user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x40(%rbp),%rsi
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  lea    D17(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%ecx
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  test   %ecx,%ecx
  je     L39
  nopl   0x0(%rax)
L123:
  mov    -0x50(%rbp),%rsi
  mov    %r12,%rdi
  mov    %rsp,-0x48(%rbp)
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  sub    %rsi,%rcx
  cmp    %rcx,%rsp
  je     L136
L138:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L138
L136:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L98
  orq    $0x0,-0x8(%rsp,%rax,1)
L98:
  mov    %rsp,%rbx
  test   %edx,%edx
  je     L168
  mov    %rbx,%r14
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L25:
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%r15d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    -0x3c(%rbp),%r8d
  cmp    %r15d,%r8d
  ja     L25
  test   %r8d,%r8d
  je     L168
  mov    %r8d,%eax
  xor    %r9d,%r9d
  xor    %esi,%esi
  lea    (%rbx,%rax,4),%rdi
  nopl   0x0(%rax)
L50:
  mov    %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L164:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jbe    L63
  mov    %ecx,(%rax)
  add    $0x1,%esi
  mov    %edx,0x4(%rax)
L63:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L164
  add    $0x1,%r9d
  cmp    %r8d,%r9d
  jne    L50
L60:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <printf@plt>
  mov    -0x3c(%rbp),%edx
  test   %edx,%edx
  jne    L53
  jmp    L15
  nopl   (%rax)
L107:
  add    $0x1,%r15
  cmp    %r15d,%eax
  jbe    L15
L53:
  mov    (%rbx,%r15,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%eax
  lea    -0x1(%rax),%ecx
  cmp    %r15d,%ecx
  ja     L107
  mov    $0xa,%edi
  add    $0x1,%r15
  call   <putchar@plt>
  mov    -0x3c(%rbp),%eax
  cmp    %r15d,%eax
  ja     L53
L15:
  subl   $0x1,-0x40(%rbp)
  mov    -0x40(%rbp),%eax
  mov    -0x48(%rbp),%rsp
  test   %eax,%eax
  jne    L123
L39:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L168:
  xor    %esi,%esi
  jmp    L60
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D1: %d 

tool: D17: %u

tool: D6: %d


assistant: ```c
int main() {
  int i;
  unsigned int n, m;
  scanf("%u", &n);
  while (n) {
    scanf("%u", &m);
    unsigned int v[m];
    for (i = 0; i < m; i++) {
      scanf("%u", &v[i]);
    }
    int veses = 0, i, j, aux;
    for (j = 0; j < m; j++) {
      for (i = 0; i < m; i++) {
        if (v[i] > v[i + 1]) {
          aux = v[i];
          v[i] = v[i + 1];
          v[i + 1] = aux;
          veses++;
        }
      }
    }
    printf("%d\n", veses);
    for (i = 0; i < m; i++) {
      printf("%d ", v[i]);
      if (i >= m - 1) {
        printf("\n");
      }
    }
    n--;
    veses = 0;
  }
  return 0;
}
```