ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<RjNA40562122444414_br_find_libexec_dir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <RjNA40562122444414_br_find_prefix@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <RjNA40562122444414_br_build_path@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <free@plt>
L17:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %rbp,%r12
  test   %rbp,%rbp
  je     L17
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: libexec

assistant: ```c
char *RjNA40562122444414_br_find_libexec_dir(const char *default_libexec_dir) {
  char *prefix, *dir;
  prefix = RjNA40562122444414_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_libexec_dir != (const char *)((char *)0))
      return strdup(default_libexec_dir);
    else
      return (char *)((char *)0);
  }
  dir = RjNA40562122444414_br_build_path(prefix, "libexec");
  free(prefix);
  return dir;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RjNA40562122444414_br_find_libexec_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <RjNA40562122444414_br_find_prefix@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rbp
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <RjNA40562122444414_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  test   %r12,%r12
  je     L18
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L18:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: libexec

assistant: ```c
char *RjNA40562122444414_br_find_libexec_dir(const char *default_libexec_dir) {
  char *prefix, *dir;
  prefix = RjNA40562122444414_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_libexec_dir != (const char *)((char *)0))
      return strdup(default_libexec_dir);
    else
      return (char *)((char *)0);
  }
  dir = RjNA40562122444414_br_build_path(prefix, "libexec");
  free(prefix);
  return dir;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RjNA40562122444414_br_find_libexec_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <RjNA40562122444414_br_find_prefix@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rbp
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <RjNA40562122444414_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  test   %r12,%r12
  je     L10
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L10:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: libexec

assistant: ```c
char *RjNA40562122444414_br_find_libexec_dir(const char *default_libexec_dir) {
  char *prefix, *dir;
  prefix = RjNA40562122444414_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_libexec_dir != (const char *)((char *)0))
      return strdup(default_libexec_dir);
    else
      return (char *)((char *)0);
  }
  dir = RjNA40562122444414_br_build_path(prefix, "libexec");
  free(prefix);
  return dir;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Kit_TruthCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void Kit_TruthCopy(unsigned *pOut, unsigned *pIn, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    pOut[w] = pIn[w];
}
```
user: What is the c source code of the assembly code below?

```asm
<Kit_TruthCopy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%edi
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  js     L7
  cltq
L0:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L0
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Kit_TruthCopy(unsigned *pOut, unsigned *pIn, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    pOut[w] = pIn[w];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Kit_TruthCopy>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x8,%rsp
  call   <Kit_TruthWordNum@plt>
  sub    $0x1,%eax
  js     L7
  cltq
  xchg   %ax,%ax
L4:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L4
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Kit_TruthCopy(unsigned *pOut, unsigned *pIn, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    pOut[w] = pIn[w];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Kit_TruthCopy>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x8,%rsp
  call   <Kit_TruthWordNum@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L22
  movslq %eax,%rcx
  mov    %eax,%edi
  mov    %rbx,%rax
  sub    %rbp,%rax
  shl    $0x2,%rcx
  add    $0xc,%rax
  cmp    $0x8,%rax
  jbe    L66
