ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<syscon_degree_of_dobldobl_polynomial>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x153,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_degree_of_dobldobl_polynomial(int k, int *d) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(339, &k, d, c);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<syscon_degree_of_dobldobl_polynomial>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x153,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_degree_of_dobldobl_polynomial(int k, int *d) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(339, &k, d, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<syscon_degree_of_dobldobl_polynomial>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x153,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_degree_of_dobldobl_polynomial(int k, int *d) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(339, &k, d, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<extended_62>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L30
  cmpl   $0x0,-0x4(%rbp)
  jns    L54
  jmp    L16
L30:
  cmpl   $0x2,-0x4(%rbp)
  je     L53
  jmp    L16
L54:
  mov    -0x30(%rbp),%rax
  movq   $0x8,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <handle_dsform@plt>
  jmp    L14
L53:
  mov    -0x30(%rbp),%rax
  movq   $0x10,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <handle_dsform@plt>
  jmp    L14
L16:
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
bool extended_62(uint32_t insn, unsigned long *gprs, unsigned long *addr, unsigned long *size) {
  int subopc = (((insn) >> (32 - (30) - (2))) & ((1 << (2)) - 1));
  switch (subopc) {
  case 0:
  case 1:
    *size = 8;
    return handle_dsform(insn, gprs, addr);
  case 2:
    *size = 16;
    return handle_dsform(insn, gprs, addr);
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extended_62>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  and    $0x3,%eax
  test   $0x2,%dil
  je     L35
  cmp    $0x2,%eax
  jne    L36
  movq   $0x10,(%rcx)
  call   <handle_dsform@plt>
  jmp    L24
L36:
  mov    $0x0,%eax
L24:
  add    $0x8,%rsp
  ret
L35:
  movq   $0x8,(%rcx)
  call   <handle_dsform@plt>
  jmp    L24
```

assistant: ```c
bool extended_62(uint32_t insn, unsigned long *gprs, unsigned long *addr, unsigned long *size) {
  int subopc = (((insn) >> (32 - (30) - (2))) & ((1 << (2)) - 1));
  switch (subopc) {
  case 0:
  case 1:
    *size = 8;
    return handle_dsform(insn, gprs, addr);
  case 2:
    *size = 16;
    return handle_dsform(insn, gprs, addr);
  }
  return false;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extended_62>:
  endbr64
  mov    %edi,%eax
  and    $0x3,%eax
  test   $0x2,%dil
  je     L9
  cmp    $0x2,%eax
  jne    L4
  movq   $0x10,(%rcx)
  jmp    1050 <handle_dsform@plt>
L9:
  movq   $0x8,(%rcx)
  jmp    1050 <handle_dsform@plt>
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool extended_62(uint32_t insn, unsigned long *gprs, unsigned long *addr, unsigned long *size) {
  int subopc = (((insn) >> (32 - (30) - (2))) & ((1 << (2)) - 1));
  switch (subopc) {
  case 0:
  case 1:
    *size = 8;
    return handle_dsform(insn, gprs, addr);
  case 2:
    *size = 16;
    return handle_dsform(insn, gprs, addr);
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extended_62>:
  endbr64
  mov    %edi,%eax
  and    $0x3,%eax
  test   $0x2,%dil
  je     L2
  cmp    $0x2,%eax
  jne    L16
  movq   $0x10,(%rcx)
  jmp    1050 <handle_dsform@plt>
L2:
  movq   $0x8,(%rcx)
  jmp    1050 <handle_dsform@plt>
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool extended_62(uint32_t insn, unsigned long *gprs, unsigned long *addr, unsigned long *size) {
  int subopc = (((insn) >> (32 - (30) - (2))) & ((1 << (2)) - 1));
  switch (subopc) {
  case 0:
  case 1:
    *size = 8;
    return handle_dsform(insn, gprs, addr);
  case 2:
    *size = 16;
    return handle_dsform(insn, gprs, addr);
