ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3,%esi
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000003,%rax
  movl   $0x2d,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x14(%rsp),%rbp
  mov    %rbx,%r13
  mov    %rax,(%rsp)
  movabs $0x2000000037,%rax
  mov    %rax,0x8(%rsp)
L25:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  je     L29
  mov    0x0(%r13),%esi
  jmp    L25
  nopl   0x0(%rax)
L29:
  mov    $0xa,%edi
  mov    %rbx,%r13
  call   <putchar@plt>
  mov    $0x3,%esi
L51:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  je     L70
  mov    0x0(%r13),%esi
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L70:
  mov    $0xa,%edi
  mov    %rbx,%r13
  call   <putchar@plt>
  mov    $0x3,%esi
L77:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  je     L0
  mov    0x0(%r13),%esi
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x3,%esi
L52:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L89
  mov    (%rbx),%esi
  jmp    L52
  xchg   %ax,%ax
L89:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: D6: %d	

assistant: ```c
int main() {
  int a[] = {3, 4, 55, 32, 45}, i, *idx;
  for (i = 0; i < 5; i++) {
    printf("%d\t", *(a + i));
  }
  printf("\n");
  idx = a;
  for (i = 0; i < 5; i++) {
    printf("%d\t", idx[i]);
  }
  printf("\n");
  for (i = 0; i < 5; i++) {
    printf("%d\t", *(a + i));
  }
  printf("\n");
  for (i = 0; i < 5; i++) {
    printf("%d\t", *(idx + i));
  }
  printf("\n");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movdqa D15(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2d,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x14(%rsp),%rbp
  movaps %xmm0,(%rsp)
  mov    %rbx,%r13
L46:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L46
  mov    $0xa,%edi
  mov    %rbx,%r13
  call   <putchar@plt>
L47:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L47
  mov    $0xa,%edi
  mov    %rbx,%r13
  call   <putchar@plt>
L49:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L49
  mov    $0xa,%edi
  call   <putchar@plt>
L38:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L38
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: byte[16]

tool: D1: %d	

tool: {"D15": [0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x37,0x00,0x00,0x00,0x20,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[] = {3, 4, 55, 32, 45}, i, *idx;
  for (i = 0; i < 5; i++) {
    printf("%d\t", *(a + i));
  }
  printf("\n");
  idx = a;
  for (i = 0; i < 5; i++) {
    printf("%d\t", idx[i]);
  }
  printf("\n");
  for (i = 0; i < 5; i++) {
    printf("%d\t", *(a + i));
  }
  printf("\n");
  for (i = 0; i < 5; i++) {
    printf("%d\t", *(idx + i));
  }
  printf("\n");
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<web_get_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L10
L7:
  movsbl -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x1c(%rbp),%eax
  jmp    L10
L11:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
unsigned int web_get_word(const char *data, unsigned int size, char delim) {
  char *p;
  if (!size)
    return 0;
  p = memchr(data, delim, size);
  if (p == 0)
    return size;
  return p - data;
}
```
user: What is the c source code of the assembly code below:

```asm
<web_get_word>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  test   %esi,%esi
  jne    L13
L3:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    %rdi,%rbp
  movsbl %dl,%esi
  mov    %ebx,%edx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  cmovne %edx,%ebx
  jmp    L3
```

assistant: ```c
unsigned int web_get_word(const char *data, unsigned int size, char delim) {
  char *p;
  if (!size)
    return 0;
  p = memchr(data, delim, size);
  if (p == 0)
