ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L36
L44:
  mov    -0x24(%rbp),%eax
  cltq
  movl   $0x0,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x24(%rbp)
L36:
  cmpl   $0x5,-0x24(%rbp)
  jle    L44
  movl   $0x0,-0x24(%rbp)
  jmp    L106
L76:
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  cmp    $0x1,%eax
  jne    L9
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
L9:
  mov    -0x28(%rbp),%eax
  cmp    $0x2,%eax
  jne    L16
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
L16:
  mov    -0x28(%rbp),%eax
  cmp    $0x3,%eax
  jne    L125
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L125:
  mov    -0x28(%rbp),%eax
  cmp    $0x4,%eax
  jne    L67
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L67:
  mov    -0x28(%rbp),%eax
  cmp    $0x5,%eax
  jne    L32
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L32:
  mov    -0x28(%rbp),%eax
  cmp    $0x6,%eax
  jne    L128
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L128:
  addl   $0x1,-0x24(%rbp)
L106:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L76
  movl   $0x0,-0x24(%rbp)
  jmp    L59
L64:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L59:
  cmpl   $0x5,-0x24(%rbp)
  jle    L64
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D37
data_type: string
name: unpack_data
arguments: data_label: D45
data_type: string
name: unpack_data
arguments: data_label: D32
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string

tool: D37: informe quantas jogadas: 

tool: D45: %d

tool: D32: informe os valores de cada lancamento: 

tool: D16: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n, l, i;
  int p[6];
  printf("informe quantas jogadas: \n");
  scanf("%d", &n);
  printf("informe os valores de cada lancamento: \n");
  for (i = 0; i < 6; i++) {
    p[i] = 0;
  }
  for (i = 0; i < n; i++) {
    scanf("%d", &l);
    if (l == 1) {
      p[0]++;
    }
    if (l == 2) {
      p[1]++;
    }
    if (l == 3) {
      p[2]++;
    }
    if (l == 4) {
      p[3]++;
    }
    if (l == 5) {
      p[4]++;
    }
    if (l == 6) {
      p[5]++;
    }
  }
  for (i = 0; i < 6; i++) {
    printf("%d ", p[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  cmpl   $0x0,0x8(%rsp)
  jle    L23
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
  jmp    L59
L109:
  addl   $0x1,0x10(%rsp)
L89:
  cmp    $0x4,%eax
  jne    L62
  addl   $0x1,0x1c(%rsp)
L15:
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jle    L23
L59:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  je     L109
  cmp    $0x2,%eax
  jne    L9
  addl   $0x1,0x14(%rsp)
L62:
  cmp    $0x5,%eax
  jne    L46
  addl   $0x1,0x20(%rsp)
  jmp    L15
L9:
  cmp    $0x3,%eax
  jne    L89
  addl   $0x1,0x18(%rsp)
L46:
  cmp    $0x6,%eax
  jne    L15
  addl   $0x1,0x24(%rsp)
  jmp    L15
L23:
  lea    0x10(%rsp),%rbx
  lea    0x28(%rsp),%r12
  lea    D8(%rip),%rbp
L111:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L111
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D49
data_type: string
name: extract_symbolic_data
arguments: data_label: D7
data_type: string
name: extract_symbolic_data
arguments: data_label: D27
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D49: informe quantas jogadas: 

tool: D7: %d

tool: D27: informe os valores de cada lancamento: 

tool: D8: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n, l, i;
  int p[6];
  printf("informe quantas jogadas: \n");
  scanf("%d", &n);
  printf("informe os valores de cada lancamento: \n");
  for (i = 0; i < 6; i++) {
    p[i] = 0;
  }
  for (i = 0; i < n; i++) {
    scanf("%d", &l);
    if (l == 1) {
      p[0]++;
    }
    if (l == 2) {
      p[1]++;
    }
    if (l == 3) {
      p[2]++;
    }
    if (l == 4) {
      p[3]++;
    }
    if (l == 5) {
      p[4]++;
    }
    if (l == 6) {
      p[5]++;
    }
  }
  for (i = 0; i < 6; i++) {
    printf("%d ", p[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  test   %eax,%eax
  jle    L115
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r12
  jmp    L158
  nopl   0x0(%rax)
L68:
  cmp    $0x2,%eax
  je     L40
  cmp    $0x3,%eax
  jne    L126
  addl   $0x1,0x18(%rsp)
L71:
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jle    L115
L158:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  jne    L68
  addl   $0x1,0x10(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jg     L158
L115:
  lea    0x10(%rsp),%rbx
  lea    0x28(%rsp),%r12
  lea    D35(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L132:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L132
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L91
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L126:
  cmp    $0x4,%eax
  jne    L83
  addl   $0x1,0x1c(%rsp)
  jmp    L71
  nop
L40:
  addl   $0x1,0x14(%rsp)
  jmp    L71
L83:
  cmp    $0x5,%eax
  jne    L116
  addl   $0x1,0x20(%rsp)
  jmp    L71
L116:
  cmp    $0x6,%eax
  jne    L71
  addl   $0x1,0x24(%rsp)
  jmp    L71
L91:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D15
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D35
type_guessed: string

