ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<sqrt8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D11(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L9
L0:
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  D11(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L9:
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L0
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L0
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
datatype: f64

tool: D11: 2

assistant: ```c
double sqrt8(const double fg) {
  double n = fg / 2.0;
  double lstX = 0.0;
  while (n != lstX) {
    lstX = n;
    n = (n + fg / n) / 2.0;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqrt8>:
  endbr64
  movapd %xmm0,%xmm1
  mulsd  D25(%rip),%xmm1
  ucomisd D23(%rip),%xmm1
  jp     L25
  je     L22
L25:
  movsd  D25(%rip),%xmm4
L29:
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm1,%xmm3
  movapd %xmm2,%xmm1
  mulsd  %xmm4,%xmm1
  ucomisd %xmm3,%xmm1
  jp     L29
  jne    L29
L22:
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D25
type: f32[2]
name: disassemble_data
arguments: tag: D23
type: f32[2]

tool: {"D25": [0.0,1.75]}

tool: {"D23": [0.0,0.0]}

assistant: ```c
double sqrt8(const double fg) {
  double n = fg / 2.0;
  double lstX = 0.0;
  while (n != lstX) {
    lstX = n;
    n = (n + fg / n) / 2.0;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sqrt8>:
  endbr64
  movsd  D10(%rip),%xmm4
  movapd %xmm0,%xmm3
  mulsd  %xmm4,%xmm0
  ucomisd D1(%rip),%xmm0
  jp     L37
  je     L10
L37:
  movapd %xmm3,%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm4,%xmm0
  ucomisd %xmm2,%xmm0
  jp     L37
  jne    L37
L10:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: f32[2]
name: parse_data
arguments: data_label: D1
type_infered: f32[2]

tool: {"D10": [0.0,1.75]}

tool: {"D1": [0.0,0.0]}

assistant: ```c
double sqrt8(const double fg) {
  double n = fg / 2.0;
  double lstX = 0.0;
  while (n != lstX) {
    lstX = n;
    n = (n + fg / n) / 2.0;
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sqrt8>:
  endbr64
  movsd  D0(%rip),%xmm4
  movapd %xmm0,%xmm3
  mulsd  %xmm4,%xmm0
  ucomisd D9(%rip),%xmm0
  jp     L19
  je     L10
L19:
  movapd %xmm3,%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm4,%xmm0
  ucomisd %xmm2,%xmm0
  jp     L19
  jne    L19
L10:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: f32[2]
name: parse_data
arguments: data_tag: D9
type: f32[2]

tool: {"D0": [0.0,1.75]}

tool: {"D9": [0.0,0.0]}

assistant: ```c
double sqrt8(const double fg) {
  double n = fg / 2.0;
  double lstX = 0.0;
  while (n != lstX) {
    lstX = n;
    n = (n + fg / n) / 2.0;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L37
L3:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jg     L3
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L1
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L31
L1:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D30
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D19
type_infered: string
name: unpack_data
arguments: label: D6
type_infered: string

tool: D30: %d

tool: D9:  %d

tool: D19: Acertou


tool: D6: Errou


assistant: ```c
int main() {
  int N, soma = 0, X, pp;
  scanf("%d", &N);
  while (N > 0) {
    scanf(" %d", &X);
    soma += X;
    N--;
  }
  scanf(" %d", &pp);
  pp == soma ? printf("Acertou\n") : printf("Errou\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L58
  mov    $0x0,%ebx
  lea    D40(%rip),%rbp
L42:
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    0x10(%rsp),%ebx
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jg     L42
L34:
  lea    0x14(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  cmp    %ebx,0x14(%rsp)
  je     L39
  lea    D16(%rip),%rdi
  call   <printf@plt>
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L58:
  mov    $0x0,%ebx
  jmp    L34
L39:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L38
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D40
datatype: string
name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D31
datatype: string

tool: D6: %d

tool: D40:  %d

tool: D16: Errou


tool: D31: Acertou


assistant: ```c
int main() {
  int N, soma = 0, X, pp;
  scanf("%d", &N);
  while (N > 0) {
    scanf(" %d", &X);
    soma += X;
    N--;
  }
  scanf(" %d", &pp);
  pp == soma ? printf("Acertou\n") : printf("Errou\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%rdi
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L5
  lea    0x10(%rsp),%r12
  lea    D24(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  add    0x10(%rsp),%ebx
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jg     L45
L5:
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x14(%rsp)
  je     L47
  lea    D43(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string
name: parse_data
arguments: data_tag: D43
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string

