ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<pb__get_type>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L33
L16:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  lea    D56(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  je     L16
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x3,%eax
  test   %r8,%r8
  je     L16
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x4,%eax
  test   %r8,%r8
  je     L16
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x5,%eax
  test   %r8,%r8
  je     L16
  mov    %rbp,%rdi
  lea    D50(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x6,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D21
type_infered: string
name: read_data
arguments: data_tag: D56
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D23
type_infered: string
name: read_data
arguments: data_tag: D50
type_infered: string

tool: D21: uInt32

tool: D56: int32

tool: D15: sInt32

tool: D24: float

tool: D23: double

tool: D50: string

assistant: ```c
int pb__get_type(const char *type) {
  if (strcmp(type, "uInt32") == 0)
    return 1;
  if (strcmp(type, "int32") == 0)
    return 2;
  if (strcmp(type, "sInt32") == 0)
    return 3;
  if (strcmp(type, "float") == 0)
    return 4;
  if (strcmp(type, "double") == 0)
    return 5;
  if (strcmp(type, "string") == 0)
    return 6;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pb__get_type>:
  endbr64
  push   %rbp
  lea    D40(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L49
L35:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  lea    D54(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  je     L35
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x3,%eax
  test   %r8,%r8
  je     L35
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x4,%eax
  test   %r8,%r8
  je     L35
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x5,%eax
  test   %r8,%r8
  je     L35
  mov    %rbp,%rdi
  lea    D16(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x6,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D40
type_infered: string
name: parse_data
arguments: tag: D54
type_infered: string
name: parse_data
arguments: tag: D30
type_infered: string
name: parse_data
arguments: tag: D20
type_infered: string
name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D16
type_infered: string

tool: D40: uInt32

tool: D54: int32

tool: D30: sInt32

tool: D20: float

tool: D4: double

tool: D16: string

assistant: ```c
int pb__get_type(const char *type) {
  if (strcmp(type, "uInt32") == 0)
    return 1;
  if (strcmp(type, "int32") == 0)
    return 2;
  if (strcmp(type, "sInt32") == 0)
    return 3;
  if (strcmp(type, "float") == 0)
    return 4;
  if (strcmp(type, "double") == 0)
    return 5;
  if (strcmp(type, "string") == 0)
    return 6;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movabs $0x100000208,%rdx
  movsbq -0x4(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void output_char(char c) {
  *(long *)(0x100000208) = c;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<output_char>:
  endbr64
  movsbq %dil,%rax
  movabs %rax,0x100000208
  ret
```

assistant: ```c
void output_char(char c) {
  *(long *)(0x100000208) = c;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<output_char>:
  endbr64
  movsbq %dil,%rax
  movabs %rax,0x100000208
  ret
```

assistant: ```c
void output_char(char c) {
  *(long *)(0x100000208) = c;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<output_char>:
  endbr64
  movsbq %dil,%rax
  movabs %rax,0x100000208
  ret
```

assistant: ```c
void output_char(char c) {
  *(long *)(0x100000208) = c;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_symbolic_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_clause@plt>
  jmp    L0
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_clause@plt>
L0:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L3
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int _symbolic_mode(char const **mode) {
  _clause(mode);
  while (**mode == ',') {
    (*mode)++;
    _clause(mode);
  }
  return **mode == '\0' ? 0 : 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_symbolic_mode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <_clause@plt>
  mov    (%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x2c,%dl
  jne    L16
L7:
  add    $0x1,%rax
  mov    %rax,(%rbx)
  mov    %rbx,%rdi
  call   <_clause@plt>
  mov    (%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x2c,%dl
  je     L7
L16:
  test   %dl,%dl
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int _symbolic_mode(char const **mode) {
  _clause(mode);
  while (**mode == ',') {
    (*mode)++;
    _clause(mode);
  }
  return **mode == '\0' ? 0 : 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_symbolic_mode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  mov    %rbx,%rdi
  mov    %rax,(%rbx)
L16:
  call   <_clause@plt>
  mov    (%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x2c,%dl
  je     L1
  xor    %eax,%eax
  test   %dl,%dl
  pop    %rbx
  setne  %al
  ret
```

