ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rearrange_syms>:
  endbr64
  test   %rdi,%rdi
  je     L20
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r14,%rdi
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  lea    0x1(%rsi),%ebx
  call   <get_s_header@plt>
  test   %rax,%rax
  je     L32
  nopl   0x0(%rax,%rax,1)
L10:
  mov    D8(%rip),%rcx
  mov    (%rax),%rdx
  cmp    (%rcx),%rdx
  je     L50
  mov    D11(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L50
L85:
  mov    %ebx,%esi
L94:
  mov    %r14,%rdi
  lea    0x1(%rsi),%ebx
  call   <get_s_header@plt>
  test   %rax,%rax
  jne    L10
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L50:
  movslq 0x8(%rax),%rdx
  shr    $0x3,%rdx
  test   %edx,%edx
  jle    L85
  mov    0x10(%rax),%rcx
  sub    $0x1,%edx
  add    %r14,%rcx
  lea    0x8(%rcx),%rax
  lea    (%rax,%rdx,8),%rsi
  jmp    L68
L104:
  add    $0x8,%rax
L68:
  mov    (%rcx),%rdx
  test   %rdx,%rdx
  je     L13
  cmp    %rdx,%rbp
  ja     L13
  cmp    %rdx,%r12
  jbe    L13
  add    %r13,%rdx
  mov    %rdx,(%rcx)
  nopl   0x0(%rax)
L13:
  mov    %rax,%rcx
  cmp    %rsi,%rax
  jne    L104
  mov    %ebx,%esi
  jmp    L94
  nopl   0x0(%rax)
L20:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int rearrange_syms(char *elf, void *base, void *top, size_t n) {
  if (!elf)
    return 1;
  int sh_num;
  sh_num = 0;
  Elf64_Shdr *shdr;
  while ((shdr = get_s_header(elf, sh_num++))) {
    if (shdr->sh_type == SHT_DYNSYM || shdr->sh_type == SHT_SYMTAB) {
      int num;
      num = shdr->sh_size / sizeof(Elf64_Sym);
      int i;
      Elf64_Sym *sym;
      for (i = 0; i < num; i++) {
        unsigned long long addr;
        addr = ((unsigned long long)elf + shdr->sh_offset + (i * sizeof(Elf64_Sym)));
        sym = (Elf64_Sym *)addr;
        if ((unsigned long long)sym->st_value > 0) {
          if ((unsigned long long)sym->st_value >= (unsigned long long)base && (unsigned long long)sym->st_value < (unsigned long long)top)
            sym->st_value += n;
        }
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rearrange_syms>:
  endbr64
  test   %rdi,%rdi
  je     L28
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r14,%rdi
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  lea    0x1(%rsi),%ebx
  call   <get_s_header@plt>
  test   %rax,%rax
  je     L78
  nopl   0x0(%rax,%rax,1)
L17:
  mov    D0(%rip),%rcx
  mov    (%rax),%rdx
  cmp    (%rcx),%rdx
  je     L57
  mov    D8(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L57
L19:
  mov    %ebx,%esi
L94:
  mov    %r14,%rdi
  lea    0x1(%rsi),%ebx
  call   <get_s_header@plt>
  test   %rax,%rax
  jne    L17
L78:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L57:
  movslq 0x8(%rax),%rdx
  shr    $0x3,%rdx
  test   %edx,%edx
  jle    L19
  mov    0x10(%rax),%rcx
  sub    $0x1,%edx
  add    %r14,%rcx
  lea    0x8(%rcx),%rax
  lea    (%rax,%rdx,8),%rsi
  jmp    L59
L21:
  add    $0x8,%rax
L59:
  mov    (%rcx),%rdx
  test   %rdx,%rdx
  je     L90
  cmp    %rdx,%rbp
  ja     L90
  cmp    %rdx,%r12
  jbe    L90
  add    %r13,%rdx
  mov    %rdx,(%rcx)
  nopl   0x0(%rax)
L90:
  mov    %rax,%rcx
  cmp    %rax,%rsi
  jne    L21
  mov    %ebx,%esi
  jmp    L94
  nopl   0x0(%rax)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int rearrange_syms(char *elf, void *base, void *top, size_t n) {
  if (!elf)
    return 1;
  int sh_num;
  sh_num = 0;
  Elf64_Shdr *shdr;
  while ((shdr = get_s_header(elf, sh_num++))) {
    if (shdr->sh_type == SHT_DYNSYM || shdr->sh_type == SHT_SYMTAB) {
      int num;
      num = shdr->sh_size / sizeof(Elf64_Sym);
      int i;
      Elf64_Sym *sym;
      for (i = 0; i < num; i++) {
        unsigned long long addr;
