ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unfs_child_of>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jle    L28
  lea    0x1(%rbp),%rdi
  cmp    $0x1,%eax
  je     L7
  movslq %eax,%rbx
  add    %rbp,%rbx
  cmpb   $0x2f,(%rbx)
  je     L16
L28:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L28
  lea    0x1(%rbx),%rdi
L7:
  mov    $0x2f,%esi
  call   <strchr@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int unfs_child_of(const char *child, const char *parent) {
  int clen = strlen(child);
  int plen = strlen(parent);
  if (clen <= plen)
    return 0;
  if (plen == 1)
    return (strchr(child + 1, '/') == 0);
  const char *s = child + plen;
  return (*s == '/' && !strncmp(child, parent, plen) && !strchr(s + 1, '/'));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unfs_child_of>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jle    L20
  lea    0x1(%rbp),%rdi
  cmp    $0x1,%eax
  je     L34
  movslq %eax,%rbx
  add    %rbp,%rbx
  cmpb   $0x2f,(%rbx)
  je     L33
L20:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L33:
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L20
  lea    0x1(%rbx),%rdi
L34:
  mov    $0x2f,%esi
  call   <strchr@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int unfs_child_of(const char *child, const char *parent) {
  int clen = strlen(child);
  int plen = strlen(parent);
  if (clen <= plen)
    return 0;
  if (plen == 1)
    return (strchr(child + 1, '/') == 0);
  const char *s = child + plen;
  return (*s == '/' && !strncmp(child, parent, plen) && !strchr(s + 1, '/'));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ALLOC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *ALLOC(int size) {
  void *a = calloc(1, size);
  if (a == NULL)
    abort();
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ALLOC>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
L6:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L9
```

assistant: ```c
void *ALLOC(int size) {
  void *a = calloc(1, size);
  if (a == NULL)
    abort();
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ALLOC>:
  endbr64
  push   %r12
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r12,%rax
  pop    %r12
  ret
L7:
  xor    %eax,%eax
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *ALLOC(int size) {
  void *a = calloc(1, size);
  if (a == NULL)
    abort();
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ALLOC>:
  endbr64
  push   %r12
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r12,%rax
  pop    %r12
  ret
L1:
  xor    %eax,%eax
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *ALLOC(int size) {
  void *a = calloc(1, size);
  if (a == NULL)
    abort();
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: Thread is working

assistant: ```c
void *func(void *p) {
  puts("Thread is working");
  pthread_exit(NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<func>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: Thread is working

assistant: ```c
void *func(void *p) {
  puts("Thread is working");
  pthread_exit(NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: Thread is working

assistant: ```c
void *func(void *p) {
  puts("Thread is working");
  pthread_exit(NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: Thread is working

assistant: ```c
void *func(void *p) {
  puts("Thread is working");
  pthread_exit(NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<synchnet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xf000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0xff0,%rsp
  mov    %edi,-0xffe4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xffd4(%rbp)
L15:
  mov    D7(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xffe0(%rbp),%rdx
  mov    -0xffe4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0xffe0(%rbp),%eax
  test   %eax,%eax
  je     L13
  addl   $0x1,-0xffd4(%rbp)
  movl   $0x4,-0xffd8(%rbp)
  lea    -0xffd8(%rbp),%rcx
  lea    -0xffdc(%rbp),%rdx
  lea    -0xffd0(%rbp),%rsi
  mov    -0xffe4(%rbp),%eax
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0xffbc,%edx
  mov    %eax,%edi
  call   <recvfrom@plt>
  jmp    L15
L13:
  mov    -0xffd4(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int synchnet(int f) {
  int i, j = 0;
  char rbuf[65464 + 4];
  struct sockaddr_in from;
  int fromlen;
  while (1) {
