ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<libcperciva_be16enc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x1c(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void libcperciva_be16enc(void *pp, uint16_t x) {
  uint8_t *p = (uint8_t *)pp;
  p[1] = x & 0xff;
  p[0] = (x >> 8) & 0xff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<libcperciva_be16enc>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  mov    %edx,0x4(%rdi)
  movzbl %ah,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void libcperciva_be16enc(void *pp, uint16_t x) {
  uint8_t *p = (uint8_t *)pp;
  p[1] = x & 0xff;
  p[0] = (x >> 8) & 0xff;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<libcperciva_be16enc>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  movzbl %ah,%eax
  mov    %edx,0x4(%rdi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void libcperciva_be16enc(void *pp, uint16_t x) {
  uint8_t *p = (uint8_t *)pp;
  p[1] = x & 0xff;
  p[0] = (x >> 8) & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<libcperciva_be16enc>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  movzbl %ah,%eax
  mov    %edx,0x4(%rdi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void libcperciva_be16enc(void *pp, uint16_t x) {
  uint8_t *p = (uint8_t *)pp;
  p[1] = x & 0xff;
  p[0] = (x >> 8) & 0xff;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mz_rawout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0x5(%rbp)
  movb   $0xff,-0x5(%rbp)
  jmp    L7
L19:
  movzbl -0x14(%rbp),%eax
  test   %al,%al
  jns    L36
  mov    $0x0,%eax
  call   <lp@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L21
L36:
  mov    $0x0,%eax
  call   <sp@plt>
L21:
  shlb   -0x14(%rbp)
  movzbl -0x5(%rbp),%eax
  shr    %al
  mov    %al,-0x5(%rbp)
L7:
  cmpb   $0x0,-0x5(%rbp)
  jne    L19
  mov    $0x0,%eax
  call   <lp@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int mz_rawout(unsigned char b) {
  unsigned int cs = 0;
  unsigned char i = 0;
  for (i = 0xff; i; i /= 2) {
    if (b & 0x80) {
      lp();
      cs++;
    } else
      sp();
    b *= 2;
  }
  lp();
  return cs;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mz_rawout>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%ebp
  mov    $0x0,%r12d
  jmp    L35
L27:
  mov    $0x0,%eax
  call   <sp@plt>
L28:
  add    %ebx,%ebx
  sub    $0x1,%ebp
  je     L37
L35:
  test   %bl,%bl
  jns    L27
  mov    $0x0,%eax
  call   <lp@plt>
  add    $0x1,%r12d
  jmp    L28
L37:
  mov    $0x0,%eax
  call   <lp@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int mz_rawout(unsigned char b) {
  unsigned int cs = 0;
  unsigned char i = 0;
  for (i = 0xff; i; i /= 2) {
    if (b & 0x80) {
      lp();
      cs++;
    } else
      sp();
    b *= 2;
  }
  lp();
  return cs;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mz_rawout>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    %edi,%ebx
  jmp    L18
  nopl   0x0(%rax)
L20:
  call   <sp@plt>
  add    %ebx,%ebx
  sub    $0x1,%ebp
  je     L9
L18:
  xor    %eax,%eax
  test   %bl,%bl
  jns    L20
  call   <lp@plt>
  add    $0x1,%r12d
  add    %ebx,%ebx
  sub    $0x1,%ebp
  jne    L18
L9:
  xor    %eax,%eax
  call   <lp@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int mz_rawout(unsigned char b) {
  unsigned int cs = 0;
  unsigned char i = 0;
  for (i = 0xff; i; i /= 2) {
    if (b & 0x80) {
      lp();
      cs++;
    } else
      sp();
    b *= 2;
  }
  lp();
  return cs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mz_rawout>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    %edi,%ebx
  jmp    L1
  nopl   0x0(%rax)
L12:
  call   <sp@plt>
  add    %ebx,%ebx
  sub    $0x1,%ebp
  je     L22
L1:
  xor    %eax,%eax
  test   %bl,%bl
  jns    L12
  call   <lp@plt>
  add    $0x1,%r12d
  add    %ebx,%ebx
  sub    $0x1,%ebp
  jne    L1
L22:
  xor    %eax,%eax
  call   <lp@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int mz_rawout(unsigned char b) {
  unsigned int cs = 0;
  unsigned char i = 0;
  for (i = 0xff; i; i /= 2) {
    if (b & 0x80) {
      lp();
      cs++;
    } else
      sp();
    b *= 2;
  }
  lp();
  return cs;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RunMaliTest_sim3_t760>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Mali_SetBase@plt>
  mov    $0x0,%eax
  call   <RunMaliTest_sim3_t760_part0@plt>
  mov    $0x0,%eax
  call   <RunMaliTest_sim3_t760_part1@plt>
  nop
  leave
  ret
```

assistant: ```c
int RunMaliTest_sim3_t760(int *base) {
  Mali_SetBase(base);
  RunMaliTest_sim3_t760_part0();
  RunMaliTest_sim3_t760_part1();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RunMaliTest_sim3_t760>:
  endbr64
  sub    $0x8,%rsp
  call   <Mali_SetBase@plt>
  mov    $0x0,%eax
  call   <RunMaliTest_sim3_t760_part0@plt>
  mov    $0x0,%eax
  call   <RunMaliTest_sim3_t760_part1@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int RunMaliTest_sim3_t760(int *base) {
  Mali_SetBase(base);
  RunMaliTest_sim3_t760_part0();
  RunMaliTest_sim3_t760_part1();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RunMaliTest_sim3_t760>:
  endbr64
  sub    $0x8,%rsp
  call   <Mali_SetBase@plt>
  xor    %eax,%eax
  call   <RunMaliTest_sim3_t760_part0@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <RunMaliTest_sim3_t760_part1@plt>
```

