ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mean>:
  endbr64
  test   %rdx,%rdx
  mov    %edi,%ecx
  sete   %al
  shr    $0x1f,%edi
  or     %dil,%al
  jne    L84
  test   %rsi,%rsi
  je     L84
  test   %ecx,%ecx
  je     L4
  lea    -0x1(%rcx),%eax
  cmp    $0x2,%eax
  jbe    L9
  mov    %ecx,%edi
  mov    %rsi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rsi,%rdi,1),%rdi
  nopl   (%rax)
L58:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rdi,%rax
  jne    L58
  movdqa %xmm0,%xmm1
  mov    %ecx,%edi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edi
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%cl
  je     L70
L29:
  movslq %edi,%r8
  lea    0x0(,%r8,4),%r9
  add    (%rsi,%r8,4),%eax
  lea    0x1(%rdi),%r8d
  cmp    %r8d,%ecx
  jle    L70
  add    $0x2,%edi
  add    0x4(%rsi,%r9,1),%eax
  cmp    %edi,%ecx
  jle    L70
  add    0x8(%rsi,%r9,1),%eax
L70:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L98:
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  cvtsi2sd %ecx,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  ret
  nopl   (%rax)
L84:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  pxor   %xmm0,%xmm0
  jmp    L98
L9:
  xor    %eax,%eax
  xor    %edi,%edi
  jmp    L29
```

assistant: ```c
int mean(int size, int *values, double *result) {
  int i;
  int sum;
  if ((values == NULL) || (result == NULL) || (size < 0)) {
    return 1;
  }
  sum = 0;
  for (i = 0; i < size; i++) {
    sum += values[i];
  }
  *result = ((double)sum) / size;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<colamd_set_defaults>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L36:
  cmpl   $0x13,-0x4(%rbp)
  jle    L8
  mov    -0x18(%rbp),%rax
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L19
L12:
  nop
L19:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D27
type_guessed: byte[8]
name: read_data
arguments: label: D16
type_guessed: byte[8]

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void colamd_set_defaults(double knobs[20]) {
  int i;
  if (!knobs) {
    return;
  }
  for (i = 0; i < 20; i++) {
    knobs[i] = 0;
  }
  knobs[0] = 10;
  knobs[1] = 10;
  knobs[2] = (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<colamd_set_defaults>:
  endbr64
  test   %rdi,%rdi
  je     L10
  mov    %rdi,%rax
  lea    0xa0(%rdi),%rdx
L11:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L11
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  %xmm0,0x8(%rdi)
  mov    D0(%rip),%rax
  mov    %rax,0x10(%rdi)
L10:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type: byte[8]
name: disassemble_data
arguments: data_label: D0
type: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void colamd_set_defaults(double knobs[20]) {
  int i;
  if (!knobs) {
    return;
  }
  for (i = 0; i < 20; i++) {
    knobs[i] = 0;
  }
  knobs[0] = 10;
  knobs[1] = 10;
  knobs[2] = (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<colamd_set_defaults>:
  endbr64
  mov    %rdi,%rdx
  test   %rdi,%rdi
  je     L8
  lea    0x10(%rdi),%rdi
  mov    %edx,%eax
  movq   $0x0,0x88(%rdi)
  movsd  D7(%rip),%xmm0
  and    $0xfffffffffffffff8,%rdi
  sub    %edi,%eax
  lea    0xa0(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  mov    D0(%rip),%rax
  movsd  %xmm0,(%rdx)
  movsd  %xmm0,0x8(%rdx)
  mov    %rax,0x10(%rdx)
L8:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: byte[8]
name: unpack_data
arguments: data_tag: D0
type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void colamd_set_defaults(double knobs[20]) {
  int i;
  if (!knobs) {
    return;
  }
  for (i = 0; i < 20; i++) {
    knobs[i] = 0;
  }
  knobs[0] = 10;
  knobs[1] = 10;
  knobs[2] = (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<colamd_set_defaults>:
