ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<is_prime_new>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L49
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  test   $0x1,%dil
  jne    L10
  cmp    $0x2,%edi
  jne    L51
L10:
  mov    $0x3,%ebx
L38:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jle    L3
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%eax
  test   %edx,%edx
  je     L51
  add    $0x2,%ebx
  jmp    L38
L3:
  mov    $0x1,%eax
L51:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L49:
  ret
```

assistant: ```c
int is_prime_new(int x) {
  int ret = 1;
  int i;
  if (x == 1 || (x % 2 == 0 && x != 2)) {
    ret = 0;
    return ret;
  }
  for (i = 3; i < sqrt(x); i += 2) {
    if (x % i == 0) {
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_prime_new>:
  endbr64
  cmp    $0x1,%edi
  je     L25
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L48
  test   $0x1,%dil
  je     L35
L48:
  mov    $0x3,%ebx
  jmp    L19
  nopl   (%rax)
L52:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L35
  add    $0x2,%ebx
L19:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jg     L52
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L35:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_prime_new(int x) {
  int ret = 1;
  int i;
  if (x == 1 || (x % 2 == 0 && x != 2)) {
    ret = 0;
    return ret;
  }
  for (i = 3; i < sqrt(x); i += 2) {
    if (x % i == 0) {
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_prime_new>:
  endbr64
  cmp    $0x1,%edi
  je     L35
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L20
  test   $0x1,%dil
  je     L29
L20:
  mov    $0x3,%ebx
  jmp    L43
  nopl   (%rax)
L42:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L29
  add    $0x2,%ebx
L43:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jg     L42
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_prime_new(int x) {
  int ret = 1;
  int i;
  if (x == 1 || (x % 2 == 0 && x != 2)) {
    ret = 0;
    return ret;
  }
  for (i = 3; i < sqrt(x); i += 2) {
    if (x % i == 0) {
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<quickhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L19
L16:
  mov    %ebx,%eax
  shl    $0x3,%eax
  add    %ebx,%eax
  mov    %r12d,%ebx
  xor    %eax,%ebx
L19:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%r12d
  test   %r12d,%r12d
  jne    L16
  mov    %ebx,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned quickhash(char *sym) {
  register unsigned int hash = 0;
  register unsigned c;
  while ((c = *sym++))
    hash = hash * 9 ^ c;
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<quickhash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movsbl (%rdi),%edx
  test   %edx,%edx
  je     L16
  mov    $0x0,%eax
L3:
  lea    (%rax,%rax,8),%eax
  xor    %edx,%eax
  add    $0x1,%rcx
  movsbl -0x1(%rcx),%edx
  test   %edx,%edx
  jne    L3
  ret
L16:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned quickhash(char *sym) {
  register unsigned int hash = 0;
  register unsigned c;
  while ((c = *sym++))
    hash = hash * 9 ^ c;
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quickhash>:
  endbr64
  movsbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  xor    %eax,%eax
  test   %edx,%edx
  je     L9
  nopl   0x0(%rax)
L7:
  lea    (%rax,%rax,8),%eax
  add    $0x1,%rcx
  xor    %edx,%eax
  movsbl -0x1(%rcx),%edx
  test   %edx,%edx
  jne    L7
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
unsigned quickhash(char *sym) {
  register unsigned int hash = 0;
  register unsigned c;
  while ((c = *sym++))
    hash = hash * 9 ^ c;
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quickhash>:
  endbr64
  movsbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  xor    %eax,%eax
  test   %edx,%edx
  je     L11
  nopl   0x0(%rax)
L8:
  lea    (%rax,%rax,8),%eax
  add    $0x1,%rcx
  xor    %edx,%eax
  movsbl -0x1(%rcx),%edx
  test   %edx,%edx
  jne    L8
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
unsigned quickhash(char *sym) {
  register unsigned int hash = 0;
  register unsigned c;
  while ((c = *sym++))
    hash = hash * 9 ^ c;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<linspace_ui32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  lea    -0x1(%rdx),%esi
  mov    $0x0,%edx
  div    %esi
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L19:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jb     L19
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void linspace_ui32(unsigned int *out, const unsigned int len, const unsigned int start, const unsigned int end) {
  unsigned int incr;
  unsigned int i;
  incr = (end - start) / (len - 1);
  for (i = 0; i < len - 1; i++) {
    out[i] = start + (incr * i);
  }
  out[i] = end;
}
```
user: Translate the below assembly code into C programming language:

```asm
<linspace_ui32>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%edi
  lea    -0x1(%rsi),%r8d
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    $0x0,%edx
  div    %r8d
  test   %r8d,%r8d
  je     L6
  mov    %r9,%rdx
  lea    -0x2(%rsi),%esi
  lea    0x4(%r9,%rsi,4),%rsi
L17:
  mov    %edi,(%rdx)
  add    %eax,%edi
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L17
L6:
  mov    %r8d,%r8d
  mov    %ecx,(%r9,%r8,4)
  ret
```

