ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cmpl   $0x0,-0x14(%rbp)
  je     L25
  cmpl   $0x0,-0x10(%rbp)
  jne    L25
  movl   $0x1,-0xc(%rbp)
L25:
  cmpl   $0x2,-0x14(%rbp)
  jg     L47
  cmpl   $0x10,-0x10(%rbp)
  jg     L35
L47:
  movl   $0x17,-0xc(%rbp)
  jmp    L43
L35:
  movl   $0x1bc,-0xc(%rbp)
L43:
  movl   $0x4,-0x14(%rbp)
  jmp    L14
L81:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L14:
  cmpl   $0x9,-0x14(%rbp)
  jle    L81
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L97
L76:
  addl   $0xa,-0x14(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L97:
  cmpl   $0x9,-0x4(%rbp)
  jle    L76
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L52
L86:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  add    %eax,-0x10(%rbp)
L52:
  cmpl   $0x9,-0x14(%rbp)
  jle    L86
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
L75:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  jle    L75
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test2() {
  int i, j, k;
  if (i && !j) {
    k = 1;
  }
  if (i > 2 || j < 17) {
    k = 23;
  } else {
    k = 444;
  }
  for (i = 4; i < 10; ++i) {
    ++k;
  }
  for (int y = 0, x = 0; x < 10; x++, y--) {
    i += 10;
    j += y + x;
  }
  i = 0;
  j = 0;
  while (i < 10)
    j += i++;
  i = 0;
  j = 0;
  do {
    j += ++i;
  } while (i < 10);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test2>:
  endbr64
  ret
```

assistant: ```c
void test2() {
  int i, j, k;
  if (i && !j) {
    k = 1;
  }
  if (i > 2 || j < 17) {
    k = 23;
  } else {
    k = 444;
  }
  for (i = 4; i < 10; ++i) {
    ++k;
  }
  for (int y = 0, x = 0; x < 10; x++, y--) {
    i += 10;
    j += y + x;
  }
  i = 0;
  j = 0;
  while (i < 10)
    j += i++;
  i = 0;
  j = 0;
  do {
    j += ++i;
  } while (i < 10);
}
```
user: What is the c source code of the assembly code below:

```asm
<test2>:
  endbr64
  ret
```

assistant: ```c
void test2() {
  int i, j, k;
  if (i && !j) {
    k = 1;
  }
  if (i > 2 || j < 17) {
    k = 23;
  } else {
    k = 444;
  }
  for (i = 4; i < 10; ++i) {
    ++k;
  }
  for (int y = 0, x = 0; x < 10; x++, y--) {
    i += 10;
    j += y + x;
  }
  i = 0;
  j = 0;
  while (i < 10)
    j += i++;
  i = 0;
  j = 0;
  do {
    j += ++i;
  } while (i < 10);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test2>:
  endbr64
  ret
```

assistant: ```c
void test2() {
  int i, j, k;
  if (i && !j) {
    k = 1;
  }
  if (i > 2 || j < 17) {
    k = 23;
  } else {
    k = 444;
  }
  for (i = 4; i < 10; ++i) {
    ++k;
  }
  for (int y = 0, x = 0; x < 10; x++, y--) {
    i += 10;
    j += y + x;
  }
  i = 0;
  j = 0;
  while (i < 10)
    j += i++;
  i = 0;
  j = 0;
  do {
    j += ++i;
  } while (i < 10);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<epilogue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x2,%edx
  mov    $0x0,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <get_value@plt>
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D26
type_guessed: string
name: read_data
arguments: tag: D9
type_guessed: string
name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D31
type_guessed: string

tool: D26: 
You are about to enter the %s...


tool: D9: If you want to continue press [0], skip the stage press [1]

tool: D2: Use your keyboard.

