ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rand_seq3>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  test   %esi,%esi
  jle    L9
  mov    %esi,%edx
  mov    $0x0,%eax
L34:
  mov    %eax,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L34
L9:
  cmp    $0x1,%r13d
  jle    L3
  lea    0x4(%r12),%rbp
  mov    $0x1,%ebx
L12:
  mov    %ebx,%edi
  call   <randInt@plt>
  lea    (%r12,%rax,4),%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,%r13d
  jne    L12
L3:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int rand_seq3(int A[], int N) {
  int i, j;
  for (i = 0; i < N; i++)
    A[i] = i;
  for (i = 1; i < N; i++)
    swap(&A[i], &A[randInt(i)]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<rand_seq3>:
  endbr64
  test   %esi,%esi
  jle    L27
  push   %r13
  movslq %esi,%rdx
  mov    %esi,%r13d
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L30:
  mov    %eax,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L30
  cmp    $0x1,%r13d
  jle    L21
  lea    0x4(%r12),%rbp
  mov    $0x1,%ebx
  nopl   (%rax)
L34:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <randInt@plt>
  mov    %rbp,%rdi
  add    $0x4,%rbp
  lea    (%r12,%rax,4),%rsi
  call   <swap@plt>
  cmp    %ebx,%r13d
  jne    L34
L21:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rand_seq3(int A[], int N) {
  int i, j;
  for (i = 0; i < N; i++)
    A[i] = i;
  for (i = 1; i < N; i++)
    swap(&A[i], &A[randInt(i)]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rand_seq3>:
  endbr64
  test   %esi,%esi
  jle    L42
  push   %r13
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%eax
  jbe    L82
  mov    %esi,%edx
  movdqa D11(%rip),%xmm0
  movdqa D12(%rip),%xmm2
  mov    %rdi,%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L53:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L53
  mov    %r12d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r12b
  je     L90
L80:
  movslq %eax,%rdx
  mov    %eax,0x0(%r13,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jle    L40
  add    $0x2,%eax
  mov    %edx,0x4(%r13,%rcx,1)
  cmp    %eax,%r12d
  jle    L90
  mov    %eax,0x8(%r13,%rcx,1)
L90:
  lea    0x4(%r13),%rbp
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L99:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <randInt@plt>
  mov    %rbp,%rdi
  add    $0x4,%rbp
  lea    0x0(%r13,%rax,4),%rsi
  call   <swap@plt>
  cmp    %ebx,%r12d
  jne    L99
L91:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L42:
  xor    %eax,%eax
  ret
L82:
  xor    %eax,%eax
  jmp    L80
L40:
  cmp    $0x1,%r12d
  jg     L90
  jmp    L91
```

tool_calls: name: unpack_data
arguments: data_tag: D11
data_type: byte[16]
name: unpack_data
arguments: data_tag: D12
data_type: byte[16]

tool: {"D11": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D12": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int rand_seq3(int A[], int N) {
  int i, j;
  for (i = 0; i < N; i++)
    A[i] = i;
  for (i = 1; i < N; i++)
    swap(&A[i], &A[randInt(i)]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_call>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <emit_load_imm@plt>
  mov    -0x8(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <emit1@plt>
  mov    -0x8(%rbp),%rax
  mov    $0xd0,%esi
  mov    %rax,%rdi
  call   <emit1@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_call(struct jit_state *state, void *target) {
  emit_load_imm(state, 0, (uintptr_t)target);
  emit1(state, 0xff);
  emit1(state, 0xd0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<emit_call>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <emit_load_imm@plt>
  mov    $0xff,%esi
  mov    %rbx,%rdi
  call   <emit1@plt>
  mov    $0xd0,%esi
  mov    %rbx,%rdi
  call   <emit1@plt>
  pop    %rbx
  ret
```

assistant: ```c
void emit_call(struct jit_state *state, void *target) {
  emit_load_imm(state, 0, (uintptr_t)target);
  emit1(state, 0xff);
  emit1(state, 0xd0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<emit_call>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rdi,%rbp
  xor    %esi,%esi
  call   <emit_load_imm@plt>
  mov    %rbp,%rdi
  mov    $0xff,%esi
  call   <emit1@plt>
  mov    %rbp,%rdi
  mov    $0xd0,%esi
  pop    %rbp
  jmp    1070 <emit1@plt>
```

assistant: ```c
void emit_call(struct jit_state *state, void *target) {
  emit_load_imm(state, 0, (uintptr_t)target);
  emit1(state, 0xff);
  emit1(state, 0xd0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<emit_call>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rdi,%rbp
  xor    %esi,%esi
  call   <emit_load_imm@plt>
  mov    %rbp,%rdi
  mov    $0xff,%esi
  call   <emit1@plt>
  mov    %rbp,%rdi
