ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_rx_queue_name>:
  endbr64
  push   %r12
  lea    D16(%rip),%r12
  mov    %edi,%ecx
  mov    $0x14,%esi
  mov    %r12,%rdi
  lea    D8(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: MProc_Client_%u_RX

assistant: ```c
const char *get_rx_queue_name(unsigned id) {
  static char buffer[sizeof("MProc_Client_%u_RX") + 2];
  snprintf(buffer, sizeof(buffer) - 1, "MProc_Client_%u_RX", id);
  return buffer;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_rx_queue_name>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  mov    %edi,%ecx
  mov    $0x14,%esi
  mov    %r12,%rdi
  lea    D4(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: MProc_Client_%u_RX

assistant: ```c
const char *get_rx_queue_name(unsigned id) {
  static char buffer[sizeof("MProc_Client_%u_RX") + 2];
  snprintf(buffer, sizeof(buffer) - 1, "MProc_Client_%u_RX", id);
  return buffer;
}
```
user: What is the c source code of the assembly code below:

```asm
<pin_group_color>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x10,-0x4(%rbp)
  ja     L104
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D94(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D94(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D67(%rip),%rax
  jmp    L78
  lea    D78(%rip),%rax
  jmp    L78
  lea    D57(%rip),%rax
  jmp    L78
  lea    D67(%rip),%rax
  jmp    L78
  lea    D101(%rip),%rax
  jmp    L78
  lea    D101(%rip),%rax
  jmp    L78
  lea    D155(%rip),%rax
  jmp    L78
  lea    D151(%rip),%rax
  jmp    L78
  lea    D67(%rip),%rax
  jmp    L78
  lea    D168(%rip),%rax
  jmp    L78
  lea    D101(%rip),%rax
  jmp    L78
  lea    D78(%rip),%rax
  jmp    L78
  lea    D168(%rip),%rax
  jmp    L78
  lea    D57(%rip),%rax
  jmp    L78
  lea    D148(%rip),%rax
  jmp    L78
  lea    D99(%rip),%rax
  jmp    L78
  mov    $0x0,%eax
  jmp    L78
L104:
  mov    $0x0,%eax
L78:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D67
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D78
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D57
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D101
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D155
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D151
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D168
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D148
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D99
type_guessed: string

tool: D67: RED

tool: D78: TEAL

tool: D57: PURPLE

tool: D101: OLIVE

tool: D155: PINK

tool: D151: GREEN

tool: D168: ORANGE

tool: D148: GRAY

tool: D99: LIME

assistant: ```c
const char *pin_group_color(unsigned group, unsigned block) {
  (void)block;
  switch (group) {
  case 0:
    return "RED";
  case 1:
    return "TEAL";
  case 2:
    return "PURPLE";
  case 3:
    return "RED";
  case 4:
    return "OLIVE";
  case 5:
    return "OLIVE";
  case 6:
    return "PINK";
  case 7:
    return "GREEN";
  case 8:
    return "RED";
  case 9:
    return "ORANGE";
  case 10:
    return "OLIVE";
  case 11:
    return "TEAL";
  case 12:
    return "ORANGE";
  case 13:
    return "PURPLE";
  case 14:
    return "GRAY";
  case 15:
    return "LIME";
  case 16:
    return NULL;
  default:
    return NULL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pin_group_color>:
  endbr64
  cmp    $0x10,%edi
  ja     L5
  mov    %edi,%edi
  lea    D121(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D80(%rip),%rax
  ret
  lea    D42(%rip),%rax
  ret
  lea    D24(%rip),%rax
  ret
  lea    D24(%rip),%rax
  ret
  lea    D98(%rip),%rax
  ret
  lea    D45(%rip),%rax
  ret
  lea    D27(%rip),%rax
  ret
  lea    D24(%rip),%rax
  ret
  lea    D27(%rip),%rax
  ret
  lea    D42(%rip),%rax
  ret
  lea    D20(%rip),%rax
  ret
  lea    D33(%rip),%rax
  ret
  mov    $0x0,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
  lea    D70(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_label: D80
type_infered: string
name: read_data
arguments: data_label: D42
type_infered: string
name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D98
type_infered: string
name: read_data
arguments: data_label: D45
type_infered: string
name: read_data
arguments: data_label: D27
type_infered: string
name: read_data
arguments: data_label: D20
type_infered: string
name: read_data
arguments: data_label: D33
type_infered: string
name: read_data
arguments: data_label: D70
type_infered: string

