ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<hc_vec_rms>:
  endbr64
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%rax,8),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L37:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L37
L30:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm2
  ja     L14
  sqrtsd %xmm0,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
L4:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  jmp    L30
L14:
  push   %rax
  call   <sqrt@plt>
  pop    %rdx
  cvtsd2ss %xmm0,%xmm0
  ret
```

assistant: ```c
float hc_vec_rms(a, n)
double *a;
int n;
{
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += a[i] * a[i];
  }
  return sqrt(sum / n);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hc_vec_rms>:
  endbr64
  test   %esi,%esi
  jle    L48
  cmp    $0x1,%esi
  je     L40
  mov    %esi,%edx
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  shr    %edx
  movapd %xmm3,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L3:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L3
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%sil
  je     L61
L68:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L61:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm3
  ja     L5
  sqrtsd %xmm0,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  jmp    L61
L40:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L68
L5:
  push   %rax
  call   <sqrt@plt>
  pop    %rdx
  cvtsd2ss %xmm0,%xmm0
  ret
```

assistant: ```c
float hc_vec_rms(a, n)
double *a;
int n;
{
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += a[i] * a[i];
  }
  return sqrt(sum / n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cst_errmsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1f3f,%edi
  call   <HRError@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int cst_errmsg(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  HRError(7999, fmt, args);
  va_end(args);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cst_errmsg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x1f3f,%edi
  call   <HRError@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cst_errmsg(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  HRError(7999, fmt, args);
  va_end(args);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cst_errmsg>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1f3f,%edi
  call   <HRError@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cst_errmsg(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  HRError(7999, fmt, args);
  va_end(args);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cst_errmsg>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1f3f,%edi
  call   <HRError@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cst_errmsg(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  HRError(7999, fmt, args);
  va_end(args);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mg_is_big_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: 

assistant: ```c
int mg_is_big_endian(void) {
  static const int n = 1;
  return ((char *)&n)[0] == 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mg_is_big_endian>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int mg_is_big_endian(void) {
  static const int n = 1;
  return ((char *)&n)[0] == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mg_is_big_endian>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int mg_is_big_endian(void) {
  static const int n = 1;
  return ((char *)&n)[0] == 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mg_is_big_endian>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int mg_is_big_endian(void) {
  static const int n = 1;
  return ((char *)&n)[0] == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D1
type: string

tool: D5: I'm matching


tool: D1: All the expect blocks


assistant: ```c
int main(int argc, char *argv[]) {
  printf("I'm matching\n");
  printf("All the expect blocks\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string
name: read_data
arguments: data_label: D12
datatype: string

tool: D9: I'm matching


tool: D12: All the expect blocks


assistant: ```c
int main(int argc, char *argv[]) {
  printf("I'm matching\n");
  printf("All the expect blocks\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D0: I'm matching


tool: D2: All the expect blocks


assistant: ```c
int main(int argc, char *argv[]) {
  printf("I'm matching\n");
  printf("All the expect blocks\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D5
type: string

