ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D39(%rip),%r15
  push   %r14
  lea    D36(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D35(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  cmp    $0x1,%edi
  jle    L67
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L76
L32:
  mov    0x8(%rbx),%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L75
  mov    0x4(%rsp),%eax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  test   %eax,%eax
  lea    (%r12,%rax,1),%edx
  cmovs  %edx,%r12d
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L32
L76:
  mov    0x10(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  mov    %r12d,%ecx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  mov    0x8(%rbx),%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L67
  mov    0x4(%rsp),%eax
  lea    (%r12,%rax,1),%edx
  test   %eax,%eax
  cmovg  %edx,%r12d
  jmp    L54
L67:
  mov    $0x1,%eax
  jmp    L0
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D39
type_infered: string
name: disassemble_data
arguments: data_label: D36
type_infered: string
name: disassemble_data
arguments: data_label: D35
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string

tool: D39: pos

tool: D36: neg

tool: D35: %d

tool: D13: Sum of %s integers in %s is: %d

assistant: ```c
int main(int argc, char **argv) {
  int num, sum = 0;
  if (argc < 2) {
    return 1;
  }
  while (scanf("%d", &num) == 1) {
    if (strcmp("neg", argv[1]) == 0) {
      if (num < 0) {
        sum += num;
      }
    } else if (strcmp("pos", argv[1]) == 0) {
      if (num > 0) {
        sum += num;
      }
    } else {
      return 1;
    }
  }
  printf("Sum of %s integers in %s is: %d", argv[1], argv[2], sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rand_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x41c64e6d,%eax,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x3039,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0x10,%eax
  and    $0x7ff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x41c64e6d,%eax,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x3039,-0x8(%rbp)
  shll   $0xa,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0x10,%eax
  and    $0x3ff,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x41c64e6d,%eax,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x3039,-0x8(%rbp)
  shll   $0xa,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0x10,%eax
  and    $0x3ff,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rand_r(unsigned int *seed) {
  unsigned int next = *seed;
  int result;
  next *= 1103515245;
  next += 12345;
  result = (unsigned int)(next / 65536) % 2048;
  next *= 1103515245;
  next += 12345;
  result <<= 10;
  result ^= (unsigned int)(next / 65536) % 1024;
  next *= 1103515245;
  next += 12345;
  result <<= 10;
  result ^= (unsigned int)(next / 65536) % 1024;
  *seed = next;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rand_r>:
  endbr64
  imul   $0x41c64e6d,(%rdi),%edx
  add    $0x3039,%edx
  imul   $0x41c64e6d,%edx,%eax
  add    $0x3039,%eax
  shr    $0x6,%edx
  and    $0x1ffc00,%edx
  mov    %eax,%ecx
  shr    $0x10,%ecx
  and    $0x3ff,%ecx
  or     %ecx,%edx
  imul   $0x41c64e6d,%eax,%eax
  add    $0x3039,%eax
  shl    $0xa,%edx
  mov    %eax,(%rdi)
  shr    $0x10,%eax
  and    $0x3ff,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
int rand_r(unsigned int *seed) {
  unsigned int next = *seed;
  int result;
  next *= 1103515245;
  next += 12345;
  result = (unsigned int)(next / 65536) % 2048;
  next *= 1103515245;
  next += 12345;
  result <<= 10;
  result ^= (unsigned int)(next / 65536) % 1024;
  next *= 1103515245;
  next += 12345;
  result <<= 10;
  result ^= (unsigned int)(next / 65536) % 1024;
  *seed = next;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rand_r>:
  endbr64
  imul   $0x41c64e6d,(%rdi),%edx
  add    $0x3039,%edx
  imul   $0x41c64e6d,%edx,%eax
  shr    $0x6,%edx
  and    $0x1ffc00,%edx
  add    $0x3039,%eax
  mov    %eax,%ecx
  imul   $0x41c64e6d,%eax,%eax
  shr    $0x10,%ecx
  and    $0x3ff,%ecx
  add    $0x3039,%eax
