ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<hdSurEncPhase2_D2_0F_11_sub>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  movzbl %dl,%r12d
L13:
  movzbl 0x0(%r13,%rbx,1),%edi
  mov    %r12d,%esi
  call   <hdSurEncCryptLookup_D2_0F_11@plt>
  mov    %al,(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x8,%rbx
  jne    L13
  movzbl 0x7(%rsp),%r8d
  mov    %rsp,%rdi
  lea    0x6(%rsp),%rdx
L38:
  mov    %rdx,%rsi
  movzbl 0x1(%rsp),%eax
  shr    $0x4,%al
  movzbl (%rdx),%ecx
  shl    $0x4,%ecx
  or     %ecx,%eax
  mov    %al,0x1(%rdx)
  sub    $0x1,%rdx
  cmp    %rsi,%rdi
  jne    L38
  movzbl (%rsp),%edx
  shr    $0x4,%dl
  mov    %r8d,%eax
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %al,(%rsp)
  mov    $0x0,%eax
L17:
  movzbl (%rsp,%rax,1),%edx
  xor    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hdSurEncPhase2_D2_0F_11_sub(unsigned char *CWa, unsigned char *CWb, unsigned char AddrInd) {
  unsigned char Buffer[8];
  unsigned char tmp, i;
  for (i = 0; i <= 7; ++i) {
    Buffer[i] = hdSurEncCryptLookup_D2_0F_11(CWb[i], AddrInd);
  }
  tmp = Buffer[7];
  for (i = 7; i >= 1; --i) {
    Buffer[i] = ((Buffer[1] >> 4) & 0xFF) | ((Buffer[i - 1] << 4) & 0xFF);
  }
  Buffer[0] = ((Buffer[0] >> 4) & 0xFF) | ((tmp << 4) & 0xFF);
  for (i = 0; i <= 7; ++i) {
    CWa[i] = CWa[i] ^ Buffer[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hdSurEncPhase2_D2_0F_11_sub>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  movzbl %dl,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nop
L9:
  movzbl (%r14,%rbx,1),%edi
  mov    %r13d,%esi
  call   <hdSurEncCryptLookup_D2_0F_11@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x8,%rbx
  jne    L9
  movzbl 0x7(%rsp),%esi
  lea    0x6(%rsp),%rdx
  nopl   (%rax)
L21:
  movzbl 0x1(%rsp),%eax
  movzbl (%rdx),%ecx
  mov    %rdx,%rdi
  sub    $0x1,%rdx
  shr    $0x4,%al
  shl    $0x4,%ecx
  or     %ecx,%eax
  mov    %al,0x2(%rdx)
  cmp    %rdi,%rbp
  jne    L21
  movzbl (%rsp),%eax
  shl    $0x4,%esi
  mov    %esi,%edx
  shr    $0x4,%al
  or     %eax,%edx
  xor    %eax,%eax
  mov    %dl,(%rsp)
  jmp    L39
  nopl   0x0(%rax)
L18:
  movzbl 0x0(%rbp,%rax,1),%edx
L39:
  xor    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L18
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hdSurEncPhase2_D2_0F_11_sub(unsigned char *CWa, unsigned char *CWb, unsigned char AddrInd) {
  unsigned char Buffer[8];
  unsigned char tmp, i;
  for (i = 0; i <= 7; ++i) {
    Buffer[i] = hdSurEncCryptLookup_D2_0F_11(CWb[i], AddrInd);
  }
  tmp = Buffer[7];
  for (i = 7; i >= 1; --i) {
    Buffer[i] = ((Buffer[1] >> 4) & 0xFF) | ((Buffer[i - 1] << 4) & 0xFF);
  }
  Buffer[0] = ((Buffer[0] >> 4) & 0xFF) | ((tmp << 4) & 0xFF);
  for (i = 0; i <= 7; ++i) {
    CWa[i] = CWa[i] ^ Buffer[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hdSurEncPhase2_D2_0F_11_sub>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  movzbl %dl,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  nop
L16:
  movzbl 0x0(%r13,%rbx,1),%edi
  mov    %r12d,%esi
  call   <hdSurEncCryptLookup_D2_0F_11@plt>
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x8,%rbx
  jne    L16
  movzbl (%rsp),%ecx
  movzbl 0x7(%rsp),%edi
  movzbl 0x1(%rsp),%esi
  movzbl 0x3(%rsp),%r8d
  mov    %ecx,%edx
  shl    $0x4,%edi
  movzbl 0x4(%rsp),%r9d
  movzbl 0x5(%rsp),%r10d
  shr    $0x4,%dl
  movzbl 0x6(%rsp),%r11d
  mov    %esi,%eax
  shl    $0x4,%ecx
  shr    $0x4,%al
  or     %edi,%edx
  movzbl 0x2(%rsp),%edi
  shl    $0x4,%esi
  shl    $0x4,%r8d
  shl    $0x4,%r9d
  or     %eax,%ecx
  or     %eax,%esi
  shl    $0x4,%edi
  shl    $0x4,%r10d
  or     %eax,%r8d
  or     %eax,%r9d
  shl    $0x4,%r11d
  or     %eax,%edi
  or     %eax,%r10d
  movzbl %r9b,%r9d
  or     %r11d,%eax
  movzbl %r10b,%r10d
  movzbl %r8b,%r8d
  movzbl %dil,%edi
  movzbl %al,%eax
  movzbl %sil,%esi
  movzbl %cl,%ecx
  movzbl %dl,%edx
  shl    $0x8,%rax
  movq   0x0(%rbp),%xmm0
  or     %r10,%rax
  shl    $0x8,%rax
  or     %r9,%rax
  shl    $0x8,%rax
  or     %r8,%rax
  shl    $0x8,%rax
  or     %rdi,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  movq   %rax,%xmm1
  pxor   %xmm1,%xmm0
