ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<QSort1>:
  endbr64
  cmp    %edx,%esi
  jge    L71
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %edx,%r15d
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  mov    (%rax),%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
  jmp    L30
L24:
  cmp    %ebp,%ebx
  jle    L75
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%rax
L42:
  cmp    %r12d,(%rax)
  jg     L74
  add    $0x1,%ebp
  add    $0x4,%rax
  cmp    %ebx,%ebp
  jne    L42
  mov    %ebx,%ebp
L75:
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%rsi
  mov    0x8(%rsp),%rdi
  call   <Swap@plt>
  lea    -0x1(%rbp),%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <QSort1>
  lea    0x1(%rbx),%esi
  mov    %r15d,%edx
  mov    %r13,%rdi
  call   <QSort1>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  cmp    %ebx,%ebp
  jge    L75
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%rdi
  call   <Swap@plt>
L30:
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,4),%rsi
  cmp    %r12d,(%rsi)
  jl     L24
  sub    $0x1,%ebx
  cmp    %ebp,%ebx
  jg     L30
  jmp    L75
L71:
  ret
```

assistant: ```c
void QSort1(int a[], int left, int right) {
  if (left < right) {
    int i = left, j = right;
    int pivot = a[left];
    while (i < j) {
      while (i < j && a[j] >= pivot)
        j--;
      while (i < j && a[i] <= pivot)
        i++;
      if (i < j) {
        Swap(a + i, a + j);
      }
    }
    Swap(a + left, a + i);
    QSort1(a, left, i - 1);
    QSort1(a, j + 1, right);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<QSort1>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %esi,%edx
  jle    L39
L31:
  movslq %r12d,%rax
  mov    0xc(%rsp),%ebp
  movslq %r12d,%rbx
  lea    (%r14,%rax,4),%r13
  mov    0x0(%r13),%r15d
  cs nopw 0x0(%rax,%rax,1)
L48:
  movslq %ebp,%rax
  lea    (%r14,%rax,4),%rsi
  jmp    L97
  nopl   0x0(%rax)
L118:
  mov    %eax,%ebp
L97:
  cmp    %r15d,(%rsi)
  jl     L7
  lea    -0x1(%rbp),%eax
  sub    $0x4,%rsi
  cmp    %ebx,%eax
  jg     L118
  lea    -0x1(%rbx),%r15d
L68:
  lea    (%r14,%rbx,4),%rsi
  mov    %r13,%rdi
  call   <Swap@plt>
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <QSort1>
  cmp    %ebp,0xc(%rsp)
  jle    L39
  mov    %ebp,%r12d
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    %ebp,%ebx
  jge    L89
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%rdi
  jmp    L126
  nopl   (%rax)
L127:
  lea    0x1(%rbx),%eax
  add    $0x4,%rdi
  cmp    %ebp,%eax
  je     L15
  movslq %eax,%rbx
L126:
  cmp    %r15d,(%rdi)
  jle    L127
  call   <Swap@plt>
  cmp    %ebp,%ebx
  jl     L48
L89:
  lea    -0x1(%rbx),%r15d
  add    $0x1,%ebp
  jmp    L68
  nopl   (%rax)
L15:
  lea    0x2(%rbx),%eax
  mov    %ebx,%r15d
  movslq %ebp,%rbx
  mov    %eax,%ebp
  jmp    L68
L39:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void QSort1(int a[], int left, int right) {
  if (left < right) {
    int i = left, j = right;
    int pivot = a[left];
    while (i < j) {
      while (i < j && a[j] >= pivot)
        j--;
      while (i < j && a[i] <= pivot)
        i++;
      if (i < j) {
        Swap(a + i, a + j);
      }
    }
    Swap(a + left, a + i);
    QSort1(a, left, i - 1);
    QSort1(a, j + 1, right);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<QSort1>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %esi,%edx
