ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<get_file_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %eax,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_file_size(FILE *restrict file) {
  fseek(file, 0, SEEK_END);
  int size = (int)ftell(file);
  fseek(file, 0, SEEK_SET);
  return size;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_file_size>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %rax,%rbx
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <fseek@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_file_size(FILE *restrict file) {
  fseek(file, 0, SEEK_END);
  int size = (int)ftell(file);
  fseek(file, 0, SEEK_SET);
  return size;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_file_size>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    %rax,%rbx
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_file_size(FILE *restrict file) {
  fseek(file, 0, SEEK_END);
  int size = (int)ftell(file);
  fseek(file, 0, SEEK_SET);
  return size;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_file_size>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    %rax,%rbx
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_file_size(FILE *restrict file) {
  fseek(file, 0, SEEK_END);
  int size = (int)ftell(file);
  fseek(file, 0, SEEK_SET);
  return size;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfc0(%rbp)
  movl   $0x0,-0xfc0(%rbp)
  jmp    L46
L28:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xfb0(%rbp),%rdx
  mov    -0xfc0(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfc0(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    $0x2a,%eax
  je     L86
  addl   $0x1,-0xfc0(%rbp)
L46:
  cmpl   $0x3e7,-0xfc0(%rbp)
  jle    L28
  jmp    L55
L86:
  nop
L55:
  mov    -0xfc0(%rbp),%eax
  mov    %eax,-0xfb8(%rbp)
  movl   $0x0,-0xfc0(%rbp)
  jmp    L27
L38:
  movl   $0x0,-0xfbc(%rbp)
  jmp    L85
L64:
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfbc(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L58
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,-0xfb4(%rbp)
  mov    -0xfbc(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  mov    -0xfbc(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfb4(%rbp),%edx
  mov    %edx,-0xfb0(%rbp,%rax,4)
L58:
  addl   $0x1,-0xfbc(%rbp)
L85:
  mov    -0xfb8(%rbp),%eax
  sub    -0xfc0(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xfbc(%rbp)
  jl     L64
  addl   $0x1,-0xfc0(%rbp)
L27:
  mov    -0xfb8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xfc0(%rbp)
  jl     L38
  movl   $0x0,-0xfc0(%rbp)
  jmp    L57
L31:
  mov    -0xfc0(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xfc0(%rbp)
L57:
  mov    -0xfc0(%rbp),%eax
  cmp    -0xfb8(%rbp),%eax
  jl     L31
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L83
  call   <__stack_chk_fail@plt>
L83:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D25
type_infered: string
name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D7
type_infered: string

tool: D25: Number:

tool: D24: %d

tool: D7: %d 


assistant: ```c
int main() {
  int a[1000];
  int i = 0, max, d, z;
  for (i = 0; i < 1000; i++) {
    printf("Number:");
    scanf("%d", &a[i]);
    if (a[i] == 42)
      break;
  }
  max = i;
  for (i = 0; i < max - 1; i++) {
    for (d = 0; d < max - i - 1; d++) {
      if (a[d] > a[d + 1]) {
        z = a[d];
        a[d] = a[d + 1];
        a[d + 1] = z;
      }
    }
  }
  for (i = 0; i < max; i++) {
    printf("%d \n", a[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r12
  mov    $0x0,%ebx
  lea    D7(%rip),%r14
  lea    D28(%rip),%r13
L33:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpl   $0x2a,(%r12)
  je     L138
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    $0x3e8,%ebx
  jne    L33
  mov    $0x3e7,%edi
  jmp    L135
L138:
  lea    -0x1(%rbx),%edi
  test   %edi,%edi
  jle    L2
L135:
  lea    0x4(%rbp),%r8
  jmp    L108
L31:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L80
L81:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L31
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L31
L80:
  sub    $0x1,%edi
  je     L2
L108:
  test   %edi,%edi
  jle    L80
  lea    -0x1(%rdi),%eax
  lea    (%r8,%rax,4),%rsi
  mov    %rbp,%rax
  jmp    L81
L2:
  test   %ebx,%ebx
  jle    L36
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp,%rax,4),%r12
  lea    D3(%rip),%rbx
L14:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %rbp,%r12
  jne    L14
L36:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    $0x0,%eax
  add    $0xfb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D28
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string

