ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<two_sum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8,(%rsp)
  mov    %r9,0x8(%rsp)
  cmp    %edx,%esi
  jge    L60
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r15d
  mov    %ecx,%eax
  neg    %eax
  mov    %eax,0x14(%rsp)
  jmp    L92
L24:
  jle    L69
  sub    $0x1,%r12d
L106:
  cmp    %r12d,%ebp
  jge    L60
L92:
  movslq %ebp,%rax
  lea    (%rbx,%rax,4),%r14
  movslq %r12d,%rax
  lea    (%rbx,%rax,4),%r13
  mov    0x0(%r13),%eax
  add    (%r14),%eax
  cmp    %r15d,%eax
  jge    L24
  add    $0x1,%ebp
  jmp    L106
L69:
  mov    0x8(%rsp),%rcx
  movslq (%rcx),%rax
  mov    (%rsp),%rsi
  lea    (%rsi,%rax,8),%rax
  mov    %rax,0x18(%rsp)
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    0x18(%rsp),%rdi
  mov    %rax,(%rdi)
  mov    0x8(%rsp),%rcx
  movslq (%rcx),%rax
  mov    (%rsp),%rsi
  mov    (%rsi,%rax,8),%rax
  mov    0x14(%rsp),%edi
  mov    %edi,(%rax)
  movslq (%rcx),%rax
  mov    (%rsi,%rax,8),%rax
  mov    (%r14),%edx
  mov    %edx,0x4(%rax)
  movslq (%rcx),%rax
  mov    (%rsi,%rax,8),%rax
  mov    0x0(%r13),%edx
  mov    %edx,0x8(%rax)
  addl   $0x1,(%rcx)
  lea    0x1(%rbp),%eax
  cltq
L81:
  mov    %eax,%ebp
  cmp    %eax,%r12d
  jle    L52
  mov    (%rbx,%rax,4),%edx
  add    $0x1,%rax
  cmp    -0x8(%rbx,%rax,4),%edx
  je     L81
L52:
  lea    -0x1(%r12),%eax
  cltq
L22:
  mov    %eax,%r12d
  cmp    %eax,%ebp
  jge    L60
  mov    (%rbx,%rax,4),%edx
  sub    $0x1,%rax
  cmp    0x8(%rbx,%rax,4),%edx
  je     L22
  jmp    L92
L60:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void two_sum(int *nums, int low, int high, int target, int **results, int *count) {
  while (low < high) {
    int sum = nums[low] + nums[high];
    if (sum < target) {
      low++;
    } else if (sum > target) {
      high--;
    } else {
      results[*count] = malloc(3 * sizeof(int));
      results[*count][0] = -target;
      results[*count][1] = nums[low];
      results[*count][2] = nums[high];
      (*count)++;
      while (++low < high && nums[low] == nums[low - 1]) {
      }
      while (--high > low && nums[high] == nums[high + 1]) {
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<two_sum>:
  endbr64
  cmp    %edx,%esi
  jge    L98
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  mov    %ecx,%edx
  push   %r12
  neg    %edx
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  jmp    L80
  nop
L81:
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  jle    L115
L80:
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  mov    (%rcx),%eax
  add    (%rsi),%eax
  cmp    %r14d,%eax
  jl     L81
  lea    -0x1(%r13),%ebx
  jle    L53
  mov    %ebx,%r13d
  cmp    %r12d,%r13d
  jg     L80
L115:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L53:
  movslq (%r15),%rax
  mov    $0xc,%edi
  mov    %edx,0x2c(%rsp)
  mov    %rcx,0x20(%rsp)
  lea    (%r8,%rax,8),%r9
  mov    %rsi,0x18(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r9
  mov    0x10(%rsp),%r8
  mov    0x2c(%rsp),%edx
  mov    0x18(%rsp),%rsi
  mov    %rax,(%r9)
  movslq (%r15),%rax
  mov    0x20(%rsp),%rcx
  mov    (%r8,%rax,8),%rax
  mov    %edx,(%rax)
  movslq (%r15),%rax
  mov    (%rsi),%esi
  mov    (%r8,%rax,8),%rax
  mov    %esi,0x4(%rax)
  movslq (%r15),%rax
  mov    (%rcx),%ecx
  mov    (%r8,%rax,8),%rax
  mov    %ecx,0x8(%rax)
  lea    0x1(%r12),%eax
  addl   $0x1,(%r15)
  cltq
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L60:
  mov    0x0(%rbp,%rax,4),%ecx
  add    $0x1,%rax
  cmp    -0x8(%rbp,%rax,4),%ecx
  jne    L18
L50:
  mov    %eax,%r12d
  cmp    %eax,%r13d
  jg     L60
L18:
  movslq %ebx,%rax
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L47:
  mov    0x0(%rbp,%rax,4),%ecx
  sub    $0x1,%rax
  cmp    0x8(%rbp,%rax,4),%ecx
  jne    L80
L25:
  mov    %eax,%r13d
  cmp    %eax,%r12d
  jl     L47
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L98:
  ret
```

assistant: ```c
void two_sum(int *nums, int low, int high, int target, int **results, int *count) {
