ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %edx,%r12d
  sub    %edi,%esi
  mov    %esi,%r14d
  lea    0x1(%rsi),%r15d
  sub    %edx,%ecx
  lea    0x1(%rcx),%ebx
  movslq %r15d,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r15d,%edi
  imul   %ebx,%edi
  movslq %edi,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L15
L32:
  test   %r13,%r13
  je     L1
L38:
  movslq %r12d,%r12
  shl    $0x3,%r12
  sub    %r12,%r13
  mov    %r13,0x0(%rbp)
  cmp    $0x1,%r15d
  jle    L41
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  mov    %rbp,%rax
  lea    -0x1(%r14),%edx
  lea    0x8(%rbp,%rdx,8),%rcx
L10:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rbx,%rdx
  mov    %rdx,(%rax)
  cmp    %rcx,%rax
  jne    L10
L41:
  movslq 0xc(%rsp),%rdx
  shl    $0x3,%rdx
  mov    %rbp,%rax
  sub    %rdx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  lea    D4(%rip),%rdx
  lea    D25(%rip),%rsi
  mov    $0x272,%edi
  call   <errhandler@plt>
  jmp    L32
L1:
  lea    D4(%rip),%rdx
  lea    D25(%rip),%rsi
  mov    $0x273,%edi
  call   <errhandler@plt>
  jmp    L38
```

tool_calls: name: read_data
arguments: label: D4
type: string
name: read_data
arguments: label: D25
type: string

tool: D4: Storage cannot be allocated

tool: D25: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c

assistant: ```c
double **matrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  int nrow = nrh - nrl + 1;
  int ncol = nch - ncl + 1;
  double **pArray = (double **)malloc((size_t)(nrow * sizeof(double *)));
  double *pMatrix = (double *)malloc((size_t)(nrow * ncol * sizeof(double)));
  if (pArray == 0)
    errhandler(626, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c", "Storage cannot be allocated");
  if (pMatrix == 0)
    errhandler(627, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c", "Storage cannot be allocated");
  pArray[0] = pMatrix - ncl;
  for (i = 1; i < nrow; i++) {
    pArray[i] = pArray[i - 1] + ncol;
  }
  return pArray - nrl;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix>:
  endbr64
  push   %r15
  movslq %edx,%r15
  push   %r14
  sub    %r15d,%ecx
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  sub    %ebp,%esi
  lea    0x1(%rcx),%ebx
  lea    0x1(%rsi),%r14d
  mov    %esi,%r12d
  movslq %r14d,%rdi
  sub    $0x18,%rsp
  shl    $0x3,%rdi
  mov    %ebx,0xc(%rsp)
  imul   %r14d,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  movslq %ebx,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r13,%r13
  je     L60
  test   %rbx,%rbx
  je     L51
L15:
  shl    $0x3,%r15
  sub    %r15,%rbx
  mov    %rbx,0x0(%r13)
  mov    %rbx,%rdx
  cmp    $0x1,%r14d
  jle    L41
  movslq 0xc(%rsp),%rcx
  lea    -0x1(%r12),%esi
  lea    0x8(%r13),%rax
  lea    0x8(%r13,%rsi,8),%rsi
  shl    $0x3,%rcx
  jmp    L34
  nopl   0x0(%rax)
L11:
  add    $0x8,%rax
L34:
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L11
L41:
  add    $0x18,%rsp
  shl    $0x3,%rbp
  mov    %r13,%rax
  pop    %rbx
  sub    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  lea    D12(%rip),%rdx
  lea    D35(%rip),%rsi
  mov    $0x272,%edi
  call   <errhandler@plt>
  test   %rbx,%rbx
  jne    L15
L51:
  lea    D12(%rip),%rdx
  lea    D35(%rip),%rsi
  mov    $0x273,%edi
  call   <errhandler@plt>
  jmp    L15
```

tool_calls: name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D35
type: string

