ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L61:
  cmp    %rdx,%rsp
  je     L28
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L61
L28:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L84
  orq    $0x0,-0x8(%rsp,%rax,1)
L84:
  lea    0x7(%rsp),%r12
  mov    %r12,%rax
  shr    $0x3,%rax
  mov    %rax,-0x48(%rbp)
  and    $0xfffffffffffffff8,%r12
  test   %r13d,%r13d
  jle    L71
  mov    %r12,%rbx
  mov    %r13d,%eax
  lea    (%r12,%rax,8),%r15
L101:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D18(%rip),%xmm0
  subsd  D4(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L101
L71:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r14d,%r14d
  jle    L54
  mov    $0x0,%ebx
L45:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    D1(%rip),%rax
  movq   %rax,%xmm0
  mov    %r13d,%edi
  call   <c_dscal@plt>
  movsd  (%r12),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L26
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jne    L45
  jmp    L54
L26:
  lea    D41(%rip),%rdi
  call   <printf@plt>
L54:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    -0x48(%rbp),%rax
  movsd  0x0(,%rax,8),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L5
L32:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L5:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: f64
name: retrieve_data
arguments: data_tag: D4
type_guessed: f64
name: retrieve_data
arguments: data_tag: D1
type_guessed: f64
name: retrieve_data
arguments: data_tag: D41
type_guessed: string

tool: D18: 200

tool: D4: 100

tool: D1: 5

tool: D41: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 200.0) - 100.0;
  }
  t = tic();
  for (i = 0; i < iterations; i++) {
    c_dscal(len, 5.0, x, 1);
    if (x[0] != x[0]) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (x[0] != x[0]) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L93
L103:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L103
L93:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L62
L50:
  lea    0x7(%rsp),%rbx
  mov    %rbx,%rax
  and    $0xfffffffffffffff8,%rbx
  shr    $0x3,%rax
  mov    %rax,-0x50(%rbp)
  test   %r12d,%r12d
  jle    L94
  mov    %r12d,%eax
  mov    %rbx,%r15
  lea    (%rbx,%rax,8),%r14
  nopw   0x0(%rax,%rax,1)
L83:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D28(%rip),%xmm0
  subsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L83
L94:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r13d,%r13d
  jle    L88
  xor    %r14d,%r14d
  jmp    L36
  nopl   0x0(%rax)
L129:
  add    $0x1,%r14d
  cmp    %r14d,%r13d
  je     L88
L36:
  mov    D36(%rip),%rax
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  movq   %rax,%xmm0
  call   <c_dscal@plt>
  movsd  (%rbx),%xmm0
  ucomisd %xmm0,%xmm0
  jnp    L129
  lea    D23(%rip),%rdi
  call   <printf@plt>
L88:
  xor    %eax,%eax
  call   <tic@plt>
  mov    -0x50(%rbp),%rax
  subsd  -0x48(%rbp),%xmm0
  movsd  0x0(,%rax,8),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L17
L125:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  lea    D23(%rip),%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
  jmp    L125
  nopl   0x0(%rax,%rax,1)
L62:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L50
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D28
datatype: f64
name: read_data
arguments: label: D16
datatype: f64
name: read_data
arguments: label: D36
datatype: f64
name: read_data
arguments: label: D23
datatype: string

tool: D28: 200

tool: D16: 100

tool: D36: 5

tool: D23: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 200.0) - 100.0;
  }
  t = tic();
  for (i = 0; i < iterations; i++) {
    c_dscal(len, 5.0, x, 1);
    if (x[0] != x[0]) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (x[0] != x[0]) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L119
L8:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L8
L119:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L91
L47:
  lea    0x7(%rsp),%rbx
  mov    %rbx,%rax
  and    $0xfffffffffffffff8,%rbx
  shr    $0x3,%rax
  mov    %rax,-0x50(%rbp)
  test   %r12d,%r12d
  jle    L65
  mov    %r12d,%eax
  mov    %rbx,%r15
  lea    (%rbx,%rax,8),%r14
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D6(%rip),%xmm0
  subsd  D40(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L33
L65:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r13d,%r13d
  jle    L29
  xor    %r14d,%r14d
  jmp    L68
  nopl   0x0(%rax)
L76:
  add    $0x1,%r14d
  cmp    %r14d,%r13d
  je     L29
L68:
  mov    D35(%rip),%rax
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  movq   %rax,%xmm0
  call   <c_dscal@plt>
  movsd  (%rbx),%xmm0
  ucomisd %xmm0,%xmm0
  jnp    L76
  lea    D28(%rip),%rdi
  call   <printf@plt>
L29:
  xor    %eax,%eax
  call   <tic@plt>
  mov    -0x50(%rbp),%rax
  subsd  -0x48(%rbp),%xmm0
  movsd  0x0(,%rax,8),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L73
L32:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  lea    D28(%rip),%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L91:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L47
L110:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: f64
name: disassemble_data
arguments: label: D40
type_infered: f64
name: disassemble_data
arguments: label: D35
type_infered: f64
name: disassemble_data
arguments: label: D28
type_infered: string

