user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<preprocessor2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D82(%rip),%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D86(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x39,%edx
  lea    D9(%rip),%r12
  mov    %r12,%rsi
  lea    D59(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x3f,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  mov    $0x9,%edi
  mov    $0xffffffff,%ebp
  lea    D14(%rip),%r13
  jmp    L15
L7:
  mov    %ebx,%eax
  sub    %ebp,%eax
  sub    $0x1,%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %eax,%edx
  lea    0x8(%rdx),%ebp
L33:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L33
  mov    %r12d,%ebp
L50:
  add    $0x1,%rbx
  movzbl 0x0(%r13,%rbx,1),%edi
  test   %dil,%dil
  je     L3
L15:
  mov    %ebx,%r12d
  cmp    $0x1f,%dil
  jg     L50
  cmp    $0x9,%dil
  je     L7
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L50
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x4c,%edx
  lea    D9(%rip),%rsi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D82(%rip),%rsi
  lea    D87(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D82
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string
name: parse_data
arguments: label: D86
type_guessed: string
name: parse_data
arguments: label: D9
type_guessed: string
name: parse_data
arguments: label: D59
type_guessed: string
name: parse_data
arguments: label: D14
type_guessed: string
name: parse_data
arguments: label: D87
type_guessed: string

tool: D82: preprocessor2

tool: D19: ----- START %s


tool: D86: a= %d	

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/reslaurentii/sandbox/refs/heads/master/src/preprocessor.c

tool: D59: ** look at %s:%d **


tool: D14: 	wihch	if?

tool: D87: ----- END %s


assistant: ```c
int preprocessor2(void) {
  printf("----- START %s\n", __FUNCTION__);
  {
    int x = 1;
    printf("a= %d\t", (int)(- -x));
    putchar('\n');
  }
  printf("** look at %s:%d **\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/reslaurentii/sandbox/refs/heads/master/src/preprocessor.c", 57);
  {
    printf("a= %d\t", (int)((((10080 / 60) / 24) / 7)));
    putchar('\n');
    printf("a= %d\t", (int)((((86400 / 60) / 60) / 24)));
    putchar('\n');
  }
  printf("** look at %s:%d **\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/reslaurentii/sandbox/refs/heads/master/src/preprocessor.c", 63);
  {
    static char input[] = "\twihch\tif?";
    char c;
    int i, oldi, temp;
    for (oldi = -1, i = 0; (c = input[i]) != '\0'; i++)
      if (c < ' ')
        if (c == '\t')
          for (temp = 8 - (i - oldi - 1) % 8, oldi = i; temp; temp--)
            putchar(' ');
        else
          putchar(c);
    putchar('\n');
  }
  printf("** look at %s:%d **\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/reslaurentii/sandbox/refs/heads/master/src/preprocessor.c", 76);
  printf("----- END %s\n", __FUNCTION__);
  return 0;
}
```