ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<open_weak_exclusive>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L51
  mov    D24(%rip),%rax
  mov    %ebp,%ecx
  and    (%rax),%ecx
  je     L51
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  add    $0xffffff80,%eax
  cmp    $0x7,%eax
  ja     L22
L51:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L4
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  not    %esi
  and    %ebp,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <open@plt>
  mov    %eax,%ebx
  jmp    L51
L4:
  mov    D1(%rip),%rax
  movl   $0x86,(%rax)
  jmp    L51
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_weak_exclusive(const char *pathname, int flags, mode_t mode) {
  int ret;
  struct stat filestat;
  ret = open(pathname, flags, mode);
  if (ret != -1 || !(flags & O_EXCL)) {
    return ret;
  }
  switch (errno) {
  case EACCES:
  case EEXIST:
  case EINTR:
  case EISDIR:
  case ELOOP:
  case ENAMETOOLONG:
  case ENOENT:
  case ENOTDIR:
    return ret;
  }
  if (stat(pathname, &filestat) != -1) {
    errno = EEXIST;
    return -1;
  } else {
    return open(pathname, flags & ~O_EXCL, mode);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<open_weak_exclusive>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  jne    L4
  mov    D7(%rip),%r14
  mov    %ebx,%eax
  and    (%r14),%eax
  je     L4
  mov    D0(%rip),%r15
  mov    (%r15),%eax
  add    $0xffffff80,%eax
  cmp    $0x7,%eax
  jbe    L4
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L47
  mov    (%r14),%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  not    %esi
  and    %ebx,%esi
  call   <open@plt>
  mov    %eax,%r12d
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  movl   $0x86,(%r15)
  jmp    L4
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_weak_exclusive(const char *pathname, int flags, mode_t mode) {
  int ret;
  struct stat filestat;
  ret = open(pathname, flags, mode);
  if (ret != -1 || !(flags & O_EXCL)) {
    return ret;
  }
  switch (errno) {
  case EACCES:
  case EEXIST:
  case EINTR:
  case EISDIR:
  case ELOOP:
  case ENAMETOOLONG:
  case ENOENT:
  case ENOTDIR:
    return ret;
  }
  if (stat(pathname, &filestat) != -1) {
    errno = EEXIST;
    return -1;
  } else {
    return open(pathname, flags & ~O_EXCL, mode);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<open_weak_exclusive>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  jne    L38
  mov    D14(%rip),%r14
  mov    %ebx,%eax
  and    (%r14),%eax
  je     L38
  mov    D19(%rip),%r15
  mov    (%r15),%eax
  add    $0xffffff80,%eax
  cmp    $0x7,%eax
  jbe    L38
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L20
  mov    (%r14),%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  not    %esi
  and    %ebx,%esi
  call   <open@plt>
  mov    %eax,%r12d
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  movl   $0x86,(%r15)
  jmp    L38
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_weak_exclusive(const char *pathname, int flags, mode_t mode) {
  int ret;
  struct stat filestat;
  ret = open(pathname, flags, mode);
  if (ret != -1 || !(flags & O_EXCL)) {
    return ret;
  }
  switch (errno) {
  case EACCES:
  case EEXIST:
  case EINTR:
  case EISDIR:
  case ELOOP:
  case ENAMETOOLONG:
  case ENOENT:
  case ENOTDIR:
    return ret;
  }
  if (stat(pathname, &filestat) != -1) {
    errno = EEXIST;
    return -1;
  } else {
    return open(pathname, flags & ~O_EXCL, mode);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <syscall_read@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void read() {
  char c;
  syscall_read(0, &c, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%edi
  call   <syscall_read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read() {
  char c;
  syscall_read(0, &c, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <syscall_read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read() {
  char c;
  syscall_read(0, &c, 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <syscall_read@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void read() {
  char c;
  syscall_read(0, &c, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movabs $0x8be589eac7,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x1,-0x18(%rbp)
  jmp    L34
L10:
  mov    -0x8(%rbp),%rax
  cqto
  idivq  -0x18(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L31
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L31
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L31
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  addq   $0x1,-0x18(%rbp)
L34:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  cmp    %rax,-0x18(%rbp)
  jl     L10
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: maior: %lld


assistant: ```c
int main() {
  long long num;
  num = 600851475143;
  long long i, bigPrime = 0;
  for (i = 1; i < sqrt(num); i++) {
    if (num % i == 0 && isPrime(i) && i > bigPrime) {
      bigPrime = i;
      printf("maior: %lld\n", bigPrime);
    }
  }
  getchar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  movabs $0x8be589eac7,%rbp
  lea    D5(%rip),%r13
  jmp    L56
L27:
  add    $0x1,%rbx
L56:
  mov    %rbp,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L5
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L27
  mov    %rbx,%rdi
  call   <isPrime@plt>
  cmp    %r12,%rbx
  jle    L27
  test   %rax,%rax
  je     L27
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%r12
  jmp    L27
L5:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: maior: %lld


