ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<limat_quantize>:
  endbr64
  sub    $0x18,%rsp
  movaps %xmm0,%xmm3
  movss  %xmm0,0x8(%rsp)
  movss  D27(%rip),%xmm0
  comiss %xmm1,%xmm0
  jb     L57
L28:
  movss  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
L57:
  movss  %xmm1,0xc(%rsp)
  movaps %xmm3,%xmm0
  call   <fmod@plt>
  movss  0xc(%rsp),%xmm1
  mulss  D4(%rip),%xmm1
  comiss %xmm1,%xmm0
  jae    L7
  xorps  D23(%rip),%xmm1
  comiss %xmm0,%xmm1
  jb     L34
  movss  0x8(%rsp),%xmm1
  subss  %xmm0,%xmm1
  subss  0xc(%rsp),%xmm1
  movss  %xmm1,0x8(%rsp)
  jmp    L28
L7:
  movss  0x8(%rsp),%xmm1
  subss  %xmm0,%xmm1
  addss  0xc(%rsp),%xmm1
  movss  %xmm1,0x8(%rsp)
  jmp    L28
L34:
  movss  0x8(%rsp),%xmm4
  subss  %xmm0,%xmm4
  movss  %xmm4,0x8(%rsp)
  jmp    L28
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
type: byte[4]
name: disassemble_data
arguments: data_tag: D4
type: byte[4]
name: disassemble_data
arguments: data_tag: D23
type: byte[16]

tool: {"D27": [0x08,0xe5,0x3c,0x1e]}

tool: {"D4": [0x00,0x00,0x00,0x3f]}

tool: {"D23": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float limat_quantize(float value, float resolution) {
  float tmp;
  if (resolution <= 1E-20f)
    return value;
  tmp = fmod(value, resolution);
  if (tmp >= 0.5f * resolution)
    return value - tmp + resolution;
  else if (tmp <= -0.5f * resolution)
    return value - tmp - resolution;
  else
    return value - tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<limat_quantize>:
  endbr64
  movaps %xmm0,%xmm2
  movss  D4(%rip),%xmm0
  comiss %xmm1,%xmm0
  jb     L7
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  sub    $0x18,%rsp
  movaps %xmm2,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <fmod@plt>
  movss  0xc(%rsp),%xmm1
  movss  D20(%rip),%xmm3
  movss  0x8(%rsp),%xmm2
  mulss  %xmm1,%xmm3
  subss  %xmm0,%xmm2
  comiss %xmm3,%xmm0
  jae    L6
  xorps  D17(%rip),%xmm3
  comiss %xmm0,%xmm3
  jb     L15
  subss  %xmm1,%xmm2
L15:
  movaps %xmm2,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L6:
  addss  %xmm1,%xmm2
  add    $0x18,%rsp
  movaps %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: byte[4]
name: unpack_data
arguments: label: D20
type: byte[4]
name: unpack_data
arguments: label: D17
type: byte[16]

tool: {"D4": [0x08,0xe5,0x3c,0x1e]}

tool: {"D20": [0x00,0x00,0x00,0x3f]}

tool: {"D17": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float limat_quantize(float value, float resolution) {
  float tmp;
  if (resolution <= 1E-20f)
    return value;
  tmp = fmod(value, resolution);
  if (tmp >= 0.5f * resolution)
    return value - tmp + resolution;
  else if (tmp <= -0.5f * resolution)
    return value - tmp - resolution;
  else
    return value - tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<limat_quantize>:
  endbr64
  movaps %xmm0,%xmm2
  movss  D18(%rip),%xmm0
  comiss %xmm1,%xmm0
  jb     L18
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  sub    $0x18,%rsp
  movaps %xmm2,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <fmod@plt>
  movss  0xc(%rsp),%xmm1
  movss  D13(%rip),%xmm3
  movss  0x8(%rsp),%xmm2
  mulss  %xmm1,%xmm3
  subss  %xmm0,%xmm2
  comiss %xmm3,%xmm0
  jae    L22
  xorps  D26(%rip),%xmm3
  comiss %xmm0,%xmm3
  jb     L8
  subss  %xmm1,%xmm2
L8:
  movaps %xmm2,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L22:
  addss  %xmm1,%xmm2
  add    $0x18,%rsp
  movaps %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: byte[4]
name: extract_symbolic_data
arguments: label: D13
type_guessed: byte[4]
name: extract_symbolic_data
arguments: label: D26
type_guessed: byte[16]

