ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<oauth_url_unescape>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L24
  call   <strlen@plt>
  lea    0x1(%rax),%r14d
  movslq %r14d,%r14
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %rax,0x8(%rsp)
  mov    %r14,%rbp
  sub    $0x1,%rbp
  je     L69
  mov    $0x0,%r13d
  lea    0x25(%rsp),%rax
  mov    %rax,0x18(%rsp)
  jmp    L105
L59:
  lea    0x1(%r13),%rax
  mov    %r12b,(%r15,%r13,1)
  add    $0x1,%rbx
  mov    %rbp,%rdx
  sub    $0x1,%rdx
  je     L43
  mov    %rax,%r13
  mov    %rbp,%r14
  mov    %rdx,%rbp
L105:
  movzbl (%rbx),%r12d
  cmp    $0x25,%r12b
  jne    L59
  movzbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L59
  movzbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L59
  movzbl 0x1(%rbx),%eax
  mov    %al,0x25(%rsp)
  movzbl 0x2(%rbx),%eax
  mov    %al,0x26(%rsp)
  movb   $0x0,0x27(%rsp)
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    0x18(%rsp),%rdi
  call   <strtol@plt>
  mov    %eax,%r12d
  add    $0x2,%rbx
  lea    -0x3(%r14),%rbp
  jmp    L59
L69:
  mov    %rbp,%rax
L43:
  movb   $0x0,(%r15,%rax,1)
  mov    0x10(%rsp),%rcx
  test   %rcx,%rcx
  je     L86
  mov    %rax,(%rcx)
L86:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    0x8(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  mov    %rdi,0x8(%rsp)
  jmp    L86
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *oauth_url_unescape(const char *string, size_t *olen) {
  size_t alloc, strindex = 0;
  char *ns = NULL;
  unsigned char in;
  long hex;
  if (!string)
    return NULL;
  alloc = strlen(string) + 1;
  ns = (char *)malloc(alloc);
  while (--alloc > 0) {
    in = *string;
    if (('%' == in) && (isxdigit((int)((unsigned char)string[1]))) && (isxdigit((int)((unsigned char)string[2])))) {
      char hexstr[3];
      hexstr[0] = string[1];
      hexstr[1] = string[2];
      hexstr[2] = 0;
      hex = strtol(hexstr, NULL, 16);
      in = (unsigned char)hex;
      string += 2;
      alloc -= 2;
    }
    ns[strindex++] = in;
    string++;
  }
  ns[strindex] = 0;
  if (olen)
    *olen = strindex;
  return ns;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<oauth_url_unescape>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L119
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%ecx
  movslq %ecx,%r13
  mov    %r13,%rdi
  mov    %r13,%rbp
  call   <malloc@plt>
  mov    %rax,%r14
  sub    $0x1,%rbp
  je     L87
  lea    0x15(%rsp),%rax
  xor    %r15d,%r15d
  mov    %rax,0x8(%rsp)
  jmp    L27
  nopl   0x0(%rax)
L116:
  mov    %rbp,%rdx
  mov    %r12b,(%r14,%r15,1)
  lea    0x1(%r15),%rax
  add    $0x1,%rbx
  sub    $0x1,%rdx
  je     L8
  mov    %rbp,%r13
  mov    %rax,%r15
  mov    %rdx,%rbp
L27:
  movzbl (%rbx),%r12d
  cmp    $0x25,%r12b
  jne    L116
  movzbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L116
  movzbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L116
  movzwl 0x1(%rbx),%eax
  mov    0x8(%rsp),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  movb   $0x0,0x17(%rsp)
  add    $0x2,%rbx
  lea    -0x3(%r13),%rbp
  mov    %ax,0x15(%rsp)
  call   <strtol@plt>
  mov    %eax,%r12d
  jmp    L116
  nopl   0x0(%rax,%rax,1)
L8:
  lea    (%r14,%rax,1),%rdx
L45:
  mov    (%rsp),%rcx
  movb   $0x0,(%rdx)
  test   %rcx,%rcx
  je     L85
  mov    %rax,(%rcx)
L85:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L119:
  xor    %r14d,%r14d
  jmp    L85
  nopl   (%rax)
L87:
  mov    %rax,%rdx
  xor    %eax,%eax
  jmp    L45
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *oauth_url_unescape(const char *string, size_t *olen) {
  size_t alloc, strindex = 0;
  char *ns = NULL;
  unsigned char in;
  long hex;
  if (!string)
    return NULL;
  alloc = strlen(string) + 1;
  ns = (char *)malloc(alloc);
  while (--alloc > 0) {
    in = *string;
    if (('%' == in) && (isxdigit((int)((unsigned char)string[1]))) && (isxdigit((int)((unsigned char)string[2])))) {
      char hexstr[3];
      hexstr[0] = string[1];
      hexstr[1] = string[2];
      hexstr[2] = 0;
      hex = strtol(hexstr, NULL, 16);
      in = (unsigned char)hex;
      string += 2;
      alloc -= 2;
    }
    ns[strindex++] = in;
    string++;
  }
  ns[strindex] = 0;
  if (olen)
    *olen = strindex;
  return ns;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<oauth_url_unescape>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L26
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%ecx
  movslq %ecx,%r13
  mov    %r13,%rdi
  mov    %r13,%rbp
  call   <malloc@plt>
  mov    %rax,%r14
  sub    $0x1,%rbp
  je     L70
  lea    0x14(%rsp),%rax
  xor    %r15d,%r15d
  mov    %rax,0x8(%rsp)
  jmp    L58
  nopl   0x0(%rax)
L54:
  mov    %rbp,%rdx
  mov    %r12b,(%r14,%r15,1)
  lea    0x1(%r15),%rax
  add    $0x1,%rbx
  sub    $0x1,%rdx
  je     L8
  mov    %rbp,%r13
  mov    %rax,%r15
  mov    %rdx,%rbp
L58:
  movzbl (%rbx),%r12d
  cmp    $0x25,%r12b
  jne    L54
  movzbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L54
  movzbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L54
  movzwl 0x1(%rbx),%eax
  mov    0x8(%rsp),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  movb   $0x0,0x16(%rsp)
  add    $0x2,%rbx
  lea    -0x3(%r13),%rbp
  mov    %ax,0x14(%rsp)
  call   <strtol@plt>
  mov    %eax,%r12d
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L8:
  lea    (%r14,%rax,1),%rdx
L49:
  mov    (%rsp),%rcx
  movb   $0x0,(%rdx)
  test   %rcx,%rcx
  je     L45
  mov    %rax,(%rcx)
L45:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x28,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L26:
  xor    %r14d,%r14d
  jmp    L45
  nopl   (%rax)
L70:
  mov    %rax,%rdx
  xor    %eax,%eax
  jmp    L49
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *oauth_url_unescape(const char *string, size_t *olen) {
  size_t alloc, strindex = 0;
  char *ns = NULL;
  unsigned char in;
  long hex;
  if (!string)
    return NULL;
  alloc = strlen(string) + 1;
  ns = (char *)malloc(alloc);
  while (--alloc > 0) {
    in = *string;
    if (('%' == in) && (isxdigit((int)((unsigned char)string[1]))) && (isxdigit((int)((unsigned char)string[2])))) {
      char hexstr[3];
      hexstr[0] = string[1];
      hexstr[1] = string[2];
      hexstr[2] = 0;
      hex = strtol(hexstr, NULL, 16);
      in = (unsigned char)hex;
      string += 2;
      alloc -= 2;
    }
    ns[strindex++] = in;
    string++;
  }
  ns[strindex] = 0;
  if (olen)
    *olen = strindex;
  return ns;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <myprintf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <myprintf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <myprintf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D33
type_guessed: string
name: parse_data
arguments: tag: D0
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D15
type_guessed: string

