ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<signalhandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  lea    D19(%rip),%rax
  mov    %rax,%rdx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <printerror@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D19: caught signal #%d

tool: D4: +INFO

assistant: ```c
void signalhandler(int sig) {
  printerror(0, "+INFO", "caught signal #%d", sig);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<signalhandler>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%ecx
  lea    D14(%rip),%rdx
  lea    D12(%rip),%rsi
  mov    $0x0,%edi
  call   <printerror@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type_guessed: string
name: disassemble_data
arguments: data_label: D12
type_guessed: string

tool: D14: caught signal #%d

tool: D12: +INFO

assistant: ```c
void signalhandler(int sig) {
  printerror(0, "+INFO", "caught signal #%d", sig);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<signalhandler>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%ecx
  xor    %edi,%edi
  lea    D1(%rip),%rdx
  lea    D15(%rip),%rsi
  call   <printerror@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D1: caught signal #%d

tool: D15: +INFO

assistant: ```c
void signalhandler(int sig) {
  printerror(0, "+INFO", "caught signal #%d", sig);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<signalhandler>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%ecx
  xor    %edi,%edi
  lea    D10(%rip),%rdx
  lea    D14(%rip),%rsi
  call   <printerror@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D14
datatype: string

tool: D10: caught signal #%d

tool: D14: +INFO

assistant: ```c
void signalhandler(int sig) {
  printerror(0, "+INFO", "caught signal #%d", sig);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CountFib1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <Fib1@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int CountFib1(int n) {
  int calls = 0;
  Fib1(n, &calls);
  return calls;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CountFib1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <Fib1@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CountFib1(int n) {
  int calls = 0;
  Fib1(n, &calls);
  return calls;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CountFib1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <Fib1@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CountFib1(int n) {
  int calls = 0;
  Fib1(n, &calls);
  return calls;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CountFib1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <Fib1@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CountFib1(int n) {
  int calls = 0;
  Fib1(n, &calls);
  return calls;
}
```
user: What is the c source code of the assembly code below:

```asm
<limat_number_is_finite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <finite@plt>
  test   %rax,%rax
  je     L11
  movss  D7(%rip),%xmm0
  jmp    L17
L11:
  pxor   %xmm0,%xmm0
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float limat_number_is_finite(float value) {
  if (finite(value))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<limat_number_is_finite>:
  endbr64
  sub    $0x8,%rsp
  call   <finite@plt>
  movss  D0(%rip),%xmm0
  test   %rax,%rax
  jne    L1
  pxor   %xmm0,%xmm0
L1:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: byte[4]

