ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fail_func>:
  endbr64
  movl   $0x0,(%rsi)
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L57
  xor    %edx,%edx
  mov    $0x1,%r9d
  mov    $0x1,%ecx
  jmp    L15
  nopl   0x0(%rax)
L14:
  test   %edx,%edx
  jle    L39
  mov    -0x4(%rsi,%r8,4),%edx
L27:
  movslq %r9d,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L57
L15:
  movslq %edx,%r8
  cmp    %al,(%rdi,%r8,1)
  jne    L14
  add    $0x1,%edx
  add    $0x1,%r9d
  mov    %edx,(%rsi,%rcx,4)
  movslq %r9d,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  jne    L15
L57:
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  movl   $0x0,(%rsi,%rcx,4)
  add    $0x1,%r9d
  jmp    L27
```

assistant: ```c
void fail_func(const char *p, int *next) {
  next[0] = 0;
  for (int i = 1, j = 0; *(p + i);)
    if (p[j] == p[i])
      next[i++] = ++j;
    else {
      if (j > 0)
        j = next[j - 1];
      else {
        next[i++] = 0;
      }
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fail_func>:
  endbr64
  movl   $0x0,(%rsi)
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L59
  xor    %edx,%edx
  mov    $0x1,%r9d
  mov    $0x1,%ecx
  jmp    L7
  nopl   0x0(%rax)
L65:
  test   %edx,%edx
  jle    L27
  mov    -0x4(%rsi,%r8,4),%edx
L41:
  movslq %r9d,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L59
L7:
  movslq %edx,%r8
  cmp    %al,(%rdi,%r8,1)
  jne    L65
  add    $0x1,%edx
  add    $0x1,%r9d
  mov    %edx,(%rsi,%rcx,4)
  movslq %r9d,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  jne    L7
L59:
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  movl   $0x0,(%rsi,%rcx,4)
  add    $0x1,%r9d
  jmp    L41
```

assistant: ```c
void fail_func(const char *p, int *next) {
  next[0] = 0;
  for (int i = 1, j = 0; *(p + i);)
    if (p[j] == p[i])
      next[i++] = ++j;
    else {
      if (j > 0)
        j = next[j - 1];
      else {
        next[i++] = 0;
      }
    }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L85
L54:
  cmpl   $0x0,-0xc(%rbp)
  jle    L16
  cmpl   $0x1,-0x8(%rbp)
  jle    L16
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L87
L16:
  cmpl   $0x0,-0xc(%rbp)
  jle    L23
  cmpl   $0xffffffff,-0x8(%rbp)
  jge    L23
  mov    -0x8(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L87
L23:
  movl   $0x0,-0x10(%rbp)
L87:
  addl   $0x1,-0x14(%rbp)
L85:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L75
  cmpl   $0x0,-0x10(%rbp)
  jg     L54
L75:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c, flag, x, y, z;
  c = 0;
  flag = 1;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while ((y < z) && (flag > 0)) {
    if ((y > 0) && (x > 1)) {
      y = x * y;
    } else {
      if ((y > 0) && (x < -1)) {
        y = -x * y;
      } else {
        flag = 0;
      }
    }
    c = c + 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    %eax,%ebx
  jge    L40
  mov    %ebp,%ecx
  neg    %ecx
  jmp    L25
L37:
  imul   %ebp,%ebx
L48:
  cmp    %eax,%ebx
  jge    L40
L25:
  test   %ebx,%ebx
  setg   %dl
  cmp    $0x1,%ebp
  jle    L58
  test   %dl,%dl
  jne    L37
L58:
  cmp    $0xffffffff,%ebp
  jge    L40
  test   %dl,%dl
  je     L40
  imul   %ecx,%ebx
  jmp    L48
L40:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c, flag, x, y, z;
  c = 0;
  flag = 1;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while ((y < z) && (flag > 0)) {
    if ((y > 0) && (x > 1)) {
      y = x * y;
    } else {
      if ((y > 0) && (x < -1)) {
        y = -x * y;
      } else {
        flag = 0;
      }
    }
    c = c + 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c, flag, x, y, z;
  c = 0;
  flag = 1;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while ((y < z) && (flag > 0)) {
    if ((y > 0) && (x > 1)) {
      y = x * y;
    } else {
      if ((y > 0) && (x < -1)) {
        y = -x * y;
      } else {
        flag = 0;
      }
    }
    c = c + 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c, flag, x, y, z;
  c = 0;
