ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_indexof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  sub    %eax,%ebp
  js     L23
  mov    %eax,%r15d
  xor    %ebx,%ebx
  jmp    L30
  nopl   0x0(%rax)
L15:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jl     L23
L30:
  lea    (%r12,%rbx,1),%rdi
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %ebx,%r14d
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L15
L18:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0xffffffff,%r14d
  jmp    L18
```

assistant: ```c
int str_indexof(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  int hlen = (int)strlen(haystack);
  int nlen = (int)strlen(needle);
  for (int i = 0; i <= hlen - nlen; i++) {
    if (!strncmp(&haystack[i], needle, nlen))
      return i;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_indexof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  sub    %eax,%ebp
  js     L14
  mov    %eax,%r15d
  xor    %ebx,%ebx
  jmp    L21
  nopl   0x0(%rax)
L31:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jl     L14
L21:
  lea    (%r12,%rbx,1),%rdi
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %ebx,%r14d
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L31
L8:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xffffffff,%r14d
  jmp    L8
```

assistant: ```c
int str_indexof(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  int hlen = (int)strlen(haystack);
  int nlen = (int)strlen(needle);
  for (int i = 0; i <= hlen - nlen; i++) {
    if (!strncmp(&haystack[i], needle, nlen))
      return i;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x14,%esi
  mov    $0x2100,%edi
  call   <__send_to_ppe@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int getchar() {
  int ret;
  ;
  return __send_to_ppe(0x2100, 20, &ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getchar>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    $0x14,%esi
  mov    $0x2100,%edi
  call   <__send_to_ppe@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getchar() {
  int ret;
  ;
  return __send_to_ppe(0x2100, 20, &ret);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getchar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x14,%esi
  mov    $0x2100,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__send_to_ppe@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getchar() {
  int ret;
  ;
  return __send_to_ppe(0x2100, 20, &ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getchar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x14,%esi
  mov    $0x2100,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__send_to_ppe@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getchar() {
  int ret;
  ;
  return __send_to_ppe(0x2100, 20, &ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_valid_id_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L39
  cmpb   $0x5a,-0x4(%rbp)
  jle    L77
L39:
  cmpb   $0x60,-0x4(%rbp)
  jle    L73
  cmpb   $0x7a,-0x4(%rbp)
  jle    L77
L73:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L11
  cmpb   $0x39,-0x4(%rbp)
  jle    L77
L11:
  cmpb   $0x5f,-0x4(%rbp)
  je     L77
  cmpb   $0x2d,-0x4(%rbp)
  je     L77
  cmpb   $0x0,-0x4(%rbp)
  jne    L78
L77:
  mov    $0x1,%eax
  jmp    L5
L78:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int is_valid_id_char(char current, char previous) {
  (void)(previous);
  if (0 || (current >= 'A' && current <= 'Z') || (current >= 'a' && current <= 'z') || (current >= '0' && current <= '9') || (current == '_') || (current == '-') || (current == '\0')) {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_valid_id_char>:
  endbr64
  mov    %edi,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  mov    $0x1,%eax
  cmp    $0x19,%dl
  jbe    L8
  test   %dil,%dil
  je     L22
  lea    -0x2d(%rdi),%ecx
  mov    $0x0,%eax
  cmp    $0x32,%cl
  ja     L8
  movabs $0x4000000001ff9,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L22:
  mov    $0x1,%eax
L8:
  ret
```

assistant: ```c
int is_valid_id_char(char current, char previous) {
  (void)(previous);
  if (0 || (current >= 'A' && current <= 'Z') || (current >= 'a' && current <= 'z') || (current >= '0' && current <= '9') || (current == '_') || (current == '-') || (current == '\0')) {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_valid_id_char>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L13
  test   %dil,%dil
  je     L13
  lea    -0x2d(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x32,%cl
  ja     L13
  movabs $0x4000000001ff9,%rax
  shr    %cl,%rax
  and    $0x1,%eax
L13:
  ret
```

