ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  lea    D45(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    %r13,%rbp
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L47
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L6
L47:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r13,%rdi
  call   <move1@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L16
  xor    %ebx,%ebx
  lea    D47(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L34:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L34
L16:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D45
datatype: string
name: unpack_data
arguments: label: D53
datatype: string
name: unpack_data
arguments: label: D26
datatype: string
name: unpack_data
arguments: label: D27
datatype: string
name: unpack_data
arguments: label: D47
datatype: string

tool: D19: How many numbers?

tool: D45: %d

tool: D53: input %d numbers:


tool: D26: how many place do you want move?

tool: D27: Now,they are:

tool: D47: %d 

assistant: ```c
int main() {
  void move1(int[20], int, int);
  int number[20], n, m, i;
  printf("How many numbers?");
  scanf("%d", &n);
  printf("input %d numbers:\n", n);
  for (i = 0; i < n; i++) {
    scanf("%d", &number[i]);
  }
  printf("how many place do you want move?");
  scanf("%d", &m);
  move1(number, n, m);
  printf("Now,they are:\n");
  for (i = 0; i < n; i++) {
    printf("%d ", number[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int create(void *opaque) {
  assert(opaque);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<create>:
  endbr64
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int create(void *opaque) {
  assert(opaque);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<create>:
  endbr64
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int create(void *opaque) {
  assert(opaque);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<countChild>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L48
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  jne    L10
L13:
  addl   $0x1,-0xc(%rbp)
L10:
  addq   $0x1,-0x8(%rbp)
L48:
  cmpq   $0x0,-0x8(%rbp)
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L22:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int countChild(char *nodeString) {
  int count = 0;
  char *stringPtr = nodeString;
  while (stringPtr != NULL && *stringPtr != '\0') {
    if (*stringPtr == '(' || *stringPtr == '[') {
      count++;
    }
    stringPtr++;
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<countChild>:
  endbr64
  mov    $0x0,%edx
  test   %rdi,%rdi
  jne    L23
L5:
  mov    %edx,%eax
  ret
L32:
  add    $0x1,%edx
L41:
  add    $0x1,%rdi
L23:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  cmp    $0x28,%al
  je     L32
  cmp    $0x5b,%al
  jne    L41
  jmp    L32
```

assistant: ```c
int countChild(char *nodeString) {
  int count = 0;
  char *stringPtr = nodeString;
  while (stringPtr != NULL && *stringPtr != '\0') {
    if (*stringPtr == '(' || *stringPtr == '[') {
      count++;
    }
    stringPtr++;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<countChild>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  jne    L2
  jmp    L25
  xchg   %ax,%ax
L14:
  add    $0x1,%rdi
L2:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L25
  cmp    $0x28,%al
  je     L1
  cmp    $0x5b,%al
  jne    L14
L1:
  add    $0x1,%r8d
  jmp    L14
  nopl   0x0(%rax)
L25:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int countChild(char *nodeString) {
  int count = 0;
  char *stringPtr = nodeString;
  while (stringPtr != NULL && *stringPtr != '\0') {
    if (*stringPtr == '(' || *stringPtr == '[') {
      count++;
    }
    stringPtr++;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<countChild>:
  endbr64
  test   %rdi,%rdi
  je     L63
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L5
  jmp    L23
  nopl   (%rax)
L27:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L23
L5:
  cmp    $0x28,%al
  je     L28
  cmp    $0x5b,%al
  jne    L27
L28:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  add    $0x1,%r8d
  test   %al,%al
  jne    L5
L23:
  mov    %r8d,%eax
  ret
L63:
  xor    %r8d,%r8d
  jmp    L23
```

assistant: ```c
int countChild(char *nodeString) {
  int count = 0;
  char *stringPtr = nodeString;
  while (stringPtr != NULL && *stringPtr != '\0') {
    if (*stringPtr == '(' || *stringPtr == '[') {
      count++;
    }
    stringPtr++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<putseqend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <alignbits@plt>
  mov    $0x20,%esi
  mov    $0x1b7,%edi
  call   <putbits@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void putseqend(void) {
  {
    alignbits();
    putbits(439, 32);
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<putseqend>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <alignbits@plt>
  mov    $0x20,%esi
  mov    $0x1b7,%edi
  call   <putbits@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void putseqend(void) {
  {
    alignbits();
    putbits(439, 32);
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<putseqend>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <alignbits@plt>
  mov    $0x20,%esi
  mov    $0x1b7,%edi
  add    $0x8,%rsp
  jmp    1070 <putbits@plt>
```

assistant: ```c
void putseqend(void) {
  {
    alignbits();
    putbits(439, 32);
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putseqend>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <alignbits@plt>
  mov    $0x20,%esi
  mov    $0x1b7,%edi
  add    $0x8,%rsp
  jmp    1070 <putbits@plt>
```

assistant: ```c
void putseqend(void) {
  {
    alignbits();
    putbits(439, 32);
    return;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <hash_table_test@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: hash table test OK!


