ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_method_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L31:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L48
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L56
L48:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L10
  addl   $0x1,-0x4(%rbp)
L5:
  cmpq   $0x0,-0x18(%rbp)
  je     L43
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  jmp    L43
L10:
  nop
L43:
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L56:
  leave
  ret
```

assistant: ```c
void get_method_path(const char *p, const char **method, unsigned *methodl, const char **path) {
  unsigned i;
  for (i = 0; p && p[i]; i++) {
    if (p[i] == ':') {
      *method = p;
      *methodl = ++i;
      *path = p + i;
      return;
    }
    if (!isalpha((int)(unsigned char)p[i]))
      break;
  }
  *method = 0;
  *methodl = 0;
  *path = p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_method_path>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    $0x0,%ebx
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L48
L7:
  mov    %ebx,%eax
  movzbl 0x0(%rbp,%rax,1),%edi
  test   %dil,%dil
  je     L46
  cmp    $0x3a,%dil
  je     L10
  movzbl %dil,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L2
  add    $0x1,%ebx
  jmp    L7
L10:
  add    $0x1,%ebx
  mov    %ebx,%edx
  mov    %rbp,%rax
  lea    0x0(%rbp,%rdx,1),%rbp
  jmp    L48
L46:
  mov    $0x0,%eax
  mov    $0x0,%ebx
L48:
  mov    %rax,(%r14)
  mov    %ebx,0x0(%r13)
  mov    %rbp,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  mov    $0x0,%eax
  mov    $0x0,%ebx
  jmp    L48
```

assistant: ```c
void get_method_path(const char *p, const char **method, unsigned *methodl, const char **path) {
  unsigned i;
  for (i = 0; p && p[i]; i++) {
    if (p[i] == ':') {
      *method = p;
      *methodl = ++i;
      *path = p + i;
      return;
    }
    if (!isalpha((int)(unsigned char)p[i]))
      break;
  }
  *method = 0;
  *methodl = 0;
  *path = p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_method_path>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  jne    L36
  jmp    L8
  nopl   0x0(%rax)
L19:
  cmp    $0x3a,%dil
  je     L7
  call   <isalpha@plt>
  test   %eax,%eax
  je     L34
  add    $0x1,%r14d
L36:
  mov    %r14d,%eax
  movzbl (%rbx,%rax,1),%edi
  test   %dil,%dil
  jne    L19
L34:
  xor    %eax,%eax
  xor    %r14d,%r14d
L8:
  mov    %rax,0x0(%r13)
  mov    %r14d,(%r12)
  mov    %rbx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  lea    0x1(%r14),%edx
  mov    %rbx,%rax
  mov    %rdx,%r14
  add    %rdx,%rbx
  jmp    L8
```

assistant: ```c
void get_method_path(const char *p, const char **method, unsigned *methodl, const char **path) {
  unsigned i;
  for (i = 0; p && p[i]; i++) {
    if (p[i] == ':') {
      *method = p;
      *methodl = ++i;
      *path = p + i;
      return;
    }
    if (!isalpha((int)(unsigned char)p[i]))
      break;
  }
  *method = 0;
  *methodl = 0;
  *path = p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_method_path>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  jne    L56
  jmp    L21
  nopl   0x0(%rax)
L13:
  cmp    $0x3a,%dil
  je     L28
  call   <isalpha@plt>
  test   %eax,%eax
  je     L30
  add    $0x1,%r14d
L56:
  mov    %r14d,%eax
  movzbl (%rbx,%rax,1),%edi
  test   %dil,%dil
  jne    L13
L30:
  xor    %eax,%eax
  xor    %r14d,%r14d
L21:
  mov    %rax,0x0(%r13)
  mov    %r14d,(%r12)
  mov    %rbx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L28:
  lea    0x1(%r14),%edx
  mov    %rbx,%rax
  mov    %rdx,%r14
  add    %rdx,%rbx
  jmp    L21
```

assistant: ```c
void get_method_path(const char *p, const char **method, unsigned *methodl, const char **path) {
  unsigned i;
  for (i = 0; p && p[i]; i++) {
    if (p[i] == ':') {
      *method = p;
      *methodl = ++i;
      *path = p + i;
      return;
    }
    if (!isalpha((int)(unsigned char)p[i]))
      break;
  }
  *method = 0;
  *methodl = 0;
  *path = p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x4,%edi
  call   <omp_set_num_threads@plt>
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  mov    $0x0,%ebx
  lea    D9(%rip),%r12
  jmp    L6
L14:
  add    $0x1,%ebx
L6:
  test   %ebx,%ebx
  jne    L14
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <omp_get_num_procs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: parse_data
arguments: label: D9
type: string

