ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <strlen@plt>
  cmp    $0x2,%eax
  jle    L139
  mov    %eax,%ebx
  cmp    $0x1,%r12d
  je     L139
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  lea    -0x1(%r12),%r10d
  lea    (%r10,%r10,1),%r9d
  mov    %ebx,%eax
  cltd
  idiv   %r9d
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%edx
  jmp    L3
L153:
  add    $0x1,%edx
  mov    $0x0,%edi
  jmp    L56
L152:
  mov    %r9d,%r13d
  imul   %edi,%r13d
  lea    0x0(%r13,%rdx,1),%ecx
  cmp    %ecx,%ebx
  jle    L10
  lea    0x1(%rsi),%r11d
  movslq %ecx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%r14d
  movslq %esi,%rcx
  mov    %r14b,(%r8,%rcx,1)
  lea    -0x2(%r13,%r12,2),%ecx
  sub    %edx,%ecx
  cmp    %ecx,%ebx
  jle    L120
  add    $0x2,%esi
  movslq %ecx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%ecx
  movslq %r11d,%r11
  mov    %cl,(%r8,%r11,1)
  jmp    L0
L10:
  add    $0x1,%edx
  mov    $0x0,%edi
  jmp    L56
L120:
  add    $0x1,%edx
  mov    %r11d,%esi
  mov    $0x0,%edi
  jmp    L56
L58:
  add    $0x1,%edx
  mov    $0x0,%edi
L56:
  cmp    %ebx,%esi
  jge    L155
L3:
  cmp    %edx,%r10d
  je     L69
  test   %edx,%edx
  jne    L152
L69:
  mov    %r9d,%ecx
  imul   %edi,%ecx
  add    %edx,%ecx
  cmp    %ecx,%ebx
  jle    L153
  movslq %ecx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%r11d
  movslq %esi,%rcx
  mov    %r11b,(%r8,%rcx,1)
  lea    0x1(%rsi),%esi
L0:
  cmp    %edi,%eax
  jle    L58
  add    $0x1,%edi
  jmp    L56
L155:
  mov    $0x0,%edx
L137:
  movzbl (%r8,%rdx,1),%eax
  mov    %al,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L137
  mov    %r8,%rdi
  call   <free@plt>
L139:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *convert(char *s, int numRows) {
  int lenth = strlen(s);
  if (lenth <= 2 || numRows == 1)
    return s;
  char *p = (char *)malloc(lenth);
  int n = 0, m = 0;
  int cycle = numRows + numRows - 2;
  int numCols = lenth / cycle + 1;
  for (int i = 0; i < lenth;) {
    if (n == 0 || n == numRows - 1) {
      int index = m * cycle + n;
      if (index >= lenth) {
        n++;
        m = 0;
        continue;
      }
      p[i++] = s[index];
    } else {
      int index = m * cycle + n;
      if (index >= lenth) {
        n++;
        m = 0;
        continue;
      }
      p[i++] = s[index];
      index = m * cycle + numRows - 1 + numRows - 1 - n;
      if (index >= lenth) {
        n++;
        m = 0;
        continue;
      }
      p[i++] = s[index];
    }
    if (++m >= numCols) {
      m = 0;
      n++;
    }
  }
  for (int i = 0; i < lenth; i++) {
    s[i] = p[i];
  }
  free(p);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<convert>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    $0x2,%eax
  jle    L7
  cmp    $0x1,%ebx
  je     L7
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <malloc@plt>
  lea    -0x1(%rbx),%r11d
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %rax,%r8
  mov    %r12d,%eax
  lea    (%r11,%r11,1),%r10d
  cltd
  idiv   %r10d
  xor    %edx,%edx
  jmp    L54
  nopl   0x0(%rax)
L22:
  test   %edx,%edx
  je     L64
  cmp    %ecx,%r12d
  jle    L17
  movslq %ecx,%rcx
  lea    0x1(%rsi),%ebp
  movzbl 0x0(%r13,%rcx,1),%r14d
  movslq %esi,%rcx
  mov    %r14b,(%r8,%rcx,1)
  lea    -0x2(%r9,%rbx,2),%ecx
  sub    %edx,%ecx
  cmp    %ecx,%r12d
  jle    L78
  movslq %ecx,%rcx
  movslq %ebp,%rbp
  add    $0x2,%esi
  movzbl 0x0(%r13,%rcx,1),%ecx
  mov    %cl,(%r8,%rbp,1)
  cmp    %edi,%eax
  jle    L17
L36:
  add    $0x1,%edi
L15:
  cmp    %r12d,%esi
  jge    L136
L54:
  mov    %r10d,%r9d
  imul   %edi,%r9d
  lea    (%r9,%rdx,1),%ecx
  cmp    %edx,%r11d
  jne    L22
L64:
  cmp    %ecx,%r12d
  jle    L17
  movslq %ecx,%rcx
  movzbl 0x0(%r13,%rcx,1),%r9d
  movslq %esi,%rcx
  add    $0x1,%esi
  mov    %r9b,(%r8,%rcx,1)
  cmp    %edi,%eax
  jg     L36
L17:
  add    $0x1,%edx
  xor    %edi,%edi
  cmp    %r12d,%esi
  jl     L54
L136:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L94:
  movzbl (%r8,%rdx,1),%eax
  mov    %al,0x0(%r13,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%r12d
  jg     L94
  mov    %r8,%rdi
  call   <free@plt>
L7:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L78:
  add    $0x1,%edx
  mov    %ebp,%esi
  xor    %edi,%edi
  jmp    L15
```

assistant: ```c
char *convert(char *s, int numRows) {
  int lenth = strlen(s);
  if (lenth <= 2 || numRows == 1)
    return s;
  char *p = (char *)malloc(lenth);
  int n = 0, m = 0;
  int cycle = numRows + numRows - 2;
  int numCols = lenth / cycle + 1;
  for (int i = 0; i < lenth;) {
    if (n == 0 || n == numRows - 1) {
      int index = m * cycle + n;
      if (index >= lenth) {
        n++;
        m = 0;
        continue;
      }
      p[i++] = s[index];
    } else {
      int index = m * cycle + n;
      if (index >= lenth) {
        n++;
        m = 0;
        continue;
      }
      p[i++] = s[index];
      index = m * cycle + numRows - 1 + numRows - 1 - n;
      if (index >= lenth) {
        n++;
        m = 0;
        continue;
      }
      p[i++] = s[index];
    }
    if (++m >= numCols) {
      m = 0;
      n++;
    }
  }
  for (int i = 0; i < lenth; i++) {
    s[i] = p[i];
  }
  free(p);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <no_of_digits@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L8
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void shift(char *a, int n) {
  int i;
  for (i = no_of_digits(a); i >= 0; i--)
    a[i + n] = a[i];
  for (i = 0; i < n; i++)
    a[i] = '0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <no_of_digits@plt>
  test   %eax,%eax
  js     L13
  movslq %eax,%rcx
  lea    (%rbx,%rcx,1),%rdx
  lea    -0x1(%rbx,%rcx,1),%rcx
  mov    %eax,%eax
  sub    %rax,%rcx
  movslq %ebp,%rsi
L12:
  movzbl (%rdx),%eax
  mov    %al,(%rdx,%rsi,1)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L12
L13:
  test   %ebp,%ebp
  jle    L8
  mov    %rbx,%rax
  lea    -0x1(%rbp),%edx
  lea    0x1(%rbx,%rdx,1),%rdx
L36:
  movb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L36
