ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<uwsgi_hook_retryrpc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x2,%edi
  call   <sleep@plt>
L17:
  mov    %rbx,%rdi
  call   <uwsgi_hook_rpc@plt>
  test   %eax,%eax
  jne    L9
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int uwsgi_hook_retryrpc(char *arg) {
  for (;;) {
    int ret = uwsgi_hook_rpc(arg);
    if (!ret)
      break;
    sleep(2);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uwsgi_hook_retryrpc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x2,%edi
  call   <sleep@plt>
L8:
  mov    %rbx,%rdi
  call   <uwsgi_hook_rpc@plt>
  test   %eax,%eax
  jne    L17
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int uwsgi_hook_retryrpc(char *arg) {
  for (;;) {
    int ret = uwsgi_hook_rpc(arg);
    if (!ret)
      break;
    sleep(2);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mandel_iterations_at_point>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  mov    %edi,-0x44(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L28
L15:
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x38(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x40(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  addl   $0x1,-0x24(%rbp)
L28:
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  D4(%rip),%xmm0
  comisd %xmm1,%xmm0
  jb     L26
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L15
L26:
  mov    -0x24(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

assistant: ```c
int mandel_iterations_at_point(double x, double y, int max) {
  double x0 = x;
  double y0 = y;
  int iter = 0;
  while ((x * x + y * y <= 4) && iter < max) {
    double xt = x * x - y * y + x0;
    double yt = 2 * x * y + y0;
    x = xt;
    y = yt;
    ++iter;
  }
  return iter;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mandel_iterations_at_point>:
  endbr64
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm3
  movapd %xmm1,%xmm6
  mulsd  %xmm1,%xmm6
  movapd %xmm3,%xmm2
  addsd  %xmm6,%xmm2
  movsd  D2(%rip),%xmm4
  comisd %xmm2,%xmm4
  jb     L8
  test   %edi,%edi
  jle    L8
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm5
  mov    $0x0,%eax
  movapd %xmm4,%xmm7
L13:
  movapd %xmm5,%xmm4
  subsd  %xmm6,%xmm3
  movapd %xmm3,%xmm5
  addsd  %xmm0,%xmm5
  addsd  %xmm4,%xmm4
  mulsd  %xmm4,%xmm2
  addsd  %xmm1,%xmm2
  add    $0x1,%eax
  movapd %xmm5,%xmm3
  mulsd  %xmm5,%xmm3
  movapd %xmm2,%xmm6
  mulsd  %xmm2,%xmm6
  movapd %xmm3,%xmm4
  addsd  %xmm6,%xmm4
  comisd %xmm4,%xmm7
  jb     L1
  cmp    %eax,%edi
  jg     L13
  ret
L8:
  mov    $0x0,%eax
L1:
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

assistant: ```c
int mandel_iterations_at_point(double x, double y, int max) {
  double x0 = x;
  double y0 = y;
  int iter = 0;
  while ((x * x + y * y <= 4) && iter < max) {
    double xt = x * x - y * y + x0;
    double yt = 2 * x * y + y0;
    x = xt;
    y = yt;
    ++iter;
  }
  return iter;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mandel_iterations_at_point>:
  endbr64
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm6
  movsd  D6(%rip),%xmm7
  mulsd  %xmm0,%xmm3
  mulsd  %xmm1,%xmm6
  movapd %xmm3,%xmm2
  addsd  %xmm6,%xmm2
  comisd %xmm2,%xmm7
  jb     L13
  test   %edi,%edi
  jle    L13
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm5
  xor    %eax,%eax
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L38:
  cmp    %eax,%edi
  jle    L12
L2:
  movapd %xmm5,%xmm4
  subsd  %xmm6,%xmm3
  add    $0x1,%eax
  addsd  %xmm4,%xmm4
  movapd %xmm3,%xmm5
  mulsd  %xmm4,%xmm2
  addsd  %xmm0,%xmm5
  movapd %xmm5,%xmm3
  mulsd  %xmm5,%xmm3
  addsd  %xmm1,%xmm2
  movapd %xmm2,%xmm6
  mulsd  %xmm2,%xmm6
  movapd %xmm3,%xmm4
  addsd  %xmm6,%xmm4
  comisd %xmm4,%xmm7
  jae    L38
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

