ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testbed_failfnc_int>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%ebp
  mov    (%rsi),%r12d
  mov    $0x40,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%ecx
  mov    %ebp,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string

tool: D4: LHS = %d, RHS = %d

assistant: ```c
char *testbed_failfnc_int(const void *vlhs, const void *vrhs) {
  const int lhs = *((const int *)vlhs);
  const int rhs = *((const int *)vrhs);
  char *result = calloc(1, 64);
  sprintf(result, "LHS = %d, RHS = %d", lhs, rhs);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<testbed_failfnc_int>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    (%rdi),%r13d
  mov    $0x1,%edi
  mov    (%rsi),%r14d
  mov    $0x40,%esi
  call   <calloc@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  lea    D1(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: LHS = %d, RHS = %d

assistant: ```c
char *testbed_failfnc_int(const void *vlhs, const void *vrhs) {
  const int lhs = *((const int *)vlhs);
  const int rhs = *((const int *)vrhs);
  char *result = calloc(1, 64);
  sprintf(result, "LHS = %d, RHS = %d", lhs, rhs);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<testbed_failfnc_int>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    (%rdi),%r13d
  mov    $0x1,%edi
  mov    (%rsi),%r14d
  mov    $0x40,%esi
  call   <calloc@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: LHS = %d, RHS = %d

