ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mkstemp>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <_gettemp@plt>
  test   %eax,%eax
  je     L2
  mov    0x4(%rsp),%eax
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  ret
  nop
L2:
  mov    $0xffffffff,%eax
  jmp    L22
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
mkstemp(as) char *as;
{
  int fd;
  return (_gettemp(as, &fd) ? fd : -1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_add_prime_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L34
L31:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <ft_is_prime@plt>
  cmp    $0x1,%eax
  jne    L9
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L34
L9:
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L31
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ft_add_prime_sum(int nb) {
  int i;
  int sum;
  sum = 0;
  i = 2;
  while (i <= nb) {
    if (ft_is_prime(i) == 1) {
      sum += i;
      i++;
    } else
      i++;
  }
  return (sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_add_prime_sum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L9
  mov    %edi,%r12d
  mov    $0x3,%ebx
  mov    $0x0,%r13d
  jmp    L38
L0:
  add    $0x1,%ebx
  cmp    %eax,%r12d
  jl     L20
L38:
  lea    -0x1(%rbx),%ebp
  mov    %ebp,%edi
  call   <ft_is_prime@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  cmp    $0x1,%edx
  jne    L0
  add    %ebp,%r13d
  jmp    L0
L9:
  mov    $0x0,%r13d
L20:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ft_add_prime_sum(int nb) {
  int i;
  int sum;
  sum = 0;
  i = 2;
  while (i <= nb) {
    if (ft_is_prime(i) == 1) {
      sum += i;
      i++;
    } else
      i++;
  }
  return (sum);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_add_prime_sum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L16
  mov    %edi,%ebp
  xor    %r12d,%r12d
  mov    $0x2,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  call   <ft_is_prime@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  add    $0x1,%ebx
  add    %r12d,%eax
  cmp    $0x1,%r8d
  cmove  %eax,%r12d
  cmp    %ebx,%ebp
  jge    L8
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ft_add_prime_sum(int nb) {
  int i;
  int sum;
  sum = 0;
  i = 2;
  while (i <= nb) {
    if (ft_is_prime(i) == 1) {
      sum += i;
      i++;
    } else
      i++;
  }
  return (sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_add_prime_sum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L14
  mov    %edi,%ebp
  xor    %r12d,%r12d
  mov    $0x2,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  call   <ft_is_prime@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  add    $0x1,%ebx
  add    %r12d,%eax
  cmp    $0x1,%r8d
  cmove  %eax,%r12d
  cmp    %ebx,%ebp
  jge    L7
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ft_add_prime_sum(int nb) {
  int i;
  int sum;
  sum = 0;
  i = 2;
  while (i <= nb) {
    if (ft_is_prime(i) == 1) {
      sum += i;
      i++;
    } else
      i++;
  }
  return (sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L11
  mov    $0x1,%eax
  jmp    L0
L11:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int isNumber(char *i) {
  switch (*i) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    return 1;
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isNumber>:
  endbr64
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isNumber(char *i) {
  switch (*i) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    return 1;
  default:
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isNumber>:
  endbr64
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isNumber(char *i) {
  switch (*i) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    return 1;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isNumber>:
  endbr64
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isNumber(char *i) {
  switch (*i) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    return 1;
  default:
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SetStateDelayUnattached>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <SetStateUnattached@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SetStateDelayUnattached(void) {
  SetStateUnattached();
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SetStateDelayUnattached>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <SetStateUnattached@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void SetStateDelayUnattached(void) {
  SetStateUnattached();
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SetStateDelayUnattached>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <SetStateUnattached@plt>
```

assistant: ```c
void SetStateDelayUnattached(void) {
  SetStateUnattached();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SetStateDelayUnattached>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <SetStateUnattached@plt>
```

assistant: ```c
void SetStateDelayUnattached(void) {
  SetStateUnattached();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
```

assistant: ```c
int main(int argc, char **argv) {
  switch (argc) {
  case 1:
    __builtin_unreachable();
  case 4:
    __builtin_unreachable();
  default:
    __builtin_unreachable();
  }
  return 10;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
```

assistant: ```c
int main(int argc, char **argv) {
  switch (argc) {
  case 1:
    __builtin_unreachable();
  case 4:
    __builtin_unreachable();
  default:
    __builtin_unreachable();
  }
  return 10;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
```

assistant: ```c
int main(int argc, char **argv) {
  switch (argc) {
  case 1:
    __builtin_unreachable();
  case 4:
    __builtin_unreachable();
  default:
    __builtin_unreachable();
  }
  return 10;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
```

