ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<display_pic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cltq
  imul   $0x9c400,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x20(%rbp),%rax
  mov    $0x190,%r9d
  mov    $0x190,%r8d
  mov    $0x1b8,%ecx
  mov    $0xc8,%edx
  mov    %rax,%rdi
  call   <w_pic@plt>
  cmpl   $0x168,-0x4(%rbp)
  jne    L2
  movl   $0x0,-0x4(%rbp)
L2:
  addl   $0x1,-0x4(%rbp)
  jmp    L3
```

assistant: ```c
int display_pic(int screen[][(400 * 400)], int *pfb) {
  for (int i = 0;; i += 1) {
    w_pic(pfb, screen[i], 200, 440, 400, 400);
    if (i == 360)
      i = 0;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<display_pic>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x190,%r9d
  mov    $0x190,%r8d
  mov    $0x1b8,%ecx
  mov    $0xc8,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <w_pic@plt>
  mov    $0x0,%ebx
  mov    $0x0,%r13d
L7:
  add    $0x1,%ebx
  movslq %ebx,%rsi
  imul   $0x9c400,%rsi,%rsi
  add    %r12,%rsi
  mov    $0x190,%r9d
  mov    $0x190,%r8d
  mov    $0x1b8,%ecx
  mov    $0xc8,%edx
  mov    %rbp,%rdi
  call   <w_pic@plt>
  cmp    $0x168,%ebx
  cmove  %r13d,%ebx
  jmp    L7
```

assistant: ```c
int display_pic(int screen[][(400 * 400)], int *pfb) {
  for (int i = 0;; i += 1) {
    w_pic(pfb, screen[i], 200, 440, 400, 400);
    if (i == 360)
      i = 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<display_pic>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L9:
  movslq %r13d,%rsi
  mov    $0x1b8,%ecx
  mov    $0xc8,%edx
  mov    %rbx,%rdi
  imul   $0x9c400,%rsi,%rsi
  mov    $0x190,%r9d
  mov    $0x190,%r8d
  add    %rbp,%rsi
  call   <w_pic@plt>
  lea    0x1(%r13),%eax
  cmp    $0x168,%r13d
  cmove  %r12d,%eax
  mov    %eax,%r13d
  jmp    L9
```

assistant: ```c
int display_pic(int screen[][(400 * 400)], int *pfb) {
  for (int i = 0;; i += 1) {
    w_pic(pfb, screen[i], 200, 440, 400, 400);
    if (i == 360)
      i = 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<display_pic>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L3:
  movslq %r13d,%rsi
  mov    $0x1b8,%ecx
  mov    $0xc8,%edx
  mov    %rbx,%rdi
  imul   $0x9c400,%rsi,%rsi
  mov    $0x190,%r9d
  mov    $0x190,%r8d
  add    %rbp,%rsi
  call   <w_pic@plt>
  lea    0x1(%r13),%eax
  cmp    $0x168,%r13d
  cmove  %r12d,%eax
  mov    %eax,%r13d
  jmp    L3
```

assistant: ```c
int display_pic(int screen[][(400 * 400)], int *pfb) {
  for (int i = 0;; i += 1) {
    w_pic(pfb, screen[i], 200, 440, 400, 400);
    if (i == 360)
      i = 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffff,-0x8(%rbp)
  movl   $0xa,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: %d

assistant: ```c
void main() {
  int x = 0xffff, y = 10;
  printf("%d", x | y);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffff,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: %d

assistant: ```c
void main() {
  int x = 0xffff, y = 10;
  printf("%d", x | y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0xffff,%esi
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d

assistant: ```c
void main() {
  int x = 0xffff, y = 10;
  printf("%d", x | y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0xffff,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: %d

assistant: ```c
void main() {
  int x = 0xffff, y = 10;
