ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0xc0(%rsp),%rbx
  lea    0x60(%rsp),%rbp
  mov    %rsp,%r12
  jmp    L3
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sort@plt>
L3:
  mov    %rbx,%rdi
  call   <read_input@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x4,%eax
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D6: Smallest word: %s


tool: D0: Largest word: %s


assistant: ```c
int main(void) {
  char smallest[81];
  char largest[81];
  char str[81];
  while (true) {
    read_input(str);
    if (strlen(str) == 4) {
      break;
    }
    sort(str, smallest, largest);
  }
  printf("\n");
  printf("Smallest word: %s\n", smallest);
  printf("Largest word: %s\n", largest);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0xc0(%rsp),%rbx
  lea    0x60(%rsp),%rbp
  mov    %rsp,%r12
  jmp    L28
  nopl   0x0(%rax)
L14:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sort@plt>
L28:
  mov    %rbx,%rdi
  call   <read_input@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x4,%eax
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string

tool: D12: Smallest word: %s


tool: D10: Largest word: %s


assistant: ```c
int main(void) {
  char smallest[81];
  char largest[81];
  char str[81];
  while (true) {
    read_input(str);
    if (strlen(str) == 4) {
      break;
    }
    sort(str, smallest, largest);
  }
  printf("\n");
  printf("Smallest word: %s\n", smallest);
  printf("Largest word: %s\n", largest);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<puke>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void puke(const char *message) {
  perror(message);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<puke>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void puke(const char *message) {
  perror(message);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<puke>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void puke(const char *message) {
  perror(message);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<puke>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void puke(const char *message) {
  perror(message);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xa4(%rbp)
  mov    -0xa4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xa8(%rbp)
  jmp    L28
L2:
  mov    -0xa8(%rbp),%eax
  cltq
  movzbl -0xa0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0xa8(%rbp)
L28:
  cmpl   $0x0,-0xa8(%rbp)
  jns    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string

tool: D12: %[^
]s

tool: D11: %c

assistant: ```c
int main() {
  char str[140];
  int l, j;
  scanf("%[^\n]s", str);
  l = strlen(str);
  for (j = l - 1; j >= 0; j--) {
    printf("%c", str[j]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L24
  movslq %eax,%rbx
  lea    D4(%rip),%rbp
L6:
  movsbl (%rsp,%rbx,1),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L6
L24:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_guessed: string
name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D13: %[^
]s

tool: D4: %c

assistant: ```c
int main() {
  char str[140];
  int l, j;
  scanf("%[^\n]s", str);
  l = strlen(str);
  for (j = l - 1; j >= 0; j--) {
    printf("%c", str[j]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L24
  movslq %eax,%rbx
  lea    D1(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L1:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  sub    $0x1,%rbx
  call   <printf@plt>
  test   %ebx,%ebx
  jns    L1
L24:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string
name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D5: %[^
]s

tool: D1: %c

assistant: ```c
int main() {
  char str[140];
  int l, j;
  scanf("%[^\n]s", str);
  l = strlen(str);
  for (j = l - 1; j >= 0; j--) {
    printf("%c", str[j]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L16
  movslq %eax,%rbx
  lea    D3(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L12:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  sub    $0x1,%rbx
  call   <printf@plt>
  test   %ebx,%ebx
  jns    L12
L16:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D7: %[^
]s

tool: D3: %c

assistant: ```c
int main() {
  char str[140];
  int l, j;
  scanf("%[^\n]s", str);
  l = strlen(str);
  for (j = l - 1; j >= 0; j--) {
    printf("%c", str[j]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<u8_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x200,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <alloca@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x4c(%rbp),%ecx
  mov    -0x48(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jns    L47
  mov    $0x0,%eax
  jmp    L29
L47:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L25
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  movq   $0x1,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x4c(%rbp),%ecx
  mov    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
L25:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x20(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <u8_toucs@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpq   $0x0,-0x38(%rbp)
  je     L4
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L4:
  mov    -0x10(%rbp),%rax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: %ls

