ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<fact>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L22
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  je     L2
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L16:
  imul   %eax,%edx
  sub    $0x1,%eax
  jne    L16
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  ret
  nopl   0x0(%rax)
L22:
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L2:
  movsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double fact(double x) {
  if (x < 0)
    return 0;
  else {
    int retval = 1;
    int i = (int)x;
    while (i != 0)
      retval *= i--;
    return retval;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<fact>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L24
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  je     L25
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L2:
  imul   %eax,%edx
  sub    $0x1,%eax
  jne    L2
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  ret
  nopl   0x0(%rax)
L24:
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L25:
  movsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double fact(double x) {
  if (x < 0)
    return 0;
  else {
    int retval = 1;
    int i = (int)x;
    while (i != 0)
      retval *= i--;
    return retval;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<DestroyVmStatStruct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int DestroyVmStatStruct(struct VmStatistics *pStruct) {
  int nStatus = -1;
  if (pStruct != NULL) {
    free(pStruct);
    pStruct = NULL;
    nStatus = 0;
  }
  return (nStatus);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DestroyVmStatStruct>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int DestroyVmStatStruct(struct VmStatistics *pStruct) {
  int nStatus = -1;
  if (pStruct != NULL) {
    free(pStruct);
    pStruct = NULL;
    nStatus = 0;
  }
  return (nStatus);
}
```
user: Translate the below assembly code into C programming language:

```asm
<DestroyVmStatStruct>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int DestroyVmStatStruct(struct VmStatistics *pStruct) {
  int nStatus = -1;
  if (pStruct != NULL) {
    free(pStruct);
    pStruct = NULL;
    nStatus = 0;
  }
  return (nStatus);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DestroyVmStatStruct>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int DestroyVmStatStruct(struct VmStatistics *pStruct) {
  int nStatus = -1;
  if (pStruct != NULL) {
    free(pStruct);
    pStruct = NULL;
    nStatus = 0;
  }
  return (nStatus);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<increment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  jmp    L13
L10:
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  test   %eax,%eax
  jg     L10
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  je     L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x0,%eax
  jmp    L31
L42:
  mov    -0x8(%rbp),%rax
  movb   $0x30,(%rax)
  subq   $0x1,-0x8(%rbp)
  jmp    L39
L31:
  pop    %rbp
  ret
```

assistant: ```c
int increment(char *a, int len, int d) {
  for (; len - d > 0; len--)
    a++;
  while (1) {
    if (*a != '9') {
      *a = *a + 1;
      return 0;
    } else {
      *a = '0';
      ;
      a--;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<increment>:
  endbr64
  mov    %esi,%eax
  sub    %edx,%eax
  test   %eax,%eax
  jle    L10
L38:
  sub    $0x1,%eax
  test   %eax,%eax
  jg     L38
  sub    $0x1,%esi
  sub    %edx,%esi
  mov    $0x0,%eax
  cmovs  %eax,%esi
  lea    0x1(%rsi),%eax
  add    %rax,%rdi
L10:
  movzbl (%rdi),%eax
  cmp    $0x39,%al
  jne    L12
L14:
  movb   $0x30,(%rdi)
  sub    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x39,%al
  je     L14
L12:
  add    $0x1,%eax
  mov    %al,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int increment(char *a, int len, int d) {
  for (; len - d > 0; len--)
    a++;
  while (1) {
    if (*a != '9') {
      *a = *a + 1;
      return 0;
    } else {
      *a = '0';
      ;
      a--;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<increment>:
  endbr64
  cmp    %edx,%esi
  jle    L28
  sub    $0x1,%esi
  mov    $0x0,%eax
  sub    %edx,%esi
  cmovs  %eax,%esi
  movslq %esi,%rsi
  lea    0x1(%rdi,%rsi,1),%rdi
  jmp    L28
  nop
L29:
  movb   $0x30,(%rdi)
  sub    $0x1,%rdi
L28:
  movzbl (%rdi),%eax
  cmp    $0x39,%al
