ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isSubSum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  test   %edi,%edi
  js     L134
  mov    %edi,%ebp
  jne    L123
  mov    $0x1,%r13d
  test   %esi,%esi
  jns    L134
L123:
  cmp    $0x1,%esi
  sete   %al
  cmp    $0x1,%ebp
  jne    L92
  mov    $0x1,%r13d
  test   %al,%al
  je     L99
L134:
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L92:
  xor    %r13d,%r13d
  test   %al,%al
  je     L7
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L99:
  cmp    $0x1,%ebp
  jne    L92
L7:
  mov    %ebp,%r15d
  lea    -0x1(%rsi),%r14d
  sub    %esi,%r15d
  js     L147
  jne    L98
  mov    $0x1,%r13d
  test   %r14d,%r14d
  jns    L134
L98:
  cmp    $0x1,%r14d
  sete   %al
  cmp    $0x1,%r15d
  jne    L138
  mov    $0x1,%r13d
  test   %al,%al
  jne    L134
  cmp    $0x1,%r15d
  jne    L138
L11:
  lea    -0x2(%rsi),%r12d
  mov    %r15d,%edi
  mov    $0x1,%r13d
  sub    %r14d,%edi
  mov    %r12d,%esi
  call   <isSubSum>
  test   %eax,%eax
  jne    L134
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <isSubSum>
  test   %eax,%eax
  jne    L134
  nopw   0x0(%rax,%rax,1)
L147:
  mov    %r14d,%esi
  mov    %ebp,%edi
  xor    %r13d,%r13d
  call   <isSubSum>
  test   %eax,%eax
  setne  %r13b
  jmp    L134
  nopl   0x0(%rax,%rax,1)
L138:
  test   %al,%al
  jne    L147
  jmp    L11
```

assistant: ```c
int isSubSum(int m, int n) {
  if (m < 0)
    return 0;
  if (m == 0 && n >= 0)
    return 1;
  if (n == 1 && m == 1)
    return 1;
  if (n == 1 && m != 1)
    return 0;
  return isSubSum(m - n, n - 1) || isSubSum(m, n - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fn7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  not    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn7(int x, int y) {
  int tem1 = y ^ ~x;
  int tem2 = x | y;
  return tem1 & tem2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn7>:
  endbr64
  mov    %edi,%eax
  and    %esi,%eax
  ret
```

assistant: ```c
int fn7(int x, int y) {
  int tem1 = y ^ ~x;
  int tem2 = x | y;
  return tem1 & tem2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn7>:
  endbr64
  mov    %edi,%eax
  and    %esi,%eax
  ret
```

assistant: ```c
int fn7(int x, int y) {
  int tem1 = y ^ ~x;
  int tem2 = x | y;
  return tem1 & tem2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fn7>:
  endbr64
  mov    %edi,%eax
  and    %esi,%eax
  ret
```

assistant: ```c
int fn7(int x, int y) {
  int tem1 = y ^ ~x;
  int tem2 = x | y;
  return tem1 & tem2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L20:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    $0x0,%eax
  jmp    L28
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L20
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x6(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x6(%rbp),%eax
  movzbl -0x5(%rbp),%edx
  sub    %edx,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcmp(char *s1, char *s2) {
  int i;
  unsigned char c1;
  unsigned char c2;
  i = 0;
  while (s1[i] == s2[i])
    if (s1[i++] == '\0')
      return (0);
  c1 = s1[i];
  c2 = s2[i];
  return (c1 - c2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strcmp>:
  endbr64
  mov    $0x0,%eax
L5:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L13
  add    $0x1,%rax
  test   %dl,%dl
  jne    L5
  mov    $0x0,%eax
  ret
L13:
  movzbl %dl,%eax
  movzbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int ft_strcmp(char *s1, char *s2) {
  int i;
  unsigned char c1;
  unsigned char c2;
  i = 0;
  while (s1[i] == s2[i])
    if (s1[i++] == '\0')
      return (0);
  c1 = s1[i];
  c2 = s2[i];
  return (c1 - c2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  test   %dl,%dl
  je     L5
L2:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L6
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_strcmp(char *s1, char *s2) {
  int i;
  unsigned char c1;
  unsigned char c2;
  i = 0;
  while (s1[i] == s2[i])
    if (s1[i++] == '\0')
      return (0);
  c1 = s1[i];
  c2 = s2[i];
  return (c1 - c2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rax
  test   %dl,%dl
  je     L28
L18:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L5
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_strcmp(char *s1, char *s2) {
  int i;
  unsigned char c1;
  unsigned char c2;
  i = 0;
  while (s1[i] == s2[i])
    if (s1[i++] == '\0')
      return (0);
  c1 = s1[i];
  c2 = s2[i];
  return (c1 - c2);
}
```
user: What is the c source code of the assembly code below?

