ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<checkCard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %esi,%eax
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %edi,%edx
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x2,%al
  movzbl %al,%edx
  movsbl -0x14(%rbp),%eax
  cmp    %eax,%edx
  jne    L37
  cmpb   $0xff,-0x18(%rbp)
  je     L50
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x3,%eax
  mov    %eax,%edx
  movsbl -0x18(%rbp),%eax
  cmp    %eax,%edx
  jne    L37
L50:
  mov    $0x1,%eax
  jmp    L36
L37:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  mov    $0x0,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
char checkCard(char value, char lear, unsigned char *cards, int count) {
  int i;
  for (i = 0; i < count; i++) {
    if (((unsigned char)cards[i] / 4) == value && (lear == -1 || (cards[i] % 4) == lear)) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<checkCard>:
  endbr64
  test   %ecx,%ecx
  jle    L30
  mov    %rdx,%r8
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%r9
  movsbl %dil,%ecx
  movsbl %sil,%edi
  jmp    L39
L15:
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L49
L39:
  movzbl (%r8),%edx
  mov    %edx,%eax
  shr    $0x2,%al
  movzbl %al,%eax
  cmp    %ecx,%eax
  jne    L15
  cmp    $0xff,%sil
  je     L37
  and    $0x3,%edx
  cmp    %edi,%edx
  jne    L15
  mov    $0x1,%eax
  ret
L49:
  mov    $0x0,%eax
  ret
L30:
  mov    $0x0,%eax
  ret
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
char checkCard(char value, char lear, unsigned char *cards, int count) {
  int i;
  for (i = 0; i < count; i++) {
    if (((unsigned char)cards[i] / 4) == value && (lear == -1 || (cards[i] % 4) == lear)) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<checkCard>:
  endbr64
  test   %ecx,%ecx
  jle    L27
  lea    -0x1(%rcx),%eax
  movsbl %dil,%edi
  movsbl %sil,%r9d
  lea    0x1(%rdx,%rax,1),%r8
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L27
L44:
  movzbl (%rdx),%ecx
  mov    %ecx,%eax
  shr    $0x2,%al
  movzbl %al,%eax
  cmp    %edi,%eax
  jne    L3
  cmp    $0xff,%sil
  je     L47
  and    $0x3,%ecx
  cmp    %r9d,%ecx
  jne    L3
L47:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
char checkCard(char value, char lear, unsigned char *cards, int count) {
  int i;
  for (i = 0; i < count; i++) {
    if (((unsigned char)cards[i] / 4) == value && (lear == -1 || (cards[i] % 4) == lear)) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checkCard>:
  endbr64
  movsbl %sil,%r8d
  test   %ecx,%ecx
  jle    L85
  movsbl %dil,%edi
  lea    -0x1(%rcx),%eax
  cmp    $0xff,%sil
  je     L52
  lea    0x1(%rdx,%rax,1),%rsi
  jmp    L29
L78:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L85
L29:
  movzbl (%rdx),%ecx
  mov    %ecx,%eax
  shr    $0x2,%al
  movzbl %al,%eax
  cmp    %edi,%eax
  jne    L78
  and    $0x3,%ecx
  cmp    %r8d,%ecx
  jne    L78
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L85:
  xor    %eax,%eax
  ret
L52:
  lea    0x1(%rdx,%rax,1),%rcx
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L68:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L85
L7:
  movzbl (%rdx),%eax
  shr    $0x2,%al
  movzbl %al,%eax
  cmp    %edi,%eax
  jne    L68
  mov    $0x1,%eax
  ret
```

assistant: ```c
char checkCard(char value, char lear, unsigned char *cards, int count) {
  int i;
  for (i = 0; i < count; i++) {
    if (((unsigned char)cards[i] / 4) == value && (lear == -1 || (cards[i] % 4) == lear)) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L1
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void f3(int size) {
  if (size < 0) {
    void *ptr = malloc(size);
    free(ptr);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f3>:
  endbr64
  test   %edi,%edi
  js     L6
  ret
L6:
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f3(int size) {
  if (size < 0) {
    void *ptr = malloc(size);
    free(ptr);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f3>:
  endbr64
  test   %edi,%edi
