user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x94(%rbp)
  jmp    L41
L1:
  mov    -0x94(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rcx
  mov    -0x94(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x94(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rdx
  mov    -0x94(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x94(%rbp)
L41:
  cmpl   $0x4,-0x94(%rbp)
  jle    L1
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x94(%rbp)
  jmp    L28
L31:
  mov    -0x94(%rbp),%eax
  cltq
  movss  -0x90(%rbp,%rax,4),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D58(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x94(%rbp),%eax
  cltq
  movss  -0x90(%rbp,%rax,4),%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  movq   %xmm2,%rdx
  lea    -0x70(%rbp),%rsi
  mov    -0x94(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %rax,%rsi
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  addl   $0x1,-0x94(%rbp)
L28:
  cmpl   $0x4,-0x94(%rbp)
  jle    L31
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
type_guessed: string
name: retrieve_data
arguments: data_tag: D79
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D51
type_guessed: string
name: retrieve_data
arguments: data_tag: D37
type_guessed: string
name: retrieve_data
arguments: data_tag: D52
type_guessed: string
name: retrieve_data
arguments: data_tag: D58
type_guessed: f64
name: retrieve_data
arguments: data_tag: D80
type_guessed: string

tool: D26: 
Entre com nome do %d. funcionario:

tool: D79: %s

tool: D3: 
Entre com salario do %d. funcionario:

tool: D51: %f

tool: D37: 
Nome		Salario Bruto	Salario Liquido

tool: D52: 
--------------------------------------------------

tool: D58: 0.8

tool: D80: 
%s		%.2f		%.2f

assistant: ```c
int main() {
  char nomes[5][20];
  float salarios[5];
  int i;
  for (i = 0; i < 5; i++) {
    printf("\nEntre com nome do %d. funcionario:", i + 1);
    scanf("%s", nomes[i]);
    printf("\nEntre com salario do %d. funcionario:", i + 1);
    scanf("%f", &salarios[i]);
  }
  printf("\nNome\t\tSalario Bruto\tSalario Liquido");
  printf("\n--------------------------------------------------");
  for (i = 0; i < 5; i++) {
    printf("\n%s\t\t%.2f\t\t%.2f", nomes[i], salarios[i], salarios[i] * 0.8);
  }
  printf("\n--------------------------------------------------");
  return 0;
}
```