ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<fork>:
  endbr64
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t fork(void) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fork>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t fork(void) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fork>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t fork(void) {
  errno = ENOSYS;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<findNumbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rdx
  shl    $0x2,%rdx
  lea    0xf(%rdx),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L3:
  cmp    %rcx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L3
L18:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L38
  orq    $0x0,-0x8(%rsp,%rax,1)
L38:
  lea    0x3(%rsp),%rcx
  mov    %rcx,%r9
  shr    $0x2,%r9
  and    $0xfffffffffffffffc,%rcx
  mov    (%rdi),%esi
  mov    %esi,%eax
  add    -0x4(%rdi,%rdx,1),%eax
  mov    %eax,%edx
  sub    0x4(%rdi),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,0x4(,%r9,4)
  sub    %eax,%esi
  mov    %esi,0x0(,%r9,4)
  cmp    $0x3,%r8d
  jle    L59
  lea    -0x4(%r8),%esi
  add    $0x2,%rsi
  mov    $0x1,%eax
L37:
  mov    (%rdi,%rax,4),%edx
  sub    (%rcx),%edx
  mov    %edx,0x4(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L37
L59:
  test   %r8d,%r8d
  jle    L66
  mov    %rcx,%rbx
  mov    %r8d,%r8d
  lea    (%rcx,%r8,4),%r13
  lea    D8(%rip),%r12
L5:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L5
L66:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: %d 

assistant: ```c
void findNumbers(int array[], int n) {
  int num[n];
  int b_minus_a = array[n - 1] - array[1];
  num[1] = (array[0] + b_minus_a) / 2;
  num[0] = array[0] - num[1];
  int i;
  for (i = 1; i < (n - 2); ++i)
    num[i + 1] = array[i] - num[0];
  for (int i = 0; i < n; ++i)
    printf("%d ", num[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findNumbers>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  mov    %rdi,%rcx
  mov    %rdx,%r9
  shl    $0x2,%rdx
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rsp,%rdi
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rsi
  cmp    %rdi,%rsp
  je     L38
L25:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L25
L38:
  and    $0xfff,%esi
  sub    %rsi,%rsp
  test   %rsi,%rsi
  jne    L48
L85:
  mov    (%rcx),%esi
  mov    -0x4(%rcx,%rdx,1),%eax
  lea    0x3(%rsp),%rdi
  mov    %rdi,%r8
  and    $0xfffffffffffffffc,%rdi
  add    %esi,%eax
  shr    $0x2,%r8
  mov    %eax,%edx
  sub    0x4(%rcx),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  sub    %eax,%esi
  mov    %eax,0x4(,%r8,4)
  mov    %esi,0x0(,%r8,4)
  cmp    $0x3,%r9d
  jle    L47
  lea    -0x4(%r9),%r8d
  mov    $0x1,%eax
  add    $0x2,%r8
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%rcx,%rax,4),%edx
  sub    %esi,%edx
  mov    %edx,0x4(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L26
L47:
  test   %r9d,%r9d
  jle    L94
  mov    %r9d,%r9d
  lea    0x4(%rdi),%rbx
  lea    D2(%rip),%r12
  lea    (%rdi,%r9,4),%r13
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%esi
  add    $0x4,%rbx
L40:
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L1
L94:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L48:
  orq    $0x0,-0x8(%rsp,%rsi,1)
  jmp    L85
L92:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
void findNumbers(int array[], int n) {
  int num[n];
  int b_minus_a = array[n - 1] - array[1];
  num[1] = (array[0] + b_minus_a) / 2;
  num[0] = array[0] - num[1];
  int i;
  for (i = 1; i < (n - 2); ++i)
    num[i + 1] = array[i] - num[0];
  for (int i = 0; i < n; ++i)
    printf("%d ", num[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findNumbers>:
  endbr64
  push   %rbp
  movslq %esi,%rsi
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  shl    $0x2,%rsi
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%rsi),%rax
  mov    %rsp,%r8
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rdi
  cmp    %r8,%rsp
  je     L80
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L21
L80:
  and    $0xfff,%edi
  sub    %rdi,%rsp
  test   %rdi,%rdi
  jne    L78
L37:
  mov    (%rdx),%edi
  mov    -0x4(%rdx,%rsi,1),%eax
  lea    0x3(%rsp),%rbx
  lea    -0x2(%rcx),%r9d
  mov    %rbx,%r8
  and    $0xfffffffffffffffc,%rbx
  add    %edi,%eax
  shr    $0x2,%r8
  mov    %eax,%esi
  sub    0x4(%rdx),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  sub    %eax,%edi
  movd   %eax,%xmm3
  movd   %edi,%xmm0
  punpckldq %xmm3,%xmm0
  movq   %xmm0,0x0(,%r8,4)
  cmp    $0x1,%r9d
  jle    L137
  lea    -0x4(%rcx),%eax
  lea    -0x3(%rcx),%r8d
  cmp    $0x2,%eax
  jbe    L116
  mov    %r8d,%esi
  movd   %edi,%xmm2
  xor    %eax,%eax
  shr    $0x2,%esi
  pshufd $0x0,%xmm2,%xmm1
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L79:
  movdqu 0x4(%rdx,%rax,1),%xmm0
  psubd  %xmm1,%xmm0
  movups %xmm0,0x8(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L79
  mov    %r8d,%esi
  and    $0xfffffffc,%esi
  lea    0x1(%rsi),%eax
  cmp    %esi,%r8d
  je     L137
L124:
  movslq %eax,%rsi
  lea    0x0(,%rsi,4),%r10
  mov    (%rdx,%rsi,4),%esi
  lea    (%rbx,%r10,1),%r8
  sub    %edi,%esi
  mov    %esi,0x4(%r8)
  lea    0x1(%rax),%esi
  cmp    %r9d,%esi
  jge    L137
  mov    0x4(%rdx,%r10,1),%esi
  add    $0x2,%eax
  sub    %edi,%esi
  mov    %esi,0x8(%r8)
  cmp    %eax,%r9d
  jle    L137
  mov    0x8(%rdx,%r10,1),%eax
  sub    %edi,%eax
  mov    %eax,0xc(%r8)
L137:
  test   %ecx,%ecx
  jle    L26
  mov    %ecx,%ecx
  lea    D2(%rip),%r12
  lea    (%rbx,%rcx,4),%r13
  nopl   (%rax)
L125:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L125
L26:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L78:
  orq    $0x0,-0x8(%rsp,%rdi,1)
  jmp    L37
L116:
  mov    $0x1,%eax
  jmp    L124
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: %d 

