ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<chi>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r8d
  mov    $0xcccccccd,%ecx
L27:
  mov    %r8d,%eax
  imul   %rcx,%rax
  shr    $0x22,%rax
  lea    (%rax,%rax,4),%edx
  mov    %r8d,%eax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%esi
  lea    0xe(%rsp),%r9
  mov    $0x0,%eax
L24:
  mov    %eax,%edx
  imul   %rcx,%rdx
  shr    $0x22,%rdx
  lea    (%rdx,%rdx,4),%r10d
  mov    %eax,%edx
  sub    %r10d,%edx
  lea    (%rdx,%rsi,1),%r10d
  mov    %eax,%edx
  add    $0x1,%eax
  add    $0x2,%edx
  mov    %edx,%r11d
  imul   %rcx,%r11
  shr    $0x22,%r11
  lea    (%r11,%r11,4),%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rsi,1),%r11d
  mov    %eax,%edx
  imul   %rcx,%rdx
  shr    $0x22,%rdx
  lea    (%rdx,%rdx,4),%ebx
  mov    %eax,%edx
  sub    %ebx,%edx
  lea    (%rdx,%rsi,1),%edx
  movzwl (%rdi,%rdx,2),%edx
  not    %edx
  and    (%rdi,%r11,2),%dx
  xor    (%rdi,%r10,2),%dx
  mov    %dx,(%r9)
  add    $0x2,%r9
  cmp    $0x5,%eax
  jne    L24
  mov    $0x0,%edx
L32:
  mov    %edx,%eax
  imul   %rcx,%rax
  shr    $0x22,%rax
  lea    (%rax,%rax,4),%r9d
  mov    %edx,%eax
  sub    %r9d,%eax
  lea    (%rax,%rsi,1),%eax
  movzwl 0xe(%rsp,%rdx,2),%r9d
  mov    %r9w,(%rdi,%rax,2)
  add    $0x1,%rdx
  cmp    $0x5,%rdx
  jne    L32
  add    $0x1,%r8d
  cmp    $0x5,%r8d
  jne    L27
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void chi(unsigned short *A) {
  unsigned int x, y;
  unsigned short C[5];
  for (y = 0; y < 5; y++) {
    for (x = 0; x < 5; x++)
      C[x] = A[(((x) % 5) + 5 * ((y) % 5))] ^ ((~A[(((x + 1) % 5) + 5 * ((y) % 5))]) & A[(((x + 2) % 5) + 5 * ((y) % 5))]);
    for (x = 0; x < 5; x++)
      A[(((x) % 5) + 5 * ((y) % 5))] = C[x];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<chi>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%r8
  lea    0x32(%rdi),%r10
  xor    %ecx,%ecx
  mov    $0xcccccccd,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r9
L9:
  mov    $0x1,%eax
L23:
  lea    0x1(%rax),%edx
  mov    %rdx,%r11
  imul   %rdi,%rdx
  shr    $0x22,%rdx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%r11d
  mov    %eax,%edx
  imul   %rdi,%rdx
  add    %ecx,%r11d
  mov    %r11d,%r11d
  shr    $0x22,%rdx
  lea    (%rdx,%rdx,4),%ebx
  mov    %eax,%edx
  sub    %ebx,%edx
  add    %ecx,%edx
  mov    %edx,%edx
  movzwl (%rsi,%rdx,2),%edx
  not    %edx
  and    (%rsi,%r11,2),%dx
  xor    -0x2(%r8,%rax,2),%dx
  mov    %dx,-0x2(%r9,%rax,2)
  add    $0x1,%rax
  cmp    $0x6,%rax
  jne    L23
  mov    (%r9),%rax
  add    $0xa,%r8
  add    $0x5,%ecx
  mov    %rax,-0xa(%r8)
  movzwl 0x8(%r9),%eax
  mov    %ax,-0x2(%r8)
  cmp    %r10,%r8
  jne    L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x20,%rsp
  pop    %rbx
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void chi(unsigned short *A) {
  unsigned int x, y;
  unsigned short C[5];
  for (y = 0; y < 5; y++) {
    for (x = 0; x < 5; x++)
      C[x] = A[(((x) % 5) + 5 * ((y) % 5))] ^ ((~A[(((x + 1) % 5) + 5 * ((y) % 5))]) & A[(((x + 2) % 5) + 5 * ((y) % 5))]);
    for (x = 0; x < 5; x++)
      A[(((x) % 5) + 5 * ((y) % 5))] = C[x];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  jmp    L7
L17:
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D30
datatype: string

tool: D11: r

tool: D5: /bin/ls

tool: D19: yes


tool: D30: no


assistant: ```c
int main() {
  FILE *fp = fopen("/bin/ls", "r");
  if (fp != NULL) {
    printf("yes\n");
    fclose(fp);
  } else
    printf("no\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D15(%rip),%rsi
  lea    D33(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbx
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L9:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L10:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D33
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D15: r

