ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmorlet_packet>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %rdx,%rbp
  movsd  %xmm0,0x18(%rsp)
  movsd  D34(%rip),%xmm0
  call   <sqrt@plt>
  mov    %eax,%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  pxor   %xmm6,%xmm6
  cvtsi2sd %eax,%xmm6
  movsd  %xmm6,0x10(%rsp)
  test   %r13d,%r13d
  jle    L0
  mov    %r14,%rbx
  movslq %r13d,%r12
  lea    0x0(%rbp,%r12,8),%rbp
  lea    -0x1(%r13),%eax
  lea    0x8(%r14,%rax,8),%r13
  neg    %r12
  shl    $0x3,%r12
L1:
  mov    (%rbx),%r14
  movq   %r14,%xmm0
  mulsd  %xmm0,%xmm0
  xorpd  D27(%rip),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x8(%rsp)
  movq   %r14,%xmm1
  mulsd  D18(%rip),%xmm1
  cvttsd2si %xmm1,%edi
  call   <cos@plt>
  mulsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  divsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp,%r12,1)
  movsd  D18(%rip),%xmm0
  mulsd  (%rbx),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sin@plt>
  mulsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  divsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %r13,%rbx
  jne    L1
L0:
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D34
datatype: f64
name: read_data
arguments: data_label: D27
datatype: byte[16]
name: read_data
arguments: data_label: D18
datatype: byte[8]

tool: D34: 3.141592653589793

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D18": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void cmorlet_packet(double *x, int sigInLength, double *f, int sigOutLength, double ys) {
  int count;
  double con, econ, x2;
  con = 1 / sqrt(3.1415926535897931159980);
  for (count = 0; count < sigInLength; count++) {
    x2 = x[count] * x[count];
    econ = exp(-x2);
    f[count] = cos(2 * 3.1415926535897931159980 * x[count]) * econ * con / ys;
    f[count + sigInLength] = sin(2 * 3.1415926535897931159980 * x[count]) * econ * con / ys;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmorlet_packet>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  D38(%rip),%xmm0
  call   <sqrt@plt>
  pxor   %xmm5,%xmm5
  mov    %eax,%r8d
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  cvtsi2sd %eax,%xmm5
  movsd  %xmm5,0x8(%rsp)
  test   %r12d,%r12d
  jle    L5
  movslq %r12d,%rbp
  lea    -0x1(%r12),%eax
  shl    $0x3,%rbp
  lea    0x8(%r13,%rax,8),%r12
  add    %rbp,%rbx
  neg    %rbp
  nopl   0x0(%rax)
L16:
  movsd  0x0(%r13),%xmm1
  add    $0x8,%r13
  add    $0x8,%rbx
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  mulsd  %xmm1,%xmm0
  xorpd  D1(%rip),%xmm0
  call   <exp@plt>
  movsd  0x18(%rsp),%xmm1
  mulsd  D39(%rip),%xmm1
  movsd  %xmm0,(%rsp)
  cvttsd2si %xmm1,%edi
  call   <cos@plt>
  mulsd  (%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  movsd  %xmm0,-0x8(%rbx,%rbp,1)
  movsd  D39(%rip),%xmm0
  mulsd  -0x8(%r13),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sin@plt>
  mulsd  (%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  movsd  %xmm0,-0x8(%rbx)
  cmp    %r12,%r13
  jne    L16
L5:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D38
data_type: f64
name: read_data
arguments: data_tag: D1
data_type: byte[16]
name: read_data
arguments: data_tag: D39
data_type: byte[8]