    return size;
  return p - data;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<web_get_word>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L2
  movsbl %dl,%esi
  mov    %r12d,%edx
  mov    %rdi,%rbx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  cmovne %edx,%r12d
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int web_get_word(const char *data, unsigned int size, char delim) {
  char *p;
  if (!size)
    return 0;
  p = memchr(data, delim, size);
  if (p == 0)
    return size;
  return p - data;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<web_get_word>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L8
  movsbl %dl,%esi
  mov    %r12d,%edx
  mov    %rdi,%rbx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  cmovne %edx,%r12d
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int web_get_word(const char *data, unsigned int size, char delim) {
  char *p;
  if (!size)
    return 0;
  p = memchr(data, delim, size);
  if (p == 0)
    return size;
  return p - data;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<free_2d_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_2d_int(int **arr, int row) {
  int i;
  for (i = 0; i < row; i++)
    free(arr[i]);
  free(arr);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<free_2d_int>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L3:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L3
L6:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free_2d_int(int **arr, int row) {
  int i;
  for (i = 0; i < row; i++)
    free(arr[i]);
  free(arr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_2d_int>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L6
L15:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_2d_int(int **arr, int row) {
  int i;
  for (i = 0; i < row; i++)
    free(arr[i]);
  free(arr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_2d_int>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L1
L9:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_2d_int(int **arr, int row) {
  int i;
  for (i = 0; i < row; i++)
    free(arr[i]);
  free(arr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  mov    %rsi,%rcx
  mov    %edx,%r10d
  mov    %edx,%eax
  and    $0xfffffff7,%eax
  cmp    $0x2,%eax
  je     L54
  cmp    $0x10,%edx
  jne    L130
L54:
  push   %rbx
  test   %edi,%edi
  jne    L96
  movb   $0x30,(%rcx)
  cmp    $0xa,%r10d
  sete   %r11b
  mov    $0x1,%r9d
L50:
  cmp    $0x10,%r10d
  je     L120
  mov    $0xa,%esi
  test   %edi,%edi
  jle    L168
L146:
  mov    $0x0,%ebx
  jmp    L144
L130:
  movb   $0x0,(%rsi)
  ret
L96:
  cmp    $0xa,%r10d
  sete   %al
  mov    %edi,%r11d
  shr    $0x1f,%r11d
  and    %al,%r11b
  je     L64
  neg    %edi
  mov    $0x1,%ebx
  mov    $0xa,%esi
  mov    $0x0,%r9d
L144:
  add    $0x1,%r9d
  movslq %r9d,%r8
L43:
  mov    %edi,%eax
  cltd
  idiv   %esi
  lea    0x30(%rdx),%r9d
  lea    0x57(%rdx),%eax
  cmp    $0x9,%edx
  cmovle %r9d,%eax
  mov    %r8d,%r9d
  mov    %al,-0x1(%rcx,%r8,1)
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%edi
  add    $0x1,%r8
  test   %eax,%eax
  jg     L43
  test   %ebx,%ebx
  je     L168
  test   %r11b,%r11b
  je     L168
  lea    0x1(%r9),%eax
  movslq %r9d,%r9
  movb   $0x2d,(%rcx,%r9,1)
L21:
  movslq %eax,%rdx
  movb   $0x0,(%rcx,%rdx,1)
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L16
  cltq
  mov    $0x0,%edx
L33:
  movzbl (%rcx,%rdx,1),%esi
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  mov    %sil,(%rcx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L33
L16:
  pop    %rbx
  ret
L64:
  mov    %eax,%r11d
  mov    $0x0,%r9d
  jmp    L50
L168:
  mov    %r9d,%eax
  cmp    $0x10,%r10d
  jne    L21
L112:
