ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<equals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L15
  mov    $0x0,%eax
  jmp    L3
L15:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  mov    $0x1,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int equals(int *array1, int *array2, int size) {
  for (int i = 0; i < size; ++i) {
    if (array1[i] != array2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<equals>:
  endbr64
  test   %edx,%edx
  jle    L21
  mov    %edx,%edx
  mov    $0x0,%eax
L9:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jne    L24
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
  mov    $0x1,%eax
  ret
L21:
  mov    $0x1,%eax
  ret
L24:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int equals(int *array1, int *array2, int size) {
  for (int i = 0; i < size; ++i) {
    if (array1[i] != array2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<equals>:
  endbr64
  test   %edx,%edx
  jle    L24
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L7
  nop
L28:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L24
L7:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L28
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equals(int *array1, int *array2, int size) {
  for (int i = 0; i < size; ++i) {
    if (array1[i] != array2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<equals>:
  endbr64
  test   %edx,%edx
  jle    L38
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L28
  nop
L19:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L38
L28:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L19
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L38:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equals(int *array1, int *array2, int size) {
  for (int i = 0; i < size; ++i) {
    if (array1[i] != array2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eckey_param_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <d2i_ECParameters@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ECerror@plt>
  mov    $0x0,%eax
  jmp    L17
L6:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <EVP_PKEY_assign_EC_KEY@plt>
  mov    $0x1,%eax
L17:
  leave
  ret
```

assistant: ```c
int eckey_param_decode(EVP_PKEY *pkey, const unsigned char **pder, int derlen) {
  EC_KEY *eckey;
  if (!(eckey = d2i_ECParameters(NULL, pder, derlen))) {
    ECerror(ERR_R_EC_LIB);
    return 0;
  }
  EVP_PKEY_assign_EC_KEY(pkey, eckey);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<eckey_param_decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <d2i_ECParameters@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <EVP_PKEY_assign_EC_KEY@plt>
  mov    $0x1,%eax
L11:
  pop    %rbx
  ret
L14:
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <ECerror@plt>
  mov    $0x0,%eax
  jmp    L11
```

assistant: ```c
int eckey_param_decode(EVP_PKEY *pkey, const unsigned char **pder, int derlen) {
  EC_KEY *eckey;
  if (!(eckey = d2i_ECParameters(NULL, pder, derlen))) {
    ECerror(ERR_R_EC_LIB);
    return 0;
  }
  EVP_PKEY_assign_EC_KEY(pkey, eckey);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<eckey_param_decode>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <d2i_ECParameters@plt>
  test   %rax,%rax
  je     L7
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <EVP_PKEY_assign_EC_KEY@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <ECerror@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int eckey_param_decode(EVP_PKEY *pkey, const unsigned char **pder, int derlen) {
  EC_KEY *eckey;
  if (!(eckey = d2i_ECParameters(NULL, pder, derlen))) {
    ECerror(ERR_R_EC_LIB);
    return 0;
  }
  EVP_PKEY_assign_EC_KEY(pkey, eckey);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<eckey_param_decode>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <d2i_ECParameters@plt>
  test   %rax,%rax
  je     L5
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <EVP_PKEY_assign_EC_KEY@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <ECerror@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int eckey_param_decode(EVP_PKEY *pkey, const unsigned char **pder, int derlen) {
  EC_KEY *eckey;
  if (!(eckey = d2i_ECParameters(NULL, pder, derlen))) {
    ECerror(ERR_R_EC_LIB);
    return 0;
  }
  EVP_PKEY_assign_EC_KEY(pkey, eckey);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<swab32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0xc(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  jmp    L14
L10:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%eax
  mov    %eax,%ebx
  mov    %ebx,%edx
  shr    $0x18,%edx
  mov    %ebx,%eax
  shr    $0x8,%eax
  and    $0xff00,%eax
  or     %eax,%edx
  mov    %ebx,%eax
  shl    $0x8,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    %ebx,%eax
  shl    $0x18,%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
L14:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L10
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void swab32(int n, int *ovp, int *ivp) {
  while (n-- > 0) {
    register unsigned int v = *ivp++;
    *ovp++ = (v >> 24) & 0xFF | (v >> 8) & 0xFF00 | (v & 0xFF00) << 8 | (v & 0xFF) << 24;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swab32>:
  endbr64
  mov    %rsi,%r9
  test   %edi,%edi
  jle    L16
  mov    %edi,%edi
  mov    $0x0,%esi
L0:
  mov    (%rdx,%rsi,4),%eax
  mov    %eax,%ecx
  shr    $0x18,%ecx
  mov    %eax,%r8d
  shl    $0x18,%r8d
  or     %r8d,%ecx
  mov    %eax,%r8d
  shr    $0x8,%r8d
  and    $0xff00,%r8d
  or     %r8d,%ecx
  shl    $0x8,%eax
  and    $0xff0000,%eax
  or     %ecx,%eax
  mov    %eax,(%r9,%rsi,4)
  add    $0x1,%rsi
  cmp    %rdi,%rsi
  jne    L0
L16:
  ret
```

assistant: ```c
void swab32(int n, int *ovp, int *ivp) {
  while (n-- > 0) {
    register unsigned int v = *ivp++;
    *ovp++ = (v >> 24) & 0xFF | (v >> 8) & 0xFF00 | (v & 0xFF00) << 8 | (v & 0xFF) << 24;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swab32>:
  endbr64
  movslq %edi,%r8
  xor    %eax,%eax
  test   %edi,%edi
  jle    L2
  nopl   (%rax)
L7:
  mov    (%rdx,%rax,4),%ecx
  bswap  %ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L7
L2:
  ret
```

