ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<convert_nonman_nonmotoram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x448,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %rdx,-0x448(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x42c(%rbp)
  mov    -0x440(%rbp),%rdx
  lea    -0x420(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x448(%rbp),%rdx
  lea    -0x420(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x42c(%rbp),%eax
  cltq
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x428(%rbp)
  movl   $0x0,-0x430(%rbp)
  jmp    L29
L24:
  mov    -0x430(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x428(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x1,%esi
  mov    $0x400,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x430(%rbp)
L29:
  mov    -0x430(%rbp),%eax
  cmp    -0x42c(%rbp),%eax
  jl     L24
  mov    -0x428(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x438(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x428(%rbp),%rax
  mov    (%rax),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  movabs $0x5f6e616d6e6f6e5c,%rcx
  movabs $0x726f746f6d6e6f6e,%rbx
  mov    %rcx,(%rax)
  mov    %rbx,0x8(%rax)
  movabs $0x616e69622e6d615f,%rcx
  mov    %rcx,0x10(%rax)
  movw   $0x7972,0x18(%rax)
  movb   $0x0,0x1a(%rax)
  mov    -0x42c(%rbp),%edx
  lea    -0x420(%rbp),%rcx
  mov    -0x428(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <combineBinaryTablesInTpplusFile@plt>
  movl   $0x0,-0x430(%rbp)
  jmp    L4
L40:
  mov    -0x430(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x430(%rbp)
L4:
  mov    -0x430(%rbp),%eax
  cmp    -0x42c(%rbp),%eax
  jl     L40
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void convert_nonman_nonmotoram(char *binaryFilesDirectory, char *tppFilesDirectory, char *tppFileName) {
  void combineBinaryTablesInTpplusFile(char **binaryFileNames, char *tppFileName, int ntables);
  int i;
  int nTables = 1;
  char **binaryFileNames;
  char fileName[1024];
  strcpy(fileName, tppFilesDirectory);
  strcat(fileName, tppFileName);
  binaryFileNames = (char **)calloc(nTables, sizeof(char *));
  for (i = 0; i < nTables; i++)
    binaryFileNames[i] = (char *)calloc(1024, sizeof(char));
  strcpy(binaryFileNames[0], binaryFilesDirectory);
  strcat(binaryFileNames[0], "\\nonman_nonmotor_am.binary");
  combineBinaryTablesInTpplusFile(binaryFileNames, fileName, nTables);
  for (i = 0; i < nTables; i++)
    free(binaryFileNames[i]);
  free(binaryFileNames);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<convert_nonman_nonmotoram>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%r13
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    $0x8,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    $0x1,%esi
  mov    $0x400,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %rax,0x0(%rbp)
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  movabs $0x5f6e616d6e6f6e5c,%rax
  movabs $0x726f746f6d6e6f6e,%rdx
  mov    %rax,(%rbx)
  mov    %rdx,0x8(%rbx)
  movabs $0x616e69622e6d615f,%rax
  mov    %rax,0x10(%rbx)
  movw   $0x7972,0x18(%rbx)
  movb   $0x0,0x1a(%rbx)
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <combineBinaryTablesInTpplusFile@plt>
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert_nonman_nonmotoram(char *binaryFilesDirectory, char *tppFilesDirectory, char *tppFileName) {
  void combineBinaryTablesInTpplusFile(char **binaryFileNames, char *tppFileName, int ntables);
  int i;
  int nTables = 1;
  char **binaryFileNames;
  char fileName[1024];
  strcpy(fileName, tppFilesDirectory);
  strcat(fileName, tppFileName);
  binaryFileNames = (char **)calloc(nTables, sizeof(char *));
  for (i = 0; i < nTables; i++)
    binaryFileNames[i] = (char *)calloc(1024, sizeof(char));
  strcpy(binaryFileNames[0], binaryFilesDirectory);
  strcat(binaryFileNames[0], "\\nonman_nonmotor_am.binary");
  combineBinaryTablesInTpplusFile(binaryFileNames, fileName, nTables);
  for (i = 0; i < nTables; i++)
    free(binaryFileNames[i]);
  free(binaryFileNames);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert_nonman_nonmotoram>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    $0x8,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    $0x1,%esi
  mov    $0x400,%edi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %r13,%rsi
  mov    %rax,0x0(%rbp)
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    %r12,%rsi
  add    %rax,%rbx
  movdqa D0(%rip),%xmm0
  movabs $0x616e69622e6d615f,%rax
  mov    %rax,0x10(%rbx)
  mov    $0x7972,%eax
  mov    %ax,0x18(%rbx)
  movb   $0x0,0x1a(%rbx)
  movups %xmm0,(%rbx)
  call   <combineBinaryTablesInTpplusFile@plt>
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x418,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <free@plt>
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: byte[16]

