ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sqlStringArrayToString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <newDyString@plt>
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L39
  mov    %rax,%rdi
  lea    -0x1(%rbp),%eax
  lea    D6(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%rsp),%rdi
L37:
  mov    (%rbx),%rdx
  mov    %rbp,%rsi
  add    $0x8,%rbx
  call   <dyStringPrintf@plt>
  cmp    %r12,%rbx
  jne    L21
L39:
  mov    %rsp,%rdi
  call   <dyStringCannibalize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: %s,

assistant: ```c
char *sqlStringArrayToString(char **array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%s,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqlStringArrayToString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <newDyString@plt>
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L28
  mov    %rax,%rdi
  lea    -0x1(%rbp),%eax
  lea    D2(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rsp),%rdi
L19:
  mov    (%rbx),%rdx
  mov    %rbp,%rsi
  add    $0x8,%rbx
  call   <dyStringPrintf@plt>
  cmp    %r12,%rbx
  jne    L8
L28:
  mov    %rsp,%rdi
  call   <dyStringCannibalize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: %s,

assistant: ```c
char *sqlStringArrayToString(char **array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%s,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <start@plt>
  mov    $0x0,%eax
  call   <db_close@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  start();
  db_close();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <start@plt>
  mov    $0x0,%eax
  call   <db_close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  start();
  db_close();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <start@plt>
  xor    %eax,%eax
  call   <db_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  start();
  db_close();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <start@plt>
  xor    %eax,%eax
  call   <db_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  start();
  db_close();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fletcher_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movb   $0x0,-0xe(%rbp)
  movb   $0x0,-0xd(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L97
  cmpq   $0x0,-0x28(%rbp)
  je     L97
  cmpq   $0x0,-0x30(%rbp)
  jne    L89
L97:
  mov    $0xffffffff,%eax
  jmp    L49
L89:
  movl   $0x0,-0xc(%rbp)
  jmp    L61
L34:
  movzbl -0xe(%rbp),%eax
  mov    $0xff,%edx
  sub    %eax,%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,%edx
  jge    L55
  movzbl -0xe(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xe(%rbp)
L55:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    %al,-0xe(%rbp)
  cmpb   $0xff,-0xe(%rbp)
  jne    L12
  movb   $0x0,-0xe(%rbp)
L12:
  movzbl -0xd(%rbp),%eax
  mov    $0xff,%edx
  sub    %eax,%edx
  movzbl -0xe(%rbp),%eax
  cmp    %eax,%edx
  jge    L86
  movzbl -0xd(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xd(%rbp)
L86:
  movzbl -0xe(%rbp),%eax
  add    %al,-0xd(%rbp)
  cmpb   $0xff,-0xd(%rbp)
  jne    L51
  movb   $0x0,-0xd(%rbp)
L51:
  addl   $0x1,-0xc(%rbp)
L61:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L34
  mov    -0x28(%rbp),%rax
  movzbl -0xe(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x30(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0x0,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int fletcher_checksum(const void *buf, unsigned int len, unsigned char *sum1, unsigned char *sum2) {
  int i;
  unsigned char s1 = 0;
  unsigned char s2 = 0;
  const unsigned char *str = buf;
  if (!buf || !sum1 || !sum2)
    return -1;
  for (i = 0; i < len; i++) {
