ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<powerfact>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  jne    L7
L6:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    %edi,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mov    %esi,%edi
  call   <pow@plt>
  mov    %eax,%r12d
  lea    -0x1(%rbx),%esi
  mov    %ebp,%edi
  call   <powerfact>
  lea    (%r12,%rax,1),%ebx
  jmp    L6
```

assistant: ```c
int powerfact(int x, int n) {
  if (n == 0)
    return 0;
  return (int)(pow((double)x, n) + powerfact(x, n - 1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<powerfact>:
  endbr64
  push   %r14
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  test   %esi,%esi
  je     L11
  pxor   %xmm1,%xmm1
  mov    %esi,%ebx
  xor    %r12d,%r12d
  cvtsi2sd %edi,%xmm1
  movq   %xmm1,%r14
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  add    %eax,%r12d
  sub    $0x1,%ebx
  jne    L10
L11:
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
int powerfact(int x, int n) {
  if (n == 0)
    return 0;
  return (int)(pow((double)x, n) + powerfact(x, n - 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<powerfact>:
  endbr64
  push   %r14
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  test   %esi,%esi
  je     L17
  pxor   %xmm1,%xmm1
  mov    %esi,%ebx
  xor    %r12d,%r12d
  cvtsi2sd %edi,%xmm1
  movq   %xmm1,%r14
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  add    %eax,%r12d
  sub    $0x1,%ebx
  jne    L10
L17:
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
int powerfact(int x, int n) {
  if (n == 0)
    return 0;
  return (int)(pow((double)x, n) + powerfact(x, n - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<callMe2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    $0x0,%eax
  movl   $0xdead,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void callMe2() {
  const int foo = 2;
  const int bar = 3;
  (void)foo;
  (void)bar;
  *((volatile int *)0) = 0xdead;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<callMe2>:
  endbr64
  movl   $0xdead,0x0
  ret
```

assistant: ```c
void callMe2() {
  const int foo = 2;
  const int bar = 3;
  (void)foo;
  (void)bar;
  *((volatile int *)0) = 0xdead;
}
```
user: Translate the below assembly code into C programming language:

```asm
<callMe2>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void callMe2() {
  const int foo = 2;
  const int bar = 3;
  (void)foo;
  (void)bar;
  *((volatile int *)0) = 0xdead;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<callMe2>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void callMe2() {
  const int foo = 2;
  const int bar = 3;
  (void)foo;
  (void)bar;
  *((volatile int *)0) = 0xdead;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_ZSt18uninitialized_copyIPPiS1_ET0_T_S3_S2_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_ZNSt20__uninitialized_copyILb1EE18uninitialized_copyIPPiS3_EET0_T_S5_S4_@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned int **_ZSt18uninitialized_copyIPPiS1_ET0_T_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_tmp2;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp__39;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call = _ZNSt20__uninitialized_copyILb1EE18uninitialized_copyIPPiS3_EET0_T_S5_S4_(llvm_cbe_tmp, llvm_cbe_tmp1, llvm_cbe_tmp2);
  *(&llvm_cbe_retval) = llvm_cbe_call;
  llvm_cbe_tmp__39 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__39;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_ZSt18uninitialized_copyIPPiS1_ET0_T_S3_S2_>:
  endbr64
  sub    $0x8,%rsp
  call   <_ZNSt20__uninitialized_copyILb1EE18uninitialized_copyIPPiS3_EET0_T_S5_S4_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int **_ZSt18uninitialized_copyIPPiS1_ET0_T_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_tmp2;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp__39;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call = _ZNSt20__uninitialized_copyILb1EE18uninitialized_copyIPPiS3_EET0_T_S5_S4_(llvm_cbe_tmp, llvm_cbe_tmp1, llvm_cbe_tmp2);
  *(&llvm_cbe_retval) = llvm_cbe_call;
  llvm_cbe_tmp__39 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__39;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_ZSt18uninitialized_copyIPPiS1_ET0_T_S3_S2_>:
  endbr64
  jmp    1050 <_ZNSt20__uninitialized_copyILb1EE18uninitialized_copyIPPiS3_EET0_T_S5_S4_@plt>
```

assistant: ```c
unsigned int **_ZSt18uninitialized_copyIPPiS1_ET0_T_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_tmp2;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp__39;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call = _ZNSt20__uninitialized_copyILb1EE18uninitialized_copyIPPiS3_EET0_T_S5_S4_(llvm_cbe_tmp, llvm_cbe_tmp1, llvm_cbe_tmp2);
  *(&llvm_cbe_retval) = llvm_cbe_call;
  llvm_cbe_tmp__39 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__39;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_ZSt18uninitialized_copyIPPiS1_ET0_T_S3_S2_>:
  endbr64
  jmp    1050 <_ZNSt20__uninitialized_copyILb1EE18uninitialized_copyIPPiS3_EET0_T_S5_S4_@plt>
```

