ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<mempcpy3>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rsi
  lea    0x2(%rsp),%rdi
  movl   $0x4030201,0x4(%rsp)
  call   <mempcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mempcpy3() {
  char src[] = {1, 2, 3, 4};
  char dst[3];
  mempcpy(dst + 1, src + 2, 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *substring(char *unString, int start, int end) {
  char *subbuff = malloc(end - start);
  memcpy(subbuff, unString + start, end - start);
  subbuff[end - start] = '\0';
  return subbuff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<substring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  sub    %esi,%edx
  mov    %edx,%ebx
  mov    %edx,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  movslq %ebp,%rbp
  lea    0x0(%r13,%rbp,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substring(char *unString, int start, int end) {
  char *subbuff = malloc(end - start);
  memcpy(subbuff, unString + start, end - start);
  subbuff[end - start] = '\0';
  return subbuff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<substring>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  sub    %ebp,%edx
  movslq %edx,%rbx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    (%r12,%rbp,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substring(char *unString, int start, int end) {
  char *subbuff = malloc(end - start);
  memcpy(subbuff, unString + start, end - start);
  subbuff[end - start] = '\0';
  return subbuff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L20
L5:
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0xffffffff,%eax
  jmp    L20
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xc(%rbp),%eax
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D4: wb

assistant: ```c
int file_write(const char *file, unsigned char *buf, unsigned int length) {
  FILE *fd = NULL;
  fd = fopen(file, "wb");
  if (fd == NULL) {
    return -1;
  }
  int bytes = fwrite(buf, 1, length, fd);
  if (bytes != length) {
    fclose(fd);
    return -1;
  }
  fclose(fd);
  return bytes;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<file_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbx
  mov    %rax,%rcx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %eax,%ebp
  cmp    %r12d,%eax
  jne    L2
  mov    %rbx,%rdi
  call   <fclose@plt>
L25:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0xffffffff,%ebp
  jmp    L25
L10:
  mov    $0xffffffff,%ebp
  jmp    L25
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: wb

assistant: ```c
int file_write(const char *file, unsigned char *buf, unsigned int length) {
  FILE *fd = NULL;
  fd = fopen(file, "wb");
  if (fd == NULL) {
    return -1;
  }
  int bytes = fwrite(buf, 1, length, fd);
  if (bytes != length) {
    fclose(fd);
    return -1;
  }
  fclose(fd);
  return bytes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_write>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D6(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <fopen@plt>
  test   %rax,%rax
  je     L17
  mov    %r12,%rdi
  mov    %rax,%rcx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  cmp    %ebx,%eax
  jne    L16
  call   <fclose@plt>
L25:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  call   <fclose@plt>
  mov    $0xffffffff,%r12d
  jmp    L25
L17:
  mov    $0xffffffff,%r12d
  jmp    L25
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string

tool: D6: wb

assistant: ```c
int file_write(const char *file, unsigned char *buf, unsigned int length) {
  FILE *fd = NULL;
  fd = fopen(file, "wb");
  if (fd == NULL) {
    return -1;
  }
  int bytes = fwrite(buf, 1, length, fd);
  if (bytes != length) {
    fclose(fd);
    return -1;
  }
  fclose(fd);
  return bytes;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<file_write>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D3(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <fopen@plt>
  test   %rax,%rax
  je     L16
  mov    %r12,%rdi
  mov    %rax,%rcx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  cmp    %ebx,%eax
  jne    L7
  call   <fclose@plt>
L5:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  call   <fclose@plt>
  mov    $0xffffffff,%r12d
  jmp    L5
L16:
  mov    $0xffffffff,%r12d
  jmp    L5
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: wb

assistant: ```c
int file_write(const char *file, unsigned char *buf, unsigned int length) {
  FILE *fd = NULL;
  fd = fopen(file, "wb");
  if (fd == NULL) {
    return -1;
  }
  int bytes = fwrite(buf, 1, length, fd);
  if (bytes != length) {
    fclose(fd);
    return -1;
  }
  fclose(fd);
  return bytes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L0:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L0
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t map(void **array, size_t len, void (*func)(void *)) {
  size_t i;
  for (i = 0; i < len; i++) {
    func(array[i]);
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<map>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L12
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    $0x0,%ebx
L7:
  mov    (%r12,%rbx,8),%rdi
  call   *%r13
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L7
L12:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t map(void **array, size_t len, void (*func)(void *)) {
  size_t i;
  for (i = 0; i < len; i++) {
    func(array[i]);
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<map>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%rbp
  mov    %rdx,%r13
  xor    %ebx,%ebx
  xchg   %ax,%ax
L2:
  mov    0x0(%rbp,%rbx,8),%rdi
  add    $0x1,%rbx
  call   *%r13
  cmp    %rbx,%r12
  jne    L2
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t map(void **array, size_t len, void (*func)(void *)) {
  size_t i;
  for (i = 0; i < len; i++) {
    func(array[i]);
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<map>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L1
  mov    %rdi,%rbp
  mov    %rdx,%r13
  xor    %ebx,%ebx
  xchg   %ax,%ax
L3:
  mov    0x0(%rbp,%rbx,8),%rdi
  add    $0x1,%rbx
  call   *%r13
  cmp    %rbx,%r12
  jne    L3
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t map(void **array, size_t len, void (*func)(void *)) {
  size_t i;
  for (i = 0; i < len; i++) {
    func(array[i]);
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xa,-0x18(%rbp)
  movl   $0x14,-0x14(%rbp)
  movss  D36(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D32(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x8(%rbp)
  movss  -0x10(%rbp),%xmm0
  divss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8(%rbp),%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D36
data_type: f32
name: parse_data
arguments: data_label: D32
data_type: f32
name: parse_data
arguments: data_label: D16
data_type: string
name: parse_data
arguments: data_label: D6
data_type: string

