ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x4,-0xc(%rbp)
  jne    L4
  mov    -0x8(%rbp),%rax
  movl   $0x7b,(%rax)
  jmp    L15
L4:
  cmpl   $0x8,-0xc(%rbp)
  jle    L15
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L15:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: ABCDE

assistant: ```c
void func(void *ptr, int size) {
  if (size == 4) {
    *((int *)ptr) = 123;
  } else if (size > 8) {
    strcpy((char *)ptr, "ABCDE");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func>:
  endbr64
  cmp    $0x4,%esi
  je     L17
  cmp    $0x8,%esi
  jg     L4
  ret
L17:
  movl   $0x7b,(%rdi)
  ret
L4:
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: ABCDE

assistant: ```c
void func(void *ptr, int size) {
  if (size == 4) {
    *((int *)ptr) = 123;
  } else if (size > 8) {
    strcpy((char *)ptr, "ABCDE");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func>:
  endbr64
  cmp    $0x4,%esi
  je     L17
  cmp    $0x8,%esi
  jg     L18
  ret
  nop
L18:
  lea    D8(%rip),%rsi
  jmp    1050 <strcpy@plt>
  nopl   0x0(%rax)
L17:
  movl   $0x7b,(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: ABCDE

assistant: ```c
void func(void *ptr, int size) {
  if (size == 4) {
    *((int *)ptr) = 123;
  } else if (size > 8) {
    strcpy((char *)ptr, "ABCDE");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func>:
  endbr64
  cmp    $0x4,%esi
  je     L16
  cmp    $0x8,%esi
  jg     L1
  ret
  nop
L1:
  lea    D1(%rip),%rsi
  jmp    1050 <strcpy@plt>
  nopl   0x0(%rax)
L16:
  movl   $0x7b,(%rdi)
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: ABCDE

assistant: ```c
void func(void *ptr, int size) {
  if (size == 4) {
    *((int *)ptr) = 123;
  } else if (size > 8) {
    strcpy((char *)ptr, "ABCDE");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L28
L5:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D25(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <stdlib_base_float64_get_high_word@plt>
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jne    L56
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L54
L56:
  addl   $0x1,-0x2c(%rbp)
L28:
  cmpl   $0xf423f,-0x2c(%rbp)
  jle    L5
L54:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jne    L16
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D25
datatype: f64
name: disassemble_data
arguments: data_label: D3
datatype: f64
name: disassemble_data
arguments: data_label: D14
datatype: string

tool: D25: 1000

tool: D3: 500

tool: D14: unexpected result


assistant: ```c
double benchmark() {
  double elapsed;
  uint32_t h;
  double x;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) + 500.0;
    stdlib_base_float64_get_high_word(x, &h);
    if (h == 0) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (h == 0) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<benchmark>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <tic@plt>
  movq   %xmm0,%r14
  mov    $0xf4240,%ebx
  mov    %rsp,%rbp
L55:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D11(%rip),%xmm0
  addsd  D10(%rip),%xmm0
  mov    %rbp,%rdi
  call   <stdlib_base_float64_get_high_word@plt>
  cmpq   $0x0,(%rsp)
  je     L21
  sub    $0x1,%ebx
  jne    L55
  jmp    L5
L21:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L5:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r14,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  cmpq   $0x0,(%rsp)
  je     L30
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  movq   %rbx,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L30:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
datatype: f64
name: parse_data
arguments: tag: D10
datatype: f64
name: parse_data
arguments: tag: D8
datatype: string

tool: D11: 1000

tool: D10: 500

tool: D8: unexpected result


assistant: ```c
double benchmark() {
  double elapsed;
  uint32_t h;
  double x;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) + 500.0;
    stdlib_base_float64_get_high_word(x, &h);
    if (h == 0) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (h == 0) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<benchmark>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L46
  nopl   0x0(%rax)
L13:
  sub    $0x1,%ebx
  je     L33
L46:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D5(%rip),%xmm0
  mov    %rbp,%rdi
  addsd  D6(%rip),%xmm0
  call   <stdlib_base_float64_get_high_word@plt>
  cmpq   $0x0,0x10(%rsp)
  jne    L13
  lea    D32(%rip),%rdi
  call   <printf@plt>
L33:
  xor    %eax,%eax
  call   <tic@plt>
  cmpq   $0x0,0x10(%rsp)
  subsd  0x8(%rsp),%xmm0
  je     L41
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L41:
  lea    D32(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L25
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: f64
name: retrieve_data
arguments: data_tag: D6
type_guessed: f64
name: retrieve_data
arguments: data_tag: D32
type_guessed: string

