ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xilinxcorelib_a_1975148188_2959432447_p_3>:
  endbr64
  push   %rbx
  mov    0x2a20(%rdi),%rax
  mov    %rdi,%rbx
  mov    $0x10,%edx
  mov    0x790(%rdi),%rsi
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  lea    0x29e8(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x28a8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_1975148188_2959432447_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 1936U);
  t2 = *((char **)t1);
  t1 = (t0 + 10728);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 16U);
  xsi_driver_first_trans_fast_port(t1);
LAB2:
  t7 = (t0 + 10408);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chap_md5_generate_challenge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <drand48@plt>
  add    $0x2,%eax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <random_bytes@plt>
  nop
  leave
  ret
```

assistant: ```c
void chap_md5_generate_challenge(unsigned char *cp) {
  int clen;
  clen = (int)(drand48() * (24 - 16)) + 16;
  *cp++ = clen;
  random_bytes(cp, clen);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chap_md5_generate_challenge>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <drand48@plt>
  lea    0x10(,%rax,8),%esi
  mov    %sil,(%rbx)
  lea    0x1(%rbx),%rdi
  call   <random_bytes@plt>
  pop    %rbx
  ret
```

assistant: ```c
void chap_md5_generate_challenge(unsigned char *cp) {
  int clen;
  clen = (int)(drand48() * (24 - 16)) + 16;
  *cp++ = clen;
  random_bytes(cp, clen);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<chap_md5_generate_challenge>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <drand48@plt>
  lea    0x1(%rbx),%rdi
  lea    0x10(,%rax,8),%esi
  mov    %sil,(%rbx)
  pop    %rbx
  jmp    1060 <random_bytes@plt>
```

assistant: ```c
void chap_md5_generate_challenge(unsigned char *cp) {
  int clen;
  clen = (int)(drand48() * (24 - 16)) + 16;
  *cp++ = clen;
  random_bytes(cp, clen);
}
```
user: What is the c source code of the assembly code below?

```asm
<chap_md5_generate_challenge>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <drand48@plt>
  lea    0x1(%rbx),%rdi
  lea    0x10(,%rax,8),%esi
  mov    %sil,(%rbx)
  pop    %rbx
  jmp    1060 <random_bytes@plt>
```

assistant: ```c
void chap_md5_generate_challenge(unsigned char *cp) {
  int clen;
  clen = (int)(drand48() * (24 - 16)) + 16;
  *cp++ = clen;
  random_bytes(cp, clen);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L4
L59:
  cmpb   $0x9,-0x5(%rbp)
  jne    L47
  movl   $0x0,-0x4(%rbp)
  jmp    L55
L44:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L55:
  cmpl   $0x3,-0x4(%rbp)
  jle    L44
  jmp    L4
L47:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L4:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  mov    D6(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L59
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  int i;
  while ((c = getchar()) != EOF) {
    if (c == '\t') {
      for (i = 0; i < 4; i++) {
        putchar(' ');
      }
    } else
      putchar(c);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L39
L26:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
L39:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D4(%rip),%rdx
  cmp    %al,(%rdx)
  je     L8
  cmp    $0x9,%al
  je     L26
  movsbl %al,%edi
  call   <putchar@plt>
  jmp    L39
L8:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  int i;
  while ((c = getchar()) != EOF) {
    if (c == '\t') {
      for (i = 0; i < 4; i++) {
        putchar(' ');
      }
    } else
      putchar(c);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    D3(%rip),%rbx
L13:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  je     L6
L36:
  cmp    $0x9,%al
  je     L10
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L36
L6:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L13
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  int i;
  while ((c = getchar()) != EOF) {
    if (c == '\t') {
      for (i = 0; i < 4; i++) {
        putchar(' ');
      }
    } else
      putchar(c);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  je     L16
L13:
  cmp    $0x9,%al
  je     L21
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L13
L16:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L2
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  int i;
  while ((c = getchar()) != EOF) {
    if (c == '\t') {
      for (i = 0; i < 4; i++) {
        putchar(' ');
      }
    } else
