ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<mqc_FINDstrINline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L44
  mov    $0xffffffff,%eax
  jmp    L6
L44:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L46
L7:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L59
  mov    -0xc(%rbp),%eax
  jmp    L6
L59:
  addl   $0x1,-0xc(%rbp)
L46:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L7
  mov    $0xffffffff,%eax
L6:
  leave
  ret
```

assistant: ```c
int mqc_FINDstrINline(char *string, char *line) {
  int i, imax;
  int stringlen;
  stringlen = (int)strlen(string);
  if (stringlen == 0)
    return (-1);
  imax = (int)strlen(line) - stringlen + 1;
  for (i = 0; i < imax; i++) {
    if (0 == strncmp(&line[i], string, (size_t)stringlen)) {
      return (i);
    }
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mqc_FINDstrINline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  je     L58
  mov    %rax,%rbx
  mov    %eax,%r14d
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  sub    %ebx,%r13d
  js     L9
  mov    $0x0,%ebx
  movslq %r14d,%r14
L7:
  mov    %ebx,%r15d
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L54
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L7
  mov    $0xffffffff,%r15d
L54:
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  mov    $0xffffffff,%r15d
  jmp    L54
L9:
  mov    $0xffffffff,%r15d
  jmp    L54
```

assistant: ```c
int mqc_FINDstrINline(char *string, char *line) {
  int i, imax;
  int stringlen;
  stringlen = (int)strlen(string);
  if (stringlen == 0)
    return (-1);
  imax = (int)strlen(line) - stringlen + 1;
  for (i = 0; i < imax; i++) {
    if (0 == strncmp(&line[i], string, (size_t)stringlen)) {
      return (i);
    }
  }
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mqc_FINDstrINline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L5
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %eax,%r14d
  sub    %ebp,%r14d
  js     L5
  movslq %ebp,%rbp
  xor    %ebx,%ebx
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rbx
  cmp    %ebx,%r14d
  jl     L5
L47:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %ebx,%r15d
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L12
L15:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%r15d
  jmp    L15
```

assistant: ```c
int mqc_FINDstrINline(char *string, char *line) {
  int i, imax;
  int stringlen;
  stringlen = (int)strlen(string);
  if (stringlen == 0)
    return (-1);
  imax = (int)strlen(line) - stringlen + 1;
  for (i = 0; i < imax; i++) {
    if (0 == strncmp(&line[i], string, (size_t)stringlen)) {
      return (i);
    }
  }
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mqc_FINDstrINline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L3
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %eax,%r14d
  sub    %ebp,%r14d
  js     L3
  movslq %ebp,%rbp
  xor    %ebx,%ebx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rbx
  cmp    %ebx,%r14d
  jl     L3
L24:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %ebx,%r15d
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L19
L45:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%r15d
  jmp    L45
```

assistant: ```c
int mqc_FINDstrINline(char *string, char *line) {
  int i, imax;
  int stringlen;
  stringlen = (int)strlen(string);
  if (stringlen == 0)
    return (-1);
  imax = (int)strlen(line) - stringlen + 1;
  for (i = 0; i < imax; i++) {
    if (0 == strncmp(&line[i], string, (size_t)stringlen)) {
      return (i);
    }
  }
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L25
  mov    -0x18(%rbp),%rax
  jmp    L7
L25:
  movq   $0x0,-0x8(%rbp)
  jmp    L30
L5:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L5
  mov    -0x18(%rbp),%rax
L7:
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *s, const void *ct, size_t n) {
  if (s == ct) {
    return (s);
  }
  for (size_t i = 0; i < n; ++i) {
    ((uint8_t *)s)[i] = ((uint8_t *)ct)[i];
  }
  return (s);
}
```
user: What is the c source code of the assembly code below?

