ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<mirrorV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L17:
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L31:
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L31
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L17
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mirrorV(int w, int h, char *pattern, char *result) {
  for (int y = 0; y < h; y++)
    for (int x = 0; x < w; x++)
      result[x + y * w] = pattern[w - x - 1 + y * w];
  result[w * h] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mirrorV>:
  endbr64
  mov    %edi,%r9d
  mov    %esi,%r10d
  mov    %rcx,%r11
  test   %esi,%esi
  jle    L23
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x0,%r8d
  mov    $0x0,%edi
  movslq %r9d,%rbp
  sub    $0x1,%rbp
  lea    -0x1(%r9),%eax
  lea    0x1(%rcx,%rax,1),%r12
  jmp    L31
L2:
  movslq %r8d,%rsi
  lea    0x0(%rbp,%rsi,1),%rdx
  add    %rbx,%rdx
  lea    (%r11,%rsi,1),%rax
  add    %r12,%rsi
L53:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L53
L25:
  add    $0x1,%edi
  add    %r9d,%r8d
  cmp    %edi,%r10d
  je     L49
L31:
  test   %r9d,%r9d
  jg     L2
  jmp    L25
L49:
  imul   %r9d,%r10d
  movslq %r10d,%rax
  movb   $0x0,(%r11,%rax,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  imul   %edi,%r10d
  movslq %r10d,%rax
  movb   $0x0,(%rcx,%rax,1)
  ret
```

assistant: ```c
void mirrorV(int w, int h, char *pattern, char *result) {
  for (int y = 0; y < h; y++)
    for (int x = 0; x < w; x++)
      result[x + y * w] = pattern[w - x - 1 + y * w];
  result[w * h] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mirrorV>:
  endbr64
  mov    %edi,%r9d
  mov    %esi,%r10d
  mov    %rcx,%r11
  test   %esi,%esi
  jle    L8
  push   %r12
  lea    -0x1(%r9),%eax
  xor    %r8d,%r8d
  xor    %edi,%edi
  push   %rbp
  movslq %r9d,%rbp
  lea    0x1(%rcx,%rax,1),%r12
  push   %rbx
  sub    $0x1,%rbp
  mov    %rdx,%rbx
  nopl   (%rax)
L20:
  test   %r9d,%r9d
  jle    L16
  movslq %r8d,%rsi
  lea    0x0(%rbp,%rsi,1),%rdx
  lea    (%r11,%rsi,1),%rax
  add    %r12,%rsi
  add    %rbx,%rdx
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L14
L16:
  add    $0x1,%edi
  add    %r9d,%r8d
  cmp    %edi,%r10d
  jne    L20
  imul   %r9d,%r10d
  pop    %rbx
  pop    %rbp
  pop    %r12
  movslq %r10d,%rax
  movb   $0x0,(%r11,%rax,1)
  ret
L8:
  imul   %edi,%r10d
  movslq %r10d,%rax
  movb   $0x0,(%rcx,%rax,1)
  ret
```

assistant: ```c
void mirrorV(int w, int h, char *pattern, char *result) {
  for (int y = 0; y < h; y++)
    for (int x = 0; x < w; x++)
      result[x + y * w] = pattern[w - x - 1 + y * w];
  result[w * h] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mirrorV>:
  endbr64
  push   %rbp
  mov    %esi,%r10d
  mov    %rcx,%rbp
  push   %rbx
  mov    %edi,%ebx
  test   %esi,%esi
  jle    L22
  test   %edi,%edi
  jle    L22
  movslq %edi,%r11
  lea    -0x1(%rdi),%ecx
  xor    %r8d,%r8d
  lea    -0x1(%rdx,%r11,1),%r9
  lea    0x1(%rbp,%rcx,1),%rdi
  nopl   0x0(%rax)
L2:
  mov    %rdi,%rax
  mov    %r9,%rdx
  sub    %rcx,%rax
  sub    $0x1,%rax
  nopl   (%rax)
L0:
  movzbl (%rdx),%esi
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %sil,-0x1(%rax)
  cmp    %rdi,%rax
  jne    L0
  add    $0x1,%r8d
  add    %r11,%r9
  add    %r11,%rdi
  cmp    %r8d,%r10d
  jne    L2
L22:
  imul   %ebx,%r10d
  pop    %rbx
  movslq %r10d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  pop    %rbp
  ret
```

assistant: ```c
void mirrorV(int w, int h, char *pattern, char *result) {
  for (int y = 0; y < h; y++)
    for (int x = 0; x < w; x++)
      result[x + y * w] = pattern[w - x - 1 + y * w];
  result[w * h] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fx@plt>
  movsd  -0x8(%rbp),%xmm0
  ucomisd D16(%rip),%xmm0
  jp     L11
  movsd  -0x8(%rbp),%xmm0
  ucomisd D16(%rip),%xmm0
  je     L5
L11:
  mov    $0x0,%eax
  call   <foo@plt>
