ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<numl>:
  endbr64
  xor    %r8d,%r8d
  jmp    L18
  nopl   0x0(%rax)
L16:
  cmp    $0xa,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
L18:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L16
  mov    %r8d,%eax
  ret
```

assistant: ```c
int numl(const char *s) {
  int i = 0;
  for (;;) {
    switch (*s++) {
    case '\0':
      break;
    case '\n':
      i++;
    default:
      continue;
    }
    break;
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<numl>:
  endbr64
  xor    %r8d,%r8d
  jmp    L7
  nopl   0x0(%rax)
L13:
  cmp    $0xa,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
L7:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L13
  mov    %r8d,%eax
  ret
```

assistant: ```c
int numl(const char *s) {
  int i = 0;
  for (;;) {
    switch (*s++) {
    case '\0':
      break;
    case '\n':
      i++;
    default:
      continue;
    }
    break;
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xfffffffe,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  jae    L28
  movl   $0xa,-0xc(%rbp)
L28:
  cmpl   $0x0,-0xc(%rbp)
  js     L24
  andl   $0xffffff00,-0x4(%rbp)
  jmp    L20
L24:
  nop
L20:
  pop    %rbp
  ret
```

assistant: ```c
void main(void) {
  unsigned min;
  int value, latency;
  latency = -2;
  if (latency > (((min) >> 8) & 0xff)) {
    value = 0xa;
  }
  if (value < 0)
    return;
  ((min) = (((min) & ~0xff)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main(void) {
  unsigned min;
  int value, latency;
  latency = -2;
  if (latency > (((min) >> 8) & 0xff)) {
    value = 0xa;
  }
  if (value < 0)
    return;
  ((min) = (((min) & ~0xff)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main(void) {
  unsigned min;
  int value, latency;
  latency = -2;
  if (latency > (((min) >> 8) & 0xff)) {
    value = 0xa;
  }
  if (value < 0)
    return;
  ((min) = (((min) & ~0xff)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main(void) {
  unsigned min;
  int value, latency;
  latency = -2;
  if (latency > (((min) >> 8) & 0xff)) {
    value = 0xa;
  }
  if (value < 0)
    return;
  ((min) = (((min) & ~0xff)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<show_shell_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D5(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D5: q: quit
help: show this help

Brainfuck cheatsheet:
	< >: move the pointer
	+ -: increment/decrement the value at pointer position
	. ,: write/read text to/from stdout/stdin
	[ ]: start/end loop

tool: D3: %s


assistant: ```c
void show_shell_help() {
  const char *help = "q: quit\n"
                     "help: show this help\n\n"
                     "Brainfuck cheatsheet:\n"
                     "\t< >: move the pointer\n"
                     "\t+ -: increment/decrement the value at pointer position\n"
                     "\t. ,: write/read text to/from stdout/stdin\n"
                     "\t[ ]: start/end loop";
  printf("%s\n", help);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<show_shell_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string

tool: D5: q: quit
help: show this help

Brainfuck cheatsheet:
	< >: move the pointer
	+ -: increment/decrement the value at pointer position
	. ,: write/read text to/from stdout/stdin
	[ ]: start/end loop

tool: D14: %s


assistant: ```c
void show_shell_help() {
  const char *help = "q: quit\n"
                     "help: show this help\n\n"
                     "Brainfuck cheatsheet:\n"
                     "\t< >: move the pointer\n"
                     "\t+ -: increment/decrement the value at pointer position\n"
                     "\t. ,: write/read text to/from stdout/stdin\n"
                     "\t[ ]: start/end loop";
  printf("%s\n", help);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<show_shell_help>:
  endbr64
  lea    D3(%rip),%rsi
  lea    D13(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D3: q: quit
help: show this help

Brainfuck cheatsheet:
	< >: move the pointer
	+ -: increment/decrement the value at pointer position
	. ,: write/read text to/from stdout/stdin
	[ ]: start/end loop

tool: D13: %s


assistant: ```c
void show_shell_help() {
  const char *help = "q: quit\n"
                     "help: show this help\n\n"
                     "Brainfuck cheatsheet:\n"
                     "\t< >: move the pointer\n"
                     "\t+ -: increment/decrement the value at pointer position\n"
                     "\t. ,: write/read text to/from stdout/stdin\n"
                     "\t[ ]: start/end loop";
  printf("%s\n", help);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_shell_help>:
  endbr64
  lea    D7(%rip),%rsi
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string

