ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<arctanh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D15(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  ja     L6
  movsd  -0x18(%rbp),%xmm0
  movsd  D3(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L44
L6:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  jmp    L5
L44:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L19
L30:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <dpow@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%edx
  lea    -0x1(%rdx),%ecx
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x63,-0xc(%rbp)
  jle    L30
  movsd  -0x8(%rbp),%xmm0
L5:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type: f32[2]
name: retrieve_data
arguments: data_label: D3
type: f32[2]

tool: {"D15": [0.0,-1.875]}

tool: {"D3": [0.0,1.875]}

assistant: ```c
double arctanh(double n) {
  if (n < -1 || n > 1) {
    return 0. / 0.;
  }
  double sum = 0;
  int i;
  for (i = 1; i < 100; i++) {
    sum += dpow(n, 2 * i - 1) / (2 * i - 1);
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<arctanh>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%r14
  movsd  D19(%rip),%xmm0
  movq   %r14,%xmm2
  comisd %xmm2,%xmm0
  ja     L8
  comisd D8(%rip),%xmm2
  ja     L8
  mov    $0x1,%ebx
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
L36:
  mov    %ebx,%edi
  movq   %r14,%xmm0
  call   <dpow@plt>
  cltd
  idiv   %ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x2,%ebx
  cmp    $0xc7,%ebx
  jne    L36
  jmp    L19
L8:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rsp)
L19:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type_guessed: f32[2]
name: read_data
arguments: data_tag: D8
type_guessed: f32

tool: {"D19": [0.0,-1.875]}

tool: D8: 0

assistant: ```c
double arctanh(double n) {
  if (n < -1 || n > 1) {
    return 0. / 0.;
  }
  double sum = 0;
  int i;
  for (i = 1; i < 100; i++) {
    sum += dpow(n, 2 * i - 1) / (2 * i - 1);
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arctanh>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm2
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  D2(%rip),%xmm0
  comisd %xmm2,%xmm0
  ja     L26
  comisd D18(%rip),%xmm2
  ja     L26
  pxor   %xmm3,%xmm3
  mov    $0x1,%ebx
  movsd  %xmm3,(%rsp)
  nopl   0x0(%rax)
L22:
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%edi
  call   <dpow@plt>
  pxor   %xmm0,%xmm0
  cltd
  idiv   %ebx
  add    $0x2,%ebx
  cvtsi2sd %eax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0xc7,%ebx
  jne    L22
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,(%rsp)
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: f32[2]
name: extract_symbolic_data
arguments: label: D18
data_type: f32

tool: {"D2": [0.0,-1.875]}

tool: D18: 0

assistant: ```c
double arctanh(double n) {
  if (n < -1 || n > 1) {
    return 0. / 0.;
  }
  double sum = 0;
  int i;
  for (i = 1; i < 100; i++) {
    sum += dpow(n, 2 * i - 1) / (2 * i - 1);
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arctanh>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm2
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  D19(%rip),%xmm0
  comisd %xmm2,%xmm0
  ja     L1
  comisd D1(%rip),%xmm2
  ja     L1
  pxor   %xmm3,%xmm3
  mov    $0x1,%ebx
  movsd  %xmm3,(%rsp)
  nopl   0x0(%rax)
L2:
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%edi
  call   <dpow@plt>
  pxor   %xmm0,%xmm0
  cltd
  idiv   %ebx
  add    $0x2,%ebx
  cvtsi2sd %eax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0xc7,%ebx
  jne    L2
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,(%rsp)
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
datatype: f32[2]
name: disassemble_data
arguments: data_tag: D1
datatype: f32

