ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_linux_version_newer>:
  endbr64
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  mov    (%rsp),%rdi
  mov    %r14,%rsi
  call   <strtok@plt>
  test   %rax,%rax
  je     L35
  mov    %rax,%rdi
  call   <atoi@plt>
  shl    $0x18,%eax
  mov    %eax,%ebp
L35:
  xor    %edi,%edi
  mov    %r14,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L16
  call   <atoi@plt>
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %eax,%ebp
L16:
  xor    %edi,%edi
  mov    %r14,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L23
  call   <atoi@plt>
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %eax,%ebp
L23:
  shl    $0x10,%ebx
  shl    $0x18,%r13d
  xor    %eax,%eax
  and    $0xff0000,%ebx
  shl    $0x8,%r12d
  or     %r13d,%ebx
  movzwl %r12w,%r12d
  or     %r12d,%ebx
  cmp    %ebp,%ebx
  setle  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: .

assistant: ```c
int check_linux_version_newer(int major, int minor, int subminor) {
  int newer = 0;
  int check_version, current_version;
  struct utsname uname_buffer;
  char *ptr;
  int current_major = 0, current_minor = 0, current_sub = 0;
  uname(&uname_buffer);
  ptr = strtok(uname_buffer.release, ".");
  if (ptr != NULL)
    current_major = atoi(ptr);
  ptr = strtok(NULL, ".");
  if (ptr != NULL)
    current_minor = atoi(ptr);
  ptr = strtok(NULL, ".");
  if (ptr != NULL)
    current_sub = atoi(ptr);
  check_version = (((major & 0xff) << 24) | ((minor & 0xff) << 16) | ((subminor & 0xff) << 8));
  current_version = (((current_major & 0xff) << 24) | ((current_minor & 0xff) << 16) | ((current_sub & 0xff) << 8));
  if (current_version >= check_version)
    newer = 1;
  return newer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<psmat3_rotation_y>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <mat3_rotation_y@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct mat3 *psmat3_rotation_y(struct mat3 *result, float angle) {
  mat3_rotation_y((float *)result, angle);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<psmat3_rotation_y>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mat3_rotation_y@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct mat3 *psmat3_rotation_y(struct mat3 *result, float angle) {
  mat3_rotation_y((float *)result, angle);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<psmat3_rotation_y>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat3_rotation_y@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat3 *psmat3_rotation_y(struct mat3 *result, float angle) {
  mat3_rotation_y((float *)result, angle);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<psmat3_rotation_y>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat3_rotation_y@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat3 *psmat3_rotation_y(struct mat3 *result, float angle) {
  mat3_rotation_y((float *)result, angle);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PrintNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %al,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movzbl -0x24(%rbp),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%ecx
  lea    D3(%rip),%rdx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L7
L13:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <OutChar@plt>
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: %d

assistant: ```c
void PrintNumber(unsigned char n) {
  char buf[4];
  char *p = buf;
  snprintf(buf, 3, "%d", (int)n);
  while (*p)
    OutChar(*p++);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PrintNumber>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl %dil,%ecx
  lea    0x4(%rsp),%rdi
  lea    D0(%rip),%rdx
  mov    $0x3,%esi
  call   <snprintf@plt>
  movzbl 0x4(%rsp),%edi
  test   %dil,%dil
  je     L14
  lea    0x4(%rsp),%rbx
L16:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <OutChar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L16
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: %d

assistant: ```c
void PrintNumber(unsigned char n) {
  char buf[4];
  char *p = buf;
  snprintf(buf, 3, "%d", (int)n);
  while (*p)
    OutChar(*p++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PrintNumber>:
  endbr64
  push   %rbx
  movzbl %dil,%ecx
  mov    $0x3,%esi
  lea    D7(%rip),%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  movsbl 0x4(%rsp),%edi
  test   %dil,%dil
  je     L14
L1:
  call   <OutChar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: %d

assistant: ```c
void PrintNumber(unsigned char n) {
  char buf[4];
  char *p = buf;
  snprintf(buf, 3, "%d", (int)n);
  while (*p)
    OutChar(*p++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PrintNumber>:
  endbr64
  push   %rbx
  movzbl %dil,%ecx
  mov    $0x3,%esi
  lea    D4(%rip),%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  movsbl 0x4(%rsp),%edi
  test   %dil,%dil
  je     L0
L17:
  call   <OutChar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L17
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: %d

assistant: ```c
void PrintNumber(unsigned char n) {
  char buf[4];
  char *p = buf;
  snprintf(buf, 3, "%d", (int)n);
  while (*p)
    OutChar(*p++);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_list_ele>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L10
L16:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: %d


assistant: ```c
int print_list_ele(void *data) {
  if (data == NULL) {
    return 0;
  }
  int number = *(int *)data;
  printf("%d\n", number);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_list_ele>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  mov    (%rdi),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0x0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: %d


