ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L81
L25:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L68
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L81
L68:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L81:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L33
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L25
  jmp    L33
L4:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L33:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  jmp    L85
L17:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L85:
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L17
  nop
  pop    %rbp
  ret
```

assistant: ```c
int merge(int lf[], int rt[], int a[], int m, int n) {
  int i, j, k;
  i = 0;
  j = 0;
  k = 0;
  while (i < m && j < n) {
    if (lf[i] < rt[j])
      a[k++] = lf[i++];
    else
      a[k++] = rt[j++];
  }
  while (i < m)
    a[k++] = lf[i++];
  while (j < n)
    a[k++] = rt[j++];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<merge>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%r10
  mov    %rdx,%rbx
  mov    %ecx,%edi
  test   %ecx,%ecx
  jle    L82
  test   %r8d,%r8d
  jle    L82
  mov    %rdx,%rsi
  mov    $0x1,%edx
  mov    $0x0,%eax
  mov    $0x0,%ecx
  jmp    L105
L74:
  add    $0x1,%eax
  mov    %edx,%r12d
  mov    %r9d,(%rsi)
L75:
  add    $0x1,%edx
  add    $0x4,%rsi
  cmp    %edi,%ecx
  jge    L89
  cmp    %r8d,%eax
  jge    L89
L105:
  movslq %ecx,%r9
  mov    (%r11,%r9,4),%ebp
  movslq %eax,%r9
  mov    (%r10,%r9,4),%r9d
  cmp    %r9d,%ebp
  jge    L74
  add    $0x1,%ecx
  mov    %edx,%r12d
  mov    %ebp,(%rsi)
  jmp    L75
L82:
  mov    $0x0,%r12d
  mov    $0x0,%eax
  mov    $0x0,%ecx
L89:
  cmp    %ecx,%edi
  jle    L60
  movslq %ecx,%rdx
  movslq %r12d,%rsi
  sub    %rdx,%rsi
  lea    (%rbx,%rsi,4),%r9
L39:
  mov    (%r11,%rdx,4),%esi
  mov    %esi,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%edi
  jg     L39
  add    %r12d,%edi
  sub    %ecx,%edi
  mov    %edi,%r12d
L60:
  cmp    %eax,%r8d
  jle    L13
  cltq
  movslq %r12d,%r12
  sub    %rax,%r12
  lea    (%rbx,%r12,4),%rcx
L45:
  mov    (%r10,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L45
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int merge(int lf[], int rt[], int a[], int m, int n) {
  int i, j, k;
  i = 0;
  j = 0;
  k = 0;
  while (i < m && j < n) {
    if (lf[i] < rt[j])
      a[k++] = lf[i++];
    else
      a[k++] = rt[j++];
  }
  while (i < m)
    a[k++] = lf[i++];
  while (j < n)
    a[k++] = rt[j++];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rdi,%r11
  mov    %rsi,%r10
  mov    %ecx,%edi
  push   %rbx
  mov    %rdx,%rbx
  test   %ecx,%ecx
  jle    L34
  test   %r8d,%r8d
  jle    L34
  mov    $0x1,%edx
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L96
  nopl   (%rax)
L71:
  add    $0x1,%esi
  mov    %ecx,-0x4(%rbx,%rdx,4)
  add    $0x1,%rdx
  cmp    %edi,%esi
  jge    L48
L83:
  cmp    %r8d,%eax
  jge    L48
L96:
  movslq %esi,%rcx
  movslq %eax,%r9
  movslq %edx,%rbp
  mov    (%r11,%rcx,4),%ecx
  mov    (%r10,%r9,4),%r9d
  cmp    %r9d,%ecx
  jl     L71
  mov    %r9d,%ecx
  add    $0x1,%eax
  mov    %ecx,-0x4(%rbx,%rdx,4)
  add    $0x1,%rdx
  cmp    %edi,%esi
  jl     L83
L48:
  cmp    %esi,%edi
  jle    L109
  movslq %esi,%rdx
  movslq %ebp,%rcx
  sub    %rdx,%rcx
  lea    (%rbx,%rcx,4),%r9
  nopl   (%rax)
L74:
  mov    (%r11,%rdx,4),%ecx
  mov    %ecx,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%edi
  jg     L74
  add    %ebp,%edi
  sub    %esi,%edi
  movslq %edi,%rbp
L109:
  cmp    %eax,%r8d
  jle    L31
  cltq
  sub    %rax,%rbp
  lea    (%rbx,%rbp,4),%rcx
  nopl   (%rax)
L42:
  mov    (%r10,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L42
L31:
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L34:
  xor    %ebp,%ebp
