ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jne    L68
  mov    $0x0,%eax
  jmp    L13
L68:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
L9:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L0
  mov    $0xffffffff,%eax
  jmp    L13
L0:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  cmovae %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L38
L36:
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L67
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x1c(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L13
L67:
  addl   $0x1,-0x1c(%rbp)
L38:
  mov    -0x1c(%rbp),%eax
  cmp    %rax,-0x8(%rbp)
  ja     L36
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  if (str1 == str2) {
    return 0;
  }
  if ((str1[0] == '\0' || str2[0] == '\0') && (str1[0] != str2[0])) {
    return -1;
  }
  size_t str1_len = strlen(str1);
  size_t str2_len = strlen(str2);
  size_t longest_len = (str1_len > str2_len) ? str1_len : str2_len;
  for (unsigned int i = 0; i < longest_len; i++) {
    if (!(str1[i] == str2[i])) {
      return (int)str1[i] - str2[i];
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L66
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  cmpb   $0x0,(%rdi)
  je     L60
  mov    $0xffffffff,%eax
  cmpb   $0x0,(%rsi)
  je     L68
  jmp    L7
L60:
  cmpb   $0x0,(%rsi)
  jne    L62
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %rax,%r12
  cmovae %r12,%rax
  test   %rax,%rax
  je     L8
  mov    $0x0,%ecx
  mov    $0x0,%edx
L4:
  movzbl 0x0(%rbp,%rdx,1),%esi
  movzbl (%rbx,%rdx,1),%edx
  cmp    %dl,%sil
  jne    L33
  add    $0x1,%ecx
  mov    %ecx,%edx
  cmp    %rax,%rdx
  jb     L4
  mov    $0x0,%eax
  jmp    L68
L33:
  movsbl %sil,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
L68:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  mov    $0x0,%eax
  ret
L62:
  mov    $0xffffffff,%eax
  jmp    L68
L8:
  mov    $0x0,%eax
  jmp    L68
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  if (str1 == str2) {
    return 0;
  }
  if ((str1[0] == '\0' || str2[0] == '\0') && (str1[0] != str2[0])) {
    return -1;
  }
  size_t str1_len = strlen(str1);
  size_t str2_len = strlen(str2);
  size_t longest_len = (str1_len > str2_len) ? str1_len : str2_len;
  for (unsigned int i = 0; i < longest_len; i++) {
    if (!(str1[i] == str2[i])) {
      return (int)str1[i] - str2[i];
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L66
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  movzbl (%rsi),%edx
  test   %bl,%bl
  jne    L23
  test   %dl,%dl
  jne    L36
L64:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    %rax,%r12
  cmovae %r12,%rax
  test   %rax,%rax
  je     L10
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    L45
  nopl   0x0(%rax)
L25:
  lea    0x1(%rcx),%edx
  mov    %rdx,%rcx
  cmp    %rax,%rdx
  jae    L10
  movzbl 0x0(%r13,%rdx,1),%ebx
L45:
  movsbl 0x0(%rbp,%rdx,1),%edx
  cmp    %bl,%dl
  je     L25
  add    $0x8,%rsp
  movsbl %bl,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0xffffffff,%eax
  test   %dl,%dl
  jne    L64
L55:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L66:
  xor    %eax,%eax
  ret
L36:
  or     $0xffffffff,%eax
  jmp    L55
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  if (str1 == str2) {
    return 0;
  }
  if ((str1[0] == '\0' || str2[0] == '\0') && (str1[0] != str2[0])) {
    return -1;
  }
  size_t str1_len = strlen(str1);
  size_t str2_len = strlen(str2);
  size_t longest_len = (str1_len > str2_len) ? str1_len : str2_len;
  for (unsigned int i = 0; i < longest_len; i++) {
    if (!(str1[i] == str2[i])) {
      return (int)str1[i] - str2[i];
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L8
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  movzbl (%rsi),%edx
  test   %bl,%bl
  jne    L13
  test   %dl,%dl
  jne    L31
L21:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    %rax,%r12
  cmovae %r12,%rax
  test   %rax,%rax
  je     L66
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    L17
  nopl   0x0(%rax)
L0:
  lea    0x1(%rcx),%edx
  mov    %rdx,%rcx
  cmp    %rax,%rdx
  jae    L66
  movzbl 0x0(%r13,%rdx,1),%ebx
L17:
  movsbl 0x0(%rbp,%rdx,1),%edx
  cmp    %bl,%dl
  je     L0
  add    $0x8,%rsp
  movsbl %bl,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0xffffffff,%eax
  test   %dl,%dl
  jne    L21
L52:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L66:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  ret
L31:
  or     $0xffffffff,%eax
  jmp    L52
