ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_atoi>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  lea    D7(%rip),%r12
  jmp    L52
L40:
  cmp    $0x2d,%al
  je     L38
  lea    0x0(%r13,%r13,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%r13d
L38:
  add    $0x1,%rbx
L52:
  mov    %rbp,%rdi
  call   <str_len@plt>
  cmp    %ebx,%eax
  jle    L5
  movzbl 0x0(%rbp,%rbx,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L40
  cmp    $0x2d,%al
  je     L40
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L38
L5:
  mov    %r13d,%eax
  neg    %eax
  cmpb   $0x2d,0x0(%rbp)
  cmove  %eax,%r13d
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: Invalid input!

assistant: ```c
int my_atoi(char num[]) {
  int i;
  int n;
  n = 0;
  for (i = 0; i < str_len(num); i++) {
    if (((num[i] >= '0') && (num[i] <= '9')) || (num[i] == '-')) {
      if (num[i] != '-') {
        n = n * 10 + (num[i] - '0');
      }
    } else {
      printf("Invalid input!");
      exit(0);
    }
  }
  if (num[0] == '-') {
    return (~(n) + 1);
  } else {
    return n;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_atoi>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L5
  nop
L50:
  cmp    $0x2d,%al
  je     L23
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
L23:
  add    $0x1,%rbx
L5:
  mov    %rbp,%rdi
  call   <str_len@plt>
  cmp    %ebx,%eax
  jle    L32
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L50
  cmp    $0x2d,%al
  je     L23
  lea    0x0(%r13,%r13,4),%edx
  lea    -0x30(%rax,%rdx,2),%r13d
  jmp    L23
L32:
  mov    %r13d,%eax
  neg    %eax
  cmpb   $0x2d,0x0(%rbp)
  cmove  %eax,%r13d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: Invalid input!

assistant: ```c
int my_atoi(char num[]) {
  int i;
  int n;
  n = 0;
  for (i = 0; i < str_len(num); i++) {
    if (((num[i] >= '0') && (num[i] <= '9')) || (num[i] == '-')) {
      if (num[i] != '-') {
        n = n * 10 + (num[i] - '0');
      }
    } else {
      printf("Invalid input!");
      exit(0);
    }
  }
  if (num[0] == '-') {
    return (~(n) + 1);
  } else {
    return n;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_atoi>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L24
  nop
L28:
  cmp    $0x2d,%al
  je     L59
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
L59:
  add    $0x1,%rbx
L24:
  mov    %rbp,%rdi
  call   <str_len@plt>
  cmp    %ebx,%eax
  jle    L45
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L28
  cmp    $0x2d,%al
  je     L59
  lea    0x0(%r13,%r13,4),%edx
  lea    -0x30(%rax,%rdx,2),%r13d
  jmp    L59
L45:
  mov    %r13d,%eax
  neg    %eax
  cmpb   $0x2d,0x0(%rbp)
  cmove  %eax,%r13d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: Invalid input!

assistant: ```c
int my_atoi(char num[]) {
  int i;
  int n;
  n = 0;
  for (i = 0; i < str_len(num); i++) {
    if (((num[i] >= '0') && (num[i] <= '9')) || (num[i] == '-')) {
      if (num[i] != '-') {
        n = n * 10 + (num[i] - '0');
      }
    } else {
      printf("Invalid input!");
      exit(0);
    }
  }
  if (num[0] == '-') {
    return (~(n) + 1);
  } else {
    return n;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isup_put_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L58
  mov    -0x30(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L33
L58:
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L33
L43:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L50
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <char2digit@plt>
  and    $0xf,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  mov    %edx,%ecx
  mov    %esi,%edx
  or     %edx,%ecx
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L41
L50:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <char2digit@plt>
  shl    $0x4,%eax
  and    $0xf0,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  mov    %edx,%ecx
