ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<vuln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmpl   $0xc0deface,-0x24(%rbp)
  jne    L28
  mov    $0x0,%eax
  call   <give_shell@plt>
  jmp    L26
L28:
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L26:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: The secret is %x


assistant: ```c
void vuln(char *input) {
  char buf[16];
  int secret = 0;
  strcpy(buf, input);
  if (secret == 0xc0deface) {
    give_shell();
  } else {
    printf("The secret is %x\n", secret);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vuln>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    $0x0,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: The secret is %x


assistant: ```c
void vuln(char *input) {
  char buf[16];
  int secret = 0;
  strcpy(buf, input);
  if (secret == 0xc0deface) {
    give_shell();
  } else {
    printf("The secret is %x\n", secret);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vuln>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  xor    %esi,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: The secret is %x


assistant: ```c
void vuln(char *input) {
  char buf[16];
  int secret = 0;
  strcpy(buf, input);
  if (secret == 0xc0deface) {
    give_shell();
  } else {
    printf("The secret is %x\n", secret);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vuln>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: The secret is %x


assistant: ```c
void vuln(char *input) {
  char buf[16];
  int secret = 0;
  strcpy(buf, input);
  if (secret == 0xc0deface) {
    give_shell();
  } else {
    printf("The secret is %x\n", secret);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lpwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string

tool: D1: Current working directory: %s


assistant: ```c
int lpwd() {
  char *wd = (char *)malloc(1024);
  getcwd(wd, 1024);
  printf("Current working directory: %s\n", wd);
  free(wd);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lpwd>:
  endbr64
  push   %rbx
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: Current working directory: %s


assistant: ```c
int lpwd() {
  char *wd = (char *)malloc(1024);
  getcwd(wd, 1024);
  printf("Current working directory: %s\n", wd);
  free(wd);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lpwd>:
  endbr64
  push   %rbp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    $0x400,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: Current working directory: %s


assistant: ```c
int lpwd() {
  char *wd = (char *)malloc(1024);
  getcwd(wd, 1024);
  printf("Current working directory: %s\n", wd);
  free(wd);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lpwd>:
  endbr64
  push   %rbp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    $0x400,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: Current working directory: %s


assistant: ```c
int lpwd() {
  char *wd = (char *)malloc(1024);
  getcwd(wd, 1024);
  printf("Current working directory: %s\n", wd);
  free(wd);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SbCJ22537442193159_br_find_sbin_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <SbCJ22537442193159_br_find_prefix@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L9
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L39
L28:
  mov    $0x0,%eax
  jmp    L39
L9:
  mov    -0x10(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <SbCJ22537442193159_br_build_path@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: sbin

assistant: ```c
char *SbCJ22537442193159_br_find_sbin_dir(const char *default_sbin_dir) {
  char *prefix, *dir;
  prefix = SbCJ22537442193159_br_find_prefix((const char *)((void *)0));
  if (prefix == (char *)((void *)0)) {
    if (default_sbin_dir != (const char *)((void *)0))
      return strdup(default_sbin_dir);
    else
      return (char *)((void *)0);
  }
  dir = SbCJ22537442193159_br_build_path(prefix, "sbin");
  free(prefix);
  return dir;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SbCJ22537442193159_br_find_sbin_dir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <SbCJ22537442193159_br_find_prefix@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rbx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <SbCJ22537442193159_br_build_path@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <free@plt>
L4:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %rbp,%r12
  test   %rbp,%rbp
  je     L4
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: sbin

assistant: ```c
char *SbCJ22537442193159_br_find_sbin_dir(const char *default_sbin_dir) {
  char *prefix, *dir;
  prefix = SbCJ22537442193159_br_find_prefix((const char *)((void *)0));
  if (prefix == (char *)((void *)0)) {
    if (default_sbin_dir != (const char *)((void *)0))
      return strdup(default_sbin_dir);
    else
      return (char *)((void *)0);
  }
  dir = SbCJ22537442193159_br_build_path(prefix, "sbin");
  free(prefix);
  return dir;
}
```
user: What is the c source code of the assembly code below?

```asm
<SbCJ22537442193159_br_find_sbin_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <SbCJ22537442193159_br_find_prefix@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbp
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <SbCJ22537442193159_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  test   %r12,%r12
  je     L5
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L5:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: sbin

assistant: ```c
char *SbCJ22537442193159_br_find_sbin_dir(const char *default_sbin_dir) {
  char *prefix, *dir;
  prefix = SbCJ22537442193159_br_find_prefix((const char *)((void *)0));
  if (prefix == (char *)((void *)0)) {
    if (default_sbin_dir != (const char *)((void *)0))
      return strdup(default_sbin_dir);
    else
      return (char *)((void *)0);
  }
  dir = SbCJ22537442193159_br_build_path(prefix, "sbin");
  free(prefix);
  return dir;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SbCJ22537442193159_br_find_sbin_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <SbCJ22537442193159_br_find_prefix@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rbp
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <SbCJ22537442193159_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  test   %r12,%r12
  je     L9
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L9:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: sbin

