ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<cpuid_ebx>:
  endbr64
  sub    $0x28,%rsp
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) unsigned int cpuid_ebx(unsigned int op) {
  unsigned int eax, ebx, ecx, edx;
  cpuid(op, &eax, &ebx, &ecx, &edx);
  return ebx;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpuid_ebx>:
  endbr64
  sub    $0x28,%rsp
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) unsigned int cpuid_ebx(unsigned int op) {
  unsigned int eax, ebx, ecx, edx;
  cpuid(op, &eax, &ebx, &ecx, &edx);
  return ebx;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reset_signal_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L34:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  jne    L39
  mov    $0x46,%edi
  call   <exit_errno@plt>
L39:
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  mov    $0x0,%eax
  call   <unblock_signals@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void reset_signal_handler(const int list[], const int list_len) {
  struct sigaction act;
  memset(&act, 0, sizeof(struct sigaction));
  act.sa_handler = SIG_DFL;
  for (int i = 0; i < list_len; ++i) {
    if (sigaction(list[i], &act, NULL) == -1)
      exit_errno(70);
  }
  unblock_signals();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reset_signal_handler>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  test   %ebp,%ebp
  jle    L15
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    0x4(%rsp),%rbp
  jmp    L38
L5:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L15
L38:
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  jne    L5
  mov    $0x46,%edi
  call   <exit_errno@plt>
  jmp    L5
L15:
  mov    $0x0,%eax
  call   <unblock_signals@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void reset_signal_handler(const int list[], const int list_len) {
  struct sigaction act;
  memset(&act, 0, sizeof(struct sigaction));
  act.sa_handler = SIG_DFL;
  for (int i = 0; i < list_len; ++i) {
    if (sigaction(list[i], &act, NULL) == -1)
      exit_errno(70);
  }
  unblock_signals();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reset_signal_handler>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  test   %r12d,%r12d
  jle    L33
  lea    -0x1(%r12),%eax
  lea    0x4(%rbx,%rax,4),%r12
  jmp    L16
  nopl   0x0(%rax)
L29:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L33
L16:
  mov    (%rbx),%edi
  xor    %edx,%edx
  mov    %rbp,%rsi
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  jne    L29
  mov    $0x46,%edi
  add    $0x4,%rbx
  call   <exit_errno@plt>
  cmp    %r12,%rbx
  jne    L16
  nopl   (%rax)
L33:
  xor    %eax,%eax
  call   <unblock_signals@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void reset_signal_handler(const int list[], const int list_len) {
  struct sigaction act;
  memset(&act, 0, sizeof(struct sigaction));
  act.sa_handler = SIG_DFL;
  for (int i = 0; i < list_len; ++i) {
    if (sigaction(list[i], &act, NULL) == -1)
      exit_errno(70);
  }
  unblock_signals();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reset_signal_handler>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  test   %r12d,%r12d
  jle    L28
  lea    -0x1(%r12),%eax
  lea    0x4(%rbx,%rax,4),%r12
  jmp    L58
  nopl   0x0(%rax)
L34:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L28
L58:
  mov    (%rbx),%edi
  xor    %edx,%edx
  mov    %rbp,%rsi
  call   <sigaction@plt>
  cmp    $0xffffffff,%eax
  jne    L34
  mov    $0x46,%edi
  add    $0x4,%rbx
  call   <exit_errno@plt>
  cmp    %r12,%rbx
  jne    L58
  nopl   (%rax)
L28:
  xor    %eax,%eax
  call   <unblock_signals@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void reset_signal_handler(const int list[], const int list_len) {