assistant: ```c
void linspace_ui32(unsigned int *out, const unsigned int len, const unsigned int start, const unsigned int end) {
  unsigned int incr;
  unsigned int i;
  incr = (end - start) / (len - 1);
  for (i = 0; i < len - 1; i++) {
    out[i] = start + (incr * i);
  }
  out[i] = end;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<linspace_ui32>:
  endbr64
  mov    %ecx,%eax
  mov    %rdi,%r8
  lea    -0x1(%rsi),%r9d
  mov    %edx,%edi
  sub    %edx,%eax
  xor    %edx,%edx
  div    %r9d
  test   %r9d,%r9d
  je     L17
  sub    $0x2,%esi
  mov    %r8,%rdx
  lea    0x4(%r8,%rsi,4),%rsi
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %edi,(%rdx)
  add    $0x4,%rdx
  add    %eax,%edi
  cmp    %rsi,%rdx
  jne    L10
  lea    (%r8,%r9,4),%r8
L17:
  mov    %ecx,(%r8)
  ret
```

assistant: ```c
void linspace_ui32(unsigned int *out, const unsigned int len, const unsigned int start, const unsigned int end) {
  unsigned int incr;
  unsigned int i;
  incr = (end - start) / (len - 1);
  for (i = 0; i < len - 1; i++) {
    out[i] = start + (incr * i);
  }
  out[i] = end;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<linspace_ui32>:
  endbr64
  mov    %ecx,%r8d
  mov    %edx,%r9d
  lea    -0x1(%rsi),%ecx
  mov    %r8d,%eax
  sub    %edx,%eax
  xor    %edx,%edx
  div    %ecx
  test   %ecx,%ecx
  je     L68
  sub    $0x2,%esi
  cmp    $0x2,%esi
  jbe    L30
  mov    %ecx,%esi
  movd   %eax,%xmm7
  mov    %rdi,%rdx
  movdqa D12(%rip),%xmm2
  shr    $0x2,%esi
  pshufd $0x0,%xmm7,%xmm3
  movdqa D11(%rip),%xmm5
  movd   %r9d,%xmm7
  sub    $0x1,%esi
  movdqa %xmm3,%xmm4
  pshufd $0x0,%xmm7,%xmm6
  shl    $0x4,%rsi
  psrlq  $0x20,%xmm4
  lea    0x10(%rdi,%rsi,1),%rsi
  nopw   0x0(%rax,%rax,1)
L0:
  movdqa %xmm2,%xmm0
  add    $0x10,%rdx
  paddd  %xmm5,%xmm2
  movdqa %xmm0,%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm3,%xmm1
  pmuludq %xmm4,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  paddd  %xmm6,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rsi,%rdx
  jne    L0
  mov    %ecx,%edx
  and    $0xfffffffc,%edx
  test   $0x3,%cl
  je     L28
L56:
  mov    %edx,%esi
  mov    %edx,%r10d
  imul   %eax,%esi
  lea    (%rsi,%r9,1),%r11d
  mov    %r11d,(%rdi,%r10,4)
  lea    0x1(%rdx),%r10d
  cmp    %r10d,%ecx
  jbe    L28
  add    %eax,%esi
  add    $0x2,%edx
  lea    (%r9,%rsi,1),%r11d
  mov    %r11d,(%rdi,%r10,4)
  cmp    %edx,%ecx
  jbe    L28
  add    %esi,%eax
  add    %r9d,%eax
  mov    %eax,(%rdi,%rdx,4)
L28:
  lea    (%rdi,%rcx,4),%rdi
L68:
  mov    %r8d,(%rdi)
  ret
L30:
  xor    %edx,%edx
  jmp    L56
```

