ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L59
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jl     L140
L59:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L48
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L48
L140:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L150
L48:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L31
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jl     L77
L31:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L157
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L157
L77:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L150
L157:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L96
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jl     L27
L96:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L78
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L78
L27:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L150
L78:
  mov    $0x0,%eax
L150:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string
name: unpack_data
arguments: data_label: D36
data_type: string
name: unpack_data
arguments: data_label: D40
data_type: string

tool: D4: Please enter 3 numbers separated by spaces > 

tool: D36: %i %i %i

tool: D40: %i is the median


assistant: ```c
int main(void) {
  int num1, num2, num3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%i %i %i", &num1, &num2, &num3);
  if ((((num1 > num2) && (num1 < num3))) || ((num1 > num3) && (num1 < num2))) {
    printf("%i is the median\n", num1);
    return 0;
  } else if ((((num2 > num1) && (num2 < num3))) || ((num2 > num3) && (num2 < num1))) {
    printf("%i is the median\n", num2);
    return 0;
  } else if ((((num3 > num2) && (num3 < num1))) || ((num3 > num1) && (num3 < num2))) {
    printf("%i is the median\n", num3);
    return 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  jle    L98
  mov    0x14(%rsp),%edx
  cmp    %edx,%esi
  jl     L43
  setg   %cl
  cmp    %edx,%eax
  setl   %dil
  setg   %r8b
  cmp    %eax,%esi
  jle    L22
  test   %r8b,%r8b
  je     L22
L113:
  mov    %eax,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L111
L98:
  mov    0x14(%rsp),%edx
  setl   %r8b
  cmp    %edx,%esi
  setg   %cl
  test   %r8b,%r8b
  je     L101
  test   %cl,%cl
  jne    L43
L101:
  cmp    %edx,%eax
  setl   %dil
  test   %r8b,%r8b
  je     L136
  test   %dil,%dil
  jne    L113
L136:
  cmp    %edx,%eax
  setg   %r8b
L22:
  test   %dil,%dil
  je     L77
  test   %cl,%cl
  jne    L35
L77:
  cmp    %edx,%esi
  jge    L111
  test   %r8b,%r8b
  je     L111
L35:
  mov    %edx,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L111
L43:
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L111:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D20
type: string

tool: D0: Please enter 3 numbers separated by spaces > 

tool: D22: %i %i %i

tool: D20: %i is the median


assistant: ```c
int main(void) {
  int num1, num2, num3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%i %i %i", &num1, &num2, &num3);
  if ((((num1 > num2) && (num1 < num3))) || ((num1 > num3) && (num1 < num2))) {
    printf("%i is the median\n", num1);
    return 0;
  } else if ((((num2 > num1) && (num2 < num3))) || ((num2 > num3) && (num2 < num1))) {
    printf("%i is the median\n", num2);
    return 0;
  } else if ((((num3 > num2) && (num3 < num1))) || ((num3 > num1) && (num3 < num2))) {
    printf("%i is the median\n", num3);
    return 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r9d
  mov    0x14(%rsp),%r8d
  cmp    %r9d,%esi
  jle    L139
  cmp    %r8d,%esi
  jl     L86
  setg   %al
  cmp    %r8d,%r9d
  setl   %cl
  jg     L51
L124:
  test   %al,%al
  je     L130
  test   %cl,%cl
  je     L130
  jmp    L34
L139:
  setl   %dl
  cmp    %r8d,%esi
  setg   %al
  jle    L68
  test   %dl,%dl
  jne    L86
L68:
  cmp    %r8d,%r9d
  setl   %cl
  jge    L96
  test   %dl,%dl
  jne    L51
L96:
  cmp    %r8d,%r9d
  jle    L124
  cmp    %r8d,%esi
  jge    L130
L34:
  mov    %r8d,%esi
L86:
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L130:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L51:
  mov    %r9d,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L130
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string
name: disassemble_data
arguments: tag: D25
datatype: string
name: disassemble_data
arguments: tag: D8
datatype: string