  jle    L10
L46:
  movslq %r12d,%rax
  mov    0xc(%rsp),%ebp
  movslq %r12d,%rbx
  lea    (%r14,%rax,4),%r13
  mov    0x0(%r13),%r15d
  cs nopw 0x0(%rax,%rax,1)
L26:
  movslq %ebp,%rax
  lea    (%r14,%rax,4),%rsi
  jmp    L13
  nopl   0x0(%rax)
L28:
  mov    %eax,%ebp
L13:
  cmp    %r15d,(%rsi)
  jl     L8
  lea    -0x1(%rbp),%eax
  sub    $0x4,%rsi
  cmp    %ebx,%eax
  jg     L28
  lea    -0x1(%rbx),%r15d
L118:
  lea    (%r14,%rbx,4),%rsi
  mov    %r13,%rdi
  call   <Swap@plt>
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <QSort1>
  cmp    %ebp,0xc(%rsp)
  jle    L10
  mov    %ebp,%r12d
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    %ebp,%ebx
  jge    L25
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%rdi
  jmp    L106
  nopl   (%rax)
L32:
  lea    0x1(%rbx),%eax
  add    $0x4,%rdi
  cmp    %ebp,%eax
  je     L6
  movslq %eax,%rbx
L106:
  cmp    %r15d,(%rdi)
  jle    L32
  call   <Swap@plt>
  cmp    %ebp,%ebx
  jl     L26
L25:
  lea    -0x1(%rbx),%r15d
  add    $0x1,%ebp
  jmp    L118
  nopl   (%rax)
L6:
  lea    0x2(%rbx),%eax
  mov    %ebx,%r15d
  movslq %ebp,%rbx
  mov    %eax,%ebp
  jmp    L118
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void QSort1(int a[], int left, int right) {
  if (left < right) {
    int i = left, j = right;
    int pivot = a[left];
    while (i < j) {
      while (i < j && a[j] >= pivot)
        j--;
      while (i < j && a[i] <= pivot)
        i++;
      if (i < j) {
        Swap(a + i, a + j);
      }
    }
    Swap(a + left, a + i);
    QSort1(a, left, i - 1);
    QSort1(a, j + 1, right);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<suffix_change>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L38
L19:
  subl   $0x1,-0x4(%rbp)
L38:
  cmpl   $0x0,-0x4(%rbp)
  je     L16
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L19
L16:
  cmpl   $0x0,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  nop
  leave
  ret
```

assistant: ```c
void suffix_change(char *name, char *suffix) {
  int j;
  j = strlen(name) - 1;
  while (j && name[j - 1] != '.')
    j--;
  if (j)
    name[j - 1] = '\0';
  strcat(name, suffix);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<suffix_change>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  sub    $0x1,%eax
  je     L24
  cltq
L34:
  cmpb   $0x2e,-0x1(%rbx,%rax,1)
  je     L2
  sub    $0x1,%rax
  test   %eax,%eax
  jne    L34
  jmp    L24
L2:
  test   %eax,%eax
  je     L24
  movslq %eax,%rdx
  movb   $0x0,-0x1(%rbx,%rdx,1)
L24:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void suffix_change(char *name, char *suffix) {
  int j;
  j = strlen(name) - 1;
  while (j && name[j - 1] != '.')
    j--;
  if (j)
    name[j - 1] = '\0';
  strcat(name, suffix);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<suffix_change>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%eax
  je     L35
  cltq
  lea    -0x1(%rbp,%rax,1),%rdx
  movslq %ecx,%rax
  sub    $0x2,%ecx
  lea    -0x3(%rbp,%rax,1),%rax
  sub    %rcx,%rax
  jmp    L2
  nopl   0x0(%rax)
L34:
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L35
L2:
  cmpb   $0x2e,(%rdx)
  jne    L34
  movb   $0x0,(%rdx)
L35:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcat@plt>
```

assistant: ```c
void suffix_change(char *name, char *suffix) {
  int j;
  j = strlen(name) - 1;
  while (j && name[j - 1] != '.')
