ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mygetline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L23:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L39:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L10
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L10
  cmpl   $0xa,-0xc(%rbp)
  jne    L23
L10:
  cmpl   $0xa,-0xc(%rbp)
  jne    L29
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L29:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
int mygetline(char *s, int lim) {
  int c;
  char *t = s;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n')
    *t++ = c;
  if (c == '\n')
    *t++ = c;
  *t = '\0';
  return t - s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mygetline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  cmp    $0x1,%esi
  jle    L60
  lea    -0x2(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    %rdi,%rbx
L66:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L19
  cmp    $0xa,%eax
  je     L19
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %r12,%rbx
  jne    L66
  mov    %r12,%rbx
  jmp    L44
L60:
  mov    %rdi,%rbx
L19:
  cmp    $0xa,%eax
  je     L22
L44:
  movb   $0x0,(%rbx)
  mov    %ebx,%eax
  sub    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  movb   $0xa,(%rbx)
  lea    0x1(%rbx),%rbx
  jmp    L44
```

assistant: ```c
int mygetline(char *s, int lim) {
  int c;
  char *t = s;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n')
    *t++ = c;
  if (c == '\n')
    *t++ = c;
  *t = '\0';
  return t - s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mygetline>:
  endbr64
  push   %r13
  mov    %rdi,%rcx
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L27
  lea    -0x2(%rsi),%eax
  mov    D3(%rip),%rbx
  mov    %rdi,%r13
  lea    0x1(%rdi,%rax,1),%rbp
  jmp    L12
  nop
L13:
  lea    0x1(%r13),%rdx
  mov    %rdx,%rcx
  cmp    $0xa,%eax
  je     L29
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rbp
  je     L18
  mov    %rdx,%r13
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L13
  lea    0x1(%r13),%rdx
  cmp    $0xa,%eax
  je     L29
  mov    %r13d,%eax
  mov    %r13,%rcx
  sub    %r12d,%eax
L27:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  movb   $0xa,0x0(%r13)
  mov    %rdx,%rcx
L18:
  movb   $0x0,(%rcx)
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  sub    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mygetline(char *s, int lim) {
  int c;
  char *t = s;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n')
    *t++ = c;
  if (c == '\n')
    *t++ = c;
  *t = '\0';
  return t - s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mygetline>:
  endbr64
  push   %r13
  mov    %rdi,%rcx
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L56
  lea    -0x2(%rsi),%eax
  mov    D8(%rip),%rbp
  mov    %rdi,%r13
  lea    0x1(%rdi,%rax,1),%rbx
  jmp    L1
  nop
L50:
  lea    0x1(%r13),%rdx
  mov    %rdx,%rcx
  cmp    $0xa,%eax
  je     L25
  mov    %al,-0x1(%rdx)
  cmp    %rbx,%rcx
  je     L38
  mov    %rdx,%r13
L1:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L50
  lea    0x1(%r13),%rdx
  cmp    $0xa,%eax
  je     L25
  mov    %r13d,%eax
  mov    %r13,%rcx
  sub    %r12d,%eax
L56:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rdx,%rcx
  movb   $0xa,0x0(%r13)
  mov    %edx,%eax
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  sub    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  movb   $0x0,(%rcx)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  sub    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mygetline(char *s, int lim) {
  int c;
  char *t = s;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n')
    *t++ = c;
  if (c == '\n')
    *t++ = c;
  *t = '\0';
  return t - s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <set_ioctl@plt>
  test   %eax,%eax
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L6
L5:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
int read_mem(int sock, struct ifreq *req) {
  struct zdap_ioctl *zdreq = NULL;
  int i;
  if (!set_ioctl(sock, req))
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_mem>:
  endbr64
  sub    $0x8,%rsp
  call   <set_ioctl@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int read_mem(int sock, struct ifreq *req) {
  struct zdap_ioctl *zdreq = NULL;
  int i;
  if (!set_ioctl(sock, req))
    return -1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_mem>:
  endbr64
  sub    $0x8,%rsp
  call   <set_ioctl@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int read_mem(int sock, struct ifreq *req) {
  struct zdap_ioctl *zdreq = NULL;
  int i;
  if (!set_ioctl(sock, req))
    return -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_mem>:
  endbr64
  sub    $0x8,%rsp
  call   <set_ioctl@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int read_mem(int sock, struct ifreq *req) {
  struct zdap_ioctl *zdreq = NULL;
  int i;
  if (!set_ioctl(sock, req))
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <system_@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <remove_char@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0xb9,%ecx
  lea    D7(%rip),%rdx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <s_internal@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <downcase@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D35
type: string
name: disassemble_data
arguments: tag: D20
type: string
name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D0
type: string

tool: D35: uname

tool: D20: 


tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/JulienBoubechtoulaAmabis/roswell/refs/heads/maBranche/src/util.c

tool: D0: p

assistant: ```c
char *uname(void) {
  char *p = system_("uname");
  char *p2;
  p2 = remove_char("\r\n", p);
  (s_internal(p, "p", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/JulienBoubechtoulaAmabis/roswell/refs/heads/maBranche/src/util.c", 185));
  return downcase(p2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <system_@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D1(%rip),%rdi
  call   <remove_char@plt>
  mov    %rax,%rbp
  mov    $0xb9,%ecx
  lea    D26(%rip),%rdx
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <s_internal@plt>
  mov    %rbp,%rdi
  call   <downcase@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D26
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D6: uname

tool: D1: 


tool: D26: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/JulienBoubechtoulaAmabis/roswell/refs/heads/maBranche/src/util.c

tool: D13: p

assistant: ```c
char *uname(void) {
  char *p = system_("uname");
  char *p2;
  p2 = remove_char("\r\n", p);
  (s_internal(p, "p", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/JulienBoubechtoulaAmabis/roswell/refs/heads/maBranche/src/util.c", 185));
  return downcase(p2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uname>:
  endbr64
  push   %r12
  lea    D36(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <system_@plt>
  lea    D26(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <remove_char@plt>
  mov    %rbp,%rdi
  mov    $0xb9,%ecx
  lea    D14(%rip),%rdx
  lea    D17(%rip),%rsi
  mov    %rax,%r12
  call   <s_internal@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <downcase@plt>
```

