ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sortedSquares>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,(%rdx)
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  lea    -0x1(%rbx),%ecx
  mov    0x0(%rbp),%esi
  imul   %esi,%esi
  movslq %ecx,%rdx
  lea    0x0(,%rdx,4),%rax
  mov    0x0(%rbp,%rdx,4),%edx
  imul   %edx,%edx
  test   %ecx,%ecx
  js     L2
  add    %r8,%rax
  mov    $0x0,%edi
  jmp    L20
L33:
  mov    %edx,(%rax)
  sub    $0x1,%ecx
  js     L21
  movslq %ecx,%rdx
  mov    0x0(%rbp,%rdx,4),%edx
  imul   %edx,%edx
L21:
  sub    $0x4,%rax
  cmp    %ecx,%edi
  jg     L2
L20:
  cmp    %edx,%esi
  jle    L33
  mov    %esi,(%rax)
  add    $0x1,%edi
  cmp    %edi,%ebx
  jle    L21
  movslq %edi,%rsi
  mov    0x0(%rbp,%rsi,4),%esi
  imul   %esi,%esi
  jmp    L21
L2:
  mov    %r8,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *sortedSquares(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *returnA = (int *)malloc(sizeof(int) * ASize);
  int l = 0, r = ASize - 1;
  int i = A[l] * A[l], j = A[r] * A[r], k = ASize - 1;
  while (l <= r) {
    if (i > j) {
      returnA[k--] = i;
      l++;
      if (l < ASize) {
        i = A[l] * A[l];
      }
    } else {
      returnA[k--] = j;
      r--;
      if (r >= 0) {
        j = A[r] * A[r];
      }
    }
  }
  return returnA;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sortedSquares>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,4),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    %esi,(%rdx)
  call   <malloc@plt>
  lea    -0x1(%rbx),%ecx
  mov    0x0(%rbp),%edi
  movslq %ecx,%rsi
  mov    0x0(%rbp,%rsi,4),%edx
  imul   %edi,%edi
  lea    (%rax,%rsi,4),%rsi
  imul   %edx,%edx
  test   %ecx,%ecx
  js     L51
  xor    %r8d,%r8d
  jmp    L9
  nopl   (%rax)
L42:
  add    $0x1,%r8d
  mov    %edi,(%rsi)
  cmp    %r8d,%ebx
  jle    L5
  movslq %r8d,%rdi
  mov    0x0(%rbp,%rdi,4),%edi
  imul   %edi,%edi
L5:
  sub    $0x4,%rsi
  cmp    %r8d,%ecx
  jl     L51
L9:
  cmp    %edi,%edx
  jl     L42
  mov    %edx,(%rsi)
  sub    $0x1,%ecx
  js     L5
  movslq %ecx,%rdx
  sub    $0x4,%rsi
  mov    0x0(%rbp,%rdx,4),%edx
  imul   %edx,%edx
  cmp    %r8d,%ecx
  jge    L9
L51:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *sortedSquares(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *returnA = (int *)malloc(sizeof(int) * ASize);
  int l = 0, r = ASize - 1;
  int i = A[l] * A[l], j = A[r] * A[r], k = ASize - 1;
  while (l <= r) {
    if (i > j) {
      returnA[k--] = i;
      l++;
      if (l < ASize) {
        i = A[l] * A[l];
      }
    } else {
      returnA[k--] = j;
      r--;
      if (r >= 0) {
        j = A[r] * A[r];
      }
    }
  }
  return returnA;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sortedSquares>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,4),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    %esi,(%rdx)
  call   <malloc@plt>
  lea    -0x1(%rbx),%ecx
  mov    0x0(%rbp),%edi
  movslq %ecx,%rsi
  mov    0x0(%rbp,%rsi,4),%edx
  imul   %edi,%edi
  lea    (%rax,%rsi,4),%rsi
  imul   %edx,%edx
  test   %ecx,%ecx
  js     L30
  xor    %r8d,%r8d
  jmp    L21
  nopl   (%rax)
L25:
  add    $0x1,%r8d
  mov    %edi,(%rsi)
  cmp    %r8d,%ebx
  jle    L35
  movslq %r8d,%rdi
  mov    0x0(%rbp,%rdi,4),%edi
  imul   %edi,%edi
L35:
  sub    $0x4,%rsi
  cmp    %r8d,%ecx
  jl     L30
L21:
  cmp    %edi,%edx
  jl     L25
  mov    %edx,(%rsi)
  sub    $0x1,%ecx
  js     L35
  movslq %ecx,%rdx
  sub    $0x4,%rsi
  mov    0x0(%rbp,%rdx,4),%edx
  imul   %edx,%edx
  cmp    %r8d,%ecx
  jge    L21
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *sortedSquares(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *returnA = (int *)malloc(sizeof(int) * ASize);
  int l = 0, r = ASize - 1;
  int i = A[l] * A[l], j = A[r] * A[r], k = ASize - 1;
