ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_zero_pad>:
  endbr64
  push   %r15
  add    %esi,%ecx
  lea    (%rdx,%r8,1),%r11d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %esi,0x24(%rsp)
  mov    %ecx,0x3c(%rsp)
  test   %esi,%esi
  jle    L111
  movslq %edx,%rax
  mov    %edx,%ebp
  mov    %rdi,%r15
  mov    %edx,%r10d
  shl    $0x3,%rax
  mov    %rdi,%r12
  mov    %r9,%rbx
  and    $0xfffffffe,%ebp
  mov    %rax,(%rsp)
  movslq %r11d,%rax
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  shl    $0x3,%rax
  mov    %rax,0x28(%rsp)
  mov    %edx,%eax
  shr    %eax
  lea    -0x1(%rax),%ecx
  lea    -0x1(%r8),%eax
  xor    %r8d,%r8d
  lea    0x8(,%rax,8),%rax
  add    $0x1,%rcx
  mov    %rax,0x30(%rsp)
  lea    -0x1(%rdx),%eax
  shl    $0x4,%rcx
  mov    %eax,0x38(%rsp)
L127:
  test   %r10d,%r10d
  jle    L105
  lea    0x8(%r12),%rax
  cmp    %rax,%rbx
  je     L5
  cmpl   $0x2,0x38(%rsp)
  jbe    L5
  xor    %eax,%eax
L13:
  movupd (%r12,%rax,1),%xmm1
  movups %xmm1,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L13
  cmp    %r10d,%ebp
  je     L105
  lea    0x0(%r13,%rbp,1),%eax
  cltq
  movsd  (%r15,%rax,8),%xmm0
  lea    (%r14,%rbp,1),%eax
  cltq
  movsd  %xmm0,(%r9,%rax,8)
L105:
  cmp    %r11d,%r10d
  jge    L82
  mov    (%rsp),%rax
  mov    0x30(%rsp),%rdx
  xor    %esi,%esi
  mov    %r9,0x18(%rsp)
  mov    %r10d,0x20(%rsp)
  lea    (%rax,%rbx,1),%rdi
  mov    %rcx,0x10(%rsp)
  mov    %r8d,0xc(%rsp)
  mov    %r11d,0x8(%rsp)
  call   <memset@plt>
  mov    0x18(%rsp),%r9
  mov    0x20(%rsp),%r10d
  mov    0x10(%rsp),%rcx
  mov    0xc(%rsp),%r8d
  mov    0x8(%rsp),%r11d
L82:
  add    $0x1,%r8d
  add    %r10d,%r13d
  add    %r11d,%r14d
  add    (%rsp),%r12
  add    0x28(%rsp),%rbx
  cmp    %r8d,0x24(%rsp)
  jne    L127
L111:
  mov    0x24(%rsp),%ebp
  mov    0x3c(%rsp),%r12d
  cmp    %r12d,%ebp
  jge    L119
  test   %r11d,%r11d
  jle    L119
  mov    %r11d,%eax
  movslq %r11d,%rbx
  imul   %ebp,%eax
  shl    $0x3,%rbx
  cltq
  lea    (%r9,%rax,8),%rcx
L37:
  mov    %rcx,%rdi
  mov    %rbx,%rdx
  xor    %esi,%esi
  add    $0x1,%ebp
  call   <memset@plt>
  mov    %rax,%rcx
  add    %rbx,%rcx
  cmp    %ebp,%r12d
  jne    L37
L119:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    0x38(%rsp),%esi
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L62:
  movsd  (%r12,%rax,8),%xmm0
  mov    %rax,%rdx
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L62
  jmp    L105
```

assistant: ```c
void add_zero_pad(double *X, int rows, int cols, int zrow, int zcol, double *Y) {
  int r, c, i, j, u, v;
  r = rows + zrow;
  c = cols + zcol;
  for (i = 0; i < rows; ++i) {
    u = i * c;
    v = i * cols;
    for (j = 0; j < cols; ++j) {
      Y[u + j] = X[v + j];
    }
    for (j = cols; j < c; ++j) {
      Y[u + j] = 0.;
    }
  }
  for (i = rows; i < r; ++i) {
    u = i * c;
    for (j = 0; j < c; ++j) {
      Y[u + j] = 0.;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<show_ciphers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L15
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    D58(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <BIO_printf@plt>
  mov    D1(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D7(%rip)
  mov    D7(%rip),%eax
  cmp    $0x3,%eax
  jne    L18
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <BIO_printf@plt>
  movl   $0x0,D7(%rip)
  jmp    L0
L18:
  mov    -0x8(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <BIO_printf@plt>
  jmp    L0
L15:
  nop
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D58
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D22
datatype: string

tool: D58: -%-25s

tool: D7: 


tool: D22:  

assistant: ```c
void show_ciphers(const OBJ_NAME *name, void *bio_) {
  BIO *bio = bio_;
  static int n;
  if (!islower((unsigned char)*name->name))
    return;
  BIO_printf(bio, "-%-25s", name->name);
  if (++n == 3) {
    BIO_printf(bio, "\n");
    n = 0;
  } else
    BIO_printf(bio, " ");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<show_ciphers>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%rax
  movzbl (%rax),%edi
  call   <islower@plt>
  test   %eax,%eax
  jne    L38
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    (%rbx),%rdx
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <BIO_printf@plt>
  mov    D34(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D29(%rip)
  cmp    $0x3,%eax
  je     L18
  lea    D29(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <BIO_printf@plt>
  jmp    L36
L18:
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <BIO_printf@plt>
  movl   $0x0,D29(%rip)
  jmp    L36
```