```asm
<concat_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movw   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x58(%rbp)
  jne    L21
  mov    -0x4c(%rbp),%edx
  lea    -0x40(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L25
L21:
  mov    -0x4c(%rbp),%ecx
  mov    -0x58(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L25:
  lea    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string

tool: D5: %d

tool: D14: %s%d

assistant: ```c
void concat_num(char *str, int x, char *sep) {
  char buf[50] = {0};
  if (sep == NULL)
    sprintf(buf, "%d", x);
  else
    sprintf(buf, "%s%d", sep, x);
  strcat(str, buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<concat_num>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movw   $0x0,0x30(%rsp)
  test   %rdx,%rdx
  je     L3
  mov    %rsp,%rdi
  lea    D10(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
L18:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x40,%rsp
  pop    %rbx
  ret
L3:
  mov    %rsp,%rdi
  mov    %esi,%edx
  lea    D11(%rip),%rsi
  call   <sprintf@plt>
  jmp    L18
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string

tool: D10: %s%d

tool: D11: %d

assistant: ```c
void concat_num(char *str, int x, char *sep) {
  char buf[50] = {0};
  if (sep == NULL)
    sprintf(buf, "%d", x);
  else
    sprintf(buf, "%s%d", sep, x);
  strcat(str, buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<concat_num>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %esi,%ecx
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %si,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  test   %rdx,%rdx
  je     L14
  lea    D12(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
L28:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L14:
  mov    %ecx,%edx
  lea    D18(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  jmp    L28
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D18
type_guessed: string

tool: D12: %s%d

tool: D18: %d

assistant: ```c
void concat_num(char *str, int x, char *sep) {
  char buf[50] = {0};
  if (sep == NULL)
    sprintf(buf, "%d", x);
  else
    sprintf(buf, "%s%d", sep, x);
  strcat(str, buf);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<concat_num>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %esi,%ecx
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %si,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  test   %rdx,%rdx
  je     L13
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
L11:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L13:
  mov    %ecx,%edx
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  jmp    L11
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D5
type: string

tool: D16: %s%d

tool: D5: %d

assistant: ```c
void concat_num(char *str, int x, char *sep) {
  char buf[50] = {0};
  if (sep == NULL)
    sprintf(buf, "%d", x);
  else
    sprintf(buf, "%s%d", sep, x);
  strcat(str, buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kputchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  lea    -0x4(%rbp),%rax
  mov    %rax,%rdi
  call   <putchar_framebuffer_wob@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int kputchar(char c) {
  putchar_framebuffer_wob(&c);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kputchar>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <putchar_framebuffer_wob@plt>
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int kputchar(char c) {
  putchar_framebuffer_wob(&c);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kputchar>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <putchar_framebuffer_wob@plt>
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int kputchar(char c) {
  putchar_framebuffer_wob(&c);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<kputchar>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <putchar_framebuffer_wob@plt>
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int kputchar(char c) {
  putchar_framebuffer_wob(&c);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <sum_array@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: string

tool: D7: sum: %d


assistant: ```c
int main(void) {
  int array[3] = {1, 2, 3};
  printf("sum: %d\n", sum_array(array, 3));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x3,%esi
  call   <sum_array@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0: sum: %d


assistant: ```c
int main(void) {
  int array[3] = {1, 2, 3};
  printf("sum: %d\n", sum_array(array, 3));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  lea    0xc(%rsp),%rdi
  movl   $0x3,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <sum_array@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: sum: %d


assistant: ```c
int main(void) {
  int array[3] = {1, 2, 3};
  printf("sum: %d\n", sum_array(array, 3));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x8(%rsp),%rdi
  movl   $0x3,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <sum_array@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: byte[8]
name: read_data
arguments: data_label: D14
type_infered: string

tool: {"D6": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D14: sum: %d


assistant: ```c
int main(void) {
  int array[3] = {1, 2, 3};
  printf("sum: %d\n", sum_array(array, 3));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  lock bts %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_bit(unsigned int nr, volatile unsigned long *addr) {
  if ((__builtin_constant_p(nr))) {
    asm volatile("\n\tlock; "
                 "orb %1,%0"
                 : "+m"(*(volatile long *)((void *)(addr) + ((nr) >> 3)))
                 : "iq"((unsigned char)(1 << ((nr)&7)))
                 : "memory");
  } else {
    asm volatile("\n\tlock; "
                 "bts %1,%0"
                 : "+m"(*(volatile long *)(addr))
                 : "Ir"(nr)
                 : "memory");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_bit>:
  endbr64
  lock bts %edi,(%rsi)
  ret
```

assistant: ```c
void set_bit(unsigned int nr, volatile unsigned long *addr) {
  if ((__builtin_constant_p(nr))) {
    asm volatile("\n\tlock; "
                 "orb %1,%0"
                 : "+m"(*(volatile long *)((void *)(addr) + ((nr) >> 3)))
                 : "iq"((unsigned char)(1 << ((nr)&7)))
                 : "memory");
  } else {
    asm volatile("\n\tlock; "
                 "bts %1,%0"
                 : "+m"(*(volatile long *)(addr))
                 : "Ir"(nr)
                 : "memory");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set_bit>:
  endbr64
  lock bts %edi,(%rsi)
  ret
```

