ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<countWords>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isAlphabetic@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L31
  cmpl   $0x0,-0x10(%rbp)
  jne    L31
  movl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  jmp    L74
L31:
  cmpl   $0x0,-0x4(%rbp)
  jne    L74
  cmpl   $0x0,-0x10(%rbp)
  je     L74
  movl   $0x0,-0x10(%rbp)
L74:
  addl   $0x1,-0x8(%rbp)
L30:
  cmpl   $0x4f,-0x8(%rbp)
  jg     L35
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
L35:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int countWords(char line[]) {
  bool isAlphabetic(char);
  bool onWord = false;
  int wordsCount = 0, i;
  for (i = 0; i < 81 - 1 && line[i] != '\0'; i++) {
    bool isLetter = isAlphabetic(line[i]);
    if (isLetter && !onWord) {
      onWord = true;
      wordsCount++;
    } else if (!isLetter && onWord) {
      onWord = false;
    }
  }
  return wordsCount;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<countWords>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x50(%rdi),%r13
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L11
L28:
  add    $0x1,%r12d
  mov    $0x1,%ebp
L59:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L13
L11:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L13
  movsbl %dil,%edi
  call   <isAlphabetic@plt>
  test   %eax,%eax
  je     L2
  test   %ebp,%ebp
  je     L28
L2:
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %eax,%ebp
  jmp    L59
L13:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int countWords(char line[]) {
  bool isAlphabetic(char);
  bool onWord = false;
  int wordsCount = 0, i;
  for (i = 0; i < 81 - 1 && line[i] != '\0'; i++) {
    bool isLetter = isAlphabetic(line[i]);
    if (isLetter && !onWord) {
      onWord = true;
      wordsCount++;
    } else if (!isLetter && onWord) {
      onWord = false;
    }
  }
  return wordsCount;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<countWords>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    0x50(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L37
  xchg   %ax,%ax
L50:
  add    $0x1,%r12d
  mov    $0x1,%r14d
L13:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L34
L37:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L34
  call   <isAlphabetic@plt>
  test   %eax,%eax
  je     L62
  test   $0x1,%r14b
  je     L50
  test   %eax,%eax
  jne    L13
L62:
  test   $0x1,%r14b
  cmovne %r13d,%r14d
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L37
L34:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int countWords(char line[]) {
  bool isAlphabetic(char);
  bool onWord = false;
  int wordsCount = 0, i;
  for (i = 0; i < 81 - 1 && line[i] != '\0'; i++) {
    bool isLetter = isAlphabetic(line[i]);
    if (isLetter && !onWord) {
      onWord = true;
      wordsCount++;
    } else if (!isLetter && onWord) {
      onWord = false;
    }
  }
  return wordsCount;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<countWords>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    0x50(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L11
  xchg   %ax,%ax
L24:
  add    $0x1,%r12d
  mov    $0x1,%r14d
L62:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L56
L11:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L56
  call   <isAlphabetic@plt>
  test   %eax,%eax
  je     L10
  test   $0x1,%r14b
  je     L24
  test   %eax,%eax
  jne    L62
L10:
  test   $0x1,%r14b
  cmovne %r13d,%r14d
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L11
L56:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int countWords(char line[]) {
  bool isAlphabetic(char);
  bool onWord = false;
  int wordsCount = 0, i;
  for (i = 0; i < 81 - 1 && line[i] != '\0'; i++) {
    bool isLetter = isAlphabetic(line[i]);
    if (isLetter && !onWord) {
      onWord = true;
      wordsCount++;
    } else if (!isLetter && onWord) {
      onWord = false;
    }
  }
  return wordsCount;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<imagetag_cmdline_required>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <imagetag_cmdline_required2@plt>