  struct sigaction act;
  memset(&act, 0, sizeof(struct sigaction));
  act.sa_handler = SIG_DFL;
  for (int i = 0; i < list_len; ++i) {
    if (sigaction(list[i], &act, NULL) == -1)
      exit_errno(70);
  }
  unblock_signals();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dirname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L5
L11:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
char *dirname(char *path) {
  char *p;
  p = strrchr(path, '/');
  if (!p)
    return path + strlen(path);
  *p = '\0';
  return path;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dirname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L18
  movb   $0x0,(%rax)
  mov    %rbx,%rax
L5:
  pop    %rbx
  ret
L18:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jmp    L5
```

assistant: ```c
char *dirname(char *path) {
  char *p;
  p = strrchr(path, '/');
  if (!p)
    return path + strlen(path);
  *p = '\0';
  return path;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dirname>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L3
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  pop    %rbx
  ret
  nop
L3:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *dirname(char *path) {
  char *p;
  p = strrchr(path, '/');
  if (!p)
    return path + strlen(path);
  *p = '\0';
  return path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dirname>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  pop    %rbx
  ret
  nop
L7:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *dirname(char *path) {
  char *p;
  p = strrchr(path, '/');
  if (!p)
    return path + strlen(path);
  *p = '\0';
  return path;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<t1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movb   $0x0,-0x11(%rbp)
  movsbl -0x11(%rbp),%eax
  cltq
  mov    -0xc(%rbp,%rax,4),%eax
  mov    %eax,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void t1() {
  int array[1] = {0};
  char sudirript = 0;
  int val = array[sudirript];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t1>:
  endbr64
  ret
```

assistant: ```c
void t1() {
  int array[1] = {0};
  char sudirript = 0;
  int val = array[sudirript];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<t1>:
  endbr64
  ret
```

assistant: ```c
void t1() {
  int array[1] = {0};
  char sudirript = 0;
  int val = array[sudirript];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<t1>:
  endbr64
  ret
```

assistant: ```c
void t1() {
  int array[1] = {0};
  char sudirript = 0;
  int val = array[sudirript];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nokia_lcd_flash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  jmp    L17
L0:
  mov    $0x5dc,%edi
  call   <DelayMs@plt>
  mov    $0xd,%edi
  call   <nokia_lcd_cmd@plt>
  mov    $0x5dc,%edi
  call   <DelayMs@plt>
  mov    $0xc,%edi
  call   <nokia_lcd_cmd@plt>
  movzbl -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x4(%rbp)
L17:
  cmpb   $0x0,-0x4(%rbp)
  jg     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void nokia_lcd_flash(char flash_number) {
  while (flash_number > 0) {
    DelayMs(1500);
    nokia_lcd_cmd(0x0d);
    DelayMs(1500);
    nokia_lcd_cmd(0x0c);
    flash_number--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nokia_lcd_flash>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %dil,%dil
  jle    L1
L2:
  mov    $0x5dc,%edi
  call   <DelayMs@plt>
  mov    $0xd,%edi
  call   <nokia_lcd_cmd@plt>
  mov    $0x5dc,%edi
  call   <DelayMs@plt>
  mov    $0xc,%edi
  call   <nokia_lcd_cmd@plt>
  sub    $0x1,%bl
  jne    L2
L1:
  pop    %rbx
  ret
```

assistant: ```c
void nokia_lcd_flash(char flash_number) {
  while (flash_number > 0) {
