ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcasecmpend>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jae    L9
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcasecmp@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  sub    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdx
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <strncasecmp@plt>
```

assistant: ```c
int strcasecmpend(const char *s1, const char *s2) {
  size_t n1 = strlen(s1), n2 = strlen(s2);
  if (n2 > n1)
    return strcasecmp(s1, s2);
  else
    return strncasecmp(s1 + (n1 - n2), s2, n2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bc_iso3166_numeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0xf8,-0x8(%rbp)
  jmp    L47
L69:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D16(%rip),%rax
  movzwl (%rdx,%rax,1),%eax
  cwtl
  cmp    %eax,-0x14(%rbp)
  jle    L46
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L47
L46:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D16(%rip),%rax
  movzwl (%rdx,%rax,1),%eax
  cwtl
  cmp    %eax,-0x14(%rbp)
  jge    L9
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L47
L9:
  mov    $0x1,%eax
  jmp    L66
L47:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L69
  mov    $0x0,%eax
L66:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string

tool: D16: 

assistant: ```c
int bc_iso3166_numeric(int cc) {
  static const short codes[249] = {
      4, 8, 10, 12, 16, 20, 24, 28, 31, 32, 36, 40, 44, 48, 50, 51, 52, 56, 60, 64, 68, 70, 72, 74, 76, 84, 86, 90, 92, 96, 100, 104, 108, 112, 116, 120, 124, 132, 136, 140, 144, 148, 152, 156, 158, 162, 166, 170, 174, 175, 178, 180, 184, 188, 191, 192, 196, 203, 204, 208, 212, 214, 218, 222, 226, 231, 232, 233, 234, 238, 239, 242, 246, 248, 250, 254, 258, 260, 262, 266, 268, 270, 275, 276, 288, 292, 296, 300, 304, 308, 312, 316, 320, 324, 328, 332, 334, 336, 340, 344, 348, 352, 356, 360, 364, 368, 372, 376, 380, 384, 388, 392, 398, 400, 404, 408, 410, 414, 417, 418, 422, 426, 428, 430, 434, 438, 440, 442, 446, 450, 454, 458, 462, 466, 470, 474, 478, 480, 484, 492, 496, 498, 499, 500, 504, 508, 512, 516, 520, 524, 528, 531, 533, 534, 535, 540, 548, 554, 558, 562, 566, 570, 574, 578, 580, 581, 583, 584, 585, 586, 591, 598, 600, 604, 608, 612, 616, 620, 624, 626, 630, 634, 638, 642, 643, 646, 652, 654, 659, 660, 662, 663, 666, 670, 674, 678, 682, 686, 688, 690, 694, 702, 703, 704, 705, 706, 710, 716, 724, 728, 729, 732, 740, 744, 748, 752, 756, 760, 762, 764, 768, 772, 776, 780, 784, 788, 792, 795, 796, 798, 800, 804, 807, 818, 826, 831, 832, 833, 834, 840, 850, 854, 858, 860, 862, 876, 882, 887, 894,
  };
  int s = 0, e = ((int)(sizeof(codes) / sizeof((codes)[0]))) - 1;
  while (s <= e) {
    int m = (s + e) / 2;
    if (codes[m] < cc) {
      s = m + 1;
    } else if (codes[m] > cc) {
      e = m - 1;
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bc_iso3166_numeric>:
  endbr64
  mov    $0xf8,%esi
  mov    $0x0,%ecx
  lea    D1(%rip),%r8
  jmp    L35
L2:
  jle    L28
  lea    -0x1(%rax),%esi
L23:
  cmp    %esi,%ecx
  jg     L49
L35:
  lea    (%rcx,%rsi,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  movswl (%r8,%rdx,2),%edx
  cmp    %edi,%edx
  jge    L2
  lea    0x1(%rax),%ecx
  jmp    L23
L49:
  mov    $0x0,%eax
  ret
L28:
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: 

