ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%edx
  test   %dl,%dl
  je     L63
  mov    $0x0,%eax
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    $0x0,%r8d
  jmp    L35
L2:
  add    $0x1,%r8d
L84:
  cmp    %esi,%r8d
  cmove  %edi,%ecx
  add    $0x1,%rax
  movzbl (%rsp,%rax,1),%edx
  test   %dl,%dl
  je     L0
L35:
  mov    %eax,%edi
  cmp    $0x30,%dl
  je     L2
  add    $0x1,%esi
  jmp    L84
L0:
  test   %ecx,%ecx
  jne    L93
  cmp    %esi,%r8d
  jge    L40
  mov    %r8d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L45:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L63:
  mov    $0x0,%esi
L40:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L45
L93:
  mov    %ecx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L45
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D18: %s

tool: D9: 
%d


assistant: ```c
int main() {
  char arr[100];
  scanf("%s", arr);
  int n0 = 0, n1 = 0, i = 0, max = 0;
  while (arr[i] != '\0') {
    arr[i] == '0' ? n0++ : n1++;
    if (n0 == n1)
      max = i;
    i++;
  }
  if (max == 0)
    if (n0 < n1)
      printf("\n%d\n", n0);
    else
      printf("\n%d\n", n1);
  else
    printf("\n%d\n", max);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D18(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  movzbl (%rsp),%edx
  test   %dl,%dl
  je     L23
  xor    %eax,%eax
  xor    %r8d,%r8d
  xor    %esi,%esi
  xor    %r9d,%r9d
  jmp    L17
  nop
L41:
  add    $0x1,%esi
L90:
  cmp    %esi,%r9d
  cmove  %ecx,%r8d
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L18
L17:
  mov    %eax,%ecx
  cmp    $0x30,%dl
  jne    L41
  add    $0x1,%r9d
  jmp    L90
  nopl   0x0(%rax,%rax,1)
L18:
  test   %r8d,%r8d
  jne    L80
  cmp    %esi,%r9d
  jge    L40
  mov    %r9d,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L83
L80:
  mov    %r8d,%esi
L40:
  lea    D16(%rip),%rdi
  call   <printf@plt>
L83:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L23:
  xor    %esi,%esi
  jmp    L40
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
data_type: string
name: extract_symbolic_data
arguments: data_label: D16
data_type: string

tool: D18: %s

tool: D16: 
%d


assistant: ```c
int main() {
  char arr[100];
  scanf("%s", arr);
  int n0 = 0, n1 = 0, i = 0, max = 0;
  while (arr[i] != '\0') {
    arr[i] == '0' ? n0++ : n1++;
    if (n0 == n1)
      max = i;
    i++;
  }
  if (max == 0)
    if (n0 < n1)
      printf("\n%d\n", n0);
    else
      printf("\n%d\n", n1);
  else
    printf("\n%d\n", max);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  movzbl (%rsp),%edx
  test   %dl,%dl
  je     L29
  xor    %eax,%eax
  xor    %r8d,%r8d
  xor    %esi,%esi
  xor    %r9d,%r9d
  jmp    L38
  nop
L89:
  add    $0x1,%esi
L37:
  cmp    %esi,%r9d
  cmove  %ecx,%r8d
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L85
L38:
  mov    %eax,%ecx
  cmp    $0x30,%dl
  jne    L89
  add    $0x1,%r9d
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L85:
  test   %r8d,%r8d
  jne    L9
  cmp    %esi,%r9d
  jge    L26
  mov    %r9d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L9:
  mov    %r8d,%esi
L26:
  lea    D4(%rip),%rdi
  call   <printf@plt>
L23:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L29:
  xor    %esi,%esi
  jmp    L26
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string

tool: D12: %s

tool: D4: 
%d


assistant: ```c
int main() {
  char arr[100];
  scanf("%s", arr);
  int n0 = 0, n1 = 0, i = 0, max = 0;
  while (arr[i] != '\0') {
    arr[i] == '0' ? n0++ : n1++;
    if (n0 == n1)
      max = i;
    i++;
  }
  if (max == 0)
    if (n0 < n1)
      printf("\n%d\n", n0);
    else
      printf("\n%d\n", n1);
  else
    printf("\n%d\n", max);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<si1133_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  mov    $0xb,%edi
  call   <si1133_write8@plt>
  mov    $0x64,%edi
  call   <SI1133_delay_msek@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void si1133_reset() {
  si1133_write8(0X0B, 0X01);
  SI1133_delay_msek(100);
}
```
user: Translate the below assembly code into C programming language:

```asm
<si1133_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xb,%edi
  call   <si1133_write8@plt>
  mov    $0x64,%edi
  call   <SI1133_delay_msek@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void si1133_reset() {
  si1133_write8(0X0B, 0X01);
  SI1133_delay_msek(100);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<si1133_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%edi
  mov    $0x1,%esi
  call   <si1133_write8@plt>
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1070 <SI1133_delay_msek@plt>
```

assistant: ```c
void si1133_reset() {
  si1133_write8(0X0B, 0X01);
  SI1133_delay_msek(100);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<si1133_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%edi
  mov    $0x1,%esi
  call   <si1133_write8@plt>
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1070 <SI1133_delay_msek@plt>
```

assistant: ```c
void si1133_reset() {
  si1133_write8(0X0B, 0X01);
  SI1133_delay_msek(100);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6767666765726673,%rax
  mov    %rax,-0x16(%rbp)
  movl   $0x68686868,-0xe(%rbp)
  movw   $0x66,-0xa(%rbp)
  movl   $0x68676766,-0x1b(%rbp)
  movb   $0x0,-0x17(%rbp)
  lea    -0x1b(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2c(%rbp)
  lea    -0x16(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x2c(%rbp),%ecx
  lea    -0x1b(%rbp),%rdx
  lea    -0x16(%rbp),%rax
  mov    %rax,%rdi
  call   <Horspool@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L5
  movl   $0x0,-0x30(%rbp)
  jmp    L42
L21:
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x30(%rbp)
L42:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L21
  jmp    L34
L5:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L34:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D26
data_type: string
name: retrieve_data
arguments: label: D28
data_type: string
name: retrieve_data
arguments: label: D9
data_type: string

tool: D26: %3c

tool: D28: no found

tool: D9: 

assistant: ```c
int main(void) {
  char str[] = "sfregfgghhhhf", pattern[] = "fggh";
  int i, len = strlen(pattern);
  char *p;
  p = Horspool(str, strlen(str), pattern, len);
  if (p) {
    for (i = 0; i < len; i++) {
      printf("%3c", *(p + i));
    }
  } else {
    printf("no found\r\n");
  }
  printf("\r\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6767666765726673,%rax
  mov    %rax,0xa(%rsp)
  movl   $0x68686868,0x12(%rsp)
  movw   $0x66,0x16(%rsp)
  movl   $0x68676766,0x5(%rsp)
  movb   $0x0,0x9(%rsp)
  lea    0x5(%rsp),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0xa(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <Horspool@plt>
  test   %rax,%rax
  je     L14
  test   %ebp,%ebp
  jle    L2
  mov    %rax,%rbx
  lea    -0x1(%rbp),%edx
  lea    0x1(%rax,%rdx,1),%r12
  lea    D24(%rip),%rbp
L9:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L9
L2:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L2
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D24
type: string
name: retrieve_data
arguments: data_label: D0
type: string
name: retrieve_data
arguments: data_label: D26
type: string

tool: D24: %3c

tool: D0: 