    if ((255 - s1) < str[i])
      s1++;
    s1 += str[i];
    if (s1 == 255)
      s1 = 0;
    if ((255 - s2) < s1)
      s2++;
    s2 += s1;
    if (s2 == 255)
      s2 = 0;
  }
  *sum1 = s1;
  *sum2 = s2;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fletcher_checksum>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  test   %rdx,%rdx
  sete   %dl
  test   %rcx,%rcx
  sete   %cl
  or     %cl,%dl
  jne    L11
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L11
  test   %esi,%esi
  je     L15
  movzbl (%rdi),%edi
  mov    %rax,%rcx
  lea    -0x1(%rsi),%edx
  lea    (%rax,%rdx,1),%rsi
  mov    $0x0,%edx
  mov    $0x0,%eax
  mov    $0xff,%r10d
  mov    $0x0,%r11d
  jmp    L24
L15:
  mov    $0x0,%edx
  mov    $0x0,%eax
L73:
  mov    %al,(%rbx)
  mov    %dl,0x0(%rbp)
  mov    $0x0,%eax
L58:
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x0,%eax
L41:
  add    %eax,%edx
  cmp    $0xff,%dl
  cmove  %r11d,%edx
  cmp    %rcx,%rsi
  je     L73
  movzbl 0x1(%rcx),%edi
  movzbl %al,%r8d
  mov    %r10d,%r9d
  sub    %r8d,%r9d
  movzbl %dil,%r8d
  cmp    %r8d,%r9d
  setl   %r8b
  add    %r8d,%eax
  add    $0x1,%rcx
L24:
  add    %edi,%eax
  cmp    $0xff,%al
  je     L19
  movzbl %dl,%edi
  mov    %r10d,%r8d
  sub    %edi,%r8d
  movzbl %al,%edi
  cmp    %edi,%r8d
  setl   %dil
  add    %edi,%edx
  jmp    L41
L11:
  mov    $0xffffffff,%eax
  jmp    L58
```

assistant: ```c
int fletcher_checksum(const void *buf, unsigned int len, unsigned char *sum1, unsigned char *sum2) {
  int i;
  unsigned char s1 = 0;
  unsigned char s2 = 0;
  const unsigned char *str = buf;
  if (!buf || !sum1 || !sum2)
    return -1;
  for (i = 0; i < len; i++) {
    if ((255 - s1) < str[i])
      s1++;
    s1 += str[i];
    if (s1 == 255)
      s1 = 0;
    if ((255 - s2) < s1)
      s2++;
    s2 += s1;
    if (s2 == 255)
      s2 = 0;
  }
  *sum1 = s1;
  *sum2 = s2;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fletcher_checksum>:
  endbr64
  test   %rdx,%rdx
  mov    %rdx,%r11
  sete   %al
  test   %rcx,%rcx
  sete   %dl
  or     %dl,%al
  jne    L48
  test   %rdi,%rdi
  je     L48
  push   %rbp
  xor    %edx,%edx
  xor    %eax,%eax
  push   %rbx
  mov    %rcx,%rbx
  test   %esi,%esi
  je     L73
  lea    -0x1(%rsi),%r9d
  movzbl (%rdi),%ecx
  xor    %edx,%edx
  xor    %eax,%eax
  add    %rdi,%r9
  mov    $0xff,%r8d
  xor    %r10d,%r10d
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L67:
  movzbl %dl,%esi
  mov    %r8d,%ecx
  sub    %esi,%ecx
  movzbl %al,%esi
  cmp    %esi,%ecx
  setl   %cl
  add    %ecx,%edx
  add    %eax,%edx
  cmp    $0xff,%dl
  cmove  %r10d,%edx
  cmp    %r9,%rdi
  je     L73
  movzbl 0x1(%rdi),%ecx
  mov    %r8d,%ebp
  sub    %esi,%ebp
  movzbl %cl,%esi
  cmp    %esi,%ebp
  setl   %sil
  add    %esi,%eax
L55:
  add    $0x1,%rdi
L20:
  add    %ecx,%eax
  cmp    $0xff,%al
  jne    L67
  cmp    %r9,%rdi
  je     L14
  movzbl 0x1(%rdi),%ecx
  xor    %eax,%eax
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
L73:
  mov    %al,(%r11)
  xor    %eax,%eax
  mov    %dl,(%rbx)
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fletcher_checksum(const void *buf, unsigned int len, unsigned char *sum1, unsigned char *sum2) {
  int i;
  unsigned char s1 = 0;
  unsigned char s2 = 0;
  const unsigned char *str = buf;
  if (!buf || !sum1 || !sum2)
    return -1;
  for (i = 0; i < len; i++) {
    if ((255 - s1) < str[i])
      s1++;
    s1 += str[i];
    if (s1 == 255)
      s1 = 0;
    if ((255 - s2) < s1)
      s2++;
    s2 += s1;
    if (s2 == 255)
      s2 = 0;
  }
  *sum1 = s1;
  *sum2 = s2;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<fletcher_checksum>:
  endbr64
  test   %rdx,%rdx
