ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<ILLutil_linked_radixsort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  movslq %ecx,%rax
  mov    %rdi,%r9
  sub    %rdi,%rsi
  mov    %fs:0x28,%rcx
  mov    %rcx,0x1018(%rsp)
  xor    %ecx,%ecx
  mov    %rdx,%rcx
  mov    %eax,%edx
  sub    %rdi,%rcx
  sub    $0x1,%edx
  js     L17
  movslq %edx,%r10
  lea    -0x2(%rcx,%rax,1),%rbx
  mov    %edx,%edx
  mov    %rsi,%r11
  add    %rcx,%r10
  sub    %rdx,%rbx
  lea    0x10(%rsp),%r8
  xor    %eax,%eax
  lea    0x810(%rsp),%rsi
  lea    0x8(%rsp),%rbp
L48:
  mov    $0x100,%ecx
  mov    %r8,%rdi
  mov    %r8,%rdx
  rep stos %rax,%es:(%rdi)
  mov    %rsi,%rcx
L30:
  mov    %rdx,(%rcx)
  add    $0x8,%rdx
  add    $0x8,%rcx
  cmp    %rsi,%rdx
  jne    L30
  test   %r9,%r9
  je     L70
  nopl   (%rax)
L10:
  movzbl (%r9,%r10,1),%edx
  mov    0x810(%rsp,%rdx,8),%rcx
  mov    %r9,(%rcx)
  add    %r11,%r9
  mov    %r9,0x810(%rsp,%rdx,8)
  mov    (%r9),%r9
  test   %r9,%r9
  jne    L10
L70:
  xor    %edx,%edx
  mov    %rbp,%rdi
L75:
  mov    (%r8,%rdx,1),%rcx
  test   %rcx,%rcx
  je     L25
  mov    %rcx,(%rdi)
  mov    (%rsi,%rdx,1),%rdi
L25:
  add    $0x8,%rdx
  cmp    $0x800,%rdx
  jne    L75
  sub    $0x1,%r10
  movq   $0x0,(%rdi)
  mov    0x8(%rsp),%r9
  cmp    %rbx,%r10
  jne    L48
L17:
  mov    0x1018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x1028,%rsp
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ILLutil_linked_radixsort(char *data, char *datanext, char *dataval, int valsize) {
  size_t nextoff = datanext - data;
  size_t valoff = dataval - data;
  int i;
  char *head[(1 << (8))];
  char **tail[(1 << (8))];
  char *p;
  char **last;
  int j;
  int v;
  for (j = valsize - 1; j >= 0; j--) {
    for (i = 0; i < (1 << (8)); i++) {
      head[i] = (char *)NULL;
      tail[i] = &head[i];
    }
    for (p = data; p; p = *(char **)(p + nextoff)) {
      v = (unsigned char)p[valoff + j];
      *tail[v] = p;
      tail[v] = (char **)(p + nextoff);
    }
    last = &data;
    for (i = 0; i < (1 << (8)); i++) {
      if (head[i]) {
        *last = head[i];
        last = tail[i];
      }
    }
    *last = (char *)NULL;
  }
  return data;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bn_sub_words>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %ecx,%ebx
  mov    %ecx,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  test   %ebx,%ebx
  jle    L35
  lea    -0x4(%rbx),%ecx
  lea    -0x1(%rbx),%eax
  and    $0xfffffffc,%eax
  sub    %eax,%ecx
  mov    %ebx,%esi
  and    $0x3,%esi
  mov    $0x0,%eax
  jmp    L67
L81:
  sub    $0x4,%ebx
  cmp    %ecx,%ebx
  je     L40
  add    $0x20,%r12
  add    $0x20,%r13
  add    $0x20,%rbp
L67:
  mov    (%r12),%r8
  mov    0x0(%r13),%rdi
  movslq %eax,%rdx
  add    %rdi,%rdx
  mov    %r8,%r9
  sub    %rdx,%r9
  mov    %r9,0x0(%rbp)
  cmp    %rdi,%r8
  je     L19
  setb   %al
  movzbl %al,%eax
L19:
  cmp    $0x1,%ebx
  jle    L40
  mov    0x8(%r12),%r8
  mov    0x8(%r13),%rdi
  mov    %r8,%rdx
  sub    %rdi,%rdx
  movslq %eax,%r9
  sub    %r9,%rdx
  mov    %rdx,0x8(%rbp)
  cmp    %rdi,%r8
  je     L44
  setb   %al
  movzbl %al,%eax
L44:
  cmp    $0x2,%ebx
  jle    L40
  mov    0x10(%r12),%r8
  mov    0x10(%r13),%rdi
  mov    %r8,%rdx
  sub    %rdi,%rdx
  movslq %eax,%r9
  sub    %r9,%rdx
  mov    %rdx,0x10(%rbp)
  cmp    %rdi,%r8
  je     L82
  setb   %al
  movzbl %al,%eax
L82:
  cmp    %esi,%ebx
  je     L40
  mov    0x18(%r12),%r8
  mov    0x18(%r13),%rdi
