ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<strn_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L59
L30:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L20
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L20
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x20,%eax
  jmp    L29
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
L29:
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  cmp    $0x40,%dl
  jle    L91
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  cmp    $0x5a,%dl
  jg     L91
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  add    $0x20,%edx
  jmp    L40
L91:
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
L40:
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L56
  cmpl   $0x0,-0x4(%rbp)
  jns    L94
  mov    $0xffffffff,%eax
  jmp    L12
L94:
  mov    $0x1,%eax
  jmp    L12
L56:
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x24(%rbp)
L59:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L82
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L67
L82:
  cmpl   $0x0,-0x24(%rbp)
  jg     L30
L67:
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int strn_cmp(char *arg1, char *arg2, int n) {
  int chk, i;
  for (i = 0; (*(arg1 + i) || *(arg2 + i)) && (n > 0); i++, n--)
    if (chk = (((*(arg1 + i)) >= 'A' && (*(arg1 + i)) <= 'Z') ? ((*(arg1 + i)) + ('a' - 'A')) : (*(arg1 + i))) - (((*(arg2 + i)) >= 'A' && (*(arg2 + i)) <= 'Z') ? ((*(arg2 + i)) + ('a' - 'A')) : (*(arg2 + i))))
      if (chk < 0)
        return (-1);
      else
        return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strn_cmp>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    $0x0,%esi
  jmp    L19
L46:
  sar    $0x1f,%eax
  or     $0x1,%eax
  ret
L34:
  mov    $0x0,%eax
  ret
L9:
  test   %edx,%edx
  jle    L69
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L4
  movsbl %al,%eax
  add    $0x20,%eax
L71:
  movzbl (%r9,%rsi,1),%ecx
  lea    -0x41(%rcx),%r10d
  movsbl %cl,%edi
  add    $0x20,%edi
  movsbl %cl,%ecx
  cmp    $0x19,%r10b
  cmovbe %edi,%ecx
  add    $0x1,%rsi
  sub    %ecx,%eax
  jne    L46
  sub    $0x1,%edx
L19:
  movzbl (%r8,%rsi,1),%eax
  test   %al,%al
  jne    L9
  cmpb   $0x0,(%r9,%rsi,1)
  je     L34
  test   %edx,%edx
  jle    L47
L4:
  movsbl %al,%eax
  jmp    L71
L69:
  mov    $0x0,%eax
  ret
L47:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strn_cmp(char *arg1, char *arg2, int n) {
  int chk, i;
  for (i = 0; (*(arg1 + i) || *(arg2 + i)) && (n > 0); i++, n--)
    if (chk = (((*(arg1 + i)) >= 'A' && (*(arg1 + i)) <= 'Z') ? ((*(arg1 + i)) + ('a' - 'A')) : (*(arg1 + i))) - (((*(arg2 + i)) >= 'A' && (*(arg2 + i)) <= 'Z') ? ((*(arg2 + i)) + ('a' - 'A')) : (*(arg2 + i))))
      if (chk < 0)
        return (-1);
      else
        return (1);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strn_cmp>:
  endbr64
  mov    %rsi,%r9
  mov    %rdi,%r8
  xor    %esi,%esi
  jmp    L20
  xchg   %ax,%ax
L11:
  movsbl (%r9,%rsi,1),%ecx
  test   %cl,%cl
  je     L5
  test   %edx,%edx
  jle    L5
L18:
  lea    -0x41(%rcx),%r10d
  lea    0x20(%rcx),%edi
  cmp    $0x19,%r10b
  movsbl %dil,%edi
  cmovbe %edi,%ecx
  add    $0x1,%rsi
  sub    %ecx,%eax
  jne    L37
  sub    $0x1,%edx
L20:
  movsbl (%r8,%rsi,1),%eax
  test   %al,%al
  je     L11
  test   %edx,%edx
  jle    L5
  lea    -0x41(%rax),%edi
  movsbl (%r9,%rsi,1),%ecx
  cmp    $0x19,%dil
  ja     L18
  add    $0x20,%eax
  movsbl %al,%eax
  jmp    L18
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  sar    $0x1f,%eax
  or     $0x1,%eax
  ret
```

assistant: ```c
int strn_cmp(char *arg1, char *arg2, int n) {
  int chk, i;
  for (i = 0; (*(arg1 + i) || *(arg2 + i)) && (n > 0); i++, n--)