tool: D7: Number:

tool: D28: %d

tool: D3: %d 


assistant: ```c
int main() {
  int a[1000];
  int i = 0, max, d, z;
  for (i = 0; i < 1000; i++) {
    printf("Number:");
    scanf("%d", &a[i]);
    if (a[i] == 42)
      break;
  }
  max = i;
  for (i = 0; i < max - 1; i++) {
    for (d = 0; d < max - i - 1; d++) {
      if (a[d] > a[d + 1]) {
        z = a[d];
        a[d] = a[d + 1];
        a[d + 1] = z;
      }
    }
  }
  for (i = 0; i < max; i++) {
    printf("%d \n", a[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rbx
  jmp    L7
  nop
L2:
  add    $0x1,%r12d
  add    $0x4,%rbx
  cmp    $0x3e8,%r12d
  je     L61
L7:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpl   $0x2a,(%rbx)
  jne    L2
  lea    -0x1(%r12),%r8d
  mov    %r8d,%r9d
  test   %r8d,%r8d
  jle    L64
L40:
  xor    %edi,%edi
  lea    -0x2(%r12),%r11d
  lea    0x4(%rbp),%r10
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r8d,%eax
  sub    %edi,%eax
  test   %eax,%eax
  jle    L60
  mov    %r11d,%eax
  sub    %edi,%eax
  lea    (%r10,%rax,4),%rsi
  mov    %rbp,%rax
  nopl   (%rax)
L26:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L50
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L50:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L26
L60:
  add    $0x1,%edi
  cmp    %edi,%r9d
  jg     L22
L64:
  test   %r12d,%r12d
  je     L109
  lea    0x4(%rbp),%rbx
  lea    D14(%rip),%r12
  lea    (%rbx,%r8,4),%r13
  jmp    L1
  nopl   (%rax)
L13:
  add    $0x4,%rbx
L1:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rbx,%rbp
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L13
L109:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0xfb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L61:
  mov    $0x3e7,%r9d
  mov    $0x3e7,%r8d
  jmp    L40
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D23
type_infered: string
name: retrieve_data
arguments: data_label: D14
type_infered: string

tool: D5: Number:

tool: D23: %d

tool: D14: %d 


assistant: ```c
int main() {
  int a[1000];
  int i = 0, max, d, z;
  for (i = 0; i < 1000; i++) {
    printf("Number:");
    scanf("%d", &a[i]);
    if (a[i] == 42)
      break;
  }
  max = i;
  for (i = 0; i < max - 1; i++) {
    for (d = 0; d < max - i - 1; d++) {
      if (a[d] > a[d + 1]) {
        z = a[d];
        a[d] = a[d + 1];
        a[d + 1] = z;
      }
    }
  }
  for (i = 0; i < max; i++) {
    printf("%d \n", a[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rbp
  jmp    L8
  nop
L41:
  add    $0x1,%r12d
  add    $0x4,%rbp
  cmp    $0x3e8,%r12d
  je     L39
L8:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpl   $0x2a,0x0(%rbp)
  jne    L41
  lea    -0x1(%r12),%r8d
  mov    %r8d,%r9d
  test   %r8d,%r8d
  jle    L37
L91:
  xor    %edi,%edi
  lea    -0x2(%r12),%r11d
  lea    0x4(%rbx),%r10
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r8d,%eax
  sub    %edi,%eax
  test   %eax,%eax
  jle    L100
  mov    %r11d,%eax
  mov    %rbx,%rdx
  sub    %edi,%eax
  lea    (%r10,%rax,4),%rsi
  nopl   (%rax)
L54:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L10
  movq   %xmm1,(%rdx)
L10:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L54
L100:
  add    $0x1,%edi
  cmp    %edi,%r9d
  jg     L33
L37:
  test   %r12d,%r12d
  je     L121
  lea    0x4(%rbx),%rbp
  lea    D4(%rip),%r12
  lea    0x0(%rbp,%r8,4),%r13
  jmp    L128
  xchg   %ax,%ax
L22:
  add    $0x4,%rbp
L128:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rbp,%rbx
  call   <printf@plt>
  cmp    %r13,%rbp
  jne    L22
L121:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0xfb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  mov    $0x3e7,%r9d
  mov    $0x3e7,%r8d
  jmp    L91
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string
name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D4
type: string