assistant: ```c
char *SbCJ22537442193159_br_find_sbin_dir(const char *default_sbin_dir) {
  char *prefix, *dir;
  prefix = SbCJ22537442193159_br_find_prefix((const char *)((void *)0));
  if (prefix == (char *)((void *)0)) {
    if (default_sbin_dir != (const char *)((void *)0))
      return strdup(default_sbin_dir);
    else
      return (char *)((void *)0);
  }
  dir = SbCJ22537442193159_br_build_path(prefix, "sbin");
  free(prefix);
  return dir;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floatinvert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L4:
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  movss  -0x24(%rbp),%xmm0
  subss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  addq   $0x4,-0x8(%rbp)
L0:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void floatinvert(float *in, size_t size, float base) {
  float *pt = in;
  for (; pt < in + size; pt++)
    *pt = base - *pt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floatinvert>:
  endbr64
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdi
  jae    L6
L3:
  movaps %xmm0,%xmm1
  subss  (%rdi),%xmm1
  movss  %xmm1,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jb     L3
L6:
  ret
```

assistant: ```c
void floatinvert(float *in, size_t size, float base) {
  float *pt = in;
  for (; pt < in + size; pt++)
    *pt = base - *pt;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<floatinvert>:
  endbr64
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdi
  jae    L3
  nopl   (%rax)
L11:
  movaps %xmm0,%xmm1
  subss  (%rdi),%xmm1
  add    $0x4,%rdi
  movss  %xmm1,-0x4(%rdi)
  cmp    %rax,%rdi
  jb     L11
L3:
  ret
```

assistant: ```c
void floatinvert(float *in, size_t size, float base) {
  float *pt = in;
  for (; pt < in + size; pt++)
    *pt = base - *pt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<floatinvert>:
  endbr64
  shl    $0x2,%rsi
  mov    %rdi,%rdx
  lea    (%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L35
  sub    $0x1,%rsi
  mov    %rdi,%rax
  mov    %rsi,%r8
  shr    $0x2,%r8
  lea    0x1(%r8),%rdi
  cmp    $0xb,%rsi
  jbe    L62
  mov    %rdi,%rcx
  movaps %xmm0,%xmm2
  shr    $0x2,%rcx
  shufps $0x0,%xmm2,%xmm2
  shl    $0x4,%rcx
  add    %rdx,%rcx
  nopl   (%rax)
L37:
  movups (%rax),%xmm3
  movaps %xmm2,%xmm1
  add    $0x10,%rax
  subps  %xmm3,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L37
  mov    %rdi,%rcx
  and    $0xfffffffffffffffc,%rcx
  lea    (%rdx,%rcx,4),%rax
  cmp    %rcx,%rdi
  je     L16
L61:
  sub    %rcx,%rdi
  cmp    %rcx,%r8
  je     L51
  lea    (%rdx,%rcx,4),%rdx
  movaps %xmm0,%xmm1
  movq   (%rdx),%xmm2
  shufps $0xe0,%xmm1,%xmm1
  subps  %xmm2,%xmm1
  movlps %xmm1,(%rdx)
  mov    %rdi,%rdx
  and    $0xfffffffffffffffe,%rdx
  lea    (%rax,%rdx,4),%rax
  cmp    %rdx,%rdi
  je     L35
L51:
  subss  (%rax),%xmm0
  movss  %xmm0,(%rax)
L35:
  ret
  nopl   0x0(%rax)
L16:
  ret
L62:
  xor    %ecx,%ecx
  jmp    L61
```

assistant: ```c
void floatinvert(float *in, size_t size, float base) {
  float *pt = in;
  for (; pt < in + size; pt++)
    *pt = base - *pt;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<aes_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x24,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_aesenclast_si128@plt>
  leave
  ret
```

assistant: ```c
__m128i aes_encrypt(__m128i in, __m128i *k) {
  __m128i x = _mm_xor_si128(in, k[0]);
  x = _mm_aesenc_si128(x, k[1]);
  x = _mm_aesenc_si128(x, k[2]);
  x = _mm_aesenc_si128(x, k[3]);
  x = _mm_aesenc_si128(x, k[4]);
  x = _mm_aesenc_si128(x, k[5]);
  x = _mm_aesenc_si128(x, k[6]);
  x = _mm_aesenc_si128(x, k[7]);
  x = _mm_aesenc_si128(x, k[8]);
  x = _mm_aesenc_si128(x, k[9]);
  return _mm_aesenclast_si128(x, k[10]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<aes_encrypt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%esi
  call   <_mm_xor_si128@plt>
  mov    %eax,%edi
  mov    0x4(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0x8(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0xc(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0x10(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0x14(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0x18(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0x1c(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0x20(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0x24(%rbx),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    0x28(%rbx),%esi
  call   <_mm_aesenclast_si128@plt>
  pop    %rbx
  ret
```

assistant: ```c
__m128i aes_encrypt(__m128i in, __m128i *k) {
  __m128i x = _mm_xor_si128(in, k[0]);
  x = _mm_aesenc_si128(x, k[1]);
  x = _mm_aesenc_si128(x, k[2]);
  x = _mm_aesenc_si128(x, k[3]);
  x = _mm_aesenc_si128(x, k[4]);
  x = _mm_aesenc_si128(x, k[5]);
  x = _mm_aesenc_si128(x, k[6]);
  x = _mm_aesenc_si128(x, k[7]);
  x = _mm_aesenc_si128(x, k[8]);
  x = _mm_aesenc_si128(x, k[9]);
  return _mm_aesenclast_si128(x, k[10]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<aes_encrypt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%esi
  call   <_mm_xor_si128@plt>
  mov    0x4(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x8(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0xc(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x10(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x14(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x18(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x1c(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x20(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x24(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x28(%rbx),%esi
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <_mm_aesenclast_si128@plt>
```

