ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sumOfTwoEle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x61000(%rsp),%r11
L31:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L31
  sub    $0xab0,%rsp
  mov    %rdi,-0x61aa8(%rbp)
  mov    %esi,-0x61aac(%rbp)
  mov    %edx,-0x61ab0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x61a90(%rbp),%rax
  mov    $0x61a80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x61a98(%rbp)
  jmp    L13
L29:
  mov    -0x61a98(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x61aa8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x61ab0(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x61a94(%rbp)
  cmpl   $0x0,-0x61a94(%rbp)
  js     L51
  mov    -0x61a94(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L51
  mov    -0x61a98(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x61aa8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x61ab0(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x61a98(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x61aa8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L51:
  mov    -0x61a98(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x61aa8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  movl   $0x1,-0x61a90(%rbp,%rax,4)
  addl   $0x1,-0x61a98(%rbp)
L13:
  mov    -0x61a98(%rbp),%eax
  cmp    -0x61aac(%rbp),%eax
  jl     L29
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string

tool: D5: The two elements are: %d and %d


assistant: ```c
void sumOfTwoEle(int A[], int n, int sum) {
  int map[100000] = {0};
  int i, temp;
  for (i = 0; i < n; i++) {
    temp = sum - A[i];
    if (temp >= 0 && map[temp])
      printf("The two elements are: %d and %d\n", A[i], sum - A[i]);
    map[A[i]] = 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sumOfTwoEle>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0xa90,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x61a80,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L46
  mov    %r13,%rbx
  lea    -0x1(%r12),%eax
  lea    0x4(%r13,%rax,4),%r12
  lea    D0(%rip),%r13
  jmp    L59
L76:
  movslq (%r14),%rax
  movl   $0x1,(%rsp,%rax,4)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L46
L59:
  mov    %rbx,%r14
  mov    (%rbx),%esi
  mov    %ebp,%edx
  sub    %esi,%edx
  js     L76
  movslq %edx,%rax
  cmpl   $0x0,(%rsp,%rax,4)
  je     L76
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L76
L46:
  mov    0x61a88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x61a90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D0: The two elements are: %d and %d


assistant: ```c
void sumOfTwoEle(int A[], int n, int sum) {
  int map[100000] = {0};
  int i, temp;
  for (i = 0; i < n; i++) {
    temp = sum - A[i];
    if (temp >= 0 && map[temp])
      printf("The two elements are: %d and %d\n", A[i], sum - A[i]);
    map[A[i]] = 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sumOfTwoEle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L36:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L36
  sub    $0xa98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a88(%rsp)
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rbx
  mov    %edx,%r13d
  xor    %esi,%esi
  mov    %rsp,%rdi
  mov    $0x61a80,%edx
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L62
  lea    -0x1(%rbp),%eax
  lea    D4(%rip),%r12
  lea    0x4(%rbx,%rax,4),%rbp
  jmp    L56
  nopl   0x0(%rax)
L35:
  add    $0x4,%rbx
  movl   $0x1,(%rsp,%rsi,4)
  cmp    %rbp,%rbx
  je     L62
L56:
  movslq (%rbx),%rsi
  mov    %r13d,%edx
  sub    %esi,%edx
  js     L35
  movslq %edx,%rax
  mov    (%rsp,%rax,4),%eax
  test   %eax,%eax
  je     L35
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  movslq -0x4(%rbx),%rsi
  movl   $0x1,(%rsp,%rsi,4)
  cmp    %rbp,%rbx
  jne    L56
L62:
  mov    0x61a88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x61a98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4: The two elements are: %d and %d


