ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ne_test_pcmpc>:
  endbr64
  sub    $0x258,%rsp
  mov    %edi,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x248(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x30(%rsp)
  mov    $0x0,%ecx
  lea    0x4(%rsp),%rdi
  lea    0x34(%rsp),%rsi
  jmp    L7
L37:
  movl   $0x2,0x60(%rsp,%rcx,2)
  movl   $0x11,0xb0(%rsp,%rcx,2)
  movl   $0x4,0x64(%rsp,%rcx,2)
  movl   $0x11,0xb4(%rsp,%rcx,2)
  mov    (%rsp,%rcx,1),%eax
  add    $0x4,%eax
  mov    %eax,(%rdi,%rcx,1)
  mov    0x30(%rsp,%rcx,1),%eax
  add    $0x2,%eax
  mov    %eax,(%rsi,%rcx,1)
  add    $0x4,%rcx
  cmp    $0x28,%rcx
  je     L32
L7:
  mov    %rcx,%rdx
  mov    $0x0,%eax
L47:
  add    $0x1,%eax
  mov    %eax,0x100(%rsp,%rdx,4)
  movl   $0x14,0x1a0(%rsp,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x4,%eax
  jne    L47
  jmp    L37
L32:
  mov    %rsp,%rcx
  lea    0x1a0(%rsp),%rdx
  lea    0x100(%rsp),%rsi
  sub    $0x8,%rsp
  lea    0x38(%rsp),%rax
  push   %rax
  lea    0xc0(%rsp),%r9
  lea    0x70(%rsp),%r8
  mov    %r10d,%edi
  call   <ne_put_cmap_params_cc@plt>
  add    $0x10,%rsp
  mov    0x248(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x258,%rsp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ne_test_pcmpc(int fileid) {
  int iproc, j, n_cntr, e_cntr;
  int nmap_ids[4 * 10], nmap_n_cnts[4 * 10];
  int nmap_proc_ptr[10 + 1];
  int emap_ids[2 * 10], emap_e_cnts[2 * 10];
  int emap_proc_ptr[10 + 1];
  nmap_proc_ptr[0] = 0;
  emap_proc_ptr[0] = 0;
  n_cntr = 0;
  e_cntr = 0;
  for (iproc = 0; iproc < 10; iproc++) {
    for (j = 0; j < 4; j++) {
      nmap_ids[n_cntr] = (j + 1);
      nmap_n_cnts[n_cntr++] = 20;
    }
    for (j = 0; j < 2; j++) {
      emap_ids[e_cntr] = 2 * (j + 1);
      emap_e_cnts[e_cntr++] = 17;
    }
    nmap_proc_ptr[iproc + 1] = nmap_proc_ptr[iproc] + 4;
    emap_proc_ptr[iproc + 1] = emap_proc_ptr[iproc] + 2;
  }
  return (ne_put_cmap_params_cc(fileid, nmap_ids, nmap_n_cnts, nmap_proc_ptr, emap_ids, emap_e_cnts, emap_proc_ptr));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ne_test_pcmpc>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  xor    %r11d,%r11d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x250,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x248(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  lea    0x100(%rsp),%rsi
  lea    0x1a0(%rsp),%r10
  movl   $0x0,0x30(%rsp)
  lea    0x60(%rsp),%r8
  lea    0x4(%rsp),%r12
  lea    0xb0(%rsp),%r9
  lea    0x34(%rsp),%rbx
  nop
L18:
  mov    %ecx,%edi
  mov    %rcx,%rdx
  xor    %eax,%eax
L25:
  add    $0x1,%eax
  movl   $0x14,(%r10,%rdx,4)
  mov    %eax,(%rsi,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x4,%eax
  jne    L25
  add    $0x2,%r11d
  add    $0x4,%edi
  movl   $0x2,(%r8,%rcx,2)
  movl   $0x11,(%r9,%rcx,2)
  movl   $0x4,0x4(%r8,%rcx,2)
  movl   $0x11,0x4(%r9,%rcx,2)
  mov    %edi,(%r12,%rcx,1)
  mov    %r11d,(%rbx,%rcx,1)
  add    $0x4,%rcx
  cmp    $0x28,%rcx
  jne    L18
  sub    $0x8,%rsp
  mov    %r10,%rdx
  mov    %ebp,%edi
  lea    0x38(%rsp),%rax
  push   %rax
  lea    0x10(%rsp),%rcx
  call   <ne_put_cmap_params_cc@plt>
  pop    %rdx
  pop    %rcx
  mov    0x248(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x250,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ne_test_pcmpc(int fileid) {
  int iproc, j, n_cntr, e_cntr;
  int nmap_ids[4 * 10], nmap_n_cnts[4 * 10];
