ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<emit_fmuls>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  mov    %edi,%edx
  lea    D7(%rip),%rdi
  mov    %ebx,%esi
  call   <assem_debug@plt>
  mov    %r12d,%edi
  mov    %ebx,%eax
  shl    $0x5,%r12d
  sar    %edi
  and    $0x20,%r12d
  shl    $0x16,%eax
  and    $0x7,%edi
  and    $0x400000,%eax
  shl    $0xb,%ebx
  or     %r12d,%edi
  and    $0x7000,%ebx
  or     %eax,%edi
  mov    %ebp,%eax
  shl    $0x7,%ebp
  shl    $0xf,%eax
  movzbl %bpl,%ebp
  and    $0x70000,%eax
  or     %eax,%edi
  or     %ebp,%edi
  or     %ebx,%edi
  pop    %rbx
  pop    %rbp
  or     $0xee200a00,%edi
  pop    %r12
  jmp    1070 <output_w32@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7: fmuls s%d,s%d,s%d

assistant: ```c
void emit_fmuls(int s1, int s2, int d) {
  assem_debug("fmuls s%d,s%d,s%d", d, s1, s2);
  output_w32(0xee200a00 | ((d & 14) << 11) | ((d & 1) << 22) | ((s1 & 14) << 15) | ((s1 & 1) << 7) | ((s2 & 14) >> 1) | ((s2 & 1) << 5));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<emit_fmuls>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  mov    %edi,%edx
  lea    D2(%rip),%rdi
  mov    %ebx,%esi
  call   <assem_debug@plt>
  mov    %r12d,%edi
  mov    %ebx,%eax
  shl    $0x5,%r12d
  sar    %edi
  and    $0x20,%r12d
  shl    $0x16,%eax
  and    $0x7,%edi
  and    $0x400000,%eax
  shl    $0xb,%ebx
  or     %r12d,%edi
  and    $0x7000,%ebx
  or     %eax,%edi
  mov    %ebp,%eax
  shl    $0x7,%ebp
  shl    $0xf,%eax
  movzbl %bpl,%ebp
  and    $0x70000,%eax
  or     %eax,%edi
  or     %ebp,%edi
  or     %ebx,%edi
  pop    %rbx
  pop    %rbp
  or     $0xee200a00,%edi
  pop    %r12
  jmp    1070 <output_w32@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: fmuls s%d,s%d,s%d

assistant: ```c
void emit_fmuls(int s1, int s2, int d) {
  assem_debug("fmuls s%d,s%d,s%d", d, s1, s2);
  output_w32(0xee200a00 | ((d & 14) << 11) | ((d & 1) << 22) | ((s1 & 14) << 15) | ((s1 & 1) << 7) | ((s2 & 14) >> 1) | ((s2 & 1) << 5));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_extract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  ja     L3
  movq   $0x0,-0x10(%rbp)
  jmp    L0
L3:
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L40
  mov    $0x0,%eax
  jmp    L43
L40:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  je     L25
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
L25:
  mov    -0x8(%rbp),%rax
L43:
  leave
  ret
```

assistant: ```c
char *_extract(char *a, char *b, size_t *len_ret) {
  size_t n;
  char *str;
  if (b <= a)
    n = 0;
  else
    n = b - a;
  str = malloc(n + 1);
  if (str == NULL)
    return NULL;
  memcpy(str, a, n);
  str[n] = '\0';
  if (len_ret != NULL)
    *len_ret = n;
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<_extract>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    %rsi,%rbp
  sub    %rdi,%rbp
  cmp    %rdi,%rsi
  mov    $0x0,%eax
  cmovbe %rax,%rbp
  lea    0x1(%rbp),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  test   %r13,%r13
  je     L5
  mov    %rbp,0x0(%r13)
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *_extract(char *a, char *b, size_t *len_ret) {
  size_t n;
  char *str;
  if (b <= a)
    n = 0;
  else
    n = b - a;
  str = malloc(n + 1);
  if (str == NULL)
    return NULL;
  memcpy(str, a, n);
  str[n] = '\0';
  if (len_ret != NULL)
    *len_ret = n;
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_extract>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rdi,%rsi
  jbe    L7
  mov    %rsi,%rbx
  sub    %rdi,%rbx
  lea    0x1(%rbx),%rdi
L1:
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L23
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  test   %r13,%r13
  je     L23
  mov    %rbx,0x0(%r13)
L23:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%edi
  xor    %ebx,%ebx
  jmp    L1
```

