ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlcat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L65
  jmp    L25
  nop
L70:
  add    $0x1,%rax
  add    $0x1,%rdi
  cmp    %rax,%rdx
  je     L25
L65:
  cmpb   $0x0,(%rdi)
  jne    L70
L51:
  movzbl (%rsi),%ecx
  sub    %rax,%rsi
  mov    %cl,(%rdi)
  test   %cl,%cl
  je     L58
  xchg   %ax,%ax
L42:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  cmp    %rdx,%rax
  adc    $0x0,%rdi
  mov    %cl,(%rdi)
  test   %cl,%cl
  jne    L42
L58:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  lea    0x7(%rsp),%rdi
  jmp    L51
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t strlcat(register char *dst, register const char *src, size_t n) {
  size_t len;
  char dummy[1];
  len = 0;
  while (1) {
    if (len >= n) {
      dst = dummy;
      break;
    }
    if (!*dst) {
      break;
    }
    ++dst;
    ++len;
  }
  while ((*dst = *src) != 0) {
    if (++len < n) {
      ++dst;
    }
    ++src;
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlcat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L66
  jmp    L23
  nop
L49:
  add    $0x1,%rax
  add    $0x1,%rdi
  cmp    %rax,%rdx
  je     L23
L66:
  cmpb   $0x0,(%rdi)
  jne    L49
L78:
  movzbl (%rsi),%ecx
  sub    %rax,%rsi
  mov    %cl,(%rdi)
  test   %cl,%cl
  je     L69
  xchg   %ax,%ax
L40:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  cmp    %rdx,%rax
  adc    $0x0,%rdi
  mov    %cl,(%rdi)
  test   %cl,%cl
  jne    L40
L69:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  lea    0x7(%rsp),%rdi
  jmp    L78
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t strlcat(register char *dst, register const char *src, size_t n) {
  size_t len;
  char dummy[1];
  len = 0;
  while (1) {
    if (len >= n) {
      dst = dummy;
      break;
    }
    if (!*dst) {
      break;
    }
    ++dst;
    ++len;
  }
  while ((*dst = *src) != 0) {
    if (++len < n) {
      ++dst;
    }
    ++src;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<profile_timestamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  rdtsc
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) uint64_t profile_timestamp(void) {
  uint64_t tsc;
  __asm__ __volatile__("rdtsc" : "=A"(tsc));
  return tsc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<profile_timestamp>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
__attribute__((always_)) uint64_t profile_timestamp(void) {
  uint64_t tsc;
  __asm__ __volatile__("rdtsc" : "=A"(tsc));
  return tsc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<profile_timestamp>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
__attribute__((always_)) uint64_t profile_timestamp(void) {
  uint64_t tsc;
  __asm__ __volatile__("rdtsc" : "=A"(tsc));
  return tsc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<profile_timestamp>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
__attribute__((always_)) uint64_t profile_timestamp(void) {
  uint64_t tsc;
  __asm__ __volatile__("rdtsc" : "=A"(tsc));
  return tsc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<x_cgo_mmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x30(%rbp),%r8d
  mov    -0x2c(%rbp),%edi
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <mmap@plt>
  mov    %rax,-0x8(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L4
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cltq
  jmp    L16
L4:
  mov    -0x8(%rbp),%rax
L16:
  leave
  ret
```

assistant: ```c
uintptr_t x_cgo_mmap(void *addr, uintptr_t length, int32_t prot, int32_t flags, int32_t fd, uint32_t offset) {
  void *p;
  ;
