ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_collapse>:
  endbr64
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L4:
  mov    $0x10,%r12d
L26:
  mov    $0x10,%ebp
  nop
L8:
  mov    $0x10,%ebx
  nopl   (%rax)
L7:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L7
  sub    $0x1,%ebp
  jne    L8
  sub    $0x1,%r12d
  jne    L26
  sub    $0x1,%r13d
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp target teams distribute collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp target teams distribute collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute collapse(2) firstprivate(i)
  for (i = 0; i < 16; ++i)
    for (int j = 0; j < 16; ++j)
#pragma omp parallel for reduction(+ : i, j)
      for (int k = 0; k < 16; ++k)
        i += j;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x41,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: %s

assistant: ```c
int main() {
  char str[1024];
  memset(str, 65, 10);
  printf("%s", str);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0xa,%edx
  mov    $0x41,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: %s

assistant: ```c
int main() {
  char str[1024];
  memset(str, 65, 10);
  printf("%s", str);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x41,%esi
  mov    $0xa,%edx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: %s

assistant: ```c
int main() {
  char str[1024];
  memset(str, 65, 10);
  printf("%s", str);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x41,%esi
  mov    $0xa,%edx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D1: %s

assistant: ```c
int main() {
  char str[1024];
  memset(str, 65, 10);
  printf("%s", str);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fat_raw_to_humanreadable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L62:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jbe    L100
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  ja     L100
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    $0x20,%edx
  mov    %dl,(%rax)
L100:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L9
  cmpl   $0x8,-0x8(%rbp)
  jg     L9
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L60
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2e,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x8(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x9(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x3(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xa(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L48
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L48:
  cmpl   $0xb,-0x4(%rbp)
  jle    L21
  jmp    L9
L60:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L77
L9:
  addl   $0x1,-0x8(%rbp)
L31:
  cmpl   $0xb,-0x8(%rbp)
  jle    L62
  nop
L77:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fat_raw_to_humanreadable(unsigned char filename[11]) {
  int i;
  for (i = 0; i <= 11; i++) {
    if (filename[i] >= 'A' && filename[i] <= 'Z')
      filename[i] = filename[i] + 32;
    if (filename[i] == ' ') {
      if (i <= 8) {
        if (filename[8] != 32) {
          filename[i] = '.';
          filename[i + 1] = filename[8];
          filename[i + 2] = filename[9];
          filename[i + 3] = filename[10];
          int k;
          for (k = i + 4; k <= 11; k++)
            filename[k] = '\0';
        } else {
          filename[i] = '\0';
          break;
        }
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fat_raw_to_humanreadable>:
  endbr64
  mov    %rdi,%r9
  mov    %rdi,%rdx
  mov    $0x4,%edi
  mov    $0x1,%ecx
  mov    $0x8,%r10d
  jmp    L36
L3:
  lea    -0x1(%rcx),%esi
  cmp    $0x8,%esi
  jg     L9
  cmp    $0x20,%al
  jne    L9
  cmpb   $0x20,0x8(%r9)
  je     L44
  movb   $0x2e,(%rdx)
  movzbl 0x8(%r9),%eax
  mov    %al,0x1(%rdx)
  movzbl 0x9(%r9),%eax
  mov    %al,0x2(%rdx)
  movzbl 0xa(%r9),%eax
  mov    %al,0x3(%rdx)
  cmp    $0xb,%edi
  jg     L79
  lea    0x4(%rdx),%rax
  mov    %r10d,%esi
  sub    %ecx,%esi
  lea    0x5(%rdx,%rsi,1),%rsi
L12:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L12
  jmp    L79
L44:
  movb   $0x0,(%rdx)
  ret
L9:
  cmp    $0xb,%ecx
  jg     L41
L79:
  add    $0x1,%rdx
  add    $0x1,%ecx
  add    $0x1,%edi
L36:
  movzbl (%rdx),%eax
  lea    -0x41(%rax),%esi
  cmp    $0x19,%sil
  ja     L3
