ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strreplace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,0x18(%rsp)
  mov    %rdx,0x20(%rsp)
  mov    %ecx,%r15d
  mov    $0x0,%edi
  test   %rbp,%rbp
  je     L3
  cmpq   $0x0,0x0(%rbp)
  je     L3
  test   %rsi,%rsi
  setne  %al
  test   %rdx,%rdx
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
L3:
  call   <assert@plt>
  mov    0x0(%rbp),%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    0x18(%rsp),%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rax,0x10(%rsp)
  mov    0x20(%rsp),%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rax,%rcx
  sub    %rbx,%rcx
  mov    %rcx,0x28(%rsp)
  add    %rax,%r12
  sub    %rbx,%r12
  movq   $0x0,0x8(%rsp)
  jmp    L43
L24:
  lea    0x0(%r13,%rbx,1),%rax
  mov    %rax,0x8(%rsp)
  mov    %r12,%rdx
  sub    %r13,%rdx
  sub    %rbx,%rdx
  mov    0x10(%rsp),%rcx
  lea    (%rcx,%rbx,1),%rsi
  add    0x0(%rbp),%rsi
  add    0x0(%rbp),%rax
  mov    %rax,%rdi
  call   <memmove@plt>
  add    0x0(%rbp),%rbx
  mov    %rbx,%rdi
  mov    %r13,%rdx
  mov    0x20(%rsp),%rsi
  call   <memcpy@plt>
  mov    0x0(%rbp),%rax
  movb   $0x0,(%rax,%r12,1)
  sub    $0x1,%r15d
  add    0x28(%rsp),%r12
L43:
  mov    0x0(%rbp),%r14
  mov    0x8(%rsp),%rdi
  add    %r14,%rdi
  mov    0x18(%rsp),%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
  test   %r15d,%r15d
  je     L18
  sub    %r14,%rbx
  cmp    %r13,0x10(%rsp)
  jae    L24
  lea    0x1(%r12),%rsi
  mov    %r14,%rdi
  call   <xrealloc@plt>
  mov    %rax,0x0(%rbp)
  jmp    L24
L18:
  mov    %r14,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *strreplace(char **s, const char *find, const char *replace, int n_replace) {
  char *found;
  size_t s_len, find_len, replace_len, offset;
  assert(s != NULL && *s != NULL && find != NULL && replace != NULL);
  found = NULL;
  s_len = strlen(*s);
  find_len = strlen(find);
  replace_len = strlen(replace);
  offset = 0;
  while ((found = strstr(*s + offset, find)) != NULL && n_replace-- != 0) {
    offset = found - *s;
    if (replace_len > find_len)
      *s = xrealloc(*s, s_len + replace_len - find_len + 1);
    memmove(*s + offset + replace_len, *s + offset + find_len, s_len - offset - find_len);
    memcpy(*s + offset, replace, replace_len);
    s_len += replace_len - find_len;
    *(*s + s_len) = 0;
    offset += replace_len;
  }
  return *s;
}
```
user: What is the c source code of the assembly code below?

