ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CANInit>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  lea    0x20(%r12),%rbx
  sub    $0x8,%rsp
  call   <CANRegWrite@plt>
L31:
  mov    %rbx,%rdi
  call   <CANRegRead@plt>
  test   $0x80,%ah
  jne    L31
  lea    0x24(%r12),%r13
  mov    $0xb0,%esi
  mov    $0x1,%ebp
  mov    %r13,%rdi
  call   <CANRegWrite@plt>
  lea    0x34(%r12),%rdi
  xor    %esi,%esi
  call   <CANRegWrite@plt>
  lea    0x38(%r12),%rdi
  xor    %esi,%esi
  call   <CANRegWrite@plt>
  nopl   0x0(%rax)
L29:
  mov    %rbx,%rdi
  call   <CANRegRead@plt>
  test   $0x80,%ah
  jne    L29
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <CANRegWrite@plt>
  cmp    $0x21,%rbp
  jne    L29
  mov    $0xc,%esi
  mov    %r13,%rdi
  mov    $0x1,%ebp
  call   <CANRegWrite@plt>
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rdi
  call   <CANRegRead@plt>
  test   $0x80,%ah
  jne    L4
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <CANRegWrite@plt>
  cmp    $0x21,%rbp
  jne    L4
  add    $0x8,%rsp
  lea    0x4(%r12),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <CANRegRead@plt>
```

assistant: ```c
void CANInit(unsigned long ulBase) {
  unsigned long ulMsg;
  ;
  CANRegWrite(ulBase + 0x00000000, 0x00000001);
  while (CANRegRead(ulBase + 0x00000020) & 0x00008000) {
  }
  CANRegWrite(ulBase + 0x00000024, 0x00000080 | 0x00000020 | 0x00000010);
  CANRegWrite(ulBase + 0x00000034, 0);
  CANRegWrite(ulBase + 0x00000038, 0);
  for (ulMsg = 1; ulMsg <= 32; ulMsg++) {
    while (CANRegRead(ulBase + 0x00000020) & 0x00008000) {
    }
    CANRegWrite(ulBase + 0x00000020, ulMsg);
  }
  CANRegWrite(ulBase + 0x00000024, 0x00000004 | 0x00000008);
  for (ulMsg = 1; ulMsg <= 32; ulMsg++) {
    while (CANRegRead(ulBase + 0x00000020) & 0x00008000) {
    }
    CANRegWrite(ulBase + 0x00000020, ulMsg);
  }
  CANRegRead(ulBase + 0x00000004);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putc@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void puts(char s[]) {
  for (int i = 0; s[i]; i++) {
    putc(s[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<puts>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  push   %rbx
  lea    0x1(%rdi),%rbx
L7:
  movsbl %al,%edi
  call   <putc@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L7
  pop    %rbx
  ret
L9:
  ret
```

assistant: ```c
void puts(char s[]) {
  for (int i = 0; s[i]; i++) {
    putc(s[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<puts>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  push   %rbx
  lea    0x1(%rdi),%rbx
L12:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putc@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L12
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void puts(char s[]) {
  for (int i = 0; s[i]; i++) {
    putc(s[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<puts>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  push   %rbx
  lea    0x1(%rdi),%rbx
L7:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putc@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L7
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void puts(char s[]) {
  for (int i = 0; s[i]; i++) {
    putc(s[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<calRef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L56
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L56
  cmpl   $0x0,-0x10(%rbp)
  js     L56
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L56
  cmpl   $0x0,-0x10(%rbp)
  jne    L40
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L60
L40:
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L60
L56:
  pxor   %xmm0,%xmm0
L60:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double calRef(const double value[], int length, int index, int n) {
  if (n > 0 && n < length && index >= 0 && index < length) {
    if (index == 0) {
      return value[index];
    } else {
      return value[index - n];
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calRef>:
  endbr64
  test   %ecx,%ecx
  jle    L49
  cmp    %esi,%ecx
  jge    L49
  test   %edx,%edx
  js     L3
  cmp    %edx,%esi
  jle    L3
  test   %edx,%edx
  jne    L18
  movsd  (%rdi),%xmm0
  ret
L18:
  sub    %ecx,%edx
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm0
  ret
L49:
  pxor   %xmm0,%xmm0
  ret
L3:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double calRef(const double value[], int length, int index, int n) {
  if (n > 0 && n < length && index >= 0 && index < length) {
    if (index == 0) {
      return value[index];
    } else {
      return value[index - n];