  add    $0x20,%eax
  mov    %al,(%rdx)
  jmp    L9
L41:
  ret
```

assistant: ```c
void fat_raw_to_humanreadable(unsigned char filename[11]) {
  int i;
  for (i = 0; i <= 11; i++) {
    if (filename[i] >= 'A' && filename[i] <= 'Z')
      filename[i] = filename[i] + 32;
    if (filename[i] == ' ') {
      if (i <= 8) {
        if (filename[8] != 32) {
          filename[i] = '.';
          filename[i + 1] = filename[8];
          filename[i + 2] = filename[9];
          filename[i + 3] = filename[10];
          int k;
          for (k = i + 4; k <= 11; k++)
            filename[k] = '\0';
        } else {
          filename[i] = '\0';
          break;
        }
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fat_raw_to_humanreadable>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x8,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L75
  nopl   0x0(%rax)
L62:
  add    $0x20,%eax
  mov    %al,(%rbx)
L67:
  cmp    $0xc,%ebp
  je     L59
L60:
  add    $0x1,%rbx
  add    $0x1,%ebp
L75:
  movzbl (%rbx),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  jbe    L62
  lea    -0x1(%rbp),%edx
  cmp    $0x8,%edx
  jg     L67
  cmp    $0x20,%al
  jne    L67
  cmpb   $0x20,0x8(%r13)
  je     L38
  movb   $0x2e,(%rbx)
  movzbl 0x8(%r13),%eax
  mov    %al,0x1(%rbx)
  movzbl 0x9(%r13),%eax
  mov    %al,0x2(%rbx)
  movzbl 0xa(%r13),%eax
  mov    %al,0x3(%rbx)
  cmp    $0x9,%ebp
  je     L60
  mov    %r12d,%edx
  lea    0x4(%rbx),%rdi
  xor    %esi,%esi
  sub    %ebp,%edx
  add    $0x1,%rdx
  call   <memset@plt>
  jmp    L60
L38:
  movb   $0x0,(%rbx)
L59:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void fat_raw_to_humanreadable(unsigned char filename[11]) {
  int i;
  for (i = 0; i <= 11; i++) {
    if (filename[i] >= 'A' && filename[i] <= 'Z')
      filename[i] = filename[i] + 32;
    if (filename[i] == ' ') {
      if (i <= 8) {
        if (filename[8] != 32) {
          filename[i] = '.';
          filename[i + 1] = filename[8];
          filename[i + 2] = filename[9];
          filename[i + 3] = filename[10];
          int k;
          for (k = i + 4; k <= 11; k++)
            filename[k] = '\0';
        } else {
          filename[i] = '\0';
          break;
        }
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fat_raw_to_humanreadable>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x8,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L79
  nopl   0x0(%rax)
L70:
  add    $0x20,%eax
  mov    %al,(%rbx)
L7:
  cmp    $0xc,%ebp
  je     L67
L16:
  add    $0x1,%rbx
  add    $0x1,%ebp
L79:
  movzbl (%rbx),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  jbe    L70
  lea    -0x1(%rbp),%edx
  cmp    $0x8,%edx
  jg     L7
  cmp    $0x20,%al
  jne    L7
  cmpb   $0x20,0x8(%r13)
  je     L29
  movb   $0x2e,(%rbx)
  movzbl 0x8(%r13),%eax
  mov    %al,0x1(%rbx)
  movzbl 0x9(%r13),%eax
  mov    %al,0x2(%rbx)
  movzbl 0xa(%r13),%eax
  mov    %al,0x3(%rbx)
  cmp    $0x9,%ebp
  je     L16
  mov    %r12d,%edx
  lea    0x4(%rbx),%rdi
  xor    %esi,%esi
  sub    %ebp,%edx
  add    $0x1,%rdx
  call   <memset@plt>
  jmp    L16
L29:
  movb   $0x0,(%rbx)
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void fat_raw_to_humanreadable(unsigned char filename[11]) {
  int i;
  for (i = 0; i <= 11; i++) {
    if (filename[i] >= 'A' && filename[i] <= 'Z')
      filename[i] = filename[i] + 32;
    if (filename[i] == ' ') {
      if (i <= 8) {
        if (filename[8] != 32) {
          filename[i] = '.';
          filename[i + 1] = filename[8];
          filename[i + 2] = filename[9];
          filename[i + 3] = filename[10];
          int k;
          for (k = i + 4; k <= 11; k++)
            filename[k] = '\0';
        } else {
          filename[i] = '\0';
          break;
        }
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<FindHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0xffffffff,(%rax)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L41:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L24
  addl   $0x1,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L24:
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L41
  cmpl   $0x1,-0x4(%rbp)
  je     L48
  mov    $0x1,%eax
  jmp    L25
L48:
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L25:
  leave
  ret
```

