ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<testFreeNonMallocPointerWithOffset>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void testFreeNonMallocPointerWithOffset() {
  char c;
  char *r = &c;
  free(r + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<testFreeNonMallocPointerWithOffset>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void testFreeNonMallocPointerWithOffset() {
  char c;
  char *r = &c;
  free(r + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testFreeNonMallocPointerWithOffset>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void testFreeNonMallocPointerWithOffset() {
  char c;
  char *r = &c;
  free(r + 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printlbase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,%eax
  mov    %al,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jb     L6
  movzbl -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,%rdi
  mov    -0xc(%rbp),%eax
  mov    %ecx,%edx
  mov    %eax,%esi
  call   <printlbase>
L6:
  movzbl -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L3
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  lea    0x10(%rax),%rdx
  lea    D15(%rip),%rax
  add    %rdx,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <print@plt>
  jmp    L23
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  lea    D15(%rip),%rax
  add    %rdx,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <print@plt>
L23:
  nop
  leave
  ret
```

assistant: ```c
void printlbase(unsigned long l, int base, unsigned char flags) {
  static char tab[32] = "0123456789abcdef0123456789ABCDEF";
  if (l / base != 0)
    printlbase(l / base, base, flags);
  if (flags & 0x01) {
    print(&tab[(l % base) + 16], sizeof(tab[l % base]));
  } else {
    print(&tab[l % base], sizeof(tab[l % base]));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printlbase>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r12d
  movslq %esi,%rbp
  cmp    %rdi,%rbp
  jbe    L15
L16:
  test   $0x1,%r12b
  je     L23
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rbp
  lea    D5(%rip),%rax
  lea    0x10(%rax,%rdx,1),%rdi
  mov    $0x1,%esi
  call   <print@plt>
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  movzbl %dl,%ecx
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rbp
  mov    %rax,%rdi
  mov    %ecx,%edx
  call   <printlbase>
  jmp    L16
L23:
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rbp
  lea    D5(%rip),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    $0x1,%esi
  call   <print@plt>
  jmp    L7
```

assistant: ```c
void printlbase(unsigned long l, int base, unsigned char flags) {
  static char tab[32] = "0123456789abcdef0123456789ABCDEF";
  if (l / base != 0)
    printlbase(l / base, base, flags);
  if (flags & 0x01) {
    print(&tab[(l % base) + 16], sizeof(tab[l % base]));
  } else {
    print(&tab[l % base], sizeof(tab[l % base]));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printlbase>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    %rdi,%rbp
  jbe    L6
L25:
  xor    %edx,%edx
  mov    %rbx,%rax
  div    %rbp
  lea    D0(%rip),%rax
  and    $0x1,%r12d
  lea    0x10(%rax,%rdx,1),%rdi
  jne    L14
  lea    (%rdx,%rax,1),%rdi
L14:
  pop    %rbx
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  jmp    1050 <print@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  movzbl %dl,%ecx
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rbp
  mov    %ecx,%edx
  mov    %rax,%rdi
  call   <printlbase>
  jmp    L25
```

assistant: ```c
void printlbase(unsigned long l, int base, unsigned char flags) {
  static char tab[32] = "0123456789abcdef0123456789ABCDEF";
  if (l / base != 0)
    printlbase(l / base, base, flags);
  if (flags & 0x01) {
    print(&tab[(l % base) + 16], sizeof(tab[l % base]));
  } else {
    print(&tab[l % base], sizeof(tab[l % base]));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printlbase>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  movslq %esi,%rbp
  and    $0x1,%r12d
  push   %rbx
  mov    %rdi,%rbx
  cmp    %rdi,%rbp
  jbe    L48
  test   %r12b,%r12b
  lea    D29(%rip),%r12
  jne    L95
L29:
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  lea    (%r12,%rdx,1),%rdi
L38:
  pop    %rbx
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <print@plt>
  nopl   0x0(%rax,%rax,1)
L48:
  mov    %edx,%ecx
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rbp
  mov    %rax,%r13
  cmp    %rax,%rbp
  jbe    L26
  test   %r12b,%r12b
  lea    D29(%rip),%r12
  je     L54
L33:
  mov    %r13,%rax
  xor    %edx,%edx
  mov    $0x1,%esi
  div    %rbp
  lea    0x10(%r12,%rdx,1),%rdi
  call   <print@plt>
L95:
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  lea    0x10(%r12,%rdx,1),%rdi
  jmp    L38
  nopl   0x0(%rax)
L67:
  lea    (%r12,%rdx,1),%rdi
  mov    $0x1,%esi
  call   <print@plt>
L54:
  mov    %r13,%rax
  xor    %edx,%edx
  mov    $0x1,%esi
  div    %rbp
  lea    (%r12,%rdx,1),%rdi
  call   <print@plt>
  jmp    L29
  nopl   0x0(%rax)
L26:
  xor    %edx,%edx
  div    %rbp
  mov    %rax,%r14
  cmp    %rax,%rbp
  jbe    L46
L96:
  xor    %edx,%edx
  mov    %r14,%rax
  div    %rbp
  test   %r12b,%r12b
  lea    D29(%rip),%r12
  je     L67
  lea    0x10(%r12,%rdx,1),%rdi
  mov    $0x1,%esi
  call   <print@plt>
  jmp    L33
  nopl   (%rax)
L46:
  xor    %edx,%edx
  movzbl %cl,%r8d
  div    %rbp
  mov    %r8d,%edx
  mov    %rax,%rdi
  call   <printlbase>
  jmp    L96
```

