ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<rename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__rename@plt>
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rename(const char *old, const char *new) {
  int ret;
  __rename(old, new);
  ret = 0;
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rename>:
  endbr64
  sub    $0x8,%rsp
  call   <__rename@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rename(const char *old, const char *new) {
  int ret;
  __rename(old, new);
  ret = 0;
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rename>:
  endbr64
  sub    $0x8,%rsp
  call   <__rename@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rename(const char *old, const char *new) {
  int ret;
  __rename(old, new);
  ret = 0;
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rename>:
  endbr64
  sub    $0x8,%rsp
  call   <__rename@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rename(const char *old, const char *new) {
  int ret;
  __rename(old, new);
  ret = 0;
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divConqSearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L47
  mov    $0xffffffff,%eax
  jmp    L25
L47:
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x28(%rbp)
  jne    L48
  mov    -0x4(%rbp),%eax
  jmp    L25
L48:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x28(%rbp)
  jle    L10
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <divConqSearch>
L10:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <divConqSearch>
L25:
  leave
  ret
```

assistant: ```c
int divConqSearch(int A[], int n, int start, int end, int key) {
  if (start > end)
    return -1;
  int mid = (start + end) / 2;
  if (key == A[mid])
    return mid;
  if (key > A[mid])
    divConqSearch(A, n, mid + 1, end, key);
  divConqSearch(A, n, 0, mid - 1, key);
}
```
user: What is the c source code of the assembly code below:

```asm
<divConqSearch>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    %ecx,%edx
  jg     L10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %r8d,%r13d
  add    %ecx,%edx
  mov    %edx,%ebx
  shr    $0x1f,%ebx
  add    %edx,%ebx
  sar    %ebx
  mov    %ebx,%eax
  movslq %ebx,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %r8d,%edx
  je     L11
  jl     L30
L7:
  lea    -0x1(%rbx),%ecx
  mov    %r13d,%r8d
  mov    $0x0,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <divConqSearch>
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  lea    0x1(%rbx),%edx
  call   <divConqSearch>
  jmp    L7
L10:
  ret
```

assistant: ```c
int divConqSearch(int A[], int n, int start, int end, int key) {
  if (start > end)
    return -1;
  int mid = (start + end) / 2;
  if (key == A[mid])
    return mid;
  if (key > A[mid])
    divConqSearch(A, n, mid + 1, end, key);
  divConqSearch(A, n, 0, mid - 1, key);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movw   $0x0,-0xa(%rbp)
  jmp    L49
L27:
  movw   $0x1,-0xa(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L40:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L8
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  movw   $0x0,-0xa(%rbp)
L8:
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L40
  subl   $0x1,-0x1c(%rbp)
L49:
  cmpw   $0x0,-0xa(%rbp)
  je     L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble_sort(int *vector, int len) {
  short done = 0;
  while (!done) {
    done = 1;
    int i;
    for (i = 0; i < len - 1; i++) {
      if (vector[i] > vector[i + 1]) {
        int tmp = vector[i];
        vector[i] = vector[i + 1];
        vector[i + 1] = tmp;
        done = 0;
      }
    }
    len--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bubble_sort>:
  endbr64
  push   %rbx
  lea    0x4(%rdi),%rbx
  mov    $0x1,%r11d
  mov    $0x0,%r10d
  jmp    L1
L0:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L32
L15:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L0
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  mov    %r10d,%r9d
  jmp    L0
L32:
  test   %r9w,%r9w
  jne    L61
L1:
  mov    %esi,%edx
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L61
  mov    %rdi,%rax
  lea    -0x2(%rdx),%edx
  lea    (%rbx,%rdx,4),%r8
  mov    %r11d,%r9d
  jmp    L15
L61:
  pop    %rbx
  ret
```

assistant: ```c
void bubble_sort(int *vector, int len) {
  short done = 0;
  while (!done) {
    done = 1;
    int i;
    for (i = 0; i < len - 1; i++) {
      if (vector[i] > vector[i + 1]) {
        int tmp = vector[i];
        vector[i] = vector[i + 1];
        vector[i + 1] = tmp;
        done = 0;
      }
    }
    len--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bubble_sort>:
  endbr64
L45:
  xor    %edx,%edx
  mov    $0x1,%r10d
  nopl   0x0(%rax)
L12:
  lea    -0x1(%rsi),%r9d
  cmp    %edx,%r9d
  jle    L49
L40:
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rax
L16:
  mov    (%rax),%ecx
  mov    0x4(%rax),%r8d
  add    $0x1,%edx
  cmp    %r8d,%ecx
  jle    L12
  mov    %r8d,(%rax)
  xor    %r10d,%r10d
  add    $0x4,%rax
  mov    %ecx,(%rax)
  cmp    %edx,%r9d
  jg     L16
  mov    %r9d,%esi
  jmp    L45
  nopl   0x0(%rax)
L49:
  test   %r10w,%r10w
  je     L62
L64:
  ret
  nop
L62:
  lea    -0x2(%rsi),%eax
  cmp    $0x2,%esi
  jle    L64
  mov    %r9d,%esi
  xor    %edx,%edx
  mov    %eax,%r9d
  mov    $0x1,%r10d
  jmp    L40
```

