ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L63
  mov    %rdi,%rbp
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L63
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L23
  mov    $0x0,%r12d
  movslq %r14d,%r15
L8:
  add    $0x1,%r12d
  lea    (%rax,%r15,1),%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L8
L15:
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    %r14d,%eax
  imul   %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    (%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L25
  movslq %r14d,%r14
L27:
  mov    %r15,%rdi
  call   <strlen@plt>
  movslq %eax,%rdi
  add    %r15,%rdi
  mov    %r12d,%edx
  sub    %ebx,%edx
  mov    %rbx,%rsi
  call   <strncpy@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  movslq %eax,%rdi
  add    %r15,%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  lea    (%r12,%r14,1),%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L27
L25:
  mov    %r15,%rdi
  call   <strlen@plt>
  movslq %eax,%rdi
  add    %r15,%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  mov    %r15,%rbx
L63:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    $0x0,%r12d
  jmp    L15
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: 

assistant: ```c
char *str_replace(char const *search, char const *replace, char *subject) {
  char *p = NULL, *old = NULL, *new_subject = NULL;
  int c = 0, search_size;
  if (search == NULL || replace == NULL)
    return subject;
  search_size = strlen(search);
  for (p = strstr(subject, search); p != NULL; p = strstr(p + search_size, search)) {
    c++;
  }
  c = (strlen(replace) - search_size) * c + strlen(subject);
  new_subject = malloc(c);
  strcpy(new_subject, "");
  old = subject;
  for (p = strstr(subject, search); p != NULL; p = strstr(p + search_size, search)) {
    strncpy(new_subject + strlen(new_subject), old, p - old);
    strcpy(new_subject + strlen(new_subject), replace);
    old = p + search_size;
  }
  strcpy(new_subject + strlen(new_subject), old);
  return new_subject;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L39
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L39
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movslq %eax,%r14
  call   <strstr@plt>
  test   %rax,%rax
  je     L16
  movslq %r14d,%r15
  xor    %r12d,%r12d
  nop
L43:
  lea    (%rax,%r15,1),%rdi
  mov    %rbx,%rsi
  add    $0x1,%r12d
  call   <strstr@plt>
  test   %rax,%rax
  jne    L43
L51:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  sub    %r14d,%eax
  imul   %eax,%r12d
  call   <strlen@plt>
  lea    (%r12,%rax,1),%edi
  call   <malloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strcpy@plt>
  jmp    L20
  nopl   0x0(%rax)
L7:
  call   <strlen@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  movslq %eax,%rdi
  sub    %ebp,%edx
  lea    (%r12,%r14,1),%rbp
  add    %r15,%rdi
  call   <strncpy@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  movslq %eax,%rdi
  add    %r15,%rdi
  call   <strcpy@plt>
L20:
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <strstr@plt>
  mov    %r15,%rdi
  mov    %rax,%r12
  test   %rax,%rax
  jne    L7
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r15,%rbp
  movslq %eax,%rdi
  add    %r15,%rdi
  call   <strcpy@plt>
L39:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  xor    %r12d,%r12d
  jmp    L51
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: 

assistant: ```c
char *str_replace(char const *search, char const *replace, char *subject) {
  char *p = NULL, *old = NULL, *new_subject = NULL;
  int c = 0, search_size;
  if (search == NULL || replace == NULL)
    return subject;
  search_size = strlen(search);
  for (p = strstr(subject, search); p != NULL; p = strstr(p + search_size, search)) {
    c++;
  }
  c = (strlen(replace) - search_size) * c + strlen(subject);
  new_subject = malloc(c);
  strcpy(new_subject, "");
  old = subject;
  for (p = strstr(subject, search); p != NULL; p = strstr(p + search_size, search)) {
    strncpy(new_subject + strlen(new_subject), old, p - old);
    strcpy(new_subject + strlen(new_subject), replace);
    old = p + search_size;
  }
  strcpy(new_subject + strlen(new_subject), old);
  return new_subject;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L23
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L23
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movslq %eax,%r14
  call   <strstr@plt>
  test   %rax,%rax
  je     L34
  movslq %r14d,%r15
  xor    %r12d,%r12d
  nop
L36:
  lea    (%rax,%r15,1),%rdi
  mov    %rbx,%rsi
  add    $0x1,%r12d
  call   <strstr@plt>
  test   %rax,%rax
  jne    L36
L18:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  sub    %r14d,%eax
  imul   %eax,%r12d
  call   <strlen@plt>
  lea    (%r12,%rax,1),%edi
  call   <malloc@plt>
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strcpy@plt>
  jmp    L5
  nopl   0x0(%rax)
L31:
  call   <strlen@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  movslq %eax,%rdi
  sub    %ebp,%edx
  lea    (%r12,%r14,1),%rbp
  add    %r15,%rdi
  call   <strncpy@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  movslq %eax,%rdi
  add    %r15,%rdi
  call   <strcpy@plt>
L5:
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <strstr@plt>
  mov    %r15,%rdi
  mov    %rax,%r12
  test   %rax,%rax
  jne    L31
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r15,%rbp
  movslq %eax,%rdi
  add    %r15,%rdi
  call   <strcpy@plt>
L23:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  xor    %r12d,%r12d
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: 