tool: D80: TEAL

tool: D42: PURPLE

tool: D24: OLIVE

tool: D98: PINK

tool: D45: GREEN

tool: D27: ORANGE

tool: D20: GRAY

tool: D33: LIME

tool: D70: RED

assistant: ```c
const char *pin_group_color(unsigned group, unsigned block) {
  (void)block;
  switch (group) {
  case 0:
    return "RED";
  case 1:
    return "TEAL";
  case 2:
    return "PURPLE";
  case 3:
    return "RED";
  case 4:
    return "OLIVE";
  case 5:
    return "OLIVE";
  case 6:
    return "PINK";
  case 7:
    return "GREEN";
  case 8:
    return "RED";
  case 9:
    return "ORANGE";
  case 10:
    return "OLIVE";
  case 11:
    return "TEAL";
  case 12:
    return "ORANGE";
  case 13:
    return "PURPLE";
  case 14:
    return "GRAY";
  case 15:
    return "LIME";
  case 16:
    return NULL;
  default:
    return NULL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pin_group_color>:
  endbr64
  cmp    $0xf,%edi
  ja     L3
  lea    D83(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D42(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D27(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D29(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D23(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D20(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D6(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D75(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D47(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D18(%rip),%rax
  ret
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D42
data_type: string
name: retrieve_data
arguments: label: D27
data_type: string
name: retrieve_data
arguments: label: D29
data_type: string
name: retrieve_data
arguments: label: D23
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string
name: retrieve_data
arguments: label: D75
data_type: string
name: retrieve_data
arguments: label: D47
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D42: OLIVE

tool: D27: RED

tool: D29: PURPLE

tool: D23: ORANGE

tool: D20: TEAL

tool: D6: PINK

tool: D75: GREEN

tool: D47: LIME

tool: D18: GRAY

assistant: ```c
const char *pin_group_color(unsigned group, unsigned block) {
  (void)block;
  switch (group) {
  case 0:
    return "RED";
  case 1:
    return "TEAL";
  case 2:
    return "PURPLE";
  case 3:
    return "RED";
  case 4:
    return "OLIVE";
  case 5:
    return "OLIVE";
  case 6:
    return "PINK";
  case 7:
    return "GREEN";
  case 8:
    return "RED";
  case 9:
    return "ORANGE";
  case 10:
    return "OLIVE";
  case 11:
    return "TEAL";
  case 12:
    return "ORANGE";
  case 13:
    return "PURPLE";
  case 14:
    return "GRAY";
  case 15:
    return "LIME";
  case 16:
    return NULL;
  default:
    return NULL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pin_group_color>:
  endbr64
  cmp    $0xf,%edi
  ja     L9
  lea    D69(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D91(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D79(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D29(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D3(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D86(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D16(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D42(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D15(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D19(%rip),%rax
  ret
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D91
datatype: string
name: extract_symbolic_data
arguments: data_label: D79
datatype: string
name: extract_symbolic_data
arguments: data_label: D29
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D86
datatype: string
name: extract_symbolic_data
arguments: data_label: D16
datatype: string
name: extract_symbolic_data
arguments: data_label: D42
datatype: string
name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string

tool: D91: OLIVE

tool: D79: RED

tool: D29: PURPLE

tool: D3: ORANGE

tool: D86: TEAL

tool: D16: PINK

tool: D42: GREEN

tool: D15: LIME

tool: D19: GRAY

assistant: ```c
const char *pin_group_color(unsigned group, unsigned block) {
  (void)block;
  switch (group) {
  case 0:
    return "RED";
  case 1:
    return "TEAL";
  case 2:
    return "PURPLE";
  case 3:
    return "RED";
  case 4:
    return "OLIVE";
  case 5:
    return "OLIVE";
  case 6:
    return "PINK";
  case 7:
    return "GREEN";
  case 8:
    return "RED";
  case 9:
    return "ORANGE";
  case 10:
    return "OLIVE";
  case 11:
    return "TEAL";
  case 12:
    return "ORANGE";
  case 13:
    return "PURPLE";
  case 14:
    return "GRAY";
  case 15:
    return "LIME";
  case 16:
    return NULL;
  default:
    return NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rdbyte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4: %2x

assistant: ```c
int rdbyte(char **s, int *sum) {
  int x;
  sscanf(*s, "%2x", &x);
  *s += 2;
  *sum += x;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rdbyte>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    D7(%rip),%rsi
  mov    (%rdi),%rdi
  call   <sscanf@plt>
  addq   $0x2,(%rbx)
  mov    0x4(%rsp),%eax
  add    %eax,0x0(%rbp)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7: %2x

assistant: ```c
int rdbyte(char **s, int *sum) {
  int x;
  sscanf(*s, "%2x", &x);
  *s += 2;
  *sum += x;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rdbyte>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    D9(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  addq   $0x2,(%rbx)
  mov    0x4(%rsp),%eax
  add    %eax,0x0(%rbp)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: %2x

assistant: ```c
int rdbyte(char **s, int *sum) {
  int x;
  sscanf(*s, "%2x", &x);
  *s += 2;
  *sum += x;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rdbyte>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    D1(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  addq   $0x2,(%rbx)
  mov    0x4(%rsp),%eax
  add    %eax,0x0(%rbp)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string

