ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<draw_line>:
  endbr64
  sub    $0x8,%rsp
  cmp    %ecx,%esi
  je     L27
  cmp    %r8d,%edx
  je     L31
  call   <draw_line_oblique@plt>
L22:
  add    $0x8,%rsp
  ret
L27:
  call   <draw_line_v@plt>
  jmp    L22
L31:
  call   <draw_line_h@plt>
  jmp    L22
```

assistant: ```c
void draw_line(char *fbp, int x1, int y1, int x2, int y2) {
  if (x1 == x2)
    draw_line_v(fbp, x1, y1, x2, y2);
  else if (y1 == y2)
    draw_line_h(fbp, x1, y1, x2, y2);
  else
    draw_line_oblique(fbp, x1, y1, x2, y2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw_line>:
  endbr64
  cmp    %ecx,%esi
  je     L7
  cmp    %r8d,%edx
  je     L18
  jmp    1090 <draw_line_oblique@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %edx,%r8d
  jmp    1070 <draw_line_h@plt>
L7:
  mov    %esi,%ecx
  jmp    1080 <draw_line_v@plt>
```

assistant: ```c
void draw_line(char *fbp, int x1, int y1, int x2, int y2) {
  if (x1 == x2)
    draw_line_v(fbp, x1, y1, x2, y2);
  else if (y1 == y2)
    draw_line_h(fbp, x1, y1, x2, y2);
  else
    draw_line_oblique(fbp, x1, y1, x2, y2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<draw_line>:
  endbr64
  cmp    %ecx,%esi
  je     L5
  cmp    %r8d,%edx
  je     L8
  jmp    1090 <draw_line_oblique@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %edx,%r8d
  jmp    1070 <draw_line_h@plt>
L5:
  mov    %esi,%ecx
  jmp    1080 <draw_line_v@plt>
```

assistant: ```c
void draw_line(char *fbp, int x1, int y1, int x2, int y2) {
  if (x1 == x2)
    draw_line_v(fbp, x1, y1, x2, y2);
  else if (y1 == y2)
    draw_line_h(fbp, x1, y1, x2, y2);
  else
    draw_line_oblique(fbp, x1, y1, x2, y2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tabsep_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L42
L69:
  cmpb   $0x9,-0x11(%rbp)
  jne    L44
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jge    L58
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L58:
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L44:
  addq   $0x1,-0x28(%rbp)
L42:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L69
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jge    L10
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L10:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L37
L64:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L64
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int tabsep_string(char *s, char **arr, int nCols, char *def) {
  char ch;
  char *p = s;
  int result, cnt = 0;
  while ((ch = *s)) {
    if (ch == '\t') {
      *s = 0;
      if (cnt < nCols) {
        arr[cnt++] = p;
      }
      p = s + 1;
    }
    s++;
  }
  if (cnt < nCols)
    arr[cnt++] = p;
  result = cnt;
  for (; cnt < nCols; cnt++) {
    arr[cnt] = def;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tabsep_string>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rcx,%rdi
  movzbl (%r8),%ecx
  test   %cl,%cl
  je     L72
  lea    0x1(%r8),%rax
  mov    $0x0,%esi
  jmp    L89
L29:
  mov    %rcx,%r8
L10:
  add    $0x1,%rax
  movzbl -0x1(%rax),%ecx
  test   %cl,%cl
  je     L68
L89:
  cmp    $0x9,%cl
  jne    L10
  mov    %rax,%rcx
  movb   $0x0,-0x1(%rax)
  cmp    %esi,%edx
  jle    L29
  movslq %esi,%r10
  mov    %r8,(%r9,%r10,8)
  lea    0x1(%rsi),%esi
  jmp    L29
L72:
  mov    $0x0,%esi
L68:
  mov    %esi,%ecx
  cmp    %esi,%edx
  jle    L56
  lea    0x1(%rsi),%ecx
  movslq %esi,%rsi
  mov    %r8,(%r9,%rsi,8)
  cmp    %ecx,%edx
  jle    L56
  movslq %ecx,%rsi
  lea    (%r9,%rsi,8),%rax
  sub    $0x1,%edx
  sub    %ecx,%edx
  add    %rsi,%rdx
  lea    0x8(%r9,%rdx,8),%rdx
L34:
  mov    %rdi,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L34
L56:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int tabsep_string(char *s, char **arr, int nCols, char *def) {
  char ch;
