ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<packData>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movb   $0x23,(%rdi)
  add    $0x61,%edx
  mov    %dl,0x1(%rdi)
  mov    %sil,0x2(%rdi)
  test   %r8d,%r8d
  je     L63
  mov    %rcx,%r10
  mov    $0x0,%r9d
  mov    $0x3,%esi
  mov    $0x0,%r11d
  jmp    L39
L68:
  mov    %eax,%r9d
  mov    %r11d,%eax
  mov    %r11d,%ecx
  mov    $0x0,%r8d
L10:
  mov    %esi,%ebp
  mov    %edx,%ebx
  shr    $0x2,%bl
  add    $0x3d,%ebx
  mov    %bl,(%rdi,%rbp,1)
  lea    0x1(%rsi),%ebx
  shl    $0x4,%edx
  and    $0x30,%edx
  mov    %eax,%ebp
  shr    $0x4,%bpl
  or     %ebp,%edx
  add    $0x3d,%edx
  mov    %dl,(%rdi,%rbx,1)
  lea    0x3(%rsi),%edx
  lea    0x2(%rsi),%ebx
  shl    $0x2,%eax
  and    $0x3c,%eax
  mov    %ecx,%ebp
  shr    $0x6,%bpl
  or     %ebp,%eax
  add    $0x3d,%eax
  mov    %al,(%rdi,%rbx,1)
  add    $0x4,%esi
  mov    %edx,%eax
  and    $0x3f,%ecx
  add    $0x3d,%ecx
  mov    %cl,(%rdi,%rax,1)
  test   %r8d,%r8d
  je     L55
L39:
  lea    0x1(%r9),%eax
  movzbl %r9b,%edx
  movzbl (%r10,%rdx,1),%edx
  cmp    $0x1,%r8d
  je     L68
  lea    0x2(%r9),%ecx
  movzbl %al,%eax
  movzbl (%r10,%rax,1),%eax
  cmp    $0x2,%r8d
  je     L64
  add    $0x3,%r9d
  movzbl %cl,%ecx
  movzbl (%r10,%rcx,1),%ecx
  sub    $0x3,%r8d
  jmp    L10
L64:
  mov    %ecx,%r9d
  mov    %r11d,%ecx
  mov    $0x0,%r8d
  jmp    L10
L63:
  mov    $0x3,%esi
L55:
  call   <addCRC@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int packData(char *txBuffer, unsigned char cmd, unsigned char addr, unsigned char *snd, int len) {
  unsigned int pt = 0;
  unsigned char a, b, c;
  unsigned char ptr = 0;
  int length = 0;
  txBuffer[pt++] = '#';
  txBuffer[pt++] = 'a' + addr;
  txBuffer[pt++] = cmd;
  while (len) {
    if (len) {
      a = snd[ptr++];
      len--;
    } else
      a = 0;
    if (len) {
      b = snd[ptr++];
      len--;
    } else
      b = 0;
    if (len) {
      c = snd[ptr++];
      len--;
    } else
      c = 0;
    txBuffer[pt++] = '=' + (a >> 2);
    txBuffer[pt++] = '=' + (((a & 0x03) << 4) | ((b & 0xf0) >> 4));
    txBuffer[pt++] = '=' + (((b & 0x0f) << 2) | ((c & 0xc0) >> 6));
    txBuffer[pt++] = '=' + (c & 0x3f);
  }
  length = addCRC(txBuffer, pt);
  return length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<packData>:
  endbr64
  add    $0x61,%edx
  movb   $0x23,(%rdi)
  mov    %dl,0x1(%rdi)
  mov    %sil,0x2(%rdi)
  test   %r8d,%r8d
  je     L45
  push   %rbp
  mov    %rcx,%r10
  mov    $0x3,%esi
  xor    %ecx,%ecx
  push   %rbx
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl %dl,%edx
  lea    0x2(%rcx),%r11d
  movzbl (%r10,%rdx,1),%edx
  mov    %edx,%ebx
  shl    $0x2,%edx
  shr    $0x4,%bl
  and    $0x3c,%edx
  cmp    $0x2,%r8d
  je     L36
  movzbl %r11b,%r11d
  add    $0x3,%ecx