tool: D19: %d

tool: D24:  %d

tool: D43: Errou


tool: D0: Acertou


assistant: ```c
int main() {
  int N, soma = 0, X, pp;
  scanf("%d", &N);
  while (N > 0) {
    scanf(" %d", &X);
    soma += X;
    N--;
  }
  scanf(" %d", &pp);
  pp == soma ? printf("Acertou\n") : printf("Errou\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D42(%rip),%rdi
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L15
  lea    0x10(%rsp),%r12
  lea    D25(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  add    0x10(%rsp),%ebx
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jg     L14
L15:
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x14(%rsp)
  je     L8
  lea    D15(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D42
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string
name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string

tool: D42: %d

tool: D25:  %d

tool: D15: Errou


tool: D0: Acertou


assistant: ```c
int main() {
  int N, soma = 0, X, pp;
  scanf("%d", &N);
  while (N > 0) {
    scanf(" %d", &X);
    soma += X;
    N--;
  }
  scanf(" %d", &pp);
  pp == soma ? printf("Acertou\n") : printf("Errou\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<checkCols>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L99
L87:
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L82:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getPosInCol@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x3f,%eax
  test   %eax,%eax
  jne    L84
  mov    -0x4(%rbp),%eax
  and    $0xffffffc0,%eax
  test   %eax,%eax
  je     L84
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <maskBoxExceptCol@plt>
  or     %eax,-0x8(%rbp)
  jmp    L112
L84:
  mov    -0x4(%rbp),%eax
  and    $0x1c7,%eax
  test   %eax,%eax
  jne    L40
  mov    -0x4(%rbp),%eax
  and    $0xfffffe38,%eax
  test   %eax,%eax
  je     L40
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <maskBoxExceptCol@plt>
  or     %eax,-0x8(%rbp)
  jmp    L112
L40:
  mov    -0x4(%rbp),%eax
  and    $0x1f8,%eax
  test   %eax,%eax
  jne    L112
  mov    -0x4(%rbp),%eax
  and    $0xfffffe07,%eax
  test   %eax,%eax
  je     L112
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    %rax,%rdi
  call   <maskBoxExceptCol@plt>
  or     %eax,-0x8(%rbp)
L112:
  addl   $0x1,-0xc(%rbp)
L11:
  cmpl   $0x8,-0xc(%rbp)
  jle    L82
  addl   $0x1,-0x10(%rbp)
L99:
  cmpl   $0x8,-0x10(%rbp)
  jle    L87
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int checkCols(struct Board *board) {
  int col, val, change;
  unsigned int pos;
  change = 0;
  for (col = 0; col < 9; col++) {
    for (val = 0; val < 9; val++) {
      pos = getPosInCol(board, val, col);
      if (!(pos & 0x3F) && (pos & ~0x3F)) {
        change |= maskBoxExceptCol(board, col, 0, ~(1 << val));
      } else if (!(pos & 0x1C7) && (pos & ~0x1C7)) {
        change |= maskBoxExceptCol(board, col, 1, ~(1 << val));
      } else if (!(pos & 0x1F8) && (pos & ~0x1F8)) {
        change |= maskBoxExceptCol(board, col, 2, ~(1 << val));
      }
    }
  }
  return change;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<checkCols>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  mov    $0x1,%r14d
  jmp    L86
L100:
  mov    %r14d,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  not    %ecx
  mov    $0x0,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <maskBoxExceptCol@plt>
  or     %eax,%r13d
L41:
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  je     L57
L65:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <getPosInCol@plt>
  test   $0x3f,%al
  jne    L61
  test   $0xffffffc0,%eax
  jne    L100
L61:
  test   $0x1c7,%eax
  jne    L16
  test   $0xfffffe38,%eax
  jne    L29
L16:
  test   $0x1f8,%eax
  jne    L41
  test   $0xfffffe07,%eax
  je     L41
  mov    %r14d,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  not    %ecx
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <maskBoxExceptCol@plt>
  or     %eax,%r13d
  jmp    L41
L29:
  mov    %r14d,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  not    %ecx
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <maskBoxExceptCol@plt>
