ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dotestsumAnn>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sumAnn@plt>
  mov    %rax,%rbp
  cmp    %rbx,%rax
  je     L3
  mov    %rax,%rdx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
L3:
  xor    %edi,%edi
  cmp    %rbx,%rbp
  sete   %dil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <assert@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: Error. Expected %llu
 but got %llu


assistant: ```c
void dotestsumAnn(int n, long long exp) {
  long long act = sumAnn(n);
  if (act != exp)
    printf("Error. Expected %llu\n but got %llu\n", exp, act);
  assert(act == exp);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dotestsumAnn>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sumAnn@plt>
  mov    %rax,%rbp
  cmp    %rbx,%rax
  je     L8
  mov    %rax,%rdx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
L8:
  xor    %edi,%edi
  cmp    %rbx,%rbp
  sete   %dil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <assert@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: Error. Expected %llu
 but got %llu


assistant: ```c
void dotestsumAnn(int n, long long exp) {
  long long act = sumAnn(n);
  if (act != exp)
    printf("Error. Expected %llu\n but got %llu\n", exp, act);
  assert(act == exp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<handle_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <kbhit@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  jmp    L47
L6:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x1(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <tcflush@plt>
  cmpb   $0x3,-0x1(%rbp)
  je     L32
  cmpb   $0x71,-0x1(%rbp)
  je     L32
  cmpb   $0x51,-0x1(%rbp)
  jne    L29
L32:
  mov    $0x1,%eax
  jmp    L47
L29:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <menu_handle_input@plt>
L47:
  leave
  ret
```

assistant: ```c
int handle_input(void) {
  if (!kbhit()) {
    return 0;
  }
  char c = getch();
  tcflush(STDIN_FILENO, TCIFLUSH);
  if (c == 3 || c == 'q' || c == 'Q') {
    return 1;
  }
  return menu_handle_input(c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<handle_input>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <kbhit@plt>
  test   %eax,%eax
  jne    L31
L32:
  pop    %rbx
  ret
L31:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <tcflush@plt>
  mov    %ebx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%al
  je     L0
  cmp    $0x3,%bl
  je     L0
  movsbl %bl,%edi
  call   <menu_handle_input@plt>
  jmp    L32
L0:
  mov    $0x1,%eax
  jmp    L32
```

assistant: ```c
int handle_input(void) {
  if (!kbhit()) {
    return 0;
  }
  char c = getch();
  tcflush(STDIN_FILENO, TCIFLUSH);
  if (c == 3 || c == 'q' || c == 'Q') {
    return 1;
  }
  return menu_handle_input(c);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<handle_input>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <kbhit@plt>
  test   %eax,%eax
  jne    L0
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <tcflush@plt>
  mov    %ebx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%al
  je     L10
  cmp    $0x3,%bl
  je     L10
  movsbl %bl,%edi
  pop    %rbx
  jmp    10b0 <menu_handle_input@plt>
  nop
L10:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int handle_input(void) {
  if (!kbhit()) {
    return 0;
  }
  char c = getch();
  tcflush(STDIN_FILENO, TCIFLUSH);
  if (c == 3 || c == 'q' || c == 'Q') {
    return 1;
  }
  return menu_handle_input(c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<handle_input>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <kbhit@plt>
  test   %eax,%eax
  jne    L27
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <tcflush@plt>
  mov    %ebx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%al
  je     L13
  cmp    $0x3,%bl
  je     L13
  movsbl %bl,%edi
  pop    %rbx
  jmp    10b0 <menu_handle_input@plt>
  nop
L13:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int handle_input(void) {
  if (!kbhit()) {
    return 0;
  }
  char c = getch();
  tcflush(STDIN_FILENO, TCIFLUSH);
  if (c == 3 || c == 'q' || c == 'Q') {
    return 1;
  }
  return menu_handle_input(c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1ac(%rbp)
  lea    -0x1b4(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movl   $0x0,-0x1a8(%rbp)
  jmp    L10
L62:
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1b0(%rbp),%eax
  add    $0x1,%edx
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a8(%rbp)
L10:
  mov    -0x1b4(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jl     L62
  movl   $0x1,-0x1a4(%rbp)
  jmp    L7
L66:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L0
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,-0x1ac(%rbp)
  jmp    L14
L0:
  nop
L14:
  addl   $0x1,-0x1a4(%rbp)
L7:
  cmpl   $0x64,-0x1a4(%rbp)
  jle    L66
  mov    -0x1ac(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: %d

