ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<put_char>:
  endbr64
  cmp    $0x4f,%esi
  ja     L15
  cmp    $0x17,%edx
  jbe    L12
L15:
  ret
L12:
  lea    (%rdx,%rdx,4),%eax
  shl    $0x4,%eax
  add    %esi,%eax
  cltq
  mov    %dil,(%rcx,%rax,1)
  jmp    L15
```

assistant: ```c
void put_char(char c, int x, int y, char *buffer) {
  if (x >= 0 && x < 80 && y >= 0 && y < 24)
    buffer[x + y * 80] = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<put_char>:
  endbr64
  cmp    $0x4f,%esi
  ja     L7
  cmp    $0x17,%edx
  jbe    L15
L7:
  ret
  nop
L15:
  lea    (%rdx,%rdx,4),%eax
  shl    $0x4,%eax
  add    %esi,%eax
  cltq
  mov    %dil,(%rcx,%rax,1)
  ret
```

assistant: ```c
void put_char(char c, int x, int y, char *buffer) {
  if (x >= 0 && x < 80 && y >= 0 && y < 24)
    buffer[x + y * 80] = c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<put_char>:
  endbr64
  cmp    $0x4f,%esi
  ja     L16
  cmp    $0x17,%edx
  jbe    L13
L16:
  ret
  nop
L13:
  lea    (%rdx,%rdx,4),%eax
  shl    $0x4,%eax
  add    %esi,%eax
  cltq
  mov    %dil,(%rcx,%rax,1)
  ret
```

assistant: ```c
void put_char(char c, int x, int y, char *buffer) {
  if (x >= 0 && x < 80 && y >= 0 && y < 24)
    buffer[x + y * 80] = c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<start3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L6:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L6
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <main@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0xc,%eax
  int    $0x30
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int start3(int argc, char **argv) {
  unsigned long long *origin, *target;
  int i;
  for (i = 0; i < argc; i++) {
    origin = ((unsigned long long *)argv) + ((i * 2) + 1);
    target = ((unsigned long long *)argv) + i;
    *target = *origin;
  }
  i = main(argc, argv);
  asm volatile("int $0x30" ::"a"(12));
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<start3>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L13
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r8
  mov    %rsi,%rax
  mov    %rsi,%rcx
  neg    %rcx
L6:
  mov    0x8(%rcx,%rax,2),%rdx
  mov    %rdx,(%rax)
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L6
L13:
  mov    $0x0,%eax
  call   <main@plt>
  mov    %eax,%edx
  mov    $0xc,%eax
  int    $0x30
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int start3(int argc, char **argv) {
  unsigned long long *origin, *target;
  int i;
  for (i = 0; i < argc; i++) {
    origin = ((unsigned long long *)argv) + ((i * 2) + 1);
    target = ((unsigned long long *)argv) + i;
    *target = *origin;
  }
  i = main(argc, argv);
  asm volatile("int $0x30" ::"a"(12));
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<start3>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L3
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rcx
  lea    0x8(%rsi,%rax,8),%r8
  neg    %rcx
  mov    %rsi,%rax
  nopl   (%rax)
L16:
  mov    0x8(%rcx,%rax,2),%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %r8,%rax
  jne    L16
L3:
  xor    %eax,%eax
  call   <main@plt>
  mov    %eax,%r8d
  mov    $0xc,%eax
  int    $0x30
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int start3(int argc, char **argv) {
  unsigned long long *origin, *target;
  int i;
  for (i = 0; i < argc; i++) {
    origin = ((unsigned long long *)argv) + ((i * 2) + 1);
    target = ((unsigned long long *)argv) + i;
    *target = *origin;
  }
  i = main(argc, argv);
  asm volatile("int $0x30" ::"a"(12));
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<start3>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L62
  movslq %edi,%rax
  lea    -0x1(%rdi),%edx
  lea    (%rsi,%rax,8),%rcx
  lea    0x8(%rsi),%rax
  cmp    %rcx,%rax
  jb     L61
  cmp    $0x3,%edx
  jbe    L61
  mov    %edx,%ecx
  xor    %eax,%eax
  shr    %ecx
  shl    $0x4,%rcx
  xchg   %ax,%ax
L14:
  movdqu 0x8(%rsi,%rax,2),%xmm0
  movdqu 0x18(%rsi,%rax,2),%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L14
  and    $0xfffffffe,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  cltq
  lea    0x0(,%rcx,8),%r9
  mov    0x8(%rsi,%rax,8),%r8
  mov    %r8,(%rsi,%rcx,8)
  cmp    %edx,%edi
  jle    L62
  mov    0x18(%rsi,%rax,8),%rax
  mov    %rax,0x8(%rsi,%r9,1)
L62:
  xor    %eax,%eax
  call   <main@plt>
  mov    %eax,%r8d
  mov    $0xc,%eax
  int    $0x30
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  mov    %rsi,%rcx
  lea    (%rax,%rdx,8),%r8
  mov    %rsi,%rax
  neg    %rcx
  nopl   (%rax)
L59:
  mov    0x8(%rcx,%rax,2),%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%r8
  jne    L59
  jmp    L62
```

assistant: ```c
int start3(int argc, char **argv) {
  unsigned long long *origin, *target;
  int i;
  for (i = 0; i < argc; i++) {
    origin = ((unsigned long long *)argv) + ((i * 2) + 1);
