ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<calculate_num_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  mov    $0x1,%eax
  jmp    L37
L2:
  addq   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L59
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L59
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L2
L59:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L62
L14:
  mov    $0x1,%eax
  jmp    L37
L62:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
L37:
  leave
  ret
```

assistant: ```c
unsigned long calculate_num_lines(const char *atatline, char which) {
  char *p = strchr(atatline, which);
  if (!p)
    return 1;
  while (*p && *p != ',' && *p != ' ')
    p++;
  if (!*p || *p == ' ')
    return 1;
  return strtoul(p + 1, NULL, 10);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calculate_num_lines>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L70
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L27
  cmp    $0x2c,%dl
  je     L27
L78:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L27
  cmp    $0x2c,%dl
  jne    L78
L27:
  mov    $0x1,%ecx
  test   $0xdf,%dl
  jne    L35
L19:
  mov    %rcx,%rax
  add    $0x8,%rsp
  ret
L35:
  lea    0x1(%rax),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,%rcx
  jmp    L19
L70:
  mov    $0x1,%ecx
  jmp    L19
```

assistant: ```c
unsigned long calculate_num_lines(const char *atatline, char which) {
  char *p = strchr(atatline, which);
  if (!p)
    return 1;
  while (*p && *p != ',' && *p != ' ')
    p++;
  if (!*p || *p == ' ')
    return 1;
  return strtoul(p + 1, NULL, 10);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calculate_num_lines>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L22
  movzbl (%rax),%edx
  cmp    $0x2c,%dl
  je     L75
  test   %dl,%dl
  jne    L4
  jmp    L75
  nopl   0x0(%rax)
L19:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L75
  cmp    $0x2c,%dl
  je     L75
L4:
  cmp    $0x20,%dl
  jne    L19
L22:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  and    $0xdf,%edx
  je     L22
  lea    0x1(%rax),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  add    $0x8,%rsp
  jmp    1070 <strtoul@plt>
```

assistant: ```c
unsigned long calculate_num_lines(const char *atatline, char which) {
  char *p = strchr(atatline, which);
  if (!p)
    return 1;
  while (*p && *p != ',' && *p != ' ')
    p++;
  if (!*p || *p == ' ')
    return 1;
  return strtoul(p + 1, NULL, 10);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calculate_num_lines>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L70
  movzbl (%rax),%edx
  cmp    $0x2c,%dl
  je     L48
  test   %dl,%dl
  jne    L77
  jmp    L48
  nopl   0x0(%rax)
L28:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L48
  cmp    $0x2c,%dl
  je     L48
L77:
  cmp    $0x20,%dl
  jne    L28
L70:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  and    $0xdf,%edx
  je     L70
  lea    0x1(%rax),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  add    $0x8,%rsp
  jmp    1070 <strtoul@plt>
```

assistant: ```c
unsigned long calculate_num_lines(const char *atatline, char which) {
  char *p = strchr(atatline, which);
  if (!p)
    return 1;
  while (*p && *p != ',' && *p != ' ')
    p++;
  if (!*p || *p == ' ')
    return 1;
  return strtoul(p + 1, NULL, 10);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PinTypeI2S>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <PinModeSet@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x60,%esi
  mov    %rax,%rdi
  call   <PinConfigSet@plt>
  nop
  leave
  ret
```

assistant: ```c
void PinTypeI2S(unsigned long ulPin, unsigned long ulPinMode) {
  PinModeSet(ulPin, ulPinMode);
  PinConfigSet(ulPin, 0x00000020 | 0x00000040, 0x00000000);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PinTypeI2S>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <PinModeSet@plt>
  mov    $0x0,%edx
  mov    $0x60,%esi
  mov    %rbx,%rdi
  call   <PinConfigSet@plt>
  pop    %rbx
  ret
```

assistant: ```c
void PinTypeI2S(unsigned long ulPin, unsigned long ulPinMode) {
  PinModeSet(ulPin, ulPinMode);
  PinConfigSet(ulPin, 0x00000020 | 0x00000040, 0x00000000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PinTypeI2S>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <PinModeSet@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x60,%esi
  pop    %rbp
  jmp    1060 <PinConfigSet@plt>
```

assistant: ```c
void PinTypeI2S(unsigned long ulPin, unsigned long ulPinMode) {
  PinModeSet(ulPin, ulPinMode);
  PinConfigSet(ulPin, 0x00000020 | 0x00000040, 0x00000000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PinTypeI2S>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <PinModeSet@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x60,%esi
  pop    %rbp
  jmp    1060 <PinConfigSet@plt>
```