tool: D7: Please enter 3 numbers separated by spaces > 

tool: D25: %i %i %i

tool: D8: %i is the median


assistant: ```c
int main(void) {
  int num1, num2, num3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%i %i %i", &num1, &num2, &num3);
  if ((((num1 > num2) && (num1 < num3))) || ((num1 > num3) && (num1 < num2))) {
    printf("%i is the median\n", num1);
    return 0;
  } else if ((((num2 > num1) && (num2 < num3))) || ((num2 > num3) && (num2 < num1))) {
    printf("%i is the median\n", num2);
    return 0;
  } else if ((((num3 > num2) && (num3 < num1))) || ((num3 > num1) && (num3 < num2))) {
    printf("%i is the median\n", num3);
    return 0;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%r9d
  mov    0x14(%rsp),%r8d
  cmp    %r9d,%esi
  jle    L97
  cmp    %r8d,%esi
  jl     L56
  setg   %al
  cmp    %r8d,%r9d
  setl   %cl
  jg     L66
L109:
  test   %al,%al
  je     L58
  test   %cl,%cl
  je     L58
  jmp    L115
L97:
  setl   %dl
  cmp    %r8d,%esi
  setg   %al
  jle    L78
  test   %dl,%dl
  jne    L56
L78:
  cmp    %r8d,%r9d
  setl   %cl
  jge    L52
  test   %dl,%dl
  jne    L66
L52:
  cmp    %r8d,%r9d
  jle    L109
  cmp    %r8d,%esi
  jge    L58
L115:
  mov    %r8d,%esi
L56:
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L58:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L66:
  mov    %r9d,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type: string
name: disassemble_data
arguments: data_label: D20
type: string
name: disassemble_data
arguments: data_label: D22
type: string

