ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<cal_cksum>:
  endbr64
  mov    $0x0,%r8d
  cmp    $0x1,%esi
  jle    L8
  lea    -0x2(%rsi),%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,2),%rdx
  mov    $0x0,%eax
L43:
  add    $0x2,%rdi
  add    -0x2(%rdi),%ax
  cmp    %rdx,%rdi
  jne    L43
  neg    %ecx
  lea    -0x2(%rsi,%rcx,2),%esi
L26:
  cmp    $0x1,%esi
  je     L24
L22:
  not    %eax
  ret
L8:
  mov    %rdi,%rdx
  mov    $0x0,%eax
  jmp    L26
L24:
  mov    (%rdx),%r8b
  add    %r8d,%eax
  jmp    L22
```

assistant: ```c
unsigned short cal_cksum(unsigned short *addr, int len) {
  int nleft = len;
  uint32_t sum = 0;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cal_cksum>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L9
  sub    $0x2,%esi
  mov    %esi,%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,2),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  add    $0x2,%rdi
  add    -0x2(%rdi),%ax
  cmp    %rdx,%rdi
  jne    L8
  neg    %ecx
  lea    (%rsi,%rcx,2),%esi
L5:
  cmp    $0x1,%esi
  jne    L39
  mov    (%rdx),%r8b
  add    %r8d,%eax
L39:
  not    %eax
  ret
L9:
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
unsigned short cal_cksum(unsigned short *addr, int len) {
  int nleft = len;
  uint32_t sum = 0;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cal_cksum>:
  endbr64
  mov    %rdi,%rdx
  xor    %r10d,%r10d
  cmp    $0x1,%esi
  jle    L9
  lea    -0x2(%rsi),%r9d
  mov    %r9d,%r11d
  shr    %r11d
  lea    0x1(%r11),%ecx
  cmp    $0xd,%r9d
  jbe    L78
  mov    %rdi,%rax
  mov    %ecx,%edi
  pxor   %xmm0,%xmm0
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopl   0x0(%rax,%rax,1)
L61:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddw  %xmm2,%xmm0
  cmp    %rdi,%rax
  jne    L61
  movdqa %xmm0,%xmm1
  mov    %ecx,%r8d
  psrldq $0x8,%xmm1
  and    $0xfffffff8,%r8d
  paddw  %xmm1,%xmm0
  mov    %r8d,%edi
  movdqa %xmm0,%xmm1
  neg    %edi
  psrldq $0x4,%xmm1
  lea    (%rsi,%rdi,2),%esi
  mov    %r8d,%edi
  paddw  %xmm1,%xmm0
  lea    (%rdx,%rdi,2),%rdi
  movdqa %xmm0,%xmm1
  psrldq $0x2,%xmm1
  paddw  %xmm1,%xmm0
  pextrw $0x0,%xmm0,%eax
  cmp    %r8d,%ecx
  je     L1
L98:
  lea    -0x2(%rsi),%r8d
  add    (%rdi),%ax
  cmp    $0x1,%r8d
  jle    L1
  lea    -0x4(%rsi),%r8d
  add    0x2(%rdi),%ax
  cmp    $0x1,%r8d
  jle    L1
  lea    -0x6(%rsi),%r8d
  add    0x4(%rdi),%ax
  cmp    $0x1,%r8d
  jle    L1
  lea    -0x8(%rsi),%r8d
  add    0x6(%rdi),%ax
  cmp    $0x1,%r8d
  jle    L1
  lea    -0xa(%rsi),%r8d
  add    0x8(%rdi),%ax
  cmp    $0x1,%r8d
  jle    L1
  add    0xa(%rdi),%ax
  cmp    $0xd,%esi
  jle    L1
  add    0xc(%rdi),%ax
L1:
  mov    %ecx,%esi
  mov    %r11d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r9,%rcx,2),%esi
L94:
  cmp    $0x1,%esi
  jne    L120
  mov    (%rdx),%r10b
  add    %r10d,%eax
L120:
  not    %eax
  ret
  nop
L9:
  xor    %eax,%eax
  jmp    L94
L78:
  xor    %eax,%eax
  jmp    L98
```