  char *p = s;
  int result, cnt = 0;
  while ((ch = *s)) {
    if (ch == '\t') {
      *s = 0;
      if (cnt < nCols) {
        arr[cnt++] = p;
      }
      p = s + 1;
    }
    s++;
  }
  if (cnt < nCols)
    arr[cnt++] = p;
  result = cnt;
  for (; cnt < nCols; cnt++) {
    arr[cnt] = def;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tabsep_string>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r9
  xor    %r8d,%r8d
  test   %al,%al
  jne    L62
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L37:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L29
L62:
  add    $0x1,%rdi
  cmp    $0x9,%al
  jne    L37
  movb   $0x0,-0x1(%rdi)
  cmp    %r8d,%edx
  jle    L48
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %r9,(%rsi,%rax,8)
L48:
  movzbl (%rdi),%eax
  mov    %rdi,%r9
  test   %al,%al
  jne    L62
L29:
  mov    %r8d,%r10d
  cmp    %r8d,%edx
  jle    L31
  movslq %r8d,%r8
  add    $0x1,%r10d
  mov    %r9,(%rsi,%r8,8)
  cmp    %r10d,%edx
  jle    L31
  movslq %r10d,%rax
L72:
  mov    %rcx,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L72
L31:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int tabsep_string(char *s, char **arr, int nCols, char *def) {
  char ch;
  char *p = s;
  int result, cnt = 0;
  while ((ch = *s)) {
    if (ch == '\t') {
      *s = 0;
      if (cnt < nCols) {
        arr[cnt++] = p;
      }
      p = s + 1;
    }
    s++;
  }
  if (cnt < nCols)
    arr[cnt++] = p;
  result = cnt;
  for (; cnt < nCols; cnt++) {
    arr[cnt] = def;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tabsep_string>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r9
  xor    %r8d,%r8d
  test   %al,%al
  jne    L66
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L55:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L60
L66:
  add    $0x1,%rdi
  cmp    $0x9,%al
  jne    L55
  movb   $0x0,-0x1(%rdi)
  cmp    %r8d,%edx
  jle    L50
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %r9,(%rsi,%rax,8)
L50:
  movzbl (%rdi),%eax
  mov    %rdi,%r9
  test   %al,%al
  jne    L66
L60:
  cmp    %r8d,%edx
  jle    L26
  movslq %r8d,%rax
  lea    0x1(%r8),%r10d
  mov    %r9,(%rsi,%rax,8)
  lea    0x0(,%rax,8),%rdi
  cmp    %r10d,%edx
  jle    L103
  sub    %r8d,%edx
  lea    -0x1(%rdx),%r8d
  cmp    $0x2,%edx
  je     L120
  mov    %r8d,%eax
  lea    0x8(%rsi,%rdi,1),%rdx
  movq   %rcx,%xmm0
  shr    %eax
  punpcklqdq %xmm0,%xmm0
  lea    -0x1(%rax),%edi
  lea    0x10(%rdx),%rax
  shl    $0x4,%rdi
  add    %rax,%rdi
  jmp    L3
  nopl   0x0(%rax)
L110:
  add    $0x10,%rax
L3:
  movups %xmm0,(%rdx)
  mov    %rax,%rdx
  cmp    %rax,%rdi
  jne    L110
  mov    %r8d,%edx
  and    $0xfffffffe,%edx
  lea    (%rdx,%r10,1),%eax
  cmp    %edx,%r8d
  je     L103
L54:
  cltq
  mov    %rcx,(%rsi,%rax,8)
L103:
  mov    %r10d,%r8d
L26:
  mov    %r8d,%eax
  ret
L120:
  mov    %r10d,%eax
  jmp    L54
```

assistant: ```c
int tabsep_string(char *s, char **arr, int nCols, char *def) {
  char ch;
  char *p = s;
  int result, cnt = 0;
  while ((ch = *s)) {
    if (ch == '\t') {
      *s = 0;
      if (cnt < nCols) {
        arr[cnt++] = p;
      }
      p = s + 1;
    }
    s++;
  }
  if (cnt < nCols)
    arr[cnt++] = p;
  result = cnt;
  for (; cnt < nCols; cnt++) {
    arr[cnt] = def;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<update>:
  endbr64
  cmp    $0x2,%edi
  jle    L15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%r8
  mov    %rcx,%r9
  lea    -0x1(%rdi),%ebp
  mov    $0x0,%r11d
  mov    $0x1,%ebx
  lea    -0x3(%rsi),%r13d
  lea    0x4(%rdx),%r12
  jmp    L38
L10:
  lea    (%r11,%r10,1),%edx
  movslq %r11d,%rax
  lea    (%r8,%rax,4),%rcx
  lea    (%r10,%rdx,1),%esi
  movslq %esi,%rsi
  lea    (%r8,%rsi,4),%rsi
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %r13,%rax
  lea    (%r12,%rax,4),%rdi
