ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<b>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  lea    0x48(%rsp),%rax
  mov    %rax,0x18(%rsp)
L25:
  lea    0x50(%rsp),%r15
  lea    0x78(%rsp),%rax
  mov    %rax,0x10(%rsp)
L39:
  lea    0x80(%rsp),%r13
  lea    0xa8(%rsp),%rax
  mov    %rax,0x8(%rsp)
L45:
  lea    0xb0(%rsp),%rbp
  lea    0xd8(%rsp),%rax
  mov    %rax,(%rsp)
L13:
  lea    0xe0(%rsp),%rbx
  lea    0x108(%rsp),%r12
L0:
  mov    $0x2,%edx
  lea    D7(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    (%r15),%edi
  add    (%r14),%edi
  add    0x0(%r13),%edi
  add    0x0(%rbp),%edi
  add    (%rbx),%edi
  call   <c@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L0
  add    $0x4,%rbp
  cmp    (%rsp),%rbp
  jne    L13
  add    $0x4,%r13
  cmp    0x8(%rsp),%r13
  jne    L45
  add    $0x4,%r15
  cmp    0x10(%rsp),%r15
  jne    L39
  add    $0x4,%r14
  cmp    0x18(%rsp),%r14
  jne    L25
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string

tool: D7: B


assistant: ```c
void b(int x) {
  size_t pi, qi, ri, si, ti;
  int p[10], q[10], r[10], s[10], t[10];
  for (pi = 0; pi < 10; pi += 1)
    for (qi = 0; qi < 10; qi += 1)
      for (ri = 0; ri < 10; ri += 1)
        for (si = 0; si < 10; si += 1)
          for (ti = 0; ti < 10; ti += 1) {
            write(1, "B\n", 2);
            c(p[pi] + q[qi] + r[ri] + s[si] + t[ti]);
          }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<b>:
  endbr64
  push   %r15
  lea    D5(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  lea    0x78(%rsp),%rax
  lea    0x50(%rsp),%r13
  mov    %rax,0x30(%rsp)
  lea    0x110(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x138(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0xe0(%rsp),%rax
  mov    %rax,0x28(%rsp)
  lea    0x108(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    0xb0(%rsp),%rax
  mov    %rax,0x48(%rsp)
  lea    0xd8(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    0x80(%rsp),%rax
  mov    %rax,0x40(%rsp)
  lea    0xa8(%rsp),%rax
  mov    %rax,0x38(%rsp)
L53:
  mov    0x40(%rsp),%r14
L52:
  mov    0x48(%rsp),%r12
L25:
  mov    0x28(%rsp),%rbp
  nopl   (%rax)
L23:
  mov    0x10(%rsp),%rbx
  nopl   (%rax)
L12:
  mov    $0x2,%edx
  mov    %r15,%rsi
  mov    $0x1,%edi
  add    $0x4,%rbx
  call   <write@plt>
  mov    (%r14),%edi
  add    0x0(%r13),%edi
  add    (%r12),%edi
  add    0x0(%rbp),%edi
  add    -0x4(%rbx),%edi
  call   <c@plt>
  cmp    0x8(%rsp),%rbx
  jne    L12
  add    $0x4,%rbp
  cmp    0x18(%rsp),%rbp
  jne    L23
  add    $0x4,%r12
  cmp    0x20(%rsp),%r12
  jne    L25
  add    $0x4,%r14
  cmp    0x38(%rsp),%r14
  jne    L52
  add    $0x4,%r13
  cmp    0x30(%rsp),%r13
  jne    L53
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x148,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: B


assistant: ```c
void b(int x) {
  size_t pi, qi, ri, si, ti;
  int p[10], q[10], r[10], s[10], t[10];
  for (pi = 0; pi < 10; pi += 1)
    for (qi = 0; qi < 10; qi += 1)
      for (ri = 0; ri < 10; ri += 1)
        for (si = 0; si < 10; si += 1)
          for (ti = 0; ti < 10; ti += 1) {
            write(1, "B\n", 2);
            c(p[pi] + q[qi] + r[ri] + s[si] + t[ti]);
          }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<b>:
  endbr64
  push   %r15
  lea    D4(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  lea    0x78(%rsp),%rax
  lea    0x50(%rsp),%r13
  mov    %rax,0x30(%rsp)
  lea    0x110(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x138(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0xe0(%rsp),%rax
  mov    %rax,0x28(%rsp)
  lea    0x108(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    0xb0(%rsp),%rax
  mov    %rax,0x48(%rsp)
  lea    0xd8(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    0x80(%rsp),%rax
  mov    %rax,0x40(%rsp)
  lea    0xa8(%rsp),%rax
  mov    %rax,0x38(%rsp)
L38:
  mov    0x40(%rsp),%r14
L51:
  mov    0x48(%rsp),%r12
L29:
  mov    0x28(%rsp),%rbp
  nopl   (%rax)
L50:
  mov    0x10(%rsp),%rbx
  nopl   (%rax)
L21:
  mov    $0x2,%edx
  mov    %r15,%rsi
  mov    $0x1,%edi
  add    $0x4,%rbx
  call   <write@plt>
  mov    (%r14),%edi
  add    0x0(%r13),%edi
  add    (%r12),%edi
  add    0x0(%rbp),%edi
  add    -0x4(%rbx),%edi
  call   <c@plt>
  cmp    0x8(%rsp),%rbx
  jne    L21
  add    $0x4,%rbp
  cmp    0x18(%rsp),%rbp
  jne    L50
  add    $0x4,%r12
  cmp    0x20(%rsp),%r12
  jne    L29
  add    $0x4,%r14
  cmp    0x38(%rsp),%r14
  jne    L51
  add    $0x4,%r13
  cmp    0x30(%rsp),%r13
  jne    L38
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x148,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: B


