ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ro2qu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x54(%rbp),%edx
  lea    -0x30(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ro2ax@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x54(%rbp),%edx
  mov    -0x50(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ax2qu@plt>
  mov    %eax,-0x34(%rbp)
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int ro2qu(double *ro, double *qu, int p) {
  double ax[4];
  int trash;
  trash = ro2ax(ro, ax, p);
  trash = ax2qu(ax, qu, p);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ro2qu>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <ro2ax@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ax2qu@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x1,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ro2qu(double *ro, double *qu, int p) {
  double ax[4];
  int trash;
  trash = ro2ax(ro, ax, p);
  trash = ax2qu(ax, qu, p);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ro2qu>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <ro2ax@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ax2qu@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ro2qu(double *ro, double *qu, int p) {
  double ax[4];
  int trash;
  trash = ro2ax(ro, ax, p);
  trash = ax2qu(ax, qu, p);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ro2qu>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <ro2ax@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ax2qu@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ro2qu(double *ro, double *qu, int p) {
  double ax[4];
  int trash;
  trash = ro2ax(ro, ax, p);
  trash = ax2qu(ax, qu, p);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<peach>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L16
  mov    $0x1,%eax
  jmp    L13
L16:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <peach>
  add    $0x1,%eax
  add    %eax,%eax
L13:
  leave
  ret
```

assistant: ```c
int peach(int n) {
  if (n == 1)
    return 1;
  else
    return (peach(n - 1) + 1) * 2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<peach>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%edi
  jne    L6
  ret
L6:
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%edi
  call   <peach>
  lea    0x2(%rax,%rax,1),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int peach(int n) {
  if (n == 1)
    return 1;
  else
    return (peach(n - 1) + 1) * 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<peach>:
  endbr64
  mov    $0x1,%eax
  xor    %edx,%edx
  cmp    $0x1,%edi
  je     L2
L4:
  add    %eax,%eax
  sub    $0x1,%edi
  add    %eax,%edx
  cmp    $0x1,%edi
  jne    L4
  add    %edx,%eax
L2:
  ret
```

assistant: ```c
int peach(int n) {
  if (n == 1)
    return 1;
  else
    return (peach(n - 1) + 1) * 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<peach>:
  endbr64
  mov    $0x1,%eax
  xor    %edx,%edx
  cmp    $0x1,%edi
  je     L16
L19:
  add    %eax,%eax
  sub    $0x1,%edi
  add    %eax,%edx
  cmp    $0x1,%edi
  jne    L19
  add    %edx,%eax
L16:
  ret
```

assistant: ```c
int peach(int n) {
  if (n == 1)
    return 1;
  else
    return (peach(n - 1) + 1) * 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_MOVBE_RtoM_32@plt>
  mov    $0x0,%eax
  call   <test_MOVBE_RtoM_16@plt>
  mov    $0x0,%eax
  call   <test_MOVBE_MtoR_32@plt>
  mov    $0x0,%eax
  call   <test_MOVBE_MtoR_16@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  test_MOVBE_RtoM_32();
  test_MOVBE_RtoM_16();
  test_MOVBE_MtoR_32();
  test_MOVBE_MtoR_16();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_MOVBE_RtoM_32@plt>
  mov    $0x0,%eax
  call   <test_MOVBE_RtoM_16@plt>
  mov    $0x0,%eax
  call   <test_MOVBE_MtoR_32@plt>
  mov    $0x0,%eax
  call   <test_MOVBE_MtoR_16@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_MOVBE_RtoM_32();
  test_MOVBE_RtoM_16();
  test_MOVBE_MtoR_32();
  test_MOVBE_MtoR_16();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_MOVBE_RtoM_32@plt>
  xor    %eax,%eax
  call   <test_MOVBE_RtoM_16@plt>
  xor    %eax,%eax
  call   <test_MOVBE_MtoR_32@plt>
  xor    %eax,%eax
  call   <test_MOVBE_MtoR_16@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_MOVBE_RtoM_32();
  test_MOVBE_RtoM_16();
  test_MOVBE_MtoR_32();
  test_MOVBE_MtoR_16();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<le32enc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void le32enc(void *pp, uint32_t u) {
  uint8_t *p = (uint8_t *)pp;
  p[0] = u & 0xff;
  p[1] = (u >> 8) & 0xff;
  p[2] = (u >> 16) & 0xff;
