ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<sys$deq>:
  endbr64
  mov    %ecx,%r10d
  mov    %edx,%edx
  mov    %edi,%edi
  mov    $0x1d,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$deq(unsigned int lkid, void *valblk, unsigned int acmode, unsigned int flags) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)(flags);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(valblk);
    register long int _a1 asm("rdi") = (long)(lkid);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(29), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: What is the c source code of the assembly code below?

```asm
<sys$deq>:
  endbr64
  mov    %ecx,%r10d
  mov    %edx,%edx
  mov    %edi,%edi
  mov    $0x1d,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$deq(unsigned int lkid, void *valblk, unsigned int acmode, unsigned int flags) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)(flags);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(valblk);
    register long int _a1 asm("rdi") = (long)(lkid);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(29), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HashTable_removeFiles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc30,%rsp
  mov    %rdi,-0xc28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc14(%rbp)
  mov    -0xc28(%rbp),%rdx
  lea    -0xc10(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0xc10(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    %eax,%edx
  mov    -0xc14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc14(%rbp)
  mov    -0xc28(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  lea    D20(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    %eax,%edx
  mov    -0xc14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc14(%rbp)
  mov    -0xc28(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    %eax,%edx
  mov    -0xc14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc14(%rbp)
  mov    -0xc14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string

tool: D15: %s_meta

tool: D20: %s_state

tool: D9: %s_array

assistant: ```c
int HashTable_removeFiles(char *filename) {
  int success = 0;
  char meta_fn[1024];
  sprintf(meta_fn, "%s_meta", filename);
  success += unlink(meta_fn);
  char state_fn[1024];
  sprintf(state_fn, "%s_state", filename);
  success += unlink(state_fn);
  char array_fn[1024];
  sprintf(array_fn, "%s_array", filename);
  success += unlink(array_fn);
  return success;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HashTable_removeFiles>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rdx
  lea    D29(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <unlink@plt>
  mov    %rax,%rbx
  lea    0x400(%rsp),%r12
  mov    %rbp,%rdx
  lea    D10(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <unlink@plt>
  add    %eax,%ebx
  lea    0x800(%rsp),%r12
  mov    %rbp,%rdx
  lea    D7(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <unlink@plt>
  add    %ebx,%eax
  mov    0xc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0xc10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D29
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D29: %s_meta

tool: D10: %s_state

tool: D7: %s_array

assistant: ```c
int HashTable_removeFiles(char *filename) {
  int success = 0;
  char meta_fn[1024];
  sprintf(meta_fn, "%s_meta", filename);
  success += unlink(meta_fn);
  char state_fn[1024];
  sprintf(state_fn, "%s_state", filename);
  success += unlink(state_fn);
  char array_fn[1024];
  sprintf(array_fn, "%s_array", filename);
  success += unlink(array_fn);
  return success;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HashTable_removeFiles>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    %rdi,%r12
  lea    D7(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    0x400(%rsp),%rbp
  call   <unlink@plt>
  mov    %r12,%rdx
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    0x800(%rsp),%rbp
  call   <unlink@plt>
  mov    %r12,%rdx
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  add    %eax,%ebx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  add    %ebx,%eax
  mov    0xc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0xc10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
data_type: string
name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D14
data_type: string

tool: D7: %s_meta

tool: D10: %s_state

tool: D14: %s_array

assistant: ```c
int HashTable_removeFiles(char *filename) {
  int success = 0;
  char meta_fn[1024];
  sprintf(meta_fn, "%s_meta", filename);
  success += unlink(meta_fn);
  char state_fn[1024];
  sprintf(state_fn, "%s_state", filename);
  success += unlink(state_fn);
  char array_fn[1024];
  sprintf(array_fn, "%s_array", filename);
  success += unlink(array_fn);
  return success;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HashTable_removeFiles>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    %rdi,%r12
  lea    D12(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    0x400(%rsp),%rbp
  call   <unlink@plt>
  mov    %r12,%rdx
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    0x800(%rsp),%rbp
  call   <unlink@plt>
  mov    %r12,%rdx
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  add    %eax,%ebx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  add    %ebx,%eax
  mov    0xc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0xc10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D25
data_type: string

tool: D12: %s_meta

tool: D17: %s_state

tool: D25: %s_array

assistant: ```c
int HashTable_removeFiles(char *filename) {
  int success = 0;
  char meta_fn[1024];
  sprintf(meta_fn, "%s_meta", filename);
  success += unlink(meta_fn);
  char state_fn[1024];
  sprintf(state_fn, "%s_state", filename);
  success += unlink(state_fn);
  char array_fn[1024];
  sprintf(array_fn, "%s_array", filename);
  success += unlink(array_fn);
  return success;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stmt_for>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <stmt_expression@plt>
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <list_new@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <stmt_compound@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <to_boolean@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <stmt_while@plt>
  mov    %rax,%rbx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <stmt_expression@plt>
  mov    $0x0,%ecx
  mov    %rbx,%rdx
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <list_new@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <stmt_compound@plt>
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
struct statement *stmt_for(const struct expression *init, const struct expression *cond, const struct expression *next, const struct statement *body) {
  struct list *body_stmts = list_new((1 << 1), body, stmt_expression(next), NULL);
  struct statement *body_compound = stmt_compound(body_stmts);
  struct list *li = list_new((1 << 1), stmt_expression(init), stmt_while(to_boolean(cond), body_compound), NULL);
  return stmt_compound(li);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stmt_for>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rdi
  mov    %rcx,%rbx
  call   <stmt_expression@plt>
  mov    %rax,%rdx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    $0x2,%edi
  call   <list_new@plt>
  mov    %rax,%rdi
  call   <stmt_compound@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <to_boolean@plt>
  mov    %eax,%edi
  mov    %rbx,%rsi
  call   <stmt_while@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <stmt_expression@plt>
  mov    %rax,%rsi
  mov    $0x0,%ecx
  mov    %rbx,%rdx
  mov    $0x2,%edi
  call   <list_new@plt>
  mov    %rax,%rdi
  call   <stmt_compound@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct statement *stmt_for(const struct expression *init, const struct expression *cond, const struct expression *next, const struct statement *body) {
  struct list *body_stmts = list_new((1 << 1), body, stmt_expression(next), NULL);
  struct statement *body_compound = stmt_compound(body_stmts);
  struct list *li = list_new((1 << 1), stmt_expression(init), stmt_while(to_boolean(cond), body_compound), NULL);
  return stmt_compound(li);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stmt_for>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  call   <stmt_expression@plt>
  xor    %ecx,%ecx
  mov    %r12,%rsi
  mov    $0x2,%edi
  mov    %rax,%rdx
  call   <list_new@plt>
  mov    %rax,%rdi
  call   <stmt_compound@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <to_boolean@plt>
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <stmt_while@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <stmt_expression@plt>
  mov    %r12,%rdx
  mov    $0x2,%edi
  xor    %ecx,%ecx
  mov    %rax,%rsi
  call   <list_new@plt>
  pop    %rbp
  pop    %r12
  mov    %rax,%rdi
  pop    %r13
  jmp    10b0 <stmt_compound@plt>
```