    j--;
  if (j)
    name[j - 1] = '\0';
  strcat(name, suffix);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<suffix_change>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%eax
  je     L0
  cltq
  lea    -0x1(%rbp,%rax,1),%rdx
  movslq %ecx,%rax
  sub    $0x2,%ecx
  lea    -0x3(%rbp,%rax,1),%rax
  sub    %rcx,%rax
  jmp    L17
  nopl   0x0(%rax)
L4:
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L0
L17:
  cmpb   $0x2e,(%rdx)
  jne    L4
  movb   $0x0,(%rdx)
L0:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcat@plt>
```

assistant: ```c
void suffix_change(char *name, char *suffix) {
  int j;
  j = strlen(name) - 1;
  while (j && name[j - 1] != '.')
    j--;
  if (j)
    name[j - 1] = '\0';
  strcat(name, suffix);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<config_change_prefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <gui_chat_prefix_build@plt>
  nop
  leave
  ret
```

assistant: ```c
void config_change_prefix(void *data, struct t_config_option *option) {
  (void)data;
  (void)option;
  gui_chat_prefix_build();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<config_change_prefix>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gui_chat_prefix_build@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void config_change_prefix(void *data, struct t_config_option *option) {
  (void)data;
  (void)option;
  gui_chat_prefix_build();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<config_change_prefix>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <gui_chat_prefix_build@plt>
```

assistant: ```c
void config_change_prefix(void *data, struct t_config_option *option) {
  (void)data;
  (void)option;
  gui_chat_prefix_build();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<config_change_prefix>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <gui_chat_prefix_build@plt>
```

assistant: ```c
void config_change_prefix(void *data, struct t_config_option *option) {
  (void)data;
  (void)option;
  gui_chat_prefix_build();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_adc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x0,-0xa(%rbp)
  lea    -0xa(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    $0x2,%eax
  je     L33
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L12
L33:
  movzbl -0xa(%rbp),%eax
  movsbl %al,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  sar    $0x4,%al
  movsbl %al,%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  and    $0x800,%eax
  test   %eax,%eax
  je     L22
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
L22:
  mov    $0x0,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string

tool: D7: Adafruit_ADS1015: Failed to read data

assistant: ```c
int read_adc(int fd, int *data) {
  char buf[2] = {0};
  if (read(fd, buf, 2) != 2) {
    printf("Adafruit_ADS1015: Failed to read data");
    return -1;
  }
  *data = ((int)buf[0]) << 4 | ((int)buf[1]) >> 4;
  if ((*data & 0x800) != 0)
    *data = (*data || 0x7FF);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_adc>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x0,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  mov    $0x2,%edx
  call   <read@plt>
  cmp    $0x2,%eax
  jne    L43
  movsbl 0x6(%rsp),%eax
  shl    $0x4,%eax
  movzbl 0x7(%rsp),%edx
  sar    $0x4,%dl
  movsbl %dl,%edx
  or     %edx,%eax
  mov    %eax,%edx
  and    $0x800,%edx
  jne    L42
  mov    %eax,(%rbx)
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L43:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edx
  jmp    L46
L42:
  movl   $0x1,(%rbx)
  mov    $0x0,%edx
  jmp    L46
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string

tool: D7: Adafruit_ADS1015: Failed to read data

assistant: ```c
