ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L17:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L29:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <decisionFunc@plt>
  cmp    $0x1,%eax
  jne    L20
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L29
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D27
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string

tool: D7: Results for image %d:


tool: D27: %f


tool: D19: Image %d is symbol %d.


assistant: ```c
void out(double **result, int images_num, int results_num) {
  int i, j;
  for (i = 0; i < images_num; i++) {
    printf("Results for image %d:\n", i);
    for (j = 0; j < results_num; j++) {
      printf("%f\n", result[i][j]);
      if (decisionFunc(result[i][j]) == 1) {
        printf("Image %d is symbol %d.\n", i, j);
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<out>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L57
  mov    %rdi,%rbp
  mov    $0x0,%r15d
  lea    D29(%rip),%r14
  jmp    L36
L19:
  mov    %ebx,%edx
  mov    %r15d,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L52:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L2
L55:
  mov    0x0(%rbp),%rax
  cvttsd2si (%rax,%rbx,8),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%rax
  movsd  (%rax,%rbx,8),%xmm0
  call   <decisionFunc@plt>
  cmp    $0x1,%eax
  jne    L52
  jmp    L19
L2:
  add    $0x1,%r15d
  add    $0x8,%rbp
  cmp    %r15d,0x8(%rsp)
  je     L57
L36:
  mov    %r15d,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L2
  mov    %eax,%r13d
  mov    $0x0,%ebx
  jmp    L55
L57:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D29
data_type: string
name: parse_data
arguments: data_label: D21
data_type: string
name: parse_data
arguments: data_label: D19
data_type: string

tool: D29: %f


tool: D21: Image %d is symbol %d.


tool: D19: Results for image %d:


assistant: ```c
void out(double **result, int images_num, int results_num) {
  int i, j;
  for (i = 0; i < images_num; i++) {
    printf("Results for image %d:\n", i);
    for (j = 0; j < results_num; j++) {
      printf("%f\n", result[i][j]);
      if (decisionFunc(result[i][j]) == 1) {
        printf("Image %d is symbol %d.\n", i, j);
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<out>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L52
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  lea    D27(%rip),%rbp
  movslq %edx,%r13
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r14d,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L1
  xor    %r15d,%r15d
  jmp    L56
  cs nopw 0x0(%rax,%rax,1)
L25:
  add    $0x1,%r15
  cmp    %r15,%r13
  je     L1
L56:
  mov    (%rbx),%rax
  mov    %rbp,%rdi
  cvttsd2si (%rax,%r15,8),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%rax
  movsd  (%rax,%r15,8),%xmm0
  call   <decisionFunc@plt>
  cmp    $0x1,%eax
  jne    L25
  mov    %r15d,%edx
  mov    %r14d,%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%r15
  cmp    %r15,%r13
  jne    L56
  nopl   0x0(%rax)
L1:
  add    $0x1,%r14d
  add    $0x8,%rbx
  cmp    %r14d,0x8(%rsp)
  jne    L7
L52:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
type: string
name: extract_symbolic_data
arguments: data_tag: D22
type: string
name: extract_symbolic_data
arguments: data_tag: D26
type: string

tool: D27: %f


tool: D22: Results for image %d:


tool: D26: Image %d is symbol %d.


assistant: ```c
void out(double **result, int images_num, int results_num) {
  int i, j;
  for (i = 0; i < images_num; i++) {
    printf("Results for image %d:\n", i);
    for (j = 0; j < results_num; j++) {
      printf("%f\n", result[i][j]);
      if (decisionFunc(result[i][j]) == 1) {
        printf("Image %d is symbol %d.\n", i, j);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<out>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L37
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  lea    D28(%rip),%rbp
  movslq %edx,%r13
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r14d,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L34
  xor    %r15d,%r15d
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L36:
  add    $0x1,%r15
  cmp    %r13,%r15
  je     L34
L43:
  mov    (%rbx),%rax
  mov    %rbp,%rdi
  cvttsd2si (%rax,%r15,8),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%rax
  movsd  (%rax,%r15,8),%xmm0
  call   <decisionFunc@plt>
  cmp    $0x1,%eax
  jne    L36
  mov    %r15d,%edx
  mov    %r14d,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%r15
  cmp    %r13,%r15
  jne    L43
  nopl   0x0(%rax)
L34:
  add    $0x1,%r14d
  add    $0x8,%rbx
  cmp    %r14d,0x8(%rsp)
  jne    L38
L37:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D18
datatype: string

tool: D28: %f


tool: D8: Results for image %d:


tool: D18: Image %d is symbol %d.


