ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_loopback>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  mov    %edi,%ebp
  mov    $0x10,%esi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x60(%rsp),%rax
  movl   $0x10,0x10(%rsp)
  mov    %rdi,(%rsp)
  mov    %rax,0x8(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  call   <fill_random_buffer@plt>
  mov    %rsp,%rsi
  mov    %ebp,%edi
  call   <send_all_loopback_buffer@plt>
  mov    0xa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0xb0,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_loopback(int fd) {
  uint8_t tx_buf[16] = {0};
  uint8_t rx_buf[(int)(sizeof(tx_buf) / sizeof((tx_buf)[0]))] = {0};
  struct spi_ioc_transfer data = {
      .tx_buf = (unsigned long)tx_buf,
      .rx_buf = (unsigned long)rx_buf,
      .len = (int)(sizeof(tx_buf) / sizeof((tx_buf)[0])),
  };
  fill_random_buffer(tx_buf, (int)(sizeof(tx_buf) / sizeof((tx_buf)[0])));
  return send_all_loopback_buffer(fd, &data);
}
```
user: What is the c source code of the assembly code below?

```asm
<test_loopback>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  mov    %edi,%ebp
  mov    $0x10,%esi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x60(%rsp),%rax
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movq   %rax,%xmm1
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movq   %rdi,%xmm0
  punpcklqdq %xmm1,%xmm0
  movl   $0x10,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <fill_random_buffer@plt>
  mov    %rsp,%rsi
  mov    %ebp,%edi
  call   <send_all_loopback_buffer@plt>
  mov    0xa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0xb0,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_loopback(int fd) {
  uint8_t tx_buf[16] = {0};
  uint8_t rx_buf[(int)(sizeof(tx_buf) / sizeof((tx_buf)[0]))] = {0};
  struct spi_ioc_transfer data = {
      .tx_buf = (unsigned long)tx_buf,
      .rx_buf = (unsigned long)rx_buf,
      .len = (int)(sizeof(tx_buf) / sizeof((tx_buf)[0])),
  };
  fill_random_buffer(tx_buf, (int)(sizeof(tx_buf) / sizeof((tx_buf)[0])));
  return send_all_loopback_buffer(fd, &data);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L10
  mov    $0x1,%eax
  jmp    L2
L10:
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L36:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L36
  mov    -0x14(%rbp),%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int power(int a, int b) {
  int i;
  if (b == 0) {
    return 1;
  }
  for (i = 1; i < b; i++) {
    a *= a;
  }
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<power>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L1
  cmp    $0x1,%esi
  jle    L20
  mov    $0x1,%edx
L2:
  imul   %eax,%eax
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L2
  ret
L1:
  mov    $0x1,%eax
L20:
  ret
```

assistant: ```c
int power(int a, int b) {
  int i;
  if (b == 0) {
    return 1;
  }
  for (i = 1; i < b; i++) {
    a *= a;
  }
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<power>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L21
  cmp    $0x1,%esi
  jle    L8
  mov    $0x1,%edx
  nopl   0x0(%rax)
L13:
  add    $0x1,%edx
  imul   %eax,%eax
  cmp    %edx,%esi
  jne    L13
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0x1,%eax
L8:
  ret
```

assistant: ```c
int power(int a, int b) {
  int i;
  if (b == 0) {
    return 1;
  }
  for (i = 1; i < b; i++) {
    a *= a;
  }
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<power>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L22
  cmp    $0x1,%esi
  jle    L25
  mov    $0x1,%edx
  nopl   0x0(%rax)
L19:
  add    $0x1,%edx
  imul   %eax,%eax
  cmp    %edx,%esi
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%eax
L25:
  ret
```

assistant: ```c
int power(int a, int b) {
  int i;
  if (b == 0) {
    return 1;
  }
  for (i = 1; i < b; i++) {
    a *= a;
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<intToEsp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int32_t intToEsp(int32_t v) {
  int32_t ret;
  char *p = (char *)&ret;
  *p++ = (v >> 0) & 0xff;
  *p++ = (v >> 8) & 0xff;
  *p++ = (v >> 16) & 0xff;
  *p++ = (v >> 24) & 0xff;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<intToEsp>:
  endbr64
  mov    %edi,%ecx
  mov    $0x0,%eax
  mov    %dil,%al
  mov    %ch,%ah
  mov    %edi,%esi
  and    $0xff0000,%esi
  movzwl %ax,%eax
  and    $0xff000000,%ecx
  or     %esi,%eax
  or     %ecx,%eax
  ret
```

