ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<encode_url>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %sil,%sil
  je     L97
  mov    %rdi,%rbx
  xor    %ebp,%ebp
  lea    D0(%rip),%r15
  lea    D5(%rip),%r12
  lea    0x4(%rsp),%r14
  lea    D33(%rip),%r13
  jmp    L19
  nop
L24:
  movslq %ebp,%rax
  add    $0x1,%rbx
  add    $0x1,%ebp
  mov    %sil,(%r15,%rax,1)
  movzbl (%rbx),%esi
  xor    %eax,%eax
  test   %sil,%sil
  je     L37
L19:
  test   %eax,%eax
  jne    L24
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L42
  cmpb   $0x0,0x1(%rbx)
  movzbl (%rbx),%eax
  jne    L48
  test   %al,%al
  js     L42
L48:
  movslq %ebp,%rdx
  add    $0x1,%ebp
  mov    %al,(%r15,%rdx,1)
L8:
  movsbl (%rbx),%eax
  movzbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  shr    $0x1f,%eax
  test   %sil,%sil
  jne    L19
L37:
  movslq %ebp,%rbp
  movb   $0x0,(%r15,%rbp,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L42:
  movslq %ebp,%rax
  mov    %r13,%rsi
  mov    %r14,%rdi
  movb   $0x25,(%r15,%rax,1)
  movzbl (%rbx),%edx
  call   <sprintf@plt>
  lea    0x1(%rbp),%edx
  movzbl 0x4(%rsp),%ecx
  lea    0x2(%rbp),%eax
  movslq %edx,%rdx
  cltq
  add    $0x3,%ebp
  mov    %cl,(%r15,%rdx,1)
  movzbl 0x5(%rsp),%edx
  mov    %dl,(%r15,%rax,1)
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L97:
  xor    %ebp,%ebp
  lea    D0(%rip),%r15
  jmp    L37
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string
name: unpack_data
arguments: data_label: D33
datatype: string

tool: D5: ~`!@#$%%^&*()-_=+[{]}\|;:'",<.>/? 