  sub    $0x3,%r8d
  movzbl (%r10,%r11,1),%r11d
  mov    %r11d,%r9d
  and    $0x3f,%r11d
  shr    $0x6,%r9b
  or     %edx,%r9d
  lea    0x3d(%r11),%edx
  add    $0x3d,%r9d
L2:
  mov    %eax,%r11d
  shl    $0x4,%eax
  mov    %esi,%ebp
  shr    $0x2,%r11b
  and    $0x30,%eax
  add    $0x3d,%r11d
  or     %ebx,%eax
  mov    %r11b,(%rdi,%rbp,1)
  add    $0x3d,%eax
  lea    0x1(%rsi),%r11d
  mov    %al,(%rdi,%r11,1)
  lea    0x3(%rsi),%eax
  lea    0x2(%rsi),%r11d
  add    $0x4,%esi
  mov    %r9b,(%rdi,%r11,1)
  mov    %dl,(%rdi,%rax,1)
  test   %r8d,%r8d
  je     L1
L3:
  movzbl %cl,%eax
  lea    0x1(%rcx),%edx
  movzbl (%r10,%rax,1),%eax
  cmp    $0x1,%r8d
  jne    L4
  mov    %edx,%ecx
  mov    $0x3d,%r9d
  mov    $0x3d,%edx
  xor    %ebx,%ebx
  xor    %r8d,%r8d
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L1:
  pop    %rbx
  pop    %rbp
  jmp    1050 <addCRC@plt>
  nopw   0x0(%rax,%rax,1)
L36:
  lea    0x3d(%rdx),%r9d
  mov    %r11d,%ecx
  mov    $0x3d,%edx
  xor    %r8d,%r8d
  jmp    L2
  nopl   0x0(%rax)
L45:
  mov    $0x3,%esi
  jmp    1050 <addCRC@plt>
```

assistant: ```c
int packData(char *txBuffer, unsigned char cmd, unsigned char addr, unsigned char *snd, int len) {
  unsigned int pt = 0;
  unsigned char a, b, c;
  unsigned char ptr = 0;
  int length = 0;
  txBuffer[pt++] = '#';
  txBuffer[pt++] = 'a' + addr;
  txBuffer[pt++] = cmd;
  while (len) {
    if (len) {
      a = snd[ptr++];
      len--;
    } else
      a = 0;
    if (len) {
      b = snd[ptr++];
      len--;
    } else
      b = 0;
    if (len) {
      c = snd[ptr++];
      len--;
    } else
      c = 0;
    txBuffer[pt++] = '=' + (a >> 2);
    txBuffer[pt++] = '=' + (((a & 0x03) << 4) | ((b & 0xf0) >> 4));
    txBuffer[pt++] = '=' + (((b & 0x0f) << 2) | ((c & 0xc0) >> 6));
    txBuffer[pt++] = '=' + (c & 0x3f);
  }
  length = addCRC(txBuffer, pt);
  return length;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<packData>:
  endbr64
  add    $0x61,%edx
  movb   $0x23,(%rdi)
  mov    %dl,0x1(%rdi)
  mov    %sil,0x2(%rdi)
  test   %r8d,%r8d
  je     L64
  push   %rbp
  mov    %rcx,%r10
  mov    $0x3,%esi
  xor    %ecx,%ecx
  push   %rbx
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L57:
  movzbl %dl,%edx
  lea    0x2(%rcx),%r11d
  movzbl (%r10,%rdx,1),%edx
  mov    %edx,%ebx
  shl    $0x2,%edx
  shr    $0x4,%bl
  and    $0x3c,%edx
  cmp    $0x2,%r8d
  je     L13
  movzbl %r11b,%r11d
  add    $0x3,%ecx
  sub    $0x3,%r8d
  movzbl (%r10,%r11,1),%r11d
  mov    %r11d,%r9d
  and    $0x3f,%r11d
  shr    $0x6,%r9b
  or     %edx,%r9d
  lea    0x3d(%r11),%edx
  add    $0x3d,%r9d
L14:
  mov    %eax,%r11d
  shl    $0x4,%eax
  mov    %esi,%ebp
  shr    $0x2,%r11b
  and    $0x30,%eax
  add    $0x3d,%r11d
  or     %ebx,%eax
  mov    %r11b,(%rdi,%rbp,1)
  add    $0x3d,%eax