tool: D38: 3.141592653589793

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D39": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void cmorlet_packet(double *x, int sigInLength, double *f, int sigOutLength, double ys) {
  int count;
  double con, econ, x2;
  con = 1 / sqrt(3.1415926535897931159980);
  for (count = 0; count < sigInLength; count++) {
    x2 = x[count] * x[count];
    econ = exp(-x2);
    f[count] = cos(2 * 3.1415926535897931159980 * x[count]) * econ * con / ys;
    f[count + sigInLength] = sin(2 * 3.1415926535897931159980 * x[count]) * econ * con / ys;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmorlet_packet>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  D37(%rip),%xmm0
  call   <sqrt@plt>
  pxor   %xmm5,%xmm5
  mov    %eax,%r8d
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  cvtsi2sd %eax,%xmm5
  movsd  %xmm5,0x8(%rsp)
  test   %r12d,%r12d
  jle    L15
  movslq %r12d,%rbp
  lea    -0x1(%r12),%eax
  shl    $0x3,%rbp
  lea    0x8(%r13,%rax,8),%r12
  add    %rbp,%rbx
  neg    %rbp
  nopl   0x0(%rax)
L18:
  movsd  0x0(%r13),%xmm1
  add    $0x8,%r13
  add    $0x8,%rbx
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  mulsd  %xmm1,%xmm0
  xorpd  D27(%rip),%xmm0
  call   <exp@plt>
  movsd  0x18(%rsp),%xmm1
  mulsd  D34(%rip),%xmm1
  movsd  %xmm0,(%rsp)
  cvttsd2si %xmm1,%edi
  call   <cos@plt>
  mulsd  (%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  movsd  %xmm0,-0x8(%rbx,%rbp,1)
  movsd  D34(%rip),%xmm0
  mulsd  -0x8(%r13),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sin@plt>
  mulsd  (%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  movsd  %xmm0,-0x8(%rbx)
  cmp    %r12,%r13
  jne    L18
L15:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D37
data_type: f64
name: disassemble_data
arguments: tag: D27
data_type: byte[16]
name: disassemble_data
arguments: tag: D34
data_type: byte[8]

tool: D37: 3.141592653589793

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D34": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void cmorlet_packet(double *x, int sigInLength, double *f, int sigOutLength, double ys) {
  int count;
  double con, econ, x2;
  con = 1 / sqrt(3.1415926535897931159980);
  for (count = 0; count < sigInLength; count++) {
    x2 = x[count] * x[count];
    econ = exp(-x2);
    f[count] = cos(2 * 3.1415926535897931159980 * x[count]) * econ * con / ys;
    f[count + sigInLength] = sin(2 * 3.1415926535897931159980 * x[count]) * econ * con / ys;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_bool>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    -0xc(%rbp),%eax
  jmp    L57
L13:
  mov    -0x8(%rbp),%rax
  lea    D46(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L83
  mov    -0x8(%rbp),%rax
  lea    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L83
  mov    -0x8(%rbp),%rax
  lea    D51(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <streq@plt>
  test   %rax,%rax
  je     L48
L83:
  mov    $0x1,%eax
  jmp    L57
L48:
  mov    -0x8(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L71
  mov    -0x8(%rbp),%rax
  lea    D55(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L71
  mov    -0x8(%rbp),%rax
  lea    D32(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <streq@plt>
  test   %rax,%rax
  je     L31
L71:
  mov    $0x0,%eax
  jmp    L57
L31:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <parse_int@plt>
L57:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D46
datatype: string
name: parse_data
arguments: tag: D25
datatype: string
name: parse_data
arguments: tag: D51
datatype: string
name: parse_data
arguments: tag: D28
datatype: string
name: parse_data
arguments: tag: D55
datatype: string
name: parse_data
arguments: tag: D32
datatype: string