```asm
<strreplace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rdx,0x20(%rsp)
  test   %r12,%r12
  je     L18
  cmpq   $0x0,(%r12)
  je     L18
  test   %rsi,%rsi
  setne  %al
  xor    %edi,%edi
  test   %rdx,%rdx
  setne  %dil
  and    %eax,%edi
L18:
  call   <assert@plt>
  mov    (%r12),%r14
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    0x18(%rsp),%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    0x20(%rsp),%rdi
  mov    %rax,%r15
  mov    %rax,0x8(%rsp)
  call   <strlen@plt>
  xor    %r9d,%r9d
  mov    %rax,%rcx
  add    %rax,%rbx
  mov    %rax,%rbp
  sub    %r15,%rcx
  sub    %r15,%rbx
  mov    %rcx,0x28(%rsp)
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x8(%rsp),%rax
  mov    %rbx,%rdx
  lea    0x0(%rbp,%r15,1),%r9
  sub    $0x1,%r13d
  sub    %rbp,%rdx
  lea    (%r14,%r9,1),%rdi
  mov    %r9,0x10(%rsp)
  lea    (%rax,%r15,1),%rsi
  sub    %r15,%rdx
  add    %r14,%rsi
  call   <memmove@plt>
  mov    (%r12),%rdi
  mov    0x20(%rsp),%rsi
  mov    %rbp,%rdx
  add    %r15,%rdi
  call   <memcpy@plt>
  mov    (%r12),%rax
  mov    0x10(%rsp),%r9
  movb   $0x0,(%rax,%rbx,1)
  mov    (%r12),%r14
  add    0x28(%rsp),%rbx
L35:
  mov    0x18(%rsp),%rsi
  lea    (%r14,%r9,1),%rdi
  call   <strstr@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L3
  test   %r13d,%r13d
  je     L3
  sub    %r14,%rcx
  mov    %rcx,%r15
  cmp    %rbp,0x8(%rsp)
  jae    L0
  mov    %r14,%rdi
  lea    0x1(%rbx),%rsi
  call   <xrealloc@plt>
  mov    %rax,(%r12)
  mov    %rax,%r14
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L3:
  add    $0x38,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *strreplace(char **s, const char *find, const char *replace, int n_replace) {
  char *found;
  size_t s_len, find_len, replace_len, offset;
  assert(s != NULL && *s != NULL && find != NULL && replace != NULL);
  found = NULL;
  s_len = strlen(*s);
  find_len = strlen(find);
  replace_len = strlen(replace);
  offset = 0;
  while ((found = strstr(*s + offset, find)) != NULL && n_replace-- != 0) {
    offset = found - *s;
    if (replace_len > find_len)
      *s = xrealloc(*s, s_len + replace_len - find_len + 1);
    memmove(*s + offset + replace_len, *s + offset + find_len, s_len - offset - find_len);
    memcpy(*s + offset, replace, replace_len);
    s_len += replace_len - find_len;
    *(*s + s_len) = 0;
    offset += replace_len;
  }
  return *s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RIPEMD160_Final>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    0x38(%rsi),%r12
  mov    (%rsi),%rdi
  movb   $0x80,(%r12,%rdi,1)
  add    $0x1,%rdi
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  lea    -0x8(%rdx),%eax
  cltq
  cmp    %rdi,%rax
  jb     L11
L12:
  mov    D17(%rip),%r13
  mov    0x0(%r13),%eax
  lea    -0x8(%rax),%edx
  sub    %edi,%edx
  add    %r12,%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  movslq 0x0(%r13),%rax
  lea    -0x8(%r12,%rax,1),%rax
  mov    0x8(%rbx),%edx
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  mov    %edx,0x4(%rax)
  lea    0x8(%rax),%r12
  movslq 0x0(%r13),%rax
  sub    %rax,%r12
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <ripemd160_block_data_order@plt>
  movq   $0x0,(%rbx)
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  call   <OPENSSL_cleanse@plt>
  mov    0x10(%rbx),%rax
  mov    %eax,0x0(%rbp)
  mov    0x18(%rbx),%rax
  mov    %eax,0x4(%rbp)
  mov    0x20(%rbx),%rax
  mov    %eax,0x8(%rbp)
  mov    0x28(%rbx),%rax
  mov    %eax,0xc(%rbp)
  mov    0x30(%rbx),%rax
  mov    %eax,0x10(%rbp)
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  sub    %edi,%edx
  add    %r12,%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <ripemd160_block_data_order@plt>
  mov    $0x0,%edi
  jmp    L12
```

assistant: ```c
int RIPEMD160_Final(unsigned char *md, RIPEMD160_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (RIPEMD160_CBLOCK - 8)) {
    memset(p + n, 0, RIPEMD160_CBLOCK - n);
    n = 0;
    ripemd160_block_data_order(c, p, 1);
  }
  memset(p + n, 0, RIPEMD160_CBLOCK - 8 - n);
  p += RIPEMD160_CBLOCK - 8;
  (void)(*((unsigned int *)(p)) = (c->Nl), (p) += 4, c->Nl);
  (void)(*((unsigned int *)(p)) = (c->Nh), (p) += 4, c->Nh);
