ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<wday>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    $0xe,%eax
  sub    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  sub    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x7,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  lea    (%rcx,%rax,1),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int wday(int year, int month, int day) {
  int adjustment, mm, yy;
  adjustment = (14 - month) / 12;
  mm = month + 12 * adjustment - 2;
  yy = year - adjustment;
  return (day + (13 * mm - 1) / 5 + yy + yy / 4 - yy / 100 + yy / 400) % 7;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wday>:
  endbr64
  mov    %edi,%ecx
  mov    %edx,%edi
  mov    $0xe,%edx
  sub    %esi,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  sub    %eax,%ecx
  lea    (%rax,%rax,2),%eax
  lea    -0x2(%rsi,%rax,4),%eax
  lea    (%rax,%rax,2),%edx
  lea    -0x1(%rax,%rdx,4),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rdi,1),%edx
  add    %ecx,%edx
  lea    0x3(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x2,%eax
  add    %eax,%edx
  movslq %ecx,%rax
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rdi
  sar    $0x25,%rdi
  sar    $0x1f,%ecx
  mov    %ecx,%esi
  sub    %edi,%esi
  add    %esi,%edx
  sar    $0x27,%rax
  sub    %ecx,%eax
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int wday(int year, int month, int day) {
  int adjustment, mm, yy;
  adjustment = (14 - month) / 12;
  mm = month + 12 * adjustment - 2;
  yy = year - adjustment;
  return (day + (13 * mm - 1) / 5 + yy + yy / 4 - yy / 100 + yy / 400) % 7;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wday>:
  endbr64
  mov    %edx,%r8d
  mov    $0xe,%edx
  sub    %esi,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x21,%rax
  sub    %edx,%eax
  sub    %eax,%edi
  lea    (%rax,%rax,2),%eax
  lea    -0x2(%rsi,%rax,4),%eax
  mov    %edi,%ecx
  lea    (%rax,%rax,2),%edx
  lea    -0x1(%rax,%rdx,4),%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%r8,1),%edx
  lea    0x3(%rdi),%eax
  add    %edi,%edx
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x1f,%ecx
  sar    $0x2,%eax
  add    %eax,%edx
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rsi
  sar    $0x27,%rax
  sar    $0x25,%rsi
  sub    %ecx,%eax
  mov    %rsi,%rdi
  mov    %ecx,%esi
  sub    %edi,%esi
  add    %esi,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int wday(int year, int month, int day) {
  int adjustment, mm, yy;
  adjustment = (14 - month) / 12;
  mm = month + 12 * adjustment - 2;
  yy = year - adjustment;
  return (day + (13 * mm - 1) / 5 + yy + yy / 4 - yy / 100 + yy / 400) % 7;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L12:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foobar@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x63,-0x4(%rbp)
  jle    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void foo(void) {
  int i;
  for (i = 0; i < 100; i++) {
    foobar(i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L7:
  mov    %ebx,%edi
  call   <foobar@plt>
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
void foo(void) {
  int i;
  for (i = 0; i < 100; i++) {
    foobar(i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <foobar@plt>
  cmp    $0x64,%ebx
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
void foo(void) {
  int i;
  for (i = 0; i < 100; i++) {
    foobar(i);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <foobar@plt>
  cmp    $0x64,%ebx
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void foo(void) {
  int i;
  for (i = 0; i < 100; i++) {
    foobar(i);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcasecmp_diff_length_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D15(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D15: abc

tool: D9: aBdef

assistant: ```c
void strcasecmp_diff_length_1() {
  char *x = "abc";
  char *y = "aBdef";
  clang_analyzer_eval(strcasecmp(x, y) == -1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcasecmp_diff_length_1>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <strcasecmp@plt>
  cmp    $0xffffffff,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D11: aBdef

tool: D14: abc

assistant: ```c
void strcasecmp_diff_length_1() {
  char *x = "abc";
  char *y = "aBdef";
  clang_analyzer_eval(strcasecmp(x, y) == -1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcasecmp_diff_length_1>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  lea    D3(%rip),%rsi
  call   <strcasecmp@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1070 <clang_analyzer_eval@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D0: abc

tool: D3: aBdef

assistant: ```c
void strcasecmp_diff_length_1() {
  char *x = "abc";
  char *y = "aBdef";
  clang_analyzer_eval(strcasecmp(x, y) == -1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcasecmp_diff_length_1>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  lea    D0(%rip),%rsi
  call   <strcasecmp@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1070 <clang_analyzer_eval@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D12: abc

tool: D0: aBdef

assistant: ```c
void strcasecmp_diff_length_1() {
  char *x = "abc";
  char *y = "aBdef";
  clang_analyzer_eval(strcasecmp(x, y) == -1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_UIntOk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D19(%rip),%rax
  mov    %rax,%rdx
  mov    $0xd7,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <ASRT_Mark@plt>
  mov    $0x25,%esi
  mov    $0x25,%edi
  call   <ASRT_Int@plt>
  test   %rax,%rax
  je     L17
  mov    $0x1,%eax
  jmp    L15
L17:
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D19: 37 == 37

