ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x80(%rbp)
  jmp    L80
L62:
  addl   $0x1,-0x80(%rbp)
L80:
  mov    -0x80(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L62
  movl   $0x0,-0x7c(%rbp)
  movl   $0x1,-0x78(%rbp)
  mov    -0x80(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x74(%rbp)
  jmp    L74
L7:
  mov    -0x80(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L4
  movl   $0x0,-0x78(%rbp)
L4:
  subl   $0x1,-0x80(%rbp)
  addl   $0x1,-0x7c(%rbp)
L74:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jge    L59
  cmpl   $0x1,-0x78(%rbp)
  je     L7
L59:
  cmpl   $0x1,-0x78(%rbp)
  jne    L51
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L60
L51:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L60:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D41
type: string
name: retrieve_data
arguments: label: D35
type: string
name: retrieve_data
arguments: label: D37
type: string
name: retrieve_data
arguments: label: D12
type: string

tool: D0: Inserire una parola:

tool: D41: %s

tool: D35: 
Palindromo.

tool: D37: 
Non palindromo.

tool: D12: PAUSE

assistant: ```c
int main() {
  int cont;
  int i;
  char parola[100];
  int palindromo;
  int medio;
  printf("Inserire una parola:");
  scanf("%s", parola);
  cont = 0;
  while (parola[cont] != 0) {
    cont++;
  }
  i = 0;
  palindromo = 1;
  medio = cont / 2;
  while (i < medio && palindromo == 1) {
    if (parola[cont - 1] != parola[i]) {
      palindromo = 0;
    }
    cont--;
    i++;
  }
  if (palindromo == 1) {
    printf("\nPalindromo.");
  } else {
    printf("\nNon palindromo.");
  }
  system("PAUSE");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0x0,(%rsp)
  je     L12
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
L74:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,(%rcx,%rax,1)
  jne    L74
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %edx,%ecx
  sar    %ecx
  cmp    $0x1,%edx
  jle    L12
  movslq %edx,%rdx
  lea    (%rsp,%rdx,1),%rdx
  mov    $0x0,%eax
  mov    %rsp,%rsi
  jmp    L76
L37:
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%ecx
  jle    L12
L76:
  movzbl (%rsi,%rax,1),%edi
  cmp    %dil,-0x1(%rdx)
  je     L37
  lea    D31(%rip),%rdi
  call   <printf@plt>
L9:
  lea    D36(%rip),%rdi
  call   <system@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L12:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type: string
name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D31
type: string
name: retrieve_data
arguments: data_label: D36
type: string
name: retrieve_data
arguments: data_label: D11
type: string

tool: D20: Inserire una parola:

tool: D2: %s

tool: D31: 
Non palindromo.

tool: D36: PAUSE

tool: D11: 
Palindromo.

assistant: ```c
int main() {
  int cont;
  int i;
  char parola[100];
  int palindromo;
  int medio;
  printf("Inserire una parola:");
  scanf("%s", parola);
  cont = 0;
  while (parola[cont] != 0) {
    cont++;
  }
  i = 0;
  palindromo = 1;
  medio = cont / 2;
  while (i < medio && palindromo == 1) {
    if (parola[cont - 1] != parola[i]) {
      palindromo = 0;
    }
    cont--;
    i++;
  }
  if (palindromo == 1) {
    printf("\nPalindromo.");
  } else {
    printf("\nNon palindromo.");
  }
  system("PAUSE");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  lea    D27(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%ecx
  test   %cl,%cl
  je     L11
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rsi
  nopl   (%rax)
L38:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L38
  mov    %edx,%edi
  sar    %edi
  je     L11
  mov    $0x1,%eax
  add    %rbx,%rdx
  jmp    L62
  nopl   (%rax)
L49:
  movzbl (%rbx,%rax,1),%ecx
  add    $0x1,%rax
L62:
  mov    %rax,%rsi
  neg    %rsi
  movzbl (%rdx,%rsi,1),%esi
  cmp    %eax,%edi
  jle    L79
  cmp    %cl,%sil
  je     L49
L57:
  lea    D24(%rip),%rdi
  call   <printf@plt>
L66:
  lea    D14(%rip),%rdi
  call   <system@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L79:
  cmp    %cl,%sil
  jne    L57
L11:
  lea    D40(%rip),%rdi
  call   <printf@plt>
  jmp    L66
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
data_type: string
name: extract_symbolic_data
arguments: label: D22
data_type: string
name: extract_symbolic_data
arguments: label: D24
data_type: string
name: extract_symbolic_data
arguments: label: D14
data_type: string
name: extract_symbolic_data
arguments: label: D40
data_type: string

tool: D27: Inserire una parola:

tool: D22: %s

tool: D24: 
Non palindromo.

