ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x5,%edi
  call   <create_graph@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <detect_cycle@plt>
  test   %rax,%rax
  je     L14
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L14:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string

tool: D15: Cycle present

tool: D1: Cycle not present

assistant: ```c
void main() {
  struct graph *G = create_graph(5);
  add_edge(G, 1, 3);
  add_edge(G, 1, 5);
  add_edge(G, 2, 3);
  add_edge(G, 4, 5);
  add_edge(G, 5, 2);
  add_edge(G, 2, 1);
  if (detect_cycle(G)) {
    printf("Cycle present");
  } else {
    printf("Cycle not present");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5,%edi
  call   <create_graph@plt>
  mov    %rax,%rbx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <add_edge@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <add_edge@plt>
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <add_edge@plt>
  mov    $0x2,%edx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <add_edge@plt>
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <add_edge@plt>
  mov    %rbx,%rdi
  call   <detect_cycle@plt>
  test   %rax,%rax
  je     L9
  lea    D12(%rip),%rdi
  call   <printf@plt>
L14:
  pop    %rbx
  ret
L9:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D12: Cycle present

tool: D11: Cycle not present

assistant: ```c
void main() {
  struct graph *G = create_graph(5);
  add_edge(G, 1, 3);
  add_edge(G, 1, 5);
  add_edge(G, 2, 3);
  add_edge(G, 4, 5);
  add_edge(G, 5, 2);
  add_edge(G, 2, 1);
  if (detect_cycle(G)) {
    printf("Cycle present");
  } else {
    printf("Cycle not present");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x5,%edi
  call   <create_graph@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <add_edge@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <add_edge@plt>
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <add_edge@plt>
  mov    $0x2,%edx
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <add_edge@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <add_edge@plt>
  mov    %rbp,%rdi
  call   <detect_cycle@plt>
  test   %rax,%rax
  je     L0
  lea    D5(%rip),%rdi
  pop    %rbp
  jmp    1090 <printf@plt>
L0:
  lea    D19(%rip),%rdi
  pop    %rbp
  jmp    1090 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D19
type: string

tool: D5: Cycle present

tool: D19: Cycle not present

assistant: ```c
void main() {
  struct graph *G = create_graph(5);
  add_edge(G, 1, 3);
  add_edge(G, 1, 5);
  add_edge(G, 2, 3);
  add_edge(G, 4, 5);
  add_edge(G, 5, 2);
  add_edge(G, 2, 1);
  if (detect_cycle(G)) {
    printf("Cycle present");
  } else {
    printf("Cycle not present");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x5,%edi
  call   <create_graph@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <add_edge@plt>
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <add_edge@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <add_edge@plt>
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <add_edge@plt>
  mov    $0x2,%edx
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <add_edge@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <add_edge@plt>
  mov    %rbp,%rdi
  call   <detect_cycle@plt>
  test   %rax,%rax
  je     L4
  lea    D5(%rip),%rdi
  pop    %rbp
  jmp    1090 <printf@plt>
L4:
  lea    D1(%rip),%rdi
  pop    %rbp
  jmp    1090 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D1
data_type: string