tool: D11: I'm matching


tool: D5: All the expect blocks


assistant: ```c
int main(int argc, char *argv[]) {
  printf("I'm matching\n");
  printf("All the expect blocks\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<iswild>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L3
L15:
  cmpb   $0x2a,-0x1(%rbp)
  je     L34
  cmpb   $0x3f,-0x1(%rbp)
  jne    L3
L34:
  mov    $0x1,%eax
  jmp    L14
L3:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L15
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
iswild(str) char *str;
{
  char c;
  while ((c = *str++) != '\0')
    if (c == '*' || c == '?')
      return (1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<iswild>:
  endbr64
L17:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L21
  cmp    $0x2a,%al
  je     L10
  cmp    $0x3f,%al
  jne    L17
L10:
  mov    $0x1,%eax
  ret
L21:
  mov    $0x0,%eax
  ret
```

assistant: ```c
iswild(str) char *str;
{
  char c;
  while ((c = *str++) != '\0')
    if (c == '*' || c == '?')
      return (1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<iswild>:
  endbr64
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L29:
  cmp    $0x2a,%al
  je     L10
  cmp    $0x3f,%al
  je     L10
L2:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L29
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
iswild(str) char *str;
{
  char c;
  while ((c = *str++) != '\0')
    if (c == '*' || c == '?')
      return (1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<iswild>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L38:
  cmp    $0x2a,%al
  je     L11
  cmp    $0x3f,%al
  je     L11
L0:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L38
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
iswild(str) char *str;
{
  char c;
  while ((c = *str++) != '\0')
    if (c == '*' || c == '?')
      return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rcx
  mov    %rsi,%rax
  mov    %edx,-0x14(%rbp)
  cmp    %rcx,%rax
  jae    L2
  jmp    L15
L51:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
L15:
  mov    -0x14(%rbp),%edx
  lea    -0x1(%rdx),%esi
  mov    %esi,-0x14(%rbp)
  test   %edx,%edx
  jne    L51
  jmp    L21
L2:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  sub    $0x1,%rdx
  add    %rcx,%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L57
L17:
  mov    -0x10(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L57:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L17
L21:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bcopy(register char *src, register char *dest, int len) {
  if (dest < src)
    while (len--)
      *dest++ = *src++;
  else {
    char *lasts = src + (len - 1);
    char *lastd = dest + (len - 1);
    while (len--)
      *(char *)lastd-- = *(char *)lasts--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bcopy>:
  endbr64
  cmp    %rdi,%rsi
  jae    L8
  test   %edx,%edx
  je     L26
  mov    %edx,%edx
  mov    $0x0,%eax
L38:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L38
  ret
L8:
  movslq %edx,%rax
  sub    $0x1,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  test   %edx,%edx
  je     L26
  lea    -0x1(%rdx),%ecx
  not    %rcx
  mov    $0x0,%eax
L35:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rcx
  jne    L35
L26:
  ret
```

assistant: ```c
void bcopy(register char *src, register char *dest, int len) {
  if (dest < src)
    while (len--)
      *dest++ = *src++;
  else {
    char *lasts = src + (len - 1);
    char *lastd = dest + (len - 1);
    while (len--)
      *(char *)lastd-- = *(char *)lasts--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bcopy>:
  endbr64
  cmp    %rdi,%rsi
  jae    L28
  mov    %edx,%ecx
  xor    %eax,%eax
  test   %edx,%edx
  je     L1
  nopl   0x0(%rax)
L32:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L32
  ret
  nopl   0x0(%rax)
L28:
  movslq %edx,%rax
  sub    $0x1,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  test   %edx,%edx
  je     L1
  lea    -0x1(%rdx),%ecx
  xor    %eax,%eax
  not    %rcx
  nopl   0x0(%rax)
L16:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rcx
  jne    L16
L1:
  ret
```

assistant: ```c
void bcopy(register char *src, register char *dest, int len) {
  if (dest < src)
    while (len--)
      *dest++ = *src++;
  else {
    char *lasts = src + (len - 1);
    char *lastd = dest + (len - 1);
    while (len--)
      *(char *)lastd-- = *(char *)lasts--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bcopy>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %edx,%edi
  lea    -0x1(%rdx),%edx
  cmp    %rax,%rsi
  jae    L151
  test   %edi,%edi
  je     L91
  lea    0x1(%rax),%r8
  sub    %r8,%rsi
  cmp    $0xe,%rsi
  jbe    L23
  cmp    $0x6,%edx
  jbe    L23
  cmp    $0xe,%edx
  jbe    L103
  mov    %edi,%r8d
  xor    %esi,%esi
  shr    $0x4,%r8d
  shl    $0x4,%r8
L177:
  movdqu (%rax,%rsi,1),%xmm0
  movups %xmm0,(%rcx,%rsi,1)
  add    $0x10,%rsi
  cmp    %rsi,%r8
  jne    L177
  mov    %edi,%esi
  and    $0xfffffff0,%esi
  mov    %esi,%r8d
  sub    %esi,%edx
  lea    (%rax,%r8,1),%r9
  add    %rcx,%r8
  cmp    %esi,%edi
  je     L168
L145:
  sub    %esi,%edi
  lea    -0x1(%rdi),%r10d
  cmp    $0x6,%r10d
  jbe    L154
  mov    (%rax,%rsi,1),%rax
  mov    %rax,(%rcx,%rsi,1)
  mov    %edi,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%ecx
  sub    %eax,%edx
  add    %rcx,%r9
  add    %rcx,%r8
  cmp    %eax,%edi
  je     L91
L154:
  movzbl (%r9),%eax
  mov    %al,(%r8)
  test   %edx,%edx
  je     L91
  movzbl 0x1(%r9),%eax
  mov    %al,0x1(%r8)
  cmp    $0x1,%edx
  je     L91
  movzbl 0x2(%r9),%eax
  mov    %al,0x2(%r8)
  cmp    $0x2,%edx
  je     L91
  movzbl 0x3(%r9),%eax
  mov    %al,0x3(%r8)
  cmp    $0x3,%edx
  je     L91
  movzbl 0x4(%r9),%eax
  mov    %al,0x4(%r8)
  cmp    $0x4,%edx
  je     L91
  movzbl 0x5(%r9),%eax
  mov    %al,0x5(%r8)
  cmp    $0x5,%edx
  je     L91
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%r8)
  ret
  nopl   (%rax)
L151:
  movslq %edi,%r8
  sub    $0x1,%r8
  lea    (%rax,%r8,1),%rsi
  add    %r8,%rcx
  test   %edi,%edi
  je     L91
  not    %rdx
  xor    %eax,%eax
  nop
L36:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L36
L91:
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L179:
  movzbl (%rax,%rsi,1),%edi
  mov    %dil,(%rcx,%rsi,1)
  mov    %rsi,%rdi
  add    $0x1,%rsi
  cmp    %rdx,%rdi
  jne    L179
  ret
L103:
  mov    %rcx,%r8
  mov    %rax,%r9
  xor    %esi,%esi
  jmp    L145
L168:
  ret
```