tool: D14: PAUSE

tool: D40: 
Palindromo.

assistant: ```c
int main() {
  int cont;
  int i;
  char parola[100];
  int palindromo;
  int medio;
  printf("Inserire una parola:");
  scanf("%s", parola);
  cont = 0;
  while (parola[cont] != 0) {
    cont++;
  }
  i = 0;
  palindromo = 1;
  medio = cont / 2;
  while (i < medio && palindromo == 1) {
    if (parola[cont - 1] != parola[i]) {
      palindromo = 0;
    }
    cont--;
    i++;
  }
  if (palindromo == 1) {
    printf("\nPalindromo.");
  } else {
    printf("\nNon palindromo.");
  }
  system("PAUSE");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D49(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0x0,(%rsp)
  je     L39
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rsi
  nopl   0x0(%rax,%rax,1)
L23:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L23
  mov    %edx,%r10d
  sar    %r10d
  je     L39
  mov    $0x1,%eax
  lea    (%rbx,%rdx,1),%r9
  xchg   %ax,%ax
L3:
  mov    %rax,%rdx
  neg    %rdx
  cmp    %eax,%r10d
  movzbl (%r9,%rdx,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  setg   %r8b
  cmp    %dl,%cl
  sete   %dil
  add    $0x1,%rax
  test   %dil,%r8b
  jne    L3
  cmp    %dl,%cl
  je     L39
  lea    D2(%rip),%rdi
  call   <printf@plt>
L53:
  lea    D15(%rip),%rdi
  call   <system@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L39:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D49
type: string
name: unpack_data
arguments: data_label: D43
type: string
name: unpack_data
arguments: data_label: D2
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D38
type: string

tool: D49: Inserire una parola:

tool: D43: %s

tool: D2: 
Non palindromo.

tool: D15: PAUSE

tool: D38: 
Palindromo.

assistant: ```c
int main() {
  int cont;
  int i;
  char parola[100];
  int palindromo;
  int medio;
  printf("Inserire una parola:");
  scanf("%s", parola);
  cont = 0;
  while (parola[cont] != 0) {
    cont++;
  }
  i = 0;
  palindromo = 1;
  medio = cont / 2;
  while (i < medio && palindromo == 1) {
    if (parola[cont - 1] != parola[i]) {
      palindromo = 0;
    }
    cont--;
    i++;
  }
  if (palindromo == 1) {
    printf("\nPalindromo.");
  } else {
    printf("\nNon palindromo.");
  }
  system("PAUSE");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itakura>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm2
  movaps %xmm2,%xmm4
  jmp    L8
L19:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movaps %xmm4,%xmm3
  addss  %xmm3,%xmm0
  movaps %xmm0,%xmm4
L8:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L19
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  movaps %xmm4,%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float itakura(int p, float *b, float *c, float *r, float *gain) {
  register float s;
  for (s = *c; p--;)
    s += *r++ * *b++;
  return (s / *gain);
}
```
user: Translate the below assembly code into C programming language:

```asm
<itakura>:
  endbr64
  movss  (%rdx),%xmm0
  test   %edi,%edi
  je     L4
  mov    %edi,%edi
  mov    $0x0,%eax
L0:
  movss  (%rcx,%rax,4),%xmm1
  mulss  (%rsi,%rax,4),%xmm1
  addss  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L0
L4:
  divss  (%r8),%xmm0
  ret
```

assistant: ```c
float itakura(int p, float *b, float *c, float *r, float *gain) {
  register float s;
  for (s = *c; p--;)
    s += *r++ * *b++;
  return (s / *gain);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itakura>:
  endbr64
  movss  (%rdx),%xmm0
  test   %edi,%edi
  je     L13
  mov    %edi,%edi
  xor    %eax,%eax
L3:
  movss  (%rcx,%rax,4),%xmm1
  mulss  (%rsi,%rax,4),%xmm1
  add    $0x1,%rax
  addss  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L3
L13:
  divss  (%r8),%xmm0
  ret
```

