user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L121:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L121
  sub    $0x948,%rsp
  lea    D27(%rip),%rdi
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    D8(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x3d0938(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rcx
  lea    0x24(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  lea    0x2c(%rsp),%r8
  call   <scanf@plt>
  mov    0x20(%rsp),%ecx
  test   %ecx,%ecx
  jle    L139
L35:
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  jle    L11
  lea    0x30(%rsp,%r14,4),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L137:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x24(%rsp)
  jg     L137
L11:
  mov    0x20(%rsp),%eax
  add    $0x1,%r13d
  add    $0x3e8,%r14
  mov    %eax,0xc(%rsp)
  cmp    %r13d,%eax
  jg     L35
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L139
  movslq 0x28(%rsp),%rax
  movslq 0x2c(%rsp),%r12
  xor    %ebx,%ebx
  xor    %r10d,%r10d
  mov    $0xfffffffffffff060,%rdx
  mov    0x24(%rsp),%ebp
  mov    %rax,%r15
  imul   $0xfa0,%rax,%rax
  mov    %r12,%r11
  mov    %rax,0x10(%rsp)
  lea    -0x1(%r15),%eax
  imul   $0xfa0,%rax,%rax
  sub    %rax,%rdx
  lea    0xfd0(%rsp,%rax,1),%r9
  mov    %rdx,0x18(%rsp)
L133:
  mov    %ebx,%r14d
  add    %r15d,%ebx
  test   %ebp,%ebp
  jle    L114
  mov    0x18(%rsp),%rax
  xor    %r8d,%r8d
  xor    %edi,%edi
  xor    %esi,%esi
  lea    (%rax,%r9,1),%r13
  nop
L48:
  add    %r11d,%esi
  mov    %r13,%rcx
  xor    %edx,%edx
  cmp    %r14d,%ebx
  jle    L80
  nopl   (%rax)
L106:
  mov    %r8,%rax
  cmp    %edi,%esi
  jle    L21
  nopw   0x0(%rax,%rax,1)
L3:
  add    (%rcx,%rax,4),%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L3
L21:
  add    $0xfa0,%rcx
  cmp    %r9,%rcx
  jne    L106
L80:
  cmp    %edx,%r10d
  cmovl  %edx,%r10d
  add    %r11d,%edi
  add    %r12,%r8
  cmp    %ebp,%esi
  jl     L48
L114:
  add    0x10(%rsp),%r9
  cmp    %ebx,0xc(%rsp)
  jg     L133
L19:
  mov    %r10d,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x3d0938(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x3d0948,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L139:
  xor    %r10d,%r10d
  jmp    L19
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D28
data_type: string

tool: D27:  %d %d %d %d

tool: D8:  %d

tool: D28: %d

assistant: ```c
int main() {
  int plantacao[1000][1000];
  int lin, col;
  int m, n;
  int max;
  int cur;
  int i, j, k, l;
  scanf(" %d %d %d %d", &lin, &col, &m, &n);
  max = 0;
  for (i = 0; i < lin; i++)
    for (j = 0; j < col; j++)
      scanf(" %d", &(plantacao[i][j]));
  for (i = 0; i < lin; i += m) {
    for (j = 0; j < col; j += n) {
      cur = 0;
      for (k = i; k < (i + m); k++)
        for (l = j; l < (j + n); l++)
          cur += plantacao[k][l];
      if (cur > max)
        max = cur;
    }
  }
  printf("%d", max);
  return 0;
}
```