  test   %rax,%rax
  jle    L17
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L17:
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <imagetag_cmdline_free@plt>
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int imagetag_cmdline_required(struct gengetopt_args_info *args_info, const char *prog_name) {
  int result = EXIT_SUCCESS;
  if (imagetag_cmdline_required2(args_info, prog_name, 0) > 0)
    result = EXIT_FAILURE;
  if (result == EXIT_FAILURE) {
    imagetag_cmdline_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<imagetag_cmdline_required>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    D39(%rip),%rax
  mov    (%rax),%ebp
  mov    $0x0,%edx
  call   <imagetag_cmdline_required2@plt>
  test   %rax,%rax
  jle    L1
  mov    D33(%rip),%rax
  mov    (%rax),%ebp
L2:
  mov    %rbx,%rdi
  call   <imagetag_cmdline_free@plt>
  mov    D33(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L16
L1:
  mov    D33(%rip),%rax
  cmp    %ebp,(%rax)
  je     L2
L16:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int imagetag_cmdline_required(struct gengetopt_args_info *args_info, const char *prog_name) {
  int result = EXIT_SUCCESS;
  if (imagetag_cmdline_required2(args_info, prog_name, 0) > 0)
    result = EXIT_FAILURE;
  if (result == EXIT_FAILURE) {
    imagetag_cmdline_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<imagetag_cmdline_required>:
  endbr64
  push   %r12
  mov    D0(%rip),%rax
  xor    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rax),%r12d
  call   <imagetag_cmdline_required2@plt>
  mov    D4(%rip),%rbx
  test   %rax,%rax
  jle    L18
  mov    (%rbx),%r12d
L17:
  mov    %rbp,%rdi
  call   <imagetag_cmdline_free@plt>
  mov    (%rbx),%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  cmp    %r12d,(%rbx)
  je     L17
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int imagetag_cmdline_required(struct gengetopt_args_info *args_info, const char *prog_name) {
  int result = EXIT_SUCCESS;
  if (imagetag_cmdline_required2(args_info, prog_name, 0) > 0)
    result = EXIT_FAILURE;
  if (result == EXIT_FAILURE) {
    imagetag_cmdline_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imagetag_cmdline_required>:
  endbr64
  push   %r12
  mov    D6(%rip),%rax
  xor    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rax),%r12d
  call   <imagetag_cmdline_required2@plt>
  mov    D19(%rip),%rbx
  test   %rax,%rax
  jle    L10
  mov    (%rbx),%r12d
L16:
  mov    %rbp,%rdi
  call   <imagetag_cmdline_free@plt>
  mov    (%rbx),%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    %r12d,(%rbx)
  je     L16
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int imagetag_cmdline_required(struct gengetopt_args_info *args_info, const char *prog_name) {
  int result = EXIT_SUCCESS;
  if (imagetag_cmdline_required2(args_info, prog_name, 0) > 0)
    result = EXIT_FAILURE;
  if (result == EXIT_FAILURE) {
    imagetag_cmdline_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<stderr_vsyslog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <perrno_stderr_vsyslog@plt>
  mov    D5(%rip),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void stderr_vsyslog(int priority, const char *format, va_list args) {
  int perrno = errno;
  perrno_stderr_vsyslog(perrno, priority, format, args);
  errno = perrno;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stderr_vsyslog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ecx
  mov    D8(%rip),%rbx
  mov    (%rbx),%ebp
  mov    %rsi,%rdx
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <perrno_stderr_vsyslog@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void stderr_vsyslog(int priority, const char *format, va_list args) {
  int perrno = errno;
  perrno_stderr_vsyslog(perrno, priority, format, args);
  errno = perrno;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stderr_vsyslog>:
  endbr64
  push   %rbp
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    %edi,%esi
  push   %rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%rbx
  mov    (%rbx),%ebp
  mov    %ebp,%edi
