ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<needquotes>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  cmp    $0x22,%dil
  je     L16
  test   %dil,%dil
  je     L29
  mov    %r12,%rbp
  jmp    L21
L47:
  test   %eax,%eax
  jne    L25
L21:
  call   <is_white@plt>
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  mov    %eax,%ebx
  call   <is_tobequoted@plt>
  movsbl 0x0(%rbp),%edi
  add    %ebx,%eax
  test   %dil,%dil
  jne    L47
L25:
  cmpb   $0x0,(%r12)
  jne    L16
L29:
  mov    $0x1,%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
needquotes(const char *string) {
  int encapsulation = 0;
  const char *ps = string;
  if (string[0] != '\"') {
    while ((*ps) && (!(encapsulation))) {
      encapsulation = is_white(*ps) + is_tobequoted(*ps);
      ps++;
    }
  } else
    encapsulation = 0;
  if (strlen(string) == 0)
    encapsulation = 1;
  return (encapsulation);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<needquotes>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  cmp    $0x22,%dil
  je     L3
  test   %dil,%dil
  je     L17
  mov    %r12,%rbp
  jmp    L7
L4:
  test   %eax,%eax
  jne    L45
L7:
  call   <is_white@plt>
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  mov    %eax,%ebx
  call   <is_tobequoted@plt>
  movsbl 0x0(%rbp),%edi
  add    %ebx,%eax
  test   %dil,%dil
  jne    L4
L45:
  cmpb   $0x0,(%r12)
  jne    L3
L17:
  mov    $0x1,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
needquotes(const char *string) {
  int encapsulation = 0;
  const char *ps = string;
  if (string[0] != '\"') {
    while ((*ps) && (!(encapsulation))) {
      encapsulation = is_white(*ps) + is_tobequoted(*ps);
      ps++;
    }
  } else
    encapsulation = 0;
  if (strlen(string) == 0)
    encapsulation = 1;
  return (encapsulation);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<regular_char_wildcard_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <regular_char_wildcard_p@plt>
  test   %rax,%rax
  je     L15
  movzbl -0x4(%rbp),%eax
  or     $0xffffff80,%eax
  jmp    L4
L15:
  movzbl -0x4(%rbp),%eax
L4:
  leave
  ret
```

assistant: ```c
char regular_char_wildcard_encode(char c) {
  if (regular_char_wildcard_p(c)) {
    return c | ((char)0x80);
  } else {
    return c;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<regular_char_wildcard_encode>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <regular_char_wildcard_p@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  or     $0xffffff80,%eax
  test   %rdx,%rdx
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char regular_char_wildcard_encode(char c) {
  if (regular_char_wildcard_p(c)) {
    return c | ((char)0x80);
  } else {
    return c;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<regular_char_wildcard_encode>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <regular_char_wildcard_p@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  or     $0xffffff80,%eax
  test   %r8,%r8
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char regular_char_wildcard_encode(char c) {
  if (regular_char_wildcard_p(c)) {
    return c | ((char)0x80);
  } else {
    return c;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<regular_char_wildcard_encode>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <regular_char_wildcard_p@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  or     $0xffffff80,%eax
  test   %r8,%r8
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char regular_char_wildcard_encode(char c) {
  if (regular_char_wildcard_p(c)) {
    return c | ((char)0x80);
  } else {
    return c;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<remove_double_dots>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L37
L42:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L37
  jmp    L33
L22:
  addq   $0x1,-0x18(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L22
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L22
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void remove_double_dots(char *s) {
  char *p = s;
  while (*s != '\0') {
    *p++ = *s++;
    if (s[-1] == '/')
      while (*s == '.' || *s == '/')
        s++;
  }
  *p = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_double_dots>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L72
  mov    %rdi,%rcx
  jmp    L44
L50:
  movzbl 0x1(%rdi),%edx
  sub    $0x2e,%edx
  cmp    $0x1,%dl
  ja     L69
L75:
  add    $0x1,%rax
  movzbl (%rax),%esi
  lea    -0x2e(%rsi),%edx
  cmp    $0x1,%dl
  jbe    L75
  mov    %rax,%rdi
L41:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L59
L44:
  lea    0x1(%rdi),%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  cmp    $0x2f,%dl
  je     L50
  mov    %rax,%rdi