L21:
  mov    0x4(%rcx),%eax
  add    (%rcx),%eax
  add    0x8(%rcx),%eax
  add    (%r8,%rdx,1),%eax
  add    0x8(%r8,%rdx,1),%eax
  add    (%rsi),%eax
  add    0x4(%rsi),%eax
  add    0x8(%rsi),%eax
  cmp    $0x2,%eax
  sete   %r14b
  movzbl %r14b,%r14d
  imul   0x4(%r8,%rdx,1),%r14d
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  add    %r14d,%eax
  mov    %eax,0x4(%r9,%rdx,1)
  add    $0x4,%rcx
  add    $0x4,%rsi
  add    $0x4,%rdx
  cmp    %rdi,%rcx
  jne    L21
L44:
  add    $0x1,%ebx
  add    %r10d,%r11d
  cmp    %ebp,%ebx
  je     L4
L38:
  cmp    $0x2,%r10d
  jg     L10
  jmp    L44
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  ret
```

assistant: ```c
void update(int Nrows, int Ncolumns, int *board, int *newboard) {
  int r, c;
  for (r = 1; r < Nrows - 1; ++r) {
    for (c = 1; c < Ncolumns - 1; ++c) {
      int s = board[((r - 1) * Ncolumns + (c - 1))] + board[((r - 1) * Ncolumns + (c - 0))] + board[((r - 1) * Ncolumns + (c + 1))] + board[((r + 0) * Ncolumns + (c - 1))] + board[((r + 0) * Ncolumns + (c + 1))] + board[((r + 1) * Ncolumns + (c - 1))] + board[((r + 1) * Ncolumns + (c - 0))] + board[((r + 1) * Ncolumns + (c + 1))];
      newboard[((r)*Ncolumns + (c))] = (s < 2) * 0 + (s == 2) * board[((r)*Ncolumns + (c))] + (s == 3) * 1 + (s > 3) * 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<update>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x1,%ebp
  push   %rbx
  cmp    $0x1,%ebp
  jle    L29
  mov    %esi,%r11d
  mov    %rdx,%rdi
  mov    %rcx,%r9
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    -0x3(%rsi),%r13d
  lea    0x4(%rdx),%r12
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%ebx
  lea    (%r11,%rax,1),%r10d
  cmp    $0x2,%r11d
  jle    L11
  lea    (%r10,%r11,1),%edx
  lea    (%rdi,%rax,4),%rcx
  add    %r13,%rax
  movslq %edx,%rdx
  lea    (%r12,%rax,4),%r8
  lea    (%rdi,%rdx,4),%rsi
  movslq %r10d,%rdx
  shl    $0x2,%rdx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x4(%rcx),%eax
  add    (%rcx),%eax
  xor    %r14d,%r14d
  add    0x8(%rcx),%eax
  add    (%rdi,%rdx,1),%eax
  add    0x8(%rdi,%rdx,1),%eax
  add    (%rsi),%eax
  add    0x4(%rsi),%eax
  add    0x8(%rsi),%eax
  cmp    $0x2,%eax
  sete   %r14b
  imul   0x4(%rdi,%rdx,1),%r14d
  cmp    $0x3,%eax
  sete   %al
  add    $0x4,%rcx
  add    $0x4,%rsi
  movzbl %al,%eax
  add    %r14d,%eax
  mov    %eax,0x4(%r9,%rdx,1)
  add    $0x4,%rdx
  cmp    %r8,%rcx
  jne    L9
L11:
  movslq %r10d,%rax
  cmp    %ebx,%ebp
  jne    L30
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void update(int Nrows, int Ncolumns, int *board, int *newboard) {
  int r, c;
  for (r = 1; r < Nrows - 1; ++r) {
    for (c = 1; c < Ncolumns - 1; ++c) {
      int s = board[((r - 1) * Ncolumns + (c - 1))] + board[((r - 1) * Ncolumns + (c - 0))] + board[((r - 1) * Ncolumns + (c + 1))] + board[((r + 0) * Ncolumns + (c - 1))] + board[((r + 0) * Ncolumns + (c + 1))] + board[((r + 1) * Ncolumns + (c - 1))] + board[((r + 1) * Ncolumns + (c - 0))] + board[((r + 1) * Ncolumns + (c + 1))];
      newboard[((r)*Ncolumns + (c))] = (s < 2) * 0 + (s == 2) * board[((r)*Ncolumns + (c))] + (s == 3) * 1 + (s > 3) * 0;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mystrcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mystrlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <mystrcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mystrcat(char *s1, const char *s2) {
  mystrcpy(&s1[mystrlen(s1)], s2);
  return s1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mystrcat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <mystrlen@plt>
  lea    (%rbx,%rax,1),%rdi
  mov    %rbp,%rsi
  call   <mystrcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mystrcat(char *s1, const char *s2) {
  mystrcpy(&s1[mystrlen(s1)], s2);
