ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<TimerCHNConfigure>:
  endbr64
  lea    -0x4(,%rsi,4),%ecx
  mov    0x20(%rdi),%rsi
  mov    $0x4,%eax
  shl    %cl,%eax
  cltq
  not    %rax
  and    %rsi,%rax
  mov    %rax,0x20(%rdi)
  mov    0x20(%rdi),%rax
  shl    %cl,%rdx
  or     %rax,%rdx
  mov    %rdx,0x20(%rdi)
  ret
```

assistant: ```c
void TimerCHNConfigure(unsigned long ulBase, unsigned long ulChannel, unsigned long ulCCxN) {
  unsigned long ulTemp = 0;

  ;

  ;

  ;
  ulTemp = (0x00000004 << ((ulChannel - 1) * 4));
  (*((volatile unsigned long *)(ulBase + 0x00000020))) &= ~ulTemp;
  (*((volatile unsigned long *)(ulBase + 0x00000020))) |= ulCCxN << ((ulChannel - 1) * 4);
}
```
user: What is the c source code of the assembly code below?

```asm
<TimerCHNConfigure>:
  endbr64
  lea    -0x4(,%rsi,4),%ecx
  mov    $0x4,%eax
  mov    0x20(%rdi),%rsi
  shl    %cl,%eax
  shl    %cl,%rdx
  cltq
  not    %rax
  and    %rsi,%rax
  mov    %rax,0x20(%rdi)
  mov    0x20(%rdi),%rax
  or     %rax,%rdx
  mov    %rdx,0x20(%rdi)
  ret
```

assistant: ```c
void TimerCHNConfigure(unsigned long ulBase, unsigned long ulChannel, unsigned long ulCCxN) {
  unsigned long ulTemp = 0;

  ;

  ;

  ;
  ulTemp = (0x00000004 << ((ulChannel - 1) * 4));
  (*((volatile unsigned long *)(ulBase + 0x00000020))) &= ~ulTemp;
  (*((volatile unsigned long *)(ulBase + 0x00000020))) |= ulCCxN << ((ulChannel - 1) * 4);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TimerCHNConfigure>:
  endbr64
  lea    -0x4(,%rsi,4),%ecx
  mov    $0x4,%eax
  mov    0x20(%rdi),%rsi
  shl    %cl,%eax
  shl    %cl,%rdx
  cltq
  not    %rax
  and    %rsi,%rax
  mov    %rax,0x20(%rdi)
  mov    0x20(%rdi),%rax
  or     %rax,%rdx
  mov    %rdx,0x20(%rdi)
  ret
```

assistant: ```c
void TimerCHNConfigure(unsigned long ulBase, unsigned long ulChannel, unsigned long ulCCxN) {
  unsigned long ulTemp = 0;

  ;

  ;

  ;
  ulTemp = (0x00000004 << ((ulChannel - 1) * 4));
  (*((volatile unsigned long *)(ulBase + 0x00000020))) &= ~ulTemp;
  (*((volatile unsigned long *)(ulBase + 0x00000020))) |= ulCCxN << ((ulChannel - 1) * 4);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<myStrLen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L19:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int myStrLen(char *pStr) {
  int ii = 0;
  while (*pStr++ != '\n')
    ii++;
  return ii;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<myStrLen>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0xa,(%rdi)
  je     L0
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L15:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rax)
  jne    L15
L4:
  mov    %ecx,%eax
  ret
L0:
  mov    $0x0,%ecx
  jmp    L4
```

assistant: ```c
int myStrLen(char *pStr) {
  int ii = 0;
  while (*pStr++ != '\n')
    ii++;
  return ii;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<myStrLen>:
  endbr64
  cmpb   $0xa,(%rdi)
  lea    0x1(%rdi),%rax
  je     L9
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L4:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rax)
  jne    L4
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int myStrLen(char *pStr) {
  int ii = 0;
  while (*pStr++ != '\n')
    ii++;
  return ii;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<myStrLen>:
  endbr64
  cmpb   $0xa,(%rdi)
  lea    0x1(%rdi),%rax
  je     L12
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L6:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rax)
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int myStrLen(char *pStr) {
  int ii = 0;
  while (*pStr++ != '\n')
    ii++;
  return ii;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<runhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sha256_transform@plt>
  nop
  leave
  ret
```

assistant: ```c
void runhash(void *state, const void *input, const void *init) {
  memcpy(state, init, 32);
  sha256_transform((uint32_t *)state, (uint8_t *)input);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<runhash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    $0x20,%edx
  call   <memcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sha256_transform@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void runhash(void *state, const void *input, const void *init) {
  memcpy(state, init, 32);
  sha256_transform((uint32_t *)state, (uint8_t *)input);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<runhash>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    $0x20,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <sha256_transform@plt>
```

