ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<SuperFastHash>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L7
  test   %rdi,%rdi
  je     L7
  mov    %esi,%r9d
  and    $0x3,%r9d
  mov    %esi,%r8d
  sar    $0x2,%r8d
  test   %r8d,%r8d
  jle    L1
  mov    %r8d,%eax
  lea    (%rdi,%rax,8),%rsi
  mov    %rdi,%rcx
L83:
  mov    0x8(%rcx),%eax
  shl    $0x8,%eax
  add    (%rcx),%eax
  add    %edx,%eax
  mov    0xa(%rcx),%edx
  shl    $0x8,%edx
  add    0x2(%rcx),%edx
  shl    $0xb,%edx
  xor    %eax,%edx
  shl    $0x10,%eax
  xor    %edx,%eax
  add    $0x8,%rcx
  mov    %eax,%edx
  sar    $0xb,%edx
  add    %eax,%edx
  cmp    %rsi,%rcx
  jne    L83
  mov    %r8d,%r8d
  lea    (%rdi,%r8,8),%rdi
L1:
  cmp    $0x2,%r9d
  je     L12
  cmp    $0x3,%r9d
  je     L98
  cmp    $0x1,%r9d
  je     L50
L37:
  lea    0x0(,%rdx,8),%eax
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0x5,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0x11,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shl    $0x19,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0x6,%eax
  add    %edx,%eax
  ret
L98:
  mov    0x8(%rdi),%eax
  shl    $0x8,%eax
  add    (%rdi),%eax
  add    %edx,%eax
  mov    %eax,%ecx
  shl    $0x10,%ecx
  movsbl 0x4(%rdi),%edx
  shl    $0x12,%edx
  xor    %edx,%eax
  xor    %ecx,%eax
  mov    %eax,%edx
  sar    $0xb,%edx
  add    %eax,%edx
  jmp    L37
L12:
  mov    0x8(%rdi),%eax
  shl    $0x8,%eax
  add    (%rdi),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shl    $0xb,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  sar    $0x11,%edx
  add    %eax,%edx
  jmp    L37
L50:
  movsbl (%rdi),%eax
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  sar    %edx
  add    %eax,%edx
  jmp    L37
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t SuperFastHash(const char *data, int len) {
  uint32_t hash = len, tmp;
  int rem;
  if (len <= 0 || data == NULL)
    return 0;
  rem = len & 3;
  len >>= 2;
  for (; len > 0; len--) {
    hash += ((((uint32_t)(((const uint8_t *)(data))[1])) << 8) + (uint32_t)(((const uint8_t *)(data))[0]));
    tmp = (((((uint32_t)(((const uint8_t *)(data + 2))[1])) << 8) + (uint32_t)(((const uint8_t *)(data + 2))[0])) << 11) ^ hash;
    hash = (hash << 16) ^ tmp;
    data += 2 * sizeof(uint16_t);
    hash += hash >> 11;
  }
  switch (rem) {
  case 3:
    hash += ((((uint32_t)(((const uint8_t *)(data))[1])) << 8) + (uint32_t)(((const uint8_t *)(data))[0]));
    hash ^= hash << 16;
    hash ^= data[sizeof(uint16_t)] << 18;
    hash += hash >> 11;
    break;
  case 2:
    hash += ((((uint32_t)(((const uint8_t *)(data))[1])) << 8) + (uint32_t)(((const uint8_t *)(data))[0]));
    hash ^= hash << 11;
    hash += hash >> 17;
    break;
  case 1:
    hash += *data;
    hash ^= hash << 10;
    hash += hash >> 1;
  }
  hash ^= hash << 3;
  hash += hash >> 5;
  hash ^= hash << 4;
  hash += hash >> 17;
  hash ^= hash << 25;
  hash += hash >> 6;
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<achieve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L58
L0:
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L49:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  je     L3
  mov    $0x0,%eax
  jmp    L8
L3:
  addl   $0x1,-0x8(%rbp)
L32:
  cmpl   $0x3,-0x8(%rbp)
  jle    L49
  addl   $0x1,-0xc(%rbp)
L58:
  cmpl   $0x3,-0xc(%rbp)
  jle    L0
  mov    $0x1,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int achieve(char tmp[4][4]) {
  int i, j, c;
  c = tmp[0][0];
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      if (tmp[i][j] != c)
        return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<achieve>:
  endbr64
  movzbl (%rdi),%ecx
  lea    0x4(%rdi),%rdx
  add    $0x14,%rdi
  jmp    L42
L24:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L13
L42:
  lea    -0x4(%rdx),%rax
L16:
  cmp    (%rax),%cl
  jne    L40
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
  jmp    L24
L40:
  mov    $0x0,%eax
  ret
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int achieve(char tmp[4][4]) {
  int i, j, c;
  c = tmp[0][0];
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      if (tmp[i][j] != c)
        return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<achieve>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rax
  add    $0x11,%rdi
L46:
  cmp    (%rax),%dl
  jne    L11
  cmp    0x1(%rax),%dl
  jne    L11
  cmp    0x2(%rax),%dl
  jne    L11
  add    $0x4,%rax
  cmp    %rax,%rdi
  je     L1
