ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbx
  mov    (%rdi),%rcx
  mov    %rsi,%rdx
  add    $0x136ff696,%rcx
  test   $0x10,%cl
  je     L37
  mov    %ecx,%esi
  mov    %rcx,%rax
  sar    $0x8,%si
  test   $0x8,%cl
  je     L58
  mov    %ecx,%ebx
  mov    %rcx,%rdi
  shl    $0x8,%rcx
  movzbl %sil,%esi
  shl    $0x8,%ebx
  shr    $0x18,%rdi
  sar    $0x18,%ebx
  and    $0xff0000,%edi
  shr    $0x38,%rcx
  shl    $0x28,%rcx
  mov    %bl,%ah
  shl    $0x30,%rsi
  and    $0xffffffffff00ffff,%rax
  or     %rdi,%rax
  movabs $0xffff00ffffffffff,%rdi
  and    %rdi,%rax
  or     %rcx,%rax
  movabs $0xff00ffffffffffff,%rcx
  and    %rcx,%rax
  or     %rsi,%rax
  jmp    L26
  nop
L37:
  test   $0x1,%cl
  jne    L49
  movabs $0xff00ffffffffffff,%rax
  movzbl %ch,%esi
  and    %rcx,%rax
  shl    $0x30,%rsi
  shl    $0x8,%rcx
  or     %rsi,%rax
  sar    $0x38,%rcx
  mov    %cl,%ah
L26:
  imul   $0x26b89ca2,%rax,%rax
  pop    %rbx
  movabs $0xfccace8a5ca761d8,%rcx
  add    %rcx,%rax
  mov    %rax,(%rdx)
  ret
  nop
L49:
  lea    0x0(,%rcx,4),%rax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L58:
  movabs $0xffffff00ffffffff,%rdi
  mov    %ecx,%esi
  rol    $0x8,%si
  mov    %si,%ax
  mov    %rcx,%rsi
  shl    $0x18,%rcx
  shr    $0x38,%rsi
  and    %rdi,%rax
  shr    $0x38,%rcx
  shl    $0x20,%rsi
  shl    $0x38,%rcx
  or     %rsi,%rax
  movabs $0xffffffffffffff,%rsi
  and    %rsi,%rax
  or     %rcx,%rax
  jmp    L26
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  char copy12;
  char copy13;
  char copy16;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = copy11;
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy12;
        copy12 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 6);
        *((char *)(&state[0UL]) + 6) = copy12;
      } else {
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
    } else if (state[0UL] & 1UL) {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    } else {
      copy16 = *((char *)(&state[0UL]) + 6);
      *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy16;
    }
    output[0UL] = state[0UL] * 649632930UL - 231145337200877096UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbx
  mov    (%rdi),%rcx
  mov    %rsi,%rdx
  add    $0x136ff696,%rcx
  test   $0x10,%cl
  je     L1
  mov    %ecx,%esi
  mov    %rcx,%rax
  sar    $0x8,%si
  test   $0x8,%cl
  je     L9
  mov    %ecx,%ebx
  mov    %rcx,%rdi
  shl    $0x8,%rcx
  movzbl %sil,%esi
  shl    $0x8,%ebx
  shr    $0x18,%rdi
  sar    $0x18,%ebx
  and    $0xff0000,%edi
  shr    $0x38,%rcx
  shl    $0x28,%rcx
  mov    %bl,%ah
  shl    $0x30,%rsi
  and    $0xffffffffff00ffff,%rax
  or     %rdi,%rax
  movabs $0xffff00ffffffffff,%rdi
  and    %rdi,%rax
  or     %rcx,%rax
  movabs $0xff00ffffffffffff,%rcx
  and    %rcx,%rax
  or     %rsi,%rax
  jmp    L38
  nop
L1:
  test   $0x1,%cl
  jne    L36
  movabs $0xff00ffffffffffff,%rax
  movzbl %ch,%esi
  and    %rcx,%rax
  shl    $0x30,%rsi
  shl    $0x8,%rcx
  or     %rsi,%rax
  sar    $0x38,%rcx
  mov    %cl,%ah
L38:
  imul   $0x26b89ca2,%rax,%rax
  pop    %rbx
  movabs $0xfccace8a5ca761d8,%rcx
  add    %rcx,%rax
  mov    %rax,(%rdx)
  ret
  nop
L36:
  lea    0x0(,%rcx,4),%rax
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L9:
  movabs $0xffffff00ffffffff,%rdi
  mov    %ecx,%esi
  rol    $0x8,%si
  mov    %si,%ax
  mov    %rcx,%rsi
  shl    $0x18,%rcx
  shr    $0x38,%rsi
  and    %rdi,%rax
  shr    $0x38,%rcx
  shl    $0x20,%rsi
  shl    $0x38,%rcx
