ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<symbolify>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %rbx,%rdi
  movslq %eax,%r15
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %r15,%r13
  lea    0x1(%r15,%rax,1),%esi
  call   <lmAlloc@plt>
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    %rbx,%rdi
  add    %r12,%r15
  call   <skipLeadingSpaces@plt>
  mov    %r15,(%rsp)
  movzbl (%rax),%ebx
  test   %bl,%bl
  je     L35
  lea    0x1(%rax),%rbp
  jmp    L19
  nopl   (%rax)
L55:
  movb   $0x5f,(%r15)
  add    $0x1,%r15
L28:
  movzbl 0x0(%rbp),%ebx
  add    $0x1,%rbp
  test   %bl,%bl
  je     L35
L19:
  movsbl %bl,%r14d
  mov    %r14d,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L55
  mov    %r14d,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L57
  cmp    $0x2e,%bl
  je     L57
  cmp    $0x5f,%bl
  jne    L28
  nopl   0x0(%rax)
L57:
  add    $0x1,%rbp
  mov    %bl,(%r15)
  add    $0x1,%r15
  movzbl -0x1(%rbp),%ebx
  test   %bl,%bl
  jne    L19
L35:
  movb   $0x0,(%r15)
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %r13d,%eax
  cmp    $0x20,%eax
  jg     L8
L23:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  mov    0x8(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <hmacMd5@plt>
  mov    (%rsp),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <freeMem@plt>
  jmp    L23
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: 

assistant: ```c
char *symbolify(char *prefix, char *original, struct lm *lm) {
  int prefixSize = strlen(prefix);
  char *result = lmAlloc(lm, strlen(original) + prefixSize + 1);
  memcpy(result, prefix, prefixSize);
  char *in = skipLeadingSpaces(original);
  char *out = result + prefixSize;
  char c;
  while ((c = *in++) != 0) {
    if (isspace(c))
      *out++ = '_';
    else if (isalnum(c) || c == '.' || c == '_')
      *out++ = c;
  }
  *out++ = 0;
  int len = strlen(result) - prefixSize;
  if (len > 32) {
    char *md5 = hmacMd5("", original);
    strcpy(result + prefixSize, md5);
    freeMem(md5);
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  D41(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D51(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D51(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D26(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D41
type: f64
name: retrieve_data
arguments: data_label: D51
type: f64
name: retrieve_data
arguments: data_label: D3
type: f64
name: retrieve_data
arguments: data_label: D26
type: byte[8]
name: retrieve_data
arguments: data_label: D12
type: string

tool: D41: 3

tool: D51: 4

tool: D3: 1.5

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x40,0x50,0x40]}

tool: D12: Result = %f


assistant: ```c
int main(int argc, const char *argv[]) {
  double doubleResult = 3.0;
  doubleResult *= doubleResult;
  doubleResult /= (4 % 7);
  doubleResult += 4.0 * doubleResult;
  doubleResult -= -1.5;
  doubleResult += 'A';
  printf("Result = %f\n", doubleResult);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D4(%rip),%xmm0
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: byte[8]
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x70,0x53,0x40]}

tool: D10: Result = %f


assistant: ```c
int main(int argc, const char *argv[]) {
  double doubleResult = 3.0;
  doubleResult *= doubleResult;
  doubleResult /= (4 % 7);
  doubleResult += 4.0 * doubleResult;
  doubleResult -= -1.5;
  doubleResult += 'A';
  printf("Result = %f\n", doubleResult);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D10(%rip),%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: byte[8]
name: read_data
arguments: data_tag: D8
type_infered: string

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x70,0x53,0x40]}

tool: D8: Result = %f


assistant: ```c
int main(int argc, const char *argv[]) {
  double doubleResult = 3.0;
  doubleResult *= doubleResult;
  doubleResult /= (4 % 7);
  doubleResult += 4.0 * doubleResult;
  doubleResult -= -1.5;
  doubleResult += 'A';
  printf("Result = %f\n", doubleResult);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D2(%rip),%xmm0
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: byte[8]
name: read_data
arguments: label: D3
type_infered: string

