ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xerr2>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x2,%edi
  mov    $0x2,%edx
  lea    D6(%rip),%rsi
  call   <write@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <xerr@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: : 

assistant: ```c
void xerr2(const char *a, const char *b) {
  write(2, a, strlen(a));
  write(2, ": ", 2);
  xerr(b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xerr2>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x2,%edi
  mov    $0x2,%edx
  lea    D2(%rip),%rsi
  call   <write@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <xerr@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: : 

assistant: ```c
void xerr2(const char *a, const char *b) {
  write(2, a, strlen(a));
  write(2, ": ", 2);
  xerr(b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ERR_clear_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <ERR_get_state@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L12:
  mov    -0x8(%rbp),%rax
  mov    0x38(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x30(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x28(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L37
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L37
  mov    -0x8(%rbp),%rax
  mov    0x28(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    0x28(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L37:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x20(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L12
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x10(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x18(%rax)
  nop
  leave
  ret
```

assistant: ```c
void ERR_clear_error(void) {
  int i;
  ERR_STATE *es;
  es = ERR_get_state();
  for (i = 0; i < ERR_NUM_ERRORS; i++) {
    do {
      (es)->err_flags[i] = 0;
      (es)->err_buffer[i] = 0;
      do {
        if (((es)->err_data[i] != NULL) && (es)->err_data_flags[i] & ERR_TXT_MALLOCED) {
          free((es)->err_data[i]);
          (es)->err_data[i] = NULL;
        }
        (es)->err_data_flags[i] = 0;
      } while (0);
      (es)->err_file[i] = NULL;
      (es)->err_line[i] = -1;
    } while (0);
  }
  es->top = es->bottom = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ERR_clear_error>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <ERR_get_state@plt>
  mov    %rax,%rbp
  mov    D4(%rip),%rax
  cmpl   $0x0,(%rax)
  jle    L45
  mov    $0x0,%ebx
  jmp    L26
L13:
  mov    0x0(%rbp),%rax
  movl   $0x0,(%rax,%rbx,4)
  mov    0x20(%rbp),%rax
  movq   $0x0,(%rax,%r12,1)
  mov    0x8(%rbp),%rax
  movl   $0xffffffff,(%rax,%rbx,4)
  add    $0x1,%rbx
  mov    D4(%rip),%rax
  cmp    %ebx,(%rax)
  jle    L45
L26:
  lea    0x0(,%rbx,8),%r12
  mov    0x38(%rbp),%rax
  movq   $0x0,(%rax,%rbx,8)
  mov    0x30(%rbp),%rax
  movq   $0x0,(%rax,%rbx,8)
  mov    0x28(%rbp),%rax
  mov    (%rax,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L13
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,4),%eax
  mov    D6(%rip),%rdx
  and    (%rdx),%eax
  je     L13
  call   <free@plt>
  mov    0x28(%rbp),%rax
  movq   $0x0,(%rax,%r12,1)
  jmp    L13
L45:
  movq   $0x0,0x10(%rbp)
  movq   $0x0,0x18(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ERR_clear_error(void) {
  int i;
  ERR_STATE *es;
  es = ERR_get_state();
  for (i = 0; i < ERR_NUM_ERRORS; i++) {
    do {
      (es)->err_flags[i] = 0;
      (es)->err_buffer[i] = 0;
      do {
        if (((es)->err_data[i] != NULL) && (es)->err_data_flags[i] & ERR_TXT_MALLOCED) {
          free((es)->err_data[i]);
          (es)->err_data[i] = NULL;
        }
        (es)->err_data_flags[i] = 0;
