ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<miller>:
  endbr64
  cmp    $0x1,%rdi
  jle    L64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cmp    $0x2,%rdi
  je     L160
  test   $0x1,%dil
  je     L176
  lea    -0x1(%rdi),%rbx
  je     L160
  mov    %rbx,%r12
  nopl   0x0(%rax,%rax,1)
L54:
  sar    %r12
  test   $0x1,%r12b
  je     L54
L93:
  xor    %r13d,%r13d
  test   %r14,%r14
  jle    L71
  nopl   0x0(%rax)
L142:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rsi
  cqto
  idiv   %rbx
  lea    0x1(%rdx),%rdi
  mov    %rbp,%rdx
  call   <mod@plt>
  mov    %rax,%rdi
  cmp    %rbx,%r12
  je     L101
  cmp    $0x1,%rax
  je     L101
  cmp    %rbx,%rax
  je     L138
  mov    %r12,%r15
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    $0x1,%rax
  je     L18
  cmp    %rbx,%rax
  je     L138
L19:
  mov    %rdi,%rsi
  mov    %rbp,%rdx
  add    %r15,%r15
  call   <mul@plt>
  mov    %rax,%rdi
  cmp    %rbx,%r15
  jne    L0
L18:
  cmp    %rbx,%rdi
  je     L138
  and    $0x1,%r15d
  je     L176
L138:
  add    $0x1,%r13
  cmp    %r13,%r14
  jne    L142
L71:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L176:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L101:
  mov    %r12,%r15
  jmp    L18
L160:
  mov    %rbx,%r12
  jmp    L93
L64:
  xor    %eax,%eax
  ret
```

assistant: ```c
int miller(long long p, long long it) {
  if (p < 2)
    return 0;
  if (p != 2 && p % 2 == 0)
    return 0;
  long long s, i, a, tt, md;
  s = p - 1;
  while (s % 2 == 0)
    s /= 2;
  for (i = 0; i < it; i++) {
    a = rand() % (p - 1) + 1;
    tt = s;
    md = mod(a, tt, p);
    while (tt != p - 1 && md != 1 && md != p - 1) {
      md = mul(md, md, p);
      tt *= 2;
    }
    if (md != p - 1 && tt % 2 == 0)
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delaySeconds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nop
  leave
  ret
```

assistant: ```c
void delaySeconds(int sec) {
  usleep((sec * 1000 * 1000));
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<delaySeconds>:
  endbr64
  sub    $0x8,%rsp
  imul   $0xf4240,%edi,%edi
  call   <usleep@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void delaySeconds(int sec) {
  usleep((sec * 1000 * 1000));
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<delaySeconds>:
  endbr64
  imul   $0xf4240,%edi,%edi
  jmp    1050 <usleep@plt>
```

assistant: ```c
void delaySeconds(int sec) {
  usleep((sec * 1000 * 1000));
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<delaySeconds>:
  endbr64
  imul   $0xf4240,%edi,%edi
  jmp    1050 <usleep@plt>
```

