ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D41(%rip),%rdi
  call   <puts@plt>
  lea    D27(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D35(%rip),%rbx
  lea    D43(%rip),%r13
  jmp    L6
L18:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  jbe    L15
L6:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  ja     L18
L15:
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D41
type_guessed: string
name: disassemble_data
arguments: data_tag: D27
type_guessed: string
name: disassemble_data
arguments: data_tag: D35
type_guessed: string
name: disassemble_data
arguments: data_tag: D43
type_guessed: string
name: disassemble_data
arguments: data_tag: D36
type_guessed: string

tool: D41: do-while Loop Example 2


tool: D27: Enter a number from 1 to 10: 

tool: D35: %d

tool: D43: Number is not in proper range!

tool: D36: 
You entered %d.



assistant: ```c
int main() {
  int num;
  printf("do-while Loop Example 2\n\n");
  do {
    printf("Enter a number from 1 to 10: ");
    scanf("%d", &num);
    if (num < 1 || num > 10)
      printf("Number is not in proper range!\n");
  } while (num < 1 || num > 10);
  printf("\nYou entered %d.\n\n", num);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D38(%rip),%rdi
  lea    D37(%rip),%r13
  push   %r12
  lea    D45(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D10(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L4:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  ja     L37
L39:
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L37:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  ja     L4
  jmp    L39
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D38
type_guessed: string
name: disassemble_data
arguments: tag: D37
type_guessed: string
name: disassemble_data
arguments: tag: D45
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D42
type_guessed: string

tool: D38: do-while Loop Example 2


tool: D37: Number is not in proper range!

tool: D45: Enter a number from 1 to 10: 

tool: D10: %d

tool: D42: 
You entered %d.



assistant: ```c
int main() {
  int num;
  printf("do-while Loop Example 2\n\n");
  do {
    printf("Enter a number from 1 to 10: ");
    scanf("%d", &num);
    if (num < 1 || num > 10)
      printf("Number is not in proper range!\n");
  } while (num < 1 || num > 10);
  printf("\nYou entered %d.\n\n", num);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D20(%rip),%rdi
  lea    D39(%rip),%r13
  push   %r12
  lea    D41(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D21(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L35:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  ja     L15
L13:
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  ja     L35
  jmp    L13
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D20
type_infered: string
name: disassemble_data
arguments: data_label: D39
type_infered: string
name: disassemble_data
arguments: data_label: D41
type_infered: string
name: disassemble_data
arguments: data_label: D21
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: string

tool: D20: do-while Loop Example 2


tool: D39: Number is not in proper range!

tool: D41: Enter a number from 1 to 10: 

tool: D21: %d

tool: D22: 
You entered %d.



assistant: ```c
int main() {
  int num;
  printf("do-while Loop Example 2\n\n");
  do {
    printf("Enter a number from 1 to 10: ");
    scanf("%d", &num);
    if (num < 1 || num > 10)
      printf("Number is not in proper range!\n");
  } while (num < 1 || num > 10);
  printf("\nYou entered %d.\n\n", num);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<capability_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x80,-0x4(%rbp)
  je     L52
  cmpl   $0x80,-0x4(%rbp)
  jg     L47
  cmpl   $0x20,-0x4(%rbp)
  jg     L139
  cmpl   $0x0,-0x4(%rbp)
  jle    L47
  cmpl   $0x20,-0x4(%rbp)
  ja     L47
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D93(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D93(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L139:
  cmpl   $0x40,-0x4(%rbp)
  je     L3
  jmp    L47
  lea    D35(%rip),%rax
  jmp    L53
  lea    D57(%rip),%rax
  jmp    L53
  lea    D8(%rip),%rax
  jmp    L53
  lea    D52(%rip),%rax
  jmp    L53
  lea    D104(%rip),%rax
  jmp    L53
  lea    D66(%rip),%rax
  jmp    L53
L3:
  lea    D102(%rip),%rax
  jmp    L53
L52:
  lea    D34(%rip),%rax
  jmp    L53
L47:
  lea    D101(%rip),%rax
L53:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D35
data_type: string
name: extract_symbolic_data
arguments: tag: D57
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D52
data_type: string
name: extract_symbolic_data
arguments: tag: D104
data_type: string
name: extract_symbolic_data
arguments: tag: D66
data_type: string
name: extract_symbolic_data
arguments: tag: D102
data_type: string
name: extract_symbolic_data
arguments: tag: D34
data_type: string
name: extract_symbolic_data
arguments: tag: D101
data_type: string

