ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generate_binary_key_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x41,%edi
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L16
  nopl   0x0(%rax)
L20:
  mov    $0x8,%edx
  mov    %r12,%rdi
  call   <strncat@plt>
  cmp    $0x7,%rbx
  je     L6
L27:
  add    $0x1,%rbx
L16:
  movzbl 0x0(%rbp,%rbx,1),%edi
  call   <translate_char_to_binary_string@plt>
  mov    %rax,%rsi
  test   %rbx,%rbx
  jne    L20
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L6:
  movb   $0x0,0x40(%r12)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char *generate_binary_key_string(unsigned char *key) {
  unsigned char *binary_key_string = (unsigned char *)malloc(8 * 8 * sizeof(char) + 1);
  unsigned char *binary_char_string;
  for (int i = 0; i < 8; i++) {
    binary_char_string = translate_char_to_binary_string(key[i]);
    if (i == 0) {
      strcpy((char *)binary_key_string, (char *)binary_char_string);
    } else {
      strncat((char *)binary_key_string, (char *)binary_char_string, 8);
    }
  }
  binary_key_string[64] = '\0';
  return binary_key_string;
}
```
user: What is the c source code of the assembly code below:

```asm
<cstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <getbyte@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <sbrk@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L12
  mov    $0x4,%edx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L12:
  movl   $0x1,-0x10(%rbp)
  jmp    L23
L15:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getbyte@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L15
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: OOM


assistant: ```c
char *cstr(uint16_t s) {
  char *st;
  int n, i;
  n = getbyte(s, 0);
  st = sbrk(n + 1);
  if (st == (char *)-1) {
    write(2, "OOM\n", 4);
    exit(1);
  }
  for (i = 1; i <= n; i++)
    st[i - 1] = getbyte(s, i);
  st[n] = 0;
  return st;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x0,%esi
  call   <getbyte@plt>
  mov    %rax,%r14
  mov    %eax,%r13d
  lea    0x1(%rax),%edi
  call   <sbrk@plt>
  mov    %rax,%rbp
  cmp    $0xffffffffffffffff,%rax
  je     L18
L15:
  test   %r14d,%r14d
  jle    L11
  mov    $0x1,%ebx
L23:
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <getbyte@plt>
  mov    %al,-0x1(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L23
L11:
  movslq %r14d,%r14
  movb   $0x0,0x0(%rbp,%r14,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    $0x4,%edx
  lea    D0(%rip),%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0: OOM


assistant: ```c
char *cstr(uint16_t s) {
  char *st;
  int n, i;
  n = getbyte(s, 0);
  st = sbrk(n + 1);
  if (st == (char *)-1) {
    write(2, "OOM\n", 4);
    exit(1);
  }
  for (i = 1; i <= n; i++)
    st[i - 1] = getbyte(s, i);
  st[n] = 0;
  return st;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cstr>:
  endbr64
  push   %r14
  xor    %esi,%esi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  call   <getbyte@plt>
  lea    0x1(%rax),%edi
  mov    %rax,%r14
  mov    %eax,%r13d
  call   <sbrk@plt>
  mov    %rax,%r12
  cmp    $0xffffffffffffffff,%rax
  je     L36
L24:
  test   %r14d,%r14d
  jle    L34
  mov    $0x1,%ebx
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <getbyte@plt>
  mov    %al,-0x1(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L5
L34:
  movslq %r14d,%r14
  mov    %r12,%rax
  movb   $0x0,(%r12,%r14,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    $0x4,%edx
  lea    D6(%rip),%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L24
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string