  while (l <= r) {
    if (i > j) {
      returnA[k--] = i;
      l++;
      if (l < ASize) {
        i = A[l] * A[l];
      }
    } else {
      returnA[k--] = j;
      r--;
      if (r >= 0) {
        j = A[r] * A[r];
      }
    }
  }
  return returnA;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<chirp_client_stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %rdx,-0x438(%rbp)
  mov    %ecx,-0x43c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rcx
  mov    -0x430(%rbp),%rax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <url_encode@plt>
  lea    -0x410(%rbp),%rdx
  mov    -0x43c(%rbp),%esi
  mov    -0x428(%rbp),%rax
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  mov    %rax,%rdi
  call   <simple_command@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  js     L11
  mov    -0x43c(%rbp),%ecx
  mov    -0x438(%rbp),%rdx
  mov    -0x430(%rbp),%rsi
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <get_stat_result@plt>
  mov    %rax,-0x418(%rbp)
L11:
  mov    -0x418(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: stat %s


assistant: ```c
int64_t chirp_client_stat(struct chirp_client *c, const char *path, struct chirp_stat *info, time_t stoptime) {
  char safepath[1024];
  url_encode(path, safepath, sizeof(safepath));
  int64_t result = simple_command(c, stoptime, "stat %s\n", safepath);
  if (result >= 0)
    result = get_stat_result(c, path, info, stoptime);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chirp_client_stat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    $0x400,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <url_encode@plt>
  mov    %r14,%rcx
  lea    D3(%rip),%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <simple_command@plt>
  test   %rax,%rax
  jns    L20
L7:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <get_stat_result@plt>
  jmp    L7
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: stat %s


assistant: ```c
int64_t chirp_client_stat(struct chirp_client *c, const char *path, struct chirp_stat *info, time_t stoptime) {
  char safepath[1024];
  url_encode(path, safepath, sizeof(safepath));
  int64_t result = simple_command(c, stoptime, "stat %s\n", safepath);
  if (result >= 0)
    result = get_stat_result(c, path, info, stoptime);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<chirp_client_stat>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  mov    $0x400,%edx
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    %r15,%rsi
  call   <url_encode@plt>
  mov    %r15,%rcx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  lea    D9(%rip),%rdx
  call   <simple_command@plt>
  test   %rax,%rax
  js     L7
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <get_stat_result@plt>
L7:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: stat %s


assistant: ```c
int64_t chirp_client_stat(struct chirp_client *c, const char *path, struct chirp_stat *info, time_t stoptime) {
  char safepath[1024];
  url_encode(path, safepath, sizeof(safepath));
  int64_t result = simple_command(c, stoptime, "stat %s\n", safepath);
  if (result >= 0)
    result = get_stat_result(c, path, info, stoptime);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chirp_client_stat>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  mov    $0x400,%edx
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    %r15,%rsi
  call   <url_encode@plt>
  mov    %r15,%rcx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  lea    D9(%rip),%rdx
  call   <simple_command@plt>
  test   %rax,%rax
  js     L12
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <get_stat_result@plt>
L12:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: stat %s


assistant: ```c
int64_t chirp_client_stat(struct chirp_client *c, const char *path, struct chirp_stat *info, time_t stoptime) {
