ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<dtranspose>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %edx,%esi
  mov    %edx,%r14d
  cmovle %esi,%r14d
  mov    $0x1,%r9d
  sub    %esi,%r9d
  cmp    %r9d,%edx
  jle    L74
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%r10d
  mov    %rcx,%r15
  movslq %r9d,%rax
  lea    (%rdi,%rax,4),%rbp
  mov    %esi,%ebx
  imul   %r9d,%ebx
  mov    %r9d,%r11d
  imul   %edx,%r11d
  neg    %r11d
  movslq %edx,%rax
  lea    0x4(,%rax,4),%r8
  movslq %esi,%rax
  lea    0x4(,%rax,4),%rdi
  mov    $0x0,%esi
  mov    %r13d,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rsp)
  jmp    L40
L55:
  add    $0x1,%esi
  cmp    %r14d,%esi
  cmovg  %r14d,%esi
  test   %esi,%esi
  jle    L25
  movslq %r11d,%rax
  lea    (%r12,%rax,4),%rcx
  mov    %r9d,%eax
  neg    %eax
  cltq
  lea    (%r15,%rax,4),%rdx
  mov    $0x0,%eax
L38:
  movss  (%rcx),%xmm0
  movss  %xmm0,(%rdx)
  add    $0x1,%eax
  add    %r8,%rcx
  add    %rdi,%rdx
  cmp    %eax,%esi
  jne    L38
L25:
  add    $0x1,%r9d
  add    $0x4,%rbp
  add    %r13d,%ebx
  sub    %r10d,%r11d
  cmp    %r9d,%r10d
  je     L74
L40:
  test   %r9d,%r9d
  jle    L55
  mov    -0x4(%rsp),%eax
  lea    (%rax,%r9,1),%edx
  lea    -0x1(%rsi),%eax
  cmp    %r14d,%eax
  cmovg  %r14d,%eax
  test   %edx,%edx
  cmovg  %eax,%esi
  test   %esi,%esi
  jle    L25
  movslq %ebx,%rax
  lea    (%r15,%rax,4),%rcx
  mov    %rbp,%rdx
  mov    $0x0,%eax
L9:
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x1,%eax
  add    %r8,%rdx
  add    %rdi,%rcx
  cmp    %eax,%esi
  jne    L9
  jmp    L25
L74:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void dtranspose(float *sig, int rows, int cols, float *col) {
  int max, ud, i, k;
  if (rows >= cols) {
    max = cols;
  } else {
    max = rows;
  }
  ud = 0;
  for (i = -rows + 1; i < cols; i++) {
    if (i <= 0) {
      ud++;
      if (ud >= max)
        ud = max;
      for (k = 0; k < ud; k++) {
        col[k * rows + k - i] = sig[(k - i) * cols + k];
      }
    } else {
      if (i - cols + rows > 0) {
        ud--;
        if (ud >= max)
          ud = max;
      }
      for (k = 0; k < ud; k++) {
        col[(k + i) * rows + k] = sig[k * cols + k + i];
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dtranspose>:
  endbr64
  push   %r15
  cmp    %edx,%esi
  mov    $0x1,%r9d
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  cmovle %esi,%r12d
  sub    %esi,%r9d
  push   %rbx
  mov    %rdi,-0x8(%rsp)
  cmp    %r9d,%edx
  jle    L2
  mov    %r9d,%r11d
  movslq %r9d,%rax
  mov    %esi,%ebx
  mov    %esi,%r13d
  imul   %edx,%r11d
  lea    (%rdi,%rax,4),%rbp
  movslq %edx,%rax
  mov    %r13d,%r15d
  imul   %r9d,%ebx
  mov    %edx,%r10d
  mov    %rcx,%r14
  sub    %edx,%r15d
  lea    0x4(,%rax,4),%r8
  movslq %esi,%rax
  xor    %esi,%esi
  neg    %r11d
  lea    0x4(,%rax,4),%rdi
  nopl   0x0(%rax)
L33:
  test   %r9d,%r9d
  jle    L22
  lea    -0x1(%rsi),%eax
  lea    (%r15,%r9,1),%edx
  cmp    %r12d,%eax
  cmovg  %r12d,%eax
  test   %edx,%edx
  cmovg  %eax,%esi
  test   %esi,%esi
  jle    L49
  movslq %ebx,%rax
  mov    %rbp,%rdx
  lea    (%r14,%rax,4),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L63:
  movss  (%rdx),%xmm0
  add    $0x1,%eax
  add    %r8,%rdx
  movss  %xmm0,(%rcx)
  add    %rdi,%rcx
  cmp    %eax,%esi
  jne    L63
L49:
  add    $0x1,%r9d
  add    $0x4,%rbp
  add    %r13d,%ebx
  sub    %r10d,%r11d
  cmp    %r9d,%r10d
  jne    L33
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x1,%esi
  cmp    %r12d,%esi
  cmovg  %r12d,%esi
  test   %esi,%esi
  jle    L49
  mov    -0x8(%rsp),%rcx
  movslq %r11d,%rax
  lea    (%rcx,%rax,4),%rcx
  mov    %r9d,%eax
  neg    %eax
  cltq
  lea    (%r14,%rax,4),%rdx
  xor    %eax,%eax
  nop
L24:
  movss  (%rcx),%xmm0
  add    $0x1,%eax
  add    %r8,%rcx
  movss  %xmm0,(%rdx)
  add    %rdi,%rdx
  cmp    %eax,%esi
  jne    L24
  jmp    L49
```

assistant: ```c
void dtranspose(float *sig, int rows, int cols, float *col) {
  int max, ud, i, k;
  if (rows >= cols) {
    max = cols;
  } else {
    max = rows;
  }
  ud = 0;
  for (i = -rows + 1; i < cols; i++) {
    if (i <= 0) {
      ud++;
      if (ud >= max)
        ud = max;
      for (k = 0; k < ud; k++) {
        col[k * rows + k - i] = sig[(k - i) * cols + k];
      }
    } else {
      if (i - cols + rows > 0) {
        ud--;
        if (ud >= max)
          ud = max;
      }
      for (k = 0; k < ud; k++) {
        col[(k + i) * rows + k] = sig[k * cols + k + i];
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<dtranspose>:
  endbr64
  push   %r15
  cmp    %edx,%esi
  mov    %edx,%r8d
  push   %r14
  cmovle %esi,%r8d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x1,%edi
  sub    %esi,%edi
  push   %rbp
  push   %rbx
  cmp    %edi,%edx
  jle    L58
  mov    %esi,%ebp
  mov    %edx,%r11d
  mov    %rcx,%r14
  test   %edi,%edi
  jg     L57
  lea    -0x1(%rdx),%r13d
  xor    %eax,%eax
  mov    %edi,%ebx
  movslq %edx,%r15
  test   %r13d,%r13d
  lea    0x4(,%r15,4),%r10
  cmovg  %eax,%r13d
  imul   %edx,%ebx
  movslq %esi,%rax
  mov    %rax,-0x8(%rsp)
  lea    0x4(,%rax,4),%r9
  xor    %eax,%eax
  neg    %ebx
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x1,%eax
  cmp    %r8d,%eax
  cmovg  %r8d,%eax
  test   %eax,%eax
  jle    L89
  movslq %ebx,%rdx
  lea    (%r12,%rdx,4),%rsi
  mov    %edi,%edx
  neg    %edx
  lea    (%r14,%rdx,4),%rcx
  xor    %edx,%edx
  nop
L47:
  movss  (%rsi),%xmm0
  add    $0x1,%edx
  add    %r10,%rsi
  movss  %xmm0,(%rcx)
  add    %r9,%rcx
  cmp    %edx,%eax
  jne    L47
L89:
  add    $0x1,%edi
  sub    %r11d,%ebx
  cmp    %edi,%r13d
  jge    L12
  cmp    %edi,%r11d
  jle    L58
L14:
  mov    %edi,%r10d
  mov    -0x8(%rsp),%rsi
  movslq %edi,%rdx
  mov    %ebp,%r13d
  imul   %ebp,%r10d
  lea    (%r12,%rdx,4),%rbx
  sub    %r11d,%r13d
  lea    0x4(,%r15,4),%r12
  lea    0x4(,%rsi,4),%r9
  xchg   %ax,%ax
L43:
  lea    -0x1(%rax),%edx
  lea    0x0(%r13,%rdi,1),%ecx
  cmp    %r8d,%edx
  cmovg  %r8d,%edx
  test   %ecx,%ecx
  cmovg  %edx,%eax
  test   %eax,%eax
  jle    L68
  movslq %r10d,%rdx
  mov    %rbx,%rcx
  lea    (%r14,%rdx,4),%rsi
  xor    %edx,%edx
  nopl   0x0(%rax)
L21:
  movss  (%rcx),%xmm0
  add    $0x1,%edx
  add    %r12,%rcx
  movss  %xmm0,(%rsi)
  add    %r9,%rsi
  cmp    %eax,%edx
  jne    L21
L68:
  add    $0x1,%edi
  add    $0x4,%rbx
  add    %ebp,%r10d
  cmp    %edi,%r11d
  jg     L43
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  movslq %esi,%rbx
  xor    %eax,%eax
  movslq %edx,%r15
  mov    %rbx,-0x8(%rsp)
  jmp    L14
```

