ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L7
L3:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L31
  movl   $0x1,-0x4(%rbp)
  jmp    L39
L31:
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L3
L39:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(int n) {
  int i, i2;
  int prime;
  prime = 0;
  for (i = 2; i <= n - 1; i++) {
    if (n % i == 0) {
      prime = 1;
      break;
    }
  }
  return prime;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L15
  test   $0x1,%dil
  je     L23
  mov    $0x2,%ecx
L35:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L17
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L35
  mov    $0x1,%eax
  ret
L17:
  mov    $0x0,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_prime(int n) {
  int i, i2;
  int prime;
  prime = 0;
  for (i = 2; i <= n - 1; i++) {
    if (n % i == 0) {
      prime = 1;
      break;
    }
  }
  return prime;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L25
  test   $0x1,%dil
  je     L19
  mov    $0x2,%ecx
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L19
L16:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L2
L25:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_prime(int n) {
  int i, i2;
  int prime;
  prime = 0;
  for (i = 2; i <= n - 1; i++) {
    if (n % i == 0) {
      prime = 1;
      break;
    }
  }
  return prime;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L22
  test   $0x1,%dil
  je     L29
  mov    $0x2,%ecx
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L29
L3:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L28
L22:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_prime(int n) {
  int i, i2;
  int prime;
  prime = 0;
  for (i = 2; i <= n - 1; i++) {
    if (n % i == 0) {
      prime = 1;
      break;
    }
  }
  return prime;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_serial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L1:
  mov    $0x0,%eax
  call   <serial_received@plt>
  test   %rax,%rax
  je     L1
  mov    $0x3f8,%edi
  call   <inb@plt>
  pop    %rbp
  ret
```

assistant: ```c
char read_serial() {
  while (serial_received() == 0)
    ;
  return inb(0x3f8);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_serial>:
  endbr64
  sub    $0x8,%rsp
L7:
  mov    $0x0,%eax
  call   <serial_received@plt>
  test   %rax,%rax
  je     L7
  mov    $0x3f8,%edi
  call   <inb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char read_serial() {
  while (serial_received() == 0)
    ;
  return inb(0x3f8);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_serial>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <serial_received@plt>
  test   %rax,%rax
  je     L0
  mov    $0x3f8,%edi
  add    $0x8,%rsp
  jmp    1060 <inb@plt>
```

assistant: ```c
char read_serial() {
  while (serial_received() == 0)
    ;
  return inb(0x3f8);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_serial>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <serial_received@plt>
  test   %rax,%rax
  je     L1
  mov    $0x3f8,%edi
  add    $0x8,%rsp
  jmp    1060 <inb@plt>
```

assistant: ```c
char read_serial() {
  while (serial_received() == 0)
    ;
  return inb(0x3f8);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<utilMkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  je     L0
  mov    D33(%rip),%rax
  mov    (%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L13
L0:
  mov    $0x0,%eax
  jmp    L21
L13:
  mov    $0x1,%eax
L21:
  leave
  ret
```

