ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  jne    L68
L53:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,0x14(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r15d
  mov    %eax,0x18(%rsp)
  call   <strlen@plt>
  mov    %ebx,%ecx
  sub    %r12d,%ecx
  sub    %r15d,%eax
  mov    %eax,0x1c(%rsp)
  js     L58
  xor    %ebx,%ebx
  xor    %r9d,%r9d
  lea    D20(%rip),%rbp
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L63:
  mov    %ecx,%r15d
  movslq %ebx,%rdi
  lea    (%r12,%r8,1),%rsi
  mov    %ecx,0x8(%rsp)
  sub    %r9d,%r15d
  add    %rbp,%rdi
  mov    %r15d,%edx
  add    %r15d,%ebx
  call   <strncpy@plt>
  movslq %ebx,%rdi
  mov    %r14,%rsi
  add    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%ecx
  mov    0x18(%rsp),%eax
  mov    %r13,%rsi
  add    0x14(%rsp),%ebx
  lea    (%rax,%rcx,1),%r9d
  movslq %r9d,%r8
  mov    %r9d,0x10(%rsp)
  lea    (%r12,%r8,1),%r15
  mov    %r8,0x8(%rsp)
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    0x8(%rsp),%r8
  mov    0x10(%rsp),%r9d
  test   %rax,%rax
  mov    %rax,%rcx
  jne    L38
L60:
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
L39:
  mov    %r15,%rsi
  lea    D20(%rip),%r12
  call   <strcpy@plt>
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L38:
  sub    %r12d,%ecx
  cmp    %r9d,0x1c(%rsp)
  jge    L63
  jmp    L60
L58:
  mov    %r12,%r15
  lea    D20(%rip),%rdi
  jmp    L39
```

assistant: ```c
char *replace(char *string, char *oldpiece, char *newpiece) {
  int str_index, newstr_index, oldpiece_index, end, new_len, old_len, cpy_len;
  char *c;
  static char newstring[10000];
  if ((c = (char *)strstr(string, oldpiece)) == NULL)
    return string;
  new_len = strlen(newpiece);
  old_len = strlen(oldpiece);
  end = strlen(string) - old_len;
  oldpiece_index = c - string;
  newstr_index = 0;
  str_index = 0;
  while (str_index <= end && c != NULL) {
    cpy_len = oldpiece_index - str_index;
    strncpy(newstring + newstr_index, string + str_index, cpy_len);
    newstr_index += cpy_len;
    str_index += cpy_len;
    strcpy(newstring + newstr_index, newpiece);
    newstr_index += new_len;
    str_index += old_len;
    if ((c = (char *)strstr(string + str_index, oldpiece)) != NULL)
      oldpiece_index = c - string;
  }
  strcpy(newstring + newstr_index, string + str_index);
  return newstring;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  jne    L20
L14:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,0x14(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r15d
  mov    %eax,0x18(%rsp)
  call   <strlen@plt>
  mov    %ebx,%ecx
  sub    %r12d,%ecx
  sub    %r15d,%eax
  mov    %eax,0x1c(%rsp)
  js     L55
  xor    %ebx,%ebx
  xor    %r9d,%r9d
  lea    D9(%rip),%rbp
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %ecx,%r15d
  movslq %ebx,%rdi
  lea    (%r12,%r8,1),%rsi
  mov    %ecx,0x8(%rsp)
  sub    %r9d,%r15d
  add    %rbp,%rdi
  mov    %r15d,%edx
  add    %r15d,%ebx
  call   <strncpy@plt>
  movslq %ebx,%rdi
  mov    %r14,%rsi
  add    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%ecx
  mov    0x18(%rsp),%eax
  mov    %r13,%rsi
  add    0x14(%rsp),%ebx
  lea    (%rax,%rcx,1),%r9d
  movslq %r9d,%r8
  mov    %r9d,0x10(%rsp)
  lea    (%r12,%r8,1),%r15
  mov    %r8,0x8(%rsp)
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    0x8(%rsp),%r8
  mov    0x10(%rsp),%r9d
  test   %rax,%rax
  mov    %rax,%rcx
  jne    L47
L53:
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
L63:
  mov    %r15,%rsi
  lea    D9(%rip),%r12
  call   <strcpy@plt>
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L47:
  sub    %r12d,%ecx
  cmp    %r9d,0x1c(%rsp)
  jge    L33
  jmp    L53
L55:
  mov    %r12,%r15
  lea    D9(%rip),%rdi
  jmp    L63
```