  or     %eax,%r13d
  jmp    L41
L57:
  add    $0x1,%ebp
  cmp    $0x9,%ebp
  je     L83
L86:
  mov    $0x0,%ebx
  jmp    L65
L83:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int checkCols(struct Board *board) {
  int col, val, change;
  unsigned int pos;
  change = 0;
  for (col = 0; col < 9; col++) {
    for (val = 0; val < 9; val++) {
      pos = getPosInCol(board, val, col);
      if (!(pos & 0x3F) && (pos & ~0x3F)) {
        change |= maskBoxExceptCol(board, col, 0, ~(1 << val));
      } else if (!(pos & 0x1C7) && (pos & ~0x1C7)) {
        change |= maskBoxExceptCol(board, col, 1, ~(1 << val));
      } else if (!(pos & 0x1F8) && (pos & ~0x1F8)) {
        change |= maskBoxExceptCol(board, col, 2, ~(1 << val));
      }
    }
  }
  return change;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<checkCols>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L46:
  xor    %r14d,%r14d
  jmp    L80
  nopl   (%rax)
L18:
  test   $0x1c7,%eax
  jne    L92
  test   $0xfffffe38,%eax
  jne    L37
L92:
  test   $0x1f8,%eax
  jne    L41
  test   $0xfffffe07,%eax
  jne    L5
L41:
  add    $0x1,%r14d
  cmp    $0x9,%r14d
  je     L22
L80:
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <getPosInCol@plt>
  test   $0x3f,%al
  jne    L18
  test   $0xffffffc0,%eax
  je     L18
  mov    %r14d,%ecx
  mov    %r13d,%eax
  xor    %edx,%edx
  mov    %ebx,%esi
  shl    %cl,%eax
  mov    %rbp,%rdi
  add    $0x1,%r14d
  mov    %eax,%ecx
  not    %ecx
  call   <maskBoxExceptCol@plt>
  or     %eax,%r12d
  cmp    $0x9,%r14d
  jne    L80
  nop
L22:
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L46
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L37:
  mov    %r14d,%ecx
  mov    %r13d,%eax
  mov    $0x1,%edx
  mov    %ebx,%esi
  shl    %cl,%eax
  mov    %rbp,%rdi
  mov    %eax,%ecx
  not    %ecx
  call   <maskBoxExceptCol@plt>
  or     %eax,%r12d
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r14d,%ecx
  mov    %r13d,%eax
  mov    $0x2,%edx
  mov    %ebx,%esi
  shl    %cl,%eax
  mov    %rbp,%rdi
  mov    %eax,%ecx
  not    %ecx
  call   <maskBoxExceptCol@plt>
  or     %eax,%r12d
  jmp    L41
```

assistant: ```c
int checkCols(struct Board *board) {
  int col, val, change;
  unsigned int pos;
  change = 0;
  for (col = 0; col < 9; col++) {
    for (val = 0; val < 9; val++) {
      pos = getPosInCol(board, val, col);
      if (!(pos & 0x3F) && (pos & ~0x3F)) {
        change |= maskBoxExceptCol(board, col, 0, ~(1 << val));
      } else if (!(pos & 0x1C7) && (pos & ~0x1C7)) {
        change |= maskBoxExceptCol(board, col, 1, ~(1 << val));
      } else if (!(pos & 0x1F8) && (pos & ~0x1F8)) {
        change |= maskBoxExceptCol(board, col, 2, ~(1 << val));
      }
    }
  }
  return change;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkCols>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L72:
  xor    %r14d,%r14d
  jmp    L85
  nopl   (%rax)
L51:
  test   $0x1c7,%eax
  jne    L62
  test   $0xfffffe38,%eax
  jne    L4
L62:
  test   $0x1f8,%eax
  jne    L8
  test   $0xfffffe07,%eax
  jne    L49
L8:
  add    $0x1,%r14d
  cmp    $0x9,%r14d
  je     L69
L85:
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <getPosInCol@plt>
  test   $0x3f,%al
  jne    L51
  test   $0xffffffc0,%eax
  je     L51
  mov    %r14d,%ecx
  mov    %r13d,%eax
  xor    %edx,%edx
  mov    %ebx,%esi
  shl    %cl,%eax
  mov    %rbp,%rdi
  add    $0x1,%r14d
  mov    %eax,%ecx
  not    %ecx
  call   <maskBoxExceptCol@plt>
  or     %eax,%r12d
  cmp    $0x9,%r14d
  jne    L85
  nop
L69:
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L72
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L4:
  mov    %r14d,%ecx
  mov    %r13d,%eax
  mov    $0x1,%edx
  mov    %ebx,%esi
  shl    %cl,%eax
  mov    %rbp,%rdi
  mov    %eax,%ecx
  not    %ecx
  call   <maskBoxExceptCol@plt>
  or     %eax,%r12d
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %r14d,%ecx
  mov    %r13d,%eax
  mov    $0x2,%edx
  mov    %ebx,%esi
  shl    %cl,%eax
  mov    %rbp,%rdi
  mov    %eax,%ecx
  not    %ecx
  call   <maskBoxExceptCol@plt>
  or     %eax,%r12d
  jmp    L8
```