assistant: ```c
void delaySeconds(int sec) {
  usleep((sec * 1000 * 1000));
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L26
  mov    $0xffffffff,%eax
  jmp    L19
L2:
  mov    $0x0,%eax
  call   <inbyte@plt>
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x4(%rbp)
L26:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jg     L2
  mov    -0x18(%rbp),%eax
L19:
  leave
  ret
```

assistant: ```c
int read(int fd, char *buf, int len) {
  int _len = len;
  if (fd != 0)
    return (-1);
  while (len-- > 0) {
    *buf++ = inbyte();
    _len--;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read>:
  endbr64
  test   %edi,%edi
  jne    L3
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L8
  mov    %edx,%edx
  lea    (%rsi,%rdx,1),%rbp
L0:
  mov    $0x0,%eax
  call   <inbyte@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L0
  mov    $0xffffffff,%eax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int read(int fd, char *buf, int len) {
  int _len = len;
  if (fd != 0)
    return (-1);
  while (len-- > 0) {
    *buf++ = inbyte();
    _len--;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read>:
  endbr64
  test   %edi,%edi
  jne    L7
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L29
  push   %rbp
  movslq %edx,%rdx
  push   %rbx
  lea    (%rsi,%rdx,1),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nop
L27:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <inbyte@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L27
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L29:
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int read(int fd, char *buf, int len) {
  int _len = len;
  if (fd != 0)
    return (-1);
  while (len-- > 0) {
    *buf++ = inbyte();
    _len--;
  }
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read>:
  endbr64
  test   %edi,%edi
  jne    L7
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L5
  push   %rbp
  movslq %edx,%rdx
  push   %rbx
  lea    (%rsi,%rdx,1),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nop
L20:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <inbyte@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L20
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L5:
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int read(int fd, char *buf, int len) {
  int _len = len;
  if (fd != 0)
    return (-1);
  while (len-- > 0) {
    *buf++ = inbyte();
    _len--;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void my_swap(int *a, int *b) {
  int swap;
  swap = *b;
  *b = *a;
  *a = swap;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_swap>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void my_swap(int *a, int *b) {
  int swap;
  swap = *b;
  *b = *a;
  *a = swap;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_swap>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void my_swap(int *a, int *b) {
  int swap;
  swap = *b;
  *b = *a;
  *a = swap;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_swap>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void my_swap(int *a, int *b) {
  int swap;
  swap = *b;
  *b = *a;
  *a = swap;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L124
L104:
  addl   $0x1,-0x8(%rbp)
L124:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L104
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L104
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L104
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xc,%al
  je     L104
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L104
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xb,%al
  je     L104
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L17
  movl   $0xffffffff,-0x4(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L40
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L41
L40:
  addl   $0x1,-0x8(%rbp)
L41:
  movl   $0x0,-0xc(%rbp)
  jmp    L77
L123:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L77:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L71
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L123
L71:
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  int nb;
  int i;
  int sign;
  i = 0;
  sign = 1;
  while (str[i] == ' ' || str[i] == '\t' || str[i] == '\n' || str[i] == '\f' || str[i] == '\r' || str[i] == '\v')
    i++;
  if (str[i] == '-')
    sign = -1;
  if (str[i] == '-' || str[i] == '+')
    i++;
  nb = 0;
  while (str[i] >= '0' && str[i] <= '9')
    nb = (nb * 10) + (str[i++] - '0');
  return (nb * sign);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_atoi>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L12
  cmp    $0x20,%dl
  jne    L5
L12:
  mov    $0x1,%eax
L106:
  mov    %eax,%esi
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L106
  cmp    $0x20,%dl
  je     L106
L2:
  cmp    $0x2d,%dl
  je     L10
  sub    $0x2b,%edx
  mov    $0x1,%eax
  test   $0xfd,%dl
  je     L11
L3:
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L74
  lea    0x1(%rdi,%rsi,1),%rsi
  mov    $0x0,%ecx
L23:
  lea    (%rcx,%rcx,4),%ecx
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rcx,2),%ecx
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  jbe    L23
L67:
  imul   %ecx,%eax
  ret
L5:
  mov    $0x0,%esi
  jmp    L2
L10:
  mov    $0xffffffff,%eax
L11:
  add    $0x1,%esi
  jmp    L3
L74:
  mov    $0x0,%ecx
  jmp    L67
```

