ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<mergesort>:
  endbr64
  mov    $0x0,%eax
  cmp    %edx,%esi
  jl     L9
  ret
L9:
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  add    %esi,%r12d
  mov    %r12d,%edx
  call   <mergesort>
  mov    %eax,%r13d
  add    $0x1,%r12d
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <mergesort>
  add    %eax,%r13d
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <merge@plt>
  add    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mergesort(int arr[], int low, int high) {
  int invCount = 0;
  if (low < high) {
    int mid = low + (high - low) / 2;
    invCount = mergesort(arr, low, mid);
    invCount += mergesort(arr, mid + 1, high);
    invCount += merge(arr, low, mid + 1, high);
  }
  return invCount;
}
```
user: What is the c source code of the assembly code below:

```asm
<mergesort>:
  endbr64
  cmp    %edx,%esi
  jl     L1
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  sub    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sar    %r13d
  mov    %esi,%ebp
  push   %rbx
  add    %esi,%r13d
  mov    %r13d,%edx
  add    $0x1,%r13d
  call   <mergesort>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <mergesort>
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  add    %eax,%ebx
  call   <merge@plt>
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mergesort(int arr[], int low, int high) {
  int invCount = 0;
  if (low < high) {
    int mid = low + (high - low) / 2;
    invCount = mergesort(arr, low, mid);
    invCount += mergesort(arr, mid + 1, high);
    invCount += merge(arr, low, mid + 1, high);
  }
  return invCount;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L1
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L1:
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <freeaddrinfo@plt>
L15:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: 
Press any key to exit


assistant: ```c
void die(const char *s, int sock, struct addrinfo *res) {
  perror(s);
  if (sock)
    close(sock);
  if (res)
    freeaddrinfo(res);
  printf("\nPress any key to exit\n");
  getchar();
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %rdx,%rbx
  call   <perror@plt>
  test   %ebp,%ebp
  jne    L25
L28:
  test   %rbx,%rbx
  je     L23
  mov    %rbx,%rdi
  call   <freeaddrinfo@plt>
L23:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L28
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 
Press any key to exit


assistant: ```c
void die(const char *s, int sock, struct addrinfo *res) {
  perror(s);
  if (sock)
    close(sock);
  if (res)
    freeaddrinfo(res);
  printf("\nPress any key to exit\n");
  getchar();
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<die>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <perror@plt>
  test   %r12d,%r12d
  jne    L20
L0:
  test   %rbp,%rbp
  je     L19
  mov    %rbp,%rdi
  call   <freeaddrinfo@plt>
L19:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    10e0 <exit@plt>
  nopl   0x0(%rax)
L20:
  mov    %r12d,%edi
  call   <close@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: 
Press any key to exit


assistant: ```c
void die(const char *s, int sock, struct addrinfo *res) {
  perror(s);
  if (sock)
    close(sock);
  if (res)
    freeaddrinfo(res);
  printf("\nPress any key to exit\n");
  getchar();
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <perror@plt>
  test   %r12d,%r12d
  jne    L26
L25:
  test   %rbp,%rbp
  je     L28
  mov    %rbp,%rdi
  call   <freeaddrinfo@plt>
L28:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    10e0 <exit@plt>
  nopl   0x0(%rax)
L26:
  mov    %r12d,%edi
  call   <close@plt>
  jmp    L25
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: 
Press any key to exit