tool: D6: Number:

tool: D8: %d

tool: D4: %d 


assistant: ```c
int main() {
  int a[1000];
  int i = 0, max, d, z;
  for (i = 0; i < 1000; i++) {
    printf("Number:");
    scanf("%d", &a[i]);
    if (a[i] == 42)
      break;
  }
  max = i;
  for (i = 0; i < max - 1; i++) {
    for (d = 0; d < max - i - 1; d++) {
      if (a[d] > a[d + 1]) {
        z = a[d];
        a[d] = a[d + 1];
        a[d + 1] = z;
      }
    }
  }
  for (i = 0; i < max; i++) {
    printf("%d \n", a[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uart1GetchRTS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <uart1_set_rts@plt>
  mov    $0xe0010014,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
  mov    $0x0,%eax
  call   <uart1_clear_rts@plt>
  mov    $0xe0010000,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  jmp    L1
L14:
  mov    $0x0,%eax
  call   <uart1_clear_rts@plt>
  mov    $0xffffffff,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int uart1GetchRTS(void) {
  uart1_set_rts();
  if ((*((volatile unsigned char *)0xE0010014)) & (1 << 0)) {
    uart1_clear_rts();
    return (*((volatile unsigned char *)0xE0010000));
  }
  uart1_clear_rts();
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uart1GetchRTS>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <uart1_set_rts@plt>
  movabs 0xe0010014,%al
  test   $0x1,%al
  je     L2
  mov    $0x0,%eax
  call   <uart1_clear_rts@plt>
  movabs 0xe0010000,%al
  movzbl %al,%eax
L6:
  add    $0x8,%rsp
  ret
L2:
  mov    $0x0,%eax
  call   <uart1_clear_rts@plt>
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int uart1GetchRTS(void) {
  uart1_set_rts();
  if ((*((volatile unsigned char *)0xE0010014)) & (1 << 0)) {
    uart1_clear_rts();
    return (*((volatile unsigned char *)0xE0010000));
  }
  uart1_clear_rts();
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart1GetchRTS>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <uart1_set_rts@plt>
  movabs 0xe0010014,%al
  test   $0x1,%al
  mov    $0x0,%eax
  je     L17
  call   <uart1_clear_rts@plt>
  movabs 0xe0010000,%al
  movzbl %al,%eax
L2:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  call   <uart1_clear_rts@plt>
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int uart1GetchRTS(void) {
  uart1_set_rts();
  if ((*((volatile unsigned char *)0xE0010014)) & (1 << 0)) {
    uart1_clear_rts();
    return (*((volatile unsigned char *)0xE0010000));
  }
  uart1_clear_rts();
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart1GetchRTS>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <uart1_set_rts@plt>
  movabs 0xe0010014,%al
  test   $0x1,%al
  mov    $0x0,%eax
  je     L15
  call   <uart1_clear_rts@plt>
  movabs 0xe0010000,%al
  movzbl %al,%eax
L13:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  call   <uart1_clear_rts@plt>
  mov    $0xffffffff,%eax
  jmp    L13
```

assistant: ```c
int uart1GetchRTS(void) {
  uart1_set_rts();
  if ((*((volatile unsigned char *)0xE0010014)) & (1 << 0)) {
    uart1_clear_rts();
    return (*((volatile unsigned char *)0xE0010000));
  }
  uart1_clear_rts();
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<m_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L2
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mem_list_add@plt>
  mov    -0x8(%rbp),%rax
L2:
  leave
  ret
```

