ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_size>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtoll@plt>
  mov    (%rsp),%rdi
  mov    %rax,%rsi
  movzbl (%rdi),%edx
  lea    -0x47(%rdx),%ecx
  cmp    $0x26,%cl
  ja     L72
  movabs $0x100000001,%rax
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   %rax,%rdx
  jne    L62
  movabs $0x4000000040,%rax
  test   %rax,%rdx
  jne    L48
  movabs $0x1000000010,%rax
  and    %rdx,%rax
  jne    L78
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L48:
  lea    0x1(%rdi),%rdx
  mov    %rsi,%rax
  mov    %rdx,(%rsp)
  movzbl 0x1(%rdi),%edx
  shl    $0x14,%rax
L72:
  test   %dl,%dl
  mov    $0x0,%edx
  cmovne %rdx,%rax
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L62:
  lea    0x1(%rdi),%rdx
  mov    %rsi,%rax
  mov    %rdx,(%rsp)
  movzbl 0x1(%rdi),%edx
  shl    $0x1e,%rax
  test   %dl,%dl
  mov    $0x0,%edx
  cmovne %rdx,%rax
  jmp    L39
L78:
  lea    0x1(%rdi),%rdx
  mov    %rsi,%rax
  mov    %rdx,(%rsp)
  movzbl 0x1(%rdi),%edx
  shl    $0xa,%rax
  test   %dl,%dl
  mov    $0x0,%edx
  cmovne %rdx,%rax
  jmp    L39
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long parse_size(const char *p) {
  unsigned long long size;
  char *q;
  size = strtoll(p, &q, 10);
  switch (*q) {
  case 'K':
  case 'k':
    size *= 1024;
    q++;
    break;
  case 'M':
  case 'm':
    size *= 1024 * 1024;
    q++;
    break;
  case 'G':
  case 'g':
    size *= 1024 * 1024 * 1024;
    q++;
    break;
  default:
    break;
  }
  if (*q != '\0')
    size = 0;
  return size;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<iw_imgtype_num_channels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x110,-0x4(%rbp)
  je     L76
  cmpl   $0x110,-0x4(%rbp)
  jg     L47
  cmpl   $0x10,-0x4(%rbp)
  je     L19
  cmpl   $0x101,-0x4(%rbp)
  je     L63
  jmp    L47
L76:
  mov    $0x4,%eax
  jmp    L54
L19:
  mov    $0x3,%eax
  jmp    L54
L63:
  mov    $0x2,%eax
  jmp    L54
L47:
  mov    $0x1,%eax
L54:
  pop    %rbp
  ret
```

assistant: ```c
int iw_imgtype_num_channels(int t) {
  switch (t) {
  case 0x0110:
    return 4;
  case 0x0010:
    return 3;
  case 0x0101:
    return 2;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<iw_imgtype_num_channels>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x101,%edi
  je     L19
  mov    $0x4,%eax
  cmp    $0x110,%edi
  je     L19
  cmp    $0x10,%edi
  sete   %al
  movzbl %al,%eax
  lea    0x1(%rax,%rax,1),%eax
L19:
  ret
```

assistant: ```c
int iw_imgtype_num_channels(int t) {
  switch (t) {
  case 0x0110:
    return 4;
  case 0x0010:
    return 3;
  case 0x0101:
    return 2;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iw_imgtype_num_channels>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x101,%edi
  je     L9
  mov    $0x4,%eax
  cmp    $0x110,%edi
  je     L9
  xor    %eax,%eax
  cmp    $0x10,%edi
  sete   %al
  lea    0x1(%rax,%rax,1),%eax
L9:
  ret
```

assistant: ```c
int iw_imgtype_num_channels(int t) {
  switch (t) {
  case 0x0110:
    return 4;
  case 0x0010:
    return 3;
  case 0x0101:
    return 2;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iw_imgtype_num_channels>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x101,%edi
  je     L6
  mov    $0x4,%eax
  cmp    $0x110,%edi
  je     L6
  xor    %eax,%eax
  cmp    $0x10,%edi
  sete   %al
  lea    0x1(%rax,%rax,1),%eax
L6:
  ret
```

