ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D8(%rip),%r15
  push   %r14
  push   %r13
  lea    D54(%rip),%r13
  push   %r12
  lea    D42(%rip),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  lea    0x10(%rsp),%r14
  lea    0xc(%rsp),%rbx
L23:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    D58(%rip),%rdx
  movsd  0x10(%rsp),%xmm3
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movq   %rdx,%xmm4
  nopw   0x0(%rax,%rax,1)
L10:
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  add    $0x1,%eax
  movapd %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  movapd %xmm4,%xmm2
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  cmp    $0xf4241,%eax
  jne    L10
  movapd %xmm3,%xmm0
  mov    %r12,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %rbx,%rsi
  lea    D41(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  je     L23
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D54
datatype: string
name: retrieve_data
arguments: data_tag: D42
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D58
datatype: byte[8]
name: retrieve_data
arguments: data_tag: D41
datatype: string

tool: D8: Please input x:

tool: D54: %lf

tool: D42: x=%4.2lf,func_x=%16.12lf


tool: D2: 1:next  0:exit

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D41: %d

assistant: ```c
int main() {
  int k, i = 1;
  double x, func_x;
  while (i == 1) {
    func_x = 0;
    printf("Please input x:");
    scanf("%lf", &x);
    for (k = 1; k <= 1000000; k++) {
      func_x = func_x + 1 / ((x + k) * k);
    }
    printf("x=%4.2lf,func_x=%16.12lf\n", x, func_x);
    printf("1:next  0:exit\n");
    scanf("%d", &i);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D33(%rip),%r15
  push   %r14
  push   %r13
  lea    D52(%rip),%r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  lea    D54(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  lea    0x10(%rsp),%r14
  lea    0xc(%rsp),%rbx
L28:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    D40(%rip),%rdx
  movsd  0x10(%rsp),%xmm3
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movq   %rdx,%xmm4
  nopw   0x0(%rax,%rax,1)
L8:
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  add    $0x1,%eax
  movapd %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  movapd %xmm4,%xmm2
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  cmp    $0xf4241,%eax
  jne    L8
  movapd %xmm3,%xmm0
  mov    %r12,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %rbx,%rsi
  lea    D47(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  je     L28
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D33
datatype: string
name: read_data
arguments: data_label: D52
datatype: string
name: read_data
arguments: data_label: D14
datatype: string
name: read_data
arguments: data_label: D54
datatype: string
name: read_data
arguments: data_label: D40
datatype: byte[8]
name: read_data
arguments: data_label: D47
datatype: string

tool: D33: Please input x:

tool: D52: %lf

tool: D14: x=%4.2lf,func_x=%16.12lf


tool: D54: 1:next  0:exit

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D47: %d

assistant: ```c
int main() {
  int k, i = 1;
  double x, func_x;
  while (i == 1) {
    func_x = 0;
    printf("Please input x:");
    scanf("%lf", &x);
    for (k = 1; k <= 1000000; k++) {
      func_x = func_x + 1 / ((x + k) * k);
    }
    printf("x=%4.2lf,func_x=%16.12lf\n", x, func_x);
    printf("1:next  0:exit\n");
    scanf("%d", &i);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<atoi_my>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L20
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%esi
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x18(%rbp),%rdi
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%esi
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x18(%rbp),%rdi
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  cmpl   $0x62,-0x8(%rbp)
  jg     L14
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D27
datatype: string

tool: D0: 
----func_atoi_my---

tool: D2: In step %d sum = %8d; * string = "%c" in char, %d as digital and %p as pointer;


tool: D14: In step %d sum = %8d; * string = "%c" in char, %d as digital and %p as pointer;



tool: D26: After cycle sum = %d;


tool: D27: ----end_of_func_atoi_my---

assistant: ```c
int atoi_my(char *string) {
  int i = 0;
  int sum = 0;
  printf("\n----func_atoi_my---\n");
  while (i < 100 - 1 && *string != '\0') {
    printf("In step %d sum = %8d; * string = \"%c\" in char, %d as digital and %p as pointer;\n", i, sum, *string, *string, &*string);
    sum = sum * 10 + (*string - '0');
    *string++;
    i++;
    printf("In step %d sum = %8d; * string = \"%c\" in char, %d as digital and %p as pointer;\n\n", i, sum, *string, *string, &*string);
  };
  printf("After cycle sum = %d;\n", sum);
  printf("----end_of_func_atoi_my---\n");
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atoi_my>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  lea    D6(%rip),%r14
  lea    D47(%rip),%r13
L9:
  movzbl (%rbx),%r8d
  test   %r8b,%r8b
  je     L16
  movsbl %r8b,%ecx
  mov    %rbx,%r9
  mov    %ecx,%r8d
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  add    $0x1,%rbx
  add    $0x1,%r12d
  movsbl (%rbx),%ecx
  mov    %rbx,%r9
  mov    %ecx,%r8d
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x63,%r12d
  jne    L9
L16:
  mov    %ebp,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string
name: retrieve_data
arguments: data_label: D47
type_infered: string
name: retrieve_data
arguments: data_label: D28
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D17: 
----func_atoi_my---

