ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<escape_char>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  movsbl %sil,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <char_occurrences@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%r14
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L21:
  movzbl (%r12,%rbx,1),%edx
  cmp    %r13b,%dl
  jne    L25
  movb   $0x5c,(%rcx)
  add    $0x1,%ebp
  movzbl (%r12,%rbx,1),%edx
  movslq %ebp,%rax
L25:
  mov    %dl,(%r14,%rax,1)
  add    $0x1,%rbx
  add    $0x1,%ebp
L29:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  movslq %ebp,%rax
  lea    (%r14,%rax,1),%rcx
  cmp    %ebx,%r8d
  jg     L21
  movb   $0x0,(%rcx)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *escape_char(char *s, char c) {
  int n = char_occurrences(s, c);
  char *new = malloc(strlen(s) + n + 1);
  int j = 0;
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == c)
      new[j++] = '\\';
    new[j++] = s[i];
  }
  new[j] = '\0';
  return new;
}
```
user: Translate the below assembly code into C programming language:

```asm
<escape_char>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  movsbl %sil,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <char_occurrences@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%r14
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl (%r12,%rbx,1),%edx
  cmp    %r13b,%dl
  jne    L11
  movb   $0x5c,(%rcx)
  add    $0x1,%ebp
  movzbl (%r12,%rbx,1),%edx
  movslq %ebp,%rax
L11:
  mov    %dl,(%r14,%rax,1)
  add    $0x1,%rbx
  add    $0x1,%ebp
L21:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  movslq %ebp,%rax
  lea    (%r14,%rax,1),%rcx
  cmp    %ebx,%r8d
  jg     L25
  movb   $0x0,(%rcx)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *escape_char(char *s, char c) {
  int n = char_occurrences(s, c);
  char *new = malloc(strlen(s) + n + 1);
  int j = 0;
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == c)
      new[j++] = '\\';
    new[j++] = s[i];
  }
  new[j] = '\0';
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<indexof_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L40
L16:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L16
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L38
  mov    -0x4(%rbp),%eax
  jmp    L12
L38:
  mov    $0xffffffff,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int indexof_char(char *s, int ch) {
  int i = 0;
  while (*s && (*s) != ch) {
    s++;
    i++;
  }
  if (*s)
    return i;
  else
    return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<indexof_char>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  mov    $0xffffffff,%r8d
  test   %dl,%dl
  je     L13
L29:
  mov    %eax,%r8d
  movsbl %dl,%ecx
  cmp    %esi,%ecx
  je     L7
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L29
  mov    $0xffffffff,%r8d
  jmp    L13
L7:
  test   %dl,%dl
  mov    $0xffffffff,%eax
  cmove  %eax,%r8d
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int indexof_char(char *s, int ch) {
  int i = 0;
  while (*s && (*s) != ch) {
    s++;
    i++;
  }
  if (*s)
    return i;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<indexof_char>:
  endbr64
  movsbl (%rdi),%eax
  xor    %edx,%edx
  test   %al,%al
  jne    L14
  jmp    L35
  nop
L28:
  add    $0x1,%rdx
  movsbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L35
L14:
  mov    %edx,%r8d
  cmp    %esi,%eax
  jne    L28
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int indexof_char(char *s, int ch) {
  int i = 0;
  while (*s && (*s) != ch) {
    s++;
    i++;
  }
  if (*s)
    return i;
  else
    return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<indexof_char>:
  endbr64
  movsbl (%rdi),%eax
  xor    %edx,%edx
  test   %al,%al
  jne    L18
  jmp    L15
  nop
L19:
  add    $0x1,%rdx
  movsbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L15
L18:
  mov    %edx,%r8d
  cmp    %esi,%eax
  jne    L19
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int indexof_char(char *s, int ch) {
  int i = 0;
  while (*s && (*s) != ch) {
    s++;
    i++;
  }
  if (*s)
    return i;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hash(char *sz) {
  int i;
  for (i = 0; *sz; sz++)
    i += *sz;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  mov    $0x0,%edx
L3:
  movsbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L3
L21:
  mov    %edx,%eax
  ret
L11:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
int hash(char *sz) {
  int i;
  for (i = 0; *sz; sz++)
    i += *sz;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L18
  xchg   %ax,%ax
L6:
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L6
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hash(char *sz) {
  int i;
  for (i = 0; *sz; sz++)
    i += *sz;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L0
  xchg   %ax,%ax
L3:
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L3
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hash(char *sz) {
  int i;
  for (i = 0; *sz; sz++)
    i += *sz;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dibujarCartaTapada>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getmaxyx@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L5
L37:
  movl   $0x2,-0x10(%rbp)
  jmp    L22
L21:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rax,%rdi
  call   <mvwprintw@plt>
  addl   $0x1,-0x10(%rbp)
L22:
  mov    -0x10(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x4(%rbp)
  jg     L21
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L37
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wrefresh@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: .