    if (chk = (((*(arg1 + i)) >= 'A' && (*(arg1 + i)) <= 'Z') ? ((*(arg1 + i)) + ('a' - 'A')) : (*(arg1 + i))) - (((*(arg2 + i)) >= 'A' && (*(arg2 + i)) <= 'Z') ? ((*(arg2 + i)) + ('a' - 'A')) : (*(arg2 + i))))
      if (chk < 0)
        return (-1);
      else
        return (1);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<strn_cmp>:
  endbr64
  mov    %rsi,%r9
  mov    %rdi,%r8
  xor    %esi,%esi
  jmp    L77
  xchg   %ax,%ax
L38:
  movsbl (%r9,%rsi,1),%ecx
  test   %cl,%cl
  je     L64
  test   %edx,%edx
  jle    L64
L52:
  lea    -0x41(%rcx),%edi
  cmp    $0x19,%dil
  ja     L31
L85:
  add    $0x20,%ecx
  add    $0x1,%rsi
  movsbl %cl,%ecx
  sub    %ecx,%eax
  jne    L70
L42:
  sub    $0x1,%edx
L77:
  movsbl (%r8,%rsi,1),%eax
  test   %al,%al
  je     L38
  test   %edx,%edx
  jle    L64
  lea    -0x41(%rax),%edi
  movsbl (%r9,%rsi,1),%ecx
  cmp    $0x19,%dil
  ja     L52
  add    $0x20,%eax
  lea    -0x41(%rcx),%edi
  movsbl %al,%eax
  cmp    $0x19,%dil
  jbe    L85
L31:
  add    $0x1,%rsi
  sub    %ecx,%eax
  je     L42
L70:
  sar    $0x1f,%eax
  or     $0x1,%eax
  ret
L64:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strn_cmp(char *arg1, char *arg2, int n) {
  int chk, i;
  for (i = 0; (*(arg1 + i) || *(arg2 + i)) && (n > 0); i++, n--)
    if (chk = (((*(arg1 + i)) >= 'A' && (*(arg1 + i)) <= 'Z') ? ((*(arg1 + i)) + ('a' - 'A')) : (*(arg1 + i))) - (((*(arg2 + i)) >= 'A' && (*(arg2 + i)) <= 'Z') ? ((*(arg2 + i)) + ('a' - 'A')) : (*(arg2 + i))))
      if (chk < 0)
        return (-1);
      else
        return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<next_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  and    -0x8(%rbp),%rax
  test   %rax,%rax
  je     L1
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    %rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x2,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x4,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  or     %rax,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L29
L1:
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t next_power(size_t size) {
  if ((size & (size - 1)) != 0) {
    --size;
    size |= size >> 1;
    size |= size >> 2;
    size |= size >> 4;
    size |= size >> 8;
    size |= size >> 16;
    ++size;
  } else if (size == 0) {
    ++size;
  }
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_power>:
  endbr64
  lea    -0x1(%rdi),%rdx
  test   %rdi,%rdi
  mov    $0x1,%eax
  cmovne %rdi,%rax
  test   %rdi,%rdx
  je     L2
  mov    %rdx,%rax
  shr    %rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x2,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x8,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  or     %rdx,%rax
  add    $0x1,%rax
L2:
  ret
```

assistant: ```c
size_t next_power(size_t size) {
  if ((size & (size - 1)) != 0) {
    --size;
    size |= size >> 1;
    size |= size >> 2;
    size |= size >> 4;
    size |= size >> 8;
    size |= size >> 16;
    ++size;
  } else if (size == 0) {
    ++size;
  }
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<next_power>:
  endbr64
  test   %rdi,%rdi
  mov    $0x1,%eax
  lea    -0x1(%rdi),%rdx
  cmovne %rdi,%rax
  test   %rdi,%rdx
  je     L0
  mov    %rdx,%rax
  shr    %rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x2,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x8,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  or     %rdx,%rax
  add    $0x1,%rax
L0:
  ret
```

assistant: ```c
size_t next_power(size_t size) {
  if ((size & (size - 1)) != 0) {
    --size;
    size |= size >> 1;
    size |= size >> 2;
    size |= size >> 4;
    size |= size >> 8;
    size |= size >> 16;
    ++size;
  } else if (size == 0) {
    ++size;
  }
