ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<neio_putln>:
  endbr64
  sub    $0x8,%rsp
  call   <neio_puts@plt>
  test   %rax,%rax
  jne    L3
  mov    $0xa,%edi
  call   <neio_putc@plt>
  neg    %rax
  sbb    %eax,%eax
L19:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int neio_putln(const char *s) {
  do {
    if ((neio_puts(s)))
      return -1;
  } while (0);
  do {
    if ((neio_putc('\n')))
      return -1;
  } while (0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_mergesort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  je     L1
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L16
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <my_mergesort>
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <my_mergesort>
  mov    -0x30(%rbp),%r8
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <my_merge@plt>
  jmp    L16
L1:
  nop
L16:
  leave
  ret
```

assistant: ```c
void my_mergesort(char *arr, int start, int end, char buf[100], int *total_inv) {
  if (end - start == 1) {
    return;
  }
  if (start < end) {
    int mid = start + (end - start) / 2;
    my_mergesort(arr, start, mid, buf, total_inv);
    my_mergesort(arr, mid, end, buf, total_inv);
    my_merge(arr, start, mid, end, buf, total_inv);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_mergesort>:
  endbr64
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    %esi,%edx
  jle    L23
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %rcx,%r13
  mov    %r8,%r14
  cmp    $0x1,%eax
  jne    L4
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %eax,%r15d
  shr    $0x1f,%r15d
  add    %eax,%r15d
  sar    %r15d
  add    %esi,%r15d
  mov    %r15d,%edx
  call   <my_mergesort>
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %ebp,%edx
  mov    %r15d,%esi
  mov    %r12,%rdi
  call   <my_mergesort>
  mov    %r14,%r9
  mov    %r13,%r8
  mov    %ebp,%ecx
  mov    %r15d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <my_merge@plt>
  jmp    L28
L23:
  ret
```

assistant: ```c
void my_mergesort(char *arr, int start, int end, char buf[100], int *total_inv) {
  if (end - start == 1) {
    return;
  }
  if (start < end) {
    int mid = start + (end - start) / 2;
    my_mergesort(arr, start, mid, buf, total_inv);
    my_mergesort(arr, mid, end, buf, total_inv);
    my_merge(arr, start, mid, end, buf, total_inv);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_mergesort>:
  endbr64
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0x1,%eax
  je     L3
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edx
  jg     L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %eax,%r15d
  mov    %rdi,%r13
  mov    %rcx,%rbx
  mov    %r8,%r14
  shr    $0x1f,%r15d
  add    %eax,%r15d
  sar    %r15d
  add    %esi,%r15d
  mov    %r15d,%edx
  call   <my_mergesort>
  mov    %r14,%r8
  mov    %rbx,%rcx
  mov    %r12d,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <my_mergesort>
  add    $0x8,%rsp
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r12d,%ecx
  pop    %rbx
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <my_merge@plt>
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void my_mergesort(char *arr, int start, int end, char buf[100], int *total_inv) {
  if (end - start == 1) {
    return;
  }
  if (start < end) {
    int mid = start + (end - start) / 2;
    my_mergesort(arr, start, mid, buf, total_inv);
    my_mergesort(arr, mid, end, buf, total_inv);
    my_merge(arr, start, mid, end, buf, total_inv);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_mergesort>:
  endbr64
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0x1,%eax
  je     L25
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %esi,%edx
  jg     L49
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %eax,%edx
  mov    %rdi,%r14
  mov    %rcx,%r13
  mov    %r8,%rbx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  lea    (%rdx,%rsi,1),%r15d
  cmp    %r15d,%esi
  jge    L24
  cmp    $0x1,%edx
  je     L24
  test   %eax,%eax
  lea    0x3(%rax),%r10d
  cmovns %eax,%r10d
  sar    $0x2,%r10d
  add    %esi,%r10d
  mov    %r10d,%edx
  mov    %r10d,0xc(%rsp)
  call   <my_mergesort>
  mov    0xc(%rsp),%esi
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r15d,%edx
  mov    %r14,%rdi
  call   <my_mergesort>
  mov    0xc(%rsp),%edx
  mov    %rbx,%r9
  mov    %r13,%r8
  mov    %r15d,%ecx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <my_merge@plt>
L24:
  mov    %r12d,%eax
  sub    %r15d,%eax
  cmp    %r15d,%r12d
  jle    L26
  cmp    $0x1,%eax
  je     L26
  mov    %eax,%r10d
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r15d,%esi
  shr    $0x1f,%r10d
  mov    %r14,%rdi
  add    %eax,%r10d
  sar    %r10d
  add    %r15d,%r10d
  mov    %r10d,%edx
  mov    %r10d,0xc(%rsp)
  call   <my_mergesort>
  mov    0xc(%rsp),%esi
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %r14,%rdi
  call   <my_mergesort>
  mov    0xc(%rsp),%edx
  mov    %rbx,%r9
  mov    %r13,%r8
  mov    %r12d,%ecx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <my_merge@plt>
L26:
  add    $0x18,%rsp
  mov    %rbx,%r9
  mov    %r13,%r8
  mov    %r12d,%ecx
  pop    %rbx
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <my_merge@plt>
  nopl   0x0(%rax)
L25:
  ret
```

assistant: ```c
void my_mergesort(char *arr, int start, int end, char buf[100], int *total_inv) {
  if (end - start == 1) {
    return;
  }
  if (start < end) {
    int mid = start + (end - start) / 2;
    my_mergesort(arr, start, mid, buf, total_inv);
    my_mergesort(arr, mid, end, buf, total_inv);
    my_merge(arr, start, mid, end, buf, total_inv);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<typ_function_arity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <typ_is_function@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <definition_const@plt>
  mov    %eax,%edi
  call   <node_fun_all_args_count@plt>
  leave
  ret
```