assistant: ```c
int utilMkdir(char *dn) {
  if (mkdir(dn, S_IRUSR | S_IWUSR | S_IXUSR) == 0 || errno == EEXIST) {
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utilMkdir>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    D12(%rip),%rax
  or     (%rax),%esi
  mov    D31(%rip),%rax
  or     (%rax),%esi
  call   <mkdir@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L9
  mov    D5(%rip),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
L9:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int utilMkdir(char *dn) {
  if (mkdir(dn, S_IRUSR | S_IWUSR | S_IXUSR) == 0 || errno == EEXIST) {
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utilMkdir>:
  endbr64
  sub    $0x8,%rsp
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  mov    D14(%rip),%rax
  or     (%rax),%esi
  mov    D1(%rip),%rax
  or     (%rax),%esi
  call   <mkdir@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L5
  mov    D49(%rip),%rdx
  mov    D16(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int utilMkdir(char *dn) {
  if (mkdir(dn, S_IRUSR | S_IWUSR | S_IXUSR) == 0 || errno == EEXIST) {
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<utilMkdir>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    D28(%rip),%rax
  or     (%rax),%esi
  mov    D7(%rip),%rax
  or     (%rax),%esi
  call   <mkdir@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L6
  mov    D9(%rip),%rdx
  mov    D41(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int utilMkdir(char *dn) {
  if (mkdir(dn, S_IRUSR | S_IWUSR | S_IXUSR) == 0 || errno == EEXIST) {
    return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Msort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L5
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L17
L5:
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <MSort@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <MSort@plt>
  mov    -0x28(%rbp),%edi
  mov    -0x4(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <Merge@plt>
L17:
  nop
  leave
  ret
```

assistant: ```c
void Msort(int R[], int R1[], int s, int t) {
  int m;
  if (s == t)
    R1[s] = R[s];
  else {
    m = (s + t) / 2;
    MSort(R, R1, s, m);
    MSort(R, R1, m + 1, t);
    Merge(R1, R, s, m, t);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Msort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebx
  cmp    %ecx,%edx
  jne    L1
  movslq %edx,%rbx
  mov    (%rdi,%rbx,4),%eax
  mov    %eax,(%rsi,%rbx,4)
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  mov    %ecx,%ebp
  lea    (%rdx,%rcx,1),%eax
  mov    %eax,%r14d
  shr    $0x1f,%r14d
  add    %eax,%r14d
  sar    %r14d
  mov    %r14d,%ecx
  call   <MSort@plt>
  lea    0x1(%r14),%edx
  mov    %ebp,%ecx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <MSort@plt>
  mov    %ebp,%r8d
  mov    %r14d,%ecx
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <Merge@plt>
  jmp    L9
```

assistant: ```c
void Msort(int R[], int R1[], int s, int t) {
  int m;
  if (s == t)
    R1[s] = R[s];
  else {
    m = (s + t) / 2;
    MSort(R, R1, s, m);
    MSort(R, R1, m + 1, t);
    Merge(R1, R, s, m, t);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Msort>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cmp    %ecx,%r12d
  jne    L1
  mov    (%rdi,%r12,4),%eax
  mov    %eax,(%rsi,%r12,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    (%r12,%rcx,1),%eax
  mov    %ecx,%ebx
  mov    %r12d,%edx
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%ecx
  call   <MSort@plt>
  lea    0x1(%r13),%edx
  mov    %ebx,%ecx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <MSort@plt>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  pop    %rbx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <Merge@plt>
```

assistant: ```c
void Msort(int R[], int R1[], int s, int t) {
  int m;
  if (s == t)
    R1[s] = R[s];
  else {
    m = (s + t) / 2;
    MSort(R, R1, s, m);
    MSort(R, R1, m + 1, t);
    Merge(R1, R, s, m, t);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Msort>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cmp    %ecx,%r12d
  jne    L6
  mov    (%rdi,%r12,4),%eax
  mov    %eax,(%rsi,%r12,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    (%r12,%rcx,1),%eax
  mov    %ecx,%ebx
  mov    %r12d,%edx
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%ecx
  call   <MSort@plt>
  lea    0x1(%r13),%edx
  mov    %ebx,%ecx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <MSort@plt>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  pop    %rbx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <Merge@plt>
```

assistant: ```c
void Msort(int R[], int R1[], int s, int t) {
  int m;
  if (s == t)
    R1[s] = R[s];
  else {
    m = (s + t) / 2;
    MSort(R, R1, s, m);
    MSort(R, R1, m + 1, t);
    Merge(R1, R, s, m, t);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L8:
  mov    $0x0,%eax
  call   <keydown@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x71,-0x4(%rbp)
  je     L25
  cmpl   $0x1b,-0x4(%rbp)
  je     L25
  jmp    L8
L25:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D23
type: string
name: parse_data
arguments: label: D25
type: string
name: parse_data
arguments: label: D21
type: string

tool: D23: press 'q' or 'Esc' to quit.

tool: D25: %d


tool: D21: down.

assistant: ```c
int main(int argc, char **argv) {
  int c;
  printf("press 'q' or 'Esc' to quit.\n");
  while (1) {
    printf("%d\n", c = keydown());
    if (c == 'q' || c == '')
      break;
  }
  printf("down.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    D7(%rip),%rbp
L18:
  mov    $0x0,%eax
  call   <keydown@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x71,%ebx
  je     L2
  cmp    $0x1b,%ebx
  jne    L18
L2:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D7
datatype: string
name: unpack_data
arguments: label: D2
datatype: string

tool: D19: press 'q' or 'Esc' to quit.

