ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L3
  lea    D8(%rip),%rdi
  call   <puts@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D35
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string
name: retrieve_data
arguments: label: D8
type_guessed: string
name: retrieve_data
arguments: label: D15
type_guessed: string

tool: D35: Your age: 

tool: D10: %d

tool: D8: Invalid input

tool: D15: You will be %d years old next year


assistant: ```c
int main() {
  int age, r;
  printf("Your age: ");
  r = scanf("%d", &age);
  if (r == 0)
    puts("Invalid input");
  else
    printf("You will be %d years old next year\n", age + 1);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D35(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L24
  lea    D16(%rip),%rdi
  call   <puts@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L24:
  mov    0x4(%rsp),%eax
  lea    D38(%rip),%rdi
  lea    0x1(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
data_type: string
name: extract_symbolic_data
arguments: label: D25
data_type: string
name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D38
data_type: string

tool: D35: Your age: 

tool: D25: %d

tool: D16: Invalid input

tool: D38: You will be %d years old next year


assistant: ```c
int main() {
  int age, r;
  printf("Your age: ");
  r = scanf("%d", &age);
  if (r == 0)
    puts("Invalid input");
  else
    printf("You will be %d years old next year\n", age + 1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L23
  lea    D9(%rip),%rdi
  call   <puts@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  mov    0x4(%rsp),%eax
  lea    D29(%rip),%rdi
  lea    0x1(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L27
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D35
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D29
type_infered: string

tool: D18: Your age: 

tool: D35: %d

tool: D9: Invalid input

tool: D29: You will be %d years old next year


assistant: ```c
int main() {
  int age, r;
  printf("Your age: ");
  r = scanf("%d", &age);
  if (r == 0)
    puts("Invalid input");
  else
    printf("You will be %d years old next year\n", age + 1);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<examine_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L42
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L86
L42:
  mov    -0x38(%rbp),%rax
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L6
L4:
  addl   $0x1,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0xff,-0x24(%rbp)
  jbe    L62
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L86
L62:
  lea    D30(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x20(%rbp)
L6:
  cmpq   $0x0,-0x20(%rbp)
  jne    L4
  cmpl   $0x4,-0x28(%rbp)
  je     L32
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L86
L32:
  mov    $0x1,%eax
L86:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D30
data_type: string
name: extract_symbolic_data
arguments: label: D48
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: string

tool: D1: alamat yang di masukkan salah, mohon jangan ada spasi


tool: D30: .

tool: D48: alamat ip tidak ada yang lebih dari 255


tool: D20: alamat tidak valid


assistant: ```c
int examine_addr(char *addr) {
  char *ex;
  char sec_addr[3];
  char *token;
  unsigned int tes;
  int chk_ip = 0;
  ex = strchr(addr, ' ');
  if (ex != NULL) {
    printf("alamat yang di masukkan salah, mohon jangan ada spasi\n");
    return 0;
  }
  token = strtok(addr, ".");
  while (token != NULL) {
    chk_ip++;
    tes = atoi(token);
    if (tes > 255) {
      printf("alamat ip tidak ada yang lebih dari 255\n");
      return 0;
    }
    token = strtok(NULL, ".");
  }
  if (chk_ip != 4) {
    printf("alamat tidak valid\n");
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<examine_addr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x20,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L58
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L58:
  lea    D44(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L4
  mov    $0x0,%ebx
  lea    D44(%rip),%rbp
L42:
  add    $0x1,%ebx
  call   <atoi@plt>
  cmp    $0xff,%eax
  ja     L25
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L42
  mov    $0x1,%eax
  cmp    $0x4,%ebx
  je     L21
L4:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L21
L25:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type_guessed: string
name: retrieve_data
arguments: data_tag: D44
type_guessed: string
name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D37
type_guessed: string

tool: D22: alamat yang di masukkan salah, mohon jangan ada spasi


tool: D44: .