assistant: ```c
int main() {
  int number_of_socks;
  int number_of_pairs = 0;
  scanf("%d", &number_of_socks);
  int socks[101] = {0};
  for (int i = 0; i < number_of_socks; i++) {
    int color;
    scanf("%d", &color);
    socks[color] += 1;
  }
  for (int color = 1; color < 101; color++) {
    if (socks[color] == 0)
      continue;
    number_of_pairs += socks[color] / 2;
  }
  printf("%d", number_of_pairs);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x32,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  cmpl   $0x0,0x8(%rsp)
  jle    L51
  mov    $0x0,%ebx
  lea    D14(%rip),%rbp
L12:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  addl   $0x1,0x10(%rsp,%rax,4)
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jg     L12
L51:
  lea    0x14(%rsp),%rdx
  lea    0x1a4(%rsp),%rdi
  mov    $0x0,%esi
  jmp    L44
L34:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L41
L44:
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  je     L34
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %eax,%esi
  jmp    L34
L41:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
datatype: string

tool: D14: %d

assistant: ```c
int main() {
  int number_of_socks;
  int number_of_pairs = 0;
  scanf("%d", &number_of_socks);
  int socks[101] = {0};
  for (int i = 0; i < number_of_socks; i++) {
    int color;
    scanf("%d", &color);
    socks[color] += 1;
  }
  for (int color = 1; color < 101; color++) {
    if (socks[color] == 0)
      continue;
    number_of_pairs += socks[color] / 2;
  }
  printf("%d", number_of_pairs);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  mov    0x8(%rsp),%eax
  movl   $0x0,(%rdi)
  test   %eax,%eax
  jle    L28
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  addl   $0x1,0x10(%rsp,%rax,4)
  cmp    %ebx,0x8(%rsp)
  jg     L20
L28:
  lea    0x14(%rsp),%rdx
  lea    0x1a4(%rsp),%rdi
  xor    %esi,%esi
  nopl   (%rax)
L34:
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  je     L48
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %eax,%esi
L48:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L34
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: %d

