ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jle    L24
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L22
L18:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jg     L29
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L29:
  addl   $0x1,-0x10(%rbp)
L22:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L18
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L24:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L36:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D61
type: string
name: read_data
arguments: tag: D41
type: string
name: read_data
arguments: tag: D17
type: string

tool: D18: Girdiginiz sayi hem karsilastirilir
hemde kendinden sonra kac sayi girilcegini belirler.

tool: D4: Sayi giriniz:

tool: D61: %d

tool: D41: %d minumum sayidir.

tool: D17: Ilk sayi olarak sifir veya Negatif bir sayi girdiniz.

assistant: ```c
int main() {
  int minumum, sayici, sayi_limiti, sayi;
  printf("Girdiginiz sayi hem karsilastirilir\nhemde kendinden sonra kac sayi girilcegini belirler.\n");
  printf("Sayi giriniz:");
  scanf("%d", &minumum);
  if (minumum >= 1) {
    sayi_limiti = minumum;
    for (sayici = 1; sayici <= sayi_limiti; sayici++) {
      printf("Sayi giriniz:");
      scanf("%d", &sayi);
      if (sayi <= minumum) {
        minumum = sayi;
      }
    }
    printf("%d minumum sayidir.", minumum);
  } else {
    printf("Ilk sayi olarak sifir veya Negatif bir sayi girdiniz.");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  test   %ebp,%ebp
  jle    L23
  mov    $0x1,%ebx
  lea    D5(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D37(%rip),%r12
  jmp    L63
L33:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L41
L63:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    (%rsp),%eax
  jg     L33
  mov    %eax,(%rsp)
  jmp    L33
L41:
  mov    (%rsp),%esi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L42
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D44
type_infered: string
name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D37
type_infered: string
name: read_data
arguments: label: D33
type_infered: string
name: read_data
arguments: label: D67
type_infered: string

tool: D44: Girdiginiz sayi hem karsilastirilir
hemde kendinden sonra kac sayi girilcegini belirler.

tool: D5: Sayi giriniz:

tool: D37: %d

tool: D33: %d minumum sayidir.

tool: D67: Ilk sayi olarak sifir veya Negatif bir sayi girdiniz.

assistant: ```c
int main() {
  int minumum, sayici, sayi_limiti, sayi;
  printf("Girdiginiz sayi hem karsilastirilir\nhemde kendinden sonra kac sayi girilcegini belirler.\n");
  printf("Sayi giriniz:");
  scanf("%d", &minumum);
  if (minumum >= 1) {
    sayi_limiti = minumum;
    for (sayici = 1; sayici <= sayi_limiti; sayici++) {
      printf("Sayi giriniz:");
      scanf("%d", &sayi);
      if (sayi <= minumum) {
        minumum = sayi;
      }
    }
    printf("%d minumum sayidir.", minumum);
  } else {
    printf("Ilk sayi olarak sifir veya Negatif bir sayi girdiniz.");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D25(%rip),%rdi
  push   %r13
  lea    D32(%rip),%r13
  push   %r12
  lea    D38(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  test   %ebp,%ebp
  jle    L12
  mov    $0x1,%ebx
  lea    0x4(%rsp),%r14
L0:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    (%rsp),%eax
  jg     L11
  mov    %eax,(%rsp)
L11:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L0
  mov    (%rsp),%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L31
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
type: string
name: disassemble_data
arguments: data_tag: D32
type: string
name: disassemble_data
arguments: data_tag: D38
type: string
name: disassemble_data
arguments: data_tag: D40
type: string
name: disassemble_data
arguments: data_tag: D23
type: string

tool: D25: Girdiginiz sayi hem karsilastirilir
hemde kendinden sonra kac sayi girilcegini belirler.

tool: D32: %d

tool: D38: Sayi giriniz:

tool: D40: %d minumum sayidir.

tool: D23: Ilk sayi olarak sifir veya Negatif bir sayi girdiniz.

assistant: ```c
int main() {
  int minumum, sayici, sayi_limiti, sayi;
  printf("Girdiginiz sayi hem karsilastirilir\nhemde kendinden sonra kac sayi girilcegini belirler.\n");
  printf("Sayi giriniz:");
  scanf("%d", &minumum);
  if (minumum >= 1) {
    sayi_limiti = minumum;
    for (sayici = 1; sayici <= sayi_limiti; sayici++) {
      printf("Sayi giriniz:");
      scanf("%d", &sayi);
      if (sayi <= minumum) {
        minumum = sayi;
      }
    }
    printf("%d minumum sayidir.", minumum);
  } else {
    printf("Ilk sayi olarak sifir veya Negatif bir sayi girdiniz.");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%rdi
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D46(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  test   %ebp,%ebp
  jle    L3
  mov    $0x1,%ebx
  lea    0x4(%rsp),%r14
L48:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    (%rsp),%esi
  cmp    %esi,%eax
  jg     L32
  mov    %eax,(%rsp)
  mov    %eax,%esi
L32:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L48
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L27
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D46
type_infered: string
name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string

tool: D5: Girdiginiz sayi hem karsilastirilir
hemde kendinden sonra kac sayi girilcegini belirler.

