user: 请从给定的汇编指令推导出C源代码：

```asm
<test_lex_look_ahead_3>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D40(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%r12
  mov    $0x0,%r8d
  lea    D67(%rip),%r14
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x4(%rsp),%r8d
  lea    0x3(%r8),%eax
  mov    %eax,0x4(%rsp)
  add    $0x4,%r8d
  lea    D10(%rip),%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%r8d
  mov    %r8d,0x4(%rsp)
  lea    D69(%rip),%r13
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%r8d
  mov    %r8d,0x4(%rsp)
  lea    D62(%rip),%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%r8d
  mov    %r8d,0x4(%rsp)
  lea    D41(%rip),%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x4(%rsp),%r8d
  lea    0x1(%r8),%eax
  mov    %eax,0x4(%rsp)
  add    $0x2,%r8d
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x4(%rsp),%r8d
  lea    0x3(%r8),%eax
  mov    %eax,0x4(%rsp)
  add    $0x4,%r8d
  lea    D20(%rip),%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%r8d
  mov    %r8d,0x4(%rsp)
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%r8d
  mov    %r8d,0x4(%rsp)
  lea    D32(%rip),%rcx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <check_token@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D40
type_guessed: string
name: retrieve_data
arguments: data_label: D67
type_guessed: string
name: retrieve_data
arguments: data_label: D10
type_guessed: string
name: retrieve_data
arguments: data_label: D69
type_guessed: string
name: retrieve_data
arguments: data_label: D62
type_guessed: string
name: retrieve_data
arguments: data_label: D41
type_guessed: string
name: retrieve_data
arguments: data_label: D20
type_guessed: string
name: retrieve_data
arguments: data_label: D32
type_guessed: string

tool: D40: int a=2; int b=17;

tool: D67: int

tool: D10: a

tool: D69: =

tool: D62: 2

tool: D41: ;

tool: D20: b

tool: D32: 17

assistant: ```c
void test_lex_look_ahead_3() {
  const char *input = "int a=2; int b=17;";
  unsigned int len, pos;
  len = strlen(input);
  pos = 0;
  check_token(input, len, &pos, "int", 0);
  pos += 3;
  check_token(input, len, &pos, "a", pos + 1);
  pos += 1;
  check_token(input, len, &pos, "=", pos);
  pos += 1;
  check_token(input, len, &pos, "2", pos);
  pos += 1;
  check_token(input, len, &pos, ";", pos);
  pos += 1;
  check_token(input, len, &pos, "int", pos + 1);
  pos += 3;
  check_token(input, len, &pos, "b", pos + 1);
  pos += 1;
  check_token(input, len, &pos, "=", pos);
  pos += 1;
  check_token(input, len, &pos, "17", pos);
}
```