  js     L9
  ret
  nopl   0x0(%rax)
L9:
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void f3(int size) {
  if (size < 0) {
    void *ptr = malloc(size);
    free(ptr);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f3>:
  endbr64
  test   %edi,%edi
  js     L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void f3(int size) {
  if (size < 0) {
    void *ptr = malloc(size);
    free(ptr);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  jmp    L13
L17:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <mash_reg_W@plt>
  mov    %eax,%r12d
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <mash_mem_L@plt>
  mov    %eax,%ebx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <mash_reg_L@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L13:
  cmpl   $0xf,-0x1c(%rbp)
  jle    L17
  mov    $0x1,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D4: 0x%x -> 0x%2x 0x%2x 0x%2x


assistant: ```c
int main(void) {
  int i, ii;
  for (i = 0; i < 0x10; i++) {
    ii = i;
    printf("0x%x -> 0x%2x 0x%2x 0x%2x\n", i, mash_reg_L(i), mash_mem_L(&ii), mash_reg_W(i));
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D8(%rip),%r13
L3:
  mov    %ebx,0x4(%rsp)
  mov    %ebx,%edi
  call   <mash_reg_W@plt>
  mov    %eax,%r12d
  lea    0x4(%rsp),%rdi
  call   <mash_mem_L@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <mash_reg_L@plt>
  mov    %eax,%edx
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L3
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x1,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: 0x%x -> 0x%2x 0x%2x 0x%2x


assistant: ```c
int main(void) {
  int i, ii;
  for (i = 0; i < 0x10; i++) {
    ii = i;
    printf("0x%x -> 0x%2x 0x%2x 0x%2x\n", i, mash_reg_L(i), mash_mem_L(&ii), mash_reg_W(i));
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  xchg   %ax,%ax
L11:
  mov    %ebx,%edi
  mov    %ebx,0x4(%rsp)
  call   <mash_reg_W@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <mash_mem_L@plt>
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <mash_reg_L@plt>
  mov    %ebx,%esi
  mov    %r14d,%r8d
  mov    %r12d,%ecx
  mov    %eax,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x10,%ebx
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: 0x%x -> 0x%2x 0x%2x 0x%2x


assistant: ```c
int main(void) {
  int i, ii;
  for (i = 0; i < 0x10; i++) {
    ii = i;
    printf("0x%x -> 0x%2x 0x%2x 0x%2x\n", i, mash_reg_L(i), mash_mem_L(&ii), mash_reg_W(i));
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  xchg   %ax,%ax
L0:
  mov    %ebx,%edi
  mov    %ebx,0x4(%rsp)
  call   <mash_reg_W@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <mash_mem_L@plt>
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <mash_reg_L@plt>
  mov    %ebx,%esi
  mov    %r14d,%r8d
  mov    %r12d,%ecx
  mov    %eax,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x10,%ebx
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: 0x%x -> 0x%2x 0x%2x 0x%2x


assistant: ```c
int main(void) {
  int i, ii;
  for (i = 0; i < 0x10; i++) {
    ii = i;
    printf("0x%x -> 0x%2x 0x%2x 0x%2x\n", i, mash_reg_L(i), mash_mem_L(&ii), mash_reg_W(i));
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gdt_compare_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int gdt_compare_string(const void *p1, const void *p2) {
  char *s1 = *((char **)p1);
  char *s2 = *((char **)p2);
  return strcmp(s1, s2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gdt_compare_string>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gdt_compare_string(const void *p1, const void *p2) {
  char *s1 = *((char **)p1);
  char *s2 = *((char **)p2);
  return strcmp(s1, s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gdt_compare_string>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int gdt_compare_string(const void *p1, const void *p2) {
  char *s1 = *((char **)p1);
  char *s2 = *((char **)p2);
  return strcmp(s1, s2);
}
```
user: What is the c source code of the assembly code below?