assistant: ```c
int RunMaliTest_sim3_t760(int *base) {
  Mali_SetBase(base);
  RunMaliTest_sim3_t760_part0();
  RunMaliTest_sim3_t760_part1();
}
```
user: Translate the below assembly code into C programming language:

```asm
<RunMaliTest_sim3_t760>:
  endbr64
  sub    $0x8,%rsp
  call   <Mali_SetBase@plt>
  xor    %eax,%eax
  call   <RunMaliTest_sim3_t760_part0@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <RunMaliTest_sim3_t760_part1@plt>
```

assistant: ```c
int RunMaliTest_sim3_t760(int *base) {
  Mali_SetBase(base);
  RunMaliTest_sim3_t760_part0();
  RunMaliTest_sim3_t760_part1();
}
```
user: What is the c source code of the assembly code below?

```asm
<write_to_tty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x20(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
  jmp    L4
L7:
  mov    -0x2c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x20(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
L4:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L7
  nop
  leave
  ret
```

assistant: ```c
void write_to_tty(int ttyfd, int fillfd, int totalsize, int buffsize, char buf[], int buffmaxsize) {
  write(ttyfd, buf, buffsize);
  totalsize -= buffsize;
  while (totalsize > 0) {
    int readmax;
    readmax = (((totalsize) < (buffmaxsize)) ? (totalsize) : (buffmaxsize));
    buffsize = read(fillfd, buf, readmax);
    write(ttyfd, buf, buffsize);
    totalsize -= buffsize;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_to_tty>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%r15d
  mov    %edx,%ebx
  mov    %ecx,%ebp
  mov    %r8,%r12
  mov    %r9d,%r13d
  mov    %ecx,%edx
  mov    %r8,%rsi
  call   <write@plt>
  sub    %ebp,%ebx
  test   %ebx,%ebx
  jle    L16
L15:
  cmp    %ebx,%r13d
  mov    %ebx,%edx
  cmovle %r13d,%edx
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <read@plt>
  mov    %eax,%ebp
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <write@plt>
  sub    %ebp,%ebx
  test   %ebx,%ebx
  jg     L15
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void write_to_tty(int ttyfd, int fillfd, int totalsize, int buffsize, char buf[], int buffmaxsize) {
  write(ttyfd, buf, buffsize);
  totalsize -= buffsize;
  while (totalsize > 0) {
    int readmax;
    readmax = (((totalsize) < (buffmaxsize)) ? (totalsize) : (buffmaxsize));
    buffsize = read(fillfd, buf, readmax);
    write(ttyfd, buf, buffsize);
    totalsize -= buffsize;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_to_tty>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %esi,%r14d
  mov    %r8,%rsi
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %ecx,%edx
  sub    %r15d,%ebx
  sub    $0x8,%rsp
  call   <write@plt>
  test   %ebx,%ebx
  jle    L19
  nopl   0x0(%rax)
L12:
  cmp    %ebx,%r12d
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  cmovle %r12d,%edx
  call   <read@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    %eax,%r15d
  mov    %eax,%edx
  call   <write@plt>
  sub    %r15d,%ebx
  test   %ebx,%ebx
  jg     L12
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void write_to_tty(int ttyfd, int fillfd, int totalsize, int buffsize, char buf[], int buffmaxsize) {
  write(ttyfd, buf, buffsize);
  totalsize -= buffsize;
  while (totalsize > 0) {
    int readmax;
    readmax = (((totalsize) < (buffmaxsize)) ? (totalsize) : (buffmaxsize));
    buffsize = read(fillfd, buf, readmax);
