ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<get_next_path>:
  endbr64
  movslq (%rdi),%rax
  mov    %rdi,%r9
  lea    (%rsi,%rax,1),%r10
  mov    %rax,%rcx
  movzbl (%r10),%r8d
  cmp    $0x2e,%r8b
  je     L112
L4:
  mov    %r8d,%edx
  cmp    $0xff,%ecx
  jle    L80
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L101:
  add    $0x1,%rax
  cmp    $0xff,%eax
  jg     L8
  movzbl (%rsi,%rax,1),%edx
L80:
  movslq %eax,%rdi
  cmp    $0x2f,%dl
  jne    L101
  movb   $0x0,(%rsi,%rdi,1)
  mov    %eax,(%r9)
L9:
  mov    %r10,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  test   %r8b,%r8b
  je     L19
  lea    0x1(%rcx),%eax
  cltq
  jmp    L27
  nopl   0x0(%rax)
L3:
  movzbl (%rsi,%rax,1),%r8d
  add    $0x1,%rax
L27:
  test   %r8b,%r8b
  jne    L3
  mov    %eax,(%r9)
  mov    %r10,%rax
  ret
  nopl   (%rax)
L112:
  movzbl 0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L74
  cmp    $0x2e,%dl
  jne    L4
  cmpb   $0x0,0x2(%rsi,%rax,1)
  jne    L4
  add    $0x2,%ecx
  mov    %ecx,(%rdi)
  jmp    L9
  nopl   0x0(%rax)
L19:
  xor    %r10d,%r10d
  mov    %r10,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L74:
  add    $0x1,%ecx
  mov    %r10,%rax
  mov    %ecx,(%rdi)
  ret
```

assistant: ```c
char *get_next_path(int *start, char *path) {
  int i = *start, j = i;
  if (path[i] == '.' && path[i + 1] == '\0') {
    *start = *start + 1;
    return &path[i];
  }
  if (path[i] == '.' && path[i + 1] == '.' && path[i + 2] == '\0') {
    *start = *start + 2;
    return &path[i];
  }
  for (; i < 256; i++) {
    if (path[i] == '/') {
      path[i] = '\0';
      *start = i;
      return &path[j];
    }
  }
  i = j;
  if (path[i] != '\0') {
    while (path[i++] != '\0')
      ;
    *start = i;
    return &path[j];
  }
  return ((void *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_next_path>:
  endbr64
  movslq (%rdi),%rax
  lea    (%rsi,%rax,1),%r8
  mov    %rax,%rcx
  movzbl (%r8),%r9d
  cmp    $0x2e,%r9b
  je     L81
  cmp    $0xff,%eax
  jg     L107
L108:
  mov    %r8,%rax
  mov    %ecx,%edx
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L20:
  add    $0x1,%edx
  add    $0x1,%rax
  cmp    $0x100,%edx
  je     L107
L41:
  cmpb   $0x2f,(%rax)
  jne    L20
  movb   $0x0,(%rax)
  mov    %edx,(%rdi)
L58:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L107:
  test   %r9b,%r9b
  je     L60
L55:
  lea    0x1(%rcx),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L63:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x2(%rsi,%rax,1)
  jne    L63
  mov    %edx,(%rdi)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L81:
  movzbl 0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L119
  cmp    $0x2e,%dl
  je     L17
L49:
  cmp    $0xff,%ecx
  jle    L108
  jmp    L55
L17:
  cmpb   $0x0,0x2(%rsi,%rax,1)
  jne    L49
  add    $0x2,%ecx
  mov    %ecx,(%rdi)
  jmp    L58
  xchg   %ax,%ax
L60:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L119:
  add    $0x1,%ecx
  mov    %r8,%rax
  mov    %ecx,(%rdi)
  ret
```

assistant: ```c
char *get_next_path(int *start, char *path) {
  int i = *start, j = i;
  if (path[i] == '.' && path[i + 1] == '\0') {
    *start = *start + 1;
    return &path[i];
  }
  if (path[i] == '.' && path[i + 1] == '.' && path[i + 2] == '\0') {
    *start = *start + 2;
    return &path[i];
  }
  for (; i < 256; i++) {
    if (path[i] == '/') {
      path[i] = '\0';
      *start = i;
      return &path[j];
    }
  }
  i = j;
  if (path[i] != '\0') {
    while (path[i++] != '\0')
      ;
    *start = i;
    return &path[j];
  }
  return ((void *)0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<displayBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x80000000,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x8(%rbp)
  jmp    L18
L48:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L36
  mov    $0x31,%eax
  jmp    L11
L36:
  mov    $0x30,%eax
L11:
  mov    %eax,%edi
  call   <putchar@plt>
  shll   -0x14(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L24
  mov    $0x20,%edi
  call   <putchar@plt>
L24:
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x20,-0x8(%rbp)
  jbe    L48
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: %7u = 

