ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_tftp_url>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%rbp
  test   %rdi,%rdi
  je     L155
  mov    %rdi,%r15
  mov    $0x7,%edx
  lea    D2(%rip),%rsi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L155
  add    $0x7,%r15
  movl   $0x0,0x0(%rbp)
  mov    $0x3a,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L92
  movl   $0x10000,0x0(%rbp)
  mov    $0x1,%r14d
L49:
  movb   $0x0,(%rbx)
  mov    %r15,(%r12)
  mov    %r15,%rdi
  call   <isvalhostname@plt>
  test   %eax,%eax
  je     L155
  movslq %r14d,%rax
  add    %rax,%rbx
  cmpl   $0x0,0x0(%rbp)
  jne    L89
  movl   $0x45,0x0(%rbp)
L101:
  mov    %rbx,0x0(%r13)
  mov    $0x1,%eax
  cmpb   $0x0,(%rbx)
  jne    L80
L123:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L92:
  mov    $0x2f,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L82
  mov    %r15,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %r15,%rbx
  mov    $0x0,%r14d
  jmp    L49
L82:
  mov    $0x1,%r14d
  jmp    L49
L89:
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L119
L150:
  movb   $0x0,(%r15)
  mov    %rbx,%rdi
  call   <isport@plt>
  mov    %eax,0x0(%rbp)
  test   %eax,%eax
  je     L155
  movslq %r14d,%r14
  lea    (%r15,%r14,1),%rbx
  jmp    L101
L119:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%r15
  add    %rbx,%r15
  mov    $0x0,%r14d
  jmp    L150
L80:
  mov    %rbx,%rdi
  call   <isvalpath@plt>
  test   %eax,%eax
  je     L155
  cltq
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  setne  %al
  movzbl %al,%eax
  add    $0x1,%eax
  jmp    L123
L155:
  movq   $0x0,(%r12)
  movq   $0x0,0x0(%r13)
  movl   $0x0,0x0(%rbp)
  mov    $0xffffffff,%eax
  jmp    L123
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: tftp://

assistant: ```c
int parse_tftp_url(char *url, char **host, char **path, int *port) {
  char *pos, *end;
  int l = 1;
  if (url == NULL || strncasecmp(url, "tftp://", 7) != 0)
    goto fail;
  pos = url + 7;
  *port = 0;
  end = strchr(pos, ':');
  if (end != NULL)
    *port = 0x010000;
  else
    end = strchr(pos, '/');
  if (end == NULL) {
    end = pos + strlen(pos);
    l = 0;
  }
  *end = '\0';
  *host = pos;
  if (!isvalhostname(*host))
    goto fail;
  pos = end + l;
  if (*port) {
    end = strchr(pos, '/');
    if (end == NULL) {
      end = pos + strlen(pos);
      l = 0;
    }
    *end = '\0';
    *port = isport(pos);
    if (*port == 0)
      goto fail;
    pos = end + l;
  } else
    *port = 69;
  *path = pos;
  if (!**path)
    return 1;
  l = isvalpath(pos);
  if (!l)
    goto fail;
  if (pos[l - 1] == '/')
    return 1;
  return 2;
fail:
  *host = NULL;
  *path = NULL;
  *port = 0;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_tftp_url>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L26
  mov    $0x7,%edx
  lea    D0(%rip),%rsi
  mov    %rdi,%r15
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L26
  movl   $0x0,(%rbx)
  add    $0x7,%r15
  mov    $0x3a,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L9
  movl   $0x10000,(%rbx)
  mov    $0x1,%r14d
L86:
  movb   $0x0,0x0(%rbp)
  mov    %r15,%rdi
  mov    %r15,(%r12)
  call   <isvalhostname@plt>
  test   %eax,%eax
  je     L26
  movslq %r14d,%rax
  add    %rax,%rbp
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L120
  movl   $0x45,(%rbx)
L16:
  mov    %rbp,0x0(%r13)
  cmpb   $0x0,0x0(%rbp)
  jne    L40
L150:
  mov    $0x1,%r8d
L70:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L40:
  mov    %rbp,%rdi
  call   <isvalpath@plt>
  test   %eax,%eax
  je     L26
  cltq
  mov    $0x2,%r8d
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  jne    L70
  jmp    L150
  nopl   0x0(%rax)
L120:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L138
L59:
  movb   $0x0,(%r15)
  mov    %rbp,%rdi
  call   <isport@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  je     L26
  lea    (%r15,%r14,1),%rbp
  jmp    L16
  nopl   (%rax)
L9:
  mov    $0x2f,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L23
  mov    %r15,%rdi
  xor    %r14d,%r14d
  call   <strlen@plt>
  movslq %eax,%rbp
  add    %r15,%rbp
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L138:
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <strlen@plt>
  movslq %eax,%r15
  add    %rbp,%r15
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L26:
  movq   $0x0,(%r12)
  mov    $0xffffffff,%r8d
  movq   $0x0,0x0(%r13)
  movl   $0x0,(%rbx)
  jmp    L70
L23:
  mov    $0x1,%r14d
  jmp    L86
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0: tftp://

assistant: ```c