tool: D6: In step %d sum = %8d; * string = "%c" in char, %d as digital and %p as pointer;


tool: D47: In step %d sum = %8d; * string = "%c" in char, %d as digital and %p as pointer;



tool: D28: After cycle sum = %d;


tool: D5: ----end_of_func_atoi_my---

assistant: ```c
int atoi_my(char *string) {
  int i = 0;
  int sum = 0;
  printf("\n----func_atoi_my---\n");
  while (i < 100 - 1 && *string != '\0') {
    printf("In step %d sum = %8d; * string = \"%c\" in char, %d as digital and %p as pointer;\n", i, sum, *string, *string, &*string);
    sum = sum * 10 + (*string - '0');
    *string++;
    i++;
    printf("In step %d sum = %8d; * string = \"%c\" in char, %d as digital and %p as pointer;\n\n", i, sum, *string, *string, &*string);
  };
  printf("After cycle sum = %d;\n", sum);
  printf("----end_of_func_atoi_my---\n");
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atoi_my>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L28
  nopl   0x0(%rax)
L12:
  movsbl %r8b,%ecx
  mov    %rbx,%r9
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %ecx,%r8d
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movsbl -0x1(%rbx),%eax
  lea    (%r12,%r12,4),%edx
  movsbl (%rbx),%ecx
  add    $0x1,%r14d
  mov    %rbx,%r9
  mov    %rbp,%rdi
  lea    -0x30(%rax,%rdx,2),%r12d
  mov    %ecx,%r8d
  xor    %eax,%eax
  mov    %r14d,%esi
  mov    %r12d,%edx
  call   <printf@plt>
  cmp    $0x63,%r14d
  je     L6
L28:
  movzbl (%rbx),%r8d
  test   %r8b,%r8b
  jne    L12
L6:
  mov    %r12d,%esi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string
name: retrieve_data
arguments: tag: D34
datatype: string
name: retrieve_data
arguments: tag: D29
datatype: string

tool: D10: In step %d sum = %8d; * string = "%c" in char, %d as digital and %p as pointer;


tool: D5: In step %d sum = %8d; * string = "%c" in char, %d as digital and %p as pointer;



tool: D26: 
----func_atoi_my---

tool: D34: After cycle sum = %d;


tool: D29: ----end_of_func_atoi_my---

assistant: ```c
int atoi_my(char *string) {
  int i = 0;
  int sum = 0;
  printf("\n----func_atoi_my---\n");
  while (i < 100 - 1 && *string != '\0') {
    printf("In step %d sum = %8d; * string = \"%c\" in char, %d as digital and %p as pointer;\n", i, sum, *string, *string, &*string);
    sum = sum * 10 + (*string - '0');
    *string++;
    i++;
    printf("In step %d sum = %8d; * string = \"%c\" in char, %d as digital and %p as pointer;\n\n", i, sum, *string, *string, &*string);
  };
  printf("After cycle sum = %d;\n", sum);
  printf("----end_of_func_atoi_my---\n");
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atoi_my>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D48(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D40(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L6
  nopl   0x0(%rax)
L19:
  movsbl %r8b,%ecx
  mov    %rbx,%r9
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %ecx,%r8d
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movsbl -0x1(%rbx),%eax
  lea    (%r12,%r12,4),%edx
  movsbl (%rbx),%ecx
  add    $0x1,%r14d
  mov    %rbx,%r9
  mov    %rbp,%rdi
  lea    -0x30(%rax,%rdx,2),%r12d
  mov    %ecx,%r8d
  xor    %eax,%eax
  mov    %r14d,%esi
  mov    %r12d,%edx
  call   <printf@plt>
  cmp    $0x63,%r14d
  je     L22
L6:
  movzbl (%rbx),%r8d
  test   %r8b,%r8b
  jne    L19
L22:
  mov    %r12d,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D48
datatype: string
name: read_data
arguments: tag: D40
datatype: string
name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D11
datatype: string

tool: D48: In step %d sum = %8d; * string = "%c" in char, %d as digital and %p as pointer;


tool: D40: In step %d sum = %8d; * string = "%c" in char, %d as digital and %p as pointer;



tool: D10: 
----func_atoi_my---

tool: D0: After cycle sum = %d;


