ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<nextMove>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    $0x1,%esi
  mov    $0x0,%edi
  mov    $0x0,%r8d
L100:
  mov    %rdx,%rcx
  mov    $0x0,%eax
L8:
  cmpb   $0x64,(%rcx,%rax,1)
  cmove  %edi,%ebp
  cmove  %eax,%ebx
  cmove  %r8d,%esi
  add    $0x1,%rax
  cmp    $0x5,%rax
  jne    L8
  add    $0x1,%edi
  add    $0x5,%rdx
  cmp    $0x5,%edi
  jne    L100
  cmp    $0x1,%esi
  je     L92
  movswl %bp,%eax
  cmp    %r13d,%eax
  je     L24
L73:
  movswl %bx,%ebx
  sub    %r12d,%ebx
  js     L41
  test   %ebx,%ebx
  jg     L45
  movswl %bp,%ebp
  sub    %r13d,%ebp
  js     L38
  test   %ebp,%ebp
  jg     L10
L110:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  movswl %bx,%eax
  cmp    %r12d,%eax
  jne    L73
L92:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L73
L41:
  lea    D47(%rip),%rdi
  call   <printf@plt>
  jmp    L110
L45:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L110
L38:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L110
L10:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L110
```

tool_calls: name: disassemble_data
arguments: data_tag: D32
datatype: string
name: disassemble_data
arguments: data_tag: D47
datatype: string
name: disassemble_data
arguments: data_tag: D22
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D32: CLEAN


tool: D47: LEFT


tool: D22: RIGHT


tool: D1: UP


tool: D3: DOWN


assistant: ```c
void nextMove(int posr, int posc, char board[5][5]) {
  int i, j, up, left, flag = 1;
  short princess[2];
  for (i = 0; i < 5; ++i) {
    for (j = 0; j < 5; ++j) {
      if (board[i][j] == 'd') {
        princess[0] = i;
        princess[1] = j;
        flag = 0;
      }
    }
  }
  if (flag == 1 || princess[0] == posr && princess[1] == posc)
    printf("CLEAN\n");
  if ((left = princess[1] - posc) < 0) {
    printf("LEFT\n");
    return;
  } else if (left > 0) {
    printf("RIGHT\n");
    return;
  }
  if ((up = princess[0] - posr) < 0) {
    printf("UP\n");
    return;
  } else if (up > 0) {
    printf("DOWN\n");
    return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nextMove>:
  endbr64
  push   %r13
  xor    %r8d,%r8d
  mov    %esi,%r13d
  mov    $0x1,%esi
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L50:
  xor    %eax,%eax
L73:
  cmpb   $0x64,(%rdx,%rax,1)
  cmove  %edi,%ebp
  cmove  %eax,%ecx
  cmove  %r8d,%esi
  add    $0x1,%rax
  cmp    $0x5,%rax
  jne    L73
  add    $0x1,%edi
  add    $0x5,%rdx
  cmp    $0x5,%edi
  jne    L50
  movswl %cx,%ebx
  cmp    $0x1,%esi
  je     L47
  movswl %bp,%eax
  cmp    %r12d,%eax
  je     L91
L56:
  lea    D44(%rip),%rdi
  cmp    %r13d,%ebx
  js     L48
  lea    D40(%rip),%rdi
  jne    L48
  movswl %bp,%ebp
  lea    D13(%rip),%rdi
  cmp    %r12d,%ebp
  js     L48
  jne    L92
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L92:
  lea    D12(%rip),%rdi
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
L91:
  cmp    %ebx,%r13d
  jne    L56
L47:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L56
```

tool_calls: name: unpack_data
arguments: tag: D44
datatype: string
name: unpack_data
arguments: tag: D40
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D8
datatype: string

