ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strcmp2>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L56
  jmp    L16
  nopl   (%rax)
L54:
  test   %al,%al
  je     L26
  movsbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  lea    0x1(%rsi),%rax
  test   %dl,%dl
  je     L43
  mov    %rax,%rsi
L56:
  movsbl (%rsi),%eax
  cmp    %dl,%al
  je     L54
L26:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L43:
  movsbl 0x1(%rsi),%eax
  xor    %edx,%edx
  sub    %edx,%eax
  ret
L16:
  movsbl (%rsi),%eax
  xor    %edx,%edx
  jmp    L26
```

assistant: ```c
int ft_strcmp2(char *str1, char *str2) {
  while (*str1 && *str2 && *str1 == *str2) {
    ++str1;
    ++str2;
  }
  return (*str2 - *str1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_strcmp2>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L17
  jmp    L33
  nopl   (%rax)
L18:
  test   %al,%al
  je     L8
  movsbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  lea    0x1(%rsi),%rax
  test   %dl,%dl
  je     L0
  mov    %rax,%rsi
L17:
  movsbl (%rsi),%eax
  cmp    %dl,%al
  je     L18
L8:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L0:
  movsbl 0x1(%rsi),%eax
  xor    %edx,%edx
  sub    %edx,%eax
  ret
L33:
  movsbl (%rsi),%eax
  xor    %edx,%edx
  jmp    L8
```

assistant: ```c
int ft_strcmp2(char *str1, char *str2) {
  while (*str1 && *str2 && *str1 == *str2) {
    ++str1;
    ++str2;
  }
  return (*str2 - *str1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <lgamma@plt>
  movq   %xmm0,%rax
  mov    -0x40(%rbp),%rdx
  mov    %rax,(%rdx)
  pxor   %xmm0,%xmm0
  comisd -0x38(%rbp),%xmm0
  jb     L28
  movsd  -0x38(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  jmp    L59
L28:
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D18(%rip),%xmm0
  divsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L23
L32:
  movsd  -0x8(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x38(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movq   D3(%rip),%xmm2
  andpd  %xmm0,%xmm2
  movsd  D37(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  jbe    L49
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x30(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L59
L49:
  addl   $0x1,-0x1c(%rbp)
L23:
  cmpl   $0x64,-0x1c(%rbp)
  jle    L32
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L59:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
data_type: f64
name: unpack_data
arguments: label: D3
data_type: qword
name: unpack_data
arguments: label: D37
data_type: byte[8]
name: unpack_data
arguments: label: D42
data_type: string

