ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<qstrunique>:
  endbr64
  push   %r14
  xor    %esi,%esi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x20(%rsp),%rbp
  call   <gettimeofday@plt>
  test   %rbx,%rbx
  mov    0x8(%rsp),%r14
  lea    D18(%rip),%rax
  cmove  %rax,%rbx
  xor    %edi,%edi
  call   <time@plt>
  mov    %rax,%r13
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  push   %rbx
  mov    %r12d,%r8d
  mov    %r13,%r9
  push   %r14
  mov    %eax,%ecx
  lea    D5(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  lea    0x20(%rsp),%r12
  call   <strlen@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <qhashmd5@plt>
  mov    $0x10,%esi
  mov    %r12,%rdi
  call   <qhex_encode@plt>
  pop    %rdx
  pop    %rcx
  mov    0xa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: 

tool: D5: %u%d%lu%ld%s

assistant: ```c
char *qstrunique(const char *seed) {
  long int usec;
  struct timeval tv;
  gettimeofday(&tv, NULL);
  usec = tv.tv_usec;
  char uniquestr[128];
  snprintf(uniquestr, sizeof(uniquestr), "%u%d%lu%ld%s", getpid(), rand(), (unsigned long int)time(NULL), usec, (seed != NULL) ? seed : "");
  unsigned char md5hash[16];
  qhashmd5(uniquestr, strlen(uniquestr), md5hash);
  char *md5ascii = qhex_encode(md5hash, 16);
  return md5ascii;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bmStrstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    %ecx,%esi
  jl     L88
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  sub    %ecx,%r14d
  mov    %rsp,%rdx
  mov    %ecx,%esi
  mov    %rbx,%rdi
  call   <makeBMTable1@plt>
  mov    $0x1,%r8d
  mov    $0xffffffff,%eax
  cmp    %ebp,%r14d
  jge    L4
  jmp    L0
L30:
  lea    -0x1(%rsi),%ecx
  sub    $0x1,%rax
  test   %eax,%eax
  jle    L98
L133:
  mov    %eax,%esi
  mov    %eax,%ecx
  movzbl -0x1(%rdi,%rax,1),%edx
  cmp    %dl,-0x1(%rbx,%rax,1)
  je     L30
  cmp    $0x78,%dl
  je     L30
L98:
  test   %ecx,%ecx
  je     L24
  lea    0x0(%rbp,%rcx,1),%eax
  cltq
  movsbq -0x1(%r13,%rax,1),%rax
  mov    (%rsp,%rax,4),%eax
  test   %eax,%eax
  je     L95
  mov    %r12d,%edx
  sub    %ecx,%edx
  mov    %eax,%ecx
  sub    %edx,%ecx
  cmp    %edx,%eax
  cmovl  %r8d,%ecx
L95:
  add    %ecx,%ebp
  cmp    %ebp,%r14d
  jl     L52
L4:
  movslq %r12d,%rax
  movslq %ebp,%rdi
  add    %r13,%rdi
  mov    %r12d,%ecx
  test   %r12d,%r12d
  jg     L133
  jmp    L98
L88:
  mov    $0xffffffff,%eax
  jmp    L0
L24:
  mov    %ebp,%eax
L0:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L75
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  mov    $0xffffffff,%eax
  jmp    L0
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bmStrstr(char *text, int txtLen, char *pattern, int patLen, int txtIdx) {
  int bmTable[256];
  int patIdx, shtIdx, i1, i2;
  if (0)
    printf("txtIdx = [");
  if (txtLen < patLen) {
    if (0)
      printf("]\n");
    return -1;
  }
  txtLen -= patLen;
  makeBMTable1(pattern, patLen, bmTable);
  while (txtIdx <= txtLen) {
    patIdx = patLen;
    if (0)
      printf("%d, ", txtIdx);
    for (; patIdx > 0; --patIdx)
      if (text[txtIdx + patIdx - 1] != pattern[patIdx - 1] && text[txtIdx + patIdx - 1] != 'x')
        break;
    if (patIdx == 0) {
      if (0)
        printf("]\n");
      return txtIdx;
    }
    i1 = bmTable[text[txtIdx + patIdx - 1]];
    shtIdx = patIdx;
    if (i1) {
      i2 = patLen - patIdx;
