ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<removeDuplicates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L43
  mov    $0x0,%eax
  jmp    L47
L43:
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L12
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L12:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x8(%rbp),%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int j = 1;
  for (int i = 1; i < numsSize; ++i)
    if (nums[i] != nums[j - 1])
      nums[j++] = nums[i];
  return j;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<removeDuplicates>:
  endbr64
  mov    $0x0,%edx
  test   %esi,%esi
  jle    L25
  cmp    $0x1,%esi
  jle    L39
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi,%rdx,4),%r8
  mov    $0x1,%edx
  jmp    L29
L50:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L25
L29:
  mov    (%rax),%esi
  movslq %edx,%rcx
  cmp    -0x4(%rdi,%rcx,4),%esi
  je     L50
  add    $0x1,%edx
  mov    %esi,(%rdi,%rcx,4)
  jmp    L50
L39:
  mov    $0x1,%edx
L25:
  mov    %edx,%eax
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int j = 1;
  for (int i = 1; i < numsSize; ++i)
    if (nums[i] != nums[j - 1])
      nums[j++] = nums[i];
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<removeDuplicates>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L21
  cmp    $0x1,%esi
  je     L7
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  mov    $0x1,%r8d
  lea    0x8(%rdi,%rdx,4),%rsi
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %r8d,%rdx
  mov    (%rax),%ecx
  cmp    -0x4(%rdi,%rdx,4),%ecx
  je     L4
  mov    %ecx,(%rdi,%rdx,4)
  add    $0x1,%r8d
L4:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L1
L21:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%r8d
  jmp    L21
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int j = 1;
  for (int i = 1; i < numsSize; ++i)
    if (nums[i] != nums[j - 1])
      nums[j++] = nums[i];
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<removeDuplicates>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L13
  cmp    $0x1,%esi
  je     L20
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  mov    $0x1,%r8d
  lea    0x8(%rdi,%rdx,4),%rsi
  nopw   0x0(%rax,%rax,1)
L19:
  movslq %r8d,%rdx
  mov    (%rax),%ecx
  cmp    -0x4(%rdi,%rdx,4),%ecx
  je     L15
  mov    %ecx,(%rdi,%rdx,4)
  add    $0x1,%r8d
L15:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L19
L13:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%r8d
  jmp    L13
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int j = 1;
  for (int i = 1; i < numsSize; ++i)
    if (nums[i] != nums[j - 1])
      nums[j++] = nums[i];
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Lcd_Draw_Vine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L5:
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Lcd_Draw_Pixel@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void Lcd_Draw_Vine(int col, int row1, int row2, int color) {
  int i;
  for (i = row1; i <= row2; i++)
    Lcd_Draw_Pixel(i, col, color);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Lcd_Draw_Vine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%r12d
  cmp    %edx,%esi
  jg     L4
L11:
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <Lcd_Draw_Pixel@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L11
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void Lcd_Draw_Vine(int col, int row1, int row2, int color) {
  int i;
  for (i = row1; i <= row2; i++)
    Lcd_Draw_Pixel(i, col, color);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Lcd_Draw_Vine>:
  endbr64
  cmp    %edx,%esi
  jg     L9
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  mov    %ebx,%edi
  mov    %r12d,%edx
  mov    %r13d,%esi
  add    $0x1,%ebx
  call   <Lcd_Draw_Pixel@plt>
  cmp    %ebx,%ebp
  jge    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L9:
  ret
```

assistant: ```c
void Lcd_Draw_Vine(int col, int row1, int row2, int color) {
  int i;
  for (i = row1; i <= row2; i++)
    Lcd_Draw_Pixel(i, col, color);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Lcd_Draw_Vine>:
  endbr64
  cmp    %edx,%esi
  jg     L13
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    %ebx,%edi
  mov    %r12d,%edx
  mov    %r13d,%esi
  add    $0x1,%ebx
  call   <Lcd_Draw_Pixel@plt>
  cmp    %ebx,%ebp
  jge    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L13:
  ret
```

