ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    $0x16,%edx
  imul   %edx,%eax
  add    $0x1c,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L29
L16:
  movb   $0x0,-0xb(%rbp)
  jmp    L6
L44:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  movzbl -0xb(%rbp),%ecx
  movzbl -0xa(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jge    L38
  movzbl -0xb(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xb(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%eax
  movzbl -0x9(%rbp),%edx
  imul   %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L55
L38:
  movzbl -0x9(%rbp),%eax
  movzbl -0x9(%rbp),%edx
  imul   %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0xb(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  mov    %ecx,%eax
  imul   %edx,%eax
  mov    %al,-0x9(%rbp)
L55:
  movzbl -0xb(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xb(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xb(%rbp)
  jb     L44
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L16
  movzbl -0x9(%rbp),%eax
  lea    -0x2c(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] < local2 + local1) {
          state[local2] += state[0UL];
          state[0UL] *= state[0UL];
        } else {
          state[0UL] *= state[0UL];
          state[0UL] = state[local1] * state[local2];
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 507365164UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%edx
  mov    %edx,%eax
  mulb   (%rdi)
  add    $0x1c,%eax
  movzbl 0x1(%rdi),%r9d
  test   %r9b,%r9b
  je     L7
  movzbl %r9b,%edi
  mov    $0x0,%r8d
  jmp    L13
L11:
  imul   %eax,%eax
  imul   %eax,%eax
L1:
  add    $0x1,%edx
  cmp    %edx,%edi
  je     L55
L15:
  movzbl %al,%ecx
  cmp    %edx,%ecx
  jge    L11
  add    %eax,%eax
  imul   %eax,%eax
  jmp    L1
L55:
  add    $0x1,%r8d
  add    $0x1,%edi
  cmp    %r8b,%r9b
  jbe    L7
L13:
  mov    %r8d,%edx
  jmp    L15
L7:
  sub    $0x2c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] < local2 + local1) {
          state[local2] += state[0UL];
          state[0UL] *= state[0UL];
        } else {
          state[0UL] *= state[0UL];
          state[0UL] = state[local1] * state[local2];
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 507365164UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  movzbl 0x1(%rdi),%r9d
  add    $0x1c,%eax
  test   %r9b,%r9b
  je     L48
  movzbl %r9b,%edi
  xor    %r8d,%r8d
  nop
L47:
  mov    %r8d,%edx
  jmp    L24
  nopl   (%rax)
L58:
  add    %eax,%eax
  add    $0x1,%edx
  imul   %eax,%eax
  cmp    %edi,%edx
  je     L12
L24:
  movzbl %al,%ecx
  cmp    %edx,%ecx
  jl     L58
  imul   %eax,%eax
  add    $0x1,%edx
  imul   %eax,%eax
  cmp    %edi,%edx
  jne    L24
L12:
  add    $0x1,%r8d
  add    $0x1,%edi
  cmp    %r8b,%r9b
  ja     L47
L48:
  sub    $0x2c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] < local2 + local1) {
          state[local2] += state[0UL];
          state[0UL] *= state[0UL];
        } else {
          state[0UL] *= state[0UL];
          state[0UL] = state[local1] * state[local2];
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 507365164UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  movzbl 0x1(%rdi),%r9d
  add    $0x1c,%eax
  test   %r9b,%r9b
  je     L38
  movzbl %r9b,%edi
  xor    %r8d,%r8d
  nop
L0:
  mov    %r8d,%edx
  jmp    L52
  nopl   (%rax)
L48:
  imul   %eax,%eax
  add    $0x1,%edx
  imul   %eax,%eax
  cmp    %edx,%edi
  je     L33
L52:
  movzbl %al,%ecx
  cmp    %ecx,%edx
  jle    L48
  add    %eax,%eax
  add    $0x1,%edx
  imul   %eax,%eax
  cmp    %edx,%edi
  jne    L52
L33:
  add    $0x1,%r8d
  add    $0x1,%edi
  cmp    %r8b,%r9b
  ja     L0
L38:
  sub    $0x2c,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] < local2 + local1) {
          state[local2] += state[0UL];
          state[0UL] *= state[0UL];
        } else {
          state[0UL] *= state[0UL];
          state[0UL] = state[local1] * state[local2];
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 507365164UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_partial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L34:
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L18
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L18:
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x8(%rbp),%eax
  jmp    L0
L4:
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  mov    $0xffffffff,%eax
L0:
  leave
  ret
```

assistant: ```c
int find_partial(const char *in, int in_size, const char *sub, int sub_size) {
  int n;
  int size;
  for (n = 0; n < in_size; ++n) {
    if (sub_size < in_size - n)
      size = sub_size;
    else
      size = in_size - n;
    if (memcmp(in + n, sub, size) == 0)
      return n;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_partial>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L20
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,%r14
  mov    %ecx,%ebp
  mov    %esi,%r15d
  mov    $0x0,%ebx
L1:
  mov    %ebx,0xc(%rsp)
  mov    %r12d,%edx
  sub    %ebx,%edx
  cmp    %ebp,%edx
  cmovg  %ebp,%edx
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r14,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L36
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L1
  movl   $0xffffffff,0xc(%rsp)
L36:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L36
```

assistant: ```c
int find_partial(const char *in, int in_size, const char *sub, int sub_size) {
  int n;
  int size;
  for (n = 0; n < in_size; ++n) {
    if (sub_size < in_size - n)
      size = sub_size;
    else
      size = in_size - n;
    if (memcmp(in + n, sub, size) == 0)
      return n;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_partial>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L18
  movslq %esi,%rax
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %rax,0x8(%rsp)
  mov    %ecx,%ebx
  xor    %r15d,%r15d
  jmp    L49
  nopl   (%rax)
L35:
  add    $0x1,%r15
  cmp    0x8(%rsp),%r15
  je     L18
L49:
  mov    %ebp,%edx
  lea    (%r12,%r15,1),%rdi
  mov    %r13,%rsi
  mov    %r15d,%r14d
  sub    %r15d,%edx
  cmp    %ebx,%edx
  cmovg  %ebx,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L35
L48:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%r14d
  jmp    L48
```

assistant: ```c
int find_partial(const char *in, int in_size, const char *sub, int sub_size) {
  int n;
  int size;
  for (n = 0; n < in_size; ++n) {
    if (sub_size < in_size - n)
      size = sub_size;
    else
      size = in_size - n;
    if (memcmp(in + n, sub, size) == 0)
      return n;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_partial>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L37
  movslq %esi,%rax
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %rax,0x8(%rsp)
  mov    %ecx,%ebx
  xor    %r15d,%r15d
  jmp    L43
  nopl   (%rax)
L20:
  add    $0x1,%r15
  cmp    0x8(%rsp),%r15
  je     L37
L43:
  mov    %ebp,%edx
  lea    (%r12,%r15,1),%rdi
  mov    %r13,%rsi
  mov    %r15d,%r14d
  sub    %r15d,%edx
  cmp    %ebx,%edx
  cmovg  %ebx,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L20
L19:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    $0xffffffff,%r14d
  jmp    L19
```

assistant: ```c
int find_partial(const char *in, int in_size, const char *sub, int sub_size) {
  int n;
  int size;
  for (n = 0; n < in_size; ++n) {
    if (sub_size < in_size - n)
      size = sub_size;
    else
      size = in_size - n;
    if (memcmp(in + n, sub, size) == 0)
      return n;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<iso_lib_is_compatible>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <iso_lib_version@plt>
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L21
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L1
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jl     L21
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jne    L1
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jg     L1
L21:
  mov    $0x1,%eax
  jmp    L61
L1:
  mov    $0x0,%eax
L61:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

assistant: ```c
int iso_lib_is_compatible(int major, int minor, int micro) {
  int cmajor, cminor, cmicro;
  iso_lib_version(&cmajor, &cminor, &cmicro);
  return cmajor > major || (cmajor == major && (cminor > minor || (cminor == minor && cmicro >= micro)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<iso_lib_is_compatible>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <iso_lib_version@plt>
  mov    0xc(%rsp),%edx
  mov    $0x1,%eax
  cmp    %ebx,%edx
  jg     L31
  mov    $0x0,%eax
  je     L40
L31:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  mov    0x10(%rsp),%edx
  mov    $0x1,%eax
  cmp    %ebp,%edx
  jg     L31
