ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<kernel_dgecp_2_3_lib4>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  sete   %al
  add    %eax,%esi
  test   %esi,%esi
  jle    L62
  shl    $0x2,%ecx
  push   %rbx
  mov    %edi,%r10d
  movslq %ecx,%rcx
  lea    (%rdx,%rcx,8),%r11
  cmp    $0x3,%esi
  jle    L8
  lea    -0x4(%rsi),%r9d
  mov    %r11,%rcx
  mov    %r8,%rax
  shr    $0x2,%r9d
  lea    0x1(%r9),%ebx
  mov    %rbx,%r9
  shl    $0x7,%rbx
  lea    (%rdx,%rbx,1),%rdi
  nopw   0x0(%rax,%rax,1)
L60:
  movsd  0x18(%rdx),%xmm0
  sub    $0xffffffffffffff80,%rdx
  sub    $0xffffffffffffff80,%rcx
  sub    $0xffffffffffffff80,%rax
  movsd  %xmm0,-0x80(%rax)
  movsd  -0x80(%rcx),%xmm0
  movsd  %xmm0,-0x78(%rax)
  movsd  -0x48(%rdx),%xmm0
  movsd  %xmm0,-0x60(%rax)
  movsd  -0x60(%rcx),%xmm0
  movsd  %xmm0,-0x58(%rax)
  movsd  -0x28(%rdx),%xmm0
  movsd  %xmm0,-0x40(%rax)
  movsd  -0x40(%rcx),%xmm0
  movsd  %xmm0,-0x38(%rax)
  movsd  -0x8(%rdx),%xmm0
  movsd  %xmm0,-0x20(%rax)
  movsd  -0x20(%rcx),%xmm0
  movsd  %xmm0,-0x18(%rax)
  cmp    %rdi,%rdx
  jne    L60
  lea    0x0(,%r9,4),%edx
  add    %rbx,%r11
  add    %rbx,%r8
  cmp    %esi,%edx
  jge    L12
L67:
  mov    %edx,%ecx
  xor    %eax,%eax
L29:
  movsd  0x18(%rdi,%rax,1),%xmm0
  add    $0x1,%ecx
  movsd  %xmm0,(%r8,%rax,1)
  movsd  (%r11,%rax,1),%xmm0
  movsd  %xmm0,0x8(%r8,%rax,1)
  add    $0x20,%rax
  cmp    %ecx,%esi
  jg     L29
  lea    -0x1(%rsi),%eax
  sub    %edx,%eax
  add    $0x1,%rax
  shl    $0x5,%rax
  cmp    %edx,%esi
  mov    $0x20,%edx
  cmovle %rdx,%rax
  add    %rax,%r11
  add    %rax,%r8
L12:
  cmp    $0x1,%r10d
  je     L28
  pop    %rbx
  ret
  nopl   0x0(%rax)
L28:
  movsd  (%r11),%xmm0
  pop    %rbx
  movsd  %xmm0,0x8(%r8)
  ret
  nopl   (%rax)
L62:
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdx,%rdi
  xor    %edx,%edx
  jmp    L67
```

assistant: ```c
void kernel_dgecp_2_3_lib4(int tri, int kmax, double *A0, int sda, double *B) {
  if (tri == 1) {
    kmax += 1;
  }
  if (kmax <= 0)
    return;
  const int bs = 4;
  double *A1 = A0 + bs * sda;
  int k;
  for (k = 0; k < kmax - 3; k += 4) {
    B[0 + bs * 0] = A0[3 + bs * 0];
    B[1 + bs * 0] = A1[0 + bs * 0];
    B[0 + bs * 1] = A0[3 + bs * 1];
    B[1 + bs * 1] = A1[0 + bs * 1];
    B[0 + bs * 2] = A0[3 + bs * 2];
    B[1 + bs * 2] = A1[0 + bs * 2];
    B[0 + bs * 3] = A0[3 + bs * 3];
    B[1 + bs * 3] = A1[0 + bs * 3];
    A0 += 16;
    A1 += 16;
    B += 16;
  }
  for (; k < kmax; k++) {
    B[0 + bs * 0] = A0[3 + bs * 0];
    B[1 + bs * 0] = A1[0 + bs * 0];
    A0 += 4;
    A1 += 4;
    B += 4;
  }
  if (tri == 1) {
    B[1 + bs * 0] = A1[0 + bs * 0];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<kernel_dgecp_2_3_lib4>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  sete   %al
  add    %eax,%esi
  test   %esi,%esi
  jle    L9
  shl    $0x2,%ecx
  push   %rbx
  mov    %edi,%r10d
  movslq %ecx,%rcx
  lea    (%rdx,%rcx,8),%r11
  cmp    $0x3,%esi
  jle    L34
  lea    -0x4(%rsi),%eax
  mov    %r11,%rcx
  shr    $0x2,%eax
  lea    0x1(%rax),%ebx
  mov    %r8,%rax
  mov    %rbx,%rdi
  shl    $0x7,%rbx
  lea    (%rdx,%rbx,1),%r9
  nopw   0x0(%rax,%rax,1)
L7:
  movsd  0x18(%rdx),%xmm0
  sub    $0xffffffffffffff80,%rdx
  sub    $0xffffffffffffff80,%rcx
  sub    $0xffffffffffffff80,%rax
  movsd  %xmm0,-0x80(%rax)
  movsd  -0x80(%rcx),%xmm0
  movsd  %xmm0,-0x78(%rax)
  movsd  -0x48(%rdx),%xmm0
  movsd  %xmm0,-0x60(%rax)
  movsd  -0x60(%rcx),%xmm0
  movsd  %xmm0,-0x58(%rax)
  movsd  -0x28(%rdx),%xmm0
  movsd  %xmm0,-0x40(%rax)
  movsd  -0x40(%rcx),%xmm0
  movsd  %xmm0,-0x38(%rax)
  movsd  -0x8(%rdx),%xmm0
  movsd  %xmm0,-0x20(%rax)
  movsd  -0x20(%rcx),%xmm0
  movsd  %xmm0,-0x18(%rax)
  cmp    %r9,%rdx
  jne    L7
  lea    0x0(,%rdi,4),%eax
  add    %rbx,%r11
  add    %rbx,%r8
  cmp    %esi,%eax
  jge    L47
L0:
  movsd  0x18(%r9),%xmm0
  lea    0x1(%rax),%edx
  movsd  %xmm0,(%r8)
  movsd  (%r11),%xmm0
  movsd  %xmm0,0x8(%r8)
  cmp    %edx,%esi
  jle    L78
  movsd  0x38(%r9),%xmm0
  lea    0x2(%rax),%edx
  movsd  %xmm0,0x20(%r8)
  movsd  0x20(%r11),%xmm0
  movsd  %xmm0,0x28(%r8)
  cmp    %edx,%esi
  jle    L78
  movsd  0x58(%r9),%xmm0
  lea    0x3(%rax),%edx
  movsd  %xmm0,0x40(%r8)
  movsd  0x40(%r11),%xmm0
  movsd  %xmm0,0x48(%r8)
  cmp    %edx,%esi
  jle    L78
  movsd  0x78(%r9),%xmm0
  movsd  %xmm0,0x60(%r8)
  movsd  0x60(%r11),%xmm0
  movsd  %xmm0,0x68(%r8)
L78:
  lea    -0x1(%rsi),%edx
  sub    %eax,%edx
  add    $0x1,%rdx
  shl    $0x5,%rdx
  cmp    %eax,%esi
  mov    $0x20,%eax
  cmovle %rax,%rdx
  add    %rdx,%r11
  add    %rdx,%r8
L47:
  cmp    $0x1,%r10d
  je     L25
  pop    %rbx
  ret
  nop
L25:
  movsd  (%r11),%xmm0
  pop    %rbx
  movsd  %xmm0,0x8(%r8)
  ret
  nopl   (%rax)
L9:
  ret
  nopl   0x0(%rax)
L34:
  mov    %rdx,%r9
  xor    %eax,%eax
  jmp    L0
```

