ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ccnl_ccnb_fillContent>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %r8,%rdi
  push   %r14
  mov    %rsi,%r14
  mov    $0x40,%esi
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edx,%r12d
  mov    $0x2,%edx
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ccnl_ccnb_mkHeader@plt>
  mov    %r15,%rdi
  movslq %eax,%rsi
  mov    %rsi,%rbx
  add    %rbp,%rsi
  call   <ccnl_ccnb_mkName@plt>
  mov    $0x2,%edx
  mov    $0x13,%esi
  add    %eax,%ebx
  movslq %ebx,%rdi
  add    %rbp,%rdi
  call   <ccnl_ccnb_mkHeader@plt>
  mov    $0x5,%edx
  mov    %r12d,%esi
  add    %eax,%ebx
  movslq %ebx,%rdi
  add    %rbp,%rdi
  call   <ccnl_ccnb_mkHeader@plt>
  add    %eax,%ebx
  test   %r13,%r13
  je     L7
  mov    %ebx,0x0(%r13)
  movslq %ebx,%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  add    %rbp,%rdi
  call   <memcpy@plt>
  mov    %ebx,0x0(%r13)
L13:
  add    %r12d,%ebx
  movslq %ebx,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  lea    0x1(%rbx),%eax
  cltq
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  lea    0x2(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  movslq %ebx,%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  add    %rbp,%rdi
  call   <memcpy@plt>
  jmp    L13
```

assistant: ```c
int ccnl_ccnb_fillContent(struct ccnl_prefix_s *name, unsigned char *data, int datalen, int *contentpos, unsigned char *out) {
  int len = 0;
  len = ccnl_ccnb_mkHeader(out, 64, 2);
  len += ccnl_ccnb_mkName(name, out + len);
  len += ccnl_ccnb_mkHeader(out + len, 19, 2);
  len += ccnl_ccnb_mkHeader(out + len, datalen, 5);
  if (contentpos)
    *contentpos = len;
  memcpy(out + len, data, datalen);
  if (contentpos)
    *contentpos = len;
  len += datalen;
  out[len++] = 0;
  out[len++] = 0;
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_time_remain>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r9
  cmp    $0x1517f,%rdi
  ja     L1
  mov    %rdi,%rdx
  shr    $0x4,%rdx
  movabs $0x91a2b3c4d5e6f81,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %edx,%esi
  imul   $0xe10,%edx,%ecx
  mov    %ecx,%eax
  mov    %rdi,%r8
  sub    %rax,%r8
  movabs $0x8888888888888889,%rdx
  mov    %r8,%rax
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%r8
  sub    %ecx,%r9d
  imul   $0x3c,%edx,%eax
  sub    %eax,%r9d
  mov    %esi,%ecx
  lea    D38(%rip),%rdx
  mov    $0x40,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
L17:
  lea    D26(%rip),%rax
  add    $0x8,%rsp
  ret
L1:
  movabs $0xc22e450672894ab7,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x10,%rdx
  mov    %edx,%esi
  imul   $0x15180,%edx,%edx
  mov    %edx,%edx
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  mov    %rcx,%rdx
  shr    $0x4,%rdx
  movabs $0x91a2b3c4d5e6f81,%rdi
  mov    %rdx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  mov    %rdx,%r8
  imul   $0xe10,%edx,%edi
  mov    %edi,%eax
  mov    %rcx,%r9
  sub    %rax,%r9
  movabs $0x8888888888888889,%rdx
  mov    %r9,%rax
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%r9
  sub    $0x8,%rsp
  sub    %edi,%ecx
  imul   $0x3c,%edx,%eax
  sub    %eax,%ecx
  push   %rcx
  mov    %esi,%ecx
  lea    D8(%rip),%rdx
  mov    $0x40,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    $0x10,%rsp
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: label: D38
type: string
name: extract_symbolic_data
arguments: label: D8
type: string

tool: D38: %02u:%02u:%02u

tool: D8: %u days %02u:%02u:%02u

assistant: ```c
char *get_time_remain(unsigned long remain_second) {
  unsigned int day, hour, min, second;