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void shift(char *a, int n) {
  int i;
  for (i = no_of_digits(a); i >= 0; i--)
    a[i + n] = a[i];
  for (i = 0; i < n; i++)
    a[i] = '0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shift>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <no_of_digits@plt>
  test   %eax,%eax
  js     L22
  cltq
  movslq %ebx,%r9
  lea    -0x1(%rbp,%rax,1),%r8
  lea    0x0(%rbp,%rax,1),%rcx
  sub    %rax,%r8
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl (%rcx),%eax
  sub    $0x1,%rcx
  mov    %al,0x1(%rcx,%r9,1)
  cmp    %r8,%rcx
  jne    L19
L22:
  test   %ebx,%ebx
  jle    L12
  add    $0x8,%rsp
  movslq %ebx,%rdx
  mov    %rbp,%rdi
  mov    $0x30,%esi
  pop    %rbx
  pop    %rbp
  jmp    1060 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void shift(char *a, int n) {
  int i;
  for (i = no_of_digits(a); i >= 0; i--)
    a[i + n] = a[i];
  for (i = 0; i < n; i++)
    a[i] = '0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shift>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <no_of_digits@plt>
  test   %eax,%eax
  js     L17
  cltq
  movslq %ebx,%r9
  lea    -0x1(%rbp,%rax,1),%r8
  lea    0x0(%rbp,%rax,1),%rcx
  sub    %rax,%r8
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl (%rcx),%eax
  sub    $0x1,%rcx
  mov    %al,0x1(%rcx,%r9,1)
  cmp    %rcx,%r8
  jne    L26
L17:
  test   %ebx,%ebx
  jle    L4
  add    $0x8,%rsp
  movslq %ebx,%rdx
  mov    %rbp,%rdi
  mov    $0x30,%esi
  pop    %rbx
  pop    %rbp
  jmp    1060 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void shift(char *a, int n) {
  int i;
  for (i = no_of_digits(a); i >= 0; i--)
    a[i + n] = a[i];
  for (i = 0; i < n; i++)
    a[i] = '0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x3f8(%rbp)
  jmp    L27
L24:
  mov    -0x3f4(%rbp),%edx
  mov    -0x3f8(%rbp),%ecx
  lea    -0x3f0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fold@plt>
L27:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <_getline@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jg     L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int main() {
  int lineLength, foldLimit;
  foldLimit = 4;
  char string[1000];
  while ((lineLength = _getline(string, 1000)) > 0) {
    fold(string, foldLimit, lineLength);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L1
L21:
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <fold@plt>
L1:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <_getline@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L21
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int lineLength, foldLimit;
  foldLimit = 4;
  char string[1000];
  while ((lineLength = _getline(string, 1000)) > 0) {
    fold(string, foldLimit, lineLength);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L29
  nopl   0x0(%rax)
L27:
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <fold@plt>
L29:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <_getline@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L27
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int lineLength, foldLimit;
  foldLimit = 4;
  char string[1000];
  while ((lineLength = _getline(string, 1000)) > 0) {
    fold(string, foldLimit, lineLength);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L19
  nopl   0x0(%rax)
L0:
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <fold@plt>
L19:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <_getline@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L0
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int lineLength, foldLimit;
  foldLimit = 4;
  char string[1000];
  while ((lineLength = _getline(string, 1000)) > 0) {
    fold(string, foldLimit, lineLength);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RB_XMLDB_Generate_Header_End>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: </section>


assistant: ```c
void RB_XMLDB_Generate_Header_End(FILE *dest_doc, struct RB_header *cur_header) {
  (cur_header = cur_header);
  ;
  fprintf(dest_doc, "</section>\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RB_XMLDB_Generate_Header_End>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: </section>


assistant: ```c
void RB_XMLDB_Generate_Header_End(FILE *dest_doc, struct RB_header *cur_header) {
  (cur_header = cur_header);
  ;
  fprintf(dest_doc, "</section>\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RB_XMLDB_Generate_Header_End>:
  endbr64
  lea    D2(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: </section>


assistant: ```c
void RB_XMLDB_Generate_Header_End(FILE *dest_doc, struct RB_header *cur_header) {
  (cur_header = cur_header);
  ;
  fprintf(dest_doc, "</section>\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RB_XMLDB_Generate_Header_End>:
  endbr64
  lea    D6(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: </section>


assistant: ```c
void RB_XMLDB_Generate_Header_End(FILE *dest_doc, struct RB_header *cur_header) {
  (cur_header = cur_header);
  ;
  fprintf(dest_doc, "</section>\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<solve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L8
L12:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <even@plt>
  test   %rax,%rax
  je     L17
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L12
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solve(int p) {
  int sum = 0;
  int snd = 0;
  int fst = 1;
  int cur = 1;
  while (cur <= p) {
    if (even(cur)) {
      sum += cur;
    }
    snd = fst;
    fst = cur;
    cur = snd + fst;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<solve>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L34
  mov    %edi,%r13d
  mov    $0x1,%ebx
  mov    $0x1,%r12d
  mov    $0x0,%ebp
  jmp    L32
L12:
  mov    %eax,%ebx
L32:
  mov    %ebx,%edi
  call   <even@plt>
  mov    %rax,%rdx
  lea    0x0(%rbp,%rbx,1),%eax
  test   %rdx,%rdx
  cmovne %eax,%ebp
  lea    (%r12,%rbx,1),%eax
  mov    %ebx,%r12d
  cmp    %eax,%r13d
  jge    L12
L30:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    $0x0,%ebp
  jmp    L30
```

