ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  movl   $0x1,-0x3c(%rbp)
  jmp    L39
L26:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L39:
  mov    -0x3c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L26
  lea    D9(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D50(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D67(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D64(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L20
L41:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L20:
  mov    -0x3c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L41
  movl   $0x0,-0x38(%rbp)
  jmp    L19
L61:
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L19:
  cmpl   $0x9,-0x38(%rbp)
  jle    L61
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string
name: unpack_data
arguments: data_label: D50
type_infered: string
name: unpack_data
arguments: data_label: D67
type_infered: string
name: unpack_data
arguments: data_label: D64
type_infered: string
name: unpack_data
arguments: data_label: D37
type_infered: string
name: unpack_data
arguments: data_label: D49
type_infered: string

tool: D15: arg %d: %s


tool: D9: California

tool: D50: Oregon

tool: D67: Washington

tool: D64: Texas

tool: D37: state %d: %s


tool: D49: index %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("state %d: %s\n", i, states[i]);
  }
  for (int j = 0; j < 10; j++) {
    printf("index %d\n", j);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L19
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x1,%ebx
  lea    D1(%rip),%r13
L45:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L45
L19:
  lea    D49(%rip),%rax
  mov    %rax,(%rsp)
  lea    D29(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D65(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D11(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%ebx
  lea    D53(%rip),%rbp
L31:
  mov    (%rsp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L31
  mov    $0x0,%ebx
  lea    D61(%rip),%rbp
L43:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L43
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D49
datatype: string
name: retrieve_data
arguments: label: D29
datatype: string
name: retrieve_data
arguments: label: D65
datatype: string
name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D53
datatype: string
name: retrieve_data
arguments: label: D61
datatype: string

tool: D1: arg %d: %s


tool: D49: California

tool: D29: Oregon

tool: D65: Washington

tool: D11: Texas

tool: D53: state %d: %s


tool: D61: index %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("state %d: %s\n", i, states[i]);
  }
  for (int j = 0; j < 10; j++) {
    printf("index %d\n", j);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L11
  mov    %rsi,%rbp
  movslq %edi,%r13
  mov    $0x1,%ebx
  lea    D57(%rip),%r12
  nopl   (%rax)
L6:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L6
L11:
  lea    D46(%rip),%rax
  xor    %ebx,%ebx
  lea    D58(%rip),%rdx
  mov    %rax,0x8(%rsp)
  lea    D51(%rip),%rax
  lea    D16(%rip),%rbp
  mov    %rax,0x10(%rsp)
  lea    D20(%rip),%rax
  mov    %rax,0x18(%rsp)
L54:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L43
  mov    (%rsp,%rbx,8),%rdx
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L43:
  xor    %ebx,%ebx
  lea    D50(%rip),%rbp
  nopl   0x0(%rax)
L17:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L17
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D57
data_type: string
name: unpack_data
arguments: label: D46
data_type: string
name: unpack_data
arguments: label: D58
data_type: string
name: unpack_data
arguments: label: D51
data_type: string
name: unpack_data
arguments: label: D16
data_type: string
name: unpack_data
arguments: label: D20
data_type: string
name: unpack_data
arguments: label: D50
data_type: string

tool: D57: arg %d: %s


tool: D46: Oregon

tool: D58: California

tool: D51: Washington

tool: D16: state %d: %s


tool: D20: Texas

tool: D50: index %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("state %d: %s\n", i, states[i]);
  }
  for (int j = 0; j < 10; j++) {
    printf("index %d\n", j);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L24
  mov    %rsi,%r12
  movslq %edi,%rbp
  mov    $0x1,%ebx
  lea    D67(%rip),%r13
  nopl   (%rax)
L1:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L1
L24:
  lea    D31(%rip),%rax
  lea    D13(%rip),%rcx
  xor    %ebx,%ebx
  mov    %rsp,%r12
  movq   %rcx,%xmm0
  movq   %rax,%xmm1
  lea    D40(%rip),%rcx
  punpcklqdq %xmm1,%xmm0
  lea    D14(%rip),%rax
  lea    D28(%rip),%rbp
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm2
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L42:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L42
  xor    %ebx,%ebx
  lea    D49(%rip),%rbp
  nopl   0x0(%rax)
L43:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L43
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D67
type: string
name: retrieve_data
arguments: data_tag: D31
type: string
name: retrieve_data
arguments: data_tag: D13
type: string
name: retrieve_data
arguments: data_tag: D40
type: string
name: retrieve_data
arguments: data_tag: D14
type: string
name: retrieve_data
arguments: data_tag: D28
type: string
name: retrieve_data
arguments: data_tag: D49
type: string