assistant: ```c
int bc_iso3166_numeric(int cc) {
  static const short codes[249] = {
      4, 8, 10, 12, 16, 20, 24, 28, 31, 32, 36, 40, 44, 48, 50, 51, 52, 56, 60, 64, 68, 70, 72, 74, 76, 84, 86, 90, 92, 96, 100, 104, 108, 112, 116, 120, 124, 132, 136, 140, 144, 148, 152, 156, 158, 162, 166, 170, 174, 175, 178, 180, 184, 188, 191, 192, 196, 203, 204, 208, 212, 214, 218, 222, 226, 231, 232, 233, 234, 238, 239, 242, 246, 248, 250, 254, 258, 260, 262, 266, 268, 270, 275, 276, 288, 292, 296, 300, 304, 308, 312, 316, 320, 324, 328, 332, 334, 336, 340, 344, 348, 352, 356, 360, 364, 368, 372, 376, 380, 384, 388, 392, 398, 400, 404, 408, 410, 414, 417, 418, 422, 426, 428, 430, 434, 438, 440, 442, 446, 450, 454, 458, 462, 466, 470, 474, 478, 480, 484, 492, 496, 498, 499, 500, 504, 508, 512, 516, 520, 524, 528, 531, 533, 534, 535, 540, 548, 554, 558, 562, 566, 570, 574, 578, 580, 581, 583, 584, 585, 586, 591, 598, 600, 604, 608, 612, 616, 620, 624, 626, 630, 634, 638, 642, 643, 646, 652, 654, 659, 660, 662, 663, 666, 670, 674, 678, 682, 686, 688, 690, 694, 702, 703, 704, 705, 706, 710, 716, 724, 728, 729, 732, 740, 744, 748, 752, 756, 760, 762, 764, 768, 772, 776, 780, 784, 788, 792, 795, 796, 798, 800, 804, 807, 818, 826, 831, 832, 833, 834, 840, 850, 854, 858, 860, 862, 876, 882, 887, 894,
  };
  int s = 0, e = ((int)(sizeof(codes) / sizeof((codes)[0]))) - 1;
  while (s <= e) {
    int m = (s + e) / 2;
    if (codes[m] < cc) {
      s = m + 1;
    } else if (codes[m] > cc) {
      e = m - 1;
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bc_iso3166_numeric>:
  endbr64
  mov    $0x1b2,%edx
  mov    $0xf8,%esi
  xor    %ecx,%ecx
  mov    $0xf8,%eax
  lea    D7(%rip),%r8
  jmp    L11
  xchg   %ax,%ax
L31:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jg     L0
L49:
  lea    (%rcx,%rsi,1),%eax
  mov    %eax,%edx
  sar    %edx
  movslq %edx,%rdx
  movswl (%r8,%rdx,2),%edx
L11:
  sar    %eax
  cmp    %edi,%edx
  jl     L31
  jle    L43
  lea    -0x1(%rax),%esi
  cmp    %esi,%ecx
  jle    L49
L0:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: 

assistant: ```c
int bc_iso3166_numeric(int cc) {
  static const short codes[249] = {
      4, 8, 10, 12, 16, 20, 24, 28, 31, 32, 36, 40, 44, 48, 50, 51, 52, 56, 60, 64, 68, 70, 72, 74, 76, 84, 86, 90, 92, 96, 100, 104, 108, 112, 116, 120, 124, 132, 136, 140, 144, 148, 152, 156, 158, 162, 166, 170, 174, 175, 178, 180, 184, 188, 191, 192, 196, 203, 204, 208, 212, 214, 218, 222, 226, 231, 232, 233, 234, 238, 239, 242, 246, 248, 250, 254, 258, 260, 262, 266, 268, 270, 275, 276, 288, 292, 296, 300, 304, 308, 312, 316, 320, 324, 328, 332, 334, 336, 340, 344, 348, 352, 356, 360, 364, 368, 372, 376, 380, 384, 388, 392, 398, 400, 404, 408, 410, 414, 417, 418, 422, 426, 428, 430, 434, 438, 440, 442, 446, 450, 454, 458, 462, 466, 470, 474, 478, 480, 484, 492, 496, 498, 499, 500, 504, 508, 512, 516, 520, 524, 528, 531, 533, 534, 535, 540, 548, 554, 558, 562, 566, 570, 574, 578, 580, 581, 583, 584, 585, 586, 591, 598, 600, 604, 608, 612, 616, 620, 624, 626, 630, 634, 638, 642, 643, 646, 652, 654, 659, 660, 662, 663, 666, 670, 674, 678, 682, 686, 688, 690, 694, 702, 703, 704, 705, 706, 710, 716, 724, 728, 729, 732, 740, 744, 748, 752, 756, 760, 762, 764, 768, 772, 776, 780, 784, 788, 792, 795, 796, 798, 800, 804, 807, 818, 826, 831, 832, 833, 834, 840, 850, 854, 858, 860, 862, 876, 882, 887, 894,