assistant: ```c
char *str_replace(char const *search, char const *replace, char *subject) {
  char *p = NULL, *old = NULL, *new_subject = NULL;
  int c = 0, search_size;
  if (search == NULL || replace == NULL)
    return subject;
  search_size = strlen(search);
  for (p = strstr(subject, search); p != NULL; p = strstr(p + search_size, search)) {
    c++;
  }
  c = (strlen(replace) - search_size) * c + strlen(subject);
  new_subject = malloc(c);
  strcpy(new_subject, "");
  old = subject;
  for (p = strstr(subject, search); p != NULL; p = strstr(p + search_size, search)) {
    strncpy(new_subject + strlen(new_subject), old, p - old);
    strcpy(new_subject + strlen(new_subject), replace);
    old = p + search_size;
  }
  strcpy(new_subject + strlen(new_subject), old);
  return new_subject;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alloc_2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L6
L17:
  mov    -0x14(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
float **alloc_2D(int size1, int size2) {
  int a;
  float **array_2D = (float **)malloc(size1 * sizeof(float *));
  float *array_1D = (float *)malloc(size1 * size2 * sizeof(float));
  for (a = 0; a < size1; a++) {
    array_2D[a] = &array_1D[a * size2];
  }
  return array_2D;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<alloc_2D>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edi
  imul   %r12d,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L13
  movslq %r12d,%rcx
  shl    $0x2,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%ebx
  lea    0x0(%rbp,%rbx,8),%rsi
L18:
  mov    %rax,(%rdx)
  add    %rcx,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L18
L13:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
float **alloc_2D(int size1, int size2) {
  int a;
  float **array_2D = (float **)malloc(size1 * sizeof(float *));
  float *array_1D = (float *)malloc(size1 * size2 * sizeof(float));
  for (a = 0; a < size1; a++) {
    array_2D[a] = &array_1D[a * size2];
  }
  return array_2D;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<alloc_2D>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %ebp,%edi
  imul   %ebx,%edi
  mov    %rax,%r12
  shl    $0x2,%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L8
  movslq %ebx,%rcx
  mov    %r12,%rdx
  lea    (%r12,%rbp,8),%rsi
  shl    $0x2,%rcx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rax,(%rdx)
  add    $0x8,%rdx
  add    %rcx,%rax
  cmp    %rsi,%rdx
  jne    L0
L8:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
float **alloc_2D(int size1, int size2) {
  int a;
  float **array_2D = (float **)malloc(size1 * sizeof(float *));
  float *array_1D = (float *)malloc(size1 * size2 * sizeof(float));
  for (a = 0; a < size1; a++) {
    array_2D[a] = &array_1D[a * size2];
  }
  return array_2D;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtotimeval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoumax@plt>
  mov    -0x40(%rbp),%rdx
  mov    %eax,0x8(%rdx)
  movq   $0x0,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L59
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L54
L40:
  addl   $0x1,-0x24(%rbp)
  cmpl   $0x6,-0x24(%rbp)
  jg     L5
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L5:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L54:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L40
  jmp    L24
L61:
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x24(%rbp)
L24:
  cmpl   $0x5,-0x24(%rbp)
  jle    L61
L59:
  mov    -0x40(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
char *strtotimeval(const char *str, struct timeval *ts) {
  int n;
  char *s, *s0;
  long fs;
  ts->tv_sec = strtoumax(str, &s, 10);
  fs = 0;
  if (*s == '.') {
    int count;
    s0 = s + 1;
    fs = 0;
    count = 0;
    while (*s && isdigit(*s)) {
      if (++count < 7)
        fs = fs * 10 + (*s - '0');
      s++;
    }
    for (; count < 6; count++)
      fs *= 10;
  }
  ts->tv_usec = fs;
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<strtotimeval>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtoumax@plt>
  mov    %eax,0x8(%r12)
  mov    (%rsp),%rax
  movzbl (%rax),%edi
  mov    $0x0,%ebx
  cmp    $0x2e,%dil
  je     L53
L42:
  mov    %rbx,(%r12)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    (%rsp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L17
