ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<number_of_standard_factors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x44,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int number_of_standard_factors(int *nf) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(68, nf, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<number_of_standard_factors>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x44,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int number_of_standard_factors(int *nf) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(68, nf, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<number_of_standard_factors>:
  endbr64
  mov    %rdi,%rsi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x44,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int number_of_standard_factors(int *nf) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(68, nf, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<number_of_standard_factors>:
  endbr64
  mov    %rdi,%rsi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x44,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int number_of_standard_factors(int *nf) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(68, nf, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Lcd_Draw_Cross>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%edi
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  call   <Lcd_Draw_Hline@plt>
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%edi
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  call   <Lcd_Draw_Vine@plt>
  nop
  leave
  ret
```

assistant: ```c
void Lcd_Draw_Cross(int row, int col, int halflen, int color) {
  Lcd_Draw_Hline(row, col - halflen, col + halflen, color);
  Lcd_Draw_Vine(col, row - halflen, row + halflen, color);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Lcd_Draw_Cross>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%r13d
  lea    (%rsi,%rdx,1),%edx
  sub    %ebp,%esi
  call   <Lcd_Draw_Hline@plt>
  lea    0x0(%rbp,%rbx,1),%edx
  sub    %ebp,%ebx
  mov    %ebx,%esi
  mov    %r13d,%ecx
  mov    %r12d,%edi
  call   <Lcd_Draw_Vine@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void Lcd_Draw_Cross(int row, int col, int halflen, int color) {
  Lcd_Draw_Hline(row, col - halflen, col + halflen, color);
  Lcd_Draw_Vine(col, row - halflen, row + halflen, color);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Lcd_Draw_Cross>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%edx
  push   %rbx
  sub    %ebp,%esi
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <Lcd_Draw_Hline@plt>
  add    $0x8,%rsp
  lea    0x0(%rbp,%rbx,1),%edx
  sub    %ebp,%ebx
  mov    %ebx,%esi
  mov    %r13d,%ecx
  pop    %rbx
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <Lcd_Draw_Vine@plt>
```

assistant: ```c
void Lcd_Draw_Cross(int row, int col, int halflen, int color) {
  Lcd_Draw_Hline(row, col - halflen, col + halflen, color);
  Lcd_Draw_Vine(col, row - halflen, row + halflen, color);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Lcd_Draw_Cross>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%edx
  push   %rbx
  sub    %ebp,%esi
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <Lcd_Draw_Hline@plt>
  add    $0x8,%rsp
  lea    0x0(%rbp,%rbx,1),%edx
  sub    %ebp,%ebx
  mov    %ebx,%esi
  mov    %r13d,%ecx
  pop    %rbx
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <Lcd_Draw_Vine@plt>
```

assistant: ```c
void Lcd_Draw_Cross(int row, int col, int halflen, int color) {
  Lcd_Draw_Hline(row, col - halflen, col + halflen, color);
  Lcd_Draw_Vine(col, row - halflen, row + halflen, color);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_striter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rdi
  call   *%rax
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  int i;
  i = 0;
  while (s[i]) {
    f(&s[i]);
    i++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_striter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x0,(%rdi)
  je     L10
L17:
  mov    %rbx,%rdi
  call   *%rbp
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L17
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  int i;
  i = 0;
  while (s[i]) {
    f(&s[i]);
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_striter>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L16:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  int i;
  i = 0;