  flag = 1;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while ((y < z) && (flag > 0)) {
    if ((y > 0) && (x > 1)) {
      y = x * y;
    } else {
      if ((y > 0) && (x < -1)) {
        y = -x * y;
      } else {
        flag = 0;
      }
    }
    c = c + 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arrotondamento>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x18(%rbp)
  mov    %eax,%eax
  test   %rax,%rax
  js     L36
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L23
L36:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L23:
  movss  %xmm0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x18(%rbp)
  mov    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L18
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  D7(%rip),%xmm0
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L26
L18:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int arrotondamento(int subtotale, unsigned int numero_elementi) {
  int media_aritmetica;
  float new_subtotal;
  new_subtotal = (subtotale / numero_elementi);
  subtotale = (subtotale % numero_elementi);
  if (subtotale >= 0.5)
    media_aritmetica = ((new_subtotal -= subtotale) + 1);
  else
    media_aritmetica = (new_subtotal -= subtotale);
  return (media_aritmetica);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arrotondamento>:
  endbr64
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  test   %edx,%edx
  jle    L7
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  subss  %xmm1,%xmm0
  addss  D7(%rip),%xmm0
  cvttss2si %xmm0,%eax
  ret
L7:
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  subss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int arrotondamento(int subtotale, unsigned int numero_elementi) {
  int media_aritmetica;
  float new_subtotal;
  new_subtotal = (subtotale / numero_elementi);
  subtotale = (subtotale % numero_elementi);
  if (subtotale >= 0.5)
    media_aritmetica = ((new_subtotal -= subtotale) + 1);
  else
    media_aritmetica = (new_subtotal -= subtotale);
  return (media_aritmetica);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arrotondamento>:
  endbr64
  mov    %edi,%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  xor    %edx,%edx
  div    %esi
  cvtsi2ss %rax,%xmm0
  cvtsi2ss %edx,%xmm1
  subss  %xmm1,%xmm0
  test   %edx,%edx
  jle    L9
  addss  D9(%rip),%xmm0
  cvttss2si %xmm0,%eax
  ret
L9:
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int arrotondamento(int subtotale, unsigned int numero_elementi) {
  int media_aritmetica;
  float new_subtotal;
  new_subtotal = (subtotale / numero_elementi);
  subtotale = (subtotale % numero_elementi);
  if (subtotale >= 0.5)
    media_aritmetica = ((new_subtotal -= subtotale) + 1);
  else
    media_aritmetica = (new_subtotal -= subtotale);
  return (media_aritmetica);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arrotondamento>:
  endbr64
  mov    %edi,%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  xor    %edx,%edx
  div    %esi
  cvtsi2ss %rax,%xmm0
  cvtsi2ss %edx,%xmm1
  subss  %xmm1,%xmm0
  test   %edx,%edx
  jle    L6
  addss  D0(%rip),%xmm0
  cvttss2si %xmm0,%eax
  ret
L6:
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: byte[4]

tool: {"D0": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int arrotondamento(int subtotale, unsigned int numero_elementi) {
  int media_aritmetica;
  float new_subtotal;
  new_subtotal = (subtotale / numero_elementi);
  subtotale = (subtotale % numero_elementi);
  if (subtotale >= 0.5)
    media_aritmetica = ((new_subtotal -= subtotale) + 1);
  else
    media_aritmetica = (new_subtotal -= subtotale);
  return (media_aritmetica);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mmmul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  jmp    L61
L54:
  movl   $0x0,-0x60(%rbp)
  jmp    L15
L66:
  mov    -0x60(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x50(%rbp,%rax,8)
  addl   $0x1,-0x60(%rbp)
L15:
  cmpl   $0x2,-0x60(%rbp)
  jle    L66
  addl   $0x1,-0x64(%rbp)
L61:
  cmpl   $0x2,-0x64(%rbp)
  jle    L54
  movl   $0x0,-0x5c(%rbp)
  jmp    L22
L64:
  movl   $0x0,-0x58(%rbp)
  jmp    L109
L39:
  movl   $0x0,-0x54(%rbp)
  jmp    L94
L73:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movsd  -0x50(%rbp,%rax,8),%xmm1
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x54(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm2
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x80(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x58(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movsd  %xmm0,-0x50(%rbp,%rax,8)
  addl   $0x1,-0x54(%rbp)
L94:
  cmpl   $0x2,-0x54(%rbp)
  jle    L73
  addl   $0x1,-0x58(%rbp)
L109:
  cmpl   $0x2,-0x58(%rbp)
  jle    L39
  addl   $0x1,-0x5c(%rbp)
L22:
  cmpl   $0x2,-0x5c(%rbp)
  jle    L64
  mov    -0x88(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mcopy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void mmmul(double A[3][3], double B[3][3], double C[3][3]) {
  double T[3][3];
  for (int i = 0; i < 3; ++i) {
    for (int j = 0; j < 3; ++j) {
      T[i][j] = 0.0;
    }
  }
  for (int i = 0; i < 3; ++i) {
    for (int j = 0; j < 3; ++j) {
      for (int k = 0; k < 3; ++k) {
        T[i][j] += A[i][k] * B[k][j];
      }
    }
  }
  mcopy(T, C);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mmmul>:
  endbr64
  sub    $0x58,%rsp
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  mov    %rsp,%r8
  mov    %rdi,%rcx
  add    $0x48,%rdi
  lea    0x18(%rsi),%rsi
L16:
  mov    %r9,%rax
  movsd  (%rcx),%xmm4
  movsd  0x8(%rcx),%xmm3
  movsd  0x10(%rcx),%xmm2
  mov    %r8,%rdx
L1:
  movapd %xmm4,%xmm0
  mulsd  (%rax),%xmm0
  addsd  (%rdx),%xmm0
  movapd %xmm3,%xmm1
  mulsd  0x18(%rax),%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  0x30(%rax),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  add    $0x8,%rax
  cmp    %rax,%rsi
  jne    L1
  add    $0x18,%r8
  add    $0x18,%rcx
  cmp    %rdi,%rcx
  jne    L16
  mov    %rsp,%rdi
  mov    %r10,%rsi
  call   <mcopy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x58,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mmmul(double A[3][3], double B[3][3], double C[3][3]) {
  double T[3][3];
  for (int i = 0; i < 3; ++i) {
    for (int j = 0; j < 3; ++j) {
      T[i][j] = 0.0;
    }
  }
  for (int i = 0; i < 3; ++i) {
    for (int j = 0; j < 3; ++j) {
      for (int k = 0; k < 3; ++k) {
        T[i][j] += A[i][k] * B[k][j];
      }
    }
  }
  mcopy(T, C);
}
```
user: What is the c source code of the assembly code below:

```asm
<mmmul>:
  endbr64
  push   %rbp
  mov    %rsi,%r10
  lea    0x48(%rdi),%r11
  mov    %rdx,%rsi
  pxor   %xmm1,%xmm1
  lea    0x18(%r10),%r9
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbp
  movq   $0x0,0x8(%rsp)
  mov    %rbp,%r8
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
L10:
  movsd  (%rdi),%xmm4
  movsd  0x8(%rdi),%xmm3
  mov    %r10,%rax
  mov    %r8,%rcx
  movsd  0x10(%rdi),%xmm2
L9:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  add    $0x8,%rcx
  mulsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x10(%rax),%xmm1
  mulsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x28(%rax),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rcx)
  cmp    %r9,%rax
  je     L15
  movsd  (%rcx),%xmm1
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x18,%rdi
  add    $0x18,%r8
  cmp    %rdi,%r11
  je     L45
  movsd  (%r8),%xmm1
  jmp    L10
  nopl   0x0(%rax)
L45:
  mov    %rbp,%rdi
  call   <mcopy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x50,%rsp
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mmmul(double A[3][3], double B[3][3], double C[3][3]) {
  double T[3][3];
  for (int i = 0; i < 3; ++i) {
    for (int j = 0; j < 3; ++j) {
      T[i][j] = 0.0;
    }
  }
  for (int i = 0; i < 3; ++i) {
    for (int j = 0; j < 3; ++j) {
      for (int k = 0; k < 3; ++k) {
        T[i][j] += A[i][k] * B[k][j];
      }
    }
  }
  mcopy(T, C);
}
```
user: What is the c source code of the assembly code below?

