user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <elegirCantDigitos@plt>
  mov    %eax,%r13d
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,0x8(%rsp)
  mov    $0x4,%esi
  mov    %r13d,%edi
  call   <calloc@plt>
  test   %rbx,%rbx
  je     L90
  mov    %rax,%r15
  mov    %rbx,%rdi
  test   %rax,%rax
  je     L90
  mov    %r13d,%esi
  call   <generaAleatorio@plt>
  mov    $0xa,%edi
  call   <elegirNivel@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jle    L109
  lea    -0x1(%r13),%eax
  lea    0x4(%r15,%rax,4),%r12
  mov    $0x1,%r14d
  lea    D49(%rip),%rbp
  jmp    L40
L48:
  lea    D69(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L76
L28:
  lea    D34(%rip),%rdi
  call   <puts@plt>
L54:
  add    $0x1,%r14d
  cmp    %r14d,0x4(%rsp)
  jl     L109
L40:
  mov    %r13d,%esi
  mov    %r15,%rdi
  call   <leerNumero@plt>
  lea    D62(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L58
  mov    %r15,%rbx
L43:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L43
L58:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    0x8(%rsp),%rdi
  call   <coincideNumero@plt>
  test   %rax,%rax
  jne    L48
  cmp    %r14d,0x4(%rsp)
  je     L28
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L54
L109:
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L97
  mov    0x8(%rsp),%rcx
  mov    %rcx,%rbx
  lea    -0x1(%r13),%eax
  lea    0x4(%rcx,%rax,4),%r12
  lea    D49(%rip),%rbp
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L4
L97:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  jmp    L76
L90:
  mov    $0x0,%eax
L76:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D49
type_infered: string
name: parse_data
arguments: label: D69
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string
name: parse_data
arguments: label: D62
type_infered: string
name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D43
type_infered: string

tool: D49: %d

tool: D69: 
~~~ GANASTE! ~~~


tool: D34: 
~~~ Perdiste ~~~


tool: D62: Numero ingresado = 

tool: D29: 
~~~ Intenta de nuevo ~~~


tool: D43: El numero era: 

assistant: ```c
int main(void) {
  srand(time(0));
  int *incognita;
  int *numero;
  int digits, nivel, i, j;
  digits = elegirCantDigitos();
  incognita = malloc(digits * sizeof(int));
  numero = calloc(digits, sizeof(int));
  if (incognita == NULL || numero == NULL) {
    return 0;
  }
  generaAleatorio(incognita, digits);
  nivel = elegirNivel(10);
  for (i = 1; i <= nivel; i++) {
    leerNumero(numero, digits);
    printf("Numero ingresado = ");
    for (j = 0; j < digits; j++) {
      printf("%d", numero[j]);
    }
    printf("\n");
    if (coincideNumero(incognita, numero, digits)) {
      printf("\n~~~ GANASTE! ~~~\n\n");
      return 1;
    } else if (i == nivel)
      printf("\n~~~ Perdiste ~~~\n\n");
    else
      printf("\n~~~ Intenta de nuevo ~~~\n\n");
  }
  printf("El numero era: ");
  for (i = 0; i < digits; i++) {
    printf("%d", incognita[i]);
  }
  printf("\n");
  return 1;
}
```