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  je     L16
  test   %rdx,%rdx
  je     L16
  mov    $0x0,%ecx
L22:
  mov    (%rsi,%rcx,4),%r8d
  mov    %r8d,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L22
L16:
  ret
```

assistant: ```c
void *memcpy(void *s, const void *ct, size_t n) {
  if (s == ct) {
    return (s);
  }
  for (size_t i = 0; i < n; ++i) {
    ((uint8_t *)s)[i] = ((uint8_t *)ct)[i];
  }
  return (s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  je     L2
  test   %rdx,%rdx
  je     L2
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rsi,%rcx,4),%r8d
  mov    %r8d,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L19
L2:
  ret
```

assistant: ```c
void *memcpy(void *s, const void *ct, size_t n) {
  if (s == ct) {
    return (s);
  }
  for (size_t i = 0; i < n; ++i) {
    ((uint8_t *)s)[i] = ((uint8_t *)ct)[i];
  }
  return (s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  cmp    %rsi,%rdi
  je     L79
  test   %rdx,%rdx
  je     L79
  lea    0x4(%rsi),%rsi
  mov    %rdi,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L51
  lea    -0x1(%rdx),%rax
  cmp    $0x2,%rax
  jbe    L51
  mov    %rdx,%rsi
  xor    %eax,%eax
  shr    $0x2,%rsi
  shl    $0x4,%rsi
  nop
L77:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L77
  mov    %rdx,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%dl
  je     L79
  mov    (%rcx,%rax,4),%edi
  lea    0x0(,%rax,4),%rsi
  mov    %edi,(%r8,%rax,4)
  lea    0x1(%rax),%rdi
  cmp    %rdi,%rdx
  jbe    L79
  mov    0x4(%rcx,%rsi,1),%edi
  add    $0x2,%rax
  mov    %edi,0x4(%r8,%rsi,1)
  cmp    %rax,%rdx
  jbe    L79
  mov    0x8(%rcx,%rsi,1),%eax
  mov    %eax,0x8(%r8,%rsi,1)
L79:
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L51:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L74:
  mov    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L74
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memcpy(void *s, const void *ct, size_t n) {
  if (s == ct) {
    return (s);
  }
  for (size_t i = 0; i < n; ++i) {
    ((uint8_t *)s)[i] = ((uint8_t *)ct)[i];
  }
  return (s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    (%rdi),%ebp
  cmp    $0x1fff,%rdx
  jg     L11
  cmp    $0xf,%rdx
  jle    L18
L36:
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  jmp    L36
L11:
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  jmp    L11
L18:
  mov    %rbp,(%rdi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((__target__("sse4"))) void bar(unsigned long long *x, const void *b, long long m) {
  const unsigned char *p = (const unsigned char *)b;
  const unsigned char *e = p + m;
  unsigned int l = *x;
  unsigned long long n = l;
  if ((e - p) >= 8192) {
    while ((e - p) >= 128) {
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
    }
  }
  while ((e - p) >= 16) {
    n = __builtin_ia32_crc32di(n, foo(p));
    n = __builtin_ia32_crc32di(n, foo(p));
  }
  l = n;
  *x = l;
}
```
user: What is the c source code of the assembly code below?