tool: D18: 1

tool: D3: 9223372036854775807

tool: {"D37": [0x76,0x83,0x0d,0xf4,0xf5,0x21,0x94,0x3e]}

tool: D42: a too large, ITMAX too small in routine gser

assistant: ```c
void gser(double *gamser, double a, double x, double *gln) {
  int n;
  double sum, del, ap;
  *gln = lgamma(a);
  if (x <= 0.0) {
    assert(x >= 0.);
    *gamser = 0.0;
    return;
  } else {
    ap = a;
    del = sum = 1.0 / a;
    for (n = 1; n <= 100; n++) {
      ++ap;
      del *= x / ap;
      sum += del;
      if (fabs(del) < fabs(sum) * 3.0e-7) {
        *gamser = sum * exp(-x + a * log(x) - (*gln));
        return;
      }
    }
    printf("a too large, ITMAX too small in routine gser");
    return;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gser>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  movq   %xmm0,%rbx
  movsd  %xmm1,0x8(%rsp)
  mov    %rsi,%r13
  call   <lgamma@plt>
  movq   %xmm0,%rbp
  movsd  %xmm0,0x0(%r13)
  pxor   %xmm0,%xmm0
  comisd 0x8(%rsp),%xmm0
  jae    L33
  movsd  D28(%rip),%xmm0
  movq   %rbx,%xmm6
  divsd  %xmm6,%xmm0
  movq   %xmm0,%r13
  movq   %rbx,%xmm2
  mov    $0x64,%eax
  movsd  D28(%rip),%xmm6
  movq   D4(%rip),%xmm3
  movsd  D35(%rip),%xmm5
L5:
  addsd  %xmm6,%xmm2
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  movq   %r13,%xmm7
  addsd  %xmm0,%xmm7
  movq   %xmm7,%r13
  movapd %xmm0,%xmm4
  andpd  %xmm3,%xmm4
  movapd %xmm7,%xmm1
  andpd  %xmm3,%xmm1
  mulsd  %xmm5,%xmm1
  comisd %xmm4,%xmm1
  ja     L9
  sub    $0x1,%eax
  jne    L5
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L33:
  movsd  0x8(%rsp),%xmm6
  ucomisd %xmm0,%xmm6
  setnp  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  cmovne %eax,%edi
  call   <assert@plt>
  movq   $0x0,(%r12)
  jmp    L18
L9:
  movsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movq   %rbx,%xmm5
  mulsd  %xmm5,%xmm0
  subsd  0x8(%rsp),%xmm0
  movq   %rbp,%xmm6
  subsd  %xmm6,%xmm0
  call   <exp@plt>
  movq   %r13,%xmm5
  mulsd  %xmm5,%xmm0
  movsd  %xmm0,(%r12)
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D28
type_guessed: f64
name: disassemble_data
arguments: label: D4
type_guessed: qword
name: disassemble_data
arguments: label: D35
type_guessed: byte[8]
name: disassemble_data
arguments: label: D36
type_guessed: string

tool: D28: 1

tool: D4: 9223372036854775807

tool: {"D35": [0x76,0x83,0x0d,0xf4,0xf5,0x21,0x94,0x3e]}

tool: D36: a too large, ITMAX too small in routine gser

assistant: ```c
void gser(double *gamser, double a, double x, double *gln) {
  int n;
  double sum, del, ap;
  *gln = lgamma(a);
  if (x <= 0.0) {
    assert(x >= 0.);
    *gamser = 0.0;
    return;
  } else {
    ap = a;
    del = sum = 1.0 / a;
    for (n = 1; n <= 100; n++) {
      ++ap;
      del *= x / ap;
      sum += del;
      if (fabs(del) < fabs(sum) * 3.0e-7) {
        *gamser = sum * exp(-x + a * log(x) - (*gln));
        return;
      }
    }
    printf("a too large, ITMAX too small in routine gser");
    return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gser>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <lgamma@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm10
  movapd %xmm0,%xmm11
  movsd  %xmm0,0x0(%rbp)
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jae    L28
  movsd  D6(%rip),%xmm8
  movapd %xmm10,%xmm5
  mov    $0x64,%eax
  movq   D18(%rip),%xmm6
  movsd  D0(%rip),%xmm9
  movapd %xmm8,%xmm2
  divsd  %xmm10,%xmm2
  movapd %xmm2,%xmm4
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L24:
  sub    $0x1,%eax
  je     L8
L32:
  addsd  %xmm8,%xmm5
  movapd %xmm1,%xmm3
  divsd  %xmm5,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm4
  movapd %xmm2,%xmm7
  andpd  %xmm6,%xmm7
  movapd %xmm4,%xmm3
  andpd  %xmm6,%xmm3
  mulsd  %xmm9,%xmm3
  comisd %xmm7,%xmm3
  jbe    L24
  movapd %xmm1,%xmm0
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm10,0x18(%rsp)
  movsd  %xmm11,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm10
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm11
  mulsd  %xmm10,%xmm0
  subsd  %xmm1,%xmm0
  subsd  %xmm11,%xmm0
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm4
  mulsd  %xmm4,%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  xor    %edi,%edi
  ucomisd %xmm0,%xmm1
  mov    $0x0,%eax
  setnp  %dil
  cmovne %eax,%edi
  call   <assert@plt>
  movq   $0x0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L8:
  add    $0x28,%rsp
  lea    D38(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1090 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D6
datatype: f64
name: parse_data
arguments: label: D18
datatype: qword
name: parse_data
arguments: label: D0
datatype: byte[8]
name: parse_data
arguments: label: D38
datatype: string

