ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %rbp,%rdi
  movl   $0x75,0x14(%rsp)
  movq   $0x0,0x20(%rsp)
  call   <sigemptyset@plt>
  mov    D1(%rip),%rax
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rbp
  mov    (%rax),%esi
  call   <sigaddset@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbx,%r8
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <select@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbx,%r8
  mov    $0x1,%edi
  movq   $0x0,0x18(%rsp)
  movl   $0x71,0x14(%rsp)
  call   <select@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbx,%r8
  mov    %rbp,%rsi
  mov    $0xffffffff,%edi
  movq   $0x0,0x18(%rsp)
  movl   $0x78,0x14(%rsp)
  call   <select@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbx,%r8
  mov    $0xffffffffffffffff,%rsi
  mov    $0x1,%edi
  movq   $0x0,0x18(%rsp)
  movl   $0x79,0x14(%rsp)
  call   <select@plt>
  xor    %ecx,%ecx
  mov    %rbx,%r8
  mov    %rbp,%rsi
  mov    $0xffffffffffffffff,%rdx
  mov    $0x1,%edi
  movq   $0x0,0x18(%rsp)
  movl   $0x7a,0x14(%rsp)
  call   <select@plt>
  xor    %edx,%edx
  mov    %rbx,%r8
  mov    %rbp,%rsi
  mov    $0xffffffffffffffff,%rcx
  mov    $0x1,%edi
  movq   $0x0,0x18(%rsp)
  movl   $0x7b,0x14(%rsp)
  call   <select@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0xffffffffffffffff,%r8
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <select@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int fd;
  struct timespec tim = {0, 200000000};
  sigset_t sigs;
  fd_set rfds;
  struct timeval tv = {0, 117};
  sigemptyset(&sigs);
  sigaddset(&sigs, SIGUSR2);
  select(1, &rfds, NULL, NULL, &tv);
  tv.tv_sec = 0;
  tv.tv_usec = 113;
  select(1, NULL, NULL, NULL, &tv);
  tv.tv_sec = 0;
  tv.tv_usec = 120;
  select(-1, &rfds, NULL, NULL, &tv);
  tv.tv_sec = 0;
  tv.tv_usec = 121;
  select(1, (fd_set *)-1, NULL, NULL, &tv);
  tv.tv_sec = 0;
  tv.tv_usec = 122;
  select(1, &rfds, (fd_set *)-1, NULL, &tv);
  tv.tv_sec = 0;
  tv.tv_usec = 123;
  select(1, &rfds, NULL, (fd_set *)-1, &tv);
  select(1, &rfds, NULL, NULL, (struct timeval *)-1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printUsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D35
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D38
type_infered: string
name: retrieve_data
arguments: label: D41
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string

tool: D35: 
Usage: 


tool: D26:    lcd             - without any parameters will act like TEE


tool: D38:    lcd c           - erase LCD screen


tool: D41:    lcd g 2 5       - set cursor to the row 2 column 5


tool: D15:    lcd p "Hello"   - print Hello message on LCD and exit


tool: D0:    lcd o 123       - set LCD cOntrast to 123 


tool: D10:    lcd b 123       - set LCD brightness to 123 



assistant: ```c
void printUsage() {
  printf("\nUsage: \n");
  printf("   lcd             - without any parameters will act like TEE\n");
  printf("   lcd c           - erase LCD screen\n");
  printf("   lcd g 2 5       - set cursor to the row 2 column 5\n");
  printf("   lcd p \"Hello\"   - print Hello message on LCD and exit\n");
  printf("   lcd o 123       - set LCD cOntrast to 123 \n");
  printf("   lcd b 123       - set LCD brightness to 123 \n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<printUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D66
type_guessed: string
name: retrieve_data
arguments: data_label: D35
type_guessed: string
name: retrieve_data
arguments: data_label: D49
type_guessed: string
name: retrieve_data
arguments: data_label: D42
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D44
type_guessed: string

tool: D66: 
Usage: 


tool: D35:    lcd             - without any parameters will act like TEE


tool: D49:    lcd c           - erase LCD screen


tool: D42:    lcd g 2 5       - set cursor to the row 2 column 5


tool: D12:    lcd p "Hello"   - print Hello message on LCD and exit


tool: D13:    lcd o 123       - set LCD cOntrast to 123 


tool: D44:    lcd b 123       - set LCD brightness to 123 



assistant: ```c
void printUsage() {
  printf("\nUsage: \n");
  printf("   lcd             - without any parameters will act like TEE\n");
  printf("   lcd c           - erase LCD screen\n");
  printf("   lcd g 2 5       - set cursor to the row 2 column 5\n");
  printf("   lcd p \"Hello\"   - print Hello message on LCD and exit\n");
  printf("   lcd o 123       - set LCD cOntrast to 123 \n");
  printf("   lcd b 123       - set LCD brightness to 123 \n\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D53
datatype: string
name: extract_symbolic_data
arguments: label: D24
datatype: string
name: extract_symbolic_data
arguments: label: D56
datatype: string
name: extract_symbolic_data
arguments: label: D44
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D45
datatype: string
name: extract_symbolic_data
arguments: label: D49
datatype: string

