ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<f2m_print_human>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0x10(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L30
L63:
  subl   $0x1,-0x14(%rbp)
  movl   $0x80000000,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L52:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    %esi,%eax
  test   %eax,%eax
  je     L107
  cmpl   $0x0,-0x10(%rbp)
  je     L8
  movl   $0x0,-0x10(%rbp)
  jmp    L103
L8:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L103:
  mov    -0x14(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    $0x1f,%eax
  sub    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L101
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L107
L101:
  cmpl   $0x1,-0x4(%rbp)
  jne    L33
  mov    $0x7a,%edi
  call   <putchar@plt>
  jmp    L107
L33:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L107:
  addl   $0x1,-0xc(%rbp)
L13:
  cmpl   $0x1f,-0xc(%rbp)
  jle    L52
L30:
  cmpl   $0x0,-0x14(%rbp)
  jg     L63
  cmpl   $0x0,-0x10(%rbp)
  je     L109
  mov    $0x30,%edi
  call   <putchar@plt>
L109:
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D25
datatype: string
name: read_data
arguments: data_tag: D12
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string

tool: D25: f(z) = 

tool: D12:  + 

tool: D5: z^%d

assistant: ```c
void f2m_print_human(uint32_t t, uint32_t *A) {
  uint32_t i;
  bool first = true;
  printf("f(z) = ");
  for (i = t; i > 0;) {
    i--;
    uint32_t j;
    uint32_t mask = 0x80000000;
    for (j = 0; j < 32; j++) {
      if (A[i] & (mask >> j)) {
        if (first) {
          first = false;
        } else {
          printf(" + ");
        }
        int exp = i * 32 + (31 - j);
        if (exp == 0) {
          printf("1");
        } else if (exp == 1) {
          printf("z");
        } else {
          printf("z^%d", exp);
        }
      }
    }
  }
  if (first) {
    printf("0");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<f2m_print_human>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rbx
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r15d,%r15d
  jle    L64
  movslq %r15d,%rax
  lea    (%rbx,%rax,4),%r13
  mov    $0x1,%r12d
  mov    $0x80000000,%r14d
  jmp    L129
L22:
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
L58:
  mov    $0x31,%edi
  call   <putchar@plt>
L123:
  add    $0x1,%ebx
  sub    $0x1,%ebp
  cmp    $0x20,%ebx
  je     L57
L111:
  mov    %r14d,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    -0x4(%r13),%eax
  je     L123
  test   %r12d,%r12d
  je     L22
L34:
  mov    %ebp,%r12d
  test   %ebp,%ebp
  je     L58
  cmp    $0x1,%ebp
  je     L93
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r15d,%r12d
  jmp    L123
L93:
  mov    $0x7a,%edi
  call   <putchar@plt>
  mov    %r15d,%r12d
  jmp    L123
L57:
  sub    $0x4,%r13
  cmpl   $0x0,0xc(%rsp)
  je     L96
L129:
  subl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  mov    %eax,%ebp
  shl    $0x5,%ebp
  add    $0x1f,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  jmp    L111
L96:
  test   %r12d,%r12d
  jne    L64
L85:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L85
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D14
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D16: f(z) = 

tool: D14:  + 

tool: D8: z^%d

assistant: ```c
void f2m_print_human(uint32_t t, uint32_t *A) {
  uint32_t i;
  bool first = true;
  printf("f(z) = ");
  for (i = t; i > 0;) {
    i--;
    uint32_t j;
    uint32_t mask = 0x80000000;
    for (j = 0; j < 32; j++) {
      if (A[i] & (mask >> j)) {
        if (first) {
          first = false;
        } else {
          printf(" + ");
        }
        int exp = i * 32 + (31 - j);
        if (exp == 0) {
          printf("1");
        } else if (exp == 1) {
          printf("z");
        } else {
          printf("z^%d", exp);
        }
      }
    }
  }
  if (first) {
    printf("0");
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f2m_print_human>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %edi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    D8(%rip),%rdi
  call   <printf@plt>
  test   %r15d,%r15d
  jle    L12
  movslq %r15d,%rax
  mov    $0x80000000,%r12d
  mov    $0x1,%r15d
  lea    (%rbx,%rax,4),%rbp
  lea    D11(%rip),%r13
  nopl   (%rax)
L29:
  subl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%edx
  xor    %ebx,%ebx
  shl    $0x5,%edx
  lea    0x1f(%rdx),%r14d
  jmp    L84
  nopl   0x0(%rax)
L16:
  mov    %r14d,%r15d
  test   %r14d,%r14d
  je     L81
L13:
  cmp    $0x1,%r14d
  je     L79
  mov    %r14d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <printf@plt>
L90:
  add    $0x1,%ebx
  sub    $0x1,%r14d
  cmp    $0x20,%ebx
  je     L67
L84:
  mov    %r12d,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    -0x4(%rbp),%eax
  je     L90
  test   %r15d,%r15d
  jne    L16
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  mov    %r14d,%r15d
  call   <printf@plt>
  test   %r14d,%r14d
  jne    L13
L81:
  mov    $0x31,%edi
  add    $0x1,%ebx
  sub    $0x1,%r14d
  call   <putchar@plt>
  cmp    $0x20,%ebx
  jne    L84
  nopl   0x0(%rax,%rax,1)
L67:
  mov    0xc(%rsp),%eax
  sub    $0x4,%rbp
  test   %eax,%eax
  jne    L29
  test   %r15d,%r15d
  jne    L12
L124:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   (%rax)
L79:
  mov    $0x7a,%edi
  xor    %r15d,%r15d
  call   <putchar@plt>
  jmp    L90
L12:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L124
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D11
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D8: f(z) = 