assistant: ```c
size_t u8_vprintf(const char *fmt, va_list ap) {
  size_t cnt, sz = 0, nc, needfree = 0;
  char *buf;
  uint32_t *wcs;
  sz = 512;
  buf = (char *)alloca(sz);
  cnt = vsnprintf(buf, sz, fmt, ap);
  if ((intptr_t)cnt < 0)
    return 0;
  if (cnt >= sz) {
    buf = (char *)malloc(cnt + 1);
    needfree = 1;
    vsnprintf(buf, cnt + 1, fmt, ap);
  }
  wcs = (uint32_t *)alloca((cnt + 1) * sizeof(uint32_t));
  nc = u8_toucs(wcs, cnt + 1, buf, cnt);
  wcs[nc] = 0;
  printf("%ls", (wchar_t *)wcs);
  if (needfree)
    free(buf);
  return nc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<u8_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x200,%edi
  call   <alloca@plt>
  mov    %rax,%r13
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  js     L18
  mov    %rax,%rbx
  cmp    $0x1ff,%rax
  ja     L8
  lea    0x1(%rax),%r12
  lea    0x0(,%r12,8),%rdi
  call   <alloca@plt>
  mov    %rax,%r14
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <u8_toucs@plt>
  mov    %rax,%r12
  movq   $0x0,(%r14,%rax,8)
  mov    %r14,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
L18:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %r12,%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L8:
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  lea    0x0(,%r12,8),%rdi
  call   <alloca@plt>
  mov    %rax,%r14
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <u8_toucs@plt>
  mov    %rax,%r12
  movq   $0x0,(%r14,%rax,8)
  mov    %r14,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L18
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type_guessed: string

tool: D12: %ls

assistant: ```c
size_t u8_vprintf(const char *fmt, va_list ap) {
  size_t cnt, sz = 0, nc, needfree = 0;
  char *buf;
  uint32_t *wcs;
  sz = 512;
  buf = (char *)alloca(sz);
  cnt = vsnprintf(buf, sz, fmt, ap);
  if ((intptr_t)cnt < 0)
    return 0;
  if (cnt >= sz) {
    buf = (char *)malloc(cnt + 1);
    needfree = 1;
    vsnprintf(buf, cnt + 1, fmt, ap);
  }
  wcs = (uint32_t *)alloca((cnt + 1) * sizeof(uint32_t));
  nc = u8_toucs(wcs, cnt + 1, buf, cnt);
  wcs[nc] = 0;
  printf("%ls", (wchar_t *)wcs);
  if (needfree)
    free(buf);
  return nc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<u8_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %rdi,%r14
  mov    $0x200,%edi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <vsnprintf@plt>
  test   %rax,%rax
  js     L31
  lea    0x1(%rax),%r13
  mov    %rax,%r12
  lea    0x0(,%r13,8),%r8
  cmp    $0x1ff,%rax
  ja     L1
  mov    %r8,%rdi
  call   <alloca@plt>
  mov    %r13,%rsi
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <u8_toucs@plt>
  mov    %r14,%rsi
  lea    D7(%rip),%rdi
  movq   $0x0,(%r14,%rax,8)
  mov    %rax,%r13
  call   <printf@plt>
L31:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  lea    -0x28(%rbp),%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L1:
  mov    %r13,%rdi
  mov    %r8,-0x48(%rbp)
  call   <malloc@plt>
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <vsnprintf@plt>
  mov    -0x48(%rbp),%rdi
  call   <alloca@plt>
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <u8_toucs@plt>
  mov    %r14,%rsi
  lea    D7(%rip),%rdi
  movq   $0x0,(%r14,%rax,8)
  mov    %rax,%r13
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L31
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: %ls

assistant: ```c
size_t u8_vprintf(const char *fmt, va_list ap) {
  size_t cnt, sz = 0, nc, needfree = 0;
  char *buf;
  uint32_t *wcs;
  sz = 512;
  buf = (char *)alloca(sz);
  cnt = vsnprintf(buf, sz, fmt, ap);
  if ((intptr_t)cnt < 0)
    return 0;
  if (cnt >= sz) {
    buf = (char *)malloc(cnt + 1);
    needfree = 1;
    vsnprintf(buf, cnt + 1, fmt, ap);
  }
  wcs = (uint32_t *)alloca((cnt + 1) * sizeof(uint32_t));
  nc = u8_toucs(wcs, cnt + 1, buf, cnt);
  wcs[nc] = 0;
  printf("%ls", (wchar_t *)wcs);
  if (needfree)
    free(buf);
  return nc;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<u8_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %rdi,%r14
  mov    $0x200,%edi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <vsnprintf@plt>
  test   %rax,%rax
  js     L32
  lea    0x1(%rax),%r13
  mov    %rax,%r12
  lea    0x0(,%r13,8),%r8
  cmp    $0x1ff,%rax
  ja     L4
  mov    %r8,%rdi
  call   <alloca@plt>
  mov    %r13,%rsi
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <u8_toucs@plt>
  mov    %r14,%rsi
  lea    D18(%rip),%rdi
  movq   $0x0,(%r14,%rax,8)
  mov    %rax,%r13
  call   <printf@plt>
L32:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  lea    -0x28(%rbp),%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L4:
  mov    %r13,%rdi
  mov    %r8,-0x48(%rbp)
  call   <malloc@plt>
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <vsnprintf@plt>
  mov    -0x48(%rbp),%rdi
  call   <alloca@plt>
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <u8_toucs@plt>
  mov    %r14,%rsi
  lea    D18(%rip),%rdi
  movq   $0x0,(%r14,%rax,8)
  mov    %rax,%r13
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L32
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_guessed: string

