ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L34
L37:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L40
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L40
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
L40:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L34:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string

tool: D15: Enter an integer > 

tool: D6: %d

tool: D16: %d


assistant: ```c
int main(void) {
  int n, digit;
  printf("Enter an integer > ");
  scanf("%d", &n);
  while (n != 0) {
    digit = n % 10;
    n = n / 10;
    if ((digit < 0) && (n == 0))
      printf("%d\n", digit);
    else
      printf("%d\n", abs(digit));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L57
  lea    D14(%rip),%rbx
  jmp    L55
L48:
  mov    %esi,%eax
  neg    %eax
  cmovns %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L45:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L57
L55:
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  cltd
  sub    %edx,%esi
  mov    %esi,%ecx
  lea    (%rsi,%rsi,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  mov    %ecx,0x4(%rsp)
  test   %ecx,%ecx
  jne    L48
  test   %eax,%eax
  jns    L48
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L45
L57:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
type_guessed: string
name: read_data
arguments: tag: D22
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: string

tool: D11: Enter an integer > 

tool: D22: %d

tool: D14: %d


assistant: ```c
int main(void) {
  int n, digit;
  printf("Enter an integer > ");
  scanf("%d", &n);
  while (n != 0) {
    digit = n % 10;
    n = n / 10;
    if ((digit < 0) && (n == 0))
      printf("%d\n", digit);
    else
      printf("%d\n", abs(digit));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L1
  lea    D17(%rip),%rbx
  nopl   (%rax)
L41:
  movslq %eax,%rsi
  cltd
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  mov    %esi,0x4(%rsp)
  mov    %esi,%ecx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  jns    L17
  test   %ecx,%ecx
  je     L24
L17:
  mov    %esi,%eax
  neg    %eax
  cmovns %eax,%esi
L24:
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L41
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
datatype: string
name: retrieve_data
arguments: data_tag: D24
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string

tool: D10: Enter an integer > 

tool: D24: %d

tool: D17: %d


assistant: ```c
int main(void) {
  int n, digit;
  printf("Enter an integer > ");
  scanf("%d", &n);
  while (n != 0) {
    digit = n % 10;
    n = n / 10;
    if ((digit < 0) && (n == 0))
      printf("%d\n", digit);
    else
      printf("%d\n", abs(digit));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D29(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L32
  lea    D8(%rip),%rbx
  nopl   (%rax)
L43:
  movslq %eax,%rsi
  cltd
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,4),%edx
  mov    %esi,0x4(%rsp)
  mov    %esi,%ecx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  jns    L22
  test   %ecx,%ecx
  je     L30
L22:
  mov    %esi,%eax
  neg    %eax
  cmovns %eax,%esi
L30:
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L43
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D29
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D29: Enter an integer > 

tool: D9: %d

tool: D8: %d


assistant: ```c
int main(void) {
  int n, digit;
  printf("Enter an integer > ");
  scanf("%d", &n);
  while (n != 0) {
    digit = n % 10;
    n = n / 10;
    if ((digit < 0) && (n == 0))
      printf("%d\n", digit);
    else
      printf("%d\n", abs(digit));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<llib_led_utils_euclid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L29
  mov    -0x8(%rbp),%eax
  jmp    L45
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L18
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
  jmp    L29
L18:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L29:
  cmpl   $0x0,-0x8(%rbp)
  jne    L27
  mov    -0x4(%rbp),%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int llib_led_utils_euclid(int a, int b) {
  if (!a)
    return b;
  while (b)
    if (a > b)
      a -= b;
    else
      b -= a;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<llib_led_utils_euclid>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L24
  test   %esi,%esi
  jne    L34
  jmp    L55
L21:
  sub    %eax,%esi
L1:
  test   %esi,%esi
  je     L9
L34:
  cmp    %esi,%eax
  jle    L21
  sub    %esi,%eax
  jmp    L1
L9:
  ret
L24:
  mov    %esi,%eax
L55:
  ret
```

assistant: ```c
int llib_led_utils_euclid(int a, int b) {
  if (!a)
    return b;
  while (b)
    if (a > b)
      a -= b;
    else
      b -= a;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<llib_led_utils_euclid>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L22
  test   %esi,%esi
  je     L23
L31:
  cmp    %eax,%esi
  jge    L46
L18:
  sub    %esi,%eax
  cmp    %eax,%esi
  jl     L18
L46:
  sub    %eax,%esi
  jne    L31
  ret
  nopl   (%rax)
L22:
  mov    %esi,%eax
L23:
  ret
```

