ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_linedel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x2028(%rbp)
  mov    %esi,-0x202c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2028(%rbp),%rax
  mov    %rax,-0x2018(%rbp)
  movl   $0x1,-0x2020(%rbp)
  movl   $0x0,-0x201c(%rbp)
  movb   $0x0,-0x2010(%rbp)
  jmp    L75
L21:
  mov    -0x2020(%rbp),%eax
  cmp    -0x202c(%rbp),%eax
  je     L0
  mov    -0x201c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x201c(%rbp)
  mov    -0x2018(%rbp),%rdx
  movzbl (%rdx),%edx
  cltq
  mov    %dl,-0x2010(%rbp,%rax,1)
L0:
  mov    -0x2018(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L7
  mov    -0x2018(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L25
  mov    -0x2020(%rbp),%eax
  cmp    -0x202c(%rbp),%eax
  je     L17
  addq   $0x1,-0x2018(%rbp)
  mov    -0x201c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x201c(%rbp)
  mov    -0x2018(%rbp),%rdx
  movzbl (%rdx),%edx
  cltq
  mov    %dl,-0x2010(%rbp,%rax,1)
  jmp    L25
L17:
  addq   $0x1,-0x2018(%rbp)
L25:
  addl   $0x1,-0x2020(%rbp)
L7:
  addq   $0x1,-0x2018(%rbp)
L75:
  mov    -0x2018(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  mov    -0x201c(%rbp),%eax
  cltq
  movb   $0x0,-0x2010(%rbp,%rax,1)
  mov    -0x2028(%rbp),%rax
  mov    %rax,%rdi
  call   <free_string@plt>
  lea    -0x2010(%rbp),%rax
  mov    %rax,%rdi
  call   <str_dup@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
char *string_linedel(char *string, int line) {
  char *strtmp = string;
  char buf[8192];
  int cnt = 1, tmp = 0;
  buf[0] = '\0';
  for (; *strtmp != '\0'; strtmp++) {
    if (cnt != line)
      buf[tmp++] = *strtmp;
    if (*strtmp == '\n') {
      if (*(strtmp + 1) == '\r') {
        if (cnt != line)
          buf[tmp++] = *(++strtmp);
        else
          ++strtmp;
      }
      cnt++;
    }
  }
  buf[tmp] = '\0';
  free_string(string);
  return str_dup(buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_linedel>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsp)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  mov    %rdi,%rcx
  mov    $0x0,%r8d
  mov    $0x1,%r9d
  jmp    L65
L61:
  add    $0x1,%rcx
L48:
  add    $0x1,%r9d
  mov    %rcx,%rdx
L2:
  lea    0x1(%rdx),%rcx
  movzbl 0x1(%rdx),%eax
  test   %al,%al
  je     L79
L65:
  cmp    %r9d,%esi
  je     L87
  movslq %r8d,%rdx
  mov    %al,(%rsp,%rdx,1)
  lea    0x1(%r8),%r8d
L87:
  mov    %rcx,%rdx
  cmp    $0xa,%al
  jne    L2
  cmpb   $0xd,0x1(%rcx)
  jne    L48
  cmp    %r9d,%esi
  je     L61
  add    $0x1,%rcx
  movslq %r8d,%rax
  movb   $0xd,(%rsp,%rax,1)
  lea    0x1(%r8),%r8d
  jmp    L48
L16:
  mov    $0x0,%r8d
L79:
  movslq %r8d,%r8
  movb   $0x0,(%rsp,%r8,1)
  call   <free_string@plt>
  mov    %rsp,%rdi
  call   <str_dup@plt>
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x2018,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *string_linedel(char *string, int line) {
  char *strtmp = string;
  char buf[8192];
  int cnt = 1, tmp = 0;
  buf[0] = '\0';
  for (; *strtmp != '\0'; strtmp++) {
    if (cnt != line)
      buf[tmp++] = *strtmp;
    if (*strtmp == '\n') {
      if (*(strtmp + 1) == '\r') {
        if (cnt != line)
          buf[tmp++] = *(++strtmp);
        else
          ++strtmp;
      }
      cnt++;
    }
  }
  buf[tmp] = '\0';
  free_string(string);
  return str_dup(buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<string_linedel>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  movzbl (%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsp)
  test   %cl,%cl
  je     L98
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  mov    $0x1,%r10d
  jmp    L12
L71:
  mov    %eax,%ecx
  mov    %r9,%rdx
  test   %al,%al
  je     L62
L12:
  cmp    %r10d,%esi
  je     L17
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %cl,(%rsp,%rax,1)
L17:
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%r9
  cmp    $0xa,%cl
  jne    L71
  cmp    $0xd,%al
  je     L106
