ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<formats>:
  endbr64
  test   %rdi,%rdi
  je     L45
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  js     L10
  movslq %eax,%rcx
  mov    %eax,%eax
  lea    (%rbx,%rcx,1),%rdx
  lea    -0x1(%rbx,%rcx,1),%rcx
  sub    %rax,%rcx
  jmp    L55
  nopl   0x0(%rax)
L43:
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L10
L55:
  movzbl (%rdx),%eax
  cmp    $0x7c,%al
  je     L64
  cmp    $0xa,%al
  jne    L43
L64:
  movb   $0x20,(%rdx)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L55
L10:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  ret
```

assistant: ```c
void formats(char *s) {
  int i;
  if (!s)
    return;
  for (i = (int)strlen(s); i >= 0; i--) {
    if ((s[i] == '|') || (s[i] == '\n'))
      s[i] = ' ';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mode_Bet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D16(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L3
  movsd  -0x10(%rbp),%xmm0
  movsd  D16(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L3
  movsd  -0x8(%rbp),%xmm0
  movsd  D16(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  -0x10(%rbp),%xmm1
  movsd  D28(%rip),%xmm2
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  jmp    L4
L3:
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x10(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
L4:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D28
type_guessed: byte[8]

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double mode_Bet(double a, double b) {
  if ((a > 1) && (b > 1)) {
    return ((a - 1) / (a + b - 2));
  } else {
    return (a / (a + b));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mode_Bet>:
  endbr64
  comisd D7(%rip),%xmm0
  jbe    L1
  comisd D7(%rip),%xmm1
  jbe    L1
  movapd %xmm0,%xmm2
  subsd  D7(%rip),%xmm2
  addsd  %xmm0,%xmm1
  subsd  D15(%rip),%xmm1
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  ret
L1:
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: byte[16]
name: extract_symbolic_data
arguments: label: D15
datatype: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double mode_Bet(double a, double b) {
  if ((a > 1) && (b > 1)) {
    return ((a - 1) / (a + b - 2));
  } else {
    return (a / (a + b));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mode_Bet>:
  endbr64
  movsd  D17(%rip),%xmm2
  movapd %xmm0,%xmm3
  addsd  %xmm1,%xmm3
  comisd %xmm2,%xmm0
  jbe    L18
  comisd %xmm2,%xmm1
  jbe    L18
  subsd  %xmm2,%xmm0
  subsd  D14(%rip),%xmm3
  divsd  %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L18:
  divsd  %xmm3,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: byte[8]
name: unpack_data
arguments: tag: D14
type_infered: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double mode_Bet(double a, double b) {
  if ((a > 1) && (b > 1)) {
    return ((a - 1) / (a + b - 2));
  } else {
    return (a / (a + b));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mode_Bet>:
  endbr64
  movsd  D3(%rip),%xmm2
  movapd %xmm0,%xmm3
  addsd  %xmm1,%xmm3
  comisd %xmm2,%xmm0
  jbe    L2
  comisd %xmm2,%xmm1
  jbe    L2
  subsd  %xmm2,%xmm0
  subsd  D16(%rip),%xmm3
  divsd  %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L2:
  divsd  %xmm3,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: byte[8]
name: disassemble_data
arguments: data_label: D16
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double mode_Bet(double a, double b) {
  if ((a > 1) && (b > 1)) {
    return ((a - 1) / (a + b - 2));
  } else {
    return (a / (a + b));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_check_times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    %rax,-0x8(%rbp)
  ja     L9
  cmpl   $0x10000000,-0xc(%rbp)
  jbe    L7
L9:
  mov    $0x180,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L7:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/assert.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/assert.c", 384));
