ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Q_PrintStrlen>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L30
  movzbl (%rdi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rbx
  add    $0x1,%r12d
  mov    %edi,%eax
L73:
  test   %al,%al
  je     L54
  movsbq 0x1(%rbx),%rdi
  cmp    $0x5e,%al
  jne    L13
  test   %dil,%dil
  jne    L17
  add    $0x1,%r12d
L54:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L4
  movzbl 0x1(%rbx),%edi
  jmp    L13
L4:
  movzbl 0x2(%rbx),%eax
  add    $0x2,%rbx
  jmp    L73
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if ((p && *(p) == '^' && *((p) + 1) && isalnum(*((p) + 1)))) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Q_PrintStrlen>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L73
  movzbl (%rdi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L68:
  add    $0x1,%rbx
  add    $0x1,%r12d
  mov    %edi,%eax
L32:
  test   %al,%al
  je     L77
  movsbq 0x1(%rbx),%rdi
  cmp    $0x5e,%al
  jne    L68
  test   %dil,%dil
  jne    L8
  add    $0x1,%r12d
L77:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L24
  movzbl 0x1(%rbx),%edi
  jmp    L68
L24:
  movzbl 0x2(%rbx),%eax
  add    $0x2,%rbx
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L73:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if ((p && *(p) == '^' && *((p) + 1) && isalnum(*((p) + 1)))) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<play>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <isPlaying@plt>
  test   %rax,%rax
  je     L3
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <putTextItemToQueue@plt>
  jmp    L7
L3:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execute@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  leave
  ret
```

assistant: ```c
void play(char *synthCommand, char *playerCommand, char *text) {
  assert(synthCommand);
  assert(playerCommand);
  assert(text);
  if (isPlaying()) {
    putTextItemToQueue(synthCommand, playerCommand, text);
    return;
  }
  execute(synthCommand, playerCommand, text);
  free(synthCommand);
  free(playerCommand);
  free(text);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<play>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <isPlaying@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <execute@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <putTextItemToQueue@plt>
  jmp    L11
```

assistant: ```c
void play(char *synthCommand, char *playerCommand, char *text) {
  assert(synthCommand);
  assert(playerCommand);
  assert(text);
  if (isPlaying()) {
    putTextItemToQueue(synthCommand, playerCommand, text);
    return;
  }
  execute(synthCommand, playerCommand, text);
  free(synthCommand);
  free(playerCommand);
  free(text);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<play>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  xor    %eax,%eax
  call   <isPlaying@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  test   %rax,%rax
  jne    L5
  call   <execute@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <free@plt>
  xchg   %ax,%ax
L5:
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <putTextItemToQueue@plt>
```

assistant: ```c
void play(char *synthCommand, char *playerCommand, char *text) {
  assert(synthCommand);
  assert(playerCommand);
  assert(text);
  if (isPlaying()) {
    putTextItemToQueue(synthCommand, playerCommand, text);
    return;
  }
  execute(synthCommand, playerCommand, text);
  free(synthCommand);
  free(playerCommand);
  free(text);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<play>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  xor    %eax,%eax
  call   <isPlaying@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  test   %rax,%rax
  jne    L0
  call   <execute@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <free@plt>
  xchg   %ax,%ax
L0:
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <putTextItemToQueue@plt>
```