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L48
```

assistant: ```c
int merge(int lf[], int rt[], int a[], int m, int n) {
  int i, j, k;
  i = 0;
  j = 0;
  k = 0;
  while (i < m && j < n) {
    if (lf[i] < rt[j])
      a[k++] = lf[i++];
    else
      a[k++] = rt[j++];
  }
  while (i < m)
    a[k++] = lf[i++];
  while (j < n)
    a[k++] = rt[j++];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unsigned_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jb     L11
  mov    -0x4(%rbp),%eax
  jmp    L19
L11:
  mov    -0x8(%rbp),%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
unsigned unsigned_max(unsigned x, unsigned y) {
  if (x >= y) {
    return x;
  } else {
    return y;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unsigned_max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovae %edi,%eax
  ret
```

assistant: ```c
unsigned unsigned_max(unsigned x, unsigned y) {
  if (x >= y) {
    return x;
  } else {
    return y;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unsigned_max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovae %edi,%eax
  ret
```

assistant: ```c
unsigned unsigned_max(unsigned x, unsigned y) {
  if (x >= y) {
    return x;
  } else {
    return y;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L5
  mov    $0xffffffff,%eax
  jmp    L17
L5:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L27
  mov    $0x1,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int verify(int row[], int col[], int no_of_mat) {
  int i;
  for (i = 0; i < no_of_mat - 1; i++)
    if (col[i] != row[i + 1])
      return -1;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<verify>:
  endbr64
  cmp    $0x1,%edx
  jle    L13
  lea    -0x2(%rdx),%ecx
  mov    $0x0,%eax
  jmp    L30
L16:
  mov    %rdx,%rax
L30:
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %edx,(%rsi,%rax,4)
  jne    L8
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rax
  jne    L16
  mov    $0x1,%eax
  ret
L13:
  mov    $0x1,%eax
  ret
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int verify(int row[], int col[], int no_of_mat) {
  int i;
  for (i = 0; i < no_of_mat - 1; i++)
    if (col[i] != row[i + 1])
      return -1;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<verify>:
  endbr64
  cmp    $0x1,%edx
  jle    L29
  lea    -0x2(%rdx),%ecx
  xor    %eax,%eax
  jmp    L26
L31:
  lea    0x1(%rax),%rdx
  cmp    %rax,%rcx
  je     L29
  mov    %rdx,%rax
L26:
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %edx,(%rsi,%rax,4)
  je     L31
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int verify(int row[], int col[], int no_of_mat) {
  int i;
  for (i = 0; i < no_of_mat - 1; i++)
    if (col[i] != row[i + 1])
      return -1;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<verify>:
  endbr64
  cmp    $0x1,%edx
  jle    L17
  lea    -0x2(%rdx),%ecx
  xor    %eax,%eax
  jmp    L38
L33:
  lea    0x1(%rax),%rdx
  cmp    %rax,%rcx
  je     L17
  mov    %rdx,%rax
L38:
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %edx,(%rsi,%rax,4)
  je     L33
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int verify(int row[], int col[], int no_of_mat) {
  int i;
  for (i = 0; i < no_of_mat - 1; i++)
    if (col[i] != row[i + 1])
      return -1;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__SHADD8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x18,%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  shl    $0x18,%eax
  sar    $0x18,%eax
  add    %edx,%eax
  sar    %eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x10,%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  shl    $0x10,%eax
  sar    $0x18,%eax
  add    %edx,%eax
  sar    %eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x8,%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  shl    $0x8,%eax