  mov    %r8,%rdx
  sub    %rdi,%rdx
  movslq %eax,%r9
  sub    %r9,%rdx
  mov    %rdx,0x18(%rbp)
  cmp    %rdi,%r8
  je     L81
  setb   %al
  movzbl %al,%eax
  jmp    L81
L40:
  cltq
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long long bn_sub_words(unsigned long long *r, unsigned long long *a, unsigned long long *b, int n) {
  unsigned long long t1, t2;
  int c = 0;
  assert(n >= 0);
  if (n <= 0)
    return ((unsigned long long)0);
  for (;;) {
    t1 = a[0];
    t2 = b[0];
    r[0] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[1];
    t2 = b[1];
    r[1] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[2];
    t2 = b[2];
    r[2] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[3];
    t2 = b[3];
    r[3] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    a += 4;
    b += 4;
    r += 4;
  }
  return (c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bn_sub_words>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %ecx,%edi
  push   %rbx
  not    %edi
  mov    %ecx,%ebx
  shr    $0x1f,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  jle    L14
  xor    %ecx,%ecx
  jmp    L88
  cs nopw 0x0(%rax,%rax,1)
L82:
  mov    0x8(%r12),%rdi
  mov    0x8(%r13),%rsi
  mov    %rdi,%rdx
  sub    %rsi,%rdx
  sub    %rax,%rdx
  mov    %rdx,0x8(%rbp)
  cmp    %rsi,%rdi
  je     L41
  setb   %cl
  setb   %al
  movzbl %cl,%ecx
  movzbl %al,%eax
L41:
  cmp    $0x2,%ebx
  je     L14
  mov    0x10(%r12),%rdi
  mov    0x10(%r13),%rsi
  mov    %rdi,%rdx
  sub    %rsi,%rdx
  sub    %rax,%rdx
  mov    %rdx,0x10(%rbp)
  cmp    %rsi,%rdi
  je     L36
  setb   %cl
  setb   %al
  movzbl %cl,%ecx
  movzbl %al,%eax
L36:
  cmp    $0x3,%ebx
  je     L14
  mov    0x18(%r12),%rdi
  mov    0x18(%r13),%rsi
  mov    %rdi,%rdx
  sub    %rsi,%rdx
  sub    %rax,%rdx
  mov    %rdx,0x18(%rbp)
  cmp    %rsi,%rdi
  je     L30
  setb   %cl
  setb   %al
  movzbl %cl,%ecx
  movzbl %al,%eax
L30:
  sub    $0x4,%ebx
  je     L14
  add    $0x20,%r12
  add    $0x20,%r13
  add    $0x20,%rbp
L88:
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdx
  movslq %ecx,%rax
  lea    (%rax,%rdx,1),%r8
  mov    %rsi,%rdi
  sub    %r8,%rdi
  mov    %rdi,0x0(%rbp)
  cmp    %rdx,%rsi
  je     L32
  setb   %cl
  setb   %al
  movzbl %cl,%ecx
  movzbl %al,%eax
L32:
  cmp    $0x1,%ebx
  jne    L82
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long long bn_sub_words(unsigned long long *r, unsigned long long *a, unsigned long long *b, int n) {
  unsigned long long t1, t2;
  int c = 0;
  assert(n >= 0);
  if (n <= 0)
    return ((unsigned long long)0);
  for (;;) {
    t1 = a[0];
    t2 = b[0];
    r[0] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[1];
    t2 = b[1];
    r[1] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[2];
    t2 = b[2];
    r[2] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[3];
    t2 = b[3];
    r[3] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    a += 4;
    b += 4;
    r += 4;
  }
  return (c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bn_sub_words>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %ecx,%edi
  push   %rbx
  not    %edi
  mov    %ecx,%ebx
  shr    $0x1f,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  jle    L7
  xor    %ecx,%ecx
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    0x8(%r12),%rdi
  mov    0x8(%r13),%rsi
  mov    %rdi,%rdx
  sub    %rsi,%rdx
  sub    %rax,%rdx
  mov    %rdx,0x8(%rbp)
  cmp    %rsi,%rdi
  je     L18
  setb   %cl
  setb   %al
