ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jle    L14
  mov    -0x4(%rbp),%eax
  jmp    L9
L14:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <foo>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
L9:
  leave
  ret
```

assistant: ```c
int foo(int a) {
  if (a > 3)
    return a;
  return a + foo(a + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x3,%edi
  jle    L12
L10:
  mov    %ebx,%eax
  pop    %rbx
  ret
L12:
  lea    0x1(%rdi),%edi
  call   <foo>
  add    %eax,%ebx
  jmp    L10
```

assistant: ```c
int foo(int a) {
  if (a > 3)
    return a;
  return a + foo(a + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  cmp    $0x3,%edi
  jg     L5
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %edi,%edx
  add    $0x1,%edi
  add    %edx,%eax
  cmp    $0x4,%edi
  jne    L11
  add    $0x4,%eax
  ret
L5:
  mov    %edi,%eax
  ret
```

assistant: ```c
int foo(int a) {
  if (a > 3)
    return a;
  return a + foo(a + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  mov    %edi,%edx
  cmp    $0x3,%edi
  jg     L36
  mov    $0x3,%eax
  mov    $0x4,%esi
  sub    %edi,%eax
  sub    %edi,%esi
  cmp    $0x9,%eax
  jbe    L60
  movd   %edi,%xmm4
  mov    %esi,%ecx
  movdqa D15(%rip),%xmm3
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm1
  paddd  D11(%rip),%xmm1
  shr    $0x2,%ecx
  pxor   %xmm0,%xmm0
  nopw   0x0(%rax,%rax,1)
L34:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%ecx
  jne    L34
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  add    %ecx,%edx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %ecx,%esi
  je     L39
L73:
  lea    0x1(%rdx),%ecx
  add    %edx,%eax
  cmp    $0x3,%edx
  je     L39
  lea    0x2(%rdx),%esi
  add    %ecx,%eax
  cmp    $0x2,%edx
  je     L39
  lea    0x3(%rdx),%ecx
  add    %esi,%eax
  cmp    $0x1,%edx
  je     L39
  lea    0x4(%rdx),%esi
  add    %ecx,%eax
  test   %edx,%edx
  je     L39
  lea    0x5(%rdx),%ecx
  add    %esi,%eax
  cmp    $0xffffffff,%edx
  je     L39
  lea    0x6(%rdx),%esi
  add    %ecx,%eax
  cmp    $0xfffffffe,%edx
  je     L39
  lea    0x7(%rdx),%ecx
  add    %esi,%eax
  cmp    $0xfffffffd,%edx
  je     L39
  lea    0x8(%rdx),%esi
  add    %ecx,%eax
  cmp    $0xfffffffc,%edx
  je     L39
  add    %esi,%eax
  add    $0x9,%edx
  lea    (%rax,%rdx,1),%ecx
  cmp    $0x4,%edx
  cmovne %ecx,%eax
L39:
  add    $0x4,%eax
  ret
  nopl   (%rax)
L36:
  mov    %edi,%eax
  ret
L60:
  xor    %eax,%eax
  jmp    L73
```

tool_calls: name: parse_data
arguments: tag: D15
datatype: byte[16]
name: parse_data
arguments: tag: D11
datatype: byte[16]

