ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<x34_teardown>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  lea    D2(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: iptables -D INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x34_teardown() {
  char cmd[256];
  sprintf(cmd, "iptables -D INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<x34_teardown>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  lea    D7(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string

tool: D7: iptables -D INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d

assistant: ```c
int x34_teardown() {
  char cmd[256];
  sprintf(cmd, "iptables -D INPUT -p tcp -m multiport --sport 53,80 --tcp-flags SYN,ACK SYN,ACK -j NFQUEUE --queue-num %d", 1);
  system(cmd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string

tool: D1: Hello World!


tool: D11: It worked 0 times


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello World!\n");
  printf("It worked 0 times\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string
name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D3: Hello World!


tool: D9: It worked 0 times


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello World!\n");
  printf("It worked 0 times\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D5
datatype: string

tool: D10: Hello World!


tool: D5: It worked 0 times


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello World!\n");
  printf("It worked 0 times\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string

tool: D0: Hello World!


tool: D18: It worked 0 times


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello World!\n");
  printf("It worked 0 times\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RoutineWithoutReplacement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pop    %rbp
  ret
```

assistant: ```c
void *RoutineWithoutReplacement() {
  register void *funptr __asm__("%eax");
  return funptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RoutineWithoutReplacement>:
  endbr64
  ret
```

assistant: ```c
void *RoutineWithoutReplacement() {
  register void *funptr __asm__("%eax");
  return funptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<RoutineWithoutReplacement>:
  endbr64
  ret
```

assistant: ```c
void *RoutineWithoutReplacement() {
  register void *funptr __asm__("%eax");
  return funptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RoutineWithoutReplacement>:
  endbr64
  ret
```

assistant: ```c
void *RoutineWithoutReplacement() {
  register void *funptr __asm__("%eax");
  return funptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rpmlget32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int rpmlget32(FILE *fp) {
  int r;
  r = getc(fp);
  r = r << 8 | getc(fp);
  r = r << 8 | getc(fp);
  r = r << 8 | getc(fp);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rpmlget32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <getc@plt>
  shl    $0x8,%eax
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <getc@plt>
  or     %eax,%ebx
  shl    $0x8,%ebx
  mov    %rbp,%rdi
  call   <getc@plt>
  or     %eax,%ebx
  shl    $0x8,%ebx
  mov    %rbp,%rdi
  call   <getc@plt>
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rpmlget32(FILE *fp) {
  int r;
  r = getc(fp);
  r = r << 8 | getc(fp);
  r = r << 8 | getc(fp);
  r = r << 8 | getc(fp);
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rpmlget32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rdi
  shl    $0x8,%eax
  mov    %eax,%ebx
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %eax,%ebx
  call   <getc@plt>
  shl    $0x8,%ebx
  mov    %rbp,%rdi
  or     %eax,%ebx
  call   <getc@plt>
  shl    $0x8,%ebx
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rpmlget32(FILE *fp) {
  int r;
  r = getc(fp);
  r = r << 8 | getc(fp);
  r = r << 8 | getc(fp);
  r = r << 8 | getc(fp);
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rpmlget32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rdi
  shl    $0x8,%eax
  mov    %eax,%ebx
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %eax,%ebx
  call   <getc@plt>
  shl    $0x8,%ebx
  mov    %rbp,%rdi
  or     %eax,%ebx
  call   <getc@plt>
  shl    $0x8,%ebx
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rpmlget32(FILE *fp) {
  int r;
  r = getc(fp);
  r = r << 8 | getc(fp);
  r = r << 8 | getc(fp);
  r = r << 8 | getc(fp);
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<symmetry_mat2D_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L37:
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L33:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  ucomiss %xmm1,%xmm0
  setp   %al
  mov    $0x1,%edx
  ucomiss %xmm1,%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jb     L33
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jb     L37
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int symmetry_mat2D_float(float **mat2D_float, int x, int y) {
  unsigned int i, j, s;
  for (i = 0, s = 0; i < x; ++i)
    for (j = 0; j < i; ++j)
      s += (mat2D_float[i][j] == mat2D_float[j][i] ? 0 : 1);
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<symmetry_mat2D_float>:
  endbr64
  test   %esi,%esi
  je     L34
  lea    -0x1(%rsi),%r11d
  add    $0x1,%r11
  mov    $0x1,%ecx
  mov    $0x0,%esi
  mov    $0x1,%r10d
  jmp    L10
L24:
  mov    (%rdi,%rcx,8),%r9
  lea    0x0(,%rcx,4),%r8
  mov    $0x0,%eax
L29:
  mov    (%rdi,%rax,8),%rdx
  movss  (%rdx,%r8,1),%xmm0
  ucomiss (%r9,%rax,4),%xmm0
  setp   %dl
  movzbl %dl,%edx
  cmovne %r10d,%edx
  add    %edx,%esi
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L29
L8:
  add    $0x1,%rcx
L10:
  cmp    %r11,%rcx
  je     L34
  test   %ecx,%ecx
  jne    L24
  jmp    L8
L34:
  mov    %esi,%eax
  ret
```

assistant: ```c
int symmetry_mat2D_float(float **mat2D_float, int x, int y) {
  unsigned int i, j, s;
  for (i = 0, s = 0; i < x; ++i)
    for (j = 0; j < i; ++j)
      s += (mat2D_float[i][j] == mat2D_float[j][i] ? 0 : 1);
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<symmetry_mat2D_float>:
  endbr64
  mov    $0x4,%r9d
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    $0x1,%r11d
  test   %esi,%esi
  je     L4
  add    $0x1,%r8d
  cmp    %esi,%r8d
  je     L9
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%rdi,%r9,2),%r10
  xor    %edx,%edx
  xchg   %ax,%ax
L33:
  mov    (%rdi,%rdx,8),%rcx
  movss  (%rcx,%r9,1),%xmm0
  xor    %ecx,%ecx
  ucomiss (%r10,%rdx,4),%xmm0
  setp   %cl
  cmovne %r11d,%ecx
  add    $0x1,%rdx
  add    %ecx,%eax
  cmp    %edx,%r8d
  ja     L33
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %esi,%r8d
  jne    L3
L9:
  ret
L4:
  ret
```

