ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Double_QR_Iteration>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  mov    %r9,%rcx
  push   %rbp
  mov    %r12d,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  mov    %ebx,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  mov    0x58(%rsp),%eax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <Product_and_Sum_of_Shifts@plt>
  movsd  0x20(%rsp),%xmm1
  mov    %ebx,%ecx
  mov    %r12d,%edx
  movsd  0x18(%rsp),%xmm0
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <Two_Consecutive_Small_Subdiagonal@plt>
  mov    %r12d,%edx
  mov    %ebx,%r9d
  mov    %r14,%r8
  movsd  0x20(%rsp),%xmm1
  mov    %eax,%ecx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  movsd  0x18(%rsp),%xmm0
  call   <Double_QR_Step@plt>
  pop    %rax
  pop    %rdx
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Double_QR_Iteration(double *H, double *S, int min_row, int max_row, int n, double *shift, int iteration) {
  int k;
  double trace, det;
  Product_and_Sum_of_Shifts(H, n, max_row, shift, &trace, &det, iteration);
  k = Two_Consecutive_Small_Subdiagonal(H, min_row, max_row, n, trace, det);
  Double_QR_Step(H, min_row, max_row, k, trace, det, S, n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L20
L13:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <xcalc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L35
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <num_string@plt>
  mov    %rbx,%rdx
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L28
L35:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <num_free@plt>
  addl   $0x1,-0x1c(%rbp)
L20:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D11
datatype: string

tool: D9: %s <- %s


tool: D11: ERR!

assistant: ```c
int main(int argc, char **argv) {
  int i;
  struct num *num;
  for (i = 1; i < argc; i++) {
    num = xcalc(argv[i]);
    if (num)
      printf("%s <- %s\n", num_string(num), argv[i]);
    else
      printf("ERR!\n");
    num_free(num);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L39
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbp
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r13
  lea    D12(%rip),%r15
  lea    D5(%rip),%r14
  jmp    L42
L5:
  mov    0x0(%rbp),%r12
  mov    %rax,%rdi
  call   <num_string@plt>
  mov    %rax,%rsi
  mov    %r12,%rdx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L49:
  mov    %rbx,%rdi
  call   <num_free@plt>
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L43
L42:
  mov    0x0(%rbp),%rdi
  call   <xcalc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L5
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L49
L43:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    $0x0,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D5
datatype: string

tool: D12: ERR!

tool: D5: %s <- %s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  struct num *num;
  for (i = 1; i < argc; i++) {
    num = xcalc(argv[i]);
    if (num)
      printf("%s <- %s\n", num_string(num), argv[i]);
    else
      printf("ERR!\n");
    num_free(num);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L41
  push   %r15
  lea    -0x2(%rdi),%eax
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    0x10(%rsi,%rax,8),%r12
  push   %rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%r15
  mov    %rax,%rdi
  call   <num_string@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %r15,%rdx
  xor    %eax,%eax
  call   <printf@plt>
L4:
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <num_free@plt>
  cmp    %r12,%rbx
  je     L23
L37:
  mov    (%rbx),%rdi
  call   <xcalc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L2
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L23:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string

tool: D9: ERR!

tool: D16: %s <- %s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  struct num *num;
  for (i = 1; i < argc; i++) {
    num = xcalc(argv[i]);
    if (num)
      printf("%s <- %s\n", num_string(num), argv[i]);
    else
      printf("ERR!\n");
    num_free(num);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L46
  push   %r15
  lea    -0x2(%rdi),%eax
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  lea    0x10(%rsi,%rax,8),%r12
  push   %rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L12:
  mov    (%rbx),%rdi
  call   <xcalc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L14
  mov    (%rbx),%r15
  mov    %rax,%rdi
  add    $0x8,%rbx
  call   <num_string@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %r15,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <num_free@plt>
  cmp    %r12,%rbx
  jne    L12
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L14:
  mov    %r14,%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  xor    %edi,%edi
  call   <num_free@plt>
  cmp    %r12,%rbx
  jne    L12
  jmp    L17
L46:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type: string
name: extract_symbolic_data
arguments: label: D8
type: string

tool: D16: ERR!

