ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<draw>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%eax
  movslq %edi,%rbp
  imul   $0x10624dd3,%rbp,%rbp
  sar    $0x26,%rbp
  cltd
  sub    %edx,%ebp
  imul   $0x3e8,%ebp,%edx
  mov    %edi,%ebp
  sub    %edx,%ebp
  movslq %ebp,%rbx
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x25,%rbx
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%ebx
  imul   $0x64,%ebx,%edx
  mov    %ebp,%ebx
  sub    %edx,%ebx
  movslq %ebx,%r12
  imul   $0x66666667,%r12,%r12
  sar    $0x22,%r12
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%r12d
  lea    (%r12,%r12,4),%edx
  add    %edx,%edx
  mov    %ebx,%r12d
  sub    %edx,%r12d
  cmp    $0x3e7,%edi
  jg     L3
L66:
  cmp    $0x63,%ebp
  jg     L63
L51:
  cmp    $0x9,%ebx
  jg     L32
L33:
  test   %r12d,%r12d
  jg     L61
L76:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  movslq %edi,%rdi
  imul   $0x10624dd3,%rdi,%rdi
  sar    $0x26,%rdi
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <drawThousands@plt>
  jmp    L66
L63:
  movslq %ebp,%rdi
  imul   $0x51eb851f,%rdi,%rdi
  sar    $0x25,%rdi
  sar    $0x1f,%ebp
  sub    %ebp,%edi
  call   <drawHundreds@plt>
  jmp    L51
L32:
  movslq %ebx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  sar    $0x1f,%ebx
  sub    %ebx,%edi
  call   <drawTens@plt>
  jmp    L33
L61:
  mov    %r12d,%edi
  call   <drawOnes@plt>
  jmp    L76
```

assistant: ```c
void draw(int v) {
  int thousands = v / 1000;
  v %= 1000;
  int hundreds = v / 100;
  v %= 100;
  int tens = v / 10;
  int ones = v % 10;
  if (thousands > 0) {
    drawThousands(thousands);
  }
  if (hundreds > 0) {
    drawHundreds(hundreds);
  }
  if (tens > 0) {
    drawTens(tens);
  }
  if (ones > 0) {
    drawOnes(ones);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<draw>:
  endbr64
  movslq %edi,%rdi
  push   %r14
  mov    %rdi,%rax
  imul   $0x10624dd3,%rdi,%rdi
  push   %r13
  mov    %eax,%ecx
  push   %r12
  sar    $0x1f,%ecx
  push   %rbp
  sar    $0x26,%rdi
  push   %rbx
  mov    %edi,%r12d
  sub    %ecx,%r12d
  imul   $0x3e8,%r12d,%edx
  mov    %eax,%r12d
  sub    %edx,%r12d
  movslq %r12d,%r14
  mov    %r12d,%edx
  imul   $0x51eb851f,%r14,%rbx
  sar    $0x1f,%edx
  sar    $0x25,%rbx
  sub    %edx,%ebx
  imul   $0x64,%ebx,%edx
  mov    %r12d,%ebx
  sub    %edx,%ebx
  movslq %ebx,%r13
  mov    %ebx,%edx
  imul   $0x66666667,%r13,%rbp
  sar    $0x1f,%edx
  sar    $0x22,%rbp
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,4),%edx
  mov    %ebx,%ebp
  add    %edx,%edx
  sub    %edx,%ebp
  cmp    $0x3e7,%eax
  jg     L52
L16:
  cmp    $0x63,%r12d
  jg     L43
L12:
  cmp    $0x9,%ebx
  jg     L10
L41:
  test   %ebp,%ebp
  jg     L53
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L53:
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <drawOnes@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  imul   $0x66666667,%r13,%rdi
  sar    $0x1f,%ebx
  sar    $0x22,%rdi
  sub    %ebx,%edi
  call   <drawTens@plt>
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L43:
  imul   $0x51eb851f,%r14,%rdi
  sar    $0x1f,%r12d
  sar    $0x25,%rdi
  sub    %r12d,%edi
  call   <drawHundreds@plt>
  jmp    L12
  nopl   0x0(%rax)
L52:
  sub    %ecx,%edi
  call   <drawThousands@plt>
  jmp    L16
```

assistant: ```c
void draw(int v) {
  int thousands = v / 1000;
  v %= 1000;
  int hundreds = v / 100;
  v %= 100;
  int tens = v / 10;
  int ones = v % 10;
  if (thousands > 0) {
    drawThousands(thousands);
  }
  if (hundreds > 0) {
    drawHundreds(hundreds);
  }
  if (tens > 0) {
    drawTens(tens);
  }
  if (ones > 0) {
    drawOnes(ones);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<draw>:
  endbr64
  movslq %edi,%rdi
