ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<otrl_base64_encode>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmp    $0x2,%rdx
  jbe    L18
  nopl   0x0(%rax)
L11:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x3,%edx
  sub    $0x3,%r12
  call   <encodeblock@plt>
  add    $0x4,%rbp
  add    $0x4,%r14
  add    $0x3,%r13
  cmp    $0x2,%r12
  ja     L11
L18:
  test   %r12,%r12
  jne    L12
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  add    $0x4,%r14
  call   <encodeblock@plt>
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t otrl_base64_encode(char *base64data, const unsigned char *data, size_t datalen) {
  size_t base64len = 0;
  while (datalen > 2) {
    encodeblock(base64data, data, 3);
    base64data += 4;
    base64len += 4;
    data += 3;
    datalen -= 3;
  }
  if (datalen > 0) {
    encodeblock(base64data, data, datalen);
    base64len += 4;
  }
  return base64len;
}
```
user: What is the c source code of the assembly code below?

```asm
<otrl_base64_encode>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmp    $0x2,%rdx
  jbe    L26
  nopl   0x0(%rax)
L2:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x3,%edx
  sub    $0x3,%r12
  call   <encodeblock@plt>
  add    $0x4,%rbp
  add    $0x4,%r14
  add    $0x3,%r13
  cmp    $0x2,%r12
  ja     L2
L26:
  test   %r12,%r12
  jne    L3
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  add    $0x4,%r14
  call   <encodeblock@plt>
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t otrl_base64_encode(char *base64data, const unsigned char *data, size_t datalen) {
  size_t base64len = 0;
  while (datalen > 2) {
    encodeblock(base64data, data, 3);
    base64data += 4;
    base64len += 4;
    data += 3;
    datalen -= 3;
  }
  if (datalen > 0) {
    encodeblock(base64data, data, datalen);
    base64len += 4;
  }
  return base64len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getCenturyAnchorDay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x190,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L81
  cmpl   $0x63,-0x4(%rbp)
  jg     L81
  mov    $0x2,%eax
  jmp    L119
L81:
  cmpl   $0x63,-0x4(%rbp)
  jle    L11
  cmpl   $0xc7,-0x4(%rbp)
  jg     L11
  mov    $0x0,%eax
  jmp    L119
L11:
  cmpl   $0xc7,-0x4(%rbp)
  jle    L83
  cmpl   $0x12b,-0x4(%rbp)
  jg     L83
  mov    $0x5,%eax
  jmp    L119
L83:
  cmpl   $0x12b,-0x4(%rbp)
  jle    L67
  cmpl   $0x18f,-0x4(%rbp)
  jg     L67
  mov    $0x3,%eax
  jmp    L119
L67:
  mov    $0x0,%eax
L119:
  pop    %rbp
  ret
```

assistant: ```c
int getCenturyAnchorDay(int year) {
  year %= 400;
  if (year >= 0 && year <= 99)
    return 2;
  if (year >= 100 && year <= 199)
    return 0;
  if (year >= 200 && year <= 299)
    return 5;
  if (year >= 300 && year <= 399)
    return 3;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getCenturyAnchorDay>:
  endbr64
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  mov    $0x2,%edx
  cmp    $0x63,%eax
  jbe    L1
  lea    -0x64(%rax),%ecx
  mov    $0x0,%edx
  cmp    $0x63,%ecx
  jbe    L1
  lea    -0xc8(%rax),%ecx
  mov    $0x5,%edx
  cmp    $0x63,%ecx
  jbe    L1
  sub    $0x12c,%eax
  cmp    $0x64,%eax
  sbb    %edx,%edx
  and    $0x3,%edx
L1:
  mov    %edx,%eax
  ret
```