  printf("%d", x | y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<makeextralist>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0xa(%rax),%rdi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L68
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L6
  test   %rbp,%rbp
  je     L18
  mov    $0x0,%eax
L11:
  movsbl (%r12,%rax,1),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbp
  jne    L11
L18:
  lea    (%rbx,%rbp,4),%rax
L55:
  test   $0x1000,%r13d
  je     L90
  movl   $0x2a,(%rax)
  movl   $0x3f,0x4(%rax)
  movl   $0x5b,0x8(%rax)
  movl   $0x23,0xc(%rax)
  lea    0x10(%rax),%rax
L90:
  test   $0x4,%r13b
  je     L45
  movl   $0x20,(%rax)
  lea    0x4(%rax),%rax
L45:
  test   $0x8,%r13b
  je     L46
  movl   $0x9,(%rax)
  lea    0x4(%rax),%rax
L46:
  test   $0x10,%r13b
  je     L88
  movl   $0xa,(%rax)
  lea    0x4(%rax),%rax
L88:
  test   $0x40,%r13b
  jne    L89
  movl   $0x5c,(%rax)
  lea    0x4(%rax),%rax
L89:
  movl   $0x0,(%rax)
L68:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    %rbx,%rdi
  call   <wcslen@plt>
  cltq
  lea    (%rbx,%rax,4),%rax
  jmp    L55
```

assistant: ```c
wchar_t *makeextralist(int flags, const char *src) {
  wchar_t *dst, *d;
  size_t len;
  len = strlen(src);
  if ((dst = calloc(len + 10, sizeof(*dst))) == NULL) {
    return NULL;
  }
  if (mbstowcs(dst, src, len) == (size_t)-1) {
    size_t i;
    for (i = 0; i < len; i++) {
      dst[i] = (wint_t)(u_char)src[i];
    }
    d = dst + len;
  } else {
    d = dst + wcslen(dst);
  }
  if (flags & 0x1000) {
    *d++ = L'*';
    *d++ = L'?';
    *d++ = L'[';
    *d++ = L'#';
  }
  if (flags & 0x0004) {
    *d++ = L' ';
  }
  if (flags & 0x0008) {
    *d++ = L'\t';
  }
  if (flags & 0x0010) {
    *d++ = L'\n';
  }
  if ((flags & 0x0040) == 0) {
    *d++ = L'\\';
  }
  *d = L'\0';
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<makeextralist>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x4,%esi
  lea    0xa(%rax),%rdi
  mov    %rax,%rbx
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L32
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L86
  test   %rbx,%rbx
  je     L98
  xor    %edx,%edx
  nopl   0x0(%rax)
L57:
  movsbl 0x0(%rbp,%rdx,1),%eax
  mov    %eax,(%r12,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L57
L98:
  lea    (%r12,%rbx,4),%rax
  jmp    L11
L86:
  mov    %r12,%rdi
  call   <wcslen@plt>
  cltq
  lea    (%r12,%rax,4),%rax
L11:
  test   $0x1000,%r13d
  je     L6
  movabs $0x3f0000002a,%rcx
  add    $0x10,%rax
  mov    %rcx,-0x10(%rax)
  movabs $0x230000005b,%rcx
  mov    %rcx,-0x8(%rax)
L6:
  test   $0x4,%r13b
  je     L45
  movl   $0x20,(%rax)
  add    $0x4,%rax
L45:
  test   $0x8,%r13b
  je     L64
  movl   $0x9,(%rax)
  add    $0x4,%rax
L64:
  test   $0x10,%r13b
  je     L61
  movl   $0xa,(%rax)
  add    $0x4,%rax
L61:
  and    $0x40,%r13d
  jne    L59
  movl   $0x5c,(%rax)
  add    $0x4,%rax
L59:
  movl   $0x0,(%rax)
L32:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
wchar_t *makeextralist(int flags, const char *src) {
  wchar_t *dst, *d;
  size_t len;
  len = strlen(src);
  if ((dst = calloc(len + 10, sizeof(*dst))) == NULL) {
    return NULL;
  }
  if (mbstowcs(dst, src, len) == (size_t)-1) {
    size_t i;
    for (i = 0; i < len; i++) {
      dst[i] = (wint_t)(u_char)src[i];
    }
    d = dst + len;
  } else {
    d = dst + wcslen(dst);
  }
  if (flags & 0x1000) {
    *d++ = L'*';
    *d++ = L'?';
    *d++ = L'[';
    *d++ = L'#';
  }
  if (flags & 0x0004) {
    *d++ = L' ';
  }
  if (flags & 0x0008) {