  return size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_power>:
  endbr64
  test   %rdi,%rdi
  mov    $0x1,%eax
  lea    -0x1(%rdi),%rdx
  cmovne %rdi,%rax
  test   %rdi,%rdx
  je     L0
  mov    %rdx,%rax
  shr    %rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x2,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x8,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  or     %rdx,%rax
  add    $0x1,%rax
L0:
  ret
```

assistant: ```c
size_t next_power(size_t size) {
  if ((size & (size - 1)) != 0) {
    --size;
    size |= size >> 1;
    size |= size >> 2;
    size |= size >> 4;
    size |= size >> 8;
    size |= size >> 16;
    ++size;
  } else if (size == 0) {
    ++size;
  }
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drv_GU311_make_text_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x16,%edx
  imul   %edx,%eax
  mov    -0x18(%rbp),%edx
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x57,-0x1(%rbp)
  ja     L33
  cmpl   $0x57,-0x24(%rbp)
  jg     L12
  movzbl -0x1(%rbp),%eax
  mov    %al,D29(%rip)
  mov    -0x24(%rbp),%eax
  mov    %al,D24(%rip)
  lea    D4(%rip),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x24(%rbp),%eax
  add    $0x5,%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <drv_GU311_send_string@plt>
  jmp    L15
L33:
  nop
  jmp    L15
L12:
  nop
L15:
  leave
  ret
```

assistant: ```c
void drv_GU311_make_text_string(const int row, const int col, const char *data, int len) {
  static char cmd[96] = {0x01, 'C', 0, 0, 'S', 0};
  unsigned char start_addr;
  start_addr = (0x16 * row) + col;
  if (start_addr > 0x57)
    return;
  if (len > 0x57)
    return;
  cmd[2] = start_addr;
  cmd[3] = len;
  memcpy(cmd + 5, data, len);
  drv_GU311_send_string(cmd, len + 5);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<drv_GU311_make_text_string>:
  endbr64
  mov    $0x16,%eax
  imul   %edi,%eax
  add    %esi,%eax
  cmp    $0x57,%ecx
  jg     L5
  push   %rbx
  mov    %rdx,%rsi
  mov    %ecx,%ebx
  cmp    $0x57,%al
  jbe    L16
L13:
  pop    %rbx
  ret
L16:
  mov    %al,D18(%rip)
  mov    %cl,D10(%rip)
  mov    %ecx,%edx
  lea    D36(%rip),%rdi
  call   <memcpy@plt>
  lea    0x5(%rbx),%esi
  lea    D0(%rip),%rdi
  call   <drv_GU311_send_string@plt>
  jmp    L13
L5:
  ret
```

assistant: ```c
void drv_GU311_make_text_string(const int row, const int col, const char *data, int len) {
  static char cmd[96] = {0x01, 'C', 0, 0, 'S', 0};
  unsigned char start_addr;
  start_addr = (0x16 * row) + col;
  if (start_addr > 0x57)
    return;
  if (len > 0x57)
    return;
  cmd[2] = start_addr;
  cmd[3] = len;
  memcpy(cmd + 5, data, len);
  drv_GU311_send_string(cmd, len + 5);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<drv_GU311_make_text_string>:
  endbr64
  mov    $0x16,%eax
  imul   %edi,%eax
  add    %esi,%eax
  cmp    $0x57,%al
  ja     L0
  push   %rbx
  mov    %ecx,%ebx
  cmp    $0x57,%ecx
  jle    L6
  pop    %rbx
  ret
  nopl   0x0(%rax)
L6:
  mov    %rdx,%rsi
  lea    D13(%rip),%rdi
  mov    %ecx,%edx
  mov    %al,D15(%rip)
  mov    %cl,D4(%rip)
  call   <memcpy@plt>
  lea    0x5(%rbx),%esi
  lea    D35(%rip),%rdi
  pop    %rbx
  jmp    1060 <drv_GU311_send_string@plt>
  nopl   (%rax)
L0:
  ret
```

assistant: ```c
void drv_GU311_make_text_string(const int row, const int col, const char *data, int len) {
  static char cmd[96] = {0x01, 'C', 0, 0, 'S', 0};
  unsigned char start_addr;
  start_addr = (0x16 * row) + col;
  if (start_addr > 0x57)
    return;
  if (len > 0x57)
    return;
  cmd[2] = start_addr;
  cmd[3] = len;
  memcpy(cmd + 5, data, len);
  drv_GU311_send_string(cmd, len + 5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drv_GU311_make_text_string>:
  endbr64
  mov    $0x16,%eax
  imul   %edi,%eax