  return word_ans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_check_times>:
  endbr64
  push   %rbx
  mov    %edi,%edi
  mov    %esi,%esi
  imul   %rsi,%rdi
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    %rax,%rdi
  ja     L2
  cmp    $0x10000000,%edi
  jbe    L8
L2:
  mov    $0x180,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L8:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/assert.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/assert.c", 384));
  return word_ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L10
  cmp    $0x10000000,%edi
  ja     L10
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    $0x180,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/assert.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/assert.c", 384));
  return word_ans;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L5
  cmp    $0x10000000,%edi
  ja     L5
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x180,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/assert.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/assert.c", 384));
  return word_ans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_return>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchr@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L26
  cmpl   $0xd,-0x4(%rbp)
  je     L26
  cmpl   $0x20,-0x4(%rbp)
  je     L26
  cmpl   $0xfffffffe,-0x4(%rbp)
  je     L26
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ungetcc@plt>
L26:
  nop
  leave
  ret
```

assistant: ```c
void get_return(void) {
  int c;
  c = getchr();
  if (c != '\n' && c != '\r' && c != ' ' && c != (-2))
    ungetcc(c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_return>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchr@plt>
  mov    %eax,%edi
  lea    0x2(%rax),%eax
  cmp    $0x22,%eax
  ja     L25
  movabs $0x400009001,%rdx
  bt     %rax,%rdx
  jae    L25
L28:
  add    $0x8,%rsp
  ret
L25:
  call   <ungetcc@plt>
  jmp    L28
```

assistant: ```c
void get_return(void) {
  int c;
  c = getchr();
  if (c != '\n' && c != '\r' && c != ' ' && c != (-2))
    ungetcc(c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_return>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchr@plt>
  mov    %eax,%edi
  add    $0x2,%eax
  cmp    $0x22,%eax
  jbe    L3
L18:
  add    $0x8,%rsp
  jmp    1070 <ungetcc@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  movabs $0xfffffffbffff6ffe,%rdx
  bt     %rax,%rdx
  jb     L18
  add    $0x8,%rsp
  ret
```

assistant: ```c
void get_return(void) {
  int c;
  c = getchr();
  if (c != '\n' && c != '\r' && c != ' ' && c != (-2))
    ungetcc(c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_return>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchr@plt>
  mov    %eax,%edi
  add    $0x2,%eax
  cmp    $0x22,%eax
  jbe    L7
L19:
  add    $0x8,%rsp
  jmp    1070 <ungetcc@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  movabs $0xfffffffbffff6ffe,%rdx
  bt     %rax,%rdx
  jb     L19
  add    $0x8,%rsp
  ret
```

assistant: ```c
void get_return(void) {
  int c;
  c = getchr();
  if (c != '\n' && c != '\r' && c != ' ' && c != (-2))
    ungetcc(c);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<validar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L22
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  movss  D28(%rip),%xmm0
  comiss %xmm1,%xmm0
  jae    L26
L22:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L26:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_infered: string
name: unpack_data
arguments: data_tag: D28
type_infered: byte[4]
name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D17: %f

tool: {"D28": [0x00,0x00,0x20,0x41]}

tool: D5: 
Nota invalida, tente novamente: 

assistant: ```c
void validar(float *var) {
  while (1) {
    scanf("%f", var);
    if (*var >= 0 && *var <= 10)
      return;
    printf("\nNota invalida, tente novamente: ");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<validar>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D20(%rip),%rbp
