ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<sas_discovery_flags_to_text>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  and    $0x2,%ebx
  and    $0x1,%edi
  movb   $0x0,D1(%rip)
  jne    L9
  test   %ebx,%ebx
  je     L7
  mov    %r12,%rdi
  lea    D30(%rip),%rbp
L13:
  lea    D13(%rip),%rdx
  mov    %rbp,%rsi
  call   <sprintf@plt>
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L9:
  lea    D30(%rip),%rbp
  lea    D26(%rip),%rdx
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <sprintf@plt>
  test   %ebx,%ebx
  je     L7
  movslq %eax,%rdi
  add    %r12,%rdi
  test   %eax,%eax
  jle    L13
  lea    0x1(%rax),%edi
  movslq %eax,%rdx
  movslq %edi,%rdi
  movb   $0x2c,(%r12,%rdx,1)
  add    %r12,%rdi
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: label: D30
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D26
datatype: string

tool: D30: %s

tool: D13: DEVICE_CHANGE

tool: D26: IN_PROGRESS

assistant: ```c
const char *sas_discovery_flags_to_text(uint8_t flags) {
  static char text[128];
  int i = 0;
  text[0] = 0;
  if (flags & (0x01))
    i += sprintf(text, "%s", "IN_PROGRESS");
  if (flags & (0x02)) {
    if (i > 0)
      text[i++] = ',';
    sprintf(text + i, "%s", "DEVICE_CHANGE");
  }
  return text;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sas_discovery_flags_to_text>:
  endbr64
  push   %r12
  lea    D43(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  and    $0x2,%ebx
  and    $0x1,%edi
  movb   $0x0,D43(%rip)
  jne    L41
  test   %ebx,%ebx
  je     L19
  mov    %r12,%rdi
  lea    D4(%rip),%rbp
L42:
  lea    D53(%rip),%rdx
  mov    %rbp,%rsi
  call   <sprintf@plt>
L19:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L41:
  lea    D4(%rip),%rbp
  lea    D38(%rip),%rdx
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <sprintf@plt>
  test   %ebx,%ebx
  je     L19
  movslq %eax,%rdi
  add    %r12,%rdi
  test   %eax,%eax
  jle    L42
  lea    0x1(%rax),%edi
  movslq %eax,%rdx
  movslq %edi,%rdi
  movb   $0x2c,(%r12,%rdx,1)
  add    %r12,%rdi
  jmp    L42
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string
name: retrieve_data
arguments: data_label: D53
type_infered: string
name: retrieve_data
arguments: data_label: D38
type_infered: string