assistant: ```c
unsigned int **_ZSt18uninitialized_copyIPPiS1_ET0_T_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_tmp2;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp__39;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call = _ZNSt20__uninitialized_copyILb1EE18uninitialized_copyIPPiS3_EET0_T_S5_S4_(llvm_cbe_tmp, llvm_cbe_tmp1, llvm_cbe_tmp2);
  *(&llvm_cbe_retval) = llvm_cbe_call;
  llvm_cbe_tmp__39 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__39;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D3(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <modf@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: f64
name: unpack_data
arguments: data_label: D5
data_type: string

tool: D3: 3.14

tool: D5: integerPart = %.0f, fractionPart = %.2f


assistant: ```c
int main(int argc, const char *argv[]) {
  double pi = 3.14;
  double integerPart;
  double fractionPart;
  fractionPart = modf(pi, &integerPart);
  printf("integerPart = %.0f, fractionPart = %.2f\n", integerPart, fractionPart);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D8(%rip),%xmm1
  movsd  D0(%rip),%xmm0
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D0
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D14
datatype: string

tool: {"D8": [0xf0,0x51,0xb8,0x1e,0x85,0xeb,0xc1,0x3f]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D14: integerPart = %.0f, fractionPart = %.2f


assistant: ```c
int main(int argc, const char *argv[]) {
  double pi = 3.14;
  double integerPart;
  double fractionPart;
  fractionPart = modf(pi, &integerPart);
  printf("integerPart = %.0f, fractionPart = %.2f\n", integerPart, fractionPart);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D11(%rip),%xmm1
  movsd  D29(%rip),%xmm0
  lea    D25(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D29
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D25
type_guessed: string

tool: {"D11": [0xf0,0x51,0xb8,0x1e,0x85,0xeb,0xc1,0x3f]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D25: integerPart = %.0f, fractionPart = %.2f


assistant: ```c
int main(int argc, const char *argv[]) {
  double pi = 3.14;
  double integerPart;
  double fractionPart;
  fractionPart = modf(pi, &integerPart);
  printf("integerPart = %.0f, fractionPart = %.2f\n", integerPart, fractionPart);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D18(%rip),%xmm1
  movsd  D8(%rip),%xmm0
  lea    D23(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D8
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D23
type_infered: string

tool: {"D18": [0xf0,0x51,0xb8,0x1e,0x85,0xeb,0xc1,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D23: integerPart = %.0f, fractionPart = %.2f


assistant: ```c
int main(int argc, const char *argv[]) {
  double pi = 3.14;
  double integerPart;
  double fractionPart;
  fractionPart = modf(pi, &integerPart);
  printf("integerPart = %.0f, fractionPart = %.2f\n", integerPart, fractionPart);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x10(%rbp),%rax
  jmp    L16
L0:
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <gcd>
L16:
  leave
  ret
```

assistant: ```c
long gcd(long a, long b) {
  if (a == 0) {
    return b;
  } else {
    return gcd(b % a, a);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gcd>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  jne    L2
  ret
L2:
  sub    $0x8,%rsp
  cqto
  idiv   %rdi
  mov    %rdi,%rsi
  mov    %rdx,%rdi
  call   <gcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long gcd(long a, long b) {
  if (a == 0) {
    return b;
  } else {
    return gcd(b % a, a);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gcd>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  test   %rdi,%rdi
  jne    L27
  jmp    L0
  nopl   0x0(%rax)
L13:
  mov    %rdx,%r8
L27:
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L13
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L0:
  mov    %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long gcd(long a, long b) {
  if (a == 0) {
    return b;
  } else {
    return gcd(b % a, a);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcd>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  test   %rdi,%rdi
  jne    L15
  jmp    L26
  nopl   0x0(%rax)
L19:
  mov    %rdx,%r8
L15:
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L19
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L26:
  mov    %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long gcd(long a, long b) {
  if (a == 0) {
    return b;
  } else {
    return gcd(b % a, a);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L3:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int slen(char s[]) {
  int n = 0;
  while (s[n] != 0)
    n++;
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<slen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L14
  mov    $0x1,%eax
L17:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L17
L13:
  mov    %edx,%eax
  ret
L14:
  mov    $0x0,%edx
  jmp    L13
```

