ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<count_alphanumeric>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
  mov    $0x1,%edx
  mov    $0x0,%ecx
  jmp    L30
L7:
  add    $0x1,%ecx
  mov    %edx,%eax
L32:
  cltq
  movzbl (%rdi,%rax,1),%eax
  add    $0x1,%edx
  test   %al,%al
  je     L3
L30:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L7
  mov    %edx,%eax
  jmp    L32
L6:
  mov    $0x0,%ecx
L3:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int count_alphanumeric(char *string) {
  int alphanumeric_counter = 0;
  int i = 0;
  while (string[i] != '\0') {
    if (string[i] <= 57 && string[i] >= 48) {
      i++;
      continue;
    } else
      alphanumeric_counter++;
    i++;
  }
  return alphanumeric_counter;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<count_alphanumeric>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L14
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L0:
  sub    $0x30,%eax
  cmp    $0xa,%al
  sbb    $0xffffffff,%r8d
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L0
  mov    %r8d,%eax
  ret
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_alphanumeric(char *string) {
  int alphanumeric_counter = 0;
  int i = 0;
  while (string[i] != '\0') {
    if (string[i] <= 57 && string[i] >= 48) {
      i++;
      continue;
    } else
      alphanumeric_counter++;
    i++;
  }
  return alphanumeric_counter;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_alphanumeric>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L13:
  sub    $0x30,%eax
  cmp    $0xa,%al
  sbb    $0xffffffff,%r8d
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L13
  mov    %r8d,%eax
  ret
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_alphanumeric(char *string) {
  int alphanumeric_counter = 0;
  int i = 0;
  while (string[i] != '\0') {
    if (string[i] <= 57 && string[i] >= 48) {
      i++;
      continue;
    } else
      alphanumeric_counter++;
    i++;
  }
  return alphanumeric_counter;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cpufv_toggle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <cpufv_get@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x2,-0x8(%rbp)
  jle    L5
  movl   $0x0,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int cpufv_toggle(void) {
  int mode, next;
  mode = cpufv_get();
  next = (mode % 3) + 1;
  if (next > 2)
    next = 0;
  return next;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cpufv_toggle>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cpufv_get@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cmp    $0x3,%eax
  mov    $0x0,%edx
  cmovge %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cpufv_toggle(void) {
  int mode, next;
  mode = cpufv_get();
  next = (mode % 3) + 1;
  if (next > 2)
    next = 0;
  return next;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpufv_toggle>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cpufv_get@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  cmp    $0x2,%eax
  lea    0x1(%rax),%r8d
  mov    $0x0,%eax
  cmove  %eax,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int cpufv_toggle(void) {
  int mode, next;
  mode = cpufv_get();
  next = (mode % 3) + 1;
  if (next > 2)
    next = 0;
  return next;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpufv_toggle>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cpufv_get@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  cmp    $0x2,%eax
  lea    0x1(%rax),%r8d
  mov    $0x0,%eax
  cmove  %eax,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int cpufv_toggle(void) {
  int mode, next;
  mode = cpufv_get();
  next = (mode % 3) + 1;
  if (next > 2)
    next = 0;
  return next;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<md4_sem_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <semop@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void md4_sem_unlock(int semid, int semnum) {
  struct sembuf sops;
  sops.sem_num = semnum;
  sops.sem_op = 1;
  sops.sem_flg = SEM_UNDO;
  semop(semid, &sops, 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<md4_sem_unlock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %esi,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  call   <semop@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void md4_sem_unlock(int semid, int semnum) {
  struct sembuf sops;
  sops.sem_num = semnum;
  sops.sem_op = 1;
  sops.sem_flg = SEM_UNDO;
  semop(semid, &sops, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<md4_sem_unlock>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  movl   $0x1,0x10(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  call   <semop@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void md4_sem_unlock(int semid, int semnum) {
  struct sembuf sops;
  sops.sem_num = semnum;
  sops.sem_op = 1;
  sops.sem_flg = SEM_UNDO;
  semop(semid, &sops, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<md4_sem_unlock>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  movl   $0x1,0x10(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  call   <semop@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void md4_sem_unlock(int semid, int semnum) {