  p = mmap(addr, length, prot, flags, fd, offset);
  ;
  if (p == MAP_FAILED) {
    return (uintptr_t)errno;
  }
  return (uintptr_t)p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<x_cgo_mmap>:
  endbr64
  sub    $0x8,%rsp
  call   <mmap@plt>
  mov    %rax,%rdx
  mov    D15(%rip),%rcx
  cmp    %rax,(%rcx)
  je     L15
L19:
  mov    %rdx,%rax
  add    $0x8,%rsp
  ret
L15:
  mov    D16(%rip),%rax
  movslq (%rax),%rdx
  jmp    L19
```

assistant: ```c
uintptr_t x_cgo_mmap(void *addr, uintptr_t length, int32_t prot, int32_t flags, int32_t fd, uint32_t offset) {
  void *p;
  ;
  p = mmap(addr, length, prot, flags, fd, offset);
  ;
  if (p == MAP_FAILED) {
    return (uintptr_t)errno;
  }
  return (uintptr_t)p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<x_cgo_mmap>:
  endbr64
  sub    $0x8,%rsp
  call   <mmap@plt>
  mov    D6(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L1
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L1:
  mov    D7(%rip),%rax
  movslq (%rax),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uintptr_t x_cgo_mmap(void *addr, uintptr_t length, int32_t prot, int32_t flags, int32_t fd, uint32_t offset) {
  void *p;
  ;
  p = mmap(addr, length, prot, flags, fd, offset);
  ;
  if (p == MAP_FAILED) {
    return (uintptr_t)errno;
  }
  return (uintptr_t)p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<x_cgo_mmap>:
  endbr64
  sub    $0x8,%rsp
  call   <mmap@plt>
  mov    D1(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L4
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L4:
  mov    D15(%rip),%rax
  movslq (%rax),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uintptr_t x_cgo_mmap(void *addr, uintptr_t length, int32_t prot, int32_t flags, int32_t fd, uint32_t offset) {
  void *p;
  ;
  p = mmap(addr, length, prot, flags, fd, offset);
  ;
  if (p == MAP_FAILED) {
    return (uintptr_t)errno;
  }
  return (uintptr_t)p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decoded_number_basefmt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  cmpb   $0x20,-0x2(%rbp)
  jbe    L5
  cmpb   $0x7e,-0x2(%rbp)
  jbe    L34
L5:
  mov    $0xffff8000,%eax
  jmp    L31
L34:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x20,-0x1(%rbp)
  jbe    L45
  cmpb   $0x7e,-0x1(%rbp)
  jbe    L38
L45:
  mov    $0xffff8000,%eax
  jmp    L31
L38:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  movzbl -0x2(%rbp),%eax
  sub    $0x21,%eax
  imul   $0x5e,%eax,%edx
  movzbl -0x1(%rbp),%eax
  sub    $0x21,%eax
  add    %edx,%eax
  sub    $0x1142,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int decoded_number_basefmt(char **buf) {
  unsigned char c1, c2;
  c1 = (*buf)[0];
  if (c1 < '!' || c1 > '~')
    return (-32768);
  (*buf)++;
  c2 = (*buf)[0];
  if (c2 < '!' || c2 > '~')
    return (-32768);
  (*buf)++;
  return (((c1 - '!') * 94 + (c2 - '!')) - 4418);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decoded_number_basefmt>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  lea    -0x21(%rax),%ecx
  cmp    $0x5d,%cl
  ja     L10
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  movzbl 0x1(%rdx),%ecx
  lea    -0x21(%rcx),%esi
  cmp    $0x5d,%sil
  ja     L5
  add    $0x2,%rdx
  mov    %rdx,(%rdi)
  movzbl %al,%eax
  sub    $0x21,%eax
  imul   $0x5e,%eax,%eax
  movzbl %cl,%ecx
  lea    -0x1163(%rax,%rcx,1),%eax
  ret
L10:
  mov    $0xffff8000,%eax
  ret
L5:
  mov    $0xffff8000,%eax
  ret
```

assistant: ```c
int decoded_number_basefmt(char **buf) {
  unsigned char c1, c2;
  c1 = (*buf)[0];
  if (c1 < '!' || c1 > '~')
    return (-32768);
  (*buf)++;
  c2 = (*buf)[0];
