ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getProcName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb4(%rbp),%edx
  lea    -0xa0(%rbp),%rax
  mov    %edx,%ecx
  lea    D42(%rip),%rdx
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xa0(%rbp),%rax
  lea    D44(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0xa8(%rbp)
  cmpq   $0x0,-0xa8(%rbp)
  jne    L10
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L6
L28:
  lea    -0x70(%rbp),%rax
  mov    $0x5,%edx
  lea    D30(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L36
  jmp    L10
L36:
  lea    -0x70(%rbp),%rax
  add    $0x6,%rax
  mov    %rax,-0xb0(%rbp)
  jmp    L79
L34:
  addq   $0x1,-0xb0(%rbp)
L79:
  mov    -0xb0(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L34
  jmp    L7
L10:
  mov    -0xa8(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L28
L7:
  mov    -0xa8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xb0(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D42
type: string
name: unpack_data
arguments: data_tag: D57
type: string
name: unpack_data
arguments: data_tag: D44
type: string
name: unpack_data
arguments: data_tag: D3
type: string
name: unpack_data
arguments: data_tag: D30
type: string
name: unpack_data
arguments: data_tag: D17
type: string

tool: D42: /proc/%d/status

tool: D57: opening proc %s


tool: D44: r

tool: D3: not found file.

tool: D30: Name:

tool: D17: name is %s


assistant: ```c
char *getProcName(int pid) {
  char path[40], line[100], *p;
  FILE *statusf;
  snprintf(path, 40, "/proc/%d/status", pid);
  printf("opening proc %s\n", path);
  statusf = fopen(path, "r");
  if (!statusf) {
    printf("not found file.\n");
    return NULL;
  }
  while (fgets(line, 100, statusf)) {
    if (strncmp(line, "Name:", 5) != 0)
      continue;
    p = line + 6;
    while (isspace(*p))
      ++p;
    break;
  }
  fclose(statusf);
  printf("name is %s\n", p);
  return strdup(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getProcName>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %edi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D17(%rip),%rdx
  mov    $0x28,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    D31(%rip),%r12
  test   %rax,%rax
  je     L29
L23:
  lea    0x30(%rsp),%rdi
  mov    %rbp,%rdx
  mov    $0x64,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L4
  lea    0x30(%rsp),%rdi
  mov    $0x5,%edx
  mov    %r12,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L23
  lea    0x36(%rsp),%rbx
  jmp    L37
L29:
  lea    D55(%rip),%rdi
  call   <puts@plt>
  jmp    L15
L10:
  add    $0x1,%rbx
L37:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
L4:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
L15:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    %rbp,%rax
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string
name: extract_symbolic_data
arguments: data_tag: D3
type: string
name: extract_symbolic_data
arguments: data_tag: D31
type: string
name: extract_symbolic_data
arguments: data_tag: D55
type: string
name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D17: /proc/%d/status

tool: D19: opening proc %s


tool: D3: r

tool: D31: Name:

tool: D55: not found file.

tool: D2: name is %s


assistant: ```c
char *getProcName(int pid) {
  char path[40], line[100], *p;
  FILE *statusf;
  snprintf(path, 40, "/proc/%d/status", pid);
  printf("opening proc %s\n", path);
  statusf = fopen(path, "r");
  if (!statusf) {
    printf("not found file.\n");
    return NULL;
  }
  while (fgets(line, 100, statusf)) {
    if (strncmp(line, "Name:", 5) != 0)
      continue;
    p = line + 6;
    while (isspace(*p))
      ++p;
    break;
  }
  fclose(statusf);
  printf("name is %s\n", p);
  return strdup(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getProcName>:
  endbr64
  push   %r13
  mov    %edi,%ecx
  lea    D57(%rip),%rdx
  mov    $0x28,%esi
  push   %r12
  lea    D19(%rip),%r13
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x30(%rsp),%rbx
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L63
L69:
  mov    %r12,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L13
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L69
  lea    0x36(%rsp),%rbp
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L49:
  add    $0x1,%rbp
L16:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L49
L13:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
L56:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0xa8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L63:
  lea    D45(%rip),%rdi
  call   <puts@plt>
  jmp    L56
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D57
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D45
type_guessed: string

tool: D57: /proc/%d/status

tool: D19: Name:

tool: D9: opening proc %s


tool: D1: r

tool: D2: name is %s


tool: D45: not found file.

