ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%edi
  call   <abs@plt>
  cmp    %rax,%rbx
  jge    L30
  lea    D26(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L30:
  mov    (%rsp),%edi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%edi
  call   <abs@plt>
  cmp    %rax,%rbx
  jle    L36
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L36:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D27
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string

tool: D7: %d %d

tool: D26: Ant


tool: D27: Bug


tool: D6: Draw


assistant: ```c
int main(void) {
  int ant, bug;
  scanf("%d %d", &ant, &bug);
  if (abs(ant) < abs(bug)) {
    printf("Ant\n");
  } else if (abs(ant) > abs(bug)) {
    printf("Bug\n");
  } else {
    printf("Draw\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edi
  call   <abs@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%rbx
  call   <abs@plt>
  cmp    %rax,%rbx
  jge    L17
  lea    D5(%rip),%rdi
  call   <printf@plt>
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L17:
  mov    (%rsp),%edi
  call   <abs@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%rbx
  call   <abs@plt>
  cmp    %rax,%rbx
  jle    L19
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L19:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string

tool: D10: %d %d

tool: D5: Ant


tool: D39: Bug


tool: D26: Draw


assistant: ```c
int main(void) {
  int ant, bug;
  scanf("%d %d", &ant, &bug);
  if (abs(ant) < abs(bug)) {
    printf("Ant\n");
  } else if (abs(ant) > abs(bug)) {
    printf("Bug\n");
  } else {
    printf("Draw\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D16(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edi
  call   <abs@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%rbx
  call   <abs@plt>
  cmp    %rax,%rbx
  jge    L24
  lea    D14(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L24:
  mov    (%rsp),%edi
  call   <abs@plt>
  mov    0x4(%rsp),%edi
  mov    %rax,%rbx
  call   <abs@plt>
  cmp    %rax,%rbx
  jle    L10
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L10:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D34
type: string
name: extract_symbolic_data
arguments: data_label: D23
type: string

tool: D16: %d %d

tool: D14: Ant


tool: D34: Bug


tool: D23: Draw


assistant: ```c
int main(void) {
  int ant, bug;
  scanf("%d %d", &ant, &bug);
  if (abs(ant) < abs(bug)) {
    printf("Ant\n");
  } else if (abs(ant) > abs(bug)) {
    printf("Bug\n");
  } else {
    printf("Draw\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,%edx
  jne    L1
  mov    %eax,%ecx
  sar    $0x18,%ecx
  movzbl %ah,%edx
  shl    $0x18,%edx
  and    $0xffffff,%eax
  or     %eax,%edx
  mov    %cl,%dh
L1:
  add    $0x5c2969f6,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[local1] += state[local1];
        }
      } else if (state[0UL] < local1) {
        state[local1] += state[local1];
      } else {
        copy12 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 245604622UL) + 1300613352U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  add    $0x5c2969f6,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[local1] += state[local1];
        }
      } else if (state[0UL] < local1) {
        state[local1] += state[local1];
      } else {
        copy12 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 245604622UL) + 1300613352U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  add    $0x5c2969f6,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[local1] += state[local1];
        }
      } else if (state[0UL] < local1) {
        state[local1] += state[local1];
      } else {
        copy12 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 245604622UL) + 1300613352U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfd8(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%ebp
  cmpl   $0x0,0x14(%rsp)
  jne    L46
L81:
  mov    0xfd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0xfe8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L144:
  mov    0x14(%rsp),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jle    L34
L114:
  mov    %r12d,%edi
  sub    0x1c(%rsp),%edi
  call   <abs@plt>
  mov    %rax,%rbp
  mov    0x20(%rsp,%rbx,4),%eax
  add    0x0(%r13),%eax
  mov    0x1c(%rsp),%edi
  sub    %eax,%edi
  call   <abs@plt>
  cmp    %rax,%rbp
  jle    L144
  mov    0x20(%rsp,%rbx,4),%r12d
  add    0x0(%r13),%r12d
  jmp    L144
L34:
  add    $0x1,%r14
  add    $0x4,%r13
  lea    -0x1(%r14),%edx
  cmp    %edx,%eax
  jle    L37
L92:
  cmp    %r14d,0x14(%rsp)
  jle    L37
  mov    %r14,%rbx
  jmp    L114
L37:
  mov    %r12d,%edx
  mov    0x1c(%rsp),%esi
  lea    D60(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r15d
  cmp    %r15d,0x18(%rsp)
  jl     L94
L121:
  mov    (%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L37
  lea    0x20(%rsp),%r13
  mov    $0x1,%r14d
  jmp    L92
L94:
  lea    0x14(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  je     L81
  mov    0xc(%rsp),%ebp
L46:
  lea    0x20(%rsp),%r12
  mov    $0x0,%ebx
  cmpl   $0x0,0x14(%rsp)
  jle    L24
L139:
  mov    %r12,%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,0x14(%rsp)
  jg     L139
L24:
  lea    0x18(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  lea    0x1(%rbp),%eax
  mov    %eax,0xc(%rsp)
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x18(%rsp)
  jle    L94
  mov    $0x4000000,%r12d
  mov    $0x1,%r15d
  lea    0x1c(%rsp),%rax
  mov    %rax,(%rsp)
  jmp    L121
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type_guessed: string
name: unpack_data
arguments: tag: D60
type_guessed: string
name: unpack_data
arguments: tag: D40
type_guessed: string
name: unpack_data
arguments: tag: D22
type_guessed: string

tool: D12: %d


tool: D60: Closest sum to %d is %d.