  int nmap_proc_ptr[10 + 1];
  int emap_ids[2 * 10], emap_e_cnts[2 * 10];
  int emap_proc_ptr[10 + 1];
  nmap_proc_ptr[0] = 0;
  emap_proc_ptr[0] = 0;
  n_cntr = 0;
  e_cntr = 0;
  for (iproc = 0; iproc < 10; iproc++) {
    for (j = 0; j < 4; j++) {
      nmap_ids[n_cntr] = (j + 1);
      nmap_n_cnts[n_cntr++] = 20;
    }
    for (j = 0; j < 2; j++) {
      emap_ids[e_cntr] = 2 * (j + 1);
      emap_e_cnts[e_cntr++] = 17;
    }
    nmap_proc_ptr[iproc + 1] = nmap_proc_ptr[iproc] + 4;
    emap_proc_ptr[iproc + 1] = emap_proc_ptr[iproc] + 2;
  }
  return (ne_put_cmap_params_cc(fileid, nmap_ids, nmap_n_cnts, nmap_proc_ptr, emap_ids, emap_e_cnts, emap_proc_ptr));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<flip_B6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x8,%rax
  and    -0x30(%rbp),%rax
  and    $0x4000,%eax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x9,%rax
  and    -0x30(%rbp),%rax
  and    $0x2000,%eax
  or     %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0x1f0000,%eax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  and    $0x400000,%eax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L16
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    $0x400000,%eax
  sub    %rdx,%rax
  or     %rax,-0x20(%rbp)
L16:
  movabs $0x204081000000000,%rax
  and    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movabs $0x4081020000000,%rax
  and    -0x30(%rbp),%rax
  movabs $0x1fbf7efc0000000,%rdx
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x20000000,%rax
  and    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L5
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  movabs $0x4081020000000,%rax
  and    %rdx,%rax
  or     %rax,-0x20(%rbp)
L5:
  movabs $0x4040404000000000,%rax
  and    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movabs $0x40404040000000,%rax
  and    -0x30(%rbp),%rax
  movabs $0x3fbfbfbf80000000,%rdx
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x40000000,%rax
  and    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L15
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  movabs $0x40404040000000,%rax
  and    %rdx,%rax
  or     %rax,-0x20(%rbp)
L15:
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long flip_B6(const unsigned long long discs_player, const unsigned long long discs_opponent) {
  unsigned long long my_discs, opp_discs, r;
  unsigned long long flipped = (discs_opponent & 0X0000000000004000ULL) & (discs_player << 8);
  flipped |= (discs_opponent & 0X0000000000002000ULL) & (discs_player << 9);
  my_discs = discs_player & 0X00000000001F0000ULL;
  r = ((my_discs << 1) + discs_opponent) & 0X0000000000400000ULL;
  if (r != 0) {
    flipped |= 0X0000000000400000ULL - (0X2ULL << last_bit(my_discs));
  }
  my_discs = discs_player & 0X0204081000000000ULL;
  opp_discs = (discs_opponent & 0X0004081020000000ULL) | 0X01FBF7EFC0000000ULL;
  r = (opp_discs + 0X0000000020000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X0004081020000000ULL;
  }
  my_discs = discs_player & 0X4040404000000000ULL;
  opp_discs = (discs_opponent & 0X0040404040000000ULL) | 0X3FBFBFBF80000000ULL;
  r = (opp_discs + 0X0000000040000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X0040404040000000ULL;
  }
  return flipped;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flip_B6>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdi,%rax