tool: {"D19": [0.0,-1.875]}

tool: D1: 0

assistant: ```c
double arctanh(double n) {
  if (n < -1 || n > 1) {
    return 0. / 0.;
  }
  double sum = 0;
  int i;
  for (i = 1; i < 100; i++) {
    sum += dpow(n, 2 * i - 1) / (2 * i - 1);
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <sieve_of_eratosthenes@plt>
  mov    $0x0,%eax
  call   <print_numbers@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  sieve_of_eratosthenes();
  print_numbers();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sieve_of_eratosthenes@plt>
  mov    $0x0,%eax
  call   <print_numbers@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sieve_of_eratosthenes();
  print_numbers();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sieve_of_eratosthenes@plt>
  xor    %eax,%eax
  call   <print_numbers@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sieve_of_eratosthenes();
  print_numbers();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sieve_of_eratosthenes@plt>
  xor    %eax,%eax
  call   <print_numbers@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sieve_of_eratosthenes();
  print_numbers();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<srx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x18(%rbp)
  mov    %al,-0xc(%rbp)
  sarb   -0xc(%rbp)
  cmpb   $0x0,-0xc(%rbp)
  je     L2
  movsbl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%rcx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   *%rcx
  movsbl -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <srx>
  jmp    L0
L2:
  nop
L0:
  leave
  ret
```

assistant: ```c
void srx(char *n, char l, void (*fn)(char *, char)) {
  if (!(l >>= 1)) {
    return;
  }
  (*fn)(n, l);
  srx(n, l, fn);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<srx>:
  endbr64
  sar    %sil
  je     L3
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  movsbl %sil,%ebx
  mov    %ebx,%esi
  call   *%rdx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <srx>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

assistant: ```c
void srx(char *n, char l, void (*fn)(char *, char)) {
  if (!(l >>= 1)) {
    return;
  }
  (*fn)(n, l);
  srx(n, l, fn);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<srx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  sar    %sil
  je     L37
  movsbl %sil,%esi
  mov    %rdi,%r12
  mov    %rdx,%r13
  call   *%rdx
  mov    %ebx,%esi
  sar    $0x2,%sil
  je     L37
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   *%r13
  mov    %ebx,%esi
  sar    $0x3,%sil
  je     L37
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   *%r13
  mov    %ebx,%esi
  sar    $0x4,%sil
  je     L37
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   *%r13
  mov    %ebx,%esi
  sar    $0x5,%sil
  je     L37
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   *%r13
  sar    $0x6,%bl
  je     L37
  movsbl %bl,%ebp
  mov    %r12,%rdi
  mov    %ebp,%esi
  call   *%r13
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %ebp,%esi
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1100 <srx>
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void srx(char *n, char l, void (*fn)(char *, char)) {
  if (!(l >>= 1)) {
    return;
  }
  (*fn)(n, l);
  srx(n, l, fn);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<srx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  sar    %sil
  je     L29
  movsbl %sil,%esi
  mov    %rdi,%r12
  mov    %rdx,%r13
  call   *%rdx
  mov    %ebx,%esi
  sar    $0x2,%sil
  je     L29
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   *%r13
  mov    %ebx,%esi
  sar    $0x3,%sil
  je     L29
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   *%r13
  mov    %ebx,%esi
  sar    $0x4,%sil
  je     L29
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   *%r13
  mov    %ebx,%esi
  sar    $0x5,%sil
  je     L29
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   *%r13
  sar    $0x6,%bl
  je     L29
  movsbl %bl,%ebp
  mov    %r12,%rdi
  mov    %ebp,%esi
  call   *%r13
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %ebp,%esi
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1100 <srx>
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void srx(char *n, char l, void (*fn)(char *, char)) {
  if (!(l >>= 1)) {
    return;
  }
  (*fn)(n, l);
  srx(n, l, fn);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xh_ptr_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int xh_ptr_equal(const void *key1, const void *key2, void *data) {
  (void)data;
  return *(const void **)key1 == *(const void **)key2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xh_ptr_equal>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int xh_ptr_equal(const void *key1, const void *key2, void *data) {
