ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L17
  xor    %ecx,%ecx
  nopl   (%rax)
L8:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L8
  mov    %ecx,%edx
  mov    %ecx,%eax
  imul   $0x446f8657,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
  nopl   (%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned hash(char *s) {
  unsigned hashval;
  for (hashval = 0; *s != '\0'; ++s)
    hashval = *s + 31 * hashval;
  return hashval % 101;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L1
  xor    %ecx,%ecx
  nopl   (%rax)
L10:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L10
  mov    %ecx,%edx
  mov    %ecx,%eax
  imul   $0x446f8657,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned hash(char *s) {
  unsigned hashval;
  for (hashval = 0; *s != '\0'; ++s)
    hashval = *s + 31 * hashval;
  return hashval % 101;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_occurence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L56
  cmpq   $0x0,-0x20(%rbp)
  je     L56
  jmp    L62
L47:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L60
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L29
  mov    -0x18(%rbp),%rax
  jmp    L64
L29:
  addq   $0x1,-0x8(%rbp)
L60:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  addq   $0x1,-0x18(%rbp)
L62:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
L56:
  mov    $0x0,%eax
L64:
  pop    %rbp
  ret
```

assistant: ```c
char *find_occurence(char *source, char *str) {
  char *tmp;
  if (source != NULL && str != NULL)
    for (; *source != '\0'; source++)
      for (tmp = str; *tmp != '\0'; tmp++)
        if (*source == *tmp)
          return source;
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<find_occurence>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L0
  test   %rsi,%rsi
  je     L0
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L62
  movzbl (%rsi),%edi
L36:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  je     L2
L68:
  cmp    %r8b,%dl
  je     L31
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L68
L2:
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  jne    L36
  mov    $0x0,%eax
L31:
  ret
L0:
  mov    $0x0,%eax
  ret
L62:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *find_occurence(char *source, char *str) {
  char *tmp;
  if (source != NULL && str != NULL)
    for (; *source != '\0'; source++)
      for (tmp = str; *tmp != '\0'; tmp++)
        if (*source == *tmp)
          return source;
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<find_occurence>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L8
  test   %rsi,%rsi
  je     L8
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L8
  movzbl (%rsi),%edi
L49:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  jne    L18
  jmp    L69
  nopl   0x0(%rax)
L76:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L69
L18:
  cmp    %r8b,%dl
  jne    L76
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L49
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *find_occurence(char *source, char *str) {
  char *tmp;
  if (source != NULL && str != NULL)
    for (; *source != '\0'; source++)
      for (tmp = str; *tmp != '\0'; tmp++)
        if (*source == *tmp)
          return source;
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_occurence>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L29
  test   %rsi,%rsi
  je     L29
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L29
  movzbl (%rsi),%edi
L74:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  jne    L71
  jmp    L60
  nopl   0x0(%rax)
L68:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L60
L71:
  cmp    %r8b,%dl
  jne    L68
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L74
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *find_occurence(char *source, char *str) {
  char *tmp;
  if (source != NULL && str != NULL)
    for (; *source != '\0'; source++)
      for (tmp = str; *tmp != '\0'; tmp++)
        if (*source == *tmp)
          return source;
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hammingWeight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L4:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x0,-0x14(%rbp)
  jg     L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hammingWeight(uint32_t n) {
  int count = 0;
  while (n > 0) {
    n = n & (n - 1);
    count++;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hammingWeight>:
  endbr64
  test   %edi,%edi
  jle    L18
  mov    $0x0,%edx
L19:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edx
  and    %eax,%edi
  jg     L19
L0:
  mov    %edx,%eax
  ret
L18:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
int hammingWeight(uint32_t n) {
  int count = 0;
  while (n > 0) {
    n = n & (n - 1);
    count++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hammingWeight>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L11
  nopl   0x0(%rax,%rax,1)
L16:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L16
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hammingWeight(uint32_t n) {
  int count = 0;
  while (n > 0) {
    n = n & (n - 1);
    count++;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hammingWeight>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L6
  nopl   0x0(%rax,%rax,1)
L14:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L14
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hammingWeight(uint32_t n) {
  int count = 0;
  while (n > 0) {
    n = n & (n - 1);
    count++;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
unsigned dealloc(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++)
    if (argv[i] != NULL)
      free(argv[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dealloc>:
  endbr64
  test   %edi,%edi
  jle    L1
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
  jmp    L14
L44:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L8
L14:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L44
  call   <free@plt>
  jmp    L44
L8:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned dealloc(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++)
    if (argv[i] != NULL)
      free(argv[i]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dealloc>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L13:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L25
  call   <free@plt>
L25:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned dealloc(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++)
    if (argv[i] != NULL)
      free(argv[i]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dealloc>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L0
  call   <free@plt>
L0:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned dealloc(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++)
    if (argv[i] != NULL)
      free(argv[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x17,%edx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  movb   $0x0,-0x9(%rbp)
  jmp    L27
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x9(%rbp)
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L27:
  movzbl -0x9(%rbp),%eax
  cmp    $0x7e,%al
  jne    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: Echo!