tool_calls: name: retrieve_data
arguments: label: D12
type: byte[16]
name: retrieve_data
arguments: label: D11
type: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D11": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void linspace_ui32(unsigned int *out, const unsigned int len, const unsigned int start, const unsigned int end) {
  unsigned int incr;
  unsigned int i;
  incr = (end - start) / (len - 1);
  for (i = 0; i < len - 1; i++) {
    out[i] = start + (incr * i);
  }
  out[i] = end;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  D32(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D28(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D32
type: f64
name: parse_data
arguments: tag: D28
type: f64
name: parse_data
arguments: tag: D34
type: string
name: parse_data
arguments: tag: D1
type: byte[8]
name: parse_data
arguments: tag: D42
type: string

tool: D32: 10.5

tool: D28: 500.5

tool: D34: pettycash=%.2f


tool: {"D1": [0x8c,0x2e,0xba,0xe8,0xa2,0x8b,0xee,0x3f]}

tool: D42: grandtotal=%.2f


assistant: ```c
int main(int argc, char **argv) {
  double pettycash = 10.5;
  double grandtotal = 500.50;
  printf("pettycash=%.2f\n", pettycash);
  pettycash = 10.5 / 11;
  printf("pettycash=%.2f\n", pettycash);
  printf("grandtotal=%.2f\n", grandtotal);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  movsd  D44(%rip),%xmm0
  lea    D46(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movsd  D18(%rip),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  movsd  D39(%rip),%xmm0
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D44
data_type: f64
name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D18
data_type: byte[8]
name: unpack_data
arguments: tag: D39
data_type: f64
name: unpack_data
arguments: tag: D29
data_type: string

tool: D44: 10.5

tool: D46: pettycash=%.2f


tool: {"D18": [0x8c,0x2e,0xba,0xe8,0xa2,0x8b,0xee,0x3f]}

tool: D39: 500.5

tool: D29: grandtotal=%.2f


assistant: ```c
int main(int argc, char **argv) {
  double pettycash = 10.5;
  double grandtotal = 500.50;
  printf("pettycash=%.2f\n", pettycash);
  pettycash = 10.5 / 11;
  printf("pettycash=%.2f\n", pettycash);
  printf("grandtotal=%.2f\n", grandtotal);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  movsd  D2(%rip),%xmm0
  lea    D34(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D27(%rip),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D0(%rip),%xmm0
  lea    D32(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: f64
name: read_data
arguments: tag: D34
type: string
name: read_data
arguments: tag: D27
type: byte[8]
name: read_data
arguments: tag: D0
type: f64
name: read_data
arguments: tag: D32
type: string

tool: D2: 10.5

tool: D34: pettycash=%.2f


tool: {"D27": [0x8c,0x2e,0xba,0xe8,0xa2,0x8b,0xee,0x3f]}

tool: D0: 500.5

tool: D32: grandtotal=%.2f


assistant: ```c
int main(int argc, char **argv) {
  double pettycash = 10.5;
  double grandtotal = 500.50;
  printf("pettycash=%.2f\n", pettycash);
  pettycash = 10.5 / 11;
  printf("pettycash=%.2f\n", pettycash);
  printf("grandtotal=%.2f\n", grandtotal);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  movsd  D27(%rip),%xmm0
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D10(%rip),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D49(%rip),%xmm0
  lea    D30(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D27
data_type: f64
name: read_data
arguments: label: D15
data_type: string
name: read_data
arguments: label: D10
data_type: byte[8]
name: read_data
arguments: label: D49
data_type: f64
name: read_data
arguments: label: D30
data_type: string

