ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mapFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L3
  mov    -0x28(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
L3:
  cmpl   $0x0,-0xc(%rbp)
  jns    L20
  mov    $0x0,%eax
  jmp    L34
L20:
  lea    -0x10(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  cmpq   $0x0,-0x30(%rbp)
  je     L7
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L7:
  mov    D5(%rip),%rax
  mov    (%rax),%ecx
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%esi
  mov    $0x0,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
void *mapFile(const char *name, int flags, int *fileFD, unsigned int *fileSize) {
  int fd = open(name, flags);
  if (fileFD) {
    *fileFD = fd;
  }
  if (fd < 0) {
    return NULL;
  }
  struct stat fileStats;
  fstat(fd, &fileStats);
  if (fileSize) {
    *fileSize = fileStats.st_size;
  }
  return mmap(NULL, fileStats.st_size, PROT_READ, MAP_PRIVATE, fd, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mapFile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%ebx
  test   %rbp,%rbp
  je     L13
  mov    %eax,0x0(%rbp)
L13:
  mov    $0x0,%eax
  test   %ebx,%ebx
  js     L26
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edi
  call   <fstat@plt>
  test   %r12,%r12
  je     L38
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
L38:
  mov    $0x0,%r9d
  mov    %ebx,%r8d
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    0x4(%rsp),%esi
  mov    $0x0,%edi
  call   <mmap@plt>
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *mapFile(const char *name, int flags, int *fileFD, unsigned int *fileSize) {
  int fd = open(name, flags);
  if (fileFD) {
    *fileFD = fd;
  }
  if (fd < 0) {
    return NULL;
  }
  struct stat fileStats;
  fstat(fd, &fileStats);
  if (fileSize) {
    *fileSize = fileStats.st_size;
  }
  return mmap(NULL, fileStats.st_size, PROT_READ, MAP_PRIVATE, fd, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mapFile>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%ebx
  test   %rbp,%rbp
  je     L37
  mov    %eax,0x0(%rbp)
L37:
  xor    %eax,%eax
  test   %ebx,%ebx
  js     L38
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edi
  call   <fstat@plt>
  mov    0x4(%rsp),%esi
  test   %r12,%r12
  je     L18
  mov    %esi,(%r12)
L18:
  mov    D6(%rip),%rax
  xor    %r9d,%r9d
  mov    %ebx,%r8d
  xor    %edi,%edi
  mov    (%rax),%ecx
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  call   <mmap@plt>
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *mapFile(const char *name, int flags, int *fileFD, unsigned int *fileSize) {
  int fd = open(name, flags);
  if (fileFD) {
    *fileFD = fd;
  }
  if (fd < 0) {
    return NULL;
  }
  struct stat fileStats;
  fstat(fd, &fileStats);
  if (fileSize) {
    *fileSize = fileStats.st_size;
  }
  return mmap(NULL, fileStats.st_size, PROT_READ, MAP_PRIVATE, fd, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mapFile>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%ebx
  test   %rbp,%rbp
  je     L29
  mov    %eax,0x0(%rbp)
L29:
  xor    %eax,%eax
  test   %ebx,%ebx
  js     L21
  lea    0x4(%rsp),%rsi
  mov    %ebx,%edi
  call   <fstat@plt>
  mov    0x4(%rsp),%esi
  test   %r12,%r12
  je     L18
  mov    %esi,(%r12)
L18:
  mov    D18(%rip),%rax
  xor    %r9d,%r9d
  mov    %ebx,%r8d
  xor    %edi,%edi
  mov    (%rax),%ecx
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  call   <mmap@plt>
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *mapFile(const char *name, int flags, int *fileFD, unsigned int *fileSize) {
  int fd = open(name, flags);
  if (fileFD) {
    *fileFD = fd;
  }
  if (fd < 0) {
    return NULL;
  }
  struct stat fileStats;
  fstat(fd, &fileStats);
  if (fileSize) {
    *fileSize = fileStats.st_size;
  }
  return mmap(NULL, fileStats.st_size, PROT_READ, MAP_PRIVATE, fd, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ltoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  mov    $0x10,%edi
  call   <my_mallocc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string

tool: D15: string

tool: D10: %ld

assistant: ```c
char *ltoa(long in) {
  char *r = my_mallocc(16, "string");
  sprintf(r, "%ld", in);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ltoa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D4(%rip),%rsi
  mov    $0x10,%edi
  call   <my_mallocc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  lea    D17(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string

tool: D4: string

tool: D17: %ld

assistant: ```c
char *ltoa(long in) {
  char *r = my_mallocc(16, "string");
  sprintf(r, "%ld", in);
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ltoa>:
  endbr64
  push   %r13
  lea    D9(%rip),%rsi
  mov    %rdi,%r13
  mov    $0x10,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <my_mallocc@plt>
  mov    %r13,%rdx
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string

tool: D9: string

tool: D10: %ld

assistant: ```c
char *ltoa(long in) {
  char *r = my_mallocc(16, "string");
  sprintf(r, "%ld", in);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ltoa>:
  endbr64
  push   %r13
  lea    D13(%rip),%rsi
  mov    %rdi,%r13
  mov    $0x10,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <my_mallocc@plt>
  mov    %r13,%rdx
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D18
type: string