tool: D44: LEFT


tool: D40: RIGHT


tool: D13: UP


tool: D12: DOWN


tool: D8: CLEAN


assistant: ```c
void nextMove(int posr, int posc, char board[5][5]) {
  int i, j, up, left, flag = 1;
  short princess[2];
  for (i = 0; i < 5; ++i) {
    for (j = 0; j < 5; ++j) {
      if (board[i][j] == 'd') {
        princess[0] = i;
        princess[1] = j;
        flag = 0;
      }
    }
  }
  if (flag == 1 || princess[0] == posr && princess[1] == posc)
    printf("CLEAN\n");
  if ((left = princess[1] - posc) < 0) {
    printf("LEFT\n");
    return;
  } else if (left > 0) {
    printf("RIGHT\n");
    return;
  }
  if ((up = princess[0] - posr) < 0) {
    printf("UP\n");
    return;
  } else if (up > 0) {
    printf("DOWN\n");
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lw_server_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <lw_sock_exit@plt>
  mov    $0x0,%eax
  call   <log_exit@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void lw_server_exit(int code) {
  lw_sock_exit();
  log_exit();
  exit(code);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lw_server_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <lw_sock_exit@plt>
  mov    $0x0,%eax
  call   <log_exit@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void lw_server_exit(int code) {
  lw_sock_exit();
  log_exit();
  exit(code);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lw_server_exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <lw_sock_exit@plt>
  xor    %eax,%eax
  call   <log_exit@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

assistant: ```c
void lw_server_exit(int code) {
  lw_sock_exit();
  log_exit();
  exit(code);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lw_server_exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <lw_sock_exit@plt>
  xor    %eax,%eax
  call   <log_exit@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

assistant: ```c
void lw_server_exit(int code) {
  lw_sock_exit();
  log_exit();
  exit(code);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__ffs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    $0xffffffff,%eax
  bsf    -0x14(%rbp),%edx
  cmove  %eax,%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int __ffs(x)
int x;
{
  int cnt;
  int tmp;
  asm("bsfl %2,%0\n"
      "cmovel %1,%0\n"
      : "=&r"(cnt), "=r"(tmp)
      : "rm"(x), "1"(-1));
  return cnt + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__ffs>:
  endbr64
  mov    $0xffffffff,%edx
  bsf    %edi,%eax
  cmove  %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int __ffs(x)
int x;
{
  int cnt;
  int tmp;
  asm("bsfl %2,%0\n"
      "cmovel %1,%0\n"
      : "=&r"(cnt), "=r"(tmp)
      : "rm"(x), "1"(-1));
  return cnt + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__ffs>:
  endbr64
  mov    $0xffffffff,%edx
  bsf    %edi,%eax
  cmove  %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int __ffs(x)
int x;
{
  int cnt;
  int tmp;
  asm("bsfl %2,%0\n"
      "cmovel %1,%0\n"
      : "=&r"(cnt), "=r"(tmp)
      : "rm"(x), "1"(-1));
  return cnt + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ap_str_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L54
  jmp    L14
L64:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
L14:
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L64
  jmp    L54
L27:
  nop
L54:
  cmpq   $0x0,-0x8(%rbp)
  jne    L47
  cmpq   $0x0,-0x38(%rbp)
  je     L61
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L61:
  nop
L30:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
L47:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t ap_str_strlcpy(char *dst, const char *src, size_t size) {
  char *d = dst;
  const char *s = src;
  size_t n = size;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0') {
        break;
      }
    }
  }
  if (n == 0) {
    if (size != 0) {
      *d = '\0';
    }
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ap_str_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L25
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
L49:
  cmp    %rcx,%rdi
  je     L45
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  jne    L49
  jmp    L12
L25:
  mov    %rsi,%rax
L51:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L51
L12:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L45:
  movb   $0x0,(%rdi)
  jmp    L51
```

assistant: ```c
size_t ap_str_strlcpy(char *dst, const char *src, size_t size) {
  char *d = dst;
  const char *s = src;
  size_t n = size;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0') {
        break;
      }
    }
  }
  if (n == 0) {
    if (size != 0) {
      *d = '\0';
    }
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ap_str_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L13
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L17
L4:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L8
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L22
L17:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L22
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t ap_str_strlcpy(char *dst, const char *src, size_t size) {
  char *d = dst;
  const char *s = src;
  size_t n = size;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0') {
        break;
      }
    }
  }
  if (n == 0) {
    if (size != 0) {
      *d = '\0';
    }
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ap_str_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L22
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L58:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L32
L57:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L58
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L50
L32:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L50:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L50
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t ap_str_strlcpy(char *dst, const char *src, size_t size) {
  char *d = dst;
  const char *s = src;
  size_t n = size;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0') {
        break;
      }
    }
  }
  if (n == 0) {
    if (size != 0) {
      *d = '\0';
    }
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<disk_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <statvfs@plt>
  test   %rax,%rax
  jns    L24
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <warn@plt>
  mov    $0x0,%eax
  jmp    L18
L24:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    $0x400,%esi
  mov    %eax,%edi
  call   <fmt_human@plt>
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: statvfs '%s':

assistant: ```c
const char *disk_free(const char *path) {
  struct statvfs fs;
  if (statvfs(path, &fs) < 0) {
    warn("statvfs '%s':", path);
    return NULL;
  }
  return fmt_human(fs.f_frsize * fs.f_bavail, 1024);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<disk_free>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <statvfs@plt>
  test   %rax,%rax
  js     L23
  mov    (%rsp),%edi
  imul   0x4(%rsp),%edi
  mov    $0x400,%esi
  call   <fmt_human@plt>
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  ret
L23:
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  call   <warn@plt>
  mov    $0x0,%eax
  jmp    L7
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string

tool: D3: statvfs '%s':

assistant: ```c
const char *disk_free(const char *path) {
  struct statvfs fs;
  if (statvfs(path, &fs) < 0) {
    warn("statvfs '%s':", path);
    return NULL;
  }
  return fmt_human(fs.f_frsize * fs.f_bavail, 1024);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<disk_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <statvfs@plt>
  test   %rax,%rax
  js     L29
  mov    (%rsp),%edi
  imul   0x4(%rsp),%edi
  mov    $0x400,%esi
  call   <fmt_human@plt>
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L29:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <warn@plt>
  xor    %eax,%eax
  jmp    L19
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D2: statvfs '%s':

assistant: ```c
const char *disk_free(const char *path) {
  struct statvfs fs;
  if (statvfs(path, &fs) < 0) {
    warn("statvfs '%s':", path);
    return NULL;
  }
  return fmt_human(fs.f_frsize * fs.f_bavail, 1024);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<disk_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <statvfs@plt>
  test   %rax,%rax
  js     L18
  mov    (%rsp),%edi
  imul   0x4(%rsp),%edi
  mov    $0x400,%esi
  call   <fmt_human@plt>
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <warn@plt>
  xor    %eax,%eax
  jmp    L4
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: statvfs '%s':

assistant: ```c
const char *disk_free(const char *path) {
  struct statvfs fs;
  if (statvfs(path, &fs) < 0) {
    warn("statvfs '%s':", path);
    return NULL;
  }
  return fmt_human(fs.f_frsize * fs.f_bavail, 1024);
}
```
user: What is the c source code of the assembly code below:

```asm
<strndup_3_Bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <unknown@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  jle    L2
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x5,%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strndup@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L5
L24:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x61,(%rax)
  addl   $0x1,-0x18(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L24
L2:
  nop
  leave
  ret
```