tool: {"D0": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float limat_number_is_finite(float value) {
  if (finite(value))
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<limat_number_is_finite>:
  endbr64
  sub    $0x8,%rsp
  call   <finite@plt>
  movss  D6(%rip),%xmm0
  test   %rax,%rax
  jne    L5
  pxor   %xmm0,%xmm0
L5:
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float limat_number_is_finite(float value) {
  if (finite(value))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<limat_number_is_finite>:
  endbr64
  sub    $0x8,%rsp
  call   <finite@plt>
  movss  D6(%rip),%xmm0
  test   %rax,%rax
  jne    L5
  pxor   %xmm0,%xmm0
L5:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float limat_number_is_finite(float value) {
  if (finite(value))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  shl    $0x8,%rax
  and    $0x86400000,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy12;
  char copy13;
  unsigned short copy14;
  unsigned short copy15;
  unsigned short copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    if ((state[0UL] >> 1UL) & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        if ((state[0UL] >> 4UL) & 1UL) {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy13;
          copy13 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy13;
          copy14 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy14;
        }
      } else if ((state[0UL] >> 4UL) & 1UL) {
        copy15 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy15;
        copy15 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy15;
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> 4UL) & 7UL) | 1UL;
        copy16 = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy16;
      }
    } else {
      state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
      copy17 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy17;
    }
    output[0UL] = state[0UL] & 37694211456UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  shl    $0x8,%rax
  and    $0x86400000,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy12;
  char copy13;
  unsigned short copy14;
  unsigned short copy15;
  unsigned short copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    if ((state[0UL] >> 1UL) & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        if ((state[0UL] >> 4UL) & 1UL) {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy13;
          copy13 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy13;
          copy14 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy14;
        }
      } else if ((state[0UL] >> 4UL) & 1UL) {
        copy15 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy15;
        copy15 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy15;
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> 4UL) & 7UL) | 1UL;
        copy16 = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy16;
      }
    } else {
      state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
      copy17 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy17;
    }
    output[0UL] = state[0UL] & 37694211456UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  shl    $0x8,%rax
  and    $0x86400000,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy12;
  char copy13;
  unsigned short copy14;
  unsigned short copy15;
  unsigned short copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    if ((state[0UL] >> 1UL) & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        if ((state[0UL] >> 4UL) & 1UL) {
          copy12 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy12;
          copy12 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy12;
        } else {
          copy13 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy13;
          copy13 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy13;
          copy14 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy14;
        }
      } else if ((state[0UL] >> 4UL) & 1UL) {
        copy15 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy15;
        copy15 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy15;
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> 4UL) & 7UL) | 1UL;
        copy16 = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy16;
      }
    } else {
      state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
      copy17 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy17;
    }
    output[0UL] = state[0UL] & 37694211456UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x14(%rbp)
  shll   -0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L1
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int add(unsigned int i, unsigned int j) {
  unsigned int carry;
  do {
    carry = j;
    j &= i;
    i ^= carry;
  } while ((j <<= 1) != 0);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<add>:
  endbr64
  mov    %edi,%eax
L8:
  mov    %eax,%edx
  and    %esi,%edx
  xor    %esi,%eax
  mov    %edx,%esi
  add    %esi,%esi
  jne    L8
  ret
```

assistant: ```c
unsigned int add(unsigned int i, unsigned int j) {
  unsigned int carry;
  do {
    carry = j;
    j &= i;
    i ^= carry;
  } while ((j <<= 1) != 0);
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add>:
  endbr64
  mov    %edi,%eax
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %eax,%edx
  xor    %esi,%eax
  and    %esi,%edx
  mov    %edx,%esi
  add    %esi,%esi
  jne    L3
  ret
```

assistant: ```c
unsigned int add(unsigned int i, unsigned int j) {
  unsigned int carry;
  do {
    carry = j;
    j &= i;
    i ^= carry;
  } while ((j <<= 1) != 0);
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add>:
  endbr64
  mov    %edi,%eax
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %eax,%edx
  xor    %esi,%eax
  and    %esi,%edx
  mov    %edx,%esi
  add    %esi,%esi
  jne    L9
  ret
```

assistant: ```c
unsigned int add(unsigned int i, unsigned int j) {
  unsigned int carry;
  do {
    carry = j;
    j &= i;
    i ^= carry;
  } while ((j <<= 1) != 0);
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_in_ready_queue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  cmpl   $0x7,-0x1c(%rbp)
  ja     L5
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D17(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <insert_sort_by_timestamp@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L5
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <insert_process_at_end_of_queue@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L5
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <insert_sort_by_priority@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L5
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <insert_sort_by_burst_duration@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L5
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <insert_sort_by_remaining_time@plt>
  mov    %rax,-0x10(%rbp)
  nop
L5:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct queue *insert_in_ready_queue(struct process_node *p, struct queue *r, struct queue *node, unsigned parameter) {
  switch (parameter) {
  case 1:
    r = insert_sort_by_timestamp(p, r, node);
    break;
  case 2:
  case 6:
  case 7:
    r = insert_process_at_end_of_queue(r, node);
    break;
  case 3:
    r = insert_sort_by_priority(p, r, node);
    break;
  case 4:
    r = insert_sort_by_burst_duration(r, node);
    break;
  case 5:
    r = insert_sort_by_remaining_time(p, r, node);
    break;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insert_in_ready_queue>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  cmp    $0x7,%ecx
  ja     L43
  sub    $0x8,%rsp
  mov    %ecx,%ecx
  lea    D6(%rip),%rsi
  movslq (%rsi,%rcx,4),%rax
  add    %rsi,%rax
  notrack jmp *%rax
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <insert_sort_by_timestamp@plt>
L6:
  add    $0x8,%rsp
  ret
  mov    %rdx,%rsi
  call   <insert_process_at_end_of_queue@plt>
  jmp    L6
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <insert_sort_by_priority@plt>
  jmp    L6
  mov    %rdx,%rsi
  call   <insert_sort_by_burst_duration@plt>
  jmp    L6
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <insert_sort_by_remaining_time@plt>
  jmp    L6
  mov    %rdi,%rax
  jmp    L6
L43:
  mov    %rsi,%rax
  ret
```