assistant: ```c
int ft_atoi(const char *str) {
  int nb;
  int i;
  int sign;
  i = 0;
  sign = 1;
  while (str[i] == ' ' || str[i] == '\t' || str[i] == '\n' || str[i] == '\f' || str[i] == '\r' || str[i] == '\v')
    i++;
  if (str[i] == '-')
    sign = -1;
  if (str[i] == '-' || str[i] == '+')
    i++;
  nb = 0;
  while (str[i] >= '0' && str[i] <= '9')
    nb = (nb * 10) + (str[i++] - '0');
  return (nb * sign);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_atoi>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L48
  cmp    $0x20,%dl
  jne    L24
L48:
  mov    $0x1,%eax
  nopl   0x0(%rax)
L7:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L7
  cmp    $0x20,%dl
  je     L7
L37:
  cmp    $0x2d,%dl
  je     L21
  mov    $0x1,%r8d
  cmp    $0x2b,%dl
  je     L31
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L32
L87:
  lea    0x1(%rdi,%rsi,1),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L17:
  sub    $0x30,%edx
  lea    (%rax,%rax,4),%eax
  add    $0x1,%rcx
  movsbl %dl,%edx
  lea    (%rdx,%rax,2),%eax
  movzbl -0x1(%rcx),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L17
  imul   %r8d,%eax
  ret
L21:
  mov    $0xffffffff,%r8d
L31:
  add    $0x1,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L87
L32:
  xor    %eax,%eax
  ret
L24:
  xor    %esi,%esi
  jmp    L37
```

assistant: ```c
int ft_atoi(const char *str) {
  int nb;
  int i;
  int sign;
  i = 0;
  sign = 1;
  while (str[i] == ' ' || str[i] == '\t' || str[i] == '\n' || str[i] == '\f' || str[i] == '\r' || str[i] == '\v')
    i++;
  if (str[i] == '-')
    sign = -1;
  if (str[i] == '-' || str[i] == '+')
    i++;
  nb = 0;
  while (str[i] >= '0' && str[i] <= '9')
    nb = (nb * 10) + (str[i++] - '0');
  return (nb * sign);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_atoi>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L76
  cmp    $0x20,%dl
  jne    L56
L76:
  mov    $0x1,%eax
  nopl   0x0(%rax)
L65:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L65
  cmp    $0x20,%dl
  je     L65
L17:
  cmp    $0x2d,%dl
  je     L34
  mov    $0x1,%r8d
  cmp    $0x2b,%dl
  je     L64
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L30
L5:
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    0x1(%rdi,%rsi,1),%rcx
  nopl   0x0(%rax,%rax,1)
L16:
  sub    $0x30,%edx
  lea    (%rax,%rax,4),%eax
  add    $0x1,%rcx
  movsbl %dl,%edx
  lea    (%rdx,%rax,2),%eax
  movzbl -0x1(%rcx),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L16
  imul   %r8d,%eax
  ret
L34:
  mov    $0xffffffff,%r8d
L64:
  add    $0x1,%esi
  movslq %esi,%rax
  movzbl (%rdi,%rax,1),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L5
L30:
  xor    %eax,%eax
  ret
L56:
  xor    %esi,%esi
  jmp    L17
```

assistant: ```c
int ft_atoi(const char *str) {
  int nb;
  int i;
  int sign;
  i = 0;
  sign = 1;
  while (str[i] == ' ' || str[i] == '\t' || str[i] == '\n' || str[i] == '\f' || str[i] == '\r' || str[i] == '\v')
    i++;
  if (str[i] == '-')
    sign = -1;
  if (str[i] == '-' || str[i] == '+')
    i++;
  nb = 0;
  while (str[i] >= '0' && str[i] <= '9')
    nb = (nb * 10) + (str[i++] - '0');
  return (nb * sign);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L64
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x40,-0x9(%rbp)
  jle    L4
  cmpb   $0x5a,-0x9(%rbp)
  jg     L4
  movzbl -0x9(%rbp),%eax
  add    $0x20,%eax
  mov    %al,-0x9(%rbp)
L4:
  cmpb   $0x2f,-0x9(%rbp)
  jle    L72
  cmpb   $0x39,-0x9(%rbp)
  jg     L72
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movsbl -0x9(%rbp),%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L34
L72:
  cmpb   $0x60,-0x9(%rbp)
  jle    L34
  cmpb   $0x66,-0x9(%rbp)
  jg     L34
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movsbl -0x9(%rbp),%eax
  sub    $0x57,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L34:
  movsbl -0x9(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L64:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string

