ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x2d,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int sum = 0;
  for (i = 0; i < 10; i++) {
    sum += i;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clock@plt>
  mov    $0x0,%ebx
  lea    D9(%rip),%rbp
L4:
  mov    %ebx,%edi
  call   <fibonacci@plt>
  mov    %rax,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x2d,%ebx
  jne    L4
  mov    $0x0,%eax
  call   <clock@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: %4d %20ld


assistant: ```c
int main(void) {
  int i;
  long l;
  clock_t begin, end;
  double time_spent;
  begin = clock();
  for (i = 0; i < 45; i++) {
    l = fibonacci(i);
    printf("%4d %20ld\n", i, l);
  }
  end = clock();
  time_spent = (double)(end - begin) / CLOCKS_PER_SEC;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <clock@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  call   <fibonacci@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  call   <printf@plt>
  cmp    $0x2d,%ebx
  jne    L4
  xor    %eax,%eax
  call   <clock@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string

tool: D3: %4d %20ld


assistant: ```c
int main(void) {
  int i;
  long l;
  clock_t begin, end;
  double time_spent;
  begin = clock();
  for (i = 0; i < 45; i++) {
    l = fibonacci(i);
    printf("%4d %20ld\n", i, l);
  }
  end = clock();
  time_spent = (double)(end - begin) / CLOCKS_PER_SEC;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <clock@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edi
  call   <fibonacci@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  call   <printf@plt>
  cmp    $0x2d,%ebx
  jne    L0
  xor    %eax,%eax
  call   <clock@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: %4d %20ld


assistant: ```c
int main(void) {
  int i;
  long l;
  clock_t begin, end;
  double time_spent;
  begin = clock();
  for (i = 0; i < 45; i++) {
    l = fibonacci(i);
    printf("%4d %20ld\n", i, l);
  }
  end = clock();
  time_spent = (double)(end - begin) / CLOCKS_PER_SEC;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movw   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L22
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  add    %ax,-0xc(%rbp)
  movzwl -0xc(%rbp),%eax
  cmp    -0xa(%rbp),%ax
  jae    L39
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L39:
  addq   $0x2,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L15
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L46
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  add    %ax,-0xc(%rbp)
  movzwl -0xc(%rbp),%eax
  cmp    -0xa(%rbp),%ax
  jae    L46
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L46:
  movzwl -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short checksum(unsigned char *data, unsigned long size) {
  unsigned long n;
  unsigned short d, cs = 0;
  for (n = 0; n < size; n += 2) {
    d = ((unsigned short)(unsigned char)(data[n + 0]) + (((unsigned short)(unsigned char)(data[n + 1])) << 8));
    cs += d;
    if (cs < d)
      cs++;
  }
  if (size & 1) {
    d = data[n];
    cs += d;
    if (cs < d)
      cs++;
  }
  return cs;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<checksum>:
  endbr64
  test   %rsi,%rsi
  je     L29
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl (%rdi),%edx
  add    %edx,%eax
  mov    $0x0,%ecx
  jmp    L15
L29:
  mov    $0x0,%eax
  ret
L16:
  movzbl 0x1(%rdi,%rcx,1),%edx
  shl    $0x8,%edx
  movzbl (%rdi,%rcx,1),%r8d
