ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<_dl_elf_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %rax,%rax
  je     L0
  movzbl 0x1(%rdi),%ecx
  test   %cl,%cl
  je     L0
  shl    $0x4,%rax
  movzbl %cl,%ecx
  add    %rcx,%rax
  movzbl 0x2(%rdi),%ecx
  test   %cl,%cl
  je     L0
  shl    $0x4,%rax
  movzbl %cl,%ecx
  add    %rcx,%rax
  movzbl 0x3(%rdi),%ecx
  test   %cl,%cl
  je     L0
  shl    $0x4,%rax
  movzbl %cl,%ecx
  add    %rcx,%rax
  movzbl 0x4(%rdi),%ecx
  test   %cl,%cl
  je     L0
  shl    $0x4,%rax
  movzbl %cl,%ecx
  add    %rcx,%rax
  lea    0x5(%rdi),%rcx
  movzbl 0x5(%rdi),%edx
  test   %dl,%dl
  je     L16
L69:
  shl    $0x4,%rax
  add    $0x1,%rcx
  movzbl %dl,%edx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x18,%rax
  and    $0xf0,%eax
  xor    %rdx,%rax
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L69
L16:
  and    $0xfffffff,%eax
L0:
  ret
```

assistant: ```c
unsigned int __attribute__((unused)) _dl_elf_hash(const char *name_arg) {
  const unsigned char *name = (const unsigned char *)name_arg;
  unsigned long int hash = *name;
  if (hash != 0 && name[1] != '\0') {
    hash = (hash << 4) + name[1];
    if (name[2] != '\0') {
      hash = (hash << 4) + name[2];
      if (name[3] != '\0') {
        hash = (hash << 4) + name[3];
        if (name[4] != '\0') {
          hash = (hash << 4) + name[4];
          name += 5;
          while (*name != '\0') {
            unsigned long int hi;
            hash = (hash << 4) + *name++;
            hi = hash & 0xf0000000;
            hash ^= hi >> 24;
          }
          hash &= 0x0fffffff;
        }
      }
    }
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_dl_elf_hash>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%rcx
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L3
  movzbl 0x1(%rcx),%edx
  test   %dl,%dl
  je     L53
  movzbl %dl,%eax
  movzbl 0x2(%rcx),%edx
  shl    $0x4,%rsi
  add    %rsi,%rax
  test   %dl,%dl
  je     L3
  shl    $0x4,%rax
  add    %rdx,%rax
  movzbl 0x3(%rcx),%edx
  test   %dl,%dl
  je     L3
  shl    $0x4,%rax
  add    %rdx,%rax
  movzbl 0x4(%rcx),%edx
  test   %dl,%dl
  je     L3
  shl    $0x4,%rax
  lea    0x5(%rcx),%rsi
  add    %rdx,%rax
  movzbl 0x5(%rcx),%edx
  test   %dl,%dl
  je     L3
  nopl   0x0(%rax)
L58:
  shl    $0x4,%rax
  add    $0x1,%rsi
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x18,%rax
  and    $0xf0,%eax
  xor    %rdx,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L58
  and    $0xfffffff,%eax
L3:
  ret
  nopw   0x0(%rax,%rax,1)
L53:
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((unused)) _dl_elf_hash(const char *name_arg) {
  const unsigned char *name = (const unsigned char *)name_arg;
  unsigned long int hash = *name;
  if (hash != 0 && name[1] != '\0') {
    hash = (hash << 4) + name[1];
    if (name[2] != '\0') {
      hash = (hash << 4) + name[2];
      if (name[3] != '\0') {
        hash = (hash << 4) + name[3];
        if (name[4] != '\0') {
          hash = (hash << 4) + name[4];
          name += 5;
          while (*name != '\0') {
            unsigned long int hi;
            hash = (hash << 4) + *name++;
            hi = hash & 0xf0000000;
            hash ^= hi >> 24;
          }
          hash &= 0x0fffffff;
        }
      }
    }
  }
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<_dl_elf_hash>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%rcx
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L2
  movzbl 0x1(%rcx),%edx
  test   %dl,%dl
  je     L61
  movzbl %dl,%eax
  movzbl 0x2(%rcx),%edx
  shl    $0x4,%rsi
  add    %rsi,%rax
  test   %dl,%dl
  je     L2
  shl    $0x4,%rax
  add    %rdx,%rax