  cmp    -0x1(%rax),%dl
  je     L46
L11:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int achieve(char tmp[4][4]) {
  int i, j, c;
  c = tmp[0][0];
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      if (tmp[i][j] != c)
        return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<achieve>:
  endbr64
  movzbl (%rdi),%eax
  cmp    0x1(%rdi),%al
  jne    L120
  cmp    0x2(%rdi),%al
  jne    L120
  cmp    0x3(%rdi),%al
  jne    L120
  cmp    0x4(%rdi),%al
  jne    L120
  cmp    0x5(%rdi),%al
  jne    L120
  cmp    0x6(%rdi),%al
  jne    L120
  cmp    0x7(%rdi),%al
  jne    L120
  cmp    0x8(%rdi),%al
  jne    L120
  cmp    0x9(%rdi),%al
  jne    L120
  cmp    0xa(%rdi),%al
  jne    L120
  cmp    0xb(%rdi),%al
  jne    L120
  cmp    0xc(%rdi),%al
  jne    L120
  cmp    0xd(%rdi),%al
  jne    L120
  cmp    0xe(%rdi),%al
  jne    L120
  cmp    %al,0xf(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L120:
  xor    %eax,%eax
  ret
```

assistant: ```c
int achieve(char tmp[4][4]) {
  int i, j, c;
  c = tmp[0][0];
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      if (tmp[i][j] != c)
        return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<av_mallocz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <av_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *av_mallocz(unsigned int size) {
  void *ptr;
  ptr = av_malloc(size);
  if (ptr)
    memset(ptr, 0, size);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<av_mallocz>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <av_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *av_mallocz(unsigned int size) {
  void *ptr;
  ptr = av_malloc(size);
  if (ptr)
    memset(ptr, 0, size);
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<av_mallocz>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x8,%rsp
  call   <av_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *av_mallocz(unsigned int size) {
  void *ptr;
  ptr = av_malloc(size);
  if (ptr)
    memset(ptr, 0, size);
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<av_mallocz>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x8,%rsp
  call   <av_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *av_mallocz(unsigned int size) {
  void *ptr;
  ptr = av_malloc(size);
  if (ptr)
    memset(ptr, 0, size);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D19(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <stueckzahl_eingabe@plt>
  mov    %eax,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x4(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type: f32
name: read_data
arguments: data_tag: D0
type: string

tool: D19: 8.99

tool: D0: The sum is %.2f


assistant: ```c
int main() {
  int productCount;
  float productPrize;
  productPrize = 8.99;
  productCount = stueckzahl_eingabe();
  printf("The sum is %.2f\n", productPrize * productCount);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <stueckzahl_eingabe@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  D11(%rip),%xmm0
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
data_type: f32
name: extract_symbolic_data
arguments: data_label: D16
data_type: string

tool: D11: 8.99

tool: D16: The sum is %.2f


assistant: ```c
int main() {
  int productCount;
  float productPrize;
  productPrize = 8.99;
  productCount = stueckzahl_eingabe();
  printf("The sum is %.2f\n", productPrize * productCount);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <stueckzahl_eingabe@plt>
  pxor   %xmm0,%xmm0
  lea    D11(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mulss  D8(%rip),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D8
datatype: f32

tool: D11: The sum is %.2f


tool: D8: 8.99

assistant: ```c
int main() {
  int productCount;
  float productPrize;
  productPrize = 8.99;
  productCount = stueckzahl_eingabe();
  printf("The sum is %.2f\n", productPrize * productCount);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <stueckzahl_eingabe@plt>
  pxor   %xmm0,%xmm0
  lea    D16(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mulss  D7(%rip),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D7
type: f32

tool: D16: The sum is %.2f


tool: D7: 8.99

assistant: ```c
int main() {
  int productCount;
  float productPrize;
  productPrize = 8.99;
  productCount = stueckzahl_eingabe();
  printf("The sum is %.2f\n", productPrize * productCount);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <distance@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0x4,%r8d
