ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<fd_file_size>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <lseek@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <lseek@plt>
  pop    %rbx
  ret
```

assistant: ```c
int64_t fd_file_size(int fd) {
  int64_t size;
  (void)lseek(fd, 0L, SEEK_SET);
  size = (lseek(fd, (off_t)0, SEEK_END));
  return (size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fd_file_size>:
  endbr64
  mov    D2(%rip),%rax
  push   %rbp
  xor    %esi,%esi
  mov    %edi,%ebp
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    D3(%rip),%rax
  mov    %ebp,%edi
  xor    %esi,%esi
  pop    %rbp
  mov    (%rax),%edx
  jmp    1050 <lseek@plt>
```

assistant: ```c
int64_t fd_file_size(int fd) {
  int64_t size;
  (void)lseek(fd, 0L, SEEK_SET);
  size = (lseek(fd, (off_t)0, SEEK_END));
  return (size);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fd_file_size>:
  endbr64
  mov    D9(%rip),%rax
  push   %rbp
  xor    %esi,%esi
  mov    %edi,%ebp
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    D13(%rip),%rax
  mov    %ebp,%edi
  xor    %esi,%esi
  pop    %rbp
  mov    (%rax),%edx
  jmp    1050 <lseek@plt>
```

assistant: ```c
int64_t fd_file_size(int fd) {
  int64_t size;
  (void)lseek(fd, 0L, SEEK_SET);
  size = (lseek(fd, (off_t)0, SEEK_END));
  return (size);
}
```
user: What is the c source code of the assembly code below?

```asm
<temp_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *temp_calloc(size_t nmemb, size_t size) {
  (void)nmemb;
  (void)size;
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<temp_calloc>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *temp_calloc(size_t nmemb, size_t size) {
  (void)nmemb;
  (void)size;
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<temp_calloc>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
void *temp_calloc(size_t nmemb, size_t size) {
  (void)nmemb;
  (void)size;
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<temp_calloc>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
void *temp_calloc(size_t nmemb, size_t size) {
  (void)nmemb;
  (void)size;
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L14
L75:
  movss  -0x64(%rbp),%xmm0
  mov    -0x68(%rbp),%eax
  lea    -0x60(%rbp),%rdx
  mov    %rdx,%rsi
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x68(%rbp),%xmm0
  comiss D40(%rip),%xmm0
  ja     L65
  jmp    L14
L65:
  movss  -0x68(%rbp),%xmm1
  movss  D32(%rip),%xmm0
  comiss %xmm1,%xmm0
  ja     L50
  jmp    L14
L50:
  movss  -0x64(%rbp),%xmm0
  comiss D15(%rip),%xmm0
  ja     L57
  jmp    L14
L57:
  movss  -0x64(%rbp),%xmm1
  movss  D50(%rip),%xmm0
  comiss %xmm1,%xmm0
  ja     L34
  jmp    L14
L34:
  movss  -0x64(%rbp),%xmm0
  mov    -0x68(%rbp),%eax
  lea    -0x60(%rbp),%rdx
  mov    %rdx,%rsi
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  lea    -0x60(%rbp),%rcx
  lea    -0x64(%rbp),%rdx
  lea    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  je     L75
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D40
type: byte[4]
name: unpack_data
arguments: label: D32
type: byte[4]
name: unpack_data
arguments: label: D15
type: byte[4]
name: unpack_data
arguments: label: D50
type: byte[4]
name: unpack_data
arguments: label: D33
type: string

tool: D22: %f,%f,%s


tool: {"D40": [0x00,0x00,0xd0,0x41]}

tool: {"D32": [0x00,0x00,0x08,0x42]}

tool: {"D15": [0x00,0x00,0x80,0xc2]}

tool: {"D50": [0x00,0x00,0x98,0xc2]}

tool: D33: %f,%f,%79[^
]

assistant: ```c
int main() {
  float lat, lng;
  char info[80];
  while (scanf("%f,%f,%79[^\n]", &lat, &lng, info) == 3) {
    printf("%f,%f,%s\n", lat, lng, info);
    if (lat > 26 && lat < 34) {
      if (lng > -64 && lng < -76) {
        printf("%f,%f,%s\n", lat, lng, info);
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rbx
  lea    D26(%rip),%rbp
L29:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L9
  lea    0x10(%rsp),%rsi
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  comiss D41(%rip),%xmm0
  jbe    L29
  movss  D50(%rip),%xmm2