tool: D8: %s <- %s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  struct num *num;
  for (i = 1; i < argc; i++) {
    num = xcalc(argv[i]);
    if (num)
      printf("%s <- %s\n", num_string(num), argv[i]);
    else
      printf("ERR!\n");
    num_free(num);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ICCITTQuantize>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  test   $0x1,%sil
  je     L83
  mov    (%rcx),%eax
  test   %eax,%eax
  jle    L44
  lea    0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  mov    %eax,(%rcx)
L133:
  test   $0x1,%dil
  je     L35
  lea    0x4(%rcx),%rax
  add    $0x100,%rcx
  jmp    L15
L44:
  jns    L133
  lea    -0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  mov    %eax,(%rcx)
  jmp    L133
L83:
  mov    (%rcx),%eax
  test   %eax,%eax
  jle    L2
  lea    0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  sub    $0x1,%eax
  mov    %eax,(%rcx)
  jmp    L133
L2:
  jns    L133
  lea    -0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  add    $0x1,%eax
  mov    %eax,(%rcx)
  jmp    L133
L107:
  js     L143
L127:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L104
L15:
  mov    (%rax),%edx
  test   %edx,%edx
  jle    L107
  lea    0x1(%rdx,%rdx,1),%edx
  imul   %edi,%edx
  mov    %edx,(%rax)
  jmp    L127
L143:
  lea    -0x1(%rdx,%rdx,1),%edx
  imul   %edi,%edx
  mov    %edx,(%rax)
  jmp    L127
L104:
  ret
L35:
  lea    0x4(%rcx),%rax
  add    $0x100,%rcx
  jmp    L205
L200:
  js     L156
L124:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L197
L205:
  mov    (%rax),%edx
  test   %edx,%edx
  jle    L200
  lea    0x1(%rdx,%rdx,1),%edx
  imul   %edi,%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
  jmp    L124
L156:
  lea    -0x1(%rdx,%rdx,1),%edx
  imul   %edi,%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  jmp    L124
L197:
  ret
```

assistant: ```c
void ICCITTQuantize(int *matrix, int dcqfact, int acqfact) {
  static char RoutineName[] = "ICCITTQuantize";
  int *mptr;
  if (dcqfact & 1) {
    if (*matrix > 0) {
      *matrix = ((*matrix << 1) + 1) * dcqfact;
    } else if (*matrix < 0) {
      *matrix = ((*matrix << 1) - 1) * dcqfact;
    }
  } else {
    if (*matrix > 0) {
      *matrix = (((*matrix << 1) + 1) * dcqfact) - 1;
    } else if (*matrix < 0) {
      *matrix = (((*matrix << 1) - 1) * dcqfact) + 1;
    }
  }
  if (acqfact & 1) {
    for (mptr = matrix + 1; mptr < matrix + 64; mptr++) {
      if (*mptr > 0) {
        *mptr = ((*mptr << 1) + 1) * acqfact;
      } else if (*mptr < 0) {
        *mptr = ((*mptr << 1) - 1) * acqfact;
      }
    }
  } else {
    for (mptr = matrix + 1; mptr < matrix + 64; mptr++) {
      if (*mptr > 0) {
        *mptr = (((*mptr << 1) + 1) * acqfact) - 1;
      } else if (*mptr < 0) {
        *mptr = (((*mptr << 1) - 1) * acqfact) + 1;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ICCITTQuantize>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    (%rcx),%eax
  test   $0x1,%sil
  je     L5
  test   %eax,%eax
  jle    L137
  lea    0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  mov    %eax,(%rcx)
  jmp    L97
  nopl   0x0(%rax)
L5:
  test   %eax,%eax
  jle    L143
  lea    0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  sub    $0x1,%eax
  mov    %eax,(%rcx)
L97:
  lea    0x4(%rcx),%rax
  add    $0x100,%rcx
  test   $0x1,%dil
  je     L93
  jmp    L148
  nop
L102:
  lea    0x1(%rdx,%rdx,1),%edx
  imul   %edi,%edx
  mov    %edx,(%rax)
L41:
  add    $0x4,%rax
  cmp    %rax,%rcx
  je     L84
L148:
  mov    (%rax),%edx
  test   %edx,%edx
  jg     L102
  je     L41
  lea    -0x1(%rdx,%rdx,1),%edx
  add    $0x4,%rax
  imul   %edi,%edx
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L148
L84:
  ret
  xchg   %ax,%ax
L110:
  lea    0x1(%rdx,%rdx,1),%edx
  imul   %edi,%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
L71:
  add    $0x4,%rax
  cmp    %rax,%rcx
  je     L61
L93:
  mov    (%rax),%edx
  test   %edx,%edx
  jg     L110
  je     L71
  lea    -0x1(%rdx,%rdx,1),%edx
  add    $0x4,%rax
  imul   %edi,%edx
  add    $0x1,%edx
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L93
L61:
  ret
L143:
  je     L97
  lea    -0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  add    $0x1,%eax
  mov    %eax,(%rcx)
  jmp    L97
L137:
  je     L97
  lea    -0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  mov    %eax,(%rcx)
  jmp    L97
```