L74:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L17
  add    $0x1,%ebp
  cmp    $0x6,%ebp
  jg     L4
  lea    (%rbx,%rbx,4),%rdx
  mov    (%rsp),%rax
  movsbl (%rax),%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rbx
  jmp    L4
L17:
  cmp    $0x5,%ebp
  jg     L42
L97:
  lea    (%rbx,%rbx,4),%rbx
  add    %rbx,%rbx
  add    $0x1,%ebp
  cmp    $0x6,%ebp
  jne    L97
  jmp    L42
L53:
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L74
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtotimeval(const char *str, struct timeval *ts) {
  int n;
  char *s, *s0;
  long fs;
  ts->tv_sec = strtoumax(str, &s, 10);
  fs = 0;
  if (*s == '.') {
    int count;
    s0 = s + 1;
    fs = 0;
    count = 0;
    while (*s && isdigit(*s)) {
      if (++count < 7)
        fs = fs * 10 + (*s - '0');
      s++;
    }
    for (; count < 6; count++)
      fs *= 10;
  }
  ts->tv_usec = fs;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strtotimeval>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtoumax@plt>
  mov    (%rsp),%r8
  mov    %eax,0x8(%r12)
  movsbl (%r8),%edi
  cmp    $0x2e,%dil
  je     L1
L41:
  mov    %rbx,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  jmp    L37
  xchg   %ax,%ax
L52:
  add    $0x1,%ebp
  mov    (%rsp),%rax
  cmp    $0x6,%ebp
  jg     L84
  movsbl (%rax),%edx
  lea    (%rbx,%rbx,4),%rcx
  sub    $0x30,%edx
  movslq %edx,%rdx
  lea    (%rdx,%rcx,2),%rbx
L84:
  lea    0x1(%rax),%r8
  mov    %r8,(%rsp)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L28
L37:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L52
  mov    (%rsp),%r8
L28:
  cmp    $0x5,%ebp
  jg     L41
  nopl   0x0(%rax)
L88:
  lea    (%rbx,%rbx,4),%rbx
  add    $0x1,%ebp
  add    %rbx,%rbx
  cmp    $0x6,%ebp
  jne    L88
  jmp    L41
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtotimeval(const char *str, struct timeval *ts) {
  int n;
  char *s, *s0;
  long fs;
  ts->tv_sec = strtoumax(str, &s, 10);
  fs = 0;
  if (*s == '.') {
    int count;
    s0 = s + 1;
    fs = 0;
    count = 0;
    while (*s && isdigit(*s)) {
      if (++count < 7)
        fs = fs * 10 + (*s - '0');
      s++;
    }
    for (; count < 6; count++)
      fs *= 10;
  }
  ts->tv_usec = fs;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtotimeval>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtoumax@plt>
  mov    (%rsp),%r8
  mov    %eax,0x8(%rbp)
  movsbl (%r8),%edi
  cmp    $0x2e,%dil
  je     L52
L118:
  mov    %r12,0x0(%rbp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x10,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L52:
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L7
  nop
L1:
  add    $0x1,%ebx
  mov    (%rsp),%rax
  cmp    $0x6,%ebx
  jg     L90
  movsbl (%rax),%edx
  lea    (%r12,%r12,4),%rcx
  sub    $0x30,%edx
  movslq %edx,%rdx
  lea    (%rdx,%rcx,2),%r12
L90:
  lea    0x1(%rax),%r8
  mov    %r8,(%rsp)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L51
L7:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L1
  mov    (%rsp),%r8
L51:
  cmp    $0x5,%ebx
  jg     L118
  lea    (%r12,%r12,4),%rax
  lea    (%rax,%rax,1),%rdx
  je     L111
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  cmp    $0x4,%ebx
  je     L6
  imul   $0x3e8,%r12,%rax
  cmp    $0x3,%ebx
  je     L6
  imul   $0x2710,%r12,%rdx
  lea    0x4(%rbx),%eax
  cmp    $0x2,%ebx
  je     L111
  imul   $0x186a0,%r12,%rdx
  cmp    $0x4,%eax
  jne    L111
  imul   $0xf4240,%r12,%r12
  jmp    L118
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rax,%r12
  jmp    L118
  nopl   0x0(%rax,%rax,1)
L111:
  mov    %rdx,%r12
  jmp    L118
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtotimeval(const char *str, struct timeval *ts) {
  int n;
  char *s, *s0;
  long fs;
  ts->tv_sec = strtoumax(str, &s, 10);
  fs = 0;
  if (*s == '.') {
    int count;
    s0 = s + 1;
    fs = 0;
    count = 0;
    while (*s && isdigit(*s)) {
      if (++count < 7)
        fs = fs * 10 + (*s - '0');
      s++;
    }
    for (; count < 6; count++)
      fs *= 10;
  }
  ts->tv_usec = fs;
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_bin2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  add    %edx,%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sprintf@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string

