ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<testRotation>:
  endbr64
  sub    $0x8,%rsp
  mov    D76(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D76(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D76(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D76(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D21(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D21(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D21(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D21(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D76
type: byte[8]
name: parse_data
arguments: tag: D21
type: byte[8]

tool: {"D76": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D21": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0xbf]}

assistant: ```c
void testRotation() {
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<testRotation>:
  endbr64
  sub    $0x8,%rsp
  movsd  D40(%rip),%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D40(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D40(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D40(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  movsd  D54(%rip),%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D54(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D54(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D54(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1080 <wait10Msec@plt>
```

tool_calls: name: parse_data
arguments: data_label: D40
type_infered: byte[8]
name: parse_data
arguments: data_label: D54
type_infered: byte[8]

tool: {"D40": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D54": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0xbf]}

assistant: ```c
void testRotation() {
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testRotation>:
  endbr64
  sub    $0x8,%rsp
  movsd  D31(%rip),%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D31(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D31(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D31(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  movsd  D40(%rip),%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D40(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D40(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  call   <wait10Msec@plt>
  mov    D40(%rip),%rax
  movq   %rax,%xmm0
  call   <rotateRobot@plt>
  xor    %eax,%eax
  call   <stopRobot@plt>
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1080 <wait10Msec@plt>
```

tool_calls: name: read_data
arguments: tag: D31
type: byte[8]
name: read_data
arguments: tag: D40
type: byte[8]

tool: {"D31": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D40": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0xbf]}

assistant: ```c
void testRotation() {
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
  rotateRobot(-3.14159265358979323846 / 2);
  stopRobot();
  wait10Msec(100);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBFS_BUS_RESET_ISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <USBFS_ReInitComponent@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBFS_BUS_RESET_ISR(void) {
  do {
  } while (0);
  USBFS_ReInitComponent();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<USBFS_BUS_RESET_ISR>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <USBFS_ReInitComponent@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void USBFS_BUS_RESET_ISR(void) {
  do {
  } while (0);
  USBFS_ReInitComponent();
}
```
user: What is the c source code of the assembly code below:

```asm
<USBFS_BUS_RESET_ISR>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <USBFS_ReInitComponent@plt>
```

assistant: ```c
void USBFS_BUS_RESET_ISR(void) {
  do {
  } while (0);
  USBFS_ReInitComponent();
}
```
user: What is the c source code of the assembly code below?

```asm
<USBFS_BUS_RESET_ISR>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <USBFS_ReInitComponent@plt>
```

assistant: ```c
void USBFS_BUS_RESET_ISR(void) {
  do {
  } while (0);
  USBFS_ReInitComponent();
}
```
user: What is the c source code of the assembly code below?

```asm
<issymname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L1
  mov    $0x0,%eax
  jmp    L18
L66:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L1
  mov    $0x0,%eax
  jmp    L18
L1:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L66
  mov    $0x1,%eax
L18:
  leave
  ret
```

assistant: ```c
int issymname(char *label) {
  if (!isalpha(*label) && *label != '_')
    return 0;
  while (*++label)
    if (!isalnum(*label) && *label != '_')
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<issymname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L59
  cmpb   $0x5f,0x0(%rbp)
  jne    L70
L59:
  lea    0x1(%rbp),%rbx
  movzbl 0x1(%rbp),%edi
  test   %dil,%dil
  jne    L73
  mov    $0x1,%eax
  jmp    L70
L34:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L74
L73:
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L34
  cmpb   $0x5f,(%rbx)
  je     L34
  jmp    L70
L74:
  mov    $0x1,%eax
L70:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int issymname(char *label) {
  if (!isalpha(*label) && *label != '_')
    return 0;
  while (*++label)
    if (!isalnum(*label) && *label != '_')
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<issymname>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L29
  cmpb   $0x5f,0x0(%rbp)
  jne    L6
L29:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rbx
  test   %dil,%dil
  je     L21
  nopl   0x0(%rax)
L26:
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L5
  cmpb   $0x5f,(%rbx)
  jne    L6
L5:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L26
L21:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int issymname(char *label) {
  if (!isalpha(*label) && *label != '_')
    return 0;
  while (*++label)
    if (!isalnum(*label) && *label != '_')
      return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<issymname>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L3
  cmpb   $0x5f,0x0(%rbp)
  jne    L9
L3:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rbx
  test   %dil,%dil
  je     L20
  nopl   0x0(%rax)
L34:
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L45
  cmpb   $0x5f,(%rbx)
  jne    L9
L45:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L34
L20:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int issymname(char *label) {
  if (!isalpha(*label) && *label != '_')
    return 0;
  while (*++label)
    if (!isalnum(*label) && *label != '_')
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vlad_sizeof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpl   $0x6,-0x1c(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L26:
  cmpl   $0xf,-0x1c(%rbp)
  jne    L15
  shlq   -0x8(%rbp)
L15:
  cmpl   $0x11,-0x1c(%rbp)
  jne    L28
  shlq   -0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t vlad_sizeof(int k, int d, int flags) {
  size_t s = d * k;
  if (flags == 6)
    s *= 3;
  if (flags == 15)
    s *= 2;
  if (flags == 17)
    s *= 2;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vlad_sizeof>:
  endbr64
  imul   %edi,%esi
  movslq %esi,%rax
  cmp    $0x6,%edx
  je     L29
  cmp    $0xf,%edx
  jne    L27
  add    %rax,%rax
  ret
L29:
  lea    (%rax,%rax,2),%rax
  ret
L27:
  cmp    $0x11,%edx
  jne    L22
  add    %rax,%rax
L22:
  ret
```