assistant: ```c
void sumOfTwoEle(int A[], int n, int sum) {
  int map[100000] = {0};
  int i, temp;
  for (i = 0; i < n; i++) {
    temp = sum - A[i];
    if (temp >= 0 && map[temp])
      printf("The two elements are: %d and %d\n", A[i], sum - A[i]);
    map[A[i]] = 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sumOfTwoEle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L59:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L59
  sub    $0xa98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a88(%rsp)
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rbx
  mov    %edx,%r13d
  xor    %esi,%esi
  mov    %rsp,%rdi
  mov    $0x61a80,%edx
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L67
  lea    -0x1(%rbp),%eax
  lea    D6(%rip),%r12
  lea    0x4(%rbx,%rax,4),%rbp
  jmp    L28
  nopl   0x0(%rax)
L61:
  add    $0x4,%rbx
  movl   $0x1,(%rsp,%rsi,4)
  cmp    %rbp,%rbx
  je     L67
L28:
  movslq (%rbx),%rsi
  mov    %r13d,%edx
  sub    %esi,%edx
  js     L61
  movslq %edx,%rax
  mov    (%rsp,%rax,4),%eax
  test   %eax,%eax
  je     L61
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  movslq -0x4(%rbx),%rsi
  movl   $0x1,(%rsp,%rsi,4)
  cmp    %rbp,%rbx
  jne    L28
L67:
  mov    0x61a88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x61a98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: D6: The two elements are: %d and %d


assistant: ```c
void sumOfTwoEle(int A[], int n, int sum) {
  int map[100000] = {0};
  int i, temp;
  for (i = 0; i < n; i++) {
    temp = sum - A[i];
    if (temp >= 0 && map[temp])
      printf("The two elements are: %d and %d\n", A[i], sum - A[i]);
    map[A[i]] = 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L24
  cmpl   $0x1,-0x4(%rbp)
  je     L34
  jmp    L19
L24:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L46
L34:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L46
L19:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L46:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D28
type: string
name: read_data
arguments: label: D18
type: string
name: read_data
arguments: label: D21
type: string
name: read_data
arguments: label: D17
type: string

tool: D28: red pants are hip

tool: D18: green pants are weird

tool: D21: yet another color

tool: D17: pants = %d


assistant: ```c
int main() {
  typedef enum { red, green, blue } Color;
  Color pants = green;
  switch (pants) {
  case red:
    printf("red pants are hip\n");
    break;
  case green:
    printf("green pants are weird\n");
    break;
  default:
    printf("yet another color\n");
  }
  printf("pants = %d\n", pants);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D14
datatype: string

tool: D1: green pants are weird

tool: D14: pants = %d


assistant: ```c
int main() {
  typedef enum { red, green, blue } Color;
  Color pants = green;
  switch (pants) {
  case red:
    printf("red pants are hip\n");
    break;
  case green:
    printf("green pants are weird\n");
    break;
  default:
    printf("yet another color\n");
  }
  printf("pants = %d\n", pants);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string
name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D8: green pants are weird

tool: D3: pants = %d


assistant: ```c
int main() {
  typedef enum { red, green, blue } Color;
  Color pants = green;
  switch (pants) {
  case red:
    printf("red pants are hip\n");
    break;
  case green:
    printf("green pants are weird\n");
    break;
  default:
    printf("yet another color\n");
  }
  printf("pants = %d\n", pants);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D5: green pants are weird

