ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<MonthFromTime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  call   <DayWithinYear@plt>
  mov    %eax,%ebx
  movq   %rbp,%xmm0
  call   <InLeapYear@plt>
  mov    $0x0,%edx
  cmp    $0x1e,%ebx
  jle    L39
  lea    0x3a(%rax),%ecx
  mov    $0x1,%edx
  cmp    %ebx,%ecx
  jge    L39
  lea    0x59(%rax),%ecx
  mov    $0x2,%edx
  cmp    %ebx,%ecx
  jge    L39
  lea    0x77(%rax),%ecx
  mov    $0x3,%edx
  cmp    %ebx,%ecx
  jge    L39
  lea    0x96(%rax),%ecx
  mov    $0x4,%edx
  cmp    %ebx,%ecx
  jge    L39
  lea    0xb4(%rax),%ecx
  mov    $0x5,%edx
  cmp    %ebx,%ecx
  jge    L39
  lea    0xd3(%rax),%ecx
  mov    $0x6,%edx
  cmp    %ebx,%ecx
  jge    L39
  lea    0xf2(%rax),%ecx
  mov    $0x7,%edx
  cmp    %ebx,%ecx
  jge    L39
  lea    0x110(%rax),%ecx
  mov    $0x8,%edx
  cmp    %ebx,%ecx
  jge    L39
  lea    0x12f(%rax),%ecx
  mov    $0x9,%edx
  cmp    %ebx,%ecx
  jge    L39
  add    $0x14d,%eax
  cmp    %ebx,%eax
  setl   %dl
  movzbl %dl,%edx
  add    $0xa,%edx
L39:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int MonthFromTime(double t) {
  int day = DayWithinYear(t);
  int leap = InLeapYear(t);
  if (day < 31)
    return 0;
  if (day < 59 + leap)
    return 1;
  if (day < 90 + leap)
    return 2;
  if (day < 120 + leap)
    return 3;
  if (day < 151 + leap)
    return 4;
  if (day < 181 + leap)
    return 5;
  if (day < 212 + leap)
    return 6;
  if (day < 243 + leap)
    return 7;
  if (day < 273 + leap)
    return 8;
  if (day < 304 + leap)
    return 9;
  if (day < 334 + leap)
    return 10;
  return 11;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MonthFromTime>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <DayWithinYear@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  call   <InLeapYear@plt>
  xor    %r8d,%r8d
  cmp    $0x1e,%ebx
  jle    L46
  lea    0x3a(%rax),%edx
  mov    $0x1,%r8d
  cmp    %ebx,%edx
  jge    L46
  lea    0x59(%rax),%edx
  mov    $0x2,%r8d
  cmp    %ebx,%edx
  jge    L46
  lea    0x77(%rax),%edx
  mov    $0x3,%r8d
  cmp    %ebx,%edx
  jge    L46
  lea    0x96(%rax),%edx
  mov    $0x4,%r8d
  cmp    %ebx,%edx
  jge    L46
  lea    0xb4(%rax),%edx
  mov    $0x5,%r8d
  cmp    %ebx,%edx
  jge    L46
  lea    0xd3(%rax),%edx
  mov    $0x6,%r8d
  cmp    %ebx,%edx
  jge    L46
  lea    0xf2(%rax),%edx
  mov    $0x7,%r8d
  cmp    %ebx,%edx
  jge    L46
  lea    0x110(%rax),%edx
  mov    $0x8,%r8d
  cmp    %ebx,%edx
  jge    L46
  lea    0x12f(%rax),%edx
  mov    $0x9,%r8d
  cmp    %ebx,%edx
  jge    L46
  add    $0x14d,%eax
  xor    %r8d,%r8d
  cmp    %ebx,%eax
  setl   %r8b
  add    $0xa,%r8d
L46:
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
int MonthFromTime(double t) {
  int day = DayWithinYear(t);
  int leap = InLeapYear(t);
  if (day < 31)
    return 0;
  if (day < 59 + leap)
    return 1;
  if (day < 90 + leap)
    return 2;
  if (day < 120 + leap)
    return 3;
  if (day < 151 + leap)
    return 4;
  if (day < 181 + leap)
    return 5;
  if (day < 212 + leap)
    return 6;
  if (day < 243 + leap)
    return 7;
  if (day < 273 + leap)
    return 8;
  if (day < 304 + leap)
    return 9;
  if (day < 334 + leap)
    return 10;
  return 11;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<MonthFromTime>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <DayWithinYear@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  call   <InLeapYear@plt>
  xor    %r8d,%r8d
  cmp    $0x1e,%ebx
  jle    L41
  lea    0x3a(%rax),%edx
  mov    $0x1,%r8d
  cmp    %ebx,%edx
  jge    L41
  lea    0x59(%rax),%edx
  mov    $0x2,%r8d
  cmp    %ebx,%edx
  jge    L41
  lea    0x77(%rax),%edx
  mov    $0x3,%r8d
  cmp    %ebx,%edx
  jge    L41
  lea    0x96(%rax),%edx
  mov    $0x4,%r8d
  cmp    %ebx,%edx