assistant: ```c
void dtranspose(float *sig, int rows, int cols, float *col) {
  int max, ud, i, k;
  if (rows >= cols) {
    max = cols;
  } else {
    max = rows;
  }
  ud = 0;
  for (i = -rows + 1; i < cols; i++) {
    if (i <= 0) {
      ud++;
      if (ud >= max)
        ud = max;
      for (k = 0; k < ud; k++) {
        col[k * rows + k - i] = sig[(k - i) * cols + k];
      }
    } else {
      if (i - cols + rows > 0) {
        ud--;
        if (ud >= max)
          ud = max;
      }
      for (k = 0; k < ud; k++) {
        col[(k + i) * rows + k] = sig[k * cols + k + i];
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D40(%rip),%rax
  mov    %rax,%rdx
  lea    D40(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D109(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D104(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdx
  lea    D40(%rip),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
L11:
  cmpl   $0x1,-0xc(%rbp)
  je     L27
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L27:
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L19:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D112(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L11
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jle    L11
  mov    -0x10(%rbp),%eax
  cmp    $0x5,%eax
  jg     L11
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D40
data_type: string
name: retrieve_data
arguments: label: D9
data_type: string
name: retrieve_data
arguments: label: D109
data_type: string
name: retrieve_data
arguments: label: D104
data_type: string
name: retrieve_data
arguments: label: D35
data_type: string
name: retrieve_data
arguments: label: D79
data_type: string
name: retrieve_data
arguments: label: D46
data_type: string
name: retrieve_data
arguments: label: D27
data_type: string
name: retrieve_data
arguments: label: D85
data_type: string
name: retrieve_data
arguments: label: D112
data_type: string