  static char str_time_remain[64];
  if (remain_second < 24 * 3600) {
    hour = remain_second / 3600;
    min = (remain_second - 3600 * hour) / 60;
    second = remain_second - hour * 3600 - min * 60;
    snprintf(str_time_remain, sizeof(str_time_remain), "%02u:%02u:%02u", hour, min, second);
  } else {
    day = remain_second / 24 / 3600;
    remain_second = remain_second - day * 24 * 3600;
    hour = remain_second / 3600;
    min = (remain_second - 3600 * hour) / 60;
    second = remain_second - hour * 3600 - min * 60;
    snprintf(str_time_remain, sizeof(str_time_remain), "%u days %02u:%02u:%02u", day, hour, min, second);
  }
  return str_time_remain;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_time_remain>:
  endbr64
  push   %r12
  mov    %rdi,%r9
  cmp    $0x1517f,%rdi
  ja     L5
  mov    %rdi,%rdx
  mov    %rdi,%r8
  movabs $0x91a2b3c4d5e6f81,%rcx
  mov    $0x40,%esi
  shr    $0x4,%rdx
  lea    D19(%rip),%r12
  mov    %rdx,%rax
  mov    %r12,%rdi
  mul    %rcx
  shr    $0x3,%rdx
  imul   $0xe10,%edx,%eax
  mov    %edx,%r10d
  movabs $0x8888888888888889,%rdx
  sub    %rax,%r8
  mov    %rax,%rcx
  mov    %r8,%rax
  sub    %ecx,%r9d
  mov    %r10d,%ecx
  mul    %rdx
  shr    $0x5,%rdx
  imul   $0x3c,%edx,%eax
  mov    %rdx,%r8
  lea    D9(%rip),%rdx
  sub    %eax,%r9d
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L5:
  mov    %rdi,%rax
  mov    %rdi,%rcx
  movabs $0xc22e450672894ab7,%rdx
  movabs $0x91a2b3c4d5e6f81,%rsi
  mul    %rdx
  sub    $0x8,%rsp
  lea    D19(%rip),%r12
  mov    %r12,%rdi
  shr    $0x10,%rdx
  mov    %edx,%r10d
  imul   $0x15180,%edx,%edx
  sub    %rdx,%rcx
  mov    %rcx,%rdx
  mov    %rcx,%r9
  shr    $0x4,%rdx
  mov    %rdx,%rax
  mul    %rsi
  shr    $0x3,%rdx
  imul   $0xe10,%edx,%eax
  mov    %rdx,%r8
  movabs $0x8888888888888889,%rdx
  sub    %rax,%r9
  mov    %rax,%rsi
  mov    %r9,%rax
  sub    %esi,%ecx
  mov    $0x40,%esi
  mul    %rdx
  shr    $0x5,%rdx
  imul   $0x3c,%edx,%eax
  mov    %rdx,%r9
  lea    D1(%rip),%rdx
  sub    %eax,%ecx
  xor    %eax,%eax
  push   %rcx
  mov    %r10d,%ecx
  call   <snprintf@plt>
  pop    %rax
  mov    %r12,%rax
  pop    %rdx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D9: %02u:%02u:%02u

tool: D1: %u days %02u:%02u:%02u

assistant: ```c
char *get_time_remain(unsigned long remain_second) {
  unsigned int day, hour, min, second;
  static char str_time_remain[64];
  if (remain_second < 24 * 3600) {
    hour = remain_second / 3600;
    min = (remain_second - 3600 * hour) / 60;
    second = remain_second - hour * 3600 - min * 60;
    snprintf(str_time_remain, sizeof(str_time_remain), "%02u:%02u:%02u", hour, min, second);
  } else {
    day = remain_second / 24 / 3600;
    remain_second = remain_second - day * 24 * 3600;
    hour = remain_second / 3600;
    min = (remain_second - 3600 * hour) / 60;
    second = remain_second - hour * 3600 - min * 60;
    snprintf(str_time_remain, sizeof(str_time_remain), "%u days %02u:%02u:%02u", day, hour, min, second);
  }
  return str_time_remain;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_time_remain>:
  endbr64
  push   %r12
  mov    %rdi,%r9
  cmp    $0x1517f,%rdi
  ja     L8
  mov    %rdi,%rdx
  mov    %rdi,%r8
  movabs $0x91a2b3c4d5e6f81,%rcx
  mov    $0x40,%esi
  shr    $0x4,%rdx
  lea    D28(%rip),%r12
  mov    %rdx,%rax
  mov    %r12,%rdi
  mul    %rcx
  shr    $0x3,%rdx
  imul   $0xe10,%edx,%eax
  mov    %edx,%r10d
  movabs $0x8888888888888889,%rdx
  sub    %rax,%r8
  mov    %rax,%rcx
  mov    %r8,%rax
  sub    %ecx,%r9d
  mov    %r10d,%ecx
  mul    %rdx
  shr    $0x5,%rdx
