ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  mov    $0xa,%edx
  mov    %rbx,%rsi
  sub    $0x30,%rsp
  movdqa D29(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  xor    %eax,%eax
  movl   $0x0,0x18(%rsp)
  movaps %xmm0,(%rsp)
  movq   $0x74736574,0x10(%rsp)
  mov    %ax,0x1c(%rsp)
  call   <strtoul@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%rsi
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type_guessed: byte[16]
name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: {"D29": [0x32,0x30,0x33,0x30,0x33,0x30,0x30,0x20,0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20]}

tool: D10: The number(unsigned long integer) is %lu


tool: D4: String part is |%s|


assistant: ```c
int main() {
  char str[30] = "2030300 This is test";
  char **ptr;
  long ret;
  ret = strtoul(str, ptr, 10);
  printf("The number(unsigned long integer) is %lu\n", ret);
  printf("String part is |%s|\n", *ptr);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  mov    $0xa,%edx
  mov    %rbx,%rsi
  sub    $0x30,%rsp
  movdqa D23(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  xor    %eax,%eax
  movl   $0x0,0x18(%rsp)
  movaps %xmm0,(%rsp)
  movq   $0x74736574,0x10(%rsp)
  mov    %ax,0x1c(%rsp)
  call   <strtoul@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%rsi
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: {"D23": [0x32,0x30,0x33,0x30,0x33,0x30,0x30,0x20,0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20]}

tool: D7: The number(unsigned long integer) is %lu


tool: D9: String part is |%s|


assistant: ```c
int main() {
  char str[30] = "2030300 This is test";
  char **ptr;
  long ret;
  ret = strtoul(str, ptr, 10);
  printf("The number(unsigned long integer) is %lu\n", ret);
  printf("String part is |%s|\n", *ptr);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eliminar_espacios>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  jmp    L11
L19:
  cmpb   $0x20,-0x11(%rbp)
  je     L29
  mov    -0x10(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
L29:
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
L11:
  cmpb   $0x0,-0x11(%rbp)
  jne    L19
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *eliminar_espacios(char *texto) {
  char *auxiliar, *reserva;
  auxiliar = (char *)malloc(sizeof(char));
  reserva = auxiliar;
  char c = *texto;
  while (c != '\0') {
    if (c != ' ') {
      *auxiliar = c;
      auxiliar++;
    }
    texto++;
    c = *texto;
  }
  texto = reserva;
  return reserva;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eliminar_espacios>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L24
  mov    %rax,%rcx
  jmp    L47
L21:
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L24
L47:
  cmp    $0x20,%dl
  je     L21
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  jmp    L21
L24:
  pop    %rbx
  ret
```

assistant: ```c
char *eliminar_espacios(char *texto) {
  char *auxiliar, *reserva;
  auxiliar = (char *)malloc(sizeof(char));
  reserva = auxiliar;
  char c = *texto;
  while (c != '\0') {
    if (c != ' ') {
      *auxiliar = c;
      auxiliar++;
    }
    texto++;
    c = *texto;
  }
  texto = reserva;
  return reserva;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eliminar_espacios>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L24
  mov    %rax,%rcx
  nopl   0x0(%rax)
L13:
  cmp    $0x20,%dl
  je     L28
  mov    %dl,(%rcx)
  add    $0x1,%rcx
L28:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  jne    L13
L24:
  pop    %rbx
  ret
```

