ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PasswordCompare>:
  endbr64
  test   %rdi,%rdi
  je     L9
  test   %rsi,%rsi
  je     L9
  mov    %rdi,%rax
  lea    0x10(%rdi),%rdx
  nopl   (%rax)
L14:
  cmpb   $0x0,(%rax)
  jne    L32
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L14
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L32:
  sub    $0x8,%rsp
  mov    $0x10,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int PasswordCompare(const char *pcMD5Pass, const char *pcMD5PassTest) {
  int i;
  ;
  ;
  if (!pcMD5Pass || !pcMD5PassTest)
    return 0;
  for (i = 0; i < 16; i++)
    if (pcMD5Pass[i])
      break;
  if (i >= 16)
    return 1;
  return !memcmp(pcMD5Pass, pcMD5PassTest, 16);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PasswordCompare>:
  endbr64
  test   %rdi,%rdi
  je     L64
  test   %rsi,%rsi
  je     L64
  cmpb   $0x0,(%rdi)
  jne    L97
  cmpb   $0x0,0x1(%rdi)
  jne    L97
  cmpb   $0x0,0x2(%rdi)
  jne    L97
  cmpb   $0x0,0x3(%rdi)
  jne    L97
  cmpb   $0x0,0x4(%rdi)
  jne    L97
  cmpb   $0x0,0x5(%rdi)
  jne    L97
  cmpb   $0x0,0x6(%rdi)
  jne    L97
  cmpb   $0x0,0x7(%rdi)
  jne    L97
  cmpb   $0x0,0x8(%rdi)
  jne    L97
  cmpb   $0x0,0x9(%rdi)
  jne    L97
  cmpb   $0x0,0xa(%rdi)
  jne    L97
  cmpb   $0x0,0xb(%rdi)
  jne    L97
  cmpb   $0x0,0xc(%rdi)
  jne    L97
  cmpb   $0x0,0xd(%rdi)
  jne    L97
  cmpb   $0x0,0xe(%rdi)
  jne    L97
  cmpb   $0x0,0xf(%rdi)
  jne    L97
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L97:
  sub    $0x8,%rsp
  mov    $0x10,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
  ret
```

assistant: ```c
int PasswordCompare(const char *pcMD5Pass, const char *pcMD5PassTest) {
  int i;
  ;
  ;
  if (!pcMD5Pass || !pcMD5PassTest)
    return 0;
  for (i = 0; i < 16; i++)
    if (pcMD5Pass[i])
      break;
  if (i >= 16)
    return 1;
  return !memcmp(pcMD5Pass, pcMD5PassTest, 16);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ext_part>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L50
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_path_sep@plt>
  test   %rax,%rax
  jne    L56
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L32
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L41
L32:
  subl   $0x1,-0x4(%rbp)
L50:
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
  jmp    L44
L56:
  nop
L44:
  lea    D3(%rip),%rax
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: 

assistant: ```c
const char *ext_part(const char *path) {
  int n;
  for (n = (int)strlen(path) - 1; n >= 0; --n) {
    if (is_path_sep(path[n])) {
      break;
    }
    if (path[n] == '.') {
      return &path[n];
    }
  }
  return "";
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ext_part>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    D23(%rip),%rbp
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L6
  movslq %ebx,%rbx
  add    %r12,%rbx
  movslq %eax,%rdx
  lea    -0x2(%r12,%rdx,1),%r12
  lea    -0x1(%rax),%eax
  sub    %rax,%r12
L1:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  call   <is_path_sep@plt>
  test   %rax,%rax
  jne    L19
  cmpb   $0x2e,(%rbx)
  je     L6
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L1
  lea    D23(%rip),%rbp
  jmp    L6
L19:
  lea    D23(%rip),%rbp
L6:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type: string

tool: 

assistant: ```c
const char *ext_part(const char *path) {
  int n;
  for (n = (int)strlen(path) - 1; n >= 0; --n) {
    if (is_path_sep(path[n])) {
      break;
    }
    if (path[n] == '.') {
      return &path[n];
    }
  }
  return "";
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ext_part>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L42
  movslq %edx,%rbx
  cltq
  mov    %edx,%edx
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L1:
  cmpb   $0x2e,(%rbx)
  je     L43
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L42
L14:
  movsbl (%rbx),%edi
  mov    %rbx,%r12
  call   <is_path_sep@plt>
  test   %rax,%rax
  je     L1
L42:
  lea    D9(%rip),%r12
L43:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: 

assistant: ```c
const char *ext_part(const char *path) {
  int n;
  for (n = (int)strlen(path) - 1; n >= 0; --n) {
    if (is_path_sep(path[n])) {
      break;
    }
    if (path[n] == '.') {
      return &path[n];
    }
  }
  return "";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ext_part>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L10
  movslq %edx,%rbx
  cltq
  mov    %edx,%edx
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L17:
  cmpb   $0x2e,(%rbx)
  je     L43
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L10
L3:
  movsbl (%rbx),%edi
  mov    %rbx,%r12
  call   <is_path_sep@plt>
  test   %rax,%rax
  je     L17
L10:
  lea    D2(%rip),%r12
L43:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: 

assistant: ```c
const char *ext_part(const char *path) {
  int n;
  for (n = (int)strlen(path) - 1; n >= 0; --n) {
    if (is_path_sep(path[n])) {
      break;
    }
    if (path[n] == '.') {
      return &path[n];
    }
  }
  return "";
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<endianConvScript>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L17:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <le16toh@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void endianConvScript(int n, ushort s[]) {
  int i;
  for (i = 0; i < n; ++i) {
    s[i] = le16toh(s[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<endianConvScript>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rbp
L11:
  mov    (%rbx),%edi
  call   <le16toh@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  ret
```