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x70,0x53,0x40]}

tool: D3: Result = %f


assistant: ```c
int main(int argc, const char *argv[]) {
  double doubleResult = 3.0;
  doubleResult *= doubleResult;
  doubleResult /= (4 % 7);
  doubleResult += 4.0 * doubleResult;
  doubleResult -= -1.5;
  doubleResult += 'A';
  printf("Result = %f\n", doubleResult);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<srate2blocksize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2edf,-0x4(%rbp)
  ja     L16
  mov    $0x100,%eax
  jmp    L6
L16:
  cmpl   $0x59d7,-0x4(%rbp)
  ja     L10
  mov    $0x200,%eax
  jmp    L6
L10:
  cmpl   $0xabdf,-0x4(%rbp)
  ja     L2
  mov    $0x400,%eax
  jmp    L6
L2:
  mov    $0x800,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int srate2blocksize(unsigned int srate_chan_product) {
  if (srate_chan_product < 12000)
    return 256;
  if (srate_chan_product < 23000)
    return 512;
  if (srate_chan_product < 44000)
    return 1024;
  return 2048;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<srate2blocksize>:
  endbr64
  mov    $0x100,%eax
  cmp    $0x2edf,%edi
  jbe    L16
  mov    $0x200,%eax
  cmp    $0x59d7,%edi
  jbe    L16
  cmp    $0xabe0,%edi
  sbb    %eax,%eax
  and    $0xfffffc00,%eax
  add    $0x800,%eax
L16:
  ret
```

assistant: ```c
unsigned int srate2blocksize(unsigned int srate_chan_product) {
  if (srate_chan_product < 12000)
    return 256;
  if (srate_chan_product < 23000)
    return 512;
  if (srate_chan_product < 44000)
    return 1024;
  return 2048;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<srate2blocksize>:
  endbr64
  mov    $0x100,%eax
  cmp    $0x2edf,%edi
  jbe    L14
  mov    $0x200,%eax
  cmp    $0x59d7,%edi
  jbe    L14
  cmp    $0xabe0,%edi
  sbb    %eax,%eax
  and    $0xfffffc00,%eax
  add    $0x800,%eax
L14:
  ret
```

assistant: ```c
unsigned int srate2blocksize(unsigned int srate_chan_product) {
  if (srate_chan_product < 12000)
    return 256;
  if (srate_chan_product < 23000)
    return 512;
  if (srate_chan_product < 44000)
    return 1024;
  return 2048;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<srate2blocksize>:
  endbr64
  mov    $0x100,%eax
  cmp    $0x2edf,%edi
  jbe    L7
  mov    $0x200,%eax
  cmp    $0x59d7,%edi
  jbe    L7
  cmp    $0xabe0,%edi
  sbb    %eax,%eax
  and    $0xfffffc00,%eax
  add    $0x800,%eax
L7:
  ret
```

assistant: ```c
unsigned int srate2blocksize(unsigned int srate_chan_product) {
  if (srate_chan_product < 12000)
    return 256;
  if (srate_chan_product < 23000)
    return 512;
  if (srate_chan_product < 44000)
    return 1024;
  return 2048;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bin2Hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L4:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <int2char@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <int2char@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  leave
  ret
```

assistant: ```c
int bin2Hex(unsigned char *target, const unsigned char *src, int srcLen) {
  for (int i = 0; i < srcLen; i++) {
    *(target) = int2char(*src >> 4);
    target++;
    *(target) = int2char(*src & 0x0f);
    target++;
    src++;
  }
  return srcLen * 2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bin2Hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L12
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%eax
  lea    (%rdi,%rax,2),%r12
L18:
  movzbl 0x0(%rbp),%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <int2char@plt>
  mov    %al,(%rbx)
  movzbl 0x0(%rbp),%edi
  and    $0xf,%edi
  call   <int2char@plt>
  mov    %al,0x1(%rbx)
  add    $0x2,%rbx
  add    $0x1,%rbp
  cmp    %rbx,%r12
  jne    L18
L12:
  lea    0x0(%r13,%r13,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int bin2Hex(unsigned char *target, const unsigned char *src, int srcLen) {
  for (int i = 0; i < srcLen; i++) {
    *(target) = int2char(*src >> 4);
    target++;
    *(target) = int2char(*src & 0x0f);
    target++;
    src++;
  }
  return srcLen * 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bin2Hex>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L0
  movslq %edx,%rax
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    (%rdi,%rax,2),%r12
  nopw   0x0(%rax,%rax,1)
L4:
  movzbl 0x0(%rbp),%edi
  add    $0x2,%rbx
  add    $0x1,%rbp
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <int2char@plt>
  mov    %al,-0x2(%rbx)
  movzbl -0x1(%rbp),%edi
  and    $0xf,%edi
  call   <int2char@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%r12
  jne    L4
L0:
  add    $0x8,%rsp
  lea    0x0(%r13,%r13,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int bin2Hex(unsigned char *target, const unsigned char *src, int srcLen) {
  for (int i = 0; i < srcLen; i++) {
    *(target) = int2char(*src >> 4);
    target++;
    *(target) = int2char(*src & 0x0f);
    target++;
    src++;
  }
  return srcLen * 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bin2Hex>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L2
  movslq %edx,%rax
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    (%rdi,%rax,2),%r12
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl 0x0(%rbp),%edi
  add    $0x2,%rbx
  add    $0x1,%rbp
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <int2char@plt>
  mov    %al,-0x2(%rbx)
  movzbl -0x1(%rbp),%edi
  and    $0xf,%edi
  call   <int2char@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%r12
  jne    L5
L2:
  add    $0x8,%rsp
  lea    0x0(%r13,%r13,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int bin2Hex(unsigned char *target, const unsigned char *src, int srcLen) {
  for (int i = 0; i < srcLen; i++) {
    *(target) = int2char(*src >> 4);
    target++;
    *(target) = int2char(*src & 0x0f);
    target++;
    src++;
  }
  return srcLen * 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<third>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L56
L33:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L78
  cmp    $0x1,%eax
  je     L41
  jmp    L87
L78:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L60
L41:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rcx
  sub    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L16
  lea    D30(%rip),%rax
  jmp    L38
L16:
  lea    D48(%rip),%rax
L38:
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L60
L87:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L60:
  addl   $0x1,-0x4(%rbp)
L56:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L33
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D30
type_infered: string
name: parse_data
arguments: data_label: D48
type_infered: string