assistant: ```c
int getCenturyAnchorDay(int year) {
  year %= 400;
  if (year >= 0 && year <= 99)
    return 2;
  if (year >= 100 && year <= 199)
    return 0;
  if (year >= 200 && year <= 299)
    return 5;
  if (year >= 300 && year <= 399)
    return 3;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getCenturyAnchorDay>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  mov    $0x2,%r8d
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x27,%rax
  sub    %edx,%eax
  imul   $0x190,%eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  cmp    $0x63,%eax
  jbe    L11
  lea    -0x64(%rax),%edx
  xor    %r8d,%r8d
  cmp    $0x63,%edx
  jbe    L11
  lea    -0xc8(%rax),%edx
  mov    $0x5,%r8d
  cmp    $0x63,%edx
  jbe    L11
  sub    $0x12c,%eax
  cmp    $0x64,%eax
  sbb    %r8d,%r8d
  and    $0x3,%r8d
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getCenturyAnchorDay(int year) {
  year %= 400;
  if (year >= 0 && year <= 99)
    return 2;
  if (year >= 100 && year <= 199)
    return 0;
  if (year >= 200 && year <= 299)
    return 5;
  if (year >= 300 && year <= 399)
    return 3;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getCenturyAnchorDay>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  mov    $0x2,%r8d
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x27,%rax
  sub    %edx,%eax
  imul   $0x190,%eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  cmp    $0x63,%eax
  jbe    L24
  lea    -0x64(%rax),%edx
  xor    %r8d,%r8d
  cmp    $0x63,%edx
  jbe    L24
  lea    -0xc8(%rax),%edx
  mov    $0x5,%r8d
  cmp    $0x63,%edx
  jbe    L24
  sub    $0x12c,%eax
  cmp    $0x64,%eax
  sbb    %r8d,%r8d
  and    $0x3,%r8d
L24:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getCenturyAnchorDay(int year) {
  year %= 400;
  if (year >= 0 && year <= 99)
    return 2;
  if (year >= 100 && year <= 199)
    return 0;
  if (year >= 200 && year <= 299)
    return 5;
  if (year >= 300 && year <= 399)
    return 3;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  movabs $0xfffffc01c0000008,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x3,%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  sarq   %cl,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzwl %ax,%eax
  pop    %rbp
  ret
```

assistant: ```c
extern unsigned int inw(unsigned long addr) {
  long result = *(volatile int *)((addr << 5) + ((0xfffffc0000000000UL) + 0x1c0000000UL) + 0x08);
  result >>= (addr & 3) * 8;
  return 0xffffUL & result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inw>:
  endbr64
  mov    %rdi,%rax
  shl    $0x5,%rax
  movabs $0xfffffc01c0000008,%rdx
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  and    $0x3,%edi
  lea    0x0(,%rdi,8),%ecx
  sar    %cl,%rax
  movzwl %ax,%eax
  ret
```

assistant: ```c
extern unsigned int inw(unsigned long addr) {
  long result = *(volatile int *)((addr << 5) + ((0xfffffc0000000000UL) + 0x1c0000000UL) + 0x08);
  result >>= (addr & 3) * 8;
  return 0xffffUL & result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inw>:
  endbr64
  movabs $0xfffffc01c0000008,%rdx
  mov    %rdi,%rax
  and    $0x3,%edi
  shl    $0x5,%rax
  lea    0x0(,%rdi,8),%ecx
  add    %rdx,%rax
  movslq (%rax),%rax
  sar    %cl,%rax
  movzwl %ax,%eax
  ret
```

assistant: ```c
extern unsigned int inw(unsigned long addr) {
  long result = *(volatile int *)((addr << 5) + ((0xfffffc0000000000UL) + 0x1c0000000UL) + 0x08);
  result >>= (addr & 3) * 8;
  return 0xffffUL & result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<inw>:
  endbr64
  movabs $0xfffffc01c0000008,%rdx
  mov    %rdi,%rax
  and    $0x3,%edi
  shl    $0x5,%rax
  lea    0x0(,%rdi,8),%ecx
  add    %rdx,%rax
  movslq (%rax),%rax
  sar    %cl,%rax
  movzwl %ax,%eax
  ret
```

assistant: ```c
extern unsigned int inw(unsigned long addr) {
  long result = *(volatile int *)((addr << 5) + ((0xfffffc0000000000UL) + 0x1c0000000UL) + 0x08);
  result >>= (addr & 3) * 8;
  return 0xffffUL & result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_XTransGetHostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <gethostname@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _XTransGetHostname(char *buf, int maxlen) {
  int len;
  buf[0] = '\0';
  (void)gethostname(buf, maxlen);
  buf[maxlen - 1] = '\0';
  len = strlen(buf);
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_XTransGetHostname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  movb   $0x0,(%rdi)
  call   <gethostname@plt>
  movslq %ebp,%rbp
  movb   $0x0,-0x1(%rbx,%rbp,1)
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _XTransGetHostname(char *buf, int maxlen) {
  int len;
  buf[0] = '\0';
  (void)gethostname(buf, maxlen);
  buf[maxlen - 1] = '\0';
  len = strlen(buf);
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_XTransGetHostname>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  movb   $0x0,(%rdi)
  call   <gethostname@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
int _XTransGetHostname(char *buf, int maxlen) {
  int len;
  buf[0] = '\0';
  (void)gethostname(buf, maxlen);
  buf[maxlen - 1] = '\0';
  len = strlen(buf);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_XTransGetHostname>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  movb   $0x0,(%rdi)
  call   <gethostname@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
int _XTransGetHostname(char *buf, int maxlen) {
  int len;
  buf[0] = '\0';
  (void)gethostname(buf, maxlen);
  buf[maxlen - 1] = '\0';
  len = strlen(buf);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<julian_get_month_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%r9
  lea    -0x14(%rbp),%r8
  lea    -0x18(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x1c(%rbp),%rsi
  lea    -0x20(%rbp),%rdi
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <jul2greg@plt>
  mov    -0x20(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int julian_get_month_number(double current) {
  int year, month, day, hour, minute;
  double seconds;
  jul2greg(current, &month, &day, &year, &hour, &minute, &seconds);
  return month;
}
```
user: What is the c source code of the assembly code below:

```asm
<julian_get_month_number>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <jul2greg@plt>
  mov    0x10(%rsp),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int julian_get_month_number(double current) {
  int year, month, day, hour, minute;
  double seconds;
  jul2greg(current, &month, &day, &year, &hour, &minute, &seconds);
  return month;
}
```
user: Translate the below assembly code into C programming language:

```asm
<julian_get_month_number>:
  endbr64
  sub    $0x38,%rsp
  lea    0x18(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <jul2greg@plt>
  mov    0x10(%rsp),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int julian_get_month_number(double current) {
  int year, month, day, hour, minute;
  double seconds;
  jul2greg(current, &month, &day, &year, &hour, &minute, &seconds);
  return month;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<julian_get_month_number>:
  endbr64
  sub    $0x38,%rsp
  lea    0x18(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <jul2greg@plt>
  mov    0x10(%rsp),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int julian_get_month_number(double current) {
  int year, month, day, hour, minute;
  double seconds;
  jul2greg(current, &month, &day, &year, &hour, &minute, &seconds);
  return month;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<axp_set_chargevoltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int axp_set_chargevoltage(int vol) {
  int ret = 0;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<axp_set_chargevoltage>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int axp_set_chargevoltage(int vol) {
  int ret = 0;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<axp_set_chargevoltage>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int axp_set_chargevoltage(int vol) {
  int ret = 0;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<axp_set_chargevoltage>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int axp_set_chargevoltage(int vol) {
  int ret = 0;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<progress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xd,%edi
  call   <fputc@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <fprintf@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  nop
  leave
  ret
```

assistant: ```c
void progress(char *c, int i) {
  fputc('\r', stdout);
  fprintf(stdout, c, i);
  fflush(stdout);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<progress>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    D7(%rip),%rbx
  mov    (%rbx),%esi
  mov    $0xd,%edi
  call   <fputc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <fprintf@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void progress(char *c, int i) {
  fputc('\r', stdout);
  fprintf(stdout, c, i);
  fflush(stdout);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<progress>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xd,%edi
  push   %rbx
  mov    D1(%rip),%rbx
  mov    (%rbx),%esi
  call   <fputc@plt>
  mov    (%rbx),%edi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <fprintf@plt>
  mov    (%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <fflush@plt>
```

assistant: ```c
void progress(char *c, int i) {
  fputc('\r', stdout);
  fprintf(stdout, c, i);
  fflush(stdout);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<progress>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xd,%edi
  push   %rbx
  mov    D1(%rip),%rbx
  mov    (%rbx),%esi
  call   <fputc@plt>
  mov    (%rbx),%edi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <fprintf@plt>
  mov    (%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <fflush@plt>
```

assistant: ```c
void progress(char *c, int i) {
  fputc('\r', stdout);
  fprintf(stdout, c, i);
  fflush(stdout);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <init_dec@plt>
  mov    $0x80,%edi
  call   <test@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  init();
  init_dec();
  test((1 << 8) / 2);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <init_dec@plt>
  mov    $0x80,%edi
  call   <test@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  init_dec();
  test((1 << 8) / 2);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <init_dec@plt>
  mov    $0x80,%edi
  call   <test@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  init_dec();
  test((1 << 8) / 2);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <init_dec@plt>
  mov    $0x80,%edi
  call   <test@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  init_dec();
  test((1 << 8) / 2);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CLAMP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  -0x8(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L29
  movss  -0x8(%rbp),%xmm0
  jmp    L31
L29:
  movss  -0x4(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L4
  movss  -0xc(%rbp),%xmm0
  jmp    L31
L4:
  movss  -0x4(%rbp),%xmm0
L31:
  pop    %rbp
  ret
```

assistant: ```c
float CLAMP(float x, float min, float max) {
  if (x < min)
    return min;
  if (x > max)
    return max;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CLAMP>:
  endbr64
  comiss %xmm0,%xmm1
  ja     L0
  minss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
L0:
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float CLAMP(float x, float min, float max) {
  if (x < min)
    return min;
  if (x > max)
    return max;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CLAMP>:
  endbr64
  comiss %xmm0,%xmm1
  ja     L2
  minss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L2:
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float CLAMP(float x, float min, float max) {
  if (x < min)
    return min;
  if (x > max)
    return max;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CLAMP>:
  endbr64
  comiss %xmm0,%xmm1
  ja     L4
  minss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L4:
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float CLAMP(float x, float min, float max) {
  if (x < min)
    return min;
  if (x > max)
    return max;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f11>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0xf,%al
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
signed int f11(signed int v_foo) {
  signed int v_shr = v_foo << 2;
  signed int v_and = v_shr & -241;
  return v_and;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f11>:
  endbr64
  lea    0x0(,%rdi,4),%eax
  and    $0xf,%al
  ret
```

assistant: ```c
signed int f11(signed int v_foo) {
  signed int v_shr = v_foo << 2;
  signed int v_and = v_shr & -241;
  return v_and;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f11>:
  endbr64
  lea    0x0(,%rdi,4),%eax
  and    $0xf,%al
  ret
```

assistant: ```c
signed int f11(signed int v_foo) {
  signed int v_shr = v_foo << 2;
  signed int v_and = v_shr & -241;
  return v_and;
}
```