tool: D36: 10.24

tool: D32: 9.68

tool: D16: integer divission: %d


tool: D6: floating point divission: %f


assistant: ```c
int main(void) {
  int x = 10, y = 20, z;
  float m = 10.24, n = 9.68, o;
  z = y / x;
  o = m / n;
  printf("integer divission: %d\n", z);
  printf("floating point divission: %f\n", o);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D11(%rip),%xmm0
  lea    D21(%rip),%rdi
  call   <printf@plt>
  movss  D18(%rip),%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D18
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: {"D11": [0x00,0x00,0x00,0x40]}

tool: D21: integer divission: %d


tool: {"D18": [0xab,0x67,0x87,0x3f]}

tool: D8: floating point divission: %f


assistant: ```c
int main(void) {
  int x = 10, y = 20, z;
  float m = 10.24, n = 9.68, o;
  z = y / x;
  o = m / n;
  printf("integer divission: %d\n", z);
  printf("floating point divission: %f\n", o);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D0(%rip),%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  movss  D25(%rip),%xmm0
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D8
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D19
type_guessed: string

tool: {"D0": [0x00,0x00,0x00,0x40]}

tool: D8: integer divission: %d


tool: {"D25": [0xab,0x67,0x87,0x3f]}

tool: D19: floating point divission: %f


assistant: ```c
int main(void) {
  int x = 10, y = 20, z;
  float m = 10.24, n = 9.68, o;
  z = y / x;
  o = m / n;
  printf("integer divission: %d\n", z);
  printf("floating point divission: %f\n", o);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D8(%rip),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  movss  D25(%rip),%xmm0
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string

tool: {"D8": [0x00,0x00,0x00,0x40]}

tool: D0: integer divission: %d


tool: {"D25": [0xab,0x67,0x87,0x3f]}

tool: D16: floating point divission: %f


assistant: ```c
int main(void) {
  int x = 10, y = 20, z;
  float m = 10.24, n = 9.68, o;
  z = y / x;
  o = m / n;
  printf("integer divission: %d\n", z);
  printf("floating point divission: %f\n", o);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<char_to_wide>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L27
  mov    %rdi,(%rsp)
L0:
  movzbl (%rbx),%eax
  mov    $0x0,%edx
  test   %al,%al
  je     L9
L49:
  movzbl %al,%eax
  mov    (%rsp),%rcx
  mov    %ax,(%rcx,%rdx,2)
  add    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%eax
  test   %al,%al
  jne    L49
L9:
  mov    (%rsp),%rax
  movw   $0x0,(%rax,%rdx,2)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x10,%rsp
  pop    %rbx
  ret
L27:
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x2(%rax,%rax,1),%esi
  mov    %rsp,%rdi
  mov    $0xa,%ecx
  lea    D0(%rip),%rdx
  call   <willus_mem_alloc_warn@plt>
  jmp    L0
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string

tool: D0: char_to_wide

assistant: ```c
short *char_to_wide(short *d, char *s) {
  static char *funcname = "char_to_wide";
  unsigned short *x;
  unsigned char *p;
  int i;
  if (d == NULL)
    willus_mem_alloc_warn((void **)&x, sizeof(short) * (strlen(s) + 1), funcname, 10);
  else
    x = (unsigned short *)d;
  p = (unsigned char *)s;
  for (i = 0; p[i] != '\0'; i++)
    x[i] = p[i];
  x[i] = 0;
  return ((short *)x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<char_to_wide>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  test   %rdi,%rdi
  je     L18
  movzbl (%rbx),%edx
  mov    %rdi,(%rsp)
  mov    %rdi,%rax
  xor    %ecx,%ecx
  test   %dl,%dl
  je     L19
  nopl   0x0(%rax)
L9:
  mov    %dx,(%rax,%rcx,2)
  add    $0x1,%rcx
  movzbl (%rbx,%rcx,1),%edx
  test   %dl,%dl
  jne    L9
  lea    (%rax,%rcx,2),%rdx
L48:
  xor    %ecx,%ecx
  mov    %cx,(%rdx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    $0xa,%ecx
  lea    D0(%rip),%rdx
  mov    %rsp,%rdi
  lea    0x2(%rax,%rax,1),%esi
  call   <willus_mem_alloc_warn@plt>
  movzbl (%rbx),%edx
  mov    (%rsp),%rax
  xor    %ecx,%ecx
  test   %dl,%dl
  jne    L9
  nopl   (%rax)
L19:
  mov    %rax,%rdx
  jmp    L48
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: char_to_wide

