ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<Helper>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x5,%edx
  lea    0x28(%rsp),%rcx
  jmp    L9
L6:
  test   %edx,%edx
  je     L21
L9:
  mov    %rsp,%rax
L35:
  cmpq   $0x1,(%rax)
  adc    $0xffffffff,%edx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L35
  jmp    L6
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Helper() {
  const int *nodes[5];
  int num_active = 5;
  while (num_active)
#pragma clang loop unroll(full)
    for (int i = 0; i < 5; ++i)
      if (nodes[i])
        --num_active;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Helper>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x5,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x28(%rsp),%rcx
  nopl   (%rax)
L10:
  mov    %rsi,%rax
L0:
  cmpq   $0x1,(%rax)
  adc    $0xffffffff,%edx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L0
  test   %edx,%edx
  jne    L10
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x38,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Helper() {
  const int *nodes[5];
  int num_active = 5;
  while (num_active)
#pragma clang loop unroll(full)
    for (int i = 0; i < 5; ++i)
      if (nodes[i])
        --num_active;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Helper>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%rdx
  mov    0x8(%rsp),%r8
  mov    $0x5,%eax
  mov    0x10(%rsp),%rdi
  mov    0x18(%rsp),%rcx
  mov    0x20(%rsp),%rsi
  jmp    L119
  nopw   0x0(%rax,%rax,1)
L355:
  test   %rcx,%rcx
  je     L258
  test   %rdi,%rdi
  je     L90
  test   %r8,%r8
  je     L198
  test   %eax,%eax
  je     L349
  cmp    $0x1,%rdx
  adc    $0xfffffffc,%eax
L189:
  sub    $0x1,%eax
L119:
  test   %rsi,%rsi
  jne    L355
  test   %rcx,%rcx
  je     L149
  test   %rdi,%rdi
  je     L47
  test   %r8,%r8
  je     L81
  test   %eax,%eax
  je     L349
L407:
  cmp    $0x1,%rdx
  adc    $0xfffffffc,%eax
  test   %eax,%eax
  jne    L407
  nopl   0x0(%rax)
L349:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L125
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L258:
  test   %rdi,%rdi
  je     L417
L90:
  test   %r8,%r8
  je     L260
L198:
  test   %eax,%eax
  je     L349
  cmp    $0x1,%rdx
  adc    $0xfffffffd,%eax
  jmp    L189
L417:
  test   %r8,%r8
  je     L399
L260:
  test   %eax,%eax
  je     L349
  cmp    $0x1,%rdx
  adc    $0xffffffff,%eax
  sub    $0x1,%eax
  jmp    L189
  nopl   0x0(%rax,%rax,1)
L149:
  test   %rdi,%rdi
  je     L76
  test   %r8,%r8
  je     L78
  test   %eax,%eax
  je     L349
L166:
  cmp    $0x1,%rdx
  adc    $0xfffffffd,%eax
  test   %eax,%eax
  jne    L166
  jmp    L349
  nopw   0x0(%rax,%rax,1)
L47:
  test   %r8,%r8
  je     L73
  test   %eax,%eax
  je     L349
L37:
  cmp    $0x1,%rdx
  adc    $0xfffffffd,%eax
  test   %eax,%eax
  jne    L37
  jmp    L349
L81:
  test   %eax,%eax
  je     L349
L334:
  cmp    $0x1,%rdx
  adc    $0xfffffffd,%eax
  test   %eax,%eax
  jne    L334
  jmp    L349
L76:
  test   %r8,%r8
  je     L386
  test   %eax,%eax
  je     L349
L380:
  cmp    $0x1,%rdx
  adc    $0xffffffff,%eax
  sub    $0x1,%eax
  jne    L380
  jmp    L349
  nopw   0x0(%rax,%rax,1)
L399:
  test   %eax,%eax
  je     L349
  cmp    $0x1,%rdx
  adc    $0xffffffff,%eax
  jmp    L189
L354:
  sub    $0x1,%eax
L386:
  test   %eax,%eax
  je     L349
  test   %rdx,%rdx
  jne    L354
L324:
  jmp    L324
  cs nopw 0x0(%rax,%rax,1)
L78:
  test   %eax,%eax
  je     L349
L123:
  cmp    $0x1,%rdx
  adc    $0xffffffff,%eax
  sub    $0x1,%eax
  jne    L123
  jmp    L349
L73:
  test   %eax,%eax
  je     L349
L319:
  cmp    $0x1,%rdx
  adc    $0xffffffff,%eax
  sub    $0x1,%eax
  jne    L319
  jmp    L349
L125:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Helper() {
  const int *nodes[5];
  int num_active = 5;
  while (num_active)
#pragma clang loop unroll(full)
    for (int i = 0; i < 5; ++i)
      if (nodes[i])
        --num_active;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hex_char_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L16
  cmpb   $0x39,-0x4(%rbp)
  jg     L16
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L57
L16:
  cmpb   $0x60,-0x4(%rbp)
  jle    L48
  cmpb   $0x66,-0x4(%rbp)
  jg     L48
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L57
L48:
  mov    $0xffffffff,%eax
L57:
  pop    %rbp
  ret
```

assistant: ```c
int hex_char_to_int(char c) {
  if ('0' <= c && c <= '9')
    return c - '0';
  if ('a' <= c && c <= 'f')
    return c - 'a' + 10;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex_char_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L4
  lea    -0x61(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x57,%eax
  cmp    $0x6,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L4:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
```

