ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_thread>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%ebp
  movl   $0x0,0x4(%rsp)
  add    %ebp,%ebp
  test   %ebp,%ebp
  jle    L21
  mov    $0x0,%ebx
  lea    0x4(%rsp),%r12
  jmp    L4
L56:
  mov    %ebx,%edi
  call   <enqueue@plt>
L44:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L21
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  test   %eax,%eax
  jg     L56
  mov    %r12,%rdi
  call   <dequeue@plt>
  jmp    L44
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *my_thread(void *ptr) {
  int num = *(int *)ptr;
  int ret = 0;
  int tot = 2 * num;
  for (int i = 0; i < tot; i++) {
    if ((rand() % 2 + 1) > 1) {
      enqueue(i);
    } else {
      dequeue(&ret);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_thread>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    (%rdi),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  add    %ebp,%ebp
  test   %ebp,%ebp
  jle    L11
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  jmp    L38
  nopl   (%rax)
L25:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <dequeue@plt>
  cmp    %ebx,%ebp
  je     L11
L38:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L25
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <enqueue@plt>
  cmp    %ebx,%ebp
  jne    L38
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *my_thread(void *ptr) {
  int num = *(int *)ptr;
  int ret = 0;
  int tot = 2 * num;
  for (int i = 0; i < tot; i++) {
    if ((rand() % 2 + 1) > 1) {
      enqueue(i);
    } else {
      dequeue(&ret);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_thread>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    (%rdi),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  add    %ebp,%ebp
  test   %ebp,%ebp
  jle    L32
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  jmp    L49
  nopl   (%rax)
L13:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <dequeue@plt>
  cmp    %ebx,%ebp
  je     L32
L49:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L13
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <enqueue@plt>
  cmp    %ebx,%ebp
  jne    L49
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *my_thread(void *ptr) {
  int num = *(int *)ptr;
  int ret = 0;
  int tot = 2 * num;
  for (int i = 0; i < tot; i++) {
    if ((rand() % 2 + 1) > 1) {
      enqueue(i);
    } else {
      dequeue(&ret);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: wb

assistant: ```c
void write_float(const float *x, const int n, const char *fNam) {
  FILE *f;
  f = fopen(fNam, "wb");
  fwrite(x, sizeof(float), n, f);
  fclose(f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_float>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%rdi
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rcx
  mov    %r12d,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: wb

assistant: ```c
void write_float(const float *x, const int n, const char *fNam) {
  FILE *f;
  f = fopen(fNam, "wb");
  fwrite(x, sizeof(float), n, f);
  fclose(f);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_float>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  lea    D4(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %r13d,%edx
  mov    $0x4,%esi
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <fclose@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: wb

assistant: ```c
void write_float(const float *x, const int n, const char *fNam) {
  FILE *f;
  f = fopen(fNam, "wb");
  fwrite(x, sizeof(float), n, f);
  fclose(f);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_float>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  lea    D1(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %r13d,%edx
  mov    $0x4,%esi
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <fclose@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: wb

assistant: ```c
void write_float(const float *x, const int n, const char *fNam) {
  FILE *f;
  f = fopen(fNam, "wb");
  fwrite(x, sizeof(float), n, f);
  fclose(f);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x2,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x4,-0x58(%rbp)
  movl   $0x3,-0x54(%rbp)
  movl   $0x0,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x60(%rbp)
  jmp    L1
L0:
  movl   $0x0,-0x5c(%rbp)
  jmp    L4
L58:
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x60(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x5c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x60(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  addl   $0x1,-0x5c(%rbp)
L4:
  mov    -0x5c(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L58
  addl   $0x1,-0x60(%rbp)
L1:
  mov    -0x60(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jl     L0
  movl   $0x0,-0x60(%rbp)
  jmp    L28
L44:
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x60(%rbp)
L28:
  mov    -0x60(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jl     L44
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: %d 