tool: D6: OOM


assistant: ```c
char *cstr(uint16_t s) {
  char *st;
  int n, i;
  n = getbyte(s, 0);
  st = sbrk(n + 1);
  if (st == (char *)-1) {
    write(2, "OOM\n", 4);
    exit(1);
  }
  for (i = 1; i <= n; i++)
    st[i - 1] = getbyte(s, i);
  st[n] = 0;
  return st;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cstr>:
  endbr64
  push   %r14
  xor    %esi,%esi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  call   <getbyte@plt>
  lea    0x1(%rax),%edi
  mov    %rax,%r14
  mov    %eax,%r13d
  call   <sbrk@plt>
  mov    %rax,%r12
  cmp    $0xffffffffffffffff,%rax
  je     L18
L9:
  test   %r14d,%r14d
  jle    L22
  mov    $0x1,%ebx
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <getbyte@plt>
  mov    %al,-0x1(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L7
L22:
  movslq %r14d,%r14
  mov    %r12,%rax
  movb   $0x0,(%r12,%r14,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x4,%edx
  lea    D2(%rip),%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: OOM


assistant: ```c
char *cstr(uint16_t s) {
  char *st;
  int n, i;
  n = getbyte(s, 0);
  st = sbrk(n + 1);
  if (st == (char *)-1) {
    write(2, "OOM\n", 4);
    exit(1);
  }
  for (i = 1; i <= n; i++)
    st[i - 1] = getbyte(s, i);
  st[n] = 0;
  return st;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x98(%rbp)
  movl   $0x0,-0x94(%rbp)
  lea    -0xac(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L60:
  lea    -0xa8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xa8(%rbp),%eax
  test   %eax,%eax
  js     L60
  mov    -0xa8(%rbp),%eax
  cmp    $0x1,%eax
  jg     L60
L37:
  lea    -0xa4(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xa4(%rbp),%eax
  test   %eax,%eax
  js     L37
  mov    -0xa4(%rbp),%eax
  cmp    $0x7,%eax
  jg     L37
  movl   $0x1f,-0xa0(%rbp)
  jmp    L81
L88:
  mov    -0xac(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0xa0(%rbp),%eax
  cltq
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0xac(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xac(%rbp)
  subl   $0x1,-0xa0(%rbp)
L81:
  cmpl   $0x0,-0xa0(%rbp)
  jns    L88
  mov    -0xa4(%rbp),%edx
  mov    $0x1f,%eax
  sub    %edx,%eax
  mov    -0xa8(%rbp),%edx
  cltq
  mov    %edx,-0x90(%rbp,%rax,4)
  movl   $0x1,-0x9c(%rbp)
  movl   $0x1f,-0xa0(%rbp)
  jmp    L7
L26:
  mov    -0xa0(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x9c(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  add    %eax,-0x98(%rbp)
  shll   -0x9c(%rbp)
  subl   $0x1,-0xa0(%rbp)
L7:
  cmpl   $0x0,-0xa0(%rbp)
  jns    L26
  mov    -0x98(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D23
datatype: string

tool: D23: %d

assistant: ```c
int main() {
  int n, v, p, i, a, b = 0, num = 0;
  int arr[31];
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v < 0 || v > 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  for (i = 31; i >= 0; i--) {
    arr[i] = n % 2;
    n = n / 2;
  }
  arr[31 - p] = v;
  a = 1;
  for (i = 31; i >= 0; i--) {
    num = arr[i] * a;
    b = num + b;
    a = a * 2;
  }
  printf("%d", b);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rbx
L25:
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x8(%rsp)
  ja     L25
  lea    D34(%rip),%rbx
L29:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  cmp    $0x7,%r9d
  ja     L29
  mov    0x4(%rsp),%eax
  lea    0x10(%rsp),%r8
  lea    0x8c(%rsp),%rcx
  mov    %rcx,%rsi
L6:
  mov    %eax,%edi
  shr    $0x1f,%edi
  lea    (%rax,%rdi,1),%edx
  and    $0x1,%edx
  sub    %edi,%edx
  mov    %edx,(%rsi)
  add    %edi,%eax
  sar    %eax
  mov    %rsi,%rdx
  sub    $0x4,%rsi
  cmp    %r8,%rdx
  jne    L6
  mov    %eax,0x4(%rsp)
  mov    $0x1f,%eax
  sub    %r9d,%eax
  cltq
  mov    0x8(%rsp),%edx
  mov    %edx,0x10(%rsp,%rax,4)
  mov    $0x0,%esi
  mov    $0x1,%eax
L42:
  mov    %eax,%edx
  imul   (%rcx),%edx
  add    %edx,%esi
  add    %eax,%eax
  mov    %rcx,%rdx
  sub    $0x4,%rcx
  cmp    %r8,%rdx
  jne    L42
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xa0,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D34
type_guessed: string