  };
  int s = 0, e = ((int)(sizeof(codes) / sizeof((codes)[0]))) - 1;
  while (s <= e) {
    int m = (s + e) / 2;
    if (codes[m] < cc) {
      s = m + 1;
    } else if (codes[m] > cc) {
      e = m - 1;
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bc_iso3166_numeric>:
  endbr64
  mov    $0x1b2,%edx
  mov    $0xf8,%esi
  xor    %ecx,%ecx
  mov    $0xf8,%eax
  lea    D3(%rip),%r8
  jmp    L34
  xchg   %ax,%ax
L5:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jg     L27
L17:
  lea    (%rcx,%rsi,1),%eax
  mov    %eax,%edx
  sar    %edx
  movslq %edx,%rdx
  movswl (%r8,%rdx,2),%edx
L34:
  sar    %eax
  cmp    %edi,%edx
  jl     L5
  jle    L1
  lea    -0x1(%rax),%esi
  cmp    %esi,%ecx
  jle    L17
L27:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D3: 

assistant: ```c
int bc_iso3166_numeric(int cc) {
  static const short codes[249] = {
      4, 8, 10, 12, 16, 20, 24, 28, 31, 32, 36, 40, 44, 48, 50, 51, 52, 56, 60, 64, 68, 70, 72, 74, 76, 84, 86, 90, 92, 96, 100, 104, 108, 112, 116, 120, 124, 132, 136, 140, 144, 148, 152, 156, 158, 162, 166, 170, 174, 175, 178, 180, 184, 188, 191, 192, 196, 203, 204, 208, 212, 214, 218, 222, 226, 231, 232, 233, 234, 238, 239, 242, 246, 248, 250, 254, 258, 260, 262, 266, 268, 270, 275, 276, 288, 292, 296, 300, 304, 308, 312, 316, 320, 324, 328, 332, 334, 336, 340, 344, 348, 352, 356, 360, 364, 368, 372, 376, 380, 384, 388, 392, 398, 400, 404, 408, 410, 414, 417, 418, 422, 426, 428, 430, 434, 438, 440, 442, 446, 450, 454, 458, 462, 466, 470, 474, 478, 480, 484, 492, 496, 498, 499, 500, 504, 508, 512, 516, 520, 524, 528, 531, 533, 534, 535, 540, 548, 554, 558, 562, 566, 570, 574, 578, 580, 581, 583, 584, 585, 586, 591, 598, 600, 604, 608, 612, 616, 620, 624, 626, 630, 634, 638, 642, 643, 646, 652, 654, 659, 660, 662, 663, 666, 670, 674, 678, 682, 686, 688, 690, 694, 702, 703, 704, 705, 706, 710, 716, 724, 728, 729, 732, 740, 744, 748, 752, 756, 760, 762, 764, 768, 772, 776, 780, 784, 788, 792, 795, 796, 798, 800, 804, 807, 818, 826, 831, 832, 833, 834, 840, 850, 854, 858, 860, 862, 876, 882, 887, 894,
  };
  int s = 0, e = ((int)(sizeof(codes) / sizeof((codes)[0]))) - 1;
  while (s <= e) {
    int m = (s + e) / 2;
    if (codes[m] < cc) {
      s = m + 1;
    } else if (codes[m] > cc) {
      e = m - 1;
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_perfect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L2
L8:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x10(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L16
  mov    -0x10(%rbp),%rax
  add    %rax,-0x8(%rbp)
L16:
  addq   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L8
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_perfect(unsigned long n) {
  unsigned long i, sum = 0;
  for (i = 1; i < n; i++) {
    if (n % i == 0) {
      sum += i;
    }
  }
  return sum == n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_perfect>:
  endbr64
  cmp    $0x1,%rdi
  jbe    L8
  mov    $0x0,%esi
  mov    $0x1,%ecx
L14:
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  lea    (%rsi,%rcx,1),%rax
  test   %rdx,%rdx
  cmove  %rax,%rsi
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L14
L19:
  cmp    %rsi,%rdi
  sete   %al
  movzbl %al,%eax
  ret
L8:
  mov    $0x0,%esi
  jmp    L19
```

