ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <lire_entier@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <lire_entier@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <lire_entier@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L31
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L86
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L20
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L62
L20:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L62
L86:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L62
L31:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L36
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L62
L36:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L82
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L62
L82:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L62:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: Le max est %d et le min est %d 


assistant: ```c
int main() {
  int a, b, c, max, min;
  a = lire_entier();
  b = lire_entier();
  c = lire_entier();
  if (a < b) {
    if (a < c) {
      min = a;
      if (b < c)
        max = c;
      else
        max = b;
    } else {
      min = c;
      max = b;
    }
  } else {
    if (a < c) {
      min = b;
      max = c;
    } else if (b < c) {
      min = b;
      max = a;
    } else {
      min = c;
      max = a;
    }
  }
  printf("Le max est %d et le min est %d \n", max, min);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <lire_entier@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <lire_entier@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <lire_entier@plt>
  mov    %eax,%edx
  cmp    %ebx,%ebp
  jge    L40
  cmp    %eax,%ebp
  jge    L8
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  mov    %ebp,%edx
  jmp    L8
L40:
  cmp    %eax,%ebp
  jl     L30
  cmp    %ebx,%eax
  cmovg  %ebx,%edx
  mov    %ebp,%ebx
  jmp    L8
L30:
  mov    %ebx,%eax
  mov    %edx,%ebx
  mov    %eax,%edx
L8:
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: Le max est %d et le min est %d 


assistant: ```c
int main() {
  int a, b, c, max, min;
  a = lire_entier();
  b = lire_entier();
  c = lire_entier();
  if (a < b) {
    if (a < c) {
      min = a;
      if (b < c)
        max = c;
      else
        max = b;
    } else {
      min = c;
      max = b;
    }
  } else {
    if (a < c) {
      min = b;
      max = c;
    } else if (b < c) {
      min = b;
      max = a;
    } else {
      min = c;
      max = a;
    }
  }
  printf("Le max est %d et le min est %d \n", max, min);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <lire_entier@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <lire_entier@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <lire_entier@plt>
  mov    %eax,%edx
  cmp    %ebp,%ebx
  jge    L23
  cmp    %eax,%ebx
  jge    L32
  cmp    %eax,%ebp
  mov    %ebx,%edx
  cmovl  %eax,%ebp
L32:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  cmp    %eax,%ebx
  jge    L25
  xchg   %edx,%ebp
  jmp    L32
L25:
  cmp    %ebp,%eax
  cmovg  %ebp,%edx
  mov    %ebx,%ebp
  jmp    L32
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: Le max est %d et le min est %d 


assistant: ```c
int main() {
  int a, b, c, max, min;
  a = lire_entier();
  b = lire_entier();
  c = lire_entier();
  if (a < b) {
    if (a < c) {
      min = a;
      if (b < c)
        max = c;
      else
        max = b;
    } else {
      min = c;
      max = b;
    }
  } else {
    if (a < c) {
      min = b;
      max = c;
    } else if (b < c) {
      min = b;
      max = a;
    } else {
      min = c;
      max = a;
    }
  }
  printf("Le max est %d et le min est %d \n", max, min);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <lire_entier@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <lire_entier@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <lire_entier@plt>
  mov    %eax,%edx
  cmp    %ebp,%ebx
  jge    L23
  cmp    %eax,%ebx
  jge    L35
  cmp    %eax,%ebp
  mov    %ebx,%edx
  cmovl  %eax,%ebp
L35:
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  cmp    %eax,%ebx