assistant: ```c
void swab32(int n, int *ovp, int *ivp) {
  while (n-- > 0) {
    register unsigned int v = *ivp++;
    *ovp++ = (v >> 24) & 0xFF | (v >> 8) & 0xFF00 | (v & 0xFF00) << 8 | (v & 0xFF) << 24;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swab32>:
  endbr64
  movslq %edi,%r8
  xor    %eax,%eax
  test   %edi,%edi
  jle    L15
  nopl   (%rax)
L11:
  mov    (%rdx,%rax,4),%ecx
  bswap  %ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L11
L15:
  ret
```

assistant: ```c
void swab32(int n, int *ovp, int *ivp) {
  while (n-- > 0) {
    register unsigned int v = *ivp++;
    *ovp++ = (v >> 24) & 0xFF | (v >> 8) & 0xFF00 | (v & 0xFF00) << 8 | (v & 0xFF) << 24;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uDMAChannelPriorityClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x4(%rbp),%eax
  add    $0x3c,%eax
  cltq
  mov    %rax,%rcx
  movslq %edx,%rax
  mov    %rax,(%rcx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uDMAChannelPriorityClear(uint32_t ui32Base, uint32_t ui32ChannelNum) {
  ;
  ;
  (*((volatile unsigned long *)(ui32Base + 0x0000003C))) = 1 << ui32ChannelNum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uDMAChannelPriorityClear>:
  endbr64
  add    $0x3c,%edi
  movslq %edi,%rdi
  mov    $0x1,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  cltq
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void uDMAChannelPriorityClear(uint32_t ui32Base, uint32_t ui32ChannelNum) {
  ;
  ;
  (*((volatile unsigned long *)(ui32Base + 0x0000003C))) = 1 << ui32ChannelNum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uDMAChannelPriorityClear>:
  endbr64
  mov    $0x1,%eax
  mov    %esi,%ecx
  add    $0x3c,%edi
  shl    %cl,%eax
  movslq %edi,%rdi
  cltq
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void uDMAChannelPriorityClear(uint32_t ui32Base, uint32_t ui32ChannelNum) {
  ;
  ;
  (*((volatile unsigned long *)(ui32Base + 0x0000003C))) = 1 << ui32ChannelNum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__negsf2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x80000000,%edx
  xor    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
float __negsf2(float a) {
  long lc = (*(const long *)&a) ^ 0x80000000;
  return (*(const float *)&lc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__negsf2>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mov    $0x80000000,%eax
  xor    -0x4(%rsp),%eax
  movd   %eax,%xmm0
  ret
```