assistant: ```c
void runhash(void *state, const void *input, const void *init) {
  memcpy(state, init, 32);
  sha256_transform((uint32_t *)state, (uint8_t *)input);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<runhash>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    $0x20,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <sha256_transform@plt>
```

assistant: ```c
void runhash(void *state, const void *input, const void *init) {
  memcpy(state, init, 32);
  sha256_transform((uint32_t *)state, (uint8_t *)input);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<I2CSlaveAddressSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <I2CSlaveBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmpb   $0x1,-0xc(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  movzbl -0x10(%rbp),%eax
  not    %eax
  shr    $0x7,%al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  movzbl -0xc(%rbp),%eax
  test   %eax,%eax
  je     L27
  cmp    $0x1,%eax
  je     L15
  jmp    L7
L27:
  mov    -0x8(%rbp),%rax
  movzbl -0x10(%rbp),%edx
  mov    %rdx,(%rax)
  jmp    L7
L15:
  movzbl -0x10(%rbp),%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  mov    %rax,%rcx
  movzbl %dl,%eax
  mov    %rax,(%rcx)
  nop
L7:
  nop
  leave
  ret
```

assistant: ```c
void I2CSlaveAddressSet(unsigned long ulBase, unsigned char ucAddrNum, unsigned char ucSlaveAddr) {
  DEBUG_ASSERT(I2CSlaveBaseValid(ulBase));
  DEBUG_ASSERT(!(ucAddrNum > 1));
  DEBUG_ASSERT(!(ucSlaveAddr & 0x80));
  switch (ucAddrNum) {
  case 0: {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) = ucSlaveAddr;
    break;
  }
  case 1: {
    (*((volatile unsigned long *)(ulBase + 0x0000001C))) = 0x00000080 | ucSlaveAddr;
    break;
  }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<I2CSlaveAddressSet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  call   <I2CSlaveBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmp    $0x1,%bpl
  setbe  %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  movsbl %bl,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <DEBUG_ASSERT@plt>
  test   %bpl,%bpl
  je     L14
  cmp    $0x1,%bpl
  je     L7
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  movzbl %bl,%ebx
  mov    %rbx,(%r12)
  jmp    L10
L7:
  or     $0xffffff80,%ebx
  movzbl %bl,%ebx
  mov    %rbx,0x1c(%r12)
  jmp    L10
```

assistant: ```c
void I2CSlaveAddressSet(unsigned long ulBase, unsigned char ucAddrNum, unsigned char ucSlaveAddr) {
  DEBUG_ASSERT(I2CSlaveBaseValid(ulBase));
  DEBUG_ASSERT(!(ucAddrNum > 1));
  DEBUG_ASSERT(!(ucSlaveAddr & 0x80));
  switch (ucAddrNum) {
  case 0: {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) = ucSlaveAddr;
    break;
  }
  case 1: {
    (*((volatile unsigned long *)(ulBase + 0x0000001C))) = 0x00000080 | ucSlaveAddr;
    break;
  }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<I2CSlaveAddressSet>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <I2CSlaveBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x1,%bpl
  setbe  %dil
  call   <DEBUG_ASSERT@plt>
  movsbl %bl,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <DEBUG_ASSERT@plt>
  test   %bpl,%bpl
  je     L8
  cmp    $0x1,%bpl
  jne    L5
  or     $0xffffff80,%ebx
  movzbl %bl,%ebx
  mov    %rbx,0x1c(%r12)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl %bl,%ebx
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void I2CSlaveAddressSet(unsigned long ulBase, unsigned char ucAddrNum, unsigned char ucSlaveAddr) {
  DEBUG_ASSERT(I2CSlaveBaseValid(ulBase));
  DEBUG_ASSERT(!(ucAddrNum > 1));
  DEBUG_ASSERT(!(ucSlaveAddr & 0x80));
  switch (ucAddrNum) {
  case 0: {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) = ucSlaveAddr;
    break;
  }
  case 1: {
    (*((volatile unsigned long *)(ulBase + 0x0000001C))) = 0x00000080 | ucSlaveAddr;
    break;
  }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<I2CSlaveAddressSet>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <I2CSlaveBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x1,%bpl
  setbe  %dil
  call   <DEBUG_ASSERT@plt>
  movsbl %bl,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <DEBUG_ASSERT@plt>
  test   %bpl,%bpl
  je     L18
  cmp    $0x1,%bpl
  jne    L10