    (void)ioctl(f, FIONREAD, &i);
    if (i) {
      j++;
      fromlen = sizeof from;
      (void)recvfrom(f, rbuf, sizeof(rbuf), 0, (struct sockaddr *)&from, &fromlen);
    } else {
      return (j);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<synchnet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf000(%rsp),%r11
L39:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L39
  sub    $0xfe0,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0xffd8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  lea    0x4(%rsp),%r12
  jmp    L4
L2:
  add    $0x1,%ebp
  movl   $0x4,0xc(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%r9
  lea    0x8(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0xffbc,%edx
  mov    %ebx,%edi
  call   <recvfrom@plt>
L4:
  mov    %r12,%rdx
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  cmpl   $0x0,0x4(%rsp)
  jne    L2
  mov    0xffd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %ebp,%eax
  add    $0xffe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synchnet(int f) {
  int i, j = 0;
  char rbuf[65464 + 4];
  struct sockaddr_in from;
  int fromlen;
  while (1) {
    (void)ioctl(f, FIONREAD, &i);
    if (i) {
      j++;
      fromlen = sizeof from;
      (void)recvfrom(f, rbuf, sizeof(rbuf), 0, (struct sockaddr *)&from, &fromlen);
    } else {
      return (j);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<synchnet>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf000(%rsp),%r11
L21:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L21
  sub    $0xfe0,%rsp
  mov    D6(%rip),%rbp
  xor    %r14d,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0xffd8(%rsp)
  xor    %eax,%eax
  mov    %edi,%ebx
  lea    0x4(%rsp),%r12
  lea    0xc(%rsp),%r13
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L30:
  lea    0x10(%rsp),%rsi
  mov    %r13,%r9
  lea    0x8(%rsp),%r8
  xor    %ecx,%ecx
  mov    $0xffbc,%edx
  mov    %ebx,%edi
  movl   $0x4,0xc(%rsp)
  add    $0x1,%r14d
  call   <recvfrom@plt>
L34:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdx
  mov    %ebx,%edi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L30
  mov    0xffd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0xffe0,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synchnet(int f) {
  int i, j = 0;
  char rbuf[65464 + 4];
  struct sockaddr_in from;
  int fromlen;
  while (1) {
    (void)ioctl(f, FIONREAD, &i);
    if (i) {
      j++;
      fromlen = sizeof from;
      (void)recvfrom(f, rbuf, sizeof(rbuf), 0, (struct sockaddr *)&from, &fromlen);
    } else {
      return (j);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<synchnet>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0xfe0,%rsp
  mov    D0(%rip),%rbp
  xor    %r14d,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0xffd8(%rsp)
  xor    %eax,%eax
  mov    %edi,%ebx
  lea    0x4(%rsp),%r12
  lea    0xc(%rsp),%r13
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L2:
  lea    0x10(%rsp),%rsi
  mov    %r13,%r9
  lea    0x8(%rsp),%r8
  xor    %ecx,%ecx
  mov    $0xffbc,%edx
  mov    %ebx,%edi
  movl   $0x4,0xc(%rsp)
  add    $0x1,%r14d
  call   <recvfrom@plt>
L5:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdx
  mov    %ebx,%edi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L2
  mov    0xffd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0xffe0,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synchnet(int f) {
  int i, j = 0;
  char rbuf[65464 + 4];
  struct sockaddr_in from;
  int fromlen;
  while (1) {
    (void)ioctl(f, FIONREAD, &i);
    if (i) {
      j++;
      fromlen = sizeof from;
      (void)recvfrom(f, rbuf, sizeof(rbuf), 0, (struct sockaddr *)&from, &fromlen);
    } else {
      return (j);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0xc(%rbp)
  movl   $0x5,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type: string
name: extract_symbolic_data
arguments: tag: D13
type: string

tool: D10: x=%d & y=%d


tool: D13: El resultado es = %d

assistant: ```c
int main() {
  int x, y, suma;
  float pi;
  x = 3;
  y = 5;
  suma = x + y;
  printf("x=%d & y=%d\n", x, y);
  printf("El resultado es = %d", suma);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x3,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D13
type: string

tool: D19: x=%d & y=%d


tool: D13: El resultado es = %d

assistant: ```c