assistant: ```c
struct statement *stmt_for(const struct expression *init, const struct expression *cond, const struct expression *next, const struct statement *body) {
  struct list *body_stmts = list_new((1 << 1), body, stmt_expression(next), NULL);
  struct statement *body_compound = stmt_compound(body_stmts);
  struct list *li = list_new((1 << 1), stmt_expression(init), stmt_while(to_boolean(cond), body_compound), NULL);
  return stmt_compound(li);
}
```
user: Translate the below assembly code into C programming language:

```asm
<stmt_for>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  call   <stmt_expression@plt>
  xor    %ecx,%ecx
  mov    %r12,%rsi
  mov    $0x2,%edi
  mov    %rax,%rdx
  call   <list_new@plt>
  mov    %rax,%rdi
  call   <stmt_compound@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <to_boolean@plt>
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <stmt_while@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <stmt_expression@plt>
  mov    %r12,%rdx
  mov    $0x2,%edi
  xor    %ecx,%ecx
  mov    %rax,%rsi
  call   <list_new@plt>
  pop    %rbp
  pop    %r12
  mov    %rax,%rdi
  pop    %r13
  jmp    10b0 <stmt_compound@plt>
```

assistant: ```c
struct statement *stmt_for(const struct expression *init, const struct expression *cond, const struct expression *next, const struct statement *body) {
  struct list *body_stmts = list_new((1 << 1), body, stmt_expression(next), NULL);
  struct statement *body_compound = stmt_compound(body_stmts);
  struct list *li = list_new((1 << 1), stmt_expression(init), stmt_while(to_boolean(cond), body_compound), NULL);
  return stmt_compound(li);
}
```
user: What is the c source code of the assembly code below?

```asm
<expect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <assembler_err@plt>
  mov    $0xffffffff,%eax
  jmp    L6
L7:
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: expected operand

assistant: ```c
int expect(struct instr *instr, struct value_nd *nd) {
  if (!nd) {
    assembler_err(instr, "expected operand");
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<expect>:
  endbr64
  test   %rsi,%rsi
  je     L0
  mov    $0x0,%eax
  ret
L0:
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  call   <assembler_err@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: expected operand

assistant: ```c
int expect(struct instr *instr, struct value_nd *nd) {
  if (!nd) {
    assembler_err(instr, "expected operand");
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<expect>:
  endbr64
  test   %rsi,%rsi
  je     L0
  xor    %eax,%eax
  ret
L0:
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  call   <assembler_err@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: expected operand

assistant: ```c
int expect(struct instr *instr, struct value_nd *nd) {
  if (!nd) {
    assembler_err(instr, "expected operand");
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<expect>:
  endbr64
  test   %rsi,%rsi
  je     L5
  xor    %eax,%eax
  ret
L5:
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  call   <assembler_err@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: expected operand

assistant: ```c
int expect(struct instr *instr, struct value_nd *nd) {
  if (!nd) {
    assembler_err(instr, "expected operand");
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_noswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L9
L17:
  mov    -0x8(%rbp),%rax
L9:
  leave
  ret
```