  movq   %xmm0,0x0(%rbp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hdSurEncPhase2_D2_0F_11_sub(unsigned char *CWa, unsigned char *CWb, unsigned char AddrInd) {
  unsigned char Buffer[8];
  unsigned char tmp, i;
  for (i = 0; i <= 7; ++i) {
    Buffer[i] = hdSurEncCryptLookup_D2_0F_11(CWb[i], AddrInd);
  }
  tmp = Buffer[7];
  for (i = 7; i >= 1; --i) {
    Buffer[i] = ((Buffer[1] >> 4) & 0xFF) | ((Buffer[i - 1] << 4) & 0xFF);
  }
  Buffer[0] = ((Buffer[0] >> 4) & 0xFF) | ((tmp << 4) & 0xFF);
  for (i = 0; i <= 7; ++i) {
    CWa[i] = CWa[i] ^ Buffer[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<remove_newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L7:
  nop
  leave
  ret
```

assistant: ```c
void remove_newline(char *string) {
  char *newline;
  size_t position;
  size_t cpy_length;
  size_t str_length = strlen(string);
  if (NULL != (newline = strrchr(string, '\n'))) {
    cpy_length = strlen(newline);
    position = str_length - cpy_length;
    string[position] = '\0';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_newline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbp,%rax
  sub    %rdx,%rax
  movb   $0x0,(%rbx,%rax,1)
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_newline(char *string) {
  char *newline;
  size_t position;
  size_t cpy_length;
  size_t str_length = strlen(string);
  if (NULL != (newline = strrchr(string, '\n'))) {
    cpy_length = strlen(newline);
    position = str_length - cpy_length;
    string[position] = '\0';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_newline>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%r8
  mov    %rbp,%rax
  sub    %r8,%rax
  movb   $0x0,(%rbx,%rax,1)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_newline(char *string) {
  char *newline;
  size_t position;
  size_t cpy_length;
  size_t str_length = strlen(string);
  if (NULL != (newline = strrchr(string, '\n'))) {
    cpy_length = strlen(newline);
    position = str_length - cpy_length;
    string[position] = '\0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remove_newline>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%r8
  mov    %rbp,%rax
  sub    %r8,%rax
  movb   $0x0,(%rbx,%rax,1)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_newline(char *string) {
  char *newline;
  size_t position;
  size_t cpy_length;
  size_t str_length = strlen(string);
  if (NULL != (newline = strrchr(string, '\n'))) {
    cpy_length = strlen(newline);
    position = str_length - cpy_length;
    string[position] = '\0';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<snprintf_units>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0xf423f,-0x14(%rbp)
  jbe    L21
  mov    -0x14(%rbp),%eax
  mov    %eax,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x12,%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  lea    D20(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
L21:
  cmpl   $0x3e7,-0x14(%rbp)
  jbe    L9
  mov    -0x14(%rbp),%eax
  mov    %eax,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x6,%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  lea    D4(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L12
L9:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  lea    D16(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
L12:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D20
data_type: string
name: read_data
arguments: data_label: D4
data_type: string
name: read_data
arguments: data_label: D16
data_type: string

tool: D20: %3dM

tool: D4: %3dK

tool: D16: %3d

assistant: ```c
void snprintf_units(char *buf, size_t n, unsigned int val) {
  if (val >= 1000000)
    snprintf(buf, n, "%3dM", val / 1000000);
  if (val >= 1000)
    snprintf(buf, n, "%3dK", val / 1000);
  else
    snprintf(buf, n, "%3d", val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<snprintf_units>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  cmp    $0xf423f,%edx
  ja     L20
  cmp    $0x3e7,%edx
  ja     L22
  mov    %edx,%ecx
  lea    D17(%rip),%rdx
  call   <snprintf@plt>
  jmp    L7
L20:
  mov    %edx,%ecx
  imul   $0x431bde83,%rcx,%rcx
  shr    $0x32,%rcx
  lea    D19(%rip),%rdx
  call   <snprintf@plt>
L22:
  mov    %ebx,%ecx
  imul   $0x10624dd3,%rcx,%rcx
  shr    $0x26,%rcx