tool: D40: ***********************************************

tool: D9: 
%s%s


tool: D109: Enter the number of the desired hotel: 

tool: D104: 1) Fairfield Arms 2) Hotel Olympic

tool: D35: 3) Chertworthy Plaza 4) The Stockton

tool: D79: 5) quit

tool: D46: %s%s


tool: D27: %*s

tool: D85: Enter an integer from 1 to 5, please.

tool: D112: %d

assistant: ```c
int menu(void) {
  int code, status;
  printf("\n%s%s\n", "***********************************************", "***********************************************");
  printf("Enter the number of the desired hotel: \n");
  printf("1) Fairfield Arms 2) Hotel Olympic\n");
  printf("3) Chertworthy Plaza 4) The Stockton\n");
  printf("5) quit\n");
  printf("%s%s\n", "***********************************************", "***********************************************");
  while ((status = scanf("%d", &code)) != 1 || (code < 1 || code > 5)) {
    if (status != 1)
      scanf("%*s");
    printf("Enter an integer from 1 to 5, please.\n");
  }
  return code;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<menu>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rbx
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D84(%rip),%rdi
  call   <puts@plt>
  lea    D87(%rip),%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  lea    D72(%rip),%rbx
  lea    D17(%rip),%r13
  lea    D14(%rip),%r12
  jmp    L20
L1:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x4,%edx
  jbe    L43
L8:
  mov    %r12,%rdi
  call   <puts@plt>
L20:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L1
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L8
L43:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D24
type_guessed: string
name: disassemble_data
arguments: tag: D31
type_guessed: string
name: disassemble_data
arguments: tag: D52
type_guessed: string
name: disassemble_data
arguments: tag: D84
type_guessed: string
name: disassemble_data
arguments: tag: D87
type_guessed: string
name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D58
type_guessed: string
name: disassemble_data
arguments: tag: D72
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string

tool: D24: ***********************************************

tool: D31: 
%s%s


tool: D52: Enter the number of the desired hotel: 

tool: D84: 1) Fairfield Arms 2) Hotel Olympic

tool: D87: 3) Chertworthy Plaza 4) The Stockton

tool: D16: 5) quit

tool: D58: %s%s


tool: D72: %d

tool: D17: %*s

tool: D14: Enter an integer from 1 to 5, please.