  movzbl %cl,%ecx
  movzbl %al,%eax
L18:
  cmp    $0x2,%ebx
  je     L7
  mov    0x10(%r12),%rdi
  mov    0x10(%r13),%rsi
  mov    %rdi,%rdx
  sub    %rsi,%rdx
  sub    %rax,%rdx
  mov    %rdx,0x10(%rbp)
  cmp    %rsi,%rdi
  je     L21
  setb   %cl
  setb   %al
  movzbl %cl,%ecx
  movzbl %al,%eax
L21:
  cmp    $0x3,%ebx
  je     L7
  mov    0x18(%r12),%rdi
  mov    0x18(%r13),%rsi
  mov    %rdi,%rdx
  sub    %rsi,%rdx
  sub    %rax,%rdx
  mov    %rdx,0x18(%rbp)
  cmp    %rsi,%rdi
  je     L99
  setb   %cl
  setb   %al
  movzbl %cl,%ecx
  movzbl %al,%eax
L99:
  sub    $0x4,%ebx
  je     L7
  add    $0x20,%r12
  add    $0x20,%r13
  add    $0x20,%rbp
L49:
  mov    (%r12),%rsi
  mov    0x0(%r13),%rdx
  movslq %ecx,%rax
  lea    (%rax,%rdx,1),%r8
  mov    %rsi,%rdi
  sub    %r8,%rdi
  mov    %rdi,0x0(%rbp)
  cmp    %rdx,%rsi
  je     L65
  setb   %cl
  setb   %al
  movzbl %cl,%ecx
  movzbl %al,%eax
L65:
  cmp    $0x1,%ebx
  jne    L17
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long long bn_sub_words(unsigned long long *r, unsigned long long *a, unsigned long long *b, int n) {
  unsigned long long t1, t2;
  int c = 0;
  assert(n >= 0);
  if (n <= 0)
    return ((unsigned long long)0);
  for (;;) {
    t1 = a[0];
    t2 = b[0];
    r[0] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[1];
    t2 = b[1];
    r[1] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[2];
    t2 = b[2];
    r[2] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    t1 = a[3];
    t2 = b[3];
    r[3] = (t1 - t2 - c) & (0xffffffffffffffffLL);
    if (t1 != t2)
      c = (t1 < t2);
    if (--n <= 0)
      break;
    a += 4;
    b += 4;
    r += 4;
  }
  return (c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mystrncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L35
L8:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L35
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x10(%rbp),%rdx
  sub    $0x1,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  sub    %edx,%eax
  jmp    L28
L35:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int __attribute__((always_)) mystrncmp(const char *s1, const char *s2, size_t n) {
  while (n--)
    if (*s1++ != *s2++)
      return *(unsigned char *)(s1 - 1) - *(unsigned char *)(s2 - 1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mystrncmp>:
  endbr64
  mov    $0x0,%eax
L11:
  cmp    %rax,%rdx
  je     L15
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L11
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int __attribute__((always_)) mystrncmp(const char *s1, const char *s2, size_t n) {
  while (n--)
    if (*s1++ != *s2++)
      return *(unsigned char *)(s1 - 1) - *(unsigned char *)(s2 - 1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mystrncmp>:
  endbr64
  xor    %eax,%eax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L29
L22:
  cmp    %rax,%rdx
  jne    L11
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
```

assistant: ```c
int __attribute__((always_)) mystrncmp(const char *s1, const char *s2, size_t n) {
  while (n--)
    if (*s1++ != *s2++)
      return *(unsigned char *)(s1 - 1) - *(unsigned char *)(s2 - 1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mystrncmp>:
  endbr64
  xor    %eax,%eax
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L27:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L24
L10:
  cmp    %rax,%rdx
  jne    L27
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
```

assistant: ```c
