ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x7c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x7c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x7c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_bruteforce_card>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L112
L88:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x7a,%eax
  jg     L3
  cmp    $0x61,%eax
  jge    L8
  cmp    $0x39,%eax
  jg     L30
  cmp    $0x30,%eax
  jge    L108
  jmp    L3
L30:
  sub    $0x41,%eax
  cmp    $0x19,%eax
  ja     L3
  jmp    L89
L108:
  movl   $0x1,-0x10(%rbp)
  jmp    L32
L8:
  movl   $0x1,-0xc(%rbp)
  jmp    L32
L89:
  movl   $0x1,-0x8(%rbp)
  jmp    L32
L3:
  movl   $0x1,-0x4(%rbp)
  nop
L32:
  addl   $0x1,-0x14(%rbp)
L112:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  ja     L88
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   $0x1a,%eax,%eax
  add    %edx,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  imul   $0x1a,%eax,%eax
  add    %edx,%eax
  add    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int calc_bruteforce_card(const char *password, unsigned int password_len, unsigned int n_symbols) {
  int i, digit, lower, upper, symbol;
  digit = lower = upper = symbol = 0;
  for (i = 0; i < password_len; ++i) {
    switch (password[i]) {
    case '0' ... '9':
      digit = 1;
      break;
    case 'a' ... 'z':
      lower = 1;
      break;
    case 'A' ... 'Z':
      upper = 1;
      break;
    default:
      symbol = 1;
      break;
    }
  }
  return digit * ('9' - '0' + 1) + lower * ('z' - 'a' + 1) + upper * ('Z' - 'A' + 1) + symbol * n_symbols;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calc_bruteforce_card>:
  endbr64
  mov    %edx,%r11d
  test   %esi,%esi
  je     L18
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r9
  mov    $0x0,%edx
  mov    $0x0,%r10d
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x1,%ecx
  jmp    L31
L0:
  cmp    $0x40,%al
  jg     L42
  sub    $0x30,%eax
  cmp    $0xa,%al
  cmovae %ecx,%edx
  cmovb  %ecx,%edi
L15:
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L38
L31:
  movzbl (%r8),%eax
  cmp    $0x5a,%al
  jle    L0
  sub    $0x61,%eax
  cmp    $0x1a,%al
  cmovae %ecx,%edx
  cmovb  %ecx,%esi
  jmp    L15
L42:
  mov    %ecx,%r10d
  jmp    L15
L18:
  mov    $0x0,%edx
  mov    $0x0,%r10d
  mov    $0x0,%esi
  mov    $0x0,%edi
L38:
  lea    (%rdi,%rdi,4),%eax
  imul   $0x1a,%esi,%esi
  lea    (%rsi,%rax,2),%eax
  imul   %r11d,%edx
  imul   $0x1a,%r10d,%r10d
  add    %r10d,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int calc_bruteforce_card(const char *password, unsigned int password_len, unsigned int n_symbols) {
  int i, digit, lower, upper, symbol;
  digit = lower = upper = symbol = 0;
  for (i = 0; i < password_len; ++i) {
    switch (password[i]) {
    case '0' ... '9':
      digit = 1;
      break;
    case 'a' ... 'z':
      lower = 1;
      break;
    case 'A' ... 'Z':
      upper = 1;
      break;
    default:
      symbol = 1;
      break;
    }
  }
  return digit * ('9' - '0' + 1) + lower * ('z' - 'a' + 1) + upper * ('Z' - 'A' + 1) + symbol * n_symbols;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_bruteforce_card>:
  endbr64
  mov    %edx,%r11d
  test   %esi,%esi
  je     L15
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  xor    %r10d,%r10d
  xor    %esi,%esi
  lea    0x1(%rdi,%rax,1),%r9
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L26:
  cmp    $0x40,%al
  jg     L1
  sub    $0x30,%eax
  cmp    $0xa,%al
  cmovae %ecx,%edx
  cmovb  %ecx,%r8d
L17:
  add    $0x1,%rdi
  cmp    %rdi,%r9
  je     L30
  nopl   0x0(%rax)
L59:
  movzbl (%rdi),%eax
  cmp    $0x5a,%al
  jle    L26
  sub    $0x61,%eax
  cmp    $0x1a,%al
  cmovae %ecx,%edx
  cmovb  %ecx,%esi
  add    $0x1,%rdi
  cmp    %rdi,%r9
  jne    L59
L30:
  imul   $0x1a,%esi,%esi
  lea    (%r8,%r8,4),%eax
  imul   %r11d,%edx
  imul   $0x1a,%r10d,%r10d
  lea    (%rsi,%rax,2),%eax
  add    %r10d,%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%r10d
  jmp    L17
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int calc_bruteforce_card(const char *password, unsigned int password_len, unsigned int n_symbols) {
  int i, digit, lower, upper, symbol;
  digit = lower = upper = symbol = 0;
  for (i = 0; i < password_len; ++i) {
    switch (password[i]) {
    case '0' ... '9':
      digit = 1;
      break;
    case 'a' ... 'z':
      lower = 1;
      break;
    case 'A' ... 'Z':
      upper = 1;
      break;
    default:
      symbol = 1;
      break;
    }
  }
  return digit * ('9' - '0' + 1) + lower * ('z' - 'a' + 1) + upper * ('Z' - 'A' + 1) + symbol * n_symbols;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calc_bruteforce_card>:
  endbr64
  mov    %edx,%r11d
  test   %esi,%esi
  je     L53
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  xor    %r10d,%r10d
  xor    %esi,%esi
  lea    0x1(%rdi,%rax,1),%r9
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L55:
  cmp    $0x40,%al
