user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x616e3f2f20544547,%rax
  movabs $0x26726569703d656d,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x616d3d6c69616d65,%rax
  movabs $0x2e6f616d3034256f,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x656d6d6f63267469,%rax
  movabs $0x636e61663d73746e,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x50545448206f6c75,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x312e312f,-0x18(%rbp)
  movb   $0x0,-0x14(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x90(%rbp)
  mov    -0x90(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x80(%rbp)
  mov    -0x90(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    $0x26,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  sub    -0x80(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x8c(%rbp)
  mov    -0x8c(%rbp),%edx
  mov    -0x80(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stampa@plt>
  mov    -0x90(%rbp),%eax
  lea    -0x50(%rbp),%rcx
  mov    -0x78(%rbp),%rdx
  sub    %rcx,%rdx
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x78(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x70(%rbp)
  mov    -0x90(%rbp),%eax
  lea    -0x50(%rbp),%rcx
  mov    -0x78(%rbp),%rdx
  sub    %rcx,%rdx
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  mov    $0x26,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  sub    -0x70(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x88(%rbp)
  mov    -0x88(%rbp),%edx
  mov    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stampa@plt>
  mov    -0x90(%rbp),%eax
  lea    -0x50(%rbp),%rcx
  mov    -0x68(%rbp),%rdx
  sub    %rcx,%rdx
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  add    $0x1,%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x90(%rbp),%eax
  lea    -0x50(%rbp),%rcx
  mov    -0x68(%rbp),%rdx
  sub    %rcx,%rdx
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  add    $0x1,%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  sub    -0x60(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x84(%rbp)
  mov    -0x84(%rbp),%edx
  mov    -0x60(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stampa@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int len;
  int diff;
  int diff1;
  int diff2;
  char *ret1;
  char *ret2;
  char *ret3;
  char *ret4;
  char *ret5;
  char *ret6;
  char str[] = "GET /?name=pier&email=mao%40mao.it&comments=fanculo HTTP/1.1";
  len = strlen(str);
  ret1 = memchr(str, '=', len) + 1;
  ret2 = memchr(str, '&', len) + 1;
  diff = (ret2 - ret1) - 1;
  stampa(ret1, diff);
  ret3 = memchr(ret2, '=', len - (ret2 - str)) + 1;
  ret4 = memchr(ret2 + 1, '&', len - (ret2 - str)) + 1;
  diff1 = (ret4 - ret3) - 1;
  stampa(ret3, diff1);
  ret5 = memchr(ret4 + 1, '=', len - (ret4 - str)) + 1;
  ret6 = memchr(ret4 + 1, ' ', len - (ret4 - str)) + 1;
  diff2 = (ret6 - ret5) - 1;
  stampa(ret5, diff2);
}
```