ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D45(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
  cs nopw 0x0(%rax,%rax,1)
L36:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0xa,%ebx
  jne    L36
  lea    0x28(%r12),%rsi
  mov    %r12,%rax
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L94
  nopl   0x0(%rax)
L14:
  movslq %ebx,%rcx
  add    $0x4,%rax
  add    $0x1,%ebx
  mov    %edx,(%rsp,%rcx,4)
  cmp    %rsi,%rax
  je     L65
L94:
  mov    (%rax),%edx
  test   %edx,%edx
  jg     L14
  movslq %ebp,%rcx
  add    $0x4,%rax
  add    $0x1,%ebp
  mov    %edx,0x30(%rsp,%rcx,4)
  cmp    %rsi,%rax
  jne    L94
L65:
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  je     L13
  lea    -0x1(%rbx),%eax
  lea    0x4(%r12),%rbx
  lea    (%rbx,%rax,4),%r14
  lea    D39(%rip),%r13
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x4,%rbx
L32:
  mov    (%r12),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rbx,%r12
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L39
L13:
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L91
  lea    -0x1(%rbp),%eax
  lea    0x30(%rsp),%rbx
  lea    0x34(%rsp,%rax,4),%rbp
  lea    D39(%rip),%r13
L108:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L108
L91:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string
name: parse_data
arguments: label: D45
type_guessed: string
name: parse_data
arguments: label: D14
type_guessed: string
name: parse_data
arguments: label: D39
type_guessed: string
name: parse_data
arguments: label: D28
type_guessed: string

tool: D1: entre com o A[%d]: 

tool: D45: %d

tool: D14: 
vetor A: 

tool: D39:  %d 

tool: D28: 
vetor B: 

assistant: ```c
int main() {
  int a[10], b[10], i, aux = 0, aux2 = 0;
  for (i = 0; i < 10; i++) {
    printf("entre com o A[%d]: ", i + 1);
    scanf("%d", &a[i]);
  }
  for (i = 0; i < 10; i++) {
    if (a[i] <= 0) {
      b[aux] = a[i];
      aux++;
    } else {
      a[aux2] = a[i];
      aux2++;
    }
  }
  printf("\nvetor A: ");
  for (i = 0; i < aux2; i++)
    printf(" %d ", a[i]);
  printf("\nvetor B: ");
  for (i = 0; i < aux; i++)
    printf(" %d ", b[i]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L45
L47:
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x3,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x3(%rax),%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x2,-0x10(%rbp)
L45:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L47
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L26:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L26
  mov    -0xc(%rbp),%eax
  lea    0x2b2feb28(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] + 724560680UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%r8d
  test   %r8d,%r8d
  je     L13
  mov    $0x0,%edx
  lea    0x4(%rsp),%r9
L2:
  mov    %edx,%eax
  lea    (%r9,%rax,4),%rax
  movzbl (%rax),%ecx
  movzbl 0x3(%rax),%edi
  mov    %dil,(%rax)
  mov    %cl,0x3(%rax)
  add    $0x2,%edx
  cmp    %r8d,%edx
  jb     L2
  shll   0x4(%rsp)
L13:
  mov    0x4(%rsp),%eax
  add    $0x2b2feb28,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] + 724560680UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  mov    %eax,0x4(%rsp)
  test   %r8d,%r8d
  je     L2
  xor    %edx,%edx
  lea    0x4(%rsp),%r9
  nopl   0x0(%rax)
L13:
  mov    %edx,%eax
  add    $0x2,%edx
  lea    (%r9,%rax,4),%rax
  movzbl (%rax),%ecx
  movzbl 0x3(%rax),%edi
  mov    %cl,0x3(%rax)
  mov    %dil,(%rax)
  cmp    %r8d,%edx
  jb     L13
  mov    0x4(%rsp),%eax
  add    %eax,%eax
L2:
  add    $0x2b2feb28,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] + 724560680UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  mov    %eax,0x4(%rsp)
  test   %r8d,%r8d
  je     L22
  xor    %edx,%edx
  lea    0x4(%rsp),%r9
  nopl   0x0(%rax)
L27:
  mov    %edx,%eax
  add    $0x2,%edx
  lea    (%r9,%rax,4),%rax
  movzbl (%rax),%ecx
  movzbl 0x3(%rax),%edi
  mov    %cl,0x3(%rax)
  mov    %dil,(%rax)
  cmp    %r8d,%edx
  jb     L27
  mov    0x4(%rsp),%eax
  add    %eax,%eax
L22:
  add    $0x2b2feb28,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] + 724560680UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x28(%rbp)
  movss  D63(%rip),%xmm0
  movss  %xmm0,-0x24(%rbp)
  movsd  D65(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movb   $0x41,-0x29(%rbp)
  movl   $0x6e616e41,-0x16(%rbp)
  movw   $0x64,-0x12(%rbp)
  movabs $0x7261686179654a,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd -0x24(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsbl -0x29(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x16(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl -0x29(%rbp),%edx
  lea    -0x10(%rbp),%rcx
  lea    -0x16(%rbp),%rax
  mov    %rax,%rsi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D63
type_infered: byte[4]
name: parse_data
arguments: label: D65
type_infered: f64
name: parse_data
arguments: label: D36
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D57
type_infered: string
name: parse_data
arguments: label: D53
type_infered: string
name: parse_data
arguments: label: D79
type_infered: string