assistant: ```c
int _symbolic_mode(char const **mode) {
  _clause(mode);
  while (**mode == ',') {
    (*mode)++;
    _clause(mode);
  }
  return **mode == '\0' ? 0 : 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_symbolic_mode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rax
  mov    %rbx,%rdi
  mov    %rax,(%rbx)
L15:
  call   <_clause@plt>
  mov    (%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x2c,%dl
  je     L14
  xor    %eax,%eax
  test   %dl,%dl
  pop    %rbx
  setne  %al
  ret
```

assistant: ```c
int _symbolic_mode(char const **mode) {
  _clause(mode);
  while (**mode == ',') {
    (*mode)++;
    _clause(mode);
  }
  return **mode == '\0' ? 0 : 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<little32VersNatif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <systemeBigEndian@plt>
  test   %rax,%rax
  je     L6
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <barriereNatif32@plt>
  jmp    L12
L6:
  mov    -0x4(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int little32VersNatif(int little) {
  if (systemeBigEndian()) {
    return barriereNatif32(little);
  } else {
    return little;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<little32VersNatif>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <systemeBigEndian@plt>
  test   %rax,%rax
  jne    L0
L5:
  mov    %ebx,%eax
  pop    %rbx
  ret
L0:
  mov    %ebx,%edi
  call   <barriereNatif32@plt>
  mov    %eax,%ebx
  jmp    L5
```

assistant: ```c
int little32VersNatif(int little) {
  if (systemeBigEndian()) {
    return barriereNatif32(little);
  } else {
    return little;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<little32VersNatif>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <systemeBigEndian@plt>
  test   %rax,%rax
  jne    L9
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12d,%edi
  pop    %r12
  jmp    1070 <barriereNatif32@plt>
```

assistant: ```c
int little32VersNatif(int little) {
  if (systemeBigEndian()) {
    return barriereNatif32(little);
  } else {
    return little;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<little32VersNatif>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <systemeBigEndian@plt>
  test   %rax,%rax
  jne    L7
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r12d,%edi
  pop    %r12
  jmp    1070 <barriereNatif32@plt>
```

assistant: ```c
int little32VersNatif(int little) {
  if (systemeBigEndian()) {
    return barriereNatif32(little);
  } else {
    return little;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  D30(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd -0x8(%rbp),%xmm1
  movsd  D36(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D36(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D30
data_type: f32
name: parse_data
arguments: label: D35
data_type: string
name: parse_data
arguments: label: D36
data_type: f64
name: parse_data
arguments: label: D48
data_type: string

tool: D30: 14.2

tool: D35: The turkey weighs %f.


tool: D36: 15

tool: D48: Cook it for %f minutes.


assistant: ```c
int main(int argc, const char *argv[]) {
  float weight;
  weight = 14.2;
  printf("The turkey weighs %f.\n", weight);
  float cookingTime;
  cookingTime = 15.0 + 15.0 * weight;
  printf("Cook it for %f minutes.\n", cookingTime);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D38(%rip),%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  movss  D7(%rip),%xmm0
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D38
datatype: f32
name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D7
datatype: byte[4]
name: unpack_data
arguments: tag: D20
datatype: string

tool: D38: 14.2

tool: D15: The turkey weighs %f.


tool: {"D7": [0x00,0x00,0x64,0x43]}

tool: D20: Cook it for %f minutes.


assistant: ```c
int main(int argc, const char *argv[]) {
  float weight;
  weight = 14.2;
  printf("The turkey weighs %f.\n", weight);
  float cookingTime;
  cookingTime = 15.0 + 15.0 * weight;
  printf("Cook it for %f minutes.\n", cookingTime);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D9(%rip),%xmm0
  lea    D13(%rip),%rdi
  call   <printf@plt>
  movss  D10(%rip),%xmm0
  lea    D39(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: f32
name: unpack_data
arguments: label: D13
type_guessed: string
name: unpack_data
arguments: label: D10
type_guessed: byte[4]
name: unpack_data
arguments: label: D39
type_guessed: string

tool: D9: 14.2

tool: D13: The turkey weighs %f.


tool: {"D10": [0x00,0x00,0x64,0x43]}

tool: D39: Cook it for %f minutes.


assistant: ```c
int main(int argc, const char *argv[]) {
  float weight;
  weight = 14.2;
  printf("The turkey weighs %f.\n", weight);
  float cookingTime;
  cookingTime = 15.0 + 15.0 * weight;
  printf("Cook it for %f minutes.\n", cookingTime);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D7(%rip),%xmm0
  lea    D10(%rip),%rdi
  call   <printf@plt>
  movss  D5(%rip),%xmm0
  lea    D35(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: f32
name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: byte[4]
name: extract_symbolic_data
arguments: tag: D35
type_infered: string

tool: D7: 14.2

tool: D10: The turkey weighs %f.


