ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<fmt_convert_s8_to_double>:
  endbr64
  test   %edx,%edx
  jle    L12
  mov    %edx,%edx
  mov    $0x0,%eax
  movsd  D6(%rip),%xmm1
L15:
  movapd %xmm1,%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L15
L12:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f]}

assistant: ```c
void fmt_convert_s8_to_double(void *dest_v, void *src_v, int n) {
  double *dest = dest_v;
  int8_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = src[i] / 128.0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fmt_convert_s8_to_double>:
  endbr64
  test   %edx,%edx
  jle    L18
  movsd  D4(%rip),%xmm1
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L6:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L6
L18:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f]}

assistant: ```c
void fmt_convert_s8_to_double(void *dest_v, void *src_v, int n) {
  double *dest = dest_v;
  int8_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = src[i] / 128.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fmt_convert_s8_to_double>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L43
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L45
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L45
  mov    %edx,%edi
  movapd D13(%rip),%xmm1
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L2:
  movupd (%rsi,%rax,1),%xmm0
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L2
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L43
  movsd  D13(%rip),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  movsd  D13(%rip),%xmm1
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L9:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L9
L43:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_infered: byte[16]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f]}

assistant: ```c
void fmt_convert_s8_to_double(void *dest_v, void *src_v, int n) {
  double *dest = dest_v;
  int8_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = src[i] / 128.0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<progname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
L7:
  lea    D5(%rip),%rax
  mov    %rax,-0x18(%rbp)
L22:
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L37
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L37
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L30
L37:
  mov    -0x18(%rbp),%rax
L30:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/LuaDist2/cqueues/refs/heads/master/util/tcp-urgent.c

assistant: ```c
const char *progname(const char *progname) {
  const char *basename;
  if (!progname || !*progname)
    progname = "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/LuaDist2/cqueues/refs/heads/master/util/tcp-urgent.c";
  if ((basename = strrchr(progname, '/')) && basename[1])
    return &basename[1];
  return progname;
}
```
user: What is the c source code of the assembly code below?

```asm
<progname>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  test   %rdi,%rdi
  je     L8
  cmpb   $0x0,(%rdi)
  cmovne %rdi,%rbx
L8:
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L17
  cmpb   $0x0,0x1(%rax)
  jne    L28
L17:
  mov    %rbx,%rax
  pop    %rbx
  ret
L28:
  lea    0x1(%rax),%rbx
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/LuaDist2/cqueues/refs/heads/master/util/tcp-urgent.c

assistant: ```c
const char *progname(const char *progname) {
  const char *basename;
  if (!progname || !*progname)
    progname = "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/LuaDist2/cqueues/refs/heads/master/util/tcp-urgent.c";
  if ((basename = strrchr(progname, '/')) && basename[1])
    return &basename[1];
  return progname;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<progname>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  test   %rdi,%rdi
  je     L14
  cmpb   $0x0,(%rdi)
  cmovne %rdi,%r12
L14:
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  cmpb   $0x0,0x1(%rax)
  jne    L6
L4:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    0x1(%rax),%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/LuaDist2/cqueues/refs/heads/master/util/tcp-urgent.c

assistant: ```c
const char *progname(const char *progname) {
  const char *basename;
  if (!progname || !*progname)
    progname = "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/LuaDist2/cqueues/refs/heads/master/util/tcp-urgent.c";
  if ((basename = strrchr(progname, '/')) && basename[1])
    return &basename[1];
  return progname;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<progname>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  test   %rdi,%rdi
  je     L20
  cmpb   $0x0,(%rdi)
  cmovne %rdi,%r12
L20:
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L8
  cmpb   $0x0,0x1(%rax)
  jne    L6
L8:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    0x1(%rax),%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/LuaDist2/cqueues/refs/heads/master/util/tcp-urgent.c

assistant: ```c
const char *progname(const char *progname) {
  const char *basename;
  if (!progname || !*progname)
    progname = "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/LuaDist2/cqueues/refs/heads/master/util/tcp-urgent.c";
  if ((basename = strrchr(progname, '/')) && basename[1])
    return &basename[1];
  return progname;
}
```
user: Translate the below assembly code into C programming language:

```asm
<byteReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  (void)buf;
  (void)longs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<byteReverse>:
  endbr64
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  (void)buf;
  (void)longs;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<byteReverse>:
  endbr64
  ret
```

assistant: ```c
void byteReverse(unsigned char *buf, unsigned longs) {
  (void)buf;
  (void)longs;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  je     L4
  mov    $0xffffffff,%eax
  jmp    L12
L4:
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int readByte(FILE *fp, unsigned char *result) {
  if (fread(result, 1, 1, fp) != 1)
    return (-1);
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<readByte>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int readByte(FILE *fp, unsigned char *result) {
  if (fread(result, 1, 1, fp) != 1)
    return (-1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readByte>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    %rsi,%rdi
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    $0x1,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int readByte(FILE *fp, unsigned char *result) {
  if (fread(result, 1, 1, fp) != 1)
    return (-1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pre_ft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pre_syn@plt>
  mov    $0x49,%edi
  call   <font_push@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int pre_ft(const struct roff_meta *meta, struct roff_node *n) {
  pre_syn(n);
  font_push('I');
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pre_ft>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <pre_syn@plt>
  mov    $0x49,%edi
  call   <font_push@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pre_ft(const struct roff_meta *meta, struct roff_node *n) {
  pre_syn(n);
  font_push('I');
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pre_ft>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <pre_syn@plt>
  mov    $0x49,%edi
  call   <font_push@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pre_ft(const struct roff_meta *meta, struct roff_node *n) {
  pre_syn(n);
  font_push('I');
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pre_ft>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <pre_syn@plt>
  mov    $0x49,%edi
  call   <font_push@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pre_ft(const struct roff_meta *meta, struct roff_node *n) {
  pre_syn(n);
  font_push('I');
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L19:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x34(%rbp),%eax
  sub    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jb     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(void *out, void const *in, unsigned size) {
  unsigned char *a;
  unsigned char const *b;
  unsigned i;
  a = out;
  b = in;
  for (i = 0; i < size; ++i)
    a[size - i - 1] = b[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap>:
  endbr64
  test   %edx,%edx
  je     L1
  mov    %edx,%r8d
  add    %rsi,%r8
  mov    %rsi,%rax
  lea    -0x1(%rdx,%rsi,1),%esi
L13:
  movzbl (%rax),%ecx
  mov    %esi,%edx
  sub    %eax,%edx
  mov    %cl,(%rdi,%rdx,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L13
L1:
  ret
```

assistant: ```c
void swap(void *out, void const *in, unsigned size) {
  unsigned char *a;
  unsigned char const *b;
  unsigned i;
  a = out;
  b = in;
  for (i = 0; i < size; ++i)
    a[size - i - 1] = b[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  test   %edx,%edx
  je     L11
  mov    %edx,%ecx
  lea    -0x1(%rdx,%rsi,1),%r8d
  add    %rsi,%rcx
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl (%rsi),%edx
  mov    %r8d,%eax
  sub    %esi,%eax
  add    $0x1,%rsi
  mov    %dl,(%rdi,%rax,1)
  cmp    %rcx,%rsi
  jne    L7
L11:
  ret
```

assistant: ```c
void swap(void *out, void const *in, unsigned size) {
  unsigned char *a;
  unsigned char const *b;
  unsigned i;
  a = out;
  b = in;
  for (i = 0; i < size; ++i)
    a[size - i - 1] = b[i];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap>:
  endbr64
  test   %edx,%edx
  je     L12
  mov    %edx,%ecx
  lea    -0x1(%rdx,%rsi,1),%r8d
  add    %rsi,%rcx
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl (%rsi),%edx
  mov    %r8d,%eax
  sub    %esi,%eax
  add    $0x1,%rsi
  mov    %dl,(%rdi,%rax,1)
  cmp    %rcx,%rsi
  jne    L14
L12:
  ret
```