      putchar(c);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ctl_epoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x2c(%rbp)
  je     L28
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <epoll_ctl@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L4
L28:
  mov    -0x28(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <epoll_ctl@plt>
  mov    %eax,-0x14(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int ctl_epoll(int epfd, int cfd, int action, int event_type) {
  int ret;
  if (action != EPOLL_CTL_DEL) {
    struct epoll_event ev;
    memset(&ev, 0, sizeof(struct epoll_event));
    ev.data.fd = cfd;
    ev.events = event_type;
    ret = epoll_ctl(epfd, action, cfd, &ev);
  } else {
    ret = epoll_ctl(epfd, action, cfd, NULL);
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ctl_epoll>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  cmp    %edx,(%rax)
  je     L2
  mov    %ecx,%r13d
  mov    %rsp,%r14
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  mov    %ebp,0x4(%rsp)
  mov    %r13d,(%rsp)
  mov    %r14,%rcx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <epoll_ctl@plt>
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  mov    $0x0,%ecx
  mov    %esi,%edx
  mov    %ebx,%esi
  call   <epoll_ctl@plt>
  jmp    L16
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ctl_epoll(int epfd, int cfd, int action, int event_type) {
  int ret;
  if (action != EPOLL_CTL_DEL) {
    struct epoll_event ev;
    memset(&ev, 0, sizeof(struct epoll_event));
    ev.data.fd = cfd;
    ev.events = event_type;
    ret = epoll_ctl(epfd, action, cfd, &ev);
  } else {
    ret = epoll_ctl(epfd, action, cfd, NULL);
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ctl_epoll>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D3(%rip),%rax
  cmp    %edx,(%rax)
  je     L20
  mov    %rsp,%r14
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %ecx,%ebx
  mov    %r14,%rdi
  call   <memset@plt>
  mov    %r12d,%edx
  mov    %r14,%rcx
  mov    %ebp,%esi
  mov    %r13d,%edi
  mov    %r12d,0x4(%rsp)
  mov    %ebx,(%rsp)
  call   <epoll_ctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  mov    %esi,%edx
  xor    %ecx,%ecx
  mov    %ebp,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <epoll_ctl@plt>
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ctl_epoll(int epfd, int cfd, int action, int event_type) {
  int ret;
  if (action != EPOLL_CTL_DEL) {
    struct epoll_event ev;
    memset(&ev, 0, sizeof(struct epoll_event));
    ev.data.fd = cfd;
    ev.events = event_type;
    ret = epoll_ctl(epfd, action, cfd, &ev);
  } else {
    ret = epoll_ctl(epfd, action, cfd, NULL);
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ctl_epoll>:
  endbr64
  push   %r14
  movd   %ecx,%xmm0
  movd   %esi,%xmm1
  push   %r13
  punpckldq %xmm1,%xmm0
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  movq   %xmm0,0x8(%rsp)
  cmp    %edx,(%rax)
  je     L21
  lea    0x10(%rsp),%r14
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %r14,%rdi
  call   <memset@plt>
  mov    %r12d,%edx
  mov    %r14,%rcx
  mov    %ebp,%esi
  movq   0x8(%rsp),%xmm0
  mov    %r13d,%edi
  movq   %xmm0,0x10(%rsp)
  call   <epoll_ctl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  mov    %esi,%edx
  xor    %ecx,%ecx
  mov    %ebp,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <epoll_ctl@plt>
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ctl_epoll(int epfd, int cfd, int action, int event_type) {
  int ret;
  if (action != EPOLL_CTL_DEL) {
    struct epoll_event ev;
    memset(&ev, 0, sizeof(struct epoll_event));
    ev.data.fd = cfd;
    ev.events = event_type;
    ret = epoll_ctl(epfd, action, cfd, &ev);
  } else {
    ret = epoll_ctl(epfd, action, cfd, NULL);
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<elf_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L19:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0xf0000000,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L27
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  xor    %eax,-0x8(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int elf_hash(const unsigned char *name) {
  unsigned int h = 0, g;
  while (*name) {
    h = (h << 4) + *(name++);
    if ((g = h & 0xf0000000))
      h ^= g >> 24;
    h ^= g;
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<elf_hash>:
  endbr64
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  movzbl %cl,%eax
  mov    $0x0,%edx
  test   %cl,%cl
  jne    L19
  mov    $0x0,%eax
  ret
L4:
  shl    $0x4,%eax
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  mov    %edx,%ecx
  shr    $0x18,%ecx
