ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1f8(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    -0x1f0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x3c,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L25
L5:
  lea    -0x1f4(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x1f4(%rbp),%edx
  lea    -0x1f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getArray@plt>
  mov    -0x1f4(%rbp),%edx
  lea    -0x1f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <reverseArray@plt>
  mov    -0x1f4(%rbp),%edx
  lea    -0x1f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    -0x1f8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1f8(%rbp)
L25:
  mov    -0x1f8(%rbp),%eax
  test   %eax,%eax
  jne    L5
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type: string

tool: D12: %u

assistant: ```c
void main(void) {
  unsigned N;
  scanf("%u", &N);
  getchar();
  unsigned count;
  unsigned i;
  int array[120] = {0};
  for (; N; --N) {
    scanf("%u", &count);
    getchar();
    getArray(array, count);
    reverseArray(array, count);
    printArray(array, count);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x3c,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  cmpl   $0x0,0x8(%rsp)
  je     L17
  lea    D1(%rip),%rbp
L19:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    0x10(%rsp),%rbx
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <getArray@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <reverseArray@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x8(%rsp)
  jne    L19
L17:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: %u

assistant: ```c
void main(void) {
  unsigned N;
  scanf("%u", &N);
  getchar();
  unsigned count;
  unsigned i;
  int array[120] = {0};
  for (; N; --N) {
    scanf("%u", &count);
    getchar();
    getArray(array, count);
    reverseArray(array, count);
    printArray(array, count);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  mov    $0x3c,%ecx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L10
  lea    0xc(%rsp),%r12
  nopl   0x0(%rax)
L14:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <getArray@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <reverseArray@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  subl   $0x1,0x8(%rsp)
  jne    L14
L10:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x200,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: %u

assistant: ```c
void main(void) {
  unsigned N;
  scanf("%u", &N);
  getchar();
  unsigned count;
  unsigned i;
  int array[120] = {0};
  for (; N; --N) {
    scanf("%u", &count);
    getchar();
    getArray(array, count);
    reverseArray(array, count);
    printArray(array, count);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  mov    $0x3c,%ecx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L10
  lea    0xc(%rsp),%r12
  nopl   0x0(%rax)
L11:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <getArray@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <reverseArray@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  subl   $0x1,0x8(%rsp)
  jne    L11
L10:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x200,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: %u