assistant: ```c
void swap(void *out, void const *in, unsigned size) {
  unsigned char *a;
  unsigned char const *b;
  unsigned i;
  a = out;
  b = in;
  for (i = 0; i < size; ++i)
    a[size - i - 1] = b[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitmask_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L33
L19:
  shll   -0x8(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  je     L19
  mov    -0x18(%rbp),%eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  je     L27
  mov    -0x4(%rbp),%eax
  or     %eax,-0xc(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  not    %eax
  and    %eax,-0x14(%rbp)
  shll   -0x4(%rbp)
L33:
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L8
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned bitmask_get(unsigned mask, unsigned value) {
  unsigned res, inmask, outmask;
  res = 0;
  inmask = outmask = 1;
  while ((value & mask) != 0) {
    while ((mask & inmask) == 0)
      inmask = inmask << 1;
    if ((value & inmask) != 0)
      res |= outmask;
    mask &= (~inmask);
    outmask = outmask << 1;
  }
  return (res);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitmask_get>:
  endbr64
  mov    %edi,%edx
  and    %esi,%edx
  je     L12
  mov    $0x1,%ecx
  mov    $0x1,%eax
  mov    $0x0,%edx
  jmp    L23
L16:
  add    %eax,%eax
  test   %edi,%eax
  je     L16
L19:
  mov    %edx,%r8d
  or     %ecx,%r8d
  test   %eax,%esi
  cmovne %r8d,%edx
  mov    %eax,%r8d
  not    %r8d
  and    %r8d,%edi
  add    %ecx,%ecx
  test   %edi,%esi
  je     L12
L23:
  test   %eax,%edi
  je     L16
  jmp    L19
L12:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned bitmask_get(unsigned mask, unsigned value) {
  unsigned res, inmask, outmask;
  res = 0;
  inmask = outmask = 1;
  while ((value & mask) != 0) {
    while ((mask & inmask) == 0)
      inmask = inmask << 1;
    if ((value & inmask) != 0)
      res |= outmask;
    mask &= (~inmask);
    outmask = outmask << 1;
  }
  return (res);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bitmask_get>:
  endbr64
  mov    %edi,%r8d
  and    %esi,%r8d
  je     L2
  mov    $0x1,%edx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L20:
  add    %eax,%eax
L17:
  test   %edi,%eax
  je     L20
  mov    %r8d,%ecx
  or     %edx,%ecx
  test   %eax,%esi
  cmovne %ecx,%r8d
  mov    %eax,%ecx
  add    %edx,%edx
  not    %ecx
  and    %ecx,%edi
  test   %edi,%esi
  jne    L17
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned bitmask_get(unsigned mask, unsigned value) {
  unsigned res, inmask, outmask;
  res = 0;
  inmask = outmask = 1;
  while ((value & mask) != 0) {
    while ((mask & inmask) == 0)
      inmask = inmask << 1;
    if ((value & inmask) != 0)
      res |= outmask;
    mask &= (~inmask);
    outmask = outmask << 1;
  }
  return (res);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitmask_get>:
  endbr64
  mov    %edi,%r8d
  and    %esi,%r8d
  je     L1
  mov    $0x1,%edx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L23:
  add    %eax,%eax
L3:
  test   %edi,%eax
  je     L23
  mov    %r8d,%ecx
  or     %edx,%ecx
  test   %eax,%esi
  cmovne %ecx,%r8d
  mov    %eax,%ecx
  add    %edx,%edx
  not    %ecx
  and    %ecx,%edi
  test   %edi,%esi
  jne    L3
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned bitmask_get(unsigned mask, unsigned value) {
  unsigned res, inmask, outmask;
  res = 0;
  inmask = outmask = 1;
  while ((value & mask) != 0) {
    while ((mask & inmask) == 0)
      inmask = inmask << 1;
    if ((value & inmask) != 0)
      res |= outmask;
    mask &= (~inmask);
    outmask = outmask << 1;
  }
  return (res);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matrix_mul_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L31
L19:
  movl   $0x0,-0x8(%rbp)
  jmp    L47
L34:
  movw   $0x0,-0xe(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L58
L13:
  mov    -0xc(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  imul   %eax,%ecx
  mov    %ecx,%edx
  movzwl -0xe(%rbp),%eax
  add    %edx,%eax
  mov    %ax,-0xe(%rbp)
  addl   $0x1,-0x4(%rbp)
L58:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L13
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzwl -0xe(%rbp),%eax
  mov    %ax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jb     L34
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jb     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrix_mul_short(const short *a, const short *b, short *c, const unsigned int dimX1Y2, const unsigned int dimY1, const unsigned int dimX2) {