assistant: ```c
size_t vlad_sizeof(int k, int d, int flags) {
  size_t s = d * k;
  if (flags == 6)
    s *= 3;
  if (flags == 15)
    s *= 2;
  if (flags == 17)
    s *= 2;
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vlad_sizeof>:
  endbr64
  imul   %edi,%esi
  movslq %esi,%rax
  cmp    $0x6,%edx
  je     L12
  cmp    $0xf,%edx
  jne    L13
L20:
  add    %rax,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  cmp    $0x11,%edx
  je     L20
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  lea    (%rax,%rax,2),%rax
  ret
```

assistant: ```c
size_t vlad_sizeof(int k, int d, int flags) {
  size_t s = d * k;
  if (flags == 6)
    s *= 3;
  if (flags == 15)
    s *= 2;
  if (flags == 17)
    s *= 2;
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vlad_sizeof>:
  endbr64
  imul   %edi,%esi
  movslq %esi,%rax
  cmp    $0x6,%edx
  je     L18
  cmp    $0xf,%edx
  jne    L23
L12:
  add    %rax,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  cmp    $0x11,%edx
  je     L12
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  lea    (%rax,%rax,2),%rax
  ret
```

assistant: ```c
size_t vlad_sizeof(int k, int d, int flags) {
  size_t s = d * k;
  if (flags == 6)
    s *= 3;
  if (flags == 15)
    s *= 2;
  if (flags == 17)
    s *= 2;
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<processObjects>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa4(%rbp)
  jmp    L7
L16:
  mov    -0xb8(%rbp),%rdx
  lea    -0xa0(%rbp),%rax
  mov    $0x26,%esi
  mov    %rax,%rdi
  call   <CK_Cross_freadInt16LE@plt>
  cmp    $0x26,%eax
  je     L69
  mov    $0x0,%eax
  jmp    L38
L69:
  mov    -0xa4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xa8(%rbp)
  jmp    L52
L36:
  mov    -0xa8(%rbp),%eax
  cltq
  mov    -0xa0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xa8(%rbp)
L52:
  cmpl   $0x25,-0xa8(%rbp)
  jle    L36
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xa4(%rbp)
L7:
  cmpl   $0x63,-0xa4(%rbp)
  jle    L16
  mov    $0x1,%eax
L38:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D15: Obj %02X:

tool: D19:  %04X

assistant: ```c
bool processObjects(FILE *fp) {
  uint16_t objFields[38];
  int i, j;
  for (j = 0; j < 100; ++j) {
    if (CK_Cross_freadInt16LE(&objFields, 38, fp) != 38)
      return false;
    printf("Obj %02X:", j);
    for (i = 0; i < 38; ++i)
      printf(" %04X", objFields[i]);
    printf("\n");
  }
  return true;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<processObjects>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r13d
  mov    %rsp,%r15
  lea    0x98(%rsp),%r12
  lea    D0(%rip),%rbp
  jmp    L5
L23:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  cmp    $0x64,%r13d
  je     L46
L5:
  mov    %r14,%rdx
  mov    $0x26,%esi
  mov    %r15,%rdi
  call   <CK_Cross_freadInt16LE@plt>
  cmp    $0x26,%eax
  jne    L69
  mov    %r13d,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
L43:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L43
  jmp    L23
L46:
  mov    $0x1,%eax
  jmp    L68
L69:
  mov    $0x0,%eax
L68:
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D5
type: string