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  if (str1 == str2) {
    return 0;
  }
  if ((str1[0] == '\0' || str2[0] == '\0') && (str1[0] != str2[0])) {
    return -1;
  }
  size_t str1_len = strlen(str1);
  size_t str2_len = strlen(str2);
  size_t longest_len = (str1_len > str2_len) ? str1_len : str2_len;
  for (unsigned int i = 0; i < longest_len; i++) {
    if (!(str1[i] == str2[i])) {
      return (int)str1[i] - str2[i];
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Set_Time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  movb   $0x80,(%rax)
  mov    $0x0,%eax
  call   <Enable_1302@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Write_1302_Data@plt>
  nop
  leave
  ret
```

assistant: ```c
void Set_Time(unsigned char *TimeBuffer) {
  TimeBuffer[7] = '\x80';
  Enable_1302();
  Write_1302_Data(TimeBuffer);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Set_Time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movb   $0x80,0x7(%rdi)
  mov    $0x0,%eax
  call   <Enable_1302@plt>
  mov    %rbx,%rdi
  call   <Write_1302_Data@plt>
  pop    %rbx
  ret
```

assistant: ```c
void Set_Time(unsigned char *TimeBuffer) {
  TimeBuffer[7] = '\x80';
  Enable_1302();
  Write_1302_Data(TimeBuffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Set_Time>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  movb   $0x80,0x7(%rdi)
  call   <Enable_1302@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <Write_1302_Data@plt>
```

assistant: ```c
void Set_Time(unsigned char *TimeBuffer) {
  TimeBuffer[7] = '\x80';
  Enable_1302();
  Write_1302_Data(TimeBuffer);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Set_Time>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  movb   $0x80,0x7(%rdi)
  call   <Enable_1302@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <Write_1302_Data@plt>
```

assistant: ```c
void Set_Time(unsigned char *TimeBuffer) {
  TimeBuffer[7] = '\x80';
  Enable_1302();
  Write_1302_Data(TimeBuffer);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<kepler_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D9(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double kepler_value(double *pars, double *q) {
  double R;
  R = sqrt(q[0] * q[0] + q[1] * q[1] + q[2] * q[2]);
  return -pars[0] * pars[1] / R;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kepler_value>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsd  (%rsi),%xmm0
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L8
  sqrtsd %xmm1,%xmm1
L4:
  movsd  (%rbx),%xmm0
  xorpd  D2(%rip),%xmm0
  mulsd  0x8(%rbx),%xmm0
  divsd  %xmm1,%xmm0
  pop    %rbx
  ret
L8:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D2
type_infered: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double kepler_value(double *pars, double *q) {
  double R;
  R = sqrt(q[0] * q[0] + q[1] * q[1] + q[2] * q[2]);
  return -pars[0] * pars[1] / R;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kepler_value>:
  endbr64
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm0
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L7
  sqrtsd %xmm1,%xmm1
L3:
  movsd  (%rdi),%xmm0
  xorpd  D5(%rip),%xmm0
  mulsd  0x8(%rdi),%xmm0
  add    $0x18,%rsp
  divsd  %xmm1,%xmm0
  ret
L7:
  movapd %xmm1,%xmm0
  mov    %rdi,0x8(%rsp)
  call   <sqrt@plt>
  mov    0x8(%rsp),%rdi
  movapd %xmm0,%xmm1
  jmp    L3
```

tool_calls: name: read_data
arguments: label: D5
data_type: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double kepler_value(double *pars, double *q) {
  double R;
  R = sqrt(q[0] * q[0] + q[1] * q[1] + q[2] * q[2]);
  return -pars[0] * pars[1] / R;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kepler_value>:
  endbr64
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm0
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L9
  sqrtsd %xmm1,%xmm1
L15:
  movsd  (%rdi),%xmm0
  xorpd  D7(%rip),%xmm0
  mulsd  0x8(%rdi),%xmm0
  add    $0x18,%rsp
  divsd  %xmm1,%xmm0
  ret
L9:
  movapd %xmm1,%xmm0
  mov    %rdi,0x8(%rsp)
  call   <sqrt@plt>
  mov    0x8(%rsp),%rdi
  movapd %xmm0,%xmm1
  jmp    L15
```

tool_calls: name: read_data
arguments: label: D7
datatype: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double kepler_value(double *pars, double *q) {
  double R;
  R = sqrt(q[0] * q[0] + q[1] * q[1] + q[2] * q[2]);
  return -pars[0] * pars[1] / R;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jac_chain_nm5_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int jac_chain_nm5_free(void *mem) {
