user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D182(%rip),%rdi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D170(%rip),%r12
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  lea    D199(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L88
  nopl   0x0(%rax,%rax,1)
L294:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L28
  mov    %rbp,%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    %r13d,0x4(%rsp)
  jg     L294
L88:
  lea    D126(%rip),%rdi
  mov    $0x1,%r13d
  lea    D170(%rip),%r12
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  lea    D24(%rip),%rbp
  test   %edx,%edx
  jle    L68
  nopl   0x0(%rax)
L67:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L172:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L172
  mov    %rbp,%rdi
  lea    0x1(%r13),%ebx
  call   <printf@plt>
  cmp    %r13d,0x4(%rsp)
  jle    L68
  mov    %ebx,%r13d
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L68:
  lea    D146(%rip),%rdi
  lea    D24(%rip),%rbp
  call   <printf@plt>
  mov    0x4(%rsp),%r14d
  lea    D170(%rip),%r13
  mov    %r14d,%r12d
  test   %r14d,%r14d
  jle    L211
  nopw   0x0(%rax,%rax,1)
L59:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L272
  nopw   0x0(%rax,%rax,1)
L285:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L285
L272:
  mov    %rbp,%rdi
  sub    $0x1,%r12d
  call   <printf@plt>
  mov    %r14d,%eax
  sub    %r12d,%eax
  cmp    %eax,0x4(%rsp)
  jg     L59
L211:
  lea    D34(%rip),%rdi
  xor    %r12d,%r12d
  lea    D24(%rip),%rbp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D170(%rip),%r14
  lea    D57(%rip),%r13
  test   %eax,%eax
  jle    L12
  nopl   0x0(%rax)
L221:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L199:
  cmp    %ebx,%r12d
  jle    L19
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L199
L291:
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jg     L221
L12:
  lea    D161(%rip),%rdi
  lea    D24(%rip),%rbp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D57(%rip),%r14
  lea    D170(%rip),%r13
  lea    -0x1(%rax),%r15d
  mov    %r15d,%r12d
  test   %eax,%eax
  jle    L224
  nopl   (%rax)
L169:
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L111
  cs nopw 0x0(%rax,%rax,1)
L235:
  cmp    %r12d,%ebx
  jl     L89
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    0x4(%rsp),%ebx
  jl     L235
L111:
  mov    %rbp,%rdi
  sub    $0x1,%r12d
  call   <printf@plt>
  mov    %r15d,%edx
  mov    0x4(%rsp),%eax
  sub    %r12d,%edx
  cmp    %edx,%eax
  jg     L169
L224:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax,%rax,1),%edx
  test   %edx,%edx
  jle    L253
  xor    %r15d,%r15d
  mov    $0x1,%r12d
  xor    %r14d,%r14d
  lea    D24(%rip),%rbp
  lea    D170(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L72:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L116
  nopw   0x0(%rax,%rax,1)
L273:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L273
  mov    0x4(%rsp),%eax
L116:
  test   %r15d,%r15d
  jne    L202
  cmp    %r12d,%eax
  je     L202
  add    $0x1,%r12d
L156:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax,%rax,1),%edx
  cmp    %r14d,%edx
  jg     L72
L253:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L199
  jmp    L291
  nopw   0x0(%rax,%rax,1)
L89:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L235
  jmp    L111
  nopw   0x0(%rax,%rax,1)
L202:
  sub    $0x1,%r12d
  mov    $0x1,%r15d
  jmp    L156
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D182
type_guessed: string
name: retrieve_data
arguments: data_label: D170
type_guessed: string
name: retrieve_data
arguments: data_label: D24
type_guessed: string
name: retrieve_data
arguments: data_label: D199
type_guessed: string
name: retrieve_data
arguments: data_label: D126
type_guessed: string
name: retrieve_data
arguments: data_label: D146
type_guessed: string
name: retrieve_data
arguments: data_label: D34
type_guessed: string
name: retrieve_data
arguments: data_label: D57
type_guessed: string
name: retrieve_data
arguments: data_label: D161
type_guessed: string
name: retrieve_data
arguments: data_label: D53
type_guessed: string

tool: D182: %d

tool: D170: * 

tool: D24: 


tool: D199: 
------------ Exemplo 1 ------------



tool: D126: 
------------ Exemplo 2 ------------



tool: D146: 
------------ Exemplo 3 ------------



tool: D34: 
------------ Exemplo 4 ------------



tool: D57:   

tool: D161: 
------------ Exemplo 5 ------------



tool: D53: 
------------ Exemplo 6 ------------



assistant: ```c
int main() {
  int i, j, x;
  scanf("%d", &x);
  printf("\n------------ Exemplo 1 ------------\n\n");
  for (i = 0; i < x; i++) {
    for (j = 0; j < x; j++) {
      printf("* ");
    }
    printf("\n");
  }
  printf("\n------------ Exemplo 2 ------------\n\n");
  int k = 1;
  for (i = 0; i < x; i++) {
    for (j = 0; j < k; j++) {
      printf("* ");
    }
    k++;
    printf("\n");
  }
  printf("\n------------ Exemplo 3 ------------\n\n");
  k = x;
  for (i = 0; i < x; i++) {
    for (j = 0; j < k; j++) {
      printf("* ");
    }
    k--;
    printf("\n");
  }
  printf("\n------------ Exemplo 4 ------------\n\n");
  k = 0;
  for (i = 0; i < x; i++) {
    for (j = 0; j < x; j++) {
      printf(j >= k ? "* " : "  ");
    }
    k++;
    printf("\n");
  }
  printf("\n------------ Exemplo 5 ------------\n\n");
  k = x - 1;
  for (i = 0; i < x; i++) {
    for (j = 0; j < x; j++) {
      printf(j < k ? "  " : "* ");
    }
    k--;
    printf("\n");
  }
  printf("\n------------ Exemplo 6 ------------\n\n");
  k = 1;
  int r = 0;
  for (i = 0; i < x + (x - 1); i++) {
    for (j = 0; j < k; j++) {
      printf("* ");
    }
    if (k == x) {
      r = 1;
    }
    if (r == 0) {
      k++;
    } else {
      k--;
    }
    printf("\n");
  }
  return 0;
}
```