ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D40(%rip),%r15
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x400(%rsp),%rbp
  call   <printf@plt>
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getlinee@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <getlinee@plt>
  mov    %r12d,%edx
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  lea    D18(%rip),%r12
  call   <any@plt>
  xchg   %ax,%ax
L49:
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  and    $0xffffffdf,%eax
  cmp    $0x59,%eax
  je     L47
  cmp    $0x4e,%eax
  je     L35
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L47:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getlinee@plt>
  mov    %r13,%rdi
  mov    %eax,0xc(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3e8,%esi
  call   <getlinee@plt>
  mov    0xc(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %eax,%ecx
  call   <any@plt>
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L35:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D40
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D40: I don't understand that command


tool: D28: Please enter the first sentence


tool: D14: Please enter the second sentence


tool: D18: Do you want to continue?(Y\N)

tool: D1: Have a nice day!!

assistant: ```c
int main() {
  int first, s1_char, s2_char, c;
  char s1[1000];
  char s2[1000];
  first = 0;
  while (1) {
    if (first != 0) {
      printf("Do you want to continue?(Y\\N)");
      if (((c = getchar()) == 'y') || (c == 'Y')) {
        getchar();
        printf("Please enter the first sentence\n");
        s1_char = getlinee(s1, 1000);
        printf("Please enter the second sentence\n");
        s2_char = getlinee(s2, 1000);
        any(s1, s2, s1_char, s2_char);
      } else if ((c == 'n') || (c == 'N')) {
        printf("Have a nice day!!");
        break;
      } else
        printf("I don't understand that command\n");
    } else {
      printf("Please enter the first sentence\n");
      s1_char = getlinee(s1, 1000);
      printf("Please enter the second sentence\n");
      getlinee(s2, 1000);
      any(s1, s2, s1_char, s2_char);
      first = 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D32(%rip),%r15
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  lea    D30(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x400(%rsp),%rbp
  call   <printf@plt>
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getlinee@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <getlinee@plt>
  mov    %r12d,%edx
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  lea    D36(%rip),%r12
  call   <any@plt>
  xchg   %ax,%ax
L1:
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  and    $0xffffffdf,%eax
  cmp    $0x59,%eax
  je     L33
  cmp    $0x4e,%eax
  je     L12
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getlinee@plt>
  mov    %r13,%rdi
  mov    %eax,0xc(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3e8,%esi
  call   <getlinee@plt>
  mov    0xc(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %eax,%ecx
  call   <any@plt>
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L12:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D32
datatype: string
name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D30
datatype: string
name: read_data
arguments: data_tag: D36
datatype: string
name: read_data
arguments: data_tag: D6
datatype: string

tool: D32: I don't understand that command


tool: D22: Please enter the first sentence


tool: D30: Please enter the second sentence


tool: D36: Do you want to continue?(Y\N)

tool: D6: Have a nice day!!

assistant: ```c
int main() {
  int first, s1_char, s2_char, c;
  char s1[1000];
  char s2[1000];
  first = 0;
  while (1) {
    if (first != 0) {
      printf("Do you want to continue?(Y\\N)");
      if (((c = getchar()) == 'y') || (c == 'Y')) {
        getchar();
        printf("Please enter the first sentence\n");
        s1_char = getlinee(s1, 1000);
        printf("Please enter the second sentence\n");
        s2_char = getlinee(s2, 1000);
        any(s1, s2, s1_char, s2_char);
      } else if ((c == 'n') || (c == 'N')) {
        printf("Have a nice day!!");
        break;
      } else
        printf("I don't understand that command\n");
    } else {
      printf("Please enter the first sentence\n");
      s1_char = getlinee(s1, 1000);
      printf("Please enter the second sentence\n");
      getlinee(s2, 1000);
      any(s1, s2, s1_char, s2_char);
      first = 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<remove_trailing_whitespaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L48
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L36:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L19
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0x0,-0x8(%rbp)
  jns    L36
  jmp    L40
L48:
  nop
  jmp    L40
L19:
  nop
L40:
  leave
  ret
```

assistant: ```c
void remove_trailing_whitespaces(char *str) {
  int i, size;
  assert(str != NULL);
  if (str == NULL)
    return;
  size = strlen(str);
  for (i = size - 1; i >= 0; i--) {
    if (str[i] == ' ') {
      str[i] = '\0';
    } else
      break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<remove_trailing_whitespaces>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L9
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L9
  movslq %edx,%rdx
  add    %rbx,%rdx
  cltq
  lea    -0x2(%rbx,%rax,1),%rax
  lea    -0x1(%rcx),%ecx
  sub    %rcx,%rax
L4:
  cmpb   $0x20,(%rdx)
  jne    L9
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L4
L9:
  pop    %rbx
  ret
```