  while (s[i]) {
    f(&s[i]);
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_striter>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L12:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  int i;
  i = 0;
  while (s[i]) {
    f(&s[i]);
    i++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L20
  mov    $0x0,%eax
  jmp    L68
L20:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L102
  cmpl   $0x2,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L68
L102:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L18
  cmpl   $0x3,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L68
L18:
  movl   $0x5,-0x4(%rbp)
  jmp    L105
L73:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L0
  mov    $0x0,%eax
  jmp    L68
L0:
  addl   $0x2,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L43
  mov    $0x0,%eax
  jmp    L68
L43:
  addl   $0x4,-0x4(%rbp)
L105:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L73
  mov    $0x1,%eax
L68:
  pop    %rbp
  ret
```

assistant: ```c
bool isPrime(uint64_t n) {
  uint64_t test;
  if (n < 2)
    return false;
  if (n % 2 == 0)
    return n == 2;
  if (n % 3 == 0)
    return n == 3;
  test = 5;
  while (test * test < n) {
    if (n % test == 0)
      return false;
    test += 2;
    if (n % test == 0)
      return false;
    test += 4;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPrime>:
  endbr64
  mov    %edi,%ecx
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L91
  test   $0x1,%dil
  je     L12
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  je     L9
  cmp    $0x19,%edi
  jle    L17
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L91
  movslq %edi,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x2,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L91
  mov    $0x5,%esi
L54:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jge    L78
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  je     L91
  add    $0x8,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  test   %edx,%edx
  jne    L54
L91:
  ret
L12:
  cmp    $0x2,%edi
  sete   %al
  movzbl %al,%eax
  ret
L9:
  cmp    $0x3,%edi
  sete   %al
  movzbl %al,%eax
  ret
L78:
  mov    $0x1,%eax
  ret
L17:
  mov    $0x1,%eax
  jmp    L91
```

assistant: ```c
bool isPrime(uint64_t n) {
  uint64_t test;
  if (n < 2)
    return false;
  if (n % 2 == 0)
    return n == 2;
  if (n % 3 == 0)
    return n == 3;
  test = 5;
  while (test * test < n) {
    if (n % test == 0)
      return false;
    test += 2;
    if (n % test == 0)
      return false;
    test += 4;
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isPrime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L17
  test   $0x1,%dil
  je     L88
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L76
  cmp    $0x19,%edi
  jle    L7
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  je     L17
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %edi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L17
  mov    $0x5,%esi
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L91:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L17
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L17
L56:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jl     L91
L7:
  mov    $0x1,%edx
L17:
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L88:
  xor    %edx,%edx
  cmp    $0x2,%edi
  sete   %dl
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  xor    %edx,%edx
  cmp    $0x3,%edi
  sete   %dl
  mov    %edx,%eax
  ret
```

assistant: ```c
bool isPrime(uint64_t n) {
  uint64_t test;
  if (n < 2)
    return false;
  if (n % 2 == 0)
    return n == 2;
  if (n % 3 == 0)
    return n == 3;
  test = 5;
  while (test * test < n) {
    if (n % test == 0)
      return false;
    test += 2;
    if (n % test == 0)
      return false;
    test += 4;
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPrime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L57
  test   $0x1,%dil
  je     L81
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L54
  cmp    $0x19,%edi
  jle    L24
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  je     L57
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %edi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L57
  mov    $0x5,%esi
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L57
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L57