assistant: ```c
char *getProcName(int pid) {
  char path[40], line[100], *p;
  FILE *statusf;
  snprintf(path, 40, "/proc/%d/status", pid);
  printf("opening proc %s\n", path);
  statusf = fopen(path, "r");
  if (!statusf) {
    printf("not found file.\n");
    return NULL;
  }
  while (fgets(line, 100, statusf)) {
    if (strncmp(line, "Name:", 5) != 0)
      continue;
    p = line + 6;
    while (isspace(*p))
      ++p;
    break;
  }
  fclose(statusf);
  printf("name is %s\n", p);
  return strdup(p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getProcName>:
  endbr64
  push   %r13
  mov    %edi,%ecx
  lea    D37(%rip),%rdx
  mov    $0x28,%esi
  push   %r12
  lea    D49(%rip),%r13
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x30(%rsp),%rbx
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L47
L7:
  mov    %r12,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L32
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L7
  lea    0x36(%rsp),%rbp
  jmp    L30
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x1,%rbp
L30:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L11
L32:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rsi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
L49:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0xa8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  lea    D40(%rip),%rdi
  call   <puts@plt>
  jmp    L49
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D49
type_infered: string
name: read_data
arguments: data_label: D2
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D47
type_infered: string
name: read_data
arguments: data_label: D40
type_infered: string

tool: D37: /proc/%d/status

tool: D49: Name:

tool: D2: opening proc %s


tool: D3: r

tool: D47: name is %s


tool: D40: not found file.

assistant: ```c
char *getProcName(int pid) {
  char path[40], line[100], *p;
  FILE *statusf;
  snprintf(path, 40, "/proc/%d/status", pid);
  printf("opening proc %s\n", path);
  statusf = fopen(path, "r");
  if (!statusf) {
    printf("not found file.\n");
    return NULL;
  }
  while (fgets(line, 100, statusf)) {
    if (strncmp(line, "Name:", 5) != 0)
      continue;
    p = line + 6;
    while (isspace(*p))
      ++p;
    break;
  }
  fclose(statusf);
  printf("name is %s\n", p);
  return strdup(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L25
L7:
  mov    -0x20(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L33
  pxor   %xmm1,%xmm1
  cvtss2sd -0x10(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0xc(%rbp),%xmm1
  mulss  -0x10(%rbp),%xmm1
  subss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x20(%rbp)
L33:
  addl   $0x1,-0x18(%rbp)
L25:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L7
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D18
type_infered: f64

tool: D1: %d

tool: D18: 0.02

assistant: ```c
int main() {
  int n, m, c, k, i, sum = 0;
  float p = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  c = m;
  for (i = 1; i <= n; i++) {
    sum = sum + m;
    if (i % k == 0) {
      p = p + 0.02;
      m = c - c * p;
    }
  }
  printf("%d", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%r10d
  mov    0xc(%rsp),%r9d
  test   %r9d,%r9d
  jle    L25
  mov    0x14(%rsp),%edi
  add    $0x1,%r9d
  mov    %r10d,%r8d
  mov    $0x0,%r11d
  pxor   %xmm0,%xmm0
  mov    $0x0,%esi
  mov    $0x1,%ecx
  movsd  D2(%rip),%xmm3
  mov    $0x1,%ebx
  jmp    L35
L42:
  add    $0x1,%ecx
  cmp    %r9d,%ecx
  je     L34
L35:
  add    %r8d,%esi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L42
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r10d,%xmm1
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  subss  %xmm2,%xmm1
  cvttss2si %xmm1,%r8d
  mov    %ebx,%r11d
  jmp    L42
L34:
  test   %r11b,%r11b
  je     L41
  mov    %r8d,0x10(%rsp)
L41:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L25:
  mov    $0x0,%esi
  jmp    L41
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: f64

tool: D4: %d

tool: D2: 0.02

assistant: ```c
int main() {
  int n, m, c, k, i, sum = 0;
  float p = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  c = m;
  for (i = 1; i <= n; i++) {
    sum = sum + m;
    if (i % k == 0) {
      p = p + 0.02;
      m = c - c * p;
    }
  }
  printf("%d", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  mov    0x10(%rsp),%r10d
  test   %r9d,%r9d
  jle    L53
  mov    0x14(%rsp),%edi
  add    $0x1,%r9d
  mov    %r10d,%r8d
  xor    %r11d,%r11d
  movsd  D18(%rip),%xmm3
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %ecx,%eax
  add    %r8d,%esi
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L52
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm3,%xmm0
  mov    $0x1,%r11d
  cvtsi2ss %r10d,%xmm1
  cvtsd2ss %xmm0,%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  subss  %xmm2,%xmm1
  cvttss2si %xmm1,%r8d
L52:
  add    $0x1,%ecx
  cmp    %r9d,%ecx
  jne    L27
  test   %r11b,%r11b
  je     L24
  mov    %r8d,0x10(%rsp)
L24:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L53:
  xor    %esi,%esi
  jmp    L24
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: f64