assistant: ```c
void endianConvScript(int n, ushort s[]) {
  int i;
  for (i = 0; i < n; ++i) {
    s[i] = le16toh(s[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<endianConvScript>:
  endbr64
  test   %edi,%edi
  jle    L6
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x4(%rsi,%rax,4),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <le16toh@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void endianConvScript(int n, ushort s[]) {
  int i;
  for (i = 0; i < n; ++i) {
    s[i] = le16toh(s[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<endianConvScript>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x4(%rsi,%rax,4),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L11:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <le16toh@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void endianConvScript(int n, ushort s[]) {
  int i;
  for (i = 0; i < n; ++i) {
    s[i] = le16toh(s[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_branch_protected_scope>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
L33:
  addl   $0x1,-0x74(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L40
L15:
  cmpl   $0x5,-0x74(%rbp)
  jne    L41
  jmp    L33
L41:
  cmpl   $0x6,-0x74(%rbp)
  je     L11
  cmpl   $0x7,-0x74(%rbp)
  je     L65
  cmpl   $0x8,-0x74(%rbp)
  jne    L48
  jmp    L98
L65:
  nop
  jmp    L98
L121:
  nop
L98:
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x74(%rbp),%eax
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
L48:
  addl   $0x1,-0x74(%rbp)
L40:
  cmpl   $0xf,-0x74(%rbp)
  jle    L15
  mov    -0x70(%rbp),%eax
  test   %eax,%eax
  je     L121
  mov    -0x6c(%rbp),%eax
  cmp    $0x1,%eax
  jne    L81
  jmp    L33
L11:
  nop
L81:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void test_branch_protected_scope() {
  int i = 0;
L1:
  ++i;
  int x[24];
#pragma omp target teams distribute parallel for
  for (i = 0; i < 16; ++i) {
    if (i == 5)
      goto L1;
    else if (i == 6)
      return;
    else if (i == 7)
      goto L2;
    else if (i == 8) {
    L2:
      x[i]++;
    }
  }
  if (x[0] == 0)
    goto L2;
  else if (x[1] == 1)
    goto L1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_branch_protected_scope>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
L0:
  mov    %rsp,%rdx
  mov    $0x0,%eax
  jmp    L71
L25:
  add    $0x1,%eax
  add    $0x4,%rdx
L71:
  cmp    $0xf,%eax
  jg     L9
  cmp    $0x5,%eax
  je     L0
  cmp    $0x6,%eax
  je     L7
  lea    -0x7(%rax),%ecx
  cmp    $0x1,%ecx
  ja     L25
L13:
  addl   $0x1,(%rdx)
  jmp    L25
L9:
  cmpl   $0x0,(%rsp)
  je     L13
  cmpl   $0x1,0x4(%rsp)
  je     L0
L7:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x78,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_branch_protected_scope() {
