ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<save_file>:
  endbr64
  test   %rsi,%rsi
  je     L0
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %rdi,%rdi
  je     L26
  mov    $0x1,%r12d
  mov    %rsi,%rbx
  sub    %esi,%r12d
  cmpb   $0x0,(%rsi)
  je     L3
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  lea    (%r12,%rbx,1),%eax
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L3
  imul   $0xcccccccd,%eax,%eax
  ror    $0x4,%eax
  cmp    $0x3333333,%eax
  ja     L4
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L0:
  ret
  nopl   0x0(%rax)
L26:
  pop    %rbx
  lea    D6(%rip),%rsi
  pop    %rbp
  mov    $0xffffffff,%edi
  pop    %r12
  jmp    1070 <fatal_error@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D6: could not open output file.

assistant: ```c
void save_file(FILE *file, char *str) {
  if (!str)
    return;
  if (!file) {
    fatal_error(-1, "could not open output file.");
    return;
  }
  int index = 0;
  while (str[index] != '\0') {
    if (index % 80 == 0 && index != 0) {
      fputc('\n', file);
    }
    fputc(str[index], file);
    index++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pmrrr_dscal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L2:
  mov    -0x14(%rbp),%eax
  imul   -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  imul   -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L2
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pmrrr_dscal(int *n, double *alpha, double *restrict x, int *incx) {
  int i;
  int stride = *incx;
  int size = *n;
  double s = *alpha;
  for (i = 0; i < size; i++)
    x[i * stride] *= s;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pmrrr_dscal>:
  endbr64
  mov    %rsi,%rax
  mov    (%rcx),%ecx
  mov    (%rdi),%esi
  movsd  (%rax),%xmm1
  test   %esi,%esi
  jle    L9
  movslq %ecx,%rcx
  shl    $0x3,%rcx
  mov    $0x0,%eax
L12:
  movapd %xmm1,%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%eax
  add    %rcx,%rdx
  cmp    %eax,%esi
  jne    L12
L9:
  ret
```

assistant: ```c
void pmrrr_dscal(int *n, double *alpha, double *restrict x, int *incx) {
  int i;
  int stride = *incx;
  int size = *n;
  double s = *alpha;
  for (i = 0; i < size; i++)
    x[i * stride] *= s;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pmrrr_dscal>:
  endbr64
  mov    %rsi,%r8
  mov    (%rdi),%esi
  movslq (%rcx),%rcx
  movsd  (%r8),%xmm1
  test   %esi,%esi
  jle    L16
  shl    $0x3,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L1:
  movsd  (%rdx),%xmm0
  add    $0x1,%eax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    %rcx,%rdx
  cmp    %eax,%esi
  jne    L1
L16:
  ret
```

assistant: ```c
void pmrrr_dscal(int *n, double *alpha, double *restrict x, int *incx) {
  int i;
  int stride = *incx;
  int size = *n;
  double s = *alpha;
  for (i = 0; i < size; i++)
    x[i * stride] *= s;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pmrrr_dscal>:
  endbr64
  movslq (%rcx),%rax
  mov    (%rdi),%ecx
  movsd  (%rsi),%xmm0
  test   %ecx,%ecx
  jle    L53
  cmp    $0x1,%eax
  jne    L51
  cmp    $0x1,%ecx
  je     L43
  mov    %ecx,%esi
  movapd %xmm0,%xmm2
  mov    %rdx,%rax
  shr    %esi
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdx,%rsi,1),%rsi
  nopw   0x0(%rax,%rax,1)
L29:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L29
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L2
L8:
  cltq
  lea    (%rdx,%rax,8),%rax
  mulsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L53:
  ret
  xchg   %ax,%ax
L2:
  ret
  nopl   0x0(%rax)
L51:
  lea    0x0(,%rax,8),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L23:
  movsd  (%rdx),%xmm1
  add    $0x1,%eax
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  add    %rsi,%rdx
  cmp    %eax,%ecx
  jne    L23
  ret
L43:
  xor    %eax,%eax
  jmp    L8
```

assistant: ```c
void pmrrr_dscal(int *n, double *alpha, double *restrict x, int *incx) {
  int i;
  int stride = *incx;
  int size = *n;
  double s = *alpha;
  for (i = 0; i < size; i++)
    x[i * stride] *= s;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_chain_idx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  add    $0x8,%rax
  movq   $0x1,(%rax)
  movq   $0x1,-0x20(%rbp)
  movq   $0x2,-0x18(%rbp)
  jmp    L17
L16:
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x10,%rax
  mov    -0x18(%rbp),%rdx
  sub    $0x1,%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L0
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
L0:
  addq   $0x1,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L16
