ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_scramble>:
  endbr64
  mov    %rdi,%rax
  shr    $0x10,%rax
  xor    %rdi,%rax
  imul   $0x45d9f3b,%rax,%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  xor    %rax,%rdx
  imul   $0x45d9f3b,%rdx,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  xor    %rdx,%rax
  ret
```

assistant: ```c
size_t hash_scramble(size_t h) {
  h = ((h >> 16) ^ h) * 0x45d9f3b;
  h = ((h >> 16) ^ h) * 0x45d9f3b;
  h = (h >> 16) ^ h;
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_scramble>:
  endbr64
  mov    %rdi,%rax
  shr    $0x10,%rax
  xor    %rdi,%rax
  imul   $0x45d9f3b,%rax,%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  xor    %rax,%rdx
  imul   $0x45d9f3b,%rdx,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  xor    %rdx,%rax
  ret
```

assistant: ```c
size_t hash_scramble(size_t h) {
  h = ((h >> 16) ^ h) * 0x45d9f3b;
  h = ((h >> 16) ^ h) * 0x45d9f3b;
  h = (h >> 16) ^ h;
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x12c,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L5
L18:
  mov    -0x14(%rbp),%eax
  lea    -0x20(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L18
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D30
type_infered: string
name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D20
type_infered: string

tool: D30: celcius

tool: D2: fahrenheit

tool: D3: %s  %s


tool: D20: %10d  %7d


assistant: ```c
int main() {
  int fahr, celcius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  printf("%s  %s\n", "fahrenheit", "celcius");
  for (fahr = upper; fahr >= lower; fahr = fahr - step) {
    celcius = (5 * (fahr - 32)) / 9;
    printf("%10d  %7d\n", fahr, celcius);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D38(%rip),%rdx
  lea    D26(%rip),%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x53c,%ebp
  mov    $0x12c,%ebx
  lea    D29(%rip),%r12
L8:
  movslq %ebp,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x14,%ebx
  sub    $0x64,%ebp
  cmp    $0xffffffec,%ebx
  jne    L8
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D38
type_infered: string
name: parse_data
arguments: tag: D26
type_infered: string
name: parse_data
arguments: tag: D30
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: string

tool: D38: celcius

tool: D26: fahrenheit

tool: D30: %s  %s


tool: D29: %10d  %7d


assistant: ```c
int main() {
  int fahr, celcius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  printf("%s  %s\n", "fahrenheit", "celcius");
  for (fahr = upper; fahr >= lower; fahr = fahr - step) {
    celcius = (5 * (fahr - 32)) / 9;
    printf("%10d  %7d\n", fahr, celcius);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdx
  lea    D29(%rip),%rsi
  xor    %eax,%eax
  push   %rbp
  lea    D33(%rip),%rdi
  mov    $0x53c,%r12d
  lea    D6(%rip),%rbp
  push   %rbx
  mov    $0x12c,%ebx
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%eax
  sub    $0x14,%ebx
  sub    $0x64,%r12d
  sar    $0x21,%rdx
  sub    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xffffffec,%ebx
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type: string
name: read_data
arguments: tag: D29
type: string
name: read_data
arguments: tag: D33
type: string
name: read_data
arguments: tag: D6
type: string

tool: D11: celcius

tool: D29: fahrenheit

tool: D33: %s  %s


tool: D6: %10d  %7d


assistant: ```c
int main() {
  int fahr, celcius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  printf("%s  %s\n", "fahrenheit", "celcius");
  for (fahr = upper; fahr >= lower; fahr = fahr - step) {
    celcius = (5 * (fahr - 32)) / 9;
    printf("%10d  %7d\n", fahr, celcius);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D35(%rip),%rdx
  lea    D4(%rip),%rsi
  xor    %eax,%eax
  push   %rbp
  lea    D37(%rip),%rdi
  mov    $0x53c,%r12d
  lea    D14(%rip),%rbp
  push   %rbx
  mov    $0x12c,%ebx
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L5:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%eax
  sub    $0x14,%ebx
  sub    $0x64,%r12d
  sar    $0x21,%rdx
  sub    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xffffffec,%ebx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D35
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D37
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D35: celcius