  lea    D15(%rip),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <snprintf@plt>
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D17
type: string
name: read_data
arguments: tag: D19
type: string
name: read_data
arguments: tag: D15
type: string

tool: D17: %3d

tool: D19: %3dM

tool: D15: %3dK

assistant: ```c
void snprintf_units(char *buf, size_t n, unsigned int val) {
  if (val >= 1000000)
    snprintf(buf, n, "%3dM", val / 1000000);
  if (val >= 1000)
    snprintf(buf, n, "%3dK", val / 1000);
  else
    snprintf(buf, n, "%3d", val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<snprintf_units>:
  endbr64
  push   %rbx
  mov    %edx,%ecx
  sub    $0x10,%rsp
  cmp    $0xf423f,%edx
  ja     L22
  cmp    $0x3e7,%edx
  ja     L21
  add    $0x10,%rsp
  lea    D20(%rip),%rdx
  pop    %rbx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax)
L22:
  mov    %edx,%ebx
  lea    D12(%rip),%rdx
  mov    %rsi,0x8(%rsp)
  imul   $0x431bde83,%rbx,%rcx
  mov    %rdi,(%rsp)
  shr    $0x32,%rcx
  call   <snprintf@plt>
  mov    (%rsp),%rdi
  mov    0x8(%rsp),%rsi
L18:
  imul   $0x10624dd3,%rbx,%rcx
  add    $0x10,%rsp
  lea    D29(%rip),%rdx
  pop    %rbx
  shr    $0x26,%rcx
  jmp    1050 <snprintf@plt>
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %edx,%ebx
  jmp    L18
```

tool_calls: name: read_data
arguments: label: D20
type_infered: string
name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D29
type_infered: string

tool: D20: %3d

tool: D12: %3dM

tool: D29: %3dK

assistant: ```c
void snprintf_units(char *buf, size_t n, unsigned int val) {
  if (val >= 1000000)
    snprintf(buf, n, "%3dM", val / 1000000);
  if (val >= 1000)
    snprintf(buf, n, "%3dK", val / 1000);
  else
    snprintf(buf, n, "%3d", val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<snprintf_units>:
  endbr64
  push   %rbx
  mov    %edx,%ecx
  sub    $0x10,%rsp
  cmp    $0xf423f,%edx
  ja     L14
  cmp    $0x3e7,%edx
  ja     L13
  add    $0x10,%rsp
  lea    D27(%rip),%rdx
  pop    %rbx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax)
L14:
  mov    %edx,%ebx
  lea    D1(%rip),%rdx
  mov    %rsi,0x8(%rsp)
  imul   $0x431bde83,%rbx,%rcx
  mov    %rdi,(%rsp)
  shr    $0x32,%rcx
  call   <snprintf@plt>
  mov    (%rsp),%rdi
  mov    0x8(%rsp),%rsi
L29:
  imul   $0x10624dd3,%rbx,%rcx
  add    $0x10,%rsp
  lea    D26(%rip),%rdx
  pop    %rbx
  shr    $0x26,%rcx
  jmp    1050 <snprintf@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %edx,%ebx
  jmp    L29
```

tool_calls: name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D26
data_type: string

tool: D27: %3d

tool: D1: %3dM

tool: D26: %3dK

assistant: ```c
void snprintf_units(char *buf, size_t n, unsigned int val) {
  if (val >= 1000000)
    snprintf(buf, n, "%3dM", val / 1000000);
  if (val >= 1000)
    snprintf(buf, n, "%3dK", val / 1000);
  else
    snprintf(buf, n, "%3d", val);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mempcpy9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  add    $0x4,%rcx
  lea    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  lea    -0x20(%rbp),%rcx
  add    $0x8,%rcx
  lea    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void mempcpy9() {
  int a[4] = {0};
  mempcpy(a + 2, a + 1, 4);
  mempcpy(a + 1, a + 2, 4);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mempcpy9>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x4(%rsp),%rbx
  lea    0x8(%rsp),%rbp
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <mempcpy@plt>
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mempcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mempcpy9() {
  int a[4] = {0};
  mempcpy(a + 2, a + 1, 4);
  mempcpy(a + 1, a + 2, 4);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mempcpy9>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x4,%edx
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    0x8(%rsp),%r12
  movaps %xmm0,(%rsp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mempcpy@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mempcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mempcpy9() {
  int a[4] = {0};
  mempcpy(a + 2, a + 1, 4);
  mempcpy(a + 1, a + 2, 4);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mempcpy9>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x4,%edx
