user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  lea    D23(%rip),%r15
  push   %r14
  push   %r13
  lea    D62(%rip),%r13
  push   %r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  lea    D24(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  movl   $0x1,0x14(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L116:
  movl   $0xffffffff,0x10(%rsp)
L153:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xb,%edx
  ja     L153
  lea    D0(%rip),%r14
  cs nopw 0x0(%rax,%rax,1)
L157:
  cmp    $0xc,%eax
  ja     L152
  mov    %eax,%edx
  movslq (%rbx,%rdx,4),%rdx
  add    %rbx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
  lea    D110(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  nopl   0x0(%rax,%rax,1)
L152:
  sub    $0x1,%eax
  mov    %eax,0x10(%rsp)
  test   %eax,%eax
  jg     L157
  mov    %r15,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  je     L116
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L146
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
  lea    D74(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopw   0x0(%rax,%rax,1)
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopw   0x0(%rax,%rax,1)
  lea    D76(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopl   (%rax)
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopl   0x0(%rax)
  lea    D159(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopl   (%rax)
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopl   (%rax)
  lea    D103(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopl   (%rax)
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopl   (%rax)
  lea    D158(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopl   (%rax)
  lea    D139(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
  nopl   (%rax)
  lea    D136(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  jmp    L152
L146:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
type_guessed: string
name: disassemble_data
arguments: data_label: D62
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string
name: disassemble_data
arguments: data_label: D110
type_guessed: string
name: disassemble_data
arguments: data_label: D74
type_guessed: string
name: disassemble_data
arguments: data_label: D13
type_guessed: string
name: disassemble_data
arguments: data_label: D76
type_guessed: string
name: disassemble_data
arguments: data_label: D159
type_guessed: string
name: disassemble_data
arguments: data_label: D48
type_guessed: string
name: disassemble_data
arguments: data_label: D103
type_guessed: string
name: disassemble_data
arguments: data_label: D29
type_guessed: string
name: disassemble_data
arguments: data_label: D158
type_guessed: string
name: disassemble_data
arguments: data_label: D139
type_guessed: string
name: disassemble_data
arguments: data_label: D136
type_guessed: string

tool: D23: Would you like to continue? (1 = yes, 0 = no): 

tool: D62: Please enter an integer in the range [1,12]: 

tool: D25: %d

tool: D0: 10 Lords a Leaping


tool: D110: 12 Drummers Drumming


tool: D74: 11 Pipers Piping


tool: D13: 9 Ladies Dancing


tool: D76: 8 Maids a Milking


tool: D159: 7 Swans a Swimming


tool: D48: 6 Geese a Laying


tool: D103: 5 Golden Rings


tool: D29: 4 Calling Birds


tool: D158: 3 French Hens


tool: D139: ...and a Partridge in a Pear Tree!


tool: D136: 2 Turtle Doves


assistant: ```c
void main() {
  int num;
  int cont = 1;
  while (cont == 1) {
    for (num = -1; (num < 1) || (num > 12);) {
      printf("Please enter an integer in the range [1,12]: ");
      scanf("%d", &num);
    }
    while (num > 0) {
      switch (num) {
      case 1:
        printf("...and a Partridge in a Pear Tree!\n");
        break;
      case 2:
        printf("2 Turtle Doves\n");
        break;
      case 3:
        printf("3 French Hens\n");
        break;
      case 4:
        printf("4 Calling Birds\n");
        break;
      case 5:
        printf("5 Golden Rings\n");
        break;
      case 6:
        printf("6 Geese a Laying\n");
        break;
      case 7:
        printf("7 Swans a Swimming\n");
        break;
      case 8:
        printf("8 Maids a Milking\n");
        break;
      case 9:
        printf("9 Ladies Dancing\n");
        break;
      case 10:
        printf("10 Lords a Leaping\n");
        break;
      case 11:
        printf("11 Pipers Piping\n");
        break;
      case 12:
        printf("12 Drummers Drumming\n");
        break;
      }
      num -= 1;
    }
    printf("Would you like to continue? (1 = yes, 0 = no): ");
    scanf("%d", &cont);
  }
}
```