ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x6a,%eax
  xor    $0xb,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  lea    0x52(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] |= (state[0UL] & (unsigned char)63) << 4UL;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)));
      }
      if (state[0UL] <= local1) {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      } else {
        state[local1] |= (state[local1] & (unsigned char)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (unsigned char)82;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x6a,%eax
  xor    $0xb,%eax
  add    $0x52,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] |= (state[0UL] & (unsigned char)63) << 4UL;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)));
      }
      if (state[0UL] <= local1) {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      } else {
        state[local1] |= (state[local1] & (unsigned char)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (unsigned char)82;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x6a,%eax
  xor    $0xb,%eax
  add    $0x52,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] |= (state[0UL] & (unsigned char)63) << 4UL;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)));
      }
      if (state[0UL] <= local1) {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      } else {
        state[local1] |= (state[local1] & (unsigned char)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (unsigned char)82;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x6a,%eax
  xor    $0xb,%eax
  add    $0x52,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[local1] |= (state[0UL] & (unsigned char)63) << 4UL;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)));
      }
      if (state[0UL] <= local1) {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      } else {
        state[local1] |= (state[local1] & (unsigned char)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (unsigned char)82;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rc_url_post_playing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %rcx,-0xc0(%rbp)
  mov    %r8d,-0xc4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb8(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  je     L4
  mov    $0xffffffff,%eax
  jmp    L30
L4:
  mov    -0xc0(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  je     L29
  mov    $0xffffffff,%eax
  jmp    L30
L29:
  mov    -0xc4(%rbp),%edi
  lea    -0x50(%rbp),%rcx
  lea    -0x90(%rbp),%rdx
  mov    -0xb0(%rbp),%rsi
  mov    -0xa8(%rbp),%rax
  mov    %edi,%r9d
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D3(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %eax,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  cltq
  cmp    %rax,-0xb0(%rbp)
  ja     L34
  mov    $0xffffffff,%eax
  jmp    L30
L34:
  mov    $0x0,%eax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: http://retroachievements.org/dorequest.php?r=postactivity&u=%s&t=%s&a=3&m=%u

assistant: ```c
int rc_url_post_playing(char *buffer, size_t size, const char *user_name, const char *login_token, unsigned gameid) {
  char urle_user_name[64];
  char urle_login_token[64];
  int written;
  if (rc_url_encode(urle_user_name, sizeof(urle_user_name), user_name) != 0) {
    return -1;
  }
  if (rc_url_encode(urle_login_token, sizeof(urle_login_token), login_token) != 0) {
    return -1;
  }
  written = snprintf(buffer, size, "http://retroachievements.org/dorequest.php?r=postactivity&u=%s&t=%s&a=3&m=%u", urle_user_name, urle_login_token, gameid);
  return (size_t)written >= size ? -1 : 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rc_url_post_playing>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rcx,%rbp
  mov    %r8d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x40,%esi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L9
  lea    0x40(%rsp),%rdi
  mov    %rbp,%rdx
  mov    $0x40,%esi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L4
  mov    %rsp,%rcx
  mov    %r13d,%r9d
  lea    0x40(%rsp),%r8
  lea    D1(%rip),%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <snprintf@plt>
  cltq
  cmp    %rbx,%rax
  setae  %al
  movzbl %al,%eax
  neg    %eax
L45:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L45
L4:
  mov    $0xffffffff,%eax
  jmp    L45
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: http://retroachievements.org/dorequest.php?r=postactivity&u=%s&t=%s&a=3&m=%u

assistant: ```c
int rc_url_post_playing(char *buffer, size_t size, const char *user_name, const char *login_token, unsigned gameid) {
  char urle_user_name[64];
  char urle_login_token[64];
  int written;
  if (rc_url_encode(urle_user_name, sizeof(urle_user_name), user_name) != 0) {
    return -1;
  }
  if (rc_url_encode(urle_login_token, sizeof(urle_login_token), login_token) != 0) {
    return -1;
  }
  written = snprintf(buffer, size, "http://retroachievements.org/dorequest.php?r=postactivity&u=%s&t=%s&a=3&m=%u", urle_user_name, urle_login_token, gameid);
  return (size_t)written >= size ? -1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rc_url_post_playing>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x40,%esi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L26
  lea    0x40(%rsp),%r15
  mov    %r12,%rdx
  mov    $0x40,%esi
  mov    %r15,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L26
  mov    %r13d,%r9d
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdx
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cltq
  cmp    %rbx,%rax
  setae  %al
  movzbl %al,%eax
  neg    %eax
L2:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  mov    $0xffffffff,%eax
  jmp    L2
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string

tool: D8: http://retroachievements.org/dorequest.php?r=postactivity&u=%s&t=%s&a=3&m=%u

