ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<compare_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdi,%rdi
  je     L99
  test   %rsi,%rsi
  je     L99
L2:
  mov    %rbx,%rax
  mov    %rbp,%r8
  mov    $0x0,%edi
  mov    $0x0,%esi
  mov    $0x1,%r9d
  jmp    L59
L99:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L2
L98:
  add    $0x1,%rax
  mov    %r9d,%esi
  jmp    L45
L36:
  cmpb   $0x2a,0x1(%rax)
  jne    L31
  add    $0x2,%rax
  mov    %r9d,%esi
  jmp    L45
L35:
  mov    %r8,%rdx
  sub    %rbp,%rdx
  test   %edi,%edi
  cmove  %edx,%edi
  add    $0x1,%rax
L113:
  add    $0x1,%r8
L45:
  cmpb   $0x0,(%rax)
  je     L137
L59:
  movzbl (%r8),%ecx
  test   %cl,%cl
  je     L13
  movzbl (%rax),%edx
  cmp    $0x2a,%dl
  je     L98
  cmp    $0x5c,%dl
  je     L36
L31:
  cmp    %cl,%dl
  je     L35
  test   %esi,%esi
  cmove  %esi,%edi
  cmove  %rbx,%rax
  jmp    L113
L137:
  sub    %rbp,%r8
  mov    %edi,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L13:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L83:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D3
type_infered: string

tool: D12: invalid string of NULL.

tool: D21: %s is substring to %s, start_index=%d, end_index=%d


tool: D3: %s is not substring to %s


assistant: ```c
void compare_string(char *str1, char *str2) {
  char *pstr1_tmp = str1;
  char *pstr2_tmp = str2;
  uint8_t star_mode_on = 0;
  uint16_t start_index = 0;
  if (str1 == NULL || str2 == NULL) {
    printf("invalid string of NULL.\n");
  }
  while (*pstr1_tmp != '\0') {
    if (*pstr2_tmp == '*') {
      star_mode_on = 1;
      pstr2_tmp += 1;
    } else if (*pstr2_tmp == '\\' && *(pstr2_tmp + 1) == '*') {
      star_mode_on = 1;
      pstr2_tmp += 2;
    } else {
      if (*pstr2_tmp == *pstr1_tmp) {
        if (start_index == 0) {
          start_index = pstr1_tmp - str1;
        }
        pstr2_tmp += 1;
      } else {
        if (star_mode_on == 0) {
          start_index = 0;
          pstr2_tmp = str2;
        }
      }
      pstr1_tmp += 1;
    }
    if (*pstr2_tmp == '\0') {
      printf("%s is substring to %s, start_index=%d, end_index=%d\n", str2, str1, start_index, pstr1_tmp - str1);
      return;
    }
  }
  printf("%s is not substring to %s\n", str2, str1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compare_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L105
  test   %rsi,%rsi
  je     L105
L74:
  mov    %rbp,%rdx
  mov    %r12,%r8
  xor    %r9d,%r9d
  xor    %esi,%esi
  jmp    L4
L101:
  cmp    $0x5c,%al
  je     L18
L92:
  cmp    %cl,%al
  je     L6
  test   %esi,%esi
  jne    L130
  movzbl 0x0(%rbp),%eax
  xor    %r9d,%r9d
  mov    %rbp,%rdx
L130:
  add    $0x1,%r8
L39:
  test   %al,%al
  je     L46
L4:
  movzbl (%r8),%ecx
  test   %cl,%cl
  je     L5
  movzbl (%rdx),%eax
  cmp    $0x2a,%al
  jne    L101
  movzbl 0x1(%rdx),%eax
  mov    $0x1,%esi
  add    $0x1,%rdx
  test   %al,%al
  jne    L4
L46:
  add    $0x8,%rsp
  sub    %r12,%r8
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r9d,%ecx
  pop    %rbp
  lea    D25(%rip),%rdi
  pop    %r12
  jmp    1070 <printf@plt>
  nopl   (%rax)
L18:
  cmpb   $0x2a,0x1(%rdx)
  jne    L92
  movzbl 0x2(%rdx),%eax
  mov    $0x1,%esi
  add    $0x2,%rdx
  jmp    L39
  nopl   (%rax)
L6:
  mov    %r8,%rax
  sub    %r12,%rax
  test   %r9d,%r9d
  cmove  %eax,%r9d
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  jmp    L130
  nop
L5:
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  pop    %rbp
  lea    D27(%rip),%rdi
  pop    %r12
  jmp    1070 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L105:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  jmp    L74
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D27
type_infered: string
name: extract_symbolic_data
arguments: tag: D21
type_infered: string

