ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_rfc2409_prime_768>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    $0x60,%esi
  lea    D6(%rip),%rdi
  call   <BN_bin2bn@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
BIGNUM *get_rfc2409_prime_768(BIGNUM *bn) {
  static const unsigned char RFC2409_PRIME_768[] = {
      0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xC9, 0x0F, 0xDA, 0xA2, 0x21, 0x68, 0xC2, 0x34, 0xC4, 0xC6, 0x62, 0x8B, 0x80, 0xDC, 0x1C, 0xD1, 0x29, 0x02, 0x4E, 0x08, 0x8A, 0x67, 0xCC, 0x74, 0x02, 0x0B, 0xBE, 0xA6, 0x3B, 0x13, 0x9B, 0x22, 0x51, 0x4A, 0x08, 0x79, 0x8E, 0x34, 0x04, 0xDD, 0xEF, 0x95, 0x19, 0xB3, 0xCD, 0x3A, 0x43, 0x1B, 0x30, 0x2B, 0x0A, 0x6D, 0xF2, 0x5F, 0x14, 0x37, 0x4F, 0xE1, 0x35, 0x6D, 0x6D, 0x51, 0xC2, 0x45, 0xE4, 0x85, 0xB5, 0x76, 0x62, 0x5E, 0x7E, 0xC6, 0xF4, 0x4C, 0x42, 0xE9, 0xA6, 0x3A, 0x36, 0x20, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  };
  return BN_bin2bn(RFC2409_PRIME_768, sizeof(RFC2409_PRIME_768), bn);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_rfc2409_prime_768>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x60,%esi
  lea    D9(%rip),%rdi
  jmp    1050 <BN_bin2bn@plt>
```

assistant: ```c
BIGNUM *get_rfc2409_prime_768(BIGNUM *bn) {
  static const unsigned char RFC2409_PRIME_768[] = {
      0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xC9, 0x0F, 0xDA, 0xA2, 0x21, 0x68, 0xC2, 0x34, 0xC4, 0xC6, 0x62, 0x8B, 0x80, 0xDC, 0x1C, 0xD1, 0x29, 0x02, 0x4E, 0x08, 0x8A, 0x67, 0xCC, 0x74, 0x02, 0x0B, 0xBE, 0xA6, 0x3B, 0x13, 0x9B, 0x22, 0x51, 0x4A, 0x08, 0x79, 0x8E, 0x34, 0x04, 0xDD, 0xEF, 0x95, 0x19, 0xB3, 0xCD, 0x3A, 0x43, 0x1B, 0x30, 0x2B, 0x0A, 0x6D, 0xF2, 0x5F, 0x14, 0x37, 0x4F, 0xE1, 0x35, 0x6D, 0x6D, 0x51, 0xC2, 0x45, 0xE4, 0x85, 0xB5, 0x76, 0x62, 0x5E, 0x7E, 0xC6, 0xF4, 0x4C, 0x42, 0xE9, 0xA6, 0x3A, 0x36, 0x20, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  };
  return BN_bin2bn(RFC2409_PRIME_768, sizeof(RFC2409_PRIME_768), bn);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_rfc2409_prime_768>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x60,%esi
  lea    D7(%rip),%rdi
  jmp    1050 <BN_bin2bn@plt>
```