assistant: ```c
void *alloc_noswap(int size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr == NULL)
    return NULL;
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc_noswap>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *alloc_noswap(int size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr == NULL)
    return NULL;
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<alloc_noswap>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *alloc_noswap(int size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr == NULL)
    return NULL;
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<alloc_noswap>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *alloc_noswap(int size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr == NULL)
    return NULL;
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(char *a, char *b) {
  char t;
  t = *a;
  *a = *b;
  *b = t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swap(char *a, char *b) {
  char t;
  t = *a;
  *a = *b;
  *b = t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swap(char *a, char *b) {
  char t;
  t = *a;
  *a = *b;
  *b = t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cttestexit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cttestexit() {
  return;
  exit(2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cttestexit>:
  endbr64
  ret
```

assistant: ```c
void cttestexit() {
  return;
  exit(2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cttestexit>:
  endbr64
  ret
```

assistant: ```c
void cttestexit() {
  return;
  exit(2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  movl   $0x0,-0xc(%rbp)
  jmp    L33
L21:
  mov    -0x18(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L4:
  addl   $0x1,-0xc(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L21
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D31
type_infered: string
name: read_data
arguments: data_label: D39
type_infered: string

tool: D21: 
No enough memory to store a matrix with

tool: D31:  
row = %d  col = %d num_bytes = %d


tool: D39:  
col = %d


assistant: ```c
void **matrix(int row, int col, int num_bytes) {
  int loop;
  void **pointer;
  pointer = (void **)malloc((unsigned long)(row * sizeof(void *)));
  if (!pointer) {
    printf("\nNo enough memory to store a matrix with");
    printf(" \nrow = %d  col = %d num_bytes = %d\n", row, col, num_bytes);
    exit(1);
  }
  for (loop = 0; loop < row; loop++) {
    pointer[loop] = (void *)malloc((unsigned long)(col * num_bytes));
    if (!pointer[loop]) {
      printf("\nNo enough memory to store a matrix with");
      printf(" \ncol = %d\n", col);
      exit(1);
    }
  }
  return pointer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r14d
  mov    %edx,%ebp
  movslq %edi,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L24
L62:
  test   %r12d,%r12d
  jle    L39
  imul   %r14d,%ebp
  movslq %ebp,%rbp
  mov    %r13,%rbx
  mov    %r12d,%r12d
  lea    0x0(%r13,%r12,8),%r12
  lea    D4(%rip),%r15
  jmp    L55
L24:
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r12d,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L62
L65:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L39
L55:
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L65
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14d,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L65
L39:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D4: 
No enough memory to store a matrix with

tool: D16:  
row = %d  col = %d num_bytes = %d


tool: D5:  
col = %d


assistant: ```c
void **matrix(int row, int col, int num_bytes) {
  int loop;
  void **pointer;
  pointer = (void **)malloc((unsigned long)(row * sizeof(void *)));
  if (!pointer) {
    printf("\nNo enough memory to store a matrix with");
    printf(" \nrow = %d  col = %d num_bytes = %d\n", row, col, num_bytes);
    exit(1);
  }
  for (loop = 0; loop < row; loop++) {
    pointer[loop] = (void *)malloc((unsigned long)(col * num_bytes));
    if (!pointer[loop]) {
      printf("\nNo enough memory to store a matrix with");
      printf(" \ncol = %d\n", col);
      exit(1);
    }
  }
  return pointer;
}
```