    target = ((unsigned long long *)argv) + i;
    *target = *origin;
  }
  i = main(argc, argv);
  asm volatile("int $0x30" ::"a"(12));
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  mov    -0x4(%rbp),%eax
  mov    %eax,D9(%rip)
  jmp    L3
L15:
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,D0(%rip)
L3:
  mov    D0(%rip),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test1(int x) {
  static int thestatic;
  if (x < 0)
    thestatic = x;
  else
    thestatic = -x;
  return thestatic + x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test1>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  neg    %eax
  mov    %eax,D5(%rip)
  add    %edi,%eax
  ret
```

assistant: ```c
int test1(int x) {
  static int thestatic;
  if (x < 0)
    thestatic = x;
  else
    thestatic = -x;
  return thestatic + x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test1>:
  endbr64
  test   %edi,%edi
  js     L4
  neg    %edi
  xor    %eax,%eax
  mov    %edi,D4(%rip)
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %edi,D8(%rip)
  lea    (%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int test1(int x) {
  static int thestatic;
  if (x < 0)
    thestatic = x;
  else
    thestatic = -x;
  return thestatic + x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test1>:
  endbr64
  test   %edi,%edi
  js     L8
  neg    %edi
  xor    %eax,%eax
  mov    %edi,D0(%rip)
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %edi,D5(%rip)
  lea    (%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int test1(int x) {
  static int thestatic;
  if (x < 0)
    thestatic = x;
  else
    thestatic = -x;
  return thestatic + x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mybasename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L17
L5:
  mov    -0x18(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
char *mybasename(char *path) {
  char *s;
  if ((s = strrchr(path, '/')) != 0) {
    return (s + 1);
  }
  return (path);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mybasename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *mybasename(char *path) {
  char *s;
  if ((s = strrchr(path, '/')) != 0) {
    return (s + 1);
  }
  return (path);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mybasename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *mybasename(char *path) {
  char *s;
  if ((s = strrchr(path, '/')) != 0) {
    return (s + 1);
  }
  return (path);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mybasename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *mybasename(char *path) {
  char *s;
  if ((s = strrchr(path, '/')) != 0) {
    return (s + 1);
  }
  return (path);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0xb,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x16,-0x14(%rbp)
  movl   $0x3,-0x10(%rbp)
  movl   $0x21,-0xc(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L25
L2:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <print_big@plt>
  addl   $0x1,-0x24(%rbp)
L25:
  cmpl   $0x5,-0x24(%rbp)
  jle    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  int array[] = {1, 11, 2, 22, 3, 33};
  int i;
  for (i = 0; i < 6; i++) {
    print_big(array[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0xb,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x16,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x21,0x14(%rsp)
  mov    %rsp,%rbx
  lea    0x18(%rsp),%rbp
L4:
  mov    (%rbx),%edi
  call   <print_big@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L4
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[] = {1, 11, 2, 22, 3, 33};
  int i;
  for (i = 0; i < 6; i++) {
    print_big(array[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%rbp
  movabs $0x1600000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x2100000003,%rax
  movl   $0xb,0x4(%rsp)
  mov    %rax,0x10(%rsp)
  jmp    L0
  nop
L28:
  mov    (%rbx),%edi
L0:
  call   <print_big@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L28
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[] = {1, 11, 2, 22, 3, 33};
  int i;
  for (i = 0; i < 6; i++) {
    print_big(array[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%rbp
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <print_big@plt>
  cmp    %rbx,%rbp
  jne    L1
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D3
data_type: byte[8]

tool: {"D19": [0x01,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x16,0x00,0x00,0x00]}

tool: {"D3": [0x03,0x00,0x00,0x00,0x21,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int array[] = {1, 11, 2, 22, 3, 33};
  int i;
  for (i = 0; i < 6; i++) {
    print_big(array[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  jmp    L22
L12:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L22:
  cmpl   $0x62,-0x24(%rbp)
  jle    L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: %d	%c