tool: D5: Cycle present

tool: D1: Cycle not present

assistant: ```c
void main() {
  struct graph *G = create_graph(5);
  add_edge(G, 1, 3);
  add_edge(G, 1, 5);
  add_edge(G, 2, 3);
  add_edge(G, 4, 5);
  add_edge(G, 5, 2);
  add_edge(G, 2, 1);
  if (detect_cycle(G)) {
    printf("Cycle present");
  } else {
    printf("Cycle not present");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Bin2Dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L13
L15:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  shl    $0x2,%eax
  add    %ebx,%eax
  add    %eax,%eax
  mov    %edx,%ebx
  sub    %eax,%ebx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L13:
  cmpl   $0x7,-0x18(%rbp)
  jle    L15
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int Bin2Dec(int a) {
  int b = a;
  int i;
  int ret = 0;
  for (i = 0; i <= 7; i++) {
    ret = ret + (b % 10) * pow(2, i);
    b = (b - (b % 10)) / 10;
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Bin2Dec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
L6:
  movslq %r13d,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %r13d,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %r13d,%ebx
  sub    %eax,%ebx
  mov    %ebp,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,%r12d
  mov    %r13d,%edx
  sub    %ebx,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%r13d
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L6
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int Bin2Dec(int a) {
  int b = a;
  int i;
  int ret = 0;
  for (i = 0; i <= 7; i++) {
    ret = ret + (b % 10) * pow(2, i);
    b = (b - (b % 10)) / 10;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Bin2Dec>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L4:
  movslq %ebp,%rbx
  mov    %ebp,%eax
  mov    %r13d,%esi
  mov    $0x2,%edi
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  add    $0x1,%r13d
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %ebp,%ebx
  add    %eax,%eax
  sub    %eax,%ebx
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,%r12d
  mov    %ebp,%eax
  sub    %ebx,%eax
  movslq %eax,%rbp
  sar    $0x1f,%eax
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  sub    %eax,%ebp
  cmp    $0x8,%r13d
  jne    L4
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int Bin2Dec(int a) {
  int b = a;
  int i;
  int ret = 0;
  for (i = 0; i <= 7; i++) {
    ret = ret + (b % 10) * pow(2, i);
    b = (b - (b % 10)) / 10;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Bin2Dec>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L2:
  movslq %ebp,%rbx
  mov    %ebp,%eax
  mov    %r13d,%esi
  mov    $0x2,%edi
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  add    $0x1,%r13d
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %ebp,%ebx
  add    %eax,%eax
  sub    %eax,%ebx
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,%r12d
  mov    %ebp,%eax
  sub    %ebx,%eax
  movslq %eax,%rbp
  sar    $0x1f,%eax
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  sub    %eax,%ebp
  cmp    $0x8,%r13d
  jne    L2
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int Bin2Dec(int a) {
  int b = a;
  int i;
  int ret = 0;
  for (i = 0; i <= 7; i++) {
    ret = ret + (b % 10) * pow(2, i);
    b = (b - (b % 10)) / 10;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x2f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2e8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x60(%rsp),%r15
  mov    %r15,%rbp
  mov    $0x1,%ebx
  lea    D35(%rip),%r12
L16:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,0x8(%rsp,%rbx,8)
  add    $0x1,%rbx
  add    $0x40,%rbp
  cmp    $0xb,%rbx
  jne    L16
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  movq   $0x1,(%rsp)
  lea    0x58(%rsp),%r14
  jmp    L102
L65:
  add    $0x8,%rbx
  cmp    %r14,%rbx
  je     L36
L11:
  mov    0x8(%rbx),%r12
  mov    0x0(%r13),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <c_insensitive@plt>
  test   %rax,%rax
  jle    L65
  mov    %r12,0x0(%r13)
  mov    %rbp,0x8(%rbx)
  jmp    L65
L36:
  addq   $0x1,(%rsp)
  mov    (%rsp),%rax
  add    $0x8,%r13
  cmp    $0xa,%rax
  je     L23
L102:
  cmpl   $0x9,(%rsp)
  jg     L36
  mov    %r13,%rbx
  jmp    L11
L23:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0x280(%r15),%rbp
  lea    D27(%rip),%rbx
L49:
  mov    %r15,%rdx
  mov    0x8(%rsp),%r14
  mov    (%r14),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rax
  add    $0x8,%rax
  mov    %rax,0x8(%rsp)
  add    $0x40,%r15
  cmp    %rbp,%r15
  jne    L49
L20:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x7e,%al
  jne    L20
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x2e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    $0x0,%eax
  add    $0x2f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type_infered: string
name: read_data
arguments: data_tag: D35
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D27
type_infered: string

tool: D11: Enter %d types of fruits:


tool: D35: #%d: 

tool: D18: 

Sorted list:	Original list:

