ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s_hval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L13:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int s_hval(char *s) {
  int h = 0;
  while (*s)
    h = h * 31 + *(s++);
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<s_hval>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  mov    $0x0,%ecx
L17:
  mov    %ecx,%edx
  shl    $0x5,%edx
  sub    %ecx,%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%ecx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L17
L3:
  mov    %ecx,%eax
  ret
L11:
  mov    $0x0,%ecx
  jmp    L3
```

assistant: ```c
int s_hval(char *s) {
  int h = 0;
  while (*s)
    h = h * 31 + *(s++);
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<s_hval>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L5
  xchg   %ax,%ax
L0:
  mov    %r8d,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %r8d,%edx
  lea    (%rax,%rdx,1),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L0
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int s_hval(char *s) {
  int h = 0;
  while (*s)
    h = h * 31 + *(s++);
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s_hval>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L9
  xchg   %ax,%ax
L4:
  mov    %r8d,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %r8d,%edx
  lea    (%rax,%rdx,1),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L4
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int s_hval(char *s) {
  int h = 0;
  while (*s)
    h = h * 31 + *(s++);
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bx_unicode_sqlite3StrNICmp16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
L47:
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    %eax,-0x14(%rbp)
  addq   $0x2,-0x10(%rbp)
  addq   $0x2,-0x8(%rbp)
  subl   $0x1,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jle    L10
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  je     L10
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L47
L10:
  cmpl   $0x0,-0x34(%rbp)
  js     L46
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  jmp    L13
L46:
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int bx_unicode_sqlite3StrNICmp16(const void *zLeft, const void *zRight, int N) {
  const unsigned short *a = zLeft;
  const unsigned short *b = zRight;
  signed int ua = 0, ub = 0;
  do {
    ua = *a;
    ub = *b;
    ua = ua = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ua, 0, 0));
    ub = ub = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ub, 0, 0));
    a++;
    b++;
  } while (--N > 0 && *a != 0 && ua == ub);
  return N < 0 ? 0 : ua - ub;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bx_unicode_sqlite3StrNICmp16>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %edx,%r12d
L4:
  movzwl 0x0(%r13),%r14d
  movzwl (%rbx),%edi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    %eax,%ebp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %r14d,%edi
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  add    $0x2,%rbx
  add    $0x2,%r13
  sub    $0x1,%r12d
  test   %r12d,%r12d
  jle    L45
  cmpw   $0x0,(%rbx)
  je     L37
  cmp    %eax,%ebp
  je     L4
L37:
  sub    %eax,%ebp
L35:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  je     L37
  mov    $0x0,%ebp
  jmp    L35
```

assistant: ```c
int bx_unicode_sqlite3StrNICmp16(const void *zLeft, const void *zRight, int N) {
  const unsigned short *a = zLeft;
  const unsigned short *b = zRight;
  signed int ua = 0, ub = 0;
  do {
    ua = *a;
    ub = *b;
    ua = ua = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ua, 0, 0));
    ub = ub = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ub, 0, 0));
    a++;
    b++;
  } while (--N > 0 && *a != 0 && ua == ub);
  return N < 0 ? 0 : ua - ub;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bx_unicode_sqlite3StrNICmp16>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzwl (%rdi),%edi
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L3:
  movzwl 0x0(%rbp),%edi
  cmp    %eax,%ebx
  jne    L9
  test   %di,%di
  je     L9
L2:
  xor    %edx,%edx
  xor    %esi,%esi
  movzwl 0x0(%r13),%r14d
  sub    $0x1,%r12d
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  add    $0x2,%rbp
  add    $0x2,%r13
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r14d,%edi
  mov    %eax,%ebx
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  test   %r12d,%r12d
