ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L2
L78:
  mov    %rsp,%rsi
  mov    0x8(%rbx),%rdi
  call   <Load_Mem@plt>
  mov    %eax,%ebx
  cmp    $0x64,%eax
  jne    L123
L83:
  mov    %rsp,%r9
  mov    %r9,%rdi
  mov    $0x1,%eax
  lea    -0x1(%rbx),%r10d
  add    $0x4,%r9
  jmp    L0
L2:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L78
L123:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  test   %ebx,%ebx
  jg     L83
L38:
  test   $0x1,%bl
  jne    L4
  mov    $0x2,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cltq
  mov    (%rsp,%rax,4),%esi
  add    (%rsp,%rdx,4),%esi
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
L128:
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L126
  mov    $0x0,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  ret
L41:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  je     L94
L113:
  mov    (%rdi),%esi
  mov    0x4(%rdx),%ecx
  cmp    %ecx,%esi
  jle    L41
  mov    %esi,0x4(%rdx)
  mov    %ecx,(%rdi)
  jmp    L41
L94:
  add    $0x1,%rax
  add    $0x4,%rdi
L0:
  cmp    %eax,%ebx
  jle    L38
  mov    %r10d,%edx
  sub    %eax,%edx
  lea    -0x1(%rax,%rdx,1),%rdx
  lea    (%r9,%rdx,4),%r8
  mov    %rdi,%rdx
  jmp    L113
L4:
  mov    $0x2,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cltq
  mov    (%rsp,%rax,4),%esi
  jmp    L128
L126:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D22
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: D7: usage: ./P1-2 valuefile

tool: D22: valuefiles must contain 100 entries

tool: D14: The median of the array is %d


assistant: ```c
int main(int argc, char *argv[]) {
  int Nums[100];
  int NumNums, Median;
  int Load_Mem(char *, int *);
  if (argc != 2) {
    printf("usage: ./P1-2 valuefile\n");
    exit(1);
  }
  NumNums = Load_Mem(*++argv, Nums);
  if (NumNums != 100) {
    printf("valuefiles must contain 100 entries\n");
    exit(1);
  }
  int i, j, temp;
  for (i = 0; i < NumNums; i++) {
    for (j = i + 1; j < NumNums; j++) {
      if (Nums[i] > Nums[j]) {
        temp = Nums[j];
        Nums[j] = Nums[i];
        Nums[i] = temp;
      }
    }
  }
  if (NumNums % 2 == 0) {
    Median = (Nums[NumNums / 2] + Nums[NumNums / 2 - 1]) / 2;
  } else {
    Median = (Nums[NumNums / 2]);
  }
  printf("The median of the array is %d\n", Median);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L48
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L48:
  mov    0x8(%rbp),%rdi
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <Load_Mem@plt>
  mov    %eax,%ebp
  cmp    $0x64,%eax
  jne    L16
L73:
  mov    $0x1,%r8d
  mov    %rbx,%rsi
  lea    -0x1(%rbp),%r10d
  lea    0x4(%rsp),%r9
  cmp    %r8d,%ebp
  jle    L1
  nop
L13:
  mov    %r10d,%eax
  sub    %r8d,%eax
  lea    -0x1(%r8,%rax,1),%rax
  lea    (%r9,%rax,4),%rdi
  mov    %rsi,%rax
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rsi),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L95
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rsi)
L95:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L19
  add    $0x1,%r8
  add    $0x4,%rsi
  cmp    %r8d,%ebp
  jg     L13
L1:
  mov    %ebp,%edx
  shr    $0x1f,%edx
  add    %ebp,%edx
  sar    %edx
  and    $0x1,%ebp
  movslq %edx,%rax
  mov    (%rsp,%rax,4),%esi
  jne    L74
  sub    $0x1,%edx
  mov    $0x2,%ecx
  movslq %edx,%rdx
  add    (%rsp,%rdx,4),%esi
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
L74:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x1a8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  test   %ebp,%ebp
  jg     L73
  jmp    L1
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D21
type: string
name: read_data
arguments: data_tag: D24
type: string
name: read_data
arguments: data_tag: D9
type: string

