ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x14,%eax
L20:
  sub    $0x1,%eax
  jne    L20
  mov    $0x13,%ebx
  lea    D5(%rip),%rbp
  jmp    L36
L14:
  cmp    $0x7531,%ebx
  je     L42
L36:
  add    $0x2,%ebx
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rdx
  shr    $0x20,%rdx
  mov    %ebx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edx
  mov    %ebx,%ecx
  sub    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x2,%eax
  sub    %esi,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  or     %eax,%ecx
  jne    L14
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L14
L42:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main() {
  int i, k, n, j;
  k = 0;
  do {
    k = k + 1;
  } while (k <= 19);
  if (k = 19)
    ;
  {
    do {
      k = k + 2;
      if (k % 3 == 0 && k % 7 == 0) {
        printf("%d\n", k);
      }
    } while (k <= 30000);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  mov    $0x13,%ebp
  push   %rbx
  lea    D2(%rip),%rbx
  jmp    L17
  nopl   0x0(%rax)
L37:
  cmp    $0x7531,%ebp
  je     L23
L17:
  lea    0x2(%rbp),%edx
  mov    %rdx,%rax
  mov    %rdx,%rbp
  mov    %edx,%ecx
  imul   %r12,%rax
  imul   $0x24924925,%rdx,%rdx
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  shr    $0x20,%rdx
  sub    %eax,%ecx
  mov    %ebp,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  or     %eax,%ecx
  jne    L37
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    $0x7531,%ebp
  jne    L17
L23:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D2: %d


assistant: ```c
int main() {
  int i, k, n, j;
  k = 0;
  do {
    k = k + 1;
  } while (k <= 19);
  if (k = 19)
    ;
  {
    do {
      k = k + 2;
      if (k % 3 == 0 && k % 7 == 0) {
        printf("%d\n", k);
      }
    } while (k <= 30000);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  mov    $0x13,%ebp
  push   %rbx
  lea    D0(%rip),%rbx
  jmp    L34
  nopl   0x0(%rax)
L18:
  cmp    $0x7531,%ebp
  je     L31
L34:
  lea    0x2(%rbp),%edx
  mov    %rdx,%rax
  mov    %rdx,%rbp
  mov    %edx,%ecx
  imul   %r12,%rax
  imul   $0x24924925,%rdx,%rdx
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  shr    $0x20,%rdx
  sub    %eax,%ecx
  mov    %ebp,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  or     %eax,%ecx
  jne    L18
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    $0x7531,%ebp
  jne    L34
L31:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main() {
  int i, k, n, j;
  k = 0;
  do {
    k = k + 1;
  } while (k <= 19);
  if (k = 19)
    ;
  {
    do {
      k = k + 2;
      if (k % 3 == 0 && k % 7 == 0) {
        printf("%d\n", k);
      }
    } while (k <= 30000);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_builtin_choose_expr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <__emit_expression_range@plt>
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <__emit_expression_range@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_builtin_choose_expr(int i) {
  __emit_expression_range(0, __builtin_choose_expr(1, i, i) + i);
  __emit_expression_range(0, i + __builtin_choose_expr(1, i, i));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_builtin_choose_expr>:
  endbr64
  push   %rbx
  lea    (%rdi,%rdi,1),%ebx
  mov    %ebx,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <__emit_expression_range@plt>
  mov    %ebx,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <__emit_expression_range@plt>
  pop    %rbx
  ret
```

assistant: ```c
void test_builtin_choose_expr(int i) {
  __emit_expression_range(0, __builtin_choose_expr(1, i, i) + i);
  __emit_expression_range(0, i + __builtin_choose_expr(1, i, i));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_builtin_choose_expr>:
  endbr64
  push   %rbp
  lea    (%rdi,%rdi,1),%ebp
  xor    %eax,%eax
  xor    %edi,%edi
  mov    %ebp,%esi
  call   <__emit_expression_range@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <__emit_expression_range@plt>
```

assistant: ```c
void test_builtin_choose_expr(int i) {
  __emit_expression_range(0, __builtin_choose_expr(1, i, i) + i);
  __emit_expression_range(0, i + __builtin_choose_expr(1, i, i));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_builtin_choose_expr>:
  endbr64
  push   %rbp
  lea    (%rdi,%rdi,1),%ebp
  xor    %eax,%eax
  xor    %edi,%edi
  mov    %ebp,%esi
  call   <__emit_expression_range@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <__emit_expression_range@plt>
```

assistant: ```c