assistant: ```c
BIGNUM *get_rfc2409_prime_768(BIGNUM *bn) {
  static const unsigned char RFC2409_PRIME_768[] = {
      0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xC9, 0x0F, 0xDA, 0xA2, 0x21, 0x68, 0xC2, 0x34, 0xC4, 0xC6, 0x62, 0x8B, 0x80, 0xDC, 0x1C, 0xD1, 0x29, 0x02, 0x4E, 0x08, 0x8A, 0x67, 0xCC, 0x74, 0x02, 0x0B, 0xBE, 0xA6, 0x3B, 0x13, 0x9B, 0x22, 0x51, 0x4A, 0x08, 0x79, 0x8E, 0x34, 0x04, 0xDD, 0xEF, 0x95, 0x19, 0xB3, 0xCD, 0x3A, 0x43, 0x1B, 0x30, 0x2B, 0x0A, 0x6D, 0xF2, 0x5F, 0x14, 0x37, 0x4F, 0xE1, 0x35, 0x6D, 0x6D, 0x51, 0xC2, 0x45, 0xE4, 0x85, 0xB5, 0x76, 0x62, 0x5E, 0x7E, 0xC6, 0xF4, 0x4C, 0x42, 0xE9, 0xA6, 0x3A, 0x36, 0x20, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
  };
  return BN_bin2bn(RFC2409_PRIME_768, sizeof(RFC2409_PRIME_768), bn);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<IntWallStyle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,8),%rdx
  lea    D3(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *IntWallStyle(const int i) {
  static const char *wallStyles[] = {"steel", "brick", "carbon", "steelwood", "stone", "plasteel", "granite"};
  return wallStyles[abs(i) % 7];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<IntWallStyle>:
  endbr64
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  lea    D9(%rip),%rax
  mov    (%rax,%rdx,8),%rax
  ret
```

assistant: ```c
const char *IntWallStyle(const int i) {
  static const char *wallStyles[] = {"steel", "brick", "carbon", "steelwood", "stone", "plasteel", "granite"};
  return wallStyles[abs(i) % 7];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IntWallStyle>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  mov    %eax,%ecx
  mov    %eax,%edx
  imul   $0x24924925,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %ecx,%edx
  shr    %edx
  add    %ecx,%edx
  shr    $0x2,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  lea    D4(%rip),%rdx
  sub    %ecx,%eax
  cltq
  mov    (%rdx,%rax,8),%rax
  ret
```

assistant: ```c
const char *IntWallStyle(const int i) {
  static const char *wallStyles[] = {"steel", "brick", "carbon", "steelwood", "stone", "plasteel", "granite"};
  return wallStyles[abs(i) % 7];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IntWallStyle>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  mov    %eax,%ecx
  mov    %eax,%edx
  imul   $0x24924925,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %ecx,%edx
  shr    %edx
  add    %ecx,%edx
  shr    $0x2,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  lea    D4(%rip),%rdx
  sub    %ecx,%eax
  cltq
  mov    (%rdx,%rax,8),%rax
  ret
```

assistant: ```c
const char *IntWallStyle(const int i) {
  static const char *wallStyles[] = {"steel", "brick", "carbon", "steelwood", "stone", "plasteel", "granite"};
  return wallStyles[abs(i) % 7];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<constructor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <noexecve_enabled@plt>
  test   %rax,%rax
  je     L2
  mov    $0x0,%eax
  call   <disable_execve@plt>
L2:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((constructor)) constructor(void) {
  if (noexecve_enabled()) {
    disable_execve();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<constructor>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <noexecve_enabled@plt>
  test   %rax,%rax
  jne    L0
L12:
  add    $0x8,%rsp
  ret
L0:
  mov    $0x0,%eax
  call   <disable_execve@plt>
  jmp    L12
```

assistant: ```c
void __attribute__((constructor)) constructor(void) {
  if (noexecve_enabled()) {
    disable_execve();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<constructor>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <noexecve_enabled@plt>
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  ret
L6:
  xor    %eax,%eax
  pop    %rdx
  jmp    1070 <disable_execve@plt>
```

assistant: ```c
void __attribute__((constructor)) constructor(void) {
  if (noexecve_enabled()) {
    disable_execve();
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<constructor>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <noexecve_enabled@plt>
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  ret
L9:
  xor    %eax,%eax
  pop    %rdx
  jmp    1070 <disable_execve@plt>
```

assistant: ```c
void __attribute__((constructor)) constructor(void) {
  if (noexecve_enabled()) {
    disable_execve();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<acc_kernels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void acc_kernels() {
  int i, j, k;
#pragma acc kernels num_gangs(i)
  ;
#pragma acc kernels num_workers(j)
  ;
#pragma acc kernels vector_length(k)
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<acc_kernels>:
  endbr64
  ret
```

assistant: ```c
void acc_kernels() {
  int i, j, k;
#pragma acc kernels num_gangs(i)
  ;
#pragma acc kernels num_workers(j)
  ;
#pragma acc kernels vector_length(k)
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<acc_kernels>:
  endbr64
  ret
```

