ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<n_char>:
  endbr64
  push   %r12
  call   <strlen@plt>
  mov    %eax,%r12d
  cmp    $0x32,%eax
  jg     L8
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: String is longer than 50 characters


assistant: ```c
int n_char(char string[]) {
  int n;
  n = strlen(string);
  if (n > 50) {
    printf("String is longer than 50 characters\n");
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<n_char>:
  endbr64
  push   %r12
  call   <strlen@plt>
  mov    %eax,%r12d
  cmp    $0x32,%eax
  jg     L9
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: String is longer than 50 characters


assistant: ```c
int n_char(char string[]) {
  int n;
  n = strlen(string);
  if (n > 50) {
    printf("String is longer than 50 characters\n");
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pivot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L16
L0:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L13
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L13:
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pivot(int k, int *min, int *max) {
  int i = 0, max_dist = max[i] - min[i], ret = 0;
  for (i = 1; i < k; i++) {
    int dist = max[i] - min[i];
    if (dist > max_dist) {
      max_dist = dist;
      ret = i;
    }
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pivot>:
  endbr64
  mov    (%rdx),%r8d
  sub    (%rsi),%r8d
  cmp    $0x1,%edi
  jle    L20
  mov    %edi,%edi
  mov    $0x1,%eax
  mov    $0x0,%r9d
  jmp    L44
L10:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L48
L44:
  mov    (%rdx,%rax,4),%ecx
  sub    (%rsi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jle    L10
  mov    %eax,%r9d
  mov    %ecx,%r8d
  jmp    L10
L20:
  mov    $0x0,%r9d
L48:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int pivot(int k, int *min, int *max) {
  int i = 0, max_dist = max[i] - min[i], ret = 0;
  for (i = 1; i < k; i++) {
    int dist = max[i] - min[i];
    if (dist > max_dist) {
      max_dist = dist;
      ret = i;
    }
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pivot>:
  endbr64
  mov    (%rdx),%r8d
  sub    (%rsi),%r8d
  cmp    $0x1,%edi
  jle    L15
  movslq %edi,%rdi
  mov    $0x1,%eax
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rdx,%rax,4),%ecx
  sub    (%rsi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jle    L12
  mov    %eax,%r9d
  mov    %ecx,%r8d
L12:
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L2
  mov    %r9d,%eax
  ret
  xchg   %ax,%ax
L15:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int pivot(int k, int *min, int *max) {
  int i = 0, max_dist = max[i] - min[i], ret = 0;
  for (i = 1; i < k; i++) {
    int dist = max[i] - min[i];
    if (dist > max_dist) {
      max_dist = dist;
      ret = i;
    }
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pivot>:
  endbr64
  mov    (%rdx),%r8d
  sub    (%rsi),%r8d
  cmp    $0x1,%edi
  jle    L4
  movslq %edi,%rdi
  mov    $0x1,%eax
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rdx,%rax,4),%ecx
  sub    (%rsi,%rax,4),%ecx
  cmp    %ecx,%r8d
  jge    L22
  mov    %eax,%r9d
  mov    %ecx,%r8d
L22:
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L2
  mov    %r9d,%eax
  ret
  xchg   %ax,%ax
L4:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int pivot(int k, int *min, int *max) {
  int i = 0, max_dist = max[i] - min[i], ret = 0;
  for (i = 1; i < k; i++) {
    int dist = max[i] - min[i];
    if (dist > max_dist) {
      max_dist = dist;
      ret = i;
    }
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x64,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x19,-0xc(%rbp)
  movl   $0x4,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
data_type: string
name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D40
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D38
data_type: string

tool: D16: a - b = %i


tool: D14: b * c = %i


tool: D40: a / c = %i


tool: D20: a + b * c  = %i


tool: D38: a * b + c * d  = %i


assistant: ```c
int main(void) {
  int a = 100;
  int b = 2;
  int c = 25;
  int d = 4;
  int result;
  result = a - b;
  printf("a - b = %i\n", result);
  result = b * c;
  printf("b * c = %i\n", result);
  result = a / c;
  printf("a / c = %i\n", result);
  result = a + b * c;
  printf("a + b * c  = %i\n", result);
  printf("a * b + c * d  = %i\n", a * b + c * d);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x62,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x96,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0x12c,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D38
type: string
name: parse_data
arguments: tag: D1
type: string
name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D35
type: string
name: parse_data
arguments: tag: D20
type: string

