ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getRow>:
  endbr64
  test   %esi,%esi
  jle    L5
  movslq %ecx,%rcx
  lea    (%rdx,%rcx,8),%rdi
  mov    %esi,%esi
  shl    $0x3,%rsi
  mov    $0x0,%eax
L13:
  mov    (%r8,%rax,1),%rdx
  mov    (%rdi),%rcx
  movsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L13
L5:
  ret
```

assistant: ```c
void getRow(int m, int n, double **mat, int r, double **store) {
  int j = 0;
  for (; j < n; j++) {
    store[j][0] = mat[r][j];
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getRow>:
  endbr64
  test   %esi,%esi
  jle    L8
  movslq %ecx,%rcx
  movslq %esi,%rsi
  xor    %eax,%eax
  mov    (%rdx,%rcx,8),%rcx
  nopl   0x0(%rax)
L11:
  movsd  (%rcx,%rax,8),%xmm0
  mov    (%r8,%rax,8),%rdx
  add    $0x1,%rax
  movsd  %xmm0,(%rdx)
  cmp    %rsi,%rax
  jne    L11
L8:
  ret
```

assistant: ```c
void getRow(int m, int n, double **mat, int r, double **store) {
  int j = 0;
  for (; j < n; j++) {
    store[j][0] = mat[r][j];
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getRow>:
  endbr64
  test   %esi,%esi
  jle    L15
  movslq %ecx,%rcx
  movslq %esi,%rsi
  xor    %eax,%eax
  mov    (%rdx,%rcx,8),%rcx
  nopl   0x0(%rax)
L14:
  movsd  (%rcx,%rax,8),%xmm0
  mov    (%r8,%rax,8),%rdx
  add    $0x1,%rax
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rsi
  jne    L14
L15:
  ret
```

assistant: ```c
void getRow(int m, int n, double **mat, int r, double **store) {
  int j = 0;
  for (; j < n; j++) {
    store[j][0] = mat[r][j];
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xdg_mime_mime_type_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <xdg_mime_init@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_xdg_mime_mime_type_equal@plt>
  leave
  ret
```

assistant: ```c
int xdg_mime_mime_type_equal(const char *mime_a, const char *mime_b) {
  xdg_mime_init();
  return _xdg_mime_mime_type_equal(mime_a, mime_b);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xdg_mime_mime_type_equal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <xdg_mime_init@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <_xdg_mime_mime_type_equal@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int xdg_mime_mime_type_equal(const char *mime_a, const char *mime_b) {
  xdg_mime_init();
  return _xdg_mime_mime_type_equal(mime_a, mime_b);
}
```
user: What is the c source code of the assembly code below:

```asm
<xdg_mime_mime_type_equal>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <xdg_mime_init@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_xdg_mime_mime_type_equal@plt>
```

assistant: ```c
int xdg_mime_mime_type_equal(const char *mime_a, const char *mime_b) {
  xdg_mime_init();
  return _xdg_mime_mime_type_equal(mime_a, mime_b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xdg_mime_mime_type_equal>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <xdg_mime_init@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_xdg_mime_mime_type_equal@plt>
```

assistant: ```c
int xdg_mime_mime_type_equal(const char *mime_a, const char *mime_b) {
  xdg_mime_init();
  return _xdg_mime_mime_type_equal(mime_a, mime_b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_consective_blank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L55:
  cmp    %rdx,%rsp
  je     L88
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L55
L88:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L77
  orq    $0x0,-0x8(%rsp,%rax,1)
L77:
  mov    %rsp,%r13
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L70
  lea    0x1(%rbx),%rax
  mov    $0x0,%ebx
  jmp    L53
L47:
  movslq %ebx,%rcx
  mov    %dl,0x0(%r13,%rcx,1)
  add    $0x1,%ebx
L35:
  add    $0x1,%rax
  movzbl -0x1(%rax),%ecx
  mov    %edx,%r12d
  test   %cl,%cl
  je     L3
  mov    %ecx,%edx
L53:
  cmp    $0x20,%r12b
  jne    L47
  cmp    $0x20,%dl
  jne    L47
  jmp    L35
L70:
  mov    $0x0,%ebx
L3:
  movslq %ebx,%r14
  movb   $0x0,0x0(%r13,%r14,1)
  lea    0x2(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%r14,1)
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  mov    %r12,%rax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L82:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *remove_consective_blank(const char *input) {