assistant: ```c
char *_extract(char *a, char *b, size_t *len_ret) {
  size_t n;
  char *str;
  if (b <= a)
    n = 0;
  else
    n = b - a;
  str = malloc(n + 1);
  if (str == NULL)
    return NULL;
  memcpy(str, a, n);
  str[n] = '\0';
  if (len_ret != NULL)
    *len_ret = n;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_extract>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rdi,%rsi
  jbe    L6
  mov    %rsi,%rbx
  sub    %rdi,%rbx
  lea    0x1(%rbx),%rdi
L19:
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  test   %r13,%r13
  je     L3
  mov    %rbx,0x0(%r13)
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%edi
  xor    %ebx,%ebx
  jmp    L19
```

assistant: ```c
char *_extract(char *a, char *b, size_t *len_ret) {
  size_t n;
  char *str;
  if (b <= a)
    n = 0;
  else
    n = b - a;
  str = malloc(n + 1);
  if (str == NULL)
    return NULL;
  memcpy(str, a, n);
  str[n] = '\0';
  if (len_ret != NULL)
    *len_ret = n;
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_morton1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x638f227,-0x12c(%rbp)
  movl   $0x75410c5,-0x128(%rbp)
  movl   $0x1f7,-0x120(%rbp)
  movl   $0x1fd,-0x11c(%rbp)
  movl   $0x989680,-0x124(%rbp)
  jmp    L11
L25:
  mov    -0x128(%rbp),%edx
  mov    -0x12c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <morton_encode@plt>
  mov    %rax,-0x118(%rbp)
  lea    -0x130(%rbp),%rdx
  lea    -0x134(%rbp),%rcx
  mov    -0x118(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <morton_decode@plt>
  mov    -0x134(%rbp),%eax
  cmp    %eax,-0x12c(%rbp)
  jne    L1
  mov    -0x130(%rbp),%eax
  cmp    %eax,-0x128(%rbp)
  je     L19
L1:
  lea    D7(%rip),%rax
  jmp    L51
L19:
  mov    -0x120(%rbp),%eax
  add    %eax,-0x12c(%rbp)
  mov    -0x11c(%rbp),%eax
  add    %eax,-0x128(%rbp)
  subl   $0x1,-0x124(%rbp)
L11:
  cmpl   $0x0,-0x124(%rbp)
  jne    L25
  mov    $0x0,%eax
L51:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: result unequal


assistant: ```c
char *test_morton1() {
  unsigned x = 104395303;
  unsigned y = 122949829;
  const unsigned stridex = 503;
  const unsigned stridey = 509;
  unsigned loop = 10000000;
  unsigned long long s;
  unsigned rx, ry;
  char outstr[256];
  for (; loop > 0; --loop) {
    s = morton_encode(x, y);
    morton_decode(s, &rx, &ry);
    do {
      if (!(((x == rx) && (y == ry))))
        return "result unequal\n";
    } while (0);
    x += stridex;
    y += stridey;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_morton1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x75410c5,%ebp
  mov    $0x638f227,%ebx
  lea    0x4(%rsp),%r12
L14:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <morton_encode@plt>
  mov    %rax,%rdi
  mov    %rsp,%rsi
  mov    %r12,%rdx
  call   <morton_decode@plt>
  cmp    %ebx,(%rsp)
  jne    L47
  cmp    %ebp,0x4(%rsp)
  jne    L59
  add    $0x1f7,%ebx
  add    $0x1fd,%ebp
  cmp    $0x3208a7a7,%ebx
  jne    L14
  mov    $0x0,%eax
  jmp    L51
L47:
  lea    D15(%rip),%rax
L51:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  lea    D15(%rip),%rax
  jmp    L51
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D15
data_type: string

tool: D15: result unequal


assistant: ```c
char *test_morton1() {
  unsigned x = 104395303;
  unsigned y = 122949829;
  const unsigned stridex = 503;
  const unsigned stridey = 509;
  unsigned loop = 10000000;
  unsigned long long s;
  unsigned rx, ry;
  char outstr[256];
  for (; loop > 0; --loop) {
    s = morton_encode(x, y);
    morton_decode(s, &rx, &ry);
    do {
      if (!(((x == rx) && (y == ry))))
        return "result unequal\n";
    } while (0);
    x += stridex;
    y += stridey;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_morton1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x75410c5,%ebp
  push   %rbx
  mov    $0x638f227,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %rsp,%r12
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L18:
  cmp    %ebp,0x4(%rsp)
  jne    L11
  add    $0x1f7,%ebx
  add    $0x1fd,%ebp
  cmp    $0x3208a7a7,%ebx
  je     L32
L49:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <morton_encode@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <morton_decode@plt>
  cmp    %ebx,(%rsp)
  je     L18
L11:
  lea    D6(%rip),%rax
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  xor    %eax,%eax
  jmp    L48
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string

tool: D6: result unequal


assistant: ```c
char *test_morton1() {
  unsigned x = 104395303;
  unsigned y = 122949829;
  const unsigned stridex = 503;
  const unsigned stridey = 509;
  unsigned loop = 10000000;
  unsigned long long s;
  unsigned rx, ry;
  char outstr[256];
  for (; loop > 0; --loop) {
    s = morton_encode(x, y);
    morton_decode(s, &rx, &ry);
    do {
      if (!(((x == rx) && (y == ry))))
        return "result unequal\n";
    } while (0);
    x += stridex;
    y += stridey;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_morton1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x75410c5,%ebp
  push   %rbx
  mov    $0x638f227,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %rsp,%r12
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    %ebp,0x4(%rsp)
  jne    L41
  add    $0x1f7,%ebx
  add    $0x1fd,%ebp
  cmp    $0x3208a7a7,%ebx
  je     L14
L19:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <morton_encode@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <morton_decode@plt>
  cmp    %ebx,(%rsp)
  je     L10
L41:
  lea    D3(%rip),%rax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  xor    %eax,%eax
  jmp    L25
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: result unequal


assistant: ```c
char *test_morton1() {
  unsigned x = 104395303;
  unsigned y = 122949829;
  const unsigned stridex = 503;
  const unsigned stridey = 509;
  unsigned loop = 10000000;
  unsigned long long s;
  unsigned rx, ry;
  char outstr[256];
  for (; loop > 0; --loop) {
    s = morton_encode(x, y);
    morton_decode(s, &rx, &ry);
    do {
      if (!(((x == rx) && (y == ry))))
        return "result unequal\n";
    } while (0);
    x += stridex;
    y += stridey;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%r12d
  cmpl   $0x0,-0x14(%rbp)
  jns    L23
  add    $0x1,%r12d
  negl   -0x14(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,%ebx
  mov    %ebx,%ecx
  imul   -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  cmp    %eax,%edx
  jle    L12
  add    $0x1,%ebx
L12:
  imul   -0x18(%rbp),%ebx
  test   %r12d,%r12d
  je     L17
  neg    %ebx
L17:
  mov    %ebx,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
quant(n, m) int n, m;
{
  register i, neg;
  neg = 0;
  if (n < 0) {
    neg++;
    n = -n;
  }
  i = n / m;
  if ((n - m * i) > (m / 2))
    i += 1;
  i *= m;
  if (neg)
    i = -i;
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quant>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  test   %edi,%edi
  js     L1
  cltd
  idiv   %esi
  shr    $0x1f,%esi
  add    %ecx,%esi
  sar    %esi
  cmp    %esi,%edx
  jg     L35
  imul   %ecx,%eax
  ret
L1:
  neg    %eax
  cltd
  idiv   %esi
  shr    $0x1f,%esi
  add    %ecx,%esi
  sar    %esi
  cmp    %esi,%edx
  jg     L3
  imul   %eax,%ecx
L16:
  mov    %ecx,%eax
  neg    %eax
  ret
L3:
  add    $0x1,%eax
  imul   %eax,%ecx
  jmp    L16
L35:
  add    $0x1,%eax
  imul   %ecx,%eax
  ret
```

