ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L12:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int len(char a[]) {
  int i, count = 0;
  for (i = 0; a[i] != '\0'; i++)
    count++;
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L28
  mov    $0x1,%eax
L22:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L22
L27:
  mov    %edx,%eax
  ret
L28:
  mov    $0x0,%edx
  jmp    L27
```

assistant: ```c
int len(char a[]) {
  int i, count = 0;
  for (i = 0; a[i] != '\0'; i++)
    count++;
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L16
  mov    $0x1,%eax
  xchg   %ax,%ax
L7:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L7
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int len(char a[]) {
  int i, count = 0;
  for (i = 0; a[i] != '\0'; i++)
    count++;
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L13
  mov    $0x1,%eax
  xchg   %ax,%ax
L2:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L2
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int len(char a[]) {
  int i, count = 0;
  for (i = 0; a[i] != '\0'; i++)
    count++;
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L12:
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L1:
  cmpl   $0x2,-0xc(%rbp)
  jle    L12
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_infered: string
name: disassemble_data
arguments: tag: D6
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D29: cbrt

tool: D6: # c::%s


tool: D10: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "cbrt");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D17(%rip),%r13
  lea    D29(%rip),%r12
  lea    D0(%rip),%rbp
L5:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L5
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type: string
name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D17: cbrt

tool: D29: # c::%s


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "cbrt");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D26(%rip),%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D26
type_infered: string
name: read_data
arguments: label: D9
type_infered: string
name: read_data
arguments: label: D7
type_infered: string

tool: D26: cbrt

tool: D9: # c::%s


tool: D7: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "cbrt");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D14(%rip),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D19
type: string
name: disassemble_data
arguments: tag: D10
type: string

tool: D14: cbrt

tool: D19: # c::%s


tool: D10: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "cbrt");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: CTF{Time_to_read_that_underrated_Large_Memory_Management_Vulnerabilities_paper}

assistant: ```c
int main(void) {
  puts("CTF{Time_to_read_that_underrated_Large_Memory_Management_Vulnerabilities_paper}");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: CTF{Time_to_read_that_underrated_Large_Memory_Management_Vulnerabilities_paper}

assistant: ```c
int main(void) {
  puts("CTF{Time_to_read_that_underrated_Large_Memory_Management_Vulnerabilities_paper}");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: CTF{Time_to_read_that_underrated_Large_Memory_Management_Vulnerabilities_paper}

assistant: ```c
int main(void) {
  puts("CTF{Time_to_read_that_underrated_Large_Memory_Management_Vulnerabilities_paper}");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: CTF{Time_to_read_that_underrated_Large_Memory_Management_Vulnerabilities_paper}

assistant: ```c
int main(void) {
  puts("CTF{Time_to_read_that_underrated_Large_Memory_Management_Vulnerabilities_paper}");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0x51,-0x8(%rbp)
  movl   $0x51,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <PrintRandoms@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int lower = 1, upper = 81, count = 81;
  PrintRandoms(lower, upper, count);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x51,%edx
  mov    $0x51,%esi
  mov    $0x1,%edi
  call   <PrintRandoms@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int lower = 1, upper = 81, count = 81;
  PrintRandoms(lower, upper, count);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x51,%edx
  mov    $0x51,%esi
  mov    $0x1,%edi
  call   <PrintRandoms@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int lower = 1, upper = 81, count = 81;
  PrintRandoms(lower, upper, count);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Initial_39_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1d8,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x950,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <xsi_vlogvar_assign_value@plt>
  nop
  leave
  ret
```

assistant: ```c
void Initial_39_1(char *t0) {
  char *t1;
  char *t2;
LAB0:
  t1 = (t0 + 472);
  t2 = *((char **)t1);
  t1 = (t0 + 2384);
  xsi_vlogvar_assign_value(t1, t2, 0, 0, 1);
LAB1:
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Initial_39_1>:
  endbr64
  sub    $0x8,%rsp
  mov    0x1d8(%rdi),%rsi
  add    $0x950,%rdi
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  call   <xsi_vlogvar_assign_value@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Initial_39_1(char *t0) {
  char *t1;
  char *t2;
LAB0:
  t1 = (t0 + 472);
  t2 = *((char **)t1);
  t1 = (t0 + 2384);
  xsi_vlogvar_assign_value(t1, t2, 0, 0, 1);
LAB1:
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Initial_39_1>:
  endbr64
  mov    0x1d8(%rdi),%rsi
  mov    $0x1,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  add    $0x950,%rdi
  jmp    1050 <xsi_vlogvar_assign_value@plt>
```

assistant: ```c
void Initial_39_1(char *t0) {
  char *t1;
  char *t2;
LAB0:
  t1 = (t0 + 472);
  t2 = *((char **)t1);
  t1 = (t0 + 2384);
  xsi_vlogvar_assign_value(t1, t2, 0, 0, 1);
LAB1:
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<Initial_39_1>:
  endbr64
  mov    0x1d8(%rdi),%rsi
  mov    $0x1,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  add    $0x950,%rdi
  jmp    1050 <xsi_vlogvar_assign_value@plt>
```

