ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbx
  mov    %rax,%rcx
  mov    $0x1a,%edx
  mov    $0x1,%esi
  lea    D29(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L14:
  mov    $0x0,%eax
  pop    %rbx
  ret
L8:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D7: a

tool: D1: ./directorio/p1

tool: D29: Tengo acceso de escritura


tool: D0: ERROR: NO SE PUDO ABRIR EL FICHERO!!


assistant: ```c
int main(void) {
  FILE *f;
  f = fopen("./directorio/p1", "a");
  if (f != NULL) {
    fputs("Tengo acceso de escritura\n", f);
    fclose(f);
  } else {
    printf("ERROR: NO SE PUDO ABRIR EL FICHERO!!\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rsi
  lea    D22(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbp
  mov    %rax,%rcx
  mov    $0x1a,%edx
  mov    $0x1,%esi
  lea    D14(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L0:
  xor    %eax,%eax
  pop    %rbp
  ret
L10:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string

tool: D18: a

tool: D22: ./directorio/p1

tool: D14: Tengo acceso de escritura


tool: D26: ERROR: NO SE PUDO ABRIR EL FICHERO!!


assistant: ```c
int main(void) {
  FILE *f;
  f = fopen("./directorio/p1", "a");
  if (f != NULL) {
    fputs("Tengo acceso de escritura\n", f);
    fclose(f);
  } else {
    printf("ERROR: NO SE PUDO ABRIR EL FICHERO!!\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D35(%rip),%rsi
  lea    D11(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbp
  mov    %rax,%rcx
  mov    $0x1a,%edx
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L5:
  xor    %eax,%eax
  pop    %rbp
  ret
L17:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: tag: D35
datatype: string
name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D2
datatype: string

tool: D35: a

tool: D11: ./directorio/p1

tool: D6: Tengo acceso de escritura


tool: D2: ERROR: NO SE PUDO ABRIR EL FICHERO!!


assistant: ```c
int main(void) {
  FILE *f;
  f = fopen("./directorio/p1", "a");
  if (f != NULL) {
    fputs("Tengo acceso de escritura\n", f);
    fclose(f);
  } else {
    printf("ERROR: NO SE PUDO ABRIR EL FICHERO!!\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<func5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x17,-0x14(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1b,-0x18(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void func5() {
  int val = 0, val2 = 23;
  int *x = &val;
  x = &val2;
  val = 27;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func5>:
  endbr64
  ret
```

assistant: ```c
void func5() {
  int val = 0, val2 = 23;
  int *x = &val;
  x = &val2;
  val = 27;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func5>:
  endbr64
  ret
```

assistant: ```c
void func5() {
  int val = 0, val2 = 23;
  int *x = &val;
  x = &val2;
  val = 27;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adaptString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L56
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x27,(%rax)
  addq   $0x1,-0x18(%rbp)
  jmp    L46
L89:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L53
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x27,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x27,(%rax)
  addq   $0x1,-0x18(%rbp)
  jmp    L46
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L48
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x22,(%rax)
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L46
  addq   $0x1,-0x18(%rbp)
  jmp    L46
L48:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L89
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x27,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L76
L56:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L76:
  nop
  leave
  ret
```

assistant: ```c
void adaptString(char *str, char *result) {
  int i, len;
  i = 0;
  len = strlen(str);
  if (*str == '"') {
    result[i++] = '\'';
    str++;
    while (*str != '\0') {
      if (*str == '\'') {
        result[i++] = '\'';
        result[i++] = '\'';
        str++;
      } else if (*str == '"') {
        result[i++] = '"';
        str++;
        if (*str == '"') {
          str++;
        }
      } else {
        result[i++] = *str;
        str++;
      }
    }
    i--;
    result[i++] = '\'';
    result[i++] = '\0';
  } else {
    strcpy(result, str);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<adaptString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmpb   $0x22,0x0(%rbp)
  jne    L14
  movb   $0x27,(%rbx)
  lea    0x1(%rbp),%rcx
  movzbl 0x1(%rbp),%edx
  test   %dl,%dl
  je     L34
  mov    $0x1,%eax
  jmp    L58
L108:
  lea    0x1(%rax),%edx
  movslq %eax,%rsi
  movb   $0x27,(%rbx,%rsi,1)
  add    $0x2,%eax
  movslq %edx,%rdx
  movb   $0x27,(%rbx,%rdx,1)
  add    $0x1,%rcx
L88:
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L31
L58:
  cmp    $0x27,%dl
  je     L108
  cmp    $0x22,%dl
  je     L13
  movslq %eax,%rsi
  mov    %dl,(%rbx,%rsi,1)
  add    $0x1,%rcx
  lea    0x1(%rax),%eax
  jmp    L88
L13:
  lea    0x1(%rax),%edx
  cltq
  movb   $0x22,(%rbx,%rax,1)
  cmpb   $0x22,0x1(%rcx)
  je     L15
  add    $0x1,%rcx
  mov    %edx,%eax
  jmp    L88
L15:
  add    $0x2,%rcx
  mov    %edx,%eax
  jmp    L88
L34:
  mov    $0x1,%eax
L31:
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  movb   $0x27,(%rbx,%rdx,1)
  cltq
  movb   $0x0,(%rbx,%rax,1)
L68:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L68
```