  p -= RIPEMD160_CBLOCK;
  ripemd160_block_data_order(c, p, 1);
  c->num = 0;
  OPENSSL_cleanse(p, RIPEMD160_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->E;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
  } while (0);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RIPEMD160_Final>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x38(%rsi),%rbp
  mov    (%rsi),%rax
  mov    D9(%rip),%r12
  movb   $0x80,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  mov    (%r12),%edx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %eax,%esi
  lea    -0x8(%rdx),%ecx
  movslq %ecx,%rcx
  cmp    %rax,%rcx
  jb     L9
L5:
  sub    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%edx
  call   <memset@plt>
  movslq (%r12),%rax
  mov    0x8(%rbx),%edx
  mov    %rbx,%rdi
  lea    -0x8(%rbp,%rax,1),%rax
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  lea    0x8(%rax),%rbp
  mov    %edx,0x4(%rax)
  movslq (%r12),%rax
  mov    $0x1,%edx
  sub    %rax,%rbp
  mov    %rbp,%rsi
  call   <ripemd160_block_data_order@plt>
  movq   $0x0,(%rbx)
  mov    (%r12),%esi
  mov    %rbp,%rdi
  call   <OPENSSL_cleanse@plt>
  mov    0x10(%rbx),%rax
  mov    %eax,0x0(%r13)
  mov    0x18(%rbx),%rax
  mov    %eax,0x4(%r13)
  mov    0x20(%rbx),%rax
  mov    %eax,0x8(%r13)
  mov    0x28(%rbx),%rax
  mov    %eax,0xc(%r13)
  mov    0x30(%rbx),%rax
  mov    %eax,0x10(%r13)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  sub    %eax,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <ripemd160_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  jmp    L5
```

assistant: ```c
int RIPEMD160_Final(unsigned char *md, RIPEMD160_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (RIPEMD160_CBLOCK - 8)) {
    memset(p + n, 0, RIPEMD160_CBLOCK - n);
    n = 0;
    ripemd160_block_data_order(c, p, 1);
  }
  memset(p + n, 0, RIPEMD160_CBLOCK - 8 - n);
  p += RIPEMD160_CBLOCK - 8;
  (void)(*((unsigned int *)(p)) = (c->Nl), (p) += 4, c->Nl);
  (void)(*((unsigned int *)(p)) = (c->Nh), (p) += 4, c->Nh);
  p -= RIPEMD160_CBLOCK;
  ripemd160_block_data_order(c, p, 1);
  c->num = 0;
  OPENSSL_cleanse(p, RIPEMD160_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->E;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
  } while (0);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RIPEMD160_Final>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x38(%rsi),%rbp
  mov    (%rsi),%rax
  mov    D5(%rip),%r12
  movb   $0x80,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  mov    (%r12),%edx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %eax,%esi
  lea    -0x8(%rdx),%ecx
  movslq %ecx,%rcx
  cmp    %rax,%rcx
  jb     L11
L12:
  sub    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%edx
  call   <memset@plt>
  movslq (%r12),%rax
  mov    0x8(%rbx),%edx
  mov    %rbx,%rdi
  lea    -0x8(%rbp,%rax,1),%rax
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  lea    0x8(%rax),%rbp
  mov    %edx,0x4(%rax)
  movslq (%r12),%rax
  mov    $0x1,%edx
  sub    %rax,%rbp
  mov    %rbp,%rsi
  call   <ripemd160_block_data_order@plt>
  movq   $0x0,(%rbx)
  mov    (%r12),%esi
  mov    %rbp,%rdi
  call   <OPENSSL_cleanse@plt>
  movdqu 0x10(%rbx),%xmm0
  movdqu 0x20(%rbx),%xmm1
  mov    0x30(%rbx),%rax
  shufps $0x88,%xmm1,%xmm0
  movups %xmm0,0x0(%r13)
  mov    %eax,0x10(%r13)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  sub    %eax,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <ripemd160_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  jmp    L12
```

assistant: ```c
int RIPEMD160_Final(unsigned char *md, RIPEMD160_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (RIPEMD160_CBLOCK - 8)) {
    memset(p + n, 0, RIPEMD160_CBLOCK - n);
    n = 0;
    ripemd160_block_data_order(c, p, 1);
  }
  memset(p + n, 0, RIPEMD160_CBLOCK - 8 - n);
  p += RIPEMD160_CBLOCK - 8;
  (void)(*((unsigned int *)(p)) = (c->Nl), (p) += 4, c->Nl);
  (void)(*((unsigned int *)(p)) = (c->Nh), (p) += 4, c->Nh);
  p -= RIPEMD160_CBLOCK;
  ripemd160_block_data_order(c, p, 1);
  c->num = 0;
  OPENSSL_cleanse(p, RIPEMD160_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
    ll = (c)->E;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4, ll);