  jge    L41
  lea    0xb4(%rax),%edx
  mov    $0x5,%r8d
  cmp    %ebx,%edx
  jge    L41
  lea    0xd3(%rax),%edx
  mov    $0x6,%r8d
  cmp    %ebx,%edx
  jge    L41
  lea    0xf2(%rax),%edx
  mov    $0x7,%r8d
  cmp    %ebx,%edx
  jge    L41
  lea    0x110(%rax),%edx
  mov    $0x8,%r8d
  cmp    %ebx,%edx
  jge    L41
  lea    0x12f(%rax),%edx
  mov    $0x9,%r8d
  cmp    %ebx,%edx
  jge    L41
  add    $0x14d,%eax
  xor    %r8d,%r8d
  cmp    %ebx,%eax
  setl   %r8b
  add    $0xa,%r8d
L41:
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
int MonthFromTime(double t) {
  int day = DayWithinYear(t);
  int leap = InLeapYear(t);
  if (day < 31)
    return 0;
  if (day < 59 + leap)
    return 1;
  if (day < 90 + leap)
    return 2;
  if (day < 120 + leap)
    return 3;
  if (day < 151 + leap)
    return 4;
  if (day < 181 + leap)
    return 5;
  if (day < 212 + leap)
    return 6;
  if (day < 243 + leap)
    return 7;
  if (day < 273 + leap)
    return 8;
  if (day < 304 + leap)
    return 9;
  if (day < 334 + leap)
    return 10;
  return 11;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<file_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L20
  mov    $0x1,%eax
  jmp    L1
L20:
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int file_exists(char *filename) {
  struct stat buffer;
  if (stat(filename, &buffer) == 0)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(char *filename) {
  struct stat buffer;
  if (stat(filename, &buffer) == 0)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(char *filename) {
  struct stat buffer;
  if (stat(filename, &buffer) == 0)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(char *filename) {
  struct stat buffer;
  if (stat(filename, &buffer) == 0)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mfill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L9:
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L6:
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L6
  mov    -0x24(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mfill(double alpha, double *A, int ALda, int Ai, int Aj, int m, int n) {
  int i, j;
  int offsetA = Aj * ALda + Ai;
  for (j = 0; j < n; ++j) {
    for (i = 0; i < m; ++i) {
      A[offsetA + i] = alpha;
    }
    offsetA += ALda;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mfill>:
  endbr64
  mov    %rdi,%rax
  imul   %esi,%ecx
  add    %edx,%ecx
  test   %r9d,%r9d
  jle    L24
  movslq %esi,%rsi
  shl    $0x3,%rsi
  lea    -0x1(%r8),%edi
  movslq %ecx,%rcx
  lea    (%rcx,%rdi,1),%rdx
  lea    0x8(%rax,%rdx,8),%rdx
  mov    $0x0,%ecx
  not    %rdi
  shl    $0x3,%rdi
  jmp    L42
L35:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L35
L47:
  add    $0x1,%ecx
  add    %rsi,%rdx
  cmp    %ecx,%r9d
  je     L24
L42:
  lea    (%rdi,%rdx,1),%rax
  test   %r8d,%r8d
  jg     L35
  jmp    L47
L24:
  ret
```

assistant: ```c
void mfill(double alpha, double *A, int ALda, int Ai, int Aj, int m, int n) {
  int i, j;
  int offsetA = Aj * ALda + Ai;
  for (j = 0; j < n; ++j) {
    for (i = 0; i < m; ++i) {
      A[offsetA + i] = alpha;
    }
    offsetA += ALda;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mfill>:
  endbr64
  imul   %esi,%ecx
  mov    %rdi,%rax
  add    %edx,%ecx
  test   %r9d,%r9d
  jle    L13
  lea    -0x1(%r8),%edi
  movslq %ecx,%rcx
  movslq %esi,%rsi
  lea    (%rcx,%rdi,1),%rdx
  not    %rdi
  shl    $0x3,%rsi
  xor    %ecx,%ecx
  lea    0x8(%rax,%rdx,8),%rdx
  shl    $0x3,%rdi
  nopl   0x0(%rax)
L19:
  lea    (%rdi,%rdx,1),%rax
  test   %r8d,%r8d
  jle    L5
  nopl   0x0(%rax)
L34:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L34
L5:
  add    $0x1,%ecx
  add    %rsi,%rdx
  cmp    %ecx,%r9d
  jne    L19
L13:
  ret
```

assistant: ```c
void mfill(double alpha, double *A, int ALda, int Ai, int Aj, int m, int n) {