assistant: ```c
void displayBits(int value) {
  unsigned c, displayMask = 1 << 31;
  printf("%7u = ", value);
  for (c = 1; c <= 32; c++) {
    putchar(value & displayMask ? '1' : '0');
    value <<= 1;
    if (c % 8 == 0)
      putchar(' ');
  }
  putchar('\n');
}
```
user: What is the c source code of the assembly code below?

```asm
<displayBits>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  jmp    L33
L34:
  mov    $0x20,%edi
  call   <putchar@plt>
L11:
  add    $0x1,%ebx
  cmp    $0x21,%ebx
  je     L5
L33:
  mov    %ebp,%edi
  shr    $0x1f,%edi
  add    $0x30,%edi
  call   <putchar@plt>
  add    %ebp,%ebp
  test   $0x7,%bl
  jne    L11
  jmp    L34
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: %7u = 

assistant: ```c
void displayBits(int value) {
  unsigned c, displayMask = 1 << 31;
  printf("%7u = ", value);
  for (c = 1; c <= 32; c++) {
    putchar(value & displayMask ? '1' : '0');
    value <<= 1;
    if (c % 8 == 0)
      putchar(' ');
  }
  putchar('\n');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<displayBits>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D7(%rip),%rdi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  jmp    L31
  nopl   0x0(%rax)
L7:
  add    $0x1,%ebx
  cmp    $0x21,%ebx
  je     L5
L31:
  mov    %ebp,%edi
  add    %ebp,%ebp
  shr    $0x1f,%edi
  add    $0x30,%edi
  call   <putchar@plt>
  test   $0x7,%bl
  jne    L7
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x21,%ebx
  jne    L31
L5:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: %7u = 

assistant: ```c
void displayBits(int value) {
  unsigned c, displayMask = 1 << 31;
  printf("%7u = ", value);
  for (c = 1; c <= 32; c++) {
    putchar(value & displayMask ? '1' : '0');
    value <<= 1;
    if (c % 8 == 0)
      putchar(' ');
  }
  putchar('\n');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<displayBits>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D9(%rip),%rdi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  jmp    L10
  nopl   0x0(%rax)
L21:
  add    $0x1,%ebx
  cmp    $0x21,%ebx
  je     L24
L10:
  mov    %ebp,%edi
  add    %ebp,%ebp
  shr    $0x1f,%edi
  add    $0x30,%edi
  call   <putchar@plt>
  test   $0x7,%bl
  jne    L21
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x21,%ebx
  jne    L10
L24:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string

