ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <dpdk_linux_tcpip_init@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L18
L17:
  mov    $0x59,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <app_init@plt>
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string
name: extract_symbolic_data
arguments: tag: D10
datatype: string

tool: D8: Invalid arguments


tool: D10: 192.168.1.1

assistant: ```c
int main(int argc, char **argv) {
  int ret = dpdk_linux_tcpip_init(argc, argv);
  if (ret < 0) {
    printf("Invalid arguments\n");
    return 1;
  }
  app_init("192.168.1.1", 89);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <dpdk_linux_tcpip_init@plt>
  test   %eax,%eax
  js     L2
  mov    $0x59,%esi
  lea    D13(%rip),%rdi
  call   <app_init@plt>
  mov    $0x0,%eax
L17:
  add    $0x8,%rsp
  ret
L2:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D14
type_infered: string

tool: D13: 192.168.1.1

tool: D14: Invalid arguments


assistant: ```c
int main(int argc, char **argv) {
  int ret = dpdk_linux_tcpip_init(argc, argv);
  if (ret < 0) {
    printf("Invalid arguments\n");
    return 1;
  }
  app_init("192.168.1.1", 89);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <dpdk_linux_tcpip_init@plt>
  test   %eax,%eax
  js     L5
  mov    $0x59,%esi
  lea    D19(%rip),%rdi
  call   <app_init@plt>
  xor    %eax,%eax
L7:
  add    $0x8,%rsp
  ret
L5:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string