L54:
  add    $0x1,%r10d
  mov    %eax,%ecx
  mov    %r9,%rdx
  test   %al,%al
  jne    L12
L62:
  movslq %r8d,%r8
  movb   $0x0,(%rsp,%r8,1)
  call   <free_string@plt>
  mov    %rsp,%rdi
  call   <str_dup@plt>
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x2018,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L106:
  movzbl 0x2(%rdx),%eax
  lea    0x2(%rdx),%r9
  cmp    %r10d,%esi
  je     L54
  movslq %r8d,%rcx
  add    $0x1,%r8d
  movb   $0xd,(%rsp,%rcx,1)
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L98:
  xor    %r8d,%r8d
  jmp    L62
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *string_linedel(char *string, int line) {
  char *strtmp = string;
  char buf[8192];
  int cnt = 1, tmp = 0;
  buf[0] = '\0';
  for (; *strtmp != '\0'; strtmp++) {
    if (cnt != line)
      buf[tmp++] = *strtmp;
    if (*strtmp == '\n') {
      if (*(strtmp + 1) == '\r') {
        if (cnt != line)
          buf[tmp++] = *(++strtmp);
        else
          ++strtmp;
      }
      cnt++;
    }
  }
  buf[tmp] = '\0';
  free_string(string);
  return str_dup(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_linedel>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  movzbl (%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsp)
  test   %cl,%cl
  je     L78
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  mov    $0x1,%r10d
  jmp    L27
L68:
  mov    %eax,%ecx
  mov    %r9,%rdx
  test   %al,%al
  je     L14
L27:
  cmp    %r10d,%esi
  je     L39
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %cl,(%rsp,%rax,1)
L39:
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%r9
  cmp    $0xa,%cl
  jne    L68
  cmp    $0xd,%al
  je     L36
L83:
  add    $0x1,%r10d
  mov    %eax,%ecx
  mov    %r9,%rdx
  test   %al,%al
  jne    L27
L14:
  movslq %r8d,%r8
  movb   $0x0,(%rsp,%r8,1)
  call   <free_string@plt>
  mov    %rsp,%rdi
  call   <str_dup@plt>
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L109
  add    $0x2018,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L36:
  movzbl 0x2(%rdx),%eax
  lea    0x2(%rdx),%r9
  cmp    %r10d,%esi
  je     L83
  movslq %r8d,%rcx
  add    $0x1,%r8d
  movb   $0xd,(%rsp,%rcx,1)
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L78:
  xor    %r8d,%r8d
  jmp    L14
L109:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *string_linedel(char *string, int line) {
  char *strtmp = string;
  char buf[8192];
  int cnt = 1, tmp = 0;
  buf[0] = '\0';
  for (; *strtmp != '\0'; strtmp++) {
    if (cnt != line)
      buf[tmp++] = *strtmp;
    if (*strtmp == '\n') {
      if (*(strtmp + 1) == '\r') {
        if (cnt != line)
          buf[tmp++] = *(++strtmp);
        else
          ++strtmp;
      }
      cnt++;
    }
  }
  buf[tmp] = '\0';
  free_string(string);
  return str_dup(buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dec_brightness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <get_brightness@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jle    L3
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  jmp    L4
L3:
  mov    $0x0,%eax
L4:
  mov    %eax,%edi
  call   <set_brightness@plt>
  nop
  leave
  ret
```

assistant: ```c
void dec_brightness() {
  int brightness = get_brightness();
  set_brightness(brightness <= 2 ? 0 : brightness / 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dec_brightness>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_brightness@plt>
  mov    $0x0,%edi
  cmp    $0x2,%eax
  jle    L1
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
L1:
  call   <set_brightness@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dec_brightness() {
  int brightness = get_brightness();
  set_brightness(brightness <= 2 ? 0 : brightness / 2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dec_brightness>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_brightness@plt>
  mov    %eax,%edi
  sar    %edi
  cmp    $0x2,%eax
  mov    $0x0,%eax
  cmovle %eax,%edi
  add    $0x8,%rsp