  add    %r8d,%edx
  add    %dx,%ax
  adc    $0x0,%ax
L15:
  add    $0x2,%rcx
  cmp    %rcx,%rsi
  ja     L16
  test   $0x1,%sil
  je     L14
  movzbl (%rdi,%rcx,1),%edx
  add    %dx,%ax
  adc    $0x0,%ax
  ret
L14:
  ret
```

assistant: ```c
unsigned short checksum(unsigned char *data, unsigned long size) {
  unsigned long n;
  unsigned short d, cs = 0;
  for (n = 0; n < size; n += 2) {
    d = ((unsigned short)(unsigned char)(data[n + 0]) + (((unsigned short)(unsigned char)(data[n + 1])) << 8));
    cs += d;
    if (cs < d)
      cs++;
  }
  if (size & 1) {
    d = data[n];
    cs += d;
    if (cs < d)
      cs++;
  }
  return cs;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checksum>:
  endbr64
  test   %rsi,%rsi
  je     L29
  movzbl 0x1(%rdi),%eax
  movzbl (%rdi),%edx
  xor    %ecx,%ecx
  shl    $0x8,%eax
  add    %edx,%eax
  jmp    L31
  nopl   0x0(%rax)
L18:
  movzbl 0x1(%rdi,%rcx,1),%edx
  movzbl (%rdi,%rcx,1),%r8d
  shl    $0x8,%edx
  add    %r8d,%edx
  add    %dx,%ax
  adc    $0x0,%ax
L31:
  add    $0x2,%rcx
  cmp    %rcx,%rsi
  ja     L18
  and    $0x1,%esi
  je     L22
  movzbl (%rdi,%rcx,1),%edx
  add    %dx,%ax
  adc    $0x0,%ax
  ret
  nopl   0x0(%rax)
L22:
  ret
  nopl   0x0(%rax)
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned short checksum(unsigned char *data, unsigned long size) {
  unsigned long n;
  unsigned short d, cs = 0;
  for (n = 0; n < size; n += 2) {
    d = ((unsigned short)(unsigned char)(data[n + 0]) + (((unsigned short)(unsigned char)(data[n + 1])) << 8));
    cs += d;
    if (cs < d)
      cs++;
  }
  if (size & 1) {
    d = data[n];
    cs += d;
    if (cs < d)
      cs++;
  }
  return cs;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<checksum>:
  endbr64
  test   %rsi,%rsi
  je     L4
  movzbl 0x1(%rdi),%eax
  movzbl (%rdi),%edx
  mov    $0x2,%ecx
  shl    $0x8,%eax
  add    %edx,%eax
  cmp    $0x2,%rsi
  jbe    L36
L27:
  movzbl 0x1(%rdi,%rcx,1),%edx
  movzbl (%rdi,%rcx,1),%r8d
  shl    $0x8,%edx
  add    %r8d,%edx
  add    %dx,%ax
  adc    $0x0,%ax
  add    $0x2,%rcx
  cmp    %rcx,%rsi
  ja     L27
L36:
  and    $0x1,%esi
  je     L5
  movzbl (%rdi,%rcx,1),%edx
  add    %dx,%ax
  adc    $0x0,%ax
  ret
  nopl   0x0(%rax)
L5:
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned short checksum(unsigned char *data, unsigned long size) {
  unsigned long n;
  unsigned short d, cs = 0;
  for (n = 0; n < size; n += 2) {
    d = ((unsigned short)(unsigned char)(data[n + 0]) + (((unsigned short)(unsigned char)(data[n + 1])) << 8));
    cs += d;
    if (cs < d)
      cs++;
  }
  if (size & 1) {
    d = data[n];
    cs += d;
    if (cs < d)
      cs++;
  }
  return cs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L49
L6:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jae    L12
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L43
L12:
  mov    -0x10(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L43:
  addq   $0x2,-0x18(%rbp)
L49:
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L6
  mov    -0x10(%rbp),%rax
  lea    0x4d76914(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 29120926UL) + 110346930UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  mov    0x8(%rdi),%r8
  test   %r8,%r8
  je     L16
  mov    $0x0,%edx
L2:
  lea    (%rax,%rax,1),%rcx
  lea    0x0(,%rax,4),%rdi
  cmp    %rax,%rdx
  mov    %rcx,%rax
  cmovae %rdi,%rax
  add    $0x2,%rdx
  cmp    %r8,%rdx
  jb     L2
L16:
  add    $0x4d76914,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 29120926UL) + 110346930UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%r8
  sub    $0x99f4bb,%rax
  test   %r8,%r8
  je     L7
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L11:
  lea    (%rax,%rax,1),%rcx
  cmp    %rdx,%rax
  lea    0x0(,%rax,4),%rdi
  mov    %rcx,%rax
  cmovbe %rdi,%rax
  add    $0x2,%rdx
  cmp    %r8,%rdx
  jb     L11
L7:
  add    $0x4d76914,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 29120926UL) + 110346930UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%r8
  sub    $0x99f4bb,%rax
  test   %r8,%r8
  je     L14
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L16:
  lea    (%rax,%rax,1),%rcx
  cmp    %rdx,%rax
  lea    0x0(,%rax,4),%rdi
  mov    %rcx,%rax
  cmovbe %rdi,%rax
  add    $0x2,%rdx
  cmp    %r8,%rdx
  jb     L16
L14:
  add    $0x4d76914,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 29120926UL) + 110346930UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L5
  mov    $0x1,%eax
  jmp    L13
L5:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <sum>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
L13:
  leave
  ret
```

assistant: ```c
int sum(int n) {
  if (1 == n) {
    return 1;
  } else {
    return n + sum(n - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sum>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jne    L7
L13:
  mov    %ebx,%eax
  pop    %rbx
  ret
L7:
  lea    -0x1(%rdi),%edi
  call   <sum>
  add    %eax,%ebx
  jmp    L13
```

assistant: ```c
int sum(int n) {
  if (1 == n) {
    return 1;
  } else {
    return n + sum(n - 1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L15
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %edi,%edx
  sub    $0x1,%edi
  add    %edx,%eax
  cmp    $0x1,%edi
  jne    L9
  add    $0x1,%eax
  ret
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int sum(int n) {
  if (1 == n) {
    return 1;
  } else {
    return n + sum(n - 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum>:
  endbr64
  cmp    $0x1,%edi
  je     L68
  lea    -0x2(%rdi),%eax
  lea    -0x1(%rdi),%ecx
  cmp    $0x9,%eax
  jbe    L67
  movd   %edi,%xmm4
  mov    %ecx,%edx
  movdqa D4(%rip),%xmm3
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm1
  paddd  D5(%rip),%xmm1
  shr    $0x2,%edx
  pxor   %xmm0,%xmm0
L43:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L43
  movdqa %xmm0,%xmm1
  mov    %ecx,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  sub    %edx,%edi
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%ecx
  je     L89
  lea    -0x1(%rdi),%ecx
L33:
  add    %edi,%eax
  cmp    $0x1,%ecx
  je     L89
  lea    -0x2(%rdi),%edx
  add    %ecx,%eax
  cmp    $0x3,%edi
  je     L89
  lea    -0x3(%rdi),%ecx
  add    %edx,%eax
  cmp    $0x4,%edi
  je     L89
  lea    -0x4(%rdi),%edx
  add    %ecx,%eax
  cmp    $0x5,%edi
  je     L89
  lea    -0x5(%rdi),%ecx
  add    %edx,%eax
  cmp    $0x6,%edi
  je     L89
  lea    -0x6(%rdi),%edx
  add    %ecx,%eax
  cmp    $0x7,%edi
  je     L89
  lea    -0x7(%rdi),%ecx
  add    %edx,%eax
  cmp    $0x8,%edi
  je     L89
  lea    -0x8(%rdi),%edx
  add    %ecx,%eax
  cmp    $0x9,%edi
  je     L89
  add    %edx,%eax
  sub    $0x9,%edi
  lea    (%rax,%rdi,1),%edx
  cmp    $0x1,%edi
  cmovne %edx,%eax
L89:
  add    $0x1,%eax
  ret
  xchg   %ax,%ax
L68:
  mov    $0x1,%eax
  ret
L67:
  xor    %eax,%eax
  jmp    L33
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D5
type_guessed: byte[16]