assistant: ```c
int is_valid_id_char(char current, char previous) {
  (void)(previous);
  if (0 || (current >= 'A' && current <= 'Z') || (current >= 'a' && current <= 'z') || (current >= '0' && current <= '9') || (current == '_') || (current == '-') || (current == '\0')) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_valid_id_char>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L9
  test   %dil,%dil
  je     L9
  lea    -0x2d(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x32,%cl
  ja     L9
  movabs $0x4000000001ff9,%rax
  shr    %cl,%rax
  and    $0x1,%eax
L9:
  ret
```

assistant: ```c
int is_valid_id_char(char current, char previous) {
  (void)(previous);
  if (0 || (current >= 'A' && current <= 'Z') || (current >= 'a' && current <= 'z') || (current >= '0' && current <= '9') || (current == '_') || (current == '-') || (current == '\0')) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<file_remove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <file_exists@plt>
  test   %rax,%rax
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L15
L8:
  mov    $0x1,%eax
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: Removing file '%s'...

assistant: ```c
int file_remove(char *filename) {
  if (file_exists(filename)) {
    debug("Removing file '%s'...", filename);
    return (!unlink(filename));
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_remove>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <file_exists@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L19
L10:
  pop    %rbx
  ret
L19:
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <debug@plt>
  mov    %rbx,%rdi
  call   <unlink@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: Removing file '%s'...

assistant: ```c
int file_remove(char *filename) {
  if (file_exists(filename)) {
    debug("Removing file '%s'...", filename);
    return (!unlink(filename));
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<file_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <file_exists@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L5
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: D9: Removing file '%s'...

assistant: ```c
int file_remove(char *filename) {
  if (file_exists(filename)) {
    debug("Removing file '%s'...", filename);
    return (!unlink(filename));
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<file_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <file_exists@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L8
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: Removing file '%s'...

assistant: ```c
int file_remove(char *filename) {
  if (file_exists(filename)) {
    debug("Removing file '%s'...", filename);
    return (!unlink(filename));
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SplitFN>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L181
  mov    %rax,%rdi
  test   %rbx,%rbx
  je     L230
  movb   $0x0,(%rbx)
L230:
  test   %r12,%r12
  je     L19
  movb   $0x0,(%r12)
L19:
  test   %edi,%edi
  jle    L170
  lea    -0x1(%rdi),%r8d
  add    $0x2,%r8
  mov    $0x1,%eax
  mov    $0x0,%esi
  movabs $0x200000000801,%r9
  jmp    L85
L109:
  mov    %r9,%r10
  shr    %cl,%r10
  test   $0x1,%r10b
  cmovne %eax,%esi
L231:
  test   %rbx,%rbx
  je     L195
  mov    %dl,-0x1(%rbx,%rax,1)
L195:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L227
L85:
  movzbl -0x1(%rbp,%rax,1),%edx
  lea    -0x2f(%rdx),%ecx
  cmp    $0x2d,%cl
  ja     L231
  jmp    L109
L227:
  test   %rbx,%rbx
  je     L217
  movslq %edi,%rax
  movb   $0x0,(%rbx,%rax,1)
  test   %esi,%esi
  je     L236
L242:
  cmp    %esi,%edi
  jle    L24
  mov    %esi,%r9d
  lea    -0x1(%rdi),%ecx
  sub    %esi,%ecx
  mov    $0x0,%eax
  movslq %esi,%r8
  add    %rbp,%r8
  jmp    L118
L92:
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rax
  je     L31
  mov    %rdx,%rax
L118:
  test   %r12,%r12
  je     L92
  movzbl (%r8,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  jmp    L92
L31:
  sub    %r9d,%edi
L6:
  test   %r12,%r12
  je     L16
  movslq %edi,%rdi
  movb   $0x0,(%r12,%rdi,1)
L16:
  mov    %esi,%eax
  test   %rbx,%rbx
  je     L181
  movslq %esi,%rax
  movb   $0x0,(%rbx,%rax,1)
  mov    %esi,%eax
L181:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    $0x0,%edi
  jmp    L6
L210:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L191
L217:
  mov    %esi,%eax
  test   %esi,%esi
  je     L181
  jmp    L242
L170:
  mov    $0x0,%esi
  test   %rbx,%rbx
  je     L217
  movb   $0x0,(%rbx)
L236:
  test   %r12,%r12
  jne    L210
L191:
  movb   $0x0,(%rbx)
  mov    $0x0,%eax
  jmp    L181
```