  lea    0x1(%rsi),%r11d
  mov    %al,(%rdi,%r11,1)
  lea    0x3(%rsi),%eax
  lea    0x2(%rsi),%r11d
  add    $0x4,%esi
  mov    %r9b,(%rdi,%r11,1)
  mov    %dl,(%rdi,%rax,1)
  test   %r8d,%r8d
  je     L39
L11:
  movzbl %cl,%eax
  lea    0x1(%rcx),%edx
  movzbl (%r10,%rax,1),%eax
  cmp    $0x1,%r8d
  jne    L57
  mov    %edx,%ecx
  mov    $0x3d,%r9d
  mov    $0x3d,%edx
  xor    %ebx,%ebx
  xor    %r8d,%r8d
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L39:
  pop    %rbx
  pop    %rbp
  jmp    1050 <addCRC@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  lea    0x3d(%rdx),%r9d
  mov    %r11d,%ecx
  mov    $0x3d,%edx
  xor    %r8d,%r8d
  jmp    L14
  nopl   0x0(%rax)
L64:
  mov    $0x3,%esi
  jmp    1050 <addCRC@plt>
```

assistant: ```c
int packData(char *txBuffer, unsigned char cmd, unsigned char addr, unsigned char *snd, int len) {
  unsigned int pt = 0;
  unsigned char a, b, c;
  unsigned char ptr = 0;
  int length = 0;
  txBuffer[pt++] = '#';
  txBuffer[pt++] = 'a' + addr;
  txBuffer[pt++] = cmd;
  while (len) {
    if (len) {
      a = snd[ptr++];
      len--;
    } else
      a = 0;
    if (len) {
      b = snd[ptr++];
      len--;
    } else
      b = 0;
    if (len) {
      c = snd[ptr++];
      len--;
    } else
      c = 0;
    txBuffer[pt++] = '=' + (a >> 2);
    txBuffer[pt++] = '=' + (((a & 0x03) << 4) | ((b & 0xf0) >> 4));
    txBuffer[pt++] = '=' + (((b & 0x0f) << 2) | ((c & 0xc0) >> 6));
    txBuffer[pt++] = '=' + (c & 0x3f);
  }
  length = addCRC(txBuffer, pt);
  return length;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<splitStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L18
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x30(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void splitStr(char *src, const char *sep, char *des[], int *total) {
  int i = 0;
  char *token = NULL;
  i = 0;
  token = strtok(src, sep);
  while (token != NULL) {
    strcpy(des[i], token);
    token = strtok(NULL, sep);
    i++;
  }
  *total = i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<splitStr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  call   <strtok@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,%rsi
  mov    $0x1,%r13d
L5:
  mov    -0x8(%rbp,%r13,8),%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  mov    %r13d,%eax
  add    $0x1,%r13
  test   %rsi,%rsi
  jne    L5
L2:
  mov    %eax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    $0x0,%eax
  jmp    L2
```

assistant: ```c
void splitStr(char *src, const char *sep, char *des[], int *total) {
  int i = 0;
  char *token = NULL;
  i = 0;
  token = strtok(src, sep);
  while (token != NULL) {
    strcpy(des[i], token);
    token = strtok(NULL, sep);
    i++;
  }
  *total = i;
}
```
user: What is the c source code of the assembly code below?