tool: {"D0": [0x5c,0x6e,0x6f,0x6e,0x6d,0x61,0x6e,0x5f,0x6e,0x6f,0x6e,0x6d,0x6f,0x74,0x6f,0x72]}

assistant: ```c
void convert_nonman_nonmotoram(char *binaryFilesDirectory, char *tppFilesDirectory, char *tppFileName) {
  void combineBinaryTablesInTpplusFile(char **binaryFileNames, char *tppFileName, int ntables);
  int i;
  int nTables = 1;
  char **binaryFileNames;
  char fileName[1024];
  strcpy(fileName, tppFilesDirectory);
  strcat(fileName, tppFileName);
  binaryFileNames = (char **)calloc(nTables, sizeof(char *));
  for (i = 0; i < nTables; i++)
    binaryFileNames[i] = (char *)calloc(1024, sizeof(char));
  strcpy(binaryFileNames[0], binaryFilesDirectory);
  strcat(binaryFileNames[0], "\\nonman_nonmotor_am.binary");
  combineBinaryTablesInTpplusFile(binaryFileNames, fileName, nTables);
  for (i = 0; i < nTables; i++)
    free(binaryFileNames[i]);
  free(binaryFileNames);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<convert_nonman_nonmotoram>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    $0x8,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    $0x1,%esi
  mov    $0x400,%edi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %r13,%rsi
  mov    %rax,0x0(%rbp)
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    %r12,%rsi
  add    %rax,%rbx
  movdqa D0(%rip),%xmm0
  movabs $0x616e69622e6d615f,%rax
  mov    %rax,0x10(%rbx)
  mov    $0x7972,%eax
  mov    %ax,0x18(%rbx)
  movb   $0x0,0x1a(%rbx)
  movups %xmm0,(%rbx)
  call   <combineBinaryTablesInTpplusFile@plt>
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x418,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <free@plt>
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: byte[16]

tool: {"D0": [0x5c,0x6e,0x6f,0x6e,0x6d,0x61,0x6e,0x5f,0x6e,0x6f,0x6e,0x6d,0x6f,0x74,0x6f,0x72]}

assistant: ```c
void convert_nonman_nonmotoram(char *binaryFilesDirectory, char *tppFilesDirectory, char *tppFileName) {
  void combineBinaryTablesInTpplusFile(char **binaryFileNames, char *tppFileName, int ntables);
  int i;
  int nTables = 1;
  char **binaryFileNames;
  char fileName[1024];
  strcpy(fileName, tppFilesDirectory);
  strcat(fileName, tppFileName);
  binaryFileNames = (char **)calloc(nTables, sizeof(char *));
  for (i = 0; i < nTables; i++)
    binaryFileNames[i] = (char *)calloc(1024, sizeof(char));
  strcpy(binaryFileNames[0], binaryFilesDirectory);
  strcat(binaryFileNames[0], "\\nonman_nonmotor_am.binary");
  combineBinaryTablesInTpplusFile(binaryFileNames, fileName, nTables);
  for (i = 0; i < nTables; i++)
    free(binaryFileNames[i]);
  free(binaryFileNames);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jle    L1
  movl   $0x1,-0x1c(%rbp)
  jmp    L27
L78:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <hailstone@plt>
  addl   $0x1,-0x1c(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L78
  jmp    L71
L1:
  cmpl   $0x2,-0x24(%rbp)
  jne    L10
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x1,-0x18(%rbp)
  jmp    L29
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <hailstone@plt>
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L0
  jmp    L71
L10:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L71:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D25
type: string
name: read_data
arguments: label: D7
type: string
name: read_data
arguments: label: D36
type: string
name: read_data
arguments: label: D29
type: string