  push   %rbp
  sete   %al
  test   %rcx,%rcx
  push   %rbx
  mov    %rdx,%rbx
  sete   %dl
  or     %dl,%al
  jne    L25
  test   %rdi,%rdi
  je     L25
  mov    %rcx,%rbp
  xor    %edx,%edx
  xor    %eax,%eax
  test   %esi,%esi
  je     L39
  lea    -0x1(%rsi),%r9d
  movzbl (%rdi),%ecx
  xor    %edx,%edx
  xor    %eax,%eax
  add    %rdi,%r9
  mov    $0xff,%r8d
  xor    %r11d,%r11d
  jmp    L87
  nopw   0x0(%rax,%rax,1)
L41:
  movzbl %dl,%r10d
  mov    %r8d,%ecx
  movzbl %al,%esi
  sub    %r10d,%ecx
  cmp    %esi,%ecx
  setl   %cl
  add    %ecx,%edx
  add    %eax,%edx
  cmp    $0xff,%dl
  cmove  %r11d,%edx
  cmp    %r9,%rdi
  je     L39
  movzbl 0x1(%rdi),%ecx
  mov    %r8d,%r10d
  sub    %esi,%r10d
  movzbl %cl,%esi
  cmp    %esi,%r10d
  setl   %sil
  add    %esi,%eax
L35:
  add    $0x1,%rdi
L87:
  add    %ecx,%eax
  cmp    $0xff,%al
  jne    L41
  cmp    %r9,%rdi
  je     L31
  movzbl 0x1(%rdi),%ecx
  xor    %eax,%eax
  jmp    L35
  nop
L31:
  xor    %eax,%eax
L39:
  mov    %al,(%rbx)
  xor    %eax,%eax
  mov    %dl,0x0(%rbp)
L19:
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int fletcher_checksum(const void *buf, unsigned int len, unsigned char *sum1, unsigned char *sum2) {
  int i;
  unsigned char s1 = 0;
  unsigned char s2 = 0;
  const unsigned char *str = buf;
  if (!buf || !sum1 || !sum2)
    return -1;
  for (i = 0; i < len; i++) {
    if ((255 - s1) < str[i])
      s1++;
    s1 += str[i];
    if (s1 == 255)
      s1 = 0;
    if ((255 - s2) < s1)
      s2++;
    s2 += s1;
    if (s2 == 255)
      s2 = 0;
  }
  *sum1 = s1;
  *sum2 = s2;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readArgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: %d

assistant: ```c
int readArgs() {
  int n;
  scanf("%d", &n);
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readArgs>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: %d

assistant: ```c
int readArgs() {
  int n;
  scanf("%d", &n);
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readArgs>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: %d

assistant: ```c
int readArgs() {
  int n;
  scanf("%d", &n);
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readArgs>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: %d

assistant: ```c
int readArgs() {
  int n;
  scanf("%d", &n);
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipDigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L13
L17:
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skipDigits(char *arg) {
  while (isdigit(*arg))
    ++arg;
  return arg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skipDigits>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L6
L11:
  add    $0x1,%rbx
L6:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L11
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skipDigits(char *arg) {
  while (isdigit(*arg))
    ++arg;
  return arg;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<skipDigits>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%r12
L16:
  movsbl (%r12),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L10
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipDigits(char *arg) {
  while (isdigit(*arg))
    ++arg;
  return arg;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skipDigits>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%r12
L11:
  movsbl (%r12),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L4
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipDigits(char *arg) {
  while (isdigit(*arg))
    ++arg;
  return arg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memmove8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__builtin_memmove@plt>
  leave
  ret
```