      shtIdx = (i1 < i2) ? 1 : i1 - i2;
    }
    txtIdx += shtIdx;
  }
  if (0)
    printf("]\n");
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bmStrstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    %ecx,%esi
  jl     L41
  mov    %esi,%r14d
  mov    %rdx,%rbp
  mov    %rdi,%r12
  mov    %r8d,%ebx
  sub    %ecx,%r14d
  mov    %rsp,%rdx
  mov    %ecx,%esi
  mov    %rbp,%rdi
  mov    %ecx,%r13d
  call   <makeBMTable1@plt>
  cmp    %ebx,%r14d
  jl     L41
  nopw   0x0(%rax,%rax,1)
L82:
  movslq %ebx,%rdi
  movslq %r13d,%rax
  mov    %r13d,%ecx
  add    %r12,%rdi
  test   %r13d,%r13d
  jle    L5
  nopl   0x0(%rax)
L111:
  movsbq -0x1(%rdi,%rax,1),%rdx
  mov    %eax,%esi
  mov    %eax,%ecx
  lea    (%rbx,%rax,1),%r8d
  cmp    %dl,-0x1(%rbp,%rax,1)
  je     L25
  cmp    $0x78,%dl
  jne    L31
L25:
  sub    $0x1,%rax
  lea    -0x1(%rsi),%ecx
  test   %eax,%eax
  jg     L111
L5:
  test   %ecx,%ecx
  je     L46
  lea    (%rcx,%rbx,1),%r8d
  movslq %r8d,%rax
  movsbq -0x1(%r12,%rax,1),%rdx
L31:
  mov    (%rsp,%rdx,4),%eax
  test   %eax,%eax
  je     L88
  mov    %r13d,%esi
  mov    %eax,%edx
  sub    %ecx,%esi
  lea    0x1(%rbx),%ecx
  sub    %esi,%edx
  add    %ebx,%edx
  cmp    %esi,%eax
  mov    %ecx,%ebx
  cmovge %edx,%ebx
L6:
  cmp    %ebx,%r14d
  jge    L82
L41:
  mov    $0xffffffff,%eax
L20:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L88:
  mov    %r8d,%ebx
  jmp    L6
L46:
  mov    %ebx,%eax
  jmp    L20
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bmStrstr(char *text, int txtLen, char *pattern, int patLen, int txtIdx) {
  int bmTable[256];
  int patIdx, shtIdx, i1, i2;
  if (0)
    printf("txtIdx = [");
  if (txtLen < patLen) {
    if (0)
      printf("]\n");
    return -1;
  }
  txtLen -= patLen;
  makeBMTable1(pattern, patLen, bmTable);
  while (txtIdx <= txtLen) {
    patIdx = patLen;
    if (0)
      printf("%d, ", txtIdx);
    for (; patIdx > 0; --patIdx)
      if (text[txtIdx + patIdx - 1] != pattern[patIdx - 1] && text[txtIdx + patIdx - 1] != 'x')
        break;
    if (patIdx == 0) {
      if (0)
        printf("]\n");
      return txtIdx;
    }
    i1 = bmTable[text[txtIdx + patIdx - 1]];
    shtIdx = patIdx;
    if (i1) {
      i2 = patLen - patIdx;
      shtIdx = (i1 < i2) ? 1 : i1 - i2;
    }
    txtIdx += shtIdx;
  }
  if (0)
    printf("]\n");
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bmStrstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    %ecx,%esi
  jl     L101
  mov    %esi,%r14d
  mov    %rdx,%rbp
  mov    %rdi,%r12
  mov    %r8d,%ebx
  sub    %ecx,%r14d
  mov    %rsp,%rdx
  mov    %ecx,%esi
  mov    %rbp,%rdi
  mov    %ecx,%r13d
  call   <makeBMTable1@plt>
  cmp    %ebx,%r14d
  jl     L101
  nopw   0x0(%rax,%rax,1)
L112:
  movslq %ebx,%rdi
  movslq %r13d,%rax
  mov    %r13d,%ecx
  add    %r12,%rdi
  test   %r13d,%r13d
  jle    L78
  nopl   0x0(%rax)
L74:
  movsbq -0x1(%rdi,%rax,1),%rdx
  mov    %eax,%esi
  mov    %eax,%ecx
  lea    (%rbx,%rax,1),%r8d
  cmp    %dl,-0x1(%rbp,%rax,1)
  je     L118
  cmp    $0x78,%dl
  jne    L52
L118:
  sub    $0x1,%rax
  lea    -0x1(%rsi),%ecx
  test   %eax,%eax
  jg     L74
L78:
  test   %ecx,%ecx
  je     L88
  lea    (%rcx,%rbx,1),%r8d
  movslq %r8d,%rax
  movsbq -0x1(%r12,%rax,1),%rdx
L52:
  mov    (%rsp,%rdx,4),%eax
  test   %eax,%eax
  je     L41
  mov    %r13d,%esi
  mov    %eax,%edx
  sub    %ecx,%esi
  lea    0x1(%rbx),%ecx