  mov    $0x4,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%ecx
  mov    $0xfffffffc,%edx
  mov    $0xfffffffc,%esi
  mov    $0x1,%edi
  call   <distance@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0x2,%r8d
  mov    $0xfffffffc,%ecx
  mov    $0xfffffffc,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xfffffff9,%ecx
  mov    $0xfffffffd,%edx
  mov    $0xfffffffb,%esi
  mov    $0x2,%edi
  call   <distance@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0xfffffff9,%r8d
  mov    $0xfffffffd,%ecx
  mov    $0xfffffffb,%edx
  mov    $0x2,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: distance between two points for points x%d,y%d  x%d,y%d:  %f


assistant: ```c
int main() {
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         1, 1, 4, 4, distance(1, 1, 4, 4));
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         1, -4, -4, 2, distance(1, -4, -4, 2));
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         2, -5, -3, -7, distance(2, -5, -3, -7));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <distance@plt>
  mov    $0x4,%r8d
  mov    $0x4,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%ecx
  mov    $0xfffffffc,%edx
  mov    $0xfffffffc,%esi
  mov    $0x1,%edi
  call   <distance@plt>
  mov    $0x2,%r8d
  mov    $0xfffffffc,%ecx
  mov    $0xfffffffc,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xfffffff9,%ecx
  mov    $0xfffffffd,%edx
  mov    $0xfffffffb,%esi
  mov    $0x2,%edi
  call   <distance@plt>
  mov    $0xfffffff9,%r8d
  mov    $0xfffffffd,%ecx
  mov    $0xfffffffb,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: distance between two points for points x%d,y%d  x%d,y%d:  %f


assistant: ```c
int main() {
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         1, 1, 4, 4, distance(1, 1, 4, 4));
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         1, -4, -4, 2, distance(1, -4, -4, 2));
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         2, -5, -3, -7, distance(2, -5, -3, -7));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rbp
  mov    $0x1,%edi
  call   <distance@plt>
  mov    $0x4,%r8d
  mov    %rbp,%rdi
  mov    $0x4,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0x2,%ecx
  mov    $0xfffffffc,%edx
  mov    $0xfffffffc,%esi
  mov    $0x1,%edi
  call   <distance@plt>
  mov    $0x2,%r8d
  mov    %rbp,%rdi
  mov    $0xfffffffc,%ecx
  mov    $0xfffffffc,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0xfffffff9,%ecx
  mov    $0xfffffffd,%edx
  mov    $0xfffffffb,%esi
  mov    $0x2,%edi
  call   <distance@plt>
  mov    %rbp,%rdi
  mov    $0xfffffff9,%r8d
  mov    $0xfffffffd,%ecx
  mov    $0xfffffffb,%edx
  mov    $0x2,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: distance between two points for points x%d,y%d  x%d,y%d:  %f


assistant: ```c
int main() {
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         1, 1, 4, 4, distance(1, 1, 4, 4));
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         1, -4, -4, 2, distance(1, -4, -4, 2));
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         2, -5, -3, -7, distance(2, -5, -3, -7));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rbp
  mov    $0x1,%edi
  call   <distance@plt>
  mov    $0x4,%r8d
  mov    %rbp,%rdi
  mov    $0x4,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0x2,%ecx
  mov    $0xfffffffc,%edx
  mov    $0xfffffffc,%esi
  mov    $0x1,%edi
  call   <distance@plt>
  mov    $0x2,%r8d
  mov    %rbp,%rdi
  mov    $0xfffffffc,%ecx
  mov    $0xfffffffc,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0xfffffff9,%ecx
  mov    $0xfffffffd,%edx
  mov    $0xfffffffb,%esi
  mov    $0x2,%edi
  call   <distance@plt>
  mov    %rbp,%rdi
  mov    $0xfffffff9,%r8d
  mov    $0xfffffffd,%ecx
  mov    $0xfffffffb,%edx
  mov    $0x2,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: distance between two points for points x%d,y%d  x%d,y%d:  %f


assistant: ```c
int main() {
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         1, 1, 4, 4, distance(1, 1, 4, 4));
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         1, -4, -4, 2, distance(1, -4, -4, 2));
  printf("distance between two points for points"
         " x%d,y%d  x%d,y%d:  %f\n",
         2, -5, -3, -7, distance(2, -5, -3, -7));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<in_process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x100,%eax
  test   %eax,%eax
  jne    L42