  return s1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mystrcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <mystrlen@plt>
  mov    %rbp,%rsi
  lea    (%r12,%rax,1),%rdi
  call   <mystrcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrcat(char *s1, const char *s2) {
  mystrcpy(&s1[mystrlen(s1)], s2);
  return s1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mystrcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <mystrlen@plt>
  mov    %rbp,%rsi
  lea    (%r12,%rax,1),%rdi
  call   <mystrcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrcat(char *s1, const char *s2) {
  mystrcpy(&s1[mystrlen(s1)], s2);
  return s1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L4
  mov    -0x18(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L14
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D27
datatype: string

tool: D6: Digite a idade #%d: 

tool: D17:  %d

tool: D27: 
Media das idades entradas: %d.


assistant: ```c
void main() {
  int i = 1, soma = 0, num = 0, idade;
  do {
    printf("Digite a idade #%d: ", i);
    i++;
    scanf(" %d", &idade);
    if (idade != 0) {
      soma += idade;
      num++;
    }
  } while (idade != 0);
  printf("\nMedia das idades entradas: %d.\n", soma / num);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D16(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D28(%rip),%r12
  jmp    L19
L1:
  add    %edx,%ebp
  add    $0x1,%ebx
L19:
  lea    0x1(%rbx),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L1
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D8
type_infered: string

tool: D16: Digite a idade #%d: 

tool: D28:  %d

tool: D8: 
Media das idades entradas: %d.


assistant: ```c
void main() {
  int i = 1, soma = 0, num = 0, idade;
  do {
    printf("Digite a idade #%d: ", i);
    i++;
    scanf(" %d", &idade);
    if (idade != 0) {
      soma += idade;
      num++;
    }
  } while (idade != 0);
  printf("\nMedia das idades entradas: %d.\n", soma / num);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D24(%rip),%r15
  push   %r14
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L5:
  lea    0x1(%rbp),%ebx
  mov    %r15,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L24
  mov    %r12d,%eax
  lea    D27(%rip),%rdi
  cltd
  idiv   %ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  add    %eax,%r12d
  mov    %ebx,%ebp
  jmp    L5
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string

tool: D24: Digite a idade #%d: 

tool: D26:  %d

tool: D27: 
Media das idades entradas: %d.


assistant: ```c
void main() {
  int i = 1, soma = 0, num = 0, idade;
  do {
    printf("Digite a idade #%d: ", i);
    i++;
    scanf(" %d", &idade);
    if (idade != 0) {
      soma += idade;
      num++;
    }
  } while (idade != 0);
  printf("\nMedia das idades entradas: %d.\n", soma / num);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D17(%rip),%r15
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L6:
  lea    0x1(%rbp),%ebx
  mov    %r15,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L23
  mov    %r12d,%eax
  lea    D27(%rip),%rdi
  cltd
  idiv   %ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  add    %eax,%r12d
  mov    %ebx,%ebp
  jmp    L6
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type: string
name: extract_symbolic_data
arguments: tag: D9
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string

tool: D17: Digite a idade #%d: 

tool: D9:  %d

tool: D27: 
Media das idades entradas: %d.


assistant: ```c
void main() {
  int i = 1, soma = 0, num = 0, idade;
  do {
    printf("Digite a idade #%d: ", i);
    i++;
    scanf(" %d", &idade);
    if (idade != 0) {
      soma += idade;
      num++;
    }
  } while (idade != 0);
  printf("\nMedia das idades entradas: %d.\n", soma / num);
}
```
user: What is the c source code of the assembly code below?