int parse_tftp_url(char *url, char **host, char **path, int *port) {
  char *pos, *end;
  int l = 1;
  if (url == NULL || strncasecmp(url, "tftp://", 7) != 0)
    goto fail;
  pos = url + 7;
  *port = 0;
  end = strchr(pos, ':');
  if (end != NULL)
    *port = 0x010000;
  else
    end = strchr(pos, '/');
  if (end == NULL) {
    end = pos + strlen(pos);
    l = 0;
  }
  *end = '\0';
  *host = pos;
  if (!isvalhostname(*host))
    goto fail;
  pos = end + l;
  if (*port) {
    end = strchr(pos, '/');
    if (end == NULL) {
      end = pos + strlen(pos);
      l = 0;
    }
    *end = '\0';
    *port = isport(pos);
    if (*port == 0)
      goto fail;
    pos = end + l;
  } else
    *port = 69;
  *path = pos;
  if (!**path)
    return 1;
  l = isvalpath(pos);
  if (!l)
    goto fail;
  if (pos[l - 1] == '/')
    return 1;
  return 2;
fail:
  *host = NULL;
  *path = NULL;
  *port = 0;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_tftp_url>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L41
  mov    $0x7,%edx
  lea    D3(%rip),%rsi
  mov    %rdi,%r15
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L41
  movl   $0x0,(%rbx)
  add    $0x7,%r15
  mov    $0x3a,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L99
  movl   $0x10000,(%rbx)
  mov    $0x1,%r14d
L120:
  movb   $0x0,0x0(%rbp)
  mov    %r15,%rdi
  mov    %r15,(%r12)
  call   <isvalhostname@plt>
  test   %eax,%eax
  je     L41
  mov    (%rbx),%eax
  add    %r14,%rbp
  test   %eax,%eax
  jne    L12
  movl   $0x45,(%rbx)
L44:
  mov    %rbp,0x0(%r13)
  cmpb   $0x0,0x0(%rbp)
  jne    L74
L123:
  mov    $0x1,%eax
L53:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L74:
  mov    %rbp,%rdi
  call   <isvalpath@plt>
  test   %eax,%eax
  je     L41
  cltq
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  je     L123
  add    $0x8,%rsp
  mov    $0x2,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L12:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L58
L144:
  movb   $0x0,(%r15)
  mov    %rbp,%rdi
  call   <isport@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  je     L41
  lea    (%r15,%r14,1),%rbp
  jmp    L44
  nopl   (%rax)
L99:
  mov    $0x2f,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L15
  mov    %r15,%rdi
  xor    %r14d,%r14d
  call   <strlen@plt>
  movslq %eax,%rbp
  add    %r15,%rbp
  jmp    L120
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <strlen@plt>
  movslq %eax,%r15
  add    %rbp,%r15
  jmp    L144
  nopl   0x0(%rax,%rax,1)
L41:
  movq   $0x0,(%r12)
  mov    $0xffffffff,%eax
  movq   $0x0,0x0(%r13)
  movl   $0x0,(%rbx)
  jmp    L53
L15:
  mov    $0x1,%r14d
  jmp    L120
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: tftp://

assistant: ```c
int parse_tftp_url(char *url, char **host, char **path, int *port) {
  char *pos, *end;
  int l = 1;
  if (url == NULL || strncasecmp(url, "tftp://", 7) != 0)
    goto fail;
  pos = url + 7;
  *port = 0;
  end = strchr(pos, ':');
  if (end != NULL)
    *port = 0x010000;
  else
    end = strchr(pos, '/');
  if (end == NULL) {
    end = pos + strlen(pos);
    l = 0;
  }
  *end = '\0';
  *host = pos;
  if (!isvalhostname(*host))
    goto fail;
  pos = end + l;
  if (*port) {
    end = strchr(pos, '/');
    if (end == NULL) {
      end = pos + strlen(pos);
      l = 0;
    }
    *end = '\0';
    *port = isport(pos);
    if (*port == 0)
      goto fail;
    pos = end + l;
  } else
    *port = 69;
  *path = pos;
  if (!**path)
    return 1;
  l = isvalpath(pos);
  if (!l)
    goto fail;
  if (pos[l - 1] == '/')
    return 1;
  return 2;
fail:
  *host = NULL;
  *path = NULL;
  *port = 0;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bpf_obj_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ptr_to_u64@plt>
  mov    %eax,-0xc(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rcx
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sys_bpf@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int bpf_obj_get(const char *pathname) {
  union bpf_attr attr;
  memset(&attr, 0, sizeof(attr));
  attr.pathname = ptr_to_u64((void *)pathname);
  return sys_bpf(BPF_OBJ_GET, &attr, sizeof(attr));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bpf_obj_get>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <ptr_to_u64@plt>
  mov    %eax,0x4(%rsp)
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <sys_bpf@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_obj_get(const char *pathname) {
  union bpf_attr attr;
  memset(&attr, 0, sizeof(attr));
  attr.pathname = ptr_to_u64((void *)pathname);
