ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<inputData>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D18(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D5(%rip),%r12
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <scanf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D18: Enter the day: 

tool: D5: %d

tool: D9: Enter the year: 

assistant: ```c
void inputData(int *nd, int *y) {
  printf("Enter the day: ");
  scanf("%d", nd);
  printf("Enter the year: ");
  scanf("%d", y);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inputData>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D0(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D27(%rip),%r12
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <scanf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string
name: extract_symbolic_data
arguments: data_tag: D12
data_type: string

tool: D0: Enter the day: 

tool: D27: %d

tool: D12: Enter the year: 

assistant: ```c
void inputData(int *nd, int *y) {
  printf("Enter the day: ");
  scanf("%d", nd);
  printf("Enter the year: ");
  scanf("%d", y);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<func2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L5
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x0,(%rax)
L5:
  movq   $0x0,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int func2(void) {
  int x;
  int *p;
  int **pp;
  x = 1;
  p = &x;
  pp = &p;
  if (p != 0)
    **pp = 0;
  p = 0;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func2>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func2(void) {
  int x;
  int *p;
  int **pp;
  x = 1;
  p = &x;
  pp = &p;
  if (p != 0)
    **pp = 0;
  p = 0;
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<func2>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func2(void) {
  int x;
  int *p;
  int **pp;
  x = 1;
  p = &x;
  pp = &p;
  if (p != 0)
    **pp = 0;
  p = 0;
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func2>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func2(void) {
  int x;
  int *p;
  int **pp;
  x = 1;
  p = &x;
  pp = &p;
  if (p != 0)
    **pp = 0;
  p = 0;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Buf_toLong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x9,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L7:
  cmp    %rdx,%rsp
  je     L0
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L0:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L18
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L18:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x20(%rbp),%rdx
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x20(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long Buf_toLong(const char *x) {
  int len = sizeof(long) + 1;
  char buf[len];
  memcpy(buf, x, sizeof(long));
  buf[len - 1] = '\0';
  return strtol(buf, NULL, 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Buf_toLong>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbx
  mov    $0x8,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x17(%rsp)
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long Buf_toLong(const char *x) {
  int len = sizeof(long) + 1;
  char buf[len];
  memcpy(buf, x, sizeof(long));
  buf[len - 1] = '\0';
  return strtol(buf, NULL, 10);
}
```
user: What is the c source code of the assembly code below?

```asm
<Buf_toLong>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x8,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  call   <strtol@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long Buf_toLong(const char *x) {
  int len = sizeof(long) + 1;
  char buf[len];
  memcpy(buf, x, sizeof(long));
  buf[len - 1] = '\0';
  return strtol(buf, NULL, 10);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Buf_toLong>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x8,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  call   <strtol@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x20,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long Buf_toLong(const char *x) {
  int len = sizeof(long) + 1;
  char buf[len];
  memcpy(buf, x, sizeof(long));
  buf[len - 1] = '\0';
  return strtol(buf, NULL, 10);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<umatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <dump_error@plt>
L30:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L34
L28:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L15
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <dump_error@plt>
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L28
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type: string
name: parse_data
arguments: data_label: D8
type: string

tool: D13: allocation failure 1 in umatrix()

tool: D8: allocation failure 2 in umatrix()

assistant: ```c
unsigned int **umatrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  unsigned int **m;
  m = (unsigned int **)malloc((unsigned)(nrh - nrl + 1) * sizeof(unsigned int *));
  if (!m)
    dump_error("allocation failure 1 in umatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (unsigned int *)malloc((unsigned)(nch - ncl + 1) * sizeof(unsigned int));
    if (!m[i])
      dump_error("allocation failure 2 in umatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<umatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %ecx,%r15d
  mov    %esi,%eax
  sub    %edi,%eax
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
L10:
  movslq %r14d,%rbx
  lea    0x0(,%rbx,8),%rax
  sub    %rax,%rbp
  cmp    %r14d,%r13d
  jl     L33
  sub    %r12d,%r15d
  lea    0x4(,%r15,4),%r14d
  movslq %r12d,%r12
  shl    $0x2,%r12
  neg    %r12
  lea    D4(%rip),%r15
  jmp    L18
L6:
  lea    D3(%rip),%rdi
  call   <dump_error@plt>
  jmp    L10
L53:
  add    %r12,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jl     L33
L18:
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  test   %rax,%rax
  jne    L53
  mov    %r15,%rdi
  call   <dump_error@plt>
  jmp    L53
L33:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type: string
name: parse_data
arguments: tag: D3
type: string

tool: D4: allocation failure 2 in umatrix()