assistant: ```c
int checkCols(struct Board *board) {
  int col, val, change;
  unsigned int pos;
  change = 0;
  for (col = 0; col < 9; col++) {
    for (val = 0; val < 9; val++) {
      pos = getPosInCol(board, val, col);
      if (!(pos & 0x3F) && (pos & ~0x3F)) {
        change |= maskBoxExceptCol(board, col, 0, ~(1 << val));
      } else if (!(pos & 0x1C7) && (pos & ~0x1C7)) {
        change |= maskBoxExceptCol(board, col, 1, ~(1 << val));
      } else if (!(pos & 0x1F8) && (pos & ~0x1F8)) {
        change |= maskBoxExceptCol(board, col, 2, ~(1 << val));
      }
    }
  }
  return change;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L3
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %ecx,%eax
  jmp    L4
L3:
  mov    -0x4(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int f(int u, int v) {
  if (v > 0)
    return 5 * u + 3 * v;
  return u;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jg     L1
L11:
  ret
L1:
  lea    (%rdi,%rdi,4),%eax
  lea    (%rsi,%rsi,2),%edx
  add    %edx,%eax
  jmp    L11
```

assistant: ```c
int f(int u, int v) {
  if (v > 0)
    return 5 * u + 3 * v;
  return u;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jg     L2
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  lea    (%rdi,%rdi,4),%eax
  lea    (%rsi,%rsi,2),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int f(int u, int v) {
  if (v > 0)
    return 5 * u + 3 * v;
  return u;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jg     L0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  lea    (%rdi,%rdi,4),%eax
  lea    (%rsi,%rsi,2),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int f(int u, int v) {
  if (v > 0)
    return 5 * u + 3 * v;
  return u;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x9,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x8,%edi
  call   <stdout_password@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3d,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x8,%edi
  call   <stdout_password@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5e,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x8,%edi
  call   <stdout_password@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D32
type_infered: string

tool: D0: Simple Password Generator - %d digits / 1 part


tool: D29: 0-9 			

tool: D15: 0-9 + a-z + A-Z 	

tool: D32: 0-9 + a-z + A-Z + sign 	

assistant: ```c
int main() {
  int rnd;
  int i, j;
  printf("Simple Password Generator - %d digits / 1 part\n", 8);
  srand((unsigned)time(NULL));
  printf("0-9 \t\t\t");
  stdout_password(8, 3, 0, 9);
  putchar('\n');
  printf("0-9 + a-z + A-Z \t");
  stdout_password(8, 3, 0, 61);
  putchar('\n');
  printf("0-9 + a-z + A-Z + sign \t");
  stdout_password(8, 3, 0, 94);
  putchar('\n');
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x9,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x8,%edi
  call   <stdout_password@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3d,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x8,%edi
  call   <stdout_password@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5e,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x8,%edi
  call   <stdout_password@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D26
type_guessed: string
name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D39
type_guessed: string

tool: D3: Simple Password Generator - %d digits / 1 part


tool: D26: 0-9 			

tool: D9: 0-9 + a-z + A-Z 	

tool: D39: 0-9 + a-z + A-Z + sign 	

assistant: ```c
int main() {
  int rnd;
  int i, j;
  printf("Simple Password Generator - %d digits / 1 part\n", 8);
  srand((unsigned)time(NULL));
  printf("0-9 \t\t\t");
  stdout_password(8, 3, 0, 9);
  putchar('\n');
  printf("0-9 + a-z + A-Z \t");
  stdout_password(8, 3, 0, 61);
  putchar('\n');
  printf("0-9 + a-z + A-Z + sign \t");
  stdout_password(8, 3, 0, 94);
  putchar('\n');
  return (0);
}
```