```asm
<splitStr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rsi
  mov    $0x1,%r13d
  nopw   0x0(%rax,%rax,1)
L13:
  mov    -0x8(%rbp,%r13,8),%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  mov    %r13d,%eax
  add    $0x1,%r13
  test   %rsi,%rsi
  jne    L13
  mov    %eax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  mov    %eax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void splitStr(char *src, const char *sep, char *des[], int *total) {
  int i = 0;
  char *token = NULL;
  i = 0;
  token = strtok(src, sep);
  while (token != NULL) {
    strcpy(des[i], token);
    token = strtok(NULL, sep);
    i++;
  }
  *total = i;
}
```
user: What is the c source code of the assembly code below?

```asm
<splitStr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L16
  mov    %rax,%rsi
  mov    $0x1,%r13d
  nopw   0x0(%rax,%rax,1)
L19:
  mov    -0x8(%rbp,%r13,8),%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  mov    %r13d,%eax
  add    $0x1,%r13
  test   %rsi,%rsi
  jne    L19
  mov    %eax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  mov    %eax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void splitStr(char *src, const char *sep, char *des[], int *total) {
  int i = 0;
  char *token = NULL;
  i = 0;
  token = strtok(src, sep);
  while (token != NULL) {
    strcpy(des[i], token);
    token = strtok(NULL, sep);
    i++;
  }
  *total = i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrealpath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <xstrdup@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dirname@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <realpath@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <xbasename@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  lea    D3(%rip),%rdx
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <concat@plt>
  mov    %rax,-0x20(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string

tool: D3: /

assistant: ```c
char *xrealpath(const char *path) {
  char *dirc = xstrdup(path);
  char *dname = dirname(dirc);
  char *absdir = realpath(dname, NULL);
  char *abstarget = NULL;
  if (absdir)
    abstarget = concat(3, absdir, "/", xbasename(path));
  free(dirc);
  free(absdir);
  return abstarget;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrealpath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <xstrdup@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <dirname@plt>
  mov    %rax,%rdi
  mov    $0x0,%esi
  call   <realpath@plt>
  mov    %rax,%rbx
  mov    %rax,%r13
  test   %rax,%rax
  je     L3
  mov    %r12,%rdi
  call   <xbasename@plt>
  mov    %eax,%ecx
  lea    D7(%rip),%rdx
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <concat@plt>
  mov    %rax,%r13
L3:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: /

assistant: ```c
char *xrealpath(const char *path) {
  char *dirc = xstrdup(path);
  char *dname = dirname(dirc);
  char *absdir = realpath(dname, NULL);
  char *abstarget = NULL;
  if (absdir)
    abstarget = concat(3, absdir, "/", xbasename(path));
  free(dirc);
  free(absdir);
  return abstarget;
}
```
user: What is the c source code of the assembly code below:

```asm
<xrealpath>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <xstrdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <dirname@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <realpath@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
  mov    %r13,%rdi
  call   <xbasename@plt>
  lea    D2(%rip),%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  mov    %eax,%ecx
  call   <concat@plt>
  mov    %rax,%r14
L6:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: /

assistant: ```c
char *xrealpath(const char *path) {
  char *dirc = xstrdup(path);
  char *dname = dirname(dirc);
  char *absdir = realpath(dname, NULL);
  char *abstarget = NULL;
  if (absdir)
    abstarget = concat(3, absdir, "/", xbasename(path));
  free(dirc);
  free(absdir);