  movslq %r9d,%rax
  movb   $0x78,(%rcx,%rax,1)
  lea    0x2(%r9),%eax
  add    $0x1,%r9d
  movslq %r9d,%r9
  movb   $0x30,(%rcx,%r9,1)
  jmp    L21
L120:
  mov    %r10d,%esi
  test   %edi,%edi
  jg     L146
  jmp    L112
```

assistant: ```c
void itoa(int value, char *str, int base) {
  uint8_t i = 0;
  uint8_t j = 0;
  uint8_t divisor = 10;
  uint8_t is_negative = 0;
  uint8_t remainder;
  uint8_t tmp;
  if ((base != 2) && (base != 10) && (base != 16)) {
    *str = '\0';
    return;
  }
  if (value == 0)
    str[i++] = '0';
  if (base == 10 && value < 0) {
    is_negative = 1;
    value = -value;
  } else if (base == 16)
    divisor = 16;
  while (value > 0) {
    remainder = value % divisor;
    str[i++] = (remainder < 10) ? remainder + '0' : remainder + 'a' - 10;
    value = value / divisor;
  }
  if (base == 10 && is_negative)
    str[i++] = '-';
  if (base == 16) {
    str[i++] = 'x';
    str[i++] = '0';
  }
  str[i] = '\0';
  for (i = i - 1, j = 0; j < i; i--, j++) {
    tmp = str[j];
    str[j] = str[i];
    str[i] = tmp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa>:
  endbr64
  mov    %edx,%r10d
  and    $0xfffffff7,%edx
  mov    %edi,%eax
  mov    %rsi,%rcx
  cmp    $0x2,%edx
  je     L140
  cmp    $0x10,%r10d
  jne    L1
L140:
  cmp    $0xa,%r10d
  sete   %r11b
  test   %eax,%eax
  je     L130
  mov    %eax,%edx
  shr    $0x1f,%edx
  and    %dl,%r11b
  je     L111
  neg    %eax
  mov    $0xa,%r8d
L68:
  mov    $0x1,%esi
  nopl   (%rax)
L5:
  cltd
  idiv   %r8d
  cmp    $0x9,%edx
  lea    0x30(%rdx),%r9d
  lea    0x57(%rdx),%edi
  mov    %esi,%edx
  cmovle %r9d,%edi
  mov    %dil,-0x1(%rcx,%rsi,1)
  add    $0x1,%rsi
  test   %eax,%eax
  jne    L5
  movslq %edx,%rsi
  mov    %rsi,%rax
  test   %r11b,%r11b
  je     L153
  add    $0x1,%edx
  movb   $0x2d,(%rcx,%rsi,1)
  movslq %edx,%rdx
  movb   $0x0,(%rcx,%rdx,1)
L109:
  xor    %edx,%edx
  nopl   0x0(%rax)
L186:
  movzbl (%rcx,%rdx,1),%esi
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  add    $0x1,%rdx
  mov    %sil,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L186
  ret
  nopl   (%rax)
L130:
  movb   $0x30,(%rcx)
  cmp    $0x10,%r10d
  je     L24
  mov    $0x1,%edx
  mov    $0x1,%esi
L81:
  sub    $0x1,%edx
  movb   $0x0,(%rcx,%rsi,1)
  test   %edx,%edx
  jg     L104
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movb   $0x0,(%rsi)
  ret
  nopl   0x0(%rax)
L153:
  cmp    $0x10,%r10d
  jne    L81
L198:
  lea    0x1(%rdx),%eax
  add    $0x2,%edx
  movb   $0x78,(%rcx,%rsi,1)
  cltq
  movslq %edx,%rdx
  movb   $0x30,(%rcx,%rax,1)
  movb   $0x0,(%rcx,%rdx,1)
  jmp    L109
L104:
  movslq %edx,%rax
  jmp    L109
L24:
  mov    $0x1,%esi
  mov    $0x1,%edx
  jmp    L198
L111:
  cmp    $0x10,%r10d
  je     L61
  test   %eax,%eax
  jle    L36
  mov    $0xa,%r8d
  jmp    L68
L61:
  test   %eax,%eax
  jle    L63
  mov    $0x10,%r8d
  jmp    L68
L36:
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    L81
L63:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L198
```

assistant: ```c
void itoa(int value, char *str, int base) {
  uint8_t i = 0;
  uint8_t j = 0;
  uint8_t divisor = 10;
  uint8_t is_negative = 0;
  uint8_t remainder;
  uint8_t tmp;
  if ((base != 2) && (base != 10) && (base != 16)) {
    *str = '\0';
    return;
  }
  if (value == 0)
    str[i++] = '0';
  if (base == 10 && value < 0) {
    is_negative = 1;
    value = -value;
  } else if (base == 16)
    divisor = 16;
  while (value > 0) {
    remainder = value % divisor;
    str[i++] = (remainder < 10) ? remainder + '0' : remainder + 'a' - 10;
    value = value / divisor;
  }
  if (base == 10 && is_negative)
    str[i++] = '-';
  if (base == 16) {
    str[i++] = 'x';
    str[i++] = '0';