  shl    $0x8,%rax
  and    %rsi,%rax
  and    $0x4000,%eax
  mov    %rdi,%rbp
  shl    $0x9,%rbp
  and    %rsi,%rbp
  and    $0x2000,%ebp
  or     %rax,%rbp
  and    $0x1f0000,%edi
  lea    (%rsi,%rdi,2),%rax
  test   $0x400000,%eax
  jne    L10
L34:
  movabs $0x4081020000000,%rax
  and    %rbx,%rax
  movabs $0x1fbf7efc0000000,%rdx
  or     %rdx,%rax
  add    $0x20000000,%rax
  and    %r12,%rax
  movabs $0x204081000000000,%rdx
  and    %rdx,%rax
  je     L1
  sub    $0x1,%rax
  movabs $0x4081020000000,%rdx
  and    %rdx,%rax
  or     %rax,%rbp
L1:
  movabs $0x40404040000000,%rax
  and    %rax,%rbx
  movabs $0x3fbfbfbf80000000,%rax
  or     %rax,%rbx
  add    $0x40000000,%rbx
  and    %r12,%rbx
  movabs $0x4040404000000000,%rax
  and    %rax,%rbx
  je     L18
  sub    $0x1,%rbx
  movabs $0x40404040000000,%rax
  and    %rax,%rbx
  or     %rbx,%rbp
L18:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    $0x400000,%eax
  sub    %rdx,%rax
  or     %rax,%rbp
  jmp    L34
```

assistant: ```c
unsigned long long flip_B6(const unsigned long long discs_player, const unsigned long long discs_opponent) {
  unsigned long long my_discs, opp_discs, r;
  unsigned long long flipped = (discs_opponent & 0X0000000000004000ULL) & (discs_player << 8);
  flipped |= (discs_opponent & 0X0000000000002000ULL) & (discs_player << 9);
  my_discs = discs_player & 0X00000000001F0000ULL;
  r = ((my_discs << 1) + discs_opponent) & 0X0000000000400000ULL;
  if (r != 0) {
    flipped |= 0X0000000000400000ULL - (0X2ULL << last_bit(my_discs));
  }
  my_discs = discs_player & 0X0204081000000000ULL;
  opp_discs = (discs_opponent & 0X0004081020000000ULL) | 0X01FBF7EFC0000000ULL;
  r = (opp_discs + 0X0000000020000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X0004081020000000ULL;
  }
  my_discs = discs_player & 0X4040404000000000ULL;
  opp_discs = (discs_opponent & 0X0040404040000000ULL) | 0X3FBFBFBF80000000ULL;
  r = (opp_discs + 0X0000000040000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X0040404040000000ULL;
  }
  return flipped;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<flip_B6>:
  endbr64
  push   %r12
  mov    %rdi,%rax
  mov    %rdi,%r12
  shl    $0x8,%rax
  shl    $0x9,%r12
  push   %rbp
  mov    %rdi,%rbp
  and    %rsi,%rax
  and    %rsi,%r12
  and    $0x1f0000,%edi
  push   %rbx
  and    $0x4000,%eax
  and    $0x2000,%r12d
  mov    %rsi,%rbx
  or     %rax,%r12
  lea    (%rsi,%rdi,2),%rax
  test   $0x400000,%eax
  jne    L24
L28:
  movabs $0x4081020000000,%rcx
  mov    %rbx,%rax
  movabs $0x1fbf7efc0000000,%rdx
  and    %rcx,%rax
  or     %rdx,%rax
  movabs $0x204081000000000,%rdx
  add    $0x20000000,%rax
  and    %rbp,%rax
  and    %rdx,%rax
  je     L29
  sub    $0x1,%rax
  and    %rcx,%rax
  or     %rax,%r12
L29:
  movabs $0x40404040000000,%rdx
  movabs $0x3fbfbfbf80000000,%rax
  and    %rdx,%rbx
  or     %rax,%rbx
  movabs $0x4040404000000000,%rax
  add    $0x40000000,%rbx
  and    %rbp,%rbx
  and    %rax,%rbx
  je     L8
  sub    $0x1,%rbx
  and    %rdx,%rbx
  or     %rbx,%r12
L8:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  mov    $0x400000,%eax
  shl    %cl,%rdx
  sub    %rdx,%rax
  or     %rax,%r12
  jmp    L28
```

assistant: ```c
unsigned long long flip_B6(const unsigned long long discs_player, const unsigned long long discs_opponent) {
  unsigned long long my_discs, opp_discs, r;
