ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D11
type_infered: string

tool: D8: input a and b

tool: D21: %d%d

tool: D11: a+b=%d


assistant: ```c
void main() {
  int a, b;
  printf("input a and b\n");
  scanf("%d%d", &a, &b);
  printf("a+b=%d\n", a + b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<us_elapsed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L10
  mov    -0x10(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  sub    %eax,%esi
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0xf4240,%eax,%eax
  add    %esi,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  jmp    L8
L10:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    $0xf4240,%edx
  sub    %eax,%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0xf4240,%eax,%eax
  add    %esi,%eax
  cltq
  mov    %rax,-0x18(%rbp)
L8:
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
long int us_elapsed(struct timeval *prev) {
  struct timeval aux;
  gettimeofday(&aux, NULL);
  long int result;
  if (aux.tv_usec >= prev->tv_usec) {
    result = aux.tv_usec - prev->tv_usec + (aux.tv_sec - prev->tv_sec) * 1000000;
  } else {
    result = 1000000 - prev->tv_usec + aux.tv_usec + (aux.tv_sec - 1 - prev->tv_sec) * 1000000;
  }
  *prev = aux;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<us_elapsed>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    (%rbx),%ecx
  cmp    %ecx,%edx
  jl     L15
  mov    0x4(%rsp),%eax
  sub    0x4(%rbx),%eax
  imul   $0xf4240,%eax,%eax
  sub    %ecx,%edx
  add    %edx,%eax
  cltq
L26:
  mov    (%rsp),%rdx
  mov    %rdx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  ret
L15:
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  sub    0x4(%rbx),%eax
  imul   $0xf4240,%eax,%eax
  sub    %ecx,%edx
  lea    0xf4240(%rax,%rdx,1),%eax
  cltq
  jmp    L26
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long int us_elapsed(struct timeval *prev) {
  struct timeval aux;
  gettimeofday(&aux, NULL);
  long int result;
  if (aux.tv_usec >= prev->tv_usec) {
    result = aux.tv_usec - prev->tv_usec + (aux.tv_sec - prev->tv_sec) * 1000000;
  } else {
    result = 1000000 - prev->tv_usec + aux.tv_usec + (aux.tv_sec - 1 - prev->tv_sec) * 1000000;
  }
  *prev = aux;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<us_elapsed>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    (%rbx),%ecx
  mov    0x4(%rsp),%eax
  cmp    %ecx,%edx
  jl     L5
  sub    0x4(%rbx),%eax
  sub    %ecx,%edx
  imul   $0xf4240,%eax,%eax
  add    %edx,%eax
  cltq
L16:
  mov    (%rsp),%rdx
  mov    %rdx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  ret
  nop
L5:
  sub    $0x1,%eax
  sub    0x4(%rbx),%eax
  sub    %ecx,%edx
  imul   $0xf4240,%eax,%eax
  lea    0xf4240(%rax,%rdx,1),%eax
  cltq
  jmp    L16
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long int us_elapsed(struct timeval *prev) {
  struct timeval aux;
  gettimeofday(&aux, NULL);
  long int result;
  if (aux.tv_usec >= prev->tv_usec) {
    result = aux.tv_usec - prev->tv_usec + (aux.tv_sec - prev->tv_sec) * 1000000;
  } else {
    result = 1000000 - prev->tv_usec + aux.tv_usec + (aux.tv_sec - 1 - prev->tv_sec) * 1000000;
  }
  *prev = aux;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<us_elapsed>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    (%rbx),%ecx
  mov    0x4(%rsp),%eax
  cmp    %ecx,%edx
  jl     L23
  sub    0x4(%rbx),%eax
  sub    %ecx,%edx
  imul   $0xf4240,%eax,%eax
  add    %edx,%eax
  cltq
L18:
  mov    (%rsp),%rdx
  mov    %rdx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
  nop
L23:
  sub    $0x1,%eax
  sub    0x4(%rbx),%eax
  sub    %ecx,%edx
  imul   $0xf4240,%eax,%eax
  lea    0xf4240(%rax,%rdx,1),%eax
  cltq
  jmp    L18
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long int us_elapsed(struct timeval *prev) {
  struct timeval aux;
  gettimeofday(&aux, NULL);