assistant: ```c
void strndup_3_Bad() {
  int size = unknown();
  if (size >= 10) {
    char *s1 = (char *)malloc(sizeof(char) * size);
    s1[5] = '\0';
    char *s2 = strndup(s1, size - 1);
    for (int i = 0; i < size - 1; i++) {
      s2[i] = 'a';
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strndup_3_Bad>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <unknown@plt>
  cmp    $0x9,%eax
  jg     L0
L6:
  pop    %rbx
  ret
L0:
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movb   $0x0,0x5(%rax)
  sub    $0x1,%ebx
  mov    %ebx,%esi
  call   <strndup@plt>
  mov    %ebx,%ebx
  lea    (%rbx,%rax,1),%rdx
L9:
  movb   $0x61,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
  jmp    L6
```

assistant: ```c
void strndup_3_Bad() {
  int size = unknown();
  if (size >= 10) {
    char *s1 = (char *)malloc(sizeof(char) * size);
    s1[5] = '\0';
    char *s2 = strndup(s1, size - 1);
    for (int i = 0; i < size - 1; i++) {
      s2[i] = 'a';
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strndup_3_Bad>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <unknown@plt>
  cmp    $0x9,%eax
  jg     L5
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <malloc@plt>
  sub    $0x1,%ebx
  movb   $0x0,0x5(%rax)
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <strndup@plt>
  mov    %ebx,%edx
  mov    $0x61,%esi
  pop    %rbx
  mov    %rax,%rdi
  jmp    1080 <memset@plt>
```

