ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rege>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L85
  mov    %esi,%ecx
  mov    $0x0,%eax
  mov    $0x0,%esi
  mov    $0x0,%edi
  jmp    L49
L102:
  mov    %eax,%edi
  movaps %xmm2,%xmm0
L23:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L87
L49:
  movss  (%rdx,%rax,4),%xmm2
  comiss %xmm0,%xmm2
  ja     L102
  comiss %xmm2,%xmm1
  cmova  %eax,%esi
  minss  %xmm1,%xmm2
  movaps %xmm2,%xmm1
  jmp    L23
L26:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L117
L107:
  cmp    %eax,%edi
  je     L26
  movaps %xmm0,%xmm2
  addss  (%rdx,%rax,4),%xmm2
  movss  %xmm2,(%rdx,%rax,4)
  jmp    L26
L35:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L17
L47:
  cmp    %eax,%esi
  je     L35
  movss  (%rdx,%rax,4),%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdx,%rax,4)
  jmp    L35
L17:
  ret
L117:
  movslq %esi,%rax
  lea    (%rdx,%rax,4),%rax
  movss  (%rax),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,(%rax)
  divss  D40(%rip),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  divsd  D23(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  D18(%rip),%xmm0
  mov    $0x0,%eax
  jmp    L47
L87:
  movslq %edi,%rax
  movaps %xmm0,%xmm2
  mulss  D7(%rip),%xmm2
  movss  %xmm2,(%rdx,%rax,4)
  divss  D40(%rip),%xmm0
  mov    $0x0,%eax
  jmp    L107
L85:
  mulss  D7(%rip),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D40
type: f32
name: unpack_data
arguments: data_tag: D23
type: f64
name: unpack_data
arguments: data_tag: D18
type: byte[4]
name: unpack_data
arguments: data_tag: D7
type: byte[4]

tool: D40: 18

tool: D23: 0.01

tool: {"D18": [0x00,0x00,0xc8,0x42]}

tool: {"D7": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void rege(float *r, int length, float min, float max) {
  int i = 0;
  int j = 0;
  float r_max = min, r_min = max;
  int r_max_index = 0, r_min_index = 0;
  for (j = 0; j < length; j++) {
    if (r[j] > r_max) {
      r_max = r[j];
      r_max_index = j;
    } else if (r[j] < r_min) {
      r_min = r[j];
      r_min_index = j;
    }
  }
  r[r_max_index] = r_max / 2;
  float ava = r_max / 18;
  for (i = 0; i < length; i++) {
    if (i == r_max_index)
      continue;
    r[i] += ava;
  }
  r[r_min_index] *= 2.0;
  ava = r_min / 18;
  ava = ava / 0.01;
  ava = ava * 100;
  for (i = 0; i < length; i++) {
    if (i == r_min_index)
      continue;
    r[i] -= ava;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rege>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L65
  movslq %esi,%rcx
  xor    %eax,%eax
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L39:
  comiss %xmm2,%xmm1
  minss  %xmm1,%xmm2
  cmova  %eax,%esi
  add    $0x1,%rax
  movaps %xmm2,%xmm1
  cmp    %rcx,%rax
  je     L43
L17:
  movss  (%rdx,%rax,4),%xmm2
  comiss %xmm0,%xmm2
  jbe    L39
  mov    %eax,%edi
  add    $0x1,%rax
  movaps %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L17
L43:
  movss  D40(%rip),%xmm2
  movss  D31(%rip),%xmm3
  movslq %edi,%rax
  mulss  %xmm0,%xmm2
  divss  %xmm3,%xmm0
  movss  %xmm2,(%rdx,%rax,4)
  xor    %eax,%eax
L42:
  cmp    %eax,%edi
  je     L31
  movss  (%rdx,%rax,4),%xmm2
  addss  %xmm0,%xmm2
  movss  %xmm2,(%rdx,%rax,4)
L31:
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L42
  divss  %xmm3,%xmm1
  movslq %esi,%rax
  lea    (%rdx,%rax,4),%rax
  movss  (%rax),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,(%rax)
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  cvtss2sd %xmm1,%xmm0
  divsd  D27(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  D10(%rip),%xmm0
L45:
  cmp    %eax,%esi
  je     L29
  movss  (%rdx,%rax,4),%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdx,%rax,4)
L29:
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L45
  ret
  nopl   0x0(%rax)
L65:
  mulss  D40(%rip),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D40
datatype: byte[4]
name: disassemble_data
arguments: label: D31
datatype: f32
name: disassemble_data
arguments: label: D27
datatype: f64
name: disassemble_data
arguments: label: D10
datatype: byte[4]