  int i = 0;
  int k = 0;
  char output[strlen(input)];
  char pre_ch;
  while (1) {
    if (input[i] == '\0') {
      break;
    }
    if (input[i] != ' ' || pre_ch != ' ') {
      output[k] = input[i];
      k++;
    }
    pre_ch = input[i];
    i++;
  }
  output[k] = '\0';
  char *retstr = (char *)malloc(sizeof(char) * (k + 2));
  strncpy(retstr, output, k);
  retstr[k] = '\0';
  return retstr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<remove_consective_blank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L69
L1:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L1
L69:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L24
L57:
  movzbl (%rbx),%eax
  mov    %rsp,%r14
  test   %al,%al
  je     L96
  lea    0x1(%rbx),%rdi
  xor    %r12d,%r12d
  jmp    L74
  cs nopw 0x0(%rax,%rax,1)
L90:
  mov    %edx,%eax
L74:
  cmp    $0x20,%r13b
  jne    L93
  cmp    $0x20,%al
  je     L95
L93:
  movslq %r12d,%rdx
  add    $0x1,%r12d
  mov    %al,(%r14,%rdx,1)
L95:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    %eax,%r13d
  test   %dl,%dl
  jne    L90
  movslq %r12d,%rax
  lea    0x2(%r12),%edi
  mov    %rax,%rbx
L8:
  movb   $0x0,(%r14,%rax,1)
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  lea    -0x20(%rbp),%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L24:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L57
L96:
  xor    %ebx,%ebx
  mov    $0x2,%edi
  xor    %r12d,%r12d
  xor    %eax,%eax
  jmp    L8
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *remove_consective_blank(const char *input) {
  int i = 0;
  int k = 0;
  char output[strlen(input)];
  char pre_ch;
  while (1) {
    if (input[i] == '\0') {
      break;
    }
    if (input[i] != ' ' || pre_ch != ' ') {
      output[k] = input[i];
      k++;
    }
    pre_ch = input[i];
    i++;
  }
  output[k] = '\0';
  char *retstr = (char *)malloc(sizeof(char) * (k + 2));
  strncpy(retstr, output, k);
  retstr[k] = '\0';
  return retstr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<remove_consective_blank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L51
L103:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L103
L51:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L100
L113:
  movzbl (%rbx),%eax
  mov    %rsp,%r14
  test   %al,%al
  je     L88
  lea    0x1(%rbx),%rdi
  xor    %r12d,%r12d
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L77:
  movslq %r12d,%rdx
  add    $0x1,%rdi
  add    $0x1,%r12d
  mov    %al,(%r14,%rdx,1)
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L37
L53:
  mov    %eax,%r13d
  mov    %edx,%eax
L23:
  cmp    $0x20,%r13b
  jne    L77
  cmp    $0x20,%al
  jne    L77
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L53
  nopl   0x0(%rax)
L37:
  movslq %r12d,%rax
  lea    0x2(%r12),%edi
  mov    %rax,%rbx
L85:
  movb   $0x0,(%r14,%rax,1)
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  lea    -0x20(%rbp),%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L100:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L113
L88:
  xor    %ebx,%ebx
  mov    $0x2,%edi
  xor    %r12d,%r12d
  xor    %eax,%eax
  jmp    L85
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *remove_consective_blank(const char *input) {
  int i = 0;
  int k = 0;
  char output[strlen(input)];
  char pre_ch;
  while (1) {
    if (input[i] == '\0') {
      break;
    }
    if (input[i] != ' ' || pre_ch != ' ') {
      output[k] = input[i];
      k++;
    }
    pre_ch = input[i];
    i++;
  }
  output[k] = '\0';
  char *retstr = (char *)malloc(sizeof(char) * (k + 2));
  strncpy(retstr, output, k);
  retstr[k] = '\0';
  return retstr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L2:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  je     L5
  cmpl   $0x71,-0x4(%rbp)
  jne    L34
L5:
  mov    $0x0,%edi
  call   <close_end@plt>
L34:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void check_input() {
  int c = 0;
  while (c != -1) {
    c = getch();
    if (c == 4 || c == 'q') {
      close_end(0);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_input>:
  endbr64
  push   %rbx
  jmp    L10
L18:
  mov    $0x0,%edi
  call   <close_end@plt>
L49:
  cmp    $0xffffffff,%ebx
  je     L23