  unsigned long long flipped = (discs_opponent & 0X0000000000004000ULL) & (discs_player << 8);
  flipped |= (discs_opponent & 0X0000000000002000ULL) & (discs_player << 9);
  my_discs = discs_player & 0X00000000001F0000ULL;
  r = ((my_discs << 1) + discs_opponent) & 0X0000000000400000ULL;
  if (r != 0) {
    flipped |= 0X0000000000400000ULL - (0X2ULL << last_bit(my_discs));
  }
  my_discs = discs_player & 0X0204081000000000ULL;
  opp_discs = (discs_opponent & 0X0004081020000000ULL) | 0X01FBF7EFC0000000ULL;
  r = (opp_discs + 0X0000000020000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X0004081020000000ULL;
  }
  my_discs = discs_player & 0X4040404000000000ULL;
  opp_discs = (discs_opponent & 0X0040404040000000ULL) | 0X3FBFBFBF80000000ULL;
  r = (opp_discs + 0X0000000040000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X0040404040000000ULL;
  }
  return flipped;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flip_B6>:
  endbr64
  push   %r12
  mov    %rdi,%rax
  mov    %rdi,%r12
  shl    $0x8,%rax
  shl    $0x9,%r12
  push   %rbp
  mov    %rdi,%rbp
  and    %rsi,%rax
  and    %rsi,%r12
  and    $0x1f0000,%edi
  push   %rbx
  and    $0x4000,%eax
  and    $0x2000,%r12d
  mov    %rsi,%rbx
  or     %rax,%r12
  lea    (%rsi,%rdi,2),%rax
  test   $0x400000,%eax
  jne    L8
L21:
  movabs $0x4081020000000,%rcx
  mov    %rbx,%rax
  movabs $0x1fbf7efc0000000,%rdx
  and    %rcx,%rax
  or     %rdx,%rax
  movabs $0x204081000000000,%rdx
  add    $0x20000000,%rax
  and    %rbp,%rax
  and    %rdx,%rax
  je     L36
  sub    $0x1,%rax
  and    %rcx,%rax
  or     %rax,%r12
L36:
  movabs $0x40404040000000,%rdx
  movabs $0x3fbfbfbf80000000,%rax
  and    %rdx,%rbx
  or     %rax,%rbx
  movabs $0x4040404000000000,%rax
  add    $0x40000000,%rbx
  and    %rbp,%rbx
  and    %rax,%rbx
  je     L23
  sub    $0x1,%rbx
  and    %rdx,%rbx
  or     %rbx,%r12
L23:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  mov    $0x400000,%eax
  shl    %cl,%rdx
  sub    %rdx,%rax
  or     %rax,%r12
  jmp    L21
```

assistant: ```c
unsigned long long flip_B6(const unsigned long long discs_player, const unsigned long long discs_opponent) {
  unsigned long long my_discs, opp_discs, r;
  unsigned long long flipped = (discs_opponent & 0X0000000000004000ULL) & (discs_player << 8);
  flipped |= (discs_opponent & 0X0000000000002000ULL) & (discs_player << 9);
  my_discs = discs_player & 0X00000000001F0000ULL;
  r = ((my_discs << 1) + discs_opponent) & 0X0000000000400000ULL;
  if (r != 0) {
    flipped |= 0X0000000000400000ULL - (0X2ULL << last_bit(my_discs));
  }
  my_discs = discs_player & 0X0204081000000000ULL;
  opp_discs = (discs_opponent & 0X0004081020000000ULL) | 0X01FBF7EFC0000000ULL;
  r = (opp_discs + 0X0000000020000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X0004081020000000ULL;
  }
  my_discs = discs_player & 0X4040404000000000ULL;
  opp_discs = (discs_opponent & 0X0040404040000000ULL) | 0X3FBFBFBF80000000ULL;
  r = (opp_discs + 0X0000000040000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X0040404040000000ULL;
  }
  return flipped;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strtr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L45
  jmp    L32
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  movb   $0x20,(%rax)
L1:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  jmp    L36
L45:
  nop
L36:
  leave
  ret
```

assistant: ```c
void strtr(char *s) {