  while (low < high) {
    int sum = nums[low] + nums[high];
    if (sum < target) {
      low++;
    } else if (sum > target) {
      high--;
    } else {
      results[*count] = malloc(3 * sizeof(int));
      results[*count][0] = -target;
      results[*count][1] = nums[low];
      results[*count][2] = nums[high];
      (*count)++;
      while (++low < high && nums[low] == nums[low - 1]) {
      }
      while (--high > low && nums[high] == nums[high + 1]) {
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<two_sum>:
  endbr64
  cmp    %edx,%esi
  jge    L113
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  mov    %ecx,%edx
  push   %r12
  neg    %edx
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  jmp    L4
  nop
L63:
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  jle    L70
L4:
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  mov    (%rcx),%eax
  add    (%rsi),%eax
  cmp    %r14d,%eax
  jl     L63
  lea    -0x1(%r13),%ebx
  jle    L118
  mov    %ebx,%r13d
  cmp    %r12d,%r13d
  jg     L4
L70:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L118:
  movslq (%r15),%rax
  mov    $0xc,%edi
  mov    %edx,0x2c(%rsp)
  mov    %rcx,0x20(%rsp)
  lea    (%r8,%rax,8),%r9
  mov    %rsi,0x18(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r9
  mov    0x10(%rsp),%r8
  mov    0x2c(%rsp),%edx
  mov    0x18(%rsp),%rsi
  mov    %rax,(%r9)
  movslq (%r15),%rax
  mov    0x20(%rsp),%rcx
  mov    (%r8,%rax,8),%rax
  mov    %edx,(%rax)
  movslq (%r15),%rax
  mov    (%rsi),%esi
  mov    (%r8,%rax,8),%rax
  mov    %esi,0x4(%rax)
  movslq (%r15),%rax
  mov    (%rcx),%ecx
  mov    (%r8,%rax,8),%rax
  mov    %ecx,0x8(%rax)
  lea    0x1(%r12),%eax
  addl   $0x1,(%r15)
  cltq
  jmp    L100
  nopw   0x0(%rax,%rax,1)
L75:
  mov    0x0(%rbp,%rax,4),%ecx
  add    $0x1,%rax
  cmp    -0x8(%rbp,%rax,4),%ecx
  jne    L119
L100:
  mov    %eax,%r12d
  cmp    %eax,%r13d
  jg     L75
L119:
  movslq %ebx,%rax
  jmp    L105
  nopl   0x0(%rax,%rax,1)
L68:
  mov    0x0(%rbp,%rax,4),%ecx
  sub    $0x1,%rax
  cmp    0x8(%rbp,%rax,4),%ecx
  jne    L4
L105:
  mov    %eax,%r13d
  cmp    %eax,%r12d
  jl     L68
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L113:
  ret
```

assistant: ```c
void two_sum(int *nums, int low, int high, int target, int **results, int *count) {
  while (low < high) {
    int sum = nums[low] + nums[high];
    if (sum < target) {
      low++;
    } else if (sum > target) {
      high--;
    } else {
      results[*count] = malloc(3 * sizeof(int));
      results[*count][0] = -target;
      results[*count][1] = nums[low];
      results[*count][2] = nums[high];
      (*count)++;
      while (++low < high && nums[low] == nums[low - 1]) {
      }
      while (--high > low && nums[high] == nums[high + 1]) {
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<imget_fits_float_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L7:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L13:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L15
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L15:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <imget_fits_value@plt>
  cmp    $0x1,%eax
  jne    L8
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movd   %xmm0,%eax
  mov    -0x48(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x1,%eax
  jmp    L24
L8:
  mov    -0x48(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    $0x0,%eax
L24:
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int imget_fits_float_value(struct icom *comp, char *key, float *fout) {
  char tmp[BUFSIZ];
  if (imget_fits_value(comp, key, tmp) == 1) {
    *fout = atof(tmp);
    return 1;
  } else {
    *fout = 0;
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<imget_fits_float_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L24:
  cmp    %rdx,%rsp
  je     L11
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L24
L11:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L5
  orq    $0x0,-0x8(%rsp,%rax,1)
L5:
  mov    %rsp,%r13