assistant: ```c
short *char_to_wide(short *d, char *s) {
  static char *funcname = "char_to_wide";
  unsigned short *x;
  unsigned char *p;
  int i;
  if (d == NULL)
    willus_mem_alloc_warn((void **)&x, sizeof(short) * (strlen(s) + 1), funcname, 10);
  else
    x = (unsigned short *)d;
  p = (unsigned char *)s;
  for (i = 0; p[i] != '\0'; i++)
    x[i] = p[i];
  x[i] = 0;
  return ((short *)x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<char_to_wide>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  test   %rdi,%rdi
  je     L2
  movzbl (%rbx),%edx
  mov    %rdi,(%rsp)
  mov    %rdi,%rax
  xor    %ecx,%ecx
  test   %dl,%dl
  je     L4
  nopl   0x0(%rax)
L50:
  mov    %dx,(%rax,%rcx,2)
  add    $0x1,%rcx
  movzbl (%rbx,%rcx,1),%edx
  test   %dl,%dl
  jne    L50
  lea    (%rax,%rcx,2),%rdx
L3:
  xor    %ecx,%ecx
  mov    %cx,(%rdx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    $0xa,%ecx
  lea    D6(%rip),%rdx
  mov    %rsp,%rdi
  lea    0x2(%rax,%rax,1),%esi
  call   <willus_mem_alloc_warn@plt>
  movzbl (%rbx),%edx
  mov    (%rsp),%rax
  xor    %ecx,%ecx
  test   %dl,%dl
  jne    L50
  nopl   (%rax)
L4:
  mov    %rax,%rdx
  jmp    L3
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: char_to_wide

assistant: ```c
short *char_to_wide(short *d, char *s) {
  static char *funcname = "char_to_wide";
  unsigned short *x;
  unsigned char *p;
  int i;
  if (d == NULL)
    willus_mem_alloc_warn((void **)&x, sizeof(short) * (strlen(s) + 1), funcname, 10);
  else
    x = (unsigned short *)d;
  p = (unsigned char *)s;
  for (i = 0; p[i] != '\0'; i++)
    x[i] = p[i];
  x[i] = 0;
  return ((short *)x);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n >>= m;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n >>= m;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n >>= m;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n >>= m;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strings_prefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <strings_length@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <strings_alloc@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strings_prefix(char *string, unsigned int length) {
  assert(string);
  unsigned int string_length = strings_length(string);
  assert(length <= string_length);
  char *ret = strings_alloc(length + 1);
  memcpy(ret, string, length * sizeof(char));
  ret[length] = '\0';
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strings_prefix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <strings_length@plt>
  cmp    %ebx,%eax
  setae  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  lea    0x1(%rbx),%edi
  mov    $0x0,%eax
  call   <strings_alloc@plt>
  movslq %eax,%rbp
  mov    %ebx,%ebx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strings_prefix(char *string, unsigned int length) {
  assert(string);
  unsigned int string_length = strings_length(string);
  assert(length <= string_length);
  char *ret = strings_alloc(length + 1);
  memcpy(ret, string, length * sizeof(char));
  ret[length] = '\0';
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strings_prefix>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <strings_length@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  setae  %dil
  xor    %eax,%eax
  call   <assert@plt>
  lea    0x1(%rbx),%edi
  xor    %eax,%eax
  call   <strings_alloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rax,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strings_prefix(char *string, unsigned int length) {
  assert(string);
  unsigned int string_length = strings_length(string);
  assert(length <= string_length);
  char *ret = strings_alloc(length + 1);
  memcpy(ret, string, length * sizeof(char));
  ret[length] = '\0';
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strings_prefix>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <strings_length@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  setae  %dil
  xor    %eax,%eax
  call   <assert@plt>
  lea    0x1(%rbx),%edi
  xor    %eax,%eax
  call   <strings_alloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rax,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strings_prefix(char *string, unsigned int length) {
  assert(string);
  unsigned int string_length = strings_length(string);
  assert(length <= string_length);
  char *ret = strings_alloc(length + 1);
  memcpy(ret, string, length * sizeof(char));
  ret[length] = '\0';
  return ret;
}
```