user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D56(%rip),%rsi
  lea    D45(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r14
  lea    0x20(%rsp),%rdx
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  cmpl   $0x0,0x20(%rsp)
  jle    L138
  movl   $0x0,0x14(%rsp)
  lea    D18(%rip),%r15
  jmp    L139
L29:
  mov    $0x5f5e0ff,%ebp
  jmp    L97
L39:
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%edi
  je     L99
L88:
  cmp    %edx,%esi
  je     L39
  mov    (%r9),%eax
  sub    (%rcx),%eax
  mov    (%r8),%r11d
  sub    (%rcx,%rbx,1),%r11d
  imul   %eax,%eax
  imul   %r11d,%r11d
  add    %r11d,%eax
  cmp    %eax,%ebp
  cmovg  %eax,%ebp
  jmp    L39
L99:
  add    $0x1,%esi
  add    $0x4,%r10
  cmp    %esi,%edi
  je     L97
L110:
  mov    %r10,%r9
  lea    (%r10,%rbx,1),%r8
  mov    %r13,%rcx
  mov    $0x0,%edx
  jmp    L88
L74:
  mov    $0x5f5e0ff,%ebp
L97:
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  lea    D52(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  D11(%rip),%xmm0
  lea    D61(%rip),%rdi
  call   <printf@plt>
  cmp    0x20(%rsp),%ebx
  jge    L138
L139:
  lea    0x24(%rsp),%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <fscanf@plt>
  mov    0x24(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x24(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  cmpl   $0x0,0x24(%rsp)
  jle    L74
  mov    %r13,%rbp
  mov    $0x0,%r12d
  mov    %r13,0x8(%rsp)
  mov    %rax,%r13
L84:
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <fscanf@plt>
  mov    %r13,%rbx
  sub    0x8(%rsp),%rbx
  lea    0x0(%rbp,%rbx,1),%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <fscanf@plt>
  add    $0x1,%r12d
  mov    0x24(%rsp),%edi
  add    $0x4,%rbp
  cmp    %r12d,%edi
  jg     L84
  mov    0x8(%rsp),%r13
  test   %edi,%edi
  jle    L29
  mov    %r13,%r10
  mov    $0x5f5e0ff,%ebp
  mov    $0x0,%esi
  jmp    L110
L138:
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L92:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D56
type_infered: string
name: disassemble_data
arguments: label: D45
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D52
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: byte[8]
name: disassemble_data
arguments: label: D61
type_infered: string

tool: D56: rt

tool: D45: squirrels.in

tool: D18:  %d

tool: D52: Campus #%d:


tool: {"D11": [0x11,0x2d,0x44,0x54,0xfb,0x21,0xe9,0x3f]}

tool: D61: Maximum territory area = %.3f



assistant: ```c
int main() {
  int c, t;
  int *x, *y;
  int testCase, i, j;
  int min;
  FILE *in = fopen("squirrels.in", "rt");
  fscanf(in, " %d", &c);
  for (testCase = 0; testCase < c; testCase++) {
    fscanf(in, " %d", &t);
    x = (int *)malloc(t * sizeof(int));
    y = (int *)malloc(t * sizeof(int));
    for (i = 0; i < t; i++) {
      fscanf(in, " %d", &(x[i]));
      fscanf(in, " %d", &(y[i]));
    }
    min = 99999999;
    for (i = 0; i < t; i++) {
      for (j = 0; j < t; j++) {
        if (i != j) {
          int dx = x[i] - x[j];
          int dy = y[i] - y[j];
          int distSq = dx * dx + dy * dy;
          if (min > distSq)
            min = distSq;
        }
      }
    }
    free(x);
    free(y);
    double answer = 3.14159265358979 / 4.0 * min;
    printf("Campus #%d:\n", testCase + 1);
    printf("Maximum territory area = %.3f\n\n", answer);
  }
  fclose(in);
  return 0;
}
```