tool: D38: a - b = %i


tool: D1: b * c = %i


tool: D16: a / c = %i


tool: D35: a + b * c  = %i


tool: D20: a * b + c * d  = %i


assistant: ```c
int main(void) {
  int a = 100;
  int b = 2;
  int c = 25;
  int d = 4;
  int result;
  result = a - b;
  printf("a - b = %i\n", result);
  result = b * c;
  printf("b * c = %i\n", result);
  result = a / c;
  printf("a / c = %i\n", result);
  result = a + b * c;
  printf("a + b * c  = %i\n", result);
  printf("a * b + c * d  = %i\n", a * b + c * d);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x62,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    $0x96,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x12c,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
datatype: string
name: read_data
arguments: data_label: D0
datatype: string
name: read_data
arguments: data_label: D41
datatype: string
name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D43
datatype: string

tool: D10: a - b = %i


tool: D0: b * c = %i


tool: D41: a / c = %i


tool: D2: a + b * c  = %i


tool: D43: a * b + c * d  = %i


assistant: ```c
int main(void) {
  int a = 100;
  int b = 2;
  int c = 25;
  int d = 4;
  int result;
  result = a - b;
  printf("a - b = %i\n", result);
  result = b * c;
  printf("b * c = %i\n", result);
  result = a / c;
  printf("a / c = %i\n", result);
  result = a + b * c;
  printf("a + b * c  = %i\n", result);
  printf("a * b + c * d  = %i\n", a * b + c * d);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x62,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x96,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x12c,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D38
type_guessed: string
name: read_data
arguments: label: D18
type_guessed: string
name: read_data
arguments: label: D30
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D39
type_guessed: string

tool: D38: a - b = %i


tool: D18: b * c = %i


tool: D30: a / c = %i


tool: D14: a + b * c  = %i


tool: D39: a * b + c * d  = %i


assistant: ```c
int main(void) {
  int a = 100;
  int b = 2;
  int c = 25;
  int d = 4;
  int result;
  result = a - b;
  printf("a - b = %i\n", result);
  result = b * c;
  printf("b * c = %i\n", result);
  result = a / c;
  printf("a / c = %i\n", result);
  result = a + b * c;
  printf("a + b * c  = %i\n", result);
  printf("a * b + c * d  = %i\n", a * b + c * d);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  jmp    L5
L37:
  movl   $0x0,-0x34(%rbp)
  jmp    L11
L13:
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  imul   %eax,%edx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  add    %rsi,%rax
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L11:
  cmpl   $0x2,-0x34(%rbp)
  jle    L13
  addl   $0x1,-0x38(%rbp)
L5:
  cmpl   $0x2,-0x38(%rbp)
  jle    L37
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <matrix_print@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <matrix_traspone@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <matrix_print@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D12
type: string

tool: D15: Matrice


tool: D12: 


assistant: ```c
void matrix(void) {
  int matrix[3][3];
  int x, y;
  for (x = 0; x < 3; x++) {
    for (y = 0; y < 3; y++)
      matrix[x][y] = (x + 1) * (y + 1);
  }
  printf("Matrice\n");
  matrix_print(matrix);
  printf("\n");
  matrix_traspone(matrix);
  matrix_print(matrix);
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <matrix_print@plt>
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <matrix_traspone@plt>
  mov    %rbx,%rdi
  call   <matrix_print@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D14
type_infered: string

tool: D19: Matrice


tool: D14: 


assistant: ```c
void matrix(void) {
  int matrix[3][3];
  int x, y;
  for (x = 0; x < 3; x++) {
    for (y = 0; y < 3; y++)
      matrix[x][y] = (x + 1) * (y + 1);
  }
  printf("Matrice\n");
  matrix_print(matrix);
  printf("\n");
  matrix_traspone(matrix);
  matrix_print(matrix);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrix>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  lea    D14(%rip),%r12
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbp
  movl   $0x9,0x20(%rsp)
  mov    %rax,(%rsp)
  add    $0x2,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000004,%rax
  mov    %rax,0x10(%rsp)
  sub    $0x1,%rax
  mov    %rax,0x18(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <matrix_print@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <matrix_traspone@plt>
  mov    %rbp,%rdi
  call   <matrix_print@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D14
datatype: string

tool: D0: Matrice


tool: D14: 