  movzbl 0x3(%rcx),%edx
  test   %dl,%dl
  je     L2
  shl    $0x4,%rax
  add    %rdx,%rax
  movzbl 0x4(%rcx),%edx
  test   %dl,%dl
  je     L2
  shl    $0x4,%rax
  lea    0x5(%rcx),%rsi
  add    %rdx,%rax
  movzbl 0x5(%rcx),%edx
  test   %dl,%dl
  je     L2
  nopl   0x0(%rax)
L33:
  shl    $0x4,%rax
  add    $0x1,%rsi
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x18,%rax
  and    $0xf0,%eax
  xor    %rdx,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L33
  and    $0xfffffff,%eax
L2:
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((unused)) _dl_elf_hash(const char *name_arg) {
  const unsigned char *name = (const unsigned char *)name_arg;
  unsigned long int hash = *name;
  if (hash != 0 && name[1] != '\0') {
    hash = (hash << 4) + name[1];
    if (name[2] != '\0') {
      hash = (hash << 4) + name[2];
      if (name[3] != '\0') {
        hash = (hash << 4) + name[3];
        if (name[4] != '\0') {
          hash = (hash << 4) + name[4];
          name += 5;
          while (*name != '\0') {
            unsigned long int hi;
            hash = (hash << 4) + *name++;
            hi = hash & 0xf0000000;
            hash ^= hi >> 24;
          }
          hash &= 0x0fffffff;
        }
      }
    }
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<web__Test1_html>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0xad,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <WEB_write_blk@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xad,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%eax
  jmp    L7
L2:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L7:
  leave
  ret
```

assistant: ```c
int web__Test1_html(struct connstruct *cn, char *datap) {
  int send_len = 0;
  int total_send_len = 0;
  send_len = WEB_write_blk(cn, datap, 0, 173);
  if (send_len != 173)
    return send_len;
  total_send_len += send_len;
  return total_send_len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<web__Test1_html>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xad,%ecx
  mov    $0x0,%edx
  call   <WEB_write_blk@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int web__Test1_html(struct connstruct *cn, char *datap) {
  int send_len = 0;
  int total_send_len = 0;
  send_len = WEB_write_blk(cn, datap, 0, 173);
  if (send_len != 173)
    return send_len;
  total_send_len += send_len;
  return total_send_len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<web__Test1_html>:
  endbr64
  mov    $0xad,%ecx
  xor    %edx,%edx
  jmp    1050 <WEB_write_blk@plt>
```

assistant: ```c
int web__Test1_html(struct connstruct *cn, char *datap) {
  int send_len = 0;
  int total_send_len = 0;
  send_len = WEB_write_blk(cn, datap, 0, 173);
  if (send_len != 173)
    return send_len;
  total_send_len += send_len;
  return total_send_len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<web__Test1_html>:
  endbr64
  mov    $0xad,%ecx
  xor    %edx,%edx
  jmp    1050 <WEB_write_blk@plt>
```

assistant: ```c
int web__Test1_html(struct connstruct *cn, char *datap) {
  int send_len = 0;
  int total_send_len = 0;
  send_len = WEB_write_blk(cn, datap, 0, 173);
  if (send_len != 173)
    return send_len;
  total_send_len += send_len;
  return total_send_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_game_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L186
L59:
  movl   $0x0,-0x8(%rbp)
  jmp    L106
L33:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L83
  addl   $0x1,-0x4(%rbp)
L83:
  addl   $0x1,-0x8(%rbp)
L106:
  cmpl   $0x3,-0x8(%rbp)
  jle    L33
  addl   $0x1,-0xc(%rbp)
L186:
  cmpl   $0x3,-0xc(%rbp)
  jle    L59
  cmpl   $0x10,-0x4(%rbp)
  jne    L111
  movl   $0x0,-0xc(%rbp)