tool: D4: %s

tool: D53: DEVICE_CHANGE

tool: D38: IN_PROGRESS

assistant: ```c
const char *sas_discovery_flags_to_text(uint8_t flags) {
  static char text[128];
  int i = 0;
  text[0] = 0;
  if (flags & (0x01))
    i += sprintf(text, "%s", "IN_PROGRESS");
  if (flags & (0x02)) {
    if (i > 0)
      text[i++] = ',';
    sprintf(text + i, "%s", "DEVICE_CHANGE");
  }
  return text;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CreateCats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <CreateRelCat@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x0,%eax
  call   <CreateAttrCat@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x0,%eax
  jmp    L19
L16:
  mov    $0xffffffff,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int CreateCats() {
  if (CreateRelCat() == 0 && CreateAttrCat() == 0)
    return 0;
  else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CreateCats>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CreateRelCat@plt>
  test   %rax,%rax
  jne    L17
  call   <CreateAttrCat@plt>
  neg    %rax
  sbb    %eax,%eax
L9:
  add    $0x8,%rsp
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int CreateCats() {
  if (CreateRelCat() == 0 && CreateAttrCat() == 0)
    return 0;
  else
    return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CreateCats>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CreateRelCat@plt>
  test   %rax,%rax
  jne    L13
  call   <CreateAttrCat@plt>
  neg    %rax
  sbb    %eax,%eax
L19:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int CreateCats() {
  if (CreateRelCat() == 0 && CreateAttrCat() == 0)
    return 0;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CreateCats>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CreateRelCat@plt>
  test   %rax,%rax
  jne    L12
  call   <CreateAttrCat@plt>
  neg    %rax
  sbb    %eax,%eax
L8:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    $0xffffffff,%eax
  jmp    L8
```

assistant: ```c
int CreateCats() {
  if (CreateRelCat() == 0 && CreateAttrCat() == 0)
    return 0;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sse_level>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xffffffff,-0x14(%rbp)
  mov    $0x1,%eax
  mov    %ebx,%edi
  cpuid
  mov    %ebx,%esi
  mov    %edi,%ebx
  mov    %eax,-0x10(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %ecx,-0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  and    $0x2000000,%eax
  test   %rax,%rax
  je     L3
  movl   $0x1,-0x14(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cltq
  and    $0x4000000,%eax
  test   %rax,%rax
  je     L2
  movl   $0x2,-0x14(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cltq
  and    $0x1,%eax
  test   %rax,%rax
  je     L15
  movl   $0x3,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sse_level() {
  int level = -1;
  int a, b, c, d;
  __asm__ __volatile__("         movl %%ebx, %%edi;         cpuid;		          movl %%ebx, %1;	          movl %%edi, %%ebx" : "=a"(a), "=r"(b), "=c"(c), "=d"(d) : "a"(1) : "edi");
  ;
  if (d & (1L << 25)) {
    level = 1;
  }
  if (d & (1L << 26)) {
    level = 2;
  }
  if (c & (1L << 0)) {
    level = 3;
  }
  return level;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sse_level>:
  endbr64
  mov    $0x1,%eax
  mov    %ebx,%edi
  cpuid
  mov    %ebx,%esi
  mov    %edi,%ebx
  mov    %edx,%eax
  and    $0x2000000,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  or     $0x1,%eax
  test   $0x4000000,%edx
  mov    $0x2,%edx
  cmovne %edx,%eax
  test   $0x1,%cl
  mov    $0x3,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int sse_level() {
  int level = -1;
  int a, b, c, d;
  __asm__ __volatile__("         movl %%ebx, %%edi;         cpuid;		          movl %%ebx, %1;	          movl %%edi, %%ebx" : "=a"(a), "=r"(b), "=c"(c), "=d"(d) : "a"(1) : "edi");
  ;
  if (d & (1L << 25)) {
    level = 1;
  }
  if (d & (1L << 26)) {
    level = 2;
  }
  if (c & (1L << 0)) {
    level = 3;
  }
  return level;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sse_level>:
  endbr64
  mov    $0x1,%eax
  mov    %ebx,%edi
  cpuid
  mov    %ebx,%esi
  mov    %edi,%ebx
  mov    %edx,%eax
  and    $0x2000000,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  or     $0x1,%eax
  and    $0x4000000,%edx
  mov    $0x2,%edx
  cmovne %edx,%eax
  and    $0x1,%ecx
  mov    $0x3,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int sse_level() {
  int level = -1;
  int a, b, c, d;
  __asm__ __volatile__("         movl %%ebx, %%edi;         cpuid;		          movl %%ebx, %1;	          movl %%edi, %%ebx" : "=a"(a), "=r"(b), "=c"(c), "=d"(d) : "a"(1) : "edi");
  ;
  if (d & (1L << 25)) {
    level = 1;
  }
  if (d & (1L << 26)) {
    level = 2;
  }
  if (c & (1L << 0)) {
    level = 3;
  }
  return level;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sse_level>:
  endbr64
  mov    $0x1,%eax
  mov    %ebx,%edi
  cpuid
  mov    %ebx,%esi
  mov    %edi,%ebx
  mov    %edx,%eax
  and    $0x2000000,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  or     $0x1,%eax
  and    $0x4000000,%edx
  mov    $0x2,%edx
  cmovne %edx,%eax
  and    $0x1,%ecx
  mov    $0x3,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int sse_level() {
  int level = -1;
  int a, b, c, d;
  __asm__ __volatile__("         movl %%ebx, %%edi;         cpuid;		          movl %%ebx, %1;	          movl %%edi, %%ebx" : "=a"(a), "=r"(b), "=c"(c), "=d"(d) : "a"(1) : "edi");
  ;
  if (d & (1L << 25)) {
    level = 1;
  }
  if (d & (1L << 26)) {
    level = 2;
  }
  if (c & (1L << 0)) {
    level = 3;
  }
  return level;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sortArrayByParityII>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L27
L18:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  lea    0x2(%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    %edx,-0x10(%rbp,%rax,4)
  addl   $0x1,-0x20(%rbp)