assistant: ```c
void printlbase(unsigned long l, int base, unsigned char flags) {
  static char tab[32] = "0123456789abcdef0123456789ABCDEF";
  if (l / base != 0)
    printlbase(l / base, base, flags);
  if (flags & 0x01) {
    print(&tab[(l % base) + 16], sizeof(tab[l % base]));
  } else {
    print(&tab[l % base], sizeof(tab[l % base]));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L26
L66:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <isPowOfTwo@plt>
  cmp    $0x1,%eax
  jne    L15
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mult@plt>
  mov    %eax,-0x1c(%rbp)
  jmp    L28
L18:
  mov    -0x18(%rbp),%rax
  cqto
  shr    $0x3f,%rdx
  add    %rdx,%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jne    L40
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x18(%rbp)
  jmp    L63
L40:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x18(%rbp)
L63:
  addl   $0x1,-0x1c(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <isPowOfTwo@plt>
  test   %eax,%eax
  je     L18
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mult@plt>
  add    %eax,-0x1c(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x1c(%rbp)
L26:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L66
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string
name: extract_symbolic_data
arguments: label: D31
data_type: string

tool: D33: %d

tool: D18: %ld

tool: D31: %d


assistant: ```c
void main() {
  int t, k = 0;
  long int a, b;
  scanf("%d", &t);
  while (t-- != 0) {
    scanf("%ld", &a);
    scanf("%ld", &b);
    if (isPowOfTwo(a) == 1)
      k = mult(a, b);
    else {
      while (isPowOfTwo(a) == 0) {
        if (a % 2 == 1)
          a = (a - 1) / 2;
        else
          a = a / 2;
        k++;
      }
      k = k + mult(a, b);
    }
    printf("%d\n", k);
    k = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L20
  lea    0x8(%rsp),%r14
  lea    D10(%rip),%rbp
  lea    0x10(%rsp),%r13
  lea    D7(%rip),%r12
  jmp    L76
L69:
  mov    %rdx,%rax
  shr    $0x3f,%rax
  add    %rdx,%rax
  sar    %rax
L54:
  mov    %rax,0x8(%rsp)
  add    $0x1,%ebx
L35:
  mov    0x8(%rsp),%rdi
  call   <isPowOfTwo@plt>
  test   %eax,%eax
  jne    L11
  mov    0x8(%rsp),%rdx
  mov    %rdx,%rcx
  shr    $0x3f,%rcx
  lea    (%rdx,%rcx,1),%rax
  and    $0x1,%eax
  sub    %rcx,%rax
  cmp    $0x1,%rax
  jne    L69
  sub    $0x1,%rdx
  mov    %rdx,%rax
  shr    $0x3f,%rax
  add    %rdx,%rax
  sar    %rax
  jmp    L54
L11:
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <mult@plt>
  lea    (%rax,%rbx,1),%esi
L21:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L20
L76:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  call   <isPowOfTwo@plt>
  mov    $0x0,%ebx
  cmp    $0x1,%eax
  jne    L35
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <mult@plt>
  mov    %eax,%esi
  jmp    L21
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D25: %d

