ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<marginal_j_mean>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  test   %ebp,%ebp
  jle    L23
  mov    %ebx,%eax
  mov    %r8,%r13
  mov    %r9,%r14
  xor    %r15d,%r15d
  imul   %ebp,%eax
  pxor   %xmm1,%xmm1
  mov    %eax,0x14(%rsp)
  xchg   %ax,%ax
L12:
  cmp    %r15d,%ebx
  je     L11
  movsd  (%r14,%r15,8),%xmm0
  subsd  (%r12,%r15,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  mov    0x14(%rsp),%eax
  movsd  0x8(%rsp),%xmm1
  lea    (%rax,%r15,1),%edx
  movslq %edx,%rdx
  mulsd  0x0(%r13,%rdx,8),%xmm0
  addsd  %xmm0,%xmm1
L11:
  add    $0x1,%r15
  cmp    %r15,%rbp
  jne    L12
L29:
  mov    0x18(%rsp),%rax
  divsd  (%rax,%rbx,8),%xmm1
  movapd %xmm1,%xmm0
  call   <atan@plt>
  addsd  (%r12,%rbx,8),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L23:
  pxor   %xmm1,%xmm1
  jmp    L29
```

assistant: ```c
double marginal_j_mean(int p, int j, double *mu, double *kappa, double *lambda, double *theta_i) {
  int l;
  double acum = 0.;
  for (l = 0; l < p; l++) {
    if (l != j) {
      acum += lambda[j * p + l] * sin(theta_i[l] - mu[l]);
    }
  }
  return mu[j] + atan(acum / kappa[j]);
}
```
user: What is the c source code of the assembly code below?