  char safepath[1024];
  url_encode(path, safepath, sizeof(safepath));
  int64_t result = simple_command(c, stoptime, "stat %s\n", safepath);
  if (result >= 0)
    result = get_stat_result(c, path, info, stoptime);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gang_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <clear@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L12
L32:
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L5:
  mov    -0x18(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <place@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L8:
  cmpl   $0x3f,-0x14(%rbp)
  jle    L5
  addl   $0x1,-0x18(%rbp)
L12:
  mov    -0x2c(%rbp),%eax
  lea    0x3f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x6,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L32
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <check@plt>
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int gang_3(int *ary, int size) {
  clear(ary, size);
#pragma acc parallel num_workers(32) vector_length(32) copy(ary [0:size]) firstprivate(size)
  {
#pragma acc loop auto
    for (int jx = 0; jx < size / 64; jx++)
#pragma acc loop auto
      for (int ix = 0; ix < 64; ix++)
        ary[ix + jx * 64] = place();
  }
  return check(ary, size, 1, 0, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gang_3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r14d
  call   <clear@plt>
  lea    0x3f(%r14),%r13d
  test   %r14d,%r14d
  cmovns %r14d,%r13d
  sar    $0x6,%r13d
  cmp    $0x3f,%r14d
  jle    L26
  lea    0x100(%r15),%rbp
  mov    $0x0,%r12d
L18:
  lea    -0x100(%rbp),%rbx
L25:
  mov    $0x0,%eax
  call   <place@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L25
  add    $0x1,%r12d
  add    $0x100,%rbp
  cmp    %r13d,%r12d
  jl     L18
L26:
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <check@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int gang_3(int *ary, int size) {
  clear(ary, size);
#pragma acc parallel num_workers(32) vector_length(32) copy(ary [0:size]) firstprivate(size)
  {
#pragma acc loop auto
    for (int jx = 0; jx < size / 64; jx++)
#pragma acc loop auto
      for (int ix = 0; ix < 64; ix++)
        ary[ix + jx * 64] = place();
  }
  return check(ary, size, 1, 0, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gang_3>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    0x3f(%r14),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <clear@plt>
  test   %r14d,%r14d
  cmovns %r14d,%r13d
  sar    $0x6,%r13d
  cmp    $0x3f,%r14d
  jle    L13
  lea    0x100(%r15),%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L24:
  lea    -0x100(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <place@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L14
  add    $0x1,%r12d
  add    $0x100,%rbp
  cmp    %r12d,%r13d
  jg     L24
L13:
  add    $0x8,%rsp
  mov    %r14d,%esi
  mov    %r15,%rdi
  mov    $0x1,%r8d
  pop    %rbx
  xor    %ecx,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <check@plt>
```

assistant: ```c
int gang_3(int *ary, int size) {
  clear(ary, size);
#pragma acc parallel num_workers(32) vector_length(32) copy(ary [0:size]) firstprivate(size)
  {
#pragma acc loop auto
    for (int jx = 0; jx < size / 64; jx++)
#pragma acc loop auto
      for (int ix = 0; ix < 64; ix++)
        ary[ix + jx * 64] = place();
  }
  return check(ary, size, 1, 0, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gang_3>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    0x3f(%r14),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <clear@plt>
  test   %r14d,%r14d
  cmovns %r14d,%r13d
  sar    $0x6,%r13d
  cmp    $0x3f,%r14d
  jle    L29
  lea    0x100(%r15),%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L5:
  lea    -0x100(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <place@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L1
  add    $0x1,%r12d
  add    $0x100,%rbp
  cmp    %r12d,%r13d
  jg     L5
L29:
  add    $0x8,%rsp
  mov    %r14d,%esi
  mov    %r15,%rdi
  mov    $0x1,%r8d
  pop    %rbx
  xor    %ecx,%ecx
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <check@plt>
```

assistant: ```c
int gang_3(int *ary, int size) {
  clear(ary, size);
#pragma acc parallel num_workers(32) vector_length(32) copy(ary [0:size]) firstprivate(size)
  {
#pragma acc loop auto
    for (int jx = 0; jx < size / 64; jx++)
#pragma acc loop auto
      for (int ix = 0; ix < 64; ix++)
        ary[ix + jx * 64] = place();
  }
  return check(ary, size, 1, 0, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getnbyte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L18:
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getnbyte(unsigned char *pnt, int nbytes) {
  unsigned int result = 0;
  int i;
  for (i = 0; i < nbytes; i++)
    result = (result << 8) | (pnt[i] & 0xff);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<getnbyte>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x0,%eax
L16:
  shl    $0x8,%eax
  movzbl (%rdx),%ecx
  or     %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L16
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int getnbyte(unsigned char *pnt, int nbytes) {
  unsigned int result = 0;
  int i;
  for (i = 0; i < nbytes; i++)
    result = (result << 8) | (pnt[i] & 0xff);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getnbyte>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    $0x1,%rdi
  or     %edx,%eax
  cmp    %rcx,%rdi
  jne    L8
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int getnbyte(unsigned char *pnt, int nbytes) {
  unsigned int result = 0;
  int i;
  for (i = 0; i < nbytes; i++)
    result = (result << 8) | (pnt[i] & 0xff);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getnbyte>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    $0x1,%rdi
  or     %edx,%eax
  cmp    %rdi,%rcx
  jne    L2
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int getnbyte(unsigned char *pnt, int nbytes) {
  unsigned int result = 0;
  int i;
  for (i = 0; i < nbytes; i++)
    result = (result << 8) | (pnt[i] & 0xff);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_mpyhir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %ax,-0xa(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  movswq -0xa(%rbp),%rax
  imul   %rdx,%rax
  add    $0x4000,%rax
  mov    %rax,-0x8(%rbp)
  sarq   $0xf,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int _mpyhir(int src1, int src2) {
  short s1 = src1 >> 16;
  long long result = ((long long)src2) * s1 + (1 << 14);
  result >>= 15;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_mpyhir>:
  endbr64
  sar    $0x10,%edi
  movswq %di,%rdi
  movslq %esi,%rsi
  imul   %rsi,%rdi
  lea    0x4000(%rdi),%rax
  sar    $0xf,%rax
  ret
```

assistant: ```c
int _mpyhir(int src1, int src2) {
  short s1 = src1 >> 16;
  long long result = ((long long)src2) * s1 + (1 << 14);
  result >>= 15;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_mpyhir>:
  endbr64
  sar    $0x10,%edi
  movslq %esi,%rsi
  movslq %edi,%rdi
  imul   %rsi,%rdi
  lea    0x4000(%rdi),%rax
  sar    $0xf,%rax
  ret
```

assistant: ```c
int _mpyhir(int src1, int src2) {
  short s1 = src1 >> 16;
  long long result = ((long long)src2) * s1 + (1 << 14);
  result >>= 15;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<_mpyhir>:
  endbr64
  sar    $0x10,%edi
  movslq %esi,%rsi
  movslq %edi,%rdi
  imul   %rsi,%rdi
  lea    0x4000(%rdi),%rax
  sar    $0xf,%rax
  ret
```

assistant: ```c
int _mpyhir(int src1, int src2) {
  short s1 = src1 >> 16;
  long long result = ((long long)src2) * s1 + (1 << 14);
