ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bsdar_warnc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <bsdar_vwarnc@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void bsdar_warnc(struct bsdar *bsdar, int code, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  bsdar_vwarnc(bsdar, code, fmt, ap);
  va_end(ap);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bsdar_warnc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <bsdar_vwarnc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bsdar_warnc(struct bsdar *bsdar, int code, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  bsdar_vwarnc(bsdar, code, fmt, ap);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bsdar_warnc>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <bsdar_vwarnc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void bsdar_warnc(struct bsdar *bsdar, int code, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  bsdar_vwarnc(bsdar, code, fmt, ap);
  va_end(ap);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bsdar_warnc>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <bsdar_vwarnc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void bsdar_warnc(struct bsdar *bsdar, int code, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  bsdar_vwarnc(bsdar, code, fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x2f,-0x410(%rbp)
  movq   $0x0,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x430(%rbp),%rax
  mov    (%rax),%rcx
  lea    -0x410(%rbp),%rax
  mov    $0x3fe,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  lea    -0x414(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x414(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L30
L39:
  mov    $0x0,%eax
  call   <abort@plt>
L30:
  lea    -0x414(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L11
  mov    -0x414(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  jne    L10
L11:
  mov    $0x0,%eax
  call   <abort@plt>
L10:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D9: .

tool: D16: pass


assistant: ```c
int main(int argc, char *argv[]) {
  char path[1024] = "/";
  struct stat buf;
  strncat(path, argv[0], sizeof(path) - 2);
  if (lstat(".", &buf) != 0 || !S_ISDIR(buf.st_mode))
    abort();
  if (lstat(path, &buf) != 0 || !S_ISREG(buf.st_mode))
    abort();
  printf("pass\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  movq   $0x2f,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x20(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x10(%rsp),%rdi
  mov    $0x3fe,%edx
  mov    (%rsi),%rsi
  call   <strncat@plt>
  lea    0xc(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L11
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L15
L11:
  mov    $0x0,%eax
  call   <abort@plt>
L15:
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L19
  mov    0xc(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  jne    L8
L19:
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x428,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D15: .

tool: D4: pass


assistant: ```c
int main(int argc, char *argv[]) {
  char path[1024] = "/";
  struct stat buf;
  strncat(path, argv[0], sizeof(path) - 2);
  if (lstat(".", &buf) != 0 || !S_ISDIR(buf.st_mode))
    abort();
  if (lstat(path, &buf) != 0 || !S_ISREG(buf.st_mode))
    abort();
  printf("pass\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7e,%ecx
  mov    $0x3fe,%edx
  push   %rbp
  sub    $0x428,%rsp
  mov    (%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%rbp
  movq   $0x2f,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0xc(%rsp),%r12
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    %r12,%rsi
  lea    D4(%rip),%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L13
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L13
L48:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L30
  mov    0xc(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  je     L30
L62:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x428,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L62
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L48
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string
name: retrieve_data
arguments: data_tag: D18
datatype: string

tool: D4: .

tool: D18: pass


assistant: ```c
int main(int argc, char *argv[]) {
  char path[1024] = "/";
  struct stat buf;
  strncat(path, argv[0], sizeof(path) - 2);
  if (lstat(".", &buf) != 0 || !S_ISDIR(buf.st_mode))
    abort();
  if (lstat(path, &buf) != 0 || !S_ISREG(buf.st_mode))
    abort();
  printf("pass\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7e,%ecx
  mov    $0x3fe,%edx
  push   %rbp
  sub    $0x428,%rsp
  mov    (%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%rbp
  movq   $0x2f,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0xc(%rsp),%r12
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L48
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L48
L33:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L0
  mov    0xc(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  je     L0
L67:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x428,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L67
  nopl   0x0(%rax)
L48:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L33
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: string

tool: D0: .

tool: D17: pass


assistant: ```c
int main(int argc, char *argv[]) {
  char path[1024] = "/";
  struct stat buf;
  strncat(path, argv[0], sizeof(path) - 2);
  if (lstat(".", &buf) != 0 || !S_ISDIR(buf.st_mode))
    abort();
  if (lstat(path, &buf) != 0 || !S_ISREG(buf.st_mode))
    abort();
  printf("pass\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copyKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L15:
  movzbl -0x24(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copyKey(const unsigned char *from, unsigned char *to, const unsigned char keyLen) {
  int i;
  for (i = 0; i < keyLen; i++) {
    to[i] = from[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copyKey>:
  endbr64
  and    $0xff,%edx
  je     L4
  mov    $0x0,%eax
L6:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L6
L4:
  ret
```

assistant: ```c
void copyKey(const unsigned char *from, unsigned char *to, const unsigned char keyLen) {
  int i;
  for (i = 0; i < keyLen; i++) {
    to[i] = from[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copyKey>:
  endbr64
  and    $0xff,%edx
  je     L19
  xor    %eax,%eax
  xchg   %ax,%ax
L10:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L10
L19:
  ret
```