assistant: ```c
void die(const char *s, int sock, struct addrinfo *res) {
  perror(s);
  if (sock)
    close(sock);
  if (res)
    freeaddrinfo(res);
  printf("\nPress any key to exit\n");
  getchar();
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L3
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putc@plt>
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    putc(*s++);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L2:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putc@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L2
L17:
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    putc(*s++);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L9
L4:
  call   <putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L4
L9:
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    putc(*s++);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L11
L7:
  call   <putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L11:
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    putc(*s++);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reflectYchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L36:
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L29:
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x8(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%eax
  sub    -0x8(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reflectYchar(char *image, int width, int height) {
  int row, col;
  char temp;
  for (row = 0; row < (height / 2); row++) {
    for (col = 0; col < width; col++) {
      temp = image[row * width + col];
      image[row * width + col] = image[(height - row - 1) * width + col];
      image[(height - row - 1) * width + col] = temp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reflectYchar>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r13d
  shr    $0x1f,%r13d
  add    %edx,%r13d
  sar    %r13d
  cmp    $0x1,%edx
  jle    L53
  mov    %rdi,%rbx
  mov    %esi,%r11d
  lea    -0x1(%rdx),%r10d
  imul   %esi,%r10d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r14
  jmp    L17
L0:
  movslq %r12d,%r8
  lea    (%rbx,%r8,1),%rax
  lea    (%r14,%r8,1),%r9
  movslq %r10d,%rcx
L5:
  movzbl (%rax),%esi
  mov    %rax,%rdx
  sub    %r8,%rdx
  movzbl (%rdx,%rcx,1),%edi
  mov    %dil,(%rax)
  mov    %sil,(%rdx,%rcx,1)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L5
L46:
  add    $0x1,%ebp
  add    %r11d,%r12d
  sub    %r11d,%r10d
  cmp    %r13d,%ebp
  jge    L53
L17:
  test   %r11d,%r11d
  jg     L0
  jmp    L46
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void reflectYchar(char *image, int width, int height) {
  int row, col;
  char temp;
  for (row = 0; row < (height / 2); row++) {
    for (col = 0; col < width; col++) {
      temp = image[row * width + col];
      image[row * width + col] = image[(height - row - 1) * width + col];
      image[(height - row - 1) * width + col] = temp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reflectYchar>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  shr    $0x1f,%r13d
  push   %r12
  add    %edx,%r13d
  push   %rbp
  sar    %r13d
  push   %rbx
  cmp    $0x1,%edx
  jle    L14
  lea    -0x1(%rdx),%r10d
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  mov    %esi,%r11d
  imul   %esi,%r10d
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%r14
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L20:
  test   %r11d,%r11d
  jle    L12
  movslq %r12d,%r8
  movslq %r10d,%rcx
  lea    (%rbx,%r8,1),%rax
  lea    (%r14,%r8,1),%r9
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %rax,%rdx
  movzbl (%rax),%esi
  add    $0x1,%rax
  sub    %r8,%rdx
  movzbl (%rdx,%rcx,1),%edi
  mov    %dil,-0x1(%rax)
  mov    %sil,(%rdx,%rcx,1)
  cmp    %r9,%rax
  jne    L38
L12:
  add    $0x1,%ebp
  add    %r11d,%r12d
  sub    %r11d,%r10d
  cmp    %r13d,%ebp
  jl     L20
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void reflectYchar(char *image, int width, int height) {
  int row, col;
  char temp;
  for (row = 0; row < (height / 2); row++) {
    for (col = 0; col < width; col++) {
      temp = image[row * width + col];
      image[row * width + col] = image[(height - row - 1) * width + col];
      image[(height - row - 1) * width + col] = temp;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utf8_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L4:
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <utf8_charsize@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L20
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <skip_chars@plt>
  mov    %eax,-0x8(%rbp)
L20:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L4
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int utf8_strlen(const char *str) {
  char c;
  int len = 0;
  for (int i = 0; (c = str[i]) != '\0'; i++) {
    int size = utf8_charsize(c);
    if (size > 1)
      i = skip_chars(str, i, size - 1);
    len++;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<utf8_strlen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L33
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L19
L28:
  add    $0x1,%ebp
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl (%r12,%rax,1),%edi
  test   %dil,%dil
  je     L15
L19:
  movsbl %dil,%edi
  call   <utf8_charsize@plt>
  cmp    $0x1,%eax
  jle    L28
  lea    -0x1(%rax),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <skip_chars@plt>
  mov    %eax,%ebx
  jmp    L28
L33:
  mov    $0x0,%ebp
L15:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int utf8_strlen(const char *str) {
  char c;
  int len = 0;
  for (int i = 0; (c = str[i]) != '\0'; i++) {
    int size = utf8_charsize(c);
    if (size > 1)
      i = skip_chars(str, i, size - 1);
    len++;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<utf8_strlen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L27
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L26:
  call   <utf8_charsize@plt>
  cmp    $0x1,%eax
  jle    L21
  mov    %ebp,%esi
  lea    -0x1(%rax),%edx
  mov    %rbx,%rdi
  call   <skip_chars@plt>
  mov    %eax,%ebp
L21:
  add    $0x1,%ebp
  add    $0x1,%r12d
  movslq %ebp,%rax
  movsbl (%rbx,%rax,1),%edi
  test   %dil,%dil
  jne    L26
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int utf8_strlen(const char *str) {
  char c;
  int len = 0;
  for (int i = 0; (c = str[i]) != '\0'; i++) {
    int size = utf8_charsize(c);
    if (size > 1)
      i = skip_chars(str, i, size - 1);
    len++;
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utf8_strlen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L29
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L14:
  call   <utf8_charsize@plt>
  cmp    $0x1,%eax
  jg     L1
  add    $0x1,%ebp
  add    $0x1,%r12d
  movslq %ebp,%rax
  movsbl (%rbx,%rax,1),%edi
  test   %dil,%dil
  jne    L14
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L1:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  lea    -0x1(%rax),%edx
  add    $0x1,%r12d
  call   <skip_chars@plt>
  lea    0x1(%rax),%ebp
  movslq %ebp,%rax
  movsbl (%rbx,%rax,1),%edi
  test   %dil,%dil
  jne    L14
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int utf8_strlen(const char *str) {
  char c;
  int len = 0;
  for (int i = 0; (c = str[i]) != '\0'; i++) {
    int size = utf8_charsize(c);
    if (size > 1)
      i = skip_chars(str, i, size - 1);
    len++;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <qstrstr@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string