  mov    $0xd0,%esi
  pop    %rbp
  jmp    1070 <emit1@plt>
```

assistant: ```c
void emit_call(struct jit_state *state, void *target) {
  emit_load_imm(state, 0, (uintptr_t)target);
  emit1(state, 0xff);
  emit1(state, 0xd0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ssl_x509_load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    $0x0,%eax
  call   <ssl_init@plt>
  cmp    $0xffffffff,%eax
  jne    L56
  mov    $0x0,%eax
  jmp    L8
L56:
  mov    $0x0,%eax
  call   <SSLv23_server_method@plt>
  mov    %eax,%edi
  call   <SSL_CTX_new@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L17
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SSL_CTX_use_certificate_file@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jne    L67
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_get_certificate@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L79
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ssl_x509_refcount_inc@plt>
L79:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_free@plt>
  jmp    L47
L67:
  nop
  jmp    L47
L3:
  nop
L47:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_CTX_free@plt>
  jmp    L44
L17:
  nop
L44:
  mov    -0x18(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
X509 *ssl_x509_load(const char *filename) {
  X509 *crt = NULL;
  SSL_CTX *tmpctx;
  SSL *tmpssl;
  int rv;
  if (ssl_init() == -1)
    return NULL;
  tmpctx = SSL_CTX_new(SSLv23_server_method());
  if (!tmpctx)
    goto leave1;
  rv = SSL_CTX_use_certificate_file(tmpctx, filename, SSL_FILETYPE_PEM);
  if (rv != 1)
    goto leave2;
  tmpssl = SSL_new(tmpctx);
  if (!tmpssl)
    goto leave2;
  crt = SSL_get_certificate(tmpssl);
  if (crt)
    ssl_x509_refcount_inc(crt);
  SSL_free(tmpssl);
leave2:
  SSL_CTX_free(tmpctx);
leave1:
  return crt;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ssl_x509_load>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <ssl_init@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    $0x0,%eax
  call   <SSLv23_server_method@plt>
  mov    %eax,%edi
  call   <SSL_CTX_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L25
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <SSL_CTX_use_certificate_file@plt>
  mov    $0x0,%ebp
  cmp    $0x1,%eax
  je     L23
L42:
  mov    %rbx,%rdi
  call   <SSL_CTX_free@plt>
L10:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    %rbx,%rdi
  call   <SSL_new@plt>
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %rax,%rax
  je     L42
  mov    %rax,%rdi
  call   <SSL_get_certificate@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L31
  mov    %rax,%rdi
  call   <ssl_x509_refcount_inc@plt>
L31:
  mov    %r12,%rdi
  call   <SSL_free@plt>
  jmp    L42
L3:
  mov    $0x0,%ebp
  jmp    L10
L25:
  mov    %rax,%rbp
  jmp    L10
```

assistant: ```c
X509 *ssl_x509_load(const char *filename) {
  X509 *crt = NULL;
  SSL_CTX *tmpctx;
  SSL *tmpssl;
  int rv;
  if (ssl_init() == -1)
    return NULL;
  tmpctx = SSL_CTX_new(SSLv23_server_method());
  if (!tmpctx)
    goto leave1;
  rv = SSL_CTX_use_certificate_file(tmpctx, filename, SSL_FILETYPE_PEM);
  if (rv != 1)
    goto leave2;
  tmpssl = SSL_new(tmpctx);
  if (!tmpssl)
    goto leave2;
  crt = SSL_get_certificate(tmpssl);
  if (crt)
    ssl_x509_refcount_inc(crt);
  SSL_free(tmpssl);
leave2:
  SSL_CTX_free(tmpctx);
leave1:
  return crt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ssl_x509_load>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <ssl_init@plt>
  cmp    $0xffffffff,%eax
  je     L13
  xor    %eax,%eax
  call   <SSLv23_server_method@plt>
  mov    %eax,%edi
  call   <SSL_CTX_new@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L13
  mov    D6(%rip),%rax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <SSL_CTX_use_certificate_file@plt>
  cmp    $0x1,%eax
  je     L19
L24:
  xor    %r12d,%r12d
L54:
  mov    %rbp,%rdi
  call   <SSL_CTX_free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L19:
  mov    %rbp,%rdi
  call   <SSL_new@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L24
  mov    %rax,%rdi
  call   <SSL_get_certificate@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  mov    %rax,%rdi
  call   <ssl_x509_refcount_inc@plt>
L18:
  mov    %r13,%rdi
  call   <SSL_free@plt>
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
X509 *ssl_x509_load(const char *filename) {
  X509 *crt = NULL;
  SSL_CTX *tmpctx;
  SSL *tmpssl;
  int rv;
  if (ssl_init() == -1)
    return NULL;
  tmpctx = SSL_CTX_new(SSLv23_server_method());
  if (!tmpctx)
    goto leave1;
  rv = SSL_CTX_use_certificate_file(tmpctx, filename, SSL_FILETYPE_PEM);
  if (rv != 1)
    goto leave2;
  tmpssl = SSL_new(tmpctx);