  jmp    L56
L39:
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L4:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  cmp    %eax,%edx
  jne    L134
  mov    $0x2,%eax
  jmp    L128
L134:
  addl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0x2,-0x8(%rbp)
  jle    L4
  addl   $0x1,-0xc(%rbp)
L56:
  cmpl   $0x3,-0xc(%rbp)
  jle    L39
  movl   $0x0,-0x8(%rbp)
  jmp    L89
L102:
  movl   $0x0,-0xc(%rbp)
  jmp    L114
L68:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  cmp    %eax,%edx
  jne    L184
  mov    $0x2,%eax
  jmp    L128
L184:
  addl   $0x1,-0xc(%rbp)
L114:
  cmpl   $0x2,-0xc(%rbp)
  jle    L68
  addl   $0x1,-0x8(%rbp)
L89:
  cmpl   $0x3,-0x8(%rbp)
  jle    L102
  mov    $0x1,%eax
  jmp    L128
L111:
  mov    $0x0,%eax
L128:
  pop    %rbp
  ret
```

assistant: ```c
int check_game_end(int num[4][4]) {
  int i;
  int j;
  int sum = 0;
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      if (num[i][j])
        sum++;
    }
  }
  if (sum == 4 * 4) {
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4 - 1; j++) {
        if (num[i][j] == num[i][j + 1]) {
          return 2;
        }
      }
    }
    for (j = 0; j < 4; j++) {
      for (i = 0; i < 4 - 1; i++) {
        if (num[i][j] == num[i + 1][j]) {
          return 2;
        }
      }
    }
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_game_end>:
  endbr64
  lea    0x10(%rdi),%r8
  lea    0x50(%rdi),%rsi
  mov    %r8,%rcx
  mov    $0x0,%edx
L10:
  lea    -0x10(%rcx),%rax
L28:
  cmpl   $0x1,(%rax)
  sbb    $0xffffffff,%edx
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L28
  add    $0x10,%rcx
  cmp    %rsi,%rcx
  jne    L10
  cmp    $0x10,%edx
  je     L40
  mov    $0x0,%eax
  ret
L40:
  lea    0x40(%rdi),%r9
  mov    %rdi,%rax
L41:
  mov    %rax,%rsi
  mov    0x4(%rax),%edx
  cmp    %edx,(%rax)
  je     L55
  mov    0x8(%rax),%ecx
  cmp    %ecx,%edx
  je     L31
  cmp    %ecx,0xc(%rsi)
  je     L38
  add    $0x10,%rax
  cmp    %r9,%rax
  jne    L41
L22:
  mov    %rdi,%rcx
  mov    0x10(%rdi),%eax
  cmp    %eax,(%rdi)
  je     L49
  mov    0x20(%rdi),%edx
  cmp    %edx,%eax
  je     L99
  cmp    %edx,0x30(%rcx)
  je     L109
  add    $0x4,%rdi
  cmp    %rdi,%r8
  jne    L22
  mov    $0x1,%eax
  ret
L99:
  mov    $0x2,%eax
  ret
L38:
  mov    $0x2,%eax
  ret
L55:
  mov    $0x2,%eax
  ret
L31:
  mov    $0x2,%eax
  ret
L109:
  mov    $0x2,%eax
  ret
L49:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int check_game_end(int num[4][4]) {
  int i;
  int j;
  int sum = 0;
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      if (num[i][j])
        sum++;
    }
  }
  if (sum == 4 * 4) {
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4 - 1; j++) {
        if (num[i][j] == num[i][j + 1]) {
          return 2;
        }
      }
    }
    for (j = 0; j < 4; j++) {
      for (i = 0; i < 4 - 1; i++) {
        if (num[i][j] == num[i + 1][j]) {
          return 2;
        }
      }
    }
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_game_end>:
  endbr64
  lea    0x10(%rdi),%r8
  lea    0x50(%rdi),%rsi
  xor    %edx,%edx
  mov    %r8,%rcx
L85:
  lea    -0x10(%rcx),%rax
L105:
  cmpl   $0x1,(%rax)
  sbb    $0xffffffff,%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L105
  lea    0x10(%rax),%rcx
  cmp    %rsi,%rcx
  jne    L85
  cmp    $0x10,%edx
  je     L15
  xor    %eax,%eax
  ret
  nopl   (%rax)
L15:
  lea    0x40(%rdi),%rsi
  mov    %rdi,%rax
L108:
  mov    0x4(%rax),%edx
  cmp    (%rax),%edx
  je     L69
  mov    0x8(%rax),%ecx
  cmp    %ecx,%edx
  je     L69
  cmp    %ecx,0xc(%rax)
  je     L69
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L108
L22:
  mov    0x10(%rdi),%eax