      } while (0);
      (es)->err_file[i] = NULL;
      (es)->err_line[i] = -1;
    } while (0);
  }
  es->top = es->bottom = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ERR_clear_error>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <ERR_get_state@plt>
  mov    D2(%rip),%r14
  mov    %rax,%rbp
  mov    (%r14),%eax
  test   %eax,%eax
  jle    L59
  mov    0x28(%rbp),%rcx
  xor    %ebx,%ebx
  jmp    L13
L37:
  movl   $0x0,(%rax)
  mov    0x20(%rbp),%rax
  add    $0x1,%rbx
  movq   $0x0,(%rax,%r13,1)
  mov    0x8(%rbp),%rax
  movl   $0xffffffff,(%rax,%r12,1)
  cmp    %ebx,(%r14)
  jle    L59
L13:
  mov    0x38(%rbp),%rax
  mov    (%rcx,%rbx,8),%rdi
  lea    0x0(,%rbx,4),%r12
  lea    0x0(,%rbx,8),%r13
  movq   $0x0,(%rax,%rbx,8)
  mov    0x30(%rbp),%rax
  movq   $0x0,(%rax,%rbx,8)
  mov    0x0(%rbp),%rax
  add    %r12,%rax
  test   %rdi,%rdi
  je     L37
  mov    D8(%rip),%rsi
  mov    (%rax),%edx
  and    (%rsi),%edx
  je     L37
  call   <free@plt>
  mov    0x28(%rbp),%rcx
  movq   $0x0,(%rcx,%r13,1)
  mov    0x0(%rbp),%rax
  add    %r12,%rax
  jmp    L37
  nopl   0x0(%rax)
L59:
  movq   $0x0,0x10(%rbp)
  movq   $0x0,0x18(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void ERR_clear_error(void) {
  int i;
  ERR_STATE *es;
  es = ERR_get_state();
  for (i = 0; i < ERR_NUM_ERRORS; i++) {
    do {
      (es)->err_flags[i] = 0;
      (es)->err_buffer[i] = 0;
      do {
        if (((es)->err_data[i] != NULL) && (es)->err_data_flags[i] & ERR_TXT_MALLOCED) {
          free((es)->err_data[i]);
          (es)->err_data[i] = NULL;
        }
        (es)->err_data_flags[i] = 0;
      } while (0);
      (es)->err_file[i] = NULL;
      (es)->err_line[i] = -1;
    } while (0);
  }
  es->top = es->bottom = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ERR_clear_error>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <ERR_get_state@plt>
  mov    D18(%rip),%r14
  mov    %rax,%rbp
  mov    (%r14),%eax
  test   %eax,%eax
  jle    L36
  mov    0x28(%rbp),%rcx
  xor    %ebx,%ebx
  jmp    L39
L12:
  movl   $0x0,(%rax)
  mov    0x20(%rbp),%rax
  add    $0x1,%rbx
  movq   $0x0,(%rax,%r13,1)
  mov    0x8(%rbp),%rax
  movl   $0xffffffff,(%rax,%r12,1)
  cmp    %ebx,(%r14)
  jle    L36
L39:
  mov    0x38(%rbp),%rax
  mov    (%rcx,%rbx,8),%rdi
  lea    0x0(,%rbx,4),%r12
  lea    0x0(,%rbx,8),%r13
  movq   $0x0,(%rax,%rbx,8)
  mov    0x30(%rbp),%rax
  movq   $0x0,(%rax,%rbx,8)
  mov    0x0(%rbp),%rax
  add    %r12,%rax
  test   %rdi,%rdi
  je     L12
  mov    D5(%rip),%rsi
  mov    (%rax),%edx
  and    (%rsi),%edx
  je     L12
  call   <free@plt>
  mov    0x28(%rbp),%rcx
  movq   $0x0,(%rcx,%r13,1)
  mov    0x0(%rbp),%rax
  add    %r12,%rax
  jmp    L12
  nopl   0x0(%rax)
L36:
  pxor   %xmm0,%xmm0
  movups %xmm0,0x10(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void ERR_clear_error(void) {
  int i;
  ERR_STATE *es;
  es = ERR_get_state();
  for (i = 0; i < ERR_NUM_ERRORS; i++) {
    do {
      (es)->err_flags[i] = 0;
      (es)->err_buffer[i] = 0;
      do {
        if (((es)->err_data[i] != NULL) && (es)->err_data_flags[i] & ERR_TXT_MALLOCED) {
          free((es)->err_data[i]);
          (es)->err_data[i] = NULL;
        }
        (es)->err_data_flags[i] = 0;
      } while (0);
      (es)->err_file[i] = NULL;
      (es)->err_line[i] = -1;
    } while (0);
  }
  es->top = es->bottom = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aligned_alloc__>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  add    $0x8,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L5
L1:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  lea    0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  neg    %rax