L10:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x4,%eax
  je     L18
  cmp    $0x71,%eax
  jne    L49
  jmp    L18
L23:
  pop    %rbx
  ret
```

assistant: ```c
void check_input() {
  int c = 0;
  while (c != -1) {
    c = getch();
    if (c == 4 || c == 'q') {
      close_end(0);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_input>:
  endbr64
  push   %rbx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    $0xffffffff,%ebx
  je     L15
L14:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x4,%eax
  je     L17
  cmp    $0x71,%eax
  jne    L36
L17:
  xor    %edi,%edi
  call   <close_end@plt>
  cmp    $0xffffffff,%ebx
  jne    L14
L15:
  pop    %rbx
  ret
```

assistant: ```c
void check_input() {
  int c = 0;
  while (c != -1) {
    c = getch();
    if (c == 4 || c == 'q') {
      close_end(0);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_input>:
  endbr64
  push   %rbx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L8:
  cmp    $0xffffffff,%ebx
  je     L41
L13:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x4,%eax
  je     L23
  cmp    $0x71,%eax
  jne    L8
L23:
  xor    %edi,%edi
  call   <close_end@plt>
  cmp    $0xffffffff,%ebx
  jne    L13
L41:
  pop    %rbx
  ret
```

assistant: ```c
void check_input() {
  int c = 0;
  while (c != -1) {
    c = getch();
    if (c == 4 || c == 'q') {
      close_end(0);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<verify_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int verify_callback(int i, X509_STORE_CTX *ctx) {
  (void)(i), (void)(ctx);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<verify_callback>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int verify_callback(int i, X509_STORE_CTX *ctx) {
  (void)(i), (void)(ctx);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<verify_callback>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int verify_callback(int i, X509_STORE_CTX *ctx) {
  (void)(i), (void)(ctx);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<verify_callback>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int verify_callback(int i, X509_STORE_CTX *ctx) {
  (void)(i), (void)(ctx);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <fib@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string
name: retrieve_data
arguments: label: D17
type_guessed: string
name: retrieve_data
arguments: label: D16
type_guessed: string

tool: D2: Input number: 

tool: D17: %d

tool: D16: fibonacci(%d) = %d


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int g3;
  int local0;
  printf("Input number: ");
  scanf("%d", &local0);
  g3 = fib();
  printf("fibonacci(%d) = %d\n", local0, g3);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <fib@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D21
type_infered: string

tool: D1: Input number: 

tool: D11: %d

tool: D21: fibonacci(%d) = %d


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int g3;
  int local0;
  printf("Input number: ");
  scanf("%d", &local0);
  g3 = fib();
  printf("fibonacci(%d) = %d\n", local0, g3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <fib@plt>
  mov    0x4(%rsp),%esi
  lea    D12(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D27
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string

tool: D27: Input number: 

tool: D7: %d

tool: D12: fibonacci(%d) = %d


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int g3;
  int local0;
  printf("Input number: ");
  scanf("%d", &local0);
  g3 = fib();
  printf("fibonacci(%d) = %d\n", local0, g3);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <fib@plt>
  mov    0x4(%rsp),%esi
  lea    D10(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D10
type_guessed: string

tool: D4: Input number: 

tool: D18: %d

tool: D10: fibonacci(%d) = %d


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  int g3;
  int local0;
  printf("Input number: ");
  scanf("%d", &local0);
  g3 = fib();
  printf("fibonacci(%d) = %d\n", local0, g3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<upper_bound>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  imul   -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L21
L5:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x40(%rbp),%rax
