ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<left_rotate>:
  endbr64
  cmp    %edx,%esi
  je     L20
  mov    %edx,%eax
  push   %r14
  cltd
  push   %r13
  idiv   %esi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r13d
  cmp    %edx,%esi
  jle    L10
  sub    $0x1,%esi
  movslq %edx,%rax
  lea    D5(%rip),%r12
  sub    %edx,%esi
  lea    (%rdi,%rax,4),%rbp
  add    %rax,%rsi
  lea    0x4(%rdi,%rsi,4),%r14
  xchg   %ax,%ax
L7:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L7
L10:
  test   %r13d,%r13d
  jle    L18
  lea    -0x1(%r13),%eax
  lea    D5(%rip),%r12
  lea    0x4(%rbx,%rax,4),%rbp
  nopl   0x0(%rax)
L31:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L31
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L20:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string

tool: D5: %d 

assistant: ```c
void left_rotate(int *arr, int size, int rotation) {
  if (size != rotation) {
    for (int i = rotation % size; i < size; i++) {
      printf("%d ", arr[i]);
    }
    for (int j = 0; j < rotation % size; j++) {
      printf("%d ", arr[j]);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<left_rotate>:
  endbr64
  cmp    %edx,%esi
  je     L16
  mov    %edx,%eax
  push   %r14
  cltd
  push   %r13
  idiv   %esi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r13d
  cmp    %edx,%esi
  jle    L24
  sub    $0x1,%esi
  movslq %edx,%rax
  lea    D19(%rip),%r12
  sub    %edx,%esi
  lea    (%rdi,%rax,4),%rbp
  add    %rax,%rsi
  lea    0x4(%rdi,%rsi,4),%r14
  xchg   %ax,%ax
L8:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L8
L24:
  test   %r13d,%r13d
  jle    L35
  lea    -0x1(%r13),%eax
  lea    D19(%rip),%r12
  lea    0x4(%rbx,%rax,4),%rbp
  nopl   0x0(%rax)
L33:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L33
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L16:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
datatype: string

tool: D19: %d 

assistant: ```c
void left_rotate(int *arr, int size, int rotation) {
  if (size != rotation) {
    for (int i = rotation % size; i < size; i++) {
      printf("%d ", arr[i]);
    }
    for (int j = 0; j < rotation % size; j++) {
      printf("%d ", arr[j]);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<countSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%r8
  and    $0xfffffffffffffff0,%r8
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L36:
  cmp    %rdx,%rsp
  je     L79
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L79:
  mov    %r8,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L52
  orq    $0x0,-0x8(%rsp,%rax,1)
L52:
  mov    %rsp,%r8
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  test   %esi,%esi
  jle    L45
  mov    %rdi,%r9
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
L80:
  mov    (%r9),%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%eax
  movslq %eax,%rdx
  addl   $0x1,-0x30(%rbp,%rdx,4)
  add    $0x4,%r9
  cmp    %r10,%r9
  jne    L80
L45:
  lea    -0x2c(%rbp),%rax
  lea    -0x8(%rbp),%r9
L103:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L103
  mov    %esi,%r9d
  sub    $0x1,%r9d
  js     L74
  movslq %r9d,%r9
L15:
  mov    (%rdi,%r9,4),%r10d
  mov    %r10d,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp,%rdx,4),%eax
  sub    $0x1,%eax
  movslq %eax,%r11
  mov    %r10d,(%r8,%r11,4)
  mov    %eax,-0x30(%rbp,%rdx,4)
  sub    $0x1,%r9
  test   %r9d,%r9d
  jns    L15
L74:
  test   %esi,%esi
  jle    L89
  mov    %esi,%esi
  mov    $0x0,%eax
L61:
  mov    (%r8,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L61
L89:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  leave
  ret
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void countSort(int arr[], int n, int exp) {
  int output[n];
  int i, count[10] = {0};
  for (i = 0; i < n; ++i)
    count[(arr[i] / exp) % 10]++;
  for (i = 1; i < 10; ++i)
    count[i] += count[i - 1];
  for (i = (n - 1); i >= 0; --i) {
    output[count[(arr[i] / exp) % 10] - 1] = arr[i];
    count[(arr[i] / exp) % 10]--;
  }
  for (i = 0; i < n; ++i)
    arr[i] = output[i];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<countSort>:
  endbr64
  push   %rbp
  movslq %esi,%r9
