ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_with_duplicates>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    $0x6363,%eax
  movl   $0x62626161,0x1(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <remove_duplicates@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: abc

assistant: ```c
int test_with_duplicates() {
  char input[] = "aabbcc";
  remove_duplicates(input);
  return strcmp(input, "abc") == 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L16:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L0
  addl   $0x1,-0x4(%rbp)
L0:
  sarl   -0x14(%rbp)
L6:
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_1_1(int v) {
  int num = 0;
  while (v) {
    if (v % 2 == 1) {
      num++;
    }
    v >>= 1;
  }
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<count_1_1>:
  endbr64
  test   %edi,%edi
  je     L15
  mov    $0x0,%ecx
L8:
  mov    %edi,%edx
  shr    $0x1f,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%ecx
  sar    %edi
  jne    L8
L27:
  mov    %ecx,%eax
  ret
L15:
  mov    %edi,%ecx
  jmp    L27
```

assistant: ```c
int count_1_1(int v) {
  int num = 0;
  while (v) {
    if (v % 2 == 1) {
      num++;
    }
    v >>= 1;
  }
  return num;
}
```
user: What is the c source code of the assembly code below:

```asm
<count_1_1>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L19
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %edi,%edx
  shr    $0x1f,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
  sar    %edi
  jne    L13
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_1_1(int v) {
  int num = 0;
  while (v) {
    if (v % 2 == 1) {
      num++;
    }
    v >>= 1;
  }
  return num;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<count_1_1>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L10
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %edi,%edx
  shr    $0x1f,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
  sar    %edi
  jne    L8
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_1_1(int v) {
  int num = 0;
  while (v) {
    if (v % 2 == 1) {
      num++;
    }
    v >>= 1;
  }
  return num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L21:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L21
  sub    $0xc70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9c64(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x9c5c(%rbp)
  movl   $0x0,-0x9c60(%rbp)
  jmp    L62
L64:
  lea    -0x9c50(%rbp),%rdx
  mov    -0x9c60(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x9c60(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  add    %eax,-0x9c5c(%rbp)
  addl   $0x1,-0x9c60(%rbp)
L62:
  mov    -0x9c64(%rbp),%eax
  cmp    %eax,-0x9c60(%rbp)
  jl     L64
  mov    -0x9c64(%rbp),%edx
  mov    -0x9c64(%rbp),%eax
  imul   %eax,%edx
  mov    -0x9c64(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  add    %eax,-0x9c5c(%rbp)
  cmpl   $0x0,-0x9c5c(%rbp)
  js     L45
  mov    -0x9c64(%rbp),%ecx
  mov    -0x9c5c(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L45
  movl   $0x0,-0x9c54(%rbp)
  mov    -0x9c64(%rbp),%ecx
  mov    -0x9c5c(%rbp),%eax
  cltd
  idiv   %ecx
  add    $0x1,%eax
  mov    %eax,-0x9c58(%rbp)
  movl   $0x0,-0x9c60(%rbp)
  jmp    L43
L82:
  mov    -0x9c60(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  cmp    %eax,-0x9c58(%rbp)
  jge    L26
  mov    -0x9c60(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  sub    -0x9c58(%rbp),%eax
  add    %eax,-0x9c54(%rbp)
L26:
  addl   $0x1,-0x9c58(%rbp)
  addl   $0x1,-0x9c60(%rbp)
L43:
  mov    -0x9c64(%rbp),%eax
  cmp    %eax,-0x9c60(%rbp)
  jl     L82
  mov    -0x9c54(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L95
L45:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L95:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D34
datatype: string
name: parse_data
arguments: data_label: D35
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string

tool: D34:  %d

tool: D35: %d


tool: D3: -1

assistant: ```c
int main() {
  int vetor[10000];
  int i, n;
  int soma;
  int altura;
  int movimentos;
  scanf(" %d", &n);
  soma = 0;
  for (i = 0; i < n; i++) {
    scanf(" %d", &vetor[i]);
    soma += vetor[i];
  }
  soma -= (n * n + n) / 2;
  if (soma >= 0 && soma % n == 0) {
    movimentos = 0;
    altura = (soma / n) + 1;
    for (i = 0; i < n; i++) {
      if (vetor[i] > altura)