  sar    $0x18,%eax
  add    %edx,%eax
  sar    %eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  sar    $0x18,%eax
  add    %edx,%eax
  sar    %eax
  and    $0xff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0xc(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  or     -0x10(%rbp),%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SHADD8(uint32_t x, uint32_t y) {
  int32_t r, s, t, u;
  r = (((((int32_t)x << 24) >> 24) + (((int32_t)y << 24) >> 24)) >> 1) & (int32_t)0x000000FF;
  s = (((((int32_t)x << 16) >> 24) + (((int32_t)y << 16) >> 24)) >> 1) & (int32_t)0x000000FF;
  t = (((((int32_t)x << 8) >> 24) + (((int32_t)y << 8) >> 24)) >> 1) & (int32_t)0x000000FF;
  u = (((((int32_t)x) >> 24) + (((int32_t)y) >> 24)) >> 1) & (int32_t)0x000000FF;
  return ((uint32_t)((u << 24) | (t << 16) | (s << 8) | (r)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__SHADD8>:
  endbr64
  push   %rbx
  mov    %rdi,%rdx
  mov    %rsi,%rbx
  movsbl %dil,%eax
  movsbl %sil,%ecx
  add    %ecx,%eax
  sar    %eax
  movzbl %al,%eax
  mov    %edi,%ecx
  sar    $0x18,%ecx
  sar    $0x18,%esi
  add    %esi,%ecx
  sar    %ecx
  shl    $0x18,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %ebx,%esi
  shl    $0x8,%esi
  sar    $0x18,%esi
  add    %esi,%ecx
  shl    $0xf,%ecx
  and    $0xff0000,%ecx
  or     %ecx,%eax
  movsbl %dh,%edx
  movsbl %bh,%ebx
  add    %ebx,%edx
  shl    $0x7,%edx
  and    $0xff00,%edx
  or     %edx,%eax
  cltq
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SHADD8(uint32_t x, uint32_t y) {
  int32_t r, s, t, u;
  r = (((((int32_t)x << 24) >> 24) + (((int32_t)y << 24) >> 24)) >> 1) & (int32_t)0x000000FF;
  s = (((((int32_t)x << 16) >> 24) + (((int32_t)y << 16) >> 24)) >> 1) & (int32_t)0x000000FF;
  t = (((((int32_t)x << 8) >> 24) + (((int32_t)y << 8) >> 24)) >> 1) & (int32_t)0x000000FF;
  u = (((((int32_t)x) >> 24) + (((int32_t)y) >> 24)) >> 1) & (int32_t)0x000000FF;
  return ((uint32_t)((u << 24) | (t << 16) | (s << 8) | (r)));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__SHADD8>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rcx
  shl    $0x18,%esi
  mov    %rdi,%rdx
  shl    $0x18,%eax
  sar    $0x18,%esi
  sar    $0x18,%eax
  add    %esi,%eax
  mov    %edi,%esi
  mov    %ecx,%edi
  sar    $0x18,%edi
  sar    $0x18,%esi
  add    %edi,%esi
  sar    %eax
  mov    %ecx,%edi
  sar    %esi
  movzbl %al,%eax
  shl    $0x8,%edi
  shl    $0x18,%esi
  sar    $0x18,%edi
  or     %esi,%eax
  mov    %edx,%esi
  shl    $0x10,%ecx
  shl    $0x8,%esi
  shl    $0x10,%edx
  sar    $0x18,%esi
  sar    $0x18,%edx
  add    %edi,%esi
  sar    $0x18,%ecx
  shl    $0xf,%esi
  add    %ecx,%edx
  and    $0xff0000,%esi
  shl    $0x7,%edx
  or     %esi,%eax
  and    $0xff00,%edx
  or     %edx,%eax
  cltq
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SHADD8(uint32_t x, uint32_t y) {
  int32_t r, s, t, u;
  r = (((((int32_t)x << 24) >> 24) + (((int32_t)y << 24) >> 24)) >> 1) & (int32_t)0x000000FF;
  s = (((((int32_t)x << 16) >> 24) + (((int32_t)y << 16) >> 24)) >> 1) & (int32_t)0x000000FF;
  t = (((((int32_t)x << 8) >> 24) + (((int32_t)y << 8) >> 24)) >> 1) & (int32_t)0x000000FF;
  u = (((((int32_t)x) >> 24) + (((int32_t)y) >> 24)) >> 1) & (int32_t)0x000000FF;
  return ((uint32_t)((u << 24) | (t << 16) | (s << 8) | (r)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__SHADD8>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rcx
  shl    $0x18,%esi
  mov    %rdi,%rdx
  shl    $0x18,%eax
  sar    $0x18,%esi
  sar    $0x18,%eax
  add    %esi,%eax
  mov    %edi,%esi
  mov    %ecx,%edi
  sar    $0x18,%edi
  sar    $0x18,%esi
  add    %edi,%esi
  sar    %eax
  mov    %ecx,%edi
  sar    %esi
  movzbl %al,%eax
  shl    $0x8,%edi
  shl    $0x18,%esi
  sar    $0x18,%edi
  or     %esi,%eax
  mov    %edx,%esi