assistant: ```c
int mandel_iterations_at_point(double x, double y, int max) {
  double x0 = x;
  double y0 = y;
  int iter = 0;
  while ((x * x + y * y <= 4) && iter < max) {
    double xt = x * x - y * y + x0;
    double yt = 2 * x * y + y0;
    x = xt;
    y = yt;
    ++iter;
  }
  return iter;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mandel_iterations_at_point>:
  endbr64
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm6
  movsd  D6(%rip),%xmm7
  mulsd  %xmm0,%xmm3
  mulsd  %xmm1,%xmm6
  movapd %xmm3,%xmm2
  addsd  %xmm6,%xmm2
  comisd %xmm2,%xmm7
  jb     L12
  test   %edi,%edi
  jle    L12
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm5
  xor    %eax,%eax
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    %eax,%edi
  jle    L28
L20:
  movapd %xmm5,%xmm4
  subsd  %xmm6,%xmm3
  add    $0x1,%eax
  addsd  %xmm4,%xmm4
  movapd %xmm3,%xmm5
  mulsd  %xmm4,%xmm2
  addsd  %xmm0,%xmm5
  movapd %xmm5,%xmm3
  mulsd  %xmm5,%xmm3
  addsd  %xmm1,%xmm2
  movapd %xmm2,%xmm6
  mulsd  %xmm2,%xmm6
  movapd %xmm3,%xmm4
  addsd  %xmm6,%xmm4
  comisd %xmm4,%xmm7
  jae    L10
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