  int i, j;
  int offsetA = Aj * ALda + Ai;
  for (j = 0; j < n; ++j) {
    for (i = 0; i < m; ++i) {
      A[offsetA + i] = alpha;
    }
    offsetA += ALda;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mfill>:
  endbr64
  imul   %esi,%ecx
  add    %ecx,%edx
  test   %r9d,%r9d
  jle    L31
  test   %r8d,%r8d
  jle    L31
  movslq %edx,%rax
  push   %r12
  mov    %r8d,%r11d
  movapd %xmm0,%xmm1
  lea    (%rdi,%rax,8),%rcx
  mov    %r8d,%eax
  push   %rbp
  movslq %esi,%rbp
  shr    %eax
  push   %rbx
  mov    %esi,%r10d
  shl    $0x3,%rbp
  lea    -0x1(%rax),%ebx
  and    $0xfffffffe,%r11d
  unpcklpd %xmm1,%xmm1
  xor    %esi,%esi
  add    $0x1,%rbx
  shl    $0x4,%rbx
  nopl   (%rax)
L61:
  lea    (%rbx,%rcx,1),%r12
  mov    %rcx,%rax
  cmp    $0x1,%r8d
  je     L69
  nopl   (%rax)
L40:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %r12,%rax
  jne    L40
  mov    %r11d,%eax
  cmp    %r11d,%r8d
  je     L37
L1:
  add    %edx,%eax
  cltq
  movsd  %xmm0,(%rdi,%rax,8)
L37:
  add    $0x1,%esi
  add    %r10d,%edx
  add    %rbp,%rcx
  cmp    %esi,%r9d
  jne    L61
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L69:
  xor    %eax,%eax
  jmp    L1
L31:
  ret
```

assistant: ```c
void mfill(double alpha, double *A, int ALda, int Ai, int Aj, int m, int n) {
  int i, j;
  int offsetA = Aj * ALda + Ai;
  for (j = 0; j < n; ++j) {
    for (i = 0; i < m; ++i) {
      A[offsetA + i] = alpha;
    }
    offsetA += ALda;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jge    L53
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r10d
  mov    %edx,%ebp
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r11
  mov    %edx,%ebx
  mov    %esi,%edx
  jmp    L20
L15:
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%r9
  mov    (%r9),%edi
  cmp    %ecx,%edi
  jle    L17
  lea    -0x4(%r12,%rax,4),%rax
L87:
  sub    $0x1,%ebx
  mov    %rax,%r9
  sub    $0x4,%rax
  mov    0x4(%rax),%edi
  cmp    %ecx,%edi
  jg     L87
L17:
  cmp    %ebx,%edx
  jge    L3
  mov    %edi,(%r8)
  mov    %esi,(%r9)
L20:
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%r12,%rax,1),%r8
  mov    (%r8),%esi
  mov    (%r11),%ecx
  cmp    %edx,%ebp
  jle    L15
  lea    0x4(%r12,%rax,1),%rax
  cmp    %ecx,%esi
  jg     L15
L66:
  add    $0x1,%edx
  mov    %rax,%r8
  mov    (%rax),%esi
  add    $0x4,%rax
  cmp    %edx,%ebp
  jle    L15
  cmp    %ecx,%esi
  jle    L66
  jmp    L15
L3:
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%r11)
  mov    %ecx,(%rax)
  lea    -0x1(%rbx),%edx
  mov    %r10d,%esi
  mov    %r12,%rdi
  call   <quicksort>
  lea    0x1(%rbx),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <quicksort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  ret
```

assistant: ```c
void quicksort(int number[25], int first, int last) {
  int i, j, pivot, temp;
  if (first < last) {
    pivot = first;
    i = first;
    j = last;
    while (i < j) {
      while (number[i] <= number[pivot] && i < last)
        i++;
      while (number[j] > number[pivot])
        j--;
      if (i < j) {
        temp = number[i];
        number[i] = number[j];
        number[j] = temp;
      }
    }
    temp = number[pivot];
    number[pivot] = number[j];
    number[j] = temp;
    quicksort(number, first, j - 1);
    quicksort(number, j + 1, last);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jge    L16
  push   %r12
  mov    %esi,%r10d
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
L5:
  movslq %r10d,%rax
  mov    %ebp,%ebx
  mov    %r10d,%edx
  lea    (%r12,%rax,4),%r11
  nopl   0x0(%rax)
L3:
  movslq %edx,%rax
  mov    (%r11),%ecx
  shl    $0x2,%rax
  lea    (%r12,%rax,1),%r8
  mov    (%r8),%esi
  cmp    %edx,%ebp
  jle    L53
  lea    0x4(%r12,%rax,1),%rax
  jmp    L21
  nopl   0x0(%rax)