tool_calls: name: disassemble_data
arguments: data_label: D25
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: string

tool: D25: -%-25s

tool: D29:  

tool: D27: 


assistant: ```c
void show_ciphers(const OBJ_NAME *name, void *bio_) {
  BIO *bio = bio_;
  static int n;
  if (!islower((unsigned char)*name->name))
    return;
  BIO_printf(bio, "-%-25s", name->name);
  if (++n == 3) {
    BIO_printf(bio, "\n");
    n = 0;
  } else
    BIO_printf(bio, " ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_ciphers>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  movzbl (%rax),%edi
  call   <islower@plt>
  test   %eax,%eax
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <BIO_printf@plt>
  mov    D14(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D23(%rip)
  cmp    $0x3,%eax
  je     L11
  add    $0x8,%rsp
  mov    %rbp,%rdi
  lea    D23(%rip),%rsi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <BIO_printf@plt>
  nop
L11:
  mov    %rbp,%rdi
  lea    D6(%rip),%rsi
  xor    %eax,%eax
  call   <BIO_printf@plt>
  movl   $0x0,D23(%rip)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string
name: retrieve_data
arguments: tag: D23
type: string
name: retrieve_data
arguments: tag: D6
type: string

tool: D5: -%-25s

tool: D23:  

tool: D6: 


assistant: ```c
void show_ciphers(const OBJ_NAME *name, void *bio_) {
  BIO *bio = bio_;
  static int n;
  if (!islower((unsigned char)*name->name))
    return;
  BIO_printf(bio, "-%-25s", name->name);
  if (++n == 3) {
    BIO_printf(bio, "\n");
    n = 0;
  } else
    BIO_printf(bio, " ");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<show_ciphers>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  movzbl (%rax),%edi
  call   <islower@plt>
  test   %eax,%eax
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%rdx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <BIO_printf@plt>
  mov    D56(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D35(%rip)
  cmp    $0x3,%eax
  je     L17
  add    $0x8,%rsp
  mov    %rbp,%rdi
  lea    D35(%rip),%rsi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <BIO_printf@plt>
  nop
L17:
  mov    %rbp,%rdi
  lea    D20(%rip),%rsi
  xor    %eax,%eax
  call   <BIO_printf@plt>
  movl   $0x0,D35(%rip)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D35
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string