assistant: ```c
int print_list_ele(void *data) {
  if (data == NULL) {
    return 0;
  }
  int number = *(int *)data;
  printf("%d\n", number);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_list_ele>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  mov    (%rdi),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: %d


assistant: ```c
int print_list_ele(void *data) {
  if (data == NULL) {
    return 0;
  }
  int number = *(int *)data;
  printf("%d\n", number);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_list_ele>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  mov    (%rdi),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: %d


assistant: ```c
int print_list_ele(void *data) {
  if (data == NULL) {
    return 0;
  }
  int number = *(int *)data;
  printf("%d\n", number);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<op_STRING_CMP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <OP1_TYPECAST@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <OP2_TYPECAST@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L36:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L43
  mov    $0x1,%eax
  jmp    L67
L43:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L68
  mov    $0xffffffffffffffff,%rax
  jmp    L67
L68:
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    $0x0,%eax
L67:
  leave
  ret
```

assistant: ```c
void *op_STRING_CMP(void *inpString1, void *inpString2) {
  char *s1 = (char *)OP1_TYPECAST(inpString1);
  char *s2 = (char *)OP2_TYPECAST(inpString2);
  int i;
  for (i = 0; (s1[i] || s2[i]); i++) {
    if (s1[i] > s2[i]) {
      return (void *)1;
    } else if (s1[i] < s2[i]) {
      return (void *)(-1);
    }
  }
  return (void *)0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_STRING_CMP>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <OP1_TYPECAST@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <OP2_TYPECAST@plt>
  mov    %rax,%rdx
  sub    %rax,%rbx
  mov    %rbx,%rdi
  jmp    L26
L36:
  movzbl (%rdx),%esi
  cmp    %cl,%sil
  jl     L17
  add    $0x1,%rdx
  cmp    %cl,%sil
  jg     L50
L26:
  movzbl (%rdi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L36
  cmpb   $0x0,(%rdx)
  jne    L36
  mov    $0x0,%eax
  jmp    L43
L17:
  mov    $0x1,%eax
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  mov    $0xffffffffffffffff,%rax
  jmp    L43
```

assistant: ```c
void *op_STRING_CMP(void *inpString1, void *inpString2) {
  char *s1 = (char *)OP1_TYPECAST(inpString1);
  char *s2 = (char *)OP2_TYPECAST(inpString2);
  int i;
  for (i = 0; (s1[i] || s2[i]); i++) {
    if (s1[i] > s2[i]) {
      return (void *)1;
    } else if (s1[i] < s2[i]) {
      return (void *)(-1);
    }
  }
  return (void *)0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<op_STRING_CMP>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <OP1_TYPECAST@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <OP2_TYPECAST@plt>
  mov    %rbx,%rdx
  sub    %rbx,%rax
  jmp    L6
  nopl   (%rax)
L33:
  cmp    %cl,%sil
  jg     L38
  add    $0x1,%rdx
  cmp    %cl,%sil
  jl     L15
L6:
  movzbl (%rdx),%esi
  movzbl (%rax,%rdx,1),%ecx
  mov    %esi,%ebx
  or     %cl,%bl
  jne    L33
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L38:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L15:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *op_STRING_CMP(void *inpString1, void *inpString2) {
  char *s1 = (char *)OP1_TYPECAST(inpString1);
  char *s2 = (char *)OP2_TYPECAST(inpString2);
  int i;
  for (i = 0; (s1[i] || s2[i]); i++) {
    if (s1[i] > s2[i]) {
      return (void *)1;
    } else if (s1[i] < s2[i]) {
      return (void *)(-1);
    }
  }
  return (void *)0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<op_STRING_CMP>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <OP1_TYPECAST@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <OP2_TYPECAST@plt>
  mov    %rbx,%rdx
  sub    %rbx,%rax
  jmp    L36
  nopl   (%rax)
L23:
  cmp    %cl,%sil
  jg     L12
  add    $0x1,%rdx
  cmp    %cl,%sil
  jl     L33
L36:
  movzbl (%rdx),%esi
  movzbl (%rax,%rdx,1),%ecx
  mov    %esi,%ebx
  or     %cl,%bl
  jne    L23
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L12:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L33:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *op_STRING_CMP(void *inpString1, void *inpString2) {
  char *s1 = (char *)OP1_TYPECAST(inpString1);
  char *s2 = (char *)OP2_TYPECAST(inpString2);
  int i;
  for (i = 0; (s1[i] || s2[i]); i++) {
    if (s1[i] > s2[i]) {
      return (void *)1;
    } else if (s1[i] < s2[i]) {
      return (void *)(-1);
    }
  }
  return (void *)0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L10
  movss  D4(%rip),%xmm0
  jmp    L5
L10:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
L5:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: byte[4]

