ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sinc>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  movss  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  movss  %xmm1,0x10(%rsp)
  call   <fabsf@plt>
  movsd  D9(%rip),%xmm3
  movss  0x8(%rsp),%xmm2
  comisd %xmm0,%xmm3
  jbe    L8
L17:
  add    $0x28,%rsp
  movaps %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  movss  0x10(%rsp),%xmm1
  movss  %xmm2,0x18(%rsp)
  movaps %xmm1,%xmm0
  call   <fabsf@plt>
  pxor   %xmm4,%xmm4
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm4
  movapd %xmm0,%xmm3
  movapd %xmm4,%xmm0
  movsd  %xmm4,0x8(%rsp)
  mulsd  D26(%rip),%xmm0
  comisd %xmm0,%xmm3
  ja     L17
  movss  0x10(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  movaps %xmm1,%xmm3
  movss  %xmm1,0x1c(%rsp)
  mulss  %xmm2,%xmm3
  cvtss2sd %xmm3,%xmm3
  mulsd  D2(%rip),%xmm3
  movapd %xmm3,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <sin@plt>
  movss  0x1c(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm1
  mulss  %xmm2,%xmm0
  divsd  %xmm4,%xmm1
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm3,%xmm0
  cvttsd2si %xmm1,%edi
  movsd  %xmm0,0x10(%rsp)
  call   <fabs@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <compute_func@plt>
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  mulsd  0x10(%rsp),%xmm2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  cvtsd2ss %xmm2,%xmm2
  movaps %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: byte[8]
name: parse_data
arguments: label: D26
type_guessed: byte[8]
name: parse_data
arguments: label: D2
type_guessed: f64

tool: {"D9": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D2: 3.14159263

assistant: ```c
float sinc(float cutoff, float x, int N, struct FuncDef *window_func) {
  float xx = x * cutoff;
  if (fabsf(x) < 1e-6)
    return cutoff;
  else if (fabsf(x) > .5 * N)
    return 0;
  return cutoff * sin(3.14159263 * xx) / (3.14159263 * xx) * compute_func(fabs(2. * x / N), window_func);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sinc>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  movss  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  movss  %xmm1,0x10(%rsp)
  call   <fabsf@plt>
  movsd  D8(%rip),%xmm3
  movss  0x8(%rsp),%xmm2
  comisd %xmm0,%xmm3
  jbe    L17
L8:
  add    $0x28,%rsp
  movaps %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L17:
  movss  0x10(%rsp),%xmm1
  movss  %xmm2,0x18(%rsp)
  movaps %xmm1,%xmm0
  call   <fabsf@plt>
  pxor   %xmm4,%xmm4
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm4
  movapd %xmm0,%xmm3
  movapd %xmm4,%xmm0
  movsd  %xmm4,0x8(%rsp)
  mulsd  D14(%rip),%xmm0
  comisd %xmm0,%xmm3
  ja     L8
  movss  0x10(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  movaps %xmm1,%xmm3
  movss  %xmm1,0x1c(%rsp)
  mulss  %xmm2,%xmm3
  cvtss2sd %xmm3,%xmm3
  mulsd  D0(%rip),%xmm3
  movapd %xmm3,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <sin@plt>
  movss  0x1c(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm1
  mulss  %xmm2,%xmm0
  divsd  %xmm4,%xmm1
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm3,%xmm0
  cvttsd2si %xmm1,%edi
  movsd  %xmm0,0x10(%rsp)
  call   <fabs@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <compute_func@plt>
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  mulsd  0x10(%rsp),%xmm2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  cvtsd2ss %xmm2,%xmm2
  movaps %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: byte[8]
name: read_data
arguments: label: D14
type_guessed: byte[8]
name: read_data
arguments: label: D0
type_guessed: f64