  }
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PAGE_TrimInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <PAGE_RemoveAllObjects@plt>
  mov    $0x0,%eax
  call   <_show_page@plt>
  nop
  leave
  ret
```

assistant: ```c
void PAGE_TrimInit(int page) {
  (void)page;
  PAGE_RemoveAllObjects();
  _show_page();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PAGE_TrimInit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <PAGE_RemoveAllObjects@plt>
  mov    $0x0,%eax
  call   <_show_page@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void PAGE_TrimInit(int page) {
  (void)page;
  PAGE_RemoveAllObjects();
  _show_page();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PAGE_TrimInit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PAGE_RemoveAllObjects@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <_show_page@plt>
```

assistant: ```c
void PAGE_TrimInit(int page) {
  (void)page;
  PAGE_RemoveAllObjects();
  _show_page();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PAGE_TrimInit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PAGE_RemoveAllObjects@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <_show_page@plt>
```

assistant: ```c
void PAGE_TrimInit(int page) {
  (void)page;
  PAGE_RemoveAllObjects();
  _show_page();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<primeiroUltimo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L32
L1:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L34
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L34:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L0:
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void primeiroUltimo(char clubes[][50], int pontos[], int n, char primeiro[50], char ultimo[50]) {
  int i, max = pontos[0], min = pontos[0];
  for (i = 1; i < n; i++) {
    if (pontos[i] > max) {
      max = pontos[i];
      strcpy(primeiro, clubes[i]);
    }
    if (pontos[i] < min) {
      min = pontos[i];
      strcpy(ultimo, clubes[i]);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<primeiroUltimo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rcx,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  mov    (%rsi),%r14d
  cmp    $0x1,%edx
  jle    L12
  lea    0x4(%rsi),%rbx
  lea    0x32(%rdi),%rbp
  lea    -0x2(%rdx),%eax
  lea    0x8(%rsi,%rax,4),%r15
  mov    %r14d,0xc(%rsp)
  jmp    L2
L52:
  mov    %rbp,%rsi
  mov    0x10(%rsp),%rdi
  call   <strcpy@plt>
  mov    %r12d,%r14d
  jmp    L50
L40:
  add    $0x4,%rbx
  add    $0x32,%rbp
  cmp    %r15,%rbx
  je     L12
L2:
  mov    %rbx,%r13
  mov    (%rbx),%r12d
  cmp    %r14d,%r12d
  jg     L52
L50:
  mov    0x0(%r13),%r12d
  cmp    0xc(%rsp),%r12d
  jge    L40
  mov    %rbp,%rsi
  mov    0x18(%rsp),%rdi
  call   <strcpy@plt>
  mov    %r12d,0xc(%rsp)
  jmp    L40
L12:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void primeiroUltimo(char clubes[][50], int pontos[], int n, char primeiro[50], char ultimo[50]) {
  int i, max = pontos[0], min = pontos[0];
  for (i = 1; i < n; i++) {
    if (pontos[i] > max) {
      max = pontos[i];
      strcpy(primeiro, clubes[i]);
    }
    if (pontos[i] < min) {
      min = pontos[i];
      strcpy(ultimo, clubes[i]);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<primeiroUltimo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%ecx
  cmp    $0x1,%edx
  jle    L51
  lea    -0x2(%rdx),%eax
  mov    %r8,%r14
  lea    0x4(%rsi),%rbx
  mov    %ecx,%edx
  lea    0x32(%rdi),%r12
  lea    0x8(%rsi,%rax,4),%r15
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L25:
  cmp    %edx,%ebp
  jl     L67
L58:
  add    $0x4,%rbx
  add    $0x32,%r12
  cmp    %r15,%rbx
  je     L51
L30:
  mov    (%rbx),%ebp
  cmp    %ecx,%ebp
  jle    L25
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %edx,0xc(%rsp)
  call   <strcpy@plt>
  mov    %ebp,%ecx
  mov    0xc(%rsp),%edx
  mov    (%rbx),%ebp
  cmp    %edx,%ebp
  jge    L58