  add    %esi,%eax
  cmp    $0x57,%al
  ja     L15
  push   %rbx
  mov    %ecx,%ebx
  cmp    $0x57,%ecx
  jle    L9
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  mov    %rdx,%rsi
  xor    %edx,%edx
  lea    D1(%rip),%rdi
  mov    %al,%dl
  mov    %cl,%dh
  mov    %dx,D6(%rip)
  mov    %ecx,%edx
  call   <memcpy@plt>
  lea    0x5(%rbx),%esi
  lea    D12(%rip),%rdi
  pop    %rbx
  jmp    1060 <drv_GU311_send_string@plt>
  xchg   %ax,%ax
L15:
  ret
```

assistant: ```c
void drv_GU311_make_text_string(const int row, const int col, const char *data, int len) {
  static char cmd[96] = {0x01, 'C', 0, 0, 'S', 0};
  unsigned char start_addr;
  start_addr = (0x16 * row) + col;
  if (start_addr > 0x57)
    return;
  if (len > 0x57)
    return;
  cmd[2] = start_addr;
  cmd[3] = len;
  memcpy(cmd + 5, data, len);
  drv_GU311_send_string(cmd, len + 5);
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L34
L23:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    $0x1,%eax
  jmp    L67
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L39
  mov    $0xffffffff,%eax
  jmp    L67
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L79
  mov    $0x1,%eax
  jmp    L67
L79:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    $0x0,%eax
  jmp    L67
L22:
  mov    $0xffffffff,%eax
L67:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; *s1; s1++, s2++) {
    if (!*s2)
      return 1;
    if (*s1 < *s2)
      return -1;
    if (*s1 > *s2)
      return 1;
  }
  return !*s2 ? 0 : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L41
L9:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L3
  cmp    %al,%dl
  jg     L36
  jl     L32
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L9
L41:
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
L3:
  mov    $0x1,%eax
  ret
L36:
  mov    $0xffffffff,%eax
  ret
L32:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; *s1; s1++, s2++) {
    if (!*s2)
      return 1;
    if (*s1 < *s2)
      return -1;
    if (*s1 > *s2)
      return 1;
  }
  return !*s2 ? 0 : -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcmp>:
  endbr64
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L27:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L20
  cmp    %al,%dl
  jg     L8
  jl     L20
  add    $0x1,%rdi
  add    $0x1,%rsi
L38:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L27
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; *s1; s1++, s2++) {
    if (!*s2)
      return 1;
    if (*s1 < *s2)
      return -1;
    if (*s1 > *s2)
      return 1;
  }
  return !*s2 ? 0 : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcmp>:
  endbr64
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L10:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L40
  cmp    %al,%dl
  jg     L36
  jl     L40
  add    $0x1,%rdi
  add    $0x1,%rsi
L16:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
  nopl   0x0(%rax)
L40:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L36:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; *s1; s1++, s2++) {
    if (!*s2)
      return 1;
    if (*s1 < *s2)
      return -1;
    if (*s1 > *s2)
      return 1;
  }
  return !*s2 ? 0 : -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<call_by_ptr_bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x34(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,%rdi
  call   <ptr_set_to_zero@plt>
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movl   $0x7b,-0x30(%rbp,%rax,4)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void call_by_ptr_bad() {
  int arr[10];
  int i = 5;
  ptr_set_to_zero(&i);
  arr[i - 1] = 123;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<call_by_ptr_bad>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <ptr_set_to_zero@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void call_by_ptr_bad() {