  jge    L46
  xchg   %edx,%ebp
  jmp    L35
L46:
  cmp    %ebp,%eax
  cmovg  %ebp,%edx
  mov    %ebx,%ebp
  jmp    L35
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: Le max est %d et le min est %d 


assistant: ```c
int main() {
  int a, b, c, max, min;
  a = lire_entier();
  b = lire_entier();
  c = lire_entier();
  if (a < b) {
    if (a < c) {
      min = a;
      if (b < c)
        max = c;
      else
        max = b;
    } else {
      min = c;
      max = b;
    }
  } else {
    if (a < c) {
      min = b;
      max = c;
    } else if (b < c) {
      min = b;
      max = a;
    } else {
      min = c;
      max = a;
    }
  }
  printf("Le max est %d et le min est %d \n", max, min);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_check_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  jmp    L38
L46:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L53
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L23
L53:
  addl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x4,-0x8(%rbp)
  jle    L1
  mov    $0x0,%eax
  jmp    L76
L1:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L21
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L21
  movl   $0x0,-0x8(%rbp)
  addl   $0x5,-0x4(%rbp)
L21:
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    $0x1,%eax
L76:
  pop    %rbp
  ret
```

assistant: ```c
int ft_check_line(char *s) {
  int i;
  int j;
  int add_5;
  i = 0;
  j = 0;
  add_5 = 4;
  while (s[i] != '\0') {
    if (s[i] == '.' || s[i] == '#')
      j++;
    if (j > 4)
      return (0);
    if (s[i] == '\n' && i == add_5) {
      j = 0;
      add_5 += 5;
    }
    i++;
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_check_line>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L76
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    $0x0,%ecx
  jmp    L15
L77:
  add    $0x1,%ecx
L94:
  cmp    $0x4,%ecx
  jg     L61
  cmp    %edx,%esi
  jne    L7
  cmp    $0xa,%al
  je     L91
L7:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L42
L15:
  cmp    $0x2e,%al
  je     L77
  cmp    $0x23,%al
  jne    L94
  jmp    L77
L91:
  add    $0x5,%esi
  mov    $0x0,%ecx
  jmp    L7
L42:
  mov    $0x1,%eax
  ret
L76:
  mov    $0x1,%eax
  ret
L61:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_check_line(char *s) {
  int i;
  int j;
  int add_5;
  i = 0;
  j = 0;
  add_5 = 4;
  while (s[i] != '\0') {
    if (s[i] == '.' || s[i] == '#')
      j++;
    if (j > 4)
      return (0);
    if (s[i] == '\n' && i == add_5) {
      j = 0;
      add_5 += 5;
    }
    i++;
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_check_line>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L41
  xor    %edx,%edx
  mov    $0x4,%esi
  xor    %ecx,%ecx
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L60:
  cmp    $0x5,%ecx
  je     L39
L8:
  cmp    $0xa,%al
  jne    L28
  cmp    %edx,%esi
  je     L21
L28:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L41
L45:
  cmp    $0x2e,%al
  je     L86
  cmp    $0x23,%al
  jne    L60
L86:
  add    $0x1,%ecx
  cmp    $0x5,%ecx
  jne    L8
L39:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L21:
  add    $0x1,%rdx
  add    $0x5,%esi
  xor    %ecx,%ecx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L45
L41:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ft_check_line(char *s) {
  int i;
  int j;
  int add_5;
  i = 0;
  j = 0;
  add_5 = 4;
  while (s[i] != '\0') {
    if (s[i] == '.' || s[i] == '#')
      j++;
    if (j > 4)
      return (0);
    if (s[i] == '\n' && i == add_5) {
      j = 0;
      add_5 += 5;
    }
    i++;
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_check_line>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
  xor    %edx,%edx
  mov    $0x4,%esi
  xor    %ecx,%ecx
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L47:
  cmp    $0x5,%ecx
  je     L41
L82:
  cmp    $0xa,%al
  jne    L49
  cmp    %edx,%esi
  je     L32
L49:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L26
L37:
  cmp    $0x2e,%al
  je     L17
  cmp    $0x23,%al
  jne    L47
L17:
  add    $0x1,%ecx