  cmp    $0x2,%edx
  jbe    L66
  mov    %edi,%esi
  sub    $0x10,%rcx
  xor    %eax,%eax
  shr    $0x2,%esi
  lea    0x0(%rbp,%rcx,1),%r8
  add    %rbx,%rcx
  neg    %rsi
  shl    $0x4,%rsi
  xchg   %ax,%ax
L32:
  movdqu (%r8,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  sub    $0x10,%rax
  cmp    %rax,%rsi
  jne    L32
  mov    %edi,%ecx
  mov    %edx,%eax
  and    $0xfffffffc,%ecx
  sub    %ecx,%eax
  cmp    %ecx,%edi
  je     L22
  movslq %eax,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
  mov    %ecx,(%rbx,%rdx,4)
  lea    -0x1(%rax),%ecx
  test   %eax,%eax
  je     L22
  movslq %ecx,%rcx
  mov    0x0(%rbp,%rcx,4),%esi
  lea    0x0(,%rcx,4),%rdx
  mov    %esi,(%rbx,%rcx,4)
  cmp    $0x1,%eax
  je     L22
  mov    -0x4(%rbp,%rdx,1),%eax
  mov    %eax,-0x4(%rbx,%rdx,1)
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  movslq %edx,%rax
  nopl   0x0(%rax,%rax,1)
L44:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L44
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Kit_TruthCopy(unsigned *pOut, unsigned *pIn, int nVars) {
  int w;
  for (w = Kit_TruthWordNum(nVars) - 1; w >= 0; w--)
    pOut[w] = pIn[w];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L26
L29:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L20
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L20:
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L29
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int d(unsigned int n) {
  unsigned int sum = 0;
  unsigned int i;
  for (i = 1; i < n; i++) {
    if (n % i == 0) {
      sum += i;
    }
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<d>:
  endbr64
  cmp    $0x1,%edi
  jbe    L10
  mov    $0x1,%ecx
  mov    $0x0,%esi
L9:
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L9
L18:
  mov    %esi,%eax
  ret
L10:
  mov    $0x0,%esi
  jmp    L18
```

assistant: ```c
unsigned int d(unsigned int n) {
  unsigned int sum = 0;
  unsigned int i;
  for (i = 1; i < n; i++) {
    if (n % i == 0) {
      sum += i;
    }
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<d>:
  endbr64
  cmp    $0x1,%edi
  jbe    L17
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L6:
  xor    %edx,%edx
  mov    %edi,%eax
  div    %ecx
  lea    (%r8,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L6
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int d(unsigned int n) {
  unsigned int sum = 0;
  unsigned int i;
  for (i = 1; i < n; i++) {
    if (n % i == 0) {
      sum += i;
    }
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d>:
  endbr64
  cmp    $0x1,%edi
  jbe    L0
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L10:
  xor    %edx,%edx
  mov    %edi,%eax
  div    %ecx
  lea    (%r8,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L10
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int d(unsigned int n) {
  unsigned int sum = 0;
  unsigned int i;
  for (i = 1; i < n; i++) {
    if (n % i == 0) {
      sum += i;
    }
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clearScreen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L5:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x62,-0x4(%rbp)
  jle    L5
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: 


assistant: ```c
void clearScreen() {
  int i;
  for (i = 0; i < 99; i++) {
    printf("\n");
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<clearScreen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x63,%ebx
  lea    D0(%rip),%rbp
L0:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: 


assistant: ```c
void clearScreen() {
  int i;
  for (i = 0; i < 99; i++) {
    printf("\n");
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<clearScreen>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x63,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: 


assistant: ```c
void clearScreen() {
  int i;
  for (i = 0; i < 99; i++) {
    printf("\n");
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clearScreen>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    $0x63,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: D7: 


assistant: ```c
void clearScreen() {
  int i;
  for (i = 0; i < 99; i++) {
    printf("\n");
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <func@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  i = func(&i);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <func@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i;
