ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<MMX_PSLLD_imm>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x66,%edi
  or     $0xf0,%bl
  sub    $0x8,%rsp
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x72,%edi
  call   <addbyte@plt>
  mov    %ebx,%edi
  call   <addbyte@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void MMX_PSLLD_imm(int dst_reg, int amount) {
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x72);
  addbyte(0xc0 | dst_reg | 0x30);
  addbyte(amount);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<MMX_PSLLD_imm>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x66,%edi
  or     $0xf0,%bl
  sub    $0x8,%rsp
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x72,%edi
  call   <addbyte@plt>
  mov    %ebx,%edi
  call   <addbyte@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void MMX_PSLLD_imm(int dst_reg, int amount) {
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x72);
  addbyte(0xc0 | dst_reg | 0x30);
  addbyte(amount);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<put_box>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x20,%eax
  je     L16
  cmp    $0x2e,%eax
  je     L2
  jmp    L27
L16:
  mov    $0x24,%eax
  jmp    L49
L2:
  mov    $0x2a,%eax
  jmp    L49
L27:
  movzbl -0x4(%rbp),%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
char put_box(char ch) {
  switch (ch) {
  case ' ':
    return '$';
  case '.':
    return '*';
  default:
    return ch;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<put_box>:
  endbr64
  mov    %edi,%eax
  cmp    $0x20,%dil
  je     L1
  cmp    $0x2e,%dil
  mov    $0x2a,%edx
  cmove  %edx,%eax
  ret
L1:
  mov    $0x24,%eax
  ret
```

assistant: ```c
char put_box(char ch) {
  switch (ch) {
  case ' ':
    return '$';
  case '.':
    return '*';
  default:
    return ch;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<put_box>:
  endbr64
  mov    $0x24,%eax
  cmp    $0x20,%dil
  je     L7
  cmp    $0x2e,%dil
  mov    $0x2a,%eax
  cmovne %edi,%eax
L7:
  ret
```

assistant: ```c
char put_box(char ch) {
  switch (ch) {
  case ' ':
    return '$';
  case '.':
    return '*';
  default:
    return ch;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<put_box>:
  endbr64
  mov    $0x24,%eax
  cmp    $0x20,%dil
  je     L4
  cmp    $0x2e,%dil
  mov    $0x2a,%eax
  cmovne %edi,%eax
L4:
  ret
```

assistant: ```c
char put_box(char ch) {
  switch (ch) {
  case ' ':
    return '$';
  case '.':
    return '*';
  default:
    return ch;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<scale_signal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void scale_signal(double *data, int n, double scale) {
  int j;
  for (j = 0; j < n; j++) {
    data[j] *= scale;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scale_signal>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L11:
  movapd %xmm0,%xmm1
  mulsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L11
L16:
  ret
```

assistant: ```c
void scale_signal(double *data, int n, double scale) {
  int j;
  for (j = 0; j < n; j++) {
    data[j] *= scale;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scale_signal>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
L15:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rdi)
  cmp    %rax,%rdi
  jne    L15
L9:
  ret
```

assistant: ```c
void scale_signal(double *data, int n, double scale) {
  int j;
  for (j = 0; j < n; j++) {
    data[j] *= scale;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scale_signal>:
  endbr64
  test   %esi,%esi
  jle    L35
  cmp    $0x1,%esi
  je     L48
  mov    %esi,%edx
  movapd %xmm0,%xmm2
  mov    %rdi,%rax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L36:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L36
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L25
L31:
  cltq
  lea    (%rdi,%rax,8),%rax
  mulsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L35:
  ret
  xchg   %ax,%ax
L25:
  ret
L48:
  xor    %eax,%eax
  jmp    L31
```

assistant: ```c
void scale_signal(double *data, int n, double scale) {
  int j;
  for (j = 0; j < n; j++) {
    data[j] *= scale;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: usage: runner [options] progname progarg1 progarg2 ... 
									
  options:								
     --input=<file>        redirect program input from file		
     --output=<file>       redirect program output to file		
     --mem=<size>          set the runtime memory limit to <size>	
     --stack=<size>        set the runtime stack limit to <size>	
     --time=<seconds>      set the run time limit in seconds (float)    
     --fsize=<size>        set the limit on amount of data outputted	
     --chroot=<dir>        chroot to the directory before executing     
     --debug               increase verbosity, do not redirect stderr.	
     --help                display this help page			
									
  <size> is in human readable format (12M, 12k etc., case insensitive.) 
  If no suffix is provided, it is understood to be bytes. 1k is 1024    
  bytes and 1M is 1024k.						
									