  endbr64
  mov    %rdi,%rdx
  test   %rdi,%rdi
  je     L6
  lea    0x18(%rdi),%rdi
  mov    %edx,%eax
  movq   $0x0,0x80(%rdi)
  movapd D2(%rip),%xmm0
  and    $0xfffffffffffffff8,%rdi
  sub    %edi,%eax
  lea    0xa0(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  mov    D11(%rip),%rax
  movups %xmm0,(%rdx)
  mov    %rax,0x10(%rdx)
L6:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D11
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void colamd_set_defaults(double knobs[20]) {
  int i;
  if (!knobs) {
    return;
  }
  for (i = 0; i < 20; i++) {
    knobs[i] = 0;
  }
  knobs[0] = 10;
  knobs[1] = 10;
  knobs[2] = (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L86
L76:
  movl   $0x0,-0x34(%rbp)
  jmp    L10
L17:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  add    %rsi,%rax
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L10:
  cmpl   $0x2,-0x34(%rbp)
  jle    L17
  addl   $0x1,-0x38(%rbp)
L86:
  cmpl   $0x2,-0x38(%rbp)
  jle    L76
  movl   $0x0,-0x38(%rbp)
  jmp    L65
L51:
  movl   $0x0,-0x34(%rbp)
  jmp    L68
L8:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L68:
  cmpl   $0x2,-0x34(%rbp)
  jle    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x38(%rbp)
L65:
  cmpl   $0x2,-0x38(%rbp)
  jle    L51
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4: %i 

assistant: ```c
int main() {
  int m[3][3];
  int i, j;
  srand(time(NULL));
  for (i = 0; i < 3; i++)
    for (j = 0; j < 3; j++)
      m[i][j] = rand() % 10;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf("%i ", m[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rsp,%rbx
  lea    0x24(%rsp),%r12
  mov    %rbx,%rbp
L21:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,0x8(%rbp)
  add    $0xc,%rbp
  cmp    %r12,%rbp
  jne    L21
  lea    D3(%rip),%rbp
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0xc,%rbx
  cmp    %r12,%rbx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: %i 

assistant: ```c
int main() {
  int m[3][3];
  int i, j;
  srand(time(NULL));
  for (i = 0; i < 3; i++)
    for (j = 0; j < 3; j++)
      m[i][j] = rand() % 10;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf("%i ", m[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x24(%rsp),%rbp
  call   <time@plt>
  mov    %r12,%rbx
  mov    %eax,%edi
  call   <srand@plt>
L6:
  xor    %eax,%eax
  add    $0xc,%rbx
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %rbx,%rbp
  jne    L6
  lea    D6(%rip),%rbx
L28:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0xc,%r12
  call   <printf@plt>
  mov    -0x8(%r12),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x4(%r12),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%r12
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: %i 

assistant: ```c
int main() {
  int m[3][3];
  int i, j;
  srand(time(NULL));
  for (i = 0; i < 3; i++)
    for (j = 0; j < 3; j++)
      m[i][j] = rand() % 10;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf("%i ", m[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x24(%rsp),%rbp
  call   <time@plt>
  mov    %r12,%rbx
  mov    %eax,%edi
  call   <srand@plt>
L7:
  xor    %eax,%eax
  add    $0xc,%rbx
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbx)
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %rbx,%rbp
  jne    L7
  lea    D3(%rip),%rbx
L26:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0xc,%r12
  call   <printf@plt>
  mov    -0x8(%r12),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x4(%r12),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%r12
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: %i 

assistant: ```c
int main() {
  int m[3][3];
  int i, j;
  srand(time(NULL));
  for (i = 0; i < 3; i++)
    for (j = 0; j < 3; j++)