assistant: ```c
int iw_imgtype_num_channels(int t) {
  switch (t) {
  case 0x0110:
    return 4;
  case 0x0010:
    return 3;
  case 0x0101:
    return 2;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__encap_ip6udp_mpls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rbx
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <___constant_swab16@plt>
  cmp    %rax,%rbx
  jne    L8
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D38(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <encap_ipv6@plt>
  jmp    L15
L8:
  mov    D22(%rip),%rax
  mov    (%rax),%eax
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
__attribute__((section("encap_ip6udp_mpls"), used)) int __encap_ip6udp_mpls(struct __sk_buff *skb) {
  if (skb->protocol == ___constant_swab16(ETH_P_IPV6))
    return encap_ipv6(skb, IPPROTO_UDP, ETH_P_MPLS_UC);
  else
    return TC_ACT_OK;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__encap_ip6udp_mpls>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%rbp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <___constant_swab16@plt>
  cmp    %rax,%rbp
  je     L12
  mov    D9(%rip),%rax
  mov    (%rax),%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    D39(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <encap_ipv6@plt>
  jmp    L17
```

assistant: ```c
__attribute__((section("encap_ip6udp_mpls"), used)) int __encap_ip6udp_mpls(struct __sk_buff *skb) {
  if (skb->protocol == ___constant_swab16(ETH_P_IPV6))
    return encap_ipv6(skb, IPPROTO_UDP, ETH_P_MPLS_UC);
  else
    return TC_ACT_OK;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__encap_ip6udp_mpls>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D32(%rip),%rax
  mov    (%rdi),%rbx
  mov    (%rax),%edi
  call   <___constant_swab16@plt>
  cmp    %rax,%rbx
  je     L1
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    D5(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%edx
  mov    D35(%rip),%rax
  mov    (%rax),%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <encap_ipv6@plt>
```

assistant: ```c
__attribute__((section("encap_ip6udp_mpls"), used)) int __encap_ip6udp_mpls(struct __sk_buff *skb) {
  if (skb->protocol == ___constant_swab16(ETH_P_IPV6))
    return encap_ipv6(skb, IPPROTO_UDP, ETH_P_MPLS_UC);
  else
    return TC_ACT_OK;
}
```
user: What is the c source code of the assembly code below:

```asm
<__encap_ip6udp_mpls>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D21(%rip),%rax
  mov    (%rdi),%rbx
  mov    (%rax),%edi
  call   <___constant_swab16@plt>
  cmp    %rax,%rbx
  je     L7
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    D5(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <encap_ipv6@plt>
```

assistant: ```c
__attribute__((section("encap_ip6udp_mpls"), used)) int __encap_ip6udp_mpls(struct __sk_buff *skb) {
  if (skb->protocol == ___constant_swab16(ETH_P_IPV6))
    return encap_ipv6(skb, IPPROTO_UDP, ETH_P_MPLS_UC);
  else
    return TC_ACT_OK;
}
```
user: What is the c source code of the assembly code below?

```asm
<my2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L13:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x31,(%rax)
  jmp    L4
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
L4:
  sarq   -0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    $0x3f,%eax
  jbe    L13
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void my2bin(long long n, char s[]) {
  int i;
  for (i = 0; i < sizeof(n) * 8; i++) {
    if (n & 1)
      s[i] = '1';
    else
      s[i] = '0';
    n = n >> 1;
  }
  s[i] = 0;
  reverse(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my2bin>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rdi
  mov    %rsi,%rax
  lea    0x40(%rsi),%rcx
  jmp    L38
L22:
  movb   $0x30,(%rax)
L10:
  sar    %rdx
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L0
L38:
  test   $0x1,%dl
  je     L22
  movb   $0x31,(%rax)
  jmp    L10
L0:
  movb   $0x0,0x40(%rdi)
  call   <reverse@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void my2bin(long long n, char s[]) {
  int i;
  for (i = 0; i < sizeof(n) * 8; i++) {
    if (n & 1)
      s[i] = '1';
    else
      s[i] = '0';
    n = n >> 1;
  }
  s[i] = 0;
  reverse(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my2bin>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%r8
  lea    0x40(%rsi),%rdi
  mov    %rsi,%rax
  nopl   0x0(%rax)
L8:
  mov    %rcx,%rdx
  add    $0x1,%rax
  sar    %rcx
  and    $0x1,%edx
  add    $0x30,%rdx
  mov    %dl,-0x1(%rax)
  cmp    %rdi,%rax
  jne    L8
  movb   $0x0,0x40(%r8)
  mov    %r8,%rdi
  jmp    1050 <reverse@plt>
```

