ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<vgs2_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <vgs2_pallet256@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int vgs2_init() {
  vgs2_pallet256(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vgs2_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <vgs2_pallet256@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int vgs2_init() {
  vgs2_pallet256(0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L57
  mov    D18(%rip),%rax
  jmp    L46
L57:
  cmpl   $0x1,-0xc(%rbp)
  jne    L41
  mov    -0x8(%rbp),%rax
  jmp    L46
L41:
  cmpl   $0x0,-0xc(%rbp)
  jns    L27
  negl   -0xc(%rbp)
  movsd  D18(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L56
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movq   %xmm0,%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <my_pow>
  movq   %xmm0,%rax
  jmp    L46
L56:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movq   %xmm0,%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <my_pow>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movq   %xmm1,%rax
L46:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
type_guessed: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double my_pow(double x, int n) {
  if (n == 0) {
    return 1;
  }
  if (n == 1) {
    return x;
  }
  if (n < 0) {
    n = -n;
    x = 1 / x;
  }
  return n % 2 == 0 ? my_pow(x * x, n / 2) : my_pow(x * x, n / 2) * x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_pow>:
  endbr64
  test   %edi,%edi
  je     L51
  push   %rbx
  movq   %xmm0,%rbx
  cmp    $0x1,%edi
  je     L18
  test   %edi,%edi
  js     L29
L35:
  test   $0x1,%dil
  jne    L5
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %eax,%edi
  sar    %edi
  movq   %rbx,%xmm0
  mulsd  %xmm0,%xmm0
  call   <my_pow>
L18:
  pop    %rbx
  ret
L29:
  neg    %edi
  movsd  D11(%rip),%xmm0
  movq   %rbx,%xmm4
  divsd  %xmm4,%xmm0
  movq   %xmm0,%rbx
  jmp    L35
L5:
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %eax,%edi
  sar    %edi
  movq   %rbx,%xmm0
  mulsd  %xmm0,%xmm0
  call   <my_pow>
  movq   %rbx,%xmm3
  mulsd  %xmm3,%xmm0
  jmp    L18
L51:
  movsd  D11(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D11
datatype: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double my_pow(double x, int n) {
  if (n == 0) {
    return 1;
  }
  if (n == 1) {
    return x;
  }
  if (n < 0) {
    n = -n;
    x = 1 / x;
  }
  return n % 2 == 0 ? my_pow(x * x, n / 2) : my_pow(x * x, n / 2) * x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_pow>:
  endbr64
  test   %edi,%edi
  je     L50
  cmp    $0x1,%edi
  je     L62
  movsd  D8(%rip),%xmm2
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L49:
  test   %edi,%edi
  je     L50
  cmp    $0x1,%edi
  je     L62
L8:
  movapd %xmm0,%xmm1
  test   %edi,%edi
  jns    L4
  movapd %xmm2,%xmm3
  neg    %edi
  divsd  %xmm0,%xmm3
  movapd %xmm3,%xmm1
L4:
  mov    %edi,%eax
  movapd %xmm1,%xmm0
  sar    %edi
  mulsd  %xmm1,%xmm0
  and    $0x1,%eax
  test   %eax,%eax
  je     L49
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <my_pow>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  ret
L62:
  ret
  nopl   0x0(%rax)
L50:
  movsd  D8(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double my_pow(double x, int n) {
  if (n == 0) {
    return 1;
  }
  if (n == 1) {
    return x;
  }
  if (n < 0) {
    n = -n;
    x = 1 / x;
  }
  return n % 2 == 0 ? my_pow(x * x, n / 2) : my_pow(x * x, n / 2) * x;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<my_pow>:
  endbr64
  test   %edi,%edi
  je     L38
  movapd %xmm0,%xmm2
  cmp    $0x1,%edi
  je     L82
  movsd  D10(%rip),%xmm0
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L95:
  test   %edi,%edi
  je     L38
  cmp    $0x1,%edi
  je     L82
L64:
  movapd %xmm2,%xmm1
  test   %edi,%edi
  jns    L21
  movapd %xmm0,%xmm4
  neg    %edi
  divsd  %xmm2,%xmm4
  movapd %xmm4,%xmm1
L21:
  mov    %edi,%eax
  movapd %xmm1,%xmm2
  sar    %edi
  mulsd  %xmm1,%xmm2
  and    $0x1,%eax
  test   %eax,%eax
  je     L95
  test   %edi,%edi
  jne    L54
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L112:
  test   $0x1,%dil
  jne    L60
  mulsd  %xmm2,%xmm2
  sar    %edi
L54:
  cmp    $0x1,%edi
  jne    L112
L42:
  mulsd  %xmm2,%xmm1
L14:
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  movsd  D10(%rip),%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L82:
  movapd %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L60:
  movapd %xmm2,%xmm3
  sar    %edi
  mulsd  %xmm2,%xmm3
  cmp    $0x1,%edi
  jne    L52
  jmp    L111
  nopl   0x0(%rax)
L62:
  mulsd  %xmm3,%xmm3
  sar    %edi
  cmp    $0x1,%edi
  je     L111
L52:
  test   $0x1,%dil
  je     L62
  movapd %xmm3,%xmm0
  sub    $0x28,%rsp
  sar    %edi
  mulsd  %xmm3,%xmm0
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <my_pow>
  movsd  0x8(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  add    $0x28,%rsp
  mulsd  %xmm0,%xmm3
  mulsd  %xmm3,%xmm2
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
L111:
  mulsd  %xmm3,%xmm2
  jmp    L42
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double my_pow(double x, int n) {
  if (n == 0) {
    return 1;
  }
  if (n == 1) {
    return x;
  }
  if (n < 0) {
    n = -n;
    x = 1 / x;
  }
  return n % 2 == 0 ? my_pow(x * x, n / 2) : my_pow(x * x, n / 2) * x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<useLocal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x19,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string
name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D1: 
local x in useLocal is %d after entering useLocal