assistant: ```c
unsigned short cal_cksum(unsigned short *addr, int len) {
  int nleft = len;
  uint32_t sum = 0;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<realloc_no_free_bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <realloc_wrapper@plt>
  mov    %rax,-0x8(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void realloc_no_free_bad() {
  int *p = (int *)malloc(sizeof(int));
  int *q = realloc_wrapper(p, sizeof(int));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<realloc_no_free_bad>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x4,%esi
  call   <realloc_wrapper@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void realloc_no_free_bad() {
  int *p = (int *)malloc(sizeof(int));
  int *q = realloc_wrapper(p, sizeof(int));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<realloc_no_free_bad>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    $0x4,%esi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <realloc_wrapper@plt>
```

assistant: ```c
void realloc_no_free_bad() {
  int *p = (int *)malloc(sizeof(int));
  int *q = realloc_wrapper(p, sizeof(int));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<realloc_no_free_bad>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    $0x4,%esi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <realloc_wrapper@plt>
```

assistant: ```c
void realloc_no_free_bad() {
  int *p = (int *)malloc(sizeof(int));
  int *q = realloc_wrapper(p, sizeof(int));
}
```
user: Translate the below assembly code into C programming language:

```asm
<iterative_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L17
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x64,-0x4(%rbp)
  jle    L4
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: Iterative count : %d 


assistant: ```c
void iterative_count(int x) {
  while (x <= 100) {
    printf("Iterative count : %d \n", x);
    x++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<iterative_count>:
  endbr64
  cmp    $0x64,%edi
  jg     L17
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    D2(%rip),%rbp
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D2: Iterative count : %d 


assistant: ```c
void iterative_count(int x) {
  while (x <= 100) {
    printf("Iterative count : %d \n", x);
    x++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iterative_count>:
  endbr64
  cmp    $0x64,%edi
  jg     L13
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x65,%ebx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L13:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D6: Iterative count : %d 


assistant: ```c
void iterative_count(int x) {
  while (x <= 100) {
    printf("Iterative count : %d \n", x);
    x++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iterative_count>:
  endbr64
  cmp    $0x64,%edi
  jg     L0
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x65,%ebx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string

tool: D2: Iterative count : %d 


assistant: ```c
void iterative_count(int x) {
  while (x <= 100) {
    printf("Iterative count : %d \n", x);
    x++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x64,-0x20(%rbp)
  jmp    L25
L48:
  movl   $0x64,-0x1c(%rbp)
  jmp    L4
L14:
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <revStr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L29
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  addl   $0x1,-0x1c(%rbp)
L4:
  cmpl   $0x3e7,-0x1c(%rbp)
  jle    L14
  addl   $0x1,-0x20(%rbp)
L25:
  cmpl   $0x3e7,-0x20(%rbp)
  jle    L48
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D18
type: string

tool: D2: %d

tool: D18: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  for (int x = 100; x < 1000; x++) {
    for (int y = 100; y < 1000; y++) {
      int z = x * y;
      char *zStr;
      sprintf(zStr, "%d", z);
      char *zRev = revStr(zStr);
      int zRevInt = atoi(zRev);
      if (z == zRevInt) {
        printf("%d\n", zRevInt);
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x64,0xc(%rsp)
  lea    D10(%rip),%r14
  lea    D0(%rip),%r15
  jmp    L12
L16:
  add    %r13d,%ebx
  sub    $0x1,%ebp
  je     L21
L56:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    $0x0,%r12d
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <revStr@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  cmp    %eax,%ebx
  jne    L16
  mov    %eax,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L16
L21:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0x3e8,%eax
  je     L31
L12:
  mov    0xc(%rsp),%eax
  mov    %eax,%r13d
  imul   $0x64,%eax,%ebx
  mov    $0x384,%ebp
  jmp    L56
L31:
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D10: %d