tool: D34: %d

assistant: ```c
int main() {
  int n, v, p, i, a, b = 0, num = 0;
  int arr[31];
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v < 0 || v > 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  for (i = 31; i >= 0; i--) {
    arr[i] = n % 2;
    n = n / 2;
  }
  arr[31 - p] = v;
  a = 1;
  for (i = 31; i >= 0; i--) {
    num = arr[i] * a;
    b = num + b;
    a = a * 2;
  }
  printf("%d", b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x8(%rsp),%rbx
  call   <scanf@plt>
  nopl   0x0(%rax)
L17:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x8(%rsp)
  ja     L17
  lea    0xc(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  cmp    $0x7,%r9d
  ja     L5
  lea    0x8c(%rsp),%rcx
  mov    0x4(%rsp),%eax
  lea    0x10(%rsp),%r8
  mov    %rcx,%rsi
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %eax,%edi
  shr    $0x1f,%edi
  lea    (%rax,%rdi,1),%edx
  add    %edi,%eax
  and    $0x1,%edx
  sar    %eax
  sub    %edi,%edx
  mov    %edx,(%rsi)
  mov    %rsi,%rdx
  sub    $0x4,%rsi
  cmp    %r8,%rdx
  jne    L43
  mov    %eax,0x4(%rsp)
  mov    $0x1f,%eax
  mov    0x8(%rsp),%edx
  xor    %esi,%esi
  sub    %r9d,%eax
  cltq
  mov    %edx,0x10(%rsp,%rax,4)
  mov    $0x1,%eax
  nopl   0x0(%rax)
L19:
  mov    (%rcx),%edx
  imul   %eax,%edx
  add    %eax,%eax
  add    %edx,%esi
  mov    %rcx,%rdx
  sub    $0x4,%rcx
  cmp    %r8,%rdx
  jne    L19
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: %d

assistant: ```c
int main() {
  int n, v, p, i, a, b = 0, num = 0;
  int arr[31];
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v < 0 || v > 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  for (i = 31; i >= 0; i--) {
    arr[i] = n % 2;
    n = n / 2;
  }
  arr[31 - p] = v;
  a = 1;
  for (i = 31; i >= 0; i--) {
    num = arr[i] * a;
    b = num + b;
    a = a * 2;
  }
  printf("%d", b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x8(%rsp),%rbx
  call   <scanf@plt>
  nopl   0x0(%rax)
L1:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x8(%rsp)
  ja     L1
  lea    0xc(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  cmp    $0x7,%r9d
  ja     L44
  lea    0x8c(%rsp),%rcx
  mov    0x4(%rsp),%eax
  lea    0x10(%rsp),%r8
  mov    %rcx,%rsi
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %eax,%edi
  shr    $0x1f,%edi
  lea    (%rax,%rdi,1),%edx
  add    %edi,%eax
  and    $0x1,%edx
  sar    %eax
  sub    %edi,%edx
  mov    %edx,(%rsi)
  mov    %rsi,%rdx
  sub    $0x4,%rsi
  cmp    %r8,%rdx
  jne    L38
  mov    %eax,0x4(%rsp)
  mov    $0x1f,%eax
  mov    0x8(%rsp),%edx
  xor    %esi,%esi
  sub    %r9d,%eax
  cltq
  mov    %edx,0x10(%rsp,%rax,4)
  mov    $0x1,%eax
  nopl   0x0(%rax)
L13:
  mov    (%rcx),%edx
  imul   %eax,%edx
  add    %eax,%eax
  add    %edx,%esi
  mov    %rcx,%rdx
  sub    $0x4,%rcx
  cmp    %r8,%rdx
  jne    L13
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: %d