  mov    %edx,%ecx
  mov    %r9,%r8
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r9,4),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L91
L112:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L112
L91:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L87
L47:
  pxor   %xmm0,%xmm0
  movq   $0x0,-0x20(%rbp)
  mov    %rsp,%rsi
  movaps %xmm0,-0x40(%rbp)
  movaps %xmm0,-0x30(%rbp)
  test   %r8d,%r8d
  jle    L107
  lea    -0x1(%r8),%eax
  mov    %rdi,%r10
  mov    %rax,%rbx
  lea    0x4(%rdi,%rax,4),%r11
  nopl   0x0(%rax)
L124:
  mov    (%r10),%eax
  add    $0x4,%r10
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  mov    %eax,%r12d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r12d
  sar    $0x22,%rdx
  sub    %r12d,%edx
  lea    (%rdx,%rdx,4),%r12d
  add    %r12d,%r12d
  sub    %r12d,%eax
  movslq %eax,%rdx
  addl   $0x1,-0x40(%rbp,%rdx,4)
  cmp    %r10,%r11
  jne    L124
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%r10d
L44:
  lea    -0x3c(%rbp),%rax
  lea    -0x18(%rbp),%r11
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L108:
  mov    (%rax),%edx
  mov    -0x4(%rax),%r10d
L33:
  add    %r10d,%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %r11,%rax
  jne    L108
  movslq %ebx,%r10
  test   %ebx,%ebx
  js     L64
  nopl   0x0(%rax)
L30:
  mov    (%rdi,%r10,4),%r11d
  sub    $0x1,%r10
  mov    %r11d,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  mov    %eax,%ebx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ebx
  sar    $0x22,%rdx
  sub    %ebx,%edx
  lea    (%rdx,%rdx,4),%ebx
  add    %ebx,%ebx
  sub    %ebx,%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp,%rdx,4),%eax
  sub    $0x1,%eax
  movslq %eax,%rbx
  mov    %eax,-0x40(%rbp,%rdx,4)
  mov    %r11d,(%rsi,%rbx,4)
  test   %r10d,%r10d
  jns    L30
L64:
  test   %r8d,%r8d
  jle    L9
  lea    0x0(,%r9,4),%rdx
  call   <memcpy@plt>
L9:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  xchg   %ax,%ax
L87:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L47
L107:
  xor    %r10d,%r10d
  xor    %edx,%edx
  lea    -0x1(%r8),%ebx
  jmp    L44
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void countSort(int arr[], int n, int exp) {
  int output[n];
  int i, count[10] = {0};
  for (i = 0; i < n; ++i)
    count[(arr[i] / exp) % 10]++;
  for (i = 1; i < 10; ++i)
    count[i] += count[i - 1];
  for (i = (n - 1); i >= 0; --i) {
    output[count[(arr[i] / exp) % 10] - 1] = arr[i];
    count[(arr[i] / exp) % 10]--;
  }
  for (i = 0; i < n; ++i)
    arr[i] = output[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x4e,-0x4(%rbp)
  jle    L1
  movl   $0x4f,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int map(int rms) {
  int v = rms / 8;
  if (v >= (80 - 1)) {
    v = 80 - 1;
  }
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<map>:
  endbr64
  mov    $0x4f,%eax
  cmp    $0x277,%edi
  jg     L2
  lea    0x7(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x3,%eax
L2:
  ret
```

assistant: ```c
int map(int rms) {
  int v = rms / 8;
  if (v >= (80 - 1)) {
    v = 80 - 1;
  }
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<map>:
  endbr64
  mov    $0x4f,%eax
  cmp    $0x277,%edi
  jg     L6
  test   %edi,%edi
  lea    0x7(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x3,%eax
L6:
  ret
```

assistant: ```c
int map(int rms) {
  int v = rms / 8;
  if (v >= (80 - 1)) {
    v = 80 - 1;
  }
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<map>:
  endbr64
  mov    $0x4f,%eax
  cmp    $0x277,%edi
  jg     L1
  test   %edi,%edi
  lea    0x7(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x3,%eax
L1:
  ret
```

assistant: ```c
int map(int rms) {
  int v = rms / 8;
  if (v >= (80 - 1)) {
    v = 80 - 1;
  }
  return v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x8(%rbp)
  jmp    L9
L17:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%esi
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  cmp    %dl,%sil
  je     L9
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L8
  mov    $0xffffffff,%eax
  jmp    L44
L8:
  mov    $0x1,%eax
  jmp    L44
L9:
  mov    %rax,%rdx
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  jne    L17