  jmp    L41
L69:
  mov    %rax,%rdi
  jmp    L41
L72:
  mov    %rdi,%rcx
L59:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void remove_double_dots(char *s) {
  char *p = s;
  while (*s != '\0') {
    *p++ = *s++;
    if (s[-1] == '/')
      while (*s == '.' || *s == '/')
        s++;
  }
  *p = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_double_dots>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
  mov    %rdi,%rdx
  jmp    L4
L11:
  test   %al,%al
  je     L33
L4:
  add    $0x1,%rdi
  lea    0x1(%rdx),%rcx
  cmp    $0x2f,%al
  mov    %al,-0x1(%rdi)
  movzbl 0x1(%rdx),%eax
  mov    %rcx,%rdx
  jne    L11
  lea    -0x2e(%rax),%edx
  cmp    $0x1,%dl
  mov    %rcx,%rdx
  ja     L11
  nopl   (%rax)
L32:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  lea    -0x2e(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L32
  test   %al,%al
  jne    L4
L33:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void remove_double_dots(char *s) {
  char *p = s;
  while (*s != '\0') {
    *p++ = *s++;
    if (s[-1] == '/')
      while (*s == '.' || *s == '/')
        s++;
  }
  *p = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_double_dots>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L54
  mov    %rdi,%rdx
  jmp    L21
L66:
  test   %al,%al
  je     L54
L21:
  add    $0x1,%rdi
  lea    0x1(%rdx),%rcx
  cmp    $0x2f,%al
  mov    %al,-0x1(%rdi)
  movzbl 0x1(%rdx),%eax
  mov    %rcx,%rdx
  jne    L66
  lea    -0x2e(%rax),%edx
  cmp    $0x1,%dl
  mov    %rcx,%rdx
  ja     L66
  nopl   (%rax)
L37:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  lea    -0x2e(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L37
  test   %al,%al
  jne    L21
L54:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void remove_double_dots(char *s) {
  char *p = s;
  while (*s != '\0') {
    *p++ = *s++;
    if (s[-1] == '/')
      while (*s == '.' || *s == '/')
        s++;
  }
  *p = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<filename_to_title>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  jmp    L27
L9:
  addq   $0x1,-0x28(%rbp)
L27:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L72
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L9
  jmp    L72
L30:
  addq   $0x1,-0x28(%rbp)
L72:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L30
  jmp    L54
L87:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x19(%rbp),%edx
  mov    %dl,(%rax)
L54:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L87
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L23:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *filename_to_title(const char *filename) {
  char *title = malloc(strlen(filename) * 2 + 1);
  char *s, *out = title;
  s = strrchr(filename, '/');
  if (s)
    filename = s + 1;
  while (*filename >= '0' && *filename <= '9')
    filename++;
  while (*filename == ' ')
    filename++;
  while (*filename) {
    char c = *filename++;
    *out++ = c;
  }
  *out = 0;
  s = strrchr(title, '.');
  if (s)
    *s = 0;
  return title;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<filename_to_title>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L51
L72:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L72
L51:
  cmpb   $0x20,(%rbx)
  jne    L60
L29:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L29
L60:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L24
  mov    %rbp,%rdx
L2:
  add    $0x1,%rbx
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L2
L57:
  movb   $0x0,(%rdx)
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L36
  movb   $0x0,(%rax)
L36:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    %rbp,%rdx
  jmp    L57
```

assistant: ```c
char *filename_to_title(const char *filename) {
  char *title = malloc(strlen(filename) * 2 + 1);
  char *s, *out = title;
  s = strrchr(filename, '/');
  if (s)
    filename = s + 1;
  while (*filename >= '0' && *filename <= '9')
    filename++;
  while (*filename == ' ')
    filename++;
  while (*filename) {
    char c = *filename++;
    *out++ = c;
  }
  *out = 0;
  s = strrchr(title, '.');
  if (s)
    *s = 0;
  return title;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<filename_to_title>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    $0x2f,%esi
  mov    %rax,%r12
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  movzbl (%rbx),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L15
  nopw   0x0(%rax,%rax,1)
L68:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L68
  cmp    $0x20,%al
  jne    L57
  nopl   0x0(%rax)
L34:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
L15:
  cmp    $0x20,%al
  je     L34
L57:
  mov    %r12,%rdx
  test   %al,%al
  je     L19
  nopl   0x0(%rax,%rax,1)
