ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sr_skip_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L17
L9:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *sr_skip_whitespace(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sr_skip_whitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L4
L15:
  add    $0x1,%rbx
L4:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *sr_skip_whitespace(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sr_skip_whitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%r12
L6:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L11
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *sr_skip_whitespace(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sr_skip_whitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%r12
L14:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *sr_skip_whitespace(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crypt_firmware>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %rdx,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x118(%rbp)
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x114(%rbp)
  mov    -0x128(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x11c(%rbp)
  jmp    L36
L49:
  mov    -0x11c(%rbp),%edx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x11c(%rbp),%eax
  mov    %dl,-0x110(%rbp,%rax,1)
  addl   $0x1,-0x11c(%rbp)
L36:
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x11c(%rbp)
  jb     L49
  movl   $0x0,-0x11c(%rbp)
  jmp    L33
L47:
  mov    -0x11c(%rbp),%edx
  mov    -0x130(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x118(%rbp),%eax
  movzbl -0x110(%rbp,%rax,1),%eax
  or     $0xffffff80,%eax
  mov    %edx,%ecx
  xor    %eax,%ecx
  mov    -0x11c(%rbp),%edx
  mov    -0x130(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x118(%rbp),%eax
  add    $0x1,%eax
  mov    -0x114(%rbp),%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,-0x118(%rbp)
  addl   $0x1,-0x11c(%rbp)
L33:
  mov    -0x11c(%rbp),%eax
  cmp    %rax,-0x138(%rbp)
  ja     L47
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
bool crypt_firmware(const char *key, unsigned char *buffer, size_t len) {
  char key_cpy[255];
  unsigned int i;
  unsigned int tmp = 0;
  int key_length = strlen(key);
  strcpy(key_cpy, key);
  for (i = 0; i < strlen(key); i++)
    key_cpy[i] = key[i] - 1;
  for (i = 0; i < len; i++) {
    buffer[i] ^= key_cpy[tmp] | 0x80;
    tmp = (tmp + 1) % key_length;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crypt_firmware>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rsp,%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  mov    $0x0,%ebx
  jmp    L43
L13:
  movzbl (%r14,%rbx,1),%eax
  sub    $0x1,%eax
  mov    %al,(%rsp,%rbx,1)
  add    $0x1,%rbx
L43:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L13
  test   %r13,%r13
  je     L19
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%ecx
L17:
  mov    %edx,%eax
  movzbl (%rsp,%rax,1),%eax
  or     $0xffffff80,%eax
  xor    %al,(%r12,%rcx,1)
  lea    0x1(%rdx),%eax
  mov    $0x0,%edx
  div    %ebp
  add    $0x1,%esi
  mov    %esi,%ecx
  cmp    %r13,%rcx
  jb     L17
L19:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x1,%eax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool crypt_firmware(const char *key, unsigned char *buffer, size_t len) {
  char key_cpy[255];
  unsigned int i;
  unsigned int tmp = 0;
  int key_length = strlen(key);
  strcpy(key_cpy, key);
  for (i = 0; i < strlen(key); i++)
    key_cpy[i] = key[i] - 1;
  for (i = 0; i < len; i++) {
    buffer[i] ^= key_cpy[tmp] | 0x80;
    tmp = (tmp + 1) % key_length;
  }
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<crypt_firmware>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <strlen@plt>
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strcpy@plt>
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L47:
  movzbl (%r15,%rbx,1),%eax
  sub    $0x1,%eax
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
L7:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L47
  test   %r13,%r13
  je     L11
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %edx,%eax
  movzbl (%rsp,%rax,1),%eax
  or     $0xffffff80,%eax
  xor    %al,(%r12,%rcx,1)
  lea    0x1(%rdx),%eax
  xor    %edx,%edx
  lea    0x1(%rsi),%ecx
  div    %ebp
  mov    %rcx,%rsi
  cmp    %r13,%rcx
  jb     L35
L11:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x118,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool crypt_firmware(const char *key, unsigned char *buffer, size_t len) {
  char key_cpy[255];
  unsigned int i;
  unsigned int tmp = 0;
  int key_length = strlen(key);
  strcpy(key_cpy, key);
  for (i = 0; i < strlen(key); i++)
    key_cpy[i] = key[i] - 1;
  for (i = 0; i < len; i++) {
    buffer[i] ^= key_cpy[tmp] | 0x80;
    tmp = (tmp + 1) % key_length;
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crypt_firmware>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <strlen@plt>
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strcpy@plt>
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L36:
  movzbl (%r15,%rbx,1),%eax
  sub    $0x1,%eax
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
L28:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L36
  test   %r13,%r13
  je     L18
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %edx,%eax
  movzbl (%rsp,%rax,1),%eax
  or     $0xffffff80,%eax
  xor    %al,(%r12,%rcx,1)
  lea    0x1(%rdx),%eax
  xor    %edx,%edx
  lea    0x1(%rsi),%ecx
  div    %ebp
  mov    %rcx,%rsi
  cmp    %r13,%rcx
  jb     L21
L18:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x118,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool crypt_firmware(const char *key, unsigned char *buffer, size_t len) {
  char key_cpy[255];
  unsigned int i;
  unsigned int tmp = 0;
  int key_length = strlen(key);
  strcpy(key_cpy, key);
  for (i = 0; i < strlen(key); i++)
    key_cpy[i] = key[i] - 1;
  for (i = 0; i < len; i++) {
    buffer[i] ^= key_cpy[tmp] | 0x80;
    tmp = (tmp + 1) % key_length;
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_bit_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L12
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L23
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <count_bit_set>
  jmp    L17
L12:
  mov    -0x8(%rbp),%eax
L17:
  leave
  ret
```

assistant: ```c
int count_bit_set(unsigned int number, int count) {
  if (number) {
    if (number & 0x01)
      count++;
    return count_bit_set((number >> 1), count);
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<count_bit_set>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  jne    L8
  ret
L8:
  sub    $0x8,%rsp
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  mov    %eax,%esi
  call   <count_bit_set>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int count_bit_set(unsigned int number, int count) {
  if (number) {
    if (number & 0x01)
      count++;
    return count_bit_set((number >> 1), count);
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_bit_set>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  je     L18
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  jne    L12
L18:
  ret
```