assistant: ```c
void matrix(void) {
  int matrix[3][3];
  int x, y;
  for (x = 0; x < 3; x++) {
    for (y = 0; y < 3; y++)
      matrix[x][y] = (x + 1) * (y + 1);
  }
  printf("Matrice\n");
  matrix_print(matrix);
  printf("\n");
  matrix_traspone(matrix);
  matrix_print(matrix);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<matrix>:
  endbr64
  push   %r12
  lea    D32(%rip),%rdi
  lea    D16(%rip),%r12
  push   %rbp
  sub    $0x38,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x9,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D4(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <matrix_print@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <matrix_traspone@plt>
  mov    %rbp,%rdi
  call   <matrix_print@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D32
type: string
name: disassemble_data
arguments: label: D16
type: string
name: disassemble_data
arguments: label: D26
type: byte[16]
name: disassemble_data
arguments: label: D4
type: byte[16]

tool: D32: Matrice


tool: D16: 


tool: {"D26": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D4": [0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

assistant: ```c
void matrix(void) {
  int matrix[3][3];
  int x, y;
  for (x = 0; x < 3; x++) {
    for (y = 0; y < 3; y++)
      matrix[x][y] = (x + 1) * (y + 1);
  }
  printf("Matrice\n");
  matrix_print(matrix);
  printf("\n");
  matrix_traspone(matrix);
  matrix_print(matrix);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xa(%rbp),%eax
  mov    %eax,%edx
  mov    $0xffffffdb,%eax
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: %c

assistant: ```c
int main() {
  char l, m;
  scanf("%c", &l);
  m = 'a' + 'z' - l;
  printf("%c", m);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  movsbl %sil,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: %c

assistant: ```c
int main() {
  char l, m;
  scanf("%c", &l);
  m = 'a' + 'z' - l;
  printf("%c", m);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  mov    %rbp,%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: %c

assistant: ```c
int main() {
  char l, m;
  scanf("%c", &l);
  m = 'a' + 'z' - l;
  printf("%c", m);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  mov    %rbp,%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %c

assistant: ```c
int main() {
  char l, m;
  scanf("%c", &l);
  m = 'a' + 'z' - l;
  printf("%c", m);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_http_ipv4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x14(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  jne    L15
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <err_msg@plt>
  jmp    L0
L15:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <send_msg@plt>
  jmp    L36
L40:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  mov    $0x7d0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L36:
  mov    -0x38(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    $0x7d0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <recv_msg@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L40
L0:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
datatype: string
name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D13
datatype: string

tool: D17: connect()

tool: D1: Connect success

tool: D13: %s

assistant: ```c
void get_http_ipv4(const u_int *fd, struct sockaddr_in *saddr4, char *buff) {
  u_int nrecv;
  u_int trx_fd = *fd;
  struct sockaddr_in addr4;
  memcpy(&addr4, saddr4, sizeof(*saddr4));
  if (connect(trx_fd, (struct sockaddr *)&addr4, sizeof(addr4)) == -1)
    err_msg("connect()");
  else {
    printf("Connect success\n");
    send_msg(trx_fd, buff);
    while ((nrecv = recv_msg(trx_fd, buff, 2000)) > 0) {
      printf("%s", buff);
      memset(buff, 0, 2000);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<get_http_ipv4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%ebp
  lea    0x4(%rsp),%r12
  mov    $0x4,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L34
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send_msg@plt>
  lea    D7(%rip),%r12
  jmp    L7
L34:
  lea    D11(%rip),%rdi
  call   <err_msg@plt>
  jmp    L43
L49:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7d0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
L7:
  mov    $0x7d0,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recv_msg@plt>
  test   %eax,%eax
  jg     L49
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D11
data_type: string

tool: D3: Connect success

tool: D7: %s

tool: D11: connect()

assistant: ```c
void get_http_ipv4(const u_int *fd, struct sockaddr_in *saddr4, char *buff) {
  u_int nrecv;
  u_int trx_fd = *fd;
  struct sockaddr_in addr4;
  memcpy(&addr4, saddr4, sizeof(*saddr4));
  if (connect(trx_fd, (struct sockaddr *)&addr4, sizeof(addr4)) == -1)
    err_msg("connect()");
  else {
    printf("Connect success\n");
    send_msg(trx_fd, buff);
    while ((nrecv = recv_msg(trx_fd, buff, 2000)) > 0) {
      printf("%s", buff);
      memset(buff, 0, 2000);
    }
  }
}
```