tool: D13: string

tool: D18: %ld

assistant: ```c
char *ltoa(long in) {
  char *r = my_mallocc(16, "string");
  sprintf(r, "%ld", in);
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<fir_highpass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movss  %xmm0,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L0:
  movss  -0x28(%rbp),%xmm0
  movss  D12(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x2c(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movaps %xmm0,%xmm2
  mulss  -0x28(%rbp),%xmm2
  movd   %xmm2,%eax
  movd   %eax,%xmm0
  call   <sinc@plt>
  movss  -0x2c(%rbp),%xmm1
  mulss  %xmm0,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  D16(%rip),%xmm0
  subss  -0x28(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x24(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_label: D16
type_infered: byte[4]

tool: {"D12": [0x00,0x00,0x00,0x80]}

tool: {"D16": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int fir_highpass(float *h, float *w, int N, float fc) {
  int i, j;
  int delay;
  assert(N & 1);
  delay = (N - 1) / 2;
  for (i = 0, j = N - 1; i <= delay; i++, j--) {
    h[i] = -(float)fc * sinc(fc * (i - delay)) * w[i];
    h[j] = h[i];
  }
  h[delay] = 1 - fc;
  return N;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fir_highpass>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %edx,%r15d
  movss  %xmm0,0x8(%rsp)
  mov    %edx,%edi
  and    $0x1,%edi
  call   <assert@plt>
  lea    -0x1(%r15),%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0xffffffff,%eax
  jl     L19
  cltq
  lea    0x0(%r13,%rax,4),%rbp
  mov    $0x0,%ebx
  movss  0x8(%rsp),%xmm3
  xorps  D9(%rip),%xmm3
  movss  %xmm3,0xc(%rsp)
L6:
  mov    %ebx,%eax
  sub    %r12d,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  0x8(%rsp),%xmm0
  call   <sinc@plt>
  mulss  0xc(%rsp),%xmm0
  mulss  (%r14,%rbx,4),%xmm0
  movss  %xmm0,0x0(%r13,%rbx,4)
  movss  %xmm0,0x0(%rbp)
  add    $0x1,%rbx
  sub    $0x4,%rbp
  cmp    %ebx,%r12d
  jge    L6
L19:
  movslq %r12d,%r12
  movss  D3(%rip),%xmm0
  subss  0x8(%rsp),%xmm0
  movss  %xmm0,0x0(%r13,%r12,4)
  mov    %r15d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: byte[16]
name: extract_symbolic_data
arguments: data_tag: D3
type: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int fir_highpass(float *h, float *w, int N, float fc) {
  int i, j;
  int delay;
  assert(N & 1);
  delay = (N - 1) / 2;
  for (i = 0, j = N - 1; i <= delay; i++, j--) {
    h[i] = -(float)fc * sinc(fc * (i - delay)) * w[i];
    h[j] = h[i];
  }
  h[delay] = 1 - fc;
  return N;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fir_highpass>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  and    $0x1,%edi
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <assert@plt>
  lea    -0x1(%r12),%eax
  mov    %eax,%r15d
  shr    $0x1f,%r15d
  add    %eax,%r15d
  sar    %r15d
  cmp    $0xffffffff,%eax
  jl     L10
  movss  0x8(%rsp),%xmm3
  xorps  D5(%rip),%xmm3
  cltq
  xor    %r13d,%r13d
  lea    (%rbx,%rax,4),%r14
  movss  %xmm3,0xc(%rsp)
  xchg   %ax,%ax
L11:
  mov    %r13d,%eax
  pxor   %xmm0,%xmm0
  sub    $0x4,%r14
  sub    %r15d,%eax
  cvtsi2ss %eax,%xmm0
  mulss  0x8(%rsp),%xmm0
  call   <sinc@plt>
  mulss  0xc(%rsp),%xmm0
  mulss  0x0(%rbp,%r13,4),%xmm0
  movss  %xmm0,(%rbx,%r13,4)
  add    $0x1,%r13
  movss  %xmm0,0x4(%r14)
  cmp    %r13d,%r15d
  jge    L11
L10:
  movss  D13(%rip),%xmm0
  movslq %r15d,%r15
  mov    %r12d,%eax
  subss  0x8(%rsp),%xmm0
  movss  %xmm0,(%rbx,%r15,4)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: byte[16]
name: parse_data
arguments: tag: D13
type_guessed: byte[4]