tool: {"D40": [0x00,0x00,0x00,0x3f]}

tool: D31: 18

tool: D27: 0.01

tool: {"D10": [0x00,0x00,0xc8,0x42]}

assistant: ```c
void rege(float *r, int length, float min, float max) {
  int i = 0;
  int j = 0;
  float r_max = min, r_min = max;
  int r_max_index = 0, r_min_index = 0;
  for (j = 0; j < length; j++) {
    if (r[j] > r_max) {
      r_max = r[j];
      r_max_index = j;
    } else if (r[j] < r_min) {
      r_min = r[j];
      r_min_index = j;
    }
  }
  r[r_max_index] = r_max / 2;
  float ava = r_max / 18;
  for (i = 0; i < length; i++) {
    if (i == r_max_index)
      continue;
    r[i] += ava;
  }
  r[r_min_index] *= 2.0;
  ava = r_min / 18;
  ava = ava / 0.01;
  ava = ava * 100;
  for (i = 0; i < length; i++) {
    if (i == r_min_index)
      continue;
    r[i] -= ava;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rege>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L14
  movslq %esi,%rcx
  xor    %eax,%eax
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L63:
  comiss %xmm2,%xmm1
  minss  %xmm1,%xmm2
  cmova  %eax,%esi
  add    $0x1,%rax
  movaps %xmm2,%xmm1
  cmp    %rcx,%rax
  je     L86
L57:
  movss  (%rdx,%rax,4),%xmm2
  comiss %xmm0,%xmm2
  jbe    L63
  mov    %eax,%edi
  add    $0x1,%rax
  movaps %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L57
L86:
  movss  D34(%rip),%xmm2
  movss  D38(%rip),%xmm3
  movslq %edi,%rax
  mulss  %xmm0,%xmm2
  divss  %xmm3,%xmm0
  movss  %xmm2,(%rdx,%rax,4)
  xor    %eax,%eax
L10:
  cmp    %eax,%edi
  je     L46
  movss  (%rdx,%rax,4),%xmm2
  addss  %xmm0,%xmm2
  movss  %xmm2,(%rdx,%rax,4)
L46:
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L10
  divss  %xmm3,%xmm1
  movslq %esi,%rax
  lea    (%rdx,%rax,4),%rax
  movss  (%rax),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,(%rax)
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  cvtss2sd %xmm1,%xmm0
  divsd  D24(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  D48(%rip),%xmm0
L44:
  cmp    %eax,%esi
  je     L20
  movss  (%rdx,%rax,4),%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdx,%rax,4)
L20:
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L44
  ret
  nopl   0x0(%rax)
L14:
  mulss  D34(%rip),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D34
type: byte[4]
name: retrieve_data
arguments: data_label: D38
type: f32
name: retrieve_data
arguments: data_label: D24
type: f64
name: retrieve_data
arguments: data_label: D48
type: byte[4]

