ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<serial_out>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <check_serial_input@plt>
  cmp    $0xa,%ebp
  je     L4
L17:
  xor    %eax,%eax
  mov    $0xff000000,%ebx
  call   <check_serial_input@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L35
  nopw   0x0(%rax,%rax,1)
L38:
  xor    %edi,%edi
  call   <set_leds@plt>
  xor    %eax,%eax
  call   <check_serial_input@plt>
  mov    (%rbx),%edx
  test   %edx,%edx
  jne    L38
L35:
  mov    %ebp,%eax
  mov    %ebp,%edi
  movabs %eax,0xff000000
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <set_leds@plt>
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  mov    $0xff000000,%ebx
  call   <check_serial_input@plt>
  xor    %eax,%eax
  call   <check_serial_input@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L9
  nopl   0x0(%rax)
L19:
  xor    %edi,%edi
  call   <set_leds@plt>
  xor    %eax,%eax
  call   <check_serial_input@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L19
L9:
  mov    $0xff000000,%eax
  mov    $0xd,%edi
  movl   $0xd,(%rax)
  call   <set_leds@plt>
  jmp    L17
```

assistant: ```c
void serial_out(unsigned ch) {
  check_serial_input();
  if (ch == '\n')
    serial_out('\r');
  check_serial_input();
  while ((*(volatile unsigned *)0xFF000000 != 0)) {
    set_leds(0);
    check_serial_input();
  }
  (*(volatile unsigned *)0xFF000000 = (ch));
  set_leds(ch);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<serial_out>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <check_serial_input@plt>
  cmp    $0xa,%ebp
  je     L4
L46:
  xor    %eax,%eax
  mov    $0xff000000,%ebx
  call   <check_serial_input@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L12
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %edi,%edi
  call   <set_leds@plt>
  xor    %eax,%eax
  call   <check_serial_input@plt>
  mov    (%rbx),%edx
  test   %edx,%edx
  jne    L45
L12:
  mov    %ebp,%eax
  mov    %ebp,%edi
  movabs %eax,0xff000000
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <set_leds@plt>
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  mov    $0xff000000,%ebx
  call   <check_serial_input@plt>
  xor    %eax,%eax
  call   <check_serial_input@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L23
  nopl   0x0(%rax)
L11:
  xor    %edi,%edi
  call   <set_leds@plt>
  xor    %eax,%eax
  call   <check_serial_input@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L11
L23:
  mov    $0xff000000,%eax
  mov    $0xd,%edi
  movl   $0xd,(%rax)
  call   <set_leds@plt>
  jmp    L46
```

assistant: ```c
void serial_out(unsigned ch) {
  check_serial_input();
  if (ch == '\n')
    serial_out('\r');
  check_serial_input();
  while ((*(volatile unsigned *)0xFF000000 != 0)) {
    set_leds(0);
    check_serial_input();
  }
  (*(volatile unsigned *)0xFF000000 = (ch));
  set_leds(ch);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reccursive_natural_till_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L5
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <reccursive_natural_till_0>
  jmp    L2
L5:
  mov    $0x0,%eax
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: %d


assistant: ```c
int reccursive_natural_till_0(int num) {
  if (num >= 0)
    printf("%d\n", num);
  else
    return 0;
  reccursive_natural_till_0(num - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reccursive_natural_till_0>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L0
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    -0x1(%rbx),%edi
  call   <reccursive_natural_till_0>
  pop    %rbx
  ret
L0:
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int reccursive_natural_till_0(int num) {
  if (num >= 0)
    printf("%d\n", num);
  else
    return 0;
  reccursive_natural_till_0(num - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reccursive_natural_till_0>:
  endbr64
  test   %edi,%edi
  js     L7
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jae    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string

tool: D7: %d


assistant: ```c
int reccursive_natural_till_0(int num) {
  if (num >= 0)
    printf("%d\n", num);
  else
    return 0;
  reccursive_natural_till_0(num - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<reccursive_natural_till_0>:
  endbr64
  test   %edi,%edi
  js     L19
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jae    L16
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string