int read_adc(int fd, int *data) {
  char buf[2] = {0};
  if (read(fd, buf, 2) != 2) {
    printf("Adafruit_ADS1015: Failed to read data");
    return -1;
  }
  *data = ((int)buf[0]) << 4 | ((int)buf[1]) >> 4;
  if ((*data & 0x800) != 0)
    *data = (*data || 0x7FF);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_adc>:
  endbr64
  push   %rbx
  mov    $0x2,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rsi
  xor    %eax,%eax
  mov    %ax,0x6(%rsp)
  call   <read@plt>
  cmp    $0x2,%eax
  jne    L19
  movzbl 0x7(%rsp),%edx
  movsbl 0x6(%rsp),%eax
  sar    $0x4,%dl
  shl    $0x4,%eax
  movsbl %dl,%edx
  or     %edx,%eax
  mov    %eax,%r8d
  and    $0x800,%r8d
  jne    L24
  mov    %eax,(%rbx)
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  movl   $0x1,(%rbx)
  xor    %r8d,%r8d
  jmp    L42
L19:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%r8d
  jmp    L42
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: Adafruit_ADS1015: Failed to read data

assistant: ```c
int read_adc(int fd, int *data) {
  char buf[2] = {0};
  if (read(fd, buf, 2) != 2) {
    printf("Adafruit_ADS1015: Failed to read data");
    return -1;
  }
  *data = ((int)buf[0]) << 4 | ((int)buf[1]) >> 4;
  if ((*data & 0x800) != 0)
    *data = (*data || 0x7FF);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_adc>:
  endbr64
  push   %rbx
  mov    $0x2,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rsi
  xor    %eax,%eax
  mov    %ax,0x6(%rsp)
  call   <read@plt>
  cmp    $0x2,%eax
  jne    L8
  movzbl 0x7(%rsp),%edx
  movsbl 0x6(%rsp),%eax
  sar    $0x4,%dl
  shl    $0x4,%eax
  movsbl %dl,%edx
  or     %edx,%eax
  mov    %eax,%r8d
  and    $0x800,%r8d
  jne    L23
  mov    %eax,(%rbx)
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  movl   $0x1,(%rbx)
  xor    %r8d,%r8d
  jmp    L19
L8:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%r8d
  jmp    L19
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string

tool: D6: Adafruit_ADS1015: Failed to read data

assistant: ```c
int read_adc(int fd, int *data) {
  char buf[2] = {0};
  if (read(fd, buf, 2) != 2) {
    printf("Adafruit_ADS1015: Failed to read data");
    return -1;
  }
  *data = ((int)buf[0]) << 4 | ((int)buf[1]) >> 4;
  if ((*data & 0x800) != 0)
    *data = (*data || 0x7FF);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  cmp    $0x2,%edi
  je     L55
L3:
  mov    0xc(%rsp),%edi
  mov    $0x0,%eax
  call   <validate_range@plt>
  test   %eax,%eax
  je     L33
  mov    0xc(%rsp),%eax
  mov    $0x4,%ebx
  cltd
  idiv   %ebx
  mov    %edx,0x10(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <generate_numbers@plt>
  mov    0x10(%rsp),%eax
  add    $0x2,%eax
  cltd
  idiv   %ebx
  mov    %edx,0x40(%rsp)
  lea    0x40(%rsp),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <generate_numbers@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <print_first@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print_second@plt>
  mov    0xc(%rsp),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <print_combinations@plt>
  mov    $0x0,%eax
L42:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  mov    %rsi,%rbx
  lea    0xc(%rsp),%rdx
  mov    0x8(%rsi),%rdi
  lea    D27(%rip),%rsi
  call   <sscanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jne    L3
  mov    0x8(%rbx),%rax
  cmpb   $0x30,(%rax)
  je     L3
  movl   $0xffffffff,0xc(%rsp)
  jmp    L3
L33:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0x27,%edx
  mov    $0x0,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L42
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D25
datatype: string

tool: D27: %2d

tool: D19: Usage: ./lockpro THIRD

tool: D25: THIRD should be an integer between %d and %d.


