ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %esi,%esi
  test   %edx,%edx
  je     L1
  nopl   0x0(%rax,%rax,1)
L12:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cmp    $0x7,%edx
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%esi
  mov    %eax,%edx
  test   %eax,%eax
  jne    L12
  movl   $0x0,0x4(%rsp)
L1:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D17: %d

tool: D0: %d


assistant: ```c
main() {
  int a, b;
  b = 0;
  scanf("%d", &a);
  while (a != 0) {
    if ((a % 10) == 7)
      b++;
    a /= 10;
  }
  printf("%d\n", b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Array1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  mov    $0x10,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D11
type_infered: string

tool: D0: %d, %d


tool: D11: %d, %d, %d, %d


assistant: ```c
void Array1() {
  int a[] = {1, 2, 3, 4};
  int *p = a;
  printf("%d, %d\n", a, p);
  printf("%d, %d, %d, %d\n", a[2], *(a + 2), *(2 + a), 2 [a]);
  printf("%d, %d\n", sizeof(a), sizeof(p));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Array1>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  mov    %rsp,%rsi
  mov    %rsi,%rdx
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    %esi,%r8d
  mov    %esi,%ecx
  mov    %esi,%edx
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  mov    $0x10,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D2
type_guessed: string

tool: D16: %d, %d


tool: D2: %d, %d, %d, %d


assistant: ```c
void Array1() {
  int a[] = {1, 2, 3, 4};
  int *p = a;
  printf("%d, %d\n", a, p);
  printf("%d, %d, %d, %d\n", a[2], *(a + 2), *(2 + a), 2 [a]);
  printf("%d, %d\n", sizeof(a), sizeof(p));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Array1>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rsi
  mov    %rsi,%rdx
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,%edx
  mov    %esi,%r8d
  mov    %esi,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x8,%edx
  mov    %rbp,%rdi
  mov    $0x10,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string

tool: D10: %d, %d


tool: D0: %d, %d, %d, %d


assistant: ```c
void Array1() {
  int a[] = {1, 2, 3, 4};
  int *p = a;
  printf("%d, %d\n", a, p);
  printf("%d, %d, %d, %d\n", a[2], *(a + 2), *(2 + a), 2 [a]);
  printf("%d, %d\n", sizeof(a), sizeof(p));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Array1>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    %rsi,%rdx
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,%edx
  mov    %esi,%r8d
  mov    %esi,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x8,%edx
  mov    %rbp,%rdi
  mov    $0x10,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D26
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D22
type_guessed: string

tool: D25: %d, %d


tool: {"D26": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D22: %d, %d, %d, %d


assistant: ```c
void Array1() {
  int a[] = {1, 2, 3, 4};
  int *p = a;
  printf("%d, %d\n", a, p);
  printf("%d, %d, %d, %d\n", a[2], *(a + 2), *(2 + a), 2 [a]);
  printf("%d, %d\n", sizeof(a), sizeof(p));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<to_newick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <subtree@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L18
L4:
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <append_to@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string

tool: D6: ;

assistant: ```c
char *to_newick(struct rnode *node) {
  char *result;
  result = subtree(node);
  if (NULL == result)
    return NULL;
  result = append_to(result, ";");
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<to_newick>:
  endbr64
  sub    $0x8,%rsp
  call   <subtree@plt>
  test   %rax,%rax
  je     L0
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <append_to@plt>
L0:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: ;

assistant: ```c
char *to_newick(struct rnode *node) {
  char *result;
  result = subtree(node);
  if (NULL == result)
    return NULL;
  result = append_to(result, ";");
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<to_newick>:
  endbr64
  sub    $0x8,%rsp
  call   <subtree@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  lea    D3(%rip),%rsi
  add    $0x8,%rsp
  jmp    1060 <append_to@plt>
  nopl   (%rax)
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: string

tool: D3: ;

assistant: ```c
char *to_newick(struct rnode *node) {
  char *result;
  result = subtree(node);
  if (NULL == result)
    return NULL;
  result = append_to(result, ";");
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<to_newick>:
  endbr64
  sub    $0x8,%rsp
  call   <subtree@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  lea    D4(%rip),%rsi
  add    $0x8,%rsp
  jmp    1060 <append_to@plt>
  nopl   (%rax)
L3:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: ;