assistant: ```c
void copyKey(const unsigned char *from, unsigned char *to, const unsigned char keyLen) {
  int i;
  for (i = 0; i < keyLen; i++) {
    to[i] = from[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vp_decode_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L19
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x1c,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x15,%eax
  and    $0xfe00000,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0xe,%eax
  and    $0x1fc000,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x7,%eax
  and    $0x3f80,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x7f,%eax
  add    %edx,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int vp_decode_size(const char *buf) {
  if (buf == NULL)
    return 0;
  return ((unsigned int)(buf[0] & 0x7f) << 28) + ((unsigned int)(buf[1] & 0x7f) << 21) + ((unsigned int)(buf[2] & 0x7f) << 14) + ((unsigned int)(buf[3] & 0x7f) << 7) + ((unsigned int)(buf[4] & 0x7f));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vp_decode_size>:
  endbr64
  test   %rdi,%rdi
  je     L2
  movsbl (%rdi),%eax
  shl    $0x1c,%eax
  movzbl 0x4(%rdi),%edx
  and    $0x7f,%edx
  add    %edx,%eax
  movsbl 0x1(%rdi),%edx
  shl    $0x15,%edx
  and    $0xfe00000,%edx
  add    %edx,%eax
  movsbl 0x2(%rdi),%edx
  shl    $0xe,%edx
  and    $0x1fc000,%edx
  add    %edx,%eax
  movsbl 0x3(%rdi),%edx
  shl    $0x7,%edx
  and    $0x3f80,%edx
  add    %edx,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int vp_decode_size(const char *buf) {
  if (buf == NULL)
    return 0;
  return ((unsigned int)(buf[0] & 0x7f) << 28) + ((unsigned int)(buf[1] & 0x7f) << 21) + ((unsigned int)(buf[2] & 0x7f) << 14) + ((unsigned int)(buf[3] & 0x7f) << 7) + ((unsigned int)(buf[4] & 0x7f));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vp_decode_size>:
  endbr64
  test   %rdi,%rdi
  je     L4
  movsbl (%rdi),%eax
  movzbl 0x4(%rdi),%edx
  shl    $0x1c,%eax
  and    $0x7f,%edx
  add    %edx,%eax
  movsbl 0x1(%rdi),%edx
  shl    $0x15,%edx
  and    $0xfe00000,%edx
  add    %edx,%eax
  movsbl 0x2(%rdi),%edx
  shl    $0xe,%edx
  and    $0x1fc000,%edx
  add    %edx,%eax
  movsbl 0x3(%rdi),%edx
  shl    $0x7,%edx
  and    $0x3f80,%edx
  add    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int vp_decode_size(const char *buf) {
  if (buf == NULL)
    return 0;
  return ((unsigned int)(buf[0] & 0x7f) << 28) + ((unsigned int)(buf[1] & 0x7f) << 21) + ((unsigned int)(buf[2] & 0x7f) << 14) + ((unsigned int)(buf[3] & 0x7f) << 7) + ((unsigned int)(buf[4] & 0x7f));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<vp_decode_size>:
  endbr64
  test   %rdi,%rdi
  je     L8
  movsbl (%rdi),%eax
  movzbl 0x4(%rdi),%edx
  shl    $0x1c,%eax
  and    $0x7f,%edx
  add    %edx,%eax
  movsbl 0x1(%rdi),%edx
  shl    $0x15,%edx
  and    $0xfe00000,%edx
  add    %edx,%eax
  movsbl 0x2(%rdi),%edx
  shl    $0xe,%edx
  and    $0x1fc000,%edx
  add    %edx,%eax
  movsbl 0x3(%rdi),%edx
  shl    $0x7,%edx
  and    $0x3f80,%edx
  add    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int vp_decode_size(const char *buf) {
  if (buf == NULL)
    return 0;
  return ((unsigned int)(buf[0] & 0x7f) << 28) + ((unsigned int)(buf[1] & 0x7f) << 21) + ((unsigned int)(buf[2] & 0x7f) << 14) + ((unsigned int)(buf[3] & 0x7f) << 7) + ((unsigned int)(buf[4] & 0x7f));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L17
L12:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L35
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L5
L35:
  addl   $0x1,-0x24(%rbp)
L17:
  cmpl   $0x5,-0x24(%rbp)
  jle    L12
  mov    -0x40(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%r14
  mov    -0x40(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rbx
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %r14,%r8
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <loadmap@plt>
  mov    $0x0,%eax
L5:
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
data_type: string
name: read_data
arguments: data_label: D19
data_type: string

tool: D12: convertidor de csv a mapa binario


tool: D19: usage:csvconv [WHITE|COMMA] nombre_archivo_a_convertir nro_columnas nro_filas nombre_archivo_nuevo