tool: D3: %d %d


assistant: ```c
int htoi(char s[]) {
  int i;
  char c;
  int n = 0;
  for (i = 0; s[i] != '\0'; ++i) {
    c = s[i];
    if (c >= 'A' && c <= 'Z') {
      c = c - ('A' - 'a');
    }
    if (c >= '0' && c <= '9') {
      n = n * 16 + (c - '0');
    } else if (c >= 'a' && c <= 'f') {
      n = n * 16 + (c - 'a' + 10);
    }
    printf("%d %d\n", c, n);
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<htoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L30
  lea    0x1(%rdi),%rbp
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
  jmp    L3
L13:
  lea    -0x30(%rsi),%edx
  cmp    $0x9,%dl
  ja     L16
  shl    $0x4,%ebx
  movsbl %sil,%eax
  lea    -0x30(%rbx,%rax,1),%ebx
L9:
  movsbl %sil,%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%esi
  test   %sil,%sil
  je     L56
L3:
  mov    %esi,%eax
  lea    -0x41(%rsi),%edx
  cmp    $0x19,%dl
  ja     L13
  lea    0x20(%rsi),%eax
  mov    %eax,%esi
L16:
  sub    $0x61,%eax
  cmp    $0x5,%al
  ja     L9
  shl    $0x4,%ebx
  movsbl %sil,%eax
  lea    -0x57(%rbx,%rax,1),%ebx
  jmp    L9
L30:
  mov    $0x0,%ebx
L56:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string

tool: D4: %d %d


assistant: ```c
int htoi(char s[]) {
  int i;
  char c;
  int n = 0;
  for (i = 0; s[i] != '\0'; ++i) {
    c = s[i];
    if (c >= 'A' && c <= 'Z') {
      c = c - ('A' - 'a');
    }
    if (c >= '0' && c <= '9') {
      n = n * 16 + (c - '0');
    } else if (c >= 'a' && c <= 'f') {
      n = n * 16 + (c - 'a' + 10);
    }
    printf("%d %d\n", c, n);
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<htoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L1
  lea    0x1(%rdi),%rbp
  xor    %r12d,%r12d
  lea    D8(%rip),%rbx
  jmp    L46
L30:
  add    $0x20,%esi
L2:
  cmp    $0x5,%al
  ja     L54
  lea    -0x57(%rsi),%eax
  shl    $0x4,%r12d
  movsbl %al,%eax
  add    %eax,%r12d
L54:
  movsbl %sil,%esi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  movzbl -0x1(%rbp),%esi
  test   %sil,%sil
  je     L5
L46:
  lea    -0x41(%rsi),%eax
  cmp    $0x19,%al
  jbe    L30
  lea    -0x30(%rsi),%eax
  cmp    $0x9,%al
  ja     L60
  shl    $0x4,%r12d
  movsbl %al,%eax
  add    %eax,%r12d
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r12d,%r12d
L5:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L60:
  lea    -0x61(%rsi),%eax
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: %d %d


assistant: ```c
int htoi(char s[]) {
  int i;
  char c;
  int n = 0;
  for (i = 0; s[i] != '\0'; ++i) {
    c = s[i];
    if (c >= 'A' && c <= 'Z') {
      c = c - ('A' - 'a');
    }
    if (c >= '0' && c <= '9') {
      n = n * 16 + (c - '0');
    } else if (c >= 'a' && c <= 'f') {
      n = n * 16 + (c - 'a' + 10);
    }
    printf("%d %d\n", c, n);
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<htoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L68
  lea    0x1(%rdi),%rbp
  xor    %r12d,%r12d
  lea    D0(%rip),%rbx
  jmp    L7
L53:
  add    $0x20,%esi
L66:
  cmp    $0x5,%al
  ja     L25
  lea    -0x57(%rsi),%eax
  shl    $0x4,%r12d
  movsbl %al,%eax
  add    %eax,%r12d
L25:
  movsbl %sil,%esi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  movzbl -0x1(%rbp),%esi
  test   %sil,%sil
  je     L32
L7:
  lea    -0x41(%rsi),%eax
  cmp    $0x19,%al
  jbe    L53
  lea    -0x30(%rsi),%eax
  cmp    $0x9,%al
  ja     L20
  shl    $0x4,%r12d
  movsbl %al,%eax
  add    %eax,%r12d
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L68:
  xor    %r12d,%r12d
L32:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  lea    -0x61(%rsi),%eax
  jmp    L66
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: %d %d