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  jmp    L24
L42:
  mov    -0x14(%rbp),%eax
  and    $0x1ff,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x103,-0x4(%rbp)
  je     L4
  cmpl   $0x104,-0x4(%rbp)
  je     L19
  jmp    L62
L4:
  mov    $0xd,%eax
  jmp    L24
L19:
  mov    $0x8,%eax
  jmp    L24
L62:
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int in_process(unsigned int key) {
  if (!(key & 0x0100)) {
    return key & 0xFF;
  } else {
    int raw_code = key & 0x01FF;
    switch (raw_code) {
    case (0x03 + 0x0100):
      return 0x0d;
    case (0x04 + 0x0100):
      return 0x08;
    }
  }
  return 0x00;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<in_process>:
  endbr64
  test   $0x100,%edi
  je     L16
  and    $0x1ff,%edi
  mov    $0xd,%eax
  cmp    $0x103,%edi
  je     L14
  cmp    $0x104,%edi
  sete   %al
  movzbl %al,%eax
  shl    $0x3,%eax
L14:
  ret
L16:
  movzbl %dil,%eax
  ret
```

assistant: ```c
int in_process(unsigned int key) {
  if (!(key & 0x0100)) {
    return key & 0xFF;
  } else {
    int raw_code = key & 0x01FF;
    switch (raw_code) {
    case (0x03 + 0x0100):
      return 0x0d;
    case (0x04 + 0x0100):
      return 0x08;
    }
  }
  return 0x00;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<in_process>:
  endbr64
  test   $0x100,%edi
  je     L8
  and    $0x1ff,%edi
  mov    $0xd,%eax
  cmp    $0x103,%edi
  je     L15
  xor    %eax,%eax
  cmp    $0x104,%edi
  sete   %al
  shl    $0x3,%eax
L15:
  ret
  xchg   %ax,%ax
L8:
  movzbl %dil,%eax
  ret
```

assistant: ```c
int in_process(unsigned int key) {
  if (!(key & 0x0100)) {
    return key & 0xFF;
  } else {
    int raw_code = key & 0x01FF;
    switch (raw_code) {
    case (0x03 + 0x0100):
      return 0x0d;
    case (0x04 + 0x0100):
      return 0x08;
    }
  }
  return 0x00;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<in_process>:
  endbr64
  test   $0x100,%edi
  je     L3
  and    $0x1ff,%edi
  mov    $0xd,%eax
  cmp    $0x103,%edi
  je     L13
  xor    %eax,%eax
  cmp    $0x104,%edi
  sete   %al
  shl    $0x3,%eax
L13:
  ret
  xchg   %ax,%ax
L3:
  movzbl %dil,%eax
  ret
```

assistant: ```c
int in_process(unsigned int key) {
  if (!(key & 0x0100)) {
    return key & 0xFF;
  } else {
    int raw_code = key & 0x01FF;
    switch (raw_code) {
    case (0x03 + 0x0100):
      return 0x0d;
    case (0x04 + 0x0100):
      return 0x08;
    }
  }
  return 0x00;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_ch8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x11(%rbp),%rax
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x30(%rbp),%rdx
  lea    -0x11(%rbp),%rax
  mov    %rdx,%rcx
  lea    D5(%rip),%rdx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x28(%rbp),%rdx
  lea    -0x11(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: %s

assistant: ```c
void write_ch8(FILE *f, const char *s) {
  char buffer[9];
  memset(buffer, 0, sizeof(buffer));
  snprintf(buffer, sizeof(buffer), "%s", s);
  fwrite(buffer, 8, 1, f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_ch8>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbx
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %r12,%rcx
  lea    D2(%rip),%rdx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: %s

assistant: ```c
void write_ch8(FILE *f, const char *s) {
  char buffer[9];
  memset(buffer, 0, sizeof(buffer));
  snprintf(buffer, sizeof(buffer), "%s", s);
  fwrite(buffer, 8, 1, f);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_ch8>:
  endbr64
  push   %r13
  mov    $0x9,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r13,%rcx
  mov    $0x9,%esi
  mov    %rbp,%rdi
  lea    D0(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <fwrite@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: %s

assistant: ```c
void write_ch8(FILE *f, const char *s) {
  char buffer[9];
  memset(buffer, 0, sizeof(buffer));
  snprintf(buffer, sizeof(buffer), "%s", s);
  fwrite(buffer, 8, 1, f);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_ch8>:
  endbr64
  push   %r13
  mov    $0x9,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r13,%rcx
  mov    $0x9,%esi
  mov    %rbp,%rdi
  lea    D6(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <fwrite@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: %s

assistant: ```c
void write_ch8(FILE *f, const char *s) {
  char buffer[9];
  memset(buffer, 0, sizeof(buffer));
  snprintf(buffer, sizeof(buffer), "%s", s);
  fwrite(buffer, 8, 1, f);
}
```