assistant: ```c
void set_bit(unsigned int nr, volatile unsigned long *addr) {
  if ((__builtin_constant_p(nr))) {
    asm volatile("\n\tlock; "
                 "orb %1,%0"
                 : "+m"(*(volatile long *)((void *)(addr) + ((nr) >> 3)))
                 : "iq"((unsigned char)(1 << ((nr)&7)))
                 : "memory");
  } else {
    asm volatile("\n\tlock; "
                 "bts %1,%0"
                 : "+m"(*(volatile long *)(addr))
                 : "Ir"(nr)
                 : "memory");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_bit>:
  endbr64
  lock bts %edi,(%rsi)
  ret
```

assistant: ```c
void set_bit(unsigned int nr, volatile unsigned long *addr) {
  if ((__builtin_constant_p(nr))) {
    asm volatile("\n\tlock; "
                 "orb %1,%0"
                 : "+m"(*(volatile long *)((void *)(addr) + ((nr) >> 3)))
                 : "iq"((unsigned char)(1 << ((nr)&7)))
                 : "memory");
  } else {
    asm volatile("\n\tlock; "
                 "bts %1,%0"
                 : "+m"(*(volatile long *)(addr))
                 : "Ir"(nr)
                 : "memory");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getCurrentTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void getCurrentTime(struct tm *result) {
  time_t currentunixtime;
  time(&currentunixtime);
  localtime_r(&currentunixtime, result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getCurrentTime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <localtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getCurrentTime(struct tm *result) {
  time_t currentunixtime;
  time(&currentunixtime);
  localtime_r(&currentunixtime, result);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getCurrentTime>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <time@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <localtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getCurrentTime(struct tm *result) {
  time_t currentunixtime;
  time(&currentunixtime);
  localtime_r(&currentunixtime, result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getCurrentTime>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <time@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <localtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getCurrentTime(struct tm *result) {
  time_t currentunixtime;
  time(&currentunixtime);
  localtime_r(&currentunixtime, result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shiftRDdouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L16:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L16
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double shiftRDdouble(double zIn, double z[], int N) {
  int i;
  double zOut;
  zOut = z[0];
  for (i = 0; i < N - 1; i++) {
    z[i] = z[i + 1];
  }
  z[N - 1] = zIn;
  return (zOut);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shiftRDdouble>:
  endbr64
  movsd  (%rdi),%xmm2
  cmp    $0x1,%esi
  jle    L11
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L15:
  movsd  0x8(%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L15
L11:
  movslq %esi,%rsi
  movsd  %xmm0,-0x8(%rdi,%rsi,8)
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
double shiftRDdouble(double zIn, double z[], int N) {
  int i;
  double zOut;
  zOut = z[0];
  for (i = 0; i < N - 1; i++) {
    z[i] = z[i + 1];
  }
  z[N - 1] = zIn;
  return (zOut);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<shiftRDdouble>:
  endbr64
  push   %rbx
  movslq %esi,%rbx
  sub    $0x10,%rsp
  movsd  (%rdi),%xmm1
  cmp    $0x1,%ebx
  jle    L1
  lea    -0x2(%rbx),%eax
  lea    0x8(%rdi),%rsi
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(,%rax,8),%rdx
  movsd  %xmm1,(%rsp)
  call   <memmove@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  (%rsp),%xmm1
  mov    %rax,%rdi
L1:
  movsd  %xmm0,-0x8(%rdi,%rbx,8)
  add    $0x10,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double shiftRDdouble(double zIn, double z[], int N) {
  int i;
  double zOut;
  zOut = z[0];
  for (i = 0; i < N - 1; i++) {
    z[i] = z[i + 1];
  }
  z[N - 1] = zIn;
  return (zOut);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shiftRDdouble>:
  endbr64
  push   %rbx
  movslq %esi,%rbx
  sub    $0x10,%rsp
  movsd  (%rdi),%xmm1
  cmp    $0x1,%ebx
  jle    L8
  lea    -0x2(%rbx),%eax
  lea    0x8(%rdi),%rsi
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(,%rax,8),%rdx
  movsd  %xmm1,(%rsp)
  call   <memmove@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  (%rsp),%xmm1
  mov    %rax,%rdi
L8:
  movsd  %xmm0,-0x8(%rdi,%rbx,8)
  add    $0x10,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double shiftRDdouble(double zIn, double z[], int N) {
  int i;
  double zOut;
  zOut = z[0];
  for (i = 0; i < N - 1; i++) {
    z[i] = z[i + 1];
  }
  z[N - 1] = zIn;
  return (zOut);
}
```