tool: D0: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  for (int x = 100; x < 1000; x++) {
    for (int y = 100; y < 1000; y++) {
      int z = x * y;
      char *zStr;
      sprintf(zStr, "%d", z);
      char *zRev = revStr(zStr);
      int zRevInt = atoi(zRev);
      if (z == zRevInt) {
        printf("%d\n", zRevInt);
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  mov    $0x64,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L27:
  imul   $0x64,%r12d,%ebx
  mov    $0x384,%ebp
  jmp    L37
  nopl   0x0(%rax)
L35:
  add    %r12d,%ebx
  sub    $0x1,%ebp
  je     L17
L37:
  xor    %r15d,%r15d
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <revStr@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  cmp    %eax,%ebx
  jne    L35
  mov    %ebx,%esi
  mov    %r14,%rdi
  add    %r12d,%ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L37
L17:
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  jne    L27
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type_guessed: string
name: read_data
arguments: data_tag: D19
type_guessed: string

tool: D14: %d


tool: D19: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  for (int x = 100; x < 1000; x++) {
    for (int y = 100; y < 1000; y++) {
      int z = x * y;
      char *zStr;
      sprintf(zStr, "%d", z);
      char *zRev = revStr(zStr);
      int zRevInt = atoi(zRev);
      if (z == zRevInt) {
        printf("%d\n", zRevInt);
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  mov    $0x64,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L2:
  imul   $0x64,%r12d,%ebx
  mov    $0x384,%ebp
  jmp    L37
  nopl   0x0(%rax)
L42:
  add    %r12d,%ebx
  sub    $0x1,%ebp
  je     L28
L37:
  xor    %r15d,%r15d
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <revStr@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  cmp    %eax,%ebx
  jne    L42
  mov    %ebx,%esi
  mov    %r14,%rdi
  add    %r12d,%ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L37
L28:
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string

tool: D19: %d


tool: D16: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  for (int x = 100; x < 1000; x++) {
    for (int y = 100; y < 1000; y++) {
      int z = x * y;
      char *zStr;
      sprintf(zStr, "%d", z);
      char *zRev = revStr(zStr);
      int zRevInt = atoi(zRev);
      if (z == zRevInt) {
        printf("%d\n", zRevInt);
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<qd_mul_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,-0x68(%rbp)
  movsd  %xmm0,-0x70(%rbp)
  mov    %rsi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x48(%rbp),%rdx
  movsd  -0x70(%rbp),%xmm0
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dd_two_prod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x68(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x40(%rbp),%rdx
  movsd  -0x70(%rbp),%xmm0
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dd_two_prod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x68(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    -0x38(%rbp),%rdx
  movsd  -0x70(%rbp),%xmm0
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dd_two_prod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x68(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x70(%rbp),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x78(%rbp),%rax
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x78(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x48(%rbp),%rax
  mov    -0x78(%rbp),%rcx
  lea    0x8(%rcx),%rbx
  movsd  -0x20(%rbp),%xmm0
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dd_two_sum@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  mov    -0x78(%rbp),%rax
  lea    0x10(%rax),%rcx
  lea    -0x58(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <qd_three_sum@plt>
  lea    -0x50(%rbp),%rdx
  lea    -0x38(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <qd_three_sum2@plt>
  mov    -0x78(%rbp),%rax
  add    $0x18,%rax
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x38(%rbp),%xmm1
  movsd  -0x58(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x78(%rbp),%rax
  lea    0x18(%rax),%rcx
  mov    -0x78(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x78(%rbp),%rax
  lea    0x8(%rax),%rsi
  lea    -0x30(%rbp),%rdi
  mov    -0x78(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <qd_renorm5@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void qd_mul_d(const double *a, double b, double *c) {
  double p0, p1, p2, p3, q0, q1, q2, s4;
  p0 = dd_two_prod(a[0], b, &q0);
  p1 = dd_two_prod(a[1], b, &q1);
  p2 = dd_two_prod(a[2], b, &q2);
  p3 = a[3] * b;
  c[0] = p0;
  c[1] = dd_two_sum(q0, p1, &c[2]);
  qd_three_sum(&c[2], &q1, &p2);
  qd_three_sum2(&q1, &q2, &p3);
  c[3] = q1;
  s4 = q2 + p2;
  qd_renorm5(&c[0], &c[1], &c[2], &c[3], &s4);
}
```
user: Translate the below assembly code into C programming language:

```asm
<qd_mul_d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%r12
  movq   %xmm0,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rdi
  movapd %xmm0,%xmm1
  movsd  (%r12),%xmm0
  call   <dd_two_prod@plt>
  movsd  %xmm0,0x8(%rsp)
  lea    0x30(%rsp),%r13
  movsd  0x8(%r12),%xmm0
  mov    %r13,%rdi
  movq   %rbp,%xmm1
  call   <dd_two_prod@plt>
  movq   %xmm0,%r14
  lea    0x38(%rsp),%r15
  movsd  0x10(%r12),%xmm0
  mov    %r15,%rdi
  movq   %rbp,%xmm1
  call   <dd_two_prod@plt>
  movsd  %xmm0,0x18(%rsp)
  movq   %rbp,%xmm0
  mulsd  0x18(%r12),%xmm0
  movsd  %xmm0,0x20(%rsp)
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm2,(%rbx)
  lea    0x10(%rbx),%rbp
  mov    %rbp,%rdi
  movq   %r14,%xmm1
  movsd  0x28(%rsp),%xmm0
  call   <dd_two_sum@plt>
  movsd  %xmm0,0x8(%rbx)
  lea    0x18(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <qd_three_sum@plt>
  lea    0x20(%rsp),%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <qd_three_sum2@plt>
  movsd  0x30(%rsp),%xmm0
  movsd  %xmm0,0x18(%rbx)
  movsd  0x38(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x40(%rsp)
  lea    0x18(%rbx),%rcx
  lea    0x8(%rbx),%rsi
  lea    0x40(%rsp),%r8
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <qd_renorm5@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void qd_mul_d(const double *a, double b, double *c) {
  double p0, p1, p2, p3, q0, q1, q2, s4;
  p0 = dd_two_prod(a[0], b, &q0);
  p1 = dd_two_prod(a[1], b, &q1);
  p2 = dd_two_prod(a[2], b, &q2);
  p3 = a[3] * b;
  c[0] = p0;
  c[1] = dd_two_sum(q0, p1, &c[2]);
  qd_three_sum(&c[2], &q1, &p2);
  qd_three_sum2(&q1, &q2, &p3);
  c[3] = q1;
  s4 = q2 + p2;
  qd_renorm5(&c[0], &c[1], &c[2], &c[3], &s4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qd_mul_d>:
  endbr64
  push   %r14
  movapd %xmm0,%xmm1
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  movsd  (%rbx),%xmm0
  lea    0x28(%rsp),%rdi
  lea    0x30(%rsp),%r13
  lea    0x38(%rsp),%r14
  call   <dd_two_prod@plt>
  movsd  (%rsp),%xmm1
  mov    %r13,%rdi
  movq   %xmm0,%r12
  movsd  0x8(%rbx),%xmm0
  call   <dd_two_prod@plt>
  movsd  (%rsp),%xmm1
  mov    %r14,%rdi
  movsd  %xmm0,0x8(%rsp)
  movsd  0x10(%rbx),%xmm0
  call   <dd_two_prod@plt>
  movsd  (%rsp),%xmm1
  mulsd  0x18(%rbx),%xmm1
  mov    %r12,0x0(%rbp)
  movsd  0x8(%rsp),%xmm2
  lea    0x10(%rbp),%r12
  movsd  %xmm0,0x18(%rsp)
  movsd  0x28(%rsp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm1,0x20(%rsp)
  movapd %xmm2,%xmm1
  call   <dd_two_sum@plt>
  lea    0x18(%rsp),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rbp)
  call   <qd_three_sum@plt>
  lea    0x20(%rsp),%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <qd_three_sum2@plt>
  lea    0x18(%rbp),%rcx
  lea    0x8(%rbp),%rsi
  mov    %r12,%rdx
  movsd  0x30(%rsp),%xmm0
  lea    0x40(%rsp),%r8
  mov    %rbp,%rdi
  movsd  %xmm0,0x18(%rbp)
  movsd  0x38(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x40(%rsp)
  call   <qd_renorm5@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void qd_mul_d(const double *a, double b, double *c) {
  double p0, p1, p2, p3, q0, q1, q2, s4;
  p0 = dd_two_prod(a[0], b, &q0);
  p1 = dd_two_prod(a[1], b, &q1);
  p2 = dd_two_prod(a[2], b, &q2);
  p3 = a[3] * b;
  c[0] = p0;
  c[1] = dd_two_sum(q0, p1, &c[2]);
  qd_three_sum(&c[2], &q1, &p2);
  qd_three_sum2(&q1, &q2, &p3);
  c[3] = q1;
  s4 = q2 + p2;
  qd_renorm5(&c[0], &c[1], &c[2], &c[3], &s4);
}
```
user: What is the c source code of the assembly code below?