  long int result;
  if (aux.tv_usec >= prev->tv_usec) {
    result = aux.tv_usec - prev->tv_usec + (aux.tv_sec - prev->tv_sec) * 1000000;
  } else {
    result = 1000000 - prev->tv_usec + aux.tv_usec + (aux.tv_sec - 1 - prev->tv_sec) * 1000000;
  }
  *prev = aux;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<handle_the_player>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L9
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <player_command@plt>
L9:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <get_input_line@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  nop
  leave
  ret
```

assistant: ```c
handle_the_player() {
  char *player_line;
  while ((player_line = get_input_line(stdin)) != 0)
    player_command(player_line);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<handle_the_player>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
  jmp    L6
L5:
  call   <player_command@plt>
L6:
  mov    (%rbx),%edi
  call   <get_input_line@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
handle_the_player() {
  char *player_line;
  while ((player_line = get_input_line(stdin)) != 0)
    player_command(player_line);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_the_player>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
  jmp    L15
  xchg   %ax,%ax
L13:
  call   <player_command@plt>
L15:
  mov    (%rbx),%edi
  call   <get_input_line@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L13
  pop    %rbx
  ret
```

assistant: ```c
handle_the_player() {
  char *player_line;
  while ((player_line = get_input_line(stdin)) != 0)
    player_command(player_line);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_the_player>:
  endbr64
  push   %rbx
  mov    D6(%rip),%rbx
  jmp    L7
  xchg   %ax,%ax
L5:
  call   <player_command@plt>
L7:
  mov    (%rbx),%edi
  call   <get_input_line@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
handle_the_player() {
  char *player_line;
  while ((player_line = get_input_line(stdin)) != 0)
    player_command(player_line);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<id_hyper_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  cmpb   $0x0,-0x14(%rbp)
  js     L69
  movq   $0x1,-0x8(%rbp)
  jmp    L47
L69:
  movsbl -0x14(%rbp),%eax
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  jne    L27
  movq   $0x2,-0x8(%rbp)
  jmp    L47
L27:
  movsbl -0x14(%rbp),%eax
  and    $0xf0,%eax
  cmp    $0xe0,%eax
  jne    L81
  movq   $0x3,-0x8(%rbp)
  jmp    L47
L81:
  movsbl -0x14(%rbp),%eax
  and    $0xf8,%eax
  cmp    $0xf0,%eax
  jne    L3
  movq   $0x4,-0x8(%rbp)
  jmp    L47
L3:
  movsbl -0x14(%rbp),%eax
  and    $0xfc,%eax
  cmp    $0xf8,%eax
  jne    L37
  movq   $0x5,-0x8(%rbp)
  jmp    L47
L37:
  movsbl -0x14(%rbp),%eax
  and    $0xfe,%eax
  cmp    $0xfc,%eax
  jne    L40
  movq   $0x6,-0x8(%rbp)
  jmp    L47
L40:
  movq   $0x0,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t id_hyper_length(char ch) {
  size_t bytes_number;
  if ((ch & 0x80) == 0)
    bytes_number = 1;
  else if ((ch & 0xe0) == 0xc0)
    bytes_number = 2;
  else if ((ch & 0xf0) == 0xe0)
    bytes_number = 3;
  else if ((ch & 0xf8) == 0xf0)
    bytes_number = 4;
  else if ((ch & 0xfc) == 0xf8)
    bytes_number = 5;
  else if ((ch & 0xfe) == 0xfc)
    bytes_number = 6;
  else
    bytes_number = 0;
  return bytes_number;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<id_hyper_length>:
  endbr64
  mov    $0x1,%eax
  test   %dil,%dil
  js     L25
L17:
  ret
L25:
  movsbl %dil,%edx
  and    $0xe0,%edi
  mov    $0x2,%eax
  cmp    $0xc0,%edi
  je     L17
  mov    %edx,%ecx
  and    $0xf0,%ecx
  mov    $0x3,%eax
  cmp    $0xe0,%ecx
  je     L17
  mov    %edx,%ecx
  and    $0xf8,%ecx
  mov    $0x4,%eax
  cmp    $0xf0,%ecx
  je     L17
  mov    %edx,%ecx
  and    $0xfc,%ecx
  mov    $0x5,%eax
  cmp    $0xf8,%ecx
