ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<isPermissible>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%ecx
  test   %edx,%edx
  jle    L20
  movslq %esi,%rax
  shl    $0x5,%rax
  add    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rax,%rdx,4),%rdx
L87:
  cmpl   $0x1,(%rax)
  je     L33
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L87
L20:
  mov    %ecx,%eax
  not    %eax
  shr    $0x1f,%eax
  mov    %eax,%r10d
  mov    %ecx,%eax
  or     %esi,%eax
  js     L84
  movslq %esi,%rax
  movslq %ecx,%rdx
  lea    (%rdx,%rax,8),%rax
  lea    (%r9,%rax,4),%rdx
  mov    %esi,%eax
  mov    %ecx,%edi
  sub    %esi,%edi
L74:
  cmpl   $0x1,(%rdx)
  je     L78
  sub    $0x1,%eax
  sub    $0x24,%rdx
  mov    %edi,%r8d
  add    %eax,%r8d
  js     L84
  test   %eax,%eax
  jns    L74
L84:
  cmp    $0x7,%esi
  jg     L40
  test   %r10b,%r10b
  je     L40
  movslq %esi,%rax
  movslq %ecx,%rdx
  lea    (%rdx,%rax,8),%rax
  lea    (%r9,%rax,4),%rdx
  mov    %esi,%eax
L59:
  cmpl   $0x1,(%rdx)
  je     L106
  add    $0x1,%eax
  add    $0x1c,%rdx
  mov    %esi,%edi
  sub    %eax,%edi
  add    %ecx,%edi
  js     L96
  cmp    $0x7,%eax
  jle    L59
L96:
  mov    $0x1,%eax
  ret
L33:
  mov    $0x0,%eax
  ret
L78:
  mov    $0x0,%eax
  ret
L40:
  mov    $0x1,%eax
  ret
L106:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isPermissible(int board[8][8], int row, int column) {
  int x, y;
  for (y = 0; y < column; y++) {
    if (board[row][y] == 1) {
      return 0;
    }
  }
  for (x = row, y = column; x >= 0 && y >= 0; x--, y--) {
    if (board[x][y] == 1) {
      return 0;
    }
  }
  for (x = row, y = column; x <= 8 - 1 && y >= 0; x++, y--) {
    if (board[x][y] == 1) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isPermissible>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%ecx
  test   %edx,%edx
  jle    L99
  movslq %esi,%rax
  lea    -0x1(%rdx),%edx
  shl    $0x5,%rax
  add    %rdi,%rax
  lea    0x4(%rax,%rdx,4),%rdx
  jmp    L97
  nopl   0x0(%rax)
L125:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L99
L97:
  cmpl   $0x1,(%rax)
  jne    L125
L134:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L99:
  mov    %ecx,%eax
  not    %eax
  shr    $0x1f,%eax
  mov    %eax,%r10d
  mov    %ecx,%eax
  or     %esi,%eax
  js     L21
  movslq %ecx,%rdx
  movslq %esi,%rax
  mov    %ecx,%edi
  lea    (%rdx,%rax,8),%rax
  sub    %esi,%edi
  lea    (%r9,%rax,4),%rdx
  mov    %esi,%eax
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L136:
  sub    $0x1,%eax
  mov    %edi,%r8d
  sub    $0x24,%rdx
  add    %eax,%r8d
  js     L21
  test   %eax,%eax
  js     L21
L11:
  cmpl   $0x1,(%rdx)
  jne    L136
  jmp    L134
  nopw   0x0(%rax,%rax,1)
L21:
  cmp    $0x7,%esi
  jg     L117
  test   %r10b,%r10b
  je     L117
  movslq %ecx,%rdx
  movslq %esi,%rax
  lea    (%rdx,%rax,8),%rax
  lea    (%r9,%rax,4),%rdx
  mov    %esi,%eax
  jmp    L31
  nopl   0x0(%rax)
L140:
  add    $0x1,%eax
  mov    %esi,%edi
  add    $0x1c,%rdx
  sub    %eax,%edi
  add    %ecx,%edi
  js     L117
  cmp    $0x7,%eax
  jg     L117
L31:
  cmpl   $0x1,(%rdx)
  jne    L140
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L117:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isPermissible(int board[8][8], int row, int column) {
  int x, y;
  for (y = 0; y < column; y++) {
    if (board[row][y] == 1) {
      return 0;
    }
  }
  for (x = row, y = column; x >= 0 && y >= 0; x--, y--) {
    if (board[x][y] == 1) {
      return 0;
    }
  }
  for (x = row, y = column; x <= 8 - 1 && y >= 0; x++, y--) {
    if (board[x][y] == 1) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isPermissible>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%r8d
  test   %edx,%edx
  jle    L250
  movslq %esi,%rax
  shl    $0x5,%rax
  add    %rdi,%rax
  cmpl   $0x1,(%rax)
  je     L146
  cmp    $0x1,%edx
  je     L250
  cmpl   $0x1,0x4(%rax)
  je     L146
  cmp    $0x2,%edx
  je     L250
  cmpl   $0x1,0x8(%rax)
  je     L146
  cmp    $0x3,%edx
  je     L250
  cmpl   $0x1,0xc(%rax)
  je     L146
  cmp    $0x4,%edx
  je     L250
  cmpl   $0x1,0x10(%rax)
  je     L146
  cmp    $0x5,%edx
  je     L250
  cmpl   $0x1,0x14(%rax)
  je     L146
  cmp    $0x6,%edx
  je     L250
  cmpl   $0x1,0x18(%rax)
  je     L146
  cmp    $0x7,%edx
  je     L250
  cmpl   $0x1,0x1c(%rax)
  je     L146
  cmp    $0x8,%edx
  je     L250
  cmpl   $0x1,0x20(%rax)
  je     L146
  cmp    $0x9,%edx
  je     L250
  mov    $0x9,%ecx
  jmp    L154
  nopl   (%rax)
L71:
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jle    L250
L154:
  cmpl   $0x1,(%rax,%rcx,4)
  jne    L71
L146:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L250:
  mov    %edx,%eax
  not    %eax
  shr    $0x1f,%eax
  mov    %eax,%r10d
  mov    %edx,%eax
  or     %r8d,%eax
  js     L110
  movslq %edx,%rcx
  movslq %r8d,%rax
  mov    %edx,%esi
  lea    (%rcx,%rax,8),%rax
  sub    %r8d,%esi
  lea    (%r9,%rax,4),%rcx
  mov    %r8d,%eax
  jmp    L25
  nopl   0x0(%rax)
L307:
  sub    $0x1,%eax
  mov    %esi,%edi
  sub    $0x24,%rcx
  add    %eax,%edi
  js     L110
  test   %eax,%eax
  js     L110
L25:
  cmpl   $0x1,(%rcx)
  jne    L307
  jmp    L146
  nopl   0x0(%rax,%rax,1)
L110:
  cmp    $0x7,%r8d
  jg     L156
  test   %r10b,%r10b
  je     L156
  movslq %edx,%rcx
  movslq %r8d,%rax
  lea    (%rcx,%rax,8),%rax
  lea    (%r9,%rax,4),%rcx
  mov    %r8d,%eax
  jmp    L75
  xchg   %ax,%ax
L105:
  add    $0x1,%eax
  mov    %r8d,%esi
  add    $0x1c,%rcx
  sub    %eax,%esi
  add    %edx,%esi
  js     L156
  cmp    $0x7,%eax
  jg     L156
L75:
  cmpl   $0x1,(%rcx)
  jne    L105
  xor    %eax,%eax
  ret
  nopl   (%rax)
L156:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isPermissible(int board[8][8], int row, int column) {
  int x, y;
  for (y = 0; y < column; y++) {
    if (board[row][y] == 1) {
      return 0;
    }
  }
  for (x = row, y = column; x >= 0 && y >= 0; x--, y--) {
    if (board[x][y] == 1) {
      return 0;
    }
  }
  for (x = row, y = column; x <= 8 - 1 && y >= 0; x++, y--) {
    if (board[x][y] == 1) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L21
L3:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addq   $0x4,-0x38(%rbp)
L21:
  lea    -0x30(%rbp),%rax
  add    $0x28,%rax
  cmp    %rax,-0x38(%rbp)
  jb     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L39
L36:
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L39:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L36
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: %d