  or     %rsi,%rax
  movabs $0xffffffffffffff,%rsi
  and    %rsi,%rax
  or     %rcx,%rax
  jmp    L38
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  char copy12;
  char copy13;
  char copy16;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = copy11;
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy12;
        copy12 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 6);
        *((char *)(&state[0UL]) + 6) = copy12;
      } else {
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
    } else if (state[0UL] & 1UL) {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    } else {
      copy16 = *((char *)(&state[0UL]) + 6);
      *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy16;
    }
    output[0UL] = state[0UL] * 649632930UL - 231145337200877096UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<twoSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x2233c,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x2233c,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L30
L2:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <check_num_in_idx_hash@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  je     L42
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0x20(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L31
L42:
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <insert_num_to_idx_hash@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L31
L10:
  addl   $0x1,-0x20(%rbp)
L30:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L2
  mov    $0x0,%eax
L31:
  leave
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *nums_idx = malloc(sizeof(int) * 2);
  int *nums_idx_hash = malloc(sizeof(int) * 35023);
  memset(nums_idx_hash, 0, sizeof(int) * 35023);
  int i;
  int num, num_hash;
  int pair_num_idx;
  int insert_flag;
  for (int i = 0; i < numsSize; i++) {
    num = nums[i];
    if ((pair_num_idx = check_num_in_idx_hash(target - num, nums, nums_idx_hash)) != -1) {
      nums_idx_hash[0] = pair_num_idx;
      nums_idx_hash[1] = i + 1;
      return nums_idx_hash;
    }
    insert_flag = insert_num_to_idx_hash(num, i + 1, nums_idx_hash);
    if (insert_flag == 0)
      return NULL;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<twoSum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,%r15d
  mov    %edx,0x8(%rsp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x2233c,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x2233c,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x0,%ebx
L31:
  mov    %ebx,%ebp
  mov    %ebx,0xc(%rsp)
  cmp    %ebx,%r15d
  jle    L21
  mov    (%r14,%rbx,4),%r12d
  mov    0x8(%rsp),%edi
  sub    %r12d,%edi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <check_num_in_idx_hash@plt>
  cmp    $0xffffffff,%eax
  jne    L38
  lea    0x1(%rbp),%esi
  mov    %r13,%rdx
  mov    %r12d,%edi
  call   <insert_num_to_idx_hash@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  jne    L31
  mov    $0x0,%r13d
  jmp    L5
L38:
  mov    %eax,0x0(%r13)
  mov    0xc(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%r13)
  jmp    L5
L21:
  mov    $0x0,%r13d
L5:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *nums_idx = malloc(sizeof(int) * 2);
  int *nums_idx_hash = malloc(sizeof(int) * 35023);
  memset(nums_idx_hash, 0, sizeof(int) * 35023);
  int i;
  int num, num_hash;
  int pair_num_idx;
  int insert_flag;
  for (int i = 0; i < numsSize; i++) {
    num = nums[i];
    if ((pair_num_idx = check_num_in_idx_hash(target - num, nums, nums_idx_hash)) != -1) {