L5:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
data_type: f32[2]

tool: {"D16": [0.0,2.125]}

assistant: ```c
int main() {
  double a = 0, fx(double), foo();
  fx(a);
  if (a != 3)
    foo();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <fx@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  double a = 0, fx(double), foo();
  fx(a);
  if (a != 3)
    foo();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <fx@plt>
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  double a = 0, fx(double), foo();
  fx(a);
  if (a != 3)
    foo();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  call   <fx@plt>
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  double a = 0, fx(double), foo();
  fx(a);
  if (a != 3)
    foo();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0xa,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0xa,(%rax)
  cmpq   $0x0,-0x10(%rbp)
  jne    L33
  mov    $0xffffffff,%edi
  call   <exit@plt>
L33:
  mov    -0x8(%rbp),%rax
  movl   $0xf,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0xf,(%rax)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  mov    $0xffffffff,%edi
  call   <exit@plt>
L24:
  mov    -0x8(%rbp),%rax
  movl   $0x14,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x14,(%rax)
  cmpl   $0x0,-0x14(%rbp)
  je     L15
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movl   $0x1e,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x1e,(%rax)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0x14(%rbp)
  je     L17
  cmpq   $0x0,-0x8(%rbp)
  je     L58
  cmpq   $0x0,-0x10(%rbp)
  jne    L17
L58:
  mov    $0xffffffff,%edi
  call   <exit@plt>
L17:
  mov    $0x0,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movl   $0x28,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x28,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: ???

assistant: ```c
int main(void) {
  int *v, *u, r;
  u = (int *)malloc(sizeof(*u));
  v = (int *)malloc(sizeof(*v));
  *u = 10;
  *v = 10;
  if (v == 0)
    exit(-1);
  *u = 15;
  *v = 15;
  if (u == 0)
    exit(-1);
  *u = 20;
  *v = 20;
  if (r) {
    u = (int *)malloc(sizeof(*u));
    v = (int *)malloc(sizeof(*v));
  }
  *u = 30;
  *v = 30;
  printf("???");
  if (r) {
    if (u == 0 || v == 0)
      exit(-1);
  }
  assert(0);
  *u = 40;
  *v = 40;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0xa,0x0(%rbp)
  movl   $0xa,(%rax)
  test   %rax,%rax
  je     L35
L12:
  movl   $0xf,0x0(%rbp)
  movl   $0xf,(%rbx)
  test   %rbp,%rbp
  je     L2
L4:
  movl   $0x1e,0x0(%rbp)
  movl   $0x1e,(%rbx)
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  movl   $0x28,(%r12)
  movl   $0x28,(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L12
L2:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: ???

assistant: ```c
int main(void) {
  int *v, *u, r;
  u = (int *)malloc(sizeof(*u));
  v = (int *)malloc(sizeof(*v));
  *u = 10;
  *v = 10;
  if (v == 0)
    exit(-1);
  *u = 15;
  *v = 15;
  if (u == 0)
    exit(-1);
  *u = 20;
  *v = 20;
  if (r) {
    u = (int *)malloc(sizeof(*u));
    v = (int *)malloc(sizeof(*v));
  }
  *u = 30;
  *v = 30;
  printf("???");
  if (r) {
    if (u == 0 || v == 0)
      exit(-1);
  }
  assert(0);
  *u = 40;
  *v = 40;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edi
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbp
  mov    %rax,%r12
  call   <malloc@plt>
  movl   $0xa,0x0(%rbp)
  mov    %rax,%rbx
  movl   $0xa,(%rax)
  test   %rax,%rax
  je     L22
L6:
  movl   $0xf,0x0(%rbp)
  movl   $0xf,(%rbx)
  test   %rbp,%rbp
  je     L38
L18:
  movl   $0x14,0x0(%rbp)
  lea    D7(%rip),%rdi
  movl   $0x1e,(%r12)
  movl   $0x1e,(%rbx)
  call   <printf@plt>
  xor    %edi,%edi
  call   <assert@plt>
  movl   $0x28,(%r12)
  xor    %eax,%eax
  movl   $0x28,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L6
L38:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L18
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: ???