    *d++ = L'\t';
  }
  if (flags & 0x0010) {
    *d++ = L'\n';
  }
  if ((flags & 0x0040) == 0) {
    *d++ = L'\\';
  }
  *d = L'\0';
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D32(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
L3:
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  D32(%rip),%xmm0
  divss  -0x4(%rbp),%xmm0
  addss  -0x4(%rbp),%xmm0
  movss  D28(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x4(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  comisd D4(%rip),%xmm0
  ja     L3
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D32
data_type: byte[4]
name: extract_symbolic_data
arguments: tag: D28
data_type: byte[4]
name: extract_symbolic_data
arguments: tag: D4
data_type: f64
name: extract_symbolic_data
arguments: tag: D44
data_type: string

tool: {"D32": [0x00,0x00,0x7a,0x44]}

tool: {"D28": [0x00,0x00,0x00,0x40]}

tool: D4: 0.001

tool: D44: sqrt(1000) = %.6f


assistant: ```c
int main() {
  float prev, next;
  next = 1000;
  do {
    prev = next;
    next = (prev + 1000 / prev) / 2;
  } while (prev - next > 0.001);
  printf("sqrt(1000) = %.6f\n", next);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D36(%rip),%xmm1
  movaps %xmm1,%xmm5
  movss  D13(%rip),%xmm4
  movsd  D31(%rip),%xmm3
L6:
  movaps %xmm5,%xmm2
  divss  %xmm1,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm1,%xmm0
  movaps %xmm2,%xmm1
  mulss  %xmm4,%xmm1
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  comisd %xmm3,%xmm0
  ja     L6
  movaps %xmm1,%xmm0
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D36
type_guessed: byte[4]
name: read_data
arguments: label: D13
type_guessed: byte[4]
name: read_data
arguments: label: D31
type_guessed: f64
name: read_data
arguments: label: D6
type_guessed: string

tool: {"D36": [0x00,0x00,0x7a,0x44]}

tool: {"D13": [0x00,0x00,0x00,0x3f]}

tool: D31: 0.001

tool: D6: sqrt(1000) = %.6f


assistant: ```c
int main() {
  float prev, next;
  next = 1000;
  do {
    prev = next;
    next = (prev + 1000 / prev) / 2;
  } while (prev - next > 0.001);
  printf("sqrt(1000) = %.6f\n", next);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D25(%rip),%xmm3
  movss  D16(%rip),%xmm5
  movsd  D19(%rip),%xmm4
  movaps %xmm3,%xmm1
  nopl   0x0(%rax,%rax,1)
L2:
  movaps %xmm3,%xmm2
  movaps %xmm1,%xmm0
  divss  %xmm1,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm1
  mulss  %xmm5,%xmm1
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  comisd %xmm4,%xmm0
  ja     L2
  movaps %xmm1,%xmm0
  lea    D24(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D25
type_infered: byte[4]
name: parse_data
arguments: data_tag: D16
type_infered: byte[4]
name: parse_data
arguments: data_tag: D19
type_infered: f64
name: parse_data
arguments: data_tag: D24
type_infered: string

tool: {"D25": [0x00,0x00,0x7a,0x44]}

tool: {"D16": [0x00,0x00,0x00,0x3f]}

tool: D19: 0.001

tool: D24: sqrt(1000) = %.6f


assistant: ```c
int main() {
  float prev, next;
  next = 1000;
  do {
    prev = next;
    next = (prev + 1000 / prev) / 2;
  } while (prev - next > 0.001);
  printf("sqrt(1000) = %.6f\n", next);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D26(%rip),%xmm3
  movss  D7(%rip),%xmm5
  movsd  D16(%rip),%xmm4
  movaps %xmm3,%xmm1
  nopl   0x0(%rax,%rax,1)
L6:
  movaps %xmm3,%xmm2
  movaps %xmm1,%xmm0
  divss  %xmm1,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm1
  mulss  %xmm5,%xmm1