assistant: ```c
int FindHeader(char *token, char **headerNames, int nHeaders, int *index) {
  int i, match = 0, nMatches;
  *index = -1;
  nMatches = 0;
  for (i = 0; i < nHeaders; i++) {
    if (!strcmp(token, headerNames[i])) {
      nMatches++;
      match = i;
    }
  }
  if (nMatches != 1)
    return (1);
  *index = match;
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<FindHeader>:
  endbr64
  movl   $0xffffffff,(%rcx)
  test   %edx,%edx
  jle    L21
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rcx,%r15
  mov    %edx,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  movl   $0x0,0xc(%rsp)
  jmp    L46
L8:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L29
L46:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L8
  add    $0x1,%r14d
  mov    %ebx,0xc(%rsp)
  jmp    L8
L29:
  mov    $0x1,%eax
  cmp    $0x1,%r14d
  jne    L33
  mov    0xc(%rsp),%eax
  mov    %eax,(%r15)
  mov    $0x0,%eax
L33:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int FindHeader(char *token, char **headerNames, int nHeaders, int *index) {
  int i, match = 0, nMatches;
  *index = -1;
  nMatches = 0;
  for (i = 0; i < nHeaders; i++) {
    if (!strcmp(token, headerNames[i])) {
      nMatches++;
      match = i;
    }
  }
  if (nMatches != 1)
    return (1);
  *index = match;
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FindHeader>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0xffffffff,(%rcx)
  mov    %rcx,0x8(%rsp)
  test   %edx,%edx
  jle    L8
  mov    %rdi,%r12
  mov    %rsi,%r15
  movslq %edx,%rbp
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%r15,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L34
  add    $0x1,%r13d
  mov    %ebx,%r14d
L34:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L18
  mov    $0x1,%eax
  cmp    $0x1,%r13d
  jne    L33
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  xor    %eax,%eax
L33:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int FindHeader(char *token, char **headerNames, int nHeaders, int *index) {
  int i, match = 0, nMatches;
  *index = -1;
  nMatches = 0;
  for (i = 0; i < nHeaders; i++) {
    if (!strcmp(token, headerNames[i])) {
      nMatches++;
      match = i;
    }
  }
  if (nMatches != 1)
    return (1);
  *index = match;
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FindHeader>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0xffffffff,(%rcx)
  mov    %rcx,0x8(%rsp)
  test   %edx,%edx
  jle    L20
  mov    %rdi,%r12
  mov    %rsi,%r15
  movslq %edx,%rbp
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L28:
  mov    (%r15,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L18
  add    $0x1,%r13d
  mov    %ebx,%r14d
L18:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L28
  mov    $0x1,%eax
  cmp    $0x1,%r13d
  jne    L1
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  xor    %eax,%eax
L1:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L20:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int FindHeader(char *token, char **headerNames, int nHeaders, int *index) {
  int i, match = 0, nMatches;
  *index = -1;
  nMatches = 0;
  for (i = 0; i < nHeaders; i++) {
    if (!strcmp(token, headerNames[i])) {
      nMatches++;
      match = i;
    }
  }
  if (nMatches != 1)
    return (1);
  *index = match;
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x4,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0xb,-0x20(%rbp)
  movl   $0x11,-0x1c(%rbp)
  movl   $0x5a,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <binarySearch@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <binarySearch@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D15
type_infered: string

tool: D0: The index of 5 is %d.


tool: D15: The index of 4 is %d.


assistant: ```c
int main() {
  int a[] = {0, 1, 4, 9, 11, 17, 90};
  printf("The index of 5 is %d.\n", binarySearch(a, 7, 5));
  printf("The index of 4 is %d.\n", binarySearch(a, 7, 4));
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0xb,0x10(%rsp)
  movl   $0x11,0x14(%rsp)
  movl   $0x5a,0x18(%rsp)
  mov    %rsp,%rbx
  mov    $0x5,%edx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <binarySearch@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%edx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <binarySearch@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string

tool: D5: The index of 5 is %d.


tool: D19: The index of 4 is %d.


assistant: ```c
int main() {
  int a[] = {0, 1, 4, 9, 11, 17, 90};
  printf("The index of 5 is %d.\n", binarySearch(a, 7, 5));
  printf("The index of 4 is %d.\n", binarySearch(a, 7, 4));
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x5,%edx
  mov    $0x7,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x100000000,%rax
  mov    %rsp,%rbp
  movl   $0x5a,0x18(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x900000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x110000000b,%rax
  mov    %rax,0x10(%rsp)
  call   <binarySearch@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x4,%edx
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <binarySearch@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string

tool: D14: The index of 5 is %d.


tool: D5: The index of 4 is %d.


assistant: ```c
int main() {
  int a[] = {0, 1, 4, 9, 11, 17, 90};
  printf("The index of 5 is %d.\n", binarySearch(a, 7, 5));
  printf("The index of 4 is %d.\n", binarySearch(a, 7, 4));
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x5,%edx
  mov    $0x7,%esi
  sub    $0x30,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D0(%rip),%rax
  movl   $0x5a,0x18(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <binarySearch@plt>
  lea    D30(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x4,%edx
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <binarySearch@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: byte[16]
name: unpack_data
arguments: tag: D0
type_guessed: byte[8]
name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string

tool: {"D8": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D0": [0x0b,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

tool: D30: The index of 5 is %d.


tool: D13: The index of 4 is %d.


assistant: ```c
int main() {
  int a[] = {0, 1, 4, 9, 11, 17, 90};
  printf("The index of 5 is %d.\n", binarySearch(a, 7, 5));
  printf("The index of 4 is %d.\n", binarySearch(a, 7, 4));
  getchar();
}
```