ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  test   %al,%al
  je     L28
  cmp    %cl,%al
  jne    L28
  mov    $0x1,%edx
L30:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  je     L28
  cmp    %cl,%al
  je     L30
L28:
  movsbl %al,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a == *b) {
    if (*a == '\0') {
      break;
    }
    ++a, ++b;
  }
  return *a - *b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L10
  mov    $0x1,%eax
  jmp    L21
  nopl   (%rax)
L27:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L10
L21:
  test   %dl,%dl
  jne    L27
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a == *b) {
    if (*a == '\0') {
      break;
    }
    ++a, ++b;
  }
  return *a - *b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L23
  mov    $0x1,%eax
  jmp    L21
  nopl   (%rax)
L19:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L23
L21:
  test   %dl,%dl
  jne    L19
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a == *b) {
    if (*a == '\0') {
      break;
    }
    ++a, ++b;
  }
  return *a - *b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isgraph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L4
L6:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isprint@plt>
L4:
  leave
  ret
```

assistant: ```c
int isgraph(int ch) {
  if (ch == ' ')
    return 0;
  return isprint(ch);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isgraph>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x20,%edi
  je     L2
  sub    $0x8,%rsp
  call   <isprint@plt>
  add    $0x8,%rsp
  ret
L2:
  ret
```

assistant: ```c
int isgraph(int ch) {
  if (ch == ' ')
    return 0;
  return isprint(ch);
}
```
user: Translate the below assembly code into C programming language:

```asm
<isgraph>:
  endbr64
  cmp    $0x20,%edi
  je     L1
  jmp    1050 <isprint@plt>
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isgraph(int ch) {
  if (ch == ' ')
    return 0;
  return isprint(ch);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isgraph>:
  endbr64
  cmp    $0x20,%edi
  je     L6
  jmp    1050 <isprint@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isgraph(int ch) {
  if (ch == ' ')
    return 0;
  return isprint(ch);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  movl   $0x5,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  *((int *)0) = 5;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  movl   $0x5,0x0
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  *((int *)0) = 5;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
int main() {
  *((int *)0) = 5;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
int main() {
  *((int *)0) = 5;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_resolve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  shl    $0x3,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x50,-0x1c(%rbp)
  jle    L49
  mov    $0x1,%eax
  jmp    L16
L49:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L24
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_resolve>
  jmp    L16
L24:
  movl   $0x1,-0xc(%rbp)
  jmp    L22
L72:
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ft_pos_ok@plt>
  test   %rax,%rax
  je     L25
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_resolve>
  test   %eax,%eax
  je     L25
  mov    $0x1,%eax
  jmp    L16
L25:
  addl   $0x1,-0xc(%rbp)
L22:
  cmpl   $0x9,-0xc(%rbp)
  jle    L72
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int ft_resolve(int **tab, int pos) {
  int k;
  int x;
  int y;
  x = pos / 9;
  y = pos % 9;
  if (pos >= 81)
    return (1);
  if (tab[x][y])
    return (ft_resolve(tab, pos + 1));
  k = 1;
  while (k < 10) {
    if (ft_pos_ok(k, tab, x, y)) {
      tab[x][y] = k;
      if (ft_resolve(tab, pos + 1))
        return (1);
    }
    k++;
  }
  tab[x][y] = 0;
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_resolve>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x1,0x8(%rsp)
  cmp    $0x50,%esi
  jg     L12
  mov    %rdi,%r12
  movslq %esi,%rbp
  imul   $0x38e38e39,%rbp,%rbp
  sar    $0x21,%rbp
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  lea    0x0(%rbp,%rbp,8),%eax
  mov    %esi,%r13d
  sub    %eax,%r13d
  movslq %ebp,%rax
  lea    (%rdi,%rax,8),%r14
  movslq %r13d,%r15
  lea    0x0(,%r15,4),%rax
  mov    %rax,(%rsp)
  mov    (%r14),%rax
  mov    (%rax,%r15,4),%eax
  mov    %eax,0x8(%rsp)
  mov    $0x1,%ebx
  lea    0x1(%rsi),%ecx
  mov    %ecx,0xc(%rsp)
  test   %eax,%eax
  je     L16
  mov    %ecx,%esi
  call   <ft_resolve>
  mov    %eax,0x8(%rsp)
  jmp    L12
L19:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L9
L16:
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <ft_pos_ok@plt>
  test   %rax,%rax
  je     L19
  mov    (%r14),%rax
  mov    (%rsp),%rdx
  mov    %ebx,(%rax,%rdx,1)
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <ft_resolve>
  test   %eax,%eax
  je     L19
  movl   $0x1,0x8(%rsp)
  jmp    L12
L9:
  mov    (%r14),%rax
  movl   $0x0,(%rax,%r15,4)
L12:
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ft_resolve(int **tab, int pos) {
  int k;
  int x;
  int y;
  x = pos / 9;
  y = pos % 9;
  if (pos >= 81)
    return (1);
  if (tab[x][y])
    return (ft_resolve(tab, pos + 1));
  k = 1;
  while (k < 10) {
    if (ft_pos_ok(k, tab, x, y)) {
      tab[x][y] = k;
      if (ft_resolve(tab, pos + 1))
        return (1);
    }
    k++;
  }
  tab[x][y] = 0;
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_resolve>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %rbx,%rax
  imul   $0x38e38e39,%rbx,%rbx
  cltd
  mov    %eax,%r12d
  sub    $0x18,%rsp
  sar    $0x21,%rbx
  sub    %edx,%ebx
  lea    (%rbx,%rbx,8),%edx
  sub    %edx,%r12d
  cmp    $0x50,%eax
  jle    L7
  jmp    L34
  nopl   0x0(%rax)
L82:
  add    $0x1,%eax
  movslq %eax,%rbx
  cltd
  mov    %eax,%r12d
  imul   $0x38e38e39,%rbx,%rbx
  sar    $0x21,%rbx
  sub    %edx,%ebx
  lea    (%rbx,%rbx,8),%edx
  sub    %edx,%r12d
  cmp    $0x51,%eax
  je     L34
L7:
  movslq %ebx,%rdx
  lea    (%r14,%rdx,8),%r15
  movslq %r12d,%rdx
  mov    (%r15),%rcx
  lea    0x0(,%rdx,4),%rbp
  mov    (%rcx,%rdx,4),%r13d
  test   %r13d,%r13d
  jne    L82
  add    $0x1,%eax
  mov    $0x1,%r9d
  mov    %eax,0xc(%rsp)
  jmp    L44
  nop
L51:
  add    $0x1,%r9d
  cmp    $0xa,%r9d
  je     L62
L44:
  mov    %r9d,%edi
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r9d,0x8(%rsp)
  call   <ft_pos_ok@plt>
  mov    0x8(%rsp),%r9d
  test   %rax,%rax
  je     L51
  mov    (%r15),%rax
  mov    0xc(%rsp),%esi
  mov    %r14,%rdi
  mov    %r9d,0x8(%rsp)
  mov    %r9d,(%rax,%rbp,1)
  call   <ft_resolve>
  mov    0x8(%rsp),%r9d
  test   %eax,%eax
  je     L51
  nopw   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%r13d
L81:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  mov    (%r15),%rax
  movl   $0x0,(%rax,%rbp,1)
  jmp    L81
```

assistant: ```c
int ft_resolve(int **tab, int pos) {
  int k;
  int x;
  int y;
  x = pos / 9;
  y = pos % 9;
  if (pos >= 81)
    return (1);
  if (tab[x][y])
    return (ft_resolve(tab, pos + 1));
  k = 1;
  while (k < 10) {
    if (ft_pos_ok(k, tab, x, y)) {
      tab[x][y] = k;
      if (ft_resolve(tab, pos + 1))
        return (1);
    }
    k++;
  }
  tab[x][y] = 0;
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_resolve>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %rbx,%rax
  imul   $0x38e38e39,%rbx,%rbx
  cltd
  mov    %eax,%r12d
  sub    $0x18,%rsp
  sar    $0x21,%rbx
  sub    %edx,%ebx
  lea    (%rbx,%rbx,8),%edx
  sub    %edx,%r12d
  cmp    $0x50,%eax
  jle    L68
  jmp    L65
  nopl   0x0(%rax)
L64:
  add    $0x1,%eax
  movslq %eax,%rbx
  cltd
  mov    %eax,%r12d
  imul   $0x38e38e39,%rbx,%rbx
  sar    $0x21,%rbx
  sub    %edx,%ebx
  lea    (%rbx,%rbx,8),%edx
  sub    %edx,%r12d
  cmp    $0x51,%eax
  je     L65
L68:
  movslq %ebx,%rdx
  lea    (%r14,%rdx,8),%r15
  movslq %r12d,%rdx
  mov    (%r15),%rcx
  lea    0x0(,%rdx,4),%rbp
  mov    (%rcx,%rdx,4),%r13d
  test   %r13d,%r13d
  jne    L64
  add    $0x1,%eax
  mov    $0x1,%r9d
  mov    %eax,0xc(%rsp)
  jmp    L81
  nop
L36:
  add    $0x1,%r9d
  cmp    $0xa,%r9d
  je     L10
L81:
  mov    %r9d,%edi
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r9d,0x8(%rsp)
  call   <ft_pos_ok@plt>
  mov    0x8(%rsp),%r9d
  test   %rax,%rax
  je     L36
  mov    (%r15),%rax
  mov    0xc(%rsp),%esi
  mov    %r14,%rdi
  mov    %r9d,0x8(%rsp)
  mov    %r9d,(%rax,%rbp,1)
  call   <ft_resolve>
  mov    0x8(%rsp),%r9d
  test   %eax,%eax
  je     L36
  nopw   0x0(%rax,%rax,1)
L65:
  mov    $0x1,%r13d
L54:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%r15),%rax
  movl   $0x0,(%rax,%rbp,1)
  jmp    L54
```

