ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<IncopyOut2>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D1(%rip),%rbx
  cmp    (%rbx),%eax
  jne    L26
  jmp    L15
  nopl   0x0(%rax)
L54:
  mov    %eax,%edi
  call   <putchar@plt>
L55:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L15
L26:
  cmp    $0x9,%eax
  je     L83
  cmp    $0x8,%eax
  je     L43
  cmp    $0x5c,%eax
  jne    L54
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L26
L15:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L83:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L55
  xchg   %ax,%ax
L43:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L55
```

assistant: ```c
int IncopyOut2() {
  int ch;
  ch = getchar();
  while (ch != EOF) {
    if (ch == '\t') {
      putchar('\\');
      putchar('t');
    } else if (ch == '\b') {
      putchar('\\');
      putchar('b');
    } else if (ch == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(ch);
    }
    ch = getchar();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gleIntLoad_Version_3_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <gleIntClear@plt>
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_1_Version_3_1@plt>
  test   %eax,%eax
  jne    L49
  movl   $0x0,-0x4(%rbp)
L49:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_2_Version_3_1@plt>
  test   %eax,%eax
  jne    L77
  movl   $0x0,-0x4(%rbp)
L77:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_3_Version_3_1@plt>
  test   %eax,%eax
  jne    L20
  movl   $0x0,-0x4(%rbp)
L20:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_4_Version_3_1@plt>
  test   %eax,%eax
  jne    L22
  movl   $0x0,-0x4(%rbp)
L22:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_5_Version_3_1@plt>
  test   %eax,%eax
  jne    L19
  movl   $0x0,-0x4(%rbp)
L19:
  mov    $0x0,%eax
  call   <gleIntLoadCore_2_0_Version_3_1@plt>
  test   %eax,%eax
  jne    L27
  movl   $0x0,-0x4(%rbp)
L27:
  mov    $0x0,%eax
  call   <gleIntLoadCore_2_1_Version_3_1@plt>
  test   %eax,%eax
  jne    L59
  movl   $0x0,-0x4(%rbp)
L59:
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_0_Version_3_1@plt>
  test   %eax,%eax
  jne    L18
  movl   $0x0,-0x4(%rbp)
L18:
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  jne    L50
  movl   $0x0,-0x4(%rbp)
L50:
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  jne    L84
  movl   $0x0,-0x4(%rbp)
L84:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int gleIntLoad_Version_3_2() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gleIntLoad_Version_3_2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gleIntClear@plt>
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_1_Version_3_1@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_2_Version_3_1@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L2
  test   %ebp,%ebp
  setne  %bl
  movzbl %bl,%ebx
L2:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_3_Version_3_1@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_4_Version_3_1@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_5_Version_3_1@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_2_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_2_1_Version_3_1@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int gleIntLoad_Version_3_2() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gleIntLoad_Version_3_2>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <gleIntClear@plt>
  xor    %eax,%eax
  call   <gleIntLoadCore_1_1_Version_3_1@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <gleIntLoadCore_1_2_Version_3_1@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L5
  xor    %r12d,%r12d
  test   %ebx,%ebx
  setne  %r12b
L5:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <gleIntLoadCore_1_3_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_4_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_5_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_1_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int gleIntLoad_Version_3_2() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gleIntLoad_Version_3_2>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <gleIntClear@plt>
  xor    %eax,%eax
  call   <gleIntLoadCore_1_1_Version_3_1@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <gleIntLoadCore_1_2_Version_3_1@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L3
  xor    %r12d,%r12d
  test   %ebx,%ebx
  setne  %r12b
L3:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <gleIntLoadCore_1_3_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_4_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_5_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_1_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int gleIntLoad_Version_3_2() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitmap_test_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L100