L48:
  add    $0x1,%rbx
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L48
L19:
  movb   $0x0,(%rdx)
  mov    $0x2e,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L25
  movb   $0x0,(%rax)
L25:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *filename_to_title(const char *filename) {
  char *title = malloc(strlen(filename) * 2 + 1);
  char *s, *out = title;
  s = strrchr(filename, '/');
  if (s)
    filename = s + 1;
  while (*filename >= '0' && *filename <= '9')
    filename++;
  while (*filename == ' ')
    filename++;
  while (*filename) {
    char c = *filename++;
    *out++ = c;
  }
  *out = 0;
  s = strrchr(title, '.');
  if (s)
    *s = 0;
  return title;
}
```
user: What is the c source code of the assembly code below:

```asm
<filename_to_title>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    $0x2f,%esi
  mov    %rax,%r12
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  movzbl (%rbx),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L9
  nopw   0x0(%rax,%rax,1)
L35:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L35
  cmp    $0x20,%al
  jne    L63
  nopl   0x0(%rax)
L23:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
L9:
  cmp    $0x20,%al
  je     L23
L63:
  mov    %r12,%rdx
  test   %al,%al
  je     L60
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rbx
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L45
L60:
  movb   $0x0,(%rdx)
  mov    $0x2e,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L19
  movb   $0x0,(%rax)
L19:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *filename_to_title(const char *filename) {
  char *title = malloc(strlen(filename) * 2 + 1);
  char *s, *out = title;
  s = strrchr(filename, '/');
  if (s)
    filename = s + 1;
  while (*filename >= '0' && *filename <= '9')
    filename++;
  while (*filename == ' ')
    filename++;
  while (*filename) {
    char c = *filename++;
    *out++ = c;
  }
  *out = 0;
  s = strrchr(title, '.');
  if (s)
    *s = 0;
  return title;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L8:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
L2:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L28
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L8
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void readstr(out, in, limit) char out[];
char **in;
int limit;
{
  int i;
  i = 0;
  while ((isalpha(**in)) && (i < limit - 1)) {
    out[i] = **in;
    i = i + 1;
    *in = *in + 1;
  };
  out[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readstr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    -0x1(%rdx),%r15d
  jmp    L6
L14:
  mov    %r12b,(%r14,%rbx,1)
  addq   $0x1,0x0(%rbp)
  add    $0x1,%rbx
L6:
  mov    %ebx,%r13d
  mov    0x0(%rbp),%rax
  movzbl (%rax),%r12d
  movsbl %r12b,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L13
  cmp    %ebx,%r15d
  jg     L14
L13:
  movslq %r13d,%r13
  movb   $0x0,(%r14,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void readstr(out, in, limit) char out[];
char **in;
int limit;
{
  int i;
  i = 0;
  while ((isalpha(**in)) && (i < limit - 1)) {
    out[i] = **in;
    i = i + 1;
    *in = *in + 1;
  };
  out[i] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readstr>:
  endbr64
  push   %r14
  mov    (%rsi),%rax
  mov    %rsi,%r14
  push   %r13
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L21
  xchg   %ax,%ax
L4:
  add    $0x1,%rbx
  mov    %ebx,%eax
  sub    %ebp,%eax
  sub    $0x1,%eax
  cmp    %eax,%r12d
  jle    L11
  mov    %r13b,-0x1(%rbx)
  mov    (%r14),%rax
  add    $0x1,%rax
  mov    %rax,(%r14)
L21:
  movsbl (%rax),%edi
  mov    %edi,%r13d
  call   <isalpha@plt>
  mov    %rbx,%rdx
  test   %eax,%eax
  jne    L4
L11:
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void readstr(out, in, limit) char out[];
char **in;
int limit;
{
  int i;
  i = 0;
  while ((isalpha(**in)) && (i < limit - 1)) {
    out[i] = **in;
    i = i + 1;
    *in = *in + 1;
  };
  out[i] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readstr>:
  endbr64
  push   %r14
  mov    (%rsi),%rax
  mov    %rsi,%r14
  push   %r13
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L25
  xchg   %ax,%ax
L0:
  add    $0x1,%rbx
  mov    %ebx,%eax
  sub    %ebp,%eax
  sub    $0x1,%eax
  cmp    %eax,%r12d
  jle    L21
  mov    %r13b,-0x1(%rbx)
  mov    (%r14),%rax
  add    $0x1,%rax
  mov    %rax,(%r14)
L25:
  movsbl (%rax),%edi
  mov    %edi,%r13d
  call   <isalpha@plt>
  mov    %rbx,%rdx
  test   %eax,%eax
  jne    L0
L21:
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void readstr(out, in, limit) char out[];
char **in;
int limit;
{
  int i;
  i = 0;
  while ((isalpha(**in)) && (i < limit - 1)) {
    out[i] = **in;
    i = i + 1;