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x10(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x40(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_chain_idx(long num_residue, long **seidx, char *ChainID, long *nchain, long **chain_idx) {
  long n, j, k1, k2;
  chain_idx[1][1] = 1;
  n = 1;
  for (j = 2; j <= num_residue; j++) {
    k1 = seidx[j - 1][1];
    k2 = seidx[j][1];
    chain_idx[n][2] = j - 1;
    if (ChainID[k1] != ChainID[k2]) {
      n++;
      chain_idx[n][1] = j;
    }
  }
  chain_idx[n][2] = num_residue;
  *nchain = n;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_chain_idx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rcx,%r12
  mov    0x8(%r8),%rax
  movq   $0x1,0x8(%rax)
  cmp    $0x1,%rdi
  jle    L33
  mov    %rdx,%rdi
  lea    0x1(%rbx),%r13
  mov    $0x2,%eax
  mov    $0x1,%edx
  jmp    L44
L27:
  add    $0x1,%rax
  cmp    %r13,%rax
  je     L14
L44:
  mov    -0x8(%rsi,%rax,8),%rcx
  mov    0x8(%rcx),%r9
  mov    (%rsi,%rax,8),%rcx
  mov    0x8(%rcx),%rcx
  lea    0x0(,%rdx,8),%rbp
  mov    (%r8,%rdx,8),%r10
  lea    -0x1(%rax),%r11
  mov    %r11,0x10(%r10)
  movzbl (%rdi,%rcx,1),%ecx
  cmp    %cl,(%rdi,%r9,1)
  je     L27
  add    $0x1,%rdx
  mov    0x8(%r8,%rbp,1),%rcx
  mov    %rax,0x8(%rcx)
  jmp    L27
L33:
  mov    $0x1,%edx
L14:
  mov    (%r8,%rdx,8),%rax
  mov    %rbx,0x10(%rax)
  mov    %rdx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void get_chain_idx(long num_residue, long **seidx, char *ChainID, long *nchain, long **chain_idx) {
  long n, j, k1, k2;
  chain_idx[1][1] = 1;
  n = 1;
  for (j = 2; j <= num_residue; j++) {
    k1 = seidx[j - 1][1];
    k2 = seidx[j][1];
    chain_idx[n][2] = j - 1;
    if (ChainID[k1] != ChainID[k2]) {
      n++;
      chain_idx[n][1] = j;
    }
  }
  chain_idx[n][2] = num_residue;
  *nchain = n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_chain_idx>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  mov    0x8(%r8),%rdx
  movq   $0x1,0x8(%rdx)
  cmp    $0x1,%rbx
  jle    L24
  lea    0x1(%rbx),%r12
  mov    $0x2,%eax
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L20:
  mov    -0x8(%rsi,%rax,8),%r9
  lea    -0x1(%rax),%r11
  mov    0x8(%r9),%r10
  mov    (%rsi,%rax,8),%r9
  mov    0x8(%r9),%r9
  mov    %r11,0x10(%rdx)
  movzbl (%rdi,%r9,1),%r11d
  cmp    %r11b,(%rdi,%r10,1)
  je     L7
  add    $0x1,%rcx
  mov    (%r8,%rcx,8),%rdx
  mov    %rax,0x8(%rdx)
L7:
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L20
  mov    %rbx,0x10(%rdx)
  pop    %rbx
  mov    %rcx,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L24:
  mov    $0x1,%ecx
  mov    %rbx,0x10(%rdx)
  pop    %rbx
  mov    %rcx,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void get_chain_idx(long num_residue, long **seidx, char *ChainID, long *nchain, long **chain_idx) {
  long n, j, k1, k2;
  chain_idx[1][1] = 1;
  n = 1;
  for (j = 2; j <= num_residue; j++) {
    k1 = seidx[j - 1][1];
    k2 = seidx[j][1];
    chain_idx[n][2] = j - 1;
    if (ChainID[k1] != ChainID[k2]) {
      n++;
      chain_idx[n][1] = j;
    }
  }
  chain_idx[n][2] = num_residue;
  *nchain = n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_chain_idx>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  mov    0x8(%r8),%rdx
  movq   $0x1,0x8(%rdx)
  cmp    $0x1,%rbx
  jle    L10
  lea    0x1(%rbx),%r12
  mov    $0x2,%eax
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L19:
  mov    -0x8(%rsi,%rax,8),%r9
  lea    -0x1(%rax),%r11
  mov    0x8(%r9),%r10
  mov    (%rsi,%rax,8),%r9
  mov    0x8(%r9),%r9
  mov    %r11,0x10(%rdx)
  movzbl (%rdi,%r9,1),%r11d
  cmp    %r11b,(%rdi,%r10,1)
  je     L29
  add    $0x1,%rcx
  mov    (%r8,%rcx,8),%rdx
  mov    %rax,0x8(%rdx)
L29:
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L19
  mov    %rbx,0x10(%rdx)
  pop    %rbx
  mov    %rcx,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L10:
  mov    $0x1,%ecx
  mov    %rbx,0x10(%rdx)
  pop    %rbx
  mov    %rcx,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void get_chain_idx(long num_residue, long **seidx, char *ChainID, long *nchain, long **chain_idx) {
  long n, j, k1, k2;
  chain_idx[1][1] = 1;
  n = 1;
  for (j = 2; j <= num_residue; j++) {
    k1 = seidx[j - 1][1];
    k2 = seidx[j][1];
    chain_idx[n][2] = j - 1;
    if (ChainID[k1] != ChainID[k2]) {
      n++;
      chain_idx[n][1] = j;
    }
  }
  chain_idx[n][2] = num_residue;
  *nchain = n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,-0x14(%rbp)
L6:
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    %ebx,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
  mov    $0xa,%edi
  call   <sleep@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: I am process %d from process %d, Now it's %d.