assistant: ```c
void adaptString(char *str, char *result) {
  int i, len;
  i = 0;
  len = strlen(str);
  if (*str == '"') {
    result[i++] = '\'';
    str++;
    while (*str != '\0') {
      if (*str == '\'') {
        result[i++] = '\'';
        result[i++] = '\'';
        str++;
      } else if (*str == '"') {
        result[i++] = '"';
        str++;
        if (*str == '"') {
          str++;
        }
      } else {
        result[i++] = *str;
        str++;
      }
    }
    i--;
    result[i++] = '\'';
    result[i++] = '\0';
  } else {
    strcpy(result, str);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adaptString>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x22,(%r12)
  jne    L29
  movb   $0x27,0x0(%rbp)
  movzbl 0x1(%r12),%eax
  lea    0x1(%r12),%rsi
  test   %al,%al
  je     L12
  mov    $0x1,%ecx
  jmp    L47
  nop
L66:
  cmp    $0x22,%al
  je     L62
  mov    %al,(%rdx)
  mov    %edi,%ecx
  movzbl 0x1(%rsi),%eax
  mov    %r8,%rsi
L50:
  test   %al,%al
  je     L39
L47:
  movslq %ecx,%rdx
  lea    0x1(%rcx),%edi
  lea    0x1(%rsi),%r8
  add    %rbp,%rdx
  cmp    $0x27,%al
  jne    L66
  movslq %edi,%rdi
  movb   $0x27,(%rdx)
  add    $0x2,%ecx
  movb   $0x27,0x0(%rbp,%rdi,1)
  movzbl 0x1(%rsi),%eax
  mov    %r8,%rsi
  test   %al,%al
  jne    L47
L39:
  lea    -0x1(%rcx),%eax
  movslq %ecx,%rcx
  cltq
  add    %rbp,%rax
L64:
  movb   $0x27,(%rax)
  movb   $0x0,0x0(%rbp,%rcx,1)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  movb   $0x22,(%rdx)
  movzbl 0x1(%rsi),%eax
  cmp    $0x22,%al
  je     L44
  mov    %edi,%ecx
  mov    %r8,%rsi
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
L44:
  movzbl 0x2(%rsi),%eax
  mov    %edi,%ecx
  add    $0x2,%rsi
  jmp    L50
  nop
L12:
  mov    %rbp,%rax
  mov    $0x1,%ecx
  jmp    L64
```

assistant: ```c
void adaptString(char *str, char *result) {
  int i, len;
  i = 0;
  len = strlen(str);
  if (*str == '"') {
    result[i++] = '\'';
    str++;
    while (*str != '\0') {
      if (*str == '\'') {
        result[i++] = '\'';
        result[i++] = '\'';
        str++;
      } else if (*str == '"') {
        result[i++] = '"';
        str++;
        if (*str == '"') {
          str++;
        }
      } else {
        result[i++] = *str;
        str++;
      }
    }
    i--;
    result[i++] = '\'';
    result[i++] = '\0';
  } else {
    strcpy(result, str);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<adaptString>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x22,(%r12)
  jne    L69
  movb   $0x27,0x0(%rbp)
  movzbl 0x1(%r12),%eax
  lea    0x1(%r12),%r8
  test   %al,%al
  je     L75
  mov    $0x1,%ecx
  jmp    L87
  nop
L5:
  cmp    $0x22,%al
  je     L58
  mov    %al,(%rdx)
  mov    %esi,%ecx
  movzbl 0x1(%r8),%eax
  mov    %rdi,%r8
L38:
  test   %al,%al
  je     L64
L87:
  movslq %ecx,%rdx
  lea    0x1(%rcx),%esi
  lea    0x1(%r8),%rdi
  add    %rbp,%rdx
  cmp    $0x27,%al
  jne    L5
  movslq %esi,%rsi
  movb   $0x27,(%rdx)
  add    $0x2,%ecx
  add    %rbp,%rsi
  movb   $0x27,(%rsi)
  movzbl 0x1(%r8),%eax
  mov    %rsi,%rdx
  mov    %rdi,%r8
  test   %al,%al
  jne    L87
L64:
  movslq %ecx,%rcx
L18:
  movb   $0x27,(%rdx)
  movb   $0x0,0x0(%rbp,%rcx,1)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L58:
  movb   $0x22,(%rdx)
  movzbl 0x1(%r8),%eax
  cmp    $0x22,%al
  je     L43
  mov    %esi,%ecx
  mov    %rdi,%r8
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L69:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
L43:
  movzbl 0x2(%r8),%eax
  mov    %esi,%ecx
  add    $0x2,%r8
  jmp    L38
L75:
  mov    %rbp,%rdx
  mov    $0x1,%ecx
  jmp    L18
```