tool: D21: usage: ./P1-2 valuefile

tool: D24: The median of the array is %d


tool: D9: valuefiles must contain 100 entries

assistant: ```c
int main(int argc, char *argv[]) {
  int Nums[100];
  int NumNums, Median;
  int Load_Mem(char *, int *);
  if (argc != 2) {
    printf("usage: ./P1-2 valuefile\n");
    exit(1);
  }
  NumNums = Load_Mem(*++argv, Nums);
  if (NumNums != 100) {
    printf("valuefiles must contain 100 entries\n");
    exit(1);
  }
  int i, j, temp;
  for (i = 0; i < NumNums; i++) {
    for (j = i + 1; j < NumNums; j++) {
      if (Nums[i] > Nums[j]) {
        temp = Nums[j];
        Nums[j] = Nums[i];
        Nums[i] = temp;
      }
    }
  }
  if (NumNums % 2 == 0) {
    Median = (Nums[NumNums / 2] + Nums[NumNums / 2 - 1]) / 2;
  } else {
    Median = (Nums[NumNums / 2]);
  }
  printf("The median of the array is %d\n", Median);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L37
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L37:
  mov    0x8(%rbx),%rdi
  mov    %rsp,%rsi
  call   <Load_Mem@plt>
  mov    %eax,%ebx
  cmp    $0x64,%eax
  jne    L10
L91:
  lea    0x4(%rsp),%rdi
  mov    $0x1,%r8d
  nop
L45:
  mov    -0x4(%rdi),%esi
  mov    %rdi,%rax
  mov    %r8d,%edx
  nopl   0x0(%rax)
L42:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jge    L32
  mov    %esi,(%rax)
  mov    %ecx,%esi
  mov    %ecx,-0x4(%rdi)
L32:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%ebx
  jg     L42
  add    $0x1,%r8d
  add    $0x4,%rdi
  cmp    %r8d,%ebx
  jne    L45
L14:
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  and    $0x1,%ebx
  movslq %edx,%rax
  mov    (%rsp,%rax,4),%esi
  jne    L59
  sub    $0x1,%edx
  mov    $0x2,%ecx
  movslq %edx,%rdx
  add    (%rsp,%rdx,4),%esi
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
L59:
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L10:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  test   %ebx,%ebx
  jle    L14
  cmp    $0x1,%ebx
  jne    L91
  jmp    L14
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string