  sub    %esi,%edx
  add    %ebx,%edx
  cmp    %esi,%eax
  mov    %ecx,%ebx
  cmovge %edx,%ebx
L98:
  cmp    %ebx,%r14d
  jge    L112
L101:
  mov    $0xffffffff,%eax
L34:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L41:
  mov    %r8d,%ebx
  jmp    L98
L88:
  mov    %ebx,%eax
  jmp    L34
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bmStrstr(char *text, int txtLen, char *pattern, int patLen, int txtIdx) {
  int bmTable[256];
  int patIdx, shtIdx, i1, i2;
  if (0)
    printf("txtIdx = [");
  if (txtLen < patLen) {
    if (0)
      printf("]\n");
    return -1;
  }
  txtLen -= patLen;
  makeBMTable1(pattern, patLen, bmTable);
  while (txtIdx <= txtLen) {
    patIdx = patLen;
    if (0)
      printf("%d, ", txtIdx);
    for (; patIdx > 0; --patIdx)
      if (text[txtIdx + patIdx - 1] != pattern[patIdx - 1] && text[txtIdx + patIdx - 1] != 'x')
        break;
    if (patIdx == 0) {
      if (0)
        printf("]\n");
      return txtIdx;
    }
    i1 = bmTable[text[txtIdx + patIdx - 1]];
    shtIdx = patIdx;
    if (i1) {
      i2 = patLen - patIdx;
      shtIdx = (i1 < i2) ? 1 : i1 - i2;
    }
    txtIdx += shtIdx;
  }
  if (0)
    printf("]\n");
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<remove_nl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <index@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L3:
  nop
  leave
  ret
```

assistant: ```c
remove_nl(char *s) {
  char *p;
  if ((p = index(s, '\n')) != NULL)
    *p = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<remove_nl>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <index@plt>
  test   %rax,%rax
  je     L3
  movb   $0x0,(%rax)
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
remove_nl(char *s) {
  char *p;
  if ((p = index(s, '\n')) != NULL)
    *p = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<remove_nl>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <index@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
L9:
  add    $0x8,%rsp
  ret
```

assistant: ```c
remove_nl(char *s) {
  char *p;
  if ((p = index(s, '\n')) != NULL)
    *p = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_nl>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <index@plt>
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax)
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
remove_nl(char *s) {
  char *p;
  if ((p = index(s, '\n')) != NULL)
    *p = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<is_excluded>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jg     L124
  mov    $0x0,%eax
  jmp    L20
L133:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jg     L124
  mov    $0x0,%eax
  jmp    L20
L124:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jg     L133
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  je     L38
  mov    $0x0,%eax
  jmp    L20
L18:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jg     L95
  mov    $0x0,%eax
  jmp    L20
L95:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  je     L38
  mov    $0x0,%eax
  jmp    L20
L38:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x4,%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jg     L18
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x4,%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L127
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L127
  mov    $0x1,%eax
  jmp    L20
L127:
  mov    $0x0,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int is_excluded(long *exclude, long i0, long i1, long *iex, long nexclude) {
  if (*iex >= nexclude)
    return 0;
  while (exclude[2 * (*iex)] < i0) {
    (*iex)++;
    if (*iex >= nexclude)
      return 0;
  }
  if (exclude[2 * (*iex)] != i0)
    return 0;
  while (exclude[2 * (*iex) + 1] < i1) {
    (*iex)++;
    if (*iex >= nexclude)
      return 0;
    if (exclude[2 * (*iex)] != i0)
      return 0;
  }
  return ((exclude[2 * (*iex) + 1] == i1) && (exclude[2 * (*iex)] == i0));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_excluded>:
  endbr64
  mov    %rdx,%r9
  mov    %rcx,%rdx
  mov    $0x0,%eax
  cmp    %r8,(%rcx)
  jge    L65
L39:
  mov    (%rdx),%rax
  mov    %rax,%rcx
  shl    $0x4,%rcx
  mov    (%rdi,%rcx,1),%rcx
  cmp    %rsi,%rcx
  jge    L28
  add    $0x1,%rax
  mov    %rax,(%rdx)
  cmp    %r8,%rax
  jl     L39
  mov    $0x0,%eax
  ret
L65:
  ret
L28:
  mov    $0x0,%eax
  jne    L14
L33:
  mov    (%rdx),%rax
  mov    %rax,%rcx
  shl    $0x4,%rcx
  mov    0x8(%rdi,%rcx,1),%r10
  cmp    %r9,%r10
  jge    L64
  add    $0x1,%rax
  mov    %rax,(%rdx)
  cmp    %r8,%rax
  jge    L71
  cmp    %rsi,0x10(%rdi,%rcx,1)
  je     L33
  mov    $0x0,%eax
L14:
  ret
L64:
  mov    $0x0,%eax
  jne    L14
  cmp    %rsi,(%rdi,%rcx,1)
  sete   %al
  movzbl %al,%eax
  ret
L71:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_excluded(long *exclude, long i0, long i1, long *iex, long nexclude) {
  if (*iex >= nexclude)
    return 0;
  while (exclude[2 * (*iex)] < i0) {
    (*iex)++;
    if (*iex >= nexclude)
      return 0;
  }
  if (exclude[2 * (*iex)] != i0)
    return 0;
  while (exclude[2 * (*iex) + 1] < i1) {
    (*iex)++;
    if (*iex >= nexclude)
      return 0;
    if (exclude[2 * (*iex)] != i0)
      return 0;
  }
  return ((exclude[2 * (*iex) + 1] == i1) && (exclude[2 * (*iex)] == i0));
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_excluded>:
  endbr64
  mov    (%rcx),%rax
  mov    %rdi,%r9
  cmp    %r8,%rax
  jl     L20
  jmp    L103
  nopl   0x0(%rax)
L43:
  add    $0x1,%rax
  mov    %rax,(%rcx)
  cmp    %r8,%rax
  je     L103
L20:
  mov    %rax,%rdi
  shl    $0x4,%rdi
  cmp    %rsi,(%r9,%rdi,1)
  jl     L43
  je     L5
  nopl   0x0(%rax,%rax,1)
L103:
  xor    %eax,%eax
L66:
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%rax
  mov    %rax,(%rcx)
  cmp    %r8,%rax
  jge    L103
  add    $0x10,%rdi
  cmp    %rsi,(%r9,%rdi,1)
  jne    L103
L5:
  cmp    %rdx,0x8(%r9,%rdi,1)
  jl     L28
  jne    L103
  mov    $0x1,%eax
  cmp    %rsi,(%r9,%rdi,1)
  je     L66
  xor    %eax,%eax
  jmp    L66
```

assistant: ```c
int is_excluded(long *exclude, long i0, long i1, long *iex, long nexclude) {
  if (*iex >= nexclude)
    return 0;
  while (exclude[2 * (*iex)] < i0) {
    (*iex)++;
    if (*iex >= nexclude)
      return 0;
  }
  if (exclude[2 * (*iex)] != i0)
    return 0;
  while (exclude[2 * (*iex) + 1] < i1) {
    (*iex)++;
    if (*iex >= nexclude)
      return 0;
    if (exclude[2 * (*iex)] != i0)
      return 0;
  }
  return ((exclude[2 * (*iex) + 1] == i1) && (exclude[2 * (*iex)] == i0));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_excluded>:
  endbr64
  mov    (%rcx),%rax
  mov    %rsi,%r9
  cmp    %r8,%rax
  jl     L32
  jmp    L80
  nopl   0x0(%rax)
L15:
  add    $0x1,%rax
  mov    %rax,(%rcx)
  cmp    %r8,%rax
  je     L80
L32:
  mov    %rax,%rsi
  shl    $0x4,%rsi
  cmp    %r9,(%rdi,%rsi,1)
  jl     L15
  jne    L80
  add    $0x1,%rax
  add    %rsi,%rdi
  jmp    L52
  nopl   0x0(%rax)
L36:
  mov    %rax,(%rcx)
  cmp    %r8,%rax
  jge    L80
  add    $0x1,%rax
  add    $0x10,%rdi
  cmp    %r9,0x10(%rsi)
  jne    L80
L52:
  mov    %rdi,%rsi
  cmp    %rdx,0x8(%rdi)
  jl     L36
  mov    $0x1,%eax
  je     L30
  cs nopw 0x0(%rax,%rax,1)
L80:
  xor    %eax,%eax
L30:
  ret
```

assistant: ```c
int is_excluded(long *exclude, long i0, long i1, long *iex, long nexclude) {
  if (*iex >= nexclude)
    return 0;
  while (exclude[2 * (*iex)] < i0) {
    (*iex)++;
    if (*iex >= nexclude)
      return 0;
  }
  if (exclude[2 * (*iex)] != i0)
    return 0;
  while (exclude[2 * (*iex) + 1] < i1) {
    (*iex)++;
    if (*iex >= nexclude)
      return 0;
    if (exclude[2 * (*iex)] != i0)
      return 0;
  }
  return ((exclude[2 * (*iex) + 1] == i1) && (exclude[2 * (*iex)] == i0));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sdb_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x8(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int sdb_integer(int n, char **p, void *closure) {
  int *i = (int *)closure;
  *i = atoi(p[0]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sdb_integer>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    (%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int sdb_integer(int n, char **p, void *closure) {
  int *i = (int *)closure;
  *i = atoi(p[0]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sdb_integer>:
  endbr64
  push   %rbx
  mov    (%rsi),%rdi
  mov    %rdx,%rbx
  call   <atoi@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int sdb_integer(int n, char **p, void *closure) {
  int *i = (int *)closure;
  *i = atoi(p[0]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sdb_integer>:
  endbr64
  push   %rbx
  mov    (%rsi),%rdi
  mov    %rdx,%rbx
  call   <atoi@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int sdb_integer(int n, char **p, void *closure) {
  int *i = (int *)closure;
  *i = atoi(p[0]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rastafont8x8_blit8>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    $0x1f,%ecx
  sub    %r13d,%ecx
  shl    %cl,%edx
  sar    $0x1f,%edx
  mov    (%rdi),%edi
  call   <rastafont8x8_select@plt>
  mov    %eax,(%rbx)
  mov    $0x1e,%ecx
  sub    %r13d,%ecx
  mov    %ebp,%edx
  shl    %cl,%edx
  sar    $0x1f,%edx
  mov    0x4(%rbx),%edi
  mov    %r12d,%esi
  call   <rastafont8x8_select@plt>
  mov    %eax,0x4(%rbx)
  mov    $0x1d,%ecx
  sub    %r13d,%ecx
  mov    %ebp,%edx
  shl    %cl,%edx
  sar    $0x1f,%edx
  mov    0x8(%rbx),%edi
  mov    %r12d,%esi
  call   <rastafont8x8_select@plt>
  mov    %eax,0x8(%rbx)
  mov    $0x1c,%ecx
  sub    %r13d,%ecx
  mov    %ebp,%edx
  shl    %cl,%edx
  sar    $0x1f,%edx
  mov    0xc(%rbx),%edi
  mov    %r12d,%esi
  call   <rastafont8x8_select@plt>
  mov    %eax,0xc(%rbx)
  mov    $0x1b,%ecx
  sub    %r13d,%ecx
  mov    %ebp,%edx
  shl    %cl,%edx
  sar    $0x1f,%edx
  mov    0x10(%rbx),%edi
  mov    %r12d,%esi
  call   <rastafont8x8_select@plt>
  mov    %eax,0x10(%rbx)
  mov    $0x1a,%ecx
  sub    %r13d,%ecx
  mov    %ebp,%edx
  shl    %cl,%edx
  sar    $0x1f,%edx
  mov    0x14(%rbx),%edi
  mov    %r12d,%esi
  call   <rastafont8x8_select@plt>
  mov    %eax,0x14(%rbx)
  mov    $0x19,%ecx
  sub    %r13d,%ecx