tool: D26: no found

assistant: ```c
int main(void) {
  char str[] = "sfregfgghhhhf", pattern[] = "fggh";
  int i, len = strlen(pattern);
  char *p;
  p = Horspool(str, strlen(str), pattern, len);
  if (p) {
    for (i = 0; i < len; i++) {
      printf("%3c", *(p + i));
    }
  } else {
    printf("no found\r\n");
  }
  printf("\r\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6767666765726673,%rax
  lea    0x5(%rsp),%r13
  lea    0xa(%rsp),%r12
  movl   $0x68686868,0x12(%rsp)
  mov    %r13,%rdi
  movl   $0x68676766,0x5(%rsp)
  movb   $0x0,0x9(%rsp)
  mov    %rax,0xa(%rsp)
  mov    $0x66,%eax
  mov    %ax,0x16(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <Horspool@plt>
  test   %rax,%rax
  je     L18
  test   %ebp,%ebp
  jle    L24
  mov    %rax,%rbx
  lea    -0x1(%rbp),%eax
  lea    D17(%rip),%rbp
  lea    0x1(%rbx,%rax,1),%r12
L8:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
L24:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L24
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D17
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string

tool: D17: %3c

tool: D10: 

tool: D26: no found

assistant: ```c
int main(void) {
  char str[] = "sfregfgghhhhf", pattern[] = "fggh";
  int i, len = strlen(pattern);
  char *p;
  p = Horspool(str, strlen(str), pattern, len);
  if (p) {
    for (i = 0; i < len; i++) {
      printf("%3c", *(p + i));
    }
  } else {
    printf("no found\r\n");
  }
  printf("\r\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6767666765726673,%rax
  lea    0x5(%rsp),%r13
  lea    0xa(%rsp),%r12
  movl   $0x68686868,0x12(%rsp)
  mov    %r13,%rdi
  movl   $0x68676766,0x5(%rsp)
  movb   $0x0,0x9(%rsp)
  mov    %rax,0xa(%rsp)
  mov    $0x66,%eax
  mov    %ax,0x16(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <Horspool@plt>
  test   %rax,%rax
  je     L46
  test   %ebp,%ebp
  jle    L44
  mov    %rax,%rbx
  lea    -0x1(%rbp),%eax
  lea    D0(%rip),%rbp
  lea    0x1(%rbx,%rax,1),%r12
L26:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L26
L44:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  jmp    L44
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D0: %3c

tool: D5: 