tool: D4: usage: ./P1-2 valuefile

tool: D20: The median of the array is %d


tool: D26: valuefiles must contain 100 entries

assistant: ```c
int main(int argc, char *argv[]) {
  int Nums[100];
  int NumNums, Median;
  int Load_Mem(char *, int *);
  if (argc != 2) {
    printf("usage: ./P1-2 valuefile\n");
    exit(1);
  }
  NumNums = Load_Mem(*++argv, Nums);
  if (NumNums != 100) {
    printf("valuefiles must contain 100 entries\n");
    exit(1);
  }
  int i, j, temp;
  for (i = 0; i < NumNums; i++) {
    for (j = i + 1; j < NumNums; j++) {
      if (Nums[i] > Nums[j]) {
        temp = Nums[j];
        Nums[j] = Nums[i];
        Nums[i] = temp;
      }
    }
  }
  if (NumNums % 2 == 0) {
    Median = (Nums[NumNums / 2] + Nums[NumNums / 2 - 1]) / 2;
  } else {
    Median = (Nums[NumNums / 2]);
  }
  printf("The median of the array is %d\n", Median);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_ahtoi>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  mov    %eax,%edi
  movzbl (%rbx),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L108
  cmp    $0x20,%al
  jne    L27
L108:
  mov    $0x1,%eax
L2:
  mov    %eax,%esi
  movzbl (%rbx,%rax,1),%edx
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L2
  cmp    $0x20,%dl
  je     L2
L46:
  cmp    %esi,%edi
  jle    L113
  movslq %esi,%rdx
  lea    -0x1(%rdi),%ecx
  sub    %esi,%ecx
  shl    $0x2,%ecx
  mov    $0x0,%r8d
  jmp    L32
L27:
  mov    $0x0,%esi
  jmp    L46
L75:
  cmp    $0x39,%al
  jg     L129
  movsbl %al,%eax
  sub    $0x30,%eax
  shl    %cl,%eax
  add    %eax,%r8d
L129:
  add    $0x1,%rdx
  sub    $0x4,%ecx
  cmp    %edx,%edi
  jle    L94
L32:
  movzbl (%rbx,%rdx,1),%eax
  test   %al,%al
  je     L94
  mov    %eax,%esi
  and    $0xffffffdf,%esi
  sub    $0x41,%esi
  cmp    $0x5,%sil
  jbe    L75
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L129
  jmp    L75
L113:
  mov    $0x0,%r8d
L94:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ft_ahtoi(char const *str) {
  int i;
  int len;
  int val;
  i = 0;
  len = ft_strlen(str);
  val = 0;
  while ((str[i] >= 9 && str[i] <= 13) || str[i] == 32)
    i++;
  while (i < len && str[i] != 0) {
    if ((str[i] >= 48 && str[i] <= 57) || (str[i] >= 65 && str[i] <= 70) || (str[i] >= 97 && str[i] <= 102)) {
      if (str[i] <= 57)
        val += (str[i] - 48) * (1 << (4 * (len - 1 - i)));
      else if (str[i] <= 65 && str[i] >= 70)
        val += (str[i] - 55) * (1 << (4 * (len - 1 - i)));
      else if (str[i] <= 97 && str[i] >= 102)
        val += (str[i] - 87) * (1 << (4 * (len - 1 - i)));
    }
    i++;
  }
  return (val);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_ahtoi>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  mov    %eax,%edi
  movzbl (%rbx),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L10
  cmp    $0x20,%al
  jne    L11
L10:
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L69:
  movzbl (%rbx,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L69
  cmp    $0x20,%dl
  je     L69
L129:
  cmp    %esi,%edi
  jle    L47
  lea    -0x1(%rdi),%ecx
  movslq %esi,%rdx
  xor    %r8d,%r8d
  sub    %esi,%ecx
  shl    $0x2,%ecx
  jmp    L102
  nopl   0x0(%rax,%rax,1)
L91:
  add    $0x1,%rdx
  sub    $0x4,%ecx
  cmp    %edx,%edi
  jle    L83
L102:
  movsbl (%rbx,%rdx,1),%eax
  test   %al,%al
  je     L83
  mov    %eax,%esi
  and    $0xffffffdf,%esi
  sub    $0x41,%esi
  cmp    $0x5,%sil
  jbe    L106
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L91
L106:
  cmp    $0x39,%al
  jg     L91
  sub    $0x30,%eax
  add    $0x1,%rdx
  shl    %cl,%eax
  sub    $0x4,%ecx
  add    %eax,%r8d
  cmp    %edx,%edi
  jg     L102
L83:
  mov    %r8d,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  xor    %esi,%esi
  jmp    L129
L47:
  xor    %r8d,%r8d
  jmp    L83
```

assistant: ```c
int ft_ahtoi(char const *str) {
  int i;
  int len;
  int val;
  i = 0;
  len = ft_strlen(str);
  val = 0;
  while ((str[i] >= 9 && str[i] <= 13) || str[i] == 32)
    i++;
  while (i < len && str[i] != 0) {
    if ((str[i] >= 48 && str[i] <= 57) || (str[i] >= 65 && str[i] <= 70) || (str[i] >= 97 && str[i] <= 102)) {
      if (str[i] <= 57)
        val += (str[i] - 48) * (1 << (4 * (len - 1 - i)));
      else if (str[i] <= 65 && str[i] >= 70)
        val += (str[i] - 55) * (1 << (4 * (len - 1 - i)));
      else if (str[i] <= 97 && str[i] >= 102)
        val += (str[i] - 87) * (1 << (4 * (len - 1 - i)));
    }
    i++;
  }
  return (val);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_ahtoi>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  mov    %eax,%edi
  movzbl (%rbx),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L57
  cmp    $0x20,%al
  jne    L139
L57:
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L127:
  movzbl (%rbx,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L127
  cmp    $0x20,%dl
  je     L127
L90:
  cmp    %esi,%edi
  jle    L84
  lea    -0x1(%rdi),%ecx
  movslq %esi,%rdx
  xor    %r8d,%r8d
  sub    %esi,%ecx
  shl    $0x2,%ecx
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x1,%rdx
  sub    $0x4,%ecx
  cmp    %edx,%edi
  jle    L83
L17:
  movsbl (%rbx,%rdx,1),%eax
  test   %al,%al
  je     L83
  mov    %eax,%esi
  and    $0xffffffdf,%esi
  sub    $0x41,%esi
  cmp    $0x5,%sil
  jbe    L33
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L73
L33:
  cmp    $0x39,%al
  jg     L73
  sub    $0x30,%eax
  add    $0x1,%rdx
  shl    %cl,%eax
  sub    $0x4,%ecx
  add    %eax,%r8d
  cmp    %edx,%edi
  jg     L17
L83:
  mov    %r8d,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L139:
  xor    %esi,%esi
  jmp    L90
L84:
  xor    %r8d,%r8d
  jmp    L83
```