assistant: ```c
void findNumbers(int array[], int n) {
  int num[n];
  int b_minus_a = array[n - 1] - array[1];
  num[1] = (array[0] + b_minus_a) / 2;
  num[0] = array[0] - num[1];
  int i;
  for (i = 1; i < (n - 2); ++i)
    num[i + 1] = array[i] - num[0];
  for (int i = 0; i < n; ++i)
    printf("%d ", num[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1c200,%edi
  call   <serial_init@plt>
  mov    $0x0,%eax
  call   <fp_enable@plt>
  mov    $0x0,%eax
  call   <arm_float@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: Done


assistant: ```c
void test_float(void) {
  int reg;
  serial_init(115200);
  fp_enable();
  arm_float();
  puts("Done\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_float>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1c200,%edi
  call   <serial_init@plt>
  mov    $0x0,%eax
  call   <fp_enable@plt>
  mov    $0x0,%eax
  call   <arm_float@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: Done


assistant: ```c
void test_float(void) {
  int reg;
  serial_init(115200);
  fp_enable();
  arm_float();
  puts("Done\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_float>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1c200,%edi
  call   <serial_init@plt>
  xor    %eax,%eax
  call   <fp_enable@plt>
  xor    %eax,%eax
  call   <arm_float@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string

tool: D1: Done


assistant: ```c
void test_float(void) {
  int reg;
  serial_init(115200);
  fp_enable();
  arm_float();
  puts("Done\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_float>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1c200,%edi
  call   <serial_init@plt>
  xor    %eax,%eax
  call   <fp_enable@plt>
  xor    %eax,%eax
  call   <arm_float@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: Done


assistant: ```c
void test_float(void) {
  int reg;
  serial_init(115200);
  fp_enable();
  arm_float();
  puts("Done\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<touchmanager_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <touchmanager_detach_all@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int touchmanager_init() {
  touchmanager_detach_all();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<touchmanager_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <touchmanager_detach_all@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int touchmanager_init() {
  touchmanager_detach_all();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<touchmanager_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <touchmanager_detach_all@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int touchmanager_init() {
  touchmanager_detach_all();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<touchmanager_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <touchmanager_detach_all@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int touchmanager_init() {
  touchmanager_detach_all();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clockget>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D5(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: f64