assistant: ```c
float itakura(int p, float *b, float *c, float *r, float *gain) {
  register float s;
  for (s = *c; p--;)
    s += *r++ * *b++;
  return (s / *gain);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<itakura>:
  endbr64
  mov    %rdx,%r9
  mov    %rcx,%rdx
  movss  (%r9),%xmm0
  lea    -0x1(%rdi),%r9d
  test   %edi,%edi
  je     L26
  cmp    $0x2,%r9d
  jbe    L1
  mov    %edi,%ecx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L2:
  movups (%rdx,%rax,1),%xmm1
  movups (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulps  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L2
  mov    %edi,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  sub    %ecx,%r9d
  shl    $0x2,%rax
  add    %rax,%rsi
  add    %rax,%rdx
  cmp    %ecx,%edi
  je     L26
L1:
  movss  (%rdx),%xmm1
  mulss  (%rsi),%xmm1
  addss  %xmm1,%xmm0
  test   %r9d,%r9d
  je     L26
  movss  0x4(%rdx),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  cmp    $0x1,%r9d
  je     L26
  movss  0x8(%rsi),%xmm1
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
L26:
  divss  (%r8),%xmm0
  ret
```

assistant: ```c
float itakura(int p, float *b, float *c, float *r, float *gain) {
  register float s;
  for (s = *c; p--;)
    s += *r++ * *b++;
  return (s / *gain);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copy_string_parse_katcl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <get_string_parse_katcl@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L3
L19:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
char *copy_string_parse_katcl(struct katcl_parse *p, unsigned int index) {
  char *ptr;
  ptr = get_string_parse_katcl(p, index);
  if (ptr) {
    return strdup(ptr);
  } else {
    return NULL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy_string_parse_katcl>:
  endbr64
  sub    $0x8,%rsp
  call   <get_string_parse_katcl@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rdi
  call   <strdup@plt>
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *copy_string_parse_katcl(struct katcl_parse *p, unsigned int index) {
  char *ptr;
  ptr = get_string_parse_katcl(p, index);
  if (ptr) {
    return strdup(ptr);
  } else {
    return NULL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<copy_string_parse_katcl>:
  endbr64
  sub    $0x8,%rsp
  call   <get_string_parse_katcl@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <strdup@plt>
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *copy_string_parse_katcl(struct katcl_parse *p, unsigned int index) {
  char *ptr;
  ptr = get_string_parse_katcl(p, index);
  if (ptr) {
    return strdup(ptr);
  } else {
    return NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_string_parse_katcl>:
  endbr64
  sub    $0x8,%rsp
  call   <get_string_parse_katcl@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <strdup@plt>
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *copy_string_parse_katcl(struct katcl_parse *p, unsigned int index) {
  char *ptr;
  ptr = get_string_parse_katcl(p, index);
  if (ptr) {
    return strdup(ptr);
  } else {
    return NULL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_dm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L20:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L57
L46:
  addl   $0x1,-0x10(%rbp)
L57:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L46
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L31
L7:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L7
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L20
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void print_dm(const double **rows, int np) {
  int i, j, k;
  const double *row;
  ;
  for (i = 0; i < np - 1; i++) {
    row = rows[i];
    for (j = 0; j <= i; j++) {
      ;
    }
    for (k = 0, j = i + 1; j < np; j++, k++) {
      ;
    };
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_dm>:
  endbr64
  cmp    $0x1,%esi
  jle    L60
  mov    $0x1,%edx
  jmp    L45
L36:
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L36
L73:
  mov    %edx,%eax
  cmp    %edx,%esi
  jle    L28
L7:
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L7
L28:
  add    $0x1,%edx
  cmp    %esi,%edx
  je     L60
L45:
  mov    $0x0,%eax
  mov    %edx,%ecx
  sub    $0x1,%ecx
  jns    L36
  jmp    L73
L60:
  ret
```

assistant: ```c
void print_dm(const double **rows, int np) {
  int i, j, k;
  const double *row;
  ;
  for (i = 0; i < np - 1; i++) {
    row = rows[i];
    for (j = 0; j <= i; j++) {
      ;
    }
    for (k = 0, j = i + 1; j < np; j++, k++) {
      ;
    };
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_dm>:
  endbr64
  ret
```

assistant: ```c
void print_dm(const double **rows, int np) {
  int i, j, k;
  const double *row;
  ;
  for (i = 0; i < np - 1; i++) {
    row = rows[i];
    for (j = 0; j <= i; j++) {
      ;
    }
    for (k = 0, j = i + 1; j < np; j++, k++) {
      ;
    };
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_dm>:
  endbr64
  ret
```