  (void)data;
  return *(const void **)key1 == *(const void **)key2;
}
```
user: What is the c source code of the assembly code below:

```asm
<xh_ptr_equal>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int xh_ptr_equal(const void *key1, const void *key2, void *data) {
  (void)data;
  return *(const void **)key1 == *(const void **)key2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xh_ptr_equal>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int xh_ptr_equal(const void *key1, const void *key2, void *data) {
  (void)data;
  return *(const void **)key1 == *(const void **)key2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_file_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L1
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xc(%rbp),%eax
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: a

assistant: ```c
int write_file_text(char *data, char *file) {
  int r;
  FILE *fp;
  if ((fp = fopen(file, "a")) == NULL)
    return 0;
  r = fwrite(data, 1, strlen(data), fp);
  fclose(fp);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_file_text>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L0
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rcx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <fclose@plt>
L0:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: a

assistant: ```c
int write_file_text(char *data, char *file) {
  int r;
  FILE *fp;
  if ((fp = fopen(file, "a")) == NULL)
    return 0;
  r = fwrite(data, 1, strlen(data), fp);
  fclose(fp);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_file_text>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  lea    D0(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  test   %rax,%rax
  je     L7
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %eax,%edx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <fclose@plt>
L7:
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: a

assistant: ```c
int write_file_text(char *data, char *file) {
  int r;
  FILE *fp;
  if ((fp = fopen(file, "a")) == NULL)
    return 0;
  r = fwrite(data, 1, strlen(data), fp);
  fclose(fp);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<write_file_text>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  lea    D0(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  test   %rax,%rax
  je     L4
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %eax,%edx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <fclose@plt>
L4:
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: a

assistant: ```c
int write_file_text(char *data, char *file) {
  int r;
  FILE *fp;
  if ((fp = fopen(file, "a")) == NULL)
    return 0;
  r = fwrite(data, 1, strlen(data), fp);
  fclose(fp);
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<smmu_pmd_addr_end_lpae>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x15,%edi
  call   <BIT@plt>
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x15,%edi
  call   <BIT@plt>
  neg    %eax
  cltq
  and    %rbx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,%rdx
  jae    L2
  mov    -0x18(%rbp),%rax
  jmp    L14
L2:
  mov    -0x30(%rbp),%rax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long smmu_pmd_addr_end_lpae(unsigned long addr, unsigned long end) {
  unsigned long boundary = (addr + BIT((21))) & (~(BIT((21)) - 1));
  return (boundary - 1 < end - 1) ? boundary : end;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smmu_pmd_addr_end_lpae>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x15,%edi
  call   <BIT@plt>
  movslq %eax,%rbx
  add    %r12,%rbx
  mov    $0x15,%edi
  call   <BIT@plt>
  neg    %eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  and    %rbx,%rax
  sub    $0x1,%rax
  lea    -0x1(%rbp),%rcx
  and    %rbx,%rdx
  cmp    %rcx,%rax
  mov    %rbp,%rax
  cmovb  %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long smmu_pmd_addr_end_lpae(unsigned long addr, unsigned long end) {
  unsigned long boundary = (addr + BIT((21))) & (~(BIT((21)) - 1));
  return (boundary - 1 < end - 1) ? boundary : end;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<smmu_pmd_addr_end_lpae>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x15,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <BIT@plt>
  mov    $0x15,%edi
  movslq %eax,%rbx
  call   <BIT@plt>
  add    %r12,%rbx
  lea    -0x1(%rbp),%rdx
  neg    %eax
  cltq
  and    %rbx,%rax
  pop    %rbx
  lea    -0x1(%rax),%rcx
  cmp    %rdx,%rcx
  cmovae %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long smmu_pmd_addr_end_lpae(unsigned long addr, unsigned long end) {
  unsigned long boundary = (addr + BIT((21))) & (~(BIT((21)) - 1));