L50:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jl     L66
L24:
  mov    $0x1,%edx
L57:
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L81:
  xor    %edx,%edx
  cmp    $0x2,%edi
  sete   %dl
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  xor    %edx,%edx
  cmp    $0x3,%edi
  sete   %dl
  mov    %edx,%eax
  ret
```

assistant: ```c
bool isPrime(uint64_t n) {
  uint64_t test;
  if (n < 2)
    return false;
  if (n % 2 == 0)
    return n == 2;
  if (n % 3 == 0)
    return n == 3;
  test = 5;
  while (test * test < n) {
    if (n % test == 0)
      return false;
    test += 2;
    if (n % test == 0)
      return false;
    test += 4;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heading_true_degrees>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm2
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x4,%eax
  call   <heading@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D36(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D39(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd D39(%rip),%xmm0
  jb     L4
  movsd  -0x8(%rbp),%xmm0
  movsd  D39(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L4:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: f64
name: extract_symbolic_data
arguments: data_label: D36
type: f64
name: extract_symbolic_data
arguments: data_label: D39
type: f64

tool: D0: 180

tool: D36: 3.141592653589793

tool: D39: 360

assistant: ```c
double heading_true_degrees(double lat1, double lon1, double lat2, double lon2) {
  double h = 360.0 - ((heading(lat1, lon1, lat2, lon2)) * 180.0 / 3.14159265358979323846);
  if (h >= 360.0)
    h -= 360.0;
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heading_true_degrees>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%eax
  call   <heading@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D17(%rip),%xmm0
  divsd  D25(%rip),%xmm0
  movsd  D21(%rip),%xmm2
  movapd %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  comisd %xmm2,%xmm1
  jb     L8
  subsd  %xmm2,%xmm1
L8:
  movapd %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
datatype: f64
name: unpack_data
arguments: data_label: D25
datatype: f64
name: unpack_data
arguments: data_label: D21
datatype: f64

tool: D17: 180

tool: D25: 3.141592653589793

tool: D21: 360

assistant: ```c
double heading_true_degrees(double lat1, double lon1, double lat2, double lon2) {
  double h = 360.0 - ((heading(lat1, lon1, lat2, lon2)) * 180.0 / 3.14159265358979323846);
  if (h >= 360.0)
    h -= 360.0;
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heading_true_degrees>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%eax
  call   <heading@plt>
  movsd  D0(%rip),%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D3(%rip),%xmm0
  movapd %xmm2,%xmm1
  divsd  D10(%rip),%xmm0
  subsd  %xmm0,%xmm1
  comisd %xmm2,%xmm1
  jb     L4
  subsd  %xmm2,%xmm1
L4:
  movapd %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: f64
name: unpack_data
arguments: label: D3
datatype: f64
name: unpack_data
arguments: label: D10
datatype: f64

tool: D0: 360

tool: D3: 180

tool: D10: 3.141592653589793

assistant: ```c
double heading_true_degrees(double lat1, double lon1, double lat2, double lon2) {
  double h = 360.0 - ((heading(lat1, lon1, lat2, lon2)) * 180.0 / 3.14159265358979323846);
  if (h >= 360.0)
    h -= 360.0;
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heading_true_degrees>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%eax
  call   <heading@plt>
  movsd  D14(%rip),%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D21(%rip),%xmm0
  movapd %xmm2,%xmm1
  divsd  D26(%rip),%xmm0
  subsd  %xmm0,%xmm1
  comisd %xmm2,%xmm1
  jb     L3
  subsd  %xmm2,%xmm1
L3:
  movapd %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type: f64
name: read_data
arguments: data_tag: D21
type: f64
name: read_data
arguments: data_tag: D26
type: f64

tool: D14: 360

tool: D21: 180

tool: D26: 3.141592653589793

assistant: ```c
double heading_true_degrees(double lat1, double lon1, double lat2, double lon2) {
  double h = 360.0 - ((heading(lat1, lon1, lat2, lon2)) * 180.0 / 3.14159265358979323846);
  if (h >= 360.0)
    h -= 360.0;
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_GF_mul_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L40
L2:
  cmpl   $0x0,-0x4(%rbp)
  je     L15
  cmpq   $0x0,-0x30(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  lea    (%rdx,%rax,1),%rcx