tool: D8: %d


assistant: ```c
int reccursive_natural_till_0(int num) {
  if (num >= 0)
    printf("%d\n", num);
  else
    return 0;
  reccursive_natural_till_0(num - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_operator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x2a,%eax
  cmp    $0x16,%eax
  ja     L17
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D4(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x8(%rbp),%rax
  mov    $0x2b,%esi
  mov    %rax,%rdi
  call   <do_binop@plt>
  jmp    L13
  mov    -0x8(%rbp),%rax
  mov    $0x2d,%esi
  mov    %rax,%rdi
  call   <do_binop@plt>
  jmp    L13
  mov    -0x8(%rbp),%rax
  mov    $0x2a,%esi
  mov    %rax,%rdi
  call   <do_binop@plt>
  jmp    L13
  mov    -0x8(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <do_binop@plt>
  jmp    L13
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <do_print@plt>
  jmp    L13
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <do_clear@plt>
  jmp    L13
L17:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <err_operator@plt>
  nop
L13:
  nop
  leave
  ret
```

assistant: ```c
void do_operator(struct stack *stackRpn, char *oper) {
  switch (*oper) {
  case '+':
    do_binop(stackRpn, '+');
    break;
  case '-':
    do_binop(stackRpn, '-');
    break;
  case '*':
    do_binop(stackRpn, '*');
    break;
  case '/':
    do_binop(stackRpn, '/');
    break;
  case ';':
    do_print(stackRpn);
    break;
  case '@':
    do_clear(stackRpn);
    break;
  default:
    err_operator(oper);
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_operator>:
  endbr64
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  sub    $0x2a,%eax
  cmp    $0x16,%al
  ja     L28
  movzbl %al,%eax
  lea    D9(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2b,%esi
  call   <do_binop@plt>
L56:
  add    $0x8,%rsp
  ret
  mov    $0x2d,%esi
  call   <do_binop@plt>
  jmp    L56
  mov    $0x2a,%esi
  call   <do_binop@plt>
  jmp    L56
  mov    $0x2f,%esi
  call   <do_binop@plt>
  jmp    L56
  call   <do_print@plt>
  jmp    L56
  call   <do_clear@plt>
  jmp    L56
L28:
  mov    %rsi,%rdi
  call   <err_operator@plt>
  jmp    L56
```

assistant: ```c
void do_operator(struct stack *stackRpn, char *oper) {
  switch (*oper) {
  case '+':
    do_binop(stackRpn, '+');
    break;
  case '-':
    do_binop(stackRpn, '-');
    break;
  case '*':
    do_binop(stackRpn, '*');
    break;
  case '/':
    do_binop(stackRpn, '/');
    break;
  case ';':
    do_print(stackRpn);
    break;
  case '@':
    do_clear(stackRpn);
    break;
  default:
    err_operator(oper);
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_operator>:
  endbr64
  movzbl (%rsi),%eax
  sub    $0x2a,%eax
  cmp    $0x16,%al
  ja     L4
  lea    D9(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rsi,%rdi
  jmp    10b0 <err_operator@plt>
  mov    $0x2a,%esi
  jmp    1090 <do_binop@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2b,%esi
  jmp    1090 <do_binop@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2d,%esi
  jmp    1090 <do_binop@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2f,%esi
  jmp    1090 <do_binop@plt>
  nopw   0x0(%rax,%rax,1)
  jmp    10a0 <do_print@plt>
  nopl   (%rax)
  jmp    1080 <do_clear@plt>
```

assistant: ```c
void do_operator(struct stack *stackRpn, char *oper) {
  switch (*oper) {
  case '+':
    do_binop(stackRpn, '+');
    break;
  case '-':
    do_binop(stackRpn, '-');
    break;
  case '*':
    do_binop(stackRpn, '*');
    break;
  case '/':
    do_binop(stackRpn, '/');
    break;
  case ';':
    do_print(stackRpn);
    break;
  case '@':
    do_clear(stackRpn);
    break;
  default:
    err_operator(oper);
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_operator>:
  endbr64
  movzbl (%rsi),%eax
  sub    $0x2a,%eax
  cmp    $0x16,%al
  ja     L5
  lea    D6(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rsi,%rdi
  jmp    10b0 <err_operator@plt>
  mov    $0x2a,%esi
  jmp    1090 <do_binop@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2b,%esi
  jmp    1090 <do_binop@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2d,%esi
  jmp    1090 <do_binop@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2f,%esi
  jmp    1090 <do_binop@plt>
  nopw   0x0(%rax,%rax,1)
  jmp    10a0 <do_print@plt>
  nopl   (%rax)
  jmp    1080 <do_clear@plt>
```

assistant: ```c
void do_operator(struct stack *stackRpn, char *oper) {
  switch (*oper) {
  case '+':
    do_binop(stackRpn, '+');
    break;
  case '-':
    do_binop(stackRpn, '-');
    break;
  case '*':
    do_binop(stackRpn, '*');
    break;
  case '/':
    do_binop(stackRpn, '/');
    break;
  case ';':
    do_print(stackRpn);
    break;
  case '@':
    do_clear(stackRpn);
    break;
  default:
    err_operator(oper);
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x70,-0x1c(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x64,-0x1c(%rbp)
  je     L50
  cmpl   $0x70,-0x1c(%rbp)
  je     L3
  jmp    L46
L50:
  movl   $0xa,-0x20(%rbp)
  jmp    L59
L12:
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <debug_array@plt>
  addl   $0x1,-0x20(%rbp)
L59:
  cmpl   $0x63,-0x20(%rbp)
  jle    L12
  jmp    L46
L3:
  movq   $0xa,-0x18(%rbp)
  movq   $0x16,-0x10(%rbp)
  movq   $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x10,%edx
  mov    %rax,%rdi
  call   <report@plt>
  nop
L46:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: Hello, World!