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cohadar/c-learning/refs/heads/master/src/asrt_tests.c

assistant: ```c
int test_UIntOk() {
  do {
    ASRT_Mark("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cohadar/c-learning/refs/heads/master/src/asrt_tests.c", 215,
              "37"
              " == "
              "37");
    if (ASRT_Int(37, 37)) {
      return 1;
    };
  } while (0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_UIntOk>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdx
  mov    $0xd7,%esi
  lea    D1(%rip),%rdi
  call   <ASRT_Mark@plt>
  mov    $0x25,%esi
  mov    $0x25,%edi
  call   <ASRT_Int@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string

tool: D6: 37 == 37

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cohadar/c-learning/refs/heads/master/src/asrt_tests.c

assistant: ```c
int test_UIntOk() {
  do {
    ASRT_Mark("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cohadar/c-learning/refs/heads/master/src/asrt_tests.c", 215,
              "37"
              " == "
              "37");
    if (ASRT_Int(37, 37)) {
      return 1;
    };
  } while (0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_UIntOk>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdx
  mov    $0xd7,%esi
  lea    D5(%rip),%rdi
  call   <ASRT_Mark@plt>
  mov    $0x25,%esi
  mov    $0x25,%edi
  call   <ASRT_Int@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string
name: retrieve_data
arguments: data_label: D5
type: string

tool: D0: 37 == 37

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cohadar/c-learning/refs/heads/master/src/asrt_tests.c

assistant: ```c
int test_UIntOk() {
  do {
    ASRT_Mark("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cohadar/c-learning/refs/heads/master/src/asrt_tests.c", 215,
              "37"
              " == "
              "37");
    if (ASRT_Int(37, 37)) {
      return 1;
    };
  } while (0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_UIntOk>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdx
  mov    $0xd7,%esi
  lea    D11(%rip),%rdi
  call   <ASRT_Mark@plt>
  mov    $0x25,%esi
  mov    $0x25,%edi
  call   <ASRT_Int@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type: string
name: retrieve_data
arguments: tag: D11
type: string

tool: D10: 37 == 37

tool: D11: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cohadar/c-learning/refs/heads/master/src/asrt_tests.c

assistant: ```c
int test_UIntOk() {
  do {
    ASRT_Mark("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cohadar/c-learning/refs/heads/master/src/asrt_tests.c", 215,
              "37"
              " == "
              "37");
    if (ASRT_Int(37, 37)) {
      return 1;
    };
  } while (0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L87:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  je     L38
  cmp    $0x3,%eax
  jg     L10
  cmp    $0x1,%eax
  je     L55
  cmp    $0x2,%eax
  je     L6
  jmp    L10
L55:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <insert@plt>
  jmp    L10
L6:
  mov    $0x0,%eax
  call   <deleteQueue@plt>
  jmp    L10
L38:
  mov    $0x0,%eax
  call   <display@plt>
  nop
L10:
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  jne    L87
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D69
datatype: string
name: disassemble_data
arguments: label: D46
datatype: string
name: disassemble_data
arguments: label: D44
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string
name: disassemble_data
arguments: label: D35
datatype: string
name: disassemble_data
arguments: label: D43
datatype: string

tool: D69: 1.Insert


tool: D46: 2.Delete


tool: D44: 3.Display


tool: D9: Enter choice: 

tool: D35: %d

tool: D43: Enter the value: 

assistant: ```c
int main() {
  int choice, value;
  printf("1.Insert\n");
  printf("2.Delete\n");
  printf("3.Display\n");
  do {
    printf("Enter choice: ");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      printf("Enter the value: ");
      scanf("%d", &value);
      insert(value);
      break;
    case 2:
      deleteQueue();
      break;
    case 3:
      display();
      break;
    }
  } while (choice != 3);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%r12
  mov    %rsp,%rbp
  lea    D57(%rip),%rbx
  lea    D16(%rip),%r13
L62:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  cmp    $0x2,%eax
  je     L64
  cmp    $0x3,%eax
  je     L53
  cmp    $0x1,%eax
  jne    L62
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <insert@plt>
L44:
  cmpl   $0x3,(%rsp)
  jne    L62
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  mov    $0x0,%eax
  call   <deleteQueue@plt>
  jmp    L44
L53:
  mov    $0x0,%eax
  call   <display@plt>
  jmp    L44
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D55
datatype: string
name: disassemble_data
arguments: tag: D33
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D36
datatype: string
name: disassemble_data
arguments: tag: D57
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string