Type '~' to exit


assistant: ```c
int main(int argc, char **argv) {
  write(1,
        "Echo!\n"
        "Type '~' to exit\n",
        sizeof("Echo!\n"
               "Type '~' to exit\n") -
            1);
  char c = '\0';
  while (c != '~') {
    c = getchar();
    write(1, &c, 1);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x17,%edx
  lea    D8(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  movb   $0x0,0x7(%rsp)
  lea    0x7(%rsp),%rbx
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,0x7(%rsp)
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  cmpb   $0x7e,0x7(%rsp)
  jne    L9
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: Echo!
Type '~' to exit


assistant: ```c
int main(int argc, char **argv) {
  write(1,
        "Echo!\n"
        "Type '~' to exit\n",
        sizeof("Echo!\n"
               "Type '~' to exit\n") -
            1);
  char c = '\0';
  while (c != '~') {
    c = getchar();
    write(1, &c, 1);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x17,%edx
  mov    $0x1,%edi
  lea    D1(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  call   <write@plt>
  movb   $0x0,0x7(%rsp)
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  mov    %al,0x7(%rsp)
  call   <write@plt>
  cmpb   $0x7e,0x7(%rsp)
  jne    L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: Echo!
Type '~' to exit


assistant: ```c
int main(int argc, char **argv) {
  write(1,
        "Echo!\n"
        "Type '~' to exit\n",
        sizeof("Echo!\n"
               "Type '~' to exit\n") -
            1);
  char c = '\0';
  while (c != '~') {
    c = getchar();
    write(1, &c, 1);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x17,%edx
  mov    $0x1,%edi
  lea    D7(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  call   <write@plt>
  movb   $0x0,0x7(%rsp)
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  mov    %al,0x7(%rsp)
  call   <write@plt>
  cmpb   $0x7e,0x7(%rsp)
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: Echo!