  or     %ecx,%edx
  mov    %eax,(%rdi)
  shr    $0x10,%eax
  shl    $0xa,%edx
  and    $0x3ff,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
int rand_r(unsigned int *seed) {
  unsigned int next = *seed;
  int result;
  next *= 1103515245;
  next += 12345;
  result = (unsigned int)(next / 65536) % 2048;
  next *= 1103515245;
  next += 12345;
  result <<= 10;
  result ^= (unsigned int)(next / 65536) % 1024;
  next *= 1103515245;
  next += 12345;
  result <<= 10;
  result ^= (unsigned int)(next / 65536) % 1024;
  *seed = next;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<rand_r>:
  endbr64
  imul   $0x41c64e6d,(%rdi),%edx
  add    $0x3039,%edx
  imul   $0x41c64e6d,%edx,%eax
  shr    $0x6,%edx
  and    $0x1ffc00,%edx
  add    $0x3039,%eax
  mov    %eax,%ecx
  imul   $0x41c64e6d,%eax,%eax
  shr    $0x10,%ecx
  and    $0x3ff,%ecx
  add    $0x3039,%eax
  or     %ecx,%edx
  mov    %eax,(%rdi)
  shr    $0x10,%eax
  shl    $0xa,%edx
  and    $0x3ff,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
int rand_r(unsigned int *seed) {
  unsigned int next = *seed;
  int result;
  next *= 1103515245;
  next += 12345;
  result = (unsigned int)(next / 65536) % 2048;
  next *= 1103515245;
  next += 12345;
  result <<= 10;
  result ^= (unsigned int)(next / 65536) % 1024;
  next *= 1103515245;
  next += 12345;
  result <<= 10;
  result ^= (unsigned int)(next / 65536) % 1024;
  *seed = next;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<start_video_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <write_register@plt>
  mov    $0x400,%esi
  mov    $0x1,%edi
  call   <write_register@plt>
  mov    $0x300,%esi
  mov    $0x2,%edi
  call   <write_register@plt>
  mov    $0x20,%esi
  mov    $0x3,%edi
  call   <write_register@plt>
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <write_register@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void start_video_mode() {
  write_register(0x4, 0x00);
  write_register(0x1, 1024);
  write_register(0x2, 768);
  write_register(0x3, 32);
  write_register(0x4, 0x01);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<start_video_mode>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <write_register@plt>
  mov    $0x400,%esi
  mov    $0x1,%edi
  call   <write_register@plt>
  mov    $0x300,%esi
  mov    $0x2,%edi
  call   <write_register@plt>
  mov    $0x20,%esi
  mov    $0x3,%edi
  call   <write_register@plt>
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <write_register@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void start_video_mode() {
  write_register(0x4, 0x00);
  write_register(0x1, 1024);
  write_register(0x2, 768);
  write_register(0x3, 32);
  write_register(0x4, 0x01);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<start_video_mode>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x4,%edi
  call   <write_register@plt>
  mov    $0x400,%esi
  mov    $0x1,%edi
  call   <write_register@plt>
  mov    $0x300,%esi
  mov    $0x2,%edi
  call   <write_register@plt>
  mov    $0x20,%esi
  mov    $0x3,%edi
  call   <write_register@plt>
  mov    $0x1,%esi
  mov    $0x4,%edi
  add    $0x8,%rsp
  jmp    1050 <write_register@plt>
```

assistant: ```c
void start_video_mode() {
  write_register(0x4, 0x00);
  write_register(0x1, 1024);
  write_register(0x2, 768);
  write_register(0x3, 32);
  write_register(0x4, 0x01);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<start_video_mode>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x4,%edi
  call   <write_register@plt>
  mov    $0x400,%esi
  mov    $0x1,%edi
  call   <write_register@plt>
  mov    $0x300,%esi
  mov    $0x2,%edi
  call   <write_register@plt>
  mov    $0x20,%esi
  mov    $0x3,%edi
  call   <write_register@plt>
  mov    $0x1,%esi
  mov    $0x4,%edi
  add    $0x8,%rsp
  jmp    1050 <write_register@plt>
```

assistant: ```c
void start_video_mode() {
  write_register(0x4, 0x00);
  write_register(0x1, 1024);
  write_register(0x2, 768);
  write_register(0x3, 32);
  write_register(0x4, 0x01);
}
```
user: Translate the below assembly code into C programming language:

```asm
<replace_p>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x30000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0xd50,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x30d48(%rsp)
  xor    %eax,%eax
  lea    0x186a0(%rsp),%rdi
  call   <clear_string@plt>
  movzbl 0x0(%rbp),%edx
  cmp    $0x3e,%dl
  je     L8
  mov    $0x1,%eax
  lea    0x1869f(%rsp),%rcx
L10:
  mov    %dl,(%rcx,%rax,1)
  mov    %eax,%ebx
  add    $0x1,%rax
  movzbl -0x1(%rbp,%rax,1),%edx
  cmp    $0x3e,%dl
  jne    L10
L46:
  movslq %ebx,%rax
  movb   $0x3e,0x186a0(%rsp,%rax,1)
  lea    0x1(%rbx),%r13d
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <clear_string@plt>
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <itoa_my@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x0(%r13,%rax,1),%r12d
  lea    0x186a0(%rsp),%rdi
  mov    %r14,%rsi
  call   <strcat@plt>
  movslq %r12d,%rax
  movb   $0x0,0x186a0(%rsp,%rax,1)
  movslq %r13d,%rax
  cmpb   $0x3c,0x0(%rbp,%rax,1)
  je     L66
  lea    0x2(%rbx),%eax
  cltq
L92:
  mov    %eax,%r13d
  add    $0x1,%rax
  cmpb   $0x3c,-0x1(%rbp,%rax,1)
  jne    L92
L66:
  movslq %r13d,%r13
  add    %rbp,%r13
  movzbl 0x0(%r13),%edx
  mov    $0x0,%eax
  movslq %r12d,%r12
  lea    0x186a0(%rsp,%r12,1),%rcx
L81:
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  movzbl 0x0(%r13,%rax,1),%edx
  test   %dl,%dl
  jne    L81
  mov    %rbp,%rdi
  call   <clear_string@plt>
  movzbl 0x186a0(%rsp),%edx
  test   %dl,%dl
  je     L74
  mov    $0x0,%eax
L11:
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  movzbl 0x186a0(%rsp,%rax,1),%edx
  test   %dl,%dl
  jne    L11
L74:
  mov    0x30d48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30d50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    $0x0,%ebx
  jmp    L46
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void replace_p(int true_note, char string[100000]) {
  int i = 0;
  int j = 0;
  char note_string[100000];
  char full_string[100000];
  clear_string(full_string);
  while (string[i] != '>') {
    full_string[j] = string[i];
    i++;
    j++;
  };
  full_string[j] = string[i];
  i++;
  j++;
  clear_string(note_string);
  itoa_my(true_note, note_string);
  j += strlen(note_string);
  strcat(full_string, note_string);
  full_string[j] = '\0';
  while (string[i] != '<') {
    i++;
  };
  while (string[i] != '\0') {
    full_string[j] = string[i];
    j++;
    i++;
  };
  clear_string(string);
  i = 0;
  while (full_string[i] != '\0') {
    string[i] = full_string[i];
    i++;
  };
}
```
user: What is the c source code of the assembly code below:

```asm
<replace_p>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x30000(%rsp),%r11
L96:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L96
  sub    $0xd68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30d58(%rsp)
  xor    %eax,%eax
  lea    0x186b0(%rsp),%r12
  mov    %rsi,%rbx
  mov    %edi,%r14d
  mov    %r12,%rdi
  call   <clear_string@plt>
  movzbl (%rbx),%edx
  cmp    $0x3e,%dl
  je     L54
  mov    $0x1,%eax
  lea    0x186af(%rsp),%rsi
L93:
  mov    %dl,(%rsi,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl -0x1(%rbx,%rax,1),%edx
  cmp    $0x3e,%dl
  jne    L93
  lea    0x1(%rcx),%ebp
  movslq %ebp,%rax
  mov    %ebp,%r13d
  mov    %rax,0x8(%rsp)
L89:
  lea    0x10(%rsp),%r15
  movb   $0x3e,0x186b0(%rsp,%rcx,1)
  mov    %r15,%rdi
  call   <clear_string@plt>
  mov    %r15,%rsi
  mov    %r14d,%edi
  call   <itoa_my@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  add    %eax,%r13d
  call   <strcat@plt>
  movslq %r13d,%rax
  movb   $0x0,0x186b0(%rsp,%rax,1)
  mov    0x8(%rsp),%rax
  cmpb   $0x3c,(%rbx,%rax,1)
  je     L33
  lea    0x1(%rbp),%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %eax,%ebp
  add    $0x1,%rax
  cmpb   $0x3c,-0x1(%rbx,%rax,1)
  jne    L26
L33:
  movslq %ebp,%rbp
  mov    %r13d,%ecx
  xor    %eax,%eax
  mov    $0x3c,%edx
  add    %r12,%rcx
  add    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L68
  mov    %rbx,%rdi
  call   <clear_string@plt>
  movzbl 0x186b0(%rsp),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L45
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  movzbl (%r12,%rax,1),%edx
  test   %dl,%dl
  jne    L31
L45:
  mov    0x30d58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x30d68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L54:
  movq   $0x1,0x8(%rsp)
  mov    $0x1,%r13d
  mov    $0x1,%ebp
  xor    %ecx,%ecx
  jmp    L89
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void replace_p(int true_note, char string[100000]) {
  int i = 0;
  int j = 0;
  char note_string[100000];
  char full_string[100000];
  clear_string(full_string);
  while (string[i] != '>') {
    full_string[j] = string[i];
    i++;
    j++;
  };
  full_string[j] = string[i];
  i++;
  j++;
  clear_string(note_string);
  itoa_my(true_note, note_string);
  j += strlen(note_string);
  strcat(full_string, note_string);
  full_string[j] = '\0';
  while (string[i] != '<') {
    i++;
  };
  while (string[i] != '\0') {
    full_string[j] = string[i];
    j++;
    i++;
  };
  clear_string(string);
  i = 0;
  while (full_string[i] != '\0') {
    string[i] = full_string[i];
    i++;
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<replace_p>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x30000(%rsp),%r11
L55:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L55
  sub    $0xd68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30d58(%rsp)
  xor    %eax,%eax
  lea    0x186b0(%rsp),%r12
  mov    %rsi,%rbx
  mov    %edi,%r14d
  mov    %r12,%rdi
  call   <clear_string@plt>
  movzbl (%rbx),%edx
  cmp    $0x3e,%dl
  je     L82
  mov    $0x1,%eax
  lea    0x186af(%rsp),%rsi
L43:
  mov    %dl,(%rsi,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl -0x1(%rbx,%rax,1),%edx
  cmp    $0x3e,%dl
  jne    L43
  lea    0x1(%rcx),%ebp
  movslq %ebp,%rax
  mov    %ebp,%r13d
  mov    %rax,0x8(%rsp)
L36:
  lea    0x10(%rsp),%r15
  movb   $0x3e,0x186b0(%rsp,%rcx,1)
  mov    %r15,%rdi
  call   <clear_string@plt>
  mov    %r15,%rsi
  mov    %r14d,%edi
  call   <itoa_my@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  add    %eax,%r13d
  call   <strcat@plt>
  movslq %r13d,%rax
  movb   $0x0,0x186b0(%rsp,%rax,1)
  mov    0x8(%rsp),%rax
  cmpb   $0x3c,(%rbx,%rax,1)
  je     L54
  lea    0x1(%rbp),%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L93:
  mov    %eax,%ebp
  add    $0x1,%rax
  cmpb   $0x3c,-0x1(%rbx,%rax,1)
  jne    L93
L54:
  movslq %ebp,%rbp
  mov    %r13d,%ecx
  xor    %eax,%eax
  mov    $0x3c,%edx
  add    %r12,%rcx
  add    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L5
  mov    %rbx,%rdi
  call   <clear_string@plt>
  movzbl 0x186b0(%rsp),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L56
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  movzbl (%r12,%rax,1),%edx
  test   %dl,%dl
  jne    L19
L56:
  mov    0x30d58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x30d68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L82:
  movq   $0x1,0x8(%rsp)
  mov    $0x1,%r13d
  mov    $0x1,%ebp
  xor    %ecx,%ecx
  jmp    L36
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void replace_p(int true_note, char string[100000]) {
  int i = 0;
  int j = 0;
  char note_string[100000];
  char full_string[100000];
  clear_string(full_string);
  while (string[i] != '>') {
    full_string[j] = string[i];
    i++;
    j++;
  };
  full_string[j] = string[i];
  i++;
  j++;
  clear_string(note_string);
  itoa_my(true_note, note_string);
  j += strlen(note_string);
  strcat(full_string, note_string);
  full_string[j] = '\0';
  while (string[i] != '<') {
    i++;
  };
  while (string[i] != '\0') {
    full_string[j] = string[i];
    j++;
    i++;
  };
  clear_string(string);
  i = 0;
  while (full_string[i] != '\0') {
    string[i] = full_string[i];
    i++;
  };
}
```
user: What is the c source code of the assembly code below?