tool: D40:  %d

tool: D22: Case %d:


assistant: ```c
int main(void) {
  int i, n, m, num[1005], t;
  scanf("%d\n", &n);
  t = 1;
  while (0 != n) {
    for (i = 0; i < n; i++)
      scanf(" %d", &num[i]);
    int q, k, m, dif, s;
    dif = (1 << 26);
    scanf("%d\n", &q);
    printf("Case %d:\n", t++);
    for (i = 1; i <= q; i++) {
      scanf("%d\n", &s);
      for (k = 0; k < n; k++)
        for (m = k + 1; m < n; m++)
          if (abs(dif - s) > abs(s - (num[k] + num[m])))
            dif = (num[k] + num[m]);
      printf("Closest sum to %d is %d.\n", s, dif);
    }
    scanf("%d\n", &n);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ram_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D49(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    D17(%rip),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L25
L30:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
L25:
  mov    D1(%rip),%rax
  cmp    %rax,-0x10(%rbp)
  jb     L30
  mov    D31(%rip),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L38
L21:
  mov    -0x10(%rbp),%rax
  movq   $0x0,(%rax)
  addq   $0x8,-0x10(%rbp)
L38:
  mov    D11(%rip),%rax
  cmp    %rax,-0x10(%rbp)
  jb     L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ram_init() {
  extern long __end_of_text__;
  extern long __data_start__, __data_end__;
  extern long __bss_start__, __bss_end__;
  long *src = &__end_of_text__;
  long *dst = &__data_start__;
  while (dst < &__data_end__)
    *dst = *src;
  for (dst = &__bss_start__; dst < &__bss_end__; dst++)
    *dst = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ram_init>:
  endbr64
  mov    D30(%rip),%rax
  cmp    %rax,D74(%rip)
  jae    L26
  mov    D22(%rip),%rax
  mov    (%rax),%rcx
  mov    D74(%rip),%rdx
  mov    D30(%rip),%rax
L1:
  cmp    %rax,%rdx
  jb     L1
  mov    D74(%rip),%rax
  mov    %rcx,(%rax)
L26:
  mov    D43(%rip),%rax
  cmp    %rax,D72(%rip)
  jae    L16
  lea    -0x1(%rax),%rdx
  mov    D72(%rip),%rax
  sub    %rax,%rdx
  shr    $0x3,%rdx
  lea    0x8(%rax,%rdx,8),%rdx
L29:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L29
L16:
  ret
```

assistant: ```c
void ram_init() {
  extern long __end_of_text__;
  extern long __data_start__, __data_end__;
  extern long __bss_start__, __bss_end__;
  long *src = &__end_of_text__;
  long *dst = &__data_start__;
  while (dst < &__data_end__)
    *dst = *src;
  for (dst = &__bss_start__; dst < &__bss_end__; dst++)
    *dst = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ram_init>:
  endbr64
  mov    D33(%rip),%rax
  cmp    %rax,D11(%rip)
  jae    L28
L8:
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    D36(%rip),%rdi
  mov    D20(%rip),%rax
  cmp    %rax,%rdi
  jae    L15
  sub    $0x1,%rax
  xor    %esi,%esi
  sub    %rdi,%rax
  shr    $0x3,%rax
  lea    0x8(,%rax,8),%rdx
  jmp    1050 <memset@plt>
  nopl   (%rax)
L15:
  ret
```