tool: D67: arg %d: %s


tool: D31: Oregon

tool: D13: California

tool: D40: Washington

tool: D14: Texas

tool: D28: state %d: %s


tool: D49: index %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("state %d: %s\n", i, states[i]);
  }
  for (int j = 0; j < 10; j++) {
    printf("index %d\n", j);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calculaDigitos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x8,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jne    L10
  movl   $0x9,-0xc(%rbp)
L10:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L26:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L26
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int calculaDigitos(int digitoVerificador, int cpf[], int multiplicador[]) {
  int k = 8, i = 0, calc = 0;
  if (digitoVerificador == 2) {
    k = 9;
  }
  calc = 0;
  for (i = 0; i <= k; i++) {
    calc += multiplicador[i] * cpf[i];
  }
  return calc;
}
```
user: What is the c source code of the assembly code below?

```asm
<calculaDigitos>:
  endbr64
  cmp    $0x2,%edi
  sete   %al
  movzbl %al,%eax
  lea    0x24(,%rax,4),%r8
  mov    $0x0,%eax
  mov    $0x0,%edi
L8:
  mov    (%rdx,%rax,1),%ecx
  imul   (%rsi,%rax,1),%ecx
  add    %ecx,%edi
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L8
  mov    %edi,%eax
  ret
```

assistant: ```c
int calculaDigitos(int digitoVerificador, int cpf[], int multiplicador[]) {
  int k = 8, i = 0, calc = 0;
  if (digitoVerificador == 2) {
    k = 9;
  }
  calc = 0;
  for (i = 0; i <= k; i++) {
    calc += multiplicador[i] * cpf[i];
  }
  return calc;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calculaDigitos>:
  endbr64
  xor    %eax,%eax
  cmp    $0x2,%edi
  sete   %al
  xor    %r8d,%r8d
  lea    0x24(,%rax,4),%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  mov    (%rdx,%rax,1),%ecx
  imul   (%rsi,%rax,1),%ecx
  add    $0x4,%rax
  add    %ecx,%r8d
  cmp    %rax,%rdi
  jne    L1
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calculaDigitos(int digitoVerificador, int cpf[], int multiplicador[]) {
  int k = 8, i = 0, calc = 0;
  if (digitoVerificador == 2) {
    k = 9;
  }
  calc = 0;
  for (i = 0; i <= k; i++) {
    calc += multiplicador[i] * cpf[i];
  }
  return calc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calculaDigitos>:
  endbr64
  movdqu 0x10(%rdx),%xmm1
  movdqu 0x10(%rsi),%xmm2
  cmp    $0x2,%edi
  movdqu 0x10(%rdx),%xmm0
  movdqu 0x10(%rsi),%xmm4
  sete   %dil
  psrlq  $0x20,%xmm2
  movdqu (%rsi),%xmm3
  mov    0x20(%rdx),%eax
  movzbl %dil,%edi
  psrlq  $0x20,%xmm1
  pmuludq %xmm4,%xmm0
  movdqu (%rsi),%xmm5
  pmuludq %xmm2,%xmm1
  movdqu (%rdx),%xmm2
  psrlq  $0x20,%xmm3
  imul   0x20(%rsi),%eax
  pmuludq %xmm5,%xmm2
  pshufd $0x8,%xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  movdqu (%rdx),%xmm1
  pshufd $0x8,%xmm2,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm3,%xmm1
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm2
  paddd  %xmm2,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%ecx
  add    %ecx,%eax
  cmp    $0x1,%edi
  jne    L7
  mov    0x24(%rdx),%edx
  imul   0x24(%rsi),%edx
  add    %edx,%eax
L7:
  ret
```