tool: D25: %s is substring to %s, start_index=%d, end_index=%d


tool: D27: %s is not substring to %s


tool: D21: invalid string of NULL.

assistant: ```c
void compare_string(char *str1, char *str2) {
  char *pstr1_tmp = str1;
  char *pstr2_tmp = str2;
  uint8_t star_mode_on = 0;
  uint16_t start_index = 0;
  if (str1 == NULL || str2 == NULL) {
    printf("invalid string of NULL.\n");
  }
  while (*pstr1_tmp != '\0') {
    if (*pstr2_tmp == '*') {
      star_mode_on = 1;
      pstr2_tmp += 1;
    } else if (*pstr2_tmp == '\\' && *(pstr2_tmp + 1) == '*') {
      star_mode_on = 1;
      pstr2_tmp += 2;
    } else {
      if (*pstr2_tmp == *pstr1_tmp) {
        if (start_index == 0) {
          start_index = pstr1_tmp - str1;
        }
        pstr2_tmp += 1;
      } else {
        if (star_mode_on == 0) {
          start_index = 0;
          pstr2_tmp = str2;
        }
      }
      pstr1_tmp += 1;
    }
    if (*pstr2_tmp == '\0') {
      printf("%s is substring to %s, start_index=%d, end_index=%d\n", str2, str1, start_index, pstr1_tmp - str1);
      return;
    }
  }
  printf("%s is not substring to %s\n", str2, str1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compare_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L27
  test   %rsi,%rsi
  je     L27
L94:
  mov    %rbp,%rdx
  mov    %r12,%r8
  xor    %r9d,%r9d
  xor    %esi,%esi
  jmp    L72
L101:
  cmp    $0x5c,%al
  je     L11
L110:
  cmp    %cl,%al
  je     L31
  test   %esi,%esi
  jne    L76
  movzbl 0x0(%rbp),%eax
  xor    %r9d,%r9d
  mov    %rbp,%rdx
L76:
  add    $0x1,%r8
L74:
  test   %al,%al
  je     L108
L72:
  movzbl (%r8),%ecx
  test   %cl,%cl
  je     L18
  movzbl (%rdx),%eax
  cmp    $0x2a,%al
  jne    L101
  movzbl 0x1(%rdx),%eax
  mov    $0x1,%esi
  add    $0x1,%rdx
  test   %al,%al
  jne    L72
L108:
  add    $0x8,%rsp
  sub    %r12,%r8
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r9d,%ecx
  pop    %rbp
  lea    D18(%rip),%rdi
  pop    %r12
  jmp    1070 <printf@plt>
  nopl   (%rax)
L11:
  cmpb   $0x2a,0x1(%rdx)
  jne    L110
  movzbl 0x2(%rdx),%eax
  mov    $0x1,%esi
  add    $0x2,%rdx
  jmp    L74
  nopl   (%rax)
L31:
  mov    %r8,%rax
  sub    %r12,%rax
  test   %r9d,%r9d
  cmove  %eax,%r9d
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  jmp    L76
  nop
L18:
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  pop    %rbp
  lea    D17(%rip),%rdi
  pop    %r12
  jmp    1070 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L27:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L94
```

tool_calls: name: parse_data
arguments: data_label: D18
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D19
type_infered: string

tool: D18: %s is substring to %s, start_index=%d, end_index=%d


tool: D17: %s is not substring to %s


tool: D19: invalid string of NULL.

assistant: ```c
void compare_string(char *str1, char *str2) {
  char *pstr1_tmp = str1;
  char *pstr2_tmp = str2;
  uint8_t star_mode_on = 0;
  uint16_t start_index = 0;
  if (str1 == NULL || str2 == NULL) {
    printf("invalid string of NULL.\n");
  }
  while (*pstr1_tmp != '\0') {
    if (*pstr2_tmp == '*') {
      star_mode_on = 1;
      pstr2_tmp += 1;
    } else if (*pstr2_tmp == '\\' && *(pstr2_tmp + 1) == '*') {
      star_mode_on = 1;
      pstr2_tmp += 2;
    } else {
      if (*pstr2_tmp == *pstr1_tmp) {
        if (start_index == 0) {
          start_index = pstr1_tmp - str1;
        }
        pstr2_tmp += 1;
      } else {
        if (star_mode_on == 0) {
          start_index = 0;
          pstr2_tmp = str2;
        }
      }
      pstr1_tmp += 1;
    }
    if (*pstr2_tmp == '\0') {
      printf("%s is substring to %s, start_index=%d, end_index=%d\n", str2, str1, start_index, pstr1_tmp - str1);
      return;
    }
  }
  printf("%s is not substring to %s\n", str2, str1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<func_2e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x14,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_infered: string
name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D14: func_2e : %d >> 

tool: D5: %d


assistant: ```c
void func_2e(int const **const i) {
  printf("func_2e : %d >> ", **i);
  {
    int const *bkup = *i;
    int x = 20;
    int const *y = &x;
    *i = y;
    printf("%d\n", **i);
    *i = bkup;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func_2e>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  mov    (%rax),%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rbp
  movl   $0x14,0x4(%rsp)
  lea    0x4(%rsp),%rax
  mov    %rax,(%rbx)
  mov    $0x14,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string

tool: D13: func_2e : %d >> 

tool: D14: %d


assistant: ```c
void func_2e(int const **const i) {
  printf("func_2e : %d >> ", **i);
  {
    int const *bkup = *i;
    int x = 20;
    int const *y = &x;