tool: D10: %ld

tool: D7: %d


assistant: ```c
void main() {
  int t, k = 0;
  long int a, b;
  scanf("%d", &t);
  while (t-- != 0) {
    scanf("%ld", &a);
    scanf("%ld", &b);
    if (isPowOfTwo(a) == 1)
      k = mult(a, b);
    else {
      while (isPowOfTwo(a) == 0) {
        if (a % 2 == 1)
          a = (a - 1) / 2;
        else
          a = a / 2;
        k++;
      }
      k = k + mult(a, b);
    }
    printf("%d\n", k);
    k = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L43
  lea    0x8(%rsp),%r14
  lea    D11(%rip),%rbp
  lea    0x10(%rsp),%r13
  lea    D12(%rip),%r12
  nopl   0x0(%rax)
L38:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  call   <isPowOfTwo@plt>
  cmp    $0x1,%eax
  je     L63
  mov    0x8(%rsp),%rdi
  xor    %ebx,%ebx
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    0x8(%rsp),%rdx
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%rdi
  shr    $0x3f,%rcx
  sar    %rdi
  lea    (%rdx,%rcx,1),%rax
  and    $0x1,%eax
  sub    %rcx,%rax
  cmp    $0x1,%rax
  je     L61
  mov    %rdx,%rdi
  shr    $0x3f,%rdi
  add    %rdx,%rdi
  sar    %rdi
L61:
  mov    %rdi,0x8(%rsp)
  add    $0x1,%ebx
L22:
  call   <isPowOfTwo@plt>
  test   %eax,%eax
  je     L69
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <mult@plt>
  lea    (%rax,%rbx,1),%esi
L31:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L38
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <mult@plt>
  mov    %eax,%esi
  jmp    L31
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D12
type_infered: string

tool: D6: %d

tool: D11: %ld

tool: D12: %d


assistant: ```c
void main() {
  int t, k = 0;
  long int a, b;
  scanf("%d", &t);
  while (t-- != 0) {
    scanf("%ld", &a);
    scanf("%ld", &b);
    if (isPowOfTwo(a) == 1)
      k = mult(a, b);
    else {
      while (isPowOfTwo(a) == 0) {
        if (a % 2 == 1)
          a = (a - 1) / 2;
        else
          a = a / 2;
        k++;
      }
      k = k + mult(a, b);
    }
    printf("%d\n", k);
    k = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L4
  lea    0x8(%rsp),%r14
  lea    D28(%rip),%rbp
  lea    0x10(%rsp),%r13
  lea    D14(%rip),%r12
  nopl   0x0(%rax)
L44:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  call   <isPowOfTwo@plt>
  cmp    $0x1,%eax
  je     L19
  mov    0x8(%rsp),%rdi
  xor    %ebx,%ebx
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    0x8(%rsp),%rdx
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%rdi
  shr    $0x3f,%rcx
  sar    %rdi
  lea    (%rdx,%rcx,1),%rax
  and    $0x1,%eax
  sub    %rcx,%rax
  cmp    $0x1,%rax
  je     L40
  mov    %rdx,%rdi
  shr    $0x3f,%rdi
  add    %rdx,%rdi
  sar    %rdi
L40:
  mov    %rdi,0x8(%rsp)
  add    $0x1,%ebx
L45:
  call   <isPowOfTwo@plt>
  test   %eax,%eax
  je     L7
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <mult@plt>
  lea    (%rax,%rbx,1),%esi
L50:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L44
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <mult@plt>
  mov    %eax,%esi
  jmp    L50
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D28
type: string
name: disassemble_data
arguments: data_tag: D14
type: string

tool: D0: %d

tool: D28: %ld

tool: D14: %d


assistant: ```c
void main() {
  int t, k = 0;
  long int a, b;
  scanf("%d", &t);
  while (t-- != 0) {
    scanf("%ld", &a);
    scanf("%ld", &b);
    if (isPowOfTwo(a) == 1)
      k = mult(a, b);
    else {
      while (isPowOfTwo(a) == 0) {
        if (a % 2 == 1)
          a = (a - 1) / 2;
        else
          a = a / 2;
        k++;
      }
      k = k + mult(a, b);
    }
    printf("%d\n", k);
    k = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isamax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jg     L107
  mov    $0xffffffff,%eax
  jmp    L78
L107:
  cmpl   $0x1,-0x24(%rbp)
  jne    L93
  mov    $0x0,%eax
  jmp    L78
L93:
  cmpl   $0x1,-0x28(%rbp)
  je     L81
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D26(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  add    %eax,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L75
L8:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D26(%rip),%xmm1
  andpd  %xmm1,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L86
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D26(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L86:
  addl   $0x1,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  add    %eax,-0x10(%rbp)
L75:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  mov    -0xc(%rbp),%eax
  jmp    L78
L81:
  movl   $0x0,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D26(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L28
L99:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D26(%rip),%xmm1
  andpd  %xmm1,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L118
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D26(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L118:
  addl   $0x1,-0x14(%rbp)
L28:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L99
  mov    -0xc(%rbp),%eax
L78:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D26
data_type: qword