assistant: ```c
int main() {
  unsigned int slot = 0;
  while (1) {
    printf("I am process %d from process %d, Now it's %d.\n", getpid(), getppid(), slot);
    slot++;
    sleep(10);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  lea    D5(%rip),%r12
L6:
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  mov    $0xa,%edi
  call   <sleep@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: I am process %d from process %d, Now it's %d.


assistant: ```c
int main() {
  unsigned int slot = 0;
  while (1) {
    printf("I am process %d from process %d, Now it's %d.\n", getpid(), getppid(), slot);
    slot++;
    sleep(10);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebx,%ecx
  mov    %rbp,%rdi
  mov    %r12d,%edx
  mov    %eax,%esi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: I am process %d from process %d, Now it's %d.


assistant: ```c
int main() {
  unsigned int slot = 0;
  while (1) {
    printf("I am process %d from process %d, Now it's %d.\n", getpid(), getppid(), slot);
    slot++;
    sleep(10);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebx,%ecx
  mov    %rbp,%rdi
  mov    %r12d,%edx
  mov    %eax,%esi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: I am process %d from process %d, Now it's %d.


assistant: ```c
int main() {
  unsigned int slot = 0;
  while (1) {
    printf("I am process %d from process %d, Now it's %d.\n", getpid(), getppid(), slot);
    slot++;
    sleep(10);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_time_usecs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x1c(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0xf4240,%eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
long get_time_usecs() {
  struct timeval time;
  struct timezone tz;
  memset(&tz, '\0', sizeof(struct timezone));
  gettimeofday(&time, &tz);
  long usecs = time.tv_sec * 1000000 + time.tv_usec;
  return usecs;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_time_usecs>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x10(%rsp),%eax
  add    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  cltq
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_time_usecs() {
  struct timeval time;
  struct timezone tz;
  memset(&tz, '\0', sizeof(struct timezone));
  gettimeofday(&time, &tz);
  long usecs = time.tv_sec * 1000000 + time.tv_usec;
  return usecs;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_time_usecs>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  xor    %esi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x10(%rsp),%eax
  add    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  cltq
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_time_usecs() {
  struct timeval time;
  struct timezone tz;
  memset(&tz, '\0', sizeof(struct timezone));
  gettimeofday(&time, &tz);
  long usecs = time.tv_sec * 1000000 + time.tv_usec;
  return usecs;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_time_usecs>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  xor    %esi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x10(%rsp),%eax
  add    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  cltq
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_time_usecs() {
  struct timeval time;
  struct timezone tz;
  memset(&tz, '\0', sizeof(struct timezone));
  gettimeofday(&time, &tz);
  long usecs = time.tv_sec * 1000000 + time.tv_usec;
  return usecs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<smalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <logSysExit@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: malloc (smalloc)

assistant: ```c
void *smalloc(size_t size) {
  void *rv;
  if ((rv = malloc(size)) == NULL) {
    logSysExit("malloc (smalloc)");
  }
  return rv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<smalloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L13
L0:
  mov    %rbx,%rax
  pop    %rbx
  ret
L13:
  lea    D4(%rip),%rdi
  call   <logSysExit@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: malloc (smalloc)

