user: 这段汇编代码用C语言表示是什么样的？

```asm
<splitline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L66
L21:
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <emalloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x34(%rbp)
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  cltq
  shr    $0x3,%rax
  mov    %eax,-0x38(%rbp)
  jmp    L16
L83:
  addq   $0x1,-0x20(%rbp)
L2:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L83
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L83
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L129
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x38(%rbp)
  jg     L35
  mov    D56(%rip),%rax
  mov    (%rax),%edx
  mov    -0x34(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <erealloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  add    %eax,-0x34(%rbp)
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  cltq
  shr    $0x3,%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x38(%rbp)
L35:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x1,-0x2c(%rbp)
  jmp    L41
L118:
  addl   $0x1,-0x2c(%rbp)
L41:
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L95
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L95
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L118
L95:
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <newstr@plt>
  mov    %rax,(%rbx)
L16:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  jmp    L109
L129:
  nop
L109:
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
L66:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
extern char **splitline(char *line) {
  char **arglist;
  int spots = 0;
  int bufspace = 0;
  int argnum = 0;
  char *cp = line;
  char *start;
  int len;
  if (line == NULL)
    return NULL;
  arglist = (char **)emalloc(BUFSIZ);
  bufspace = BUFSIZ;
  spots = BUFSIZ / sizeof(char *);
  while (*cp != '\0') {
    while (((*cp) == ' ' || (*cp) == '\t'))
      cp++;
    if (*cp == '\0')
      break;
    if (argnum + 1 >= spots) {
      arglist = (char **)erealloc(arglist, bufspace + BUFSIZ);
      bufspace += BUFSIZ;
      spots += BUFSIZ / sizeof(char *);
    }
    start = cp;
    len = 1;
    while (*++cp != '\0' && !(((*cp) == ' ' || (*cp) == '\t')))
      len++;
    arglist[argnum++] = newstr(start, len);
  }
  arglist[argnum] = NULL;
  return arglist;
}
```