tool: D31: %u

assistant: ```c
int epilogue(char *str) {
  printf("\nYou are about to enter the %s...\n", str);
  printf("If you want to continue press [0], skip the stage press [1]\n");
  printf("Use your keyboard.\n");
  return get_value("%u", 0, 2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<epilogue>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edx
  mov    $0x0,%esi
  lea    D14(%rip),%rdi
  call   <get_value@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D35
datatype: string
name: retrieve_data
arguments: label: D37
datatype: string
name: retrieve_data
arguments: label: D32
datatype: string
name: retrieve_data
arguments: label: D14
datatype: string

tool: D35: 
You are about to enter the %s...


tool: D37: If you want to continue press [0], skip the stage press [1]

tool: D32: Use your keyboard.

tool: D14: %u

assistant: ```c
int epilogue(char *str) {
  printf("\nYou are about to enter the %s...\n", str);
  printf("If you want to continue press [0], skip the stage press [1]\n");
  printf("Use your keyboard.\n");
  return get_value("%u", 0, 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<epilogue>:
  endbr64
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edx
  xor    %esi,%esi
  add    $0x8,%rsp
  lea    D29(%rip),%rdi
  jmp    1090 <get_value@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string

tool: D20: 
You are about to enter the %s...


tool: D15: If you want to continue press [0], skip the stage press [1]

tool: D10: Use your keyboard.

tool: D29: %u

assistant: ```c
int epilogue(char *str) {
  printf("\nYou are about to enter the %s...\n", str);
  printf("If you want to continue press [0], skip the stage press [1]\n");
  printf("Use your keyboard.\n");
  return get_value("%u", 0, 2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<epilogue>:
  endbr64
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edx
  xor    %esi,%esi
  add    $0x8,%rsp
  lea    D14(%rip),%rdi
  jmp    1090 <get_value@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
datatype: string
name: extract_symbolic_data
arguments: tag: D29
datatype: string
name: extract_symbolic_data
arguments: tag: D23
datatype: string
name: extract_symbolic_data
arguments: tag: D14
datatype: string

tool: D34: 
You are about to enter the %s...


tool: D29: If you want to continue press [0], skip the stage press [1]

tool: D23: Use your keyboard.

tool: D14: %u

assistant: ```c
int epilogue(char *str) {
  printf("\nYou are about to enter the %s...\n", str);
  printf("If you want to continue press [0], skip the stage press [1]\n");
  printf("Use your keyboard.\n");
  return get_value("%u", 0, 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<t1_init_spb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x220,%eax
  cmp    $0x20,%eax
  sete   %al
  movzbl %al,%edx
  mov    -0x24(%rbp),%eax
  and    $0x880,%eax
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
  add    %edx,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <int_min@plt>
  mov    %eax,%ebx
  mov    -0x24(%rbp),%eax
  and    $0x220,%eax
  cmp    $0x220,%eax
  sete   %al
  movzbl %al,%edx
  mov    -0x24(%rbp),%eax
  and    $0x880,%eax
  cmp    $0x880,%eax
  sete   %al
  movzbl %al,%eax
  add    %edx,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <int_min@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x110,%eax