tool: D6: 1

tool: D18: 9223372036854775807

tool: {"D0": [0x76,0x83,0x0d,0xf4,0xf5,0x21,0x94,0x3e]}

tool: D38: a too large, ITMAX too small in routine gser

assistant: ```c
void gser(double *gamser, double a, double x, double *gln) {
  int n;
  double sum, del, ap;
  *gln = lgamma(a);
  if (x <= 0.0) {
    assert(x >= 0.);
    *gamser = 0.0;
    return;
  } else {
    ap = a;
    del = sum = 1.0 / a;
    for (n = 1; n <= 100; n++) {
      ++ap;
      del *= x / ap;
      sum += del;
      if (fabs(del) < fabs(sum) * 3.0e-7) {
        *gamser = sum * exp(-x + a * log(x) - (*gln));
        return;
      }
    }
    printf("a too large, ITMAX too small in routine gser");
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gser>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <lgamma@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm10
  movapd %xmm0,%xmm11
  movsd  %xmm0,0x0(%rbp)
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jae    L10
  movsd  D17(%rip),%xmm8
  movapd %xmm10,%xmm5
  mov    $0x64,%eax
  movq   D25(%rip),%xmm6
  movsd  D26(%rip),%xmm9
  movapd %xmm8,%xmm2
  divsd  %xmm10,%xmm2
  movapd %xmm2,%xmm4
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x1,%eax
  je     L33
L16:
  addsd  %xmm8,%xmm5
  movapd %xmm1,%xmm3
  divsd  %xmm5,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm4
  movapd %xmm2,%xmm7
  andpd  %xmm6,%xmm7
  movapd %xmm4,%xmm3
  andpd  %xmm6,%xmm3
  mulsd  %xmm9,%xmm3
  comisd %xmm7,%xmm3
  jbe    L0
  movapd %xmm1,%xmm0
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm10,0x18(%rsp)
  movsd  %xmm11,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm10
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm11
  mulsd  %xmm10,%xmm0
  subsd  %xmm1,%xmm0
  subsd  %xmm11,%xmm0
  call   <exp@plt>
  movsd  0x10(%rsp),%xmm4
  mulsd  %xmm4,%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  xor    %edi,%edi
  ucomisd %xmm0,%xmm1
  mov    $0x0,%eax
  setnp  %dil
  cmovne %eax,%edi
  call   <assert@plt>
  movq   $0x0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L33:
  add    $0x28,%rsp
  lea    D31(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1090 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
type_infered: f64
name: disassemble_data
arguments: label: D25
type_infered: qword
name: disassemble_data
arguments: label: D26
type_infered: byte[8]
name: disassemble_data
arguments: label: D31
type_infered: string

tool: D17: 1

tool: D25: 9223372036854775807

tool: {"D26": [0x76,0x83,0x0d,0xf4,0xf5,0x21,0x94,0x3e]}

tool: D31: a too large, ITMAX too small in routine gser

assistant: ```c
void gser(double *gamser, double a, double x, double *gln) {
  int n;
  double sum, del, ap;
  *gln = lgamma(a);
  if (x <= 0.0) {
    assert(x >= 0.);
    *gamser = 0.0;
    return;
  } else {
    ap = a;
    del = sum = 1.0 / a;
    for (n = 1; n <= 100; n++) {
      ++ap;
      del *= x / ap;
      sum += del;
      if (fabs(del) < fabs(sum) * 3.0e-7) {
        *gamser = sum * exp(-x + a * log(x) - (*gln));
        return;
      }
    }
    printf("a too large, ITMAX too small in routine gser");
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x70(%rbp)
  jmp    L32
L25:
  mov    -0x70(%rbp),%eax
  mov    %eax,%edi
  call   <calcStudentMark@plt>
  movq   %xmm0,%rax
  mov    -0x70(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x60(%rbp,%rdx,8)
  mov    -0x70(%rbp),%eax
  cltq
  movsd  -0x60(%rbp,%rax,8),%xmm0
  movsd  -0x68(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x68(%rbp)
  addl   $0x1,-0x70(%rbp)
L32:
  cmpl   $0x9,-0x70(%rbp)
  jle    L25
  movl   $0x0,-0x6c(%rbp)
  jmp    L40
L17:
  mov    -0x6c(%rbp),%eax
  cltq
  movsd  -0x60(%rbp,%rax,8),%xmm0
  mov    -0x6c(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movq   %xmm2,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    -0x6c(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  call   <studentMarkPrint@plt>
  addl   $0x1,-0x6c(%rbp)
L40:
  cmpl   $0x9,-0x6c(%rbp)
  jle    L17
  movsd  -0x68(%rbp),%xmm0
  movsd  D14(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  -0x68(%rbp),%xmm0
  movsd  D14(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <studentMarkPrint@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: byte[8]
name: retrieve_data
arguments: label: D17
type_guessed: string