tool: D11: z^%d

tool: D2:  + 

assistant: ```c
void f2m_print_human(uint32_t t, uint32_t *A) {
  uint32_t i;
  bool first = true;
  printf("f(z) = ");
  for (i = t; i > 0;) {
    i--;
    uint32_t j;
    uint32_t mask = 0x80000000;
    for (j = 0; j < 32; j++) {
      if (A[i] & (mask >> j)) {
        if (first) {
          first = false;
        } else {
          printf(" + ");
        }
        int exp = i * 32 + (31 - j);
        if (exp == 0) {
          printf("1");
        } else if (exp == 1) {
          printf("z");
        } else {
          printf("z^%d", exp);
        }
      }
    }
  }
  if (first) {
    printf("0");
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f2m_print_human>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %edi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    D15(%rip),%rdi
  call   <printf@plt>
  test   %r15d,%r15d
  jle    L104
  movslq %r15d,%rax
  mov    $0x80000000,%r12d
  mov    $0x1,%r15d
  lea    (%rbx,%rax,4),%rbp
  lea    D9(%rip),%r13
  nopl   (%rax)
L19:
  subl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%edx
  xor    %ebx,%ebx
  shl    $0x5,%edx
  lea    0x1f(%rdx),%r14d
  jmp    L90
  nopl   0x0(%rax)
L47:
  mov    %r14d,%r15d
  test   %r14d,%r14d
  je     L74
L127:
  cmp    $0x1,%r14d
  je     L30
  mov    %r14d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <printf@plt>
L117:
  add    $0x1,%ebx
  sub    $0x1,%r14d
  cmp    $0x20,%ebx
  je     L33
L90:
  mov    %r12d,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    -0x4(%rbp),%eax
  je     L117
  test   %r15d,%r15d
  jne    L47
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  mov    %r14d,%r15d
  call   <printf@plt>
  test   %r14d,%r14d
  jne    L127
L74:
  mov    $0x31,%edi
  add    $0x1,%ebx
  sub    $0x1,%r14d
  call   <putchar@plt>
  cmp    $0x20,%ebx
  jne    L90
  nopl   0x0(%rax,%rax,1)
L33:
  mov    0xc(%rsp),%eax
  sub    $0x4,%rbp
  test   %eax,%eax
  jne    L19
  test   %r15d,%r15d
  jne    L104
L126:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   (%rax)
L30:
  mov    $0x7a,%edi
  xor    %r15d,%r15d
  call   <putchar@plt>
  jmp    L117
L104:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L126
```

tool_calls: name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D9
type_guessed: string
name: read_data
arguments: label: D0
type_guessed: string

tool: D15: f(z) = 

tool: D9: z^%d

tool: D0:  + 

assistant: ```c
void f2m_print_human(uint32_t t, uint32_t *A) {
  uint32_t i;
  bool first = true;
  printf("f(z) = ");
  for (i = t; i > 0;) {
    i--;
    uint32_t j;
    uint32_t mask = 0x80000000;
    for (j = 0; j < 32; j++) {
      if (A[i] & (mask >> j)) {
        if (first) {
          first = false;
        } else {
          printf(" + ");
        }
        int exp = i * 32 + (31 - j);
        if (exp == 0) {
          printf("1");
        } else if (exp == 1) {
          printf("z");
        } else {
          printf("z^%d", exp);
        }
      }
    }
  }
  if (first) {
    printf("0");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<aim_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int aim_main(int argc, char *argv[]) {
  (void)argc;
  (void)argv;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aim_main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int aim_main(int argc, char *argv[]) {
  (void)argc;
  (void)argv;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<aim_main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int aim_main(int argc, char *argv[]) {
  (void)argc;
  (void)argv;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aim_main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int aim_main(int argc, char *argv[]) {
  (void)argc;
  (void)argv;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tu_strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  je     L115
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L105
L115:
  mov    $0x0,%eax
  jmp    L2
L105:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L2
L38:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L12:
  movl   $0x0,-0x14(%rbp)
  jmp    L118
L126:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L114
  movl   $0x1,-0x10(%rbp)
  jmp    L62
L114:
  addl   $0x1,-0x14(%rbp)
L118:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jb     L126
L62:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  cmpl   $0x1,-0x10(%rbp)
  je     L20
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L6:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  jmp    L70
L20:
  nop
L70:
  cmpl   $0x0,-0x10(%rbp)
  jne    L49
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
L49:
  mov    -0x8(%rbp),%rax
L2:
  leave
  ret
```