  shl    $0x10,%ecx
  shl    $0x8,%esi
  shl    $0x10,%edx
  sar    $0x18,%esi
  sar    $0x18,%edx
  add    %edi,%esi
  sar    $0x18,%ecx
  shl    $0xf,%esi
  add    %ecx,%edx
  and    $0xff0000,%esi
  shl    $0x7,%edx
  or     %esi,%eax
  and    $0xff00,%edx
  or     %edx,%eax
  cltq
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __SHADD8(uint32_t x, uint32_t y) {
  int32_t r, s, t, u;
  r = (((((int32_t)x << 24) >> 24) + (((int32_t)y << 24) >> 24)) >> 1) & (int32_t)0x000000FF;
  s = (((((int32_t)x << 16) >> 24) + (((int32_t)y << 16) >> 24)) >> 1) & (int32_t)0x000000FF;
  t = (((((int32_t)x << 8) >> 24) + (((int32_t)y << 8) >> 24)) >> 1) & (int32_t)0x000000FF;
  u = (((((int32_t)x) >> 24) + (((int32_t)y) >> 24)) >> 1) & (int32_t)0x000000FF;
  return ((uint32_t)((u << 24) | (t << 16) | (s << 8) | (r)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnpcbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %rdx,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rax
  mov    %rax,-0x118(%rbp)
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L70
L6:
  movsbq -0x119(%rbp),%rax
  movb   $0x1,-0x110(%rbp,%rax,1)
L70:
  mov    -0x130(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x130(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x119(%rbp)
  cmpb   $0x0,-0x119(%rbp)
  jne    L6
  jmp    L62
L18:
  movsbq -0x119(%rbp),%rax
  movzbl -0x110(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L33
L62:
  mov    -0x138(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x138(%rbp)
  test   %rax,%rax
  je     L2
  mov    -0x118(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x118(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x119(%rbp)
  cmpb   $0x0,-0x119(%rbp)
  jne    L18
  jmp    L2
L33:
  nop
L2:
  cmpb   $0x0,-0x119(%rbp)
  je     L97
  mov    -0x118(%rbp),%rax
  sub    $0x1,%rax
  jmp    L60
L97:
  mov    $0x0,%eax
L60:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L83
  call   <__stack_chk_fail@plt>
L83:
  leave
  ret
```

assistant: ```c
char *(strnpcbrk)(const char *string, const char *skipset, size_t maxlen) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256 * sizeof(char));
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  while (maxlen-- && ((c = *s++)))
    if (set[(size_t)c])
      break;
  return c ? (s - 1) : NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<strnpcbrk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x100,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x1(%r12),%rdx
  movzbl (%r12),%eax
  test   %al,%al
  je     L74
L54:
  movsbq %al,%rax
  movb   $0x1,(%rsp,%rax,1)
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L54
L74:
  lea    (%rbx,%rbp,1),%rcx
  mov    $0x0,%eax
L82:
  cmp    %rcx,%rbx
  je     L12
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L65
  movsbq %al,%rdx
  cmpb   $0x0,(%rsp,%rdx,1)
  je     L82
  jmp    L48
L65:
  mov    $0x0,%eax
  jmp    L4
L12:
  test   %al,%al
  je     L15
L48:
  lea    -0x1(%rbx),%rax
L4:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    $0x0,%eax
  jmp    L4
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *(strnpcbrk)(const char *string, const char *skipset, size_t maxlen) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256 * sizeof(char));
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  while (maxlen-- && ((c = *s++)))
    if (set[(size_t)c])
      break;
  return c ? (s - 1) : NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnpcbrk>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x100,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movsbq (%r12),%rax
  lea    0x1(%r12),%rdx
  test   %al,%al
  je     L53
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rdx
  movb   $0x1,(%rsp,%rax,1)
  movsbq -0x1(%rdx),%rax
  test   %al,%al
  jne    L4
L53:
  lea    (%rbx,%rbp,1),%rsi
  xor    %eax,%eax
  jmp    L42
  nopl   0x0(%rax)
L24:
  movzbl (%rbx),%eax
  lea    0x1(%rbx),%rdx
  test   %al,%al
  je     L14
  movsbq %al,%rcx
  cmpb   $0x0,(%rsp,%rcx,1)
  jne    L55
  mov    %rdx,%rbx
L42:
  cmp    %rsi,%rbx
  jne    L24
  test   %al,%al
  je     L14
  lea    -0x1(%rbx),%rax
L61:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  jmp    L61
  nopl   0x0(%rax)
L55:
  mov    %rbx,%rax
  jmp    L61
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *(strnpcbrk)(const char *string, const char *skipset, size_t maxlen) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256 * sizeof(char));
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  while (maxlen-- && ((c = *s++)))
    if (set[(size_t)c])
      break;
  return c ? (s - 1) : NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strnpcbrk>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x100,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movsbq (%r12),%rax
  lea    0x1(%r12),%rdx
  test   %al,%al
  je     L70
  nopl   0x0(%rax,%rax,1)
L85:
  add    $0x1,%rdx
  movb   $0x1,(%rsp,%rax,1)
  movsbq -0x1(%rdx),%rax
  test   %al,%al
  jne    L85
L70:
  lea    (%rbx,%rbp,1),%rsi
  xor    %eax,%eax
  jmp    L1
  nopl   0x0(%rax)
L89:
  movzbl (%rbx),%eax
  lea    0x1(%rbx),%rdx
  test   %al,%al
  je     L75
  movsbq %al,%rcx
  cmpb   $0x0,(%rsp,%rcx,1)
  jne    L35
  mov    %rdx,%rbx
L1:
  cmp    %rsi,%rbx
  jne    L89
  test   %al,%al
  je     L75
  lea    -0x1(%rbx),%rax
L18:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L75:
  xor    %eax,%eax
  jmp    L18
  nopl   0x0(%rax)
L35:
  mov    %rbx,%rax
  jmp    L18
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *(strnpcbrk)(const char *string, const char *skipset, size_t maxlen) {
  char set[256];
  char c;
  const char *s = string;
  memset(set, 0, 256 * sizeof(char));
  while ((c = *skipset++))
    set[(size_t)c] = 1;
  while (maxlen-- && ((c = *s++)))
    if (set[(size_t)c])
      break;
  return c ? (s - 1) : NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<countdigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x1,-0x1(%rbp)
  jmp    L19
L17:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char countdigits(unsigned long n) {
  unsigned char d;
  for (d = 1; n /= 10; d++)
    ;
  return d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<countdigits>:
  endbr64
  movabs $0xcccccccccccccccd,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x3,%rdx
  cmp    $0x9,%rdi
  jbe    L4
  mov    $0x1,%ecx
  movabs $0xcccccccccccccccd,%rdi
L29:
  add    $0x1,%ecx
  mov    %rdx,%rsi
  mov    %rdx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  cmp    $0x9,%rsi
  ja     L29
L0:
  mov    %ecx,%eax
  ret
L4:
  mov    $0x1,%ecx
  jmp    L0
```

assistant: ```c
unsigned char countdigits(unsigned long n) {
  unsigned char d;
  for (d = 1; n /= 10; d++)
    ;
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<countdigits>:
  endbr64
  movabs $0xcccccccccccccccd,%rsi
  mov    %rdi,%rax
  mov    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rdi
  jbe    L1
  nopl   0x0(%rax)
L14:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  ja     L14
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char countdigits(unsigned long n) {
  unsigned char d;
  for (d = 1; n /= 10; d++)
    ;
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<countdigits>:
  endbr64
  movabs $0xcccccccccccccccd,%rsi
  mov    %rdi,%rax
  mov    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rdi
  jbe    L12
  nopl   0x0(%rax)
L14:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  ja     L14
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char countdigits(unsigned long n) {
  unsigned char d;
  for (d = 1; n /= 10; d++)
    ;
  return d;
}
```