int __attribute__((always_)) mystrncmp(const char *s1, const char *s2, size_t n) {
  while (n--)
    if (*s1++ != *s2++)
      return *(unsigned char *)(s1 - 1) - *(unsigned char *)(s2 - 1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calcUglyNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L21
  mov    $0x1,%eax
  jmp    L61
L59:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <isUglyNumber@plt>
  test   %eax,%eax
  jne    L36
  jmp    L21
L36:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L21
  mov    -0x8(%rbp),%rax
  jmp    L61
L21:
  addq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L59
L61:
  leave
  ret
```

assistant: ```c
long calcUglyNumber(int nth) {
  long number = 1;
  int n = 1;
  if (nth == 1)
    return 1;
  while (++number) {
    if (!isUglyNumber(number))
      continue;
    n++;
    if (n == nth)
      return number;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<calcUglyNumber>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  cmp    $0x1,%edi
  je     L32
  mov    %edi,%r12d
  mov    $0x2,%ebx
  mov    $0x1,%ebp
  jmp    L13
L16:
  add    $0x1,%rbx
L13:
  mov    %rbx,%rdi
  call   <isUglyNumber@plt>
  test   %eax,%eax
  je     L16
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jne    L16
L32:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long calcUglyNumber(int nth) {
  long number = 1;
  int n = 1;
  if (nth == 1)
    return 1;
  while (++number) {
    if (!isUglyNumber(number))
      continue;
    n++;
    if (n == nth)
      return number;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calcUglyNumber>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L19
  mov    %edi,%ebp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%r12
  mov    %r12,%rdi
  call   <isUglyNumber@plt>
  test   %eax,%eax
  je     L3
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L3
L19:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long calcUglyNumber(int nth) {
  long number = 1;
  int n = 1;
  if (nth == 1)
    return 1;
  while (++number) {
    if (!isUglyNumber(number))
      continue;
    n++;
    if (n == nth)
      return number;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<calcUglyNumber>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L6
  mov    %edi,%ebp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%r12
  mov    %r12,%rdi
  call   <isUglyNumber@plt>
  test   %eax,%eax
  je     L20
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L20
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long calcUglyNumber(int nth) {
  long number = 1;
  int n = 1;
  if (nth == 1)
    return 1;
  while (++number) {
    if (!isUglyNumber(number))
      continue;
    n++;
    if (n == nth)
      return number;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kinematicsInverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  %xmm3,-0x20(%rbp)
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x1c(%rbp),%xmm0
  jae    L26
  pxor   %xmm0,%xmm0
  comiss -0x20(%rbp),%xmm0
  jb     L23
L26:
  mov    $0x0,%eax
  jmp    L27
L23:
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  subss  %xmm0,%xmm1
  movss  -0x20(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  subss  %xmm0,%xmm1
  cvtss2sd %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x1c(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd -0x20(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  pxor   %xmm7,%xmm7
  cvtsd2ss %xmm1,%xmm7
  movd   %xmm7,%eax
  movd   %eax,%xmm0
  call   <acosf@plt>
