ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<show_options>:
  endbr64
  push   %r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  lea    D10(%rip),%rbx
  lea    0x50(%rbx),%r12
L7:
  mov    0x8(%rbx),%rdx
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x10,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
type_infered: string

tool: D15:   %-28s%s


assistant: ```c
void show_options(void) {
  static const struct {
    const char *name;
    const char *desc;
  } opts[] = {{"-a, --allow-root", "allow running command as root user"}, {"-u, --user=USERNAME", "run command as specified user name"}, {"-h, --help", "display this help and exit"}, {"-v, --version", "output version information and exit"}, {"--", "stop processing command line options"}};
  unsigned int i;
  for (i = 0; i < sizeof(opts) / sizeof(opts[0]); i++) {
    printf("  %-28s%s\n", opts[i].name, opts[i].desc);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x14,-0x4(%rbp)
  jg     L5
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <recurse>
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <recurse>
L5:
  nop
  leave
  ret
```

assistant: ```c
void recurse(const int depth) {
  if (depth < 21) {
#pragma omp task default(none) firstprivate(depth)
    { recurse(depth + 1); }
#pragma omp task default(none) firstprivate(depth)
    { recurse(depth + 1); }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<recurse>:
  endbr64
  cmp    $0x14,%edi
  jle    L2
  ret
L2:
  push   %rbx
  lea    0x1(%rdi),%ebx
  mov    %ebx,%edi
  call   <recurse>
  mov    %ebx,%edi
  call   <recurse>
  pop    %rbx
  ret
```