assistant: ```c
size_t typ_function_arity(const struct typ *t) {
  assert(typ_is_function(t));
  return node_fun_all_args_count(definition_const(t));
}
```
user: What is the c source code of the assembly code below:

```asm
<typ_function_arity>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <typ_is_function@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <definition_const@plt>
  mov    %eax,%edi
  call   <node_fun_all_args_count@plt>
  pop    %rbx
  ret
```

assistant: ```c
size_t typ_function_arity(const struct typ *t) {
  assert(typ_is_function(t));
  return node_fun_all_args_count(definition_const(t));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<typ_function_arity>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <typ_is_function@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <definition_const@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    10b0 <node_fun_all_args_count@plt>
```

assistant: ```c
size_t typ_function_arity(const struct typ *t) {
  assert(typ_is_function(t));
  return node_fun_all_args_count(definition_const(t));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<typ_function_arity>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <typ_is_function@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <definition_const@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    10b0 <node_fun_all_args_count@plt>
```

assistant: ```c
size_t typ_function_arity(const struct typ *t) {
  assert(typ_is_function(t));
  return node_fun_all_args_count(definition_const(t));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x20(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x64,-0x30(%rbp)
  jmp    L23
L47:
  mov    -0x34(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,-0x30(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x2c(%rbp)
  addl   $0x1,-0x28(%rbp)
L23:
  cmpl   $0x0,-0x30(%rbp)
  jg     L47
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L11
L30:
  mov    -0x34(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x34(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   -0x14(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x20(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x20(%rbp)
  subl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x24(%rbp)
L11:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L30
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: D16: %d

tool: D3: Reverse of %d is %d

assistant: ```c
int main() {
  int a, b, c, d = 10, e, f, g, h = 0, i, j = 0, k, l;
  double m, n;
  scanf("%d", &a);
  l = a;
  for (c = 100; c >= 1;) {
    c = a / d;
    d = d * 10;
    h = h + 1;
  }
  k = h;
  for (i = 1; i <= h; i = i + 1) {
    b = a % 10;
    a = a - b;
    a = a / 10;
    m = b * pow(10, k - 1);
    j = j + m;
    k = k - 1;
  }
  printf("Reverse of %d is %d", l, j);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r13d
  mov    $0x0,%ebp
  mov    $0xa,%ecx
L34:
  mov    %r13d,%eax
  cltd
  idiv   %ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  mov    %ebp,%r15d
  add    $0x1,%ebp
  test   %eax,%eax
  jg     L34
  test   %ebp,%ebp
  jle    L10
  mov    %ebp,%r12d
  mov    $0x0,%r14d
L23:
  mov    0x4(%rsp),%edx
  movslq %edx,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %edx,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %edx,%ebx
  sub    %eax,%ebx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,0x4(%rsp)
  sub    $0x1,%r12d
  mov    %r12d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r14d,%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%r14d