assistant: ```c
int main() {
  char a[20];
  for (int i = 0; i < 99; ++i) {
    i[a] = (char)i;
    printf("%d\t%c\n", i, i[a]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
L2:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x63,%ebx
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: %d	%c


assistant: ```c
int main() {
  char a[20];
  for (int i = 0; i < 99; ++i) {
    i[a] = (char)i;
    printf("%d\t%c\n", i, i[a]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x63,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type: string

tool: D7: %d	%c


assistant: ```c
int main() {
  char a[20];
  for (int i = 0; i < 99; ++i) {
    i[a] = (char)i;
    printf("%d\t%c\n", i, i[a]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x63,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: %d	%c


assistant: ```c
int main() {
  char a[20];
  for (int i = 0; i < 99; ++i) {
    i[a] = (char)i;
    printf("%d\t%c\n", i, i[a]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
L12:
  movl   $0x0,-0x4(%rbp)
  jmp    L41
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L23
  mov    -0x18(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1,%ecx
  lock cmpxchg %ecx,(%rdx)
  sete   %al
  test   %al,%al
  jne    L13
L23:
  addl   $0x1,-0x4(%rbp)
L41:
  cmpl   $0x270f,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  call   <sched_yield@plt>
  jmp    L12
L13:
  nop
  leave
  ret
```

assistant: ```c
void _lock(unsigned int *lock) {
  while (1) {
    int i;
    for (i = 0; i < 10000; i++) {
      __asm__ __volatile__("" ::: "memory");
      if (*lock == 0) {
        if (__sync_bool_compare_and_swap(lock, 0, 1)) {
          return;
        }
      }
    }
    sched_yield();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_lock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%r12d
  mov    $0x1,%ebp
L25:
  mov    $0x2710,%edx
L4:
  cmpl   $0x0,(%rbx)
  jne    L10
  mov    %r12d,%eax
  lock cmpxchg %ebp,(%rbx)
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  sub    $0x1,%edx
  jne    L4
  mov    $0x0,%eax
  call   <sched_yield@plt>
  jmp    L25
```

assistant: ```c
void _lock(unsigned int *lock) {
  while (1) {
    int i;
    for (i = 0; i < 10000; i++) {
      __asm__ __volatile__("" ::: "memory");
      if (*lock == 0) {
        if (__sync_bool_compare_and_swap(lock, 0, 1)) {
          return;
        }
      }
    }
    sched_yield();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_lock>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
L13:
  mov    $0x2710,%edx
L28:
  mov    (%rdi),%eax
  test   %eax,%eax
  jne    L1
  mov    %ebp,%eax
  lock cmpxchg %ebx,(%rdi)
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  sub    $0x1,%edx
  jne    L28
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  call   <sched_yield@plt>
  mov    0x8(%rsp),%rdi
  jmp    L13
```

assistant: ```c
void _lock(unsigned int *lock) {
  while (1) {
    int i;
    for (i = 0; i < 10000; i++) {
      __asm__ __volatile__("" ::: "memory");
      if (*lock == 0) {
        if (__sync_bool_compare_and_swap(lock, 0, 1)) {
          return;
        }
      }
    }
    sched_yield();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_lock>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
L19:
  mov    $0x2710,%edx
L5:
  mov    (%rdi),%eax
  test   %eax,%eax
  jne    L6
  mov    %ebp,%eax
  lock cmpxchg %ebx,(%rdi)
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  sub    $0x1,%edx
  jne    L5
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  call   <sched_yield@plt>
  mov    0x8(%rsp),%rdi
  jmp    L19
```

assistant: ```c
void _lock(unsigned int *lock) {
  while (1) {
    int i;
    for (i = 0; i < 10000; i++) {
      __asm__ __volatile__("" ::: "memory");
      if (*lock == 0) {
        if (__sync_bool_compare_and_swap(lock, 0, 1)) {
          return;
        }
      }
    }
    sched_yield();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isunsignedfloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L115
  addl   $0x1,-0x4(%rbp)
  jmp    L115
L28:
  addl   $0x1,-0x4(%rbp)
L115:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L108
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L28
L108:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    $0x1,%eax
  jmp    L82
L27:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L45
  addl   $0x1,-0x4(%rbp)
  jmp    L45
L89:
  addl   $0x1,-0x4(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L89
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    $0x1,%eax
  jmp    L82
L20:
  mov    $0x0,%eax
L82:
  pop    %rbp
  ret
```

assistant: ```c
int isunsignedfloat(char *str) {
  int i = 0;
  if (str[i] == '+')
    i++;
  while (str[i] >= '0' && str[i] <= '9')
    i++;
  if (!str[i])
    return 1;
  if (str[i] == '.')