tool: D33: /bin/ls

tool: D18: yes


tool: D0: no


assistant: ```c
int main() {
  FILE *fp = fopen("/bin/ls", "r");
  if (fp != NULL) {
    printf("yes\n");
    fclose(fp);
  } else
    printf("no\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rsi
  lea    D26(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L10:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D26
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string
name: extract_symbolic_data
arguments: data_label: D32
type: string

tool: D0: r

tool: D26: /bin/ls

tool: D10: yes


tool: D32: no


assistant: ```c
int main() {
  FILE *fp = fopen("/bin/ls", "r");
  if (fp != NULL) {
    printf("yes\n");
    fclose(fp);
  } else
    printf("no\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rsi
  lea    D22(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbp
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L12:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D22
datatype: string
name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D1
datatype: string

tool: D19: r

tool: D22: /bin/ls

tool: D23: yes


tool: D1: no


assistant: ```c
int main() {
  FILE *fp = fopen("/bin/ls", "r");
  if (fp != NULL) {
    printf("yes\n");
    fclose(fp);
  } else
    printf("no\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<m_conf_multiple_choice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  je     L62
  mov    D15(%rip),%rax
  jmp    L49
L62:
  mov    D18(%rip),%rax
L49:
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L6
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jne    L12
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  jmp    L48
L12:
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L35
L6:
  mov    $0x0,%eax
L48:
  leave
  ret
```

assistant: ```c
int m_conf_multiple_choice(char *ope, char *opestr, char *val, char **choice, int choice_n, int case_sensitive) {
  int i;
  int (*compare)(const char *, const char *);
  compare = (case_sensitive) ? strcmp : strcasecmp;
  if (strcmp(ope, opestr) == 0) {
    for (i = 0; i < choice_n; i++) {
      if (compare(val, choice[i]) == 0)
        return i + 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<m_conf_multiple_choice>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8d,%ebp
  test   %r9d,%r9d
  jne    L59
  mov    D19(%rip),%r15
L71:
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L5
  test   %ebp,%ebp
  jle    L31
  mov    %ebp,%ebp
  mov    $0x0,%ebx
L72:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r12,%rdi
  call   *%r15
  test   %eax,%eax
  je     L62
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L72
  mov    $0x0,%eax
  jmp    L5
L59:
  mov    D17(%rip),%r15
  jmp    L71
L62:
  lea    0x1(%rbx),%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  mov    $0x0,%eax
  jmp    L5
```

assistant: ```c
int m_conf_multiple_choice(char *ope, char *opestr, char *val, char **choice, int choice_n, int case_sensitive) {
  int i;
  int (*compare)(const char *, const char *);
  compare = (case_sensitive) ? strcmp : strcasecmp;
  if (strcmp(ope, opestr) == 0) {
    for (i = 0; i < choice_n; i++) {
      if (compare(val, choice[i]) == 0)
        return i + 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<m_conf_multiple_choice>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %r8d,%ebx
  test   %r9d,%r9d
  jne    L54
  mov    D10(%rip),%r13
L49:
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L57
  test   %ebx,%ebx
  jle    L57
  lea    0x1(%rbx),%r14d
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L30:
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    %rbp,%rdi
  call   *%r13
  mov    %ebx,%r8d
  test   %eax,%eax
  je     L34
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L30
L57:
  xor    %r8d,%r8d
L34:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  mov    D5(%rip),%r13
  jmp    L49
```

assistant: ```c
int m_conf_multiple_choice(char *ope, char *opestr, char *val, char **choice, int choice_n, int case_sensitive) {
  int i;
  int (*compare)(const char *, const char *);
  compare = (case_sensitive) ? strcmp : strcasecmp;
  if (strcmp(ope, opestr) == 0) {
    for (i = 0; i < choice_n; i++) {
      if (compare(val, choice[i]) == 0)
        return i + 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<m_conf_multiple_choice>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %r8d,%ebx
  test   %r9d,%r9d
  jne    L28
  mov    D0(%rip),%r13
L15:
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L6
  test   %ebx,%ebx
  jle    L6
  lea    0x1(%rbx),%r14d
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L48:
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    %rbp,%rdi
  call   *%r13
  mov    %ebx,%r8d
  test   %eax,%eax
  je     L24
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L48
L6:
  xor    %r8d,%r8d
L24:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    D3(%rip),%r13
  jmp    L15
```