tool: D4: fahrenheit

tool: D37: %s  %s


tool: D14: %10d  %7d


assistant: ```c
int main() {
  int fahr, celcius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  printf("%s  %s\n", "fahrenheit", "celcius");
  for (fahr = upper; fahr >= lower; fahr = fahr - step) {
    celcius = (5 * (fahr - 32)) / 9;
    printf("%10d  %7d\n", fahr, celcius);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Barcode_128c_verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    $0xffffffff,%eax
  jmp    L20
L33:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  and    $0x1,%eax
  test   %eax,%eax
  je     L40
  mov    $0xffffffff,%eax
  jmp    L20
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L42
  mov    $0xffffffff,%eax
  jmp    L20
L42:
  addq   $0x1,-0x8(%rbp)
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    $0x0,%eax
L20:
  leave
  ret
```

assistant: ```c
int Barcode_128c_verify(unsigned char *text) {
  if (text[0] == '\0')
    return -1;
  if (strlen(text) % 2)
    return -1;
  for (; *text; text++)
    if (!isdigit(*text))
      return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Barcode_128c_verify>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L27
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   $0x1,%al
  jne    L8
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L53
L61:
  movzbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L57
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L61
  mov    $0x0,%eax
  jmp    L78
L27:
  mov    $0xffffffff,%eax
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L78
L53:
  mov    $0x0,%eax
  jmp    L78
L57:
  mov    $0xffffffff,%eax
L78:
  pop    %rbx
  ret
```

assistant: ```c
int Barcode_128c_verify(unsigned char *text) {
  if (text[0] == '\0')
    return -1;
  if (strlen(text) % 2)
    return -1;
  for (; *text; text++)
    if (!isdigit(*text))
      return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Barcode_128c_verify>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L23
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   $0x1,%al
  je     L20
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L43:
  call   <isdigit@plt>
  test   %eax,%eax
  je     L39
  add    $0x1,%rbx
L20:
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L43
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L39:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
L23:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int Barcode_128c_verify(unsigned char *text) {
  if (text[0] == '\0')
    return -1;
  if (strlen(text) % 2)
    return -1;
  for (; *text; text++)
    if (!isdigit(*text))
      return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Barcode_128c_verify>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L25
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   $0x1,%al
  je     L12
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L8:
  call   <isdigit@plt>
  test   %eax,%eax
  je     L41
  add    $0x1,%rbx
L12:
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L8
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L41:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
L25:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int Barcode_128c_verify(unsigned char *text) {
  if (text[0] == '\0')
    return -1;
  if (strlen(text) % 2)
    return -1;
  for (; *text; text++)
    if (!isdigit(*text))
      return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_add_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L13:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L13
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x20(%rbp),%eax
  mov    %al,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void str_add_char(char *S, int n, char a) {
  int len = strlen(S);
  for (int i = len; i >= n; i--) {
    S[i + 1] = S[i];
  }
  S[n] = a;
}
```
user: What is the c source code of the assembly code below:

```asm
<str_add_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L7
  movslq %eax,%rcx
  lea    0x0(%rbp,%rcx,1),%rdx
  lea    -0x1(%rbp,%rcx,1),%rcx
  sub    %ebx,%eax
  sub    %rax,%rcx
L4:
  movzbl (%rdx),%eax
  mov    %al,0x1(%rdx)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L4
L7:
  movslq %ebx,%rbx
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void str_add_char(char *S, int n, char a) {
  int len = strlen(S);
  for (int i = len; i >= n; i--) {
    S[i + 1] = S[i];
  }
  S[n] = a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_add_char>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L1
  mov    %eax,%edx
  cltq
  sub    %ebx,%edx
  mov    %rax,%rsi
  add    $0x1,%rax
  sub    %rdx,%rsi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L1:
  mov    %bpl,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void str_add_char(char *S, int n, char a) {
  int len = strlen(S);
  for (int i = len; i >= n; i--) {
    S[i + 1] = S[i];
  }
  S[n] = a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_add_char>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L7
  mov    %eax,%edx
  cltq
  sub    %ebx,%edx
  mov    %rax,%rsi
  add    $0x1,%rax
  sub    %rdx,%rsi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L7:
  mov    %bpl,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void str_add_char(char *S, int n, char a) {
  int len = strlen(S);
  for (int i = len; i >= n; i--) {
    S[i + 1] = S[i];
  }
  S[n] = a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fil_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x48(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x50(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L43
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <plintf@plt>
  mov    $0x0,%eax
  jmp    L26
L43:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L85
L80:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <IsDirectory@plt>
  test   %rax,%rax
  je     L49
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L27
  mov    -0x48(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L27
L49:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <wild_match@plt>
  test   %rax,%rax
  je     L27
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L27
  mov    -0x50(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
L27:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x10(%rbp)
L85:
  cmpq   $0x0,-0x10(%rbp)
  jne    L80
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    $0x1,%eax
L26:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9:  % is not a directory 