  }
  str[i] = '\0';
  for (i = i - 1, j = 0; j < i; i--, j++) {
    tmp = str[j];
    str[j] = str[i];
    str[i] = tmp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa>:
  endbr64
  mov    %edx,%r9d
  and    $0xfffffff7,%edx
  mov    %edi,%eax
  mov    %rsi,%rcx
  cmp    $0x2,%edx
  je     L112
  cmp    $0x10,%r9d
  jne    L164
L112:
  cmp    $0xa,%r9d
  sete   %dl
  test   %eax,%eax
  je     L59
  mov    %eax,%esi
  shr    $0x1f,%esi
  and    %sil,%dl
  mov    %edx,%r10d
  je     L114
  neg    %eax
  mov    $0xa,%edi
L32:
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L176:
  cltd
  mov    %esi,%r8d
  idiv   %edi
  cmp    $0x9,%edx
  jg     L116
  add    $0x30,%edx
  mov    %dl,-0x1(%rcx,%rsi,1)
  add    $0x1,%rsi
  test   %eax,%eax
  jne    L176
  movslq %r8d,%rdx
  mov    %rdx,%rax
  test   %r10b,%r10b
  je     L115
L9:
  add    $0x1,%r8d
  movb   $0x2d,(%rcx,%rdx,1)
  movslq %r8d,%r8
  movb   $0x0,(%rcx,%r8,1)
L223:
  xor    %edx,%edx
  nop
L182:
  movzbl (%rcx,%rdx,1),%esi
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  add    $0x1,%rdx
  mov    %sil,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L182
  ret
  nopl   (%rax)
L59:
  movb   $0x30,(%rcx)
  cmp    $0x10,%r9d
  je     L149
  mov    $0x1,%r8d
  mov    $0x1,%edx
L62:
  sub    $0x1,%r8d
  movb   $0x0,(%rcx,%rdx,1)
  test   %r8d,%r8d
  jg     L20
  ret
  nopw   0x0(%rax,%rax,1)
L164:
  movb   $0x0,(%rsi)
  ret
  nopl   0x0(%rax)
L116:
  add    $0x57,%edx
  mov    %dl,-0x1(%rcx,%rsi,1)
  add    $0x1,%rsi
  test   %eax,%eax
  jne    L176
  movslq %r8d,%rdx
  mov    %rdx,%rax
  test   %r10b,%r10b
  jne    L9
L115:
  cmp    $0x10,%r9d
  jne    L62
  lea    0x1(%r8),%esi
  lea    0x2(%r8),%eax
  movslq %esi,%rdi
  cltq
  mov    %esi,%r8d
L133:
  movb   $0x78,(%rcx,%rdx,1)
  movb   $0x30,(%rcx,%rdi,1)
  movb   $0x0,(%rcx,%rax,1)
  movslq %r8d,%rax
  jmp    L223
L20:
  movslq %r8d,%rax
  jmp    L223
L149:
  mov    $0x3,%eax
  mov    $0x2,%edi
  mov    $0x2,%r8d
  mov    $0x1,%edx
  jmp    L133
L114:
  cmp    $0x10,%r9d
  je     L153
  test   %eax,%eax
  jle    L226
  mov    $0xa,%edi
  jmp    L32
L153:
  test   %eax,%eax
  jle    L40
  mov    $0x10,%edi
  jmp    L32
L226:
  xor    %r8d,%r8d
  xor    %edx,%edx
  jmp    L62
L40:
  mov    $0x2,%eax
  mov    $0x1,%edi
  mov    $0x1,%r8d
  xor    %edx,%edx
  jmp    L133
```

assistant: ```c
void itoa(int value, char *str, int base) {
  uint8_t i = 0;
  uint8_t j = 0;
  uint8_t divisor = 10;
  uint8_t is_negative = 0;
  uint8_t remainder;
  uint8_t tmp;
  if ((base != 2) && (base != 10) && (base != 16)) {
    *str = '\0';
    return;
  }
  if (value == 0)
    str[i++] = '0';
  if (base == 10 && value < 0) {
    is_negative = 1;
    value = -value;
  } else if (base == 16)
    divisor = 16;
  while (value > 0) {
    remainder = value % divisor;
    str[i++] = (remainder < 10) ? remainder + '0' : remainder + 'a' - 10;
    value = value / divisor;
  }
  if (base == 10 && is_negative)
    str[i++] = '-';
  if (base == 16) {
    str[i++] = 'x';
    str[i++] = '0';
  }
  str[i] = '\0';
  for (i = i - 1, j = 0; j < i; i--, j++) {
    tmp = str[j];
    str[j] = str[i];
    str[i] = tmp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rbx
  mov    -0x30(%rbp),%r12
  cmp    %r12,%rbx
  jne    L0
  mov    $0x0,%eax
  jmp    L38
L0:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x12(%rbp)
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x12(%rbp)
  je     L18
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  je     L0
  jmp    L3
L18:
  nop
L3:
  movzbl -0x12(%rbp),%eax
  movzbl -0x11(%rbp),%edx
  sub    %edx,%eax
L38:
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int strcasecmp(s1, s2) const char *s1;
