ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<invert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  sub    -0x1c(%rbp),%eax
  mov    $0xffffffff,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  not    %eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <getInvertedbits@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned invert(unsigned x, int p, int n) {
  unsigned inverted, mask, x_mask;
  mask = 0;
  mask = (~mask << n) << (p + 1 - n) | ~(~0 << (p + 1 - n));
  x_mask = x & mask;
  inverted = getInvertedbits(x, p, n);
  inverted |= x_mask;
  return inverted;
}
```
user: What is the c source code of the assembly code below:

```asm
<invert>:
  endbr64
  push   %rbx
  lea    0x1(%rsi),%r8d
  sub    %edx,%r8d
  mov    $0xffffffff,%eax
  mov    %eax,%ebx
  mov    %edx,%ecx
  shl    %cl,%ebx
  mov    %r8d,%ecx
  shl    %cl,%ebx
  shl    %cl,%eax
  not    %eax
  or     %eax,%ebx
  and    %edi,%ebx
  call   <getInvertedbits@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned invert(unsigned x, int p, int n) {
  unsigned inverted, mask, x_mask;
  mask = 0;
  mask = (~mask << n) << (p + 1 - n) | ~(~0 << (p + 1 - n));
  x_mask = x & mask;
  inverted = getInvertedbits(x, p, n);
  inverted |= x_mask;
  return inverted;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<invert>:
  endbr64
  lea    0x1(%rsi),%r8d
  mov    $0xffffffff,%eax
  push   %rbx
  mov    %edx,%ecx
  sub    %edx,%r8d
  mov    %eax,%ebx
  shl    %cl,%ebx
  mov    %r8d,%ecx
  shl    %cl,%eax
  shl    %cl,%ebx
  not    %eax
  or     %eax,%ebx
  and    %edi,%ebx
  call   <getInvertedbits@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned invert(unsigned x, int p, int n) {
  unsigned inverted, mask, x_mask;
  mask = 0;
  mask = (~mask << n) << (p + 1 - n) | ~(~0 << (p + 1 - n));
  x_mask = x & mask;
  inverted = getInvertedbits(x, p, n);
  inverted |= x_mask;
  return inverted;
}
```
user: Translate the below assembly code into C programming language:

```asm
<invert>:
  endbr64
  lea    0x1(%rsi),%r8d
  mov    $0xffffffff,%eax
  push   %rbx
  mov    %edx,%ecx
  sub    %edx,%r8d
  mov    %eax,%ebx
  shl    %cl,%ebx
  mov    %r8d,%ecx
  shl    %cl,%eax
  shl    %cl,%ebx
  not    %eax
  or     %eax,%ebx
  and    %edi,%ebx
  call   <getInvertedbits@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned invert(unsigned x, int p, int n) {
  unsigned inverted, mask, x_mask;
  mask = 0;
  mask = (~mask << n) << (p + 1 - n) | ~(~0 << (p + 1 - n));
  x_mask = x & mask;
  inverted = getInvertedbits(x, p, n);
  inverted |= x_mask;
  return inverted;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <crypt@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <decrypt@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D4: Bir cumle giriniz:

tool: D10: %s

assistant: ```c
int main() {
  char str[256];
  printf("Bir cumle giriniz:\n");
  scanf("%s", str);
  crypt(str);
  printf("%s\n", str);
  decrypt(str);
  printf("%s\n", str);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <crypt@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <decrypt@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string

tool: D9: Bir cumle giriniz:

tool: D14: %s

assistant: ```c
int main() {
  char str[256];
  printf("Bir cumle giriniz:\n");
  scanf("%s", str);
  crypt(str);
  printf("%s\n", str);
  decrypt(str);
  printf("%s\n", str);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <crypt@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <decrypt@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string

tool: D2: Bir cumle giriniz:

tool: D12: %s

assistant: ```c
int main() {
  char str[256];
  printf("Bir cumle giriniz:\n");
  scanf("%s", str);
  crypt(str);
  printf("%s\n", str);
  decrypt(str);
  printf("%s\n", str);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <crypt@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <decrypt@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D1: Bir cumle giriniz:

tool: D0: %s

assistant: ```c
int main() {
  char str[256];
  printf("Bir cumle giriniz:\n");
  scanf("%s", str);
  crypt(str);
  printf("%s\n", str);
  decrypt(str);
  printf("%s\n", str);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<numcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L22
  mov    $0x1,%eax
  jmp    L34
L22:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L19
  mov    $0xffffffff,%eax
  jmp    L34
L19:
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int numcmp(const void *a, const void *b) {
  int x = *((int *)a);
  int y = *((int *)b);
  if (x > y)
    return 1;
  if (x < y)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<numcmp>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  jg     L3
  setl   %al
  movzbl %al,%eax
  neg    %eax
L3:
  ret
```

assistant: ```c
int numcmp(const void *a, const void *b) {
  int x = *((int *)a);
  int y = *((int *)b);
  if (x > y)
    return 1;
  if (x < y)
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<numcmp>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L7
  setl   %al
  movzbl %al,%eax
  neg    %eax
L7:
  ret
```

assistant: ```c
int numcmp(const void *a, const void *b) {
  int x = *((int *)a);
  int y = *((int *)b);
  if (x > y)
    return 1;
  if (x < y)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<numcmp>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L0
  setl   %al
  movzbl %al,%eax
  neg    %eax
L0:
  ret
```

assistant: ```c
int numcmp(const void *a, const void *b) {
  int x = *((int *)a);
  int y = *((int *)b);
  if (x > y)
    return 1;
  if (x < y)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ASCII2BCD>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  call   <strlen@plt>
  test   $0x1,%al
  jne    L42
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %edx,(%r12)
  test   %eax,%eax
  jle    L74
  mov    %rbp,%rcx
  sub    $0x1,%eax
  shr    %eax
  lea    0x1(%rax),%edi
  add    %rbx,%rdi
  jmp    L83
L21:
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  ja     L173
  shl    $0x4,%eax
  sub    $0x70,%eax
  jmp    L105
L173:
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L67
  shl    $0x4,%eax
  sub    $0x70,%eax
  jmp    L105
L84:
  lea    -0x61(%rdx),%esi
  cmp    $0x5,%sil
  ja     L30
  sub    $0x57,%edx
  or     %edx,%eax
L52:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  add    $0x2,%rcx
  cmp    %rbx,%rdi
  je     L53
L83:
  mov    %rcx,%rsi
  movzbl (%rcx),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L21
  shl    $0x4,%eax
L105:
  mov    %al,(%rbx)
  movzbl 0x1(%rsi),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  ja     L84
  and    $0xf,%edx
  or     %edx,%eax
  jmp    L52
L30:
  lea    -0x41(%rdx),%esi
  cmp    $0x5,%sil
  ja     L107
  sub    $0x37,%edx
  or     %edx,%eax
  jmp    L52
L53:
  mov    $0x0,%eax
L164:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  mov    $0xffffffff,%eax
  jmp    L164
L74:
  mov    $0x0,%eax
  jmp    L164
L67:
  mov    $0xfffffffe,%eax
  jmp    L164
L107:
  mov    $0xfffffffd,%eax
  jmp    L164
```