assistant: ```c
int main() {
  int n, v, p, i, a, b = 0, num = 0;
  int arr[31];
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v < 0 || v > 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  for (i = 31; i >= 0; i--) {
    arr[i] = n % 2;
    n = n / 2;
  }
  arr[31 - p] = v;
  a = 1;
  for (i = 31; i >= 0; i--) {
    num = arr[i] * a;
    b = num + b;
    a = a * 2;
  }
  printf("%d", b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_IRQ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <local_irq_disable@plt>
  mov    $0x0,%eax
  call   <irq_enter@plt>
  mov    $0x0,%eax
  call   <get_cpu@plt>
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <rcu_check_callbacks@plt>
  mov    $0x0,%eax
  call   <local_irq_enable@plt>
  mov    $0x0,%eax
  call   <irq_exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void do_IRQ(void) {
  local_irq_disable();
  irq_enter();
  rcu_check_callbacks(get_cpu(), 0);
  local_irq_enable();
  irq_exit();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_IRQ>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <local_irq_disable@plt>
  mov    $0x0,%eax
  call   <irq_enter@plt>
  mov    $0x0,%eax
  call   <get_cpu@plt>
  mov    %eax,%edi
  mov    $0x0,%esi
  call   <rcu_check_callbacks@plt>
  mov    $0x0,%eax
  call   <local_irq_enable@plt>
  mov    $0x0,%eax
  call   <irq_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void do_IRQ(void) {
  local_irq_disable();
  irq_enter();
  rcu_check_callbacks(get_cpu(), 0);
  local_irq_enable();
  irq_exit();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_IRQ>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <local_irq_disable@plt>
  xor    %eax,%eax
  call   <irq_enter@plt>
  xor    %eax,%eax
  call   <get_cpu@plt>
  xor    %esi,%esi
  mov    %eax,%edi
  call   <rcu_check_callbacks@plt>
  xor    %eax,%eax
  call   <local_irq_enable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10f0 <irq_exit@plt>
```

assistant: ```c
void do_IRQ(void) {
  local_irq_disable();
  irq_enter();
  rcu_check_callbacks(get_cpu(), 0);
  local_irq_enable();
  irq_exit();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<do_IRQ>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <local_irq_disable@plt>
  xor    %eax,%eax
  call   <irq_enter@plt>
  xor    %eax,%eax
  call   <get_cpu@plt>
  xor    %esi,%esi
  mov    %eax,%edi
  call   <rcu_check_callbacks@plt>
  xor    %eax,%eax
  call   <local_irq_enable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10f0 <irq_exit@plt>
```

assistant: ```c
void do_IRQ(void) {
  local_irq_disable();
  irq_enter();
  rcu_check_callbacks(get_cpu(), 0);
  local_irq_enable();
  irq_exit();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write_routine>:
  endbr64
  push   %r12
  mov    D17(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax)
L16:
  mov    (%r12),%edx
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  movzbl (%rbx),%eax
  cmp    $0x71,%eax
  jne    L44
  cmpb   $0xa,0x1(%rbx)
  jne    L44
  cmpb   $0x0,0x2(%rbx)
  jne    L44
L59:
  mov    D8(%rip),%rax
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  mov    (%rax),%esi
  jmp    1090 <shutdown@plt>
  nopl   0x0(%rax)
L44:
  cmp    $0x51,%eax
  jne    L61
  cmpb   $0xa,0x1(%rbx)
  jne    L61
  cmpb   $0x0,0x2(%rbx)
  je     L59
  nopl   0x0(%rax)
L61:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  jmp    L16
```

assistant: ```c
void write_routine(int sock, char *buf) {
  while (1) {
    fgets(buf, 30, stdin);
    if (!strcmp(buf, "q\n") || !strcmp(buf, "Q\n")) {
      shutdown(sock, SHUT_WR);
      return;
    }
    write(sock, buf, strlen(buf));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_routine>:
  endbr64
  push   %r12
  mov    D18(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax)
L52:
  mov    (%r12),%edx
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  movzbl (%rbx),%eax
  cmp    $0x71,%eax
  jne    L66
  cmpb   $0xa,0x1(%rbx)
  jne    L66
  cmpb   $0x0,0x2(%rbx)
  jne    L66
L61:
  mov    D10(%rip),%rax
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  mov    (%rax),%esi
  jmp    1090 <shutdown@plt>
  nopl   0x0(%rax)
L66:
  cmp    $0x51,%eax
  jne    L45
  cmpb   $0xa,0x1(%rbx)
  jne    L45
  cmpb   $0x0,0x2(%rbx)
  je     L61
  nopl   0x0(%rax)
L45:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  jmp    L52
```