assistant: ```c
quant(n, m) int n, m;
{
  register i, neg;
  neg = 0;
  if (n < 0) {
    neg++;
    n = -n;
  }
  i = n / m;
  if ((n - m * i) > (m / 2))
    i += 1;
  i *= m;
  if (neg)
    i = -i;
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quant>:
  endbr64
  mov    %esi,%ecx
  mov    %edi,%eax
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  test   %edi,%edi
  js     L28
  cltd
  idiv   %esi
  cmp    %edx,%ecx
  jge    L26
  add    $0x1,%eax
L26:
  imul   %esi,%eax
  ret
  nopl   0x0(%rax)
L28:
  neg    %eax
  cltd
  idiv   %esi
  cmp    %ecx,%edx
  jle    L10
  add    $0x1,%eax
L10:
  imul   %eax,%esi
  mov    %esi,%eax
  neg    %eax
  ret
```

assistant: ```c
quant(n, m) int n, m;
{
  register i, neg;
  neg = 0;
  if (n < 0) {
    neg++;
    n = -n;
  }
  i = n / m;
  if ((n - m * i) > (m / 2))
    i += 1;
  i *= m;
  if (neg)
    i = -i;
  return (i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quant>:
  endbr64
  mov    %esi,%ecx
  mov    %edi,%eax
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  test   %edi,%edi
  js     L21
  cltd
  idiv   %esi
  cmp    %edx,%ecx
  jge    L23
  add    $0x1,%eax
L23:
  imul   %esi,%eax
  ret
  nopl   0x0(%rax)
L21:
  neg    %eax
  cltd
  idiv   %esi
  cmp    %ecx,%edx
  jle    L27
  add    $0x1,%eax
L27:
  imul   %eax,%esi
  mov    %esi,%eax
  neg    %eax
  ret
```