tool: D27: %12s	%12s


assistant: ```c
int main() {
  char input[10][64];
  char *isort[10];
  char *temp;
  int x, a, b;
  printf("Enter %d types of fruits:\n", 10);
  for (x = 0; x < 10; x++) {
    printf("#%d: ", x + 1);
    gets(input[x]);
    isort[x] = input[x];
  }
  for (a = 0; a < 10 - 1; a++)
    for (b = a + 1; b < 10; b++)
      if (c_insensitive(isort[a], isort[b]) > 0) {
        temp = isort[a];
        isort[a] = isort[b];
        isort[b] = temp;
      }
  printf("\n\nSorted list:\tOriginal list:\n");
  for (x = 0; x < 10; x++)
    printf("%12s\t%12s\n", isort[x], input[x]);
  while (getchar() != '~')
    continue;
  getchar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xa,%esi
  lea    D32(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x2f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2e8(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%r14
  lea    0x10(%rsp),%r13
  mov    %r14,%rbp
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,-0x8(%r13,%rbx,8)
  add    $0x1,%rbx
  add    $0x40,%rbp
  cmp    $0xb,%rbx
  jne    L58
  mov    %r13,0x8(%rsp)
  mov    %r13,%rbp
  lea    0x58(%rsp),%r12
  movq   $0x0,(%rsp)
  nopl   0x0(%rax)
L49:
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L57:
  mov    0x8(%rbx),%r13
  mov    0x0(%rbp),%r15
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <c_insensitive@plt>
  test   %rax,%rax
  jle    L36
  mov    %r13,0x0(%rbp)
  mov    %r15,0x8(%rbx)
L36:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L57
  addq   $0x1,(%rsp)
  mov    (%rsp),%rax
  add    $0x8,%rbp
  cmp    $0x9,%rax
  jne    L49
  lea    D0(%rip),%rdi
  lea    0x280(%r14),%rbp
  call   <puts@plt>
  lea    D35(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    0x8(%rsp),%r15
  mov    %r14,%rdx
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x40,%r14
  mov    (%r15),%rsi
  call   <printf@plt>
  mov    %r15,%rax
  add    $0x8,%rax
  mov    %rax,0x8(%rsp)
  cmp    %r14,%rbp
  jne    L23
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x7e,%al
  jne    L9
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x2e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x2f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D32
data_type: string
name: extract_symbolic_data
arguments: data_label: D34
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string
name: extract_symbolic_data
arguments: data_label: D35
data_type: string

tool: D32: Enter %d types of fruits:


tool: D34: #%d: 

tool: D0: 

Sorted list:	Original list:

tool: D35: %12s	%12s


assistant: ```c
int main() {
  char input[10][64];
  char *isort[10];
  char *temp;
  int x, a, b;
  printf("Enter %d types of fruits:\n", 10);
  for (x = 0; x < 10; x++) {
    printf("#%d: ", x + 1);
    gets(input[x]);
    isort[x] = input[x];
  }
  for (a = 0; a < 10 - 1; a++)
    for (b = a + 1; b < 10; b++)
      if (c_insensitive(isort[a], isort[b]) > 0) {
        temp = isort[a];
        isort[a] = isort[b];
        isort[b] = temp;
      }
  printf("\n\nSorted list:\tOriginal list:\n");
  for (x = 0; x < 10; x++)
    printf("%12s\t%12s\n", isort[x], input[x]);
  while (getchar() != '~')
    continue;
  getchar();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xa,%esi
  lea    D12(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x2f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2e8(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%r14
  lea    0x10(%rsp),%r13
  mov    %r14,%rbp
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,-0x8(%r13,%rbx,8)
  add    $0x1,%rbx
  add    $0x40,%rbp
  cmp    $0xb,%rbx
  jne    L66
  mov    %r13,0x8(%rsp)
  mov    %r13,%rbp
  lea    0x58(%rsp),%r12
  movq   $0x0,(%rsp)
  nopl   0x0(%rax)
L7:
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L65:
  mov    0x8(%rbx),%r13
  mov    0x0(%rbp),%r15
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <c_insensitive@plt>
  test   %rax,%rax
  jle    L69
  mov    %r13,0x0(%rbp)
  mov    %r15,0x8(%rbx)
L69:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L65
  addq   $0x1,(%rsp)
  mov    (%rsp),%rax
  add    $0x8,%rbp
  cmp    $0x9,%rax
  jne    L7
  lea    D25(%rip),%rdi
  lea    0x280(%r14),%rbp
  call   <puts@plt>
  lea    D3(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0x8(%rsp),%r15
  mov    %r14,%rdx
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x40,%r14
  mov    (%r15),%rsi
  call   <printf@plt>
  mov    %r15,%rax
  add    $0x8,%rax
  mov    %rax,0x8(%rsp)
  cmp    %rbp,%r14
  jne    L5
L33:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x7e,%al
  jne    L33
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x2e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x2f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string
name: extract_symbolic_data
arguments: tag: D25
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D12: Enter %d types of fruits:


tool: D2: #%d: 

tool: D25: 