assistant: ```c
void Lcd_Draw_Vine(int col, int row1, int row2, int color) {
  int i;
  for (i = row1; i <= row2; i++)
    Lcd_Draw_Pixel(i, col, color);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<invert_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xa4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xb0(%rbp),%rax
  mov    %rax,-0x98(%rbp)
  movl   $0x1f,-0xa0(%rbp)
  jmp    L44
L31:
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdx
  mov    -0xa0(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <getb@plt>
  mov    %eax,-0x9c(%rbp)
  cmpl   $0x0,-0x9c(%rbp)
  jne    L5
  mov    -0x98(%rbp),%rax
  mov    %rax,%rcx
  mov    -0xa0(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <setb@plt>
  jmp    L2
L5:
  mov    -0x98(%rbp),%rax
  mov    %rax,%rcx
  mov    -0xa0(%rbp),%eax
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <setb@plt>
L2:
  subl   $0x1,-0xa0(%rbp)
L44:
  cmpl   $0x0,-0xa0(%rbp)
  jns    L31
  cmpq   $0x0,-0xb8(%rbp)
  je     L53
  mov    -0x98(%rbp),%rax
  mov    %rax,%rcx
  mov    -0xb8(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <bcopy@plt>
L53:
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x98(%rbp),%rax
  mov    %rax,%rsi
  lea    -0x90(%rbp),%rdx
  mov    -0xa4(%rbp),%eax
  mov    %eax,%edi
  call   <inet_ntop@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
char *invert_mask(int af, void *addr, void *conv) {
  char buf[128];
  int i, bit;
  union {
    struct in6_addr *in6;
    struct in_addr *in;
  } adu;
  bzero(&buf[0], sizeof(buf));
  assert(af == PF_INET);
  adu.in = (struct in_addr *)addr;
  for (i = 32 - 1; i >= 0; i--) {
    bit = getb((u_char *)&adu.in->s_addr, i);
    if (bit == 0)
      setb((u_char *)&adu.in->s_addr, i, 1);
    else
      setb((u_char *)&adu.in->s_addr, i, 0);
  }
  if (conv != NULL)
    (void)bcopy(&adu.in->s_addr, conv, sizeof(adu.in->s_addr));
  inet_ntop(af, &adu.in->s_addr, &buf[0], INET_ADDRSTRLEN);
  return (strdup(&buf[0]));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<invert_mask>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x80,%esi
  call   <bzero@plt>
  mov    D14(%rip),%rax
  cmp    %r12d,(%rax)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1f,%ebx
  jmp    L5
L28:
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <setb@plt>
L34:
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L44
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <getb@plt>
  test   %eax,%eax
  jne    L28
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <setb@plt>
  jmp    L34
L44:
  test   %r13,%r13
  je     L32
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <bcopy@plt>
L32:
  mov    %rsp,%rbx
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <inet_ntop@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *invert_mask(int af, void *addr, void *conv) {
  char buf[128];
  int i, bit;
  union {
    struct in6_addr *in6;
    struct in_addr *in;
  } adu;
  bzero(&buf[0], sizeof(buf));
  assert(af == PF_INET);
  adu.in = (struct in_addr *)addr;
  for (i = 32 - 1; i >= 0; i--) {
    bit = getb((u_char *)&adu.in->s_addr, i);
    if (bit == 0)
      setb((u_char *)&adu.in->s_addr, i, 1);
    else
      setb((u_char *)&adu.in->s_addr, i, 0);
  }
  if (conv != NULL)
    (void)bcopy(&adu.in->s_addr, conv, sizeof(adu.in->s_addr));
  inet_ntop(af, &adu.in->s_addr, &buf[0], INET_ADDRSTRLEN);
  return (strdup(&buf[0]));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<invert_mask>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x80,%esi
  push   %rbx
  mov    $0x1f,%ebx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <bzero@plt>
  mov    D19(%rip),%rax
  xor    %edi,%edi
  cmp    %r12d,(%rax)
  sete   %dil
  call   <assert@plt>
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <setb@plt>
  sub    $0x1,%ebx
  jb     L5
L57:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <getb@plt>
  test   %eax,%eax
  je     L2
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <setb@plt>
  sub    $0x1,%ebx
  jae    L57
L5:
  test   %r13,%r13
  je     L30
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <bcopy@plt>
L30:
  mov    D2(%rip),%rax
  mov    %r14,%rdx
  mov    %r12d,%edi
  mov    %rbp,%rsi
  mov    (%rax),%ecx
  call   <inet_ntop@plt>
  mov    %r14,%rdi
  call   <strdup@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *invert_mask(int af, void *addr, void *conv) {
  char buf[128];
  int i, bit;
  union {
    struct in6_addr *in6;
    struct in_addr *in;
  } adu;
  bzero(&buf[0], sizeof(buf));
  assert(af == PF_INET);
  adu.in = (struct in_addr *)addr;
  for (i = 32 - 1; i >= 0; i--) {
    bit = getb((u_char *)&adu.in->s_addr, i);
    if (bit == 0)
      setb((u_char *)&adu.in->s_addr, i, 1);
    else
      setb((u_char *)&adu.in->s_addr, i, 0);
  }
  if (conv != NULL)
    (void)bcopy(&adu.in->s_addr, conv, sizeof(adu.in->s_addr));
  inet_ntop(af, &adu.in->s_addr, &buf[0], INET_ADDRSTRLEN);
  return (strdup(&buf[0]));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<invert_mask>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x80,%esi
  push   %rbx
  mov    $0x1f,%ebx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <bzero@plt>
  mov    D11(%rip),%rax
  xor    %edi,%edi
  cmp    %r12d,(%rax)
  sete   %dil
  call   <assert@plt>
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <setb@plt>
  sub    $0x1,%ebx
  jb     L16
L43:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <getb@plt>
  test   %eax,%eax
  je     L28
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <setb@plt>
  sub    $0x1,%ebx
  jae    L43
L16:
  test   %r13,%r13
  je     L20
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <bcopy@plt>
L20:
  mov    D3(%rip),%rax
  mov    %r14,%rdx
  mov    %r12d,%edi
  mov    %rbp,%rsi
  mov    (%rax),%ecx
  call   <inet_ntop@plt>
  mov    %r14,%rdi
  call   <strdup@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *invert_mask(int af, void *addr, void *conv) {
  char buf[128];
  int i, bit;
  union {
    struct in6_addr *in6;
    struct in_addr *in;
  } adu;
  bzero(&buf[0], sizeof(buf));
  assert(af == PF_INET);
  adu.in = (struct in_addr *)addr;
  for (i = 32 - 1; i >= 0; i--) {
    bit = getb((u_char *)&adu.in->s_addr, i);
    if (bit == 0)
      setb((u_char *)&adu.in->s_addr, i, 1);
    else
      setb((u_char *)&adu.in->s_addr, i, 0);
  }
  if (conv != NULL)
    (void)bcopy(&adu.in->s_addr, conv, sizeof(adu.in->s_addr));
  inet_ntop(af, &adu.in->s_addr, &buf[0], INET_ADDRSTRLEN);
  return (strdup(&buf[0]));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cJSON_Version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xc,%r8d
  mov    $0x7,%ecx
  mov    $0x1,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D28(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 7, 12);
  return version;
}
```
user: What is the c source code of the assembly code below:

```asm
<cJSON_Version>:
  endbr64
  push   %rbx
  mov    $0xc,%r8d
  mov    $0x7,%ecx
  mov    $0x1,%edx
  lea    D19(%rip),%rsi
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D19
type_guessed: string

tool: D19: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 7, 12);
  return version;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cJSON_Version>:
  endbr64
  push   %r12
  mov    $0xc,%r8d
  mov    $0x7,%ecx
  lea    D0(%rip),%r12
  mov    %r12,%rdi
  mov    $0x1,%edx
  lea    D18(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_infered: string

tool: D18: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 7, 12);
  return version;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cJSON_Version>:
  endbr64
  push   %r12
  mov    $0xc,%r8d
  mov    $0x7,%ecx
  lea    D14(%rip),%r12
  mov    %r12,%rdi
  mov    $0x1,%edx
  lea    D13(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_infered: string

tool: D13: %i.%i.%i

assistant: ```c
const char *cJSON_Version(void) {
  static char version[15];
  sprintf(version, "%i.%i.%i", 1, 7, 12);
  return version;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%esi
  mov    $0x7,%edi
  call   <binom@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
datatype: string

tool: D6: %lu


assistant: ```c
int main(void) {
  printf("%lu\n", binom(7, 3));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x7,%edi
  call   <binom@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string