tool: D11: -%-25s

tool: D35:  

tool: D20: 


assistant: ```c
void show_ciphers(const OBJ_NAME *name, void *bio_) {
  BIO *bio = bio_;
  static int n;
  if (!islower((unsigned char)*name->name))
    return;
  BIO_printf(bio, "-%-25s", name->name);
  if (++n == 3) {
    BIO_printf(bio, "\n");
    n = 0;
  } else
    BIO_printf(bio, " ");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <runforpath@plt>
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int status = EXIT_SUCCESS;
  for (int argi = 1; argi < argc; ++argi) {
    status = runforpath(argv[argi]);
  }
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    $0x1,%edi
  jle    L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L13:
  mov    (%rbx),%rdi
  call   <runforpath@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int status = EXIT_SUCCESS;
  for (int argi = 1; argi < argc; ++argi) {
    status = runforpath(argv[argi]);
  }
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    $0x1,%edi
  jle    L4
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <runforpath@plt>
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int status = EXIT_SUCCESS;
  for (int argi = 1; argi < argc; ++argi) {
    status = runforpath(argv[argi]);
  }
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    $0x1,%edi
  jle    L0
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <runforpath@plt>
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int status = EXIT_SUCCESS;
  for (int argi = 1; argi < argc; ++argi) {
    status = runforpath(argv[argi]);
  }
  return status;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jns    L20
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L26
L20:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L26:
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L46
L42:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <Fibonacci@plt>
  mov    %eax,%esi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L46:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L42
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D35
type_infered: string
name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D36
type_infered: string
name: unpack_data
arguments: data_tag: D42
type_infered: string
name: unpack_data
arguments: data_tag: D62
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D78
type_infered: string

tool: D35: Enter an integer to find factorial

tool: D15: %d

tool: D36: Negative integers are not allowed.

tool: D42: %d! = %ld


tool: D62: Give a number to calcuate Fibonacci Series : 

tool: D16: 
Fibonacci series

tool: D78: %d


assistant: ```c
int main() {
  int n, i = 0, c;
  int num;
  long f;
  printf("Enter an integer to find factorial\n");
  scanf("%d", &num);
  if (num < 0)
    printf("Negative integers are not allowed.\n");
  else {
    f = factorial(num);
    printf("%d! = %ld\n", num, f);
  }
  printf("Give a number to calcuate Fibonacci Series : ");
  scanf("%d", &n);
  printf("\nFibonacci series\n");
  for (c = 1; c <= n; c++) {
    printf("%d\n", Fibonacci(i));
    i++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L16
  call   <factorial@plt>
  mov    %rax,%rdx
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  lea    D70(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,(%rsp)
  jle    L1
  mov    $0x0,%ebx
  lea    D41(%rip),%rbp
L4:
  mov    %ebx,%edi
  call   <Fibonacci@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  add    $0x2,%eax
  cmp    %eax,(%rsp)
  jge    L4
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    D76(%rip),%rdi
  call   <puts@plt>
  jmp    L6
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D34
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D70
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D41
type_guessed: string
name: extract_symbolic_data
arguments: tag: D76
type_guessed: string

tool: D7: Enter an integer to find factorial

tool: D34: %d

tool: D8: %d! = %ld


tool: D70: Give a number to calcuate Fibonacci Series : 

tool: D6: 
Fibonacci series

tool: D41: %d


tool: D76: Negative integers are not allowed.

