user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  lea    0x7(%rsp),%rdx
  lea    0x6(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsbl 0x4(%rsp),%r8d
  mov    %r8d,%eax
  sub    $0x30,%eax
  cmp    $0x21,%al
  ja     L151
  lea    D56(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L151:
  lea    -0x30(%r8),%edx
L21:
  movsbl 0x6(%rsp),%esi
  mov    %esi,%eax
  sub    $0x30,%eax
  cmp    $0x21,%al
  ja     L122
  lea    D48(%rip),%rcx
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
L40:
  mov    $0xe,%edx
L122:
  lea    -0x30(%rsi),%eax
  cs nopw 0x0(%rax,%rax,1)
L61:
  cmp    %edx,%eax
  jl     L95
  jne    L51
  movzbl 0x7(%rsp),%eax
  cmp    %al,0x5(%rsp)
  jge    L51
L95:
  movsbl 0x5(%rsp),%edx
  mov    %r8d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L156
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
  movsbl 0x6(%rsp),%esi
  mov    %esi,%eax
  sub    $0x30,%eax
  cmp    $0x21,%al
  ja     L40
  lea    D54(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xc,%edx
L108:
  movsbl 0x6(%rsp),%esi
  mov    %esi,%eax
  sub    $0x30,%eax
  cmp    $0x21,%al
  ja     L122
  lea    D31(%rip),%rcx
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  mov    $0xb,%edx
  jmp    L108
  mov    $0xd,%edx
  jmp    L21
  mov    $0xe,%edx
  mov    $0x51,%esi
  mov    $0xc,%eax
  jmp    L61
  mov    $0xe,%edx
  mov    $0x4a,%esi
  mov    $0xb,%eax
  jmp    L61
  mov    $0xe,%edx
  mov    $0x41,%esi
  mov    $0xe,%eax
  jmp    L61
  mov    $0xe,%edx
  mov    $0x30,%esi
  mov    $0xa,%eax
  jmp    L61
  mov    $0x4b,%esi
L51:
  movsbl 0x7(%rsp),%edx
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L25
  mov    $0xa,%edx
  jmp    L108
  mov    $0x4b,%esi
  mov    $0xd,%eax
  jmp    L61
L156:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string
name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D5: %c %c 

tool: D6: %c %c


assistant: ```c
int main(void) {
  char c0_dig, c0_suit, c1_dig, c1_suit;
  int c0_val, c1_val;
  scanf("%c %c ", &c0_dig, &c0_suit);
  scanf("%c %c ", &c1_dig, &c1_suit);
  switch (c0_dig) {
  case 'A':
    c0_val = 14;
    break;
  case 'K':
    c0_val = 13;
    break;
  case 'Q':
    c0_val = 12;
    break;
  case 'J':
    c0_val = 11;
    break;
  case '0':
    c0_val = 10;
    break;
  default:
    c0_val = c0_dig - '0';
  }
  switch (c1_dig) {
  case 'A':
    c1_val = 14;
    break;
  case 'K':
    c1_val = 13;
    break;
  case 'Q':
    c1_val = 12;
    break;
  case 'J':
    c1_val = 11;
    break;
  case '0':
    c1_val = 10;
    break;
  default:
    c1_val = c1_dig - '0';
  }
  if (c0_val > c1_val || (c0_val == c1_val && c0_suit < c1_suit))
    printf("%c %c\n", c0_dig, c0_suit);
  else
    printf("%c %c\n", c1_dig, c1_suit);
  return 0;
}
```