ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_203_0_0>:
  endbr64
  mov    %esi,%eax
  and    (%rdi),%al
  or     %edx,%eax
  xor    %esi,%eax
  not    %eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_203_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D & S;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_203_0_0>:
  endbr64
  movzbl (%rdi),%eax
  and    %esi,%eax
  or     %edx,%eax
  xor    %esi,%eax
  not    %eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_203_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D & S;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rop3_203_0_0>:
  endbr64
  movzbl (%rdi),%eax
  and    %esi,%eax
  or     %edx,%eax
  xor    %esi,%eax
  not    %eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_203_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D & S;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D45
data_type: string
name: extract_symbolic_data
arguments: data_tag: D24
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D9: 
Enter total revenue: 

tool: D45: %f

tool: D24: 
Enter total cost: 

tool: D1: 
Your profit is $%.2f


assistant: ```c
int main() {
  float fRevenue, fCost;
  printf("\nEnter total revenue: ");
  scanf("%f", &fRevenue);
  printf("\nEnter total cost: ");
  scanf("%f", &fCost);
  printf("\nYour profit is $%.2f\n", fRevenue - fCost);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D18(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D22
type_infered: string
name: unpack_data
arguments: data_label: D18
type_infered: string

tool: D7: 
Enter total revenue: 

tool: D19: %f

tool: D22: 
Enter total cost: 

tool: D18: 
Your profit is $%.2f


assistant: ```c
int main() {
  float fRevenue, fCost;
  printf("\nEnter total revenue: ");
  scanf("%f", &fRevenue);
  printf("\nEnter total cost: ");
  scanf("%f", &fCost);
  printf("\nYour profit is $%.2f\n", fRevenue - fCost);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D31(%rip),%rdi
  lea    D39(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  lea    D33(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D31
type_guessed: string
name: disassemble_data
arguments: tag: D39
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D33
type_guessed: string

tool: D31: 
Enter total revenue: 

tool: D39: %f

tool: D28: 
Enter total cost: 

tool: D33: 
Your profit is $%.2f


assistant: ```c
int main() {
  float fRevenue, fCost;
  printf("\nEnter total revenue: ");
  scanf("%f", &fRevenue);
  printf("\nEnter total cost: ");
  scanf("%f", &fCost);
  printf("\nYour profit is $%.2f\n", fRevenue - fCost);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D30(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  lea    D33(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D30
type: string
name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D33
type: string

tool: D0: 
Enter total revenue: 

tool: D30: %f

tool: D19: 
Enter total cost: 

tool: D33: 
Your profit is $%.2f


assistant: ```c
int main() {
  float fRevenue, fCost;
  printf("\nEnter total revenue: ");
  scanf("%f", &fRevenue);
  printf("\nEnter total cost: ");
  scanf("%f", &fCost);
  printf("\nYour profit is $%.2f\n", fRevenue - fCost);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printPointer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D9
type_infered: string

tool: D5: -... %p 


tool: D9: ... %p 


assistant: ```c
void printPointer(const void *p) {
  void **o = (void **)p;
  printf("-... %p \n", *o);
  printf("... %p \n", p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printPointer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string
name: unpack_data
arguments: data_tag: D13
data_type: string

tool: D8: -... %p 


tool: D13: ... %p 


assistant: ```c
void printPointer(const void *p) {
  void **o = (void **)p;
  printf("-... %p \n", *o);
  printf("... %p \n", p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printPointer>:
  endbr64
  push   %rbp
  mov    (%rdi),%rsi
  mov    %rdi,%rbp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_infered: string
name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D17: -... %p 


tool: D7: ... %p 


assistant: ```c
void printPointer(const void *p) {
  void **o = (void **)p;
  printf("-... %p \n", *o);
  printf("... %p \n", p);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printPointer>:
  endbr64
  push   %rbp
  mov    (%rdi),%rsi
  mov    %rdi,%rbp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_infered: string
name: disassemble_data
arguments: tag: D16
type_infered: string