  xor    %eax,%ecx
  test   %edx,%edx
  cmovne %ecx,%eax
L19:
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L4
  ret
```

assistant: ```c
unsigned int elf_hash(const unsigned char *name) {
  unsigned int h = 0, g;
  while (*name) {
    h = (h << 4) + *(name++);
    if ((g = h & 0xf0000000))
      h ^= g >> 24;
    h ^= g;
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<elf_hash>:
  endbr64
  movzbl (%rdi),%eax
  xor    %edx,%edx
  add    $0x1,%rdi
  test   %al,%al
  jne    L26
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L17:
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  mov    %edx,%ecx
  shr    $0x18,%ecx
  xor    %eax,%ecx
  test   %edx,%edx
  cmovne %ecx,%eax
L26:
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L17
  ret
  nop
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int elf_hash(const unsigned char *name) {
  unsigned int h = 0, g;
  while (*name) {
    h = (h << 4) + *(name++);
    if ((g = h & 0xf0000000))
      h ^= g >> 24;
    h ^= g;
  }
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<elf_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L29
  nopw   0x0(%rax,%rax,1)
L28:
  shl    $0x4,%eax
  add    $0x1,%rcx
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L43
  mov    %edx,%esi
  shr    $0x18,%esi
  xor    %esi,%eax
  xor    %edx,%eax
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L28
  ret
  nopl   0x0(%rax)
L43:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L28
  ret
L29:
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int elf_hash(const unsigned char *name) {
  unsigned int h = 0, g;
  while (*name) {
    h = (h << 4) + *(name++);
    if ((g = h & 0xf0000000))
      h ^= g >> 24;
    h ^= g;
  }
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gs1_compliant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <check_force_gs1@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x47,-0x14(%rbp)
  jg     L67
  cmpl   $0x17,-0x14(%rbp)
  jge    L23
  jmp    L54
L81:
  mov    -0x14(%rbp),%eax
  sub    $0x5c,%eax
  movabs $0x32000000800001,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L24
  jmp    L54
L23:
  mov    -0x14(%rbp),%eax
  sub    $0x17,%eax
  movabs $0x1000800000003,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L24
  jmp    L54
L67:
  cmpl   $0x91,-0x14(%rbp)
  jg     L54
  cmpl   $0x5c,-0x14(%rbp)
  jge    L81
  jmp    L54
L24:
  movl   $0x1,-0x4(%rbp)
  nop
L54:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int gs1_compliant(const int symbology) {
  int result = check_force_gs1(symbology);
  switch (symbology) {
  case 23:
  case 92:
  case 71:
  case 141:
  case 24:
  case 58:
  case 115:
  case 145:
  case 144:
    result = 1;
    break;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gs1_compliant>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <check_force_gs1@plt>
  cmp    $0x47,%ebx
  jle    L39
  lea    -0x5c(%rbx),%ecx
  cmp    $0x35,%ecx
  ja     L5
  movabs $0x32000000800001,%rdx
  shr    %cl,%rdx
  test   $0x1,%dl
  mov    $0x1,%edx
  cmovne %edx,%eax
L5:
  pop    %rbx
  ret
L39:
  cmp    $0x16,%ebx
  jle    L5
  lea    -0x17(%rbx),%ecx
  movabs $0x1000800000003,%rdx
  shr    %cl,%rdx
  test   $0x1,%dl
  mov    $0x1,%edx
  cmovne %edx,%eax
  jmp    L5
```

assistant: ```c
int gs1_compliant(const int symbology) {
  int result = check_force_gs1(symbology);
  switch (symbology) {
  case 23:
  case 92:
  case 71:
  case 141:
  case 24:
  case 58:
  case 115:
  case 145:
  case 144:
    result = 1;
    break;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gs1_compliant>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <check_force_gs1@plt>
  cmp    $0x47,%ebx
  jle    L7
  lea    -0x5c(%rbx),%ecx
  cmp    $0x35,%ecx
  ja     L17
  movabs $0x32000000800001,%rdx
  shr    %cl,%rdx
  and    $0x1,%edx
  mov    $0x1,%edx
  cmovne %edx,%eax
L17:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    $0x16,%ebx
  jle    L17
  movabs $0x1000800000003,%rdx
  lea    -0x17(%rbx),%ecx
  pop    %rbx
  shr    %cl,%rdx
  and    $0x1,%edx
  mov    $0x1,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int gs1_compliant(const int symbology) {
  int result = check_force_gs1(symbology);
  switch (symbology) {
  case 23:
  case 92:
  case 71:
  case 141:
  case 24:
  case 58:
  case 115:
  case 145:
  case 144:
    result = 1;
    break;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gs1_compliant>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <check_force_gs1@plt>
  cmp    $0x47,%ebx
  jle    L14
  lea    -0x5c(%rbx),%ecx