tool: D9: %7u = 

assistant: ```c
void displayBits(int value) {
  unsigned c, displayMask = 1 << 31;
  printf("%7u = ", value);
  for (c = 1; c <= 32; c++) {
    putchar(value & displayMask ? '1' : '0');
    value <<= 1;
    if (c % 8 == 0)
      putchar(' ');
  }
  putchar('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x6e6143202c415355,%rax
  movabs $0x78654d202c616461,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x726542202c6f6369,%rax
  movabs $0x7247202c6164756d,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x42202c6164616e65,%rax
  mov    %rax,0x20(%rsp)
  movl   $0x7a696c65,0x28(%rsp)
  movw   $0x65,0x2c(%rsp)
  mov    $0x170,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  lea    D1(%rip),%r15
  jmp    L73
L38:
  cmp    $0x2d,%ebx
  je     L47
L85:
  add    $0x1,%ebx
  movslq %ebx,%rax
  cmp    $0x2d,%rax
  ja     L79
L73:
  movslq %ebx,%rax
  cmpb   $0x2c,(%rsp,%rax,1)
  jne    L38
  lea    0x1(%rbx),%eax
  cltq
  cmpb   $0x20,(%rsp,%rax,1)
  jne    L38
L47:
  mov    %ebx,%edi
  sub    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  cmp    %r12d,%ebx
  jle    L78
  mov    %ebx,%edi
  mov    %r12d,%r8d
  lea    -0x1(%rbx),%ecx
  sub    %r12d,%ecx
  mov    $0x0,%eax
  movslq %r12d,%r12
  lea    (%rsp,%r12,1),%rsi
L66:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L66
  mov    %edi,%eax
  sub    %r8d,%eax
  mov    %ebx,%r12d
L44:
  cltq
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <printf@plt>
  movslq %r13d,%rax
  mov    %rbp,(%r14,%rax,8)
  add    $0x1,%ebx
  add    $0x2,%r12d
  add    $0x1,%r13d
  jmp    L85
L78:
  mov    $0x0,%eax
  jmp    L44
L79:
  mov    0x18(%r14),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  char countries[] = "USA, Canada, Mexico, Bermuda, Grenada, Belize";
  unsigned long elements = sizeof(countries);
  char **countriesSet = malloc(sizeof(char *) * elements);
  int i = 0;
  int j = 0;
  int countryIndex = 0;
  for (; i < elements; i++) {
    if ((countries[i] == ',' && countries[i + 1] == ' ') || i == elements - 1) {
      char *newCountry = malloc((i - j) * sizeof(char));
      int lettercount = 0;
      for (; j < i; j++) {
        newCountry[lettercount] = countries[j];
        lettercount++;
      }
      newCountry[lettercount] = '\0';
      printf("%s\n", newCountry);
      countriesSet[countryIndex] = newCountry;
      i = i + 1;
      j = j + 2;
      countryIndex++;
    }
  }
  printf("%s\n", countriesSet[3]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x170,%edi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x58,%rsp
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x7a696c65,0x38(%rsp)
  movabs $0x42202c6164616e65,%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D2(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  mov    $0x65,%eax
  mov    %ax,0x3c(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <malloc@plt>
  mov    $0x55,%edx
  mov    %rax,0x8(%rsp)
  jmp    L76
  nopl   0x0(%rax)
L25:
  cmp    $0x2d,%ebx
  je     L85
  cmp    $0x2d,%eax
  jg     L50
L5:
  movslq %eax,%rdx
  mov    %eax,%ebx
  movzbl 0x10(%rsp,%rdx,1),%edx
L76:
  lea    0x1(%rbx),%eax
  cmp    $0x2c,%dl
  jne    L25
  movslq %eax,%rdx
  cmpb   $0x20,0x10(%rsp,%rdx,1)
  jne    L25
L85:
  mov    %ebx,%r15d
  sub    %r14d,%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  cmp    %r14d,%ebx
  jle    L42
  lea    -0x1(%rbx),%edx
  mov    %rax,%rdi
  sub    %r14d,%edx
  movslq %r14d,%r14
  lea    0x10(%rsp,%r14,1),%rsi
  add    $0x1,%rdx
  mov    %ebx,%r14d
  call   <memcpy@plt>
L68:
  movslq %r15d,%r15
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x2,%r14d
  movb   $0x0,(%r12,%r15,1)
  call   <printf@plt>
  mov    0x8(%rsp),%rcx
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %r12,(%rcx,%rax,8)
  lea    0x2(%rbx),%eax
  cmp    $0x2d,%eax
  jle    L5
L50:
  mov    0x8(%rsp),%rax
  mov    %r13,%rdi
  mov    0x18(%rax),%rsi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  xor    %r15d,%r15d
  jmp    L68
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
data_type: string
name: disassemble_data
arguments: label: D13
data_type: byte[16]
name: disassemble_data
arguments: label: D2
data_type: byte[16]

tool: D15: %s


tool: {"D13": [0x55,0x53,0x41,0x2c,0x20,0x43,0x61,0x6e,0x61,0x64,0x61,0x2c,0x20,0x4d,0x65,0x78]}

tool: {"D2": [0x69,0x63,0x6f,0x2c,0x20,0x42,0x65,0x72,0x6d,0x75,0x64,0x61,0x2c,0x20,0x47,0x72]}

