ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<brkstring>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    $0x0,%r15d
  jmp    L96
L73:
  add    $0x1,%rbx
  movb   $0x0,-0x1(%rbx)
L61:
  movzbl (%rbx),%ebp
  movsbl %bpl,%r12d
  mov    %r13,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <brkany@plt>
  test   %eax,%eax
  jne    L73
  test   %bpl,%bpl
  je     L17
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L17
  lea    D34(%rip),%rax
  mov    %rbx,(%rax,%r15,8)
L72:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L79
  movsbl %al,%ebp
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <brkany@plt>
  test   %eax,%eax
  jne    L79
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <brkany@plt>
  test   %eax,%eax
  je     L72
L79:
  add    $0x1,%r15
  cmp    $0x19,%r15
  je     L70
L96:
  mov    %r15d,0xc(%rsp)
  jmp    L61
L17:
  movb   $0x0,(%rbx)
  movslq 0xc(%rsp),%rax
  lea    D34(%rip),%rdx
  movq   $0x0,(%rdx,%rax,8)
L22:
  lea    D34(%rip),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L70:
  movq   $0x0,D10(%rip)
  jmp    L22
```

assistant: ```c
char **brkstring(strg, brksep, brkterm)
char *strg;
char *brksep, *brkterm;
{
  register char c, *sp;
  static char *broken[25 + 1];
  int bi;
  sp = strg;
  for (bi = 0; bi < 25; bi++) {
    while (brkany(c = *sp, brksep))
      *sp++ = 0;
    if (!c || brkany(c, brkterm)) {
      *sp = 0;
      broken[bi] = 0;
      return (broken);
    }
    broken[bi] = sp;
    while ((c = *++sp) && !brkany(c, brksep) && !brkany(c, brkterm))
      ;
  }
  broken[25] = 0;
  return (broken);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<brkstring>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L12:
  mov    %r13d,0xc(%rsp)
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L76:
  movb   $0x0,(%r14)
  add    $0x1,%r14
L68:
  movsbl (%r14),%r15d
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L76
  test   %r15b,%r15b
  je     L49
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L49
  lea    D15(%rip),%rax
  mov    %r14,(%rax,%r13,8)
  jmp    L83
L67:
  movsbl %dil,%r15d
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L10
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L10
L83:
  movzbl 0x1(%r14),%edi
  add    $0x1,%r14
  test   %dil,%dil
  jne    L67
L10:
  add    $0x1,%r13
  cmp    $0x19,%r13
  jne    L12
  movq   $0x0,D9(%rip)
  jmp    L90
L49:
  movslq 0xc(%rsp),%r15
  lea    D15(%rip),%rax
  movb   $0x0,(%r14)
  movq   $0x0,(%rax,%r15,8)
L90:
  add    $0x18,%rsp
  lea    D15(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **brkstring(strg, brksep, brkterm)
char *strg;
char *brksep, *brkterm;
{
  register char c, *sp;
  static char *broken[25 + 1];
  int bi;
  sp = strg;
  for (bi = 0; bi < 25; bi++) {
    while (brkany(c = *sp, brksep))
      *sp++ = 0;
    if (!c || brkany(c, brkterm)) {
      *sp = 0;
      broken[bi] = 0;
      return (broken);
    }
    broken[bi] = sp;
    while ((c = *++sp) && !brkany(c, brksep) && !brkany(c, brkterm))
      ;
  }
  broken[25] = 0;
  return (broken);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<brkstring>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L40:
  mov    %r13d,0xc(%rsp)
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L1:
  movb   $0x0,(%r14)
  add    $0x1,%r14
L33:
  movsbl (%r14),%r15d
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L1
  test   %r15b,%r15b
  je     L64
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L64
  lea    D16(%rip),%rax
  mov    %r14,(%rax,%r13,8)
  jmp    L71
L2:
  movsbl %dil,%r15d
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L94
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <brkany@plt>
  test   %eax,%eax
  jne    L94
L71:
  movzbl 0x1(%r14),%edi
  add    $0x1,%r14
  test   %dil,%dil
  jne    L2
L94:
  add    $0x1,%r13
  cmp    $0x19,%r13
  jne    L40
  movq   $0x0,D19(%rip)
  jmp    L85
L64:
  movslq 0xc(%rsp),%r15
  lea    D16(%rip),%rax
  movb   $0x0,(%r14)
  movq   $0x0,(%rax,%r15,8)
L85:
  add    $0x18,%rsp
  lea    D16(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **brkstring(strg, brksep, brkterm)
char *strg;
char *brksep, *brkterm;
{