tool: D3: Final result for student %d : %0.2f - 

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D17: The average mark of the class is : %0.2f - 

assistant: ```c
int main() {
  double studentsMarks[10], sumOfAllPoints;
  for (int inputMarks = 0; inputMarks < 10; inputMarks++) {
    studentsMarks[inputMarks] = calcStudentMark(inputMarks);
    sumOfAllPoints += studentsMarks[inputMarks];
  }
  for (int printMarks = 0; printMarks < 10; printMarks++) {
    printf("Final result for student %d : %0.2f - ", printMarks + 1, studentsMarks[printMarks]);
    studentMarkPrint(studentsMarks[printMarks]);
  }
  printf("The average mark of the class is : %0.2f - ", (double)sumOfAllPoints / 10);
  studentMarkPrint((double)sumOfAllPoints / 10);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
L29:
  mov    %ebx,%edi
  call   <calcStudentMark@plt>
  movsd  %xmm0,0x10(%rsp,%rbx,8)
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L29
  mov    $0x1,%ebx
  lea    D4(%rip),%r12
L11:
  mov    0x8(%rsp,%rbx,8),%rbp
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  movq   %rbp,%xmm1
  mov    %r12,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movq   %rbp,%xmm0
  call   <studentMarkPrint@plt>
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  jne    L11
  movsd  0x8(%rsp),%xmm3
  divsd  D0(%rip),%xmm3
  movq   %xmm3,%rbx
  movapd %xmm3,%xmm0
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movq   %rbx,%xmm0
  call   <studentMarkPrint@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string
name: extract_symbolic_data
arguments: label: D0
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D22
datatype: string

tool: D4: Final result for student %d : %0.2f - 

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D22: The average mark of the class is : %0.2f - 

assistant: ```c
int main() {
  double studentsMarks[10], sumOfAllPoints;
  for (int inputMarks = 0; inputMarks < 10; inputMarks++) {
    studentsMarks[inputMarks] = calcStudentMark(inputMarks);
    sumOfAllPoints += studentsMarks[inputMarks];
  }
  for (int printMarks = 0; printMarks < 10; printMarks++) {
    printf("Final result for student %d : %0.2f - ", printMarks + 1, studentsMarks[printMarks]);
    studentMarkPrint(studentsMarks[printMarks]);
  }
  printf("The average mark of the class is : %0.2f - ", (double)sumOfAllPoints / 10);
  studentMarkPrint((double)sumOfAllPoints / 10);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%edi
  call   <calcStudentMark@plt>
  movsd  %xmm0,0x0(%rbp,%rbx,8)
  addsd  (%rsp),%xmm0
  add    $0x1,%rbx
  movsd  %xmm0,(%rsp)
  cmp    $0xa,%rbx
  jne    L11
  mov    $0x1,%ebx
  lea    D1(%rip),%r12
  nopl   (%rax)
L29:
  pxor   %xmm0,%xmm0
  movsd  -0x8(%rbp,%rbx,8),%xmm1
  mov    %r12,%rdi
  mov    $0x2,%eax
  cvtsi2sd %ebx,%xmm0
  add    $0x1,%rbx
  movsd  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm1,%xmm0
  call   <studentMarkPrint@plt>
  cmp    $0xb,%rbx
  jne    L29
  lea    D12(%rip),%rdi
  mov    $0x1,%eax
  movsd  (%rsp),%xmm0
  divsd  D11(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  call   <studentMarkPrint@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string
name: parse_data
arguments: label: D11
type_guessed: byte[8]

