ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
L27:
  mov    $0x6400000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L28
L7:
  mov    -0x8(%rbp),%rax
  mov    $0x6400000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L27
L28:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D11: malloc failed

tool: D7: Currently allocating %d MB


assistant: ```c
int main(int argc, char *argv[]) {
  void *myblock = NULL;
  long long count = 0;
  while (1) {
    myblock = (void *)malloc(100 * 1024 * 1024);
    if (!myblock) {
      printf("malloc failed\n");
      break;
    }
    memset(myblock, 1, 100 * 1024 * 1024);
    printf("Currently allocating %d MB\n", ++count * 100);
  }
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%ebx
  lea    D17(%rip),%rbp
  jmp    L18
L16:
  mov    $0x6400000,%edx
  mov    $0x1,%esi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x64,%rbx
L18:
  mov    $0x6400000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L16
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D17: Currently allocating %d MB


tool: D13: malloc failed

assistant: ```c
int main(int argc, char *argv[]) {
  void *myblock = NULL;
  long long count = 0;
  while (1) {
    myblock = (void *)malloc(100 * 1024 * 1024);
    if (!myblock) {
      printf("malloc failed\n");
      break;
    }
    memset(myblock, 1, 100 * 1024 * 1024);
    printf("Currently allocating %d MB\n", ++count * 100);
  }
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x6400000,%edx
  mov    $0x1,%esi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x64,%rbx
L5:
  mov    $0x6400000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L18
  lea    D2(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
datatype: string
name: retrieve_data
arguments: label: D2
datatype: string

tool: D19: Currently allocating %d MB


tool: D2: malloc failed

assistant: ```c
int main(int argc, char *argv[]) {
  void *myblock = NULL;
  long long count = 0;
  while (1) {
    myblock = (void *)malloc(100 * 1024 * 1024);
    if (!myblock) {
      printf("malloc failed\n");
      break;
    }
    memset(myblock, 1, 100 * 1024 * 1024);
    printf("Currently allocating %d MB\n", ++count * 100);
  }
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x6400000,%edx
  mov    $0x1,%esi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x64,%rbx
L15:
  mov    $0x6400000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L8
  lea    D11(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D11
type_infered: string

tool: D7: Currently allocating %d MB


tool: D11: malloc failed

assistant: ```c
int main(int argc, char *argv[]) {
  void *myblock = NULL;
  long long count = 0;
  while (1) {
    myblock = (void *)malloc(100 * 1024 * 1024);
    if (!myblock) {
      printf("malloc failed\n");
      break;
    }
    memset(myblock, 1, 100 * 1024 * 1024);
    printf("Currently allocating %d MB\n", ++count * 100);
  }
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x40,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x8000,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D15
type_infered: string
name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D14: default settings

tool: D15: denormals are zero

tool: D7: flush to zero

assistant: ```c
int main() {
  test("default settings", 0);
  test("denormals are zero", 0x0040);
  test("flush to zero", 0x8000);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D27(%rip),%rdi
  call   <test@plt>
  mov    $0x40,%esi
  lea    D14(%rip),%rdi
  call   <test@plt>
  mov    $0x8000,%esi
  lea    D11(%rip),%rdi
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string

tool: D27: default settings

tool: D14: denormals are zero

tool: D11: flush to zero

assistant: ```c
int main() {
  test("default settings", 0);
  test("denormals are zero", 0x0040);
  test("flush to zero", 0x8000);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D6(%rip),%rdi
  call   <test@plt>
  mov    $0x40,%esi
  lea    D24(%rip),%rdi
  call   <test@plt>
  mov    $0x8000,%esi
  lea    D25(%rip),%rdi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string
name: retrieve_data
arguments: tag: D24
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string