  p[3] = (u >> 24) & 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<le32enc>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  mov    %edx,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x8(%rdi)
  shr    $0x18,%eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void le32enc(void *pp, uint32_t u) {
  uint8_t *p = (uint8_t *)pp;
  p[0] = u & 0xff;
  p[1] = (u >> 8) & 0xff;
  p[2] = (u >> 16) & 0xff;
  p[3] = (u >> 24) & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<le32enc>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  shr    $0x18,%eax
  mov    %edx,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %eax,0xc(%rdi)
  and    $0xff,%edx
  mov    %edx,0x8(%rdi)
  ret
```

assistant: ```c
void le32enc(void *pp, uint32_t u) {
  uint8_t *p = (uint8_t *)pp;
  p[0] = u & 0xff;
  p[1] = (u >> 8) & 0xff;
  p[2] = (u >> 16) & 0xff;
  p[3] = (u >> 24) & 0xff;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<le32enc>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  movzbl %sil,%ecx
  sar    $0x10,%edx
  movd   %ecx,%xmm0
  movzbl %ah,%ecx
  shr    $0x18,%eax
  movzbl %dl,%esi
  movd   %ecx,%xmm2
  movd   %eax,%xmm3
  movd   %esi,%xmm1
  punpckldq %xmm2,%xmm0
  punpckldq %xmm3,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void le32enc(void *pp, uint32_t u) {
  uint8_t *p = (uint8_t *)pp;
  p[0] = u & 0xff;
  p[1] = (u >> 8) & 0xff;
  p[2] = (u >> 16) & 0xff;
  p[3] = (u >> 24) & 0xff;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<insist_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L5
L7:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L37
  mov    -0x8(%rbp),%rax
  jmp    L38
L37:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
L5:
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
  mov    -0x10(%rbp),%rax
L38:
  leave
  ret
```

assistant: ```c
ssize_t insist_write(int fd, const void *buf, size_t cnt) {
  ssize_t ret;
  size_t orig_cnt = cnt;
  while (cnt > 0) {
    ret = write(fd, buf, cnt);
    if (ret < 0)
      return ret;
    buf += ret;
    cnt -= ret;
  }
  return orig_cnt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insist_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L18
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
L5:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  js     L0
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L5
L18:
  mov    %r13,%rax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t insist_write(int fd, const void *buf, size_t cnt) {
  ssize_t ret;
  size_t orig_cnt = cnt;
  while (cnt > 0) {
    ret = write(fd, buf, cnt);
    if (ret < 0)
      return ret;
    buf += ret;
    cnt -= ret;
  }
  return orig_cnt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insist_write>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L32
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  jmp    L27
  nopl   0x0(%rax)
L30:
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L32
L27:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jns    L30
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L32:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t insist_write(int fd, const void *buf, size_t cnt) {
  ssize_t ret;
  size_t orig_cnt = cnt;
  while (cnt > 0) {
    ret = write(fd, buf, cnt);
    if (ret < 0)
      return ret;
    buf += ret;
    cnt -= ret;
  }
  return orig_cnt;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<insist_write>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L33
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  jmp    L36
  nopl   0x0(%rax)
L31:
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L33
L36:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jns    L31
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L33:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t insist_write(int fd, const void *buf, size_t cnt) {
  ssize_t ret;
  size_t orig_cnt = cnt;
  while (cnt > 0) {
    ret = write(fd, buf, cnt);
    if (ret < 0)
      return ret;
    buf += ret;
    cnt -= ret;
  }
  return orig_cnt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atan>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm3,%xmm3
  xorpd  D88(%rip),%xmm0
  comisd %xmm2,%xmm3
  movapd %xmm2,%xmm1
  cmpltsd %xmm3,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm2,%xmm1
  orpd   %xmm1,%xmm0
  movsd  D114(%rip),%xmm1
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  movapd %xmm0,%xmm1
  mulsd  D54(%rip),%xmm1