  (void)mem;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jac_chain_nm5_free>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int jac_chain_nm5_free(void *mem) {
  (void)mem;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jac_chain_nm5_free>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int jac_chain_nm5_free(void *mem) {
  (void)mem;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jac_chain_nm5_free>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int jac_chain_nm5_free(void *mem) {
  (void)mem;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <format@plt>
  nop
  leave
  ret
```

assistant: ```c
printf(fmt, args) char *fmt;
unsigned args;
{
  extern int putchar();
  format(putchar, fmt, &args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printf>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  mov    %rdi,%rsi
  mov    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <format@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
printf(fmt, args) char *fmt;
unsigned args;
{
  extern int putchar();
  format(putchar, fmt, &args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printf>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  mov    %esi,0xc(%rsp)
  mov    %rdi,%rsi
  mov    D2(%rip),%rdi
  lea    0xc(%rsp),%rdx
  call   <format@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
printf(fmt, args) char *fmt;
unsigned args;
{
  extern int putchar();
  format(putchar, fmt, &args);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printf>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  mov    %esi,0xc(%rsp)
  mov    %rdi,%rsi
  mov    D3(%rip),%rdi
  lea    0xc(%rsp),%rdx
  call   <format@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
printf(fmt, args) char *fmt;
unsigned args;
{
  extern int putchar();
  format(putchar, fmt, &args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<solve_quadratic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x18(%rbp),%xmm2
  movsd  D3(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L18
  mov    $0x0,%eax
  jmp    L6
L18:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x20(%rbp),%xmm0
  movq   D16(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x8(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    $0x1,%eax
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: f64
name: disassemble_data
arguments: label: D16
type_guessed: f32[2]

tool: D3: 4

tool: {"D16": [0.0,-0.0]}

assistant: ```c
bool solve_quadratic(double a, double b, double c, double *t1, double *t2) {
  const double discriminant = b * b - 4.0 * a * c;
  if (discriminant < 0.0)
    return false;
  const double root = sqrt(discriminant);
  *t1 = (-b + root) / (2.0 * a);
  *t2 = (-b - root) / (2.0 * a);
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<solve_quadratic>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movapd %xmm0,%xmm4
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm3
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  mulsd  D16(%rip),%xmm4
  movapd %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L22
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  ucomisd %xmm0,%xmm1
  ja     L0
  sqrtsd %xmm0,%xmm0
  movapd %xmm0,%xmm1
L2:
  movsd  (%rsp),%xmm2
  addsd  %xmm2,%xmm2
  movapd %xmm1,%xmm0
  movsd  0x8(%rsp),%xmm5
  subsd  %xmm5,%xmm0
  divsd  %xmm2,%xmm0
  movsd  %xmm0,0x0(%rbp)
  xorpd  D8(%rip),%xmm5
  movapd %xmm5,%xmm0
  subsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  movsd  %xmm0,(%rbx)
  mov    $0x1,%eax
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type: f64
name: disassemble_data
arguments: data_label: D8
type: f32[4]

tool: D16: 4

tool: {"D8": [0.0,-0.0,0.0,0.0]}

assistant: ```c
bool solve_quadratic(double a, double b, double c, double *t1, double *t2) {
  const double discriminant = b * b - 4.0 * a * c;
  if (discriminant < 0.0)
    return false;
  const double root = sqrt(discriminant);
  *t1 = (-b + root) / (2.0 * a);
  *t2 = (-b - root) / (2.0 * a);
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<solve_quadratic>:
  endbr64
  movsd  D6(%rip),%xmm4
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm4
  mulsd  %xmm2,%xmm4
  pxor   %xmm2,%xmm2
  subsd  %xmm4,%xmm0
  comisd %xmm0,%xmm2
  ja     L1
  sub    $0x28,%rsp
  ucomisd %xmm0,%xmm2
  ja     L26
  sqrtsd %xmm0,%xmm0
L24:
  movapd %xmm0,%xmm2
  addsd  %xmm3,%xmm3
  mov    $0x1,%eax
  subsd  %xmm1,%xmm2
  xorpd  D18(%rip),%xmm1
  subsd  %xmm0,%xmm1
  divsd  %xmm3,%xmm2
  divsd  %xmm3,%xmm1
  movsd  %xmm2,(%rdi)
  movsd  %xmm1,(%rsi)
  add    $0x28,%rsp
  ret