  comiss %xmm0,%xmm2
  jbe    L29
  movss  0xc(%rsp),%xmm1
  comiss D15(%rip),%xmm1
  jbe    L29
  movss  D45(%rip),%xmm3
  comiss %xmm1,%xmm3
  jbe    L29
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L29
L9:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type: string
name: retrieve_data
arguments: label: D26
type: string
name: retrieve_data
arguments: label: D41
type: byte[4]
name: retrieve_data
arguments: label: D50
type: byte[4]
name: retrieve_data
arguments: label: D15
type: byte[4]
name: retrieve_data
arguments: label: D45
type: byte[4]

tool: D18: %f,%f,%79[^
]

tool: D26: %f,%f,%s


tool: {"D41": [0x00,0x00,0xd0,0x41]}

tool: {"D50": [0x00,0x00,0x08,0x42]}

tool: {"D15": [0x00,0x00,0x80,0xc2]}

tool: {"D45": [0x00,0x00,0x98,0xc2]}

assistant: ```c
int main() {
  float lat, lng;
  char info[80];
  while (scanf("%f,%f,%79[^\n]", &lat, &lng, info) == 3) {
    printf("%f,%f,%s\n", lat, lng, info);
    if (lat > 26 && lat < 34) {
      if (lng > -64 && lng < -76) {
        printf("%f,%f,%s\n", lat, lng, info);
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r12
  nopl   (%rax)
L69:
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L17
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  comiss D56(%rip),%xmm0
  jbe    L69
  movss  D12(%rip),%xmm2
  comiss %xmm0,%xmm2
  jbe    L69
  movss  0xc(%rsp),%xmm1
  comiss D50(%rip),%xmm1
  jbe    L69
  movss  D3(%rip),%xmm3
  comiss %xmm1,%xmm3
  jbe    L69
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L17:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
type: string
name: unpack_data
arguments: data_label: D18
type: string
name: unpack_data
arguments: data_label: D56
type: byte[4]
name: unpack_data
arguments: data_label: D12
type: byte[4]
name: unpack_data
arguments: data_label: D50
type: byte[4]
name: unpack_data
arguments: data_label: D3
type: byte[4]

tool: D21: %f,%f,%s


tool: D18: %f,%f,%79[^
]

tool: {"D56": [0x00,0x00,0xd0,0x41]}

tool: {"D12": [0x00,0x00,0x08,0x42]}

tool: {"D50": [0x00,0x00,0x80,0xc2]}

tool: {"D3": [0x00,0x00,0x98,0xc2]}

assistant: ```c
int main() {
  float lat, lng;
  char info[80];
  while (scanf("%f,%f,%79[^\n]", &lat, &lng, info) == 3) {
    printf("%f,%f,%s\n", lat, lng, info);
    if (lat > 26 && lat < 34) {
      if (lng > -64 && lng < -76) {
        printf("%f,%f,%s\n", lat, lng, info);
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r12
  nopl   (%rax)
L16:
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L1
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  comiss D21(%rip),%xmm0
  jbe    L16
  movss  D12(%rip),%xmm2
  comiss %xmm0,%xmm2
  jbe    L16
  movss  0xc(%rsp),%xmm1
  comiss D46(%rip),%xmm1
  jbe    L16
  movss  D36(%rip),%xmm3
  comiss %xmm1,%xmm3
  jbe    L16
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D21
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_label: D46
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_label: D36
type_guessed: byte[4]

tool: D2: %f,%f,%s


tool: D17: %f,%f,%79[^
]

tool: {"D21": [0x00,0x00,0xd0,0x41]}

tool: {"D12": [0x00,0x00,0x08,0x42]}

tool: {"D46": [0x00,0x00,0x80,0xc2]}

tool: {"D36": [0x00,0x00,0x98,0xc2]}

assistant: ```c
int main() {
  float lat, lng;
  char info[80];
  while (scanf("%f,%f,%79[^\n]", &lat, &lng, info) == 3) {
    printf("%f,%f,%s\n", lat, lng, info);
    if (lat > 26 && lat < 34) {
      if (lng > -64 && lng < -76) {
        printf("%f,%f,%s\n", lat, lng, info);
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mostFrequentChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x418(%rbp)
  jmp    L38
L51:
  mov    -0x418(%rbp),%eax
  cltq
  movl   $0x0,-0x410(%rbp,%rax,4)
  addl   $0x1,-0x418(%rbp)
L38:
  cmpl   $0xfe,-0x418(%rbp)
  jle    L51
  movb   $0x0,-0x419(%rbp)
  movl   $0x0,-0x414(%rbp)
  jmp    L10
L9:
  mov    -0x414(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x414(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%edx
  mov    -0x414(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x428(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x1,%edx