assistant: ```c
void ram_init() {
  extern long __end_of_text__;
  extern long __data_start__, __data_end__;
  extern long __bss_start__, __bss_end__;
  long *src = &__end_of_text__;
  long *dst = &__data_start__;
  while (dst < &__data_end__)
    *dst = *src;
  for (dst = &__bss_start__; dst < &__bss_end__; dst++)
    *dst = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ram_init>:
  endbr64
  mov    D30(%rip),%rax
  cmp    %rax,D20(%rip)
  jae    L23
L17:
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    D16(%rip),%rdi
  mov    D38(%rip),%rax
  cmp    %rax,%rdi
  jae    L16
  sub    $0x1,%rax
  xor    %esi,%esi
  sub    %rdi,%rax
  shr    $0x3,%rax
  lea    0x8(,%rax,8),%rdx
  jmp    1050 <memset@plt>
  nopl   (%rax)
L16:
  ret
```

assistant: ```c
void ram_init() {
  extern long __end_of_text__;
  extern long __data_start__, __data_end__;
  extern long __bss_start__, __bss_end__;
  long *src = &__end_of_text__;
  long *dst = &__data_start__;
  while (dst < &__data_end__)
    *dst = *src;
  for (dst = &__bss_start__; dst < &__bss_end__; dst++)
    *dst = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<curmod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  cmp    %edx,%eax
  jle    L29
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L17
L29:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L17
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L17:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void curmod(const int change, int *current, const u_int max_current) {
  *current += change;
  if (*current > (int)max_current) {
    *current = 0;
  } else if (*current < 0) {
    *current = (int)max_current;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<curmod>:
  endbr64
  add    (%rsi),%edi
  cmp    %edx,%edi
  jle    L3
  movl   $0x0,(%rsi)
  ret
L3:
  test   %edi,%edi
  cmovs  %edx,%edi
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void curmod(const int change, int *current, const u_int max_current) {
  *current += change;
  if (*current > (int)max_current) {
    *current = 0;
  } else if (*current < 0) {
    *current = (int)max_current;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<curmod>:
  endbr64
  add    (%rsi),%edi
  cmp    %edx,%edi
  jle    L3
  movl   $0x0,(%rsi)
  ret
  nopl   0x0(%rax)
L3:
  test   %edi,%edi
  cmovs  %edx,%edi
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void curmod(const int change, int *current, const u_int max_current) {
  *current += change;
  if (*current > (int)max_current) {
    *current = 0;
  } else if (*current < 0) {
    *current = (int)max_current;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<curmod>:
  endbr64
  add    (%rsi),%edi
  cmp    %edx,%edi
  jle    L7
  movl   $0x0,(%rsi)
  ret
  nopl   0x0(%rax)
L7:
  test   %edi,%edi
  cmovs  %edx,%edi
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void curmod(const int change, int *current, const u_int max_current) {
  *current += change;
  if (*current > (int)max_current) {
    *current = 0;
  } else if (*current < 0) {
    *current = (int)max_current;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<localtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  leave
  ret
```

assistant: ```c
struct tm *localtime(const time_t *timer) {
  static struct tm tm;
  return localtime_r(timer, &tm);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<localtime>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <localtime_r@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct tm *localtime(const time_t *timer) {
  static struct tm tm;
  return localtime_r(timer, &tm);
}
```
user: Translate the below assembly code into C programming language:

```asm
<localtime>:
  endbr64
  lea    D2(%rip),%rsi
  jmp    1050 <localtime_r@plt>
```

assistant: ```c
struct tm *localtime(const time_t *timer) {
  static struct tm tm;
  return localtime_r(timer, &tm);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<localtime>:
  endbr64
  lea    D3(%rip),%rsi
  jmp    1050 <localtime_r@plt>
```

assistant: ```c
struct tm *localtime(const time_t *timer) {
  static struct tm tm;
  return localtime_r(timer, &tm);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L20
L16:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L20
  subl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x0,-0x8(%rbp)
  jns    L16
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x >= 0) {
    x = x + y;
    if (y >= 0) {
      y = y - 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  js     L19
L10:
  add    %eax,%ebx
  cmp    $0x80000000,%eax
  sbb    $0x0,%eax
  test   %ebx,%ebx
  jns    L10
L19:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x >= 0) {
    x = x + y;
    if (y >= 0) {
      y = y - 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  js     L7
  nopl   0x0(%rax)
L3:
  add    %eax,%ebx
  cmp    $0x80000000,%eax
  sbb    $0x0,%eax
  test   %ebx,%ebx
  jns    L3
L7:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x >= 0) {
    x = x + y;
    if (y >= 0) {
      y = y - 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  js     L23
  nopl   0x0(%rax)
L27:
  add    %eax,%ebx
  test   %eax,%eax
  js     L31
  sub    $0x1,%eax
  test   %ebx,%ebx
  jns    L27
L23:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L31:
  test   %ebx,%ebx
  js     L23
L46:
  add    %eax,%ebx
  jns    L46
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x >= 0) {
    x = x + y;
    if (y >= 0) {
      y = y - 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L32:
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L29:
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0x18,-0x8(%rbp)
  jle    L29
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x13,-0x4(%rbp)
  jle    L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f(int i, int j) {
#pragma acc kernels
#pragma acc loop collapse(2)
  for (i = 0; i < 20; ++i)
    for (j = 0; j < 25; ++j)
      ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f>:
  endbr64
  mov    $0x14,%edx
L4:
  mov    $0x19,%eax
L2:
  sub    $0x1,%eax
  jne    L2
  sub    $0x1,%edx
  jne    L4
  ret
```

assistant: ```c
void f(int i, int j) {
#pragma acc kernels
#pragma acc loop collapse(2)
  for (i = 0; i < 20; ++i)
    for (j = 0; j < 25; ++j)
      ;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int i, int j) {
#pragma acc kernels
#pragma acc loop collapse(2)
  for (i = 0; i < 20; ++i)
    for (j = 0; j < 25; ++j)
      ;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int i, int j) {
#pragma acc kernels
#pragma acc loop collapse(2)
  for (i = 0; i < 20; ++i)
    for (j = 0; j < 25; ++j)
      ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L16:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x33af3e2f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  imul   $0x13d,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hash_index(char *text) {
  int i, h = 0;
  for (i = 0; text[i] != '\0'; i++)
    h = (h * 36 + text[i]) % 317;
  return h;
}
```