ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<computeResidualAtIdx_CFP32_INT64>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rcx,%rsi
  mov    %r8,0x8(%rsp)
  mov    0x60(%rsp),%rcx
  mov    0x68(%rsp),%rdi
  test   %rdi,%rdi
  jle    L5
  mov    %rdx,%r15
  mov    $0x0,%eax
L10:
  mov    (%r9,%rax,8),%rdx
  lea    -0x8(%rsi,%rdx,8),%rdx
  movss  (%rdx),%xmm1
  movss  0x4(%rdx),%xmm0
  movss  %xmm1,(%rcx,%rax,8)
  movss  %xmm0,0x4(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L10
  mov    %r9,0x10(%rsp)
  mov    %rcx,%rbp
  lea    (%rcx,%rax,8),%rax
  mov    %rax,0x18(%rsp)
L54:
  mov    0x10(%rsp),%rax
  mov    %rax,%r14
  mov    (%rax),%rax
  mov    -0x8(%r13,%rax,8),%rbx
  cmp    0x0(%r13,%rax,8),%rbx
  jge    L13
L12:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%r12,%rbx,8),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%r12,%rbx,8),%xmm1
  xorpd  D5(%rip),%xmm1
  mov    -0x8(%r15,%rbx,8),%rax
  mov    0x8(%rsp),%rsi
  lea    -0x8(%rsi,%rax,8),%rax
  pxor   %xmm2,%xmm2
  cvtss2sd (%rax),%xmm2
  pxor   %xmm3,%xmm3
  cvtss2sd 0x4(%rax),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm2,%xmm4
  movapd %xmm1,%xmm5
  mulsd  %xmm3,%xmm5
  subsd  %xmm5,%xmm4
  movapd %xmm0,%xmm5
  mulsd  %xmm3,%xmm5
  movapd %xmm1,%xmm6
  mulsd  %xmm2,%xmm6
  addsd  %xmm6,%xmm5
  ucomisd %xmm4,%xmm5
  jp     L29
L49:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rbp),%xmm0
  subsd  %xmm5,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x0(%rbp),%xmm1
  subsd  %xmm4,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0x0(%rbp)
  movss  %xmm0,0x4(%rbp)
  add    $0x1,%rbx
  mov    (%r14),%rax
  cmp    %rbx,0x0(%r13,%rax,8)
  jg     L12
L13:
  addq   $0x8,0x10(%rsp)
  add    $0x8,%rbp
  cmp    0x18(%rsp),%rbp
  jne    L54
L5:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__muldc3>
  movapd %xmm0,%xmm4
  movapd %xmm1,%xmm5
  jmp    L49
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void computeResidualAtIdx_CFP32_INT64(long long *rowptr, float _Complex *valA, long long *colA, float _Complex *b, float _Complex *x, long long *Idxs, float _Complex *local_r, long long blockSize) {
  long long i, tt;
  for (i = 0; i < blockSize; ++i) {
    local_r[i] = b[Idxs[i] - 1];
  }
  for (i = 0; i < blockSize; ++i) {
    for (tt = rowptr[Idxs[i] - 1]; tt <= rowptr[Idxs[i]] - 1; ++tt) {
      local_r[i] -= conj(valA[tt - 1]) * x[colA[tt - 1] - 1];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<computeResidualAtIdx_CFP32_INT64>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  mov    %r9,%rdx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    0x78(%rsp),%r9
  mov    0x70(%rsp),%r12
  test   %r9,%r9
  jle    L0
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %rcx,%rdi
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L61:
  mov    (%rdx,%rcx,8),%rsi
  lea    -0x8(%rdi,%rsi,8),%rsi
  movss  (%rsi),%xmm1
  movss  0x4(%rsi),%xmm0
  movss  %xmm1,(%r12,%rcx,8)
  movss  %xmm0,0x4(%r12,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L61
  movq   D17(%rip),%xmm7
  lea    (%r12,%r9,8),%rcx
  lea    -0x8(%rax),%rsi
  nopl   0x0(%rax,%rax,1)
L54:
  mov    (%rdx),%r9
  mov    -0x8(%r14,%r9,8),%rdi
  mov    (%r14,%r9,8),%r9
  cmp    %r9,%rdi
  jge    L33
  shl    $0x3,%rdi
  movss  (%r12),%xmm6
  movss  0x4(%r12),%xmm4
  lea    (%rsi,%r9,8),%r13
  lea    -0x8(%rax,%rdi,1),%rbp
  lea    -0x4(%r15,%rdi,1),%rbx
  nopl   0x0(%rax)
L25:
  mov    0x0(%rbp),%rdi
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  pxor   %xmm3,%xmm3
  pxor   %xmm8,%xmm8
  cvtss2sd (%rbx),%xmm1
  xorpd  %xmm7,%xmm1
  lea    -0x8(%r8,%rdi,8),%rdi
  cvtss2sd -0x4(%rbx),%xmm8
  movapd %xmm1,%xmm0
  movapd %xmm8,%xmm5
  cvtss2sd (%rdi),%xmm2
  cvtss2sd 0x4(%rdi),%xmm3
  mulsd  %xmm2,%xmm5
  movapd %xmm1,%xmm9
  mulsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm9
  subsd  %xmm0,%xmm5
  movapd %xmm8,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm9,%xmm0
  ucomisd %xmm5,%xmm0
  jp     L6
L34:
  cvtss2sd %xmm6,%xmm6
  cvtss2sd %xmm4,%xmm4
  subsd  %xmm5,%xmm6
  subsd  %xmm0,%xmm4
  add    $0x8,%rbp
  add    $0x8,%rbx
  cvtsd2ss %xmm6,%xmm6
  cvtsd2ss %xmm4,%xmm4
  movss  %xmm6,(%r12)
  movss  %xmm4,0x4(%r12)
  cmp    %r13,%rbp
  jne    L25
L33:
  add    $0x8,%r12
  add    $0x8,%rdx
  cmp    %r12,%rcx
  jne    L54
L0:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  movapd %xmm8,%xmm0
  mov    %rsi,0x28(%rsp)
  mov    %r8,0x20(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x8(%rsp)
  movss  %xmm4,0x4(%rsp)
  movss  %xmm6,(%rsp)
  call   <__muldc3>
  mov    0x28(%rsp),%rsi
  mov    0x20(%rsp),%r8
  movapd %xmm0,%xmm5
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%rdx
  movapd %xmm1,%xmm0
  movq   D17(%rip),%xmm7
  mov    0x8(%rsp),%rcx
  movss  0x4(%rsp),%xmm4
  movss  (%rsp),%xmm6
  jmp    L34
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_guessed: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void computeResidualAtIdx_CFP32_INT64(long long *rowptr, float _Complex *valA, long long *colA, float _Complex *b, float _Complex *x, long long *Idxs, float _Complex *local_r, long long blockSize) {
  long long i, tt;
  for (i = 0; i < blockSize; ++i) {
    local_r[i] = b[Idxs[i] - 1];
  }
  for (i = 0; i < blockSize; ++i) {
    for (tt = rowptr[Idxs[i] - 1]; tt <= rowptr[Idxs[i]] - 1; ++tt) {
      local_r[i] -= conj(valA[tt - 1]) * x[colA[tt - 1] - 1];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_convert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L38
  mov    -0x1c(%rbp),%eax
  jmp    L9
L38:
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L8:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L13:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L8
  mov    -0x4(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int str_convert(char **str, int err) {
  int i;
  if (!isdigit(**str))
    return (err);
  for (i = 0; isdigit(**str); *str += 1)
    i = 10 * i + **str - '0';
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_convert>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    (%rdi),%rax
  movsbl (%rax),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L26
  mov    $0x0,%ebx
  jmp    L0
L25:
  mov    0x0(%rbp),%rax
  lea    (%rbx,%rbx,4),%ecx
  movsbl (%rax),%edx
  lea    -0x30(%rdx,%rcx,2),%ebx
  add    $0x1,%rax
  mov    %rax,0x0(%rbp)
L0:
  mov    0x0(%rbp),%rax
  movsbl (%rax),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L25
L26:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int str_convert(char **str, int err) {
  int i;
  if (!isdigit(**str))
    return (err);
  for (i = 0; isdigit(**str); *str += 1)
    i = 10 * i + **str - '0';
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_convert>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  movsbl (%rax),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L7
  mov    (%rbx),%rax
  xor    %r12d,%r12d
  jmp    L22
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%rax
  lea    (%r12,%r12,4),%ecx
  movsbl (%rax),%edx
  add    $0x1,%rax
  mov    %rax,(%rbx)
  lea    -0x30(%rdx,%rcx,2),%r12d
L22:
  movsbl (%rax),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L0
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int str_convert(char **str, int err) {
  int i;
  if (!isdigit(**str))
    return (err);
  for (i = 0; isdigit(**str); *str += 1)
    i = 10 * i + **str - '0';
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_convert>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  movsbl (%rax),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L16
  mov    (%rbx),%rax