  cmp    $0x5,%ecx
  jne    L82
L41:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L32:
  add    $0x1,%rdx
  add    $0x5,%esi
  xor    %ecx,%ecx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L37
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ft_check_line(char *s) {
  int i;
  int j;
  int add_5;
  i = 0;
  j = 0;
  add_5 = 4;
  while (s[i] != '\0') {
    if (s[i] == '.' || s[i] == '#')
      j++;
    if (j > 4)
      return (0);
    if (s[i] == '\n' && i == add_5) {
      j = 0;
      add_5 += 5;
    }
    i++;
  }
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<syncall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x11,%edi
  call   <put_serverbyte@plt>
  mov    $0x13,%edi
  call   <put_serverbyte@plt>
  mov    $0x0,%eax
  call   <get_serverbyte@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void syncall() {
  put_serverbyte(0x11);
  put_serverbyte(0x13);
  (void)get_serverbyte();
}
```
user: Translate the below assembly code into C programming language:

```asm
<syncall>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <put_serverbyte@plt>
  mov    $0x13,%edi
  call   <put_serverbyte@plt>
  mov    $0x0,%eax
  call   <get_serverbyte@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void syncall() {
  put_serverbyte(0x11);
  put_serverbyte(0x13);
  (void)get_serverbyte();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<syncall>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <put_serverbyte@plt>
  mov    $0x13,%edi
  call   <put_serverbyte@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <get_serverbyte@plt>
```

assistant: ```c
void syncall() {
  put_serverbyte(0x11);
  put_serverbyte(0x13);
  (void)get_serverbyte();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<syncall>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <put_serverbyte@plt>
  mov    $0x13,%edi
  call   <put_serverbyte@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <get_serverbyte@plt>
```

assistant: ```c
void syncall() {
  put_serverbyte(0x11);
  put_serverbyte(0x13);
  (void)get_serverbyte();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str2dbl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    $0x0,%edx
  mov    $0x2e,%esi
  call   <firstIndexOf@plt>
  mov    %eax,0x8(%rsp)
  movzbl (%r12),%r15d
  cmp    $0x2d,%r15b
  sete   %r13b
  sete   %bpl
  movzbl %bpl,%ebp
  cmp    $0xffffffff,%eax
  je     L84
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%ebx
  sub    %ebp,%ebx
  cmp    %ebp,%eax
  jle    L74
  movzbl %r13b,%ebp
  add    %r12,%rbp
  movzbl %r13b,%ecx
  mov    %ecx,0xc(%rsp)
  mov    %ecx,%r14d
  sub    %eax,%r14d
  add    %ebx,%r14d
  pxor   %xmm5,%xmm5
  movsd  %xmm5,(%rsp)
L72:
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movsbl 0x0(%rbp),%edx
  sub    $0x30,%edx
  movsbl %al,%eax
  imul   %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  sub    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r14d,%ebx
  jne    L72
  movzbl %r13b,%r13d
  sub    0xc(%rsp),%r13d
  mov    0x8(%rsp),%ebp
  add    %r13d,%ebp
L32:
  lea    0x1(%rbp),%ebx
  movslq %ebx,%rbx
  jmp    L81
L84:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  sub    %ebp,%ebx
  js     L63
  movzbl %r13b,%r13d
  add    %r12,%r13
  pxor   %xmm6,%xmm6
  movsd  %xmm6,(%rsp)
L13:
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movsbl 0x0(%r13),%edx
  sub    $0x30,%edx
  movsbl %al,%eax
  imul   %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  sub    $0x1,%ebx
  add    $0x1,%r13
  cmp    $0xffffffff,%ebx
  jne    L13
  jmp    L102
L74:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
  jmp    L32
L22:
  mov    %r13d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movsbl (%r12,%rbx,1),%edx
  sub    $0x30,%edx
  movsbl %al,%eax
  imul   %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%rbx
L81:
  mov    %ebp,%r13d
  sub    %ebx,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L22
L102:
  cmp    $0x2d,%r15b
  jne    L75
  movsd  (%rsp),%xmm4
  xorpd  D5(%rip),%xmm4
  movsd  %xmm4,(%rsp)
L75:
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