tool: D6: default settings

tool: D24: denormals are zero

tool: D25: flush to zero

assistant: ```c
int main() {
  test("default settings", 0);
  test("denormals are zero", 0x0040);
  test("flush to zero", 0x8000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D15(%rip),%rdi
  call   <test@plt>
  mov    $0x40,%esi
  lea    D12(%rip),%rdi
  call   <test@plt>
  mov    $0x8000,%esi
  lea    D27(%rip),%rdi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
type: string
name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D27
type: string

tool: D15: default settings

tool: D12: denormals are zero

tool: D27: flush to zero

assistant: ```c
int main() {
  test("default settings", 0);
  test("denormals are zero", 0x0040);
  test("flush to zero", 0x8000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x12c,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L8
L7:
  mov    -0x14(%rbp),%eax
  lea    -0x20(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  add    %eax,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D1: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int inicio, fim, incr;
  inicio = 0;
  fim = 300;
  incr = 20;
  fahr = inicio;
  while (fahr <= fim) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + incr;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xffffff60,%ebp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L8:
  movslq %ebp,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  add    $0x64,%ebp
  cmp    $0x140,%ebx
  jne    L8
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int inicio, fim, incr;
  inicio = 0;
  fim = 300;
  incr = 20;
  fahr = inicio;
  while (fahr <= fim) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + incr;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffff60,%r12d
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%eax
  add    $0x14,%ebx
  add    $0x64,%r12d
  sar    $0x21,%rdx
  sub    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int inicio, fim, incr;
  inicio = 0;
  fim = 300;
  incr = 20;
  fahr = inicio;
  while (fahr <= fim) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + incr;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffff60,%r12d
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%eax
  add    $0x14,%ebx
  add    $0x64,%r12d
  sar    $0x21,%rdx
  sub    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int inicio, fim, incr;
  inicio = 0;
  fim = 300;
  incr = 20;
  fahr = inicio;
  while (fahr <= fim) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + incr;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_block(void *d, const void *s) {
  ((uint32_t *)d)[0] = ((uint32_t *)s)[0];
  ((uint32_t *)d)[1] = ((uint32_t *)s)[1];
  ((uint32_t *)d)[2] = ((uint32_t *)s)[2];
  ((uint32_t *)d)[3] = ((uint32_t *)s)[3];
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_block>:
  endbr64
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  mov    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  mov    %eax,0x8(%rdi)
  mov    0xc(%rsi),%eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void copy_block(void *d, const void *s) {
  ((uint32_t *)d)[0] = ((uint32_t *)s)[0];
  ((uint32_t *)d)[1] = ((uint32_t *)s)[1];
  ((uint32_t *)d)[2] = ((uint32_t *)s)[2];
  ((uint32_t *)d)[3] = ((uint32_t *)s)[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_block>:
  endbr64
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  mov    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  mov    %eax,0x8(%rdi)
  mov    0xc(%rsi),%eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void copy_block(void *d, const void *s) {
  ((uint32_t *)d)[0] = ((uint32_t *)s)[0];
  ((uint32_t *)d)[1] = ((uint32_t *)s)[1];
  ((uint32_t *)d)[2] = ((uint32_t *)s)[2];
  ((uint32_t *)d)[3] = ((uint32_t *)s)[3];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_block>:
  endbr64
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  mov    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  mov    %eax,0x8(%rdi)
  mov    0xc(%rsi),%eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void copy_block(void *d, const void *s) {
  ((uint32_t *)d)[0] = ((uint32_t *)s)[0];
  ((uint32_t *)d)[1] = ((uint32_t *)s)[1];
  ((uint32_t *)d)[2] = ((uint32_t *)s)[2];
  ((uint32_t *)d)[3] = ((uint32_t *)s)[3];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<matrix4MulVecf>:
  endbr64
  movss  (%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x10(%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x1c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x20(%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x2c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  movss  0x30(%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x34(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x38(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x3c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdx)
  ret
```

assistant: ```c
void matrix4MulVecf(float *mat, float *v, float *out) {
  out[0] = mat[0] * v[0] + mat[1] * v[1] + mat[2] * v[2] + mat[3] * v[3];
  out[1] = mat[4] * v[0] + mat[5] * v[1] + mat[6] * v[2] + mat[7] * v[3];
  out[2] = mat[8] * v[0] + mat[9] * v[1] + mat[10] * v[2] + mat[11] * v[3];
  out[3] = mat[12] * v[0] + mat[13] * v[1] + mat[14] * v[2] + mat[15] * v[3];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<matrix4MulVecf>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x10(%rdi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x1c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x20(%rdi),%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x2c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  movss  0x30(%rdi),%xmm0
  movss  0x34(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x38(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x3c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdx)
  ret
```

