ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<div>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printd@plt>
  lea    D0(%rip),%rdi
  call   <print@plt>
  mov    %ebx,%edi
  call   <printd@plt>
  lea    D1(%rip),%rdi
  call   <print@plt>
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edi
  call   <printd@plt>
  add    $0x8,%rsp
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %r12
  jmp    1060 <print@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D4
datatype: string

tool: D0:  / 

tool: D1:  -> 

tool: D4: 


assistant: ```c
void div(int a, int b) {
  printd(a);
  print(" / ");
  printd(b);
  print(" -> ");
  printd(a / b);
  print("\r\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<div>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printd@plt>
  lea    D0(%rip),%rdi
  call   <print@plt>
  mov    %ebx,%edi
  call   <printd@plt>
  lea    D16(%rip),%rdi
  call   <print@plt>
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edi
  call   <printd@plt>
  add    $0x8,%rsp
  lea    D27(%rip),%rdi
  pop    %rbx
  pop    %r12
  jmp    1060 <print@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string
name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D27
type: string

tool: D0:  / 

tool: D16:  -> 

tool: D27: 


assistant: ```c
void div(int a, int b) {
  printd(a);
  print(" / ");
  printd(b);
  print(" -> ");
  printd(a / b);
  print("\r\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  sete   %al
  mov    %al,-0x1f(%rbp)
  jmp    L5
L20:
  mov    -0x18(%rbp),%rax
  add    %rax,-0x10(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  sete   %al
  mov    %al,-0x1f(%rbp)
L5:
  cmpb   $0x0,-0x1f(%rbp)
  jne    L20
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1e(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1d(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type_guessed: string
name: extract_symbolic_data
arguments: tag: D31
type_guessed: string
name: extract_symbolic_data
arguments: tag: D58
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D47
type_guessed: string

tool: D21: Please enter an integer to be summed 

tool: D31: (q to quit): 

tool: D58: %ld

tool: D14: Please enter next integer (q to quit): 

tool: D47: Those integers sum to %ld.


assistant: ```c
int main(void) {
  long num;
  long sum = 0L;
  _Bool input_is_good;
  printf("Please enter an integer to be summed ");
  printf("(q to quit): ");
  int n = scanf("%ld", &num);
  input_is_good = (n == 1);
  while (input_is_good) {
    sum += num;
    printf("Please enter next integer (q to quit): ");
    input_is_good = (scanf("%ld", &num) == 1);
  }
  printf("Those integers sum to %ld.\n", sum);
  char ch = getchar();
  char ch2 = getchar();
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L0
  mov    $0x0,%ebx
  lea    D22(%rip),%r13
  mov    %rsp,%r12
  lea    D28(%rip),%rbp
L12:
  add    (%rsp),%rbx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L12
L15:
  mov    %rbx,%rsi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    $0x0,%ebx
  jmp    L15
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D28
data_type: string
name: parse_data
arguments: data_label: D22
data_type: string
name: parse_data
arguments: data_label: D47
data_type: string

tool: D14: Please enter an integer to be summed 

tool: D20: (q to quit): 

tool: D28: %ld

tool: D22: Please enter next integer (q to quit): 

tool: D47: Those integers sum to %ld.


assistant: ```c
int main(void) {
  long num;
  long sum = 0L;
  _Bool input_is_good;
  printf("Please enter an integer to be summed ");
  printf("(q to quit): ");
  int n = scanf("%ld", &num);
  input_is_good = (n == 1);
  while (input_is_good) {
    sum += num;
    printf("Please enter next integer (q to quit): ");
    input_is_good = (scanf("%ld", &num) == 1);
  }
  printf("Those integers sum to %ld.\n", sum);
  char ch = getchar();
  char ch2 = getchar();
  getchar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%rdi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D24(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <printf@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L29
  lea    D40(%rip),%r13
  nopl   (%rax)
L25:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    (%rsp),%rbp
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L25
L29:
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D24
type_infered: string
name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D40
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string

tool: D9: Please enter an integer to be summed 

tool: D24: %ld

tool: D15: (q to quit): 

tool: D40: Please enter next integer (q to quit): 

tool: D10: Those integers sum to %ld.


