user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<loosen_labels>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,%r14d
  lea    0x0(,%rcx,4),%edi
  call   <malloc_or_die@plt>
  mov    %rax,%rbp
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movzbl (%rbx),%esi
  movl   $0x1,0x0(%rbp)
  cmp    $0x1,%r14d
  jle    L151
  mov    %r14d,%r10d
  mov    $0x1,%eax
  mov    $0x1,%edx
  jmp    L29
L69:
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %esi,%edx
  sar    %edx
  add    $0x1,%edx
  sub    %edx,%r8d
  movslq %r8d,%r8
  movl   $0x1,0x0(%rbp,%r8,4)
  mov    %edi,%esi
  mov    %ecx,%edx
  jmp    L83
L138:
  add    $0x1,%edx
L83:
  add    $0x1,%rax
  cmp    %r10,%rax
  je     L106
L29:
  mov    %eax,%r8d
  movzbl (%rbx,%rax,1),%edi
  cmp    %sil,%dil
  je     L138
  cmp    %eax,%edx
  je     L81
  mov    %edx,%esi
  shr    $0x1f,%esi
  lea    (%rdx,%rsi,1),%ecx
  and    $0x1,%ecx
  sub    %esi,%ecx
  cmp    $0x1,%ecx
  je     L69
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  sar    %edx
  neg    %edx
  lea    (%rdx,%rax,1),%ecx
  movslq %ecx,%rcx
  movl   $0x1,0x0(%rbp,%rcx,4)
  lea    -0x1(%rax,%rdx,1),%edx
  movslq %edx,%rdx
  movl   $0x1,0x0(%rbp,%rdx,4)
  mov    %edi,%esi
  mov    $0x1,%edx
  jmp    L83
L81:
  mov    %edi,%esi
  mov    $0x1,%edx
  jmp    L83
L162:
  movzbl (%rbx,%r8,1),%eax
L15:
  add    $0x1,%r11
  add    $0x1,%r8
  add    $0x1,%rdi
  add    $0x8,%r14
  cmp    %r10,%r8
  je     L151
L56:
  cmp    %al,(%rbx,%r8,1)
  je     L15
  test   %r13d,%r13d
  jle    L162
  lea    0x0(%rbp,%r8,4),%rax
  lea    (%r12,%r8,1),%rdx
  lea    (%r12,%r11,1),%rcx
  lea    -0x4(%r14),%r9
L76:
  cmpl   $0x0,(%rax)
  jne    L162
  mov    %r9,%rsi
  sub    %rax,%rsi
  cmpl   $0x0,(%rsi)
  jne    L162
  movb   $0x2e,(%rdx)
  movb   $0x2e,(%rcx)
  add    $0x4,%rax
  add    $0x1,%rdx
  sub    $0x1,%rcx
  cmp    %rdi,%rdx
  jne    L76
  jmp    L162
L151:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L106:
  movzbl (%rbx),%eax
  lea    -0x1(%r13),%edx
  lea    0x2(%r12,%rdx,1),%rdi
  lea    0x8(%rbp,%rbp,1),%r14
  mov    $0x1,%r8d
  mov    $0x0,%r11d
  jmp    L56
```

assistant: ```c
void loosen_labels(char *labels, char *loose_labels, int label_looseness, int seq_len) {
  int *locked_labels;
  int reg_len;
  int i, j;
  char cur;
  locked_labels = (int *)(malloc_or_die(seq_len * sizeof(int)));
  memcpy(loose_labels, labels, seq_len * sizeof(char));
  reg_len = 1;
  cur = labels[0];
  locked_labels[0] = 1;
  for (i = 1; i < seq_len; i++) {
    if (labels[i] != cur) {
      cur = labels[i];
      if (reg_len == i) {
      } else {
        if (reg_len % 2 == 1) {
          locked_labels[i - (reg_len / 2 + 1)] = 1;
        } else {
          locked_labels[i - reg_len / 2] = 1;
          locked_labels[i - (reg_len / 2 + 1)] = 1;
        }
      }
      reg_len = 1;
    } else {
      reg_len++;
    }
  }
  reg_len = 1;
  cur = labels[0];
  for (i = 1; i < seq_len; i++) {
    if (labels[i] != cur) {
      for (j = 0; j < label_looseness; j++) {
        if (locked_labels[i + j] == 0 && locked_labels[i - 1 - j] == 0) {
          loose_labels[i + j] = '.';
          loose_labels[i - 1 - j] = '.';
        } else {
          break;
        }
      }
      cur = labels[i];
      reg_len = 1;
    } else {
      reg_len++;
    }
  }
  free(locked_labels);
}
```