tool: D27: 10.5

tool: D15: pettycash=%.2f


tool: {"D10": [0x8c,0x2e,0xba,0xe8,0xa2,0x8b,0xee,0x3f]}

tool: D49: 500.5

tool: D30: grandtotal=%.2f


assistant: ```c
int main(int argc, char **argv) {
  double pettycash = 10.5;
  double grandtotal = 500.50;
  printf("pettycash=%.2f\n", pettycash);
  pettycash = 10.5 / 11;
  printf("pettycash=%.2f\n", pettycash);
  printf("grandtotal=%.2f\n", grandtotal);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HYDValence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x6,-0x14(%rbp)
  jne    L38
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    $0x4,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L76
L38:
  cmpl   $0x7,-0x14(%rbp)
  je     L67
  cmpl   $0xf,-0x14(%rbp)
  jne    L68
L67:
  mov    -0x18(%rbp),%eax
  add    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L76
L68:
  cmpl   $0x8,-0x14(%rbp)
  je     L66
  cmpl   $0x10,-0x14(%rbp)
  jne    L76
L66:
  mov    -0x18(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
L76:
  cmpl   $0x0,-0x4(%rbp)
  jns    L30
  movl   $0x0,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jbe    L55
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L55:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int HYDValence(unsigned int elem, int q, unsigned int val) {
  int impval = 0;
  if (elem == 6) {
    impval = 4 - abs(q);
  } else if (elem == 7 || elem == 15) {
    impval = 3 + q;
  } else if (elem == 8 || elem == 16) {
    impval = 2 + q;
  }
  if (impval < 0) {
    impval = 0;
  }
  if (val > impval) {
    impval = val;
  }
  return impval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HYDValence>:
  endbr64
  sub    $0x6,%edi
  cmp    $0xa,%edi
  ja     L11
  mov    %edi,%edi
  lea    D3(%rip),%rcx
  movslq (%rcx,%rdi,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  mov    %esi,%ecx
  neg    %ecx
  cmovs  %esi,%ecx
  mov    $0x4,%eax
  sub    %ecx,%eax
L13:
  test   %eax,%eax
  mov    $0x0,%ecx
  cmovs  %ecx,%eax
L1:
  cmp    %edx,%eax
  cmovb  %edx,%eax
  ret
  lea    0x3(%rsi),%eax
  jmp    L13
  lea    0x2(%rsi),%eax
  jmp    L13
L11:
  mov    $0x0,%eax
  jmp    L1
```

assistant: ```c
unsigned int HYDValence(unsigned int elem, int q, unsigned int val) {
  int impval = 0;
  if (elem == 6) {
    impval = 4 - abs(q);
  } else if (elem == 7 || elem == 15) {
    impval = 3 + q;
  } else if (elem == 8 || elem == 16) {
    impval = 2 + q;
  }
  if (impval < 0) {
    impval = 0;
  }
  if (val > impval) {
    impval = val;
  }
  return impval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<HYDValence>:
  endbr64
  sub    $0x6,%edi
  cmp    $0xa,%edi
  ja     L3
  lea    D1(%rip),%rcx
  movslq (%rcx,%rdi,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L3:
  xor    %esi,%esi
  cmp    %esi,%edx
  mov    %esi,%eax
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  add    $0x2,%esi
L10:
  xor    %eax,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  cmp    %esi,%edx
  mov    %esi,%eax
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  add    $0x3,%esi
  jmp    L10
  nopl   (%rax)
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  mov    $0x4,%esi
  sub    %eax,%esi
  jmp    L10
```

assistant: ```c
unsigned int HYDValence(unsigned int elem, int q, unsigned int val) {
  int impval = 0;
  if (elem == 6) {
    impval = 4 - abs(q);
  } else if (elem == 7 || elem == 15) {
    impval = 3 + q;
  } else if (elem == 8 || elem == 16) {
    impval = 2 + q;
  }
  if (impval < 0) {
    impval = 0;
  }
  if (val > impval) {
    impval = val;
  }
  return impval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HYDValence>:
  endbr64
  sub    $0x6,%edi
  cmp    $0xa,%edi
  ja     L16
  lea    D6(%rip),%rcx
  movslq (%rcx,%rdi,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L16:
  xor    %esi,%esi
  cmp    %esi,%edx
  mov    %esi,%eax
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  add    $0x2,%esi
L25:
  xor    %eax,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  cmp    %esi,%edx
  mov    %esi,%eax
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  add    $0x3,%esi
  jmp    L25
  nopl   (%rax)
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  mov    $0x4,%esi
  sub    %eax,%esi
  jmp    L25
```

assistant: ```c
unsigned int HYDValence(unsigned int elem, int q, unsigned int val) {
  int impval = 0;
  if (elem == 6) {
    impval = 4 - abs(q);
  } else if (elem == 7 || elem == 15) {
    impval = 3 + q;
  } else if (elem == 8 || elem == 16) {
    impval = 2 + q;
  }
  if (impval < 0) {
    impval = 0;
  }
  if (val > impval) {
    impval = val;
  }
  return impval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jae_rj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0x73,%edi
  call   <put8@plt>
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <put8@plt>
  nop
  leave
  ret
```