assistant: ```c
int mandel_iterations_at_point(double x, double y, int max) {
  double x0 = x;
  double y0 = y;
  int iter = 0;
  while ((x * x + y * y <= 4) && iter < max) {
    double xt = x * x - y * y + x0;
    double yt = 2 * x * y + y0;
    x = xt;
    y = yt;
    ++iter;
  }
  return iter;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
  mov    $0x56000010,%eax
  movl   $0x0,(%rax)
  mov    $0x56000018,%eax
  movl   $0x0,(%rax)
  mov    $0x56000010,%eax
  movl   $0x15400,(%rax)
L56:
  mov    $0x56000054,%eax
  mov    (%rax),%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L41
  mov    $0x56000014,%eax
  mov    (%rax),%eax
  mov    $0x56000014,%edx
  or     $0x20,%eax
  mov    %eax,(%rdx)
  jmp    L34
L41:
  mov    $0x56000014,%eax
  mov    (%rax),%eax
  mov    $0x56000014,%edx
  and    $0xffffffdf,%eax
  mov    %eax,(%rdx)
L34:
  mov    -0x8(%rbp),%rax
  and    $0x2,%eax
  test   %rax,%rax
  je     L30
  mov    $0x56000014,%eax
  mov    (%rax),%eax
  mov    $0x56000014,%edx
  or     $0x40,%eax
  mov    %eax,(%rdx)
  jmp    L63
L30:
  mov    $0x56000014,%eax
  mov    (%rax),%eax
  mov    $0x56000014,%edx
  and    $0xffffffbf,%eax
  mov    %eax,(%rdx)
L63:
  mov    -0x8(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L62
  mov    $0x56000014,%eax
  mov    (%rax),%eax
  mov    $0x56000014,%edx
  or     $0x80,%al
  mov    %eax,(%rdx)
  jmp    L13
L62:
  mov    $0x56000014,%eax
  mov    (%rax),%eax
  mov    $0x56000014,%edx
  and    $0x7f,%al
  mov    %eax,(%rdx)
L13:
  mov    -0x8(%rbp),%rax
  and    $0x10,%eax
  test   %rax,%rax
  je     L28
  mov    $0x56000014,%eax
  mov    (%rax),%eax
  mov    $0x56000014,%edx
  or     $0x1,%ah
  mov    %eax,(%rdx)
  jmp    L56
L28:
  mov    $0x56000014,%eax
  mov    (%rax),%eax
  mov    $0x56000014,%edx
  and    $0xfe,%ah
  mov    %eax,(%rdx)
  jmp    L56
```

assistant: ```c
int atime(void) {
  unsigned long i = 0;
  (*(volatile unsigned *)0x56000010) = 0X0;
  (*(volatile unsigned *)0x56000018) = 0X0;
  (*(volatile unsigned *)0x56000010) = (1 << (5 * 2)) | (1 << (6 * 2)) | (1 << (7 * 2)) | (1 << (8 * 2));
  while (1) {
    i = (*(volatile unsigned *)0x56000054);
    if (i & (1 << 0))
      (*(volatile unsigned *)0x56000014) |= (1 << 5);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 5);
    if (i & (1 << 1))
      (*(volatile unsigned *)0x56000014) |= (1 << 6);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 6);
    if (i & (1 << 2))
      (*(volatile unsigned *)0x56000014) |= (1 << 7);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 7);
    if (i & (1 << 4))
      (*(volatile unsigned *)0x56000014) |= (1 << 8);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 8);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atime>:
  endbr64
  movl   $0x0,0x56000010
  movl   $0x0,0x56000018
  movl   $0x15400,0x56000010
  jmp    L23
L8:
  mov    0x56000014,%edx
  and    $0xffffffdf,%edx
  mov    %edx,0x56000014
  jmp    L43
L13:
  mov    0x56000014,%edx
  and    $0xffffffbf,%edx
  mov    %edx,0x56000014
  jmp    L31
L75:
  mov    0x56000014,%edx
  and    $0x7f,%dl
  mov    %edx,0x56000014
  jmp    L52
L69:
  mov    0x56000014,%eax
  or     $0x1,%ah
  mov    %eax,0x56000014
L23:
  mov    0x56000054,%eax
  test   $0x1,%al
  je     L8
  mov    0x56000014,%edx
  or     $0x20,%edx
  mov    %edx,0x56000014
L43:
  test   $0x2,%al
  je     L13
  mov    0x56000014,%edx
  or     $0x40,%edx
  mov    %edx,0x56000014
L31:
  test   $0x4,%al
  je     L75
  mov    0x56000014,%edx
  or     $0x80,%dl
  mov    %edx,0x56000014
L52:
  test   $0x10,%al
  jne    L69
  mov    0x56000014,%eax
  and    $0xfe,%ah
  mov    %eax,0x56000014
  jmp    L23
```