tool: {"D63": [0x7b,0x14,0x16,0x40]}

tool: D65: 56789.4532

tool: D36: You are %d miles away. 


tool: D19: you have %f levels of power. 


tool: D13: You have %f awesome super powers


tool: D23: I have an initial %c.


tool: D57: I have a first name %s. 


tool: D53: I have a last name %s. 


tool: D79: My full name is %c %s. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Anand";
  char last_name[] = "Jeyahar";
  printf("You are %d miles away. \n", distance);
  printf("you have %f levels of power. \n", power);
  printf("You have %f awesome super powers\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name %s. \n", first_name);
  printf("I have a last name %s. \n", last_name);
  printf("My full name is %c %s. %s.\n", first_name, initial, last_name);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x6e616e41,0xa(%rsp)
  movw   $0x64,0xe(%rsp)
  movabs $0x7261686179654a,%rax
  mov    %rax,0x10(%rsp)
  mov    $0x64,%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D41(%rip),%xmm0
  lea    D49(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  D81(%rip),%xmm0
  lea    D50(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xa(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D83(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rcx
  mov    $0x41,%edx
  mov    %rbx,%rsi
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D31
type_guessed: string
name: retrieve_data
arguments: data_label: D41
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D49
type_guessed: string
name: retrieve_data
arguments: data_label: D81
type_guessed: f64
name: retrieve_data
arguments: data_label: D50
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D38
type_guessed: string
name: retrieve_data
arguments: data_label: D83
type_guessed: string
name: retrieve_data
arguments: data_label: D64
type_guessed: string

tool: D31: You are %d miles away. 


tool: {"D41": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D49: you have %f levels of power. 


tool: D81: 56789.4532

tool: D50: You have %f awesome super powers


tool: D4: I have an initial %c.


tool: D38: I have a first name %s. 


tool: D83: I have a last name %s. 


tool: D64: My full name is %c %s. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Anand";
  char last_name[] = "Jeyahar";
  printf("You are %d miles away. \n", distance);
  printf("you have %f levels of power. \n", power);
  printf("You have %f awesome super powers\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name %s. \n", first_name);
  printf("I have a last name %s. \n", last_name);
  printf("My full name is %c %s. %s.\n", first_name, initial, last_name);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D81(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x64,%eax
  movl   $0x6e616e41,0xa(%rsp)
  lea    0xa(%rsp),%rbp
  mov    %ax,0xe(%rsp)
  lea    0x10(%rsp),%r12
  movabs $0x7261686179654a,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D18(%rip),%xmm0
  mov    $0x1,%eax
  lea    D52(%rip),%rdi
  call   <printf@plt>
  movsd  D55(%rip),%xmm0
  mov    $0x1,%eax
  lea    D73(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D89(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    $0x41,%edx
  mov    %rbp,%rsi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D81
datatype: string
name: parse_data
arguments: tag: D18
datatype: byte[8]
name: parse_data
arguments: tag: D52
datatype: string
name: parse_data
arguments: tag: D55
datatype: f64
name: parse_data
arguments: tag: D73
datatype: string
name: parse_data
arguments: tag: D61
datatype: string
name: parse_data
arguments: tag: D89
datatype: string
name: parse_data
arguments: tag: D49
datatype: string
name: parse_data
arguments: tag: D39
datatype: string

tool: D81: You are %d miles away. 