  jg     L5
  sub    $0x30,%eax
  cmp    $0xa,%al
  cmovae %ecx,%edx
  cmovb  %ecx,%r8d
L54:
  add    $0x1,%rdi
  cmp    %rdi,%r9
  je     L60
  nopl   0x0(%rax)
L42:
  movzbl (%rdi),%eax
  cmp    $0x5a,%al
  jle    L55
  sub    $0x61,%eax
  cmp    $0x1a,%al
  cmovae %ecx,%edx
  cmovb  %ecx,%esi
  add    $0x1,%rdi
  cmp    %rdi,%r9
  jne    L42
L60:
  imul   $0x1a,%esi,%esi
  lea    (%r8,%r8,4),%eax
  imul   %r11d,%edx
  imul   $0x1a,%r10d,%r10d
  lea    (%rsi,%rax,2),%eax
  add    %r10d,%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%r10d
  jmp    L54
L53:
  xor    %eax,%eax
  ret
```

assistant: ```c
int calc_bruteforce_card(const char *password, unsigned int password_len, unsigned int n_symbols) {
  int i, digit, lower, upper, symbol;
  digit = lower = upper = symbol = 0;
  for (i = 0; i < password_len; ++i) {
    switch (password[i]) {
    case '0' ... '9':
      digit = 1;
      break;
    case 'a' ... 'z':
      lower = 1;
      break;
    case 'A' ... 'Z':
      upper = 1;
      break;
    default:
      symbol = 1;
      break;
    }
  }
  return digit * ('9' - '0' + 1) + lower * ('z' - 'a' + 1) + upper * ('Z' - 'A' + 1) + symbol * n_symbols;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<no_curor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void no_curor(void) {
  ;
  ;
  ;
}
```
user: What is the c source code of the assembly code below:

```asm
<no_curor>:
  endbr64
  ret
```

assistant: ```c
void no_curor(void) {
  ;
  ;
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<no_curor>:
  endbr64
  ret
```

assistant: ```c
void no_curor(void) {
  ;
  ;
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<no_curor>:
  endbr64
  ret
```

assistant: ```c
void no_curor(void) {
  ;
  ;
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<max_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sysconf@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L8
  mov    -0x4(%rbp),%eax
  jmp    L12
L8:
  mov    $0x1000,%eax
L12:
  leave
  ret
```

assistant: ```c
int max_fd(void) {
  int ret = sysconf(_SC_OPEN_MAX);
  return ret != -1 ? ret : 4096;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<max_fd>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  cmp    $0xffffffff,%eax
  mov    $0x1000,%edx
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int max_fd(void) {
  int ret = sysconf(_SC_OPEN_MAX);
  return ret != -1 ? ret : 4096;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<max_fd>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    $0x1000,%edx
  cmp    $0xffffffff,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int max_fd(void) {
  int ret = sysconf(_SC_OPEN_MAX);
  return ret != -1 ? ret : 4096;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<max_fd>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    $0x1000,%edx
  cmp    $0xffffffff,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int max_fd(void) {
  int ret = sysconf(_SC_OPEN_MAX);
  return ret != -1 ? ret : 4096;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<q0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x61,-0x4(%rbp)
  jne    L37
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L20
L37:
  cmpb   $0x62,-0x4(%rbp)
  jne    L20
  mov    $0x1,%eax
  jmp    L20
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: *** state 0 ***


assistant: ```c
int q0(char c) {
  if (c == 'a') {
    printf("*** state 0 ***\n");
    return 0;
  } else if (c == 'b') {
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<q0>:
  endbr64
  cmp    $0x61,%dil
  je     L16
  mov    $0x1,%eax
  cmp    $0x62,%dil
  je     L11
  ret
L16:
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L11:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: *** state 0 ***


assistant: ```c
int q0(char c) {
  if (c == 'a') {
    printf("*** state 0 ***\n");
    return 0;
  } else if (c == 'b') {
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<q0>:
  endbr64
  cmp    $0x61,%dil
  je     L2
  mov    $0x1,%eax
  cmp    $0x62,%dil
  je     L6
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6: *** state 0 ***


assistant: ```c
int q0(char c) {
  if (c == 'a') {
    printf("*** state 0 ***\n");
    return 0;
  } else if (c == 'b') {
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<q0>:
  endbr64
  cmp    $0x61,%dil
  je     L14
  mov    $0x1,%eax
  cmp    $0x62,%dil
  je     L11
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  ret
  nopl   0x0(%rax)
L14:
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: *** state 0 ***


assistant: ```c
int q0(char c) {
  if (c == 'a') {
    printf("*** state 0 ***\n");
    return 0;
  } else if (c == 'b') {
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <time_clock_digital@plt>
  mov    $0x0,%eax
  call   <time_clock_date_words@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_time(void) {
  time_clock_digital();
  time_clock_date_words();
}
```
user: What is the c source code of the assembly code below?