assistant: ```c
void kernel_dgecp_2_3_lib4(int tri, int kmax, double *A0, int sda, double *B) {
  if (tri == 1) {
    kmax += 1;
  }
  if (kmax <= 0)
    return;
  const int bs = 4;
  double *A1 = A0 + bs * sda;
  int k;
  for (k = 0; k < kmax - 3; k += 4) {
    B[0 + bs * 0] = A0[3 + bs * 0];
    B[1 + bs * 0] = A1[0 + bs * 0];
    B[0 + bs * 1] = A0[3 + bs * 1];
    B[1 + bs * 1] = A1[0 + bs * 1];
    B[0 + bs * 2] = A0[3 + bs * 2];
    B[1 + bs * 2] = A1[0 + bs * 2];
    B[0 + bs * 3] = A0[3 + bs * 3];
    B[1 + bs * 3] = A1[0 + bs * 3];
    A0 += 16;
    A1 += 16;
    B += 16;
  }
  for (; k < kmax; k++) {
    B[0 + bs * 0] = A0[3 + bs * 0];
    B[1 + bs * 0] = A1[0 + bs * 0];
    A0 += 4;
    A1 += 4;
    B += 4;
  }
  if (tri == 1) {
    B[1 + bs * 0] = A1[0 + bs * 0];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L6
  movsd  -0x8(%rbp),%xmm0
  jmp    L15
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
L15:
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L23
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: byte[8]