assistant: ```c
int main(int argc, char **argv) {
  switch (argc) {
  case 1:
    __builtin_unreachable();
  case 4:
    __builtin_unreachable();
  default:
    __builtin_unreachable();
  }
  return 10;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ExportA@plt>
  mov    $0x0,%eax
  call   <ExportB@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  ExportA();
  ExportB();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ExportA@plt>
  mov    $0x0,%eax
  call   <ExportB@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ExportA();
  ExportB();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ExportA@plt>
  xor    %eax,%eax
  call   <ExportB@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ExportA();
  ExportB();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ExportA@plt>
  xor    %eax,%eax
  call   <ExportB@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ExportA();
  ExportB();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HexDigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %al,-0x24(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movsbl -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  jmp    L5
L23:
  movsbl -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L21
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L5
L21:
  mov    $0x0,%eax
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D5
type: string

tool: D14: 0123456789ABCDEF

tool: D5: 0123456789abcdef

assistant: ```c
int HexDigit(char hex) {
  const char *Digits = "0123456789ABCDEF";
  const char *digits = "0123456789abcdef";
  char *ofs = strchr(digits, hex);
  if (ofs) {
    return ofs - digits;
  }
  ofs = strchr(Digits, hex);
  if (ofs) {
    return ofs - Digits;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<HexDigit>:
  endbr64
  push   %rbx
  movsbl %dil,%ebx
  mov    %ebx,%esi
  lea    D39(%rip),%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L22
  lea    D39(%rip),%rdx
  sub    %edx,%eax
L1:
  pop    %rbx
  ret
L22:
  mov    %ebx,%esi
  lea    D36(%rip),%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L1
  lea    D36(%rip),%rcx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L1
```

tool_calls: name: read_data
arguments: tag: D39
type_guessed: string
name: read_data
arguments: tag: D36
type_guessed: string

tool: D39: 0123456789abcdef

tool: D36: 0123456789ABCDEF

assistant: ```c
int HexDigit(char hex) {
  const char *Digits = "0123456789ABCDEF";
  const char *digits = "0123456789abcdef";
  char *ofs = strchr(digits, hex);
  if (ofs) {
    return ofs - digits;
  }
  ofs = strchr(Digits, hex);
  if (ofs) {
    return ofs - Digits;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<HexDigit>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  lea    D12(%rip),%rbx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L1:
  lea    D19(%rip),%rbx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D19
type: string

tool: D12: 0123456789abcdef

tool: D19: 0123456789ABCDEF

assistant: ```c
int HexDigit(char hex) {
  const char *Digits = "0123456789ABCDEF";
  const char *digits = "0123456789abcdef";
  char *ofs = strchr(digits, hex);
  if (ofs) {
    return ofs - digits;
  }
  ofs = strchr(Digits, hex);
  if (ofs) {
    return ofs - Digits;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HexDigit>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  lea    D1(%rip),%rbx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  add    $0x8,%rsp
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L5:
  lea    D12(%rip),%rbx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D12
datatype: string

tool: D1: 0123456789abcdef

tool: D12: 0123456789ABCDEF

assistant: ```c
int HexDigit(char hex) {
  const char *Digits = "0123456789ABCDEF";
  const char *digits = "0123456789abcdef";
  char *ofs = strchr(digits, hex);
  if (ofs) {
    return ofs - digits;
  }
  ofs = strchr(Digits, hex);
  if (ofs) {
    return ofs - Digits;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char str[], int length) {
  int start = 0;
  int end = length - 1;
  while (start < end) {
    char tmp = str[end];
    str[end] = str[start];
    str[start] = tmp;
    start++;
    end--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L3
  movslq %esi,%rsi
  mov    $0x0,%eax
L15:
  movzbl (%rdi,%rsi,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L15
L3:
  ret
```

assistant: ```c
void reverse(char str[], int length) {
  int start = 0;
  int end = length - 1;
  while (start < end) {
    char tmp = str[end];
    str[end] = str[start];
    str[start] = tmp;
    start++;
    end--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L4
  movslq %esi,%rsi
  xor    %eax,%eax
L6:
  movzbl (%rdi,%rsi,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %esi,%eax
  jl     L6
L4:
  ret
```

assistant: ```c
void reverse(char str[], int length) {
  int start = 0;
  int end = length - 1;
  while (start < end) {
    char tmp = str[end];
    str[end] = str[start];
    str[start] = tmp;
    start++;
    end--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L18
  movslq %esi,%rsi
  xor    %eax,%eax
L12:
  movzbl (%rdi,%rsi,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L12
L18:
  ret
```