      m[i][j] = rand() % 10;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf("%i ", m[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<encode_stream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L52
L85:
  mov    -0x38(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x2,-0x1c(%rbp)
  jg     L21
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L94
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L21
L94:
  movl   $0x1,-0x20(%rbp)
L21:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L52
  cmpl   $0x0,-0x18(%rbp)
  jle    L52
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  lea    -0x14(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <encode_3byte@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x28(%rbp)
L52:
  mov    -0x28(%rbp),%eax
  add    $0xc,%eax
  cmp    %eax,-0x3c(%rbp)
  jle    L65
  cmpl   $0x0,-0x20(%rbp)
  jne    L65
  cmpl   $0x0,-0x24(%rbp)
  je     L85
L65:
  cmpl   $0x0,-0x24(%rbp)
  je     L82
  movl   $0xffffffff,-0x28(%rbp)
L82:
  mov    -0x28(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: fread

assistant: ```c
int32_t encode_stream(FILE *fp, int32_t dlen, uint8_t *dst) {
  int32_t cnt = 0;
  int32_t err_flag = 0;
  int32_t eof_flag = 0;
  while ((cnt + 3 * 4) < dlen && (!eof_flag) && (!err_flag)) {
    uint8_t ibuf[3];
    int32_t ret;
    int32_t nread;
    ret = fread(ibuf, 1, 3, fp);
    if (ret < 3) {
      if (ferror(fp)) {
        perror("fread");
        err_flag = 1;
      } else {
        eof_flag = 1;
      }
    }
    nread = ret;
    if (!err_flag && nread > 0) {
      ret = encode_3byte(nread, ibuf, dst + cnt);
      assert(ret > 0);
      cnt += ret;
    }
  }
  if (err_flag) {
    cnt = -1;
  }
  return cnt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encode_stream>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0xc,%esi
  jle    L50
  mov    %rdi,%r13
  mov    %esi,%r15d
  mov    $0x0,%ebp
  lea    0x1c(%rsp),%r14
  jmp    L93
L35:
  mov    %r13,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L78
  mov    $0x1,%r12d
  jmp    L13
L78:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
L80:
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovne %eax,%ebp
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  mov    %ebp,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  lea    0xc(%rbp),%eax
  cmp    %r15d,%eax
  jge    L103
  test   %r12d,%r12d
  jne    L114
L93:
  mov    %r13,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <fread@plt>
  mov    %eax,%ebx
  mov    $0x0,%r12d
  cmp    $0x2,%eax
  jle    L35
L13:
  test   %ebx,%ebx
  jle    L7
  movslq %ebp,%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,4),%rdx
  mov    %r14,%rsi
  mov    %ebx,%edi
  call   <encode_3byte@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    %ebx,%ebp
  jmp    L7
L114:
  mov    $0x0,%eax
  jmp    L80
L103:
  mov    $0x0,%eax
  jmp    L80
L50:
  mov    $0x0,%ebp
  jmp    L0
L110:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: fread

assistant: ```c
int32_t encode_stream(FILE *fp, int32_t dlen, uint8_t *dst) {
  int32_t cnt = 0;
  int32_t err_flag = 0;
  int32_t eof_flag = 0;
  while ((cnt + 3 * 4) < dlen && (!eof_flag) && (!err_flag)) {
    uint8_t ibuf[3];
    int32_t ret;
    int32_t nread;
    ret = fread(ibuf, 1, 3, fp);
    if (ret < 3) {
      if (ferror(fp)) {
        perror("fread");
        err_flag = 1;
      } else {
        eof_flag = 1;
      }
    }
    nread = ret;
    if (!err_flag && nread > 0) {
      ret = encode_3byte(nread, ibuf, dst + cnt);
      assert(ret > 0);
      cnt += ret;
    }
  }
  if (err_flag) {
    cnt = -1;
  }
  return cnt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encode_stream>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0xc,%esi
