ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sorthelp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L24
  mov    $0x1,%eax
  jmp    L36
L24:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L6
  mov    $0xffffffff,%eax
  jmp    L36
L6:
  mov    $0x0,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int sorthelp(const void *a, const void *b) {
  const int *oa, *ob;
  oa = a;
  ob = b;
  if (*oa > *ob)
    return 1;
  if (*oa < *ob)
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sorthelp>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  jg     L4
  setl   %al
  movzbl %al,%eax
  neg    %eax
L4:
  ret
```

assistant: ```c
int sorthelp(const void *a, const void *b) {
  const int *oa, *ob;
  oa = a;
  ob = b;
  if (*oa > *ob)
    return 1;
  if (*oa < *ob)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sorthelp>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L7
  setl   %al
  movzbl %al,%eax
  neg    %eax
L7:
  ret
```

assistant: ```c
int sorthelp(const void *a, const void *b) {
  const int *oa, *ob;
  oa = a;
  ob = b;
  if (*oa > *ob)
    return 1;
  if (*oa < *ob)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sorthelp>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L1
  setl   %al
  movzbl %al,%eax
  neg    %eax
L1:
  ret
```

assistant: ```c
int sorthelp(const void *a, const void *b) {
  const int *oa, *ob;
  oa = a;
  ob = b;
  if (*oa > *ob)
    return 1;
  if (*oa < *ob)
    return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<alloc_kmem_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <alloc_dcache@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *alloc_kmem_fn(void *arg) {
  alloc_dcache(NULL, (void *)100);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<alloc_kmem_fn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <alloc_dcache@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *alloc_kmem_fn(void *arg) {
  alloc_dcache(NULL, (void *)100);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<alloc_kmem_fn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <alloc_dcache@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *alloc_kmem_fn(void *arg) {
  alloc_dcache(NULL, (void *)100);
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<alloc_kmem_fn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  xor    %edi,%edi
  call   <alloc_dcache@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *alloc_kmem_fn(void *arg) {
  alloc_dcache(NULL, (void *)100);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aes_decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <EVP_DecryptInit_ex@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edi
  mov    -0x30(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <EVP_DecryptUpdate@plt>
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EVP_DecryptFinal_ex@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
uint8_t *aes_decrypt(EVP_CIPHER_CTX *e, uint8_t *ciphertext, intmax_t *len) {
  intmax_t f_len = 0;
  intmax_t p_len = *len;
  uint8_t *plaintext = malloc(*len);
  EVP_DecryptInit_ex(e, NULL, NULL, NULL, NULL);
  EVP_DecryptUpdate(e, plaintext, (int *)&p_len, ciphertext, *len);
  EVP_DecryptFinal_ex(e, plaintext + p_len, (int *)&f_len);
  *len = p_len + f_len;
  return plaintext;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aes_decrypt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  mov    (%rdx),%edi
  mov    %edi,0x4(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <EVP_DecryptInit_ex@plt>
  lea    0x4(%rsp),%rdx
  mov    (%rbx),%r8d
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_DecryptUpdate@plt>
  mov    %rsp,%rdx
  movslq 0x4(%rsp),%rax
  lea    (%r12,%rax,4),%rsi
  mov    %rbp,%rdi
  call   <EVP_DecryptFinal_ex@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t *aes_decrypt(EVP_CIPHER_CTX *e, uint8_t *ciphertext, intmax_t *len) {
  intmax_t f_len = 0;
  intmax_t p_len = *len;
  uint8_t *plaintext = malloc(*len);
  EVP_DecryptInit_ex(e, NULL, NULL, NULL, NULL);
  EVP_DecryptUpdate(e, plaintext, (int *)&p_len, ciphertext, *len);
  EVP_DecryptFinal_ex(e, plaintext + p_len, (int *)&f_len);
  *len = p_len + f_len;
  return plaintext;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aes_decrypt>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    (%rdx),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  mov    %edi,0x4(%rsp)
  call   <malloc@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_DecryptInit_ex@plt>
  mov    (%rbx),%r8d
  lea    0x4(%rsp),%rdx
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_DecryptUpdate@plt>
  movslq 0x4(%rsp),%rax
  mov    %rsp,%rdx
  mov    %rbp,%rdi
  lea    (%r12,%rax,4),%rsi
  call   <EVP_DecryptFinal_ex@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t *aes_decrypt(EVP_CIPHER_CTX *e, uint8_t *ciphertext, intmax_t *len) {
  intmax_t f_len = 0;
  intmax_t p_len = *len;
  uint8_t *plaintext = malloc(*len);
  EVP_DecryptInit_ex(e, NULL, NULL, NULL, NULL);
  EVP_DecryptUpdate(e, plaintext, (int *)&p_len, ciphertext, *len);
  EVP_DecryptFinal_ex(e, plaintext + p_len, (int *)&f_len);
  *len = p_len + f_len;
  return plaintext;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aes_decrypt>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    (%rdx),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  mov    %edi,0x4(%rsp)
  call   <malloc@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_DecryptInit_ex@plt>
  mov    (%rbx),%r8d
  lea    0x4(%rsp),%rdx
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_DecryptUpdate@plt>
  movslq 0x4(%rsp),%rax
  mov    %rsp,%rdx
  mov    %rbp,%rdi
  lea    (%r12,%rax,4),%rsi
  call   <EVP_DecryptFinal_ex@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t *aes_decrypt(EVP_CIPHER_CTX *e, uint8_t *ciphertext, intmax_t *len) {
  intmax_t f_len = 0;
  intmax_t p_len = *len;
  uint8_t *plaintext = malloc(*len);
  EVP_DecryptInit_ex(e, NULL, NULL, NULL, NULL);
  EVP_DecryptUpdate(e, plaintext, (int *)&p_len, ciphertext, *len);
  EVP_DecryptFinal_ex(e, plaintext + p_len, (int *)&f_len);
  *len = p_len + f_len;
  return plaintext;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string

tool: D9: hello xmake!