const char *s2;
{
  register const unsigned char *p1 = (const unsigned char *)s1;
  register const unsigned char *p2 = (const unsigned char *)s2;
  unsigned char c1, c2;
  if (p1 == p2)
    return 0;
  do {
    c1 = tolower(*p1++);
    c2 = tolower(*p2++);
    if (c1 == '\0')
      break;
  } while (c1 == c2);
  return c1 - c2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  cmp    %rsi,%rdi
  je     L33
L34:
  add    $0x1,%r12
  movzbl -0x1(%r12),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edi
  call   <tolower@plt>
  cmp    %al,%bl
  jne    L37
  test   %bl,%bl
  jne    L34
L37:
  movzbl %bl,%ebx
  movzbl %al,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    $0x0,%eax
  jmp    L5
```

assistant: ```c
int strcasecmp(s1, s2) const char *s1;
const char *s2;
{
  register const unsigned char *p1 = (const unsigned char *)s1;
  register const unsigned char *p2 = (const unsigned char *)s2;
  unsigned char c1, c2;
  if (p1 == p2)
    return 0;
  do {
    c1 = tolower(*p1++);
    c2 = tolower(*p2++);
    if (c1 == '\0')
      break;
  } while (c1 == c2);
  return c1 - c2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strcasecmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L8
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L13
  nopl   (%rax)
L21:
  test   %bl,%bl
  je     L35
L13:
  movzbl (%r12),%edi
  add    $0x1,%rbp
  add    $0x1,%r12
  call   <tolower@plt>
  movzbl -0x1(%rbp),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %al,%bl
  je     L21
L35:
  movzbl %bl,%ebx
  movzbl %al,%edx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcasecmp(s1, s2) const char *s1;
const char *s2;
{
  register const unsigned char *p1 = (const unsigned char *)s1;
  register const unsigned char *p2 = (const unsigned char *)s2;
  unsigned char c1, c2;
  if (p1 == p2)
    return 0;
  do {
    c1 = tolower(*p1++);
    c2 = tolower(*p2++);
    if (c1 == '\0')
      break;
  } while (c1 == c2);
  return c1 - c2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcasecmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L19
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L22
  nopl   (%rax)
L21:
  test   %bl,%bl
  je     L29
L22:
  movzbl (%r12),%edi
  add    $0x1,%rbp
  add    $0x1,%r12
  call   <tolower@plt>
  movzbl -0x1(%rbp),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %al,%bl
  je     L21
L29:
  movzbl %bl,%ebx
  movzbl %al,%edx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcasecmp(s1, s2) const char *s1;
const char *s2;
{
  register const unsigned char *p1 = (const unsigned char *)s1;
  register const unsigned char *p2 = (const unsigned char *)s2;
  unsigned char c1, c2;
  if (p1 == p2)
    return 0;
  do {
    c1 = tolower(*p1++);
    c2 = tolower(*p2++);
    if (c1 == '\0')
      break;
  } while (c1 == c2);
  return c1 - c2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<echo_read_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferevent_get_input@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferevent_get_output@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <evbuffer_get_length@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_copyout@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add_buffer@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string

tool: D8: data: %s


assistant: ```c
void echo_read_cb(struct bufferevent *bev, void *ctx) {
  struct evbuffer *input = bufferevent_get_input(bev);
  struct evbuffer *output = bufferevent_get_output(bev);
  size_t length = evbuffer_get_length(input);
  char *data = malloc(length);
  evbuffer_copyout(input, data, length);
  printf("data: %s\n", data);
  evbuffer_add_buffer(output, input);
  free(data);
}
```