assistant: ```c
int ft_resolve(int **tab, int pos) {
  int k;
  int x;
  int y;
  x = pos / 9;
  y = pos % 9;
  if (pos >= 81)
    return (1);
  if (tab[x][y])
    return (ft_resolve(tab, pos + 1));
  k = 1;
  while (k < 10) {
    if (ft_pos_ok(k, tab, x, y)) {
      tab[x][y] = k;
      if (ft_resolve(tab, pos + 1))
        return (1);
    }
    k++;
  }
  tab[x][y] = 0;
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clock_micro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
uint64_t clock_micro() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return (uint64_t)tv.tv_sec * 1000000ULL + (uint64_t)tv.tv_usec;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<clock_micro>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t clock_micro() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return (uint64_t)tv.tv_sec * 1000000ULL + (uint64_t)tv.tv_usec;
}
```
user: What is the c source code of the assembly code below?

```asm
<clock_micro>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t clock_micro() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return (uint64_t)tv.tv_sec * 1000000ULL + (uint64_t)tv.tv_usec;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clock_micro>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t clock_micro() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return (uint64_t)tv.tv_sec * 1000000ULL + (uint64_t)tv.tv_usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<call_putch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <eval_exp@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: %c

assistant: ```c
call_putch() {
  int value;
  eval_exp(&value);
  printf("%c", value);
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<call_putch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <eval_exp@plt>
  mov    0x4(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: %c

assistant: ```c
call_putch() {
  int value;
  eval_exp(&value);
  printf("%c", value);
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call_putch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <eval_exp@plt>
  mov    0x4(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string

tool: D2: %c

assistant: ```c
call_putch() {
  int value;
  eval_exp(&value);
  printf("%c", value);
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<call_putch>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <eval_exp@plt>
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: %c

assistant: ```c
call_putch() {
  int value;
  eval_exp(&value);
  printf("%c", value);
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_double_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  D6(%rip),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  setp   %al
  mov    $0x1,%edx
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: byte[8]
name: read_data
arguments: label: D15
type_infered: string

tool: {"D6": [0x75,0x9b,0x5a,0x70,0xd1,0x48,0x71,0xbf]}

tool: D15: gamcs[3] != 0

assistant: ```c
void test_double_array() {
  const static double gamcs[4] = {+.8571195590989331421920062399942e-2, +.4415381324841006757191315771652e-2, +.5685043681599363378632664588789e-1, -.4219835396418560501012500186624e-2};
  assertTrue("gamcs[3] != 0", gamcs[3] != 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_double_array>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  call   <assertTrue@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: gamcs[3] != 0

assistant: ```c
void test_double_array() {
  const static double gamcs[4] = {+.8571195590989331421920062399942e-2, +.4415381324841006757191315771652e-2, +.5685043681599363378632664588789e-1, -.4219835396418560501012500186624e-2};
  assertTrue("gamcs[3] != 0", gamcs[3] != 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_double_array>:
  endbr64
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  jmp    1050 <assertTrue@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: gamcs[3] != 0

assistant: ```c
void test_double_array() {
  const static double gamcs[4] = {+.8571195590989331421920062399942e-2, +.4415381324841006757191315771652e-2, +.5685043681599363378632664588789e-1, -.4219835396418560501012500186624e-2};
  assertTrue("gamcs[3] != 0", gamcs[3] != 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_double_array>:
  endbr64
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  jmp    1050 <assertTrue@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: gamcs[3] != 0

assistant: ```c
void test_double_array() {
  const static double gamcs[4] = {+.8571195590989331421920062399942e-2, +.4415381324841006757191315771652e-2, +.5685043681599363378632664588789e-1, -.4219835396418560501012500186624e-2};
  assertTrue("gamcs[3] != 0", gamcs[3] != 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Safe_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <Safe_strndup@plt>
  leave
  ret
```

assistant: ```c
char *Safe_strdup(const char *sz) {
  assert(sz);
  return Safe_strndup(sz, strlen(sz));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Safe_strdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <Safe_strndup@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *Safe_strdup(const char *sz) {
  assert(sz);
  return Safe_strndup(sz, strlen(sz));
}
```
user: What is the c source code of the assembly code below:

```asm
<Safe_strdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1080 <Safe_strndup@plt>
```

assistant: ```c
char *Safe_strdup(const char *sz) {
  assert(sz);
  return Safe_strndup(sz, strlen(sz));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Safe_strdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1080 <Safe_strndup@plt>
```

assistant: ```c
char *Safe_strdup(const char *sz) {
  assert(sz);
  return Safe_strndup(sz, strlen(sz));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x4,-0x4(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: num: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    printf("num: %d\n", i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D6(%rip),%rbp
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: num: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    printf("num: %d\n", i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L2:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D7: num: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    printf("num: %d\n", i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L6:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: num: %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 5; i++) {
    printf("num: %d\n", i);
  }
}
```