tool: D33: %02X

assistant: ```c
char *encode_url(unsigned char *s) {
  int i, j, half = 0;
  static char buf[1024];
  char a[4];
  j = 0;
  for (i = 0; s[i]; i++) {
    if ((!half && strchr("~`!@#$%%^&*()-_=+[{]}\\|;:'\",<.>/? ", s[i])) || (s[i + 1] == 0 && !half && (unsigned char)s[i] >= 128)) {
      buf[j++] = '%';
      sprintf(a, "%02X", s[i]);
      buf[j++] = a[0];
      buf[j++] = a[1];
    } else
      buf[j++] = s[i];
    if (half)
      half = 0;
    else if ((unsigned char)s[i] >= 128)
      half = 1;
  }
  buf[j] = 0;
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<asnReadIntegerL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <asnReadLength@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L16
L8:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <asnReadInteger@plt>
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int asnReadIntegerL(long *value) {
  long length;
  if (asnReadLength(&length) == -1)
    return -1;
  return asnReadInteger(value, (int)length);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<asnReadIntegerL>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asnReadLength@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  call   <asnReadInteger@plt>
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asnReadIntegerL(long *value) {
  long length;
  if (asnReadLength(&length) == -1)
    return -1;
  return asnReadInteger(value, (int)length);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<asnReadIntegerL>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asnReadLength@plt>
  cmp    $0xffffffff,%eax
  je     L11
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <asnReadInteger@plt>
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asnReadIntegerL(long *value) {
  long length;
  if (asnReadLength(&length) == -1)
    return -1;
  return asnReadInteger(value, (int)length);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<asnReadIntegerL>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asnReadLength@plt>
  cmp    $0xffffffff,%eax
  je     L8
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <asnReadInteger@plt>
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asnReadIntegerL(long *value) {
  long length;
  if (asnReadLength(&length) == -1)
    return -1;
  return asnReadInteger(value, (int)length);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<opdi_str_to_uint16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D13(%rip),%rax
  movq   $0x0,(%rax)
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L38
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L31
L38:
  mov    $0x5,%eax
  jmp    L45
L31:
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
uint8_t opdi_str_to_uint16(const char *str, uint16_t *result) {
  char *p;
  long res;
  errno = 0;
  res = strtol(str, &p, 10);
  if (errno != 0 || *p != 0 || p == str)
    return 5;
  *result = (uint16_t)res;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<opdi_str_to_uint16>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%r12
  movq   $0x0,(%r12)
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    $0x5,%edx
  cmpq   $0x0,(%r12)
  jne    L24
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L9
  cmp    %rbx,%rdx
  je     L9
  mov    %rax,0x0(%rbp)
  mov    $0x0,%edx
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    $0x5,%edx
  jmp    L24
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t opdi_str_to_uint16(const char *str, uint16_t *result) {
  char *p;
  long res;
  errno = 0;
  res = strtol(str, &p, 10);
  if (errno != 0 || *p != 0 || p == str)
    return 5;
  *result = (uint16_t)res;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<opdi_str_to_uint16>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    D6(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%r12)
  call   <strtol@plt>
  cmpq   $0x0,(%r12)
  mov    $0x5,%r8d
  jne    L31
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L17
  cmp    %rbx,%rdx
  je     L17
  mov    %rax,0x0(%rbp)
  xor    %r8d,%r8d
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  mov    $0x5,%r8d
  jmp    L31
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t opdi_str_to_uint16(const char *str, uint16_t *result) {
  char *p;
  long res;
  errno = 0;
  res = strtol(str, &p, 10);
  if (errno != 0 || *p != 0 || p == str)
    return 5;
  *result = (uint16_t)res;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<opdi_str_to_uint16>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    D6(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%r12)
  call   <strtol@plt>
  cmpq   $0x0,(%r12)
  mov    $0x5,%r8d
  jne    L45
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L11
  cmp    %rbx,%rdx
  je     L11
  mov    %rax,0x0(%rbp)
  xor    %r8d,%r8d
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x5,%r8d
  jmp    L45
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t opdi_str_to_uint16(const char *str, uint16_t *result) {
  char *p;
  long res;
  errno = 0;
  res = strtol(str, &p, 10);
  if (errno != 0 || *p != 0 || p == str)
    return 5;
  *result = (uint16_t)res;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sendDataAboutAttacks>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x478,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x468(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%r14
  imul   $0x66666667,%r14,%r14
  sar    $0x22,%r14
  cltd
  sub    %edx,%r14d
  lea    (%r14,%r14,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%ebx
  lea    0x80(%rsp),%rdi
  mov    %ebx,%edx
  lea    D0(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  test   %ebx,%ebx
  jle    L5
  mov    %ebx,%r14d
  mov    $0x0,%r13d
  lea    D12(%rip),%r15
L23:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  movslq %r12d,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %r12d,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%r12d
  movslq %ebp,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %ebp,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%ebp
  lea    0x1(%rbp),%ecx
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ebx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  lea    0x1(%rbx),%edx
  lea    0x10(%rsp),%rbx
  lea    0x1(%rax),%r9d
  lea    0x1(%r12),%r8d
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0x80(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strcat@plt>
  add    $0x1,%r13d
  cmp    %r14d,%r13d
  jne    L23
L5:
  lea    0x80(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    0xc(%rsp),%edi
  call   <send@plt>
  mov    0x468(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x478,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string

tool: D0: A %i

tool: D12:  %i_%i_%i_%i

assistant: ```c
void sendDataAboutAttacks(void *socket_desc) {
  int sock = *(int *)socket_desc;
  int i = 0;
  char message[1000];
  int count = rand() % 10 + 1;
  sprintf(message, "A %i", count);
  for (i = 0; i < count; i++) {
    int pid = rand() % 10 + 1;
    int amount = rand() % 100 + 1;
    int from = rand() % 10 + 1;
    int time = rand() % 100 + 1;
    char attack[100];
    sprintf(attack, " %i_%i_%i_%i", pid, amount, from, time);
    strcat(message, attack);
  }
  send(sock, message, strlen(message), 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sendDataAboutAttacks>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x478,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x468(%rsp)
  mov    (%rdi),%eax
  lea    0x80(%rsp),%r13
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  lea    D1(%rip),%rsi
  mov    %r13,%rdi
  movslq %eax,%rbp
  cltd
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%ebx
  mov    %eax,0x8(%rsp)
  xor    %eax,%eax
  mov    %ebx,%edx
  call   <sprintf@plt>
  test   %ebx,%ebx
  jle    L14
  xor    %r15d,%r15d
  lea    0x10(%rsp),%r12
  lea    D15(%rip),%r14
  nopl   (%rax)
L1:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%edx
  mov    %eax,%esi
  cltq
  imul   $0x51eb851f,%rax,%rax
  mov    %esi,%edi
  sar    $0x1f,%edi
  sar    $0x25,%rax
  sub    %edi,%eax
  imul   $0x64,%eax,%eax
  sub    %eax,%esi
  movslq 0x4(%rsp),%rax
  lea    0x1(%rsi),%r9d
  mov    %r14,%rsi
  mov    %rax,%rcx
  imul   $0x66666667,%rax,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sar    $0x22,%rax
  sub    %edi,%eax
  mov    %ebp,%edi
  lea    (%rax,%rax,4),%eax
  sar    $0x1f,%edi
  add    %eax,%eax
  sub    %eax,%ecx
  movslq %ebp,%rax
  imul   $0x51eb851f,%rax,%rax
  lea    0x1(%rcx),%r8d
  sar    $0x25,%rax
  sub    %edi,%eax
  mov    %r12,%rdi
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  lea    0x1(%rdx),%r11d
  mov    %ebx,%edx
  sar    $0x1f,%edx
  mov    %r11d,%ecx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  xor    %eax,%eax
  lea    0x1(%rbx),%edx
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %r15d,%eax
  add    $0x1,%r15d
  cmp    %eax,0x8(%rsp)
  jne    L1
L14:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    0xc(%rsp),%edi
  xor    %ecx,%ecx
  mov    %r13,%rsi
  mov    %eax,%edx
  call   <send@plt>
  mov    0x468(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x478,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string