assistant: ```c
void bubble_sort(int *vector, int len) {
  short done = 0;
  while (!done) {
    done = 1;
    int i;
    for (i = 0; i < len - 1; i++) {
      if (vector[i] > vector[i + 1]) {
        int tmp = vector[i];
        vector[i] = vector[i + 1];
        vector[i + 1] = tmp;
        done = 0;
      }
    }
    len--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bubble_sort>:
  endbr64
L35:
  xor    %edx,%edx
  mov    $0x1,%r10d
  nopl   0x0(%rax)
L68:
  lea    -0x1(%rsi),%r9d
  cmp    %edx,%r9d
  jle    L63
L26:
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rcx
L24:
  movq   (%rcx),%xmm0
  add    $0x1,%edx
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%r8d
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%r8d
  jle    L68
  movq   %xmm1,(%rcx)
  xor    %r10d,%r10d
  add    $0x4,%rcx
  cmp    %edx,%r9d
  jg     L24
  mov    %r9d,%esi
  jmp    L35
  nopl   0x0(%rax)
L63:
  test   %r10w,%r10w
  je     L1
L32:
  ret
  nop
L1:
  lea    -0x2(%rsi),%eax
  cmp    $0x2,%esi
  jle    L32
  mov    %r9d,%esi
  xor    %edx,%edx
  mov    %eax,%r9d
  mov    $0x1,%r10d
  jmp    L26
```

assistant: ```c
void bubble_sort(int *vector, int len) {
  short done = 0;
  while (!done) {
    done = 1;
    int i;
    for (i = 0; i < len - 1; i++) {
      if (vector[i] > vector[i + 1]) {
        int tmp = vector[i];
        vector[i] = vector[i + 1];
        vector[i + 1] = tmp;
        done = 0;
      }
    }
    len--;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<memcmp3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4030201,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void memcmp3() {
  char a[] = {1, 2, 3, 4};
  clang_analyzer_eval(memcmp(a, a, 4) == 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<memcmp3>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4030201,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rdi,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memcmp3() {
  char a[] = {1, 2, 3, 4};
  clang_analyzer_eval(memcmp(a, a, 4) == 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memcmp3>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x4030201,0x4(%rsp)
  mov    %rdi,%rsi
  call   <memcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <clang_analyzer_eval@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memcmp3() {
  char a[] = {1, 2, 3, 4};
  clang_analyzer_eval(memcmp(a, a, 4) == 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memcmp3>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x4030201,0x4(%rsp)
  mov    %rdi,%rsi
  call   <memcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <clang_analyzer_eval@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memcmp3() {
  char a[] = {1, 2, 3, 4};
  clang_analyzer_eval(memcmp(a, a, 4) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x20000(%rsp),%r11
L15:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L15
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20018(%rbp)
  nop
L10:
  mov    -0x20018(%rbp),%rax
  mov    $0xffffffff,%edx
  cmp    %rdx,%rax
  cmovg  %rdx,%rax
  mov    %eax,-0x2001c(%rbp)
  cmpl   $0x0,-0x2001c(%rbp)
  jne    L10
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
void crc() {
  int toread;
  long long nleft;
  unsigned char buf[(128 * 1024)];
  nleft = 0;
  while (toread = (nleft < (2147483647 * 2U + 1U)) ? nleft : (2147483647 * 2U + 1U))
    ;
}
```
user: What is the c source code of the assembly code below:

```asm
<crc>:
  endbr64
  ret
```

assistant: ```c
void crc() {
  int toread;
  long long nleft;
  unsigned char buf[(128 * 1024)];
  nleft = 0;
  while (toread = (nleft < (2147483647 * 2U + 1U)) ? nleft : (2147483647 * 2U + 1U))
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crc>:
  endbr64
  ret
```

assistant: ```c
void crc() {
  int toread;
  long long nleft;
  unsigned char buf[(128 * 1024)];
  nleft = 0;
  while (toread = (nleft < (2147483647 * 2U + 1U)) ? nleft : (2147483647 * 2U + 1U))
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<crc>:
  endbr64
  ret
```