L67:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x4,%rbx
  mov    %ecx,0xc(%rsp)
  call   <strcpy@plt>
  add    $0x32,%r12
  mov    0xc(%rsp),%ecx
  mov    %ebp,%edx
  cmp    %r15,%rbx
  jne    L30
L51:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void primeiroUltimo(char clubes[][50], int pontos[], int n, char primeiro[50], char ultimo[50]) {
  int i, max = pontos[0], min = pontos[0];
  for (i = 1; i < n; i++) {
    if (pontos[i] > max) {
      max = pontos[i];
      strcpy(primeiro, clubes[i]);
    }
    if (pontos[i] < min) {
      min = pontos[i];
      strcpy(ultimo, clubes[i]);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<primeiroUltimo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%ecx
  cmp    $0x1,%edx
  jle    L31
  lea    -0x2(%rdx),%eax
  mov    %r8,%r14
  lea    0x4(%rsi),%rbx
  mov    %ecx,%edx
  lea    0x32(%rdi),%r12
  lea    0x8(%rsi,%rax,4),%r15
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L39:
  cmp    %ebp,%edx
  jg     L25
L69:
  add    $0x4,%rbx
  add    $0x32,%r12
  cmp    %r15,%rbx
  je     L31
L63:
  mov    (%rbx),%ebp
  cmp    %ecx,%ebp
  jle    L39
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %edx,0xc(%rsp)
  call   <strcpy@plt>
  mov    %ebp,%ecx
  mov    0xc(%rsp),%edx
  mov    (%rbx),%ebp
  cmp    %ebp,%edx
  jle    L69
L25:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x4,%rbx
  mov    %ecx,0xc(%rsp)
  call   <strcpy@plt>
  add    $0x32,%r12
  mov    0xc(%rsp),%ecx
  mov    %ebp,%edx
  cmp    %r15,%rbx
  jne    L63
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void primeiroUltimo(char clubes[][50], int pontos[], int n, char primeiro[50], char ultimo[50]) {
  int i, max = pontos[0], min = pontos[0];
  for (i = 1; i < n; i++) {
    if (pontos[i] > max) {
      max = pontos[i];
      strcpy(primeiro, clubes[i]);
    }
    if (pontos[i] < min) {
      min = pontos[i];
      strcpy(ultimo, clubes[i]);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nvram_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <nvram_get_option@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%edi
  call   <nvram_init@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L4
  mov    $0x0,%eax
  call   <nvram_close@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L26
L4:
  mov    -0xc(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L47
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <nvram_get@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L47
  mov    $0x0,%eax
  call   <nvram_close@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  jmp    L26
L47:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_nvram_set@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <nvram_close@plt>
  mov    -0x10(%rbp),%eax
L26:
  leave
  ret
```

assistant: ```c
int nvram_set(const char *name, const char *value) {
  int ret = 0;
  unsigned int opt = nvram_get_option(name);
  nvram_init(NULL);
  if (opt & 0x80000000) {
    nvram_close();
    return EINVAL;
  }
  if (opt & 0x02) {
    char *exist = nvram_get(name);
    if (exist && *exist) {
      nvram_close();
      return EACCES;
    }
  }
  ret = _nvram_set(name, value);
  nvram_close();
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nvram_set>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <nvram_get_option@plt>
  mov    %eax,%ebp
  mov    $0x0,%edi
  call   <nvram_init@plt>
  test   %ebp,%ebp
  js     L29
  test   $0x2,%bpl
  je     L48
  mov    %rbx,%rdi
  call   <nvram_get@plt>
  test   %rax,%rax
  je     L48
  cmpb   $0x0,(%rax)
  jne    L41
L48:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <_nvram_set@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <nvram_close@plt>
L50:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    $0x0,%eax
  call   <nvram_close@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%ebx
  jmp    L50
L41:
  mov    $0x0,%eax
  call   <nvram_close@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%ebx
  jmp    L50