assistant: ```c
char *eliminar_espacios(char *texto) {
  char *auxiliar, *reserva;
  auxiliar = (char *)malloc(sizeof(char));
  reserva = auxiliar;
  char c = *texto;
  while (c != '\0') {
    if (c != ' ') {
      *auxiliar = c;
      auxiliar++;
    }
    texto++;
    c = *texto;
  }
  texto = reserva;
  return reserva;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<eliminar_espacios>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L23
  mov    %rax,%rcx
  nopl   0x0(%rax)
L13:
  cmp    $0x20,%dl
  je     L11
  add    $0x1,%rbx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L13
L23:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  jne    L13
  pop    %rbx
  ret
```

assistant: ```c
char *eliminar_espacios(char *texto) {
  char *auxiliar, *reserva;
  auxiliar = (char *)malloc(sizeof(char));
  reserva = auxiliar;
  char c = *texto;
  while (c != '\0') {
    if (c != ' ') {
      *auxiliar = c;
      auxiliar++;
    }
    texto++;
    c = *texto;
  }
  texto = reserva;
  return reserva;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rdbuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L38
L22:
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  sub    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L32
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L32:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L38
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L38:
  cmpq   $0x0,-0x8(%rbp)
  jne    L22
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D10
type: string

tool: D1: Unexpected EOF

tool: D10: Error writing

assistant: ```c
void rdbuf(FILE *fd, void *buf, size_t sz) {
  size_t n;
  n = sz;
  while (n > 0) {
    n -= fread(buf, 1, n, fd);
    if (feof(fd))
      die("Unexpected EOF");
    if (ferror(fd))
      die("Error writing");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rdbuf>:
  endbr64
  test   %rdx,%rdx
  je     L20
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  lea    D5(%rip),%r14
  lea    D19(%rip),%r13
  jmp    L50
L16:
  mov    %r14,%rdi
  call   <die@plt>
  jmp    L62
L5:
  test   %rbx,%rbx
  je     L54
L50:
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  sub    %rax,%rbx
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L16
L62:
  mov    %rbp,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L5
  mov    %r13,%rdi
  call   <die@plt>
  jmp    L5
L54:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string

tool: D5: Unexpected EOF

tool: D19: Error writing

assistant: ```c
void rdbuf(FILE *fd, void *buf, size_t sz) {
  size_t n;
  n = sz;
  while (n > 0) {
    n -= fread(buf, 1, n, fd);
    if (feof(fd))
      die("Unexpected EOF");
    if (ferror(fd))
      die("Error writing");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rdbuf>:
  endbr64
  test   %rdx,%rdx
  je     L21
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L57
  xchg   %ax,%ax
L52:
  mov    %rbp,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L40
L1:
  test   %rbx,%rbx
  je     L42
L57:
  mov    %rbx,%rdx
  mov    %r12,%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    %rbp,%rdi
  sub    %rax,%rbx
  call   <feof@plt>
  test   %rax,%rax
  je     L52
  mov    %r14,%rdi
  call   <die@plt>
  mov    %rbp,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L1
L40:
  mov    %r13,%rdi
  call   <die@plt>
  test   %rbx,%rbx
  jne    L57
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D14
type_guessed: string

tool: D19: Unexpected EOF

tool: D14: Error writing

assistant: ```c
void rdbuf(FILE *fd, void *buf, size_t sz) {
  size_t n;
  n = sz;
  while (n > 0) {
    n -= fread(buf, 1, n, fd);
    if (feof(fd))
      die("Unexpected EOF");
    if (ferror(fd))
      die("Error writing");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rdbuf>:
  endbr64
  test   %rdx,%rdx
  je     L2
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L18
  xchg   %ax,%ax
L65:
  mov    %rbp,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L16
L47:
  test   %rbx,%rbx
  je     L56
L18:
  mov    %rbx,%rdx
  mov    %r12,%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    %rbp,%rdi
  sub    %rax,%rbx
  call   <feof@plt>
  test   %rax,%rax
  je     L65
  mov    %r14,%rdi
  call   <die@plt>
  mov    %rbp,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L47