assistant: ```c
char *tu_strtok(char **str, unsigned int *match_length, const char *delimiters) {
  char *start_ptr;
  unsigned int cur_delimiter, delimiters_length, delimiter_found;
  *match_length = 0;
  if (str == NULL || *str == NULL)
    return NULL;
  delimiters_length = strlen(delimiters);
  if (delimiters_length == 0)
    return NULL;
  start_ptr = *str;
  delimiter_found = 0;
  while (**str) {
    for (cur_delimiter = 0; cur_delimiter < delimiters_length; cur_delimiter++)
      if (**str == *(delimiters + cur_delimiter)) {
        delimiter_found = 1;
        break;
      }
    (*str)++;
    if (delimiter_found == 1)
      break;
    (*match_length)++;
  }
  if (delimiter_found == 0)
    *match_length = 0;
  return start_ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tu_strtok>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L1
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  mov    %rdx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L33
  mov    (%rbx),%rdi
  movzbl (%rdi),%edx
  mov    %rdi,%rsi
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%rcx
  test   %dl,%dl
  jne    L41
L36:
  movl   $0x0,0x0(%rbp)
L1:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  add    $0x1,%rsi
  mov    %rsi,(%rbx)
  addl   $0x1,0x0(%rbp)
  mov    (%rbx),%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L36
L41:
  mov    %r12,%rax
L54:
  cmp    %dl,(%rax)
  je     L67
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L54
  jmp    L28
L33:
  mov    $0x0,%edi
  jmp    L1
L67:
  add    $0x1,%rsi
  mov    %rsi,(%rbx)
  jmp    L1
```

assistant: ```c
char *tu_strtok(char **str, unsigned int *match_length, const char *delimiters) {
  char *start_ptr;
  unsigned int cur_delimiter, delimiters_length, delimiter_found;
  *match_length = 0;
  if (str == NULL || *str == NULL)
    return NULL;
  delimiters_length = strlen(delimiters);
  if (delimiters_length == 0)
    return NULL;
  start_ptr = *str;
  delimiter_found = 0;
  while (**str) {
    for (cur_delimiter = 0; cur_delimiter < delimiters_length; cur_delimiter++)
      if (**str == *(delimiters + cur_delimiter)) {
        delimiter_found = 1;
        break;
      }
    (*str)++;
    if (delimiter_found == 1)
      break;
    (*match_length)++;
  }
  if (delimiter_found == 0)
    *match_length = 0;
  return start_ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tu_strtok>:
  endbr64
  movl   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L49
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  je     L52
  mov    %rdx,%rdi
  mov    %rsi,%rbx
  mov    %rdx,%r12
  call   <strlen@plt>
  test   %eax,%eax
  je     L52
  mov    0x0(%rbp),%r9
  movzbl (%r9),%ecx
  test   %cl,%cl
  je     L8
  sub    $0x1,%eax
  mov    %r9,%r8
  lea    0x1(%r12,%rax,1),%rdi
  nopl   0x0(%rax)
L68:
  mov    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L13:
  cmp    %cl,(%rax)
  je     L56
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L13
  add    $0x1,%r8
  mov    %r8,0x0(%rbp)
  addl   $0x1,(%rbx)
  movzbl (%r8),%ecx
  test   %cl,%cl
  jne    L68
L8:
  movl   $0x0,(%rbx)
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L52:
  xor    %r9d,%r9d
  pop    %rbx
  pop    %rbp
  mov    %r9,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L56:
  add    $0x1,%r8
  mov    %r9,%rax
  mov    %r8,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *tu_strtok(char **str, unsigned int *match_length, const char *delimiters) {
  char *start_ptr;
  unsigned int cur_delimiter, delimiters_length, delimiter_found;
  *match_length = 0;
  if (str == NULL || *str == NULL)
    return NULL;
  delimiters_length = strlen(delimiters);
  if (delimiters_length == 0)
    return NULL;
  start_ptr = *str;
  delimiter_found = 0;
  while (**str) {
    for (cur_delimiter = 0; cur_delimiter < delimiters_length; cur_delimiter++)
      if (**str == *(delimiters + cur_delimiter)) {
        delimiter_found = 1;
        break;
      }
    (*str)++;
    if (delimiter_found == 1)
      break;
    (*match_length)++;
  }
  if (delimiter_found == 0)
    *match_length = 0;
  return start_ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tu_strtok>:
  endbr64
  movl   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L36
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  je     L68
  mov    %rdx,%rdi
  mov    %rsi,%rbx
  mov    %rdx,%r12
  call   <strlen@plt>
  test   %eax,%eax
  je     L68
  mov    0x0(%rbp),%r9
  movzbl (%r9),%ecx
  test   %cl,%cl
  je     L0
  sub    $0x1,%eax
  mov    %r9,%r8
  lea    0x1(%r12,%rax,1),%rdi
  nopl   0x0(%rax)
L50:
  mov    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L42:
  cmp    %cl,(%rax)
  je     L58
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L42
  add    $0x1,%r8
  mov    %r8,0x0(%rbp)
  addl   $0x1,(%rbx)
  movzbl (%r8),%ecx
  test   %cl,%cl
  jne    L50
L0:
  movl   $0x0,(%rbx)
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L68:
  xor    %r9d,%r9d
  pop    %rbx
  pop    %rbp
  mov    %r9,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L58:
  add    $0x1,%r8
  mov    %r9,%rax
  mov    %r8,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *tu_strtok(char **str, unsigned int *match_length, const char *delimiters) {
  char *start_ptr;
  unsigned int cur_delimiter, delimiters_length, delimiter_found;
  *match_length = 0;
  if (str == NULL || *str == NULL)
    return NULL;
  delimiters_length = strlen(delimiters);
  if (delimiters_length == 0)
    return NULL;
  start_ptr = *str;
  delimiter_found = 0;
  while (**str) {
    for (cur_delimiter = 0; cur_delimiter < delimiters_length; cur_delimiter++)
      if (**str == *(delimiters + cur_delimiter)) {
        delimiter_found = 1;
        break;
      }
    (*str)++;
    if (delimiter_found == 1)
      break;
    (*match_length)++;
  }
  if (delimiter_found == 0)
    *match_length = 0;
  return start_ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_ordered_queue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <init_base_queue@plt>
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  nop
  leave
  ret
```