tool: {"D8": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D0: 3.14159263

assistant: ```c
float sinc(float cutoff, float x, int N, struct FuncDef *window_func) {
  float xx = x * cutoff;
  if (fabsf(x) < 1e-6)
    return cutoff;
  else if (fabsf(x) > .5 * N)
    return 0;
  return cutoff * sin(3.14159263 * xx) / (3.14159263 * xx) * compute_func(fabs(2. * x / N), window_func);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %edi,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L50
  lea    -0x1(%rbp),%eax
  lea    (%rbx,%rax,8),%rbp
  lea    D8(%rip),%r12
  jmp    L108
L137:
  cmp    $0x2f,%al
  jne    L19
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%r13
  ucomisd D21(%rip),%xmm0
  jp     L26
  jne    L26
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L37
L124:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%r13
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %r13,%xmm2
  mulsd  %xmm2,%xmm0
  call   <push@plt>
L37:
  cmp    %rbp,%rbx
  je     L50
L108:
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  movzbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L139
  jg     L137
  cmp    $0x2a,%al
  je     L124
  cmp    $0x2b,%al
  jne    L19
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%r13
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %r13,%xmm1
  addsd  %xmm1,%xmm0
  call   <push@plt>
  jmp    L37
L139:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%r13
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %r13,%xmm3
  subsd  %xmm3,%xmm0
  call   <push@plt>
  jmp    L37
L26:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %r13,%xmm6
  divsd  %xmm6,%xmm0
  call   <push@plt>
  jmp    L37
L19:
  call   <atof@plt>
  call   <push@plt>
  jmp    L37
L50:
  mov    $0x0,%eax
  call   <pop@plt>
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D20
datatype: string
name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D21
datatype: f64
name: parse_data
arguments: label: D13
datatype: string

tool: D20: total commod line arguments:%d


tool: D8: error: zero divisor

tool: D21: 0

tool: D13: 	%.8g


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  double op2;
  char s[100];
  i = 1;
  printf("total commod line arguments:%d\n", argc);
  while (i < argc) {
    switch (*(*++argv)) {
    case '+':
      push(pop() + pop());
      break;
    case '*':
      push(pop() * pop());
      break;
    case '-':
      op2 = pop();
      push(pop() - op2);
      break;
    case '/':
      op2 = pop();
      if (op2 != 0.0)
        push(pop() / op2);
      else
        printf("error: zero divisor\n");
      break;
    default:
      push(atof(*argv));
      break;
    }
    i++;
  }
  printf("\t%.8g\n", pop());
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  lea    D21(%rip),%rdi
  sub    $0x10,%rsp
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L44
  lea    -0x1(%rbp),%eax
  lea    D23(%rip),%r12
  lea    (%rbx,%rax,8),%rbp
  jmp    L131
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    $0x2b,%al
  jne    L101
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  addsd  0x8(%rsp),%xmm0
  call   <push@plt>
L125:
  cmp    %rbp,%rbx
  je     L44
L131:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  movzbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L22
  jg     L31
  cmp    $0x2a,%al
  jne    L36
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  mulsd  0x8(%rsp),%xmm0
  call   <push@plt>
  cmp    %rbp,%rbx
  jne    L131
L44:
  xor    %eax,%eax
  call   <pop@plt>
  lea    D14(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L31:
  cmp    $0x2f,%al
  jne    L101
  xor    %eax,%eax
  call   <pop@plt>
  pxor   %xmm5,%xmm5
  ucomisd %xmm5,%xmm0
  movapd %xmm0,%xmm1
  jp     L12
  je     L56
L12:
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  call   <pop@plt>
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  call   <push@plt>
  jmp    L125
  nopl   0x0(%rax)
L101:
  call   <atof@plt>
  call   <push@plt>
  jmp    L125
  nop
L22:
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  subsd  0x8(%rsp),%xmm0
  call   <push@plt>
  jmp    L125
  nopl   0x0(%rax)
L56:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L125
```

tool_calls: name: retrieve_data
arguments: data_label: D21
type_guessed: string
name: retrieve_data
arguments: data_label: D23
type_guessed: string
name: retrieve_data
arguments: data_label: D14
type_guessed: string

tool: D21: total commod line arguments:%d


tool: D23: error: zero divisor

tool: D14: 	%.8g


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  double op2;
  char s[100];
  i = 1;
  printf("total commod line arguments:%d\n", argc);
  while (i < argc) {
    switch (*(*++argv)) {
    case '+':
      push(pop() + pop());
      break;
    case '*':
      push(pop() * pop());
      break;
    case '-':
      op2 = pop();
      push(pop() - op2);
      break;
    case '/':
      op2 = pop();
      if (op2 != 0.0)
        push(pop() / op2);
      else
        printf("error: zero divisor\n");
      break;
    default:
      push(atof(*argv));
      break;
    }
    i++;
  }
  printf("\t%.8g\n", pop());
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  sub    $0x10,%rsp
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L113
  lea    -0x1(%rbp),%eax
  lea    D18(%rip),%r12
  lea    (%rbx,%rax,8),%rbp
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L27:
  cmp    $0x2b,%al
  jne    L2
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  addsd  0x8(%rsp),%xmm0
  call   <push@plt>
L8:
  cmp    %rbp,%rbx
  je     L113
L70:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  movzbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L104
  jg     L61
  cmp    $0x2a,%al
  jne    L27
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  mulsd  0x8(%rsp),%xmm0
  call   <push@plt>
  cmp    %rbp,%rbx
  jne    L70
L113:
  xor    %eax,%eax
  call   <pop@plt>
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L61:
  cmp    $0x2f,%al
  jne    L2
  xor    %eax,%eax
  call   <pop@plt>
  pxor   %xmm5,%xmm5
  ucomisd %xmm5,%xmm0
  movapd %xmm0,%xmm1
  jp     L59
  je     L14
L59:
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  call   <pop@plt>
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  call   <push@plt>
  jmp    L8
  nopl   0x0(%rax)
L2:
  call   <atof@plt>
  call   <push@plt>
  jmp    L8
  nop
L104:
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  subsd  0x8(%rsp),%xmm0
  call   <push@plt>
  jmp    L8
  nopl   0x0(%rax)
L14:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D18
data_type: string
name: extract_symbolic_data
arguments: data_label: D19
data_type: string

tool: D6: total commod line arguments:%d


tool: D18: error: zero divisor

tool: D19: 	%.8g


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  double op2;
  char s[100];
  i = 1;
  printf("total commod line arguments:%d\n", argc);
  while (i < argc) {
    switch (*(*++argv)) {
    case '+':
      push(pop() + pop());
      break;
    case '*':
      push(pop() * pop());
      break;
    case '-':
      op2 = pop();
      push(pop() - op2);
      break;
    case '/':
      op2 = pop();
      if (op2 != 0.0)
        push(pop() / op2);
      else
        printf("error: zero divisor\n");
      break;
    default:
      push(atof(*argv));
      break;
    }
    i++;
  }
  printf("\t%.8g\n", pop());
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<InsertionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L20
L11:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L29
L19:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  subl   $0x1,-0xc(%rbp)
L29:
  cmpl   $0x0,-0xc(%rbp)
  js     L3
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss -0x4(%rbp),%xmm0
  ja     L19
L3:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void InsertionSort(float x[], int n) {
  float a;
  int i, j;
  for (j = 1; j < n; j++) {
    a = x[j];
    i = j - 1;
    while (i >= 0 && x[i] > a) {
      x[i + 1] = x[i];
      i--;
    }
    x[i + 1] = a;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InsertionSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L16
  mov    %rdi,%r8
  lea    -0x1(%rsi),%esi
  mov    $0x0,%ecx
  jmp    L24
L13:
  movslq %edx,%rdx
  movss  %xmm1,0x4(%rdi,%rdx,4)
  add    $0x1,%rcx
  add    $0x4,%r8
  cmp    %rsi,%rcx
  je     L16
L24:
  movss  0x4(%r8),%xmm1
  mov    %ecx,%edx
  mov    %r8,%rax
  test   %ecx,%ecx
  js     L13
L43:
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L13
  movss  %xmm0,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L43
  jmp    L13
L16:
  ret
```

