user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jg     L56
  xor    %eax,%eax
  mov    $0x64,%r15d
  mov    $0x64,%ebp
  mov    $0x3e8,%r12d
  call   <omp_get_max_threads@plt>
  lea    D18(%rip),%rdi
  mov    $0x64,%r14d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%r8d
  mov    $0x3e8,%ecx
  xor    %eax,%eax
  mov    $0x64,%edx
  mov    $0x3e8,%esi
  lea    D52(%rip),%rdi
  call   <printf@plt>
  movl   $0x3e8,0xc(%rsp)
L108:
  lea    D7(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L102:
  mov    %ebp,%ebx
  nopw   0x0(%rax,%rax,1)
L79:
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r14d,%edi
  call   <dgemm_gflops@plt>
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    %ebp,%ebx
  call   <printf@plt>
  cmp    %r12d,%ebx
  jle    L79
  add    %r15d,%r14d
  cmp    0xc(%rsp),%r14d
  jle    L102
L49:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  mov    %edi,%ebx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbp
  call   <atoi@plt>
  mov    %eax,0xc(%rsp)
  cmp    $0x2,%ebx
  je     L33
  mov    0x10(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%r14d
  cmp    $0x3,%ebx
  je     L114
  mov    0x18(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  cmp    $0x4,%ebx
  je     L63
  mov    0x20(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L98:
  xor    %eax,%eax
  call   <omp_get_max_threads@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%ebx
  xor    %eax,%eax
  mov    %ebp,%r8d
  mov    %r12d,%ecx
  mov    %r14d,%edx
  lea    D52(%rip),%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %r14d,%ebx
  jl     L49
  mov    %r14d,%r15d
  cmp    %r12d,%ebp
  jle    L108
  jmp    L49
L33:
  mov    $0x64,%r14d
L114:
  xor    %eax,%eax
  call   <omp_get_max_threads@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%ebx
  xor    %eax,%eax
  mov    $0x3e8,%ecx
  mov    $0x64,%r8d
  mov    %r14d,%edx
  lea    D52(%rip),%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %r14d,%ebx
  jl     L49
  mov    %r14d,%r15d
  mov    $0x64,%ebp
  mov    $0x3e8,%r12d
  jmp    L108
L63:
  mov    $0x64,%ebp
  jmp    L98
```

tool_calls: name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D52
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D18: testing DGEMM %d threads 


tool: D52: maxm=%d, incm=%d, maxk=%d, inck=%d


tool: D7: m=n=%5d, k=%5d = %lf GF/s 


assistant: ```c
int main(int argc, char *argv[]) {
  int maxm = (argc > 1) ? atoi(argv[1]) : 1000;
  int incm = (argc > 2) ? atoi(argv[2]) : 100;
  int maxk = (argc > 3) ? atoi(argv[3]) : 1000;
  int inck = (argc > 4) ? atoi(argv[4]) : 100;
  printf("testing DGEMM %d threads \n", omp_get_max_threads());
  printf("maxm=%d, incm=%d, maxk=%d, inck=%d\n", maxm, incm, maxk, inck);
  for (int m = incm; m <= maxm; m += incm) {
    int n = m;
    for (int k = inck; k <= maxk; k += inck) {
      double eff_peak = dgemm_gflops(m, n, k);
      printf("m=n=%5d, k=%5d = %lf GF/s \n", m, k, eff_peak);
    }
  }
  return 0;
}
```