tool: D33: vector:%djik


tool: D0: dfufhdufhd


tool: D1: fahad

tool: D15: %s

assistant: ```c
main() {
  int v = 5;
  myprintf("vector:%djik\n", v);
  myprintf("dfufhdufhd\n");
  myprintf("%s", "fahad");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <myprintf@plt>
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <myprintf@plt>
  lea    D6(%rip),%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <myprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
type: string
name: extract_symbolic_data
arguments: data_label: D26
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D28
type: string

tool: D27: vector:%djik


tool: D26: dfufhdufhd


tool: D6: fahad

tool: D28: %s

assistant: ```c
main() {
  int v = 5;
  myprintf("vector:%djik\n", v);
  myprintf("dfufhdufhd\n");
  myprintf("%s", "fahad");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <myprintf@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <myprintf@plt>
  lea    D18(%rip),%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <myprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type_infered: string
name: retrieve_data
arguments: data_label: D33
type_infered: string
name: retrieve_data
arguments: data_label: D18
type_infered: string
name: retrieve_data
arguments: data_label: D29
type_infered: string

tool: D14: vector:%djik


tool: D33: dfufhdufhd


tool: D18: fahad

tool: D29: %s

assistant: ```c
main() {
  int v = 5;
  myprintf("vector:%djik\n", v);
  myprintf("dfufhdufhd\n");
  myprintf("%s", "fahad");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <myprintf@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <myprintf@plt>
  lea    D32(%rip),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <myprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D35
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D32
type_infered: string
name: unpack_data
arguments: tag: D19
type_infered: string