  mov    $0x1,%eax
  jmp    L156
L100:
  movsbl -0x4(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  jne    L143
  mov    $0x2,%eax
  jmp    L156
L143:
  movsbl -0x4(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  jne    L52
  mov    $0x3,%eax
  jmp    L156
L52:
  movsbl -0x4(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L134
  mov    $0x4,%eax
  jmp    L156
L134:
  movsbl -0x4(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  jne    L51
  mov    $0x5,%eax
  jmp    L156
L51:
  movsbl -0x4(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  jne    L128
  mov    $0x6,%eax
  jmp    L156
L128:
  movsbl -0x4(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  jne    L9
  mov    $0x7,%eax
  jmp    L156
L9:
  cmpb   $0x0,-0x4(%rbp)
  js     L157
  mov    $0x8,%eax
  jmp    L156
L157:
  mov    $0x0,%eax
L156:
  pop    %rbp
  ret
```

assistant: ```c
int bitmap_test_free(char content) {
  if (!(content & 1)) {
    return 1;
  }
  if (!((content & 2) >> 1)) {
    return 2;
  }
  if (!((content & 4) >> 2)) {
    return 3;
  }
  if (!((content & 8) >> 3)) {
    return 4;
  }
  if (!((content & 16) >> 4)) {
    return 5;
  }
  if (!((content & 32) >> 5)) {
    return 6;
  }
  if (!((content & 64) >> 6)) {
    return 7;
  }
  if (!((content & 128) >> 7)) {
    return 8;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitmap_test_free>:
  endbr64
  mov    $0x1,%eax
  test   $0x1,%dil
  je     L39
  mov    $0x2,%eax
  test   $0x2,%dil
  je     L39
  mov    $0x3,%eax
  test   $0x4,%dil
  je     L39
  mov    $0x4,%eax
  test   $0x8,%dil
  je     L39
  mov    $0x5,%eax
  test   $0x10,%dil
  je     L39
  mov    $0x6,%eax
  test   $0x20,%dil
  je     L39
  mov    $0x7,%eax
  test   $0x40,%dil
  je     L39
  movsbl %dil,%edi
  not    %edi
  shr    $0x1f,%edi
  lea    0x0(,%rdi,8),%eax
L39:
  ret
```

assistant: ```c
int bitmap_test_free(char content) {
  if (!(content & 1)) {
    return 1;
  }
  if (!((content & 2) >> 1)) {
    return 2;
  }
  if (!((content & 4) >> 2)) {
    return 3;
  }
  if (!((content & 8) >> 3)) {
    return 4;
  }
  if (!((content & 16) >> 4)) {
    return 5;
  }
  if (!((content & 32) >> 5)) {
    return 6;
  }
  if (!((content & 64) >> 6)) {
    return 7;
  }
  if (!((content & 128) >> 7)) {
    return 8;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_test_free>:
  endbr64
  mov    $0x1,%eax
  test   $0x1,%dil
  je     L23
  mov    $0x2,%eax
  test   $0x2,%dil
  je     L23
  mov    $0x3,%eax
  test   $0x4,%dil
  je     L23
  mov    $0x4,%eax
  test   $0x8,%dil
  je     L23
  mov    $0x5,%eax
  test   $0x10,%dil
  je     L23
  mov    $0x6,%eax
  test   $0x20,%dil
  je     L23
  mov    $0x7,%eax
  test   $0x40,%dil
  je     L23
  movsbl %dil,%edi
  not    %edi
  shr    $0x1f,%edi
  lea    0x0(,%rdi,8),%eax
L23:
  ret
```

assistant: ```c
int bitmap_test_free(char content) {
  if (!(content & 1)) {
    return 1;
  }
  if (!((content & 2) >> 1)) {
    return 2;
  }
  if (!((content & 4) >> 2)) {
    return 3;
  }
  if (!((content & 8) >> 3)) {
    return 4;
  }
  if (!((content & 16) >> 4)) {
    return 5;
  }
  if (!((content & 32) >> 5)) {
    return 6;
  }
  if (!((content & 64) >> 6)) {
    return 7;
  }
  if (!((content & 128) >> 7)) {
    return 8;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_test_free>:
  endbr64
  mov    $0x1,%eax
  test   $0x1,%dil
  je     L42
  mov    $0x2,%eax
  test   $0x2,%dil
  je     L42
  mov    $0x3,%eax
  test   $0x4,%dil
  je     L42
  mov    $0x4,%eax
  test   $0x8,%dil
  je     L42
  mov    $0x5,%eax
  test   $0x10,%dil
  je     L42
  mov    $0x6,%eax
  test   $0x20,%dil
  je     L42
  mov    $0x7,%eax
  test   $0x40,%dil
  je     L42
  movsbl %dil,%edi
  not    %edi
  shr    $0x1f,%edi
  lea    0x0(,%rdi,8),%eax
L42:
  ret
```

assistant: ```c
int bitmap_test_free(char content) {
  if (!(content & 1)) {
    return 1;
  }
  if (!((content & 2) >> 1)) {
    return 2;
  }
  if (!((content & 4) >> 2)) {
    return 3;
  }
  if (!((content & 8) >> 3)) {
    return 4;
  }
  if (!((content & 16) >> 4)) {
    return 5;
  }
  if (!((content & 32) >> 5)) {
    return 6;
  }
  if (!((content & 64) >> 6)) {
    return 7;
  }
  if (!((content & 128) >> 7)) {
    return 8;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<addvecteur>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0x1c(%rbp),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  -0x1c(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  -0x1c(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void addvecteur(float *res, float *vect1, float *vect2, float speed) {