assistant: ```c
int main() {
  int number_of_socks;
  int number_of_pairs = 0;
  scanf("%d", &number_of_socks);
  int socks[101] = {0};
  for (int i = 0; i < number_of_socks; i++) {
    int color;
    scanf("%d", &color);
    socks[color] += 1;
  }
  for (int color = 1; color < 101; color++) {
    if (socks[color] == 0)
      continue;
    number_of_pairs += socks[color] / 2;
  }
  printf("%d", number_of_pairs);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  mov    0x8(%rsp),%eax
  movl   $0x0,(%rdi)
  test   %eax,%eax
  jle    L14
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  addl   $0x1,0x10(%rsp,%rax,4)
  cmp    %ebx,0x8(%rsp)
  jg     L32
L14:
  pxor   %xmm2,%xmm2
  lea    0x14(%rsp),%rax
  lea    0x1a4(%rsp),%rdx
  movdqa %xmm2,%xmm3
  nopl   0x0(%rax,%rax,1)
L21:
  movdqu (%rax),%xmm0
  movdqa %xmm3,%xmm4
  add    $0x10,%rax
  pcmpgtd %xmm0,%xmm4
  movdqa %xmm0,%xmm1
  pcmpeqd %xmm3,%xmm0
  psubd  %xmm4,%xmm1
  psrad  $0x1,%xmm1
  pandn  %xmm1,%xmm0
  paddd  %xmm0,%xmm2
  cmp    %rdx,%rax
  jne    L21
  movdqa %xmm2,%xmm0
  mov    %rbp,%rdi
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movd   %xmm2,%esi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main() {
  int number_of_socks;
  int number_of_pairs = 0;
  scanf("%d", &number_of_socks);
  int socks[101] = {0};
  for (int i = 0; i < number_of_socks; i++) {
    int color;
    scanf("%d", &color);
    socks[color] += 1;
  }
  for (int color = 1; color < 101; color++) {
    if (socks[color] == 0)
      continue;
    number_of_pairs += socks[color] / 2;
  }
  printf("%d", number_of_pairs);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %esi,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L0
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int skip_atoi(const char **c) {
  int i = 0;
  do {
    i = i * 10 + *((*c)++) - '0';
  } while (isdigit(**c));
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_atoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L6:
  mov    0x0(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x0(%rbp)
  lea    (%rbx,%rbx,4),%ecx
  movsbl (%rax),%edx
  lea    -0x30(%rdx,%rcx,2),%ebx
  movsbl 0x1(%rax),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L6
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int skip_atoi(const char **c) {
  int i = 0;
  do {
    i = i * 10 + *((*c)++) - '0';
  } while (isdigit(**c));
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<skip_atoi>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  mov    (%rbx),%rax
  lea    (%r12,%r12,4),%ecx
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl (%rax),%edx
  movsbl 0x1(%rax),%edi
  lea    -0x30(%rdx,%rcx,2),%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L4
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int skip_atoi(const char **c) {
  int i = 0;
  do {
    i = i * 10 + *((*c)++) - '0';
  } while (isdigit(**c));
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_atoi>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%rax
  lea    (%r12,%r12,4),%ecx
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl (%rax),%edx
  movsbl 0x1(%rax),%edi
  lea    -0x30(%rdx,%rcx,2),%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int skip_atoi(const char **c) {
  int i = 0;
  do {
    i = i * 10 + *((*c)++) - '0';
  } while (isdigit(**c));
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<recget>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x5c0,%rsp
  mov    %edi,-0x25a4(%rbp)
  mov    %rsi,-0x25b0(%rbp)
  mov    %rdx,-0x25b8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1f50(%rbp),%rdx
  mov    -0x25a4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <numrecvars@plt>
  mov    %eax,-0x2594(%rbp)
  cmpl   $0xffffffff,-0x2594(%rbp)
  jne    L94
  mov    $0xffffffff,%eax
  jmp    L6
L94:
  mov    -0x25b0(%rbp),%rax
  mov    %rax,-0x2590(%rbp)
  movl   $0x1,-0x2598(%rbp)
  jmp    L10
L69:
  mov    -0x2598(%rbp),%eax
  cltq
  movq   $0x0,-0x2590(%rbp,%rax,8)
  addl   $0x1,-0x2598(%rbp)
L10:
  mov    -0x2598(%rbp),%eax
  cmp    -0x2594(%rbp),%eax
  jl     L69
  movl   $0x0,-0x2598(%rbp)
  jmp    L40
L17:
  mov    -0x2598(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x25b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    -0x2598(%rbp),%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%ecx
  lea    -0x2270(%rbp),%rdx
  mov    -0x25a4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <dimsizes@plt>
  movq   $0x1,-0x2270(%rbp)
  mov    -0x2598(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x25b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdi
  mov    -0x2598(%rbp),%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%esi
  lea    -0x2270(%rbp),%rcx
  lea    -0x2590(%rbp),%rdx
  mov    -0x25a4(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <ncvarget@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  mov    $0xffffffff,%eax
  jmp    L6
L3:
  addl   $0x1,-0x2598(%rbp)
L40:
  mov    -0x2598(%rbp),%eax
  cmp    -0x2594(%rbp),%eax
  jl     L17
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L90
  call   <__stack_chk_fail@plt>
L90:
  leave
  ret
```

assistant: ```c
int recget(ncid, recnum, datap)
int ncid;
long recnum;
void **datap;
{
  int iv;
  int rvids[2000];
  int nrvars = numrecvars(ncid, rvids);
  long start[100];
  long edges[100];
  if (nrvars == -1)
    return -1;
  start[0] = recnum;
  for (iv = 1; iv < nrvars; iv++)
    start[iv] = 0;
  for (iv = 0; iv < nrvars; iv++) {
    if (datap[iv] != 0) {
      (void)dimsizes(ncid, rvids[iv], edges);
      edges[0] = 1;