assistant: ```c
int hex_char_to_int(char c) {
  if ('0' <= c && c <= '9')
    return c - '0';
  if ('a' <= c && c <= 'f')
    return c - 'a' + 10;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hex_char_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L3
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L3:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hex_char_to_int(char c) {
  if ('0' <= c && c <= '9')
    return c - '0';
  if ('a' <= c && c <= 'f')
    return c - 'a' + 10;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<hex_char_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L5
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L5:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hex_char_to_int(char c) {
  if ('0' <= c && c <= '9')
    return c - '0';
  if ('a' <= c && c <= 'f')
    return c - 'a' + 10;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_lseek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _lseek(int file, int ptr, int dir) {
  (void)(file);
  (void)(ptr);
  (void)(dir);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_lseek>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int _lseek(int file, int ptr, int dir) {
  (void)(file);
  (void)(ptr);
  (void)(dir);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_lseek>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int _lseek(int file, int ptr, int dir) {
  (void)(file);
  (void)(ptr);
  (void)(dir);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_lseek>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int _lseek(int file, int ptr, int dir) {
  (void)(file);
  (void)(ptr);
  (void)(dir);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_d2f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float test_d2f(double d) {
  float f;
  f = d;
  return f;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_d2f>:
  endbr64
  cvtsd2ss %xmm0,%xmm0
  ret
```

assistant: ```c
float test_d2f(double d) {
  float f;
  f = d;
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_d2f>:
  endbr64
  cvtsd2ss %xmm0,%xmm0
  ret
```