tool: {"D5": [0x00,0x00,0x00,0xa2,0x94,0x1a,0x6d,0xc2]}

assistant: ```c
double max(float *data, int n) {
  double m = -1e12;
  int i;
  for (i = 0; i < n; i++) {
    m = ((m) > ((double)*(data + i)) ? (m) : ((double)*(data + i)));
  }
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<max>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  movsd  D7(%rip),%xmm0
L2:
  pxor   %xmm1,%xmm1
  cvtss2sd (%rax),%xmm1
  maxsd  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L2
  ret
L13:
  movsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0xa2,0x94,0x1a,0x6d,0xc2]}

assistant: ```c
double max(float *data, int n) {
  double m = -1e12;
  int i;
  for (i = 0; i < n; i++) {
    m = ((m) > ((double)*(data + i)) ? (m) : ((double)*(data + i)));
  }
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<max>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  movsd  D16(%rip),%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax,%rax,1)
L17:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtss2sd -0x4(%rdi),%xmm1
  maxsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L17
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  movsd  D16(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
datatype: byte[8]

tool: {"D16": [0x00,0x00,0x00,0xa2,0x94,0x1a,0x6d,0xc2]}

assistant: ```c
double max(float *data, int n) {
  double m = -1e12;
  int i;
  for (i = 0; i < n; i++) {
    m = ((m) > ((double)*(data + i)) ? (m) : ((double)*(data + i)));
  }
  return m;
}
```
user: What is the c source code of the assembly code below?

```asm
<max>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  movsd  D13(%rip),%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax,%rax,1)
L10:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtss2sd -0x4(%rdi),%xmm1
  maxsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L10
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  movsd  D13(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_infered: byte[8]

tool: {"D13": [0x00,0x00,0x00,0xa2,0x94,0x1a,0x6d,0xc2]}

assistant: ```c
double max(float *data, int n) {
  double m = -1e12;
  int i;
  for (i = 0; i < n; i++) {
    m = ((m) > ((double)*(data + i)) ? (m) : ((double)*(data + i)));
  }
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x726f776f6c6c6568,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x646c,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L6
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L6:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void f4(int size) {
  char src[12] = "helloworld";
  char dest[12];
  if (size > 0)
    memmove(dest, src, size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f4>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x726f776f6c6c6568,%rax
  mov    %rax,(%rsp)
  movl   $0x646c,0x8(%rsp)
  test   %edi,%edi
  jg     L19
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  ret
L19:
  mov    %edi,%edx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  call   <memmove@plt>
  jmp    L8
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f4(int size) {
  char src[12] = "helloworld";
  char dest[12];
  if (size > 0)
    memmove(dest, src, size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f4>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x726f776f6c6c6568,%rax
  movl   $0x646c,0x8(%rsp)
  mov    %rax,(%rsp)
  test   %edi,%edi
  jle    L9
  mov    %edi,%edx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  call   <memmove@plt>
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f4(int size) {
  char src[12] = "helloworld";
  char dest[12];
  if (size > 0)
    memmove(dest, src, size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f4>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x726f776f6c6c6568,%rax
  movl   $0x646c,0x8(%rsp)
  mov    %rax,(%rsp)
  test   %edi,%edi
  jle    L4
  mov    %edi,%edx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  call   <memmove@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f4(int size) {
  char src[12] = "helloworld";
  char dest[12];
  if (size > 0)
    memmove(dest, src, size);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mpfq_copyd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x10(%rbp)
  jmp    L1
L10:
  subq   $0x4,-0x10(%rbp)
  subq   $0x4,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L1:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mpfq_copyd(mp_limb_t *dst, const mp_limb_t *src, mp_size_t n) {
  for (dst += n, src += n; n--;)
    *--dst = *--src;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mpfq_copyd>:
  endbr64
  movslq %edx,%rax
  shl    $0x2,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  test   %edx,%edx
  je     L4
  lea    -0x1(%rdx),%eax
  neg    %rax
  lea    -0x8(,%rax,4),%rcx
  mov    $0xfffffffffffffffc,%rax
L8:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L8
L4:
  ret
```

assistant: ```c
void mpfq_copyd(mp_limb_t *dst, const mp_limb_t *src, mp_size_t n) {
  for (dst += n, src += n; n--;)
    *--dst = *--src;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mpfq_copyd>:
  endbr64
  movslq %edx,%rax
  shl    $0x2,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  test   %edx,%edx
  je     L17
  lea    -0x1(%rdx),%eax
  neg    %rax
  lea    -0x8(,%rax,4),%rcx
  mov    $0xfffffffffffffffc,%rax
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L11
L17:
  ret
```

