ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<data_collection>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4b0,%edi
  call   <malloc@plt>
  lea    D58(%rip),%rdx
  lea    D29(%rip),%rcx
  movq   %rdx,%xmm1
  movq   %rcx,%xmm0
  lea    D50(%rip),%rdx
  punpcklqdq %xmm1,%xmm0
  lea    D51(%rip),%rsi
  movq   %rdx,%xmm2
  movups %xmm0,(%rax)
  movq   %rsi,%xmm0
  lea    D36(%rip),%rdx
  lea    D16(%rip),%rdi
  punpcklqdq %xmm2,%xmm0
  movq   %rdx,%xmm3
  movups %xmm0,0x10(%rax)
  movq   %rdi,%xmm0
  punpcklqdq %xmm3,%xmm0
  movups %xmm0,0x20(%rax)
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D58
type_infered: string
name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D50
type_infered: string
name: parse_data
arguments: label: D51
type_infered: string
name: parse_data
arguments: label: D36
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string

tool: D58: ./data/Capsules-i100-889.dat

tool: D29: ./data/Capsules-i100-1090.dat

tool: D50: ./data/Capsules-i103-990.dat

tool: D51: ./data/Capsules-i101-404.dat

tool: D36: ---

tool: D16: ./data/Capsules-i122-1617.dat

assistant: ```c
char **data_collection() {
  int n_data_1 = 150;
  char **data_collection_1 = (char **)malloc(n_data_1 * sizeof(char *));
  int n_data = 0;
  data_collection_1[n_data++] = "./data/Capsules-i100-1090.dat";
  data_collection_1[n_data++] = "./data/Capsules-i100-889.dat";
  data_collection_1[n_data++] = "./data/Capsules-i101-404.dat";
  data_collection_1[n_data++] = "./data/Capsules-i103-990.dat";
  data_collection_1[n_data++] = "./data/Capsules-i122-1617.dat";
  data_collection_1[n_data++] = "---";
  return data_collection_1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<APHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xaaaaaaaa,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L38:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L35
  mov    -0x8(%rbp),%eax
  shl    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%edx
  shr    $0x3,%edx
  imul   %edx,%eax
  xor    %ecx,%eax
  jmp    L19
L35:
  mov    -0x8(%rbp),%eax
  shl    $0xb,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%eax
  shr    $0x5,%eax
  xor    %edx,%eax
  add    %ecx,%eax
  not    %eax
L19:
  xor    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L38
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int APHash(char *str, unsigned int len) {
  unsigned int hash = 0xAAAAAAAA;
  unsigned int i = 0;
  for (; i < len; str++, i++)
    hash ^= ((i & 1) == 0) ? ((hash << 7) ^ (*str) * (hash >> 3)) : (~((hash << 11) + ((*str) ^ (hash >> 5))));
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<APHash>:
  endbr64
  test   %esi,%esi
  je     L14
  mov    %esi,%esi
  mov    $0x0,%edx
  mov    $0xaaaaaaaa,%ecx
  jmp    L10
L41:
  movsbl (%rdi,%rdx,1),%eax
  mov    %ecx,%r8d
  shr    $0x5,%r8d
  xor    %r8d,%eax
  mov    %ecx,%r8d
  shl    $0xb,%r8d
  add    %r8d,%eax
  not    %eax
L7:
  xor    %eax,%ecx
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L35
L10:
  test   $0x1,%dl
  jne    L41
  movsbl (%rdi,%rdx,1),%eax
  mov    %ecx,%r8d
  shr    $0x3,%r8d
  imul   %r8d,%eax
  mov    %ecx,%r8d
  shl    $0x7,%r8d
  xor    %r8d,%eax
  jmp    L7
L14:
  mov    $0xaaaaaaaa,%ecx
L35:
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned int APHash(char *str, unsigned int len) {
  unsigned int hash = 0xAAAAAAAA;
  unsigned int i = 0;
  for (; i < len; str++, i++)
    hash ^= ((i & 1) == 0) ? ((hash << 7) ^ (*str) * (hash >> 3)) : (~((hash << 11) + ((*str) ^ (hash >> 5))));
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<APHash>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  je     L5
  mov    %esi,%esi
  xor    %edx,%edx
  mov    $0xaaaaaaaa,%r8d
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L17:
  shr    $0x3,%edi
