user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L50
L38:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L104
L20:
  mov    $0x20,%edi
  call   <putchar@plt>
  subl   $0x1,-0x10(%rbp)
L104:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L20
  movl   $0x1,-0x10(%rbp)
  jmp    L77
L156:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L77:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L156
  movl   $0x1,-0xc(%rbp)
  jmp    L8
L157:
  subl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L157
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L50:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L38
  movl   $0x1,-0x14(%rbp)
  jmp    L82
L169:
  movl   $0x1,-0x10(%rbp)
  jmp    L29
L115:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L115
  movl   $0x1,-0x10(%rbp)
  jmp    L84
L66:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L84:
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  sub    $0x1,%edx
  sub    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jle    L66
  movl   $0x1,-0xc(%rbp)
  jmp    L121
L52:
  subl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L121:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L52
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L82:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L169
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L116
  call   <__stack_chk_fail@plt>
L116:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D52
datatype: string

tool: D11:  Enter the number of lines 

tool: D52: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int n, i, j, k;
  printf(" Enter the number of lines \n");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = n; j > i; j--)
      printf(" ");
    for (j = 1; j <= i; j++)
      printf("%d", j);
    for (k = 1; k <= i - 1; k++)
      printf("%d", --j - 1);
    printf("\n");
  }
  for (i = 1; i <= n; i++) {
    for (j = 1; j < i; j++)
      printf(" ");
    for (j = 1; j <= n - (i - 1); j++)
      printf("%d", j);
    for (k = 1; k <= n - (i); k++)
      printf("%d", --j - 1);
    printf("\n");
  }
  return 0;
}
```