  return abstarget;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrealpath>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <xstrdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <dirname@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <realpath@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L1
  mov    %r13,%rdi
  call   <xbasename@plt>
  lea    D7(%rip),%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  mov    %eax,%ecx
  call   <concat@plt>
  mov    %rax,%r14
L1:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string

tool: D7: /

assistant: ```c
char *xrealpath(const char *path) {
  char *dirc = xstrdup(path);
  char *dname = dirname(dirc);
  char *absdir = realpath(dname, NULL);
  char *abstarget = NULL;
  if (absdir)
    abstarget = concat(3, absdir, "/", xbasename(path));
  free(dirc);
  free(absdir);
  return abstarget;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<drawFrame1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <_vClear@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L16:
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L3:
  mov    $0xf,%esi
  mov    $0x20,%edi
  call   <_vWriteFormat@plt>
  addl   $0x1,-0x8(%rbp)
L30:
  cmpl   $0x4f,-0x8(%rbp)
  jle    L3
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0x18,-0x4(%rbp)
  jle    L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void drawFrame1() {
  int x, y;
  _vClear();
  for (y = 0; y < 25; y++) {
    for (x = 0; x < 80; x++) {
      _vWriteFormat(' ', 0x00 | 0x0F);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<drawFrame1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <_vClear@plt>
  mov    $0x19,%ebp
L9:
  mov    $0x50,%ebx
L2:
  mov    $0xf,%esi
  mov    $0x20,%edi
  call   <_vWriteFormat@plt>
  sub    $0x1,%ebx
  jne    L2
  sub    $0x1,%ebp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drawFrame1() {
  int x, y;
  _vClear();
  for (y = 0; y < 25; y++) {
    for (x = 0; x < 80; x++) {
      _vWriteFormat(' ', 0x00 | 0x0F);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<drawFrame1>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    $0x19,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <_vClear@plt>
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0x50,%ebx
  nopl   (%rax)
L19:
  mov    $0xf,%esi
  mov    $0x20,%edi
  call   <_vWriteFormat@plt>
  sub    $0x1,%ebx
  jne    L19
  sub    $0x1,%ebp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drawFrame1() {
  int x, y;
  _vClear();
  for (y = 0; y < 25; y++) {
    for (x = 0; x < 80; x++) {
      _vWriteFormat(' ', 0x00 | 0x0F);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drawFrame1>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    $0x19,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <_vClear@plt>
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    $0x50,%ebx
  nopl   (%rax)
L8:
  mov    $0xf,%esi
  mov    $0x20,%edi
  call   <_vWriteFormat@plt>
  sub    $0x1,%ebx
  jne    L8
  sub    $0x1,%ebp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drawFrame1() {
  int x, y;
  _vClear();
  for (y = 0; y < 25; y++) {
    for (x = 0; x < 80; x++) {
      _vWriteFormat(' ', 0x00 | 0x0F);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_stackable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x36,-0x4(%rbp)
  jg     L113
  mov    $0x1,%eax
  jmp    L182
L113:
  cmpl   $0x3c,-0x4(%rbp)
  jne    L132
  mov    $0x1,%eax
  jmp    L182
L132:
  cmpl   $0x45,-0x4(%rbp)
  jne    L33
  mov    $0x1,%eax
  jmp    L182
L33:
  cmpl   $0x48,-0x4(%rbp)
  jne    L82
  mov    $0x1,%eax
  jmp    L182
L82:
  cmpl   $0x4b,-0x4(%rbp)
  jne    L118
  mov    $0x1,%eax
  jmp    L182
L118:
  cmpl   $0x4d,-0x4(%rbp)
  jne    L34
  mov    $0x1,%eax
  jmp    L182
L34:
  cmpl   $0x56,-0x4(%rbp)
  jne    L93
  mov    $0x1,%eax
  jmp    L182
L93:
  cmpl   $0x57,-0x4(%rbp)
  jne    L26
  mov    $0x1,%eax
  jmp    L182
L26:
  cmpl   $0x59,-0x4(%rbp)
  jne    L131
  mov    $0x1,%eax
  jmp    L182
L131:
  cmpl   $0x81,-0x4(%rbp)
  jne    L10
  mov    $0x1,%eax