    DelayMs(1500);
    nokia_lcd_cmd(0x0d);
    DelayMs(1500);
    nokia_lcd_cmd(0x0c);
    flash_number--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nokia_lcd_flash>:
  endbr64
  test   %dil,%dil
  jle    L3
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax)
L4:
  mov    $0x5dc,%edi
  call   <DelayMs@plt>
  mov    $0xd,%edi
  call   <nokia_lcd_cmd@plt>
  mov    $0x5dc,%edi
  call   <DelayMs@plt>
  mov    $0xc,%edi
  call   <nokia_lcd_cmd@plt>
  sub    $0x1,%bl
  jne    L4
  pop    %rbx
  ret
  nop
L3:
  ret
```

assistant: ```c
void nokia_lcd_flash(char flash_number) {
  while (flash_number > 0) {
    DelayMs(1500);
    nokia_lcd_cmd(0x0d);
    DelayMs(1500);
    nokia_lcd_cmd(0x0c);
    flash_number--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nokia_lcd_flash>:
  endbr64
  test   %dil,%dil
  jle    L4
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax)
L16:
  mov    $0x5dc,%edi
  call   <DelayMs@plt>
  mov    $0xd,%edi
  call   <nokia_lcd_cmd@plt>
  mov    $0x5dc,%edi
  call   <DelayMs@plt>
  mov    $0xc,%edi
  call   <nokia_lcd_cmd@plt>
  sub    $0x1,%bl
  jne    L16
  pop    %rbx
  ret
  nop
L4:
  ret
```

assistant: ```c
void nokia_lcd_flash(char flash_number) {
  while (flash_number > 0) {
    DelayMs(1500);
    nokia_lcd_cmd(0x0d);
    DelayMs(1500);
    nokia_lcd_cmd(0x0c);
    flash_number--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<merge_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,-0x28(%rsp)
  mov    %rdx,%rsi
  mov    %rcx,-0x10(%rsp)
  mov    %r8,%r14
  mov    %r9,-0x8(%rsp)
  mov    0x38(%rsp),%edx
  mov    0x40(%rsp),%r13
  test   %edi,%edi
  jle    L46
  movslq %edi,%r15
  lea    0x0(,%r15,8),%rax
  mov    %rax,-0x20(%rsp)
  movslq %edx,%rax
  shl    $0x3,%rax
  mov    %rax,-0x18(%rsp)
  mov    %r13,%rdi
  mov    %r15,%r12
  neg    %r12
  shl    $0x3,%r12
  mov    $0x0,%ebp
  mov    $0x0,%r11d
  mov    $0x0,%r10d
  mov    %ebx,%r9d
L104:
  mov    %r11d,%eax
  mov    $0x0,%ecx
L113:
  movapd %xmm0,%xmm4
  mulsd  (%rsi,%rcx,8),%xmm4
  movsd  %xmm4,(%rdi,%rcx,8)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L113
  cmp    %edx,%ebx
  jge    L38
  movslq %ebp,%rcx
  lea    (%r12,%rcx,8),%rcx
  add    -0x10(%rsp),%rcx
  cltq
  lea    0x0(%r13,%rax,8),%r8
  mov    %r15,%rax
L0:
  movapd %xmm1,%xmm4
  mulsd  (%rcx,%rax,8),%xmm4
  movsd  %xmm4,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L0
L38:
  add    $0x1,%r10d
  add    -0x20(%rsp),%rsi
  add    %edx,%r11d
  add    -0x18(%rsp),%rdi
  add    -0x28(%rsp),%ebp
  cmp    %r10d,%ebx
  jne    L104
L46:
  cmp    %edx,%ebx
  jge    L64
  movslq -0x28(%rsp),%rax
  shl    $0x3,%rax
  mov    %rax,-0x28(%rsp)
  movslq %ebx,%r15
  mov    %r15,%rax
  neg    %rax
  mov    -0x8(%rsp),%rdi
  lea    (%rdi,%rax,8),%rdi
  mov    %ebx,%eax
  imul   %edx,%eax
  mov    %eax,%r12d
  movslq %edx,%rcx
  lea    0x0(,%rcx,8),%rsi
  mov    %rsi,-0x20(%rsp)
  cltq
  lea    0x0(%r13,%rax,8),%rsi
  mov    %ebx,%r8d
  mov    $0x0,%ebp
  lea    -0x1(%rbx),%r11d
  jmp    L26
L100:
  movslq %ebp,%rax
  lea    (%r14,%rax,8),%r10
  movslq %r12d,%rax
  lea    0x0(%r13,%rax,8),%r9
  mov    $0x0,%eax
L115:
  movapd %xmm2,%xmm0
  mulsd  (%r10,%rax,8),%xmm0
  movsd  %xmm0,(%r9,%rax,8)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %r11,%rcx
  jne    L115
L44:
  mov    %r15,%rax
L4:
  movapd %xmm3,%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L4
  add    $0x1,%r8d
  add    -0x28(%rsp),%rdi
  add    %edx,%r12d
  add    -0x20(%rsp),%rsi
  add    %ebx,%ebp
  cmp    %r8d,%edx
  je     L64
L26:
  test   %ebx,%ebx
  jg     L100
  jmp    L44