tool: D3: allocation failure 1 in umatrix()

assistant: ```c
unsigned int **umatrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  unsigned int **m;
  m = (unsigned int **)malloc((unsigned)(nrh - nrl + 1) * sizeof(unsigned int *));
  if (!m)
    dump_error("allocation failure 1 in umatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (unsigned int *)malloc((unsigned)(nch - ncl + 1) * sizeof(unsigned int));
    if (!m[i])
      dump_error("allocation failure 2 in umatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<umatrix>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  sub    %edi,%eax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    0x8(,%rax,8),%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L12
L2:
  movslq %r12d,%r14
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r12d,%ebp
  jl     L62
  sub    %ebx,%r13d
  shl    $0x2,%rbx
  lea    0x4(,%r13,4),%r12d
  neg    %rbx
  lea    D12(%rip),%r13
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L36:
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jl     L62
L15:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  jne    L36
  mov    %r13,%rdi
  call   <dump_error@plt>
  mov    (%r15,%r14,8),%rax
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L15
L62:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L12:
  lea    D8(%rip),%rdi
  call   <dump_error@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
datatype: string
name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D12: allocation failure 2 in umatrix()

tool: D8: allocation failure 1 in umatrix()

assistant: ```c
unsigned int **umatrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  unsigned int **m;
  m = (unsigned int **)malloc((unsigned)(nrh - nrl + 1) * sizeof(unsigned int *));
  if (!m)
    dump_error("allocation failure 1 in umatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (unsigned int *)malloc((unsigned)(nch - ncl + 1) * sizeof(unsigned int));
    if (!m[i])
      dump_error("allocation failure 2 in umatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<umatrix>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  sub    %edi,%eax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    0x8(,%rax,8),%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L37
L63:
  movslq %r12d,%r14
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r12d,%ebp
  jl     L38
  sub    %ebx,%r13d
  shl    $0x2,%rbx
  lea    0x4(,%r13,4),%r12d
  neg    %rbx
  lea    D8(%rip),%r13
  nopl   (%rax)
L7:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  je     L39
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L7
L38:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r13,%rdi
  call   <dump_error@plt>
  add    %rbx,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L7
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L37:
  lea    D19(%rip),%rdi
  call   <dump_error@plt>
  jmp    L63
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string
name: disassemble_data
arguments: tag: D19
datatype: string

tool: D8: allocation failure 2 in umatrix()

tool: D19: allocation failure 1 in umatrix()

assistant: ```c
unsigned int **umatrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  unsigned int **m;
  m = (unsigned int **)malloc((unsigned)(nrh - nrl + 1) * sizeof(unsigned int *));
  if (!m)
    dump_error("allocation failure 1 in umatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (unsigned int *)malloc((unsigned)(nch - ncl + 1) * sizeof(unsigned int));
    if (!m[i])
      dump_error("allocation failure 2 in umatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_time_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x48(%rbp),%rax
  movl   $0x0,(%rax)
  lea    -0x18(%rbp),%r8
  lea    -0x1c(%rbp),%rdi
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    -0x10(%rbp),%rsi
  push   %rsi
  lea    -0x14(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  add    $0x10,%rsp
  mov    %eax,-0xc(%rbp)
  cmpl   $0x2,-0xc(%rbp)
  jle    L11
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <julian_day@plt>
  mov    -0x40(%rbp),%rdx
  mov    %eax,(%rdx)
L11:
  cmpl   $0x4,-0xc(%rbp)
  jle    L27
  mov    -0x18(%rbp),%eax
  imul   $0xe10,%eax,%edx
  mov    -0x14(%rbp),%eax
  imul   $0x3c,%eax,%eax
  add    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
L27:
  cmpl   $0x5,-0xc(%rbp)
  jle    L14
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
L14:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: %4d-%2d-%2d %2d:%2d:%2d

assistant: ```c
void read_time_string(const char *timestr, int *jul, int *secs) {
  int yy, mm, dd, hh, min, ss, n;
  *jul = 0;
  *secs = 0;
  n = sscanf(timestr, "%4d-%2d-%2d %2d:%2d:%2d", &yy, &mm, &dd, &hh, &min, &ss);
  if (n > 2)
    *jul = julian_day(yy, mm, dd);
  if (n > 4)
    *secs = 3600 * hh + 60 * min;
  if (n > 5)
    *secs += ss;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_time_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x14(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  lea    D8(%rip),%rsi
  call   <sscanf@plt>
  mov    %eax,%ebx
  add    $0x10,%rsp
  cmp    $0x2,%eax
  jg     L14
L24:
  cmp    $0x4,%ebx
  jle    L8
  imul   $0xe10,0xc(%rsp),%eax
  imul   $0x3c,0x10(%rsp),%edx
  add    %edx,%eax
  mov    %eax,0x0(%rbp)
L8:
  cmp    $0x5,%ebx
  jle    L3
  mov    0x14(%rsp),%eax
  add    %eax,0x0(%rbp)
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <julian_day@plt>
  mov    %eax,(%r12)
  jmp    L24
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: %4d-%2d-%2d %2d:%2d:%2d