    i++;
  while (str[i] >= '0' && str[i] <= '9')
    i++;
  if (!str[i])
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isunsignedfloat>:
  endbr64
  cmpb   $0x2b,(%rdi)
  sete   %sil
  movzbl %sil,%esi
  sete   %al
  movzbl %al,%eax
  movzbl (%rdi,%rax,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L47
  add    $0x1,%esi
  movslq %esi,%rax
L41:
  mov    %eax,%esi
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L41
L47:
  mov    $0x1,%eax
  test   %dl,%dl
  je     L14
  cmp    $0x2e,%dl
  sete   %al
  movzbl %al,%eax
  add    %eax,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%edx
  lea    -0x30(%rdx),%ecx
  lea    0x1(%rdi,%rsi,1),%rax
  cmp    $0x9,%cl
  ja     L31
L11:
  movzbl (%rax),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L11
L31:
  test   %dl,%dl
  sete   %al
  movzbl %al,%eax
L14:
  ret
```

assistant: ```c
int isunsignedfloat(char *str) {
  int i = 0;
  if (str[i] == '+')
    i++;
  while (str[i] >= '0' && str[i] <= '9')
    i++;
  if (!str[i])
    return 1;
  if (str[i] == '.')
    i++;
  while (str[i] >= '0' && str[i] <= '9')
    i++;
  if (!str[i])
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isunsignedfloat>:
  endbr64
  xor    %esi,%esi
  cmpb   $0x2b,(%rdi)
  sete   %al
  sete   %sil
  movzbl %al,%eax
  movzbl (%rdi,%rax,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L35
  add    $0x1,%esi
  movslq %esi,%rax
  nopl   0x0(%rax)
L36:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L36
L35:
  mov    $0x1,%eax
  test   %dl,%dl
  je     L38
  xor    %eax,%eax
  cmp    $0x2e,%dl
  sete   %al
  add    %eax,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%edx
  lea    0x1(%rdi,%rsi,1),%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L2
  nopl   0x0(%rax)
L29:
  movzbl (%rax),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L29
L2:
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
L38:
  ret
```

assistant: ```c
int isunsignedfloat(char *str) {
  int i = 0;
  if (str[i] == '+')
    i++;
  while (str[i] >= '0' && str[i] <= '9')
    i++;
  if (!str[i])
    return 1;
  if (str[i] == '.')
    i++;
  while (str[i] >= '0' && str[i] <= '9')
    i++;
  if (!str[i])
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isunsignedfloat>:
  endbr64
  xor    %esi,%esi
  cmpb   $0x2b,(%rdi)
  sete   %al
  sete   %sil
  movzbl %al,%eax
  movzbl (%rdi,%rax,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L11
  add    $0x1,%esi
  movslq %esi,%rax
  nopl   0x0(%rax)
L58:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L58
L11:
  mov    $0x1,%eax
  test   %dl,%dl
  je     L62
  cmp    $0x2e,%dl
  je     L65
L56:
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
L62:
  ret
L65:
  add    $0x1,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L56
  lea    0x1(%rdi,%rsi,1),%rax
  cs nopw 0x0(%rax,%rax,1)
L38:
  movzbl (%rax),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L38
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  jmp    L62
```

assistant: ```c
int isunsignedfloat(char *str) {
  int i = 0;
  if (str[i] == '+')
    i++;
  while (str[i] >= '0' && str[i] <= '9')
    i++;
  if (!str[i])
    return 1;
  if (str[i] == '.')
    i++;
  while (str[i] >= '0' && str[i] <= '9')
    i++;
  if (!str[i])
    return 1;
  return 0;
}
```