assistant: ```c
void Initial_39_1(char *t0) {
  char *t1;
  char *t2;
LAB0:
  t1 = (t0 + 472);
  t2 = *((char **)t1);
  t1 = (t0 + 2384);
  xsi_vlogvar_assign_value(t1, t2, 0, 0, 1);
LAB1:
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sync_load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <g_load_library@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long sync_load(long param1, long param2) {
  long rv;
  char *libname;
  libname = (char *)param1;
  rv = g_load_library(libname);
  return rv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sync_load>:
  endbr64
  sub    $0x8,%rsp
  call   <g_load_library@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long sync_load(long param1, long param2) {
  long rv;
  char *libname;
  libname = (char *)param1;
  rv = g_load_library(libname);
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sync_load>:
  endbr64
  jmp    1050 <g_load_library@plt>
```

assistant: ```c
long sync_load(long param1, long param2) {
  long rv;
  char *libname;
  libname = (char *)param1;
  rv = g_load_library(libname);
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sync_load>:
  endbr64
  jmp    1050 <g_load_library@plt>
```

assistant: ```c
long sync_load(long param1, long param2) {
  long rv;
  char *libname;
  libname = (char *)param1;
  rv = g_load_library(libname);
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy_tlatch_to_do32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    0x20(%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_tlatch_to_do32(void *ao, void *ai) {
  unsigned *dox = (unsigned *)ao;
  unsigned *tlx = (unsigned *)ai;
  dox[(16)] = tlx[(16 * sizeof(short) / sizeof(unsigned))];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<copy_tlatch_to_do32>:
  endbr64
  mov    0x20(%rsi),%eax
  mov    %eax,0x40(%rdi)
  ret
```

assistant: ```c
void copy_tlatch_to_do32(void *ao, void *ai) {
  unsigned *dox = (unsigned *)ao;
  unsigned *tlx = (unsigned *)ai;
  dox[(16)] = tlx[(16 * sizeof(short) / sizeof(unsigned))];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_tlatch_to_do32>:
  endbr64
  mov    0x20(%rsi),%eax
  mov    %eax,0x40(%rdi)
  ret
```

assistant: ```c
void copy_tlatch_to_do32(void *ao, void *ai) {
  unsigned *dox = (unsigned *)ao;
  unsigned *tlx = (unsigned *)ai;
  dox[(16)] = tlx[(16 * sizeof(short) / sizeof(unsigned))];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_tlatch_to_do32>:
  endbr64
  mov    0x20(%rsi),%eax
  mov    %eax,0x40(%rdi)
  ret
```

assistant: ```c
void copy_tlatch_to_do32(void *ao, void *ai) {
  unsigned *dox = (unsigned *)ao;
  unsigned *tlx = (unsigned *)ai;
  dox[(16)] = tlx[(16 * sizeof(short) / sizeof(unsigned))];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x74(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type: string
name: retrieve_data
arguments: data_label: D6
type: string

tool: D19: test2 called-

tool: D6: %d

assistant: ```c
void test2(int val) {
  printf("test2 called-");
  char buf[100];
  sprintf(buf, "%d", val);
  printf(buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<test2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbp
  mov    %ebx,%edx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
datatype: string
name: disassemble_data
arguments: tag: D6
datatype: string

tool: D15: test2 called-

tool: D6: %d

assistant: ```c
void test2(int val) {
  printf("test2 called-");
  char buf[100];
  sprintf(buf, "%d", val);
  printf(buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test2>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D6(%rip),%rdi
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%edx
  lea    D5(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D6: test2 called-

tool: D5: %d

assistant: ```c
void test2(int val) {
  printf("test2 called-");
  char buf[100];
  sprintf(buf, "%d", val);
  printf(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test2>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D17(%rip),%rdi
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%edx
  lea    D16(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string

tool: D17: test2 called-

tool: D16: %d

assistant: ```c
void test2(int val) {
  printf("test2 called-");
  char buf[100];
  sprintf(buf, "%d", val);
  printf(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<drawhorzline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L23
  cmpl   $0x1df,-0x1c(%rbp)
  jg     L23
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L19
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L19:
  cmpl   $0x0,-0x18(%rbp)
  js     L97
  cmpl   $0x27f,-0x14(%rbp)
  jg     L70
  cmpl   $0x27f,-0x18(%rbp)
  jle    L44
  movl   $0x27f,-0x18(%rbp)
L44:
  cmpl   $0x0,-0x14(%rbp)
  jns    L80
  movl   $0x0,-0x14(%rbp)
  jmp    L80
L98:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <drawdotfast@plt>
  addl   $0x1,-0x14(%rbp)
L80:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L98
  jmp    L79
L23:
  nop
  jmp    L79
L97:
  nop
  jmp    L79
L70:
  nop
L79:
  leave
  ret
```