assistant: ```c
void acc_kernels() {
  int i, j, k;
#pragma acc kernels num_gangs(i)
  ;
#pragma acc kernels num_workers(j)
  ;
#pragma acc kernels vector_length(k)
  ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<acc_kernels>:
  endbr64
  ret
```

assistant: ```c
void acc_kernels() {
  int i, j, k;
#pragma acc kernels num_gangs(i)
  ;
#pragma acc kernels num_workers(j)
  ;
#pragma acc kernels vector_length(k)
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<emit_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  jmp    L23
L1:
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x40,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <emit_copy_less_than64@plt>
  mov    %rax,-0x8(%rbp)
  subl   $0x40,-0x10(%rbp)
L23:
  cmpl   $0x43,-0x10(%rbp)
  jg     L1
  cmpl   $0x40,-0x10(%rbp)
  jle    L6
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x3c,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <emit_copy_less_than64@plt>
  mov    %rax,-0x8(%rbp)
  subl   $0x3c,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <emit_copy_less_than64@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *emit_copy(char *op, int offset, int len) {
  while (len >= 68) {
    op = emit_copy_less_than64(op, offset, 64);
    len -= 64;
  }
  if (len > 64) {
    op = emit_copy_less_than64(op, offset, 60);
    len -= 60;
  }
  op = emit_copy_less_than64(op, offset, len);
  return op;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emit_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  cmp    $0x43,%edx
  jle    L31
  mov    %edx,%ebx
L14:
  mov    $0x40,%edx
  mov    %ebp,%esi
  call   <emit_copy_less_than64@plt>
  mov    %rax,%rdi
  sub    $0x40,%ebx
  cmp    $0x43,%ebx
  jg     L14
  lea    -0x44(%r12),%eax
  and    $0xffffffc0,%eax
  neg    %eax
  lea    -0x40(%r12,%rax,1),%r12d
L31:
  cmp    $0x40,%r12d
  jg     L23
L9:
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <emit_copy_less_than64@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0x3c,%edx
  mov    %ebp,%esi
  call   <emit_copy_less_than64@plt>
  mov    %rax,%rdi
  sub    $0x3c,%r12d
  jmp    L9
```

assistant: ```c
char *emit_copy(char *op, int offset, int len) {
  while (len >= 68) {
    op = emit_copy_less_than64(op, offset, 64);
    len -= 64;
  }
  if (len > 64) {
    op = emit_copy_less_than64(op, offset, 60);
    len -= 60;
  }
  op = emit_copy_less_than64(op, offset, len);
  return op;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emit_copy>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x43,%edx
  jle    L5
  mov    %edx,%ebx
  nopl   0x0(%rax)
L18:
  mov    $0x40,%edx
  mov    %ebp,%esi
  sub    $0x40,%ebx
  call   <emit_copy_less_than64@plt>
  mov    %rax,%rdi
  cmp    $0x43,%ebx
  jg     L18
  lea    -0x44(%r12),%eax
  and    $0xffffffc0,%eax
  neg    %eax
  lea    -0x40(%r12,%rax,1),%r12d
L5:
  cmp    $0x40,%r12d
  jg     L27
  pop    %rbx
  mov    %r12d,%edx
  mov    %ebp,%esi
  pop    %rbp
  pop    %r12
  jmp    1050 <emit_copy_less_than64@plt>
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %ebp,%esi
  mov    $0x3c,%edx
  sub    $0x3c,%r12d
  call   <emit_copy_less_than64@plt>
  pop    %rbx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <emit_copy_less_than64@plt>
```

assistant: ```c
char *emit_copy(char *op, int offset, int len) {
  while (len >= 68) {
    op = emit_copy_less_than64(op, offset, 64);
    len -= 64;
  }
  if (len > 64) {
    op = emit_copy_less_than64(op, offset, 60);
    len -= 60;
  }
  op = emit_copy_less_than64(op, offset, len);
  return op;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emit_copy>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x43,%edx
  jle    L14
  mov    %edx,%ebx
  nopl   0x0(%rax)
L29:
  mov    $0x40,%edx
  mov    %ebp,%esi
  sub    $0x40,%ebx
  call   <emit_copy_less_than64@plt>
  mov    %rax,%rdi
  cmp    $0x43,%ebx
  jg     L29
  lea    -0x44(%r12),%eax
  and    $0xffffffc0,%eax
  neg    %eax
  lea    -0x40(%r12,%rax,1),%r12d
L14:
  cmp    $0x40,%r12d
  jg     L25
  pop    %rbx
  mov    %r12d,%edx
  mov    %ebp,%esi
  pop    %rbp
  pop    %r12
  jmp    1050 <emit_copy_less_than64@plt>
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %ebp,%esi
  mov    $0x3c,%edx
  sub    $0x3c,%r12d
  call   <emit_copy_less_than64@plt>
  pop    %rbx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <emit_copy_less_than64@plt>
```