tool: D13: #.%c.#

tool: D30: .%c.#

tool: D48: .%c.*

assistant: ```c
void third(char *str, size_t len) {
  printf("#.%c.#", str[0]);
  for (int i = 1; i < len; i++) {
    switch (i % 3) {
    case 0:
      printf(".%c.#", str[i]);
      break;
    case 1:
      printf(i == len - 1 ? ".%c.#" : ".%c.*", str[i]);
      break;
    default:
      printf(".%c.*", str[i]);
    }
  }
  putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<third>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  movsbl (%rdi),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%rbp
  jbe    L41
  mov    $0x1,%ebx
  lea    D18(%rip),%r14
  lea    D20(%rip),%r13
  lea    -0x1(%rbp),%r15
  jmp    L9
L18:
  movsbl (%r12,%rbx,1),%esi
  mov    %r14,%rdi
  call   <printf@plt>
L31:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L41
L9:
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L18
  cmp    $0x1,%eax
  je     L13
  movsbl (%r12,%rbx,1),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L31
L13:
  movsbl (%r12,%rbx,1),%esi
  cmp    %rbx,%r15
  mov    %r13,%rdi
  cmove  %r14,%rdi
  call   <printf@plt>
  jmp    L31
L41:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string
name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D20
type: string

tool: D8: #.%c.#

tool: D18: .%c.#

tool: D20: .%c.*

assistant: ```c
void third(char *str, size_t len) {
  printf("#.%c.#", str[0]);
  for (int i = 1; i < len; i++) {
    switch (i % 3) {
    case 0:
      printf(".%c.#", str[i]);
      break;
    case 1:
      printf(i == len - 1 ? ".%c.#" : ".%c.*", str[i]);
      break;
    default:
      printf(".%c.*", str[i]);
    }
  }
  putchar('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<third>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  lea    D25(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movsbl (%rdi),%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    -0x1(%rbx),%rax
  mov    %rax,0x8(%rsp)
  cmp    $0x1,%rbx
  ja     L32
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r13,%rdi
  call   <printf@plt>
L35:
  add    $0x1,%r15
  cmp    %r15,%rbx
  je     L60
L32:
  mov    %r15d,%eax
  movsbl 0x0(%rbp,%r15,1),%esi
  imul   %r12,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%ecx
  mov    %r15d,%eax
  sub    %ecx,%eax
  je     L5
  cmp    $0x1,%eax
  jne    L9
  cmp    %r15,0x8(%rsp)
  mov    %r14,%rdi
  cmovne %r13,%rdi
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L32
L60:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L35
```

tool_calls: name: parse_data
arguments: label: D25
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string

tool: D25: .%c.#

tool: D0: .%c.*

tool: D19: #.%c.#

assistant: ```c
void third(char *str, size_t len) {
  printf("#.%c.#", str[0]);
  for (int i = 1; i < len; i++) {
    switch (i % 3) {
    case 0:
      printf(".%c.#", str[i]);
      break;
    case 1:
      printf(i == len - 1 ? ".%c.#" : ".%c.*", str[i]);
      break;
    default:
      printf(".%c.*", str[i]);
    }
  }
  putchar('\n');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<third>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  mov    $0xaaaaaaab,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movsbl (%rdi),%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    -0x1(%rbx),%rax
  mov    %rax,0x8(%rsp)
  cmp    $0x1,%rbx
  ja     L58
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r13,%rdi
  call   <printf@plt>
L29:
  add    $0x1,%r15
  cmp    %r15,%rbx
  je     L19
L58:
  mov    %r15d,%eax
  movsbl 0x0(%rbp,%r15,1),%esi
  imul   %r12,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%ecx
  mov    %r15d,%eax
  sub    %ecx,%eax
  je     L1
  cmp    $0x1,%eax
  jne    L8