  lea    D15(%rip),%r12
  jmp    L9
L11:
  mov    %r12,%rdi
  call   <printf@plt>
L9:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rbx),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L11
  movss  D19(%rip),%xmm2
  comiss %xmm0,%xmm2
  jb     L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D20
data_type: string
name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: byte[4]

tool: D20: %f

tool: D15: 
Nota invalida, tente novamente: 

tool: {"D19": [0x00,0x00,0x20,0x41]}

assistant: ```c
void validar(float *var) {
  while (1) {
    scanf("%f", var);
    if (*var >= 0 && *var <= 10)
      return;
    printf("\nNota invalida, tente novamente: ");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<validar>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r12,%rdi
  call   <printf@plt>
L1:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rbx),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L25
  movss  D12(%rip),%xmm2
  comiss %xmm0,%xmm2
  jb     L25
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_guessed: string
name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D12
type_guessed: byte[4]

tool: D13: 
Nota invalida, tente novamente: 

tool: D16: %f

tool: {"D12": [0x00,0x00,0x20,0x41]}

assistant: ```c
void validar(float *var) {
  while (1) {
    scanf("%f", var);
    if (*var >= 0 && *var <= 10)
      return;
    printf("\nNota invalida, tente novamente: ");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<validar>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r12,%rdi
  call   <printf@plt>
L12:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rbx),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L2
  movss  D5(%rip),%xmm2
  comiss %xmm0,%xmm2
  jb     L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
type: string
name: read_data
arguments: data_label: D27
type: string
name: read_data
arguments: data_label: D5
type: byte[4]

tool: D19: 
Nota invalida, tente novamente: 

tool: D27: %f

tool: {"D5": [0x00,0x00,0x20,0x41]}

assistant: ```c
void validar(float *var) {
  while (1) {
    scanf("%f", var);
    if (*var >= 0 && *var <= 10)
      return;
    printf("\nNota invalida, tente novamente: ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<interpolate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L25
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L30
L25:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jg     L24
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L30
L24:
  movl   $0x1,-0x8(%rbp)
  jmp    L16
L70:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jg     L46
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L70
  jmp    L56
L46:
  nop
L56:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  sub    %ecx,%eax
  imul   %edx,%eax
  add    %eax,%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  mov    -0x8(%rbp),%ecx
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%rsi
  mov    -0x20(%rbp),%rcx
  add    %rsi,%rcx
  mov    (%rcx),%ecx
  mov    %edx,%edi
  sub    %ecx,%edi
  cltd
  idiv   %edi
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int interpolate(int x, int n, int const *tabx, int const *taby) {
  int index;
  int y;
  if (x >= tabx[0])
    y = taby[0];
  else if (x <= tabx[n - 1])
    y = taby[n - 1];
  else {
    for (index = 1; index < n; index++)
      if (x > tabx[index])
        break;
    y = (taby[index - 1] - taby[index]) * (x - tabx[index]) * 2 / (tabx[index - 1] - tabx[index]);
    y = (y + 1) / 2;
    y += taby[index];
  }
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<interpolate>:
  endbr64
  mov    %rdx,%r8
  cmp    %edi,(%rdx)
  jg     L48
  mov    (%rcx),%eax
  ret
L48:
  movslq %esi,%rax
  lea    0x0(,%rax,4),%rdx
  cmp    %edi,-0x4(%r8,%rax,4)
  jge    L42
  lea    0x4(%r8),%rdx
  mov    $0x1,%eax
  cmp    $0x1,%esi
  jle    L14
L33:
  cmp    %edi,(%rdx)
  jl     L14