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calRef>:
  endbr64
  test   %ecx,%ecx
  jle    L34
  cmp    %esi,%ecx
  jge    L34
  test   %edx,%edx
  js     L34
  cmp    %edx,%esi
  jle    L34
  test   %edx,%edx
  jne    L20
  movsd  (%rdi),%xmm0
  ret
  nopl   (%rax)
L34:
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L20:
  sub    %ecx,%edx
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm0
  ret
```

assistant: ```c
double calRef(const double value[], int length, int index, int n) {
  if (n > 0 && n < length && index >= 0 && index < length) {
    if (index == 0) {
      return value[index];
    } else {
      return value[index - n];
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calRef>:
  endbr64
  test   %ecx,%ecx
  jle    L48
  cmp    %esi,%ecx
  jge    L48
  test   %edx,%edx
  js     L48
  cmp    %edx,%esi
  jle    L48
  test   %edx,%edx
  jne    L43
  movsd  (%rdi),%xmm0
  ret
  nopl   (%rax)
L48:
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L43:
  sub    %ecx,%edx
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm0
  ret
```

assistant: ```c
double calRef(const double value[], int length, int index, int n) {
  if (n > 0 && n < length && index >= 0 && index < length) {
    if (index == 0) {
      return value[index];
    } else {
      return value[index - n];
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strEscapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x22,(%rax)
  jmp    L27
L20:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L6
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L6
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L14
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x5c,(%rax)
L14:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L27:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x22,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strEscapify(const char *in, char *out) {
  const char *scanin = in;
  char *scanout = out;
  *scanout++ = '\"';
  while (*scanin != '\0') {
    if ((*scanin == '\'') || (*scanin == '\"') || (*scanin == '\\'))
      *(scanout++) = '\\';
    *(scanout++) = *(scanin++);
  }
  *scanout++ = '\"';
  *scanout++ = '\0';
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strEscapify>:
  endbr64
  mov    %rsi,%rax
  lea    0x1(%rsi),%rcx
  movb   $0x22,(%rsi)
  movzbl (%rdi),%edx
  movabs $0x400000000000021,%r9
  test   %dl,%dl
  jne    L11
  mov    %rcx,%r8
L33:
  movb   $0x22,(%r8)
  movb   $0x0,0x1(%r8)
  ret
L26:
  movb   $0x5c,(%rcx)
  lea    0x1(%rcx),%rcx
L30:
  add    $0x1,%rdi
  lea    0x1(%rcx),%r8
  movzbl -0x1(%rdi),%edx
  mov    %dl,(%rcx)
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L33
  mov    %r8,%rcx
L11:
  sub    $0x22,%edx
  cmp    $0x3a,%dl
  ja     L30
  bt     %rdx,%r9
  jae    L30
  jmp    L26
```

assistant: ```c
char *strEscapify(const char *in, char *out) {
  const char *scanin = in;
  char *scanout = out;
  *scanout++ = '\"';
  while (*scanin != '\0') {
    if ((*scanin == '\'') || (*scanin == '\"') || (*scanin == '\\'))
      *(scanout++) = '\\';
    *(scanout++) = *(scanin++);
  }
  *scanout++ = '\"';
  *scanout++ = '\0';
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strEscapify>:
  endbr64
  movb   $0x22,(%rsi)
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  lea    0x1(%rsi),%rcx
  movabs $0x400000000000021,%r9
  test   %dl,%dl
  jne    L27
  jmp    L49
  nopl   0x0(%rax)
L36:
  mov    %r8,%rcx
L27:
  sub    $0x22,%edx
  cmp    $0x3a,%dl
  ja     L1
  bt     %rdx,%r9
  jae    L1
  movb   $0x5c,(%rcx)
  add    $0x1,%rcx
L1:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  lea    0x1(%rcx),%r8
  mov    %dl,(%rcx)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L36
  mov    $0x22,%edx
  mov    %dx,(%r8)
  ret
  xchg   %ax,%ax
L49:
  mov    %rcx,%r8
  mov    $0x22,%edx
  mov    %dx,(%r8)
  ret
```

assistant: ```c
char *strEscapify(const char *in, char *out) {
  const char *scanin = in;
  char *scanout = out;
  *scanout++ = '\"';
  while (*scanin != '\0') {
    if ((*scanin == '\'') || (*scanin == '\"') || (*scanin == '\\'))
      *(scanout++) = '\\';
    *(scanout++) = *(scanin++);
  }
  *scanout++ = '\"';
  *scanout++ = '\0';
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strEscapify>:
  endbr64
  movb   $0x22,(%rsi)
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  lea    0x1(%rsi),%rcx
  movabs $0x400000000000021,%r9
  test   %dl,%dl
  jne    L47
  jmp    L40
  nopl   0x0(%rax)
L25:
  mov    %r8,%rcx
L47:
  lea    -0x22(%rdx),%r8d
  cmp    $0x3a,%r8b
  ja     L45
  bt     %r8,%r9
  jae    L45
  movb   $0x5c,(%rcx)
  movzbl (%rdi),%edx