tool: {"D18": [0x08,0xe5,0x3c,0x1e]}

tool: {"D13": [0x00,0x00,0x00,0x3f]}

tool: {"D26": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float limat_quantize(float value, float resolution) {
  float tmp;
  if (resolution <= 1E-20f)
    return value;
  tmp = fmod(value, resolution);
  if (tmp >= 0.5f * resolution)
    return value - tmp + resolution;
  else if (tmp <= -0.5f * resolution)
    return value - tmp - resolution;
  else
    return value - tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fibonnaci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  cmpl   $0x0,-0x14(%rbp)
  je     L6
  cmpl   $0x1,-0x14(%rbp)
  jne    L25
L6:
  mov    -0x14(%rbp),%eax
  jmp    L5
L25:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fibonnaci>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fibonnaci>
  add    %ebx,%eax
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibonnaci(int n, int *c) {
  *c = *c + 1;
  if (n == 0 || n == 1)
    return n;
  return fibonnaci(n - 1, c) + fibonnaci(n - 2, c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fibonnaci>:
  endbr64
  addl   $0x1,(%rsi)
  mov    %edi,%eax
  cmp    $0x1,%edi
  jbe    L3
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    -0x1(%rdi),%edi
  call   <fibonnaci>
  mov    %eax,%r12d
  lea    -0x2(%rbx),%edi
  mov    %rbp,%rsi
  call   <fibonnaci>
  add    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

assistant: ```c
int fibonnaci(int n, int *c) {
  *c = *c + 1;
  if (n == 0 || n == 1)
    return n;
  return fibonnaci(n - 1, c) + fibonnaci(n - 2, c);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_the_nb_marker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L17:
  movl   $0x0,-0x8(%rbp)
  jmp    L60
L1:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L6
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L6
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L65
L6:
  addl   $0x1,-0x8(%rbp)
L60:
  cmpl   $0x2,-0x8(%rbp)
  jbe    L1
  addl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0x2,-0x4(%rbp)
  jbe    L17
  mov    $0x0,%eax
L65:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int get_the_nb_marker(unsigned int **nb) {
  unsigned int i, j;
  for (j = 0; j < 3; j++)
    for (i = 0; i < 3; i++)
      if (nb[j][i] > 0 && nb[j][i] != (unsigned int)(-1))
        return nb[j][i];
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_the_nb_marker>:
  endbr64
  lea    0x18(%rdi),%rsi
L35:
  mov    (%rdi),%rdx
  mov    (%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L25
  mov    0x4(%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L31
  mov    0x8(%rdx),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xfffffffd,%edx
  jbe    L25
  add    $0x8,%rdi
  cmp    %rsi,%rdi
  jne    L35
  mov    $0x0,%eax
L25:
  ret
L31:
  ret
```

assistant: ```c
unsigned int get_the_nb_marker(unsigned int **nb) {
  unsigned int i, j;
  for (j = 0; j < 3; j++)
    for (i = 0; i < 3; i++)
      if (nb[j][i] > 0 && nb[j][i] != (unsigned int)(-1))
        return nb[j][i];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_the_nb_marker>:
  endbr64
  lea    0x18(%rdi),%rsi
L25:
  mov    (%rdi),%rdx
  mov    (%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L2
  mov    0x4(%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L39
  mov    0x8(%rdx),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xfffffffd,%edx
  jbe    L2
  add    $0x8,%rdi
  cmp    %rsi,%rdi
  jne    L25
  xor    %eax,%eax
L2:
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  ret
```