assistant: ```c
void crc() {
  int toread;
  long long nleft;
  unsigned char buf[(128 * 1024)];
  nleft = 0;
  while (toread = (nleft < (2147483647 * 2U + 1U)) ? nleft : (2147483647 * 2U + 1U))
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mov_reg32_preg32pimm32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x8b,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  or     $0x80,%al
  or     -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <put8@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void mov_reg32_preg32pimm32(int reg1, int reg2, unsigned int imm32) {
  put8(0x8B);
  put8(0x80 | (reg1 << 3) | reg2);
  put32(imm32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mov_reg32_preg32pimm32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    $0x8b,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %r12d,%edi
  or     $0x80,%dil
  call   <put8@plt>
  mov    %ebp,%edi
  call   <put32@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mov_reg32_preg32pimm32(int reg1, int reg2, unsigned int imm32) {
  put8(0x8B);
  put8(0x80 | (reg1 << 3) | reg2);
  put32(imm32);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mov_reg32_preg32pimm32>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8b,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %r12d,%edi
  or     $0x80,%dil
  call   <put8@plt>
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <put32@plt>
```

assistant: ```c
void mov_reg32_preg32pimm32(int reg1, int reg2, unsigned int imm32) {
  put8(0x8B);
  put8(0x80 | (reg1 << 3) | reg2);
  put32(imm32);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mov_reg32_preg32pimm32>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8b,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %r12d,%edi
  or     $0x80,%dil
  call   <put8@plt>
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <put32@plt>
```

assistant: ```c
void mov_reg32_preg32pimm32(int reg1, int reg2, unsigned int imm32) {
  put8(0x8B);
  put8(0x80 | (reg1 << 3) | reg2);
  put32(imm32);
}
```
user: What is the c source code of the assembly code below?

```asm
<speaker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D34(%rip),%eax
  test   %eax,%eax
  jne    L0
  movl   $0x1,D34(%rip)
  mov    $0x3,%edi
  call   <iopl@plt>
L0:
  mov    $0x43,%esi
  mov    $0xb6,%edi
  call   <outb@plt>
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    $0x42,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    $0x42,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    $0x61,%edi
  call   <inb@plt>
  mov    %eax,D37(%rip)
  mov    D37(%rip),%eax
  or     $0x3,%eax
  mov    $0x61,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    -0x8(%rbp),%eax
  imul   $0x2710,%eax,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  mov    D37(%rip),%eax
  or     $0xfc,%al
  mov    $0x61,%esi
  mov    %eax,%edi
  call   <outb@plt>
  nop
  leave
  ret
```

assistant: ```c
int speaker(unsigned int freq, unsigned int delay) {
  static int flag = 0;
  static int bit;
  if (flag == 0) {
    flag = 1;
    iopl(3);
  }
  outb(0xb6, 0x43);
  outb((freq & 0xff), 0x42);
  outb((freq >> 8), 0x42);
  bit = inb(0x61);
  outb(3 | bit, 0x61);
  usleep(10000 * delay);
  outb(0xfc | bit, 0x61);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<speaker>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmpl   $0x0,D10(%rip)
  je     L9
L18:
  mov    $0x43,%esi
  mov    $0xb6,%edi
  call   <outb@plt>
  movzbl %bl,%edi
  mov    $0x42,%esi
  call   <outb@plt>
  shr    $0x8,%ebx
  mov    %ebx,%edi
  mov    $0x42,%esi
  call   <outb@plt>
  mov    $0x61,%edi
  call   <inb@plt>
  mov    %eax,D36(%rip)
  or     $0x3,%eax
  mov    %eax,%edi
  mov    $0x61,%esi
  call   <outb@plt>
  imul   $0x2710,%ebp,%edi
  call   <usleep@plt>
  mov    D36(%rip),%edi
  or     $0xfc,%dil
  mov    $0x61,%esi
  call   <outb@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  movl   $0x1,D10(%rip)
  mov    $0x3,%edi
  call   <iopl@plt>
  jmp    L18
```