assistant: ```c
int m_conf_multiple_choice(char *ope, char *opestr, char *val, char **choice, int choice_n, int case_sensitive) {
  int i;
  int (*compare)(const char *, const char *);
  compare = (case_sensitive) ? strcmp : strcasecmp;
  if (strcmp(ope, opestr) == 0) {
    for (i = 0; i < choice_n; i++) {
      if (compare(val, choice[i]) == 0)
        return i + 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<append_timestamp_katcl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <before_append_katcl@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L14
L8:
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <add_timestamp_parse_katcl@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <after_append_katcl@plt>
L14:
  leave
  ret
```

assistant: ```c
int append_timestamp_katcl(struct katcl_line *l, int flags, struct timeval *tv) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_timestamp_parse_katcl(p, flags, tv);
  return after_append_katcl(l, flags, result);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<append_timestamp_katcl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <add_timestamp_parse_katcl@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <after_append_katcl@plt>
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int append_timestamp_katcl(struct katcl_line *l, int flags, struct timeval *tv) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_timestamp_parse_katcl(p, flags, tv);
  return after_append_katcl(l, flags, result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_timestamp_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L3
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <add_timestamp_parse_katcl@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <after_append_katcl@plt>
L3:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int append_timestamp_katcl(struct katcl_line *l, int flags, struct timeval *tv) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_timestamp_parse_katcl(p, flags, tv);
  return after_append_katcl(l, flags, result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<append_timestamp_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L3
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <add_timestamp_parse_katcl@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <after_append_katcl@plt>
L3:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int append_timestamp_katcl(struct katcl_line *l, int flags, struct timeval *tv) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_timestamp_parse_katcl(p, flags, tv);
  return after_append_katcl(l, flags, result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L4:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <varbessel2@plt>
  movq   %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0x4(%rbp),%ecx
  movq   %rax,%xmm0
  mov    %ecx,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x5,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_infered: f64
name: disassemble_data
arguments: data_label: D20
type_infered: string

tool: D4: 0.5

tool: D20: 
varbessel2(%d,%4.2f)=%e

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\nvarbessel2(%d,%4.2f)=%e", n, n * 0.5, varbessel2(n, n * 0.5));
  }
  getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D8(%rip),%r12
L1:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D15(%rip),%xmm0
  cvttsd2si %xmm0,%ebp
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <varbessel2@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L1
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string
name: retrieve_data
arguments: label: D15
data_type: f64

tool: D8: 
varbessel2(%d,%4.2f)=%e

tool: D15: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\nvarbessel2(%d,%4.2f)=%e", n, n * 0.5, varbessel2(n, n * 0.5));
  }
  getch();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
L3:
  pxor   %xmm0,%xmm0
  mov    %ebx,%edi
  cvtsi2sd %ebx,%xmm0
  mulsd  D17(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  mov    %r12d,%esi
  call   <varbessel2@plt>
  mov    %ebx,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L3
  xor    %eax,%eax
  call   <getch@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_guessed: string
name: unpack_data
arguments: label: D17
type_guessed: f64

tool: D13: 
varbessel2(%d,%4.2f)=%e

tool: D17: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\nvarbessel2(%d,%4.2f)=%e", n, n * 0.5, varbessel2(n, n * 0.5));
  }
  getch();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
L2:
  pxor   %xmm0,%xmm0
  mov    %ebx,%edi
  cvtsi2sd %ebx,%xmm0
  mulsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  mov    %r12d,%esi
  call   <varbessel2@plt>
  mov    %ebx,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L2
  xor    %eax,%eax
  call   <getch@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: f64

tool: D2: 
varbessel2(%d,%4.2f)=%e

tool: D8: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\nvarbessel2(%d,%4.2f)=%e", n, n * 0.5, varbessel2(n, n * 0.5));
  }
  getch();
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x4d,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L53
L58:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jbe    L31
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl -0x9(%rbp),%edx
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L47
L31:
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
L47:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jne    L49
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  add    %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L66
L49:
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
L66:
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L53:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L58
  movzbl -0x9(%rbp),%eax
  lea    0x4f(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[local1] = state[0UL] + state[local1];
        state[local1] += state[local1];
      }
      if (state[0UL] == local1) {
        state[0UL] += state[local1];
        state[0UL] += state[0UL];
      } else {
        state[0UL] -= state[local1];
        state[local1] += state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] + 78796879UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x4d,%eax
  movzbl 0x1(%rdi),%r8d
  test   %r8b,%r8b
  je     L6
  mov    $0x0,%edx
  mov    $0x0,%edi
L17:
  lea    0x0(,%rax,4),%ecx
  cmp    %al,%dl
  cmova  %edi,%ecx
  lea    0x0(,%rcx,4),%eax
  cmp    %dl,%cl
  cmovne %edi,%eax
  add    $0x1,%edx
  cmp    %r8b,%dl
  jne    L17
L6:
  add    $0x4f,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[local1] = state[0UL] + state[local1];
        state[local1] += state[local1];
      }
      if (state[0UL] == local1) {
        state[0UL] += state[local1];
        state[0UL] += state[0UL];
      } else {
        state[0UL] -= state[local1];
        state[local1] += state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] + 78796879UL;
  }
}
```