tool: D11: ----end_of_func_atoi_my---

assistant: ```c
int atoi_my(char *string) {
  int i = 0;
  int sum = 0;
  printf("\n----func_atoi_my---\n");
  while (i < 100 - 1 && *string != '\0') {
    printf("In step %d sum = %8d; * string = \"%c\" in char, %d as digital and %p as pointer;\n", i, sum, *string, *string, &*string);
    sum = sum * 10 + (*string - '0');
    *string++;
    i++;
    printf("In step %d sum = %8d; * string = \"%c\" in char, %d as digital and %p as pointer;\n\n", i, sum, *string, *string, &*string);
  };
  printf("After cycle sum = %d;\n", sum);
  printf("----end_of_func_atoi_my---\n");
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gna>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  cmp    %rax,%rdx
  cmovle %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <init_str@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <print_all@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void gna(long long number) {
  char *str;
  long long rem;
  long long round;
  long long page_size;
  page_size = (number > INT_MAX) ? INT_MAX : number;
  str = init_str(page_size);
  round = number / page_size;
  rem = number % page_size;
  print_all(str, page_size, round, rem);
  free(str);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gna>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    D6(%rip),%rax
  mov    (%rax),%rbp
  cmp    %rbp,%rdi
  cmovle %rdi,%rbp
  mov    %rbp,%rdi
  call   <init_str@plt>
  mov    %rax,%r12
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <print_all@plt>
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void gna(long long number) {
  char *str;
  long long rem;
  long long round;
  long long page_size;
  page_size = (number > INT_MAX) ? INT_MAX : number;
  str = init_str(page_size);
  round = number / page_size;
  rem = number % page_size;
  print_all(str, page_size, round, rem);
  free(str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gna>:
  endbr64
  mov    D1(%rip),%rax
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rax),%rbp
  mov    %rdi,%rbx
  cmp    %rbp,%rdi
  cmovle %rdi,%rbp
  mov    %rbp,%rdi
  call   <init_str@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rbx,%rax
  cqto
  mov    %r12,%rdi
  idiv   %rbp
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <print_all@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <free@plt>
```

assistant: ```c
void gna(long long number) {
  char *str;
  long long rem;
  long long round;
  long long page_size;
  page_size = (number > INT_MAX) ? INT_MAX : number;
  str = init_str(page_size);
  round = number / page_size;
  rem = number % page_size;
  print_all(str, page_size, round, rem);
  free(str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gna>:
  endbr64
  mov    D0(%rip),%rax
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rax),%rbp
  mov    %rdi,%rbx
  cmp    %rbp,%rdi
  cmovle %rdi,%rbp
  mov    %rbp,%rdi
  call   <init_str@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rbx,%rax
  cqto
  mov    %r12,%rdi
  idiv   %rbp
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <print_all@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <free@plt>
```

assistant: ```c
void gna(long long number) {
  char *str;
  long long rem;
  long long round;
  long long page_size;
  page_size = (number > INT_MAX) ? INT_MAX : number;
  str = init_str(page_size);
  round = number / page_size;
  rem = number % page_size;
  print_all(str, page_size, round, rem);
  free(str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main_test_2_ipc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <stoi@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sem_get@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <shm_get@plt>
  mov    %rax,-0x8(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_up@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string
name: parse_data
arguments: label: D16
datatype: string

tool: D2: Ingrese mensaje: 

tool: D16: %s


assistant: ```c
void main_test_2_ipc(int argc, char **argv) {
  uint64_t key = stoi(argv[0]);
  void *sem = sem_get(key);
  char *shm = shm_get(key);
  printf("Ingrese mensaje: ");
  scanf("%s\n", shm);
  sem_up(sem);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main_test_2_ipc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <stoi@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <sem_get@plt>
  mov    %rax,%rbp
  mov    %ebx,%edi
  call   <shm_get@plt>
  mov    %rax,%rbx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <sem_up@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D8: Ingrese mensaje: 

tool: D4: %s


assistant: ```c
void main_test_2_ipc(int argc, char **argv) {
  uint64_t key = stoi(argv[0]);
  void *sem = sem_get(key);
  char *shm = shm_get(key);
  printf("Ingrese mensaje: ");
  scanf("%s\n", shm);
  sem_up(sem);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main_test_2_ipc>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <stoi@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <sem_get@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <shm_get@plt>
  lea    D19(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <sem_up@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
data_type: string
name: read_data
arguments: data_label: D4
data_type: string

tool: D19: Ingrese mensaje: 

tool: D4: %s


assistant: ```c
void main_test_2_ipc(int argc, char **argv) {
  uint64_t key = stoi(argv[0]);
  void *sem = sem_get(key);
  char *shm = shm_get(key);
  printf("Ingrese mensaje: ");
  scanf("%s\n", shm);
  sem_up(sem);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main_test_2_ipc>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <stoi@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <sem_get@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <shm_get@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <sem_up@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
datatype: string
name: disassemble_data
arguments: tag: D8
datatype: string

tool: D10: Ingrese mensaje: 

tool: D8: %s


assistant: ```c
void main_test_2_ipc(int argc, char **argv) {
  uint64_t key = stoi(argv[0]);
  void *sem = sem_get(key);
  char *shm = shm_get(key);
  printf("Ingrese mensaje: ");
  scanf("%s\n", shm);
  sem_up(sem);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_206_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_206_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = *D & stk3;
  stk1 = S | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_206_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  not    %edx
  and    (%rdi),%dl
  or     %esi,%edx
  mov    %eax,%ecx
  not    %ecx
  and    %ecx,%edx
  and    (%rdi),%al
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_206_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = *D & stk3;
  stk1 = S | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_206_1_1>:
  endbr64
  mov    %edx,%eax
  not    %edx
  and    (%rdi),%dl
  or     %esi,%eax
  or     %esi,%edx
  mov    %eax,%ecx
  and    (%rdi),%al
  not    %ecx
  and    %ecx,%edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_206_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = *D & stk3;
  stk1 = S | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```