tool: D12: -... %p 


tool: D16: ... %p 


assistant: ```c
void printPointer(const void *p) {
  void **o = (void **)p;
  printf("-... %p \n", *o);
  printf("... %p \n", p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L37
L25:
  mov    -0x20(%rbp),%rax
  mov    %r12d,%edx
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L22
  mov    %rbx,%rax
  jmp    L2
L22:
  add    $0x1,%rbx
L37:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  jne    L25
  mov    $0x0,%eax
L2:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(s1, s2)
char *s1, *s2;
{
  register char *p = s1;
  extern char *strchr();
  extern int strncmp();
  register int len = strlen(s2);
  for (; (p = strchr(p, *s2)) != 0; p++) {
    if (strncmp(p, s2, len) == 0) {
      return (p);
    }
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strstr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  movsbl 0x0(%rbp),%r13d
  movslq %eax,%r12
  jmp    L0
L22:
  add    $0x1,%rbx
L0:
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L22
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(s1, s2)
char *s1, *s2;
{
  register char *p = s1;
  extern char *strchr();
  extern int strncmp();
  register int len = strlen(s2);
  for (; (p = strchr(p, *s2)) != 0; p++) {
    if (strncmp(p, s2, len) == 0) {
      return (p);
    }
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strstr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movsbl (%rbx),%r13d
  movslq %eax,%rbp
  jmp    L18
  nopl   (%rax)
L21:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L13
  add    $0x1,%r12
L18:
  mov    %r12,%rdi
  mov    %r13d,%esi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L21
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(s1, s2)
char *s1, *s2;
{
  register char *p = s1;
  extern char *strchr();
  extern int strncmp();
  register int len = strlen(s2);
  for (; (p = strchr(p, *s2)) != 0; p++) {
    if (strncmp(p, s2, len) == 0) {
      return (p);
    }
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<strstr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movsbl (%rbx),%r13d
  movslq %eax,%rbp
  jmp    L21
  nopl   (%rax)
L8:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L25
  add    $0x1,%r12
L21:
  mov    %r12,%rdi
  mov    %r13d,%esi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L8
L25:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(s1, s2)
char *s1, *s2;
{
  register char *p = s1;
  extern char *strchr();
  extern int strncmp();
  register int len = strlen(s2);
  for (; (p = strchr(p, *s2)) != 0; p++) {
    if (strncmp(p, s2, len) == 0) {
      return (p);
    }
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strtoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L34
L83:
  addq   $0x1,-0x18(%rbp)
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L83
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L108
  addq   $0x1,-0x18(%rbp)
  jmp    L156
L108:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L156
  addq   $0x1,-0x18(%rbp)
  movl   $0x1,-0x10(%rbp)
L156:
  cmpl   $0x0,-0x24(%rbp)
  jne    L62
  movl   $0xa,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L62
  addq   $0x1,-0x18(%rbp)
  movl   $0x8,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  jne    L62
  addq   $0x1,-0x18(%rbp)
  movl   $0x10,-0x24(%rbp)
L62:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x60,-0xc(%rbp)
  jbe    L102
  subl   $0x57,-0xc(%rbp)
  jmp    L149
L102:
  cmpl   $0x40,-0xc(%rbp)
  jbe    L133
  subl   $0x37,-0xc(%rbp)
  jmp    L149
L133:
  cmpl   $0x39,-0xc(%rbp)
  ja     L149
  subl   $0x30,-0xc(%rbp)
L149:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jae    L8
  mov    -0x24(%rbp),%eax
  cltq
  imul   -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L62
L8:
  nop
  cmpq   $0x0,-0x20(%rbp)
  je     L31
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L31:
  cmpl   $0x0,-0x10(%rbp)
  je     L168
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L100
L168:
  mov    -0x8(%rbp),%rax
L100:
  leave
  ret
```

assistant: ```c
unsigned long strtoul(const char *nptr, char **endptr, int base) {
  unsigned long val = 0;
  int negate = 0;
  unsigned int digit;
  while (isspace(*nptr))
    nptr++;
  if (*nptr == '+') {
    nptr++;
  } else if (*nptr == '-') {
    nptr++;
    negate = 1;
  }
  if (base == 0) {
    base = 10;
    if (*nptr == '0') {