assistant: ```c
int symmetry_mat2D_float(float **mat2D_float, int x, int y) {
  unsigned int i, j, s;
  for (i = 0, s = 0; i < x; ++i)
    for (j = 0; j < i; ++j)
      s += (mat2D_float[i][j] == mat2D_float[j][i] ? 0 : 1);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<symmetry_mat2D_float>:
  endbr64
  test   %esi,%esi
  je     L15
  cmp    $0x1,%esi
  je     L15
  mov    %esi,%r11d
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x1,%r10d
  nopl   (%rax)
L23:
  mov    (%rdi,%rsi,8),%r9
  lea    0x0(,%rsi,4),%r8
  xor    %edx,%edx
  xchg   %ax,%ax
L5:
  mov    (%rdi,%rdx,8),%rcx
  movss  (%rcx,%r8,1),%xmm0
  xor    %ecx,%ecx
  ucomiss (%r9,%rdx,4),%xmm0
  setp   %cl
  cmovne %r10d,%ecx
  add    $0x1,%rdx
  add    %ecx,%eax
  cmp    %rsi,%rdx
  jne    L5
  add    $0x1,%rsi
  cmp    %rsi,%r11
  jne    L23
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int symmetry_mat2D_float(float **mat2D_float, int x, int y) {
  unsigned int i, j, s;
  for (i = 0, s = 0; i < x; ++i)
    for (j = 0; j < i; ++j)
      s += (mat2D_float[i][j] == mat2D_float[j][i] ? 0 : 1);
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fmodf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x14(%rbp),%xmm0
  divss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rdi
  movd   %eax,%xmm0
  call   <modff@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
float fmodf(float x, float div) {
  float n0;
  x /= div;
  x = modff(x, &n0);
  x *= div;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fmodf>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movss  %xmm1,0xc(%rsp)
  divss  %xmm1,%xmm0
  lea    0x14(%rsp),%rdi
  call   <modff@plt>
  mulss  0xc(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float fmodf(float x, float div) {
  float n0;
  x /= div;
  x = modff(x, &n0);
  x *= div;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fmodf>:
  endbr64
  divss  %xmm1,%xmm0
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdi
  movss  %xmm1,0xc(%rsp)
  call   <modff@plt>
  movss  0xc(%rsp),%xmm1
  mulss  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float fmodf(float x, float div) {
  float n0;
  x /= div;
  x = modff(x, &n0);
  x *= div;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fmodf>:
  endbr64
  divss  %xmm1,%xmm0
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdi
  movss  %xmm1,0xc(%rsp)
  call   <modff@plt>
  movss  0xc(%rsp),%xmm1
  mulss  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float fmodf(float x, float div) {
  float n0;
  x /= div;
  x = modff(x, &n0);
  x *= div;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rdtsc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  rdtsc
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long rdtsc(void) {
  unsigned long long int x;
  __asm__ volatile(".byte 0x0f, 0x31" : "=A"(x));
  return (x);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rdtsc>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
unsigned long long rdtsc(void) {
  unsigned long long int x;
  __asm__ volatile(".byte 0x0f, 0x31" : "=A"(x));
  return (x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdtsc>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
unsigned long long rdtsc(void) {
  unsigned long long int x;
  __asm__ volatile(".byte 0x0f, 0x31" : "=A"(x));
  return (x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rdtsc>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
unsigned long long rdtsc(void) {
  unsigned long long int x;
  __asm__ volatile(".byte 0x0f, 0x31" : "=A"(x));
  return (x);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edi
  movq   %rax,%xmm0
  call   <foo@plt>
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  double y;
  return foo(y, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  pxor   %xmm0,%xmm0
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  double y;
  return foo(y, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x1,%edi
  pxor   %xmm0,%xmm0
  jmp    1050 <foo@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  double y;
  return foo(y, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x1,%edi
  pxor   %xmm0,%xmm0
  jmp    1050 <foo@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  double y;
  return foo(y, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L6:
  mov    $0x0,%edi
  call   <myfunction@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  cmpl   $0x3e7,-0x8(%rbp)
  jle    L6
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <myfunction2@plt>
  leave
  ret
```

assistant: ```c
int main(void) {
  int i, j;
  for (i = 0, j = 0; i < 1000; ++i)
    j += myfunction(0);
  return myfunction2(j);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3e8,%ebx
  mov    $0x0,%ebp
L1:
  mov    $0x0,%edi
  call   <myfunction@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L1
  mov    %ebp,%edi
  call   <myfunction2@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i, j;
  for (i = 0, j = 0; i < 1000; ++i)
    j += myfunction(0);
  return myfunction2(j);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  xor    %edi,%edi
  call   <myfunction@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L9
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <myfunction2@plt>
```