tool: {"D15": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int foo(int a) {
  if (a > 3)
    return a;
  return a + foo(a + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L195:
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L59:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L56
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L56
  cmpl   $0x0,-0x8(%rbp)
  jle    L56
  cmpl   $0x0,-0x4(%rbp)
  jg     L169
L56:
  cmpl   $0x0,-0x4(%rbp)
  jne    L9
  cmpl   $0x0,-0x8(%rbp)
  jne    L9
L169:
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
  jmp    L133
L9:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L104
  cmpl   $0x0,-0x8(%rbp)
  je     L10
L104:
  cmpl   $0x0,-0x4(%rbp)
  jne    L32
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L32
L10:
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  jmp    L133
L32:
  cmpl   $0x0,-0x4(%rbp)
  je     L205
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  je     L205
  cmpl   $0x0,-0x8(%rbp)
  je     L205
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L99
L205:
  mov    $0x2a,%edi
  call   <ft_putchar@plt>
  jmp    L133
L99:
  mov    $0x20,%edi
  call   <ft_putchar@plt>
L133:
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L59
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L195
  nop
  nop
  leave
  ret
```

assistant: ```c
void rush(int x, int y) {
  int it_x;
  int it_y;
  it_y = 0;
  while (it_y < y) {
    it_x = 0;
    while (it_x < x) {
      if ((it_y == y - 1 && it_x == x - 1 && it_x > 0 && it_y > 0) || (it_y == 0 && it_x == 0))
        ft_putchar('/');
      else if ((it_y == y - 1 && it_x == 0) || (it_y == 0 && it_x == x - 1))
        ft_putchar('\\');
      else if (it_y == 0 || it_y == y - 1 || it_x == 0 || it_x == x - 1)
        ft_putchar('*');
      else
        ft_putchar(' ');
      it_x++;
    }
    ft_putchar('\n');
    it_y++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rush>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,0xc(%rsp)
  mov    $0x0,%ebp
  lea    -0x1(%rsi),%r13d
  lea    -0x1(%rdi),%r14d
  test   %esi,%esi
  jg     L138
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L147:
  cmp    %ebx,%r14d
  je     L34
L164:
  mov    %ebx,%eax
  or     %ebp,%eax
  je     L115
  test   %ebx,%ebx
  je     L103
  test   %ebp,%ebp
  jne    L68
L118:
  cmp    %ebx,%r14d
  je     L103
L68:
  mov    $0x2a,%edi
  call   <ft_putchar@plt>
  jmp    L57
L34:
  test   %ebx,%ebx
  jle    L164
  test   %ebp,%ebp
  jle    L164
L115:
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
L57:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L42
L76:
  cmp    %ebp,%r13d
  je     L147
  mov    %ebx,%eax
  or     %ebp,%eax
  je     L115
  test   %ebx,%ebx
  sete   %al
  test   %ebp,%ebp
  je     L118
  test   %al,%al
  jne    L68
  test   %r15b,%r15b
  jne    L68
  cmp    %ebx,%r14d
  je     L68
  mov    $0x20,%edi
  call   <ft_putchar@plt>
  jmp    L57
L103:
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  jmp    L57
L42:
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  je     L12
L138:
  cmp    %ebp,%r13d
  sete   %r15b
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L76
  jmp    L42
```

assistant: ```c
void rush(int x, int y) {
  int it_x;
  int it_y;
  it_y = 0;
  while (it_y < y) {
    it_x = 0;
    while (it_x < x) {
      if ((it_y == y - 1 && it_x == x - 1 && it_x > 0 && it_y > 0) || (it_y == 0 && it_x == 0))
        ft_putchar('/');
      else if ((it_y == y - 1 && it_x == 0) || (it_y == 0 && it_x == x - 1))
        ft_putchar('\\');
      else if (it_y == 0 || it_y == y - 1 || it_x == 0 || it_x == x - 1)
        ft_putchar('*');
      else
        ft_putchar(' ');
      it_x++;
    }
    ft_putchar('\n');
    it_y++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rush>:
  endbr64
  test   %esi,%esi
  jle    L180
  push   %r15
  mov    %esi,%r15d
  push   %r14
  lea    -0x1(%rdi),%r14d
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L156:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jg     L65
  jmp    L139
  nopl   0x0(%rax)
L19:
  test   %ebp,%ebp
  je     L14
  test   %ebx,%ebx
  je     L20
  cmp    %ebx,%r14d
  je     L20
  mov    $0x20,%edi
  call   <ft_putchar@plt>
  nop
L81:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L139
L65:
  cmp    %ebp,%r13d
  je     L94
  mov    %ebx,%eax
  or     %ebp,%eax
  jne    L19
L120:
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
L111:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L65
L139:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <ft_putchar@plt>
  cmp    %ebp,%r15d
  jne    L156
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L94:
  cmp    %ebx,%r14d
  je     L200
L143:
  mov    %ebx,%eax
  or     %ebp,%eax
  je     L120
  test   %ebx,%ebx
  je     L4
  test   %ebp,%ebp
  jne    L20
  nopl   0x0(%rax,%rax,1)
L14:
  cmp    %ebx,%r14d
  je     L4
L20:
  mov    $0x2a,%edi
  call   <ft_putchar@plt>
  jmp    L81
  nopl   0x0(%rax)
L4:
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  jmp    L81
  nop
L200:
  test   %r14d,%r14d
  jle    L143
  test   %r13d,%r13d
  jle    L143
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
  jmp    L111
L180:
  ret
```

assistant: ```c
void rush(int x, int y) {
  int it_x;
  int it_y;
  it_y = 0;
  while (it_y < y) {
    it_x = 0;
    while (it_x < x) {
      if ((it_y == y - 1 && it_x == x - 1 && it_x > 0 && it_y > 0) || (it_y == 0 && it_x == 0))
        ft_putchar('/');
      else if ((it_y == y - 1 && it_x == 0) || (it_y == 0 && it_x == x - 1))
        ft_putchar('\\');
      else if (it_y == 0 || it_y == y - 1 || it_x == 0 || it_x == x - 1)
        ft_putchar('*');
      else
        ft_putchar(' ');
      it_x++;
    }
    ft_putchar('\n');
    it_y++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rush>:
  endbr64
  test   %esi,%esi
  jle    L29
  push   %r15
  lea    -0x1(%rsi),%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    -0x1(%rdi),%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L43:
  test   %ebp,%ebp
  jle    L7
  xor    %ebx,%ebx
  cmp    %r12d,%r15d
  je     L163
  test   %r12d,%r12d
  jne    L140
  jmp    L244
  nopl   0x0(%rax)
L247:
  cmp    %r13d,%ebx
  je     L265
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebx,%ebp
  je     L7
  cs nopw 0x0(%rax,%rax,1)
L140:
  test   %ebx,%ebx
  jne    L247
L265:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebx,%ebp
  jne    L140
  nopl   (%rax)
L7:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <ft_putchar@plt>
  cmp    %r12d,%r14d
  jne    L43
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L255:
  cmp    %ebx,%r13d
  je     L278
  mov    $0x2a,%edi
  call   <ft_putchar@plt>
L93:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L7
L244:
  test   %ebx,%ebx
  jne    L255
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
  jmp    L93
  cs nopw 0x0(%rax,%rax,1)
L278:
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  jmp    L93
  nopl   0x0(%rax)
L163:
  test   %r15d,%r15d
  jne    L101
  jmp    L152
  nopw   0x0(%rax,%rax,1)
L131:
  test   %ebx,%ebx
  je     L183
  mov    $0x2a,%edi
  call   <ft_putchar@plt>
L263:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L7
L101:
  cmp    %r13d,%ebx
  jne    L131
  test   %ebx,%ebx
  jle    L131
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
  jmp    L263
L211:
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
L204:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L7
L152:
  cmp    %ebx,%r13d
  je     L237
  test   %ebx,%ebx
  je     L211
  mov    $0x2a,%edi
  call   <ft_putchar@plt>
  jmp    L204
L183:
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  jmp    L263
  nopl   0x0(%rax)
L237:
  test   %r13d,%r13d
  je     L211
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  jmp    L204
L29:
  ret
```

