ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fc8080_set_xtal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4000000,%edx
  mov    $0x278,%esi
  call   <bbm_long_write@plt>
  mov    $0x80,%edx
  mov    $0x27c,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x80,%edx
  mov    $0x27d,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x2,%edx
  mov    $0x27e,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x2,%edx
  mov    $0x120,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0xf,%edx
  mov    $0x121,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0xd,%edx
  mov    $0x122,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x0,%edx
  mov    $0x123,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x4,%edx
  mov    $0x124,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x3,%edx
  mov    $0x125,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x1c,%edx
  mov    $0x126,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x19,%edx
  mov    $0x127,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x2,%edx
  mov    $0x128,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0xc,%edx
  mov    $0x129,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x4,%edx
  mov    $0x12a,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x30,%edx
  mov    $0x12b,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0xed,%edx
  mov    $0x12c,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x13,%edx
  mov    $0x12d,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x4f,%edx
  mov    $0x12e,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x6b,%edx
  mov    $0x12f,%esi
  mov    %rbx,%rdi
  call   <bbm_byte_write@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fc8080_set_xtal(void *handle) {
  bbm_long_write(handle, 0x0278, 0x04000000);
  bbm_byte_write(handle, 0x027c, 0x80);
  bbm_byte_write(handle, 0x027d, 0x80);
  bbm_byte_write(handle, 0x027e, 0x02);
  bbm_byte_write(handle, 0x0120, 0x02);
  bbm_byte_write(handle, 0x0121, 0x0f);
  bbm_byte_write(handle, 0x0122, 0x0d);
  bbm_byte_write(handle, 0x0123, 0x00);
  bbm_byte_write(handle, 0x0124, 0x04);
  bbm_byte_write(handle, 0x0125, 0x03);
  bbm_byte_write(handle, 0x0126, 0x1c);
  bbm_byte_write(handle, 0x0127, 0x19);
  bbm_byte_write(handle, 0x0128, 0x02);
  bbm_byte_write(handle, 0x0129, 0x0c);
  bbm_byte_write(handle, 0x012a, 0x04);
  bbm_byte_write(handle, 0x012b, 0x30);
  bbm_byte_write(handle, 0x012c, 0xed);
  bbm_byte_write(handle, 0x012d, 0x13);
  bbm_byte_write(handle, 0x012e, 0x4f);
  bbm_byte_write(handle, 0x012f, 0x6b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fc8080_set_xtal>:
  endbr64
  push   %rbp
  mov    $0x4000000,%edx
  mov    %rdi,%rbp
  mov    $0x278,%esi
  call   <bbm_long_write@plt>
  mov    %rbp,%rdi
  mov    $0x80,%edx
  mov    $0x27c,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x80,%edx
  mov    $0x27d,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x27e,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x120,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0xf,%edx
  mov    $0x121,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0xd,%edx
  mov    $0x122,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x123,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x124,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    $0x125,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x1c,%edx
  mov    $0x126,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x19,%edx
  mov    $0x127,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x128,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0xc,%edx
  mov    $0x129,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x12a,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x30,%edx
  mov    $0x12b,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0xed,%edx
  mov    $0x12c,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x13,%edx
  mov    $0x12d,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x4f,%edx
  mov    $0x12e,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x6b,%edx
  mov    $0x12f,%esi
  call   <bbm_byte_write@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fc8080_set_xtal(void *handle) {
  bbm_long_write(handle, 0x0278, 0x04000000);
  bbm_byte_write(handle, 0x027c, 0x80);
  bbm_byte_write(handle, 0x027d, 0x80);
  bbm_byte_write(handle, 0x027e, 0x02);
  bbm_byte_write(handle, 0x0120, 0x02);
  bbm_byte_write(handle, 0x0121, 0x0f);
  bbm_byte_write(handle, 0x0122, 0x0d);
  bbm_byte_write(handle, 0x0123, 0x00);