tool: D8: alamat tidak valid


tool: D37: alamat ip tidak ada yang lebih dari 255


assistant: ```c
int examine_addr(char *addr) {
  char *ex;
  char sec_addr[3];
  char *token;
  unsigned int tes;
  int chk_ip = 0;
  ex = strchr(addr, ' ');
  if (ex != NULL) {
    printf("alamat yang di masukkan salah, mohon jangan ada spasi\n");
    return 0;
  }
  token = strtok(addr, ".");
  while (token != NULL) {
    chk_ip++;
    tes = atoi(token);
    if (tes > 255) {
      printf("alamat ip tidak ada yang lebih dari 255\n");
      return 0;
    }
    token = strtok(NULL, ".");
  }
  if (chk_ip != 4) {
    printf("alamat tidak valid\n");
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<examine_addr>:
  endbr64
  push   %r12
  mov    $0x20,%esi
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L0
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L68:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L0:
  lea    D10(%rip),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L66
  xor    %ebx,%ebx
  jmp    L67
  xchg   %ax,%ax
L4:
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L52
L67:
  add    $0x1,%ebx
  call   <atoi@plt>
  cmp    $0xff,%eax
  jbe    L4
  lea    D15(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L52:
  cmp    $0x4,%ebx
  jne    L66
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L68
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D10
type_guessed: string
name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string

tool: D3: alamat yang di masukkan salah, mohon jangan ada spasi


tool: D10: .

tool: D15: alamat ip tidak ada yang lebih dari 255


tool: D21: alamat tidak valid


assistant: ```c
int examine_addr(char *addr) {
  char *ex;
  char sec_addr[3];
  char *token;
  unsigned int tes;
  int chk_ip = 0;
  ex = strchr(addr, ' ');
  if (ex != NULL) {
    printf("alamat yang di masukkan salah, mohon jangan ada spasi\n");
    return 0;
  }
  token = strtok(addr, ".");
  while (token != NULL) {
    chk_ip++;
    tes = atoi(token);
    if (tes > 255) {
      printf("alamat ip tidak ada yang lebih dari 255\n");
      return 0;
    }
    token = strtok(NULL, ".");
  }
  if (chk_ip != 4) {
    printf("alamat tidak valid\n");
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<examine_addr>:
  endbr64
  push   %r12
  mov    $0x20,%esi
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L51
  lea    D30(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L51:
  lea    D35(%rip),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L48
  xor    %ebx,%ebx
  jmp    L41
  xchg   %ax,%ax
L45:
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L32
L41:
  add    $0x1,%ebx
  call   <atoi@plt>
  cmp    $0xff,%eax
  jbe    L45
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  cmp    $0x4,%ebx
  jne    L48
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L12
```

tool_calls: name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D35
type: string
name: read_data
arguments: data_tag: D5
type: string
name: read_data
arguments: data_tag: D32
type: string

tool: D30: alamat yang di masukkan salah, mohon jangan ada spasi


tool: D35: .

tool: D5: alamat ip tidak ada yang lebih dari 255


tool: D32: alamat tidak valid


assistant: ```c
int examine_addr(char *addr) {
  char *ex;
  char sec_addr[3];
  char *token;
  unsigned int tes;
  int chk_ip = 0;
  ex = strchr(addr, ' ');
  if (ex != NULL) {
    printf("alamat yang di masukkan salah, mohon jangan ada spasi\n");
    return 0;
  }
  token = strtok(addr, ".");
  while (token != NULL) {
    chk_ip++;
    tes = atoi(token);
    if (tes > 255) {
      printf("alamat ip tidak ada yang lebih dari 255\n");
      return 0;
    }
    token = strtok(NULL, ".");
  }
  if (chk_ip != 4) {
    printf("alamat tidak valid\n");
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<g1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  mov    $0x0,%edi
  call   <foo@plt>
L0:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int g1(int x) {
  if (!--x)
    foo((void *)0);
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g1>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x1,%ebx
  je     L16
L5:
  mov    %ebx,%eax
  pop    %rbx
  ret
L16:
  mov    $0x0,%edi
  call   <foo@plt>
  jmp    L5
```