assistant: ```c
void read_time_string(const char *timestr, int *jul, int *secs) {
  int yy, mm, dd, hh, min, ss, n;
  *jul = 0;
  *secs = 0;
  n = sscanf(timestr, "%4d-%2d-%2d %2d:%2d:%2d", &yy, &mm, &dd, &hh, &min, &ss);
  if (n > 2)
    *jul = julian_day(yy, mm, dd);
  if (n > 4)
    *secs = 3600 * hh + 60 * min;
  if (n > 5)
    *secs += ss;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_time_string>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  movl   $0x0,(%rsi)
  lea    0x4(%rsp),%rcx
  movl   $0x0,(%rdx)
  mov    %rsp,%rdx
  lea    D9(%rip),%rsi
  push   %rax
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <sscanf@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0x2,%eax
  jg     L2
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %eax,%ebp
  mov    (%rsp),%edi
  call   <julian_day@plt>
  mov    %eax,(%r12)
  cmp    $0x4,%ebp
  jle    L11
  imul   $0xe10,0xc(%rsp),%eax
  imul   $0x3c,0x10(%rsp),%edx
  add    %edx,%eax
  mov    %eax,(%rbx)
  cmp    $0x5,%ebp
  je     L11
  add    0x14(%rsp),%eax
  mov    %eax,(%rbx)
  jmp    L11
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: %4d-%2d-%2d %2d:%2d:%2d

assistant: ```c
void read_time_string(const char *timestr, int *jul, int *secs) {
  int yy, mm, dd, hh, min, ss, n;
  *jul = 0;
  *secs = 0;
  n = sscanf(timestr, "%4d-%2d-%2d %2d:%2d:%2d", &yy, &mm, &dd, &hh, &min, &ss);
  if (n > 2)
    *jul = julian_day(yy, mm, dd);
  if (n > 4)
    *secs = 3600 * hh + 60 * min;
  if (n > 5)
    *secs += ss;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_time_string>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  movl   $0x0,(%rsi)
  lea    0x4(%rsp),%rcx
  movl   $0x0,(%rdx)
  mov    %rsp,%rdx
  lea    D5(%rip),%rsi
  push   %rax
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <sscanf@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0x2,%eax
  jg     L17
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %eax,%ebp
  mov    (%rsp),%edi
  call   <julian_day@plt>
  mov    %eax,(%r12)
  cmp    $0x4,%ebp
  jle    L12
  imul   $0xe10,0xc(%rsp),%eax
  imul   $0x3c,0x10(%rsp),%edx
  add    %edx,%eax
  mov    %eax,(%rbx)
  cmp    $0x5,%ebp
  je     L12
  add    0x14(%rsp),%eax
  mov    %eax,(%rbx)
  jmp    L12
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: %4d-%2d-%2d %2d:%2d:%2d

assistant: ```c
void read_time_string(const char *timestr, int *jul, int *secs) {
  int yy, mm, dd, hh, min, ss, n;
  *jul = 0;
  *secs = 0;
  n = sscanf(timestr, "%4d-%2d-%2d %2d:%2d:%2d", &yy, &mm, &dd, &hh, &min, &ss);
  if (n > 2)
    *jul = julian_day(yy, mm, dd);
  if (n > 4)
    *secs = 3600 * hh + 60 * min;
  if (n > 5)
    *secs += ss;
}
```
user: What is the c source code of the assembly code below?

```asm
<raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tcgetattr@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <CATCH_EINTR@plt>
  cmpl   $0x0,-0xc(%rbp)
  jns    L18
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L26
L18:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <cfmakeraw@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <CATCH_EINTR@plt>
  cmpl   $0x0,-0xc(%rbp)
  jns    L43
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L26
L43:
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int raw(int fd) {
  struct termios tt;
  int err;
  CATCH_EINTR(err = tcgetattr(fd, &tt));
  if (err < 0)
    return -errno;
  cfmakeraw(&tt);
  CATCH_EINTR(err = tcsetattr(fd, TCSADRAIN, &tt));
  if (err < 0)
    return -errno;
  return 0;
}
```