assistant: ```c
void ICCITTQuantize(int *matrix, int dcqfact, int acqfact) {
  static char RoutineName[] = "ICCITTQuantize";
  int *mptr;
  if (dcqfact & 1) {
    if (*matrix > 0) {
      *matrix = ((*matrix << 1) + 1) * dcqfact;
    } else if (*matrix < 0) {
      *matrix = ((*matrix << 1) - 1) * dcqfact;
    }
  } else {
    if (*matrix > 0) {
      *matrix = (((*matrix << 1) + 1) * dcqfact) - 1;
    } else if (*matrix < 0) {
      *matrix = (((*matrix << 1) - 1) * dcqfact) + 1;
    }
  }
  if (acqfact & 1) {
    for (mptr = matrix + 1; mptr < matrix + 64; mptr++) {
      if (*mptr > 0) {
        *mptr = ((*mptr << 1) + 1) * acqfact;
      } else if (*mptr < 0) {
        *mptr = ((*mptr << 1) - 1) * acqfact;
      }
    }
  } else {
    for (mptr = matrix + 1; mptr < matrix + 64; mptr++) {
      if (*mptr > 0) {
        *mptr = (((*mptr << 1) + 1) * acqfact) - 1;
      } else if (*mptr < 0) {
        *mptr = (((*mptr << 1) - 1) * acqfact) + 1;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ICCITTQuantize>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    (%rcx),%eax
  test   $0x1,%sil
  je     L26
  test   %eax,%eax
  jle    L169
  lea    0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  mov    %eax,(%rcx)
  jmp    L80
  nopl   0x0(%rax)
L26:
  test   %eax,%eax
  jle    L151
  lea    0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  sub    $0x1,%eax
  mov    %eax,(%rcx)
L80:
  lea    0x4(%rcx),%rax
  add    $0x100,%rcx
  test   $0x1,%dil
  je     L103
  jmp    L40
  nop
L145:
  lea    0x1(%rdx,%rdx,1),%edx
  imul   %edi,%edx
  mov    %edx,(%rax)
L64:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L142
L40:
  mov    (%rax),%edx
  test   %edx,%edx
  jg     L145
  je     L64
  lea    -0x1(%rdx,%rdx,1),%edx
  add    $0x4,%rax
  imul   %edi,%edx
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L40
L142:
  ret
  xchg   %ax,%ax
L20:
  lea    0x1(%rdx,%rdx,1),%edx
  imul   %edi,%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
L91:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L150
L103:
  mov    (%rax),%edx
  test   %edx,%edx
  jg     L20
  je     L91
  lea    -0x1(%rdx,%rdx,1),%edx
  add    $0x4,%rax
  imul   %edi,%edx
  add    $0x1,%edx
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L103
L150:
  ret
L151:
  je     L80
  lea    -0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  add    $0x1,%eax
  mov    %eax,(%rcx)
  jmp    L80
L169:
  je     L80
  lea    -0x1(%rax,%rax,1),%eax
  imul   %esi,%eax
  mov    %eax,(%rcx)
  jmp    L80
```

assistant: ```c
void ICCITTQuantize(int *matrix, int dcqfact, int acqfact) {
  static char RoutineName[] = "ICCITTQuantize";
  int *mptr;
  if (dcqfact & 1) {
    if (*matrix > 0) {
      *matrix = ((*matrix << 1) + 1) * dcqfact;
    } else if (*matrix < 0) {
      *matrix = ((*matrix << 1) - 1) * dcqfact;
    }
  } else {
    if (*matrix > 0) {
      *matrix = (((*matrix << 1) + 1) * dcqfact) - 1;
    } else if (*matrix < 0) {
      *matrix = (((*matrix << 1) - 1) * dcqfact) + 1;
    }
  }
  if (acqfact & 1) {
    for (mptr = matrix + 1; mptr < matrix + 64; mptr++) {
      if (*mptr > 0) {
        *mptr = ((*mptr << 1) + 1) * acqfact;
      } else if (*mptr < 0) {
        *mptr = ((*mptr << 1) - 1) * acqfact;
      }
    }
  } else {
    for (mptr = matrix + 1; mptr < matrix + 64; mptr++) {
      if (*mptr > 0) {
        *mptr = (((*mptr << 1) + 1) * acqfact) - 1;
      } else if (*mptr < 0) {
        *mptr = (((*mptr << 1) - 1) * acqfact) + 1;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<numberOfNeighbors>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    %edx,%esi
  mov    %ecx,%edi
  lea    -0x1(%r8),%eax
  mov    %edx,%ecx
  sub    $0x1,%ecx
  cmovs  %eax,%ecx
  mov    %edi,%r11d
  sub    $0x1,%r11d
  cmovs  %eax,%r11d
  lea    0x1(%rdi),%eax
  cltd
  idiv   %r8d
  movslq %ecx,%rcx
  lea    (%rcx,%rcx,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rax
  movslq %r11d,%r11
  movslq %edi,%rdi
  mov    (%rax,%rdi,4),%ecx
  add    (%rax,%r11,4),%ecx
  movslq %edx,%r10
  add    (%rax,%r10,4),%ecx
  movslq %esi,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rax
  add    (%rax,%r11,4),%ecx
  add    (%rax,%r10,4),%ecx
  lea    0x1(%rsi),%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rdx
  mov    %ecx,%eax
  add    (%rdx,%r11,4),%eax
  add    (%rdx,%rdi,4),%eax
  add    (%rdx,%r10,4),%eax
  ret
```