assistant: ```c
void dibujarCartaTapada(WINDOW *ventana) {
  int row, col;
  getmaxyx(ventana, row, col);
  int x, y;
  for (y = 2; y + 2 < row; y++) {
    for (x = 2; x + 2 < col; x++) {
      mvwprintw(ventana, y, x, ".");
    }
  }
  wrefresh(ventana);
}
```
user: What is the c source code of the assembly code below:

```asm
<dibujarCartaTapada>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <getmaxyx@plt>
  mov    %rbx,%rdi
  call   <wrefresh@plt>
  pop    %rbx
  ret
```

assistant: ```c
void dibujarCartaTapada(WINDOW *ventana) {
  int row, col;
  getmaxyx(ventana, row, col);
  int x, y;
  for (y = 2; y + 2 < row; y++) {
    for (x = 2; x + 2 < col; x++) {
      mvwprintw(ventana, y, x, ".");
    }
  }
  wrefresh(ventana);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dibujarCartaTapada>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rdi,%rbp
  xor    %esi,%esi
  call   <getmaxyx@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <wrefresh@plt>
```

assistant: ```c
void dibujarCartaTapada(WINDOW *ventana) {
  int row, col;
  getmaxyx(ventana, row, col);
  int x, y;
  for (y = 2; y + 2 < row; y++) {
    for (x = 2; x + 2 < col; x++) {
      mvwprintw(ventana, y, x, ".");
    }
  }
  wrefresh(ventana);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dibujarCartaTapada>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rdi,%rbp
  xor    %esi,%esi
  call   <getmaxyx@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <wrefresh@plt>
```

assistant: ```c
void dibujarCartaTapada(WINDOW *ventana) {
  int row, col;
  getmaxyx(ventana, row, col);
  int x, y;
  for (y = 2; y + 2 < row; y++) {
    for (x = 2; x + 2 < col; x++) {
      mvwprintw(ventana, y, x, ".");
    }
  }
  wrefresh(ventana);
}
```
user: Translate the below assembly code into C programming language:

```asm
<answer_ping>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L16
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string
name: parse_data
arguments: tag: D12
data_type: string

tool: D3: ping %d

tool: D12: pong %d


assistant: ```c
void answer_ping(char *c) {
  int tmp;
  if (sscanf(c, "ping %d", &tmp) == 1)
    printf("pong %d\n", tmp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<answer_ping>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    D0(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L23
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  ret
L23:
  mov    0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string

tool: D0: ping %d

tool: D7: pong %d


assistant: ```c
void answer_ping(char *c) {
  int tmp;
  if (sscanf(c, "ping %d", &tmp) == 1)
    printf("pong %d\n", tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<answer_ping>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L5
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D1: ping %d

tool: D3: pong %d


assistant: ```c
void answer_ping(char *c) {
  int tmp;
  if (sscanf(c, "ping %d", &tmp) == 1)
    printf("pong %d\n", tmp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<answer_ping>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L28
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string

tool: D19: ping %d

tool: D1: pong %d


assistant: ```c
void answer_ping(char *c) {
  int tmp;
  if (sscanf(c, "ping %d", &tmp) == 1)
    printf("pong %d\n", tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BlinkC__Timer2__fired>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <BlinkC__Leds__led2Toggle@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BlinkC__Timer2__fired(void) {
  ;
  BlinkC__Leds__led2Toggle();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<BlinkC__Timer2__fired>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <BlinkC__Leds__led2Toggle@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BlinkC__Timer2__fired(void) {
  ;
  BlinkC__Leds__led2Toggle();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BlinkC__Timer2__fired>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <BlinkC__Leds__led2Toggle@plt>
```