assistant: ```c
int main() {
  long long num;
  num = 600851475143;
  long long i, bigPrime = 0;
  for (i = 1; i < sqrt(num); i++) {
    if (num % i == 0 && isPrime(i) && i > bigPrime) {
      bigPrime = i;
      printf("maior: %lld\n", bigPrime);
    }
  }
  getchar();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  movabs $0x8be589eac7,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x1,%rbx
L37:
  mov    %r12,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L10
  mov    %r12,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L36
  mov    %rbx,%rdi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L36
  cmp    %rbp,%rbx
  jle    L36
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    %rbx,%rbp
  call   <printf@plt>
  jmp    L36
L10:
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0: maior: %lld


assistant: ```c
int main() {
  long long num;
  num = 600851475143;
  long long i, bigPrime = 0;
  for (i = 1; i < sqrt(num); i++) {
    if (num % i == 0 && isPrime(i) && i > bigPrime) {
      bigPrime = i;
      printf("maior: %lld\n", bigPrime);
    }
  }
  getchar();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  movabs $0x8be589eac7,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rbx
L13:
  mov    %r12,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L32
  mov    %r12,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L26
  mov    %rbx,%rdi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L26
  cmp    %rbp,%rbx
  jle    L26
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    %rbx,%rbp
  call   <printf@plt>
  jmp    L26
L32:
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: maior: %lld


assistant: ```c
int main() {
  long long num;
  num = 600851475143;
  long long i, bigPrime = 0;
  for (i = 1; i < sqrt(num); i++) {
    if (num % i == 0 && isPrime(i) && i > bigPrime) {
      bigPrime = i;
      printf("maior: %lld\n", bigPrime);
    }
  }
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<max4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max4(int a, int b, int c, int d) {
  int ret;
  ret = 0;
  ret = (ret > a ? ret : a);
  ret = (ret > b ? ret : b);
  ret = (ret > c ? ret : c);
  ret = (ret > d ? ret : d);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<max4>:
  endbr64
  test   %ecx,%ecx
  mov    $0x0,%eax
  cmovs  %eax,%ecx
  cmp    %edx,%ecx
  cmovl  %edx,%ecx
  cmp    %esi,%ecx
  cmovl  %esi,%ecx
  cmp    %edi,%ecx
  mov    %edi,%eax
  cmovge %ecx,%eax
  ret
```

assistant: ```c
int max4(int a, int b, int c, int d) {
  int ret;
  ret = 0;
  ret = (ret > a ? ret : a);
  ret = (ret > b ? ret : b);
  ret = (ret > c ? ret : c);
  ret = (ret > d ? ret : d);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<max4>:
  endbr64
  xor    %eax,%eax
  test   %ecx,%ecx
  cmovs  %eax,%ecx
  mov    %edi,%eax
  cmp    %edx,%ecx
  cmovl  %edx,%ecx
  cmp    %esi,%ecx
  cmovl  %esi,%ecx
  cmp    %edi,%ecx
  cmovge %ecx,%eax
  ret
```

assistant: ```c
int max4(int a, int b, int c, int d) {
  int ret;
  ret = 0;
  ret = (ret > a ? ret : a);
  ret = (ret > b ? ret : b);
  ret = (ret > c ? ret : c);
  ret = (ret > d ? ret : d);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x64,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <loop1@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <loop2@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <loop3@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <loop4@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int n = 100;
  int sum = 0;
  loop1(sum, n);
  loop2(sum, n);
  loop3(sum, n);
  loop4(sum, n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <loop1@plt>
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <loop2@plt>
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <loop3@plt>
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <loop4@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int n = 100;
  int sum = 0;
  loop1(sum, n);
  loop2(sum, n);
  loop3(sum, n);
  loop4(sum, n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <loop1@plt>
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <loop2@plt>
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <loop3@plt>
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <loop4@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int n = 100;
  int sum = 0;
  loop1(sum, n);
  loop2(sum, n);
  loop3(sum, n);
  loop4(sum, n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <loop1@plt>
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <loop2@plt>
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <loop3@plt>
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <loop4@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int n = 100;
  int sum = 0;
  loop1(sum, n);
  loop2(sum, n);
  loop3(sum, n);
  loop4(sum, n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<constant_test_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x5,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int(constant_test_bit)(int nr, unsigned long const volatile *addr) {
  unsigned long const volatile *mem_3;
  {
    mem_3 = addr + (nr >> 5);
    return (((1UL << (nr & 31)) & (unsigned long)(*mem_3)) != 0UL);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<constant_test_bit>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  sar    $0x5,%eax
  cltq
  lea    (%rsi,%rax,8),%rax
  mov    (%rax),%rax
  and    $0x1f,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int(constant_test_bit)(int nr, unsigned long const volatile *addr) {
  unsigned long const volatile *mem_3;
  {
    mem_3 = addr + (nr >> 5);
    return (((1UL << (nr & 31)) & (unsigned long)(*mem_3)) != 0UL);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<constant_test_bit>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  sar    $0x5,%eax
  and    $0x1f,%ecx
  cltq
  lea    (%rsi,%rax,8),%rax
  mov    (%rax),%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int(constant_test_bit)(int nr, unsigned long const volatile *addr) {
  unsigned long const volatile *mem_3;
  {
    mem_3 = addr + (nr >> 5);
    return (((1UL << (nr & 31)) & (unsigned long)(*mem_3)) != 0UL);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<constant_test_bit>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  sar    $0x5,%eax
  and    $0x1f,%ecx
  cltq
  lea    (%rsi,%rax,8),%rax
  mov    (%rax),%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int(constant_test_bit)(int nr, unsigned long const volatile *addr) {
  unsigned long const volatile *mem_3;
  {
    mem_3 = addr + (nr >> 5);
    return (((1UL << (nr & 31)) & (unsigned long)(*mem_3)) != 0UL);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<malloc_char_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <message_exit@plt>
L13:
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L23:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <message_exit@plt>
L4:
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L23
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: char