assistant: ```c
int ft_ahtoi(char const *str) {
  int i;
  int len;
  int val;
  i = 0;
  len = ft_strlen(str);
  val = 0;
  while ((str[i] >= 9 && str[i] <= 13) || str[i] == 32)
    i++;
  while (i < len && str[i] != 0) {
    if ((str[i] >= 48 && str[i] <= 57) || (str[i] >= 65 && str[i] <= 70) || (str[i] >= 97 && str[i] <= 102)) {
      if (str[i] <= 57)
        val += (str[i] - 48) * (1 << (4 * (len - 1 - i)));
      else if (str[i] <= 65 && str[i] >= 70)
        val += (str[i] - 55) * (1 << (4 * (len - 1 - i)));
      else if (str[i] <= 97 && str[i] >= 102)
        val += (str[i] - 87) * (1 << (4 * (len - 1 - i)));
    }
    i++;
  }
  return (val);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<produto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  mov    -0x40(%rbp),%edx
  mov    -0x34(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <matriz_nula@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L56
L55:
  movl   $0x0,-0x10(%rbp)
  jmp    L10
L50:
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L12:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L12
  addl   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L50
  addl   $0x1,-0x14(%rbp)
L56:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L55
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **produto(double **M1, double **M2, int l1, int c1, int l2, int c2) {
  int i, j, k;
  double **produto = matriz_nula(l1, c2);
  for (i = 0; i < l1; i++)
    for (j = 0; j < c2; j++)
      for (k = 0; k < c1; k++)
        produto[i][j] += M1[i][k] * M2[k][j];
  return produto;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<produto>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %ecx,%ebp
  mov    %r9d,%r12d
  mov    %r9d,%esi
  mov    %edx,%edi
  call   <matriz_nula@plt>
  mov    %rax,%r9
  test   %r13d,%r13d
  jle    L50
  mov    %rax,%rsi
  mov    %r14,%rdi
  mov    %r13d,%r13d
  lea    (%rax,%r13,8),%r11
  lea    -0x1(%r12),%eax
  lea    0x8(,%rax,8),%r10
  lea    -0x1(%rbp),%eax
  lea    0x8(,%rax,8),%r8
  jmp    L89
L9:
  mov    %rcx,%rdx
  add    (%rsi),%rdx
  mov    (%rbx,%rax,1),%r13
  mov    (%rdi),%r14
  movsd  (%r14,%rax,1),%xmm0
  mulsd  0x0(%r13,%rcx,1),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %rax,%r8
  jne    L9
L41:
  add    $0x8,%rcx
  cmp    %r10,%rcx
  je     L66
L70:
  mov    $0x0,%eax
  test   %ebp,%ebp
  jg     L9
  jmp    L41
L66:
  add    $0x8,%rsi
  add    $0x8,%rdi
  cmp    %r11,%rsi
  je     L50
L89:
  mov    $0x0,%ecx
  test   %r12d,%r12d
  jg     L70
  jmp    L66
L50:
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double **produto(double **M1, double **M2, int l1, int c1, int l2, int c2) {
  int i, j, k;
  double **produto = matriz_nula(l1, c2);
  for (i = 0; i < l1; i++)
    for (j = 0; j < c2; j++)
      for (k = 0; k < c1; k++)
        produto[i][j] += M1[i][k] * M2[k][j];
  return produto;
}
```
user: Translate the below assembly code into C programming language:

```asm
<produto>:
  endbr64
  push   %r14
  movslq %edx,%r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r14d,%edi
  push   %rbx
  mov    %rsi,%rbx
  mov    %r9d,%esi
  call   <matriz_nula@plt>
  mov    %rax,%r11
  test   %r14d,%r14d
  jle    L24
  lea    -0x1(%r13),%eax
  xor    %r9d,%r9d
  movslq %r12d,%r8
  lea    0x8(,%rax,8),%r10
L4:
  xor    %ecx,%ecx
  test   %r13d,%r13d
  jle    L47
  nopw   0x0(%rax,%rax,1)
L32:
  test   %r12d,%r12d
  jle    L20
  mov    (%r11,%r9,8),%rsi
  mov    0x0(%rbp,%r9,8),%rdi
  xor    %eax,%eax
  add    %rcx,%rsi
  movsd  (%rsi),%xmm1
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %r8,%rax
  jne    L1
L20:
  add    $0x8,%rcx
  cmp    %rcx,%r10
  jne    L32
L47:
  add    $0x1,%r9
  cmp    %r9,%r14
  jne    L4
L24:
  pop    %rbx
  mov    %r11,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double **produto(double **M1, double **M2, int l1, int c1, int l2, int c2) {
  int i, j, k;
  double **produto = matriz_nula(l1, c2);
  for (i = 0; i < l1; i++)
    for (j = 0; j < c2; j++)
      for (k = 0; k < c1; k++)
        produto[i][j] += M1[i][k] * M2[k][j];
  return produto;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<produto>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %rsi,%rbx
  mov    %r9d,%esi
  sub    $0x8,%rsp
  call   <matriz_nula@plt>
  mov    %rax,%r13
  test   %r15d,%r15d
  jle    L22
  test   %r12d,%r12d
  jle    L22
  test   %r14d,%r14d
  jle    L22
  movslq %r12d,%r10
  movslq %r15d,%r11
  xor    %r12d,%r12d
  movslq %r14d,%r8
  shl    $0x3,%r10
  nopl   (%rax)
L3:
  mov    0x0(%r13,%r12,8),%r9
  mov    0x0(%rbp,%r12,8),%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L8:
  lea    (%r9,%rcx,1),%rsi
  xor    %eax,%eax
  movsd  (%rsi),%xmm1
  nopw   0x0(%rax,%rax,1)
L33:
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rax,%r8
  jne    L33
  add    $0x8,%rcx
  cmp    %rcx,%r10
  jne    L8
  add    $0x1,%r12
  cmp    %r12,%r11
  jne    L3
L22:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **produto(double **M1, double **M2, int l1, int c1, int l2, int c2) {
  int i, j, k;
  double **produto = matriz_nula(l1, c2);
  for (i = 0; i < l1; i++)
    for (j = 0; j < c2; j++)
      for (k = 0; k < c1; k++)
        produto[i][j] += M1[i][k] * M2[k][j];
  return produto;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x2c(%rbp)
  movb   $0x0,-0x6(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L32:
  mov    -0x20(%rbp),%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  jne    L43
  mov    -0x4(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x6(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bin_n@plt>
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L4
L43:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  xor    $0x43,%eax
  mov    %al,-0x5(%rbp)
  shlb   -0x6(%rbp)
  movzbl -0x5(%rbp),%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sar    $0x7,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  movzbl -0x6(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x6(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7,%al
  jbe    L2
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  movzwl (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
L2:
  addl   $0x1,-0x4(%rbp)
L9:
  movzbl -0x2c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L32
  movzbl -0x2c(%rbp),%edx
  movzbl -0x6(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bin_n@plt>
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzbl -0x6(%rbp),%eax
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string
name: retrieve_data
arguments: tag: D18
type_guessed: string

tool: D6: %s DATA UNDERFLOW


tool: D18: %s 

assistant: ```c
unsigned char get_bits(unsigned char **data, unsigned short *len, unsigned char *bitpos, unsigned char n) {
  unsigned char bits = 0;
  unsigned char byte;
  for (int i = 0; i < n; i++) {
    if (*len == 0) {
      printf("%s DATA UNDERFLOW\n", bin_n(bits, i));
      return 0;
    }
    byte = *data[0] ^ 0x43;
    bits <<= 1;
    bits |= ((byte << *bitpos) & 0x80) >> 7;
    (*bitpos)++;
    if (*bitpos > 7) {
      (*data)++;
      (*len)--;
      *bitpos = 0;
    }
  }
  printf("%s ", bin_n(bits, n));
  return bits;
}
```