  mov    %ebp,%edx
  shl    %cl,%edx
  sar    $0x1f,%edx
  mov    0x18(%rbx),%edi
  mov    %r12d,%esi
  call   <rastafont8x8_select@plt>
  mov    %eax,0x18(%rbx)
  mov    $0x18,%ecx
  sub    %r13d,%ecx
  mov    %ebp,%edx
  shl    %cl,%edx
  sar    $0x1f,%edx
  mov    0x1c(%rbx),%edi
  mov    %r12d,%esi
  call   <rastafont8x8_select@plt>
  mov    %eax,0x1c(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((always_)) void rastafont8x8_blit8(unsigned *output, unsigned colour, unsigned m, unsigned b) {
  output[0] = rastafont8x8_select(output[0], colour, (int)(m << (31 - b)) >> 31);
  output[1] = rastafont8x8_select(output[1], colour, (int)(m << (30 - b)) >> 31);
  output[2] = rastafont8x8_select(output[2], colour, (int)(m << (29 - b)) >> 31);
  output[3] = rastafont8x8_select(output[3], colour, (int)(m << (28 - b)) >> 31);
  output[4] = rastafont8x8_select(output[4], colour, (int)(m << (27 - b)) >> 31);
  output[5] = rastafont8x8_select(output[5], colour, (int)(m << (26 - b)) >> 31);
  output[6] = rastafont8x8_select(output[6], colour, (int)(m << (25 - b)) >> 31);
  output[7] = rastafont8x8_select(output[7], colour, (int)(m << (24 - b)) >> 31);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rastafont8x8_blit8>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  mov    $0x1f,%ecx
  push   %r12
  sub    %r13d,%ecx
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  shl    %cl,%edx
  push   %rbx
  mov    %rdi,%rbx
  sar    $0x1f,%edx
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <rastafont8x8_select@plt>
  mov    $0x1e,%ecx
  mov    %ebp,%edx
  mov    0x4(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x1d,%ecx
  mov    %ebp,%edx
  mov    0x8(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x4(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x1c,%ecx
  mov    %ebp,%edx
  mov    0xc(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x8(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x1b,%ecx
  mov    %ebp,%edx
  mov    0x10(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0xc(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x1a,%ecx
  mov    %ebp,%edx
  mov    0x14(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x10(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x19,%ecx
  mov    %ebp,%edx
  mov    0x18(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x14(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x18,%ecx
  mov    %ebp,%edx
  mov    0x1c(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x18(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    %eax,0x1c(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((always_)) void rastafont8x8_blit8(unsigned *output, unsigned colour, unsigned m, unsigned b) {
  output[0] = rastafont8x8_select(output[0], colour, (int)(m << (31 - b)) >> 31);
  output[1] = rastafont8x8_select(output[1], colour, (int)(m << (30 - b)) >> 31);
  output[2] = rastafont8x8_select(output[2], colour, (int)(m << (29 - b)) >> 31);
  output[3] = rastafont8x8_select(output[3], colour, (int)(m << (28 - b)) >> 31);
  output[4] = rastafont8x8_select(output[4], colour, (int)(m << (27 - b)) >> 31);
  output[5] = rastafont8x8_select(output[5], colour, (int)(m << (26 - b)) >> 31);
  output[6] = rastafont8x8_select(output[6], colour, (int)(m << (25 - b)) >> 31);
  output[7] = rastafont8x8_select(output[7], colour, (int)(m << (24 - b)) >> 31);
}
```