L27:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L18
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int *sortArrayByParityII(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *sortedArray = (int *)malloc(sizeof(int) * ASize);
  int ind[2] = {0, 1};
  int r = 0;
  for (int i = 0; i < ASize; i++) {
    r = A[i] % 2;
    sortedArray[ind[r]] = A[i];
    ind[r] += 2;
  }
  return sortedArray;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sortArrayByParityII>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rdx)
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  test   %ebx,%ebx
  jle    L16
  mov    %rbp,%rcx
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp,%rax,4),%r9
L9:
  mov    (%rcx),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%edx
  movslq %edx,%rdi
  mov    %esi,(%r8,%rdi,4)
  add    $0x2,%edx
  mov    %edx,(%rsp,%rax,4)
  add    $0x4,%rcx
  cmp    %r9,%rcx
  jne    L9
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %r8,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *sortArrayByParityII(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *sortedArray = (int *)malloc(sizeof(int) * ASize);
  int ind[2] = {0, 1};
  int r = 0;
  for (int i = 0; i < ASize; i++) {
    r = A[i] % 2;
    sortedArray[ind[r]] = A[i];
    ind[r] += 2;
  }
  return sortedArray;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sortArrayByParityII>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rdx)
  call   <malloc@plt>
  mov    %rax,%r8
  movabs $0x100000000,%rax
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L4
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rcx
  lea    0x4(%rbx,%rax,4),%r9
  nopl   (%rax)
L27:
  mov    (%rcx),%esi
  add    $0x4,%rcx
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cltq
  movslq (%rsp,%rax,4),%rdi
  mov    %rdi,%rdx
  mov    %esi,(%r8,%rdi,4)
  add    $0x2,%edx
  mov    %edx,(%rsp,%rax,4)
  cmp    %rcx,%r9
  jne    L27
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *sortArrayByParityII(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *sortedArray = (int *)malloc(sizeof(int) * ASize);
  int ind[2] = {0, 1};
  int r = 0;
  for (int i = 0; i < ASize; i++) {
    r = A[i] % 2;
    sortedArray[ind[r]] = A[i];
    ind[r] += 2;
  }
  return sortedArray;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sortArrayByParityII>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rdx)
  call   <malloc@plt>
  mov    %rax,%r8
  mov    D2(%rip),%rax
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L7
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rcx
  lea    0x4(%rbx,%rax,4),%r9
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rcx),%esi
  add    $0x4,%rcx
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cltq
  movslq (%rsp,%rax,4),%rdi
  mov    %rdi,%rdx
  mov    %esi,(%r8,%rdi,4)
  add    $0x2,%edx
  mov    %edx,(%rsp,%rax,4)
  cmp    %rcx,%r9
  jne    L17
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int *sortArrayByParityII(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *sortedArray = (int *)malloc(sizeof(int) * ASize);
  int ind[2] = {0, 1};
  int r = 0;
  for (int i = 0; i < ASize; i++) {
    r = A[i] % 2;
    sortedArray[ind[r]] = A[i];
    ind[r] += 2;
  }
  return sortedArray;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L1:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: allocation failure in dvector()

assistant: ```c
double *dvector(int nl, int nh) {
  double *v;
  v = (double *)calloc((unsigned)(nh - nl + 1), sizeof(double));
  if (!v)
    nrerror("allocation failure in dvector()");
  return v - nl;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dvector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  sub    %edi,%esi
  lea    0x1(%rsi),%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L9
L16:
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  mov    %rbp,%rax
  sub    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D0: allocation failure in dvector()

assistant: ```c
double *dvector(int nl, int nh) {
  double *v;
  v = (double *)calloc((unsigned)(nh - nl + 1), sizeof(double));
  if (!v)
    nrerror("allocation failure in dvector()");
  return v - nl;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dvector>:
  endbr64
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    %ebx,%esi
  lea    0x1(%rsi),%edi
  mov    $0x8,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
L0:
  shl    $0x3,%rbx
  mov    %rbp,%rax
  add    $0x8,%rsp
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L16:
  lea    D6(%rip),%rdi
  call   <nrerror@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D6: allocation failure in dvector()

assistant: ```c
double *dvector(int nl, int nh) {
  double *v;
  v = (double *)calloc((unsigned)(nh - nl + 1), sizeof(double));
  if (!v)
    nrerror("allocation failure in dvector()");
  return v - nl;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dvector>:
  endbr64
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    %ebx,%esi
  lea    0x1(%rsi),%edi
  mov    $0x8,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L3
L14:
  shl    $0x3,%rbx
  mov    %rbp,%rax
  add    $0x8,%rsp
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  lea    D2(%rip),%rdi
  call   <nrerror@plt>
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2: allocation failure in dvector()

assistant: ```c
double *dvector(int nl, int nh) {
  double *v;
  v = (double *)calloc((unsigned)(nh - nl + 1), sizeof(double));
  if (!v)
    nrerror("allocation failure in dvector()");
  return v - nl;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<digits_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  mov    $0x1,%eax
  jmp    L23
L12:
  cmpl   $0x0,-0x4(%rbp)
  jle    L1
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  jmp    L23
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x2,%eax
L23:
  leave
  ret
```