assistant: ```c
int g1(int x) {
  if (!--x)
    foo((void *)0);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<g1>:
  endbr64
  sub    $0x1,%edi
  push   %r12
  mov    %edi,%r12d
  je     L3
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  xor    %edi,%edi
  call   <foo@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int g1(int x) {
  if (!--x)
    foo((void *)0);
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<g1>:
  endbr64
  sub    $0x1,%edi
  push   %r12
  mov    %edi,%r12d
  je     L7
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  xor    %edi,%edi
  call   <foo@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int g1(int x) {
  if (!--x)
    foo((void *)0);
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x5(%rbp)
  mov    D3(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L57
  mov    $0xffffffff,%eax
  jmp    L36
L57:
  cmpb   $0xa,-0x5(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L36
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L14
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L14
L36:
  leave
  ret
```

assistant: ```c
int read_line(FILE *fp, char *line, int max_length) {
  int i;
  char ch;
  i = 0;
  for (;;) {
    ch = fgetc(fp);
    if (ch == EOF)
      return -1;
    if (ch == '\n') {
      line[i] = '\0';
      return 0;
    }
    if (i < max_length)
      line[i++] = ch;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %edx,%r12d
  mov    $0x0,%ebp
L17:
  mov    %ebp,%r14d
L7:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    D7(%rip),%rdx
  cmp    %al,(%rdx)
  je     L24
  cmp    $0xa,%al
  je     L32
  cmp    %ebp,%r12d
  jle    L7
  mov    %al,0x0(%r13,%rbp,1)
  add    $0x1,%rbp
  jmp    L17
L32:
  movslq %r14d,%r14
  movb   $0x0,0x0(%r13,%r14,1)
  mov    $0x0,%eax
  jmp    L43
L24:
  mov    $0xffffffff,%eax
L43:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int read_line(FILE *fp, char *line, int max_length) {
  int i;
  char ch;
  i = 0;
  for (;;) {
    ch = fgetc(fp);
    if (ch == EOF)
      return -1;
    if (ch == '\n') {
      line[i] = '\0';
      return 0;
    }
    if (i < max_length)
      line[i++] = ch;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_line>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%r13
L1:
  movslq %ebp,%r15
  jmp    L16
  nopl   0x0(%rax)
L10:
  cmp    $0xa,%al
  je     L19
  cmp    %ebp,%r12d
  jg     L45
L16:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    %al,0x0(%r13)
  jne    L10
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  movb   $0x0,(%r14,%r15,1)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    %al,(%r14,%rbp,1)
  add    $0x1,%rbp
  jmp    L1
```

assistant: ```c
int read_line(FILE *fp, char *line, int max_length) {
  int i;
  char ch;
  i = 0;
  for (;;) {
    ch = fgetc(fp);
    if (ch == EOF)
      return -1;
    if (ch == '\n') {
      line[i] = '\0';
      return 0;
    }
    if (i < max_length)
      line[i++] = ch;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_line>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbp
L14:
  movslq %r14d,%r13
  cmp    %r14d,%r15d
  jle    L43
  jmp    L56
  nop
L6:
  cmp    $0xa,%al
  je     L63
L43:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    0x0(%rbp),%al
  jne    L6
L15:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    %al,0x0(%rbp)
  je     L15
  cmp    $0xa,%al
  je     L63
  mov    %al,(%r12,%r14,1)
  add    $0x1,%r14
  jmp    L14
L63:
  movb   $0x0,(%r12,%r13,1)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int read_line(FILE *fp, char *line, int max_length) {
  int i;
  char ch;
  i = 0;
  for (;;) {
    ch = fgetc(fp);
    if (ch == EOF)
      return -1;
    if (ch == '\n') {
      line[i] = '\0';
      return 0;
    }
    if (i < max_length)
      line[i++] = ch;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L13
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L13:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L16
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L16:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L8
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D9: %d%d%d