tool: D1: %d

tool: D18: 0.02

assistant: ```c
int main() {
  int n, m, c, k, i, sum = 0;
  float p = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  c = m;
  for (i = 1; i <= n; i++) {
    sum = sum + m;
    if (i % k == 0) {
      p = p + 0.02;
      m = c - c * p;
    }
  }
  printf("%d", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  mov    0x10(%rsp),%r10d
  test   %r9d,%r9d
  jle    L38
  mov    0x14(%rsp),%edi
  add    $0x1,%r9d
  mov    %r10d,%r8d
  xor    %r11d,%r11d
  movsd  D13(%rip),%xmm3
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ecx,%eax
  add    %r8d,%esi
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L14
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm3,%xmm0
  mov    $0x1,%r11d
  cvtsi2ss %r10d,%xmm1
  cvtsd2ss %xmm0,%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  subss  %xmm2,%xmm1
  cvttss2si %xmm1,%r8d
L14:
  add    $0x1,%ecx
  cmp    %r9d,%ecx
  jne    L12
  test   %r11b,%r11b
  je     L13
  mov    %r8d,0x10(%rsp)
L13:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L38:
  xor    %esi,%esi
  jmp    L13
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D16
type: string
name: unpack_data
arguments: data_label: D13
type: f64

tool: D16: %d

tool: D13: 0.02

assistant: ```c
int main() {
  int n, m, c, k, i, sum = 0;
  float p = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  c = m;
  for (i = 1; i <= n; i++) {
    sum = sum + m;
    if (i % k == 0) {
      p = p + 0.02;
      m = c - c * p;
    }
  }
  printf("%d", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expand_ddval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L10:
  cmpb   $0x40,-0x1d(%rbp)
  jne    L6
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <lookup_ddval@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L8
L6:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L8:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1d(%rbp)
  cmpb   $0x0,-0x1d(%rbp)
  jne    L10
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void expand_ddval(const char *ddval_raw, char *ddval_expanded) {
  char c, *ddval;
  int i = 0, j = 0, len;
  while ((c = ddval_raw[i]) != '\0') {
    if (c == '@') {
      ddval = lookup_ddval(&ddval_raw[i + 1], &len);
      strcpy(&ddval_expanded[j], ddval);
      i += len;
      j += strlen(ddval);
    } else
      ddval_expanded[j++] = ddval_raw[i++];
  }
  ddval_expanded[j] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expand_ddval>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  mov    %rdi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x0,%edx
  lea    0x4(%rsp),%r14
  jmp    L15
L19:
  lea    0x1(%r12,%rdx,1),%rdi
  mov    %r14,%rsi
  call   <lookup_ddval@plt>
  mov    %rax,%r15
  movslq %ebx,%rdi
  add    %r13,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
  add    0x4(%rsp),%ebp
  mov    %r15,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
L39:
  movslq %ebp,%rdx
  movzbl (%r12,%rdx,1),%eax
  test   %al,%al
  je     L41
L15:
  cmp    $0x40,%al
  je     L19
  add    $0x1,%ebp
  movslq %ebx,%rdx
  mov    %al,0x0(%r13,%rdx,1)
  lea    0x1(%rbx),%ebx
  jmp    L39
L5:
  mov    $0x0,%ebx
L41:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void expand_ddval(const char *ddval_raw, char *ddval_expanded) {
  char c, *ddval;
  int i = 0, j = 0, len;
  while ((c = ddval_raw[i]) != '\0') {
    if (c == '@') {
      ddval = lookup_ddval(&ddval_raw[i + 1], &len);
      strcpy(&ddval_expanded[j], ddval);
      i += len;
      j += strlen(ddval);
    } else
      ddval_expanded[j++] = ddval_raw[i++];
  }
  ddval_expanded[j] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<expand_ddval>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L32
  mov    %rdi,%r14
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  xor    %ecx,%ecx
  lea    0x14(%rsp),%r8
  jmp    L6
  nopl   (%rax)
L10:
  add    $0x1,%r12d
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  movslq %r12d,%rcx
  movzbl (%r14,%rcx,1),%eax
  test   %al,%al
  je     L20
L6:
  movslq %ebx,%rdx
  lea    0x0(%r13,%rdx,1),%rbp
  cmp    $0x40,%al
  jne    L10
  lea    0x1(%r14,%rcx,1),%rdi
  mov    %r8,%rsi
  mov    %r8,0x8(%rsp)
  call   <lookup_ddval@plt>
  mov    %rbp,%rdi
  mov    %rax,%r15
  mov    %rax,%rsi
  call   <strcpy@plt>
  add    0x14(%rsp),%r12d
  mov    %r15,%rdi
  call   <strlen@plt>
  movslq %r12d,%rcx
  mov    0x8(%rsp),%r8
  add    %eax,%ebx
  movzbl (%r14,%rcx,1),%eax
  test   %al,%al
  jne    L6
L20:
  movslq %ebx,%rbx
  add    %rbx,%r13
L32:
  movb   $0x0,0x0(%r13)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void expand_ddval(const char *ddval_raw, char *ddval_expanded) {
  char c, *ddval;
  int i = 0, j = 0, len;
  while ((c = ddval_raw[i]) != '\0') {
    if (c == '@') {
      ddval = lookup_ddval(&ddval_raw[i + 1], &len);
      strcpy(&ddval_expanded[j], ddval);
      i += len;
      j += strlen(ddval);
    } else
      ddval_expanded[j++] = ddval_raw[i++];
  }
  ddval_expanded[j] = 0;
}
```