ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x38(%rbp),%xmm0
  jbe    L6
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
L6:
  mov    -0x30(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x1c,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  movsd  0x18(%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  0x22(%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x1,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  movsd  -0x20(%rbp,%rax,8),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L3
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
L3:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
datatype: string
name: disassemble_data
arguments: tag: D8
datatype: f64
name: disassemble_data
arguments: tag: D45
datatype: string
name: disassemble_data
arguments: tag: D37
datatype: string

tool: D29: testing floats on heap


tool: D8: 4

tool: D45: testing floats on stack


tool: D37: all done


assistant: ```c
int main() {
  char *p1;
  float f;
  double d;
  double da[2];
  int i;
  printf("testing floats on heap\n");
  p1 = (char *)malloc(64);
  f = *((float *)p1);
  if (f < 0.f)
    d = 4.;
  d = *((double *)(p1 + 8));
  *((float *)(p1 + 16)) = 0.f;
  d = *((double *)(p1 + 16));
  *((float *)(p1 + 28)) = 0.f;
  d = *((double *)(p1 + 24));
  d = *((double *)(p1 + 34));
  free((void *)p1);
  printf("testing floats on stack\n");
  da[0] = 0.;
  i = 1;
  if (da[i] < 0.f)
    d = 4.;
  printf("all done\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movl   $0x0,0x10(%rax)
  movl   $0x0,0x1c(%rax)
  call   <free@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D25
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string

tool: D25: testing floats on heap


tool: D22: testing floats on stack


tool: D13: all done


assistant: ```c
int main() {
  char *p1;
  float f;
  double d;
  double da[2];
  int i;
  printf("testing floats on heap\n");
  p1 = (char *)malloc(64);
  f = *((float *)p1);
  if (f < 0.f)
    d = 4.;
  d = *((double *)(p1 + 8));
  *((float *)(p1 + 16)) = 0.f;
  d = *((double *)(p1 + 16));
  *((float *)(p1 + 28)) = 0.f;
  d = *((double *)(p1 + 24));
  d = *((double *)(p1 + 34));
  free((void *)p1);
  printf("testing floats on stack\n");
  da[0] = 0.;
  i = 1;
  if (da[i] < 0.f)
    d = 4.;
  printf("all done\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x40,%edi
  call   <malloc@plt>
  movl   $0x0,0x10(%rax)
  mov    %rax,%rdi
  movl   $0x0,0x1c(%rax)
  call   <free@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D28
type_guessed: string

tool: D0: testing floats on heap


tool: D27: testing floats on stack


tool: D28: all done


assistant: ```c
int main() {
  char *p1;
  float f;
  double d;
  double da[2];
  int i;
  printf("testing floats on heap\n");
  p1 = (char *)malloc(64);
  f = *((float *)p1);
  if (f < 0.f)
    d = 4.;
  d = *((double *)(p1 + 8));
  *((float *)(p1 + 16)) = 0.f;
  d = *((double *)(p1 + 16));
  *((float *)(p1 + 28)) = 0.f;
  d = *((double *)(p1 + 24));
  d = *((double *)(p1 + 34));
  free((void *)p1);
  printf("testing floats on stack\n");
  da[0] = 0.;
  i = 1;
  if (da[i] < 0.f)
    d = 4.;
  printf("all done\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x40,%edi
  call   <malloc@plt>
  movl   $0x0,0x10(%rax)
  mov    %rax,%rdi
  movl   $0x0,0x1c(%rax)
  call   <free@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D12
datatype: string