  and    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
void *aligned_alloc__(size_t boundary, size_t size) {
  void *ptr = malloc(boundary + size + sizeof(uintptr_t));
  if (!ptr)
    return NULL;
  uintptr_t addr = ((uintptr_t)ptr + sizeof(uintptr_t) + boundary) & ~(boundary - 1);
  void **place = (void **)addr;
  place[-1] = ptr;
  return (void *)addr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aligned_alloc__>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rsi,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L9
  lea    0x8(%rax,%rbx,1),%rax
  neg    %rbx
  and    %rbx,%rax
  mov    %rdx,-0x8(%rax)
L9:
  pop    %rbx
  ret
```

assistant: ```c
void *aligned_alloc__(size_t boundary, size_t size) {
  void *ptr = malloc(boundary + size + sizeof(uintptr_t));
  if (!ptr)
    return NULL;
  uintptr_t addr = ((uintptr_t)ptr + sizeof(uintptr_t) + boundary) & ~(boundary - 1);
  void **place = (void **)addr;
  place[-1] = ptr;
  return (void *)addr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aligned_alloc__>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rsi,1),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdx
  lea    0x8(%rax,%rbx,1),%rax
  neg    %rbx
  and    %rbx,%rax
  mov    %rdx,-0x8(%rax)
  pop    %rbx
  ret
L0:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *aligned_alloc__(size_t boundary, size_t size) {
  void *ptr = malloc(boundary + size + sizeof(uintptr_t));
  if (!ptr)
    return NULL;
  uintptr_t addr = ((uintptr_t)ptr + sizeof(uintptr_t) + boundary) & ~(boundary - 1);
  void **place = (void **)addr;
  place[-1] = ptr;
  return (void *)addr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aligned_alloc__>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rsi,1),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdx
  lea    0x8(%rax,%rbx,1),%rax
  neg    %rbx
  and    %rbx,%rax
  mov    %rdx,-0x8(%rax)
  pop    %rbx
  ret
L0:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *aligned_alloc__(size_t boundary, size_t size) {
  void *ptr = malloc(boundary + size + sizeof(uintptr_t));
  if (!ptr)
    return NULL;
  uintptr_t addr = ((uintptr_t)ptr + sizeof(uintptr_t) + boundary) & ~(boundary - 1);
  void **place = (void **)addr;
  place[-1] = ptr;
  return (void *)addr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tostr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %al,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char **tostr(char c, char **s, int totimes, int vtimes, int *k) {
  s[*k][totimes - vtimes] = c;
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<tostr>:
  endbr64
  mov    %rsi,%rax
  mov    %ecx,%esi
  movslq (%r8),%rcx
  sub    %esi,%edx
  movslq %edx,%rdx
  mov    (%rax,%rcx,8),%rcx
  mov    %dil,(%rcx,%rdx,1)
  ret
```

assistant: ```c
char **tostr(char c, char **s, int totimes, int vtimes, int *k) {
  s[*k][totimes - vtimes] = c;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tostr>:
  endbr64
  mov    %ecx,%r9d
  movslq (%r8),%rcx
  mov    %rsi,%rax
  sub    %r9d,%edx
  mov    (%rsi,%rcx,8),%rcx
  movslq %edx,%rdx
  mov    %dil,(%rcx,%rdx,1)
  ret
```

assistant: ```c
char **tostr(char c, char **s, int totimes, int vtimes, int *k) {
  s[*k][totimes - vtimes] = c;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tostr>:
  endbr64
  mov    %ecx,%r9d
  movslq (%r8),%rcx
  mov    %rsi,%rax
  sub    %r9d,%edx
  mov    (%rsi,%rcx,8),%rcx
  movslq %edx,%rdx
  mov    %dil,(%rcx,%rdx,1)
  ret
```

assistant: ```c
char **tostr(char c, char **s, int totimes, int vtimes, int *k) {
  s[*k][totimes - vtimes] = c;