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  comisd %xmm4,%xmm0
  ja     L6
  movaps %xmm1,%xmm0
  lea    D20(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D26
datatype: byte[4]
name: read_data
arguments: data_tag: D7
datatype: byte[4]
name: read_data
arguments: data_tag: D16
datatype: f64
name: read_data
arguments: data_tag: D20
datatype: string

tool: {"D26": [0x00,0x00,0x7a,0x44]}

tool: {"D7": [0x00,0x00,0x00,0x3f]}

tool: D16: 0.001

tool: D20: sqrt(1000) = %.6f


assistant: ```c
int main() {
  float prev, next;
  next = 1000;
  do {
    prev = next;
    next = (prev + 1000 / prev) / 2;
  } while (prev - next > 0.001);
  printf("sqrt(1000) = %.6f\n", next);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_79_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_79_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D | stk3;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_79_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  mov    %edi,%edx
  not    %edx
  or     $0xff,%dl
  and    %edx,%eax
  or     %edi,%eax
  not    %eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_79_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D | stk3;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_79_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  mov    %edi,%edx
  shl    $0x8,%eax
  not    %edx
  or     %esi,%eax
  or     $0xff,%dl
  and    %edx,%eax
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_79_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D | stk3;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_79_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  mov    %edi,%edx
  shl    $0x8,%eax
  not    %edx
  or     %esi,%eax
  or     $0xff,%dl
  and    %edx,%eax
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_79_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D | stk3;
  stk1 = T & stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ti_crossany>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L47
L15:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L8
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jae    L4
L8:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L32
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jb     L32
L4:
  mov    $0x1,%ecx
  jmp    L10
L32:
  mov    $0x0,%ecx
L10:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L47:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ti_crossany(int size, double const *const *inputs, double const *options, double *const *outputs) {
  const double *a = inputs[0];
  const double *b = inputs[1];
  (void)options;
  double *output = outputs[0];
  int i;
  for (i = 1; i < size; ++i) {
    *output++ = (a[i] > b[i] && a[i - 1] <= b[i - 1]) || (a[i] < b[i] && a[i - 1] >= b[i - 1]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ti_crossany>:
  endbr64
  mov    %rcx,%rax
  mov    (%rsi),%rcx
  mov    0x8(%rsi),%rsi
  mov    (%rax),%r8
  cmp    $0x1,%edi
  jle    L54
  lea    -0x1(%rdi),%edi
  mov    $0x0,%eax
  mov    $0x0,%r10d
  mov    $0x1,%r9d
  jmp    L5
L35:
  mov    %r10d,%edx
  comisd %xmm0,%xmm1
  jbe    L51
  movsd  (%rcx,%rax,8),%xmm0
  comisd (%rsi,%rax,8),%xmm0
  setae  %dl
  movzbl %dl,%edx
L51:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L54
L5:
  movsd  0x8(%rcx,%rax,8),%xmm0
  movsd  0x8(%rsi,%rax,8),%xmm1
  comisd %xmm1,%xmm0
  jbe    L35
  movsd  (%rsi,%rax,8),%xmm2
  mov    %r9d,%edx