  lea    (%rax,%rax,1),%rsi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  imul   -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    -0x48(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jns    L2
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L21
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  ja     L5
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *upper_bound(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  void *left = (void *)base, *right = (void *)base + size * nmemb, *mid;
  while (left + size < right) {
    mid = left + ((right - left) / (size << 1) * size);
    if (compar(key, mid) < 0) {
      right = mid;
    } else {
      left = mid;
    }
  }
  return right;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<upper_bound>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  imul   %rcx,%rdx
  lea    (%rsi,%rdx,1),%r12
  lea    (%rsi,%rcx,1),%rax
  cmp    %rax,%r12
  jbe    L3
  mov    %rsi,%rbp
  mov    %rcx,%r13
  mov    %r8,%r15
  lea    (%rcx,%rcx,1),%r14
L9:
  mov    %r12,%rax
  sub    %rbp,%rax
  mov    $0x0,%edx
  div    %r14
  imul   %r13,%rax
  lea    0x0(%rbp,%rax,1),%rbx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   *%r15
  test   %eax,%eax
  cmovns %rbx,%rbp
  cmovs  %rbx,%r12
  lea    0x0(%rbp,%r13,1),%rax
  cmp    %rax,%r12
  ja     L9
L3:
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *upper_bound(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  void *left = (void *)base, *right = (void *)base + size * nmemb, *mid;
  while (left + size < right) {
    mid = left + ((right - left) / (size << 1) * size);
    if (compar(key, mid) < 0) {
      right = mid;
    } else {
      left = mid;
    }
  }
  return right;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<upper_bound>:
  endbr64
  push   %r15
  imul   %rcx,%rdx
  push   %r14
  push   %r13
  push   %r12
  lea    (%rsi,%rcx,1),%r12
  push   %rbp
  lea    (%rsi,%rdx,1),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8,(%rsp)
  cmp    %r12,%rbp
  jbe    L29
  lea    (%rcx,%rcx,1),%rax
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rcx,%rbx
  mov    %rax,0x8(%rsp)
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L45:
  lea    (%r15,%rbx,1),%r12
  mov    %r15,%r14
  cmp    %r12,%rbp
  jbe    L29
L23:
  mov    %rbp,%rax
  xor    %edx,%edx
  mov    %r13,%rdi
  sub    %r14,%rax
  divq   0x8(%rsp)
  imul   %rbx,%rax
  lea    (%r14,%rax,1),%r15
  mov    (%rsp),%rax
  mov    %r15,%rsi
  call   *%rax
  test   %eax,%eax
  jns    L45
  mov    %r15,%rbp
  cmp    %r12,%rbp
  ja     L23
L29:
  add    $0x18,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *upper_bound(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  void *left = (void *)base, *right = (void *)base + size * nmemb, *mid;
  while (left + size < right) {
    mid = left + ((right - left) / (size << 1) * size);
    if (compar(key, mid) < 0) {
      right = mid;
    } else {
      left = mid;
    }
  }
  return right;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<upper_bound>:
  endbr64
  imul   %rcx,%rdx
  push   %r15
  lea    (%rsi,%rcx,1),%rax
  push   %r14
  push   %r13
  push   %r12
  lea    (%rsi,%rdx,1),%r15
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rax,%r15
  jbe    L20
  lea    (%rcx,%rcx,1),%rax
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rcx,%rbp
  mov    %rax,0x8(%rsp)
  mov    %r8,%r13
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r15,%rax
  xor    %edx,%edx
  mov    %r12,%rdi
  sub    %r14,%rax
  divq   0x8(%rsp)
  imul   %rbp,%rax
  lea    (%r14,%rax,1),%rbx
  mov    %rbx,%rsi
  call   *%r13
  test   %eax,%eax
  js     L47
  lea    (%rbx,%rbp,1),%rax
  cmp    %rax,%r15
  jbe    L20
  mov    %rbx,%r14
  jmp    L10
L47:
  lea    (%r14,%rbp,1),%rax
  mov    %rbx,%r15
  cmp    %rax,%rbx
  ja     L10
L20:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *upper_bound(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  void *left = (void *)base, *right = (void *)base + size * nmemb, *mid;
  while (left + size < right) {
    mid = left + ((right - left) / (size << 1) * size);
    if (compar(key, mid) < 0) {
      right = mid;
    } else {
      left = mid;
    }
  }
  return right;
}
```