void test_builtin_choose_expr(int i) {
  __emit_expression_range(0, __builtin_choose_expr(1, i, i) + i);
  __emit_expression_range(0, i + __builtin_choose_expr(1, i, i));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0xa,-0x4(%rbp)
  jle    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: %d	

assistant: ```c
int main(void) {
  int counter;
  for (counter = 1; counter <= 10; ++counter) {
    printf("%d\t", counter);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D6(%rip),%rbp
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: %d	

assistant: ```c
int main(void) {
  int counter;
  for (counter = 1; counter <= 10; ++counter) {
    printf("%d\t", counter);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: %d	

assistant: ```c
int main(void) {
  int counter;
  for (counter = 1; counter <= 10; ++counter) {
    printf("%d\t", counter);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: %d	

assistant: ```c
int main(void) {
  int counter;
  for (counter = 1; counter <= 10; ++counter) {
    printf("%d\t", counter);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<updateYoungObject>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    %rax,%rdi
  call   <updatePointer@plt>
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    $0x3b4,%eax
  jne    L1
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L22
L1:
  mov    -0x18(%rbp),%rax
  mov    0x20(%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L22
L31:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <updatePointer@plt>
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L31
  nop
  nop
  leave
  ret
```

assistant: ```c
void updateYoungObject(int *object) {
  updatePointer(object + 3);
  int field = *(object + 4);
  int fieldEnd;
  if (*(object + 3) == (237 << 2)) {
    fieldEnd = *(object + 6) + *(object + *(object + 4) + 2);
  } else {
    fieldEnd = *(object + 8);
  }
  for (; field < fieldEnd; ++field) {
    updatePointer(object + field);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<updateYoungObject>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0xc(%rdi),%rdi
  call   <updatePointer@plt>
  mov    0x10(%rbp),%edx
  cmpl   $0x3b4,0xc(%rbp)
  je     L1
  mov    0x20(%rbp),%eax
L12:
  cmp    %edx,%eax
  jle    L37
  movslq %edx,%rcx
  lea    0x0(%rbp,%rcx,4),%rbx
  sub    %edx,%eax
  lea    -0x1(%rax),%eax
  add    %rcx,%rax
  lea    0x4(%rbp,%rax,4),%rbp
L10:
  mov    %rbx,%rdi
  call   <updatePointer@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L10
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  movslq %edx,%rcx
  mov    0x18(%rbp),%eax
  add    0x8(%rbp,%rcx,4),%eax
  jmp    L12
```

assistant: ```c
void updateYoungObject(int *object) {
  updatePointer(object + 3);
  int field = *(object + 4);
  int fieldEnd;
  if (*(object + 3) == (237 << 2)) {
    fieldEnd = *(object + 6) + *(object + *(object + 4) + 2);
  } else {
    fieldEnd = *(object + 8);
  }
  for (; field < fieldEnd; ++field) {
    updatePointer(object + field);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<updateYoungObject>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  add    $0xc,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <updatePointer@plt>
  cmpl   $0x3b4,0xc(%rbp)
  mov    0x10(%rbp),%edx
  je     L34
  mov    0x20(%rbp),%eax
L3:
  cmp    %edx,%eax
  jle    L10
  sub    %edx,%eax
  movslq %edx,%rcx
  sub    $0x1,%eax
  lea    0x0(%rbp,%rcx,4),%rbx
  add    %rcx,%rax
  lea    0x4(%rbp,%rax,4),%rbp
  xchg   %ax,%ax
L26:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <updatePointer@plt>
  cmp    %rbp,%rbx
  jne    L26
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  movslq %edx,%rcx
  mov    0x18(%rbp),%eax
  add    0x8(%rbp,%rcx,4),%eax
  jmp    L3
```

assistant: ```c
void updateYoungObject(int *object) {
  updatePointer(object + 3);
  int field = *(object + 4);
  int fieldEnd;
  if (*(object + 3) == (237 << 2)) {
    fieldEnd = *(object + 6) + *(object + *(object + 4) + 2);
  } else {
    fieldEnd = *(object + 8);
  }
  for (; field < fieldEnd; ++field) {
    updatePointer(object + field);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<updateYoungObject>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  add    $0xc,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <updatePointer@plt>
  cmpl   $0x3b4,0xc(%rbp)
  mov    0x10(%rbp),%edx
  je     L15
  mov    0x20(%rbp),%eax
L32:
  cmp    %edx,%eax
  jle    L22
  sub    %edx,%eax
  movslq %edx,%rcx
  sub    $0x1,%eax
  lea    0x0(%rbp,%rcx,4),%rbx
