ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findRootBetween>:
  endbr64
  push   %rbp
  push   %rbx
  movq   %xmm0,%rbx
  sub    $0x18,%rsp
  nop
L4:
  movq   %rbx,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <middleOf@plt>
  call   <f@plt>
  mov    %eax,%edi
  call   <isSmallNumber@plt>
  movsd  0x8(%rsp),%xmm1
  test   %eax,%eax
  jne    L2
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <f@plt>
  movsd  0x8(%rsp),%xmm1
  movq   %rbx,%xmm0
  mov    %eax,%ebp
  call   <middleOf@plt>
  call   <f@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <sameSign@plt>
  movsd  0x8(%rsp),%xmm1
  test   %rax,%rax
  je     L19
  movq   %rbx,%xmm0
  call   <middleOf@plt>
  movapd %xmm0,%xmm1
  jmp    L4
L19:
  movq   %rbx,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <middleOf@plt>
  movsd  0x8(%rsp),%xmm1
  movq   %xmm0,%rbx
  jmp    L4
L2:
  add    $0x18,%rsp
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  jmp    10b0 <middleOf@plt>
```

assistant: ```c
double findRootBetween(double a, double b) {
  double l = a, u = b;
  while (!isSmallNumber(f(middleOf(l, u)))) {
    if (sameSign(f(middleOf(l, u)), f(u)))
      u = middleOf(l, u);
    else
      l = middleOf(l, u);
  }
  return middleOf(l, u);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pkey_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  mov    -0x20(%rbp),%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <wrpkru@plt>
  leave
  ret
```

assistant: ```c
int pkey_set(int pkey, unsigned long rights, unsigned long flags) {
  unsigned int pkru = (rights << (2 * pkey));
  return wrpkru(pkru);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pkey_set>:
  endbr64
  sub    $0x8,%rsp
  lea    (%rdi,%rdi,1),%ecx
  shl    %cl,%rsi
  mov    %rsi,%rdi
  call   <wrpkru@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pkey_set(int pkey, unsigned long rights, unsigned long flags) {
  unsigned int pkru = (rights << (2 * pkey));
  return wrpkru(pkru);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pkey_set>:
  endbr64
  lea    (%rdi,%rdi,1),%ecx
  shl    %cl,%rsi
  mov    %rsi,%rdi
  jmp    1050 <wrpkru@plt>
```

assistant: ```c
int pkey_set(int pkey, unsigned long rights, unsigned long flags) {
  unsigned int pkru = (rights << (2 * pkey));
  return wrpkru(pkru);
}
```
user: What is the c source code of the assembly code below?

```asm
<pkey_set>:
  endbr64
  lea    (%rdi,%rdi,1),%ecx
  shl    %cl,%rsi
  mov    %rsi,%rdi
  jmp    1050 <wrpkru@plt>
```

assistant: ```c
int pkey_set(int pkey, unsigned long rights, unsigned long flags) {
  unsigned int pkru = (rights << (2 * pkey));
  return wrpkru(pkru);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: %d 

assistant: ```c
void print_arr(int ar_size, int *ar) {
  for (int i = 0; i < ar_size; i++) {
    printf("%d ", ar[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_arr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L7
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r12
  lea    D0(%rip),%rbp
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L3
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d 

assistant: ```c
void print_arr(int ar_size, int *ar) {
  for (int i = 0; i < ar_size; i++) {
    printf("%d ", ar[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_arr>:
  endbr64
  test   %edi,%edi
  jle    L5
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: %d 

assistant: ```c
void print_arr(int ar_size, int *ar) {
  for (int i = 0; i < ar_size; i++) {
    printf("%d ", ar[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_arr>:
  endbr64
  test   %edi,%edi
  jle    L13
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: %d 