tool: D25: %lu


tool: D7: usage: hailstone n [m ...]

tool: D36: If only n is given, runs all integers in [1..n]

tool: D29: If n, m, ... are given, runs each [n, m, ...]

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  unsigned long n;
  if (argc > 2) {
    for (i = 1; i < argc; i++) {
      n = (unsigned long)atol(argv[i]);
      printf("%lu\n", n);
      hailstone(n);
    }
  } else if (argc == 2) {
    unsigned long k, l;
    l = (unsigned long)atol(argv[1]);
    for (k = 1; k < l; k++) {
      hailstone(k);
    }
  } else {
    printf("usage: hailstone n [m ...]\n");
    printf("If only n is given, runs all integers in [1..n]\n");
    printf("If n, m, ... are given, runs each [n, m, ...]\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L17
  lea    0x8(%rsi),%rbp
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r13
  lea    D39(%rip),%r12
L45:
  mov    0x0(%rbp),%rdi
  call   <atol@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <hailstone@plt>
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L45
L7:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  je     L50
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L50:
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %rax,%rbp
  cmp    $0x1,%rax
  jbe    L7
  mov    $0x1,%ebx
L27:
  mov    %rbx,%rdi
  call   <hailstone@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L27
  jmp    L7
```

tool_calls: name: unpack_data
arguments: tag: D39
type_infered: string
name: unpack_data
arguments: tag: D2
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D34
type_infered: string

tool: D39: %lu


tool: D2: usage: hailstone n [m ...]

tool: D15: If only n is given, runs all integers in [1..n]

tool: D34: If n, m, ... are given, runs each [n, m, ...]

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  unsigned long n;
  if (argc > 2) {
    for (i = 1; i < argc; i++) {
      n = (unsigned long)atol(argv[i]);
      printf("%lu\n", n);
      hailstone(n);
    }
  } else if (argc == 2) {
    unsigned long k, l;
    l = (unsigned long)atol(argv[1]);
    for (k = 1; k < l; k++) {
      hailstone(k);
    }
  } else {
    printf("usage: hailstone n [m ...]\n");
    printf("If only n is given, runs all integers in [1..n]\n");
    printf("If n, m, ... are given, runs each [n, m, ...]\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L61
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r13
  lea    D35(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atol@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <hailstone@plt>
  cmp    %r13,%rbx
  jne    L59
L23:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  je     L33
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  jmp    L23
L33:
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %rax,%rbp
  cmp    $0x1,%rax
  jbe    L23
  mov    $0x1,%ebx
  nopl   (%rax)
L46:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <hailstone@plt>
  cmp    %rbx,%rbp
  jne    L46
  jmp    L23
```

tool_calls: name: parse_data
arguments: label: D35
type: string
name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D2
type: string
name: parse_data
arguments: label: D4
type: string

tool: D35: %lu


tool: D1: usage: hailstone n [m ...]

tool: D2: If only n is given, runs all integers in [1..n]

tool: D4: If n, m, ... are given, runs each [n, m, ...]