tool: D8: no found

assistant: ```c
int main(void) {
  char str[] = "sfregfgghhhhf", pattern[] = "fggh";
  int i, len = strlen(pattern);
  char *p;
  p = Horspool(str, strlen(str), pattern, len);
  if (p) {
    for (i = 0; i < len; i++) {
      printf("%3c", *(p + i));
    }
  } else {
    printf("no found\r\n");
  }
  printf("\r\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sort>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %esi,%ecx
  cmp    $0x78,%dl
  je     L32
  mov    (%rdi),%rdx
  movsd  0x8(%rdx),%xmm0
  movslq %esi,%rdx
  mov    -0x8(%rdi,%rdx,8),%rdx
  movsd  0x8(%rdx),%xmm1
  mov    $0x1,%edx
L150:
  comisd %xmm0,%xmm1
  ja     L187
  cmp    $0x2,%ecx
  jle    L29
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%r8
  lea    0x8(%rax),%rbx
  lea    -0x3(%rcx),%edx
  lea    0x10(%rax,%rdx,8),%r11
  mov    %rbx,%rdi
  jmp    L23
L32:
  mov    (%rdi),%rdx
  movsd  (%rdx),%xmm0
  movslq %esi,%rdx
  mov    -0x8(%rdi,%rdx,8),%rdx
  movsd  (%rdx),%xmm1
  mov    $0x0,%edx
  jmp    L150
L187:
  cmp    $0x2,%ecx
  jle    L29
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%r8
  lea    0x8(%rax),%rbx
  lea    -0x3(%rcx),%edx
  lea    0x10(%rax,%rdx,8),%r11
  mov    %rbx,%rdi
  jmp    L94
L183:
  add    $0x8,%rax
  cmp    %r11,%rax
  je     L57
L78:
  mov    %rdi,%r9
  mov    %rax,%rcx
  mov    (%rdi),%rdx
  mov    (%rax),%rsi
  movsd  (%rsi,%r8,1),%xmm0
  comisd (%rdx,%r8,1),%xmm0
  jbe    L183
  mov    $0x0,%edx
L123:
  mov    %rdx,%rsi
  add    (%r9),%rsi
  movsd  (%rsi),%xmm0
  mov    (%rcx),%r10
  movsd  (%r10,%rdx,1),%xmm1
  movsd  %xmm1,(%rsi)
  mov    (%rcx),%rsi
  movsd  %xmm0,(%rsi,%rdx,1)
  add    $0x8,%rdx
  cmp    $0x18,%rdx
  jne    L123
  jmp    L183
L57:
  add    $0x8,%rdi
  cmp    %r11,%rdi
  je     L29
L94:
  mov    %rbx,%rax
  jmp    L78
L77:
  add    $0x8,%rax
  cmp    %r11,%rax
  je     L116
L30:
  mov    %rdi,%r9
  mov    %rax,%rcx
  mov    (%rdi),%rsi
  mov    (%rax),%rdx
  movsd  (%rsi,%r8,1),%xmm0
  comisd (%rdx,%r8,1),%xmm0
  jbe    L77
  mov    $0x0,%edx
L163:
  mov    %rdx,%rsi
  add    (%r9),%rsi
  movsd  (%rsi),%xmm0
  mov    (%rcx),%r10
  movsd  (%r10,%rdx,1),%xmm1
  movsd  %xmm1,(%rsi)
  mov    (%rcx),%rsi
  movsd  %xmm0,(%rsi,%rdx,1)
  add    $0x8,%rdx
  cmp    $0x18,%rdx
  jne    L163
  jmp    L77
L116:
  add    $0x8,%rdi
  cmp    %r11,%rdi
  je     L29
L23:
  mov    %rbx,%rax
  jmp    L30
L29:
  pop    %rbx
  ret
```

assistant: ```c
void sort(double **arr, int size, char u) {
  double temp[3];
  int i, j, k, l;
  double u0, u1;
  if (u == 'x') {
    u0 = arr[0][0];
    u1 = arr[size - 1][0];
    k = 0;