      nums_idx_hash[0] = pair_num_idx;
      nums_idx_hash[1] = i + 1;
      return nums_idx_hash;
    }
    insert_flag = insert_num_to_idx_hash(num, i + 1, nums_idx_hash);
    if (insert_flag == 0)
      return NULL;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<twoSum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x2233c,%edi
  call   <malloc@plt>
  mov    $0x2233c,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memset@plt>
  jmp    L20
  nopl   (%rax)
L23:
  mov    0x0(%rbp,%rbx,4),%r14d
  mov    %r13d,%edi
  mov    %rbp,%rsi
  mov    %r15,%rdx
  sub    %r14d,%edi
  call   <check_num_in_idx_hash@plt>
  lea    0x1(%rbx),%esi
  cmp    $0xffffffff,%eax
  jne    L12
  mov    %r15,%rdx
  mov    %r14d,%edi
  add    $0x1,%rbx
  call   <insert_num_to_idx_hash@plt>
  test   %eax,%eax
  je     L47
L20:
  cmp    %ebx,%r12d
  jg     L23
L47:
  xor    %r15d,%r15d
L27:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %eax,(%r15)
  mov    %esi,0x4(%r15)
  jmp    L27
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *nums_idx = malloc(sizeof(int) * 2);
  int *nums_idx_hash = malloc(sizeof(int) * 35023);
  memset(nums_idx_hash, 0, sizeof(int) * 35023);
  int i;
  int num, num_hash;
  int pair_num_idx;
  int insert_flag;
  for (int i = 0; i < numsSize; i++) {
    num = nums[i];
    if ((pair_num_idx = check_num_in_idx_hash(target - num, nums, nums_idx_hash)) != -1) {
      nums_idx_hash[0] = pair_num_idx;
      nums_idx_hash[1] = i + 1;
      return nums_idx_hash;
    }
    insert_flag = insert_num_to_idx_hash(num, i + 1, nums_idx_hash);
    if (insert_flag == 0)
      return NULL;
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<twoSum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x2233c,%edi
  call   <malloc@plt>
  mov    $0x2233c,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memset@plt>
  jmp    L34
  nopl   (%rax)
L43:
  mov    0x0(%rbp,%rbx,4),%r14d
  mov    %r13d,%edi
  mov    %rbp,%rsi
  mov    %r15,%rdx
  sub    %r14d,%edi
  call   <check_num_in_idx_hash@plt>
  lea    0x1(%rbx),%esi
  cmp    $0xffffffff,%eax
  jne    L21
  mov    %r15,%rdx
  mov    %r14d,%edi
  add    $0x1,%rbx
  call   <insert_num_to_idx_hash@plt>
  test   %eax,%eax
  je     L45
L34:
  cmp    %ebx,%r12d
  jg     L43
L45:
  xor    %r15d,%r15d
L16:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  movd   %eax,%xmm0
  movd   %esi,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%r15)
  jmp    L16
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *nums_idx = malloc(sizeof(int) * 2);
  int *nums_idx_hash = malloc(sizeof(int) * 35023);
  memset(nums_idx_hash, 0, sizeof(int) * 35023);
  int i;
  int num, num_hash;
  int pair_num_idx;
  int insert_flag;
  for (int i = 0; i < numsSize; i++) {
    num = nums[i];
    if ((pair_num_idx = check_num_in_idx_hash(target - num, nums, nums_idx_hash)) != -1) {
      nums_idx_hash[0] = pair_num_idx;
      nums_idx_hash[1] = i + 1;
      return nums_idx_hash;
    }
    insert_flag = insert_num_to_idx_hash(num, i + 1, nums_idx_hash);
    if (insert_flag == 0)
      return NULL;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L5
L10:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0xa,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <modular_pow@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jg     L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D22
type: string
name: unpack_data
arguments: tag: D17
type: string