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L7
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  leave
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strlen(s);
  if (len > n) {
    len = n;
  }
  char *new_string = (char *)malloc((len + 1) * sizeof(char));
  return strcpy(new_string, s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strndup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  cmp    %rbp,%rax
  cmova  %rbp,%rax
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strlen(s);
  if (len > n) {
    len = n;
  }
  char *new_string = (char *)malloc((len + 1) * sizeof(char));
  return strcpy(new_string, s);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmova  %rbx,%rax
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  pop    %rbx
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strlen(s);
  if (len > n) {
    len = n;
  }
  char *new_string = (char *)malloc((len + 1) * sizeof(char));
  return strcpy(new_string, s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmova  %rbx,%rax
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  pop    %rbx
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t len = strlen(s);
  if (len > n) {
    len = n;
  }
  char *new_string = (char *)malloc((len + 1) * sizeof(char));
  return strcpy(new_string, s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<generate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x68db8bad,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xc,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0x2710,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L31:
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L67:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L60
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L66
L60:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L2
  mov    -0x30(%rbp),%r8
  mov    -0x28(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <generate>
  mov    %eax,-0xc(%rbp)
L2:
  addl   $0x1,-0x4(%rbp)
L59:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  imul   -0x28(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L67
L66:
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L31
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int generate(int **A, int x, int y, int k, int m, int *p) {
  int rdm, i, j;
  rdm = rand() % 10000;
  for (i = 0; i <= x; i++) {
    for (j = 0; j <= p[i] * m; j++) {
      if (i == x && j == y)
        break;
      else {
        if (rdm == A[i][j])
          rdm = generate(A, x, y, k, m, p);
      }
    }
  }
  return rdm;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,%ebx
  mov    %esi,0x8(%rsp)
  mov    %edx,%r14d
  mov    %ecx,0xc(%rsp)
  mov    %r8d,%r13d
  mov    %r9,%r12
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  cltq
  imul   $0x68db8bad,%rax,%rax
  sar    $0x2c,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x2710,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x0,%ebp
  test   %ebx,%ebx
  jns    L47
L30:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  mov    %r12,%r9
  mov    %r13d,%r8d
  mov    0xc(%rsp),%ecx
  mov    %r14d,%edx
  mov    0x8(%rsp),%esi
  mov    %r15,%rdi
  call   <generate>
  jmp    L64
L25:
  add    $0x1,%rbp
  cmp    %ebp,0x8(%rsp)
  jl     L30
L47:
  mov    %r13d,%edx
  imul   (%r12,%rbp,4),%edx
  test   %edx,%edx
  js     L25
  cmp    %ebp,0x8(%rsp)
  sete   0x7(%rsp)
  movzbl 0x7(%rsp),%edi
  test   %r14d,%r14d
  jne    L7
  test   %dil,%dil
  jne    L25
L7:
  mov    $0x0,%ebx
L59:
  mov    (%r15,%rbp,8),%rdx
  cmp    %eax,(%rdx,%rbx,4)
  je     L68
L64:
  lea    0x1(%rbx),%edx
  mov    %r13d,%ecx
  imul   (%r12,%rbp,4),%ecx
  cmp    %edx,%ecx
  jl     L25
  add    $0x1,%rbx
  cmp    %r14d,%edx
  jne    L59
  cmpb   $0x0,0x7(%rsp)
  je     L59
  jmp    L25
```

assistant: ```c
int generate(int **A, int x, int y, int k, int m, int *p) {
  int rdm, i, j;
  rdm = rand() % 10000;
  for (i = 0; i <= x; i++) {
    for (j = 0; j <= p[i] * m; j++) {
      if (i == x && j == y)
        break;
      else {
        if (rdm == A[i][j])
          rdm = generate(A, x, y, k, m, p);
      }
    }
  }
  return rdm;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<generate>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %esi,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %r9,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %ecx,0x8(%rsp)
  call   <rand@plt>
  mov    (%rsp),%rdi
  movslq %eax,%r8
  cltd
  imul   $0x68db8bad,%r8,%r8
  sar    $0x2c,%r8
  sub    %edx,%r8d
  imul   $0x2710,%r8d,%edx
  sub    %edx,%eax
  test   %r15d,%r15d
  mov    %eax,%r8d
  js     L70
L28:
  mov    (%r12,%rbp,4),%eax
  imul   %r13d,%eax
  test   %eax,%eax
  js     L71
  cmp    %ebp,%r15d
  sete   %r10b
  test   %r14d,%r14d
  jne    L52
  test   %r10b,%r10b
  jne    L71
L52:
  xor    %ebx,%ebx
L34:
  mov    (%rdi,%rbp,8),%rax
  cmp    %r8d,(%rax,%rbx,4)
  je     L92
L83:
  mov    (%r12,%rbp,4),%edx
  lea    0x1(%rbx),%eax
  imul   %r13d,%edx
  cmp    %edx,%eax
  jg     L71
  add    $0x1,%rbx
  cmp    %r14d,%eax
  jne    L34
  test   %r10b,%r10b
  je     L34
L71:
  add    $0x1,%rbp
  cmp    %ebp,%r15d
  jge    L28
L70:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L92:
  mov    0x8(%rsp),%ecx
  mov    %r13d,%r8d
  mov    %r12,%r9
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %r10b,0xf(%rsp)
  mov    %rdi,(%rsp)
  call   <generate>
  movzbl 0xf(%rsp),%r10d
  mov    (%rsp),%rdi
  mov    %eax,%r8d
  jmp    L83
```

assistant: ```c
int generate(int **A, int x, int y, int k, int m, int *p) {
  int rdm, i, j;
  rdm = rand() % 10000;
  for (i = 0; i <= x; i++) {
    for (j = 0; j <= p[i] * m; j++) {
      if (i == x && j == y)
        break;
      else {
        if (rdm == A[i][j])
          rdm = generate(A, x, y, k, m, p);
      }
    }
  }
  return rdm;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0xe,%eax
  je     L46
  mov    $0x0,%eax
  jmp    L60
L46:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strptime@plt>
  test   %rax,%rax
  jne    L48
  mov    $0x0,%eax
  jmp    L60
L48:
  movl   $0xffffffff,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L14
  mov    $0x0,%eax
  jmp    L60
L14:
  mov    $0x1,%eax
L60:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: %Y%m%d %H:%M

assistant: ```c
int check_date(char *str_date, time_t *t) {
  struct tm tm = {0};
  if (strlen(str_date) != 14)
    return 0;
  if (strptime(str_date, "%Y%m%d %H:%M", &tm) == NULL)
    return 0;
  tm.tm_isdst = -1;
  *t = mktime(&tm);
  if (*t == -1)
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_date>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xe,%edx
  je     L17
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %rsp,%rdx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <strptime@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L10
  movl   $0xffffffff,(%rsp)
  mov    %rsp,%rdi
  call   <mktime@plt>
  mov    %eax,0x0(%rbp)
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L10
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: %Y%m%d %H:%M