assistant: ```c
void my2bin(long long n, char s[]) {
  int i;
  for (i = 0; i < sizeof(n) * 8; i++) {
    if (n & 1)
      s[i] = '1';
    else
      s[i] = '0';
    n = n >> 1;
  }
  s[i] = 0;
  reverse(s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my2bin>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rax
  lea    0x40(%rsi),%rcx
  mov    %rsi,%rdi
  nopl   0x0(%rax)
L1:
  test   $0x1,%dl
  jne    L13
  movb   $0x30,(%rax)
  add    $0x1,%rax
  sar    %rdx
  cmp    %rax,%rcx
  jne    L1
  movb   $0x0,0x40(%rdi)
  jmp    1050 <reverse@plt>
  nopl   (%rax)
L13:
  movb   $0x31,(%rax)
  add    $0x1,%rax
  sar    %rdx
  cmp    %rax,%rcx
  jne    L1
  movb   $0x0,0x40(%rdi)
  jmp    1050 <reverse@plt>
```

assistant: ```c
void my2bin(long long n, char s[]) {
  int i;
  for (i = 0; i < sizeof(n) * 8; i++) {
    if (n & 1)
      s[i] = '1';
    else
      s[i] = '0';
    n = n >> 1;
  }
  s[i] = 0;
  reverse(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rb_init_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
L5:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rb_init_double(double *obj_val) {
  if (obj_val) {
    *obj_val = 0.0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rb_init_double>:
  endbr64
  test   %rdi,%rdi
  je     L6
  movq   $0x0,(%rdi)
L6:
  ret
```

assistant: ```c
void rb_init_double(double *obj_val) {
  if (obj_val) {
    *obj_val = 0.0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rb_init_double>:
  endbr64
  test   %rdi,%rdi
  je     L8
  movq   $0x0,(%rdi)
L8:
  ret
```

assistant: ```c
void rb_init_double(double *obj_val) {
  if (obj_val) {
    *obj_val = 0.0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rb_init_double>:
  endbr64
  test   %rdi,%rdi
  je     L6
  movq   $0x0,(%rdi)
L6:
  ret
```

assistant: ```c
void rb_init_double(double *obj_val) {
  if (obj_val) {
    *obj_val = 0.0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo() {
  return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int foo() {
  return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo() {
  return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo() {
  return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<triangulo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glBegin@plt>
  mov    -0x8(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    $0x2,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glVertex2d@plt>
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glVertex2d@plt>
  mov    -0x8(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glVertex2d@plt>
  mov    $0x0,%eax
  call   <glEnd@plt>
  nop
  leave
  ret
```

assistant: ```c
void triangulo(int x, int y) {
  glBegin(GL_TRIANGLES);
  glVertex2d(x - 2, y - 2);
  glVertex2d(x, y + 2);
  glVertex2d(x + 2, y - 2);
  glEnd();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<triangulo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <glBegin@plt>
  lea    -0x2(%rbp),%r12d
  lea    -0x2(%rbx),%edi
  mov    %r12d,%esi
  call   <glVertex2d@plt>
  lea    0x2(%rbp),%esi
  mov    %ebx,%edi
  call   <glVertex2d@plt>
  lea    0x2(%rbx),%edi
  mov    %r12d,%esi
  call   <glVertex2d@plt>
  mov    $0x0,%eax
  call   <glEnd@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void triangulo(int x, int y) {
  glBegin(GL_TRIANGLES);
  glVertex2d(x - 2, y - 2);
  glVertex2d(x, y + 2);
  glVertex2d(x + 2, y - 2);
  glEnd();
}
```
user: What is the c source code of the assembly code below?

```asm
<triangulo>:
  endbr64
  mov    D3(%rip),%rax
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    (%rax),%edi
  lea    -0x2(%rbp),%r12d
  call   <glBegin@plt>
  lea    -0x2(%rbx),%edi
  mov    %r12d,%esi
  call   <glVertex2d@plt>
  lea    0x2(%rbp),%esi
  mov    %ebx,%edi
  call   <glVertex2d@plt>
  lea    0x2(%rbx),%edi
  mov    %r12d,%esi
  call   <glVertex2d@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1090 <glEnd@plt>
```