tool: D16: pants = %d


assistant: ```c
int main() {
  typedef enum { red, green, blue } Color;
  Color pants = green;
  switch (pants) {
  case red:
    printf("red pants are hip\n");
    break;
  case green:
    printf("green pants are weird\n");
    break;
  default:
    printf("yet another color\n");
  }
  printf("pants = %d\n", pants);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<signal_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x63206c616e676953,%rax
  movabs $0xa2e7468677561,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movq   $0xf,-0x30(%rbp)
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0x34(%rbp),%rdx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D20(%rip),%rax
  mov    (%rax),%edx
  lea    -0x34(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigismember@plt>
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void signal_handler(int signo, siginfo_t *info, void *uc) {
  ssize_t written;
  const char str[] = "Signal caught.\n";
  size_t len = sizeof(str) - 1;
  sigset_t current;
  written = write(STDOUT_FILENO, str, len);
  assert(written == len);
  assert(!sigprocmask(SIG_BLOCK, NULL, &current));
  assert(sigismember(&current, SIGUSR1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<signal_handler>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x63206c616e676953,%rax
  movabs $0xa2e7468677561,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  lea    0x10(%rsp),%rsi
  mov    $0xf,%edx
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  cmp    $0xf,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigismember@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void signal_handler(int signo, siginfo_t *info, void *uc) {
  ssize_t written;
  const char str[] = "Signal caught.\n";
  size_t len = sizeof(str) - 1;
  sigset_t current;
  written = write(STDOUT_FILENO, str, len);
  assert(written == len);
  assert(!sigprocmask(SIG_BLOCK, NULL, &current));
  assert(sigismember(&current, SIGUSR1));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_obs_x264_parse_options@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_obs_x264_parse_options();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_obs_x264_parse_options@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_obs_x264_parse_options();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_obs_x264_parse_options@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_obs_x264_parse_options();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_obs_x264_parse_options@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_obs_x264_parse_options();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<load_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
uint16_t load_u16(uint8_t *buf) {
  uint16_t ret;
  memcpy(&ret, buf, sizeof(ret));
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<load_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t load_u16(uint8_t *buf) {
  uint16_t ret;
  memcpy(&ret, buf, sizeof(ret));
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<load_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t load_u16(uint8_t *buf) {
  uint16_t ret;
  memcpy(&ret, buf, sizeof(ret));
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<load_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t load_u16(uint8_t *buf) {
  uint16_t ret;
  memcpy(&ret, buf, sizeof(ret));
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<conget_yc_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  je     L12
  cmpq   $0x0,-0x30(%rbp)
  je     L12
  mov    $0x0,%eax
  call   <houston_Rev@plt>
  test   %eax,%eax
  jg     L43
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L55
L43:
  lea    -0x20(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x8d,%edi
  call   <houston_ReadReg@plt>
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  lea    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x47,%edi
  call   <houston_ReadReg@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x74,%edi
  call   <houston_ReadReg@plt>
  mov    -0x18(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  jne    L74
  mov    -0x10(%rbp),%rax
  and    $0x20,%eax
  test   %rax,%rax
  jne    L74
  mov    $0x1,%edx
  jmp    L11
L74:
  mov    $0x0,%edx
L11:
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L55
L12:
  nop
L55:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
void conget_yc_filter(int *p_luma_filter, int *p_chroma_filter) {
  unsigned long reg, reg07, reg34;
  if (!p_luma_filter || !p_chroma_filter)
    return;
  if (houston_Rev() < 1) {
    *p_luma_filter = 0;
    *p_chroma_filter = 0;
    return;
  }
  houston_ReadReg(0x8d, &reg, 1);
  *p_luma_filter = (reg ? 1 : 0);
  houston_ReadReg(0x47, &reg07, 1);
  houston_ReadReg(0x74, &reg34, 1);
  *p_chroma_filter = !((0x08 & reg07) || (0x20 & reg34));
}
```
user: Translate the below assembly code into C programming language:

```asm
<conget_yc_filter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L14
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L14
  call   <houston_Rev@plt>
  test   %eax,%eax
  jle    L26
  mov    %rsp,%rsi
  mov    $0x1,%edx
  mov    $0x8d,%edi
  call   <houston_ReadReg@plt>
  cmpq   $0x0,(%rsp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,(%rbx)
  lea    0x8(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x47,%edi
  call   <houston_ReadReg@plt>
  lea    0x10(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x74,%edi
  call   <houston_ReadReg@plt>
  mov    0x8(%rsp),%rax
  and    $0x8,%eax
  mov    0x10(%rsp),%rdx
  and    $0x20,%edx
  or     %rdx,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,0x0(%rbp)
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  movl   $0x0,(%rbx)
  movl   $0x0,0x0(%rbp)
  jmp    L14
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void conget_yc_filter(int *p_luma_filter, int *p_chroma_filter) {
  unsigned long reg, reg07, reg34;
  if (!p_luma_filter || !p_chroma_filter)
    return;
  if (houston_Rev() < 1) {
    *p_luma_filter = 0;
    *p_chroma_filter = 0;
    return;
  }
  houston_ReadReg(0x8d, &reg, 1);
  *p_luma_filter = (reg ? 1 : 0);
  houston_ReadReg(0x47, &reg07, 1);
  houston_ReadReg(0x74, &reg34, 1);
  *p_chroma_filter = !((0x08 & reg07) || (0x20 & reg34));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<conget_yc_filter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L40
  mov    %rdi,%rbx
  call   <houston_Rev@plt>
  test   %eax,%eax
  jle    L22
  mov    %rsp,%rsi
  mov    $0x1,%edx
  mov    $0x8d,%edi
  call   <houston_ReadReg@plt>
  xor    %eax,%eax
  cmpq   $0x0,(%rsp)
  lea    0x8(%rsp),%rsi
  setne  %al
  mov    $0x1,%edx
  mov    $0x47,%edi
  mov    %eax,(%rbx)
  call   <houston_ReadReg@plt>
  mov    $0x1,%edx
  lea    0x10(%rsp),%rsi
  mov    $0x74,%edi
  call   <houston_ReadReg@plt>
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%rdx
  and    $0x8,%eax
  and    $0x20,%edx
  or     %rdx,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,0x0(%rbp)
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L22:
  movl   $0x0,(%rbx)
  movl   $0x0,0x0(%rbp)
  jmp    L40
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void conget_yc_filter(int *p_luma_filter, int *p_chroma_filter) {
  unsigned long reg, reg07, reg34;
  if (!p_luma_filter || !p_chroma_filter)
    return;
  if (houston_Rev() < 1) {
    *p_luma_filter = 0;
    *p_chroma_filter = 0;
    return;
  }
  houston_ReadReg(0x8d, &reg, 1);
  *p_luma_filter = (reg ? 1 : 0);
  houston_ReadReg(0x47, &reg07, 1);
  houston_ReadReg(0x74, &reg34, 1);
  *p_chroma_filter = !((0x08 & reg07) || (0x20 & reg34));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<conget_yc_filter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L44
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L44
  mov    %rdi,%rbx
  call   <houston_Rev@plt>
  test   %eax,%eax
  jle    L9
  mov    %rsp,%rsi
  mov    $0x1,%edx
  mov    $0x8d,%edi
  call   <houston_ReadReg@plt>
  xor    %eax,%eax
  cmpq   $0x0,(%rsp)
  lea    0x8(%rsp),%rsi
  setne  %al
  mov    $0x1,%edx
  mov    $0x47,%edi
  mov    %eax,(%rbx)
  call   <houston_ReadReg@plt>
  mov    $0x1,%edx
  lea    0x10(%rsp),%rsi
  mov    $0x74,%edi
  call   <houston_ReadReg@plt>
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%rdx
  and    $0x8,%eax
  and    $0x20,%edx
  or     %rdx,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,0x0(%rbp)
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  movl   $0x0,(%rbx)
  movl   $0x0,0x0(%rbp)
  jmp    L44
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void conget_yc_filter(int *p_luma_filter, int *p_chroma_filter) {
  unsigned long reg, reg07, reg34;
  if (!p_luma_filter || !p_chroma_filter)
    return;
  if (houston_Rev() < 1) {
    *p_luma_filter = 0;
    *p_chroma_filter = 0;
    return;
  }
  houston_ReadReg(0x8d, &reg, 1);
  *p_luma_filter = (reg ? 1 : 0);
  houston_ReadReg(0x47, &reg07, 1);
  houston_ReadReg(0x74, &reg34, 1);
  *p_chroma_filter = !((0x08 & reg07) || (0x20 & reg34));
}
```