  cmp    %eax,(%rdi)
  je     L69
  mov    0x20(%rdi),%edx
  cmp    %edx,%eax
  je     L69
  cmp    0x30(%rdi),%edx
  je     L69
  add    $0x4,%rdi
  cmp    %r8,%rdi
  jne    L22
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L69:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int check_game_end(int num[4][4]) {
  int i;
  int j;
  int sum = 0;
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      if (num[i][j])
        sum++;
    }
  }
  if (sum == 4 * 4) {
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4 - 1; j++) {
        if (num[i][j] == num[i][j + 1]) {
          return 2;
        }
      }
    }
    for (j = 0; j < 4; j++) {
      for (i = 0; i < 4 - 1; i++) {
        if (num[i][j] == num[i + 1][j]) {
          return 2;
        }
      }
    }
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_game_end>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rdi,%rdx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%r13d
  mov    0x4(%rdi),%r9d
  mov    0x8(%rdi),%r11d
  test   %r13d,%r13d
  mov    0xc(%rdi),%ebx
  mov    0x14(%rdi),%ecx
  setne  %al
  cmp    $0x1,%r9d
  mov    0x18(%rdi),%esi
  mov    0x1c(%rdi),%r14d
  sbb    $0xffffffff,%eax
  cmp    $0x1,%r11d
  mov    %ebx,-0x8(%rsp)
  mov    0x20(%rdi),%ebp
  sbb    $0xffffffff,%eax
  cmp    $0x1,%ebx
  mov    0x10(%rdi),%ebx
  mov    0x24(%rdi),%edi
  sbb    $0xffffffff,%eax
  mov    0x28(%rdx),%r10d
  mov    0x2c(%rdx),%r15d
  cmp    $0x1,%ebx
  mov    0x30(%rdx),%r8d
  mov    0x34(%rdx),%r12d
  sbb    $0xffffffff,%eax
  cmp    $0x1,%ecx
  sbb    $0xffffffff,%eax
  cmp    $0x1,%esi
  mov    %r8d,-0x4(%rsp)
  sbb    $0xffffffff,%eax
  cmp    $0x1,%r14d
  sbb    $0xffffffff,%eax
  cmp    $0x1,%ebp
  sbb    $0xffffffff,%eax
  cmp    $0x1,%edi
  sbb    $0xffffffff,%eax
  cmp    $0x1,%r10d
  sbb    $0xffffffff,%eax
  cmp    $0x1,%r15d
  sbb    $0xffffffff,%eax
  cmp    $0x1,%r8d
  mov    0x38(%rdx),%r8d
  sbb    $0xffffffff,%eax
  cmp    $0x1,%r12d
  sbb    $0xffffffff,%eax
  test   %r8d,%r8d
  je     L12
  mov    0x3c(%rdx),%edx
  test   %edx,%edx
  je     L59
  cmp    $0xe,%eax
  jne    L59
  cmp    %r9d,%r13d
  je     L196
  cmp    %r11d,%r9d
  je     L196
  cmp    -0x8(%rsp),%r11d
  je     L196
  cmp    %ecx,%ebx
  je     L196
  cmp    %esi,%ecx
  je     L196
  cmp    %r14d,%esi
  je     L196
  cmp    %edi,%ebp
  je     L196
  cmp    %r10d,%edi
  je     L196
  cmp    %r15d,%r10d
  je     L196
  cmp    -0x4(%rsp),%r12d
  je     L196
  cmp    %r12d,%r8d
  je     L196
  cmp    %edx,%r8d
  je     L196
  cmp    %ebx,%r13d
  je     L196
  cmp    %ebp,%ebx
  je     L196
  cmp    %ebp,-0x4(%rsp)
  je     L196
  cmp    %ecx,%r9d
  je     L196
  cmp    %edi,%ecx
  je     L196
  cmp    %edi,%r12d
  je     L196
  cmp    %esi,%r11d
  je     L196
  cmp    %r10d,%esi
  je     L196
  cmp    %r10d,%r8d
  je     L196
  cmp    %r14d,-0x8(%rsp)
  je     L196
  cmp    %r15d,%r14d
  je     L196
  xor    %r8d,%r8d
  cmp    %r15d,%edx
  sete   %r8b
  add    $0x1,%r8d
L12:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L196:
  mov    $0x2,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int check_game_end(int num[4][4]) {
  int i;
  int j;
  int sum = 0;
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      if (num[i][j])
        sum++;
    }
  }
  if (sum == 4 * 4) {
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4 - 1; j++) {
        if (num[i][j] == num[i][j + 1]) {
          return 2;
        }
      }
    }
    for (j = 0; j < 4; j++) {
      for (i = 0; i < 4 - 1; i++) {
        if (num[i][j] == num[i + 1][j]) {
          return 2;
        }
      }
    }
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