tool: D55: 1.Insert


tool: D33: 2.Delete


tool: D1: 3.Display


tool: D36: Enter choice: 

tool: D57: %d

tool: D16: Enter the value: 

assistant: ```c
int main() {
  int choice, value;
  printf("1.Insert\n");
  printf("2.Delete\n");
  printf("3.Display\n");
  do {
    printf("Enter choice: ");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      printf("Enter the value: ");
      scanf("%d", &value);
      insert(value);
      break;
    case 2:
      deleteQueue();
      break;
    case 3:
      display();
      break;
    }
  } while (choice != 3);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D35(%rip),%rdi
  lea    D41(%rip),%r13
  push   %r12
  lea    D56(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  cmp    $0x2,%eax
  je     L58
  cmp    $0x3,%eax
  je     L63
  cmp    $0x1,%eax
  jne    L7
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <insert@plt>
  mov    (%rsp),%eax
L34:
  cmp    $0x3,%eax
  jne    L7
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  xor    %eax,%eax
  call   <display@plt>
  mov    (%rsp),%eax
  jmp    L34
  nopl   0x0(%rax)
L58:
  xor    %eax,%eax
  call   <deleteQueue@plt>
  mov    (%rsp),%eax
  jmp    L34
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D35
datatype: string
name: read_data
arguments: data_tag: D41
datatype: string
name: read_data
arguments: data_tag: D56
datatype: string
name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D32
datatype: string

tool: D35: 1.Insert


tool: D41: Enter the value: 

tool: D56: Enter choice: 

tool: D8: %d

tool: D1: 2.Delete


tool: D32: 3.Display


assistant: ```c
int main() {
  int choice, value;
  printf("1.Insert\n");
  printf("2.Delete\n");
  printf("3.Display\n");
  do {
    printf("Enter choice: ");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      printf("Enter the value: ");
      scanf("%d", &value);
      insert(value);
      break;
    case 2:
      deleteQueue();
      break;
    case 3:
      display();
      break;
    }
  } while (choice != 3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  lea    D28(%rip),%r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D49(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  cmp    $0x2,%eax
  je     L3
  cmp    $0x3,%eax
  je     L8
  cmp    $0x1,%eax
  jne    L1
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <insert@plt>
  mov    (%rsp),%eax
L61:
  cmp    $0x3,%eax
  jne    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <display@plt>
  mov    (%rsp),%eax
  jmp    L61
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  call   <deleteQueue@plt>
  mov    (%rsp),%eax
  jmp    L61
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D22
data_type: string
name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string
name: parse_data
arguments: data_tag: D49
data_type: string
name: parse_data
arguments: data_tag: D26
data_type: string
name: parse_data
arguments: data_tag: D41
data_type: string

tool: D22: 1.Insert


tool: D28: Enter the value: 

tool: D10: Enter choice: 

tool: D49: %d

tool: D26: 2.Delete


tool: D41: 3.Display


assistant: ```c
int main() {
  int choice, value;
  printf("1.Insert\n");
  printf("2.Delete\n");
  printf("3.Display\n");
  do {
    printf("Enter choice: ");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      printf("Enter the value: ");
      scanf("%d", &value);
      insert(value);
      break;
    case 2:
      deleteQueue();
      break;
    case 3:
      display();
      break;
    }
  } while (choice != 3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<closest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    %r9d,-0x48(%rbp)
  movsd  D24(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L45
L26:
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   D21(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L18
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   D21(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L18:
  addl   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L6
  addl   $0x1,-0x14(%rbp)
L45:
  mov    -0x14(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L26
  mov    -0x38(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D24
data_type: f64
name: read_data
arguments: label: D21
data_type: qword

tool: D24: 99

tool: D21: 9223372036854775807

assistant: ```c
void closest(double x[], double v[], int *ribest, double *rbest, int nx, int nv) {
  int i, j, ibest;
  double best;
  best = 99.;
  ibest = 0;
  for (i = 0; i < nx; i++) {
    for (j = 0; j < nv; j++) {
      if (fabs(x[i] - v[j]) < best) {
        best = fabs(x[i] - v[j]);
        ibest = i;
      }
    }
  }
  *ribest = ibest;
  *rbest = best;
}
```