assistant: ```c
char *replace(char *string, char *oldpiece, char *newpiece) {
  int str_index, newstr_index, oldpiece_index, end, new_len, old_len, cpy_len;
  char *c;
  static char newstring[10000];
  if ((c = (char *)strstr(string, oldpiece)) == NULL)
    return string;
  new_len = strlen(newpiece);
  old_len = strlen(oldpiece);
  end = strlen(string) - old_len;
  oldpiece_index = c - string;
  newstr_index = 0;
  str_index = 0;
  while (str_index <= end && c != NULL) {
    cpy_len = oldpiece_index - str_index;
    strncpy(newstring + newstr_index, string + str_index, cpy_len);
    newstr_index += cpy_len;
    str_index += cpy_len;
    strcpy(newstring + newstr_index, newpiece);
    newstr_index += new_len;
    str_index += old_len;
    if ((c = (char *)strstr(string + str_index, oldpiece)) != NULL)
      oldpiece_index = c - string;
  }
  strcpy(newstring + newstr_index, string + str_index);
  return newstring;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rbx
L29:
  lea    -0x2c(%rbp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x270f,%edx
  ja     L29
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L114:
  cmp    %rdx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L114
L18:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L12
  orq    $0x0,-0x8(%rsp,%rax,1)
L12:
  mov    %rsp,%rbx
  mov    $0x0,%r12d
L48:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x288df0cb,%rdx,%rdx
  sar    $0x24,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx,%r12,4)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%r12
  cmp    %r12d,%eax
  jg     L48
  test   %eax,%eax
  jle    L78
  lea    -0x1(%rax),%r10d
  mov    %rbx,%rsi
  mov    $0x0,%r8d
  lea    -0x2(%rax),%r9d
  lea    0x4(%rbx),%r11
  jmp    L41
L15:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L75
L105:
  mov    0x4(%rax),%ecx
  mov    (%rsi),%edx
  cmp    %edx,%ecx
  jge    L15
  mov    %ecx,(%rsi)
  mov    %edx,0x4(%rax)
  jmp    L15
L75:
  add    $0x1,%r8
  add    $0x4,%rsi
L41:
  cmp    %r10,%r8
  je     L10
  mov    %r9d,%eax
  sub    %r8d,%eax
  add    %r8,%rax
  lea    (%r11,%rax,4),%rdi
  mov    %rsi,%rax
  jmp    L105
L10:
  mov    $0x0,%r12d
  lea    D4(%rip),%r13
L110:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12
  cmp    %r12d,-0x2c(%rbp)
  jg     L110
L78:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L122
  mov    $0x0,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L122:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D4
data_type: string