tool: D35: Other

tool: D57: Repeater/Hub

tool: D8: Bridge/Switch

tool: D52: Wireless LAN

tool: D104: Router

tool: D66: Telephone

tool: D102: DOCSIS/Cable Modem

tool: D34: Station

tool: D101: Unknown

assistant: ```c
char *capability_name(uint16_t capability) {
  switch (capability) {
  case 1:
    return "Other";
  case 2:
    return "Repeater/Hub";
  case 4:
    return "Bridge/Switch";
  case 8:
    return "Wireless LAN";
  case 16:
    return "Router";
  case 32:
    return "Telephone";
  case 64:
    return "DOCSIS/Cable Modem";
  case 128:
    return "Station";
  default:
    return "Unknown";
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<capability_name>:
  endbr64
  cmp    $0x20,%edi
  jg     L19
  lea    D35(%rip),%rax
  test   %edi,%edi
  jle    L8
  cmp    $0x20,%edi
  ja     L36
  mov    %edi,%edi
  lea    D75(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D116(%rip),%rax
  ret
L36:
  lea    D35(%rip),%rax
  ret
L19:
  lea    D7(%rip),%rax
  cmp    $0x40,%edi
  je     L8
  cmp    $0x80,%edi
  lea    D35(%rip),%rax
  lea    D113(%rip),%rdx
  cmove  %rdx,%rax
  ret
  lea    D64(%rip),%rax
  ret
  lea    D80(%rip),%rax
  ret
  lea    D114(%rip),%rax
  ret
  lea    D93(%rip),%rax
  ret
  lea    D69(%rip),%rax
L8:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D35
type: string
name: parse_data
arguments: data_tag: D116
type: string
name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D113
type: string
name: parse_data
arguments: data_tag: D64
type: string
name: parse_data
arguments: data_tag: D80
type: string
name: parse_data
arguments: data_tag: D114
type: string
name: parse_data
arguments: data_tag: D93
type: string
name: parse_data
arguments: data_tag: D69
type: string

tool: D35: Unknown

tool: D116: Repeater/Hub

tool: D7: DOCSIS/Cable Modem

tool: D113: Station

tool: D64: Bridge/Switch

tool: D80: Wireless LAN

tool: D114: Router

tool: D93: Telephone

tool: D69: Other

assistant: ```c
char *capability_name(uint16_t capability) {
  switch (capability) {
  case 1:
    return "Other";
  case 2:
    return "Repeater/Hub";
  case 4:
    return "Bridge/Switch";
  case 8:
    return "Wireless LAN";
  case 16:
    return "Router";
  case 32:
    return "Telephone";
  case 64:
    return "DOCSIS/Cable Modem";
  case 128:
    return "Station";
  default:
    return "Unknown";
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<capability_name>:
  endbr64
  cmp    $0x20,%edi
  jg     L27
  lea    D86(%rip),%rax
  test   %edi,%edi
  jle    L10
  cmp    $0x20,%edi
  ja     L19
  lea    D37(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L19:
  lea    D86(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D68(%rip),%rax
L10:
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  lea    D44(%rip),%rax
  cmp    $0x40,%edi
  je     L10
  cmp    $0x80,%edi
  lea    D27(%rip),%rdx
  lea    D86(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopl   (%rax)
  lea    D77(%rip),%rax
  ret
  lea    D113(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D4(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D112(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D50(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D86
datatype: string
name: parse_data
arguments: label: D68
datatype: string
name: parse_data
arguments: label: D44
datatype: string
name: parse_data
arguments: label: D27
datatype: string
name: parse_data
arguments: label: D77
datatype: string
name: parse_data
arguments: label: D113
datatype: string
name: parse_data
arguments: label: D4
datatype: string
name: parse_data
arguments: label: D112
datatype: string
name: parse_data
arguments: label: D50
datatype: string