tool: D0:  %04X

tool: D5: Obj %02X:

assistant: ```c
bool processObjects(FILE *fp) {
  uint16_t objFields[38];
  int i, j;
  for (j = 0; j < 100; ++j) {
    if (CK_Cross_freadInt16LE(&objFields, 38, fp) != 38)
      return false;
    printf("Obj %02X:", j);
    for (i = 0; i < 38; ++i)
      printf(" %04X", objFields[i]);
    printf("\n");
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<processObjects>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x98(%rsp),%rbp
L19:
  mov    %r14,%rdx
  mov    $0x26,%esi
  mov    %r13,%rdi
  call   <CK_Cross_freadInt16LE@plt>
  cmp    $0x26,%eax
  jne    L27
  mov    %r12d,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  mov    %r13,%r15
  call   <printf@plt>
  nopl   0x0(%rax)
L6:
  mov    (%r15),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L6
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0x64,%r12d
  jne    L19
  mov    $0x1,%eax
  jmp    L18
L27:
  xor    %eax,%eax
L18:
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D15:  %04X

tool: D13: Obj %02X:

assistant: ```c
bool processObjects(FILE *fp) {
  uint16_t objFields[38];
  int i, j;
  for (j = 0; j < 100; ++j) {
    if (CK_Cross_freadInt16LE(&objFields, 38, fp) != 38)
      return false;
    printf("Obj %02X:", j);
    for (i = 0; i < 38; ++i)
      printf(" %04X", objFields[i]);
    printf("\n");
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<processObjects>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  lea    D17(%rip),%rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x98(%rsp),%rbp
L2:
  mov    %r14,%rdx
  mov    $0x26,%esi
  mov    %r13,%rdi
  call   <CK_Cross_freadInt16LE@plt>
  cmp    $0x26,%eax
  jne    L38
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  mov    %r13,%r15
  call   <printf@plt>
  nopl   0x0(%rax)
L46:
  mov    (%r15),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L46
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0x64,%r12d
  jne    L2
  mov    $0x1,%eax
  jmp    L44
L38:
  xor    %eax,%eax
L44:
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D17:  %04X

tool: D4: Obj %02X:

assistant: ```c
bool processObjects(FILE *fp) {
  uint16_t objFields[38];
  int i, j;
  for (j = 0; j < 100; ++j) {
    if (CK_Cross_freadInt16LE(&objFields, 38, fp) != 38)
      return false;
    printf("Obj %02X:", j);
    for (i = 0; i < 38; ++i)
      printf(" %04X", objFields[i]);
    printf("\n");
  }
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<writeSection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x10(%rbp),%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x10(%rbp),%rax
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x10(%rbp),%rax
  shr    $0x18,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x18(%rbp),%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x18,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void writeSection(FILE *file, unsigned long num, unsigned long size) {
  putc((int)(num & 0xFF), file);
  putc((int)((num >> 8) & 0xFF), file);
  putc((int)((num >> 16) & 0xFF), file);
  putc((int)((num >> 24) & 0xFF), file);
  putc((int)(size & 0xFF), file);
  putc((int)((size >> 8) & 0xFF), file);
  putc((int)((size >> 16) & 0xFF), file);
  putc((int)((size >> 24) & 0xFF), file);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writeSection>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  movzbl %sil,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  mov    %r12d,%eax
  movzbl %ah,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  mov    %r12,%rdi
  shr    $0x10,%rdi
  movzbl %dil,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  mov    %r12d,%edi
  shr    $0x18,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  movzbl %bpl,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  mov    %rbp,%rdi
  shr    $0x10,%rdi
  movzbl %dil,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  mov    %ebp,%edi
  shr    $0x18,%edi
  mov    %rbx,%rsi
  call   <putc@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void writeSection(FILE *file, unsigned long num, unsigned long size) {
  putc((int)(num & 0xFF), file);
  putc((int)((num >> 8) & 0xFF), file);
  putc((int)((num >> 16) & 0xFF), file);
  putc((int)((num >> 24) & 0xFF), file);
  putc((int)(size & 0xFF), file);
  putc((int)((size >> 8) & 0xFF), file);
  putc((int)((size >> 16) & 0xFF), file);
  putc((int)((size >> 24) & 0xFF), file);
}
```