assistant: ```c
int main() {
  int n, i = 0, c;
  int num;
  long f;
  printf("Enter an integer to find factorial\n");
  scanf("%d", &num);
  if (num < 0)
    printf("Negative integers are not allowed.\n");
  else {
    f = factorial(num);
    printf("%d! = %ld\n", num, f);
  }
  printf("Give a number to calcuate Fibonacci Series : ");
  scanf("%d", &n);
  printf("\nFibonacci series\n");
  for (c = 1; c <= n; c++) {
    printf("%d\n", Fibonacci(i));
    i++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D52(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L39
  call   <factorial@plt>
  mov    0x4(%rsp),%esi
  lea    D16(%rip),%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
L25:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L14
  xor    %ebx,%ebx
  lea    D43(%rip),%rbp
  nopl   (%rax)
L40:
  mov    %ebx,%edi
  call   <Fibonacci@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  add    $0x2,%eax
  cmp    %eax,(%rsp)
  jge    L40
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L39:
  lea    D62(%rip),%rdi
  call   <puts@plt>
  jmp    L25
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D52
type_infered: string
name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D8
type_infered: string
name: unpack_data
arguments: tag: D43
type_infered: string
name: unpack_data
arguments: tag: D62
type_infered: string

tool: D11: Enter an integer to find factorial

tool: D52: %d

tool: D16: %d! = %ld


tool: D9: Give a number to calcuate Fibonacci Series : 

tool: D8: 
Fibonacci series

tool: D43: %d


tool: D62: Negative integers are not allowed.

assistant: ```c
int main() {
  int n, i = 0, c;
  int num;
  long f;
  printf("Enter an integer to find factorial\n");
  scanf("%d", &num);
  if (num < 0)
    printf("Negative integers are not allowed.\n");
  else {
    f = factorial(num);
    printf("%d! = %ld\n", num, f);
  }
  printf("Give a number to calcuate Fibonacci Series : ");
  scanf("%d", &n);
  printf("\nFibonacci series\n");
  for (c = 1; c <= n; c++) {
    printf("%d\n", Fibonacci(i));
    i++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L30
  call   <factorial@plt>
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
L27:
  lea    D63(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L4
  xor    %ebx,%ebx
  lea    D55(%rip),%rbp
  nopl   (%rax)
L13:
  mov    %ebx,%edi
  call   <Fibonacci@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  add    $0x2,%eax
  cmp    %eax,(%rsp)
  jge    L13
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L30:
  lea    D67(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D10
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: string
name: retrieve_data
arguments: data_label: D63
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string
name: retrieve_data
arguments: data_label: D55
data_type: string
name: retrieve_data
arguments: data_label: D67
data_type: string

tool: D0: Enter an integer to find factorial

tool: D10: %d

tool: D4: %d! = %ld


tool: D63: Give a number to calcuate Fibonacci Series : 

tool: D23: 
Fibonacci series

tool: D55: %d


tool: D67: Negative integers are not allowed.

assistant: ```c
int main() {
  int n, i = 0, c;
  int num;
  long f;
  printf("Enter an integer to find factorial\n");
  scanf("%d", &num);
  if (num < 0)
    printf("Negative integers are not allowed.\n");
  else {
    f = factorial(num);
    printf("%d! = %ld\n", num, f);
  }
  printf("Give a number to calcuate Fibonacci Series : ");
  scanf("%d", &n);
  printf("\nFibonacci series\n");
  for (c = 1; c <= n; c++) {
    printf("%d\n", Fibonacci(i));
    i++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  lea    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <productExceptSelf@plt>
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L18
L8:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L18:
  mov    -0x30(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L8
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {1, 2, 3, 4};
  int len, i;
  int *res = productExceptSelf(a, 4, &len);
  for (i = 0; i < len; i++) {
    printf("%d ", res[i]);
  }
  free(res);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x4,0x1c(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    $0x4,%esi
  call   <productExceptSelf@plt>
  mov    %rax,%rbp
  cmpl   $0x0,0xc(%rsp)
  jle    L16
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L3:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L3
L16:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {1, 2, 3, 4};
  int len, i;
  int *res = productExceptSelf(a, 4, &len);
  for (i = 0; i < len; i++) {
    printf("%d ", res[i]);
  }
  free(res);
  return 0;
}
```