  movabs $0x8080808080808081,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x7,%rax
  mov    %rax,%rdx
  shl    $0x8,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L9
L15:
  mov    $0x0,%eax
L9:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L40:
  cmpl   $0xff,-0x4(%rbp)
  jle    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gen_GF_mul_table(const uint8_t *GF_log, const uint8_t *GF_ilog, uint8_t *tbl, uint8_t val) {
  int i;
  for (i = 0; i < 0x100; i++)
    tbl[i] = ((i) && (val) ? GF_ilog[(GF_log[(i)] + GF_log[(val)]) % 0xff] : 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gen_GF_mul_table>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %rsi,%r10
  mov    %rdx,%rdi
  mov    %rcx,%r8
  lea    (%r9,%rcx,8),%rbx
  mov    $0x1,%ecx
  mov    $0x0,%eax
  mov    $0x0,%ebp
  movabs $0x8080808080808081,%r11
  jmp    L6
L40:
  mov    %rbp,%rax
L17:
  add    $0x1,%rcx
L6:
  mov    %rax,-0x8(%rdi,%rcx,8)
  cmp    $0x100,%rcx
  je     L10
  test   %ecx,%ecx
  je     L40
  test   %r8,%r8
  je     L40
  mov    (%rbx),%rsi
  add    (%r9,%rcx,8),%rsi
  mov    %rsi,%rax
  mul    %r11
  shr    $0x7,%rdx
  mov    %rdx,%rax
  shl    $0x8,%rax
  sub    %rdx,%rax
  sub    %rax,%rsi
  mov    (%r10,%rsi,8),%rax
  jmp    L17
L10:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void gen_GF_mul_table(const uint8_t *GF_log, const uint8_t *GF_ilog, uint8_t *tbl, uint8_t val) {
  int i;
  for (i = 0; i < 0x100; i++)
    tbl[i] = ((i) && (val) ? GF_ilog[(GF_log[(i)] + GF_log[(val)]) % 0xff] : 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen_GF_mul_table>:
  endbr64
  mov    %rdi,%r9
  push   %rbx
  mov    %rcx,%rdi
  mov    %rsi,%r10
  lea    (%r9,%rcx,8),%rbx
  mov    %rdx,%r8
  xor    %ecx,%ecx
  xor    %eax,%eax
  movabs $0x8080808080808081,%r11
  jmp    L2
  nopl   (%rax)
L26:
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L13
  mov    (%rbx),%rsi
  add    0x8(%r9,%rcx,1),%rsi
  mov    %rsi,%rax
  mul    %r11
  shr    $0x7,%rdx
  mov    %rdx,%rax
  shl    $0x8,%rax
  sub    %rdx,%rax
  sub    %rax,%rsi
  mov    (%r10,%rsi,8),%rax
L13:
  add    $0x8,%rcx
L2:
  mov    %rax,(%r8,%rcx,1)
  cmp    $0x7f8,%rcx
  jne    L26
  pop    %rbx
  ret
```

assistant: ```c
void gen_GF_mul_table(const uint8_t *GF_log, const uint8_t *GF_ilog, uint8_t *tbl, uint8_t val) {
  int i;
  for (i = 0; i < 0x100; i++)
    tbl[i] = ((i) && (val) ? GF_ilog[(GF_log[(i)] + GF_log[(val)]) % 0xff] : 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_GF_mul_table>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%rdi
  lea    (%r8,%rcx,8),%r10
  test   %rcx,%rcx
  je     L23
  movq   $0x0,(%rdx)
  mov    $0x8,%esi
  movabs $0x8080808080808081,%r11
  nopl   0x0(%rax)
L18:
  mov    (%r10),%rcx
  add    (%r8,%rsi,1),%rcx
  mov    %rcx,%rax
  mul    %r11
  shr    $0x7,%rdx
  mov    %rdx,%rax
  shl    $0x8,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  mov    (%r9,%rcx,8),%rax
  mov    %rax,(%rdi,%rsi,1)
  add    $0x8,%rsi
  cmp    $0x800,%rsi
  jne    L18
  ret
L23:
  mov    %rdx,%rax
  pxor   %xmm0,%xmm0
  lea    0x800(%rdx),%rdx
  nopw   0x0(%rax,%rax,1)
L17:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L17
  ret
```

assistant: ```c
void gen_GF_mul_table(const uint8_t *GF_log, const uint8_t *GF_ilog, uint8_t *tbl, uint8_t val) {
  int i;
  for (i = 0; i < 0x100; i++)
    tbl[i] = ((i) && (val) ? GF_ilog[(GF_log[(i)] + GF_log[(val)]) % 0xff] : 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rax
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  lea    -0x60(%rbp),%rsi
  mov    -0x64(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x50,%edx
  mov    %eax,%edi
  call   <recv@plt>
  lea    -0x60(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <normalizeString@plt>
  lea    -0x60(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  mov    $0x1,%eax
  jmp    L39
L25:
  lea    -0x60(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L42
  mov    $0x2,%eax
  jmp    L39
L42:
  mov    $0x0,%eax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string

tool: D17: SINGLE

tool: D15: MULTI

assistant: ```c
int getType(int in) {
  char inputline[80];
  bzero(inputline, 80);
  recv(in, inputline, 80, 0);
  normalizeString(inputline, 1);
  if (strcmp(inputline, "SINGLE") == 0)
    return 1;
  else if (strcmp(inputline, "MULTI") == 0)
    return 2;
  else
    return 0;
}
```