tool: D7: %d

tool: D4: %4d

assistant: ```c
main() {
  int i, nl, k, j;
  do {
    scanf("%d", &nl);
  } while ((nl <= 0) || (nl > 10000));
  int a[nl];
  for (i = 0; i < nl; i++) {
    a[i] = rand() % 101;
  }
  for (i = 0; i < nl; i++) {
    for (j = i + 1; j < nl; j++) {
      if (a[j] < a[i]) {
        k = a[i];
        a[i] = a[j];
        a[j] = k;
      }
    }
  }
  for (i = 0; i < nl; i++) {
    printf("%4d", a[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    -0x2c(%rbp),%r12
  push   %rbx
  lea    D10(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  lea    -0x1(%rax),%edx
  cmp    $0x270f,%edx
  ja     L8
  lea    0xf(,%rax,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L88
L77:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L77
L88:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L5
L71:
  mov    %rsp,%rbx
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L111:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x288df0cb,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x24,%rdx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx,%r12,4)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%r12
  cmp    %r12d,%eax
  jg     L111
  test   %eax,%eax
  jle    L92
  lea    -0x1(%rax),%r10d
  xor    %r8d,%r8d
  lea    -0x2(%rax),%r9d
  mov    %rbx,%rsi
  lea    0x4(%rbx),%r11
  cmp    %r10,%r8
  je     L113
  nopl   0x0(%rax)
L116:
  mov    %r9d,%eax
  sub    %r8d,%eax
  add    %r8,%rax
  lea    (%r11,%rax,4),%rdi
  mov    %rsi,%rax
L60:
  mov    0x4(%rax),%ecx
  mov    (%rsi),%edx
  cmp    %edx,%ecx
  jge    L13
  mov    %ecx,(%rsi)
  mov    %edx,0x4(%rax)
L13:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L60
  add    $0x1,%r8
  add    $0x4,%rsi
  cmp    %r10,%r8
  jne    L116
L113:
  xor    %r12d,%r12d
  lea    D9(%rip),%r13
  xchg   %ax,%ax
L55:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L55
L92:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  lea    -0x18(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L5:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L71
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type: string
name: read_data
arguments: data_label: D9
type: string

tool: D10: %d

tool: D9: %4d

assistant: ```c
main() {
  int i, nl, k, j;
  do {
    scanf("%d", &nl);
  } while ((nl <= 0) || (nl > 10000));
  int a[nl];
  for (i = 0; i < nl; i++) {
    a[i] = rand() % 101;
  }
  for (i = 0; i < nl; i++) {
    for (j = i + 1; j < nl; j++) {
      if (a[j] < a[i]) {
        k = a[i];
        a[i] = a[j];
        a[j] = k;
      }
    }
  }
  for (i = 0; i < nl; i++) {
    printf("%4d", a[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    -0x2c(%rbp),%r12
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L97:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  lea    -0x1(%rax),%edx
  cmp    $0x270f,%edx
  ja     L97
  lea    0xf(,%rax,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L65
L111:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L111
L65:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L2
L28:
  mov    %rsp,%rbx
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L57:
  xor    %eax,%eax
  call   <rand@plt>
  mov    -0x2c(%rbp),%edi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x288df0cb,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x24,%rdx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,%edi
  jg     L57
  test   %edi,%edi
  jle    L45
  mov    %rbx,%rsi
  movslq %edi,%r9
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  je     L87
  cs nopw 0x0(%rax,%rax,1)
L48:
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L54:
  mov    (%rbx,%rax,4),%ecx
  mov    (%rsi),%edx
  cmp    %edx,%ecx
  jge    L30
  mov    %ecx,(%rsi)
  mov    %edx,(%rbx,%rax,4)
L30:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L54
  add    $0x1,%r8
  add    $0x4,%rsi
  cmp    %r9,%r8
  jne    L48
L87:
  xor    %r12d,%r12d
  lea    D3(%rip),%r13
  nopl   (%rax)
L91:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L91
L45:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L114
  lea    -0x18(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L2:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L28
L114:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string