assistant: ```c
int main(void) {
  long num;
  long sum = 0L;
  _Bool input_is_good;
  printf("Please enter an integer to be summed ");
  printf("(q to quit): ");
  int n = scanf("%ld", &num);
  input_is_good = (n == 1);
  while (input_is_good) {
    sum += num;
    printf("Please enter next integer (q to quit): ");
    input_is_good = (scanf("%ld", &num) == 1);
  }
  printf("Those integers sum to %ld.\n", sum);
  char ch = getchar();
  char ch2 = getchar();
  getchar();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D48(%rip),%rdi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <printf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L26
  lea    D39(%rip),%r13
  nopl   (%rax)
L19:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    (%rsp),%rbp
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L19
L26:
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D48
type_guessed: string
name: disassemble_data
arguments: data_label: D33
type_guessed: string
name: disassemble_data
arguments: data_label: D41
type_guessed: string
name: disassemble_data
arguments: data_label: D39
type_guessed: string
name: disassemble_data
arguments: data_label: D27
type_guessed: string

tool: D48: Please enter an integer to be summed 

tool: D33: %ld

tool: D41: (q to quit): 

tool: D39: Please enter next integer (q to quit): 

tool: D27: Those integers sum to %ld.


assistant: ```c
int main(void) {
  long num;
  long sum = 0L;
  _Bool input_is_good;
  printf("Please enter an integer to be summed ");
  printf("(q to quit): ");
  int n = scanf("%ld", &num);
  input_is_good = (n == 1);
  while (input_is_good) {
    sum += num;
    printf("Please enter next integer (q to quit): ");
    input_is_good = (scanf("%ld", &num) == 1);
  }
  printf("Those integers sum to %ld.\n", sum);
  char ch = getchar();
  char ch2 = getchar();
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<readmnull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <readmsg@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L6
  mov    $0x0,%eax
  call   <readmend@plt>
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int readmnull(int msg) {
  int x;
  x = readmsg(msg);
  if (x == (1))
    x = readmend();
  return (x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readmnull>:
  endbr64
  sub    $0x8,%rsp
  call   <readmsg@plt>
  cmp    $0x1,%eax
  je     L7
L8:
  add    $0x8,%rsp
  ret
L7:
  mov    $0x0,%eax
  call   <readmend@plt>
  jmp    L8
```

assistant: ```c
int readmnull(int msg) {
  int x;
  x = readmsg(msg);
  if (x == (1))
    x = readmend();
  return (x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readmnull>:
  endbr64
  sub    $0x8,%rsp
  call   <readmsg@plt>
  cmp    $0x1,%eax
  je     L5
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <readmend@plt>
```