  jmp    L102
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: f32[4]

tool: {"D5": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double str2dbl(char *str) {
  int j = 0, i, n = firstIndexOf(str, '.', 0), neg = 0;
  double result = 0;
  if (str[0] == '-') {
    neg = 1;
    j = 1;
  }
  if (n == -1) {
    n = strlen(str);
    for (i = n - 1 - neg; i >= 0; i--) {
      result += pow(10, i) * (str[j] - 48);
      j++;
    }
  } else {
    j = n - 1 - neg;
    for (i = neg ? 1 : 0; i < n; i++) {
      result += pow(10, j) * (str[i] - 48);
      j--;
    }
    i++;
    j = -1;
    for (i = i; i < strlen(str); i++) {
      result += pow(10, j) * (str[i] - 48);
      j--;
    }
  }
  if (neg)
    result *= -1;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str2dbl>:
  endbr64
  push   %r15
  xor    %edx,%edx
  mov    $0x2e,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <firstIndexOf@plt>
  movzbl (%rbx),%r12d
  cmp    $0x2d,%r12b
  sete   %r13b
  sete   %r15b
  movzbl %r13b,%r13d
  cmp    $0xffffffff,%eax
  je     L0
  lea    -0x1(%rax),%r14d
  mov    %eax,%ebp
  sub    %r13d,%r14d
  cmp    %eax,%r13d
  jge    L69
  movzbl %r15b,%r15d
  sub    %eax,%r13d
  pxor   %xmm5,%xmm5
  add    %rbx,%r15
  add    %r14d,%r13d
  movsd  %xmm5,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L73:
  mov    %r14d,%esi
  mov    $0xa,%edi
  sub    $0x1,%r14d
  add    $0x1,%r15
  call   <pow@plt>
  movsbl -0x1(%r15),%edx
  pxor   %xmm0,%xmm0
  movsbl %al,%eax
  sub    $0x30,%edx
  imul   %eax,%edx
  cvtsi2sd %edx,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %r13d,%r14d
  jne    L73
L29:
  lea    0x1(%rbp),%r13d
  movslq %r13d,%r13
  jmp    L59
  nopl   (%rax)
L58:
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movsbl (%rbx,%r13,1),%edx
  pxor   %xmm0,%xmm0
  add    $0x1,%r13
  movsbl %al,%eax
  sub    $0x30,%edx
  imul   %eax,%edx
  cvtsi2sd %edx,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
L59:
  mov    %ebp,%r14d
  mov    %rbx,%rdi
  sub    %r13d,%r14d
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L58
L32:
  cmp    $0x2d,%r12b
  jne    L80
  movsd  0x8(%rsp),%xmm4
  xorpd  D6(%rip),%xmm4
  movsd  %xmm4,0x8(%rsp)
L80:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L0:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  sub    %r13d,%ebp
  js     L44
  movzbl %r15b,%r15d
  pxor   %xmm6,%xmm6
  add    %r15,%rbx
  movsd  %xmm6,0x8(%rsp)
  nopl   0x0(%rax)
L1:
  mov    %ebp,%esi
  mov    $0xa,%edi
  sub    $0x1,%ebp
  add    $0x1,%rbx
  call   <pow@plt>
  movsbl -0x1(%rbx),%edx
  pxor   %xmm0,%xmm0
  movsbl %al,%eax
  sub    $0x30,%edx
  imul   %eax,%edx
  cvtsi2sd %edx,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    $0xffffffff,%ebp
  jne    L1
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L69:
  pxor   %xmm7,%xmm7
  mov    %r13d,%ebp
  movsd  %xmm7,0x8(%rsp)
  jmp    L29
L44:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L32
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: f32[4]

tool: {"D6": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double str2dbl(char *str) {
  int j = 0, i, n = firstIndexOf(str, '.', 0), neg = 0;
  double result = 0;
  if (str[0] == '-') {
    neg = 1;
    j = 1;
  }
  if (n == -1) {
    n = strlen(str);
    for (i = n - 1 - neg; i >= 0; i--) {
      result += pow(10, i) * (str[j] - 48);
      j++;
    }
  } else {
    j = n - 1 - neg;
    for (i = neg ? 1 : 0; i < n; i++) {
      result += pow(10, j) * (str[i] - 48);
      j--;
    }
    i++;
    j = -1;
    for (i = i; i < strlen(str); i++) {
      result += pow(10, j) * (str[i] - 48);
      j--;
    }
  }
  if (neg)
    result *= -1;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<str2dbl>:
  endbr64
  push   %r15
  xor    %edx,%edx
  mov    $0x2e,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <firstIndexOf@plt>
  movzbl (%rbx),%r12d
  cmp    $0x2d,%r12b
  sete   %r13b
  sete   %r15b
  movzbl %r13b,%r13d
  cmp    $0xffffffff,%eax
  je     L108
  lea    -0x1(%rax),%r14d
  mov    %eax,%ebp
  sub    %r13d,%r14d
  cmp    %eax,%r13d