  return (boundary - 1 < end - 1) ? boundary : end;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<smmu_pmd_addr_end_lpae>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x15,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <BIT@plt>
  mov    $0x15,%edi
  movslq %eax,%rbx
  call   <BIT@plt>
  add    %r12,%rbx
  lea    -0x1(%rbp),%rdx
  neg    %eax
  cltq
  and    %rbx,%rax
  pop    %rbx
  lea    -0x1(%rax),%rcx
  cmp    %rdx,%rcx
  cmovae %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long smmu_pmd_addr_end_lpae(unsigned long addr, unsigned long end) {
  unsigned long boundary = (addr + BIT((21))) & (~(BIT((21)) - 1));
  return (boundary - 1 < end - 1) ? boundary : end;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1,%edi
  call   <worker@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  worker(1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <worker@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  worker(1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <worker@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  worker(1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show_task>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x3,-0x24(%rbp)
  je     L106
  cmpl   $0x3,-0x24(%rbp)
  ja     L109
  cmpl   $0x2,-0x24(%rbp)
  je     L70
  cmpl   $0x2,-0x24(%rbp)
  ja     L109
  cmpl   $0x0,-0x24(%rbp)
  je     L64
  cmpl   $0x1,-0x24(%rbp)
  je     L27
  jmp    L109
L64:
  lea    -0x20(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L115
L27:
  lea    -0x20(%rbp),%rax
  lea    D51(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L115
L70:
  lea    -0x20(%rbp),%rax
  lea    D38(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L115
L106:
  lea    -0x20(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L115
L109:
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  lea    D27(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
L115:
  mov    -0x38(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%edx
  mov    -0x38(%rbp),%eax
  movzbl %al,%eax
  lea    -0x20(%rbp),%rcx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D51
type: string
name: extract_symbolic_data
arguments: label: D38
type: string
name: extract_symbolic_data
arguments: label: D31
type: string
name: extract_symbolic_data
arguments: label: D27
type: string
name: extract_symbolic_data
arguments: label: D4
type: string

tool: D14: run

tool: D51: block

tool: D38: create

tool: D31: destroy

tool: D27: code %d

tool: D4: TASK %d, pri %d: %s

assistant: ```c
void show_task(int port, unsigned data) {
  unsigned code = data >> 16;
  char buf[16];
  switch (code) {
  case 0:
    strcpy(buf, "run");
    break;
  case 1:
    strcpy(buf, "block");
    break;
  case 2:
    strcpy(buf, "create");
    break;
  case 3:
    strcpy(buf, "destroy");
    break;
  default:
    sprintf(buf, "code %d", code);
    break;
  }
  printf("TASK %d, pri %d: %s", (data >> 0) & 0xff, (data >> 8) & 0xff, buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<show_task>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %esi,%edx
  shr    $0x10,%edx
  cmp    $0x2,%edx
  je     L81
  ja     L0
  test   %edx,%edx
  je     L84
  cmp    $0x1,%edx
  jne    L41
  mov    %rsp,%rdi
  lea    D57(%rip),%rsi
  call   <strcpy@plt>
  jmp    L44
L0:
  cmp    $0x3,%edx
  jne    L41
  mov    %rsp,%rdi
  lea    D38(%rip),%rsi
  call   <strcpy@plt>
  jmp    L44
L84:
  mov    %rsp,%rdi
  lea    D4(%rip),%rsi
  call   <strcpy@plt>
L44:
  mov    %rsp,%rcx
  movzbl %bh,%edx
  movzbl %bl,%esi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x20,%rsp
  pop    %rbx
  ret
L81:
  mov    %rsp,%rdi
  lea    D50(%rip),%rsi
  call   <strcpy@plt>
  jmp    L44
L41:
  mov    %rsp,%rdi
  lea    D58(%rip),%rsi
  call   <sprintf@plt>
  jmp    L44
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D57
data_type: string
name: read_data
arguments: tag: D38
data_type: string
name: read_data
arguments: tag: D4
data_type: string
name: read_data
arguments: tag: D34
data_type: string
name: read_data
arguments: tag: D50
data_type: string
name: read_data
arguments: tag: D58
data_type: string

tool: D57: block

tool: D38: destroy

tool: D4: run

tool: D34: TASK %d, pri %d: %s

tool: D50: create

tool: D58: code %d

assistant: ```c
void show_task(int port, unsigned data) {
  unsigned code = data >> 16;
  char buf[16];
  switch (code) {
  case 0:
    strcpy(buf, "run");
    break;
  case 1:
    strcpy(buf, "block");
    break;
  case 2:
    strcpy(buf, "create");
    break;
  case 3:
    strcpy(buf, "destroy");
    break;
  default:
    sprintf(buf, "code %d", code);
    break;
  }
  printf("TASK %d, pri %d: %s", (data >> 0) & 0xff, (data >> 8) & 0xff, buf);
}
```