  int arr[10];
  int i = 5;
  ptr_set_to_zero(&i);
  arr[i - 1] = 123;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call_by_ptr_bad>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x5,0x4(%rsp)
  call   <ptr_set_to_zero@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void call_by_ptr_bad() {
  int arr[10];
  int i = 5;
  ptr_set_to_zero(&i);
  arr[i - 1] = 123;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<call_by_ptr_bad>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x5,0x4(%rsp)
  call   <ptr_set_to_zero@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void call_by_ptr_bad() {
  int arr[10];
  int i = 5;
  ptr_set_to_zero(&i);
  arr[i - 1] = 123;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xCalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <xMalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xCalloc(const size_t count, const size_t eltsize) {
  void *temp = xMalloc(count * eltsize);
  memset(temp, 0, count * eltsize);
  return temp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xCalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <xMalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *xCalloc(const size_t count, const size_t eltsize) {
  void *temp = xMalloc(count * eltsize);
  memset(temp, 0, count * eltsize);
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xCalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <xMalloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xCalloc(const size_t count, const size_t eltsize) {
  void *temp = xMalloc(count * eltsize);
  memset(temp, 0, count * eltsize);
  return temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xCalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <xMalloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xCalloc(const size_t count, const size_t eltsize) {
  void *temp = xMalloc(count * eltsize);
  memset(temp, 0, count * eltsize);
  return temp;
}
```
user: What is the c source code of the assembly code below:

```asm
<zeros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L10
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L3
L10:
  nop
L3:
  leave
  ret
```

assistant: ```c
void zeros(int *list, int n) {
  if (n == 0)
    return;
  memset(list, 0, n * sizeof(int));
}
```
user: Translate the below assembly code into C programming language:

```asm
<zeros>:
  endbr64
  test   %esi,%esi
  jne    L8
  ret
L8:
  sub    $0x8,%rsp
  lea    0x0(,%rsi,4),%edx
  mov    $0x0,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void zeros(int *list, int n) {
  if (n == 0)
    return;
  memset(list, 0, n * sizeof(int));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zeros>:
  endbr64
  test   %esi,%esi
  jne    L9
  ret
  nopl   0x0(%rax)
L9:
  lea    0x0(,%rsi,4),%edx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void zeros(int *list, int n) {
  if (n == 0)
    return;
  memset(list, 0, n * sizeof(int));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<zeros>:
  endbr64
  test   %esi,%esi
  jne    L0
  ret
  nopl   0x0(%rax)
L0:
  lea    0x0(,%rsi,4),%edx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void zeros(int *list, int n) {
  if (n == 0)
    return;
  memset(list, 0, n * sizeof(int));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D4: Hello World ! 


assistant: ```c
int main() {
  printf("Hello World ! \n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0: Hello World ! 


assistant: ```c
int main() {
  printf("Hello World ! \n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D4: Hello World ! 


assistant: ```c
int main() {
  printf("Hello World ! \n");
  return 0;
}
```