  if (!tmpssl)
    goto leave2;
  crt = SSL_get_certificate(tmpssl);
  if (crt)
    ssl_x509_refcount_inc(crt);
  SSL_free(tmpssl);
leave2:
  SSL_CTX_free(tmpctx);
leave1:
  return crt;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ssl_x509_load>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <ssl_init@plt>
  cmp    $0xffffffff,%eax
  je     L30
  xor    %eax,%eax
  call   <SSLv23_server_method@plt>
  mov    %eax,%edi
  call   <SSL_CTX_new@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L30
  mov    D3(%rip),%rax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <SSL_CTX_use_certificate_file@plt>
  cmp    $0x1,%eax
  je     L15
L55:
  xor    %r12d,%r12d
L42:
  mov    %rbp,%rdi
  call   <SSL_CTX_free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L15:
  mov    %rbp,%rdi
  call   <SSL_new@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L55
  mov    %rax,%rdi
  call   <SSL_get_certificate@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
  mov    %rax,%rdi
  call   <ssl_x509_refcount_inc@plt>
L19:
  mov    %r13,%rdi
  call   <SSL_free@plt>
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
X509 *ssl_x509_load(const char *filename) {
  X509 *crt = NULL;
  SSL_CTX *tmpctx;
  SSL *tmpssl;
  int rv;
  if (ssl_init() == -1)
    return NULL;
  tmpctx = SSL_CTX_new(SSLv23_server_method());
  if (!tmpctx)
    goto leave1;
  rv = SSL_CTX_use_certificate_file(tmpctx, filename, SSL_FILETYPE_PEM);
  if (rv != 1)
    goto leave2;
  tmpssl = SSL_new(tmpctx);
  if (!tmpssl)
    goto leave2;
  crt = SSL_get_certificate(tmpssl);
  if (crt)
    ssl_x509_refcount_inc(crt);
  SSL_free(tmpssl);
leave2:
  SSL_CTX_free(tmpctx);
leave1:
  return crt;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sig_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <unmask_shutter@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D9: Caught INT signal - Exiting ...


assistant: ```c
void sig_handler(int signo) {
  printf("Caught INT signal - Exiting ...\n");
  unmask_shutter();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <unmask_shutter@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: Caught INT signal - Exiting ...


assistant: ```c
void sig_handler(int signo) {
  printf("Caught INT signal - Exiting ...\n");
  unmask_shutter();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <unmask_shutter@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4: Caught INT signal - Exiting ...


assistant: ```c
void sig_handler(int signo) {
  printf("Caught INT signal - Exiting ...\n");
  unmask_shutter();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <unmask_shutter@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: Caught INT signal - Exiting ...


assistant: ```c
void sig_handler(int signo) {
  printf("Caught INT signal - Exiting ...\n");
  unmask_shutter();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<call_echo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L35
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x6e,%al
  jne    L35
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <simple_echo@plt>
  jmp    L16
L35:
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L45
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x65,%al
  jne    L45
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <echo_e@plt>
  jmp    L16
L45:
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L39
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   1070 <echo_$@plt>
  jmp    L16
L39:
  mov    $0x1,%eax
  jmp    L80
L16:
  mov    $0x0,%eax
L80:
  leave
  ret
```

assistant: ```c
int call_echo(char **s, char **env) {
  if (s[1][0] == '-' && s[1][1] == 'n')
    simple_echo(s);
  else if (s[1][0] == '-' && s[1][1] == 'e')
    echo_e(s);
  else if (s[1][0] == '$')
    echo_$(s, env);
  else
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<call_echo>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rdx
  movzbl (%rdx),%eax
  cmp    $0x2d,%al
  je     L11
  mov    $0x1,%edx
  cmp    $0x24,%al
  je     L53
L66:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L11:
  movzbl 0x1(%rdx),%eax
  cmp    $0x6e,%al
  je     L18
  mov    $0x1,%edx
  cmp    $0x65,%al
  jne    L66
  mov    $0x0,%eax
  call   <echo_e@plt>
  mov    $0x0,%edx
  jmp    L66
L18:
  mov    $0x0,%eax
  call   <simple_echo@plt>
  mov    $0x0,%edx
  jmp    L66
L53:
  mov    $0x0,%eax
  call   1070 <echo_$@plt>
  mov    $0x0,%edx
  jmp    L66
```

assistant: ```c
int call_echo(char **s, char **env) {
  if (s[1][0] == '-' && s[1][1] == 'n')
    simple_echo(s);
  else if (s[1][0] == '-' && s[1][1] == 'e')
    echo_e(s);
  else if (s[1][0] == '$')
    echo_$(s, env);
  else