assistant: ```c
int rc_url_post_playing(char *buffer, size_t size, const char *user_name, const char *login_token, unsigned gameid) {
  char urle_user_name[64];
  char urle_login_token[64];
  int written;
  if (rc_url_encode(urle_user_name, sizeof(urle_user_name), user_name) != 0) {
    return -1;
  }
  if (rc_url_encode(urle_login_token, sizeof(urle_login_token), login_token) != 0) {
    return -1;
  }
  written = snprintf(buffer, size, "http://retroachievements.org/dorequest.php?r=postactivity&u=%s&t=%s&a=3&m=%u", urle_user_name, urle_login_token, gameid);
  return (size_t)written >= size ? -1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rc_url_post_playing>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x40,%esi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L0
  lea    0x40(%rsp),%r15
  mov    %r12,%rdx
  mov    $0x40,%esi
  mov    %r15,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L0
  mov    %r13d,%r9d
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rbx,%rsi
  lea    D5(%rip),%rdx
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cltq
  cmp    %rbx,%rax
  setae  %al
  movzbl %al,%eax
  neg    %eax
L7:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L7
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: http://retroachievements.org/dorequest.php?r=postactivity&u=%s&t=%s&a=3&m=%u

assistant: ```c
int rc_url_post_playing(char *buffer, size_t size, const char *user_name, const char *login_token, unsigned gameid) {
  char urle_user_name[64];
  char urle_login_token[64];
  int written;
  if (rc_url_encode(urle_user_name, sizeof(urle_user_name), user_name) != 0) {
    return -1;
  }
  if (rc_url_encode(urle_login_token, sizeof(urle_login_token), login_token) != 0) {
    return -1;
  }
  written = snprintf(buffer, size, "http://retroachievements.org/dorequest.php?r=postactivity&u=%s&t=%s&a=3&m=%u", urle_user_name, urle_login_token, gameid);
  return (size_t)written >= size ? -1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L9
L16:
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jg     L16
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <http_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: %d

assistant: ```c
char *itoa(int value) {
  char *val_str;
  int tmp = value, len = 1;
  while ((tmp /= 10) > 0)
    len++;
  val_str = (char *)http_malloc(len + 1);
  sprintf(val_str, "%d", value);
  return val_str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  cmp    $0x9,%edi
  jle    L26
  mov    $0x1,%edi
L28:
  add    $0x1,%edi
  mov    %edx,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L28
L10:
  add    $0x1,%edi
  call   <http_malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    $0x1,%edi
  jmp    L10
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %d

assistant: ```c
char *itoa(int value) {
  char *val_str;
  int tmp = value, len = 1;
  while ((tmp /= 10) > 0)
    len++;
  val_str = (char *)http_malloc(len + 1);
  sprintf(val_str, "%d", value);
  return val_str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  movslq %edi,%rax
  push   %r13
  push   %r12
  mov    %rax,%r12
  imul   $0x66666667,%rax,%rax
  mov    %r12d,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    $0x8,%rsp
  sub    %edx,%eax
  cmp    $0x9,%r12d
  jle    L26
  mov    $0x1,%ecx
L22:
  cltq
  mov    %ecx,%edi
  add    $0x1,%ecx
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  cmp    $0x9,%edx
  jg     L22
  add    $0x2,%edi
L6:
  call   <http_malloc@plt>
  mov    %r12d,%edx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0x2,%edi
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %d

assistant: ```c
char *itoa(int value) {
  char *val_str;
  int tmp = value, len = 1;
  while ((tmp /= 10) > 0)
    len++;
  val_str = (char *)http_malloc(len + 1);
  sprintf(val_str, "%d", value);
  return val_str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<itoa>:
  endbr64
  movslq %edi,%rax
  push   %r13
  push   %r12
  mov    %rax,%r12
  imul   $0x66666667,%rax,%rax
  mov    %r12d,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    $0x8,%rsp
  sub    %edx,%eax
  cmp    $0x9,%r12d
  jle    L14
  mov    $0x1,%ecx
L6:
  cltq
  mov    %ecx,%edi
  add    $0x1,%ecx
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  cmp    $0x9,%edx
  jg     L6
  add    $0x2,%edi
L0:
  call   <http_malloc@plt>
  mov    %r12d,%edx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0x2,%edi
  jmp    L0
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: %d

assistant: ```c
char *itoa(int value) {
  char *val_str;
  int tmp = value, len = 1;
  while ((tmp /= 10) > 0)
    len++;
  val_str = (char *)http_malloc(len + 1);
  sprintf(val_str, "%d", value);
  return val_str;
}
```
user: What is the c source code of the assembly code below:

```asm
<CopyBits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r11d
  test   %dil,%dil
  je     L7
  mov    %rsi,%r10
  mov    %edx,%esi
  cmp    $0x1,%cl
  sbb    %r13,%r13
  and    $0x2,%r13d
  sub    $0x1,%r13
  cmp    $0x1,%r11b
  sbb    %r12,%r12
  and    $0x2,%r12d
  sub    $0x1,%r12
  mov    $0x8,%ebp
  mov    $0xff,%r11d
  mov    $0x8,%ebx
  jmp    L46
L12:
  movzbl (%r10),%r14d
  neg    %ecx
  sar    %cl,%r14d
  mov    %ebp,%edx
  sub    %esi,%edx
  jmp    L64
L29:
  sub    %dl,%dil
  je     L7
L46:
  mov    %r9d,%ecx
  sub    %esi,%ecx
  test   %cl,%cl
  jle    L12
  movzbl (%r10),%r14d
  shl    %cl,%r14d
  mov    %ebp,%edx
  sub    %r9d,%edx
L64:
  cmp    %dil,%dl
  cmova  %edi,%edx
  lea    (%rdx,%r9,1),%ecx
  mov    %r11d,%eax
  shl    %cl,%eax
  mov    %ebx,%ecx
  sub    %r9d,%ecx
  mov    %r11d,%r15d
  sar    %cl,%r15d
  or     %r15d,%eax
  mov    %eax,%ecx
  and    (%r8),%cl
  not    %eax
  and    %r14d,%eax
  or     %eax,%ecx
  mov    %cl,(%r8)
  add    %edx,%esi
  cmp    $0x7,%sil
  jbe    L22
  add    %r13,%r10
  mov    $0x0,%esi
L22:
  add    %edx,%r9d
  cmp    $0x7,%r9b
  jbe    L29
  add    %r12,%r8
  mov    $0x0,%r9d
  jmp    L29
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void CopyBits(unsigned char NbBits, unsigned char *SrcByteIndex, unsigned char SrcBitIndex, unsigned char SrcBigEndian, unsigned char *DestByteIndex, unsigned char DestBitIndex, unsigned char DestBigEndian) {
  while (NbBits > 0) {
    signed char Vect = DestBitIndex - SrcBitIndex;
    unsigned char Aligned = Vect > 0 ? *SrcByteIndex << Vect : *SrcByteIndex >> -Vect;
    unsigned char BoudaryLimit = (Vect > 0 ? 8 - DestBitIndex : 8 - SrcBitIndex);
    unsigned char BitsToCopy = BoudaryLimit > NbBits ? NbBits : BoudaryLimit;
    unsigned char Mask = ((0xff << (DestBitIndex + BitsToCopy)) | (0xff >> (8 - DestBitIndex)));
    unsigned char Filtered = Aligned & ~Mask;
    *DestByteIndex &= Mask;
    *DestByteIndex |= Filtered;
    if ((SrcBitIndex += BitsToCopy) > 7) {
      SrcBitIndex = 0;
      SrcByteIndex += (SrcBigEndian ? -1 : 1);
    }
    if ((DestBitIndex += BitsToCopy) > 7) {
      DestBitIndex = 0;
      DestByteIndex += (DestBigEndian ? -1 : 1);
    }
    NbBits -= BitsToCopy;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CopyBits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r11d
  test   %dil,%dil
  je     L68
  cmp    $0x1,%cl
  mov    %rsi,%r10
  mov    $0x8,%ebp
  mov    %edx,%esi
  sbb    %r13,%r13
  mov    $0x8,%ebx
  and    $0x2,%r13d
  sub    $0x1,%r13
  cmp    $0x1,%r11b
  mov    $0xff,%r11d
  sbb    %r12,%r12
  and    $0x2,%r12d
  sub    $0x1,%r12
  jmp    L14
L45:
  mov    %ebp,%edx
  shl    %cl,%r14d
  sub    %r9d,%edx
L5:
  cmp    %dil,%dl
  mov    %r11d,%eax
  mov    %r11d,%r15d
  cmova  %edi,%edx
  lea    (%r9,%rdx,1),%ecx
  add    %edx,%esi
  shl    %cl,%eax
  mov    %ebx,%ecx
  sub    %r9d,%ecx
  sar    %cl,%r15d
  movzbl (%r8),%ecx
  or     %r15d,%eax
  and    %eax,%ecx
  not    %eax
  and    %r14d,%eax
  or     %eax,%ecx
  mov    %cl,(%r8)
  cmp    $0x7,%sil
  jbe    L49
  add    %r13,%r10
  xor    %esi,%esi
L49:
  add    %edx,%r9d
  cmp    $0x7,%r9b
  jbe    L30
  add    %r12,%r8
  xor    %r9d,%r9d
L30:
  sub    %dl,%dil
  je     L68
L14:
  mov    %r9d,%ecx
  movzbl (%r10),%r14d
  sub    %esi,%ecx
  movsbl %cl,%eax
  test   %cl,%cl
  jg     L45
  neg    %eax
  mov    %ebp,%edx
  mov    %eax,%ecx
  sub    %esi,%edx