  jg     L3
  je     L9
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L9:
  sub    %eax,%ebx
  mov    %ebx,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bx_unicode_sqlite3StrNICmp16(const void *zLeft, const void *zRight, int N) {
  const unsigned short *a = zLeft;
  const unsigned short *b = zRight;
  signed int ua = 0, ub = 0;
  do {
    ua = *a;
    ub = *b;
    ua = ua = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ua, 0, 0));
    ub = ub = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ub, 0, 0));
    a++;
    b++;
  } while (--N > 0 && *a != 0 && ua == ub);
  return N < 0 ? 0 : ua - ub;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bx_unicode_sqlite3StrNICmp16>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L28:
  cmpw   $0x0,(%rbx)
  je     L21
  cmp    %eax,%ebp
  jne    L21
L23:
  movzwl (%rbx),%edi
  xor    %edx,%edx
  xor    %esi,%esi
  movzwl 0x0(%r13),%r14d
  sub    $0x1,%r12d
  add    $0x2,%rbx
  add    $0x2,%r13
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r14d,%edi
  mov    %eax,%ebp
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  test   %r12d,%r12d
  jg     L28
  je     L21
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L21:
  mov    %ebp,%r8d
  pop    %rbx
  pop    %rbp
  sub    %eax,%r8d
  pop    %r12
  pop    %r13
  mov    %r8d,%eax
  pop    %r14
  ret
```

assistant: ```c
int bx_unicode_sqlite3StrNICmp16(const void *zLeft, const void *zRight, int N) {
  const unsigned short *a = zLeft;
  const unsigned short *b = zRight;
  signed int ua = 0, ub = 0;
  do {
    ua = *a;
    ub = *b;
    ua = ua = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ua, 0, 0));
    ub = ub = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ub, 0, 0));
    a++;
    b++;
  } while (--N > 0 && *a != 0 && ua == ub);
  return N < 0 ? 0 : ua - ub;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_add_test_case>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_add_test_case(char **data, char *s1, char *s2, char *n) {
  data[0] = s1;
  data[1] = s2;
  data[2] = n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_add_test_case>:
  endbr64
  mov    %rsi,(%rdi)
  mov    %rdx,0x8(%rdi)
  mov    %rcx,0x10(%rdi)
  ret
```

assistant: ```c
void ft_add_test_case(char **data, char *s1, char *s2, char *n) {
  data[0] = s1;
  data[1] = s2;
  data[2] = n;
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_add_test_case>:
  endbr64
  mov    %rsi,(%rdi)
  mov    %rdx,0x8(%rdi)
  mov    %rcx,0x10(%rdi)
  ret
```

assistant: ```c
void ft_add_test_case(char **data, char *s1, char *s2, char *n) {
  data[0] = s1;
  data[1] = s2;
  data[2] = n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_add_test_case>:
  endbr64
  movq   %rsi,%xmm0
  movq   %rdx,%xmm1
  mov    %rcx,0x10(%rdi)
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void ft_add_test_case(char **data, char *s1, char *s2, char *n) {
  data[0] = s1;
  data[1] = s2;
  data[2] = n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__stdfix_smul_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L15
  mov    D25(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L15
  mov    D20(%rip),%rax
  mov    (%rax),%rax
  jmp    L29
L15:
  mov    -0x8(%rbp),%rax
  imul   -0x10(%rbp),%rax
  sar    $0xf,%rax
  mov    %rax,%rdi
  call   <__stdfix_sat_r@plt>
  nop
L29:
  leave
  ret
```

assistant: ```c
int32_t __stdfix_smul_r(int32_t x, int32_t y) {
  if (x == INT16_MIN && y == INT16_MIN)
    return (INT16_MAX);
  return ((int32_t)__stdfix_sat_r(((int32_t)x * (int32_t)y) >> 15));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__stdfix_smul_r>:
  endbr64
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rsi,%rax
  jne    L7
  cmp    %rdi,%rax
  je     L14
L7:
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  sar    $0xf,%rdi
  call   <__stdfix_sat_r@plt>
  add    $0x8,%rsp
  ret
L14:
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  ret
```

assistant: ```c
int32_t __stdfix_smul_r(int32_t x, int32_t y) {
  if (x == INT16_MIN && y == INT16_MIN)
    return (INT16_MAX);
  return ((int32_t)__stdfix_sat_r(((int32_t)x * (int32_t)y) >> 15));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__stdfix_smul_r>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rsi,%rax
  jne    L7
  cmp    %rdi,%rax
  je     L17
L7:
  imul   %rsi,%rdi
  sar    $0xf,%rdi