assistant: ```c
char *testbed_failfnc_int(const void *vlhs, const void *vrhs) {
  const int lhs = *((const int *)vlhs);
  const int rhs = *((const int *)vrhs);
  char *result = calloc(1, 64);
  sprintf(result, "LHS = %d, RHS = %d", lhs, rhs);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2a,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i = 42;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 42;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 42;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 42;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<c_put_cmsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %edx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    %r9d,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <CMSG_FIRSTHDR@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x64(%rbp),%eax
  mov    %eax,%edi
  call   <CMSG_SPACE@plt>
  mov    -0x50(%rbp),%edx
  add    %edx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jg     L8
  mov    -0x58(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x58(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x64(%rbp),%eax
  mov    %eax,%edi
  call   <CMSG_LEN@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <CMSG_DATA@plt>
  mov    %eax,%ecx
  mov    -0x64(%rbp),%edx
  mov    -0x60(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <memcpy@plt>
  jmp    L26
L8:
  movl   $0x0,-0x34(%rbp)
L26:
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
uint64_t c_put_cmsg(void *buf, uint64_t buflen, uint64_t curlen, struct cmsghdr *cmsg, void *data, uint64_t datalen) {
  struct msghdr mhdr;
  struct cmsghdr *f, *p = 0;
  mhdr.msg_control = buf;
  mhdr.msg_controllen = buflen;
  mhdr.msg_flags = 0;
  f = CMSG_FIRSTHDR(&mhdr);
  p = ((struct cmsghdr *)(((char *)f) + curlen));
  uint64_t new_length = curlen + CMSG_SPACE(datalen);
  if (new_length <= buflen) {
    p->cmsg_level = cmsg->cmsg_level;
    p->cmsg_type = cmsg->cmsg_type;
    p->cmsg_len = CMSG_LEN(datalen);
    memcpy(CMSG_DATA(p), data, datalen);
  } else {
    new_length = 0;
  }
  return new_length;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<c_put_cmsg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    %r9d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x20(%rsp)
  mov    %esi,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x10(%rsp),%rdi
  call   <CMSG_FIRSTHDR@plt>
  mov    %rax,0x8(%rsp)
  mov    %r13d,%edi
  call   <CMSG_SPACE@plt>
  lea    (%rax,%rbx,1),%ebp
  cmp    %ebp,%r12d
  jge    L1
  mov    $0x0,%ebp
L5:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %ebp,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  movslq %ebx,%rbx
  add    0x8(%rsp),%rbx
  mov    0x8(%r14),%eax
  mov    %eax,0x8(%rbx)
  mov    0x4(%r14),%eax
  mov    %eax,0x4(%rbx)
  mov    %r13d,%edi
  call   <CMSG_LEN@plt>
  mov    %eax,(%rbx)
  mov    %rbx,%rdi
  call   <CMSG_DATA@plt>
  mov    %eax,%edi
  mov    %r13d,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  jmp    L5
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t c_put_cmsg(void *buf, uint64_t buflen, uint64_t curlen, struct cmsghdr *cmsg, void *data, uint64_t datalen) {
  struct msghdr mhdr;
  struct cmsghdr *f, *p = 0;
  mhdr.msg_control = buf;
  mhdr.msg_controllen = buflen;
  mhdr.msg_flags = 0;
  f = CMSG_FIRSTHDR(&mhdr);
  p = ((struct cmsghdr *)(((char *)f) + curlen));
  uint64_t new_length = curlen + CMSG_SPACE(datalen);
  if (new_length <= buflen) {
    p->cmsg_level = cmsg->cmsg_level;
    p->cmsg_type = cmsg->cmsg_type;
    p->cmsg_len = CMSG_LEN(datalen);
    memcpy(CMSG_DATA(p), data, datalen);
  } else {
    new_length = 0;
  }
  return new_length;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<c_put_cmsg>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x38,%rsp
  mov    %r8,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x20(%rsp)
  lea    0x10(%rsp),%rdi
  mov    %esi,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <CMSG_FIRSTHDR@plt>
  mov    %r13d,%edi
  mov    %rax,%rbp
  call   <CMSG_SPACE@plt>
  lea    (%rax,%r15,1),%r12d
  cmp    %r12d,%ebx
  jge    L11
  xor    %r12d,%r12d
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  movslq %r15d,%rax
  mov    %r13d,%edi
  add    %rax,%rbp
  mov    0x8(%r14),%eax
  mov    %eax,0x8(%rbp)
  mov    0x4(%r14),%eax
  mov    %eax,0x4(%rbp)
  call   <CMSG_LEN@plt>
  mov    %rbp,%rdi
  mov    %eax,0x0(%rbp)
  call   <CMSG_DATA@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13d,%edx
  mov    %eax,%edi
  call   <memcpy@plt>
  jmp    L0
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t c_put_cmsg(void *buf, uint64_t buflen, uint64_t curlen, struct cmsghdr *cmsg, void *data, uint64_t datalen) {
  struct msghdr mhdr;
  struct cmsghdr *f, *p = 0;
  mhdr.msg_control = buf;
  mhdr.msg_controllen = buflen;
  mhdr.msg_flags = 0;
  f = CMSG_FIRSTHDR(&mhdr);
  p = ((struct cmsghdr *)(((char *)f) + curlen));
  uint64_t new_length = curlen + CMSG_SPACE(datalen);
  if (new_length <= buflen) {
    p->cmsg_level = cmsg->cmsg_level;
    p->cmsg_type = cmsg->cmsg_type;
    p->cmsg_len = CMSG_LEN(datalen);
    memcpy(CMSG_DATA(p), data, datalen);
  } else {
    new_length = 0;
  }
  return new_length;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<c_put_cmsg>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x20(%rsp)
  lea    0x10(%rsp),%rdi
  mov    %esi,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <CMSG_FIRSTHDR@plt>
  mov    %r13d,%edi
  mov    %rax,0x8(%rsp)
  call   <CMSG_SPACE@plt>
  lea    (%rax,%rbx,1),%r12d
  cmp    %r12d,%r15d
  jge    L23
  xor    %r12d,%r12d
L5:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    0x8(%rsp),%r15
  movslq %ebx,%rax
  mov    %r13d,%edi
  add    %rax,%r15
  mov    0x4(%r14),%rax
  mov    %rax,0x4(%r15)
  call   <CMSG_LEN@plt>
  mov    %r15,%rdi
  mov    %eax,(%r15)
  call   <CMSG_DATA@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <memcpy@plt>
  jmp    L5
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t c_put_cmsg(void *buf, uint64_t buflen, uint64_t curlen, struct cmsghdr *cmsg, void *data, uint64_t datalen) {
  struct msghdr mhdr;
  struct cmsghdr *f, *p = 0;
  mhdr.msg_control = buf;
  mhdr.msg_controllen = buflen;
  mhdr.msg_flags = 0;
  f = CMSG_FIRSTHDR(&mhdr);
  p = ((struct cmsghdr *)(((char *)f) + curlen));
  uint64_t new_length = curlen + CMSG_SPACE(datalen);
  if (new_length <= buflen) {
    p->cmsg_level = cmsg->cmsg_level;
    p->cmsg_type = cmsg->cmsg_type;
    p->cmsg_len = CMSG_LEN(datalen);
    memcpy(CMSG_DATA(p), data, datalen);
  } else {
    new_length = 0;
  }
  return new_length;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jne    L52
  mov    -0x18(%rbp),%eax
  cmp    $0x2,%eax
  jne    L52
  mov    -0x14(%rbp),%eax
  cmp    $0x4,%eax
  jne    L52
  mov    -0x10(%rbp),%eax
  cmp    $0x5,%eax
  jne    L52
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L51
L52:
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jne    L49
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jne    L49
  mov    -0x1c(%rbp),%eax
  cmp    $0x3,%eax
  jne    L49
  mov    -0x18(%rbp),%eax
  cmp    $0x4,%eax
  jne    L49
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L51
L49:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L51:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D15
data_type: string
name: read_data
arguments: label: D16
data_type: string