assistant: ```c
int SplitFN(char *lpdir, char *lpfil, char *lpext) {
  int i, j, k, l;
  char c;
  k = 0;
  i = (int)strlen(lpext);
  if (i) {
    if (lpdir)
      *lpdir = 0;
    if (lpfil)
      *lpfil = 0;
    for (j = 0; j < i; j++) {
      c = lpext[j];
      if ((c == ':') || (c == '\\') || (c == '/')) {
        k = j + 1;
      }
      if (lpdir)
        lpdir[j] = c;
    }
    if (lpdir)
      lpdir[j] = 0;
    if (k) {
      j = 0;
      for (l = k; l < i; l++) {
        c = lpext[l];
        if (lpfil)
          lpfil[j] = c;
        j++;
      }
      if (lpfil)
        lpfil[j] = 0;
      if (lpdir)
        lpdir[k] = 0;
    } else {
      if (lpfil && lpdir)
        strcpy(lpfil, lpdir);
      if (lpdir)
        *lpdir = 0;
    }
  }
  return k;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SplitFN>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L117
  mov    %rax,%rsi
  mov    %eax,%edi
  test   %rbx,%rbx
  je     L90
  movb   $0x0,(%rbx)
L90:
  test   %r12,%r12
  je     L191
  movb   $0x0,(%r12)
L191:
  movabs $0xffffdffffffff7fe,%r10
  xor    %eax,%eax
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L146
  nop
L25:
  movzbl 0x0(%rbp,%rax,1),%edx
  lea    -0x2f(%rdx),%ecx
  cmp    $0x2d,%cl
  ja     L10
  mov    %r10,%r11
  lea    0x1(%rax),%r9d
  sar    %cl,%r11
  mov    %r11,%rcx
  and    $0x1,%ecx
  cmove  %r9d,%r8d
L10:
  test   %rbx,%rbx
  je     L139
  mov    %dl,(%rbx,%rax,1)
L139:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L25
  test   %rbx,%rbx
  je     L64
  movslq %esi,%rax
  movb   $0x0,(%rbx,%rax,1)
  test   %r8d,%r8d
  je     L180
L176:
  cmp    %esi,%r8d
  jge    L85
  lea    -0x1(%rsi),%ecx
  movslq %r8d,%rdi
  xor    %eax,%eax
  sub    %r8d,%ecx
  add    %rbp,%rdi
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L84:
  mov    %rdx,%rax
L13:
  test   %r12,%r12
  je     L127
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
L127:
  lea    0x1(%rax),%rdx
  cmp    %rax,%rcx
  jne    L84
  sub    %r8d,%esi
L8:
  test   %r12,%r12
  je     L114
  movslq %esi,%rsi
  movb   $0x0,(%r12,%rsi,1)
L114:
  test   %rbx,%rbx
  je     L26
  movslq %r8d,%rax
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L64:
  test   %r8d,%r8d
  jne    L176
  nopl   (%rax)
L117:
  xor    %r8d,%r8d
L26:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L146:
  test   %rbx,%rbx
  je     L117
  movb   $0x0,(%rbx)
L180:
  test   %r12,%r12
  je     L118
  test   %rbx,%rbx
  je     L118
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L118:
  xor    %r8d,%r8d
  movb   $0x0,(%rbx)
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L85:
  xor    %esi,%esi
  jmp    L8
```

assistant: ```c
int SplitFN(char *lpdir, char *lpfil, char *lpext) {
  int i, j, k, l;
  char c;
  k = 0;
  i = (int)strlen(lpext);
  if (i) {
    if (lpdir)
      *lpdir = 0;
    if (lpfil)
      *lpfil = 0;
    for (j = 0; j < i; j++) {
      c = lpext[j];
      if ((c == ':') || (c == '\\') || (c == '/')) {
        k = j + 1;
      }
      if (lpdir)
        lpdir[j] = c;
    }
    if (lpdir)
      lpdir[j] = 0;
    if (k) {
      j = 0;
      for (l = k; l < i; l++) {
        c = lpext[l];
        if (lpfil)
          lpfil[j] = c;
        j++;
      }
      if (lpfil)
        lpfil[j] = 0;
      if (lpdir)
        lpdir[k] = 0;
    } else {
      if (lpfil && lpdir)
        strcpy(lpfil, lpdir);
      if (lpdir)
        *lpdir = 0;
    }
  }
  return k;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ldexp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x2c(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm1,-0x38(%rbp)
  fldl   -0x38(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  fldl   -0x38(%rbp)
  fscale
  fxch   %st(1)
  fstpl  -0x10(%rbp)
  fstpl  -0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double ldexp(double value, int exp) {
  double temp, texp, temp2;
  texp = exp;
  __asm("fscale " : "=u"(temp2), "=t"(temp) : "0"(texp), "1"(value));
  return (temp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ldexp>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  movsd  %xmm1,-0x8(%rsp)
  fldl   -0x8(%rsp)
  movsd  %xmm0,-0x8(%rsp)
  fldl   -0x8(%rsp)
  fscale
  fstp   %st(1)
  fstpl  -0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  ret
```

assistant: ```c
double ldexp(double value, int exp) {
  double temp, texp, temp2;
  texp = exp;
  __asm("fscale " : "=u"(temp2), "=t"(temp) : "0"(texp), "1"(value));
  return (temp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ldexp>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  movsd  %xmm1,-0x8(%rsp)
  fldl   -0x8(%rsp)
  movsd  %xmm0,-0x8(%rsp)
  fldl   -0x8(%rsp)
  fscale
  fstp   %st(1)
  fstpl  -0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  ret
```

assistant: ```c
double ldexp(double value, int exp) {
  double temp, texp, temp2;
  texp = exp;
  __asm("fscale " : "=u"(temp2), "=t"(temp) : "0"(texp), "1"(value));
  return (temp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ldexp>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  movsd  %xmm1,-0x8(%rsp)
  fldl   -0x8(%rsp)
  movsd  %xmm0,-0x8(%rsp)
  fldl   -0x8(%rsp)
  fscale
  fstp   %st(1)
  fstpl  -0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  ret
```

