ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverseVowels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L21
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isVowel@plt>
  test   %rax,%rax
  je     L27
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isVowel@plt>
  test   %rax,%rax
  je     L27
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
  jmp    L21
L27:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isVowel@plt>
  test   %rax,%rax
  jne    L2
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isVowel@plt>
  test   %rax,%rax
  jne    L21
  subl   $0x1,-0x4(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L14
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *reverseVowels(char *s) {
  int l = 0;
  int r = strlen(s) - 1;
  while (l < r) {
    if (isVowel(s[l]) && isVowel(s[r])) {
      swap(s + l, s + r);
      l++;
      r--;
    } else {
      if (!isVowel(s[l]))
        l++;
      if (!isVowel(s[r]))
        r--;
    }
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverseVowels>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  test   %ebp,%ebp
  jle    L26
  mov    $0x0,%r12d
  jmp    L22
L46:
  movsbl (%rbx),%edi
  call   <isVowel@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
  movslq %ebp,%rax
  movsbl 0x0(%r13,%rax,1),%edi
  call   <isVowel@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%ebp
L56:
  cmp    %ebp,%r12d
  jge    L26
L22:
  movslq %r12d,%rbx
  add    %r13,%rbx
  movsbl (%rbx),%edi
  call   <isVowel@plt>
  test   %rax,%rax
  je     L46
  movslq %ebp,%r14
  add    %r13,%r14
  movsbl (%r14),%edi
  call   <isVowel@plt>
  test   %rax,%rax
  je     L46
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <swap@plt>
  add    $0x1,%r12d
  sub    $0x1,%ebp
  jmp    L56
L26:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *reverseVowels(char *s) {
  int l = 0;
  int r = strlen(s) - 1;
  while (l < r) {
    if (isVowel(s[l]) && isVowel(s[r])) {
      swap(s + l, s + r);
      l++;
      r--;
    } else {
      if (!isVowel(s[l]))
        l++;
      if (!isVowel(s[r]))
        r--;
    }
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverseVowels>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  test   %ebx,%ebx
  jle    L6
  xor    %r13d,%r13d
  jmp    L37
L24:
  movsbl 0x0(%rbp),%edi
  call   <isVowel@plt>
  movsbl (%r12),%edi
  cmp    $0x1,%rax
  adc    $0x0,%r13d
  call   <isVowel@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%ebx
  cmp    %r13d,%ebx
  jle    L6
L37:
  movslq %r13d,%rbp
  movslq %ebx,%r12
  add    %r14,%rbp
  add    %r14,%r12
  movsbl 0x0(%rbp),%edi
  call   <isVowel@plt>
  test   %rax,%rax
  je     L24
  movsbl (%r12),%edi
  call   <isVowel@plt>
  test   %rax,%rax
  je     L24
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r13d
  sub    $0x1,%ebx
  call   <swap@plt>
  cmp    %r13d,%ebx
  jg     L37
L6:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *reverseVowels(char *s) {
  int l = 0;
  int r = strlen(s) - 1;
  while (l < r) {
    if (isVowel(s[l]) && isVowel(s[r])) {
      swap(s + l, s + r);
      l++;
      r--;
    } else {
      if (!isVowel(s[l]))
        l++;
      if (!isVowel(s[r]))
        r--;
    }
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverseVowels>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  test   %ebx,%ebx
  jle    L53
  xor    %r13d,%r13d
  jmp    L15
L36:
  movsbl 0x0(%rbp),%edi
  call   <isVowel@plt>
  movsbl (%r12),%edi
  cmp    $0x1,%rax
  adc    $0x0,%r13d
  call   <isVowel@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%ebx
  cmp    %r13d,%ebx
  jle    L53
L15:
  movslq %r13d,%rbp
  movslq %ebx,%r12
  add    %r14,%rbp
  add    %r14,%r12
  movsbl 0x0(%rbp),%edi
  call   <isVowel@plt>
  test   %rax,%rax
  je     L36
  movsbl (%r12),%edi
  call   <isVowel@plt>
  test   %rax,%rax
  je     L36
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r13d
  sub    $0x1,%ebx
  call   <swap@plt>
  cmp    %r13d,%ebx
  jg     L15
L53:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *reverseVowels(char *s) {
  int l = 0;
  int r = strlen(s) - 1;
  while (l < r) {
    if (isVowel(s[l]) && isVowel(s[r])) {
      swap(s + l, s + r);
      l++;
      r--;
    } else {
      if (!isVowel(s[l]))
        l++;
      if (!isVowel(s[r]))
        r--;
    }
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L11
  cmpl   $0x80,-0x4(%rbp)
  jne    L33
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  jmp    L26
L33:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  nop
  cmpl   $0x3e7,-0x8(%rbp)
  jle    L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
L26:
  leave
  ret
```

assistant: ```c
int getLine(FILE *filein, char *line) {
  int i = 0;
  int c;
  while (1) {
    c = getc(filein);
    switch (c) {
    case EOF:
    case '\n':
      line[i] = '\0';