tool: D5: 1e-06

assistant: ```c
double clockget() {
  struct timeval tv2;
  double dt;
  gettimeofday(&tv2, (struct timezone *)0);
  dt = ((tv2).tv_sec + 0.000001 * (tv2).tv_usec);
  return (dt);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clockget>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  movsd  D8(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: f64

tool: D8: 1e-06

assistant: ```c
double clockget() {
  struct timeval tv2;
  double dt;
  gettimeofday(&tv2, (struct timezone *)0);
  dt = ((tv2).tv_sec + 0.000001 * (tv2).tv_usec);
  return (dt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clockget>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  D5(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: f64

tool: D5: 1e-06

assistant: ```c
double clockget() {
  struct timeval tv2;
  double dt;
  gettimeofday(&tv2, (struct timezone *)0);
  dt = ((tv2).tv_sec + 0.000001 * (tv2).tv_usec);
  return (dt);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clockget>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  D9(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: f64

tool: D9: 1e-06

assistant: ```c
double clockget() {
  struct timeval tv2;
  double dt;
  gettimeofday(&tv2, (struct timezone *)0);
  dt = ((tv2).tv_sec + 0.000001 * (tv2).tv_usec);
  return (dt);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x2,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x18(%rbp)
  jmp    L21
L45:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x18(%rbp)
L21:
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jle    L45
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  movl   $0x2,-0x18(%rbp)
  jmp    L9
L11:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L28
L39:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L39
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L11
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *getRow(int rowIndex, int *returnSize) {
  int *a = (int *)malloc((rowIndex + 2) * sizeof(int));
  *returnSize = rowIndex + 1;
  int i = 0;
  for (; i < rowIndex + 2; i++) {
    a[i] = 0;
  }
  int temp1 = 0;
  int temp2 = 0;
  a[0] = 1;
  a[1] = 1;
  i = 2;
  for (; i <= rowIndex; i++) {
    temp1 = a[0];
    temp2 = a[1];
    int j = 1;
    for (; j <= i; j++) {
      a[j] = temp1 + temp2;
      temp1 = temp2;
      temp2 = a[j + 1];
    }
    a[i] = 1;
  }
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getRow>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    0x8(,%rdi,4),%edi
  call   <malloc@plt>
  lea    0x1(%rbx),%edx
  mov    %edx,0x0(%rbp)
  test   %edx,%edx
  js     L32
  mov    %rax,%rdx
  lea    0x1(%rbx),%ecx
  lea    0x4(%rax,%rcx,4),%rcx
L18:
  movl   $0x0,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L18
L32:
  movl   $0x1,(%rax)
  movl   $0x1,0x4(%rax)
  cmp    $0x1,%ebx
  jle    L22
  lea    0xc(%rax),%rdi
  lea    0x1(%rbx),%r9d
  mov    $0x2,%r8d
L8:
  mov    (%rax),%ecx
  mov    0x4(%rax),%esi
  test   %r8d,%r8d
  jle    L27
  lea    0x4(%rax),%rdx
L28:
  add    %esi,%ecx
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  mov    %esi,%ecx
  mov    (%rdx),%esi
  cmp    %rdi,%rdx
  jne    L28
L27:
  movl   $0x1,-0x4(%rdi)
  add    $0x1,%r8d
  add    $0x4,%rdi
  cmp    %r9d,%r8d
  jne    L8
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *getRow(int rowIndex, int *returnSize) {
  int *a = (int *)malloc((rowIndex + 2) * sizeof(int));
  *returnSize = rowIndex + 1;
  int i = 0;
  for (; i < rowIndex + 2; i++) {
    a[i] = 0;
  }
  int temp1 = 0;
  int temp2 = 0;
  a[0] = 1;
  a[1] = 1;
  i = 2;
  for (; i <= rowIndex; i++) {
    temp1 = a[0];
    temp2 = a[1];
    int j = 1;
    for (; j <= i; j++) {
      a[j] = temp1 + temp2;
      temp1 = temp2;
      temp2 = a[j + 1];
    }
    a[i] = 1;
  }
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getRow>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x8(,%rdi,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  lea    0x1(%rbx),%eax
  mov    %eax,0x0(%rbp)
  test   %eax,%eax
  js     L3
  cltq
  mov    %r8,%rdi
  xor    %esi,%esi
  lea    0x4(,%rax,4),%rdx
  call   <memset@plt>
  mov    %rax,%r8
L3:
  movabs $0x100000001,%rax
  mov    %rax,(%r8)
  cmp    $0x1,%ebx
  jle    L17
  lea    -0x2(%rbx),%eax
  lea    0xc(%r8),%rsi
  mov    $0x1,%ecx
  mov    $0x1,%edx
  lea    0x10(%r8,%rax,4),%r9
  lea    0x4(%r8),%rdi
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L38:
  add    %ecx,%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  mov    %ecx,%edx
  mov    (%rax),%ecx
  cmp    %rsi,%rax
  jne    L38
  movl   $0x1,-0x4(%rsi)
  add    $0x4,%rsi
  cmp    %r9,%rsi
  je     L17
  mov    (%r8),%edx
  mov    0x4(%r8),%ecx
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *getRow(int rowIndex, int *returnSize) {
  int *a = (int *)malloc((rowIndex + 2) * sizeof(int));
  *returnSize = rowIndex + 1;
  int i = 0;
  for (; i < rowIndex + 2; i++) {
    a[i] = 0;
  }
  int temp1 = 0;
  int temp2 = 0;
  a[0] = 1;
  a[1] = 1;
  i = 2;
  for (; i <= rowIndex; i++) {
    temp1 = a[0];
    temp2 = a[1];
    int j = 1;
    for (; j <= i; j++) {
      a[j] = temp1 + temp2;
      temp1 = temp2;
      temp2 = a[j + 1];
    }
    a[i] = 1;
  }
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<getRow>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x8(,%rdi,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  lea    0x1(%rbx),%eax
  mov    %eax,0x0(%rbp)
  test   %eax,%eax
  js     L21
  cltq
  mov    %r8,%rdi
  xor    %esi,%esi
  lea    0x4(,%rax,4),%rdx
  call   <memset@plt>
  mov    %rax,%r8
L21:
  mov    D7(%rip),%rax
  mov    %rax,(%r8)
  cmp    $0x1,%ebx
  jle    L26
  lea    -0x2(%rbx),%eax
  lea    0xc(%r8),%rsi
  mov    $0x1,%ecx
  mov    $0x1,%edx
  lea    0x10(%r8,%rax,4),%r9
  lea    0x4(%r8),%rdi
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L28:
  add    %ecx,%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  mov    %ecx,%edx
  mov    (%rax),%ecx
  cmp    %rax,%rsi
  jne    L28
  movl   $0x1,-0x4(%rsi)
  add    $0x4,%rsi
  cmp    %r9,%rsi
  je     L26
  mov    (%r8),%edx
  mov    0x4(%r8),%ecx
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: byte[8]