assistant: ```c
int calculaDigitos(int digitoVerificador, int cpf[], int multiplicador[]) {
  int k = 8, i = 0, calc = 0;
  if (digitoVerificador == 2) {
    k = 9;
  }
  calc = 0;
  for (i = 0; i <= k; i++) {
    calc += multiplicador[i] * cpf[i];
  }
  return calc;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BGBDTC_SigNext>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  jbe    L140
  sub    $0x41,%eax
  cmp    $0x17,%al
  ja     L78
  sub    $0x8,%rsp
  movzbl %al,%eax
  lea    D9(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L140:
  lea    0x1(%rdi),%rax
  ret
  add    $0x1,%rdi
  call   <BGBDTC_SigNext>
  jmp    L154
L143:
  add    $0x1,%rdi
  cmpb   $0x50,(%rdi)
  je     L143
  call   <BGBDTC_SigNext>
  jmp    L154
L169:
  add    $0x1,%rdi
  cmpb   $0x51,(%rdi)
  je     L169
  call   <BGBDTC_SigNext>
  jmp    L154
  lea    0x1(%rdi),%rax
  movzbl 0x1(%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L158
  test   %dl,%dl
  je     L100
  cmp    $0x3b,%dl
  je     L100
L99:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L100
  cmp    $0x3b,%dl
  jne    L99
L100:
  cmp    $0x3b,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  jmp    L154
L158:
  add    $0x1,%rax
  movzbl (%rax),%esi
  lea    -0x30(%rsi),%edx
  cmp    $0x9,%dl
  jbe    L158
  jmp    L154
  movzbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L97
  add    $0x1,%rdi
L29:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L29
  call   <BGBDTC_SigNext>
  jmp    L154
L97:
  add    $0x2,%rdi
  call   <BGBDTC_SigNext>
  jmp    L154
  mov    %rdi,%rax
L154:
  add    $0x8,%rsp
  ret
L78:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *BGBDTC_SigNext(char *sig) {
  char *s;
  s = sig;
  if ((*s >= 'a') && (*s <= 'z'))
    return (s + 1);
  if ((*s == 'C') || (*s == 'D') || (*s == 'R')) {
    return (BGBDTC_SigNext(s + 1));
  }
  if (*s == 'P') {
    while (*s == 'P')
      s++;
    return (BGBDTC_SigNext(s));
  }
  if (*s == 'Q') {
    while (*s == 'Q')
      s++;
    return (BGBDTC_SigNext(s));
  }
  if ((*s == 'X') || (*s == 'L') || (*s == 'U')) {
    s++;
    if ((*s >= '0') && (*s <= '9')) {
      while ((*s >= '0') && (*s <= '9'))
        s++;
    } else {
      while (*s && (*s != ';'))
        s++;
      if (*s == ';')
        s++;
    }
    return (s);
  }
  if (*s == 'A') {
    s++;
    if ((*s >= '0') && (*s <= '9')) {
      while ((*s >= '0') && (*s <= '9'))
        s++;
      return (BGBDTC_SigNext(s));
    } else {
      return (BGBDTC_SigNext(s + 1));
    }
  }
  return (s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<BGBDTC_SigNext>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  jbe    L152
  lea    D4(%rip),%rcx
L29:
  sub    $0x41,%edx
  cmp    $0x17,%dl
  ja     L31
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  xchg   %ax,%ax
L2:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x50,%dl
  je     L2
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L29
L152:
  add    $0x1,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L114:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x51,%dl
  je     L114
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L29
  jmp    L152
  nopw   0x0(%rax,%rax,1)
L31:
  ret
  nopl   0x0(%rax)
  lea    0x1(%rax),%rdx
  movzbl 0x1(%rax),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L180
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L9
  mov    %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
L180:
  test   %al,%al
  je     L30
  cmp    $0x3b,%al
  jne    L24
L30:
  cmp    $0x3b,%al
  sete   %al
  movzbl %al,%eax
  add    %rdx,%rax
  ret
  nopl   0x0(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L29
  jmp    L152
  nopw   0x0(%rax,%rax,1)
  movzbl 0x1(%rax),%edi
  lea    -0x30(%rdi),%edx
  cmp    $0x9,%dl
  jbe    L124
  movzbl 0x2(%rax),%edx
  add    $0x2,%rax
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L29
  jmp    L152
  xchg   %ax,%ax
L124:
  add    $0x1,%rax
  nopl   0x0(%rax)
L7:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L7
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L29
  jmp    L152
```

assistant: ```c
char *BGBDTC_SigNext(char *sig) {
  char *s;
  s = sig;
  if ((*s >= 'a') && (*s <= 'z'))
    return (s + 1);
  if ((*s == 'C') || (*s == 'D') || (*s == 'R')) {
    return (BGBDTC_SigNext(s + 1));
  }
  if (*s == 'P') {
    while (*s == 'P')
      s++;
    return (BGBDTC_SigNext(s));
  }
  if (*s == 'Q') {
    while (*s == 'Q')
      s++;
    return (BGBDTC_SigNext(s));
  }
  if ((*s == 'X') || (*s == 'L') || (*s == 'U')) {
    s++;
    if ((*s >= '0') && (*s <= '9')) {
      while ((*s >= '0') && (*s <= '9'))
        s++;
    } else {
      while (*s && (*s != ';'))
        s++;
      if (*s == ';')
        s++;
    }
    return (s);
  }
  if (*s == 'A') {
    s++;
    if ((*s >= '0') && (*s <= '9')) {
      while ((*s >= '0') && (*s <= '9'))
        s++;
      return (BGBDTC_SigNext(s));
    } else {
      return (BGBDTC_SigNext(s + 1));
    }
  }
  return (s);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BGBDTC_SigNext>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  jbe    L105
  lea    D9(%rip),%rcx
L170:
  sub    $0x41,%edx
  cmp    $0x17,%dl
  ja     L30
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  xchg   %ax,%ax
L83:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x50,%dl
  je     L83
L187:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L170
L105:
  add    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L149:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x51,%dl
  jne    L187
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x51,%dl
  je     L149
  jmp    L187
  nopl   0x0(%rax)
L30:
  ret
  nopl   0x0(%rax)
  lea    0x1(%rax),%rdx
  movzbl 0x1(%rax),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L92
  nopl   0x0(%rax,%rax,1)
L44:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L44
  mov    %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L77:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
L92:
  test   %al,%al
  je     L165
  cmp    $0x3b,%al
  jne    L77
L165:
  cmp    $0x3b,%al
  sete   %al
  movzbl %al,%eax
  add    %rdx,%rax
  ret
  nopl   0x0(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L170
  jmp    L105
  nopw   0x0(%rax,%rax,1)
  movzbl 0x1(%rax),%edi
  lea    -0x30(%rdi),%edx
  cmp    $0x9,%dl
  jbe    L96
  movzbl 0x2(%rax),%edx
  add    $0x2,%rax
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L170
  jmp    L105
  xchg   %ax,%ax
L96:
  add    $0x1,%rax
  nopl   0x0(%rax)
L101:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L101
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L170
  jmp    L105
```