L74:
  add    $0x1,%edx
  mov    (%rax),%esi
  mov    %rax,%r8
  add    $0x4,%rax
  cmp    %edx,%ebp
  jle    L53
L21:
  cmp    %ecx,%esi
  jle    L74
L53:
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%r9
  mov    (%r9),%edi
  cmp    %ecx,%edi
  jle    L19
  lea    -0x4(%r12,%rax,4),%rax
  nop
L35:
  mov    %rax,%r9
  mov    (%rax),%edi
  sub    $0x4,%rax
  sub    $0x1,%ebx
  cmp    %ecx,%edi
  jg     L35
L19:
  cmp    %ebx,%edx
  jl     L4
  mov    (%r9),%eax
  mov    %r10d,%esi
  lea    -0x1(%rbx),%edx
  mov    %r12,%rdi
  mov    %eax,(%r11)
  mov    %ecx,(%r9)
  call   <quicksort>
  lea    0x1(%rbx),%r10d
  cmp    %ebp,%r10d
  jl     L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L4:
  mov    %edi,(%r8)
  mov    %esi,(%r9)
  jmp    L3
L16:
  ret
```

assistant: ```c
void quicksort(int number[25], int first, int last) {
  int i, j, pivot, temp;
  if (first < last) {
    pivot = first;
    i = first;
    j = last;
    while (i < j) {
      while (number[i] <= number[pivot] && i < last)
        i++;
      while (number[j] > number[pivot])
        j--;
      if (i < j) {
        temp = number[i];
        number[i] = number[j];
        number[j] = temp;
      }
    }
    temp = number[pivot];
    number[pivot] = number[j];
    number[j] = temp;
    quicksort(number, first, j - 1);
    quicksort(number, j + 1, last);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jge    L62
  push   %r12
  mov    %esi,%r10d
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
L28:
  movslq %r10d,%rax
  mov    %ebp,%ebx
  mov    %r10d,%edx
  lea    (%r12,%rax,4),%r11
  nopl   0x0(%rax)
L54:
  movslq %edx,%rax
  mov    (%r11),%ecx
  shl    $0x2,%rax
  lea    (%r12,%rax,1),%r8
  mov    (%r8),%edi
  cmp    %edx,%ebp
  jle    L46
  lea    0x4(%r12,%rax,1),%rax
  jmp    L22
  nopl   0x0(%rax)
L8:
  add    $0x1,%edx
  mov    (%rax),%edi
  mov    %rax,%r8
  add    $0x4,%rax
  cmp    %edx,%ebp
  jle    L46
L22:
  cmp    %ecx,%edi
  jle    L8
L46:
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%r9
  mov    (%r9),%esi
  cmp    %ecx,%esi
  jle    L5
  lea    -0x4(%r12,%rax,4),%rax
  nop
L0:
  mov    %rax,%r9
  mov    (%rax),%esi
  sub    $0x4,%rax
  sub    $0x1,%ebx
  cmp    %ecx,%esi
  jg     L0
L5:
  cmp    %ebx,%edx
  jl     L17
  mov    %esi,(%r11)
  lea    -0x1(%rbx),%edx
  mov    %r10d,%esi
  mov    %r12,%rdi
  mov    %ecx,(%r9)
  call   <quicksort>
  lea    0x1(%rbx),%r10d
  cmp    %ebp,%r10d
  jl     L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %esi,(%r8)
  mov    %edi,(%r9)
  jmp    L54
L62:
  ret
```

assistant: ```c
void quicksort(int number[25], int first, int last) {
  int i, j, pivot, temp;
  if (first < last) {
    pivot = first;
    i = first;
    j = last;
    while (i < j) {
      while (number[i] <= number[pivot] && i < last)
        i++;
      while (number[j] > number[pivot])
        j--;
      if (i < j) {
        temp = number[i];
        number[i] = number[j];
        number[j] = temp;
      }
    }
    temp = number[pivot];
    number[pivot] = number[j];
    number[j] = temp;
    quicksort(number, first, j - 1);
    quicksort(number, j + 1, last);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<preprocess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  nop
L6:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L57
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L6
L57:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L16
  mov    $0x0,%eax
  jmp    L30
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  jne    L24
  mov    -0x8(%rbp),%rax
  movb   $0x20,(%rax)
  mov    $0x1,%eax
  jmp    L30
L24:
  mov    $0x0,%eax
L30:
  leave
  ret
```

assistant: ```c
bool preprocess(char *cmdline) {
  char *tmp = cmdline + strlen(cmdline);
  while (isspace(*--tmp) && tmp >= cmdline) {
