ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<d_l_print>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  movslq %edi,%rdx
  push   %rbp
  lea    (%rcx,%rdx,4),%rcx
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rcx),%eax
  mov    %rcx,0x8(%rsp)
  test   %eax,%eax
  js     L7
  imul   %edi,%r8d
  mov    %edi,%ebp
  mov    %r9,%r13
  xor    %ebx,%ebx
  lea    D8(%rip),%r15
  movslq %r8d,%r8
  lea    (%rsi,%r8,8),%r14
L18:
  movsd  (%r14,%rbx,8),%xmm0
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <fprintf@plt>
  mov    0x8(%rsp),%rax
  cmp    %ebx,(%rax)
  jge    L18
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string

tool: D8: %s %3d %3d % 12.7lf


assistant: ```c
void d_l_print(int Q, double *par, const char s[], int *Lq, int nL, FILE *f) {
  for (int L = 0; L <= Lq[Q]; L++) {
    fprintf(f, "%s %3d %3d % 12.7lf\n", s, Q, L, par[Q * nL + L]);
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: Random Number: %d

assistant: ```c
int main() {
  int r;
  srand(time(NULL));
  r = rand();
  printf("Random Number: %d", r);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: Random Number: %d

assistant: ```c
int main() {
  int r;
  srand(time(NULL));
  r = rand();
  printf("Random Number: %d", r);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: Random Number: %d

assistant: ```c
int main() {
  int r;
  srand(time(NULL));
  r = rand();
  printf("Random Number: %d", r);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D3: Random Number: %d

assistant: ```c
int main() {
  int r;
  srand(time(NULL));
  r = rand();
  printf("Random Number: %d", r);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L7:
  mov    -0xc(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dot(int N, double *A, int Astride, double *B, int Bstride) {
  int i;
  double val = 0;
  for (i = 0; i < N; i++)
    val += A[i * Astride] * B[i * Bstride];
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dot>:
  endbr64
  test   %edi,%edi
  jle    L17
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%r9
  movslq %r8d,%r8
  lea    0x0(,%r8,8),%rdx
  pxor   %xmm1,%xmm1
  mov    $0x0,%eax
L24:
  movsd  (%rsi),%xmm0
  mulsd  (%rcx),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%eax
  add    %r9,%rsi
  add    %rdx,%rcx
  cmp    %eax,%edi
  jne    L24
L28:
  movapd %xmm1,%xmm0
  ret
L17:
  pxor   %xmm1,%xmm1
  jmp    L28
```

assistant: ```c
double dot(int N, double *A, int Astride, double *B, int Bstride) {
  int i;
  double val = 0;
  for (i = 0; i < N; i++)
    val += A[i * Astride] * B[i * Bstride];
  return val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dot>:
  endbr64
  test   %edi,%edi
  jle    L0
  movslq %edx,%rdx
  movslq %r8d,%r8
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  lea    0x0(,%rdx,8),%r9
  lea    0x0(,%r8,8),%rdx
  nopl   0x0(%rax)
L10:
  movsd  (%rsi),%xmm0
  mulsd  (%rcx),%xmm0
  add    $0x1,%eax
  add    %r9,%rsi
  add    %rdx,%rcx
  addsd  %xmm0,%xmm1
  cmp    %eax,%edi
  jne    L10
  movapd %xmm1,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dot(int N, double *A, int Astride, double *B, int Bstride) {
  int i;
  double val = 0;
  for (i = 0; i < N; i++)
    val += A[i * Astride] * B[i * Bstride];
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dot>:
  endbr64
  test   %edi,%edi
  jle    L15
  cmp    $0x1,%r8d
  jne    L32
  cmp    $0x1,%edx
  jne    L32
  cmp    $0x1,%edi
  je     L24
  mov    %edi,%edx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %edx
  shl    $0x4,%rdx
  xchg   %ax,%ax
L75:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L75
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L1
L39:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rcx,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L1:
  ret
  nopl   0x0(%rax)
L32:
  movslq %edx,%rdx
  movslq %r8d,%r8
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  shl    $0x3,%rdx
  shl    $0x3,%r8
  nopl   0x0(%rax)
L63:
  movsd  (%rsi),%xmm1
  mulsd  (%rcx),%xmm1
  add    $0x1,%eax
  add    %rdx,%rsi
  add    %r8,%rcx
  addsd  %xmm1,%xmm0
  cmp    %eax,%edi
  jne    L63
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  pxor   %xmm0,%xmm0
  ret
L24:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L39
```