tool: D9: 
 Nombre de proc=%d, Nombre de threads=%d


assistant: ```c
int main(int argc, const char *argv[]) {
  static long num_steps = 10000000000;
  int i, nthreads;
  double pi;
  double step;
  double x;
  double sum = 0.0;
  step = (1.0 / (double)num_steps);
  omp_set_num_threads(4);
  double wtime;
  wtime = omp_get_wtime();
#pragma omp parallel for reduction(+ : sum) private(x)
  for (i = 0; i <= num_steps; i++) {
    if (i == 0)
      printf("\n Nombre de proc=%d, Nombre de threads=%d\n", omp_get_num_procs(), omp_get_num_threads());
    x = (double)((double)i + 0.5) * step;
    sum += 4.0 / (1.0 + x * x);
  }
  pi = step * sum;
  wtime = omp_get_wtime() - wtime;
  printf(" Elapsed wall clock time = %f with %ld steps\n", wtime, num_steps);
  printf(" \n Calcul Serie Pi = %f\n", pi);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x8,%rsp
  call   <omp_set_num_threads@plt>
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_procs@plt>
  pxor   %xmm0,%xmm0
  mov    %ebp,%esi
  mov    %rbx,%rdi
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: 
 Nombre de proc=%d, Nombre de threads=%d


assistant: ```c
int main(int argc, const char *argv[]) {
  static long num_steps = 10000000000;
  int i, nthreads;
  double pi;
  double step;
  double x;
  double sum = 0.0;
  step = (1.0 / (double)num_steps);
  omp_set_num_threads(4);
  double wtime;
  wtime = omp_get_wtime();
#pragma omp parallel for reduction(+ : sum) private(x)
  for (i = 0; i <= num_steps; i++) {
    if (i == 0)
      printf("\n Nombre de proc=%d, Nombre de threads=%d\n", omp_get_num_procs(), omp_get_num_threads());
    x = (double)((double)i + 0.5) * step;
    sum += 4.0 / (1.0 + x * x);
  }
  pi = step * sum;
  wtime = omp_get_wtime() - wtime;
  printf(" Elapsed wall clock time = %f with %ld steps\n", wtime, num_steps);
  printf(" \n Calcul Serie Pi = %f\n", pi);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x8,%rsp
  call   <omp_set_num_threads@plt>
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_procs@plt>
  pxor   %xmm0,%xmm0
  mov    %ebp,%esi
  mov    %rbx,%rdi
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D7: 
 Nombre de proc=%d, Nombre de threads=%d