assistant: ```c
float __negsf2(float a) {
  long lc = (*(const long *)&a) ^ 0x80000000;
  return (*(const float *)&lc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__negsf2>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mov    -0x4(%rsp),%edx
  mov    $0x80000000,%eax
  xor    %edx,%eax
  movd   %eax,%xmm0
  ret
```

assistant: ```c
float __negsf2(float a) {
  long lc = (*(const long *)&a) ^ 0x80000000;
  return (*(const float *)&lc);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__negsf2>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mov    -0x4(%rsp),%edx
  mov    $0x80000000,%eax
  xor    %edx,%eax
  movd   %eax,%xmm0
  ret
```

assistant: ```c
float __negsf2(float a) {
  long lc = (*(const long *)&a) ^ 0x80000000;
  return (*(const float *)&lc);
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_basic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    $0x20,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  xor    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  ja     L9
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  shr    $0x12,%eax
  imul   $0xf4240,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash_basic(unsigned int *tab) {
  unsigned int res = tab[0];
  for (int i = 1; i < tab[0]; i++) {
    res ^= (tab[i] << i) | (tab[i] >> (sizeof(int) * 8 - i));
  }
  return (res % 1000000);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_basic>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x1,%edx
  jbe    L0
  mov    %edx,%esi
  mov    $0x1,%ecx
L12:
  mov    (%rdi,%rcx,4),%eax
  rol    %cl,%eax
  xor    %eax,%edx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L12
L0:
  mov    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  imul   $0xf4240,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned int hash_basic(unsigned int *tab) {
  unsigned int res = tab[0];
  for (int i = 1; i < tab[0]; i++) {
    res ^= (tab[i] << i) | (tab[i] >> (sizeof(int) * 8 - i));
  }
  return (res % 1000000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_basic>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x1,%edx
  jbe    L14
  mov    %edx,%esi
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%rdi,%rcx,4),%eax
  rol    %cl,%eax
  add    $0x1,%rcx
  xor    %eax,%edx
  cmp    %rcx,%rsi
  jne    L16
L14:
  mov    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  imul   $0xf4240,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned int hash_basic(unsigned int *tab) {
  unsigned int res = tab[0];
  for (int i = 1; i < tab[0]; i++) {
    res ^= (tab[i] << i) | (tab[i] >> (sizeof(int) * 8 - i));
  }
  return (res % 1000000);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash_basic>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x1,%edx
  jbe    L5
  mov    %edx,%esi
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rdi,%rcx,4),%eax
  rol    %cl,%eax
  add    $0x1,%rcx
  xor    %eax,%edx
  cmp    %rcx,%rsi
  jne    L2
L5:
  mov    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x32,%rax
  imul   $0xf4240,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned int hash_basic(unsigned int *tab) {
  unsigned int res = tab[0];
  for (int i = 1; i < tab[0]; i++) {
    res ^= (tab[i] << i) | (tab[i] >> (sizeof(int) * 8 - i));
  }
  return (res % 1000000);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getOutputFilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D2: output_

assistant: ```c
char *getOutputFilename(char *fName) {
  char *outputName = "output_";
  char *newName = (char *)malloc(strlen(outputName) + strlen(fName));
  strcpy(newName, outputName);
  strcat(newName, fName);
  newName[strlen(newName)] = '\0';
  return newName;
}
```
user: What is the c source code of the assembly code below:

```asm
<getOutputFilename>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x7(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type: string

tool: D4: output_

assistant: ```c
char *getOutputFilename(char *fName) {
  char *outputName = "output_";
  char *newName = (char *)malloc(strlen(outputName) + strlen(fName));
  strcpy(newName, outputName);
  strcat(newName, fName);
  newName[strlen(newName)] = '\0';
  return newName;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getOutputFilename>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x7(%rax),%rdi
  call   <malloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: output_

assistant: ```c
char *getOutputFilename(char *fName) {
  char *outputName = "output_";
  char *newName = (char *)malloc(strlen(outputName) + strlen(fName));
  strcpy(newName, outputName);
  strcat(newName, fName);
  newName[strlen(newName)] = '\0';
  return newName;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getOutputFilename>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x7(%rax),%rdi
  call   <malloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5: output_

assistant: ```c
char *getOutputFilename(char *fName) {
  char *outputName = "output_";
  char *newName = (char *)malloc(strlen(outputName) + strlen(fName));
  strcpy(newName, outputName);
  strcat(newName, fName);
  newName[strlen(newName)] = '\0';
  return newName;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x24(%rbp)
  jg     L63
  mov    $0x1,%eax
  jmp    L62
L63:
  movq   $0x1,-0x10(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L32
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L8
L32:
  movl   $0x1,-0x18(%rbp)
  jmp    L65
L31:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L65:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L31
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L8:
  mov    $0x0,%eax
L62:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_guessed: string
name: disassemble_data
arguments: data_label: D16
type_guessed: string

tool: D19: Error!!! Factorial of negative number doesn't exist.

tool: D16: Factorial = %lu


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2)
    return 1;
  int n, count;
  unsigned long long int factorial = 1;
  time_t t;
  srand((unsigned)time(&t));
  n = (int)argv[1][0];
  if (n < 0)
    printf("Error!!! Factorial of negative number doesn't exist.\n");
  else {
    for (count = 1; count <= n; ++count) {
      factorial *= count;
    }
    printf("Factorial = %lu\n", factorial);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L13
  mov    %rsi,%rbx
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    0x8(%rbx),%rax
  movsbl (%rax),%edx
  test   %edx,%edx
  js     L30
  mov    $0x1,%eax
  mov    $0x1,%esi
  jle    L23
L46:
  imul   %rax,%rsi
  add    $0x1,%rax
  cmp    %eax,%edx
  jge    L46
L23:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  ret
L30:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L13
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D10
type: string

tool: D15: Factorial = %lu


tool: D10: Error!!! Factorial of negative number doesn't exist.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2)
    return 1;
  int n, count;
  unsigned long long int factorial = 1;
  time_t t;
  srand((unsigned)time(&t));
  n = (int)argv[1][0];
  if (n < 0)
    printf("Error!!! Factorial of negative number doesn't exist.\n");
  else {
    for (count = 1; count <= n; ++count) {
      factorial *= count;
    }
    printf("Factorial = %lu\n", factorial);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L34
  lea    0x4(%rsp),%rdi
  mov    %rsi,%rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    0x8(%rbx),%rax
  movsbl (%rax),%edx
  test   %edx,%edx
  js     L16
  mov    $0x1,%eax
  mov    $0x1,%esi
  je     L46
  nopl   0x0(%rax)
L10:
  imul   %rax,%rsi
  add    $0x1,%rax
  cmp    %eax,%edx
  jge    L10
L46:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L34
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D17: Factorial = %lu


tool: D1: Error!!! Factorial of negative number doesn't exist.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2)
    return 1;
  int n, count;
  unsigned long long int factorial = 1;
  time_t t;
  srand((unsigned)time(&t));
  n = (int)argv[1][0];
  if (n < 0)
    printf("Error!!! Factorial of negative number doesn't exist.\n");
  else {
    for (count = 1; count <= n; ++count) {
      factorial *= count;
    }
    printf("Factorial = %lu\n", factorial);
  }
  return 0;
}
```