tool: D4: local x in useLocal is %d before exiting useLocal


assistant: ```c
void useLocal(void) {
  int x = 25;
  printf("\nlocal x in useLocal is %d after entering useLocal\n", x);
  x++;
  printf("local x in useLocal is %d before exiting useLocal\n", x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<useLocal>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x19,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x1a,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
datatype: string
name: disassemble_data
arguments: data_tag: D13
datatype: string

tool: D15: 
local x in useLocal is %d after entering useLocal


tool: D13: local x in useLocal is %d before exiting useLocal


assistant: ```c
void useLocal(void) {
  int x = 25;
  printf("\nlocal x in useLocal is %d after entering useLocal\n", x);
  x++;
  printf("local x in useLocal is %d before exiting useLocal\n", x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<useLocal>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x19,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1a,%esi
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D8: 
local x in useLocal is %d after entering useLocal


tool: D4: local x in useLocal is %d before exiting useLocal


assistant: ```c
void useLocal(void) {
  int x = 25;
  printf("\nlocal x in useLocal is %d after entering useLocal\n", x);
  x++;
  printf("local x in useLocal is %d before exiting useLocal\n", x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<useLocal>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x19,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x1a,%esi
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D14
datatype: string

tool: D16: 
local x in useLocal is %d after entering useLocal


tool: D14: local x in useLocal is %d before exiting useLocal


assistant: ```c
void useLocal(void) {
  int x = 25;
  printf("\nlocal x in useLocal is %d after entering useLocal\n", x);
  x++;
  printf("local x in useLocal is %d before exiting useLocal\n", x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %rdx,%rbp
  mov    %rcx,%r14
  mov    %rdx,%rdi
  call   <length@plt>
  mov    %rax,%rbx
  mov    %eax,0x8(%rsp)
  mov    %r14,%rdi
  call   <length@plt>
  mov    %eax,%r13d
  mov    %r12,%rdi
  call   <length@plt>
  mov    %rax,%rcx
  movslq %ebx,%rbx
  mov    %rax,%r8
  sub    %rbx,%r8
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%r9d
  js     L136
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%edx
  mov    $0x0,%r9d
  movslq %r13d,%r13
  mov    0x8(%rsp),%r11d
  sub    $0x1,%r11d
  movslq %r11d,%r11
  jmp    L102
L140:
  mov    0x8(%rsp),%rdx
L0:
  cmp    %rax,%rbx
  je     L64
L70:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jg     L136
L102:
  lea    (%r12,%rdx,1),%r10
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%r10)
  jne    L99
  mov    $0x0,%eax
  test   %rbx,%rbx
  jle    L99
  mov    %rdx,0x8(%rsp)
L77:
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  cmp    %dl,(%r10,%rax,1)
  jne    L140
  cmp    %rbx,%rax
  jl     L77
  mov    0x8(%rsp),%rdx
  jmp    L0
L64:
  add    $0x1,%r9d
  cmp    %rdi,%rdx
  jle    L44
  mov    %rdi,%rax
  mov    %rsi,%r10
  sub    %rdi,%r10
  add    %r15,%r10
  mov    %rcx,0x8(%rsp)
L85:
  movzbl (%r12,%rax,1),%ecx
  mov    %cl,(%r10,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L85
  mov    0x8(%rsp),%rcx
L44:
  mov    %rdx,%r10
  sub    %rdi,%r10
  add    %rsi,%r10
  test   %r13,%r13
  jle    L154
  mov    $0x0,%eax
  lea    (%r15,%r10,1),%rdi
L162:
  movzbl (%r14,%rax,1),%esi
  mov    %sil,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L162
L154:
  lea    (%r10,%r13,1),%rsi
  lea    (%rbx,%rdx,1),%rdi
  add    %r11,%rdx
  jmp    L70
L99:
  mov    $0x0,%eax
  jmp    L0
L136:
  cmp    %rdi,%rcx
  jl     L143
  add    $0x1,%rcx
  mov    %rdi,%rax
  sub    %rdi,%rsi
  add    %r15,%rsi
L49:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L49
L143:
  movslq %r9d,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
long replace(char *str, char *str2, char *s, char *t) {
  int ls, lt, c;
  long a, b, fl, f, e, m;
  ls = length(s);
  lt = length(t);
  fl = length(str);
  c = 0;
  f = 0;
  e = 0;
  for (a = 0; a <= fl - ls; a++) {
    b = 0;
    while (*(str + a + b) == *(s + b) && b < ls)
      b++;
    if (b == ls) {
      c++;
      for (m = f; m < a; m++)
        *(str2 + e + m - f) = *(str + m);
      e += a - f;