  imul   $0x3c,%edx,%eax
  mov    %rdx,%r8
  lea    D9(%rip),%rdx
  sub    %eax,%r9d
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L8:
  mov    %rdi,%rax
  mov    %rdi,%rcx
  movabs $0xc22e450672894ab7,%rdx
  movabs $0x91a2b3c4d5e6f81,%rsi
  mul    %rdx
  sub    $0x8,%rsp
  lea    D28(%rip),%r12
  mov    %r12,%rdi
  shr    $0x10,%rdx
  mov    %edx,%r10d
  imul   $0x15180,%edx,%edx
  sub    %rdx,%rcx
  mov    %rcx,%rdx
  mov    %rcx,%r9
  shr    $0x4,%rdx
  mov    %rdx,%rax
  mul    %rsi
  shr    $0x3,%rdx
  imul   $0xe10,%edx,%eax
  mov    %rdx,%r8
  movabs $0x8888888888888889,%rdx
  sub    %rax,%r9
  mov    %rax,%rsi
  mov    %r9,%rax
  sub    %esi,%ecx
  mov    $0x40,%esi
  mul    %rdx
  shr    $0x5,%rdx
  imul   $0x3c,%edx,%eax
  mov    %rdx,%r9
  lea    D31(%rip),%rdx
  sub    %eax,%ecx
  xor    %eax,%eax
  push   %rcx
  mov    %r10d,%ecx
  call   <snprintf@plt>
  pop    %rax
  mov    %r12,%rax
  pop    %rdx
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D31
type_guessed: string

tool: D9: %02u:%02u:%02u

tool: D31: %u days %02u:%02u:%02u

assistant: ```c
char *get_time_remain(unsigned long remain_second) {
  unsigned int day, hour, min, second;
  static char str_time_remain[64];
  if (remain_second < 24 * 3600) {
    hour = remain_second / 3600;
    min = (remain_second - 3600 * hour) / 60;
    second = remain_second - hour * 3600 - min * 60;
    snprintf(str_time_remain, sizeof(str_time_remain), "%02u:%02u:%02u", hour, min, second);
  } else {
    day = remain_second / 24 / 3600;
    remain_second = remain_second - day * 24 * 3600;
    hour = remain_second / 3600;
    min = (remain_second - 3600 * hour) / 60;
    second = remain_second - hour * 3600 - min * 60;
    snprintf(str_time_remain, sizeof(str_time_remain), "%u days %02u:%02u:%02u", day, hour, min, second);
  }
  return str_time_remain;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L76:
  cmpl   $0x9,-0x4(%rbp)
  je     L38
  cmpl   $0xa,-0x4(%rbp)
  je     L38
  cmpl   $0x20,-0x4(%rbp)
  jne    L64
L38:
  cmpl   $0x1,-0x8(%rbp)
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L64:
  cmpl   $0x0,-0x8(%rbp)
  jne    L17
  movl   $0x1,-0x8(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L76
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int c, state = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\t' || c == '\n' || c == ' ') {
      if (state == 1) {
        putchar('\n');
        state = 0;
      }
    } else {
      if (state == 0)
        state = 1;
      putchar(c);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L4
L37:
  call   <putchar@plt>
  mov    $0x1,%ebx
L4:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    D9(%rip),%rax
  cmp    %edi,(%rax)
  je     L31
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L22
  cmp    $0x20,%edi
  jne    L37
L22:
  cmp    $0x1,%ebx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%ebx
  jmp    L4
L31:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int c, state = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\t' || c == '\n' || c == ' ') {
      if (state == 1) {
        putchar('\n');
        state = 0;
      }
    } else {
      if (state == 0)
        state = 1;
      putchar(c);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L40
L50:
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L0
  cmp    $0x20,%edi
  je     L0
  call   <putchar@plt>
  xor    %eax,%eax
  mov    $0x1,%ebp
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L50
L40:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    $0x1,%ebp
  jne    L32
  mov    $0xa,%edi