assistant: ```c
void b(int x) {
  size_t pi, qi, ri, si, ti;
  int p[10], q[10], r[10], s[10], t[10];
  for (pi = 0; pi < 10; pi += 1)
    for (qi = 0; qi < 10; qi += 1)
      for (ri = 0; ri < 10; ri += 1)
        for (si = 0; si < 10; si += 1)
          for (ti = 0; ti < 10; ti += 1) {
            write(1, "B\n", 2);
            c(p[pi] + q[qi] + r[ri] + s[si] + t[ti]);
          }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
L52:
  mov    $0x0,%eax
  call   <c40_getchar@plt>
  cmp    $0x31,%eax
  je     L34
  cmp    $0x32,%eax
  je     L24
  jmp    L47
L34:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  mov    $0x28,%eax
  jmp    L14
L24:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  mov    $0x32,%eax
  jmp    L14
L47:
  mov    $0x7,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  jmp    L52
L14:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D40
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D42
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D55
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string

tool: D40: 



tool: D42: 1) 40 MHz
2) 50 MHz


tool: D55: Selection => 

tool: D17: 


tool: D25: %c

assistant: ```c
unsigned long get_clock(void) {
  c40_printf("\n\n");
  c40_printf("1) 40 MHz\n2) 50 MHz\n");
  c40_printf("Selection => ");
  while (1) {
    switch (c40_getchar()) {
    case '1':
      c40_printf("\n");
      return ((unsigned long)40);
    case '2':
      c40_printf("\n");
      return ((unsigned long)50);
    default:
      c40_printf("%c", 7);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_clock>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  lea    D23(%rip),%rbx
L9:
  mov    $0x0,%eax
  call   <c40_getchar@plt>
  cmp    $0x31,%eax
  je     L3
  cmp    $0x32,%eax
  je     L17
  mov    $0x7,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  jmp    L9
L3:
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  mov    $0x28,%eax
L37:
  pop    %rbx
  ret
L17:
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <c40_printf@plt>
  mov    $0x32,%eax
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D23
datatype: string
name: disassemble_data
arguments: data_tag: D16
datatype: string

tool: D2: 



tool: D1: 1) 40 MHz
2) 50 MHz


tool: D12: Selection => 

tool: D23: %c

tool: D16: 


assistant: ```c
unsigned long get_clock(void) {
  c40_printf("\n\n");
  c40_printf("1) 40 MHz\n2) 50 MHz\n");
  c40_printf("Selection => ");
  while (1) {
    switch (c40_getchar()) {
    case '1':
      c40_printf("\n");
      return ((unsigned long)40);
    case '2':
      c40_printf("\n");
      return ((unsigned long)50);
    default:
      c40_printf("%c", 7);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_clock>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  lea    D0(%rip),%rbx
  call   <c40_printf@plt>
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <c40_printf@plt>
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <c40_printf@plt>
  xor    %eax,%eax
  call   <c40_getchar@plt>
  cmp    $0x31,%eax
  je     L2
L18:
  cmp    $0x32,%eax
  je     L23
  xor    %eax,%eax
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <c40_printf@plt>
  xor    %eax,%eax
  call   <c40_getchar@plt>
  cmp    $0x31,%eax
  jne    L18
L2:
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <c40_printf@plt>
  mov    $0x28,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <c40_printf@plt>
  mov    $0x32,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string
name: read_data
arguments: tag: D49
type_guessed: string
name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D57
type_guessed: string

tool: D8: 



tool: D0: %c

tool: D49: 1) 40 MHz
2) 50 MHz


tool: D23: Selection => 

tool: D57: 