assistant: ```c
void BlinkC__Timer2__fired(void) {
  ;
  BlinkC__Leds__led2Toggle();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_vscprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _vscprintf(const char *format, va_list argp) {
  int r;
  va_list argc;
  va_copy(argc, argp);
  r = vsnprintf(NULL, 0, format, argc);
  va_end(argc);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_vscprintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_copy@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _vscprintf(const char *format, va_list argp) {
  int r;
  va_list argc;
  va_copy(argc, argp);
  r = vsnprintf(NULL, 0, format, argc);
  va_end(argc);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_vscprintf>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_copy@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _vscprintf(const char *format, va_list argp) {
  int r;
  va_list argc;
  va_copy(argc, argp);
  r = vsnprintf(NULL, 0, format, argc);
  va_end(argc);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_vscprintf>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_copy@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _vscprintf(const char *format, va_list argp) {
  int r;
  va_list argc;
  va_copy(argc, argp);
  r = vsnprintf(NULL, 0, format, argc);
  va_end(argc);
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strip_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L16
  cmpq   $0x0,-0x20(%rbp)
  je     L16
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L26
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L26
  mov    -0xc(%rbp),%eax
  cltq
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L17
L16:
  nop
  jmp    L17
L26:
  nop
L17:
  leave
  ret
```

assistant: ```c
void strip_ext(char *name, const char *ext) {
  char *ext_loc;
  int ext_len;
  int name_len;
  if (!name || !ext)
    return;
  ext_len = (int)strlen(ext);
  name_len = (int)strlen(name);
  if (ext_len == 0 || name_len <= ext_len)
    return;
  ext_loc = name + name_len - ext_len;
  if (strcasecmp(ext_loc, ext) == 0)
    *ext_loc = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strip_ext>:
  endbr64
  test   %rdi,%rdi
  je     L13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L17
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L17
  cmp    %eax,%r12d
  jge    L17
  cltq
  movslq %r12d,%r12
  sub    %r12,%rax
  add    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L17
  movb   $0x0,(%rbx)
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  ret
```

assistant: ```c
void strip_ext(char *name, const char *ext) {
  char *ext_loc;
  int ext_len;
  int name_len;
  if (!name || !ext)
    return;
  ext_len = (int)strlen(ext);
  name_len = (int)strlen(name);
  if (ext_len == 0 || name_len <= ext_len)
    return;
  ext_loc = name + name_len - ext_len;
  if (strcasecmp(ext_loc, ext) == 0)
    *ext_loc = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_ext>:
  endbr64
  test   %rdi,%rdi
  je     L44
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %rsi,%rsi
  je     L47
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L47
  cmp    %eax,%r12d
  jge    L47
  cltq
  movslq %r12d,%r12
  mov    %rbp,%rsi
  sub    %r12,%rax
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L47
  movb   $0x0,(%rbx)
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  ret
```

assistant: ```c
void strip_ext(char *name, const char *ext) {
  char *ext_loc;
  int ext_len;
  int name_len;
  if (!name || !ext)
    return;
  ext_len = (int)strlen(ext);
  name_len = (int)strlen(name);
  if (ext_len == 0 || name_len <= ext_len)
    return;
  ext_loc = name + name_len - ext_len;
  if (strcasecmp(ext_loc, ext) == 0)
    *ext_loc = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip_ext>:
  endbr64
  test   %rdi,%rdi
  je     L41
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %rsi,%rsi
  je     L37
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L37
  cmp    %eax,%r12d
  jge    L37
  cltq
  movslq %r12d,%r12
  mov    %rbp,%rsi
  sub    %r12,%rax
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L37
  movb   $0x0,(%rbx)
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  ret
```