      nptr++;
      base = 8;
      if ((*nptr | 0x20) == 'x') {
        nptr++;
        base = 16;
      }
    }
  }
  while (1) {
    digit = *(nptr++);
    if (digit >= 'a') {
      digit = (digit - 'a' + 10);
    } else if (digit >= 'A') {
      digit = (digit - 'A' + 10);
    } else if (digit <= '9') {
      digit = (digit - '0');
    }
    if (digit >= (unsigned int)base)
      break;
    val = ((val * base) + digit);
  }
  if (endptr)
    *endptr = ((char *)nptr);
  return (negate ? -val : val);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strtoul>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  jmp    L67
L147:
  add    $0x1,%rbx
L67:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L147
  movzbl (%rbx),%eax
  cmp    $0x2b,%al
  je     L84
  mov    $0x0,%edi
  cmp    $0x2d,%al
  je     L128
L117:
  test   %ebp,%ebp
  jne    L32
  mov    $0xa,%ebp
  cmpb   $0x30,(%rbx)
  je     L145
L32:
  mov    $0x0,%eax
  movslq %ebp,%rcx
  jmp    L53
L84:
  add    $0x1,%rbx
  mov    $0x0,%edi
  jmp    L117
L128:
  add    $0x1,%rbx
  mov    $0x1,%edi
  jmp    L117
L145:
  movzbl 0x1(%rbx),%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  je     L47
  add    $0x1,%rbx
  mov    $0x8,%ebp
  jmp    L32
L47:
  add    $0x2,%rbx
  mov    $0x10,%ebp
  jmp    L32
L136:
  cmp    $0x40,%edx
  jbe    L9
  sub    $0x37,%edx
L120:
  cmp    %edx,%ebp
  jbe    L38
  imul   %rcx,%rax
  mov    %edx,%edx
  add    %rdx,%rax
L53:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edx
  cmp    $0x60,%edx
  jbe    L136
  sub    $0x57,%edx
  jmp    L120
L9:
  lea    -0x30(%rdx),%esi
  cmp    $0x3a,%edx
  cmovb  %esi,%edx
  jmp    L120
L38:
  test   %r12,%r12
  je     L15
  mov    %rbx,(%r12)
L15:
  mov    %rax,%rdx
  neg    %rdx
  test   %edi,%edi
  cmovne %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long strtoul(const char *nptr, char **endptr, int base) {
  unsigned long val = 0;
  int negate = 0;
  unsigned int digit;
  while (isspace(*nptr))
    nptr++;
  if (*nptr == '+') {
    nptr++;
  } else if (*nptr == '-') {
    nptr++;
    negate = 1;
  }
  if (base == 0) {
    base = 10;
    if (*nptr == '0') {
      nptr++;
      base = 8;
      if ((*nptr | 0x20) == 'x') {
        nptr++;
        base = 16;
      }
    }
  }
  while (1) {
    digit = *(nptr++);
    if (digit >= 'a') {
      digit = (digit - 'a' + 10);
    } else if (digit >= 'A') {
      digit = (digit - 'A' + 10);
    } else if (digit <= '9') {
      digit = (digit - '0');
    }
    if (digit >= (unsigned int)base)
      break;
    val = ((val * base) + digit);
  }
  if (endptr)
    *endptr = ((char *)nptr);
  return (negate ? -val : val);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strtoul>:
  endbr64
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax)
L17:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  mov    %rbp,%rcx
  lea    0x1(%rbp),%rbp
  test   %rax,%rax
  jne    L17
  movsbl (%rcx),%edx
  cmp    $0x2b,%dl
  je     L5
  xor    %r8d,%r8d
  cmp    $0x2d,%dl
  je     L31
L133:
  mov    %r12d,%esi
  test   %r12d,%r12d
  jne    L0
  mov    $0xa,%esi
  mov    $0xa,%r12d
  cmp    $0x30,%dl
  je     L28
L0:
  xor    %eax,%eax
  jmp    L78
  nopl   0x0(%rax)
L116:
  sub    $0x57,%edx
L15:
  cmp    %esi,%edx
  jae    L107
L39:
  imul   %r12,%rax
  mov    %edx,%edx
  add    %rdx,%rax
  movsbl (%rcx),%edx
L78:
  add    $0x1,%rcx
  cmp    $0x60,%edx
  ja     L116
  cmp    $0x40,%edx
  jbe    L103
  sub    $0x37,%edx
  cmp    %esi,%edx
  jb     L39
L107:
  test   %rbx,%rbx
  je     L83
  mov    %rcx,(%rbx)
L83:
  mov    %rax,%rdx
  pop    %rbx
  pop    %rbp
  neg    %rdx
  test   %r8d,%r8d
  pop    %r12
  cmovne %rdx,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L103:
  lea    -0x30(%rdx),%edi
  cmp    $0x3a,%edx
  cmovb  %edi,%edx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L31:
  movsbl 0x1(%rcx),%edx
  mov    $0x1,%r8d
  mov    %rbp,%rcx
  jmp    L133
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl 0x1(%rcx),%edx
  xor    %r8d,%r8d
  mov    %rbp,%rcx
  jmp    L133
  nopw   0x0(%rax,%rax,1)
L28:
  movsbl 0x1(%rcx),%edx
  mov    %edx,%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  je     L1
  add    $0x1,%rcx
  mov    $0x8,%esi
  mov    $0x8,%r12d
  jmp    L0
L1:
  movsbl 0x2(%rcx),%edx
  mov    $0x10,%esi
  add    $0x2,%rcx
  mov    $0x10,%r12d
  jmp    L0
```

