ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<soma>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  jge    L9
  nopw   0x0(%rax,%rax,1)
L0:
  add    %edi,%eax
  add    $0x1,%edi
  cmp    %edi,%esi
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
int soma(int n1, int n2) {
  int soma = 0;
  for (int i = n1; i < n2; i++)
    soma += i;
  return soma;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<soma>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%ecx
  cmp    %esi,%edi
  jge    L88
  mov    %esi,%edi
  sub    %edx,%edi
  lea    -0x1(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L40
  movd   %edx,%xmm4
  mov    %edi,%esi
  movdqa D6(%rip),%xmm3
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm1
  paddd  D16(%rip),%xmm1
  shr    $0x2,%esi
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax)
L120:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %esi,%eax
  jne    L120
  movdqa %xmm0,%xmm1
  mov    %edi,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  paddd  %xmm1,%xmm0
  add    %esi,%edx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%edi
  je     L129
L29:
  lea    0x1(%rdx),%esi
  add    %edx,%eax
  cmp    %esi,%ecx
  jle    L58
  add    %esi,%eax
  lea    0x2(%rdx),%esi
  cmp    %esi,%ecx
  jle    L58
  add    %esi,%eax
  lea    0x3(%rdx),%esi
  cmp    %esi,%ecx
  jle    L58
  add    %esi,%eax
  lea    0x4(%rdx),%esi
  cmp    %esi,%ecx
  jle    L58
  add    %esi,%eax
  lea    0x5(%rdx),%esi
  cmp    %esi,%ecx
  jle    L58
  add    %esi,%eax
  lea    0x6(%rdx),%esi
  cmp    %esi,%ecx
  jle    L58
  add    %esi,%eax
  lea    0x7(%rdx),%esi
  cmp    %esi,%ecx
  jle    L58
  add    %esi,%eax
  lea    0x8(%rdx),%esi
  cmp    %esi,%ecx
  jle    L58
  add    %esi,%eax
  add    $0x9,%edx
  lea    (%rax,%rdx,1),%esi
  cmp    %edx,%ecx
  cmovg  %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L88:
  xor    %eax,%eax
L58:
  ret
  nopl   0x0(%rax,%rax,1)
L129:
  ret
L40:
  xor    %eax,%eax
  jmp    L29
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: byte[16]
name: unpack_data
arguments: data_tag: D16
type: byte[16]

tool: {"D6": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int soma(int n1, int n2) {
  int soma = 0;
  for (int i = n1; i < n2; i++)
    soma += i;
  return soma;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_oct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <print_to_base@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <fputsn@plt>
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int print_oct(int fd, int n) {
  int count;
  char buffer[20] = {0};
  count = print_to_base(n, buffer, 8);
  fputsn(fd, buffer, count);
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_oct>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebp
  mov    %esi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  mov    %rsp,%r12
  mov    $0x8,%edx
  mov    %r12,%rsi
  call   <print_to_base@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <fputsn@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int print_oct(int fd, int n) {
  int count;
  char buffer[20] = {0};
  count = print_to_base(n, buffer, 8);
  fputsn(fd, buffer, count);
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_oct>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    $0x8,%edx
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movl   $0x0,0x10(%rsp)
  mov    %r13,%rsi
  movaps %xmm0,(%rsp)
  call   <print_to_base@plt>
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  mov    %eax,%r12d
  call   <fputsn@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int print_oct(int fd, int n) {
  int count;
  char buffer[20] = {0};
  count = print_to_base(n, buffer, 8);
  fputsn(fd, buffer, count);
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_oct>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    $0x8,%edx
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movl   $0x0,0x10(%rsp)
  mov    %r13,%rsi
  movaps %xmm0,(%rsp)
  call   <print_to_base@plt>
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  mov    %eax,%r12d
  call   <fputsn@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int print_oct(int fd, int n) {
  int count;
  char buffer[20] = {0};
  count = print_to_base(n, buffer, 8);
  fputsn(fd, buffer, count);
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: this is cmd2!


assistant: ```c
int main() {
  printf("this is cmd2!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string

tool: D5: this is cmd2!


assistant: ```c
int main() {
  printf("this is cmd2!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: this is cmd2!