assistant: ```c
void matrix4MulVecf(float *mat, float *v, float *out) {
  out[0] = mat[0] * v[0] + mat[1] * v[1] + mat[2] * v[2] + mat[3] * v[3];
  out[1] = mat[4] * v[0] + mat[5] * v[1] + mat[6] * v[2] + mat[7] * v[3];
  out[2] = mat[8] * v[0] + mat[9] * v[1] + mat[10] * v[2] + mat[11] * v[3];
  out[3] = mat[12] * v[0] + mat[13] * v[1] + mat[14] * v[2] + mat[15] * v[3];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matrix4MulVecf>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x10(%rdi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x1c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x20(%rdi),%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x2c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  movss  0x30(%rdi),%xmm0
  movss  0x34(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x38(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x3c(%rdi),%xmm1
  mulss  0xc(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdx)
  ret
```

assistant: ```c
void matrix4MulVecf(float *mat, float *v, float *out) {
  out[0] = mat[0] * v[0] + mat[1] * v[1] + mat[2] * v[2] + mat[3] * v[3];
  out[1] = mat[4] * v[0] + mat[5] * v[1] + mat[6] * v[2] + mat[7] * v[3];
  out[2] = mat[8] * v[0] + mat[9] * v[1] + mat[10] * v[2] + mat[11] * v[3];
  out[3] = mat[12] * v[0] + mat[13] * v[1] + mat[14] * v[2] + mat[15] * v[3];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<solcon_write_solution_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L57:
  cmp    %rdx,%rsp
  je     L25
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L57
L25:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L53
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L53:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xcd,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x3c(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L28
L40:
  mov    -0x30(%rbp),%rax
  mov    -0x40(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%edx
  mov    -0x40(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x50(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x40(%rbp)
L28:
  mov    -0x40(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L40
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x3c(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int solcon_write_solution_vector(int k, int n, char *s) {
  int a[2], b[n], fail, i;
  double *c;
  a[0] = k;
  a[1] = n;
  fail = _ada_use_c2phc4c(205, a, b, c, 0);
  for (i = 0; i < n; i++)
    s[i] = b[i];
  s[n] = '\0';
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<solcon_write_solution_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%r14d
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%r13
  lea    0xf(,%r13,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L56:
  cmp    %rdx,%rsp
  je     L42
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L56
L42:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L32
  orq    $0x0,-0x8(%rsp,%rax,1)
L32:
  mov    %rsp,%r12
  mov    %edi,-0x30(%rbp)
  mov    %r14d,-0x2c(%rbp)
  lea    -0x30(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %r12,%rdx
  mov    $0xcd,%edi
  call   <_ada_use_c2phc4c@plt>
  test   %r14d,%r14d
  jle    L50
  mov    %r14d,%esi
  mov    $0x0,%edx
L58:
  mov    (%r12,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L58
L50:
  movb   $0x0,(%rbx,%r13,1)
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_write_solution_vector(int k, int n, char *s) {
  int a[2], b[n], fail, i;
  double *c;
  a[0] = k;
  a[1] = n;
  fail = _ada_use_c2phc4c(205, a, b, c, 0);
  for (i = 0; i < n; i++)
    s[i] = b[i];
  s[n] = '\0';
  return fail;
}
```