L64:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void merge_matrix(int n1, int n2, double c_ll, const double *a_ll, double c_lh, const double *a_lh, double c_hl, const double *a_hl, double c_hh, const double *a_hh, int n, double *a) {
  int i, j;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n1; j++) {
      a[i * n + j] = c_ll * a_ll[i * n1 + j];
    }
    for (j = n1; j < n; j++) {
      a[i * n + j] = c_lh * a_lh[i * n2 + (j - n1)];
    }
  }
  for (i = n1; i < n; i++) {
    for (j = 0; j < n1; j++) {
      a[i * n + j] = c_hl * a_hl[(i - n1) * n1 + j];
    }
    for (j = n1; j < n; j++) {
      a[i * n + j] = c_hh * a_hh[(i - n1) * n2 + (j - n1)];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<merge_matrix>:
  endbr64
  mov    %edi,%r11d
  push   %r15
  mov    %rdx,%rdi
  mov    %r9,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    0x38(%rsp),%edx
  test   %r11d,%r11d
  jle    L57
  mov    %rcx,%r13
  movslq %edx,%r12
  movslq %r11d,%r10
  mov    0x40(%rsp),%rcx
  shl    $0x3,%r12
  lea    0x0(,%r10,8),%rbp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L38:
  movsd  (%rdi,%rax,8),%xmm4
  mulsd  %xmm0,%xmm4
  movsd  %xmm4,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r10
  jne    L38
  cmp    %edx,%r11d
  jge    L26
  movslq %r9d,%rax
  lea    0x0(%r13,%rax,8),%rsi
  mov    %r10,%rax
  sub    %rbp,%rsi
  nopw   0x0(%rax,%rax,1)
L59:
  movsd  (%rsi,%rax,8),%xmm4
  mulsd  %xmm1,%xmm4
  movsd  %xmm4,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L59
L26:
  add    $0x1,%r8d
  add    %ebx,%r9d
  add    %r12,%rcx
  add    %rbp,%rdi
  cmp    %r8d,%r11d
  jne    L28
L57:
  cmp    %edx,%r11d
  jge    L87
  movslq %ebx,%r10
  movslq %r11d,%rbx
  mov    0x40(%rsp),%rsi
  movslq %edx,%rbp
  mov    %rbx,%rax
  shl    $0x3,%r10
  mov    %r11d,%r9d
  xor    %r12d,%r12d
  neg    %rax
  shl    $0x3,%rbp
  lea    -0x1(%r11),%r8d
  lea    (%r15,%rax,8),%rdi
  mov    %r11d,%eax
  imul   %edx,%eax
  cltq
  lea    (%rsi,%rax,8),%rcx
  nop
L83:
  test   %r11d,%r11d
  jle    L73
  movslq %r12d,%rax
  lea    (%r14,%rax,8),%r13
  xor    %eax,%eax
  xchg   %ax,%ax
L17:
  movsd  0x0(%r13,%rax,8),%xmm0
  mov    %rax,%rsi
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%r8
  jne    L17
L73:
  mov    %rbx,%rax
  nop
L72:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L72
  add    $0x1,%r9d
  add    %r10,%rdi
  add    %rbp,%rcx
  add    %r11d,%r12d
  cmp    %r9d,%edx
  jne    L83
L87:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void merge_matrix(int n1, int n2, double c_ll, const double *a_ll, double c_lh, const double *a_lh, double c_hl, const double *a_hl, double c_hh, const double *a_hh, int n, double *a) {
  int i, j;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n1; j++) {
      a[i * n + j] = c_ll * a_ll[i * n1 + j];
    }
    for (j = n1; j < n; j++) {
      a[i * n + j] = c_lh * a_lh[i * n2 + (j - n1)];
    }
  }
  for (i = n1; i < n; i++) {
    for (j = 0; j < n1; j++) {
      a[i * n + j] = c_hl * a_hl[(i - n1) * n1 + j];
    }
    for (j = n1; j < n; j++) {
      a[i * n + j] = c_hh * a_hh[(i - n1) * n2 + (j - n1)];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  call   <fork@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L4
  call   <fork@plt>
  mov    %eax,-0x8(%rbp)
L4:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: Ha terminato %d


assistant: ```c
int main() {
  int i = 0, status, j = 0;
  i = fork();
  if (i > 0) {
    i = fork();
  }
  printf("Ha terminato %d\n", getpid());
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  test   %eax,%eax
  jg     L10
L15:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L10:
  call   <fork@plt>
  jmp    L15
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: Ha terminato %d


assistant: ```c
int main() {
  int i = 0, status, j = 0;