    *i = y;
    printf("%d\n", **i);
    *i = bkup;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func_2e>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  lea    D6(%rip),%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  lea    0x4(%rsp),%rax
  mov    (%rbx),%rbp
  mov    $0x14,%esi
  mov    %rax,(%rbx)
  lea    D16(%rip),%rdi
  movl   $0x14,0x4(%rsp)
  call   <printf@plt>
  mov    %rbp,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string

tool: D6: func_2e : %d >> 

tool: D16: %d


assistant: ```c
void func_2e(int const **const i) {
  printf("func_2e : %d >> ", **i);
  {
    int const *bkup = *i;
    int x = 20;
    int const *y = &x;
    *i = y;
    printf("%d\n", **i);
    *i = bkup;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func_2e>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  lea    D18(%rip),%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  lea    0x4(%rsp),%rax
  mov    (%rbx),%rbp
  mov    $0x14,%esi
  mov    %rax,(%rbx)
  lea    D17(%rip),%rdi
  movl   $0x14,0x4(%rsp)
  call   <printf@plt>
  mov    %rbp,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D17
data_type: string

tool: D18: func_2e : %d >> 

tool: D17: %d


assistant: ```c
void func_2e(int const **const i) {
  printf("func_2e : %d >> ", **i);
  {
    int const *bkup = *i;
    int x = 20;
    int const *y = &x;
    *i = y;
    printf("%d\n", **i);
    *i = bkup;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L17:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x14(%rbp)
L0:
  cmpl   $0x0,-0x14(%rbp)
  jg     L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fact(int n) {
  int r = 1;
  while (n > 0) {
    r *= n;
    n--;
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fact>:
  endbr64
  test   %edi,%edi
  jle    L4
  mov    $0x1,%eax
L14:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L14
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fact(int n) {
  int r = 1;
  while (n > 0) {
    r *= n;
    n--;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jle    L8
  nopl   (%rax)
L9:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L9
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
int fact(int n) {
  int r = 1;
  while (n > 0) {
    r *= n;
    n--;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jle    L9
  nopl   (%rax)
L19:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L19
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
int fact(int n) {
  int r = 1;
  while (n > 0) {
    r *= n;
    n--;
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sunpackf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsunpackf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void sunpackf(const void *buffer, const char *format, ...) {
  va_list args;
  va_start(args, format);
  vsunpackf(buffer, format, args);
  va_end(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sunpackf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsunpackf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sunpackf(const void *buffer, const char *format, ...) {
  va_list args;
  va_start(args, format);
  vsunpackf(buffer, format, args);
  va_end(args);
}
```
user: What is the c source code of the assembly code below?

```asm
<sunpackf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vsunpackf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sunpackf(const void *buffer, const char *format, ...) {
  va_list args;
  va_start(args, format);
  vsunpackf(buffer, format, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sunpackf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vsunpackf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sunpackf(const void *buffer, const char *format, ...) {
  va_list args;
  va_start(args, format);
  vsunpackf(buffer, format, args);
  va_end(args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  mov    $0x1,%eax
  jmp    L49
L11:
  mov    $0x0,%eax
L49:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L17
L10:
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  and    $0x3ff,%eax
  mov    %eax,-0x10(%rbp)
L17:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L10
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int hash(char *name) {
  char *s;
  int c, k;
  assert(name && *name);
  s = name;
  k = *s;
  while ((c = (int)*(++s)) != 0)
    k = (31 * k + c) & (1024 - 1);
  return (k);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  test   %rbx,%rbx
  je     L4
  cmpb   $0x0,(%rbx)
  setne  %dil
  movzbl %dil,%edi
L4:
  call   <assert@plt>
  movsbl (%rbx),%eax
  lea    0x1(%rbx),%rsi
  movsbl 0x1(%rbx),%ecx
  test   %ecx,%ecx
  je     L12
L9:
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  lea    (%rdx,%rcx,1),%eax
  and    $0x3ff,%eax
  add    $0x1,%rsi
  movsbl (%rsi),%ecx
  test   %ecx,%ecx
  jne    L9
L12:
  pop    %rbx
  ret
```