assistant: ```c
void jae_rj(unsigned char saut) {
  put8(0x73);
  put8(saut);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<jae_rj>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x73,%edi
  call   <put8@plt>
  movzbl %bl,%edi
  call   <put8@plt>
  pop    %rbx
  ret
```

assistant: ```c
void jae_rj(unsigned char saut) {
  put8(0x73);
  put8(saut);
}
```
user: What is the c source code of the assembly code below:

```asm
<jae_rj>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x73,%edi
  call   <put8@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <put8@plt>
```

assistant: ```c
void jae_rj(unsigned char saut) {
  put8(0x73);
  put8(saut);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<jae_rj>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x73,%edi
  call   <put8@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <put8@plt>
```

assistant: ```c
void jae_rj(unsigned char saut) {
  put8(0x73);
  put8(saut);
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2c_write_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <i2c_write@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L1
  mov    $0xffffffff,%eax
  jmp    L21
L1:
  cmpl   $0x2,-0x14(%rbp)
  je     L46
  mov    $0xffffffff,%eax
  jmp    L21
L46:
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
int i2c_write_word(int file_handle, uint16_t word_value) {
  uint8_t byte_value[2];
  byte_value[0] = ((word_value & 0xFF00) >> 8);
  byte_value[1] = (word_value & 0x00FF);
  int16_t return_value = i2c_write(file_handle, byte_value, 2);
  if (return_value < 0)
    return -1;
  else if (return_value != 2)
    return -1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2c_write_word>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  movzbl %ah,%edx
  mov    %edx,(%rsp)
  and    $0xff,%eax
  mov    %eax,0x4(%rsp)
  mov    %rsp,%rsi
  mov    $0x2,%edx
  call   <i2c_write@plt>
  cmp    $0x2,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_word(int file_handle, uint16_t word_value) {
  uint8_t byte_value[2];
  byte_value[0] = ((word_value & 0xFF00) >> 8);
  byte_value[1] = (word_value & 0x00FF);
  int16_t return_value = i2c_write(file_handle, byte_value, 2);
  if (return_value < 0)
    return -1;
  else if (return_value != 2)
    return -1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<i2c_write_word>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  movzbl %ah,%edx
  mov    %rsp,%rsi
  and    $0xff,%eax
  mov    %edx,(%rsp)
  mov    $0x2,%edx
  mov    %eax,0x4(%rsp)
  call   <i2c_write@plt>
  cmp    $0x2,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_word(int file_handle, uint16_t word_value) {
  uint8_t byte_value[2];
  byte_value[0] = ((word_value & 0xFF00) >> 8);
  byte_value[1] = (word_value & 0x00FF);
  int16_t return_value = i2c_write(file_handle, byte_value, 2);
  if (return_value < 0)
    return -1;
  else if (return_value != 2)
    return -1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i2c_write_word>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  movzbl %ah,%edx
  mov    %rsp,%rsi
  and    $0xff,%eax
  mov    %edx,(%rsp)
  mov    $0x2,%edx
  mov    %eax,0x4(%rsp)
  call   <i2c_write@plt>
  cmp    $0x2,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_word(int file_handle, uint16_t word_value) {
  uint8_t byte_value[2];
  byte_value[0] = ((word_value & 0xFF00) >> 8);
  byte_value[1] = (word_value & 0x00FF);
  int16_t return_value = i2c_write(file_handle, byte_value, 2);
  if (return_value < 0)
    return -1;
  else if (return_value != 2)
    return -1;
  else
    return 0;
}
```