assistant: ```c
int slen(char s[]) {
  int n = 0;
  while (s[n] != 0)
    n++;
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<slen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  mov    $0x1,%eax
  xchg   %ax,%ax
L2:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L2
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int slen(char s[]) {
  int n = 0;
  while (s[n] != 0)
    n++;
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<slen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x1,%eax
  xchg   %ax,%ax
L10:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L10
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int slen(char s[]) {
  int n = 0;
  while (s[n] != 0)
    n++;
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calEXPMEMA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  movsd  %xmm0,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <calEma@plt>
  nop
  leave
  ret
```

assistant: ```c
void calEXPMEMA(const double dataX[], const int countX, const int N, const double smooth, double expmema[]) {
  expmema[0] = smooth;
  calEma(dataX, countX, N, expmema);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calEXPMEMA>:
  endbr64
  sub    $0x8,%rsp
  movsd  %xmm0,(%rcx)
  call   <calEma@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void calEXPMEMA(const double dataX[], const int countX, const int N, const double smooth, double expmema[]) {
  expmema[0] = smooth;
  calEma(dataX, countX, N, expmema);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calEXPMEMA>:
  endbr64
  movsd  %xmm0,(%rcx)
  jmp    1050 <calEma@plt>
```

assistant: ```c
void calEXPMEMA(const double dataX[], const int countX, const int N, const double smooth, double expmema[]) {
  expmema[0] = smooth;
  calEma(dataX, countX, N, expmema);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calEXPMEMA>:
  endbr64
  movsd  %xmm0,(%rcx)
  jmp    1050 <calEma@plt>
```

assistant: ```c
void calEXPMEMA(const double dataX[], const int countX, const int N, const double smooth, double expmema[]) {
  expmema[0] = smooth;
  calEma(dataX, countX, N, expmema);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L6:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L26:
  cmpl   $0x4,-0x14(%rbp)
  jle    L6
  mov    -0x10(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L21:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L13:
  cmpl   $0x4,-0x14(%rbp)
  jle    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string

tool: D18: Preencha o vetor

tool: D5: %d

tool: D13: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int *vetor;
  int i, v;
  vetor = (int *)malloc(sizeof(int) * 5);
  printf("Preencha o vetor\n");
  for (i = 0; i < 5; i++) {
    scanf("%d", &v);
    vetor[i] = v;
  }
  bubble_sort(vetor, 5);
  for (i = 0; i < 5; i++) {
    printf("%d ", vetor[i]);
  }
  printf("\n");
  free(vetor);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    %r13,%rbx
  lea    0x14(%r13),%r12
  mov    %r13,%rbp
  lea    D4(%rip),%r14
L8:
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L8
  mov    $0x5,%esi
  mov    %r13,%rdi
  call   <bubble_sort@plt>
  lea    D23(%rip),%rbp
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D23
type_infered: string

tool: D18: Preencha o vetor

tool: D4: %d

tool: D23: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int *vetor;
  int i, v;
  vetor = (int *)malloc(sizeof(int) * 5);
  printf("Preencha o vetor\n");
  for (i = 0; i < 5; i++) {
    scanf("%d", &v);
    vetor[i] = v;
  }
  bubble_sort(vetor, 5);
  for (i = 0; i < 5; i++) {
    printf("%d ", vetor[i]);
  }
  printf("\n");
  free(vetor);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x14,%edi
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r15
  call   <malloc@plt>
  lea    D21(%rip),%rdi
  mov    %rax,%r13
  call   <puts@plt>
  mov    %r13,%rbx
  lea    0x14(%r13),%r12
  mov    %r13,%rbp
L8:
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbp
  jne    L8
  mov    $0x5,%esi
  mov    %r13,%rdi
  lea    D4(%rip),%rbp
  call   <bubble_sort@plt>
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D4
datatype: string

tool: D18: %d

tool: D21: Preencha o vetor

tool: D4: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int *vetor;
  int i, v;
  vetor = (int *)malloc(sizeof(int) * 5);
  printf("Preencha o vetor\n");
  for (i = 0; i < 5; i++) {
    scanf("%d", &v);
    vetor[i] = v;
  }
  bubble_sort(vetor, 5);
  for (i = 0; i < 5; i++) {
    printf("%d ", vetor[i]);
  }
  printf("\n");
  free(vetor);
  return 0;
}
```