assistant: ```c
int main() {
  int array[3][4] = {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}};
  int col = 4, row = 3;
  int col_sum[4] = {0, 0, 0, 0};
  int i, j;
  for (i = 0; i < col; i++) {
    for (j = 0; j < row; j++) {
      col_sum[i] += array[j][i];
    }
  }
  for (i = 0; i < col; i++) {
    printf("%d ", col_sum[i]);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x4,0x1c(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x2,0x24(%rsp)
  movl   $0x3,0x28(%rsp)
  movl   $0x4,0x2c(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0x2,0x34(%rsp)
  movl   $0x3,0x38(%rsp)
  movl   $0x4,0x3c(%rsp)
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %rsp,%rbx
  lea    0x10(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  mov    %rbx,%rcx
L28:
  mov    (%rcx),%eax
  add    (%rdx),%eax
  add    0x10(%rdx),%eax
  add    0x20(%rdx),%eax
  mov    %eax,(%rcx)
  add    $0x4,%rcx
  add    $0x4,%rdx
  cmp    %rdx,%rsi
  jne    L28
  lea    0x10(%rbx),%r12
  lea    D3(%rip),%rbp
L25:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: %d 

assistant: ```c
int main() {
  int array[3][4] = {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}};
  int col = 4, row = 3;
  int col_sum[4] = {0, 0, 0, 0};
  int i, j;
  for (i = 0; i < col; i++) {
    for (j = 0; j < row; j++) {
      col_sum[i] += array[j][i];
    }
  }
  for (i = 0; i < col; i++) {
    printf("%d ", col_sum[i]);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  movabs $0x200000001,%rdx
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdx,0x20(%rsp)
  lea    0x20(%rsp),%rdi
  movl   $0x2,0x14(%rsp)
  mov    %rbx,%rcx
  movabs $0x400000003,%rax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rax,0x28(%rsp)
  mov    %rdx,0x30(%rsp)
  lea    0x10(%rsp),%rdx
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
L26:
  add    %esi,%eax
  add    $0x4,%rdx
  add    0xc(%rdx),%eax
  add    0x1c(%rdx),%eax
  mov    %eax,(%rcx)
  add    $0x4,%rcx
  cmp    %rdi,%rdx
  je     L0
  mov    (%rcx),%eax
  mov    (%rdx),%esi
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    0x10(%rbx),%r12
  lea    D0(%rip),%rbp
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: %d 

assistant: ```c
int main() {
  int array[3][4] = {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}};
  int col = 4, row = 3;
  int col_sum[4] = {0, 0, 0, 0};
  int i, j;
  for (i = 0; i < col; i++) {
    for (j = 0; j < row; j++) {
      col_sum[i] += array[j][i];
    }
  }
  for (i = 0; i < col; i++) {
    printf("%d ", col_sum[i]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x10(%rsp),%r12
  movaps %xmm0,(%rsp)
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string
name: unpack_data
arguments: data_label: D11
type: byte[16]