assistant: ```c
void adaptString(char *str, char *result) {
  int i, len;
  i = 0;
  len = strlen(str);
  if (*str == '"') {
    result[i++] = '\'';
    str++;
    while (*str != '\0') {
      if (*str == '\'') {
        result[i++] = '\'';
        result[i++] = '\'';
        str++;
      } else if (*str == '"') {
        result[i++] = '"';
        str++;
        if (*str == '"') {
          str++;
        }
      } else {
        result[i++] = *str;
        str++;
      }
    }
    i--;
    result[i++] = '\'';
    result[i++] = '\0';
  } else {
    strcpy(result, str);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Merge_Pass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L55
L40:
  mov    -0x28(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  lea    -0x1(%rax),%edi
  mov    -0x8(%rbp),%edx
  mov    -0x28(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <Merge1@plt>
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  add    %eax,-0x8(%rbp)
L55:
  mov    -0x28(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x24(%rbp),%eax
  sub    %edx,%eax
  cmp    %eax,-0x8(%rbp)
  jle    L40
  mov    -0x8(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x24(%rbp)
  jle    L5
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x8(%rbp),%edx
  mov    -0x28(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <Merge1@plt>
  jmp    L53
L5:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L20
L42:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L42
  nop
L53:
  leave
  ret
```

assistant: ```c
void Merge_Pass(int A[], int TmpA[], int N, int length) {
  int i, j;
  for (i = 0; i <= N - 2 * length; i += 2 * length)
    Merge1(A, TmpA, i, i + length, i + 2 * length - 1);
  if (i + length < N)
    Merge1(A, TmpA, i, i + length, N - 1);
  else
    for (j = i; j < N; j++)
      TmpA[j] = A[j];
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Merge_Pass>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,0xc(%rsp)
  lea    (%rcx,%rcx,1),%esi
  mov    %esi,0x8(%rsp)
  mov    %edx,%r14d
  sub    %esi,%r14d
  js     L32
  mov    %ecx,%eax
  mov    $0x0,%ebx
  sub    %esi,%eax
  mov    %eax,%r15d
L0:
  mov    %ebx,%edx
  add    0x8(%rsp),%ebx
  lea    (%r15,%rbx,1),%ecx
  lea    -0x1(%rbx),%r8d
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <Merge1@plt>
  cmp    %r14d,%ebx
  jle    L0
L15:
  mov    0xc(%rsp),%ecx
  add    %ebx,%ecx
  cmp    %r13d,%ecx
  jl     L5
  movslq %ebx,%rax
  cmp    %ebx,%r13d
  jle    L21
L45:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r13d
  jg     L45
L21:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    $0x0,%ebx
  jmp    L15
L5:
  lea    -0x1(%r13),%r8d
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <Merge1@plt>
  jmp    L21
```

