user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x16,-0x50(%rbp)
  movl   $0x24,-0x4c(%rbp)
  movl   $0x1b,-0x48(%rbp)
  movl   $0x17,-0x44(%rbp)
  movl   $0x2,-0x40(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D32(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D116(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D113(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x5,-0x64(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L46
L28:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D117(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L46:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L28
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L65
L42:
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L65:
  mov    -0x64(%rbp),%eax
  cmp    -0x68(%rbp),%eax
  jge    L42
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0xffffffff,-0x68(%rbp)
  jmp    L24
L75:
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  addl   $0x1,-0x68(%rbp)
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L75
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  jmp    L18
L89:
  mov    -0x60(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x58(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x4,-0x60(%rbp)
L18:
  lea    -0x50(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x64(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jl     L89
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type: string
name: retrieve_data
arguments: data_tag: D32
type: string
name: retrieve_data
arguments: data_tag: D116
type: string
name: retrieve_data
arguments: data_tag: D4
type: string
name: retrieve_data
arguments: data_tag: D113
type: string
name: retrieve_data
arguments: data_tag: D117
type: string
name: retrieve_data
arguments: data_tag: D60
type: string
name: retrieve_data
arguments: data_tag: D13
type: string
name: retrieve_data
arguments: data_tag: D43
type: string
name: retrieve_data
arguments: data_tag: D97
type: string

tool: D22: Alan

tool: D32: Frank

tool: D116: Mary

tool: D4: John

tool: D113: Lisa

tool: D117: %s is %d years old


tool: D60: ---

tool: D13: %s is %d years alive


tool: D43: %s has lived %d years


tool: D97: %s's age is %d


assistant: ```c
int main(int argc, char *argv[]) {
  int ages[] = {22, 36, 27, 23, 2};
  char *names[] = {"Alan", "Frank", "Mary", "John", "Lisa"};
  int count = sizeof(ages) / sizeof(int);
  int i = 0;
  for (; i < count; i++) {
    printf("%s is %d years old\n", names[i], ages[i]);
  }
  printf("---\n");
  int *cur_age = ages;
  char **cur_name = names;
  for (i = 0; i < count + 1; i++) {
    printf("%s is %d years alive\n", *(cur_name + i), *(cur_age + i));
  }
  printf("---\n");
  for (i = -1; i++, i < count;) {
    printf("%s has lived %d years\n", cur_name[i], cur_age[i]);
  }
  printf("---\n");
  for (cur_age = ages, cur_name = names; (cur_age - ages) < count; cur_age++) {
    printf("%s's age is %d\n", *cur_name, *cur_age);
  }
  return 0;
}
```