  mov    %esi,%edx
  or     %edx,%ecx
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L41:
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L43
  nop
  nop
  leave
  ret
```

assistant: ```c
void isup_put_number(unsigned char *dest, char *src, int *len, int *oddeven) {
  int i = 0;
  int numlen = strlen(src);
  if (numlen % 2) {
    *oddeven = 1;
    *len = numlen / 2 + 1;
  } else {
    *oddeven = 0;
    *len = numlen / 2;
  }
  while (i < numlen) {
    if (!(i % 2)) {
      dest[i / 2] |= char2digit(src[i]) & 0xf;
    } else {
      dest[i / 2] |= (char2digit(src[i]) << 4) & 0xf0;
    }
    i++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isup_put_number>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   $0x1,%al
  je     L24
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  add    $0x1,%edx
  mov    $0x1,%ecx
L6:
  mov    %ecx,(%r12)
  mov    %edx,(%rbx)
  test   %eax,%eax
  jle    L35
  mov    %eax,%r12d
  mov    $0x0,%ebx
  jmp    L12
L24:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    $0x0,%ecx
  jmp    L6
L36:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <char2digit@plt>
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  movslq %edx,%rdx
  shl    $0x4,%eax
  or     %al,0x0(%rbp,%rdx,1)
L19:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L35
L12:
  test   $0x1,%bl
  jne    L36
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <char2digit@plt>
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  movslq %edx,%rdx
  and    $0xf,%eax
  or     %al,0x0(%rbp,%rdx,1)
  jmp    L19
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void isup_put_number(unsigned char *dest, char *src, int *len, int *oddeven) {
  int i = 0;
  int numlen = strlen(src);
  if (numlen % 2) {
    *oddeven = 1;
    *len = numlen / 2 + 1;
  } else {
    *oddeven = 0;
    *len = numlen / 2;
  }
  while (i < numlen) {
    if (!(i % 2)) {
      dest[i / 2] |= char2digit(src[i]) & 0xf;
    } else {
      dest[i / 2] |= (char2digit(src[i]) << 4) & 0xf0;
    }
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isup_put_number>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  test   $0x1,%al
  je     L22
  add    $0x1,%edx
  mov    $0x1,%ecx
L22:
  mov    %ecx,0x0(%r13)
  xor    %r14d,%r14d
  lea    -0x1(%rax),%r13d
  mov    %edx,(%rbx)
  test   %eax,%eax
  jg     L41
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L46:
  call   <char2digit@plt>
  and    $0xf,%eax
  or     (%rbx),%al
  mov    %al,(%rbx)
  lea    0x1(%r14),%rax
  cmp    %r13,%r14
  je     L34
L48:
  mov    %rax,%r14
L41:
  mov    %r14d,%ebx
  movsbl 0x0(%rbp,%r14,1),%edi
  sar    %ebx
  movslq %ebx,%rbx
  add    %r12,%rbx
  test   $0x1,%r14b
  je     L46
  call   <char2digit@plt>
  shl    $0x4,%eax
  or     (%rbx),%al
  mov    %al,(%rbx)
  lea    0x1(%r14),%rax
  cmp    %r13,%r14
  jne    L48
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void isup_put_number(unsigned char *dest, char *src, int *len, int *oddeven) {
  int i = 0;
  int numlen = strlen(src);
  if (numlen % 2) {
    *oddeven = 1;
    *len = numlen / 2 + 1;
  } else {
    *oddeven = 0;
    *len = numlen / 2;
  }
  while (i < numlen) {
    if (!(i % 2)) {
      dest[i / 2] |= char2digit(src[i]) & 0xf;
    } else {
      dest[i / 2] |= (char2digit(src[i]) << 4) & 0xf0;
    }
    i++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isup_put_number>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  test   $0x1,%al
  je     L8
  add    $0x1,%edx
  mov    $0x1,%ecx
L8:
  mov    %ecx,0x0(%r13)
  xor    %r14d,%r14d
  lea    -0x1(%rax),%r13d
  mov    %edx,(%rbx)
  test   %eax,%eax
  jg     L39
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L33:
  call   <char2digit@plt>
  and    $0xf,%eax
  or     %al,(%rbx)
  lea    0x1(%r14),%rax
  cmp    %r13,%r14
  je     L26
L15:
  mov    %rax,%r14