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, register size_t cnt) {
  const unsigned char *s1p = (const unsigned char *)s1;
  const unsigned char *s2p = (const unsigned char *)s2;
  while (cnt-- > 0) {
    if (*s1p++ != *s2p++)
      return (s1p[-1] < s2p[-1]) ? -1 : +1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<memcmp>:
  endbr64
  mov    $0x0,%eax
L14:
  cmp    %rax,%rdx
  je     L10
  movzbl (%rdi,%rax,1),%r8d
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%r8b
  je     L14
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, register size_t cnt) {
  const unsigned char *s1p = (const unsigned char *)s1;
  const unsigned char *s2p = (const unsigned char *)s2;
  while (cnt-- > 0) {
    if (*s1p++ != *s2p++)
      return (s1p[-1] < s2p[-1]) ? -1 : +1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  jne    L6
L29:
  cmp    %rax,%rdx
  jne    L13
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, register size_t cnt) {
  const unsigned char *s1p = (const unsigned char *)s1;
  const unsigned char *s2p = (const unsigned char *)s2;
  while (cnt-- > 0) {
    if (*s1p++ != *s2p++)
      return (s1p[-1] < s2p[-1]) ? -1 : +1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  jne    L26
L28:
  cmp    %rax,%rdx
  jne    L6
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, register size_t cnt) {
  const unsigned char *s1p = (const unsigned char *)s1;
  const unsigned char *s2p = (const unsigned char *)s2;
  while (cnt-- > 0) {
    if (*s1p++ != *s2p++)
      return (s1p[-1] < s2p[-1]) ? -1 : +1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x100,-0x4(%rbp)
  jle    L9
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D15: %d - 

tool: D2: %c


assistant: ```c
int main() {
  int a;
  for (a = 0; a <= 256; a++) {
    printf("%d - ", a);
    printf("%c\n", a);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
  lea    D15(%rip),%rbp
L0:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x101,%ebx
  jne    L0
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string

tool: D5: %d - 

tool: D15: %c


assistant: ```c
int main() {
  int a;
  for (a = 0; a <= 256; a++) {
    printf("%d - ", a);
    printf("%c\n", a);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x101,%ebx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string

tool: D8: %d - 

tool: D11: %c


assistant: ```c
int main() {
  int a;
  for (a = 0; a <= 256; a++) {
    printf("%d - ", a);
    printf("%c\n", a);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x101,%ebx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D16: %d - 

tool: D8: %c


assistant: ```c
int main() {
  int a;
  for (a = 0; a <= 256; a++) {
    printf("%d - ", a);
    printf("%c\n", a);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exit_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D10
type_guessed: string

tool: D18: I cought a signal. It's number is %d


tool: D10: Will exit now

assistant: ```c
void exit_function(int signal) {
  printf("I cought a signal. It's number is %d\n", signal);
  printf("Will exit now\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<exit_function>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string

tool: D5: I cought a signal. It's number is %d


tool: D17: Will exit now

assistant: ```c
void exit_function(int signal) {
  printf("I cought a signal. It's number is %d\n", signal);
  printf("Will exit now\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<exit_function>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D18
type: string

tool: D5: I cought a signal. It's number is %d


tool: D18: Will exit now

assistant: ```c
void exit_function(int signal) {
  printf("I cought a signal. It's number is %d\n", signal);
  printf("Will exit now\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<exit_function>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D15
type: string

tool: D19: I cought a signal. It's number is %d


tool: D15: Will exit now

assistant: ```c
void exit_function(int signal) {
  printf("I cought a signal. It's number is %d\n", signal);
  printf("Will exit now\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <println@plt>
