user: 请从给定的汇编指令推导出C源代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r14d
  mov    %esi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %esi,%eax
  cltq
  shl    $0x2,%rax
  lea    0xf(%rax),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L21:
  cmp    %rcx,%rsp
  je     L36
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L21
L36:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L25
  orq    $0x0,-0x8(%rsp,%rdx,1)
L25:
  mov    %rsp,%r13
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L85:
  cmp    %rdx,%rsp
  je     L32
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L85
L32:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L129
  orq    $0x0,-0x8(%rsp,%rax,1)
L129:
  lea    0x3(%rsp),%r12
  mov    %r12,%rax
  shr    $0x2,%rax
  mov    %rax,-0x50(%rbp)
  and    $0xfffffffffffffffc,%r12
  mov    -0x44(%rbp),%eax
  test   %eax,%eax
  jle    L113
  mov    %eax,%r15d
  mov    $0x0,%ebx
L144:
  movss  D4(%rip),%xmm1
  movss  D37(%rip),%xmm0
  call   <rand_uniformf@plt>
  movss  %xmm0,0x0(%r13,%rbx,4)
  movl   $0x0,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L144
L113:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r14d,%r14d
  jle    L40
  mov    $0x0,%ebx
L114:
  mov    $0x1,%r8d
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    -0x44(%rbp),%edi
  call   <stdlib_strided_strunc@plt>
  movss  (%r12),%xmm0
  ucomiss %xmm0,%xmm0
  jp     L10
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jne    L114
  jmp    L40
L10:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L40:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    -0x50(%rbp),%rax
  movss  0x0(,%rax,4),%xmm0
  ucomiss %xmm0,%xmm0
  jp     L70
L123:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L70:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L123
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: byte[4]
name: parse_data
arguments: data_tag: D37
type: byte[4]
name: parse_data
arguments: data_tag: D5
type: string

tool: {"D4": [0x00,0x00,0x20,0x41]}

tool: {"D37": [0x00,0x00,0x20,0xc1]}

tool: D5: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float y[len];
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = rand_uniformf(-10.0f, 10.0f);
    y[i] = 0.0f;
  }
  t = tic();
  for (i = 0; i < iterations; i++) {
    stdlib_strided_strunc(len, x, 1, y, 1);
    if (y[0] != y[0]) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y[0] != y[0]) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```