  mov    $0x0,%eax
  jne    L31
  cmp    %r12d,0x14(%rsp)
  setge  %al
  movzbl %al,%eax
  jmp    L31
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int iso_lib_is_compatible(int major, int minor, int micro) {
  int cmajor, cminor, cmicro;
  iso_lib_version(&cmajor, &cminor, &cmicro);
  return cmajor > major || (cmajor == major && (cminor > minor || (cminor == minor && cmicro >= micro)));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<iso_lib_is_compatible>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <iso_lib_version@plt>
  mov    $0x1,%eax
  cmp    %ebx,0xc(%rsp)
  jg     L50
  mov    $0x0,%eax
  je     L38
L50:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0x1,%eax
  cmp    %ebp,0x10(%rsp)
  jg     L50
  mov    $0x0,%eax
  jne    L50
  xor    %eax,%eax
  cmp    %r12d,0x14(%rsp)
  setge  %al
  jmp    L50
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int iso_lib_is_compatible(int major, int minor, int micro) {
  int cmajor, cminor, cmicro;
  iso_lib_version(&cmajor, &cminor, &cmicro);
  return cmajor > major || (cmajor == major && (cminor > minor || (cminor == minor && cmicro >= micro)));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<iso_lib_is_compatible>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <iso_lib_version@plt>
  mov    $0x1,%eax
  cmp    %ebx,0xc(%rsp)
  jg     L26
  mov    $0x0,%eax
  je     L10
L26:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  cmp    %ebp,0x10(%rsp)
  jg     L26
  mov    $0x0,%eax
  jne    L26
  xor    %eax,%eax
  cmp    %r12d,0x14(%rsp)
  setge  %al
  jmp    L26
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int iso_lib_is_compatible(int major, int minor, int micro) {
  int cmajor, cminor, cmicro;
  iso_lib_version(&cmajor, &cminor, &cmicro);
  return cmajor > major || (cmajor == major && (cminor > minor || (cminor == minor && cmicro >= micro)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_palindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L34
L21:
  mov    -0x18(%rbp),%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L34:
  cmpq   $0x0,-0x18(%rbp)
  jne    L21
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L9
  mov    $0x1,%eax
  jmp    L4
L9:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int check_palindrome(unsigned long int n) {
  unsigned long int t1, t2, r;
  t1 = n;
  while (t1) {
    r = t1 % 10;
    t1 = t1 / 10;
    t2 = t2 * 10 + r;
  }
  if (t2 == n)
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_palindrome>:
  endbr64
  test   %rdi,%rdi
  je     L10
  mov    %rdi,%rcx
  movabs $0xcccccccccccccccd,%r9
L19:
  mov    %rcx,%rax
  mul    %r9
  shr    $0x3,%rdx
  mov    %rdx,%r8
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  mov    %r8,%rcx
  lea    (%rsi,%rsi,4),%rsi
  lea    (%rdx,%rsi,2),%rsi
  cmp    $0x9,%rax
  ja     L19
L10:
  cmp    %rsi,%rdi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int check_palindrome(unsigned long int n) {
  unsigned long int t1, t2, r;
  t1 = n;
  while (t1) {
    r = t1 % 10;
    t1 = t1 / 10;
    t2 = t2 * 10 + r;
  }
  if (t2 == n)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_palindrome>:
  endbr64
  test   %rdi,%rdi
  je     L1
  movabs $0xcccccccccccccccd,%r9
  mov    %rdi,%rcx
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %rcx,%rax
  mul    %r9
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rsi
  mov    %rdx,%rax
  mov    %rcx,%rdx
  add    %rsi,%rsi
  sub    %rsi,%rdx
  mov    %rcx,%rsi
  mov    %rax,%rcx
  lea    (%r8,%r8,4),%rax
  lea    (%rdx,%rax,2),%r8
  cmp    $0x9,%rsi
  ja     L19
L1:
  xor    %eax,%eax
  cmp    %r8,%rdi
  sete   %al
  ret
```

assistant: ```c
int check_palindrome(unsigned long int n) {
  unsigned long int t1, t2, r;
  t1 = n;
  while (t1) {
    r = t1 % 10;
    t1 = t1 / 10;
    t2 = t2 * 10 + r;
  }
  if (t2 == n)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_palindrome>:
  endbr64
  test   %rdi,%rdi
  je     L8
  movabs $0xcccccccccccccccd,%r9
  mov    %rdi,%rcx
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %rcx,%rax
  mul    %r9
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rsi
  mov    %rdx,%rax
  mov    %rcx,%rdx
  add    %rsi,%rsi
  sub    %rsi,%rdx
  mov    %rcx,%rsi
  mov    %rax,%rcx
  lea    (%r8,%r8,4),%rax
  lea    (%rdx,%rax,2),%r8
  cmp    $0x9,%rsi
  ja     L4
L8:
  xor    %eax,%eax
  cmp    %r8,%rdi
  sete   %al