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<base64_decode>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    0x36(,%rdx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movabs $0x4847464544434241,%rax
  movabs $0x504f4e4d4c4b4a49,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x5857565554535251,%rax
  movabs $0x6665646362615a59,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6e6d6c6b6a696867,%rax
  movabs $0x767574737271706f,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x333231307a797877,%rax
  movabs $0x2f2b393837363534,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movb   $0x0,0x50(%rsp)
  movb   $0x0,0x0(%r13)
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L48
  add    $0x1,%rbp
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r12
  jmp    L3
L37:
  lea    0xc(%rsp),%rdi
  mov    %r13,%rsi
  call   <decodeblock@plt>
L48:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%esi
  mov    %r13,%rdi
  call   <realloc@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%eax
  test   %al,%al
  je     L48
L3:
  movsbl %al,%esi
  cmp    $0x3d,%al
  je     L37
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L32
  movslq %ebx,%rdx
  sub    %r12,%rax
  mov    %al,0xc(%rsp,%rdx,1)
  lea    0x1(%rbx),%edx
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  lea    (%rdx,%rax,1),%ebx
  and    $0x3,%ebx
  sub    %eax,%ebx
  test   $0x3,%dl
  jne    L32
  lea    0xc(%rsp),%rdi
  mov    %r13,%rsi
  call   <decodeblock@plt>
  movb   $0x0,0xf(%rsp)
  movb   $0x0,0xe(%rsp)
  movb   $0x0,0xd(%rsp)
  movb   $0x0,0xc(%rsp)
  jmp    L32
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *base64_decode(char *b64src) {
  char *clrdst = (char *)malloc(((strlen(b64src) - 1) / 3) * 4 + 4 + 50);
  char b64[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int c, phase, i;
  unsigned char in[4];
  char *p;
  clrdst[0] = '\0';
  phase = 0;
  i = 0;
  while (b64src[i]) {
    c = (int)b64src[i];
    if (c == '=') {
      decodeblock(in, clrdst);
      break;
    }
    p = strchr(b64, c);
    if (p) {
      in[phase] = p - b64;
      phase = (phase + 1) % 4;
      if (phase == 0) {
        decodeblock(in, clrdst);
        in[0] = in[1] = in[2] = in[3] = 0;
      }
    }
    i++;
  }
  clrdst = (char *)realloc(clrdst, strlen(clrdst) + 1);
  return clrdst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<base64_decode>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    0x36(,%rdx,4),%edi
  call   <malloc@plt>
  movdqa D21(%rip),%xmm0
  movb   $0x0,0x50(%rsp)
  movb   $0x0,(%rax)
  mov    %rax,%rbp
  movzbl (%r12),%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D8(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D26(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D20(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  test   %al,%al
  je     L88
  add    $0x1,%r12
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r13
  jmp    L76
  nopl   (%rax)
L12:
  movzbl (%r12),%eax
  add    $0x1,%r12
  test   %al,%al
  je     L88
L76:
  movsbl %al,%esi
  cmp    $0x3d,%al
  je     L87
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  movslq %ebx,%rdx
  sub    %r13,%rax
  add    $0x1,%ebx
  mov    %al,0xc(%rsp,%rdx,1)
  and    $0x3,%ebx
  jne    L12
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rsi
  add    $0x1,%r12
  call   <decodeblock@plt>
  movzbl -0x1(%r12),%eax
  movl   $0x0,0xc(%rsp)
  test   %al,%al
  jne    L76
  cs nopw 0x0(%rax,%rax,1)
L88:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rax),%esi
  call   <realloc@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L87:
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rsi
  call   <decodeblock@plt>
  jmp    L88
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
datatype: byte[16]