  jle    L94
  mov    %rdi,%r15
  mov    %esi,%ebx
  mov    %rdx,%r14
  xor    %r12d,%r12d
  lea    0xc(%rsp),%r13
L10:
  mov    %r15,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %eax,%ebp
  cmp    $0x2,%eax
  jle    L77
  movslq %r12d,%rax
  mov    %ebp,%edi
  mov    %r13,%rsi
  lea    (%r14,%rax,4),%rdx
  call   <encode_3byte@plt>
  xor    %edi,%edi
  mov    %eax,%ebp
  test   %eax,%eax
  setg   %dil
  add    %ebp,%r12d
  call   <assert@plt>
  lea    0xc(%r12),%eax
  cmp    %eax,%ebx
  jg     L10
  jmp    L86
  nopl   (%rax)
L77:
  mov    %r15,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L22
  test   %ebp,%ebp
  jg     L21
L86:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  lea    D9(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <perror@plt>
  jmp    L86
L94:
  xor    %r12d,%r12d
  jmp    L86
L21:
  movslq %r12d,%rax
  mov    %r13,%rsi
  mov    %ebp,%edi
  lea    (%r14,%rax,4),%rdx
  call   <encode_3byte@plt>
  xor    %edi,%edi
  test   %eax,%eax
  mov    %eax,%ebx
  setg   %dil
  add    %ebx,%r12d
  call   <assert@plt>
  jmp    L86
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string

tool: D9: fread

assistant: ```c
int32_t encode_stream(FILE *fp, int32_t dlen, uint8_t *dst) {
  int32_t cnt = 0;
  int32_t err_flag = 0;
  int32_t eof_flag = 0;
  while ((cnt + 3 * 4) < dlen && (!eof_flag) && (!err_flag)) {
    uint8_t ibuf[3];
    int32_t ret;
    int32_t nread;
    ret = fread(ibuf, 1, 3, fp);
    if (ret < 3) {
      if (ferror(fp)) {
        perror("fread");
        err_flag = 1;
      } else {
        eof_flag = 1;
      }
    }
    nread = ret;
    if (!err_flag && nread > 0) {
      ret = encode_3byte(nread, ibuf, dst + cnt);
      assert(ret > 0);
      cnt += ret;
    }
  }
  if (err_flag) {
    cnt = -1;
  }
  return cnt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<encode_stream>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0xc,%esi
  jle    L48
  mov    %rdi,%r15
  mov    %esi,%ebx
  mov    %rdx,%r14
  xor    %r12d,%r12d
  lea    0xc(%rsp),%r13
L20:
  mov    %r15,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %eax,%ebp
  cmp    $0x2,%eax
  jle    L41
  movslq %r12d,%rax
  mov    %ebp,%edi
  mov    %r13,%rsi
  lea    (%r14,%rax,4),%rdx
  call   <encode_3byte@plt>
  xor    %edi,%edi
  mov    %eax,%ebp
  test   %eax,%eax
  setg   %dil
  add    %ebp,%r12d
  call   <assert@plt>
  lea    0xc(%r12),%eax
  cmp    %eax,%ebx
  jg     L20
  jmp    L24
  nopl   (%rax)
L41:
  mov    %r15,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L78
  test   %ebp,%ebp
  jg     L11
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  lea    D0(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <perror@plt>
  jmp    L24
L48:
  xor    %r12d,%r12d
  jmp    L24
L11:
  movslq %r12d,%rax
  mov    %r13,%rsi
  mov    %ebp,%edi
  lea    (%r14,%rax,4),%rdx
  call   <encode_3byte@plt>
  xor    %edi,%edi
  test   %eax,%eax
  mov    %eax,%ebx
  setg   %dil
  add    %ebx,%r12d
  call   <assert@plt>
  jmp    L24
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string

tool: D0: fread

assistant: ```c
int32_t encode_stream(FILE *fp, int32_t dlen, uint8_t *dst) {
  int32_t cnt = 0;
  int32_t err_flag = 0;
  int32_t eof_flag = 0;
  while ((cnt + 3 * 4) < dlen && (!eof_flag) && (!err_flag)) {
    uint8_t ibuf[3];
    int32_t ret;
    int32_t nread;
    ret = fread(ibuf, 1, 3, fp);
    if (ret < 3) {
      if (ferror(fp)) {
        perror("fread");
        err_flag = 1;
      } else {
        eof_flag = 1;
      }
    }
    nread = ret;
    if (!err_flag && nread > 0) {
      ret = encode_3byte(nread, ibuf, dst + cnt);
      assert(ret > 0);
      cnt += ret;
    }
  }
  if (err_flag) {
    cnt = -1;
  }
  return cnt;
}
```