ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pbu_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L26:
  subq   $0x1,-0x8(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L24
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L26
L24:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *pbu_ext(const char *path) {
  const char *p = path + strlen(path);
  while (path < p && '.' != p[-1])
    --p;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pbu_ext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jae    L24
L3:
  cmpb   $0x2e,-0x1(%rax)
  je     L24
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L3
  mov    %rbx,%rax
L24:
  pop    %rbx
  ret
```

assistant: ```c
const char *pbu_ext(const char *path) {
  const char *p = path + strlen(path);
  while (path < p && '.' != p[-1])
    --p;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pbu_ext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jb     L8
  jmp    L25
  nopl   0x0(%rax)
L15:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L25
L8:
  cmpb   $0x2e,-0x1(%rax)
  jne    L15
L25:
  pop    %rbx
  ret
```

assistant: ```c
const char *pbu_ext(const char *path) {
  const char *p = path + strlen(path);
  while (path < p && '.' != p[-1])
    --p;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pbu_ext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jb     L33
  jmp    L15
  nopl   0x0(%rax)
L30:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L15
L33:
  cmpb   $0x2e,-0x1(%rax)
  jne    L30
L15:
  pop    %rbx
  ret
```

assistant: ```c
const char *pbu_ext(const char *path) {
  const char *p = path + strlen(path);
  while (path < p && '.' != p[-1])
    --p;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  cmpl   $0x0,-0xc(%rbp)
  jne    L58
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L58
  cmpl   $0x0,-0x4(%rbp)
  jg     L18
L58:
  mov    $0x0,%eax
  jmp    L31
L17:
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L38
  cmpl   $0x0,-0x4(%rbp)
  jg     L17
L38:
  cmpl   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
L31:
  leave
  ret
```

assistant: ```c
int main() {
  int j;
  int k;
  int n;
  if (!((j == 0) && (k == n) && (n > 0)))
    return 0;
  while (j < n && n > 0) {
    j++;
    k--;
  }
  assert((k == 0));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int j;
  int k;
  int n;
  if (!((j == 0) && (k == n) && (n > 0)))
    return 0;
  while (j < n && n > 0) {
    j++;
    k--;
  }
  assert((k == 0));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int j;
  int k;
  int n;
  if (!((j == 0) && (k == n) && (n > 0)))
    return 0;
  while (j < n && n > 0) {
    j++;
    k--;
  }
  assert((k == 0));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int j;
  int k;
  int n;
  if (!((j == 0) && (k == n) && (n > 0)))
    return 0;
  while (j < n && n > 0) {
    j++;
    k--;
  }
  assert((k == 0));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inspect_fw_phexdecdef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L2
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L11
L2:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L11:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: string
name: disassemble_data
arguments: data_tag: D20
data_type: string

tool: D24: %-23s: 0x%08x / %8u bytes 

tool: D1: (== OpenWrt default)

tool: D20: (OpenWrt default: 0x%08x)


assistant: ```c
void inspect_fw_phexdecdef(char *label, uint32_t val, uint32_t defval) {
  printf("%-23s: 0x%08x / %8u bytes ", label, val, val);
  if (val == defval)
    printf("(== OpenWrt default)\n");
  else
    printf("(OpenWrt default: 0x%08x)\n", defval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inspect_fw_phexdecdef>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %esi,%ecx
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L14
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: label: D2
type: string
name: parse_data
arguments: label: D10
type: string
name: parse_data
arguments: label: D5
type: string

tool: D2: %-23s: 0x%08x / %8u bytes 

tool: D10: (OpenWrt default: 0x%08x)


tool: D5: (== OpenWrt default)

assistant: ```c
void inspect_fw_phexdecdef(char *label, uint32_t val, uint32_t defval) {
  printf("%-23s: 0x%08x / %8u bytes ", label, val, val);
  if (val == defval)
    printf("(== OpenWrt default)\n");
  else
    printf("(OpenWrt default: 0x%08x)\n", defval);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inspect_fw_phexdecdef>:
  endbr64
  push   %rbp
  mov    %esi,%ecx
  mov    %edx,%ebp
  xor    %eax,%eax
  push   %rbx
  mov    %esi,%edx
  mov    %esi,%ebx
  mov    %rdi,%rsi
  lea    D21(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L9
  add    $0x8,%rsp
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   (%rax)
L9:
  add    $0x8,%rsp
  lea    D3(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D3
data_type: string