  bbm_byte_write(handle, 0x0124, 0x04);
  bbm_byte_write(handle, 0x0125, 0x03);
  bbm_byte_write(handle, 0x0126, 0x1c);
  bbm_byte_write(handle, 0x0127, 0x19);
  bbm_byte_write(handle, 0x0128, 0x02);
  bbm_byte_write(handle, 0x0129, 0x0c);
  bbm_byte_write(handle, 0x012a, 0x04);
  bbm_byte_write(handle, 0x012b, 0x30);
  bbm_byte_write(handle, 0x012c, 0xed);
  bbm_byte_write(handle, 0x012d, 0x13);
  bbm_byte_write(handle, 0x012e, 0x4f);
  bbm_byte_write(handle, 0x012f, 0x6b);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fc8080_set_xtal>:
  endbr64
  push   %rbp
  mov    $0x4000000,%edx
  mov    %rdi,%rbp
  mov    $0x278,%esi
  call   <bbm_long_write@plt>
  mov    %rbp,%rdi
  mov    $0x80,%edx
  mov    $0x27c,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x80,%edx
  mov    $0x27d,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x27e,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x120,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0xf,%edx
  mov    $0x121,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0xd,%edx
  mov    $0x122,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x123,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x124,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  mov    $0x125,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x1c,%edx
  mov    $0x126,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x19,%edx
  mov    $0x127,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x128,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0xc,%edx
  mov    $0x129,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x12a,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x30,%edx
  mov    $0x12b,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0xed,%edx
  mov    $0x12c,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x13,%edx
  mov    $0x12d,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x4f,%edx
  mov    $0x12e,%esi
  call   <bbm_byte_write@plt>
  mov    %rbp,%rdi
  mov    $0x6b,%edx
  mov    $0x12f,%esi
  call   <bbm_byte_write@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fc8080_set_xtal(void *handle) {
  bbm_long_write(handle, 0x0278, 0x04000000);
  bbm_byte_write(handle, 0x027c, 0x80);
  bbm_byte_write(handle, 0x027d, 0x80);
  bbm_byte_write(handle, 0x027e, 0x02);
  bbm_byte_write(handle, 0x0120, 0x02);
  bbm_byte_write(handle, 0x0121, 0x0f);
  bbm_byte_write(handle, 0x0122, 0x0d);
  bbm_byte_write(handle, 0x0123, 0x00);
  bbm_byte_write(handle, 0x0124, 0x04);
  bbm_byte_write(handle, 0x0125, 0x03);
  bbm_byte_write(handle, 0x0126, 0x1c);
  bbm_byte_write(handle, 0x0127, 0x19);
  bbm_byte_write(handle, 0x0128, 0x02);
  bbm_byte_write(handle, 0x0129, 0x0c);
  bbm_byte_write(handle, 0x012a, 0x04);
  bbm_byte_write(handle, 0x012b, 0x30);
  bbm_byte_write(handle, 0x012c, 0xed);
  bbm_byte_write(handle, 0x012d, 0x13);
  bbm_byte_write(handle, 0x012e, 0x4f);
  bbm_byte_write(handle, 0x012f, 0x6b);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stb__sbgrowf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L12
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rax
  mov    (%rax),%eax
  add    %eax,%eax
  jmp    L70
L12:
  mov    $0x0,%eax
L70:
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L32
  mov    -0x28(%rbp),%rax
  mov    -0x4(%rax),%eax
  jmp    L86
L32:
  mov    $0x0,%eax
L86:
  mov    -0x2c(%rbp),%edx
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cltq
  lea    0x8(%rax),%rdx
  cmpq   $0x0,-0x28(%rbp)
  je     L84
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rax
  jmp    L0
L84:
  mov    $0x0,%eax
L0:
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L34
  cmpq   $0x0,-0x28(%rbp)
  jne    L11
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
L11:
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  jmp    L89
L34:
  mov    $0x8,%eax
L89:
  leave
  ret
```

assistant: ```c
void *stb__sbgrowf(void *arr, int increment, int itemsize) {
  int dbl_cur = arr ? 2 * ((int *)(arr)-2)[0] : 0;
  int min_needed = ((arr) ? ((int *)(arr)-2)[1] : 0) + increment;
  int m = dbl_cur > min_needed ? dbl_cur : min_needed;
  int *p = (int *)realloc(arr ? ((int *)(arr)-2) : 0, itemsize * m + sizeof(int) * 2);
  if (p) {
    if (!arr)
      p[1] = 0;
    p[0] = m;
    return p + 2;
  } else {
    return (void *)(2 * sizeof(int));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stb__sbgrowf>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L3
  mov    -0x8(%rdi),%eax
  lea    (%rax,%rax,1),%ebx
  add    -0x4(%rdi),%esi