```asm
<hisfc350_get_best_clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xc,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x25,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x38,-0x20(%rbp)
  movl   $0xc,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L31
L6:
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jb     L39
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
  addl   $0x2,-0x38(%rbp)
L31:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L6
  jmp    L19
L39:
  nop
L19:
  mov    -0x34(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void hisfc350_get_best_clock(unsigned int *clock) {
  int ix;
  int clk_reg;
  unsigned int sysclk[] = {
      (((24) + 1) >> 1), (0 << 2), (((74) + 1) >> 1), ((0 << 3) | (1 << 2)), (((112) + 1) >> 1), ((1 << 3) | (1 << 2)), 0, 0,
  };
  clk_reg = (0 << 2);
  for (ix = 0; sysclk[ix]; ix += 2) {
    if (*clock < sysclk[ix])
      break;
    clk_reg = sysclk[ix + 1];
  }
  *clock = clk_reg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hisfc350_get_best_clock>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xc,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x25,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x38,0x10(%rsp)
  movl   $0xc,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  mov    (%rdi),%esi
  mov    %rsp,%rax
  mov    $0x0,%ecx
  mov    $0xc,%edx
L27:
  cmp    %edx,%esi
  jb     L7
  mov    0x4(%rax),%ecx
  add    $0x8,%rax
  mov    (%rax),%edx
  test   %edx,%edx
  jne    L27
L7:
  mov    %ecx,(%rdi)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hisfc350_get_best_clock(unsigned int *clock) {
  int ix;
  int clk_reg;
  unsigned int sysclk[] = {
      (((24) + 1) >> 1), (0 << 2), (((74) + 1) >> 1), ((0 << 3) | (1 << 2)), (((112) + 1) >> 1), ((1 << 3) | (1 << 2)), 0, 0,
  };
  clk_reg = (0 << 2);
  for (ix = 0; sysclk[ix]; ix += 2) {
    if (*clock < sysclk[ix])
      break;
    clk_reg = sysclk[ix + 1];
  }
  *clock = clk_reg;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hisfc350_get_best_clock>:
  endbr64
  sub    $0x38,%rsp
  xor    %ecx,%ecx
  mov    (%rdi),%esi
  mov    $0xc,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movabs $0x400000025,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xc00000038,%rax
  mov    %rax,0x10(%rsp)
  mov    %rsp,%rax
  movq   $0x0,0x18(%rsp)
  jmp    L37
  nopl   (%rax)
L20:
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%edx
  add    $0x8,%rax
  test   %edx,%edx
  je     L39
L37:
  cmp    %edx,%esi
  jae    L20
L39:
  mov    %ecx,(%rdi)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hisfc350_get_best_clock(unsigned int *clock) {
  int ix;
  int clk_reg;
  unsigned int sysclk[] = {
      (((24) + 1) >> 1), (0 << 2), (((74) + 1) >> 1), ((0 << 3) | (1 << 2)), (((112) + 1) >> 1), ((1 << 3) | (1 << 2)), 0, 0,
  };
  clk_reg = (0 << 2);
  for (ix = 0; sysclk[ix]; ix += 2) {
    if (*clock < sysclk[ix])
      break;
    clk_reg = sysclk[ix + 1];
  }
  *clock = clk_reg;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hisfc350_get_best_clock>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x24,%edx
  jbe    L30
  mov    $0xc,%eax
  cmp    $0x37,%edx
  jbe    L12
L4:
  mov    %eax,(%rdi)
  ret
L30:
  xor    %eax,%eax
  jmp    L4
L12:
  mov    $0x4,%eax
  jmp    L4
```

assistant: ```c
void hisfc350_get_best_clock(unsigned int *clock) {
  int ix;
  int clk_reg;
  unsigned int sysclk[] = {
      (((24) + 1) >> 1), (0 << 2), (((74) + 1) >> 1), ((0 << 3) | (1 << 2)), (((112) + 1) >> 1), ((1 << 3) | (1 << 2)), 0, 0,
  };
  clk_reg = (0 << 2);
  for (ix = 0; sysclk[ix]; ix += 2) {
    if (*clock < sysclk[ix])
      break;
    clk_reg = sysclk[ix + 1];
  }
  *clock = clk_reg;
}
```