```

assistant: ```c
int nvram_set(const char *name, const char *value) {
  int ret = 0;
  unsigned int opt = nvram_get_option(name);
  nvram_init(NULL);
  if (opt & 0x80000000) {
    nvram_close();
    return EINVAL;
  }
  if (opt & 0x02) {
    char *exist = nvram_get(name);
    if (exist && *exist) {
      nvram_close();
      return EACCES;
    }
  }
  ret = _nvram_set(name, value);
  nvram_close();
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nvram_set>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <nvram_get_option@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <nvram_init@plt>
  test   %ebx,%ebx
  js     L47
  and    $0x2,%ebx
  je     L13
  mov    %rbp,%rdi
  call   <nvram_get@plt>
  test   %rax,%rax
  je     L13
  cmpb   $0x0,(%rax)
  jne    L39
L13:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <_nvram_set@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <nvram_close@plt>
L46:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  call   <nvram_close@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%r12d
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L47:
  xor    %eax,%eax
  call   <nvram_close@plt>
  mov    D13(%rip),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rax),%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int nvram_set(const char *name, const char *value) {
  int ret = 0;
  unsigned int opt = nvram_get_option(name);
  nvram_init(NULL);
  if (opt & 0x80000000) {
    nvram_close();
    return EINVAL;
  }
  if (opt & 0x02) {
    char *exist = nvram_get(name);
    if (exist && *exist) {
      nvram_close();
      return EACCES;
    }
  }
  ret = _nvram_set(name, value);
  nvram_close();
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nvram_set>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <nvram_get_option@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <nvram_init@plt>
  test   %ebx,%ebx
  js     L15
  and    $0x2,%ebx
  je     L17
  mov    %rbp,%rdi
  call   <nvram_get@plt>
  test   %rax,%rax
  je     L17
  cmpb   $0x0,(%rax)
  jne    L42
L17:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <_nvram_set@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <nvram_close@plt>
L45:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L42:
  xor    %eax,%eax
  call   <nvram_close@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%r12d
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  call   <nvram_close@plt>
  mov    D17(%rip),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rax),%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int nvram_set(const char *name, const char *value) {
  int ret = 0;
  unsigned int opt = nvram_get_option(name);
  nvram_init(NULL);
  if (opt & 0x80000000) {
    nvram_close();
    return EINVAL;
  }
  if (opt & 0x02) {
    char *exist = nvram_get(name);
    if (exist && *exist) {
      nvram_close();
      return EACCES;
    }
  }
  ret = _nvram_set(name, value);
  nvram_close();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ignoreleak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <__builtin_memset@plt>
  nop
  leave
  ret
```

assistant: ```c
void ignoreleak(void) {
  char *p = (char *)malloc(10);
  __builtin_memset(&(p[0]), 0, 10);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ignoreleak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <__builtin_memset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ignoreleak(void) {
  char *p = (char *)malloc(10);
  __builtin_memset(&(p[0]), 0, 10);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ignoreleak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    $0xa,%edx
  xor    %esi,%esi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <__builtin_memset@plt>
```

assistant: ```c
void ignoreleak(void) {
  char *p = (char *)malloc(10);