assistant: ```c
int main(int argc, const char *argv[]) {
  char countries[] = "USA, Canada, Mexico, Bermuda, Grenada, Belize";
  unsigned long elements = sizeof(countries);
  char **countriesSet = malloc(sizeof(char *) * elements);
  int i = 0;
  int j = 0;
  int countryIndex = 0;
  for (; i < elements; i++) {
    if ((countries[i] == ',' && countries[i + 1] == ' ') || i == elements - 1) {
      char *newCountry = malloc((i - j) * sizeof(char));
      int lettercount = 0;
      for (; j < i; j++) {
        newCountry[lettercount] = countries[j];
        lettercount++;
      }
      newCountry[lettercount] = '\0';
      printf("%s\n", newCountry);
      countriesSet[countryIndex] = newCountry;
      i = i + 1;
      j = j + 2;
      countryIndex++;
    }
  }
  printf("%s\n", countriesSet[3]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x170,%edi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x58,%rsp
  movdqa D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x7a696c65,0x38(%rsp)
  movabs $0x42202c6164616e65,%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D15(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  mov    $0x65,%eax
  mov    %ax,0x3c(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <malloc@plt>
  mov    $0x55,%edx
  mov    %rax,0x8(%rsp)
  jmp    L26
  nopl   0x0(%rax)
L42:
  cmp    $0x2d,%ebx
  je     L72
  cmp    $0x2d,%eax
  jg     L51
L28:
  movslq %eax,%rdx
  mov    %eax,%ebx
  movzbl 0x10(%rsp,%rdx,1),%edx
L26:
  lea    0x1(%rbx),%eax
  cmp    $0x2c,%dl
  jne    L42
  movslq %eax,%rdx
  cmpb   $0x20,0x10(%rsp,%rdx,1)
  jne    L42
L72:
  mov    %ebx,%r15d
  sub    %r14d,%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  cmp    %r14d,%ebx
  jle    L49
  lea    -0x1(%rbx),%edx
  mov    %rax,%rdi
  sub    %r14d,%edx
  movslq %r14d,%r14
  lea    0x10(%rsp,%r14,1),%rsi
  add    $0x1,%rdx
  mov    %ebx,%r14d
  call   <memcpy@plt>
L21:
  movslq %r15d,%r15
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x2,%r14d
  movb   $0x0,(%r12,%r15,1)
  call   <printf@plt>
  mov    0x8(%rsp),%rcx
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %r12,(%rcx,%rax,8)
  lea    0x2(%rbx),%eax
  cmp    $0x2d,%eax
  jle    L28
L51:
  mov    0x8(%rsp),%rax
  mov    %r13,%rdi
  mov    0x18(%rax),%rsi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  xor    %r15d,%r15d
  jmp    L21
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: byte[16]
name: retrieve_data
arguments: label: D15
type_guessed: byte[16]

tool: D21: %s


tool: {"D22": [0x55,0x53,0x41,0x2c,0x20,0x43,0x61,0x6e,0x61,0x64,0x61,0x2c,0x20,0x4d,0x65,0x78]}

tool: {"D15": [0x69,0x63,0x6f,0x2c,0x20,0x42,0x65,0x72,0x6d,0x75,0x64,0x61,0x2c,0x20,0x47,0x72]}

assistant: ```c
int main(int argc, const char *argv[]) {
  char countries[] = "USA, Canada, Mexico, Bermuda, Grenada, Belize";
  unsigned long elements = sizeof(countries);
  char **countriesSet = malloc(sizeof(char *) * elements);
  int i = 0;
  int j = 0;
  int countryIndex = 0;
  for (; i < elements; i++) {
    if ((countries[i] == ',' && countries[i + 1] == ' ') || i == elements - 1) {
      char *newCountry = malloc((i - j) * sizeof(char));
      int lettercount = 0;
      for (; j < i; j++) {
        newCountry[lettercount] = countries[j];
        lettercount++;
      }
      newCountry[lettercount] = '\0';
      printf("%s\n", newCountry);
      countriesSet[countryIndex] = newCountry;
      i = i + 1;
      j = j + 2;
      countryIndex++;
    }
  }
  printf("%s\n", countriesSet[3]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x20,-0x1(%rbp)
  je     L53
  mov    $0x0,%eax
  jmp    L43
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <g@plt>
  test   %rax,%rax
  je     L58
  addq   $0x1,-0x18(%rbp)
  jmp    L53
L58:
  cmpb   $0x20,-0x1(%rbp)
  je     L36
  mov    $0x0,%eax
  jmp    L43
L36:
  nop
  mov    $0x1,%eax
L43:
  leave
  ret
```

assistant: ```c
f(char *p) {
  char c;
  c = *++p;
  if (c != ' ')
    return 0;
  for (; 1;) {
    c = *p;
    if (g(c))
      p++;
    else {
      if (c == ' ')
        break;
      else
        return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x20,0x1(%rdi)
  jne    L11
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x1(%rdi),%rbx
  jmp    L29
L15:
  add    $0x1,%rbx
L29:
  movzbl (%rbx),%ebp
  movsbl %bpl,%edi
  call   <g@plt>
  test   %rax,%rax
  jne    L15
  cmp    $0x20,%bpl
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  ret
```