  push   %r14
  mov    %rdi,%rax
  imul   $0x10624dd3,%rdi,%rdi
  push   %r13
  mov    %eax,%ecx
  push   %r12
  sar    $0x1f,%ecx
  push   %rbp
  sar    $0x26,%rdi
  push   %rbx
  mov    %edi,%r12d
  sub    %ecx,%r12d
  imul   $0x3e8,%r12d,%edx
  mov    %eax,%r12d
  sub    %edx,%r12d
  movslq %r12d,%r14
  mov    %r12d,%edx
  imul   $0x51eb851f,%r14,%rbx
  sar    $0x1f,%edx
  sar    $0x25,%rbx
  sub    %edx,%ebx
  imul   $0x64,%ebx,%edx
  mov    %r12d,%ebx
  sub    %edx,%ebx
  movslq %ebx,%r13
  mov    %ebx,%edx
  imul   $0x66666667,%r13,%rbp
  sar    $0x1f,%edx
  sar    $0x22,%rbp
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,4),%edx
  mov    %ebx,%ebp
  add    %edx,%edx
  sub    %edx,%ebp
  cmp    $0x3e7,%eax
  jg     L19
L63:
  cmp    $0x63,%r12d
  jg     L68
L50:
  cmp    $0x9,%ebx
  jg     L44
L54:
  test   %ebp,%ebp
  jg     L57
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L57:
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <drawOnes@plt>
  nopw   0x0(%rax,%rax,1)
L44:
  imul   $0x66666667,%r13,%rdi
  sar    $0x1f,%ebx
  sar    $0x22,%rdi
  sub    %ebx,%edi
  call   <drawTens@plt>
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L68:
  imul   $0x51eb851f,%r14,%rdi
  sar    $0x1f,%r12d
  sar    $0x25,%rdi
  sub    %r12d,%edi
  call   <drawHundreds@plt>
  jmp    L50
  nopl   0x0(%rax)
L19:
  sub    %ecx,%edi
  call   <drawThousands@plt>
  jmp    L63
```

assistant: ```c
void draw(int v) {
  int thousands = v / 1000;
  v %= 1000;
  int hundreds = v / 100;
  v %= 100;
  int tens = v / 10;
  int ones = v % 10;
  if (thousands > 0) {
    drawThousands(thousands);
  }
  if (hundreds > 0) {
    drawHundreds(hundreds);
  }
  if (tens > 0) {
    drawTens(tens);
  }
  if (ones > 0) {
    drawOnes(ones);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<kd_tree_split_training_patterns_via_pivot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x2,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L4
L9:
  mov    -0x20(%rbp),%eax
  imul   -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <kth_smallest@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%edi
  mov    -0x18(%rbp),%ecx
  mov    -0x34(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x10(%rbp),%rax
  movd   %edi,%xmm0
  mov    %rax,%rdi
  call   <partition_array_via_pivot@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int kd_tree_split_training_patterns_via_pivot(void *XI, int left, int right, int axis, int dim) {
  int i;
  int count = right - left;
  int size_per_elt = dim * sizeof(float) + sizeof(int);
  void *array = (void *)(XI + left * size_per_elt);
  float *tmp = (float *)malloc(count * sizeof(float));
  for (i = 0; i < count; i++) {
    tmp[i] = ((float *)(array + i * size_per_elt))[axis];
  }
  float pivot_value = kth_smallest(tmp, count, count / 2);
  free(tmp);
  partition_array_via_pivot(array, count, axis, size_per_elt, pivot_value);
  return left + count / 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kd_tree_split_training_patterns_via_pivot>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%eax
  mov    %esi,0xc(%rsp)
  mov    %ecx,%r14d
  mov    %edx,%ebx
  sub    %esi,%ebx
  lea    0x4(,%r8,4),%r15d
  imul   %r15d,%eax
  cltq
  lea    (%rdi,%rax,1),%r13
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L17
  movslq %r15d,%rsi
  movslq %r14d,%rax
  lea    0x0(%r13,%rax,4),%rdx
  mov    %r12,%rax
  mov    %ebx,%ecx
  lea    (%r12,%rcx,4),%rcx
L15:
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  add    %rsi,%rdx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L15
L17:
  mov    %ebx,%ebp
  shr    $0x1f,%ebp
  add    %ebx,%ebp
  sar    %ebp
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <kth_smallest@plt>