  add    $0x1,%rdx
  imul   %edi,%eax
  mov    %r8d,%edi
  shl    $0x7,%edi
  xor    %edi,%eax
  xor    %eax,%r8d
  cmp    %rsi,%rdx
  je     L18
L42:
  movsbl (%rcx,%rdx,1),%eax
  mov    %r8d,%edi
  test   $0x1,%dl
  je     L17
  shr    $0x5,%edi
  add    $0x1,%rdx
  xor    %edi,%eax
  mov    %r8d,%edi
  shl    $0xb,%edi
  add    %edi,%eax
  not    %eax
  xor    %eax,%r8d
  cmp    %rsi,%rdx
  jne    L42
L18:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L5:
  mov    $0xaaaaaaaa,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int APHash(char *str, unsigned int len) {
  unsigned int hash = 0xAAAAAAAA;
  unsigned int i = 0;
  for (; i < len; str++, i++)
    hash ^= ((i & 1) == 0) ? ((hash << 7) ^ (*str) * (hash >> 3)) : (~((hash << 11) + ((*str) ^ (hash >> 5))));
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<APHash>:
  endbr64
  test   %esi,%esi
  je     L14
  mov    %esi,%esi
  xor    %edx,%edx
  mov    $0xaaaaaaaa,%eax
  nopl   0x0(%rax)
L33:
  movsbl (%rdi,%rdx,1),%ecx
  mov    %eax,%r8d
  test   $0x1,%dl
  jne    L39
  shr    $0x3,%r8d
  add    $0x1,%rdx
  imul   %r8d,%ecx
  mov    %eax,%r8d
  shl    $0x7,%r8d
  xor    %r8d,%ecx
  xor    %ecx,%eax
  cmp    %rdx,%rsi
  jne    L33
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  shr    $0x5,%r8d
  add    $0x1,%rdx
  xor    %r8d,%ecx
  mov    %eax,%r8d
  shl    $0xb,%r8d
  add    %r8d,%ecx
  xor    %ecx,%eax
  not    %eax
  cmp    %rdx,%rsi
  jne    L33
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0xaaaaaaaa,%eax
  ret
```

assistant: ```c
unsigned int APHash(char *str, unsigned int len) {
  unsigned int hash = 0xAAAAAAAA;
  unsigned int i = 0;
  for (; i < len; str++, i++)
    hash ^= ((i & 1) == 0) ? ((hash << 7) ^ (*str) * (hash >> 3)) : (~((hash << 11) + ((*str) ^ (hash >> 5))));
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L44
  cmpl   $0x0,-0x18(%rbp)
  je     L22
  cmpl   $0x0,-0x1c(%rbp)
  je     L22
L44:
  mov    $0x1,%eax
  jmp    L77
L22:
  mov    $0x0,%eax
L77:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L39
  cmpl   $0x0,-0x18(%rbp)
  jne    L68
L39:
  cmpl   $0x0,-0x1c(%rbp)
  je     L51
L68:
  mov    $0x1,%eax
  jmp    L53
L51:
  mov    $0x0,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
f(a, b, c) {
  int i = a || b && c;
  return i && b || c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  mov    $0x1,%ecx
  test   %edi,%edi
  jne    L6
  test   %esi,%esi
  setne  %al
  test   %edx,%edx
  setne  %cl
  movzbl %cl,%ecx
  and    %eax,%ecx
L6:
  test   %esi,%esi
  setne  %al
  and    %ecx,%eax
  test   %edx,%edx
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
f(a, b, c) {
  int i = a || b && c;
  return i && b || c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f>:
  endbr64
  test   %edi,%edi
  jne    L38
  test   %edx,%edx
  setne  %dl
  test   %esi,%esi
  je     L2
  mov    $0x1,%eax
  test   %dl,%dl
  je     L2
L9:
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L9
  test   %edx,%edx
  setne  %dl
L2:
  movzbl %dl,%eax
  ret
```

assistant: ```c
f(a, b, c) {
  int i = a || b && c;
  return i && b || c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  test   %edi,%edi
  jne    L37
  test   %edx,%edx
  setne  %dl
  test   %esi,%esi
  je     L27
  mov    $0x1,%eax
  test   %dl,%dl
  je     L27
L28:
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L28
  test   %edx,%edx
  setne  %dl
L27:
  movzbl %dl,%eax
  ret
```

assistant: ```c
f(a, b, c) {
  int i = a || b && c;
  return i && b || c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readUInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1c,-0x10(%rbp)
  jmp    L90
L2:
  mov    -0x10(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x20,%esi
  mov    $0x8,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L44