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  unsigned long n;
  if (argc > 2) {
    for (i = 1; i < argc; i++) {
      n = (unsigned long)atol(argv[i]);
      printf("%lu\n", n);
      hailstone(n);
    }
  } else if (argc == 2) {
    unsigned long k, l;
    l = (unsigned long)atol(argv[1]);
    for (k = 1; k < l; k++) {
      hailstone(k);
    }
  } else {
    printf("usage: hailstone n [m ...]\n");
    printf("If only n is given, runs all integers in [1..n]\n");
    printf("If n, m, ... are given, runs each [n, m, ...]\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L35
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r13
  lea    D10(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atol@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <hailstone@plt>
  cmp    %r13,%rbx
  jne    L26
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  je     L0
  lea    D0(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L17
L0:
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %rax,%rbp
  cmp    $0x1,%rax
  jbe    L17
  mov    $0x1,%ebx
  nopl   (%rax)
L54:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <hailstone@plt>
  cmp    %rbx,%rbp
  jne    L54
  jmp    L17
```

tool_calls: name: unpack_data
arguments: tag: D10
type: string
name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D39
type: string
name: unpack_data
arguments: tag: D9
type: string

tool: D10: %lu


tool: D0: usage: hailstone n [m ...]

tool: D39: If only n is given, runs all integers in [1..n]

tool: D9: If n, m, ... are given, runs each [n, m, ...]

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  unsigned long n;
  if (argc > 2) {
    for (i = 1; i < argc; i++) {
      n = (unsigned long)atol(argv[i]);
      printf("%lu\n", n);
      hailstone(n);
    }
  } else if (argc == 2) {
    unsigned long k, l;
    l = (unsigned long)atol(argv[1]);
    for (k = 1; k < l; k++) {
      hailstone(k);
    }
  } else {
    printf("usage: hailstone n [m ...]\n");
    printf("If only n is given, runs all integers in [1..n]\n");
    printf("If n, m, ... are given, runs each [n, m, ...]\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int getInt(void *data) {
  int v;
  cpy(&v, data, sizeof(int));
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getInt>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <cpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInt(void *data) {
  int v;
  cpy(&v, data, sizeof(int));
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getInt>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <cpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInt(void *data) {
  int v;
  cpy(&v, data, sizeof(int));
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getInt>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <cpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInt(void *data) {
  int v;
  cpy(&v, data, sizeof(int));
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  D66(%rip),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D56
datatype: string
name: retrieve_data
arguments: data_tag: D71
datatype: string
name: retrieve_data
arguments: data_tag: D51
datatype: string
name: retrieve_data
arguments: data_tag: D24
datatype: string
name: retrieve_data
arguments: data_tag: D66
datatype: byte[4]
name: retrieve_data
arguments: data_tag: D33
datatype: string

tool: D56: Enter Principal: 

tool: D71: %f

tool: D51: Enter Rate: 

tool: D24: Enter Time: 

tool: {"D66": [0x00,0x00,0xc8,0x42]}

tool: D33: Simple Interest is: %0.2f

assistant: ```c
int main() {
  float p, r, t;
  printf("Enter Principal: ");
  scanf("%f", &p);
  printf("Enter Rate: ");
  scanf("%f", &r);
  printf("Enter Time: ");
  scanf("%f", &t);
  printf("Simple Interest is: %0.2f", (p * r * t) / 100);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  mulss  0x10(%rsp),%xmm0
  mulss  0x14(%rsp),%xmm0
  divss  D25(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D2(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D26
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string
name: read_data
arguments: data_label: D58
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D25
type_infered: byte[4]
name: read_data
arguments: data_label: D2
type_infered: string

tool: D26: Enter Principal: 

tool: D13: %f

tool: D58: Enter Rate: 

tool: D8: Enter Time: 

tool: {"D25": [0x00,0x00,0xc8,0x42]}

tool: D2: Simple Interest is: %0.2f

assistant: ```c
int main() {
  float p, r, t;
  printf("Enter Principal: ");
  scanf("%f", &p);
  printf("Enter Rate: ");
  scanf("%f", &r);
  printf("Enter Time: ");
  scanf("%f", &t);
  printf("Simple Interest is: %0.2f", (p * r * t) / 100);
}
```