assistant: ```c
void main() {
  int a[10];
  int *p;
  for (p = a; p < (a + 10); p++)
    scanf("%d", p);
  printf("\n");
  p = a;
  for (int i = 0; i < 10; i++)
    printf("%d", *p++);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D2(%rip),%rbp
L20:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  lea    0x28(%rsp),%rax
  cmp    %rax,%rbx
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rbx
  lea    D2(%rip),%rbp
L19:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x28(%rsp),%rax
  cmp    %rax,%rbx
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: %d

assistant: ```c
void main() {
  int a[10];
  int *p;
  for (p = a; p < (a + 10); p++)
    scanf("%d", p);
  printf("\n");
  p = a;
  for (int i = 0; i < 10; i++)
    printf("%d", *p++);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r13
  mov    %rbx,%rbp
L15:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r13,%rbp
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  xchg   %ax,%ax
L24:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L24
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: %d

assistant: ```c
void main() {
  int a[10];
  int *p;
  for (p = a; p < (a + 10); p++)
    scanf("%d", p);
  printf("\n");
  p = a;
  for (int i = 0; i < 10; i++)
    printf("%d", *p++);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r13
  mov    %rbx,%rbp
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r13,%rbp
  jne    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  xchg   %ax,%ax
L25:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: %d

assistant: ```c
void main() {
  int a[10];
  int *p;
  for (p = a; p < (a + 10); p++)
    scanf("%d", p);
  printf("\n");
  p = a;
  for (int i = 0; i < 10; i++)
    printf("%d", *p++);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eloop_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int eloop_open(struct eloop *eloop) {
  (void)((eloop));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eloop_open>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int eloop_open(struct eloop *eloop) {
  (void)((eloop));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eloop_open>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int eloop_open(struct eloop *eloop) {
  (void)((eloop));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eloop_open>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int eloop_open(struct eloop *eloop) {
  (void)((eloop));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<setoid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L9
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  lea    D0(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: net.%s.debug