assistant: ```c
int ASCII2BCD(const unsigned char *ascii, unsigned char *bcd, int *bcdLen) {
  unsigned char *pbcd;
  int i;
  int len = strlen((char *)ascii);
  pbcd = bcd;
  if (len % 2)
    return -1;
  *bcdLen = len / 2;
  for (i = 0; i < len; i += 2) {
    if (ascii[i] <= '9' && ascii[i] >= '0') {
      *pbcd = ((ascii[i] - '0') << 4) & 0xf0;
    } else if (ascii[i] <= 'f' && ascii[i] >= 'a') {
      *pbcd = ((ascii[i] - 'a' + 0x0a) << 4) & 0xf0;
    } else if (ascii[i] <= 'F' && ascii[i] >= 'A') {
      *pbcd = ((ascii[i] - 'A' + 0x0a) << 4) & 0xf0;
    } else {
      return -2;
    }
    if (ascii[i + 1] <= '9' && ascii[i + 1] >= '0') {
      *pbcd |= (ascii[i + 1] - '0') & 0x0f;
    } else if (ascii[i + 1] <= 'f' && ascii[i + 1] >= 'a') {
      *pbcd |= (ascii[i + 1] - 'a' + 0x0a) & 0x0f;
    } else if (ascii[i + 1] <= 'F' && ascii[i + 1] >= 'A') {
      *pbcd |= (ascii[i + 1] - 'A' + 0x0a) & 0x0f;
    } else {
      return -3;
    }
    pbcd++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ASCII2BCD>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   $0x1,%al
  jne    L78
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %ecx,(%r12)
  test   %eax,%eax
  jle    L69
  sub    $0x1,%eax
  mov    %rbp,%rdi
  shr    %eax
  lea    0x1(%rax),%esi
  add    %rbx,%rsi
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L137:
  shl    $0x4,%eax
  mov    %al,(%rbx)
  movzbl 0x1(%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L29
L22:
  and    $0xf,%edx
  or     %edx,%eax
L12:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  add    $0x2,%rdi
  cmp    %rbx,%rsi
  je     L69
L40:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L137
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  jbe    L99
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L124
L99:
  shl    $0x4,%eax
  sub    $0x70,%eax
  mov    %al,(%rbx)
  movzbl 0x1(%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L22
L29:
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L126
  sub    $0x57,%edx
  add    $0x1,%rbx
  add    $0x2,%rdi
  or     %edx,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%rsi
  jne    L40
L69:
  xor    %eax,%eax
L118:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L126:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L36
  sub    $0x37,%edx
  or     %edx,%eax
  jmp    L12
L124:
  pop    %rbx
  mov    $0xfffffffe,%eax
  pop    %rbp
  pop    %r12
  ret
L36:
  pop    %rbx
  mov    $0xfffffffd,%eax
  pop    %rbp
  pop    %r12
  ret
L78:
  mov    $0xffffffff,%eax
  jmp    L118
```

assistant: ```c
int ASCII2BCD(const unsigned char *ascii, unsigned char *bcd, int *bcdLen) {
  unsigned char *pbcd;
  int i;
  int len = strlen((char *)ascii);
  pbcd = bcd;
  if (len % 2)
    return -1;
  *bcdLen = len / 2;
  for (i = 0; i < len; i += 2) {
    if (ascii[i] <= '9' && ascii[i] >= '0') {
      *pbcd = ((ascii[i] - '0') << 4) & 0xf0;
    } else if (ascii[i] <= 'f' && ascii[i] >= 'a') {
      *pbcd = ((ascii[i] - 'a' + 0x0a) << 4) & 0xf0;
    } else if (ascii[i] <= 'F' && ascii[i] >= 'A') {
      *pbcd = ((ascii[i] - 'A' + 0x0a) << 4) & 0xf0;
    } else {
      return -2;
    }
    if (ascii[i + 1] <= '9' && ascii[i + 1] >= '0') {
      *pbcd |= (ascii[i + 1] - '0') & 0x0f;
    } else if (ascii[i + 1] <= 'f' && ascii[i + 1] >= 'a') {
      *pbcd |= (ascii[i + 1] - 'a' + 0x0a) & 0x0f;
    } else if (ascii[i + 1] <= 'F' && ascii[i + 1] >= 'A') {
      *pbcd |= (ascii[i + 1] - 'A' + 0x0a) & 0x0f;
    } else {
      return -3;
    }
    pbcd++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ASCII2BCD>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   $0x1,%al
  jne    L89
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %ecx,(%r12)
  test   %eax,%eax
  jle    L102
  sub    $0x1,%eax
  mov    %rbp,%rdi
  shr    %eax
  lea    0x1(%rax),%esi
  add    %rbx,%rsi
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L137:
  shl    $0x4,%eax
  mov    %al,(%rbx)
  movzbl 0x1(%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L66
L113:
  and    $0xf,%edx
  or     %edx,%eax
L43:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  add    $0x2,%rdi
  cmp    %rsi,%rbx
  je     L102
L68:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L137
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  jbe    L134
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L136
L134:
  shl    $0x4,%eax
  sub    $0x70,%eax
  mov    %al,(%rbx)
  movzbl 0x1(%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L113
L66:
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L25
  sub    $0x57,%edx
  add    $0x1,%rbx
  add    $0x2,%rdi
  or     %edx,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rsi,%rbx
  jne    L68
L102:
  xor    %eax,%eax
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L34
  sub    $0x37,%edx
  or     %edx,%eax
  jmp    L43
L136:
  pop    %rbx
  mov    $0xfffffffe,%eax
  pop    %rbp
  pop    %r12
  ret
L34:
  pop    %rbx
  mov    $0xfffffffd,%eax
  pop    %rbp
  pop    %r12
  ret
L89:
  mov    $0xffffffff,%eax
  jmp    L38
```