tool: D8: informe quantas jogadas: 

tool: D15: %d

tool: D24: informe os valores de cada lancamento: 

tool: D35: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n, l, i;
  int p[6];
  printf("informe quantas jogadas: \n");
  scanf("%d", &n);
  printf("informe os valores de cada lancamento: \n");
  for (i = 0; i < 6; i++) {
    p[i] = 0;
  }
  for (i = 0; i < n; i++) {
    scanf("%d", &l);
    if (l == 1) {
      p[0]++;
    }
    if (l == 2) {
      p[1]++;
    }
    if (l == 3) {
      p[2]++;
    }
    if (l == 4) {
      p[3]++;
    }
    if (l == 5) {
      p[4]++;
    }
    if (l == 6) {
      p[5]++;
    }
  }
  for (i = 0; i < 6; i++) {
    printf("%d ", p[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rdi
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  pxor   %xmm0,%xmm0
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  test   %eax,%eax
  jle    L70
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r12
  jmp    L96
  nopl   0x0(%rax,%rax,1)
L59:
  cmp    $0x2,%eax
  je     L114
  cmp    $0x3,%eax
  jne    L24
  addl   $0x1,0x18(%rsp)
L44:
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jle    L70
L96:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  jne    L59
  addl   $0x1,0x10(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jg     L96
L70:
  lea    0x10(%rsp),%rbx
  lea    0x28(%rsp),%r12
  lea    D1(%rip),%rbp
  nop
L150:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L150
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L121
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  cmp    $0x4,%eax
  jne    L98
  addl   $0x1,0x1c(%rsp)
  jmp    L44
  nopl   0x0(%rax)
L114:
  addl   $0x1,0x14(%rsp)
  jmp    L44
L98:
  cmp    $0x5,%eax
  jne    L104
  addl   $0x1,0x20(%rsp)
  jmp    L44
L104:
  cmp    $0x6,%eax
  jne    L44
  addl   $0x1,0x24(%rsp)
  jmp    L44
L121:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D22
datatype: string
name: extract_symbolic_data
arguments: data_label: D21
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D12: informe quantas jogadas: 

tool: D22: %d

tool: D21: informe os valores de cada lancamento: 

