ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_memccpy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <puts@plt>
  movabs $0x3837363534333231,%rax
  movabs $0x4645444342413039,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  mov    %rsp,%rbx
  mov    $0xf,%ecx
  mov    $0x63,%edx
  lea    D4(%rip),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memccpy@plt>
  lea    0x20(%rsp),%rbp
  mov    $0xf,%ecx
  mov    $0x63,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <ft_memccpy@plt>
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L16
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L27:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D23
data_type: string
name: unpack_data
arguments: tag: D58
data_type: string
name: unpack_data
arguments: tag: D29
data_type: string

tool: D11: -----------------------ft_memccpy

tool: D4: IAcMALIVE

tool: D5: >>>>>>>FAIL<<<<<<<

tool: D23:    memccpy = "%s"


tool: D58: ft_memccpy = "%s"


tool: D29: >>>>>SUCCESS<<<<<

assistant: ```c
void test_memccpy() {
  printf("-----------------------ft_memccpy\n");
  char str5[20] = "1234567890ABCDEF";
  char str6[20] = "1234567890ABCDEF";
  memccpy((void *)str5, (const void *)"IAcMALIVE", 'c', 15);
  ft_memccpy((void *)str6, (const void *)"IAcMALIVE", 'c', 15);
  if (memcmp(str5, str6, 10) != 0) {
    printf(">>>>>>>FAIL<<<<<<<\n");
    printf("   memccpy = \"%s\"\n", (char *)str5);
    printf("ft_memccpy = \"%s\"\n", (char *)str6);
  } else
    printf(">>>>>SUCCESS<<<<<\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_memccpy>:
  endbr64
  push   %r13
  lea    D8(%rip),%rdi
  lea    D40(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%rbp
  call   <puts@plt>
  mov    $0xf,%ecx
  mov    %r13,%rsi
  mov    %r12,%rdi
  movdqa D28(%rip),%xmm0
  mov    $0x63,%edx
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <memccpy@plt>
  mov    $0x63,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0xf,%ecx
  call   <ft_memccpy@plt>
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L25
  lea    D61(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L29:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  jmp    L29
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string
name: parse_data
arguments: data_label: D40
datatype: string
name: parse_data
arguments: data_label: D28
datatype: byte[16]
name: parse_data
arguments: data_label: D61
datatype: string
name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D33
datatype: string

tool: D8: -----------------------ft_memccpy

tool: D40: IAcMALIVE

tool: {"D28": [0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x30,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: D61: >>>>>>>FAIL<<<<<<<

tool: D30:    memccpy = "%s"


tool: D0: ft_memccpy = "%s"


tool: D33: >>>>>SUCCESS<<<<<

assistant: ```c
void test_memccpy() {
  printf("-----------------------ft_memccpy\n");
  char str5[20] = "1234567890ABCDEF";
  char str6[20] = "1234567890ABCDEF";
  memccpy((void *)str5, (const void *)"IAcMALIVE", 'c', 15);
  ft_memccpy((void *)str6, (const void *)"IAcMALIVE", 'c', 15);
  if (memcmp(str5, str6, 10) != 0) {
    printf(">>>>>>>FAIL<<<<<<<\n");
    printf("   memccpy = \"%s\"\n", (char *)str5);
    printf("ft_memccpy = \"%s\"\n", (char *)str6);
  } else
    printf(">>>>>SUCCESS<<<<<\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_memccpy>:
  endbr64
  push   %r13
  lea    D44(%rip),%rdi
  lea    D63(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%rbp
  call   <puts@plt>
  mov    $0xf,%ecx
  mov    %r13,%rsi
  mov    %r12,%rdi
  movdqa D21(%rip),%xmm0
  mov    $0x63,%edx
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <memccpy@plt>
  mov    $0x63,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0xf,%ecx
  call   <ft_memccpy@plt>
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L18
  lea    D66(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L1:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x40,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  jmp    L1
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D44
data_type: string
name: unpack_data
arguments: tag: D63
data_type: string
name: unpack_data
arguments: tag: D21
data_type: byte[16]
name: unpack_data
arguments: tag: D66
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D43
data_type: string
name: unpack_data
arguments: tag: D14
data_type: string

tool: D44: -----------------------ft_memccpy

tool: D63: IAcMALIVE

tool: {"D21": [0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x30,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: D66: >>>>>>>FAIL<<<<<<<