tool: D27: testing floats on heap


tool: D24: testing floats on stack


tool: D12: all done


assistant: ```c
int main() {
  char *p1;
  float f;
  double d;
  double da[2];
  int i;
  printf("testing floats on heap\n");
  p1 = (char *)malloc(64);
  f = *((float *)p1);
  if (f < 0.f)
    d = 4.;
  d = *((double *)(p1 + 8));
  *((float *)(p1 + 16)) = 0.f;
  d = *((double *)(p1 + 16));
  *((float *)(p1 + 28)) = 0.f;
  d = *((double *)(p1 + 24));
  d = *((double *)(p1 + 34));
  free((void *)p1);
  printf("testing floats on stack\n");
  da[0] = 0.;
  i = 1;
  if (da[i] < 0.f)
    d = 4.;
  printf("all done\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<addsz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D32(%rip),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__builtin_add_overflow@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L7
  mov    D28(%rip),%rax
  mov    (%rax),%edx
  mov    D32(%rip),%rax
  mov    %edx,(%rax)
L7:
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  leave
  ret
```

assistant: ```c
int addsz(size_t a, size_t b, size_t *r) {
  errno = 0;
  if (__builtin_expect(!!(__builtin_add_overflow(a, b, r)), 1))
    errno = ERANGE;
  return -errno;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<addsz>:
  endbr64
  sub    $0x8,%rsp
  mov    D27(%rip),%rax
  movl   $0x0,(%rax)
  call   <__builtin_add_overflow@plt>
  test   %eax,%eax
  setne  %dil
  movzbl %dil,%edi
  mov    $0x1,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L3
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  mov    %edx,(%rax)
L3:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int addsz(size_t a, size_t b, size_t *r) {
  errno = 0;
  if (__builtin_expect(!!(__builtin_add_overflow(a, b, r)), 1))
    errno = ERANGE;
  return -errno;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addsz>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
  movl   $0x0,(%rbx)
  call   <__builtin_add_overflow@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  test   %eax,%eax
  setne  %dil
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L1
  mov    (%rbx),%eax
  pop    %rbx
  neg    %eax
  ret
  nopl   0x0(%rax)
L1:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  neg    %eax
  pop    %rbx
  ret
```

