user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ispandigital>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    $0x28,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L60
L209:
  mov    -0x44(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x34(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x44(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jle    L60
  mov    $0x0,%eax
  jmp    L89
L60:
  cmpl   $0x0,-0x44(%rbp)
  jne    L209
  mov    -0x30(%rbp),%eax
  test   %eax,%eax
  je     L201
  mov    $0x0,%eax
  jmp    L89
L46:
  mov    -0x48(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x38(%rbp)
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x48(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jle    L201
  mov    $0x0,%eax
  jmp    L89
L201:
  cmpl   $0x0,-0x48(%rbp)
  jne    L46
  mov    -0x30(%rbp),%eax
  test   %eax,%eax
  je     L9
  mov    $0x0,%eax
  jmp    L89
L109:
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x3c(%rbp)
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jle    L9
  mov    $0x0,%eax
  jmp    L89
L9:
  cmpl   $0x0,-0x4c(%rbp)
  jne    L109
  mov    -0x30(%rbp),%eax
  test   %eax,%eax
  je     L75
  mov    $0x0,%eax
  jmp    L89
L75:
  movl   $0x1,-0x40(%rbp)
  jmp    L44
L68:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  je     L69
  mov    $0x0,%eax
  jmp    L89
L69:
  addl   $0x1,-0x40(%rbp)
L44:
  cmpl   $0x9,-0x40(%rbp)
  jle    L68
  mov    $0x1,%eax
L89:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
int ispandigital(int a, int b, int c) {
  int counts[10];
  int i;
  memset(counts, 0, sizeof(counts));
  while (a) {
    int digit = a % 10;
    a /= 10;
    counts[digit]++;
    if (counts[digit] > 1)
      return 0;
  }
  if (counts[0])
    return 0;
  while (b) {
    int digit = b % 10;
    b /= 10;
    counts[digit]++;
    if (counts[digit] > 1)
      return 0;
  }
  if (counts[0])
    return 0;
  while (c) {
    int digit = c % 10;
    c /= 10;
    counts[digit]++;
    if (counts[digit] > 1)
      return 0;
  }
  if (counts[0])
    return 0;
  for (i = 1; i < 10; ++i) {
    if (counts[i] != 1)
      return 0;
  }
  return 1;
}
```