assistant: ```c
void PinTypeI2S(unsigned long ulPin, unsigned long ulPinMode) {
  PinModeSet(ulPin, ulPinMode);
  PinConfigSet(ulPin, 0x00000020 | 0x00000040, 0x00000000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FreeFileList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L20:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L3:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L20
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void FreeFileList(char **list, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (list[i]) {
      free(list[i]);
      list[i] = 0;
    }
  }
  free(list);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FreeFileList>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L22
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
  jmp    L25
L12:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L22
L25:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L12
  call   <free@plt>
  movq   $0x0,(%rbx)
  jmp    L12
L22:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void FreeFileList(char **list, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (list[i]) {
      free(list[i]);
      list[i] = 0;
    }
  }
  free(list);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FreeFileList>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L10
  call   <free@plt>
  movq   $0x0,(%rbx)
L10:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L0
L20:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void FreeFileList(char **list, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (list[i]) {
      free(list[i]);
      list[i] = 0;
    }
  }
  free(list);
}
```
user: Translate the below assembly code into C programming language:

```asm
<FreeFileList>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L24
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L23:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L28
  call   <free@plt>
  movq   $0x0,(%rbx)
L28:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L23
L24:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void FreeFileList(char **list, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (list[i]) {
      free(list[i]);
      list[i] = 0;
    }
  }
  free(list);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L12:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  shr    %eax
  cmp    %eax,-0x4(%rbp)
  jb     L12
  mov    -0x8(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0xffff,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint16_t calc_checksum(const uint16_t *data, unsigned int bytes) {
  uint32_t sum;
  unsigned int i;
  sum = 0;
  for (i = 0; i < bytes / 2; i++)
    sum += data[i];
  sum = (sum & 0xffff) + (sum >> 16);
  sum = htons(0xffff - sum);
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calc_checksum>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%ecx
  shr    %ecx
  cmp    $0x1,%esi
  jbe    L26
  mov    $0x0,%eax
  mov    $0x0,%edx
L21:
  add    (%rdi,%rax,4),%edx
  add    $0x1,%rax
  cmp    %eax,%ecx
  ja     L21
L27:
  movzwl %dx,%eax
  sar    $0x10,%edx
  add    %edx,%eax
  mov    $0xffff,%edi
  sub    %eax,%edi
  call   <htons@plt>
  add    $0x8,%rsp
  ret
L26:
  mov    $0x0,%edx
  jmp    L27
```

assistant: ```c
uint16_t calc_checksum(const uint16_t *data, unsigned int bytes) {
  uint32_t sum;
  unsigned int i;
  sum = 0;
  for (i = 0; i < bytes / 2; i++)
    sum += data[i];
  sum = (sum & 0xffff) + (sum >> 16);
  sum = htons(0xffff - sum);
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_checksum>:
  endbr64
  shr    %esi
  je     L12
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdi,%rdx
  jne    L0
  movzwl %ax,%edx
  sar    $0x10,%eax
  mov    $0xffff,%edi
  add    %edx,%eax
  sub    %eax,%edi
  jmp    1050 <htons@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xffff,%edi
  jmp    1050 <htons@plt>
```

assistant: ```c
uint16_t calc_checksum(const uint16_t *data, unsigned int bytes) {
  uint32_t sum;
  unsigned int i;
  sum = 0;
  for (i = 0; i < bytes / 2; i++)
    sum += data[i];
  sum = (sum & 0xffff) + (sum >> 16);
  sum = htons(0xffff - sum);
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_checksum>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%edi
  shr    %edi
  je     L24
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L66
  shr    $0x3,%esi
  mov    %rdx,%rax
  pxor   %xmm0,%xmm0
  lea    -0x1(%rsi),%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdx,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L55:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L55
  movdqa %xmm0,%xmm1
  shl    $0x2,%esi
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%edi
  je     L69
L47:
  mov    %esi,%ecx
  add    (%rdx,%rcx,4),%eax
  lea    0x1(%rsi),%ecx
  cmp    %edi,%ecx
  jae    L69
  add    $0x2,%esi
  add    (%rdx,%rcx,4),%eax
  cmp    %esi,%edi
  jbe    L69
  add    (%rdx,%rsi,4),%eax
L69:
  movzwl %ax,%edx
  sar    $0x10,%eax
  mov    $0xffff,%edi
  add    %edx,%eax
  sub    %eax,%edi
  jmp    1050 <htons@plt>
  nopl   0x0(%rax,%rax,1)
L24:
  mov    $0xffff,%edi
  jmp    1050 <htons@plt>
L66:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L47
```

assistant: ```c
uint16_t calc_checksum(const uint16_t *data, unsigned int bytes) {
  uint32_t sum;
  unsigned int i;
  sum = 0;
  for (i = 0; i < bytes / 2; i++)
    sum += data[i];
  sum = (sum & 0xffff) + (sum >> 16);
  sum = htons(0xffff - sum);
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ring_data_avail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L8
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L7
L8:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  sub    -0x18(%rbp),%rax
L7:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ring_data_avail(uint32_t size, uint32_t head, uint32_t tail) {
  if (head >= tail)
    return head - tail;
  else
    return size + head - tail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ring_data_avail>:
  endbr64
  mov    %rsi,%rcx
  sub    %rdx,%rcx
  lea    (%rsi,%rdi,1),%rax
  sub    %rdx,%rax
  mov    %rax,%rdi
  cmp    %rdx,%rsi
  mov    %rcx,%rax
  cmovl  %rdi,%rax
  ret
```