```asm
<bar>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%ebp
  cmp    $0x1fff,%rdx
  jg     L9
  cmp    $0xf,%rdx
  jle    L16
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  jmp    L38
  nopl   0x0(%rax)
L9:
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  jmp    L9
L16:
  mov    %rbp,(%rdi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((__target__("sse4"))) void bar(unsigned long long *x, const void *b, long long m) {
  const unsigned char *p = (const unsigned char *)b;
  const unsigned char *e = p + m;
  unsigned int l = *x;
  unsigned long long n = l;
  if ((e - p) >= 8192) {
    while ((e - p) >= 128) {
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
    }
  }
  while ((e - p) >= 16) {
    n = __builtin_ia32_crc32di(n, foo(p));
    n = __builtin_ia32_crc32di(n, foo(p));
  }
  l = n;
  *x = l;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bar>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%ebp
  cmp    $0x1fff,%rdx
  jg     L11
  cmp    $0xf,%rdx
  jle    L17
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  jmp    L7
  nopl   0x0(%rax)
L11:
  mov    %rbx,%rdi
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <__builtin_ia32_crc32di@plt>
  mov    %rax,%rbp
  jmp    L11
L17:
  mov    %rbp,(%rdi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((__target__("sse4"))) void bar(unsigned long long *x, const void *b, long long m) {
  const unsigned char *p = (const unsigned char *)b;
  const unsigned char *e = p + m;
  unsigned int l = *x;
  unsigned long long n = l;
  if ((e - p) >= 8192) {
    while ((e - p) >= 128) {
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
      n = __builtin_ia32_crc32di(n, foo(p));
    }
  }
  while ((e - p) >= 16) {
    n = __builtin_ia32_crc32di(n, foo(p));
    n = __builtin_ia32_crc32di(n, foo(p));
  }
  l = n;
  *x = l;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pri_clear_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L17
  mov    -0x20(%rbp),%rax
  and    $0x7,%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %al,-0x2(%rbp)
  mov    -0x28(%rbp),%rax
  not    %eax
  and    $0x7,%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %al,-0x1(%rbp)
  shrq   $0x3,-0x20(%rbp)
  shrq   $0x3,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L2
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  movzbl -0x2(%rbp),%eax
  or     -0x1(%rbp),%al
  mov    %eax,%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L43
L2:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rdx),%edx
  mov    -0x18(%rbp),%rcx
  add    %rax,%rcx
  mov    %edx,%eax
  and    -0x2(%rbp),%al
  mov    %al,(%rcx)
  jmp    L25
L37:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
L25:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L37
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  and    -0x1(%rbp),%al
  mov    %al,(%rdx)
  jmp    L43
L17:
  nop
L43:
  pop    %rbp
  ret
```

assistant: ```c
void pri_clear_bits(unsigned char *buf, unsigned long i1, unsigned long i2) {
  unsigned char m1, m2;
  if (i2 < i1) {
    return;
  }
  m1 = ~(0xff >> (i1 & 7));
  m2 = ~(0xff << (~i2 & 7));
  i1 >>= 3;
  i2 >>= 3;
  if (i1 == i2) {
    buf[i1] &= m1 | m2;
  } else {
    buf[i1++] &= m1;
    while (i1 < i2) {
      buf[i1++] = 0;
    }
    buf[i2] &= m2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pri_clear_bits>:
  endbr64
  cmp    %rsi,%rdx
  jb     L0
  mov    %esi,%ecx
  and    $0x7,%ecx
  mov    $0xff,%eax
  mov    %eax,%r8d
  sar    %cl,%r8d
  mov    %edx,%ecx
  not    %ecx
  and    $0x7,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  shr    $0x3,%rsi
  shr    $0x3,%rdx
  cmp    %rdx,%rsi
  je     L31
  lea    0x1(%rsi),%rax
  not    %r8d
  and    %r8b,(%rdi,%rsi,1)
  cmp    %rax,%rdx
  jbe    L35
  add    %rdi,%rax
  lea    (%rdi,%rdx,1),%rsi
L34:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L34
L35:
  mov    %ecx,%eax
  not    %eax
  and    %al,(%rdi,%rdx,1)
L0:
  ret
L31:
  and    %r8d,%eax
  not    %eax
  and    %al,(%rdi,%rsi,1)
  ret
```

assistant: ```c
void pri_clear_bits(unsigned char *buf, unsigned long i1, unsigned long i2) {