assistant: ```c
int ASCII2BCD(const unsigned char *ascii, unsigned char *bcd, int *bcdLen) {
  unsigned char *pbcd;
  int i;
  int len = strlen((char *)ascii);
  pbcd = bcd;
  if (len % 2)
    return -1;
  *bcdLen = len / 2;
  for (i = 0; i < len; i += 2) {
    if (ascii[i] <= '9' && ascii[i] >= '0') {
      *pbcd = ((ascii[i] - '0') << 4) & 0xf0;
    } else if (ascii[i] <= 'f' && ascii[i] >= 'a') {
      *pbcd = ((ascii[i] - 'a' + 0x0a) << 4) & 0xf0;
    } else if (ascii[i] <= 'F' && ascii[i] >= 'A') {
      *pbcd = ((ascii[i] - 'A' + 0x0a) << 4) & 0xf0;
    } else {
      return -2;
    }
    if (ascii[i + 1] <= '9' && ascii[i + 1] >= '0') {
      *pbcd |= (ascii[i + 1] - '0') & 0x0f;
    } else if (ascii[i + 1] <= 'f' && ascii[i + 1] >= 'a') {
      *pbcd |= (ascii[i + 1] - 'a' + 0x0a) & 0x0f;
    } else if (ascii[i + 1] <= 'F' && ascii[i + 1] >= 'A') {
      *pbcd |= (ascii[i + 1] - 'A' + 0x0a) & 0x0f;
    } else {
      return -3;
    }
    pbcd++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<findx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L147
L127:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L67
  movl   $0x1,-0x4(%rbp)
  jmp    L22
L67:
  addl   $0x1,-0xc(%rbp)
L147:
  cmpl   $0x8,-0xc(%rbp)
  jle    L127
L22:
  movl   $0x0,-0xc(%rbp)
  jmp    L79
L63:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L11
  movl   $0x1,-0x4(%rbp)
  jmp    L70
L11:
  addl   $0x1,-0xc(%rbp)
L79:
  cmpl   $0x8,-0xc(%rbp)
  jg     L70
  cmpl   $0x1,-0x4(%rbp)
  jne    L63
L70:
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L58:
  movl   $0x0,-0x8(%rbp)
  jmp    L104
L82:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L139
  movl   $0x1,-0x4(%rbp)
L139:
  addl   $0x1,-0x8(%rbp)
L104:
  cmpl   $0x2,-0x8(%rbp)
  jle    L82
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x2,-0xc(%rbp)
  jg     L140
  cmpl   $0x1,-0x4(%rbp)
  jne    L58
L140:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int findx(int x, int *H_arr, int *V_arr[9], int *B_arr[3]) {
  int i, j, find = 0;
  for (i = 0; i < 9; i++) {
    if (H_arr[i] == x) {
      find = 1;
      break;
    }
  }
  for (i = 0; i < 9 && find != 1; i++) {
    if (*V_arr[i] == x) {
      find = 1;
      break;
    }
  }
  for (i = 0; i < 3 && find != 1; i++) {
    for (j = 0; j < 3; j++) {
