ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <malloc@plt>
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  char c, *c0 = malloc(0), *c1;
  c = *c0;
  c0 = realloc(c0, 10);
  assert(c0);
  c = *c0;
  c1 = c0;
  c0 = realloc(c0, 0);
  assert(!c0);
  c = *c1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <malloc@plt>
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  char c, *c0 = malloc(0), *c1;
  c = *c0;
  c0 = realloc(c0, 10);
  assert(c0);
  c = *c0;
  c1 = c0;
  c0 = realloc(c0, 0);
  assert(!c0);
  c = *c1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L26
L27:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jle    L9
  sarq   -0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
  jmp    L26
L9:
  sarq   -0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L27
  mov    -0x4(%rbp),%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
long long dist(long long a, long long b) {
  int count;
  while (a != b) {
    if (a > b) {
      a = a >> 1;
      count += 1;
    } else {
      b = b >> 1;
      count += 1;
    }
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dist>:
  endbr64
  cmp    %rsi,%rdi
  je     L30
  mov    $0x1,%edx
  jmp    L14
L40:
  sar    %rsi
  mov    %edx,%eax
L34:
  add    $0x1,%edx
  cmp    %rsi,%rdi
  je     L30
L14:
  cmp    %rsi,%rdi
  jle    L40
  sar    %rdi
  mov    %edx,%eax
  jmp    L34
L30:
  cltq
  ret
```

assistant: ```c
long long dist(long long a, long long b) {
  int count;
  while (a != b) {
    if (a > b) {
      a = a >> 1;
      count += 1;
    } else {
      b = b >> 1;
      count += 1;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dist>:
  endbr64
  cmp    %rsi,%rdi
  jne    L36
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L33:
  sar    %rdi
  cmp    %rdi,%rsi
  je     L34
L36:
  add    $0x1,%eax
  cmp    %rdi,%rsi
  jl     L33
  sar    %rsi
  cmp    %rdi,%rsi
  jne    L36
L34:
  cltq
  ret
```

assistant: ```c
long long dist(long long a, long long b) {
  int count;
  while (a != b) {
    if (a > b) {
      a = a >> 1;
      count += 1;
    } else {
      b = b >> 1;
      count += 1;
    }
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dist>:
  endbr64
  nopl   0x0(%rax)
L0:
  cmp    %rsi,%rdi
  je     L28
L4:
  add    $0x1,%eax
  cmp    %rsi,%rdi
  jle    L25
  sar    %rdi
  cmp    %rdi,%rsi
  jne    L4
L28:
  cltq
  ret
L25:
  sar    %rsi
  jmp    L0
```

assistant: ```c
long long dist(long long a, long long b) {
  int count;
  while (a != b) {
    if (a > b) {
      a = a >> 1;
      count += 1;
    } else {
      b = b >> 1;
      count += 1;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L94:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x5(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x5(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L94
  cmpb   $0x9,-0x5(%rbp)
  je     L94
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L122
  cmpb   $0x2e,-0x5(%rbp)
  je     L122
  cmpb   $0x2d,-0x5(%rbp)
  je     L122
  movzbl -0x5(%rbp),%eax
  jmp    L129
L122:
  movl   $0x0,-0x4(%rbp)
  cmpb   $0x2d,-0x5(%rbp)
  jne    L111
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L25
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  mov    -0x18(%rbp),%rax
  movb   $0x2d,(%rax)
  jmp    L111
L25:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  mov    $0x2d,%eax
  jmp    L129
L111:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L23
  cmpb   $0x2e,-0x5(%rbp)
  je     L23
  nop
L145:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x5(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L145
L23:
  cmpb   $0x2e,-0x5(%rbp)
  jne    L12
  nop
L142:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x5(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L142
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D8(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  je     L96
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L96:
  mov    $0x30,%eax
L129:
  leave
  ret
```

assistant: ```c
char getop(char str[]) {
  int i;
  char ch;
  while ((str[0] = ch = getch()) == ' ' || ch == '\t')
    ;
  if (!isdigit(ch) && ch != '.' && ch != '-') {
    return ch;
  }
  i = 0;
  if (ch == '-') {
    if (isdigit(ch = getch())) {
      ungetch(ch);
      str[0] = '-';
    } else {
      ungetch(ch);
      return '-';
    }
  }
  if (isdigit(ch) && ch != '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  if (ch == '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  str[i] = '\0';
  if (ch != EOF) {
    ungetch(ch);
  }
  return '0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L60:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%al
  je     L60
  cmp    $0x20,%al
  je     L60