  register char c, *sp;
  static char *broken[25 + 1];
  int bi;
  sp = strg;
  for (bi = 0; bi < 25; bi++) {
    while (brkany(c = *sp, brksep))
      *sp++ = 0;
    if (!c || brkany(c, brkterm)) {
      *sp = 0;
      broken[bi] = 0;
      return (broken);
    }
    broken[bi] = sp;
    while ((c = *++sp) && !brkany(c, brksep) && !brkany(c, brkterm))
      ;
  }
  broken[25] = 0;
  return (broken);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L59
L41:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L46
L57:
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L4
  cmpl   $0x0,-0xc(%rbp)
  jg     L57
L4:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L59:
  cmpl   $0x0,-0xc(%rbp)
  jle    L3
  cmpl   $0x0,-0x10(%rbp)
  jg     L41
L3:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  int tmp;
  int xtmp;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (y > 0 && x > 0) {
    tmp = y;
    xtmp = x;
    while (xtmp >= y && y > 0) {
      xtmp = xtmp - y;
    }
    y = xtmp;
    x = tmp;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jle    L46
  test   %ebx,%ebx
  jg     L3
L46:
  mov    $0x0,%eax
  pop    %rbx
  ret
L28:
  sub    %eax,%ebx
  cmp    %eax,%ebx
  jge    L28
L27:
  test   %ebx,%ebx
  setg   %cl
  test   %eax,%eax
  setg   %dl
  test   %dl,%cl
  je     L46
  mov    %ebx,%edx
  mov    %eax,%ebx
  mov    %edx,%eax
L3:
  cmp    %eax,%ebx
  jge    L28
  jmp    L27
```

assistant: ```c
int main() {
  int x;
  int y;
  int tmp;
  int xtmp;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (y > 0 && x > 0) {
    tmp = y;
    xtmp = x;
    while (xtmp >= y && y > 0) {
      xtmp = xtmp - y;
    }
    y = xtmp;
    x = tmp;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jle    L3
  test   %ebx,%ebx
  jle    L3
  nopl   (%rax)
L31:
  cmp    %eax,%ebx
  jl     L0
  nopl   0x0(%rax)
L17:
  sub    %eax,%ebx
  cmp    %eax,%ebx
  jge    L17
  test   %ebx,%ebx
  jle    L3
L0:
  mov    %ebx,%edx
  mov    %eax,%ebx
  mov    %edx,%eax
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  int tmp;
  int xtmp;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (y > 0 && x > 0) {
    tmp = y;
    xtmp = x;
    while (xtmp >= y && y > 0) {
      xtmp = xtmp - y;
    }
    y = xtmp;
    x = tmp;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jle    L1
  test   %ebx,%ebx
  jle    L1
  nopl   (%rax)
L40:
  cmp    %eax,%ebx
  jl     L24
  nopl   0x0(%rax)
L15:
  sub    %eax,%ebx
  cmp    %eax,%ebx
  jge    L15
  test   %ebx,%ebx
  jle    L1
L24:
  mov    %ebx,%edx
  mov    %eax,%ebx
  mov    %edx,%eax
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  int tmp;
  int xtmp;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (y > 0 && x > 0) {
    tmp = y;
    xtmp = x;
    while (xtmp >= y && y > 0) {
      xtmp = xtmp - y;
    }
    y = xtmp;
    x = tmp;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<InitializeOS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <CommandInitialize@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0x1,%edi
  call   <CommandInitialize@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0x0,%esi
  mov    $0x400f7080,%edi
  call   <McDevIf_AddPacket@plt>
  mov    $0x0,%eax
  call   <McDevIf_ExecutePacket@plt>
  mov    %rax,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
signed long InitializeOS(void) {
  signed long sdRet;
  sdRet = CommandInitialize((0UL));
  if (((signed long)0) == sdRet) {
    sdRet = CommandInitialize((1UL));
    if (((signed long)0) == sdRet) {
      McDevIf_AddPacket(((0x40000000UL) | (0x000F0000UL) | (((unsigned long)(112)) << 8) | (unsigned long)(0x80)), 0);
      sdRet = McDevIf_ExecutePacket();
    }
  }
  return sdRet;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InitializeOS>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <CommandInitialize@plt>
  test   %rax,%rax
  je     L9
L22:
  add    $0x8,%rsp
  ret
L9:
  mov    $0x1,%edi
  call   <CommandInitialize@plt>
  test   %rax,%rax
  jne    L22
  mov    $0x0,%esi
  mov    $0x400f7080,%edi
  call   <McDevIf_AddPacket@plt>
  mov    $0x0,%eax
  call   <McDevIf_ExecutePacket@plt>
  jmp    L22
```

assistant: ```c