      if (*(B_arr[i] + j) == x) {
        find = 1;
      }
    }
  }
  return find;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<findx>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  add    $0x24,%rsi
L24:
  cmp    %eax,(%rdi)
  je     L104
  add    $0x4,%rdi
  cmp    %rdi,%rsi
  jne    L24
  mov    %rdx,%rsi
  lea    0x48(%rdx),%rdi
L28:
  mov    (%rsi),%rdx
  cmp    %eax,(%rdx)
  je     L47
  add    $0x8,%rsi
  cmp    %rsi,%rdi
  jne    L28
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    $0x1,%r9d
  jmp    L100
L40:
  cmp    $0x2,%edx
  setle  %r8b
  cmp    $0x1,%esi
  setne  %dil
  add    $0x1,%rdx
  test   %dil,%r8b
  je     L95
L100:
  mov    -0x8(%rcx,%rdx,8),%rdi
  cmp    %eax,(%rdi)
  cmove  %r9d,%esi
  cmp    %eax,0x4(%rdi)
  je     L108
  cmp    %eax,0x8(%rdi)
  jne    L40
  mov    $0x1,%esi
  jmp    L95
L104:
  mov    $0x1,%esi
  jmp    L95
L47:
  mov    $0x1,%esi
  jmp    L95
L108:
  mov    $0x1,%esi
L95:
  mov    %esi,%eax
  ret
```

assistant: ```c
int findx(int x, int *H_arr, int *V_arr[9], int *B_arr[3]) {
  int i, j, find = 0;
  for (i = 0; i < 9; i++) {
    if (H_arr[i] == x) {
      find = 1;
      break;
    }
  }
  for (i = 0; i < 9 && find != 1; i++) {
    if (*V_arr[i] == x) {
      find = 1;
      break;
    }
  }
  for (i = 0; i < 3 && find != 1; i++) {
    for (j = 0; j < 3; j++) {
      if (*(B_arr[i] + j) == x) {
        find = 1;
      }
    }
  }
  return find;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findx>:
  endbr64
  mov    %edi,%eax
  lea    0x24(%rsi),%rdi
  nopw   0x0(%rax,%rax,1)
L53:
  cmp    %eax,(%rsi)
  je     L79
  add    $0x4,%rsi
  cmp    %rdi,%rsi
  jne    L53
  lea    0x48(%rdx),%rdi
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rdx
  cmp    %rdx,%rdi
  je     L2
L31:
  mov    (%rdx),%rsi
  cmp    %eax,(%rsi)
  jne    L6
L79:
  mov    $0x1,%r8d
L69:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%esi
  mov    $0x1,%r9d
  jmp    L38
  nopl   (%rax)
L44:
  cmp    $0x2,%esi
  mov    %r8d,%edx
  setle  %dil
  xor    $0x1,%edx
  add    $0x1,%rsi
  test   %dl,%dil
  je     L69
L38:
  mov    -0x8(%rcx,%rsi,8),%rdx
  xor    %r8d,%r8d
  cmp    %eax,(%rdx)
  sete   %r8b
  cmp    %eax,0x4(%rdx)
  cmove  %r9d,%r8d
  cmp    0x8(%rdx),%eax
  jne    L44
  jmp    L79
```