assistant: ```c
int check_date(char *str_date, time_t *t) {
  struct tm tm = {0};
  if (strlen(str_date) != 14)
    return 0;
  if (strptime(str_date, "%Y%m%d %H:%M", &tm) == NULL)
    return 0;
  tm.tm_isdst = -1;
  *t = mktime(&tm);
  if (*t == -1)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_date>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <strlen@plt>
  cmp    $0xe,%eax
  je     L13
L28:
  xor    %eax,%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L13:
  mov    %rsp,%r12
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  call   <strptime@plt>
  test   %rax,%rax
  je     L28
  mov    %r12,%rdi
  movl   $0xffffffff,(%rsp)
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  mov    %eax,(%rbx)
  setne  %al
  movzbl %al,%eax
  jmp    L6
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: %Y%m%d %H:%M

assistant: ```c
int check_date(char *str_date, time_t *t) {
  struct tm tm = {0};
  if (strlen(str_date) != 14)
    return 0;
  if (strptime(str_date, "%Y%m%d %H:%M", &tm) == NULL)
    return 0;
  tm.tm_isdst = -1;
  *t = mktime(&tm);
  if (*t == -1)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_date>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <strlen@plt>
  cmp    $0xe,%eax
  je     L29
L22:
  xor    %eax,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L29:
  mov    %rsp,%r12
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  call   <strptime@plt>
  test   %rax,%rax
  je     L22
  mov    %r12,%rdi
  movl   $0xffffffff,(%rsp)
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  mov    %eax,(%rbx)
  setne  %al
  movzbl %al,%eax
  jmp    L13
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string