  } while (0);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  addl   $0x4,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int t;
  t = t + 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int t;
  t = t + 4;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int t;
  t = t + 4;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int t;
  t = t + 4;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x2,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  lea    -0x40(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <output@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <output@plt>
  lea    -0x40(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <removeDuplicates@plt>
  mov    %eax,%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <output@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <removeDuplicates@plt>
  mov    %eax,%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <output@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main() {
  int A[] = {1, 2, 3, 4};
  int B[] = {1, 2, 3, 3, 4, 5, 5};
  output(A, sizeof(A) / sizeof(int));
  output(B, sizeof(B) / sizeof(int));
  output(A, removeDuplicates(A, sizeof(A) / sizeof(int)));
  output(B, removeDuplicates(B, sizeof(B) / sizeof(int)));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x4,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  movl   $0x5,0x28(%rsp)
  mov    %rsp,%rbp
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <output@plt>
  lea    0x10(%rsp),%rbx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <output@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <removeDuplicates@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <output@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <removeDuplicates@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <output@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int A[] = {1, 2, 3, 4};
  int B[] = {1, 2, 3, 3, 4, 5, 5};
  output(A, sizeof(A) / sizeof(int));
  output(B, sizeof(B) / sizeof(int));
  output(A, removeDuplicates(A, sizeof(A) / sizeof(int)));
  output(B, removeDuplicates(B, sizeof(B) / sizeof(int)));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  movabs $0x400000003,%rdx
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%r12
  lea    0x10(%rsp),%rbp
  mov    %rdx,0x8(%rsp)
  mov    %r12,%rdi
  movl   $0x5,0x28(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x300000003,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x20(%rsp)
  call   <output@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <output@plt>
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <removeDuplicates@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <output@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <removeDuplicates@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <output@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int A[] = {1, 2, 3, 4};
  int B[] = {1, 2, 3, 3, 4, 5, 5};
  output(A, sizeof(A) / sizeof(int));
  output(B, sizeof(B) / sizeof(int));
  output(A, removeDuplicates(A, sizeof(A) / sizeof(int)));
  output(B, removeDuplicates(B, sizeof(B) / sizeof(int)));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  sub    $0x48,%rsp
  movdqa D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x10(%rsp),%rbp
  mov    D2(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D5(%rip),%xmm0
  mov    %r12,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  movl   $0x5,0x28(%rsp)
  call   <output@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <output@plt>
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <removeDuplicates@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <output@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <removeDuplicates@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <output@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D22
type_infered: byte[16]
name: disassemble_data
arguments: tag: D2
type_infered: byte[8]
name: disassemble_data
arguments: tag: D5
type_infered: byte[16]

tool: {"D22": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D2": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D5": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int A[] = {1, 2, 3, 4};