  cltq
  mov    %edx,-0x410(%rbp,%rax,4)
  mov    -0x414(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%edx
  movsbl -0x419(%rbp),%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L2
  mov    -0x414(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x419(%rbp)
L2:
  addl   $0x1,-0x414(%rbp)
L10:
  mov    -0x414(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  movzbl -0x419(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: %c

assistant: ```c
char mostFrequentChar(char *in) {
  int occurences[255];
  for (int i = 0; i < 255; i++)
    occurences[i] = 0;
  char mostfrequent = 0;
  int i = 0;
  while (in[i] != '\0') {
    printf("%c", in[i]);
    occurences[in[i]] += 1;
    if (occurences[in[i]] > occurences[mostfrequent])
      mostfrequent = in[i];
    i++;
  }
  return mostfrequent;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mostFrequentChar>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x3fc(%rsp),%rdx
L20:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L20
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L11
  mov    $0x0,%ebp
  lea    D0(%rip),%r12
L27:
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  movzbl (%rbx),%edx
  movsbq %dl,%rcx
  mov    (%rsp,%rcx,4),%eax
  add    $0x1,%eax
  mov    %eax,(%rsp,%rcx,4)
  movsbq %bpl,%rcx
  cmp    (%rsp,%rcx,4),%eax
  cmovg  %edx,%ebp
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L27
L14:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %ebp,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    %esi,%ebp
  jmp    L14
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: %c

assistant: ```c
char mostFrequentChar(char *in) {
  int occurences[255];
  for (int i = 0; i < 255; i++)
    occurences[i] = 0;
  char mostfrequent = 0;
  int i = 0;
  while (in[i] != '\0') {
    printf("%c", in[i]);
    occurences[in[i]] += 1;
    if (occurences[in[i]] > occurences[mostfrequent])
      mostfrequent = in[i];
    i++;
  }
  return mostfrequent;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mostFrequentChar>:
  endbr64
  push   %r12
  mov    $0x7f,%ecx
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x410,%rsp
  movsbl (%rbx),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  test   %sil,%sil
  je     L28
  lea    D4(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  call   <printf@plt>
  movsbq (%rbx),%rcx
  mov    (%rsp,%rcx,4),%eax
  mov    %rcx,%rdx
  add    $0x1,%eax
  mov    %eax,(%rsp,%rcx,4)
  movsbq %r12b,%rcx
  cmp    (%rsp,%rcx,4),%eax
  cmovg  %edx,%r12d
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  jne    L7
L28:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: %c

assistant: ```c
char mostFrequentChar(char *in) {
  int occurences[255];
  for (int i = 0; i < 255; i++)
    occurences[i] = 0;
  char mostfrequent = 0;
  int i = 0;
  while (in[i] != '\0') {
    printf("%c", in[i]);
    occurences[in[i]] += 1;
    if (occurences[in[i]] > occurences[mostfrequent])
      mostfrequent = in[i];
    i++;
  }
  return mostfrequent;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mostFrequentChar>:
  endbr64
  push   %r12
  mov    $0x7f,%ecx
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x410,%rsp
  movsbl (%rbx),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  test   %sil,%sil
  je     L11
  lea    D6(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rdi
  call   <printf@plt>
  movsbq (%rbx),%rcx
  mov    (%rsp,%rcx,4),%eax
  mov    %rcx,%rdx
  add    $0x1,%eax
  mov    %eax,(%rsp,%rcx,4)
  movsbq %r12b,%rcx
  cmp    (%rsp,%rcx,4),%eax
  cmovg  %edx,%r12d
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  jne    L27
L11:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: %c

assistant: ```c
char mostFrequentChar(char *in) {
  int occurences[255];
  for (int i = 0; i < 255; i++)
    occurences[i] = 0;
  char mostfrequent = 0;
  int i = 0;
  while (in[i] != '\0') {
    printf("%c", in[i]);
    occurences[in[i]] += 1;