  jge    L94
  movzbl %r15b,%r15d
  sub    %eax,%r13d
  pxor   %xmm5,%xmm5
  add    %rbx,%r15
  add    %r14d,%r13d
  movsd  %xmm5,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r14d,%esi
  mov    $0xa,%edi
  sub    $0x1,%r14d
  add    $0x1,%r15
  call   <pow@plt>
  movsbl -0x1(%r15),%edx
  pxor   %xmm0,%xmm0
  movsbl %al,%eax
  sub    $0x30,%edx
  imul   %eax,%edx
  cvtsi2sd %edx,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %r13d,%r14d
  jne    L22
L46:
  lea    0x1(%rbp),%r13d
  movslq %r13d,%r13
  jmp    L67
  nopl   (%rax)
L79:
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  movsbl (%rbx,%r13,1),%edx
  pxor   %xmm0,%xmm0
  add    $0x1,%r13
  movsbl %al,%eax
  sub    $0x30,%edx
  imul   %eax,%edx
  cvtsi2sd %edx,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
L67:
  mov    %ebp,%r14d
  mov    %rbx,%rdi
  sub    %r13d,%r14d
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L79
L39:
  cmp    $0x2d,%r12b
  jne    L71
  movsd  0x8(%rsp),%xmm4
  xorpd  D0(%rip),%xmm4
  movsd  %xmm4,0x8(%rsp)
L71:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L108:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  sub    %r13d,%ebp
  js     L30
  movzbl %r15b,%r15d
  pxor   %xmm6,%xmm6
  add    %r15,%rbx
  movsd  %xmm6,0x8(%rsp)
  nopl   0x0(%rax)
L73:
  mov    %ebp,%esi
  mov    $0xa,%edi
  sub    $0x1,%ebp
  add    $0x1,%rbx
  call   <pow@plt>
  movsbl -0x1(%rbx),%edx
  pxor   %xmm0,%xmm0
  movsbl %al,%eax
  sub    $0x30,%edx
  imul   %eax,%edx
  cvtsi2sd %edx,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    $0xffffffff,%ebp
  jne    L73
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L94:
  pxor   %xmm7,%xmm7
  mov    %r13d,%ebp
  movsd  %xmm7,0x8(%rsp)
  jmp    L46
L30:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L39
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: f32[4]

tool: {"D0": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double str2dbl(char *str) {
  int j = 0, i, n = firstIndexOf(str, '.', 0), neg = 0;
  double result = 0;
  if (str[0] == '-') {
    neg = 1;
    j = 1;
  }
  if (n == -1) {
    n = strlen(str);
    for (i = n - 1 - neg; i >= 0; i--) {
      result += pow(10, i) * (str[j] - 48);
      j++;
    }
  } else {
    j = n - 1 - neg;
    for (i = neg ? 1 : 0; i < n; i++) {
      result += pow(10, j) * (str[i] - 48);
      j--;
    }
    i++;
    j = -1;
    for (i = i; i < strlen(str); i++) {
      result += pow(10, j) * (str[i] - 48);
      j--;
    }
  }
  if (neg)
    result *= -1;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UART_OutChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  nop
L1:
  mov    $0x4000c018,%eax
  mov    (%rax),%eax
  and    $0x20,%eax
  test   %eax,%eax
  jne    L1
  mov    $0x4000c000,%edx
  movsbl -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UART_OutChar(char data) {
  while (((*((volatile uint32_t *)0x4000C018)) & 0x00000020) != 0)
    ;
  (*((volatile uint32_t *)0x4000C000)) = data;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UART_OutChar>:
  endbr64
L2:
  mov    0x4000c018,%eax
  test   $0x20,%al
  jne    L2
  movsbl %dil,%edi
  mov    %edi,0x4000c000
  ret
```

assistant: ```c
void UART_OutChar(char data) {
  while (((*((volatile uint32_t *)0x4000C018)) & 0x00000020) != 0)
    ;
  (*((volatile uint32_t *)0x4000C000)) = data;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UART_OutChar>:
  endbr64
  nopl   0x0(%rax)
L1:
  mov    0x4000c018,%eax
  test   $0x20,%al
  jne    L1
  movsbl %dil,%edi
  mov    %edi,0x4000c000
  ret
```

assistant: ```c
void UART_OutChar(char data) {
  while (((*((volatile uint32_t *)0x4000C018)) & 0x00000020) != 0)
    ;
  (*((volatile uint32_t *)0x4000C000)) = data;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UART_OutChar>:
  endbr64
  nopl   0x0(%rax)
L0:
  mov    0x4000c018,%eax
  test   $0x20,%al
  jne    L0
  movsbl %dil,%edi
  mov    %edi,0x4000c000
  ret
```

assistant: ```c
void UART_OutChar(char data) {
  while (((*((volatile uint32_t *)0x4000C018)) & 0x00000020) != 0)
    ;
  (*((volatile uint32_t *)0x4000C000)) = data;
}
```