tool: D1: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n, l, i;
  int p[6];
  printf("informe quantas jogadas: \n");
  scanf("%d", &n);
  printf("informe os valores de cada lancamento: \n");
  for (i = 0; i < 6; i++) {
    p[i] = 0;
  }
  for (i = 0; i < n; i++) {
    scanf("%d", &l);
    if (l == 1) {
      p[0]++;
    }
    if (l == 2) {
      p[1]++;
    }
    if (l == 3) {
      p[2]++;
    }
    if (l == 4) {
      p[3]++;
    }
    if (l == 5) {
      p[4]++;
    }
    if (l == 6) {
      p[5]++;
    }
  }
  for (i = 0; i < 6; i++) {
    printf("%d ", p[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FS460_set_bridge_bypass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <sio_read_reg@plt>
  cmpl   $0x0,-0x14(%rbp)
  je     L15
  mov    -0x10(%rbp),%rax
  or     $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L16
L15:
  mov    -0x10(%rbp),%rax
  and    $0xfffffffffffffffe,%rax
  mov    %rax,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <sio_write_reg@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int FS460_set_bridge_bypass(int bypass) {
  unsigned long reg;
  sio_read_reg(0x0A, &reg);
  if (bypass)
    reg |= 0x0001;
  else
    reg &= ~(0x0001);
  sio_write_reg(0x0A, reg);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<FS460_set_bridge_bypass>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edi
  call   <sio_read_reg@plt>
  test   %ebx,%ebx
  je     L14
  mov    (%rsp),%rsi
  or     $0x1,%rsi
L21:
  mov    %rsi,(%rsp)
  mov    $0xa,%edi
  call   <sio_write_reg@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L14:
  mov    (%rsp),%rsi
  and    $0xfffffffffffffffe,%rsi
  jmp    L21
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int FS460_set_bridge_bypass(int bypass) {
  unsigned long reg;
  sio_read_reg(0x0A, &reg);
  if (bypass)
    reg |= 0x0001;
  else
    reg &= ~(0x0001);
  sio_write_reg(0x0A, reg);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FS460_set_bridge_bypass>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xa,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <sio_read_reg@plt>
  mov    (%rsp),%rsi
  test   %ebx,%ebx
  je     L19
  or     $0x1,%rsi
L5:
  mov    $0xa,%edi
  mov    %rsi,(%rsp)
  call   <sio_write_reg@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  and    $0xfffffffffffffffe,%rsi
  jmp    L5
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int FS460_set_bridge_bypass(int bypass) {
  unsigned long reg;
  sio_read_reg(0x0A, &reg);
  if (bypass)
    reg |= 0x0001;
  else
    reg &= ~(0x0001);
  sio_write_reg(0x0A, reg);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<FS460_set_bridge_bypass>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xa,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <sio_read_reg@plt>
  mov    (%rsp),%rsi
  test   %ebx,%ebx
  je     L5
  or     $0x1,%rsi
L9:
  mov    $0xa,%edi
  mov    %rsi,(%rsp)
  call   <sio_write_reg@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  and    $0xfffffffffffffffe,%rsi
  jmp    L9
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int FS460_set_bridge_bypass(int bypass) {
  unsigned long reg;
  sio_read_reg(0x0A, &reg);
  if (bypass)
    reg |= 0x0001;
  else
    reg &= ~(0x0001);
  sio_write_reg(0x0A, reg);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<InchiClock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  jmp    L18
L2:
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
clock_t InchiClock(void) {
  clock_t c = clock();
  if (c != (clock_t)-1) {
    return c;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InchiClock>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clock@plt>
  cmp    $0xffffffffffffffff,%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
clock_t InchiClock(void) {
  clock_t c = clock();
  if (c != (clock_t)-1) {
    return c;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<InchiClock>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clock@plt>
  xor    %edx,%edx
  cmp    $0xffffffffffffffff,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
clock_t InchiClock(void) {
  clock_t c = clock();
  if (c != (clock_t)-1) {
    return c;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<InchiClock>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clock@plt>
  xor    %edx,%edx
  cmp    $0xffffffffffffffff,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
clock_t InchiClock(void) {
  clock_t c = clock();
  if (c != (clock_t)-1) {
    return c;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0xa0(%rbp)
  mov    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x41,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x98(%rbp)
  mov    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0xa8(%rbp)
  lea    -0x90(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypto_sign_keypair_ecdsa256sha512@plt>
  mov    -0xa8(%rbp),%rcx
  lea    -0x90(%rbp),%rdi
  mov    -0xa0(%rbp),%rdx
  lea    -0xb0(%rbp),%rsi
  mov    -0x98(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <crypto_sign_ecdsa256sha512@plt>
  movl   $0x0,-0xb4(%rbp)
  jmp    L23
L10:
  mov    -0xb0(%rbp),%rcx
  lea    -0x50(%rbp),%rdi
  mov    -0x98(%rbp),%rdx
  lea    -0xa8(%rbp),%rsi
  mov    -0xa0(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <crypto_sign_open_ecdsa256sha512@plt>
  addl   $0x1,-0xb4(%rbp)
L23:
  cmpl   $0x270f,-0xb4(%rbp)
  jle    L10
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string

tool: D14: Hello World!