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    0x8(%rsp),%r12
  movaps %xmm0,(%rsp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mempcpy@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mempcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mempcpy9() {
  int a[4] = {0};
  mempcpy(a + 2, a + 1, 4);
  mempcpy(a + 1, a + 2, 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fatt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L12
L11:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  subl   $0x2,-0xc(%rbp)
L12:
  cmpl   $0x0,-0xc(%rbp)
  jg     L11
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: f64

tool: D2: 1

assistant: ```c
double fatt(int n) {
  double result = 1.0;
  for (int i = n; i > 0; i -= 2)
    result *= i;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fatt>:
  endbr64
  test   %edi,%edi
  jle    L7
  lea    -0x2(%rdi),%eax
  lea    -0x1(%rdi),%edx
  and    $0xfffffffe,%edx
  sub    %edx,%eax
  movsd  D19(%rip),%xmm0
L13:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  mulsd  %xmm1,%xmm0
  sub    $0x2,%edi
  cmp    %eax,%edi
  jne    L13
  ret
L7:
  movsd  D19(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type: f64

tool: D19: 1

assistant: ```c
double fatt(int n) {
  double result = 1.0;
  for (int i = n; i > 0; i -= 2)
    result *= i;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fatt>:
  endbr64
  test   %edi,%edi
  jle    L4
  lea    -0x2(%rdi),%eax
  lea    -0x1(%rdi),%ecx
  movsd  D16(%rip),%xmm0
  and    $0xfffffffe,%ecx
  mov    %eax,%edx
  sub    %ecx,%edx
  jmp    L18
  nop
L2:
  sub    $0x2,%eax
L18:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  mov    %eax,%edi
  mulsd  %xmm1,%xmm0
  cmp    %edx,%eax
  jne    L2
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsd  D16(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_infered: f64

tool: D16: 1

assistant: ```c
double fatt(int n) {
  double result = 1.0;
  for (int i = n; i > 0; i -= 2)
    result *= i;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fatt>:
  endbr64
  test   %edi,%edi
  jle    L2
  lea    -0x2(%rdi),%eax
  lea    -0x1(%rdi),%ecx
  movsd  D0(%rip),%xmm0
  and    $0xfffffffe,%ecx
  mov    %eax,%edx
  sub    %ecx,%edx
  jmp    L6
  nop
L13:
  sub    $0x2,%eax
L6:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  mov    %eax,%edi
  mulsd  %xmm1,%xmm0
  cmp    %edx,%eax
  jne    L13
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  movsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: f64

tool: D0: 1

assistant: ```c
double fatt(int n) {
  double result = 1.0;
  for (int i = n; i > 0; i -= 2)
    result *= i;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<slaGeoc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sla_geoc_@plt>
  movsd  -0x18(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x50(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void slaGeoc(double p, double h, double *r, double *z) {
  double P;
  double H;
  double R;
  double Z;
  P = p;
  H = h;
  sla_geoc_(&P, &H, &R, &Z);
  *r = R;
  *z = Z;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<slaGeoc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,0x10(%rsp)
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <sla_geoc_@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaGeoc(double p, double h, double *r, double *z) {
  double P;
  double H;
  double R;
  double Z;
  P = p;
  H = h;
  sla_geoc_(&P, &H, &R, &Z);
  *r = R;
  *z = Z;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<slaGeoc>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sla_geoc_@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaGeoc(double p, double h, double *r, double *z) {
  double P;
  double H;
  double R;
  double Z;
  P = p;
  H = h;
  sla_geoc_(&P, &H, &R, &Z);
  *r = R;
  *z = Z;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<slaGeoc>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sla_geoc_@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaGeoc(double p, double h, double *r, double *z) {
  double P;
  double H;
  double R;
  double Z;
  P = p;
  H = h;
  sla_geoc_(&P, &H, &R, &Z);
  *r = R;
  *z = Z;
}
```