tool: D7: q: quit
help: show this help

Brainfuck cheatsheet:
	< >: move the pointer
	+ -: increment/decrement the value at pointer position
	. ,: write/read text to/from stdout/stdin
	[ ]: start/end loop

tool: D5: %s


assistant: ```c
void show_shell_help() {
  const char *help = "q: quit\n"
                     "help: show this help\n\n"
                     "Brainfuck cheatsheet:\n"
                     "\t< >: move the pointer\n"
                     "\t+ -: increment/decrement the value at pointer position\n"
                     "\t. ,: write/read text to/from stdout/stdin\n"
                     "\t[ ]: start/end loop";
  printf("%s\n", help);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L40
L6:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L45
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L36
L45:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L40:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L6
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D5
type_infered: string

tool: D0: %d %d

tool: D15: %d

tool: D8: no


tool: D5: yes


assistant: ```c
int main() {
  int lenth, sequence, min;
  scanf("%d %d", &lenth, &min);
  for (int i = 1; i < lenth; i++) {
    scanf("%d", &sequence);
    if (sequence < min) {
      printf("no\n");
      return 0;
    } else {
      min = sequence;
    }
  }
  printf("yes\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L1
  mov    $0x1,%ebx
  lea    D9(%rip),%rbp
L44:
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    0x14(%rsp),%eax
  jl     L26
  mov    %eax,0x14(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L44
L1:
  lea    D21(%rip),%rdi
  call   <printf@plt>
L41:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D21
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D4: %d %d

tool: D9: %d

tool: D21: yes


tool: D19: no


assistant: ```c
int main() {
  int lenth, sequence, min;
  scanf("%d %d", &lenth, &min);
  for (int i = 1; i < lenth; i++) {
    scanf("%d", &sequence);
    if (sequence < min) {
      printf("no\n");
      return 0;
    } else {
      min = sequence;
    }
  }
  printf("yes\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D39(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L1
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r12
  lea    D19(%rip),%rbp
  jmp    L35
  nopl   0x0(%rax)
L11:
  mov    %eax,0x14(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L1
L35:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    0x14(%rsp),%eax
  jge    L11
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L58
L1:
  lea    D13(%rip),%rdi
  call   <printf@plt>
L58:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D7
data_type: string
name: retrieve_data
arguments: data_tag: D13
data_type: string

tool: D39: %d %d

tool: D19: %d

tool: D7: no


tool: D13: yes


assistant: ```c
int main() {
  int lenth, sequence, min;
  scanf("%d %d", &lenth, &min);
  for (int i = 1; i < lenth; i++) {
    scanf("%d", &sequence);
    if (sequence < min) {
      printf("no\n");
      return 0;
    } else {
      min = sequence;
    }
  }
  printf("yes\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L3
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r12
  lea    D11(%rip),%rbp
  jmp    L45
  nopl   0x0(%rax)
L9:
  mov    %eax,0x14(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L3
L45:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    0x14(%rsp),%eax
  jge    L9
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L3:
  lea    D17(%rip),%rdi
  call   <printf@plt>
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D36
type_guessed: string
name: disassemble_data
arguments: data_label: D17
type_guessed: string

tool: D19: %d %d

tool: D11: %d

tool: D36: no


tool: D17: yes


assistant: ```c
int main() {
  int lenth, sequence, min;
  scanf("%d %d", &lenth, &min);
  for (int i = 1; i < lenth; i++) {
    scanf("%d", &sequence);
    if (sequence < min) {
      printf("no\n");
      return 0;
    } else {
      min = sequence;
    }
  }
  printf("yes\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rbp
  movabs $0x6666666666666667,%rbx
  lea    D34(%rip),%r12
  jmp    L16
L21:
  mov    %rsi,%rax
  imul   %rbx
  sar    $0x2,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rsi,%rdi
  sub    %rax,%rdi
  mov    %rcx,%rax
  imul   %rbx
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  lea    (%rdi,%rdx,1),%rax
  movslq %r8d,%r8
  add    %r8,%rax
  cmp    $0x9,%rax
  setg   %r8b
  movzbl %r8b,%r8d
  add    %r8d,%r9d
  mov    %rsi,%rax
  imul   %rbx
  sar    $0x2,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rsi
  sub    %rax,%rsi
  mov    %rcx,%rax
  imul   %rbx