assistant: ```c
unsigned long get_clock(void) {
  c40_printf("\n\n");
  c40_printf("1) 40 MHz\n2) 50 MHz\n");
  c40_printf("Selection => ");
  while (1) {
    switch (c40_getchar()) {
    case '1':
      c40_printf("\n");
      return ((unsigned long)40);
    case '2':
      c40_printf("\n");
      return ((unsigned long)50);
    default:
      c40_printf("%c", 7);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_clock>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  lea    D59(%rip),%rbx
  call   <c40_printf@plt>
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <c40_printf@plt>
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <c40_printf@plt>
  xor    %eax,%eax
  call   <c40_getchar@plt>
  cmp    $0x31,%eax
  je     L27
L0:
  cmp    $0x32,%eax
  je     L26
  xor    %eax,%eax
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <c40_printf@plt>
  xor    %eax,%eax
  call   <c40_getchar@plt>
  cmp    $0x31,%eax
  jne    L0
L27:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <c40_printf@plt>
  mov    $0x28,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <c40_printf@plt>
  mov    $0x32,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D12
data_type: string
name: read_data
arguments: tag: D59
data_type: string
name: read_data
arguments: tag: D40
data_type: string
name: read_data
arguments: tag: D58
data_type: string
name: read_data
arguments: tag: D24
data_type: string

tool: D12: 



tool: D59: %c

tool: D40: 1) 40 MHz
2) 50 MHz


tool: D58: Selection => 

tool: D24: 


assistant: ```c
unsigned long get_clock(void) {
  c40_printf("\n\n");
  c40_printf("1) 40 MHz\n2) 50 MHz\n");
  c40_printf("Selection => ");
  while (1) {
    switch (c40_getchar()) {
    case '1':
      c40_printf("\n");
      return ((unsigned long)40);
    case '2':
      c40_printf("\n");
      return ((unsigned long)50);
    default:
      c40_printf("%c", 7);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ModelicaIO_transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x1,-0x20(%rbp)
  jmp    L34
L71:
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  mov    %rdx,%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  add    %rcx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L85
  jmp    L57
L89:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  mov    %rdx,%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  add    %rcx,%rax
  mov    %rax,-0x18(%rbp)
L57:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L89
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L12
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  mov    %rdx,%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  add    %rcx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L0
L9:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  mov    %rdx,%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  add    %rcx,%rax
  mov    %rax,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L9
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L15
L85:
  nop
  jmp    L15
L12:
  nop
L15:
  addq   $0x1,-0x20(%rbp)
L34:
  mov    -0x30(%rbp),%rax
  imul   -0x38(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x20(%rbp)
  jb     L71
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ModelicaIO_transpose(double *table, size_t nRow, size_t nCol) {
  size_t i;
  for (i = 1; i < nRow * nCol - 1; i++) {
    size_t x = nRow * (i % nCol) + i / nCol;
    if (x <= i) {
      continue;
    }
    while (x > i) {
      x = nRow * (x % nCol) + x / nCol;
    }
    if (x < i) {
      continue;
    }
    {
      double tmp = table[i];
      size_t s = i;
      x = nRow * (i % nCol) + i / nCol;
      while (x != i) {
        table[s] = table[x];
        s = x;
        x = nRow * (x % nCol) + x / nCol;
      }
      table[s] = tmp;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ModelicaIO_transpose>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rdx,%rsi
  mov    %r8,%r10
  imul   %rdx,%r10
  sub    $0x1,%r10
  cmp    $0x1,%r10
  jbe    L25
  mov    $0x1,%edi
  jmp    L27
L58:
  mov    %rdx,%rcx
L39:
  lea    (%r9,%rcx,8),%r11
  movsd  (%r11),%xmm0
  movsd  %xmm0,(%r9,%rax,8)
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  imul   %r8,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  cmp    %rdi,%rdx
  jne    L58
  movsd  %xmm1,(%r11)
L50:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  je     L25
L27:
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rsi
  imul   %r8,%rdx
  lea    (%rdx,%rax,1),%rcx
  cmp    %rdi,%rcx
  jbe    L50
  mov    %rcx,%rax
L45:
  mov    $0x0,%edx
  div    %rsi
  imul   %r8,%rdx
  add    %rdx,%rax
  cmp    %rdi,%rax
  ja     L45
  jb     L50
  movsd  (%r9,%rdi,8),%xmm1
  mov    %rdi,%rax
  jmp    L39
L25:
  ret
```

assistant: ```c
void ModelicaIO_transpose(double *table, size_t nRow, size_t nCol) {
  size_t i;
  for (i = 1; i < nRow * nCol - 1; i++) {
    size_t x = nRow * (i % nCol) + i / nCol;
    if (x <= i) {
      continue;
    }
    while (x > i) {
      x = nRow * (x % nCol) + x / nCol;
    }
    if (x < i) {
      continue;
    }
    {
      double tmp = table[i];
      size_t s = i;
      x = nRow * (i % nCol) + i / nCol;
      while (x != i) {
        table[s] = table[x];
        s = x;
        x = nRow * (x % nCol) + x / nCol;
      }
      table[s] = tmp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ModelicaIO_transpose>:
  endbr64
  mov    %rsi,%r8
  mov    %rdi,%r9
  mov    %rdx,%rsi
  mov    $0x1,%edi
  mov    %r8,%r10
  imul   %rdx,%r10
  sub    $0x1,%r10
  cmp    $0x1,%r10
  ja     L30
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  je     L53
L30:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rsi
  imul   %r8,%rdx
  lea    (%rdx,%rax,1),%rcx
  cmp    %rdi,%rcx
  jbe    L12
  mov    %rcx,%rax
  nopl   0x0(%rax)
L33:
  xor    %edx,%edx
  div    %rsi
  imul   %r8,%rdx
  add    %rdx,%rax
  cmp    %rdi,%rax
  ja     L33
  jb     L12
  movsd  (%r9,%rdi,8),%xmm1
  mov    %rdi,%rax
  jmp    L47
  cs nopw 0x0(%rax,%rax,1)
L76:
  mov    %rdx,%rcx
L47:
  lea    (%r9,%rcx,8),%r11
  xor    %edx,%edx
  movsd  (%r11),%xmm0
  movsd  %xmm0,(%r9,%rax,8)
  mov    %rcx,%rax
  div    %rsi
  imul   %r8,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  cmp    %rdi,%rdx
  jne    L76
  add    $0x1,%rdi
  movsd  %xmm1,(%r11)
  cmp    %r10,%rdi
  jne    L30
L53:
  ret
```