assistant: ```c
int is_perfect(unsigned long n) {
  unsigned long i, sum = 0;
  for (i = 1; i < n; i++) {
    if (n % i == 0) {
      sum += i;
    }
  }
  return sum == n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_perfect>:
  endbr64
  xor    %esi,%esi
  cmp    $0x1,%rdi
  jbe    L2
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L1:
  xor    %edx,%edx
  mov    %rdi,%rax
  div    %rcx
  lea    (%rsi,%rcx,1),%rax
  test   %rdx,%rdx
  cmove  %rax,%rsi
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L1
L2:
  xor    %eax,%eax
  cmp    %rsi,%rdi
  sete   %al
  ret
```

assistant: ```c
int is_perfect(unsigned long n) {
  unsigned long i, sum = 0;
  for (i = 1; i < n; i++) {
    if (n % i == 0) {
      sum += i;
    }
  }
  return sum == n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_perfect>:
  endbr64
  xor    %esi,%esi
  cmp    $0x1,%rdi
  jbe    L19
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L3:
  xor    %edx,%edx
  mov    %rdi,%rax
  div    %rcx
  lea    (%rsi,%rcx,1),%rax
  test   %rdx,%rdx
  cmove  %rax,%rsi
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L3
L19:
  xor    %eax,%eax
  cmp    %rsi,%rdi
  sete   %al
  ret
```