assistant: ```c
int main(void) {
  int *v, *u, r;
  u = (int *)malloc(sizeof(*u));
  v = (int *)malloc(sizeof(*v));
  *u = 10;
  *v = 10;
  if (v == 0)
    exit(-1);
  *u = 15;
  *v = 15;
  if (u == 0)
    exit(-1);
  *u = 20;
  *v = 20;
  if (r) {
    u = (int *)malloc(sizeof(*u));
    v = (int *)malloc(sizeof(*v));
  }
  *u = 30;
  *v = 30;
  printf("???");
  if (r) {
    if (u == 0 || v == 0)
      exit(-1);
  }
  assert(0);
  *u = 40;
  *v = 40;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edi
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbp
  mov    %rax,%r12
  call   <malloc@plt>
  movl   $0xa,0x0(%rbp)
  mov    %rax,%rbx
  movl   $0xa,(%rax)
  test   %rax,%rax
  je     L21
L26:
  movl   $0xf,0x0(%rbp)
  movl   $0xf,(%rbx)
  test   %rbp,%rbp
  je     L30
L32:
  movl   $0x14,0x0(%rbp)
  lea    D5(%rip),%rdi
  movl   $0x1e,(%r12)
  movl   $0x1e,(%rbx)
  call   <printf@plt>
  xor    %edi,%edi
  call   <assert@plt>
  movl   $0x28,(%r12)
  xor    %eax,%eax
  movl   $0x28,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L26
L30:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L32
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: ???

assistant: ```c
int main(void) {
  int *v, *u, r;
  u = (int *)malloc(sizeof(*u));
  v = (int *)malloc(sizeof(*v));
  *u = 10;
  *v = 10;
  if (v == 0)
    exit(-1);
  *u = 15;
  *v = 15;
  if (u == 0)
    exit(-1);
  *u = 20;
  *v = 20;
  if (r) {
    u = (int *)malloc(sizeof(*u));
    v = (int *)malloc(sizeof(*v));
  }
  *u = 30;
  *v = 30;
  printf("???");
  if (r) {
    if (u == 0 || v == 0)
      exit(-1);
  }
  assert(0);
  *u = 40;
  *v = 40;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wi_dtots>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rcx
  mov    %rdx,%rbx
  mov    %rdx,%rax
  movq   %rcx,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: f64

tool: D7: 1000000000

assistant: ```c
struct timespec wi_dtots(double d) {
  struct timespec ts;
  ts.tv_sec = (time_t)floor(d);
  ts.tv_nsec = (long)((d - ts.tv_sec) * 1000000000.0);
  return ts;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wi_dtots>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D2(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: f64

tool: D2: 1000000000

assistant: ```c
struct timespec wi_dtots(double d) {
  struct timespec ts;
  ts.tv_sec = (time_t)floor(d);
  ts.tv_nsec = (long)((d - ts.tv_sec) * 1000000000.0);
  return ts;
}
```
user: What is the c source code of the assembly code below?