assistant: ```c
int addsz(size_t a, size_t b, size_t *r) {
  errno = 0;
  if (__builtin_expect(!!(__builtin_add_overflow(a, b, r)), 1))
    errno = ERANGE;
  return -errno;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<addsz>:
  endbr64
  push   %rbx
  mov    D16(%rip),%rbx
  movl   $0x0,(%rbx)
  call   <__builtin_add_overflow@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  test   %eax,%eax
  setne  %dil
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L2
  mov    (%rbx),%eax
  pop    %rbx
  neg    %eax
  ret
  nopl   0x0(%rax)
L2:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  neg    %eax
  pop    %rbx
  ret
```

assistant: ```c
int addsz(size_t a, size_t b, size_t *r) {
  errno = 0;
  if (__builtin_expect(!!(__builtin_add_overflow(a, b, r)), 1))
    errno = ERANGE;
  return -errno;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x0,-0x50(%rbp)
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L31:
  cmp    %rdx,%rsp
  je     L59
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L31
L59:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L2
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L2:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L17
L46:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L17:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L46
  movl   $0x0,-0x54(%rbp)
  jmp    L49
L79:
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,-0x50(%rbp)
  addl   $0x1,-0x54(%rbp)
L49:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L79
  mov    -0x50(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D27
type: string
name: extract_symbolic_data
arguments: label: D14
type: string

tool: D24: %d


tool: D27: %d	

tool: D14: %d

assistant: ```c
int main() {
  int n, arr_i, j, sum = 0;
  scanf("%d\n", &n);
  int arr[n];
  for (int arr_i = 0; arr_i < n; arr_i++) {
    scanf("%d\t", &arr[arr_i]);
  }
  for (j = 0; j < n; j++) {
    sum = sum + arr[j];
  }
  printf("%d", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L39:
  cmp    %rcx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L39
L21:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L65
  orq    $0x0,-0x8(%rsp,%rax,1)
L65:
  mov    %rsp,%r15
  test   %edx,%edx
  jle    L58
  mov    %r15,%rbx
  mov    %r15,%r13
  mov    $0x0,%r12d
  lea    D15(%rip),%r14
L76:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    -0x3c(%rbp),%eax
  add    $0x4,%r13
  cmp    %r12d,%eax
  jg     L76
  test   %eax,%eax
  jle    L88
  mov    %eax,%eax
  lea    (%r15,%rax,4),%rax
  mov    $0x0,%esi
L66:
  add    (%rbx),%esi
  add    $0x4,%rbx
  cmp    %rax,%rbx
  jne    L66
L17:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L58:
  mov    $0x0,%esi
  jmp    L17
L88:
  mov    $0x0,%esi
  jmp    L17
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D29: %d


tool: D15: %d	

tool: D3: %d

assistant: ```c
int main() {
  int n, arr_i, j, sum = 0;
  scanf("%d\n", &n);
  int arr[n];
  for (int arr_i = 0; arr_i < n; arr_i++) {
    scanf("%d\t", &arr[arr_i]);
  }
  for (j = 0; j < n; j++) {
    sum = sum + arr[j];
  }
  printf("%d", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L61
L42:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L42
L61:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L72
L45:
  mov    %rsp,%r15
  test   %ecx,%ecx
  jle    L89
  mov    %r15,%rbx
  mov    %r15,%r13
  lea    D13(%rip),%r14
  xor    %r12d,%r12d
  nopl   (%rax)
L20:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  cmp    %r12d,%eax
  jg     L20
  test   %eax,%eax
  jle    L89
  lea    (%r15,%rax,4),%rax
  xor    %esi,%esi
  nopl   (%rax)
L38:
  add    (%rbx),%esi
  add    $0x4,%rbx
  cmp    %rax,%rbx
  jne    L38
L86:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L72:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L45
L89:
  xor    %esi,%esi
  jmp    L86
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D4: %d


tool: D13: %d	

tool: D9: %d

assistant: ```c
int main() {
  int n, arr_i, j, sum = 0;
  scanf("%d\n", &n);
  int arr[n];
  for (int arr_i = 0; arr_i < n; arr_i++) {
    scanf("%d\t", &arr[arr_i]);
  }
  for (j = 0; j < n; j++) {
    sum = sum + arr[j];
  }
  printf("%d", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L16
L99:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L99
L16:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L48
L113:
  mov    %rsp,%r13
  test   %ecx,%ecx
  jle    L68
  mov    %r13,%r15
  mov    %r13,%r12
  lea    D0(%rip),%r14
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L127:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L127
  test   %eax,%eax
  jle    L68
  lea    -0x1(%rax),%edx
  cmp    $0x2,%edx
  jbe    L56
  mov    %eax,%edx
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %r13,%rdx
  nopl   (%rax)
L49:
  movdqu (%r15),%xmm2
  add    $0x10,%r15
  paddd  %xmm2,%xmm0
  cmp    %rdx,%r15
  jne    L49
  movdqa %xmm0,%xmm1
  mov    %eax,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  test   $0x3,%al
  je     L36
L141:
  movslq %edx,%rcx
  lea    0x1(%rdx),%edi
  lea    0x0(%r13,%rcx,4),%rcx
  add    (%rcx),%esi
  cmp    %edi,%eax
  jle    L36
  add    $0x2,%edx
  add    0x4(%rcx),%esi
  cmp    %edx,%eax
  jle    L36
  add    0x8(%rcx),%esi
L36:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L48:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L113
L68:
  xor    %esi,%esi
  jmp    L36
L56:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L141
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D21
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string

tool: D21: %d


tool: D0: %d	

tool: D5: %d

assistant: ```c
int main() {
  int n, arr_i, j, sum = 0;
  scanf("%d\n", &n);
  int arr[n];
  for (int arr_i = 0; arr_i < n; arr_i++) {
    scanf("%d\t", &arr[arr_i]);
  }
  for (j = 0; j < n; j++) {
    sum = sum + arr[j];
  }
  printf("%d", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cJSON_Version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%r8d
  mov    $0x4,%ecx
  mov    $0x1,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D11(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
data_type: string

tool: D25: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 4, 7);
  return version;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cJSON_Version>:
  endbr64
  push   %rbx
  mov    $0x7,%r8d
  mov    $0x4,%ecx
  mov    $0x1,%edx
  lea    D3(%rip),%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string

tool: D3: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 4, 7);
  return version;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cJSON_Version>:
  endbr64
  push   %r12
  mov    $0x7,%r8d
  mov    $0x4,%ecx
  lea    D5(%rip),%r12
  mov    %r12,%rdi
  mov    $0x1,%edx
  lea    D16(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string

tool: D16: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 4, 7);
  return version;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cJSON_Version>:
  endbr64
  push   %r12
  mov    $0x7,%r8d
  mov    $0x4,%ecx
  lea    D4(%rip),%r12
  mov    %r12,%rdi
  mov    $0x1,%edx
  lea    D16(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type_guessed: string

tool: D16: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 4, 7);
  return version;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <LLL_Algorithm@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  LLL_Algorithm();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <LLL_Algorithm@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  LLL_Algorithm();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <LLL_Algorithm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  LLL_Algorithm();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <LLL_Algorithm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  LLL_Algorithm();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L1
  movl   $0x1,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubbleSort@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int main() {
  int array_size = __VERIFIER_nondet_int();
  if (array_size < 1) {
    array_size = 1;
  }
  int *numbers = (int *)alloca(array_size * sizeof(int));
  bubbleSort(numbers, array_size);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  mov    $0x1,%edx
  cmovg  %eax,%edx
  mov    %edx,%ebx
  lea    0x0(,%rdx,4),%edi
  call   <alloca@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <bubbleSort@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array_size = __VERIFIER_nondet_int();
  if (array_size < 1) {
    array_size = 1;
  }
  int *numbers = (int *)alloca(array_size * sizeof(int));
  bubbleSort(numbers, array_size);
  return 0;
}
```