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  printf("convertidor de csv a mapa binario\n");
  for (i = 1; i < 6; i++) {
    if (argv[i] == NULL) {
      printf("usage:csvconv [WHITE|COMMA] nombre_archivo_a_convertir nro_columnas nro_filas nombre_archivo_nuevo\n");
      return 1;
    }
  }
  loadmap(atoi(argv[1]), argv[2], atoi(argv[3]), atoi(argv[4]), argv[5]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rbx),%rax
  lea    0x30(%rbx),%rdx
L1:
  cmpq   $0x0,(%rax)
  je     L11
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L1
  mov    0x28(%rbx),%r14
  mov    0x20(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x10(%rbx),%r13
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  mov    %r14,%r8
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %r13,%rsi
  call   <loadmap@plt>
  mov    $0x0,%eax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L10
```

tool_calls: name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D12
type_infered: string

tool: D14: convertidor de csv a mapa binario


tool: D12: usage:csvconv [WHITE|COMMA] nombre_archivo_a_convertir nro_columnas nro_filas nombre_archivo_nuevo


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  printf("convertidor de csv a mapa binario\n");
  for (i = 1; i < 6; i++) {
    if (argv[i] == NULL) {
      printf("usage:csvconv [WHITE|COMMA] nombre_archivo_a_convertir nro_columnas nro_filas nombre_archivo_nuevo\n");
      return 1;
    }
  }
  loadmap(atoi(argv[1]), argv[2], atoi(argv[3]), atoi(argv[4]), argv[5]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <printf@plt>
  lea    0x8(%rbx),%rax
  lea    0x30(%rbx),%rdx
L16:
  cmpq   $0x0,(%rax)
  je     L21
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L16
  mov    0x20(%rbx),%rdi
  mov    0x28(%rbx),%r14
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%r13d
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  mov    0x10(%rbx),%rbp
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %r14,%r8
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <loadmap@plt>
  xor    %eax,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L13
```

tool_calls: name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string

tool: D13: convertidor de csv a mapa binario


tool: D17: usage:csvconv [WHITE|COMMA] nombre_archivo_a_convertir nro_columnas nro_filas nombre_archivo_nuevo


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  printf("convertidor de csv a mapa binario\n");
  for (i = 1; i < 6; i++) {
    if (argv[i] == NULL) {
      printf("usage:csvconv [WHITE|COMMA] nombre_archivo_a_convertir nro_columnas nro_filas nombre_archivo_nuevo\n");
      return 1;
    }
  }
  loadmap(atoi(argv[1]), argv[2], atoi(argv[3]), atoi(argv[4]), argv[5]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <printf@plt>
  cmpq   $0x0,0x8(%rbx)
  je     L40
  cmpq   $0x0,0x10(%rbx)
  je     L40
  cmpq   $0x0,0x18(%rbx)
  je     L40
  mov    0x20(%rbx),%rdi
  test   %rdi,%rdi
  je     L40
  mov    0x28(%rbx),%rbp
  test   %rbp,%rbp
  je     L40
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%r13d
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  mov    0x10(%rbx),%r14
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %rbp,%r8
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %eax,%edi
  mov    %r14,%rsi
  call   <loadmap@plt>
  xor    %eax,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D12
type: string

tool: D7: convertidor de csv a mapa binario


tool: D12: usage:csvconv [WHITE|COMMA] nombre_archivo_a_convertir nro_columnas nro_filas nombre_archivo_nuevo


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  printf("convertidor de csv a mapa binario\n");
  for (i = 1; i < 6; i++) {
    if (argv[i] == NULL) {
      printf("usage:csvconv [WHITE|COMMA] nombre_archivo_a_convertir nro_columnas nro_filas nombre_archivo_nuevo\n");
      return 1;
    }
  }
  loadmap(atoi(argv[1]), argv[2], atoi(argv[3]), atoi(argv[4]), argv[5]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<rmbinary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L52:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jle    L31
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7f,%al
  jne    L28
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L28
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x5,%eax
  jle    L26
  mov    -0x8(%rbp),%rax
  movb   $0x2e,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x2e,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x2e,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movb   $0xa,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movb   $0x0,(%rax)
  jmp    L8
L26:
  mov    -0x8(%rbp),%rax
  movb   $0xa,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L8
L28:
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
L8:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rmbinary(char *line) {
  char *pt;
  for (pt = line; *pt; ++pt) {
    if ((*pt < ' ' || *pt >= 0x7f) && *pt != '\n') {
      if (strlen(pt) > 5) {
        pt[0] = '.';
        pt[1] = '.';
        pt[2] = '.';
        pt[3] = '\n';
        pt[4] = '\0';
      } else {
        pt[0] = '\n';
        pt[1] = '\0';
      }
      break;
    }
  }
  return (line);
}
```