assistant: ```c
int atime(void) {
  unsigned long i = 0;
  (*(volatile unsigned *)0x56000010) = 0X0;
  (*(volatile unsigned *)0x56000018) = 0X0;
  (*(volatile unsigned *)0x56000010) = (1 << (5 * 2)) | (1 << (6 * 2)) | (1 << (7 * 2)) | (1 << (8 * 2));
  while (1) {
    i = (*(volatile unsigned *)0x56000054);
    if (i & (1 << 0))
      (*(volatile unsigned *)0x56000014) |= (1 << 5);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 5);
    if (i & (1 << 1))
      (*(volatile unsigned *)0x56000014) |= (1 << 6);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 6);
    if (i & (1 << 2))
      (*(volatile unsigned *)0x56000014) |= (1 << 7);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 7);
    if (i & (1 << 4))
      (*(volatile unsigned *)0x56000014) |= (1 << 8);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 8);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<atime>:
  endbr64
  movl   $0x0,0x56000010
  movl   $0x0,0x56000018
  movl   $0x15400,0x56000010
  nopl   (%rax)
L14:
  mov    0x56000054,%eax
  mov    0x56000014,%edx
  test   $0x1,%al
  je     L65
  or     $0x20,%edx
  mov    %edx,0x56000014
  mov    0x56000014,%edx
  test   $0x2,%al
  je     L88
L51:
  or     $0x40,%edx
  mov    %edx,0x56000014
  mov    0x56000014,%edx
  test   $0x4,%al
  je     L74
L54:
  or     $0x80,%dl
  test   $0x10,%al
  mov    %edx,0x56000014
  mov    0x56000014,%eax
  je     L23
L17:
  or     $0x1,%ah
  mov    %eax,0x56000014
  jmp    L14
  nopl   (%rax)
L65:
  and    $0xffffffdf,%edx
  mov    %edx,0x56000014
  mov    0x56000014,%edx
  test   $0x2,%al
  jne    L51
L88:
  and    $0xffffffbf,%edx
  mov    %edx,0x56000014
  mov    0x56000014,%edx
  test   $0x4,%al
  jne    L54
L74:
  and    $0x7f,%dl
  test   $0x10,%al
  mov    %edx,0x56000014
  mov    0x56000014,%eax
  jne    L17
L23:
  and    $0xfe,%ah
  mov    %eax,0x56000014
  jmp    L14
```

assistant: ```c
int atime(void) {
  unsigned long i = 0;
  (*(volatile unsigned *)0x56000010) = 0X0;
  (*(volatile unsigned *)0x56000018) = 0X0;
  (*(volatile unsigned *)0x56000010) = (1 << (5 * 2)) | (1 << (6 * 2)) | (1 << (7 * 2)) | (1 << (8 * 2));
  while (1) {
    i = (*(volatile unsigned *)0x56000054);
    if (i & (1 << 0))
      (*(volatile unsigned *)0x56000014) |= (1 << 5);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 5);
    if (i & (1 << 1))
      (*(volatile unsigned *)0x56000014) |= (1 << 6);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 6);
    if (i & (1 << 2))
      (*(volatile unsigned *)0x56000014) |= (1 << 7);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 7);
    if (i & (1 << 4))
      (*(volatile unsigned *)0x56000014) |= (1 << 8);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 8);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atime>:
  endbr64
  movl   $0x0,0x56000010
  movl   $0x0,0x56000018
  movl   $0x15400,0x56000010
  nopl   (%rax)
L77:
  mov    0x56000054,%eax
  mov    0x56000014,%edx
  test   $0x1,%al
  je     L60
  or     $0x20,%edx
  mov    %edx,0x56000014
  mov    0x56000014,%edx
  test   $0x2,%al
  je     L10
L41:
  or     $0x40,%edx
  mov    %edx,0x56000014
  mov    0x56000014,%edx
  test   $0x4,%al
  je     L11
L4:
  or     $0x80,%dl
  test   $0x10,%al
  mov    %edx,0x56000014
  mov    0x56000014,%eax
  je     L22
L8:
  or     $0x1,%ah
  mov    %eax,0x56000014
  jmp    L77
  nopl   (%rax)
L60:
  and    $0xffffffdf,%edx
  mov    %edx,0x56000014
  mov    0x56000014,%edx
  test   $0x2,%al
  jne    L41
L10:
  and    $0xffffffbf,%edx
  mov    %edx,0x56000014
  mov    0x56000014,%edx
  test   $0x4,%al
  jne    L4
L11:
  and    $0x7f,%dl
  test   $0x10,%al
  mov    %edx,0x56000014
  mov    0x56000014,%eax
  jne    L8
L22:
  and    $0xfe,%ah
  mov    %eax,0x56000014
  jmp    L77
```

assistant: ```c
int atime(void) {
  unsigned long i = 0;
  (*(volatile unsigned *)0x56000010) = 0X0;
  (*(volatile unsigned *)0x56000018) = 0X0;
  (*(volatile unsigned *)0x56000010) = (1 << (5 * 2)) | (1 << (6 * 2)) | (1 << (7 * 2)) | (1 << (8 * 2));
  while (1) {
    i = (*(volatile unsigned *)0x56000054);
    if (i & (1 << 0))
      (*(volatile unsigned *)0x56000014) |= (1 << 5);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 5);
    if (i & (1 << 1))
      (*(volatile unsigned *)0x56000014) |= (1 << 6);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 6);
    if (i & (1 << 2))
      (*(volatile unsigned *)0x56000014) |= (1 << 7);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 7);
    if (i & (1 << 4))
      (*(volatile unsigned *)0x56000014) |= (1 << 8);
    else
      (*(volatile unsigned *)0x56000014) &= ~(1 << 8);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recover_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void recover_memory(int *p) {
  free(p);
  p = NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<recover_memory>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void recover_memory(int *p) {
  free(p);
  p = NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recover_memory>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void recover_memory(int *p) {
  free(p);
  p = NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<recover_memory>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void recover_memory(int *p) {
  free(p);
  p = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<doindent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L3:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L3
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4:    