tool: D6: 200

tool: D40: 100

tool: D35: 5

tool: D28: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 200.0) - 100.0;
  }
  t = tic();
  for (i = 0; i < iterations; i++) {
    c_dscal(len, 5.0, x, 1);
    if (x[0] != x[0]) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (x[0] != x[0]) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rtl_asnprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <rtl_vasnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rtl_asnprintf(char **buf, size_t size, const char *format, ...) {
  va_list arg;
  int rv;
  va_start(arg, format);
  rv = rtl_vasnprintf(buf, size, format, arg);
  va_end(arg);
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rtl_asnprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <rtl_vasnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int rtl_asnprintf(char **buf, size_t size, const char *format, ...) {
  va_list arg;
  int rv;
  va_start(arg, format);
  rv = rtl_vasnprintf(buf, size, format, arg);
  va_end(arg);
  return rv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtl_asnprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <rtl_vasnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int rtl_asnprintf(char **buf, size_t size, const char *format, ...) {
  va_list arg;
  int rv;
  va_start(arg, format);
  rv = rtl_vasnprintf(buf, size, format, arg);
  va_end(arg);
  return rv;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtl_asnprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <rtl_vasnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int rtl_asnprintf(char **buf, size_t size, const char *format, ...) {
  va_list arg;
  int rv;
  va_start(arg, format);
  rv = rtl_vasnprintf(buf, size, format, arg);
  va_end(arg);
  return rv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<show_standard_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    -0x54(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <padcon_get_standard_solution@plt>
  mov    %eax,-0x4c(%rbp)
  lea    -0x50(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <solcon_length_standard_solution_string@plt>
  mov    %eax,-0x4c(%rbp)
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x50(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L10:
  cmp    %rdx,%rsp
  je     L29
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L10
L29:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L35
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L35:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x50(%rbp),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <solcon_write_standard_solution_string@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: Solution %d :
%s


assistant: ```c
void show_standard_solution(int index) {
  int fail, strlensol;
  fail = padcon_get_standard_solution(index, 0);
  fail = solcon_length_standard_solution_string(index, &strlensol);
  {
    char idxsol[strlensol + 1];
    fail = solcon_write_standard_solution_string(index, strlensol, idxsol);
    printf("Solution %d :\n%s\n", index, idxsol);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<show_standard_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%esi
  call   <padcon_get_standard_solution@plt>
  lea    -0x1c(%rbp),%rsi
  mov    %ebx,%edi
  call   <solcon_length_standard_solution_string@plt>
  mov    -0x1c(%rbp),%esi
  lea    0x1(%rsi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L17:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L17
L38:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L6
  orq    $0x0,-0x8(%rsp,%rax,1)
L6:
  mov    %rsp,%rdx
  mov    %ebx,%edi
  call   <solcon_write_standard_solution_string@plt>
  mov    %rsp,%rdx
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    -0x8(%rbp),%rbx
  leave
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: Solution %d :
%s


assistant: ```c
void show_standard_solution(int index) {
  int fail, strlensol;
  fail = padcon_get_standard_solution(index, 0);
  fail = solcon_length_standard_solution_string(index, &strlensol);
  {
    char idxsol[strlensol + 1];
    fail = solcon_write_standard_solution_string(index, strlensol, idxsol);
    printf("Solution %d :\n%s\n", index, idxsol);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<show_standard_solution>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rsp,%rbp
  push   %r12
  mov    %edi,%r12d
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <padcon_get_standard_solution@plt>
  lea    -0x1c(%rbp),%rsi
  mov    %r12d,%edi
  call   <solcon_length_standard_solution_string@plt>
  mov    -0x1c(%rbp),%esi
  mov    %rsp,%rcx
  lea    0x1(%rsi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L19
L26:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L26
L19:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L1
L48:
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <solcon_write_standard_solution_string@plt>
  mov    %rsp,%rdx
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax)
L1:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L48
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: Solution %d :
%s