tool_calls: name: disassemble_data
arguments: label: D36
type: string
name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D17
type: string

tool: D36: uname

tool: D26: 


tool: D14: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/JulienBoubechtoulaAmabis/roswell/refs/heads/maBranche/src/util.c

tool: D17: p

assistant: ```c
char *uname(void) {
  char *p = system_("uname");
  char *p2;
  p2 = remove_char("\r\n", p);
  (s_internal(p, "p", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/JulienBoubechtoulaAmabis/roswell/refs/heads/maBranche/src/util.c", 185));
  return downcase(p2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uname>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <system_@plt>
  lea    D30(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <remove_char@plt>
  mov    %rbp,%rdi
  mov    $0xb9,%ecx
  lea    D1(%rip),%rdx
  lea    D8(%rip),%rsi
  mov    %rax,%r12
  call   <s_internal@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <downcase@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string
name: disassemble_data
arguments: data_label: D30
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D2: uname

tool: D30: 


tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/JulienBoubechtoulaAmabis/roswell/refs/heads/maBranche/src/util.c

tool: D8: p

assistant: ```c
char *uname(void) {
  char *p = system_("uname");
  char *p2;
  p2 = remove_char("\r\n", p);
  (s_internal(p, "p", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/JulienBoubechtoulaAmabis/roswell/refs/heads/maBranche/src/util.c", 185));
  return downcase(p2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mxCallocInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x138,%rsp
  mov    %edi,-0x134(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x134(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <superlu_malloc@plt>
  mov    %rax,-0x128(%rbp)
  cmpq   $0x0,-0x128(%rbp)
  jne    L16
  lea    -0x120(%rbp),%rax
  lea    D23(%rip),%r8
  mov    $0x25,%ecx
  lea    D2(%rip),%rdx
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <superlu_abort_and_exit@plt>
L16:
  mov    $0x0,%ebx
  jmp    L38
L22:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  add    $0x1,%ebx
L38:
  cmp    -0x134(%rbp),%ebx
  jl     L22
  mov    -0x128(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D15
type: string

tool: D23: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/optimizers/pysparse/refs/heads/master/pysparse/direct/superlu/src/sp_coletree.c

tool: D2: SUPERLU_MALLOC fails for buf in mxCallocInt()