assistant: ```c
void write_routine(int sock, char *buf) {
  while (1) {
    fgets(buf, 30, stdin);
    if (!strcmp(buf, "q\n") || !strcmp(buf, "Q\n")) {
      shutdown(sock, SHUT_WR);
      return;
    }
    write(sock, buf, strlen(buf));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hnj_string_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L29:
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  and    $0xf0000000,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L5
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  xor    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  xor    %eax,-0x10(%rbp)
L5:
  addq   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hnj_string_hash(const char *s) {
  const char *p;
  unsigned int h = 0, g;
  for (p = s; *p != '\0'; p += 1) {
    h = (h << 4) + *p;
    if ((g = h & 0xf0000000)) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hnj_string_hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L10
  mov    $0x0,%eax
  jmp    L21
L2:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L29
L21:
  shl    $0x4,%eax
  movsbl %dl,%edx
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L2
  and    $0xfffffff,%eax
  shr    $0x18,%edx
  xor    %edx,%eax
  jmp    L2
L29:
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int hnj_string_hash(const char *s) {
  const char *p;
  unsigned int h = 0, g;
  for (p = s; *p != '\0'; p += 1) {
    h = (h << 4) + *p;
    if ((g = h & 0xf0000000)) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hnj_string_hash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L4
  nopl   (%rax)
L0:
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L11
  and    $0xfffffff,%eax
  shr    $0x18,%edx
  xor    %edx,%eax
L11:
  movsbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L0
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
unsigned int hnj_string_hash(const char *s) {
  const char *p;
  unsigned int h = 0, g;
  for (p = s; *p != '\0'; p += 1) {
    h = (h << 4) + *p;
    if ((g = h & 0xf0000000)) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hnj_string_hash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L14
  nopl   (%rax)
L0:
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L10
  and    $0xfffffff,%eax
  shr    $0x18,%edx
  xor    %edx,%eax
L10:
  movsbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L0
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
unsigned int hnj_string_hash(const char *s) {
  const char *p;
  unsigned int h = 0, g;
  for (p = s; *p != '\0'; p += 1) {
    h = (h << 4) + *p;
    if ((g = h & 0xf0000000)) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mangle_dupechar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L26
  mov    -0x1c(%rbp),%eax
  jmp    L33
L26:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    $0x3f,%eax
  jle    L28
  mov    -0x1c(%rbp),%eax
  jmp    L33
L28:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L37
L18:
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x8(%rbp)
L37:
  cmpl   $0x0,-0x8(%rbp)
  jns    L18
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int mangle_dupechar(char arr[64], int arr_len) {
  if (arr_len == 0)
    return (arr_len);
  if ((arr_len + arr_len) >= 64)
    return (arr_len);
  int arr_pos;
  for (arr_pos = arr_len - 1; arr_pos > -1; arr_pos--) {
    int new_pos = arr_pos * 2;
    arr[new_pos] = arr[arr_pos];
    arr[new_pos + 1] = arr[arr_pos];
  }
  return (arr_len * 2);
}
```