assistant: ```c
void remove_trailing_whitespaces(char *str) {
  int i, size;
  assert(str != NULL);
  if (str == NULL)
    return;
  size = strlen(str);
  for (i = size - 1; i >= 0; i--) {
    if (str[i] == ' ') {
      str[i] = '\0';
    } else
      break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<remove_trailing_whitespaces>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L34
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L34
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%rbx,%rax,1),%rax
  add    %rbx,%rdx
  sub    %rcx,%rax
  jmp    L39
L47:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L34
L39:
  cmpb   $0x20,(%rdx)
  je     L47
L34:
  pop    %rbx
  ret
```

assistant: ```c
void remove_trailing_whitespaces(char *str) {
  int i, size;
  assert(str != NULL);
  if (str == NULL)
    return;
  size = strlen(str);
  for (i = size - 1; i >= 0; i--) {
    if (str[i] == ' ') {
      str[i] = '\0';
    } else
      break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_trailing_whitespaces>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L46
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L46
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%rbx,%rax,1),%rax
  add    %rbx,%rdx
  sub    %rcx,%rax
  jmp    L23
L42:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L46
L23:
  cmpb   $0x20,(%rdx)
  je     L42
L46:
  pop    %rbx
  ret
```

assistant: ```c
void remove_trailing_whitespaces(char *str) {
  int i, size;
  assert(str != NULL);
  if (str == NULL)
    return;
  size = strlen(str);
  for (i = size - 1; i >= 0; i--) {
    if (str[i] == ' ') {
      str[i] = '\0';
    } else
      break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<saveImage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  je     L17
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L17:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type: string
name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D26
type: string

tool: D25: wb

tool: D22: could not open for writing %s


tool: D26: ERROR WRITING

assistant: ```c
int saveImage(char *filename, volatile void *address, int numbytes) {
  FILE *outfile = fopen(filename, "wb");
  if (outfile == NULL) {
    printf("could not open for writing %s\n", filename);
    exit(1);
  }
  int outlen = fwrite(address, 1, numbytes, outfile);
  if (outlen != numbytes) {
    printf("ERROR WRITING\n");
  }
  fclose(outfile);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<saveImage>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
L31:
  mov    %rbx,%rcx
  mov    %ebp,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  cmp    %eax,%ebp
  jne    L27
L38:
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %r12,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L31
L27:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L38
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D15
type_infered: string
name: read_data
arguments: tag: D22
type_infered: string

tool: D7: wb

tool: D15: could not open for writing %s


tool: D22: ERROR WRITING

assistant: ```c
int saveImage(char *filename, volatile void *address, int numbytes) {
  FILE *outfile = fopen(filename, "wb");
  if (outfile == NULL) {
    printf("could not open for writing %s\n", filename);
    exit(1);
  }
  int outlen = fwrite(address, 1, numbytes, outfile);
  if (outlen != numbytes) {
    printf("ERROR WRITING\n");
  }
  fclose(outfile);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<saveImage>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  lea    D21(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
L8:
  mov    %rbp,%rcx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  cmp    %eax,%ebx
  je     L2
  lea    D6(%rip),%rdi
  call   <puts@plt>
L2:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <fclose@plt>
  xchg   %ax,%ax
L28:
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D21: wb

tool: D6: ERROR WRITING

tool: D2: could not open for writing %s


assistant: ```c
int saveImage(char *filename, volatile void *address, int numbytes) {
  FILE *outfile = fopen(filename, "wb");
  if (outfile == NULL) {
    printf("could not open for writing %s\n", filename);
    exit(1);
  }
  int outlen = fwrite(address, 1, numbytes, outfile);
  if (outlen != numbytes) {
    printf("ERROR WRITING\n");
  }
  fclose(outfile);
}
```
user: What is the c source code of the assembly code below?