assistant: ```c
int hash(char *name) {
  char *s;
  int c, k;
  assert(name && *name);
  s = name;
  k = *s;
  while ((c = (int)*(++s)) != 0)
    k = (31 * k + c) & (1024 - 1);
  return (k);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  je     L17
  xor    %edi,%edi
  cmpb   $0x0,(%rbx)
  setne  %dil
L17:
  call   <assert@plt>
  movsbl 0x1(%rbx),%ecx
  movsbl (%rbx),%eax
  lea    0x1(%rbx),%rsi
  test   %ecx,%ecx
  je     L10
  nopl   0x0(%rax)
L28:
  mov    %eax,%edx
  add    $0x1,%rsi
  shl    $0x5,%edx
  sub    %eax,%edx
  lea    (%rdx,%rcx,1),%eax
  movsbl (%rsi),%ecx
  and    $0x3ff,%eax
  test   %ecx,%ecx
  jne    L28
L10:
  pop    %rbx
  ret
```

assistant: ```c
int hash(char *name) {
  char *s;
  int c, k;
  assert(name && *name);
  s = name;
  k = *s;
  while ((c = (int)*(++s)) != 0)
    k = (31 * k + c) & (1024 - 1);
  return (k);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  je     L3
  xor    %edi,%edi
  cmpb   $0x0,(%rbx)
  setne  %dil
L3:
  call   <assert@plt>
  movsbl 0x1(%rbx),%ecx
  movsbl (%rbx),%eax
  lea    0x1(%rbx),%rsi
  test   %ecx,%ecx
  je     L11
  nopl   0x0(%rax)
L24:
  mov    %eax,%edx
  add    $0x1,%rsi
  shl    $0x5,%edx
  sub    %eax,%edx
  lea    (%rdx,%rcx,1),%eax
  movsbl (%rsi),%ecx
  and    $0x3ff,%eax
  test   %ecx,%ecx
  jne    L24
L11:
  pop    %rbx
  ret
```