```asm
<print_prime_cut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L0
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  jmp    L70
L0:
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
L70:
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L65
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L71
L65:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L58
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  add    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,-0x4(%rbp)
  jmp    L71
L58:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  add    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,-0x4(%rbp)
  jmp    L71
L11:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L71:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5:  %d

assistant: ```c
void print_prime_cut(int primes[], int num_primes, int C) {
  int i, j;
  C = (num_primes & 0x1) ? (2 * C - 1) : (2 * C);
  if (C >= num_primes) {
    i = 0;
    j = num_primes - 1;
  } else if (num_primes & 0x1) {
    i = j = num_primes / 2;
    i = i - (C - 1) / 2;
    j = j + (C - 1) / 2;
  } else {
    i = num_primes / 2 - 1;
    j = num_primes / 2;
    i = i - (C - 2) / 2;
    j = j + (C - 2) / 2;
  }
  for (; i <= j; i++) {
    printf(" %d", primes[i]);
  }
  printf("\n");
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_prime_cut>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  test   $0x1,%sil
  je     L34
  add    %edx,%edx
  cmp    %esi,%edx
  jg     L19
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  add    %esi,%ebp
  sar    %ebp
  sub    $0x2,%edx
  sar    %edx
  neg    %edx
  lea    (%rdx,%rbp,1),%eax
  sub    %edx,%ebp
  jmp    L23
L34:
  add    %edx,%edx
  cmp    %edx,%esi
  jg     L7
L19:
  lea    -0x1(%rsi),%ebp
  mov    $0x0,%eax
L23:
  movslq %eax,%rbx
  lea    D5(%rip),%r13
  cmp    %ebp,%eax
  jg     L17
L55:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L55
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  add    %esi,%ebp
  sar    %ebp
  sub    $0x2,%edx
  sar    %edx
  neg    %edx
  lea    -0x1(%rbp,%rdx,1),%eax
  sub    %edx,%ebp
  jmp    L23
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5:  %d

assistant: ```c
void print_prime_cut(int primes[], int num_primes, int C) {
  int i, j;
  C = (num_primes & 0x1) ? (2 * C - 1) : (2 * C);
  if (C >= num_primes) {
    i = 0;
    j = num_primes - 1;
  } else if (num_primes & 0x1) {
    i = j = num_primes / 2;
    i = i - (C - 1) / 2;
    j = j + (C - 1) / 2;
  } else {
    i = num_primes / 2 - 1;
    j = num_primes / 2;
    i = i - (C - 2) / 2;
    j = j + (C - 2) / 2;
  }
  for (; i <= j; i++) {
    printf(" %d", primes[i]);
  }
  printf("\n");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_prime_cut>:
  endbr64
  push   %r13
  add    %edx,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   $0x1,%sil
  je     L34
  cmp    %edx,%esi
  jge    L33
L4:
  lea    -0x1(%rsi),%ebp
  xor    %eax,%eax
L11:
  movslq %eax,%rbx
  lea    D4(%rip),%r13
  cmp    %ebp,%eax
  jg     L40
L24:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L24
L40:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L34:
  cmp    %edx,%esi
  jle    L4
  mov    %esi,%ebp
  sub    $0x2,%edx
  shr    $0x1f,%ebp
  sar    %edx
  add    %esi,%ebp
  neg    %edx
  sar    %ebp
  lea    -0x1(%rbp,%rdx,1),%eax
  sub    %edx,%ebp
  jmp    L11
  nopl   0x0(%rax)
L33:
  mov    %esi,%ebp
  sub    $0x2,%edx
  shr    $0x1f,%ebp
  sar    %edx
  add    %esi,%ebp
  neg    %edx
  sar    %ebp
  lea    (%rdx,%rbp,1),%eax
  sub    %edx,%ebp
  jmp    L11
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4:  %d

assistant: ```c
void print_prime_cut(int primes[], int num_primes, int C) {
  int i, j;
  C = (num_primes & 0x1) ? (2 * C - 1) : (2 * C);
  if (C >= num_primes) {
    i = 0;
    j = num_primes - 1;
  } else if (num_primes & 0x1) {
    i = j = num_primes / 2;
    i = i - (C - 1) / 2;
    j = j + (C - 1) / 2;
  } else {
    i = num_primes / 2 - 1;
    j = num_primes / 2;
    i = i - (C - 2) / 2;
    j = j + (C - 2) / 2;
  }
  for (; i <= j; i++) {
    printf(" %d", primes[i]);
  }
  printf("\n");
  return;
}
```