assistant: ```c
void InsertionSort(float x[], int n) {
  float a;
  int i, j;
  for (j = 1; j < n; j++) {
    a = x[j];
    i = j - 1;
    while (i >= 0 && x[i] > a) {
      x[i + 1] = x[i];
      i--;
    }
    x[i + 1] = a;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<InsertionSort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  xor    %ecx,%ecx
  cmp    $0x1,%esi
  jle    L3
  nop
L47:
  movss  0x4(%rdi,%rcx,4),%xmm1
  mov    %rcx,%rax
  nopl   0x0(%rax)
L5:
  movss  (%rdi,%rax,4),%xmm0
  mov    %eax,%edx
  comiss %xmm1,%xmm0
  jbe    L28
  movss  %xmm0,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L5
  mov    %rdi,%rax
L18:
  add    $0x1,%rcx
  movss  %xmm1,(%rax)
  cmp    %rcx,%r8
  jne    L47
L3:
  ret
  nopl   0x0(%rax)
L28:
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  jmp    L18
```

assistant: ```c
void InsertionSort(float x[], int n) {
  float a;
  int i, j;
  for (j = 1; j < n; j++) {
    a = x[j];
    i = j - 1;
    while (i >= 0 && x[i] > a) {
      x[i + 1] = x[i];
      i--;
    }
    x[i + 1] = a;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InsertionSort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  xor    %ecx,%ecx
  cmp    $0x1,%esi
  jle    L18
  nop
L30:
  movss  0x4(%rdi,%rcx,4),%xmm1
  mov    %rcx,%rax
  nopl   0x0(%rax)
L5:
  movss  (%rdi,%rax,4),%xmm0
  mov    %eax,%edx
  comiss %xmm1,%xmm0
  jbe    L10
  movss  %xmm0,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L5
  mov    %rdi,%rax
L27:
  add    $0x1,%rcx
  movss  %xmm1,(%rax)
  cmp    %rcx,%r8
  jne    L30
L18:
  ret
  nopl   0x0(%rax)
L10:
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  jmp    L27
```