tool: D21: flock_type=bsd


tool: D15: flock_type=linux


tool: D16: flock_type=unknown


assistant: ```c
int main(int argc, char **argv) {
  struct flock lock = {1, 2, 3, 4, 5};
  if (lock.l_start == 1 && lock.l_len == 2 && lock.l_type == 4 && lock.l_whence == 5) {
    printf("flock_type=bsd\n");
    return 0;
  }
  if (lock.l_type == 1 && lock.l_whence == 2 && lock.l_start == 3 && lock.l_len == 4) {
    printf("flock_type=linux\n");
    return 0;
  }
  printf("flock_type=unknown\n");
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: flock_type=unknown


assistant: ```c
int main(int argc, char **argv) {
  struct flock lock = {1, 2, 3, 4, 5};
  if (lock.l_start == 1 && lock.l_len == 2 && lock.l_type == 4 && lock.l_whence == 5) {
    printf("flock_type=bsd\n");
    return 0;
  }
  if (lock.l_type == 1 && lock.l_whence == 2 && lock.l_start == 3 && lock.l_len == 4) {
    printf("flock_type=linux\n");
    return 0;
  }
  printf("flock_type=unknown\n");
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string

tool: D7: flock_type=unknown


assistant: ```c
int main(int argc, char **argv) {
  struct flock lock = {1, 2, 3, 4, 5};
  if (lock.l_start == 1 && lock.l_len == 2 && lock.l_type == 4 && lock.l_whence == 5) {
    printf("flock_type=bsd\n");
    return 0;
  }
  if (lock.l_type == 1 && lock.l_whence == 2 && lock.l_start == 3 && lock.l_len == 4) {
    printf("flock_type=linux\n");
    return 0;
  }
  printf("flock_type=unknown\n");
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: D4: flock_type=unknown


