ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<ProgramUsage>:
  endbr64
  push   %rbx
  lea    D19(%rip),%rcx
  lea    D32(%rip),%rdx
  lea    D11(%rip),%rbx
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
data_type: string
name: disassemble_data
arguments: label: D32
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string
name: disassemble_data
arguments: label: D29
data_type: string

tool: D19: 2004-2005

tool: D32: 1.01

tool: D11: CDTEST

tool: D10: %s v%s - by Cyber Warrior X (c)%s


tool: D29: usage: %s <drive pathname as specified in cd.c>


assistant: ```c
void ProgramUsage() {
  printf("%s v%s - by Cyber Warrior X (c)%s\n", "CDTEST", "1.01", "2004-2005");
  printf("usage: %s <drive pathname as specified in cd.c>\n", "CDTEST");
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ProgramUsage>:
  endbr64
  push   %rbp
  lea    D45(%rip),%rbp
  xor    %eax,%eax
  lea    D16(%rip),%rcx
  mov    %rbp,%rsi
  lea    D41(%rip),%rdx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D45
datatype: string
name: extract_symbolic_data
arguments: tag: D16
datatype: string
name: extract_symbolic_data
arguments: tag: D41
datatype: string
name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D45: CDTEST

tool: D16: 2004-2005

tool: D41: 1.01

tool: D13: %s v%s - by Cyber Warrior X (c)%s


tool: D3: usage: %s <drive pathname as specified in cd.c>


assistant: ```c
void ProgramUsage() {
  printf("%s v%s - by Cyber Warrior X (c)%s\n", "CDTEST", "1.01", "2004-2005");
  printf("usage: %s <drive pathname as specified in cd.c>\n", "CDTEST");
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ProgramUsage>:
  endbr64
  push   %rbp
  lea    D35(%rip),%rbp
  xor    %eax,%eax
  lea    D19(%rip),%rcx
  mov    %rbp,%rsi
  lea    D30(%rip),%rdx
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D35
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D29
type_guessed: string
name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D35: CDTEST

tool: D19: 2004-2005

tool: D30: 1.01

tool: D29: %s v%s - by Cyber Warrior X (c)%s


tool: D1: usage: %s <drive pathname as specified in cd.c>


assistant: ```c
void ProgramUsage() {
  printf("%s v%s - by Cyber Warrior X (c)%s\n", "CDTEST", "1.01", "2004-2005");
  printf("usage: %s <drive pathname as specified in cd.c>\n", "CDTEST");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L40:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L40
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20048(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x20044(%rsp),%rdx
L36:
  movl   $0xffffffff,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L36
  mov    $0x0,%eax
L34:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x8011,%rax
  jne    L34
  mov    $0x0,%ebx
  mov    $0x0,%eax
  lea    D6(%rip),%rbp
  jmp    L70
L17:
  add    $0x1,%rbx
  cmp    $0x8011,%rbx
  je     L26
L70:
  mov    %ebx,%esi
  mov    (%rsp,%rbx,4),%edx
  cmp    %ebx,%edx
  je     L17
  mov    %ebx,%ecx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L17
L26:
  mov    0x20048(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L79
  add    $0x20058,%rsp
  pop    %rbx
  pop    %rbp
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: ary[%d]=%x expected %x


assistant: ```c
int main() {
  int ary[(32 * 32 * 32 + 17)];
  int ix;
  int exit = 0;
  int ondev = 0;
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++)
    ary[ix] = -1;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32) copy(ary) copy(ondev)
  {
#pragma acc loop gang worker vector
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      if (__builtin_acc_on_device(5)) {
        int g = 0, w = 0, v = 0;
        __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
        __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
        __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
        ary[ix] = (g << 16) | (w << 8) | v;
        ondev = 1;
      } else
        ary[ix] = ix;
    }
  }
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    int expected = ix;
    if (ondev) {
      int chunk_size = ((32 * 32 * 32 + 17) + 32 * 32 * 32 - 1) / (32 * 32 * 32);
      int g = ix / (chunk_size * 32 * 32);
      int w = ix / 32 % 32;
      int v = ix % 32;
      expected = (g << 16) | (w << 8) | v;
    }
    if (ary[ix] != expected) {
      exit = 1;
      printf("ary[%d]=%x expected %x\n", ix, ary[ix], expected);
    }
  }
  return exit;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x50,%rsp
  mov    $0x20044,%edx
  mov    $0xff,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x20048(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  xor    %eax,%eax
  nop
L11:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0x8011,%rax
  jne    L11
  xor    %ebx,%ebx
  xor    %eax,%eax
  lea    D7(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  cmp    %ebx,%edx
  je     L26
  mov    %ebx,%ecx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L26:
  add    $0x1,%rbx
  cmp    $0x8011,%rbx
  jne    L7
  mov    0x20048(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x20050,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: ary[%d]=%x expected %x