assistant: ```c
void play(char *synthCommand, char *playerCommand, char *text) {
  assert(synthCommand);
  assert(playerCommand);
  assert(text);
  if (isPlaying()) {
    putTextItemToQueue(synthCommand, playerCommand, text);
    return;
  }
  execute(synthCommand, playerCommand, text);
  free(synthCommand);
  free(playerCommand);
  free(text);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<output_data_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L7
L14:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    $0x7c,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <output_char@plt>
  subl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x0,-0xc(%rbp)
  jne    L14
  mov    $0x7c,%edi
  mov    $0x0,%eax
  call   <output_flush@plt>
  nop
  leave
  ret
```

assistant: ```c
void output_data_lines(s, n) char *s;
unsigned n;
{
  assert(n > 0);
  for (; n > 0; --n)
    output_char((unsigned char)*s++, '|');
  output_flush('|');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<output_data_lines>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   %esi,%esi
  setne  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  test   %ebp,%ebp
  je     L17
  mov    %ebp,%ebp
  add    %rbx,%rbp
L9:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  mov    $0x7c,%esi
  mov    $0x0,%eax
  call   <output_char@plt>
  cmp    %rbp,%rbx
  jne    L9
L17:
  mov    $0x7c,%edi
  mov    $0x0,%eax
  call   <output_flush@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void output_data_lines(s, n) char *s;
unsigned n;
{
  assert(n > 0);
  for (; n > 0; --n)
    output_char((unsigned char)*s++, '|');
  output_flush('|');
}
```
user: What is the c source code of the assembly code below?

```asm
<output_data_lines>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %ebp,%ebp
  setne  %dil
  xor    %eax,%eax
  call   <assert@plt>
  test   %ebp,%ebp
  je     L14
  add    %rbx,%rbp
  nopl   (%rax)
L16:
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  xor    %eax,%eax
  mov    $0x7c,%esi
  call   <output_char@plt>
  cmp    %rbx,%rbp
  jne    L16
L14:
  add    $0x8,%rsp
  mov    $0x7c,%edi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1090 <output_flush@plt>
```

assistant: ```c
void output_data_lines(s, n) char *s;
unsigned n;
{
  assert(n > 0);
  for (; n > 0; --n)
    output_char((unsigned char)*s++, '|');
  output_flush('|');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_data_lines>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %ebp,%ebp
  setne  %dil
  xor    %eax,%eax
  call   <assert@plt>
  test   %ebp,%ebp
  je     L12
  add    %rbx,%rbp
  nopl   (%rax)
L10:
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  xor    %eax,%eax
  mov    $0x7c,%esi
  call   <output_char@plt>
  cmp    %rbp,%rbx
  jne    L10
L12:
  add    $0x8,%rsp
  mov    $0x7c,%edi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1090 <output_flush@plt>
```

assistant: ```c
void output_data_lines(s, n) char *s;
unsigned n;
{
  assert(n > 0);
  for (; n > 0; --n)
    output_char((unsigned char)*s++, '|');
  output_flush('|');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L16
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L55:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    %rsi,%rbp
  mov    0x8(%rsi),%rdi
  lea    D21(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L56
  mov    0x10(%rbp),%rdi
  lea    D19(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L90
L91:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L45
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L91
  movzbl %bpl,%edi
  mov    %r13,%rsi
  call   <fputc@plt>
  add    $0x1,%r12d
  jmp    L91
L56:
  mov    0x8(%rbp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L55
L90:
  mov    0x10(%rbp),%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L55
L45:
  cmp    $0x3fff,%r12d
  ja     L77
L95:
  mov    %r13,%rsi
  mov    $0x0,%edi
  call   <fputc@plt>
  add    $0x1,%r12d
  cmp    $0x4000,%r12d
  jne    L95
L77:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  jmp    L55
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string
name: read_data
arguments: data_tag: D21
type_guessed: string
name: read_data
arguments: data_tag: D19