assistant: ```c
void recurse(const int depth) {
  if (depth < 21) {
#pragma omp task default(none) firstprivate(depth)
    { recurse(depth + 1); }
#pragma omp task default(none) firstprivate(depth)
    { recurse(depth + 1); }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<recurse>:
  endbr64
  cmp    $0x14,%edi
  jg     L22
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
L36:
  add    $0x1,%r13d
  cmp    $0x15,%r13d
  je     L4
  mov    %r13d,%eax
L0:
  add    $0x1,%eax
  cmp    $0x15,%eax
  je     L36
  mov    %eax,%edx
L83:
  add    $0x1,%edx
  cmp    $0x15,%edx
  je     L0
  mov    %edx,%ecx
L75:
  add    $0x1,%ecx
  cmp    $0x15,%ecx
  je     L83
  mov    %ecx,%ebx
L16:
  add    $0x1,%ebx
  cmp    $0x15,%ebx
  je     L75
  mov    %ebx,%r12d
L105:
  add    $0x1,%r12d
  cmp    $0x15,%r12d
  je     L16
  mov    %r12d,%r14d
L32:
  add    $0x1,%r14d
  cmp    $0x15,%r14d
  je     L105
  mov    %r14d,%ebp
L96:
  add    $0x1,%ebp
  cmp    $0x15,%ebp
  je     L32
  mov    %ebp,%r15d
L88:
  add    $0x1,%r15d
  mov    %ecx,0xc(%rsp)
  mov    %r15d,%edi
  mov    %edx,0x8(%rsp)
  mov    %eax,0x4(%rsp)
  call   <recurse>
  cmp    $0x15,%r15d
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%ecx
  jne    L88
  jmp    L96
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  ret
```

assistant: ```c
void recurse(const int depth) {
  if (depth < 21) {
#pragma omp task default(none) firstprivate(depth)
    { recurse(depth + 1); }
#pragma omp task default(none) firstprivate(depth)
    { recurse(depth + 1); }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<recurse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x14,%edi
  jg     L72
  mov    %edi,%r12d
  lea    0x1(%rdi),%esi
  je     L72
  add    $0x2,%r12d
L60:
  mov    %r12d,%eax
  cmp    $0x15,%r12d
  je     L38
L35:
  add    $0x1,%eax
  cmp    $0x15,%eax
  je     L38
  mov    %eax,%edx
L16:
  add    $0x1,%edx
  cmp    $0x15,%edx
  je     L35
  mov    %edx,%ecx
L88:
  add    $0x1,%ecx
  cmp    $0x15,%ecx
  je     L16
  mov    %ecx,%ebx
L2:
  add    $0x1,%ebx
  cmp    $0x15,%ebx
  je     L88
  mov    %ebx,%ebp
L120:
  add    $0x1,%ebp
  cmp    $0x15,%ebp
  je     L2
  mov    %ebp,%r14d
L17:
  lea    0x1(%r14),%r13d
  mov    %r13d,%r14d
  cmp    $0x15,%r13d
  je     L120
L100:
  mov    %r13d,%r15d
L95:
  add    $0x1,%r15d
  mov    %esi,0xc(%rsp)
  mov    %r15d,%edi
  mov    %eax,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %ecx,(%rsp)
  call   <recurse>
  cmp    $0x15,%r15d
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%esi
  jne    L95
  add    $0x1,%r13d
  cmp    $0x15,%r13d
  jne    L100
  jmp    L17
L38:
  add    $0x1,%esi
  add    $0x1,%r12d
  cmp    $0x15,%esi
  jne    L60
L72:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void recurse(const int depth) {
  if (depth < 21) {
#pragma omp task default(none) firstprivate(depth)
    { recurse(depth + 1); }
#pragma omp task default(none) firstprivate(depth)
    { recurse(depth + 1); }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_ibft_region>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long find_ibft_region(unsigned long *sizep) {
  *sizep = 0;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_ibft_region>:
  endbr64
  movq   $0x0,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long find_ibft_region(unsigned long *sizep) {
  *sizep = 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_ibft_region>:
  endbr64
  movq   $0x0,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long find_ibft_region(unsigned long *sizep) {
  *sizep = 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_ibft_region>:
  endbr64
  movq   $0x0,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long find_ibft_region(unsigned long *sizep) {
  *sizep = 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L16
L18:
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(char *str) {
  size_t len = 0;
  while (*str++ != '\0')
    len++;
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  mov    $0x0,%eax
L18:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L18
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(char *str) {
  size_t len = 0;
  while (*str++ != '\0')
    len++;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L2
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L10
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
size_t strlen(char *str) {
  size_t len = 0;
  while (*str++ != '\0')
    len++;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L15
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L3
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
size_t strlen(char *str) {
  size_t len = 0;
  while (*str++ != '\0')
    len++;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D23(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  test   %rax,%rax
  je     L1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D23(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  jmp    L5
L1:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fact>
  imul   %rbx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  lea    D23(%rip),%rdx
  mov    %rax,(%rcx,%rdx,1)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D23(%rip),%rax
  mov    (%rdx,%rax,1),%rax
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long long int fact(int n) {
  static long long int F[13] = {1, 1, 2};
  if (F[n])
    return F[n];
  return F[n] = (long long int)(n)*fact(n - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fact>:
  endbr64
  movslq %edi,%rdx
  lea    D11(%rip),%rax
  mov    (%rax,%rdx,8),%rax
  test   %rax,%rax
  je     L2
  ret
L2:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fact>
  movslq %ebx,%rbx
  imul   %rbx,%rax
  lea    D11(%rip),%rdx
  mov    %rax,(%rdx,%rbx,8)
  pop    %rbx
  ret
```