assistant: ```c
int solve(int p) {
  int sum = 0;
  int snd = 0;
  int fst = 1;
  int cur = 1;
  while (cur <= p) {
    if (even(cur)) {
      sum += cur;
    }
    snd = fst;
    fst = cur;
    cur = snd + fst;
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<solve>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L14
  mov    %edi,%r13d
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  xor    %r12d,%r12d
  jmp    L15
  nopl   0x0(%rax)
L21:
  mov    %eax,%ebx
L15:
  mov    %ebx,%edi
  call   <even@plt>
  mov    %rax,%r8
  lea    (%r12,%rbx,1),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  lea    0x0(%rbp,%rbx,1),%eax
  mov    %ebx,%ebp
  cmp    %eax,%r13d
  jge    L21
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int solve(int p) {
  int sum = 0;
  int snd = 0;
  int fst = 1;
  int cur = 1;
  while (cur <= p) {
    if (even(cur)) {
      sum += cur;
    }
    snd = fst;
    fst = cur;
    cur = snd + fst;
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solve>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L15
  mov    %edi,%r13d
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  xor    %r12d,%r12d
  jmp    L26
  nopl   0x0(%rax)
L24:
  mov    %eax,%ebx
L26:
  mov    %ebx,%edi
  call   <even@plt>
  mov    %rax,%r8
  lea    (%r12,%rbx,1),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  lea    0x0(%rbp,%rbx,1),%eax
  mov    %ebx,%ebp
  cmp    %eax,%r13d
  jge    L24
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int solve(int p) {
  int sum = 0;
  int snd = 0;
  int fst = 1;
  int cur = 1;
  while (cur <= p) {
    if (even(cur)) {
      sum += cur;
    }
    snd = fst;
    fst = cur;
    cur = snd + fst;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<data_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0x3000000,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *data_init(void) {
  unsigned char *IVs = (unsigned char *)calloc(256 * 256 * 256 * 3, sizeof(unsigned char));
  return IVs;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<data_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x3000000,%edi
  call   <calloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char *data_init(void) {
  unsigned char *IVs = (unsigned char *)calloc(256 * 256 * 256 * 3, sizeof(unsigned char));
  return IVs;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<data_init>:
  endbr64
  mov    $0x1,%esi
  mov    $0x3000000,%edi
  jmp    1050 <calloc@plt>
```

assistant: ```c
unsigned char *data_init(void) {
  unsigned char *IVs = (unsigned char *)calloc(256 * 256 * 256 * 3, sizeof(unsigned char));
  return IVs;
}
```
user: What is the c source code of the assembly code below:

```asm
<data_init>:
  endbr64
  mov    $0x1,%esi
  mov    $0x3000000,%edi
  jmp    1050 <calloc@plt>
```

