ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0x44(%rbp),%edx
  mov    -0x48(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <getmaxyx@plt>
  mov    $0x0,%eax
  call   <desligarTodosLeds@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <lerArquivo@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <amostra@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  int row, col, i, j;
  char string[50];
  initscr();
  getmaxyx(stdscr, row, col);
  desligarTodosLeds();
  lerArquivo(string);
  amostra(string);
  getch();
  endwin();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <initscr@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  mov    $0x0,%eax
  call   <desligarTodosLeds@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <lerArquivo@plt>
  mov    %rbx,%rdi
  call   <amostra@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int row, col, i, j;
  char string[50];
  initscr();
  getmaxyx(stdscr, row, col);
  desligarTodosLeds();
  lerArquivo(string);
  amostra(string);
  getch();
  endwin();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <initscr@plt>
  mov    D5(%rip),%rax
  xor    %edx,%edx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  xor    %eax,%eax
  call   <desligarTodosLeds@plt>
  mov    %rbp,%rdi
  call   <lerArquivo@plt>
  mov    %rbp,%rdi
  call   <amostra@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int row, col, i, j;
  char string[50];
  initscr();
  getmaxyx(stdscr, row, col);
  desligarTodosLeds();
  lerArquivo(string);
  amostra(string);
  getch();
  endwin();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <initscr@plt>
  mov    D6(%rip),%rax
  xor    %edx,%edx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  xor    %eax,%eax
  call   <desligarTodosLeds@plt>
  mov    %rbp,%rdi
  call   <lerArquivo@plt>
  mov    %rbp,%rdi
  call   <amostra@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int row, col, i, j;
  char string[50];
  initscr();
  getmaxyx(stdscr, row, col);
  desligarTodosLeds();
  lerArquivo(string);
  amostra(string);
  getch();
  endwin();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sortColors1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L88
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L170
L100:
  addl   $0x1,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L43
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L100
  jmp    L43
L122:
  subl   $0x1,-0x4(%rbp)
L43:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L16
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L122
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L170
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L170:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L42
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L52
L165:
  addl   $0x1,-0x8(%rbp)
L146:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L151
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L165
  jmp    L151
L81:
  subl   $0x1,-0x4(%rbp)
L151:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L57
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L81
L57:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L52
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L52:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L146
  jmp    L121
L88:
  nop
L121:
  leave
  ret
```

assistant: ```c
void sortColors1(int *nums, int size) {
  if (size < 2)
    return;
  int index0 = 0, index1 = size - 1;
  while (index0 != index1) {
    while (nums[index0] == 0 && index0 < index1)
      index0++;
    while (nums[index1] != 0 && index0 < index1)
      index1--;
    if (index0 != index1)
      swap(nums + index0, nums + index1);
  }
  index1 = size - 1;
  while (index0 != index1) {
    while (nums[index0] == 1 && index0 < index1)
      index0++;
    while (nums[index1] != 1 && index0 < index1)
      index1--;
    if (index0 != index1)
      swap(nums + index0, nums + index1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sortColors1>:
  endbr64
  cmp    $0x1,%esi
  jle    L104