tool: {"D18": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D52: you have %f levels of power. 


tool: D55: 56789.4532

tool: D73: You have %f awesome super powers


tool: D61: I have an initial %c.


tool: D89: I have a first name %s. 


tool: D49: I have a last name %s. 


tool: D39: My full name is %c %s. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Anand";
  char last_name[] = "Jeyahar";
  printf("You are %d miles away. \n", distance);
  printf("you have %f levels of power. \n", power);
  printf("You have %f awesome super powers\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name %s. \n", first_name);
  printf("I have a last name %s. \n", last_name);
  printf("My full name is %c %s. %s.\n", first_name, initial, last_name);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D6(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x64,%eax
  movl   $0x6e616e41,0xa(%rsp)
  lea    0xa(%rsp),%rbp
  mov    %ax,0xe(%rsp)
  lea    0x10(%rsp),%r12
  movabs $0x7261686179654a,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D20(%rip),%xmm0
  mov    $0x1,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  movsd  D25(%rip),%xmm0
  mov    $0x1,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D71(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    $0x41,%edx
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: byte[8]
name: retrieve_data
arguments: tag: D31
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: f64
name: retrieve_data
arguments: tag: D22
data_type: string
name: retrieve_data
arguments: tag: D56
data_type: string
name: retrieve_data
arguments: tag: D71
data_type: string
name: retrieve_data
arguments: tag: D57
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string

tool: D6: You are %d miles away. 


tool: {"D20": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D31: you have %f levels of power. 


tool: D25: 56789.4532

tool: D22: You have %f awesome super powers


tool: D56: I have an initial %c.


tool: D71: I have a first name %s. 


tool: D57: I have a last name %s. 


tool: D3: My full name is %c %s. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Anand";
  char last_name[] = "Jeyahar";
  printf("You are %d miles away. \n", distance);
  printf("you have %f levels of power. \n", power);
  printf("You have %f awesome super powers\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name %s. \n", first_name);
  printf("I have a last name %s. \n", last_name);
  printf("My full name is %c %s. %s.\n", first_name, initial, last_name);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<config_weechat_notify_delete_option_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <config_file_option_free@plt>
  mov    $0x0,%eax
  call   <gui_buffer_notify_set_all@plt>
  mov    $0x2,%eax
  leave
  ret
```

assistant: ```c
int config_weechat_notify_delete_option_cb(const void *pointer, void *data, struct t_config_file *config_file, struct t_config_section *section, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)config_file;
  (void)section;
  config_file_option_free(option, 1);
  gui_buffer_notify_set_all();
  return 2;
}
```
user: What is the c source code of the assembly code below?

```asm
<config_weechat_notify_delete_option_cb>:
  endbr64
  sub    $0x8,%rsp
  mov    %r8,%rdi
  mov    $0x1,%esi
  call   <config_file_option_free@plt>
  mov    $0x0,%eax
  call   <gui_buffer_notify_set_all@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int config_weechat_notify_delete_option_cb(const void *pointer, void *data, struct t_config_file *config_file, struct t_config_section *section, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)config_file;
  (void)section;
  config_file_option_free(option, 1);
  gui_buffer_notify_set_all();
  return 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<config_weechat_notify_delete_option_cb>:
  endbr64
  sub    $0x8,%rsp
  mov    %r8,%rdi
  mov    $0x1,%esi
  call   <config_file_option_free@plt>
  xor    %eax,%eax
  call   <gui_buffer_notify_set_all@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int config_weechat_notify_delete_option_cb(const void *pointer, void *data, struct t_config_file *config_file, struct t_config_section *section, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)config_file;
  (void)section;
  config_file_option_free(option, 1);
  gui_buffer_notify_set_all();
  return 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<config_weechat_notify_delete_option_cb>:
  endbr64
  sub    $0x8,%rsp
  mov    %r8,%rdi
  mov    $0x1,%esi
  call   <config_file_option_free@plt>
  xor    %eax,%eax
  call   <gui_buffer_notify_set_all@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int config_weechat_notify_delete_option_cb(const void *pointer, void *data, struct t_config_file *config_file, struct t_config_section *section, struct t_config_option *option) {
  (void)pointer;
  (void)data;
  (void)config_file;
  (void)section;
  config_file_option_free(option, 1);
  gui_buffer_notify_set_all();
  return 2;
}
```