user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x64(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L79
L113:
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x5c(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x60(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L13:
  cmp    %rdx,%rsp
  je     L74
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L13
L74:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L88
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L88:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L69
L111:
  mov    -0x50(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x50(%rbp)
L69:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jl     L111
  movl   $0x0,-0x4c(%rbp)
  jmp    L21
L93:
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  test   %eax,%eax
  jg     L19
  addl   $0x1,-0x54(%rbp)
L19:
  addl   $0x1,-0x4c(%rbp)
L21:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L93
  mov    -0x5c(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L57
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L122
L57:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L122:
  movl   $0x0,-0x54(%rbp)
  mov    %rbx,%rsp
  addl   $0x1,-0x58(%rbp)
L79:
  mov    -0x64(%rbp),%eax
  cmp    %eax,-0x58(%rbp)
  jl     L113
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L109
  call   <__stack_chk_fail@plt>
L109:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D35
type_guessed: string
name: unpack_data
arguments: label: D47
type_guessed: string
name: unpack_data
arguments: label: D42
type_guessed: string
name: unpack_data
arguments: label: D20
type_guessed: string

tool: D35: %d

tool: D47: %d %d

tool: D42: NO


tool: D20: YES


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  for (int a0 = 0; a0 < t; a0++) {
    int n;
    int k;
    int onTime;
    scanf("%d %d", &n, &k);
    int a[n];
    for (int a_i = 0; a_i < n; a_i++) {
      scanf("%d", &a[a_i]);
    }
    for (int i = 0; i < n; i++) {
      if (a[i] <= 0) {
        onTime++;
      }
    }
    if (onTime >= k) {
      printf("NO\n");
    } else {
      printf("YES\n");
    }
    onTime = 0;
  }
  return 0;
}
```