assistant: ```c
void print_arr(int ar_size, int *ar) {
  for (int i = 0; i < ar_size; i++) {
    printf("%d ", ar[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<drawmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L12:
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %rax,%rdi
  call   <setpixel@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %rax,%rdi
  call   <setpixel@plt>
  mov    -0x20(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %rax,%rdi
  call   <setpixel@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %rax,%rdi
  call   <setpixel@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x4,-0x4(%rbp)
  jle    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void drawmark(struct raster *ra, int x, int y) {
  int j;
  for (j = 0; j < 5; j++) {
    setpixel(ra, x - j, y, 255, 255, 255);
    setpixel(ra, x + j, y, 255, 255, 255);
    setpixel(ra, x, y - j, 255, 255, 255);
    setpixel(ra, x, y + j, 255, 255, 255);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<drawmark>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    $0x0,%ebx
L1:
  mov    %r12d,%esi
  sub    %ebx,%esi
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <setpixel@plt>
  lea    (%r12,%rbx,1),%esi
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <setpixel@plt>
  mov    %ebp,%edx
  sub    %ebx,%edx
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <setpixel@plt>
  lea    (%rbx,%rbp,1),%edx
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <setpixel@plt>
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void drawmark(struct raster *ra, int x, int y) {
  int j;
  for (j = 0; j < 5; j++) {
    setpixel(ra, x - j, y, 255, 255, 255);
    setpixel(ra, x + j, y, 255, 255, 255);
    setpixel(ra, x, y - j, 255, 255, 255);
    setpixel(ra, x, y + j, 255, 255, 255);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<drawmark>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L8:
  mov    %r12d,%esi
  mov    $0xff,%r9d
  mov    $0xff,%ecx
  mov    %ebp,%edx
  sub    %ebx,%esi
  mov    $0xff,%r8d
  mov    %r13,%rdi
  call   <setpixel@plt>
  lea    (%rbx,%r12,1),%esi
  mov    $0xff,%ecx
  mov    %ebp,%edx
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    %r13,%rdi
  call   <setpixel@plt>
  mov    %ebp,%edx
  mov    $0xff,%r9d
  mov    %r12d,%esi
  sub    %ebx,%edx
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %r13,%rdi
  call   <setpixel@plt>
  lea    (%rbx,%rbp,1),%edx
  mov    $0xff,%ecx
  mov    %r12d,%esi
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <setpixel@plt>
  cmp    $0x5,%ebx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void drawmark(struct raster *ra, int x, int y) {
  int j;
  for (j = 0; j < 5; j++) {
    setpixel(ra, x - j, y, 255, 255, 255);
    setpixel(ra, x + j, y, 255, 255, 255);
    setpixel(ra, x, y - j, 255, 255, 255);
    setpixel(ra, x, y + j, 255, 255, 255);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<drawmark>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L8:
  mov    %r12d,%esi
  mov    $0xff,%r9d
  mov    $0xff,%ecx
  mov    %ebp,%edx
  sub    %ebx,%esi
  mov    $0xff,%r8d
  mov    %r13,%rdi
  call   <setpixel@plt>
  lea    (%rbx,%r12,1),%esi
  mov    $0xff,%ecx
  mov    %ebp,%edx
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    %r13,%rdi
  call   <setpixel@plt>
  mov    %ebp,%edx
  mov    $0xff,%r9d
  mov    %r12d,%esi
  sub    %ebx,%edx
  mov    $0xff,%r8d
  mov    $0xff,%ecx
  mov    %r13,%rdi
  call   <setpixel@plt>
  lea    (%rbx,%rbp,1),%edx
  mov    $0xff,%ecx
  mov    %r12d,%esi
  mov    $0xff,%r9d
  mov    $0xff,%r8d
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <setpixel@plt>
  cmp    $0x5,%ebx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void drawmark(struct raster *ra, int x, int y) {
  int j;
  for (j = 0; j < 5; j++) {
    setpixel(ra, x - j, y, 255, 255, 255);
    setpixel(ra, x + j, y, 255, 255, 255);
    setpixel(ra, x, y - j, 255, 255, 255);
    setpixel(ra, x, y + j, 255, 255, 255);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_ZN10UecFSMImplC1EP14UecManagerBase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_ZN10UecFSMImplC2EP14UecManagerBase@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void _ZN10UecFSMImplC1EP14UecManagerBase(struct l_class_OC_UecFSMImpl *llvm_cbe_this, struct l_class_OC_Test2 *llvm_cbe_p_uecManagerBasePtr) {
  struct l_class_OC_UecFSMImpl *llvm_cbe_this_2e_addr;
  struct l_class_OC_Test2 *llvm_cbe_p_uecManagerBasePtr_2e_addr;
  struct l_class_OC_UecFSMImpl *llvm_cbe_this1;
  struct l_class_OC_Test2 *llvm_cbe_tmp;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_p_uecManagerBasePtr_2e_addr) = llvm_cbe_p_uecManagerBasePtr;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp = *(&llvm_cbe_p_uecManagerBasePtr_2e_addr);
  _ZN10UecFSMImplC2EP14UecManagerBase(llvm_cbe_this1, llvm_cbe_tmp);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_ZN10UecFSMImplC1EP14UecManagerBase>:
  endbr64
  sub    $0x8,%rsp
  call   <_ZN10UecFSMImplC2EP14UecManagerBase@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _ZN10UecFSMImplC1EP14UecManagerBase(struct l_class_OC_UecFSMImpl *llvm_cbe_this, struct l_class_OC_Test2 *llvm_cbe_p_uecManagerBasePtr) {
  struct l_class_OC_UecFSMImpl *llvm_cbe_this_2e_addr;
  struct l_class_OC_Test2 *llvm_cbe_p_uecManagerBasePtr_2e_addr;
  struct l_class_OC_UecFSMImpl *llvm_cbe_this1;
  struct l_class_OC_Test2 *llvm_cbe_tmp;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_p_uecManagerBasePtr_2e_addr) = llvm_cbe_p_uecManagerBasePtr;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp = *(&llvm_cbe_p_uecManagerBasePtr_2e_addr);
  _ZN10UecFSMImplC2EP14UecManagerBase(llvm_cbe_this1, llvm_cbe_tmp);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_ZN10UecFSMImplC1EP14UecManagerBase>:
  endbr64
  jmp    1050 <_ZN10UecFSMImplC2EP14UecManagerBase@plt>
```

assistant: ```c
void _ZN10UecFSMImplC1EP14UecManagerBase(struct l_class_OC_UecFSMImpl *llvm_cbe_this, struct l_class_OC_Test2 *llvm_cbe_p_uecManagerBasePtr) {
  struct l_class_OC_UecFSMImpl *llvm_cbe_this_2e_addr;
  struct l_class_OC_Test2 *llvm_cbe_p_uecManagerBasePtr_2e_addr;
  struct l_class_OC_UecFSMImpl *llvm_cbe_this1;
  struct l_class_OC_Test2 *llvm_cbe_tmp;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_p_uecManagerBasePtr_2e_addr) = llvm_cbe_p_uecManagerBasePtr;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp = *(&llvm_cbe_p_uecManagerBasePtr_2e_addr);
  _ZN10UecFSMImplC2EP14UecManagerBase(llvm_cbe_this1, llvm_cbe_tmp);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_ZN10UecFSMImplC1EP14UecManagerBase>:
  endbr64
  jmp    1050 <_ZN10UecFSMImplC2EP14UecManagerBase@plt>
```