  } else {
    u0 = arr[0][1];
    u1 = arr[size - 1][1];
    k = 1;
  }
  if (u0 < u1) {
    for (i = 1; i < size - 1; ++i) {
      for (j = 1; j < size - 1; ++j) {
        if (arr[i][k] < arr[j][k]) {
          for (l = 0; l < 3; ++l) {
            temp[l] = arr[i][l];
            arr[i][l] = arr[j][l];
            arr[j][l] = temp[l];
          }
        }
      }
    }
  } else {
    for (i = 1; i < size - 1; ++i) {
      for (j = 1; j < size - 1; ++j) {
        if (arr[i][k] > arr[j][k]) {
          for (l = 0; l < 3; ++l) {
            temp[l] = arr[i][l];
            arr[i][l] = arr[j][l];
            arr[j][l] = temp[l];
          }
        }
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sort>:
  endbr64
  mov    %rdi,%rcx
  movslq %esi,%rax
  mov    %rax,%rdi
  mov    (%rcx),%rsi
  mov    -0x8(%rcx,%rax,8),%rax
  cmp    $0x78,%dl
  je     L47
  movsd  0x8(%rsi),%xmm0
  movsd  0x8(%rax),%xmm1
  mov    $0x1,%eax
L56:
  comisd %xmm0,%xmm1
  lea    -0x1(%rdi),%edx
  ja     L63
  cmp    $0x1,%edx
  jle    L3
  lea    0x0(,%rax,8),%rsi
  lea    0x8(%rcx),%r11
  lea    -0x3(%rdi),%eax
  mov    %r11,%r10
  lea    0x10(%rcx,%rax,8),%r8
  nopw   0x0(%rax,%rax,1)
L103:
  mov    (%r10),%rdi
  mov    %r11,%rdx
  lea    (%rdi,%rsi,1),%r9
  jmp    L119
  nopl   0x0(%rax)
L87:
  add    $0x8,%rdx
  cmp    %r8,%rdx
  je     L62
L119:
  mov    (%rdx),%rcx
  movsd  (%r9),%xmm0
  comisd (%rcx,%rsi,1),%xmm0
  jbe    L87
  xor    %eax,%eax
L98:
  movsd  (%rdi,%rax,1),%xmm0
  movsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%rdi,%rax,1)
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L98
  add    $0x8,%rdx
  cmp    %r8,%rdx
  jne    L119
L62:
  add    $0x8,%r10
  cmp    %r8,%r10
  jne    L103
L124:
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  cmp    $0x1,%edx
  jle    L124
  lea    0x0(,%rax,8),%rsi
  lea    0x8(%rcx),%r11
  lea    -0x3(%rdi),%eax
  mov    %r11,%r10
  lea    0x10(%rcx,%rax,8),%r8
  nopl   0x0(%rax)
L114:
  mov    (%r10),%rdi
  mov    %r11,%rdx
  lea    (%rdi,%rsi,1),%r9
  jmp    L23
  nopl   0x0(%rax)
L43:
  add    $0x8,%rdx
  cmp    %rdx,%r8
  je     L77
L23:
  mov    (%rdx),%rcx
  movsd  (%rcx,%rsi,1),%xmm0
  comisd (%r9),%xmm0
  jbe    L43
  xor    %eax,%eax
L113:
  movsd  (%rdi,%rax,1),%xmm0
  movsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%rdi,%rax,1)
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L113
  add    $0x8,%rdx
  cmp    %rdx,%r8
  jne    L23
L77:
  add    $0x8,%r10
  cmp    %r10,%r8
  jne    L114
  ret
L47:
  movsd  (%rax),%xmm1
  movsd  (%rsi),%xmm0
  xor    %eax,%eax
  jmp    L56
L3:
  ret
```