name: retrieve_data
arguments: data_tag: D8
datatype: byte[16]
name: retrieve_data
arguments: data_tag: D26
datatype: byte[16]
name: retrieve_data
arguments: data_tag: D20
datatype: byte[16]

tool: {"D21": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D8": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x61,0x62,0x63,0x64,0x65,0x66]}

tool: {"D26": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76]}

tool: {"D20": [0x77,0x78,0x79,0x7a,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x2b,0x2f]}

assistant: ```c
char *base64_decode(char *b64src) {
  char *clrdst = (char *)malloc(((strlen(b64src) - 1) / 3) * 4 + 4 + 50);
  char b64[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int c, phase, i;
  unsigned char in[4];
  char *p;
  clrdst[0] = '\0';
  phase = 0;
  i = 0;
  while (b64src[i]) {
    c = (int)b64src[i];
    if (c == '=') {
      decodeblock(in, clrdst);
      break;
    }
    p = strchr(b64, c);
    if (p) {
      in[phase] = p - b64;
      phase = (phase + 1) % 4;
      if (phase == 0) {
        decodeblock(in, clrdst);
        in[0] = in[1] = in[2] = in[3] = 0;
      }
    }
    i++;
  }
  clrdst = (char *)realloc(clrdst, strlen(clrdst) + 1);
  return clrdst;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<base64_decode>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    0x36(,%rdx,4),%edi
  call   <malloc@plt>
  movdqa D8(%rip),%xmm0
  movb   $0x0,0x50(%rsp)
  movb   $0x0,(%rax)
  mov    %rax,%rbp
  movzbl (%r12),%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D9(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D4(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D0(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  test   %al,%al
  je     L72
  add    $0x1,%r12
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r13
  jmp    L25
  nopl   (%rax)
L85:
  movzbl (%r12),%eax
  add    $0x1,%r12
  test   %al,%al
  je     L72
L25:
  movsbl %al,%esi
  cmp    $0x3d,%al
  je     L6
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L85
  movslq %ebx,%rdx
  sub    %r13,%rax
  add    $0x1,%ebx
  mov    %al,0xc(%rsp,%rdx,1)
  and    $0x3,%ebx
  jne    L85
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rsi
  add    $0x1,%r12
  call   <decodeblock@plt>
  movzbl -0x1(%r12),%eax
  movl   $0x0,0xc(%rsp)
  test   %al,%al
  jne    L25
  cs nopw 0x0(%rax,%rax,1)
L72:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rax),%esi
  call   <realloc@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L6:
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rsi
  call   <decodeblock@plt>
  jmp    L72
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: byte[16]

tool: {"D8": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D9": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x61,0x62,0x63,0x64,0x65,0x66]}

tool: {"D4": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76]}

tool: {"D0": [0x77,0x78,0x79,0x7a,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x2b,0x2f]}

assistant: ```c
char *base64_decode(char *b64src) {
  char *clrdst = (char *)malloc(((strlen(b64src) - 1) / 3) * 4 + 4 + 50);
  char b64[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
  int c, phase, i;
  unsigned char in[4];
  char *p;
  clrdst[0] = '\0';
  phase = 0;
  i = 0;
  while (b64src[i]) {
    c = (int)b64src[i];
    if (c == '=') {
      decodeblock(in, clrdst);
      break;
    }
    p = strchr(b64, c);
    if (p) {
      in[phase] = p - b64;
      phase = (phase + 1) % 4;
      if (phase == 0) {
        decodeblock(in, clrdst);
        in[0] = in[1] = in[2] = in[3] = 0;
      }
    }
    i++;
  }
  clrdst = (char *)realloc(clrdst, strlen(clrdst) + 1);
  return clrdst;
}
```