tool: D12: Storage cannot be allocated

tool: D35: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c

assistant: ```c
double **matrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  int nrow = nrh - nrl + 1;
  int ncol = nch - ncl + 1;
  double **pArray = (double **)malloc((size_t)(nrow * sizeof(double *)));
  double *pMatrix = (double *)malloc((size_t)(nrow * ncol * sizeof(double)));
  if (pArray == 0)
    errhandler(626, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c", "Storage cannot be allocated");
  if (pMatrix == 0)
    errhandler(627, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c", "Storage cannot be allocated");
  pArray[0] = pMatrix - ncl;
  for (i = 1; i < nrow; i++) {
    pArray[i] = pArray[i - 1] + ncol;
  }
  return pArray - nrl;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matrix>:
  endbr64
  push   %r15
  movslq %edx,%r15
  push   %r14
  sub    %r15d,%ecx
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  sub    %ebp,%esi
  lea    0x1(%rcx),%ebx
  lea    0x1(%rsi),%r14d
  mov    %esi,%r12d
  movslq %r14d,%rdi
  sub    $0x18,%rsp
  shl    $0x3,%rdi
  mov    %ebx,0xc(%rsp)
  imul   %r14d,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  movslq %ebx,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r13,%r13
  je     L3
  test   %rbx,%rbx
  je     L55
L28:
  shl    $0x3,%r15
  sub    %r15,%rbx
  mov    %rbx,0x0(%r13)
  mov    %rbx,%rdx
  cmp    $0x1,%r14d
  jle    L33
  movslq 0xc(%rsp),%rcx
  lea    -0x1(%r12),%esi
  lea    0x8(%r13),%rax
  lea    0x10(%r13,%rsi,8),%rsi
  shl    $0x3,%rcx
  nopw   0x0(%rax,%rax,1)
L42:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rsi,%rax
  jne    L42
L33:
  add    $0x18,%rsp
  shl    $0x3,%rbp
  mov    %r13,%rax
  pop    %rbx
  sub    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  lea    D3(%rip),%rdx
  lea    D22(%rip),%rsi
  mov    $0x272,%edi
  call   <errhandler@plt>
  test   %rbx,%rbx
  jne    L28
L55:
  lea    D3(%rip),%rdx
  lea    D22(%rip),%rsi
  mov    $0x273,%edi
  call   <errhandler@plt>
  jmp    L28
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D22
data_type: string

tool: D3: Storage cannot be allocated

tool: D22: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c

assistant: ```c
double **matrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  int nrow = nrh - nrl + 1;
  int ncol = nch - ncl + 1;
  double **pArray = (double **)malloc((size_t)(nrow * sizeof(double *)));
  double *pMatrix = (double *)malloc((size_t)(nrow * ncol * sizeof(double)));
  if (pArray == 0)
    errhandler(626, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c", "Storage cannot be allocated");
  if (pMatrix == 0)
    errhandler(627, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Backup/FinalProject/helper.c", "Storage cannot be allocated");
  pArray[0] = pMatrix - ncl;
  for (i = 1; i < nrow; i++) {
    pArray[i] = pArray[i - 1] + ncol;
  }
  return pArray - nrl;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strpos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L8
L15:
  mov    $0xffffffff,%eax
L8:
  leave
  ret
```

assistant: ```c
int strpos(char *str, char *rch) {
  char *start = strstr(str, rch);
  if (start) {
    return (int)((start - str) / sizeof(*str));
  } else {
    return -1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L17
  sub    %ebx,%eax
L15:
  pop    %rbx
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L15
```

assistant: ```c
int strpos(char *str, char *rch) {
  char *start = strstr(str, rch);
  if (start) {
    return (int)((start - str) / sizeof(*str));
  } else {
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L1
  sub    %ebx,%eax
  pop    %rbx
  ret
L1:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int strpos(char *str, char *rch) {
  char *start = strstr(str, rch);
  if (start) {
    return (int)((start - str) / sizeof(*str));
  } else {
    return -1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
  sub    %ebx,%eax
  pop    %rbx
  ret
L9:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int strpos(char *str, char *rch) {
  char *start = strstr(str, rch);
  if (start) {
    return (int)((start - str) / sizeof(*str));
  } else {
    return -1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%r9d
  lea    D38(%rip),%r8
  lea    D46(%rip),%rax
  mov    %rax,%rcx
  lea    D17(%rip),%rax
  mov    %rax,%rdx
  lea    D30(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <execl@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D38
type: string
name: retrieve_data
arguments: data_tag: D46
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D30
type: string
name: retrieve_data
arguments: data_tag: D10
type: string

tool: D38: -h

tool: D46: -a

tool: D17: -l

tool: D30: ls

tool: D10: /bin/ls

assistant: ```c
int main(int argc, char *argv[]) {
  execl("/bin/ls", "ls", "-l", "-a", "-h", NULL);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r9d
  lea    D15(%rip),%r8
  lea    D39(%rip),%rcx
  lea    D24(%rip),%rdx
  lea    D32(%rip),%rsi
  lea    D18(%rip),%rdi
  call   <execl@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D39
type_guessed: string
name: unpack_data
arguments: data_label: D24
type_guessed: string
name: unpack_data
arguments: data_label: D32
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string

tool: D15: -h

tool: D39: -a

tool: D24: -l

tool: D32: ls

tool: D18: /bin/ls

assistant: ```c
int main(int argc, char *argv[]) {
  execl("/bin/ls", "ls", "-l", "-a", "-h", NULL);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  lea    D25(%rip),%r8
  lea    D33(%rip),%rcx
  lea    D2(%rip),%rdx
  lea    D9(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <execl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string
name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D25: -h