tool: {"D34": [0x00,0x00,0x00,0x3f]}

tool: D38: 18

tool: D24: 0.01

tool: {"D48": [0x00,0x00,0xc8,0x42]}

assistant: ```c
void rege(float *r, int length, float min, float max) {
  int i = 0;
  int j = 0;
  float r_max = min, r_min = max;
  int r_max_index = 0, r_min_index = 0;
  for (j = 0; j < length; j++) {
    if (r[j] > r_max) {
      r_max = r[j];
      r_max_index = j;
    } else if (r[j] < r_min) {
      r_min = r[j];
      r_min_index = j;
    }
  }
  r[r_max_index] = r_max / 2;
  float ava = r_max / 18;
  for (i = 0; i < length; i++) {
    if (i == r_max_index)
      continue;
    r[i] += ava;
  }
  r[r_min_index] *= 2.0;
  ava = r_min / 18;
  ava = ava / 0.01;
  ava = ava * 100;
  for (i = 0; i < length; i++) {
    if (i == r_min_index)
      continue;
    r[i] -= ava;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<produire>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string

tool: D8: J'ai produit %d


assistant: ```c
int produire() {
  int res;
  res = rand();
  printf("J'ai produit %d\n", res);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<produire>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: J'ai produit %d


assistant: ```c
int produire() {
  int res;
  res = rand();
  printf("J'ai produit %d\n", res);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<produire>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string

tool: D6: J'ai produit %d


assistant: ```c
int produire() {
  int res;
  res = rand();
  printf("J'ai produit %d\n", res);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<produire>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: J'ai produit %d


assistant: ```c
int produire() {
  int res;
  res = rand();
  printf("J'ai produit %d\n", res);
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<lookForEnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  lea    (%rax,%rax,1),%ebx
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  sub    $0x4,%eax
  cmp    %eax,%ebx
  jge    L29
  jmp    L17
L15:
  mov    $0x46,%esi
  mov    $0x1e,%edi
  call   <set_motors@plt>
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <checkWallAhead@plt>
  mov    $0x0,%eax
  call   <calcP@plt>
L17:
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  lea    (%rax,%rax,1),%ebx
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  cmp    %eax,%ebx
  jl     L15
L29:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: UTURN SL%d FL%d


assistant: ```c
void lookForEnd() {
  if (2 * get_side_ir_dist(0) < get_front_ir_dist(0) - 4) {
    while (2 * get_side_ir_dist(0) < get_front_ir_dist(0)) {
      set_motors(30, 70);
      printf("UTURN SL%d FL%d\n", get_side_ir_dist(0), get_front_ir_dist(0));
      checkWallAhead();
      calcP();
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lookForEnd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  sub    $0x4,%eax
  lea    D8(%rip),%rbp
  cmp    %eax,%ebx
  jl     L23
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0x46,%esi
  mov    $0x1e,%edi
  call   <set_motors@plt>
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <checkWallAhead@plt>
  mov    $0x0,%eax
  call   <calcP@plt>
L23:
  mov    $0x0,%edi
  call   <get_side_ir_dist@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  cmp    %eax,%ebx
  jl     L0
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D8: UTURN SL%d FL%d


assistant: ```c
void lookForEnd() {
  if (2 * get_side_ir_dist(0) < get_front_ir_dist(0) - 4) {
    while (2 * get_side_ir_dist(0) < get_front_ir_dist(0)) {
      set_motors(30, 70);
      printf("UTURN SL%d FL%d\n", get_side_ir_dist(0), get_front_ir_dist(0));
      checkWallAhead();
      calcP();
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<lookForEnd>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  call   <get_side_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  sub    $0x4,%eax
  cmp    %eax,%ebx
  jl     L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L11:
  mov    $0x46,%esi
  mov    $0x1e,%edi
  call   <set_motors@plt>
  xor    %edi,%edi
  call   <get_front_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <get_side_ir_dist@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <checkWallAhead@plt>
  xor    %eax,%eax
  call   <calcP@plt>
L9:
  xor    %edi,%edi
  call   <get_side_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  cmp    %eax,%ebx
  jl     L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: UTURN SL%d FL%d