assistant: ```c
void *smalloc(size_t size) {
  void *rv;
  if ((rv = malloc(size)) == NULL) {
    logSysExit("malloc (smalloc)");
  }
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<smalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L18:
  mov    %r12,%rax
  pop    %r12
  ret
L15:
  lea    D9(%rip),%rdi
  call   <logSysExit@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D9: malloc (smalloc)

assistant: ```c
void *smalloc(size_t size) {
  void *rv;
  if ((rv = malloc(size)) == NULL) {
    logSysExit("malloc (smalloc)");
  }
  return rv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<smalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
L11:
  mov    %r12,%rax
  pop    %r12
  ret
L16:
  lea    D5(%rip),%rdi
  call   <logSysExit@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: malloc (smalloc)

assistant: ```c
void *smalloc(size_t size) {
  void *rv;
  if ((rv = malloc(size)) == NULL) {
    logSysExit("malloc (smalloc)");
  }
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<to_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x7f,-0x14(%rbp)
  jg     L7
  mov    -0x14(%rbp),%eax
  mov    %al,D51(%rip)
  movb   $0x0,D47(%rip)
  lea    D51(%rip),%rax
  jmp    L4
L27:
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    D51(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  sarl   $0x6,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x3f,-0x14(%rbp)
  jg     L27
  mov    $0x8,%eax
  sub    -0x4(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    D51(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    D51(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D51(%rip),%rax
L4:
  pop    %rbp
  ret
```

assistant: ```c
char *to_utf8(int c) {
  static char s[5];
  int nbytes = 0;
  if (c <= 0x7f) {
    s[0] = c;
    s[1] = '\0';
    return s;
  }
  while (c > 0x3f) {
    s[nbytes] = 0x80 | (c & 0x3f);
    c >>= 6;
    nbytes++;
  }
  s[nbytes] = ~0 << (8 - nbytes) | c;
  nbytes++;
  s[nbytes] = '\0';
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<to_utf8>:
  endbr64
  lea    D7(%rip),%rcx
  mov    $0x0,%edx
  cmp    $0x7f,%edi
  jle    L19
L4:
  mov    %edi,%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,(%rcx)
  sar    $0x6,%edi
  mov    %edx,%eax
  add    $0x1,%edx
  add    $0x1,%rcx
  cmp    $0x3f,%edi
  jg     L4
  lea    D7(%rip),%rsi
  movslq %edx,%r8
  mov    $0x8,%ecx
  sub    %edx,%ecx
  mov    $0xffffffff,%edx
  shl    %cl,%edx
  or     %edi,%edx
  mov    %dl,(%rsi,%r8,1)
  add    $0x2,%eax
  cltq
  movb   $0x0,(%rsi,%rax,1)
L12:
  lea    D7(%rip),%rax
  ret
L19:
  mov    %dil,D37(%rip)
  movb   $0x0,D37(%rip)
  jmp    L12
```

assistant: ```c
char *to_utf8(int c) {
  static char s[5];
  int nbytes = 0;
  if (c <= 0x7f) {
    s[0] = c;
    s[1] = '\0';
    return s;
  }
  while (c > 0x3f) {
    s[nbytes] = 0x80 | (c & 0x3f);
    c >>= 6;
    nbytes++;
  }
  s[nbytes] = ~0 << (8 - nbytes) | c;
  nbytes++;
  s[nbytes] = '\0';
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_utf8>:
  endbr64
  lea    D26(%rip),%r8
  xor    %edx,%edx
  mov    %r8,%rcx
  cmp    $0x7f,%edi
  jle    L18
L4:
  mov    %edi,%eax
  sar    $0x6,%edi
  add    $0x1,%rcx
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,-0x1(%rcx)
  mov    %edx,%eax
  add    $0x1,%edx
  cmp    $0x3f,%edi
  jg     L4
  mov    $0x8,%ecx
  movslq %edx,%rsi
  add    $0x2,%eax
  sub    %edx,%ecx
  mov    $0xffffffff,%edx
  cltq
  shl    %cl,%edx
  or     %edi,%edx
  mov    %dl,(%r8,%rsi,1)
  movb   $0x0,(%r8,%rax,1)
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %dil,D24(%rip)
  mov    %r8,%rax
  movb   $0x0,D24(%rip)
  ret
```

assistant: ```c
char *to_utf8(int c) {
  static char s[5];
  int nbytes = 0;
  if (c <= 0x7f) {
    s[0] = c;
    s[1] = '\0';
    return s;
  }
  while (c > 0x3f) {
    s[nbytes] = 0x80 | (c & 0x3f);
    c >>= 6;
    nbytes++;
  }
  s[nbytes] = ~0 << (8 - nbytes) | c;
  nbytes++;
  s[nbytes] = '\0';
  return s;
}
```