assistant: ```c
void out(double **result, int images_num, int results_num) {
  int i, j;
  for (i = 0; i < images_num; i++) {
    printf("Results for image %d:\n", i);
    for (j = 0; j < results_num; j++) {
      printf("%f\n", result[i][j]);
      if (decisionFunc(result[i][j]) == 1) {
        printf("Image %d is symbol %d.\n", i, j);
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Is_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L27
  movsd  -0x8(%rbp),%xmm0
  movq   D7(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L27:
  movsd  D19(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L13
  mov    $0x1,%eax
  jmp    L11
L13:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: byte[8]
name: unpack_data
arguments: label: D19
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D19": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

assistant: ```c
int Is_zero(double value) {
  if (value < 0) {
    value = -value;
  }
  if (value < 1e-10) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Is_zero>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L18
L19:
  movsd  D5(%rip),%xmm1
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  ret
L18:
  xorpd  D16(%rip),%xmm0
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D16
type: byte[16]

tool: {"D5": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int Is_zero(double value) {
  if (value < 0) {
    value = -value;
  }
  if (value < 1e-10) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Is_zero>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L8
  xorpd  D10(%rip),%xmm0
L8:
  movsd  D13(%rip),%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: byte[16]
name: parse_data
arguments: data_tag: D13
datatype: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D13": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

assistant: ```c
int Is_zero(double value) {
  if (value < 0) {
    value = -value;
  }
  if (value < 1e-10) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Is_zero>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L1
  xorpd  D10(%rip),%xmm0
L1:
  movsd  D1(%rip),%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  ret
```

tool_calls: name: parse_data
arguments: label: D10
data_type: byte[16]
name: parse_data
arguments: label: D1
data_type: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D1": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

assistant: ```c
int Is_zero(double value) {
  if (value < 0) {
    value = -value;
  }
  if (value < 1e-10) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(int a, int b) {
  long long aa = a;
  long long bb = b;
  return aa + bb;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int foo(int a, int b) {
  long long aa = a;
  long long bb = b;
  return aa + bb;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int foo(int a, int b) {
  long long aa = a;
  long long bb = b;
  return aa + bb;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int foo(int a, int b) {
  long long aa = a;
  long long bb = b;
  return aa + bb;
}
```
user: What is the c source code of the assembly code below:

```asm
<fatorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  nop
  cmpl   $0x1,-0x4(%rbp)
  jle    L12
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fatorial>
  imul   -0x4(%rbp),%eax
  jmp    L12
L12:
  leave
  ret
```

assistant: ```c
int fatorial(int n) {
  while (n > 1) {
    return n * fatorial(n - 1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fatorial>:
  endbr64
  cmp    $0x1,%edi
  jg     L1
  ret
L1:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fatorial>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fatorial(int n) {
  while (n > 1) {
    return n * fatorial(n - 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fatorial>:
  endbr64
  ret
```

assistant: ```c
int fatorial(int n) {
  while (n > 1) {
    return n * fatorial(n - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fatorial>:
  endbr64
  ret
```

assistant: ```c
int fatorial(int n) {
  while (n > 1) {
    return n * fatorial(n - 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L33
L9:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L3
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L25
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L33:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jg     L9
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type: string

tool: D21: %d

assistant: ```c
int main() {
  int n, i, mx = 0, cnt;
  scanf("%d", &n);
  for (; n > 0; n--) {
    scanf("%d", &i);
    if (mx < i) {
      mx = i;
      cnt = 0;
    }
    if (mx == i)
      cnt++;
  }
  printf("%d", cnt);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L57
  mov    $0x0,%ebx
  lea    D21(%rip),%r12
  jmp    L52
L63:
  je     L12
L79:
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jle    L57
L52:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jle    L63
  mov    $0x0,%ebp
L74:
  add    $0x1,%ebp
  mov    %eax,%ebx
  jmp    L79
L12:
  mov    %ebx,%eax
  jmp    L74
L57:
  mov    %ebp,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: string

tool: D21: %d

assistant: ```c
int main() {
  int n, i, mx = 0, cnt;
  scanf("%d", &n);
  for (; n > 0; n--) {
    scanf("%d", &i);
    if (mx < i) {
      mx = i;
      cnt = 0;
    }
    if (mx == i)
      cnt++;
  }
  printf("%d", cnt);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L52
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  xchg   %ax,%ax
L29:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jle    L4
  mov    $0x1,%r13d
L58:
  mov    %eax,%ebx
L17:
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jg     L29
L52:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  jne    L17
  add    $0x1,%r13d
  jmp    L58
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: %d