assistant: ```c
void Merge_Pass(int A[], int TmpA[], int N, int length) {
  int i, j;
  for (i = 0; i <= N - 2 * length; i += 2 * length)
    Merge1(A, TmpA, i, i + length, i + 2 * length - 1);
  if (i + length < N)
    Merge1(A, TmpA, i, i + length, N - 1);
  else
    for (j = i; j < N; j++)
      TmpA[j] = A[j];
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Merge_Pass>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %edx,%esi
  push   %r12
  push   %rbp
  lea    (%rcx,%rcx,1),%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  sub    %ebp,%esi
  mov    %ecx,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  js     L19
  mov    %ecx,%eax
  xor    %r12d,%r12d
  sub    %ebp,%eax
  mov    %eax,%r14d
  nopl   0x0(%rax)
L32:
  mov    %r12d,%edx
  add    %ebp,%r12d
  mov    %r13,%rsi
  mov    %r15,%rdi
  lea    (%r14,%r12,1),%ecx
  lea    -0x1(%r12),%r8d
  call   <Merge1@plt>
  cmp    0x8(%rsp),%r12d
  jle    L32
  add    %r12d,0xc(%rsp)
L11:
  cmp    %ebx,0xc(%rsp)
  jl     L34
  movslq %r12d,%rax
  cmp    %r12d,%ebx
  jle    L48
  nopl   0x0(%rax)
L16:
  mov    (%r15,%rax,4),%edx
  mov    %edx,0x0(%r13,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L16
L48:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    0xc(%rsp),%ecx
  add    $0x18,%rsp
  lea    -0x1(%rbx),%r8d
  mov    %r12d,%edx
  pop    %rbx
  mov    %r13,%rsi
  pop    %rbp
  mov    %r15,%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <Merge1@plt>
  nopl   0x0(%rax)
L19:
  xor    %r12d,%r12d
  jmp    L11
```

assistant: ```c
void Merge_Pass(int A[], int TmpA[], int N, int length) {
  int i, j;
  for (i = 0; i <= N - 2 * length; i += 2 * length)
    Merge1(A, TmpA, i, i + length, i + 2 * length - 1);
  if (i + length < N)
    Merge1(A, TmpA, i, i + length, N - 1);
  else
    for (j = i; j < N; j++)
      TmpA[j] = A[j];
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<Merge_Pass>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  lea    (%rcx,%rcx,1),%ebx
  sub    $0x18,%rsp
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  sub    %ebx,%edx
  js     L126
  mov    %ecx,%eax
  mov    %edx,%r13d
  xor    %r12d,%r12d
  sub    %ebx,%eax
  mov    %eax,%r14d
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r12d,%edx
  add    %ebx,%r12d
  mov    %rbp,%rsi
  mov    %r15,%rdi
  lea    (%r14,%r12,1),%ecx
  lea    -0x1(%r12),%r8d
  call   <Merge1@plt>
  cmp    %r13d,%r12d
  jle    L38
  add    %r12d,0xc(%rsp)
L57:
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  jg     L105
  cmp    %r12d,%eax
  jle    L112
  mov    %eax,%r9d
  movslq %r12d,%rax
  lea    0x0(,%rax,4),%rdx
  sub    %r12d,%r9d
  lea    0x0(%rbp,%rdx,1),%r8
  lea    0x4(%r15,%rdx,1),%r10
  mov    %r8,%rcx
  sub    %r10,%rcx
  cmp    $0x8,%rcx
  jbe    L63
  lea    -0x1(%r9),%ecx
  cmp    $0x2,%ecx
  jbe    L63
  mov    %r9d,%ecx
  add    %r15,%rdx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
L123:
  movdqu (%rdx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L123
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%r12d
  cmp    %eax,%r9d
  je     L112
  movslq %r12d,%rax
  mov    0x8(%rsp),%edi
  mov    (%r15,%rax,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  lea    0x1(%r12),%eax
  cmp    %eax,%edi
  jle    L112
  cltq
  add    $0x2,%r12d
  mov    (%r15,%rax,4),%ecx
  lea    0x0(,%rax,4),%rdx
  mov    %ecx,0x0(%rbp,%rax,4)
  cmp    %r12d,%edi
  jle    L112
  mov    0x4(%r15,%rdx,1),%eax
  mov    %eax,0x4(%rbp,%rdx,1)
L112:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L63:
  mov    (%r15,%rax,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %eax,0x8(%rsp)
  jg     L63
  jmp    L112
  nopl   0x0(%rax)
L105:
  add    $0x18,%rsp
  mov    %eax,%r8d
  mov    %esi,%ecx
  mov    %r12d,%edx
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  pop    %rbp
  sub    $0x1,%r8d
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <Merge1@plt>
  nopl   (%rax)
L126:
  xor    %r12d,%r12d
  jmp    L57
```