  jmp    1050 <__stdfix_sat_r@plt>
  nopl   (%rax)
L17:
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  ret
```

assistant: ```c
int32_t __stdfix_smul_r(int32_t x, int32_t y) {
  if (x == INT16_MIN && y == INT16_MIN)
    return (INT16_MAX);
  return ((int32_t)__stdfix_sat_r(((int32_t)x * (int32_t)y) >> 15));
}
```
user: Translate the below assembly code into C programming language:

```asm
<__stdfix_smul_r>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  cmp    %rsi,%rax
  jne    L9
  cmp    %rdi,%rax
  je     L15
L9:
  imul   %rsi,%rdi
  sar    $0xf,%rdi
  jmp    1050 <__stdfix_sat_r@plt>
  nopl   (%rax)
L15:
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  ret
```

assistant: ```c
int32_t __stdfix_smul_r(int32_t x, int32_t y) {
  if (x == INT16_MIN && y == INT16_MIN)
    return (INT16_MAX);
  return ((int32_t)__stdfix_sat_r(((int32_t)x * (int32_t)y) >> 15));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<remove_appaserver_error_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %edx,%eax
  mov    %al,-0x434(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rdx
  mov    -0x430(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_error_filename@plt>
  mov    %rax,-0x418(%rbp)
  cmpb   $0x79,-0x434(%rbp)
  jne    L17
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  jmp    L11
L17:
  mov    -0x418(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string

tool: D3: rm %s 2>&1 | html_paragraph_wrapper

tool: D18: <p>rm %s


assistant: ```c
void remove_appaserver_error_file(char *destination_application, char *appaserver_error_directory, char really_yn) {
  char sys_string[1024];
  char *error_filename;
  error_filename = get_error_filename(appaserver_error_directory, destination_application);
  if (really_yn == 'y') {
    sprintf(sys_string, "rm %s 2>&1 | html_paragraph_wrapper", error_filename);
    if (system(sys_string)) {
    };
  } else {
    printf("<p>rm %s\n", error_filename);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_appaserver_error_file>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %edx,%ebx
  mov    %fs:0x28,%rdx
  mov    %rdx,0x408(%rsp)
  xor    %edx,%edx
  mov    %rax,%rsi
  call   <get_error_filename@plt>
  cmp    $0x79,%bl
  je     L28
  mov    %rax,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x410,%rsp
  pop    %rbx
  ret
L28:
  mov    %rsp,%rbx
  mov    %rax,%rdx
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  jmp    L20
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D18
type: string

tool: D9: <p>rm %s


tool: D18: rm %s 2>&1 | html_paragraph_wrapper

assistant: ```c
void remove_appaserver_error_file(char *destination_application, char *appaserver_error_directory, char really_yn) {
  char sys_string[1024];
  char *error_filename;
  error_filename = get_error_filename(appaserver_error_directory, destination_application);
  if (really_yn == 'y') {
    sprintf(sys_string, "rm %s 2>&1 | html_paragraph_wrapper", error_filename);
    if (system(sys_string)) {
    };
  } else {
    printf("<p>rm %s\n", error_filename);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_appaserver_error_file>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rdi
  push   %rbx
  mov    %r8,%rsi
  mov    %edx,%ebx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <get_error_filename@plt>
  mov    %rax,%rsi
  cmp    $0x79,%bl
  je     L20
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x418,%rsp
  lea    D16(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <printf@plt>
L20:
  mov    %rsp,%rbp
  mov    %rax,%rdx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
data_type: string
name: retrieve_data
arguments: label: D7
data_type: string

tool: D16: <p>rm %s


tool: D7: rm %s 2>&1 | html_paragraph_wrapper

assistant: ```c
void remove_appaserver_error_file(char *destination_application, char *appaserver_error_directory, char really_yn) {
  char sys_string[1024];
  char *error_filename;
  error_filename = get_error_filename(appaserver_error_directory, destination_application);
  if (really_yn == 'y') {
    sprintf(sys_string, "rm %s 2>&1 | html_paragraph_wrapper", error_filename);
    if (system(sys_string)) {
    };
  } else {
    printf("<p>rm %s\n", error_filename);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<remove_appaserver_error_file>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rdi
  push   %rbx
  mov    %r8,%rsi