tool: D21: %-23s: 0x%08x / %8u bytes 

tool: D18: (OpenWrt default: 0x%08x)


tool: D3: (== OpenWrt default)

assistant: ```c
void inspect_fw_phexdecdef(char *label, uint32_t val, uint32_t defval) {
  printf("%-23s: 0x%08x / %8u bytes ", label, val, val);
  if (val == defval)
    printf("(== OpenWrt default)\n");
  else
    printf("(OpenWrt default: 0x%08x)\n", defval);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inspect_fw_phexdecdef>:
  endbr64
  push   %rbp
  mov    %esi,%ecx
  mov    %edx,%ebp
  xor    %eax,%eax
  push   %rbx
  mov    %esi,%edx
  mov    %esi,%ebx
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L8
  add    $0x8,%rsp
  mov    %ebp,%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   (%rax)
L8:
  add    $0x8,%rsp
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D27
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D3: %-23s: 0x%08x / %8u bytes 

tool: D27: (OpenWrt default: 0x%08x)


tool: D4: (== OpenWrt default)

assistant: ```c
void inspect_fw_phexdecdef(char *label, uint32_t val, uint32_t defval) {
  printf("%-23s: 0x%08x / %8u bytes ", label, val, val);
  if (val == defval)
    printf("(== OpenWrt default)\n");
  else
    printf("(OpenWrt default: 0x%08x)\n", defval);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mg_base64_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%r15
  movslq %esi,%rsi
  add    %rdi,%rsi
  lea    0x3(%rdi),%rax
  cmp    %rax,%rsi
  jbe    L114
  mov    %rdi,%rbp
  sub    %rdi,%rsi
  lea    -0x4(%rsi),%rax
  shr    $0x2,%rax
  lea    0x4(%rdi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r14d
  jmp    L112
L51:
  mov    %eax,%r14d
L6:
  add    $0x4,%rbp
  cmp    0x8(%rsp),%rbp
  je     L86
L112:
  movsbl 0x0(%rbp),%edi
  call   <mg_b64rev@plt>
  mov    %eax,%ebx
  movsbl 0x1(%rbp),%edi
  call   <mg_b64rev@plt>
  mov    %eax,%r12d
  movsbl 0x2(%rbp),%edi
  call   <mg_b64rev@plt>
  mov    %eax,%r13d
  movsbl 0x3(%rbp),%edi
  call   <mg_b64rev@plt>
  mov    %eax,%edx
  cmp    $0x40,%ebx
  je     L19
  cmp    $0x40,%r12d
  je     L8
  mov    %ebx,%eax
  or     %r12d,%eax
  or     %r13d,%eax
  or     %edx,%eax
  js     L68
  lea    0x1(%r14),%eax
  movslq %r14d,%rcx
  shl    $0x2,%ebx
  mov    %r12d,%esi
  sar    $0x4,%esi
  or     %esi,%ebx
  mov    %bl,(%r15,%rcx,1)
  cmpb   $0x3d,0x2(%rbp)
  je     L51
  lea    0x2(%r14),%ecx
  cltq
  shl    $0x4,%r12d
  mov    %r13d,%esi
  sar    $0x2,%esi
  or     %esi,%r12d
  mov    %r12b,(%r15,%rax,1)
  cmpb   $0x3d,0x3(%rbp)
  je     L16
  add    $0x3,%r14d
  movslq %ecx,%rcx
  shl    $0x6,%r13d
  or     %edx,%r13d
  mov    %r13b,(%r15,%rcx,1)
  jmp    L6
L16:
  mov    %ecx,%r14d