  result >>= 15;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<osborne_checksol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  movsd  %xmm1,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  lea    D30(%rip),%rcx
  mov    %rcx,%rdi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <gsl_test_rel@plt>
  movsd  D38(%rip),%xmm0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  movsd  -0x28(%rbp),%xmm1
  mov    %rcx,%rsi
  lea    D0(%rip),%rcx
  mov    %rcx,%rdi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <gsl_test_rel@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
data_type: byte[8]
name: parse_data
arguments: label: D30
data_type: string
name: parse_data
arguments: label: D38
data_type: byte[8]
name: parse_data
arguments: label: D0
data_type: string

tool: {"D15": [0x99,0x02,0x28,0x85,0xdb,0xa6,0x0c,0x3f]}

tool: D30: %s/%s sumsq

tool: {"D38": [0xc3,0x99,0x18,0xe2,0xb7,0x06,0xd8,0x3f]}

tool: D0: %s/%s i=0

assistant: ```c
void osborne_checksol(const double x[], const double sumsq, const double epsrel, const char *sname, const char *pname) {
  const double sumsq_exact = 5.464894697482687e-05;
  const double osborne_x[5] = {3.754100521058740e-01, -99999.0, -99999.0, -99999.0, -99999.0};
  gsl_test_rel(sumsq, sumsq_exact, epsrel, "%s/%s sumsq", sname, pname);
  gsl_test_rel(x[0], osborne_x[0], epsrel, "%s/%s i=0", sname, pname);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<osborne_checksol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  movq   %xmm1,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  lea    D39(%rip),%rdi
  movapd %xmm1,%xmm2
  movsd  D2(%rip),%xmm1
  call   <gsl_test_rel@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  movq   %rbx,%xmm2
  movsd  D13(%rip),%xmm1
  movsd  0x0(%r13),%xmm0
  call   <gsl_test_rel@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D39
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D13
type_infered: byte[8]

tool: D39: %s/%s sumsq

tool: {"D2": [0x99,0x02,0x28,0x85,0xdb,0xa6,0x0c,0x3f]}

tool: D8: %s/%s i=0

tool: {"D13": [0xc3,0x99,0x18,0xe2,0xb7,0x06,0xd8,0x3f]}

assistant: ```c
void osborne_checksol(const double x[], const double sumsq, const double epsrel, const char *sname, const char *pname) {
  const double sumsq_exact = 5.464894697482687e-05;
  const double osborne_x[5] = {3.754100521058740e-01, -99999.0, -99999.0, -99999.0, -99999.0};
  gsl_test_rel(sumsq, sumsq_exact, epsrel, "%s/%s sumsq", sname, pname);
  gsl_test_rel(x[0], osborne_x[0], epsrel, "%s/%s i=0", sname, pname);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<osborne_checksol>:
  endbr64
  push   %r12
  movapd %xmm1,%xmm2
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  sub    $0x10,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  D22(%rip),%xmm1
  call   <gsl_test_rel@plt>
  movsd  (%rbx),%xmm0
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movsd  0x8(%rsp),%xmm2
  movsd  D17(%rip),%xmm1
  add    $0x10,%rsp
  lea    D26(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <gsl_test_rel@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D22
type: byte[8]
name: read_data
arguments: tag: D17
type: byte[8]
name: read_data
arguments: tag: D26
type: string

tool: D6: %s/%s sumsq

tool: {"D22": [0x99,0x02,0x28,0x85,0xdb,0xa6,0x0c,0x3f]}

tool: {"D17": [0xc3,0x99,0x18,0xe2,0xb7,0x06,0xd8,0x3f]}

tool: D26: %s/%s i=0

assistant: ```c
void osborne_checksol(const double x[], const double sumsq, const double epsrel, const char *sname, const char *pname) {
  const double sumsq_exact = 5.464894697482687e-05;
  const double osborne_x[5] = {3.754100521058740e-01, -99999.0, -99999.0, -99999.0, -99999.0};
  gsl_test_rel(sumsq, sumsq_exact, epsrel, "%s/%s sumsq", sname, pname);
  gsl_test_rel(x[0], osborne_x[0], epsrel, "%s/%s i=0", sname, pname);
}
```