tool: D12: %d

tool: D3: %4d

assistant: ```c
main() {
  int i, nl, k, j;
  do {
    scanf("%d", &nl);
  } while ((nl <= 0) || (nl > 10000));
  int a[nl];
  for (i = 0; i < nl; i++) {
    a[i] = rand() % 101;
  }
  for (i = 0; i < nl; i++) {
    for (j = i + 1; j < nl; j++) {
      if (a[j] < a[i]) {
        k = a[i];
        a[i] = a[j];
        a[j] = k;
      }
    }
  }
  for (i = 0; i < nl; i++) {
    printf("%4d", a[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<softfloat_sub1XM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    $0x1,%rdx
  mov    %rdx,(%rax)
  cmpq   $0x0,-0x8(%rbp)
  jne    L22
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L22
  addl   $0x1,-0x10(%rbp)
  jmp    L15
L22:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void softfloat_sub1XM(uint_fast8_t size_words, uint32_t *zPtr) {
  unsigned int index, lastIndex;
  uint32_t wordA;
  index = 0;
  lastIndex = ((size_words)-1);
  for (;;) {
    wordA = zPtr[index];
    zPtr[index] = wordA - 1;
    if (wordA || (index == lastIndex))
      break;
    index += 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<softfloat_sub1XM>:
  endbr64
  sub    $0x1,%edi
  mov    (%rsi),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  test   %rax,%rax
  jne    L21
  test   %edi,%edi
  je     L21
L16:
  add    $0x1,%eax
  mov    %eax,%edx
  lea    (%rsi,%rdx,8),%rcx
  mov    (%rcx),%rdx
  lea    -0x1(%rdx),%r8
  mov    %r8,(%rcx)
  test   %rdx,%rdx
  jne    L21
  cmp    %eax,%edi
  jne    L16
L21:
  ret
```

assistant: ```c
void softfloat_sub1XM(uint_fast8_t size_words, uint32_t *zPtr) {
  unsigned int index, lastIndex;
  uint32_t wordA;
  index = 0;
  lastIndex = ((size_words)-1);
  for (;;) {
    wordA = zPtr[index];
    zPtr[index] = wordA - 1;
    if (wordA || (index == lastIndex))
      break;
    index += 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<softfloat_sub1XM>:
  endbr64
  mov    (%rsi),%rax
  sub    $0x1,%edi
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  test   %rax,%rax
  jne    L20
  test   %edi,%edi
  je     L20
  nopw   0x0(%rax,%rax,1)
L24:
  lea    0x1(%rax),%edx
  lea    (%rsi,%rdx,8),%rcx
  mov    %rdx,%rax
  mov    (%rcx),%rdx
  lea    -0x1(%rdx),%r8
  mov    %r8,(%rcx)
  test   %rdx,%rdx
  jne    L20
  cmp    %eax,%edi
  jne    L24
L20:
  ret
```