  call   <perrno_stderr_vsyslog@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void stderr_vsyslog(int priority, const char *format, va_list args) {
  int perrno = errno;
  perrno_stderr_vsyslog(perrno, priority, format, args);
  errno = perrno;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stderr_vsyslog>:
  endbr64
  push   %rbp
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    %edi,%esi
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rbx
  mov    (%rbx),%ebp
  mov    %ebp,%edi
  call   <perrno_stderr_vsyslog@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void stderr_vsyslog(int priority, const char *format, va_list args) {
  int perrno = errno;
  perrno_stderr_vsyslog(perrno, priority, format, args);
  errno = perrno;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  jle    L9
  mov    $0x2a,%edi
  call   <exit@plt>
L9:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <f@plt>
  leave
  ret
```

assistant: ```c
int g(int y) {
  if (y > 5) {
    exit(42);
  }
  return f(y - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x5,%edi
  jg     L16
L11:
  lea    -0x1(%rbx),%edi
  call   <f@plt>
  pop    %rbx
  ret
L16:
  mov    $0x2a,%edi
  call   <exit@plt>
  jmp    L11
```

assistant: ```c
int g(int y) {
  if (y > 5) {
    exit(42);
  }
  return f(y - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<g>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x5,%edi
  jg     L4
  lea    -0x1(%rbx),%edi
  pop    %rbx
  jmp    1060 <f@plt>
  nopl   (%rax)
L4:
  mov    $0x2a,%edi
  call   <exit@plt>
  lea    -0x1(%rbx),%edi
  pop    %rbx
  jmp    1060 <f@plt>
```

assistant: ```c
int g(int y) {
  if (y > 5) {
    exit(42);
  }
  return f(y - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x5,%edi
  jg     L4
  lea    -0x1(%rbx),%edi
  pop    %rbx
  jmp    1060 <f@plt>
  nopl   (%rax)
L4:
  mov    $0x2a,%edi
  call   <exit@plt>
  lea    -0x1(%rbx),%edi
  pop    %rbx
  jmp    1060 <f@plt>
```

assistant: ```c
int g(int y) {
  if (y > 5) {
    exit(42);
  }
  return f(y - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_hel_lo2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x2a,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_hel_lo2() {
  int *s = NULL;
  *s = 42;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_hel_lo2>:
  endbr64
  movl   $0x2a,0x0
  ret
```

assistant: ```c
void test_hel_lo2() {
  int *s = NULL;
  *s = 42;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_hel_lo2>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void test_hel_lo2() {
  int *s = NULL;
  *s = 42;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_hel_lo2>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void test_hel_lo2() {
  int *s = NULL;
  *s = 42;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L14
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L11
L14:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string

tool: D28: %d %d

tool: D18: %d


assistant: ```c
int main() {
  int n, p;
  scanf("%d %d", &n, &p);
  int totalNumberOfPages = n / 2;
  int totalNumberOfTurnsFromFront = p / 2;
  int totalNumberOfTurnsFromBack = totalNumberOfPages - totalNumberOfTurnsFromFront;
  if (totalNumberOfTurnsFromFront < totalNumberOfTurnsFromBack) {
    printf("%d\n", totalNumberOfTurnsFromFront);
  } else {
    printf("%d\n", totalNumberOfTurnsFromBack);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    (%rsp),%edx
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  sub    %eax,%esi
  cmp    %esi,%eax
  jge    L9
  mov    %eax,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string
name: disassemble_data
arguments: data_tag: D24
data_type: string

tool: D3: %d %d

tool: D24: %d


assistant: ```c
int main() {
  int n, p;
  scanf("%d %d", &n, &p);
  int totalNumberOfPages = n / 2;
  int totalNumberOfTurnsFromFront = p / 2;
  int totalNumberOfTurnsFromBack = totalNumberOfPages - totalNumberOfTurnsFromFront;
  if (totalNumberOfTurnsFromFront < totalNumberOfTurnsFromBack) {
    printf("%d\n", totalNumberOfTurnsFromFront);
  } else {
    printf("%d\n", totalNumberOfTurnsFromBack);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  mov    (%rsp),%eax