int main() {
  int x, y, suma;
  float pi;
  x = 3;
  y = 5;
  suma = x + y;
  printf("x=%d & y=%d\n", x, y);
  printf("El resultado es = %d", suma);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x3,%esi
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string

tool: D2: x=%d & y=%d


tool: D3: El resultado es = %d

assistant: ```c
int main() {
  int x, y, suma;
  float pi;
  x = 3;
  y = 5;
  suma = x + y;
  printf("x=%d & y=%d\n", x, y);
  printf("El resultado es = %d", suma);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x3,%esi
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
data_type: string
name: retrieve_data
arguments: data_tag: D16
data_type: string

tool: D11: x=%d & y=%d


tool: D16: El resultado es = %d

assistant: ```c
int main() {
  int x, y, suma;
  float pi;
  x = 3;
  y = 5;
  suma = x + y;
  printf("x=%d & y=%d\n", x, y);
  printf("El resultado es = %d", suma);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_triplet_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L11
L78:
  mov    -0x18(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L81
L56:
  mov    -0x14(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L89
L22:
  mov    -0x10(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0xc(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L12
  ucomiss -0x4(%rbp),%xmm0
  jne    L12
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x24(%rbp)
  jne    L12
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  imul   -0x10(%rbp),%eax
  jmp    L6
L12:
  addl   $0x1,-0x10(%rbp)
L89:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L22
  addl   $0x1,-0x14(%rbp)
L81:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L56
  addl   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L78
  mov    $0xffffffff,%eax
L6:
  leave
  ret
```

assistant: ```c
int find_triplet_product(int sum) {
  float x, y, z;
  for (int a = 1; a < sum; ++a) {
    x = pow(a, 2);
    for (int b = a + 1; b < sum; ++b) {
      y = pow(b, 2);
      for (int c = b + 1; c < sum; ++c) {
        z = pow(c, 2);
        if (x + y == z) {
          if (a + b + c == sum) {
            return a * b * c;
          }
        }
      }
    }
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find_triplet_product>:
  endbr64
  cmp    $0x1,%edi
  jle    L50
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  movl   $0x1,0xc(%rsp)
L53:
  mov    $0x2,%esi
  mov    0xc(%rsp),%ebx
  mov    %ebx,%edi
  call   <pow@plt>
  movss  %xmm0,0x8(%rsp)
  lea    0x1(%rbx),%r15d
  cmp    %r15d,%ebp
  je     L94
  lea    -0x1(%r15,%r15,1),%r12d
  mov    %r15d,%r14d
  jmp    L40
L34:
  mov    %r15d,0xc(%rsp)
  jmp    L53
L39:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L44
L100:
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <pow@plt>
  movss  0x8(%rsp),%xmm1
  addss  0x4(%rsp),%xmm1
  ucomiss %xmm0,%xmm1
  jp     L39
  jne    L39
  lea    (%rbx,%r12,1),%eax
  cmp    %eax,%ebp
  jne    L39
  mov    0xc(%rsp),%eax
  imul   %r14d,%eax
  imul   %ebx,%eax
L76:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  add    $0x1,%r12d
  mov    %r13d,%r14d
L40:
  mov    $0x2,%esi
  mov    %r14d,%edi
  call   <pow@plt>
  movss  %xmm0,0x4(%rsp)
  lea    0x1(%r14),%r13d
  cmp    %r13d,%ebp
  je     L34
  mov    %r13d,%ebx
  jmp    L100
L50:
  mov    $0xffffffff,%eax
  ret
L94:
  mov    $0xffffffff,%eax
  jmp    L76
```

assistant: ```c
int find_triplet_product(int sum) {
  float x, y, z;
  for (int a = 1; a < sum; ++a) {
    x = pow(a, 2);
    for (int b = a + 1; b < sum; ++b) {
      y = pow(b, 2);
      for (int c = b + 1; c < sum; ++c) {
        z = pow(c, 2);
        if (x + y == z) {
          if (a + b + c == sum) {
            return a * b * c;
          }
        }
      }
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<find_triplet_product>:
  endbr64
  cmp    $0x1,%edi
  jle    L87
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
L60:
  mov    $0x2,%esi
  mov    %r14d,%edi
  lea    0x1(%r14),%r13d
  call   <pow@plt>
  mov    %r13d,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  cmp    %r13d,%ebx
  je     L61
  lea    -0x1(%r13,%r13,1),%ebp
L72:
  mov    $0x2,%esi
  mov    %r13d,%edi
  lea    0x1(%r13),%r12d
  call   <pow@plt>
  cmp    %r12d,%ebx
  je     L71
  addss  0x8(%rsp),%xmm0
  mov    %r12d,%r15d
  movss  %xmm0,0x4(%rsp)