assistant: ```c
struct queue *insert_in_ready_queue(struct process_node *p, struct queue *r, struct queue *node, unsigned parameter) {
  switch (parameter) {
  case 1:
    r = insert_sort_by_timestamp(p, r, node);
    break;
  case 2:
  case 6:
  case 7:
    r = insert_process_at_end_of_queue(r, node);
    break;
  case 3:
    r = insert_sort_by_priority(p, r, node);
    break;
  case 4:
    r = insert_sort_by_burst_duration(r, node);
    break;
  case 5:
    r = insert_sort_by_remaining_time(p, r, node);
    break;
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  leave
  ret
```

assistant: ```c
char *copy_string(char *s) {
  char *tmp;
  tmp = (char *)malloc((strlen(s) + 1) * sizeof(char));
  return strcpy(tmp, s);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *copy_string(char *s) {
  char *tmp;
  tmp = (char *)malloc((strlen(s) + 1) * sizeof(char));
  return strcpy(tmp, s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *copy_string(char *s) {
  char *tmp;
  tmp = (char *)malloc((strlen(s) + 1) * sizeof(char));
  return strcpy(tmp, s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *copy_string(char *s) {
  char *tmp;
  tmp = (char *)malloc((strlen(s) + 1) * sizeof(char));
  return strcpy(tmp, s);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trim_index_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L3
  mov    -0x18(%rbp),%rax
  jmp    L23
L3:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  jne    L29
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L29:
  mov    -0x18(%rbp),%rax
L23:
  leave
  ret
```

assistant: ```c
char *trim_index_zero(char *destination, char *attribute_name) {
  char *end_ptr;
  strcpy(destination, attribute_name);
  end_ptr = destination + strlen(destination) - 1;
  if (*end_ptr != '0')
    return destination;
  end_ptr--;
  if (*end_ptr == '_')
    *end_ptr = '\0';
  return destination;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim_index_zero>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x30,(%rax)
  jne    L9
  cmpb   $0x5f,-0x1(%rax)
  je     L25
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
L25:
  movb   $0x0,-0x1(%rax)
  jmp    L9
```

assistant: ```c
char *trim_index_zero(char *destination, char *attribute_name) {
  char *end_ptr;
  strcpy(destination, attribute_name);
  end_ptr = destination + strlen(destination) - 1;
  if (*end_ptr != '0')
    return destination;
  end_ptr--;
  if (*end_ptr == '_')
    *end_ptr = '\0';
  return destination;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trim_index_zero>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmpb   $0x30,(%rax)
  jne    L0
  cmpb   $0x5f,-0x1(%rax)
  je     L15
L0:
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L15:
  movb   $0x0,-0x1(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trim_index_zero(char *destination, char *attribute_name) {
  char *end_ptr;
  strcpy(destination, attribute_name);
  end_ptr = destination + strlen(destination) - 1;
  if (*end_ptr != '0')
    return destination;
  end_ptr--;
  if (*end_ptr == '_')
    *end_ptr = '\0';
  return destination;
}
```