  i = func(&i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <func@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i;
  i = func(&i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <func@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i;
  i = func(&i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<modf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x34,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  and    $0x7ff,%eax
  sub    $0x3ff,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x33,-0x10(%rbp)
  jle    L73
  mov    -0x20(%rbp),%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  cmpl   $0x400,-0x10(%rbp)
  jne    L41
  mov    -0x8(%rbp),%eax
  shl    $0xc,%eax
  test   %eax,%eax
  je     L41
  movsd  -0x18(%rbp),%xmm0
  jmp    L35
L41:
  movl   $0x0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  jmp    L35
L73:
  cmpl   $0x0,-0x10(%rbp)
  jns    L54
  movl   $0x0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x18(%rbp),%xmm0
  jmp    L35
L54:
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L20
  mov    -0x20(%rbp),%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  jmp    L35
L20:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
L35:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double modf(double x, double *iptr) {
  union {
    double x;
    uint64_t n;
  } u = {x};
  uint64_t mask;
  int e;
  e = (int)(u.n >> 52 & 0x7ff) - 0x3ff;
  if (e >= 52) {
    *iptr = x;
    if (e == 0x400 && u.n << 12 != 0)
      return x;
    u.n &= (uint64_t)1 << 63;
    return u.x;
  }
  if (e < 0) {
    u.n &= (uint64_t)1 << 63;
    *iptr = u.x;
    return x;
  }
  mask = (uint64_t)-1 >> 12 >> e;
  if ((u.n & mask) == 0) {
    *iptr = x;
    u.n &= (uint64_t)1 << 63;
    return u.x;
  }
  u.n &= ~mask;
  *iptr = u.x;
  return x - *iptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<modf>:
  endbr64
  movq   %xmm0,%rdx
  movd   %xmm0,%esi
  movd   %xmm0,%eax
  mov    $0x34,%ecx
  sar    %cl,%eax
  and    $0x7ff,%eax
  sub    $0x3ff,%eax
  cmp    $0x33,%eax
  jle    L46
  movsd  %xmm0,(%rdi)
  cmp    $0x400,%eax
  jne    L31
  shl    $0xc,%esi
  jne    L8
L31:
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  movq   %rdx,%xmm0
  ret
L46:
  test   %eax,%eax
  js     L30
  test   %edx,%edx
  je     L20
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  mov    %rdx,(%rdi)
  movq   %rdx,%xmm1
  subsd  %xmm1,%xmm0
L8:
  ret
L30:
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  mov    %rdx,(%rdi)
  ret
L20:
  movsd  %xmm0,(%rdi)
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  movq   %rdx,%xmm0
  ret
```

assistant: ```c
double modf(double x, double *iptr) {
  union {
    double x;
    uint64_t n;
  } u = {x};
  uint64_t mask;
  int e;
  e = (int)(u.n >> 52 & 0x7ff) - 0x3ff;
  if (e >= 52) {
    *iptr = x;
    if (e == 0x400 && u.n << 12 != 0)
      return x;
    u.n &= (uint64_t)1 << 63;
    return u.x;
  }
  if (e < 0) {
    u.n &= (uint64_t)1 << 63;
    *iptr = u.x;
    return x;
  }
  mask = (uint64_t)-1 >> 12 >> e;
  if ((u.n & mask) == 0) {
    *iptr = x;
    u.n &= (uint64_t)1 << 63;
    return u.x;
  }
  u.n &= ~mask;
  *iptr = u.x;
  return x - *iptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<modf>:
  endbr64
  movd   %xmm0,%eax
  mov    $0x34,%ecx
  movq   %xmm0,%rdx
  sar    %cl,%eax
  movd   %xmm0,%esi
  and    $0x7ff,%eax
  sub    $0x3ff,%eax
  cmp    $0x33,%eax
  jle    L37
  movsd  %xmm0,(%rdi)
  cmp    $0x400,%eax
  jne    L29
  shl    $0xc,%esi
  je     L29
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  movsd  %xmm0,(%rdi)
L29:
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  movq   %rdx,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  test   %eax,%eax
  js     L12
  test   %edx,%edx
  je     L28
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  movq   %rdx,%xmm1
  mov    %rdx,(%rdi)
  subsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
double modf(double x, double *iptr) {
  union {
    double x;
    uint64_t n;
  } u = {x};
  uint64_t mask;
  int e;
  e = (int)(u.n >> 52 & 0x7ff) - 0x3ff;
  if (e >= 52) {
    *iptr = x;
    if (e == 0x400 && u.n << 12 != 0)