Sorted list:	Original list:

tool: D3: %12s	%12s


assistant: ```c
int main() {
  char input[10][64];
  char *isort[10];
  char *temp;
  int x, a, b;
  printf("Enter %d types of fruits:\n", 10);
  for (x = 0; x < 10; x++) {
    printf("#%d: ", x + 1);
    gets(input[x]);
    isort[x] = input[x];
  }
  for (a = 0; a < 10 - 1; a++)
    for (b = a + 1; b < 10; b++)
      if (c_insensitive(isort[a], isort[b]) > 0) {
        temp = isort[a];
        isort[a] = isort[b];
        isort[b] = temp;
      }
  printf("\n\nSorted list:\tOriginal list:\n");
  for (x = 0; x < 10; x++)
    printf("%12s\t%12s\n", isort[x], input[x]);
  while (getchar() != '~')
    continue;
  getchar();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CRT_getc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  nop
L7:
  mov    $0x0,%edi
  call   <kbd@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int CRT_getc(void) {
  int c;
  while ((c = kbd(0)) == 0)
    ;
  return (c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CRT_getc>:
  endbr64
  sub    $0x8,%rsp
L7:
  mov    $0x0,%edi
  call   <kbd@plt>
  test   %eax,%eax
  je     L7
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CRT_getc(void) {
  int c;
  while ((c = kbd(0)) == 0)
    ;
  return (c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CRT_getc>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %edi,%edi
  call   <kbd@plt>
  test   %eax,%eax
  je     L9
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CRT_getc(void) {
  int c;
  while ((c = kbd(0)) == 0)
    ;
  return (c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CRT_getc>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %edi,%edi
  call   <kbd@plt>
  test   %eax,%eax
  je     L9
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CRT_getc(void) {
  int c;
  while ((c = kbd(0)) == 0)
    ;
  return (c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shex4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <shex2@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <shex2@plt>
  leave
  ret
```

assistant: ```c
char *shex4(char *buf, int val) {
  buf = shex2(buf, val >> 8);
  return shex2(buf, val);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<shex4>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sar    $0x8,%esi
  call   <shex2@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <shex2@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *shex4(char *buf, int val) {
  buf = shex2(buf, val >> 8);
  return shex2(buf, val);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<shex4>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  sar    $0x8,%esi
  call   <shex2@plt>
  mov    %ebp,%esi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1050 <shex2@plt>
```

assistant: ```c
char *shex4(char *buf, int val) {
  buf = shex2(buf, val >> 8);
  return shex2(buf, val);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shex4>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  sar    $0x8,%esi
  call   <shex2@plt>
  mov    %ebp,%esi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1050 <shex2@plt>
```

assistant: ```c
char *shex4(char *buf, int val) {
  buf = shex2(buf, val >> 8);
  return shex2(buf, val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<produtoAdicao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  jne    L0
  mov    -0x4(%rbp),%eax
  jmp    L4
L0:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <produtoAdicao>
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L4:
  leave
  ret
```

assistant: ```c
int produtoAdicao(int k, int q) {
  if (q == 1)
    return k;
  return k += produtoAdicao(k, (q - 1));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<produtoAdicao>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%esi
  je     L6
  push   %rbx
  mov    %edi,%ebx
  sub    $0x1,%esi
  call   <produtoAdicao>
  add    %ebx,%eax
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
int produtoAdicao(int k, int q) {
  if (q == 1)
    return k;
  return k += produtoAdicao(k, (q - 1));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<produtoAdicao>:
  endbr64
  cmp    $0x1,%esi
  je     L2
  sub    $0x2,%esi
  imul   %edi,%esi
  lea    (%rsi,%rdi,2),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edi,%eax
  ret
```

assistant: ```c
int produtoAdicao(int k, int q) {
  if (q == 1)
    return k;
  return k += produtoAdicao(k, (q - 1));
}
```
user: What is the c source code of the assembly code below:

```asm
<produtoAdicao>:
  endbr64
  cmp    $0x1,%esi
  je     L4
  sub    $0x2,%esi
  imul   %edi,%esi
  lea    (%rsi,%rdi,2),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %edi,%eax
  ret
```

assistant: ```c
int produtoAdicao(int k, int q) {
  if (q == 1)
    return k;
  return k += produtoAdicao(k, (q - 1));
}
```