assistant: ```c
int main() {
  int ary[(32 * 32 * 32 + 17)];
  int ix;
  int exit = 0;
  int ondev = 0;
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++)
    ary[ix] = -1;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32) copy(ary) copy(ondev)
  {
#pragma acc loop gang worker vector
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      if (__builtin_acc_on_device(5)) {
        int g = 0, w = 0, v = 0;
        __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
        __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
        __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
        ary[ix] = (g << 16) | (w << 8) | v;
        ondev = 1;
      } else
        ary[ix] = ix;
    }
  }
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    int expected = ix;
    if (ondev) {
      int chunk_size = ((32 * 32 * 32 + 17) + 32 * 32 * 32 - 1) / (32 * 32 * 32);
      int g = ix / (chunk_size * 32 * 32);
      int w = ix / 32 % 32;
      int v = ix % 32;
      expected = (g << 16) | (w << 8) | v;
    }
    if (ary[ix] != expected) {
      exit = 1;
      printf("ary[%d]=%x expected %x\n", ix, ary[ix], expected);
    }
  }
  return exit;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x50,%rsp
  mov    $0x20044,%edx
  mov    $0xff,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x20048(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  movdqa D19(%rip),%xmm0
  movdqa D24(%rip),%xmm2
  lea    0x20040(%rsp),%rdx
  nopl   (%rax)
L20:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L20
  movl   $0x8010,0x20040(%rsp)
  xor    %ebx,%ebx
  xor    %eax,%eax
  lea    D21(%rip),%rbp
L5:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  cmp    %ebx,%edx
  je     L40
  mov    %ebx,%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L40:
  add    $0x1,%rbx
  cmp    $0x8011,%rbx
  jne    L5
  mov    0x20048(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x20050,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type: byte[16]
name: extract_symbolic_data
arguments: tag: D24
type: byte[16]
name: extract_symbolic_data
arguments: tag: D21
type: string

tool: {"D19": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D24": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D21: ary[%d]=%x expected %x


assistant: ```c
int main() {
  int ary[(32 * 32 * 32 + 17)];
  int ix;
  int exit = 0;
  int ondev = 0;
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++)
    ary[ix] = -1;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32) copy(ary) copy(ondev)
  {
#pragma acc loop gang worker vector
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      if (__builtin_acc_on_device(5)) {
        int g = 0, w = 0, v = 0;
        __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
        __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
        __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
        ary[ix] = (g << 16) | (w << 8) | v;
        ondev = 1;
      } else
        ary[ix] = ix;
    }
  }
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    int expected = ix;
    if (ondev) {
      int chunk_size = ((32 * 32 * 32 + 17) + 32 * 32 * 32 - 1) / (32 * 32 * 32);
      int g = ix / (chunk_size * 32 * 32);
      int w = ix / 32 % 32;
      int v = ix % 32;
      expected = (g << 16) | (w << 8) | v;
    }
    if (ary[ix] != expected) {
      exit = 1;
      printf("ary[%d]=%x expected %x\n", ix, ary[ix], expected);
    }
  }
  return exit;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SDHostDataWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L9:
  mov    -0x8(%rbp),%rax
  add    $0x224,%rax
  mov    (%rax),%rax
  and    $0x400,%eax
  test   %rax,%rax
  je     L9
  mov    -0x8(%rbp),%rax
  add    $0x220,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SDHostDataWrite(unsigned long ulBase, unsigned long ulData) {
  while (!((*((volatile unsigned long *)(ulBase + 0x00000224))) & (1 << 10))) {
  }
  (*((volatile unsigned long *)(ulBase + 0x00000220))) = ulData;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SDHostDataWrite>:
  endbr64
L7:
  mov    0x224(%rdi),%rax
  test   $0x4,%ah
  je     L7
  mov    %rsi,0x220(%rdi)
  ret
```

assistant: ```c
void SDHostDataWrite(unsigned long ulBase, unsigned long ulData) {
  while (!((*((volatile unsigned long *)(ulBase + 0x00000224))) & (1 << 10))) {
  }
  (*((volatile unsigned long *)(ulBase + 0x00000220))) = ulData;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SDHostDataWrite>:
  endbr64
  lea    0x224(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rdx),%rax
  test   $0x4,%ah
  je     L9
  mov    %rsi,0x220(%rdi)
  ret
```