assistant: ```c
void lookForEnd() {
  if (2 * get_side_ir_dist(0) < get_front_ir_dist(0) - 4) {
    while (2 * get_side_ir_dist(0) < get_front_ir_dist(0)) {
      set_motors(30, 70);
      printf("UTURN SL%d FL%d\n", get_side_ir_dist(0), get_front_ir_dist(0));
      checkWallAhead();
      calcP();
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lookForEnd>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  call   <get_side_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  sub    $0x4,%eax
  cmp    %eax,%ebx
  jl     L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L9:
  mov    $0x46,%esi
  mov    $0x1e,%edi
  call   <set_motors@plt>
  xor    %edi,%edi
  call   <get_front_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <get_side_ir_dist@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <checkWallAhead@plt>
  xor    %eax,%eax
  call   <calcP@plt>
L6:
  xor    %edi,%edi
  call   <get_side_ir_dist@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <get_front_ir_dist@plt>
  add    %ebx,%ebx
  cmp    %eax,%ebx
  jl     L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: UTURN SL%d FL%d


assistant: ```c
void lookForEnd() {
  if (2 * get_side_ir_dist(0) < get_front_ir_dist(0) - 4) {
    while (2 * get_side_ir_dist(0) < get_front_ir_dist(0)) {
      set_motors(30, 70);
      printf("UTURN SL%d FL%d\n", get_side_ir_dist(0), get_front_ir_dist(0));
      checkWallAhead();
      calcP();
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fcitx_utf8_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  jmp    L16
L12:
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fcitx_utf8_get_char@plt>
  mov    %rax,-0x28(%rbp)
  addq   $0x1,-0x10(%rbp)
L16:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) size_t fcitx_utf8_strlen(const char *s) {
  size_t l = 0;
  while (*s) {
    uint32_t chr;
    s = fcitx_utf8_get_char(s, &chr);
    l++;
  }
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fcitx_utf8_strlen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L25
  mov    $0x0,%ebx
  lea    0x4(%rsp),%rbp
L27:
  mov    %rbp,%rsi
  call   <fcitx_utf8_get_char@plt>
  mov    %rax,%rdi
  add    $0x1,%rbx
  cmpb   $0x0,(%rax)
  jne    L27
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0x0,%ebx
  jmp    L38
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) size_t fcitx_utf8_strlen(const char *s) {
  size_t l = 0;
  while (*s) {
    uint32_t chr;
    s = fcitx_utf8_get_char(s, &chr);
    l++;
  }
  return l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fcitx_utf8_strlen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L13
  lea    0x4(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbx,%rsi
  add    $0x1,%r12
  call   <fcitx_utf8_get_char@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rdi
  jne    L27
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) size_t fcitx_utf8_strlen(const char *s) {
  size_t l = 0;
  while (*s) {
    uint32_t chr;
    s = fcitx_utf8_get_char(s, &chr);
    l++;
  }
  return l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fcitx_utf8_strlen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L27
  lea    0x4(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rbx,%rsi
  add    $0x1,%r12
  call   <fcitx_utf8_get_char@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rdi
  jne    L26
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) size_t fcitx_utf8_strlen(const char *s) {
  size_t l = 0;
  while (*s) {
    uint32_t chr;
    s = fcitx_utf8_get_char(s, &chr);
    l++;
  }
  return l;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<conjugate_gradient>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,0xc(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9,0x18(%rsp)
  cmp    %edx,%esi