tool: D19: 192.168.1.1

tool: D16: Invalid arguments


assistant: ```c
int main(int argc, char **argv) {
  int ret = dpdk_linux_tcpip_init(argc, argv);
  if (ret < 0) {
    printf("Invalid arguments\n");
    return 1;
  }
  app_init("192.168.1.1", 89);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <dpdk_linux_tcpip_init@plt>
  test   %eax,%eax
  js     L19
  mov    $0x59,%esi
  lea    D15(%rip),%rdi
  call   <app_init@plt>
  xor    %eax,%eax
L5:
  add    $0x8,%rsp
  ret
L19:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L5
```

tool_calls: name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D4
datatype: string

tool: D15: 192.168.1.1

tool: D4: Invalid arguments


assistant: ```c
int main(int argc, char **argv) {
  int ret = dpdk_linux_tcpip_init(argc, argv);
  if (ret < 0) {
    printf("Invalid arguments\n");
    return 1;
  }
  app_init("192.168.1.1", 89);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x3,-0x10(%rbp)
  jmp    L6
L14:
  mov    $0x42,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L14
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D11
datatype: string

tool: D11: %d

assistant: ```c
int main(void) {
  int input;
  int result;
  scanf("%d", &input);
  for (int i = 3; i <= input; i++) {
    printf("B");
  }
  printf("%d", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x2,0x4(%rsp)
  jle    L28
  mov    $0x3,%ebx
L12:
  mov    $0x42,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L12
L28:
  mov    $0x0,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string

tool: D4: %d

assistant: ```c
int main(void) {
  int input;
  int result;
  scanf("%d", &input);
  for (int i = 3; i <= input; i++) {
    printf("B");
  }
  printf("%d", result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x2,0x4(%rsp)
  jle    L26
  mov    $0x3,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0x42,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L18
L26:
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d

assistant: ```c
int main(void) {
  int input;
  int result;
  scanf("%d", &input);
  for (int i = 3; i <= input; i++) {
    printf("B");
  }
  printf("%d", result);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x2,0x4(%rsp)
  jle    L17
  mov    $0x3,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x42,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L12
L17:
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: %d

assistant: ```c
int main(void) {
  int input;
  int result;
  scanf("%d", &input);
  for (int i = 3; i <= input; i++) {
    printf("B");
  }
  printf("%d", result);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<revstrcasestr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L32
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    %rax,-0x28(%rbp)
  jmp    L32
L45:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L30
  mov    -0x28(%rbp),%rax
  jmp    L6
L30:
  subq   $0x1,-0x28(%rbp)
L32:
  mov    -0x28(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L45
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
char *revstrcasestr(const char *haystack, const char *needle, const char *pointer) {
  size_t needle_len = strlen(needle);
  size_t tail_len = strlen(pointer);
  if (tail_len < needle_len)
    pointer += tail_len - needle_len;
  while (pointer >= haystack) {
    if (strncasecmp(pointer, needle, needle_len) == 0)
      return (char *)pointer;
    pointer--;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<revstrcasestr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    %rbx,%rdx
  cmp    %rax,%rbp
  cmova  %rdx,%rbx
  cmp    %rbx,%r13
  ja     L33
L7:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  je     L9
  sub    $0x1,%rbx
  cmp    %rbx,%r13
  jbe    L7
  mov    $0x0,%eax
  jmp    L47
L33:
  mov    $0x0,%eax
  jmp    L47
L9:
  mov    %rbx,%rax
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *revstrcasestr(const char *haystack, const char *needle, const char *pointer) {
  size_t needle_len = strlen(needle);
  size_t tail_len = strlen(pointer);
  if (tail_len < needle_len)
    pointer += tail_len - needle_len;
  while (pointer >= haystack) {
    if (strncasecmp(pointer, needle, needle_len) == 0)
      return (char *)pointer;
    pointer--;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<revstrcasestr>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    %rbx,%rdx
  cmp    %rax,%rbp
  cmova  %rdx,%rbx
  cmp    %rbx,%r13
  jbe    L32
  jmp    L13
  nopl   0x0(%rax)
L19:
  sub    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L13
L32:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L19
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *revstrcasestr(const char *haystack, const char *needle, const char *pointer) {