assistant: ```c
void ModelicaIO_transpose(double *table, size_t nRow, size_t nCol) {
  size_t i;
  for (i = 1; i < nRow * nCol - 1; i++) {
    size_t x = nRow * (i % nCol) + i / nCol;
    if (x <= i) {
      continue;
    }
    while (x > i) {
      x = nRow * (x % nCol) + x / nCol;
    }
    if (x < i) {
      continue;
    }
    {
      double tmp = table[i];
      size_t s = i;
      x = nRow * (i % nCol) + i / nCol;
      while (x != i) {
        table[s] = table[x];
        s = x;
        x = nRow * (x % nCol) + x / nCol;
      }
      table[s] = tmp;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ModelicaIO_transpose>:
  endbr64
  mov    %rsi,%r8
  mov    %rdi,%r9
  mov    %rdx,%rsi
  mov    $0x1,%edi
  mov    %r8,%r10
  imul   %rdx,%r10
  sub    $0x1,%r10
  cmp    $0x1,%r10
  ja     L49
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L59:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  je     L0
L49:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rsi
  imul   %r8,%rdx
  lea    (%rdx,%rax,1),%rcx
  cmp    %rdi,%rcx
  jbe    L59
  mov    %rcx,%rax
  nopl   0x0(%rax)
L69:
  xor    %edx,%edx
  div    %rsi
  imul   %r8,%rdx
  add    %rdx,%rax
  cmp    %rdi,%rax
  ja     L69
  jb     L59
  movsd  (%r9,%rdi,8),%xmm1
  mov    %rdi,%rax
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L81:
  mov    %rdx,%rcx
L21:
  lea    (%r9,%rcx,8),%r11
  xor    %edx,%edx
  movsd  (%r11),%xmm0
  movsd  %xmm0,(%r9,%rax,8)
  mov    %rcx,%rax
  div    %rsi
  imul   %r8,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  cmp    %rdi,%rdx
  jne    L81
  add    $0x1,%rdi
  movsd  %xmm1,(%r11)
  cmp    %r10,%rdi
  jne    L49
L0:
  ret
```

assistant: ```c
void ModelicaIO_transpose(double *table, size_t nRow, size_t nCol) {
  size_t i;
  for (i = 1; i < nRow * nCol - 1; i++) {
    size_t x = nRow * (i % nCol) + i / nCol;
    if (x <= i) {
      continue;
    }
    while (x > i) {
      x = nRow * (x % nCol) + x / nCol;
    }
    if (x < i) {
      continue;
    }
    {
      double tmp = table[i];
      size_t s = i;
      x = nRow * (i % nCol) + i / nCol;
      while (x != i) {
        table[s] = table[x];
        s = x;
        x = nRow * (x % nCol) + x / nCol;
      }
      table[s] = tmp;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0x2cdb,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  shr    $0xb,%ax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  shl    $0x5,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local2] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)11) | (state[0UL] << (unsigned short)5);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x2cdb,%ax
  rol    $0x5,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local2] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)11) | (state[0UL] << (unsigned short)5);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x2cdb,%ax
  rol    $0x5,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local2] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)11) | (state[0UL] << (unsigned short)5);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x2cdb,%ax
  rol    $0x5,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local2] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)11) | (state[0UL] << (unsigned short)5);
  }
}
```