tool: D33: -a

tool: D2: -l

tool: D9: ls

tool: D1: /bin/ls

assistant: ```c
int main(int argc, char *argv[]) {
  execl("/bin/ls", "ls", "-l", "-a", "-h", NULL);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  lea    D12(%rip),%r8
  lea    D26(%rip),%rcx
  lea    D23(%rip),%rdx
  lea    D33(%rip),%rsi
  lea    D32(%rip),%rdi
  call   <execl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
datatype: string
name: extract_symbolic_data
arguments: label: D26
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D33
datatype: string
name: extract_symbolic_data
arguments: label: D32
datatype: string

tool: D12: -h

tool: D26: -a

tool: D23: -l

tool: D33: ls

tool: D32: /bin/ls

assistant: ```c
int main(int argc, char *argv[]) {
  execl("/bin/ls", "ls", "-l", "-a", "-h", NULL);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rvstrcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %r13d,%eax
  cltq
  add    %rax,%rbx
  jmp    L15
L5:
  sub    $0x1,%rbx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rbx),%edx
  mov    %dl,(%rax)
L15:
  mov    %r13d,%eax
  lea    -0x1(%rax),%r13d
  test   %eax,%eax
  jg     L5
  movb   $0x0,(%r12)
  nop
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void rvstrcpy(register char *rvstr, register char *str) {
  register int i;
  str += (i = strlen(str));
  while (i-- > 0)
    *rvstr++ = *--str;
  *rvstr = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rvstrcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    (%rbx,%rdx,1),%rsi
  test   %eax,%eax
  jle    L7
  mov    %eax,%edi
  add    %rbp,%rdi
  mov    %rbp,%rdx
L12:
  sub    $0x1,%rsi
  add    $0x1,%rdx
  movzbl (%rsi),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L12
  mov    %eax,%eax
  add    %rax,%rbp
L7:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rvstrcpy(register char *rvstr, register char *str) {
  register int i;
  str += (i = strlen(str));
  while (i-- > 0)
    *rvstr++ = *--str;
  *rvstr = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rvstrcpy>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,1),%rsi
  test   %eax,%eax
  jle    L1
  add    %rbx,%rdx
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl -0x1(%rsi),%eax
  add    $0x1,%rbx
  sub    $0x1,%rsi
  mov    %al,-0x1(%rbx)
  cmp    %rdx,%rbx
  jne    L17
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L1:
  mov    %rbx,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rvstrcpy(register char *rvstr, register char *str) {
  register int i;
  str += (i = strlen(str));
  while (i-- > 0)
    *rvstr++ = *--str;
  *rvstr = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<rvstrcpy>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,1),%rsi
  test   %eax,%eax
  jle    L12
  add    %rbx,%rdx
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl -0x1(%rsi),%eax
  add    $0x1,%rbx
  sub    $0x1,%rsi
  mov    %al,-0x1(%rbx)
  cmp    %rdx,%rbx
  jne    L16
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L12:
  mov    %rbx,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rvstrcpy(register char *rvstr, register char *str) {
  register int i;
  str += (i = strlen(str));
  while (i-- > 0)
    *rvstr++ = *--str;
  *rvstr = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L71
  mov    %edi,%ebx
  mov    %rsi,%r12
  lea    0x8(%rsi),%rax
  lea    -0x2(%rdi),%edx
  lea    0x10(%rsi,%rdx,8),%rdi
  mov    $0x0,%edx
  mov    $0x1,%esi
L41:
  mov    (%rax),%rcx
  cmpb   $0x2d,(%rcx)
  cmove  %esi,%edx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L41
  test   %edx,%edx
  je     L69
  lea    -0x3(%rbx),%ebp
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movslq %ebx,%rbx
  mov    -0x8(%r12,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,%r14d
  mov    %ebp,0x4(%rsp)
  test   %ebp,%ebp
  je     L10
  mov    %r13,%rbp
  mov    $0x0,%ebx
L23:
  mov    0x8(%r12,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  ja     L23
L10:
  lea    0x4(%rsp),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <array_remove@plt>
  mov    %rax,%rbp
  cmpl   $0x0,0x4(%rsp)
  je     L50
  mov    $0x0,%ebx
  lea    D28(%rip),%r12
L63:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  ja     L63
L50:
  mov    %rbp,%rdi
  call   <free@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x1,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L71:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  jmp    L33
L69:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  jmp    L33
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D28: %d 