tool: {"D7": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int *getRow(int rowIndex, int *returnSize) {
  int *a = (int *)malloc((rowIndex + 2) * sizeof(int));
  *returnSize = rowIndex + 1;
  int i = 0;
  for (; i < rowIndex + 2; i++) {
    a[i] = 0;
  }
  int temp1 = 0;
  int temp2 = 0;
  a[0] = 1;
  a[1] = 1;
  i = 2;
  for (; i <= rowIndex; i++) {
    temp1 = a[0];
    temp2 = a[1];
    int j = 1;
    for (; j <= i; j++) {
      a[j] = temp1 + temp2;
      temp1 = temp2;
      temp2 = a[j + 1];
    }
    a[i] = 1;
  }
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmdline_insert_paste>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <term_read_paste@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L36
L26:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L0
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L0:
  addq   $0x1,-0x18(%rbp)
L36:
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jl     L26
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cmdline_insert_bytes@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void cmdline_insert_paste(struct cmdline *c) {
  long size, i;
  char *text = term_read_paste(&size);
  for (i = 0; i < size; i++) {
    if (text[i] == '\n')
      text[i] = ' ';
  }
  cmdline_insert_bytes(c, text, size);
  free(text);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmdline_insert_paste>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <term_read_paste@plt>
  mov    %rax,%rbx
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  jle    L1
  mov    $0x0,%eax
  jmp    L26
L34:
  add    $0x1,%rax
  mov    (%rsp),%rdx
  cmp    %rax,%rdx
  jle    L1
L26:
  cmpb   $0xa,(%rbx,%rax,1)
  jne    L34
  movb   $0x20,(%rbx,%rax,1)
  jmp    L34
L1:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <cmdline_insert_bytes@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmdline_insert_paste(struct cmdline *c) {
  long size, i;
  char *text = term_read_paste(&size);
  for (i = 0; i < size; i++) {
    if (text[i] == '\n')
      text[i] = ' ';
  }
  cmdline_insert_bytes(c, text, size);
  free(text);
}
```