ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<flipAndInvertImage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  mov    %rdx,0x8(%rsp)
  test   %esi,%esi
  je     L54
  mov    %esi,%ebx
  mov    %rcx,%r15
  mov    %r8,%rbp
  test   %rdi,%rdi
  je     L54
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,0x18(%rsp)
  mov    %ebx,0x0(%rbp)
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r15)
  test   %ebx,%ebx
  jle    L60
  mov    %ebx,%ebx
  lea    0x0(,%rbx,4),%rax
  mov    %rax,0x10(%rsp)
  mov    $0x0,%ebp
L26:
  mov    (%rsp),%rax
  mov    (%rax,%rbp,2),%rbx
  mov    0x8(%rsp),%rax
  mov    (%rax,%rbp,1),%r12d
  mov    (%r15),%rax
  mov    %r12d,(%rax,%rbp,1)
  movslq %r12d,%r13
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L7
  shl    $0x2,%r13
  lea    (%rbx,%r13,1),%rax
  lea    -0x4(%rbx,%r13,1),%rsi
  lea    -0x1(%r12),%edx
  shl    $0x2,%rdx
  sub    %rdx,%rsi
  add    %rdi,%rbx
  add    %r13,%rbx
L17:
  mov    %rbx,%rdx
  sub    %rax,%rdx
  cmpl   $0x0,-0x4(%rax)
  sete   %cl
  movzbl %cl,%ecx
  mov    %ecx,(%rdx)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L17
L7:
  mov    %rdi,(%r14)
  add    $0x4,%rbp
  add    $0x8,%r14
  cmp    0x10(%rsp),%rbp
  jne    L26
L60:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  movq   $0x0,0x18(%rsp)
  jmp    L60
```

assistant: ```c
int **flipAndInvertImage(int **A, int ARowSize, int *AColSizes, int **columnSizes, int *returnSize) {
  if (ARowSize == 0 || A == NULL) {
    return NULL;
  }
  int **retval = (int **)malloc(sizeof(int *) * ARowSize);
  *returnSize = ARowSize;
  *columnSizes = (int *)malloc(sizeof(int) * ARowSize);
  for (int nrow = 0; nrow < ARowSize; nrow++) {
    int *srcRow = A[nrow];
    int rowSize = AColSizes[nrow];
    (*columnSizes)[nrow] = rowSize;
    int *dstRow = (int *)malloc(sizeof(int) * rowSize);
    for (int ncol = 0; ncol < rowSize; ncol++) {
      int index = rowSize - ncol - 1;
      dstRow[ncol] = !(srcRow[index]);
    }
    retval[nrow] = dstRow;
  }
  return retval;
}
```
user: What is the c source code of the assembly code below:

```asm
<flipAndInvertImage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,(%rsp)
  mov    %rcx,0x10(%rsp)
  test   %esi,%esi
  je     L43
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L43
  mov    %esi,%r13d
  mov    %r8,%r15
  lea    0x0(,%rsi,8),%edi
  mov    %rcx,%r14
  call   <malloc@plt>
  mov    %r13d,(%r15)
  lea    0x0(,%r13,4),%edi
  mov    %rax,0x18(%rsp)
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %r13d,%r13d
  jle    L50
  sub    $0x1,%r13d
  xor    %r14d,%r14d
  lea    0x0(,%r13,4),%rdi
  mov    %rdi,0x8(%rsp)
  nopl   0x0(%rax)
L9:
  mov    (%rsp),%rdi
  mov    (%rbx,%r14,2),%r13
  movslq (%rdi,%r14,1),%r15
  mov    %r15d,(%rax,%r14,1)
  lea    0x0(,%r15,4),%edi
  mov    %r15,%r12
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %r15d,%r15d
  jle    L20
  shl    $0x2,%r15
  lea    -0x1(%r12),%edx
  lea    (%rdi,%r13,1),%rsi
  lea    -0x4(%r13,%r15,1),%r10
  shl    $0x2,%rdx
  lea    0x0(%r13,%r15,1),%rax
  add    %r15,%rsi
  sub    %rdx,%r10
  nopl   0x0(%rax)
L14:
  mov    -0x4(%rax),%r8d
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  sub    %rax,%rdx
  test   %r8d,%r8d
  sete   %cl
  sub    $0x4,%rax
  mov    %ecx,(%rdx)
  cmp    %rax,%r10
  jne    L14
L20:
  mov    %rdi,0x0(%rbp)
  add    $0x8,%rbp
  cmp    0x8(%rsp),%r14
  je     L50
  mov    0x10(%rsp),%rax
  add    $0x4,%r14
  mov    (%rax),%rax
  jmp    L9
L43:
  movq   $0x0,0x18(%rsp)
L50:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **flipAndInvertImage(int **A, int ARowSize, int *AColSizes, int **columnSizes, int *returnSize) {
  if (ARowSize == 0 || A == NULL) {
    return NULL;
  }
  int **retval = (int **)malloc(sizeof(int *) * ARowSize);
  *returnSize = ARowSize;
  *columnSizes = (int *)malloc(sizeof(int) * ARowSize);
  for (int nrow = 0; nrow < ARowSize; nrow++) {
    int *srcRow = A[nrow];
    int rowSize = AColSizes[nrow];
    (*columnSizes)[nrow] = rowSize;
    int *dstRow = (int *)malloc(sizeof(int) * rowSize);
