ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <getTIssue1@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <getTIssue2@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string

tool: D8: %d

assistant: ```c
int main() {
  int a, b;
  scanf("%d", &a);
  a = getTIssue1(a);
  b = getTIssue2(a);
  return (a - b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <getTIssue1@plt>
  mov    %eax,%edi
  mov    %eax,0x4(%rsp)
  call   <getTIssue2@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%eax
  sub    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string

tool: D0: %d

assistant: ```c
int main() {
  int a, b;
  scanf("%d", &a);
  a = getTIssue1(a);
  b = getTIssue2(a);
  return (a - b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <getTIssue1@plt>
  mov    %eax,%edi
  mov    %eax,0x4(%rsp)
  call   <getTIssue2@plt>
  mov    %eax,%r8d
  mov    0x4(%rsp),%eax
  sub    %r8d,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: %d

assistant: ```c
int main() {
  int a, b;
  scanf("%d", &a);
  a = getTIssue1(a);
  b = getTIssue2(a);
  return (a - b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <getTIssue1@plt>
  mov    %eax,%edi
  mov    %eax,0x4(%rsp)
  call   <getTIssue2@plt>
  mov    %eax,%r8d
  mov    0x4(%rsp),%eax
  sub    %r8d,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: %d

assistant: ```c
int main() {
  int a, b;
  scanf("%d", &a);
  a = getTIssue1(a);
  b = getTIssue2(a);
  return (a - b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L47:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L47
  cmpl   $0x9,-0x4(%rbp)
  je     L47
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L20
  cmpl   $0x2e,-0x4(%rbp)
  je     L20
  mov    -0x4(%rbp),%eax
  jmp    L38
L20:
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L82
  nop
L48:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L48
L82:
  cmpl   $0x2e,-0x4(%rbp)
  jne    L5
  nop
L58:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L58
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L6
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L6:
  mov    $0x30,%eax
L38:
  leave
  ret
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.') {
    return c;
  }
  i = 0;
  if (isdigit(c)) {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  if (c == '.') {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  s[i] = '\0';
  if (c != EOF) {
    ungetch(c);
  }
  return '0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L94:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%eax
  je     L94
  cmp    $0x20,%al
  je     L94
  movb   $0x0,0x1(%rbp)
  movsbl %al,%r12d
  mov    %r12d,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%ebx
  je     L24
  test   %rax,%rax
  je     L10
L24:
  mov    %r12d,%edi
  call   <isdigit@plt>
  mov    $0x0,%r13d
  test   %rax,%rax
  je     L82
  mov    $0x1,%r12d
L7:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L7
L82:
  cmp    $0x2e,%ebx
  je     L52
L0:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L28
  mov    $0x30,%ebx
L10:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  lea    0x1(%r13),%r12d
  movslq %r12d,%r12
L55:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L55
  jmp    L0
L28:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x30,%ebx
  jmp    L10
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.') {
    return c;
  }
  i = 0;
  if (isdigit(c)) {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  if (c == '.') {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  s[i] = '\0';
  if (c != EOF) {
    ungetch(c);
  }
  return '0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L99:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L99
  cmp    $0x20,%al
  je     L99
  movb   $0x0,0x1(%rbx)
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L101
  cmp    $0x2e,%r12d
  je     L37
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L37:
  mov    %ebp,%edi
  xor    %r13d,%r13d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L102
L39:
  lea    0x1(%rbx,%r13,1),%rbx
  nopl   0x0(%rax)
L78:
  xor    %eax,%eax
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L78
  mov    D1(%rip),%rax
  movb   $0x0,0x0(%rbp)
  cmp    %r12d,(%rax)
  jne    L58
L2:
  add    $0x8,%rsp
  mov    $0x30,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L101:
  mov    %ebp,%edi
  xor    %r13d,%r13d
  call   <isdigit@plt>
  test   %rax,%rax
  je     L56
L102:
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  movslq %ebp,%r13
  call   <getch@plt>
  mov    %al,(%rbx,%rbp,1)
  movsbl %al,%edi
  mov    %eax,%r12d
  add    $0x1,%rbp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L28
L56:
  movslq %r13d,%rbp
  add    %rbx,%rbp
  cmp    $0x2e,%r12d
  je     L39
  mov    D1(%rip),%rax
  movb   $0x0,0x0(%rbp)
  cmp    %r12d,(%rax)
  je     L2
L58:
  mov    %r12d,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.') {
    return c;
  }
  i = 0;
  if (isdigit(c)) {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  if (c == '.') {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  s[i] = '\0';
  if (c != EOF) {
    ungetch(c);
  }
  return '0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L85:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L85
  cmp    $0x20,%al
  je     L85
  movb   $0x0,0x1(%rbx)
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L36
  cmp    $0x2e,%r12d
  je     L114
L28:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L114:
  mov    %ebp,%edi
  xor    %r14d,%r14d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L45
L29:
  movslq %r14d,%r14
  lea    0x1(%rbx,%r14,1),%rbx
  nopw   0x0(%rax,%rax,1)
L111:
  xor    %eax,%eax
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L111
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L129
L45:
  mov    %ebx,%r15d
  lea    0x1(%rbx),%rbp
  neg    %r15d
  xchg   %ax,%ax
L73:
  xor    %eax,%eax
  lea    (%r15,%rbp,1),%r14d
  mov    %rbp,%r13
  add    $0x1,%rbp
  call   <getch@plt>
  mov    %al,-0x1(%rbp)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L73
L93:
  cmp    $0x2e,%r12d
  je     L29
L42:
  mov    D0(%rip),%rax
  movb   $0x0,0x0(%r13)
  cmp    %r12d,(%rax)
  je     L46
  mov    %r12d,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
  jmp    L28
  nop
L46:
  mov    $0x30,%r12d
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L129:
  mov    %rbx,%r13
  xor    %r14d,%r14d
  jmp    L93
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.') {
    return c;
  }
  i = 0;
  if (isdigit(c)) {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  if (c == '.') {
    while (isdigit(s[++i] = c = getch()))
      ;
  }
  s[i] = '\0';
  if (c != EOF) {
    ungetch(c);
  }
  return '0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strnstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x18(%rbp),%rax
  jmp    L16
L29:
  movq   $0x0,-0x10(%rbp)
  jmp    L9
L96:
  movq   $0x0,-0x8(%rbp)
  jmp    L98
L7:
  addq   $0x1,-0x8(%rbp)
L98:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L87
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x28(%rbp)
  jbe    L87
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L87
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L7
L87:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L16
L14:
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L75
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L96
L75:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strnstr(char const *s1, char const *s2, size_t n) {
  size_t i;
  size_t j;
  if (!*s2)
    return ((char *)s1);
  i = 0;
  while (s1[i] && i < n) {
    j = 0;
    while (s2[j] && i + j < n && s1[i + j] && s1[i + j] == s2[j])
      j++;
    if (s2[j] == 0)
      return ((char *)(s1 + i));
    i++;
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_strnstr>:
  endbr64
  movzbl (%rsi),%r11d
  mov    %rdi,%r10
  test   %r11b,%r11b
  je     L39
  cmpb   $0x0,(%rdi)
  je     L31
  test   %rdx,%rdx
  je     L31
  mov    $0x0,%r9d
  jmp    L28
L34:
  test   %cl,%cl
  je     L39
L109:
  add    $0x1,%r9
  sub    $0x1,%rsi
  cmpb   $0x0,(%rdi,%r9,1)
  je     L51
  cmp    %r9,%rdx
  jbe    L51
L28:
  lea    (%rdi,%r9,1),%r10
  mov    %r9,%rax
  mov    %r11d,%ecx
  cmp    %r9,%rdx
  jbe    L109
L95:
  movzbl (%rdi,%rax,1),%r8d
  cmp    %cl,%r8b
  jne    L34
  test   %r8b,%r8b
  je     L34
  movzbl 0x1(%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L39
  add    $0x1,%rax
  cmp    %rdx,%rax
  jb     L95
  jmp    L109
L31:
  mov    $0x0,%r10d
  jmp    L39
L51:
  mov    $0x0,%r10d
L39:
  mov    %r10,%rax
  ret
```

assistant: ```c
char *ft_strnstr(char const *s1, char const *s2, size_t n) {
  size_t i;
  size_t j;
  if (!*s2)
    return ((char *)s1);
  i = 0;
  while (s1[i] && i < n) {
    j = 0;
    while (s2[j] && i + j < n && s1[i + j] && s1[i + j] == s2[j])
      j++;
    if (s2[j] == 0)
      return ((char *)(s1 + i));
    i++;
  }
  return (NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strnstr>:
  endbr64
  movzbl (%rsi),%r11d
  mov    %rdi,%r10
  test   %r11b,%r11b
  je     L44
  cmpb   $0x0,(%rdi)
  je     L55
  test   %rdx,%rdx
  je     L55
  xor    %r9d,%r9d
  nopl   (%rax)
L59:
  lea    (%rdi,%r9,1),%r10
  mov    %r9,%rax
  mov    %r11d,%ecx
  cmp    %r9,%rdx
  ja     L83
  jmp    L71
  nopl   0x0(%rax)
L39:
  cmp    %cl,%r8b
  jne    L71
  movzbl 0x1(%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L44
  add    $0x1,%rax
  cmp    %rax,%rdx
  jbe    L71
L83:
  movzbl (%rdi,%rax,1),%r8d
  test   %r8b,%r8b
  jne    L39
L71:
  add    $0x1,%r9
  sub    $0x1,%rsi
  cmpb   $0x0,(%rdi,%r9,1)
  je     L55
  cmp    %r9,%rdx
  ja     L59
L55:
  xor    %r10d,%r10d
L44:
  mov    %r10,%rax
  ret
```