  mov    %rsp,%rdx
  call   <imget_fits_value@plt>
  mov    %eax,%r12d
  cmp    $0x1,%eax
  je     L40
  pxor   %xmm0,%xmm0
  mov    $0x0,%r12d
L19:
  movss  %xmm0,(%rbx)
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    %r12d,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L40:
  mov    %r13,%rdi
  call   <atof@plt>
  jmp    L19
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int imget_fits_float_value(struct icom *comp, char *key, float *fout) {
  char tmp[BUFSIZ];
  if (imget_fits_value(comp, key, tmp) == 1) {
    *fout = atof(tmp);
    return 1;
  } else {
    *fout = 0;
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<imget_fits_float_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    D8(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L14
L11:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L11
L14:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L22
L32:
  mov    %rsp,%rdx
  call   <imget_fits_value@plt>
  cmp    $0x1,%eax
  je     L0
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
L39:
  movss  %xmm0,(%rbx)
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rsp,%rdi
  mov    %eax,-0x24(%rbp)
  call   <atof@plt>
  mov    -0x24(%rbp),%eax
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L22:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L32
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int imget_fits_float_value(struct icom *comp, char *key, float *fout) {
  char tmp[BUFSIZ];
  if (imget_fits_value(comp, key, tmp) == 1) {
    *fout = atof(tmp);
    return 1;
  } else {
    *fout = 0;
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<imget_fits_float_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    D5(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L63
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L68
L63:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L22
L40:
  mov    %rsp,%rdx
  call   <imget_fits_value@plt>
  cmp    $0x1,%eax
  je     L48
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
L26:
  movss  %xmm0,(%rbx)
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %rsp,%rdi
  mov    %eax,-0x24(%rbp)
  call   <atof@plt>
  mov    -0x24(%rbp),%eax
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L22:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int imget_fits_float_value(struct icom *comp, char *key, float *fout) {
  char tmp[BUFSIZ];
  if (imget_fits_value(comp, key, tmp) == 1) {
    *fout = atof(tmp);
    return 1;
  } else {
    *fout = 0;
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<max_pid_length_base_10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <get_pid_max@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <abs@plt>
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%rax
  leave
  ret
```

assistant: ```c
size_t max_pid_length_base_10() {
  pid_t max_pid = get_pid_max();
  assert(max_pid > 0);
  return floor(log10(abs(max_pid))) + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<max_pid_length_base_10>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <get_pid_max@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <abs@plt>
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t max_pid_length_base_10() {
  pid_t max_pid = get_pid_max();
  assert(max_pid > 0);
  return floor(log10(abs(max_pid))) + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<max_pid_length_base_10>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <get_pid_max@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setg   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <abs@plt>
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  pop    %rbp
  add    $0x1,%rax
  ret
```

assistant: ```c
size_t max_pid_length_base_10() {
  pid_t max_pid = get_pid_max();
  assert(max_pid > 0);
  return floor(log10(abs(max_pid))) + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<max_pid_length_base_10>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <get_pid_max@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setg   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <abs@plt>