  je     L17
  and    $0xfe,%edx
  cmp    $0xfc,%edx
  mov    $0x6,%eax
  mov    $0x0,%edx
  cmovne %rdx,%rax
  jmp    L17
```

assistant: ```c
size_t id_hyper_length(char ch) {
  size_t bytes_number;
  if ((ch & 0x80) == 0)
    bytes_number = 1;
  else if ((ch & 0xe0) == 0xc0)
    bytes_number = 2;
  else if ((ch & 0xf0) == 0xe0)
    bytes_number = 3;
  else if ((ch & 0xf8) == 0xf0)
    bytes_number = 4;
  else if ((ch & 0xfc) == 0xf8)
    bytes_number = 5;
  else if ((ch & 0xfe) == 0xfc)
    bytes_number = 6;
  else
    bytes_number = 0;
  return bytes_number;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<id_hyper_length>:
  endbr64
  mov    $0x1,%eax
  test   %dil,%dil
  js     L41
L21:
  ret
  nop
L41:
  movsbl %dil,%edx
  and    $0xe0,%edi
  mov    $0x2,%eax
  cmp    $0xc0,%edi
  je     L21
  mov    %edx,%ecx
  mov    $0x3,%eax
  and    $0xf0,%ecx
  cmp    $0xe0,%ecx
  je     L21
  mov    %edx,%ecx
  mov    $0x4,%eax
  and    $0xf8,%ecx
  cmp    $0xf0,%ecx
  je     L21
  mov    %edx,%ecx
  mov    $0x5,%eax
  and    $0xfc,%ecx
  cmp    $0xf8,%ecx
  je     L21
  and    $0xfe,%edx
  mov    $0x6,%eax
  cmp    $0xfc,%edx
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
size_t id_hyper_length(char ch) {
  size_t bytes_number;
  if ((ch & 0x80) == 0)
    bytes_number = 1;
  else if ((ch & 0xe0) == 0xc0)
    bytes_number = 2;
  else if ((ch & 0xf0) == 0xe0)
    bytes_number = 3;
  else if ((ch & 0xf8) == 0xf0)
    bytes_number = 4;
  else if ((ch & 0xfc) == 0xf8)
    bytes_number = 5;
  else if ((ch & 0xfe) == 0xfc)
    bytes_number = 6;
  else
    bytes_number = 0;
  return bytes_number;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<id_hyper_length>:
  endbr64
  mov    $0x1,%eax
  test   %dil,%dil
  js     L40
L16:
  ret
  nop
L40:
  movsbl %dil,%edx
  and    $0xe0,%edi
  mov    $0x2,%eax
  cmp    $0xc0,%edi
  je     L16
  mov    %edx,%ecx
  mov    $0x3,%eax
  and    $0xf0,%ecx
  cmp    $0xe0,%ecx
  je     L16
  mov    %edx,%ecx
  mov    $0x4,%eax
  and    $0xf8,%ecx
  cmp    $0xf0,%ecx
  je     L16
  mov    %edx,%ecx
  mov    $0x5,%eax
  and    $0xfc,%ecx
  cmp    $0xf8,%ecx
  je     L16
  and    $0xfe,%edx
  mov    $0x6,%eax
  cmp    $0xfc,%edx
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
size_t id_hyper_length(char ch) {
  size_t bytes_number;
  if ((ch & 0x80) == 0)
    bytes_number = 1;
  else if ((ch & 0xe0) == 0xc0)
    bytes_number = 2;
  else if ((ch & 0xf0) == 0xe0)
    bytes_number = 3;
  else if ((ch & 0xf8) == 0xf0)
    bytes_number = 4;
  else if ((ch & 0xfc) == 0xf8)
    bytes_number = 5;
  else if ((ch & 0xfe) == 0xfc)
    bytes_number = 6;
  else
    bytes_number = 0;
  return bytes_number;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<roadmap_preferences_force>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <roadmap_preferences_ok@plt>
  mov    $0x1,%edi
  call   <roadmap_config_save@plt>
  nop
  leave
  ret
```

assistant: ```c
void roadmap_preferences_force(const char *name, void *data) {
  roadmap_preferences_ok(name, data);
  roadmap_config_save(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<roadmap_preferences_force>:
  endbr64
  sub    $0x8,%rsp
  call   <roadmap_preferences_ok@plt>
  mov    $0x1,%edi
  call   <roadmap_config_save@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void roadmap_preferences_force(const char *name, void *data) {
  roadmap_preferences_ok(name, data);
  roadmap_config_save(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<roadmap_preferences_force>:
  endbr64
  sub    $0x8,%rsp
  call   <roadmap_preferences_ok@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <roadmap_config_save@plt>
```

assistant: ```c
void roadmap_preferences_force(const char *name, void *data) {
  roadmap_preferences_ok(name, data);
  roadmap_config_save(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<roadmap_preferences_force>:
  endbr64
  sub    $0x8,%rsp
  call   <roadmap_preferences_ok@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <roadmap_config_save@plt>
```

assistant: ```c
void roadmap_preferences_force(const char *name, void *data) {
  roadmap_preferences_ok(name, data);
  roadmap_config_save(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<config_deblank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L4
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L15
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L15
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L15:
  addq   $0x1,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *config_deblank(char *str) {
  char *out = str;
  char *put = str;
  for (; *str != '\0'; ++str) {
    if (*str != ' ' && *str != '\n')
      *put++ = *str;
  }
  *put = '\0';
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<config_deblank>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L29
  mov    %rdi,%rsi
  mov    %rdi,%rcx
  jmp    L36
L34:
  mov    %dl,(%rsi)
  lea    0x1(%rsi),%rsi
L48:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L30
L36:
  cmp    $0x20,%dl
  je     L48
  cmp    $0xa,%dl
  jne    L34
  jmp    L48
L29:
  mov    %rdi,%rsi
L30:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
char *config_deblank(char *str) {
  char *out = str;
  char *put = str;
  for (; *str != '\0'; ++str) {
    if (*str != ' ' && *str != '\n')
      *put++ = *str;
  }
  *put = '\0';
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<config_deblank>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %rdi,%rsi
  test   %dl,%dl
  je     L3
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L20:
  cmp    $0x20,%dl
  je     L19
  cmp    $0xa,%dl
  je     L19
  mov    %dl,(%rsi)
  add    $0x1,%rsi
L19:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L20
L3:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
char *config_deblank(char *str) {
  char *out = str;
  char *put = str;
  for (; *str != '\0'; ++str) {
    if (*str != ' ' && *str != '\n')
      *put++ = *str;
  }
  *put = '\0';
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<config_deblank>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %rdi,%rsi
  test   %dl,%dl
  je     L12
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L14:
  cmp    $0x20,%dl
  je     L9
  cmp    $0xa,%dl
  je     L9
  add    $0x1,%rcx
  mov    %dl,(%rsi)
  lea    0x1(%rsi),%r8
  movzbl (%rcx),%edx
  mov    %r8,%rsi
  test   %dl,%dl
  jne    L14
L12:
  movb   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L14
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
char *config_deblank(char *str) {
  char *out = str;
  char *put = str;
  for (; *str != '\0'; ++str) {
    if (*str != ' ' && *str != '\n')
      *put++ = *str;
  }
  *put = '\0';
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L2
  jmp    L46
L42:
  addq   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  subq   $0x1,-0x8(%rbp)
  jmp    L28
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L28:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L0
L2:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *str) {
  char *end = str;
  char tmp;
  if (str) {
    while (*end) {
      ++end;
    }
    --end;
    while (str < end) {
      tmp = *str;
      *str++ = *end;
      *end-- = tmp;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverse>:
  endbr64
  test   %rdi,%rdi
  je     L18
  cmpb   $0x0,(%rdi)
  je     L37
  mov    %rdi,%rax
L4:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L4
L40:
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jae    L18
L54:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  movzbl (%rax),%ecx
  mov    %cl,-0x1(%rdi)
  sub    $0x1,%rax
  mov    %dl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L54
L18:
  ret
L37:
  mov    %rdi,%rax