assistant: ```c
int is_perfect(unsigned long n) {
  unsigned long i, sum = 0;
  for (i = 1; i < n; i++) {
    if (n % i == 0) {
      sum += i;
    }
  }
  return sum == n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<internal_print_hline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <con_printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L3:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <con_printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <con_printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D29
datatype: string

tool: D5:   +

tool: D3: ----

tool: D29: +


assistant: ```c
void internal_print_hline(int size) {
  int i;
  con_printf("  +");
  for (i = 0; i < size; i++) {
    con_printf("----");
  }
  con_printf("+\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<internal_print_hline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  call   <con_printf@plt>
  test   %ebp,%ebp
  jle    L7
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
L15:
  mov    %r12,%rdi
  call   <con_printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L15
L7:
  lea    D7(%rip),%rdi
  call   <con_printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D2
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D1:   +

tool: D2: ----

tool: D7: +


assistant: ```c
void internal_print_hline(int size) {
  int i;
  con_printf("  +");
  for (i = 0; i < size; i++) {
    con_printf("----");
  }
  con_printf("+\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<internal_print_hline>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D20(%rip),%rdi
  push   %rbx
  call   <con_printf@plt>
  test   %ebp,%ebp
  jle    L18
  xor    %ebx,%ebx
  lea    D24(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <con_printf@plt>
  cmp    %ebx,%ebp
  jne    L5
L18:
  pop    %rbx
  lea    D10(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <con_printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string

tool: D20:   +

tool: D24: ----

tool: D10: +


assistant: ```c
void internal_print_hline(int size) {
  int i;
  con_printf("  +");
  for (i = 0; i < size; i++) {
    con_printf("----");
  }
  con_printf("+\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<internal_print_hline>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D17(%rip),%rdi
  push   %rbx
  call   <con_printf@plt>
  test   %ebp,%ebp
  jle    L12
  xor    %ebx,%ebx
  lea    D0(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <con_printf@plt>
  cmp    %ebx,%ebp
  jne    L19
L12:
  pop    %rbx
  lea    D23(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <con_printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string
name: disassemble_data
arguments: data_label: D23
type_guessed: string

