user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ReadLibSVM>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  mov    %rcx,%rsi
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x68,%rsp
  mov    %rdx,0x20(%rsp)
  mov    %r8,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <VerifyFileFormat@plt>
  cmp    $0xffffffff,%eax
  je     L75
  movslq (%r12),%r14
  movslq (%rbx),%rbx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  lea    D5(%rip),%r12
  xor    %ebp,%ebp
  imul   %r14,%rbx
  mov    %r14,0x8(%rsp)
  call   <fopen@plt>
  mov    %rax,0x28(%rsp)
  lea    0x0(,%rbx,8),%rdi
  call   <malloc@plt>
  lea    0x0(,%r14,8),%rdi
  xor    %r14d,%r14d
  mov    %rax,(%r15)
  call   <malloc@plt>
  movq   $0x0,0x40(%rsp)
  mov    %rax,0x0(%r13)
  lea    0x50(%rsp),%rax
  lea    0x48(%rsp),%r13
  mov    %rax,0x38(%rsp)
  lea    0x40(%rsp),%rax
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  mov    %rax,0x30(%rsp)
  nop
L48:
  mov    0x30(%rsp),%rdi
  mov    0x28(%rsp),%rdx
  mov    0x38(%rsp),%rsi
  call   <getline@plt>
  mov    0x40(%rsp),%rdi
  cmp    $0xffffffff,%eax
  je     L109
  lea    0x0(,%r14,8),%rax
  xor    %ebx,%ebx
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L99:
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L102
  cmpb   $0xa,(%rax)
  jne    L43
  cmpb   $0x0,0x1(%rax)
  je     L102
L43:
  add    $0x1,%rbx
  cmp    $0x1,%rbx
  je     L17
  test   $0x1,%bl
  jne    L58
  call   <atoi@plt>
  xor    %edi,%edi
  mov    %rax,%rbp
  jmp    L99
  nopl   (%rax)
L58:
  call   <atof@plt>
  lea    -0x1(%rbp),%rax
  mov    (%r15),%rdx
  xor    %edi,%edi
  imul   0x8(%rsp),%rax
  add    %r14,%rax
  movsd  %xmm0,(%rdx,%rax,8)
  jmp    L99
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rax
  add    (%rcx),%rax
  mov    %rax,0x10(%rsp)
  call   <atof@plt>
  mov    0x10(%rsp),%rax
  xor    %edi,%edi
  movsd  %xmm0,(%rax)
  jmp    L99
  nopw   0x0(%rax,%rax,1)
L102:
  add    $0x1,%r14
  jmp    L48
  nopl   0x0(%rax)
L109:
  test   %rdi,%rdi
  je     L113
  call   <free@plt>
L113:
  mov    0x28(%rsp),%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L75:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D9: r

tool: D5: : 

assistant: ```c
int ReadLibSVM(const char *filename, double **X, double **y, int *d, int *n) {
  if (VerifyFileFormat(filename, d, n) == -1) {
    return -1;
  }
  long ln = (long)(*n);
  long ld = (long)(*d);
  FILE *fp = NULL;
  fp = fopen(filename, "r");
  (*X) = (double *)malloc(ln * ld * sizeof(double));
  (*y) = (double *)malloc(ln * sizeof(double));
  long i = 0;
  long numi = 0;
  double numf = 0.0;
  char *line = NULL, *str = NULL, *saveptr = NULL, *subtoken = NULL;
  ssize_t read = 0;
  size_t len = 0;
  while ((read = getline(&line, &len, fp)) != -1) {
    long cnt = 0;
    for (str = line;; str = NULL) {
      subtoken = strtok_r(str, ": ", &saveptr);
      if (subtoken == NULL || !strcmp(subtoken, "\n")) {
        break;
      } else {
        cnt++;
      }
      if (cnt == 1) {
        (*y)[i] = atof(subtoken);
      } else if (cnt % 2 == 0) {
        numi = atoi(subtoken);
      } else {
        numf = atof(subtoken);
        (*X)[i + ln * (numi - 1)] = numf;
      }
    }
    i++;
  }
  if (line) {
    free(line);
  }
  fclose(fp);
  return 0;
}
```