ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<round_function>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L7:
  mov    (%r12,%rbx,1),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,0x0(%rbp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  jne    L7
  mov    %rbp,%rdi
  call   <S_layer@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <P_layer@plt>
```

assistant: ```c
void round_function(uint16_t *data, uint16_t *rkey) {
  uint8_t i;
  for (i = 0; i < 4; i++)
    data[i] ^= READ_ROUND_KEY_WORD(rkey[i]);
  S_layer(data);
  P_layer(data);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<round_function>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L7:
  mov    (%r12,%rbx,1),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,0x0(%rbp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  jne    L7
  mov    %rbp,%rdi
  call   <S_layer@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <P_layer@plt>
```

assistant: ```c
void round_function(uint16_t *data, uint16_t *rkey) {
  uint8_t i;
  for (i = 0; i < 4; i++)
    data[i] ^= READ_ROUND_KEY_WORD(rkey[i]);
  S_layer(data);
  P_layer(data);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<starts_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L29
  mov    $0x0,%eax
  jmp    L23
L29:
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x1,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int starts_with(char *source, char *check) {
  int p = 0;
  for (; check[p] != 0; p++) {
    if (check[p] != source[p]) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<starts_with>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L2
  mov    $0x0,%eax
L15:
  cmp    %dl,(%rdi,%rax,1)
  jne    L9
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L15
  mov    $0x1,%eax
  ret
L2:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int starts_with(char *source, char *check) {
  int p = 0;
  for (; check[p] != 0; p++) {
    if (check[p] != source[p]) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<starts_with>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L31
  xor    %eax,%eax
  jmp    L4
  nop
L10:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L31
L4:
  cmp    %dl,(%rdi,%rax,1)
  je     L10
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L31:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int starts_with(char *source, char *check) {
  int p = 0;
  for (; check[p] != 0; p++) {
    if (check[p] != source[p]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<starts_with>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L10
  xor    %eax,%eax
  jmp    L37
  nop
L14:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L10
L37:
  cmp    %dl,(%rdi,%rax,1)
  je     L14
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int starts_with(char *source, char *check) {
  int p = 0;
  for (; check[p] != 0; p++) {
    if (check[p] != source[p]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L36
L35:
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  movq   $0x0,-0x10(%rbp)
  jmp    L3
L26:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L3:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L26
L24:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncat(char *d, const char *s, size_t n) {
  size_t i, e;
  for (e = 0; d[e] != '\0'; e++)
    ;
  for (i = 0; s[i] != '\0' && i < n; i++) {
    d[e + i] = s[i];
  }
  d[e + i] = '\0';
  return d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L30
  mov    $0x0,%r8d
L14:
  add    $0x1,%r8
  cmpb   $0x0,(%rax,%r8,1)
  jne    L14
L9:
  movzbl (%rsi),%r9d
  test   %rdx,%rdx
  je     L1
  test   %r9b,%r9b
  je     L1
  mov    $0x0,%ecx
  lea    (%rax,%r8,1),%rdi
L41:
  mov    %r9b,(%rdi,%rcx,1)
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r9d
  cmp    %rcx,%rdx
  jbe    L18
  test   %r9b,%r9b
  jne    L41
L18:
  add    %rax,%rcx
  movb   $0x0,(%rcx,%r8,1)
  ret
L30:
  mov    $0x0,%r8d
  jmp    L9
L1:
  mov    $0x0,%ecx
  jmp    L18
```

assistant: ```c
char *strncat(char *d, const char *s, size_t n) {
  size_t i, e;
  for (e = 0; d[e] != '\0'; e++)
    ;
  for (i = 0; s[i] != '\0' && i < n; i++) {
    d[e + i] = s[i];
  }
  d[e + i] = '\0';
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L8
  xor    %r8d,%r8d
  nop
L10:
  add    $0x1,%r8
  cmpb   $0x0,(%rax,%r8,1)
  lea    (%rax,%r8,1),%rcx
  jne    L10
L55:
  movzbl (%rsi),%r9d
  test   %rdx,%rdx
  je     L45
  test   %r9b,%r9b
  je     L45
  xor    %ecx,%ecx
  lea    (%rax,%r8,1),%rdi
  jmp    L24
  nopl   (%rax)
L62:
  test   %r9b,%r9b
  je     L35
L24:
  mov    %r9b,(%rdi,%rcx,1)
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r9d
  cmp    %rcx,%rdx
  ja     L62
L35:
  add    %r8,%rcx
  add    %rax,%rcx
L45:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  jmp    L55
```