assistant: ```c
int htoi(char s[]) {
  int i;
  char c;
  int n = 0;
  for (i = 0; s[i] != '\0'; ++i) {
    c = s[i];
    if (c >= 'A' && c <= 'Z') {
      c = c - ('A' - 'a');
    }
    if (c >= '0' && c <= '9') {
      n = n * 16 + (c - '0');
    } else if (c >= 'a' && c <= 'f') {
      n = n * 16 + (c - 'a' + 10);
    }
    printf("%d %d\n", c, n);
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CheckPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L19
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L19
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  jmp    L2
L19:
  addl   $0x1,-0x4(%rbp)
  jmp    L4
L2:
  pop    %rbp
  ret
```

assistant: ```c
CheckPrime(int K, int Prime[]) {
  int J;
  J = 1;
  while (1) {
    if (Prime[J] == 1)
      if (K % J == 0) {
        Prime[K] = 0;
        return;
      }
    J++;
  }
  Prime[K] = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CheckPrime>:
  endbr64
  mov    $0x1,%ecx
  jmp    L22
L0:
  add    $0x1,%rcx
L22:
  cmpl   $0x1,(%rsi,%rcx,4)
  jne    L0
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L0
  movslq %edi,%rdi
  movl   $0x0,(%rsi,%rdi,4)
  mov    $0x0,%eax
  ret
```

assistant: ```c
CheckPrime(int K, int Prime[]) {
  int J;
  J = 1;
  while (1) {
    if (Prime[J] == 1)
      if (K % J == 0) {
        Prime[K] = 0;
        return;
      }
    J++;
  }
  Prime[K] = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CheckPrime>:
  endbr64
  movslq %edi,%rdi
  movl   $0x0,(%rsi,%rdi,4)
  ret
```

assistant: ```c
CheckPrime(int K, int Prime[]) {
  int J;
  J = 1;
  while (1) {
    if (Prime[J] == 1)
      if (K % J == 0) {
        Prime[K] = 0;
        return;
      }
    J++;
  }
  Prime[K] = 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<CheckPrime>:
  endbr64
  movslq %edi,%rdi
  movl   $0x0,(%rsi,%rdi,4)
  ret
```

assistant: ```c
CheckPrime(int K, int Prime[]) {
  int J;
  J = 1;
  while (1) {
    if (Prime[J] == 1)
      if (K % J == 0) {
        Prime[K] = 0;
        return;
      }
    J++;
  }
  Prime[K] = 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sys_PrintString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L11:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sys_PrintChar@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void sys_PrintString(unsigned int *str) {
  unsigned int i;
  for (i = 0; str[i] != '\0'; i++) {
    sys_PrintChar(str[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sys_PrintString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%edi
  test   %edi,%edi
  je     L10
  mov    $0x0,%ebx
L18:
  call   <sys_PrintChar@plt>
  add    $0x1,%ebx
  mov    %ebx,%eax
  mov    0x0(%rbp,%rax,4),%edi
  test   %edi,%edi
  jne    L18
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sys_PrintString(unsigned int *str) {
  unsigned int i;
  for (i = 0; str[i] != '\0'; i++) {
    sys_PrintChar(str[i]);
  }
}
```