L16:
  mov    %r13,%rdi
  call   <die@plt>
  test   %rbx,%rbx
  jne    L18
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
data_type: string
name: read_data
arguments: data_label: D6
data_type: string

tool: D10: Unexpected EOF

tool: D6: Error writing

assistant: ```c
void rdbuf(FILE *fd, void *buf, size_t sz) {
  size_t n;
  n = sz;
  while (n > 0) {
    n -= fread(buf, 1, n, fd);
    if (feof(fd))
      die("Unexpected EOF");
    if (ferror(fd))
      die("Error writing");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_yajl_start_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: map open '{'


assistant: ```c
int test_yajl_start_map(void *ctx) {
  printf("map open '{'\n");
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_yajl_start_map>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string

tool: D5: map open '{'


assistant: ```c
int test_yajl_start_map(void *ctx) {
  printf("map open '{'\n");
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_yajl_start_map>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: map open '{'


assistant: ```c
int test_yajl_start_map(void *ctx) {
  printf("map open '{'\n");
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_yajl_start_map>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: map open '{'


assistant: ```c
int test_yajl_start_map(void *ctx) {
  printf("map open '{'\n");
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<XDrawPoly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%r9d
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%r8d
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   %rdi
  mov    %rax,%rdi
  call   <XDrawLine@plt>
  add    $0x10,%rsp
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L18
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edi
  mov    -0x28(%rbp),%rax
  mov    (%rax),%r9d
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%r8d
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   %rdi
  mov    %rax,%rdi
  call   <XDrawLine@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

assistant: ```c
void XDrawPoly(Display *display, Window window, GC gc, int *xverts, int *yverts, int nvert) {
  int i;
  for (i = 1; i < nvert; i++)
    XDrawLine(display, window, gc, xverts[i - 1], yverts[i - 1], xverts[i], yverts[i]);
  XDrawLine(display, window, gc, xverts[nvert - 1], yverts[nvert - 1], xverts[0], yverts[0]);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<XDrawPoly>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %rcx,0x8(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9d,0x1c(%rsp)
  cmp    $0x1,%r9d
  jle    L18
  lea    0x4(%r8),%rbx
  lea    0x4(%rcx),%rbp
  lea    -0x2(%r9),%eax
  lea    0x8(%r8,%rax,4),%r15
L17:
  mov    -0x4(%rbx),%r8d
  mov    -0x4(%rbp),%ecx
  sub    $0x8,%rsp
  mov    (%rbx),%eax
  push   %rax
  mov    0x0(%rbp),%r9d
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <XDrawLine@plt>
  add    $0x4,%rbx
  add    $0x4,%rbp
  add    $0x10,%rsp
  cmp    %r15,%rbx
  jne    L17
L18:
  movslq 0x1c(%rsp),%rax
  shl    $0x2,%rax
  mov    0x10(%rsp),%rsi
  mov    -0x4(%rsi,%rax,1),%r8d
  mov    0x8(%rsp),%rdi
  mov    -0x4(%rdi,%rax,1),%ecx
  sub    $0x8,%rsp
  mov    (%rsi),%eax
  push   %rax
  mov    (%rdi),%r9d
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <XDrawLine@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void XDrawPoly(Display *display, Window window, GC gc, int *xverts, int *yverts, int nvert) {
  int i;
  for (i = 1; i < nvert; i++)
    XDrawLine(display, window, gc, xverts[i - 1], yverts[i - 1], xverts[i], yverts[i]);
  XDrawLine(display, window, gc, xverts[nvert - 1], yverts[nvert - 1], xverts[0], yverts[0]);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<XDrawPoly>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9d,0x1c(%rsp)
  cmp    $0x1,%r9d
  jle    L16
  mov    %r9d,%eax
  lea    0x4(%r8),%rbx
  lea    0x4(%rcx),%rbp
  sub    $0x2,%eax
  lea    0x8(%r8,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%eax
  sub    $0x8,%rsp
  mov    -0x4(%rbx),%r8d
  mov    %r13d,%edx
  mov    -0x4(%rbp),%ecx
  mov    %r14d,%esi
  mov    %r15,%rdi
  add    $0x4,%rbx
  push   %rax
  mov    0x0(%rbp),%r9d
  add    $0x4,%rbp
  call   <XDrawLine@plt>
  pop    %rax
  pop    %rdx
  cmp    %r12,%rbx
  jne    L11
L16:
  movslq 0x1c(%rsp),%r12
  mov    0x10(%rsp),%rax
  mov    %r13d,%edx
  mov    %r15,%rdi
  mov    0x8(%rsp),%rsi
  sub    $0x8,%rsp
  shl    $0x2,%r12
  mov    -0x4(%rax,%r12,1),%r8d
  mov    (%rax),%eax
  mov    -0x4(%rsi,%r12,1),%ecx
  push   %rax
  mov    (%rsi),%r9d
  mov    %r14d,%esi
  call   <XDrawLine@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void XDrawPoly(Display *display, Window window, GC gc, int *xverts, int *yverts, int nvert) {
  int i;
  for (i = 1; i < nvert; i++)
    XDrawLine(display, window, gc, xverts[i - 1], yverts[i - 1], xverts[i], yverts[i]);
  XDrawLine(display, window, gc, xverts[nvert - 1], yverts[nvert - 1], xverts[0], yverts[0]);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<XDrawPoly>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9d,0x1c(%rsp)
  cmp    $0x1,%r9d
  jle    L6
  mov    %r9d,%eax
  lea    0x4(%r8),%rbx
  lea    0x4(%rcx),%rbp
  sub    $0x2,%eax
  lea    0x8(%r8,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%eax
  sub    $0x8,%rsp
  mov    -0x4(%rbx),%r8d
  mov    %r13d,%edx
  mov    -0x4(%rbp),%ecx
  mov    %r14d,%esi
  mov    %r15,%rdi
  add    $0x4,%rbx
  push   %rax
  mov    0x0(%rbp),%r9d
  add    $0x4,%rbp
  call   <XDrawLine@plt>
  pop    %rax
  pop    %rdx
  cmp    %r12,%rbx
  jne    L13
L6:
  movslq 0x1c(%rsp),%r12
  mov    0x10(%rsp),%rax
  mov    %r13d,%edx
  mov    %r15,%rdi
  mov    0x8(%rsp),%rsi
  sub    $0x8,%rsp
  shl    $0x2,%r12
  mov    -0x4(%rax,%r12,1),%r8d
  mov    (%rax),%eax
  mov    -0x4(%rsi,%r12,1),%ecx
  push   %rax
  mov    (%rsi),%r9d
  mov    %r14d,%esi
  call   <XDrawLine@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void XDrawPoly(Display *display, Window window, GC gc, int *xverts, int *yverts, int nvert) {
  int i;
  for (i = 1; i < nvert; i++)
    XDrawLine(display, window, gc, xverts[i - 1], yverts[i - 1], xverts[i], yverts[i]);
  XDrawLine(display, window, gc, xverts[nvert - 1], yverts[nvert - 1], xverts[0], yverts[0]);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_conv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%ecx
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_add@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
char *_conv(const int n, const char *const format, char *const pt, const char *const ptlim) {
  char buf[32];
  (void)snprintf(buf, sizeof(buf), format, n);
  return _add(buf, pt, ptlim);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_conv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %edi,%ecx
  mov    %rsi,%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <_add@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *_conv(const int n, const char *const format, char *const pt, const char *const ptlim) {
  char buf[32];
  (void)snprintf(buf, sizeof(buf), format, n);
  return _add(buf, pt, ptlim);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_conv>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  mov    %edi,%ecx
  push   %rbp
  mov    %rdx,%rbp
  mov    %rsi,%rdx
  mov    $0x20,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <_add@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *_conv(const int n, const char *const format, char *const pt, const char *const ptlim) {
  char buf[32];
  (void)snprintf(buf, sizeof(buf), format, n);
  return _add(buf, pt, ptlim);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_conv>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  mov    %edi,%ecx
  push   %rbp
  mov    %rdx,%rbp
  mov    %rsi,%rdx
  mov    $0x20,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <_add@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *_conv(const int n, const char *const format, char *const pt, const char *const ptlim) {
  char buf[32];
  (void)snprintf(buf, sizeof(buf), format, n);
  return _add(buf, pt, ptlim);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<statvfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__statfs@plt>
  test   %rax,%rax
  jns    L11
  mov    $0xffffffff,%eax
  jmp    L5
L11:
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fixup@plt>
  mov    $0x0,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int statvfs(const char *restrict path, struct statvfs *restrict buf) {
  struct statfs kbuf;
  if (__statfs(path, &kbuf) < 0)
    return -1;
  fixup(buf, &kbuf);
  return 0;
}
```