    for (int ncol = 0; ncol < rowSize; ncol++) {
      int index = rowSize - ncol - 1;
      dstRow[ncol] = !(srcRow[index]);
    }
    retval[nrow] = dstRow;
  }
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lzmadec_header_properties>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x1c(%rbp)
  cmpb   $0xe1,-0x1c(%rbp)
  jbe    L32
  mov    $0xffffffff,%eax
  jmp    L26
L32:
  movzbl -0x1c(%rbp),%edx
  mov    $0x6d,%ecx
  mov    %ecx,%eax
  mul    %dl
  shr    $0x8,%ax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %al
  add    %ecx,%eax
  shr    $0x5,%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  movzbl -0x1c(%rbp),%edx
  mov    $0x6d,%ecx
  mov    %ecx,%eax
  mul    %dl
  shr    $0x8,%ax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %al
  add    %ecx,%eax
  shr    $0x5,%al
  mov    $0x2d,%ecx
  imul   %ecx,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x39,%edx
  mul    %dl
  shr    $0x8,%ax
  mov    %eax,%edx
  shr    %dl
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  movzbl -0x1c(%rbp),%ecx
  mov    $0x39,%edx
  mov    %edx,%eax
  mul    %cl
  shr    $0x8,%ax
  shr    %al
  mov    %eax,%edx
  shl    $0x3,%edx
  add    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4,%al
  ja     L19
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4,%al
  ja     L19
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x8,%al
  ja     L19
  mov    $0x1,%eax
  jmp    L18
L19:
  mov    $0x0,%eax
L18:
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
L26:
  leave
  ret
```

assistant: ```c
char lzmadec_header_properties(unsigned char *pb, unsigned char *lp, unsigned char *lc, const unsigned char c) {
  if (c > (9 * 5 * 5))
    return -1;
  *pb = c / (9 * 5);
  *lp = (c % (9 * 5)) / 9;
  *lc = c % 9;
  assert(*pb < 5 && *lp < 5 && *lc < 9);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lzmadec_header_properties>:
  endbr64
  cmp    $0xe1,%cl
  ja     L15
  sub    $0x8,%rsp
  mov    %rdx,%r8
  mov    %ecx,%edx
  mov    $0x6d,%r9d
  mov    %r9d,%eax
  mul    %cl
  mov    %eax,%r9d
  shr    $0x8,%r9w
  mov    %ecx,%eax
  sub    %r9d,%eax
  shr    %al
  mov    %eax,%ecx
  lea    (%rcx,%r9,1),%eax
  shr    $0x5,%al
  mov    %al,(%rdi)
  mov    $0x2d,%ecx
  imul   %ecx,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x39,%ecx
  mul    %cl
  shr    $0x9,%ax
  mov    %al,(%rsi)
  mov    %ecx,%eax
  mul    %dl
  shr    $0x9,%ax
  lea    (%rax,%rax,8),%eax
  sub    %eax,%edx
  mov    %dl,(%r8)
  mov    $0x0,%eax
  cmpb   $0x4,(%rdi)
  ja     L9
  cmpb   $0x4,(%rsi)
  setbe  %al
  movzbl %al,%eax
L9:
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L15:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
char lzmadec_header_properties(unsigned char *pb, unsigned char *lp, unsigned char *lc, const unsigned char c) {
  if (c > (9 * 5 * 5))
    return -1;
  *pb = c / (9 * 5);
  *lp = (c % (9 * 5)) / 9;
  *lc = c % 9;
  assert(*pb < 5 && *lp < 5 && *lc < 9);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lzmadec_header_properties>:
  endbr64
  cmp    $0xe1,%cl
  ja     L3
  mov    $0x6d,%eax
  mov    %rdx,%r8
  mov    %ecx,%edx
  sub    $0x8,%rsp
  mul    %cl
  mov    %eax,%r9d
  mov    %ecx,%eax
  shr    $0x8,%r9w
  sub    %r9d,%eax
  shr    %al
  mov    %eax,%ecx
  lea    (%rcx,%r9,1),%eax
  mov    $0x2d,%ecx
  shr    $0x5,%al
  mov    %al,(%rdi)
  imul   %ecx,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x39,%ecx
  mul    %cl
  shr    $0x9,%ax
  mov    %al,(%rsi)
  mov    %ecx,%eax
  mul    %dl
  shr    $0x9,%ax
  lea    (%rax,%rax,8),%eax
  sub    %eax,%edx
  mov    %dl,(%r8)
  xor    %r8d,%r8d
  cmpb   $0x4,(%rdi)
  ja     L10
  xor    %r8d,%r8d
  cmpb   $0x4,(%rsi)
  setbe  %r8b
L10:
  mov    %r8d,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
char lzmadec_header_properties(unsigned char *pb, unsigned char *lp, unsigned char *lc, const unsigned char c) {
  if (c > (9 * 5 * 5))
    return -1;
  *pb = c / (9 * 5);
  *lp = (c % (9 * 5)) / 9;
  *lc = c % 9;