tool: D7: %d 

tool: {"D11": [0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int array[3][4] = {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}};
  int col = 4, row = 3;
  int col_sum[4] = {0, 0, 0, 0};
  int i, j;
  for (i = 0; i < col; i++) {
    for (j = 0; j < row; j++) {
      col_sum[i] += array[j][i];
    }
  }
  for (i = 0; i < col; i++) {
    printf("%d ", col_sum[i]);
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xyz2llh>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rsi,%rbx
  mov    (%rdi),%r12
  mov    0x8(%rdi),%rbp
  movsd  0x10(%rdi),%xmm6
  movsd  %xmm6,0x30(%rsp)
  movq   %r12,%xmm1
  mulsd  %xmm1,%xmm1
  movq   %rbp,%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x28(%rsp)
  mulsd  D66(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
  jmp    L17
L50:
  movsd  %xmm0,0x8(%rsp)
L17:
  movsd  0x8(%rsp),%xmm0
  addsd  0x30(%rsp),%xmm0
  movsd  %xmm0,0x10(%rsp)
  mulsd  %xmm0,%xmm0
  addsd  0x28(%rsp),%xmm0
  pxor   %xmm7,%xmm7
  ucomisd %xmm0,%xmm7
  ja     L60
  sqrtsd %xmm0,%xmm0
  movsd  %xmm0,0x18(%rsp)
L74:
  movsd  0x10(%rsp),%xmm4
  divsd  0x18(%rsp),%xmm4
  movsd  %xmm4,0x20(%rsp)
  movsd  D66(%rip),%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  movsd  D34(%rip),%xmm0
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L11
  sqrtsd %xmm0,%xmm0
L32:
  movsd  D17(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x38(%rsp)
  movapd %xmm1,%xmm0
  mulsd  D66(%rip),%xmm0
  mulsd  0x20(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm0,%xmm1
  andpd  D3(%rip),%xmm1
  movsd  D14(%rip),%xmm2
  comisd %xmm1,%xmm2
  jbe    L50
  pxor   %xmm0,%xmm0
  movsd  0x28(%rsp),%xmm7
  ucomisd %xmm7,%xmm0
  ja     L37
  sqrtsd %xmm7,%xmm7
  movapd %xmm7,%xmm1
L16:
  movsd  0x10(%rsp),%xmm0
  call   <atan2@plt>
  movsd  %xmm0,(%rbx)
  movq   %r12,%xmm1
  movq   %rbp,%xmm0
  call   <atan2@plt>
  movsd  %xmm0,0x8(%rbx)
  movsd  0x18(%rsp),%xmm0
  subsd  0x38(%rsp),%xmm0
  movsd  %xmm0,0x10(%rbx)
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L60:
  call   <sqrt@plt>
  movsd  %xmm0,0x18(%rsp)
  jmp    L74
L11:
  call   <sqrt@plt>
  jmp    L32
L37:
  movsd  0x28(%rsp),%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L16
```

tool_calls: name: parse_data
arguments: label: D66
data_type: byte[8]
name: parse_data
arguments: label: D34
data_type: f64
name: parse_data
arguments: label: D17
data_type: f64
name: parse_data
arguments: label: D3
data_type: qword[2]
name: parse_data
arguments: label: D14
data_type: byte[8]

tool: {"D66": [0x1a,0x85,0xfe,0xf1,0x90,0x6b,0x7b,0x3f]}

tool: D34: 1

tool: D17: 6378137

tool: {"D3": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D14": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

assistant: ```c
void xyz2llh(double *xyz, double *llh) {
  double a, eps, e, e2;
  double x, y, z;
  double rho2, dz, zdz, nh, slat, n, dz_new;
  a = 6378137.0;
  e = 0.0818191908426;
  eps = 1.0e-3;
  e2 = e * e;
  x = xyz[0];
  y = xyz[1];
  z = xyz[2];
  rho2 = x * x + y * y;
  dz = e2 * z;
  while (1) {
    zdz = z + dz;
    nh = sqrt(rho2 + zdz * zdz);
    slat = zdz / nh;
    n = a / sqrt(1.0 - e2 * slat * slat);
    dz_new = n * e2 * slat;
    if (fabs(dz - dz_new) < eps)
      break;
    dz = dz_new;
  }
  llh[0] = atan2(zdz, sqrt(rho2));
  llh[1] = atan2(y, x);
  llh[2] = nh - n;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_var>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L67
L22:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L52
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L52
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <get_sub_str@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L37
L31:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%eax
  jmp    L37
L52:
  addl   $0x1,-0x10(%rbp)
L67:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L22
  mov    $0x0,%eax
L37:
  leave
  ret
```