assistant: ```c
f(char *p) {
  char c;
  c = *++p;
  if (c != ' ')
    return 0;
  for (; 1;) {
    c = *p;
    if (g(c))
      p++;
    else {
      if (c == ' ')
        break;
      else
        return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  movzbl 0x1(%rdi),%ebp
  cmp    $0x20,%bpl
  jne    L4
  lea    0x1(%rdi),%rbx
  jmp    L15
  nopl   0x0(%rax)
L3:
  movzbl 0x1(%rbx),%ebp
  add    $0x1,%rbx
L15:
  movsbl %bpl,%edi
  call   <g@plt>
  test   %rax,%rax
  jne    L3
  xor    %eax,%eax
  cmp    $0x20,%bpl
  sete   %al
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
f(char *p) {
  char c;
  c = *++p;
  if (c != ' ')
    return 0;
  for (; 1;) {
    c = *p;
    if (g(c))
      p++;
    else {
      if (c == ' ')
        break;
      else
        return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  cmpb   $0x20,0x1(%rdi)
  jne    L18
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x1,%rbx
L8:
  movsbl (%rbx),%edi
  mov    %edi,%ebp
  call   <g@plt>
  test   %rax,%rax
  jne    L15
  xor    %eax,%eax
  cmp    $0x20,%bpl
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
f(char *p) {
  char c;
  c = *++p;
  if (c != ' ')
    return 0;
  for (; 1;) {
    c = *p;
    if (g(c))
      p++;
    else {
      if (c == ' ')
        break;
      else
        return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<parse_credentials>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L24
  mov    $0x0,%eax
  jmp    L40
L24:
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L43
  mov    $0x0,%eax
  jmp    L40
L43:
  cmpq   $0x0,-0x8(%rbp)
  je     L53
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strdupdelim@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <url_unescape@plt>
  jmp    L3
L53:
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strdupdelim@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <url_unescape@plt>
  mov    $0x1,%eax
L40:
  leave
  ret
```

assistant: ```c
int parse_credentials(const char *beg, const char *end, char **user, char **passwd) {
  char *colon;
  const char *userend;
  if (beg == end)
    return 0;
  colon = memchr(beg, ':', end - beg);
  if (colon == beg)
    return 0;
  if (colon) {
    *passwd = strdupdelim(colon + 1, end);
    userend = colon;
    url_unescape(*passwd);
  } else {
    *passwd = NULL;
    userend = end;
  }
  *user = strdupdelim(beg, userend);
  url_unescape(*user);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_credentials>:
  endbr64
  mov    $0x0,%eax
  cmp    %rsi,%rdi
  je     L15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %esi,%edx
  sub    %edi,%edx
  mov    $0x3a,%esi
  call   <memchr@plt>
  mov    %rax,%r12
  cmp    %rax,%rbx
  je     L29
  test   %rax,%rax
  je     L10
  lea    0x1(%rax),%rdi
  mov    %rbp,%rsi
  call   <strdupdelim@plt>
  mov    %rax,%rdi
  mov    %rax,(%r14)
  call   <url_unescape@plt>
L43:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strdupdelim@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%r13)
  call   <url_unescape@plt>
  mov    $0x1,%eax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  movq   $0x0,(%r14)
  mov    %rbp,%r12
  jmp    L43
L29:
  mov    $0x0,%eax
  jmp    L45
L15:
  ret
```

assistant: ```c
int parse_credentials(const char *beg, const char *end, char **user, char **passwd) {
  char *colon;
  const char *userend;
  if (beg == end)
    return 0;
  colon = memchr(beg, ':', end - beg);
  if (colon == beg)
    return 0;
  if (colon) {
    *passwd = strdupdelim(colon + 1, end);
    userend = colon;
    url_unescape(*passwd);
  } else {
    *passwd = NULL;
    userend = end;
  }
  *user = strdupdelim(beg, userend);
  url_unescape(*user);
  return 1;
}
```