assistant: ```c
void init_ordered_queue(struct queue_base_struct *thequeue, void (*putTheRoot)(struct queue_base_struct *)) {
  init_base_queue(thequeue);
  putTheRoot(thequeue);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init_ordered_queue>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <init_base_queue@plt>
  mov    %rbx,%rdi
  call   *%rbp
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void init_ordered_queue(struct queue_base_struct *thequeue, void (*putTheRoot)(struct queue_base_struct *)) {
  init_base_queue(thequeue);
  putTheRoot(thequeue);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_ordered_queue>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <init_base_queue@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  jmp    *%rax
```

assistant: ```c
void init_ordered_queue(struct queue_base_struct *thequeue, void (*putTheRoot)(struct queue_base_struct *)) {
  init_base_queue(thequeue);
  putTheRoot(thequeue);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<init_ordered_queue>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <init_base_queue@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  jmp    *%rax
```

assistant: ```c
void init_ordered_queue(struct queue_base_struct *thequeue, void (*putTheRoot)(struct queue_base_struct *)) {
  init_base_queue(thequeue);
  putTheRoot(thequeue);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fb_Month>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    $0x0,%edi
  movq   %rax,%xmm0
  call   <fb_hDateDecodeSerial@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int fb_Month(double serial) {
  int month;
  fb_hDateDecodeSerial(serial, 0, &month, 0);
  return month;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fb_Month>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  mov    $0x0,%edi
  call   <fb_hDateDecodeSerial@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fb_Month(double serial) {
  int month;
  fb_hDateDecodeSerial(serial, 0, &month, 0);
  return month;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fb_Month>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fb_hDateDecodeSerial@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fb_Month(double serial) {
  int month;
  fb_hDateDecodeSerial(serial, 0, &month, 0);
  return month;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fb_Month>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fb_hDateDecodeSerial@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fb_Month(double serial) {
  int month;
  fb_hDateDecodeSerial(serial, 0, &month, 0);
  return month;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<posix_spawnattr_setsigdefault>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int posix_spawnattr_setsigdefault(posix_spawnattr_t *attr, const sigset_t *sigdefault) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<posix_spawnattr_setsigdefault>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int posix_spawnattr_setsigdefault(posix_spawnattr_t *attr, const sigset_t *sigdefault) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<posix_spawnattr_setsigdefault>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int posix_spawnattr_setsigdefault(posix_spawnattr_t *attr, const sigset_t *sigdefault) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```