      return c;
      break;
    default:
      line[i++] = c;
      break;
    }
    if (i >= 1000) {
      line[i] = '\0';
      return c;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L25:
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L23
  cmp    $0x80,%eax
  je     L23
  add    $0x1,%ebx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    $0x3e8,%ebx
  jne    L25
  movb   $0x0,0x3e8(%r12)
  jmp    L19
L23:
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getLine(FILE *filein, char *line) {
  int i = 0;
  int c;
  while (1) {
    c = getc(filein);
    switch (c) {
    case EOF:
    case '\n':
      line[i] = '\0';
      return c;
      break;
    default:
      line[i++] = c;
      break;
    }
    if (i >= 1000) {
      line[i] = '\0';
      return c;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getLine>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x3e8(%rsi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L13
L26:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L30
L13:
  mov    %rbp,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L27
  cmp    $0x80,%eax
  jne    L26
L27:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  movb   $0x0,0x3e8(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getLine(FILE *filein, char *line) {
  int i = 0;
  int c;
  while (1) {
    c = getc(filein);
    switch (c) {
    case EOF:
    case '\n':
      line[i] = '\0';
      return c;
      break;
    default:
      line[i++] = c;
      break;
    }
    if (i >= 1000) {
      line[i] = '\0';
      return c;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getLine>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x3e8(%rsi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L23
L39:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L9
L23:
  mov    %rbp,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L2
  cmp    $0x80,%eax
  jne    L39
L2:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  movb   $0x0,0x3e8(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getLine(FILE *filein, char *line) {
  int i = 0;
  int c;
  while (1) {
    c = getc(filein);
    switch (c) {
    case EOF:
    case '\n':
      line[i] = '\0';
      return c;
      break;
    default:
      line[i++] = c;
      break;
    }
    if (i >= 1000) {
      line[i] = '\0';
      return c;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_long_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movabs $0x8000000000000000,%rax
  mov    %rax,-0x10(%rbp)
  movabs $0x7fffffffffffffff,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x0,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_long_range(long n) {
  const long min = (-0x7fffffffffffffffL - 1L);
  const long max = 0x7fffffffffffffffL;
  sink(f_long_1(n));
  sink(f_long_1(signed_range(min, min + 1)));
  sink(f_long_1(signed_range(min, 0)));
  sink(f_long_1(signed_range(-1, 0)));
  sink(f_long_1(signed_range(-1, 1)));
  sink(f_long_1(signed_range(0, 1)));
  sink(f_long_1(signed_range(0, max - 1)));
  sink(f_long_1(signed_range(1, max)));
  sink(f_long_1(signed_range(max - 1, max)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_long_range>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  movabs $0x8000000000000001,%rsi
  movabs $0x8000000000000000,%rbx
  mov    %rbx,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x0,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  lea    -0x2(%rbx),%rbx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  movabs $0x7fffffffffffffff,%rbp
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test_long_range(long n) {
  const long min = (-0x7fffffffffffffffL - 1L);
  const long max = 0x7fffffffffffffffL;
  sink(f_long_1(n));
  sink(f_long_1(signed_range(min, min + 1)));
  sink(f_long_1(signed_range(min, 0)));
  sink(f_long_1(signed_range(-1, 0)));
  sink(f_long_1(signed_range(-1, 1)));
  sink(f_long_1(signed_range(0, 1)));
  sink(f_long_1(signed_range(0, max - 1)));
  sink(f_long_1(signed_range(1, max)));
  sink(f_long_1(signed_range(max - 1, max)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_long_range>:
  endbr64
  push   %r12
  movabs $0x7fffffffffffffff,%r12
  push   %rbp
  movabs $0x8000000000000000,%rbp
  sub    $0x8,%rsp
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %rbp,%rdi
  movabs $0x8000000000000001,%rsi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x2,%rbp
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  xor    %esi,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    1090 <sink@plt>
```

assistant: ```c
void test_long_range(long n) {
  const long min = (-0x7fffffffffffffffL - 1L);
  const long max = 0x7fffffffffffffffL;
  sink(f_long_1(n));
  sink(f_long_1(signed_range(min, min + 1)));
  sink(f_long_1(signed_range(min, 0)));
  sink(f_long_1(signed_range(-1, 0)));