tool: D8: %lu


assistant: ```c
int main(void) {
  printf("%lu\n", binom(7, 3));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x7,%edi
  call   <binom@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: %lu


assistant: ```c
int main(void) {
  printf("%lu\n", binom(7, 3));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x7,%edi
  call   <binom@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string

tool: D6: %lu


assistant: ```c
int main(void) {
  printf("%lu\n", binom(7, 3));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findMinValueWithFrequency>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    $0x194,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L59:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L5:
  cmpl   $0x64,-0x14(%rbp)
  jle    L59
  movl   $0x0,-0x10(%rbp)
  jmp    L51
L66:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L51:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L66
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L77:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jne    L15
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L65
L15:
  addl   $0x1,-0xc(%rbp)
L3:
  cmpl   $0x64,-0xc(%rbp)
  jle    L77
L65:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int findMinValueWithFrequency(int *array, int arraySize, int frequency) {
  int *numbers = malloc(sizeof(int) * (100 + 1));
  int foundValue = -1;
  for (int i = 0; i <= 100; i++) {
    numbers[i] = 0;
  }
  for (int i = 0; i < arraySize; i++) {
    numbers[array[i]]++;
  }
  for (int i = 0; i <= 100; i++) {
    if (numbers[i] == frequency) {
      foundValue = i;
      break;
    }
  }
  free(numbers);
  return foundValue;
}
```
user: What is the c source code of the assembly code below:

```asm
<findMinValueWithFrequency>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    $0x194,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rdx
  lea    0x194(%rax),%rcx
L21:
  movl   $0x0,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L21
  test   %ebp,%ebp
  jle    L2
  mov    %r12,%rax
  lea    -0x1(%rbp),%edx
  lea    0x4(%r12,%rdx,4),%rcx
L6:
  movslq (%rax),%rdx
  addl   $0x1,(%rdi,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L6
L2:
  mov    $0x0,%edx
L22:
  mov    %edx,%ebp
  cmp    %ebx,(%rdi,%rdx,4)
  je     L12
  add    $0x1,%rdx
  cmp    $0x65,%rdx
  jne    L22
  mov    $0xffffffff,%ebp
L12:
  call   <free@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int findMinValueWithFrequency(int *array, int arraySize, int frequency) {
  int *numbers = malloc(sizeof(int) * (100 + 1));
  int foundValue = -1;
  for (int i = 0; i <= 100; i++) {
    numbers[i] = 0;
  }
  for (int i = 0; i < arraySize; i++) {
    numbers[array[i]]++;
  }
  for (int i = 0; i <= 100; i++) {
    if (numbers[i] == frequency) {
      foundValue = i;
      break;
    }
  }
  free(numbers);
  return foundValue;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<findMinValueWithFrequency>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x194,%edi
  call   <malloc@plt>
  lea    0x8(%rax),%rdi
  mov    %rax,%rcx
  movq   $0x0,(%rax)
  mov    %rax,%r8
  movq   $0x0,0x18c(%rax)
  and    $0xfffffffffffffff8,%rdi
  xor    %eax,%eax
  sub    %rdi,%rcx
  add    $0x194,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  test   %r12d,%r12d
  jle    L10
  lea    -0x1(%r12),%edx
  mov    %rbx,%rax
  lea    0x4(%rbx,%rdx,4),%rcx
  nopl   (%rax)
L37:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,(%r8,%rdx,4)
  cmp    %rcx,%rax
  jne    L37
L10:
  xor    %eax,%eax
  jmp    L19
  nopl   (%rax)
L17:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L28
L19:
  mov    %eax,%r12d
  cmp    %ebp,(%r8,%rax,4)
  jne    L17
  mov    %r8,%rdi
  call   <free@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    $0xffffffff,%r12d
  mov    %r8,%rdi
  call   <free@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int findMinValueWithFrequency(int *array, int arraySize, int frequency) {
  int *numbers = malloc(sizeof(int) * (100 + 1));
  int foundValue = -1;
  for (int i = 0; i <= 100; i++) {
    numbers[i] = 0;
  }
  for (int i = 0; i < arraySize; i++) {
    numbers[array[i]]++;
  }
  for (int i = 0; i <= 100; i++) {
    if (numbers[i] == frequency) {
      foundValue = i;
      break;
    }
  }
  free(numbers);
  return foundValue;
}
```