assistant: ```c
void mpfq_copyd(mp_limb_t *dst, const mp_limb_t *src, mp_size_t n) {
  for (dst += n, src += n; n--;)
    *--dst = *--src;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mpfq_copyd>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%rcx
  mov    %rax,%rdi
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%r9
  lea    (%rsi,%rax,1),%r8
  lea    -0x1(%rdi),%r10d
  test   %edi,%edi
  je     L37
  mov    %rcx,%rdx
  sub    %rsi,%rdx
  add    $0xc,%rdx
  cmp    $0x8,%rdx
  jbe    L72
  cmp    $0x2,%r10d
  jbe    L72
  mov    %edi,%edx
  sub    $0x10,%rax
  shr    $0x2,%edx
  add    %rax,%rsi
  add    %rax,%rcx
  xor    %eax,%eax
  neg    %rdx
  shl    $0x4,%rdx
  nopl   0x0(%rax,%rax,1)
L33:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  sub    $0x10,%rax
  cmp    %rax,%rdx
  jne    L33
  mov    %edi,%edx
  and    $0xfffffffc,%edx
  mov    %edx,%eax
  sub    %edx,%r10d
  neg    %rax
  shl    $0x2,%rax
  cmp    %edx,%edi
  je     L37
  sub    $0x4,%rax
  add    %rax,%r8
  add    %r9,%rax
  mov    (%r8),%edx
  mov    %edx,(%rax)
  test   %r10d,%r10d
  je     L37
  mov    -0x4(%r8),%edx
  mov    %edx,-0x4(%rax)
  cmp    $0x1,%r10d
  je     L37
  mov    -0x8(%r8),%edx
  mov    %edx,-0x8(%rax)
  ret
  nopl   0x0(%rax,%rax,1)
L72:
  neg    %r10
  mov    $0xfffffffffffffffc,%rax
  lea    -0x8(,%r10,4),%rcx
  nopw   0x0(%rax,%rax,1)
L70:
  mov    (%r8,%rax,1),%edx
  mov    %edx,(%r9,%rax,1)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L70
L37:
  ret
```

assistant: ```c
void mpfq_copyd(mp_limb_t *dst, const mp_limb_t *src, mp_size_t n) {
  for (dst += n, src += n; n--;)
    *--dst = *--src;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<daxpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void daxpy(double *restrict x, double *restrict y, double a, int n) {
  for (int i = 0; i < n; i++)
    y[i] = a * x[i] + y[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<daxpy>:
  endbr64
  test   %edx,%edx
  jle    L12
  mov    %edx,%edx
  mov    $0x0,%eax
L8:
  movapd %xmm0,%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
L12:
  ret
```

assistant: ```c
void daxpy(double *restrict x, double *restrict y, double a, int n) {
  for (int i = 0; i < n; i++)
    y[i] = a * x[i] + y[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<daxpy>:
  endbr64
  test   %edx,%edx
  jle    L15
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L4:
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L4
L15:
  ret
```

assistant: ```c
void daxpy(double *restrict x, double *restrict y, double a, int n) {
  for (int i = 0; i < n; i++)
    y[i] = a * x[i] + y[i];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<daxpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L4
  cmp    $0x1,%edx
  je     L48
  mov    %edx,%edi
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  shr    %edi
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L23:
  movupd (%rcx,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  mulpd  %xmm2,%xmm1
  addpd  %xmm3,%xmm1
  movups %xmm1,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L23
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L24
L39:
  cltq
  lea    (%rsi,%rax,8),%rdx
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
L4:
  ret
  nopl   (%rax)
L24:
  ret
L48:
  xor    %eax,%eax
  jmp    L39
```