      if (ncvarget(ncid, rvids[iv], start, edges, datap[iv]) == -1)
        return -1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<recget>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x598,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x2588(%rsp)
  xor    %eax,%eax
  lea    0x640(%rsp),%rsi
  call   <numrecvars@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L59
  mov    %rbx,(%rsp)
  cmp    $0x1,%eax
  jle    L47
  lea    0x8(%rsp),%rax
  lea    -0x2(%r12),%edx
  lea    0x10(%rsp,%rdx,8),%rdx
L42:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L42
L83:
  mov    $0x0,%ebx
  lea    0x320(%rsp),%r14
  jmp    L52
L47:
  mov    $0x0,%eax
  jne    L59
  jmp    L83
L27:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jle    L48
L52:
  cmpq   $0x0,0x0(%rbp,%rbx,8)
  je     L27
  lea    0x640(%rsp),%r15
  mov    (%r15,%rbx,4),%esi
  mov    %r14,%rdx
  mov    %r13d,%edi
  mov    $0x0,%eax
  call   <dimsizes@plt>
  movq   $0x1,0x320(%rsp)
  mov    %rsp,%rdx
  mov    (%r15,%rbx,4),%esi
  mov    0x0(%rbp,%rbx,8),%r8
  mov    %r14,%rcx
  mov    %r13d,%edi
  mov    $0x0,%eax
  call   <ncvarget@plt>
  cmp    $0xffffffff,%eax
  jne    L27
  jmp    L59
L48:
  mov    $0x0,%eax
L59:
  mov    0x2588(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x2598,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recget(ncid, recnum, datap)
int ncid;
long recnum;
void **datap;
{
  int iv;
  int rvids[2000];
  int nrvars = numrecvars(ncid, rvids);
  long start[100];
  long edges[100];
  if (nrvars == -1)
    return -1;
  start[0] = recnum;
  for (iv = 1; iv < nrvars; iv++)
    start[iv] = 0;
  for (iv = 0; iv < nrvars; iv++) {
    if (datap[iv] != 0) {
      (void)dimsizes(ncid, rvids[iv], edges);
      edges[0] = 1;
      if (ncvarget(ncid, rvids[iv], start, edges, datap[iv]) == -1)
        return -1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<recget>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x598,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2588(%rsp)
  xor    %eax,%eax
  lea    0x640(%rsp),%r14
  mov    %rsi,%rbx
  mov    %edi,%r13d
  mov    %r14,%rsi
  mov    %rdx,%rbp
  call   <numrecvars@plt>
  cmp    $0xffffffff,%eax
  je     L45
  mov    %rbx,(%rsp)
  mov    %eax,%r12d
  cmp    $0x1,%eax
  jle    L20
  lea    -0x1(%rax),%edx
  lea    0x8(%rsp),%rdi
  xor    %esi,%esi
  shl    $0x3,%rdx
  call   <memset@plt>
L37:
  xor    %ebx,%ebx
  lea    0x320(%rsp),%r15
  nop
L44:
  cmpq   $0x0,0x0(%rbp,%rbx,8)
  je     L88
  mov    (%r14,%rbx,4),%esi
  mov    %r15,%rdx
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <dimsizes@plt>
  mov    (%r14,%rbx,4),%esi
  mov    0x0(%rbp,%rbx,8),%r8
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %r15,%rcx
  mov    %r13d,%edi
  movq   $0x1,0x320(%rsp)
  call   <ncvarget@plt>
  cmp    $0xffffffff,%eax
  je     L45
L88:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L44
L63:
  xor    %eax,%eax
L38:
  mov    0x2588(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x2598,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  mov    $0xffffffff,%eax
  jmp    L38
L20:
  jne    L63
  jmp    L37
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recget(ncid, recnum, datap)
int ncid;
long recnum;
void **datap;
{
  int iv;
  int rvids[2000];
  int nrvars = numrecvars(ncid, rvids);
  long start[100];
  long edges[100];
  if (nrvars == -1)
    return -1;
  start[0] = recnum;
  for (iv = 1; iv < nrvars; iv++)
    start[iv] = 0;
  for (iv = 0; iv < nrvars; iv++) {
    if (datap[iv] != 0) {
      (void)dimsizes(ncid, rvids[iv], edges);
      edges[0] = 1;
      if (ncvarget(ncid, rvids[iv], start, edges, datap[iv]) == -1)
        return -1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<recget>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x598,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2588(%rsp)
  xor    %eax,%eax
  lea    0x640(%rsp),%r14
  mov    %rsi,%rbx
  mov    %edi,%r13d
  mov    %r14,%rsi
  mov    %rdx,%rbp
  call   <numrecvars@plt>
  cmp    $0xffffffff,%eax
  je     L65
  mov    %rbx,(%rsp)
  mov    %eax,%r12d
  cmp    $0x1,%eax
  jle    L79
  lea    -0x1(%rax),%edx
  lea    0x8(%rsp),%rdi
  xor    %esi,%esi
  shl    $0x3,%rdx
  call   <memset@plt>
L3:
  xor    %ebx,%ebx
  lea    0x320(%rsp),%r15
  nop
L13:
  cmpq   $0x0,0x0(%rbp,%rbx,8)
  je     L22
  mov    (%r14,%rbx,4),%esi
  mov    %r15,%rdx
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <dimsizes@plt>
  mov    (%r14,%rbx,4),%esi
  mov    0x0(%rbp,%rbx,8),%r8
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %r15,%rcx
  mov    %r13d,%edi
  movq   $0x1,0x320(%rsp)
  call   <ncvarget@plt>
  cmp    $0xffffffff,%eax
  je     L65
L22:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L13
L85:
  xor    %eax,%eax
L39:
  mov    0x2588(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L83
  add    $0x2598,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L65:
  mov    $0xffffffff,%eax
  jmp    L39
L79:
  jne    L85
  jmp    L3
L83:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int recget(ncid, recnum, datap)
int ncid;
long recnum;
void **datap;
{
  int iv;
  int rvids[2000];
  int nrvars = numrecvars(ncid, rvids);
  long start[100];
  long edges[100];
  if (nrvars == -1)
    return -1;
  start[0] = recnum;
  for (iv = 1; iv < nrvars; iv++)
    start[iv] = 0;
  for (iv = 0; iv < nrvars; iv++) {
    if (datap[iv] != 0) {
      (void)dimsizes(ncid, rvids[iv], edges);
      edges[0] = 1;
      if (ncvarget(ncid, rvids[iv], start, edges, datap[iv]) == -1)
        return -1;
    }
  }
  return 0;
}
```