ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<strcatc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rax,%rdx
  movzbl -0xc(%rbp),%eax
  mov    %al,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void strcatc(char *str, char c) {
  str[strlen(str) + 1] = 0;
  str[strlen(str)] = c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcatc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  movb   $0x0,0x1(%rbx,%rax,1)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %bpl,(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strcatc(char *str, char c) {
  str[strlen(str) + 1] = 0;
  str[strlen(str)] = c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcatc>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  movb   $0x0,0x1(%rbx,%rax,1)
  call   <strlen@plt>
  mov    %bpl,(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strcatc(char *str, char c) {
  str[strlen(str) + 1] = 0;
  str[strlen(str)] = c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcatc>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  movb   $0x0,0x1(%rbx,%rax,1)
  call   <strlen@plt>
  mov    %bpl,(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strcatc(char *str, char c) {
  str[strlen(str) + 1] = 0;
  str[strlen(str)] = c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_uart_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x90000002,%eax
  movb   $0xc7,(%rax)
  mov    $0x90000001,%eax
  movb   $0x0,(%rax)
  mov    $0x90000003,%eax
  movb   $0x3,(%rax)
  movl   $0xd,-0x4(%rbp)
  mov    $0x90000003,%eax
  movzbl (%rax),%edx
  mov    $0x90000003,%eax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  mov    $0x90000000,%eax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    $0x90000001,%eax
  mov    %dl,(%rax)
  mov    $0x90000003,%eax
  movzbl (%rax),%edx
  mov    $0x90000003,%eax
  and    $0x7f,%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _uart_init() {
  int divisor;
  *((volatile unsigned char *)(0x90000000 + 2)) = 0x01 | 0x02 | 0x04 | 0xC0;
  *((volatile unsigned char *)(0x90000000 + 1)) = 0x00;
  *((volatile unsigned char *)(0x90000000 + 3)) = 0x03 & ~(0x04 | 0x08);
  divisor = 25000000 / (16 * 115200);
  *((volatile unsigned char *)(0x90000000 + 3)) |= 0x80;
  *((volatile unsigned char *)(0x90000000 + 0)) = divisor & 0x000000ff;
  *((volatile unsigned char *)(0x90000000 + 1)) = (divisor >> 8) & 0x000000ff;
  *((volatile unsigned char *)(0x90000000 + 3)) &= ~(0x80);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_uart_init>:
  endbr64
  mov    $0x90000002,%eax
  movb   $0xc7,(%rax)
  mov    $0x90000001,%ecx
  movb   $0x0,(%rcx)
  lea    0x1(%rax),%rax
  movb   $0x3,(%rax)
  movzbl (%rax),%edx
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  mov    $0x90000000,%esi
  movb   $0xd,(%rsi)
  movb   $0x0,(%rcx)
  movzbl (%rax),%edx
  and    $0x7f,%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void _uart_init() {
  int divisor;
  *((volatile unsigned char *)(0x90000000 + 2)) = 0x01 | 0x02 | 0x04 | 0xC0;
  *((volatile unsigned char *)(0x90000000 + 1)) = 0x00;
  *((volatile unsigned char *)(0x90000000 + 3)) = 0x03 & ~(0x04 | 0x08);
  divisor = 25000000 / (16 * 115200);
  *((volatile unsigned char *)(0x90000000 + 3)) |= 0x80;
  *((volatile unsigned char *)(0x90000000 + 0)) = divisor & 0x000000ff;
  *((volatile unsigned char *)(0x90000000 + 1)) = (divisor >> 8) & 0x000000ff;
  *((volatile unsigned char *)(0x90000000 + 3)) &= ~(0x80);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_uart_init>:
  endbr64
  mov    $0x90000002,%eax
  mov    $0x90000001,%ecx
  mov    $0x90000000,%esi
  movb   $0xc7,(%rax)
  movb   $0x0,(%rcx)
  movb   $0x3,0x1(%rax)
  movzbl 0x1(%rax),%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rax)
  movb   $0xd,(%rsi)
  movb   $0x0,(%rcx)
  movzbl 0x1(%rax),%edx
  and    $0x7f,%edx
  mov    %dl,0x1(%rax)
  ret
```

assistant: ```c
void _uart_init() {
  int divisor;
  *((volatile unsigned char *)(0x90000000 + 2)) = 0x01 | 0x02 | 0x04 | 0xC0;
  *((volatile unsigned char *)(0x90000000 + 1)) = 0x00;
  *((volatile unsigned char *)(0x90000000 + 3)) = 0x03 & ~(0x04 | 0x08);
  divisor = 25000000 / (16 * 115200);
  *((volatile unsigned char *)(0x90000000 + 3)) |= 0x80;
  *((volatile unsigned char *)(0x90000000 + 0)) = divisor & 0x000000ff;
  *((volatile unsigned char *)(0x90000000 + 1)) = (divisor >> 8) & 0x000000ff;
  *((volatile unsigned char *)(0x90000000 + 3)) &= ~(0x80);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_uart_init>:
  endbr64
  mov    $0x90000002,%eax
  mov    $0x90000001,%ecx
  mov    $0x90000000,%esi
  movb   $0xc7,(%rax)
  movb   $0x0,(%rcx)
  movb   $0x3,0x1(%rax)
  movzbl 0x1(%rax),%edx
  or     $0xffffff80,%edx
  mov    %dl,0x1(%rax)
  movb   $0xd,(%rsi)
  movb   $0x0,(%rcx)
  movzbl 0x1(%rax),%edx
  and    $0x7f,%edx
  mov    %dl,0x1(%rax)
  ret
```