assistant: ```c
uint32_t ring_data_avail(uint32_t size, uint32_t head, uint32_t tail) {
  if (head >= tail)
    return head - tail;
  else
    return size + head - tail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ring_data_avail>:
  endbr64
  lea    (%rsi,%rdi,1),%rax
  mov    %rsi,%rcx
  sub    %rdx,%rax
  sub    %rdx,%rcx
  cmp    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rcx,%rax
  cmovl  %rdi,%rax
  ret
```

assistant: ```c
uint32_t ring_data_avail(uint32_t size, uint32_t head, uint32_t tail) {
  if (head >= tail)
    return head - tail;
  else
    return size + head - tail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ring_data_avail>:
  endbr64
  lea    (%rsi,%rdi,1),%rax
  mov    %rsi,%rcx
  sub    %rdx,%rax
  sub    %rdx,%rcx
  cmp    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rcx,%rax
  cmovl  %rdi,%rax
  ret
```

assistant: ```c
uint32_t ring_data_avail(uint32_t size, uint32_t head, uint32_t tail) {
  if (head >= tail)
    return head - tail;
  else
    return size + head - tail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<std_argv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L11:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char **std_argv(void *arg_p, int argc) {
  int i;
  unsigned long *argv = (unsigned long *)(arg_p + sizeof(int));
  for (i = 0; i < argc; i++)
    argv[i] = (unsigned long)(arg_p + argv[i]);
  return (char **)argv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<std_argv>:
  endbr64
  lea    0x4(%rdi),%rcx
  test   %esi,%esi
  jle    L5
  mov    %rcx,%rax
  lea    -0x1(%rsi),%edx
  lea    0xc(%rdi,%rdx,8),%rdx
L12:
  add    %rdi,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L12
L5:
  mov    %rcx,%rax
  ret
```

assistant: ```c
char **std_argv(void *arg_p, int argc) {
  int i;
  unsigned long *argv = (unsigned long *)(arg_p + sizeof(int));
  for (i = 0; i < argc; i++)
    argv[i] = (unsigned long)(arg_p + argv[i]);
  return (char **)argv;
}
```
user: What is the c source code of the assembly code below?

```asm
<std_argv>:
  endbr64
  lea    0x4(%rdi),%r8
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%edx
  mov    %r8,%rax
  lea    0xc(%rdi,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L6:
  add    %rdi,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L6
L12:
  mov    %r8,%rax
  ret
```

assistant: ```c
char **std_argv(void *arg_p, int argc) {
  int i;
  unsigned long *argv = (unsigned long *)(arg_p + sizeof(int));
  for (i = 0; i < argc; i++)
    argv[i] = (unsigned long)(arg_p + argv[i]);
  return (char **)argv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<std_argv>:
  endbr64
  lea    0x4(%rdi),%r8
  test   %esi,%esi
  jle    L19
  cmp    $0x1,%esi
  je     L35
  mov    %esi,%edx
  movq   %rdi,%xmm1
  mov    %r8,%rax
  shr    %edx
  punpcklqdq %xmm1,%xmm1
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x14(%rdi,%rdx,1),%rdx
  nopl   (%rax)
L1:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  paddq  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L1
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L19
L12:
  cltq
  add    %rdi,(%r8,%rax,8)
L19:
  mov    %r8,%rax
  ret
L35:
  xor    %eax,%eax
  jmp    L12
```

assistant: ```c
char **std_argv(void *arg_p, int argc) {
  int i;
  unsigned long *argv = (unsigned long *)(arg_p + sizeof(int));
  for (i = 0; i < argc; i++)
    argv[i] = (unsigned long)(arg_p + argv[i]);
  return (char **)argv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<state_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <error@plt>
  mov    $0xd,%eax
  leave
  ret
```

assistant: ```c
int state_error(struct private *pz, int err) {
  error(pz, err);
  return 13;
}
```
user: What is the c source code of the assembly code below?