assistant: ```c
int main(int argc, const char *argv[]) {
  static long num_steps = 10000000000;
  int i, nthreads;
  double pi;
  double step;
  double x;
  double sum = 0.0;
  step = (1.0 / (double)num_steps);
  omp_set_num_threads(4);
  double wtime;
  wtime = omp_get_wtime();
#pragma omp parallel for reduction(+ : sum) private(x)
  for (i = 0; i <= num_steps; i++) {
    if (i == 0)
      printf("\n Nombre de proc=%d, Nombre de threads=%d\n", omp_get_num_procs(), omp_get_num_threads());
    x = (double)((double)i + 0.5) * step;
    sum += 4.0 / (1.0 + x * x);
  }
  pi = step * sum;
  wtime = omp_get_wtime() - wtime;
  printf(" Elapsed wall clock time = %f with %ld steps\n", wtime, num_steps);
  printf(" \n Calcul Serie Pi = %f\n", pi);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ringPath>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %ecx,%ebx
  mov    %r8d,0xc(%rsp)
  mov    %r9,%rbp
  mov    0x50(%rsp),%r12
  lea    0x0(,%rdi,4),%r15d
  mov    %r15d,%edx
  mov    $0xffffffff,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r15d,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  movslq 0xc(%rsp),%rax
  movl   $0x1,0x0(%rbp,%rax,4)
  lea    0x0(%r13,%rax,4),%r8
  cmpl   $0x0,(%r8)
  jle    L31
  lea    (%r14,%rax,8),%r9
  mov    $0x0,%edx
  mov    $0x1,%eax
  mov    $0x0,%esi
  jmp    L125
L16:
  add    $0x1,%rdx
  cmp    %edx,(%r8)
  jle    L61
L125:
  mov    (%r9),%rcx
  mov    (%rcx,%rdx,4),%ecx
  cmp    %ecx,%ebx
  je     L16
  movslq %ecx,%rdi
  movl   $0x1,0x0(%rbp,%rdi,4)
  add    $0x1,%eax
  movslq %esi,%rdi
  mov    %ecx,(%r12,%rdi,4)
  add    $0x1,%esi
  jmp    L16
L31:
  mov    $0x1,%eax
  mov    $0x0,%esi
L61:
  mov    (%r12),%edx
  cmp    $0xffffffff,%edx
  je     L108
  lea    0x4(%r12),%r10
L40:
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%r8
  cmpl   $0x0,(%r8)
  jle    L51
  lea    (%r14,%rdx,8),%r9
  mov    $0x0,%edx
  jmp    L133
L120:
  movslq %ebx,%rbx
  movl   $0x1,0x0(%rbp,%rbx,4)
  add    $0x1,%eax
L1:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L135:
  add    $0x1,%rdx
  cmp    %edx,(%r8)
  jle    L51
L133:
  mov    (%r9),%rcx
  mov    (%rcx,%rdx,4),%ecx
  cmp    %ebx,%ecx
  je     L120
  movslq %ecx,%rdi
  lea    0x0(%rbp,%rdi,4),%rdi
  cmpl   $0x0,(%rdi)
  jne    L135
  movl   $0x1,(%rdi)
  add    $0x1,%eax
  movslq %esi,%rdi
  mov    %ecx,(%r12,%rdi,4)
  add    $0x1,%esi
  jmp    L135
L51:
  add    $0x4,%r10
  mov    -0x4(%r10),%edx
  cmp    $0xffffffff,%edx
  jne    L40
  mov    $0x0,%eax
  jmp    L1
L108:
  mov    $0x0,%eax
  jmp    L1
```

assistant: ```c
int ringPath(int nbAtoms, int *nBonds, int **bonds, int at1, int at2, int *seen, int *buf) {
  int i, jdex, k, kb, kdex;
  int rs = 0;
  memset(buf, -1, sizeof(int) * nbAtoms);
  memset(seen, 0, sizeof(int) * nbAtoms);
  seen[at2] = 1;
  rs++;
  kb = 0;
  for (i = 0; i < nBonds[at2]; i++) {
    jdex = bonds[at2][i];
    if (jdex != at1) {
      seen[jdex] = 1;
      rs++;
      buf[kb] = jdex;
      ++kb;
    }
  }
  k = 0;
  while ((jdex = buf[k]) != -1) {
    ++k;
    for (i = 0; i < nBonds[jdex]; i++) {
      kdex = bonds[jdex][i];
      if (kdex == at1) {
        seen[at1] = 1;
        rs++;
        return rs;
      }
      if (!seen[kdex]) {
        seen[kdex] = 1;
        rs++;
        buf[kb] = kdex;
        ++kb;
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ringPath>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  mov    %rdx,%rbp
  lea    0x0(,%rdi,4),%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xffffffff,%esi
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r14
  mov    %edx,0xc(%rsp)
  mov    %r14,%rdi
  call   <memset@plt>
  mov    0xc(%rsp),%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  movslq %r15d,%r8
  movl   $0x1,0x0(%r13,%r8,4)
  lea    (%rbx,%r8,4),%r9
  mov    (%r9),%eax
  test   %eax,%eax
  jle    L48
  mov    0x0(%rbp,%r8,8),%r8
  xor    %edx,%edx
  mov    $0x1,%eax
  xor    %esi,%esi
  nopl   (%rax)
L77:
  mov    (%r8,%rdx,4),%ecx
  cmp    %ecx,%r12d
  je     L40
  movslq %ecx,%rdi
  add    $0x1,%eax
  movl   $0x1,0x0(%r13,%rdi,4)
  movslq %esi,%rdi
  add    $0x1,%esi
  mov    %ecx,(%r14,%rdi,4)
L40:
  add    $0x1,%rdx
  cmp    %edx,(%r9)
  jg     L77
L73:
  movslq (%r14),%rdx
  cmp    $0xffffffff,%edx
  je     L50
  lea    0x4(%r14),%r10
L14:
  lea    (%rbx,%rdx,4),%r8
  mov    (%r8),%r15d
  test   %r15d,%r15d
  jle    L9
  mov    0x0(%rbp,%rdx,8),%r9
  xor    %edx,%edx
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L6:
  movslq %ecx,%rdi
  lea    0x0(%r13,%rdi,4),%rdi
  mov    (%rdi),%r11d
  test   %r11d,%r11d
  jne    L100
  movl   $0x1,(%rdi)
  movslq %esi,%rdi
  add    $0x1,%eax
  add    $0x1,%esi
  mov    %ecx,(%r14,%rdi,4)
L100:
  add    $0x1,%rdx
  cmp    %edx,(%r8)
  jle    L9
L56:
  mov    (%r9,%rdx,4),%ecx
  cmp    %r12d,%ecx
  jne    L6
  movl   $0x1,0x0(%r13,%r12,4)
  add    $0x18,%rsp
  add    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  movslq (%r10),%rdx
  add    $0x4,%r10
  cmp    $0xffffffff,%edx
  jne    L14
L50:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L48:
  mov    $0x1,%eax
  xor    %esi,%esi
  jmp    L73
```