  i = fork();
  if (i > 0) {
    i = fork();
  }
  printf("Ha terminato %d\n", getpid());
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  test   %eax,%eax
  jle    L6
  call   <fork@plt>
L6:
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: Ha terminato %d


assistant: ```c
int main() {
  int i = 0, status, j = 0;
  i = fork();
  if (i > 0) {
    i = fork();
  }
  printf("Ha terminato %d\n", getpid());
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  test   %eax,%eax
  jle    L7
  call   <fork@plt>
L7:
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: Ha terminato %d


assistant: ```c
int main() {
  int i = 0, status, j = 0;
  i = fork();
  if (i > 0) {
    i = fork();
  }
  printf("Ha terminato %d\n", getpid());
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skip_ws>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L56
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x20,%eax
  seta   %dl
  test   %dl,%dl
  jne    L14
  movabs $0x100003600,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L14
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x18(%rbp)
  jmp    L56
L14:
  movl   $0x1,-0x4(%rbp)
  nop
L56:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L38
  cmpl   $0x0,-0x4(%rbp)
  je     L20
L38:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skip_ws(char *string) {
  int done = 0;
  while (*string != '\0' && !done) {
    switch (*string) {
    case ' ':
    case '\n':
    case '\r':
    case '\t':
    case '\f':
      *string = '\0';
      string++;
      break;
    default:
      done = 1;
      break;
    }
  }
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skip_ws>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%r10d
  mov    $0x1,%r8d
  movabs $0x100003600,%r9
  jmp    L50
L54:
  movb   $0x0,(%rax)
  add    $0x1,%rax
L50:
  movzbl (%rax),%ecx
  test   %cl,%cl
  setne  %dil
  mov    %r10d,%esi
  mov    %r9,%rdx
  shr    %cl,%rdx
  and    $0x1,%edx
L58:
  test   %esi,%esi
  jne    L19
  test   %dil,%dil
  je     L19
  mov    %r8d,%esi
  cmp    $0x20,%cl
  ja     L58
  test   %rdx,%rdx
  je     L58
  jmp    L54
L19:
  ret
```

assistant: ```c
char *skip_ws(char *string) {
  int done = 0;
  while (*string != '\0' && !done) {
    switch (*string) {
    case ' ':
    case '\n':
    case '\r':
    case '\t':
    case '\f':
      *string = '\0';
      string++;
      break;
    default:
      done = 1;
      break;
    }
  }
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_ws>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L18
  movabs $0x100003600,%rcx
L22:
  cmp    $0x20,%dl
  ja     L18
  bt     %rdx,%rcx
  jb     L29
L18:
  ret
  nopl   0x0(%rax)
L29:
  movb   $0x0,(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L22
  ret
```

assistant: ```c
char *skip_ws(char *string) {
  int done = 0;
  while (*string != '\0' && !done) {
    switch (*string) {
    case ' ':
    case '\n':
    case '\r':
    case '\t':
    case '\f':
      *string = '\0';
      string++;
      break;
    default:
      done = 1;
      break;
    }
  }
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skip_ws>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L29
  movabs $0x100003600,%rcx
L10:
  cmp    $0x20,%dl
  ja     L29
  bt     %rdx,%rcx
  jb     L37
L29:
  ret
  nopl   0x0(%rax)
L37:
  movb   $0x0,(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L10
  ret
```

assistant: ```c
char *skip_ws(char *string) {
  int done = 0;
  while (*string != '\0' && !done) {
    switch (*string) {
    case ' ':
    case '\n':
    case '\r':
    case '\t':
    case '\f':
      *string = '\0';
      string++;
      break;
    default:
      done = 1;
      break;
    }
  }
  return string;
}
```