assistant: ```c
void main(void) {
  unsigned N;
  scanf("%u", &N);
  getchar();
  unsigned count;
  unsigned i;
  int array[120] = {0};
  for (; N; --N) {
    scanf("%u", &count);
    getchar();
    getArray(array, count);
    reverseArray(array, count);
    printArray(array, count);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<outBounds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L9
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L9
  mov    $0x0,%eax
  jmp    L12
L9:
  mov    $0xffffffff,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int outBounds(const char *start, const char *end, char *ptr) {
  if ((ptr >= start) && (ptr < end))
    return 0;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<outBounds>:
  endbr64
  cmp    %rdi,%rdx
  setae  %cl
  cmp    %rsi,%rdx
  setb   %al
  movzbl %al,%eax
  and    %ecx,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int outBounds(const char *start, const char *end, char *ptr) {
  if ((ptr >= start) && (ptr < end))
    return 0;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<outBounds>:
  endbr64
  cmp    %rdi,%rdx
  setae  %cl
  xor    %eax,%eax
  cmp    %rsi,%rdx
  setb   %al
  and    %ecx,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int outBounds(const char *start, const char *end, char *ptr) {
  if ((ptr >= start) && (ptr < end))
    return 0;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<outBounds>:
  endbr64
  cmp    %rdi,%rdx
  setae  %cl
  xor    %eax,%eax
  cmp    %rsi,%rdx
  setb   %al
  and    %ecx,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int outBounds(const char *start, const char *end, char *ptr) {
  if ((ptr >= start) && (ptr < end))
    return 0;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L10
L11:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L11
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  size_t i;
  char *ss = (char *)s;
  for (i = 0; i < n; i++)
    ss[i] = c;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L11
  mov    %rdi,%rcx
  add    %rdi,%rdx
L0:
  mov    %sil,(%rcx)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L0
L11:
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  size_t i;
  char *ss = (char *)s;
  for (i = 0; i < n; i++)
    ss[i] = c;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L6
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  size_t i;
  char *ss = (char *)s;
  for (i = 0; i < n; i++)
    ss[i] = c;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L0
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  size_t i;
  char *ss = (char *)s;
  for (i = 0; i < n; i++)
    ss[i] = c;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%ax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short inw(int port) {
  unsigned short ret;
  __asm__("inw %w1, %w0" : "=a"(ret) : "Nd"(port));
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(int port) {
  unsigned short ret;
  __asm__("inw %w1, %w0" : "=a"(ret) : "Nd"(port));
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(int port) {
  unsigned short ret;
  __asm__("inw %w1, %w0" : "=a"(ret) : "Nd"(port));
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(int port) {
  unsigned short ret;
  __asm__("inw %w1, %w0" : "=a"(ret) : "Nd"(port));
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L28:
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0xc(%rbp)
  subl   $0x2,-0x1c(%rbp)
L3:
  cmpl   $0x1,-0x1c(%rbp)
  jg     L28
  cmpl   $0x1,-0x1c(%rbp)
  jne    L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %ax,-0xe(%rbp)
  movzwl -0xe(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short checksum(void *b, int len) {
  unsigned short *buf = b;
  unsigned int sum = 0;
  unsigned short result;
  for (sum = 0; len > 1; len -= 2)
    sum += *buf++;
  if (len == 1)
    sum += *(unsigned char *)buf;
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  result = ~sum;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L49
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L46:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L46
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L40:
  cmp    $0x1,%esi
  je     L25
L20:
  mov    %eax,%edx
  shr    $0x10,%edx
  movzwl %ax,%eax
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
L49:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L40
L25:
  movzbl (%rcx),%edx
  add    %edx,%eax
  jmp    L20
```

assistant: ```c
unsigned short checksum(void *b, int len) {
  unsigned short *buf = b;
  unsigned int sum = 0;
  unsigned short result;
  for (sum = 0; len > 1; len -= 2)
    sum += *buf++;
  if (len == 1)
    sum += *(unsigned char *)buf;
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  result = ~sum;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L6
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L32:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L32
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L9:
  cmp    $0x1,%esi
  jne    L10
  movzbl (%rcx),%edx
  add    %edx,%eax
L10:
  mov    %eax,%edx
  movzwl %ax,%eax
  shr    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L9
```