  if (c2 < '!' || c2 > '~')
    return (-32768);
  (*buf)++;
  return (((c1 - '!') * 94 + (c2 - '!')) - 4418);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decoded_number_basefmt>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  lea    -0x21(%rax),%ecx
  cmp    $0x5d,%cl
  ja     L2
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  movzbl 0x1(%rdx),%ecx
  lea    -0x21(%rcx),%esi
  cmp    $0x5d,%sil
  ja     L2
  sub    $0x21,%eax
  add    $0x2,%rdx
  imul   $0x5e,%eax,%eax
  mov    %rdx,(%rdi)
  lea    -0x1163(%rax,%rcx,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0xffff8000,%eax
  ret
```

assistant: ```c
int decoded_number_basefmt(char **buf) {
  unsigned char c1, c2;
  c1 = (*buf)[0];
  if (c1 < '!' || c1 > '~')
    return (-32768);
  (*buf)++;
  c2 = (*buf)[0];
  if (c2 < '!' || c2 > '~')
    return (-32768);
  (*buf)++;
  return (((c1 - '!') * 94 + (c2 - '!')) - 4418);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decoded_number_basefmt>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  lea    -0x21(%rax),%ecx
  cmp    $0x5d,%cl
  ja     L16
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  movzbl 0x1(%rdx),%ecx
  lea    -0x21(%rcx),%esi
  cmp    $0x5d,%sil
  ja     L16
  sub    $0x21,%eax
  add    $0x2,%rdx
  imul   $0x5e,%eax,%eax
  mov    %rdx,(%rdi)
  lea    -0x1163(%rax,%rcx,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffff8000,%eax
  ret
```

assistant: ```c
int decoded_number_basefmt(char **buf) {
  unsigned char c1, c2;
  c1 = (*buf)[0];
  if (c1 < '!' || c1 > '~')
    return (-32768);
  (*buf)++;
  c2 = (*buf)[0];
  if (c2 < '!' || c2 > '~')
    return (-32768);
  (*buf)++;
  return (((c1 - '!') * 94 + (c2 - '!')) - 4418);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_mutex_tryacquire>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  movzwl %ax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x2,%eax
  movzbl %al,%eax
  or     %edx,%eax
  or     $0x13020000,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  mov    $0xffffffff,%eax
  jmp    L1
L11:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int _mutex_tryacquire(unsigned int tid, unsigned int mid) {
  unsigned int cmd;
  unsigned int sta;
  cmd = (((0x13000000)) | ((2 & ((1 << 3) - 1)) << (8 + (6 + 2))) | ((tid & ((1 << 8) - 1)) << (6 + 2)) | ((mid & ((1 << 6) - 1)) << 2));
  sta = (*(volatile unsigned int *)(cmd));
  if (((sta) != 0))
    return (-1);
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_mutex_tryacquire>:
  endbr64
  shl    $0x8,%edi
  movzwl %di,%edi
  shl    $0x2,%esi
  movzbl %sil,%esi
  or     %esi,%edi
  or     $0x13020000,%edi
  mov    (%edi),%eax
  neg    %eax
  sbb    %eax,%eax
  ret
```

assistant: ```c
int _mutex_tryacquire(unsigned int tid, unsigned int mid) {
  unsigned int cmd;
  unsigned int sta;
  cmd = (((0x13000000)) | ((2 & ((1 << 3) - 1)) << (8 + (6 + 2))) | ((tid & ((1 << 8) - 1)) << (6 + 2)) | ((mid & ((1 << 6) - 1)) << 2));
  sta = (*(volatile unsigned int *)(cmd));
  if (((sta) != 0))
    return (-1);
  else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_mutex_tryacquire>:
  endbr64
  shl    $0x8,%edi
  shl    $0x2,%esi
  movzbl %sil,%esi
  movzwl %di,%edi
  or     %esi,%edi
  or     $0x13020000,%edi
  mov    (%edi),%eax
  neg    %eax
  sbb    %eax,%eax
  ret
```

assistant: ```c
int _mutex_tryacquire(unsigned int tid, unsigned int mid) {
  unsigned int cmd;
  unsigned int sta;
  cmd = (((0x13000000)) | ((2 & ((1 << 3) - 1)) << (8 + (6 + 2))) | ((tid & ((1 << 8) - 1)) << (6 + 2)) | ((mid & ((1 << 6) - 1)) << 2));