assistant: ```c
double dot(int N, double *A, int Astride, double *B, int Bstride) {
  int i;
  double val = 0;
  for (i = 0; i < N; i++)
    val += A[i * Astride] * B[i * Bstride];
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L0:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <generate@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x7f7f7f7f,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <movmask@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  je     L37
  mov    -0xc(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L10
L37:
  addl   $0x1,-0xc(%rbp)
L2:
  cmpl   $0xf,-0xc(%rbp)
  jbe    L0
  mov    $0x1,%eax
L10:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: %08x => %x (expected %x)


assistant: ```c
int test32() {
  for (unsigned mask = 0; mask < 16; mask++) {
    const uint32_t input = generate(mask);
    assert((input & 0x7f7f7f7f) == 0);
    const uint32_t result = movmask(input);
    if (result != mask) {
      printf("%08x => %x (expected %x)\n", input, result, mask);
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
L4:
  mov    %ebp,%edi
  call   <generate@plt>
  mov    %eax,%ebx
  test   $0x7f7f7f7f,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <movmask@plt>
  cmp    %ebp,%eax
  jne    L27
  add    $0x1,%ebp
  cmp    $0x10,%ebp
  jne    L4
  mov    $0x1,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    %ebp,%ecx
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L25
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: %08x => %x (expected %x)


assistant: ```c
int test32() {
  for (unsigned mask = 0; mask < 16; mask++) {
    const uint32_t input = generate(mask);
    assert((input & 0x7f7f7f7f) == 0);
    const uint32_t result = movmask(input);
    if (result != mask) {
      printf("%08x => %x (expected %x)\n", input, result, mask);
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test32>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  xchg   %ax,%ax
L9:
  mov    %r12d,%edi
  call   <generate@plt>
  xor    %edi,%edi
  test   $0x7f7f7f7f,%eax
  mov    %eax,%ebp
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <movmask@plt>
  cmp    %r12d,%eax
  jne    L2
  add    $0x1,%r12d
  cmp    $0x10,%r12d
  jne    L9
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L2:
  mov    %r12d,%ecx
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: %08x => %x (expected %x)


assistant: ```c
int test32() {
  for (unsigned mask = 0; mask < 16; mask++) {
    const uint32_t input = generate(mask);
    assert((input & 0x7f7f7f7f) == 0);
    const uint32_t result = movmask(input);
    if (result != mask) {
      printf("%08x => %x (expected %x)\n", input, result, mask);
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test32>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  xchg   %ax,%ax
L2:
  mov    %r12d,%edi
  call   <generate@plt>
  xor    %edi,%edi
  test   $0x7f7f7f7f,%eax
  mov    %eax,%ebp
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%edi
  call   <movmask@plt>
  cmp    %r12d,%eax
  jne    L6
  add    $0x1,%r12d
  cmp    $0x10,%r12d
  jne    L2
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L6:
  mov    %r12d,%ecx
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D8: %08x => %x (expected %x)