tool: D21: Please enter 3 numbers separated by spaces > 

tool: D20: %i %i %i

tool: D22: %i is the median


assistant: ```c
int main(void) {
  int num1, num2, num3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%i %i %i", &num1, &num2, &num3);
  if ((((num1 > num2) && (num1 < num3))) || ((num1 > num3) && (num1 < num2))) {
    printf("%i is the median\n", num1);
    return 0;
  } else if ((((num2 > num1) && (num2 < num3))) || ((num2 > num3) && (num2 < num1))) {
    printf("%i is the median\n", num2);
    return 0;
  } else if ((((num3 > num2) && (num3 < num1))) || ((num3 > num1) && (num3 < num2))) {
    printf("%i is the median\n", num3);
    return 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__syscall_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D5(%rip),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  ret
```

assistant: ```c
long int __syscall_error(long int err) {
  errno = err;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__syscall_error>:
  endbr64
  mov    D7(%rip),%rax
  mov    %rdi,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long int __syscall_error(long int err) {
  errno = err;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__syscall_error>:
  endbr64
  mov    D4(%rip),%rax
  mov    %rdi,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long int __syscall_error(long int err) {
  errno = err;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__syscall_error>:
  endbr64
  mov    D9(%rip),%rax
  mov    %rdi,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long int __syscall_error(long int err) {
  errno = err;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_item_as_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_item_as_string@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L18
  movl   $0xffffffff,-0x24(%rbp)
  jmp    L44
L18:
  lea    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L44
  movl   $0xffffffff,-0x24(%rbp)
L44:
  cmpq   $0x0,-0x48(%rbp)
  je     L4
  mov    -0x48(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
L4:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
long get_item_as_long(char **str, char *trenner, int *result) {
  long v;
  char *s;
  int e;
  char *endptr;
  e = 0;
  v = 0L;
  s = get_item_as_string(str, trenner, NULL);
  if (!s) {
    e = -1;
  } else {
    v = strtol(s, (char **)&endptr, 0);
    if (s == endptr) {
      e = -1;
    }
  }
  if ((result))
    *(result) = (e);
  return (v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_item_as_long>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  call   <get_item_as_string@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%rbx
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <strtol@plt>
  cmp    %rbx,(%rsp)
  sete   %dl
  movzbl %dl,%edx
  neg    %edx
L28:
  test   %rbp,%rbp
  je     L39
  mov    %edx,0x0(%rbp)
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    $0xffffffff,%edx
  mov    $0x0,%eax
  jmp    L28
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_item_as_long(char **str, char *trenner, int *result) {
  long v;
  char *s;
  int e;
  char *endptr;
  e = 0;
  v = 0L;
  s = get_item_as_string(str, trenner, NULL);
  if (!s) {
    e = -1;
  } else {
    v = strtol(s, (char **)&endptr, 0);
    if (s == endptr) {
      e = -1;
    }
  }
  if ((result))
    *(result) = (e);
  return (v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_item_as_long>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  xor    %edx,%edx
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <get_item_as_string@plt>
  test   %rax,%rax
  je     L19
  xor    %edx,%edx
  mov    %rsp,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strtol@plt>
  xor    %edx,%edx
  cmp    %rbx,(%rsp)
  sete   %dl
  neg    %edx
L36:
  test   %rbp,%rbp
  je     L31
  mov    %edx,0x0(%rbp)
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0xffffffff,%edx
  xor    %eax,%eax
  jmp    L36
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_item_as_long(char **str, char *trenner, int *result) {
  long v;
  char *s;
  int e;
  char *endptr;
  e = 0;
  v = 0L;
  s = get_item_as_string(str, trenner, NULL);
  if (!s) {
    e = -1;
  } else {
    v = strtol(s, (char **)&endptr, 0);
    if (s == endptr) {
      e = -1;
    }
  }
  if ((result))
    *(result) = (e);
  return (v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_item_as_long>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  xor    %edx,%edx
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <get_item_as_string@plt>
  test   %rax,%rax
  je     L23
  xor    %edx,%edx
  mov    %rsp,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strtol@plt>
  xor    %edx,%edx
  cmp    %rbx,(%rsp)
  sete   %dl
  neg    %edx
L22:
  test   %rbp,%rbp
  je     L32
  mov    %edx,0x0(%rbp)
L32:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0xffffffff,%edx
  xor    %eax,%eax
  jmp    L22
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_item_as_long(char **str, char *trenner, int *result) {
  long v;
  char *s;
  int e;
  char *endptr;
  e = 0;
  v = 0L;
  s = get_item_as_string(str, trenner, NULL);
  if (!s) {
    e = -1;
  } else {
    v = strtol(s, (char **)&endptr, 0);
    if (s == endptr) {
      e = -1;
    }
  }
  if ((result))
    *(result) = (e);
  return (v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L16
L8:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    -0x38(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  mov    %eax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L8
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int *ft_map(int *tab, int length, int (*f)(int)) {
  int i;
  int *new;
  i = 0;
  new = (int *)malloc(sizeof(int) * length);
  while (i < length) {
    new[i] = f(tab[i]);
    i++;
  }
  return (new);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_map>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L7
  mov    %ebx,%ebx
  lea    (%rax,%rbx,4),%r13
  mov    %rax,%rbx
  sub    %rax,%rbp
L17:
  mov    0x0(%rbp,%rbx,1),%edi
  call   *%r12
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L17
L7:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *ft_map(int *tab, int length, int (*f)(int)) {
  int i;
  int *new;
  i = 0;
  new = (int *)malloc(sizeof(int) * length);
  while (i < length) {
    new[i] = f(tab[i]);
    i++;
  }
  return (new);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_map>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L8
  lea    (%rax,%rbx,4),%r12
  sub    %rax,%r14
  mov    %rax,%rbx
  nopl   0x0(%rax)
L17:
  mov    (%r14,%rbx,1),%edi
  add    $0x4,%rbx
  call   *%rbp
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L17
L8:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *ft_map(int *tab, int length, int (*f)(int)) {
  int i;
  int *new;
  i = 0;
  new = (int *)malloc(sizeof(int) * length);
  while (i < length) {
    new[i] = f(tab[i]);
    i++;
  }
  return (new);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_map>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L2
  lea    (%rax,%rbx,4),%r12
  sub    %rax,%r14
  mov    %rax,%rbx
  nopl   0x0(%rax)
L0:
  mov    (%r14,%rbx,1),%edi
  add    $0x4,%rbx
  call   *%rbp
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L0
L2:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *ft_map(int *tab, int length, int (*f)(int)) {
  int i;
  int *new;
  i = 0;
  new = (int *)malloc(sizeof(int) * length);
  while (i < length) {
    new[i] = f(tab[i]);
    i++;
  }
  return (new);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<standard_Newton_step>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xc7,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int standard_Newton_step(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(199, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<standard_Newton_step>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xc7,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int standard_Newton_step(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(199, a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<standard_Newton_step>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xc7,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int standard_Newton_step(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(199, a, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<standard_Newton_step>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xc7,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int standard_Newton_step(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(199, a, b, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<log_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %eax,%edx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L18
  mov    $0x1,%edi
  call   <dup@plt>
  jmp    L12
L18:
  mov    $0xffffea4d,%eax
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: ncsvc.log

assistant: ```c
int log_open(struct fd_info *info, const char *pathname) {
  if (!strcmp(basename((char *)pathname), "ncsvc.log")) {
    do {
    } while (0);
    return dup(1);
  } else
    return -5555;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<log_open>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <basename@plt>
  mov    %eax,%edi
  lea    D2(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L12
  mov    $0x1,%edi
  call   <dup@plt>
L10:
  add    $0x8,%rsp
  ret
L12:
  mov    $0xffffea4d,%eax
  jmp    L10
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: ncsvc.log

assistant: ```c
int log_open(struct fd_info *info, const char *pathname) {
  if (!strcmp(basename((char *)pathname), "ncsvc.log")) {
    do {
    } while (0);
    return dup(1);
  } else
    return -5555;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<log_open>:
  endbr64
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <basename@plt>
  lea    D4(%rip),%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L1
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <dup@plt>
L1:
  mov    $0xffffea4d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: ncsvc.log

assistant: ```c
int log_open(struct fd_info *info, const char *pathname) {
  if (!strcmp(basename((char *)pathname), "ncsvc.log")) {
    do {
    } while (0);
    return dup(1);
  } else
    return -5555;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_open>:
  endbr64
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <basename@plt>
  lea    D0(%rip),%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <dup@plt>
L8:
  mov    $0xffffea4d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0: ncsvc.log

assistant: ```c
int log_open(struct fd_info *info, const char *pathname) {
  if (!strcmp(basename((char *)pathname), "ncsvc.log")) {
    do {
    } while (0);
    return dup(1);
  } else
    return -5555;
}
```