ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<run_help>:
  endbr64
  sub    $0x8,%rsp
  call   <usage@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int run_help(int argc, char **argv, void *st_options) {
  struct st_options *o = st_options;
  usage(argc, argv, o);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<run_help>:
  endbr64
  sub    $0x8,%rsp
  call   <usage@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int run_help(int argc, char **argv, void *st_options) {
  struct st_options *o = st_options;
  usage(argc, argv, o);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0xc,%eax
  ja     L135
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D15(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D15(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x1f,-0xc(%rbp)
  jmp    L49
  movl   $0x1c,-0xc(%rbp)
  jmp    L49
  movl   $0x1f,-0xc(%rbp)
  jmp    L49
  movl   $0x1e,-0xc(%rbp)
  jmp    L49
  movl   $0x1f,-0xc(%rbp)
  jmp    L49
  movl   $0x1e,-0xc(%rbp)
  jmp    L49
  movl   $0x1f,-0xc(%rbp)
  jmp    L49
  movl   $0x1f,-0xc(%rbp)
  jmp    L49
  movl   $0x1e,-0xc(%rbp)
  jmp    L49
  movl   $0x1f,-0xc(%rbp)
  jmp    L49
  movl   $0x1e,-0xc(%rbp)
  jmp    L49
  movl   $0x1f,-0xc(%rbp)
  jmp    L49
L135:
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L49:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jle    L39
  mov    -0x10(%rbp),%eax
  cmp    $0xc,%eax
  jg     L39
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L39:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L99
  call   <__stack_chk_fail@plt>
L99:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D38
type: string
name: disassemble_data
arguments: tag: D41
type: string
name: disassemble_data
arguments: tag: D53
type: string
name: disassemble_data
arguments: tag: D20
type: string

tool: D38: Input a month: 

tool: D41: %d

tool: D53: wrong month

tool: D20: month %d has %d days

assistant: ```c
int main() {
  int month, days;
  printf("Input a month: ");
  scanf("%d", &month);
  switch (month) {
  case 1:
    days = 31;
    break;
  case 2:
    days = 28;
    break;
  case 3:
    days = 31;
    break;
  case 4:
    days = 30;
    break;
  case 5:
    days = 31;
    break;
  case 6:
    days = 30;
    break;
  case 7:
    days = 31;
    break;
  case 8:
    days = 31;
    break;
  case 9:
    days = 30;
    break;
  case 10:
    days = 31;
    break;
  case 11:
    days = 30;
    break;
  case 12:
    days = 31;
    break;
  default:
    printf("wrong month");
    break;
  }
  if (month >= 1 && month <= 12)
    printf("month %d has %d days", month, days);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  cmp    $0xc,%ecx
  ja     L73
  mov    $0x1,%eax
  shl    %cl,%rax
  test   $0x15aa,%eax
  je     L28
L57:
  mov    0x4(%rsp),%ecx
  lea    -0x1(%rcx),%eax
  cmp    $0xb,%eax
  jbe    L44
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L28:
  mov    $0x1e,%esi
  test   $0xa50,%eax
  je     L49
L70:
  mov    %esi,%edx
  mov    %ecx,%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L49:
  mov    $0x1c,%esi
  cmp    $0x2,%ecx
  je     L70
L73:
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L44:
  mov    $0x1f,%esi
  jmp    L70
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D31
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D29
type_guessed: string

tool: D13: Input a month: 

tool: D19: %d

tool: D31: month %d has %d days

tool: D29: wrong month

assistant: ```c
int main() {
  int month, days;
  printf("Input a month: ");
  scanf("%d", &month);
  switch (month) {
  case 1:
    days = 31;
    break;
  case 2:
    days = 28;
    break;
  case 3:
    days = 31;
    break;
  case 4:
    days = 30;
    break;
  case 5:
    days = 31;
    break;
  case 6:
    days = 30;
    break;
  case 7:
    days = 31;
    break;
  case 8:
    days = 31;
    break;
  case 9:
    days = 30;
    break;
  case 10:
    days = 31;
    break;
  case 11:
    days = 30;
    break;
  case 12:
    days = 31;
    break;
  default:
    printf("wrong month");
    break;
  }
  if (month >= 1 && month <= 12)
    printf("month %d has %d days", month, days);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L36
  lea    D49(%rip),%rdx
  mov    (%rdx,%rax,4),%r12d
L1:
  mov    %r12d,%edx
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L11
  jmp    L1
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D24
type_infered: string
name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D49
type_infered: string
name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string

tool: D24: Input a month: 

tool: D16: %d

tool: D49: 