tool: D15: %s at line %d in file %s


assistant: ```c
int *mxCallocInt(int n) {
  register int i;
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in mxCallocInt()", 37, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/optimizers/pysparse/refs/heads/master/pysparse/direct/superlu/src/sp_coletree.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; i++)
    buf[i] = 0;
  return (buf);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mxCallocInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rdi,4),%edi
  call   <superlu_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L19
L1:
  test   %ebx,%ebx
  jle    L46
  mov    %rbp,%rax
  mov    %ebx,%ebx
  lea    0x0(%rbp,%rbx,4),%rdx
L0:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L0
L46:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    %rbp,%rax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %rsp,%r12
  lea    D4(%rip),%r8
  mov    $0x25,%ecx
  lea    D11(%rip),%rdx
  lea    D22(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L1
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D22
type_infered: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/optimizers/pysparse/refs/heads/master/pysparse/direct/superlu/src/sp_coletree.c

tool: D11: SUPERLU_MALLOC fails for buf in mxCallocInt()

tool: D22: %s at line %d in file %s


assistant: ```c
int *mxCallocInt(int n) {
  register int i;
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in mxCallocInt()", 37, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/optimizers/pysparse/refs/heads/master/pysparse/direct/superlu/src/sp_coletree.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; i++)
    buf[i] = 0;
  return (buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mxCallocInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <superlu_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
L19:
  test   %ebx,%ebx
  jle    L5
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L5:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rsp,%rbp
  lea    D7(%rip),%r8
  mov    $0x25,%ecx
  mov    %rbp,%rdi
  lea    D18(%rip),%rdx
  lea    D19(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L19
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/optimizers/pysparse/refs/heads/master/pysparse/direct/superlu/src/sp_coletree.c

tool: D18: SUPERLU_MALLOC fails for buf in mxCallocInt()

tool: D19: %s at line %d in file %s


assistant: ```c
int *mxCallocInt(int n) {
  register int i;
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in mxCallocInt()", 37, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/optimizers/pysparse/refs/heads/master/pysparse/direct/superlu/src/sp_coletree.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; i++)
    buf[i] = 0;
  return (buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mxCallocInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <superlu_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L26
L38:
  test   %ebx,%ebx
  jle    L5
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L5:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rsp,%rbp
  lea    D7(%rip),%r8
  mov    $0x25,%ecx
  mov    %rbp,%rdi
  lea    D2(%rip),%rdx
  lea    D26(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L38
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string
name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D26
type_guessed: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/optimizers/pysparse/refs/heads/master/pysparse/direct/superlu/src/sp_coletree.c

tool: D2: SUPERLU_MALLOC fails for buf in mxCallocInt()

tool: D26: %s at line %d in file %s


assistant: ```c
int *mxCallocInt(int n) {
  register int i;
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in mxCallocInt()", 37, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/optimizers/pysparse/refs/heads/master/pysparse/direct/superlu/src/sp_coletree.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; i++)
    buf[i] = 0;
  return (buf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<skip_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
const char *skip_string(const char *string, const char *skipstring) {
  int n = 0;
  sscanf(string, skipstring, &n);
  return &string[n];
}
```
user: What is the c source code of the assembly code below:

```asm
<skip_string>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  movslq 0x4(%rsp),%rax
  add    %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *skip_string(const char *string, const char *skipstring) {
  int n = 0;
  sscanf(string, skipstring, &n);
  return &string[n];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  call   <sscanf@plt>
  movslq 0x4(%rsp),%rax
  add    %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *skip_string(const char *string, const char *skipstring) {
  int n = 0;
  sscanf(string, skipstring, &n);
  return &string[n];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<skip_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  call   <sscanf@plt>
  movslq 0x4(%rsp),%rax
  add    %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *skip_string(const char *string, const char *skipstring) {
  int n = 0;
  sscanf(string, skipstring, &n);
  return &string[n];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<seno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L19
L17:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xffffffff,%edi
  call   <pot@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <calcn@plt>
  mov    %eax,%edi
  call   <fatorial@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <calcn@plt>
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pot@plt>
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x10(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x18(%rbp)
L19:
  cmpl   $0x9,-0x18(%rbp)
  jle    L17
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double seno(int x) {
  int n;
  int numerador, denominador, term;
  double result = 0;
  for (n = 0; n < 10; n++) {
    numerador = pot(-1, n);
    denominador = fatorial(calcn(n));
    term = pot(x, calcn(n));
    result += ((double)numerador / (double)denominador) * (double)term;
  }
  return result;
}
```