tool: D10:    memccpy = "%s"


tool: D43: ft_memccpy = "%s"


tool: D14: >>>>>SUCCESS<<<<<

assistant: ```c
void test_memccpy() {
  printf("-----------------------ft_memccpy\n");
  char str5[20] = "1234567890ABCDEF";
  char str6[20] = "1234567890ABCDEF";
  memccpy((void *)str5, (const void *)"IAcMALIVE", 'c', 15);
  ft_memccpy((void *)str6, (const void *)"IAcMALIVE", 'c', 15);
  if (memcmp(str5, str6, 10) != 0) {
    printf(">>>>>>>FAIL<<<<<<<\n");
    printf("   memccpy = \"%s\"\n", (char *)str5);
    printf("ft_memccpy = \"%s\"\n", (char *)str6);
  } else
    printf(">>>>>SUCCESS<<<<<\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<long2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  lea    -0x2c(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L14
L29:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x4,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x9,-0x10(%rbp)
  jg     L45
  mov    -0x10(%rbp),%eax
  lea    0x30(%rax),%edx
  jmp    L26
L45:
  mov    -0x10(%rbp),%eax
  lea    0x37(%rax),%edx
L26:
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  mov    %edx,(%rax)
  cmpl   $0x9,-0xc(%rbp)
  jg     L37
  mov    -0xc(%rbp),%eax
  lea    0x30(%rax),%edx
  jmp    L38
L37:
  mov    -0xc(%rbp),%eax
  lea    0x37(%rax),%edx
L38:
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  mov    %edx,(%rax)
  addl   $0x2,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
  subq   $0x4,-0x8(%rbp)
L14:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L29
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int long2hex(uint8_t *d, uint64_t a) {
  int i;
  int c = 0;
  int l = sizeof(a);
  uint8_t *s = (uint8_t *)&a + l - 1;
  for (i = 0; i < l; i++, s--) {
    uint8_t h = *s >> 4;
    uint8_t l = *s & 0x0f;
    *(d++) = (h < 10) ? h + '0' : h + 'A' - 10;
    *(d++) = (l < 10) ? l + '0' : l + 'A' - 10;
    c += 2;
  }
  *d = '\0';
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<long2hex>:
  endbr64
  mov    %esi,-0x4(%rsp)
  mov    %rdi,%rcx
  lea    0x8(%rsp),%rdx
  lea    -0x8(%rsp),%r10
L8:
  mov    (%rdx),%eax
  mov    %eax,%r8d
  sar    $0x4,%r8d
  and    $0xf,%eax
  lea    0x30(%r8),%r9d
  lea    0x37(%r8),%esi
  cmp    $0x9,%r8d
  cmovle %r9d,%esi
  mov    %esi,(%rcx)
  lea    0x30(%rax),%r8d
  lea    0x37(%rax),%esi
  cmp    $0x9,%eax
  mov    %r8d,%eax
  cmovg  %esi,%eax
  add    $0x8,%rcx
  mov    %eax,-0x4(%rcx)
  sub    $0x4,%rdx
  cmp    %r10,%rdx
  jne    L8
  movl   $0x0,0x20(%rdi)
  mov    $0x8,%eax
  ret
```

assistant: ```c
int long2hex(uint8_t *d, uint64_t a) {
  int i;
  int c = 0;
  int l = sizeof(a);
  uint8_t *s = (uint8_t *)&a + l - 1;
  for (i = 0; i < l; i++, s--) {
    uint8_t h = *s >> 4;
    uint8_t l = *s & 0x0f;
    *(d++) = (h < 10) ? h + '0' : h + 'A' - 10;
    *(d++) = (l < 10) ? l + '0' : l + 'A' - 10;
    c += 2;
  }
  *d = '\0';
  return c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<long2hex>:
  endbr64
  mov    %esi,-0x4(%rsp)
  mov    %rdi,%rcx
  lea    0x8(%rsp),%rdx
  lea    -0x8(%rsp),%r10
L4:
  mov    (%rdx),%eax
  mov    %eax,%r8d
  and    $0xf,%eax
  sar    $0x4,%r8d
  cmp    $0x9,%r8d
  lea    0x30(%r8),%r9d
  lea    0x37(%r8),%esi
  cmovle %r9d,%esi
  lea    0x30(%rax),%r8d
  cmp    $0x9,%eax
  mov    %esi,(%rcx)
  lea    0x37(%rax),%esi
  mov    %r8d,%eax
  cmovg  %esi,%eax
  sub    $0x4,%rdx
  add    $0x8,%rcx
  mov    %eax,-0x4(%rcx)
  cmp    %r10,%rdx
  jne    L4
  movl   $0x0,0x20(%rdi)
  mov    $0x8,%eax
  ret
```