  cmp    %r15,0x8(%rsp)
  mov    %r14,%rdi
  cmovne %r13,%rdi
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L58
L19:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L29
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D27
type_guessed: string
name: read_data
arguments: tag: D22
type_guessed: string

tool: D16: .%c.#

tool: D27: .%c.*

tool: D22: #.%c.#

assistant: ```c
void third(char *str, size_t len) {
  printf("#.%c.#", str[0]);
  for (int i = 1; i < len; i++) {
    switch (i % 3) {
    case 0:
      printf(".%c.#", str[i]);
      break;
    case 1:
      printf(i == len - 1 ? ".%c.#" : ".%c.*", str[i]);
      break;
    default:
      printf(".%c.*", str[i]);
    }
  }
  putchar('\n');
}
```
user: What is the c source code of the assembly code below?

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jg     L70
  mov    $0x1,%eax
  jmp    L21
L70:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L67
  mov    $0x0,%eax
  jmp    L21
L67:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L71
  mov    $0x0,%eax
  jmp    L21
L71:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L53
  mov    $0x1,%eax
  jmp    L21
L53:
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <is_prime>
L21:
  leave
  ret
```

assistant: ```c
int is_prime(int n, int i) {
  if (n < 4)
    return 1;
  else if ((n % 2) == 0)
    return 0;
  else if (n % i == 0)
    return 0;
  else if (i * i > n)
    return 1;
  else
    return is_prime(n, i + 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_prime>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jle    L27
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L27
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  je     L27
  mov    %esi,%edx
  imul   %esi,%edx
  mov    $0x1,%eax
  cmp    %edi,%edx
  jle    L28
L27:
  ret
L28:
  sub    $0x8,%rsp
  add    $0x2,%esi
  call   <is_prime>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_prime(int n, int i) {
  if (n < 4)
    return 1;
  else if ((n % 2) == 0)
    return 0;
  else if (n % i == 0)
    return 0;
  else if (i * i > n)
    return 1;
  else
    return is_prime(n, i + 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_prime>:
  endbr64
  cmp    $0x3,%edi
  jle    L28
  test   $0x1,%dil
  je     L38
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L48
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %eax,%edi
  jge    L3
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %edi,%eax
  jg     L28
L3:
  mov    %edi,%eax
  add    $0x2,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L34
L48:
  mov    %edx,%eax
  ret
L28:
  mov    $0x1,%edx
  mov    %edx,%eax
  ret
L38:
  xor    %edx,%edx
  jmp    L48
```

assistant: ```c
int is_prime(int n, int i) {
  if (n < 4)
    return 1;
  else if ((n % 2) == 0)
    return 0;
  else if (n % i == 0)
    return 0;
  else if (i * i > n)
    return 1;
  else
    return is_prime(n, i + 2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_prime>:
  endbr64
  cmp    $0x3,%edi
  jle    L57
  test   $0x1,%dil
  je     L76
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L45
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %eax,%edi
  jge    L42
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %edi,%eax
  jg     L57
L42:
  mov    %edi,%eax
  add    $0x2,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L7
L45:
  mov    %edx,%eax
  ret
L57:
  mov    $0x1,%edx
  mov    %edx,%eax
  ret
L76:
  xor    %edx,%edx
  jmp    L45
```

assistant: ```c
int is_prime(int n, int i) {
  if (n < 4)
    return 1;
  else if ((n % 2) == 0)
    return 0;
  else if (n % i == 0)
    return 0;
  else if (i * i > n)
    return 1;
  else
    return is_prime(n, i + 2);
}
```