assistant: ```c
char *to_newick(struct rnode *node) {
  char *result;
  result = subtree(node);
  if (NULL == result)
    return NULL;
  result = append_to(result, ";");
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<write_fram>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x5c8,%rsp
  mov    %edi,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x5b8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <FS460_get_tv_active_lines@plt>
  mov    $0x0,%ebx
  mov    $0xffffff80,%r14d
L1:
  cmp    %ebx,%r15d
  mov    $0x10,%edx
  cmovne %r14d,%edx
  lea    0x10(%rsp),%rax
  lea    0x5b0(%rsp),%rcx
L37:
  movb   $0x80,(%rax)
  mov    %dl,0x1(%rax)
  add    $0x2,%rax
  cmp    %rax,%rcx
  jne    L37
  mov    %ebx,%edi
  call   <FS460_image_set_begin_field@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L9
  mov    $0x0,%r12d
  lea    0x10(%rsp),%r13
L38:
  mov    $0x5a0,%esi
  mov    %r13,%rdi
  call   <FS460_image_set_start_write@plt>
  movl   $0x0,0x8(%rsp)
  lea    0x8(%rsp),%rbp
L42:
  mov    %rbp,%rdi
  call   <FS460_image_is_transfer_completed@plt>
  cmpl   $0x0,0x8(%rsp)
  je     L42
  add    $0x1,%r12d
  mov    0xc(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jg     L38
L9:
  add    $0x1,%ebx
  cmp    $0x2,%ebx
  jne    L1
  mov    0x5b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x5c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_fram(int toggle) {
  char buf[720 * 2];
  int i, j, field;
  int completed;
  int full_height;
  FS460_get_tv_active_lines(&full_height);
  for (field = 0; field < 2; field++) {
    for (i = 0; i < sizeof(buf); i += 2) {
      buf[i] = (char)0x80;
      buf[i + 1] = ((field ^ toggle) ? (char)0x80 : (char)0x10);
    }
    FS460_image_set_begin_field(field);
    for (j = 0; j < full_height / 2; j++) {
      FS460_image_set_start_write(buf, sizeof(buf));
      completed = 0;
      while (!completed)
        FS460_image_is_transfer_completed(&completed);
    }
    for (; j < full_height / 2; j++) {
      for (i = 0; i < sizeof(buf); i += 2) {
        buf[i] = (char)0x80;
        buf[i + 1] = (char)0x10;
      }
      FS460_image_set_start_write(buf, sizeof(buf));
      completed = 0;
      while (!completed)
        FS460_image_is_transfer_completed(&completed);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_fram>:
  endbr64
  push   %r15
  mov    $0xffffff80,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x5d8,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x1c(%rsp),%rdi
  lea    0x20(%rsp),%r13
  lea    0x5c0(%rsp),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x5c8(%rsp)
  xor    %eax,%eax
  call   <FS460_get_tv_active_lines@plt>
L28:
  cmp    %r14d,0xc(%rsp)
  mov    $0x10,%edx
  mov    %r13,%rax
  cmovne %r15d,%edx
  nopl   (%rax)
L33:
  movb   $0x80,(%rax)
  add    $0x2,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rbx,%rax
  jne    L33
  mov    %r14d,%edi
  call   <FS460_image_set_begin_field@plt>
  cmpl   $0x1,0x1c(%rsp)
  jle    L25
  xor    %r12d,%r12d
  lea    0x18(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    $0x5a0,%esi
  mov    %r13,%rdi
  call   <FS460_image_set_start_write@plt>
  movl   $0x0,0x18(%rsp)
  nopl   (%rax)
L14:
  mov    %rbp,%rdi
  call   <FS460_image_is_transfer_completed@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  je     L14
  mov    0x1c(%rsp),%edx
  add    $0x1,%r12d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jg     L31
L25:
  cmp    $0x1,%r14d
  je     L55
  mov    $0x1,%r14d
  jmp    L28
L55:
  mov    0x5c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x5d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_fram(int toggle) {
  char buf[720 * 2];