assistant: ```c
int ringPath(int nbAtoms, int *nBonds, int **bonds, int at1, int at2, int *seen, int *buf) {
  int i, jdex, k, kb, kdex;
  int rs = 0;
  memset(buf, -1, sizeof(int) * nbAtoms);
  memset(seen, 0, sizeof(int) * nbAtoms);
  seen[at2] = 1;
  rs++;
  kb = 0;
  for (i = 0; i < nBonds[at2]; i++) {
    jdex = bonds[at2][i];
    if (jdex != at1) {
      seen[jdex] = 1;
      rs++;
      buf[kb] = jdex;
      ++kb;
    }
  }
  k = 0;
  while ((jdex = buf[k]) != -1) {
    ++k;
    for (i = 0; i < nBonds[jdex]; i++) {
      kdex = bonds[jdex][i];
      if (kdex == at1) {
        seen[at1] = 1;
        rs++;
        return rs;
      }
      if (!seen[kdex]) {
        seen[kdex] = 1;
        rs++;
        buf[kb] = kdex;
        ++kb;
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ringPath>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  mov    %rdx,%rbp
  lea    0x0(,%rdi,4),%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xffffffff,%esi
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r14
  mov    %edx,0xc(%rsp)
  mov    %r14,%rdi
  call   <memset@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  movslq %r15d,%r8
  movl   $0x1,0x0(%r13,%r8,4)
  lea    (%rbx,%r8,4),%r9
  mov    (%r9),%edi
  test   %edi,%edi
  jle    L132
  mov    0x0(%rbp,%r8,8),%r8
  xor    %edx,%edx
  mov    $0x1,%eax
  xor    %esi,%esi
  nopl   (%rax)
L33:
  mov    (%r8,%rdx,4),%ecx
  cmp    %ecx,%r12d
  je     L120
  movslq %ecx,%rdi
  add    $0x1,%rdx
  add    $0x1,%eax
  movl   $0x1,0x0(%r13,%rdi,4)
  movslq %esi,%rdi
  add    $0x1,%esi
  mov    %ecx,(%r14,%rdi,4)
  mov    (%r9),%edi
  cmp    %edx,%edi
  jg     L33
L42:
  movslq (%r14),%rdx
  lea    0x4(%r14),%r10
  cmp    $0xffffffff,%edx
  je     L19
L69:
  lea    (%rbx,%rdx,4),%r8
  mov    (%r8),%r15d
  test   %r15d,%r15d
  jle    L110
  mov    0x0(%rbp,%rdx,8),%r9
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L137:
  mov    (%r9,%rdx,4),%ecx
  cmp    %r12d,%ecx
  je     L34
L4:
  movslq %ecx,%rdi
  lea    0x0(%r13,%rdi,4),%rdi
  mov    (%rdi),%r11d
  test   %r11d,%r11d
  jne    L82
  movl   $0x1,(%rdi)
  movslq %esi,%rdi
  add    $0x1,%eax
  add    $0x1,%esi
  mov    %ecx,(%r14,%rdi,4)
  add    $0x1,%rdx
  cmp    %edx,(%r8)
  jg     L137
L110:
  movslq (%r10),%rdx
  add    $0x4,%r10
  cmp    $0xffffffff,%edx
  jne    L69
L19:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L82:
  add    $0x1,%rdx
  cmp    %edx,(%r8)
  jle    L110
  mov    (%r9,%rdx,4),%ecx
  cmp    %r12d,%ecx
  jne    L4
L34:
  movl   $0x1,0x0(%r13,%r12,4)
  add    $0x18,%rsp
  add    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L120:
  add    $0x1,%rdx
  cmp    %edx,%edi
  jg     L33
  jmp    L42
L132:
  mov    $0x1,%eax
  xor    %esi,%esi
  jmp    L42
```

assistant: ```c
int ringPath(int nbAtoms, int *nBonds, int **bonds, int at1, int at2, int *seen, int *buf) {
  int i, jdex, k, kb, kdex;
  int rs = 0;
  memset(buf, -1, sizeof(int) * nbAtoms);
  memset(seen, 0, sizeof(int) * nbAtoms);
  seen[at2] = 1;
  rs++;
  kb = 0;
  for (i = 0; i < nBonds[at2]; i++) {
    jdex = bonds[at2][i];
    if (jdex != at1) {
      seen[jdex] = 1;
      rs++;
      buf[kb] = jdex;
      ++kb;
    }
  }
  k = 0;
  while ((jdex = buf[k]) != -1) {
    ++k;
    for (i = 0; i < nBonds[jdex]; i++) {
      kdex = bonds[jdex][i];
      if (kdex == at1) {
        seen[at1] = 1;
        rs++;
        return rs;
      }
      if (!seen[kdex]) {
        seen[kdex] = 1;
        rs++;
        buf[kb] = kdex;
        ++kb;
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<significand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <ilogb@plt>
  neg    %rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <__ieee754_scalb@plt>
  nop
  leave
  ret
```