assistant: ```c
int menu(void) {
  int code, status;
  printf("\n%s%s\n", "***********************************************", "***********************************************");
  printf("Enter the number of the desired hotel: \n");
  printf("1) Fairfield Arms 2) Hotel Olympic\n");
  printf("3) Chertworthy Plaza 4) The Stockton\n");
  printf("5) quit\n");
  printf("%s%s\n", "***********************************************", "***********************************************");
  while ((status = scanf("%d", &code)) != 1 || (code < 1 || code > 5)) {
    if (status != 1)
      scanf("%*s");
    printf("Enter an integer from 1 to 5, please.\n");
  }
  return code;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<menu>:
  endbr64
  push   %r13
  lea    D71(%rip),%rdi
  lea    D77(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D86(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    D84(%rip),%rdi
  call   <puts@plt>
  lea    D74(%rip),%rdi
  call   <puts@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D66(%rip),%rdi
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
L26:
  mov    %r12,%rdi
  call   <puts@plt>
L22:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L25
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x4,%edx
  ja     L26
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D71
data_type: string
name: unpack_data
arguments: data_tag: D77
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string
name: unpack_data
arguments: data_tag: D8
data_type: string
name: unpack_data
arguments: data_tag: D86
data_type: string
name: unpack_data
arguments: data_tag: D40
data_type: string
name: unpack_data
arguments: data_tag: D84
data_type: string
name: unpack_data
arguments: data_tag: D74
data_type: string
name: unpack_data
arguments: data_tag: D37
data_type: string
name: unpack_data
arguments: data_tag: D66
data_type: string

tool: D71: 
%s%s


tool: D77: %*s

tool: D2: Enter an integer from 1 to 5, please.

tool: D8: ***********************************************

tool: D86: %d

tool: D40: Enter the number of the desired hotel: 

tool: D84: 1) Fairfield Arms 2) Hotel Olympic

tool: D74: 3) Chertworthy Plaza 4) The Stockton

tool: D37: 5) quit

tool: D66: %s%s


assistant: ```c
int menu(void) {
  int code, status;
  printf("\n%s%s\n", "***********************************************", "***********************************************");
  printf("Enter the number of the desired hotel: \n");
  printf("1) Fairfield Arms 2) Hotel Olympic\n");
  printf("3) Chertworthy Plaza 4) The Stockton\n");
  printf("5) quit\n");
  printf("%s%s\n", "***********************************************", "***********************************************");
  while ((status = scanf("%d", &code)) != 1 || (code < 1 || code > 5)) {
    if (status != 1)
      scanf("%*s");
    printf("Enter an integer from 1 to 5, please.\n");
  }
  return code;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<menu>:
  endbr64
  push   %r13
  lea    D92(%rip),%rdi
  lea    D21(%rip),%r13
  push   %r12
  lea    D64(%rip),%r12
  push   %rbp
  lea    D43(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D61(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <puts@plt>
  lea    D93(%rip),%rdi
  call   <puts@plt>
  lea    D71(%rip),%rdi
  call   <puts@plt>
  lea    D65(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D97(%rip),%rdi
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
L24:
  mov    %r12,%rdi
  call   <puts@plt>
L20:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L28
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x4,%edx
  ja     L24
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D92
data_type: string
name: parse_data
arguments: tag: D21
data_type: string
name: parse_data
arguments: tag: D64
data_type: string
name: parse_data
arguments: tag: D43
data_type: string
name: parse_data
arguments: tag: D61
data_type: string
name: parse_data
arguments: tag: D62
data_type: string
name: parse_data
arguments: tag: D93
data_type: string
name: parse_data
arguments: tag: D71
data_type: string
name: parse_data
arguments: tag: D65
data_type: string
name: parse_data
arguments: tag: D97
data_type: string

tool: D92: 
%s%s


tool: D21: %*s

tool: D64: Enter an integer from 1 to 5, please.

tool: D43: ***********************************************

tool: D61: %d

tool: D62: Enter the number of the desired hotel: 