assistant: ```c
float test_d2f(double d) {
  float f;
  f = d;
  return f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_d2f>:
  endbr64
  cvtsd2ss %xmm0,%xmm0
  ret
```

assistant: ```c
float test_d2f(double d) {
  float f;
  f = d;
  return f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <DoStuff@plt>
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <DoSum@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: 2 + 1 = %d

assistant: ```c
int main() {
  DoStuff();
  printf("2 + 1 = %d", DoSum(2, 1));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <DoStuff@plt>
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <DoSum@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: 2 + 1 = %d

assistant: ```c
int main() {
  DoStuff();
  printf("2 + 1 = %d", DoSum(2, 1));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <DoStuff@plt>
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <DoSum@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: 2 + 1 = %d

assistant: ```c
int main() {
  DoStuff();
  printf("2 + 1 = %d", DoSum(2, 1));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <DoStuff@plt>
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <DoSum@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: 2 + 1 = %d

assistant: ```c
int main() {
  DoStuff();
  printf("2 + 1 = %d", DoSum(2, 1));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getUShort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xa(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cpy@plt>
  movzwl -0xa(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned short getUShort(void *data) {
  unsigned short v;
  cpy(&v, data, sizeof(unsigned short));
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getUShort>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  mov    $0x2,%edx
  call   <cpy@plt>
  movzwl 0x6(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short getUShort(void *data) {
  unsigned short v;
  cpy(&v, data, sizeof(unsigned short));
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getUShort>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <cpy@plt>
  movzwl 0x6(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short getUShort(void *data) {
  unsigned short v;
  cpy(&v, data, sizeof(unsigned short));
  return v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getUShort>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <cpy@plt>
  movzwl 0x6(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short getUShort(void *data) {
  unsigned short v;
  cpy(&v, data, sizeof(unsigned short));
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nohtml>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L41
L59:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  jne    L49
  mov    -0x4(%rbp),%eax
  cltq
  lea    D31(%rip),%rdx
  add    %rdx,%rax
  lea    D48(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addl   $0x4,-0x4(%rbp)
  jmp    L53
L49:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L64
  mov    -0x4(%rbp),%eax
  cltq
  lea    D31(%rip),%rdx
  add    %rdx,%rax
  lea    D40(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addl   $0x4,-0x4(%rbp)
  jmp    L53
L64:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    D31(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
  addl   $0x1,-0x4(%rbp)
L53:
  addq   $0x1,-0x18(%rbp)
L41:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L50
  mov    -0x4(%rbp),%eax
  cmp    $0x137d,%eax
  jbe    L59
L50:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D31(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D31(%rip),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D48
data_type: string
name: unpack_data
arguments: data_label: D40
data_type: string

tool: D48: &lt;

tool: D40: &gt;

assistant: ```c
char *nohtml(char *s) {
  static char buf[5000];
  int i = 0;
  while (*s && i < sizeof(buf) - 10) {
    if (*s == '<') {
      strcpy(buf + i, "&lt;");
      i += 4;
    } else if (*s == '>') {
      strcpy(buf + i, "&gt;");
      i += 4;
    } else {
      buf[i] = *s;
      i++;
    }
    s++;
  }
  buf[i] = 0;
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nohtml>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L71
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
  lea    D30(%rip),%r14
  lea    D35(%rip),%r13
  jmp    L29
L58:
  movslq %ebx,%rdi
  add    %r12,%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  add    $0x4,%ebx
L1:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L69
  cmp    $0x137d,%ebx
  ja     L69
L29:
  cmp    $0x3c,%al
  je     L58
  cmp    $0x3e,%al
  je     L22
  movslq %ebx,%rdx
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%ebx
  jmp    L1
L22:
  movslq %ebx,%rdi
  add    %r12,%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  add    $0x4,%ebx
  jmp    L1
L71:
  mov    $0x0,%ebx
L69:
  lea    D5(%rip),%rax
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D30
type_guessed: string
name: unpack_data
arguments: data_label: D35
type_guessed: string

tool: D30: &gt;

tool: D35: &lt;

assistant: ```c
char *nohtml(char *s) {
  static char buf[5000];
  int i = 0;
  while (*s && i < sizeof(buf) - 10) {
    if (*s == '<') {
      strcpy(buf + i, "&lt;");
      i += 4;
    } else if (*s == '>') {
      strcpy(buf + i, "&gt;");
      i += 4;
    } else {
      buf[i] = *s;
      i++;
    }
    s++;
  }
  buf[i] = 0;
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nohtml>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L89
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  lea    D20(%rip),%r12
  lea    D17(%rip),%r14
  lea    D27(%rip),%r13
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L36:
  cmp    $0x3e,%al
  je     L40
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %al,(%r12,%rdx,1)
L29:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  cmp    $0x137d,%ebx
  jg     L52
L81:
  test   %al,%al
  je     L52
L47:
  cmp    $0x3c,%al
  jne    L36
  movslq %ebx,%rdi
  mov    %r13,%rsi
  add    $0x1,%rbp
  add    $0x4,%ebx
  add    %r12,%rdi
  call   <strcpy@plt>
  movzbl 0x0(%rbp),%eax
  cmp    $0x137d,%ebx
  jle    L81
L52:
  movslq %ebx,%rbx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  movslq %ebx,%rdi
  mov    %r14,%rsi
  add    $0x4,%ebx
  add    %r12,%rdi
  call   <strcpy@plt>
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L89:
  xor    %ebx,%ebx
  lea    D20(%rip),%r12
  jmp    L52
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
datatype: string
name: extract_symbolic_data
arguments: label: D27
datatype: string

tool: D17: &gt;

tool: D27: &lt;

assistant: ```c
char *nohtml(char *s) {
  static char buf[5000];
  int i = 0;
  while (*s && i < sizeof(buf) - 10) {
    if (*s == '<') {
      strcpy(buf + i, "&lt;");
      i += 4;
    } else if (*s == '>') {
      strcpy(buf + i, "&gt;");
      i += 4;
    } else {
      buf[i] = *s;
      i++;
    }
    s++;
  }
  buf[i] = 0;
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nohtml>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  lea    D6(%rip),%r12
  lea    D25(%rip),%r14
  lea    D17(%rip),%r13
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L56:
  cmp    $0x3e,%al
  je     L47
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %al,(%r12,%rdx,1)
L72:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  cmp    $0x137d,%ebx
  jg     L37
L22:
  test   %al,%al
  je     L37
L12:
  cmp    $0x3c,%al
  jne    L56
  movslq %ebx,%rdi
  mov    %r13,%rsi
  add    $0x1,%rbp
  add    $0x4,%ebx
  add    %r12,%rdi
  call   <strcpy@plt>
  movzbl 0x0(%rbp),%eax
  cmp    $0x137d,%ebx
  jle    L22
L37:
  movslq %ebx,%rbx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  movslq %ebx,%rdi
  mov    %r14,%rsi
  add    $0x4,%ebx
  add    %r12,%rdi
  call   <strcpy@plt>
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %ebx,%ebx
  lea    D6(%rip),%r12
  jmp    L37
```