tool: D8: month %d has %d days

tool: D13: wrong month

assistant: ```c
int main() {
  int month, days;
  printf("Input a month: ");
  scanf("%d", &month);
  switch (month) {
  case 1:
    days = 31;
    break;
  case 2:
    days = 28;
    break;
  case 3:
    days = 31;
    break;
  case 4:
    days = 30;
    break;
  case 5:
    days = 31;
    break;
  case 6:
    days = 30;
    break;
  case 7:
    days = 31;
    break;
  case 8:
    days = 31;
    break;
  case 9:
    days = 30;
    break;
  case 10:
    days = 31;
    break;
  case 11:
    days = 30;
    break;
  case 12:
    days = 31;
    break;
  default:
    printf("wrong month");
    break;
  }
  if (month >= 1 && month <= 12)
    printf("month %d has %d days", month, days);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D42(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L11
  lea    D37(%rip),%rdx
  mov    (%rdx,%rax,4),%r12d
L37:
  mov    %r12d,%edx
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L25
  jmp    L37
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D42
type_infered: string
name: read_data
arguments: tag: D29
type_infered: string
name: read_data
arguments: tag: D37
type_infered: string
name: read_data
arguments: tag: D17
type_infered: string
name: read_data
arguments: tag: D41
type_infered: string

tool: D42: Input a month: 

tool: D29: %d

tool: D37: 

tool: D17: month %d has %d days

tool: D41: wrong month

assistant: ```c
int main() {
  int month, days;
  printf("Input a month: ");
  scanf("%d", &month);
  switch (month) {
  case 1:
    days = 31;
    break;
  case 2:
    days = 28;
    break;
  case 3:
    days = 31;
    break;
  case 4:
    days = 30;
    break;
  case 5:
    days = 31;
    break;
  case 6:
    days = 30;
    break;
  case 7:
    days = 31;
    break;
  case 8:
    days = 31;
    break;
  case 9:
    days = 30;
    break;
  case 10:
    days = 31;
    break;
  case 11:
    days = 30;
    break;
  case 12:
    days = 31;
    break;
  default:
    printf("wrong month");
    break;
  }
  if (month >= 1 && month <= 12)
    printf("month %d has %d days", month, days);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <pintf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: Hello C!


assistant: ```c
int main() {
  pintf("Hello C!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <pintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Hello C!


assistant: ```c
int main() {
  pintf("Hello C!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <pintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: Hello C!


assistant: ```c
int main() {
  pintf("Hello C!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <pintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: Hello C!