  xor    %ebp,%ebp
  call   <putchar@plt>
  jmp    L32
```

assistant: ```c
main() {
  int c, state = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\t' || c == '\n' || c == ' ') {
      if (state == 1) {
        putchar('\n');
        state = 0;
      }
    } else {
      if (state == 0)
        state = 1;
      putchar(c);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L26
L22:
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L41
  cmp    $0x20,%edi
  je     L41
  call   <putchar@plt>
  xor    %eax,%eax
  mov    $0x1,%ebp
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L22
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  cmp    $0x1,%ebp
  jne    L3
  mov    $0xa,%edi
  xor    %ebp,%ebp
  call   <putchar@plt>
  jmp    L3
```

assistant: ```c
main() {
  int c, state = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\t' || c == '\n' || c == ' ') {
      if (state == 1) {
        putchar('\n');
        state = 0;
      }
    } else {
      if (state == 0)
        state = 1;
      putchar(c);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x15(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D21(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D21
type: string

tool: D1: r

tool: D14: ./makefile

tool: D21: %c

assistant: ```c
int main(int argc, char **argv) {
  FILE *fp;
  int rv;
  char c;
  fp = fopen("./makefile", "r");
  assert(fp != NULL);
  rv = fscanf(fp, "%c", &c);
  assert(rv == 1);
  rv = fclose(fp);
  assert(rv == 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rsi
  lea    D21(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x7(%rsp),%rdx
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D24
data_type: string
name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D12
data_type: string

tool: D24: r

tool: D21: ./makefile

tool: D12: %c

assistant: ```c
int main(int argc, char **argv) {
  FILE *fp;
  int rv;
  char c;
  fp = fopen("./makefile", "r");
  assert(fp != NULL);
  rv = fscanf(fp, "%c", &c);
  assert(rv == 1);
  rv = fclose(fp);
  assert(rv == 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rsi
  lea    D27(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <assert@plt>
  lea    0x7(%rsp),%rdx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_infered: string
name: disassemble_data
arguments: tag: D27
type_infered: string
name: disassemble_data
arguments: tag: D11
type_infered: string

tool: D29: r

tool: D27: ./makefile

tool: D11: %c

assistant: ```c
int main(int argc, char **argv) {
  FILE *fp;
  int rv;
  char c;
  fp = fopen("./makefile", "r");
  assert(fp != NULL);
  rv = fscanf(fp, "%c", &c);
  assert(rv == 1);
  rv = fclose(fp);
  assert(rv == 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rsi
  lea    D23(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <assert@plt>
  lea    0x7(%rsp),%rdx
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D23
type_guessed: string
name: disassemble_data
arguments: label: D28
type_guessed: string

tool: D8: r

tool: D23: ./makefile

tool: D28: %c

assistant: ```c
int main(int argc, char **argv) {
  FILE *fp;
  int rv;
  char c;
  fp = fopen("./makefile", "r");
  assert(fp != NULL);
  rv = fscanf(fp, "%c", &c);
  assert(rv == 1);
  rv = fclose(fp);
  assert(rv == 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uniquePaths>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L36
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  jmp    L28
L36:
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
L28:
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  sub    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