  __builtin_memset(&(p[0]), 0, 10);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ignoreleak>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    $0xa,%edx
  xor    %esi,%esi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <__builtin_memset@plt>
```

assistant: ```c
void ignoreleak(void) {
  char *p = (char *)malloc(10);
  __builtin_memset(&(p[0]), 0, 10);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uDMAChannelEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x400ff028,%edx
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uDMAChannelEnable(uint32_t ui32ChannelNum) {
  ;
  (*((volatile uint32_t *)(0x400FF028))) = 1 << (ui32ChannelNum & 0x1f);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uDMAChannelEnable>:
  endbr64
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  mov    %eax,0x400ff028
  ret
```

assistant: ```c
void uDMAChannelEnable(uint32_t ui32ChannelNum) {
  ;
  (*((volatile uint32_t *)(0x400FF028))) = 1 << (ui32ChannelNum & 0x1f);
}
```
user: What is the c source code of the assembly code below:

```asm
<uDMAChannelEnable>:
  endbr64
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  mov    %eax,0x400ff028
  ret
```

assistant: ```c
void uDMAChannelEnable(uint32_t ui32ChannelNum) {
  ;
  (*((volatile uint32_t *)(0x400FF028))) = 1 << (ui32ChannelNum & 0x1f);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uDMAChannelEnable>:
  endbr64
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  mov    %eax,0x400ff028
  ret
```

assistant: ```c
void uDMAChannelEnable(uint32_t ui32ChannelNum) {
  ;
  (*((volatile uint32_t *)(0x400FF028))) = 1 << (ui32ChannelNum & 0x1f);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
  movzbl -0x14(%rbp),%eax
  shr    $0x4,%al
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  add    %eax,%eax
  and    $0xffffffaa,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  sar    %eax
  and    $0x55,%eax
  or     %edx,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  sar    $0x2,%eax
  and    $0x33,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  shl    $0x2,%eax
  and    $0xffffffcc,%eax
  or     %edx,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  shr    $0x4,%al
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x1(%rbp),%eax
  jmp    L16
L33:
  movzbl -0x14(%rbp),%edx
  movzbl -0x1(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L27
  mov    $0x0,%eax
  call   <send1@plt>
  jmp    L8
L27:
  mov    $0x0,%eax
  call   <send0@plt>
L8:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L16:
  movzbl -0x1(%rbp),%eax
  cmp    $0x7,%al
  jbe    L33
  nop
  nop
  leave
  ret
```

assistant: ```c
void send(unsigned char n) {
  volatile unsigned char i = 0;
  n /= 16;
  n = ((n & 0x55) << 1) | ((n & 0xAA) >> 1);
  n = ((n & 0xCC) >> 2) | ((n & 0x33) << 2);
  n = (n >> 4) | (n << 4);
  for (i; i < 8; i++) {
    if (n & (1 << i)) {
      send1();
    } else {
      send0();
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<send>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movb   $0x0,0xf(%rsp)
  shr    $0x4,%dil
  movzbl %dil,%edi
  lea    (%rdi,%rdi,1),%eax
  and    $0xffffffaa,%eax
  sar    %edi
  and    $0x55,%edi
  or     %edi,%eax
  movzbl %al,%eax
  lea    0x0(,%rax,4),%ebx
  sar    $0x2,%eax
  and    $0xc,%ebx
  or     %eax,%ebx
  shl    $0x4,%ebx
  movzbl 0xf(%rsp),%eax
  movzbl 0xf(%rsp),%eax
  cmp    $0x7,%al
  jbe    L17
L13:
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  mov    $0x0,%eax
  call   <send0@plt>
L30:
  movzbl 0xf(%rsp),%eax
  add    $0x1,%eax
  mov    %al,0xf(%rsp)
  movzbl 0xf(%rsp),%eax
  cmp    $0x7,%al
  ja     L13
L17:
  movzbl 0xf(%rsp),%eax
  bt     %eax,%ebx
  jae    L28
  mov    $0x0,%eax
  call   <send1@plt>
  jmp    L30
```

assistant: ```c
void send(unsigned char n) {
  volatile unsigned char i = 0;
  n /= 16;
  n = ((n & 0x55) << 1) | ((n & 0xAA) >> 1);
  n = ((n & 0xCC) >> 2) | ((n & 0x33) << 2);
  n = (n >> 4) | (n << 4);
  for (i; i < 8; i++) {
    if (n & (1 << i)) {
      send1();
    } else {
      send0();
    }
  }
}
```