      for (m = 0; m < lt; m++)
        *(str2 + e + m) = *(t + m);
      e += lt;
      f = a + ls;
      a += ls - 1;
    }
  }
  for (m = f; m <= fl; m++)
    *(str2 + e + m - f) = *(str + m);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<replace>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  call   <length@plt>
  mov    %r14,%rdi
  mov    %rax,%rbp
  mov    %eax,%r12d
  call   <length@plt>
  mov    %r13,%rdi
  mov    %eax,(%rsp)
  call   <length@plt>
  movslq %ebp,%rdx
  mov    %rax,%r8
  mov    %rax,%r10
  sub    %rdx,%r8
  js     L125
  test   %rdx,%rdx
  movslq (%rsp),%rbp
  setg   %r9b
  sub    $0x1,%r12d
  xor    %edi,%edi
  xor    %esi,%esi
  movslq %r12d,%rax
  xor    %ecx,%ecx
  xor    %r11d,%r11d
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L9:
  lea    0x0(%r13,%rcx,1),%r12
  movzbl (%rbx),%eax
  cmp    %al,(%r12)
  jne    L117
  xor    %eax,%eax
  test   %r9b,%r9b
  je     L117
  mov    %rcx,(%rsp)
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L101:
  cmp    %rdx,%rax
  jge    L61
L72:
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%ecx
  cmp    %cl,(%r12,%rax,1)
  je     L101
L61:
  mov    (%rsp),%rcx
L37:
  cmp    %rax,%rdx
  je     L119
L121:
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jle    L9
  movslq %r11d,%rax
L159:
  sub    %rsi,%rdi
  lea    0x1(%r10),%rcx
  lea    (%r15,%rdi,1),%rdx
  cmp    %rsi,%r10
  jl     L20
  nopl   0x0(%rax,%rax,1)
L137:
  movzbl 0x0(%r13,%rsi,1),%edi
  mov    %dil,(%rdx,%rsi,1)
  add    $0x1,%rsi
  cmp    %rcx,%rsi
  jne    L137
L20:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L119:
  mov    %rdi,%r12
  add    $0x1,%r11d
  mov    %rsi,%rax
  sub    %rsi,%r12
  add    %r15,%r12
  cmp    %rsi,%rcx
  jle    L168
  mov    %rdx,(%rsp)
  nopl   0x0(%rax)
L152:
  movzbl 0x0(%r13,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L152
  mov    (%rsp),%rdx
L168:
  mov    %rcx,%r12
  xor    %eax,%eax
  sub    %rsi,%r12
  add    %rdi,%r12
  lea    (%r15,%r12,1),%rdi
  test   %rbp,%rbp
  jle    L156
  nopl   0x0(%rax,%rax,1)
L138:
  movzbl (%r14,%rax,1),%esi
  mov    %sil,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L138
L156:
  lea    (%rdx,%rcx,1),%rsi
  lea    (%r12,%rbp,1),%rdi
  add    0x8(%rsp),%rcx
  jmp    L121
  nopl   0x0(%rax)
L117:
  xor    %eax,%eax
  jmp    L37
L125:
  xor    %eax,%eax
  xor    %edi,%edi
  xor    %esi,%esi
  jmp    L159
```

assistant: ```c
long replace(char *str, char *str2, char *s, char *t) {
  int ls, lt, c;
  long a, b, fl, f, e, m;
  ls = length(s);
  lt = length(t);
  fl = length(str);
  c = 0;
  f = 0;
  e = 0;
  for (a = 0; a <= fl - ls; a++) {
    b = 0;
    while (*(str + a + b) == *(s + b) && b < ls)
      b++;
    if (b == ls) {
      c++;
      for (m = f; m < a; m++)
        *(str2 + e + m - f) = *(str + m);
      e += a - f;
      for (m = 0; m < lt; m++)
        *(str2 + e + m) = *(t + m);
      e += lt;
      f = a + ls;
      a += ls - 1;
    }
  }
  for (m = f; m <= fl; m++)
    *(str2 + e + m - f) = *(str + m);
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L24:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L7
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xe(%rbp)
  jle    L13
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L13:
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xe(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(char *st, int len) {
  int a, b;
  for (a = 0; a < len; a++) {
    int pos = a;
    char sm = *(st + a);
    for (b = a + 1; b < len; b++) {
      if (*(st + b) < sm) {
        sm = *(st + b);
        pos = b;
      }
    }
    char temp = *(st + a);
    *(st + a) = sm;
    *(st + pos) = temp;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sort>:
  endbr64
  test   %esi,%esi
  jle    L58
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebp
  mov    %ebp,%ebx
  mov    $0x0,%r9d
  jmp    L55
L35:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L59
L7:
  movzbl (%rdi,%rax,1),%edx
  cmp    %cl,%dl
  jge    L35
  mov    %edx,%ecx
  mov    %eax,%r8d
  jmp    L35
L29:
  mov    %r10b,(%rdi,%rbx,1)
  movslq %ebp,%rbp
  mov    %r10b,(%rdi,%rbp,1)
  pop    %rbx
  pop    %rbp
  ret
L59:
  mov    %cl,(%rdi,%r9,1)
  movslq %r8d,%r8
  mov    %r10b,(%rdi,%r8,1)
  mov    %r11,%r9
L55:
  mov    %r9d,%r8d
  movzbl (%rdi,%r9,1),%r10d
  cmp    %rbx,%r9
  je     L29
  lea    0x1(%r9),%r11
  mov    %r11,%rax
  mov    %r10d,%ecx
  jmp    L7
L58:
  ret
```