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0x2,%esi
  mov    %r15d,%edi
  call   <pow@plt>
  movss  0x4(%rsp),%xmm1
  ucomiss %xmm0,%xmm1
  jp     L24
  jne    L24
  lea    (%r15,%rbp,1),%eax
  cmp    %eax,%ebx
  je     L83
L24:
  add    $0x1,%r15d
  cmp    %r15d,%ebx
  jne    L14
  add    $0x1,%ebp
  mov    %r12d,%r13d
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L83:
  mov    %r14d,%eax
  add    $0x18,%rsp
  imul   %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  imul   %r15d,%eax
  pop    %r15
  ret
L71:
  mov    0xc(%rsp),%r14d
  jmp    L60
L61:
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L87:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int find_triplet_product(int sum) {
  float x, y, z;
  for (int a = 1; a < sum; ++a) {
    x = pow(a, 2);
    for (int b = a + 1; b < sum; ++b) {
      y = pow(b, 2);
      for (int c = b + 1; c < sum; ++c) {
        z = pow(c, 2);
        if (x + y == z) {
          if (a + b + c == sum) {
            return a * b * c;
          }
        }
      }
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_triplet_product>:
  endbr64
  cmp    $0x1,%edi
  jle    L35
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
L76:
  mov    $0x2,%esi
  mov    %r14d,%edi
  lea    0x1(%r14),%r13d
  call   <pow@plt>
  mov    %r13d,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  cmp    %r13d,%ebx
  je     L75
  lea    -0x1(%r13,%r13,1),%ebp
L84:
  mov    $0x2,%esi
  mov    %r13d,%edi
  lea    0x1(%r13),%r12d
  call   <pow@plt>
  cmp    %r12d,%ebx
  je     L17
  addss  0x8(%rsp),%xmm0
  mov    %r12d,%r15d
  movss  %xmm0,0x4(%rsp)
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x2,%esi
  mov    %r15d,%edi
  call   <pow@plt>
  movss  0x4(%rsp),%xmm1
  ucomiss %xmm0,%xmm1
  jp     L5
  jne    L5
  lea    (%r15,%rbp,1),%eax
  cmp    %ebx,%eax
  je     L34
L5:
  add    $0x1,%r15d
  cmp    %r15d,%ebx
  jne    L16
  add    $0x1,%ebp
  mov    %r12d,%r13d
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r14d,%eax
  add    $0x18,%rsp
  imul   %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  imul   %r15d,%eax
  pop    %r15
  ret
L17:
  mov    0xc(%rsp),%r14d
  jmp    L76
L75:
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int find_triplet_product(int sum) {
  float x, y, z;
  for (int a = 1; a < sum; ++a) {
    x = pow(a, 2);
    for (int b = a + 1; b < sum; ++b) {
      y = pow(b, 2);
      for (int c = b + 1; c < sum; ++c) {
        z = pow(c, 2);
        if (x + y == z) {
          if (a + b + c == sum) {
            return a * b * c;
          }
        }
      }
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  mov    %eax,%edx
  je     L18
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%ax
  mov    %eax,%ecx
  shr    $0x2,%cx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%ax
L29:
  test   %ax,%ax
  je     L15
  movzwl %ax,%edx
  imul   %edx,%edx
  shl    $0x4,%edx
  and    $0x3f0,%dx
  or     %edx,%eax
L15:
  imul   $0x274,%ax,%ax
  mov    %ax,(%rsi)
  ret
L18:
  movsbl %ah,%ecx
  mov    %cl,%dl
  mov    %al,%dh
  movzwl %dx,%r8d
  mov    %edx,%edi
  shr    $0x2,%di
  and    $0xe,%edi
  or     $0x1,%edi
  mov    $0x10,%ecx
  sub    %edi,%ecx
  mov    %r8d,%eax
  sar    %cl,%eax
  mov    %edi,%ecx
  shl    %cl,%r8d
  or     %r8d,%eax
  shl    $0x4,%eax
  and    $0x3f0,%ax
  or     %edx,%eax
  jmp    L29
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[0UL] = (state[local1] >> ((state[local1] & (unsigned short)15) | 1UL)) | (state[local1] << (16 - ((state[local1] & (unsigned short)15) | 1UL)));
        state[0UL] = (state[local1] << (((state[local1] >> (unsigned short)2) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[local1] >> (unsigned short)2) & (unsigned short)15) | 1UL)));
      } else {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        state[local1] |= (((state[local1] << (((state[0UL] >> (unsigned short)2) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[0UL] >> (unsigned short)2) & (unsigned short)15) | 1UL)))) & (unsigned short)63) << 4UL;
      }
      if (state[0UL] == local1) {
        state[local1] |= ((state[local1] + state[local1]) & (unsigned short)15) << 2UL;
      } else {
        state[local1] |= (state[local1] * state[local1] & (unsigned short)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 1062470260UL;
  }
}
```