  jmp    1070 <set_brightness@plt>
```

assistant: ```c
void dec_brightness() {
  int brightness = get_brightness();
  set_brightness(brightness <= 2 ? 0 : brightness / 2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dec_brightness>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_brightness@plt>
  mov    %eax,%edi
  sar    %edi
  cmp    $0x2,%eax
  mov    $0x0,%eax
  cmovle %eax,%edi
  add    $0x8,%rsp
  jmp    1070 <set_brightness@plt>
```

assistant: ```c
void dec_brightness() {
  int brightness = get_brightness();
  set_brightness(brightness <= 2 ? 0 : brightness / 2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<KeccakP200_OverwriteBytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  cmpl   $0x18,-0x14(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cmp    $0x19,%eax
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void KeccakP200_OverwriteBytes(void *state, const unsigned char *data, unsigned int offset, unsigned int length) {
  assert(offset < 25);
  assert(offset + length <= 25);
  memcpy((unsigned char *)state + offset, data, length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<KeccakP200_OverwriteBytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %ecx,%r12d
  cmp    $0x18,%edx
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    (%rbx,%r12,1),%eax
  cmp    $0x19,%eax
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%ebx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void KeccakP200_OverwriteBytes(void *state, const unsigned char *data, unsigned int offset, unsigned int length) {
  assert(offset < 25);
  assert(offset + length <= 25);
  memcpy((unsigned char *)state + offset, data, length);
}
```
user: What is the c source code of the assembly code below?

```asm
<KeccakP200_OverwriteBytes>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    $0x18,%ebx
  setbe  %dil
  call   <assert@plt>
  lea    (%rbx,%r12,1),%eax
  xor    %edi,%edi
  cmp    $0x19,%eax
  setbe  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %r13,%rsi
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <memcpy@plt>
```

assistant: ```c
void KeccakP200_OverwriteBytes(void *state, const unsigned char *data, unsigned int offset, unsigned int length) {
  assert(offset < 25);
  assert(offset + length <= 25);
  memcpy((unsigned char *)state + offset, data, length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<KeccakP200_OverwriteBytes>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    $0x18,%ebx
  setbe  %dil
  call   <assert@plt>
  lea    (%rbx,%r12,1),%eax
  xor    %edi,%edi
  cmp    $0x19,%eax
  setbe  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %r13,%rsi
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <memcpy@plt>
```

assistant: ```c
void KeccakP200_OverwriteBytes(void *state, const unsigned char *data, unsigned int offset, unsigned int length) {
  assert(offset < 25);
  assert(offset + length <= 25);
  memcpy((unsigned char *)state + offset, data, length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rsock_udp_optname_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x4,-0x10(%rbp)
  je     L44
  cmpq   $0x8,-0x10(%rbp)
  je     L2
  jmp    L6
L44:
  mov    $0xffffffff,%eax
  jmp    L39
L2:
  mov    $0xffffffff,%eax
  jmp    L39
L6:
  mov    $0xffffffff,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int rsock_udp_optname_to_int(const char *str, long len, int *valp) {
  switch (len) {
  case 4:
    return -1;
  case 8:
    return -1;
  default:
    if (!str || !valp) {
    }
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rsock_udp_optname_to_int>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rsock_udp_optname_to_int(const char *str, long len, int *valp) {
  switch (len) {
  case 4:
    return -1;
  case 8:
    return -1;
  default:
    if (!str || !valp) {
    }
    return -1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rsock_udp_optname_to_int>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rsock_udp_optname_to_int(const char *str, long len, int *valp) {