assistant: ```c
char *strncat(char *d, const char *s, size_t n) {
  size_t i, e;
  for (e = 0; d[e] != '\0'; e++)
    ;
  for (i = 0; s[i] != '\0' && i < n; i++) {
    d[e + i] = s[i];
  }
  d[e + i] = '\0';
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L45
  xor    %r8d,%r8d
  nop
L41:
  add    $0x1,%r8
  cmpb   $0x0,(%rax,%r8,1)
  lea    (%rax,%r8,1),%rcx
  jne    L41
L34:
  movzbl (%rsi),%r9d
  test   %rdx,%rdx
  je     L50
  test   %r9b,%r9b
  je     L50
  xor    %ecx,%ecx
  lea    (%rax,%r8,1),%rdi
  jmp    L56
  nopl   (%rax)
L70:
  test   %r9b,%r9b
  je     L35
L56:
  mov    %r9b,(%rdi,%rcx,1)
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r9d
  cmp    %rcx,%rdx
  ja     L70
L35:
  add    %r8,%rcx
  add    %rax,%rcx
L50:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax)
L45:
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  jmp    L34
```

assistant: ```c
char *strncat(char *d, const char *s, size_t n) {
  size_t i, e;
  for (e = 0; d[e] != '\0'; e++)
    ;
  for (i = 0; s[i] != '\0' && i < n; i++) {
    d[e + i] = s[i];
  }
  d[e + i] = '\0';
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x14,%edi
  call   <lcm@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  int temp = lcm(20);
  printf("%d\n", temp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main() {
  int temp = lcm(20);
  printf("%d\n", temp);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <lcm@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main() {
  int temp = lcm(20);
  printf("%d\n", temp);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <lcm@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  int temp = lcm(20);
  printf("%d\n", temp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L7:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <gets@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x9,-0x4(%rbp)
  jle    L7
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D26
type: string
name: parse_data
arguments: label: D10
type: string
name: parse_data
arguments: label: D29
type: string

tool: D26: input NO.:

tool: D10: %d

tool: D29: input name:

assistant: ```c
void input(int num[], char name[10][8]) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("input NO.:");
    scanf("%d", &num[i]);
    printf("input name:");
    getchar();
    gets(name[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<input>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x28(%rdi),%r12
  lea    D14(%rip),%r15
  lea    D28(%rip),%r14
  lea    D5(%rip),%r13
L4:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  add    $0x4,%rbx
  add    $0x8,%rbp
  cmp    %r12,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type: string
name: extract_symbolic_data
arguments: tag: D28
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D14: input NO.:

tool: D28: %d

tool: D5: input name:

assistant: ```c
void input(int num[], char name[10][8]) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("input NO.:");
    scanf("%d", &num[i]);
    printf("input name:");
    getchar();
    gets(name[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<input>:
  endbr64
  push   %r15
  lea    0x28(%rdi),%r15
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  lea    D28(%rip),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  add    $0x8,%rbp
  call   <gets@plt>
  cmp    %r15,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string

tool: D4: input NO.:

tool: D28: %d

tool: D7: input name:

assistant: ```c
void input(int num[], char name[10][8]) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("input NO.:");
    scanf("%d", &num[i]);
    printf("input name:");
    getchar();
    gets(name[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<input>:
  endbr64
  push   %r15
  lea    0x28(%rdi),%r15
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  add    $0x8,%rbp
  call   <gets@plt>
  cmp    %r15,%rbx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string
name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D2: input NO.:

tool: D20: %d

tool: D3: input name:

assistant: ```c
void input(int num[], char name[10][8]) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("input NO.:");
    scanf("%d", &num[i]);
    printf("input name:");
    getchar();
    gets(name[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L16
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L16
  cmpl   $0xa,-0x8(%rbp)
  jne    L4
L16:
  cmpl   $0xa,-0x8(%rbp)
  jne    L40
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L40:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getLine(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L48
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L33:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L6
  cmp    $0xa,%eax
  je     L6
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L33
  mov    %r12d,%ebx
  jmp    L57
L48:
  mov    $0x0,%ebx
L6:
  cmp    $0xa,%eax
  je     L15
L57:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  add    $0x1,%ebx
  jmp    L57
```

assistant: ```c
int getLine(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getLine>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L24
  mov    D7(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L59:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L34
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L11
  mov    %edx,%r14d
L56:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L59
  cmp    $0xa,%eax
  je     L25
L24:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  lea    0x1(%r14),%edx
L34:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getLine(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getLine>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L28
  mov    D9(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L57:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L59
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L25
  mov    %edx,%r14d
L50:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L57
  cmp    $0xa,%eax
  je     L47
L28:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  lea    0x1(%r14),%edx
L59:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L25:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getLine(char s[], int lim) {
  int c, i;
  for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n') {
    s[i] = c;
    ++i;
  }
  s[i] = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_quaddobl_target_Laurent_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x301,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_quaddobl_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(769, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_quaddobl_target_Laurent_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x301,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int read_quaddobl_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(769, a, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_quaddobl_target_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x301,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int read_quaddobl_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(769, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_quaddobl_target_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x301,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int read_quaddobl_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(769, a, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<birthdayGift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L24:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L24
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  movsd  D26(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: f64
name: read_data
arguments: tag: D11
type_guessed: string

tool: D23: %d

tool: D26: 2

tool: D11: %.1f

assistant: ```c
int birthdayGift(void) {
  int numSteps;
  scanf("%d", &numSteps);
  int sum = 0;
  while (numSteps--) {
    int input;
    scanf("%d", &input);
    sum += input;
  }
  printf("%.1f", sum / 2.0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<birthdayGift>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  lea    -0x1(%rbx),%eax
  mov    %eax,(%rsp)
  test   %ebx,%ebx
  je     L19
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
L15:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebx
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L15
L19:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D7(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type: string
name: read_data
arguments: data_label: D7
type: byte[8]
name: read_data
arguments: data_label: D11
type: string

tool: D3: %d

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D11: %.1f

assistant: ```c
int birthdayGift(void) {
  int numSteps;
  scanf("%d", &numSteps);
  int sum = 0;
  while (numSteps--) {
    int input;
    scanf("%d", &input);
    sum += input;
  }
  printf("%.1f", sum / 2.0);
  return 0;
}
```