tool: D35: vector:%djik


tool: D12: dfufhdufhd


tool: D32: fahad

tool: D19: %s

assistant: ```c
main() {
  int v = 5;
  myprintf("vector:%djik\n", v);
  myprintf("dfufhdufhd\n");
  myprintf("%s", "fahad");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_isascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  jg     L19
  cmpl   $0x0,-0x4(%rbp)
  js     L19
  mov    $0x1,%eax
  jmp    L2
L19:
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isascii(int c) {
  if (c <= 127 && c >= 0)
    return (1);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_isascii>:
  endbr64
  cmp    $0x7f,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_isascii(int c) {
  if (c <= 127 && c >= 0)
    return (1);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_isascii>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7f,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_isascii(int c) {
  if (c <= 127 && c >= 0)
    return (1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_isascii>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7f,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_isascii(int c) {
  if (c <= 127 && c >= 0)
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L16
L11:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L12
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
L12:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *substring(char **str, int ini, int nchars) {
  int i, j;
  char *sub = (char *)malloc(sizeof(char) * (nchars + 1));
  for (i = 0, j = ini; i < nchars && str[0][i] != '\0'; i++, j++)
    sub[i] = str[0][j];
  sub[nchars] = '\0';
  return sub;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<substring>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  lea    0x1(%rdx),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L22
  mov    %ebp,%edi
  mov    $0x0,%edx
  movslq %r12d,%rsi
L27:
  mov    (%rbx),%rcx
  cmpb   $0x0,(%rcx,%rdx,1)
  je     L22
  add    %rdx,%rcx
  movzbl (%rcx,%rsi,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L27
L22:
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *substring(char **str, int ini, int nchars) {
  int i, j;
  char *sub = (char *)malloc(sizeof(char) * (nchars + 1));
  for (i = 0, j = ini; i < nchars && str[0][i] != '\0'; i++, j++)
    sub[i] = str[0][j];
  sub[nchars] = '\0';
  return sub;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<substring>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    0x1(%rdx),%edi
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <malloc@plt>
  movslq %ebx,%rdx
  xor    %ecx,%ecx
  test   %ebx,%ebx
  jg     L5
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L16:
  add    %rcx,%rsi
  movzbl (%rsi,%rbp,1),%esi
  mov    %sil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L24
L5:
  mov    (%r12),%rsi
  cmpb   $0x0,(%rsi,%rcx,1)
  jne    L16
L24:
  movb   $0x0,(%rax,%rdx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *substring(char **str, int ini, int nchars) {
  int i, j;
  char *sub = (char *)malloc(sizeof(char) * (nchars + 1));
  for (i = 0, j = ini; i < nchars && str[0][i] != '\0'; i++, j++)
    sub[i] = str[0][j];
  sub[nchars] = '\0';
  return sub;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<substring>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    0x1(%rdx),%edi
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <malloc@plt>
  movslq %ebx,%rdx
  xor    %ecx,%ecx
  test   %ebx,%ebx
  jg     L21
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L18:
  add    %rcx,%rsi
  movzbl (%rsi,%rbp,1),%esi
  mov    %sil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L26
L21:
  mov    (%r12),%rsi
  cmpb   $0x0,(%rsi,%rcx,1)
  jne    L18
L26:
  movb   $0x0,(%rax,%rdx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *substring(char **str, int ini, int nchars) {
  int i, j;
  char *sub = (char *)malloc(sizeof(char) * (nchars + 1));
  for (i = 0, j = ini; i < nchars && str[0][i] != '\0'; i++, j++)
    sub[i] = str[0][j];
  sub[nchars] = '\0';
  return sub;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: 
Usage: cssrc2html [-options] filename
options:
  -tn  set tab spacing to n (default 4)
  -v   display version number and exit
  -h or -? display this help message and exit



assistant: ```c
void usage(void) {
  printf("\nUsage: cssrc2html [-options] filename"
         "\noptions:"
         "\n  -tn  set tab spacing to n (default 4)"
         "\n  -v   display version number and exit"
         "\n  -h or -? display this help message and exit"
         "\n\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string

tool: D2: 
Usage: cssrc2html [-options] filename
options:
  -tn  set tab spacing to n (default 4)
  -v   display version number and exit
  -h or -? display this help message and exit