assistant: ```c
void show_standard_solution(int index) {
  int fail, strlensol;
  fail = padcon_get_standard_solution(index, 0);
  fail = solcon_length_standard_solution_string(index, &strlensol);
  {
    char idxsol[strlensol + 1];
    fail = solcon_write_standard_solution_string(index, strlensol, idxsol);
    printf("Solution %d :\n%s\n", index, idxsol);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show_standard_solution>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rsp,%rbp
  push   %r12
  mov    %edi,%r12d
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <padcon_get_standard_solution@plt>
  lea    -0x1c(%rbp),%rsi
  mov    %r12d,%edi
  call   <solcon_length_standard_solution_string@plt>
  mov    -0x1c(%rbp),%esi
  mov    %rsp,%rcx
  lea    0x1(%rsi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L42
L28:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L28
L42:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L12
L8:
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <solcon_write_standard_solution_string@plt>
  mov    %rsp,%rdx
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax)
L12:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L8
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
type: string

tool: D9: Solution %d :
%s


assistant: ```c
void show_standard_solution(int index) {
  int fail, strlensol;
  fail = padcon_get_standard_solution(index, 0);
  fail = solcon_length_standard_solution_string(index, &strlensol);
  {
    char idxsol[strlensol + 1];
    fail = solcon_write_standard_solution_string(index, strlensol, idxsol);
    printf("Solution %d :\n%s\n", index, idxsol);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L12
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  jmp    L10
L0:
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L6
L12:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  if (n != 0) {
    const unsigned char *p = s;
    do {
      if (*p++ == (unsigned char)c) {
        return ((void *)(p - 1));
      }
    } while (--n != 0);
  }
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memchr>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L1
  add    %rdi,%rdx
L2:
  mov    %rdi,%rax
  add    $0x1,%rdi
  cmp    %sil,-0x1(%rdi)
  je     L1
  cmp    %rdx,%rdi
  jne    L2
  mov    $0x0,%eax
L1:
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  if (n != 0) {
    const unsigned char *p = s;
    do {
      if (*p++ == (unsigned char)c) {
        return ((void *)(p - 1));
      }
    } while (--n != 0);
  }
  return (NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memchr>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L37
  add    %rdi,%rdx
  jmp    L3
L9:
  cmp    %rdx,%rdi
  je     L24
L3:
  mov    %rdi,%rax
  lea    0x1(%rdi),%rdi
  cmp    (%rax),%sil
  jne    L9
L37:
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  if (n != 0) {
    const unsigned char *p = s;
    do {
      if (*p++ == (unsigned char)c) {
        return ((void *)(p - 1));
      }
    } while (--n != 0);
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memchr>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L30
  add    %rdi,%rdx
  jmp    L5
L14:
  cmp    %rdx,%rdi
  je     L7
L5:
  mov    %rdi,%rax
  lea    0x1(%rdi),%rdi
  cmp    (%rax),%sil
  jne    L14
L30:
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  if (n != 0) {
    const unsigned char *p = s;
    do {
      if (*p++ == (unsigned char)c) {
        return ((void *)(p - 1));
      }
    } while (--n != 0);
  }
  return (NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IntPendClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0xe,-0x8(%rbp)
  jne    L21
  mov    $0xe000ed04,%eax
  mov    (%rax),%rdx
  mov    $0xe000ed04,%eax
  or     $0x8000000,%rdx
  mov    %rdx,(%rax)
  jmp    L18
L21:
  cmpq   $0xf,-0x8(%rbp)
  jne    L17
  mov    $0xe000ed04,%eax
  mov    (%rax),%rdx
  mov    $0xe000ed04,%eax
  or     $0x2000000,%rdx
  mov    %rdx,(%rax)
  jmp    L18
L17:
  cmpq   $0xf,-0x8(%rbp)
  jbe    L2
  cmpq   $0x2f,-0x8(%rbp)
  ja     L2
  mov    -0x8(%rbp),%rax
  sub    $0x10,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    $0xe000e280,%edx
  cltq
  mov    %rax,(%rdx)
  jmp    L18
L2:
  cmpq   $0x2f,-0x8(%rbp)
  jbe    L18
  mov    -0x8(%rbp),%rax
  sub    $0x30,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    $0xe000e284,%edx
  cltq
  mov    %rax,(%rdx)
L18:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void IntPendClear(unsigned long ulInterrupt) {
  ;
  if (ulInterrupt == 14) {
    (*((volatile unsigned long *)(0xE000ED04))) |= 0x08000000;
  } else if (ulInterrupt == 15) {
    (*((volatile unsigned long *)(0xE000ED04))) |= 0x02000000;
  } else if ((ulInterrupt >= 16) && (ulInterrupt <= 47)) {
    (*((volatile unsigned long *)(0xE000E280))) = 1 << (ulInterrupt - 16);
  } else if (ulInterrupt >= 48) {
    (*((volatile unsigned long *)(0xE000E284))) = 1 << (ulInterrupt - 48);
  }
}
```