ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ct_aux_rebuild_contenttype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x10(%rbp),%edx
  add    %edx,%eax
  add    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L6
L20:
  cmpl   $0x0,-0x10(%rbp)
  je     L38
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D4(%rip),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  jmp    L37
L38:
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  lea    D11(%rip),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
L37:
  mov    -0x8(%rbp),%rax
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D11
type: string

tool: D4: %s/%s

tool: D11: %s

assistant: ```c
char *ct_aux_rebuild_contenttype(const char *in_cttype, const char *in_ctsubtype) {
  int buflen;
  char *newstr;
  int in_ctsubtype_len;
  in_ctsubtype_len = strlen(in_ctsubtype);
  buflen = strlen(in_cttype) + in_ctsubtype_len + 2;
  if ((newstr = calloc(buflen, sizeof(char))) == NULL)
    return (NULL);
  if (in_ctsubtype_len != 0)
    snprintf(newstr, buflen, "%s/%s", in_cttype, in_ctsubtype);
  else
    snprintf(newstr, buflen, "%s", in_cttype);
  return (newstr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ct_aux_rebuild_contenttype>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%r14d
  mov    $0x1,%esi
  mov    %r14d,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
  test   %ebp,%ebp
  je     L26
  mov    %r13,%r8
  mov    %r12,%rcx
  lea    D19(%rip),%rdx
  mov    %r14d,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
L27:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  mov    %r12,%rcx
  lea    D2(%rip),%rdx
  mov    %r14d,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  jmp    L27
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D19: %s/%s

tool: D2: %s

assistant: ```c
char *ct_aux_rebuild_contenttype(const char *in_cttype, const char *in_ctsubtype) {
  int buflen;
  char *newstr;
  int in_ctsubtype_len;
  in_ctsubtype_len = strlen(in_ctsubtype);
  buflen = strlen(in_cttype) + in_ctsubtype_len + 2;
  if ((newstr = calloc(buflen, sizeof(char))) == NULL)
    return (NULL);
  if (in_ctsubtype_len != 0)
    snprintf(newstr, buflen, "%s/%s", in_cttype, in_ctsubtype);
  else
    snprintf(newstr, buflen, "%s", in_cttype);
  return (newstr);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ct_aux_rebuild_contenttype>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x2(%rbx,%rax,1),%r14d
  mov    %r14d,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  test   %ebx,%ebx
  je     L2
  mov    %rax,%rdi
  mov    %rbp,%r8
  mov    %r13,%rcx
  mov    %r14d,%esi
  lea    D16(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
L16:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r13,%rcx
  mov    %r14d,%esi
  lea    D18(%rip),%rdx
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <snprintf@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D16
datatype: string
name: parse_data
arguments: label: D18
datatype: string

tool: D16: %s/%s

tool: D18: %s

assistant: ```c
char *ct_aux_rebuild_contenttype(const char *in_cttype, const char *in_ctsubtype) {
  int buflen;
  char *newstr;
  int in_ctsubtype_len;
  in_ctsubtype_len = strlen(in_ctsubtype);
  buflen = strlen(in_cttype) + in_ctsubtype_len + 2;
  if ((newstr = calloc(buflen, sizeof(char))) == NULL)
    return (NULL);
  if (in_ctsubtype_len != 0)
    snprintf(newstr, buflen, "%s/%s", in_cttype, in_ctsubtype);
  else
    snprintf(newstr, buflen, "%s", in_cttype);
  return (newstr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ct_aux_rebuild_contenttype>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x2(%rbx,%rax,1),%r14d
  mov    %r14d,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  test   %ebx,%ebx
  je     L2
  mov    %rax,%rdi
  mov    %rbp,%r8
  mov    %r13,%rcx
  mov    %r14d,%esi
  lea    D12(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
L4:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r13,%rcx
  mov    %r14d,%esi
  lea    D2(%rip),%rdx
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <snprintf@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string

tool: D12: %s/%s

tool: D2: %s

assistant: ```c
char *ct_aux_rebuild_contenttype(const char *in_cttype, const char *in_ctsubtype) {
  int buflen;
  char *newstr;
  int in_ctsubtype_len;
  in_ctsubtype_len = strlen(in_ctsubtype);
  buflen = strlen(in_cttype) + in_ctsubtype_len + 2;
  if ((newstr = calloc(buflen, sizeof(char))) == NULL)
    return (NULL);
  if (in_ctsubtype_len != 0)
    snprintf(newstr, buflen, "%s/%s", in_cttype, in_ctsubtype);
  else
    snprintf(newstr, buflen, "%s", in_cttype);
  return (newstr);
}
```
user: What is the c source code of the assembly code below?