assistant: ```c
int main() {
  printf("this is cmd2!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: this is cmd2!


assistant: ```c
int main() {
  printf("this is cmd2!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<addf_mi_attr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %esi,-0xdc(%rbp)
  mov    %rdx,-0xe8(%rbp)
  mov    %ecx,-0xe0(%rbp)
  mov    %r8,-0xf0(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L31
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L31:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc8(%rbp)
  mov    -0xf0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  lea    -0xc8(%rbp),%rdx
  mov    -0xc4(%rbp),%ecx
  mov    -0xf0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mi_print_fmt@plt>
  mov    %rax,-0xc0(%rbp)
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpq   $0x0,-0xc0(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L21
L30:
  mov    -0xc8(%rbp),%r8d
  mov    -0xdc(%rbp),%eax
  or     $0x2,%eax
  mov    %eax,%esi
  mov    -0xc0(%rbp),%rdi
  mov    -0xe0(%rbp),%ecx
  mov    -0xe8(%rbp),%rdx
  mov    -0xd8(%rbp),%rax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <add_mi_attr@plt>
L21:
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
struct mi_attr *addf_mi_attr(struct mi_node *node, int flags, char *name, int name_len, char *fmt_val, ...) {
  va_list ap;
  char *p;
  int len = 0;
  va_start(ap, fmt_val);
  p = mi_print_fmt(fmt_val, ap, &len);
  va_end(ap);
  if (p == NULL)
    return 0;
  return add_mi_attr(node, flags | (1 << 1), name, name_len, p, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<addf_mi_attr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %rdx,%r14
  mov    %ecx,%r15d
  mov    %r8,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  mov    %r8,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  lea    0x4(%rsp),%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <mi_print_fmt@plt>
  mov    %rax,%rbx
  mov    %r12d,%edi
  call   <va_end@plt>
  test   %rbx,%rbx
  je     L9
  mov    %ebp,%esi
  or     $0x2,%esi
  mov    0x4(%rsp),%r9d
  mov    %rbx,%r8
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <add_mi_attr@plt>
  mov    %rax,%rbx
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct mi_attr *addf_mi_attr(struct mi_node *node, int flags, char *name, int name_len, char *fmt_val, ...) {
  va_list ap;
  char *p;
  int len = 0;
  va_start(ap, fmt_val);
  p = mi_print_fmt(fmt_val, ap, &len);
  va_end(ap);
  if (p == NULL)
    return 0;
  return add_mi_attr(node, flags | (1 << 1), name, name_len, p, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<addf_mi_attr>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %esi,%ebx
  mov    %r8,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <va_start@plt>
  mov    %r12,%rdi
  lea    0x4(%rsp),%rdx
  mov    %ebp,%esi
  call   <mi_print_fmt@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  test   %r12,%r12
  je     L17
  mov    0x4(%rsp),%r9d
  or     $0x2,%ebx
  mov    %r12,%r8
  mov    %r15d,%ecx
  mov    %ebx,%esi
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <add_mi_attr@plt>
  mov    %rax,%r12
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct mi_attr *addf_mi_attr(struct mi_node *node, int flags, char *name, int name_len, char *fmt_val, ...) {
  va_list ap;
  char *p;
  int len = 0;
  va_start(ap, fmt_val);
  p = mi_print_fmt(fmt_val, ap, &len);
  va_end(ap);
  if (p == NULL)
    return 0;
  return add_mi_attr(node, flags | (1 << 1), name, name_len, p, len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<addf_mi_attr>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %esi,%ebx
  mov    %r8,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <va_start@plt>
  mov    %r12,%rdi
  lea    0x4(%rsp),%rdx
  mov    %ebp,%esi
  call   <mi_print_fmt@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  test   %r12,%r12
  je     L14
  mov    0x4(%rsp),%r9d
  or     $0x2,%ebx
  mov    %r12,%r8
  mov    %r15d,%ecx
  mov    %ebx,%esi
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <add_mi_attr@plt>
  mov    %rax,%r12
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct mi_attr *addf_mi_attr(struct mi_node *node, int flags, char *name, int name_len, char *fmt_val, ...) {
  va_list ap;
  char *p;
  int len = 0;
  va_start(ap, fmt_val);
  p = mi_print_fmt(fmt_val, ap, &len);
  va_end(ap);
  if (p == NULL)
    return 0;
  return add_mi_attr(node, flags | (1 << 1), name, name_len, p, len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x313f3030313f31,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <substituteWildcard@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string