assistant: ```c
int numberOfNeighbors(int gamePlane[50][50], int size, int i, int j) {
  int topLine = 0, bottomLine = 0, leftColumn = 0, rightColumn = 0, neighbors = 0;
  topLine = i - 1;
  if (topLine < 0) {
    topLine = size - 1;
  }
  leftColumn = j - 1;
  if (leftColumn < 0) {
    leftColumn = size - 1;
  }
  bottomLine = (i + 1) % size;
  rightColumn = (j + 1) % size;
  neighbors = gamePlane[topLine][leftColumn];
  neighbors = neighbors + gamePlane[topLine][j];
  neighbors = neighbors + gamePlane[topLine][rightColumn];
  neighbors = neighbors + gamePlane[i][leftColumn];
  neighbors = neighbors + gamePlane[i][rightColumn];
  neighbors = neighbors + gamePlane[bottomLine][leftColumn];
  neighbors = neighbors + gamePlane[bottomLine][j];
  neighbors = neighbors + gamePlane[bottomLine][rightColumn];
  return neighbors;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numberOfNeighbors>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%r11d
  movslq %ecx,%rdi
  mov    %edx,%ecx
  lea    -0x1(%r11),%eax
  sub    $0x1,%ecx
  mov    %edi,%r8d
  mov    %edx,%esi
  cmovs  %eax,%ecx
  sub    $0x1,%r8d
  cmovs  %eax,%r8d
  lea    0x1(%rdi),%eax
  cltd
  movslq %ecx,%rcx
  idiv   %r11d
  lea    (%rcx,%rcx,4),%rax
  movslq %r8d,%r8
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rax
  mov    (%rax,%rdi,4),%ecx
  add    (%rax,%r8,4),%ecx
  movslq %edx,%r10
  add    (%rax,%r10,4),%ecx
  movslq %esi,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rax
  add    (%rax,%r8,4),%ecx
  add    (%rax,%r10,4),%ecx
  lea    0x1(%rsi),%eax
  cltd
  idiv   %r11d
  movslq %edx,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rdx
  mov    (%rdx,%r8,4),%eax
  add    %ecx,%eax
  add    (%rdx,%rdi,4),%eax
  add    (%rdx,%r10,4),%eax
  ret
```

assistant: ```c
int numberOfNeighbors(int gamePlane[50][50], int size, int i, int j) {
  int topLine = 0, bottomLine = 0, leftColumn = 0, rightColumn = 0, neighbors = 0;
  topLine = i - 1;
  if (topLine < 0) {
    topLine = size - 1;
  }
  leftColumn = j - 1;
  if (leftColumn < 0) {
    leftColumn = size - 1;
  }
  bottomLine = (i + 1) % size;
  rightColumn = (j + 1) % size;
  neighbors = gamePlane[topLine][leftColumn];
  neighbors = neighbors + gamePlane[topLine][j];
  neighbors = neighbors + gamePlane[topLine][rightColumn];
  neighbors = neighbors + gamePlane[i][leftColumn];
  neighbors = neighbors + gamePlane[i][rightColumn];
  neighbors = neighbors + gamePlane[bottomLine][leftColumn];
  neighbors = neighbors + gamePlane[bottomLine][j];
  neighbors = neighbors + gamePlane[bottomLine][rightColumn];
  return neighbors;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<numberOfNeighbors>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%r11d
  movslq %ecx,%rdi
  mov    %edx,%ecx
  lea    -0x1(%r11),%eax
  sub    $0x1,%ecx
  mov    %edi,%r8d
  mov    %edx,%esi
  cmovs  %eax,%ecx
  sub    $0x1,%r8d
  cmovs  %eax,%r8d
  lea    0x1(%rdi),%eax
  cltd
  movslq %ecx,%rcx
  idiv   %r11d
  lea    (%rcx,%rcx,4),%rax
  movslq %r8d,%r8
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rax
  mov    (%rax,%rdi,4),%ecx
  add    (%rax,%r8,4),%ecx
  movslq %edx,%r10
  add    (%rax,%r10,4),%ecx
  movslq %esi,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rax
  add    (%rax,%r8,4),%ecx
  add    (%rax,%r10,4),%ecx
  lea    0x1(%rsi),%eax
  cltd
  idiv   %r11d
  movslq %edx,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r9,%rax,8),%rdx
  mov    (%rdx,%r8,4),%eax
  add    %ecx,%eax
  add    (%rdx,%rdi,4),%eax
  add    (%rdx,%r10,4),%eax
  ret
```