  ret
```

assistant: ```c
int check_palindrome(unsigned long int n) {
  unsigned long int t1, t2, r;
  t1 = n;
  while (t1) {
    r = t1 % 10;
    t1 = t1 / 10;
    t2 = t2 * 10 + r;
  }
  if (t2 == n)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pick_heatmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L24
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L24
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L24:
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x19,-0xc(%rbp)
  jle    L2
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char pick_heatmap(int *heatmap) {
  int i, pos, min = INT_MAX;
  for (i = 0; i <= 'z' - 'a'; i++) {
    if (heatmap[i] < min && heatmap[i] != 0) {
      min = heatmap[i];
      pos = i;
    }
  }
  return pos;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pick_heatmap>:
  endbr64
  mov    D1(%rip),%rdx
  mov    (%rdx),%esi
  mov    $0x0,%edx
  jmp    L7
L28:
  add    $0x1,%rdx
  cmp    $0x1a,%rdx
  je     L9
L7:
  mov    (%rdi,%rdx,4),%ecx
  test   %ecx,%ecx
  je     L28
  cmp    %esi,%ecx
  cmovl  %ecx,%esi
  cmovl  %edx,%eax
  jmp    L28
L9:
  ret
```

assistant: ```c
char pick_heatmap(int *heatmap) {
  int i, pos, min = INT_MAX;
  for (i = 0; i <= 'z' - 'a'; i++) {
    if (heatmap[i] < min && heatmap[i] != 0) {
      min = heatmap[i];
      pos = i;
    }
  }
  return pos;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pick_heatmap>:
  endbr64
  mov    D1(%rip),%rdx
  mov    (%rdx),%esi
  xor    %edx,%edx
  nop
L0:
  mov    (%rdi,%rdx,4),%ecx
  test   %ecx,%ecx
  je     L3
  cmp    %esi,%ecx
  setl   %r8b
  test   %r8b,%r8b
  cmovne %ecx,%esi
  cmovne %edx,%eax
L3:
  add    $0x1,%rdx
  cmp    $0x1a,%rdx
  jne    L0
  ret
```

assistant: ```c
char pick_heatmap(int *heatmap) {
  int i, pos, min = INT_MAX;
  for (i = 0; i <= 'z' - 'a'; i++) {
    if (heatmap[i] < min && heatmap[i] != 0) {
      min = heatmap[i];
      pos = i;
    }
  }
  return pos;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pick_heatmap>:
  endbr64
  mov    D7(%rip),%rdx
  mov    (%rdx),%esi
  xor    %edx,%edx
  nop
L4:
  mov    (%rdi,%rdx,4),%ecx
  test   %ecx,%ecx
  je     L19
  cmp    %ecx,%esi
  setg   %r8b
  test   %r8b,%r8b
  cmovne %ecx,%esi
  cmovne %edx,%eax
L19:
  add    $0x1,%rdx
  cmp    $0x1a,%rdx
  jne    L4
  ret
```

assistant: ```c
char pick_heatmap(int *heatmap) {
  int i, pos, min = INT_MAX;
  for (i = 0; i <= 'z' - 'a'; i++) {
    if (heatmap[i] < min && heatmap[i] != 0) {
      min = heatmap[i];
      pos = i;
    }
  }
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_xte_utf8_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  lea    D5(%rip),%rax
  mov    %rax,-0x18(%rbp)
L15:
  movq   $0x0,-0x8(%rbp)
  jmp    L25
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L25
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: 

assistant: ```c
long _xte_utf8_strlen(char const *in_string) {
  if (!in_string)
    in_string = "";
  long count = 0;
  while (*(in_string++)) {
    if ((in_string[0] & 0xC0) != 0x80)
      count++;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_xte_utf8_strlen>:
  endbr64
  mov    $0x0,%ecx
  test   %rdi,%rdi
  je     L26
  lea    0x1(%rdi),%rax
  cmpb   $0x0,(%rdi)
  je     L24
L3:
  movzbl (%rax),%edx
  mov    %edx,%esi
  and    $0xc0,%esi
  cmp    $0x80,%esi
  setne  %sil
  movzbl %sil,%esi
  add    %rsi,%rcx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L3
L26:
  mov    %rcx,%rax
  ret
L24:
  mov    $0x0,%ecx
  jmp    L26
```

assistant: ```c
long _xte_utf8_strlen(char const *in_string) {
  if (!in_string)
    in_string = "";
  long count = 0;
  while (*(in_string++)) {
    if ((in_string[0] & 0xC0) != 0x80)
      count++;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_xte_utf8_strlen>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L17
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L17
  nopl   (%rax)
L19:
  movzbl (%rax),%edx
  mov    %edx,%ecx
  and    $0xc0,%ecx
  cmp    $0x80,%ecx
  setne  %cl
  add    $0x1,%rax
  movzbl %cl,%ecx
  add    %rcx,%r8
  test   %dl,%dl
  jne    L19
L17:
  mov    %r8,%rax
  ret
```

assistant: ```c
long _xte_utf8_strlen(char const *in_string) {
  if (!in_string)
    in_string = "";
  long count = 0;
  while (*(in_string++)) {
    if ((in_string[0] & 0xC0) != 0x80)
      count++;
  }
  return count;
}
```