assistant: ```c
char *ft_strnstr(char const *s1, char const *s2, size_t n) {
  size_t i;
  size_t j;
  if (!*s2)
    return ((char *)s1);
  i = 0;
  while (s1[i] && i < n) {
    j = 0;
    while (s2[j] && i + j < n && s1[i + j] && s1[i + j] == s2[j])
      j++;
    if (s2[j] == 0)
      return ((char *)(s1 + i));
    i++;
  }
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strnstr>:
  endbr64
  movzbl (%rsi),%r11d
  mov    %rdi,%r10
  test   %r11b,%r11b
  je     L101
  cmpb   $0x0,(%rdi)
  je     L27
  test   %rdx,%rdx
  je     L27
  xor    %r9d,%r9d
  nopl   (%rax)
L64:
  lea    (%rdi,%r9,1),%r10
  mov    %r9,%rax
  mov    %r11d,%ecx
  cmp    %r9,%rdx
  ja     L74
  jmp    L28
  nopl   0x0(%rax)
L36:
  cmp    %cl,%r8b
  jne    L28
  movzbl 0x1(%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L101
  add    $0x1,%rax
  cmp    %rax,%rdx
  jbe    L28
L74:
  movzbl (%rdi,%rax,1),%r8d
  test   %r8b,%r8b
  jne    L36
L28:
  add    $0x1,%r9
  sub    $0x1,%rsi
  cmpb   $0x0,(%rdi,%r9,1)
  je     L27
  cmp    %r9,%rdx
  ja     L64
L27:
  xor    %r10d,%r10d
L101:
  mov    %r10,%rax
  ret
```

assistant: ```c
char *ft_strnstr(char const *s1, char const *s2, size_t n) {
  size_t i;
  size_t j;
  if (!*s2)
    return ((char *)s1);
  i = 0;
  while (s1[i] && i < n) {
    j = 0;
    while (s2[j] && i + j < n && s1[i + j] && s1[i + j] == s2[j])
      j++;
    if (s2[j] == 0)
      return ((char *)(s1 + i));
    i++;
  }
  return (NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add_to_dsk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x3,-0x4(%rbp)
  jmp    L15
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <add_files@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void add_to_dsk(int argc, char **argv) {
  int i;
  for (i = 3; i < argc; i++) {
    add_files(argv[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_to_dsk>:
  endbr64
  cmp    $0x3,%edi
  jle    L1
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x18(%rsi),%rbx
  lea    -0x4(%rdi),%eax
  lea    0x20(%rsi,%rax,8),%rbp
L5:
  mov    (%rbx),%rdi
  call   <add_files@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  ret
```

assistant: ```c
void add_to_dsk(int argc, char **argv) {
  int i;
  for (i = 3; i < argc; i++) {
    add_files(argv[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_to_dsk>:
  endbr64
  cmp    $0x3,%edi
  jle    L14
  push   %rbp
  lea    -0x4(%rdi),%eax
  push   %rbx
  lea    0x20(%rsi,%rax,8),%rbp
  lea    0x18(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <add_files@plt>
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void add_to_dsk(int argc, char **argv) {
  int i;
  for (i = 3; i < argc; i++) {
    add_files(argv[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<add_to_dsk>:
  endbr64
  cmp    $0x3,%edi
  jle    L6
  push   %rbp
  lea    -0x4(%rdi),%eax
  push   %rbx
  lea    0x20(%rsi,%rax,8),%rbp
  lea    0x18(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <add_files@plt>
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void add_to_dsk(int argc, char **argv) {
  int i;
  for (i = 3; i < argc; i++) {
    add_files(argv[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<jac_chain_nm7_name_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  cmpl   $0x1,-0x4(%rbp)
  je     L30
  jmp    L16
L2:
  lea    D2(%rip),%rax
  jmp    L26
L30:
  lea    D1(%rip),%rax
  jmp    L26
L16:
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string
name: parse_data
arguments: data_label: D1
datatype: string

tool: D2: o0

tool: D1: o1

assistant: ```c
const char *jac_chain_nm7_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jac_chain_nm7_name_out>:
  endbr64
  lea    D12(%rip),%rax
  test   %edi,%edi
  je     L0
  cmp    $0x1,%edi
  lea    D10(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string

tool: D12: o0

tool: D10: o1

assistant: ```c
const char *jac_chain_nm7_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jac_chain_nm7_name_out>:
  endbr64
  lea    D4(%rip),%rax
  test   %edi,%edi
  je     L9
  cmp    $0x1,%edi
  lea    D16(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L9:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string
name: unpack_data
arguments: tag: D16
type: string

tool: D4: o0

tool: D16: o1

assistant: ```c
const char *jac_chain_nm7_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jac_chain_nm7_name_out>:
  endbr64
  lea    D18(%rip),%rax
  test   %edi,%edi
  je     L3
  cmp    $0x1,%edi
  lea    D15(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L3:
  ret
```

tool_calls: name: read_data
arguments: label: D18
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D18: o0

tool: D15: o1

assistant: ```c
const char *jac_chain_nm7_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cmd_add_wchstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L4
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L1
L4:
  nop
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9: UNSUPPORTED

assistant: ```c
void cmd_add_wchstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmd_add_wchstr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L0
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D4(%rip),%rdi
  call   <report_error@plt>
L0:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: UNSUPPORTED

assistant: ```c
void cmd_add_wchstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmd_add_wchstr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L9
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <report_error@plt>
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D2: UNSUPPORTED

assistant: ```c
void cmd_add_wchstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```