  add    $0x1,%rcx
L45:
  add    $0x1,%rdi
  mov    %dl,(%rcx)
  lea    0x1(%rcx),%r8
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L25
  mov    $0x22,%edx
  mov    %dx,(%r8)
  ret
L40:
  mov    %rcx,%r8
  mov    $0x22,%edx
  mov    %dx,(%r8)
  ret
```

assistant: ```c
char *strEscapify(const char *in, char *out) {
  const char *scanin = in;
  char *scanout = out;
  *scanout++ = '\"';
  while (*scanin != '\0') {
    if ((*scanin == '\'') || (*scanin == '\"') || (*scanin == '\\'))
      *(scanout++) = '\\';
    *(scanout++) = *(scanin++);
  }
  *scanout++ = '\"';
  *scanout++ = '\0';
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <func@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: end


assistant: ```c
int main() {
  func();
  printf("end\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <func@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: end


assistant: ```c
int main() {
  func();
  printf("end\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <func@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: end


assistant: ```c
int main() {
  func();
  printf("end\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <func@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: end


assistant: ```c
int main() {
  func();
  printf("end\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fhasaccess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  jne    L112
  mov    $0x1,%eax
  jmp    L81
L112:
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  je     L48
  mov    $0x0,%eax
  jmp    L81
L48:
  mov    -0x30(%rbp),%rbx
  mov    $0x0,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbx
  jne    L110
  mov    $0x1,%eax
  jmp    L81
L110:
  mov    -0x24(%rbp),%eax
  mov    -0x38(%rbp),%ecx
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <hasopperm@plt>
  test   %rax,%rax
  je     L39
  mov    $0x1,%eax
  jmp    L81
L39:
  mov    -0x24(%rbp),%eax
  mov    -0x38(%rbp),%ecx
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <hasopperm@plt>
  test   %rax,%rax
  je     L58
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <userhasgid@plt>
  test   %rax,%rax
  je     L58
  mov    $0x1,%eax
  jmp    L81
L58:
  mov    $0x0,%eax
L81:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
bool fhasaccess(int fd, int op) {
  struct stat stat;
  if (geteuid() == 0) {
    return true;
  }
  if (fstat(fd, &stat) != 0) {
    return false;
  }
  if (stat.st_uid == geteuid()) {
    return true;
  }
  if (hasopperm(stat.st_mode, op, 0)) {
    return true;
  }
  if (hasopperm(stat.st_mode, op, 1) && userhasgid(stat.st_gid)) {
    return true;
  }
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fhasaccess>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <geteuid@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L6
L13:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    %rsp,%rsi
  mov    %ebp,%edi
  call   <fstat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L13
  mov    (%rsp),%rbp
  call   <geteuid@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rbp
  je     L13
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    0xc(%rsp),%edi
  call   <hasopperm@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L13
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    0xc(%rsp),%edi
  call   <hasopperm@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L13
  mov    0x8(%rsp),%edi
  call   <userhasgid@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L13
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool fhasaccess(int fd, int op) {
  struct stat stat;
  if (geteuid() == 0) {
    return true;
  }
  if (fstat(fd, &stat) != 0) {
    return false;
  }
  if (stat.st_uid == geteuid()) {
    return true;
  }
  if (hasopperm(stat.st_mode, op, 0)) {
    return true;
  }
  if (hasopperm(stat.st_mode, op, 1) && userhasgid(stat.st_gid)) {
    return true;
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fhasaccess>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  jne    L67
L13:
  mov    $0x1,%eax
L68:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  mov    %rsp,%rsi
  mov    %ebp,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L28
  mov    (%rsp),%rbp
  xor    %eax,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbp
  je     L13
  mov    0xc(%rsp),%edi
  xor    %edx,%edx
  mov    %r12d,%esi
  call   <hasopperm@plt>
  test   %rax,%rax
  jne    L13
  mov    0xc(%rsp),%edi
  mov    $0x1,%edx
  mov    %r12d,%esi
  call   <hasopperm@plt>
  test   %rax,%rax
  jne    L32
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  jmp    L68
  nopl   0x0(%rax)
