user: 这段汇编代码用C语言表示是什么样的?

```asm
<CI_Keyed_Update>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x250,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %esi,-0x22c(%rbp)
  mov    %rdx,-0x238(%rbp)
  mov    %ecx,-0x230(%rbp)
  mov    %r8d,-0x23c(%rbp)
  mov    %r9d,-0x240(%rbp)
  mov    0x18(%rbp),%rax
  mov    %rax,-0x248(%rbp)
  mov    0x28(%rbp),%rax
  mov    %rax,-0x250(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    0x20(%rbp),%eax
  mov    %eax,-0x220(%rbp)
  mov    -0x228(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    0x10(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x40,%eax
  sub    0x10(%rbp),%eax
  mov    0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    -0x110(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  lea    -0x23c(%rbp),%rsi
  lea    -0x220(%rbp),%rdx
  mov    -0x248(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x210(%rbp),%rcx
  push   %rcx
  push   $0x10
  push   -0x248(%rbp)
  mov    $0x4,%r9d
  mov    %rsi,%r8
  mov    $0x8,%ecx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__Hash4@plt>
  add    $0x20,%rsp
  movl   $0x0,-0x218(%rbp)
  jmp    L22
L37:
  mov    -0x218(%rbp),%eax
  cltq
  mov    -0x110(%rbp,%rax,4),%edx
  mov    -0x218(%rbp),%eax
  cltq
  mov    -0x210(%rbp,%rax,4),%eax
  xor    %eax,%edx
  mov    -0x218(%rbp),%eax
  cltq
  mov    %edx,-0x110(%rbp,%rax,4)
  addl   $0x1,-0x218(%rbp)
L22:
  mov    -0x218(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jl     L37
  mov    -0x23c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x21c(%rbp)
  jmp    L38
L9:
  mov    -0x21c(%rbp),%edx
  lea    -0x110(%rbp),%r8
  mov    -0x230(%rbp),%edi
  mov    -0x238(%rbp),%rcx
  mov    -0x22c(%rbp),%esi
  lea    -0x110(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <Flap@plt>
  lea    -0x110(%rbp),%rcx
  lea    -0x110(%rbp),%rdx
  lea    -0x21c(%rbp),%rax
  mov    %rcx,%r8
  mov    $0x40,%ecx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <__Hash2@plt>
  mov    $0x40,%eax
  sub    0x10(%rbp),%eax
  mov    0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    -0x110(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    -0x21c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x21c(%rbp)
L38:
  mov    -0x21c(%rbp),%edx
  mov    -0x240(%rbp),%eax
  cmp    %eax,%edx
  jle    L9
  lea    -0x240(%rbp),%rsi
  lea    -0x220(%rbp),%rdx
  mov    -0x248(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x210(%rbp),%rcx
  push   %rcx
  push   $0x10
  push   -0x248(%rbp)
  mov    $0x4,%r9d
  mov    %rsi,%r8
  mov    $0x8,%ecx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__Hash4@plt>
  add    $0x20,%rsp
  movl   $0x0,-0x214(%rbp)
  jmp    L12
L65:
  mov    -0x214(%rbp),%eax
  cltq
  mov    -0x110(%rbp,%rax,4),%edx
  mov    -0x214(%rbp),%eax
  cltq
  mov    -0x210(%rbp,%rax,4),%eax
  xor    %eax,%edx
  mov    -0x214(%rbp),%eax
  cltq
  mov    %edx,-0x110(%rbp,%rax,4)
  addl   $0x1,-0x214(%rbp)
L12:
  mov    -0x214(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jl     L65
  lea    -0x110(%rbp),%rcx
  mov    -0x250(%rbp),%rax
  mov    0x10(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
void CI_Keyed_Update(const uint8_t *old_hash, const uint8_t lambda, const uint8_t *salt, const uint8_t saltlen, const uint8_t old_garlic, const uint8_t new_garlic, const uint8_t hashlen, const uint8_t *key, const uint64_t uuid, uint8_t *new_hash) {
  uint8_t keystream[64];
  uint64_t tmp = (uuid);
  uint8_t c;
  uint8_t x[64];
  memcpy(x, old_hash, hashlen);
  memset(x + hashlen, 0, 64 - hashlen);
  __Hash4(key, 16, (uint8_t *)&tmp, 8, &old_garlic, sizeof(uint8_t), key, 16, keystream);
  for (int i = 0; i < hashlen; i++)
    x[i] ^= keystream[i];
  for (c = old_garlic + 1; c <= new_garlic; c++) {
    Flap(x, lambda, c, salt, saltlen, x);
    __Hash2(&c, 1, x, 64, x);
    memset(x + hashlen, 0, 64 - hashlen);
  }
  __Hash4(key, 16, (uint8_t *)&tmp, 8, &new_garlic, sizeof(uint8_t), key, 16, keystream);
  for (int i = 0; i < hashlen; i++)
    x[i] ^= keystream[i];
  memcpy(new_hash, x, hashlen);
}
```