assistant: ```c
void InsertionSort(float x[], int n) {
  float a;
  int i, j;
  for (j = 1; j < n; j++) {
    a = x[j];
    i = j - 1;
    while (i >= 0 && x[i] > a) {
      x[i + 1] = x[i];
      i--;
    }
    x[i + 1] = a;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<get_totients_under_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x15,%edi
  call   <get_totients_under@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%eax
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  add    $0x2c,%rax
  mov    (%rax),%eax
  cmp    $0xa,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  add    $0x4c,%rax
  mov    (%rax),%eax
  cmp    $0x12,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  add    $0x50,%rax
  mov    (%rax),%eax
  cmp    $0x8,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void get_totients_under_test(void) {
  int *totients = get_totients_under(21);
  assert(totients[1] == 1);
  assert(totients[2] == 1);
  assert(totients[3] == 2);
  assert(totients[4] == 2);
  assert(totients[5] == 4);
  assert(totients[10] == 4);
  assert(totients[11] == 10);
  assert(totients[19] == 18);
  assert(totients[20] == 8);
  free(totients);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_totients_under_test>:
  endbr64
  push   %rbx
  mov    $0x15,%edi
  call   <get_totients_under@plt>
  mov    %rax,%rbx
  cmpl   $0x1,0x4(%rax)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,0x8(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x2,0xc(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x2,0x10(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x4,0x14(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x4,0x28(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0xa,0x2c(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x12,0x4c(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x8,0x50(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void get_totients_under_test(void) {
  int *totients = get_totients_under(21);
  assert(totients[1] == 1);
  assert(totients[2] == 1);
  assert(totients[3] == 2);
  assert(totients[4] == 2);
  assert(totients[5] == 4);
  assert(totients[10] == 4);
  assert(totients[11] == 10);
  assert(totients[19] == 18);
  assert(totients[20] == 8);
  free(totients);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_totients_under_test>:
  endbr64
  push   %rbp
  mov    $0x15,%edi
  call   <get_totients_under@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x4(%rax)
  mov    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x8(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x2,0xc(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x2,0x10(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x4,0x14(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x4,0x28(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0xa,0x2c(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x12,0x4c(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x8,0x50(%rbp)
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void get_totients_under_test(void) {
  int *totients = get_totients_under(21);
  assert(totients[1] == 1);
  assert(totients[2] == 1);
  assert(totients[3] == 2);
  assert(totients[4] == 2);
  assert(totients[5] == 4);
  assert(totients[10] == 4);
  assert(totients[11] == 10);
  assert(totients[19] == 18);
  assert(totients[20] == 8);
  free(totients);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_totients_under_test>:
  endbr64
  push   %rbp
  mov    $0x15,%edi
  call   <get_totients_under@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x4(%rax)
  mov    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x8(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x2,0xc(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x2,0x10(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x4,0x14(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x4,0x28(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0xa,0x2c(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x12,0x4c(%rbp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x8,0x50(%rbp)
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void get_totients_under_test(void) {
  int *totients = get_totients_under(21);
  assert(totients[1] == 1);
  assert(totients[2] == 1);
  assert(totients[3] == 2);
  assert(totients[4] == 2);
  assert(totients[5] == 4);
  assert(totients[10] == 4);
  assert(totients[11] == 10);
  assert(totients[19] == 18);
  assert(totients[20] == 8);
  free(totients);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L9
L1:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x18(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L1
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <findMin@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D21
type_guessed: string

tool: D4: %d

tool: D21: 
%d


assistant: ```c
int main() {
  int low = 0, high = 0;
  scanf("%d", &high);
  int i, *arr;
  arr = (int *)malloc(high * sizeof(int));
  for (i = 0; i < high; i++)
    scanf("%d", &arr[i]);
  printf("\n%d\n", findMin(arr, 0, high - 1));
  return 0;
}
```