tool: D53: 
Usage: 


tool: D24:    lcd             - without any parameters will act like TEE


tool: D56:    lcd c           - erase LCD screen


tool: D44:    lcd g 2 5       - set cursor to the row 2 column 5


tool: D18:    lcd p "Hello"   - print Hello message on LCD and exit


tool: D45:    lcd o 123       - set LCD cOntrast to 123 


tool: D49:    lcd b 123       - set LCD brightness to 123 



assistant: ```c
void printUsage() {
  printf("\nUsage: \n");
  printf("   lcd             - without any parameters will act like TEE\n");
  printf("   lcd c           - erase LCD screen\n");
  printf("   lcd g 2 5       - set cursor to the row 2 column 5\n");
  printf("   lcd p \"Hello\"   - print Hello message on LCD and exit\n");
  printf("   lcd o 123       - set LCD cOntrast to 123 \n");
  printf("   lcd b 123       - set LCD brightness to 123 \n\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D62
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D45
type_infered: string
name: unpack_data
arguments: tag: D68
type_infered: string
name: unpack_data
arguments: tag: D20
type_infered: string
name: unpack_data
arguments: tag: D47
type_infered: string

tool: D62: 
Usage: 


tool: D4:    lcd             - without any parameters will act like TEE


tool: D1:    lcd c           - erase LCD screen


tool: D45:    lcd g 2 5       - set cursor to the row 2 column 5


tool: D68:    lcd p "Hello"   - print Hello message on LCD and exit


tool: D20:    lcd o 123       - set LCD cOntrast to 123 


tool: D47:    lcd b 123       - set LCD brightness to 123 



assistant: ```c
void printUsage() {
  printf("\nUsage: \n");
  printf("   lcd             - without any parameters will act like TEE\n");
  printf("   lcd c           - erase LCD screen\n");
  printf("   lcd g 2 5       - set cursor to the row 2 column 5\n");
  printf("   lcd p \"Hello\"   - print Hello message on LCD and exit\n");
  printf("   lcd o 123       - set LCD cOntrast to 123 \n");
  printf("   lcd b 123       - set LCD brightness to 123 \n\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<write_lsb_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %al,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  mov    %al,-0xb(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %al,-0xa(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %al,-0x9(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void write_lsb_int(int n, FILE *f) {
  unsigned char buf[4];
  buf[0] = n & 0xFF;
  buf[1] = (n >> (1 * 8)) & 0xFF;
  buf[2] = (n >> (2 * 8)) & 0xFF;
  buf[3] = (n >> (3 * 8)) & 0xFF;
  fwrite(buf, 4, 1, f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_lsb_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%eax
  mov    %rsi,%rcx
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  mov    %dil,0x4(%rsp)
  movzbl %ah,%edx
  mov    %dl,0x5(%rsp)
  mov    %edi,%edx
  sar    $0x10,%edx
  mov    %dl,0x6(%rsp)
  shr    $0x18,%eax
  mov    %al,0x7(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_lsb_int(int n, FILE *f) {
  unsigned char buf[4];
  buf[0] = n & 0xFF;
  buf[1] = (n >> (1 * 8)) & 0xFF;
  buf[2] = (n >> (2 * 8)) & 0xFF;
  buf[3] = (n >> (3 * 8)) & 0xFF;
  fwrite(buf, 4, 1, f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_lsb_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_lsb_int(int n, FILE *f) {
  unsigned char buf[4];
  buf[0] = n & 0xFF;
  buf[1] = (n >> (1 * 8)) & 0xFF;
  buf[2] = (n >> (2 * 8)) & 0xFF;
  buf[3] = (n >> (3 * 8)) & 0xFF;
  fwrite(buf, 4, 1, f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_lsb_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_lsb_int(int n, FILE *f) {
  unsigned char buf[4];
  buf[0] = n & 0xFF;
  buf[1] = (n >> (1 * 8)) & 0xFF;
  buf[2] = (n >> (2 * 8)) & 0xFF;
  buf[3] = (n >> (3 * 8)) & 0xFF;
  fwrite(buf, 4, 1, f);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xfb0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1f4,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xfbc(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0xfb8(%rbp)
  jmp    L31
L1:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L4
  mov    -0xfb8(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0xfb4(%rbp)
  jmp    L49
L59:
  mov    -0xfb4(%rbp),%eax
  cltq
  movl   $0x1,-0xfb0(%rbp,%rax,4)
  mov    -0xfb8(%rbp),%eax
  add    %eax,-0xfb4(%rbp)
L49:
  mov    -0xfbc(%rbp),%eax
  cmp    %eax,-0xfb4(%rbp)
  jle    L59
L4:
  addl   $0x1,-0xfb8(%rbp)
L31:
  mov    -0xfbc(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0xfb8(%rbp)
  jle    L1
  movl   $0x2,-0xfb8(%rbp)
  jmp    L64
L72:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L20
  mov    -0xfb8(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  addl   $0x1,-0xfb8(%rbp)
L64:
  mov    -0xfbc(%rbp),%eax
  cmp    %eax,-0xfb8(%rbp)
  jle    L72
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L74
  call   <__stack_chk_fail@plt>
L74:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string
name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D27
type: string