assistant: ```c
int main(int argc, char **argv) {
  int first[10] = {0}, second[10] = {0}, third = -1;
  if (argc == 2) {
    sscanf(argv[1], "%2d", &third);
    if (third == 0 && argv[1][0] != '0')
      third = -1;
  }
  if (!validate_range(third)) {
    printf("Usage: ./lockpro THIRD\n");
    printf("THIRD should be an integer between %d and %d.\n", 0, 39);
    return 1;
  }
  first[0] = third % 4;
  generate_numbers(first);
  second[0] = (first[0] + 2) % 4;
  generate_numbers(second);
  print_first(first);
  print_second(second, third);
  print_combinations(first, second, third);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %edi,%r8d
  mov    $0xffffffff,%edi
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0xc(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x60(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  cmp    $0x2,%r8d
  je     L34
L14:
  xor    %eax,%eax
  call   <validate_range@plt>
  test   %eax,%eax
  je     L56
  mov    0xc(%rsp),%eax
  mov    $0x4,%ebx
  lea    0x10(%rsp),%rbp
  lea    0x40(%rsp),%r12
  mov    %rbp,%rdi
  cltd
  idiv   %ebx
  xor    %eax,%eax
  mov    %edx,0x10(%rsp)
  call   <generate_numbers@plt>
  mov    0x10(%rsp),%eax
  mov    %r12,%rdi
  add    $0x2,%eax
  cltd
  idiv   %ebx
  xor    %eax,%eax
  mov    %edx,0x40(%rsp)
  call   <generate_numbers@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <print_first@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <print_second@plt>
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <print_combinations@plt>
  xor    %eax,%eax
L61:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x27,%edx
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L61
L34:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  lea    0xc(%rsp),%rdx
  lea    D19(%rip),%rsi
  call   <sscanf@plt>
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  jne    L14
  mov    0x8(%rbx),%rax
  cmpb   $0x30,(%rax)
  je     L14
  movl   $0xffffffff,0xc(%rsp)
  or     $0xffffffff,%edi
  jmp    L14
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D19
type: string

tool: D2: Usage: ./lockpro THIRD

tool: D29: THIRD should be an integer between %d and %d.


tool: D19: %2d

assistant: ```c
int main(int argc, char **argv) {
  int first[10] = {0}, second[10] = {0}, third = -1;
  if (argc == 2) {
    sscanf(argv[1], "%2d", &third);
    if (third == 0 && argv[1][0] != '0')
      third = -1;
  }
  if (!validate_range(third)) {
    printf("Usage: ./lockpro THIRD\n");
    printf("THIRD should be an integer between %d and %d.\n", 0, 39);
    return 1;
  }
  first[0] = third % 4;
  generate_numbers(first);
  second[0] = (first[0] + 2) % 4;
  generate_numbers(second);
  print_first(first);
  print_second(second, third);
  print_combinations(first, second, third);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %edi,%r8d
  mov    $0xffffffff,%edi
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0xc(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x60(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  cmp    $0x2,%r8d
  je     L68
L10:
  xor    %eax,%eax
  call   <validate_range@plt>
  test   %eax,%eax
  je     L0
  mov    0xc(%rsp),%eax
  mov    $0x4,%ebx
  lea    0x10(%rsp),%rbp
  lea    0x40(%rsp),%r12
  mov    %rbp,%rdi
  cltd
  idiv   %ebx
  xor    %eax,%eax
  mov    %edx,0x10(%rsp)
  call   <generate_numbers@plt>
  mov    0x10(%rsp),%eax
  mov    %r12,%rdi
  add    $0x2,%eax
  cltd
  idiv   %ebx
  xor    %eax,%eax
  mov    %edx,0x40(%rsp)
  call   <generate_numbers@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <print_first@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <print_second@plt>
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <print_combinations@plt>
  xor    %eax,%eax
L26:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x27,%edx
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L26
L68:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  lea    0xc(%rsp),%rdx
  lea    D25(%rip),%rsi
  call   <sscanf@plt>
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  jne    L10
  mov    0x8(%rbx),%rax
  cmpb   $0x30,(%rax)
  je     L10
  movl   $0xffffffff,0xc(%rsp)
  or     $0xffffffff,%edi
  jmp    L10
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D25
datatype: string

tool: D21: Usage: ./lockpro THIRD

tool: D9: THIRD should be an integer between %d and %d.


tool: D25: %2d

assistant: ```c
int main(int argc, char **argv) {
  int first[10] = {0}, second[10] = {0}, third = -1;
  if (argc == 2) {
    sscanf(argv[1], "%2d", &third);
    if (third == 0 && argv[1][0] != '0')
      third = -1;
  }
  if (!validate_range(third)) {
    printf("Usage: ./lockpro THIRD\n");
    printf("THIRD should be an integer between %d and %d.\n", 0, 39);
    return 1;
  }
  first[0] = third % 4;
  generate_numbers(first);
  second[0] = (first[0] + 2) % 4;
  generate_numbers(second);
  print_first(first);
  print_second(second, third);
  print_combinations(first, second, third);
  return 0;
}
```