assistant: ```c
int llib_led_utils_euclid(int a, int b) {
  if (!a)
    return b;
  while (b)
    if (a > b)
      a -= b;
    else
      b -= a;
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<llib_led_utils_euclid>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  test   %edi,%edi
  je     L13
  test   %esi,%esi
  je     L26
L22:
  cmp    %edi,%edx
  jge    L37
L5:
  sub    %edx,%edi
  cmp    %edi,%edx
  jl     L5
L37:
  sub    %edi,%edx
  jne    L22
L26:
  mov    %edi,%eax
L13:
  ret
```

assistant: ```c
int llib_led_utils_euclid(int a, int b) {
  if (!a)
    return b;
  while (b)
    if (a > b)
      a -= b;
    else
      b -= a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x3f1(%rbp)
  movsbl -0x3f1(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D34
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string

tool: D34: Enter the haystack 

tool: D20: %s

tool: D16: Enter the Needle: 

tool: D8: Returned Value: %d 


assistant: ```c
int main() {
  char str1[1000], ch;
  printf("Enter the haystack \n");
  scanf("%s", str1);
  printf("Enter the Needle: ");
  getchar();
  ch = getchar();
  printf("Returned Value: %d \n", find(str1, ch));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%esi
  mov    %rbx,%rdi
  call   <find@plt>
  mov    %eax,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D23
data_type: string
name: retrieve_data
arguments: label: D5
data_type: string
name: retrieve_data
arguments: label: D35
data_type: string

tool: D15: Enter the haystack 

tool: D23: %s

tool: D5: Enter the Needle: 

tool: D35: Returned Value: %d 


assistant: ```c
int main() {
  char str1[1000], ch;
  printf("Enter the haystack \n");
  scanf("%s", str1);
  printf("Enter the Needle: ");
  getchar();
  ch = getchar();
  printf("Returned Value: %d \n", find(str1, ch));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D32(%rip),%rdi
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  movsbl %al,%esi
  call   <find@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D32
type_infered: string
name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D25
type_infered: string
name: parse_data
arguments: label: D18
type_infered: string

tool: D32: Enter the haystack 

tool: D37: %s

tool: D25: Enter the Needle: 

tool: D18: Returned Value: %d 


assistant: ```c
int main() {
  char str1[1000], ch;
  printf("Enter the haystack \n");
  scanf("%s", str1);
  printf("Enter the Needle: ");
  getchar();
  ch = getchar();
  printf("Returned Value: %d \n", find(str1, ch));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  movsbl %al,%esi
  call   <find@plt>
  lea    D34(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D17
data_type: string
name: disassemble_data
arguments: label: D39
data_type: string
name: disassemble_data
arguments: label: D34
data_type: string

tool: D0: Enter the haystack 

tool: D17: %s

tool: D39: Enter the Needle: 

tool: D34: Returned Value: %d 


assistant: ```c
int main() {
  char str1[1000], ch;
  printf("Enter the haystack \n");
  scanf("%s", str1);
  printf("Enter the Needle: ");
  getchar();
  ch = getchar();
  printf("Returned Value: %d \n", find(str1, ch));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rewrite_unicode_to_ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x3030755c,-0x1d(%rbp)
  movb   $0x0,-0x19(%rbp)
  lea    -0x1d(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L24
  lea    -0x1d(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x28(%rbp)
  movb   $0x0,-0x31(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x2,-0x30(%rbp)
  jmp    L32
L17:
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hex_to_dec@plt>
  movsbl %al,%ebx
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x10,%edi
  call   <power@plt>
  movsbl %al,%eax
  imul   %ebx,%eax
  mov    %eax,%edx
  movzbl -0x31(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x31(%rbp)
  subl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x30(%rbp)
L32:
  cmpl   $0x5,-0x30(%rbp)
  jbe    L17
  mov    -0x28(%rbp),%rax
  movzbl -0x31(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x6,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    0x6(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x48(%rbp)
L24:
  mov    -0x48(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *rewrite_unicode_to_ascii(char *str) {
  const char unicode_literal[] = "\\u00";
  if (strstr(str, unicode_literal)) {
    char *hit = strstr(str, unicode_literal);