tool: D7: %d


tool: D2: down.

assistant: ```c
int main(int argc, char **argv) {
  int c;
  printf("press 'q' or 'Esc' to quit.\n");
  while (1) {
    printf("%d\n", c = keydown());
    if (c == 'q' || c == '')
      break;
  }
  printf("down.\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rdi
  lea    D18(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopl   (%rax)
L7:
  xor    %eax,%eax
  call   <keydown@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x71,%ebx
  je     L14
  cmp    $0x1b,%ebx
  jne    L7
L14:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D24
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string

tool: D24: press 'q' or 'Esc' to quit.

tool: D18: %d


tool: D15: down.

assistant: ```c
int main(int argc, char **argv) {
  int c;
  printf("press 'q' or 'Esc' to quit.\n");
  while (1) {
    printf("%d\n", c = keydown());
    if (c == 'q' || c == '')
      break;
  }
  printf("down.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  lea    D13(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopl   (%rax)
L16:
  xor    %eax,%eax
  call   <keydown@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x71,%ebx
  je     L11
  cmp    $0x1b,%ebx
  jne    L16
L11:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string

tool: D16: press 'q' or 'Esc' to quit.

tool: D13: %d


tool: D8: down.

assistant: ```c
int main(int argc, char **argv) {
  int c;
  printf("press 'q' or 'Esc' to quit.\n");
  while (1) {
    printf("%d\n", c = keydown());
    if (c == 'q' || c == '')
      break;
  }
  printf("down.\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<disk_used>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <statvfs@plt>
  test   %rax,%rax
  jns    L22
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <warn@plt>
  mov    $0x0,%eax
  jmp    L12
L22:
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  sub    %ecx,%edx
  imul   %edx,%eax
  mov    $0x400,%esi
  mov    %eax,%edi
  call   <fmt_human@plt>
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: statvfs '%s':

assistant: ```c
const char *disk_used(const char *path) {
  struct statvfs fs;
  if (statvfs(path, &fs) < 0) {
    warn("statvfs '%s':", path);
    return NULL;
  }
  return fmt_human(fs.f_frsize * (fs.f_blocks - fs.f_bfree), 1024);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<disk_used>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <statvfs@plt>
  test   %rax,%rax
  js     L13
  mov    0x10(%rsp),%edi
  sub    0x14(%rsp),%edi
  imul   0xc(%rsp),%edi
  mov    $0x400,%esi
  call   <fmt_human@plt>
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x20,%rsp
  pop    %rbx
  ret
L13:
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <warn@plt>
  mov    $0x0,%eax
  jmp    L1
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: statvfs '%s':

assistant: ```c
const char *disk_used(const char *path) {
  struct statvfs fs;
  if (statvfs(path, &fs) < 0) {
    warn("statvfs '%s':", path);
    return NULL;
  }
  return fmt_human(fs.f_frsize * (fs.f_blocks - fs.f_bfree), 1024);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<disk_used>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <statvfs@plt>
  test   %rax,%rax
  js     L15
  mov    0x10(%rsp),%edi
  sub    0x14(%rsp),%edi
  mov    $0x400,%esi
  imul   0xc(%rsp),%edi
  call   <fmt_human@plt>
L12:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <warn@plt>
  xor    %eax,%eax
  jmp    L12
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: statvfs '%s':

assistant: ```c
const char *disk_used(const char *path) {
  struct statvfs fs;
  if (statvfs(path, &fs) < 0) {
    warn("statvfs '%s':", path);
    return NULL;
  }
  return fmt_human(fs.f_frsize * (fs.f_blocks - fs.f_bfree), 1024);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<disk_used>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <statvfs@plt>
  test   %rax,%rax
  js     L1
  mov    0x10(%rsp),%edi
  sub    0x14(%rsp),%edi
  mov    $0x400,%esi
  imul   0xc(%rsp),%edi
  call   <fmt_human@plt>
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <warn@plt>
  xor    %eax,%eax
  jmp    L6
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: statvfs '%s':