assistant: ```c
void bcopy(register char *src, register char *dest, int len) {
  if (dest < src)
    while (len--)
      *dest++ = *src++;
  else {
    char *lasts = src + (len - 1);
    char *lastd = dest + (len - 1);
    while (len--)
      *(char *)lastd-- = *(char *)lasts--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_boolean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  movl   $0xc2b73583,-0x18(%rbp)
  movl   $0xe90f1258,-0x14(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L19
  mov    -0x18(%rbp),%ebx
  jmp    L13
L19:
  mov    -0x14(%rbp),%ebx
L13:
  mov    -0x28(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <hash_rot@plt>
  xor    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint32_t hash_boolean(bool x, uint32_t basis) {
  const uint32_t P0 = 0xc2b73583;
  const uint32_t P1 = 0xe90f1258;
  return (x ? P0 : P1) ^ hash_rot(basis, 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_boolean>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  mov    %esi,%edi
  cmp    $0x1,%eax
  sbb    %ebx,%ebx
  and    $0x2657dcd5,%ebx
  sub    $0x3d48ca7d,%ebx
  mov    $0x1,%esi
  call   <hash_rot@plt>
  xor    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t hash_boolean(bool x, uint32_t basis) {
  const uint32_t P0 = 0xc2b73583;
  const uint32_t P1 = 0xe90f1258;
  return (x ? P0 : P1) ^ hash_rot(basis, 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_boolean>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %esi,%edi
  mov    $0x1,%esi
  cmp    $0x1,%eax
  sbb    %ebx,%ebx
  call   <hash_rot@plt>
  and    $0x2657dcd5,%ebx
  sub    $0x3d48ca7d,%ebx
  xor    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t hash_boolean(bool x, uint32_t basis) {
  const uint32_t P0 = 0xc2b73583;
  const uint32_t P1 = 0xe90f1258;
  return (x ? P0 : P1) ^ hash_rot(basis, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash_boolean>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %esi,%edi
  mov    $0x1,%esi
  cmp    $0x1,%eax
  sbb    %ebx,%ebx
  call   <hash_rot@plt>
  and    $0x2657dcd5,%ebx
  sub    $0x3d48ca7d,%ebx
  xor    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t hash_boolean(bool x, uint32_t basis) {
  const uint32_t P0 = 0xc2b73583;
  const uint32_t P1 = 0xe90f1258;
  return (x ? P0 : P1) ^ hash_rot(basis, 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<buildHeap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sizeDynArr@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L12:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <_adjustHeap@plt>
  subl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x0,-0x8(%rbp)
  jns    L12
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: +++++++++ Building Heap +++++++++