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L94
  lea    -0x2d(%rbx),%eax
  cmp    $0x1,%al
  ja     L142
L94:
  cmp    $0x2d,%bl
  je     L15
L88:
  movsbl %bl,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%bl
  je     L157
  test   %rax,%rax
  jne    L41
L157:
  mov    $0x0,%r13d
L20:
  cmp    $0x2e,%bl
  je     L21
L153:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    D3(%rip),%rax
  cmp    %bl,(%rax)
  jne    L72
  mov    $0x30,%ebx
L142:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  movsbl %al,%r13d
  mov    %r13d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L59
  mov    %r13d,%edi
  call   <ungetch@plt>
  movb   $0x2d,0x0(%rbp)
  mov    %r12d,%ebx
  jmp    L88
L59:
  mov    %r13d,%edi
  call   <ungetch@plt>
  jmp    L142
L41:
  mov    $0x1,%r12d
L85:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L85
  jmp    L20
L21:
  lea    0x1(%r13),%r12d
  movslq %r12d,%r12
L105:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L105
  jmp    L153
L72:
  movsbl %bl,%edi
  call   <ungetch@plt>
  mov    $0x30,%ebx
  jmp    L142
```

assistant: ```c
char getop(char str[]) {
  int i;
  char ch;
  while ((str[0] = ch = getch()) == ' ' || ch == '\t')
    ;
  if (!isdigit(ch) && ch != '.' && ch != '-') {
    return ch;
  }
  i = 0;
  if (ch == '-') {
    if (isdigit(ch = getch())) {
      ungetch(ch);
      str[0] = '-';
    } else {
      ungetch(ch);
      return '-';
    }
  }
  if (isdigit(ch) && ch != '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  if (ch == '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  str[i] = '\0';
  if (ch != EOF) {
    ungetch(ch);
  }
  return '0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L150:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x20,%al
  je     L150
  cmp    $0x9,%al
  je     L150
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L80
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%al
  ja     L35
L80:
  cmp    $0x2d,%r12b
  je     L58
L96:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L28
  xor    %r13d,%r13d
  movslq %r13d,%rbp
  add    %rbx,%rbp
  cmp    $0x2e,%r12b
  je     L131
L139:
  mov    D2(%rip),%rax
  movb   $0x0,0x0(%rbp)
  cmp    %r12b,(%rax)
  je     L113
L93:
  movsbl %r12b,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
L35:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  cmp    $0x2e,%r12b
  je     L7
  mov    $0x1,%ebp
  nop
L3:
  xor    %eax,%eax
  movslq %ebp,%r13
  call   <getch@plt>
  movsbl %al,%edi
  mov    %dil,(%rbx,%rbp,1)
  mov    %edi,%r12d
  add    $0x1,%rbp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L3
  movslq %r13d,%rbp
  add    %rbx,%rbp
  cmp    $0x2e,%r12b
  jne    L139
  xchg   %ax,%ax
L131:
  lea    0x1(%rbx,%r13,1),%rbx
  nopl   (%rax)
L148:
  xor    %eax,%eax
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <getch@plt>
  movsbl %al,%edi
  mov    %dil,-0x1(%rbx)
  mov    %edi,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L148
  mov    D2(%rip),%rax
  movb   $0x0,0x0(%rbp)
  cmp    %r12b,(%rax)
  jne    L93
L113:
  add    $0x8,%rsp
  mov    $0x30,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  xor    %eax,%eax
  call   <getch@plt>
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L10
  call   <ungetch@plt>
  mov    %ebp,%r12d
  movb   $0x2d,(%rbx)
  jmp    L96
L7:
  xor    %r13d,%r13d
  jmp    L131
L10:
  call   <ungetch@plt>
  jmp    L35
```

assistant: ```c
char getop(char str[]) {
  int i;
  char ch;
  while ((str[0] = ch = getch()) == ' ' || ch == '\t')
    ;
  if (!isdigit(ch) && ch != '.' && ch != '-') {
    return ch;
  }
  i = 0;
  if (ch == '-') {
    if (isdigit(ch = getch())) {
      ungetch(ch);
      str[0] = '-';
    } else {
      ungetch(ch);
      return '-';
    }
  }
  if (isdigit(ch) && ch != '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  if (ch == '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  str[i] = '\0';
  if (ch != EOF) {
    ungetch(ch);
  }
  return '0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L179:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,0x0(%r13)
  mov    %eax,%r12d
  cmp    $0x20,%al
  je     L179
  cmp    $0x9,%al
  je     L179
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L165
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%al
  ja     L141
L165:
  cmp    $0x2d,%r12b
  je     L3
L134:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L44
  mov    %r13,%rbp
  xor    %r14d,%r14d
  cmp    $0x2e,%r12b
  je     L97
L32:
  mov    D0(%rip),%rax
  movb   $0x0,0x0(%rbp)
  cmp    %r12b,(%rax)
  je     L22
L62:
  movsbl %r12b,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
L141:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L44:
  cmp    $0x2e,%r12b
  je     L139