assistant: ```c
int main(int argc, char **argv) {
  printf("hello xmake!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: hello xmake!


assistant: ```c
int main(int argc, char **argv) {
  printf("hello xmake!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: hello xmake!


assistant: ```c
int main(int argc, char **argv) {
  printf("hello xmake!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: hello xmake!


assistant: ```c
int main(int argc, char **argv) {
  printf("hello xmake!\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<append_post>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L26:
  addq   $0x8,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L22
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
L22:
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void append_post(char **args, const char *name, const char *val) {
  char **last = args;
  while (*last && strcmp(*last, name))
    ++last;
  *last = (char *)name;
  *(last + 1) = (char *)val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<append_post>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
L0:
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L0
L9:
  mov    %rbp,(%rbx)
  mov    %r12,0x8(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void append_post(char **args, const char *name, const char *val) {
  char **last = args;
  while (*last && strcmp(*last, name))
    ++last;
  *last = (char *)name;
  *(last + 1) = (char *)val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<append_post>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  jne    L31
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L8:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L7
L31:
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
L7:
  mov    %rbp,(%rbx)
  mov    %r12,0x8(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void append_post(char **args, const char *name, const char *val) {
  char **last = args;
  while (*last && strcmp(*last, name))
    ++last;
  *last = (char *)name;
  *(last + 1) = (char *)val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<append_post>:
  endbr64
  push   %rbp
  movq   %rsi,%xmm0
  movq   %rdx,%xmm1
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  punpcklqdq %xmm1,%xmm0
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  movaps %xmm0,(%rsp)
  test   %rdi,%rdi
  jne    L3
  jmp    L10
  nopl   0x0(%rax)
L30:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L10
L3:
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L30
L10:
  movdqa (%rsp),%xmm2
  movups %xmm2,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void append_post(char **args, const char *name, const char *val) {
  char **last = args;
  while (*last && strcmp(*last, name))
    ++last;
  *last = (char *)name;
  *(last + 1) = (char *)val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %rsi,%rdx
  jmp    L11
L38:
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  movzbl (%rcx),%ecx
  test   %cl,%cl
  jne    L11
  mov    $0x0,%eax
  jmp    L26
L11:
  movzbl (%rax),%esi
  mov    %rdx,%rcx
  lea    0x1(%rcx),%rdx
  movzbl (%rcx),%ecx
  cmp    %cl,%sil
  je     L38
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0x1,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  sub    %edx,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(s1, s2)
register const char *s1, *s2;
{
  while (*s1 == *s2++)
    if (*s1++ == 0)
      return (0);
  return (*(const unsigned char *)s1 - *(const unsigned char *)(s2 - 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  mov    $0x0,%eax
L14:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L18
  add    $0x1,%rax
  test   %dl,%dl
  jne    L14
  mov    $0x0,%eax
  ret
L18:
  movzbl %dl,%eax
  movzbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(s1, s2)
register const char *s1, *s2;
{
  while (*s1 == *s2++)
    if (*s1++ == 0)
      return (0);
  return (*(const unsigned char *)s1 - *(const unsigned char *)(s2 - 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rax
  test   %dl,%dl
  je     L16
L29:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L19
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcmp(s1, s2)
register const char *s1, *s2;
{
  while (*s1 == *s2++)
    if (*s1++ == 0)
      return (0);
  return (*(const unsigned char *)s1 - *(const unsigned char *)(s2 - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%rax
  test   %dl,%dl
  je     L16
L26:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L28