assistant: ```c
int findx(int x, int *H_arr, int *V_arr[9], int *B_arr[3]) {
  int i, j, find = 0;
  for (i = 0; i < 9; i++) {
    if (H_arr[i] == x) {
      find = 1;
      break;
    }
  }
  for (i = 0; i < 9 && find != 1; i++) {
    if (*V_arr[i] == x) {
      find = 1;
      break;
    }
  }
  for (i = 0; i < 3 && find != 1; i++) {
    for (j = 0; j < 3; j++) {
      if (*(B_arr[i] + j) == x) {
        find = 1;
      }
    }
  }
  return find;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<findx>:
  endbr64
  mov    %edi,%eax
  cmp    (%rsi),%edi
  je     L235
  cmp    0x4(%rsi),%edi
  je     L235
  cmp    0x8(%rsi),%edi
  je     L235
  cmp    0xc(%rsi),%edi
  je     L235
  cmp    0x10(%rsi),%edi
  je     L235
  cmp    0x14(%rsi),%edi
  je     L235
  cmp    0x18(%rsi),%edi
  je     L235
  cmp    0x1c(%rsi),%edi
  je     L235
  cmp    %edi,0x20(%rsi)
  je     L235
  mov    (%rdx),%rsi
  cmp    (%rsi),%edi
  je     L235
  mov    0x8(%rdx),%rsi
  cmp    (%rsi),%edi
  je     L235
  mov    0x10(%rdx),%rsi
  cmp    (%rsi),%edi
  je     L235
  mov    0x18(%rdx),%rsi
  cmp    (%rsi),%edi
  je     L235
  mov    0x20(%rdx),%rsi
  cmp    (%rsi),%edi
  je     L235
  mov    0x28(%rdx),%rsi
  cmp    (%rsi),%edi
  je     L235
  mov    0x30(%rdx),%rsi
  cmp    (%rsi),%edi
  je     L235
  mov    0x38(%rdx),%rsi
  cmp    (%rsi),%edi
  je     L235
  mov    0x40(%rdx),%rdx
  cmp    %edi,(%rdx)
  je     L235
  mov    (%rcx),%rdx
  mov    $0x1,%r8d
  cmp    0x4(%rdx),%edi
  je     L130
  mov    (%rdx),%esi
  xor    %r8d,%r8d
  cmp    %esi,%edi
  sete   %r8b
  cmp    0x8(%rdx),%edi
  je     L235
  cmp    %esi,%edi
  je     L130
  mov    0x8(%rcx),%rdx
  mov    $0x1,%r8d
  cmp    %edi,0x4(%rdx)
  je     L130
  mov    (%rdx),%esi
  xor    %r8d,%r8d
  cmp    %edi,%esi
  sete   %r8b
  cmp    %edi,0x8(%rdx)
  je     L235
  cmp    %edi,%esi
  je     L130
  mov    0x10(%rcx),%rdx
  mov    $0x1,%r8d
  cmp    0x4(%rdx),%edi
  je     L106
  xor    %r8d,%r8d
  cmp    %edi,(%rdx)
  sete   %r8b
L106:
  cmp    0x8(%rdx),%eax
  mov    $0x1,%eax
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L235:
  mov    $0x1,%r8d
L130:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int findx(int x, int *H_arr, int *V_arr[9], int *B_arr[3]) {
  int i, j, find = 0;
  for (i = 0; i < 9; i++) {
    if (H_arr[i] == x) {
      find = 1;
      break;
    }
  }
  for (i = 0; i < 9 && find != 1; i++) {
    if (*V_arr[i] == x) {
      find = 1;
      break;
    }
  }
  for (i = 0; i < 3 && find != 1; i++) {
    for (j = 0; j < 3; j++) {
      if (*(B_arr[i] + j) == x) {
        find = 1;
      }
    }
  }
  return find;
}
```