  cmp    $0x35,%ecx
  ja     L29
  movabs $0x32000000800001,%rdx
  shr    %cl,%rdx
  and    $0x1,%edx
  mov    $0x1,%edx
  cmovne %edx,%eax
L29:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  cmp    $0x16,%ebx
  jle    L29
  movabs $0x1000800000003,%rdx
  lea    -0x17(%rbx),%ecx
  pop    %rbx
  shr    %cl,%rdx
  and    $0x1,%edx
  mov    $0x1,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int gs1_compliant(const int symbology) {
  int result = check_force_gs1(symbology);
  switch (symbology) {
  case 23:
  case 92:
  case 71:
  case 141:
  case 24:
  case 58:
  case 115:
  case 145:
  case 144:
    result = 1;
    break;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kmpVektor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0xffffffff,(%rax)
  movl   $0x1,-0xc(%rbp)
  jmp    L16
L44:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L30
L18:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L30:
  cmpl   $0x0,-0x8(%rbp)
  js     L11
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L18
L11:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L44
  nop
  nop
  leave
  ret
```

assistant: ```c
void kmpVektor(char *vzor, int vektor[]) {
  int delka = strlen(vzor);
  int stav;
  int prechod;
  vektor[0] = -1;
  for (stav = 1; stav < delka; stav++) {
    prechod = vektor[stav - 1];
    while ((prechod > -1) && (vzor[prechod] != vzor[stav - 1])) {
      prechod = vektor[prechod];
    }
    vektor[stav] = prechod + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kmpVektor>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  movl   $0xffffffff,0x0(%rbp)
  cmp    $0x1,%eax
  jle    L54
  lea    -0x1(%rax),%edi
  mov    $0x1,%esi
  mov    $0xffffffff,%eax
  jmp    L35
L22:
  add    $0x1,%rsi
L35:
  add    $0x1,%eax
  mov    %eax,0x0(%rbp,%rsi,4)
  cmp    %rdi,%rsi
  je     L54
  test   %eax,%eax
  js     L22
  movzbl (%rbx,%rsi,1),%ecx
L57:
  movslq %eax,%rdx
  cmp    %cl,(%rbx,%rdx,1)
  je     L22
  mov    0x0(%rbp,%rdx,4),%eax
  test   %eax,%eax
  jns    L57
  jmp    L22
L54:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kmpVektor(char *vzor, int vektor[]) {
  int delka = strlen(vzor);
  int stav;
  int prechod;
  vektor[0] = -1;
  for (stav = 1; stav < delka; stav++) {
    prechod = vektor[stav - 1];
    while ((prechod > -1) && (vzor[prechod] != vzor[stav - 1])) {
      prechod = vektor[prechod];
    }
    vektor[stav] = prechod + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kmpVektor>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movl   $0xffffffff,0x0(%rbp)
  cmp    $0x1,%eax
  jle    L69
  lea    -0x1(%rax),%edi
  mov    $0xffffffff,%eax
  mov    $0x1,%esi
  add    $0x1,%eax
  mov    %eax,0x0(%rbp,%rsi,4)
  cmp    %rsi,%rdi
  je     L69
  nopw   0x0(%rax,%rax,1)
L45:
  test   %eax,%eax
  js     L60
  movzbl (%rbx,%rsi,1),%ecx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L61:
  mov    0x0(%rbp,%rdx,4),%eax
  test   %eax,%eax
  js     L60
L29:
  movslq %eax,%rdx
  cmp    %cl,(%rbx,%rdx,1)
  jne    L61
L60:
  add    $0x1,%rsi
  add    $0x1,%eax
  mov    %eax,0x0(%rbp,%rsi,4)
  cmp    %rsi,%rdi
  jne    L45
L69:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kmpVektor(char *vzor, int vektor[]) {
  int delka = strlen(vzor);
  int stav;
  int prechod;
  vektor[0] = -1;
  for (stav = 1; stav < delka; stav++) {
    prechod = vektor[stav - 1];
    while ((prechod > -1) && (vzor[prechod] != vzor[stav - 1])) {
      prechod = vektor[prechod];
    }
    vektor[stav] = prechod + 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<kmpVektor>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movl   $0xffffffff,(%rbx)
  cmp    $0x1,%eax
  jle    L17
  movl   $0x0,0x4(%rbx)
  movslq %eax,%rdi
  mov    $0x2,%esi
  cmp    $0x2,%eax
  je     L17
  nopl   0x0(%rax)
L44:
  mov    -0x4(%rbx,%rsi,4),%eax
  test   %eax,%eax
  js     L56
  movzbl -0x1(%rbp,%rsi,1),%ecx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L47:
  mov    (%rbx,%rdx,4),%eax
  test   %eax,%eax
  js     L56
L27:
  movslq %eax,%rdx
  cmp    %cl,0x0(%rbp,%rdx,1)
  jne    L47
L56:
  add    $0x1,%eax
  mov    %eax,(%rbx,%rsi,4)
  add    $0x1,%rsi
  cmp    %rdi,%rsi
  jne    L44
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kmpVektor(char *vzor, int vektor[]) {
  int delka = strlen(vzor);
  int stav;
  int prechod;
  vektor[0] = -1;
  for (stav = 1; stav < delka; stav++) {
    prechod = vektor[stav - 1];
    while ((prechod > -1) && (vzor[prechod] != vzor[stav - 1])) {
      prechod = vektor[prechod];
    }
    vektor[stav] = prechod + 1;
  }
}
```