ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <uart_init@plt>
  xor    %eax,%eax
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    $0x3,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <is_external_clock_avail@plt>
  test   %eax,%eax
  je     L20
L25:
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  lea    D0(%rip),%rbp
  call   <printf@plt>
  xor    %eax,%eax
  call   <jtag_init@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <led_init@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <usb_init@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <cdc_init@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <np_init@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
L5:
  xor    %eax,%eax
  call   <np_handler@plt>
  jmp    L5
L20:
  lea    D55(%rip),%rdi
  call   <puts@plt>
  jmp    L25
```

tool_calls: name: read_data
arguments: label: D31
type_infered: string
name: read_data
arguments: label: D57
type_infered: string
name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D23
type_infered: string
name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D40
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D55
type_infered: string

tool: D31: 
NAND programmer ver: %d.%d.%d


tool: D57: JTAG init...

tool: D0: done.

tool: D23: LED init...

tool: D12: USB init...

tool: D40: CDC init...

tool: D25: Programmer init...

tool: D55: External clock not detected. Fallback to internal clock.

assistant: ```c
int main() {
  uart_init();
  printf("\r\nNAND programmer ver: %d.%d.%d\r\n", 3, 4, 1);
  if (!is_external_clock_avail())
    printf("External clock not detected. Fallback to internal clock.\r\n");
  printf("JTAG init...");
  jtag_init();
  printf("done.\r\n");
  printf("LED init...");
  led_init();
  printf("done.\r\n");
  printf("USB init...");
  usb_init();
  printf("done.\r\n");
  printf("CDC init...");
  cdc_init();
  printf("done.\r\n");
  printf("Programmer init...");
  np_init();
  printf("done.\r\n");
  while (1)
    np_handler();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<five_f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  D1(%rip),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: f64

tool: D1: 1

assistant: ```c
double five_f2(int a, int b, int c) {
  double ab, ac, bc, cb;
  ab = probability(a, b);
  ac = probability(a, c);
  bc = probability(b, c);
  cb = 1.0 - bc;
  return (2 * (ab * ac) + bc * ab + cb * ac);
}
```
user: Translate the below assembly code into C programming language:

```asm
<five_f2>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebx
  mov    %edx,%ebp
  call   <probability@plt>
  movq   %xmm0,%r14
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <probability@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <probability@plt>
  movapd %xmm0,%xmm2
  movq   %r14,%xmm3
  movq   %r14,%xmm1
  movsd  0x8(%rsp),%xmm4
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm1
  movsd  D7(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: f64

tool: D7: 1

assistant: ```c
double five_f2(int a, int b, int c) {
  double ab, ac, bc, cb;
  ab = probability(a, b);
  ac = probability(a, c);
  bc = probability(b, c);
  cb = 1.0 - bc;
  return (2 * (ab * ac) + bc * ab + cb * ac);
}
```
user: What is the c source code of the assembly code below?

```asm
<five_f2>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x10,%rsp
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %r13d,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  movsd  %xmm0,(%rsp)
  call   <probability@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm3
  movapd %xmm0,%xmm4
  movapd %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm2
  movsd  D2(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  subsd  %xmm4,%xmm0
  pop    %r13
  addsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: f64

tool: D2: 1

assistant: ```c
double five_f2(int a, int b, int c) {
  double ab, ac, bc, cb;
  ab = probability(a, b);
  ac = probability(a, c);
  bc = probability(b, c);
  cb = 1.0 - bc;
  return (2 * (ab * ac) + bc * ab + cb * ac);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<five_f2>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x10,%rsp
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %r13d,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  movsd  %xmm0,(%rsp)
  call   <probability@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm3
  movapd %xmm0,%xmm4
  movapd %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm2
  movsd  D5(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  subsd  %xmm4,%xmm0
  pop    %r13
  addsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: f64

tool: D5: 1

assistant: ```c
double five_f2(int a, int b, int c) {
  double ab, ac, bc, cb;
  ab = probability(a, b);
  ac = probability(a, c);
  bc = probability(b, c);
  cb = 1.0 - bc;
  return (2 * (ab * ac) + bc * ab + cb * ac);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D9: %s


assistant: ```c
int main() {
  char *s = NULL;
  printf("%s\n", NULL);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %s


assistant: ```c
int main() {
  char *s = NULL;
  printf("%s\n", NULL);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: %s


assistant: ```c
int main() {
  char *s = NULL;
  printf("%s\n", NULL);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: %s


assistant: ```c
int main() {
  char *s = NULL;
  printf("%s\n", NULL);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scan3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,0x18(%rsp)
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r13d
  test   %rdx,%rdx
  je     L123
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
L123:
  movl   $0x0,0x14(%rsp)
  test   %r14,%r14
  je     L148
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,0x14(%rsp)
L148:
  lea    0x20(%rsp),%r15
L63:
  mov    %r12,%rdx
  mov    $0x190,%esi
  mov    %r15,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L135
  lea    0x20(%rsp),%rbx
L90:
  add    $0x1,%rbx
  cmpb   $0x3a,-0x1(%rbx)
  jne    L90
  mov    %rbx,%rdi
  call   <atol@plt>
  mov    %rax,0x8(%rsp)
L48:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  cmpb   $0x3a,-0x1(%rbx)
  jne    L48
  test   %ebp,%ebp
  jle    L75
  add    $0x3,%rdi
  call   <atoi@plt>
  cmp    %ebp,%eax
  jne    L63
L75:
  add    $0x1,%rbx
  cmpb   $0x3a,-0x1(%rbx)
  jne    L75
  test   %r13d,%r13d
  jle    L18