  je     L29
  add    $0x1,%eax
  mov    %al,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int increment(char *a, int len, int d) {
  for (; len - d > 0; len--)
    a++;
  while (1) {
    if (*a != '9') {
      *a = *a + 1;
      return 0;
    } else {
      *a = '0';
      ;
      a--;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<increment>:
  endbr64
  cmp    %edx,%esi
  jle    L21
  sub    $0x1,%esi
  mov    $0x0,%eax
  sub    %edx,%esi
  cmovs  %eax,%esi
  movslq %esi,%rsi
  lea    0x1(%rdi,%rsi,1),%rdi
  jmp    L21
  nop
L8:
  movb   $0x30,(%rdi)
  sub    $0x1,%rdi
L21:
  movzbl (%rdi),%eax
  cmp    $0x39,%al
  je     L8
  add    $0x1,%eax
  mov    %al,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int increment(char *a, int len, int d) {
  for (; len - d > 0; len--)
    a++;
  while (1) {
    if (*a != '9') {
      *a = *a + 1;
      return 0;
    } else {
      *a = '0';
      ;
      a--;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fil_sreadU16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t fil_sreadU16(uint8_t *in) {
  uint16_t ret;
  ret = *((uint16_t *)in);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fil_sreadU16>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint16_t fil_sreadU16(uint8_t *in) {
  uint16_t ret;
  ret = *((uint16_t *)in);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fil_sreadU16>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint16_t fil_sreadU16(uint8_t *in) {
  uint16_t ret;
  ret = *((uint16_t *)in);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fil_sreadU16>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint16_t fil_sreadU16(uint8_t *in) {
  uint16_t ret;
  ret = *((uint16_t *)in);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L68
L23:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L77
L29:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L44:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L29
  addl   $0x1,-0xc(%rbp)
L77:
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jg     L44
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x3,-0x10(%rbp)
  jg     L72
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L72:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L21:
  addl   $0x1,-0x14(%rbp)
L68:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D22
type_guessed: string
name: parse_data
arguments: label: D6
type_guessed: string
name: parse_data
arguments: label: D25
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string

tool: D22: %d

tool: D6: Pop #%d: 

tool: D25: %d licks? Your goose is cooked!


tool: D19: A-one... A-two-HOO... A-%d.


assistant: ```c
int main() {
  int p;
  scanf("%d", &p);
  int t;
  for (t = 0; t < p; t++) {
    int r;
    scanf("%d", &r);
    int licks = 0;
    int factor;
    for (factor = 2; r > 1; factor++) {
      while (r % factor == 0) {
        r /= factor;
        licks++;
      }
    }
    printf("Pop #%d: ", t + 1);
    if (licks <= 3)
      printf("%d licks? Your goose is cooked!\n", licks);
    else
      printf("A-one... A-two-HOO... A-%d.\n", licks);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L12
  mov    $0x1,%r12d
  lea    D22(%rip),%r14
  mov    $0x1,%ebp
  lea    D2(%rip),%r13
  jmp    L24
L10:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  add    $0x1,%ebx
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L10
  mov    %ebp,%edi
L71:
  add    $0x1,%esi
  cmp    $0x1,%ecx
  jle    L23
L120:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L10
  jmp    L71
L23:
  test   %dil,%dil
  je     L65
  mov    %ecx,0x4(%rsp)
L65:
  mov    %r12d,%r15d
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jle    L17
  mov    %ebx,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  jmp    L129
L17:
  mov    %ebx,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
L129:
  add    $0x1,%r12d
  cmp    %r15d,(%rsp)
  jle    L12
L24:
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x0,%edi
  mov    $0x2,%esi
  mov    $0x0,%ebx
  cmp    $0x1,%ecx
  jg     L120
  mov    %r12d,%r15d
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L17
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D22
type_guessed: string
name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D37
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D22: %d

tool: D2: Pop #%d: 

tool: D37: A-one... A-two-HOO... A-%d.