assistant: ```c
int speaker(unsigned int freq, unsigned int delay) {
  static int flag = 0;
  static int bit;
  if (flag == 0) {
    flag = 1;
    iopl(3);
  }
  outb(0xb6, 0x43);
  outb((freq & 0xff), 0x42);
  outb((freq >> 8), 0x42);
  bit = inb(0x61);
  outb(3 | bit, 0x61);
  usleep(10000 * delay);
  outb(0xfc | bit, 0x61);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<speaker>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  mov    D16(%rip),%eax
  test   %eax,%eax
  je     L9
L16:
  mov    $0x43,%esi
  mov    $0xb6,%edi
  call   <outb@plt>
  movzbl %bl,%edi
  mov    $0x42,%esi
  shr    $0x8,%ebx
  call   <outb@plt>
  mov    %ebx,%edi
  mov    $0x42,%esi
  call   <outb@plt>
  mov    $0x61,%edi
  call   <inb@plt>
  mov    $0x61,%esi
  mov    %eax,D5(%rip)
  or     $0x3,%eax
  mov    %eax,%edi
  call   <outb@plt>
  imul   $0x2710,%ebp,%edi
  call   <usleep@plt>
  mov    D5(%rip),%edi
  add    $0x8,%rsp
  mov    $0x61,%esi
  pop    %rbx
  pop    %rbp
  or     $0xfc,%dil
  jmp    1090 <outb@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  movl   $0x1,D16(%rip)
  mov    $0x3,%edi
  call   <iopl@plt>
  jmp    L16
```

assistant: ```c
int speaker(unsigned int freq, unsigned int delay) {
  static int flag = 0;
  static int bit;
  if (flag == 0) {
    flag = 1;
    iopl(3);
  }
  outb(0xb6, 0x43);
  outb((freq & 0xff), 0x42);
  outb((freq >> 8), 0x42);
  bit = inb(0x61);
  outb(3 | bit, 0x61);
  usleep(10000 * delay);
  outb(0xfc | bit, 0x61);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<speaker>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  mov    D11(%rip),%eax
  test   %eax,%eax
  je     L0
L15:
  mov    $0x43,%esi
  mov    $0xb6,%edi
  call   <outb@plt>
  movzbl %bl,%edi
  mov    $0x42,%esi
  shr    $0x8,%ebx
  call   <outb@plt>
  mov    %ebx,%edi
  mov    $0x42,%esi
  call   <outb@plt>
  mov    $0x61,%edi
  call   <inb@plt>
  mov    $0x61,%esi
  mov    %eax,D35(%rip)
  or     $0x3,%eax
  mov    %eax,%edi
  call   <outb@plt>
  imul   $0x2710,%ebp,%edi
  call   <usleep@plt>
  mov    D35(%rip),%edi
  add    $0x8,%rsp
  mov    $0x61,%esi
  pop    %rbx
  pop    %rbp
  or     $0xfc,%dil
  jmp    1090 <outb@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  movl   $0x1,D11(%rip)
  mov    $0x3,%edi
  call   <iopl@plt>
  jmp    L15
```

assistant: ```c
int speaker(unsigned int freq, unsigned int delay) {
  static int flag = 0;
  static int bit;
  if (flag == 0) {
    flag = 1;
    iopl(3);
  }
  outb(0xb6, 0x43);
  outb((freq & 0xff), 0x42);
  outb((freq >> 8), 0x42);
  bit = inb(0x61);
  outb(3 | bit, 0x61);
  usleep(10000 * delay);
  outb(0xfc | bit, 0x61);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L15
L31:
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm0
  comiss D39(%rip),%xmm0
  ja     L21
  mov    -0x24(%rbp),%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L27
L21:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  pxor   %xmm3,%xmm3
  cvtsi2ss %eax,%xmm3
  movd   %xmm3,%eax
  movd   %eax,%xmm0
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L34
L27:
  mov    -0x24(%rbp),%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm0
  movss  -0x28(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x28(%rbp)
L34:
  addl   $0x1,-0x24(%rbp)
L15:
  cmpl   $0x4,-0x24(%rbp)
  jle    L31
  movss  -0x28(%rbp),%xmm0
  movss  D15(%rip),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movss  -0x28(%rbp),%xmm0
  movss  D15(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movapd %xmm2,%xmm1
  movd   %eax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D39
type_infered: byte[4]
name: unpack_data
arguments: data_label: D52
type_infered: string
name: unpack_data
arguments: data_label: D15
type_infered: byte[4]
name: unpack_data
arguments: data_label: D12
type_infered: string

tool: D3: %f

tool: {"D39": [0x00,0x00,0xc8,0x42]}

tool: D52: Invalid Input


tool: {"D15": [0x00,0x00,0xa0,0x40]}

tool: D12: Aggregate: %f
Percentage: %f %


assistant: ```c
int main() {
  float marks[5], sum = 0;
  for (int i = 0; i < 5; i++) {
    scanf("%f", &marks[i]);
    if (marks[i] > 100 || marks[i] < 0)
      printf("Invalid Input\n", i--);
    else
      sum += marks[i];
  }
  printf("Aggregate: %f\nPercentage: %f \%\n", sum / 5, (sum / 5));
}
```