assistant: ```c
int long2hex(uint8_t *d, uint64_t a) {
  int i;
  int c = 0;
  int l = sizeof(a);
  uint8_t *s = (uint8_t *)&a + l - 1;
  for (i = 0; i < l; i++, s--) {
    uint8_t h = *s >> 4;
    uint8_t l = *s & 0x0f;
    *(d++) = (h < 10) ? h + '0' : h + 'A' - 10;
    *(d++) = (l < 10) ? l + '0' : l + 'A' - 10;
    c += 2;
  }
  *d = '\0';
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<long2hex>:
  endbr64
  mov    %esi,-0xc(%rsp)
  movdqu -0xc(%rsp),%xmm7
  mov    $0x8,%eax
  movdqa D14(%rip),%xmm5
  movdqa D9(%rip),%xmm2
  movl   $0x0,0x20(%rdi)
  pshufd $0x1b,%xmm7,%xmm0
  movdqa D36(%rip),%xmm3
  movdqa %xmm0,%xmm1
  pand   D38(%rip),%xmm0
  psrad  $0x4,%xmm1
  movdqa %xmm1,%xmm4
  movdqa %xmm1,%xmm6
  pcmpgtd %xmm5,%xmm1
  paddd  %xmm3,%xmm6
  paddd  %xmm2,%xmm4
  paddd  %xmm0,%xmm3
  paddd  %xmm0,%xmm2
  pcmpgtd %xmm5,%xmm0
  pand   %xmm1,%xmm4
  pandn  %xmm6,%xmm1
  por    %xmm4,%xmm1
  pand   %xmm0,%xmm2
  pandn  %xmm3,%xmm0
  por    %xmm2,%xmm0
  movdqa %xmm1,%xmm2
  punpckldq %xmm0,%xmm2
  punpckhdq %xmm0,%xmm1
  movups %xmm2,(%rdi)
  movups %xmm1,0x10(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type_infered: byte[16]
name: parse_data
arguments: data_label: D9
type_infered: byte[16]
name: parse_data
arguments: data_label: D36
type_infered: byte[16]
name: parse_data
arguments: data_label: D38
type_infered: byte[16]

tool: {"D14": [0x09,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D9": [0x37,0x00,0x00,0x00,0x37,0x00,0x00,0x00,0x37,0x00,0x00,0x00,0x37,0x00,0x00,0x00]}

tool: {"D36": [0x30,0x00,0x00,0x00,0x30,0x00,0x00,0x00,0x30,0x00,0x00,0x00,0x30,0x00,0x00,0x00]}

tool: {"D38": [0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

assistant: ```c
int long2hex(uint8_t *d, uint64_t a) {
  int i;
  int c = 0;
  int l = sizeof(a);
  uint8_t *s = (uint8_t *)&a + l - 1;
  for (i = 0; i < l; i++, s--) {
    uint8_t h = *s >> 4;
    uint8_t l = *s & 0x0f;
    *(d++) = (h < 10) ? h + '0' : h + 'A' - 10;
    *(d++) = (l < 10) ? l + '0' : l + 'A' - 10;
    c += 2;
  }
  *d = '\0';
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write_u16_to_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl %sil,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0xc(%rbp),%edx
  movzbl %dl,%edx
  mov    %edx,(%rax)
  mov    $0x2,%eax
  pop    %rbp
  ret
```

assistant: ```c
int write_u16_to_buf(uint8_t **ptr, uint16_t val) {
  *(*ptr)++ = (val >> 8) & 0xff;
  *(*ptr)++ = val & 0xff;
  return 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_u16_to_buf>:
  endbr64
  mov    %esi,%eax
  mov    (%rdi),%rdx
  lea    0x4(%rdx),%rcx
  mov    %rcx,(%rdi)
  movzbl %ah,%ecx
  mov    %ecx,(%rdx)
  mov    (%rdi),%rdx
  lea    0x4(%rdx),%rcx
  mov    %rcx,(%rdi)
  and    $0xff,%eax
  mov    %eax,(%rdx)
  mov    $0x2,%eax
  ret
```