  mov    %r13d,%r15d
  lea    0x1(%r13),%rbx
  neg    %r15d
  nopl   0x0(%rax)
L148:
  xor    %eax,%eax
  lea    (%r15,%rbx,1),%r14d
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <getch@plt>
  movsbl %al,%edi
  mov    %dil,-0x1(%rbx)
  mov    %edi,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L148
  cmp    $0x2e,%r12b
  jne    L32
  nopl   0x0(%rax)
L97:
  movslq %r14d,%r14
  lea    0x1(%r13,%r14,1),%rbx
  nopl   0x0(%rax,%rax,1)
L153:
  xor    %eax,%eax
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <getch@plt>
  movsbl %al,%edi
  mov    %dil,-0x1(%rbx)
  mov    %edi,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L153
  mov    D0(%rip),%rax
  movb   $0x0,0x0(%rbp)
  cmp    %r12b,(%rax)
  jne    L62
L22:
  mov    $0x30,%r12d
  jmp    L141
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  call   <getch@plt>
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L163
  call   <ungetch@plt>
  mov    %ebp,%r12d
  movb   $0x2d,0x0(%r13)
  jmp    L134
L139:
  xor    %r14d,%r14d
  jmp    L97
L163:
  call   <ungetch@plt>
  jmp    L141
```

assistant: ```c
char getop(char str[]) {
  int i;
  char ch;
  while ((str[0] = ch = getch()) == ' ' || ch == '\t')
    ;
  if (!isdigit(ch) && ch != '.' && ch != '-') {
    return ch;
  }
  i = 0;
  if (ch == '-') {
    if (isdigit(ch = getch())) {
      ungetch(ch);
      str[0] = '-';
    } else {
      ungetch(ch);
      return '-';
    }
  }
  if (isdigit(ch) && ch != '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  if (ch == '.') {
    while (isdigit(str[++i] = ch = getch()))
      ;
  }
  str[i] = '\0';
  if (ch != EOF) {
    ungetch(ch);
  }
  return '0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mypower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0x1,%eax
  jmp    L12
L5:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mypower>
  imul   -0x4(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int mypower(int x, int y) {
  if (y == 0) {
    return 1;
  }
  return (x * mypower(x, y - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mypower>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L1
  ret
L1:
  push   %rbx
  mov    %edi,%ebx
  sub    $0x1,%esi
  call   <mypower>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int mypower(int x, int y) {
  if (y == 0) {
    return 1;
  }
  return (x * mypower(x, y - 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mypower>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L10
  nopl   (%rax)
L0:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L0
L10:
  ret
```

assistant: ```c
int mypower(int x, int y) {
  if (y == 0) {
    return 1;
  }
  return (x * mypower(x, y - 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mypower>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L15
  nopl   (%rax)
L17:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L17
L15:
  ret
```

assistant: ```c
int mypower(int x, int y) {
  if (y == 0) {
    return 1;
  }
  return (x * mypower(x, y - 1));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <tool_main@plt>
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  static char *argv[4] = {"mkg3states", "-c", "const", "tif_fax3sm.c"};
  return tool_main(4, argv);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  mov    $0x4,%edi
  call   <tool_main@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  static char *argv[4] = {"mkg3states", "-c", "const", "tif_fax3sm.c"};
  return tool_main(4, argv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  lea    D6(%rip),%rsi
  mov    $0x4,%edi
  jmp    1050 <tool_main@plt>
```

assistant: ```c
int main() {
  static char *argv[4] = {"mkg3states", "-c", "const", "tif_fax3sm.c"};
  return tool_main(4, argv);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  lea    D4(%rip),%rsi
  mov    $0x4,%edi
  jmp    1050 <tool_main@plt>
```

assistant: ```c
int main() {
  static char *argv[4] = {"mkg3states", "-c", "const", "tif_fax3sm.c"};
  return tool_main(4, argv);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SAVE_EA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x89,%edi
  call   <addbyte@plt>
  mov    $0x44,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  call   <addbyte@plt>
  mov    $0xc,%edi
  call   <addbyte@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SAVE_EA() {
  addbyte(0x89);
  addbyte(0x44);
  addbyte(0x24);
  addbyte(12);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SAVE_EA>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x89,%edi
  call   <addbyte@plt>
  mov    $0x44,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  call   <addbyte@plt>
  mov    $0xc,%edi
  call   <addbyte@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void SAVE_EA() {
  addbyte(0x89);