  cmp    $0x10,%eax
  sete   %al
  movzbl %al,%edx
  mov    -0x24(%rbp),%eax
  and    $0x440,%eax
  cmp    $0x40,%eax
  sete   %al
  movzbl %al,%eax
  add    %edx,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <int_min@plt>
  mov    %eax,%ebx
  mov    -0x24(%rbp),%eax
  and    $0x110,%eax
  cmp    $0x110,%eax
  sete   %al
  movzbl %al,%edx
  mov    -0x24(%rbp),%eax
  and    $0x440,%eax
  cmp    $0x440,%eax
  sete   %al
  movzbl %al,%eax
  add    %edx,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <int_min@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L62
  cmpl   $0x0,-0x14(%rbp)
  jne    L62
  movl   $0x0,-0x1c(%rbp)
  jmp    L57
L62:
  cmpl   $0x0,-0x18(%rbp)
  jg     L27
  cmpl   $0x0,-0x18(%rbp)
  jne    L4
  cmpl   $0x0,-0x14(%rbp)
  jg     L27
L4:
  mov    $0x1,%eax
  jmp    L50
L27:
  mov    $0x0,%eax
L50:
  mov    %eax,-0x1c(%rbp)
L57:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int t1_init_spb(int f) {
  int hc, vc, n;
  hc = int_min(((f & (0x0020 | 0x0200)) == 0x0020) + ((f & (0x0080 | 0x0800)) == 0x0080), 1) - int_min(((f & (0x0020 | 0x0200)) == (0x0020 | 0x0200)) + ((f & (0x0080 | 0x0800)) == (0x0080 | 0x0800)), 1);
  vc = int_min(((f & (0x0010 | 0x0100)) == 0x0010) + ((f & (0x0040 | 0x0400)) == 0x0040), 1) - int_min(((f & (0x0010 | 0x0100)) == (0x0010 | 0x0100)) + ((f & (0x0040 | 0x0400)) == (0x0040 | 0x0400)), 1);
  if (!hc && !vc) {
    n = 0;
  } else {
    n = (!(hc > 0 || (!hc && vc > 0)));
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<t1_init_spb>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%r13d
  and    $0x220,%r13d
  mov    %edi,%ebp
  and    $0x880,%ebp
  cmp    $0x20,%r13d
  sete   %dil
  movzbl %dil,%edi
  cmp    $0x80,%ebp
  sete   %al
  movzbl %al,%eax
  add    %eax,%edi
  mov    $0x1,%esi
  call   <int_min@plt>
  mov    %eax,%r12d
  cmp    $0x220,%r13d
  sete   %dil
  movzbl %dil,%edi
  cmp    $0x880,%ebp
  sete   %al
  movzbl %al,%eax
  add    %eax,%edi
  mov    $0x1,%esi
  call   <int_min@plt>
  sub    %eax,%r12d
  mov    %ebx,%r13d
  and    $0x110,%r13d
  and    $0x440,%ebx
  mov    %ebx,%ebp
  cmp    $0x10,%r13d
  sete   %dil
  movzbl %dil,%edi
  cmp    $0x40,%ebx
  sete   %al
  movzbl %al,%eax
  add    %eax,%edi
  mov    $0x1,%esi
  call   <int_min@plt>
  mov    %eax,%ebx
  cmp    $0x110,%r13d
  sete   %dil
  movzbl %dil,%edi
  cmp    $0x440,%ebp
  sete   %al
  movzbl %al,%eax
  add    %eax,%edi
  mov    $0x1,%esi
  call   <int_min@plt>
  mov    %ebx,%edx
  sub    %eax,%edx
  mov    %r12d,%eax
  or     %edx,%eax
  je     L19
  mov    $0x0,%eax
  test   %r12d,%r12d
  jle    L14
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  setne  %al
  test   %edx,%edx
  setle  %dl
  or     %edx,%eax
  movzbl %al,%eax
  jmp    L19
```

assistant: ```c
int t1_init_spb(int f) {
  int hc, vc, n;
  hc = int_min(((f & (0x0020 | 0x0200)) == 0x0020) + ((f & (0x0080 | 0x0800)) == 0x0080), 1) - int_min(((f & (0x0020 | 0x0200)) == (0x0020 | 0x0200)) + ((f & (0x0080 | 0x0800)) == (0x0080 | 0x0800)), 1);
  vc = int_min(((f & (0x0010 | 0x0100)) == 0x0010) + ((f & (0x0040 | 0x0400)) == 0x0040), 1) - int_min(((f & (0x0010 | 0x0100)) == (0x0010 | 0x0100)) + ((f & (0x0040 | 0x0400)) == (0x0040 | 0x0400)), 1);
  if (!hc && !vc) {
    n = 0;
  } else {
    n = (!(hc > 0 || (!hc && vc > 0)));