```asm
<qd_mul_d>:
  endbr64
  push   %r14
  movapd %xmm0,%xmm1
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  movsd  (%rbx),%xmm0
  lea    0x28(%rsp),%rdi
  lea    0x30(%rsp),%r13
  lea    0x38(%rsp),%r14
  call   <dd_two_prod@plt>
  movsd  (%rsp),%xmm1
  mov    %r13,%rdi
  movq   %xmm0,%r12
  movsd  0x8(%rbx),%xmm0
  call   <dd_two_prod@plt>
  movsd  (%rsp),%xmm1
  mov    %r14,%rdi
  movsd  %xmm0,0x8(%rsp)
  movsd  0x10(%rbx),%xmm0
  call   <dd_two_prod@plt>
  movsd  (%rsp),%xmm1
  mulsd  0x18(%rbx),%xmm1
  mov    %r12,0x0(%rbp)
  movsd  0x8(%rsp),%xmm2
  lea    0x10(%rbp),%r12
  movsd  %xmm0,0x18(%rsp)
  movsd  0x28(%rsp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm1,0x20(%rsp)
  movapd %xmm2,%xmm1
  call   <dd_two_sum@plt>
  lea    0x18(%rsp),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rbp)
  call   <qd_three_sum@plt>
  lea    0x20(%rsp),%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <qd_three_sum2@plt>
  lea    0x18(%rbp),%rcx
  lea    0x8(%rbp),%rsi
  mov    %r12,%rdx
  movsd  0x30(%rsp),%xmm0
  lea    0x40(%rsp),%r8
  mov    %rbp,%rdi
  movsd  %xmm0,0x18(%rbp)
  movsd  0x38(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x40(%rsp)
  call   <qd_renorm5@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void qd_mul_d(const double *a, double b, double *c) {
  double p0, p1, p2, p3, q0, q1, q2, s4;
  p0 = dd_two_prod(a[0], b, &q0);
  p1 = dd_two_prod(a[1], b, &q1);
  p2 = dd_two_prod(a[2], b, &q2);
  p3 = a[3] * b;
  c[0] = p0;
  c[1] = dd_two_sum(q0, p1, &c[2]);
  qd_three_sum(&c[2], &q1, &p2);
  qd_three_sum2(&q1, &q2, &p3);
  c[3] = q1;
  s4 = q2 + p2;
  qd_renorm5(&c[0], &c[1], &c[2], &c[3], &s4);
}
```