  int i, j, field;
  int completed;
  int full_height;
  FS460_get_tv_active_lines(&full_height);
  for (field = 0; field < 2; field++) {
    for (i = 0; i < sizeof(buf); i += 2) {
      buf[i] = (char)0x80;
      buf[i + 1] = ((field ^ toggle) ? (char)0x80 : (char)0x10);
    }
    FS460_image_set_begin_field(field);
    for (j = 0; j < full_height / 2; j++) {
      FS460_image_set_start_write(buf, sizeof(buf));
      completed = 0;
      while (!completed)
        FS460_image_is_transfer_completed(&completed);
    }
    for (; j < full_height / 2; j++) {
      for (i = 0; i < sizeof(buf); i += 2) {
        buf[i] = (char)0x80;
        buf[i + 1] = (char)0x10;
      }
      FS460_image_set_start_write(buf, sizeof(buf));
      completed = 0;
      while (!completed)
        FS460_image_is_transfer_completed(&completed);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_fram>:
  endbr64
  push   %r15
  mov    $0x80,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x5e8,%rsp
  mov    %edi,0x1c(%rsp)
  lea    0x2c(%rsp),%rdi
  lea    0x30(%rsp),%r12
  lea    0x5d0(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x5d8(%rsp)
  xor    %eax,%eax
  call   <FS460_get_tv_active_lines@plt>
L67:
  cmp    %r14d,0x1c(%rsp)
  mov    $0x10,%ecx
  mov    %r12,%rax
  cmovne %r15,%rcx
  mov    %rcx,%rdx
  shl    $0x10,%rdx
  or     $0x80,%dh
  or     %rcx,%rdx
  shl    $0x10,%rdx
  or     $0x80,%dh
  or     %rcx,%rdx
  shl    $0x10,%rdx
  or     $0x80,%dh
  or     %rcx,%rdx
  shl    $0x8,%rdx
  or     $0x80,%dl
  nopl   (%rax)
L60:
  mov    %rdx,(%rsp)
  add    $0x20,%rax
  mov    %rdx,0x8(%rsp)
  movdqa (%rsp),%xmm0
  movaps %xmm0,-0x20(%rax)
  movaps %xmm0,-0x10(%rax)
  cmp    %rax,%r13
  jne    L60
  mov    %r14d,%edi
  call   <FS460_image_set_begin_field@plt>
  cmpl   $0x1,0x2c(%rsp)
  jle    L12
  xor    %ebp,%ebp
  lea    0x28(%rsp),%rbx
  nopl   (%rax)
L33:
  mov    $0x5a0,%esi
  mov    %r12,%rdi
  call   <FS460_image_set_start_write@plt>
  movl   $0x0,0x28(%rsp)
  nopl   (%rax)
L59:
  mov    %rbx,%rdi
  call   <FS460_image_is_transfer_completed@plt>
  mov    0x28(%rsp),%eax
  test   %eax,%eax
  je     L59
  mov    0x2c(%rsp),%edx
  add    $0x1,%ebp
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %ebp,%eax
  jg     L33
L12:
  cmp    $0x1,%r14d
  je     L62
  mov    $0x1,%r14d
  jmp    L67
L62:
  mov    0x5d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x5e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_fram(int toggle) {
  char buf[720 * 2];
  int i, j, field;
  int completed;
  int full_height;
  FS460_get_tv_active_lines(&full_height);
  for (field = 0; field < 2; field++) {
    for (i = 0; i < sizeof(buf); i += 2) {
      buf[i] = (char)0x80;
      buf[i + 1] = ((field ^ toggle) ? (char)0x80 : (char)0x10);
    }
    FS460_image_set_begin_field(field);
    for (j = 0; j < full_height / 2; j++) {
      FS460_image_set_start_write(buf, sizeof(buf));
      completed = 0;
      while (!completed)
        FS460_image_is_transfer_completed(&completed);
    }
    for (; j < full_height / 2; j++) {
      for (i = 0; i < sizeof(buf); i += 2) {
        buf[i] = (char)0x80;
        buf[i + 1] = (char)0x10;
      }
      FS460_image_set_start_write(buf, sizeof(buf));
      completed = 0;
      while (!completed)
        FS460_image_is_transfer_completed(&completed);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x12c,-0x4(%rbp)
  jmp    L9
L1:
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rdx
  mov    -0x4(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x14,-0x4(%rbp)
L9:
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
data_type: byte[8]
name: retrieve_data
arguments: label: D6
data_type: string