assistant: ```c
void setoid(char oid[], size_t oidlen, const char *wlan) {
  if (wlan)
    snprintf(oid, oidlen, "net.%s.debug", wlan);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setoid>:
  endbr64
  test   %rdx,%rdx
  je     L9
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  lea    D7(%rip),%rdx
  call   <snprintf@plt>
  add    $0x8,%rsp
  ret
L9:
  ret
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string

tool: D7: net.%s.debug

assistant: ```c
void setoid(char oid[], size_t oidlen, const char *wlan) {
  if (wlan)
    snprintf(oid, oidlen, "net.%s.debug", wlan);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setoid>:
  endbr64
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L5
  lea    D4(%rip),%rdx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: net.%s.debug

assistant: ```c
void setoid(char oid[], size_t oidlen, const char *wlan) {
  if (wlan)
    snprintf(oid, oidlen, "net.%s.debug", wlan);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<setoid>:
  endbr64
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L4
  lea    D9(%rip),%rdx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: D9: net.%s.debug

assistant: ```c
void setoid(char oid[], size_t oidlen, const char *wlan) {
  if (wlan)
    snprintf(oid, oidlen, "net.%s.debug", wlan);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L18:
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x2,-0xc(%rbp)
  jle    L18
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: string

tool: D18: pdiff

tool: D13: # c::native::%s


tool: D25: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "pdiff");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D1(%rip),%r13
  lea    D6(%rip),%r12
  lea    D29(%rip),%rbp
L5:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L5
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D6
type_infered: string
name: read_data
arguments: tag: D29
type_infered: string

tool: D1: pdiff

tool: D6: # c::native::%s


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "pdiff");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D8(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L3:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L3
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string

tool: D8: pdiff

tool: D2: # c::native::%s


tool: D16: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "pdiff");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D0(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L3:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L3
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string
name: disassemble_data
arguments: data_tag: D21
type_guessed: string
name: disassemble_data
arguments: data_tag: D23
type_guessed: string

tool: D0: pdiff

tool: D21: # c::native::%s


tool: D23: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "pdiff");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What is the c source code of the assembly code below?

```asm
<int64Destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <int64Clear@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void int64Destroy(int64_t *data) {
  int64Clear(data);
  free(data);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int64Destroy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <int64Clear@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void int64Destroy(int64_t *data) {
  int64Clear(data);
  free(data);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<int64Destroy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <int64Clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void int64Destroy(int64_t *data) {
  int64Clear(data);
  free(data);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<int64Destroy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <int64Clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void int64Destroy(int64_t *data) {
  int64Clear(data);
  free(data);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcasestr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L57
L7:
  cmpq   $0x0,-0x18(%rbp)
  je     L9
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L18
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    -0x20(%rbp),%rax
  jmp    L60
L18:
  movq   $0x0,-0x18(%rbp)
  jmp    L51
L9:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L51
  mov    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L51:
  addq   $0x1,-0x28(%rbp)
L57:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0x0,%eax
L60:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strcasestr(char *haystack, char *needle) {
  char *p, *startn = NULL, *np = NULL;
  for (p = haystack; *p != '\0'; ++p) {
    if (np != NULL) {
      if (toupper(*p) == toupper(*np)) {
        if (*++np == '\0') {
          return startn;
        }
      } else {
        np = NULL;
      }
    } else if (toupper(*p) == toupper(*needle)) {
      np = needle + 1;
      startn = p;
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcasestr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L41
  mov    %rsi,%r13
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  lea    0x1(%rsi),%r14
  jmp    L30
L52:
  lea    0x1(%rbp),%rax
  cmpb   $0x0,0x1(%rbp)
  je     L44
  mov    %rax,%rbp
  jmp    L80
L35:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %rax,%r15
  movsbl 0x0(%r13),%edi
  call   <toupper@plt>
  cmp    %rax,%r15
  cmove  %r14,%rbp
  cmove  %rbx,%r12
L80:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L1
L30:
  test   %rbp,%rbp
  je     L35
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %rax,%r15
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  cmp    %rax,%r15
  je     L52
  mov    $0x0,%ebp
  jmp    L80
L1:
  mov    $0x0,%r12d
L44:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  mov    $0x0,%r12d
  jmp    L44
```

assistant: ```c
char *strcasestr(char *haystack, char *needle) {
  char *p, *startn = NULL, *np = NULL;
  for (p = haystack; *p != '\0'; ++p) {
    if (np != NULL) {
      if (toupper(*p) == toupper(*np)) {
        if (*++np == '\0') {
          return startn;
        }
      } else {
        np = NULL;
      }
    } else if (toupper(*p) == toupper(*needle)) {
      np = needle + 1;
      startn = p;
    }
  }
  return NULL;
}
```