tool: D26: 9223372036854775807

assistant: ```c
int isamax(int n, double *sx, int incx) {
  int i, ix, imax;
  double smax;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx != 1) {
    ix = 0;
    imax = 0;
    smax = fabs(sx[0]);
    ix += incx;
    for (i = 1; i < n; i++, ix += incx) {
      if (fabs(sx[ix]) > smax) {
        imax = i;
        smax = fabs(sx[ix]);
      }
    }
    return (imax);
  }
  imax = 0;
  smax = fabs(sx[0]);
  for (i = 1; i < n; i++) {
    if (fabs(sx[i]) > smax) {
      imax = i;
      smax = fabs(sx[i]);
    }
  }
  return (imax);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isamax>:
  endbr64
  test   %edi,%edi
  jle    L69
  mov    $0x0,%ecx
  cmp    $0x1,%edi
  je     L23
  cmp    $0x1,%edx
  je     L31
  movsd  (%rsi),%xmm1
  andpd  D26(%rip),%xmm1
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rdx,%rsi
  mov    $0x1,%eax
  movq   D26(%rip),%xmm2
L20:
  movsd  (%rsi),%xmm0
  andpd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  cmova  %eax,%ecx
  add    $0x1,%eax
  add    %rdx,%rsi
  cmp    %eax,%edi
  jg     L20
L23:
  mov    %ecx,%eax
  ret
L31:
  movsd  (%rsi),%xmm1
  andpd  D26(%rip),%xmm1
  mov    $0x1,%eax
  mov    $0x0,%ecx
  movq   D26(%rip),%xmm2
L36:
  movsd  (%rsi,%rax,8),%xmm0
  andpd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  cmova  %eax,%ecx
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L36
  jmp    L23
L69:
  mov    $0xffffffff,%ecx
  jmp    L23
```

tool_calls: name: parse_data
arguments: data_label: D26
data_type: qword[2]

tool: {"D26": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
int isamax(int n, double *sx, int incx) {
  int i, ix, imax;
  double smax;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx != 1) {
    ix = 0;
    imax = 0;
    smax = fabs(sx[0]);
    ix += incx;
    for (i = 1; i < n; i++, ix += incx) {
      if (fabs(sx[ix]) > smax) {
        imax = i;
        smax = fabs(sx[ix]);
      }
    }
    return (imax);
  }
  imax = 0;
  smax = fabs(sx[0]);
  for (i = 1; i < n; i++) {
    if (fabs(sx[i]) > smax) {
      imax = i;
      smax = fabs(sx[i]);
    }
  }
  return (imax);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isamax>:
  endbr64
  test   %edi,%edi
  jle    L5
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  je     L47
  movsd  (%rsi),%xmm0
  movq   D3(%rip),%xmm2
  andpd  %xmm2,%xmm0
  cmp    $0x1,%edx
  je     L1
  movslq %edx,%rdx
  mov    $0x1,%eax
  shl    $0x3,%rdx
  add    %rdx,%rsi
  nopl   0x0(%rax,%rax,1)
L33:
  movsd  (%rsi),%xmm1
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%eax
  movapd %xmm1,%xmm0
  add    %rdx,%rsi
  cmp    %eax,%edi
  jg     L33
L47:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  nopl   (%rax)
L2:
  movsd  (%rsi,%rax,8),%xmm1
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %eax,%edi
  jg     L2
  mov    %r8d,%eax
  ret
L5:
  mov    $0xffffffff,%r8d
  jmp    L47
```

tool_calls: name: parse_data
arguments: data_label: D3
type: qword

tool: D3: 9223372036854775807

assistant: ```c
int isamax(int n, double *sx, int incx) {
  int i, ix, imax;
  double smax;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx != 1) {
    ix = 0;
    imax = 0;
    smax = fabs(sx[0]);
    ix += incx;
    for (i = 1; i < n; i++, ix += incx) {
      if (fabs(sx[ix]) > smax) {
        imax = i;
        smax = fabs(sx[ix]);
      }
    }
    return (imax);
  }
  imax = 0;
  smax = fabs(sx[0]);
  for (i = 1; i < n; i++) {
    if (fabs(sx[i]) > smax) {
      imax = i;
      smax = fabs(sx[i]);
    }
  }
  return (imax);
}
```