  addbyte(0x44);
  addbyte(0x24);
  addbyte(12);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SAVE_EA>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x89,%edi
  call   <addbyte@plt>
  mov    $0x44,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  call   <addbyte@plt>
  mov    $0xc,%edi
  add    $0x8,%rsp
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void SAVE_EA() {
  addbyte(0x89);
  addbyte(0x44);
  addbyte(0x24);
  addbyte(12);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<next_word>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r14
  call   <skip_whitespace@plt>
  mov    %rbp,%rdi
  call   <peek_char@plt>
  mov    %eax,%r13d
  cmp    $0x29,%eax
  jg     L132
  cmp    $0x27,%eax
  jg     L18
  test   %eax,%eax
  jne    L47
L99:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L132:
  cmp    $0x7b,%eax
  je     L18
  jle    L28
  cmp    $0x7d,%eax
  je     L18
L47:
  mov    %rbp,%rdi
  call   <next_char@plt>
  lea    0x1(%r12),%rbx
  mov    %r13b,(%r12)
  lea    -0x1(%r14),%rax
  cmp    $0x1,%rax
  jbe    L72
  add    %rax,%r12
  jmp    L49
L28:
  cmp    $0x2c,%eax
  je     L18
  cmp    $0x3b,%eax
  jne    L47
L18:
  mov    %rbp,%rdi
  call   <next_char@plt>
  mov    %r13d,%ecx
  lea    D6(%rip),%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    $0x1,%r13d
  jmp    L99
L135:
  mov    %rbp,%rdi
  call   <next_char@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%r12
  je     L160
L49:
  mov    %rbp,%rdi
  call   <peek_char@plt>
  test   %eax,%eax
  je     L72
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  setbe  %dl
  cmp    $0x5f,%eax
  sete   %cl
  or     %cl,%dl
  jne    L135
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%eax
  jbe    L135
L72:
  movb   $0x0,(%rbx)
  mov    $0x1,%r13d
  jmp    L99
L160:
  mov    %r12,%rbx
  jmp    L72
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: %c

assistant: ```c
int next_word(struct stream *s, char *buffer, size_t size) {
  skip_whitespace(s);
  int ch = peek_char(s);
  switch (ch) {
  case '(':
  case ')':
  case '{':
  case '}':
  case ';':
  case ',':
    next_char(s);
    snprintf(buffer, size, "%c", ch);
    return 1;
  case 0:
    return 0;
  }
  next_char(s);
  *(buffer++) = ch;
  size--;
  while ((size > 1) && (ch = peek_char(s))) {
    int num = ch >= '0' && ch <= '9';
    int lowal = ch >= 'a' && ch <= 'z';
    int upal = ch >= 'A' && ch <= 'Z';
    int under = ch == '_';
    if (!num && !lowal && !upal && !under)
      break;
    *(buffer++) = next_char(s);
    size--;
  }
  *(buffer++) = '\0';
  size--;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<next_word>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <skip_whitespace@plt>
  mov    %rbp,%rdi
  call   <peek_char@plt>
  mov    %eax,%r12d
  cmp    $0x29,%eax
  jg     L43
  cmp    $0x27,%eax
  jg     L84
  test   %eax,%eax
  jne    L114
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  cmp    $0x7b,%eax
  je     L84
  jle    L52
  cmp    $0x7d,%eax
  je     L84
L114:
  mov    %rbp,%rdi
  lea    0x1(%r13),%rbx
  call   <next_char@plt>
  lea    -0x1(%r14),%rax
  mov    %r12b,0x0(%r13)
  cmp    $0x1,%rax
  jbe    L30
  add    %rax,%r13
  jmp    L17
  nop
L57:
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  setbe  %dl
  cmp    $0x5f,%eax
  sete   %cl
  or     %cl,%dl
  jne    L129
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%eax
  ja     L30
L129:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <next_char@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%r13
  je     L30
L17:
  mov    %rbp,%rdi
  call   <peek_char@plt>
  test   %eax,%eax
  jne    L57
L30:
  mov    $0x1,%r12d
  movb   $0x0,(%rbx)
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  cmp    $0x2c,%eax
  je     L84
  cmp    $0x3b,%eax
  jne    L114
L84:
  mov    %rbp,%rdi
  call   <next_char@plt>
  mov    %r12d,%ecx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x1,%r12d
  lea    D0(%rip),%rdx
  call   <snprintf@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: %c

assistant: ```c
int next_word(struct stream *s, char *buffer, size_t size) {
  skip_whitespace(s);
  int ch = peek_char(s);
  switch (ch) {
  case '(':
  case ')':
  case '{':
  case '}':
  case ';':
  case ',':
    next_char(s);
    snprintf(buffer, size, "%c", ch);
    return 1;
  case 0:
    return 0;
  }
  next_char(s);
  *(buffer++) = ch;
  size--;
  while ((size > 1) && (ch = peek_char(s))) {
    int num = ch >= '0' && ch <= '9';
    int lowal = ch >= 'a' && ch <= 'z';
    int upal = ch >= 'A' && ch <= 'Z';
    int under = ch == '_';
    if (!num && !lowal && !upal && !under)
      break;
    *(buffer++) = next_char(s);
    size--;
  }
  *(buffer++) = '\0';
  size--;
  return 1;
}
```