assistant: ```c
void *memmove8(void *to, const void *from, size_t size) {
  unsigned char s8 = size;
  return __builtin_memmove(to, from, s8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memmove8>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dl,%edx
  call   <__builtin_memmove@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *memmove8(void *to, const void *from, size_t size) {
  unsigned char s8 = size;
  return __builtin_memmove(to, from, s8);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memmove8>:
  endbr64
  movzbl %dl,%edx
  jmp    1050 <__builtin_memmove@plt>
```

assistant: ```c
void *memmove8(void *to, const void *from, size_t size) {
  unsigned char s8 = size;
  return __builtin_memmove(to, from, s8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memmove8>:
  endbr64
  movzbl %dl,%edx
  jmp    1050 <__builtin_memmove@plt>
```

assistant: ```c
void *memmove8(void *to, const void *from, size_t size) {
  unsigned char s8 = size;
  return __builtin_memmove(to, from, s8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_vec_uint16_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L7
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x7,-0x4(%rbp)
  jle    L13
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type_infered: string
name: extract_symbolic_data
arguments: label: D21
type_infered: string
name: extract_symbolic_data
arguments: label: D20
type_infered: string

tool: D27: {%04x

tool: D21: , %04x

tool: D20: }

assistant: ```c
void print_vec_uint16_hex(uint16_t v[8]) {
  int i = 0;
  printf("{%04x", v[i]);
  for (i = 1; i < 8; i++)
    printf(", %04x", v[i]);
  printf("}\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_vec_uint16_hex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    (%rdi),%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rbp),%rbx
  add    $0x20,%rbp
  lea    D11(%rip),%r12
L1:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L1
  lea    D19(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
type_guessed: string
name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D19
type_guessed: string

tool: D25: {%04x

tool: D11: , %04x

tool: D19: }

assistant: ```c
void print_vec_uint16_hex(uint16_t v[8]) {
  int i = 0;
  printf("{%04x", v[i]);
  for (i = 1; i < 8; i++)
    printf(", %04x", v[i]);
  printf("}\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_vec_uint16_hex>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D28(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%esi
  lea    D21(%rip),%rdi
  lea    0x4(%rbp),%rbx
  add    $0x20,%rbp
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L9
  pop    %rbx
  lea    D4(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D28
type: string
name: read_data
arguments: label: D21
type: string
name: read_data
arguments: label: D4
type: string

tool: D28: , %04x

tool: D21: {%04x

tool: D4: }

assistant: ```c
void print_vec_uint16_hex(uint16_t v[8]) {
  int i = 0;
  printf("{%04x", v[i]);
  for (i = 1; i < 8; i++)
    printf(", %04x", v[i]);
  printf("}\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_vec_uint16_hex>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D22(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%esi
  lea    D2(%rip),%rdi
  lea    0x4(%rbp),%rbx
  add    $0x20,%rbp
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L9
  pop    %rbx
  lea    D19(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: label: D22
type_infered: string
name: disassemble_data
arguments: label: D2
type_infered: string
name: disassemble_data
arguments: label: D19
type_infered: string

tool: D22: , %04x

tool: D2: {%04x

tool: D19: }

assistant: ```c
void print_vec_uint16_hex(uint16_t v[8]) {
  int i = 0;
  printf("{%04x", v[i]);
  for (i = 1; i < 8; i++)
    printf(", %04x", v[i]);
  printf("}\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x61,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bar(void) {
  char *nuller = 0;
  *nuller = 'a';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bar>:
  endbr64
  movb   $0x61,0x0
  ret
```

assistant: ```c
void bar(void) {
  char *nuller = 0;
  *nuller = 'a';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bar>:
  endbr64
  movb   $0x0,0x0
  ud2
```

assistant: ```c
void bar(void) {
  char *nuller = 0;
  *nuller = 'a';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  movb   $0x0,0x0
  ud2
```

assistant: ```c
void bar(void) {
  char *nuller = 0;
  *nuller = 'a';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<orf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x4f,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x52,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x52,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void orf(char *str) {
  *str = 0x4f;
  *str = 0x52;
  *str = 0x52;
}
```
user: What is the c source code of the assembly code below:

```asm
<orf>:
  endbr64
  movb   $0x52,(%rdi)
  ret
```

assistant: ```c
void orf(char *str) {
  *str = 0x4f;
  *str = 0x52;
  *str = 0x52;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<orf>:
  endbr64
  movb   $0x52,(%rdi)
  ret
```

assistant: ```c
void orf(char *str) {
  *str = 0x4f;
  *str = 0x52;
  *str = 0x52;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<orf>:
  endbr64
  movb   $0x52,(%rdi)
  ret
```

assistant: ```c
void orf(char *str) {
  *str = 0x4f;
  *str = 0x52;
  *str = 0x52;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hexchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  cltq
  lea    D2(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
char hexchar(int x) {
  static const char table[16] = "0123456789abcdef";
  return table[x & 15];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hexchar>:
  endbr64
  and    $0xf,%edi
  lea    D9(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

assistant: ```c
char hexchar(int x) {
  static const char table[16] = "0123456789abcdef";
  return table[x & 15];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hexchar>:
  endbr64
  and    $0xf,%edi
  lea    D0(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

assistant: ```c
char hexchar(int x) {
  static const char table[16] = "0123456789abcdef";
  return table[x & 15];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hexchar>:
  endbr64
  and    $0xf,%edi
  lea    D7(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

assistant: ```c
char hexchar(int x) {
  static const char table[16] = "0123456789abcdef";
  return table[x & 15];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <hej@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: Zjadles moje kanapki ?


assistant: ```c
int main() {
  hej();
  printf("Zjadles moje kanapki ?\n");
}
```