  sar    %cl,%r14d
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L68:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void CopyBits(unsigned char NbBits, unsigned char *SrcByteIndex, unsigned char SrcBitIndex, unsigned char SrcBigEndian, unsigned char *DestByteIndex, unsigned char DestBitIndex, unsigned char DestBigEndian) {
  while (NbBits > 0) {
    signed char Vect = DestBitIndex - SrcBitIndex;
    unsigned char Aligned = Vect > 0 ? *SrcByteIndex << Vect : *SrcByteIndex >> -Vect;
    unsigned char BoudaryLimit = (Vect > 0 ? 8 - DestBitIndex : 8 - SrcBitIndex);
    unsigned char BitsToCopy = BoudaryLimit > NbBits ? NbBits : BoudaryLimit;
    unsigned char Mask = ((0xff << (DestBitIndex + BitsToCopy)) | (0xff >> (8 - DestBitIndex)));
    unsigned char Filtered = Aligned & ~Mask;
    *DestByteIndex &= Mask;
    *DestByteIndex |= Filtered;
    if ((SrcBitIndex += BitsToCopy) > 7) {
      SrcBitIndex = 0;
      SrcByteIndex += (SrcBigEndian ? -1 : 1);
    }
    if ((DestBitIndex += BitsToCopy) > 7) {
      DestBitIndex = 0;
      DestByteIndex += (DestBigEndian ? -1 : 1);
    }
    NbBits -= BitsToCopy;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CopyBits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r11d
  test   %dil,%dil
  je     L45
  cmp    $0x1,%cl
  mov    %rsi,%r10
  mov    $0x8,%ebp
  mov    %edx,%esi
  sbb    %r13,%r13
  mov    $0x8,%ebx
  and    $0x2,%r13d
  sub    $0x1,%r13
  cmp    $0x1,%r11b
  mov    $0xff,%r11d
  sbb    %r12,%r12
  and    $0x2,%r12d
  sub    $0x1,%r12
  jmp    L26
L65:
  mov    %ebp,%edx
  shl    %cl,%r14d
  sub    %r9d,%edx
L2:
  cmp    %dil,%dl
  movzbl %r9b,%r15d
  mov    %ebx,%ecx
  mov    %r11d,%eax
  cmova  %edi,%edx
  sub    %r15d,%ecx
  sar    %cl,%eax
  lea    (%rdx,%r15,1),%ecx
  mov    %r11d,%r15d
  add    %edx,%esi
  shl    %cl,%r15d
  movzbl (%r8),%ecx
  or     %r15d,%eax
  and    %eax,%ecx
  not    %eax
  and    %r14d,%eax
  or     %eax,%ecx
  mov    %cl,(%r8)
  cmp    $0x7,%sil
  jbe    L59
  add    %r13,%r10
  xor    %esi,%esi
L59:
  add    %edx,%r9d
  cmp    $0x7,%r9b
  jbe    L40
  add    %r12,%r8
  xor    %r9d,%r9d
L40:
  sub    %dl,%dil
  je     L45
L26:
  mov    %r9d,%ecx
  movzbl (%r10),%r14d
  sub    %esi,%ecx
  movsbl %cl,%eax
  test   %cl,%cl
  jg     L65
  neg    %eax
  mov    %ebp,%edx
  mov    %eax,%ecx
  sub    %esi,%edx
  sar    %cl,%r14d
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void CopyBits(unsigned char NbBits, unsigned char *SrcByteIndex, unsigned char SrcBitIndex, unsigned char SrcBigEndian, unsigned char *DestByteIndex, unsigned char DestBitIndex, unsigned char DestBigEndian) {
  while (NbBits > 0) {
    signed char Vect = DestBitIndex - SrcBitIndex;
    unsigned char Aligned = Vect > 0 ? *SrcByteIndex << Vect : *SrcByteIndex >> -Vect;
    unsigned char BoudaryLimit = (Vect > 0 ? 8 - DestBitIndex : 8 - SrcBitIndex);
    unsigned char BitsToCopy = BoudaryLimit > NbBits ? NbBits : BoudaryLimit;
    unsigned char Mask = ((0xff << (DestBitIndex + BitsToCopy)) | (0xff >> (8 - DestBitIndex)));
    unsigned char Filtered = Aligned & ~Mask;
    *DestByteIndex &= Mask;
    *DestByteIndex |= Filtered;
    if ((SrcBitIndex += BitsToCopy) > 7) {
      SrcBitIndex = 0;
      SrcByteIndex += (SrcBigEndian ? -1 : 1);
    }
    if ((DestBitIndex += BitsToCopy) > 7) {
      DestBitIndex = 0;
      DestByteIndex += (DestBigEndian ? -1 : 1);
    }
    NbBits -= BitsToCopy;
  }
}
```