    ;
  }
  if (tmp < cmdline) {
    return false;
  }
  if (*tmp == '&') {
    *tmp = ' ';
    return true;
    ;
  }
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<preprocess>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
L24:
  sub    $0x1,%rbx
  movsbl (%rbx),%edi
  call   <isspace@plt>
  cmp    %rbx,%rbp
  ja     L12
  test   %rax,%rax
  jne    L24
L12:
  mov    $0x0,%eax
  cmp    %rbx,%rbp
  ja     L34
  cmpb   $0x26,(%rbx)
  je     L28
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  movb   $0x20,(%rbx)
  mov    $0x1,%eax
  jmp    L34
```

assistant: ```c
bool preprocess(char *cmdline) {
  char *tmp = cmdline + strlen(cmdline);
  while (isspace(*--tmp) && tmp >= cmdline) {
    ;
  }
  if (tmp < cmdline) {
    return false;
  }
  if (*tmp == '&') {
    *tmp = ' ';
    return true;
    ;
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<preprocess>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L31:
  cmp    %rbx,%rbp
  ja     L14
L44:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  xor    %eax,%eax
  cmp    %rbx,%rbp
  ja     L37
  cmpb   $0x26,(%rbx)
  je     L35
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L35:
  movb   $0x20,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool preprocess(char *cmdline) {
  char *tmp = cmdline + strlen(cmdline);
  while (isspace(*--tmp) && tmp >= cmdline) {
    ;
  }
  if (tmp < cmdline) {
    return false;
  }
  if (*tmp == '&') {
    *tmp = ' ';
    return true;
    ;
  }
  return false;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<preprocess>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L5:
  cmp    %rbx,%rbp
  ja     L14
L26:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  xor    %eax,%eax
  cmp    %rbx,%rbp
  ja     L45
  cmpb   $0x26,(%rbx)
  je     L23
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L23:
  movb   $0x20,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool preprocess(char *cmdline) {
  char *tmp = cmdline + strlen(cmdline);
  while (isspace(*--tmp) && tmp >= cmdline) {
    ;
  }
  if (tmp < cmdline) {
    return false;
  }
  if (*tmp == '&') {
    *tmp = ' ';
    return true;
    ;
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_uiRcSDSCGetSDKVersion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x13a4,%edx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x0,-0x1c(%rbp)
  je     L6
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <vWriteLogTxt@plt>
  mov    $0x63,%eax
  jmp    L20
L6:
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
  test   %eax,%eax
  jne    L22
  mov    $0x3,%edi
  call   <iGetParaInt@plt>
  mov    %eax,%ebx
  mov    $0x2,%edi
  call   <psGetParaBuf@plt>
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  mov    %ebx,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x3,%edi
  call   <iGetParaInt@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x3,%edi
  call   <iGetParaInt@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <vWriteLogHex@plt>
L22:
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D23
type: string

tool: D0: %u(b000, %u)

tool: D10: _uiRcSDSCGetSDKVersion iDoRemoteFunc ret = %d

tool: D23: _uiRcSDSCGetSDKVersion:

assistant: ```c
unsigned int _uiRcSDSCGetSDKVersion(char *pszVersion, unsigned int *puiVersionLen) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(b000, %u)", 5028, *puiVersionLen);
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_uiRcSDSCGetSDKVersion iDoRemoteFunc ret = %d", uiRet);
    return 99;
  }
  if (iGetParaInt(0) == 0) {
    memcpy(pszVersion, psGetParaBuf(2), iGetParaInt(3));
    pszVersion[iGetParaInt(3)] = 0;
    *puiVersionLen = iGetParaInt(3);
    vWriteLogHex("_uiRcSDSCGetSDKVersion:", pszVersion, *puiVersionLen);
  }
  return iGetParaInt(0);
}
```