assistant: ```c
void buildHeap(struct DynArr *heap) {
  if (1)
    printf("+++++++++ Building Heap +++++++++\n");
  int max = sizeDynArr(heap);
  int i;
  for (i = max / 2 - 1; i >= 0; i--)
    _adjustHeap(heap, max, i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<buildHeap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <sizeDynArr@plt>
  mov    %eax,%ebp
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  sub    $0x1,%ebx
  js     L12
L16:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_adjustHeap@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L16
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: +++++++++ Building Heap +++++++++


assistant: ```c
void buildHeap(struct DynArr *heap) {
  if (1)
    printf("+++++++++ Building Heap +++++++++\n");
  int max = sizeDynArr(heap);
  int i;
  for (i = max / 2 - 1; i >= 0; i--)
    _adjustHeap(heap, max, i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<buildHeap>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  call   <printf@plt>
  mov    %r12,%rdi
  call   <sizeDynArr@plt>
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  sub    $0x1,%ebx
  js     L9
  mov    %eax,%ebp
  nop
L7:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_adjustHeap@plt>
  sub    $0x1,%ebx
  jae    L7
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string

tool: D7: +++++++++ Building Heap +++++++++


assistant: ```c
void buildHeap(struct DynArr *heap) {
  if (1)
    printf("+++++++++ Building Heap +++++++++\n");
  int max = sizeDynArr(heap);
  int i;
  for (i = max / 2 - 1; i >= 0; i--)
    _adjustHeap(heap, max, i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<buildHeap>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  call   <printf@plt>
  mov    %r12,%rdi
  call   <sizeDynArr@plt>
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  sub    $0x1,%ebx
  js     L0
  mov    %eax,%ebp
  nop
L18:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_adjustHeap@plt>
  sub    $0x1,%ebx
  jae    L18
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string

tool: D7: +++++++++ Building Heap +++++++++


assistant: ```c
void buildHeap(struct DynArr *heap) {
  if (1)
    printf("+++++++++ Building Heap +++++++++\n");
  int max = sizeDynArr(heap);
  int i;
  for (i = max / 2 - 1; i >= 0; i--)
    _adjustHeap(heap, max, i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_hosts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L14:
  addl   $0x1,-0x4(%rbp)
  jmp    L54
L8:
  addl   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L57
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  jne    L8
L57:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  jne    L26
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_hosts(char *req) {
  int i = 0, host_c = 0;
  while (req[i] != ' ') {
    host_c++;
    while (req[i] != ' ' && req[i] != '&')
      i++;
    if (req[i] == '&')
      i++;
  }
  return host_c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<count_hosts>:
  endbr64
  cmpb   $0x20,(%rdi)
  je     L43
  mov    $0x0,%esi
  mov    $0x0,%ecx
  jmp    L69
L66:
  cmp    $0x26,%dl
  sete   %al
  movzbl %al,%eax
  add    %eax,%ecx
  movslq %ecx,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  je     L63
L69:
  add    $0x1,%esi
  movslq %ecx,%rax
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  je     L66
  cmp    $0x26,%dl
  je     L66
  add    $0x1,%ecx
  movslq %ecx,%rax
L75:
  mov    %eax,%ecx
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L66
  cmp    $0x26,%dl
  jne    L75
  jmp    L66
L43:
  mov    $0x0,%esi
L63:
  mov    %esi,%eax
  ret
```

assistant: ```c
int count_hosts(char *req) {
  int i = 0, host_c = 0;
  while (req[i] != ' ') {
    host_c++;
    while (req[i] != ' ' && req[i] != '&')
      i++;
    if (req[i] == '&')
      i++;
  }
  return host_c;
}
```