assistant: ```c
quant(n, m) int n, m;
{
  register i, neg;
  neg = 0;
  if (n < 0) {
    neg++;
    n = -n;
  }
  i = n / m;
  if ((n - m * i) > (m / 2))
    i += 1;
  i *= m;
  if (neg)
    i = -i;
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <makeEqual@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D46
datatype: string
name: retrieve_data
arguments: tag: D20
datatype: string

tool: D46: %d

tool: D20: %s

assistant: ```c
int main() {
  int n1, n2;
  scanf("%d", &n1);
  char *s1, *s2;
  s1 = (char *)malloc((n1) * sizeof(char));
  s2 = (char *)malloc((n2) * sizeof(char));
  scanf("%s", s1);
  scanf("%d", &n2);
  scanf("%s", s2);
  int count = makeEqual(s1, n1, s2, n2);
  printf("%d", count);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D7(%rip),%r12
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq (%rsp),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  movslq 0x4(%rsp),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  lea    D12(%rip),%r13
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    %rbp,%rdx
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <makeEqual@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string
name: read_data
arguments: tag: D12
datatype: string

tool: D7: %d

tool: D12: %s

assistant: ```c
int main() {
  int n1, n2;
  scanf("%d", &n1);
  char *s1, *s2;
  s1 = (char *)malloc((n1) * sizeof(char));
  s2 = (char *)malloc((n2) * sizeof(char));
  scanf("%s", s1);
  scanf("%d", &n2);
  scanf("%s", s2);
  int count = makeEqual(s1, n1, s2, n2);
  printf("%d", count);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movslq (%rsp),%rdi
  call   <malloc@plt>
  movslq 0x4(%rsp),%rdi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %rax,%r12
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r12,%rdx
  call   <makeEqual@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D19
type_infered: string

tool: D13: %s

tool: D19: %d

assistant: ```c
int main() {
  int n1, n2;
  scanf("%d", &n1);
  char *s1, *s2;
  s1 = (char *)malloc((n1) * sizeof(char));
  s2 = (char *)malloc((n2) * sizeof(char));
  scanf("%s", s1);
  scanf("%d", &n2);
  scanf("%s", s2);
  int count = makeEqual(s1, n1, s2, n2);
  printf("%d", count);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movslq (%rsp),%rdi
  call   <malloc@plt>
  movslq 0x4(%rsp),%rdi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %rax,%r12
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r12,%rdx
  call   <makeEqual@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string
name: read_data
arguments: data_tag: D2
data_type: string

tool: D3: %s

tool: D2: %d

assistant: ```c
int main() {
  int n1, n2;
  scanf("%d", &n1);
  char *s1, *s2;
  s1 = (char *)malloc((n1) * sizeof(char));
  s2 = (char *)malloc((n2) * sizeof(char));
  scanf("%s", s1);
  scanf("%d", &n2);
  scanf("%s", s2);
  int count = makeEqual(s1, n1, s2, n2);
  printf("%d", count);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<monotonic_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <get_mono@plt>
  mov    -0x20(%rbp),%rax
  imul   $0x3e8,%rax,%rcx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  add    %rcx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
unsigned long long monotonic_ms(void) {
  struct timespec ts;
  get_mono(&ts);
  return ts.tv_sec * 1000ULL + ts.tv_nsec / 1000000;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<monotonic_ms>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <get_mono@plt>
  imul   $0x3e8,(%rsp),%rax
  mov    0x8(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x32,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long monotonic_ms(void) {
  struct timespec ts;
  get_mono(&ts);
  return ts.tv_sec * 1000ULL + ts.tv_nsec / 1000000;
}
```