assistant: ```c
char *emit_copy(char *op, int offset, int len) {
  while (len >= 68) {
    op = emit_copy_less_than64(op, offset, 64);
    len -= 64;
  }
  if (len > 64) {
    op = emit_copy_less_than64(op, offset, 60);
    len -= 60;
  }
  op = emit_copy_less_than64(op, offset, len);
  return op;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_gtg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <is_g@plt>
  test   %rax,%rax
  je     L17
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <is_t@plt>
  test   %rax,%rax
  je     L17
  mov    -0xc(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <is_g@plt>
  test   %rax,%rax
  jne    L14
L17:
  mov    $0x0,%eax
  jmp    L33
L14:
  mov    $0x1,%eax
L33:
  leave
  ret
```

assistant: ```c
int is_gtg(unsigned char *seq, int n) {
  if (is_g(seq, n) == 0 || is_t(seq, n + 1) == 0 || is_g(seq, n + 2) == 0)
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_gtg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <is_g@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L8
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <is_t@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L0
  lea    0x2(%rbx),%esi
  mov    %rbp,%rdi
  call   <is_g@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L0
```

assistant: ```c
int is_gtg(unsigned char *seq, int n) {
  if (is_g(seq, n) == 0 || is_t(seq, n + 1) == 0 || is_g(seq, n + 2) == 0)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_gtg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <is_g@plt>
  test   %rax,%rax
  jne    L8
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <is_t@plt>
  test   %rax,%rax
  je     L12
  lea    0x2(%rbx),%esi
  mov    %rbp,%rdi
  call   <is_g@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_gtg(unsigned char *seq, int n) {
  if (is_g(seq, n) == 0 || is_t(seq, n + 1) == 0 || is_g(seq, n + 2) == 0)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_gtg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <is_g@plt>
  test   %rax,%rax
  jne    L4
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <is_t@plt>
  test   %rax,%rax
  je     L13
  lea    0x2(%rbx),%esi
  mov    %rbp,%rdi
  call   <is_g@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_gtg(unsigned char *seq, int n) {
  if (is_g(seq, n) == 0 || is_t(seq, n + 1) == 0 || is_g(seq, n + 2) == 0)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L12
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L12:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L22:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <encrypt@plt>
  mov    -0x10(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L35
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x8(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jbe    L22
L35:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: Usage: %s text_to_encrypt