assistant: ```c
void softfloat_sub1XM(uint_fast8_t size_words, uint32_t *zPtr) {
  unsigned int index, lastIndex;
  uint32_t wordA;
  index = 0;
  lastIndex = ((size_words)-1);
  for (;;) {
    wordA = zPtr[index];
    zPtr[index] = wordA - 1;
    if (wordA || (index == lastIndex))
      break;
    index += 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<softfloat_sub1XM>:
  endbr64
  mov    (%rsi),%rax
  sub    $0x1,%edi
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  test   %rax,%rax
  jne    L33
  test   %edi,%edi
  je     L33
  nopw   0x0(%rax,%rax,1)
L1:
  lea    0x1(%rax),%edx
  lea    (%rsi,%rdx,8),%rcx
  mov    %rdx,%rax
  mov    (%rcx),%rdx
  lea    -0x1(%rdx),%r8
  mov    %r8,(%rcx)
  test   %rdx,%rdx
  jne    L33
  cmp    %eax,%edi
  jne    L1
L33:
  ret
```

assistant: ```c
void softfloat_sub1XM(uint_fast8_t size_words, uint32_t *zPtr) {
  unsigned int index, lastIndex;
  uint32_t wordA;
  index = 0;
  lastIndex = ((size_words)-1);
  for (;;) {
    wordA = zPtr[index];
    zPtr[index] = wordA - 1;
    if (wordA || (index == lastIndex))
      break;
    index += 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_pdb_coordinates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %r8,-0x68(%rbp)
  mov    %r9,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    $0x32,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmpq   $0x0,-0x50(%rbp)
  je     L3
  mov    -0x48(%rbp),%rax
  lea    0x1e(%rax),%rcx
  lea    -0x40(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x50(%rbp),%rax
  movss  %xmm0,(%rax)
L3:
  cmpq   $0x0,-0x58(%rbp)
  je     L21
  mov    -0x48(%rbp),%rax
  lea    0x26(%rax),%rcx
  lea    -0x40(%rbp),%rax
  add    $0xa,%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x40(%rbp),%rax
  add    $0xa,%rax
  mov    %rax,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x58(%rbp),%rax
  movss  %xmm0,(%rax)
L21:
  cmpq   $0x0,-0x60(%rbp)
  je     L13
  mov    -0x48(%rbp),%rax
  lea    0x2e(%rax),%rcx
  lea    -0x40(%rbp),%rax
  add    $0x14,%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x40(%rbp),%rax
  add    $0x14,%rax
  mov    %rax,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x60(%rbp),%rax
  movss  %xmm0,(%rax)
L13:
  cmpq   $0x0,-0x68(%rbp)
  je     L44
  mov    -0x48(%rbp),%rax
  lea    0x36(%rax),%rcx
  lea    -0x40(%rbp),%rax
  add    $0x1e,%rax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x40(%rbp),%rax
  add    $0x1e,%rax
  mov    %rax,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x68(%rbp),%rax
  movss  %xmm0,(%rax)
L44:
  cmpq   $0x0,-0x70(%rbp)
  je     L36
  mov    -0x48(%rbp),%rax
  lea    0x3c(%rax),%rcx
  lea    -0x40(%rbp),%rax
  add    $0x28,%rax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x40(%rbp),%rax
  add    $0x28,%rax
  mov    %rax,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x70(%rbp),%rax
  movss  %xmm0,(%rax)
L36:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

assistant: ```c
void get_pdb_coordinates(const char *record, float *x, float *y, float *z, float *occup, float *beta) {
  char numstr[50];
  memset(numstr, 0, sizeof(numstr));
  if (x != NULL) {
    strncpy(numstr, record + 30, 8);
    *x = (float)atof(numstr);
  }
  if (y != NULL) {
    strncpy(numstr + 10, record + 38, 8);
    *y = (float)atof(numstr + 10);
  }
  if (z != NULL) {
    strncpy(numstr + 20, record + 46, 8);
    *z = (float)atof(numstr + 20);
  }
  if (occup != NULL) {
    strncpy(numstr + 30, record + 54, 6);
    *occup = (float)atof(numstr + 30);
  }
  if (beta != NULL) {
    strncpy(numstr + 40, record + 60, 6);
    *beta = (float)atof(numstr + 40);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_pdb_coordinates>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r15
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %r8,%r12
  mov    %r9,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x32,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %r15,%r15
  je     L19
  lea    0x1e(%rbx),%rsi
  lea    0x10(%rsp),%rax
  mov    $0x8,%edx
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    0x8(%rsp),%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%r15)
L19:
  test   %r14,%r14
  je     L36
  lea    0x26(%rbx),%rsi
  lea    0x1a(%rsp),%r15
  mov    $0x8,%edx
  mov    %r15,%rdi
  call   <strncpy@plt>
  mov    %r15,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%r14)
L36:
  test   %r13,%r13
  je     L10
  lea    0x2e(%rbx),%rsi
  lea    0x24(%rsp),%r14
  mov    $0x8,%edx
  mov    %r14,%rdi
  call   <strncpy@plt>
  mov    %r14,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%r13)
L10:
  test   %r12,%r12
  je     L15
  lea    0x36(%rbx),%rsi
  lea    0x2e(%rsp),%r13
  mov    $0x6,%edx
  mov    %r13,%rdi
  call   <strncpy@plt>
  mov    %r13,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%r12)
L15:
  test   %rbp,%rbp
  je     L42
  lea    0x3c(%rbx),%rsi
  lea    0x38(%rsp),%rbx
  mov    $0x6,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rdi
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp)
L42:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_pdb_coordinates(const char *record, float *x, float *y, float *z, float *occup, float *beta) {
  char numstr[50];
  memset(numstr, 0, sizeof(numstr));
  if (x != NULL) {
    strncpy(numstr, record + 30, 8);
    *x = (float)atof(numstr);
  }
  if (y != NULL) {
    strncpy(numstr + 10, record + 38, 8);
    *y = (float)atof(numstr + 10);
  }
  if (z != NULL) {
    strncpy(numstr + 20, record + 46, 8);
    *z = (float)atof(numstr + 20);
  }
  if (occup != NULL) {
    strncpy(numstr + 30, record + 54, 6);
    *occup = (float)atof(numstr + 30);
  }
  if (beta != NULL) {
    strncpy(numstr + 40, record + 60, 6);
    *beta = (float)atof(numstr + 40);
  }
}
```