signed long InitializeOS(void) {
  signed long sdRet;
  sdRet = CommandInitialize((0UL));
  if (((signed long)0) == sdRet) {
    sdRet = CommandInitialize((1UL));
    if (((signed long)0) == sdRet) {
      McDevIf_AddPacket(((0x40000000UL) | (0x000F0000UL) | (((unsigned long)(112)) << 8) | (unsigned long)(0x80)), 0);
      sdRet = McDevIf_ExecutePacket();
    }
  }
  return sdRet;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InitializeOS>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <CommandInitialize@plt>
  test   %rax,%rax
  je     L19
L15:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L19:
  mov    $0x1,%edi
  call   <CommandInitialize@plt>
  test   %rax,%rax
  jne    L15
  xor    %esi,%esi
  mov    $0x400f7080,%edi
  call   <McDevIf_AddPacket@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <McDevIf_ExecutePacket@plt>
```

assistant: ```c
signed long InitializeOS(void) {
  signed long sdRet;
  sdRet = CommandInitialize((0UL));
  if (((signed long)0) == sdRet) {
    sdRet = CommandInitialize((1UL));
    if (((signed long)0) == sdRet) {
      McDevIf_AddPacket(((0x40000000UL) | (0x000F0000UL) | (((unsigned long)(112)) << 8) | (unsigned long)(0x80)), 0);
      sdRet = McDevIf_ExecutePacket();
    }
  }
  return sdRet;
}
```
user: Translate the below assembly code into C programming language:

```asm
<InitializeOS>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <CommandInitialize@plt>
  test   %rax,%rax
  je     L13
L5:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L13:
  mov    $0x1,%edi
  call   <CommandInitialize@plt>
  test   %rax,%rax
  jne    L5
  xor    %esi,%esi
  mov    $0x400f7080,%edi
  call   <McDevIf_AddPacket@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <McDevIf_ExecutePacket@plt>
```

assistant: ```c
signed long InitializeOS(void) {
  signed long sdRet;
  sdRet = CommandInitialize((0UL));
  if (((signed long)0) == sdRet) {
    sdRet = CommandInitialize((1UL));
    if (((signed long)0) == sdRet) {
      McDevIf_AddPacket(((0x40000000UL) | (0x000F0000UL) | (((unsigned long)(112)) << 8) | (unsigned long)(0x80)), 0);
      sdRet = McDevIf_ExecutePacket();
    }
  }
  return sdRet;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x2,-0x3c(%rbp)
  movl   $0x37,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x25,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x2c,-0x28(%rbp)
  movl   $0x15,-0x24(%rbp)
  movl   $0x21,-0x20(%rbp)
  movl   $0x130,-0x1c(%rbp)
  movl   $0x2d,-0x18(%rbp)
  movl   $0x10,-0x14(%rbp)
  movl   $0xc,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <mergeSort@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L16
L7:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x48(%rbp)
L16:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L7
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %d 

assistant: ```c
main() {
  int arr[] = {1, 2, 55, 4, 37, 3, 44, 21, 33, 304, 45, 16};
  int len = sizeof(arr) / 4;
  mergeSort(arr, 0, len - 1);
  int i;
  for (i = 0; i < len; i++) {
    printf("%d ", arr[i]);
  }
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x37,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x25,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x2c,0x18(%rsp)
  movl   $0x15,0x1c(%rsp)
  movl   $0x21,0x20(%rsp)
  movl   $0x130,0x24(%rsp)
  movl   $0x2d,0x28(%rsp)
  movl   $0x10,0x2c(%rsp)
  mov    %rsp,%rbx
  mov    $0xb,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <mergeSort@plt>
  lea    0x30(%rsp),%r12
  lea    D1(%rip),%rbp
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L1
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: %d 

assistant: ```c
main() {
  int arr[] = {1, 2, 55, 4, 37, 3, 44, 21, 33, 304, 45, 16};
  int len = sizeof(arr) / 4;
  mergeSort(arr, 0, len - 1);
  int i;
  for (i = 0; i < len; i++) {
    printf("%d ", arr[i]);
  }
  getchar();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000037,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x300000025,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x150000002c,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x13000000021,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x100000002d,%rax