tool: D1: %d %d %d


assistant: ```c
int main(void) {
  int a, b, c, t;
  scanf("%d%d%d", &a, &b, &c);
  if (a > b) {
    t = a;
    a = b;
    b = t;
  }
  if (a > c) {
    t = a;
    a = c;
    c = t;
  }
  if (b > c) {
    t = b;
    b = c;
    c = t;
  }
  printf("%d %d %d\n", a, b, c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  cmp    %edx,%eax
  jle    L19
  mov    %edx,0xc(%rsp)
  mov    %eax,0x10(%rsp)
L19:
  mov    0xc(%rsp),%eax
  mov    0x14(%rsp),%edx
  cmp    %edx,%eax
  jle    L13
  mov    %edx,0xc(%rsp)
  mov    %eax,0x14(%rsp)
L13:
  mov    0x10(%rsp),%eax
  mov    0x14(%rsp),%edx
  cmp    %edx,%eax
  jle    L17
  mov    %edx,0x10(%rsp)
  mov    %eax,0x14(%rsp)
L17:
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_guessed: string
name: disassemble_data
arguments: data_label: D15
type_guessed: string

tool: D19: %d%d%d

tool: D15: %d %d %d


assistant: ```c
int main(void) {
  int a, b, c, t;
  scanf("%d%d%d", &a, &b, &c);
  if (a > b) {
    t = a;
    a = b;
    b = t;
  }
  if (a > c) {
    t = a;
    a = c;
    c = t;
  }
  if (b > c) {
    t = b;
    b = c;
    c = t;
  }
  printf("%d %d %d\n", a, b, c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%edx
  cmp    %edx,%esi
  jle    L39
  mov    %esi,%eax
  mov    %edx,0xc(%rsp)
  mov    %esi,0x10(%rsp)
  mov    %edx,%esi
  mov    %eax,%edx
L39:
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%esi
  jle    L38
  mov    %esi,%eax
  mov    %ecx,0xc(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %ecx,%esi
  mov    %eax,%ecx
L38:
  cmp    %ecx,%edx
  jle    L20
  mov    %edx,%eax
  mov    %ecx,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  mov    %ecx,%edx
  mov    %eax,%ecx
L20:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D1: %d%d%d

tool: D6: %d %d %d


assistant: ```c
int main(void) {
  int a, b, c, t;
  scanf("%d%d%d", &a, &b, &c);
  if (a > b) {
    t = a;
    a = b;
    b = t;
  }
  if (a > c) {
    t = a;
    a = c;
    c = t;
  }
  if (b > c) {
    t = b;
    b = c;
    c = t;
  }
  printf("%d %d %d\n", a, b, c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%edx
  cmp    %edx,%esi
  jle    L18
  mov    %esi,%eax
  mov    %edx,0xc(%rsp)
  mov    %esi,0x10(%rsp)
  mov    %edx,%esi
  mov    %eax,%edx
L18:
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%esi
  jle    L22
  mov    %esi,%eax
  mov    %ecx,0xc(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %ecx,%esi
  mov    %eax,%ecx
L22:
  cmp    %ecx,%edx
  jle    L34
  mov    %edx,%eax
  mov    %ecx,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  mov    %ecx,%edx
  mov    %eax,%ecx
L34:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D6
datatype: string

tool: D0: %d%d%d

tool: D6: %d %d %d


assistant: ```c
int main(void) {
  int a, b, c, t;
  scanf("%d%d%d", &a, &b, &c);
  if (a > b) {
    t = a;
    a = b;
    b = t;
  }
  if (a > c) {
    t = a;
    a = c;
    c = t;
  }
  if (b > c) {
    t = b;
    b = c;
    c = t;
  }
  printf("%d %d %d\n", a, b, c);
  return 0;
}
```