assistant: ```c
void usage(void) {
  printf("\nUsage: cssrc2html [-options] filename"
         "\noptions:"
         "\n  -tn  set tab spacing to n (default 4)"
         "\n  -v   display version number and exit"
         "\n  -h or -? display this help message and exit"
         "\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<usage>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: 
Usage: cssrc2html [-options] filename
options:
  -tn  set tab spacing to n (default 4)
  -v   display version number and exit
  -h or -? display this help message and exit



assistant: ```c
void usage(void) {
  printf("\nUsage: cssrc2html [-options] filename"
         "\noptions:"
         "\n  -tn  set tab spacing to n (default 4)"
         "\n  -v   display version number and exit"
         "\n  -h or -? display this help message and exit"
         "\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: 
Usage: cssrc2html [-options] filename
options:
  -tn  set tab spacing to n (default 4)
  -v   display version number and exit
  -h or -? display this help message and exit



assistant: ```c
void usage(void) {
  printf("\nUsage: cssrc2html [-options] filename"
         "\noptions:"
         "\n  -tn  set tab spacing to n (default 4)"
         "\n  -v   display version number and exit"
         "\n  -h or -? display this help message and exit"
         "\n\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L4:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L4
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int str2int(char num[], int a, int b) {
  int temp = 0;
  for (int i = a; i <= b; i++) {
    temp = temp * 10 + (num[i] - '0');
  }
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str2int>:
  endbr64
  cmp    %edx,%esi
  jg     L29
  movslq %esi,%rcx
  lea    (%rdi,%rcx,1),%rax
  lea    0x1(%rdi,%rcx,1),%rcx
  sub    %esi,%edx
  lea    (%rcx,%rdx,1),%rsi
  mov    $0x0,%edx
L3:
  lea    (%rdx,%rdx,4),%ecx
  movsbl (%rax),%edx
  lea    -0x30(%rdx,%rcx,2),%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L3
L0:
  mov    %edx,%eax
  ret
L29:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
int str2int(char num[], int a, int b) {
  int temp = 0;
  for (int i = a; i <= b; i++) {
    temp = temp * 10 + (num[i] - '0');
  }
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<str2int>:
  endbr64
  cmp    %edx,%esi
  jg     L12
  movslq %esi,%rcx
  sub    %esi,%edx
  xor    %r8d,%r8d
  lea    (%rdi,%rcx,1),%rax
  lea    0x1(%rdi,%rcx,1),%rcx
  lea    (%rcx,%rdx,1),%rsi
  nopl   (%rax)
L13:
  movsbl (%rax),%edx
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rax
  lea    -0x30(%rdx,%rcx,2),%r8d
  cmp    %rsi,%rax
  jne    L13
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str2int(char num[], int a, int b) {
  int temp = 0;
  for (int i = a; i <= b; i++) {
    temp = temp * 10 + (num[i] - '0');
  }
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str2int>:
  endbr64
  cmp    %edx,%esi
  jg     L15
  movslq %esi,%rcx
  sub    %esi,%edx
  xor    %r8d,%r8d
  lea    (%rdi,%rcx,1),%rax
  lea    0x1(%rdi,%rcx,1),%rcx
  lea    (%rcx,%rdx,1),%rsi
  nopl   (%rax)
L4:
  movsbl (%rax),%edx
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rax
  lea    -0x30(%rdx,%rcx,2),%r8d
  cmp    %rax,%rsi
  jne    L4
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str2int(char num[], int a, int b) {
  int temp = 0;
  for (int i = a; i <= b; i++) {
    temp = temp * 10 + (num[i] - '0');
  }
  return temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<blow_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x73,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: rad days

assistant: ```c
void blow_up(int unused) {
  char *message = "rad days";
  *message = 's';
}
```
user: What is the c source code of the assembly code below:

```asm
<blow_up>:
  endbr64
  movb   $0x73,D1(%rip)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: byte

tool: D1: 114

assistant: ```c
void blow_up(int unused) {
  char *message = "rad days";
  *message = 's';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<blow_up>:
  endbr64
  movb   $0x73,D6(%rip)
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: byte

tool: D6: 114

assistant: ```c
void blow_up(int unused) {
  char *message = "rad days";
  *message = 's';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<blow_up>:
  endbr64
  movb   $0x73,D2(%rip)
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: byte

tool: D2: 114

assistant: ```c
void blow_up(int unused) {
  char *message = "rad days";
  *message = 's';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xawrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L8:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <xwrite@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L16:
  cmpl   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t xawrite(int fd, const void *buf, size_t count) {
  int nwritten, remain;
  for (remain = count; remain; remain -= nwritten)
    buf += (nwritten = xwrite(fd, buf, remain));
  return count;
}
```