  assert(*pb < 5 && *lp < 5 && *lc < 9);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<lzmadec_header_properties>:
  endbr64
  cmp    $0xe1,%cl
  ja     L11
  mov    $0x6d,%eax
  mov    %rdx,%r8
  mov    %ecx,%edx
  sub    $0x8,%rsp
  mul    %cl
  mov    %eax,%r9d
  mov    %ecx,%eax
  shr    $0x8,%r9w
  sub    %r9d,%eax
  shr    %al
  mov    %eax,%ecx
  lea    (%rcx,%r9,1),%eax
  mov    $0x2d,%ecx
  shr    $0x5,%al
  mov    %al,(%rdi)
  imul   %ecx,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x39,%ecx
  mul    %cl
  shr    $0x9,%ax
  mov    %al,(%rsi)
  mov    %ecx,%eax
  mul    %dl
  shr    $0x9,%ax
  lea    (%rax,%rax,8),%eax
  sub    %eax,%edx
  mov    %dl,(%r8)
  xor    %r8d,%r8d
  cmpb   $0x4,(%rdi)
  ja     L15
  xor    %r8d,%r8d
  cmpb   $0x4,(%rsi)
  setbe  %r8b
L15:
  mov    %r8d,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L11:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
char lzmadec_header_properties(unsigned char *pb, unsigned char *lp, unsigned char *lc, const unsigned char c) {
  if (c > (9 * 5 * 5))
    return -1;
  *pb = c / (9 * 5);
  *lp = (c % (9 * 5)) / 9;
  *lc = c % 9;
  assert(*pb < 5 && *lp < 5 && *lc < 9);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_asserting>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <seatest_assert_true@plt>
  mov    $0x6,%edx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <seatest_assert_false@plt>
  mov    $0x7,%ecx
  lea    D17(%rip),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <seatest_assert_int_equal@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
data_type: string

tool: D17: test_asserting

assistant: ```c
void test_asserting() {
  do {
    seatest_assert_true(1 == 1, __FUNCTION__, 5);
  } while (0);
  do {
    seatest_assert_false(1 == 2, __FUNCTION__, 6);
  } while (0);
  do {
    seatest_assert_int_equal(1, 1, __FUNCTION__, 7);
  } while (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_asserting>:
  endbr64
  push   %rbx
  mov    $0x5,%edx
  lea    D8(%rip),%rbx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <seatest_assert_true@plt>
  mov    $0x6,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <seatest_assert_false@plt>
  mov    $0x7,%ecx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <seatest_assert_int_equal@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: test_asserting

assistant: ```c
void test_asserting() {
  do {
    seatest_assert_true(1 == 1, __FUNCTION__, 5);
  } while (0);
  do {
    seatest_assert_false(1 == 2, __FUNCTION__, 6);
  } while (0);
  do {
    seatest_assert_int_equal(1, 1, __FUNCTION__, 7);
  } while (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_asserting>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  mov    $0x5,%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <seatest_assert_true@plt>
  mov    %r12,%rsi
  mov    $0x6,%edx
  xor    %edi,%edi
  xor    %eax,%eax
  call   <seatest_assert_false@plt>
  mov    %r12,%rdx
  mov    $0x7,%ecx
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x1,%edi
  pop    %r12
  jmp    1080 <seatest_assert_int_equal@plt>
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: test_asserting

assistant: ```c
void test_asserting() {
  do {
    seatest_assert_true(1 == 1, __FUNCTION__, 5);
  } while (0);
  do {
    seatest_assert_false(1 == 2, __FUNCTION__, 6);
  } while (0);
  do {
    seatest_assert_int_equal(1, 1, __FUNCTION__, 7);
  } while (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_asserting>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  mov    $0x5,%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <seatest_assert_true@plt>
  mov    %r12,%rsi
  mov    $0x6,%edx
  xor    %edi,%edi
  xor    %eax,%eax
  call   <seatest_assert_false@plt>
  mov    %r12,%rdx
  mov    $0x7,%ecx
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x1,%edi
  pop    %r12
  jmp    1080 <seatest_assert_int_equal@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8: test_asserting

assistant: ```c
void test_asserting() {
  do {
    seatest_assert_true(1 == 1, __FUNCTION__, 5);