tool: D17:   +

tool: D0: ----

tool: D23: +


assistant: ```c
void internal_print_hline(int size) {
  int i;
  con_printf("  +");
  for (i = 0; i < size; i++) {
    con_printf("----");
  }
  con_printf("+\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<asn1_enc_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <asn1_get_enc_ptr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x10(%rax)
  mov    -0x8(%rbp),%rax
  movq   $0x0,0x8(%rax)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
L0:
  nop
  leave
  ret
```

assistant: ```c
void asn1_enc_init(ASN1_VALUE **pval, const ASN1_ITEM *it) {
  ASN1_ENCODING *enc;
  enc = asn1_get_enc_ptr(pval, it);
  if (enc) {
    enc->enc = NULL;
    enc->len = 0;
    enc->modified = 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<asn1_enc_init>:
  endbr64
  sub    $0x8,%rsp
  call   <asn1_get_enc_ptr@plt>
  test   %rax,%rax
  je     L6
  movq   $0x0,0x10(%rax)
  movq   $0x0,0x8(%rax)
  movl   $0x1,(%rax)
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void asn1_enc_init(ASN1_VALUE **pval, const ASN1_ITEM *it) {
  ASN1_ENCODING *enc;
  enc = asn1_get_enc_ptr(pval, it);
  if (enc) {
    enc->enc = NULL;
    enc->len = 0;
    enc->modified = 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<asn1_enc_init>:
  endbr64
  sub    $0x8,%rsp
  call   <asn1_get_enc_ptr@plt>
  test   %rax,%rax
  je     L8
  movq   $0x0,0x10(%rax)
  movq   $0x0,0x8(%rax)
  movl   $0x1,(%rax)
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void asn1_enc_init(ASN1_VALUE **pval, const ASN1_ITEM *it) {
  ASN1_ENCODING *enc;
  enc = asn1_get_enc_ptr(pval, it);
  if (enc) {
    enc->enc = NULL;
    enc->len = 0;
    enc->modified = 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<asn1_enc_init>:
  endbr64
  sub    $0x8,%rsp
  call   <asn1_get_enc_ptr@plt>
  test   %rax,%rax
  je     L6
  movq   $0x0,0x10(%rax)
  movq   $0x0,0x8(%rax)
  movl   $0x1,(%rax)
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void asn1_enc_init(ASN1_VALUE **pval, const ASN1_ITEM *it) {
  ASN1_ENCODING *enc;
  enc = asn1_get_enc_ptr(pval, it);
  if (enc) {
    enc->enc = NULL;
    enc->len = 0;
    enc->modified = 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stdlib_strided_dnansumors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jg     L14
  movsd  -0x18(%rbp),%xmm0
  jmp    L60
L14:
  cmpq   $0x1,-0x28(%rbp)
  je     L53
  cmpq   $0x0,-0x38(%rbp)
  jne    L95
L53:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <stdlib_base_is_nan@plt>
  test   %rax,%rax
  je     L64
  movsd  -0x18(%rbp),%xmm0
  jmp    L60
L64:
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  jmp    L60
L95:
  cmpq   $0x0,-0x38(%rbp)
  jns    L88
  mov    $0x1,%eax
  sub    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L21
L88:
  movq   $0x0,-0x10(%rbp)
L21:
  movq   $0x0,-0x8(%rbp)
  jmp    L25
L80:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <stdlib_base_is_nan@plt>
  test   %rax,%rax
  jne    L19
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L19:
  mov    -0x38(%rbp),%rax
  add    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L80
  movsd  -0x18(%rbp),%xmm0
L60:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double stdlib_strided_dnansumors(const int64_t N, const double *X, const int64_t stride) {
  double sum;
  int64_t ix;
  int64_t i;
  sum = 0.0;
  if (N <= 0) {
    return sum;
  }
  if (N == 1 || stride == 0) {
    if (stdlib_base_is_nan(X[0])) {
      return sum;
    }
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    if (!stdlib_base_is_nan(X[ix])) {
      sum += X[ix];
    }
    ix += stride;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stdlib_strided_dnansumors>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  jle    L4
  mov    %rdi,%r13
  mov    %rsi,%rbx
  cmp    $0x1,%rdi
  je     L104
  test   %rdx,%rdx
  je     L104
  mov    $0x0,%eax
  js     L85
L59:
  lea    0x0(,%rdx,8),%r12
  lea    (%rbx,%rax,8),%rbx
  mov    $0x0,%ebp
  mov    D7(%rip),%r14
  jmp    L23
L104:
  movsd  (%rbx),%xmm0
  call   <stdlib_base_is_nan@plt>
  mov    D7(%rip),%r14
  test   %rax,%rax
  jne    L18
  mov    (%rbx),%r14
  jmp    L18
L85:
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
  jmp    L59
L45:
  add    $0x1,%rbp
  add    %r12,%rbx
  cmp    %rbp,%r13
  je     L18
L23:
  movsd  (%rbx),%xmm0
  call   <stdlib_base_is_nan@plt>
  test   %rax,%rax
  jne    L45
  movq   %r14,%xmm1
  addsd  (%rbx),%xmm1
  movq   %xmm1,%r14
  jmp    L45
L4:
  mov    D7(%rip),%r14
L18:
  movq   %r14,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: f64

tool: D7: 0

assistant: ```c
double stdlib_strided_dnansumors(const int64_t N, const double *X, const int64_t stride) {
  double sum;
  int64_t ix;
  int64_t i;
  sum = 0.0;
  if (N <= 0) {
    return sum;
  }
  if (N == 1 || stride == 0) {
    if (stdlib_base_is_nan(X[0])) {
      return sum;
    }
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    if (!stdlib_base_is_nan(X[ix])) {
      sum += X[ix];
    }
    ix += stride;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<stdlib_strided_dnansumors>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  jle    L65
  mov    %rdi,%r13
  mov    %rsi,%rbx
  cmp    $0x1,%rdi
  je     L62
  test   %rdx,%rdx
  je     L62
  mov    $0x0,%eax
  jns    L48
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
L48:
  pxor   %xmm2,%xmm2
  lea    0x0(,%rdx,8),%r12
  lea    (%rbx,%rax,8),%rbx
  xor    %ebp,%ebp
  movq   %xmm2,%r14
L21:
  movsd  (%rbx),%xmm0
  call   <stdlib_base_is_nan@plt>
  test   %rax,%rax
  jne    L26
  movq   %r14,%xmm1
  addsd  (%rbx),%xmm1
  movq   %xmm1,%r14
L26:
  add    $0x1,%rbp
  add    %r12,%rbx
  cmp    %rbp,%r13
  jne    L21
  pop    %rbx
  movq   %r14,%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L62:
  movsd  (%rbx),%xmm0
  call   <stdlib_base_is_nan@plt>
  test   %rax,%rax
  je     L34
L65:
  pxor   %xmm3,%xmm3
  pop    %rbx
  pop    %rbp
  movq   %xmm3,%r14
  pop    %r12
  pop    %r13
  movq   %r14,%xmm0
  pop    %r14
  ret
  nopl   (%rax)
L34:
  movsd  (%rbx),%xmm4
  pop    %rbx
  pop    %rbp
  pop    %r12
  movq   %xmm4,%r14
  pop    %r13
  movq   %r14,%xmm0
  pop    %r14
  ret
```

assistant: ```c
double stdlib_strided_dnansumors(const int64_t N, const double *X, const int64_t stride) {
  double sum;
  int64_t ix;
  int64_t i;
  sum = 0.0;
  if (N <= 0) {
    return sum;
  }
  if (N == 1 || stride == 0) {
    if (stdlib_base_is_nan(X[0])) {
      return sum;
    }
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    if (!stdlib_base_is_nan(X[ix])) {
      sum += X[ix];
    }
    ix += stride;
  }
  return sum;
}
```