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  pop    %rbp
  add    $0x1,%rax
  ret
```

assistant: ```c
size_t max_pid_length_base_10() {
  pid_t max_pid = get_pid_max();
  assert(max_pid > 0);
  return floor(log10(abs(max_pid))) + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x0,-0x1e(%rbp)
  movq   $0x1,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jns    L29
  movw   $0x1,-0x1e(%rbp)
  mov    -0x18(%rbp),%eax
  neg    %eax
  mov    %eax,-0x18(%rbp)
  jmp    L64
L29:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L64
  movq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L77
L64:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L24:
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  cmpw   $0x0,-0x1e(%rbp)
  jne    L83
  mov    -0x1c(%rbp),%eax
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L83:
  mov    -0x1c(%rbp),%eax
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L31:
  addl   $0x1,-0x14(%rbp)
L22:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L24
  mov    $0x0,%eax
L77:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D54
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D29
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string

tool: D5: Please, enter a base and an exponent in the format "b^e":  

tool: D54: %d ^ %d

tool: D7: Result: %ld


tool: D29: 
%d^0:	1


tool: D12: %d^%d:	%ld


tool: D26: %d^%d:	1/%ld


assistant: ```c
int main(void) {
  int base, exp, i;
  short int negative_exponent = 0;
  unsigned long int result = 1;
  printf("Please, enter a base and an exponent in the format \"b^e\":  ");
  scanf("%d ^ %d", &base, &exp);
  if (exp < 0) {
    negative_exponent = 1;
    exp = -exp;
  } else if (exp == 0) {
    result = 1;
    printf("Result: %ld\n", result);
    return 0;
  }
  printf("\n%d^0:\t1\n", base);
  while (i <= exp) {
    result *= base;
    if (negative_exponent == 0) {
      printf("%d^%d:\t%ld\n", base, i, result);
    } else {
      printf("%d^%d:\t1/%ld\n", base, i, result);
    }
    i++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L83
  mov    $0x0,%r12d
  je     L80
L57:
  mov    (%rsp),%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  cmp    0x4(%rsp),%ebx
  jg     L26
  mov    $0x1,%ebp
  lea    D54(%rip),%r14
  lea    D44(%rip),%r13
  jmp    L87
L83:
  neg    %eax
  mov    %eax,0x4(%rsp)
  mov    $0x1,%r12d
  jmp    L57
L80:
  mov    $0x1,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  mov    %rbp,%rcx
  mov    %ebx,%edx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L70:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L26
L87:
  mov    (%rsp),%esi
  movslq %esi,%rax
  imul   %rax,%rbp
  test   %r12w,%r12w
  jne    L42
  mov    %rbp,%rcx
  mov    %ebx,%edx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L70
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type: string
name: extract_symbolic_data
arguments: label: D28
type: string
name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D54
type: string
name: extract_symbolic_data
arguments: label: D44
type: string
name: extract_symbolic_data
arguments: label: D37
type: string

tool: D22: Please, enter a base and an exponent in the format "b^e":  

tool: D28: %d ^ %d

tool: D10: 
%d^0:	1


tool: D54: %d^%d:	1/%ld


tool: D44: %d^%d:	%ld


tool: D37: Result: %ld


assistant: ```c
int main(void) {
  int base, exp, i;
  short int negative_exponent = 0;
  unsigned long int result = 1;
  printf("Please, enter a base and an exponent in the format \"b^e\":  ");
  scanf("%d ^ %d", &base, &exp);
  if (exp < 0) {
    negative_exponent = 1;
    exp = -exp;
  } else if (exp == 0) {
    result = 1;
    printf("Result: %ld\n", result);
    return 0;
  }
  printf("\n%d^0:\t1\n", base);
  while (i <= exp) {
    result *= base;
    if (negative_exponent == 0) {
      printf("%d^%d:\t%ld\n", base, i, result);
    } else {
      printf("%d^%d:\t1/%ld\n", base, i, result);
    }
    i++;
  }
  return 0;
}
```