tool: {"D19": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D6: %3d %6.2f


assistant: ```c
main() {
  int fahr;
  for (fahr = 300; fahr >= 0; fahr = fahr - 20)
    printf("%3d %6.2f\n", fahr, (5.0 / 9.0) * (fahr - 32));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x12c,%ebx
  lea    D6(%rip),%rbp
L1:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D0(%rip),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x14,%ebx
  cmp    $0xffffffec,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: byte[8]

tool: D6: %3d %6.2f


tool: {"D0": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fahr;
  for (fahr = 300; fahr >= 0; fahr = fahr - 20)
    printf("%3d %6.2f\n", fahr, (5.0 / 9.0) * (fahr - 32));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x12c,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L8:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D13(%rip),%xmm0
  sub    $0x14,%ebx
  call   <printf@plt>
  cmp    $0xffffffec,%ebx
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: byte[8]

tool: D8: %3d %6.2f


tool: {"D13": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fahr;
  for (fahr = 300; fahr >= 0; fahr = fahr - 20)
    printf("%3d %6.2f\n", fahr, (5.0 / 9.0) * (fahr - 32));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    $0x12c,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L2:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D14(%rip),%xmm0
  sub    $0x14,%ebx
  call   <printf@plt>
  cmp    $0xffffffec,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: byte[8]

tool: D15: %3d %6.2f


tool: {"D14": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fahr;
  for (fahr = 300; fahr >= 0; fahr = fahr - 20)
    printf("%3d %6.2f\n", fahr, (5.0 / 9.0) * (fahr - 32));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ILibTrimString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L116
L59:
  cmpl   $0x0,-0x4(%rbp)
  jne    L62
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x8,%al
  je     L62
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L62
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L62
  cmpl   $0x0,-0x4(%rbp)
  jne    L98
L62:
  cmpl   $0x0,-0x8(%rbp)
  jne    L26
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x8,%al
  je     L26
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L26
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L26
  cmpl   $0x0,-0x4(%rbp)
  jne    L89
L26:
  addl   $0x1,-0xc(%rbp)
L116:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L59
  jmp    L77
L98:
  nop
  jmp    L77
L89:
  nop
L77:
  mov    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ILibTrimString(char **theString, int length) {
  int i;
  int flag1 = 0, flag2 = 0;
  for (i = 0; i < length; ++i) {
    if (!flag2 && (*theString)[length - i - 1] != 8 && (*theString)[length - i - 1] != 32) {
      length -= i;
      flag2 = 1;
      if (flag1 && flag2) {
        break;
      }
    }
    if (!flag1 && (*theString)[i] != 8 && (*theString)[i] != 32) {
      *theString = *theString + i;
      length -= i;
      flag1 = 1;
      if (flag1 && flag2) {
        break;
      }
    }
  }
  return (length);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ILibTrimString>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L29
  push   %rbx
  mov    %rdi,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%r8d
  mov    $0x1,%ebx
  jmp    L55
L143:
  test   %r8d,%r8d
  je     L3
L7:
  add    $0x1,%rdx
  cmp    %edx,%eax
  jle    L116
L55:
  mov    %edx,%r9d
  test   %esi,%esi
  jne    L143
  mov    %eax,%r10d
  sub    %edx,%r10d
  movslq %r10d,%rdi
  mov    (%rcx),%r11
  movzbl -0x1(%r11,%rdi,1),%edi
  cmp    $0x20,%dil
  je     L143
  cmp    $0x8,%dil
  je     L143
  test   %r8d,%r8d
  jne    L152
  mov    %rdx,%rsi
  add    (%rcx),%rsi
  movzbl (%rsi),%eax
  cmp    $0x20,%al
  je     L142
  cmp    $0x8,%al
  jne    L67
L142:
  mov    %r10d,%eax
  mov    %ebx,%esi
  jmp    L7
L3:
  mov    %rdx,%r10
  add    (%rcx),%r10
  movzbl (%r10),%edi
  cmp    $0x20,%dil
  je     L7
  cmp    $0x8,%dil
  je     L7
  mov    %r10,(%rcx)
  sub    %r9d,%eax
  test   %esi,%esi
  jne    L116
  mov    %ebx,%r8d
  jmp    L7
L152:
  mov    %r10d,%eax
  jmp    L116
L67:
  mov    %rsi,(%rcx)
  mov    %r10d,%eax
  sub    %r9d,%eax
L116:
  pop    %rbx
  ret
L29:
  ret
```

assistant: ```c
int ILibTrimString(char **theString, int length) {
  int i;
  int flag1 = 0, flag2 = 0;
  for (i = 0; i < length; ++i) {
    if (!flag2 && (*theString)[length - i - 1] != 8 && (*theString)[length - i - 1] != 32) {
      length -= i;
      flag2 = 1;
      if (flag1 && flag2) {
        break;
      }
    }
    if (!flag1 && (*theString)[i] != 8 && (*theString)[i] != 32) {
      *theString = *theString + i;
      length -= i;
      flag1 = 1;
      if (flag1 && flag2) {
        break;
      }
    }
  }
  return (length);
}
```