assistant: ```c
int print_var(char **env, char *var) {
  int i;
  char *tmp;
  int len;
  len = strlen(var);
  i = 0;
  while (env[i]) {
    if (!(strncmp(env[i], var, len)) && env[i][len] == '=') {
      if (!(tmp = get_sub_str(env[i], len + 1, strlen(env[i]))))
        return (0);
      write(1, tmp, strlen(tmp));
      return (1);
    }
    i++;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_var>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L36
  mov    %eax,%r12d
  movslq %eax,%r14
  jmp    L17
L43:
  add    $0x8,%rbp
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L25
L17:
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <strncmp@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L43
  mov    0x0(%rbp),%rdi
  cmpb   $0x3d,(%rdi,%r14,1)
  jne    L43
  call   <strlen@plt>
  mov    %eax,%edx
  lea    0x1(%r12),%esi
  mov    0x0(%rbp),%rdi
  call   <get_sub_str@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L40
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%ebx
  jmp    L40
L25:
  mov    $0x0,%ebx
L40:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  mov    $0x0,%ebx
  jmp    L40
```

assistant: ```c
int print_var(char **env, char *var) {
  int i;
  char *tmp;
  int len;
  len = strlen(var);
  i = 0;
  while (env[i]) {
    if (!(strncmp(env[i], var, len)) && env[i][len] == '=') {
      if (!(tmp = get_sub_str(env[i], len + 1, strlen(env[i]))))
        return (0);
      write(1, tmp, strlen(tmp));
      return (1);
    }
    i++;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_var>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L2
  mov    %eax,%ebp
  movslq %eax,%r13
  nopl   0x0(%rax)
L49:
  mov    %ebp,%edx
  mov    %r12,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L1
  mov    (%rbx),%rdi
  cmpb   $0x3d,(%rdi,%r13,1)
  je     L17
L1:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L49
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x1(%rbp),%esi
  mov    %eax,%edx
  call   <get_sub_str@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int print_var(char **env, char *var) {
  int i;
  char *tmp;
  int len;
  len = strlen(var);
  i = 0;
  while (env[i]) {
    if (!(strncmp(env[i], var, len)) && env[i][len] == '=') {
      if (!(tmp = get_sub_str(env[i], len + 1, strlen(env[i]))))
        return (0);
      write(1, tmp, strlen(tmp));
      return (1);
    }
    i++;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_var>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L24
  mov    %eax,%ebp
  movslq %eax,%r13
  nopl   0x0(%rax)
L29:
  mov    %ebp,%edx
  mov    %r12,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L49
  mov    (%rbx),%rdi
  cmpb   $0x3d,(%rdi,%r13,1)
  je     L27
L49:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L29
L24:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x1(%rbp),%esi
  mov    %eax,%edx
  call   <get_sub_str@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L24
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int print_var(char **env, char *var) {
  int i;
  char *tmp;
  int len;
  len = strlen(var);
  i = 0;
  while (env[i]) {
    if (!(strncmp(env[i], var, len)) && env[i][len] == '=') {
      if (!(tmp = get_sub_str(env[i], len + 1, strlen(env[i]))))
        return (0);
      write(1, tmp, strlen(tmp));
      return (1);
    }
    i++;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fifa07ecrc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movw   $0x1a,-0x6(%rbp)
  movl   $0x28,-0x4(%rbp)
  jmp    L17
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  mov    $0x26c,%edx
  sub    %ecx,%edx
  imul   %edx,%eax
  add    %ax,-0x6(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x26b,-0x4(%rbp)
  jle    L19
  movzwl -0x6(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short fifa07ecrc(unsigned char *data) {
  unsigned short crc = 26;
  int i;
  for (i = 0x00000028; i < 0x0000026C; i++) {
    crc += data[i] * (0x0000026C - (i & ~0x3));
  }
  return crc;
}
```
user: What is the c source code of the assembly code below?

```asm
<fifa07ecrc>:
  endbr64
  mov    $0x28,%eax
  mov    $0x1a,%ecx
  mov    $0x26c,%r8d
L2:
  mov    %eax,%edx
  and    $0xfffffffc,%edx
  mov    %r8d,%esi
  sub    %edx,%esi
  movzbl (%rdi,%rax,1),%edx
  imul   %esi,%edx
  add    %edx,%ecx
  add    $0x1,%rax
  cmp    $0x26c,%rax
  jne    L2
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned short fifa07ecrc(unsigned char *data) {
  unsigned short crc = 26;
  int i;
  for (i = 0x00000028; i < 0x0000026C; i++) {
    crc += data[i] * (0x0000026C - (i & ~0x3));
  }
  return crc;
}
```