assistant: ```c
void triangulo(int x, int y) {
  glBegin(GL_TRIANGLES);
  glVertex2d(x - 2, y - 2);
  glVertex2d(x, y + 2);
  glVertex2d(x + 2, y - 2);
  glEnd();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<triangulo>:
  endbr64
  mov    D0(%rip),%rax
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    (%rax),%edi
  lea    -0x2(%rbp),%r12d
  call   <glBegin@plt>
  lea    -0x2(%rbx),%edi
  mov    %r12d,%esi
  call   <glVertex2d@plt>
  lea    0x2(%rbp),%esi
  mov    %ebx,%edi
  call   <glVertex2d@plt>
  lea    0x2(%rbx),%edi
  mov    %r12d,%esi
  call   <glVertex2d@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1090 <glEnd@plt>
```

assistant: ```c
void triangulo(int x, int y) {
  glBegin(GL_TRIANGLES);
  glVertex2d(x - 2, y - 2);
  glVertex2d(x, y + 2);
  glVertex2d(x + 2, y - 2);
  glEnd();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x28(%rbp)
  jmp    L17
L46:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  imul   %rdx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  imul   %rax,%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jle    L6
  mov    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x2c(%rbp)
  jmp    L13
L6:
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    %eax,-0x2c(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L25
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
L25:
  mov    -0x2c(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L17:
  mov    -0x34(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jle    L46
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D24
type: string
name: read_data
arguments: data_tag: D1
type: string
name: read_data
arguments: data_tag: D27
type: string

tool: D24: %d

tool: D1: %lld

tool: D27: Case %d: %d %d


assistant: ```c
int main() {
  int n;
  long long a;
  long long sq;
  int x, y;
  int i;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%lld", &a);
    sq = ceil(sqrt((double)a));
    long long m = ((((sq - 1) * (sq - 1)) + 1) + (sq * sq)) / 2;
    if (a < m) {
      x = sq - (m - a);
      y = sq;
    } else {
      x = sq;
      y = sq - (a - m);
    }
    if (sq & 1) {
      int temp = x;
      x = y;
      y = temp;
    }
    printf("Case %d: %d %d\n", i, x, y);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L35
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r13
  lea    D21(%rip),%r12
  lea    D19(%rip),%rbp
  jmp    L57
L17:
  mov    %eax,%edx
  mov    %eax,%ecx
  sub    %edi,%ecx
  add    %esi,%ecx
L2:
  test   $0x1,%al
  je     L1
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %eax,%ecx
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jl     L35
L57:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x10(%rsp),%xmm0
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  lea    -0x1(%rax),%rdx
  imul   %rdx,%rdx
  mov    %rax,%rcx
  imul   %rax,%rcx
  lea    0x1(%rdx,%rcx,1),%rdx
  mov    %rdx,%rsi
  shr    $0x3f,%rsi
  add    %rdx,%rsi
  sar    %rsi
  mov    0x10(%rsp),%rdi
  cmp    %rsi,%rdi
  jge    L17
  lea    (%rax,%rdi,1),%edx
  sub    %esi,%edx
  mov    %eax,%ecx
  jmp    L2
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
datatype: string
name: disassemble_data
arguments: label: D21
datatype: string
name: disassemble_data
arguments: label: D19
datatype: string

tool: D14: %d

tool: D21: %lld

tool: D19: Case %d: %d %d


assistant: ```c
int main() {
  int n;
  long long a;
  long long sq;
  int x, y;
  int i;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%lld", &a);
    sq = ceil(sqrt((double)a));
    long long m = ((((sq - 1) * (sq - 1)) + 1) + (sq * sq)) / 2;
    if (a < m) {
      x = sq - (m - a);
      y = sq;
    } else {
      x = sq;
      y = sq - (a - m);
    }
    if (sq & 1) {
      int temp = x;
      x = y;
      y = temp;
    }
    printf("Case %d: %d %d\n", i, x, y);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D23(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L63
  mov    $0x1,%r13d
  lea    0x10(%rsp),%r12
  lea    D3(%rip),%rbp
  lea    D25(%rip),%rbx
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L33:
  lea    (%rax,%rdi,1),%edx
  mov    %eax,%ecx
  sub    %esi,%edx
L54:
  test   $0x1,%al
  je     L38
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %eax,%ecx
L38:
  mov    %r13d,%esi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    %r13d,0xc(%rsp)
  jl     L63
L45:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x10(%rsp),%xmm0
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    0x10(%rsp),%rdi
  lea    -0x1(%rax),%rdx
  mov    %rax,%rcx
  imul   %rdx,%rdx
  imul   %rax,%rcx
  lea    0x1(%rdx,%rcx,1),%rsi
  sar    %rsi
  cmp    %rsi,%rdi
  jl     L33
  mov    %eax,%ecx
  mov    %eax,%edx
  sub    %edi,%ecx
  add    %esi,%ecx
  jmp    L54
  cs nopw 0x0(%rax,%rax,1)
L63:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D23
type: string
name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D25
type: string

tool: D23: %d

tool: D3: %lld

tool: D25: Case %d: %d %d


assistant: ```c
int main() {
  int n;
  long long a;
  long long sq;
  int x, y;
  int i;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%lld", &a);
    sq = ceil(sqrt((double)a));
    long long m = ((((sq - 1) * (sq - 1)) + 1) + (sq * sq)) / 2;
    if (a < m) {
      x = sq - (m - a);
      y = sq;
    } else {
      x = sq;
      y = sq - (a - m);
    }
    if (sq & 1) {
      int temp = x;
      x = y;
      y = temp;
    }
    printf("Case %d: %d %d\n", i, x, y);
  }
  return 0;
}
```