assistant: ```c
double ldexp(double value, int exp) {
  double temp, texp, temp2;
  texp = exp;
  __asm("fscale " : "=u"(temp2), "=t"(temp) : "0"(texp), "1"(value));
  return (temp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<permutationR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L39
L25:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <permutationR>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L39:
  nop
  leave
  ret
```

assistant: ```c
void permutationR(char *string, char *first) {
  if (*first == '\0') {
    puts(string);
  } else {
    for (char *ch = first; *ch != '\0'; ++ch) {
      char tmpChar = *ch;
      *ch = *first;
      *first = tmpChar;
      permutationR(string, first + 1);
      tmpChar = *ch;
      *ch = *first;
      *first = tmpChar;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<permutationR>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  movzbl (%rsi),%eax
  mov    %rsi,%rbp
  lea    0x1(%rsi),%r13
  test   %al,%al
  je     L19
L10:
  movzbl (%rbx),%edx
  mov    %dl,0x0(%rbp)
  mov    %al,(%rbx)
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <permutationR>
  movzbl 0x0(%rbp),%eax
  movzbl (%rbx),%edx
  mov    %dl,0x0(%rbp)
  mov    %al,(%rbx)
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L10
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <puts@plt>
  jmp    L20
```

assistant: ```c
void permutationR(char *string, char *first) {
  if (*first == '\0') {
    puts(string);
  } else {
    for (char *ch = first; *ch != '\0'; ++ch) {
      char tmpChar = *ch;
      *ch = *first;
      *first = tmpChar;
      permutationR(string, first + 1);
      tmpChar = *ch;
      *ch = *first;
      *first = tmpChar;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<permutationR>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  je     L3
  mov    %rsi,%rbp
  lea    0x1(%rsi),%r13
  mov    %eax,%edx
  mov    %rsi,%rbx
L1:
  mov    %dl,(%rbx)
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  mov    %al,0x0(%rbp)
  call   <permutationR>
  movzbl 0x0(%rbp),%eax
  movzbl -0x1(%rbx),%edx
  mov    %al,-0x1(%rbx)
  mov    %dl,0x0(%rbp)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <puts@plt>
```

assistant: ```c
void permutationR(char *string, char *first) {
  if (*first == '\0') {
    puts(string);
  } else {
    for (char *ch = first; *ch != '\0'; ++ch) {
      char tmpChar = *ch;
      *ch = *first;
      *first = tmpChar;
      permutationR(string, first + 1);
      tmpChar = *ch;
      *ch = *first;
      *first = tmpChar;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <STD_opts_help@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rdx
  mov    $0x0,%eax
  call   *%rdx
L9:
  nop
  leave
  ret
```

assistant: ```c
void print_help(void (*user_help)()) {
  STD_opts_help();
  if (user_help)
    user_help();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_help>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <STD_opts_help@plt>
  test   %rbx,%rbx
  je     L2
  mov    $0x0,%eax
  call   *%rbx
L2:
  pop    %rbx
  ret
```

assistant: ```c
void print_help(void (*user_help)()) {
  STD_opts_help();
  if (user_help)
    user_help();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_help>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <STD_opts_help@plt>
  test   %rbx,%rbx
  je     L9
  mov    %rbx,%rdx
  xor    %eax,%eax
  pop    %rbx
  jmp    *%rdx
  nopl   0x0(%rax)
L9:
  pop    %rbx
  ret
```

assistant: ```c
void print_help(void (*user_help)()) {
  STD_opts_help();
  if (user_help)
    user_help();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_help>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <STD_opts_help@plt>
  test   %rbx,%rbx
  je     L6
  mov    %rbx,%rdx
  xor    %eax,%eax
  pop    %rbx
  jmp    *%rdx
  nopl   0x0(%rax)
L6:
  pop    %rbx
  ret
```

assistant: ```c
void print_help(void (*user_help)()) {
  STD_opts_help();
  if (user_help)
    user_help();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LPCChannelStatusGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x40080000,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <LPCChannelValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  add    $0x14,%rax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
unsigned long LPCChannelStatusGet(unsigned long ulBase, unsigned long ulChannel) {
  DEBUG_ASSERT(ulBase == 0x40080000);
  DEBUG_ASSERT(LPCChannelValid(ulChannel));
  return ((*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))));
}
```