```asm
<wi_dtots>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  D0(%rip),%xmm0
  add    $0x18,%rsp
  cvttsd2si %xmm0,%rax
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: f64

tool: D0: 1000000000

assistant: ```c
struct timespec wi_dtots(double d) {
  struct timespec ts;
  ts.tv_sec = (time_t)floor(d);
  ts.tv_nsec = (long)((d - ts.tv_sec) * 1000000000.0);
  return ts;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wi_dtots>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  D3(%rip),%xmm0
  add    $0x18,%rsp
  cvttsd2si %xmm0,%rax
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: f64

tool: D3: 1000000000

assistant: ```c
struct timespec wi_dtots(double d) {
  struct timespec ts;
  ts.tv_sec = (time_t)floor(d);
  ts.tv_nsec = (long)((d - ts.tv_sec) * 1000000000.0);
  return ts;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split_24bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L3
L33:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <b64_to_int@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L26
  mov    $0xffffffff,%eax
  jmp    L14
L26:
  mov    -0x8(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L33
  mov    -0xc(%rbp),%eax
  cltq
  mov    0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  cltq
  mov    -0x30(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  cltq
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int split_24bit(const char *string, uint8_t *hash, int start, int n, uint32_t b2, uint32_t b1, uint32_t b0) {
  uint32_t tmp = 0;
  int i, value;
  for (i = start; i < start + n; i++) {
    value = b64_to_int(string[i]);
    if (value < 0)
      return -1;
    tmp |= value << (6 * (i - start));
  }
  hash[b0] = (uint8_t)(tmp & 0xff);
  hash[b1] = (uint8_t)((tmp >> 8) & 0xff);
  hash[b2] = (uint8_t)((tmp >> 16) & 0xff);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<split_24bit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r14
  mov    %r8d,0xc(%rsp)
  mov    %r9d,%r15d
  lea    (%rdx,%rcx,1),%esi
  cmp    %esi,%edx
  jge    L2
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%rbx
  lea    0x1(%rdi,%rdx,1),%r13
  lea    -0x1(%rcx),%eax
  add    %rax,%r13
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L36:
  movsbl (%rbx),%edi
  call   <b64_to_int@plt>
  test   %eax,%eax
  js     L33
  mov    %ebp,%ecx
  shl    %cl,%eax
  or     %eax,%r12d
  add    $0x1,%rbx
  add    $0x6,%ebp
  cmp    %r13,%rbx
  jne    L36
L48:
  movslq 0x50(%rsp),%rax
  movzbl %r12b,%edx
  mov    %rdx,(%r14,%rax,8)
  movslq %r15d,%r15
  mov    %r12d,%eax
  movzbl %ah,%eax
  cltq
  mov    %rax,(%r14,%r15,8)
  movslq 0xc(%rsp),%rax
  sar    $0x10,%r12d
  movzbl %r12b,%r12d
  mov    %r12,(%r14,%rax,8)
  mov    $0x0,%eax
L30:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  mov    $0x0,%r12d
  jmp    L48
L33:
  mov    $0xffffffff,%eax
  jmp    L30
```

assistant: ```c
int split_24bit(const char *string, uint8_t *hash, int start, int n, uint32_t b2, uint32_t b1, uint32_t b0) {
  uint32_t tmp = 0;
  int i, value;
  for (i = start; i < start + n; i++) {
    value = b64_to_int(string[i]);
    if (value < 0)
      return -1;
    tmp |= value << (6 * (i - start));
  }
  hash[b0] = (uint8_t)(tmp & 0xff);
  hash[b1] = (uint8_t)((tmp >> 8) & 0xff);
  hash[b2] = (uint8_t)((tmp >> 16) & 0xff);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split_24bit>:
  endbr64
  push   %r15
  push   %r14
  movslq %r9d,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    (%rdx,%rcx,1),%esi
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8d,0xc(%rsp)
  cmp    %esi,%edx
  jge    L34
  movslq %edx,%rdx
  lea    -0x1(%rcx),%eax
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  lea    0x1(%rdi,%rdx,1),%rbp
  lea    (%rdi,%rdx,1),%r15
  add    %rax,%rbp
  jmp    L12
  nopl   0x0(%rax)
L13:
  mov    %r13d,%ecx
  add    $0x1,%r15
  add    $0x6,%r13d
  shl    %cl,%eax
  or     %eax,%ebx
  cmp    %r15,%rbp
  je     L26
L12:
  movsbl (%r15),%edi
  call   <b64_to_int@plt>
  test   %eax,%eax
  jns    L13
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L26:
  movzbl %bh,%eax
  movzbl %bl,%ecx
  sar    $0x10,%ebx
  cltq
  movzbl %bl,%ebx
L20:
  movslq 0xc(%rsp),%r13
  movslq 0x50(%rsp),%rdx
  mov    %rcx,(%r12,%rdx,8)
  mov    %rax,(%r12,%r14,8)
  xor    %eax,%eax
  mov    %rbx,(%r12,%r13,8)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  xor    %ebx,%ebx
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L20
```

assistant: ```c
int split_24bit(const char *string, uint8_t *hash, int start, int n, uint32_t b2, uint32_t b1, uint32_t b0) {
  uint32_t tmp = 0;
  int i, value;
  for (i = start; i < start + n; i++) {
    value = b64_to_int(string[i]);
    if (value < 0)
      return -1;
    tmp |= value << (6 * (i - start));
  }
  hash[b0] = (uint8_t)(tmp & 0xff);
  hash[b1] = (uint8_t)((tmp >> 8) & 0xff);
  hash[b2] = (uint8_t)((tmp >> 16) & 0xff);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<split_24bit>:
  endbr64
  push   %r15
  push   %r14
  movslq %r9d,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    (%rdx,%rcx,1),%esi
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8d,0xc(%rsp)
  cmp    %esi,%edx
  jge    L10
  movslq %edx,%rdx
  lea    -0x1(%rcx),%eax
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  lea    0x1(%rdi,%rdx,1),%rbp
  lea    (%rdi,%rdx,1),%r15
  add    %rax,%rbp
  jmp    L49
  nopl   0x0(%rax)
L12:
  mov    %r13d,%ecx
  add    $0x1,%r15
  add    $0x6,%r13d
  shl    %cl,%eax
  or     %eax,%ebx
  cmp    %r15,%rbp
  je     L1
L49:
  movsbl (%r15),%edi
  call   <b64_to_int@plt>
  test   %eax,%eax
  jns    L12
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L1:
  movzbl %bh,%eax
  movzbl %bl,%ecx
  sar    $0x10,%ebx
  cltq
  movzbl %bl,%ebx
L11:
  movslq 0xc(%rsp),%r13
  movslq 0x50(%rsp),%rdx
  mov    %rcx,(%r12,%rdx,8)
  mov    %rax,(%r12,%r14,8)
  xor    %eax,%eax
  mov    %rbx,(%r12,%r13,8)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  xor    %ebx,%ebx
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L11
```

assistant: ```c
int split_24bit(const char *string, uint8_t *hash, int start, int n, uint32_t b2, uint32_t b1, uint32_t b0) {
  uint32_t tmp = 0;
  int i, value;
  for (i = start; i < start + n; i++) {
    value = b64_to_int(string[i]);
    if (value < 0)
      return -1;
    tmp |= value << (6 * (i - start));
  }
  hash[b0] = (uint8_t)(tmp & 0xff);
  hash[b1] = (uint8_t)((tmp >> 8) & 0xff);
  hash[b2] = (uint8_t)((tmp >> 16) & 0xff);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<push_stack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,%eax
  mov    %al,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  cmpl   $0x7f,-0xc(%rbp)
  jle    L4
  movl   $0x0,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x10(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int push_stack(char *stack, int top, char ch) {
  top++;
  if (top >= 128) {
    top = 0;
  }
  stack[top] = ch;
  return top;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<push_stack>:
  endbr64
  mov    %edx,%ecx
  lea    0x1(%rsi),%eax
  cmp    $0x80,%eax
  mov    $0x0,%edx
  cmovge %edx,%eax
  movslq %eax,%rdx
  mov    %cl,(%rdi,%rdx,1)
  ret
```

assistant: ```c
int push_stack(char *stack, int top, char ch) {
  top++;
  if (top >= 128) {
    top = 0;
  }
  stack[top] = ch;
  return top;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<push_stack>:
  endbr64
  lea    0x1(%rsi),%eax
  cmp    $0x7f,%eax
  jg     L4
  movslq %eax,%rcx
  add    %rcx,%rdi
  mov    %dl,(%rdi)
  ret
  nopl   (%rax)
L4:
  mov    %dl,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int push_stack(char *stack, int top, char ch) {
  top++;
  if (top >= 128) {
    top = 0;
  }
  stack[top] = ch;
  return top;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<push_stack>:
  endbr64
  lea    0x1(%rsi),%eax
  cmp    $0x7f,%eax
  jg     L3
  movslq %eax,%rcx
  add    %rcx,%rdi
  mov    %dl,(%rdi)
  ret
  nopl   (%rax)
L3:
  mov    %dl,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int push_stack(char *stack, int top, char ch) {
  top++;
  if (top >= 128) {
    top = 0;
  }
  stack[top] = ch;
  return top;
}
```