  return sys_bpf(BPF_OBJ_GET, &attr, sizeof(attr));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bpf_obj_get>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <ptr_to_u64@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %eax,0x4(%rsp)
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <sys_bpf@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_obj_get(const char *pathname) {
  union bpf_attr attr;
  memset(&attr, 0, sizeof(attr));
  attr.pathname = ptr_to_u64((void *)pathname);
  return sys_bpf(BPF_OBJ_GET, &attr, sizeof(attr));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bpf_obj_get>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <ptr_to_u64@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %eax,0x4(%rsp)
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <sys_bpf@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_obj_get(const char *pathname) {
  union bpf_attr attr;
  memset(&attr, 0, sizeof(attr));
  attr.pathname = ptr_to_u64((void *)pathname);
  return sys_bpf(BPF_OBJ_GET, &attr, sizeof(attr));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<patrnfnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  jmp    L0
L14:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L19
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L2
L19:
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L14
L2:
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int patrnfnd(inlin, patrnstr)
char *patrnstr, *inlin;
{
  int patrnfndflg, patrnlen, i, linlen;
  patrnlen = strlen(patrnstr);
  linlen = strlen(inlin);
  for (i = 0, patrnfndflg = -1; i < (linlen - patrnlen); i++)
    if (!strncmp(&(inlin[i]), patrnstr, patrnlen)) {
      patrnfndflg = i;
      break;
    }
  return patrnfndflg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<patrnfnd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %eax,%r14d
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %ebx,%eax
  test   %eax,%eax
  jle    L12
  mov    %eax,%ebp
  mov    $0x0,%ebx
  movslq %r14d,%r14
L21:
  mov    %ebx,%r15d
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L19
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L21
  mov    $0xffffffff,%r15d
L19:
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    $0xffffffff,%r15d
  jmp    L19
```

assistant: ```c
int patrnfnd(inlin, patrnstr)
char *patrnstr, *inlin;
{
  int patrnfndflg, patrnlen, i, linlen;
  patrnlen = strlen(patrnstr);
  linlen = strlen(inlin);
  for (i = 0, patrnfndflg = -1; i < (linlen - patrnlen); i++)
    if (!strncmp(&(inlin[i]), patrnstr, patrnlen)) {
      patrnfndflg = i;
      break;
    }
  return patrnfndflg;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<patrnfnd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  movslq %eax,%r14
  call   <strlen@plt>
  sub    %ebx,%eax
  test   %eax,%eax
  jle    L26
  movslq %eax,%rbp
  xor    %ebx,%ebx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L26
L12:
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %ebx,%r15d
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L27
L37:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L26:
  mov    $0xffffffff,%r15d
  jmp    L37
```

assistant: ```c
int patrnfnd(inlin, patrnstr)
char *patrnstr, *inlin;
{
  int patrnfndflg, patrnlen, i, linlen;
  patrnlen = strlen(patrnstr);
  linlen = strlen(inlin);
  for (i = 0, patrnfndflg = -1; i < (linlen - patrnlen); i++)
    if (!strncmp(&(inlin[i]), patrnstr, patrnlen)) {
      patrnfndflg = i;
      break;
    }
  return patrnfndflg;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<patrnfnd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  movslq %eax,%r14
  call   <strlen@plt>
  sub    %ebx,%eax
  test   %eax,%eax
  jle    L44
  movslq %eax,%rbp
  xor    %ebx,%ebx
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L44
L34:
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %ebx,%r15d
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L39
L18:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L44:
  mov    $0xffffffff,%r15d
  jmp    L18
```

assistant: ```c
int patrnfnd(inlin, patrnstr)
char *patrnstr, *inlin;
{
  int patrnfndflg, patrnlen, i, linlen;
  patrnlen = strlen(patrnstr);
  linlen = strlen(inlin);
  for (i = 0, patrnfndflg = -1; i < (linlen - patrnlen); i++)
    if (!strncmp(&(inlin[i]), patrnstr, patrnlen)) {
      patrnfndflg = i;
      break;
    }
  return patrnfndflg;
}
```
user: What is the c source code of the assembly code below?

```asm
<italy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <germany@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string

tool: D7: I am in  ITALY.


tool: D8: I am back in ITALY.