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<call_echo>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rdx
  movzbl (%rdx),%eax
  cmp    $0x2d,%al
  je     L4
  mov    $0x1,%r8d
  cmp    $0x24,%al
  je     L9
L3:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L9:
  xor    %eax,%eax
  call   1070 <echo_$@plt>
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movzbl 0x1(%rdx),%eax
  cmp    $0x6e,%al
  je     L52
  mov    $0x1,%r8d
  cmp    $0x65,%al
  jne    L3
  xor    %eax,%eax
  call   <echo_e@plt>
  xor    %r8d,%r8d
  jmp    L3
  xchg   %ax,%ax
L52:
  xor    %eax,%eax
  call   <simple_echo@plt>
  xor    %r8d,%r8d
  jmp    L3
```

assistant: ```c
int call_echo(char **s, char **env) {
  if (s[1][0] == '-' && s[1][1] == 'n')
    simple_echo(s);
  else if (s[1][0] == '-' && s[1][1] == 'e')
    echo_e(s);
  else if (s[1][0] == '$')
    echo_$(s, env);
  else
    return (1);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<call_echo>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rdx
  movzbl (%rdx),%eax
  cmp    $0x2d,%al
  je     L19
  mov    $0x1,%r8d
  cmp    $0x24,%al
  je     L5
L6:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  call   1070 <echo_$@plt>
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl 0x1(%rdx),%eax
  cmp    $0x6e,%al
  je     L11
  mov    $0x1,%r8d
  cmp    $0x65,%al
  jne    L6
  xor    %eax,%eax
  call   <echo_e@plt>
  xor    %r8d,%r8d
  jmp    L6
  xchg   %ax,%ax
L11:
  xor    %eax,%eax
  call   <simple_echo@plt>
  xor    %r8d,%r8d
  jmp    L6
```

assistant: ```c
int call_echo(char **s, char **env) {
  if (s[1][0] == '-' && s[1][1] == 'n')
    simple_echo(s);
  else if (s[1][0] == '-' && s[1][1] == 'e')
    echo_e(s);
  else if (s[1][0] == '$')
    echo_$(s, env);
  else
    return (1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<evf_input_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  jne    L48
  mov    $0xffffffff,%eax
  jmp    L4
L48:
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L46
  mov    $0xffffffff,%eax
  jmp    L4
L46:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int evf_input_compare(int fd, const char *path) {
  struct stat st1, st2;
  if (fstat(fd, &st1) == -1)
    return -1;
  if (stat(path, &st2) == -1)
    return -1;
  return st1.st_rdev == st2.st_rdev;
}
```
user: What is the c source code of the assembly code below?

```asm
<evf_input_compare>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L6
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L6
  mov    0x10(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  sete   %al
  movzbl %al,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x20,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int evf_input_compare(int fd, const char *path) {
  struct stat st1, st2;
  if (fstat(fd, &st1) == -1)
    return -1;
  if (stat(path, &st2) == -1)
    return -1;
  return st1.st_rdev == st2.st_rdev;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<evf_input_compare>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L0
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    0x10(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  sete   %al
  movzbl %al,%eax
L17:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%eax
  jmp    L17
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int evf_input_compare(int fd, const char *path) {
  struct stat st1, st2;
  if (fstat(fd, &st1) == -1)
    return -1;
  if (stat(path, &st2) == -1)
    return -1;
  return st1.st_rdev == st2.st_rdev;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<evf_input_compare>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L32
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L32
  mov    0x10(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  sete   %al
  movzbl %al,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0xffffffff,%eax
  jmp    L6
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int evf_input_compare(int fd, const char *path) {
  struct stat st1, st2;
  if (fstat(fd, &st1) == -1)
    return -1;
  if (stat(path, &st2) == -1)
    return -1;
  return st1.st_rdev == st2.st_rdev;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mon_assignhandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <monLock@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_assign_handler@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <monUnlock@plt>
  mov    -0x4(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
unsigned long mon_assignhandler(long hnum, unsigned long arg1, unsigned long arg2) {
  int ret;
  monLock();
  ret = _assign_handler(hnum, arg1, arg2);
  monUnlock();
  return (ret);
}
```