  movd   %xmm0,%eax
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  movss  -0x14(%rbp),%xmm0
  mov    -0x18(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <atan2f@plt>
  movd   %xmm0,%ebx
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  -0x20(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,-0x34(%rbp)
  movss  -0x1c(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm5
  mulss  %xmm0,%xmm5
  movaps %xmm5,%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movaps %xmm1,%xmm6
  addss  %xmm0,%xmm6
  movd   %xmm6,%eax
  movd   %eax,%xmm0
  call   <sqrtf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  -0x38(%rbp),%xmm0
  movss  -0x34(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <acosf@plt>
  movaps %xmm0,%xmm1
  movd   %ebx,%xmm0
  subss  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    $0x1,%eax
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int kinematicsInverse(float x, float y, float L1, float L2, float *S, float *E) {
  if (L1 <= 0 || L2 <= 0)
    return 0;
  *E = acosf((x * x + y * y - L1 * L1 - L2 * L2) / (2. * L1 * L2));
  *S = atan2f(y, x) - acosf((x * x + y * y + L1 * L1 - L2 * L2) / (2 * L1 * sqrtf(x * x + y * y)));
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<kinematicsInverse>:
  endbr64
  movaps %xmm0,%xmm7
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
  comiss %xmm2,%xmm0
  jae    L0
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movaps %xmm1,%xmm5
  movaps %xmm2,%xmm4
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  comiss %xmm3,%xmm0
  jae    L6
  movaps %xmm7,%xmm6
  movss  %xmm7,0x18(%rsp)
  mulss  %xmm7,%xmm6
  movaps %xmm6,%xmm1
  movaps %xmm5,%xmm6
  movss  %xmm5,0x1c(%rsp)
  mulss  %xmm5,%xmm6
  movaps %xmm1,%xmm2
  addss  %xmm6,%xmm2
  movaps %xmm4,%xmm5
  movaps %xmm4,%xmm6
  mulss  %xmm4,%xmm6
  movaps %xmm6,%xmm4
  movaps %xmm3,%xmm8
  mulss  %xmm3,%xmm8
  movss  %xmm2,0xc(%rsp)
  movaps %xmm2,%xmm6
  movss  %xmm4,0x10(%rsp)
  subss  %xmm4,%xmm6
  movaps %xmm6,%xmm0
  movss  %xmm8,0x14(%rsp)
  subss  %xmm8,%xmm0
  cvtss2sd %xmm0,%xmm0
  movss  %xmm5,0x8(%rsp)
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm5,%xmm1
  addsd  %xmm1,%xmm1
  cvtss2sd %xmm3,%xmm3
  mulsd  %xmm3,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <acosf@plt>
  movss  %xmm0,0x0(%rbp)
  movss  0x18(%rsp),%xmm1
  movss  0x1c(%rsp),%xmm0
  call   <atan2f@plt>
  movss  %xmm0,0x18(%rsp)
  movss  0x10(%rsp),%xmm4
  movss  0xc(%rsp),%xmm2
  addss  %xmm2,%xmm4
  movaps %xmm4,%xmm7
  subss  0x14(%rsp),%xmm7
  movss  %xmm7,0xc(%rsp)
  movaps %xmm2,%xmm0
  call   <sqrtf@plt>
  movss  0x8(%rsp),%xmm1
  addss  %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm0,%xmm1
  movss  0xc(%rsp),%xmm7
  divss  %xmm1,%xmm7
  movaps %xmm7,%xmm0
  call   <acosf@plt>
  movaps %xmm0,%xmm1
  movss  0x18(%rsp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rbx)
  mov    $0x1,%eax
L6:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  ret
```

assistant: ```c
int kinematicsInverse(float x, float y, float L1, float L2, float *S, float *E) {
  if (L1 <= 0 || L2 <= 0)
    return 0;
  *E = acosf((x * x + y * y - L1 * L1 - L2 * L2) / (2. * L1 * L2));
  *S = atan2f(y, x) - acosf((x * x + y * y + L1 * L1 - L2 * L2) / (2 * L1 * sqrtf(x * x + y * y)));
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kinematicsInverse>:
  endbr64
  movaps %xmm0,%xmm5
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  comiss %xmm2,%xmm0
  jae    L5
  comiss %xmm3,%xmm0