  jmp    L6
L114:
  mov    $0x0,%r14d
L86:
  movslq %r14d,%rax
  movb   $0x0,(%r15,%rax,1)
L118:
  mov    %r14d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    $0x0,%r14d
  jmp    L118
L8:
  mov    $0x0,%r14d
  jmp    L118
L68:
  mov    $0x0,%r14d
  jmp    L118
```

assistant: ```c
int mg_base64_decode(const char *src, int n, char *dst) {
  const char *end = src + n;
  int len = 0;
  while (src + 3 < end) {
    int a = mg_b64rev(src[0]), b = mg_b64rev(src[1]), c = mg_b64rev(src[2]), d = mg_b64rev(src[3]);
    if (a == 64 || a < 0 || b == 64 || b < 0 || c < 0 || d < 0)
      return 0;
    dst[len++] = (a << 2) | (b >> 4);
    if (src[2] != '=') {
      dst[len++] = (b << 4) | (c >> 2);
      if (src[3] != '=')
        dst[len++] = (c << 6) | d;
    }
    src += 4;
  }
  dst[len] = '\0';
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mg_base64_decode>:
  endbr64
  push   %r15
  movslq %esi,%rsi
  lea    0x3(%rdi),%rax
  push   %r14
  add    %rdi,%rsi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rax,%rsi
  jbe    L14
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %r15d,%r15d
  lea    -0x4(%rsi),%rax
  shr    $0x2,%rax
  lea    0x4(%rdi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  jmp    L103
  nopl   (%rax)
L92:
  mov    %r14d,%edi
  shl    $0x4,%r12d
  cltq
  lea    0x2(%r15),%esi
  sar    $0x2,%edi
  or     %edi,%r12d
  mov    %r12b,0x0(%r13,%rax,1)
  cmpb   $0x3d,0x3(%rbp)
  je     L118
  shl    $0x6,%r14d
  movslq %esi,%rsi
  add    $0x3,%r15d
  or     %ecx,%r14d
  mov    %r14b,0x0(%r13,%rsi,1)
L1:
  add    $0x4,%rbp
  cmp    0x8(%rsp),%rbp
  je     L58
L103:
  movsbl 0x0(%rbp),%edi
  call   <mg_b64rev@plt>
  movsbl 0x1(%rbp),%edi
  mov    %eax,%ebx
  call   <mg_b64rev@plt>
  movsbl 0x2(%rbp),%edi
  mov    %eax,%r12d
  call   <mg_b64rev@plt>
  movsbl 0x3(%rbp),%edi
  mov    %eax,%r14d
  call   <mg_b64rev@plt>
  mov    %eax,%ecx
  cmp    $0x40,%ebx
  je     L113
  cmp    $0x40,%r12d
  je     L113
  mov    %ebx,%eax
  or     %r12d,%eax
  or     %r14d,%eax
  or     %ecx,%eax
  js     L113
  mov    %r12d,%edi
  shl    $0x2,%ebx
  movslq %r15d,%rsi
  lea    0x1(%r15),%eax
  sar    $0x4,%edi
  or     %edi,%ebx
  mov    %bl,0x0(%r13,%rsi,1)
  cmpb   $0x3d,0x2(%rbp)
  jne    L92
  mov    %eax,%r15d
  add    $0x4,%rbp
  cmp    0x8(%rsp),%rbp
  jne    L103
L58:
  movslq %r15d,%rax
  add    %rax,%r13
L72:
  movb   $0x0,0x0(%r13)
  jmp    L70
  nopl   0x0(%rax)
L118:
  mov    %esi,%r15d
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L113:
  xor    %r15d,%r15d
L70:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  xor    %r15d,%r15d
  jmp    L72
```