tool: D10: %d licks? Your goose is cooked!


assistant: ```c
int main() {
  int p;
  scanf("%d", &p);
  int t;
  for (t = 0; t < p; t++) {
    int r;
    scanf("%d", &r);
    int licks = 0;
    int factor;
    for (factor = 2; r > 1; factor++) {
      while (r % factor == 0) {
        r /= factor;
        licks++;
      }
    }
    printf("Pop #%d: ", t + 1);
    if (licks <= 3)
      printf("%d licks? Your goose is cooked!\n", licks);
    else
      printf("A-one... A-two-HOO... A-%d.\n", licks);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D2(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r13
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L94
L53:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  xor    %r14d,%r14d
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x2,%esi
  cmp    $0x1,%ecx
  jle    L46
  nop
L5:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L90
  nopl   0x0(%rax)
L70:
  mov    %ecx,%eax
  add    $0x1,%r14d
  cltd
  idiv   %esi
  cltd
  mov    %eax,%ecx
  idiv   %esi
  test   %edx,%edx
  je     L70
  add    $0x1,%esi
  cmp    $0x1,%ecx
  jg     L5
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    %ecx,0x4(%rsp)
  call   <printf@plt>
  cmp    $0x3,%r14d
  jle    L4
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
L16:
  cmp    %ebx,(%rsp)
  jg     L53
L94:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L90:
  add    $0x1,%esi
  jmp    L5
L46:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L4:
  mov    %r14d,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string
name: retrieve_data
arguments: data_label: D10
type_guessed: string
name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D36
type_guessed: string

tool: D2: A-one... A-two-HOO... A-%d.


tool: D10: Pop #%d: 

tool: D9: %d

tool: D36: %d licks? Your goose is cooked!


assistant: ```c
int main() {
  int p;
  scanf("%d", &p);
  int t;
  for (t = 0; t < p; t++) {
    int r;
    scanf("%d", &r);
    int licks = 0;
    int factor;
    for (factor = 2; r > 1; factor++) {
      while (r % factor == 0) {
        r /= factor;
        licks++;
      }
    }
    printf("Pop #%d: ", t + 1);
    if (licks <= 3)
      printf("%d licks? Your goose is cooked!\n", licks);
    else
      printf("A-one... A-two-HOO... A-%d.\n", licks);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  lea    D19(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  lea    D34(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r13
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L78
L25:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  xor    %r14d,%r14d
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x2,%esi
  cmp    $0x1,%ecx
  jle    L99
  nop
L66:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L51
  nopl   0x0(%rax)
L47:
  mov    %ecx,%eax
  add    $0x1,%r14d
  cltd
  idiv   %esi
  cltd
  mov    %eax,%ecx
  idiv   %esi
  test   %edx,%edx
  je     L47
  add    $0x1,%esi
  cmp    $0x1,%ecx
  jg     L66
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    %ecx,0x4(%rsp)
  call   <printf@plt>
  cmp    $0x3,%r14d
  jle    L6
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
L16:
  cmp    %ebx,(%rsp)
  jg     L25
L78:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L51:
  add    $0x1,%esi
  jmp    L66
L99:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L6:
  mov    %r14d,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D34
type: string
name: retrieve_data
arguments: tag: D30
type: string

tool: D19: A-one... A-two-HOO... A-%d.


tool: D20: Pop #%d: 

tool: D34: %d

tool: D30: %d licks? Your goose is cooked!