  res[0] = vect1[0] + vect2[0] * speed;
  res[1] = vect1[1] + vect2[1] * speed;
  res[2] = vect1[2] + vect2[2] * speed;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<addvecteur>:
  endbr64
  movaps %xmm0,%xmm1
  mulss  (%rdx),%xmm1
  addss  (%rsi),%xmm1
  movss  %xmm1,(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x4(%rdx),%xmm1
  addss  0x4(%rsi),%xmm1
  movss  %xmm1,0x4(%rdi)
  mulss  0x8(%rdx),%xmm0
  addss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void addvecteur(float *res, float *vect1, float *vect2, float speed) {
  res[0] = vect1[0] + vect2[0] * speed;
  res[1] = vect1[1] + vect2[1] * speed;
  res[2] = vect1[2] + vect2[2] * speed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<addvecteur>:
  endbr64
  movss  (%rdx),%xmm1
  mulss  %xmm0,%xmm1
  addss  (%rsi),%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rdx),%xmm1
  mulss  %xmm0,%xmm1
  addss  0x4(%rsi),%xmm1
  movss  %xmm1,0x4(%rdi)
  mulss  0x8(%rdx),%xmm0
  addss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void addvecteur(float *res, float *vect1, float *vect2, float speed) {
  res[0] = vect1[0] + vect2[0] * speed;
  res[1] = vect1[1] + vect2[1] * speed;
  res[2] = vect1[2] + vect2[2] * speed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<addvecteur>:
  endbr64
  movss  (%rdx),%xmm1
  mulss  %xmm0,%xmm1
  addss  (%rsi),%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rdx),%xmm1
  mulss  %xmm0,%xmm1
  addss  0x4(%rsi),%xmm1
  movss  %xmm1,0x4(%rdi)
  mulss  0x8(%rdx),%xmm0
  addss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void addvecteur(float *res, float *vect1, float *vect2, float speed) {
  res[0] = vect1[0] + vect2[0] * speed;
  res[1] = vect1[1] + vect2[1] * speed;
  res[2] = vect1[2] + vect2[2] * speed;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L64
  mov    $0x0,%eax
  jmp    L31
L64:
  movl   $0x0,-0x14(%rbp)
  jmp    L69
L32:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L72
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L31
L15:
  addl   $0x1,-0x14(%rbp)
L69:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L32
  jmp    L35
L72:
  nop
L35:
  mov    $0x0,%eax
L31:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int str_equal(const char *str1, const char *str2) {
  if (strlen(str1) != strlen(str2))
    return 0;
  for (int i = 0; i < strlen(str1); i++) {
    if (str1[i] != str2[i])
      break;
    if (i == strlen(str1) - 1)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_equal>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%ebx
  jne    L22
  mov    $0x0,%ebx
  jmp    L7
L11:
  add    $0x1,%rbx
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%r12d
  cmp    %ebx,%eax
  jle    L56
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  jne    L5
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  jne    L11
  mov    $0x1,%eax
  jmp    L22
L56:
  mov    $0x0,%eax
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    $0x0,%eax
  jmp    L22
```

assistant: ```c
int str_equal(const char *str1, const char *str2) {
  if (strlen(str1) != strlen(str2))
    return 0;
  for (int i = 0; i < strlen(str1); i++) {
    if (str1[i] != str2[i])
      break;
    if (i == strlen(str1) - 1)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_equal>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jne    L15
  xor    %ebx,%ebx
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  jne    L15
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  je     L33
  add    $0x1,%rbx
L10:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L12
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int str_equal(const char *str1, const char *str2) {
  if (strlen(str1) != strlen(str2))
    return 0;
  for (int i = 0; i < strlen(str1); i++) {
    if (str1[i] != str2[i])
      break;
    if (i == strlen(str1) - 1)
      return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_equal>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jne    L34
  xor    %ebx,%ebx
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L43:
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  jne    L34
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  je     L44
  add    $0x1,%rbx
L10:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L43
L34:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L44:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int str_equal(const char *str1, const char *str2) {
  if (strlen(str1) != strlen(str2))
    return 0;
  for (int i = 0; i < strlen(str1); i++) {
    if (str1[i] != str2[i])
      break;
    if (i == strlen(str1) - 1)
      return 1;
  }
  return 0;
}
```