assistant: ```c
unsigned short checksum(void *b, int len) {
  unsigned short *buf = b;
  unsigned int sum = 0;
  unsigned short result;
  for (sum = 0; len > 1; len -= 2)
    sum += *buf++;
  if (len == 1)
    sum += *(unsigned char *)buf;
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  result = ~sum;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<checksum>:
  endbr64
  mov    %rdi,%rdx
  cmp    $0x1,%esi
  jle    L59
  lea    -0x2(%rsi),%r10d
  mov    %r10d,%r9d
  shr    %r9d
  lea    0x1(%r9),%ecx
  cmp    $0xd,%r10d
  jbe    L112
  mov    %rdi,%rax
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopl   0x0(%rax)
L54:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm3
  punpckhwd %xmm2,%xmm0
  punpcklwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rdi,%rax
  jne    L54
  movdqa %xmm1,%xmm0
  mov    %ecx,%r8d
  psrldq $0x8,%xmm0
  and    $0xfffffff8,%r8d
  paddd  %xmm0,%xmm1
  mov    %r8d,%edi
  movdqa %xmm1,%xmm0
  neg    %edi
  psrldq $0x4,%xmm0
  lea    (%rsi,%rdi,2),%esi
  mov    %r8d,%edi
  paddd  %xmm0,%xmm1
  lea    (%rdx,%rdi,2),%rdi
  movd   %xmm1,%eax
  cmp    %ecx,%r8d
  je     L4
L68:
  movzwl (%rdi),%r8d
  add    %r8d,%eax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L4
  movzwl 0x2(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L4
  movzwl 0x4(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L4
  movzwl 0x6(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L4
  movzwl 0x8(%rdi),%r8d
  add    %r8d,%eax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L4
  movzwl 0xa(%rdi),%r8d
  add    %r8d,%eax
  cmp    $0xd,%esi
  jle    L4
  movzwl 0xc(%rdi),%esi
  add    %esi,%eax
L4:
  mov    %ecx,%esi
  mov    %r9d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r10,%rcx,2),%esi
L122:
  cmp    $0x1,%esi
  jne    L7
  movzbl (%rdx),%edx
  add    %edx,%eax
L7:
  mov    %eax,%edx
  movzwl %ax,%eax
  shr    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
  jmp    L122
L112:
  xor    %eax,%eax
  jmp    L68
```

assistant: ```c
unsigned short checksum(void *b, int len) {
  unsigned short *buf = b;
  unsigned int sum = 0;
  unsigned short result;
  for (sum = 0; len > 1; len -= 2)
    sum += *buf++;
  if (len == 1)
    sum += *(unsigned char *)buf;
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  result = ~sum;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<common_prefix_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  cmp    %rax,%rbx
  jae    L8
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  jmp    L25
L8:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
L25:
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L36
L47:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L22
  addq   $0x1,-0x20(%rbp)
L36:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L47
  jmp    L51
L22:
  nop
L51:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
size_t common_prefix_length(const wchar_t *s1, const wchar_t *s2) {
  size_t i;
  size_t n = ((wcslen(s1)) < (wcslen(s2)) ? (wcslen(s1)) : (wcslen(s2)));
  for (i = 0; i < n; i++) {
    if (s1[i] != s2[i])
      break;
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<common_prefix_length>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <wcslen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <wcslen@plt>
  cmp    %rax,%r12
  jae    L3
  mov    %rbx,%rdi
  call   <wcslen@plt>
L23:
  test   %rax,%rax
  je     L40
  mov    $0x0,%edx
L20:
  mov    0x0(%rbp,%rdx,8),%rcx
  cmp    %rcx,(%rbx,%rdx,8)
  jne    L36
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L20
  jmp    L40
L3:
  mov    %rbp,%rdi
  call   <wcslen@plt>
  jmp    L23
L36:
  mov    %rdx,%rax
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t common_prefix_length(const wchar_t *s1, const wchar_t *s2) {
  size_t i;
  size_t n = ((wcslen(s1)) < (wcslen(s2)) ? (wcslen(s1)) : (wcslen(s2)));
  for (i = 0; i < n; i++) {
    if (s1[i] != s2[i])
      break;
  }
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<common_prefix_length>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <wcslen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <wcslen@plt>
  cmp    %rax,%r12
  jae    L43
  mov    %rbx,%rdi
  call   <wcslen@plt>
L44:
  test   %rax,%rax
  je     L1
  xor    %edx,%edx
  jmp    L45
  nopl   0x0(%rax)
L11:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L1
L45:
  mov    0x0(%rbp,%rdx,8),%rcx
  cmp    %rcx,(%rbx,%rdx,8)
  je     L11
  mov    %rdx,%rax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L43:
  mov    %rbp,%rdi
  call   <wcslen@plt>
  jmp    L44
```

assistant: ```c
size_t common_prefix_length(const wchar_t *s1, const wchar_t *s2) {
  size_t i;
  size_t n = ((wcslen(s1)) < (wcslen(s2)) ? (wcslen(s1)) : (wcslen(s2)));
  for (i = 0; i < n; i++) {
    if (s1[i] != s2[i])
      break;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<common_prefix_length>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <wcslen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <wcslen@plt>
  cmp    %rax,%r12
  jae    L54
  mov    %rbx,%rdi
  call   <wcslen@plt>
L18:
  test   %rax,%rax
  je     L34
  xor    %edx,%edx
  jmp    L49
  nopl   0x0(%rax)
L40:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L34
L49:
  mov    0x0(%rbp,%rdx,8),%rcx
  cmp    %rcx,(%rbx,%rdx,8)
  je     L40
  mov    %rdx,%rax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L54:
  mov    %rbp,%rdi
  call   <wcslen@plt>
  jmp    L18
```

assistant: ```c
size_t common_prefix_length(const wchar_t *s1, const wchar_t *s2) {
  size_t i;
  size_t n = ((wcslen(s1)) < (wcslen(s2)) ? (wcslen(s1)) : (wcslen(s2)));
  for (i = 0; i < n; i++) {
    if (s1[i] != s2[i])
      break;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<printString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2: %s

assistant: ```c
void printString(char headerMessage[], char value[]) {
  printf("%s", headerMessage);
  printf("%s", value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: %s

assistant: ```c
void printString(char headerMessage[], char value[]) {
  printf("%s", headerMessage);
  printf("%s", value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printString>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: %s

assistant: ```c
void printString(char headerMessage[], char value[]) {
  printf("%s", headerMessage);
  printf("%s", value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printString>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: %s

assistant: ```c
void printString(char headerMessage[], char value[]) {
  printf("%s", headerMessage);
  printf("%s", value);
}
```