  sta = (*(volatile unsigned int *)(cmd));
  if (((sta) != 0))
    return (-1);
  else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_mutex_tryacquire>:
  endbr64
  shl    $0x8,%edi
  shl    $0x2,%esi
  movzbl %sil,%esi
  movzwl %di,%edi
  or     %esi,%edi
  or     $0x13020000,%edi
  mov    (%edi),%eax
  neg    %eax
  sbb    %eax,%eax
  ret
```

assistant: ```c
int _mutex_tryacquire(unsigned int tid, unsigned int mid) {
  unsigned int cmd;
  unsigned int sta;
  cmd = (((0x13000000)) | ((2 & ((1 << 3) - 1)) << (8 + (6 + 2))) | ((tid & ((1 << 8) - 1)) << (6 + 2)) | ((mid & ((1 << 6) - 1)) << 2));
  sta = (*(volatile unsigned int *)(cmd));
  if (((sta) != 0))
    return (-1);
  else
    return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dec_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
L11:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  mov    %al,-0x12(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x12(%rbp),%eax
  mov    %al,(%rdx)
  cmpl   $0x0,-0x10(%rbp)
  jne    L11
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L22
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int dec_to_str(const int num, char ostr[]) {
  int quot, i;
  char rem;
  quot = num;
  i = 0;
  do {
    rem = (quot % 10) + '0';
    quot /= 10;
    ostr[i++] = rem;
  } while (quot);
  int start, end;
  char temp;
  for (end = i - 1, start = 0; start < end; end--, start++) {
    temp = ostr[start];
    ostr[start] = ostr[end];
    ostr[end] = temp;
  }
  ostr[i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dec_to_str>:
  endbr64
  mov    %rsi,%rcx
  mov    %rsi,%r8
  mov    $0x0,%esi
L9:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    0x30(%rdi),%r9d
  mov    %eax,%edi
  mov    %esi,%edx
  add    $0x1,%esi
  mov    %r9b,(%r8)
  add    $0x1,%r8
  test   %eax,%eax
  jne    L9
  test   %edx,%edx
  jle    L16
  movslq %edx,%rax
  mov    $0x0,%edx
L22:
  movzbl (%rcx,%rdx,1),%edi
  movzbl (%rcx,%rax,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L22
L16:
  movslq %esi,%rax
  movb   $0x0,(%rcx,%rax,1)
  mov    %esi,%eax
  ret
```

assistant: ```c
int dec_to_str(const int num, char ostr[]) {
  int quot, i;
  char rem;
  quot = num;
  i = 0;
  do {
    rem = (quot % 10) + '0';
    quot /= 10;
    ostr[i++] = rem;
  } while (quot);
  int start, end;
  char temp;
  for (end = i - 1, start = 0; start < end; end--, start++) {
    temp = ostr[start];
    ostr[start] = ostr[end];
    ostr[end] = temp;
  }
  ostr[i] = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dec_to_str>:
  endbr64
  mov    %rsi,%rcx
  mov    %rsi,%r9
  xor    %r8d,%r8d
  nopl   (%rax)
L25:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r9
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    0x30(%rdi),%esi
  mov    %eax,%edi
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %sil,-0x1(%r9)
  test   %edi,%edi
  jne    L25
  test   %eax,%eax
  je     L10
  xor    %edx,%edx
  jmp    L34
  nopl   0x0(%rax)
L15:
  movzbl (%rcx,%rax,1),%esi
L34:
  movzbl (%rcx,%rdx,1),%edi
  mov    %sil,(%rcx,%rdx,1)
  add    $0x1,%rdx
  mov    %dil,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L15
L10:
  movslq %r8d,%rax
  movb   $0x0,(%rcx,%rax,1)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int dec_to_str(const int num, char ostr[]) {
  int quot, i;
  char rem;
  quot = num;
  i = 0;
  do {
    rem = (quot % 10) + '0';
    quot /= 10;
    ostr[i++] = rem;
  } while (quot);
  int start, end;
  char temp;
  for (end = i - 1, start = 0; start < end; end--, start++) {
    temp = ostr[start];
    ostr[start] = ostr[end];
    ostr[end] = temp;
  }