tool: D18: %d

tool: D46: Sayi giriniz:

tool: D37: %d minumum sayidir.

tool: D12: Ilk sayi olarak sifir veya Negatif bir sayi girdiniz.

assistant: ```c
int main() {
  int minumum, sayici, sayi_limiti, sayi;
  printf("Girdiginiz sayi hem karsilastirilir\nhemde kendinden sonra kac sayi girilcegini belirler.\n");
  printf("Sayi giriniz:");
  scanf("%d", &minumum);
  if (minumum >= 1) {
    sayi_limiti = minumum;
    for (sayici = 1; sayici <= sayi_limiti; sayici++) {
      printf("Sayi giriniz:");
      scanf("%d", &sayi);
      if (sayi <= minumum) {
        minumum = sayi;
      }
    }
    printf("%d minumum sayidir.", minumum);
  } else {
    printf("Ilk sayi olarak sifir veya Negatif bir sayi girdiniz.");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solcon_retrieve_next_standard_initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x114,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int solcon_retrieve_next_standard_initialize(void) {
  int a, *b, fail;
  double *c;
  a = 0;
  fail = _ada_use_c2phc4c(276, &a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<solcon_retrieve_next_standard_initialize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x114,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_retrieve_next_standard_initialize(void) {
  int a, *b, fail;
  double *c;
  a = 0;
  fail = _ada_use_c2phc4c(276, &a, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_retrieve_next_standard_initialize>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x114,%edi
  movl   $0x0,0x4(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_retrieve_next_standard_initialize(void) {
  int a, *b, fail;
  double *c;
  a = 0;
  fail = _ada_use_c2phc4c(276, &a, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solcon_retrieve_next_standard_initialize>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x114,%edi
  movl   $0x0,0x4(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_retrieve_next_standard_initialize(void) {
  int a, *b, fail;
  double *c;
  a = 0;
  fail = _ada_use_c2phc4c(276, &a, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cgc_strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  strcpy(dest + cgc_strlen(dest), src);
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <cgc_strlen@plt>
  movslq %eax,%rdi
  add    %rbx,%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  strcpy(dest + cgc_strlen(dest), src);
  return dest;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <cgc_strlen@plt>
  mov    %rbp,%rsi
  movslq %eax,%rdi
  add    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  strcpy(dest + cgc_strlen(dest), src);
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <cgc_strlen@plt>
  mov    %rbp,%rsi
  movslq %eax,%rdi
  add    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  strcpy(dest + cgc_strlen(dest), src);
  return dest;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <isCoprime@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L19
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L19:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D36
type: string
name: extract_symbolic_data
arguments: label: D19
type: string

tool: D3: Enter two numbers


tool: D21: %d%d

tool: D36: The numbers are coprime

tool: D19: The numbers are not coprime

assistant: ```c
int main() {
  int a, b;
  printf("Enter two numbers\n");
  scanf("%d%d", &a, &b);
  int ans = isCoprime(a, b);
  if (ans == 1)
    printf("The numbers are coprime");
  else
    printf("The numbers are not coprime");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <isCoprime@plt>
  cmp    $0x1,%eax
  je     L0
  lea    D39(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D23
type_infered: string
name: retrieve_data
arguments: data_label: D2
type_infered: string
name: retrieve_data
arguments: data_label: D39
type_infered: string
name: retrieve_data
arguments: data_label: D36
type_infered: string

tool: D23: Enter two numbers


tool: D2: %d%d

tool: D39: The numbers are not coprime

tool: D36: The numbers are coprime

assistant: ```c
int main() {
  int a, b;
  printf("Enter two numbers\n");
  scanf("%d%d", &a, &b);
  int ans = isCoprime(a, b);
  if (ans == 1)
    printf("The numbers are coprime");
  else
    printf("The numbers are not coprime");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <isCoprime@plt>
  cmp    $0x1,%eax
  je     L23
  lea    D1(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D26
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D27: Enter two numbers