assistant: ```c
void doindent(unsigned depth) {
  unsigned i;
  for (i = 0; i < depth; i++) {
    printf("   ");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<doindent>:
  endbr64
  test   %edi,%edi
  je     L17
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L12:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0:    

assistant: ```c
void doindent(unsigned depth) {
  unsigned i;
  for (i = 0; i < depth; i++) {
    printf("   ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<doindent>:
  endbr64
  test   %edi,%edi
  je     L10
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5:    

assistant: ```c
void doindent(unsigned depth) {
  unsigned i;
  for (i = 0; i < depth; i++) {
    printf("   ");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<doindent>:
  endbr64
  test   %edi,%edi
  je     L5
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1:    

assistant: ```c
void doindent(unsigned depth) {
  unsigned i;
  for (i = 0; i < depth; i++) {
    printf("   ");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jg     L15
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L35
L15:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L4
  movl   $0x1,-0xc(%rbp)
  jmp    L35
L4:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  mov    %eax,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D9
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string

tool: D16: 
 input number:

tool: D9: %d

tool: D4: 
 %d

assistant: ```c
void main(void) {
  int n, res;
  printf("\n input number:");
  scanf("%d", &n);
  if (n <= 0)
    res = -1;
  else {
    if (n == 1)
      res = 1;
    else
      res = is_prime(n);
  }
  printf("\n %d", res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L30
  cmp    $0x1,%esi
  je     L8
  mov    %esi,%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  jmp    L8
L30:
  mov    $0xffffffff,%esi
L8:
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string

tool: D7: 
 input number:

tool: D12: %d

tool: D8: 
 %d

assistant: ```c
void main(void) {
  int n, res;
  printf("\n input number:");
  scanf("%d", &n);
  if (n <= 0)
    res = -1;
  else {
    if (n == 1)
      res = 1;
    else
      res = is_prime(n);
  }
  printf("\n %d", res);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L21
  cmp    $0x1,%esi
  jne    L18
L45:
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  ret
L18:
  mov    %esi,%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  jmp    L45
L21:
  or     $0xffffffff,%esi
  jmp    L45
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string
name: unpack_data
arguments: data_label: D23
datatype: string

tool: D13: 
 input number:

tool: D5: %d

tool: D23: 
 %d

assistant: ```c
void main(void) {
  int n, res;
  printf("\n input number:");
  scanf("%d", &n);
  if (n <= 0)
    res = -1;
  else {
    if (n == 1)
      res = 1;
    else
      res = is_prime(n);
  }
  printf("\n %d", res);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L49
  cmp    $0x1,%esi
  jne    L6
L34:
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  ret
L6:
  mov    %esi,%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  jmp    L34
L49:
  or     $0xffffffff,%esi
  jmp    L34
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D2: 
 input number:

tool: D21: %d

tool: D4: 
 %d

assistant: ```c
void main(void) {
  int n, res;
  printf("\n input number:");
  scanf("%d", &n);
  if (n <= 0)
    res = -1;
  else {
    if (n == 1)
      res = 1;
    else
      res = is_prime(n);
  }
  printf("\n %d", res);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<edit_hosts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <endwin@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D4:  /usr/bin/ee  /etc/hosts

assistant: ```c
int edit_hosts(void) {
  endwin();
  system(" /usr/bin/ee "
         " /etc/hosts");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<edit_hosts>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <endwin@plt>
  lea    D3(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3:  /usr/bin/ee  /etc/hosts

assistant: ```c
int edit_hosts(void) {
  endwin();
  system(" /usr/bin/ee "
         " /etc/hosts");
  return 0;
}
```