  ostr[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dec_to_str>:
  endbr64
  mov    %rsi,%rcx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L26:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%rsi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    0x30(%rdi),%edx
  mov    %eax,%edi
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %dl,-0x1(%rsi)
  test   %edi,%edi
  jne    L26
  test   %eax,%eax
  je     L24
  xor    %edx,%edx
  nopl   0x0(%rax)
L2:
  movzbl (%rcx,%rdx,1),%esi
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  add    $0x1,%rdx
  mov    %sil,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L2
L24:
  movslq %r8d,%rax
  movb   $0x0,(%rcx,%rax,1)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int dec_to_str(const int num, char ostr[]) {
  int quot, i;
  char rem;
  quot = num;
  i = 0;
  do {
    rem = (quot % 10) + '0';
    quot /= 10;
    ostr[i++] = rem;
  } while (quot);
  int start, end;
  char temp;
  for (end = i - 1, start = 0; start < end; end--, start++) {
    temp = ostr[start];
    ostr[start] = ostr[end];
    ostr[end] = temp;
  }
  ostr[i] = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f2u>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned f2u(float n) {
  float *p = &n;
  return *((unsigned *)p);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f2u>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
unsigned f2u(float n) {
  float *p = &n;
  return *((unsigned *)p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f2u>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
unsigned f2u(float n) {
  float *p = &n;
  return *((unsigned *)p);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f2u>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
unsigned f2u(float n) {
  float *p = &n;
  return *((unsigned *)p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <rekur_euk@plt>
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D49
type_guessed: string
name: read_data
arguments: data_tag: D36
type_guessed: string
name: read_data
arguments: data_tag: D48
type_guessed: string

tool: D2: a = 

tool: D49: %d

tool: D36: b = 

tool: D48: rekur_euk(%d)


assistant: ```c
int main(void) {
  int a, b;
  printf("a = ");
  scanf("%d", &a);
  printf("b = ");
  scanf("%d", &b);
  printf("rekur_euk(%d)\n", rekur_euk(b, (a % b)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D36(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%eax
  cltd
  idiv   %edi
  mov    %edx,%esi
  call   <rekur_euk@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D32
type_infered: string
name: retrieve_data
arguments: label: D36
type_infered: string
name: retrieve_data
arguments: label: D33
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string

tool: D32: a = 

tool: D36: %d

tool: D33: b = 

tool: D29: rekur_euk(%d)


assistant: ```c
int main(void) {
  int a, b;
  printf("a = ");
  scanf("%d", &a);
  printf("b = ");
  scanf("%d", &b);
  printf("rekur_euk(%d)\n", rekur_euk(b, (a % b)));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  lea    D12(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edi
  cltd
  idiv   %edi
  mov    %edx,%esi
  call   <rekur_euk@plt>
  lea    D35(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D7
data_type: string
name: parse_data
arguments: label: D35
data_type: string

tool: D16: a = 

tool: D12: %d

tool: D7: b = 

tool: D35: rekur_euk(%d)


assistant: ```c
int main(void) {
  int a, b;
  printf("a = ");
  scanf("%d", &a);
  printf("b = ");
  scanf("%d", &b);
  printf("rekur_euk(%d)\n", rekur_euk(b, (a % b)));
}
```