assistant: ```c
int readmnull(int msg) {
  int x;
  x = readmsg(msg);
  if (x == (1))
    x = readmend();
  return (x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readmnull>:
  endbr64
  sub    $0x8,%rsp
  call   <readmsg@plt>
  cmp    $0x1,%eax
  je     L4
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <readmend@plt>
```

assistant: ```c
int readmnull(int msg) {
  int x;
  x = readmsg(msg);
  if (x == (1))
    x = readmend();
  return (x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<perf_get_description>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: Syncs the file system (a newly created empty file system is preferable). Creates a file named perf_test_file_pid, where pid is the process id. The file is filled with random data. The size of the file is given by the -z or --size option, otherwise it defaults to 10MiB. Unmounts the file system. Mounts the file system. Reads the entire file in 32KiB size blocks. Displays the time taken for each activity. Deletes the file. Note that the file is synced after writing and that time is included in the write time and speed.

assistant: ```c
const char *perf_get_description(void) {
  return "Syncs the file system (a newly created empty file system is "
         "preferable). Creates a file named perf_test_file_pid, where "
         "pid is the process id. The file is filled with random data. "
         "The size of the file is given by the -z or --size option, "
         "otherwise it defaults to 10MiB. Unmounts the file system. "
         "Mounts the file system. Reads the entire file in 32KiB size "
         "blocks. Displays the time taken for each activity. Deletes "
         "the file. Note that the file is synced after writing and "
         "that time is included in the write time and speed.";
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<perf_get_description>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: Syncs the file system (a newly created empty file system is preferable). Creates a file named perf_test_file_pid, where pid is the process id. The file is filled with random data. The size of the file is given by the -z or --size option, otherwise it defaults to 10MiB. Unmounts the file system. Mounts the file system. Reads the entire file in 32KiB size blocks. Displays the time taken for each activity. Deletes the file. Note that the file is synced after writing and that time is included in the write time and speed.

assistant: ```c
const char *perf_get_description(void) {
  return "Syncs the file system (a newly created empty file system is "
         "preferable). Creates a file named perf_test_file_pid, where "
         "pid is the process id. The file is filled with random data. "
         "The size of the file is given by the -z or --size option, "
         "otherwise it defaults to 10MiB. Unmounts the file system. "
         "Mounts the file system. Reads the entire file in 32KiB size "
         "blocks. Displays the time taken for each activity. Deletes "
         "the file. Note that the file is synced after writing and "
         "that time is included in the write time and speed.";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<perf_get_description>:
  endbr64
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string

tool: D7: Syncs the file system (a newly created empty file system is preferable). Creates a file named perf_test_file_pid, where pid is the process id. The file is filled with random data. The size of the file is given by the -z or --size option, otherwise it defaults to 10MiB. Unmounts the file system. Mounts the file system. Reads the entire file in 32KiB size blocks. Displays the time taken for each activity. Deletes the file. Note that the file is synced after writing and that time is included in the write time and speed.

assistant: ```c
const char *perf_get_description(void) {
  return "Syncs the file system (a newly created empty file system is "
         "preferable). Creates a file named perf_test_file_pid, where "
         "pid is the process id. The file is filled with random data. "
         "The size of the file is given by the -z or --size option, "
         "otherwise it defaults to 10MiB. Unmounts the file system. "
         "Mounts the file system. Reads the entire file in 32KiB size "
         "blocks. Displays the time taken for each activity. Deletes "
         "the file. Note that the file is synced after writing and "
         "that time is included in the write time and speed.";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<perf_get_description>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: Syncs the file system (a newly created empty file system is preferable). Creates a file named perf_test_file_pid, where pid is the process id. The file is filled with random data. The size of the file is given by the -z or --size option, otherwise it defaults to 10MiB. Unmounts the file system. Mounts the file system. Reads the entire file in 32KiB size blocks. Displays the time taken for each activity. Deletes the file. Note that the file is synced after writing and that time is included in the write time and speed.

assistant: ```c
const char *perf_get_description(void) {
  return "Syncs the file system (a newly created empty file system is "
         "preferable). Creates a file named perf_test_file_pid, where "
         "pid is the process id. The file is filled with random data. "
         "The size of the file is given by the -z or --size option, "
         "otherwise it defaults to 10MiB. Unmounts the file system. "
         "Mounts the file system. Reads the entire file in 32KiB size "
         "blocks. Displays the time taken for each activity. Deletes "
         "the file. Note that the file is synced after writing and "
         "that time is included in the write time and speed.";
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_collapse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x10,%r13d
  jmp    L46
L14:
  sub    $0x1,%r13d
  je     L29
L46:
  mov    $0x10,%r12d
L32:
  mov    $0x10,%ebp
L9:
  mov    $0x10,%ebx
L33:
  mov    $0x0,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L33
  sub    $0x1,%ebp
  jne    L9
  sub    $0x1,%r12d
  jne    L32
  jmp    L14
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp parallel
#pragma omp for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp parallel
#pragma omp for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_collapse>:
  endbr64
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L33:
  mov    $0x10,%r12d
L8:
  mov    $0x10,%ebp
  nop
L17:
  mov    $0x10,%ebx
  nopl   (%rax)
L24:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L24
  sub    $0x1,%ebp
  jne    L17
  sub    $0x1,%r12d
  jne    L8
  sub    $0x1,%r13d
  jne    L33
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp parallel
#pragma omp for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp parallel
#pragma omp for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
}
```