L39:
  mov    %r14d,%ebx
  movsbl 0x0(%rbp,%r14,1),%edi
  sar    %ebx
  movslq %ebx,%rbx
  add    %r12,%rbx
  test   $0x1,%r14b
  je     L33
  call   <char2digit@plt>
  shl    $0x4,%eax
  or     %al,(%rbx)
  lea    0x1(%r14),%rax
  cmp    %r13,%r14
  jne    L15
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void isup_put_number(unsigned char *dest, char *src, int *len, int *oddeven) {
  int i = 0;
  int numlen = strlen(src);
  if (numlen % 2) {
    *oddeven = 1;
    *len = numlen / 2 + 1;
  } else {
    *oddeven = 0;
    *len = numlen / 2;
  }
  while (i < numlen) {
    if (!(i % 2)) {
      dest[i / 2] |= char2digit(src[i]) & 0xf;
    } else {
      dest[i / 2] |= (char2digit(src[i]) << 4) & 0xf0;
    }
    i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L0
  lea    -0x14(%rbp),%rax
  jmp    L12
L0:
  lea    -0x18(%rbp),%rax
L12:
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x18(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void hr(int *ed, signed char *ju) {
  int kc;
  {
    int xj;
    int *q2 = (*ed == 0) ? &xj : &kc;
    *ju = 0;
    kc = *ju;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hr>:
  endbr64
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void hr(int *ed, signed char *ju) {
  int kc;
  {
    int xj;
    int *q2 = (*ed == 0) ? &xj : &kc;
    *ju = 0;
    kc = *ju;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hr>:
  endbr64
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void hr(int *ed, signed char *ju) {
  int kc;
  {
    int xj;
    int *q2 = (*ed == 0) ? &xj : &kc;
    *ju = 0;
    kc = *ju;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<console_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %rdi,-0x1d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L14
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L14:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x1d8(%rbp),%rdx
  mov    -0x1c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x1c4(%rbp),%edx
  mov    -0x1d8(%rbp),%rcx
  lea    -0x1c0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0x1c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: %s


assistant: ```c
void console_log(const char *tmplt, ...) {
  char buffer[256];
  va_list marker;
  va_start(marker, tmplt);
  vsprintf(buffer, tmplt, marker);
  va_end(marker);
  printf("%s\n", buffer);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<console_log>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string

tool: D8: %s


assistant: ```c
void console_log(const char *tmplt, ...) {
  char buffer[256];
  va_list marker;
  va_start(marker, tmplt);
  vsprintf(buffer, tmplt, marker);
  va_end(marker);
  printf("%s\n", buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<console_log>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: %s


assistant: ```c
void console_log(const char *tmplt, ...) {
  char buffer[256];
  va_list marker;
  va_start(marker, tmplt);
  vsprintf(buffer, tmplt, marker);
  va_end(marker);
  printf("%s\n", buffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<console_log>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: %s


assistant: ```c
void console_log(const char *tmplt, ...) {
  char buffer[256];
  va_list marker;
  va_start(marker, tmplt);
  vsprintf(buffer, tmplt, marker);
  va_end(marker);
  printf("%s\n", buffer);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SetPanTiltMode_lc898122_sharp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  test   %eax,%eax
  je     L24
  cmp    $0x1,%eax
  je     L7
  jmp    L36
L24:
  mov    $0x0,%esi
  mov    $0x109,%edi
  call   <RegWriteA_lc898122_sharp@plt>
  jmp    L36
L7:
  mov    $0x1,%esi
  mov    $0x109,%edi
  call   <RegWriteA_lc898122_sharp@plt>
  nop
L36:
  nop
  leave
  ret
```

assistant: ```c
void SetPanTiltMode_lc898122_sharp(unsigned char UcPnTmod) {