tool: D8: Result of substituting for ? in %s with 0 or 1:


assistant: ```c
int main() {
  char str[] = "1?100?1";
  printf("Result of substituting for ? in %s with 0 or 1:\n", str);
  substituteWildcard(str, 8, 0);
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x313f3030313f31,%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <substituteWildcard@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D8: Result of substituting for ? in %s with 0 or 1:


assistant: ```c
int main() {
  char str[] = "1?100?1";
  printf("Result of substituting for ? in %s with 0 or 1:\n", str);
  substituteWildcard(str, 8, 0);
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x313f3030313f31,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    %rax,(%rsp)
  call   <printf@plt>
  xor    %edx,%edx
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <substituteWildcard@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: Result of substituting for ? in %s with 0 or 1:


assistant: ```c
int main() {
  char str[] = "1?100?1";
  printf("Result of substituting for ? in %s with 0 or 1:\n", str);
  substituteWildcard(str, 8, 0);
  getchar();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x313f3030313f31,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    %rax,(%rsp)
  call   <printf@plt>
  xor    %edx,%edx
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <substituteWildcard@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: Result of substituting for ? in %s with 0 or 1:


assistant: ```c
int main() {
  char str[] = "1?100?1";
  printf("Result of substituting for ? in %s with 0 or 1:\n", str);
  substituteWildcard(str, 8, 0);
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<toupper_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L19
L4:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addq   $0x1,-0x18(%rbp)
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x18(%rbp)
  jb     L4
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void toupper_string(char *text) {
  size_t j;
  for (j = 0; j < strlen(text); j++) {
    text[j] = toupper(text[j]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<toupper_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L5
L4:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void toupper_string(char *text) {
  size_t j;
  for (j = 0; j < strlen(text); j++) {
    text[j] = toupper(text[j]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toupper_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L2
  nopl   0x0(%rax)
L3:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void toupper_string(char *text) {
  size_t j;
  for (j = 0; j < strlen(text); j++) {
    text[j] = toupper(text[j]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toupper_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L7
  nopl   0x0(%rax)
L10:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void toupper_string(char *text) {
  size_t j;
  for (j = 0; j < strlen(text); j++) {
    text[j] = toupper(text[j]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp_for_qsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int strcmp_for_qsort(const void *aa, const void *bb) {
  const char **a = (const char **)aa;
  const char **b = (const char **)bb;
  return strcmp(*a, *b);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcmp_for_qsort>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int strcmp_for_qsort(const void *aa, const void *bb) {
  const char **a = (const char **)aa;
  const char **b = (const char **)bb;
  return strcmp(*a, *b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp_for_qsort>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int strcmp_for_qsort(const void *aa, const void *bb) {
  const char **a = (const char **)aa;
  const char **b = (const char **)bb;
  return strcmp(*a, *b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcmp_for_qsort>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int strcmp_for_qsort(const void *aa, const void *bb) {
  const char **a = (const char **)aa;
  const char **b = (const char **)bb;
  return strcmp(*a, *b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mc_path_islink>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  je     L23
  mov    $0x0,%eax
  jmp    L19
L23:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISLNK@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int mc_path_islink(const char *filename) {
  struct stat st;
  if (0 != lstat(filename, &st)) {
    return 0;
  }
  return !!S_ISLNK(st.st_mode);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mc_path_islink>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L17
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  ret
L17:
  mov    0x4(%rsp),%edi
  call   <S_ISLNK@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L5
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mc_path_islink(const char *filename) {
  struct stat st;
  if (0 != lstat(filename, &st)) {
    return 0;
  }
  return !!S_ISLNK(st.st_mode);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mc_path_islink>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L18
  mov    0x4(%rsp),%edi
  call   <S_ISLNK@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mc_path_islink(const char *filename) {
  struct stat st;
  if (0 != lstat(filename, &st)) {
    return 0;
  }
  return !!S_ISLNK(st.st_mode);
}
```