  addsd  D118(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D48(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D112(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D47(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D46(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D61(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D50(%rip),%xmm0
  mulsd  %xmm3,%xmm0
  addsd  D36(%rip),%xmm0
  ja     L14
L5:
  ret
L14:
  xorpd  D88(%rip),%xmm0
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D88
datatype: f32[4]
name: extract_symbolic_data
arguments: data_label: D114
datatype: f64
name: extract_symbolic_data
arguments: data_label: D54
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D118
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D48
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D112
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D47
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D46
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D61
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D50
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D36
datatype: f64

tool: {"D88": [0.0,-0.0,0.0,0.0]}

tool: D114: 1

tool: {"D54": [0x61,0xda,0x6a,0xe8,0xfc,0x9a,0x70,0xbf]}

tool: {"D118": [0x4f,0xad,0x8c,0x37,0xca,0x62,0x96,0x3f]}

tool: {"D48": [0xdc,0x29,0xa5,0x78,0x38,0xa0,0xac,0x3f]}

tool: {"D112": [0xed,0x9f,0x16,0xe8,0xfb,0xae,0xb8,0x3f]}

tool: {"D47": [0x25,0xc9,0xcd,0x5a,0x8c,0xcd,0xc1,0x3f]}

tool: {"D46": [0x8f,0x49,0xba,0xb6,0x14,0x88,0xc9,0x3f]}

tool: {"D61": [0x2b,0xb0,0x49,0x7c,0xc3,0x54,0xd5,0x3f]}

tool: {"D50": [0x61,0x79,0xda,0x99,0xfe,0xff,0xef,0x3f]}

tool: D36: 0.785398163397

assistant: ```c
double atan(x)
double x;
{
  double xi, q, q2, y;
  int sign;
  xi = (x < 0. ? -x : x);
  q = (xi - 1.0) / (xi + 1.0);
  q2 = q * q;
  y = (((((((-.0040540580 * q2 + .0218612286) * q2 - .0559098861) * q2 + .0964200441) * q2 - .1390853351) * q2 + .1994653599) * q2 - .3332985605) * q2 + .9999993329) * q + 0.785398163397;
  return (x < 0. ? -y : y);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atan>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm3,%xmm3
  xorpd  D101(%rip),%xmm0
  movapd %xmm2,%xmm1
  comisd %xmm2,%xmm3
  cmpltsd %xmm3,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm2,%xmm1
  orpd   %xmm1,%xmm0
  movsd  D112(%rip),%xmm1
  movapd %xmm0,%xmm4
  subsd  %xmm1,%xmm4
  addsd  %xmm1,%xmm0
  movsd  D95(%rip),%xmm1
  divsd  %xmm0,%xmm4
  movapd %xmm4,%xmm0
  mulsd  %xmm4,%xmm0
  mulsd  %xmm0,%xmm1
  addsd  D12(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D91(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D65(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D30(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D25(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D69(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D22(%rip),%xmm0
  mulsd  %xmm4,%xmm0
  addsd  D68(%rip),%xmm0
  ja     L3
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xorpd  D101(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D101
datatype: f32[4]
name: retrieve_data
arguments: tag: D112
datatype: f64
name: retrieve_data
arguments: tag: D95
datatype: byte[8]
name: retrieve_data
arguments: tag: D12
datatype: byte[8]
name: retrieve_data
arguments: tag: D91
datatype: byte[8]
name: retrieve_data
arguments: tag: D65
datatype: byte[8]
name: retrieve_data
arguments: tag: D30
datatype: byte[8]
name: retrieve_data
arguments: tag: D25
datatype: byte[8]
name: retrieve_data
arguments: tag: D69
datatype: byte[8]
name: retrieve_data
arguments: tag: D22
datatype: byte[8]
name: retrieve_data
arguments: tag: D68
datatype: f64

tool: {"D101": [0.0,-0.0,0.0,0.0]}

tool: D112: 1

tool: {"D95": [0x61,0xda,0x6a,0xe8,0xfc,0x9a,0x70,0xbf]}

tool: {"D12": [0x4f,0xad,0x8c,0x37,0xca,0x62,0x96,0x3f]}

tool: {"D91": [0xdc,0x29,0xa5,0x78,0x38,0xa0,0xac,0x3f]}

tool: {"D65": [0xed,0x9f,0x16,0xe8,0xfb,0xae,0xb8,0x3f]}

tool: {"D30": [0x25,0xc9,0xcd,0x5a,0x8c,0xcd,0xc1,0x3f]}

tool: {"D25": [0x8f,0x49,0xba,0xb6,0x14,0x88,0xc9,0x3f]}

tool: {"D69": [0x2b,0xb0,0x49,0x7c,0xc3,0x54,0xd5,0x3f]}

tool: {"D22": [0x61,0x79,0xda,0x99,0xfe,0xff,0xef,0x3f]}

tool: D68: 0.785398163397

assistant: ```c
double atan(x)
double x;
{
  double xi, q, q2, y;
  int sign;
  xi = (x < 0. ? -x : x);
  q = (xi - 1.0) / (xi + 1.0);
  q2 = q * q;
  y = (((((((-.0040540580 * q2 + .0218612286) * q2 - .0559098861) * q2 + .0964200441) * q2 - .1390853351) * q2 + .1994653599) * q2 - .3332985605) * q2 + .9999993329) * q + 0.785398163397;
  return (x < 0. ? -y : y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<atan>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm3,%xmm3
  xorpd  D109(%rip),%xmm0
  movapd %xmm2,%xmm1