tool: D1: Nombre de parametres insuffisants

assistant: ```c
int main(int argc, char **argv) {
  if (2 > argc) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  }
  int i, test = 0;
  for (i = 1; i < argc; i++) {
    if (*argv[i] == '-')
      test = 1;
  }
  if (test == 0) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  }
  int *arr1 = (int *)malloc((argc - 3) * sizeof(int));
  int index = atoi(argv[argc - 1]);
  unsigned int length = (argc - 3);
  for (i = 0; i < length; i++) {
    arr1[i] = atoi(argv[i + 1]);
  }
  int *result = array_remove(arr1, index, &length);
  for (i = 0; i < (length); i++)
    printf("%d ", *(result + i));
  free(result);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%ebx
  jle    L60
  lea    -0x2(%rbx),%edx
  mov    %rsi,%r12
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdx,8),%rdi
  xor    %edx,%edx
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L37:
  mov    (%rax),%rcx
  cmpb   $0x2d,(%rcx)
  cmove  %esi,%edx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L37
  test   %edx,%edx
  je     L60
  lea    -0x3(%rbx),%ebp
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    -0x8(%r12,%rbx,8),%rdi
  mov    %rax,%r13
  call   <atoi@plt>
  mov    %ebp,0x4(%rsp)
  mov    %eax,%r14d
  test   %ebp,%ebp
  je     L64
  mov    %r13,%rbp
  xor    %ebx,%ebx
  xchg   %ax,%ax
L52:
  mov    0x8(%r12,%rbx,8),%rdi
  add    $0x4,%rbp
  add    $0x1,%rbx
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %ebx,0x4(%rsp)
  ja     L52
L64:
  lea    0x4(%rsp),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <array_remove@plt>
  cmpl   $0x0,0x4(%rsp)
  mov    %rax,%rbp
  je     L19
  xor    %ebx,%ebx
  lea    D11(%rip),%r12
  xchg   %ax,%ax
L26:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  ja     L26
L19:
  mov    %rbp,%rdi
  call   <free@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L60:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  jmp    L17
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string

tool: D11: %d 

tool: D5: Nombre de parametres insuffisants

assistant: ```c
int main(int argc, char **argv) {
  if (2 > argc) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  }
  int i, test = 0;
  for (i = 1; i < argc; i++) {
    if (*argv[i] == '-')
      test = 1;
  }
  if (test == 0) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  }
  int *arr1 = (int *)malloc((argc - 3) * sizeof(int));
  int index = atoi(argv[argc - 1]);
  unsigned int length = (argc - 3);
  for (i = 0; i < length; i++) {
    arr1[i] = atoi(argv[i + 1]);
  }
  int *result = array_remove(arr1, index, &length);
  for (i = 0; i < (length); i++)
    printf("%d ", *(result + i));
  free(result);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%ebx
  jle    L86
  lea    -0x2(%rbx),%edx
  mov    %rsi,%r12
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdx,8),%rdi
  xor    %edx,%edx
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L83:
  mov    (%rax),%rcx
  cmpb   $0x2d,(%rcx)
  cmove  %esi,%edx
  add    $0x8,%rax
  cmp    %rax,%rdi
  jne    L83
  test   %edx,%edx
  je     L86
  lea    -0x3(%rbx),%ebp
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    -0x8(%r12,%rbx,8),%rdi
  mov    %rax,%r13
  call   <atoi@plt>
  mov    %ebp,0x4(%rsp)
  mov    %eax,%r14d
  test   %ebp,%ebp
  je     L64
  mov    %r13,%rbp
  xor    %ebx,%ebx
  xchg   %ax,%ax
L38:
  mov    0x8(%r12,%rbx,8),%rdi
  add    $0x4,%rbp
  add    $0x1,%rbx
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %ebx,0x4(%rsp)
  ja     L38
L64:
  lea    0x4(%rsp),%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <array_remove@plt>
  cmpl   $0x0,0x4(%rsp)
  mov    %rax,%rbp
  je     L39
  xor    %ebx,%ebx
  lea    D14(%rip),%r12
  xchg   %ax,%ax
L40:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  ja     L40
L39:
  mov    %rbp,%rdi
  call   <free@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L86:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L24
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D14: %d 

tool: D15: Nombre de parametres insuffisants

assistant: ```c
int main(int argc, char **argv) {
  if (2 > argc) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  }
  int i, test = 0;
  for (i = 1; i < argc; i++) {
    if (*argv[i] == '-')
      test = 1;
  }
  if (test == 0) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  }
  int *arr1 = (int *)malloc((argc - 3) * sizeof(int));
  int index = atoi(argv[argc - 1]);
  unsigned int length = (argc - 3);
  for (i = 0; i < length; i++) {
    arr1[i] = atoi(argv[i + 1]);
  }
  int *result = array_remove(arr1, index, &length);
  for (i = 0; i < (length); i++)
    printf("%d ", *(result + i));
  free(result);
  return 1;
}
```