assistant: ```c
const char *disk_used(const char *path) {
  struct statvfs fs;
  if (statvfs(path, &fs) < 0) {
    warn("statvfs '%s':", path);
    return NULL;
  }
  return fmt_human(fs.f_frsize * (fs.f_blocks - fs.f_bfree), 1024);
}
```
user: What is the c source code of the assembly code below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2a,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L8:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  imul   %rdx,%rax
  add    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long hash(char *word) {
  long ascii_counter = 42;
  long counter = 0;
  while (word[counter] != '\0') {
    ascii_counter = ascii_counter + (word[counter] * (counter + 1));
    counter++;
  }
  return ascii_counter;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  mov    $0x0,%edx
  mov    $0x2a,%ecx
L26:
  add    $0x1,%rdx
  movsbq %al,%rax
  imul   %rdx,%rax
  add    %rax,%rcx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L26
L0:
  mov    %rcx,%rax
  ret
L3:
  mov    $0x2a,%ecx
  jmp    L0
```

assistant: ```c
long hash(char *word) {
  long ascii_counter = 42;
  long counter = 0;
  while (word[counter] != '\0') {
    ascii_counter = ascii_counter + (word[counter] * (counter + 1));
    counter++;
  }
  return ascii_counter;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rax
  test   %al,%al
  je     L17
  xor    %edx,%edx
  mov    $0x2a,%r8d
  nopl   0x0(%rax)
L15:
  add    $0x1,%rdx
  imul   %rdx,%rax
  add    %rax,%r8
  movsbq (%rdi,%rdx,1),%rax
  test   %al,%al
  jne    L15
  mov    %r8,%rax
  ret
L17:
  mov    $0x2a,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long hash(char *word) {
  long ascii_counter = 42;
  long counter = 0;
  while (word[counter] != '\0') {
    ascii_counter = ascii_counter + (word[counter] * (counter + 1));
    counter++;
  }
  return ascii_counter;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rax
  test   %al,%al
  je     L10
  xor    %edx,%edx
  mov    $0x2a,%r8d
  nopl   0x0(%rax)
L3:
  add    $0x1,%rdx
  imul   %rdx,%rax
  add    %rax,%r8
  movsbq (%rdi,%rdx,1),%rax
  test   %al,%al
  jne    L3
  mov    %r8,%rax
  ret
L10:
  mov    $0x2a,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long hash(char *word) {
  long ascii_counter = 42;
  long counter = 0;
  while (word[counter] != '\0') {
    ascii_counter = ascii_counter + (word[counter] * (counter + 1));
    counter++;
  }
  return ascii_counter;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<west_one_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  movabs $0x101010101010101,%rax
  mov    %rax,%rsi
  mov    $0x1010101,%edi
  call   <assert_int_equal@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <assert_int_equal@plt>
  nop
  leave
  ret
```

assistant: ```c
void west_one_test(void **state) {
  assert_int_equal((((0x0202020202020202ul) >> 1) & ~0x8080808080808080ul), 0x0101010101010101ul);
  assert_int_equal((((0x0101010101010101ul) >> 1) & ~0x8080808080808080ul), 0ul);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<west_one_test>:
  endbr64
  sub    $0x8,%rsp
  movabs $0x101010101010101,%rsi
  mov    $0x1010101,%edi
  call   <assert_int_equal@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <assert_int_equal@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void west_one_test(void **state) {
  assert_int_equal((((0x0202020202020202ul) >> 1) & ~0x8080808080808080ul), 0x0101010101010101ul);
  assert_int_equal((((0x0101010101010101ul) >> 1) & ~0x8080808080808080ul), 0ul);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<west_one_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1010101,%edi
  movabs $0x101010101010101,%rsi
  call   <assert_int_equal@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1050 <assert_int_equal@plt>
```

assistant: ```c
void west_one_test(void **state) {
  assert_int_equal((((0x0202020202020202ul) >> 1) & ~0x8080808080808080ul), 0x0101010101010101ul);
  assert_int_equal((((0x0101010101010101ul) >> 1) & ~0x8080808080808080ul), 0ul);
}
```