assistant: ```c
int main(int argc, const char *argv[]) {
  int opt = 'p';
  printf("Hello, World!\n");
  switch (opt) {
  case 'd':
    for (int i = 10; i < 100; ++i)
      debug_array(i);
    break;
  case 'p': {
    size_t start = 10, end = 22, ntime = 4;
    report(start, end, sizeof(long double), ntime);
  } break;
  default:
    break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%ecx
  mov    $0x10,%edx
  mov    $0x16,%esi
  mov    $0xa,%edi
  call   <report@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: Hello, World!


assistant: ```c
int main(int argc, const char *argv[]) {
  int opt = 'p';
  printf("Hello, World!\n");
  switch (opt) {
  case 'd':
    for (int i = 10; i < 100; ++i)
      debug_array(i);
    break;
  case 'p': {
    size_t start = 10, end = 22, ntime = 4;
    report(start, end, sizeof(long double), ntime);
  } break;
  default:
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%ecx
  mov    $0x10,%edx
  mov    $0x16,%esi
  mov    $0xa,%edi
  call   <report@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: Hello, World!


assistant: ```c
int main(int argc, const char *argv[]) {
  int opt = 'p';
  printf("Hello, World!\n");
  switch (opt) {
  case 'd':
    for (int i = 10; i < 100; ++i)
      debug_array(i);
    break;
  case 'p': {
    size_t start = 10, end = 22, ntime = 4;
    report(start, end, sizeof(long double), ntime);
  } break;
  default:
    break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%ecx
  mov    $0x10,%edx
  mov    $0x16,%esi
  mov    $0xa,%edi
  call   <report@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string

tool: D8: Hello, World!


assistant: ```c
int main(int argc, const char *argv[]) {
  int opt = 'p';
  printf("Hello, World!\n");
  switch (opt) {
  case 'd':
    for (int i = 10; i < 100; ++i)
      debug_array(i);
    break;
  case 'p': {
    size_t start = 10, end = 22, ntime = 4;
    report(start, end, sizeof(long double), ntime);
  } break;
  default:
    break;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cterm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <dterm@plt>
  mov    $0x0,%eax
  call   <dterms@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cterm() {
  dterm();
  dterms();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cterm>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dterm@plt>
  mov    $0x0,%eax
  call   <dterms@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cterm() {
  dterm();
  dterms();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cterm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dterm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <dterms@plt>
```

assistant: ```c
void cterm() {
  dterm();
  dterms();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cterm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dterm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <dterms@plt>
```

assistant: ```c
void cterm() {
  dterm();
  dterms();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<opp_limit_to_ceiling>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L19
  mov    -0x14(%rbp),%eax
  mov    $0x7,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L19:
  movl   $0x0,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int opp_limit_to_ceiling(int limit) {
  unsigned int ceiling;
  if (limit >= 0)
    ceiling = (limit < 8 ? limit : 8 - 1);
  else
    ceiling = 0;
  return ceiling;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<opp_limit_to_ceiling>:
  endbr64
  mov    $0x7,%eax
  cmp    %eax,%edi
  cmovle %edi,%eax
  test   %eax,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
unsigned int opp_limit_to_ceiling(int limit) {
  unsigned int ceiling;
  if (limit >= 0)
    ceiling = (limit < 8 ? limit : 8 - 1);
  else
    ceiling = 0;
  return ceiling;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<opp_limit_to_ceiling>:
  endbr64
  mov    $0x7,%eax
  cmp    %eax,%edi
  cmovle %edi,%eax
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  ret
```

assistant: ```c
unsigned int opp_limit_to_ceiling(int limit) {
  unsigned int ceiling;
  if (limit >= 0)
    ceiling = (limit < 8 ? limit : 8 - 1);
  else
    ceiling = 0;
  return ceiling;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<floats_mat44_rotate_z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <floats_mat44_identity@plt>
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movss  -0x8(%rbp),%xmm0
  movss  D7(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x14,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x80]}

assistant: ```c
void floats_mat44_rotate_z(float rad, float out[16]) {
  floats_mat44_identity(out);
  float s = (float)sin(rad), c = (float)cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floats_mat44_rotate_z>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    %rdi,%rbx
  call   <floats_mat44_identity@plt>
  movss  0xc(%rsp),%xmm0
  call   <sin@plt>
  pxor   %xmm2,%xmm2
  cvtsi2ss %rax,%xmm2
  movd   %xmm2,%ebp
  movss  0xc(%rsp),%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%rbx)
  movd   %ebp,%xmm1
  xorps  D1(%rip),%xmm1
  movss  %xmm1,0x4(%rbx)
  mov    %ebp,0x10(%rbx)
  movss  %xmm0,0x14(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void floats_mat44_rotate_z(float rad, float out[16]) {
  floats_mat44_identity(out);
  float s = (float)sin(rad), c = (float)cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<floats_mat44_rotate_z>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <floats_mat44_identity@plt>
  movss  0x8(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  movss  %xmm1,0x8(%rsp)
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  movaps %xmm1,%xmm2
  xorps  D0(%rip),%xmm2
  movss  %xmm1,0x10(%rbx)
  movss  %xmm2,0x4(%rbx)
  movss  %xmm0,(%rbx)
  movss  %xmm0,0x14(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type: byte[16]

tool: {"D0": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void floats_mat44_rotate_z(float rad, float out[16]) {
  floats_mat44_identity(out);
  float s = (float)sin(rad), c = (float)cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: What is the c source code of the assembly code below?