  or     $0xffffff80,%ebx
  movzbl %bl,%ebx
  mov    %rbx,0x1c(%r12)
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl %bl,%ebx
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void I2CSlaveAddressSet(unsigned long ulBase, unsigned char ucAddrNum, unsigned char ucSlaveAddr) {
  DEBUG_ASSERT(I2CSlaveBaseValid(ulBase));
  DEBUG_ASSERT(!(ucAddrNum > 1));
  DEBUG_ASSERT(!(ucSlaveAddr & 0x80));
  switch (ucAddrNum) {
  case 0: {
    (*((volatile unsigned long *)(ulBase + 0x00000000))) = ucSlaveAddr;
    break;
  }
  case 1: {
    (*((volatile unsigned long *)(ulBase + 0x0000001C))) = 0x00000080 | ucSlaveAddr;
    break;
  }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x48(%rbp)
  movl   $0x1,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x1,-0x38(%rbp)
  movl   $0x2,-0x34(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x4,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  lea    -0x40(%rbp),%rcx
  lea    -0x48(%rbp),%rax
  mov    $0xb,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mk_list@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <deleteDuplicates@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  struct ListNode *head = NULL;
  int a[] = {1, 1, 1, 2, 2, 3, 4, 4, 5, 6, 6};
  mk_list(&head, a, 11);
  print(head);
  head = deleteDuplicates(head);
  print(head);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  movl   $0x4,0x28(%rsp)
  movl   $0x4,0x2c(%rsp)
  movl   $0x5,0x30(%rsp)
  movl   $0x6,0x34(%rsp)
  movl   $0x6,0x38(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0xb,%edx
  call   <mk_list@plt>
  mov    0x8(%rsp),%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rdi
  call   <deleteDuplicates@plt>
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <print@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct ListNode *head = NULL;
  int a[] = {1, 1, 1, 2, 2, 3, 4, 4, 5, 6, 6};
  mk_list(&head, a, 11);
  print(head);
  head = deleteDuplicates(head);
  print(head);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0xb,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movabs $0x100000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x400000004,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x600000005,%rax
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x30(%rsp)
  movl   $0x6,0x38(%rsp)
  call   <mk_list@plt>
  mov    0x8(%rsp),%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rdi
  call   <deleteDuplicates@plt>
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <print@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct ListNode *head = NULL;
  int a[] = {1, 1, 1, 2, 2, 3, 4, 4, 5, 6, 6};
  mk_list(&head, a, 11);
  print(head);
  head = deleteDuplicates(head);
  print(head);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  movdqa D26(%rip),%xmm0
  mov    $0xb,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D5(%rip),%xmm0
  movq   $0x0,0x8(%rsp)
  movaps %xmm0,0x20(%rsp)
  mov    %rax,0x30(%rsp)
  movl   $0x6,0x38(%rsp)
  call   <mk_list@plt>
  mov    0x8(%rsp),%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rdi
  call   <deleteDuplicates@plt>
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <print@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D8
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D5
type_infered: byte[16]

tool: {"D26": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D8": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D5": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  struct ListNode *head = NULL;
  int a[] = {1, 1, 1, 2, 2, 3, 4, 4, 5, 6, 6};
  mk_list(&head, a, 11);
  print(head);
  head = deleteDuplicates(head);
  print(head);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<add_strings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <safe_malloc@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *add_strings(s1, s2)
char *s1, *s2;
{
  char *buf_start, *buf_cp;
  int len1, len2;
  len1 = strlen(s1);
  len2 = strlen(s2);
  buf_start = safe_malloc(len1 + len2 + 1);
  strcpy(buf_start, s1);
  buf_cp = buf_start + len1;
  strcpy(buf_cp, s2);
  return buf_start;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<add_strings>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  mov    $0x0,%eax