assistant: ```c
int32_t intToEsp(int32_t v) {
  int32_t ret;
  char *p = (char *)&ret;
  *p++ = (v >> 0) & 0xff;
  *p++ = (v >> 8) & 0xff;
  *p++ = (v >> 16) & 0xff;
  *p++ = (v >> 24) & 0xff;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intToEsp>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int32_t intToEsp(int32_t v) {
  int32_t ret;
  char *p = (char *)&ret;
  *p++ = (v >> 0) & 0xff;
  *p++ = (v >> 8) & 0xff;
  *p++ = (v >> 16) & 0xff;
  *p++ = (v >> 24) & 0xff;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<intToEsp>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int32_t intToEsp(int32_t v) {
  int32_t ret;
  char *p = (char *)&ret;
  *p++ = (v >> 0) & 0xff;
  *p++ = (v >> 8) & 0xff;
  *p++ = (v >> 16) & 0xff;
  *p++ = (v >> 24) & 0xff;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L15:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jb     L10
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jae    L15
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D8: %d

tool: D1: Too small value, chose another


assistant: ```c
uint32_t read_length(uint32_t min) {
  unsigned int length = 0;
  while (!(length > min)) {
    scanf("%d", &length);
    if (!(length > min))
      printf("Too small value, chose another\n");
  }
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_length>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D10(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D7(%rip),%r13
L20:
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  ja     L19
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  ja     L20
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L20
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D7
type: string

tool: D10: %d

tool: D7: Too small value, chose another


assistant: ```c
uint32_t read_length(uint32_t min) {
  unsigned int length = 0;
  while (!(length > min)) {
    scanf("%d", &length);
    if (!(length > min))
      printf("Too small value, chose another\n");
  }
  return length;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_length>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  jmp    L6
  nopl   (%rax)
L4:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jbe    L7
L6:
  cmp    %eax,%ebx
  jae    L4
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L6
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string
name: read_data
arguments: data_label: D2
data_type: string

tool: D1: Too small value, chose another


tool: D2: %d

assistant: ```c
uint32_t read_length(uint32_t min) {
  unsigned int length = 0;
  while (!(length > min)) {
    scanf("%d", &length);
    if (!(length > min))
      printf("Too small value, chose another\n");
  }
  return length;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_length>:
  endbr64
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  jmp    L28
  nopl   (%rax)
L40:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jbe    L34
L28:
  cmp    %eax,%ebx
  jae    L40
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L28
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string