assistant: ```c
int main(int argc, char **argv) {
  struct flock lock = {1, 2, 3, 4, 5};
  if (lock.l_start == 1 && lock.l_len == 2 && lock.l_type == 4 && lock.l_whence == 5) {
    printf("flock_type=bsd\n");
    return 0;
  }
  if (lock.l_type == 1 && lock.l_whence == 2 && lock.l_start == 3 && lock.l_len == 4) {
    printf("flock_type=linux\n");
    return 0;
  }
  printf("flock_type=unknown\n");
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0xf(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%esi
  cmp    $0x2a,%sil
  je     L67
  cmp    $0x2b,%sil
  je     L87
  cmp    $0x2d,%sil
  je     L89
  cmp    $0x2f,%sil
  jne    L21
  movss  0x14(%rsp),%xmm0
  ucomiss D23(%rip),%xmm0
  jp     L106
  je     L98
L106:
  movss  0x10(%rsp),%xmm2
  divss  %xmm0,%xmm2
  jmp    L65
L67:
  movss  0x10(%rsp),%xmm2
  mulss  0x14(%rsp),%xmm2
L65:
  movsbl %sil,%esi
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  lea    D59(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
L117:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L87:
  movss  0x10(%rsp),%xmm2
  addss  0x14(%rsp),%xmm2
  jmp    L65
L89:
  movss  0x10(%rsp),%xmm2
  subss  0x14(%rsp),%xmm2
  jmp    L65
L98:
  lea    D62(%rip),%rdi
  call   <puts@plt>
  jmp    L117
L21:
  lea    D49(%rip),%rdi
  call   <puts@plt>
  jmp    L117
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D8
datatype: string
name: disassemble_data
arguments: data_label: D0
datatype: string
name: disassemble_data
arguments: data_label: D23
datatype: byte[4]
name: disassemble_data
arguments: data_label: D59
datatype: string
name: disassemble_data
arguments: data_label: D62
datatype: string
name: disassemble_data
arguments: data_label: D49
datatype: string

tool: D29: Enter two numbers and operator in format

tool: D8:  num1 operator num2

tool: D0: %f %c %f

tool: {"D23": [0x00,0x00,0x00,0x00]}

tool: D59: %f %c %f = %f


tool: D62: Division by 0!

tool: D49: Invalid operator!

assistant: ```c
int main() {
  char op;
  float num1, num2, result;
  printf("Enter two numbers and operator in format\n");
  printf(" num1 operator num2\n");
  scanf("%f %c %f", &num1, &op, &num2);
  if (op == '*') {
    result = num1 * num2;
  } else if (op == '+') {
    result = num1 + num2;
  } else if (op == '-') {
    result = num1 - num2;
  } else if (op == '/') {
    if (num2) {
      result = num1 / num2;
    } else {
      printf("Division by 0!\n");
      return 0;
    }
  } else {
    printf("Invalid operator!\n");
    return 0;
  }
  printf("%f %c %f = %f\n", num1, op, num2, result);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D53(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0xf(%rsp),%rdx
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%esi
  cmp    $0x2a,%sil
  je     L70
  cmp    $0x2b,%sil
  je     L34
  cmp    $0x2d,%sil
  je     L118
  cmp    $0x2f,%sil
  jne    L49
  movss  0x14(%rsp),%xmm0
  ucomiss D10(%rip),%xmm0
  jp     L28
  je     L54
L28:
  movss  0x10(%rsp),%xmm2
  divss  %xmm0,%xmm2
  jmp    L106
L34:
  movss  0x10(%rsp),%xmm2
  addss  0x14(%rsp),%xmm2
L106:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D15(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd %xmm2,%xmm2
  cvtss2sd 0x14(%rsp),%xmm1
  call   <printf@plt>
L117:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L70:
  movss  0x10(%rsp),%xmm2
  mulss  0x14(%rsp),%xmm2
  jmp    L106
L49:
  lea    D50(%rip),%rdi
  call   <puts@plt>
  jmp    L117
L118:
  movss  0x10(%rsp),%xmm2
  subss  0x14(%rsp),%xmm2
  jmp    L106
L54:
  lea    D48(%rip),%rdi
  call   <puts@plt>
  jmp    L117
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D27
type: string
name: disassemble_data
arguments: tag: D53
type: string
name: disassemble_data
arguments: tag: D19
type: string
name: disassemble_data
arguments: tag: D10
type: byte[4]
name: disassemble_data
arguments: tag: D15
type: string
name: disassemble_data
arguments: tag: D50
type: string
name: disassemble_data
arguments: tag: D48
type: string

tool: D27: Enter two numbers and operator in format

tool: D53:  num1 operator num2

tool: D19: %f %c %f

tool: {"D10": [0x00,0x00,0x00,0x00]}

tool: D15: %f %c %f = %f


tool: D50: Invalid operator!