        addr = ((unsigned long long)elf + shdr->sh_offset + (i * sizeof(Elf64_Sym)));
        sym = (Elf64_Sym *)addr;
        if ((unsigned long long)sym->st_value > 0) {
          if ((unsigned long long)sym->st_value >= (unsigned long long)base && (unsigned long long)sym->st_value < (unsigned long long)top)
            sym->st_value += n;
        }
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<invmod256>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  sar    %eax
  and    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  add    %eax,-0x14(%rbp)
  andl   $0x1,-0x14(%rbp)
  mov    $0x2,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  shll   -0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  sarl   $0x2,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x2,%eax
  and    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  andl   $0x3,-0x14(%rbp)
  mov    $0x4,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  shll   $0x2,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  sarl   $0x4,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  andl   $0xf,-0x14(%rbp)
  mov    $0x10,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  shll   $0x4,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int invmod256(int a) {
  int U, t1, t2, b, c;
  t1 = 0;
  c = (a >> 1) & 1;
  t1 += c;
  t1 &= 1;
  t1 = 2 - t1;
  t1 <<= 1;
  U = t1 + 1;
  b = a & 3;
  t1 = U * b;
  t1 >>= 2;
  c = (a >> 2) & 3;
  t2 = (U * c) & 3;
  t1 += t2;
  t1 *= U;
  t1 &= 3;
  t1 = 4 - t1;
  t1 <<= 2;
  U += t1;
  b = a & 15;
  t1 = U * b;
  t1 >>= 4;
  c = (a >> 4) & 15;
  t2 = (U * c) & 15;
  t1 += t2;
  t1 *= U;
  t1 &= 15;
  t1 = 16 - t1;
  t1 <<= 4;
  U += t1;
  return U;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<invmod256>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  sar    %ecx
  and    $0x1,%ecx
  mov    $0x2,%edx
  sub    %ecx,%edx
  lea    0x1(%rdx,%rdx,1),%esi
  mov    %edi,%ecx
  and    $0x3,%ecx
  imul   %esi,%ecx
  sar    $0x2,%ecx
  mov    %edi,%edx
  sar    $0x2,%edx
  imul   %esi,%edx
  and    $0x3,%edx
  add    %ecx,%edx
  imul   %esi,%edx
  and    $0x3,%edx
  mov    $0x4,%ecx
  sub    %edx,%ecx
  lea    (%rsi,%rcx,4),%esi
  mov    %edi,%ecx
  and    $0xf,%ecx
  imul   %esi,%ecx
  sar    $0x4,%ecx
  sar    $0x4,%eax
  mov    %eax,%edx
  imul   %esi,%edx
  and    $0xf,%edx
  add    %ecx,%edx
  imul   %esi,%edx
  and    $0xf,%edx
  mov    $0x10,%eax
  sub    %edx,%eax
  shl    $0x4,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int invmod256(int a) {
  int U, t1, t2, b, c;
  t1 = 0;
  c = (a >> 1) & 1;
  t1 += c;
  t1 &= 1;
  t1 = 2 - t1;
  t1 <<= 1;
  U = t1 + 1;
  b = a & 3;
  t1 = U * b;
  t1 >>= 2;
  c = (a >> 2) & 3;
  t2 = (U * c) & 3;
  t1 += t2;
  t1 *= U;
  t1 &= 3;
  t1 = 4 - t1;
  t1 <<= 2;
  U += t1;
  b = a & 15;
  t1 = U * b;
  t1 >>= 4;
  c = (a >> 4) & 15;
  t2 = (U * c) & 15;
  t1 += t2;
  t1 *= U;
  t1 &= 15;
  t1 = 16 - t1;
  t1 <<= 4;
  U += t1;
  return U;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<invmod256>:
  endbr64
  mov    %edi,%ecx
  mov    $0x2,%edx
  mov    %edi,%eax
  sar    %ecx
  sar    $0x4,%eax
  and    $0x1,%ecx
  sub    %ecx,%edx
  mov    %edi,%ecx
  lea    0x1(%rdx,%rdx,1),%esi
  mov    %edi,%edx
  and    $0x3,%ecx
  sar    $0x2,%edx
  imul   %esi,%ecx
  imul   %esi,%edx
  sar    $0x2,%ecx
  and    $0x3,%edx
  add    %ecx,%edx
  mov    $0x4,%ecx
  imul   %esi,%edx
  and    $0x3,%edx
  sub    %edx,%ecx
  mov    %eax,%edx
  mov    $0x10,%eax
  lea    (%rsi,%rcx,4),%esi
  mov    %edi,%ecx
  and    $0xf,%ecx
  imul   %esi,%edx
  imul   %esi,%ecx
  and    $0xf,%edx
  sar    $0x4,%ecx
  add    %ecx,%edx
  imul   %esi,%edx