```asm
<saveImage>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  lea    D11(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L21
L28:
  mov    %rbp,%rcx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  cmp    %eax,%ebx
  je     L9
  lea    D25(%rip),%rdi
  call   <puts@plt>
L9:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <fclose@plt>
  xchg   %ax,%ax
L21:
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L28
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: string
name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D11: wb

tool: D25: ERROR WRITING

tool: D5: could not open for writing %s


assistant: ```c
int saveImage(char *filename, volatile void *address, int numbytes) {
  FILE *outfile = fopen(filename, "wb");
  if (outfile == NULL) {
    printf("could not open for writing %s\n", filename);
    exit(1);
  }
  int outlen = fwrite(address, 1, numbytes, outfile);
  if (outlen != numbytes) {
    printf("ERROR WRITING\n");
  }
  fclose(outfile);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dp_err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <ping@plt>
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L10
  cmpl   $0x0,-0x4(%rbp)
  jns    L68
  cmpl   $0xfffffffe,-0x4(%rbp)
  je     L62
  cmpl   $0xfffffffe,-0x4(%rbp)
  jg     L68
  cmpl   $0xfffffffc,-0x4(%rbp)
  je     L81
  cmpl   $0xfffffffd,-0x4(%rbp)
  je     L98
  jmp    L68
L10:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <err_msg@plt>
  jmp    L68
L62:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <err_msg@plt>
  jmp    L68
L98:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <err_msg@plt>
  jmp    L68
L81:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <err_msg@plt>
  nop
L68:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D35
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D25
type_guessed: string

tool: D35: Input is not consistent

tool: D12: Larger nmax needed

tool: D4: Step size too small

tool: D25: Problem became stiff

assistant: ```c
void dp_err(int k) {
  ping();
  switch (k) {
  case -1:
    err_msg("Input is not consistent");
    break;
  case -2:
    err_msg("Larger nmax needed");
    break;
  case -3:
    err_msg("Step size too small");
    break;
  case -4:
    err_msg("Problem became stiff");
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dp_err>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <ping@plt>
  cmp    $0xfffffffe,%ebx
  je     L62
  cmp    $0xffffffff,%ebx
  jge    L2
  cmp    $0xfffffffc,%ebx
  je     L79
  cmp    $0xfffffffd,%ebx
  jne    L17
  lea    D10(%rip),%rdi
  call   <err_msg@plt>
  jmp    L17
L2:
  jne    L17
  lea    D24(%rip),%rdi
  call   <err_msg@plt>
L17:
  pop    %rbx
  ret
L62:
  lea    D29(%rip),%rdi
  call   <err_msg@plt>
  jmp    L17
L79:
  lea    D13(%rip),%rdi
  call   <err_msg@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: data_label: D10
data_type: string
name: disassemble_data
arguments: data_label: D24
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D13
data_type: string