tool: {"D4": [0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff]}

tool: {"D5": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfd,0xff,0xff,0xff]}

assistant: ```c
int sum(int n) {
  if (1 == n) {
    return 1;
  } else {
    return n + sum(n - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<num_columns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x1,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L21
L6:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L9
  addq   $0x1,-0x10(%rbp)
L9:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L6
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long num_columns(char *buffer, long buflen) {
  long n = 1;
  long ii;
  for (ii = 0; ii < buflen; ii++)
    if (buffer[ii] == '\t')
      n++;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_columns>:
  endbr64
  test   %rsi,%rsi
  jle    L19
  mov    %rdi,%rax
  add    %rsi,%rdi
  mov    $0x1,%edx
L18:
  cmpb   $0x9,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %rcx,%rdx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L18
L15:
  mov    %rdx,%rax
  ret
L19:
  mov    $0x1,%edx
  jmp    L15
```

assistant: ```c
long num_columns(char *buffer, long buflen) {
  long n = 1;
  long ii;
  for (ii = 0; ii < buflen; ii++)
    if (buffer[ii] == '\t')
      n++;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<num_columns>:
  endbr64
  test   %rsi,%rsi
  jle    L1
  add    %rdi,%rsi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L9:
  xor    %edx,%edx
  cmpb   $0x9,(%rdi)
  sete   %dl
  add    $0x1,%rdi
  add    %rdx,%rax
  cmp    %rsi,%rdi
  jne    L9
  ret
  nopl   (%rax)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long num_columns(char *buffer, long buflen) {
  long n = 1;
  long ii;
  for (ii = 0; ii < buflen; ii++)
    if (buffer[ii] == '\t')
      n++;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stdlib_strided_scusumkbn2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movss  %xmm0,0xc(%rsp)
  test   %rdi,%rdi
  jle    L62
  mov    %rdi,%r15
  mov    %rcx,%rax
  mov    $0x0,%edi
  test   %rdx,%rdx
  js     L58
L19:
  mov    $0x0,%ecx
  test   %r8,%r8
  js     L59
L44:
  shl    $0x2,%rdx
  mov    %rdx,0x20(%rsp)
  lea    (%rsi,%rdi,4),%r14
  lea    0x0(,%r8,4),%rsi
  mov    %rsi,0x28(%rsp)
  lea    (%rax,%rcx,4),%r13
  pxor   %xmm7,%xmm7
  movss  %xmm7,0x10(%rsp)
  movss  %xmm7,0x1c(%rsp)
  mov    $0x0,%r12d
  jmp    L6
L58:
  mov    $0x1,%edi
  sub    %r15,%rdi
  imul   %rdx,%rdi
  jmp    L19
L59:
  mov    $0x1,%ecx
  sub    %r15,%rcx
  imul   %r8,%rcx
  jmp    L44
L55:
  movd   %ebx,%xmm0
  subss  0xc(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  movss  %xmm0,0x14(%rsp)
  jmp    L45
L75:
  movss  0x14(%rsp),%xmm0
  subss  0x18(%rsp),%xmm0
  addss  0x10(%rsp),%xmm0
L76:
  addss  0x1c(%rsp),%xmm0
  movaps %xmm0,%xmm6
  movss  %xmm0,0x1c(%rsp)
  movss  0xc(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  %xmm6,%xmm0
  movss  %xmm0,0x0(%r13)
  add    $0x1,%r12
  add    0x20(%rsp),%r14
  add    0x28(%rsp),%r13
  cmp    %r12,%r15
  je     L62
  movss  0x18(%rsp),%xmm3
  movss  %xmm3,0x10(%rsp)
L6:
  mov    (%r14),%ebx
  movss  0xc(%rsp),%xmm2
  movd   %ebx,%xmm7
  addss  %xmm2,%xmm7
  movss  %xmm7,0xc(%rsp)
  movss  %xmm2,0x14(%rsp)
  movaps %xmm2,%xmm0
  call   <fabsf@plt>
  mov    %rax,%rbp
  movd   %ebx,%xmm0
  call   <fabsf@plt>
  cmp    %rax,%rbp
  jl     L55
  movss  0x14(%rsp),%xmm0
  subss  0xc(%rsp),%xmm0
  movd   %ebx,%xmm7
  addss  %xmm0,%xmm7