  and    $0xf,%edx
  sub    %edx,%eax
  shl    $0x4,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int invmod256(int a) {
  int U, t1, t2, b, c;
  t1 = 0;
  c = (a >> 1) & 1;
  t1 += c;
  t1 &= 1;
  t1 = 2 - t1;
  t1 <<= 1;
  U = t1 + 1;
  b = a & 3;
  t1 = U * b;
  t1 >>= 2;
  c = (a >> 2) & 3;
  t2 = (U * c) & 3;
  t1 += t2;
  t1 *= U;
  t1 &= 3;
  t1 = 4 - t1;
  t1 <<= 2;
  U += t1;
  b = a & 15;
  t1 = U * b;
  t1 >>= 4;
  c = (a >> 4) & 15;
  t2 = (U * c) & 15;
  t1 += t2;
  t1 *= U;
  t1 &= 15;
  t1 = 16 - t1;
  t1 <<= 4;
  U += t1;
  return U;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<invmod256>:
  endbr64
  mov    %edi,%ecx
  mov    $0x2,%edx
  mov    %edi,%eax
  sar    %ecx
  sar    $0x4,%eax
  and    $0x1,%ecx
  sub    %ecx,%edx
  mov    %edi,%ecx
  lea    0x1(%rdx,%rdx,1),%esi
  mov    %edi,%edx
  and    $0x3,%ecx
  sar    $0x2,%edx
  imul   %esi,%ecx
  imul   %esi,%edx
  sar    $0x2,%ecx
  and    $0x3,%edx
  add    %ecx,%edx
  mov    $0x4,%ecx
  imul   %esi,%edx
  and    $0x3,%edx
  sub    %edx,%ecx
  mov    %eax,%edx
  mov    $0x10,%eax
  lea    (%rsi,%rcx,4),%esi
  mov    %edi,%ecx
  and    $0xf,%ecx
  imul   %esi,%edx
  imul   %esi,%ecx
  and    $0xf,%edx
  sar    $0x4,%ecx
  add    %ecx,%edx
  imul   %esi,%edx
  and    $0xf,%edx
  sub    %edx,%eax
  shl    $0x4,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int invmod256(int a) {
  int U, t1, t2, b, c;
  t1 = 0;
  c = (a >> 1) & 1;
  t1 += c;
  t1 &= 1;
  t1 = 2 - t1;
  t1 <<= 1;
  U = t1 + 1;
  b = a & 3;
  t1 = U * b;
  t1 >>= 2;
  c = (a >> 2) & 3;
  t2 = (U * c) & 3;
  t1 += t2;
  t1 *= U;
  t1 &= 3;
  t1 = 4 - t1;
  t1 <<= 2;
  U += t1;
  b = a & 15;
  t1 = U * b;
  t1 >>= 4;
  c = (a >> 4) & 15;
  t2 = (U * c) & 15;
  t1 += t2;
  t1 *= U;
  t1 &= 15;
  t1 = 16 - t1;
  t1 <<= 4;
  U += t1;
  return U;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<destroy_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <parser_destroy@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int destroy_tests(void) {
  parser_destroy();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<destroy_tests>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <parser_destroy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int destroy_tests(void) {
  parser_destroy();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<destroy_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <parser_destroy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int destroy_tests(void) {
  parser_destroy();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroy_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <parser_destroy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int destroy_tests(void) {
  parser_destroy();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pairFind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L68
  cmpq   $0x0,-0x20(%rbp)
  jne    L70
L68:
  mov    $0xffffffff,%eax
  jmp    L73
L70:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L61:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L66
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L66
  mov    -0x4(%rbp),%eax
  jmp    L73
L66:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L61
  mov    $0xffffffff,%eax
L73:
  leave
  ret
```

assistant: ```c
int pairFind(char *child, char *parent, char *pairList[][2]) {
  if (child == NULL || parent == NULL)
    return -1;
  int pi = 0;
  for (pi = 0; pairList[pi][0] != NULL; pi++) {
    if (strcmp(child, pairList[pi][0]) == 0 && strcmp(parent, pairList[pi][1]) == 0)
      return pi;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pairFind>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L86
  mov    %rdi,%r12