  add    %rcx,%rax
  lea    0x4(%rbp,%rax,4),%rbp
  xchg   %ax,%ax
L16:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <updatePointer@plt>
  cmp    %rbp,%rbx
  jne    L16
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movslq %edx,%rcx
  mov    0x18(%rbp),%eax
  add    0x8(%rbp,%rcx,4),%eax
  jmp    L32
```

assistant: ```c
void updateYoungObject(int *object) {
  updatePointer(object + 3);
  int field = *(object + 4);
  int fieldEnd;
  if (*(object + 3) == (237 << 2)) {
    fieldEnd = *(object + 6) + *(object + *(object + 4) + 2);
  } else {
    fieldEnd = *(object + 8);
  }
  for (; field < fieldEnd; ++field) {
    updatePointer(object + field);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimerConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0xc,%rdx
  and    $0xfffffffffffffefe,%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  shr    $0x18,%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  or     $0x2,%ah
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  or     $0x2,%ah
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TimerConfigure(unsigned long ulBase, unsigned long ulConfig) {
  ;

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) &= ~(0x00000001 | 0x00000100);
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulConfig >> 24;
  (*((volatile unsigned long *)(ulBase + 0x00000004))) = (ulConfig & 255) | 0x00000200;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ((ulConfig >> 8) & 255) | 0x00000200;
}
```
user: What is the c source code of the assembly code below?

```asm
<TimerConfigure>:
  endbr64
  mov    %rsi,%rax
  mov    0xc(%rdi),%rdx
  and    $0xfffffffffffffefe,%rdx
  mov    %rdx,0xc(%rdi)
  mov    %rsi,%rdx
  shr    $0x18,%rdx
  mov    %rdx,(%rdi)
  movzbl %sil,%edx
  or     $0x2,%dh
  mov    %rdx,0x4(%rdi)
  movzbl %ah,%eax
  or     $0x2,%ah
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerConfigure(unsigned long ulBase, unsigned long ulConfig) {
  ;

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) &= ~(0x00000001 | 0x00000100);
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulConfig >> 24;
  (*((volatile unsigned long *)(ulBase + 0x00000004))) = (ulConfig & 255) | 0x00000200;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ((ulConfig >> 8) & 255) | 0x00000200;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TimerConfigure>:
  endbr64
  mov    0xc(%rdi),%rdx
  mov    %rsi,%rax
  movzbl %ah,%eax
  and    $0xfffffffffffffefe,%rdx
  or     $0x2,%ah
  mov    %rdx,0xc(%rdi)
  mov    %rsi,%rdx
  shr    $0x18,%rdx
  mov    %rdx,(%rdi)
  movzbl %sil,%edx
  or     $0x2,%dh
  mov    %rdx,0x4(%rdi)
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerConfigure(unsigned long ulBase, unsigned long ulConfig) {
  ;

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) &= ~(0x00000001 | 0x00000100);
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulConfig >> 24;
  (*((volatile unsigned long *)(ulBase + 0x00000004))) = (ulConfig & 255) | 0x00000200;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ((ulConfig >> 8) & 255) | 0x00000200;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<TimerConfigure>:
  endbr64
  mov    0xc(%rdi),%rdx
  mov    %rsi,%rax
  movzbl %ah,%eax
  and    $0xfffffffffffffefe,%rdx
  or     $0x2,%ah
  mov    %rdx,0xc(%rdi)
  mov    %rsi,%rdx
  shr    $0x18,%rdx
  mov    %rdx,(%rdi)
  movzbl %sil,%edx
  or     $0x2,%dh
  mov    %rdx,0x4(%rdi)
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerConfigure(unsigned long ulBase, unsigned long ulConfig) {
  ;

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) &= ~(0x00000001 | 0x00000100);
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulConfig >> 24;
  (*((volatile unsigned long *)(ulBase + 0x00000004))) = (ulConfig & 255) | 0x00000200;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ((ulConfig >> 8) & 255) | 0x00000200;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zerofill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %edi,-0x1024(%rbp)
  mov    %esi,-0x1028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1010(%rbp),%rax
  mov    $0x1000,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x101c(%rbp)
  jmp    L39
L36:
  movl   $0x1000,-0x1018(%rbp)
  mov    -0x101c(%rbp),%edx
  mov    -0x1018(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1028(%rbp)
  jge    L6
  mov    -0x1028(%rbp),%eax
  sub    -0x101c(%rbp),%eax
  mov    %eax,-0x1018(%rbp)
L6:
  mov    -0x1018(%rbp),%edx
  lea    -0x1010(%rbp),%rcx