        movimentos += (vetor[i] - altura);
      altura++;
    }
    printf("%d\n", movimentos);
  } else {
    printf("-1\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L56:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L56
  sub    $0xc68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L79
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  lea    D34(%rip),%r13
L1:
  lea    0x10(%rsp),%rbp
  lea    0x0(%rbp,%rbx,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    0x0(%rbp,%rbx,4),%r12d
  mov    0xc(%rsp),%ecx
  add    $0x1,%rbx
  cmp    %ebx,%ecx
  jg     L1
L92:
  mov    %ecx,%edx
  imul   %ecx,%edx
  add    %ecx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  sub    %eax,%r12d
  js     L57
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  test   %edx,%edx
  jne    L57
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r12d
  lea    0x1(%rax),%eax
  test   %ecx,%ecx
  jle    L66
  lea    0x10(%rsp),%rdi
  lea    0x1(%rcx,%r12,1),%r8d
L51:
  mov    (%rdi),%ecx
  mov    %ecx,%edx
  sub    %eax,%edx
  add    %esi,%edx
  cmp    %eax,%ecx
  cmovg  %edx,%esi
  add    $0x1,%eax
  add    $0x4,%rdi
  cmp    %r8d,%eax
  jne    L51
L66:
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L69
L79:
  mov    $0x0,%r12d
  jmp    L92
L57:
  lea    D20(%rip),%rdi
  call   <puts@plt>
L69:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x9c68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: string

tool: D34:  %d

tool: D38: %d


tool: D20: -1

assistant: ```c
int main() {
  int vetor[10000];
  int i, n;
  int soma;
  int altura;
  int movimentos;
  scanf(" %d", &n);
  soma = 0;
  for (i = 0; i < n; i++) {
    scanf(" %d", &vetor[i]);
    soma += vetor[i];
  }
  soma -= (n * n + n) / 2;
  if (soma >= 0 && soma % n == 0) {
    movimentos = 0;
    altura = (soma / n) + 1;
    for (i = 0; i < n; i++) {
      if (vetor[i] > altura)
        movimentos += (vetor[i] - altura);
      altura++;
    }
    printf("%d\n", movimentos);
  } else {
    printf("-1\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L69:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L69
  sub    $0xc68,%rsp
  lea    D25(%rip),%r13
  mov    %r13,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L66
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  cs nopw 0x0(%rax,%rax,1)
L87:
  lea    (%r12,%rbx,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  add    (%r12,%rbx,4),%ebp
  add    $0x1,%rbx
  cmp    %ebx,%ecx
  jg     L87
L37:
  lea    0x1(%rcx),%r8d
  mov    %r8d,%eax
  imul   %ecx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  mov    %ebp,%eax
  sar    %edx
  sub    %edx,%eax
  js     L81
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L81
  lea    0x1(%rax),%esi
  test   %ecx,%ecx
  jle    L80
  lea    0x10(%rsp),%rcx
  add    %eax,%r8d
  nopl   0x0(%rax,%rax,1)
L23:
  mov    (%rcx),%edi
  mov    %edi,%eax
  sub    %esi,%eax
  add    %edx,%eax
  cmp    %esi,%edi
  cmovg  %eax,%edx
  add    $0x1,%esi
  add    $0x4,%rcx
  cmp    %r8d,%esi
  jne    L23
L80:
  mov    %edx,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L82
L81:
  lea    D11(%rip),%rdi
  call   <puts@plt>
L82:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x9c68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  xor    %ebp,%ebp
  jmp    L37
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
type_infered: string
name: retrieve_data
arguments: data_label: D28
type_infered: string
name: retrieve_data
arguments: data_label: D11
type_infered: string

tool: D25:  %d

tool: D28: %d


tool: D11: -1

assistant: ```c
int main() {
  int vetor[10000];
  int i, n;
  int soma;
  int altura;
  int movimentos;
  scanf(" %d", &n);
  soma = 0;
  for (i = 0; i < n; i++) {
    scanf(" %d", &vetor[i]);
    soma += vetor[i];
  }
  soma -= (n * n + n) / 2;
  if (soma >= 0 && soma % n == 0) {
    movimentos = 0;
    altura = (soma / n) + 1;
    for (i = 0; i < n; i++) {
      if (vetor[i] > altura)
        movimentos += (vetor[i] - altura);
      altura++;
    }
    printf("%d\n", movimentos);
  } else {
    printf("-1\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_clz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void check_clz(int n) {
  __builtin_clz(n);
  __builtin_clzl(n);
  __builtin_clzll(n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_clz>:
  endbr64
  ret
```