tool: {"D4": [0x00,0x00,0x80,0xbf]}

assistant: ```c
float divide(int x, int y) {
  if (y == 0)
    return -1;
  else
    return x / y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<divide>:
  endbr64
  mov    %edi,%eax
  movss  D6(%rip),%xmm0
  test   %esi,%esi
  je     L1
  cltd
  idiv   %esi
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
L1:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: byte[4]

tool: {"D6": [0x00,0x00,0x80,0xbf]}

assistant: ```c
float divide(int x, int y) {
  if (y == 0)
    return -1;
  else
    return x / y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<divide>:
  endbr64
  movss  D5(%rip),%xmm0
  mov    %edi,%eax
  test   %esi,%esi
  je     L7
  cltd
  pxor   %xmm0,%xmm0
  idiv   %esi
  cvtsi2ss %eax,%xmm0
L7:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: byte[4]

tool: {"D5": [0x00,0x00,0x80,0xbf]}

assistant: ```c
float divide(int x, int y) {
  if (y == 0)
    return -1;
  else
    return x / y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<divide>:
  endbr64
  movss  D2(%rip),%xmm0
  mov    %edi,%eax
  test   %esi,%esi
  je     L1
  cltd
  pxor   %xmm0,%xmm0
  idiv   %esi
  cvtsi2ss %eax,%xmm0
L1:
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: byte[4]

tool: {"D2": [0x00,0x00,0x80,0xbf]}

assistant: ```c
float divide(int x, int y) {
  if (y == 0)
    return -1;
  else
    return x / y;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<floats_mat_transform_xyz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x24,%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x2c,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void floats_mat_transform_xyz(const float M[16], const float xyz[3], float r[3]) {
  r[0] = M[0] * xyz[0] + M[1] * xyz[1] + M[2] * xyz[2] + M[3];
  r[1] = M[4] * xyz[0] + M[5] * xyz[1] + M[6] * xyz[2] + M[7];
  r[2] = M[8] * xyz[0] + M[9] * xyz[1] + M[10] * xyz[2] + M[11];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<floats_mat_transform_xyz>:
  endbr64
  movss  (%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0xc(%rdi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x10(%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0x1c(%rdi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x20(%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0x2c(%rdi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void floats_mat_transform_xyz(const float M[16], const float xyz[3], float r[3]) {
  r[0] = M[0] * xyz[0] + M[1] * xyz[1] + M[2] * xyz[2] + M[3];
  r[1] = M[4] * xyz[0] + M[5] * xyz[1] + M[6] * xyz[2] + M[7];
  r[2] = M[8] * xyz[0] + M[9] * xyz[1] + M[10] * xyz[2] + M[11];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<floats_mat_transform_xyz>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0xc(%rdi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x10(%rdi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0x1c(%rdi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x20(%rdi),%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0x2c(%rdi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void floats_mat_transform_xyz(const float M[16], const float xyz[3], float r[3]) {
  r[0] = M[0] * xyz[0] + M[1] * xyz[1] + M[2] * xyz[2] + M[3];
  r[1] = M[4] * xyz[0] + M[5] * xyz[1] + M[6] * xyz[2] + M[7];
  r[2] = M[8] * xyz[0] + M[9] * xyz[1] + M[10] * xyz[2] + M[11];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floats_mat_transform_xyz>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0xc(%rdi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x10(%rdi),%xmm0
  movss  0x14(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x18(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0x1c(%rdi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x20(%rdi),%xmm0
  movss  0x24(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x28(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  addss  0x2c(%rdi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void floats_mat_transform_xyz(const float M[16], const float xyz[3], float r[3]) {
  r[0] = M[0] * xyz[0] + M[1] * xyz[1] + M[2] * xyz[2] + M[3];
  r[1] = M[4] * xyz[0] + M[5] * xyz[1] + M[6] * xyz[2] + M[7];
  r[2] = M[8] * xyz[0] + M[9] * xyz[1] + M[10] * xyz[2] + M[11];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<LZ4_createStream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1008,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x4020,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *LZ4_createStream() {
  void *lz4s = calloc(4, ((1 << (14 - 2)) + 8));
  memset(lz4s, 0, (((1 << (14 - 2)) + 8) * sizeof(unsigned int)));
  return lz4s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LZ4_createStream>:
  endbr64
  push   %rbx
  mov    $0x1008,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    $0x4020,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *LZ4_createStream() {
  void *lz4s = calloc(4, ((1 << (14 - 2)) + 8));
  memset(lz4s, 0, (((1 << (14 - 2)) + 8) * sizeof(unsigned int)));
  return lz4s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<LZ4_createStream>:
  endbr64
  push   %r12
  mov    $0x1008,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    $0x4020,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *LZ4_createStream() {
  void *lz4s = calloc(4, ((1 << (14 - 2)) + 8));
  memset(lz4s, 0, (((1 << (14 - 2)) + 8) * sizeof(unsigned int)));
  return lz4s;
}
```