tool: {"D5": [0x00,0x00,0x64,0x43]}

tool: D35: Cook it for %f minutes.


assistant: ```c
int main(int argc, const char *argv[]) {
  float weight;
  weight = 14.2;
  printf("The turkey weighs %f.\n", weight);
  float cookingTime;
  cookingTime = 15.0 + 15.0 * weight;
  printf("Cook it for %f minutes.\n", cookingTime);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    %eax,%ecx
  mov    %ecx,%ecx
  mov    %rax,%rsi
  movabs $0xffffffff00000000,%rax
  and    %rsi,%rax
  or     %rcx,%rax
  mov    %edx,%edx
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
_Complex int f3(void) {
  int x;
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<f3>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
_Complex int f3(void) {
  int x;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f3>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
_Complex int f3(void) {
  int x;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f3>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
_Complex int f3(void) {
  int x;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unhex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L53
L1:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  shll   $0x4,-0x4(%rbp)
  cmpb   $0x2f,-0x5(%rbp)
  jle    L42
  cmpb   $0x39,-0x5(%rbp)
  jg     L42
  movsbl -0x5(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L53
L42:
  cmpb   $0x40,-0x5(%rbp)
  jle    L24
  cmpb   $0x46,-0x5(%rbp)
  jg     L24
  movsbl -0x5(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x37,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L53
L24:
  cmpb   $0x60,-0x5(%rbp)
  jle    L53
  cmpb   $0x66,-0x5(%rbp)
  jg     L53
  movsbl -0x5(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x57,%eax
  mov    %eax,-0x4(%rbp)
L53:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int unhex(char *ptr, int digits) {
  unsigned int rv = 0;
  while (digits--) {
    char c = *ptr++;
    rv <<= 4;
    if ('0' <= c && c <= '9')
      rv += c - '0';
    else if ('A' <= c && c <= 'F')
      rv += c - 'A' + 10;
    else if ('a' <= c && c <= 'f')
      rv += c - 'a' + 10;
  }
  return rv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unhex>:
  endbr64
  test   %esi,%esi
  je     L28
  mov    %esi,%esi
  add    %rdi,%rsi
  mov    $0x0,%edx
  jmp    L54
L76:
  lea    -0x41(%rax),%ecx
  cmp    $0x5,%cl
  ja     L38
  movsbl %al,%eax
  lea    -0x37(%rdx,%rax,1),%edx
L78:
  cmp    %rsi,%rdi
  je     L52
L54:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  shl    $0x4,%edx
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L76
  movsbl %al,%eax
  lea    -0x30(%rdx,%rax,1),%edx
  jmp    L78
L38:
  lea    -0x61(%rax),%ecx
  cmp    $0x5,%cl
  ja     L78
  movsbl %al,%eax
  lea    -0x57(%rdx,%rax,1),%edx
  jmp    L78
L28:
  mov    $0x0,%edx
L52:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int unhex(char *ptr, int digits) {
  unsigned int rv = 0;
  while (digits--) {
    char c = *ptr++;
    rv <<= 4;
    if ('0' <= c && c <= '9')
      rv += c - '0';
    else if ('A' <= c && c <= 'F')
      rv += c - 'A' + 10;
    else if ('a' <= c && c <= 'f')
      rv += c - 'a' + 10;
  }
  return rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unhex>:
  endbr64
  test   %esi,%esi
  je     L48
  mov    %esi,%esi
  xor    %r8d,%r8d
  lea    (%rdi,%rsi,1),%rcx
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L71:
  lea    -0x30(%r8,%rax,1),%r8d
L31:
  cmp    %rdi,%rcx
  je     L5
L57:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  shl    $0x4,%r8d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L71
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L58
  lea    -0x37(%r8,%rax,1),%r8d
  cmp    %rdi,%rcx
  jne    L57
L5:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  ja     L31
  lea    -0x57(%r8,%rax,1),%r8d
  jmp    L31
  nop
L48:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int unhex(char *ptr, int digits) {
  unsigned int rv = 0;
  while (digits--) {
    char c = *ptr++;
    rv <<= 4;
    if ('0' <= c && c <= '9')
      rv += c - '0';
    else if ('A' <= c && c <= 'F')
      rv += c - 'A' + 10;
