user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x0,-0x10(%rbp)
  movl   $0x5,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L39
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L39:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L9
L0:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L32
L35:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L35
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D53
datatype: string
name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D33
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D52
datatype: string
name: read_data
arguments: tag: D64
datatype: string

tool: D53: please input the number of element: %d


tool: D3: out of memory, press any key to quit...

tool: D33: malloc array init: %d %o 0x%x


tool: D24: calloc array init: %d %o 0x%x


tool: D22: please input %d elements:


tool: D18: %d elements are:


tool: D52: %d,

tool: D64:  

assistant: ```c
void main() {
  int *array = 0, num = 5, i;
  int *carray;
  printf("please input the number of element: %d\n", num);
  array = (int *)malloc(sizeof(int) * num);
  carray = (int *)calloc(sizeof(int), num + 1);
  if (array == 0) {
    printf("out of memory, press any key to quit...\n");
    exit(0);
  }
  printf("malloc array init: %d %o 0x%x\n", array[0], array[1], array[num]);
  printf("calloc array init: %d %o 0x%x\n", carray[0], carray[1], carray[2]);
  printf("please input %d elements:\n", num);
  for (i = 0; i < num; i++) {
    array[i] = num + i;
  }
  printf("%d elements are:\n", num);
  for (i = 0; i < num; i++) {
    printf("%d,", array[i]);
  }
  printf("\b \n");
  free(array);
}
```