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<t1_init_spb>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x1,%esi
  push   %r12
  and    $0x220,%r13d
  mov    %edi,%r12d
  push   %rbp
  and    $0x880,%r12d
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x20,%r13d
  sete   %dil
  xor    %eax,%eax
  cmp    $0x80,%r12d
  sete   %al
  add    %eax,%edi
  call   <int_min@plt>
  xor    %edi,%edi
  cmp    $0x220,%r13d
  mov    %ebx,%r13d
  sete   %dil
  mov    %eax,%ebp
  xor    %eax,%eax
  cmp    $0x880,%r12d
  sete   %al
  mov    $0x1,%esi
  and    $0x110,%r13d
  and    $0x440,%ebx
  add    %eax,%edi
  call   <int_min@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  sub    %eax,%ebp
  cmp    $0x10,%r13d
  sete   %dil
  xor    %eax,%eax
  cmp    $0x40,%ebx
  sete   %al
  add    %eax,%edi
  call   <int_min@plt>
  xor    %edi,%edi
  cmp    $0x110,%r13d
  mov    $0x1,%esi
  sete   %dil
  mov    %eax,%r12d
  xor    %eax,%eax
  cmp    $0x440,%ebx
  sete   %al
  add    %eax,%edi
  call   <int_min@plt>
  mov    %r12d,%edx
  sub    %eax,%edx
  mov    %ebp,%eax
  or     %edx,%eax
  je     L14
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L11
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  setne  %al
  test   %edx,%edx
  setle  %dl
  add    $0x8,%rsp
  or     %edx,%eax
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int t1_init_spb(int f) {
  int hc, vc, n;
  hc = int_min(((f & (0x0020 | 0x0200)) == 0x0020) + ((f & (0x0080 | 0x0800)) == 0x0080), 1) - int_min(((f & (0x0020 | 0x0200)) == (0x0020 | 0x0200)) + ((f & (0x0080 | 0x0800)) == (0x0080 | 0x0800)), 1);
  vc = int_min(((f & (0x0010 | 0x0100)) == 0x0010) + ((f & (0x0040 | 0x0400)) == 0x0040), 1) - int_min(((f & (0x0010 | 0x0100)) == (0x0010 | 0x0100)) + ((f & (0x0040 | 0x0400)) == (0x0040 | 0x0400)), 1);
  if (!hc && !vc) {
    n = 0;
  } else {
    n = (!(hc > 0 || (!hc && vc > 0)));
  }
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<t1_init_spb>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x1,%esi
  push   %r12
  and    $0x220,%r13d
  mov    %edi,%r12d
  push   %rbp
  and    $0x880,%r12d
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x20,%r13d
  sete   %dil
  xor    %eax,%eax
  cmp    $0x80,%r12d
  sete   %al
  add    %eax,%edi
  call   <int_min@plt>
  xor    %edi,%edi
  cmp    $0x220,%r13d
  mov    %ebx,%r13d
  sete   %dil
  mov    %eax,%ebp
  xor    %eax,%eax
  cmp    $0x880,%r12d
  sete   %al
  mov    $0x1,%esi
  and    $0x110,%r13d
  and    $0x440,%ebx
  add    %eax,%edi
  call   <int_min@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  sub    %eax,%ebp
  cmp    $0x10,%r13d
  sete   %dil
  xor    %eax,%eax
  cmp    $0x40,%ebx
  sete   %al
  add    %eax,%edi
  call   <int_min@plt>
  xor    %edi,%edi
  cmp    $0x110,%r13d
  mov    $0x1,%esi
  sete   %dil
  mov    %eax,%r12d
  xor    %eax,%eax
  cmp    $0x440,%ebx
  sete   %al
  add    %eax,%edi
  call   <int_min@plt>
  mov    %r12d,%edx
  sub    %eax,%edx
  mov    %ebp,%eax
  or     %edx,%eax
  je     L10
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L12
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  setne  %al
  test   %edx,%edx
  setle  %dl
  add    $0x8,%rsp
  or     %edx,%eax
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int t1_init_spb(int f) {
  int hc, vc, n;