tool: D9: asbdoiwfpfqwof_11_nqoekgnwih-13r013jidnancjasnc

tool: D15: _11_

assistant: ```c
int main() {
  char *a = "asbdoiwfpfqwof_11_nqoekgnwih-13r013jidnancjasnc";
  qstrstr(a, strlen(a), "_11_");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rdx
  mov    %rbx,%rdi
  call   <qstrstr@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D11
type: string

tool: D14: asbdoiwfpfqwof_11_nqoekgnwih-13r013jidnancjasnc

tool: D11: _11_

assistant: ```c
int main() {
  char *a = "asbdoiwfpfqwof_11_nqoekgnwih-13r013jidnancjasnc";
  qstrstr(a, strlen(a), "_11_");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    D4(%rip),%rdx
  mov    %eax,%esi
  call   <qstrstr@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string

tool: D14: asbdoiwfpfqwof_11_nqoekgnwih-13r013jidnancjasnc

tool: D4: _11_

assistant: ```c
int main() {
  char *a = "asbdoiwfpfqwof_11_nqoekgnwih-13r013jidnancjasnc";
  qstrstr(a, strlen(a), "_11_");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    D3(%rip),%rdx
  mov    %eax,%esi
  call   <qstrstr@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string
name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D4: asbdoiwfpfqwof_11_nqoekgnwih-13r013jidnancjasnc

tool: D3: _11_

assistant: ```c
int main() {
  char *a = "asbdoiwfpfqwof_11_nqoekgnwih-13r013jidnancjasnc";
  qstrstr(a, strlen(a), "_11_");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mg_get_ip_address_of_nameserver>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x330,%rsp
  mov    %rdi,-0x328(%rbp)
  mov    %rsi,-0x330(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x31c(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x318(%rbp)
  cmpq   $0x0,-0x318(%rbp)
  jne    L21
  movl   $0xffffffff,-0x31c(%rbp)
  jmp    L13
L21:
  movl   $0xffffffff,-0x31c(%rbp)
  jmp    L12
L34:
  lea    -0x310(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  lea    D31(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L12
  lea    -0x310(%rbp),%rdx
  mov    -0x330(%rbp),%rsi
  mov    -0x328(%rbp),%rax
  mov    %rdx,%rcx
  lea    D16(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  movl   $0x0,-0x31c(%rbp)
  jmp    L46
L12:
  mov    -0x318(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L34
L46:
  mov    -0x318(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L13:
  mov    -0x31c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D20
type: string
name: extract_symbolic_data
arguments: data_label: D31
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string

tool: D22: r

tool: D20: /etc/resolv.conf

tool: D31: nameserver %255[^
	 #]s

tool: D16: udp://%s:53

assistant: ```c
int mg_get_ip_address_of_nameserver(char *name, size_t name_len) {
  int ret = -1;
  FILE *fp;
  char line[512];
  if ((fp = fopen("/etc/resolv.conf", "r")) == NULL) {
    ret = -1;
  } else {
    for (ret = -1; fgets(line, sizeof(line), fp) != NULL;) {
      char buf[256];
      if (sscanf(line, "nameserver %255[^\n\t #]s", buf) == 1) {
        snprintf(name, name_len, "udp://%s:53", buf);
        ret = 0;
        break;
      }
    }
    (void)fclose(fp);
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mg_get_ip_address_of_nameserver>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x318,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x308(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rsi
  lea    D38(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L58
  mov    %rax,%rbx
  lea    D30(%rip),%rbp
L7:
  lea    0x100(%rsp),%rdi
  mov    %rbx,%rdx
  mov    $0x200,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L44
  mov    %rsp,%rdx
  lea    0x100(%rsp),%rdi
  mov    %rbp,%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L7
  mov    %rsp,%rcx
  lea    D35(%rip),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    $0x0,%ebp
  jmp    L26
L44:
  mov    $0xffffffff,%ebp
L26:
  mov    %rbx,%rdi
  call   <fclose@plt>
L0:
  mov    0x308(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    %ebp,%eax
  add    $0x318,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  mov    $0xffffffff,%ebp
  jmp    L0
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string
name: read_data
arguments: data_tag: D38
data_type: string
name: read_data
arguments: data_tag: D30
data_type: string
name: read_data
arguments: data_tag: D35
data_type: string

tool: D6: r

tool: D38: /etc/resolv.conf

tool: D30: nameserver %255[^
	 #]s

tool: D35: udp://%s:53

assistant: ```c
int mg_get_ip_address_of_nameserver(char *name, size_t name_len) {
  int ret = -1;
  FILE *fp;
  char line[512];
  if ((fp = fopen("/etc/resolv.conf", "r")) == NULL) {
    ret = -1;
  } else {
    for (ret = -1; fgets(line, sizeof(line), fp) != NULL;) {
      char buf[256];
      if (sscanf(line, "nameserver %255[^\n\t #]s", buf) == 1) {
        snprintf(name, name_len, "udp://%s:53", buf);
        ret = 0;
        break;
      }
    }
    (void)fclose(fp);
  }
  return ret;
}
```