assistant: ```c
int main() {
  hash_table_test();
  printf("hash table test OK!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <hash_table_test@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6: hash table test OK!


assistant: ```c
int main() {
  hash_table_test();
  printf("hash table test OK!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hash_table_test@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string

tool: D3: hash table test OK!


assistant: ```c
int main() {
  hash_table_test();
  printf("hash table test OK!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hash_table_test@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: hash table test OK!


assistant: ```c
int main() {
  hash_table_test();
  printf("hash table test OK!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<smoothing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %ecx,%eax
  mov    %r8d,%r11d
  mov    %r9d,%r10d
  mov    0x10(%rbp),%r9d
  mov    0x18(%rbp),%r8d
  mov    0x20(%rbp),%ecx
  mov    %dil,-0x64(%rbp)
  mov    %sil,-0x68(%rbp)
  mov    %dl,-0x6c(%rbp)
  mov    %al,-0x70(%rbp)
  mov    %r11d,%eax
  mov    %al,-0x74(%rbp)
  mov    %r10d,%eax
  mov    %al,-0x78(%rbp)
  mov    %r9d,%eax
  mov    %al,-0x7c(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x80(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x64(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movzbl -0x68(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movzbl -0x6c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movzbl -0x70(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movzbl -0x74(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movzbl -0x78(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movzbl -0x7c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movzbl -0x80(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movzbl -0x84(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L11
L4:
  cmpl   $0x4,-0x5c(%rbp)
  jne    L19
  mov    -0x5c(%rbp),%eax
  cltq
  movsd  -0x50(%rbp,%rax,8),%xmm0
  addsd  %xmm0,%xmm0
  mov    -0x5c(%rbp),%eax
  cltq
  movsd  %xmm0,-0x50(%rbp,%rax,8)
L19:
  mov    -0x5c(%rbp),%eax
  cltq
  movsd  -0x50(%rbp,%rax,8),%xmm0
  movsd  -0x58(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  addl   $0x1,-0x5c(%rbp)
L11:
  cmpl   $0x8,-0x5c(%rbp)
  jle    L4
  movsd  -0x58(%rbp),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  cvttsd2si -0x58(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: f32[2]

tool: {"D7": [0.0,2.5625]}

assistant: ```c
unsigned char smoothing(unsigned char px0, unsigned char px1, unsigned char px2, unsigned char px3, unsigned char px4, unsigned char px5, unsigned char px6, unsigned char px7, unsigned char px8) {
  double px[9] = {px0, px1, px2, px3, px4, px5, px6, px7, px8};
  double px_out = 0.0;
  for (int i = 0; i < 9; i++) {
    if (i == 4) {
      px[i] *= 2;
    }
    px_out += px[i];
  }
  px_out /= 10;
  return (unsigned char)px_out;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<smoothing>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movzbl %dil,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  movsd  %xmm0,(%rsp)
  movzbl %sil,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movzbl %dl,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,0x10(%rsp)
  movzbl %cl,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  movsd  %xmm0,0x18(%rsp)
  movzbl %r8b,%r8d
  pxor   %xmm0,%xmm0
  cvtsi2sd %r8d,%xmm0
  movsd  %xmm0,0x20(%rsp)
  movzbl %r9b,%r9d
  pxor   %xmm0,%xmm0
  cvtsi2sd %r9d,%xmm0
  movsd  %xmm0,0x28(%rsp)
  movzbl 0x60(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,0x30(%rsp)
  movzbl 0x68(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,0x38(%rsp)
  movzbl 0x70(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,0x40(%rsp)
  mov    %rsp,%rdx
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
  jmp    L31
L15:
  movsd  0x20(%rsp),%xmm1
  addsd  %xmm1,%xmm1
  movsd  %xmm1,0x20(%rsp)
  addsd  (%rdx),%xmm0
L33:
  add    $0x1,%eax
  add    $0x8,%rdx
L31:
  cmp    $0x5,%eax
  je     L15
  addsd  (%rdx),%xmm0
  cmp    $0x8,%eax
  jle    L33
  divsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x58,%rsp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: f32[2]