tool: D9: %02X

assistant: ```c
void hash_bin2hex(unsigned char *bin, unsigned char *hex, int len) {
  for (int i = 0; i < len; i++) {
    sprintf(hex + 2 * i, "%02X", bin[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_bin2hex>:
  endbr64
  test   %edx,%edx
  jle    L5
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x2(%rsi,%rax,2),%r13
  lea    D4(%rip),%r12
L9:
  movzbl 0x0(%rbp),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x1,%rbp
  add    $0x2,%rbx
  cmp    %r13,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: %02X

assistant: ```c
void hash_bin2hex(unsigned char *bin, unsigned char *hex, int len) {
  for (int i = 0; i < len; i++) {
    sprintf(hex + 2 * i, "%02X", bin[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash_bin2hex>:
  endbr64
  test   %edx,%edx
  jle    L10
  push   %r13
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x2(%rsi,%rax,2),%r13
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x2,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r13,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: %02X

assistant: ```c
void hash_bin2hex(unsigned char *bin, unsigned char *hex, int len) {
  for (int i = 0; i < len; i++) {
    sprintf(hex + 2 * i, "%02X", bin[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_bin2hex>:
  endbr64
  test   %edx,%edx
  jle    L0
  push   %r13
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x2(%rsi,%rax,2),%r13
  lea    D0(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L10:
  movzbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x2,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r13,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: %02X

assistant: ```c
void hash_bin2hex(unsigned char *bin, unsigned char *hex, int len) {
  for (int i = 0; i < len; i++) {
    sprintf(hex + 2 * i, "%02X", bin[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<of_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void of_free(void *ptr) {
  if (ptr) {
    free(ptr);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<of_free>:
  endbr64
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L1:
  ret
```

assistant: ```c
void of_free(void *ptr) {
  if (ptr) {
    free(ptr);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<of_free>:
  endbr64
  test   %rdi,%rdi
  je     L8
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void of_free(void *ptr) {
  if (ptr) {
    free(ptr);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<of_free>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L0:
  ret
```

assistant: ```c
void of_free(void *ptr) {
  if (ptr) {
    free(ptr);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reallocarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <size_multiply_overflow@plt>
  test   %rax,%rax
  je     L25
  mov    $0x0,%eax
  jmp    L27
L25:
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  test   %rax,%rax
  je     L14
  mov    %eax,%edx
  jmp    L7
L14:
  mov    $0x1,%edx
L7:
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
L27:
  leave
  ret
```

assistant: ```c
__attribute__((__alloc_size__(2, 3))) void *reallocarray(void *p, size_t need, size_t size) {
  if (size_multiply_overflow(size, need))
    return NULL;
  return realloc(p, size * need ?: 1);
}
```