  mov    %ebp,%eax
  sub    %r12d,%eax
  cmp    %r15d,%eax
  jle    L23
L16:
  mov    %r14d,%edx
  mov    %r13d,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    $0x0,%r14d
  jmp    L16
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string

tool: D13: %d

tool: D12: Reverse of %d is %d

assistant: ```c
int main() {
  int a, b, c, d = 10, e, f, g, h = 0, i, j = 0, k, l;
  double m, n;
  scanf("%d", &a);
  l = a;
  for (c = 100; c >= 1;) {
    c = a / d;
    d = d * 10;
    h = h + 1;
  }
  k = h;
  for (i = 1; i <= h; i = i + 1) {
    b = a % 10;
    a = a - b;
    a = a / 10;
    m = b * pow(10, k - 1);
    j = j + m;
    k = k - 1;
  }
  printf("Reverse of %d is %d", l, j);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  mov    $0xa,%ecx
L1:
  mov    %r12d,%eax
  mov    %r13d,%ebp
  add    $0x1,%r13d
  cltd
  idiv   %ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  test   %eax,%eax
  jg     L1
  mov    %r12d,%edx
  mov    %r13d,%r15d
  xor    %r14d,%r14d
  jmp    L2
  nopl   0x0(%rax)
L13:
  mov    0x4(%rsp),%edx
L2:
  movslq %edx,%rbx
  mov    %edx,%eax
  sub    $0x1,%r15d
  mov    $0xa,%edi
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  mov    %r15d,%esi
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %edx,%ebx
  add    %eax,%eax
  movslq %eax,%rdx
  sub    %eax,%ebx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %eax,%edx
  mov    %edx,0x4(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  imul   %ebx,%eax
  cvtsi2sd %r14d,%xmm1
  cvtsi2sd %eax,%xmm0
  mov    %r13d,%eax
  sub    %r15d,%eax
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%r14d
  cmp    %ebp,%eax
  jle    L13
  mov    %r14d,%edx
  mov    %r12d,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string
name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D4: %d

tool: D7: Reverse of %d is %d

assistant: ```c
int main() {
  int a, b, c, d = 10, e, f, g, h = 0, i, j = 0, k, l;
  double m, n;
  scanf("%d", &a);
  l = a;
  for (c = 100; c >= 1;) {
    c = a / d;
    d = d * 10;
    h = h + 1;
  }
  k = h;
  for (i = 1; i <= h; i = i + 1) {
    b = a % 10;
    a = a - b;
    a = a / 10;
    m = b * pow(10, k - 1);
    j = j + m;
    k = k - 1;
  }
  printf("Reverse of %d is %d", l, j);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D14(%rip),%rdi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  mov    $0xa,%ecx
L8:
  mov    %r12d,%eax
  mov    %r13d,%ebp
  add    $0x1,%r13d
  cltd
  idiv   %ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  test   %eax,%eax
  jg     L8
  mov    %r12d,%edx
  mov    %r13d,%r15d
  xor    %r14d,%r14d
  jmp    L33
  nopl   0x0(%rax)
L23:
  mov    0x4(%rsp),%edx
L33:
  movslq %edx,%rbx
  mov    %edx,%eax
  sub    $0x1,%r15d
  mov    $0xa,%edi
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  mov    %r15d,%esi
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %edx,%ebx
  add    %eax,%eax
  movslq %eax,%rdx
  sub    %eax,%ebx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %eax,%edx
  mov    %edx,0x4(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  imul   %ebx,%eax
  cvtsi2sd %r14d,%xmm1
  cvtsi2sd %eax,%xmm0
  mov    %r13d,%eax
  sub    %r15d,%eax
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%r14d
  cmp    %ebp,%eax
  jle    L23
  mov    %r14d,%edx
  mov    %r12d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string

tool: D14: %d

tool: D18: Reverse of %d is %d

assistant: ```c
int main() {