assistant: ```c
int count_bit_set(unsigned int number, int count) {
  if (number) {
    if (number & 0x01)
      count++;
    return count_bit_set((number >> 1), count);
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<count_bit_set>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  je     L1
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  shr    %edi
  jne    L11
L1:
  ret
```

assistant: ```c
int count_bit_set(unsigned int number, int count) {
  if (number) {
    if (number & 0x01)
      count++;
    return count_bit_set((number >> 1), count);
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_klp_callbacks_mod_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <pr_info@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string
name: extract_symbolic_data
arguments: data_label: D14
datatype: string

tool: D8: test_klp_callbacks_mod_init

tool: D14: %s


assistant: ```c
int test_klp_callbacks_mod_init(void) {
  pr_info("%s\n", __func__);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_klp_callbacks_mod_init>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <pr_info@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
datatype: string
name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D19: test_klp_callbacks_mod_init

tool: D3: %s


assistant: ```c
int test_klp_callbacks_mod_init(void) {
  pr_info("%s\n", __func__);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_klp_callbacks_mod_init>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <pr_info@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D12
type_infered: string

tool: D14: test_klp_callbacks_mod_init

tool: D12: %s


assistant: ```c
int test_klp_callbacks_mod_init(void) {
  pr_info("%s\n", __func__);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_klp_callbacks_mod_init>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <pr_info@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string

tool: D3: test_klp_callbacks_mod_init

tool: D6: %s


assistant: ```c
int test_klp_callbacks_mod_init(void) {
  pr_info("%s\n", __func__);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *write(char *out, char c) {
  *out++ = c;
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write>:
  endbr64
  mov    %sil,(%rdi)
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *write(char *out, char c) {
  *out++ = c;
  return out;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write>:
  endbr64
  mov    %sil,(%rdi)
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *write(char *out, char c) {
  *out++ = c;
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write>:
  endbr64
  mov    %sil,(%rdi)
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *write(char *out, char c) {
  *out++ = c;
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fget3l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L10
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L10
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L10
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  or     -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  or     %edx,%eax
  jmp    L14
L10:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
L14:
  leave
  ret
```

assistant: ```c
int fget3l(FILE *stream) {
  int b1;
  int b2;
  int b3;
  b1 = fgetc(stream);
  b2 = fgetc(stream);
  b3 = fgetc(stream);
  if ((b1 != EOF) && (b2 != EOF) && (b3 != EOF)) {
    return b1 | (b2 * 0x0100) | (b3 * 0x010000);
  }
  return EOF;
}
```
user: What is the c source code of the assembly code below?