tool: D1: A %i

tool: D15:  %i_%i_%i_%i

assistant: ```c
void sendDataAboutAttacks(void *socket_desc) {
  int sock = *(int *)socket_desc;
  int i = 0;
  char message[1000];
  int count = rand() % 10 + 1;
  sprintf(message, "A %i", count);
  for (i = 0; i < count; i++) {
    int pid = rand() % 10 + 1;
    int amount = rand() % 100 + 1;
    int from = rand() % 10 + 1;
    int time = rand() % 100 + 1;
    char attack[100];
    sprintf(attack, " %i_%i_%i_%i", pid, amount, from, time);
    strcat(message, attack);
  }
  send(sock, message, strlen(message), 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sendDataAboutAttacks>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x478,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x468(%rsp)
  mov    (%rdi),%eax
  lea    0x80(%rsp),%r13
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  lea    D17(%rip),%rsi
  mov    %r13,%rdi
  movslq %eax,%rbp
  cltd
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%ebx
  mov    %eax,0x8(%rsp)
  xor    %eax,%eax
  mov    %ebx,%edx
  call   <sprintf@plt>
  test   %ebx,%ebx
  jle    L16
  xor    %r15d,%r15d
  lea    0x10(%rsp),%r12
  lea    D2(%rip),%r14
  nopl   (%rax)
L21:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%edx
  mov    %eax,%esi
  cltq
  imul   $0x51eb851f,%rax,%rax
  mov    %esi,%edi
  sar    $0x1f,%edi
  sar    $0x25,%rax
  sub    %edi,%eax
  imul   $0x64,%eax,%eax
  sub    %eax,%esi
  movslq 0x4(%rsp),%rax
  lea    0x1(%rsi),%r9d
  mov    %r14,%rsi
  mov    %rax,%rcx
  imul   $0x66666667,%rax,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sar    $0x22,%rax
  sub    %edi,%eax
  mov    %ebp,%edi
  lea    (%rax,%rax,4),%eax
  sar    $0x1f,%edi
  add    %eax,%eax
  sub    %eax,%ecx
  movslq %ebp,%rax
  imul   $0x51eb851f,%rax,%rax
  lea    0x1(%rcx),%r8d
  sar    $0x25,%rax
  sub    %edi,%eax
  mov    %r12,%rdi
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  lea    0x1(%rdx),%r11d
  mov    %ebx,%edx
  sar    $0x1f,%edx
  mov    %r11d,%ecx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  xor    %eax,%eax
  lea    0x1(%rbx),%edx
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %r15d,%eax
  add    $0x1,%r15d
  cmp    %eax,0x8(%rsp)
  jne    L21
L16:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    0xc(%rsp),%edi
  xor    %ecx,%ecx
  mov    %r13,%rsi
  mov    %eax,%edx
  call   <send@plt>
  mov    0x468(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x478,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D17: A %i

