user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap_my>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_infered: string
name: extract_symbolic_data
arguments: data_label: D31
type_infered: string

tool: D14: in swap.

tool: D31: a [ left = %d ] = %d; a [ right = %d ] = %d; temp = %d.


assistant: ```c
void swap_my(int a[100], int left, int right) {
  int temp = 0;
  printf("in swap.\n");
  printf("a [ left = %d ] = %d; a [ right = %d ] = %d; temp = %d.\n", left, a[left], right, a[right], temp);
  temp = a[left];
  printf("a [ left = %d ] = %d; a [ right = %d ] = %d; temp = %d.\n", left, a[left], right, a[right], temp);
  a[left] = a[right];
  printf("a [ left = %d ] = %d; a [ right = %d ] = %d; temp = %d.\n", left, a[left], right, a[right], temp);
  a[right] = temp;
  printf("a [ left = %d ] = %d; a [ right = %d ] = %d; temp = %d.\n", left, a[left], right, a[right], temp);
}
```