assistant: ```c
int numberOfNeighbors(int gamePlane[50][50], int size, int i, int j) {
  int topLine = 0, bottomLine = 0, leftColumn = 0, rightColumn = 0, neighbors = 0;
  topLine = i - 1;
  if (topLine < 0) {
    topLine = size - 1;
  }
  leftColumn = j - 1;
  if (leftColumn < 0) {
    leftColumn = size - 1;
  }
  bottomLine = (i + 1) % size;
  rightColumn = (j + 1) % size;
  neighbors = gamePlane[topLine][leftColumn];
  neighbors = neighbors + gamePlane[topLine][j];
  neighbors = neighbors + gamePlane[topLine][rightColumn];
  neighbors = neighbors + gamePlane[i][leftColumn];
  neighbors = neighbors + gamePlane[i][rightColumn];
  neighbors = neighbors + gamePlane[bottomLine][leftColumn];
  neighbors = neighbors + gamePlane[bottomLine][j];
  neighbors = neighbors + gamePlane[bottomLine][rightColumn];
  return neighbors;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<testg2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x4(%rbp)
  cmpl   $0x37,-0x4(%rbp)
  jle    L9
  mov    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int testg2(int a, int c) {
  int j = 0;
  do {
    j += a;
  } while (j < 56);
  j += c;
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<testg2>:
  endbr64
  mov    $0x0,%eax
L8:
  add    %edi,%eax
  cmp    $0x37,%eax
  jle    L8
  add    %esi,%eax
  ret
```

assistant: ```c
int testg2(int a, int c) {
  int j = 0;
  do {
    j += a;
  } while (j < 56);
  j += c;
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testg2>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    %edi,%eax
  cmp    $0x37,%eax
  jle    L1
  add    %esi,%eax
  ret
```

assistant: ```c
int testg2(int a, int c) {
  int j = 0;
  do {
    j += a;
  } while (j < 56);
  j += c;
  return j;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<testg2>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L5:
  add    %edi,%eax
  cmp    $0x37,%eax
  jle    L5
  add    %esi,%eax
  ret
```

assistant: ```c
int testg2(int a, int c) {
  int j = 0;
  do {
    j += a;
  } while (j < 56);
  j += c;
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_loop_mode_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movswl -0x4(%rbp),%eax
  cmp    $0x2,%eax
  je     L20
  cmp    $0x2,%eax
  jg     L55
  test   %eax,%eax
  je     L39
  cmp    $0x1,%eax
  je     L57
  jmp    L55
L39:
  lea    D2(%rip),%rax
  jmp    L71
L57:
  lea    D39(%rip),%rax
  jmp    L71
L20:
  lea    D11(%rip),%rax
  jmp    L71
L55:
  lea    D18(%rip),%rax
L71:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string
name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string

tool: D2: none

tool: D39: forward

tool: D11: backward

tool: D18: *** unknown

assistant: ```c
const char *get_loop_mode_str(short mode) {
  switch (mode) {
  case 0:
    return "none";
  case 1:
    return "forward";
  case 2:
    return "backward";
  };
  return "*** unknown";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_loop_mode_str>:
  endbr64
  lea    D29(%rip),%rax
  cmp    $0x1,%di
  je     L6
  lea    D18(%rip),%rax
  cmp    $0x2,%di
  je     L6
  test   %di,%di
  lea    D2(%rip),%rax
  lea    D33(%rip),%rdx
  cmove  %rdx,%rax
L6:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string

tool: D29: forward

tool: D18: backward

tool: D2: *** unknown

tool: D33: none

assistant: ```c
const char *get_loop_mode_str(short mode) {
  switch (mode) {
  case 0:
    return "none";
  case 1:
    return "forward";
  case 2:
    return "backward";
  };
  return "*** unknown";
}
```