assistant: ```c
void SDHostDataWrite(unsigned long ulBase, unsigned long ulData) {
  while (!((*((volatile unsigned long *)(ulBase + 0x00000224))) & (1 << 10))) {
  }
  (*((volatile unsigned long *)(ulBase + 0x00000220))) = ulData;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SDHostDataWrite>:
  endbr64
  lea    0x224(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rdx),%rax
  test   $0x4,%ah
  je     L4
  mov    %rsi,0x220(%rdi)
  ret
```

assistant: ```c
void SDHostDataWrite(unsigned long ulBase, unsigned long ulData) {
  while (!((*((volatile unsigned long *)(ulBase + 0x00000224))) & (1 << 10))) {
  }
  (*((volatile unsigned long *)(ulBase + 0x00000220))) = ulData;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memmove>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdx,%rsi
  cmp    %rcx,%rdi
  jbe    L94
  lea    (%rcx,%rdx,1),%rax
  cmp    %rax,%rdi
  jae    L94
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L118
L70:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L70
  jmp    L118
L94:
  cmp    $0x1f,%rsi
  jbe    L33
  mov    %rdi,%r8
  or     %rcx,%r8
  and    $0x7,%r8d
  je     L109
  lea    -0x1(%rsi),%r8
  mov    %rdi,%rdx
  jmp    L146
L33:
  mov    %rdi,%rdx
L128:
  lea    -0x1(%rsi),%r8
  test   %rsi,%rsi
  je     L118
L146:
  mov    $0x0,%eax
L77:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%rdx,%rax,1)
  mov    %rax,%rsi
  add    $0x1,%rax
  cmp    %rsi,%r8
  jne    L77
L118:
  mov    %rdi,%rax
  ret
L139:
  mov    %rax,%rsi
  jmp    L128
L109:
  lea    -0x20(%rsi),%rax
  and    $0xffffffffffffffe0,%rax
  lea    0x20(%rax),%r11
  lea    (%rdi,%r11,1),%r10
  mov    %rcx,%rax
  mov    %rdi,%rdx
L81:
  mov    (%rax),%r9
  mov    %r9,(%rdx)
  mov    0x8(%rax),%r9
  mov    %r9,0x8(%rdx)
  mov    0x10(%rax),%r9
  mov    %r9,0x10(%rdx)
  add    $0x20,%rax
  add    $0x20,%rdx
  mov    -0x8(%rax),%r9
  mov    %r9,-0x8(%rdx)
  cmp    %rdx,%r10
  jne    L81
  add    %r11,%rcx
  mov    %rsi,%rax
  and    $0x1f,%eax
  test   $0x18,%sil
  je     L139
  sub    $0x8,%rax
  shr    $0x3,%rax
  lea    0x1(%rax),%r10
L135:
  mov    (%rcx,%r8,8),%r9
  mov    %r9,(%rdx,%r8,8)
  mov    %r8,%r9
  add    $0x1,%r8
  cmp    %rax,%r9
  jne    L135
  lea    0x0(,%r10,8),%rax
  add    %rax,%rcx
  add    %rax,%rdx
  and    $0x7,%esi
  jmp    L128
```