assistant: ```c
int test32() {
  for (unsigned mask = 0; mask < 16; mask++) {
    const uint32_t input = generate(mask);
    assert((input & 0x7f7f7f7f) == 0);
    const uint32_t result = movmask(input);
    if (result != mask) {
      printf("%08x => %x (expected %x)\n", input, result, mask);
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mdcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L36
  movq   $0x0,-0x18(%rbp)
  jmp    L48
L25:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L16
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L48:
  mov    -0x18(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L25
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mdfirst@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mdfirst@plt>
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    %ebx,%esi
  mov    %ecx,%edi
  call   <memcpy@plt>
  jmp    L45
L36:
  nop
  jmp    L45
L16:
  nop
L45:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void mdcopy(void *dest, void *src, size_t el_size, size_t n, size_t *d) {
  size_t size = el_size;
  size_t dim;
  if (el_size == 0) {
    return;
  }
  for (dim = 0; dim < n; dim++) {
    if (d[dim] == 0) {
      return;
    }
    size *= d[dim];
  }
  memcpy(mdfirst(dest, n), mdfirst(src, n), size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mdcopy>:
  endbr64
  test   %rdx,%rdx
  je     L8
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  test   %rcx,%rcx
  je     L5
  mov    $0x0,%eax
L16:
  mov    (%r8,%rax,8),%rdx
  test   %rdx,%rdx
  je     L29
  imul   %rdx,%rbx
  add    $0x1,%rax
  cmp    %rax,%rbp
  jne    L16
L5:
  mov    %rbp,%rsi
  call   <mdfirst@plt>
  mov    %eax,%r13d
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mdfirst@plt>
  mov    %eax,%edi
  mov    %rbx,%rdx
  mov    %r13d,%esi
  call   <memcpy@plt>
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  ret
```

assistant: ```c
void mdcopy(void *dest, void *src, size_t el_size, size_t n, size_t *d) {
  size_t size = el_size;
  size_t dim;
  if (el_size == 0) {
    return;
  }
  for (dim = 0; dim < n; dim++) {
    if (d[dim] == 0) {
      return;
    }
    size *= d[dim];
  }
  memcpy(mdfirst(dest, n), mdfirst(src, n), size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mdcopy>:
  endbr64
  test   %rdx,%rdx
  je     L41
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L18
  xor    %eax,%eax
  jmp    L23
  nopl   (%rax)
L17:
  add    $0x1,%rax
  imul   %rdx,%r12
  cmp    %rax,%rbp
  je     L18
L23:
  mov    (%r8,%rax,8),%rdx
  test   %rdx,%rdx
  jne    L17
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  call   <mdfirst@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <mdfirst@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %r14d,%esi
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <memcpy@plt>
  cs nopw 0x0(%rax,%rax,1)
L41:
  ret
```