    char val = 0;
    unsigned i;
    unsigned exp = 3;
    for (i = 2; i < 6; i++) {
      val += hex_to_dec(hit[i]) * power(16, exp);
      exp--;
    }
    hit[0] = val;
    memmove(hit + 1, hit + 6, strlen(hit + 6) + 1);
    str = (char *)realloc(str, strlen(str) + 1);
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rewrite_unicode_to_ascii>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x3030755c,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x3(%rsp),%rsi
  call   <strstr@plt>
  mov    %rax,%r12
  mov    %r14,%rax
  test   %r12,%r12
  je     L28
  mov    $0x2,%ebp
  mov    $0x0,%r13d
  mov    $0x5,%r15d
L7:
  movsbl (%r12,%rbp,1),%edi
  call   <hex_to_dec@plt>
  mov    %eax,%ebx
  mov    %r15d,%esi
  sub    %ebp,%esi
  mov    $0x10,%edi
  call   <power@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  imul   %edx,%eax
  add    %eax,%r13d
  add    $0x1,%rbp
  cmp    $0x6,%rbp
  jne    L7
  mov    %r13b,(%r12)
  lea    0x6(%r12),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  lea    0x1(%r12),%rdi
  mov    %rbx,%rsi
  call   <memmove@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    %r14,%rdi
  call   <realloc@plt>
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *rewrite_unicode_to_ascii(char *str) {
  const char unicode_literal[] = "\\u00";
  if (strstr(str, unicode_literal)) {
    char *hit = strstr(str, unicode_literal);
    char val = 0;
    unsigned i;
    unsigned exp = 3;
    for (i = 2; i < 6; i++) {
      val += hex_to_dec(hit[i]) * power(16, exp);
      exp--;
    }
    hit[0] = val;
    memmove(hit + 1, hit + 6, strlen(hit + 6) + 1);
    str = (char *)realloc(str, strlen(str) + 1);
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rewrite_unicode_to_ascii>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rsi
  movl   $0x3030755c,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <strstr@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbp
  mov    $0x2,%ebx
  xor    %r15d,%r15d
  mov    $0x5,%r13d
L12:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <hex_to_dec@plt>
  mov    %r13d,%esi
  mov    $0x10,%edi
  sub    %ebx,%esi
  mov    %eax,%r14d
  add    $0x1,%rbx
  call   <power@plt>
  imul   %r14d,%eax
  add    %eax,%r15d
  cmp    $0x6,%rbx
  jne    L12
  mov    %r15b,0x0(%rbp)
  lea    0x6(%rbp),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp),%rdi
  mov    %r13,%rsi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  mov    %r12,%rdi
  lea    0x1(%rax),%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <realloc@plt>
  nopl   (%rax)
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *rewrite_unicode_to_ascii(char *str) {
  const char unicode_literal[] = "\\u00";
  if (strstr(str, unicode_literal)) {
    char *hit = strstr(str, unicode_literal);
    char val = 0;
    unsigned i;
    unsigned exp = 3;
    for (i = 2; i < 6; i++) {
      val += hex_to_dec(hit[i]) * power(16, exp);
      exp--;
    }
    hit[0] = val;
    memmove(hit + 1, hit + 6, strlen(hit + 6) + 1);
    str = (char *)realloc(str, strlen(str) + 1);
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rewrite_unicode_to_ascii>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rsi
  movl   $0x3030755c,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <strstr@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbp
  mov    $0x2,%ebx
  xor    %r15d,%r15d
  mov    $0x5,%r13d
L34:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <hex_to_dec@plt>
  mov    %r13d,%esi
  mov    $0x10,%edi
  sub    %ebx,%esi
  mov    %eax,%r14d
  add    $0x1,%rbx
  call   <power@plt>
  imul   %r14d,%eax
  add    %eax,%r15d
  cmp    $0x6,%rbx
  jne    L34
  mov    %r15b,0x0(%rbp)
  lea    0x6(%rbp),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp),%rdi
  mov    %r13,%rsi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x18,%rsp
  mov    %r12,%rdi
  lea    0x1(%rax),%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <realloc@plt>
  nopl   (%rax)
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *rewrite_unicode_to_ascii(char *str) {
  const char unicode_literal[] = "\\u00";
  if (strstr(str, unicode_literal)) {
    char *hit = strstr(str, unicode_literal);
    char val = 0;
    unsigned i;
    unsigned exp = 3;
    for (i = 2; i < 6; i++) {
      val += hex_to_dec(hit[i]) * power(16, exp);
      exp--;
    }
    hit[0] = val;
    memmove(hit + 1, hit + 6, strlen(hit + 6) + 1);
    str = (char *)realloc(str, strlen(str) + 1);
  }
  return str;
}
```