```asm
<thread_syn_flag_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_lock@plt>
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_cond_signal@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_unlock@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int thread_syn_flag_set(pthread_mutex_t *mutex, pthread_cond_t *cond, int *flag) {
  pthread_mutex_lock(mutex);
  *flag = 1;
  pthread_cond_signal(cond);
  pthread_mutex_unlock(mutex);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<thread_syn_flag_set>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <pthread_mutex_lock@plt>
  movl   $0x1,(%r12)
  mov    %rbp,%rdi
  call   <pthread_cond_signal@plt>
  mov    %rbx,%rdi
  call   <pthread_mutex_unlock@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int thread_syn_flag_set(pthread_mutex_t *mutex, pthread_cond_t *cond, int *flag) {
  pthread_mutex_lock(mutex);
  *flag = 1;
  pthread_cond_signal(cond);
  pthread_mutex_unlock(mutex);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<thread_syn_flag_set>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <pthread_mutex_lock@plt>
  movl   $0x1,(%rbx)
  mov    %r12,%rdi
  call   <pthread_cond_signal@plt>
  mov    %rbp,%rdi
  call   <pthread_mutex_unlock@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int thread_syn_flag_set(pthread_mutex_t *mutex, pthread_cond_t *cond, int *flag) {
  pthread_mutex_lock(mutex);
  *flag = 1;
  pthread_cond_signal(cond);
  pthread_mutex_unlock(mutex);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<thread_syn_flag_set>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <pthread_mutex_lock@plt>
  movl   $0x1,(%rbx)
  mov    %r12,%rdi
  call   <pthread_cond_signal@plt>
  mov    %rbp,%rdi
  call   <pthread_mutex_unlock@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int thread_syn_flag_set(pthread_mutex_t *mutex, pthread_cond_t *cond, int *flag) {
  pthread_mutex_lock(mutex);
  *flag = 1;
  pthread_cond_signal(cond);
  pthread_mutex_unlock(mutex);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<endEMBL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7:      

assistant: ```c
int endEMBL(char *s, int *addend) {
  *addend = 0;
  return (strncmp(s, "     ", 5) != 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<endEMBL>:
  endbr64
  sub    $0x8,%rsp
  movl   $0x0,(%rsi)
  mov    $0x5,%edx
  lea    D4(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4:      

assistant: ```c
int endEMBL(char *s, int *addend) {
  *addend = 0;
  return (strncmp(s, "     ", 5) != 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<endEMBL>:
  endbr64
  sub    $0x8,%rsp
  movl   $0x0,(%rsi)
  mov    $0x5,%edx
  lea    D3(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3:      

assistant: ```c
int endEMBL(char *s, int *addend) {
  *addend = 0;
  return (strncmp(s, "     ", 5) != 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<endEMBL>:
  endbr64
  sub    $0x8,%rsp
  movl   $0x0,(%rsi)
  mov    $0x5,%edx
  lea    D3(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string

tool: D3:      

assistant: ```c
int endEMBL(char *s, int *addend) {
  *addend = 0;
  return (strncmp(s, "     ", 5) != 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<llrintl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  fldt   0x10(%rbp)
  fistpll -0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
long long llrintl(long double x) {
  long long r;
  __asm__("fistpll %0" : "=m"(r) : "t"(x) : "st");
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<llrintl>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  fldt   0x20(%rsp)
  fistpll (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long llrintl(long double x) {
  long long r;
  __asm__("fistpll %0" : "=m"(r) : "t"(x) : "st");
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<llrintl>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  fldt   0x20(%rsp)
  fistpll (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long llrintl(long double x) {
  long long r;
  __asm__("fistpll %0" : "=m"(r) : "t"(x) : "st");
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<llrintl>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  fldt   0x20(%rsp)
  fistpll (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long llrintl(long double x) {
  long long r;
  __asm__("fistpll %0" : "=m"(r) : "t"(x) : "st");
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ZN3FSMD0Ev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <_ZN3FSMD1Ev@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <_ZdlPv@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void _ZN3FSMD0Ev(struct l_class_OC_FSM *llvm_cbe_this) {
  struct l_class_OC_FSM *llvm_cbe_this_2e_addr;
  struct l_class_OC_FSM *llvm_cbe_this1;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  _ZN3FSMD1Ev(llvm_cbe_this1);
  _ZdlPv((((unsigned char *)llvm_cbe_this1)));
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_ZN3FSMD0Ev>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <_ZN3FSMD1Ev@plt>
  mov    %rbx,%rdi
  call   <_ZdlPv@plt>
  pop    %rbx
  ret
```

assistant: ```c
void _ZN3FSMD0Ev(struct l_class_OC_FSM *llvm_cbe_this) {
  struct l_class_OC_FSM *llvm_cbe_this_2e_addr;
  struct l_class_OC_FSM *llvm_cbe_this1;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  _ZN3FSMD1Ev(llvm_cbe_this1);
  _ZdlPv((((unsigned char *)llvm_cbe_this1)));
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_ZN3FSMD0Ev>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <_ZN3FSMD1Ev@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <_ZdlPv@plt>
```