assistant: ```c
int main() {
  int p;
  scanf("%d", &p);
  int t;
  for (t = 0; t < p; t++) {
    int r;
    scanf("%d", &r);
    int licks = 0;
    int factor;
    for (factor = 2; r > 1; factor++) {
      while (r % factor == 0) {
        r /= factor;
        licks++;
      }
    }
    printf("Pop #%d: ", t + 1);
    if (licks <= 3)
      printf("%d licks? Your goose is cooked!\n", licks);
    else
      printf("A-one... A-two-HOO... A-%d.\n", licks);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_to_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L72
L16:
  addl   $0x1,-0x14(%rbp)
L72:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    D41(%rip),%rax
  mov    D91(%rip),%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rcx,%rax,1),%rdx
  mov    D193(%rip),%rax
  cmp    %rax,%rdx
  jl     L47
  mov    D41(%rip),%rax
  mov    D91(%rip),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    D193(%rip),%rax
  add    $0x200,%rax
  mov    %rax,D97(%rip)
  mov    D97(%rip),%rdx
  mov    D91(%rip),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,D97(%rip)
  mov    D97(%rip),%rax
  test   %rax,%rax
  jne    L77
  mov    D91(%rip),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  jmp    L69
L77:
  mov    D97(%rip),%rax
  mov    %rax,D97(%rip)
  mov    D97(%rip),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,D97(%rip)
  mov    D97(%rip),%rax
  movb   $0x0,(%rax)
L47:
  mov    D97(%rip),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <is_in_list@plt>
  test   %rax,%rax
  je     L27
  mov    D97(%rip),%rax
  jmp    L69
L27:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  nop
L30:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    D97(%rip),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,D97(%rip)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    D97(%rip),%rax
  movb   $0x0,(%rax)
  mov    D97(%rip),%rax
L69:
  leave
  ret
```

assistant: ```c
const char *add_to_list(const char *name) {
  static long nba = 0;
  static char *p0 = NULL;
  static char *p1 = NULL;
  const char *p = name;
  int len = 1;
  while (*p++ != '\0') {
    len++;
  }
  if (p1 - p0 + len >= nba) {
    unsigned long diff = p1 - p0;
    nba += 512;
    if ((p1 = realloc(p0, nba)) == NULL) {
      return (realloc(p0, 0));
    }
    p0 = p1;
    p1 += diff;
    *p1 = '\0';
    if (0) {
      fprintf(stderr, "DEBUG: add_to_list(): Allocated %p for list.\n", p0);
    }
  }
  if (is_in_list(p0, name)) {
    return p0;
  }
  if (0) {
    fprintf(stderr, "DEBUG: add_to_list(): Adding `%s' to list at %p.\n", name, p1);
  }
  for (p = name; (*p1++ = *p++) != '\0';) {
    ;
  }
  *p1 = '\0';
  return p0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<add_to_list>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  je     L23
  lea    0x1(%rdi),%rdx
  mov    %rdx,%rax
  mov    $0x2,%ecx
  sub    %edx,%ecx
L61:
  lea    (%rcx,%rax,1),%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L61
L16:
  mov    D41(%rip),%rdi
  mov    D93(%rip),%rbp
  sub    %rdi,%rbp
  mov    D70(%rip),%rsi
  movslq %edx,%rdx
  add    %rbp,%rdx
  cmp    %rsi,%rdx
  jl     L27
  add    $0x200,%rsi
  mov    %rsi,D37(%rip)
  call   <realloc@plt>
  mov    %rax,D37(%rip)
  test   %rax,%rax
  je     L32
  mov    %rax,D37(%rip)
  add    %rbp,%rax
  mov    %rax,D37(%rip)
  movb   $0x0,(%rax)
L27:
  mov    %rbx,%rsi