tool: D26: %d%d

tool: D1: The numbers are not coprime

tool: D0: The numbers are coprime

assistant: ```c
int main() {
  int a, b;
  printf("Enter two numbers\n");
  scanf("%d%d", &a, &b);
  int ans = isCoprime(a, b);
  if (ans == 1)
    printf("The numbers are coprime");
  else
    printf("The numbers are not coprime");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <isCoprime@plt>
  cmp    $0x1,%eax
  je     L9
  lea    D9(%rip),%rdi
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type: string
name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D27
type: string

tool: D19: Enter two numbers


tool: D8: %d%d

tool: D9: The numbers are not coprime

tool: D27: The numbers are coprime

assistant: ```c
int main() {
  int a, b;
  printf("Enter two numbers\n");
  scanf("%d%d", &a, &b);
  int ans = isCoprime(a, b);
  if (ans == 1)
    printf("The numbers are coprime");
  else
    printf("The numbers are not coprime");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yar_server_sig_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <yar_server_shutdown@plt>
  nop
  leave
  ret
```

assistant: ```c
void yar_server_sig_handler(int signo) {
  yar_server_shutdown(signo);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<yar_server_sig_handler>:
  endbr64
  sub    $0x8,%rsp
  call   <yar_server_shutdown@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void yar_server_sig_handler(int signo) {
  yar_server_shutdown(signo);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yar_server_sig_handler>:
  endbr64
  jmp    1050 <yar_server_shutdown@plt>
```

assistant: ```c
void yar_server_sig_handler(int signo) {
  yar_server_shutdown(signo);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<yar_server_sig_handler>:
  endbr64
  jmp    1050 <yar_server_shutdown@plt>
```

assistant: ```c
void yar_server_sig_handler(int signo) {
  yar_server_shutdown(signo);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Maxtrix_Sub>:
  endbr64
  mov    %rdi,%rax
  mov    %rcx,%rdi
  movzwl %si,%r9d
  movzwl %dx,%ecx
  imul   %ecx,%r9d
  mov    %r9d,%r10d
  shr    $0x2,%r10d
  je     L15
  mov    %r10d,%r10d
  shl    $0x4,%r10
  lea    (%rax,%r10,1),%rsi
  mov    %r8,%rcx
  mov    %rdi,%rdx
L12:
  movss  0x8(%rax),%xmm1
  movss  0x4(%rax),%xmm0
  subss  0x4(%rdx),%xmm0
  movss  0x8(%rdx),%xmm3
  movss  (%rax),%xmm2
  subss  (%rdx),%xmm2
  movss  %xmm2,(%rcx)
  movss  %xmm0,0x4(%rcx)
  movss  0xc(%rax),%xmm0
  subss  0xc(%rdx),%xmm0
  subss  %xmm3,%xmm1
  movss  %xmm1,0x8(%rcx)
  movss  %xmm0,0xc(%rcx)
  add    $0x10,%rax
  add    $0x10,%rdx
  add    $0x10,%rcx
  cmp    %rsi,%rax
  jne    L12
  add    %r10,%rdi
  add    %r10,%r8
L25:
  and    $0x3,%r9d
  je     L32
  mov    %r9d,%edx
  mov    $0x0,%eax
L1:
  movss  (%rsi,%rax,4),%xmm0
  subss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L1
L32:
  mov    $0x0,%eax
  ret
L15:
  mov    %rax,%rsi
  jmp    L25
```

assistant: ```c
int Maxtrix_Sub(float *pSrcA, unsigned short numRows, unsigned short numCols, float *pSrcB, float *pDst) {
  float *pIn1 = pSrcA;
  float *pIn2 = pSrcB;
  float *pOut = pDst;
  float inA1, inA2, inB1, inB2, out1, out2;
  unsigned int numSamples;
  unsigned int blkCnt;
  int status;
  numSamples = (unsigned int)numRows * numCols;
  blkCnt = numSamples >> 2u;
  while (blkCnt > 0u) {
    inA1 = pIn1[0];
    inB1 = pIn2[0];
    inA2 = pIn1[1];
    out1 = inA1 - inB1;
    inB2 = pIn2[1];
    inA1 = pIn1[2];
    out2 = inA2 - inB2;
    inB1 = pIn2[2];
    pOut[0] = out1;
    pOut[1] = out2;
    inA2 = pIn1[3];
    inB2 = pIn2[3];
    out1 = inA1 - inB1;
    out2 = inA2 - inB2;
    pOut[2] = out1;
    pOut[3] = out2;
    pIn1 += 4u;
    pIn2 += 4u;
    pOut += 4u;
    blkCnt--;
  }
  blkCnt = numSamples & 0x3u;
  while (blkCnt > 0u) {
    *pOut++ = (*pIn1++) - (*pIn2++);
    blkCnt--;
  }
  status = 0;
  return (status);
}
```