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L86
  mov    (%rdx),%rsi
  test   %rsi,%rsi
  je     L69
  lea    0x10(%rdx),%rbx
  mov    $0x0,%ebp
  jmp    L19
L22:
  add    $0x1,%ebp
  add    $0x10,%rbx
  mov    -0x10(%rbx),%rsi
  test   %rsi,%rsi
  je     L14
L19:
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    -0x8(%rbx),%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  jmp    L38
L14:
  mov    $0xffffffff,%ebp
L38:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L86:
  mov    $0xffffffff,%ebp
  jmp    L38
L69:
  mov    $0xffffffff,%ebp
  jmp    L38
```

assistant: ```c
int pairFind(char *child, char *parent, char *pairList[][2]) {
  if (child == NULL || parent == NULL)
    return -1;
  int pi = 0;
  for (pi = 0; pairList[pi][0] != NULL; pi++) {
    if (strcmp(child, pairList[pi][0]) == 0 && strcmp(parent, pairList[pi][1]) == 0)
      return pi;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pairFind>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L22
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L22
  mov    (%rdx),%rsi
  test   %rsi,%rsi
  je     L22
  mov    %rdi,%rbp
  lea    0x10(%rdx),%rbx
  xor    %r13d,%r13d
  jmp    L47
  nop
L10:
  mov    (%rbx),%rsi
  add    $0x10,%rbx
  add    $0x1,%r13d
  test   %rsi,%rsi
  je     L22
L47:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  mov    -0x8(%rbx),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int pairFind(char *child, char *parent, char *pairList[][2]) {
  if (child == NULL || parent == NULL)
    return -1;
  int pi = 0;
  for (pi = 0; pairList[pi][0] != NULL; pi++) {
    if (strcmp(child, pairList[pi][0]) == 0 && strcmp(parent, pairList[pi][1]) == 0)
      return pi;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pairFind>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L53
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L53
  mov    (%rdx),%rsi
  test   %rsi,%rsi
  je     L53
  mov    %rdi,%rbp
  lea    0x10(%rdx),%rbx
  xor    %r13d,%r13d
  jmp    L49
  nop
L0:
  mov    (%rbx),%rsi
  add    $0x10,%rbx
  add    $0x1,%r13d
  test   %rsi,%rsi
  je     L53
L49:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L0
  mov    -0x8(%rbx),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L53:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int pairFind(char *child, char *parent, char *pairList[][2]) {
  if (child == NULL || parent == NULL)
    return -1;
  int pi = 0;
  for (pi = 0; pairList[pi][0] != NULL; pi++) {
    if (strcmp(child, pairList[pi][0]) == 0 && strcmp(parent, pairList[pi][1]) == 0)
      return pi;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__ip__>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rcx
  mov    %edx,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm4
  mov    $0x0,%ebx
  jmp    L17
L9:
  movslq %ebx,%rax
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rax),%xmm1
  movslq %ebx,%rax
  shl    $0x3,%rax
  add    %rsi,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm4,%xmm3
  addsd  %xmm3,%xmm0
  movapd %xmm0,%xmm4
  add    $0x1,%ebx
L17:
  cmp    -0xc(%rbp),%ebx
  jl     L9
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double __ip__(dp1, dp2, len)
register double *dp1, *dp2;
int len;
{
  register int i;
  register double sum;
  sum = 0.0;
  for (i = 0; i < len; i++)
    sum += dp1[i] * dp2[i];
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__ip__>:
  endbr64
  test   %edx,%edx
  jle    L12
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L3:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L5:
  movapd %xmm1,%xmm0
  ret
L12:
  pxor   %xmm1,%xmm1
  jmp    L5
```

assistant: ```c
double __ip__(dp1, dp2, len)
register double *dp1, *dp2;