assistant: ```c
void mdcopy(void *dest, void *src, size_t el_size, size_t n, size_t *d) {
  size_t size = el_size;
  size_t dim;
  if (el_size == 0) {
    return;
  }
  for (dim = 0; dim < n; dim++) {
    if (d[dim] == 0) {
      return;
    }
    size *= d[dim];
  }
  memcpy(mdfirst(dest, n), mdfirst(src, n), size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mdcopy>:
  endbr64
  test   %rdx,%rdx
  je     L14
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L39
  xor    %eax,%eax
  jmp    L11
  nopl   (%rax)
L35:
  add    $0x1,%rax
  imul   %rdx,%r12
  cmp    %rax,%rbp
  je     L39
L11:
  mov    (%r8,%rax,8),%rdx
  test   %rdx,%rdx
  jne    L35
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %rbp,%rsi
  call   <mdfirst@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <mdfirst@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %r14d,%esi
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <memcpy@plt>
  cs nopw 0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void mdcopy(void *dest, void *src, size_t el_size, size_t n, size_t *d) {
  size_t size = el_size;
  size_t dim;
  if (el_size == 0) {
    return;
  }
  for (dim = 0; dim < n; dim++) {
    if (d[dim] == 0) {
      return;
    }
    size *= d[dim];
  }
  memcpy(mdfirst(dest, n), mdfirst(src, n), size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp_short_gt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  jle    L13
  mov    $0xffffffff,%eax
  jmp    L39
L13:
  movzwl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  jge    L15
  mov    $0x1,%eax
  jmp    L39
L15:
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_short_gt(const void *a, const void *b) {
  short a_ = *(short *)a;
  short b_ = *(short *)b;
  if (a_ > b_)
    return -1;
  if (a_ < b_)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmp_short_gt>:
  endbr64
  movzwl (%rdi),%ecx
  movzwl (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dx,%cx
  jg     L7
  setl   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int cmp_short_gt(const void *a, const void *b) {
  short a_ = *(short *)a;
  short b_ = *(short *)b;
  if (a_ > b_)
    return -1;
  if (a_ < b_)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmp_short_gt>:
  endbr64
  movzwl (%rsi),%eax
  cmp    %ax,(%rdi)
  mov    $0xffffffff,%edx
  setl   %al
  movzbl %al,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int cmp_short_gt(const void *a, const void *b) {
  short a_ = *(short *)a;
  short b_ = *(short *)b;
  if (a_ > b_)
    return -1;
  if (a_ < b_)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmp_short_gt>:
  endbr64
  movzwl (%rsi),%eax
  cmp    %ax,(%rdi)
  mov    $0xffffffff,%edx
  setl   %al
  movzbl %al,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int cmp_short_gt(const void *a, const void *b) {
  short a_ = *(short *)a;
  short b_ = *(short *)b;
  if (a_ > b_)
    return -1;
  if (a_ < b_)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x40(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L11
L23:
  mov    -0x44(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    %dl,-0x3a(%rbp,%rax,1)
  addl   $0x1,-0x44(%rbp)
L11:
  mov    -0x44(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L23
  lea    -0x3a(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: string

tool: D16: Entre com seu nome e sobrenome: 

tool: D13: %s

assistant: ```c
main() {
  char nomecompleto[30];
  char nome[10];
  char sobrenome[10];
  int i, j = 0;
  printf("Entre com seu nome e sobrenome: ");
  gets(nomecompleto);
  while (nomecompleto[i] != ' ') {
    nome[i] = nomecompleto[i];
    i++;
  }
  printf("%s", nome);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  call   <gets@plt>
  movzbl 0x10(%rsp),%edx
  cmp    $0x20,%dl
  je     L21
  mov    $0x0,%eax
  lea    0x6(%rsp),%rsi
  lea    0x10(%rsp),%rcx
L19:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x20,%dl
  jne    L19
L21:
  lea    0x6(%rsp),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D17
type: string

tool: D0: Entre com seu nome e sobrenome: 

tool: D17: %s

assistant: ```c
main() {
  char nomecompleto[30];
  char nome[10];
  char sobrenome[10];
  int i, j = 0;
  printf("Entre com seu nome e sobrenome: ");
  gets(nomecompleto);
  while (nomecompleto[i] != ' ') {
    nome[i] = nomecompleto[i];
    i++;
  }
  printf("%s", nome);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  xor    %ecx,%ecx
  lea    0x6(%rsp),%r8
  movzbl 0x10(%rsp,%rcx,1),%edx
  cmp    $0x20,%dl
  je     L8
  lea    0x6(%rsp),%r8
  xor    %eax,%eax
  add    %rbx,%rcx
  mov    %r8,%rsi
L0:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  cmp    $0x20,%dl
  jne    L0
L8:
  xor    %eax,%eax
  mov    %r8,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string

tool: D4: Entre com seu nome e sobrenome: 

tool: D1: %s

assistant: ```c
main() {
  char nomecompleto[30];
  char nome[10];
  char sobrenome[10];
  int i, j = 0;
  printf("Entre com seu nome e sobrenome: ");
  gets(nomecompleto);
  while (nomecompleto[i] != ' ') {
    nome[i] = nomecompleto[i];
    i++;
  }
  printf("%s", nome);
}
```