assistant: ```c
void _ZN3FSMD0Ev(struct l_class_OC_FSM *llvm_cbe_this) {
  struct l_class_OC_FSM *llvm_cbe_this_2e_addr;
  struct l_class_OC_FSM *llvm_cbe_this1;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  _ZN3FSMD1Ev(llvm_cbe_this1);
  _ZdlPv((((unsigned char *)llvm_cbe_this1)));
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_ZN3FSMD0Ev>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <_ZN3FSMD1Ev@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <_ZdlPv@plt>
```

assistant: ```c
void _ZN3FSMD0Ev(struct l_class_OC_FSM *llvm_cbe_this) {
  struct l_class_OC_FSM *llvm_cbe_this_2e_addr;
  struct l_class_OC_FSM *llvm_cbe_this1;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  _ZN3FSMD1Ev(llvm_cbe_this1);
  _ZdlPv((((unsigned char *)llvm_cbe_this1)));
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SysCtlPeripheralEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  add    $0x400fe600,%eax
  and    $0xf0000000,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  add    $0x400fe600,%eax
  shl    $0x5,%eax
  and    $0x1ffffe0,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  and    $0x3fc,%eax
  or     %edx,%eax
  or     $0x2000000,%eax
  mov    %eax,%eax
  movl   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SysCtlPeripheralEnable(uint32_t ui32Peripheral) {
  ;
  (*((volatile uint32_t *)(((uint32_t)(0x400fe600 + ((ui32Peripheral & 0xff00) >> 8)) & 0xF0000000) | 0x02000000 | (((uint32_t)(0x400fe600 + ((ui32Peripheral & 0xff00) >> 8)) & 0x000FFFFF) << 5) | ((ui32Peripheral & 0xff) << 2)))) = 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SysCtlPeripheralEnable>:
  endbr64
  mov    %edi,%edx
  movzbl %dh,%eax
  add    $0x400fe600,%eax
  shl    $0x5,%eax
  shl    $0x2,%edx
  and    $0x3fc,%edx
  or     %edx,%eax
  or     $0x42000000,%eax
  movl   $0x1,(%eax)
  ret
```