assistant: ```c
unsigned char **malloc_char_image(int xres, int yres) {
  unsigned char **image;
  int j;
  image = (unsigned char **)malloc(sizeof(unsigned char *) * yres);
  if (image == NULL)
    message_exit("char");
  for (j = 0; j < yres; j++) {
    image[j] = (unsigned char *)malloc(sizeof(unsigned char) * xres);
    if (image[j] == NULL)
      message_exit("char");
  }
  return (image);
}
```
user: Translate the below assembly code into C programming language:

```asm
<malloc_char_image>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L52
L53:
  test   %r12d,%r12d
  jle    L65
  mov    %r13,%rbx
  mov    %r12d,%r12d
  lea    0x0(%r13,%r12,8),%r12
  lea    D16(%rip),%r14
  jmp    L27
L52:
  lea    D16(%rip),%rdi
  call   <message_exit@plt>
  jmp    L53
L58:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L65
L27:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L58
  mov    %r14,%rdi
  call   <message_exit@plt>
  jmp    L58
L65:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
data_type: string

tool: D16: char

assistant: ```c
unsigned char **malloc_char_image(int xres, int yres) {
  unsigned char **image;
  int j;
  image = (unsigned char **)malloc(sizeof(unsigned char *) * yres);
  if (image == NULL)
    message_exit("char");
  for (j = 0; j < yres; j++) {
    image[j] = (unsigned char *)malloc(sizeof(unsigned char) * xres);
    if (image[j] == NULL)
      message_exit("char");
  }
  return (image);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<malloc_char_image>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L67
L22:
  test   %ebp,%ebp
  jle    L60
  mov    %r12,%r14
  lea    (%r12,%rbp,8),%rbp
  lea    D16(%rip),%r13
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x8,%r14
  cmp    %rbp,%r14
  je     L60
L49:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L8
  mov    %r13,%rdi
  add    $0x8,%r14
  call   <message_exit@plt>
  cmp    %rbp,%r14
  jne    L49
L60:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L67:
  lea    D16(%rip),%rdi
  call   <message_exit@plt>
  jmp    L22
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type: string

tool: D16: char

assistant: ```c
unsigned char **malloc_char_image(int xres, int yres) {
  unsigned char **image;
  int j;
  image = (unsigned char **)malloc(sizeof(unsigned char *) * yres);
  if (image == NULL)
    message_exit("char");
  for (j = 0; j < yres; j++) {
    image[j] = (unsigned char *)malloc(sizeof(unsigned char) * xres);
    if (image[j] == NULL)
      message_exit("char");
  }
  return (image);
}
```
user: Translate the below assembly code into C programming language:

```asm
<malloc_char_image>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L62
L34:
  test   %ebp,%ebp
  jle    L21
  mov    %r12,%r14
  lea    (%r12,%rbp,8),%rbp
  lea    D0(%rip),%r13
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%r14
  cmp    %rbp,%r14
  je     L21
L42:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L7
  mov    %r13,%rdi
  add    $0x8,%r14
  call   <message_exit@plt>
  cmp    %rbp,%r14
  jne    L42
L21:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L62:
  lea    D0(%rip),%rdi
  call   <message_exit@plt>
  jmp    L34
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string

tool: D0: char

assistant: ```c
unsigned char **malloc_char_image(int xres, int yres) {
  unsigned char **image;
  int j;
  image = (unsigned char **)malloc(sizeof(unsigned char *) * yres);
  if (image == NULL)
    message_exit("char");
  for (j = 0; j < yres; j++) {
    image[j] = (unsigned char *)malloc(sizeof(unsigned char) * xres);
    if (image[j] == NULL)
      message_exit("char");
  }
  return (image);
}
```