  movss  %xmm0,0x8(%rsp)
  mov    %r12,%rdi
  call   <free@plt>
  movss  0x8(%rsp),%xmm0
  mov    %r15d,%ecx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <partition_array_via_pivot@plt>
  mov    0xc(%rsp),%eax
  add    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int kd_tree_split_training_patterns_via_pivot(void *XI, int left, int right, int axis, int dim) {
  int i;
  int count = right - left;
  int size_per_elt = dim * sizeof(float) + sizeof(int);
  void *array = (void *)(XI + left * size_per_elt);
  float *tmp = (float *)malloc(count * sizeof(float));
  for (i = 0; i < count; i++) {
    tmp[i] = ((float *)(array + i * size_per_elt))[axis];
  }
  float pivot_value = kth_smallest(tmp, count, count / 2);
  free(tmp);
  partition_array_via_pivot(array, count, axis, size_per_elt, pivot_value);
  return left + count / 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kd_tree_split_training_patterns_via_pivot>:
  endbr64
  push   %r15
  mov    %esi,%eax
  lea    0x4(,%r8,4),%r15d
  sub    %esi,%edx
  imul   %r15d,%eax
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  cltq
  mov    %edx,%ebp
  push   %rbx
  lea    (%rdi,%rax,1),%r12
  lea    0x0(,%rdx,4),%edi
  mov    %esi,%ebx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %ebp,%ebp
  jle    L9
  movslq %r13d,%rax
  mov    %ebp,%ecx
  movslq %r15d,%rsi
  lea    (%r12,%rax,4),%rdx
  lea    (%rdi,%rcx,4),%rcx
  mov    %rdi,%rax
  nopl   (%rax)
L4:
  movss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rsi,%rdx
  movss  %xmm0,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L4
L9:
  mov    %ebp,%r14d
  mov    %ebp,%esi
  mov    %rdi,0x8(%rsp)
  shr    $0x1f,%r14d
  add    %ebp,%r14d
  sar    %r14d
  mov    %r14d,%edx
  call   <kth_smallest@plt>
  mov    0x8(%rsp),%rdi
  movss  %xmm0,0x4(%rsp)
  call   <free@plt>
  movss  0x4(%rsp),%xmm0
  mov    %r15d,%ecx
  mov    %ebp,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <partition_array_via_pivot@plt>
  add    $0x18,%rsp
  lea    (%r14,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int kd_tree_split_training_patterns_via_pivot(void *XI, int left, int right, int axis, int dim) {
  int i;
  int count = right - left;
  int size_per_elt = dim * sizeof(float) + sizeof(int);
  void *array = (void *)(XI + left * size_per_elt);
  float *tmp = (float *)malloc(count * sizeof(float));
  for (i = 0; i < count; i++) {
    tmp[i] = ((float *)(array + i * size_per_elt))[axis];
  }
  float pivot_value = kth_smallest(tmp, count, count / 2);
  free(tmp);
  partition_array_via_pivot(array, count, axis, size_per_elt, pivot_value);
  return left + count / 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kd_tree_split_training_patterns_via_pivot>:
  endbr64
  push   %r15
  mov    %esi,%eax
  lea    0x4(,%r8,4),%r15d
  sub    %esi,%edx
  imul   %r15d,%eax
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  cltq
  mov    %edx,%ebp
  push   %rbx
  lea    (%rdi,%rax,1),%r12
  lea    0x0(,%rdx,4),%edi
  mov    %esi,%ebx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %ebp,%ebp
  jle    L12
  movslq %r13d,%rax
  mov    %ebp,%ecx
  movslq %r15d,%rsi
  lea    (%r12,%rax,4),%rdx
  lea    (%rdi,%rcx,4),%rcx
  mov    %rdi,%rax
  nopl   (%rax)
L17:
  movss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rsi,%rdx
  movss  %xmm0,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L17
L12:
  mov    %ebp,%r14d
  mov    %ebp,%esi
  mov    %rdi,0x8(%rsp)
  shr    $0x1f,%r14d
  add    %ebp,%r14d
  sar    %r14d
  mov    %r14d,%edx
  call   <kth_smallest@plt>
  mov    0x8(%rsp),%rdi
  movss  %xmm0,0x4(%rsp)
  call   <free@plt>
  movss  0x4(%rsp),%xmm0
  mov    %r15d,%ecx
  mov    %ebp,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <partition_array_via_pivot@plt>
