user: 这段汇编代码用C语言表示是什么样的：

```asm
<printgraph>:
  endbr64
  push   %r15
  movsbl %dil,%edx
  push   %r14
  lea    -0x40(%rdx),%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edx,0x1c(%rsp)
  mov    %eax,0x18(%rsp)
  test   %eax,%eax
  jle    L353
  lea    -0x82(%rdx,%rdx,1),%ecx
  lea    -0x1(%rax,%rax,1),%r12d
  xor    %ebp,%ebp
  lea    0x3f(%rax,%rax,1),%eax
  mov    %ecx,0xc(%rsp)
  mov    %ecx,%r13d
  mov    %al,0x17(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L248:
  mov    0xc(%rsp),%eax
  test   %ebp,%ebp
  sete   %bl
  test   %eax,%eax
  jg     L1
  xor    %r15d,%r15d
  jmp    L429
  cs nopw 0x0(%rax,%rax,1)
L268:
  cmp    %r15d,%ebp
  jge    L43
  movzbl 0x17(%rsp),%edi
  sub    %r15d,%edi
  movsbl %dil,%edi
  call   <putchar@plt>
L385:
  add    $0x1,%r15d
  cmp    %r15d,%r12d
  jle    L109
L429:
  test   %r15d,%r15d
  je     L27
  test   %bl,%bl
  jne    L27
  cmp    %r15d,%r13d
  jne    L268
L27:
  mov    $0x41,%edi
  add    $0x1,%r15d
  call   <putchar@plt>
  cmp    %r15d,%r12d
  jg     L429
L109:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  subl   $0x1,0xc(%rsp)
  cmp    0x18(%rsp),%ebp
  jne    L248
L353:
  mov    0x1c(%rsp),%eax
  mov    %eax,%ebp
  sub    $0x42,%ebp
  js     L76
  mov    0x18(%rsp),%esi
  lea    -0x82(%rax,%rax,1),%r13d
  sub    $0x40,%eax
  mov    %eax,0x10(%rsp)
  lea    0x3f(%rsi,%rsi,1),%ecx
  lea    -0x1(%rsi,%rsi,1),%r12d
  mov    %cl,0x17(%rsp)
  nopl   0x0(%rax,%rax,1)
L69:
  test   %r12d,%r12d
  jle    L387
  mov    0x10(%rsp),%eax
  test   %ebp,%ebp
  sete   %bl
  test   %eax,%eax
  jle    L379
  cmp    %r12d,%eax
  mov    %eax,%r14d
  lea    0x41(%rbp),%eax
  cmovg  %r12d,%r14d
  mov    %al,0xc(%rsp)
  xor    %r15d,%r15d
  jmp    L211
L18:
  cmp    %ebp,%r15d
  jle    L253
  movzbl 0xc(%rsp),%edi
  call   <putchar@plt>
L13:
  add    $0x1,%r15d
  cmp    %r14d,%r15d
  jge    L202
L211:
  test   %r15d,%r15d
  je     L173
  test   %bl,%bl
  jne    L173
  cmp    %r15d,%r13d
  jne    L18
L173:
  mov    $0x41,%edi
  add    $0x1,%r15d
  call   <putchar@plt>
  cmp    %r14d,%r15d
  jl     L211
L202:
  cmp    %r12d,%r15d
  jl     L419
  jmp    L387
  nopl   0x0(%rax)
L40:
  cmp    %ebp,%r15d
  jle    L126
  movzbl 0x17(%rsp),%edi
  sub    %r15d,%edi
  movsbl %dil,%edi
  call   <putchar@plt>
L181:
  add    $0x1,%r15d
  cmp    %r12d,%r15d
  jge    L387
L419:
  test   %r15d,%r15d
  je     L41
  test   %bl,%bl
  jne    L41
  cmp    %r13d,%r15d
  jne    L40
L41:
  mov    $0x41,%edi
  add    $0x1,%r15d
  call   <putchar@plt>
  cmp    %r12d,%r15d
  jl     L419
L387:
  mov    $0xa,%edi
  sub    $0x1,%ebp
  call   <putchar@plt>
  addl   $0x1,0x10(%rsp)
  cmp    $0xffffffff,%ebp
  jne    L69
L76:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L43:
  lea    0x41(%r15),%edi
  movzbl %dil,%edi
  call   <putchar@plt>
  jmp    L385
  nopw   0x0(%rax,%rax,1)
L253:
  lea    0x41(%r15),%edi
  call   <putchar@plt>
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0xc(%rsp),%eax
  cmp    %r12d,%eax
  mov    %eax,%r14d
  lea    0x41(%rbp),%eax
  cmovg  %r12d,%r14d
  mov    %eax,0x10(%rsp)
  xor    %r15d,%r15d
  jmp    L322
  nopw   0x0(%rax,%rax,1)
L289:
  cmp    %r15d,%ebp
  jge    L123
  mov    0x10(%rsp),%edi
  call   <putchar@plt>
L259:
  add    $0x1,%r15d
  cmp    %r14d,%r15d
  jge    L285
L322:
  test   %r15d,%r15d
  je     L129
  test   %bl,%bl
  jne    L129
  cmp    %r15d,%r13d
  jne    L289
L129:
  mov    $0x41,%edi
  add    $0x1,%r15d
  call   <putchar@plt>
  cmp    %r14d,%r15d
  jl     L322
L285:
  cmp    %r12d,%r15d
  jl     L429
  jmp    L109
  cs nopw 0x0(%rax,%rax,1)
L123:
  lea    0x41(%r15),%edi
  call   <putchar@plt>
  jmp    L259
  nopl   0x0(%rax,%rax,1)
L126:
  lea    0x41(%r15),%edi
  movzbl %dil,%edi
  call   <putchar@plt>
  jmp    L181
  nopw   0x0(%rax,%rax,1)
L379:
  xor    %r15d,%r15d
  jmp    L419
```

assistant: ```c
void printgraph(char ch) {
  int i, j;
  int n = ch - 'A' + 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < 2 * n - 1; j++) {
      if (i == 0 || j == 0 || j == 2 * n - 2)
        putchar('A');
      else {
        if (j <= i)
          putchar('A' + j);
        else if (j > i && j < 2 * n - 2 - i)
          putchar('A' + i);
        else
          putchar('A' + 2 * n - 2 - j);
      }
    }
    putchar('\n');
  }
  for (i = n - 2; i >= 0; i--) {
    for (j = 0; j < 2 * n - 1; j++) {
      if (i == 0 || j == 0 || j == 2 * n - 2)
        putchar('A');
      else {
        if (j <= i)
          putchar('A' + j);
        else if (j > i && j < 2 * n - 2 - i)
          putchar('A' + i);
        else
          putchar('A' + 2 * n - 2 - j);
      }
    }
    putchar('\n');
  }
}
```