  hc = int_min(((f & (0x0020 | 0x0200)) == 0x0020) + ((f & (0x0080 | 0x0800)) == 0x0080), 1) - int_min(((f & (0x0020 | 0x0200)) == (0x0020 | 0x0200)) + ((f & (0x0080 | 0x0800)) == (0x0080 | 0x0800)), 1);
  vc = int_min(((f & (0x0010 | 0x0100)) == 0x0010) + ((f & (0x0040 | 0x0400)) == 0x0040), 1) - int_min(((f & (0x0010 | 0x0100)) == (0x0010 | 0x0100)) + ((f & (0x0040 | 0x0400)) == (0x0040 | 0x0400)), 1);
  if (!hc && !vc) {
    n = 0;
  } else {
    n = (!(hc > 0 || (!hc && vc > 0)));
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L8:
  mov    -0x14(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **cmatrix(int n, int m) {
  char *vec = (char *)malloc(n * m * sizeof(char));
  char **mat = (char **)malloc(n * sizeof(char *));
  for (int i = 0; i < n; i++)
    mat[i] = vec + i * m;
  return mat;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  imul   %esi,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x0(,%r12,8),%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  jle    L19
  movslq %ebp,%rsi
  mov    %rbx,%rcx
  mov    %rax,%rdx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%rdi
L9:
  mov    %rcx,(%rdx)
  add    %rsi,%rcx
  add    $0x8,%rdx
  cmp    %rdi,%rdx
  jne    L9
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **cmatrix(int n, int m) {
  char *vec = (char *)malloc(n * m * sizeof(char));
  char **mat = (char **)malloc(n * sizeof(char *));
  for (int i = 0; i < n; i++)
    mat[i] = vec + i * m;
  return mat;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmatrix>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %r12d,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  imul   %esi,%edi
  call   <malloc@plt>
  lea    0x0(,%r12,8),%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  test   %r12d,%r12d
  jle    L4
  movslq %ebp,%rsi
  mov    %rbx,%rcx
  lea    (%rax,%r12,8),%rdi
  mov    %rax,%rdx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rcx,(%rdx)
  add    $0x8,%rdx
  add    %rsi,%rcx
  cmp    %rdi,%rdx
  jne    L8
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **cmatrix(int n, int m) {
  char *vec = (char *)malloc(n * m * sizeof(char));
  char **mat = (char **)malloc(n * sizeof(char *));
  for (int i = 0; i < n; i++)
    mat[i] = vec + i * m;
  return mat;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmatrix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  imul   %esi,%edi
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L22
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L49
  movd   %ebp,%xmm5
  mov    %ebx,%edx
  movq   %r12,%xmm3
  mov    %r8,%rax
  pshufd $0x0,%xmm5,%xmm4
  shr    $0x2,%edx
  punpcklqdq %xmm3,%xmm3
  movdqa D6(%rip),%xmm2
  shl    $0x5,%rdx
  movdqa %xmm4,%xmm6
  movdqa D17(%rip),%xmm7
  pxor   %xmm5,%xmm5
  add    %r8,%rdx
  psrlq  $0x20,%xmm6
  nopl   0x0(%rax,%rax,1)
L1:
  movdqa %xmm2,%xmm1
  movdqa %xmm5,%xmm8
  paddd  %xmm7,%xmm2
  add    $0x20,%rax
  movdqa %xmm1,%xmm0
  psrlq  $0x20,%xmm1
  pmuludq %xmm4,%xmm0
  pmuludq %xmm6,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  pcmpgtd %xmm0,%xmm8
  movdqa %xmm0,%xmm1
  punpckldq %xmm8,%xmm1
  punpckhdq %xmm8,%xmm0
  paddq  %xmm3,%xmm1
  paddq  %xmm3,%xmm0
  movups %xmm1,-0x20(%rax)
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L1
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L22
L5:
  mov    %ebp,%edx
  movslq %eax,%rdi
  imul   %eax,%edx
  lea    0x0(,%rdi,8),%rsi