int len;
{
  register int i;
  register double sum;
  sum = 0.0;
  for (i = 0; i < len; i++)
    sum += dp1[i] * dp2[i];
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__ip__>:
  endbr64
  test   %edx,%edx
  jle    L18
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L6:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L6
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L18:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double __ip__(dp1, dp2, len)
register double *dp1, *dp2;
int len;
{
  register int i;
  register double sum;
  sum = 0.0;
  for (i = 0; i < len; i++)
    sum += dp1[i] * dp2[i];
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__ip__>:
  endbr64
  test   %edx,%edx
  jle    L30
  cmp    $0x1,%edx
  je     L31
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L2:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L2
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L47
L11:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L47:
  ret
  nopl   0x0(%rax)
L30:
  pxor   %xmm0,%xmm0
  ret
L31:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L11
```

assistant: ```c
double __ip__(dp1, dp2, len)
register double *dp1, *dp2;
int len;
{
  register int i;
  register double sum;
  sum = 0.0;
  for (i = 0; i < len; i++)
    sum += dp1[i] * dp2[i];
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<end_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xa,%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  mov    $0x1,%eax
  jmp    L6
L14:
  mov    -0x8(%rbp),%rax
  add    $0x12,%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L39
  mov    $0x1,%eax
  jmp    L6
L39:
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7:  _end


assistant: ```c
int end_line(const char *line) {
  if (strcmp(line + 10, " _end\n") == 0)
    return 1;
  else if (strcmp(line + 18, " _end\n") == 0)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<end_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    0xa(%rdi),%rdi
  lea    D9(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L4
L2:
  pop    %rbx
  ret
L4:
  lea    0x12(%rbx),%rdi
  lea    D9(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9:  _end


assistant: ```c
int end_line(const char *line) {
  if (strcmp(line + 10, " _end\n") == 0)
    return 1;
  else if (strcmp(line + 18, " _end\n") == 0)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<end_line>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rbp,%rsi
  mov    %rdi,%rbx
  add    $0xa,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L3
  lea    0x12(%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8:  _end


assistant: ```c
int end_line(const char *line) {
  if (strcmp(line + 10, " _end\n") == 0)
    return 1;
  else if (strcmp(line + 18, " _end\n") == 0)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<end_line>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rsi
  mov    %rdi,%rbx
  add    $0xa,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L2
  lea    0x12(%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0:  _end


assistant: ```c
int end_line(const char *line) {
  if (strcmp(line + 10, " _end\n") == 0)
    return 1;
  else if (strcmp(line + 18, " _end\n") == 0)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<inner_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L11
  pxor   %xmm0,%xmm0
  jmp    L10
L11:
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <inner_product>
  addsd  -0x20(%rbp),%xmm0
L10:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double inner_product(double *a, double *b, int n) {
  if (n == 0) {
    return 0.0;
  } else {
    return ((*a) * (*b)) + inner_product((a + 1), (b + 1), n - 1);
  }
}
```