assistant: ```c
__m128i aes_encrypt(__m128i in, __m128i *k) {
  __m128i x = _mm_xor_si128(in, k[0]);
  x = _mm_aesenc_si128(x, k[1]);
  x = _mm_aesenc_si128(x, k[2]);
  x = _mm_aesenc_si128(x, k[3]);
  x = _mm_aesenc_si128(x, k[4]);
  x = _mm_aesenc_si128(x, k[5]);
  x = _mm_aesenc_si128(x, k[6]);
  x = _mm_aesenc_si128(x, k[7]);
  x = _mm_aesenc_si128(x, k[8]);
  x = _mm_aesenc_si128(x, k[9]);
  return _mm_aesenclast_si128(x, k[10]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aes_encrypt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%esi
  call   <_mm_xor_si128@plt>
  mov    0x4(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x8(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0xc(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x10(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x14(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x18(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x1c(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x20(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x24(%rbx),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    0x28(%rbx),%esi
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <_mm_aesenclast_si128@plt>
```

assistant: ```c
__m128i aes_encrypt(__m128i in, __m128i *k) {
  __m128i x = _mm_xor_si128(in, k[0]);
  x = _mm_aesenc_si128(x, k[1]);
  x = _mm_aesenc_si128(x, k[2]);
  x = _mm_aesenc_si128(x, k[3]);
  x = _mm_aesenc_si128(x, k[4]);
  x = _mm_aesenc_si128(x, k[5]);
  x = _mm_aesenc_si128(x, k[6]);
  x = _mm_aesenc_si128(x, k[7]);
  x = _mm_aesenc_si128(x, k[8]);
  x = _mm_aesenc_si128(x, k[9]);
  return _mm_aesenclast_si128(x, k[10]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_v_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L30
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x4c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x4c(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  and    -0x28(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  jmp    L24
L30:
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L35
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ebx
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  and    %ebx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  jmp    L24
L35:
  mov    $0x0,%eax
L24:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
bool test_v_bit(struct sockaddr_storage *addr, uint8_t bit) {
  if (addr->ss_family == AF_INET6) {
    struct sockaddr_in6 *addr6 = (struct sockaddr_in6 *)addr;
    uint8_t byte_idx = bit / 8;
    uint8_t subbyte_idx = bit % 8;
    uint8_t subbyte = addr6->sin6_addr.s6_addr[byte_idx];
    uint8_t v_bit = subbyte & ((uint8_t)pow(2, subbyte_idx));
    return v_bit;
  } else if (addr->ss_family == AF_INET) {
    struct sockaddr_in *addr4 = (struct sockaddr_in *)addr;
    uint32_t v_bit = addr4->sin_addr.s_addr & ((uint32_t)pow(2, bit));
    return v_bit;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_v_bit>:
  endbr64
  push   %rbx
  mov    (%rdi),%rdx
  mov    D15(%rip),%rax
  cmp    (%rax),%rdx
  je     L3
  mov    $0x0,%eax
  mov    D2(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L4
L22:
  pop    %rbx
  ret
L3:
  lea    0x7(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x3,%eax
  cltq
  mov    (%rdx,%rax,4),%ebx
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%esi
  and    $0x7,%esi
  sub    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  and    %ebx,%eax
  jmp    L22
L4:
  mov    (%rdi),%ebx
  mov    $0x2,%edi
  call   <pow@plt>
  and    %ebx,%eax
  jmp    L22
```

assistant: ```c
bool test_v_bit(struct sockaddr_storage *addr, uint8_t bit) {
  if (addr->ss_family == AF_INET6) {
    struct sockaddr_in6 *addr6 = (struct sockaddr_in6 *)addr;
    uint8_t byte_idx = bit / 8;
    uint8_t subbyte_idx = bit % 8;
    uint8_t subbyte = addr6->sin6_addr.s6_addr[byte_idx];
    uint8_t v_bit = subbyte & ((uint8_t)pow(2, subbyte_idx));
    return v_bit;
  } else if (addr->ss_family == AF_INET) {
    struct sockaddr_in *addr4 = (struct sockaddr_in *)addr;
    uint32_t v_bit = addr4->sin_addr.s_addr & ((uint32_t)pow(2, bit));
    return v_bit;
  }
  return 0;
}
```