  } while (0);
  do {
    seatest_assert_false(1 == 2, __FUNCTION__, 6);
  } while (0);
  do {
    seatest_assert_int_equal(1, 1, __FUNCTION__, 7);
  } while (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parseInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L57
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L35
L57:
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L55
L35:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L44
  addq   $0x1,-0x8(%rbp)
  jmp    L17
L44:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  mov    %al,-0x15(%rbp)
  movzbl -0x15(%rbp),%esi
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0xc(%rbp)
L17:
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L31
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%eax
L55:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int parseInt(int bytes, char **s) {
  int i;
  char *b = *s;
  unsigned int ret = 0;
  int j = bytes - 1;
  for (i = 0; i < bytes;) {
    if (*b == 0 || *b == '\n') {
      *s = 0;
      return 0;
    }
    if (*(b + 1) == '\n') {
      b++;
    } else {
      unsigned char c = *b - 0x30;
      ret += ((unsigned int)c) << (6 * j);
      i++;
      j--;
    }
    b++;
  }
  *s = b;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parseInt>:
  endbr64
  mov    (%rsi),%rdx
  lea    -0x1(%rdi),%r8d
  test   %edi,%edi
  jle    L69
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  jmp    L32
L11:
  add    $0x1,%rdx
L60:
  add    $0x1,%rdx
  cmp    %edi,%r9d
  jge    L4
L32:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L78
  cmp    $0xa,%al
  je     L78
  cmpb   $0xa,0x1(%rdx)
  je     L11
  sub    $0x30,%eax
  movzbl %al,%eax
  lea    (%r8,%r8,2),%ecx
  add    %ecx,%ecx
  shl    %cl,%eax
  add    %eax,%r10d
  add    $0x1,%r9d
  sub    $0x1,%r8d
  jmp    L60
L69:
  mov    $0x0,%r10d
  jmp    L4
L78:
  mov    $0x0,%edx
  mov    $0x0,%r10d
L4:
  mov    %rdx,(%rsi)
  mov    %r10d,%eax
  ret
```

assistant: ```c
unsigned int parseInt(int bytes, char **s) {
  int i;
  char *b = *s;
  unsigned int ret = 0;
  int j = bytes - 1;
  for (i = 0; i < bytes;) {
    if (*b == 0 || *b == '\n') {
      *s = 0;
      return 0;
    }
    if (*(b + 1) == '\n') {
      b++;
    } else {
      unsigned char c = *b - 0x30;
      ret += ((unsigned int)c) << (6 * j);
      i++;
      j--;
    }
    b++;
  }
  *s = b;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parseInt>:
  endbr64
  mov    (%rsi),%rdx
  lea    -0x1(%rdi),%r8d
  xor    %r10d,%r10d
  test   %edi,%edi
  jle    L23
  xor    %r9d,%r9d
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L13:
  lea    (%r8,%r8,2),%ecx
  sub    $0x30,%eax
  add    $0x1,%r9d
  sub    $0x1,%r8d
  movzbl %al,%eax
  add    %ecx,%ecx
  add    $0x1,%rdx
  shl    %cl,%eax
  add    %eax,%r10d
  cmp    %edi,%r9d
  jge    L23
L50:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L5
  cmp    $0xa,%al
  je     L5
  cmpb   $0xa,0x1(%rdx)
  jne    L13
  add    $0x1,%rdx
  add    $0x1,%rdx
  cmp    %edi,%r9d
  jl     L50
L23:
  mov    %rdx,(%rsi)
  mov    %r10d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %edx,%edx
  xor    %r10d,%r10d
  mov    %rdx,(%rsi)
  mov    %r10d,%eax
  ret
```

assistant: ```c
unsigned int parseInt(int bytes, char **s) {
  int i;
  char *b = *s;
  unsigned int ret = 0;
  int j = bytes - 1;
  for (i = 0; i < bytes;) {
    if (*b == 0 || *b == '\n') {
      *s = 0;
      return 0;
    }
    if (*(b + 1) == '\n') {
      b++;
    } else {
      unsigned char c = *b - 0x30;
      ret += ((unsigned int)c) << (6 * j);
      i++;
      j--;
    }
    b++;
  }
  *s = b;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<parseInt>:
  endbr64
  mov    (%rsi),%rdx
  lea    -0x1(%rdi),%r8d
  xor    %r10d,%r10d
  test   %edi,%edi
  jle    L19
  xor    %r9d,%r9d
  nopl   (%rax)
L7:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L36
L63:
  cmp    $0xa,%al
  je     L36
  cmpb   $0xa,0x1(%rdx)
  je     L24
  lea    (%r8,%r8,2),%ecx
  sub    $0x30,%eax
  add    $0x1,%r9d