tool: D5: %Y%m%d %H:%M

assistant: ```c
int check_date(char *str_date, time_t *t) {
  struct tm tm = {0};
  if (strlen(str_date) != 14)
    return 0;
  if (strptime(str_date, "%Y%m%d %H:%M", &tm) == NULL)
    return 0;
  tm.tm_isdst = -1;
  *t = mktime(&tm);
  if (*t == -1)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<strrindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L26
L56:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L29:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L29
L13:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L45:
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strrindex(char s[], char t[]) {
  int i, j, k, x;
  k = -1;
  for (i = 0; s[i] != '\0'; i++) {
    for (x = i, j = 0; (t[j] != '\0') && (s[x] == t[j]); x++, j++)
      ;
    if (t[j] == '\0') {
      k = i;
    }
  }
  return k;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strrindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L41
  movzbl (%rsi),%r8d
  mov    $0x0,%ecx
  mov    $0xffffffff,%r10d
  jmp    L74
L68:
  test   %dl,%dl
  cmove  %r9d,%r10d
L78:
  movzbl 0x1(%rdi,%rcx,1),%eax
  add    $0x1,%rcx
  sub    $0x1,%rsi
  test   %al,%al
  je     L29
L74:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  je     L28
L7:
  cmp    %dl,(%rdi,%rax,1)
  jne    L68
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L7
  mov    %r9d,%r10d
  jmp    L78
L28:
  mov    %ecx,%r10d
  jmp    L78
L41:
  mov    $0xffffffff,%r10d
L29:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int strrindex(char s[], char t[]) {
  int i, j, k, x;
  k = -1;
  for (i = 0; s[i] != '\0'; i++) {
    for (x = i, j = 0; (t[j] != '\0') && (s[x] == t[j]); x++, j++)
      ;
    if (t[j] == '\0') {
      k = i;
    }
  }
  return k;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strrindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L21
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  mov    $0xffffffff,%r10d
  nopl   (%rax)
L4:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L57
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L8
L57:
  cmp    %dl,(%rdi,%rax,1)
  je     L17
L50:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L4
  mov    %r10d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %r9d,%r10d
  jmp    L50
L60:
  mov    %ecx,%r10d
  jmp    L50
L21:
  mov    $0xffffffff,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int strrindex(char s[], char t[]) {
  int i, j, k, x;
  k = -1;
  for (i = 0; s[i] != '\0'; i++) {
    for (x = i, j = 0; (t[j] != '\0') && (s[x] == t[j]); x++, j++)
      ;
    if (t[j] == '\0') {
      k = i;
    }
  }
  return k;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strrindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  mov    $0xffffffff,%r10d
  nopl   (%rax)
L41:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L70
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L50
L70:
  cmp    %dl,(%rdi,%rax,1)
  je     L73
L58:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L41
  mov    %r10d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    %r9d,%r10d
  jmp    L58
L25:
  mov    %ecx,%r10d
  jmp    L58
L11:
  mov    $0xffffffff,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int strrindex(char s[], char t[]) {
  int i, j, k, x;
  k = -1;
  for (i = 0; s[i] != '\0'; i++) {
    for (x = i, j = 0; (t[j] != '\0') && (s[x] == t[j]); x++, j++)
      ;
    if (t[j] == '\0') {
      k = i;
    }
  }
  return k;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hashfunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1505,-0x4(%rbp)
  jmp    L17
L0:
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  add    %eax,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x4(%rbp),%eax
  and    $0x7fffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hashfunction(char *str) {
  unsigned int hash = 5381;
  while (*str) {
    hash += (hash << 5) + (*str++);
  }
  return (hash & 0x7FFFFFFF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hashfunction>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L4
  mov    $0x1505,%eax
L16:
  add    $0x1,%rdi
  mov    %eax,%ecx
  shl    $0x5,%ecx
  movsbl %dl,%edx
  add    %ecx,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L16
L15:
  and    $0x7fffffff,%eax
  ret
L4:
  mov    $0x1505,%eax
  jmp    L15
```

assistant: ```c
unsigned int hashfunction(char *str) {
  unsigned int hash = 5381;
  while (*str) {
    hash += (hash << 5) + (*str++);
  }
  return (hash & 0x7FFFFFFF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hashfunction>:
  endbr64
  movsbl (%rdi),%edx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L8
L13:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  add    %ecx,%edx
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L13
  and    $0x7fffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
unsigned int hashfunction(char *str) {
  unsigned int hash = 5381;
  while (*str) {
    hash += (hash << 5) + (*str++);
  }
  return (hash & 0x7FFFFFFF);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hashfunction>:
  endbr64
  movsbl (%rdi),%edx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L5
L2:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  add    %ecx,%edx
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L2
  and    $0x7fffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
unsigned int hashfunction(char *str) {
  unsigned int hash = 5381;
  while (*str) {
    hash += (hash << 5) + (*str++);
  }
  return (hash & 0x7FFFFFFF);
}
```
user: What is the c source code of the assembly code below:

```asm
<clear_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L0:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L0
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int clear_string(char str[]) {
  int err = 0;
  int i;
  int str_length = strlen(str);
  for (i = 0; i <= str_length; str[i++] = '\0')
    ;
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  js     L1
  mov    %rbx,%rdx
  mov    %eax,%eax
  lea    0x1(%rbx,%rax,1),%rax
L13:
  movb   $0x0,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L13
L1:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int clear_string(char str[]) {
  int err = 0;
  int i;
  int str_length = strlen(str);
  for (i = 0; i <= str_length; str[i++] = '\0')
    ;
  return err;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clear_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  js     L7
  cltq
  xor    %esi,%esi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <memset@plt>
L7:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int clear_string(char str[]) {
  int err = 0;
  int i;
  int str_length = strlen(str);
  for (i = 0; i <= str_length; str[i++] = '\0')
    ;
  return err;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clear_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  js     L1
  cltq
  xor    %esi,%esi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <memset@plt>
L1:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int clear_string(char str[]) {
  int err = 0;
  int i;
  int str_length = strlen(str);
  for (i = 0; i <= str_length; str[i++] = '\0')
    ;
  return err;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *vmalloc(unsigned long size) {
  void *tmp;
  unsigned int __cil_tmp3;
  {
    {
      __cil_tmp3 = (unsigned int)size;
      tmp = malloc(__cil_tmp3);
    }
    return (tmp);
  }
}
```