L32:
  mov    0x8(%rsp),%edi
  call   <userhasgid@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L68
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool fhasaccess(int fd, int op) {
  struct stat stat;
  if (geteuid() == 0) {
    return true;
  }
  if (fstat(fd, &stat) != 0) {
    return false;
  }
  if (stat.st_uid == geteuid()) {
    return true;
  }
  if (hasopperm(stat.st_mode, op, 0)) {
    return true;
  }
  if (hasopperm(stat.st_mode, op, 1) && userhasgid(stat.st_gid)) {
    return true;
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fhasaccess>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <geteuid@plt>
  test   %rax,%rax
  jne    L49
L77:
  mov    $0x1,%eax
L56:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L72
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %rsp,%rsi
  mov    %ebp,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L13
  mov    (%rsp),%rbp
  xor    %eax,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbp
  je     L77
  mov    0xc(%rsp),%edi
  xor    %edx,%edx
  mov    %r12d,%esi
  call   <hasopperm@plt>
  test   %rax,%rax
  jne    L77
  mov    0xc(%rsp),%edi
  mov    $0x1,%edx
  mov    %r12d,%esi
  call   <hasopperm@plt>
  test   %rax,%rax
  jne    L39
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  jmp    L56
  nopl   0x0(%rax)
L39:
  mov    0x8(%rsp),%edi
  call   <userhasgid@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L56
L72:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool fhasaccess(int fd, int op) {
  struct stat stat;
  if (geteuid() == 0) {
    return true;
  }
  if (fstat(fd, &stat) != 0) {
    return false;
  }
  if (stat.st_uid == geteuid()) {
    return true;
  }
  if (hasopperm(stat.st_mode, op, 0)) {
    return true;
  }
  if (hasopperm(stat.st_mode, op, 1) && userhasgid(stat.st_gid)) {
    return true;
  }
  return false;
}
```
user: What is the c source code of the assembly code below:

```asm
<in_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movzwl -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L8
L4:
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0xc(%rbp)
  subl   $0x2,-0x10(%rbp)
L8:
  cmpl   $0x1,-0x10(%rbp)
  jg     L4
  cmpl   $0x1,-0x10(%rbp)
  jne    L24
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  leave
  ret
```

assistant: ```c
unsigned short in_sum(char *packet, int len, unsigned short csum) {
  int nleft = len;
  const unsigned short *data = (short *)packet;
  int sum = csum;
  while (nleft > 1) {
    sum += *data++;
    nleft -= 2;
  }
  if (nleft == 1)
    sum += htons(packet[len - 1] << 8);
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: What is the c source code of the assembly code below?

```asm
<in_sum>:
  endbr64
  push   %rbx
  movzwl %dx,%ebx
  cmp    $0x1,%esi
  jle    L29
  lea    -0x2(%rsi),%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,2),%rdx
L35:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%eax
  add    %eax,%ebx
  cmp    %rdx,%rdi
  jne    L35
  neg    %ecx
  lea    -0x2(%rsi,%rcx,2),%esi
L29:
  cmp    $0x1,%esi
  je     L10
L27:
  mov    %ebx,%edx
  sar    $0x10,%edx
  movzwl %bx,%ebx
  add    %ebx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  pop    %rbx
  ret
L10:
  mov    $0x0,%edi
  call   <htons@plt>
  add    %eax,%ebx
  jmp    L27
```

assistant: ```c
unsigned short in_sum(char *packet, int len, unsigned short csum) {
  int nleft = len;
  const unsigned short *data = (short *)packet;
  int sum = csum;
  while (nleft > 1) {
    sum += *data++;
    nleft -= 2;
  }
  if (nleft == 1)
    sum += htons(packet[len - 1] << 8);
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<in_sum>:
  endbr64
  push   %rbx
  movzwl %dx,%ebx
  cmp    $0x1,%esi
  jle    L12
  sub    $0x2,%esi
  mov    %esi,%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,2),%rdx
  nopl   0x0(%rax,%rax,1)
L37:
  movzwl (%rdi),%eax
  add    $0x2,%rdi
  add    %eax,%ebx
  cmp    %rdi,%rdx
  jne    L37
  neg    %ecx
  lea    (%rsi,%rcx,2),%esi
L12:
  cmp    $0x1,%esi
  je     L24
L25:
  mov    %ebx,%edx
  movzwl %bx,%ebx
  sar    $0x10,%edx
  add    %ebx,%edx
  pop    %rbx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   (%rax)
L24:
  xor    %edi,%edi
  call   <htons@plt>
  add    %eax,%ebx
  jmp    L25
```

assistant: ```c
unsigned short in_sum(char *packet, int len, unsigned short csum) {
  int nleft = len;
  const unsigned short *data = (short *)packet;
  int sum = csum;
  while (nleft > 1) {
    sum += *data++;
    nleft -= 2;
  }
  if (nleft == 1)
    sum += htons(packet[len - 1] << 8);
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```