  cmp    %esi,%ebx
  cmovl  %esi,%ebx
  imul   %ebx,%edx
  movslq %edx,%rsi
  add    $0x8,%rsi
  sub    $0x8,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L50
L10:
  mov    %ebx,(%rax)
  add    $0x8,%rax
L38:
  pop    %rbx
  ret
L50:
  mov    $0x8,%eax
  jmp    L38
L3:
  test   %esi,%esi
  mov    $0x0,%ebx
  cmovns %esi,%ebx
  imul   %ebx,%edx
  movslq %edx,%rdi
  add    $0x8,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L48
  movl   $0x0,0x4(%rax)
  jmp    L10
L48:
  mov    $0x8,%eax
  jmp    L38
```

assistant: ```c
void *stb__sbgrowf(void *arr, int increment, int itemsize) {
  int dbl_cur = arr ? 2 * ((int *)(arr)-2)[0] : 0;
  int min_needed = ((arr) ? ((int *)(arr)-2)[1] : 0) + increment;
  int m = dbl_cur > min_needed ? dbl_cur : min_needed;
  int *p = (int *)realloc(arr ? ((int *)(arr)-2) : 0, itemsize * m + sizeof(int) * 2);
  if (p) {
    if (!arr)
      p[1] = 0;
    p[0] = m;
    return p + 2;
  } else {
    return (void *)(2 * sizeof(int));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stb__sbgrowf>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L0
  mov    -0x8(%rdi),%eax
  add    -0x4(%rdi),%esi
  lea    (%rax,%rax,1),%ebx
  cmp    %esi,%ebx
  cmovl  %esi,%ebx
  sub    $0x8,%rdi
  imul   %ebx,%edx
  movslq %edx,%rsi
  add    $0x8,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L39
L36:
  mov    %ebx,(%rax)
  add    $0x8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %ebx,%ebx
  test   %esi,%esi
  cmovns %esi,%ebx
  imul   %ebx,%edx
  movslq %edx,%rdi
  add    $0x8,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L39
  movl   $0x0,0x4(%rax)
  jmp    L36
L39:
  mov    $0x8,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *stb__sbgrowf(void *arr, int increment, int itemsize) {
  int dbl_cur = arr ? 2 * ((int *)(arr)-2)[0] : 0;
  int min_needed = ((arr) ? ((int *)(arr)-2)[1] : 0) + increment;
  int m = dbl_cur > min_needed ? dbl_cur : min_needed;
  int *p = (int *)realloc(arr ? ((int *)(arr)-2) : 0, itemsize * m + sizeof(int) * 2);
  if (p) {
    if (!arr)
      p[1] = 0;
    p[0] = m;
    return p + 2;
  } else {
    return (void *)(2 * sizeof(int));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<stb__sbgrowf>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L12
  mov    -0x8(%rdi),%eax
  add    -0x4(%rdi),%esi
  lea    (%rax,%rax,1),%ebx
  cmp    %esi,%ebx
  cmovl  %esi,%ebx
  sub    $0x8,%rdi
  imul   %ebx,%edx
  movslq %edx,%rsi
  add    $0x8,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L29
L4:
  mov    %ebx,(%rax)
  add    $0x8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %ebx,%ebx
  test   %esi,%esi
  cmovns %esi,%ebx
  imul   %ebx,%edx
  movslq %edx,%rdi
  add    $0x8,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L29
  movl   $0x0,0x4(%rax)
  jmp    L4
L29:
  mov    $0x8,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *stb__sbgrowf(void *arr, int increment, int itemsize) {
  int dbl_cur = arr ? 2 * ((int *)(arr)-2)[0] : 0;
  int min_needed = ((arr) ? ((int *)(arr)-2)[1] : 0) + increment;
  int m = dbl_cur > min_needed ? dbl_cur : min_needed;
  int *p = (int *)realloc(arr ? ((int *)(arr)-2) : 0, itemsize * m + sizeof(int) * 2);
  if (p) {
    if (!arr)
      p[1] = 0;
    p[0] = m;
    return p + 2;
  } else {
    return (void *)(2 * sizeof(int));
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fprintf(FILE *f, const char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(f, fmt, arglist);
  va_end(arglist);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fprintf(FILE *f, const char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(f, fmt, arglist);
  va_end(arglist);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fprintf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fprintf(FILE *f, const char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(f, fmt, arglist);
  va_end(arglist);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fprintf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fprintf(FILE *f, const char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(f, fmt, arglist);
  va_end(arglist);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ccbi_initscr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <setupterm@plt>
  mov    D5(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L19
  mov    $0x0,%eax
  jmp    L27
L19:
  mov    $0x0,%eax
  call   <initscr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
uint8_t ccbi_initscr() {
  int err;
  if (setupterm(NULL, 1, &err) == ERR)