  int B[] = {1, 2, 3, 3, 4, 5, 5};
  output(A, sizeof(A) / sizeof(int));
  output(B, sizeof(B) / sizeof(int));
  output(A, removeDuplicates(A, sizeof(A) / sizeof(int)));
  output(B, removeDuplicates(B, sizeof(B) / sizeof(int)));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calc_vol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L39
  mov    -0x10(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L33
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <scale_from_percentage@plt>
  mov    %eax,-0x4(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  jmp    L16
L39:
  mov    -0x10(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L16
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <scale_from_percentage@plt>
  mov    %eax,-0x4(%rbp)
L16:
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <clamp@plt>
  leave
  ret
```

assistant: ```c
int calc_vol(int val, int old, int max_vol, unsigned int flags) {
  if (flags & 0x01) {
    if (flags & 0x02)
      val = scale_from_percentage(val, max_vol);
    val += old;
  } else if (flags & 0x02) {
    val = scale_from_percentage(val, max_vol);
  }
  return clamp(val, 0, max_vol);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_vol>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  test   $0x1,%cl
  je     L40
  mov    %esi,%ebp
  test   $0x2,%cl
  jne    L15
L32:
  add    %ebp,%edi
L49:
  mov    %ebx,%edx
  mov    $0x0,%esi
  call   <clamp@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %edx,%esi
  call   <scale_from_percentage@plt>
  mov    %eax,%edi
  jmp    L32
L40:
  test   $0x2,%cl
  je     L49
  mov    %edx,%esi
  call   <scale_from_percentage@plt>
  mov    %eax,%edi
  jmp    L49
```

assistant: ```c
int calc_vol(int val, int old, int max_vol, unsigned int flags) {
  if (flags & 0x01) {
    if (flags & 0x02)
      val = scale_from_percentage(val, max_vol);
    val += old;
  } else if (flags & 0x02) {
    val = scale_from_percentage(val, max_vol);
  }
  return clamp(val, 0, max_vol);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_vol>:
  endbr64
  push   %rbx
  mov    %ecx,%eax
  and    $0x2,%eax
  sub    $0x10,%rsp
  and    $0x1,%ecx
  je     L7
  mov    %esi,%ebx
  test   %eax,%eax
  jne    L16
L3:
  add    %ebx,%edi
L0:
  add    $0x10,%rsp
  xor    %esi,%esi
  pop    %rbx
  jmp    1070 <clamp@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  test   %eax,%eax
  je     L0
  mov    %edx,%esi
  mov    %edx,0xc(%rsp)
  call   <scale_from_percentage@plt>
  mov    0xc(%rsp),%edx
  add    $0x10,%rsp
  xor    %esi,%esi
  mov    %eax,%edi
  pop    %rbx
  jmp    1070 <clamp@plt>
  nopl   0x0(%rax)
L16:
  mov    %edx,%esi
  mov    %edx,0xc(%rsp)
  call   <scale_from_percentage@plt>
  mov    0xc(%rsp),%edx
  mov    %eax,%edi
  jmp    L3
```

assistant: ```c
int calc_vol(int val, int old, int max_vol, unsigned int flags) {
  if (flags & 0x01) {
    if (flags & 0x02)
      val = scale_from_percentage(val, max_vol);
    val += old;
  } else if (flags & 0x02) {
    val = scale_from_percentage(val, max_vol);
  }
  return clamp(val, 0, max_vol);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calc_vol>:
  endbr64
  push   %rbx
  mov    %ecx,%eax
  and    $0x2,%eax
  sub    $0x10,%rsp
  and    $0x1,%ecx
  je     L36
  mov    %esi,%ebx
  test   %eax,%eax
  jne    L16
L29:
  add    %ebx,%edi
L12:
  add    $0x10,%rsp
  xor    %esi,%esi
  pop    %rbx
  jmp    1070 <clamp@plt>
  nopw   0x0(%rax,%rax,1)
L36:
  test   %eax,%eax
  je     L12
  mov    %edx,%esi
  mov    %edx,0xc(%rsp)
  call   <scale_from_percentage@plt>
  mov    0xc(%rsp),%edx
  add    $0x10,%rsp
  xor    %esi,%esi
  mov    %eax,%edi
  pop    %rbx
  jmp    1070 <clamp@plt>
  nopl   0x0(%rax)
L16:
  mov    %edx,%esi
  mov    %edx,0xc(%rsp)
  call   <scale_from_percentage@plt>
  mov    0xc(%rsp),%edx
  mov    %eax,%edi
  jmp    L29
```

assistant: ```c
int calc_vol(int val, int old, int max_vol, unsigned int flags) {
  if (flags & 0x01) {
    if (flags & 0x02)
      val = scale_from_percentage(val, max_vol);
    val += old;
  } else if (flags & 0x02) {
    val = scale_from_percentage(val, max_vol);
  }
  return clamp(val, 0, max_vol);
}
```