assistant: ```c
void rush(int x, int y) {
  int it_x;
  int it_y;
  it_y = 0;
  while (it_y < y) {
    it_x = 0;
    while (it_x < x) {
      if ((it_y == y - 1 && it_x == x - 1 && it_x > 0 && it_y > 0) || (it_y == 0 && it_x == 0))
        ft_putchar('/');
      else if ((it_y == y - 1 && it_x == 0) || (it_y == 0 && it_x == x - 1))
        ft_putchar('\\');
      else if (it_y == 0 || it_y == y - 1 || it_x == 0 || it_x == x - 1)
        ft_putchar('*');
      else
        ft_putchar(' ');
      it_x++;
    }
    ft_putchar('\n');
    it_y++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<str_isnumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L24
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L11
  mov    $0x0,%eax
  jmp    L35
L11:
  addq   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    $0x1,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int str_isnumber(p) const char *p;
{
  char *q = (char *)p;
  while (*q) {
    if (!isdigit(*q))
      return 0;
    q++;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_isnumber>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
L6:
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L26
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
  mov    $0x1,%eax
  ret
L24:
  mov    $0x1,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int str_isnumber(p) const char *p;
{
  char *q = (char *)p;
  while (*q) {
    if (!isdigit(*q))
      return 0;
    q++;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_isnumber>:
  endbr64
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L21:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L22
  add    $0x1,%rdi
L18:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L21
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int str_isnumber(p) const char *p;
{
  char *q = (char *)p;
  while (*q) {
    if (!isdigit(*q))
      return 0;
    q++;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_isnumber>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L2:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L29
  add    $0x1,%rdi
L0:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L2
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
int str_isnumber(p) const char *p;
{
  char *q = (char *)p;
  while (*q) {
    if (!isdigit(*q))
      return 0;
    q++;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fake_localtime_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x0,%eax
  jmp    L19
L18:
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
L19:
  leave
  ret
```

assistant: ```c
struct tm *fake_localtime_r(const time_t *time, struct tm *result) {
  const struct tm *static_result = localtime(time);
  assert(result != NULL);
  if (static_result == NULL) {
    memset(result, 0, sizeof(*result));
    return NULL;
  } else {
    memcpy(result, static_result, sizeof(*result));
    return result;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<fake_localtime_r>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <localtime@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L5
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rbx
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  jmp    L10
```