  comisd %xmm2,%xmm3
  cmpltsd %xmm3,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm2,%xmm1
  orpd   %xmm1,%xmm0
  movsd  D90(%rip),%xmm1
  movapd %xmm0,%xmm4
  subsd  %xmm1,%xmm4
  addsd  %xmm1,%xmm0
  movsd  D86(%rip),%xmm1
  divsd  %xmm0,%xmm4
  movapd %xmm4,%xmm0
  mulsd  %xmm4,%xmm0
  mulsd  %xmm0,%xmm1
  addsd  D113(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D30(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D24(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D105(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D98(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D18(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D91(%rip),%xmm0
  mulsd  %xmm4,%xmm0
  addsd  D66(%rip),%xmm0
  ja     L9
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xorpd  D109(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D109
datatype: f32[4]
name: parse_data
arguments: data_label: D90
datatype: f64
name: parse_data
arguments: data_label: D86
datatype: byte[8]
name: parse_data
arguments: data_label: D113
datatype: byte[8]
name: parse_data
arguments: data_label: D30
datatype: byte[8]
name: parse_data
arguments: data_label: D24
datatype: byte[8]
name: parse_data
arguments: data_label: D105
datatype: byte[8]
name: parse_data
arguments: data_label: D98
datatype: byte[8]
name: parse_data
arguments: data_label: D18
datatype: byte[8]
name: parse_data
arguments: data_label: D91
datatype: byte[8]
name: parse_data
arguments: data_label: D66
datatype: f64

tool: {"D109": [0.0,-0.0,0.0,0.0]}

tool: D90: 1

tool: {"D86": [0x61,0xda,0x6a,0xe8,0xfc,0x9a,0x70,0xbf]}

tool: {"D113": [0x4f,0xad,0x8c,0x37,0xca,0x62,0x96,0x3f]}

tool: {"D30": [0xdc,0x29,0xa5,0x78,0x38,0xa0,0xac,0x3f]}

tool: {"D24": [0xed,0x9f,0x16,0xe8,0xfb,0xae,0xb8,0x3f]}

tool: {"D105": [0x25,0xc9,0xcd,0x5a,0x8c,0xcd,0xc1,0x3f]}

tool: {"D98": [0x8f,0x49,0xba,0xb6,0x14,0x88,0xc9,0x3f]}

tool: {"D18": [0x2b,0xb0,0x49,0x7c,0xc3,0x54,0xd5,0x3f]}

tool: {"D91": [0x61,0x79,0xda,0x99,0xfe,0xff,0xef,0x3f]}

tool: D66: 0.785398163397

assistant: ```c
double atan(x)
double x;
{
  double xi, q, q2, y;
  int sign;
  xi = (x < 0. ? -x : x);
  q = (xi - 1.0) / (xi + 1.0);
  q2 = q * q;
  y = (((((((-.0040540580 * q2 + .0218612286) * q2 - .0559098861) * q2 + .0964200441) * q2 - .1390853351) * q2 + .1994653599) * q2 - .3332985605) * q2 + .9999993329) * q + 0.785398163397;
  return (x < 0. ? -y : y);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uninitvar_strncpy_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %rcx,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rcx
  mov    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rsi
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strncpy_s@plt>
  mov    -0x80(%rbp),%rcx
  mov    -0x78(%rbp),%rdx
  mov    -0x58(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strncpy_s@plt>
  mov    -0x80(%rbp),%rcx
  mov    -0x50(%rbp),%rdx
  mov    -0x70(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strncpy_s@plt>
  mov    -0x48(%rbp),%rcx
  mov    -0x78(%rbp),%rdx
  mov    -0x70(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strncpy_s@plt>
  mov    -0x80(%rbp),%rcx
  mov    -0x78(%rbp),%rdx
  mov    -0x70(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strncpy_s@plt>
  mov    -0x80(%rbp),%rcx
  mov    -0x78(%rbp),%rdx
  mov    -0x70(%rbp),%rsi
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strncpy_s@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void uninitvar_strncpy_s(char *Ct, size_t N1, char *S, size_t N2) {
  char dest[42];
  char *s;
  size_t n1;
  size_t n2;
  (void)strncpy_s(dest, n1, s, n2);
  (void)strncpy_s(Ct, n1, S, N2);
  (void)strncpy_s(Ct, N1, s, N2);
  (void)strncpy_s(Ct, N1, S, n2);
  (void)strncpy_s(Ct, N1, S, N2);
  (void)strncpy_s(dest, N1, S, N2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninitvar_strncpy_s>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%r15d
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <strncpy_s@plt>
  mov    %r12,%rcx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncpy_s@plt>
  mov    $0x0,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncpy_s@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncpy_s@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_strncpy_s(char *Ct, size_t N1, char *S, size_t N2) {
  char dest[42];
  char *s;
  size_t n1;
  size_t n2;
  (void)strncpy_s(dest, n1, s, n2);
  (void)strncpy_s(Ct, n1, S, N2);
  (void)strncpy_s(Ct, N1, s, N2);
  (void)strncpy_s(Ct, N1, S, n2);
  (void)strncpy_s(Ct, N1, S, N2);
  (void)strncpy_s(dest, N1, S, N2);
}
```