type_guessed: string
name: read_data
arguments: data_tag: D22
type_guessed: string
name: read_data
arguments: data_tag: D14
type_guessed: string

tool: D4: Syntax: fill16k.exe <bin file> <rom file>

tool: D21: rb

tool: D19: wb

tool: D22: Error opening input file %s


tool: D14: Error opening output file %s


assistant: ```c
int main(int argc, char **argv) {
  FILE *in, *out;
  unsigned char dummyb;
  unsigned int counter;
  if (argc != 3) {
    printf("Syntax: fill16k.exe <bin file> <rom file>\n");
    return (1);
  }
  in = fopen(argv[1], "rb");
  if (!in) {
    printf("Error opening input file %s\n", argv[1]);
    return (1);
  }
  out = fopen(argv[2], "wb");
  if (!out) {
    printf("Error opening output file %s\n", argv[2]);
    return (1);
  }
  counter = 0;
  while (!feof(in)) {
    dummyb = fgetc(in);
    if (!feof(in)) {
      fputc(dummyb, out);
      counter++;
    }
  }
  while (counter < 16384) {
    fputc(0, out);
    counter++;
  }
  fclose(in);
  fclose(out);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L1
  lea    D45(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  lea    D37(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L95
  mov    0x10(%rbx),%rdi
  lea    D39(%rip),%rsi
  xor    %r12d,%r12d
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L109
  jmp    L72
  xchg   %ax,%ax
L119:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <feof@plt>
  test   %eax,%eax
  je     L50
L109:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L119
  cmp    $0x3fff,%r12d
  ja     L116
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r13,%rsi
  xor    %edi,%edi
  add    $0x1,%r12d
  call   <fputc@plt>
  cmp    $0x4000,%r12d
  jne    L3
L116:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  jmp    L13
L50:
  movzbl %bl,%edi
  mov    %r13,%rsi
  add    $0x1,%r12d
  call   <fputc@plt>
  jmp    L109
L95:
  mov    0x8(%rbx),%rsi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L13
L72:
  mov    0x10(%rbx),%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: data_label: D45
type_guessed: string
name: retrieve_data
arguments: data_label: D37
type_guessed: string
name: retrieve_data
arguments: data_label: D39
type_guessed: string
name: retrieve_data
arguments: data_label: D43
type_guessed: string
name: retrieve_data
arguments: data_label: D25
type_guessed: string

tool: D45: Syntax: fill16k.exe <bin file> <rom file>

tool: D37: rb

tool: D39: wb

tool: D43: Error opening input file %s


tool: D25: Error opening output file %s


assistant: ```c
int main(int argc, char **argv) {
  FILE *in, *out;
  unsigned char dummyb;
  unsigned int counter;
  if (argc != 3) {
    printf("Syntax: fill16k.exe <bin file> <rom file>\n");
    return (1);
  }
  in = fopen(argv[1], "rb");
  if (!in) {
    printf("Error opening input file %s\n", argv[1]);
    return (1);
  }
  out = fopen(argv[2], "wb");
  if (!out) {
    printf("Error opening output file %s\n", argv[2]);
    return (1);
  }
  counter = 0;
  while (!feof(in)) {
    dummyb = fgetc(in);
    if (!feof(in)) {
      fputc(dummyb, out);
      counter++;
    }
  }
  while (counter < 16384) {
    fputc(0, out);
    counter++;
  }
  fclose(in);
  fclose(out);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L56
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L56:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L83
  mov    0x10(%rbx),%rdi
  lea    D33(%rip),%rsi
  xor    %r12d,%r12d
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L114
  jmp    L77
  xchg   %ax,%ax
L45:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <feof@plt>
  test   %eax,%eax
  je     L55
L114:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L45
  cmp    $0x3fff,%r12d
  ja     L13
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %r13,%rsi
  xor    %edi,%edi
  add    $0x1,%r12d
  call   <fputc@plt>
  cmp    $0x4000,%r12d
  jne    L24
L13:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  jmp    L42
L55:
  movzbl %bl,%edi
  mov    %r13,%rsi
  add    $0x1,%r12d
  call   <fputc@plt>
  jmp    L114
L83:
  mov    0x8(%rbx),%rsi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L42
L77:
  mov    0x10(%rbx),%rsi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L42
```