  int i = 0;
L1:
  ++i;
  int x[24];
#pragma omp target teams distribute parallel for
  for (i = 0; i < 16; ++i) {
    if (i == 5)
      goto L1;
    else if (i == 6)
      return;
    else if (i == 7)
      goto L2;
    else if (i == 8) {
    L2:
      x[i]++;
    }
  }
  if (x[0] == 0)
    goto L2;
  else if (x[1] == 1)
    goto L1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_branch_protected_scope>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%esi
  mov    %rsp,%rcx
  xchg   %ax,%ax
L24:
  mov    %rcx,%rdx
  xor    %eax,%eax
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L52:
  cmp    $0x5,%eax
  je     L24
L9:
  add    $0x1,%eax
  add    $0x4,%rdx
L45:
  cmp    $0xf,%eax
  jle    L52
  test   %esi,%esi
  jne    L47
  addl   $0x1,(%rdx)
  mov    (%rsp),%esi
  jmp    L9
L47:
  cmpl   $0x1,0x4(%rsp)
  je     L24
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_branch_protected_scope() {
  int i = 0;
L1:
  ++i;
  int x[24];
#pragma omp target teams distribute parallel for
  for (i = 0; i < 16; ++i) {
    if (i == 5)
      goto L1;
    else if (i == 6)
      return;
    else if (i == 7)
      goto L2;
    else if (i == 8) {
    L2:
      x[i]++;
    }
  }
  if (x[0] == 0)
    goto L2;
  else if (x[1] == 1)
    goto L1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_branch_protected_scope>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%esi
  mov    %rsp,%rcx
  xchg   %ax,%ax
L68:
  mov    %rcx,%rdx
  xor    %eax,%eax
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L16:
  cmp    $0x5,%eax
  je     L68
L21:
  add    $0x1,%eax
  add    $0x4,%rdx
L58:
  cmp    $0xf,%eax
  jle    L16
  test   %esi,%esi
  jne    L43
  addl   $0x1,(%rdx)
  mov    (%rsp),%esi
  jmp    L21
L43:
  cmpl   $0x1,0x4(%rsp)
  je     L68
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x78,%rsp
  ret
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_branch_protected_scope() {
  int i = 0;
L1:
  ++i;
  int x[24];
#pragma omp target teams distribute parallel for
  for (i = 0; i < 16; ++i) {
    if (i == 5)
      goto L1;
    else if (i == 6)
      return;
    else if (i == 7)
      goto L2;
    else if (i == 8) {
    L2:
      x[i]++;
    }
  }
  if (x[0] == 0)
    goto L2;
  else if (x[1] == 1)
    goto L1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <index>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <index>
  leave
  ret
```

assistant: ```c
float index(float x) {
  float n;
  n = index(x);
  return index(x);
}
```
user: What is the c source code of the assembly code below?

```asm
<index>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <index>
  movss  0xc(%rsp),%xmm0
  call   <index>
  add    $0x18,%rsp
  ret
```