assistant: ```c
long long int fact(int n) {
  static long long int F[13] = {1, 1, 2};
  if (F[n])
    return F[n];
  return F[n] = (long long int)(n)*fact(n - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fact>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    D4(%rip),%rbx
  mov    (%rbx,%rbp,8),%rax
  test   %rax,%rax
  je     L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  lea    -0x1(%rdi),%r12d
  movslq %r12d,%r12
  mov    (%rbx,%r12,8),%rax
  test   %rax,%rax
  jne    L3
  lea    -0x2(%rdi),%r13d
  movslq %r13d,%r13
  mov    (%rbx,%r13,8),%rax
  test   %rax,%rax
  je     L2
L23:
  imul   %r12,%rax
  mov    %rax,(%rbx,%r12,8)
L3:
  imul   %rbp,%rax
  mov    %rax,(%rbx,%rbp,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L2:
  lea    -0x3(%rdi),%r14d
  movslq %r14d,%r14
  mov    (%rbx,%r14,8),%rax
  test   %rax,%rax
  jne    L5
  sub    $0x4,%edi
  call   <fact>
  imul   %r14,%rax
  mov    %rax,(%rbx,%r14,8)
L5:
  imul   %r13,%rax
  mov    %rax,(%rbx,%r13,8)
  jmp    L23
```

assistant: ```c
long long int fact(int n) {
  static long long int F[13] = {1, 1, 2};
  if (F[n])
    return F[n];
  return F[n] = (long long int)(n)*fact(n - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fact>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    D9(%rip),%rbx
  mov    (%rbx,%rbp,8),%rax
  test   %rax,%rax
  je     L33
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  lea    -0x1(%rdi),%r12d
  movslq %r12d,%r12
  mov    (%rbx,%r12,8),%rax
  test   %rax,%rax
  jne    L10
  lea    -0x2(%rdi),%r13d
  movslq %r13d,%r13
  mov    (%rbx,%r13,8),%rax
  test   %rax,%rax
  je     L15
L46:
  imul   %r12,%rax
  mov    %rax,(%rbx,%r12,8)
L10:
  imul   %rbp,%rax
  mov    %rax,(%rbx,%rbp,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L15:
  lea    -0x3(%rdi),%r14d
  movslq %r14d,%r14
  mov    (%rbx,%r14,8),%rax
  test   %rax,%rax
  jne    L36
  sub    $0x4,%edi
  call   <fact>
  imul   %r14,%rax
  mov    %rax,(%rbx,%r14,8)
L36:
  imul   %r13,%rax
  mov    %rax,(%rbx,%r13,8)
  jmp    L46
```

assistant: ```c
long long int fact(int n) {
  static long long int F[13] = {1, 1, 2};
  if (F[n])
    return F[n];
  return F[n] = (long long int)(n)*fact(n - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %eax,%eax
  je     L8
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L8:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string
name: extract_symbolic_data
arguments: label: D23
type: string
name: extract_symbolic_data
arguments: label: D18
type: string
name: extract_symbolic_data
arguments: label: D7
type: string

tool: D9: Enter a number:

tool: D23: %d

tool: D18: a=%d is a prime number

tool: D7: a=%d is not a prime number

assistant: ```c
void main() {
  int isPrime(int);
  int a;
  printf("Enter a number:\n");
  scanf("%d", &a);
  if (isPrime(a)) {
    printf("a=%d is a prime number", a);
  } else {
    printf("a=%d is not a prime number", a);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isPrime@plt>
  test   %eax,%eax
  je     L1
  mov    0x4(%rsp),%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L1:
  mov    0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L3
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string
name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D14: Enter a number:

tool: D15: %d

tool: D25: a=%d is a prime number

tool: D7: a=%d is not a prime number

assistant: ```c
void main() {
  int isPrime(int);
  int a;
  printf("Enter a number:\n");
  scanf("%d", &a);
  if (isPrime(a)) {
    printf("a=%d is a prime number", a);
  } else {
    printf("a=%d is not a prime number", a);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isPrime@plt>
  mov    0x4(%rsp),%esi
  test   %eax,%eax
  je     L24
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  ret
L24:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D33
type_infered: string
name: unpack_data
arguments: label: D5
type_infered: string
name: unpack_data
arguments: label: D19
type_infered: string

tool: D1: Enter a number:

tool: D33: %d

tool: D5: a=%d is a prime number

tool: D19: a=%d is not a prime number

assistant: ```c
void main() {
  int isPrime(int);
  int a;
  printf("Enter a number:\n");
  scanf("%d", &a);
  if (isPrime(a)) {
    printf("a=%d is a prime number", a);
  } else {
    printf("a=%d is not a prime number", a);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isPrime@plt>
  mov    0x4(%rsp),%esi
  test   %eax,%eax
  je     L1
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L1:
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L12
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D35
data_type: string
name: disassemble_data
arguments: data_label: D27
data_type: string

tool: D6: Enter a number:

tool: D29: %d

tool: D35: a=%d is a prime number

tool: D27: a=%d is not a prime number

assistant: ```c
void main() {
  int isPrime(int);
  int a;
  printf("Enter a number:\n");
  scanf("%d", &a);
  if (isPrime(a)) {
    printf("a=%d is a prime number", a);
  } else {
    printf("a=%d is not a prime number", a);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<badformat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <warnx@plt>
  mov    $0x0,%eax
  call   <usage@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3: illegal time format