assistant: ```c
int main() {
  int n, i, mx = 0, cnt;
  scanf("%d", &n);
  for (; n > 0; n--) {
    scanf("%d", &i);
    if (mx < i) {
      mx = i;
      cnt = 0;
    }
    if (mx == i)
      cnt++;
  }
  printf("%d", cnt);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L34
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  xchg   %ax,%ax
L30:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jle    L23
  mov    $0x1,%r13d
L37:
  mov    %eax,%ebx
L41:
  mov    (%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jg     L30
L34:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  jne    L41
  add    $0x1,%r13d
  jmp    L37
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int main() {
  int n, i, mx = 0, cnt;
  scanf("%d", &n);
  for (; n > 0; n--) {
    scanf("%d", &i);
    if (mx < i) {
      mx = i;
      cnt = 0;
    }
    if (mx == i)
      cnt++;
  }
  printf("%d", cnt);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<splitfloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  movss  %xmm0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  lea    -0x14(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void splitfloat(unsigned int *wordlow, unsigned int *wordhigh, float value) {
  wordlow = ((int *)&value)[0];
  wordhigh = ((int *)&value)[1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<splitfloat>:
  endbr64
  ret
```

assistant: ```c
void splitfloat(unsigned int *wordlow, unsigned int *wordhigh, float value) {
  wordlow = ((int *)&value)[0];
  wordhigh = ((int *)&value)[1];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<splitfloat>:
  endbr64
  ret
```

assistant: ```c
void splitfloat(unsigned int *wordlow, unsigned int *wordhigh, float value) {
  wordlow = ((int *)&value)[0];
  wordhigh = ((int *)&value)[1];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<splitfloat>:
  endbr64
  ret
```

assistant: ```c
void splitfloat(unsigned int *wordlow, unsigned int *wordhigh, float value) {
  wordlow = ((int *)&value)[0];
  wordhigh = ((int *)&value)[1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmd_mkfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x24(%rbp),%rdi
  lea    -0x20(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <parse_mkfs@plt>
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <new_fs@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <close_fs@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void cmd_mkfs(int argc, char **argv) {
  int req_inos;
  int req_blks;
  int magic;
  char *filename = argv[0];
  struct minix_fs_dat *fs;
  parse_mkfs(argc, argv, &magic, &req_blks, &req_inos);
  fs = new_fs(filename, magic, req_blks, req_inos);
  close_fs(fs);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd_mkfs>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%rbx
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%r8
  call   <parse_mkfs@plt>
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    %rbx,%rdi
  call   <new_fs@plt>
  mov    %rax,%rdi
  call   <close_fs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmd_mkfs(int argc, char **argv) {
  int req_inos;
  int req_blks;
  int magic;
  char *filename = argv[0];
  struct minix_fs_dat *fs;
  parse_mkfs(argc, argv, &magic, &req_blks, &req_inos);
  fs = new_fs(filename, magic, req_blks, req_inos);
  close_fs(fs);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmd_mkfs>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    (%rsi),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%r8
  call   <parse_mkfs@plt>
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    %rbp,%rdi
  mov    0x14(%rsp),%esi
  call   <new_fs@plt>
  mov    %rax,%rdi
  call   <close_fs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmd_mkfs(int argc, char **argv) {
  int req_inos;
  int req_blks;
  int magic;
  char *filename = argv[0];
  struct minix_fs_dat *fs;
  parse_mkfs(argc, argv, &magic, &req_blks, &req_inos);
  fs = new_fs(filename, magic, req_blks, req_inos);
  close_fs(fs);
}
```
user: What is the c source code of the assembly code below:

```asm
<cmd_mkfs>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    (%rsi),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%r8
  call   <parse_mkfs@plt>
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    %rbp,%rdi
  mov    0x14(%rsp),%esi
  call   <new_fs@plt>
  mov    %rax,%rdi
  call   <close_fs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmd_mkfs(int argc, char **argv) {
  int req_inos;
  int req_blks;
  int magic;
  char *filename = argv[0];
  struct minix_fs_dat *fs;
  parse_mkfs(argc, argv, &magic, &req_blks, &req_inos);
  fs = new_fs(filename, magic, req_blks, req_inos);
  close_fs(fs);
}
```