tool: D48: Division by 0!

assistant: ```c
int main() {
  char op;
  float num1, num2, result;
  printf("Enter two numbers and operator in format\n");
  printf(" num1 operator num2\n");
  scanf("%f %c %f", &num1, &op, &num2);
  if (op == '*') {
    result = num1 * num2;
  } else if (op == '+') {
    result = num1 + num2;
  } else if (op == '-') {
    result = num1 - num2;
  } else if (op == '/') {
    if (num2) {
      result = num1 / num2;
    } else {
      printf("Division by 0!\n");
      return 0;
    }
  } else {
    printf("Invalid operator!\n");
    return 0;
  }
  printf("%f %c %f = %f\n", num1, op, num2, result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D51(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0xf(%rsp),%rdx
  lea    D49(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%esi
  cmp    $0x2a,%sil
  je     L36
  cmp    $0x2b,%sil
  je     L10
  cmp    $0x2d,%sil
  je     L41
  cmp    $0x2f,%sil
  jne    L48
  movss  0x14(%rsp),%xmm0
  ucomiss D24(%rip),%xmm0
  jp     L73
  je     L88
L73:
  movss  0x10(%rsp),%xmm2
  divss  %xmm0,%xmm2
  jmp    L53
L10:
  movss  0x10(%rsp),%xmm2
  addss  0x14(%rsp),%xmm2
L53:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D39(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd %xmm2,%xmm2
  cvtss2sd 0x14(%rsp),%xmm1
  call   <printf@plt>
L84:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L36:
  movss  0x10(%rsp),%xmm2
  mulss  0x14(%rsp),%xmm2
  jmp    L53
L48:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  jmp    L84
L41:
  movss  0x10(%rsp),%xmm2
  subss  0x14(%rsp),%xmm2
  jmp    L53
L88:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L84
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D51
type: string
name: disassemble_data
arguments: data_label: D47
type: string
name: disassemble_data
arguments: data_label: D49
type: string
name: disassemble_data
arguments: data_label: D24
type: byte[4]
name: disassemble_data
arguments: data_label: D39
type: string
name: disassemble_data
arguments: data_label: D23
type: string
name: disassemble_data
arguments: data_label: D9
type: string

tool: D51: Enter two numbers and operator in format

tool: D47:  num1 operator num2

tool: D49: %f %c %f

tool: {"D24": [0x00,0x00,0x00,0x00]}

tool: D39: %f %c %f = %f


tool: D23: Invalid operator!

tool: D9: Division by 0!

assistant: ```c
int main() {
  char op;
  float num1, num2, result;
  printf("Enter two numbers and operator in format\n");
  printf(" num1 operator num2\n");
  scanf("%f %c %f", &num1, &op, &num2);
  if (op == '*') {
    result = num1 * num2;
  } else if (op == '+') {
    result = num1 + num2;
  } else if (op == '-') {
    result = num1 - num2;
  } else if (op == '/') {
    if (num2) {
      result = num1 / num2;
    } else {
      printf("Division by 0!\n");
      return 0;
    }
  } else {
    printf("Invalid operator!\n");
    return 0;
  }
  printf("%f %c %f = %f\n", num1, op, num2, result);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scpi_handle_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L13
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <scpi_handle_byte@plt>
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void scpi_handle_string(const char *str) {
  while (*str != 0) {
    scpi_handle_byte(*str);
    str++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scpi_handle_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L8
L12:
  movsbl %dil,%edi
  call   <scpi_handle_byte@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L12
L8:
  pop    %rbx
  ret
```

assistant: ```c
void scpi_handle_string(const char *str) {
  while (*str != 0) {
    scpi_handle_byte(*str);
    str++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scpi_handle_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L19:
  call   <scpi_handle_byte@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L19
L7:
  pop    %rbx
  ret
```

assistant: ```c
void scpi_handle_string(const char *str) {
  while (*str != 0) {
    scpi_handle_byte(*str);
    str++;
  }
}
```