```asm
<gdt_compare_string>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int gdt_compare_string(const void *p1, const void *p2) {
  char *s1 = *((char **)p1);
  char *s2 = *((char **)p2);
  return strcmp(s1, s2);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bgp_field_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L17:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int bgp_field_compare(const char *s1, const char *s2) {
  int i = 0;
  while (isspace(s1[i]))
    i++;
  return strcmp(s1 + i, s2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bgp_field_compare>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdi,%rbx
L9:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L9
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int bgp_field_compare(const char *s1, const char *s2) {
  int i = 0;
  while (isspace(s1[i]))
    i++;
  return strcmp(s1 + i, s2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bgp_field_compare>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L7:
  movsbl (%rbx),%edi
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcmp@plt>
```

assistant: ```c
int bgp_field_compare(const char *s1, const char *s2) {
  int i = 0;
  while (isspace(s1[i]))
    i++;
  return strcmp(s1 + i, s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bgp_field_compare>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L4:
  movsbl (%rbx),%edi
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcmp@plt>
```

assistant: ```c
int bgp_field_compare(const char *s1, const char *s2) {
  int i = 0;
  while (isspace(s1[i]))
    i++;
  return strcmp(s1 + i, s2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eis5_to_temp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0xb,%eax
  and    $0xf,%eax
  mov    %al,-0x5(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x7ff,%eax
  mov    %eax,%edx
  movzbl -0x5(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0xf,%eax
  cmp    $0x1,%eax
  jne    L5
  negl   -0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int eis5_to_temp(int eis5temp) {
  unsigned char exp;
  int temp = 0;
  exp = (eis5temp >> 11) & 0x0F;
  temp = (eis5temp & 0x07FF) << exp;
  if (eis5temp >> 15 == 1)
    temp = -temp;
  return temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eis5_to_temp>:
  endbr64
  mov    %edi,%eax
  and    $0x7ff,%eax
  mov    %edi,%ecx
  sar    $0xb,%ecx
  and    $0xf,%ecx
  shl    %cl,%eax
  sar    $0xf,%edi
  mov    %eax,%edx
  neg    %edx
  cmp    $0x1,%edi
  cmove  %edx,%eax
  ret
```

assistant: ```c
int eis5_to_temp(int eis5temp) {
  unsigned char exp;
  int temp = 0;
  exp = (eis5temp >> 11) & 0x0F;
  temp = (eis5temp & 0x07FF) << exp;
  if (eis5temp >> 15 == 1)
    temp = -temp;
  return temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eis5_to_temp>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  sar    $0xf,%edi
  sar    $0xb,%ecx
  and    $0x7ff,%eax
  and    $0xf,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  neg    %edx
  cmp    $0x1,%edi
  cmove  %edx,%eax
  ret
```

assistant: ```c
int eis5_to_temp(int eis5temp) {
  unsigned char exp;
  int temp = 0;
  exp = (eis5temp >> 11) & 0x0F;
  temp = (eis5temp & 0x07FF) << exp;
  if (eis5temp >> 15 == 1)
    temp = -temp;
  return temp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eis5_to_temp>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  sar    $0xf,%edi
  sar    $0xb,%ecx
  and    $0x7ff,%eax
  and    $0xf,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  neg    %edx
  cmp    $0x1,%edi
  cmove  %edx,%eax
  ret
```

assistant: ```c
int eis5_to_temp(int eis5temp) {
  unsigned char exp;
  int temp = 0;
  exp = (eis5temp >> 11) & 0x0F;
  temp = (eis5temp & 0x07FF) << exp;
  if (eis5temp >> 15 == 1)
    temp = -temp;
  return temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ultoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,%eax
  mov    %al,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x20,-0x32(%rbp)
L6:
  movzbl -0x54(%rbp),%ecx
  mov    -0x48(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  add    $0x30,%eax
  mov    %al,-0x31(%rbp)
  cmpb   $0x39,-0x31(%rbp)
  jbe    L1
  addb   $0x7,-0x31(%rbp)
L1:
  subb   $0x1,-0x32(%rbp)
  movzbl -0x32(%rbp),%eax
  movzbl -0x31(%rbp),%edx
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  movzbl -0x54(%rbp),%esi
  mov    -0x48(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x48(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  jne    L6
L14:
  movzbl -0x32(%rbp),%ecx
  mov    -0x50(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x50(%rbp)
  movslq %ecx,%rdx
  movzbl -0x30(%rbp,%rdx,1),%edx
  mov    %dl,(%rax)
  addb   $0x1,-0x32(%rbp)
  cmpb   $0x20,-0x32(%rbp)
  jne    L14
  mov    -0x50(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void _ultoa(unsigned long value, char *string, unsigned char radix) {
  char buffer[32];
  unsigned char index = 32;
  do {
    unsigned char c = '0' + (value % radix);
    if (c > (unsigned char)'9')
      c += 'A' - '9' - 1;