assistant: ```c
void *memmove(void *dst_void, const void *src_void, size_t length) {
  char *dst = dst_void;
  const char *src = src_void;
  long *aligned_dst;
  const long *aligned_src;
  if (src < dst && dst < src + length) {
    src += length;
    dst += length;
    while (length--)
      *--dst = *--src;
  } else {
    if (!((length) < (sizeof(long) << 2)) && !(((long)src & (sizeof(long) - 1)) | ((long)dst & (sizeof(long) - 1)))) {
      aligned_dst = (long *)dst;
      aligned_src = (long *)src;
      while (length >= (sizeof(long) << 2)) {
        *aligned_dst++ = *aligned_src++;
        *aligned_dst++ = *aligned_src++;
        *aligned_dst++ = *aligned_src++;
        *aligned_dst++ = *aligned_src++;
        length -= (sizeof(long) << 2);
      }
      while (length >= (sizeof(long))) {
        *aligned_dst++ = *aligned_src++;
        length -= (sizeof(long));
      }
      dst = (char *)aligned_dst;
      src = (char *)aligned_src;
    }
    while (length--)
      *dst++ = *src++;
  }
  return dst_void;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memmove>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%r8
  mov    %rdx,%rsi
  cmp    %rcx,%rdi
  jbe    L99
  lea    (%rcx,%rdx,1),%rax
  cmp    %rax,%rdi
  jae    L99
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L33
  nopl   0x0(%rax)
L19:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  sub    $0x1,%rax
  jae    L19
L33:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L99:
  cmp    $0x1f,%rsi
  ja     L103
  mov    %r8,%rdx
L8:
  lea    -0x1(%rsi),%rdi
  test   %rsi,%rsi
  je     L33
L6:
  xor    %eax,%eax
  nopl   0x0(%rax)
L21:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%rdx,%rax,1)
  mov    %rax,%rsi
  add    $0x1,%rax
  cmp    %rsi,%rdi
  jne    L21
  mov    %r8,%rax
  ret
L103:
  mov    %r8,%rdi
  or     %rcx,%rdi
  and    $0x7,%edi
  jne    L16
  lea    -0x20(%rsi),%rax
  mov    %r8,%rdx
  and    $0xffffffffffffffe0,%rax
  lea    0x20(%rax),%r11
  mov    %rcx,%rax
  lea    (%r8,%r11,1),%r10
  nopl   (%rax)
L121:
  mov    (%rax),%r9
  add    $0x20,%rax
  add    $0x20,%rdx
  mov    %r9,-0x20(%rdx)
  mov    -0x18(%rax),%r9
  mov    %r9,-0x18(%rdx)
  mov    -0x10(%rax),%r9
  mov    %r9,-0x10(%rdx)
  mov    -0x8(%rax),%r9
  mov    %r9,-0x8(%rdx)
  cmp    %rdx,%r10
  jne    L121
  mov    %rsi,%rax
  add    %r11,%rcx
  and    $0x1f,%eax
  test   $0x18,%sil
  je     L94
L27:
  mov    (%rcx,%rdi,1),%r9
  mov    %r9,(%rdx,%rdi,1)
  add    $0x8,%rdi
  mov    %rax,%r9
  sub    %rdi,%r9
  cmp    $0x7,%r9
  ja     L27
  sub    $0x8,%rax
  and    $0x7,%esi
  shr    $0x3,%rax
  lea    0x8(,%rax,8),%rax
  add    %rax,%rdx
  add    %rax,%rcx
  jmp    L8
  nopl   0x0(%rax)
L16:
  lea    -0x1(%rsi),%rdi
  mov    %r8,%rdx
  jmp    L6
L94:
  mov    %rax,%rsi
  jmp    L8
```

assistant: ```c
void *memmove(void *dst_void, const void *src_void, size_t length) {
  char *dst = dst_void;
  const char *src = src_void;
  long *aligned_dst;
  const long *aligned_src;
  if (src < dst && dst < src + length) {
    src += length;
    dst += length;
    while (length--)
      *--dst = *--src;
  } else {
    if (!((length) < (sizeof(long) << 2)) && !(((long)src & (sizeof(long) - 1)) | ((long)dst & (sizeof(long) - 1)))) {
      aligned_dst = (long *)dst;
      aligned_src = (long *)src;
      while (length >= (sizeof(long) << 2)) {
        *aligned_dst++ = *aligned_src++;
        *aligned_dst++ = *aligned_src++;
        *aligned_dst++ = *aligned_src++;
        *aligned_dst++ = *aligned_src++;
        length -= (sizeof(long) << 2);
      }
      while (length >= (sizeof(long))) {
        *aligned_dst++ = *aligned_src++;
        length -= (sizeof(long));
      }
      dst = (char *)aligned_dst;
      src = (char *)aligned_src;
    }
    while (length--)
      *dst++ = *src++;
  }
  return dst_void;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<build_second>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D18
type_guessed: string

tool: D17: %*d:%*d:%d

tool: D18: 16:19:17

assistant: ```c
int build_second() {
  int s;
  sscanf("16:19:17", "%*d:%*d:%d", &s);
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<build_second>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    D15(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string

tool: D15: %*d:%*d:%d

tool: D14: 16:19:17

assistant: ```c
int build_second() {
  int s;
  sscanf("16:19:17", "%*d:%*d:%d", &s);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<build_second>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rsi
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D12
type_guessed: string

tool: D6: %*d:%*d:%d

tool: D12: 16:19:17

assistant: ```c
int build_second() {
  int s;
  sscanf("16:19:17", "%*d:%*d:%d", &s);
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<build_second>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rsi
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string

tool: D19: %*d:%*d:%d

tool: D6: 16:19:17

assistant: ```c
int build_second() {
  int s;
  sscanf("16:19:17", "%*d:%*d:%d", &s);
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
main() {
  int a[4];
  __typeof(a) b;
  __typeof(int[4]) c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int a[4];
  __typeof(a) b;
  __typeof(int[4]) c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int a[4];
  __typeof(a) b;
  __typeof(int[4]) c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int a[4];
  __typeof(a) b;
  __typeof(int[4]) c;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_bzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void test_bzero() {
  int n = 1;
  bzero(&n, sizeof(int));
  assert(n == 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_bzero>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x4,%esi
  call   <bzero@plt>
  cmpl   $0x1,0x4(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_bzero() {
  int n = 1;
  bzero(&n, sizeof(int));
  assert(n == 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_bzero>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x1,0x4(%rsp)
  call   <bzero@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x4(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_bzero() {
  int n = 1;
  bzero(&n, sizeof(int));
  assert(n == 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_bzero>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x1,0x4(%rsp)
  call   <bzero@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x4(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_bzero() {
  int n = 1;
  bzero(&n, sizeof(int));
  assert(n == 1);
}
```