assistant: ```c
void check_clz(int n) {
  __builtin_clz(n);
  __builtin_clzl(n);
  __builtin_clzll(n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_clz>:
  endbr64
  ret
```

assistant: ```c
void check_clz(int n) {
  __builtin_clz(n);
  __builtin_clzl(n);
  __builtin_clzll(n);
}
```
user: What is the c source code of the assembly code below:

```asm
<check_clz>:
  endbr64
  ret
```

assistant: ```c
void check_clz(int n) {
  __builtin_clz(n);
  __builtin_clzl(n);
  __builtin_clzll(n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ISORegexp__string_is_white_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ISORegexp__white_space@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x0,%eax
  jmp    L26
L4:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    $0x1,%eax
L26:
  leave
  ret
```

assistant: ```c
int ISORegexp__string_is_white_space(char *p) {
  for (int i = 0; p[i]; i++)
    if (ISORegexp__white_space(p[i]) == 0)
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ISORegexp__string_is_white_space>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L1
  add    $0x1,%rbx
L30:
  movsbl %dil,%edi
  call   <ISORegexp__white_space@plt>
  test   %rax,%rax
  je     L18
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L30
  mov    $0x1,%eax
  jmp    L37
L1:
  mov    $0x1,%eax
  jmp    L37
L18:
  mov    $0x0,%eax
L37:
  pop    %rbx
  ret
```

assistant: ```c
int ISORegexp__string_is_white_space(char *p) {
  for (int i = 0; p[i]; i++)
    if (ISORegexp__white_space(p[i]) == 0)
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ISORegexp__string_is_white_space>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L11
  add    $0x1,%rbx
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L38:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L11
L4:
  call   <ISORegexp__white_space@plt>
  test   %rax,%rax
  jne    L38
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ISORegexp__string_is_white_space(char *p) {
  for (int i = 0; p[i]; i++)
    if (ISORegexp__white_space(p[i]) == 0)
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ISORegexp__string_is_white_space>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L11
  add    $0x1,%rbx
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L5:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L11
L37:
  call   <ISORegexp__white_space@plt>
  test   %rax,%rax
  jne    L5
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ISORegexp__string_is_white_space(char *p) {
  for (int i = 0; p[i]; i++)
    if (ISORegexp__white_space(p[i]) == 0)
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <inicia@plt>
  mov    $0x2a,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <tenta@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: PAUSE

assistant: ```c
int main(int argc, char *argv[]) {
  inicia();
  tenta(1, 1, '*');
  system("PAUSE");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <inicia@plt>
  mov    $0x2a,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <tenta@plt>
  lea    D0(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: PAUSE

assistant: ```c
int main(int argc, char *argv[]) {
  inicia();
  tenta(1, 1, '*');
  system("PAUSE");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <inicia@plt>
  mov    $0x2a,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <tenta@plt>
  lea    D8(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: PAUSE

assistant: ```c
int main(int argc, char *argv[]) {
  inicia();
  tenta(1, 1, '*');
  system("PAUSE");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <inicia@plt>
  mov    $0x2a,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <tenta@plt>
  lea    D0(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: PAUSE

assistant: ```c
int main(int argc, char *argv[]) {
  inicia();
  tenta(1, 1, '*');
  system("PAUSE");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <set@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0xd,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <test_assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a = 0, b = 0;
  set(&a);
  test_assert(a == 13);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <set@plt>
  cmpl   $0xd,0x4(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <test_assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a = 0, b = 0;
  set(&a);
  test_assert(a == 13);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <set@plt>
  xor    %edi,%edi
  cmpl   $0xd,0x4(%rsp)
  sete   %dil
  call   <test_assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a = 0, b = 0;
  set(&a);
  test_assert(a == 13);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <set@plt>
  xor    %edi,%edi
  cmpl   $0xd,0x4(%rsp)
  sete   %dil
  call   <test_assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a = 0, b = 0;
  set(&a);
  test_assert(a == 13);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_89_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_89_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T | stk3;
  stk1 = D ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_89_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  not    %eax
  or     %esi,%eax
  and    %esi,%edi
  xor    %edi,%eax
  xor    $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_89_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T | stk3;
  stk1 = D ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_89_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  not    %eax
  and    %esi,%edi
  or     %esi,%eax
  xor    %edi,%eax
  xor    $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_89_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T | stk3;
  stk1 = D ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xrop3_89_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  not    %eax
  and    %esi,%edi
  or     %esi,%eax
  xor    %edi,%eax
  xor    $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_89_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T | stk3;
  stk1 = D ^ stk2;
  return (stk1 & (~S)) | (D & S);
}
```