  switch (len) {
  case 4:
    return -1;
  case 8:
    return -1;
  default:
    if (!str || !valp) {
    }
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rsock_udp_optname_to_int>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rsock_udp_optname_to_int(const char *str, long len, int *valp) {
  switch (len) {
  case 4:
    return -1;
  case 8:
    return -1;
  default:
    if (!str || !valp) {
    }
    return -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  movl   $0x1,-0x60(%rbp)
  movss  D36(%rip),%xmm0
  movss  %xmm0,-0x5c(%rbp)
  movl   $0xc,-0x58(%rbp)
  movl   $0x64,-0x50(%rbp)
  movss  D22(%rip),%xmm0
  movss  %xmm0,-0x4c(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movss  D21(%rip),%xmm0
  movss  %xmm0,-0x40(%rbp)
  movl   $0x62a,-0x3c(%rbp)
  mov    -0x60(%rbp),%rax
  mov    -0x58(%rbp),%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
data_type: f32
name: extract_symbolic_data
arguments: data_label: D22
data_type: f32
name: extract_symbolic_data
arguments: data_label: D10
data_type: f64
name: extract_symbolic_data
arguments: data_label: D21
data_type: byte[4]

tool: D36: 1.3

tool: D22: 1.45

tool: D10: 45.85

tool: {"D21": [0xc0,0x78,0x11,0x48]}

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    float b;
    int c;
    struct {
      int e;
      float f;
      double g;
      struct {
        float i;
      } h;
      int j;
    } d;
  } x, y;
  x.a = 1;
  x.b = 1.3;
  x.c = 12;
  x.d.e = 100;
  x.d.f = 1.45;
  x.d.g = 45.85;
  x.d.h.i = 148963;
  x.d.j = 1578;
  y = x;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    float b;
    int c;
    struct {
      int e;
      float f;
      double g;
      struct {
        float i;
      } h;
      int j;
    } d;
  } x, y;
  x.a = 1;
  x.b = 1.3;
  x.c = 12;
  x.d.e = 100;
  x.d.f = 1.45;
  x.d.g = 45.85;
  x.d.h.i = 148963;
  x.d.j = 1578;
  y = x;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    float b;
    int c;
    struct {
      int e;
      float f;
      double g;
      struct {
        float i;
      } h;
      int j;
    } d;
  } x, y;
  x.a = 1;
  x.b = 1.3;
  x.c = 12;
  x.d.e = 100;
  x.d.f = 1.45;
  x.d.g = 45.85;
  x.d.h.i = 148963;
  x.d.j = 1578;
  y = x;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    float b;
    int c;
    struct {
      int e;
      float f;
      double g;
      struct {
        float i;
      } h;
      int j;
    } d;
  } x, y;
  x.a = 1;
  x.b = 1.3;
  x.c = 12;
  x.d.e = 100;
  x.d.f = 1.45;
  x.d.g = 45.85;
  x.d.h.i = 148963;
  x.d.j = 1578;
  y = x;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<set_16_be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_16_be(uint8_t *const p, const unsigned int x) {
  p[0] = (x >> 8) & 0xff;
  p[1] = x & 0xff;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<set_16_be>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  mov    %edx,(%rdi)
  and    $0xff,%eax
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void set_16_be(uint8_t *const p, const unsigned int x) {
  p[0] = (x >> 8) & 0xff;
  p[1] = x & 0xff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_16_be>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,(%rdi)
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void set_16_be(uint8_t *const p, const unsigned int x) {
  p[0] = (x >> 8) & 0xff;
  p[1] = x & 0xff;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<set_16_be>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,(%rdi)
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void set_16_be(uint8_t *const p, const unsigned int x) {
  p[0] = (x >> 8) & 0xff;
  p[1] = x & 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<searchSolutions>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x18(%rsp)
  mov    %rsi,%r12
  mov    $0x0,%r13d
  movl   $0x0,0x10(%rsp)
  lea    0x20(%rsp),%rbp
  mov    $0x1,%r15d
  jmp    L11
L3:
  add    $0x1,%rcx