  movl   $0x0,-0x70(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L85
L36:
  mov    -0x74(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x74(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x70(%rbp)
  addl   $0x1,-0x74(%rbp)
L85:
  mov    -0x74(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  subl   $0x1,-0x70(%rbp)
  mov    -0x70(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L57:
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <inputline@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L37
L39:
  mov    -0x6c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movsbl -0x75(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x6c(%rbp)
L37:
  mov    -0x68(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x68(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x75(%rbp)
  cmpb   $0x0,-0x75(%rbp)
  jne    L39
  cmpl   $0x0,-0x6c(%rbp)
  js     L64
  mov    -0x6c(%rbp),%eax
  cmp    -0x70(%rbp),%eax
  jg     L64
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <ed@plt>
  mov    -0x6c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  jmp    L83
L64:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L83:
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D31
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string
name: parse_data
arguments: data_tag: D0
type_infered: string

tool: 

tool: D31:           %d. %s


tool: D5: 
          Enter choice number (0 - %d): 

tool: D0:           Bad choice, try again: 

assistant: ```c
menu(table) char *table[];
{
  int i, tablesize, choice;
  char c;
  char storage[80];
  char *s = storage;
  println("");
  tablesize = 0;
  for (i = 0; *table[i] != '\0'; i++) {
    printf("          %d. %s\n", i, table[i]);
    tablesize++;
  }
  tablesize--;
  printf("\n          Enter choice number (0 - %d): ", tablesize);
  for (;;) {
    inputline(s);
    choice = 0;
    while (c = *s++)
      choice = 10 * choice + c - '0';
    if (choice >= 0 && choice <= tablesize) {
      ed(2);
      return (choice);
    }
    printf("          Bad choice, try again: ");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<menu>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <println@plt>
  mov    (%rbx),%rdx
  cmpb   $0x0,(%rdx)
  je     L83
  add    $0x8,%rbx
  mov    $0x0,%r12d
  lea    D5(%rip),%rbp
L10:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r12d
  mov    (%rbx),%rdx
  add    $0x8,%rbx
  cmpb   $0x0,(%rdx)
  jne    L10
L28:
  sub    $0x1,%r12d
  mov    %r12d,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    D14(%rip),%r13
  jmp    L44
L83:
  mov    $0x0,%r12d
  jmp    L28
L0:
  mov    $0x0,%ebx
  jmp    L91
L47:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
L44:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <inputline@plt>
  lea    0x1(%rbx),%rbp
  movzbl (%rbx),%eax
  test   %al,%al
  je     L0
  mov    $0x0,%ebx
L41:
  lea    (%rbx,%rbx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%ebx
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%eax
  test   %al,%al
  jne    L41
L91:
  test   %ebx,%ebx
  js     L47
  cmp    %ebx,%r12d
  jl     L47
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <ed@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  mov    %ebx,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D20
data_type: string
name: disassemble_data
arguments: label: D5
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string

tool: 

tool: D5:           %d. %s


tool: D18: 
          Enter choice number (0 - %d): 

tool: D14:           Bad choice, try again: 

assistant: ```c
menu(table) char *table[];
{
  int i, tablesize, choice;
  char c;
  char storage[80];
  char *s = storage;
  println("");
  tablesize = 0;
  for (i = 0; *table[i] != '\0'; i++) {
    printf("          %d. %s\n", i, table[i]);
    tablesize++;
  }
  tablesize--;
  printf("\n          Enter choice number (0 - %d): ", tablesize);
  for (;;) {
    inputline(s);
    choice = 0;
    while (c = *s++)
      choice = 10 * choice + c - '0';
    if (choice >= 0 && choice <= tablesize) {
      ed(2);
      return (choice);
    }
    printf("          Bad choice, try again: ");
  }
}
```