assistant: ```c
unsigned int get_the_nb_marker(unsigned int **nb) {
  unsigned int i, j;
  for (j = 0; j < 3; j++)
    for (i = 0; i < 3; i++)
      if (nb[j][i] > 0 && nb[j][i] != (unsigned int)(-1))
        return nb[j][i];
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_the_nb_marker>:
  endbr64
  mov    (%rdi),%rdx
  mov    (%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L26
  mov    0x4(%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L26
  mov    0x8(%rdx),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xfffffffd,%edx
  jbe    L26
  mov    0x8(%rdi),%rdx
  mov    (%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L26
  mov    0x4(%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L26
  mov    0x8(%rdx),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xfffffffd,%edx
  jbe    L26
  mov    0x10(%rdi),%rdx
  mov    (%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L26
  mov    0x4(%rdx),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0xfffffffd,%ecx
  jbe    L26
  mov    0x8(%rdx),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xfffffffd,%edx
  mov    $0x0,%edx
  cmova  %edx,%eax
L26:
  ret
```

assistant: ```c
unsigned int get_the_nb_marker(unsigned int **nb) {
  unsigned int i, j;
  for (j = 0; j < 3; j++)
    for (i = 0; i < 3; i++)
      if (nb[j][i] > 0 && nb[j][i] != (unsigned int)(-1))
        return nb[j][i];
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Dico_Long_Start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <Label_Printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <Inst_Printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string
name: read_data
arguments: label: D6
type_guessed: string
name: read_data
arguments: label: D28
type_guessed: string

tool: D9: .data

tool: D6: 3

tool: D28: .align

assistant: ```c
void Dico_Long_Start(int nb_longs) {
  Label_Printf(".data");
  Inst_Printf(".align", "3");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Dico_Long_Start>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <Label_Printf@plt>
  lea    D24(%rip),%rsi
  lea    D26(%rip),%rdi
  call   <Inst_Printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D24
data_type: string
name: parse_data
arguments: tag: D26
data_type: string

tool: D9: .data

tool: D24: 3

tool: D26: .align

assistant: ```c
void Dico_Long_Start(int nb_longs) {
  Label_Printf(".data");
  Inst_Printf(".align", "3");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Dico_Long_Start>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <Label_Printf@plt>
  lea    D11(%rip),%rsi
  lea    D25(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <Inst_Printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string

tool: D1: .data

tool: D11: 3

tool: D25: .align

assistant: ```c
void Dico_Long_Start(int nb_longs) {
  Label_Printf(".data");
  Inst_Printf(".align", "3");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Dico_Long_Start>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <Label_Printf@plt>
  lea    D10(%rip),%rsi
  lea    D12(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <Inst_Printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D12
datatype: string

tool: D8: .data

tool: D10: 3

tool: D12: .align

assistant: ```c
void Dico_Long_Start(int nb_longs) {
  Label_Printf(".data");
  Inst_Printf(".align", "3");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<path_010_expected_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  cmpl   $0x1,-0x4(%rbp)
  jmp    L18
L2:
  nop
L18:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void path_010_expected_3(int a) {
  switch (a) {
  case 0:
    break;
  case 1:
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<path_010_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_010_expected_3(int a) {
  switch (a) {
  case 0:
    break;
  case 1:
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<path_010_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_010_expected_3(int a) {
  switch (a) {
  case 0:
    break;
  case 1:
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<path_010_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_010_expected_3(int a) {
  switch (a) {
  case 0:
    break;
  case 1:
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L12
L33:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L12:
  cmpl   $0x0,-0x14(%rbp)
  jne    L33
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L5
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L5:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D20
type: string
name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D21
type: string

tool: D20: %d

tool: D0: Is palindrome


tool: D21: Not palindrome


assistant: ```c
int main() {
  int number, num, revnumber = 0, rem;
  scanf("%d", &number);
  num = number;
  while (num != 0) {
    rem = num % 10;
    revnumber = revnumber * 10 + rem;
    num /= 10;
  }
  if (number == revnumber) {
    printf("Is palindrome\n");
  } else
    printf("Not palindrome\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L1
  mov    %edi,%edx
  mov    $0x0,%ecx
L48:
  lea    (%rcx,%rcx,4),%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L48
  cmp    %ecx,%edi
  je     L1
  lea    D1(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D1
data_type: string
name: retrieve_data
arguments: data_label: D29
data_type: string

tool: D25: %d

tool: D1: Not palindrome


tool: D29: Is palindrome


assistant: ```c
int main() {
  int number, num, revnumber = 0, rem;
  scanf("%d", &number);
  num = number;
  while (num != 0) {
    rem = num % 10;
    revnumber = revnumber * 10 + rem;
    num /= 10;
  }
  if (number == revnumber) {
    printf("Is palindrome\n");
  } else
    printf("Not palindrome\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L5
  mov    %edi,%edx
  xor    %ecx,%ecx
  nopl   (%rax)
L7:
  movslq %edx,%rax
  lea    (%rcx,%rcx,4),%esi
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L7
  cmp    %ecx,%edi
  je     L5
  lea    D13(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D27
data_type: string

tool: D23: %d

tool: D13: Not palindrome


tool: D27: Is palindrome


assistant: ```c
int main() {
  int number, num, revnumber = 0, rem;
  scanf("%d", &number);
  num = number;
  while (num != 0) {
    rem = num % 10;
    revnumber = revnumber * 10 + rem;
    num /= 10;
  }
  if (number == revnumber) {
    printf("Is palindrome\n");
  } else
    printf("Not palindrome\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L14
  mov    %edi,%edx
  xor    %ecx,%ecx
  nopl   (%rax)
L27:
  movslq %edx,%rax
  lea    (%rcx,%rcx,4),%esi
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L27
  cmp    %ecx,%edi
  je     L14
  lea    D13(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L14:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D13
type_guessed: string
name: retrieve_data
arguments: label: D28
type_guessed: string

tool: D21: %d

tool: D13: Not palindrome


tool: D28: Is palindrome


assistant: ```c
int main() {
  int number, num, revnumber = 0, rem;
  scanf("%d", &number);
  num = number;
  while (num != 0) {
    rem = num % 10;
    revnumber = revnumber * 10 + rem;
    num /= 10;
  }
  if (number == revnumber) {
    printf("Is palindrome\n");
  } else
    printf("Not palindrome\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<wt_strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L58
L61:
  addq   $0x1,-0x20(%rbp)
L58:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  je     L55
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L61
L55:
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  jmp    L66
L1:
  cmpq   $0x1,-0x10(%rbp)
  je     L2
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
L2:
  addq   $0x1,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L66:
  leave
  ret
```