tool: D8: 10000 verifications complete


assistant: ```c
int main() {
  unsigned char sk[64];
  unsigned char pk[64];
  unsigned char *m = strdup("Hello World!");
  unsigned char *sm = malloc(strlen(m) + 65);
  unsigned long long smlen;
  unsigned long long mlen = strlen(m) + 1;
  crypto_sign_keypair_ecdsa256sha512(pk, sk);
  crypto_sign_ecdsa256sha512(sm, &smlen, m, mlen, sk);
  for (int i = 0; i < 10000; i++)
    crypto_sign_open_ecdsa256sha512(m, &mlen, sm, smlen, pk);
  printf("10000 verifications complete\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x41(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rbx
  lea    0x50(%rsp),%rdi
  mov    %rbx,%rsi
  call   <crypto_sign_keypair_ecdsa256sha512@plt>
  mov    %rsp,%rsi
  mov    %rbx,%r8
  mov    0x8(%rsp),%rcx
  mov    %rbp,%rdx
  mov    %r12,%rdi
  call   <crypto_sign_ecdsa256sha512@plt>
  mov    $0x2710,%ebx
  lea    0x50(%rsp),%r13
L0:
  lea    0x8(%rsp),%rsi
  mov    %r13,%r8
  mov    (%rsp),%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <crypto_sign_open_ecdsa256sha512@plt>
  sub    $0x1,%ebx
  jne    L0
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D9: Hello World!

tool: D2: 10000 verifications complete


assistant: ```c
int main() {
  unsigned char sk[64];
  unsigned char pk[64];
  unsigned char *m = strdup("Hello World!");
  unsigned char *sm = malloc(strlen(m) + 65);
  unsigned long long smlen;
  unsigned long long mlen = strlen(m) + 1;
  crypto_sign_keypair_ecdsa256sha512(pk, sk);
  crypto_sign_ecdsa256sha512(sm, &smlen, m, mlen, sk);
  for (int i = 0; i < 10000; i++)
    crypto_sign_open_ecdsa256sha512(m, &mlen, sm, smlen, pk);
  printf("10000 verifications complete\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x50(%rsp),%r13
  call   <strdup@plt>
  lea    0x8(%rsp),%r14
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x41(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%eax
  cltq
  mov    %rax,0x8(%rsp)
  call   <crypto_sign_keypair_ecdsa256sha512@plt>
  mov    0x8(%rsp),%rcx
  mov    %rbx,%r8
  mov    %rsp,%rsi
  mov    %rbp,%rdx
  mov    %r12,%rdi
  mov    $0x2710,%ebx
  call   <crypto_sign_ecdsa256sha512@plt>
  nop
L9:
  mov    (%rsp),%rcx
  mov    %r13,%r8
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <crypto_sign_open_ecdsa256sha512@plt>
  sub    $0x1,%ebx
  jne    L9
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string

tool: D5: Hello World!

tool: D17: 10000 verifications complete


assistant: ```c
int main() {
  unsigned char sk[64];
  unsigned char pk[64];
  unsigned char *m = strdup("Hello World!");
  unsigned char *sm = malloc(strlen(m) + 65);
  unsigned long long smlen;
  unsigned long long mlen = strlen(m) + 1;
  crypto_sign_keypair_ecdsa256sha512(pk, sk);
  crypto_sign_ecdsa256sha512(sm, &smlen, m, mlen, sk);
  for (int i = 0; i < 10000; i++)
    crypto_sign_open_ecdsa256sha512(m, &mlen, sm, smlen, pk);
  printf("10000 verifications complete\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x50(%rsp),%r13
  call   <strdup@plt>
  lea    0x8(%rsp),%r14
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x41(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%eax
  cltq
  mov    %rax,0x8(%rsp)
  call   <crypto_sign_keypair_ecdsa256sha512@plt>
  mov    0x8(%rsp),%rcx
  mov    %rbx,%r8
  mov    %rsp,%rsi
  mov    %rbp,%rdx
  mov    %r12,%rdi
  mov    $0x2710,%ebx
  call   <crypto_sign_ecdsa256sha512@plt>
  nop
L10:
  mov    (%rsp),%rcx
  mov    %r13,%r8
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <crypto_sign_open_ecdsa256sha512@plt>
  sub    $0x1,%ebx
  jne    L10
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D10: Hello World!

tool: D0: 10000 verifications complete


assistant: ```c
int main() {
  unsigned char sk[64];
  unsigned char pk[64];
  unsigned char *m = strdup("Hello World!");
  unsigned char *sm = malloc(strlen(m) + 65);
  unsigned long long smlen;
  unsigned long long mlen = strlen(m) + 1;
  crypto_sign_keypair_ecdsa256sha512(pk, sk);
  crypto_sign_ecdsa256sha512(sm, &smlen, m, mlen, sk);
  for (int i = 0; i < 10000; i++)
    crypto_sign_open_ecdsa256sha512(m, &mlen, sm, smlen, pk);
  printf("10000 verifications complete\n");
  exit(0);
}
```