tool: D2: Too small value, chose another


tool: D1: %d

assistant: ```c
uint32_t read_length(uint32_t min) {
  unsigned int length = 0;
  while (!(length > min)) {
    scanf("%d", &length);
    if (!(length > min))
      printf("Too small value, chose another\n");
  }
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pack_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D12(%rip),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    D43(%rip),%eax
  or     %edx,%eax
  mov    %eax,D113(%rip)
  mov    D12(%rip),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,D113(%rip)
  mov    D113(%rip),%eax
  cmp    $0x7,%eax
  jle    L15
  mov    D113(%rip),%eax
  mov    %al,-0x9(%rbp)
  mov    D113(%rip),%eax
  sub    $0x8,%eax
  mov    %eax,D113(%rip)
  mov    D113(%rip),%eax
  shr    $0x8,%eax
  mov    %eax,D113(%rip)
  mov    D113(%rip),%rax
  mov    (%rax),%edx
  lea    -0x9(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
L15:
  mov    D113(%rip),%eax
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int pack_output(unsigned code, int bits) {
  static unsigned int out_buffer = 0;
  static int out_bits = 0;
  unsigned char out_byte;
  out_buffer |= (code << out_bits);
  out_bits += bits;
  if (out_bits >= 8) {
    out_byte = out_buffer & 0xff;
    out_bits -= 8;
    out_buffer >>= 8;
    fwrite(&out_byte, sizeof(char), 1, stdout);
  }
  return (out_bits > 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pack_output>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D23(%rip),%ecx
  shl    %cl,%edi
  or     D56(%rip),%edi
  mov    %edi,D69(%rip)
  add    %esi,%ecx
  mov    %ecx,D69(%rip)
  cmp    $0x7,%ecx
  jg     L22
L18:
  cmpl   $0x0,D69(%rip)
  setg   %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  ret
L22:
  mov    %dil,0x7(%rsp)
  sub    $0x8,%ecx
  mov    %ecx,D69(%rip)
  shr    $0x8,%edi
  mov    %edi,D69(%rip)
  lea    0x7(%rsp),%rdi
  mov    D69(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  jmp    L18
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pack_output(unsigned code, int bits) {
  static unsigned int out_buffer = 0;
  static int out_bits = 0;
  unsigned char out_byte;
  out_buffer |= (code << out_bits);
  out_bits += bits;
  if (out_bits >= 8) {
    out_byte = out_buffer & 0xff;
    out_bits -= 8;
    out_buffer >>= 8;
    fwrite(&out_byte, sizeof(char), 1, stdout);
  }
  return (out_bits > 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pack_output>:
  endbr64
  sub    $0x18,%rsp
  mov    D2(%rip),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  shl    %cl,%edi
  add    %esi,%ecx
  or     D35(%rip),%edi
  mov    %edi,D8(%rip)
  mov    %ecx,D8(%rip)
  cmp    $0x7,%ecx
  jg     L5
L24:
  xor    %eax,%eax
  test   %ecx,%ecx
  setg   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L5:
  mov    D8(%rip),%rax
  sub    $0x8,%ecx
  mov    %dil,0x7(%rsp)
  shr    $0x8,%edi
  mov    %ecx,D71(%rip)
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    (%rax),%ecx
  mov    %edi,D71(%rip)
  lea    0x7(%rsp),%rdi
  call   <fwrite@plt>
  mov    D71(%rip),%ecx
  jmp    L24
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pack_output(unsigned code, int bits) {
  static unsigned int out_buffer = 0;
  static int out_bits = 0;
  unsigned char out_byte;
  out_buffer |= (code << out_bits);
  out_bits += bits;
  if (out_bits >= 8) {
    out_byte = out_buffer & 0xff;
    out_bits -= 8;
    out_buffer >>= 8;
    fwrite(&out_byte, sizeof(char), 1, stdout);
  }
  return (out_bits > 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pack_output>:
  endbr64
  sub    $0x18,%rsp
  mov    D0(%rip),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  shl    %cl,%edi
  add    %esi,%ecx
  or     D10(%rip),%edi
  mov    %edi,D2(%rip)
  mov    %ecx,D2(%rip)
  cmp    $0x7,%ecx
  jg     L16
L11:
  xor    %eax,%eax
  test   %ecx,%ecx
  setg   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L16:
  mov    D2(%rip),%rax
  sub    $0x8,%ecx
  mov    %dil,0x7(%rsp)
  shr    $0x8,%edi
  mov    %ecx,D50(%rip)
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    (%rax),%ecx
  mov    %edi,D50(%rip)
  lea    0x7(%rsp),%rdi
  call   <fwrite@plt>
  mov    D50(%rip),%ecx
  jmp    L11
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pack_output(unsigned code, int bits) {
  static unsigned int out_buffer = 0;
  static int out_bits = 0;
  unsigned char out_byte;
  out_buffer |= (code << out_bits);
  out_bits += bits;
  if (out_bits >= 8) {
    out_byte = out_buffer & 0xff;
    out_bits -= 8;
    out_buffer >>= 8;
    fwrite(&out_byte, sizeof(char), 1, stdout);
  }
  return (out_bits > 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<func4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <func3@plt>
  mov    $0x2,%eax
  leave
  ret
```

assistant: ```c
int func4(int j) {
  func3(j);
  return 2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func4>:
  endbr64
  sub    $0x8,%rsp
  call   <func3@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int func4(int j) {
  func3(j);
  return 2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func4>:
  endbr64
  sub    $0x8,%rsp
  call   <func3@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int func4(int j) {
  func3(j);
  return 2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func4>:
  endbr64
  sub    $0x8,%rsp
  call   <func3@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int func4(int j) {
  func3(j);
  return 2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x34(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x30(%rbp)
  cmpl   $0x9,-0x30(%rbp)
  jle    L44
  mov    -0x30(%rbp),%eax
  add    $0x57,%eax
  mov    %eax,%edx
  jmp    L73
L44:
  mov    -0x30(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
L73:
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L0
L5:
  mov    -0x34(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x30(%rbp)
  cmpl   $0x9,-0x30(%rbp)
  jle    L47
  mov    -0x30(%rbp),%eax
  add    $0x57,%eax
  mov    %eax,%edx
  jmp    L68
L47:
  mov    -0x30(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
L68:
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x34(%rbp)
L0:
  cmpl   $0x0,-0x34(%rbp)
  jne    L5
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L7
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x30,(%rax)
L7:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

assistant: ```c
void printx(const unsigned int data) {
  uint32_t tmp = data;
  uint32_t tmp2 = 0;
  uint32_t val = 0;
  char str[17];
  char *p = &str[sizeof(str) - 1];
  *p = '\0';
  val = tmp / 16;
  tmp2 = tmp - val * 16;
  *--p = (tmp2 >= 0xa) ? (char)('a' + tmp2 - 0xa) : (char)('0' + tmp2);
  tmp = val;
  while (tmp != 0) {
    val = tmp / 16;
    tmp2 = tmp - val * 16;
    *--p = (tmp2 >= 0xa) ? (char)('a' + tmp2 - 0xa) : (char)('0' + tmp2);
    tmp = val;
  }
  if (!strlen(p))
    *--p = '0';
  print(p, strlen(p));
}
```
user: What is the c source code of the assembly code below?

```asm
<printx>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  lea    0xf(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x4,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  add    %edx,%edi
  and    $0xf,%edi
  sub    %edx,%edi
  lea    0x57(%rdi),%esi
  lea    0x30(%rdi),%edx
  cmp    $0xa,%edi
  cmovge %esi,%edx
  mov    %dl,0xf(%rsp)
  test   %eax,%eax
  je     L48
  mov    %eax,%ecx
  lea    0xf(%rsp),%rbx
L17:
  mov    %ecx,%eax
  lea    0xf(%rcx),%edx
  test   %ecx,%ecx
  cmovns %ecx,%edx
  sar    $0x4,%edx
  mov    %edx,%ecx
  mov    %eax,%esi
  sar    $0x1f,%esi
  shr    $0x1c,%esi
  add    %esi,%eax
  and    $0xf,%eax
  sub    %esi,%eax
  lea    0x57(%rax),%edi
  lea    0x30(%rax),%esi
  cmp    $0xa,%eax
  mov    %edi,%eax
  cmovl  %esi,%eax
  sub    $0x1,%rbx
  mov    %al,(%rbx)
  test   %edx,%edx
  jne    L17
L33:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L31
  movb   $0x30,-0x1(%rbx)
  lea    -0x1(%rbx),%rbx
L31:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x20,%rsp
  pop    %rbx
  ret
L48:
  lea    0xf(%rsp),%rbx
  jmp    L33
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printx(const unsigned int data) {
  uint32_t tmp = data;
  uint32_t tmp2 = 0;
  uint32_t val = 0;
  char str[17];
  char *p = &str[sizeof(str) - 1];
  *p = '\0';
  val = tmp / 16;
  tmp2 = tmp - val * 16;
  *--p = (tmp2 >= 0xa) ? (char)('a' + tmp2 - 0xa) : (char)('0' + tmp2);
  tmp = val;
  while (tmp != 0) {
    val = tmp / 16;
    tmp2 = tmp - val * 16;
    *--p = (tmp2 >= 0xa) ? (char)('a' + tmp2 - 0xa) : (char)('0' + tmp2);
    tmp = val;
  }
  if (!strlen(p))
    *--p = '0';
  print(p, strlen(p));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printx>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  lea    0xf(%rdi),%eax
  movb   $0x0,0x10(%rsp)
  cmovns %edi,%eax
  sar    $0x1f,%edx
  lea    0xf(%rsp),%rbp
  shr    $0x1c,%edx
  add    %edx,%edi
  and    $0xf,%edi
  sub    %edx,%edi
  cmp    $0xa,%edi
  lea    0x57(%rdi),%ecx
  lea    0x30(%rdi),%edx
  cmovge %ecx,%edx
  sar    $0x4,%eax
  mov    %dl,0xf(%rsp)
  je     L13
  nop
L27:
  test   %eax,%eax
  lea    0xf(%rax),%ecx
  mov    %eax,%esi
  cmovns %eax,%ecx
  sar    $0x1f,%esi
  shr    $0x1c,%esi
  lea    (%rax,%rsi,1),%edx
  and    $0xf,%edx
  sub    %esi,%edx
  cmp    $0xa,%edx
  lea    0x57(%rdx),%esi
  lea    0x30(%rdx),%eax
  cmovge %esi,%eax
  sub    $0x1,%rbp
  mov    %al,0x0(%rbp)
  mov    %ecx,%eax
  sar    $0x4,%eax
  jne    L27
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L30
  movb   $0x30,-0x1(%rbp)
  sub    $0x1,%rbp
L30:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <print@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printx(const unsigned int data) {
  uint32_t tmp = data;
  uint32_t tmp2 = 0;
  uint32_t val = 0;
  char str[17];
  char *p = &str[sizeof(str) - 1];
  *p = '\0';
  val = tmp / 16;
  tmp2 = tmp - val * 16;
  *--p = (tmp2 >= 0xa) ? (char)('a' + tmp2 - 0xa) : (char)('0' + tmp2);
  tmp = val;
  while (tmp != 0) {
    val = tmp / 16;
    tmp2 = tmp - val * 16;
    *--p = (tmp2 >= 0xa) ? (char)('a' + tmp2 - 0xa) : (char)('0' + tmp2);
    tmp = val;
  }
  if (!strlen(p))
    *--p = '0';
  print(p, strlen(p));
}
```