Type '~' to exit


assistant: ```c
int main(int argc, char **argv) {
  write(1,
        "Echo!\n"
        "Type '~' to exit\n",
        sizeof("Echo!\n"
               "Type '~' to exit\n") -
            1);
  char c = '\0';
  while (c != '~') {
    c = getchar();
    write(1, &c, 1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testVaListArg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <test@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void testVaListArg(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  test(fmt, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<testVaListArg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <test@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void testVaListArg(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  test(fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testVaListArg>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <test@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void testVaListArg(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  test(fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<testVaListArg>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <test@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void testVaListArg(char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  test(fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sqrDiff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L3
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double sqrDiff(double *a, double *b, int lo1, int hi1) {
  double r;
  int i;
  r = 0;
  for (i = 0; i <= hi1 - lo1; i++)
    r += (a[i] - b[i]) * (a[i] - b[i]);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sqrDiff>:
  endbr64
  sub    %edx,%ecx
  js     L4
  lea    0x1(%rcx),%edx
  shl    $0x3,%rdx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L6:
  movsd  (%rdi,%rax,1),%xmm0
  subsd  (%rsi,%rax,1),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L6
L5:
  movapd %xmm1,%xmm0
  ret
L4:
  pxor   %xmm1,%xmm1
  jmp    L5
```

assistant: ```c
double sqrDiff(double *a, double *b, int lo1, int hi1) {
  double r;
  int i;
  r = 0;
  for (i = 0; i <= hi1 - lo1; i++)
    r += (a[i] - b[i]) * (a[i] - b[i]);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqrDiff>:
  endbr64
  sub    %edx,%ecx
  js     L5
  movslq %ecx,%rcx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  lea    0x8(,%rcx,8),%rdx
  nopl   0x0(%rax)
L4:
  movsd  (%rdi,%rax,1),%xmm0
  subsd  (%rsi,%rax,1),%xmm0
  add    $0x8,%rax
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L4
  movapd %xmm1,%xmm0
  ret
L5:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double sqrDiff(double *a, double *b, int lo1, int hi1) {
  double r;
  int i;
  r = 0;
  for (i = 0; i <= hi1 - lo1; i++)
    r += (a[i] - b[i]) * (a[i] - b[i]);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sqrDiff>:
  endbr64
  sub    %edx,%ecx
  js     L31
  lea    0x1(%rcx),%r8d
  test   %ecx,%ecx
  je     L46
  mov    %r8d,%edx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %edx
  shl    $0x4,%rdx
  nop
L3:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  subpd  %xmm3,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L3
  mov    %r8d,%ecx
  and    $0xfffffffe,%ecx
  and    $0x1,%r8d
  je     L5
L6:
  movslq %ecx,%rcx
  movsd  (%rdi,%rcx,8),%xmm1
  subsd  (%rsi,%rcx,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L5:
  ret
  nopl   0x0(%rax)
L31:
  pxor   %xmm0,%xmm0
  ret
L46:
  pxor   %xmm0,%xmm0
  jmp    L6
```

assistant: ```c
double sqrDiff(double *a, double *b, int lo1, int hi1) {
  double r;
  int i;
  r = 0;
  for (i = 0; i <= hi1 - lo1; i++)
    r += (a[i] - b[i]) * (a[i] - b[i]);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wcslcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L56
L24:
  addq   $0x1,-0x20(%rbp)
L56:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  je     L30
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
L30:
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L11
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  jmp    L60
L22:
  cmpq   $0x1,-0x10(%rbp)
  je     L46
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
L46:
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L60:
  leave
  ret
```

assistant: ```c
size_t wcslcat(wchar_t *dst, const wchar_t *src, size_t siz) {
  wchar_t *d = dst;
  const wchar_t *s = src;
  size_t n = siz;
  size_t dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + wcslen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wcslcat>:
  endbr64
  push   %rbx
  test   %rdx,%rdx
  je     L4
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
L68:
  cmpb   $0x0,(%rax)
  je     L38
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L68
  mov    %rcx,%rax
L38:
  mov    %rax,%rbx
  sub    %r8,%rbx
  sub    %rbx,%rdx
  je     L15
  movzbl (%rsi),%r8d
  mov    %rsi,%rcx
  test   %r8b,%r8b
  jne    L45
L46:
  movb   $0x0,(%rax)
  sub    %rsi,%rcx
  lea    (%rcx,%rbx,1),%rax
L80:
  pop    %rbx
  ret
L4:
  mov    %rdx,%rbx
L15:
  mov    %rsi,%rdi
  call   <wcslen@plt>
  add    %rbx,%rax
  jmp    L80
L58:
  add    $0x1,%rcx
  movzbl (%rcx),%r8d
  test   %r8b,%r8b
  je     L46
L45:
  cmp    $0x1,%rdx
  je     L58
  mov    %r8b,(%rax)
  sub    $0x1,%rdx
  lea    0x1(%rax),%rax
  jmp    L58
```

assistant: ```c
size_t wcslcat(wchar_t *dst, const wchar_t *src, size_t siz) {
  wchar_t *d = dst;
  const wchar_t *s = src;
  size_t n = siz;
  size_t dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + wcslen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```