tool: {"D5": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int fir_highpass(float *h, float *w, int N, float fc) {
  int i, j;
  int delay;
  assert(N & 1);
  delay = (N - 1) / 2;
  for (i = 0, j = N - 1; i <= delay; i++, j--) {
    h[i] = -(float)fc * sinc(fc * (i - delay)) * w[i];
    h[j] = h[i];
  }
  h[delay] = 1 - fc;
  return N;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fir_highpass>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  and    $0x1,%edi
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <assert@plt>
  lea    -0x1(%r12),%eax
  mov    %eax,%r15d
  shr    $0x1f,%r15d
  add    %eax,%r15d
  sar    %r15d
  cmp    $0xffffffff,%eax
  jl     L17
  movss  0x8(%rsp),%xmm3
  xorps  D5(%rip),%xmm3
  cltq
  xor    %r13d,%r13d
  lea    (%rbx,%rax,4),%r14
  movss  %xmm3,0xc(%rsp)
  xchg   %ax,%ax
L5:
  mov    %r13d,%eax
  pxor   %xmm0,%xmm0
  sub    $0x4,%r14
  sub    %r15d,%eax
  cvtsi2ss %eax,%xmm0
  mulss  0x8(%rsp),%xmm0
  call   <sinc@plt>
  mulss  0xc(%rsp),%xmm0
  mulss  0x0(%rbp,%r13,4),%xmm0
  movss  %xmm0,(%rbx,%r13,4)
  add    $0x1,%r13
  movss  %xmm0,0x4(%r14)
  cmp    %r13d,%r15d
  jge    L5
L17:
  movss  D13(%rip),%xmm0
  movslq %r15d,%r15
  mov    %r12d,%eax
  subss  0x8(%rsp),%xmm0
  movss  %xmm0,(%rbx,%r15,4)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: byte[16]
name: disassemble_data
arguments: tag: D13
type_infered: byte[4]

tool: {"D5": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int fir_highpass(float *h, float *w, int N, float fc) {
  int i, j;
  int delay;
  assert(N & 1);
  delay = (N - 1) / 2;
  for (i = 0, j = N - 1; i <= delay; i++, j--) {
    h[i] = -(float)fc * sinc(fc * (i - delay)) * w[i];
    h[j] = h[i];
  }
  h[delay] = 1 - fc;
  return N;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x60(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <str_swap@plt>
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string
name: parse_data
arguments: data_label: D41
type: string
name: parse_data
arguments: data_label: D47
type: string
name: parse_data
arguments: data_label: D4
type: string
name: parse_data
arguments: data_label: D7
type: string

tool: D0: Input a string1: 

tool: D41: %s

tool: D47: Input a string2: 

tool: D4: string1: %s


tool: D7: string2: %s


assistant: ```c
int main() {
  char str1[80], str2[80];
  printf("Input a string1: ");
  scanf("%s", str1);
  printf("Input a string2: ");
  scanf("%s", str2);
  str_swap(str1, str2);
  printf("string1: %s\n", str1);
  printf("string2: %s\n", str2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  lea    D38(%rip),%r12
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x50(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <str_swap@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D38
datatype: string
name: read_data
arguments: label: D33
datatype: string
name: read_data
arguments: label: D1
datatype: string
name: read_data
arguments: label: D30
datatype: string

tool: D7: Input a string1: 

tool: D38: %s

tool: D33: Input a string2: 

tool: D1: string1: %s


tool: D30: string2: %s


assistant: ```c
int main() {
  char str1[80], str2[80];
  printf("Input a string1: ");
  scanf("%s", str1);
  printf("Input a string2: ");
  scanf("%s", str2);
  str_swap(str1, str2);
  printf("string1: %s\n", str1);
  printf("string2: %s\n", str2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D28(%rip),%rdi
  lea    D22(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x50(%rsp),%rbp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <str_swap@plt>
  mov    %r12,%rsi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D32
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D21
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string

tool: D28: Input a string1: 

tool: D22: %s

tool: D32: Input a string2: 

tool: D21: string1: %s


tool: D15: string2: %s


assistant: ```c
int main() {
  char str1[80], str2[80];
  printf("Input a string1: ");
  scanf("%s", str1);
  printf("Input a string2: ");
  scanf("%s", str2);
  str_swap(str1, str2);
  printf("string1: %s\n", str1);
  printf("string2: %s\n", str2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D44(%rip),%rdi
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x50(%rsp),%rbp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <str_swap@plt>
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D44
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D34
data_type: string
name: extract_symbolic_data
arguments: label: D7
data_type: string
name: extract_symbolic_data
arguments: label: D21
data_type: string

tool: D44: Input a string1: 

tool: D15: %s

tool: D34: Input a string2: 

tool: D7: string1: %s


tool: D21: string2: %s


assistant: ```c
int main() {
  char str1[80], str2[80];
  printf("Input a string1: ");
  scanf("%s", str1);
  printf("Input a string2: ");
  scanf("%s", str2);
  str_swap(str1, str2);
  printf("string1: %s\n", str1);
  printf("string2: %s\n", str2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isGET>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L11
  mov    $0x1,%eax
  jmp    L6
L11:
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: GET

assistant: ```c
isGET(char *req) {
  if (strstr(req, "GET") != NULL)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isGET>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: GET

assistant: ```c
isGET(char *req) {
  if (strstr(req, "GET") != NULL)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<isGET>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: GET

assistant: ```c
isGET(char *req) {
  if (strstr(req, "GET") != NULL)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isGET>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D2: GET

assistant: ```c
isGET(char *req) {
  if (strstr(req, "GET") != NULL)
    return 1;
  return 0;
}
```