assistant: ```c
void drawhorzline(int col0, int col1, int row, int color) {
  int temp;
  if (row < 0 || row >= 480)
    return;
  if (col0 > col1) {
    temp = col0;
    col0 = col1;
    col1 = temp;
  }
  if (col1 < 0)
    return;
  if (col0 >= 640)
    return;
  if (col1 >= 640)
    col1 = 640 - 1;
  if (col0 < 0)
    col0 = 0;
  for (; col0 <= col1; col0++) {
    drawdotfast(col0, row, color);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<drawhorzline>:
  endbr64
  cmp    $0x1df,%edx
  ja     L31
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  cmp    %esi,%edi
  jle    L25
  mov    %edi,%eax
  mov    %esi,%edi
  mov    %eax,%esi
L25:
  cmp    $0x27f,%edi
  jg     L6
  test   %esi,%esi
  js     L6
  mov    $0x27f,%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  test   %edi,%edi
  mov    $0x0,%eax
  cmovns %edi,%eax
  mov    %eax,%ebx
  cmp    %eax,%esi
  jl     L6
  lea    0x1(%rsi),%ebp
L26:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <drawdotfast@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L26
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  ret
```

assistant: ```c
void drawhorzline(int col0, int col1, int row, int color) {
  int temp;
  if (row < 0 || row >= 480)
    return;
  if (col0 > col1) {
    temp = col0;
    col0 = col1;
    col1 = temp;
  }
  if (col1 < 0)
    return;
  if (col0 >= 640)
    return;
  if (col1 >= 640)
    col1 = 640 - 1;
  if (col0 < 0)
    col0 = 0;
  for (; col0 <= col1; col0++) {
    drawdotfast(col0, row, color);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<drawhorzline>:
  endbr64
  cmp    $0x1df,%edx
  ja     L8
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  jle    L46
  mov    %edi,%eax
  mov    %esi,%edi
  mov    %eax,%esi
L46:
  test   %esi,%esi
  js     L4
  cmp    $0x27f,%edi
  jg     L4
  mov    $0x27f,%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  test   %edi,%edi
  cmovns %edi,%eax
  mov    %eax,%ebx
  cmp    %eax,%esi
  jl     L4
  lea    0x1(%rsi),%ebp
  nopl   0x0(%rax)
L10:
  mov    %ebx,%edi
  mov    %r13d,%edx
  mov    %r12d,%esi
  add    $0x1,%ebx
  call   <drawdotfast@plt>
  cmp    %ebp,%ebx
  jne    L10
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L8:
  ret
```

assistant: ```c
void drawhorzline(int col0, int col1, int row, int color) {
  int temp;
  if (row < 0 || row >= 480)
    return;
  if (col0 > col1) {
    temp = col0;
    col0 = col1;
    col1 = temp;
  }
  if (col1 < 0)
    return;
  if (col0 >= 640)
    return;
  if (col1 >= 640)
    col1 = 640 - 1;
  if (col0 < 0)
    col0 = 0;
  for (; col0 <= col1; col0++) {
    drawdotfast(col0, row, color);
  }
}
```