tool: D5: 1000

tool: D6: 500

tool: D32: unexpected result


assistant: ```c
double benchmark() {
  double elapsed;
  uint32_t h;
  double x;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) + 500.0;
    stdlib_base_float64_get_high_word(x, &h);
    if (h == 0) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (h == 0) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L42
  nopl   0x0(%rax)
L36:
  sub    $0x1,%ebx
  je     L45
L42:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D39(%rip),%xmm0
  mov    %rbp,%rdi
  addsd  D35(%rip),%xmm0
  call   <stdlib_base_float64_get_high_word@plt>
  cmpq   $0x0,0x10(%rsp)
  jne    L36
  lea    D34(%rip),%rdi
  call   <printf@plt>
L45:
  xor    %eax,%eax
  call   <tic@plt>
  cmpq   $0x0,0x10(%rsp)
  subsd  0x8(%rsp),%xmm0
  je     L40
L37:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L40:
  lea    D34(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L37
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D39
type_guessed: f64
name: parse_data
arguments: label: D35
type_guessed: f64
name: parse_data
arguments: label: D34
type_guessed: string

tool: D39: 1000

tool: D35: 500

tool: D34: unexpected result


assistant: ```c
double benchmark() {
  double elapsed;
  uint32_t h;
  double x;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) + 500.0;
    stdlib_base_float64_get_high_word(x, &h);
    if (h == 0) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (h == 0) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WDT_IrqHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  jmp    L9
```

assistant: ```c
__attribute__((weak)) void WDT_IrqHandler(void) {
  while (1)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<WDT_IrqHandler>:
  endbr64
L9:
  jmp    L9
```