assistant: ```c
void significand(double x, double *result) {
  __ieee754_scalb(x, (double)-ilogb(x), result);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<significand>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  mov    %rdi,%rbp
  call   <ilogb@plt>
  neg    %rax
  mov    %rbp,%rdi
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %rbx,%xmm0
  call   <__ieee754_scalb@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void significand(double x, double *result) {
  __ieee754_scalb(x, (double)-ilogb(x), result);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<significand>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ilogb@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  neg    %rax
  mov    %rbp,%rdi
  pop    %rbp
  cvtsi2sd %rax,%xmm1
  jmp    1060 <__ieee754_scalb@plt>
```

assistant: ```c
void significand(double x, double *result) {
  __ieee754_scalb(x, (double)-ilogb(x), result);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<significand>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ilogb@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  neg    %rax
  mov    %rbp,%rdi
  pop    %rbp
  cvtsi2sd %rax,%xmm1
  jmp    1060 <__ieee754_scalb@plt>
```

assistant: ```c
void significand(double x, double *result) {
  __ieee754_scalb(x, (double)-ilogb(x), result);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <console_write@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
  nop
  leave
  ret
```

assistant: ```c
void output(const char *msg) {
  console_write(msg);
  uart_puts(msg);
}
```
user: What is the c source code of the assembly code below:

```asm
<output>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <console_write@plt>
  mov    %rbx,%rdi
  call   <uart_puts@plt>
  pop    %rbx
  ret
```

assistant: ```c
void output(const char *msg) {
  console_write(msg);
  uart_puts(msg);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <console_write@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <uart_puts@plt>
```

assistant: ```c
void output(const char *msg) {
  console_write(msg);
  uart_puts(msg);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <console_write@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <uart_puts@plt>
```

assistant: ```c
void output(const char *msg) {
  console_write(msg);
  uart_puts(msg);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clearScreen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L19:
  mov    $0x8,%edi
  call   <printChar@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  mov    $0x8,%edi
  call   <printChar@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x7cf,-0x4(%rbp)
  jle    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void clearScreen(void) {
  int i;
  for (i = 0; i < 80 * 25; i++) {
    printChar(0x08);
    printChar(0x20);
    printChar(0x08);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clearScreen>:
  endbr64
  push   %rbx
  mov    $0x7d0,%ebx
L8:
  mov    $0x8,%edi
  call   <printChar@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  mov    $0x8,%edi
  call   <printChar@plt>
  sub    $0x1,%ebx
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void clearScreen(void) {
  int i;
  for (i = 0; i < 80 * 25; i++) {
    printChar(0x08);
    printChar(0x20);
    printChar(0x08);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clearScreen>:
  endbr64
  push   %rbx
  mov    $0x7d0,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x8,%edi
  call   <printChar@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  mov    $0x8,%edi
  call   <printChar@plt>
  sub    $0x1,%ebx
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void clearScreen(void) {
  int i;
  for (i = 0; i < 80 * 25; i++) {
    printChar(0x08);
    printChar(0x20);
    printChar(0x08);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clearScreen>:
  endbr64
  push   %rbx
  mov    $0x7d0,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x8,%edi
  call   <printChar@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  mov    $0x8,%edi
  call   <printChar@plt>
  sub    $0x1,%ebx
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
void clearScreen(void) {
  int i;
  for (i = 0; i < 80 * 25; i++) {
    printChar(0x08);
    printChar(0x20);
    printChar(0x08);
  }
}
```