user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x9c(%rbp)
  jmp    L66
L142:
  movl   $0x0,-0x98(%rbp)
  jmp    L126
L147:
  lea    -0x90(%rbp),%rcx
  mov    -0x98(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x98(%rbp)
L126:
  cmpl   $0x2,-0x98(%rbp)
  jle    L147
  addl   $0x1,-0x9c(%rbp)
L66:
  cmpl   $0x2,-0x9c(%rbp)
  jle    L142
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x9c(%rbp)
  jmp    L33
L87:
  movl   $0x0,-0x98(%rbp)
  jmp    L132
L125:
  lea    -0x60(%rbp),%rcx
  mov    -0x98(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x98(%rbp)
L132:
  cmpl   $0x2,-0x98(%rbp)
  jle    L125
  addl   $0x1,-0x9c(%rbp)
L33:
  cmpl   $0x2,-0x9c(%rbp)
  jle    L87
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x9c(%rbp)
  jmp    L40
L124:
  movl   $0x0,-0x98(%rbp)
  jmp    L20
L92:
  mov    -0x98(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x9c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movl   $0x0,-0x30(%rbp,%rax,4)
  movl   $0x0,-0x94(%rbp)
  jmp    L121
L57:
  mov    -0x98(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x9c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%esi
  mov    -0x94(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x9c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x90(%rbp,%rax,4),%ecx
  mov    -0x98(%rbp),%eax
  movslq %eax,%rdi
  mov    -0x94(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rdi,%rax
  mov    -0x60(%rbp,%rax,4),%eax
  imul   %ecx,%eax
  lea    (%rsi,%rax,1),%ecx
  mov    -0x98(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    %ecx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x94(%rbp)
L121:
  cmpl   $0x2,-0x94(%rbp)
  jle    L57
  mov    -0x98(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x9c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x98(%rbp)
L20:
  cmpl   $0x2,-0x98(%rbp)
  jle    L92
  addl   $0x1,-0x9c(%rbp)
L40:
  cmpl   $0x2,-0x9c(%rbp)
  jle    L124
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L93
  call   <__stack_chk_fail@plt>
L93:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D47
type_guessed: string
name: extract_symbolic_data
arguments: tag: D51
type_guessed: string
name: extract_symbolic_data
arguments: tag: D58
type_guessed: string
name: extract_symbolic_data
arguments: tag: D52
type_guessed: string
name: extract_symbolic_data
arguments: tag: D22
type_guessed: string

tool: D47: Enter the first matrix elements

tool: D51: %d

tool: D58: Enter the second matrix elements

tool: D52: The multiplicated matrix is:

tool: D22: %d	

assistant: ```c
int main() {
  int a[3][3], b[3][3], c[3][3], i, j, k;
  printf("Enter the first matrix elements");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%d", &a[i][j]);
    }
  }
  printf("Enter the second matrix elements");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%d", &b[i][j]);
    }
  }
  printf("The multiplicated matrix is:");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      c[i][j] = 0;
      for (k = 0; k < 3; k++)
        c[i][j] = c[i][j] + a[i][k] * b[k][j];
      printf("%d\t", c[i][j]);
    }
  }
  return 0;
}
```