  This program is a part of the CMI Online Programming Contest Judge.	
  Copyright 2007-2009 Chennai Mathematical Institute. This program	
  is licensed under GNU General Public License, version 2.		
									


assistant: ```c
void print_usage() {
  printf("usage: runner [options] progname progarg1 progarg2 ... \n									\n  options:								\n     --input=<file>        redirect program input from file		\n     --output=<file>       redirect program output to file		\n     --mem=<size>          set the runtime memory limit to <size>	\n     --stack=<size>        set the runtime stack limit to <size>	\n     --time=<seconds>      set the run time limit in seconds (float)    \n     --fsize=<size>        set the limit on amount of data outputted	\n     --chroot=<dir>        chroot to the directory before executing     \n     --debug               increase verbosity, do not redirect stderr.	\n     --help                display this help page			\n									\n  <size> is in human readable format (12M, 12k etc., case insensitive.) \n  If no suffix is provided, it is understood to be bytes. 1k is 1024    \n  bytes and 1M is 1024k.				"
         "		\n									\n  This program is a part of the CMI Online Programming Contest Judge.	\n  Copyright 2007-2009 Chennai Mathematical Institute. This program	\n  is licensed under GNU General Public License, version 2.		\n									\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string

tool: D2: usage: runner [options] progname progarg1 progarg2 ... 
									
  options:								
     --input=<file>        redirect program input from file		
     --output=<file>       redirect program output to file		
     --mem=<size>          set the runtime memory limit to <size>	
     --stack=<size>        set the runtime stack limit to <size>	
     --time=<seconds>      set the run time limit in seconds (float)    
     --fsize=<size>        set the limit on amount of data outputted	
     --chroot=<dir>        chroot to the directory before executing     
     --debug               increase verbosity, do not redirect stderr.	
     --help                display this help page			
									
  <size> is in human readable format (12M, 12k etc., case insensitive.) 
  If no suffix is provided, it is understood to be bytes. 1k is 1024    
  bytes and 1M is 1024k.						
									
  This program is a part of the CMI Online Programming Contest Judge.	
  Copyright 2007-2009 Chennai Mathematical Institute. This program	
  is licensed under GNU General Public License, version 2.		
									


assistant: ```c
void print_usage() {
  printf("usage: runner [options] progname progarg1 progarg2 ... \n									\n  options:								\n     --input=<file>        redirect program input from file		\n     --output=<file>       redirect program output to file		\n     --mem=<size>          set the runtime memory limit to <size>	\n     --stack=<size>        set the runtime stack limit to <size>	\n     --time=<seconds>      set the run time limit in seconds (float)    \n     --fsize=<size>        set the limit on amount of data outputted	\n     --chroot=<dir>        chroot to the directory before executing     \n     --debug               increase verbosity, do not redirect stderr.	\n     --help                display this help page			\n									\n  <size> is in human readable format (12M, 12k etc., case insensitive.) \n  If no suffix is provided, it is understood to be bytes. 1k is 1024    \n  bytes and 1M is 1024k.				"
         "		\n									\n  This program is a part of the CMI Online Programming Contest Judge.	\n  Copyright 2007-2009 Chennai Mathematical Institute. This program	\n  is licensed under GNU General Public License, version 2.		\n									\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: usage: runner [options] progname progarg1 progarg2 ... 
									
  options:								
     --input=<file>        redirect program input from file		
     --output=<file>       redirect program output to file		
     --mem=<size>          set the runtime memory limit to <size>	
     --stack=<size>        set the runtime stack limit to <size>	
     --time=<seconds>      set the run time limit in seconds (float)    
     --fsize=<size>        set the limit on amount of data outputted	
     --chroot=<dir>        chroot to the directory before executing     
     --debug               increase verbosity, do not redirect stderr.	
     --help                display this help page			
									
  <size> is in human readable format (12M, 12k etc., case insensitive.) 
  If no suffix is provided, it is understood to be bytes. 1k is 1024    
  bytes and 1M is 1024k.						
									
