user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D76(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x3,%eax
  jle    L84
  test   $0x1,%al
  jne    L73
  lea    D105(%rip),%rdi
  call   <puts@plt>
  lea    D82(%rip),%rdi
  call   <puts@plt>
  lea    D109(%rip),%rdi
  call   <puts@plt>
  lea    D118(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x4,0x4(%rsp)
  jle    L32
  mov    $0x5,%ebx
  lea    D121(%rip),%r12
  lea    D148(%rip),%rbp
L10:
  lea    0x1(%rbx),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  add    $0x2,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L10
  jmp    L32
L84:
  lea    D129(%rip),%rdi
  call   <puts@plt>
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L73:
  lea    D105(%rip),%rdi
  call   <puts@plt>
  lea    D82(%rip),%rdi
  call   <puts@plt>
  lea    D83(%rip),%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    D112(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x5,0x4(%rsp)
  jle    L32
  mov    $0x6,%ebx
  lea    D121(%rip),%r12
  lea    D148(%rip),%rbp
L83:
  lea    0x1(%rbx),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  add    $0x2,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L83
  jmp    L32
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D76
datatype: string
name: extract_symbolic_data
arguments: data_tag: D105
datatype: string
name: extract_symbolic_data
arguments: data_tag: D82
datatype: string
name: extract_symbolic_data
arguments: data_tag: D109
datatype: string
name: extract_symbolic_data
arguments: data_tag: D118
datatype: string
name: extract_symbolic_data
arguments: data_tag: D121
datatype: string
name: extract_symbolic_data
arguments: data_tag: D148
datatype: string
name: extract_symbolic_data
arguments: data_tag: D129
datatype: string
name: extract_symbolic_data
arguments: data_tag: D83
datatype: string
name: extract_symbolic_data
arguments: data_tag: D25
datatype: string
name: extract_symbolic_data
arguments: data_tag: D112
datatype: string

tool: D76: %d

tool: D105: YES

tool: D82: 1 * 2 = 2

tool: D109: 2 * 3 = 6

tool: D118: 6 * 4 = 24

tool: D121: %d - %d = 1


tool: D148: 24 * 1 = 24

tool: D129: NO

tool: D83: 3 + 4 = 7

tool: D25: 7 + 5 = 12

tool: D112: 12 * 2 = 24

assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  if (n < 4) {
    printf("NO\n");
  } else {
    if (n % 2 == 0) {
      printf("YES\n");
      printf("1 * 2 = 2\n");
      printf("2 * 3 = 6\n");
      printf("6 * 4 = 24\n");
      for (i = 5; i <= n; i += 2) {
        printf("%d - %d = 1\n", i + 1, i);
        printf("24 * 1 = 24\n");
      }
    } else {
      printf("YES\n");
      printf("1 * 2 = 2\n");
      printf("3 + 4 = 7\n");
      printf("7 + 5 = 12\n");
      printf("12 * 2 = 24\n");
      for (i = 6; i <= n; i += 2) {
        printf("%d - %d = 1\n", i + 1, i);
        printf("24 * 1 = 24\n");
      }
    }
  }
  return 0;
}
```