  switch (UcPnTmod) {
  case 0x00:
    RegWriteA_lc898122_sharp(0x0109, 0x00);
    break;
  case 0x01:
    RegWriteA_lc898122_sharp(0x0109, 0x01);
    break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<SetPanTiltMode_lc898122_sharp>:
  endbr64
  sub    $0x8,%rsp
  test   %dil,%dil
  je     L22
  cmp    $0x1,%dil
  je     L30
L25:
  add    $0x8,%rsp
  ret
L22:
  mov    $0x0,%esi
  mov    $0x109,%edi
  call   <RegWriteA_lc898122_sharp@plt>
  jmp    L25
L30:
  mov    $0x1,%esi
  mov    $0x109,%edi
  call   <RegWriteA_lc898122_sharp@plt>
  jmp    L25
```

assistant: ```c
void SetPanTiltMode_lc898122_sharp(unsigned char UcPnTmod) {
  switch (UcPnTmod) {
  case 0x00:
    RegWriteA_lc898122_sharp(0x0109, 0x00);
    break;
  case 0x01:
    RegWriteA_lc898122_sharp(0x0109, 0x01);
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SetPanTiltMode_lc898122_sharp>:
  endbr64
  test   %dil,%dil
  je     L5
  cmp    $0x1,%dil
  jne    L8
  mov    $0x1,%esi
  mov    $0x109,%edi
  jmp    1050 <RegWriteA_lc898122_sharp@plt>
  xchg   %ax,%ax
L8:
  ret
  nopl   0x0(%rax)
L5:
  xor    %esi,%esi
  mov    $0x109,%edi
  jmp    1050 <RegWriteA_lc898122_sharp@plt>
```

assistant: ```c
void SetPanTiltMode_lc898122_sharp(unsigned char UcPnTmod) {
  switch (UcPnTmod) {
  case 0x00:
    RegWriteA_lc898122_sharp(0x0109, 0x00);
    break;
  case 0x01:
    RegWriteA_lc898122_sharp(0x0109, 0x01);
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SetPanTiltMode_lc898122_sharp>:
  endbr64
  test   %dil,%dil
  je     L4
  cmp    $0x1,%dil
  jne    L5
  mov    $0x1,%esi
  mov    $0x109,%edi
  jmp    1050 <RegWriteA_lc898122_sharp@plt>
  xchg   %ax,%ax
L5:
  ret
  nopl   0x0(%rax)
L4:
  xor    %esi,%esi
  mov    $0x109,%edi
  jmp    1050 <RegWriteA_lc898122_sharp@plt>
```

assistant: ```c
void SetPanTiltMode_lc898122_sharp(unsigned char UcPnTmod) {
  switch (UcPnTmod) {
  case 0x00:
    RegWriteA_lc898122_sharp(0x0109, 0x00);
    break;
  case 0x01:
    RegWriteA_lc898122_sharp(0x0109, 0x01);
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bullCowCalculator>:
  endbr64
  push   %rbx
  mov    %edi,%r8d
  mov    %esi,%r11d
  mov    %esi,%ecx
  mov    %edi,%edx
  mov    $0x4,%esi
  mov    $0x0,%r10d
L18:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edx,%r9d
  sub    %eax,%r9d
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %ecx,%edi
  sub    %eax,%edi
  cmp    %edi,%r9d
  sete   %al
  movzbl %al,%eax
  add    %eax,%r10d
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  sub    $0x1,%esi
  jne    L18
  mov    $0x4,%r9d
  mov    $0x0,%edi
L26:
  movslq %r8d,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  mov    %r8d,%ecx
  sub    %eax,%ecx
  mov    %r11d,%edx
  mov    $0x4,%esi
L17:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ebx
  sar    $0x1f,%ebx
  sub    %ebx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edx,%ebx
  sub    %eax,%ebx
  cmp    %ecx,%ebx
  sete   %al
  movzbl %al,%eax
  add    %eax,%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L17
  movslq %r8d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %r8d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%r8d
  sub    $0x1,%r9d
  jne    L26
  sub    %r10d,%edi
  lea    (%rdi,%rdi,4),%eax
  lea    (%r10,%rax,2),%eax
  pop    %rbx
  ret
```

assistant: ```c
int bullCowCalculator(int n, int inputNumber) {
  int i, j, cow = 0, bull = 0, tester, test, nCopy = n, inputNumberCopy = inputNumber;
  for (i = 1; i <= 4; i++) {
    if (n % 10 == inputNumber % 10) {
      bull++;
    }
    n /= 10;
    inputNumber /= 10;
  }
  n = nCopy;
  inputNumber = inputNumberCopy;
  for (i = 1; i <= 4; i++) {
    tester = n % 10;
    test = inputNumber;
    for (j = 1; j <= 4; j++) {
      if (tester == test % 10)
        cow++;
      test /= 10;
    }
    n /= 10;
  }
  cow = cow - bull;
  return cow * 10 + bull;
}
```