  jae    L5
  movaps %xmm5,%xmm7
  movaps %xmm1,%xmm0
  push   %rbp
  movaps %xmm2,%xmm6
  mulss  %xmm5,%xmm7
  push   %rbx
  movaps %xmm3,%xmm8
  mov    %rdi,%rbx
  mulss  %xmm1,%xmm0
  mov    %rsi,%rbp
  mulss  %xmm2,%xmm6
  mulss  %xmm3,%xmm8
  sub    $0x28,%rsp
  cvtss2sd %xmm3,%xmm3
  movss  %xmm1,0x18(%rsp)
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  addsd  %xmm1,%xmm1
  movss  %xmm2,0xc(%rsp)
  addss  %xmm0,%xmm7
  movss  %xmm5,0x1c(%rsp)
  movss  %xmm6,0x10(%rsp)
  mulsd  %xmm3,%xmm1
  movss  %xmm8,0x8(%rsp)
  movaps %xmm7,%xmm0
  movss  %xmm7,0x14(%rsp)
  subss  %xmm6,%xmm0
  subss  %xmm8,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <acosf@plt>
  movss  0x1c(%rsp),%xmm5
  movss  0x18(%rsp),%xmm4
  movss  %xmm0,0x0(%rbp)
  movaps %xmm5,%xmm1
  movaps %xmm4,%xmm0
  call   <atan2f@plt>
  movss  0x14(%rsp),%xmm7
  movss  0x10(%rsp),%xmm6
  movss  0x8(%rsp),%xmm8
  movd   %xmm0,%ebp
  addss  %xmm7,%xmm6
  movaps %xmm7,%xmm0
  subss  %xmm8,%xmm6
  movss  %xmm6,0x8(%rsp)
  call   <sqrtf@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm6
  cvtsi2ss %eax,%xmm0
  addss  %xmm2,%xmm2
  mulss  %xmm0,%xmm2
  divss  %xmm2,%xmm6
  movaps %xmm6,%xmm0
  call   <acosf@plt>
  mov    $0x1,%eax
  movaps %xmm0,%xmm1
  movd   %ebp,%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  ret
```

assistant: ```c
int kinematicsInverse(float x, float y, float L1, float L2, float *S, float *E) {
  if (L1 <= 0 || L2 <= 0)
    return 0;
  *E = acosf((x * x + y * y - L1 * L1 - L2 * L2) / (2. * L1 * L2));
  *S = atan2f(y, x) - acosf((x * x + y * y + L1 * L1 - L2 * L2) / (2 * L1 * sqrtf(x * x + y * y)));
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kinematicsInverse>:
  endbr64
  movaps %xmm0,%xmm5
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  comiss %xmm2,%xmm0
  jae    L15
  comiss %xmm3,%xmm0
  jae    L15
  movaps %xmm5,%xmm7
  movaps %xmm1,%xmm0
  push   %rbp
  movaps %xmm2,%xmm6
  mulss  %xmm5,%xmm7
  push   %rbx
  movaps %xmm3,%xmm8
  mov    %rdi,%rbx
  mulss  %xmm1,%xmm0
  mov    %rsi,%rbp
  mulss  %xmm2,%xmm6
  mulss  %xmm3,%xmm8
  sub    $0x28,%rsp
  cvtss2sd %xmm3,%xmm3
  movss  %xmm1,0x18(%rsp)
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  addsd  %xmm1,%xmm1
  movss  %xmm2,0xc(%rsp)
  addss  %xmm0,%xmm7
  movss  %xmm5,0x1c(%rsp)
  movss  %xmm6,0x10(%rsp)
  mulsd  %xmm3,%xmm1
  movss  %xmm8,0x8(%rsp)
  movaps %xmm7,%xmm0
  movss  %xmm7,0x14(%rsp)
  subss  %xmm6,%xmm0
  subss  %xmm8,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <acosf@plt>
  movss  0x1c(%rsp),%xmm5
  movss  0x18(%rsp),%xmm4
  movss  %xmm0,0x0(%rbp)
  movaps %xmm5,%xmm1
  movaps %xmm4,%xmm0
  call   <atan2f@plt>
  movss  0x14(%rsp),%xmm7
  movss  0x10(%rsp),%xmm6
  movss  0x8(%rsp),%xmm8
  movd   %xmm0,%ebp
  addss  %xmm7,%xmm6
  movaps %xmm7,%xmm0
  subss  %xmm8,%xmm6
  movss  %xmm6,0x8(%rsp)
  call   <sqrtf@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm6
  cvtsi2ss %eax,%xmm0
  addss  %xmm2,%xmm2
  mulss  %xmm0,%xmm2
  divss  %xmm2,%xmm6
  movaps %xmm6,%xmm0
  call   <acosf@plt>
  mov    $0x1,%eax
  movaps %xmm0,%xmm1
  movd   %ebp,%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  ret
```

assistant: ```c
int kinematicsInverse(float x, float y, float L1, float L2, float *S, float *E) {
  if (L1 <= 0 || L2 <= 0)
    return 0;
  *E = acosf((x * x + y * y - L1 * L1 - L2 * L2) / (2. * L1 * L2));
  *S = atan2f(y, x) - acosf((x * x + y * y + L1 * L1 - L2 * L2) / (2 * L1 * sqrtf(x * x + y * y)));
  return 1;
}
```