  comisd (%rcx,%rax,8),%xmm2
  jae    L51
  jmp    L35
L54:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ti_crossany(int size, double const *const *inputs, double const *options, double *const *outputs) {
  const double *a = inputs[0];
  const double *b = inputs[1];
  (void)options;
  double *output = outputs[0];
  int i;
  for (i = 1; i < size; ++i) {
    *output++ = (a[i] > b[i] && a[i - 1] <= b[i - 1]) || (a[i] < b[i] && a[i - 1] >= b[i - 1]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ti_crossany>:
  endbr64
  mov    %rcx,%r8
  mov    0x8(%rsi),%rdx
  mov    (%rsi),%rcx
  xor    %eax,%eax
  mov    (%r8),%r8
  movsd  D5(%rip),%xmm4
  lea    -0x1(%rdi),%esi
  pxor   %xmm5,%xmm5
  cmp    $0x1,%edi
  jle    L42
  nopw   0x0(%rax,%rax,1)
L12:
  movsd  0x8(%rcx,%rax,8),%xmm1
  movsd  0x8(%rdx,%rax,8),%xmm2
  comisd %xmm2,%xmm1
  jbe    L38
  movsd  (%rdx,%rax,8),%xmm3
  comisd (%rcx,%rax,8),%xmm3
  movapd %xmm4,%xmm0
  jae    L3
L38:
  comisd %xmm1,%xmm2
  movapd %xmm5,%xmm0
  jbe    L3
  movsd  (%rcx,%rax,8),%xmm2
  movsd  (%rdx,%rax,8),%xmm1
  movapd %xmm4,%xmm0
  cmplesd %xmm2,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm5,%xmm1
  orpd   %xmm1,%xmm0
L3:
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L12
L42:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int ti_crossany(int size, double const *const *inputs, double const *options, double *const *outputs) {
  const double *a = inputs[0];
  const double *b = inputs[1];
  (void)options;
  double *output = outputs[0];
  int i;
  for (i = 1; i < size; ++i) {
    *output++ = (a[i] > b[i] && a[i - 1] <= b[i - 1]) || (a[i] < b[i] && a[i - 1] >= b[i - 1]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ti_crossany>:
  endbr64
  mov    %rcx,%r8
  mov    0x8(%rsi),%rdx
  mov    (%rsi),%rcx
  xor    %eax,%eax
  mov    (%r8),%r8
  movsd  D7(%rip),%xmm4
  lea    -0x1(%rdi),%esi
  pxor   %xmm5,%xmm5
  cmp    $0x1,%edi
  jle    L4
  nopw   0x0(%rax,%rax,1)
L6:
  movsd  0x8(%rcx,%rax,8),%xmm1
  movsd  0x8(%rdx,%rax,8),%xmm2
  comisd %xmm2,%xmm1
  jbe    L13
  movsd  (%rdx,%rax,8),%xmm3
  comisd (%rcx,%rax,8),%xmm3
  movapd %xmm4,%xmm0
  jae    L38
L13:
  comisd %xmm1,%xmm2
  movapd %xmm5,%xmm0
  jbe    L38
  movsd  (%rcx,%rax,8),%xmm2
  movsd  (%rdx,%rax,8),%xmm1
  movapd %xmm4,%xmm0
  cmplesd %xmm2,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm5,%xmm1
  orpd   %xmm1,%xmm0
L38:
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L6
L4:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int ti_crossany(int size, double const *const *inputs, double const *options, double *const *outputs) {
  const double *a = inputs[0];
  const double *b = inputs[1];
  (void)options;
  double *output = outputs[0];
  int i;
  for (i = 1; i < size; ++i) {
    *output++ = (a[i] > b[i] && a[i - 1] <= b[i - 1]) || (a[i] < b[i] && a[i - 1] >= b[i - 1]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<syscon_clear_symbol_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1d,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_clear_symbol_table(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(29, a, b, c);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<syscon_clear_symbol_table>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1d,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int syscon_clear_symbol_table(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(29, a, b, c);
  return fail;
}
```