assistant: ```c
int mg_base64_decode(const char *src, int n, char *dst) {
  const char *end = src + n;
  int len = 0;
  while (src + 3 < end) {
    int a = mg_b64rev(src[0]), b = mg_b64rev(src[1]), c = mg_b64rev(src[2]), d = mg_b64rev(src[3]);
    if (a == 64 || a < 0 || b == 64 || b < 0 || c < 0 || d < 0)
      return 0;
    dst[len++] = (a << 2) | (b >> 4);
    if (src[2] != '=') {
      dst[len++] = (b << 4) | (c >> 2);
      if (src[3] != '=')
        dst[len++] = (c << 6) | d;
    }
    src += 4;
  }
  dst[len] = '\0';
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mg_base64_decode>:
  endbr64
  push   %r15
  movslq %esi,%rsi
  lea    0x3(%rdi),%rax
  push   %r14
  add    %rdi,%rsi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rax,%rsi
  jbe    L12
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %r15d,%r15d
  lea    -0x4(%rsi),%rax
  shr    $0x2,%rax
  lea    0x4(%rdi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  jmp    L39
  nopl   (%rax)
L0:
  mov    %r14d,%edi
  shl    $0x4,%r12d
  cltq
  lea    0x2(%r15),%esi
  sar    $0x2,%edi
  or     %edi,%r12d
  mov    %r12b,0x0(%r13,%rax,1)
  cmpb   $0x3d,0x3(%rbp)
  je     L17
  shl    $0x6,%r14d
  movslq %esi,%rsi
  add    $0x3,%r15d
  or     %ecx,%r14d
  mov    %r14b,0x0(%r13,%rsi,1)
L89:
  add    $0x4,%rbp
  cmp    %rbp,0x8(%rsp)
  je     L112
L39:
  movsbl 0x0(%rbp),%edi
  call   <mg_b64rev@plt>
  movsbl 0x1(%rbp),%edi
  mov    %eax,%ebx
  call   <mg_b64rev@plt>
  movsbl 0x2(%rbp),%edi
  mov    %eax,%r12d
  call   <mg_b64rev@plt>
  movsbl 0x3(%rbp),%edi
  mov    %eax,%r14d
  call   <mg_b64rev@plt>
  mov    %eax,%ecx
  cmp    $0x40,%ebx
  je     L86
  cmp    $0x40,%r12d
  je     L86
  mov    %ebx,%eax
  or     %r12d,%eax
  or     %r14d,%eax
  or     %ecx,%eax
  js     L86
  mov    %r12d,%edi
  shl    $0x2,%ebx
  movslq %r15d,%rsi
  lea    0x1(%r15),%eax
  sar    $0x4,%edi
  or     %edi,%ebx
  mov    %bl,0x0(%r13,%rsi,1)
  cmpb   $0x3d,0x2(%rbp)
  jne    L0
  mov    %eax,%r15d
  add    $0x4,%rbp
  cmp    %rbp,0x8(%rsp)
  jne    L39
L112:
  movslq %r15d,%rax
  add    %rax,%r13
L77:
  movb   $0x0,0x0(%r13)
  jmp    L8
  nopl   0x0(%rax)
L17:
  mov    %esi,%r15d
  jmp    L89
  nopl   0x0(%rax,%rax,1)
L86:
  xor    %r15d,%r15d
L8:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  xor    %r15d,%r15d
  jmp    L77
```

assistant: ```c
int mg_base64_decode(const char *src, int n, char *dst) {
  const char *end = src + n;
  int len = 0;
  while (src + 3 < end) {
    int a = mg_b64rev(src[0]), b = mg_b64rev(src[1]), c = mg_b64rev(src[2]), d = mg_b64rev(src[3]);
    if (a == 64 || a < 0 || b == 64 || b < 0 || c < 0 || d < 0)
      return 0;
    dst[len++] = (a << 2) | (b >> 4);
    if (src[2] != '=') {
      dst[len++] = (b << 4) | (c >> 2);
      if (src[3] != '=')
        dst[len++] = (c << 6) | d;
    }
    src += 4;
  }
  dst[len] = '\0';
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checkPall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L24
L29:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,%bl
  je     L1
  mov    $0x0,%eax
  jmp    L14
L1:
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L29
  mov    $0x1,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int checkPall(char str[]) {
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] != str[strlen(str) - i - 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checkPall>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L7:
  mov    %ebx,%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L27
  movzbl 0x0(%rbp,%rbx,1),%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x1,%rbx
  sub    %r13d,%eax
  cltq
  cmp    -0x1(%rbp,%rax,1),%r12b
  je     L7
  mov    $0x0,%eax
  jmp    L15
L27:
  mov    $0x1,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int checkPall(char str[]) {
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] != str[strlen(str) - i - 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<checkPall>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L10
  nopl   (%rax)
L4:
  mov    %rbp,%rdi
  movzbl 0x0(%rbp,%rbx,1),%r13d
  add    $0x1,%rbx
  call   <strlen@plt>
  sub    %r12d,%eax
  cltq
  cmp    -0x1(%rbp,%rax,1),%r13b
  jne    L24
L10:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L4
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L24:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int checkPall(char str[]) {
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] != str[strlen(str) - i - 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checkPall>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L23
  nopl   (%rax)
L8:
  mov    %rbp,%rdi
  movzbl 0x0(%rbp,%rbx,1),%r13d
  add    $0x1,%rbx
  call   <strlen@plt>
  sub    %r12d,%eax
  cltq
  cmp    -0x1(%rbp,%rax,1),%r13b
  jne    L27
L23:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L8
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L27:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int checkPall(char str[]) {
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] != str[strlen(str) - i - 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_freevect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void my_freevect(char **vect) {
  int i;
  for (i = 0; vect[i]; ++i)
    free(vect[i]);
  free(vect);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_freevect>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  lea    0x8(%rbp),%rbx
L11:
  call   <free@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L11
L1:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void my_freevect(char **vect) {
  int i;
  for (i = 0; vect[i]; ++i)
    free(vect[i]);
  free(vect);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_freevect>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L6
  lea    0x8(%rbp),%rbx
  nopl   0x0(%rax)
L11:
  call   <free@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L11
L6:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void my_freevect(char **vect) {
  int i;
  for (i = 0; vect[i]; ++i)
    free(vect[i]);
  free(vect);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_freevect>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L11
  lea    0x8(%rbp),%rbx
  nopl   0x0(%rax)
L1:
  call   <free@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L1
L11:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void my_freevect(char **vect) {
  int i;
  for (i = 0; vect[i]; ++i)
    free(vect[i]);
  free(vect);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adc_chunk_offset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <adc_chunk_type@plt>
  cmp    $0x3,%eax
  je     L18
  cmp    $0x3,%eax
  jg     L34
  cmp    $0x1,%eax
  je     L55
  cmp    $0x2,%eax
  je     L52
  jmp    L34
L55:
  mov    $0x0,%eax
  jmp    L27
L52:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  and    $0x300,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  jmp    L27
L18:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  jmp    L27
L34:
  mov    $0xffffffff,%eax
L27:
  leave
  ret
```