assistant: ```c
int digits_int(int i) {
  if (i == 0) {
    return 1;
  } else if (i > 0) {
    return floor(log10(abs(i))) + 1;
  } else {
    return floor(log10(abs(i))) + 2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<digits_int>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  test   %edi,%edi
  je     L12
  jle    L9
  mov    %edi,%eax
  neg    %eax
  cmovns %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
L12:
  add    $0x8,%rsp
  ret
L9:
  mov    %edi,%eax
  neg    %eax
  cmovns %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x2,%eax
  jmp    L12
```

assistant: ```c
int digits_int(int i) {
  if (i == 0) {
    return 1;
  } else if (i > 0) {
    return floor(log10(abs(i))) + 1;
  } else {
    return floor(log10(abs(i))) + 2;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<digits_int>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  test   %edi,%edi
  je     L11
  jle    L1
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
L11:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  neg    %edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x8,%rsp
  add    $0x2,%eax
  ret
```

assistant: ```c
int digits_int(int i) {
  if (i == 0) {
    return 1;
  } else if (i > 0) {
    return floor(log10(abs(i))) + 1;
  } else {
    return floor(log10(abs(i))) + 2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<digits_int>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  test   %edi,%edi
  je     L11
  jle    L12
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
L11:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  neg    %edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x8,%rsp
  add    $0x2,%eax
  ret
```

assistant: ```c
int digits_int(int i) {
  if (i == 0) {
    return 1;
  } else if (i > 0) {
    return floor(log10(abs(i))) + 1;
  } else {
    return floor(log10(abs(i))) + 2;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<array_print_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x24(%rbp)
  movsbl -0x24(%rbp),%eax
  cmp    $0x43,%eax
  je     L44
  cmp    $0x52,%eax
  jne    L29
  movl   $0x0,-0x8(%rbp)
  jmp    L95
L81:
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L91:
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L91
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L95:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L81
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L29
L44:
  movl   $0x0,-0x8(%rbp)
  jmp    L50
L69:
  movl   $0x0,-0x4(%rbp)
  jmp    L101
L78:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L101:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L78
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L69
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
L29:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: % 12ld 

assistant: ```c
void array_print_l(const unsigned int m, const unsigned int n, const long *A, const char layout) {
  unsigned int i, j;
  switch (layout) {
  case 'R':
    for (i = 0; i < m; i++) {
      for (j = 0; j < n; j++)
        printf("% 12ld ", A[i * n + j]);
      printf("\n");
    }
    printf("\n");
    break;
  case 'C':
    for (i = 0; i < m; i++) {
      for (j = 0; j < n; j++)
        printf("% 12ld ", A[i + j * m]);
      printf("\n");
    }
    printf("\n");
    break;
  }
}
```