *a, int beg, int end) {
  int mid;
  if (beg < end) {
    mid = (beg + end) / 2;
    mergeSort(a, beg, mid);
    mergeSort(a, mid + 1, end);
    mergeSortedArray(a, beg, mid, mid + 1, end);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mergeSort>:
  endbr64
  cmp    %edx,%esi
  jl     L7
  ret
L7:
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <mergeSort>
  lea    0x1(%r13),%r14d
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <mergeSort>
  mov    %ebp,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <mergeSortedArray@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mergeSort(int *a, int beg, int end) {
  int mid;
  if (beg < end) {
    mid = (beg + end) / 2;
    mergeSort(a, beg, mid);
    mergeSort(a, mid + 1, end);
    mergeSortedArray(a, beg, mid, mid + 1, end);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mergeSort>:
  endbr64
  cmp    %edx,%esi
  jl     L0
  ret
  nopl   0x0(%rax)
L0:
  lea    (%rsi,%rdx,1),%eax
  push   %r14
  push   %r13
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  add    %eax,%r13d
  mov    %esi,%ebp
  push   %rbx
  sar    %r13d
  mov    %edx,%ebx
  lea    0x1(%r13),%r14d
  mov    %r13d,%edx
  call   <mergeSort>
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <mergeSort>
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  pop    %rbx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <mergeSortedArray@plt>
```

assistant: ```c
void mergeSort(int *a, int beg, int end) {
  int mid;
  if (beg < end) {
    mid = (beg + end) / 2;
    mergeSort(a, beg, mid);
    mergeSort(a, mid + 1, end);
    mergeSortedArray(a, beg, mid, mid + 1, end);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<postorderTraversal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L18
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L39
L18:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <treeSize@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L45
  mov    $0x0,%eax
  jmp    L39
L45:
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x2,%ecx
  mov    %rax,%rdi
  call   <walk@plt>
  mov    -0x10(%rbp),%rax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string

tool: D3: Received NULL root

tool: D18: 
Received tree with %d elements


assistant: ```c
int *postorderTraversal(struct TreeNode *root, int *returnSize) {
  int *intarray, ix = 0;
  if (!root) {
    printf("Received NULL root\n");
    return NULL;
  }
  treeSize(root, returnSize);
  printf("\nReceived tree with %d elements\n", *returnSize);
  intarray = (int *)malloc(1 + sizeof(int) * (*returnSize));
  if (intarray == NULL)
    return NULL;
  walk(root, intarray, &ix, 0x2);
  return intarray;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<postorderTraversal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %rdi,%rdi
  je     L15
  mov    %rsi,%rbx
  call   <treeSize@plt>
  mov    (%rbx),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%eax
  lea    0x1(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  mov    $0x0,%ebx
  test   %rax,%rax
  je     L35
  mov    %rax,%rbx
  lea    0x4(%rsp),%rdx
  mov    $0x2,%ecx
  mov    %rbp,%rdi
  call   <walk@plt>
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rbx
  jmp    L35
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string

tool: D5: 
Received tree with %d elements


tool: D13: Received NULL root

assistant: ```c
int *postorderTraversal(struct TreeNode *root, int *returnSize) {
  int *intarray, ix = 0;
  if (!root) {
    printf("Received NULL root\n");
    return NULL;
  }
  treeSize(root, returnSize);
  printf("\nReceived tree with %d elements\n", *returnSize);
  intarray = (int *)malloc(1 + sizeof(int) * (*returnSize));
  if (intarray == NULL)
    return NULL;
  walk(root, intarray, &ix, 0x2);
  return intarray;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<postorderTraversal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %rdi,%rdi
  je     L2
  mov    %rsi,%rbx
  mov    %rdi,%rbp
  xor    %r12d,%r12d
  call   <treeSize@plt>
  mov    (%rbx),%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%eax
  lea    0x1(,%rax,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L37
  lea    0x4(%rsp),%rdx
  mov    $0x2,%ecx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <walk@plt>
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  lea    D2(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L37
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string

tool: D14: 
Received tree with %d elements


tool: D2: Received NULL root

assistant: ```c
int *postorderTraversal(struct TreeNode *root, int *returnSize) {
  int *intarray, ix = 0;
  if (!root) {
    printf("Received NULL root\n");
    return NULL;
  }
  treeSize(root, returnSize);
  printf("\nReceived tree with %d elements\n", *returnSize);
  intarray = (int *)malloc(1 + sizeof(int) * (*returnSize));
  if (intarray == NULL)
    return NULL;
  walk(root, intarray, &ix, 0x2);
  return intarray;
}
```