    write(ttyfd, buf, buffsize);
    totalsize -= buffsize;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_to_tty>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %esi,%r14d
  mov    %r8,%rsi
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %ecx,%edx
  sub    %r15d,%ebx
  sub    $0x8,%rsp
  call   <write@plt>
  test   %ebx,%ebx
  jle    L19
  nopl   0x0(%rax)
L17:
  cmp    %ebx,%r12d
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  cmovle %r12d,%edx
  call   <read@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    %eax,%r15d
  mov    %eax,%edx
  call   <write@plt>
  sub    %r15d,%ebx
  test   %ebx,%ebx
  jg     L17
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void write_to_tty(int ttyfd, int fillfd, int totalsize, int buffsize, char buf[], int buffmaxsize) {
  write(ttyfd, buf, buffsize);
  totalsize -= buffsize;
  while (totalsize > 0) {
    int readmax;
    readmax = (((totalsize) < (buffmaxsize)) ? (totalsize) : (buffmaxsize));
    buffsize = read(fillfd, buf, readmax);
    write(ttyfd, buf, buffsize);
    totalsize -= buffsize;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ASNDerCalcNumLengthBytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x7f,-0x8(%rbp)
  jg     L53
  mov    $0x1,%eax
  jmp    L73
L53:
  cmpq   $0xff,-0x8(%rbp)
  jg     L31
  mov    $0x2,%eax
  jmp    L73
L31:
  cmpq   $0xffff,-0x8(%rbp)
  jg     L46
  mov    $0x3,%eax
  jmp    L73
L46:
  cmpq   $0xffffff,-0x8(%rbp)
  jg     L32
  mov    $0x4,%eax
  jmp    L73
L32:
  mov    $0x5,%eax
L73:
  pop    %rbp
  ret
```

assistant: ```c
int ASNDerCalcNumLengthBytes(long nLength) {
  if (nLength <= 0x7F) {
    return 1;
  } else if (nLength <= 0xFF) {
    return 2;
  } else if (nLength <= 0xFFFF) {
    return 3;
  } else if (nLength <= 0xFFFFFF) {
    return 4;
  } else {
    return 5;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ASNDerCalcNumLengthBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%rdi
  jle    L10
  mov    $0x2,%eax
  cmp    $0xff,%rdi
  jle    L10
  mov    $0x3,%eax
  cmp    $0xffff,%rdi
  jle    L10
  cmp    $0xffffff,%rdi
  setg   %al
  movzbl %al,%eax
  add    $0x4,%eax
L10:
  ret
```

assistant: ```c
int ASNDerCalcNumLengthBytes(long nLength) {
  if (nLength <= 0x7F) {
    return 1;
  } else if (nLength <= 0xFF) {
    return 2;
  } else if (nLength <= 0xFFFF) {
    return 3;
  } else if (nLength <= 0xFFFFFF) {
    return 4;
  } else {
    return 5;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ASNDerCalcNumLengthBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%rdi
  jle    L10
  mov    $0x2,%eax
  cmp    $0xff,%rdi
  jle    L10
  mov    $0x3,%eax
  cmp    $0xffff,%rdi
  jle    L10
  xor    %eax,%eax
  cmp    $0xffffff,%rdi
  setg   %al
  add    $0x4,%eax
L10:
  ret
```

assistant: ```c
int ASNDerCalcNumLengthBytes(long nLength) {
  if (nLength <= 0x7F) {
    return 1;
  } else if (nLength <= 0xFF) {
    return 2;
  } else if (nLength <= 0xFFFF) {
    return 3;
  } else if (nLength <= 0xFFFFFF) {
    return 4;
  } else {
    return 5;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ASNDerCalcNumLengthBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%rdi
  jle    L12
  mov    $0x2,%eax
  cmp    $0xff,%rdi
  jle    L12
  mov    $0x3,%eax
  cmp    $0xffff,%rdi
  jle    L12
  xor    %eax,%eax
  cmp    $0xffffff,%rdi
  setg   %al
  add    $0x4,%eax
L12:
  ret
```