  jl     L1
  mov    %r9,%r15
  lea    0x0(,%rsi,8),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  push   $0x0
  push   %r12
  push   %r13
  push   %rax
  mov    %r15,%r9
  mov    0x30(%rsp),%r8
  mov    0x2c(%rsp),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    0x20(%rsp),%rdi
  call   <iterate_conjgrad@plt>
  mov    %eax,%ebx
  add    $0x20,%rsp
  jmp    L11
L1:
  lea    0x0(,%rsi,8),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  push   0x18(%rsp)
  push   %r12
  push   %r13
  push   %rax
  mov    %r15,%r9
  mov    0x30(%rsp),%r8
  mov    0x2c(%rsp),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    0x20(%rsp),%rdi
  call   <iterate_conjgrad@plt>
  mov    %eax,%ebx
  add    $0x20,%rsp
  test   %r15,%r15
  je     L11
  mov    %r15,%rdi
  call   <free@plt>
L11:
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int conjugate_gradient(double *A, int m, int n, int stride, double *b, double *x0) {
  double *y, *res, *dir, *tmp;
  int err;
  err = 0;
  y = NULL;
  if (m >= n) {
    tmp = malloc(m * sizeof tmp[0]);
    dir = malloc(m * sizeof dir[0]);
    res = malloc(m * sizeof res[0]);
    if ((err = iterate_conjgrad(A, m, n, stride, b, x0, res, dir, tmp, NULL)) == -1) {
      err = -1;
      goto err_out;
    }
  } else {
    y = malloc(m * sizeof y[0]);
    tmp = malloc(m * sizeof tmp[0]);
    dir = malloc(n * sizeof dir[0]);
    res = malloc(m * sizeof res[0]);
    if ((err = iterate_conjgrad(A, m, n, stride, b, y, res, dir, tmp, x0)) == -1) {
      err = -1;
      goto err_out;
    }
  }
err_out:
  if (y != NULL)
    free(y);
  free(res);
  free(dir);
  free(tmp);
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<conjugate_gradient>:
  endbr64
  push   %r15
  lea    0x0(,%rsi,8),%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  cmp    %edx,%esi
  jl     L7
  mov    %r15d,%edi
  mov    %r9,0x10(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %ecx,(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  push   $0x0
  mov    %r12d,%edx
  mov    %ebp,%esi
  push   %r13
  mov    %rbx,%rdi
  mov    %rax,%r15
  push   %r14
  push   %rax
  mov    0x30(%rsp),%r9
  mov    0x28(%rsp),%r8
  mov    0x20(%rsp),%ecx
  call   <iterate_conjgrad@plt>
  add    $0x20,%rsp
  mov    %eax,%r12d
L21:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r15d,%edi
  mov    %r9,0x18(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %ecx,0x8(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  lea    0x0(,%r12,8),%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    0x18(%rsp),%r9
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    %rax,%r15
  push   %r9
  push   %r13
  push   %r14
  push   %rax
  mov    0x20(%rsp),%r9
  mov    0x30(%rsp),%r8
  mov    0x28(%rsp),%ecx
  call   <iterate_conjgrad@plt>
  mov    0x20(%rsp),%r10
  add    $0x20,%rsp
  mov    %eax,%r12d
  test   %r10,%r10
  je     L21
  mov    %r10,%rdi
  call   <free@plt>
  jmp    L21
```

assistant: ```c
int conjugate_gradient(double *A, int m, int n, int stride, double *b, double *x0) {
  double *y, *res, *dir, *tmp;
  int err;
  err = 0;
  y = NULL;
  if (m >= n) {
    tmp = malloc(m * sizeof tmp[0]);
    dir = malloc(m * sizeof dir[0]);
    res = malloc(m * sizeof res[0]);
    if ((err = iterate_conjgrad(A, m, n, stride, b, x0, res, dir, tmp, NULL)) == -1) {
      err = -1;
      goto err_out;
    }
  } else {
    y = malloc(m * sizeof y[0]);
    tmp = malloc(m * sizeof tmp[0]);
    dir = malloc(n * sizeof dir[0]);
    res = malloc(m * sizeof res[0]);
    if ((err = iterate_conjgrad(A, m, n, stride, b, y, res, dir, tmp, x0)) == -1) {
      err = -1;
      goto err_out;
    }
  }
err_out:
  if (y != NULL)
    free(y);
  free(res);
  free(dir);
  free(tmp);
  return err;
}
```