  mov    %r13d,%edx
  mov    0x18(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L63
L18:
  add    $0x1,%rbx
  cmpb   $0x3a,-0x1(%rbx)
  jne    L18
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L129
  mov    %eax,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L63
L129:
  add    $0x1,%rbx
  cmpb   $0x3a,-0x1(%rbx)
  jne    L129
L126:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    0x8(%rsp),%rax
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L135:
  movq   $0xffffffffffffffff,0x8(%rsp)
  jmp    L126
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long int scan3(FILE *input, int date, char *variable, char *level) {
  long int pos;
  char line[400], *pntr;
  int n_var, n_lev;
  n_var = variable != NULL ? strlen(variable) : 0;
  n_lev = level != NULL ? strlen(level) : 0;
  for (;;) {
    if (fgets(line, sizeof(line), input) == NULL)
      return -1;
    pntr = line;
    while (*pntr++ != ':')
      ;
    pos = atol(pntr);
    while (*pntr++ != ':')
      ;
    if (date > 0 && date != atoi(pntr + 2))
      continue;
    while (*pntr++ != ':')
      ;
    if (n_var > 0 && strncmp(pntr, variable, n_var) != 0)
      continue;
    while (*pntr++ != ':')
      ;
    if (n_lev > 0 && strncmp(pntr, level, n_lev) != 0)
      continue;
    while (*pntr++ != ':')
      ;
    return pos;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<scan3>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1c8,%rsp
  mov    %rdx,0x18(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L133
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
L133:
  mov    0x8(%rsp),%rax
  movl   $0x0,0x14(%rsp)
  test   %rax,%rax
  je     L93
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,0x14(%rsp)
L93:
  lea    0x20(%rsp),%rbp
L137:
  mov    %r13,%rdx
  mov    $0x190,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L142
  mov    %rbp,%r15
  nopl   0x0(%rax)
L62:
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L62
  mov    %r15,%rdi
  call   <atol@plt>
  mov    %rax,%r12
  cs nopw 0x0(%rax,%rax,1)
L73:
  mov    %r15,%rdi
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L73
  test   %ebx,%ebx
  jle    L125
  add    $0x3,%rdi
  call   <atoi@plt>
  cmp    %ebx,%eax
  jne    L137
  nop
L125:
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L125
  test   %r14d,%r14d
  jle    L116
  mov    0x18(%rsp),%rsi
  mov    %r14d,%edx
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L137
  nopl   0x0(%rax)
L116:
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L116
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L14
  mov    0x8(%rsp),%rsi
  mov    %eax,%edx
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L137
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L14
L107:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x1c8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L142:
  mov    $0xffffffffffffffff,%r12
  jmp    L107
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long int scan3(FILE *input, int date, char *variable, char *level) {
  long int pos;
  char line[400], *pntr;
  int n_var, n_lev;
  n_var = variable != NULL ? strlen(variable) : 0;
  n_lev = level != NULL ? strlen(level) : 0;
  for (;;) {
    if (fgets(line, sizeof(line), input) == NULL)
      return -1;
    pntr = line;
    while (*pntr++ != ':')
      ;
    pos = atol(pntr);
    while (*pntr++ != ':')
      ;
    if (date > 0 && date != atoi(pntr + 2))
      continue;
    while (*pntr++ != ':')
      ;
    if (n_var > 0 && strncmp(pntr, variable, n_var) != 0)
      continue;
    while (*pntr++ != ':')
      ;
    if (n_lev > 0 && strncmp(pntr, level, n_lev) != 0)
      continue;
    while (*pntr++ != ':')
      ;
    return pos;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<scan3>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1c8,%rsp
  mov    %rdx,0x18(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L43
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
L43:
  mov    0x8(%rsp),%rax
  movl   $0x0,0x14(%rsp)
  test   %rax,%rax
  je     L97
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,0x14(%rsp)
L97:
  lea    0x20(%rsp),%rbp
L42:
  mov    %r13,%rdx
  mov    $0x190,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L4
  mov    %rbp,%r15
  nopl   0x0(%rax)
L128:
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L128
  mov    %r15,%rdi
  call   <atol@plt>
  mov    %rax,%r12
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %r15,%rdi
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L3
  test   %ebx,%ebx
  jle    L27
  add    $0x3,%rdi
  call   <atoi@plt>
  cmp    %ebx,%eax
  jne    L42
  nop
L27:
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L27
  test   %r14d,%r14d
  jle    L75
  mov    0x18(%rsp),%rsi
  mov    %r14d,%edx
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L42
  nopl   0x0(%rax)
L75:
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L75
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L101
  mov    0x8(%rsp),%rsi
  mov    %eax,%edx
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L42
  nopl   0x0(%rax,%rax,1)
L101:
  add    $0x1,%r15
  cmpb   $0x3a,-0x1(%r15)
  jne    L101
L99:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  add    $0x1c8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    $0xffffffffffffffff,%r12
  jmp    L99
L81:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long int scan3(FILE *input, int date, char *variable, char *level) {
  long int pos;
  char line[400], *pntr;
  int n_var, n_lev;
  n_var = variable != NULL ? strlen(variable) : 0;
  n_lev = level != NULL ? strlen(level) : 0;
  for (;;) {
    if (fgets(line, sizeof(line), input) == NULL)
      return -1;
    pntr = line;
    while (*pntr++ != ':')
      ;
    pos = atol(pntr);
    while (*pntr++ != ':')
      ;
    if (date > 0 && date != atoi(pntr + 2))
      continue;
    while (*pntr++ != ':')
      ;
    if (n_var > 0 && strncmp(pntr, variable, n_var) != 0)
      continue;
    while (*pntr++ != ':')
      ;
    if (n_lev > 0 && strncmp(pntr, level, n_lev) != 0)
      continue;
    while (*pntr++ != ':')
      ;
    return pos;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<expand_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    D15(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_array_length@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L9
  lea    D15(%rip),%rax
  leave
  ret
```