tool: D1: %2x

assistant: ```c
int rdbyte(char **s, int *sum) {
  int x;
  sscanf(*s, "%2x", &x);
  *s += 2;
  *sum += x;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spidy_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L7
L23:
  mov    $0x31,%edi
  call   <putc@plt>
  mov    $0x0,%eax
  call   <getCommand@plt>
  cmp    $0x37,%eax
  jne    L19
  movl   $0x1,-0x4(%rbp)
L19:
  mov    $0x1,%edi
  call   <sleep@plt>
L7:
  cmpl   $0x0,-0x4(%rbp)
  je     L23
  mov    $0x30,%edi
  call   <putc@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: Your friendly neighborhood Spider-Man


assistant: ```c
int spidy_main(void *unused) {
  int found = 0;
  puts("Your friendly neighborhood Spider-Man\n");
  while (!found) {
    putc(0x31);
    if (getCommand() == 0x37)
      found = 1;
    sleep(1);
  }
  putc(0x30);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<spidy_main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L9
L1:
  mov    $0x1,%edi
  call   <sleep@plt>
L9:
  mov    $0x31,%edi
  call   <putc@plt>
  mov    $0x0,%eax
  call   <getCommand@plt>
  cmp    $0x37,%eax
  jne    L1
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x30,%edi
  call   <putc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: Your friendly neighborhood Spider-Man


assistant: ```c
int spidy_main(void *unused) {
  int found = 0;
  puts("Your friendly neighborhood Spider-Man\n");
  while (!found) {
    putc(0x31);
    if (getCommand() == 0x37)
      found = 1;
    sleep(1);
  }
  putc(0x30);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<spidy_main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L1:
  mov    $0x31,%edi
  call   <putc@plt>
  xor    %eax,%eax
  call   <getCommand@plt>
  mov    $0x1,%edi
  cmp    $0x37,%eax
  je     L8
  call   <sleep@plt>
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L8:
  call   <sleep@plt>
  mov    $0x30,%edi
  call   <putc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: Your friendly neighborhood Spider-Man


assistant: ```c
int spidy_main(void *unused) {
  int found = 0;
  puts("Your friendly neighborhood Spider-Man\n");
  while (!found) {
    putc(0x31);
    if (getCommand() == 0x37)
      found = 1;
    sleep(1);
  }
  putc(0x30);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<spidy_main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L8:
  mov    $0x31,%edi
  call   <putc@plt>
  xor    %eax,%eax
  call   <getCommand@plt>
  mov    $0x1,%edi
  cmp    $0x37,%eax
  je     L18
  call   <sleep@plt>
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L18:
  call   <sleep@plt>
  mov    $0x30,%edi
  call   <putc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: Your friendly neighborhood Spider-Man


assistant: ```c
int spidy_main(void *unused) {
  int found = 0;
  puts("Your friendly neighborhood Spider-Man\n");
  while (!found) {
    putc(0x31);
    if (getCommand() == 0x37)
      found = 1;
    sleep(1);
  }
  putc(0x30);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mult_by_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L0:
  mov    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
  subl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned mult_by_add(unsigned a, unsigned b) {
  unsigned result = 0;
  while (a > 0) {
    result += b;
    a--;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mult_by_add>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L7
  mov    %edi,%edx
L6:
  sub    $0x1,%edx
  jne    L6
  imul   %esi,%eax
L7:
  ret
```

assistant: ```c
unsigned mult_by_add(unsigned a, unsigned b) {
  unsigned result = 0;
  while (a > 0) {
    result += b;
    a--;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<mult_by_add>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
unsigned mult_by_add(unsigned a, unsigned b) {
  unsigned result = 0;
  while (a > 0) {
    result += b;
    a--;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mult_by_add>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
unsigned mult_by_add(unsigned a, unsigned b) {
  unsigned result = 0;
  while (a > 0) {
    result += b;
    a--;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  shr    $0x3,%rax
  or     $0xbab5,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L22
L1:
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jae    L14
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jae    L31
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  jmp    L31
L14:
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  movzwl -0xc(%rbp),%edx
  lea    -0xa(%rbp),%rcx
  movslq %edx,%rdx
  add    %rdx,%rdx
  add    %rcx,%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
L31:
  addw   $0x2,-0xc(%rbp)
L22:
  cmpw   $0x0,-0xc(%rbp)
  je     L1
  movzwl -0xa(%rbp),%eax
  xor    $0x1251,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & (unsigned short)7) | 1UL);
        }
      } else {
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ 413274705UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%eax
  or     $0xbab5,%eax
  and    $0x6,%ecx
  or     $0x5,%ecx
  sar    %cl,%eax
  xor    $0x1251,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & (unsigned short)7) | 1UL);
        }
      } else {
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ 413274705UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%eax
  and    $0x6,%ecx
  or     $0xbab5,%eax
  or     $0x5,%ecx
  sar    %cl,%eax
  xor    $0x1251,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & (unsigned short)7) | 1UL);
        }
      } else {
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ 413274705UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%eax
  and    $0x6,%ecx
  or     $0xbab5,%eax
  or     $0x5,%ecx
  sar    %cl,%eax
  xor    $0x1251,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & (unsigned short)7) | 1UL);
        }
      } else {
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ 413274705UL;
  }
}
```