assistant: ```c
void sort(char *st, int len) {
  int a, b;
  for (a = 0; a < len; a++) {
    int pos = a;
    char sm = *(st + a);
    for (b = a + 1; b < len; b++) {
      if (*(st + b) < sm) {
        sm = *(st + b);
        pos = b;
      }
    }
    char temp = *(st + a);
    *(st + a) = sm;
    *(st + pos) = temp;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sort>:
  endbr64
  test   %esi,%esi
  jle    L40
  xor    %r9d,%r9d
  push   %rbx
  lea    -0x1(%rsi),%ebx
  movzbl (%rdi,%r9,1),%r10d
  movslq %r9d,%r8
  cmp    %r9,%rbx
  je     L20
  nopl   0x0(%rax)
L14:
  lea    0x1(%r9),%r11
  mov    %r10d,%ecx
  mov    %r11,%rax
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl (%rdi,%rax,1),%edx
  cmp    %cl,%dl
  jge    L38
  mov    %edx,%ecx
  movslq %eax,%r8
L38:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L16
  mov    %cl,(%rdi,%r9,1)
  mov    %r11,%r9
  mov    %r10b,(%rdi,%r8,1)
  movslq %r9d,%r8
  movzbl (%rdi,%r9,1),%r10d
  cmp    %r9,%rbx
  jne    L14
L20:
  pop    %rbx
  ret
L40:
  ret
```

assistant: ```c
void sort(char *st, int len) {
  int a, b;
  for (a = 0; a < len; a++) {
    int pos = a;
    char sm = *(st + a);
    for (b = a + 1; b < len; b++) {
      if (*(st + b) < sm) {
        sm = *(st + b);
        pos = b;
      }
    }
    char temp = *(st + a);
    *(st + a) = sm;
    *(st + pos) = temp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sort>:
  endbr64
  test   %esi,%esi
  jle    L32
  push   %rbx
  movzbl (%rdi),%r10d
  lea    -0x1(%rsi),%ebx
  xor    %r9d,%r9d
  cmp    $0x1,%esi
  je     L22
  nopl   0x0(%rax,%rax,1)
L4:
  movslq %r9d,%r8
  mov    %r9,%r11
  add    $0x1,%r9
  mov    %r10d,%ecx
  mov    %r9,%rax
L17:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,%cl
  jle    L15
  mov    %edx,%ecx
  movslq %eax,%r8
L15:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L17
  mov    %cl,(%rdi,%r11,1)
  mov    %r10b,(%rdi,%r8,1)
  movzbl 0x1(%rdi,%r11,1),%r10d
  cmp    %rbx,%r9
  jne    L4
L22:
  pop    %rbx
  ret
L32:
  ret
```