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcmp(s1, s2)
register const char *s1, *s2;
{
  while (*s1 == *s2++)
    if (*s1++ == 0)
      return (0);
  return (*(const unsigned char *)s1 - *(const unsigned char *)(s2 - 1));
}
```
user: What is the c source code of the assembly code below:

```asm
<get_float_from_within_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L56
L72:
  addq   $0x1,-0x10(%rbp)
L56:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L72
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x2d,%eax
  je     L51
  cmp    $0x2e,%eax
  jne    L81
  movl   $0x1,-0x18(%rbp)
  jmp    L206
L81:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L109
  mov    $0x0,%eax
  jmp    L191
L109:
  movl   $0x1,-0x14(%rbp)
  jmp    L206
L51:
  nop
L206:
  addq   $0x1,-0x10(%rbp)
  jmp    L91
L136:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L157
  movl   $0x1,-0x14(%rbp)
  jmp    L201
L157:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L21
  addl   $0x1,-0x18(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  jle    L201
  mov    $0x0,%eax
  jmp    L191
L21:
  mov    $0x0,%eax
  jmp    L191
L201:
  addq   $0x1,-0x10(%rbp)
L91:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L107
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L107
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L136
L107:
  cmpl   $0x0,-0x14(%rbp)
  je     L96
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L130
L96:
  mov    $0x0,%eax
  jmp    L191
L130:
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L191:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: string

tool: D7: %lf

assistant: ```c
int get_float_from_within_string(char **str, double *val) {
  char *p, *valstart;
  int decimal_point_cnt = 0, has_digits = 0;
  p = *str;
  while (isspace(*p))
    p++;
  valstart = p;
  switch (*p) {
  case ('-'):
    break;
  case ('.'):
    decimal_point_cnt = 1;
    break;
  default:
    if (!isdigit(*p))
      return (0);
    has_digits = 1;
    break;
  }
  p++;
  while (!isspace(*p) && *p != ('\n') && *p != ('\0')) {
    if (isdigit(*p))
      has_digits = 1;
    else if (*p == '.') {
      if (++decimal_point_cnt > 1)
        return (0);
    } else
      return (0);
    p++;
  }
  if (!has_digits || sscanf(valstart, "%lf", val) != 1)
    return (0);
  *str = p;
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_float_from_within_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,0x8(%rsp)
  mov    (%rdi),%rbp
  jmp    L57
L65:
  add    $0x1,%rbp
L57:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L65
  movzbl 0x0(%rbp),%edi
  cmp    $0x2d,%dil
  je     L104
  cmp    $0x2e,%dil
  je     L148
  movsbl %dil,%edi
  call   <isdigit@plt>
  mov    $0x0,%r13d
  test   %rax,%rax
  je     L151
  mov    $0x1,%r13d
  mov    $0x0,%r12d
  jmp    L123
L104:
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  jmp    L123
L148:
  mov    $0x0,%r13d
  mov    $0x1,%r12d
L123:
  lea    0x1(%rbp),%rbx
  mov    $0x1,%r14d
  jmp    L169
L14:
  mov    %r14d,%r13d
L88:
  add    $0x1,%rbx
L169:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L73
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L73
  cmp    $0xa,%dil
  je     L73
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L14
  cmpb   $0x2e,(%rbx)
  jne    L118
  add    $0x1,%r12d
  cmp    $0x1,%r12d
  jle    L88
  mov    $0x0,%r13d
  jmp    L151
L73:
  test   %r13d,%r13d
  jne    L23
L151:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    0x8(%rsp),%rdx
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    %eax,%r13d
  cmp    $0x1,%eax
  jne    L54
  mov    %rbx,(%r15)
  jmp    L151
L118:
  mov    $0x0,%r13d
  jmp    L151
L54:
  mov    $0x0,%r13d
  jmp    L151
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: %lf

assistant: ```c
int get_float_from_within_string(char **str, double *val) {
  char *p, *valstart;
  int decimal_point_cnt = 0, has_digits = 0;
  p = *str;
  while (isspace(*p))
    p++;
  valstart = p;
  switch (*p) {
  case ('-'):
    break;
  case ('.'):
    decimal_point_cnt = 1;
    break;
  default:
    if (!isdigit(*p))
      return (0);
    has_digits = 1;
    break;
  }
  p++;
  while (!isspace(*p) && *p != ('\n') && *p != ('\0')) {
    if (isdigit(*p))
      has_digits = 1;
    else if (*p == '.') {
      if (++decimal_point_cnt > 1)
        return (0);
    } else
      return (0);
    p++;
  }
  if (!has_digits || sscanf(valstart, "%lf", val) != 1)
    return (0);
  *str = p;
  return (1);
}
```