assistant: ```c
int main() {
  pintf("Hello C!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L41
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,-0x10(%rbp)
  lea    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <strtol@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  je     L41
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  jne    L41
L16:
  mov    -0x38(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L21
L41:
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
int parse_num(str, key, valp)
char *str;
const char *key;
int *valp;
{
  char *p, *endp;
  int i;
  p = strstr(str, key);
  if (p != 0) {
    p += strlen(key);
    i = strtol(p, &endp, 10);
    if (endp != p && (*endp == 0 || *endp == ';')) {
      *valp = i;
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_num>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strstr@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L57
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <strtol@plt>
  mov    %eax,%edx
  mov    (%rsp),%rcx
  mov    $0x0,%eax
  cmp    %rbx,%rcx
  je     L57
  movzbl (%rcx),%ecx
  test   %cl,%cl
  je     L49
  cmp    $0x3b,%cl
  je     L49
L57:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  mov    %edx,(%r12)
  mov    $0x1,%eax
  jmp    L57
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_num(str, key, valp)
char *str;
const char *key;
int *valp;
{
  char *p, *endp;
  int i;
  p = strstr(str, key);
  if (p != 0) {
    p += strlen(key);
    i = strtol(p, &endp, 10);
    if (endp != p && (*endp == 0 || *endp == ';')) {
      *valp = i;
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_num>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strstr@plt>
  test   %rax,%rax
  je     L46
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    $0xa,%edx
  mov    %rsp,%rsi
  add    %rax,%rbx
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L46
  movzbl (%rdx),%edx
  test   %dl,%dl
  je     L8
  cmp    $0x3b,%dl
  je     L8
L46:
  xor    %eax,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    %eax,(%r12)
  mov    $0x1,%eax
  jmp    L19
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_num(str, key, valp)
char *str;
const char *key;
int *valp;
{
  char *p, *endp;
  int i;
  p = strstr(str, key);
  if (p != 0) {
    p += strlen(key);
    i = strtol(p, &endp, 10);
    if (endp != p && (*endp == 0 || *endp == ';')) {
      *valp = i;
      return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_num>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strstr@plt>
  test   %rax,%rax
  je     L28
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    $0xa,%edx
  mov    %rsp,%rsi
  add    %rax,%rbx
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L28
  movzbl (%rdx),%edx
  test   %dl,%dl
  je     L35
  cmp    $0x3b,%dl
  je     L35
L28:
  xor    %eax,%eax
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L35:
  mov    %eax,(%r12)
  mov    $0x1,%eax
  jmp    L41
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_num(str, key, valp)
char *str;
const char *key;
int *valp;
{
  char *p, *endp;
  int i;
  p = strstr(str, key);
  if (p != 0) {
    p += strlen(key);
    i = strtol(p, &endp, 10);
    if (endp != p && (*endp == 0 || *endp == ';')) {
      *valp = i;
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_lmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_lmatrix(long **m, long nrl, long nrh, long ncl, long nch) {
  free((char *)(m[nrl] + ncl - 0));
  free((char *)(m + nrl - 0));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_lmatrix>:
  endbr64
  push   %rbx
  lea    (%rdi,%rsi,8),%rbx
  mov    (%rbx),%rax
  lea    (%rax,%rcx,8),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void free_lmatrix(long **m, long nrl, long nrh, long ncl, long nch) {
  free((char *)(m[nrl] + ncl - 0));
  free((char *)(m + nrl - 0));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_lmatrix>:
  endbr64
  push   %rbp
  lea    (%rdi,%rsi,8),%rbp
  mov    0x0(%rbp),%rax
  lea    (%rax,%rcx,8),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_lmatrix(long **m, long nrl, long nrh, long ncl, long nch) {
  free((char *)(m[nrl] + ncl - 0));
  free((char *)(m + nrl - 0));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<free_lmatrix>:
  endbr64
  push   %rbp
  lea    (%rdi,%rsi,8),%rbp
  mov    0x0(%rbp),%rax
  lea    (%rax,%rcx,8),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_lmatrix(long **m, long nrl, long nrh, long ncl, long nch) {
  free((char *)(m[nrl] + ncl - 0));
  free((char *)(m + nrl - 0));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x34(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x38(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
L68:
  jmp    L43
L17:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L71
  nop
L43:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L17
  jmp    L56
L71:
  nop
L56:
  jmp    L51
L21:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L68
L51:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L21
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int f(int k, int l) {
  int *k_ref = alloca(sizeof(int));
  int *l_ref = alloca(sizeof(int));
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  *k_ref = k;
  *l_ref = l;
  *i = 0;
  *j = 0;
L1:
  while (*i < *k_ref) {
    (*i)++;
    if (*i % 2) {
      continue;
    }
    goto L2;
  }
L2:
  while (*j < 1) {
    (*j)++;
    if (*i % 2) {
      continue;
    }
    goto L1;
  }
  return *i + *j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %esi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%r13
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%rcx
  mov    %r15d,(%r12)
  mov    %r14d,0x0(%r13)
  movl   $0x0,(%rbx)
  movl   $0x0,(%rax)
  jmp    L55
L43:
  mov    (%rcx),%eax
  test   %eax,%eax
  jg     L31
  add    $0x1,%eax
  mov    %eax,(%rcx)
  testb  $0x1,(%rbx)
  jne    L43
L55:
  mov    (%rbx),%edx
  cmp    (%r12),%edx
  jge    L43
  add    $0x1,%edx
  mov    %edx,(%rbx)
  test   $0x1,%dl
  je     L43
  jmp    L55
L31:
  add    (%rbx),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f(int k, int l) {
  int *k_ref = alloca(sizeof(int));
  int *l_ref = alloca(sizeof(int));
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  *k_ref = k;
  *l_ref = l;
  *i = 0;
  *j = 0;
L1:
  while (*i < *k_ref) {
    (*i)++;
    if (*i % 2) {
      continue;
    }
    goto L2;
  }
L2:
  while (*j < 1) {
    (*j)++;
    if (*i % 2) {
      continue;
    }
    goto L1;
  }
  return *i + *j;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edi,%r15d
  mov    $0x4,%edi
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  mov    %r15d,(%r12)
  xor    %edx,%edx
  mov    %r14d,0x0(%r13)
  mov    %rax,%rcx
  movl   $0x0,(%rbx)
  movl   $0x0,(%rax)
  nopl   0x0(%rax)
L34:
  cmp    %edx,(%r12)
  jle    L30
  add    $0x1,%edx
  mov    %edx,(%rbx)
  test   $0x1,%dl
  jne    L34
L30:
  mov    (%rcx),%eax
  test   %eax,%eax
  jg     L5
L53:
  add    $0x1,%eax
  mov    %eax,(%rcx)
  mov    (%rbx),%edx
  test   $0x1,%dl
  je     L34
  test   %eax,%eax
  jle    L53
L5:
  add    (%rbx),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f(int k, int l) {
  int *k_ref = alloca(sizeof(int));
  int *l_ref = alloca(sizeof(int));
  int *i = alloca(sizeof(int));
  int *j = alloca(sizeof(int));
  *k_ref = k;
  *l_ref = l;
  *i = 0;
  *j = 0;
L1:
  while (*i < *k_ref) {
    (*i)++;
    if (*i % 2) {
      continue;
    }
    goto L2;
  }
L2:
  while (*j < 1) {
    (*j)++;
    if (*i % 2) {
      continue;
    }
    goto L1;
  }
  return *i + *j;
}
```