tool_calls: name: parse_data
arguments: data_tag: D25
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string

tool: D25: &gt;

tool: D17: &lt;

assistant: ```c
char *nohtml(char *s) {
  static char buf[5000];
  int i = 0;
  while (*s && i < sizeof(buf) - 10) {
    if (*s == '<') {
      strcpy(buf + i, "&lt;");
      i += 4;
    } else if (*s == '>') {
      strcpy(buf + i, "&gt;");
      i += 4;
    } else {
      buf[i] = *s;
      i++;
    }
    s++;
  }
  buf[i] = 0;
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dict_int_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int dict_int_cmp(const void *k1, const void *k2) {
  const int a = *(const int *)k1;
  const int b = *(const int *)k2;
  return (a > b) - (a < b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dict_int_cmp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setg   %al
  movzbl %al,%eax
  setl   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int dict_int_cmp(const void *k1, const void *k2) {
  const int a = *(const int *)k1;
  const int b = *(const int *)k2;
  return (a > b) - (a < b);
}
```
user: What is the c source code of the assembly code below?

```asm
<dict_int_cmp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setg   %al
  setl   %dl
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int dict_int_cmp(const void *k1, const void *k2) {
  const int a = *(const int *)k1;
  const int b = *(const int *)k2;
  return (a > b) - (a < b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dict_int_cmp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setg   %al
  setl   %dl
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int dict_int_cmp(const void *k1, const void *k2) {
  const int a = *(const int *)k1;
  const int b = *(const int *)k2;
  return (a > b) - (a < b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<psvec3_clamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vec3_clamp@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_clamp(struct vec3 *result, struct vec3 *a, struct vec3 *lower, struct vec3 *higher) {
  vec3_clamp((float *)result, (float *)a, (float *)lower, (float *)higher);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<psvec3_clamp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec3_clamp@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_clamp(struct vec3 *result, struct vec3 *a, struct vec3 *lower, struct vec3 *higher) {
  vec3_clamp((float *)result, (float *)a, (float *)lower, (float *)higher);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<psvec3_clamp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec3_clamp@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_clamp(struct vec3 *result, struct vec3 *a, struct vec3 *lower, struct vec3 *higher) {
  vec3_clamp((float *)result, (float *)a, (float *)lower, (float *)higher);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<psvec3_clamp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec3_clamp@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_clamp(struct vec3 *result, struct vec3 *a, struct vec3 *lower, struct vec3 *higher) {
  vec3_clamp((float *)result, (float *)a, (float *)lower, (float *)higher);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  nop
L0:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L0
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strchr(char *str, int c) {
  int i;
  i = -1;
  while (*(str + (++i)) && *(str + i) != c) {
  }
  return (str + i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strchr>:
  endbr64
L3:
  mov    %rdi,%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  add    $0x1,%rdi
  movsbl %al,%eax
  cmp    %esi,%eax
  jne    L3
L10:
  mov    %rdx,%rax
  ret
```

assistant: ```c
char *ft_strchr(char *str, int c) {
  int i;
  i = -1;
  while (*(str + (++i)) && *(str + i) != c) {
  }
  return (str + i);
}
```