user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D31(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  lea    D42(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L66
L104:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L104
L66:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L117
L43:
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  mov    %rsp,%rbx
  xor    %r12d,%r12d
  call   <printf@plt>
  cmpl   $0x0,-0x2c(%rbp)
  mov    %rbx,%r13
  jle    L149
  nopl   0x0(%rax)
L141:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  cmp    %r12d,%esi
  jg     L141
  test   %esi,%esi
  jle    L149
  movslq %esi,%r10
  xor    %r8d,%r8d
  nopl   (%rax)
L119:
  mov    (%rbx,%r8,4),%r9d
  mov    %r8,%rax
  mov    $0xffffffffffffffff,%rdi
  mov    %r9d,%edx
  mov    %r9d,%ecx
  jmp    L143
  xchg   %ax,%ax
L59:
  mov    (%rbx,%rax,4),%edx
L143:
  cmp    %ecx,%edx
  jge    L115
  movslq %eax,%rdi
  mov    %edx,%ecx
L115:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L59
  cmp    $0xffffffff,%edi
  je     L108
  mov    %ecx,(%rbx,%r8,4)
  mov    %r9d,(%rbx,%rdi,4)
L108:
  add    $0x1,%r8
  cmp    %r10,%r8
  jne    L119
L149:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  lea    D19(%rip),%r13
  test   %eax,%eax
  jle    L28
  nopl   0x0(%rax)
L9:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L9
L28:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L117:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L43
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D31
datatype: string
name: disassemble_data
arguments: data_tag: D42
datatype: string
name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D19
datatype: string

tool: D31: Length of array: 

tool: D42: %d

tool: D2: 
Enter %d numbers: 

tool: D1: 
Sorted array: 

tool: D19: %d 

assistant: ```c
int main() {
  int n, i;
  printf("Length of array: ");
  scanf("%d", &n);
  int ar[n];
  printf("\nEnter %d numbers: ", n);
  for (i = 0; i < n; i++)
    scanf("%d", &ar[i]);
  for (i = 0; i < n; i++) {
    int min, j, li = -1, tmp;
    min = ar[i];
    for (j = i; j < n; j++) {
      if (ar[j] < min) {
        min = ar[j];
        li = j;
      }
    }
    if (li != -1) {
      tmp = ar[i];
      ar[i] = min;
      ar[li] = tmp;
    }
  }
  printf("\nSorted array: ");
  for (i = 0; i < n; i++)
    printf("%d ", ar[i]);
  return 0;
}
```