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rcx
  sub    %rax,%rcx
  mov    %r10d,%eax
  mov    %r10d,%edx
L2:
  mov    %rcx,%rdi
  or     %rsi,%rdi
  jne    L21
  test   %al,%al
  je     L104
  movq   $0x0,0x8(%rsp)
L104:
  test   %dl,%dl
  je     L97
  movq   $0x0,0x10(%rsp)
L97:
  cmp    $0x1,%r9d
  je     L28
  test   %r9d,%r9d
  je     L35
  mov    %r9d,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L16:
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L105
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rcx
  mov    %rsi,%rax
  or     %rcx,%rax
  je     L105
  mov    $0x0,%eax
  mov    $0x0,%edx
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x1,%r10d
  jmp    L2
L28:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L16
L35:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L16
L105:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D34
type: string
name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D38
type: string

tool: D29: %ld %ld

tool: D34: No carry operation.

tool: D8: %d carry operations.


tool: D38: 1 carry operation.

assistant: ```c
int main() {
  long a, b;
  int carry, c;
  while (scanf("%ld %ld", &a, &b) && (a != 0 || b != 0)) {
    carry = 0;
    c = 0;
    while (a != 0 || b != 0) {
      carry = (a % 10 + b % 10 + carry) > 9 ? 1 : 0;
      if (carry)
        c++;
      a /= 10;
      b /= 10;
    }
    if (c == 1)
      printf("1 carry operation.\n");
    else if (c)
      printf("%d carry operations.\n", c);
    else
      printf("No carry operation.\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  movabs $0x6666666666666667,%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L15
  mov    0x8(%rsp),%rcx
  mov    0x10(%rsp),%rdi
  mov    %rcx,%rax
  or     %rdi,%rax
  je     L15
  xor    %eax,%eax
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  jmp    L41
  nop
L39:
  mov    %rcx,%rax
  imul   %r14
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    (%rsi,%rsi,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rdi,%rax
  imul   %r14
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rdi
  lea    (%rcx,%rdi,1),%rax
  mov    %rsi,%rcx
  mov    %rdx,%rdi
  add    %r9,%rax
  xor    %r9d,%r9d
  cmp    $0x9,%rax
  mov    $0x1,%eax
  setg   %r9b
  add    %r9d,%r8d
L41:
  mov    %rcx,%rsi
  or     %rdi,%rsi
  jne    L39
  test   %al,%al
  je     L51
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
L51:
  cmp    $0x1,%r8d
  je     L93
  test   %r8d,%r8d
  je     L12
  mov    %r8d,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L38
  xchg   %ax,%ax
L12:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L38
  nopl   (%rax)
L93:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L38
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D19
type_infered: string
name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D26
type_infered: string

tool: D19: No carry operation.

tool: D1: %ld %ld

tool: D10: %d carry operations.


tool: D26: 1 carry operation.

assistant: ```c
int main() {
  long a, b;
  int carry, c;
  while (scanf("%ld %ld", &a, &b) && (a != 0 || b != 0)) {
    carry = 0;
    c = 0;
    while (a != 0 || b != 0) {
      carry = (a % 10 + b % 10 + carry) > 9 ? 1 : 0;
      if (carry)
        c++;
      a /= 10;
      b /= 10;
    }
    if (c == 1)
      printf("1 carry operation.\n");
    else if (c)
      printf("%d carry operations.\n", c);
    else
      printf("No carry operation.\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  movabs $0x6666666666666667,%r15
  push   %r14
  lea    D30(%rip),%r14
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L80
  mov    0x8(%rsp),%r10
  mov    0x10(%rsp),%rcx
  mov    %r10,%rax
  or     %rcx,%rax
  je     L80
  xor    %r9d,%r9d
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L75:
  mov    %rcx,%rax
  imul   %r15
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    (%rsi,%rsi,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %r10,%rax
  imul   %r15
  mov    %r10,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r10
  lea    (%rcx,%r10,1),%rax
  mov    %rdx,%r10
  mov    %rsi,%rcx
  add    %rdi,%rax
  xor    %edi,%edi
  cmp    $0x9,%rax
  mov    %rdx,%rax
  setg   %dil
  add    %edi,%r9d
  or     %rsi,%rax
  jne    L75
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  cmp    $0x1,%r9d
  je     L50
  test   %r9d,%r9d
  je     L44
  mov    %r9d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L44:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L4
  nopl   (%rax)
L50:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  jmp    L4
L80:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D30
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string

tool: D30: No carry operation.