tool: D18: %ls

assistant: ```c
size_t u8_vprintf(const char *fmt, va_list ap) {
  size_t cnt, sz = 0, nc, needfree = 0;
  char *buf;
  uint32_t *wcs;
  sz = 512;
  buf = (char *)alloca(sz);
  cnt = vsnprintf(buf, sz, fmt, ap);
  if ((intptr_t)cnt < 0)
    return 0;
  if (cnt >= sz) {
    buf = (char *)malloc(cnt + 1);
    needfree = 1;
    vsnprintf(buf, cnt + 1, fmt, ap);
  }
  wcs = (uint32_t *)alloca((cnt + 1) * sizeof(uint32_t));
  nc = u8_toucs(wcs, cnt + 1, buf, cnt);
  wcs[nc] = 0;
  printf("%ls", (wchar_t *)wcs);
  if (needfree)
    free(buf);
  return nc;
}
```
user: What is the c source code of the assembly code below?

```asm
<DivCheck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %rdi,-0x7e8(%rbp)
  mov    %rsi,-0x7f0(%rbp)
  mov    %rdx,-0x7f8(%rbp)
  mov    %rcx,-0x800(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Copy@plt>
  mov    -0x7f8(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <LongMul@plt>
  mov    -0x800(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Add@plt>
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7e8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Compare@plt>
  test   %rax,%rax
  jne    L19
  mov    $0x1,%eax
  jmp    L20
L19:
  mov    $0x0,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int DivCheck(unsigned a[], unsigned b[], unsigned quot[], unsigned res[]) {
  unsigned c[500];
  Copy(b, c);
  LongMul(c, quot);
  Add(c, res);
  if (Compare(a, c) == 0)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DivCheck>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <Copy@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <LongMul@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <Add@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <Compare@plt>
  test   %rax,%rax
  sete   %al
  mov    0x7d8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int DivCheck(unsigned a[], unsigned b[], unsigned quot[], unsigned res[]) {
  unsigned c[500];
  Copy(b, c);
  LongMul(c, quot);
  Add(c, res);
  if (Compare(a, c) == 0)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<DivCheck>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <Copy@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <LongMul@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <Add@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <Compare@plt>
  test   %rax,%rax
  sete   %al
  mov    0x7d8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x7e8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int DivCheck(unsigned a[], unsigned b[], unsigned quot[], unsigned res[]) {
  unsigned c[500];
  Copy(b, c);
  LongMul(c, quot);
  Add(c, res);
  if (Compare(a, c) == 0)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DivCheck>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <Copy@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <LongMul@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <Add@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <Compare@plt>
  test   %rax,%rax
  sete   %al
  mov    0x7d8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x7e8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int DivCheck(unsigned a[], unsigned b[], unsigned quot[], unsigned res[]) {
  unsigned c[500];
  Copy(b, c);
  LongMul(c, quot);
  Add(c, res);
  if (Compare(a, c) == 0)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D18(%rip),%rax
  movq   %rax,%xmm0
  call   <squareRoot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D38(%rip),%rax
  movq   %rax,%xmm0
  call   <squareRoot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D19(%rip),%rax
  movq   %rax,%xmm0
  call   <squareRoot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
data_type: f64
name: unpack_data
arguments: data_label: D49
data_type: string
name: unpack_data
arguments: data_label: D38
data_type: f64
name: unpack_data
arguments: data_label: D30
data_type: string
name: unpack_data
arguments: data_label: D19
data_type: f64
name: unpack_data
arguments: data_label: D5
data_type: string

tool: D18: 2

tool: D49: squareRoot (2.0) = %f


tool: D38: 144

tool: D30: squareRoot (144.0) = %f


tool: D19: 17.5

tool: D5: squareRoot (17.5) = %f


assistant: ```c
int main(void) {
  printf("squareRoot (2.0) = %f\n", squareRoot(2.0));
  printf("squareRoot (144.0) = %f\n", squareRoot(144.0));
  printf("squareRoot (17.5) = %f\n", squareRoot(17.5));
  return 0;
}
```