```asm
<init_time>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <time_clock_digital@plt>
  mov    $0x0,%eax
  call   <time_clock_date_words@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_time(void) {
  time_clock_digital();
  time_clock_date_words();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_time>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <time_clock_digital@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <time_clock_date_words@plt>
```

assistant: ```c
void init_time(void) {
  time_clock_digital();
  time_clock_date_words();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_time>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <time_clock_digital@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <time_clock_date_words@plt>
```

assistant: ```c
void init_time(void) {
  time_clock_digital();
  time_clock_date_words();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mult@plt>
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D26
type_infered: string
name: unpack_data
arguments: data_label: D25
type_infered: string
name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D38
type_infered: string

tool: D16: Please enter two numbers to be multiplied

tool: D26: Please enter the first value to be multiplied: 

tool: D25: %d

tool: D15: Please enter the second value to be multiplied: 

tool: D38: The product of your two numbers is %d


assistant: ```c
int main() {
  int x;
  int y;
  printf("Please enter two numbers to be multiplied\n");
  printf("Please enter the first value to be multiplied: ");
  scanf("%d", &x);
  printf("Please enter the second value to be multiplied: ");
  scanf("%d", &y);
  printf("The product of your two numbers is %d\n", mult(x, y));
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D44(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <mult@plt>
  mov    %eax,%esi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D25
datatype: string
name: unpack_data
arguments: tag: D44
datatype: string
name: unpack_data
arguments: tag: D32
datatype: string
name: unpack_data
arguments: tag: D38
datatype: string

tool: D28: Please enter two numbers to be multiplied

tool: D25: Please enter the first value to be multiplied: 

tool: D44: %d

tool: D32: Please enter the second value to be multiplied: 

tool: D38: The product of your two numbers is %d


assistant: ```c
int main() {
  int x;
  int y;
  printf("Please enter two numbers to be multiplied\n");
  printf("Please enter the first value to be multiplied: ");
  scanf("%d", &x);
  printf("Please enter the second value to be multiplied: ");
  scanf("%d", &y);
  printf("The product of your two numbers is %d\n", mult(x, y));
  getchar();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D14(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <mult@plt>
  lea    D48(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D14
type: string
name: parse_data
arguments: data_label: D27
type: string
name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D48
type: string

tool: D11: Please enter two numbers to be multiplied

tool: D14: %d

tool: D27: Please enter the first value to be multiplied: 

tool: D25: Please enter the second value to be multiplied: 

tool: D48: The product of your two numbers is %d


assistant: ```c
int main() {
  int x;
  int y;
  printf("Please enter two numbers to be multiplied\n");
  printf("Please enter the first value to be multiplied: ");
  scanf("%d", &x);
  printf("Please enter the second value to be multiplied: ");
  scanf("%d", &y);
  printf("The product of your two numbers is %d\n", mult(x, y));
  getchar();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D22(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <mult@plt>
  lea    D31(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D22
datatype: string
name: extract_symbolic_data
arguments: data_label: D40
datatype: string
name: extract_symbolic_data
arguments: data_label: D30
datatype: string
name: extract_symbolic_data
arguments: data_label: D31
datatype: string

tool: D11: Please enter two numbers to be multiplied

tool: D22: %d

tool: D40: Please enter the first value to be multiplied: 

tool: D30: Please enter the second value to be multiplied: 

tool: D31: The product of your two numbers is %d


assistant: ```c
int main() {
  int x;
  int y;
  printf("Please enter two numbers to be multiplied\n");
  printf("Please enter the first value to be multiplied: ");
  scanf("%d", &x);
  printf("Please enter the second value to be multiplied: ");
  scanf("%d", &y);
  printf("The product of your two numbers is %d\n", mult(x, y));
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<heap_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L3:
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <build_heap_tree@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void heap_sort(int *array, int n) {
  for (int i = 0; i < n; i++) {
    build_heap_tree(array, n - i);
    swap(&array[0], &array[n - 1 - i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<heap_sort>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  movslq %esi,%rsi
  lea    -0x4(%rdi,%rsi,4),%rbp
L0:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <build_heap_tree@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  sub    $0x4,%rbp
  sub    $0x1,%ebx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  ret
```

assistant: ```c
void heap_sort(int *array, int n) {
  for (int i = 0; i < n; i++) {
    build_heap_tree(array, n - i);
    swap(&array[0], &array[n - 1 - i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<heap_sort>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  push   %r12
  mov    %rdi,%r12
  cltq
  push   %rbp
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  mov    %esi,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <build_heap_tree@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    $0x4,%rbp
  call   <swap@plt>
  sub    $0x1,%ebx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void heap_sort(int *array, int n) {
  for (int i = 0; i < n; i++) {
    build_heap_tree(array, n - i);
    swap(&array[0], &array[n - 1 - i]);
  }
}
```