  xor    %r12d,%r12d
  jmp    L10
  nopl   0x0(%rax)
L26:
  mov    (%rbx),%rax
  lea    (%r12,%r12,4),%ecx
  movsbl (%rax),%edx
  add    $0x1,%rax
  mov    %rax,(%rbx)
  lea    -0x30(%rdx,%rcx,2),%r12d
L10:
  movsbl (%rax),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L26
L16:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int str_convert(char **str, int err) {
  int i;
  if (!isdigit(**str))
    return (err);
  for (i = 0; isdigit(**str); *str += 1)
    i = 10 * i + **str - '0';
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L3:
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *str1, char *str2) {
  int i, j;
  for (i = 0; str1[i] != '\0'; i++)
    ;
  for (j = 0; str2[j] != '\0'; j++)
    str1[i + j] = str2[j];
  str1[i + j] = '\0';
  return str1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L45
  mov    $0x1,%edx
L38:
  mov    %edx,%edi
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rax,%rdx,1)
  jne    L38
L10:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L27
  mov    $0x1,%edx
  movslq %edi,%r8
  add    %rax,%r8
L7:
  mov    %cl,-0x1(%r8,%rdx,1)
  mov    %edx,%r9d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L7
L24:
  add    %r9d,%edi
  movslq %edi,%rdi
  movb   $0x0,(%rax,%rdi,1)
  ret
L45:
  mov    $0x0,%edi
  jmp    L10
L27:
  mov    $0x0,%r9d
  jmp    L24
```

assistant: ```c
char *strcat(char *str1, char *str2) {
  int i, j;
  for (i = 0; str1[i] != '\0'; i++)
    ;
  for (j = 0; str2[j] != '\0'; j++)
    str1[i + j] = str2[j];
  str1[i + j] = '\0';
  return str1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L15
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L14:
  lea    (%rcx,%rdx,1),%r10d
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L14
L44:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L29
  movslq %r10d,%r9
  mov    $0x1,%edx
  add    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %cl,-0x1(%r9,%rdx,1)
  mov    %edx,%r8d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L33
  add    %r10d,%r8d
  movslq %r8d,%r8
  add    %rax,%r8
L29:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rdi,%r8
  xor    %r10d,%r10d
  jmp    L44
```

assistant: ```c
char *strcat(char *str1, char *str2) {
  int i, j;
  for (i = 0; str1[i] != '\0'; i++)
    ;
  for (j = 0; str2[j] != '\0'; j++)
    str1[i + j] = str2[j];
  str1[i + j] = '\0';
  return str1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L9
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L7:
  lea    (%rcx,%rdx,1),%r10d
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L7
L42:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L43
  movslq %r10d,%r9
  mov    $0x1,%edx
  add    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %cl,-0x1(%r9,%rdx,1)
  mov    %edx,%r8d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L22
  add    %r10d,%r8d
  movslq %r8d,%r8
  add    %rax,%r8
L43:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rdi,%r8
  xor    %r10d,%r10d
  jmp    L42
```

assistant: ```c
char *strcat(char *str1, char *str2) {
  int i, j;
  for (i = 0; str1[i] != '\0'; i++)
    ;
  for (j = 0; str2[j] != '\0'; j++)
    str1[i + j] = str2[j];
  str1[i + j] = '\0';
  return str1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<can_put>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L35
L64:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L101
  mov    $0x0,%eax
  jmp    L20
L101:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L116
  mov    $0x0,%eax
  jmp    L20
L116:
  addl   $0x1,-0x10(%rbp)
L35:
  cmpl   $0x8,-0x10(%rbp)
  jle    L64
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L18
L51:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L75
L50:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L20
L4:
  addl   $0x1,-0xc(%rbp)
L75:
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L50
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x10(%rbp)
  jle    L51
  mov    $0x1,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int can_put(int sudoku[9][9], int x, int y, int n) {
  int i, j;
  for (i = 0; i < 9; i++) {
    if (sudoku[i][y] == n) {
      return 0;
    }
    if (sudoku[x][i] == n) {
      return 0;
    }
  }
  int a = x - (x % 3);
  int b = y - (y % 3);
  for (i = a; i < a + 3; i++) {
    for (j = b; j < b + 3; j++) {
      if (sudoku[i][j] == n) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<can_put>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%edi
  mov    %edx,%esi
  mov    %ecx,%edx
  movslq %esi,%rax
  lea    (%r9,%rax,4),%rcx
  movslq %edi,%rax
  lea    (%rax,%rax,8),%rax
  lea    (%r9,%rax,4),%rax
  lea    0x24(%rax),%r8
L9:
  cmp    %edx,(%rcx)
  je     L23
  cmp    %edx,(%rax)
  je     L31
  add    $0x24,%rcx
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L9
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,2),%edi
  movslq %esi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,2),%r10d
  lea    0x2(%rdi),%r11d
  movslq %edi,%rax
  lea    (%rax,%rax,8),%rax
  lea    (%r9,%rax,4),%r8
  lea    0x2(%r10),%esi
L55:
  mov    %r8,%rcx
  movslq %r10d,%rax
L18:
  cmp    %edx,(%rcx,%rax,4)
  je     L53
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L18
  add    $0x1,%edi
  add    $0x24,%r8
  cmp    %r11d,%edi
  jle    L55
  mov    $0x1,%eax
  ret
L23:
  mov    $0x0,%eax
  ret
L31:
  mov    $0x0,%eax
  ret
L53:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int can_put(int sudoku[9][9], int x, int y, int n) {
  int i, j;
  for (i = 0; i < 9; i++) {
    if (sudoku[i][y] == n) {
      return 0;
    }
    if (sudoku[x][i] == n) {
      return 0;
    }
  }
  int a = x - (x % 3);
  int b = y - (y % 3);
  for (i = a; i < a + 3; i++) {
    for (j = b; j < b + 3; j++) {
      if (sudoku[i][j] == n) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<can_put>:
  endbr64
  movslq %esi,%rsi
  mov    %rdi,%r8
  movslq %edx,%rdi
  mov    %ecx,%edx
  lea    (%rsi,%rsi,8),%rax
  mov    %rsi,%r11
  lea    (%r8,%rdi,4),%rcx
  mov    %rdi,%r10
  lea    (%r8,%rax,4),%rax
  lea    0x24(%rax),%r9
  nopl   (%rax)
L8:
  cmp    %edx,(%rcx)
  je     L5
  cmp    %edx,(%rax)
  je     L5
  add    $0x4,%rax
  add    $0x24,%rcx
  cmp    %r9,%rax
  jne    L8
  imul   $0x55555556,%rsi,%rsi
  sar    $0x1f,%r11d
  sar    $0x1f,%r10d
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rsi
  sub    %r11d,%esi
  shr    $0x20,%rdi
  lea    (%rsi,%rsi,2),%r9d
  sub    %r10d,%edi
  movslq %r9d,%rcx
  lea    (%rdi,%rdi,2),%eax
  lea    0x2(%r9),%r10d
  lea    (%rcx,%rcx,8),%rcx
  lea    0x2(%rax),%esi
  movslq %eax,%rdi
  lea    (%r8,%rcx,4),%rcx
L31:
  mov    %rdi,%rax
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x1,%rax
  cmp    %eax,%esi
  jl     L68
L49:
  cmp    %edx,(%rcx,%rax,4)
  jne    L24
L5:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  add    $0x1,%r9d
  add    $0x24,%rcx
  cmp    %r10d,%r9d
  jle    L31
  mov    $0x1,%eax
  ret
```

assistant: ```c
int can_put(int sudoku[9][9], int x, int y, int n) {
  int i, j;
  for (i = 0; i < 9; i++) {
    if (sudoku[i][y] == n) {
      return 0;
    }
    if (sudoku[x][i] == n) {
      return 0;
    }
  }
  int a = x - (x % 3);
  int b = y - (y % 3);
  for (i = a; i < a + 3; i++) {
    for (j = b; j < b + 3; j++) {
      if (sudoku[i][j] == n) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<can_put>:
  endbr64
  mov    %ecx,%eax
  movslq %esi,%rcx
  mov    %edx,%r10d
  lea    (%rcx,%rcx,8),%rdx
  lea    (%rdi,%rdx,4),%r8
  movslq %r10d,%rdx
  lea    0x0(,%rdx,4),%r9
  cmp    (%rdi,%rdx,4),%eax
  je     L199
  cmp    (%r8),%eax
  je     L199
  cmp    0x24(%rdi,%r9,1),%eax