tool: D10: Step size too small

tool: D24: Input is not consistent

tool: D29: Larger nmax needed

tool: D13: Problem became stiff

assistant: ```c
void dp_err(int k) {
  ping();
  switch (k) {
  case -1:
    err_msg("Input is not consistent");
    break;
  case -2:
    err_msg("Larger nmax needed");
    break;
  case -3:
    err_msg("Step size too small");
    break;
  case -4:
    err_msg("Problem became stiff");
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dp_err>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <ping@plt>
  cmp    $0xfffffffe,%ebx
  je     L1
  cmp    $0xffffffff,%ebx
  jge    L44
  cmp    $0xfffffffc,%ebx
  je     L20
  cmp    $0xfffffffd,%ebx
  jne    L32
  lea    D27(%rip),%rdi
  pop    %rbx
  jmp    1070 <err_msg@plt>
  nop
L44:
  jne    L32
  lea    D32(%rip),%rdi
  pop    %rbx
  jmp    1070 <err_msg@plt>
  nop
L1:
  lea    D4(%rip),%rdi
  pop    %rbx
  jmp    1070 <err_msg@plt>
  nopl   (%rax)
L32:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  lea    D30(%rip),%rdi
  pop    %rbx
  jmp    1070 <err_msg@plt>
```

tool_calls: name: disassemble_data
arguments: label: D27
data_type: string
name: disassemble_data
arguments: label: D32
data_type: string
name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D30
data_type: string

tool: D27: Step size too small

tool: D32: Input is not consistent

tool: D4: Larger nmax needed

tool: D30: Problem became stiff

assistant: ```c
void dp_err(int k) {
  ping();
  switch (k) {
  case -1:
    err_msg("Input is not consistent");
    break;
  case -2:
    err_msg("Larger nmax needed");
    break;
  case -3:
    err_msg("Step size too small");
    break;
  case -4:
    err_msg("Problem became stiff");
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dp_err>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <ping@plt>
  cmp    $0xfffffffe,%ebx
  je     L34
  cmp    $0xffffffff,%ebx
  jge    L42
  cmp    $0xfffffffc,%ebx
  je     L22
  cmp    $0xfffffffd,%ebx
  jne    L5
  lea    D27(%rip),%rdi
  pop    %rbx
  jmp    1070 <err_msg@plt>
  nop
L42:
  jne    L5
  lea    D3(%rip),%rdi
  pop    %rbx
  jmp    1070 <err_msg@plt>
  nop
L34:
  lea    D5(%rip),%rdi
  pop    %rbx
  jmp    1070 <err_msg@plt>
  nopl   (%rax)
L5:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  lea    D21(%rip),%rdi
  pop    %rbx
  jmp    1070 <err_msg@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D27
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string

tool: D27: Step size too small

tool: D3: Input is not consistent

tool: D5: Larger nmax needed

tool: D21: Problem became stiff

assistant: ```c
void dp_err(int k) {
  ping();
  switch (k) {
  case -1:
    err_msg("Input is not consistent");
    break;
  case -2:
    err_msg("Larger nmax needed");
    break;
  case -3:
    err_msg("Step size too small");
    break;
  case -4:
    err_msg("Problem became stiff");
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str$find_first_not_in_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   1070 <str$analyze_sdesc@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x26(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   1070 <str$analyze_sdesc@plt>
  movzwl -0x28(%rbp),%eax
  test   %ax,%ax
  jne    11a7 <str$find_first_not_in_set+0x6e>
  mov    $0x1,%eax
  jmp    122e <str$find_first_not_in_set+0xf5>
  movzwl -0x26(%rbp),%eax
  test   %ax,%ax
  jne    11b7 <str$find_first_not_in_set+0x7e>
  mov    $0x0,%eax
  jmp    122e <str$find_first_not_in_set+0xf5>
  movl   $0x0,-0x24(%rbp)
  jmp    121d <str$find_first_not_in_set+0xe4>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    11fd <str$find_first_not_in_set+0xc4>
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%eax
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    11f9 <str$find_first_not_in_set+0xc0>
  movl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
  movzwl -0x26(%rbp),%eax
  movzwl %ax,%eax
  cmp    %eax,-0x20(%rbp)
  jl     11d0 <str$find_first_not_in_set+0x97>
  cmpl   $0x0,-0x1c(%rbp)
  jne    1219 <str$find_first_not_in_set+0xe0>
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltq
  jmp    122e <str$find_first_not_in_set+0xf5>
  addl   $0x1,-0x24(%rbp)
  movzwl -0x28(%rbp),%eax
  movzwl %ax,%eax
  cmp    %eax,-0x24(%rbp)
  jl     11c0 <str$find_first_not_in_set+0x87>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     1242 <str$find_first_not_in_set+0x109>
  call   <__stack_chk_fail@plt>
  leave
  ret
```

assistant: ```c
long str$find_first_not_in_set(const struct dsc$descriptor_s *first_source_string, const struct dsc$descriptor_s *second_source_string) {
  char *s1_ptr;
  unsigned short s1_length;
  char *s2_ptr;
  unsigned short s2_length;
  int loop1;
  int loop2;
  int result;
  str$analyze_sdesc(first_source_string, &s1_length, &s1_ptr);
  str$analyze_sdesc(second_source_string, &s2_length, &s2_ptr);
  if (s1_length == 0) {
    return 1;
  }
  if (s2_length == 0) {
    return 0;
  }
  for (loop1 = 0; loop1 < s1_length; loop1++) {
    result = 0;
    for (loop2 = 0; loop2 < s2_length; loop2++) {
      if (s1_ptr[loop1] == s2_ptr[loop2]) {
        result = 1;
      }
    }
    if (result == 0) {
      return loop1 + 1;
    }
  }
  return 0;
}
```