tool: {"D8": [0.0,2.5625]}

assistant: ```c
unsigned char smoothing(unsigned char px0, unsigned char px1, unsigned char px2, unsigned char px3, unsigned char px4, unsigned char px5, unsigned char px6, unsigned char px7, unsigned char px8) {
  double px[9] = {px0, px1, px2, px3, px4, px5, px6, px7, px8};
  double px_out = 0.0;
  for (int i = 0; i < 9; i++) {
    if (i == 4) {
      px[i] *= 2;
    }
    px_out += px[i];
  }
  px_out /= 10;
  return (unsigned char)px_out;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<smoothing>:
  endbr64
  movzbl %dil,%edi
  pxor   %xmm0,%xmm0
  sub    $0x58,%rsp
  movzbl %sil,%esi
  cvtsi2sd %edi,%xmm0
  movzbl %dl,%edx
  movzbl %cl,%ecx
  movzbl %r8b,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movzbl %r9b,%r9d
  movzbl 0x60(%rsp),%eax
  movsd  %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mov    %rsp,%rdx
  movsd  %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  movsd  %xmm0,0x18(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %r8d,%xmm0
  movsd  %xmm0,0x20(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %r9d,%xmm0
  movsd  %xmm0,0x28(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movzbl 0x68(%rsp),%eax
  movsd  %xmm0,0x30(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movzbl 0x70(%rsp),%eax
  movsd  %xmm0,0x38(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  xor    %eax,%eax
  movsd  %xmm0,0x40(%rsp)
  pxor   %xmm0,%xmm0
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L21:
  addsd  (%rdx),%xmm0
  cmp    $0x9,%eax
  je     L0
L18:
  add    $0x8,%rdx
L39:
  add    $0x1,%eax
  cmp    $0x5,%eax
  jne    L21
  movsd  0x20(%rsp),%xmm1
  addsd  %xmm1,%xmm1
  movsd  %xmm1,0x20(%rsp)
  addsd  (%rdx),%xmm0
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L0:
  divsd  D2(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x58,%rsp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: f32[2]

tool: {"D2": [0.0,2.5625]}

assistant: ```c
unsigned char smoothing(unsigned char px0, unsigned char px1, unsigned char px2, unsigned char px3, unsigned char px4, unsigned char px5, unsigned char px6, unsigned char px7, unsigned char px8) {
  double px[9] = {px0, px1, px2, px3, px4, px5, px6, px7, px8};
  double px_out = 0.0;
  for (int i = 0; i < 9; i++) {
    if (i == 4) {
      px[i] *= 2;
    }
    px_out += px[i];
  }
  px_out /= 10;
  return (unsigned char)px_out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smoothing>:
  endbr64
  movzbl %sil,%esi
  pxor   %xmm1,%xmm1
  movzbl %dil,%edi
  movzbl %dl,%edx
  cvtsi2sd %esi,%xmm1
  pxor   %xmm0,%xmm0
  movzbl %cl,%ecx
  movzbl %r8b,%r8d
  cvtsi2sd %edi,%xmm0
  addsd  D4(%rip),%xmm0
  movzbl %r9b,%r9d
  movzbl 0x8(%rsp),%eax
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %r8d,%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r9d,%xmm1
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movzbl 0x10(%rsp),%eax
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movzbl 0x18(%rsp),%eax
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  divsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: f64
name: retrieve_data
arguments: data_tag: D6
data_type: byte[8]

tool: D4: 0

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
unsigned char smoothing(unsigned char px0, unsigned char px1, unsigned char px2, unsigned char px3, unsigned char px4, unsigned char px5, unsigned char px6, unsigned char px7, unsigned char px8) {
  double px[9] = {px0, px1, px2, px3, px4, px5, px6, px7, px8};
  double px_out = 0.0;
  for (int i = 0; i < 9; i++) {
    if (i == 4) {
      px[i] *= 2;
    }
    px_out += px[i];
  }
  px_out /= 10;
  return (unsigned char)px_out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: usage: %s gribfile


assistant: ```c
void usage(char *prog) {
  printf("usage: %s gribfile\n", prog);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: usage: %s gribfile


assistant: ```c
void usage(char *prog) {
  printf("usage: %s gribfile\n", prog);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: usage: %s gribfile


assistant: ```c
void usage(char *prog) {
  printf("usage: %s gribfile\n", prog);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: usage: %s gribfile