    else if ('a' <= c && c <= 'f')
      rv += c - 'a' + 10;
  }
  return rv;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unhex>:
  endbr64
  test   %esi,%esi
  je     L26
  mov    %esi,%esi
  xor    %r8d,%r8d
  lea    (%rdi,%rsi,1),%rcx
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L72:
  lea    -0x30(%r8,%rax,1),%r8d
L45:
  cmp    %rdi,%rcx
  je     L16
L53:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  shl    $0x4,%r8d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L72
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L49
  lea    -0x37(%r8,%rax,1),%r8d
  cmp    %rdi,%rcx
  jne    L53
L16:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  ja     L45
  lea    -0x57(%r8,%rax,1),%r8d
  jmp    L45
  nop
L26:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int unhex(char *ptr, int digits) {
  unsigned int rv = 0;
  while (digits--) {
    char c = *ptr++;
    rv <<= 4;
    if ('0' <= c && c <= '9')
      rv += c - '0';
    else if ('A' <= c && c <= 'F')
      rv += c - 'A' + 10;
    else if ('a' <= c && c <= 'f')
      rv += c - 'a' + 10;
  }
  return rv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zero_imat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L9:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **zero_imat(int nx, int ny) {
  int **p = (int **)malloc(sizeof(int *) * nx);
  p[0] = (int *)calloc(nx * ny, sizeof(int));
  for (int i = 0; i < nx; ++i)
    p[i] = p[0] + ny * i;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zero_imat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12d,%edi
  imul   %ebx,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %r12d,%r12d
  jle    L3
  movslq %ebx,%rsi
  shl    $0x2,%rsi
  mov    %rbp,%rax
  mov    %r12d,%r12d
  lea    0x0(%rbp,%r12,8),%rdi
  mov    $0x0,%edx
L16:
  mov    %rdx,%rcx
  add    0x0(%rbp),%rcx
  mov    %rcx,(%rax)
  add    %rsi,%rdx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L16
L3:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int **zero_imat(int nx, int ny) {
  int **p = (int **)malloc(sizeof(int *) * nx);
  p[0] = (int *)calloc(nx * ny, sizeof(int));
  for (int i = 0; i < nx; ++i)
    p[i] = p[0] + ny * i;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<zero_imat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  imul   %ebx,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,(%r12)
  test   %ebp,%ebp
  jle    L8
  movslq %ebx,%rsi
  mov    %r12,%rdx
  lea    (%r12,%rbp,8),%rdi
  xor    %ecx,%ecx
  shl    $0x2,%rsi
  jmp    L10
  nopl   0x0(%rax)
L0:
  mov    (%r12),%rax
L10:
  add    %rcx,%rax
  add    $0x8,%rdx
  add    %rsi,%rcx
  mov    %rax,-0x8(%rdx)
  cmp    %rdi,%rdx
  jne    L0
L8:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int **zero_imat(int nx, int ny) {
  int **p = (int **)malloc(sizeof(int *) * nx);
  p[0] = (int *)calloc(nx * ny, sizeof(int));
  for (int i = 0; i < nx; ++i)
    p[i] = p[0] + ny * i;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<byte_value_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  lea    0x30(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void byte_value_to_string(int value[], char *output, int size) {
  for (int i = 0; i < size; i++)
    output[i] = (char)(value[i] + 48);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<byte_value_to_string>:
  endbr64
  test   %edx,%edx
  jle    L10
  mov    %edx,%edx
  mov    $0x0,%eax
L6:
  movzbl (%rdi,%rax,4),%ecx
  add    $0x30,%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L10:
  ret
```

assistant: ```c
void byte_value_to_string(int value[], char *output, int size) {
  for (int i = 0; i < size; i++)
    output[i] = (char)(value[i] + 48);
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_value_to_string>:
  endbr64
  test   %edx,%edx
  jle    L7
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L0:
  movzbl (%rdi,%rax,4),%ecx
  add    $0x30,%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L0
L7:
  ret
```

assistant: ```c
void byte_value_to_string(int value[], char *output, int size) {
  for (int i = 0; i < size; i++)
    output[i] = (char)(value[i] + 48);
}
```