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  lea    -0x1(%rsi),%ebp
  mov    %ebp,%ebx
  mov    $0x0,%r12d
  jmp    L180
L24:
  call   <swap@plt>
L180:
  movslq %r12d,%rax
  shl    $0x2,%rax
  lea    0x0(%r13,%rax,1),%rdi
  cmpl   $0x0,(%rdi)
  jne    L57
  lea    0x4(%r13,%rax,1),%rax
  cmp    %ebx,%r12d
  jge    L57
L96:
  add    $0x1,%r12d
  mov    %rax,%rdi
  add    $0x4,%rax
  cmpl   $0x0,(%rdi)
  jne    L57
  cmp    %ebx,%r12d
  jl     L96
L57:
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,4),%rsi
  cmpl   $0x0,(%rsi)
  je     L135
  cmp    %ebx,%r12d
  jge    L135
  lea    -0x4(%r13,%rax,4),%rax
L64:
  sub    $0x1,%ebx
  mov    %rax,%rsi
  sub    $0x4,%rax
  cmpl   $0x0,(%rsi)
  je     L135
  cmp    %r12d,%ebx
  jg     L64
L135:
  cmp    %ebx,%r12d
  jne    L24
  cmp    %ebx,%ebp
  jne    L43
  jmp    L19
L113:
  call   <swap@plt>
L43:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    0x0(%r13,%rax,1),%rdi
  cmpl   $0x1,(%rdi)
  jne    L132
  lea    0x4(%r13,%rax,1),%rax
  cmp    %ebp,%ebx
  jge    L132
L54:
  add    $0x1,%ebx
  mov    %rax,%rdi
  add    $0x4,%rax
  cmpl   $0x1,(%rdi)
  jne    L132
  cmp    %ebp,%ebx
  jl     L54
L132:
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%rsi
  cmpl   $0x1,(%rsi)
  je     L177
  cmp    %ebp,%ebx
  jge    L177
  lea    -0x4(%r13,%rax,4),%rax
L127:
  sub    $0x1,%ebp
  mov    %rax,%rsi
  sub    $0x4,%rax
  cmpl   $0x1,(%rsi)
  je     L177
  cmp    %ebx,%ebp
  jg     L127
L177:
  cmp    %ebp,%ebx
  jne    L113
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L104:
  ret
```

assistant: ```c
void sortColors1(int *nums, int size) {
  if (size < 2)
    return;
  int index0 = 0, index1 = size - 1;
  while (index0 != index1) {
    while (nums[index0] == 0 && index0 < index1)
      index0++;
    while (nums[index1] != 0 && index0 < index1)
      index1--;
    if (index0 != index1)
      swap(nums + index0, nums + index1);
  }
  index1 = size - 1;
  while (index0 != index1) {
    while (nums[index0] == 1 && index0 < index1)
      index0++;
    while (nums[index1] != 1 && index0 < index1)
      index1--;
    if (index0 != index1)
      swap(nums + index0, nums + index1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sortColors1>:
  endbr64
  cmp    $0x1,%esi
  jle    L184
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %ebp,%ebx
  sub    $0x8,%rsp
L51:
  movslq %r12d,%rax
  shl    $0x2,%rax
  cmp    %ebx,%r12d
  lea    0x0(%r13,%rax,1),%rdi
  setl   %dl
  mov    (%rdi),%ecx
  test   %ecx,%ecx
  jne    L105
  lea    0x4(%r13,%rax,1),%rax
  jmp    L167
  nopl   0x0(%rax)
L20:
  mov    %rax,%rdi
  add    $0x1,%r12d
  mov    (%rdi),%r10d
  cmp    %ebx,%r12d
  setl   %dl
  add    $0x4,%rax
  test   %r10d,%r10d
  jne    L105
L167:
  test   %dl,%dl
  jne    L20
L105:
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,4),%rsi
  mov    (%rsi),%r9d
  test   %r9d,%r9d
  je     L124
  test   %dl,%dl
  je     L124
  lea    -0x4(%r13,%rax,4),%rax
  jmp    L155
L25:
  cmp    %r12d,%ebx
  jle    L124
L155:
  mov    %rax,%rsi
  sub    $0x1,%ebx
  sub    $0x4,%rax
  mov    (%rsi),%r8d
  test   %r8d,%r8d
  jne    L25
L124:
  cmp    %ebx,%r12d
  jne    L12
  cmp    %ebx,%ebp
  je     L73
  nopl   0x0(%rax)
L141:
  movslq %ebx,%rax
  shl    $0x2,%rax
  cmp    %ebp,%ebx
  lea    0x0(%r13,%rax,1),%rdi
  setl   %dl
  cmpl   $0x1,(%rdi)
  jne    L162
  lea    0x4(%r13,%rax,1),%rax
  jmp    L8
  nopl   (%rax)
L152:
  add    $0x1,%ebx
  mov    %rax,%rdi
  cmp    %ebp,%ebx
  setl   %dl
  add    $0x4,%rax
  cmpl   $0x1,(%rdi)
  jne    L162
L8:
  test   %dl,%dl
  jne    L152
L162:
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%rsi
  cmpl   $0x1,(%rsi)
  je     L54
  test   %dl,%dl
  je     L54
  lea    -0x4(%r13,%rax,4),%rax
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L156:
  cmp    %ebx,%ebp
  jle    L54
L63:
  mov    %rax,%rsi
  sub    $0x1,%ebp
  sub    $0x4,%rax
  cmpl   $0x1,(%rsi)
  jne    L156
L54:
  cmp    %ebp,%ebx
  jne    L182
L73:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L182:
  call   <swap@plt>
  jmp    L141
  nopw   0x0(%rax,%rax,1)
L12:
  call   <swap@plt>
  jmp    L51
L184:
  ret
```

assistant: ```c
void sortColors1(int *nums, int size) {
  if (size < 2)
    return;
  int index0 = 0, index1 = size - 1;
  while (index0 != index1) {
    while (nums[index0] == 0 && index0 < index1)
      index0++;
    while (nums[index1] != 0 && index0 < index1)
      index1--;
    if (index0 != index1)
      swap(nums + index0, nums + index1);
  }
  index1 = size - 1;
  while (index0 != index1) {
    while (nums[index0] == 1 && index0 < index1)
      index0++;
    while (nums[index1] != 1 && index0 < index1)
      index1--;
    if (index0 != index1)
      swap(nums + index0, nums + index1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sortColors1>:
  endbr64
  cmp    $0x1,%esi
  jle    L246
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %ebp,%ebx
  sub    $0x8,%rsp
L185:
  movslq %r12d,%rax
  shl    $0x2,%rax
  cmp    %ebx,%r12d
  lea    0x0(%r13,%rax,1),%rdi
  setl   %cl
  mov    (%rdi),%edx
  test   %edx,%edx
  jne    L52
  lea    0x4(%r13,%rax,1),%rax
  jmp    L214
  nopl   0x0(%rax)
L57:
  mov    %rax,%rdi
  add    $0x1,%r12d
  mov    (%rdi),%esi
  cmp    %ebx,%r12d
  setl   %cl
  add    $0x4,%rax
  test   %esi,%esi
  jne    L52
L214:
  test   %cl,%cl
  jne    L57
L52:
  movslq %ebx,%r8
  lea    0x0(%r13,%r8,4),%rsi
  mov    (%rsi),%edx
  test   %edx,%edx
  je     L194
  test   %cl,%cl
  je     L194
  lea    -0x4(%r13,%r8,4),%rax
  jmp    L22
  nopl   0x0(%rax)
L198:
  cmp    %r12d,%ebx
  jle    L194
L22:
  mov    (%rax),%edx
  mov    %rax,%rsi
  sub    $0x1,%ebx
  sub    $0x4,%rax
  test   %edx,%edx
  jne    L198
L194:
  cmp    %ebx,%r12d
  jne    L197
  movslq %ebx,%r8
  cmp    %ebx,%ebp
  je     L233
  cmp    %ebp,%ebx
  setl   %cl
  cmp    $0x1,%edx
  jne    L138
L117:
  lea    0x4(%r13,%r8,4),%rax
  test   %cl,%cl
  jne    L30
  jmp    L138
  xchg   %ax,%ax
L173:
  test   %cl,%cl
  je     L51
L30:
  add    $0x1,%ebx
  mov    %rax,%rdi
  cmp    %ebp,%ebx
  setl   %cl
  add    $0x4,%rax
  cmpl   $0x1,(%rdi)
  je     L173
L51:
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%rsi
  cmpl   $0x1,(%rsi)
  je     L201
  test   %cl,%cl
  je     L201
  lea    -0x4(%r13,%rax,4),%rax
  jmp    L234
L150:
  cmp    %ebx,%ebp
  jle    L201
L234:
  mov    %rax,%rsi
  sub    $0x1,%ebp
  sub    $0x4,%rax
  cmpl   $0x1,(%rsi)
  jne    L150
L201:
  cmp    %ebp,%ebx
  jne    L89
L233:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L89:
  call   <swap@plt>
  movslq %ebx,%r8
  cmp    %ebp,%ebx
  mov    0x0(%r13,%r8,4),%edx
  setl   %cl
  cmp    $0x1,%edx
  je     L117
L138:
  lea    0x0(%r13,%r8,4),%rdi
  jmp    L51
  cs nopw 0x0(%rax,%rax,1)
L197:
  call   <swap@plt>
  jmp    L185
L246:
  ret
```

assistant: ```c
void sortColors1(int *nums, int size) {
  if (size < 2)
    return;
  int index0 = 0, index1 = size - 1;
  while (index0 != index1) {
    while (nums[index0] == 0 && index0 < index1)
      index0++;
    while (nums[index1] != 0 && index0 < index1)
      index1--;
    if (index0 != index1)
      swap(nums + index0, nums + index1);
  }
  index1 = size - 1;
  while (index0 != index1) {
    while (nums[index0] == 1 && index0 < index1)
      index0++;
    while (nums[index1] != 1 && index0 < index1)
      index1--;
    if (index0 != index1)
      swap(nums + index0, nums + index1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tokenLen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
L88:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x24,-0x9(%rbp)
  jne    L76
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L99
  addq   $0x2,-0x8(%rbp)
  jmp    L1
L99:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L21
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L21
  addq   $0x2,-0x8(%rbp)
  jmp    L1
L21:
  mov    -0x8(%rbp),%rax
  jmp    L95
L76:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isgraph@plt>
  test   %eax,%eax
  jne    L62
  mov    -0x8(%rbp),%rax
  jmp    L95
L62:
  addq   $0x1,-0x8(%rbp)
L1:
  jmp    L88