  struct sembuf sops;
  sops.sem_num = semnum;
  sops.sem_op = 1;
  sops.sem_flg = SEM_UNDO;
  semop(semid, &sops, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movl   $0x40,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L8
L14:
  mov    $0x0,%eax
  call   <random@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  mov    $0x0,%eax
  call   <random@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  addl   $0x1,-0x2c(%rbp)
L8:
  mov    -0x2c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L14
  movl   $0x0,-0x28(%rbp)
  jmp    L30
L35:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x28(%rbp)
L30:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L35
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  const int size = 64;
  int sizeBytes = size * sizeof(int32_t);
  int32_t *x = malloc(sizeBytes);
  int32_t *y = malloc(sizeBytes);
  int32_t *s = malloc(sizeBytes);
  int scalar = 3;
  for (int i = 0; i < size; ++i) {
    x[i] = random() % 100;
    y[i] = random() % 100;
  }
  for (int i = 0; i < size; ++i)
    s[i] = x[i] + y[i] + scalar;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ebx
L7:
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%rbx,1)
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%r12,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x100,%rbx
  jne    L7
  mov    $0x0,%eax
L3:
  mov    (%r12,%rax,1),%edx
  add    0x0(%rbp,%rax,1),%edx
  add    $0x3,%edx
  mov    %edx,0x0(%r13,%rax,1)
  add    $0x4,%rax
  cmp    $0x100,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(void) {
  const int size = 64;
  int sizeBytes = size * sizeof(int32_t);
  int32_t *x = malloc(sizeBytes);
  int32_t *y = malloc(sizeBytes);
  int32_t *s = malloc(sizeBytes);
  int scalar = 3;
  for (int i = 0; i < size; ++i) {
    x[i] = random() % 100;
    y[i] = random() % 100;
  }
  for (int i = 0; i < size; ++i)
    s[i] = x[i] + y[i] + scalar;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x100,%edi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx,%r13,1)
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%r12,%r13,1)
  add    $0x4,%r13
  cmp    $0x100,%r13
  jne    L9
  xor    %eax,%eax
  nopl   0x0(%rax)
L12:
  mov    (%r12,%rax,1),%edx
  add    (%rbx,%rax,1),%edx
  add    $0x3,%edx
  mov    %edx,0x0(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    $0x100,%rax
  jne    L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(void) {
  const int size = 64;
  int sizeBytes = size * sizeof(int32_t);
  int32_t *x = malloc(sizeBytes);
  int32_t *y = malloc(sizeBytes);
  int32_t *s = malloc(sizeBytes);
  int scalar = 3;
  for (int i = 0; i < size; ++i) {
    x[i] = random() % 100;
    y[i] = random() % 100;
  }
  for (int i = 0; i < size; ++i)
    s[i] = x[i] + y[i] + scalar;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eval_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x32,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L34
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
  jmp    L36
L34:
  shll   -0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <index@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  addq   $0x1,-0x8(%rbp)
  jmp    L18
L16:
  nop
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *eval_string(char *buf) {
  int taille = 50;
  int *tab = malloc(sizeof(int) * taille);
  int i = 1;
  char *p = buf;
  while (1) {
    int tmp = atoi(p);
    if (i < taille) {
      tab[i] = tmp;
      i++;
    } else {
      taille *= 2;
      tab = realloc(tab, sizeof(int) * taille);
    }
    if ((p = index(p, ' ')) == NULL) {
      break;
    } else
      p++;
  }
  tab = realloc(tab, sizeof(int) * i);
  tab[0] = i - 1;
  return tab;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eval_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x1,%ebp
  mov    $0x32,%r13d
  jmp    L6
L34:
  movslq %ebp,%rdx
  mov    %eax,(%r12,%rdx,4)
  add    $0x1,%ebp
L31:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <index@plt>
  test   %rax,%rax
  je     L0
  lea    0x1(%rax),%rbx
L6:
  mov    %rbx,%rdi
  call   <atoi@plt>
  cmp    %ebp,%r13d
  jg     L34
  add    %r13d,%r13d
  lea    0x0(,%r13,4),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  jmp    L31
L0:
  lea    0x0(,%rbp,4),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  sub    $0x1,%ebp
  mov    %ebp,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *eval_string(char *buf) {
  int taille = 50;
  int *tab = malloc(sizeof(int) * taille);
  int i = 1;
  char *p = buf;
  while (1) {
    int tmp = atoi(p);
    if (i < taille) {
      tab[i] = tmp;
      i++;
    } else {
      taille *= 2;
      tab = realloc(tab, sizeof(int) * taille);
    }
    if ((p = index(p, ' ')) == NULL) {
      break;
    } else
      p++;
  }
  tab = realloc(tab, sizeof(int) * i);
  tab[0] = i - 1;
  return tab;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<eval_string>:
  endbr64
  push   %r13
  mov    $0x32,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xc8,%edi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L26:
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %eax,(%r12,%rdx,4)
L19:
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <index@plt>
  test   %rax,%rax
  je     L33
  lea    0x1(%rax),%rbp
L8:
  mov    %rbp,%rdi
  call   <atoi@plt>
  cmp    %ebx,%r13d
  jg     L26
  add    %r13d,%r13d
  mov    %r12,%rdi
  lea    0x0(,%r13,4),%esi
  call   <realloc@plt>
  mov    %rax,%r12
  jmp    L19
  nopl   (%rax)
L33:
  lea    0x0(,%rbx,4),%esi
  mov    %r12,%rdi
  sub    $0x1,%ebx
  call   <realloc@plt>
  mov    %ebx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *eval_string(char *buf) {
  int taille = 50;
  int *tab = malloc(sizeof(int) * taille);
  int i = 1;
  char *p = buf;
  while (1) {
    int tmp = atoi(p);
    if (i < taille) {
      tab[i] = tmp;
      i++;
    } else {
      taille *= 2;
      tab = realloc(tab, sizeof(int) * taille);
    }
    if ((p = index(p, ' ')) == NULL) {
      break;
    } else
      p++;
  }
  tab = realloc(tab, sizeof(int) * i);
  tab[0] = i - 1;
  return tab;
}
```
user: What is the c source code of the assembly code below:

```asm
<eval_string>:
  endbr64
  push   %r13
  mov    $0x32,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xc8,%edi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L6:
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %eax,(%r12,%rdx,4)
L5:
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <index@plt>
  test   %rax,%rax
  je     L18
  lea    0x1(%rax),%rbp
L31:
  mov    %rbp,%rdi
  call   <atoi@plt>
  cmp    %ebx,%r13d
  jg     L6
  add    %r13d,%r13d
  mov    %r12,%rdi
  lea    0x0(,%r13,4),%esi
  call   <realloc@plt>
  mov    %rax,%r12
  jmp    L5
  nopl   (%rax)
L18:
  lea    0x0(,%rbx,4),%esi
  mov    %r12,%rdi
  sub    $0x1,%ebx
  call   <realloc@plt>
  mov    %ebx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *eval_string(char *buf) {
  int taille = 50;
  int *tab = malloc(sizeof(int) * taille);
  int i = 1;
  char *p = buf;
  while (1) {
    int tmp = atoi(p);
    if (i < taille) {
      tab[i] = tmp;
      i++;
    } else {
      taille *= 2;
      tab = realloc(tab, sizeof(int) * taille);
    }
    if ((p = index(p, ' ')) == NULL) {
      break;
    } else
      p++;
  }
  tab = realloc(tab, sizeof(int) * i);
  tab[0] = i - 1;
  return tab;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_contents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L28
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
L43:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  lea    (%rcx,%rax,1),%rdi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L27
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  ja     L43
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  test   %rax,%rax
  jmp    L47
L28:
  nop
  jmp    L47
L27:
  nop
L47:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: w

assistant: ```c
void write_contents(char *path, char *contents) {
  FILE *f = fopen(path, "w");
  if (f == NULL) {
    return;
  }
  size_t len = strlen(contents);
  int offset = 0;
  do {
    int res = fwrite(contents + offset, 1, len - offset, f);
    if (res < 0) {
      return;
    }
    offset += res;
  } while (offset < len);
  if (fclose(f) < 0) {
    return;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_contents>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r13
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L20
  mov    %rax,%r12
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
L17:
  movslq %ebx,%rdi
  mov    %rbp,%rdx
  sub    %rdi,%rdx
  add    %r13,%rdi
  mov    %r12,%rcx
  mov    $0x1,%esi
  call   <fwrite@plt>
  test   %eax,%eax
  js     L20
  add    %eax,%ebx
  movslq %ebx,%rax
  cmp    %rbp,%rax
  jb     L17
  mov    %r12,%rdi
  call   <fclose@plt>
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: w

assistant: ```c
void write_contents(char *path, char *contents) {
  FILE *f = fopen(path, "w");
  if (f == NULL) {
    return;
  }
  size_t len = strlen(contents);
  int offset = 0;
  do {
    int res = fwrite(contents + offset, 1, len - offset, f);
    if (res < 0) {
      return;
    }
    offset += res;
  } while (offset < len);
  if (fclose(f) < 0) {
    return;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_contents>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D0(%rip),%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L20
  mov    %rbp,%rdi
  mov    %rax,%r13
  xor    %r12d,%r12d
  call   <strlen@plt>
  xor    %edi,%edi
  mov    %rax,%rbx
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L1:
  add    %eax,%r12d
  movslq %r12d,%rdi
  cmp    %rbx,%rdi
  jae    L13
L24:
  mov    %rbx,%rdx
  mov    %r13,%rcx
  mov    $0x1,%esi
  sub    %rdi,%rdx
  add    %rbp,%rdi
  call   <fwrite@plt>
  test   %eax,%eax
  jns    L1
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <fclose@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: w

assistant: ```c
void write_contents(char *path, char *contents) {
  FILE *f = fopen(path, "w");
  if (f == NULL) {
    return;
  }
  size_t len = strlen(contents);
  int offset = 0;
  do {
    int res = fwrite(contents + offset, 1, len - offset, f);
    if (res < 0) {
      return;
    }
    offset += res;
  } while (offset < len);
  if (fclose(f) < 0) {
    return;
  }
  return;
}
```