L16:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  mov    -0x10(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L16
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rcx
  pop    %rbp
  ret
```

assistant: ```c
int uniquePaths(int m, int n) {
  int p = m < n ? m - 1 : n - 1;
  int q = m + n - 2;
  int pro1 = 1;
  long pro2 = 1;
  int i = p;
  while (i--) {
    pro1 *= p--;
    pro2 *= q--;
  }
  return pro2 / pro1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uniquePaths>:
  endbr64
  lea    -0x1(%rdi),%eax
  lea    -0x1(%rsi),%edx
  cmp    %esi,%edi
  cmovl  %eax,%edx
  lea    -0x2(%rdi,%rsi,1),%ecx
  test   %edx,%edx
  je     L24
  movslq %ecx,%rcx
  mov    $0x1,%eax
  mov    $0x1,%esi
L18:
  imul   %edx,%esi
  imul   %rcx,%rax
  sub    $0x1,%rcx
  sub    $0x1,%edx
  jne    L18
L12:
  movslq %esi,%rsi
  cqto
  idiv   %rsi
  ret
L24:
  mov    $0x1,%eax
  mov    $0x1,%esi
  jmp    L12
```

assistant: ```c
int uniquePaths(int m, int n) {
  int p = m < n ? m - 1 : n - 1;
  int q = m + n - 2;
  int pro1 = 1;
  long pro2 = 1;
  int i = p;
  while (i--) {
    pro1 *= p--;
    pro2 *= q--;
  }
  return pro2 / pro1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uniquePaths>:
  endbr64
  lea    -0x1(%rdi),%eax
  lea    -0x1(%rsi),%r8d
  cmp    %esi,%edi
  cmovl  %eax,%r8d
  lea    -0x2(%rdi,%rsi,1),%ecx
  lea    -0x1(%r8),%edx
  test   %r8d,%r8d
  je     L3
  movslq %ecx,%rcx
  mov    $0x1,%eax
  mov    $0x1,%esi
  nopl   0x0(%rax,%rax,1)
L18:
  imul   %r8d,%esi
  mov    %edx,%r8d
  sub    $0x1,%edx
  imul   %rcx,%rax
  sub    $0x1,%rcx
  cmp    $0xffffffff,%edx
  jne    L18
  movslq %esi,%rsi
  cqto
  idiv   %rsi
  ret
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int uniquePaths(int m, int n) {
  int p = m < n ? m - 1 : n - 1;
  int q = m + n - 2;
  int pro1 = 1;
  long pro2 = 1;
  int i = p;
  while (i--) {
    pro1 *= p--;
    pro2 *= q--;
  }
  return pro2 / pro1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uniquePaths>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    %esi,%edi
  lea    -0x1(%rsi),%r8d
  cmovl  %eax,%r8d
  add    %esi,%edi
  lea    -0x2(%rdi),%r9d
  test   %r8d,%r8d
  je     L12
  movslq %edi,%rdi
  lea    -0x1(%r8),%eax
  movslq %r9d,%rdx
  mov    $0x1,%esi
  lea    -0x3(%rdi),%rcx
  sub    %r9d,%r8d
  sub    %rax,%rcx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  imul   %rdx,%rax
  lea    (%r8,%rdx,1),%edi
  sub    $0x1,%rdx
  imul   %edi,%esi
  cmp    %rcx,%rdx
  jne    L10
  movslq %esi,%rsi
  cqto
  idiv   %rsi
  ret
  nopl   (%rax)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int uniquePaths(int m, int n) {
  int p = m < n ? m - 1 : n - 1;
  int q = m + n - 2;
  int pro1 = 1;
  long pro2 = 1;
  int i = p;
  while (i--) {
    pro1 *= p--;
    pro2 *= q--;
  }
  return pro2 / pro1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PTR_SWAP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PTR_SWAP(void **a, void **b) {
  void *t = *a;
  *a = *b;
  *b = t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PTR_SWAP>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void PTR_SWAP(void **a, void **b) {
  void *t = *a;
  *a = *b;
  *b = t;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PTR_SWAP>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void PTR_SWAP(void **a, void **b) {
  void *t = *a;
  *a = *b;
  *b = t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PTR_SWAP>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void PTR_SWAP(void **a, void **b) {
  void *t = *a;
  *a = *b;
  *b = t;
}
```