assistant: ```c
void Merge_Pass(int A[], int TmpA[], int N, int length) {
  int i, j;
  for (i = 0; i <= N - 2 * length; i += 2 * length)
    Merge1(A, TmpA, i, i + length, i + 2 * length - 1);
  if (i + length < N)
    Merge1(A, TmpA, i, i + length, N - 1);
  else
    for (j = i; j < N; j++)
      TmpA[j] = A[j];
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cephes_isfinite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x7ff00000,%eax
  cmp    $0x7ff00000,%eax
  je     L29
  mov    $0x1,%eax
  jmp    L6
L29:
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int cephes_isfinite(x)
double x;
{
  union {
    double d;
    unsigned short s[4];
    unsigned int i[2];
  } u;
  u.d = x;
  if (sizeof(int) == 4) {
    if ((u.i[1] & 0x7ff00000) != 0x7ff00000)
      return 1;
    return (0);
  } else {
    if ((u.s[3] & 0x7ff0) != 0x7ff0)
      return 1;
    return (0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cephes_isfinite>:
  endbr64
  movq   %xmm0,%rax
  shr    $0x20,%rax
  and    $0x7ff00000,%eax
  cmp    $0x7ff00000,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int cephes_isfinite(x)
double x;
{
  union {
    double d;
    unsigned short s[4];
    unsigned int i[2];
  } u;
  u.d = x;
  if (sizeof(int) == 4) {
    if ((u.i[1] & 0x7ff00000) != 0x7ff00000)
      return 1;
    return (0);
  } else {
    if ((u.s[3] & 0x7ff0) != 0x7ff0)
      return 1;
    return (0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cephes_isfinite>:
  endbr64
  movq   %xmm0,%rax
  shr    $0x20,%rax
  and    $0x7ff00000,%eax
  cmp    $0x7ff00000,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int cephes_isfinite(x)
double x;
{
  union {
    double d;
    unsigned short s[4];
    unsigned int i[2];
  } u;
  u.d = x;
  if (sizeof(int) == 4) {
    if ((u.i[1] & 0x7ff00000) != 0x7ff00000)
      return 1;
    return (0);
  } else {
    if ((u.s[3] & 0x7ff0) != 0x7ff0)
      return 1;
    return (0);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cephes_isfinite>:
  endbr64
  movq   %xmm0,%rax
  shr    $0x20,%rax
  and    $0x7ff00000,%eax
  cmp    $0x7ff00000,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int cephes_isfinite(x)
double x;
{
  union {
    double d;
    unsigned short s[4];
    unsigned int i[2];
  } u;
  u.d = x;
  if (sizeof(int) == 4) {
    if ((u.i[1] & 0x7ff00000) != 0x7ff00000)
      return 1;
    return (0);
  } else {
    if ((u.s[3] & 0x7ff0) != 0x7ff0)
      return 1;
    return (0);
  }
}
```