assistant: ```c
void _ZN10UecFSMImplC1EP14UecManagerBase(struct l_class_OC_UecFSMImpl *llvm_cbe_this, struct l_class_OC_Test2 *llvm_cbe_p_uecManagerBasePtr) {
  struct l_class_OC_UecFSMImpl *llvm_cbe_this_2e_addr;
  struct l_class_OC_Test2 *llvm_cbe_p_uecManagerBasePtr_2e_addr;
  struct l_class_OC_UecFSMImpl *llvm_cbe_this1;
  struct l_class_OC_Test2 *llvm_cbe_tmp;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_p_uecManagerBasePtr_2e_addr) = llvm_cbe_p_uecManagerBasePtr;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp = *(&llvm_cbe_p_uecManagerBasePtr_2e_addr);
  _ZN10UecFSMImplC2EP14UecManagerBase(llvm_cbe_this1, llvm_cbe_tmp);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<roundup_to_next_power_of_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L1
L11:
  shll   -0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int roundup_to_next_power_of_2(int x) {
  int n = 1;
  while (n < x)
    n <<= 1;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<roundup_to_next_power_of_2>:
  endbr64
  cmp    $0x1,%edi
  jle    L9
  mov    $0x1,%eax
L3:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L3
  ret
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int roundup_to_next_power_of_2(int x) {
  int n = 1;
  while (n < x)
    n <<= 1;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<roundup_to_next_power_of_2>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L11
  xchg   %ax,%ax
L1:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L1
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
int roundup_to_next_power_of_2(int x) {
  int n = 1;
  while (n < x)
    n <<= 1;
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<roundup_to_next_power_of_2>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L8
  xchg   %ax,%ax
L4:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L4
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
int roundup_to_next_power_of_2(int x) {
  int n = 1;
  while (n < x)
    n <<= 1;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fastd_hash_final>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x3,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sar    $0xb,%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0xf,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fastd_hash_final(uint32_t *hash) {
  *hash += (*hash << 3);
  *hash ^= (*hash >> 11);
  *hash += (*hash << 15);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fastd_hash_final>:
  endbr64
  mov    (%rdi),%eax
  lea    (%rax,%rax,8),%edx
  mov    %edx,%eax
  sar    $0xb,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shl    $0xf,%edx
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fastd_hash_final(uint32_t *hash) {
  *hash += (*hash << 3);
  *hash ^= (*hash >> 11);
  *hash += (*hash << 15);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fastd_hash_final>:
  endbr64
  mov    (%rdi),%eax
  lea    (%rax,%rax,8),%edx
  mov    %edx,%eax
  sar    $0xb,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shl    $0xf,%edx
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fastd_hash_final(uint32_t *hash) {
  *hash += (*hash << 3);
  *hash ^= (*hash >> 11);
  *hash += (*hash << 15);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fastd_hash_final>:
  endbr64
  mov    (%rdi),%eax
  lea    (%rax,%rax,8),%edx
  mov    %edx,%eax
  sar    $0xb,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shl    $0xf,%edx
  add    %edx,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fastd_hash_final(uint32_t *hash) {
  *hash += (*hash << 3);
  *hash ^= (*hash >> 11);
  *hash += (*hash << 15);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D47(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D55(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd D25(%rip),%xmm0
  jb     L21
  movsd  D25(%rip),%xmm0
  jmp    L8
L21:
  movsd  -0x10(%rbp),%xmm0
L8:
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D56
data_type: string
name: retrieve_data
arguments: data_tag: D1
data_type: f64
name: retrieve_data
arguments: data_tag: D47
data_type: f64
name: retrieve_data
arguments: data_tag: D55
data_type: f64
name: retrieve_data
arguments: data_tag: D25
data_type: f64
name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D56: %lf %lf