  int a, b, c, d = 10, e, f, g, h = 0, i, j = 0, k, l;
  double m, n;
  scanf("%d", &a);
  l = a;
  for (c = 100; c >= 1;) {
    c = a / d;
    d = d * 10;
    h = h + 1;
  }
  k = h;
  for (i = 1; i <= h; i = i + 1) {
    b = a % 10;
    a = a - b;
    a = a / 10;
    m = b * pow(10, k - 1);
    j = j + m;
    k = k - 1;
  }
  printf("Reverse of %d is %d", l, j);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<approxf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edi,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  jne    L67
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  jne    L67
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L67
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L27
L67:
  mov    $0x0,%eax
  jmp    L78
L27:
  pxor   %xmm0,%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jp     L15
  pxor   %xmm0,%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jne    L15
  movsd  -0x18(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  D20(%rip),%xmm0
  divsd  %xmm1,%xmm0
  comisd -0x30(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  jmp    L78
L15:
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   D3(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
L78:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: qword
name: disassemble_data
arguments: tag: D20
type: f32[2]

tool: D3: 9223372036854775807

tool: {"D20": [0.0,1.875]}

assistant: ```c
int approxf(double actual, double expected, int bits) {
  if (isinf(actual) || isinf(expected) || isnan(actual) || isnan(expected)) {
    return 0;
  }
  if (expected == 0.0) {
    return fabs(actual) < (1 / pow(2, bits));
  }
  double epsilon = fabs(expected / pow(2, bits));
  return fabs(actual - expected) <= epsilon;
}
```
user: What is the c source code of the assembly code below?

```asm
<approxf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  mov    %edi,%r12d
  call   <isinf@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L71
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L71:
  movq   %rbp,%xmm0
  call   <isinf@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L42
  movq   %rbx,%xmm0
  call   <isnan@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L42
  movq   %rbp,%xmm0
  call   <isnan@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L42
  movq   %rbp,%xmm4
  ucomisd D31(%rip),%xmm4
  jp     L61
  je     L50
L61:
  mov    %r12d,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm0
  movq   %rbp,%xmm6
  subsd  %xmm6,%xmm0
  movq   D25(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movq   %rbp,%xmm3
  divsd  %xmm2,%xmm3
  andpd  %xmm3,%xmm1
  comisd %xmm0,%xmm1
  setae  %al
  movzbl %al,%eax
  jmp    L42
L50:
  mov    %r12d,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm1
  andpd  D25(%rip),%xmm1
  movsd  D35(%rip),%xmm0
  divsd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  jmp    L42
```

tool_calls: name: read_data
arguments: data_tag: D31
datatype: f64
name: read_data
arguments: data_tag: D25
datatype: qword[2]
name: read_data
arguments: data_tag: D35
datatype: byte[8]

tool: D31: 0

tool: {"D25": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int approxf(double actual, double expected, int bits) {
  if (isinf(actual) || isinf(expected) || isnan(actual) || isnan(expected)) {
    return 0;
  }
  if (expected == 0.0) {
    return fabs(actual) < (1 / pow(2, bits));
  }
  double epsilon = fabs(expected / pow(2, bits));
  return fabs(actual - expected) <= epsilon;
}
```