  for (unsigned int y = 0; y < dimY1; y++) {
    for (unsigned int x = 0; x < dimX2; x++) {
      short val = 0;
      for (unsigned int k = 0; k < dimX1Y2; k++) {
        val += a[y * dimX2 + k] * b[k * dimX1Y2 + x];
      }
      c[y * dimX1Y2 + x] = val;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<matrix_mul_short>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,-0x4(%rsp)
  test   %r8d,%r8d
  je     L36
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %ecx,%r10d
  mov    %r9d,%ebp
  mov    %ecx,%r8d
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  movl   $0x0,-0x8(%rsp)
  mov    $0x0,%r15d
  jmp    L9
L42:
  mov    %eax,%edx
  mov    %ecx,%edi
  movzwl (%r11,%rdx,2),%edx
  imul   (%rbx,%rdi,2),%dx
  add    %edx,%esi
  add    $0x1,%eax
  add    %r10d,%ecx
  cmp    %r8d,%eax
  jne    L42
L5:
  lea    0x0(%r13,%r9,1),%eax
  mov    %si,(%r12,%rax,2)
  add    $0x1,%r9d
  cmp    %r9d,%ebp
  je     L73
L2:
  mov    %r9d,%ecx
  mov    %r14d,%eax
  mov    %r15d,%esi
  test   %r10d,%r10d
  jne    L42
  jmp    L5
L73:
  addl   $0x1,-0x8(%rsp)
  mov    -0x8(%rsp),%eax
  add    %r10d,%r13d
  add    %ebp,%r14d
  add    %ebp,%r8d
  cmp    %eax,-0x4(%rsp)
  je     L36
L9:
  mov    $0x0,%r9d
  test   %ebp,%ebp
  jne    L2
  jmp    L73
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrix_mul_short(const short *a, const short *b, short *c, const unsigned int dimX1Y2, const unsigned int dimY1, const unsigned int dimX2) {
  for (unsigned int y = 0; y < dimY1; y++) {
    for (unsigned int x = 0; x < dimX2; x++) {
      short val = 0;
      for (unsigned int k = 0; k < dimX1Y2; k++) {
        val += a[y * dimX2 + k] * b[k * dimX1Y2 + x];
      }
      c[y * dimX1Y2 + x] = val;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_mul_short>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,-0x4(%rsp)
  test   %r8d,%r8d
  je     L31
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %ecx,%r10d
  mov    %r9d,%ebp
  mov    %ecx,%r8d
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %r9d,%r9d
  test   %ebp,%ebp
  je     L39
  nop
L42:
  mov    %r9d,%ecx
  mov    %r14d,%eax
  xor    %esi,%esi
  test   %r10d,%r10d
  je     L57
  nopl   (%rax)
L7:
  mov    %eax,%edx
  mov    %ecx,%edi
  add    $0x1,%eax
  add    %r10d,%ecx
  movzwl (%r11,%rdx,2),%edx
  imul   (%rbx,%rdi,2),%dx
  add    %edx,%esi
  cmp    %r8d,%eax
  jne    L7
L57:
  lea    (%r9,%r13,1),%eax
  add    $0x1,%r9d
  mov    %si,(%r12,%rax,2)
  cmp    %r9d,%ebp
  jne    L42
L39:
  add    $0x1,%r15d
  add    %r10d,%r13d
  add    %ebp,%r14d
  add    %ebp,%r8d
  cmp    %r15d,-0x4(%rsp)
  jne    L15
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrix_mul_short(const short *a, const short *b, short *c, const unsigned int dimX1Y2, const unsigned int dimY1, const unsigned int dimX2) {
  for (unsigned int y = 0; y < dimY1; y++) {
    for (unsigned int x = 0; x < dimX2; x++) {
      short val = 0;
      for (unsigned int k = 0; k < dimX1Y2; k++) {
        val += a[y * dimX2 + k] * b[k * dimX1Y2 + x];
      }
      c[y * dimX1Y2 + x] = val;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix_mul_short>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,-0x4(%rsp)
  test   %r8d,%r8d
  je     L28
  mov    %r9d,%ebp
  test   %r9d,%r9d
  je     L28
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %ecx,%r10d
  mov    %ecx,%r8d
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L19:
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %r9d,%ecx
  mov    %r14d,%eax
  xor    %esi,%esi
  test   %r10d,%r10d
  je     L48
  nopl   (%rax)
L6:
  mov    %eax,%edx
  mov    %ecx,%edi
  add    $0x1,%eax
  add    %r10d,%ecx
  movzwl (%r11,%rdx,2),%edx
  imul   (%rbx,%rdi,2),%dx
  add    %edx,%esi
  cmp    %r8d,%eax
  jne    L6
L48:
  lea    (%r9,%r13,1),%eax
  add    $0x1,%r9d
  mov    %si,(%r12,%rax,2)
  cmp    %r9d,%ebp
  jne    L37
  add    $0x1,%r15d
  add    %r10d,%r13d
  add    %ebp,%r14d
  add    %ebp,%r8d
  cmp    %r15d,-0x4(%rsp)
  jne    L19
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrix_mul_short(const short *a, const short *b, short *c, const unsigned int dimX1Y2, const unsigned int dimY1, const unsigned int dimX2) {
  for (unsigned int y = 0; y < dimY1; y++) {
    for (unsigned int x = 0; x < dimX2; x++) {
      short val = 0;
      for (unsigned int k = 0; k < dimX1Y2; k++) {
        val += a[y * dimX2 + k] * b[k * dimX1Y2 + x];
      }
      c[y * dimX1Y2 + x] = val;
    }
  }
}
```