  call   <safe_malloc@plt>
  movslq %eax,%rbp
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  movslq %ebx,%rdi
  add    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *add_strings(s1, s2)
char *s1, *s2;
{
  char *buf_start, *buf_cp;
  int len1, len2;
  len1 = strlen(s1);
  len2 = strlen(s2);
  buf_start = safe_malloc(len1 + len2 + 1);
  strcpy(buf_start, s1);
  buf_cp = buf_start + len1;
  strcpy(buf_cp, s2);
  return buf_start;
}
```
user: What is the c source code of the assembly code below:

```asm
<add_strings>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  xor    %eax,%eax
  call   <safe_malloc@plt>
  mov    %r13,%rsi
  movslq %eax,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  movslq %ebx,%rdi
  mov    %rbp,%rsi
  add    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *add_strings(s1, s2)
char *s1, *s2;
{
  char *buf_start, *buf_cp;
  int len1, len2;
  len1 = strlen(s1);
  len2 = strlen(s2);
  buf_start = safe_malloc(len1 + len2 + 1);
  strcpy(buf_start, s1);
  buf_cp = buf_start + len1;
  strcpy(buf_cp, s2);
  return buf_start;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<add_strings>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  xor    %eax,%eax
  call   <safe_malloc@plt>
  mov    %r13,%rsi
  movslq %eax,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  movslq %ebx,%rdi
  mov    %rbp,%rsi
  add    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *add_strings(s1, s2)
char *s1, *s2;
{
  char *buf_start, *buf_cp;
  int len1, len2;
  len1 = strlen(s1);
  len2 = strlen(s2);
  buf_start = safe_malloc(len1 + len2 + 1);
  strcpy(buf_start, s1);
  buf_cp = buf_start + len1;
  strcpy(buf_cp, s2);
  return buf_start;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_constexpr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x4d,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/sizeof.c

assistant: ```c
void test_constexpr() {
  char a[sizeof(char[4])];
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/sizeof.c", 77, 4, sizeof(a));
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_constexpr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x4d,%esi
  lea    D8(%rip),%rdi
  call   <fexpect@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/sizeof.c

assistant: ```c
void test_constexpr() {
  char a[sizeof(char[4])];
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/sizeof.c", 77, 4, sizeof(a));
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_constexpr>:
  endbr64
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x4d,%esi
  lea    D7(%rip),%rdi
  jmp    1050 <fexpect@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/sizeof.c

assistant: ```c
void test_constexpr() {
  char a[sizeof(char[4])];
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/sizeof.c", 77, 4, sizeof(a));
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_constexpr>:
  endbr64
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x4d,%esi
  lea    D3(%rip),%rdi
  jmp    1050 <fexpect@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/sizeof.c

assistant: ```c
void test_constexpr() {
  char a[sizeof(char[4])];
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/sizeof.c", 77, 4, sizeof(a));
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<numl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  test   %eax,%eax
  je     L10
  cmp    $0xa,%eax
  je     L37
  jmp    L26
L37:
  addl   $0x1,-0x4(%rbp)
  jmp    L26
L10:
  nop
  jmp    L34
L26:
  jmp    L1
L34:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int numl(const char *s) {
  int i = 0;
  for (;;) {
    switch (*s++) {
    case '\0':
      break;
    case '\n':
      i++;
    default:
      continue;
    }
    break;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<numl>:
  endbr64
  mov    $0x0,%edx
  jmp    L4
L10:
  cmp    $0xa,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
L4:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
  mov    %edx,%eax
  ret
```

assistant: ```c
int numl(const char *s) {
  int i = 0;
  for (;;) {
    switch (*s++) {
    case '\0':
      break;
    case '\n':
      i++;
    default:
      continue;
    }
    break;
  }
  return i;
}
```