assistant: ```c
void italy() {
  printf("I am in  ITALY.\n");
  germany();
  printf("I am back in ITALY.\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<italy>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <germany@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string
name: retrieve_data
arguments: data_label: D3
type: string

tool: D1: I am in  ITALY.


tool: D3: I am back in ITALY.


assistant: ```c
void italy() {
  printf("I am in  ITALY.\n");
  germany();
  printf("I am back in ITALY.\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<italy>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <germany@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string

tool: D10: I am in  ITALY.


tool: D4: I am back in ITALY.


assistant: ```c
void italy() {
  printf("I am in  ITALY.\n");
  germany();
  printf("I am back in ITALY.\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<italy>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <germany@plt>
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D9: I am in  ITALY.


tool: D6: I am back in ITALY.


assistant: ```c
void italy() {
  printf("I am in  ITALY.\n");
  germany();
  printf("I am back in ITALY.\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<KeywordHash_Key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L21
L26:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L10
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L10
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    0x20(%rax),%edx
  lea    0x77(%rbx),%eax
  imul   %edx,%eax
  add    %eax,%r12d
  jmp    L2
L10:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  lea    0x77(%rbx),%eax
  imul   %edx,%eax
  add    %eax,%r12d
L2:
  add    $0x1,%ebx
L21:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    %r12d,%eax
  sar    $0xa,%eax
  xor    %r12d,%eax
  mov    %eax,%edx
  mov    %r12d,%eax
  sar    $0x14,%eax
  xor    %edx,%eax
  and    $0x1ff,%eax
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int KeywordHash_Key(char *keyword) {
  int register hash, i;
  hash = 0;
  for (i = 0; keyword[i] != '\0'; i++) {
    if (keyword[i] >= 'A' && keyword[i] <= 'Z')
      hash += (keyword[i] + ('a' - 'A')) * (119 + i);
    else
      hash += keyword[i] * (119 + i);
  }
  hash = (hash ^ (hash >> 10) ^ (hash >> 20)) & (512 - 1);
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<KeywordHash_Key>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L34
  add    $0x1,%rdi
  mov    $0x77,%ecx
  mov    $0x0,%esi
  jmp    L20
L22:
  movsbl %dl,%edx
  imul   %ecx,%edx
  add    %edx,%esi
L12:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    $0x1,%ecx
  test   %dl,%dl
  je     L16
L20:
  lea    -0x41(%rdx),%eax
  cmp    $0x19,%al
  ja     L22
  movsbl %dl,%edx
  add    $0x20,%edx
  imul   %ecx,%edx
  add    %edx,%esi
  jmp    L12
L34:
  mov    $0x0,%esi
L16:
  mov    %esi,%eax
  sar    $0xa,%eax
  mov    %esi,%edx
  sar    $0x14,%edx
  xor    %edx,%eax
  xor    %esi,%eax
  and    $0x1ff,%eax
  ret
```

assistant: ```c
int KeywordHash_Key(char *keyword) {
  int register hash, i;
  hash = 0;
  for (i = 0; keyword[i] != '\0'; i++) {
    if (keyword[i] >= 'A' && keyword[i] <= 'Z')
      hash += (keyword[i] + ('a' - 'A')) * (119 + i);
    else
      hash += keyword[i] * (119 + i);
  }
  hash = (hash ^ (hash >> 10) ^ (hash >> 20)) & (512 - 1);
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<KeywordHash_Key>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L28
  add    $0x1,%rdi
  mov    $0x77,%r8d
  xor    %ecx,%ecx
  sub    %edi,%r8d
  jmp    L41
  nopl   0x0(%rax)
L38:
  add    $0x20,%edx
  add    $0x1,%rdi
  movsbl %dl,%edx
  imul   %eax,%edx
  add    %edx,%ecx
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L20
L41:
  lea    -0x41(%rdx),%esi
  lea    (%r8,%rdi,1),%eax
  cmp    $0x19,%sil
  jbe    L38
  imul   %eax,%edx
  add    $0x1,%rdi
  add    %edx,%ecx
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L41
L20:
  mov    %ecx,%eax
  mov    %ecx,%edx
  sar    $0xa,%eax
  sar    $0x14,%edx
  xor    %edx,%eax
  xor    %ecx,%eax
  and    $0x1ff,%eax
  ret
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
int KeywordHash_Key(char *keyword) {
  int register hash, i;
  hash = 0;
  for (i = 0; keyword[i] != '\0'; i++) {
    if (keyword[i] >= 'A' && keyword[i] <= 'Z')
      hash += (keyword[i] + ('a' - 'A')) * (119 + i);
    else
      hash += keyword[i] * (119 + i);
  }
  hash = (hash ^ (hash >> 10) ^ (hash >> 20)) & (512 - 1);
  return hash;
}
```