assistant: ```c
void SysCtlPeripheralEnable(uint32_t ui32Peripheral) {
  ;
  (*((volatile uint32_t *)(((uint32_t)(0x400fe600 + ((ui32Peripheral & 0xff00) >> 8)) & 0xF0000000) | 0x02000000 | (((uint32_t)(0x400fe600 + ((ui32Peripheral & 0xff00) >> 8)) & 0x000FFFFF) << 5) | ((ui32Peripheral & 0xff) << 2)))) = 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SysCtlPeripheralEnable>:
  endbr64
  mov    %edi,%edx
  movzbl %dh,%eax
  shl    $0x2,%edx
  add    $0x400fe600,%eax
  and    $0x3fc,%edx
  shl    $0x5,%eax
  or     %edx,%eax
  or     $0x42000000,%eax
  movl   $0x1,(%eax)
  ret
```

assistant: ```c
void SysCtlPeripheralEnable(uint32_t ui32Peripheral) {
  ;
  (*((volatile uint32_t *)(((uint32_t)(0x400fe600 + ((ui32Peripheral & 0xff00) >> 8)) & 0xF0000000) | 0x02000000 | (((uint32_t)(0x400fe600 + ((ui32Peripheral & 0xff00) >> 8)) & 0x000FFFFF) << 5) | ((ui32Peripheral & 0xff) << 2)))) = 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<t32_genbytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  shr    $0x18,%rax
  mov    %al,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  mov    %al,-0xb(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x8,%rax
  mov    %al,-0xa(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %al,-0x9(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <t32_seckey@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <t32_gen@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void t32_genbytes(unsigned long frame, unsigned char *buf, int nbytes) {
  unsigned char framebuf[4];
  framebuf[0] = (frame >> 24) & 0xFF;
  framebuf[1] = (frame >> 16) & 0xFF;
  framebuf[2] = (frame >> 8) & 0xFF;
  framebuf[3] = (frame)&0xFF;
  t32_seckey(framebuf, 4);
  t32_gen(buf, nbytes);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t32_genbytes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  mov    %rdi,%rdx
  shr    $0x18,%rdx
  mov    %dl,0x4(%rsp)
  mov    %rdi,%rdx
  shr    $0x10,%rdx
  mov    %dl,0x5(%rsp)
  movzbl %ah,%ecx
  mov    %cl,0x6(%rsp)
  mov    %dil,0x7(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x4,%esi
  call   <t32_seckey@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <t32_gen@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t32_genbytes(unsigned long frame, unsigned char *buf, int nbytes) {
  unsigned char framebuf[4];
  framebuf[0] = (frame >> 24) & 0xFF;
  framebuf[1] = (frame >> 16) & 0xFF;
  framebuf[2] = (frame >> 8) & 0xFF;
  framebuf[3] = (frame)&0xFF;
  t32_seckey(framebuf, 4);
  t32_gen(buf, nbytes);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<t32_genbytes>:
  endbr64
  push   %r12
  bswap  %edi
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x4,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <t32_seckey@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <t32_gen@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t32_genbytes(unsigned long frame, unsigned char *buf, int nbytes) {
  unsigned char framebuf[4];
  framebuf[0] = (frame >> 24) & 0xFF;
  framebuf[1] = (frame >> 16) & 0xFF;
  framebuf[2] = (frame >> 8) & 0xFF;
  framebuf[3] = (frame)&0xFF;
  t32_seckey(framebuf, 4);
  t32_gen(buf, nbytes);
}
```
user: What is the c source code of the assembly code below:

```asm
<t32_genbytes>:
  endbr64
  push   %r12
  bswap  %edi
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x4,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <t32_seckey@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <t32_gen@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t32_genbytes(unsigned long frame, unsigned char *buf, int nbytes) {
  unsigned char framebuf[4];
  framebuf[0] = (frame >> 24) & 0xFF;
  framebuf[1] = (frame >> 16) & 0xFF;
  framebuf[2] = (frame >> 8) & 0xFF;
  framebuf[3] = (frame)&0xFF;
  t32_seckey(framebuf, 4);
  t32_gen(buf, nbytes);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findOne>:
  endbr64
  push   %rbx
  mov    %esi,%r9d
  mov    %rdx,%r10
  mov    %ecx,%esi
  cmp    %ecx,%r9d
  jl     L86
  test   %ecx,%ecx
  je     L65
  cmp    $0x1,%r8d
  je     L33
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  sub    %eax,%r8d
  movslq %r8d,%rcx
  shl    $0x2,%rcx
  mov    -0x4(%rdi,%rcx,1),%r11d
  movslq %eax,%rdx
  shl    $0x2,%rdx
  mov    -0x4(%r10,%rdx,1),%ebx
  cmp    %ebx,%r11d
  je     L78
  jle    L16
  mov    %esi,%ecx
  sub    %eax,%ecx
  add    %r10,%rdx
  mov    %r9d,%esi
  call   <findOne>
  jmp    L39
L86:
  mov    %r9d,%ecx
  mov    %rdi,%rdx
  mov    %r10,%rdi
  call   <findOne>
  jmp    L39
L65:
  movslq %r8d,%r8
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rdi,%r8,4),%xmm0
L39:
  pop    %rbx
  ret
L33:
  mov    (%rdx),%esi
  mov    (%rdi),%edi
  call   <min@plt>
  jmp    L39
L78:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r11d,%xmm0
  jmp    L39
L16:
  sub    %r8d,%r9d
  add    %rcx,%rdi
  mov    %eax,%r8d
  mov    %esi,%ecx
  mov    %r10,%rdx
  mov    %r9d,%esi
  call   <findOne>
  jmp    L39
```

assistant: ```c
double findOne(int *A, int m, int *B, int n, int k) {
  int mo, no;
  if (m < n)
    return findOne(B, n, A, m, k);
  if (n == 0)
    return A[k - 1];
  if (k == 1)
    return min(A[0], B[0]);
  no = (k / 2 < n) ? (k / 2) : n;
  mo = k - no;
  if (A[mo - 1] == B[no - 1])
    return A[mo - 1];
  else if (A[mo - 1] > B[no - 1])
    return findOne(A, m, B + no, n - no, k - no);
  else
    return findOne(A + mo, m - mo, B, n, k - mo);
}
```