  add    $0x18,%rsp
  lea    (%r14,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int kd_tree_split_training_patterns_via_pivot(void *XI, int left, int right, int axis, int dim) {
  int i;
  int count = right - left;
  int size_per_elt = dim * sizeof(float) + sizeof(int);
  void *array = (void *)(XI + left * size_per_elt);
  float *tmp = (float *)malloc(count * sizeof(float));
  for (i = 0; i < count; i++) {
    tmp[i] = ((float *)(array + i * size_per_elt))[axis];
  }
  float pivot_value = kth_smallest(tmp, count, count / 2);
  free(tmp);
  partition_array_via_pivot(array, count, axis, size_per_elt, pivot_value);
  return left + count / 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<copy_container_to_target_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy_container_to_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(2, a, b, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_container_to_target_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x2,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copy_container_to_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(2, a, b, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_container_to_target_system>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x2,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int copy_container_to_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(2, a, b, c);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stm_array_clone_remove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movq   $0x8,-0x10(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L13
L12:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cltq
  imul   -0x10(%rbp),%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L13:
  leave
  ret
```

assistant: ```c
void **stm_array_clone_remove(void **old_array, int old_count, int index) {
  size_t ps = sizeof(void *);
  if (old_count == 1)
    return NULL;
  void **new_array = malloc(ps * (old_count - 1));
  memcpy(&new_array[0], &old_array[0], ps * index);
  memcpy(&new_array[index], &old_array[index + 1], ps * (old_count - index - 1));
  return new_array;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stm_array_clone_remove>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  je     L8
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%r14d
  lea    -0x1(%rsi),%edi
  movslq %edi,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  movslq %r14d,%rbp
  shl    $0x3,%rbp
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  sub    %r14d,%ebx
  lea    -0x1(%rbx),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  lea    0x8(%r13,%rbp,1),%rsi
  lea    (%r12,%rbp,1),%rdi
  call   <memcpy@plt>
L11:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    $0x0,%r12d
  jmp    L11
```

assistant: ```c
void **stm_array_clone_remove(void **old_array, int old_count, int index) {
  size_t ps = sizeof(void *);
  if (old_count == 1)
    return NULL;
  void **new_array = malloc(ps * (old_count - 1));
  memcpy(&new_array[0], &old_array[0], ps * index);
  memcpy(&new_array[index], &old_array[index + 1], ps * (old_count - index - 1));
  return new_array;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stm_array_clone_remove>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  je     L9
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%edi
  mov    %edx,%r13d
  mov    %esi,%ebx
  movslq %edi,%rdi
  movslq %r13d,%r12
  sub    %r13d,%ebx
  shl    $0x3,%rdi
  shl    $0x3,%r12
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%r12,1),%rsi
  movslq %edx,%rdx
  lea    (%r14,%r12,1),%rdi
  shl    $0x3,%rdx
  call   <memcpy@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void **stm_array_clone_remove(void **old_array, int old_count, int index) {