tool_calls: name: unpack_data
arguments: tag: D15
type: string
name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D33
type: string
name: unpack_data
arguments: tag: D42
type: string
name: unpack_data
arguments: tag: D36
type: string

tool: D15: Syntax: fill16k.exe <bin file> <rom file>

tool: D3: rb

tool: D33: wb

tool: D42: Error opening input file %s


tool: D36: Error opening output file %s


assistant: ```c
int main(int argc, char **argv) {
  FILE *in, *out;
  unsigned char dummyb;
  unsigned int counter;
  if (argc != 3) {
    printf("Syntax: fill16k.exe <bin file> <rom file>\n");
    return (1);
  }
  in = fopen(argv[1], "rb");
  if (!in) {
    printf("Error opening input file %s\n", argv[1]);
    return (1);
  }
  out = fopen(argv[2], "wb");
  if (!out) {
    printf("Error opening output file %s\n", argv[2]);
    return (1);
  }
  counter = 0;
  while (!feof(in)) {
    dummyb = fgetc(in);
    if (!feof(in)) {
      fputc(dummyb, out);
      counter++;
    }
  }
  while (counter < 16384) {
    fputc(0, out);
    counter++;
  }
  fclose(in);
  fclose(out);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x811c9dc5,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x1000193,%eax,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x8(%rbp),%eax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int getHash(void *key, int keysize, long long max) {
  unsigned int hash = 2166136261;
  for (int i = 0; i < keysize; i++) {
    hash = hash ^ (*(char *)key + i);
    hash = hash * 16777619;
  }
  return hash % max;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getHash>:
  endbr64
  mov    %rdx,%r8
  test   %esi,%esi
  jle    L17
  movsbl (%rdi),%ecx
  add    %ecx,%esi
  mov    $0x811c9dc5,%eax
L1:
  xor    %ecx,%eax
  imul   $0x1000193,%eax,%eax
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L1
L18:
  mov    %eax,%eax
  cqto
  idiv   %r8
  mov    %edx,%eax
  ret
L17:
  mov    $0x811c9dc5,%eax
  jmp    L18
```

assistant: ```c
unsigned int getHash(void *key, int keysize, long long max) {
  unsigned int hash = 2166136261;
  for (int i = 0; i < keysize; i++) {
    hash = hash ^ (*(char *)key + i);
    hash = hash * 16777619;
  }
  return hash % max;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getHash>:
  endbr64
  mov    %rdx,%r8
  mov    $0x811c9dc5,%eax
  test   %esi,%esi
  jle    L5
  movsbl (%rdi),%ecx
  mov    $0x811c9dc5,%eax
  add    %ecx,%esi
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %ecx,%eax
  add    $0x1,%ecx
  imul   $0x1000193,%eax,%eax
  cmp    %ecx,%esi
  jne    L8
L5:
  cqto
  idiv   %r8
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int getHash(void *key, int keysize, long long max) {
  unsigned int hash = 2166136261;
  for (int i = 0; i < keysize; i++) {
    hash = hash ^ (*(char *)key + i);
    hash = hash * 16777619;
  }
  return hash % max;
}
```
user: What is the c source code of the assembly code below?

```asm
<getHash>:
  endbr64
  mov    %rdx,%r8
  mov    $0x811c9dc5,%eax
  test   %esi,%esi
  jle    L3
  movsbl (%rdi),%ecx
  mov    $0x811c9dc5,%eax
  add    %ecx,%esi
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %ecx,%eax
  add    $0x1,%ecx
  imul   $0x1000193,%eax,%eax
  cmp    %ecx,%esi
  jne    L16
L3:
  cqto
  idiv   %r8
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int getHash(void *key, int keysize, long long max) {
  unsigned int hash = 2166136261;
  for (int i = 0; i < keysize; i++) {
    hash = hash ^ (*(char *)key + i);
    hash = hash * 16777619;
  }
  return hash % max;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x78,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  cmpl   $0x0,-0x64(%rbp)
  jle    L13
  mov    -0x70(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <eval_args@plt>
L13:
  mov    $0x0,%eax
  call   <get_nou@plt>
  mov    %eax,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x54(%rbp),%esi
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x50(%rbp)
  movslq %ecx,%rax
  mov    %rax,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movslq %esi,%rax
  sub    $0x1,%rax
  mov    %rax,-0x48(%rbp)
  movslq %ecx,%rax
  mov    %rax,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movslq %esi,%rax
  mov    %rax,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  mov    -0x80(%rbp),%r8
  mov    -0x78(%rbp),%r9
  mov    %r9,%rdx
  mov    -0x90(%rbp),%r10
  mov    -0x88(%rbp),%r11
  imul   %r10,%rdx
  mov    %r11,%rax
  imul   %r8,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    %r8,%rax
  mul    %r10
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  movslq %esi,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    %r15,%rdx
  imul   %r12,%rdx
  mov    %r13,%rax
  imul   %r14,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    %r14,%rax
  mul    %r12
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rdx
  movslq %esi,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L25:
  cmp    %rdx,%rsp
  je     L47
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L25
L47:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L34
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L34:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fill_matrix@plt>
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <solve_matrix@plt>
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <display_result@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc > 0) {
    eval_args(argc, argv);
  }
  int nou = get_nou();
  double mat[nou][nou + 1];
  fill_matrix(nou, mat);
  solve_matrix(nou, mat);
  display_result(nou, mat);
  return 0;
}
```