  movslq %edx,%rcx
  add    %r12,%rcx
  mov    %rcx,(%r8,%rdi,8)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%ebx
  jle    L22
  add    %ebp,%edx
  add    $0x2,%eax
  movslq %edx,%rcx
  add    %r12,%rcx
  mov    %rcx,0x8(%r8,%rsi,1)
  cmp    %eax,%ebx
  jle    L22
  add    %edx,%ebp
  movslq %ebp,%rbp
  add    %rbp,%r12
  mov    %r12,0x10(%r8,%rsi,1)
L22:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
L49:
  xor    %eax,%eax
  jmp    L5
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: byte[16]
name: parse_data
arguments: tag: D17
type_infered: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D17": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
char **cmatrix(int n, int m) {
  char *vec = (char *)malloc(n * m * sizeof(char));
  char **mat = (char **)malloc(n * sizeof(char *));
  for (int i = 0; i < n; i++)
    mat[i] = vec + i * m;
  return mat;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x1e8480,%edi
  call   <alloc_init@plt>
  mov    $0x0,%eax
  call   <pthread_yield@plt>
  mov    $0x2dc6c0,%edi
  call   <allocation_stress@plt>
  mov    $0x0,%eax
  call   <alloc_fini@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *thread(void *e) {
  alloc_init(2000 * 1000);
  pthread_yield();
  allocation_stress(3000000);
  alloc_fini();
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <alloc_init@plt>
  mov    $0x0,%eax
  call   <pthread_yield@plt>
  mov    $0x2dc6c0,%edi
  call   <allocation_stress@plt>
  mov    $0x0,%eax
  call   <alloc_fini@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *e) {
  alloc_init(2000 * 1000);
  pthread_yield();
  allocation_stress(3000000);
  alloc_fini();
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <alloc_init@plt>
  xor    %eax,%eax
  call   <pthread_yield@plt>
  mov    $0x2dc6c0,%edi
  call   <allocation_stress@plt>
  xor    %eax,%eax
  call   <alloc_fini@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *e) {
  alloc_init(2000 * 1000);
  pthread_yield();
  allocation_stress(3000000);
  alloc_fini();
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <alloc_init@plt>
  xor    %eax,%eax
  call   <pthread_yield@plt>
  mov    $0x2dc6c0,%edi
  call   <allocation_stress@plt>
  xor    %eax,%eax
  call   <alloc_fini@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *e) {
  alloc_init(2000 * 1000);
  pthread_yield();
  allocation_stress(3000000);
  alloc_fini();
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<writeInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x3c000080,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void writeInt(int n) {
  int volatile *IO = (int *)(0x3c000000 + 4 * 0x00000020);
  *IO = n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<writeInt>:
  endbr64
  mov    %edi,0x3c000080
  ret
```

assistant: ```c
void writeInt(int n) {
  int volatile *IO = (int *)(0x3c000000 + 4 * 0x00000020);
  *IO = n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writeInt>:
  endbr64
  mov    %edi,0x3c000080
  ret
```

assistant: ```c
void writeInt(int n) {
  int volatile *IO = (int *)(0x3c000000 + 4 * 0x00000020);
  *IO = n;
}
```
user: What is the c source code of the assembly code below?

```asm
<writeInt>:
  endbr64
  mov    %edi,0x3c000080
  ret
```

assistant: ```c
void writeInt(int n) {
  int volatile *IO = (int *)(0x3c000000 + 4 * 0x00000020);
  *IO = n;
}
```