user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <queue_create@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L16
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L6
L16:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_pop@plt>
  movl   $0x5,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <queue_push@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D109(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_front@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_back@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x9,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <queue_push@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D109(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_front@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_back@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x3,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <queue_push@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D109(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_front@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_back@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_pop@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_front@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_back@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_destroy@plt>
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D109
type_infered: string
name: parse_data
arguments: label: D41
type_infered: string
name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string

tool: D2: creating queue failed

tool: D109: push '%d' into queue


tool: D41: front of the queue is %d


tool: D37: back of the queue is %d


tool: D9: pop the front item of the queue

assistant: ```c
int main(void) {
  int val;
  void *instance;
  int *tmp;
  instance = queue_create();
  if (instance == NULL) {
    printf("creating queue failed\n");
    return -1;
  }
  queue_pop(instance);
  val = 5;
  queue_push(instance, val);
  printf("push '%d' into queue\n", val);
  tmp = queue_front(instance);
  printf("front of the queue is %d\n", *tmp);
  tmp = queue_back(instance);
  printf("back of the queue is %d\n", *tmp);
  val = 9;
  queue_push(instance, val);
  printf("push '%d' into queue\n", val);
  tmp = queue_front(instance);
  printf("front of the queue is %d\n", *tmp);
  tmp = queue_back(instance);
  printf("back of the queue is %d\n", *tmp);
  val = 3;
  queue_push(instance, val);
  printf("push '%d' into queue\n", val);
  tmp = queue_front(instance);
  printf("front of the queue is %d\n", *tmp);
  tmp = queue_back(instance);
  printf("back of the queue is %d\n", *tmp);
  queue_pop(instance);
  printf("pop the front item of the queue\n");
  tmp = queue_front(instance);
  printf("front of the queue is %d\n", *tmp);
  tmp = queue_back(instance);
  printf("back of the queue is %d\n", *tmp);
  queue_destroy(instance);
  return 0;
}
```