    if (occurences[in[i]] > occurences[mostfrequent])
      mostfrequent = in[i];
    i++;
  }
  return mostfrequent;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x61000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0xc40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x61a90(%rbp),%rax
  mov    $0x61a80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x61c38(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x61c24(%rbp)
  movl   $0x0,-0x61c2c(%rbp)
  jmp    L37
L79:
  lea    -0x61c34(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x61c34(%rbp),%edx
  mov    -0x61c2c(%rbp),%eax
  cltq
  mov    %edx,-0x61c20(%rbp,%rax,4)
  lea    -0x61c30(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x61c28(%rbp)
  jmp    L29
L66:
  lea    -0x61c34(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x61c34(%rbp),%eax
  cltq
  movl   $0x1,-0x61a90(%rbp,%rax,4)
  addl   $0x1,-0x61c28(%rbp)
L29:
  mov    -0x61c30(%rbp),%eax
  cmp    %eax,-0x61c28(%rbp)
  jl     L66
  addl   $0x1,-0x61c2c(%rbp)
L37:
  mov    -0x61c38(%rbp),%eax
  cmp    %eax,-0x61c2c(%rbp)
  jl     L79
  movl   $0x0,-0x61c2c(%rbp)
  jmp    L82
L20:
  mov    -0x61c2c(%rbp),%eax
  cltq
  mov    -0x61c20(%rbp,%rax,4),%eax
  cltq
  movl   $0x0,-0x61a90(%rbp,%rax,4)
  addl   $0x1,-0x61c2c(%rbp)
L82:
  mov    -0x61c38(%rbp),%eax
  cmp    %eax,-0x61c2c(%rbp)
  jl     L20
  movl   $0x0,-0x61c2c(%rbp)
  jmp    L83
L96:
  mov    -0x61c2c(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L22
  addl   $0x1,-0x61c24(%rbp)
L22:
  addl   $0x1,-0x61c2c(%rbp)
L83:
  cmpl   $0x1869f,-0x61c2c(%rbp)
  jle    L96
  mov    -0x61c24(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D14: %d

tool: D11: %d


assistant: ```c
int main() {
  int n;
  int id, m;
  int a[100000] = {0};
  int b[100];
  scanf("%d", &n);
  int i, j, k;
  int count = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &id);
    b[i] = id;
    scanf("%d", &m);
    for (j = 0; j < m; j++) {
      scanf("%d", &id);
      a[id] = 1;
    }
  }
  for (i = 0; i < n; i++) {
    a[b[i]] = 0;
  }
  for (i = 0; i < 100000; i++) {
    if (a[i] == 1)
      count++;
  }
  printf("%d\n", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L21:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L21
  sub    $0xc30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61c28(%rsp)
  xor    %eax,%eax
  lea    0x1a0(%rsp),%rdi
  mov    $0x61a80,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L64
  mov    $0x0,%r12d
  lea    D18(%rip),%rbp
L62:
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,0x10(%rsp,%r12,4)
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L65
  mov    $0x0,%ebx
L50:
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  movl   $0x1,0x1a0(%rsp,%rax,4)
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L50
L65:
  mov    0x4(%rsp),%edx
  add    $0x1,%r12
  cmp    %r12d,%edx
  jg     L62
  test   %edx,%edx
  jle    L64
  lea    0x10(%rsp),%rax
  lea    -0x1(%rdx),%edx
  lea    0x14(%rsp,%rdx,4),%rcx
L79:
  movslq (%rax),%rdx
  movl   $0x0,0x1a0(%rsp,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L79
L64:
  lea    0x1a0(%rsp),%rax
  lea    0x61c20(%rsp),%rcx
  mov    $0x0,%esi
L54:
  cmpl   $0x1,(%rax)
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%esi
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L54
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x61c28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x61c30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D14
data_type: string

tool: D18: %d

tool: D14: %d


assistant: ```c
int main() {
  int n;
  int id, m;
  int a[100000] = {0};
  int b[100];
  scanf("%d", &n);
  int i, j, k;
  int count = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &id);
    b[i] = id;
    scanf("%d", &m);
    for (j = 0; j < m; j++) {
      scanf("%d", &id);
      a[id] = 1;
    }
  }
  for (i = 0; i < n; i++) {
    a[b[i]] = 0;
  }
  for (i = 0; i < 100000; i++) {
    if (a[i] == 1)
      count++;
  }
  printf("%d\n", count);
  return 0;
}
```