assistant: ```c
int fil_count(const char *direct, int *ndir, int *nfil, const char *wild, int *mld, int *mlf) {
  DIR *dirp;
  int l;
  struct dirent *dp;
  *mld = 0;
  *mlf = 0;
  dirp = opendir(direct);
  if (dirp == NULL) {
    plintf(" % is not a directory \n", direct);
    return 0;
  }
  dp = readdir(dirp);
  *ndir = 0;
  *nfil = 0;
  while (dp != NULL) {
    if (IsDirectory(direct, dp->d_name)) {
      *ndir = *ndir + 1;
      l = strlen(dp->d_name);
      if (l > *mld)
        *mld = l;
    } else {
      if (wild_match(dp->d_name, wild)) {
        *nfil = *nfil + 1;
        l = strlen(dp->d_name);
        if (l > *mlf)
          *mlf = l;
      }
    }
    dp = readdir(dirp);
  }
  closedir(dirp);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fil_count>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r15
  mov    %rcx,(%rsp)
  mov    %r8,%r14
  mov    %r9,0x8(%rsp)
  movl   $0x0,(%r8)
  movl   $0x0,(%r9)
  call   <opendir@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  movl   $0x0,0x0(%r13)
  movl   $0x0,(%r15)
  test   %rax,%rax
  jne    L99
L32:
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    $0x1,%eax
L35:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  mov    %r12,%rsi
  lea    D1(%rip),%rdi
  call   <plintf@plt>
  mov    $0x0,%eax
  jmp    L35
L68:
  mov    (%rsp),%rsi
  mov    (%rbx),%edi
  call   <wild_match@plt>
  test   %rax,%rax
  jne    L58
L95:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L32
L99:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <IsDirectory@plt>
  test   %rax,%rax
  je     L68
  addl   $0x1,0x0(%r13)
  mov    (%rbx),%edi
  call   <strlen@plt>
  cmp    %eax,(%r14)
  jge    L95
  mov    %eax,(%r14)
  jmp    L95
L58:
  addl   $0x1,(%r15)
  mov    (%rbx),%edi
  call   <strlen@plt>
  mov    0x8(%rsp),%rdx
  cmp    %eax,(%rdx)
  jge    L95
  mov    %eax,(%rdx)
  jmp    L95
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1:  % is not a directory 


assistant: ```c
int fil_count(const char *direct, int *ndir, int *nfil, const char *wild, int *mld, int *mlf) {
  DIR *dirp;
  int l;
  struct dirent *dp;
  *mld = 0;
  *mlf = 0;
  dirp = opendir(direct);
  if (dirp == NULL) {
    plintf(" % is not a directory \n", direct);
    return 0;
  }
  dp = readdir(dirp);
  *ndir = 0;
  *nfil = 0;
  while (dp != NULL) {
    if (IsDirectory(direct, dp->d_name)) {
      *ndir = *ndir + 1;
      l = strlen(dp->d_name);
      if (l > *mld)
        *mld = l;
    } else {
      if (wild_match(dp->d_name, wild)) {
        *nfil = *nfil + 1;
        l = strlen(dp->d_name);
        if (l > *mlf)
          *mlf = l;
      }
    }
    dp = readdir(dirp);
  }
  closedir(dirp);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fil_count>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movl   $0x0,(%r8)
  movl   $0x0,(%r9)
  mov    %rdx,(%rsp)
  mov    %r9,0x8(%rsp)
  call   <opendir@plt>
  test   %rax,%rax
  je     L36
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <readdir@plt>
  movl   $0x0,(%rbx)
  mov    %rax,%r15
  mov    (%rsp),%rax
  movl   $0x0,(%rax)
  test   %r15,%r15
  jne    L70
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L75:
  addl   $0x1,(%rbx)
  mov    (%r15),%edi
  call   <strlen@plt>
  cmp    %eax,0x0(%r13)
  jge    L50
  mov    %eax,0x0(%r13)
L50:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L49
L70:
  mov    (%r15),%esi
  mov    %r12,%rdi
  call   <IsDirectory@plt>
  test   %rax,%rax
  jne    L75
  mov    (%r15),%edi
  mov    %r14,%rsi
  call   <wild_match@plt>
  test   %rax,%rax
  je     L50
  mov    (%rsp),%rax
  addl   $0x1,(%rax)
  mov    (%r15),%edi
  call   <strlen@plt>
  mov    0x8(%rsp),%rdx
  cmp    %eax,(%rdx)
  jge    L50
  mov    %eax,(%rdx)
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L70
L49:
  mov    %rbp,%rdi
  call   <closedir@plt>
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  call   <plintf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0:  % is not a directory 