  je     L199
  cmp    0x4(%r8),%eax
  je     L199
  cmp    0x48(%rdi,%r9,1),%eax
  je     L199
  cmp    0x8(%r8),%eax
  je     L199
  cmp    0x6c(%rdi,%r9,1),%eax
  je     L199
  cmp    0xc(%r8),%eax
  je     L199
  cmp    0x90(%rdi,%r9,1),%eax
  je     L199
  cmp    0x10(%r8),%eax
  je     L199
  cmp    0xb4(%rdi,%r9,1),%eax
  je     L199
  cmp    0x14(%r8),%eax
  je     L199
  cmp    0xd8(%rdi,%r9,1),%eax
  je     L199
  cmp    0x18(%r8),%eax
  je     L199
  cmp    0xfc(%rdi,%r9,1),%eax
  je     L199
  cmp    0x1c(%r8),%eax
  je     L199
  cmp    %eax,0x120(%rdi,%r9,1)
  je     L199
  cmp    %eax,0x20(%r8)
  je     L199
  imul   $0x55555556,%rcx,%rcx
  sar    $0x1f,%esi
  sar    $0x1f,%r10d
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rcx
  sub    %esi,%ecx
  shr    $0x20,%rdx
  lea    (%rcx,%rcx,2),%ecx
  sub    %r10d,%edx
  lea    (%rdx,%rdx,2),%edx
  movslq %ecx,%rsi
  lea    0x2(%rcx),%r8d
  movslq %edx,%rdx
  lea    (%rsi,%rsi,8),%rsi
  add    %rsi,%rdx
  lea    (%rdi,%rdx,4),%rdx
L21:
  cmp    (%rdx),%eax
  je     L199
  cmp    %eax,0x4(%rdx)
  je     L199
  cmp    0x8(%rdx),%eax
  je     L199
  add    $0x1,%ecx
  add    $0x24,%rdx
  cmp    %r8d,%ecx
  jle    L21
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L199:
  xor    %eax,%eax
  ret
```

assistant: ```c
int can_put(int sudoku[9][9], int x, int y, int n) {
  int i, j;
  for (i = 0; i < 9; i++) {
    if (sudoku[i][y] == n) {
      return 0;
    }
    if (sudoku[x][i] == n) {
      return 0;
    }
  }
  int a = x - (x % 3);
  int b = y - (y % 3);
  for (i = a; i < a + 3; i++) {
    for (j = b; j < b + 3; j++) {
      if (sudoku[i][j] == n) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<breakme>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3e8,-0x4(%rbp)
  jle    L1
  mov    $0x0,%eax
  call   <leaf@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void breakme(int line) {
  if (line > 1000)
    leaf();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<breakme>:
  endbr64
  cmp    $0x3e8,%edi
  jg     L7
  ret
L7:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <leaf@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void breakme(int line) {
  if (line > 1000)
    leaf();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<breakme>:
  endbr64
  cmp    $0x3e8,%edi
  jg     L6
  ret
  nopl   (%rax)
L6:
  xor    %eax,%eax
  jmp    1050 <leaf@plt>
```

assistant: ```c
void breakme(int line) {
  if (line > 1000)
    leaf();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<breakme>:
  endbr64
  cmp    $0x3e8,%edi
  jg     L7
  ret
  nopl   (%rax)
L7:
  xor    %eax,%eax
  jmp    1050 <leaf@plt>
```

assistant: ```c
void breakme(int line) {
  if (line > 1000)
    leaf();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<app_getAppID>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int app_getAppID() {
  int pid = getpid();
  return pid;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<app_getAppID>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int app_getAppID() {
  int pid = getpid();
  return pid;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<app_getAppID>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <getpid@plt>
```

assistant: ```c
int app_getAppID() {
  int pid = getpid();
  return pid;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<app_getAppID>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <getpid@plt>
```

assistant: ```c
int app_getAppID() {
  int pid = getpid();
  return pid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<c_dnrm2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <dnrm2sub@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double c_dnrm2(const int N, const double *X, const int stride) {
  double nrm2;
  dnrm2sub(&N, X, &stride, &nrm2);
  return nrm2;
}
```