user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_nothing>:
  endbr64
  push   %r12
  lea    D154(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D83(%rip),%rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    D178(%rip),%rax
  movsd  %xmm0,(%rsp)
  lea    0x18(%rsp),%r12
  lea    0x70(%rsp),%rbp
  mov    %rax,0x18(%rsp)
  mov    D173(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D138(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D21(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D115(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D189(%rip),%rax
  mov    %rax,0x40(%rsp)
  mov    D14(%rip),%rax
  mov    %rax,0x48(%rsp)
  mov    D185(%rip),%rax
  mov    %rax,0x50(%rsp)
  mov    D160(%rip),%rax
  mov    %rax,0x58(%rsp)
  mov    D44(%rip),%rax
  mov    %rax,0x60(%rsp)
  mov    D13(%rip),%rax
  mov    %rax,0x68(%rsp)
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  D39(%rip),%xmm0
  movsd  (%rsp),%xmm2
  jmp    L55
  cs nopw 0x0(%rax,%rax,1)
L28:
  movsd  (%r12),%xmm0
  add    $0x8,%r12
L55:
  movapd %xmm2,%xmm1
  movsd  D137(%rip),%xmm3
  movsd  D156(%rip),%xmm5
  divsd  %xmm0,%xmm1
  andpd  %xmm1,%xmm3
  ucomisd %xmm3,%xmm5
  jbe    L53
  cvttsd2si %xmm1,%rax
  pxor   %xmm3,%xmm3
  movsd  D137(%rip),%xmm4
  andnpd %xmm1,%xmm4
  cvtsi2sd %rax,%xmm3
  orpd   %xmm4,%xmm3
  movapd %xmm3,%xmm1
L53:
  mov    %rbx,%rdi
  mov    $0x2,%eax
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <fmod@plt>
  movapd %xmm0,%xmm2
  cmp    %rbp,%r12
  jne    L28
  comisd D74(%rip),%xmm0
  ja     L22
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L22:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  sub    $0xffffffffffffff80,%rsp
  lea    D129(%rip),%rdi
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1080 <printf@plt>
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D154
data_type: string
name: extract_symbolic_data
arguments: data_tag: D83
data_type: string
name: extract_symbolic_data
arguments: data_tag: D178
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D173
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D138
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D21
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D115
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D189
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D14
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D185
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D160
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D44
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D13
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D39
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D137
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D156
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D74
data_type: f64[2]
name: extract_symbolic_data
arguments: data_tag: D129
data_type: string

tool: D154: Calculating cash notes, amount: %.3f


tool: D83: Real value: %.2f, we'll give you %.0f cash notes


tool: D178: 50

tool: D173: 20

tool: D138: 10

tool: D21: 5

tool: D115: 2

tool: D189: 1

tool: D14: 0.5

tool: D185: 0.25

tool: D160: 0.1

tool: D44: 0.05

tool: D13: 0.01

tool: D39: 100

tool: {"D137": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D156": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D74": [0.001,null]}

tool: D129: 
Ow no, missed %.2f cents... Do you accept a lollipop?



assistant: ```c
void do_nothing(double value) {
  double brazilian_current[12] = {100.0, 50.0, 20.0, 10.0, 5.0, 2.0, 1.0, 0.50, 0.25, 0.10, 0.05, 0.01};
  int array_size = 12;
  printf("Calculating cash notes, amount: %.3f\n", value);
  int i = 0;
  for (; i < array_size; ++i) {
    double base = brazilian_current[i];
    double quotient = trunc(value / base);
    printf("Real value: %.2f, we'll give you %.0f cash notes\n", base, quotient);
    value = fmod(value, base);
  }
  if (value > 0.001) {
    printf("\nOw no, missed %.2f cents... Do you accept a lollipop?\n\n", value);
  }
}
```