assistant: ```c
int write_u16_to_buf(uint8_t **ptr, uint16_t val) {
  *(*ptr)++ = (val >> 8) & 0xff;
  *(*ptr)++ = val & 0xff;
  return 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<write_u16_to_buf>:
  endbr64
  mov    (%rdi),%rdx
  mov    %esi,%eax
  movzbl %ah,%ecx
  and    $0xff,%eax
  mov    %ecx,(%rdx)
  lea    0x8(%rdx),%rcx
  mov    %rcx,(%rdi)
  mov    %eax,0x4(%rdx)
  mov    $0x2,%eax
  ret
```

assistant: ```c
int write_u16_to_buf(uint8_t **ptr, uint16_t val) {
  *(*ptr)++ = (val >> 8) & 0xff;
  *(*ptr)++ = val & 0xff;
  return 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_u16_to_buf>:
  endbr64
  mov    (%rdi),%rdx
  mov    %esi,%eax
  movzbl %ah,%ecx
  and    $0xff,%eax
  mov    %ecx,(%rdx)
  lea    0x8(%rdx),%rcx
  mov    %rcx,(%rdi)
  mov    %eax,0x4(%rdx)
  mov    $0x2,%eax
  ret
```

assistant: ```c
int write_u16_to_buf(uint8_t **ptr, uint16_t val) {
  *(*ptr)++ = (val >> 8) & 0xff;
  *(*ptr)++ = val & 0xff;
  return 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<math_addull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  not    %rax
  cmp    %rax,-0x18(%rbp)
  jbe    L16
  mov    -0x8(%rbp),%rax
  movq   $0xffffffffffffffff,(%rax)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  jmp    L8
L16:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int math_addull(unsigned long long *x, unsigned long long a, unsigned long long b) {
  if (~a < b) {
    *x = ~0ULL;
    return EOVERFLOW;
  } else {
    *x = a + b;
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<math_addull>:
  endbr64
  mov    %rsi,%rax
  add    %rdx,%rax
  jae    L6
  movq   $0xffffffffffffffff,(%rdi)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  ret
L6:
  add    %rdx,%rsi
  mov    %rsi,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int math_addull(unsigned long long *x, unsigned long long a, unsigned long long b) {
  if (~a < b) {
    *x = ~0ULL;
    return EOVERFLOW;
  } else {
    *x = a + b;
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<math_addull>:
  endbr64
  add    %rdx,%rsi
  jb     L8
  mov    %rsi,(%rdi)
  xor    %eax,%eax
  ret
L8:
  mov    D9(%rip),%rax
  movq   $0xffffffffffffffff,(%rdi)
  mov    (%rax),%eax
  ret
```

assistant: ```c
int math_addull(unsigned long long *x, unsigned long long a, unsigned long long b) {
  if (~a < b) {
    *x = ~0ULL;
    return EOVERFLOW;
  } else {
    *x = a + b;
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<math_addull>:
  endbr64
  add    %rdx,%rsi
  jb     L3
  xor    %eax,%eax
L8:
  mov    %rsi,(%rdi)
  ret
L3:
  mov    D2(%rip),%rax
  or     $0xffffffffffffffff,%rsi
  mov    (%rax),%eax
  jmp    L8
```

assistant: ```c
int math_addull(unsigned long long *x, unsigned long long a, unsigned long long b) {
  if (~a < b) {
    *x = ~0ULL;
    return EOVERFLOW;
  } else {
    *x = a + b;
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<some_complex_operation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L28
  lea    D10(%rip),%rax
  jmp    L7
L28:
  cmpl   $0x64,-0x4(%rbp)
  jle    L10
  lea    D21(%rip),%rax
  jmp    L7
L10:
  lea    D0(%rip),%rax
L7:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
data_type: string
name: retrieve_data
arguments: tag: D21
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string

tool: D10: That's a negative number

tool: D21: That's a pretty big number

tool: D0: That's a number between 0 and 100!