assistant: ```c
int fil_count(const char *direct, int *ndir, int *nfil, const char *wild, int *mld, int *mlf) {
  DIR *dirp;
  int l;
  struct dirent *dp;
  *mld = 0;
  *mlf = 0;
  dirp = opendir(direct);
  if (dirp == NULL) {
    plintf(" % is not a directory \n", direct);
    return 0;
  }
  dp = readdir(dirp);
  *ndir = 0;
  *nfil = 0;
  while (dp != NULL) {
    if (IsDirectory(direct, dp->d_name)) {
      *ndir = *ndir + 1;
      l = strlen(dp->d_name);
      if (l > *mld)
        *mld = l;
    } else {
      if (wild_match(dp->d_name, wild)) {
        *nfil = *nfil + 1;
        l = strlen(dp->d_name);
        if (l > *mlf)
          *mlf = l;
      }
    }
    dp = readdir(dirp);
  }
  closedir(dirp);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fil_count>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movl   $0x0,(%r8)
  movl   $0x0,(%r9)
  mov    %rdx,(%rsp)
  mov    %r9,0x8(%rsp)
  call   <opendir@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <readdir@plt>
  movl   $0x0,(%rbx)
  mov    %rax,%r15
  mov    (%rsp),%rax
  movl   $0x0,(%rax)
  test   %r15,%r15
  jne    L65
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L8:
  addl   $0x1,(%rbx)
  mov    (%r15),%edi
  call   <strlen@plt>
  cmp    %eax,0x0(%r13)
  jge    L22
  mov    %eax,0x0(%r13)
L22:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L10
L65:
  mov    (%r15),%esi
  mov    %r12,%rdi
  call   <IsDirectory@plt>
  test   %rax,%rax
  jne    L8
  mov    (%r15),%edi
  mov    %r14,%rsi
  call   <wild_match@plt>
  test   %rax,%rax
  je     L22
  mov    (%rsp),%rax
  addl   $0x1,(%rax)
  mov    (%r15),%edi
  call   <strlen@plt>
  mov    0x8(%rsp),%rdx
  cmp    %eax,(%rdx)
  jge    L22
  mov    %eax,(%rdx)
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L65
L10:
  mov    %rbp,%rdi
  call   <closedir@plt>
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rsi
  lea    D3(%rip),%rdi
  call   <plintf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3:  % is not a directory 


assistant: ```c
int fil_count(const char *direct, int *ndir, int *nfil, const char *wild, int *mld, int *mlf) {
  DIR *dirp;
  int l;
  struct dirent *dp;
  *mld = 0;
  *mlf = 0;
  dirp = opendir(direct);
  if (dirp == NULL) {
    plintf(" % is not a directory \n", direct);
    return 0;
  }
  dp = readdir(dirp);
  *ndir = 0;
  *nfil = 0;
  while (dp != NULL) {
    if (IsDirectory(direct, dp->d_name)) {
      *ndir = *ndir + 1;
      l = strlen(dp->d_name);
      if (l > *mld)
        *mld = l;
    } else {
      if (wild_match(dp->d_name, wild)) {
        *nfil = *nfil + 1;
        l = strlen(dp->d_name);
        if (l > *mlf)
          *mlf = l;
      }
    }
    dp = readdir(dirp);
  }
  closedir(dirp);
  return 1;
}
```