assistant: ```c
void _uart_init() {
  int divisor;
  *((volatile unsigned char *)(0x90000000 + 2)) = 0x01 | 0x02 | 0x04 | 0xC0;
  *((volatile unsigned char *)(0x90000000 + 1)) = 0x00;
  *((volatile unsigned char *)(0x90000000 + 3)) = 0x03 & ~(0x04 | 0x08);
  divisor = 25000000 / (16 * 115200);
  *((volatile unsigned char *)(0x90000000 + 3)) |= 0x80;
  *((volatile unsigned char *)(0x90000000 + 0)) = divisor & 0x000000ff;
  *((volatile unsigned char *)(0x90000000 + 1)) = (divisor >> 8) & 0x000000ff;
  *((volatile unsigned char *)(0x90000000 + 3)) &= ~(0x80);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jsendh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <jsock@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <jsend@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void jsendh(const char *jcommand, const char *jhost, int jport) {
  int sock = jsock(jhost, jport);
  jsend(jcommand, sock);
  close(sock);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jsendh>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %edx,%esi
  call   <jsock@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <jsend@plt>
  mov    %ebx,%edi
  call   <close@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void jsendh(const char *jcommand, const char *jhost, int jport) {
  int sock = jsock(jhost, jport);
  jsend(jcommand, sock);
  close(sock);
}
```
user: Translate the below assembly code into C programming language:

```asm
<jsendh>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %edx,%esi
  push   %rbp
  sub    $0x8,%rsp
  call   <jsock@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <jsend@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <close@plt>
```

assistant: ```c
void jsendh(const char *jcommand, const char *jhost, int jport) {
  int sock = jsock(jhost, jport);
  jsend(jcommand, sock);
  close(sock);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jsendh>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %edx,%esi
  push   %rbp
  sub    $0x8,%rsp
  call   <jsock@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <jsend@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <close@plt>
```

assistant: ```c
void jsendh(const char *jcommand, const char *jhost, int jport) {
  int sock = jsock(jhost, jport);
  jsend(jcommand, sock);
  close(sock);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipermute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <fatalx@plt>
L19:
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copyiarr@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L4
L20:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L20
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: Unable to allocate %d unit(s) for item 


assistant: ```c
void ipermute(int *a, int *ind, int len) {
  int i, k;
  int *rrr;
  if ((rrr = (int *)calloc((len), sizeof(int))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  copyiarr(a, rrr, len);
  for (i = 0; i < len; i++) {
    k = ind[i];
    a[i] = rrr[k];
  }
  free(rrr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ipermute>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    $0x4,%esi
  mov    %edx,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L4
L32:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <copyiarr@plt>
  test   %ebx,%ebx
  jle    L35
  mov    %ebx,%edx
  mov    $0x0,%eax
L13:
  movslq (%r12,%rax,4),%rcx
  mov    0x0(%r13,%rcx,4),%ecx
  mov    %ecx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L13
L35:
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <fatalx@plt>
  jmp    L32
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: Unable to allocate %d unit(s) for item 


assistant: ```c
void ipermute(int *a, int *ind, int len) {
  int i, k;
  int *rrr;
  if ((rrr = (int *)calloc((len), sizeof(int))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  copyiarr(a, rrr, len);
  for (i = 0; i < len; i++) {
    k = ind[i];
    a[i] = rrr[k];
  }
  free(rrr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipermute>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x4,%esi
  push   %r12
  mov    %rdi,%r12
  mov    %edx,%edi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L32
L17:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <copyiarr@plt>
  test   %ebx,%ebx
  jle    L25
  movslq %ebx,%rdx
  xor    %eax,%eax
L26:
  movslq 0x0(%r13,%rax,4),%rcx
  mov    0x0(%rbp,%rcx,4),%ecx
  mov    %ecx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L26
L25:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <fatalx@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: D8: Unable to allocate %d unit(s) for item 


assistant: ```c
void ipermute(int *a, int *ind, int len) {
  int i, k;
  int *rrr;
  if ((rrr = (int *)calloc((len), sizeof(int))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  copyiarr(a, rrr, len);
  for (i = 0; i < len; i++) {
    k = ind[i];
    a[i] = rrr[k];
  }
  free(rrr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ipermute>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x4,%esi
  push   %r12
  mov    %rdi,%r12
  mov    %edx,%edi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L25
L15:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <copyiarr@plt>
  test   %ebx,%ebx
  jle    L17
  movslq %ebx,%rdx
  xor    %eax,%eax
L1:
  movslq 0x0(%r13,%rax,4),%rcx
  mov    0x0(%rbp,%rcx,4),%ecx
  mov    %ecx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L1
L17:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  call   <fatalx@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D3: Unable to allocate %d unit(s) for item 