tool: D86: Unknown

tool: D68: Other

tool: D44: DOCSIS/Cable Modem

tool: D27: Station

tool: D77: Telephone

tool: D113: Bridge/Switch

tool: D4: Wireless LAN

tool: D112: Router

tool: D50: Repeater/Hub

assistant: ```c
char *capability_name(uint16_t capability) {
  switch (capability) {
  case 1:
    return "Other";
  case 2:
    return "Repeater/Hub";
  case 4:
    return "Bridge/Switch";
  case 8:
    return "Wireless LAN";
  case 16:
    return "Router";
  case 32:
    return "Telephone";
  case 64:
    return "DOCSIS/Cable Modem";
  case 128:
    return "Station";
  default:
    return "Unknown";
  };
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<capability_name>:
  endbr64
  cmp    $0x20,%edi
  jg     L4
  lea    D97(%rip),%rax
  test   %edi,%edi
  jle    L1
  cmp    $0x20,%edi
  ja     L11
  lea    D57(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L11:
  lea    D97(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D104(%rip),%rax
L1:
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D89(%rip),%rax
  cmp    $0x40,%edi
  je     L1
  cmp    $0x80,%edi
  lea    D4(%rip),%rdx
  lea    D97(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopl   (%rax)
  lea    D84(%rip),%rax
  ret
  lea    D31(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D19(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D76(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D64(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D97
type_guessed: string
name: retrieve_data
arguments: data_label: D104
type_guessed: string
name: retrieve_data
arguments: data_label: D89
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D84
type_guessed: string
name: retrieve_data
arguments: data_label: D31
type_guessed: string
name: retrieve_data
arguments: data_label: D19
type_guessed: string
name: retrieve_data
arguments: data_label: D76
type_guessed: string
name: retrieve_data
arguments: data_label: D64
type_guessed: string

tool: D97: Unknown

tool: D104: Other

tool: D89: DOCSIS/Cable Modem

tool: D4: Station

tool: D84: Telephone

tool: D31: Bridge/Switch

tool: D19: Wireless LAN

tool: D76: Router

tool: D64: Repeater/Hub

assistant: ```c
char *capability_name(uint16_t capability) {
  switch (capability) {
  case 1:
    return "Other";
  case 2:
    return "Repeater/Hub";
  case 4:
    return "Bridge/Switch";
  case 8:
    return "Wireless LAN";
  case 16:
    return "Router";
  case 32:
    return "Telephone";
  case 64:
    return "DOCSIS/Cable Modem";
  case 128:
    return "Station";
  default:
    return "Unknown";
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mysend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L37:
  mov    -0x14(%rbp),%eax
  mov    $0x64,%esi
  mov    %eax,%edi
  call   <can_send@plt>
  test   %rax,%rax
  je     L2
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  add    %rax,%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L18
  mov    $0xffffffff,%eax
  jmp    L21
L18:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L37
  mov    -0x10(%rbp),%eax
L21:
  leave
  ret
```

assistant: ```c
int mysend(int sck, const void *adata, int bytes) {
  int sent;
  int error;
  const char *data;
  data = (const char *)adata;
  sent = 0;
  while (sent < bytes) {
    if (can_send(sck, 100)) {
      error = send(sck, data + sent, bytes - sent, MSG_NOSIGNAL);
      if (error < 1) {
        return -1;
      }
      sent += error;
    }
  }
  return sent;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mysend>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
L13:
  cmp    %ebx,%ebp
  jle    L2
  mov    $0x64,%esi
  mov    %r12d,%edi
  call   <can_send@plt>
  test   %rax,%rax
  je     L13
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r13,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    %r12d,%edi
  call   <send@plt>
  test   %eax,%eax
  jle    L36
  add    %eax,%ebx
  jmp    L13
L36:
  mov    $0xffffffff,%ebx
L2:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mysend(int sck, const void *adata, int bytes) {
  int sent;
  int error;
  const char *data;
  data = (const char *)adata;
  sent = 0;
  while (sent < bytes) {
    if (can_send(sck, 100)) {
      error = send(sck, data + sent, bytes - sent, MSG_NOSIGNAL);
      if (error < 1) {
        return -1;
      }
      sent += error;
    }
  }
  return sent;
}
```
user: What is the c source code of the assembly code below?

```asm
<mysend>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0x64,%esi
  mov    %ebp,%edi
  call   <can_send@plt>
  test   %rax,%rax
  jne    L51
L48:
  cmp    %r12d,%ebx
  jg     L47
L56:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L51:
  mov    D5(%rip),%rax
  mov    %ebx,%edx
  movslq %r12d,%rsi
  mov    %ebp,%edi
  sub    %r12d,%edx
  add    %r13,%rsi
  mov    (%rax),%ecx
  call   <send@plt>
  test   %eax,%eax
  jle    L55
  add    %eax,%r12d
  jmp    L48
L55:
  mov    $0xffffffff,%r12d
  jmp    L56
```