  mov    %rax,0x28(%rsp)
  call   <mergeSort@plt>
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: %d 

assistant: ```c
main() {
  int arr[] = {1, 2, 55, 4, 37, 3, 44, 21, 33, 304, 45, 16};
  int len = sizeof(arr) / 4;
  mergeSort(arr, 0, len - 1);
  int i;
  for (i = 0; i < len; i++) {
    printf("%d ", arr[i]);
  }
  getchar();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D39(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <mergeSort@plt>
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L19
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
type_infered: string
name: disassemble_data
arguments: tag: D3
type_infered: byte[16]
name: disassemble_data
arguments: tag: D39
type_infered: byte[16]
name: disassemble_data
arguments: tag: D2
type_infered: byte[16]

tool: D25: %d 

tool: {"D3": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x37,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D39": [0x25,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x2c,0x00,0x00,0x00,0x15,0x00,0x00,0x00]}

tool: {"D2": [0x21,0x00,0x00,0x00,0x30,0x01,0x00,0x00,0x2d,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

assistant: ```c
main() {
  int arr[] = {1, 2, 55, 4, 37, 3, 44, 21, 33, 304, 45, 16};
  int len = sizeof(arr) / 4;
  mergeSort(arr, 0, len - 1);
  int i;
  for (i = 0; i < len; i++) {
    printf("%d ", arr[i]);
  }
  getchar();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vmaior>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L11
  mov    -0x8(%rbp),%rax
  jmp    L3
L11:
  mov    -0x10(%rbp),%rax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int *vmaior(int *valor1, int *valor2) {
  if (*valor1 >= *valor2) {
    return valor1;
  } else {
    return valor2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<vmaior>:
  endbr64
  mov    %rdi,%rax
  mov    (%rsi),%edx
  cmp    %edx,(%rdi)
  cmovl  %rsi,%rax
  ret
```

assistant: ```c
int *vmaior(int *valor1, int *valor2) {
  if (*valor1 >= *valor2) {
    return valor1;
  } else {
    return valor2;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vmaior>:
  endbr64
  mov    (%rsi),%edx
  mov    %rdi,%rax
  cmp    %edx,(%rdi)
  cmovl  %rsi,%rax
  ret
```

assistant: ```c
int *vmaior(int *valor1, int *valor2) {
  if (*valor1 >= *valor2) {
    return valor1;
  } else {
    return valor2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<vmaior>:
  endbr64
  mov    (%rsi),%edx
  mov    %rdi,%rax
  cmp    %edx,(%rdi)
  cmovl  %rsi,%rax
  ret
```

assistant: ```c
int *vmaior(int *valor1, int *valor2) {
  if (*valor1 >= *valor2) {
    return valor1;
  } else {
    return valor2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  xor    $0x29be1cdb,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rsi
  test   %rsi,%rsi
  je     L4
  mov    $0x0,%eax
L6:
  cmp    %rax,(%rsp)
  je     L28
  movq   $0x0,(%rsp,%rax,8)
L21:
  add    $0x2,%rax
  cmp    %rsi,%rax
  jb     L6
L4:
  mov    (%rsp),%rax
  or     $0x32f75143,%rax
  xor    $0xe161c,%rax
  mov    %rax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  ret
L28:
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  mov    %rax,%rdi
  shl    %cl,%rdi
  mov    %rdi,%rcx
  mov    %rdi,(%rsp,%rax,8)
  shl    $0x10,%rdi
  sar    $0x38,%rdi
  mov    %dil,0x4(%rsp)
  shl    $0x18,%rcx
  sar    $0x38,%rcx
  mov    %cl,0x5(%rsp)
  jmp    L21
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  char copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] != local1) {
        if (state[0UL] == local1) {
          copy11 = *((unsigned short *)(&state[0UL]) + 2);
          *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
          state[local1] <<= (state[local1] & 7UL) | 1UL;
        } else {
          copy12 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = copy12;
          copy12 = *((char *)(&state[0UL]) + 7);
          *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy12;
          state[local1] = state[0UL] ^ state[local1];
        }
      } else {
        state[local1] <<= ((state[local1] >> 2UL) & 7UL) | 1UL;
        copy13 = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 855068995UL) ^ 923164UL;
  }
}
```