```asm
<floats_mat44_rotate_z>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <floats_mat44_identity@plt>
  movss  0x8(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  movss  %xmm1,0x8(%rsp)
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  movaps %xmm1,%xmm3
  xorps  D1(%rip),%xmm3
  movaps %xmm0,%xmm2
  unpcklps %xmm0,%xmm1
  unpcklps %xmm3,%xmm2
  movlps %xmm1,0x10(%rbx)
  movlps %xmm2,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void floats_mat44_rotate_z(float rad, float out[16]) {
  floats_mat44_identity(out);
  float s = (float)sin(rad), c = (float)cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fatfs_get_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <FileString_GetExtension@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L17
  cmpq   $0x0,-0x20(%rbp)
  je     L17
  cmpl   $0x0,-0x24(%rbp)
  je     L17
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rax,-0x18(%rbp)
  jmp    L55
L65:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x40,-0x9(%rbp)
  jle    L2
  cmpb   $0x5a,-0x9(%rbp)
  jg     L2
  movzbl -0x9(%rbp),%eax
  add    $0x20,%eax
  mov    %al,-0x9(%rbp)
L2:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L55:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L79
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L65
L79:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L28
L17:
  mov    $0x0,%eax
L28:
  leave
  ret
```

assistant: ```c
int fatfs_get_extension(char *filename, char *out, int maxlen) {
  int len = 0;
  int ext_pos = FileString_GetExtension(filename);
  if (ext_pos > 0 && out && maxlen) {
    filename += ext_pos + 1;
    while (*filename && len < (maxlen - 1)) {
      char a = *filename++;
      if ((a >= 'A') && (a <= 'Z'))
        a += 32;
      *out++ = a;
      len++;
    }
    *out = '\0';
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<fatfs_get_extension>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  call   <FileString_GetExtension@plt>
  test   %rbx,%rbx
  setne  %cl
  test   %ebp,%ebp
  setne  %dl
  test   %dl,%cl
  je     L34
  test   %eax,%eax
  jg     L45
L34:
  mov    $0x0,%eax
L66:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  cltq
  lea    0x1(%r12,%rax,1),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L68
  cmp    $0x1,%ebp
  jle    L68
  lea    -0x2(%rbp),%ecx
  lea    0x1(%rbx,%rcx,1),%rdi
L33:
  add    $0x1,%rdx
  lea    -0x41(%rax),%esi
  lea    0x20(%rax),%ecx
  cmp    $0x1a,%sil
  cmovb  %ecx,%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movzbl (%rdx),%eax
  test   %al,%al
  je     L68
  cmp    %rdi,%rbx
  jne    L33
  mov    %rdi,%rbx
L68:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
  jmp    L66
```

assistant: ```c
int fatfs_get_extension(char *filename, char *out, int maxlen) {
  int len = 0;
  int ext_pos = FileString_GetExtension(filename);
  if (ext_pos > 0 && out && maxlen) {
    filename += ext_pos + 1;
    while (*filename && len < (maxlen - 1)) {
      char a = *filename++;
      if ((a >= 'A') && (a <= 'Z'))
        a += 32;
      *out++ = a;
      len++;
    }
    *out = '\0';
    return 1;
  }
  return 0;
}
```