L95:
  leave
  ret
```

assistant: ```c
long tokenLen(char *ptr) {
  long i = 0;
  char tmpchr;
  while (1) {
    tmpchr = ptr[i];
    if (tmpchr == '$') {
      if (ptr[i + 1] == '$') {
        i = i + 2;
        continue;
      } else {
        if (ptr[i + 1] >= '0' && ptr[i + 1] <= '9') {
          i = i + 2;
          continue;
        } else {
          return (i);
        }
      }
    }
    if (!isgraph((unsigned char)tmpchr))
      return (i);
    i++;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tokenLen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L30
L28:
  add    $0x2,%rbx
  jmp    L30
L59:
  add    $0x2,%rbx
  jmp    L30
L15:
  movzbl %dil,%edi
  call   <isgraph@plt>
  test   %eax,%eax
  je     L66
  add    $0x1,%rbx
L30:
  movzbl 0x0(%rbp,%rbx,1),%edi
  cmp    $0x24,%dil
  jne    L15
  movzbl 0x1(%rbp,%rbx,1),%eax
  cmp    $0x24,%al
  je     L28
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L59
L66:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long tokenLen(char *ptr) {
  long i = 0;
  char tmpchr;
  while (1) {
    tmpchr = ptr[i];
    if (tmpchr == '$') {
      if (ptr[i + 1] == '$') {
        i = i + 2;
        continue;
      } else {
        if (ptr[i + 1] >= '0' && ptr[i + 1] <= '9') {
          i = i + 2;
          continue;
        } else {
          return (i);
        }
      }
    }
    if (!isgraph((unsigned char)tmpchr))
      return (i);
    i++;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tokenLen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L27:
  movzbl (%rbx,%r12,1),%edi
  cmp    $0x24,%dil
  jne    L31
  movzbl 0x1(%rbx,%r12,1),%eax
  cmp    $0x24,%al
  je     L52
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L52
L35:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  call   <isgraph@plt>
  test   %eax,%eax
  je     L35
  add    $0x1,%r12
  jmp    L27
  nop
L52:
  add    $0x2,%r12
  jmp    L27
```

assistant: ```c
long tokenLen(char *ptr) {
  long i = 0;
  char tmpchr;
  while (1) {
    tmpchr = ptr[i];
    if (tmpchr == '$') {
      if (ptr[i + 1] == '$') {
        i = i + 2;
        continue;
      } else {
        if (ptr[i + 1] >= '0' && ptr[i + 1] <= '9') {
          i = i + 2;
          continue;
        } else {
          return (i);
        }
      }
    }
    if (!isgraph((unsigned char)tmpchr))
      return (i);
    i++;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tokenLen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L22:
  movzbl (%rbx,%r12,1),%edi
  cmp    $0x24,%dil
  jne    L53
  movzbl 0x1(%rbx,%r12,1),%eax
  cmp    $0x24,%al
  je     L40
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L40
L24:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  call   <isgraph@plt>
  test   %eax,%eax
  je     L24
  add    $0x1,%r12
  jmp    L22
  nop
L40:
  add    $0x2,%r12
  jmp    L22
```

assistant: ```c
long tokenLen(char *ptr) {
  long i = 0;
  char tmpchr;
  while (1) {
    tmpchr = ptr[i];
    if (tmpchr == '$') {
      if (ptr[i + 1] == '$') {
        i = i + 2;
        continue;
      } else {
        if (ptr[i + 1] >= '0' && ptr[i + 1] <= '9') {
          i = i + 2;
          continue;
        } else {
          return (i);
        }
      }
    }
    if (!isgraph((unsigned char)tmpchr))
      return (i);
    i++;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<age_of_game>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D3(%rip),%rax
  test   %rax,%rax
  jne    L4
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,D27(%rip)
L4:
  mov    D27(%rip),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <difftime@plt>
  movslq %eax,%rdx
  imul   $0xffffffffc22e4507,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x10,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <floor@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double age_of_game(time_t date) {
  static time_t tnow = 0;
  if (!tnow)
    tnow = time(NULL);
  return floor(difftime(tnow, date) / (24 * 3600));
}
```
user: What is the c source code of the assembly code below?