  unsigned char m1, m2;
  if (i2 < i1) {
    return;
  }
  m1 = ~(0xff >> (i1 & 7));
  m2 = ~(0xff << (~i2 & 7));
  i1 >>= 3;
  i2 >>= 3;
  if (i1 == i2) {
    buf[i1] &= m1 | m2;
  } else {
    buf[i1++] &= m1;
    while (i1 < i2) {
      buf[i1++] = 0;
    }
    buf[i2] &= m2;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pri_clear_bits>:
  endbr64
  cmp    %rsi,%rdx
  jb     L5
  push   %r12
  mov    %esi,%ecx
  mov    $0xff,%r12d
  shr    $0x3,%rsi
  and    $0x7,%ecx
  mov    %r12d,%eax
  push   %rbp
  mov    %rdi,%rbp
  sar    %cl,%eax
  mov    %edx,%ecx
  push   %rbx
  mov    %rdx,%rbx
  not    %ecx
  lea    (%rdi,%rsi,1),%rdx
  shr    $0x3,%rbx
  and    $0x7,%ecx
  shl    %cl,%r12d
  movzbl (%rdx),%ecx
  cmp    %rbx,%rsi
  je     L23
  not    %eax
  lea    0x1(%rsi),%rdi
  and    %ecx,%eax
  mov    %al,(%rdx)
  cmp    %rdi,%rbx
  jbe    L21
  mov    %rbx,%rdx
  add    %rbp,%rdi
  sub    %rsi,%rdx
  xor    %esi,%esi
  sub    $0x1,%rdx
  call   <memset@plt>
L21:
  not    %r12d
  and    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L23:
  and    %r12d,%eax
  not    %eax
  and    %ecx,%eax
  mov    %al,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void pri_clear_bits(unsigned char *buf, unsigned long i1, unsigned long i2) {
  unsigned char m1, m2;
  if (i2 < i1) {
    return;
  }
  m1 = ~(0xff >> (i1 & 7));
  m2 = ~(0xff << (~i2 & 7));
  i1 >>= 3;
  i2 >>= 3;
  if (i1 == i2) {
    buf[i1] &= m1 | m2;
  } else {
    buf[i1++] &= m1;
    while (i1 < i2) {
      buf[i1++] = 0;
    }
    buf[i2] &= m2;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pri_clear_bits>:
  endbr64
  cmp    %rsi,%rdx
  jb     L2
  push   %r12
  mov    %esi,%ecx
  mov    $0xff,%r12d
  shr    $0x3,%rsi
  and    $0x7,%ecx
  mov    %r12d,%eax
  push   %rbp
  mov    %rdi,%rbp
  sar    %cl,%eax
  mov    %edx,%ecx
  push   %rbx
  mov    %rdx,%rbx
  not    %ecx
  lea    (%rdi,%rsi,1),%rdx
  shr    $0x3,%rbx
  and    $0x7,%ecx
  shl    %cl,%r12d
  movzbl (%rdx),%ecx
  cmp    %rbx,%rsi
  je     L28
  not    %eax
  lea    0x1(%rsi),%rdi
  and    %ecx,%eax
  mov    %al,(%rdx)
  cmp    %rdi,%rbx
  jbe    L21
  mov    %rbx,%rdx
  add    %rbp,%rdi
  sub    %rsi,%rdx
  xor    %esi,%esi
  sub    $0x1,%rdx
  call   <memset@plt>
L21:
  not    %r12d
  and    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L28:
  and    %r12d,%eax
  not    %eax
  and    %ecx,%eax
  mov    %al,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void pri_clear_bits(unsigned char *buf, unsigned long i1, unsigned long i2) {
  unsigned char m1, m2;
  if (i2 < i1) {
    return;
  }
  m1 = ~(0xff >> (i1 & 7));
  m2 = ~(0xff << (~i2 & 7));
  i1 >>= 3;
  i2 >>= 3;
  if (i1 == i2) {
    buf[i1] &= m1 | m2;
  } else {
    buf[i1++] &= m1;
    while (i1 < i2) {
      buf[i1++] = 0;
    }
    buf[i2] &= m2;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<http_generic_404>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x194,%esi
  mov    %rax,%rdi
  call   <http_response@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int http_generic_404(struct http_request *req) {
  ;
  http_response(req, 404, NULL, 0);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<http_generic_404>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x194,%esi
  call   <http_response@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int http_generic_404(struct http_request *req) {
  ;
  http_response(req, 404, NULL, 0);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<http_generic_404>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x194,%esi
  call   <http_response@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int http_generic_404(struct http_request *req) {
  ;
  http_response(req, 404, NULL, 0);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<http_generic_404>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x194,%esi
  call   <http_response@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int http_generic_404(struct http_request *req) {
  ;
  http_response(req, 404, NULL, 0);
  return (1);
}
```