user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rdi
  mov    $0xc,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  lea    0x40(%rsp),%rbp
  lea    0x54(%rsp),%r15
  mov    %r15,%r12
  mov    $0x0,%r14d
  lea    D11(%rip),%r13
L46:
  add    $0x1,%r14d
  mov    %r14d,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%r12),%rbx
L20:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L20
  add    $0x14,%r12
  cmp    $0x5,%r14d
  jne    L46
  mov    %rsp,%r12
  lea    0x64(%rbp),%rsi
  mov    %rbp,%rdx
  mov    %r12,%rcx
L6:
  mov    (%rdx),%eax
  add    (%rcx),%eax
  add    0x4(%rdx),%eax
  add    0x8(%rdx),%eax
  add    0xc(%rdx),%eax
  add    0x10(%rdx),%eax
  mov    %eax,(%rcx)
  add    $0x4,%rcx
  add    $0x14,%rdx
  cmp    %rsi,%rdx
  jne    L6
  lea    0x20(%rsp),%rbx
  mov    %rbx,%rdx
L2:
  mov    (%rdx),%eax
  add    0x0(%rbp),%eax
  add    0x14(%rbp),%eax
  add    0x28(%rbp),%eax
  add    0x3c(%rbp),%eax
  add    0x50(%rbp),%eax
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  add    $0x4,%rbp
  cmp    %r15,%rbp
  jne    L2
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%r12),%r13
  lea    D34(%rip),%rbp
L39:
  mov    (%r12),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r12
  cmp    %r12,%r13
  jne    L39
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rbx),%r12
  lea    D34(%rip),%rbp
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    $0x0,%eax
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type: string
name: unpack_data
arguments: tag: D25
type: string
name: unpack_data
arguments: tag: D2
type: string
name: unpack_data
arguments: tag: D34
type: string
name: unpack_data
arguments: tag: D42
type: string

tool: D11: %d

tool: D25: enter a row %d


tool: D2: row totals:

tool: D34: %d 

tool: D42: column totals:

assistant: ```c
int main(void) {
  int array[5][5] = {{0}};
  int row_totals[5] = {0}, column_totals[5] = {0};
  for (int i = 0; i < 5; i++) {
    printf("enter a row %d\n", i + 1);
    for (int j = 0; j < 5; j++) {
      scanf("%d", &array[i][j]);
    }
  }
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 5; j++) {
      row_totals[i] += array[i][j];
    }
  }
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 5; j++) {
      column_totals[i] += array[j][i];
    }
  }
  printf("row totals:");
  for (int i = 0; i < 5; i++) {
    printf("%d ", row_totals[i]);
  }
  printf("\n");
  printf("column totals:");
  for (int i = 0; i < 5; i++) {
    printf("%d ", column_totals[i]);
  }
  printf("\n");
  return 0;
}
```