  This program is a part of the CMI Online Programming Contest Judge.	
  Copyright 2007-2009 Chennai Mathematical Institute. This program	
  is licensed under GNU General Public License, version 2.		
									


assistant: ```c
void print_usage() {
  printf("usage: runner [options] progname progarg1 progarg2 ... \n									\n  options:								\n     --input=<file>        redirect program input from file		\n     --output=<file>       redirect program output to file		\n     --mem=<size>          set the runtime memory limit to <size>	\n     --stack=<size>        set the runtime stack limit to <size>	\n     --time=<seconds>      set the run time limit in seconds (float)    \n     --fsize=<size>        set the limit on amount of data outputted	\n     --chroot=<dir>        chroot to the directory before executing     \n     --debug               increase verbosity, do not redirect stderr.	\n     --help                display this help page			\n									\n  <size> is in human readable format (12M, 12k etc., case insensitive.) \n  If no suffix is provided, it is understood to be bytes. 1k is 1024    \n  bytes and 1M is 1024k.				"
         "		\n									\n  This program is a part of the CMI Online Programming Contest Judge.	\n  Copyright 2007-2009 Chennai Mathematical Institute. This program	\n  is licensed under GNU General Public License, version 2.		\n									\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_usage>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: usage: runner [options] progname progarg1 progarg2 ... 
									
  options:								
     --input=<file>        redirect program input from file		
     --output=<file>       redirect program output to file		
     --mem=<size>          set the runtime memory limit to <size>	
     --stack=<size>        set the runtime stack limit to <size>	
     --time=<seconds>      set the run time limit in seconds (float)    
     --fsize=<size>        set the limit on amount of data outputted	
     --chroot=<dir>        chroot to the directory before executing     
     --debug               increase verbosity, do not redirect stderr.	
     --help                display this help page			
									
  <size> is in human readable format (12M, 12k etc., case insensitive.) 
  If no suffix is provided, it is understood to be bytes. 1k is 1024    
  bytes and 1M is 1024k.						
									
  This program is a part of the CMI Online Programming Contest Judge.	
  Copyright 2007-2009 Chennai Mathematical Institute. This program	
  is licensed under GNU General Public License, version 2.		
									


assistant: ```c
void print_usage() {
  printf("usage: runner [options] progname progarg1 progarg2 ... \n									\n  options:								\n     --input=<file>        redirect program input from file		\n     --output=<file>       redirect program output to file		\n     --mem=<size>          set the runtime memory limit to <size>	\n     --stack=<size>        set the runtime stack limit to <size>	\n     --time=<seconds>      set the run time limit in seconds (float)    \n     --fsize=<size>        set the limit on amount of data outputted	\n     --chroot=<dir>        chroot to the directory before executing     \n     --debug               increase verbosity, do not redirect stderr.	\n     --help                display this help page			\n									\n  <size> is in human readable format (12M, 12k etc., case insensitive.) \n  If no suffix is provided, it is understood to be bytes. 1k is 1024    \n  bytes and 1M is 1024k.				"
         "		\n									\n  This program is a part of the CMI Online Programming Contest Judge.	\n  Copyright 2007-2009 Chennai Mathematical Institute. This program	\n  is licensed under GNU General Public License, version 2.		\n									\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6165592073696854,%rax
  movabs $0x7261745320732772,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6e694c20676e6974,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x70552d65,-0x18(%rbp)
  movb   $0x0,-0x14(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <underline@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <strlenght@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    $0x18,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D17
type_infered: string

tool: D19: This%c string has %d characters

tool: D17: 



assistant: ```c
int main() {
  int leght;
  char *point;
  char plm[] = "This Year's Starting Line-Up";
  point = &plm;
  underline(point);
  leght = strlenght(point);
  printf("This%c string has %d characters", 24, leght);
  puts("\n\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6165592073696854,%rax
  movabs $0x7261745320732772,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x6e694c20676e6974,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x70552d65,0x18(%rsp)
  movb   $0x0,0x1c(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <underline@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <strlenght@plt>
  mov    %eax,%edx
  mov    $0x18,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D10
type_infered: string