assistant: ```c
void ipermute(int *a, int *ind, int len) {
  int i, k;
  int *rrr;
  if ((rrr = (int *)calloc((len), sizeof(int))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  copyiarr(a, rrr, len);
  for (i = 0; i < len; i++) {
    k = ind[i];
    a[i] = rrr[k];
  }
  free(rrr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x5,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <hello_world@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: calling sub


assistant: ```c
int main() {
  int a;
  int b;
  int c;
  a = 1;
  b = a + 5;
  c = a + b;
  printf("calling sub\n");
  hello_world();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <hello_world@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: calling sub


assistant: ```c
int main() {
  int a;
  int b;
  int c;
  a = 1;
  b = a + 5;
  c = a + b;
  printf("calling sub\n");
  hello_world();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <hello_world@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: calling sub


assistant: ```c
int main() {
  int a;
  int b;
  int c;
  a = 1;
  b = a + 5;
  c = a + b;
  printf("calling sub\n");
  hello_world();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <hello_world@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: calling sub


assistant: ```c
int main() {
  int a;
  int b;
  int c;
  a = 1;
  b = a + 5;
  c = a + b;
  printf("calling sub\n");
  hello_world();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__dpl_malloc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *__attribute__((malloc)) __dpl_malloc32(int32_t n) {
  void *ptr;
  int32_t *p = NULL;
  ptr = malloc(sizeof(int32_t) * (n + 1));
  if (ptr) {
    p = (int32_t *)ptr;
    p[0] = n;
    p++;
  } else {
  }
  return (void *)p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__dpl_malloc32>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x4(,%rdi,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
  mov    %ebx,(%rax)
  add    $0x4,%rax
L1:
  pop    %rbx
  ret
```

assistant: ```c
void *__attribute__((malloc)) __dpl_malloc32(int32_t n) {
  void *ptr;
  int32_t *p = NULL;
  ptr = malloc(sizeof(int32_t) * (n + 1));
  if (ptr) {
    p = (int32_t *)ptr;
    p[0] = n;
    p++;
  } else {
  }
  return (void *)p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__dpl_malloc32>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x4(,%rdi,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  mov    %ebx,(%rax)
  add    $0x4,%rax
L8:
  pop    %rbx
  ret
```

assistant: ```c
void *__attribute__((malloc)) __dpl_malloc32(int32_t n) {
  void *ptr;
  int32_t *p = NULL;
  ptr = malloc(sizeof(int32_t) * (n + 1));
  if (ptr) {
    p = (int32_t *)ptr;
    p[0] = n;
    p++;
  } else {
  }
  return (void *)p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__dpl_malloc32>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x4(,%rdi,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L3
  mov    %ebx,(%rax)
  add    $0x4,%rax
L3:
  pop    %rbx
  ret
```

assistant: ```c
void *__attribute__((malloc)) __dpl_malloc32(int32_t n) {
  void *ptr;
  int32_t *p = NULL;
  ptr = malloc(sizeof(int32_t) * (n + 1));
  if (ptr) {
    p = (int32_t *)ptr;
    p[0] = n;
    p++;
  } else {
  }
  return (void *)p;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffffb38cf9b1,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x8,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffffb38cf9b1,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x8,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x16d,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffffb38cf9b1,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x8,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x16d,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0x1e,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D2
datatype: string
name: unpack_data
arguments: label: D20
datatype: string
name: unpack_data
arguments: label: D15
datatype: string

tool: D11: %d

tool: D2: %d ano(s)


tool: D20: %d mes(es)


tool: D15: %d dia(s)


assistant: ```c
int main() {
  int day, month, year, days;
  scanf("%d", &day);
  year = day / 365;
  month = (day % 365) / 30;
  days = (day % 365) % 30;
  printf("%d ano(s)\n", year);
  printf("%d mes(es)\n", month);
  printf("%d dia(s)\n", days);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rsi
  imul   $0xffffffffb38cf9b1,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x8,%esi
  cltd
  mov    %esi,%ebp
  sub    %edx,%ebp
  imul   $0x16d,%ebp,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebp
  sub    %edx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  movslq %ebp,%rbx
  imul   $0xffffffff88888889,%rbx,%rbx
  shr    $0x20,%rbx
  add    %ebp,%ebx
  sar    $0x4,%ebx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  mov    %ebx,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  imul   $0x1e,%ebx,%ebx
  mov    %ebp,%esi
  sub    %ebx,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D35
type_guessed: string
name: unpack_data
arguments: tag: D30
type_guessed: string

tool: D5: %d

tool: D7: %d ano(s)


tool: D35: %d mes(es)


tool: D30: %d dia(s)


assistant: ```c
int main() {
  int day, month, year, days;
  scanf("%d", &day);
  year = day / 365;
  month = (day % 365) / 30;
  days = (day % 365) % 30;
  printf("%d ano(s)\n", year);
  printf("%d mes(es)\n", month);
  printf("%d dia(s)\n", days);
  return 0;
}
```