assistant: ```c
char *expand_array(char array[]) {
  static char new_array[sizeof(array) / sizeof(char) * 2];
  for (int i = 0; i < get_array_length(array); ++i) {
    new_array[i] = array[i];
  }
  return new_array;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<expand_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
  jmp    L10
L2:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L10:
  mov    %rbp,%rdi
  call   <get_array_length@plt>
  cmp    %ebx,%eax
  jg     L2
  lea    D5(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *expand_array(char array[]) {
  static char new_array[sizeof(array) / sizeof(char) * 2];
  for (int i = 0; i < get_array_length(array); ++i) {
    new_array[i] = array[i];
  }
  return new_array;
}
```
user: What is the c source code of the assembly code below:

```asm
<expand_array>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L17:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L7:
  mov    %rbp,%rdi
  call   <get_array_length@plt>
  cmp    %ebx,%eax
  jg     L17
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *expand_array(char array[]) {
  static char new_array[sizeof(array) / sizeof(char) * 2];
  for (int i = 0; i < get_array_length(array); ++i) {
    new_array[i] = array[i];
  }
  return new_array;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<expand_array>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L17:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L4:
  mov    %rbp,%rdi
  call   <get_array_length@plt>
  cmp    %ebx,%eax
  jg     L17
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *expand_array(char array[]) {
  static char new_array[sizeof(array) / sizeof(char) * 2];
  for (int i = 0; i < get_array_length(array); ++i) {
    new_array[i] = array[i];
  }
  return new_array;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_inf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7f800000,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  lea    -0xc(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
float ft_inf(int p) {
  int inf;
  inf = 0x7F800000;
  return (p * *(float *)&inf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_inf>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  mulss  D0(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: byte[4]

tool: {"D0": [0x00,0x00,0x80,0x7f]}

assistant: ```c
float ft_inf(int p) {
  int inf;
  inf = 0x7F800000;
  return (p * *(float *)&inf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_inf>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  mulss  D6(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x7f]}

assistant: ```c
float ft_inf(int p) {
  int inf;
  inf = 0x7F800000;
  return (p * *(float *)&inf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_inf>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  mulss  D4(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x7f]}

assistant: ```c
float ft_inf(int p) {
  int inf;
  inf = 0x7F800000;
  return (p * *(float *)&inf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sortv_imatrix_selection_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  jmp    L41
L49:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x50(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L37
L29:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x50(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L9
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L9:
  addl   $0x1,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L29
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L41:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jg     L49
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sortv_imatrix_selection_min(int **m, long nrl, long nrh, long ncl, long nch, long nc) {
  int i, j;
  int x, min, pos;
  int *ptr;
  for (i = nrl; i < nrh; i++) {
    min = m[i][nc];
    pos = i;
    for (j = i + 1; j <= nrh; j++) {
      x = m[j][nc];
      if (x < min) {
        min = x;
        pos = j;
      }
    }
    ptr = m[i];
    m[i] = m[pos];
    m[pos] = ptr;
  }
}
```