tool: D14: %d

tool: D22: %d %d

tool: D17: %d


assistant: ```c
int main() {
  int t, x, a, b;
  scanf("%d", &t);
  while (t-- > 0) {
    scanf("%d %d", &a, &b);
    x = modular_pow(a, b, 10);
    printf("%d\n", x);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L16
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D24(%rip),%rbp
  lea    D26(%rip),%rbx
L12:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0xa,%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <modular_pow@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L12
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D24
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: string

tool: D0: %d

tool: D24: %d %d

tool: D26: %d


assistant: ```c
int main() {
  int t, x, a, b;
  scanf("%d", &t);
  while (t-- > 0) {
    scanf("%d %d", &a, &b);
    x = modular_pow(a, b, 10);
    printf("%d\n", x);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L28
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D22(%rip),%rbp
  lea    D24(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  mov    $0xa,%edx
  call   <modular_pow@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L4
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D22
type: string
name: read_data
arguments: label: D24
type: string

tool: D17: %d

tool: D22: %d %d

tool: D24: %d


assistant: ```c
int main() {
  int t, x, a, b;
  scanf("%d", &t);
  while (t-- > 0) {
    scanf("%d %d", &a, &b);
    x = modular_pow(a, b, 10);
    printf("%d\n", x);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D23(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L29
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D24(%rip),%rbp
  lea    D27(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  mov    $0xa,%edx
  call   <modular_pow@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L3
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
data_type: string
name: extract_symbolic_data
arguments: label: D24
data_type: string
name: extract_symbolic_data
arguments: label: D27
data_type: string

tool: D23: %d

tool: D24: %d %d

tool: D27: %d


assistant: ```c
int main() {
  int t, x, a, b;
  scanf("%d", &t);
  while (t-- > 0) {
    scanf("%d %d", &a, &b);
    x = modular_pow(a, b, 10);
    printf("%d\n", x);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ss_write_bytevector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
L8:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L15
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  sub    %rax,-0x28(%rbp)
L15:
  cmpq   $0x0,-0x28(%rbp)
  je     L14
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L8
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L8
L14:
  cmpl   $0xffffffff,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int ss_write_bytevector(int fd, const char *buf, size_t count) {
  ssize_t res;
  do {
    res = write(fd, buf, count);
    if (res > 0) {
      buf += res;
      count -= res;
    }
  } while (count && (res != -1 || errno == EINTR));
  return res != -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<ss_write_bytevector>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  jmp    L51
L25:
  test   %rbx,%rbx
  je     L50
  cmp    $0xffffffff,%eax
  jne    L51
  mov    D13(%rip),%rcx
  mov    D4(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L50
L51:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L25
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %rdx,%rbx
  jne    L51
L50:
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ss_write_bytevector(int fd, const char *buf, size_t count) {
  ssize_t res;
  do {
    res = write(fd, buf, count);
    if (res > 0) {
      buf += res;
      count -= res;
    }
  } while (count && (res != -1 || errno == EINTR));
  return res != -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ss_write_bytevector>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
L0:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L34
  cltq
  add    %rax,%r12
  sub    %rax,%rbx
  jne    L0
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L34:
  test   %rbx,%rbx
  je     L4
  cmp    $0xffffffff,%eax
  jne    L0
  mov    D7(%rip),%rax
  mov    D13(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L0
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L4:
  cmp    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  setne  %al
  pop    %r12
  movzbl %al,%eax
  ret
```

assistant: ```c
int ss_write_bytevector(int fd, const char *buf, size_t count) {
  ssize_t res;
  do {
    res = write(fd, buf, count);
    if (res > 0) {
      buf += res;
      count -= res;
    }
  } while (count && (res != -1 || errno == EINTR));
  return res != -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ss_write_bytevector>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
L48:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L49
  cltq
  add    %rax,%r12
  sub    %rax,%rbx
  jne    L48
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L49:
  test   %rbx,%rbx
  je     L27
  cmp    $0xffffffff,%eax
  jne    L48
  mov    D12(%rip),%rax
  mov    D19(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L48
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L27:
  cmp    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  setne  %al
  pop    %r12
  movzbl %al,%eax
  ret
```

assistant: ```c
int ss_write_bytevector(int fd, const char *buf, size_t count) {
  ssize_t res;
  do {
    res = write(fd, buf, count);
    if (res > 0) {
      buf += res;
      count -= res;
    }
  } while (count && (res != -1 || errno == EINTR));
  return res != -1;
}
```