assistant: ```c
void sort(double **arr, int size, char u) {
  double temp[3];
  int i, j, k, l;
  double u0, u1;
  if (u == 'x') {
    u0 = arr[0][0];
    u1 = arr[size - 1][0];
    k = 0;
  } else {
    u0 = arr[0][1];
    u1 = arr[size - 1][1];
    k = 1;
  }
  if (u0 < u1) {
    for (i = 1; i < size - 1; ++i) {
      for (j = 1; j < size - 1; ++j) {
        if (arr[i][k] < arr[j][k]) {
          for (l = 0; l < 3; ++l) {
            temp[l] = arr[i][l];
            arr[i][l] = arr[j][l];
            arr[j][l] = temp[l];
          }
        }
      }
    }
  } else {
    for (i = 1; i < size - 1; ++i) {
      for (j = 1; j < size - 1; ++j) {
        if (arr[i][k] > arr[j][k]) {
          for (l = 0; l < 3; ++l) {
            temp[l] = arr[i][l];
            arr[i][l] = arr[j][l];
            arr[j][l] = temp[l];
          }
        }
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  mov    %rdi,%rax
  movslq %esi,%rcx
  mov    (%rdi),%rdi
  mov    -0x8(%rax,%rcx,8),%rcx
  cmp    $0x78,%dl
  je     L84
  movsd  0x8(%rdi),%xmm0
  movsd  0x8(%rcx),%xmm1
  mov    $0x8,%ecx
L52:
  comisd %xmm0,%xmm1
  lea    -0x1(%rsi),%edx
  ja     L129
  cmp    $0x1,%edx
  jle    L124
  lea    0x8(%rax),%r10
  lea    -0x3(%rsi),%edx
  lea    0x10(%rax,%rdx,8),%rdi
  mov    %r10,%r9
  nop
L120:
  mov    (%r9),%rsi
  mov    %r10,%rax
  lea    (%rsi,%rcx,1),%r8
  jmp    L81
  nopl   0x0(%rax)
L53:
  add    $0x8,%rax
  cmp    %rdi,%rax
  je     L99
L81:
  mov    (%rax),%rdx
  movsd  (%r8),%xmm0
  comisd (%rdx,%rcx,1),%xmm0
  jbe    L53
  movsd  (%rsi),%xmm0
  movsd  (%rdx),%xmm1
  add    $0x8,%rax
  movsd  %xmm1,(%rsi)
  movsd  0x8(%rdx),%xmm1
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm1,0x8(%rsi)
  movsd  0x10(%rdx),%xmm1
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm1,0x10(%rsi)
  movsd  %xmm0,0x10(%rdx)
  cmp    %rdi,%rax
  jne    L81
L99:
  add    $0x8,%r9
  cmp    %rdi,%r9
  jne    L120
L16:
  ret
  nopl   0x0(%rax,%rax,1)
L129:
  cmp    $0x1,%edx
  jle    L16
  lea    0x8(%rax),%r10
  lea    -0x3(%rsi),%edx
  lea    0x10(%rax,%rdx,8),%rdi
  mov    %r10,%r9
  nopl   0x0(%rax)
L101:
  mov    (%r9),%rsi
  mov    %r10,%rax
  lea    (%rsi,%rcx,1),%r8
  jmp    L1
  nopl   0x0(%rax)
L143:
  add    $0x8,%rax
  cmp    %rax,%rdi
  je     L22
L1:
  mov    (%rax),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  comisd (%r8),%xmm0
  jbe    L143
  movsd  (%rsi),%xmm0
  movsd  (%rdx),%xmm1
  add    $0x8,%rax
  movsd  %xmm1,(%rsi)
  movsd  0x8(%rdx),%xmm1
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm1,0x8(%rsi)
  movsd  0x10(%rdx),%xmm1
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm1,0x10(%rsi)
  movsd  %xmm0,0x10(%rdx)
  cmp    %rax,%rdi
  jne    L1
L22:
  add    $0x8,%r9
  cmp    %r9,%rdi
  jne    L101
  ret
L84:
  movsd  (%rcx),%xmm1
  movsd  (%rdi),%xmm0
  xor    %ecx,%ecx
  jmp    L52
L124:
  ret
```

assistant: ```c
void sort(double **arr, int size, char u) {
  double temp[3];
  int i, j, k, l;
  double u0, u1;
  if (u == 'x') {
    u0 = arr[0][0];
    u1 = arr[size - 1][0];
    k = 0;
  } else {
    u0 = arr[0][1];
    u1 = arr[size - 1][1];
    k = 1;
  }
  if (u0 < u1) {
    for (i = 1; i < size - 1; ++i) {
      for (j = 1; j < size - 1; ++j) {
        if (arr[i][k] < arr[j][k]) {
          for (l = 0; l < 3; ++l) {
            temp[l] = arr[i][l];
            arr[i][l] = arr[j][l];
            arr[j][l] = temp[l];
          }
        }
      }
    }
  } else {
    for (i = 1; i < size - 1; ++i) {
      for (j = 1; j < size - 1; ++j) {
        if (arr[i][k] > arr[j][k]) {
          for (l = 0; l < 3; ++l) {
            temp[l] = arr[i][l];
            arr[i][l] = arr[j][l];
            arr[j][l] = temp[l];
          }
        }
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <system_@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <remove_char@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x94,%ecx
  lea    D30(%rip),%rdx
  lea    D31(%rip),%rsi
  mov    %rax,%rdi
  call   <s_internal@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <downcase@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D28
type: string
name: disassemble_data
arguments: tag: D30
type: string
name: disassemble_data
arguments: tag: D31
type: string

tool: D8: uname

tool: D28: 


tool: D30: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/guicho271828/roswell/refs/heads/master/src/util.c

tool: D31: p

assistant: ```c
char *uname(void) {
  char *p = system_("uname");
  char *p2;
  p2 = remove_char("\r\n", p);
  (s_internal(p, "p", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/guicho271828/roswell/refs/heads/master/src/util.c", 148));
  return downcase(p2);
}
```