    buffer[--index] = c;
    value /= radix;
  } while (value);
  do {
    *string++ = buffer[index];
  } while (++index != 32);
  *string = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_ultoa>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x20,%edi
  movzbl %dl,%esi
  jmp    L16
L13:
  mov    %rax,%rcx
L16:
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  lea    0x30(%rdx),%eax
  add    $0x37,%edx
  cmp    $0x39,%al
  cmova  %edx,%eax
  sub    $0x1,%edi
  movzbl %dil,%edx
  mov    %al,(%rsp,%rdx,1)
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  cmp    %rcx,%rsi
  jbe    L13
  mov    %edi,%eax
  mov    %r8,%rdx
L2:
  add    $0x1,%rdx
  movzbl %al,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,-0x1(%rdx)
  add    $0x1,%eax
  cmp    $0x20,%al
  jne    L2
  mov    $0x1f,%eax
  sub    %edi,%eax
  movzbl %al,%eax
  movb   $0x0,0x1(%r8,%rax,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _ultoa(unsigned long value, char *string, unsigned char radix) {
  char buffer[32];
  unsigned char index = 32;
  do {
    unsigned char c = '0' + (value % radix);
    if (c > (unsigned char)'9')
      c += 'A' - '9' - 1;
    buffer[--index] = c;
    value /= radix;
  } while (value);
  do {
    *string++ = buffer[index];
  } while (++index != 32);
  *string = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_ultoa>:
  endbr64
  sub    $0x38,%rsp
  mov    %rsi,%r9
  movzbl %dl,%r8d
  mov    $0x20,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L40:
  mov    %rax,%rdi
L43:
  xor    %edx,%edx
  mov    %rdi,%rax
  div    %r8
  lea    0x30(%rdx),%ecx
  add    $0x37,%edx
  cmp    $0x39,%cl
  cmova  %edx,%ecx
  sub    $0x1,%esi
  movzbl %sil,%edx
  mov    %cl,(%rsp,%rdx,1)
  cmp    %r8,%rdi
  jae    L40
  mov    %esi,%eax
  mov    %r9,%rdx
  jmp    L9
  nopl   (%rax)
L34:
  movzbl %al,%ecx
  movzbl (%rsp,%rcx,1),%ecx
L9:
  add    $0x1,%eax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    $0x20,%al
  jne    L34
  mov    $0x1f,%eax
  sub    %esi,%eax
  movzbl %al,%eax
  movb   $0x0,0x1(%r9,%rax,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x38,%rsp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _ultoa(unsigned long value, char *string, unsigned char radix) {
  char buffer[32];
  unsigned char index = 32;
  do {
    unsigned char c = '0' + (value % radix);
    if (c > (unsigned char)'9')
      c += 'A' - '9' - 1;
    buffer[--index] = c;
    value /= radix;
  } while (value);
  do {
    *string++ = buffer[index];
  } while (++index != 32);
  *string = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_ultoa>:
  endbr64
  sub    $0x38,%rsp
  mov    %rsi,%r9
  movzbl %dl,%r8d
  mov    $0x20,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L20:
  lea    0x37(%rdx),%ecx
  movzbl %sil,%edx
  mov    %cl,(%rsp,%rdx,1)
  cmp    %r8,%rdi
  jb     L31
L0:
  mov    %rax,%rdi
L11:
  mov    %rdi,%rax
  xor    %edx,%edx
  sub    $0x1,%esi
  div    %r8
  lea    0x30(%rdx),%ecx
  cmp    $0x39,%cl
  ja     L20
  movzbl %sil,%edx
  mov    %cl,(%rsp,%rdx,1)
  cmp    %r8,%rdi
  jae    L0
L31:
  mov    %cl,(%r9)
  lea    0x1(%r9),%rdx
  lea    0x1(%rsi),%eax
  cmp    $0x1f,%sil
  je     L37
  nopl   0x0(%rax)
L14:
  movzbl %al,%ecx
  add    $0x1,%rdx
  add    $0x1,%eax
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    $0x20,%al
  jne    L14
L37:
  mov    $0x1f,%eax
  sub    %esi,%eax
  movzbl %al,%eax
  movb   $0x0,0x1(%r9,%rax,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x38,%rsp
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _ultoa(unsigned long value, char *string, unsigned char radix) {
  char buffer[32];
  unsigned char index = 32;
  do {
    unsigned char c = '0' + (value % radix);
    if (c > (unsigned char)'9')
      c += 'A' - '9' - 1;
    buffer[--index] = c;
    value /= radix;
  } while (value);
  do {
    *string++ = buffer[index];
  } while (++index != 32);
  *string = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<null_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L10
L16:
  mov    $0x1,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int null_free(BIO *a) {
  if (a == NULL)
    return (0);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<null_free>:
  endbr64
  test   %rdi,%rdi
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int null_free(BIO *a) {
  if (a == NULL)
    return (0);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<null_free>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %al
  ret
```

assistant: ```c
int null_free(BIO *a) {
  if (a == NULL)
    return (0);
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<null_free>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %al
  ret
```

assistant: ```c
int null_free(BIO *a) {
  if (a == NULL)
    return (0);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sub_eax_imm32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x2d,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void sub_eax_imm32(unsigned int imm32) {
  put8(0x2D);
  put32(imm32);
}
```