tool: D2:  %i_%i_%i_%i

assistant: ```c
void sendDataAboutAttacks(void *socket_desc) {
  int sock = *(int *)socket_desc;
  int i = 0;
  char message[1000];
  int count = rand() % 10 + 1;
  sprintf(message, "A %i", count);
  for (i = 0; i < count; i++) {
    int pid = rand() % 10 + 1;
    int amount = rand() % 100 + 1;
    int from = rand() % 10 + 1;
    int time = rand() % 100 + 1;
    char attack[100];
    sprintf(attack, " %i_%i_%i_%i", pid, amount, from, time);
    strcat(message, attack);
  }
  send(sock, message, strlen(message), 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x34(%rbp)
  movl   $0xa,-0x30(%rbp)
  movl   $0x14,-0x2c(%rbp)
  movl   $0x20,-0x28(%rbp)
  movl   $0x2a,-0x24(%rbp)
  movl   $0x10,-0x20(%rbp)
  movl   $0x67657247,-0xf(%rbp)
  movw   $0x726f,-0xb(%rbp)
  movb   $0x79,-0x9(%rbp)
  lea    -0xf(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <str_arr@plt>
  mov    $0xa,%edi
  call   <printChar@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L18
L5:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <printInt@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  addl   $0x1,-0x34(%rbp)
L18:
  cmpl   $0x4,-0x34(%rbp)
  jle    L5
  lea    -0x30(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <print_arr@plt>
  mov    $0xa,%edi
  call   <printChar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void main() {
  int i = 5;
  int array[5] = {10, 20, 32, 42, 16};
  char name[7] = "Gregory";
  str_arr(name, 7);
  printChar('\n');
  for (i = 0; i < 5; i++) {
    printInt(array[i]);
    printChar(' ');
  }
  print_arr(array, 5);
  printChar('\n');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xa,(%rsp)
  movl   $0x14,0x4(%rsp)
  movl   $0x20,0x8(%rsp)
  movl   $0x2a,0xc(%rsp)
  movl   $0x10,0x10(%rsp)
  movl   $0x67657247,0x21(%rsp)
  movw   $0x726f,0x25(%rsp)
  movb   $0x79,0x27(%rsp)
  lea    0x21(%rsp),%rdi
  mov    $0x7,%esi
  call   <str_arr@plt>
  mov    $0xa,%edi
  call   <printChar@plt>
  mov    %rsp,%rbx
  lea    0x14(%rsp),%rbp
L10:
  mov    (%rbx),%edi
  call   <printInt@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L10
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <print_arr@plt>
  mov    $0xa,%edi
  call   <printChar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  int i = 5;
  int array[5] = {10, 20, 32, 42, 16};
  char name[7] = "Gregory";
  str_arr(name, 7);
  printChar('\n');
  for (i = 0; i < 5; i++) {
    printInt(array[i]);
    printChar(' ');
  }
  print_arr(array, 5);
  printChar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x140000000a,%rax
  lea    0x21(%rsp),%rdi
  movb   $0x79,0x27(%rsp)
  mov    %rsp,%r12
  movl   $0x10,0x10(%rsp)
  mov    %r12,%rbx
  lea    0x14(%rsp),%rbp
  movl   $0x67657247,0x21(%rsp)
  mov    %rax,(%rsp)
  movabs $0x2a00000020,%rax
  mov    %rax,0x8(%rsp)
  mov    $0x726f,%eax
  mov    %ax,0x25(%rsp)
  call   <str_arr@plt>
  mov    $0xa,%edi
  call   <printChar@plt>
L1:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <printInt@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  cmp    %rbp,%rbx
  jne    L1
  mov    %r12,%rdi
  mov    $0x5,%esi
  call   <print_arr@plt>
  mov    $0xa,%edi
  call   <printChar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  int i = 5;
  int array[5] = {10, 20, 32, 42, 16};
  char name[7] = "Gregory";
  str_arr(name, 7);
  printChar('\n');
  for (i = 0; i < 5; i++) {
    printInt(array[i]);
    printChar(' ');
  }
  print_arr(array, 5);
  printChar('\n');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x21(%rsp),%rdi
  mov    $0x726f,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  mov    %r12,%rbx
  lea    0x14(%rsp),%rbp
  movl   $0x10,0x10(%rsp)
  movl   $0x67657247,0x21(%rsp)
  mov    %ax,0x25(%rsp)
  movb   $0x79,0x27(%rsp)
  call   <str_arr@plt>
  mov    $0xa,%edi
  call   <printChar@plt>
L7:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <printInt@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  cmp    %rbp,%rbx
  jne    L7
  mov    %r12,%rdi
  mov    $0x5,%esi
  call   <print_arr@plt>
  mov    $0xa,%edi
  call   <printChar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: byte[16]

tool: {"D0": [0x0a,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x20,0x00,0x00,0x00,0x2a,0x00,0x00,0x00]}

assistant: ```c
void main() {
  int i = 5;
  int array[5] = {10, 20, 32, 42, 16};
  char name[7] = "Gregory";
  str_arr(name, 7);
  printChar('\n');
  for (i = 0; i < 5; i++) {
    printInt(array[i]);
    printChar(' ');
  }
  print_arr(array, 5);
  printChar('\n');
}
```