tool: D8: This%c string has %d characters

tool: D10: 



assistant: ```c
int main() {
  int leght;
  char *point;
  char plm[] = "This Year's Starting Line-Up";
  point = &plm;
  underline(point);
  leght = strlenght(point);
  printf("This%c string has %d characters", 24, leght);
  puts("\n\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x70552d65,0x18(%rsp)
  movabs $0x6e694c20676e6974,%rax
  mov    %rax,0x10(%rsp)
  mov    %rbp,%rdi
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movb   $0x0,0x1c(%rsp)
  call   <underline@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <strlenght@plt>
  lea    D0(%rip),%rdi
  mov    $0x18,%esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string

tool: {"D26": [0x54,0x68,0x69,0x73,0x20,0x59,0x65,0x61,0x72,0x27,0x73,0x20,0x53,0x74,0x61,0x72]}

tool: D0: This%c string has %d characters

tool: D12: 



assistant: ```c
int main() {
  int leght;
  char *point;
  char plm[] = "This Year's Starting Line-Up";
  point = &plm;
  underline(point);
  leght = strlenght(point);
  printf("This%c string has %d characters", 24, leght);
  puts("\n\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  movdqa D21(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x70552d65,0x18(%rsp)
  movabs $0x6e694c20676e6974,%rax
  mov    %rax,0x10(%rsp)
  mov    %rbp,%rdi
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movb   $0x0,0x1c(%rsp)
  call   <underline@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <strlenght@plt>
  lea    D26(%rip),%rdi
  mov    $0x18,%esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
datatype: byte[16]
name: read_data
arguments: tag: D26
datatype: string
name: read_data
arguments: tag: D2
datatype: string

tool: {"D21": [0x54,0x68,0x69,0x73,0x20,0x59,0x65,0x61,0x72,0x27,0x73,0x20,0x53,0x74,0x61,0x72]}

tool: D26: This%c string has %d characters

tool: D2: 



assistant: ```c
int main() {
  int leght;
  char *point;
  char plm[] = "This Year's Starting Line-Up";
  point = &plm;
  underline(point);
  leght = strlenght(point);
  printf("This%c string has %d characters", 24, leght);
  puts("\n\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<closeStream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void closeStream(FILE *f) {
  if (f != stdin) {
    fclose(f);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<closeStream>:
  endbr64
  mov    D9(%rip),%rax
  cmp    %rdi,(%rax)
  je     L5
  sub    $0x8,%rsp
  call   <fclose@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
void closeStream(FILE *f) {
  if (f != stdin) {
    fclose(f);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<closeStream>:
  endbr64
  mov    D9(%rip),%rax
  cmp    %rdi,(%rax)
  je     L5
  jmp    1050 <fclose@plt>
  nopl   (%rax)
L5:
  ret
```

assistant: ```c
void closeStream(FILE *f) {
  if (f != stdin) {
    fclose(f);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<closeStream>:
  endbr64
  mov    D0(%rip),%rax
  cmp    %rdi,(%rax)
  je     L2
  jmp    1050 <fclose@plt>
  nopl   (%rax)
L2:
  ret
```

assistant: ```c
void closeStream(FILE *f) {
  if (f != stdin) {
    fclose(f);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L13:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    $0xc34f,%eax
  jbe    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay(void) {
  volatile unsigned int j;
  for (j = 0; j < 50000; j++)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<delay>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0xc34f,%eax
  ja     L18
L5:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0xc34f,%eax
  jbe    L5
L18:
  ret
```

assistant: ```c
void delay(void) {
  volatile unsigned int j;
  for (j = 0; j < 50000; j++)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<delay>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0xc34f,%eax
  ja     L11
  nopw   0x0(%rax,%rax,1)
L15:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0xc34f,%eax
  jbe    L15
L11:
  ret
```

assistant: ```c
void delay(void) {
  volatile unsigned int j;
  for (j = 0; j < 50000; j++)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<delay>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0xc34f,%eax
  ja     L2
  nopw   0x0(%rax,%rax,1)
L16:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0xc34f,%eax
  jbe    L16
L2:
  ret
```

assistant: ```c
void delay(void) {
  volatile unsigned int j;
  for (j = 0; j < 50000; j++)
    ;
}
```