  sar    %r8d
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  sub    %r8d,%esi
  cmp    %esi,%r8d
  jge    L8
  mov    %r8d,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: string

tool: D27: %d %d

tool: D15: %d


assistant: ```c
int main() {
  int n, p;
  scanf("%d %d", &n, &p);
  int totalNumberOfPages = n / 2;
  int totalNumberOfTurnsFromFront = p / 2;
  int totalNumberOfTurnsFromBack = totalNumberOfPages - totalNumberOfTurnsFromFront;
  if (totalNumberOfTurnsFromFront < totalNumberOfTurnsFromBack) {
    printf("%d\n", totalNumberOfTurnsFromFront);
  } else {
    printf("%d\n", totalNumberOfTurnsFromBack);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  mov    (%rsp),%eax
  sar    %r8d
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  sub    %r8d,%esi
  cmp    %esi,%r8d
  jge    L5
  mov    %r8d,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string

tool: D7: %d %d

tool: D25: %d


assistant: ```c
int main() {
  int n, p;
  scanf("%d %d", &n, &p);
  int totalNumberOfPages = n / 2;
  int totalNumberOfTurnsFromFront = p / 2;
  int totalNumberOfTurnsFromBack = totalNumberOfPages - totalNumberOfTurnsFromFront;
  if (totalNumberOfTurnsFromFront < totalNumberOfTurnsFromBack) {
    printf("%d\n", totalNumberOfTurnsFromFront);
  } else {
    printf("%d\n", totalNumberOfTurnsFromBack);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D45(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D13(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D27(%rip),%xmm0
  pxor   %xmm1,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L11
L23:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  call   <stdlib_base_is_infinite@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L24
  lea    D1(%rip),%rax
  jmp    L27
L24:
  lea    D12(%rip),%rax
L27:
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x30(%rbp,%rdx,8),%rdx
  mov    %rax,%rsi
  movq   %rdx,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L11:
  cmpl   $0x3,-0x38(%rbp)
  jle    L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D45
data_type: f64
name: disassemble_data
arguments: label: D13
data_type: byte[8]
name: disassemble_data
arguments: label: D27
data_type: f64
name: disassemble_data
arguments: label: D1
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string

tool: D45: 3.14

tool: {"D13": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x09,0xc0]}

tool: D27: 1

tool: D1: True

tool: D12: False

tool: D9: Value: %lf. Is infinite? %s.


assistant: ```c
int main() {
  double x[] = {3.14, -3.14, 1.0 / 0.0, 0.0 / 0.0};
  bool b;
  int i;
  for (i = 0; i < 4; i++) {
    b = stdlib_base_is_infinite(x[i]);
    printf("Value: %lf. Is infinite? %s.\n", x[i], (b) ? "True" : "False");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  mov    %rax,(%rsp)
  mov    D24(%rip),%rax
  mov    %rax,0x8(%rsp)
  pxor   %xmm0,%xmm0
  movsd  D33(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rsp)
  divsd  %xmm0,%xmm0
  movsd  %xmm0,0x18(%rsp)
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r15
  lea    D12(%rip),%r14
  lea    D45(%rip),%r13
  lea    D42(%rip),%r12
L12:
  mov    (%rbx),%rbp
  movq   %rbp,%xmm0
  call   <stdlib_base_is_infinite@plt>
  test   %eax,%eax
  mov    %r13,%rsi
  cmovne %r14,%rsi
  movq   %rbp,%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L12
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: f64
name: retrieve_data
arguments: data_label: D24
type: byte[8]
name: retrieve_data
arguments: data_label: D33
type: f64
name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D45
type: string
name: retrieve_data
arguments: data_label: D42
type: string

tool: D16: 3.14

tool: {"D24": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x09,0xc0]}

tool: D33: 1

tool: D12: True

tool: D45: False

tool: D42: Value: %lf. Is infinite? %s.


assistant: ```c
int main() {
  double x[] = {3.14, -3.14, 1.0 / 0.0, 0.0 / 0.0};
  bool b;
  int i;
  for (i = 0; i < 4; i++) {
    b = stdlib_base_is_infinite(x[i]);
    printf("Value: %lf. Is infinite? %s.\n", x[i], (b) ? "True" : "False");
  }
}
```