assistant: ```c
void reverse(char str[], int length) {
  int start = 0;
  int end = length - 1;
  while (start < end) {
    char tmp = str[end];
    str[end] = str[start];
    str[start] = tmp;
    start++;
    end--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pci_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <pci_check_direct@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pci_init(void) {
  int result;
  result = pci_check_direct();
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pci_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <pci_check_direct@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pci_init(void) {
  int result;
  result = pci_check_direct();
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pci_init>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <pci_check_direct@plt>
```

assistant: ```c
int pci_init(void) {
  int result;
  result = pci_check_direct();
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pci_init>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <pci_check_direct@plt>
```

assistant: ```c
int pci_init(void) {
  int result;
  result = pci_check_direct();
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<deallocate_protected_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <getpagesize@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <munmap@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: munmap

assistant: ```c
void deallocate_protected_space(char *p, int size) {
  int page = getpagesize();
  int status;
  int aligned_size = ((size + page - 1) / page) * page;
  status = munmap(p - page, aligned_size + 2 * page);
  if (status != 0) {
    perror("munmap");
    exit(status);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<deallocate_protected_space>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <getpagesize@plt>
  mov    %eax,%ecx
  lea    -0x1(%rax,%rbp,1),%eax
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  lea    (%rax,%rcx,2),%esi
  movslq %ecx,%rcx
  sub    %rcx,%rbx
  mov    %rbx,%rdi
  call   <munmap@plt>
  test   %eax,%eax
  jne    L10
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %eax,%ebx
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D2: munmap

assistant: ```c
void deallocate_protected_space(char *p, int size) {
  int page = getpagesize();
  int status;
  int aligned_size = ((size + page - 1) / page) * page;
  status = munmap(p - page, aligned_size + 2 * page);
  if (status != 0) {
    perror("munmap");
    exit(status);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<deallocate_protected_space>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <getpagesize@plt>
  movslq %eax,%rcx
  lea    -0x1(%rcx,%rbp,1),%eax
  sub    %rcx,%rbx
  cltd
  mov    %rbx,%rdi
  idiv   %ecx
  imul   %ecx,%eax
  lea    (%rax,%rcx,2),%esi
  call   <munmap@plt>
  test   %eax,%eax
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  lea    D8(%rip),%rdi
  mov    %eax,%ebp
  call   <perror@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: munmap

assistant: ```c
void deallocate_protected_space(char *p, int size) {
  int page = getpagesize();
  int status;
  int aligned_size = ((size + page - 1) / page) * page;
  status = munmap(p - page, aligned_size + 2 * page);
  if (status != 0) {
    perror("munmap");
    exit(status);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<deallocate_protected_space>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <getpagesize@plt>
  movslq %eax,%rcx
  lea    -0x1(%rcx,%rbp,1),%eax
  sub    %rcx,%rbx
  cltd
  mov    %rbx,%rdi
  idiv   %ecx
  imul   %ecx,%eax
  lea    (%rax,%rcx,2),%esi
  call   <munmap@plt>
  test   %eax,%eax
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  lea    D0(%rip),%rdi
  mov    %eax,%ebp
  call   <perror@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: munmap

assistant: ```c
void deallocate_protected_space(char *p, int size) {
  int page = getpagesize();
  int status;
  int aligned_size = ((size + page - 1) / page) * page;
  status = munmap(p - page, aligned_size + 2 * page);
  if (status != 0) {
    perror("munmap");
    exit(status);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<t1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1004,-0x4(%rbp)
  je     L7
  mov    $0x0,%eax
  call   <abort@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void t1(int x) {
  if (x != 4100)
    abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<t1>:
  endbr64
  cmp    $0x1004,%edi
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void t1(int x) {
  if (x != 4100)
    abort();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<t1>:
  endbr64
  cmp    $0x1004,%edi
  jne    L4
  ret
  nopl   (%rax)
L4:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void t1(int x) {
  if (x != 4100)
    abort();
}
```
user: What is the c source code of the assembly code below:

```asm
<t1>:
  endbr64
  cmp    $0x1004,%edi
  jne    L8
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void t1(int x) {
  if (x != 4100)
    abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sca_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    D24(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L10
L15:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    %eax,-0x4(%rbp)
L10:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L1
  mov    D24(%rip),%rax
  mov    (%rax),%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L15
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sca_close(int FileDescriptor) {
  int value;
  value = -1;
  errno = EINTR;
  while (value == -1 && errno == EINTR) {
    value = close(FileDescriptor);
  }
  return (value);
}
```