assistant: ```c
float index(float x) {
  float n;
  n = index(x);
  return index(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<index>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x18,%rsp
  movaps %xmm0,%xmm1
L9:
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <index>
  movss  0xc(%rsp),%xmm1
  jmp    L9
```

assistant: ```c
float index(float x) {
  float n;
  n = index(x);
  return index(x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<index>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x18,%rsp
  movaps %xmm0,%xmm1
L0:
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <index>
  movss  0xc(%rsp),%xmm1
  jmp    L0
```

assistant: ```c
float index(float x) {
  float n;
  n = index(x);
  return index(x);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jg     L37
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L37:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L52
L27:
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L46
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L52
L46:
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L52:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L27
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D63
type_guessed: string
name: unpack_data
arguments: tag: D24
type_guessed: string
name: unpack_data
arguments: tag: D10
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D27
type_guessed: string
name: unpack_data
arguments: tag: D54
type_guessed: string

tool: D63: Inital value: 

tool: D24: %d

tool: D10: Error.

tool: D9: Initial value is %d


tool: D27: Next value is %d


tool: D54: Final value %d, number of steps %d


assistant: ```c
int main() {
  int init, steps;
  steps = 0;
  printf("Inital value: ");
  scanf("%d", &init);
  if (init < 2) {
    printf("Error.");
  } else {
    printf("Initial value is %d\n", init);
    while (init != 1) {
      steps++;
      if (init % 2 == 0) {
        init = init / 2;
        printf("Next value is %d\n", init);
      } else {
        init = (init * 3) + 1;
        printf("Next value is %d\n", init);
      }
    }
    printf("Final value %d, number of steps %d\n", init, steps);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D53(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%esi
  jle    L7
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L63
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
  jmp    L59
L7:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
L0:
  lea    0x1(%rax,%rax,2),%esi
  mov    %esi,0x4(%rsp)
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L64:
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L65
L59:
  add    $0x1,%ebx
  test   $0x1,%al
  jne    L0
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %esi,0x4(%rsp)
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L64
L63:
  mov    $0x0,%ebx
L65:
  mov    %ebx,%edx
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
data_type: string
name: extract_symbolic_data
arguments: tag: D53
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D4
data_type: string
name: extract_symbolic_data
arguments: tag: D23
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string

tool: D37: Inital value: 

tool: D53: %d

tool: D19: Initial value is %d


tool: D4: Next value is %d


tool: D23: Error.

tool: D16: Final value %d, number of steps %d


assistant: ```c
int main() {
  int init, steps;
  steps = 0;
  printf("Inital value: ");
  scanf("%d", &init);
  if (init < 2) {
    printf("Error.");
  } else {
    printf("Initial value is %d\n", init);
    while (init != 1) {
      steps++;
      if (init % 2 == 0) {
        init = init / 2;
        printf("Next value is %d\n", init);
      } else {
        init = (init * 3) + 1;
        printf("Next value is %d\n", init);
      }
    }
    printf("Final value %d, number of steps %d\n", init, steps);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D43(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D55(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%esi
  jle    L7
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L58
  lea    D18(%rip),%rbx
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %eax,%esi
  mov    %rbx,%rdi
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  mov    %esi,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L58
L52:
  add    $0x1,%r12d
  test   $0x1,%al
  je     L1
  lea    0x1(%rax,%rax,2),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jne    L52
L58:
  mov    %r12d,%edx
  mov    $0x1,%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L7:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L33
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D43
data_type: string
name: unpack_data
arguments: tag: D55
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D36
data_type: string
name: unpack_data
arguments: tag: D7
data_type: string

tool: D43: Inital value: 

tool: D55: %d

tool: D13: Initial value is %d


tool: D18: Next value is %d


tool: D36: Final value %d, number of steps %d


tool: D7: Error.

assistant: ```c
int main() {
  int init, steps;
  steps = 0;
  printf("Inital value: ");
  scanf("%d", &init);
  if (init < 2) {
    printf("Error.");
  } else {
    printf("Initial value is %d\n", init);
    while (init != 1) {
      steps++;
      if (init % 2 == 0) {
        init = init / 2;
        printf("Next value is %d\n", init);
      } else {
        init = (init * 3) + 1;
        printf("Next value is %d\n", init);
      }
    }
    printf("Final value %d, number of steps %d\n", init, steps);
  }
}
```