assistant: ```c
void sort(char *st, int len) {
  int a, b;
  for (a = 0; a < len; a++) {
    int pos = a;
    char sm = *(st + a);
    for (b = a + 1; b < len; b++) {
      if (*(st + b) < sm) {
        sm = *(st + b);
        pos = b;
      }
    }
    char temp = *(st + a);
    *(st + a) = sm;
    *(st + pos) = temp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L32
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
L32:
  mov    -0x18(%rbp),%rax
  jmp    L38
L27:
  mov    -0x18(%rbp),%rax
  mov    $0x400,%edx
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <strlcpy@plt>
  lea    D22(%rip),%rax
  mov    %rax,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  lea    D22(%rip),%rax
L38:
  leave
  ret
```

assistant: ```c
const char *str_filter(const char *str) {
  static char buf[1024];
  char *s;
  if (str == NULL || *str == '\0')
    return str;
  strlcpy(buf, str, sizeof(buf));
  s = buf;
  do {
    *s = toupper(*s);
  } while (*s++);
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_filter>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L16
  cmpb   $0x0,(%rdi)
  jne    L1
L16:
  ret
L1:
  push   %rbx
  mov    $0x400,%edx
  mov    %rdi,%rsi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <strlcpy@plt>
L4:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  test   %al,%al
  jne    L4
  lea    D19(%rip),%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *str_filter(const char *str) {
  static char buf[1024];
  char *s;
  if (str == NULL || *str == '\0')
    return str;
  strlcpy(buf, str, sizeof(buf));
  s = buf;
  do {
    *s = toupper(*s);
  } while (*s++);
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_filter>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L4
  cmpb   $0x0,(%rdi)
  jne    L12
L4:
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  push   %rbx
  lea    D16(%rip),%rbx
  mov    %rdi,%rsi
  mov    $0x400,%edx
  mov    %rbx,%rdi
  call   <strlcpy@plt>
L6:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  test   %al,%al
  jne    L6
  lea    D16(%rip),%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *str_filter(const char *str) {
  static char buf[1024];
  char *s;
  if (str == NULL || *str == '\0')
    return str;
  strlcpy(buf, str, sizeof(buf));
  s = buf;
  do {
    *s = toupper(*s);
  } while (*s++);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_filter>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L20
  cmpb   $0x0,(%rdi)
  jne    L2
L20:
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  push   %rbx
  lea    D16(%rip),%rbx
  mov    %rdi,%rsi
  mov    $0x400,%edx
  mov    %rbx,%rdi
  call   <strlcpy@plt>
L4:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  test   %al,%al
  jne    L4
  lea    D16(%rip),%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *str_filter(const char *str) {
  static char buf[1024];
  char *s;
  if (str == NULL || *str == '\0')
    return str;
  strlcpy(buf, str, sizeof(buf));
  s = buf;
  do {
    *s = toupper(*s);
  } while (*s++);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <SumDivisibleBy@plt>
  mov    %eax,%ebx
  mov    $0x5,%edi
  call   <SumDivisibleBy@plt>
  add    %eax,%ebx
  mov    $0xf,%edi
  call   <SumDivisibleBy@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: string

tool: D7: %d


assistant: ```c
int main(void) {
  printf("%d\n", SumDivisibleBy(3) + SumDivisibleBy(5) - SumDivisibleBy(15));
  return 0;
}
```