assistant: ```c
size_t wt_strlcat(char *dest, const char *source, size_t nMaxLength) {
  char *d = dest;
  const char *s = source;
  size_t n = nMaxLength;
  size_t dlen;
  while (n-- != 0 && *d != '\0') {
    d++;
  }
  dlen = d - dest;
  n = nMaxLength - dlen;
  if (n == 0) {
    return (dlen + strlen(s));
  }
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - source));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wt_strlcat>:
  endbr64
  push   %rbx
  test   %rdx,%rdx
  je     L86
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
L29:
  cmpb   $0x0,(%rax)
  je     L2
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L29
  mov    %rcx,%rax
L2:
  mov    %rax,%rbx
  sub    %r8,%rbx
  sub    %rbx,%rdx
  je     L4
  movzbl (%rsi),%r8d
  mov    %rsi,%rcx
  test   %r8b,%r8b
  jne    L50
L9:
  movb   $0x0,(%rax)
  sub    %rsi,%rcx
  lea    (%rcx,%rbx,1),%rax
L73:
  pop    %rbx
  ret
L86:
  mov    %rdx,%rbx
L4:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  jmp    L73
L38:
  add    $0x1,%rcx
  movzbl (%rcx),%r8d
  test   %r8b,%r8b
  je     L9
L50:
  cmp    $0x1,%rdx
  je     L38
  mov    %r8b,(%rax)
  sub    $0x1,%rdx
  lea    0x1(%rax),%rax
  jmp    L38
```

assistant: ```c
size_t wt_strlcat(char *dest, const char *source, size_t nMaxLength) {
  char *d = dest;
  const char *s = source;
  size_t n = nMaxLength;
  size_t dlen;
  while (n-- != 0 && *d != '\0') {
    d++;
  }
  dlen = d - dest;
  n = nMaxLength - dlen;
  if (n == 0) {
    return (dlen + strlen(s));
  }
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - source));
}
```