assistant: ```c
__attribute__((weak)) void WDT_IrqHandler(void) {
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WDT_IrqHandler>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
__attribute__((weak)) void WDT_IrqHandler(void) {
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<WDT_IrqHandler>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
__attribute__((weak)) void WDT_IrqHandler(void) {
  while (1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L0:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(char s[]) {
  int i = 0;
  while (s[i] != '\0')
    ++i;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L21
  mov    $0x1,%eax
L8:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L8
L9:
  mov    %edx,%eax
  ret
L21:
  mov    $0x0,%edx
  jmp    L9
```

assistant: ```c
int strlen(char s[]) {
  int i = 0;
  while (s[i] != '\0')
    ++i;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  mov    $0x1,%eax
  xchg   %ax,%ax
L0:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L0
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char s[]) {
  int i = 0;
  while (s[i] != '\0')
    ++i;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x1,%eax
  xchg   %ax,%ax
L13:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char s[]) {
  int i = 0;
  while (s[i] != '\0')
    ++i;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L9
L33:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L11
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L38
L11:
  mov    -0x18(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    -0x14(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L38:
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L33
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D29
data_type: string
name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D38
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: string

tool: D29: %i

tool: D7: %i %i

tool: D38: divisao impossivel

tool: D0: %.1f


assistant: ```c
int main() {
  int x, y, n, i;
  scanf("%i", &n);
  for (i = 1; i <= n; i++) {
    scanf("%i %i", &x, &y);
    if (y == 0)
      printf("divisao impossivel\n");
    else
      printf("%.1f\n", (float)x / y);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L53
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r12
  lea    D2(%rip),%rbp
  lea    D13(%rip),%r14
  lea    D5(%rip),%r13
  jmp    L54
L24:
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L26:
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jl     L53
L54:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jne    L24
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L26
L53:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D36
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string

tool: D36: %i

tool: D2: %i %i

tool: D13: %.1f


tool: D5: divisao impossivel

assistant: ```c
int main() {
  int x, y, n, i;
  scanf("%i", &n);
  for (i = 1; i <= n; i++) {
    scanf("%i %i", &x, &y);
    if (y == 0)
      printf("divisao impossivel\n");
    else
      printf("%.1f\n", (float)x / y);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D38(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L40
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D22(%rip),%rbp
  lea    D28(%rip),%r15
  lea    D3(%rip),%r14
  jmp    L7
  nopl   (%rax)
L46:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    %ebx,0x14(%rsp)
  jl     L40
L7:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  je     L46
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %r15,%rdi
  add    $0x1,%ebx
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ssl 0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  cmp    %ebx,0x14(%rsp)
  jge    L7
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D38
type: string
name: retrieve_data
arguments: tag: D22
type: string
name: retrieve_data
arguments: tag: D28
type: string
name: retrieve_data
arguments: tag: D3
type: string

tool: D38: %i

tool: D22: %i %i

tool: D28: %.1f


tool: D3: divisao impossivel

assistant: ```c
int main() {
  int x, y, n, i;
  scanf("%i", &n);
  for (i = 1; i <= n; i++) {
    scanf("%i %i", &x, &y);
    if (y == 0)
      printf("divisao impossivel\n");
    else
      printf("%.1f\n", (float)x / y);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D31(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L48
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D18(%rip),%rbp
  lea    D29(%rip),%r15
  lea    D27(%rip),%r14
  nop
L22:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jne    L55
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    0x14(%rsp),%ebx
  jle    L22
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %r15,%rdi
  add    $0x1,%ebx
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ssl 0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  cmp    %ebx,0x14(%rsp)
  jge    L22
  jmp    L48
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D31
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D29
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string

tool: D31: %i

tool: D18: %i %i

tool: D29: %.1f


tool: D27: divisao impossivel

assistant: ```c
int main() {
  int x, y, n, i;
  scanf("%i", &n);
  for (i = 1; i <= n; i++) {
    scanf("%i %i", &x, &y);
    if (y == 0)
      printf("divisao impossivel\n");
    else
      printf("%.1f\n", (float)x / y);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nogr_key_from_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x8(%rbp)
  addl   $0x8,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int nogr_key_from_name(const char *str) {
  int k = 0, shf = 0;
  while (*str) {
    k |= *str << shf;
    shf += 8;
    str++;
  }
  return k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nogr_key_from_name>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  mov    $0x0,%ecx
  mov    $0x0,%edx
L28:
  movsbl %al,%eax
  shl    %cl,%eax
  or     %eax,%edx
  add    $0x8,%ecx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L28
L6:
  mov    %edx,%eax
  ret
L18:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int nogr_key_from_name(const char *str) {
  int k = 0, shf = 0;
  while (*str) {
    k |= *str << shf;
    shf += 8;
    str++;
  }
  return k;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nogr_key_from_name>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L8
  xor    %ecx,%ecx
  xor    %r8d,%r8d
L9:
  shl    %cl,%eax
  add    $0x1,%rdi
  add    $0x8,%ecx
  or     %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L9
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nogr_key_from_name(const char *str) {
  int k = 0, shf = 0;
  while (*str) {
    k |= *str << shf;
    shf += 8;
    str++;
  }
  return k;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nogr_key_from_name>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L17
  xor    %ecx,%ecx
  xor    %r8d,%r8d
L6:
  shl    %cl,%eax
  add    $0x1,%rdi
  add    $0x8,%ecx
  or     %eax,%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int nogr_key_from_name(const char *str) {
  int k = 0, shf = 0;
  while (*str) {
    k |= *str << shf;
    shf += 8;
    str++;
  }
  return k;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<abs_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L15
  pxor   %xmm0,%xmm0
  subss  -0x4(%rbp),%xmm0
  jmp    L3
L15:
  movss  -0x4(%rbp),%xmm0
L3:
  pop    %rbp
  ret
```

assistant: ```c
float abs_r(float p) {
  if (p < 0)
    return 0 - p;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<abs_r>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L10
L5:
  ret
L10:
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  jmp    L5
```

assistant: ```c
float abs_r(float p) {
  if (p < 0)
    return 0 - p;
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<abs_r>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L2
  ret
  xchg   %ax,%ax
L2:
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float abs_r(float p) {
  if (p < 0)
    return 0 - p;
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<abs_r>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L4
  ret
  xchg   %ax,%ax
L4:
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float abs_r(float p) {
  if (p < 0)
    return 0 - p;
  return p;
}
```