assistant: ```c
char *m_strdup(char *str) {
  char *ret;
  if (str == NULL)
    return NULL;
  ret = strdup(str);
  mem_list_add(ret);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<m_strdup>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L18
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <mem_list_add@plt>
L15:
  mov    %rbx,%rax
  pop    %rbx
  ret
L18:
  mov    %rdi,%rbx
  jmp    L15
```

assistant: ```c
char *m_strdup(char *str) {
  char *ret;
  if (str == NULL)
    return NULL;
  ret = strdup(str);
  mem_list_add(ret);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m_strdup>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L4
  call   <strdup@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <mem_list_add@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *m_strdup(char *str) {
  char *ret;
  if (str == NULL)
    return NULL;
  ret = strdup(str);
  mem_list_add(ret);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<m_strdup>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L6
  call   <strdup@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <mem_list_add@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *m_strdup(char *str) {
  char *ret;
  if (str == NULL)
    return NULL;
  ret = strdup(str);
  mem_list_add(ret);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  jmp    L10
L7:
  mov    -0x18(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  jmp    L10
L2:
  mov    -0x18(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
const char *getname(const char *fname) {
  char *result;
  result = strrchr(fname, '/');
  if (result)
    return ++result;
  result = strrchr(fname, '\\');
  if (result)
    return ++result;
  return fname;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  add    $0x1,%rax
L3:
  pop    %rbx
  ret
L4:
  mov    $0x5c,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%rdx
  lea    0x1(%rax),%rax
  test   %rdx,%rdx
  cmove  %rbx,%rax
  jmp    L3
```

assistant: ```c
const char *getname(const char *fname) {
  char *result;
  result = strrchr(fname, '/');
  if (result)
    return ++result;
  result = strrchr(fname, '\\');
  if (result)
    return ++result;
  return fname;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getname>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L6
  add    $0x1,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L6:
  mov    %rbx,%rdi
  mov    $0x5c,%esi
  call   <strrchr@plt>
  mov    %rax,%rdx
  lea    0x1(%rax),%rax
  test   %rdx,%rdx
  cmove  %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *getname(const char *fname) {
  char *result;
  result = strrchr(fname, '/');
  if (result)
    return ++result;
  result = strrchr(fname, '\\');
  if (result)
    return ++result;
  return fname;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getname>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  add    $0x1,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L5:
  mov    %rbx,%rdi
  mov    $0x5c,%esi
  call   <strrchr@plt>
  mov    %rax,%rdx
  lea    0x1(%rax),%rax
  test   %rdx,%rdx
  cmove  %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *getname(const char *fname) {
  char *result;
  result = strrchr(fname, '/');
  if (result)
    return ++result;
  result = strrchr(fname, '\\');
  if (result)
    return ++result;
  return fname;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gui_completion_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <gui_completion_free_data@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void gui_completion_free(struct t_gui_completion *completion) {
  gui_completion_free_data(completion);
  free(completion);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gui_completion_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <gui_completion_free_data@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void gui_completion_free(struct t_gui_completion *completion) {
  gui_completion_free_data(completion);
  free(completion);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gui_completion_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <gui_completion_free_data@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void gui_completion_free(struct t_gui_completion *completion) {
  gui_completion_free_data(completion);
  free(completion);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gui_completion_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <gui_completion_free_data@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void gui_completion_free(struct t_gui_completion *completion) {
  gui_completion_free_data(completion);
  free(completion);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <create_graph@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_graph@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <DFS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <BFS@plt>
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int V = 5;
  struct Graph *graph = create_graph(V);
  add_edge(graph, 0, 1);
  add_edge(graph, 0, 4);
  add_edge(graph, 1, 2);
  add_edge(graph, 1, 3);
  add_edge(graph, 1, 4);
  add_edge(graph, 2, 3);
  add_edge(graph, 3, 4);
  print_graph(graph);
  DFS(graph, 0);
  BFS(graph, 0);
}
```