tool: D1: Enter n

tool: D18: %d

tool: D27: %d


assistant: ```c
main() {
  int n, i, j;
  int arr[1000] = {0};
  printf("Enter n\n");
  scanf("%d", &n);
  for (i = 2; i <= sqrt(n); i++) {
    if (arr[i] == 0) {
#pragma omp parallel for
      for (j = i * i; j <= n; j = j + i)
        arr[j] = 1;
    }
  }
  for (i = 2; i <= n; i++)
    if (arr[i] == 0)
      printf("%d\n", i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x1f4,%ecx
  rep stos %rax,%es:(%rdi)
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    $0x2,%ebp
  lea    0x10(%rsp),%r12
  jmp    L57
L65:
  add    $0x1,%rbp
L57:
  mov    %ebp,%ebx
  mov    0xc(%rsp),%edi
  call   <sqrt@plt>
  cmp    %ebp,%eax
  jl     L3
  cmpl   $0x0,(%r12,%rbp,4)
  jne    L65
  imul   %ebx,%ebx
  mov    0xc(%rsp),%edx
  cmp    %edx,%ebx
  jg     L65
  movslq %ebx,%rax
L40:
  movl   $0x1,(%r12,%rax,4)
  add    %rbp,%rax
  cmp    %eax,%edx
  jge    L40
  jmp    L65
L3:
  cmpl   $0x1,0xc(%rsp)
  jle    L82
  mov    $0x2,%ebx
  lea    D20(%rip),%rbp
  jmp    L13
L103:
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jl     L82
L13:
  mov    %ebx,%esi
  cmpl   $0x0,0x10(%rsp,%rbx,4)
  jne    L103
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L103
L82:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    $0x0,%eax
  add    $0xfc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D23
datatype: string
name: retrieve_data
arguments: tag: D20
datatype: string

tool: D2: Enter n

tool: D23: %d

tool: D20: %d


assistant: ```c
main() {
  int n, i, j;
  int arr[1000] = {0};
  printf("Enter n\n");
  scanf("%d", &n);
  for (i = 2; i <= sqrt(n); i++) {
    if (arr[i] == 0) {
#pragma omp parallel for
      for (j = i * i; j <= n; j = j + i)
        arr[j] = 1;
    }
  }
  for (i = 2; i <= n; i++)
    if (arr[i] == 0)
      printf("%d\n", i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1f4,%ecx
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D7(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  jmp    L85
  nopw   0x0(%rax,%rax,1)
L106:
  add    $0x1,%rbp
L85:
  mov    %ebp,%ebx
  call   <sqrt@plt>
  cmp    %ebp,%eax
  jl     L21
  mov    (%r12,%rbp,4),%edx
  mov    0xc(%rsp),%edi
  test   %edx,%edx
  jne    L106
  imul   %ebx,%ebx
  cmp    %ebx,%edi
  jl     L106
  movslq %ebx,%rax
  nopl   (%rax)
L86:
  movl   $0x1,(%r12,%rax,4)
  add    %rbp,%rax
  cmp    %eax,%edi
  jge    L86
  jmp    L106
  nopl   0x0(%rax)
L21:
  cmpl   $0x1,0xc(%rsp)
  mov    $0x2,%ebx
  lea    D13(%rip),%rbp
  jg     L22
  jmp    L39
  nopl   (%rax)
L30:
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jl     L39
L22:
  mov    (%r12,%rbx,4),%eax
  mov    %ebx,%esi
  test   %eax,%eax
  jne    L30
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L22
L39:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D16: Enter n