  if (s == NULL)
    return;
  for (; *s != '\0'; s++)
    if (isspace(*s))
      *s = ' ';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtr>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L41
L20:
  pop    %rbx
  ret
L23:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L20
L41:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L23
  movb   $0x20,(%rbx)
  jmp    L23
L18:
  ret
```

assistant: ```c
void strtr(char *s) {
  if (s == NULL)
    return;
  for (; *s != '\0'; s++)
    if (isspace(*s))
      *s = ' ';
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtr>:
  endbr64
  test   %rdi,%rdi
  je     L27
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L8
  nopl   (%rax)
L39:
  call   <isspace@plt>
  test   %rax,%rax
  je     L3
  movb   $0x20,(%rbx)
L3:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L39
L8:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L27:
  ret
```

assistant: ```c
void strtr(char *s) {
  if (s == NULL)
    return;
  for (; *s != '\0'; s++)
    if (isspace(*s))
      *s = ' ';
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtr>:
  endbr64
  test   %rdi,%rdi
  je     L15
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L2
  nopl   (%rax)
L36:
  call   <isspace@plt>
  test   %rax,%rax
  je     L6
  movb   $0x20,(%rbx)
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L36
L2:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L6:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L36
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void strtr(char *s) {
  if (s == NULL)
    return;
  for (; *s != '\0'; s++)
    if (isspace(*s))
      *s = ' ';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xbc614e,-0x814(%rbp)
  mov    -0x814(%rbp),%eax
  mov    %eax,%edi
  call   <xorshift_k4_seed@plt>
L14:
  movl   $0x0,-0x818(%rbp)
  jmp    L16
L23:
  mov    $0x0,%eax
  call   <xorshift_k4@plt>
  mov    -0x818(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x810(%rbp,%rdx,4)
  addl   $0x1,-0x818(%rbp)
L16:
  cmpl   $0x1ff,-0x818(%rbp)
  jle    L23
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  lea    -0x810(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x800,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  jmp    L14
```

assistant: ```c
int main() {
  uint64_t seedvalue = 12345678;
  xorshift_k4_seed(seedvalue);
  uint32_t buffer[512];
  while (1) {
    for (int k = 0; k < 512; k++)
      buffer[k] = xorshift_k4();
    fwrite((void *)buffer, sizeof(buffer), 1, stdout);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    $0xbc614e,%edi
  call   <xorshift_k4_seed@plt>
  lea    0x800(%rsp),%rbp
  jmp    L6
L28:
  mov    %rsp,%rdi
  mov    D5(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x1,%edx
  mov    $0x800,%esi
  call   <fwrite@plt>
L6:
  mov    %rsp,%rbx
L5:
  mov    $0x0,%eax
  call   <xorshift_k4@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L5
  jmp    L28
```

assistant: ```c
int main() {
  uint64_t seedvalue = 12345678;
  xorshift_k4_seed(seedvalue);
  uint32_t buffer[512];
  while (1) {
    for (int k = 0; k < 512; k++)
      buffer[k] = xorshift_k4();
    fwrite((void *)buffer, sizeof(buffer), 1, stdout);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xbc614e,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x800(%rsp),%rbp
  call   <xorshift_k4_seed@plt>
  mov    D3(%rip),%r13
L3:
  mov    %r12,%rbx