  size_t needle_len = strlen(needle);
  size_t tail_len = strlen(pointer);
  if (tail_len < needle_len)
    pointer += tail_len - needle_len;
  while (pointer >= haystack) {
    if (strncasecmp(pointer, needle, needle_len) == 0)
      return (char *)pointer;
    pointer--;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<revstrcasestr>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    %rbx,%rdx
  cmp    %rax,%rbp
  cmova  %rdx,%rbx
  cmp    %rbx,%r13
  jbe    L38
  jmp    L26
  nopl   0x0(%rax)
L5:
  sub    $0x1,%rbx
  cmp    %rbx,%r13
  ja     L26
L38:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L5
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *revstrcasestr(const char *haystack, const char *needle, const char *pointer) {
  size_t needle_len = strlen(needle);
  size_t tail_len = strlen(pointer);
  if (tail_len < needle_len)
    pointer += tail_len - needle_len;
  while (pointer >= haystack) {
    if (strncasecmp(pointer, needle, needle_len) == 0)
      return (char *)pointer;
    pointer--;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xc,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movl   $0x0,-0x80(%rbp)
L12:
  lea    -0x94(%rbp),%rdx
  lea    -0x98(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x98(%rbp),%edx
  mov    -0x94(%rbp),%eax
  cmp    %eax,%edx
  je     L14
  mov    -0x98(%rbp),%eax
  mov    -0x94(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movl   $0x1,-0x70(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  mov    -0x98(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movl   $0x1,-0x70(%rbp,%rax,4)
  jmp    L12
L14:
  nop
  lea    -0x90(%rbp),%rcx
  lea    -0x70(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BFS@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: %d%d

assistant: ```c
int main() {
  int matrix[5][5] = {0};
  int i, j, s[5] = {0};
  while (1) {
    scanf("%d%d", &i, &j);
    if (i == j)
      break;
    matrix[i][j] = 1;
    matrix[j][i] = 1;
  }
  BFS(matrix, s, 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rdi
  mov    $0xc,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movl   $0x0,0x20(%rsp)
  lea    D0(%rip),%rbx
  jmp    L23
L21:
  movslq %edx,%rdx
  cltq
  lea    (%rax,%rax,4),%rcx
  add    %rdx,%rcx
  movl   $0x1,0x30(%rsp,%rcx,4)
  lea    (%rdx,%rdx,4),%rdx
  add    %rdx,%rax
  movl   $0x1,0x30(%rsp,%rax,4)
L23:
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  jne    L21
  lea    0x10(%rsp),%rsi
  lea    0x30(%rsp),%rdi
  mov    $0x0,%edx
  call   <BFS@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0xa0,%rsp
  pop    %rbx
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: %d%d

assistant: ```c
int main() {
  int matrix[5][5] = {0};
  int i, j, s[5] = {0};
  while (1) {
    scanf("%d%d", &i, &j);
    if (i == j)
      break;
    matrix[i][j] = 1;
    matrix[j][i] = 1;
  }
  BFS(matrix, s, 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xc,%ecx
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r13
  movl   $0x0,0x20(%rsp)
  lea    0xc(%rsp),%r12
  mov    %r13,%rdi
  movaps %xmm0,0x10(%rsp)
  lea    0x8(%rsp),%rbp
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  jmp    L11
  xchg   %ax,%ax
L27:
  lea    (%rax,%rax,4),%rcx
  add    %rdx,%rcx
  lea    (%rdx,%rdx,4),%rdx
  add    %rdx,%rax
  movl   $0x1,0x30(%rsp,%rcx,4)
  movl   $0x1,0x30(%rsp,%rax,4)
L11:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  cmp    %edx,%eax
  jne    L27
  xor    %edx,%edx
  lea    0x10(%rsp),%rsi
  mov    %r13,%rdi
  call   <BFS@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: %d%d

assistant: ```c
int main() {
  int matrix[5][5] = {0};
  int i, j, s[5] = {0};
  while (1) {
    scanf("%d%d", &i, &j);
    if (i == j)
      break;
    matrix[i][j] = 1;
    matrix[j][i] = 1;
  }
  BFS(matrix, s, 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xc,%ecx
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r13
  movl   $0x0,0x20(%rsp)
  lea    0xc(%rsp),%r12
  mov    %r13,%rdi
  movaps %xmm0,0x10(%rsp)
  lea    0x8(%rsp),%rbp
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  jmp    L2
  xchg   %ax,%ax
L18:
  lea    (%rax,%rax,4),%rcx
  add    %rdx,%rcx
  lea    (%rdx,%rdx,4),%rdx
  add    %rdx,%rax
  movl   $0x1,0x30(%rsp,%rcx,4)
  movl   $0x1,0x30(%rsp,%rax,4)
L2:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  cmp    %edx,%eax
  jne    L18
  xor    %edx,%edx
  lea    0x10(%rsp),%rsi
  mov    %r13,%rdi
  call   <BFS@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: %d%d

assistant: ```c
int main() {
  int matrix[5][5] = {0};
  int i, j, s[5] = {0};
  while (1) {
    scanf("%d%d", &i, &j);
    if (i == j)
      break;