    *in = *in + 1;
  };
  out[i] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<radius_effective>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  movsd  %xmm1,-0x18(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L0
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  jmp    L7
L0:
  movsd  -0x10(%rbp),%xmm0
L7:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double radius_effective(int mode, double radius, double thickness) {
  switch (mode) {
  default:
  case 1:
    return radius + thickness;
  case 2:
    return radius;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<radius_effective>:
  endbr64
  cmp    $0x2,%edi
  je     L9
  addsd  %xmm1,%xmm0
L9:
  ret
```

assistant: ```c
double radius_effective(int mode, double radius, double thickness) {
  switch (mode) {
  default:
  case 1:
    return radius + thickness;
  case 2:
    return radius;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<radius_effective>:
  endbr64
  cmp    $0x2,%edi
  je     L8
  addsd  %xmm1,%xmm0
L8:
  ret
```

assistant: ```c
double radius_effective(int mode, double radius, double thickness) {
  switch (mode) {
  default:
  case 1:
    return radius + thickness;
  case 2:
    return radius;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<radius_effective>:
  endbr64
  cmp    $0x2,%edi
  je     L9
  addsd  %xmm1,%xmm0
L9:
  ret
```

assistant: ```c
double radius_effective(int mode, double radius, double thickness) {
  switch (mode) {
  default:
  case 1:
    return radius + thickness;
  case 2:
    return radius;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nextturn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L62
L41:
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L2:
  mov    $0x1,%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%esi
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <islegal@plt>
  test   %rax,%rax
  je     L40
  addl   $0x1,-0x4(%rbp)
L40:
  addl   $0x1,-0x8(%rbp)
L28:
  cmpl   $0x7,-0x8(%rbp)
  jle    L2
  addl   $0x1,-0xc(%rbp)
L62:
  cmpl   $0x7,-0xc(%rbp)
  jle    L41
  cmpl   $0x0,-0x4(%rbp)
  je     L46
  mov    $0x1,%eax
  sub    -0x1c(%rbp),%eax
  jmp    L20
L46:
  mov    -0x1c(%rbp),%eax
L20:
  leave
  ret
```

assistant: ```c
int nextturn(int board[8][8], int turn) {
  int i, j, count = 0;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      if (islegal(i, j, board, 1 - turn))
        count++;
  if (count)
    return 1 - turn;
  else
    return turn;
}
```
user: What is the c source code of the assembly code below:

```asm
<nextturn>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,0xc(%rsp)
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  mov    $0x1,%r15d
L10:
  mov    $0x0,%ebx
L3:
  mov    %r15d,%ebp
  sub    0xc(%rsp),%ebp
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <islegal@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L3
  add    $0x1,%r13d
  cmp    $0x8,%r13d
  jne    L10
  test   %r12d,%r12d
  cmove  0xc(%rsp),%ebp
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nextturn(int board[8][8], int turn) {
  int i, j, count = 0;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      if (islegal(i, j, board, 1 - turn))
        count++;
  if (count)
    return 1 - turn;
  else
    return turn;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nextturn>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  sub    %esi,%r15d
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%edi
  call   <islegal@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L7
  add    $0x1,%r12d
  cmp    $0x8,%r12d
  jne    L13
  test   %ebp,%ebp
  cmove  %r14d,%r15d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r15d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nextturn(int board[8][8], int turn) {
  int i, j, count = 0;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      if (islegal(i, j, board, 1 - turn))
        count++;
  if (count)
    return 1 - turn;
  else
    return turn;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextturn>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  sub    %esi,%r15d
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L10:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%edi
  call   <islegal@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L4
  add    $0x1,%r12d
  cmp    $0x8,%r12d
  jne    L10
  test   %ebp,%ebp
  cmove  %r14d,%r15d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r15d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nextturn(int board[8][8], int turn) {
  int i, j, count = 0;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      if (islegal(i, j, board, 1 - turn))
        count++;
  if (count)
    return 1 - turn;
  else
    return turn;
}
```