  jmp    L40
```

assistant: ```c
void reverse(char *str) {
  char *end = str;
  char tmp;
  if (str) {
    while (*end) {
      ++end;
    }
    --end;
    while (str < end) {
      tmp = *str;
      *str++ = *end;
      *end-- = tmp;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  test   %rdi,%rdi
  je     L32
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L30
  mov    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L20
L43:
  cmp    %rdi,%rax
  ja     L3
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl (%rdi),%ecx
L3:
  movzbl (%rax),%edx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %dl,-0x1(%rdi)
  mov    %cl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L24
L32:
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  lea    -0x1(%rdi),%rax
  jmp    L43
```

assistant: ```c
void reverse(char *str) {
  char *end = str;
  char tmp;
  if (str) {
    while (*end) {
      ++end;
    }
    --end;
    while (str < end) {
      tmp = *str;
      *str++ = *end;
      *end-- = tmp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  test   %rdi,%rdi
  je     L30
  cmpb   $0x0,(%rdi)
  je     L15
  mov    %rdi,%rdx
  nopl   0x0(%rax)
L31:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L31
L29:
  cmp    %rdi,%rax
  jbe    L30
  nopl   0x0(%rax)
L37:
  movzbl (%rdi),%edx
  movzbl (%rax),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,-0x1(%rdi)
  mov    %dl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L37
L30:
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  lea    -0x1(%rdi),%rax
  jmp    L29
```

assistant: ```c
void reverse(char *str) {
  char *end = str;
  char tmp;
  if (str) {
    while (*end) {
      ++end;
    }
    --end;
    while (str < end) {
      tmp = *str;
      *str++ = *end;
      *end-- = tmp;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<changer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <yield@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: 
>>> on change de contexte !!! <<<


assistant: ```c
void changer() {
  printf("\n>>> on change de contexte !!! <<<\n");
  yield();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<changer>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <yield@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: 
>>> on change de contexte !!! <<<


assistant: ```c
void changer() {
  printf("\n>>> on change de contexte !!! <<<\n");
  yield();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<changer>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <yield@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: 
>>> on change de contexte !!! <<<


assistant: ```c
void changer() {
  printf("\n>>> on change de contexte !!! <<<\n");
  yield();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<changer>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <yield@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: 
>>> on change de contexte !!! <<<


assistant: ```c
void changer() {
  printf("\n>>> on change de contexte !!! <<<\n");
  yield();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x1,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L19
L2:
  shlq   -0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x40,-0xc(%rbp)
  jle    L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: 2^%d -> %llu 


assistant: ```c
int main() {
  unsigned long long n = 1;
  int i;
  for (i = 1; i <= 64; i++) {
    n = n << 1;
    printf("2^%d -> %llu \n", i, n);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  lea    D2(%rip),%r12
L8:
  add    %rbp,%rbp
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x41,%ebx
  jne    L8
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: 2^%d -> %llu 


assistant: ```c
int main() {
  unsigned long long n = 1;
  int i;
  for (i = 1; i <= 64; i++) {
    n = n << 1;
    printf("2^%d -> %llu \n", i, n);
  }
}
```