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <xorshift_k4@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L2
  mov    0x0(%r13),%ecx
  mov    $0x1,%edx
  mov    $0x800,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  jmp    L3
```

assistant: ```c
int main() {
  uint64_t seedvalue = 12345678;
  xorshift_k4_seed(seedvalue);
  uint32_t buffer[512];
  while (1) {
    for (int k = 0; k < 512; k++)
      buffer[k] = xorshift_k4();
    fwrite((void *)buffer, sizeof(buffer), 1, stdout);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xbc614e,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x800(%rsp),%rbp
  call   <xorshift_k4_seed@plt>
  mov    D7(%rip),%r13
L12:
  mov    %r12,%rbx
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <xorshift_k4@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L2
  mov    0x0(%r13),%ecx
  mov    $0x1,%edx
  mov    $0x800,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  jmp    L12
```

assistant: ```c
int main() {
  uint64_t seedvalue = 12345678;
  xorshift_k4_seed(seedvalue);
  uint32_t buffer[512];
  while (1) {
    for (int k = 0; k < 512; k++)
      buffer[k] = xorshift_k4();
    fwrite((void *)buffer, sizeof(buffer), 1, stdout);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fourier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    $0x1,%ebx
  jmp    L13
L16:
  mov    -0x28(%rbp),%rax
  movslq %ebx,%rdx
  movsd  (%rax,%rdx,8),%xmm2
  movsd  %xmm2,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x38(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x58(%rax),%rdx
  movslq %ebx,%rax
  movsd  (%rdx,%rax,8),%xmm3
  movsd  %xmm3,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mulsd  -0x38(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  add    $0x1,%ebx
L13:
  cmp    $0xa,%ebx
  jle    L16
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: f64

tool: D7: 2

assistant: ```c
double fourier(data, ex)
double data[2][11];
double ex;
{
  register int k;
  double fivesm, sixsm;
  sixsm = data[0][0] / 2.0;
  fivesm = 0.0;
  for (k = 1; k < 11; k++) {
    sixsm += (double)(data[0][k] * cos((double)k * ex));
    fivesm += (double)(data[1][k] * sin((double)k * ex));
  }
  sixsm = sixsm + fivesm;
  return (sixsm);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fourier>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbp
  movsd  %xmm0,0x18(%rsp)
  movsd  D9(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    $0x1,%ebx
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x10(%rsp)
  lea    0x28(%rsp),%r12
L5:
  lea    0x20(%rsp),%rsi
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  0x18(%rsp),%xmm0
  mov    %r12,%rdi
  call   <sincos@plt>
  movsd  0x20(%rsp),%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  0x28(%rsp),%xmm0
  mulsd  0x58(%rbp,%rbx,8),%xmm0
  addsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x10(%rsp)
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  jne    L5
  movsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: f32[2]

tool: {"D9": [0.0,1.75]}

assistant: ```c
double fourier(data, ex)
double data[2][11];
double ex;
{
  register int k;
  double fivesm, sixsm;
  sixsm = data[0][0] / 2.0;
  fivesm = 0.0;
  for (k = 1; k < 11; k++) {
    sixsm += (double)(data[0][k] * cos((double)k * ex));
    fivesm += (double)(data[1][k] * sin((double)k * ex));
  }
  sixsm = sixsm + fivesm;
  return (sixsm);
}
```