  mov    D37(%rip),%rdi
  call   <is_in_list@plt>
  mov    %rax,%rdx
  mov    D37(%rip),%rax
  test   %rdx,%rdx
  jne    L37
L34:
  add    $0x1,%rbx
  mov    %rax,%rcx
  add    $0x1,%rax
  movzbl -0x1(%rbx),%edx
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  jne    L34
  mov    %rax,D37(%rip)
  movb   $0x0,(%rcx)
  movb   $0x0,0x1(%rcx)
  mov    D37(%rip),%rax
L86:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  mov    $0x1,%edx
  jmp    L16
L32:
  mov    $0x0,%esi
  mov    D37(%rip),%rdi
  call   <realloc@plt>
  jmp    L86
L37:
  mov    D37(%rip),%rax
  jmp    L86
```

assistant: ```c
const char *add_to_list(const char *name) {
  static long nba = 0;
  static char *p0 = NULL;
  static char *p1 = NULL;
  const char *p = name;
  int len = 1;
  while (*p++ != '\0') {
    len++;
  }
  if (p1 - p0 + len >= nba) {
    unsigned long diff = p1 - p0;
    nba += 512;
    if ((p1 = realloc(p0, nba)) == NULL) {
      return (realloc(p0, 0));
    }
    p0 = p1;
    p1 += diff;
    *p1 = '\0';
    if (0) {
      fprintf(stderr, "DEBUG: add_to_list(): Allocated %p for list.\n", p0);
    }
  }
  if (is_in_list(p0, name)) {
    return p0;
  }
  if (0) {
    fprintf(stderr, "DEBUG: add_to_list(): Adding `%s' to list at %p.\n", name, p1);
  }
  for (p = name; (*p1++ = *p++) != '\0';) {
    ;
  }
  *p1 = '\0';
  return p0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_to_list>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rbx
  je     L13
  mov    $0x2,%ecx
  mov    %rbx,%rax
  sub    %ebx,%ecx
  nopw   0x0(%rax,%rax,1)
L40:
  lea    (%rcx,%rax,1),%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L40
  movslq %edx,%rdx
L49:
  mov    D82(%rip),%rdi
  mov    D57(%rip),%r12
  mov    D49(%rip),%rsi
  sub    %rdi,%r12
  add    %r12,%rdx
  cmp    %rsi,%rdx
  jl     L22
  add    $0x200,%rsi
  mov    %rsi,D98(%rip)
  call   <realloc@plt>
  mov    %rax,D98(%rip)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L74
  add    %rax,%r12
  mov    %rax,D98(%rip)
  mov    %r12,D98(%rip)
  movb   $0x0,(%r12)
L22:
  mov    %rbp,%rsi
  call   <is_in_list@plt>
  mov    %rax,%r8
  mov    D98(%rip),%rax
  test   %r8,%r8
  je     L29
  jmp    L63
  nopl   0x0(%rax)
L59:
  add    $0x1,%rbx
L29:
  movzbl -0x1(%rbx),%edx
  mov    %rax,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  jne    L59
  mov    %rax,D98(%rip)
  movb   $0x0,0x1(%rcx)
L63:
  pop    %rbx
  mov    D98(%rip),%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L13:
  mov    $0x1,%edx
  jmp    L49
L74:
  mov    D98(%rip),%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  jmp    1070 <realloc@plt>
```

assistant: ```c
const char *add_to_list(const char *name) {
  static long nba = 0;
  static char *p0 = NULL;
  static char *p1 = NULL;
  const char *p = name;
  int len = 1;
  while (*p++ != '\0') {
    len++;
  }
  if (p1 - p0 + len >= nba) {
    unsigned long diff = p1 - p0;
    nba += 512;
    if ((p1 = realloc(p0, nba)) == NULL) {
      return (realloc(p0, 0));
    }
    p0 = p1;
    p1 += diff;
    *p1 = '\0';
    if (0) {
      fprintf(stderr, "DEBUG: add_to_list(): Allocated %p for list.\n", p0);
    }
  }
  if (is_in_list(p0, name)) {
    return p0;
  }
  if (0) {
    fprintf(stderr, "DEBUG: add_to_list(): Adding `%s' to list at %p.\n", name, p1);
  }
  for (p = name; (*p1++ = *p++) != '\0';) {
    ;
  }
  *p1 = '\0';
  return p0;
}
```