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%esi
  jne    L33
  mov    %esi,%eax
L14:
  cltq
  lea    0x0(,%rax,4),%r9
  mov    (%rcx,%rax,4),%esi
  mov    (%r8,%rax,4),%edx
  mov    -0x4(%rcx,%r9,1),%eax
  sub    %esi,%eax
  sub    %edx,%edi
  imul   %edi,%eax
  add    %eax,%eax
  mov    -0x4(%r8,%r9,1),%ecx
  sub    %edx,%ecx
  cltd
  idiv   %ecx
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %esi,%eax
  ret
L42:
  mov    -0x4(%rcx,%rdx,1),%eax
  ret
```

assistant: ```c
int interpolate(int x, int n, int const *tabx, int const *taby) {
  int index;
  int y;
  if (x >= tabx[0])
    y = taby[0];
  else if (x <= tabx[n - 1])
    y = taby[n - 1];
  else {
    for (index = 1; index < n; index++)
      if (x > tabx[index])
        break;
    y = (taby[index - 1] - taby[index]) * (x - tabx[index]) * 2 / (tabx[index - 1] - tabx[index]);
    y = (y + 1) / 2;
    y += taby[index];
  }
  return y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<interpolate>:
  endbr64
  mov    (%rdx),%r10d
  cmp    %edi,%r10d
  jg     L18
  mov    (%rcx),%eax
  ret
  nop
L18:
  movslq %esi,%r11
  lea    0x0(,%r11,4),%rax
  cmp    %edi,-0x4(%rdx,%r11,4)
  jge    L37
  mov    $0x4,%eax
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jg     L60
  jmp    L43
  nopl   0x0(%rax)
L71:
  add    $0x1,%r8d
  add    $0x4,%rax
  cmp    %r8d,%esi
  je     L77
L60:
  mov    (%rdx,%rax,1),%r9d
  cmp    %edi,%r9d
  jge    L71
  mov    -0x4(%rdx,%rax,1),%r10d
  lea    -0x4(%rcx,%rax,1),%rsi
L44:
  mov    (%rcx,%rax,1),%ecx
  mov    (%rsi),%eax
  sub    %r9d,%edi
  sub    %r9d,%r10d
  sub    %ecx,%eax
  imul   %edi,%eax
  add    %eax,%eax
  cltd
  idiv   %r10d
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %ecx,%eax
  ret
  nopl   (%rax)
L37:
  mov    -0x4(%rcx,%rax,1),%eax
  ret
  nopl   (%rax)
L77:
  lea    0x0(,%r11,4),%rax
  mov    (%rdx,%r11,4),%r9d
  mov    -0x4(%rdx,%rax,1),%r10d
  lea    -0x4(%rcx,%rax,1),%rsi
  jmp    L44
L43:
  mov    0x4(%rdx),%r9d
  mov    %rcx,%rsi
  jmp    L44
```

assistant: ```c
int interpolate(int x, int n, int const *tabx, int const *taby) {
  int index;
  int y;
  if (x >= tabx[0])
    y = taby[0];
  else if (x <= tabx[n - 1])
    y = taby[n - 1];
  else {
    for (index = 1; index < n; index++)
      if (x > tabx[index])
        break;
    y = (taby[index - 1] - taby[index]) * (x - tabx[index]) * 2 / (tabx[index - 1] - tabx[index]);
    y = (y + 1) / 2;
    y += taby[index];
  }
  return y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<interpolate>:
  endbr64
  mov    (%rdx),%r10d
  cmp    %edi,%r10d
  jg     L66
  mov    (%rcx),%eax
  ret
  nop
L66:
  movslq %esi,%r11
  lea    0x0(,%r11,4),%rax
  cmp    %edi,-0x4(%rdx,%r11,4)
  jge    L28
  mov    $0x4,%eax
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jg     L62
  jmp    L32
  nopl   0x0(%rax)
L9:
  add    $0x1,%r8d
  add    $0x4,%rax
  cmp    %r8d,%esi
  je     L54
L62:
  mov    (%rdx,%rax,1),%r9d
  cmp    %edi,%r9d
  jge    L9
  mov    -0x4(%rdx,%rax,1),%r10d
  lea    -0x4(%rcx,%rax,1),%rsi
L0:
  mov    (%rcx,%rax,1),%ecx
  mov    (%rsi),%eax
  sub    %r9d,%edi
  sub    %r9d,%r10d
  sub    %ecx,%eax
  imul   %edi,%eax
  add    %eax,%eax
  cltd
  idiv   %r10d
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %ecx,%eax
  ret
  nopl   (%rax)
L28:
  mov    -0x4(%rcx,%rax,1),%eax
  ret
  nopl   (%rax)
L54:
  lea    0x0(,%r11,4),%rax
  mov    (%rdx,%r11,4),%r9d
  mov    -0x4(%rdx,%rax,1),%r10d
  lea    -0x4(%rcx,%rax,1),%rsi
  jmp    L0
L32:
  mov    0x4(%rdx),%r9d
  mov    %rcx,%rsi
  jmp    L0
```

assistant: ```c
int interpolate(int x, int n, int const *tabx, int const *taby) {
  int index;
  int y;
  if (x >= tabx[0])
    y = taby[0];
  else if (x <= tabx[n - 1])
    y = taby[n - 1];
  else {
    for (index = 1; index < n; index++)
      if (x > tabx[index])
        break;
    y = (taby[index - 1] - taby[index]) * (x - tabx[index]) * 2 / (tabx[index - 1] - tabx[index]);
    y = (y + 1) / 2;
    y += taby[index];
  }
  return y;
}
```