tool: D1: 3.5

tool: D47: 7.5

tool: D55: 11

tool: D25: 10

tool: D4: MEDIA = %.5f


assistant: ```c
int main(void) {
  double a, b;
  scanf("%lf %lf", &a, &b);
  double f = (a * 3.5 + b * 7.5) / 11.0;
  f = f >= 10.0 ? 10.0 : f;
  printf("MEDIA = %.5f\n", f);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D53(%rip),%rdi
  call   <scanf@plt>
  movsd  D45(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  D24(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D56(%rip),%xmm0
  comisd D25(%rip),%xmm0
  jb     L2
  movsd  D25(%rip),%xmm0
L2:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D53
data_type: string
name: disassemble_data
arguments: label: D45
data_type: f64
name: disassemble_data
arguments: label: D24
data_type: f64
name: disassemble_data
arguments: label: D56
data_type: f64
name: disassemble_data
arguments: label: D25
data_type: f64[2]
name: disassemble_data
arguments: label: D41
data_type: string

tool: D53: %lf %lf

tool: D45: 3.5

tool: D24: 7.5

tool: D56: 11

tool: {"D25": [10.0,3.5]}

tool: D41: MEDIA = %.5f


assistant: ```c
int main(void) {
  double a, b;
  scanf("%lf %lf", &a, &b);
  double f = (a * 3.5 + b * 7.5) / 11.0;
  f = f >= 10.0 ? 10.0 : f;
  printf("MEDIA = %.5f\n", f);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  D29(%rip),%xmm0
  movsd  D2(%rip),%xmm1
  lea    D38(%rip),%rdi
  mulsd  0x10(%rsp),%xmm1
  movsd  D8(%rip),%xmm2
  mulsd  0x8(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  divsd  D28(%rip),%xmm0
  cmpnlesd %xmm0,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm2,%xmm1
  orpd   %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: f64
name: retrieve_data
arguments: label: D2
type_guessed: f64
name: retrieve_data
arguments: label: D38
type_guessed: string
name: retrieve_data
arguments: label: D8
type_guessed: f64
name: retrieve_data
arguments: label: D28
type_guessed: f64

tool: D21: %lf %lf

tool: D29: 3.5

tool: D2: 7.5

tool: D38: MEDIA = %.5f


tool: D8: 10

tool: D28: 11

assistant: ```c
int main(void) {
  double a, b;
  scanf("%lf %lf", &a, &b);
  double f = (a * 3.5 + b * 7.5) / 11.0;
  f = f >= 10.0 ? 10.0 : f;
  printf("MEDIA = %.5f\n", f);
  return 0;
}
```