tool: D93: 1) Fairfield Arms 2) Hotel Olympic

tool: D71: 3) Chertworthy Plaza 4) The Stockton

tool: D65: 5) quit

tool: D97: %s%s


assistant: ```c
int menu(void) {
  int code, status;
  printf("\n%s%s\n", "***********************************************", "***********************************************");
  printf("Enter the number of the desired hotel: \n");
  printf("1) Fairfield Arms 2) Hotel Olympic\n");
  printf("3) Chertworthy Plaza 4) The Stockton\n");
  printf("5) quit\n");
  printf("%s%s\n", "***********************************************", "***********************************************");
  while ((status = scanf("%d", &code)) != 1 || (code < 1 || code > 5)) {
    if (status != 1)
      scanf("%*s");
    printf("Enter an integer from 1 to 5, please.\n");
  }
  return code;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ssd1306_i2cDataStart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ssd1306_startTransmission@plt>
  mov    $0x40,%edi
  call   <ssd1306_sendByte@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ssd1306_i2cDataStart() {
  ssd1306_startTransmission();
  ssd1306_sendByte(0x40);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ssd1306_i2cDataStart>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ssd1306_startTransmission@plt>
  mov    $0x40,%edi
  call   <ssd1306_sendByte@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ssd1306_i2cDataStart() {
  ssd1306_startTransmission();
  ssd1306_sendByte(0x40);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ssd1306_i2cDataStart>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ssd1306_startTransmission@plt>
  mov    $0x40,%edi
  add    $0x8,%rsp
  jmp    1070 <ssd1306_sendByte@plt>
```

assistant: ```c
void ssd1306_i2cDataStart() {
  ssd1306_startTransmission();
  ssd1306_sendByte(0x40);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ssd1306_i2cDataStart>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ssd1306_startTransmission@plt>
  mov    $0x40,%edi
  add    $0x8,%rsp
  jmp    1070 <ssd1306_sendByte@plt>
```

assistant: ```c
void ssd1306_i2cDataStart() {
  ssd1306_startTransmission();
  ssd1306_sendByte(0x40);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<enddata>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x3f,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L4
  mov    -0x1c(%rbp),%eax
  jmp    L12
L4:
  mov    -0x8(%rbp),%eax
  lea    -0x41(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0x40,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int enddata(char *buff, int p) {
  int pageaddr, offset;
  offset = p & 63;
  pageaddr = p - offset;
  if (offset == 0)
    return p;
  buff[pageaddr] = 0xC0 + offset - 1;
  p = pageaddr + 64;
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<enddata>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  and    $0x3f,%eax
  je     L9
  sub    %eax,%esi
  movslq %esi,%rdx
  sub    $0x41,%eax
  mov    %al,(%rdi,%rdx,1)
  lea    0x40(%rsi),%edx
L9:
  mov    %edx,%eax
  ret
```

assistant: ```c
int enddata(char *buff, int p) {
  int pageaddr, offset;
  offset = p & 63;
  pageaddr = p - offset;
  if (offset == 0)
    return p;
  buff[pageaddr] = 0xC0 + offset - 1;
  p = pageaddr + 64;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<enddata>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  and    $0x3f,%edx
  je     L3
  sub    %edx,%eax
  sub    $0x41,%edx
  movslq %eax,%rcx
  add    $0x40,%eax
  mov    %dl,(%rdi,%rcx,1)
L3:
  ret
```

assistant: ```c
int enddata(char *buff, int p) {
  int pageaddr, offset;
  offset = p & 63;
  pageaddr = p - offset;
  if (offset == 0)
    return p;
  buff[pageaddr] = 0xC0 + offset - 1;
  p = pageaddr + 64;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<enddata>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  and    $0x3f,%edx
  je     L8
  sub    %edx,%eax
  sub    $0x41,%edx
  movslq %eax,%rcx
  add    $0x40,%eax
  mov    %dl,(%rdi,%rcx,1)
L8:
  ret
```

assistant: ```c
int enddata(char *buff, int p) {
  int pageaddr, offset;
  offset = p & 63;
  pageaddr = p - offset;
  if (offset == 0)
    return p;
  buff[pageaddr] = 0xC0 + offset - 1;
  p = pageaddr + 64;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mockup_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  movl   $0x4,(%rax)
L7:
  mov    $0x4,%eax
  pop    %rbp
  ret
```

assistant: ```c
int mockup_4(void *user_data) {
  if (user_data != NULL) {
    *((int *)user_data) = 4;
  }
  return 4;
}
```
user: What is the c source code of the assembly code below:

```asm
<mockup_4>:
  endbr64
  test   %rdi,%rdi
  je     L9
  movl   $0x4,(%rdi)
L9:
  mov    $0x4,%eax
  ret
```

assistant: ```c
int mockup_4(void *user_data) {
  if (user_data != NULL) {
    *((int *)user_data) = 4;
  }
  return 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mockup_4>:
  endbr64
  test   %rdi,%rdi
  je     L0
  movl   $0x4,(%rdi)
L0:
  mov    $0x4,%eax
  ret
```

assistant: ```c
int mockup_4(void *user_data) {
  if (user_data != NULL) {
    *((int *)user_data) = 4;
  }
  return 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mockup_4>:
  endbr64
  test   %rdi,%rdi
  je     L2
  movl   $0x4,(%rdi)
L2:
  mov    $0x4,%eax
  ret
```

assistant: ```c
int mockup_4(void *user_data) {
  if (user_data != NULL) {
    *((int *)user_data) = 4;
  }
  return 4;
}
```