  cmp    $0xa,%rcx
  je     L0
L52:
  cmpl   $0x0,-0x4(%rbp,%rcx,4)
  jne    L3
  mov    %r15d,%eax
  shl    %cl,%eax
  add    %eax,(%r12,%rbx,4)
  add    $0x1,%r13d
  jmp    L3
L0:
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  je     L30
L51:
  mov    %ebx,0x4(%rsp)
  cmpl   $0x0,(%r14,%rbx,4)
  jg     L0
  mov    $0x0,%edx
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <initArray@plt>
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <elementsInColumn@plt>
  mov    0x10(%rsp),%edx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <elementsInLine@plt>
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    0x14(%rsp),%edx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <elementsInRegion@plt>
  mov    $0x1,%ecx
  jmp    L52
L30:
  addl   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%eax
  addq   $0x24,0x18(%rsp)
  add    $0x24,%r12
  cmp    $0x9,%eax
  je     L92
L11:
  mov    0x18(%rsp),%r14
  mov    0x10(%rsp),%esi
  movslq %esi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,2),%eax
  mov    %eax,0x14(%rsp)
  mov    $0x0,%ebx
  jmp    L51
L92:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    %r13d,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int searchSolutions(int sudoku[9][9], int solutions[9][9]) {
  int i, j;
  int solutionsCount = 0;
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      if (sudoku[i][j] > 0)
        continue;
      int seen[9];
      initArray(seen, 9, 0);
      elementsInColumn(seen, sudoku, j);
      elementsInLine(seen, sudoku, i);
      elementsInRegion(seen, sudoku, i - (i % (9 / 3)), j - (j % (9 / 3)));
      int k = 0;
      for (k = 0; k < 9; k++) {
        if (seen[k] == 0) {
          solutions[i][j] += 1 << k + 1;
          solutionsCount++;
        }
      }
    }
  }
  return solutionsCount;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<searchSolutions>:
  endbr64
  push   %r15
  mov    %rdi,%r9
  mov    %rsi,%r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    %r12d,%eax
  mov    $0xaaaaaaab,%esi
  xor    %ebx,%ebx
  imul   %rsi,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  mov    %eax,0xc(%rsp)
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  je     L10
L61:
  mov    (%r9,%rbx,4),%edx
  test   %edx,%edx
  jg     L43
  xor    %edx,%edx
  mov    $0x9,%esi
  mov    %r14,%rdi
  mov    %r9,(%rsp)
  mov    %ebx,0x8(%rsp)
  call   <initArray@plt>
  mov    0x8(%rsp),%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <elementsInColumn@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <elementsInLine@plt>
  mov    $0xaaaaaaab,%edx
  mov    %ebx,%eax
  mov    %rbp,%rsi
  imul   %rdx,%rax
  mov    0xc(%rsp),%edx
  mov    %r14,%rdi
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%ecx
  call   <elementsInRegion@plt>
  mov    (%rsp),%r9
  mov    $0x1,%ecx
  mov    $0x1,%r10d
  nopw   0x0(%rax,%rax,1)
L34:
  mov    -0x4(%r14,%rcx,4),%eax
  test   %eax,%eax
  jne    L48
  mov    %r10d,%eax
  add    $0x1,%r13d
  shl    %cl,%eax
  add    %eax,(%r15,%rbx,4)
L48:
  add    $0x1,%rcx
  cmp    $0xa,%rcx
  jne    L34
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  jne    L61
L10:
  add    $0x1,%r12d
  add    $0x24,%r9
  add    $0x24,%r15
  cmp    $0x9,%r12d
  jne    L56
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x48,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int searchSolutions(int sudoku[9][9], int solutions[9][9]) {
  int i, j;
  int solutionsCount = 0;
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      if (sudoku[i][j] > 0)
        continue;
      int seen[9];
      initArray(seen, 9, 0);
      elementsInColumn(seen, sudoku, j);
      elementsInLine(seen, sudoku, i);
      elementsInRegion(seen, sudoku, i - (i % (9 / 3)), j - (j % (9 / 3)));
      int k = 0;
      for (k = 0; k < 9; k++) {
        if (seen[k] == 0) {
          solutions[i][j] += 1 << k + 1;
          solutionsCount++;
        }
      }
    }
  }
  return solutionsCount;
}
```