assistant: ```c
char *some_complex_operation(int input_num) {
  if (input_num < 0) {
    return "That's a negative number";
  } else if (input_num > 100) {
    return "That's a pretty big number";
  } else {
    return "That's a number between 0 and 100!";
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<some_complex_operation>:
  endbr64
  lea    D6(%rip),%rax
  test   %edi,%edi
  js     L2
  cmp    $0x64,%edi
  lea    D13(%rip),%rax
  lea    D5(%rip),%rdx
  cmovle %rdx,%rax
L2:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string
name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D5
type: string

tool: D6: That's a negative number

tool: D13: That's a pretty big number

tool: D5: That's a number between 0 and 100!

assistant: ```c
char *some_complex_operation(int input_num) {
  if (input_num < 0) {
    return "That's a negative number";
  } else if (input_num > 100) {
    return "That's a pretty big number";
  } else {
    return "That's a number between 0 and 100!";
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<some_complex_operation>:
  endbr64
  lea    D5(%rip),%rax
  test   %edi,%edi
  js     L2
  cmp    $0x64,%edi
  lea    D22(%rip),%rax
  lea    D25(%rip),%rdx
  cmovle %rdx,%rax
L2:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string
name: retrieve_data
arguments: tag: D22
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string

tool: D5: That's a negative number

tool: D22: That's a pretty big number

tool: D25: That's a number between 0 and 100!

assistant: ```c
char *some_complex_operation(int input_num) {
  if (input_num < 0) {
    return "That's a negative number";
  } else if (input_num > 100) {
    return "That's a pretty big number";
  } else {
    return "That's a number between 0 and 100!";
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<some_complex_operation>:
  endbr64
  lea    D13(%rip),%rax
  test   %edi,%edi
  js     L2
  cmp    $0x64,%edi
  lea    D9(%rip),%rax
  lea    D4(%rip),%rdx
  cmovle %rdx,%rax
L2:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
datatype: string
name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D13: That's a negative number

tool: D9: That's a pretty big number

tool: D4: That's a number between 0 and 100!

assistant: ```c
char *some_complex_operation(int input_num) {
  if (input_num < 0) {
    return "That's a negative number";
  } else if (input_num > 100) {
    return "That's a pretty big number";
  } else {
    return "That's a number between 0 and 100!";
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_should_print_formatted_string_to_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <alloc_str@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rcx
  lea    D27(%rip),%rdx
  lea    D12(%rip),%rsi
  mov    %rax,%rdi
  call   <str_printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    $0xd,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <assert_string_equals@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_str@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D34
type_guessed: string

tool: D16: World

tool: D27: Hello

tool: D12: %s, %s!

tool: D34: Hello, World!

assistant: ```c
void test_should_print_formatted_string_to_value(void) {
  struct string *str = alloc_str();
  str_printf(str, "%s, %s!", "Hello", "World");
  assert_string_equals("Hello, World!", 13, str);
  free_str(str);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_should_print_formatted_string_to_value>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <alloc_str@plt>
  mov    %rax,%rbx
  lea    D2(%rip),%rcx
  lea    D3(%rip),%rdx
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <str_printf@plt>
  mov    %rbx,%rdx
  mov    $0xd,%esi
  lea    D0(%rip),%rdi
  call   <assert_string_equals@plt>
  mov    %rbx,%rdi
  call   <free_str@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D19
datatype: string
name: read_data
arguments: data_label: D0
datatype: string

tool: D2: World

tool: D3: Hello

tool: D19: %s, %s!

tool: D0: Hello, World!

assistant: ```c
void test_should_print_formatted_string_to_value(void) {
  struct string *str = alloc_str();
  str_printf(str, "%s, %s!", "Hello", "World");
  assert_string_equals("Hello, World!", 13, str);
  free_str(str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_should_print_formatted_string_to_value>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <alloc_str@plt>
  lea    D7(%rip),%rcx
  lea    D24(%rip),%rdx
  mov    %rax,%rbp
  lea    D39(%rip),%rsi
  mov    %rax,%rdi
  call   <str_printf@plt>
  mov    %rbp,%rdx
  mov    $0xd,%esi
  lea    D9(%rip),%rdi
  call   <assert_string_equals@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10a0 <free_str@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D39
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D7: World

tool: D24: Hello

tool: D39: %s, %s!

tool: D9: Hello, World!

assistant: ```c
void test_should_print_formatted_string_to_value(void) {
  struct string *str = alloc_str();
  str_printf(str, "%s, %s!", "Hello", "World");
  assert_string_equals("Hello, World!", 13, str);
  free_str(str);
}
```