tool: D1: Final result for student %d : %0.2f - 

tool: D12: The average mark of the class is : %0.2f - 

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
int main() {
  double studentsMarks[10], sumOfAllPoints;
  for (int inputMarks = 0; inputMarks < 10; inputMarks++) {
    studentsMarks[inputMarks] = calcStudentMark(inputMarks);
    sumOfAllPoints += studentsMarks[inputMarks];
  }
  for (int printMarks = 0; printMarks < 10; printMarks++) {
    printf("Final result for student %d : %0.2f - ", printMarks + 1, studentsMarks[printMarks]);
    studentMarkPrint(studentsMarks[printMarks]);
  }
  printf("The average mark of the class is : %0.2f - ", (double)sumOfAllPoints / 10);
  studentMarkPrint((double)sumOfAllPoints / 10);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%edi
  call   <calcStudentMark@plt>
  movsd  %xmm0,0x0(%rbp,%rbx,8)
  addsd  (%rsp),%xmm0
  add    $0x1,%rbx
  movsd  %xmm0,(%rsp)
  cmp    $0xa,%rbx
  jne    L16
  mov    $0x1,%ebx
  lea    D14(%rip),%r12
  nopl   (%rax)
L5:
  pxor   %xmm0,%xmm0
  movsd  -0x8(%rbp,%rbx,8),%xmm1
  mov    %r12,%rdi
  mov    $0x2,%eax
  cvtsi2sd %ebx,%xmm0
  add    $0x1,%rbx
  movsd  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm1,%xmm0
  call   <studentMarkPrint@plt>
  cmp    $0xb,%rbx
  jne    L5
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  movsd  (%rsp),%xmm0
  divsd  D21(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  call   <studentMarkPrint@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D21
type: byte[8]

tool: D14: Final result for student %d : %0.2f - 

tool: D16: The average mark of the class is : %0.2f - 

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
int main() {
  double studentsMarks[10], sumOfAllPoints;
  for (int inputMarks = 0; inputMarks < 10; inputMarks++) {
    studentsMarks[inputMarks] = calcStudentMark(inputMarks);
    sumOfAllPoints += studentsMarks[inputMarks];
  }
  for (int printMarks = 0; printMarks < 10; printMarks++) {
    printf("Final result for student %d : %0.2f - ", printMarks + 1, studentsMarks[printMarks]);
    studentMarkPrint(studentsMarks[printMarks]);
  }
  printf("The average mark of the class is : %0.2f - ", (double)sumOfAllPoints / 10);
  studentMarkPrint((double)sumOfAllPoints / 10);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cfilesystem_combine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movq   $0x0,-0x28(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L119
  cmpq   $0x0,-0x40(%rbp)
  je     L99
L119:
  cmpq   $0x0,-0x40(%rbp)
  je     L102
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L112
L102:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L99
L112:
  cmpq   $0x0,-0x38(%rbp)
  je     L57
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
L57:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L99
L2:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L120
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L120
  mov    $0x1,%eax
  jmp    L3
L120:
  mov    $0x0,%eax
L3:
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  add    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L81
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L81
  mov    -0x20(%rbp),%rax
  movb   $0x2f,(%rax)
  addq   $0x1,-0x20(%rbp)
L81:
  mov    -0x40(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L99:
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *cfilesystem_combine(const char *path1, const char *path2) {
  char *result = NULL;
  if (!path1 && !path2) {
  } else if (!path2 || !path2[0]) {
    result = strdup(path1);
  } else if (!path1 || !path1[0]) {
    result = strdup(path2);
  } else {
    char *ptr;
    size_t len1 = strlen(path1);
    size_t len2 = strlen(path2);
    size_t newlen = len1 + len2 + 1 + ((path1[len1 - 1] != '/' && path2[0] != '/') ? 1 : 0);
    result = (char *)malloc(newlen);
    ptr = result;
    strcpy(ptr, path1);
    ptr += len1;
    if ((ptr[-1] != '/') && (path2[0] != '/')) {
      ptr[0] = '/';
      ++ptr;
    }
    strcpy(ptr, path2);
  }
  return result;
}
```