assistant: ```c
int main(int argc, char *argv[]) {
  uint8_t *buf;
  uint32_t buflen, i;
  FILE *f;
  if (argc != 2) {
    printf("Usage: %s text_to_encrypt", argv[0]);
    exit(1);
  }
  buflen = strlen(argv[1]);
  buf = (uint8_t *)malloc(buflen);
  memcpy(buf, argv[1], buflen);
  for (i = 0; i < buflen && i + 2 * (sizeof(uint16_t)) <= buflen; i += sizeof(uint32_t)) {
    encrypt((uint16_t *)&buf[i]);
  }
  write(1, buf, buflen);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jne    L52
L41:
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x8(%rbx),%rsi
  mov    %ebp,%edx
  mov    %rax,%rdi
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L38
  movslq %ebp,%r13
  cmp    $0x7,%r13
  jbe    L38
  mov    $0x0,%ebx
  mov    $0x0,%eax
L44:
  lea    (%r12,%rax,4),%rdi
  call   <encrypt@plt>
  add    $0x4,%ebx
  cmp    %ebp,%ebx
  jge    L38
  movslq %ebx,%rax
  lea    0x8(%rax),%rdx
  cmp    %r13,%rdx
  jbe    L44
L38:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L41
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: Usage: %s text_to_encrypt

assistant: ```c
int main(int argc, char *argv[]) {
  uint8_t *buf;
  uint32_t buflen, i;
  FILE *f;
  if (argc != 2) {
    printf("Usage: %s text_to_encrypt", argv[0]);
    exit(1);
  }
  buflen = strlen(argv[1]);
  buf = (uint8_t *)malloc(buflen);
  memcpy(buf, argv[1], buflen);
  for (i = 0; i < buflen && i + 2 * (sizeof(uint16_t)) <= buflen; i += sizeof(uint32_t)) {
    encrypt((uint16_t *)&buf[i]);
  }
  write(1, buf, buflen);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L52
  mov    (%rsi),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L52:
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <malloc@plt>
  mov    0x8(%rbx),%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  test   %r12d,%r12d
  jle    L4
  movslq %r12d,%r13
  cmp    $0x7,%r12d
  jle    L4
  xor    %ebx,%ebx
  xor    %eax,%eax
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L42:
  movslq %ebx,%rax
  lea    0x8(%rax),%rdx
  cmp    %r13,%rdx
  ja     L4
L38:
  lea    0x0(%rbp,%rax,4),%rdi
  add    $0x4,%ebx
  call   <encrypt@plt>
  cmp    %r12d,%ebx
  jl     L42
L4:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: Usage: %s text_to_encrypt

assistant: ```c
int main(int argc, char *argv[]) {
  uint8_t *buf;
  uint32_t buflen, i;
  FILE *f;
  if (argc != 2) {
    printf("Usage: %s text_to_encrypt", argv[0]);
    exit(1);
  }
  buflen = strlen(argv[1]);
  buf = (uint8_t *)malloc(buflen);
  memcpy(buf, argv[1], buflen);
  for (i = 0; i < buflen && i + 2 * (sizeof(uint16_t)) <= buflen; i += sizeof(uint32_t)) {
    encrypt((uint16_t *)&buf[i]);
  }
  write(1, buf, buflen);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L12
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L12:
  mov    0x8(%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <malloc@plt>
  mov    0x8(%rbx),%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  test   %r12d,%r12d
  jle    L41
  movslq %r12d,%r13
  cmp    $0x7,%r12d
  jle    L41
  xor    %ebx,%ebx
  xor    %eax,%eax
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L1:
  movslq %ebx,%rax
  lea    0x8(%rax),%rdx
  cmp    %r13,%rdx
  ja     L41
L2:
  lea    0x0(%rbp,%rax,4),%rdi
  add    $0x4,%ebx
  call   <encrypt@plt>
  cmp    %ebx,%r12d
  jg     L1
L41:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: Usage: %s text_to_encrypt

assistant: ```c
int main(int argc, char *argv[]) {
  uint8_t *buf;
  uint32_t buflen, i;
  FILE *f;
  if (argc != 2) {
    printf("Usage: %s text_to_encrypt", argv[0]);
    exit(1);
  }
  buflen = strlen(argv[1]);
  buf = (uint8_t *)malloc(buflen);
  memcpy(buf, argv[1], buflen);
  for (i = 0; i < buflen && i + 2 * (sizeof(uint16_t)) <= buflen; i += sizeof(uint32_t)) {
    encrypt((uint16_t *)&buf[i]);
  }
  write(1, buf, buflen);
  return 0;
}
```