```asm
<mmmul>:
  endbr64
  mov    %rsi,%rax
  sub    $0x58,%rsp
  movupd 0x10(%rdi),%xmm2
  pxor   %xmm5,%xmm5
  movupd (%rax),%xmm6
  movupd 0x10(%rax),%xmm0
  mov    %rdx,%rsi
  movupd 0x20(%rax),%xmm4
  movlpd (%rdi),%xmm2
  movupd (%rdi),%xmm9
  unpcklpd %xmm6,%xmm0
  movupd 0x30(%rax),%xmm7
  movupd 0x8(%rax),%xmm1
  mulpd  %xmm0,%xmm2
  movupd 0x10(%rax),%xmm10
  movapd %xmm4,%xmm0
  movupd 0x20(%rdi),%xmm11
  mov    %fs:0x28,%rdx
  mov    %rdx,0x48(%rsp)
  xor    %edx,%edx
  movupd 0x18(%rax),%xmm8
  movupd 0x38(%rax),%xmm3
  unpckhpd %xmm10,%xmm0
  shufpd $0x1,%xmm11,%xmm9
  mulpd  %xmm9,%xmm0
  movapd %xmm11,%xmm9
  movlpd 0x10(%rdi),%xmm9
  addpd  %xmm5,%xmm2
  addpd  %xmm0,%xmm2
  movsd  0x40(%rax),%xmm0
  movhpd 0x30(%rax),%xmm0
  mulpd  %xmm9,%xmm0
  addpd  %xmm0,%xmm2
  movupd (%rdi),%xmm0
  unpcklpd %xmm0,%xmm0
  mulpd  %xmm6,%xmm0
  movaps %xmm2,0x10(%rsp)
  movapd %xmm11,%xmm2
  unpcklpd %xmm11,%xmm2
  mulpd  %xmm4,%xmm2
  unpckhpd %xmm4,%xmm4
  addpd  %xmm5,%xmm0
  movapd %xmm0,%xmm9
  movupd (%rdi),%xmm0
  unpckhpd %xmm0,%xmm0
  mulpd  %xmm8,%xmm0
  addpd  %xmm9,%xmm0
  movupd 0x10(%rdi),%xmm9
  unpcklpd %xmm9,%xmm9
  mulpd  %xmm7,%xmm9
  addpd  %xmm9,%xmm0
  movsd  0x40(%rdi),%xmm9
  movaps %xmm0,(%rsp)
  movupd 0x10(%rdi),%xmm0
  unpckhpd %xmm0,%xmm0
  mulpd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addpd  %xmm5,%xmm0
  addpd  %xmm2,%xmm0
  movapd %xmm11,%xmm2
  unpckhpd %xmm11,%xmm2
  mulpd  %xmm3,%xmm2
  unpckhpd %xmm3,%xmm3
  mulsd  %xmm9,%xmm3
  addpd  %xmm2,%xmm0
  movupd 0x30(%rdi),%xmm2
  mov    %rsp,%rdi
  movaps %xmm0,0x20(%rsp)
  movapd %xmm2,%xmm0
  unpcklpd %xmm2,%xmm0
  mulpd  %xmm6,%xmm0
  addpd  %xmm5,%xmm0
  movapd %xmm2,%xmm5
  unpckhpd %xmm2,%xmm5
  mulpd  %xmm8,%xmm5
  addpd  %xmm5,%xmm0
  movapd %xmm9,%xmm5
  unpcklpd %xmm5,%xmm5
  mulpd  %xmm7,%xmm5
  addpd  %xmm5,%xmm0
  movaps %xmm0,0x30(%rsp)
  movapd %xmm2,%xmm0
  unpckhpd %xmm2,%xmm2
  mulsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm0
  addsd  D7(%rip),%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  movsd  %xmm0,0x40(%rsp)
  call   <mcopy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x58,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: f64

tool: D7: 0

assistant: ```c
void mmmul(double A[3][3], double B[3][3], double C[3][3]) {
  double T[3][3];
  for (int i = 0; i < 3; ++i) {
    for (int j = 0; j < 3; ++j) {
      T[i][j] = 0.0;
    }
  }
  for (int i = 0; i < 3; ++i) {
    for (int j = 0; j < 3; ++j) {
      for (int k = 0; k < 3; ++k) {
        T[i][j] += A[i][k] * B[k][j];
      }
    }
  }
  mcopy(T, C);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<STC3115_CalcRamCRC8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %eax,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L30:
  shll   -0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x100,%eax
  test   %eax,%eax
  je     L33
  xorl   $0x7,-0xc(%rbp)
L33:
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x7,-0x4(%rbp)
  jle    L30
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int STC3115_CalcRamCRC8(unsigned char *data, int n) {
  int crc = 0;
  int i, j;
  for (i = 0; i < n; i++) {
    crc ^= data[i];
    for (j = 0; j < 8; j++) {
      crc <<= 1;
      if (crc & 0x100)
        crc ^= 7;
    }
  }
  return (crc & 255);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<STC3115_CalcRamCRC8>:
  endbr64
  test   %esi,%esi
  jle    L27
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x0,%eax
  jmp    L13
L17:
  add    $0x1,%r8
  cmp    %rsi,%r8
  je     L9
L13:
  movzbl (%r8),%edx
  xor    %edx,%eax
  mov    $0x8,%edx
L46:
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x7,%ecx
  test   $0x1,%ah
  cmovne %ecx,%eax
  sub    $0x1,%edx
  jne    L46
  jmp    L17
L27:
  mov    $0x0,%eax
L9:
  movzbl %al,%eax
  ret
```

assistant: ```c
int STC3115_CalcRamCRC8(unsigned char *data, int n) {
  int crc = 0;
  int i, j;
  for (i = 0; i < n; i++) {
    crc ^= data[i];
    for (j = 0; j < 8; j++) {
      crc <<= 1;
      if (crc & 0x100)
        crc ^= 7;
    }
  }
  return (crc & 255);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<STC3115_CalcRamCRC8>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl (%rdi),%edx
  xor    %edx,%eax
  mov    $0x8,%edx
  nopw   0x0(%rax,%rax,1)
L10:
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x7,%ecx
  test   $0x1,%ah
  cmovne %ecx,%eax
  sub    $0x1,%edx
  jne    L10
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L18
  movzbl %al,%eax
  ret
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int STC3115_CalcRamCRC8(unsigned char *data, int n) {
  int crc = 0;
  int i, j;
  for (i = 0; i < n; i++) {
    crc ^= data[i];
    for (j = 0; j < 8; j++) {
      crc <<= 1;
      if (crc & 0x100)
        crc ^= 7;
    }
  }
  return (crc & 255);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<STC3115_CalcRamCRC8>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rcx
  xor    %edx,%edx
  lea    0x1(%rdi,%rax,1),%rsi
  nopl   0x0(%rax)
L15:
  movzbl (%rcx),%eax
  xor    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  xor    $0x7,%edx
  test   $0x1,%ah
  cmovne %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  xor    $0x7,%edx
  test   $0x1,%ah
  cmovne %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  xor    $0x7,%edx
  test   $0x1,%ah
  cmovne %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  xor    $0x7,%edx
  test   $0x1,%ah
  cmovne %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  xor    $0x7,%edx
  test   $0x1,%ah
  cmovne %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  xor    $0x7,%edx
  test   $0x1,%ah
  cmovne %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  xor    $0x7,%edx
  test   $0x1,%ah
  cmovne %edx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%eax
  xor    $0x7,%eax
  test   $0x1,%dh
  cmovne %eax,%edx
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L15
  movzbl %dl,%eax
  ret
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int STC3115_CalcRamCRC8(unsigned char *data, int n) {
  int crc = 0;
  int i, j;
  for (i = 0; i < n; i++) {
    crc ^= data[i];
    for (j = 0; j < 8; j++) {
      crc <<= 1;
      if (crc & 0x100)
        crc ^= 7;
    }
  }
  return (crc & 255);
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    %ecx,-0x18(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    $0x0,%eax
  mov    %ecx,-0x10(%rbp)
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(void) {
  int a, b, c, d, e, f;
  asm("# Magic instruction" : "=r"(a), "=r"(d) : "r"(0) : "eax");
  asm("# Magic instruction" : "=r"(b), "=r"(e) : "r"(0) : "edx");
  asm("# Magic instruction" : "=r"(c), "=r"(f) : "r"(0) : "ecx");
  return a + b + c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  mov    $0x0,%esi
  add    %edi,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int foo(void) {
  int a, b, c, d, e, f;
  asm("# Magic instruction" : "=r"(a), "=r"(d) : "r"(0) : "eax");
  asm("# Magic instruction" : "=r"(b), "=r"(e) : "r"(0) : "edx");
  asm("# Magic instruction" : "=r"(c), "=r"(f) : "r"(0) : "ecx");
  return a + b + c;
}
```