assistant: ```c
int main(void) {
  int i, j;
  for (i = 0, j = 0; i < 1000; ++i)
    j += myfunction(0);
  return myfunction2(j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  xor    %edi,%edi
  call   <myfunction@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L0
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <myfunction2@plt>
```

assistant: ```c
int main(void) {
  int i, j;
  for (i = 0, j = 0; i < 1000; ++i)
    j += myfunction(0);
  return myfunction2(j);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_request_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L114:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %eax,%eax
  jne    L123
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L123
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L123
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L123
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L89
L123:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L88
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L88
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L89
L88:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L89
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L89
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L89
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L89
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x3,%eax
  mov    %eax,-0x14(%rbp)
L89:
  addq   $0x1,-0x10(%rbp)
L25:
  cmpl   $0x0,-0x14(%rbp)
  jg     L83
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L114
L83:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_request_len(const char *buf, int buflen) {
  const char *s, *e;
  int len = 0;
  ;
  for (s = buf, e = s + buflen - 1; len <= 0 && s < e; s++)
    if (!isprint(*(unsigned char *)s) && *s != '\r' && *s != '\n' && *(unsigned char *)s < 128) {
      len = -1;
    } else if (s[0] == '\n' && s[1] == '\n') {
      len = (int)(s - buf) + 2;
    } else if (s[0] == '\n' && &s[1] < e && s[1] == '\r' && s[2] == '\n') {
      len = (int)(s - buf) + 3;
    }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_request_len>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rsi
  lea    -0x1(%rdi,%rsi,1),%r12
  cmp    %r12,%rdi
  jae    L14
  mov    %rdi,%r13
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  mov    $0xffffffff,%r14d
  jmp    L86
L21:
  cmpb   $0xa,(%rbx)
  je     L24
L144:
  add    $0x1,%rbx
  test   %ebp,%ebp
  jg     L125
  cmp    %rbx,%r12
  jbe    L125
L86:
  movzbl (%rbx),%edi
  call   <isprint@plt>
  test   %eax,%eax
  jne    L21
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  setne  %cl
  cmp    $0xd,%al
  setne  %dl
  test   %dl,%cl
  je     L21
  test   %al,%al
  js     L21
  mov    %r14d,%ebp
  jmp    L144
L24:
  movzbl 0x1(%rbx),%eax
  cmp    $0xa,%al
  je     L10
  lea    0x1(%rbx),%rdx
  cmp    %rdx,%r12
  jbe    L144
  cmp    $0xd,%al
  jne    L144
  cmpb   $0xa,0x2(%rbx)
  jne    L144
  mov    %rbx,%rbp
  sub    %r13,%rbp
  add    $0x3,%ebp
  jmp    L144
L10:
  mov    %rbx,%rbp
  sub    %r13,%rbp
  add    $0x2,%ebp
  jmp    L144
L14:
  mov    $0x0,%ebp
L125:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_request_len(const char *buf, int buflen) {
  const char *s, *e;
  int len = 0;
  ;
  for (s = buf, e = s + buflen - 1; len <= 0 && s < e; s++)
    if (!isprint(*(unsigned char *)s) && *s != '\r' && *s != '\n' && *(unsigned char *)s < 128) {
      len = -1;
    } else if (s[0] == '\n' && s[1] == '\n') {
      len = (int)(s - buf) + 2;
    } else if (s[0] == '\n' && &s[1] < e && s[1] == '\r' && s[2] == '\n') {
      len = (int)(s - buf) + 3;
    }
  return len;
}
```