    matrix[i][j] = 1;
    matrix[j][i] = 1;
  }
  BFS(matrix, s, 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<change_rtc_minute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L23
  cmpl   $0x3b,-0x14(%rbp)
  jle    L20
L23:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
  jmp    L13
L20:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x7e005040,%eax
  mov    (%rax),%eax
  mov    $0x7e005040,%edx
  or     $0x8,%eax
  mov    %eax,(%rdx)
  mov    $0x7e005040,%eax
  movl   $0x1,(%rax)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  or     -0x8(%rbp),%eax
  mov    $0x7e005074,%edx
  mov    %eax,(%rdx)
  mov    $0x7e005040,%eax
  movl   $0x0,(%rax)
  nop
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: 
Error: Minute must between 0 to 59!

assistant: ```c
void change_rtc_minute(int value) {
  if (!(value >= 0 && value <= 59)) {
    uart_puts("\nError: Minute must between 0 to 59!");
    return;
  }
  int low = value % 10;
  int high = value / 10;
  (*(volatile unsigned int *)(0x7E005040)) |= (1 << 3);
  (*(volatile unsigned int *)(0x7E005040)) = 1;
  (*(volatile unsigned int *)(0x7E005074)) = (high << 4) | low;
  (*(volatile unsigned int *)(0x7E005040)) = 0;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<change_rtc_minute>:
  endbr64
  cmp    $0x3b,%edi
  ja     L2
  mov    0x7e005040,%eax
  or     $0x8,%eax
  mov    %eax,0x7e005040
  movl   $0x1,0x7e005040
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  mov    %edx,%eax
  or     %edi,%eax
  mov    %eax,0x7e005074
  movl   $0x0,0x7e005040
  ret
L2:
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <uart_puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: 
Error: Minute must between 0 to 59!

assistant: ```c
void change_rtc_minute(int value) {
  if (!(value >= 0 && value <= 59)) {
    uart_puts("\nError: Minute must between 0 to 59!");
    return;
  }
  int low = value % 10;
  int high = value / 10;
  (*(volatile unsigned int *)(0x7E005040)) |= (1 << 3);
  (*(volatile unsigned int *)(0x7E005040)) = 1;
  (*(volatile unsigned int *)(0x7E005074)) = (high << 4) | low;
  (*(volatile unsigned int *)(0x7E005040)) = 0;
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<change_rtc_minute>:
  endbr64
  cmp    $0x3b,%edi
  ja     L4
  mov    0x7e005040,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  or     $0x8,%eax
  mov    %eax,0x7e005040
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  movl   $0x1,0x7e005040
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  shl    $0x4,%edx
  sub    %eax,%edi
  mov    %edx,%eax
  or     %edi,%eax
  mov    %eax,0x7e005074
  movl   $0x0,0x7e005040
  ret
  nopl   (%rax)
L4:
  lea    D7(%rip),%rdi
  jmp    1050 <uart_puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D7: 
Error: Minute must between 0 to 59!

assistant: ```c
void change_rtc_minute(int value) {
  if (!(value >= 0 && value <= 59)) {
    uart_puts("\nError: Minute must between 0 to 59!");
    return;
  }
  int low = value % 10;
  int high = value / 10;
  (*(volatile unsigned int *)(0x7E005040)) |= (1 << 3);
  (*(volatile unsigned int *)(0x7E005040)) = 1;
  (*(volatile unsigned int *)(0x7E005074)) = (high << 4) | low;
  (*(volatile unsigned int *)(0x7E005040)) = 0;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<change_rtc_minute>:
  endbr64
  cmp    $0x3b,%edi
  ja     L5
  mov    0x7e005040,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  or     $0x8,%eax
  mov    %eax,0x7e005040
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  movl   $0x1,0x7e005040
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  shl    $0x4,%edx
  sub    %eax,%edi
  mov    %edx,%eax
  or     %edi,%eax
  mov    %eax,0x7e005074
  movl   $0x0,0x7e005040
  ret
  nopl   (%rax)
L5:
  lea    D6(%rip),%rdi
  jmp    1050 <uart_puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: 
Error: Minute must between 0 to 59!

assistant: ```c
void change_rtc_minute(int value) {
  if (!(value >= 0 && value <= 59)) {
    uart_puts("\nError: Minute must between 0 to 59!");
    return;
  }
  int low = value % 10;
  int high = value / 10;
  (*(volatile unsigned int *)(0x7E005040)) |= (1 << 3);
  (*(volatile unsigned int *)(0x7E005040)) = 1;
  (*(volatile unsigned int *)(0x7E005074)) = (high << 4) | low;
  (*(volatile unsigned int *)(0x7E005040)) = 0;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L15
L6:
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t n = 0;
  while (*s++)
    n++;
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L6
  mov    $0x0,%eax
L12:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L12
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t n = 0;
  while (*s++)
    n++;
  return n;
}
```