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
L26:
  mov    %rsi,0x18(%rsp)
  mov    %rdi,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <sqrt@plt>
  mov    0x18(%rsp),%rsi
  mov    0x10(%rsp),%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  jmp    L24
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: f64
name: retrieve_data
arguments: label: D18
data_type: f32[4]

tool: D6: 4

tool: {"D18": [0.0,-0.0,0.0,0.0]}

assistant: ```c
bool solve_quadratic(double a, double b, double c, double *t1, double *t2) {
  const double discriminant = b * b - 4.0 * a * c;
  if (discriminant < 0.0)
    return false;
  const double root = sqrt(discriminant);
  *t1 = (-b + root) / (2.0 * a);
  *t2 = (-b - root) / (2.0 * a);
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solve_quadratic>:
  endbr64
  movsd  D1(%rip),%xmm4
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm4
  mulsd  %xmm2,%xmm4
  pxor   %xmm2,%xmm2
  subsd  %xmm4,%xmm0
  comisd %xmm0,%xmm2
  ja     L6
  sub    $0x28,%rsp
  ucomisd %xmm0,%xmm2
  ja     L4
  sqrtsd %xmm0,%xmm0
L26:
  movapd %xmm0,%xmm2
  addsd  %xmm3,%xmm3
  mov    $0x1,%eax
  subsd  %xmm1,%xmm2
  xorpd  D16(%rip),%xmm1
  subsd  %xmm0,%xmm1
  divsd  %xmm3,%xmm2
  divsd  %xmm3,%xmm1
  movsd  %xmm2,(%rdi)
  movsd  %xmm1,(%rsi)
  add    $0x28,%rsp
  ret
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  ret
L4:
  mov    %rsi,0x18(%rsp)
  mov    %rdi,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <sqrt@plt>
  mov    0x18(%rsp),%rsi
  mov    0x10(%rsp),%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  jmp    L26
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: f64
name: parse_data
arguments: data_tag: D16
type_guessed: f32[4]

tool: D1: 4

tool: {"D16": [0.0,-0.0,0.0,0.0]}

assistant: ```c
bool solve_quadratic(double a, double b, double c, double *t1, double *t2) {
  const double discriminant = b * b - 4.0 * a * c;
  if (discriminant < 0.0)
    return false;
  const double root = sqrt(discriminant);
  *t1 = (-b + root) / (2.0 * a);
  *t2 = (-b - root) / (2.0 * a);
  return true;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x190,-0x4(%rbp)
  je     L70
  cmpl   $0x190,-0x4(%rbp)
  jg     L102
  cmpl   $0xc8,-0x4(%rbp)
  je     L6
  cmpl   $0xc8,-0x4(%rbp)
  jg     L102
  cmpl   $0x7e,-0x4(%rbp)
  je     L119
  cmpl   $0x7e,-0x4(%rbp)
  jg     L102
  cmpl   $0x64,-0x4(%rbp)
  je     L41
  cmpl   $0x64,-0x4(%rbp)
  jg     L102
  cmpl   $0x2d,-0x4(%rbp)
  jg     L138
  cmpl   $0x0,-0x4(%rbp)
  js     L102
  cmpl   $0x2d,-0x4(%rbp)
  ja     L102
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D1(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L138:
  cmpl   $0x3a,-0x4(%rbp)
  je     L219
  jmp    L102
  mov    $0x0,%eax
  jmp    L12
L41:
  mov    $0x1,%eax
  jmp    L12
  mov    $0x2,%eax
  jmp    L12
  mov    $0x3,%eax
  jmp    L12
L219:
  mov    $0x4,%eax
  jmp    L12
L119:
  mov    $0x5,%eax
  jmp    L12
  mov    $0x6,%eax
  jmp    L12
  mov    $0x7,%eax
  jmp    L12
L6:
  mov    $0x8,%eax
  jmp    L12
L70:
  mov    $0x9,%eax
  jmp    L12
  mov    $0xa,%eax
  jmp    L12
L102:
  mov    $0xffffffff,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int hash(int n) {
  switch (n) {
  case 10:
    return 0;
  case 100:
    return 1;
  case 32:
    return 2;
  case 45:
    return 3;
  case 58:
    return 4;
  case 126:
    return 5;
  case 3:
    return 6;
  case 29:
    return 7;
  case 200:
    return 8;
  case 400:
    return 9;
  case 0:
    return 10;
  default:
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  cmp    $0x2d,%edi
  jg     L68
  mov    $0xffffffff,%eax
  test   %edi,%edi
  js     L42
  cmp    $0x2d,%edi
  ja     L32
  mov    %edi,%edi
  lea    D2(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  ret
L32:
  mov    $0xffffffff,%eax
  ret
L68:
  cmp    $0x7e,%edi
  je     L1
  jle    L58
  mov    $0x8,%eax
  cmp    $0xc8,%edi
  je     L42
  cmp    $0x190,%edi
  mov    $0xffffffff,%eax
  mov    $0x9,%edx
  cmove  %edx,%eax
  ret
L58:
  mov    $0x4,%eax
  cmp    $0x3a,%edi
  je     L42
  cmp    $0x64,%edi
  sete   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0x2,%eax
  ret
L1:
  mov    $0x5,%eax
L42:
  ret
```

assistant: ```c
int hash(int n) {
  switch (n) {
  case 10:
    return 0;
  case 100:
    return 1;
  case 32:
    return 2;
  case 45:
    return 3;
  case 58:
    return 4;
  case 126:
    return 5;
  case 3:
    return 6;
  case 29:
    return 7;
  case 200:
    return 8;
  case 400:
    return 9;
  case 0:
    return 10;
  default:
    return -1;
  }
}
```