user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bullCowCalculator>:
  endbr64
  movslq %edi,%r8
  mov    %edi,%edx
  movslq %esi,%rsi
  push   %r14
  imul   $0x66666667,%r8,%r8
  sar    $0x1f,%edx
  mov    %rsi,%rax
  push   %r13
  imul   $0x66666667,%rsi,%rsi
  push   %r12
  push   %rbp
  sar    $0x22,%r8
  push   %rbx
  sub    %edx,%r8d
  sar    $0x22,%rsi
  lea    (%r8,%r8,4),%ecx
  mov    %r8d,%edx
  add    %ecx,%ecx
  mov    %edx,%r11d
  sub    %ecx,%edi
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  mov    %edi,%r8d
  sub    %ecx,%esi
  lea    (%rsi,%rsi,4),%edi
  mov    %esi,%ecx
  add    %edi,%edi
  mov    %ecx,%ebp
  sub    %edi,%eax
  movslq %edx,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  cmp    %r8d,%esi
  sete   %al
  imul   $0x66666667,%rdi,%rdi
  sar    $0x1f,%r11d
  sar    $0x1f,%ebp
  sar    $0x22,%rdi
  mov    %edi,%r10d
  sub    %r11d,%r10d
  lea    (%r10,%r10,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%edx
  mov    %edx,%r10d
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %edx,%ebx
  sub    %ebp,%ebx
  lea    (%rbx,%rbx,4),%r9d
  mov    %ecx,%ebx
  mov    %edx,%ecx
  add    %r9d,%r9d
  sub    %r9d,%ebx
  xor    %r9d,%r9d
  cmp    %r10d,%ebx
  sete   %r9b
  sub    %r11d,%edi
  sub    %ebp,%ecx
  movslq %edi,%rdx
  mov    %edi,%r13d
  mov    %ecx,%r12d
  add    %eax,%r9d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r13d
  sar    $0x1f,%r12d
  sar    $0x22,%rdx
  mov    %edx,%ebp
  sub    %r13d,%ebp
  lea    0x0(%rbp,%rbp,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%edi
  mov    %edi,%ebp
  movslq %ecx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %edi,%r11d
  sub    %r12d,%r11d
  lea    (%r11,%r11,4),%r14d
  add    %r14d,%r14d
  sub    %r14d,%ecx
  mov    %ecx,%r11d
  xor    %ecx,%ecx
  cmp    %r11d,%ebp
  sete   %cl
  sub    %r13d,%edx
  sub    %r12d,%edi
  add    %ecx,%r9d
  movslq %edx,%rcx
  mov    %edx,%r13d
  mov    %edi,%r12d
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%r13d
  sar    $0x1f,%r12d
  sar    $0x22,%rcx
  sub    %r13d,%ecx
  lea    (%rcx,%rcx,4),%r13d
  mov    %edx,%ecx
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  add    %r13d,%r13d
  sub    %r13d,%ecx
  sar    $0x22,%rdx
  sub    %r12d,%edx
  lea    (%rdx,%rdx,4),%r12d
  mov    %edi,%edx
  xor    %edi,%edi
  add    %r12d,%r12d
  sub    %r12d,%edx
  cmp    %edx,%ecx
  sete   %dil
  add    %edi,%r9d
  xor    %edi,%edi
  cmp    %r8d,%ebx
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %r11d,%r8d
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %r8d,%edx
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %esi,%r10d
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %r10d,%ebx
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %r11d,%r10d
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %r10d,%edx
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %ebp,%esi
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %ebp,%ebx
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %r11d,%ebp
  sete   %dil
  add    %edi,%eax
  xor    %edi,%edi
  cmp    %ebp,%edx
  sete   %dil
  add    %edi,%eax
  cmp    %esi,%ecx
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%eax
  xor    %esi,%esi
  cmp    %ebx,%ecx
  pop    %rbx
  sete   %sil
  pop    %rbp
  pop    %r12
  add    %esi,%eax
  xor    %esi,%esi
  cmp    %r11d,%ecx
  pop    %r13
  sete   %sil
  pop    %r14
  add    %esi,%eax
  cmp    %edx,%ecx
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  sub    %r9d,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%r9,%rax,2),%eax
  ret
```

assistant: ```c
int bullCowCalculator(int n, int inputNumber) {
  int i, j, cow = 0, bull = 0, tester, test, nCopy = n, inputNumberCopy = inputNumber;
  for (i = 1; i <= 4; i++) {
    if (n % 10 == inputNumber % 10) {
      bull++;
    }
    n /= 10;
    inputNumber /= 10;
  }
  n = nCopy;
  inputNumber = inputNumberCopy;
  for (i = 1; i <= 4; i++) {
    tester = n % 10;
    test = inputNumber;
    for (j = 1; j <= 4; j++) {
      if (tester == test % 10)
        cow++;
      test /= 10;
    }
    n /= 10;
  }
  cow = cow - bull;
  return cow * 10 + bull;
}
```