tool: D7: %d carry operations.


tool: D5: %ld %ld

tool: D27: 1 carry operation.

assistant: ```c
int main() {
  long a, b;
  int carry, c;
  while (scanf("%ld %ld", &a, &b) && (a != 0 || b != 0)) {
    carry = 0;
    c = 0;
    while (a != 0 || b != 0) {
      carry = (a % 10 + b % 10 + carry) > 9 ? 1 : 0;
      if (carry)
        c++;
      a /= 10;
      b /= 10;
    }
    if (c == 1)
      printf("1 carry operation.\n");
    else if (c)
      printf("%d carry operations.\n", c);
    else
      printf("No carry operation.\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<UARTModemControlSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x10,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x10,%edx
  mov    %edx,%edx
  and    $0xffffffdd,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0x10,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  and    $0x22,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  add    $0x10,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  or     %esi,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTModemControlSet(unsigned int baseAdd, unsigned int ctrlFlags) {
  (*((volatile unsigned int *)(baseAdd + (0x10)))) &= ~((0x00000020u) | (0x00000002u));
  (*((volatile unsigned int *)(baseAdd + (0x10)))) |= (ctrlFlags & ((0x00000020u) | (0x00000002u)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTModemControlSet>:
  endbr64
  mov    0x10(%edi),%eax
  and    $0xffffffdd,%eax
  mov    %eax,0x10(%edi)
  mov    0x10(%edi),%eax
  and    $0x22,%esi
  or     %eax,%esi
  mov    %esi,0x10(%edi)
  ret
```

assistant: ```c
void UARTModemControlSet(unsigned int baseAdd, unsigned int ctrlFlags) {
  (*((volatile unsigned int *)(baseAdd + (0x10)))) &= ~((0x00000020u) | (0x00000002u));
  (*((volatile unsigned int *)(baseAdd + (0x10)))) |= (ctrlFlags & ((0x00000020u) | (0x00000002u)));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UARTModemControlSet>:
  endbr64
  mov    0x10(%edi),%eax
  and    $0x22,%esi
  and    $0xffffffdd,%eax
  mov    %eax,0x10(%edi)
  mov    0x10(%edi),%eax
  or     %eax,%esi
  mov    %esi,0x10(%edi)
  ret
```

assistant: ```c
void UARTModemControlSet(unsigned int baseAdd, unsigned int ctrlFlags) {
  (*((volatile unsigned int *)(baseAdd + (0x10)))) &= ~((0x00000020u) | (0x00000002u));
  (*((volatile unsigned int *)(baseAdd + (0x10)))) |= (ctrlFlags & ((0x00000020u) | (0x00000002u)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UARTModemControlSet>:
  endbr64
  mov    0x10(%edi),%eax
  and    $0x22,%esi
  and    $0xffffffdd,%eax
  mov    %eax,0x10(%edi)
  mov    0x10(%edi),%eax
  or     %eax,%esi
  mov    %esi,0x10(%edi)
  ret
```

assistant: ```c
void UARTModemControlSet(unsigned int baseAdd, unsigned int ctrlFlags) {
  (*((volatile unsigned int *)(baseAdd + (0x10)))) &= ~((0x00000020u) | (0x00000002u));
  (*((volatile unsigned int *)(baseAdd + (0x10)))) |= (ctrlFlags & ((0x00000020u) | (0x00000002u)));
}
```