assistant: ```c
void daxpy(double *restrict x, double *restrict y, double a, int n) {
  for (int i = 0; i < n; i++)
    y[i] = a * x[i] + y[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L126
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D6(%rip),%r12
L26:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L26
L126:
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L86
  lea    0x10(%rsp),%r10
  mov    %r10,%r8
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  mov    $0x1,%r11d
  mov    %r10,%rbx
  lea    0x14(%rsp),%r10
  jmp    L148
L48:
  test   %cl,%cl
  je     L9
  mov    %esi,0xc(%rsp)
L82:
  cmpl   $0x0,0xc(%rsp)
  jle    L86
L9:
  mov    $0x0,%ebx
  lea    D21(%rip),%rbp
L16:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L16
L86:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  cmp    %edx,%esi
  jle    L0
  mov    %rax,%rdi
  lea    (%rbx,%rax,4),%rax
  lea    -0x1(%rsi),%ecx
  sub    %edx,%ecx
  add    %rdi,%rcx
  lea    (%r10,%rcx,4),%rdi
L5:
  mov    0x4(%rax),%ecx
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L5
L0:
  sub    $0x1,%esi
  mov    %r11d,%ecx
L2:
  cmp    %esi,%edx
  jge    L133
L167:
  movslq %edx,%rax
  mov    (%r8),%edi
  cmp    %edi,0x10(%rsp,%rax,4)
  je     L55
  add    $0x1,%edx
  jmp    L2
L133:
  add    $0x4,%r8
  cmp    %esi,%r9d
  jge    L72
L148:
  add    $0x1,%r9d
  cmp    %r9d,%esi
  jle    L48
  mov    %r9d,%edx
  jmp    L167
L72:
  test   %cl,%cl
  je     L9
  mov    %esi,0xc(%rsp)
  jmp    L82
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D45
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D44
type_guessed: string
name: unpack_data
arguments: label: D37
type_guessed: string
name: unpack_data
arguments: label: D21
type_guessed: string

tool: D45: 
Enter array size : 

tool: D6: %d

tool: D44: 
Accept Numbers : 

tool: D37: 
Array with Unique list  : 

tool: D21: %d 

assistant: ```c
int main() {
  int arr[20], i, j, k, size;
  printf("\nEnter array size : ");
  scanf("%d", &size);
  printf("\nAccept Numbers : ");
  for (i = 0; i < size; i++)
    scanf("%d", &arr[i]);
  printf("\nArray with Unique list  : ");
  for (i = 0; i < size; i++) {
    for (j = i + 1; j < size;) {
      if (arr[j] == arr[i]) {
        for (k = j; k < size; k++) {
          arr[k] = arr[k + 1];
        }
        size--;
      } else
        j++;
    }
  }
  for (i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D31(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L91
  nop
L72:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L72
L91:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L68
  lea    0x10(%rsp),%r14
  xor    %ecx,%ecx
  xor    %r13d,%r13d
  mov    $0x4,%ebp
  mov    %r14,%r12
  nopl   0x0(%rax)
L51:
  add    $0x1,%r13d
  cmp    %edx,%r13d
  jge    L4
  mov    %r13d,%ebx
  jmp    L103
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %eax,%ebx
  cmp    %edx,%ebx
  jge    L65
L103:
  movslq %ebx,%rdi
  mov    (%r12),%esi
  lea    0x1(%rbx),%eax
  cmp    %esi,0x10(%rsp,%rdi,4)
  jne    L24
  lea    -0x1(%rdx),%r15d
  shl    $0x2,%rdi
  mov    %r15d,%eax
  lea    0x4(%r14,%rdi,1),%rsi
  sub    %ebx,%eax
  cmp    %ebx,%edx
  lea    0x4(,%rax,4),%r8
  cmovle %rbp,%r8
  add    %r14,%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
  mov    %r15d,%edx
  mov    $0x1,%ecx
  cmp    %edx,%ebx
  jl     L103
  nopl   (%rax)
L65:
  add    $0x4,%r12
  cmp    %edx,%r13d
  jl     L51
L4:
  test   %cl,%cl
  je     L81
  mov    %edx,0xc(%rsp)
L81:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L68
  xor    %ebx,%ebx
  lea    D26(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L86:
  mov    (%r14,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L86
L68:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D31
data_type: string
name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D26
data_type: string

tool: D31: 
Enter array size : 

tool: D2: %d

tool: D3: 
Accept Numbers : 

tool: D5: 
Array with Unique list  : 

tool: D26: %d 

assistant: ```c
int main() {
  int arr[20], i, j, k, size;
  printf("\nEnter array size : ");
  scanf("%d", &size);
  printf("\nAccept Numbers : ");
  for (i = 0; i < size; i++)
    scanf("%d", &arr[i]);
  printf("\nArray with Unique list  : ");
  for (i = 0; i < size; i++) {
    for (j = i + 1; j < size;) {
      if (arr[j] == arr[i]) {
        for (k = j; k < size; k++) {
          arr[k] = arr[k + 1];
        }
        size--;
      } else
        j++;
    }
  }
  for (i = 0; i < size; i++) {
    printf("%d ", arr[i]);
  }
  return (0);
}
```