assistant: ```c
void strip_ext(char *name, const char *ext) {
  char *ext_loc;
  int ext_len;
  int name_len;
  if (!name || !ext)
    return;
  ext_len = (int)strlen(ext);
  name_len = (int)strlen(name);
  if (ext_len == 0 || name_len <= ext_len)
    return;
  ext_loc = name + name_len - ext_len;
  if (strcasecmp(ext_loc, ext) == 0)
    *ext_loc = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  sub    $0x8,%rsp
  lea    0x17(%rsp),%rax
  push   %rax
  lea    0x1e(%rsp),%rax
  push   %rax
  lea    0x3c(%rsp),%rax
  push   %rax
  lea    0x40(%rsp),%rax
  push   %rax
  push   %rcx
  lea    0x4c(%rsp),%r9
  lea    0x48(%rsp),%r8
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  add    $0x30,%rsp
  cmpb   $0x41,0xe(%rsp)
  je     L54
  mov    0x10(%rsp),%esi
  cmp    $0x1,%esi
  jne    L65
  cmpl   $0x2,0x14(%rsp)
  je     L17
L65:
  mov    0x14(%rsp),%eax
  lea    0x2(%rax),%edx
  add    $0x1,%esi
  sub    $0x8,%rsp
  mov    0x2c(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%r9d
  mov    0x2c(%rsp),%r8d
  mov    0x28(%rsp),%ecx
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
L37:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L54:
  mov    0x10(%rsp),%esi
  cmp    $0x1,%esi
  jne    L0
  cmpl   $0x2,0x14(%rsp)
  je     L31
L0:
  sub    $0x8,%rsp
  mov    0x2c(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%r9d
  mov    0x2c(%rsp),%r8d
  mov    0x28(%rsp),%ecx
  mov    0x24(%rsp),%edx
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  jmp    L37
L31:
  mov    0x24(%rsp),%r8d
  mov    0x20(%rsp),%ecx
  mov    0x1c(%rsp),%edx
  mov    0x18(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L17:
  mov    0x24(%rsp),%r8d
  mov    0x20(%rsp),%ecx
  mov    0x1c(%rsp),%edx
  mov    0x18(%rsp),%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D42
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D44
data_type: string

tool: D42: %1d%1d%c%1d%1d%c%1d%1d%c%c

tool: D21: %d%d:%d%d:%d%d

tool: D19: 00:%d%d:%d%d

tool: D44: 12:%d%d:%d%d

assistant: ```c
int main() {
  int h1, h2, m1, m2, s1, s2;
  char a, b, c;
  scanf("%1d%1d%c%1d%1d%c%1d%1d%c%c", &h1, &h2, &a, &m1, &m2, &a, &s1, &s2, &b, &c);
  if (b == 'A') {
    if (h1 == 1 && h2 == 2)
      printf("00:%d%d:%d%d", m1, m2, s1, s2);
    else
      printf("%d%d:%d%d:%d%d", h1, h2, m1, m2, s1, s2);
  } else {
    if (h1 == 1 && h2 == 2)
      printf("12:%d%d:%d%d", m1, m2, s1, s2);
    else
      printf("%d%d:%d%d:%d%d", h1 + 1, h2 + 2, m1, m2, s1, s2);
  }
  return 0;
}
```