L25:
  nop
  addl   $0x1,-0x8(%rbp)
L44:
  cmpl   $0x16e35f,-0x8(%rbp)
  jle    L25
  mov    $0x28,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L112
L113:
  nop
  addl   $0x1,-0x8(%rbp)
L112:
  cmpl   $0xf423f,-0x8(%rbp)
  jle    L113
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L127:
  mov    $0x28,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L63
L49:
  nop
  addl   $0x1,-0x8(%rbp)
L63:
  cmpl   $0x7a11f,-0x8(%rbp)
  jle    L49
  mov    $0x8,%esi
  mov    $0x20,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L60
L26:
  nop
  addl   $0x1,-0x8(%rbp)
L60:
  cmpl   $0x7a11f,-0x8(%rbp)
  jle    L26
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L127
  mov    $0x28,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L124:
  nop
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x26259f,-0x8(%rbp)
  jle    L124
  subl   $0x4,-0x10(%rbp)
L90:
  cmpl   $0x0,-0x10(%rbp)
  jns    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void readUInt(unsigned long val) {
  int i, j, k, v;
  for (i = 28; i >= 0; i -= 4) {
    v = (val >> i) & 0x0f;
    setLEDs(0x08, 0x20);
    for (k = 0; k < 3 * 500000; k++)
      __asm("nop");
    setLEDs(0x00, 0x28);
    for (k = 0; k < 2 * 500000; k++)
      __asm("nop");
    for (j = 0; j < v; j++) {
      setLEDs(0x00, 0x28);
      for (k = 0; k < 500000; k++)
        __asm("nop");
      setLEDs(0x20, 0x08);
      for (k = 0; k < 500000; k++)
        __asm("nop");
    }
    setLEDs(0x00, 0x28);
    for (k = 0; k < 5 * 500000; k++)
      __asm("nop");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readUInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0x1c,%ebx
L19:
  mov    %r13,%rbp
  mov    %ebx,%ecx
  shr    %cl,%rbp
  and    $0xf,%ebp
  mov    $0x20,%esi
  mov    $0x8,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  mov    $0x16e360,%eax
L61:
  nop
  sub    $0x1,%eax
  jne    L61
  mov    $0x28,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  mov    $0xf4240,%eax
L5:
  nop
  sub    $0x1,%eax
  jne    L5
  test   %ebp,%ebp
  jle    L30
  mov    $0x0,%r12d
L38:
  mov    $0x28,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  mov    $0x7a120,%eax
L20:
  nop
  sub    $0x1,%eax
  jne    L20
  mov    $0x8,%esi
  mov    $0x20,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  mov    $0x7a120,%eax
L18:
  nop
  sub    $0x1,%eax
  jne    L18
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jne    L38
L30:
  mov    $0x28,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <setLEDs@plt>
  mov    $0x2625a0,%eax
L37:
  nop
  sub    $0x1,%eax
  jne    L37
  sub    $0x4,%ebx
  cmp    $0xfffffffc,%ebx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void readUInt(unsigned long val) {
  int i, j, k, v;
  for (i = 28; i >= 0; i -= 4) {
    v = (val >> i) & 0x0f;
    setLEDs(0x08, 0x20);
    for (k = 0; k < 3 * 500000; k++)
      __asm("nop");
    setLEDs(0x00, 0x28);
    for (k = 0; k < 2 * 500000; k++)
      __asm("nop");
    for (j = 0; j < v; j++) {
      setLEDs(0x00, 0x28);
      for (k = 0; k < 500000; k++)
        __asm("nop");
      setLEDs(0x20, 0x08);
      for (k = 0; k < 500000; k++)
        __asm("nop");
    }
    setLEDs(0x00, 0x28);
    for (k = 0; k < 5 * 500000; k++)
      __asm("nop");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readUInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1c,%ebx
  sub    $0x8,%rsp
L76:
  mov    %ebx,%ecx
  mov    %rbp,%r12
  mov    $0x20,%esi
  mov    $0x8,%edi
  shr    %cl,%r12
  xor    %eax,%eax
  call   <setLEDs@plt>
  and    $0xf,%r12d
  mov    $0x16e360,%eax
  nopl   0x0(%rax,%rax,1)
L33:
  nop
  sub    $0x1,%eax
  jne    L33
  mov    $0x28,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <setLEDs@plt>
  mov    $0xf4240,%eax
  nopl   0x0(%rax)
L71:
  nop
  sub    $0x1,%eax