  sink(f_long_1(signed_range(-1, 1)));
  sink(f_long_1(signed_range(0, 1)));
  sink(f_long_1(signed_range(0, max - 1)));
  sink(f_long_1(signed_range(1, max)));
  sink(f_long_1(signed_range(max - 1, max)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_long_range>:
  endbr64
  push   %r12
  movabs $0x7fffffffffffffff,%r12
  push   %rbp
  movabs $0x8000000000000000,%rbp
  sub    $0x8,%rsp
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %rbp,%rdi
  movabs $0x8000000000000001,%rsi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x2,%rbp
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  xor    %esi,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <signed_range@plt>
  mov    %rax,%rdi
  call   <f_long_1@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    1090 <sink@plt>
```

assistant: ```c
void test_long_range(long n) {
  const long min = (-0x7fffffffffffffffL - 1L);
  const long max = 0x7fffffffffffffffL;
  sink(f_long_1(n));
  sink(f_long_1(signed_range(min, min + 1)));
  sink(f_long_1(signed_range(min, 0)));
  sink(f_long_1(signed_range(-1, 0)));
  sink(f_long_1(signed_range(-1, 1)));
  sink(f_long_1(signed_range(0, 1)));
  sink(f_long_1(signed_range(0, max - 1)));
  sink(f_long_1(signed_range(1, max)));
  sink(f_long_1(signed_range(max - 1, max)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string

tool: D8: %d 

assistant: ```c
void printA(int *a, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%d ", a[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printA>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L1
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D9(%rip),%rbp
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L16
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: %d 

assistant: ```c
void printA(int *a, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%d ", a[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printA>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: %d 

assistant: ```c
void printA(int *a, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%d ", a[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printA>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L12:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L12
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: %d 

assistant: ```c
void printA(int *a, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%d ", a[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<deserialize_float64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unpacku64@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xb,%edx
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <unpack754@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
extern double deserialize_float64(unsigned char *buf) {
  unsigned long long int fhold = unpacku64(buf);
  return ((double)(unpack754((fhold), 64, 11)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<deserialize_float64>:
  endbr64
  sub    $0x8,%rsp
  call   <unpacku64@plt>
  mov    %rax,%rdi
  mov    $0xb,%edx
  mov    $0x40,%esi
  call   <unpack754@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern double deserialize_float64(unsigned char *buf) {
  unsigned long long int fhold = unpacku64(buf);
  return ((double)(unpack754((fhold), 64, 11)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<deserialize_float64>:
  endbr64
  sub    $0x8,%rsp
  call   <unpacku64@plt>
  mov    $0xb,%edx
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <unpack754@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2sd %rax,%xmm0
  ret
```

assistant: ```c
extern double deserialize_float64(unsigned char *buf) {
  unsigned long long int fhold = unpacku64(buf);
  return ((double)(unpack754((fhold), 64, 11)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<deserialize_float64>:
  endbr64
  sub    $0x8,%rsp
  call   <unpacku64@plt>
  mov    $0xb,%edx
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <unpack754@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2sd %rax,%xmm0
  ret
```

assistant: ```c
extern double deserialize_float64(unsigned char *buf) {
  unsigned long long int fhold = unpacku64(buf);
  return ((double)(unpack754((fhold), 64, 11)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<voronoi_F1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movss  %xmm0,-0x54(%rbp)
  movss  %xmm1,-0x58(%rbp)
  movss  %xmm2,-0x5c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rsi
  lea    -0x50(%rbp),%rdi
  movss  -0x5c(%rbp),%xmm1
  movss  -0x58(%rbp),%xmm0
  mov    -0x54(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <voronoi@plt>
  movss  -0x50(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
float voronoi_F1(float x, float y, float z) {
  float da[4], pa[12];
  voronoi(x, y, z, da, pa, 1, 0);
  return da[0];
}
```