assistant: ```c
int ASNDerCalcNumLengthBytes(long nLength) {
  if (nLength <= 0x7F) {
    return 1;
  } else if (nLength <= 0xFF) {
    return 2;
  } else if (nLength <= 0xFFFF) {
    return 3;
  } else if (nLength <= 0xFFFFFF) {
    return 4;
  } else {
    return 5;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_standard_multi_homogenization>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x38e,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int solcon_standard_multi_homogenization(int m) {
  int fail;
  int b;
  double c;
  fail = _ada_use_c2phc4c(910, &m, &b, &c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<solcon_standard_multi_homogenization>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x1c(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x38e,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_standard_multi_homogenization(int m) {
  int fail;
  int b;
  double c;
  fail = _ada_use_c2phc4c(910, &m, &b, &c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solcon_standard_multi_homogenization>:
  endbr64
  sub    $0x38,%rsp
  xor    %r8d,%r8d
  mov    %edi,0xc(%rsp)
  lea    0x1c(%rsp),%rdx
  lea    0x20(%rsp),%rcx
  mov    $0x38e,%edi
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_standard_multi_homogenization(int m) {
  int fail;
  int b;
  double c;
  fail = _ada_use_c2phc4c(910, &m, &b, &c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solcon_standard_multi_homogenization>:
  endbr64
  sub    $0x38,%rsp
  xor    %r8d,%r8d
  mov    %edi,0xc(%rsp)
  lea    0x1c(%rsp),%rdx
  lea    0x20(%rsp),%rcx
  mov    $0x38e,%edi
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_standard_multi_homogenization(int m) {
  int fail;
  int b;
  double c;
  fail = _ada_use_c2phc4c(910, &m, &b, &c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L2:
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rdx
  mov    -0x4(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x14,-0x4(%rbp)
L4:
  cmpl   $0x12c,-0x4(%rbp)
  jle    L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
type_infered: byte[8]
name: parse_data
arguments: tag: D17
type_infered: string

tool: {"D13": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D17: %3d %6.1f


assistant: ```c
main() {
  int fah;
  for (fah = 0; fah <= 300; fah = fah + 20)
    printf("%3d %6.1f\n", fah, (5.0 / 9.0) * (fah - 32));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D9(%rip),%rbp
L3:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D16(%rip),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  cmp    $0x140,%ebx
  jne    L3
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D16
type_infered: byte[8]

tool: D9: %3d %6.1f


tool: {"D16": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fah;
  for (fah = 0; fah <= 300; fah = fah + 20)
    printf("%3d %6.1f\n", fah, (5.0 / 9.0) * (fah - 32));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D0(%rip),%xmm0
  add    $0x14,%ebx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D0
data_type: byte[8]

tool: D17: %3d %6.1f


tool: {"D0": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fah;
  for (fah = 0; fah <= 300; fah = fah + 20)
    printf("%3d %6.1f\n", fah, (5.0 / 9.0) * (fah - 32));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D15(%rip),%xmm0
  add    $0x14,%ebx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D15
datatype: byte[8]

tool: D17: %3d %6.1f


tool: {"D15": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
main() {
  int fah;
  for (fah = 0; fah <= 300; fah = fah + 20)
    printf("%3d %6.1f\n", fah, (5.0 / 9.0) * (fah - 32));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parent_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L54
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L54
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jg     L25
L54:
  mov    $0x0,%eax
  jmp    L32
L25:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L33
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <log_critical_perror@plt>
L33:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dirname@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L67
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L67
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <empty_or_whitespace@plt>
  test   %eax,%eax
  jne    L67
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  jmp    L32
L67:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L32:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D4: nyx: strdup

assistant: ```c
const char *parent_dir(const char *directory) {
  if (directory == NULL || *directory != '/' || strlen(directory) <= 1)
    return NULL;
  char *input = strdup(directory);
  if (input == NULL)
    log_critical_perror("nyx: strdup");
  const char *parent = dirname(input);
  if (parent && *parent != '.' && !empty_or_whitespace(parent)) {
    const char *result = strdup(parent);
    free(input);
    return result;
  }
  free(input);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parent_dir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L71
  mov    $0x0,%ebp
  cmpb   $0x2f,(%rdi)
  jne    L35
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L35
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L54
L75:
  mov    %rbx,%rdi
  call   <dirname@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L18
  cmpb   $0x2e,(%rax)
  je     L18
  mov    %rax,%rdi
  call   <empty_or_whitespace@plt>
  test   %eax,%eax
  je     L48
L18:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebp
L35:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L54:
  lea    D0(%rip),%rdi
  call   <log_critical_perror@plt>
  jmp    L75
L48:
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L35
L71:
  mov    %rdi,%rbp
  jmp    L35
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D0: nyx: strdup

assistant: ```c
const char *parent_dir(const char *directory) {
  if (directory == NULL || *directory != '/' || strlen(directory) <= 1)
    return NULL;
  char *input = strdup(directory);
  if (input == NULL)
    log_critical_perror("nyx: strdup");
  const char *parent = dirname(input);
  if (parent && *parent != '.' && !empty_or_whitespace(parent)) {
    const char *result = strdup(parent);
    free(input);
    return result;
  }
  free(input);
  return NULL;
}
```