assistant: ```c
void strndup_3_Bad() {
  int size = unknown();
  if (size >= 10) {
    char *s1 = (char *)malloc(sizeof(char) * size);
    s1[5] = '\0';
    char *s2 = strndup(s1, size - 1);
    for (int i = 0; i < size - 1; i++) {
      s2[i] = 'a';
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strndup_3_Bad>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <unknown@plt>
  cmp    $0x9,%eax
  jg     L3
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <malloc@plt>
  sub    $0x1,%ebx
  movb   $0x0,0x5(%rax)
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <strndup@plt>
  mov    %ebx,%edx
  mov    $0x61,%esi
  pop    %rbx
  mov    %rax,%rdi
  jmp    1080 <memset@plt>
```

assistant: ```c
void strndup_3_Bad() {
  int size = unknown();
  if (size >= 10) {
    char *s1 = (char *)malloc(sizeof(char) * size);
    s1[5] = '\0';
    char *s2 = strndup(s1, size - 1);
    for (int i = 0; i < size - 1; i++) {
      s2[i] = 'a';
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gladiator_gets_the_girl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L7
L4:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
bool gladiator_gets_the_girl(bool no_change, int door_glad, bool *is_girl) {
  if (no_change) {
    return is_girl[door_glad];
  } else {
    return !is_girl[door_glad];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gladiator_gets_the_girl>:
  endbr64
  test   %edi,%edi
  je     L6
  movslq %esi,%rsi
  mov    (%rdx,%rsi,4),%eax
  ret
L6:
  movslq %esi,%rsi
  cmpl   $0x0,(%rdx,%rsi,4)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool gladiator_gets_the_girl(bool no_change, int door_glad, bool *is_girl) {
  if (no_change) {
    return is_girl[door_glad];
  } else {
    return !is_girl[door_glad];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<gladiator_gets_the_girl>:
  endbr64
  movslq %esi,%rsi
  mov    (%rdx,%rsi,4),%eax
  test   %edi,%edi
  jne    L1
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L1:
  ret
```

assistant: ```c
bool gladiator_gets_the_girl(bool no_change, int door_glad, bool *is_girl) {
  if (no_change) {
    return is_girl[door_glad];
  } else {
    return !is_girl[door_glad];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gladiator_gets_the_girl>:
  endbr64
  movslq %esi,%rsi
  mov    (%rdx,%rsi,4),%eax
  test   %edi,%edi
  jne    L9
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L9:
  ret
```

assistant: ```c
bool gladiator_gets_the_girl(bool no_change, int door_glad, bool *is_girl) {
  if (no_change) {
    return is_girl[door_glad];
  } else {
    return !is_girl[door_glad];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L49
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L0
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L8
  jmp    L49
L8:
  mov    $0xffffffff,%eax
  jmp    L55
L0:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L49:
  cmpl   $0x0,-0x8(%rbp)
  jg     L34
  mov    -0x18(%rbp),%eax
L55:
  leave
  ret
```

assistant: ```c
int write_line(int sock, char buffer[], int len) {
  int left = len;
  while (left > 0) {
    ssize_t n = write(sock, buffer, (size_t)left);
    if (n == -1)
      if (errno == EINTR)
        continue;
      else
        return -1;
    left -= n;
    buffer += n;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L37
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  jmp    L6
L48:
  mov    D0(%rip),%rcx
  mov    D18(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L28
L32:
  test   %ebx,%ebx
  jle    L37
L6:
  movslq %ebx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L48
  sub    %eax,%ebx
  cltq
  add    %rax,%rbp
  jmp    L32
L28:
  mov    %eax,%r13d
L37:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_line(int sock, char buffer[], int len) {
  int left = len;
  while (left > 0) {
    ssize_t n = write(sock, buffer, (size_t)left);
    if (n == -1)
      if (errno == EINTR)
        continue;
      else
        return -1;
    left -= n;
    buffer += n;
  }
  return len;
}
```