assistant: ```c
int mysend(int sck, const void *adata, int bytes) {
  int sent;
  int error;
  const char *data;
  data = (const char *)adata;
  sent = 0;
  while (sent < bytes) {
    if (can_send(sck, 100)) {
      error = send(sck, data + sent, bytes - sent, MSG_NOSIGNAL);
      if (error < 1) {
        return -1;
      }
      sent += error;
    }
  }
  return sent;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mysend>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    %r12d,%ebp
  jle    L9
  nopl   (%rax)
L32:
  mov    $0x64,%esi
  mov    %ebx,%edi
  call   <can_send@plt>
  test   %rax,%rax
  je     L32
  mov    D1(%rip),%rax
  mov    %ebp,%edx
  movslq %r12d,%rsi
  mov    %ebx,%edi
  sub    %r12d,%edx
  add    %r13,%rsi
  mov    (%rax),%ecx
  call   <send@plt>
  test   %eax,%eax
  jle    L13
  add    %eax,%r12d
  cmp    %r12d,%ebp
  jg     L32
L9:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    $0xffffffff,%r12d
  jmp    L9
```

assistant: ```c
int mysend(int sck, const void *adata, int bytes) {
  int sent;
  int error;
  const char *data;
  data = (const char *)adata;
  sent = 0;
  while (sent < bytes) {
    if (can_send(sck, 100)) {
      error = send(sck, data + sent, bytes - sent, MSG_NOSIGNAL);
      if (error < 1) {
        return -1;
      }
      sent += error;
    }
  }
  return sent;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L7:
  mov    -0x8(%rbp),%eax
  rol    $0x5,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash_mem(const void *data, unsigned int len) {
  unsigned int h;
  unsigned int i;
  h = len;
  for (i = 0; i < len; ++i)
    h = ((h >> 27) ^ (h << 5)) ^ ((const unsigned char *)data)[i];
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_mem>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L15
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%ecx
  lea    0x1(%rdi,%rcx,1),%rsi
L16:
  rol    $0x5,%eax
  movzbl (%rdx),%ecx
  xor    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L16
L15:
  ret
```

assistant: ```c
unsigned int hash_mem(const void *data, unsigned int len) {
  unsigned int h;
  unsigned int i;
  h = len;
  for (i = 0; i < len; ++i)
    h = ((h >> 27) ^ (h << 5)) ^ ((const unsigned char *)data)[i];
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_mem>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L12
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl (%rdi),%edx
  rol    $0x5,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  cmp    %rcx,%rdi
  jne    L17
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash_mem(const void *data, unsigned int len) {
  unsigned int h;
  unsigned int i;
  h = len;
  for (i = 0; i < len; ++i)
    h = ((h >> 27) ^ (h << 5)) ^ ((const unsigned char *)data)[i];
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hash_mem>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L14
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%rdi),%edx
  rol    $0x5,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L15
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash_mem(const void *data, unsigned int len) {
  unsigned int h;
  unsigned int i;
  h = len;
  for (i = 0; i < len; ++i)
    h = ((h >> 27) ^ (h << 5)) ^ ((const unsigned char *)data)[i];
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x17447d68,%eax
  mov    %eax,%edx
  je     L0
  mov    %eax,%ecx
  shl    $0x4,%ecx
  movzbl %cl,%ecx
  or     %eax,%ecx
  movzbl %ah,%eax
  shl    $0x10,%eax
  mov    %ecx,%edx
  and    $0xff00ffff,%edx
  or     %eax,%edx
  mov    %cl,%dh
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %cl,%dl
L15:
  add    $0x5dc2c1a0,%edx
  mov    %edx,(%rsi)
  ret
L0:
  movsbl %ah,%eax
  mov    %dl,%dh
  mov    %al,%dl
  add    %edx,%edx
  jmp    L15
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] == local2 * local1) {
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          state[0UL] += state[0UL];
        } else {
          state[local2] |= ((state[local1] + state[local2]) & 31U) << 3UL;
          copy12 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 2721922656U;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%ecx
  sub    $0x17447d68,%ecx
  mov    %ecx,%edx
  jne    L4
  xor    %dx,%dx
  add    %edx,%edx
  add    $0x5dc2c1a0,%edx
  mov    %edx,(%rsi)
  ret
  xchg   %ax,%ax
L4:
  mov    %ecx,%eax
  shl    $0x4,%eax
  movzbl %al,%eax
  or     %ecx,%eax
  movzwl %ax,%ecx
  mov    %eax,%edx
  shl    $0x8,%eax
  shl    $0x8,%ecx
  and    $0xff0000ff,%edx
  sar    $0x18,%eax
  or     %ecx,%edx
  mov    %al,%dl
  add    $0x5dc2c1a0,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] == local2 * local1) {
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          state[0UL] += state[0UL];
        } else {
          state[local2] |= ((state[local1] + state[local2]) & 31U) << 3UL;
          copy12 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 2721922656U;
  }
}
```