```asm
<age_of_game>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpq   $0x0,D18(%rip)
  je     L2
L6:
  mov    %rbx,%rsi
  mov    D18(%rip),%rdi
  call   <difftime@plt>
  movslq %eax,%rdi
  imul   $0xffffffffc22e4507,%rdi,%rdi
  shr    $0x20,%rdi
  add    %eax,%edi
  sar    $0x10,%edi
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <floor@plt>
  pop    %rbx
  ret
L2:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,D6(%rip)
  jmp    L6
```

assistant: ```c
double age_of_game(time_t date) {
  static time_t tnow = 0;
  if (!tnow)
    tnow = time(NULL);
  return floor(difftime(tnow, date) / (24 * 3600));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<age_of_game>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    D15(%rip),%rdi
  test   %rdi,%rdi
  je     L9
L15:
  mov    %rbp,%rsi
  call   <difftime@plt>
  pop    %rbp
  movslq %eax,%rdi
  imul   $0xffffffffc22e4507,%rdi,%rdi
  shr    $0x20,%rdi
  add    %eax,%edi
  sar    $0x1f,%eax
  sar    $0x10,%edi
  sub    %eax,%edi
  jmp    1090 <floor@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  call   <time@plt>
  mov    %rax,D16(%rip)
  mov    %rax,%rdi
  jmp    L15
```

assistant: ```c
double age_of_game(time_t date) {
  static time_t tnow = 0;
  if (!tnow)
    tnow = time(NULL);
  return floor(difftime(tnow, date) / (24 * 3600));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<age_of_game>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    D11(%rip),%rdi
  test   %rdi,%rdi
  je     L5
L14:
  mov    %rbp,%rsi
  call   <difftime@plt>
  pop    %rbp
  movslq %eax,%rdi
  imul   $0xffffffffc22e4507,%rdi,%rdi
  shr    $0x20,%rdi
  add    %eax,%edi
  sar    $0x1f,%eax
  sar    $0x10,%edi
  sub    %eax,%edi
  jmp    1090 <floor@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  call   <time@plt>
  mov    %rax,D12(%rip)
  mov    %rax,%rdi
  jmp    L14
```

assistant: ```c
double age_of_game(time_t date) {
  static time_t tnow = 0;
  if (!tnow)
    tnow = time(NULL);
  return floor(difftime(tnow, date) / (24 * 3600));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<safe_atou32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <safe_atou@plt>
  leave
  ret
```

assistant: ```c
int safe_atou32(const char *s, uint32_t *ret_u) {
  struct _assert_struct_8 {
    char x[(sizeof(uint32_t) == sizeof(unsigned)) ? 0 : -1];
  };
  return safe_atou(s, (unsigned *)ret_u);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<safe_atou32>:
  endbr64
  sub    $0x8,%rsp
  call   <safe_atou@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int safe_atou32(const char *s, uint32_t *ret_u) {
  struct _assert_struct_8 {
    char x[(sizeof(uint32_t) == sizeof(unsigned)) ? 0 : -1];
  };
  return safe_atou(s, (unsigned *)ret_u);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<safe_atou32>:
  endbr64
  jmp    1050 <safe_atou@plt>
```

assistant: ```c
int safe_atou32(const char *s, uint32_t *ret_u) {
  struct _assert_struct_8 {
    char x[(sizeof(uint32_t) == sizeof(unsigned)) ? 0 : -1];
  };
  return safe_atou(s, (unsigned *)ret_u);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<safe_atou32>:
  endbr64
  jmp    1050 <safe_atou@plt>
```

assistant: ```c
int safe_atou32(const char *s, uint32_t *ret_u) {
  struct _assert_struct_8 {
    char x[(sizeof(uint32_t) == sizeof(unsigned)) ? 0 : -1];
  };
  return safe_atou(s, (unsigned *)ret_u);
}
```