  mov    %edx,%ebx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <get_error_filename@plt>
  mov    %rax,%rsi
  cmp    $0x79,%bl
  je     L9
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x418,%rsp
  lea    D2(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <printf@plt>
L9:
  mov    %rsp,%rbp
  mov    %rax,%rdx
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string
name: disassemble_data
arguments: data_label: D14
type: string

tool: D2: <p>rm %s


tool: D14: rm %s 2>&1 | html_paragraph_wrapper

assistant: ```c
void remove_appaserver_error_file(char *destination_application, char *appaserver_error_directory, char really_yn) {
  char sys_string[1024];
  char *error_filename;
  error_filename = get_error_filename(appaserver_error_directory, destination_application);
  if (really_yn == 'y') {
    sprintf(sys_string, "rm %s 2>&1 | html_paragraph_wrapper", error_filename);
    if (system(sys_string)) {
    };
  } else {
    printf("<p>rm %s\n", error_filename);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Strntok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L60
  mov    -0x38(%rbp),%rax
  mov    %rax,D11(%rip)
  jmp    L13
L60:
  mov    D11(%rip),%rax
  test   %rax,%rax
  jne    L13
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0xffffffff,%eax
  jmp    L59
L13:
  mov    D11(%rip),%rax
  mov    %rax,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  movq   $0x0,D11(%rip)
  jmp    L21
L64:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L94
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,D48(%rip)
  jmp    L21
L94:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L66
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L66:
  addq   $0x1,-0x18(%rbp)
  jmp    L8
L21:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  addq   $0x1,-0x10(%rbp)
  jmp    L48
L32:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L48:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L32
  mov    -0x1c(%rbp),%eax
L59:
  leave
  ret
```

assistant: ```c
int Strntok(char *dstTokenStart, size_t tokenSize, char *buf, const char *delims) {
  static char *p = NULL;
  char *end;
  char *lim;
  char *dst;
  int len;
  dst = dstTokenStart;
  lim = dst + tokenSize - 1;
  if (buf != NULL) {
    p = buf;
  } else {
    if (p == NULL) {
      *dst = '\0';
      return (-1);
    }
  }
  for (end = p;; end++) {
    if (*end == '\0') {
      p = NULL;
      break;
    }
    if (strchr(delims, (int)*end) != NULL) {
      ++end;
      p = end;
      break;
    }
    if (dst < lim)
      *dst++ = *end;
  }
  *dst = '\0';
  len = (int)(dst - dstTokenStart);
  for (++dst; dst <= lim;)
    *dst++ = 0;
  return (len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Strntok>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %rcx,%r14
  lea    -0x1(%rdi,%rsi,1),%r15
  test   %rdx,%rdx
  je     L19
  mov    %rdx,D5(%rip)
L16:
  mov    D5(%rip),%r12
  movzbl (%r12),%ebp
  mov    %r13,%rbx
  test   %bpl,%bpl
  jne    L100
L94:
  mov    $0x0,%r12d
L87:
  mov    %r12,D21(%rip)
  movb   $0x0,(%rbx)
  mov    %ebx,%eax
  sub    %r13d,%eax
  add    $0x1,%rbx
  cmp    %rbx,%r15
  jb     L79
  add    0x8(%rsp),%r13
L109:
  add    $0x1,%rbx
  movb   $0x0,-0x1(%rbx)
  cmp    %r13,%rbx
  jne    L109
L79:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  cmpq   $0x0,D21(%rip)
  jne    L16
  movb   $0x0,(%rdi)
  mov    $0xffffffff,%eax
  jmp    L79
L83:
  add    $0x1,%r12
  jmp    L87
L73:
  add    $0x1,%r12
  movzbl (%r12),%ebp
  test   %bpl,%bpl
  je     L94
L100:
  movsbl %bpl,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L83
  cmp    %rbx,%r15
  jbe    L73
  mov    %bpl,(%rbx)
  lea    0x1(%rbx),%rbx
  jmp    L73
```

assistant: ```c
int Strntok(char *dstTokenStart, size_t tokenSize, char *buf, const char *delims) {
  static char *p = NULL;
  char *end;
  char *lim;
  char *dst;
  int len;
  dst = dstTokenStart;
  lim = dst + tokenSize - 1;
  if (buf != NULL) {
    p = buf;
  } else {
    if (p == NULL) {
      *dst = '\0';
      return (-1);
    }
  }
  for (end = p;; end++) {
    if (*end == '\0') {
      p = NULL;
      break;
    }
    if (strchr(delims, (int)*end) != NULL) {
      ++end;
      p = end;
      break;
    }
    if (dst < lim)
      *dst++ = *end;
  }
  *dst = '\0';
  len = (int)(dst - dstTokenStart);
  for (++dst; dst <= lim;)
    *dst++ = 0;
  return (len);
}
```