L21:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %eax,-0xc(%rbp)
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x1,-0xc(%rbp)
  jne    L21
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jle    L21
  mov    -0x18(%rbp),%eax
  cmp    $0x9,%eax
  jg     L21
  movl   $0x1,-0x14(%rbp)
  jmp    L32
L46:
  movl   $0x1,-0x10(%rbp)
  jmp    L16
L91:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L22
  mov    $0x2c,%esi
  jmp    L59
L22:
  mov    $0xa,%esi
L59:
  mov    -0x10(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L91
  addl   $0x1,-0x14(%rbp)
L32:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L46
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D21: Please input num (1~9): 

tool: D2: %d

tool: D32: %*[^
]%*c

tool: D0: %d*%d=%d%c

assistant: ```c
int main() {
  int i = 0;
  int d = 0;
  do {
    printf("Please input num (1~9): ");
    d = scanf("%d", &i);
    scanf("%*[^\n]%*c");
  } while ((d != 1) || i < 1 || i > 9);
  int m, n;
  for (m = 1; m <= i; m++) {
    for (n = 1; n <= m; n++) {
      printf("%d*%d=%d%c", n, m, n * m, (n != m ? ',' : '\n'));
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D27(%rip),%r14
  lea    0x4(%rsp),%r12
  lea    D11(%rip),%rbp
  lea    D30(%rip),%rbx
L56:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %eax,%r13d
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x1,%r13d
  jne    L56
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x8,%eax
  ja     L56
  mov    %r13d,%ebp
  lea    D23(%rip),%r15
  jmp    L59
L67:
  cmp    %ebx,%ebp
  mov    $0x2c,%r8d
  mov    $0xa,%eax
  cmove  %eax,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r14d,%r12d
  cmp    %ebp,%ebx
  jle    L67
L74:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jl     L66
L59:
  mov    %ebp,%r14d
  mov    %ebp,%r12d
  mov    %r13d,%ebx
  test   %ebp,%ebp
  jg     L67
  jmp    L74
L66:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D27
type: string
name: unpack_data
arguments: label: D11
type: string
name: unpack_data
arguments: label: D30
type: string
name: unpack_data
arguments: label: D23
type: string

tool: D27: Please input num (1~9): 

tool: D11: %d

tool: D30: %*[^
]%*c

tool: D23: %d*%d=%d%c

assistant: ```c
int main() {
  int i = 0;
  int d = 0;
  do {
    printf("Please input num (1~9): ");
    d = scanf("%d", &i);
    scanf("%*[^\n]%*c");
  } while ((d != 1) || i < 1 || i > 9);
  int m, n;
  for (m = 1; m <= i; m++) {
    for (n = 1; n <= m; n++) {
      printf("%d*%d=%d%c", n, m, n * m, (n != m ? ',' : '\n'));
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <scanf@plt>
  cmp    $0x1,%ebx
  jne    L45
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x8,%eax
  ja     L45
  mov    $0x1,%ebp
  lea    D13(%rip),%r14
  mov    $0x2c,%r13d
  xchg   %ax,%ax
L46:
  mov    %ebp,%r12d
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L17:
  cmp    %ebx,%ebp
  mov    $0xa,%r8d
  mov    %r12d,%ecx
  mov    %ebx,%esi
  cmovne %r13d,%r8d
  mov    %ebp,%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %ebp,%r12d
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L17
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jge    L46
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string

tool: D17: Please input num (1~9): 

tool: D27: %d

tool: D16: %*[^
]%*c

tool: D13: %d*%d=%d%c

assistant: ```c
int main() {
  int i = 0;
  int d = 0;
  do {
    printf("Please input num (1~9): ");
    d = scanf("%d", &i);
    scanf("%*[^\n]%*c");
  } while ((d != 1) || i < 1 || i > 9);
  int m, n;
  for (m = 1; m <= i; m++) {
    for (n = 1; n <= m; n++) {
      printf("%d*%d=%d%c", n, m, n * m, (n != m ? ',' : '\n'));
    }
  }
  return 0;
}
```