  jne    L71
  test   %r12d,%r12d
  je     L9
  xor    %r13d,%r13d
L72:
  mov    $0x28,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <setLEDs@plt>
  mov    $0x7a120,%eax
  nopl   0x0(%rax)
L15:
  nop
  sub    $0x1,%eax
  jne    L15
  mov    $0x8,%esi
  mov    $0x20,%edi
  xor    %eax,%eax
  call   <setLEDs@plt>
  mov    $0x7a120,%eax
  nopl   0x0(%rax)
L22:
  nop
  sub    $0x1,%eax
  jne    L22
  add    $0x1,%r13d
  cmp    %r13d,%r12d
  jne    L72
L9:
  mov    $0x28,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <setLEDs@plt>
  mov    $0x2625a0,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  nop
  sub    $0x1,%eax
  jne    L5
  sub    $0x4,%ebx
  cmp    $0xfffffffc,%ebx
  jne    L76
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void readUInt(unsigned long val) {
  int i, j, k, v;
  for (i = 28; i >= 0; i -= 4) {
    v = (val >> i) & 0x0f;
    setLEDs(0x08, 0x20);
    for (k = 0; k < 3 * 500000; k++)
      __asm("nop");
    setLEDs(0x00, 0x28);
    for (k = 0; k < 2 * 500000; k++)
      __asm("nop");
    for (j = 0; j < v; j++) {
      setLEDs(0x00, 0x28);
      for (k = 0; k < 500000; k++)
        __asm("nop");
      setLEDs(0x20, 0x08);
      for (k = 0; k < 500000; k++)
        __asm("nop");
    }
    setLEDs(0x00, 0x28);
    for (k = 0; k < 5 * 500000; k++)
      __asm("nop");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<readUInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1c,%ebx
  sub    $0x8,%rsp
L13:
  mov    %ebx,%ecx
  mov    %rbp,%r12
  mov    $0x20,%esi
  mov    $0x8,%edi
  shr    %cl,%r12
  xor    %eax,%eax
  call   <setLEDs@plt>
  and    $0xf,%r12d
  mov    $0x16e360,%eax
  nopl   0x0(%rax,%rax,1)
L27:
  nop
  sub    $0x1,%eax
  jne    L27
  mov    $0x28,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <setLEDs@plt>
  mov    $0xf4240,%eax
  nopl   0x0(%rax)
L11:
  nop
  sub    $0x1,%eax
  jne    L11
  test   %r12d,%r12d
  je     L68
  xor    %r13d,%r13d
L3:
  mov    $0x28,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <setLEDs@plt>
  mov    $0x7a120,%eax
  nopl   0x0(%rax)
L46:
  nop
  sub    $0x1,%eax
  jne    L46
  mov    $0x8,%esi
  mov    $0x20,%edi
  xor    %eax,%eax
  call   <setLEDs@plt>
  mov    $0x7a120,%eax
  nopl   0x0(%rax)
L47:
  nop
  sub    $0x1,%eax
  jne    L47
  add    $0x1,%r13d
  cmp    %r13d,%r12d
  jne    L3
L68:
  mov    $0x28,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <setLEDs@plt>
  mov    $0x2625a0,%eax
  nopw   0x0(%rax,%rax,1)
L40:
  nop
  sub    $0x1,%eax
  jne    L40
  sub    $0x4,%ebx
  cmp    $0xfffffffc,%ebx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void readUInt(unsigned long val) {
  int i, j, k, v;
  for (i = 28; i >= 0; i -= 4) {
    v = (val >> i) & 0x0f;
    setLEDs(0x08, 0x20);
    for (k = 0; k < 3 * 500000; k++)
      __asm("nop");
    setLEDs(0x00, 0x28);
    for (k = 0; k < 2 * 500000; k++)
      __asm("nop");
    for (j = 0; j < v; j++) {
      setLEDs(0x00, 0x28);
      for (k = 0; k < 500000; k++)
        __asm("nop");
      setLEDs(0x20, 0x08);
      for (k = 0; k < 500000; k++)
        __asm("nop");
    }
    setLEDs(0x00, 0x28);
    for (k = 0; k < 5 * 500000; k++)
      __asm("nop");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_dobldobl_container_to_target_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xfc,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy_dobldobl_container_to_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(252, a, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_dobldobl_container_to_target_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xfc,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copy_dobldobl_container_to_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(252, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_dobldobl_container_to_target_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xfc,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int