```asm
<state_error>:
  endbr64
  sub    $0x8,%rsp
  call   <error@plt>
  mov    $0xd,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int state_error(struct private *pz, int err) {
  error(pz, err);
  return 13;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<state_error>:
  endbr64
  sub    $0x8,%rsp
  call   <error@plt>
  mov    $0xd,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int state_error(struct private *pz, int err) {
  error(pz, err);
  return 13;
}
```
user: What is the c source code of the assembly code below:

```asm
<state_error>:
  endbr64
  sub    $0x8,%rsp
  call   <error@plt>
  mov    $0xd,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int state_error(struct private *pz, int err) {
  error(pz, err);
  return 13;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L36
  mov    D8(%rip),%rax
  jmp    L25
L36:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L24
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <power>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movq   %xmm1,%rax
  jmp    L25
L24:
  mov    -0xc(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movq   %xmm0,%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <power>
  movq   %xmm0,%rax
L25:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double power(double x, unsigned n) {
  if (0 == n)
    return 1;
  else if (n % 2)
    return x * power(x, n - 1);
  else
    return power(x * x, n / 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<power>:
  endbr64
  test   %edi,%edi
  je     L25
  push   %rbx
  movq   %xmm0,%rbx
  test   $0x1,%dil
  je     L29
  sub    $0x1,%edi
  call   <power>
  movq   %rbx,%xmm1
  mulsd  %xmm1,%xmm0
L19:
  pop    %rbx
  ret
L29:
  shr    %edi
  mulsd  %xmm0,%xmm0
  call   <power>
  jmp    L19
L25:
  movsd  D1(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double power(double x, unsigned n) {
  if (0 == n)
    return 1;
  else if (n % 2)
    return x * power(x, n - 1);
  else
    return power(x * x, n / 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<power>:
  endbr64
  test   %edi,%edi
  je     L89
  movapd %xmm0,%xmm1
  test   $0x1,%dil
  je     L119
  jmp    L15
  nopl   0x0(%rax)
L179:
  test   $0x1,%dil
  jne    L15
L119:
  mulsd  %xmm1,%xmm1
  shr    %edi
  jne    L179
L89:
  movsd  D5(%rip),%xmm0
  ret
  nop
L15:
  sub    $0x1,%edi
  je     L190
  movapd %xmm1,%xmm2
  test   $0x1,%dil
  je     L93
  jmp    L34
  nopl   0x0(%rax)
L195:
  test   $0x1,%dil
  jne    L34
L93:
  mulsd  %xmm2,%xmm2
  shr    %edi
  jne    L195
L190:
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  sub    $0x1,%edi
  je     L135
  movapd %xmm2,%xmm3
  test   $0x1,%dil
  je     L108
  jmp    L193
  nopl   0x0(%rax)
L113:
  test   $0x1,%dil
  jne    L193
L108:
  mulsd  %xmm3,%xmm3
  shr    %edi
  jne    L113
L135:
  mulsd  %xmm2,%xmm1
  jmp    L190
  nopl   0x0(%rax)
L193:
  sub    $0x1,%edi
  je     L102
  movapd %xmm3,%xmm4
  test   $0x1,%dil
  je     L162
  jmp    L142
  nopl   0x0(%rax)
L10:
  test   $0x1,%dil
  jne    L142
L162:
  mulsd  %xmm4,%xmm4
  shr    %edi
  jne    L10
L102:
  mulsd  %xmm3,%xmm2
  jmp    L135
  nopl   0x0(%rax)
L142:
  sub    $0x28,%rsp
  movapd %xmm4,%xmm0
  sub    $0x1,%edi
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm4,(%rsp)
  call   <power>
  movsd  (%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  add    $0x28,%rsp
  mulsd  %xmm4,%xmm0
  mulsd  %xmm0,%xmm3
  mulsd  %xmm3,%xmm2
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double power(double x, unsigned n) {
  if (0 == n)
    return 1;
  else if (n % 2)
    return x * power(x, n - 1);
  else
    return power(x * x, n / 2);
}
```