assistant: ```c
unsigned long strtoul(const char *nptr, char **endptr, int base) {
  unsigned long val = 0;
  int negate = 0;
  unsigned int digit;
  while (isspace(*nptr))
    nptr++;
  if (*nptr == '+') {
    nptr++;
  } else if (*nptr == '-') {
    nptr++;
    negate = 1;
  }
  if (base == 0) {
    base = 10;
    if (*nptr == '0') {
      nptr++;
      base = 8;
      if ((*nptr | 0x20) == 'x') {
        nptr++;
        base = 16;
      }
    }
  }
  while (1) {
    digit = *(nptr++);
    if (digit >= 'a') {
      digit = (digit - 'a' + 10);
    } else if (digit >= 'A') {
      digit = (digit - 'A' + 10);
    } else if (digit <= '9') {
      digit = (digit - '0');
    }
    if (digit >= (unsigned int)base)
      break;
    val = ((val * base) + digit);
  }
  if (endptr)
    *endptr = ((char *)nptr);
  return (negate ? -val : val);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtoul>:
  endbr64
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax)
L114:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  mov    %rbp,%rcx
  lea    0x1(%rbp),%rbp
  test   %rax,%rax
  jne    L114
  movzbl (%rcx),%eax
  cmp    $0x2b,%al
  je     L120
  xor    %r8d,%r8d
  cmp    $0x2d,%al
  je     L149
L163:
  mov    %r12d,%esi
  test   %r12d,%r12d
  jne    L102
  mov    $0xa,%esi
  mov    $0xa,%r12d
  cmp    $0x30,%al
  je     L11
L102:
  xor    %eax,%eax
  jmp    L93
  nopw   0x0(%rax,%rax,1)
L45:
  sub    $0x57,%edx
L121:
  cmp    %esi,%edx
  jae    L129
L144:
  imul   %r12,%rax
  add    %rdx,%rax
L93:
  movsbl (%rcx),%edx
  add    $0x1,%rcx
  cmp    $0x60,%edx
  ja     L45
  cmp    $0x40,%edx
  jbe    L28
  sub    $0x37,%edx
  cmp    %esi,%edx
  jb     L144
L129:
  test   %rbx,%rbx
  je     L118
  mov    %rcx,(%rbx)
L118:
  mov    %rax,%rdx
  pop    %rbx
  pop    %rbp
  neg    %rdx
  test   %r8d,%r8d
  pop    %r12
  cmovne %rdx,%rax
  ret
L28:
  lea    -0x30(%rdx),%edi
  cmp    $0x3a,%edx
  cmovb  %rdi,%rdx
  jmp    L121
  nopl   0x0(%rax)
L149:
  movzbl 0x1(%rcx),%eax
  mov    $0x1,%r8d
  mov    %rbp,%rcx
  jmp    L163
  nop
L120:
  movzbl 0x1(%rcx),%eax
  xor    %r8d,%r8d
  mov    %rbp,%rcx
  jmp    L163
  nop
L11:
  movzbl 0x1(%rcx),%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  je     L70
  add    $0x1,%rcx
  mov    $0x8,%esi
  mov    $0x8,%r12d
  jmp    L102
L70:
  add    $0x2,%rcx
  mov    $0x10,%esi
  mov    $0x10,%r12d
  jmp    L102
```

assistant: ```c
unsigned long strtoul(const char *nptr, char **endptr, int base) {
  unsigned long val = 0;
  int negate = 0;
  unsigned int digit;
  while (isspace(*nptr))
    nptr++;
  if (*nptr == '+') {
    nptr++;
  } else if (*nptr == '-') {
    nptr++;
    negate = 1;
  }
  if (base == 0) {
    base = 10;
    if (*nptr == '0') {
      nptr++;
      base = 8;
      if ((*nptr | 0x20) == 'x') {
        nptr++;
        base = 16;
      }
    }
  }
  while (1) {
    digit = *(nptr++);
    if (digit >= 'a') {
      digit = (digit - 'a' + 10);
    } else if (digit >= 'A') {
      digit = (digit - 'A' + 10);
    } else if (digit <= '9') {
      digit = (digit - '0');
    }
    if (digit >= (unsigned int)base)
      break;
    val = ((val * base) + digit);
  }
  if (endptr)
    *endptr = ((char *)nptr);
  return (negate ? -val : val);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fadd_preg32_dword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0xd8,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <put8@plt>
  nop
  leave
  ret
```

assistant: ```c
void fadd_preg32_dword(int reg32) {
  put8(0xD8);
  put8(reg32);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fadd_preg32_dword>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xd8,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put8@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fadd_preg32_dword(int reg32) {
  put8(0xD8);
  put8(reg32);
}
```