user: 下面的汇编指令对应的C源代码是什么:

```asm
<bucketed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %rdi,-0x108(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xd0,%edi
  call   <malloc@plt>
  mov    %rax,-0xe8(%rbp)
  movb   $0x41,-0xf1(%rbp)
  movl   $0x0,-0xf0(%rbp)
  jmp    L38
L45:
  mov    -0xf0(%rbp),%eax
  cltq
  movl   $0x0,-0xe0(%rbp,%rax,4)
  mov    -0xf0(%rbp),%eax
  cltq
  movl   $0x0,-0x70(%rbp,%rax,4)
  addl   $0x1,-0xf0(%rbp)
L38:
  cmpl   $0x19,-0xf0(%rbp)
  jle    L45
  movl   $0x0,-0xf0(%rbp)
  jmp    L96
L17:
  mov    -0xf0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x108(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  movslq %eax,%rdx
  mov    -0xe0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0xe0(%rbp,%rax,4)
  mov    -0xf0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x108(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  addl   $0x1,-0xf0(%rbp)
L96:
  cmpl   $0x142a,-0xf0(%rbp)
  jle    L17
  movl   $0x0,-0xf0(%rbp)
  jmp    L104
L5:
  mov    -0xf0(%rbp),%eax
  cltq
  mov    -0xe0(%rbp,%rax,4),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xf0(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0xe8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0xec(%rbp)
  jmp    L23
L61:
  mov    $0xd,%edi
  call   <malloc@plt>
  mov    -0xf0(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0xe8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0xec(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xec(%rbp)
L23:
  mov    -0xf0(%rbp),%eax
  cltq
  mov    -0xe0(%rbp,%rax,4),%eax
  cmp    %eax,-0xec(%rbp)
  jl     L61
  addl   $0x1,-0xf0(%rbp)
L104:
  cmpl   $0x19,-0xf0(%rbp)
  jle    L5
  movl   $0x0,-0xf0(%rbp)
  jmp    L97
L30:
  mov    -0xf0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x108(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xf0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x108(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  shl    $0x3,%rax
  lea    -0x208(%rax),%rcx
  mov    -0xe8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rsi
  mov    -0xf0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x108(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  mov    -0xe0(%rbp,%rax,4),%ecx
  mov    -0xf0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdi
  mov    -0x108(%rbp),%rax
  add    %rdi,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%edi
  mov    %ecx,%eax
  sub    %edi,%eax
  cltq
  shl    $0x3,%rax
  add    %rsi,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0xf0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x108(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  sub    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  addl   $0x1,-0xf0(%rbp)
L97:
  cmpl   $0x142a,-0xf0(%rbp)
  jle    L30
  mov    -0xe8(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  leave
  ret
```

assistant: ```c
char ***bucketed(char **arr) {
  char ***buckets = (char ***)malloc(26 * sizeof(char **));
  int count[26], count_iter[26];
  char iter = 'A';
  int i, j;
  for (i = 0; i < 26; i++) {
    count[i] = 0;
    count_iter[i] = 0;
  }
  for (i = 0; i < 5163; i++) {
    count[arr[i][0] - 'A']++;
    count_iter[arr[i][0] - 'A']++;
  }
  for (i = 0; i < 26; i++) {
    buckets[i] = (char **)malloc(count[i] * sizeof(char *));
    for (j = 0; j < count[i]; j++) {
      buckets[i][j] = (char *)malloc(13 * sizeof(char));
    }
  }
  for (i = 0; i < 5163; i++) {
    strcpy(buckets[arr[i][0] - 'A'][(count[arr[i][0] - 'A'] - count_iter[arr[i][0] - 'A'])], arr[i]);
    count_iter[arr[i][0] - 'A']--;
  }
  return buckets;
}
```