user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D100(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D134(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D110(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x19(%rbp),%rax
  mov    %rax,%rsi
  lea    D100(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl -0x19(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x33,%eax
  je     L24
  cmp    $0x33,%eax
  jg     L45
  cmp    $0x31,%eax
  je     L28
  cmp    $0x32,%eax
  je     L83
  jmp    L45
L28:
  movss  -0x18(%rbp),%xmm0
  movss  D75(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L76
L83:
  movss  -0x18(%rbp),%xmm0
  movss  D118(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L76
L24:
  movss  -0x18(%rbp),%xmm0
  movss  D8(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L76
L45:
  lea    D132(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L76:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D91
type_guessed: string
name: disassemble_data
arguments: data_label: D100
type_guessed: string
name: disassemble_data
arguments: data_label: D31
type_guessed: string
name: disassemble_data
arguments: data_label: D134
type_guessed: string
name: disassemble_data
arguments: data_label: D110
type_guessed: string
name: disassemble_data
arguments: data_label: D52
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string
name: disassemble_data
arguments: data_label: D75
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D59
type_guessed: string
name: disassemble_data
arguments: data_label: D118
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D50
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D65
type_guessed: string
name: disassemble_data
arguments: data_label: D132
type_guessed: string

tool: D91: Enter size in bytes: 

tool: D100: %d

tool: D31: Conversion Options: 

tool: D134: 1. byte to KB

tool: D110: 2. byte to MB

tool: D52: 3. byte to GB

tool: D1: Enter choice: 

tool: {"D75": [0x00,0x00,0x80,0x44]}

tool: D59: Size in KB: %d

tool: {"D118": [0x00,0x00,0x80,0x49]}

tool: D50: Size in MB: %d

tool: {"D8": [0x00,0x00,0x80,0x4e]}

tool: D65: Size in GB: %d

tool: D132: Enter a valid choice.

assistant: ```c
int main(void) {
  char choice;
  float byte, kb, mb, gb;
  printf("Enter size in bytes: ");
  scanf("%d", &byte);
  printf("Conversion Options: \n");
  printf("1. byte to KB\n");
  printf("2. byte to MB\n");
  printf("3. byte to GB\n");
  printf("Enter choice: ");
  scanf("%d", &choice);
  switch (choice) {
  case '1':
    kb = byte / 1024;
    printf("Size in KB: %d", &kb);
    break;
  case '2':
    mb = byte / (1024 * 1024);
    printf("Size in MB: %d", &mb);
    break;
  case '3':
    gb = byte / (1024 * 1024 * 1024);
    printf("Size in GB: %d", &gb);
    break;
  default:
    printf("Enter a valid choice.\n");
  }
  return 0;
}
```