assistant: ```c
void usage(char *prog) {
  printf("usage: %s gribfile\n", prog);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<HEA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sar    $0x3,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sar    $0x2,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    %eax
  and    $0x1,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  sar    %eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x2,%eax
  and    $0x1,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  and    $0x1,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  or     -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x6,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t HEA(uint8_t A, uint8_t B) {
  uint8_t S0 = ((B & (0x8)) >> 3) + (A & (0x1));
  uint8_t S1 = ((B & (0x4)) >> 2) + ((A & (0x2)) >> 1);
  uint8_t S2 = ((B & (0x2)) >> 1) + ((A & (0x4)) >> 2);
  uint8_t S3 = (B & (0x1)) + ((A & (0x8)) >> 3);
  return S0 | (S1 << 2) | (S2 << 4) | (S3 << 6);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<HEA>:
  endbr64
  mov    %edi,%ecx
  mov    %esi,%edx
  mov    %edi,%eax
  sar    $0x3,%eax
  and    $0x1,%eax
  and    $0x1,%esi
  add    %esi,%eax
  shl    $0x6,%eax
  mov    %edx,%esi
  sar    $0x3,%esi
  and    $0x1,%esi
  and    $0x1,%edi
  add    %edi,%esi
  or     %esi,%eax
  mov    %edx,%esi
  sar    $0x2,%esi
  and    $0x1,%esi
  mov    %ecx,%edi
  sar    %edi
  and    $0x1,%edi
  add    %edi,%esi
  shl    $0x2,%esi
  or     %esi,%eax
  sar    %edx
  and    $0x1,%edx
  sar    $0x2,%ecx
  and    $0x1,%ecx
  add    %ecx,%edx
  shl    $0x4,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint8_t HEA(uint8_t A, uint8_t B) {
  uint8_t S0 = ((B & (0x8)) >> 3) + (A & (0x1));
  uint8_t S1 = ((B & (0x4)) >> 2) + ((A & (0x2)) >> 1);
  uint8_t S2 = ((B & (0x2)) >> 1) + ((A & (0x4)) >> 2);
  uint8_t S3 = (B & (0x1)) + ((A & (0x8)) >> 3);
  return S0 | (S1 << 2) | (S2 << 4) | (S3 << 6);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HEA>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  and    $0x1,%esi
  mov    %edi,%ecx
  sar    $0x3,%eax
  and    $0x1,%edi
  and    $0x1,%eax
  add    %esi,%eax
  mov    %edx,%esi
  sar    $0x3,%esi
  shl    $0x6,%eax
  and    $0x1,%esi
  add    %edi,%esi
  mov    %ecx,%edi
  sar    $0x2,%ecx
  or     %esi,%eax
  mov    %edx,%esi
  sar    %edi
  and    $0x1,%ecx
  sar    $0x2,%esi
  and    $0x1,%edi
  sar    %edx
  and    $0x1,%esi
  and    $0x1,%edx
  add    %edi,%esi
  add    %ecx,%edx
  shl    $0x2,%esi
  shl    $0x4,%edx
  or     %esi,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint8_t HEA(uint8_t A, uint8_t B) {
  uint8_t S0 = ((B & (0x8)) >> 3) + (A & (0x1));
  uint8_t S1 = ((B & (0x4)) >> 2) + ((A & (0x2)) >> 1);
  uint8_t S2 = ((B & (0x2)) >> 1) + ((A & (0x4)) >> 2);
  uint8_t S3 = (B & (0x1)) + ((A & (0x8)) >> 3);
  return S0 | (S1 << 2) | (S2 << 4) | (S3 << 6);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HEA>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  and    $0x1,%esi
  mov    %edi,%ecx
  sar    $0x3,%eax
  and    $0x1,%edi
  and    $0x1,%eax
  add    %esi,%eax
  mov    %edx,%esi
  sar    $0x3,%esi
  shl    $0x6,%eax
  and    $0x1,%esi
  add    %edi,%esi
  mov    %ecx,%edi
  sar    $0x2,%ecx
  or     %esi,%eax
  mov    %edx,%esi
  sar    %edi
  and    $0x1,%ecx
  sar    $0x2,%esi
  and    $0x1,%edi
  sar    %edx
  and    $0x1,%esi
  and    $0x1,%edx
  add    %edi,%esi
  add    %ecx,%edx
  shl    $0x2,%esi
  shl    $0x4,%edx
  or     %esi,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint8_t HEA(uint8_t A, uint8_t B) {
  uint8_t S0 = ((B & (0x8)) >> 3) + (A & (0x1));
  uint8_t S1 = ((B & (0x4)) >> 2) + ((A & (0x2)) >> 1);
  uint8_t S2 = ((B & (0x2)) >> 1) + ((A & (0x4)) >> 2);
  uint8_t S3 = (B & (0x1)) + ((A & (0x8)) >> 3);
  return S0 | (S1 << 2) | (S2 << 4) | (S3 << 6);
}
```