assistant: ```c
int hash(char *name) {
  char *s;
  int c, k;
  assert(name && *name);
  s = name;
  k = *s;
  while ((c = (int)*(++s)) != 0)
    k = (31 * k + c) & (1024 - 1);
  return (k);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SendByteIR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L24
L36:
  movsbl -0x1(%rbp),%eax
  mov    $0x7,%edx
  sub    %eax,%edx
  movsbl -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <BitIsClr@plt>
  test   %rax,%rax
  je     L23
  mov    $0x1,%edi
  call   <SendBitIR@plt>
  mov    $0x0,%edi
  call   <SendBitIR@plt>
  jmp    L35
L23:
  mov    $0x1,%edi
  call   <SendBitIR@plt>
  mov    $0x0,%edi
  call   <SendBitIR@plt>
  mov    $0x0,%edi
  call   <SendBitIR@plt>
  mov    $0x0,%edi
  call   <SendBitIR@plt>
L35:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L24:
  cmpb   $0x7,-0x1(%rbp)
  jle    L36
  nop
  nop
  leave
  ret
```

assistant: ```c
void SendByteIR(char Byte) {
  for (char i = 0; i <= 7; i++) {
    if (BitIsClr(Byte, 7 - i)) {
      SendBitIR(1);
      SendBitIR(0);
    } else {
      SendBitIR(1);
      SendBitIR(0);
      SendBitIR(0);
      SendBitIR(0);
    };
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SendByteIR>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x7,%ebx
  movsbl %dil,%ebp
  jmp    L11
L17:
  mov    $0x1,%edi
  call   <SendBitIR@plt>
  mov    $0x0,%edi
  call   <SendBitIR@plt>
  mov    $0x0,%edi
  call   <SendBitIR@plt>
  mov    $0x0,%edi
  call   <SendBitIR@plt>
L8:
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L25
L11:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <BitIsClr@plt>
  test   %rax,%rax
  je     L17
  mov    $0x1,%edi
  call   <SendBitIR@plt>
  mov    $0x0,%edi
  call   <SendBitIR@plt>
  jmp    L8
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SendByteIR(char Byte) {
  for (char i = 0; i <= 7; i++) {
    if (BitIsClr(Byte, 7 - i)) {
      SendBitIR(1);
      SendBitIR(0);
    } else {
      SendBitIR(1);
      SendBitIR(0);
      SendBitIR(0);
      SendBitIR(0);
    };
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SendByteIR>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  mov    $0x7,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebp,%edi
  mov    %ebx,%esi
  call   <BitIsClr@plt>
  mov    $0x1,%edi
  test   %rax,%rax
  jne    L15
  call   <SendBitIR@plt>
  xor    %edi,%edi
  call   <SendBitIR@plt>
  xor    %edi,%edi
L15:
  call   <SendBitIR@plt>
  xor    %edi,%edi
  call   <SendBitIR@plt>
  sub    $0x1,%ebx
  jae    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SendByteIR(char Byte) {
  for (char i = 0; i <= 7; i++) {
    if (BitIsClr(Byte, 7 - i)) {
      SendBitIR(1);
      SendBitIR(0);
    } else {
      SendBitIR(1);
      SendBitIR(0);
      SendBitIR(0);
      SendBitIR(0);
    };
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SendByteIR>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  mov    $0x7,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%edi
  mov    %ebx,%esi
  call   <BitIsClr@plt>
  mov    $0x1,%edi
  test   %rax,%rax
  jne    L4
  call   <SendBitIR@plt>
  xor    %edi,%edi
  call   <SendBitIR@plt>
  xor    %edi,%edi
L4:
  call   <SendBitIR@plt>
  xor    %edi,%edi
  call   <SendBitIR@plt>
  sub    $0x1,%ebx
  jae    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SendByteIR(char Byte) {
  for (char i = 0; i <= 7; i++) {
    if (BitIsClr(Byte, 7 - i)) {
      SendBitIR(1);
      SendBitIR(0);
    } else {
      SendBitIR(1);
      SendBitIR(0);
      SendBitIR(0);
      SendBitIR(0);
    };
  }
}
```