copy_dobldobl_container_to_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(252, a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<copy_dobldobl_container_to_target_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xfc,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int copy_dobldobl_container_to_target_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(252, a, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movzbl -0x5(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string

tool: D12: %hhu


tool: D15: %f


assistant: ```c
int main(void) {
  unsigned char age;
  float price;
  printf("%hhu\n", age);
  printf("%f\n", price);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  lea    D16(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D16
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D16: %hhu


tool: D10: %f


assistant: ```c
int main(void) {
  unsigned char age;
  float price;
  printf("%hhu\n", age);
  printf("%f\n", price);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  cvtsi2ss %eax,%xmm0
  lea    D17(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D17: %hhu


tool: D2: %f


assistant: ```c
int main(void) {
  unsigned char age;
  float price;
  printf("%hhu\n", age);
  printf("%f\n", price);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  cvtsi2ss %eax,%xmm0
  lea    D11(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D1
type_infered: string

tool: D11: %hhu


tool: D1: %f


assistant: ```c
int main(void) {
  unsigned char age;
  float price;
  printf("%hhu\n", age);
  printf("%f\n", price);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dobldobl_collapse_diagonal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x12b,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int dobldobl_collapse_diagonal(int k, int d) {
  int a[2], *b, fail;
  double *c;
  a[0] = k;
  a[1] = d;
  fail = _ada_use_c2phc4c(299, a, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dobldobl_collapse_diagonal>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x12b,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobldobl_collapse_diagonal(int k, int d) {
  int a[2], *b, fail;
  double *c;
  a[0] = k;
  a[1] = d;
  fail = _ada_use_c2phc4c(299, a, b, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dobldobl_collapse_diagonal>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    $0x12b,%edi
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rsi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobldobl_collapse_diagonal(int k, int d) {
  int a[2], *b, fail;
  double *c;
  a[0] = k;
  a[1] = d;
  fail = _ada_use_c2phc4c(299, a, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dobldobl_collapse_diagonal>:
  endbr64
  sub    $0x18,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  xor    %r8d,%r8d
  punpckldq %xmm1,%xmm0
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rsp,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x12b,%edi
  movq   %xmm0,(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobldobl_collapse_diagonal(int k, int d) {
  int a[2], *b, fail;
  double *c;
  a[0] = k;
  a[1] = d;
  fail = _ada_use_c2phc4c(299, a, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cpu_to_le32wu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0x1c(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    -0x1c(%rbp),%edx
  sar    $0x10,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    -0x1c(%rbp),%edx
  sar    $0x18,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cpu_to_le32wu(uint32_t *p, uint32_t v) {
  uint8_t *p1 = (uint8_t *)p;
  p1[0] = v;
  p1[1] = v >> 8;
  p1[2] = v >> 16;
  p1[3] = v >> 24;
}
```