    return 0;
  return initscr() == NULL ? 0 : 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ccbi_initscr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <setupterm@plt>
  mov    %rax,%rcx
  mov    $0x0,%eax
  mov    D9(%rip),%rdx
  cmp    (%rdx),%rcx
  je     L8
  call   <initscr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t ccbi_initscr() {
  int err;
  if (setupterm(NULL, 1, &err) == ERR)
    return 0;
  return initscr() == NULL ? 0 : 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ccbi_initscr>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <setupterm@plt>
  mov    D6(%rip),%rdx
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    (%rdx),%r8
  je     L9
  call   <initscr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t ccbi_initscr() {
  int err;
  if (setupterm(NULL, 1, &err) == ERR)
    return 0;
  return initscr() == NULL ? 0 : 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ccbi_initscr>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <setupterm@plt>
  mov    D6(%rip),%rdx
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    (%rdx),%r8
  je     L0
  call   <initscr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t ccbi_initscr() {
  int err;
  if (setupterm(NULL, 1, &err) == ERR)
    return 0;
  return initscr() == NULL ? 0 : 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<marginal_j_mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L25
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movsd  %xmm2,-0x40(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mulsd  -0x40(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L25:
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm3
  movsd  %xmm3,-0x40(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  addsd  -0x40(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double marginal_j_mean(int p, int j, double *mu, double *kappa, double *lambda, double *theta_i) {
  int l;
  double acum = 0.;
  for (l = 0; l < p; l++) {
    if (l != j) {
      acum += lambda[j * p + l] * sin(theta_i[l] - mu[l]);
    }
  }
  return mu[j] + atan(acum / kappa[j]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<marginal_j_mean>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %rcx,0x18(%rsp)
  test   %edi,%edi
  jle    L13
  mov    %r8,%r14
  mov    %r9,%r15
  mov    %esi,%eax
  imul   %edi,%eax
  mov    %eax,0x14(%rsp)
  mov    %edi,%r12d
  mov    $0x0,%ebx
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
  jmp    L38
L3:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L23
L38:
  cmp    %ebx,%ebp
  je     L3
  movsd  (%r15,%rbx,8),%xmm0
  subsd  0x0(%r13,%rbx,8),%xmm0
  call   <sin@plt>
  mov    0x14(%rsp),%eax
  add    %ebx,%eax
  cltq
  mulsd  (%r14,%rax,8),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  jmp    L3
L13:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
L23:
  movslq %ebp,%rbp
  mov    0x18(%rsp),%rax
  movsd  0x8(%rsp),%xmm0
  divsd  (%rax,%rbp,8),%xmm0
  call   <atan@plt>
  addsd  0x0(%r13,%rbp,8),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double marginal_j_mean(int p, int j, double *mu, double *kappa, double *lambda, double *theta_i) {
  int l;
  double acum = 0.;
  for (l = 0; l < p; l++) {
    if (l != j) {
      acum += lambda[j * p + l] * sin(theta_i[l] - mu[l]);
    }
  }
  return mu[j] + atan(acum / kappa[j]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<marginal_j_mean>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  test   %ebp,%ebp
  jle    L29
  mov    %ebx,%eax
  mov    %r8,%r13
  mov    %r9,%r14
  xor    %r15d,%r15d
  imul   %ebp,%eax
  pxor   %xmm1,%xmm1
  mov    %eax,0x14(%rsp)
  xchg   %ax,%ax
L14:
  cmp    %r15d,%ebx
  je     L27
  movsd  (%r14,%r15,8),%xmm0
  subsd  (%r12,%r15,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  mov    0x14(%rsp),%eax
  movsd  0x8(%rsp),%xmm1
  lea    (%rax,%r15,1),%edx
  movslq %edx,%rdx
  mulsd  0x0(%r13,%rdx,8),%xmm0
  addsd  %xmm0,%xmm1
L27:
  add    $0x1,%r15
  cmp    %r15,%rbp
  jne    L14
L21:
  mov    0x18(%rsp),%rax
  divsd  (%rax,%rbx,8),%xmm1
  movapd %xmm1,%xmm0
  call   <atan@plt>
  addsd  (%r12,%rbx,8),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  pxor   %xmm1,%xmm1
  jmp    L21
```

assistant: ```c
double marginal_j_mean(int p, int j, double *mu, double *kappa, double *lambda, double *theta_i) {
  int l;
  double acum = 0.;
  for (l = 0; l < p; l++) {
    if (l != j) {
      acum += lambda[j * p + l] * sin(theta_i[l] - mu[l]);
    }
  }
  return mu[j] + atan(acum / kappa[j]);
}
```