assistant: ```c
void print_dm(const double **rows, int np) {
  int i, j, k;
  const double *row;
  ;
  for (i = 0; i < np - 1; i++) {
    row = rows[i];
    for (j = 0; j <= i; j++) {
      ;
    }
    for (k = 0, j = i + 1; j < np; j++, k++) {
      ;
    };
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<directory_part>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L35
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L15
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L32
L15:
  subl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  nop
L32:
  nop
  leave
  ret
```

assistant: ```c
void directory_part(char *filename) {
  int i;
  for (i = strlen(filename) - 1; i >= 0; i--) {
    if (filename[i] == '/') {
      filename[i + 1] = 0;
      break;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<directory_part>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L24
  cltq
L22:
  cmpb   $0x2f,(%rbx,%rax,1)
  je     L6
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L22
  jmp    L24
L6:
  movb   $0x0,0x1(%rbx,%rax,1)
L24:
  pop    %rbx
  ret
```

assistant: ```c
void directory_part(char *filename) {
  int i;
  for (i = strlen(filename) - 1; i >= 0; i--) {
    if (filename[i] == '/') {
      filename[i + 1] = 0;
      break;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<directory_part>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L32
  cltq
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L11:
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  je     L32
L3:
  cmpb   $0x2f,(%rbx,%rax,1)
  jne    L11
  movb   $0x0,0x1(%rbx,%rax,1)
L32:
  pop    %rbx
  ret
```

assistant: ```c
void directory_part(char *filename) {
  int i;
  for (i = strlen(filename) - 1; i >= 0; i--) {
    if (filename[i] == '/') {
      filename[i + 1] = 0;
      break;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<directory_part>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L32
  cltq
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L15:
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  je     L32
L11:
  cmpb   $0x2f,(%rbx,%rax,1)
  jne    L15
  movb   $0x0,0x1(%rbx,%rax,1)
L32:
  pop    %rbx
  ret
```

assistant: ```c
void directory_part(char *filename) {
  int i;
  for (i = strlen(filename) - 1; i >= 0; i--) {
    if (filename[i] == '/') {
      filename[i + 1] = 0;
      break;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sys_cpu_pstate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  lea    D54(%rip),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L45
L34:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D82(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L45
L2:
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D82(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L45
L11:
  cmpl   $0x0,-0x1c(%rbp)
  sete   %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  lea    D82(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L45:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D54
type: string
name: parse_data
arguments: label: D67
type: string
name: parse_data
arguments: label: D82
type: string
name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D39
type: string

tool: D54: w

tool: D67: /sys/devices/system/cpu/intel_pstate/min_perf_pct

tool: D82: %i


tool: D3: /sys/devices/system/cpu/intel_pstate/max_perf_pct

tool: D39: /sys/devices/system/cpu/intel_pstate/no_turbo

assistant: ```c
int sys_cpu_pstate(int min, int max, int turbo) {
  FILE *f;
  f = fopen("/sys/devices/system/cpu/intel_pstate/min_perf_pct", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", min);
  fclose(f);
  f = fopen("/sys/devices/system/cpu/intel_pstate/max_perf_pct", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", max);
  fclose(f);
  f = fopen("/sys/devices/system/cpu/intel_pstate/no_turbo", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", turbo ? 0 : 1);
  fclose(f);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sys_cpu_pstate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%ebp
  mov    %edx,%r12d
  lea    D12(%rip),%rsi
  lea    D87(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L17
  mov    %r13d,%edx
  lea    D25(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    D12(%rip),%rsi
  lea    D53(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L17
  mov    %ebp,%edx
  lea    D25(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    D12(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L17
  test   %r12d,%r12d
  sete   %dl
  movzbl %dl,%edx
  lea    D25(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D87
type_guessed: string
name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D53
type_guessed: string
name: extract_symbolic_data
arguments: tag: D16
type_guessed: string

tool: D12: w

tool: D87: /sys/devices/system/cpu/intel_pstate/min_perf_pct

tool: D25: %i


tool: D53: /sys/devices/system/cpu/intel_pstate/max_perf_pct

tool: D16: /sys/devices/system/cpu/intel_pstate/no_turbo

assistant: ```c
int sys_cpu_pstate(int min, int max, int turbo) {
  FILE *f;
  f = fopen("/sys/devices/system/cpu/intel_pstate/min_perf_pct", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", min);
  fclose(f);
  f = fopen("/sys/devices/system/cpu/intel_pstate/max_perf_pct", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", max);
  fclose(f);
  f = fopen("/sys/devices/system/cpu/intel_pstate/no_turbo", "w");
  if (!f)
    return 0;
  fprintf(f, "%i\n", turbo ? 0 : 1);
  fclose(f);
  return 1;
}
```