assistant: ```c
char *BGBDTC_SigNext(char *sig) {
  char *s;
  s = sig;
  if ((*s >= 'a') && (*s <= 'z'))
    return (s + 1);
  if ((*s == 'C') || (*s == 'D') || (*s == 'R')) {
    return (BGBDTC_SigNext(s + 1));
  }
  if (*s == 'P') {
    while (*s == 'P')
      s++;
    return (BGBDTC_SigNext(s));
  }
  if (*s == 'Q') {
    while (*s == 'Q')
      s++;
    return (BGBDTC_SigNext(s));
  }
  if ((*s == 'X') || (*s == 'L') || (*s == 'U')) {
    s++;
    if ((*s >= '0') && (*s <= '9')) {
      while ((*s >= '0') && (*s <= '9'))
        s++;
    } else {
      while (*s && (*s != ';'))
        s++;
      if (*s == ';')
        s++;
    }
    return (s);
  }
  if (*s == 'A') {
    s++;
    if ((*s >= '0') && (*s <= '9')) {
      while ((*s >= '0') && (*s <= '9'))
        s++;
      return (BGBDTC_SigNext(s));
    } else {
      return (BGBDTC_SigNext(s + 1));
    }
  }
  return (s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: Hello, GitHub!

assistant: ```c
int main() {
  printf("Hello, GitHub!");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string

tool: D0: Hello, GitHub!

assistant: ```c
int main() {
  printf("Hello, GitHub!");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Hello, GitHub!

assistant: ```c
int main() {
  printf("Hello, GitHub!");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: Hello, GitHub!

assistant: ```c
int main() {
  printf("Hello, GitHub!");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D4: %d

assistant: ```c
int main() {
  printf("%d", factorial(9, 1));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main() {
  printf("%d", factorial(9, 1));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <factorial@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: %d

assistant: ```c
int main() {
  printf("%d", factorial(9, 1));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <factorial@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main() {
  printf("%d", factorial(9, 1));
  return 0;
}
```