  mov    -0x1024(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x1014(%rbp)
  mov    -0x1014(%rbp),%eax
  cmp    -0x1018(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x1018(%rbp),%eax
  add    %eax,-0x101c(%rbp)
L39:
  mov    -0x101c(%rbp),%eax
  cmp    -0x1028(%rbp),%eax
  jl     L36
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void zerofill(int fd, int size) {
  char buffer[4096];
  memset(buffer, 0, sizeof(buffer));
  int offset = 0;
  while (offset < size) {
    int toWrite = sizeof(buffer);
    if (offset + toWrite > size) {
      toWrite = size - offset;
    }
    int written = write(fd, buffer, toWrite);
    assert(written == toWrite);
    offset += toWrite;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<zerofill>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1000,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L3
  mov    $0x0,%ebp
  mov    $0x1000,%r14d
L18:
  lea    0x1000(%rbp),%eax
  mov    %r12d,%ebx
  sub    %ebp,%ebx
  cmp    %r12d,%eax
  cmovle %r14d,%ebx
  mov    %rsp,%rsi
  mov    %ebx,%edx
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %eax,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    %ebx,%ebp
  cmp    %ebp,%r12d
  jg     L18
L3:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zerofill(int fd, int size) {
  char buffer[4096];
  memset(buffer, 0, sizeof(buffer));
  int offset = 0;
  while (offset < size) {
    int toWrite = sizeof(buffer);
    if (offset + toWrite > size) {
      toWrite = size - offset;
    }
    int written = write(fd, buffer, toWrite);
    assert(written == toWrite);
    offset += toWrite;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<zerofill>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1000,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %esi,%ebp
  mov    %edi,%r12d
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L35
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %ebx,%eax
  add    $0x1000,%ebx
  cmp    %ebp,%ebx
  jle    L48
  sub    %eax,%ebp
  mov    %r12d,%edi
  mov    %r13,%rsi
  mov    %ebp,%edx
  call   <write@plt>
  xor    %edi,%edi
  cmp    %eax,%ebp
  sete   %dil
  call   <assert@plt>
L35:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L48:
  mov    %r12d,%edi
  mov    $0x1000,%edx
  mov    %r13,%rsi
  call   <write@plt>
  xor    %edi,%edi
  cmp    $0x1000,%eax
  sete   %dil
  call   <assert@plt>
  cmp    %ebp,%ebx
  jl     L43
  jmp    L35
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zerofill(int fd, int size) {
  char buffer[4096];
  memset(buffer, 0, sizeof(buffer));
  int offset = 0;
  while (offset < size) {
    int toWrite = sizeof(buffer);
    if (offset + toWrite > size) {
      toWrite = size - offset;
    }
    int written = write(fd, buffer, toWrite);
    assert(written == toWrite);
    offset += toWrite;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zerofill>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1000,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %edi,%r12d
  mov    %esi,%ebx
  mov    %r13,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  jle    L36
  nopw   0x0(%rax,%rax,1)
L44:
  lea    0x1000(%rax),%ebp
  cmp    %ebx,%ebp
  jle    L3
  sub    %eax,%ebx
  mov    %r12d,%edi
  mov    %r13,%rsi
  mov    %ebx,%edx
  call   <write@plt>
  xor    %edi,%edi
  cmp    %eax,%ebx
  sete   %dil
  call   <assert@plt>
L36:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%edi
  mov    $0x1000,%edx
  mov    %r13,%rsi
  call   <write@plt>
  xor    %edi,%edi
  cmp    $0x1000,%eax
  sete   %dil
  call   <assert@plt>
  cmp    %ebx,%ebp
  jge    L36
  mov    %ebp,%eax
  jmp    L44
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zerofill(int fd, int size) {
  char buffer[4096];
  memset(buffer, 0, sizeof(buffer));
  int offset = 0;
  while (offset < size) {
    int toWrite = sizeof(buffer);
    if (offset + toWrite > size) {
      toWrite = size - offset;
    }
    int written = write(fd, buffer, toWrite);
    assert(written == toWrite);
    offset += toWrite;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<admin_send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    %eax,-0x4(%rbp)
  je     L9
  mov    $0xffffffff,%eax
  jmp    L1
L9:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <shutdown@plt>
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int admin_send(int fd, const char *str) {
  int len = strlen(str);
  if (write(fd, str, len) != len)
    return -1;
  shutdown(fd, SHUT_WR);
  return 0;
}
```