assistant: ```c
int adc_chunk_offset(unsigned char *chunk_start) {
  unsigned char *c = chunk_start;
  switch (adc_chunk_type(*c)) {
  case 0x01:
    return 0;
  case 0x02:
    return ((((unsigned char)*c & 0x03)) << 8) + (unsigned char)*(c + 1);
  case 0x03:
    return (((unsigned char)*(c + 1)) << 8) + (unsigned char)*(c + 2);
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<adc_chunk_offset>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  call   <adc_chunk_type@plt>
  cmp    $0x2,%eax
  je     L11
  cmp    $0x3,%eax
  je     L31
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
L23:
  pop    %rbx
  ret
L11:
  movzbl (%rbx),%eax
  shl    $0x8,%eax
  and    $0x300,%eax
  movzbl 0x1(%rbx),%edx
  add    %edx,%eax
  jmp    L23
L31:
  movzbl 0x1(%rbx),%eax
  shl    $0x8,%eax
  movzbl 0x2(%rbx),%edx
  add    %edx,%eax
  jmp    L23
```

assistant: ```c
int adc_chunk_offset(unsigned char *chunk_start) {
  unsigned char *c = chunk_start;
  switch (adc_chunk_type(*c)) {
  case 0x01:
    return 0;
  case 0x02:
    return ((((unsigned char)*c & 0x03)) << 8) + (unsigned char)*(c + 1);
  case 0x03:
    return (((unsigned char)*(c + 1)) << 8) + (unsigned char)*(c + 2);
  }
  return -1;
}
```