assistant: ```c
void badformat(void) {
  warnx("illegal time format");
  usage();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<badformat>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <warnx@plt>
  mov    $0x0,%eax
  call   <usage@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: illegal time format

assistant: ```c
void badformat(void) {
  warnx("illegal time format");
  usage();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<badformat>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <warnx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <usage@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D9: illegal time format

assistant: ```c
void badformat(void) {
  warnx("illegal time format");
  usage();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<badformat>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <warnx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <usage@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: illegal time format

assistant: ```c
void badformat(void) {
  warnx("illegal time format");
  usage();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_letter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x60,-0x4(%rbp)
  jle    L12
  cmpb   $0x7a,-0x4(%rbp)
  jg     L12
  mov    $0x1,%eax
  jmp    L26
L12:
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
bool is_letter(char sym) {
  if (sym >= 'a' && sym <= 'z')
    return true;
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_letter>:
  endbr64
  sub    $0x61,%edi
  cmp    $0x19,%dil
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_letter(char sym) {
  if (sym >= 'a' && sym <= 'z')
    return true;
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_letter>:
  endbr64
  sub    $0x61,%edi
  xor    %eax,%eax
  cmp    $0x19,%dil
  setbe  %al
  ret
```

assistant: ```c
bool is_letter(char sym) {
  if (sym >= 'a' && sym <= 'z')
    return true;
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_letter>:
  endbr64
  sub    $0x61,%edi
  xor    %eax,%eax
  cmp    $0x19,%dil
  setbe  %al
  ret
```

assistant: ```c
bool is_letter(char sym) {
  if (sym >= 'a' && sym <= 'z')
    return true;
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sat_zextend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <sat_extend@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rcx
  imul   -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *sat_zextend(void *buf, size_t len, size_t nmemb, size_t size, size_t block) {
  buf = sat_extend(buf, len, nmemb, size, block);
  memset((char *)buf + len * size, 0, nmemb * size);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sat_zextend>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r13
  call   <sat_extend@plt>
  mov    %rax,%r12
  mov    %rbp,%rdx
  imul   %r13,%rdx
  imul   %r13,%rbx
  lea    (%rax,%rbx,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sat_zextend(void *buf, size_t len, size_t nmemb, size_t size, size_t block) {
  buf = sat_extend(buf, len, nmemb, size, block);
  memset((char *)buf + len * size, 0, nmemb * size);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sat_zextend>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  imul   %r12,%rbx
  sub    $0x8,%rsp
  call   <sat_extend@plt>
  mov    %rbp,%rdx
  xor    %esi,%esi
  imul   %r12,%rdx
  lea    (%rax,%rbx,1),%rdi
  mov    %rax,%r13
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sat_zextend(void *buf, size_t len, size_t nmemb, size_t size, size_t block) {
  buf = sat_extend(buf, len, nmemb, size, block);
  memset((char *)buf + len * size, 0, nmemb * size);
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L25
L16:
  movb   $0x41,-0x5(%rbp)
  jmp    L18
L30:
  movsbl -0x5(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzbl -0x5(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
L18:
  cmpb   $0x4a,-0x5(%rbp)
  jle    L30
  addl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0xa,-0x4(%rbp)
  jle    L16
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: %d%c%	

assistant: ```c
int main() {
  int x;
  char a;
  for (x = 1; x < 11; x++) {
    for (a = 'A'; a < 'A' + 10; a++)
      printf("%d%c%\t", x, a);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebp
  lea    D7(%rip),%r12
L6:
  mov    $0x41,%ebx
L10:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x4b,%ebx
  jne    L10
  add    $0x1,%ebp
  cmp    $0xb,%ebp
  jne    L6
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d%c%	

assistant: ```c
int main() {
  int x;
  char a;
  for (x = 1; x < 11; x++) {
    for (a = 'A'; a < 'A' + 10; a++)
      printf("%d%c%\t", x, a);
  }
  return 0;
}
```