```asm
<fget3l>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <fgetc@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%edx
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %ebp,%eax
  setne  %sil
  cmp    %r12d,%eax
  setne  %cl
  test   %cl,%sil
  je     L10
  cmp    %edx,%eax
  jne    L8
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  shl    $0x8,%ebp
  mov    %edx,%eax
  shl    $0x10,%eax
  or     %eax,%ebp
  mov    %ebp,%eax
  or     %r12d,%eax
  jmp    L10
```

assistant: ```c
int fget3l(FILE *stream) {
  int b1;
  int b2;
  int b3;
  b1 = fgetc(stream);
  b2 = fgetc(stream);
  b3 = fgetc(stream);
  if ((b1 != EOF) && (b2 != EOF) && (b3 != EOF)) {
    return b1 | (b2 * 0x0100) | (b3 * 0x010000);
  }
  return EOF;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fget3l>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <fgetc@plt>
  mov    %eax,%edx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %r12d,%eax
  setne  %sil
  cmp    %ebx,%eax
  setne  %cl
  test   %cl,%sil
  je     L1
  cmp    %edx,%eax
  jne    L2
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %edx,%eax
  shl    $0x8,%ebx
  shl    $0x10,%eax
  or     %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  or     %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int fget3l(FILE *stream) {
  int b1;
  int b2;
  int b3;
  b1 = fgetc(stream);
  b2 = fgetc(stream);
  b3 = fgetc(stream);
  if ((b1 != EOF) && (b2 != EOF) && (b3 != EOF)) {
    return b1 | (b2 * 0x0100) | (b3 * 0x010000);
  }
  return EOF;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fget3l>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <fgetc@plt>
  mov    %eax,%edx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %r12d,%eax
  setne  %sil
  cmp    %ebx,%eax
  setne  %cl
  test   %cl,%sil
  je     L13
  cmp    %edx,%eax
  jne    L5
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %edx,%eax
  shl    $0x8,%ebx
  shl    $0x10,%eax
  or     %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  or     %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int fget3l(FILE *stream) {
  int b1;
  int b2;
  int b3;
  b1 = fgetc(stream);
  b2 = fgetc(stream);
  b3 = fgetc(stream);
  if ((b1 != EOF) && (b2 != EOF) && (b3 != EOF)) {
    return b1 | (b2 * 0x0100) | (b3 * 0x010000);
  }
  return EOF;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<linear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L27
  addl   $0x1,-0xc(%rbp)
L5:
  cmpl   $0x1869f,-0xc(%rbp)
  jle    L4
  jmp    L6
L27:
  nop
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void linear(int a[], int n) {
  int i = 0, flag = 0, key;
  key = a[n];
  for (i = 0; i < 100000; i++) {
    if (a[i] == key) {
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<linear>:
  endbr64
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%edx
  mov    %rdi,%rax
  add    $0x61a80,%rdi
L11:
  cmp    %edx,(%rax)
  je     L1
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L11
L1:
  ret
```

assistant: ```c
void linear(int a[], int n) {
  int i = 0, flag = 0, key;
  key = a[n];
  for (i = 0; i < 100000; i++) {
    if (a[i] == key) {
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<linear>:
  endbr64
  ret
```

assistant: ```c
void linear(int a[], int n) {
  int i = 0, flag = 0, key;
  key = a[n];
  for (i = 0; i < 100000; i++) {
    if (a[i] == key) {
      break;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<linear>:
  endbr64
  ret
```

assistant: ```c
void linear(int a[], int n) {
  int i = 0, flag = 0, key;
  key = a[n];
  for (i = 0; i < 100000; i++) {
    if (a[i] == key) {
      break;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x;
  x = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = 0;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_char_not_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  jmp    L7
L1:
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x4(%rbp)
  jne    L1
L16:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skip_char_not_match(char ch, char *str) {
  while (*str != '\0' && *str != ch) {
    str++;
  }
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_char_not_match>:
  endbr64
  mov    %rsi,%rax
  mov    %edi,%ecx
  movzbl (%rsi),%edx
  cmp    %dil,%dl
  je     L31
  test   %dl,%dl
  je     L31
L8:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %cl,%dl
  je     L31
  test   %dl,%dl
  jne    L8
L31:
  ret
```

assistant: ```c
char *skip_char_not_match(char ch, char *str) {
  while (*str != '\0' && *str != ch) {
    str++;
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skip_char_not_match>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rsi,%rax
  mov    %edi,%ecx
  cmp    %dil,%dl
  jne    L14
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L37:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L17
L14:
  test   %dl,%dl
  jne    L37
L17:
  ret
```

assistant: ```c
char *skip_char_not_match(char ch, char *str) {
  while (*str != '\0' && *str != ch) {
    str++;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skip_char_not_match>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rsi,%rax
  mov    %edi,%ecx
  cmp    %dil,%dl
  jne    L7
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L35:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L30
L7:
  test   %dl,%dl
  jne    L35
L30:
  ret
```

assistant: ```c
char *skip_char_not_match(char ch, char *str) {
  while (*str != '\0' && *str != ch) {
    str++;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x64,%edi
  call   <sendComPrimitives@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  sendComPrimitives('d');
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <sendComPrimitives@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sendComPrimitives('d');
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <sendComPrimitives@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sendComPrimitives('d');
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <sendComPrimitives@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sendComPrimitives('d');
  return 0;
}
```