user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D125(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax)
L33:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  comiss %xmm0,%xmm2
  ja     L33
  mulss  D126(%rip),%xmm0
  xor    %ebp,%ebp
  movss  %xmm0,0x4(%rsp)
  call   <round@plt>
  movss  D120(%rip),%xmm1
  movss  %xmm0,0x4(%rsp)
  comiss %xmm1,%xmm0
  jb     L56
  nopw   0x0(%rax,%rax,1)
L4:
  subss  %xmm1,%xmm0
  add    $0x1,%ebp
  comiss D120(%rip),%xmm0
  jae    L4
  movss  %xmm0,0x4(%rsp)
L56:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D60(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D2(%rip),%xmm1
  comiss %xmm1,%xmm0
  jb     L53
  nopl   0x0(%rax)
L26:
  subss  %xmm1,%xmm0
  add    $0x1,%r12d
  comiss D2(%rip),%xmm0
  jae    L26
  movss  %xmm0,0x4(%rsp)
L53:
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D78(%rip),%rdi
  xor    %ebx,%ebx
  call   <printf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D42(%rip),%xmm1
  comiss %xmm1,%xmm0
  jb     L75
  nopl   (%rax)
L2:
  subss  %xmm1,%xmm0
  add    $0x1,%ebx
  comiss D42(%rip),%xmm0
  jae    L2
  movss  %xmm0,0x4(%rsp)
L75:
  xor    %eax,%eax
  mov    %ebx,%esi
  lea    D58(%rip),%rdi
  xor    %r13d,%r13d
  call   <printf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D7(%rip),%xmm1
  comiss %xmm1,%xmm0
  jb     L27
  nopl   0x0(%rax)
L12:
  subss  %xmm1,%xmm0
  add    $0x1,%r13d
  comiss %xmm1,%xmm0
  jae    L12
  movss  %xmm0,0x4(%rsp)
L27:
  mov    %r13d,%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    (%rbx,%r13,1),%esi
  xor    %eax,%eax
  lea    D73(%rip),%rdi
  add    %r12d,%esi
  add    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D125
datatype: string
name: extract_symbolic_data
arguments: tag: D126
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D120
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D60
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D78
datatype: string
name: extract_symbolic_data
arguments: tag: D42
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D58
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D36
datatype: string
name: extract_symbolic_data
arguments: tag: D73
datatype: string

tool: D3: How much change do you have?

tool: D125: %f

tool: {"D126": [0x00,0x00,0xc8,0x42]}

tool: {"D120": [0x00,0x00,0xc8,0x41]}

tool: D60: Quarters = %i


tool: {"D2": [0x00,0x00,0x20,0x41]}

tool: D78: Dimes = %i


tool: {"D42": [0x00,0x00,0xa0,0x40]}

tool: D58: Nickels = %i


tool: {"D7": [0x00,0x00,0x80,0x3f]}

tool: D36: Pennies = %i


tool: D73: %i


assistant: ```c
int main(void) {
  float f;
  int Q = 0;
  int D = 0;
  int N = 0;
  int P = 0;
  do {
    printf("How much change do you have?\n");
    scanf("%f", &f);
  } while (f < 0);
  f = f * 100;
  f = round(f);
  while (f >= 25) {
    f = f - 25;
    Q++;
  }
  printf("Quarters = %i\n", Q);
  while (f >= 10) {
    f = f - 10;
    D++;
  }
  printf("Dimes = %i\n", D);
  while (f >= 5) {
    f = f - 5;
    N++;
  }
  printf("Nickels = %i\n", N);
  while (f >= 1) {
    f = f - 1;
    P++;
  }
  printf("Pennies = %i\n", P);
  printf("%i\n", P + N + D + Q);
  return 0;
}
```