ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jle    L16
  mov    $0x0,%ebx
  lea    D28(%rip),%r13
  lea    0x4(%rsp),%r12
  lea    D3(%rip),%rbp
L39:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebx
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jg     L39
L38:
  mov    %ebx,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    $0x0,%ebx
  jmp    L38
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D35
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D30
data_type: string

tool: D35: Enter the number of values to be entered: 

tool: D3: %d

tool: D28: Enter number: 

tool: D30: 
The sum of the entered numbers is %d


assistant: ```c
int main() {
  int count, num;
  int sum = 0;
  printf("Enter the number of values to be entered: ");
  scanf("%d", &count);
  while (count-- > 0) {
    printf("Enter number: ");
    scanf("%d", &num);
    sum += num;
  }
  printf("\nThe sum of the entered numbers is %d\n", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%rdi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D25(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jle    L19
  lea    D16(%rip),%r13
  lea    0x4(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%ebp
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jg     L16
L19:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string
name: extract_symbolic_data
arguments: tag: D25
datatype: string
name: extract_symbolic_data
arguments: tag: D16
datatype: string
name: extract_symbolic_data
arguments: tag: D39
datatype: string

tool: D9: Enter the number of values to be entered: 

tool: D25: %d

tool: D16: Enter number: 

tool: D39: 
The sum of the entered numbers is %d


assistant: ```c
int main() {
  int count, num;
  int sum = 0;
  printf("Enter the number of values to be entered: ");
  scanf("%d", &count);
  while (count-- > 0) {
    printf("Enter number: ");
    scanf("%d", &num);
    sum += num;
  }
  printf("\nThe sum of the entered numbers is %d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D38(%rip),%rdi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jle    L3
  lea    D2(%rip),%r13
  lea    0x4(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%ebp
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jg     L19
L3:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D38
data_type: string
name: unpack_data
arguments: data_label: D6
data_type: string
name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D29
data_type: string

tool: D38: Enter the number of values to be entered: 

tool: D6: %d

tool: D2: Enter number: 

tool: D29: 
The sum of the entered numbers is %d


assistant: ```c
int main() {
  int count, num;
  int sum = 0;
  printf("Enter the number of values to be entered: ");
  scanf("%d", &count);
  while (count-- > 0) {
    printf("Enter number: ");
    scanf("%d", &num);
    sum += num;
  }
  printf("\nThe sum of the entered numbers is %d\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_as_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
__attribute__((always_)) uint64_t string_as_uint64(const char *s) {
  uint64_t u;
  memcpy(&u, s, sizeof(u));
  return u;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_as_uint64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) uint64_t string_as_uint64(const char *s) {
  uint64_t u;
  memcpy(&u, s, sizeof(u));
  return u;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<string_as_uint64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) uint64_t string_as_uint64(const char *s) {
  uint64_t u;
  memcpy(&u, s, sizeof(u));
  return u;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_as_uint64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) uint64_t string_as_uint64(const char *s) {
  uint64_t u;
  memcpy(&u, s, sizeof(u));
  return u;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D39(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D51(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm3,%xmm3
  cvtss2sd -0x4(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  addss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  movss  D9(%rip),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x8(%rbp),%xmm2
  movss  D51(%rip),%xmm0
  addss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm4,%xmm4
  cvtss2sd -0x4(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D39
type: f32
name: retrieve_data
arguments: data_label: D51
type: f32
name: retrieve_data
arguments: data_label: D20
type: string
name: retrieve_data
arguments: data_label: D9
type: byte[4]
name: retrieve_data
arguments: data_label: D13
type: string

tool: D39: 2

tool: D51: 3

tool: D20: %f	

tool: {"D9": [0x00,0x00,0xa0,0x40]}

tool: D13: %f


assistant: ```c
void main() {
  float x = 2, y = 3, z;
  z = (x) * (y);
  printf("%f\t", z);
  z = (x * x + 2 * x - 5) * (y + 3);
  printf("%f\n", z);
  getchar();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D18(%rip),%xmm0
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  D17(%rip),%xmm0
  lea    D32(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type: byte[8]
name: unpack_data
arguments: data_tag: D20
type: string
name: unpack_data
arguments: data_tag: D17
type: byte[8]
name: unpack_data
arguments: data_tag: D32
type: string