assistant: ```c
unsigned char *data_init(void) {
  unsigned char *IVs = (unsigned char *)calloc(256 * 256 * 256 * 3, sizeof(unsigned char));
  return IVs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: Helloc world

assistant: ```c
int main() {
  printf("Hello\c world");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: Helloc world

assistant: ```c
int main() {
  printf("Hello\c world");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: Helloc world

assistant: ```c
int main() {
  printf("Hello\c world");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: Helloc world

assistant: ```c
int main() {
  printf("Hello\c world");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<outstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: %4d    %2.2xH    %c


assistant: ```c
void outstr(unsigned char *s, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%4d    %2.2xH    %c\n", i, s[i], s[i]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<outstr>:
  endbr64
  test   %esi,%esi
  jle    L6
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D8(%rip),%r13
L17:
  movzbl (%r12,%rbx,1),%edx
  mov    %edx,%ecx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string

tool: D8: %4d    %2.2xH    %c


assistant: ```c
void outstr(unsigned char *s, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%4d    %2.2xH    %c\n", i, s[i], s[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<outstr>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  movzbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  mov    %edx,%ecx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: %4d    %2.2xH    %c


assistant: ```c
void outstr(unsigned char *s, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%4d    %2.2xH    %c\n", i, s[i], s[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<outstr>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L15:
  movzbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  mov    %edx,%ecx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L11:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D8: %4d    %2.2xH    %c


assistant: ```c
void outstr(unsigned char *s, int len) {
  int i;
  for (i = 0; i < len; i++)
    printf("%4d    %2.2xH    %c\n", i, s[i], s[i]);
}
```