      return x;
    u.n &= (uint64_t)1 << 63;
    return u.x;
  }
  if (e < 0) {
    u.n &= (uint64_t)1 << 63;
    *iptr = u.x;
    return x;
  }
  mask = (uint64_t)-1 >> 12 >> e;
  if ((u.n & mask) == 0) {
    *iptr = x;
    u.n &= (uint64_t)1 << 63;
    return u.x;
  }
  u.n &= ~mask;
  *iptr = u.x;
  return x - *iptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modf>:
  endbr64
  movd   %xmm0,%eax
  mov    $0x34,%ecx
  movq   %xmm0,%rdx
  sar    %cl,%eax
  movd   %xmm0,%esi
  and    $0x7ff,%eax
  sub    $0x3ff,%eax
  cmp    $0x33,%eax
  jle    L48
  movsd  %xmm0,(%rdi)
  cmp    $0x400,%eax
  jne    L38
  shl    $0xc,%esi
  je     L38
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  movsd  %xmm0,(%rdi)
L38:
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  movq   %rdx,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  test   %eax,%eax
  js     L26
  test   %edx,%edx
  je     L9
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  movq   %rdx,%xmm1
  mov    %rdx,(%rdi)
  subsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  movabs $0xffffffff00000000,%rax
  and    %rax,%rdx
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
double modf(double x, double *iptr) {
  union {
    double x;
    uint64_t n;
  } u = {x};
  uint64_t mask;
  int e;
  e = (int)(u.n >> 52 & 0x7ff) - 0x3ff;
  if (e >= 52) {
    *iptr = x;
    if (e == 0x400 && u.n << 12 != 0)
      return x;
    u.n &= (uint64_t)1 << 63;
    return u.x;
  }
  if (e < 0) {
    u.n &= (uint64_t)1 << 63;
    *iptr = u.x;
    return x;
  }
  mask = (uint64_t)-1 >> 12 >> e;
  if ((u.n & mask) == 0) {
    *iptr = x;
    u.n &= (uint64_t)1 << 63;
    return u.x;
  }
  u.n &= ~mask;
  *iptr = u.x;
  return x - *iptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mbstowcs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
L13:
  mov    -0x38(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <mbtowc@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L36
  mov    $0xffffffffffffffff,%rax
  jmp    L22
L36:
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  nop
  mov    -0x10(%rbp),%rax
  jmp    L22
L1:
  addq   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L13
L22:
  leave
  ret
```

assistant: ```c
size_t mbstowcs(wchar_t *dest, const char *src, size_t max) {
  size_t total = 0;
  size_t read = 0;
  while (1) {
    int bytes = mbtowc(&dest[total], &src[read], max - read);
    if (bytes < 0)
      return (size_t)-1;
    if (bytes == 0) {
      dest[total] = 0;
      break;
    }
    ++total;
    read += bytes;
  };
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mbstowcs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L16
L5:
  add    $0x1,%r12
  cltq
  add    %rax,%rbp
L16:
  mov    %rbx,%r15
  mov    %r13,%rdx
  sub    %rbp,%rdx
  lea    (%r14,%rbp,1),%rsi
  mov    %rbx,%rdi
  call   <mbtowc@plt>
  test   %eax,%eax
  js     L36
  add    $0x8,%rbx
  test   %eax,%eax
  jne    L5
  movq   $0x0,(%r15)
  jmp    L12
L36:
  mov    $0xffffffffffffffff,%r12
L12:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
size_t mbstowcs(wchar_t *dest, const char *src, size_t max) {
  size_t total = 0;
  size_t read = 0;
  while (1) {
    int bytes = mbtowc(&dest[total], &src[read], max - read);
    if (bytes < 0)
      return (size_t)-1;
    if (bytes == 0) {
      dest[total] = 0;
      break;
    }
    ++total;
    read += bytes;
  };
  return total;
}
```
user: What is the c source code of the assembly code below?

```asm
<mbstowcs>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x8,%r14
  test   %eax,%eax
  je     L3
  cltq
  add    $0x1,%r12
  add    %rax,%r15
L11:
  mov    %rbx,%rdx
  lea    0x0(%rbp,%r15,1),%rsi
  mov    %r14,%rdi
  mov    %r14,%r13
  sub    %r15,%rdx
  call   <mbtowc@plt>
  test   %eax,%eax
  jns    L29
  mov    $0xffffffffffffffff,%r12
L35:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  movq   $0x0,0x0(%r13)
  jmp    L35
```

assistant: ```c
size_t mbstowcs(wchar_t *dest, const char *src, size_t max) {
  size_t total = 0;
  size_t read = 0;
  while (1) {
    int bytes = mbtowc(&dest[total], &src[read], max - read);
    if (bytes < 0)
      return (size_t)-1;
    if (bytes == 0) {
      dest[total] = 0;
      break;
    }
    ++total;
    read += bytes;
  };
  return total;
}
```