  jmp    L182
L10:
  mov    $0x0,%eax
L182:
  pop    %rbp
  ret
```

assistant: ```c
int is_stackable(int symbology) {
  if (symbology < 55) {
    return 1;
  }
  if (symbology == 60) {
    return 1;
  }
  if (symbology == 69) {
    return 1;
  }
  if (symbology == 72) {
    return 1;
  }
  if (symbology == 75) {
    return 1;
  }
  if (symbology == 77) {
    return 1;
  }
  if (symbology == 86) {
    return 1;
  }
  if (symbology == 87) {
    return 1;
  }
  if (symbology == 89) {
    return 1;
  }
  if (symbology == 129) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_stackable>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x36,%edi
  jle    L6
  cmp    $0x3c,%edi
  je     L18
  lea    -0x45(%rdi),%ecx
  cmp    $0x3c,%ecx
  ja     L9
  movabs $0x1000000000160149,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L18:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
L6:
  ret
```

assistant: ```c
int is_stackable(int symbology) {
  if (symbology < 55) {
    return 1;
  }
  if (symbology == 60) {
    return 1;
  }
  if (symbology == 69) {
    return 1;
  }
  if (symbology == 72) {
    return 1;
  }
  if (symbology == 75) {
    return 1;
  }
  if (symbology == 77) {
    return 1;
  }
  if (symbology == 86) {
    return 1;
  }
  if (symbology == 87) {
    return 1;
  }
  if (symbology == 89) {
    return 1;
  }
  if (symbology == 129) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_stackable>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x36,%edi
  jle    L1
  sub    $0x3c,%edi
  xor    %eax,%eax
  cmp    $0x45,%edi
  jbe    L4
L1:
  ret
  nopl   0x0(%rax)
L4:
  lea    D6(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: 

assistant: ```c
int is_stackable(int symbology) {
  if (symbology < 55) {
    return 1;
  }
  if (symbology == 60) {
    return 1;
  }
  if (symbology == 69) {
    return 1;
  }
  if (symbology == 72) {
    return 1;
  }
  if (symbology == 75) {
    return 1;
  }
  if (symbology == 77) {
    return 1;
  }
  if (symbology == 86) {
    return 1;
  }
  if (symbology == 87) {
    return 1;
  }
  if (symbology == 89) {
    return 1;
  }
  if (symbology == 129) {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_stackable>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x36,%edi
  jle    L18
  sub    $0x3c,%edi
  xor    %eax,%eax
  cmp    $0x45,%edi
  jbe    L11
L18:
  ret
  nopl   0x0(%rax)
L11:
  lea    D8(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string

tool: D8: 

assistant: ```c
int is_stackable(int symbology) {
  if (symbology < 55) {
    return 1;
  }
  if (symbology == 60) {
    return 1;
  }
  if (symbology == 69) {
    return 1;
  }
  if (symbology == 72) {
    return 1;
  }
  if (symbology == 75) {
    return 1;
  }
  if (symbology == 77) {
    return 1;
  }
  if (symbology == 86) {
    return 1;
  }
  if (symbology == 87) {
    return 1;
  }
  if (symbology == 89) {
    return 1;
  }
  if (symbology == 129) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L15
  mov    $0x1,%eax
  jmp    L9
L15:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fact>
  imul   -0x4(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int fact(int a) {
  if (a < 2) {
    return 1;
  } else {
    return a * fact(a - 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jg     L2
  ret
L2:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fact>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fact(int a) {
  if (a < 2) {
    return 1;
  } else {
    return a * fact(a - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L9
  xchg   %ax,%ax
L11:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L11
L9:
  ret
```

assistant: ```c
int fact(int a) {
  if (a < 2) {
    return 1;
  } else {
    return a * fact(a - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L8
  xchg   %ax,%ax
L17:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L17
L8:
  ret
```

assistant: ```c
int fact(int a) {
  if (a < 2) {
    return 1;
  } else {
    return a * fact(a - 1);
  }
}
```