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: D20: %f	

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x32,0x40]}

tool: D32: %f


assistant: ```c
void main() {
  float x = 2, y = 3, z;
  z = (x) * (y);
  printf("%f\t", z);
  z = (x * x + 2 * x - 5) * (y + 3);
  printf("%f\n", z);
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D39(%rip),%rdi
  mov    $0x1,%eax
  movsd  D2(%rip),%xmm0
  call   <printf@plt>
  movsd  D37(%rip),%xmm0
  mov    $0x1,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D39
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: byte[8]
name: retrieve_data
arguments: data_label: D37
datatype: byte[8]
name: retrieve_data
arguments: data_label: D27
datatype: string

tool: D39: %f	

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x32,0x40]}

tool: D27: %f


assistant: ```c
void main() {
  float x = 2, y = 3, z;
  z = (x) * (y);
  printf("%f\t", z);
  z = (x * x + 2 * x - 5) * (y + 3);
  printf("%f\n", z);
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  mov    $0x1,%eax
  movsd  D25(%rip),%xmm0
  call   <printf@plt>
  movsd  D31(%rip),%xmm0
  mov    $0x1,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getchar@plt>
```

tool_calls: name: read_data
arguments: label: D4
datatype: string
name: read_data
arguments: label: D25
datatype: byte[8]
name: read_data
arguments: label: D31
datatype: byte[8]
name: read_data
arguments: label: D17
datatype: string

tool: D4: %f	

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0x32,0x40]}

tool: D17: %f


assistant: ```c
void main() {
  float x = 2, y = 3, z;
  z = (x) * (y);
  printf("%f\t", z);
  z = (x * x + 2 * x - 5) * (y + 3);
  printf("%f\n", z);
  getchar();
}
```
user: What is the c source code of the assembly code below:

```asm
<replaceSubStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L6
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L52
L6:
  cmpq   $0x0,-0x30(%rbp)
  jne    L5
  mov    -0x28(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L52
L5:
  cmpq   $0x0,-0x38(%rbp)
  je     L65
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L65:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L43
L25:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L43:
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L52:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: 

assistant: ```c
void replaceSubStr(char const *const aSource, char const *const aOldSubStr, char const *const aNewSubStr, char *const aoDestination) {
  char const *pOccurence;
  char const *p;
  char const *lNewSubStr = "";
  if (!aSource) {
    *aoDestination = '\0';
    return;
  }
  if (!aOldSubStr) {
    strcpy(aoDestination, aSource);
    return;
  }
  if (aNewSubStr) {
    lNewSubStr = aNewSubStr;
  }
  p = aSource;
  int lOldSubLen = strlen(aOldSubStr);
  *aoDestination = '\0';
  while ((pOccurence = strstr(p, aOldSubStr)) != NULL) {
    strncat(aoDestination, p, pOccurence - p);
    strcat(aoDestination, lNewSubStr);
    p = pOccurence + lOldSubLen;
  }
  strcat(aoDestination, p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<replaceSubStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rcx,%r12
  test   %rdi,%rdi
  je     L55
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r14
  test   %rsi,%rsi
  je     L33
  test   %rdx,%rdx
  lea    D4(%rip),%rax
  cmove  %rax,%r14
  mov    %rsi,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12)
  movslq %eax,%r15
  jmp    L24
L55:
  movb   $0x0,(%rcx)
  jmp    L39
L33:
  mov    %rdi,%rsi
  mov    %rcx,%rdi
  call   <strcpy@plt>
  jmp    L39
L18:
  mov    %ebx,%edx
  sub    %ebp,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    (%rbx,%r15,1),%rbp
L24:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L18
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: string

tool: 

assistant: ```c
void replaceSubStr(char const *const aSource, char const *const aOldSubStr, char const *const aNewSubStr, char *const aoDestination) {
  char const *pOccurence;
  char const *p;
  char const *lNewSubStr = "";
  if (!aSource) {
    *aoDestination = '\0';
    return;
  }
  if (!aOldSubStr) {
    strcpy(aoDestination, aSource);
    return;
  }
  if (aNewSubStr) {
    lNewSubStr = aNewSubStr;
  }
  p = aSource;
  int lOldSubLen = strlen(aOldSubStr);
  *aoDestination = '\0';
  while ((pOccurence = strstr(p, aOldSubStr)) != NULL) {
    strncat(aoDestination, p, pOccurence - p);
    strcat(aoDestination, lNewSubStr);
    p = pOccurence + lOldSubLen;
  }
  strcat(aoDestination, p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<replaceSubStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L34
  mov    %rdi,%r15
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L38
  mov    %rdx,%r13
  test   %rdx,%rdx
  lea    D6(%rip),%rax
  mov    %rsi,%rdi
  cmove  %rax,%r13
  call   <strlen@plt>
  movb   $0x0,0x0(%rbp)
  movslq %eax,%r14
  jmp    L20
  nop
L9:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15d,%edx
  lea    (%rbx,%r14,1),%r15