  sub    $0x1,%r8d
  movzbl %al,%eax
  add    %ecx,%ecx
  add    $0x1,%rdx
  shl    %cl,%eax
  add    %eax,%r10d
  cmp    %r9d,%edi
  jg     L7
L19:
  mov    %rdx,(%rsi)
  mov    %r10d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x2,%rdx
  cmp    %r9d,%edi
  jle    L19
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L63
L36:
  xor    %edx,%edx
  xor    %r10d,%r10d
  mov    %rdx,(%rsi)
  mov    %r10d,%eax
  ret
```

assistant: ```c
unsigned int parseInt(int bytes, char **s) {
  int i;
  char *b = *s;
  unsigned int ret = 0;
  int j = bytes - 1;
  for (i = 0; i < bytes;) {
    if (*b == 0 || *b == '\n') {
      *s = 0;
      return 0;
    }
    if (*(b + 1) == '\n') {
      b++;
    } else {
      unsigned char c = *b - 0x30;
      ret += ((unsigned int)c) << (6 * j);
      i++;
      j--;
    }
    b++;
  }
  *s = b;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<efree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void efree(void **ptr) {
  if ((*ptr) != 0)
    free((*ptr));
  *ptr = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<efree>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  call   <free@plt>
L1:
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void efree(void **ptr) {
  if ((*ptr) != 0)
    free((*ptr));
  *ptr = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<efree>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
  call   <free@plt>
L8:
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void efree(void **ptr) {
  if ((*ptr) != 0)
    free((*ptr));
  *ptr = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<efree>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L6
  call   <free@plt>
L6:
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void efree(void **ptr) {
  if ((*ptr) != 0)
    free((*ptr));
  *ptr = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getdtablesize@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: max fds: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("max fds: %d\n", getdtablesize());
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getdtablesize@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: max fds: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("max fds: %d\n", getdtablesize());
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getdtablesize@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: max fds: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("max fds: %d\n", getdtablesize());
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getdtablesize@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string

tool: D0: max fds: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("max fds: %d\n", getdtablesize());
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unpack_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohll@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t unpack_uint64(const void **pp) {
  int val = ntohll(*((uint64_t *)(*pp)));
  *pp += sizeof(uint64_t);
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<unpack_uint64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  mov    (%rax),%edi
  call   <ntohll@plt>
  addq   $0x4,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
uint64_t unpack_uint64(const void **pp) {
  int val = ntohll(*((uint64_t *)(*pp)));
  *pp += sizeof(uint64_t);
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<unpack_uint64>:
  endbr64
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  mov    (%rax),%edi
  call   <ntohll@plt>
  addq   $0x4,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
uint64_t unpack_uint64(const void **pp) {
  int val = ntohll(*((uint64_t *)(*pp)));
  *pp += sizeof(uint64_t);
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<unpack_uint64>:
  endbr64
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  mov    (%rax),%edi
  call   <ntohll@plt>
  addq   $0x4,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
uint64_t unpack_uint64(const void **pp) {
  int val = ntohll(*((uint64_t *)(*pp)));
  *pp += sizeof(uint64_t);
  return val;
}
```