user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%ebx
  movzbl 0xd(%rsp),%eax
  xor    %edi,%edi
  test   %ebx,%ebx
  jle    L94
  mov    %ebx,%ecx
  mov    $0x1,%edx
  lea    0xd(%rsp),%r8
  nopl   0x0(%rax,%rax,1)
L137:
  mov    %ecx,%esi
  and    $0xf,%esi
  cmp    $0x9,%esi
  lea    0x30(%rsi),%edi
  lea    0x37(%rsi),%eax
  cmovle %edi,%eax
  mov    %edx,%edi
  mov    %al,(%r8,%rdx,1)
  add    $0x1,%rdx
  sar    $0x4,%ecx
  jne    L137
  movl   $0x0,0x8(%rsp)
L94:
  mov    %edi,%esi
  lea    0xe(%rsp),%r10
  lea    0xf(%rsp),%rbp
  xor    %ecx,%ecx
  sar    %esi
  mov    %r10,%rdx
  mov    $0x1,%r8d
  movslq %edi,%r9
  movslq %esi,%rsi
  add    %rbp,%rsi
  jmp    L71
  nopl   0x0(%rax)
L79:
  mov    %r9,%rax
  sub    %rdx,%rax
  movzbl -0x1(%rax,%r10,2),%eax
L71:
  cmp    %al,(%rdx)
  cmovne %r8d,%ecx
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L79
  cmp    $0x1,%ecx
  jne    L19
  lea    0xd(%rsp),%r9
  mov    $0x1,%r11d
  nop
L88:
  add    $0x1,%ebx
  test   %ebx,%ebx
  jle    L111
  mov    %ebx,%edx
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %edx,%esi
  and    $0xf,%esi
  cmp    $0x9,%esi
  lea    0x30(%rsi),%edi
  lea    0x37(%rsi),%eax
  cmovle %edi,%eax
  mov    %ecx,%edi
  mov    %al,(%r9,%rcx,1)
  add    $0x1,%rcx
  sar    $0x4,%edx
  jne    L14
  mov    %edi,%r8d
  sar    %r8d
L68:
  movslq %r8d,%r8
  mov    %r10,%rcx
  xor    %esi,%esi
  movslq %edi,%r12
  add    %rbp,%r8
  jmp    L20
  xchg   %ax,%ax
L125:
  mov    %r12,%rax
  sub    %rcx,%rax
  movzbl -0x1(%rax,%r10,2),%eax
L20:
  cmp    %al,(%rcx)
  cmovne %r11d,%esi
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L125
  cmp    $0x1,%esi
  je     L88
  mov    %edx,0x8(%rsp)
L19:
  test   %edi,%edi
  je     L17
  movslq %edi,%rax
  lea    D16(%rip),%r12
  lea    -0x1(%r10,%rax,1),%rbp
  lea    (%r10,%rax,1),%rbx
  lea    -0x1(%rdi),%eax
  sub    %rax,%rbp
  nopl   0x0(%rax)
L36:
  movsbl -0x1(%rbx),%esi
  mov    %r12,%rdi
  sub    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L36
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L111:
  movzbl 0xd(%rsp),%eax
  mov    %ebx,%edx
  xor    %r8d,%r8d
  xor    %edi,%edi
  jmp    L68
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D16
type: string

tool: D14: %d

tool: D16: %c

assistant: ```c
int main() {
  int a = 0, num, i, ezway, end = 0, off;
  char hexa[10];
  scanf("%d", &num);
  off = num;
  for (i = 0; num > 0; i++) {
    ezway = num % 16;
    if (ezway < 10)
      hexa[i] = ezway + '0';
    else
      hexa[i] = ezway + 55;
    num /= 16;
  }
  while (a <= i / 2) {
    if (hexa[a] != hexa[i - a - 1])
      end = 1;
    a++;
  }
  while (end == 1) {
    off++;
    num = off;
    for (i = 0; num > 0; i++) {
      ezway = num % 16;
      if (ezway < 10)
        hexa[i] = ezway + '0';
      else
        hexa[i] = ezway + 55;
      num /= 16;
    }
    end = 0;
    a = 0;
    while (a <= i / 2) {
      if (hexa[a] != hexa[i - a - 1])
        end = 1;
      a++;
    }
  }
  while (i > 0) {
    printf("%c", hexa[i - 1]);
    i--;
  }
  return 0;
}
```