  call   <strncat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L20:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r15,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <strcat@plt>
  nopl   0x0(%rax,%rax,1)
L34:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rcx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <strcpy@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: 

assistant: ```c
void replaceSubStr(char const *const aSource, char const *const aOldSubStr, char const *const aNewSubStr, char *const aoDestination) {
  char const *pOccurence;
  char const *p;
  char const *lNewSubStr = "";
  if (!aSource) {
    *aoDestination = '\0';
    return;
  }
  if (!aOldSubStr) {
    strcpy(aoDestination, aSource);
    return;
  }
  if (aNewSubStr) {
    lNewSubStr = aNewSubStr;
  }
  p = aSource;
  int lOldSubLen = strlen(aOldSubStr);
  *aoDestination = '\0';
  while ((pOccurence = strstr(p, aOldSubStr)) != NULL) {
    strncat(aoDestination, p, pOccurence - p);
    strcat(aoDestination, lNewSubStr);
    p = pOccurence + lOldSubLen;
  }
  strcat(aoDestination, p);
}
```
user: What is the c source code of the assembly code below:

```asm
<replaceSubStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%r15
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L10
  mov    %rdx,%r13
  test   %rdx,%rdx
  lea    D5(%rip),%rax
  mov    %rsi,%rdi
  cmove  %rax,%r13
  call   <strlen@plt>
  movb   $0x0,0x0(%rbp)
  movslq %eax,%r14
  jmp    L21
  nop
L29:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15d,%edx
  lea    (%rbx,%r14,1),%r15
  call   <strncat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L21:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L29
  add    $0x8,%rsp
  mov    %r15,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <strcat@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rcx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <strcpy@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: 

assistant: ```c
void replaceSubStr(char const *const aSource, char const *const aOldSubStr, char const *const aNewSubStr, char *const aoDestination) {
  char const *pOccurence;
  char const *p;
  char const *lNewSubStr = "";
  if (!aSource) {
    *aoDestination = '\0';
    return;
  }
  if (!aOldSubStr) {
    strcpy(aoDestination, aSource);
    return;
  }
  if (aNewSubStr) {
    lNewSubStr = aNewSubStr;
  }
  p = aSource;
  int lOldSubLen = strlen(aOldSubStr);
  *aoDestination = '\0';
  while ((pOccurence = strstr(p, aOldSubStr)) != NULL) {
    strncat(aoDestination, p, pOccurence - p);
    strcat(aoDestination, lNewSubStr);
    p = pOccurence + lOldSubLen;
  }
  strcat(aoDestination, p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<YYSTART>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <yyselect@plt>
  cmp    $0x6d,%eax
  jne    L7
  mov    $0x0,%eax
  call   <program@plt>
  mov    $0x0,%eax
  call   <get_lexval@plt>
  nop
L7:
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: %d


assistant: ```c
YYSTART() {
  printf("%d\n", 3);
  switch (yyselect()) {
  case 109: {
    program();
    get_lexval();
  } break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<YYSTART>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <yyselect@plt>
  cmp    $0x6d,%eax
  je     L16
L19:
  add    $0x8,%rsp
  ret
L16:
  mov    $0x0,%eax
  call   <program@plt>
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: %d


assistant: ```c
YYSTART() {
  printf("%d\n", 3);
  switch (yyselect()) {
  case 109: {
    program();
    get_lexval();
  } break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<YYSTART>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <yyselect@plt>
  cmp    $0x6d,%eax
  je     L9
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <program@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <get_lexval@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
YYSTART() {
  printf("%d\n", 3);
  switch (yyselect()) {
  case 109: {
    program();
    get_lexval();
  } break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<YYSTART>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <yyselect@plt>
  cmp    $0x6d,%eax
  je     L7
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <program@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <get_lexval@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string

tool: D7: %d


assistant: ```c
YYSTART() {
  printf("%d\n", 3);
  switch (yyselect()) {
  case 109: {
    program();
    get_lexval();
  } break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<wad_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L6
  lea    D8(%rip),%rax
  mov    %rax,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <wad_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wad_strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: 

assistant: ```c
char *wad_strdup(const char *c) {
  char *t;
  if (!c)
    c = "";
  t = (char *)wad_malloc(strlen(c) + 1);
  wad_strcpy(t, c);
  return t;
}
```