assistant: ```c
struct tm *fake_localtime_r(const time_t *time, struct tm *result) {
  const struct tm *static_result = localtime(time);
  assert(result != NULL);
  if (static_result == NULL) {
    memset(result, 0, sizeof(*result));
    return NULL;
  } else {
    memcpy(result, static_result, sizeof(*result));
    return result;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fake_localtime_r>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <localtime@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    $0x4,%edx
  test   %r12,%r12
  je     L5
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbp,%r12
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct tm *fake_localtime_r(const time_t *time, struct tm *result) {
  const struct tm *static_result = localtime(time);
  assert(result != NULL);
  if (static_result == NULL) {
    memset(result, 0, sizeof(*result));
    return NULL;
  } else {
    memcpy(result, static_result, sizeof(*result));
    return result;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fake_localtime_r>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <localtime@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    $0x4,%edx
  test   %r12,%r12
  je     L0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbp,%r12
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct tm *fake_localtime_r(const time_t *time, struct tm *result) {
  const struct tm *static_result = localtime(time);
  assert(result != NULL);
  if (static_result == NULL) {
    memset(result, 0, sizeof(*result));
    return NULL;
  } else {
    memcpy(result, static_result, sizeof(*result));
    return result;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L34
L26:
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0xf0000000,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  shr    $0x18,%rax
  xor    -0x10(%rbp),%rax
  xor    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0x10(%rbp),%rax
L34:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long string_hash(const unsigned char *x) {
  unsigned long g, h = 0;
  if (!x)
    return 0;
  while (*x != 0) {
    h = (h << 4) + *x++;
    if ((g = h & 0xf0000000) != 0)
      h = (h ^ (g >> 24)) ^ g;
  }
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<string_hash>:
  endbr64
  test   %rdi,%rdi
  je     L46
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  movzbl %dl,%eax
  movabs $0xffffffff0fffffff,%rcx
  test   %dl,%dl
  je     L39
L9:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L34
  shl    $0x4,%rax
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L9
  and    %rcx,%rax
  shr    $0x18,%rdx
  xor    %rdx,%rax
  jmp    L9
L39:
  mov    $0x0,%eax
  ret
L34:
  ret
L46:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long string_hash(const unsigned char *x) {
  unsigned long g, h = 0;
  if (!x)
    return 0;
  while (*x != 0) {
    h = (h << 4) + *x++;
    if ((g = h & 0xf0000000) != 0)
      h = (h ^ (g >> 24)) ^ g;
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<string_hash>:
  endbr64
  test   %rdi,%rdi
  je     L38
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  movabs $0xffffffff0fffffff,%rcx
  test   %al,%al
  je     L38
L30:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L11
L37:
  shl    $0x4,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L30
  shr    $0x18,%rdx
  and    %rcx,%rax
  xor    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L37
L11:
  ret
  nopl   (%rax)
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long string_hash(const unsigned char *x) {
  unsigned long g, h = 0;
  if (!x)
    return 0;
  while (*x != 0) {
    h = (h << 4) + *x++;
    if ((g = h & 0xf0000000) != 0)
      h = (h ^ (g >> 24)) ^ g;
  }
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<string_hash>:
  endbr64
  test   %rdi,%rdi
  je     L44
  movzbl (%rdi),%eax
  test   %al,%al
  je     L44
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rcx
  movabs $0xffffffff0fffffff,%rsi
  test   %dl,%dl
  je     L5
  cs nopw 0x0(%rax,%rax,1)
L13:
  shl    $0x4,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L2
  and    %rsi,%rax
  shr    $0x18,%rdx
  xor    %rdx,%rax
L2:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
  nopl   0x0(%rax)
L44:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long string_hash(const unsigned char *x) {
  unsigned long g, h = 0;
  if (!x)
    return 0;
  while (*x != 0) {
    h = (h << 4) + *x++;
    if ((g = h & 0xf0000000) != 0)
      h = (h ^ (g >> 24)) ^ g;
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__crypt_r@plt>
  leave
  ret
```

assistant: ```c
char *crypt(const char *key, const char *salt) {
  static char buf[64];
  return __crypt_r(key, salt, (struct crypt_data *)buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<crypt>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdx
  call   <__crypt_r@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *crypt(const char *key, const char *salt) {
  static char buf[64];
  return __crypt_r(key, salt, (struct crypt_data *)buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crypt>:
  endbr64
  lea    D8(%rip),%rdx
  jmp    1050 <__crypt_r@plt>
```

assistant: ```c
char *crypt(const char *key, const char *salt) {
  static char buf[64];
  return __crypt_r(key, salt, (struct crypt_data *)buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crypt>:
  endbr64
  lea    D3(%rip),%rdx
  jmp    1050 <__crypt_r@plt>
```

assistant: ```c
char *crypt(const char *key, const char *salt) {
  static char buf[64];
  return __crypt_r(key, salt, (struct crypt_data *)buf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string

tool: D1: %d

tool: D12: O numero sorteado foi: %d


assistant: ```c
int main() {
  int x;
  scanf("%d", &x);
  printf("O numero sorteado foi: %d\n", x);
  return 0;
}
```