  movss  %xmm7,0x14(%rsp)
L45:
  movss  0x14(%rsp),%xmm3
  movss  0x10(%rsp),%xmm5
  addss  %xmm5,%xmm3
  movss  %xmm3,0x18(%rsp)
  movaps %xmm5,%xmm0
  call   <fabsf@plt>
  mov    %rax,%rbx
  movss  0x14(%rsp),%xmm0
  call   <fabsf@plt>
  cmp    %rax,%rbx
  jl     L75
  movss  0x10(%rsp),%xmm5
  subss  0x18(%rsp),%xmm5
  movaps %xmm5,%xmm0
  addss  0x14(%rsp),%xmm0
  jmp    L76
L62:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void stdlib_strided_scusumkbn2(const int64_t N, const float sum, const float *X, const int64_t strideX, float *Y, const int64_t strideY) {
  int64_t ix;
  int64_t iy;
  int64_t i;
  float ccs;
  float cs;
  float cc;
  float v;
  float t;
  float c;
  float s;
  if (N <= 0) {
    return;
  }
  if (strideX < 0) {
    ix = (1 - N) * strideX;
  } else {
    ix = 0;
  }
  if (strideY < 0) {
    iy = (1 - N) * strideY;
  } else {
    iy = 0;
  }
  s = sum;
  ccs = 0.0f;
  cs = 0.0f;
  for (i = 0; i < N; i++) {
    v = X[ix];
    t = s + v;
    if (fabsf(s) >= fabsf(v)) {
      c = (s - t) + v;
    } else {
      c = (v - t) + s;
    }
    s = t;
    t = cs + c;
    if (fabsf(cs) >= fabsf(c)) {
      cc = (cs - t) + c;
    } else {
      cc = (c - t) + cs;
    }
    cs = t;
    ccs += cc;
    Y[iy] = s + cs + ccs;
    ix += strideX;
    iy += strideY;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sqlite3Malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <sqlite3MallocRaw@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *sqlite3Malloc(int n, int doMemManage) {
  void *p = sqlite3MallocRaw(n, doMemManage);
  if (p) {
    memset(p, 0, n);
  }
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqlite3Malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <sqlite3MallocRaw@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L6:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *sqlite3Malloc(int n, int doMemManage) {
  void *p = sqlite3MallocRaw(n, doMemManage);
  if (p) {
    memset(p, 0, n);
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sqlite3Malloc>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x8,%rsp
  call   <sqlite3MallocRaw@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sqlite3Malloc(int n, int doMemManage) {
  void *p = sqlite3MallocRaw(n, doMemManage);
  if (p) {
    memset(p, 0, n);
  }
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sqlite3Malloc>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x8,%rsp
  call   <sqlite3MallocRaw@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sqlite3Malloc(int n, int doMemManage) {
  void *p = sqlite3MallocRaw(n, doMemManage);
  if (p) {
    memset(p, 0, n);
  }
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<usart_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4e0,%rsp
  mov    %edi,-0x4d4(%rbp)
  mov    %rsi,-0x4e0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x4e0(%rbp),%rdx
  mov    -0x4c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x4c4(%rbp),%ecx
  mov    -0x4e0(%rbp),%rdx
  lea    -0x4c0(%rbp),%rax
  mov    $0x3ff,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x4c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x4c0(%rbp),%rdx
  mov    -0x4d4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <usart_puts@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void usart_printf(int fd, char *message, ...) {
  va_list argp;
  char buffer[1024];
  va_start(argp, message);
  vsnprintf(buffer, 1023, message, argp);
  va_end(argp);
  usart_puts(fd, buffer);
}
```