user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D59(%rip),%rdi
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    D51(%rip),%r13
  push   %r12
  lea    D57(%rip),%r12
  push   %rbp
  lea    D21(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    0xc(%rsp),%r15
  movl   $0x636261,0x14(%rsp)
  mov    %rsi,%rdx
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movb   $0x61,0x15(%rsp)
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D41(%rip),%rdi
  movl   $0x63,0xc(%rsp)
  call   <puts@plt>
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D59
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D51
type_guessed: string
name: unpack_data
arguments: label: D57
type_guessed: string
name: unpack_data
arguments: label: D21
type_guessed: string
name: unpack_data
arguments: label: D28
type_guessed: string
name: unpack_data
arguments: label: D41
type_guessed: string
name: unpack_data
arguments: label: D4
type_guessed: string

tool: D59: val = %s , str = %s


tool: D9: address ptr %p


tool: D51: value   ptr %i


tool: D57: x       ptr %i


tool: D21: y       ptr %i


tool: D28: ptr is x

tool: D41: ptr set 99

tool: D4: ptr is y

assistant: ```c
int main() {
  int x = 4;
  int y = 5;
  int *ptr = &x;
  char val[] = "abc";
  char *pptr;
  pptr = val;
  val[1] = val[0];
  printf("val = %s , str = %s\n", val, pptr);
  printf("ptr is x\n");
  printf("address ptr %p\n", ptr);
  printf("value   ptr %i\n", *ptr);
  printf("x       ptr %i\n", x);
  printf("y       ptr %i\n", y);
  *ptr = 99;
  printf("ptr set 99\n");
  printf("address ptr %p\n", ptr);
  printf("value   ptr %i\n", *ptr);
  printf("x       ptr %i\n", x);
  printf("y       ptr %i\n", y);
  ptr = &y;
  printf("ptr is y\n");
  printf("address ptr %p\n", ptr);
  printf("value   ptr %i\n", *ptr);
  printf("x       ptr %i\n", x);
  printf("y       ptr %i\n", y);
}
```