tool: D7: %d

tool: D13: %d


assistant: ```c
main() {
  int n, i, j;
  int arr[1000] = {0};
  printf("Enter n\n");
  scanf("%d", &n);
  for (i = 2; i <= sqrt(n); i++) {
    if (arr[i] == 0) {
#pragma omp parallel for
      for (j = i * i; j <= n; j = j + i)
        arr[j] = 1;
    }
  }
  for (i = 2; i <= n; i++)
    if (arr[i] == 0)
      printf("%d\n", i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1f4,%ecx
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  jmp    L115
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rbp
L115:
  mov    %ebp,%ebx
  call   <sqrt@plt>
  cmp    %ebp,%eax
  jl     L109
  mov    (%r12,%rbp,4),%ecx
  mov    0xc(%rsp),%edi
  test   %ecx,%ecx
  jne    L13
  imul   %ebx,%ebx
  cmp    %edi,%ebx
  jg     L13
  movslq %ebx,%rax
  nopl   (%rax)
L8:
  movl   $0x1,(%r12,%rax,4)
  add    %rbp,%rax
  cmp    %eax,%edi
  jge    L8
  jmp    L13
  nopl   0x0(%rax)
L109:
  mov    0xc(%rsp),%eax
  mov    $0x2,%ebx
  lea    D3(%rip),%rbp
  cmp    $0x1,%eax
  jle    L66
  nopl   (%rax)
L19:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  test   %edx,%edx
  je     L114
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jge    L19
L66:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L114:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jge    L19
  jmp    L66
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D14: Enter n

tool: D16: %d

tool: D3: %d


assistant: ```c
main() {
  int n, i, j;
  int arr[1000] = {0};
  printf("Enter n\n");
  scanf("%d", &n);
  for (i = 2; i <= sqrt(n); i++) {
    if (arr[i] == 0) {
#pragma omp parallel for
      for (j = i * i; j <= n; j = j + i)
        arr[j] = 1;
    }
  }
  for (i = 2; i <= n; i++)
    if (arr[i] == 0)
      printf("%d\n", i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<extn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L4
  movl   $0xfffffff0,-0x4(%rbp)
  movzbl -0x14(%rbp),%eax
  or     -0x4(%rbp),%eax
  jmp    L12
L4:
  movzbl -0x14(%rbp),%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int extn(unsigned char n) {
  if (n & 0x08) {
    int x = -16;
    return (x | n);
  } else {
    return n;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extn>:
  endbr64
  movzbl %dil,%eax
  mov    %edi,%edx
  or     $0xfffffff0,%edx
  test   $0x8,%dil
  cmovne %edx,%eax
  ret
```

assistant: ```c
int extn(unsigned char n) {
  if (n & 0x08) {
    int x = -16;
    return (x | n);
  } else {
    return n;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<extn>:
  endbr64
  mov    %edi,%edx
  movzbl %dil,%eax
  or     $0xfffffff0,%edx
  and    $0x8,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int extn(unsigned char n) {
  if (n & 0x08) {
    int x = -16;
    return (x | n);
  } else {
    return n;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<extn>:
  endbr64
  mov    %edi,%edx
  movzbl %dil,%eax
  or     $0xfffffff0,%edx
  and    $0x8,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int extn(unsigned char n) {
  if (n & 0x08) {
    int x = -16;
    return (x | n);
  } else {
    return n;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<encodeIFormat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L9
  mov    $0x10,%edi
  call   <twoToThePowerOf@plt>
  add    %eax,-0x10(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <leftShift@plt>
  mov    -0x8(%rbp),%edx
  add    %edx,%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <leftShift@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <leftShift@plt>
  mov    -0x10(%rbp),%edx
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int encodeIFormat(int opcode, int rs, int rt, int immediate) {
  if (immediate < 0)
    immediate = immediate + twoToThePowerOf(16);
  return leftShift(leftShift(leftShift(opcode, 5) + rs, 5) + rt, 16) + immediate;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<encodeIFormat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%ebx
  test   %ecx,%ecx
  js     L15
L17:
  mov    $0x5,%esi
  mov    %r13d,%edi
  call   <leftShift@plt>
  lea    (%rax,%r12,1),%edi
  mov    $0x5,%esi
  call   <leftShift@plt>
  lea    (%rax,%rbp,1),%edi
  mov    $0x10,%esi
  call   <leftShift@plt>
  add    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0x10,%edi
  call   <twoToThePowerOf@plt>
  add    %eax,%ebx
  jmp    L17
```

assistant: ```c
int encodeIFormat(int opcode, int rs, int rt, int immediate) {
  if (immediate < 0)
    immediate = immediate + twoToThePowerOf(16);
  return leftShift(leftShift(leftShift(opcode, 5) + rs, 5) + rt, 16) + immediate;
}
```