  size_t ps = sizeof(void *);
  if (old_count == 1)
    return NULL;
  void **new_array = malloc(ps * (old_count - 1));
  memcpy(&new_array[0], &old_array[0], ps * index);
  memcpy(&new_array[index], &old_array[index + 1], ps * (old_count - index - 1));
  return new_array;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stm_array_clone_remove>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  je     L3
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%edi
  mov    %edx,%r13d
  mov    %esi,%ebx
  movslq %edi,%rdi
  movslq %r13d,%r12
  sub    %r13d,%ebx
  shl    $0x3,%rdi
  shl    $0x3,%r12
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%r12,1),%rsi
  movslq %edx,%rdx
  lea    (%r14,%r12,1),%rdi
  shl    $0x3,%rdx
  call   <memcpy@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void **stm_array_clone_remove(void **old_array, int old_count, int index) {
  size_t ps = sizeof(void *);
  if (old_count == 1)
    return NULL;
  void **new_array = malloc(ps * (old_count - 1));
  memcpy(&new_array[0], &old_array[0], ps * index);
  memcpy(&new_array[index], &old_array[index + 1], ps * (old_count - index - 1));
  return new_array;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wep_keygen104>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x54(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L35
L28:
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  movl   $0x0,-0x54(%rbp)
L11:
  mov    -0x54(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x54(%rbp)
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x58(%rbp),%eax
  cltq
  mov    %dl,-0x50(%rbp,%rax,1)
  addl   $0x1,-0x58(%rbp)
L35:
  cmpl   $0x3f,-0x58(%rbp)
  jle    L28
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rdi
  call   <MD5_Init@plt>
  lea    -0x50(%rbp),%rcx
  lea    -0x5c(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <MD5_Update@plt>
  lea    -0x5c(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <MD5_Final@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L34
L25:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x58(%rbp)
L34:
  cmpl   $0xc,-0x58(%rbp)
  jle    L25
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
void wep_keygen104(const char *str, u_char *keys) {
  MD5_CTX ctx;
  u_char buf[64];
  int i, j;
  j = 0;
  for (i = 0; i < 64; i++) {
    if (str[j] == 0)
      j = 0;
    buf[i] = str[j++];
  }
  MD5_Init(&ctx);
  MD5_Update(&ctx, buf, sizeof buf);
  MD5_Final(buf, &ctx);
  for (i = 0; i < 13; i++) {
    keys[i] = buf[i];
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wep_keygen104>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x50(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0x0,%esi
L2:
  movslq %ecx,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  mov    %ecx,%eax
  cmove  %esi,%eax
  lea    0x1(%rax),%ecx
  cltq
  movzbl (%rdi,%rax,1),%eax
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L2
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <MD5_Init@plt>
  lea    0x10(%rsp),%r12
  mov    $0x40,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <MD5_Update@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <MD5_Final@plt>
  mov    $0x0,%eax
L9:
  movzbl 0x10(%rsp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0xd,%rax
  jne    L9
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wep_keygen104(const char *str, u_char *keys) {
  MD5_CTX ctx;
  u_char buf[64];
  int i, j;
  j = 0;
  for (i = 0; i < 64; i++) {
    if (str[j] == 0)
      j = 0;
    buf[i] = str[j++];
  }
  MD5_Init(&ctx);
  MD5_Update(&ctx, buf, sizeof buf);
  MD5_Final(buf, &ctx);
  for (i = 0; i < 13; i++) {
    keys[i] = buf[i];
  }
  return;
}
```