user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x190,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L92
  addl   $0x190,-0x14(%rbp)
L92:
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L102
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L71
L102:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L97
L71:
  movl   $0x1,-0x4(%rbp)
  jmp    L37
L97:
  movl   $0x0,-0x4(%rbp)
L37:
  cmpl   $0x0,-0x18(%rbp)
  jle    L126
  cmpl   $0xc,-0x18(%rbp)
  jle    L6
L126:
  mov    $0xffffffff,%eax
  jmp    L60
L6:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L42
  mov    $0xffffffff,%eax
  jmp    L60
L42:
  cmpl   $0x0,-0x4(%rbp)
  je     L149
  cmpl   $0x2,-0x18(%rbp)
  jne    L149
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L26
  mov    $0xffffffff,%eax
  jmp    L60
L149:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L26
  mov    $0xffffffff,%eax
  jmp    L60
L26:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L177
  cmpl   $0x2,-0x18(%rbp)
  jg     L177
  subl   $0x1,-0x8(%rbp)
L177:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x6,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L60:
  pop    %rbp
  ret
```

assistant: ```c
int dow(int yr, int mo, int da) {
  static int totdays[12] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  static int numdays[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int addon = 0;
  int leap;
  yr %= 400;
  if (yr < 0)
    yr += 400;
  if (((((yr % 4) == 0) && ((yr % 100) != 0)) || ((yr % 400) == 0)))
    leap = 1;
  else
    leap = 0;
  if ((mo < 1) || (mo > 12))
    return (-1);
  if (da < 1)
    return (-1);
  if (leap && (mo == 2)) {
    if (da > (numdays[mo - 1] + 1))
      return (-1);
  } else if (da > numdays[mo - 1])
    return (-1);
  addon += yr;
  addon += yr / 4;
  addon -= yr / 100;
  if (leap && (mo <= 2))
    addon--;
  addon += totdays[mo - 1];
  addon += da;
  addon += 6;
  return (addon % 7);
}
```