tool: D46: true

tool: D25: on

tool: D51: yes

tool: D28: false

tool: D55: off

tool: D32: no

assistant: ```c
bool parse_bool(const char *value, bool default_value) {
  if (!value)
    return default_value;
  if (streq(value, "true") || streq(value, "on") || streq(value, "yes"))
    return true;
  if (streq(value, "false") || streq(value, "off") || streq(value, "no"))
    return false;
  return parse_int(value, default_value);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_bool>:
  endbr64
  mov    %esi,%eax
  test   %rdi,%rdi
  je     L73
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    D15(%rip),%rsi
  call   <streq@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L5
L63:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    D34(%rip),%rsi
  mov    %rbx,%rdi
  call   <streq@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L63
  lea    D46(%rip),%rsi
  mov    %rbx,%rdi
  call   <streq@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L63
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <streq@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L63
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <streq@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L63
  lea    D23(%rip),%rsi
  mov    %rbx,%rdi
  call   <streq@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L63
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <parse_int@plt>
  jmp    L63
L73:
  ret
```

tool_calls: name: read_data
arguments: label: D15
type: string
name: read_data
arguments: label: D34
type: string
name: read_data
arguments: label: D46
type: string
name: read_data
arguments: label: D8
type: string
name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D23
type: string

tool: D15: true

tool: D34: on

tool: D46: yes

tool: D8: false

tool: D11: off

tool: D23: no

assistant: ```c
bool parse_bool(const char *value, bool default_value) {
  if (!value)
    return default_value;
  if (streq(value, "true") || streq(value, "on") || streq(value, "yes"))
    return true;
  if (streq(value, "false") || streq(value, "off") || streq(value, "no"))
    return false;
  return parse_int(value, default_value);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parse_bool>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L62
  lea    D12(%rip),%rsi
  mov    %rdi,%rbp
  call   <streq@plt>
  test   %rax,%rax
  je     L0
L60:
  mov    $0x1,%eax
L30:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L60
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L60
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  je     L49
L17:
  xor    %eax,%eax
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L62:
  add    $0x8,%rsp
  mov    %esi,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  lea    D34(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L17
  lea    D40(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L17
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <parse_int@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string
name: retrieve_data
arguments: tag: D15
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string
name: retrieve_data
arguments: tag: D34
datatype: string
name: retrieve_data
arguments: tag: D40
datatype: string

tool: D12: true

tool: D6: on

tool: D15: yes

tool: D21: false

tool: D34: off

tool: D40: no

assistant: ```c
bool parse_bool(const char *value, bool default_value) {
  if (!value)
    return default_value;
  if (streq(value, "true") || streq(value, "on") || streq(value, "yes"))
    return true;
  if (streq(value, "false") || streq(value, "off") || streq(value, "no"))
    return false;
  return parse_int(value, default_value);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_bool>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L36
  lea    D18(%rip),%rsi
  mov    %rdi,%rbp
  call   <streq@plt>
  test   %rax,%rax
  je     L10
L60:
  mov    $0x1,%eax
L32:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  lea    D44(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L60
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L60
  lea    D42(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  je     L24
L19:
  xor    %eax,%eax
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x8,%rsp
  mov    %esi,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L19
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <streq@plt>
  test   %rax,%rax
  jne    L19
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <parse_int@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D44
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D42
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D18: true

tool: D44: on

tool: D10: yes

tool: D42: false

tool: D37: off

tool: D7: no

assistant: ```c
bool parse_bool(const char *value, bool default_value) {
  if (!value)
    return default_value;
  if (streq(value, "true") || streq(value, "on") || streq(value, "yes"))
    return true;
  if (streq(value, "false") || streq(value, "off") || streq(value, "no"))
    return false;
  return parse_int(value, default_value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<frog_combos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L8:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L8
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int frog_combos(int n) {
  int before_last = 1, last = 0;
  int i;
  for (i = 0; i < n + 1; i++) {
    int new_last = before_last + last;
    before_last = last;
    last = new_last;
  }
  return last;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<frog_combos>:
  endbr64
  test   %edi,%edi
  js     L10
  add    $0x1,%edi
  mov    $0x0,%edx
  mov    $0x0,%eax
  mov    $0x1,%ecx
L2:
  mov    %eax,%esi
  add    %ecx,%eax
  add    $0x1,%edx
  mov    %esi,%ecx
  cmp    %edi,%edx
  jne    L2
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int frog_combos(int n) {
  int before_last = 1, last = 0;
  int i;
  for (i = 0; i < n + 1; i++) {
    int new_last = before_last + last;
    before_last = last;
    last = new_last;
  }
  return last;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<frog_combos>:
  endbr64
  test   %edi,%edi
  js     L16
  add    $0x1,%edi
  xor    %edx,%edx
  xor    %eax,%eax
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L8:
  mov    %eax,%esi
  add    $0x1,%edx
  add    %ecx,%eax
  mov    %esi,%ecx
  cmp    %edx,%edi
  jne    L8
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int frog_combos(int n) {
  int before_last = 1, last = 0;
  int i;
  for (i = 0; i < n + 1; i++) {
    int new_last = before_last + last;
    before_last = last;
    last = new_last;
  }
  return last;
}
```
user: What is the c source code of the assembly code below?

```asm
<frog_combos>:
  endbr64
  test   %edi,%edi
  js     L16
  add    $0x1,%edi
  xor    %edx,%edx
  xor    %eax,%eax
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L15:
  mov    %eax,%esi
  add    $0x1,%edx
  add    %ecx,%eax
  mov    %esi,%ecx
  cmp    %edx,%edi
  jne    L15
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int frog_combos(int n) {
  int before_last = 1, last = 0;
  int i;
  for (i = 0; i < n + 1; i++) {
    int new_last = before_last + last;
    before_last = last;
    last = new_last;
  }
  return last;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<idc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void idc(void *p) {
  if (p)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<idc>:
  endbr64
  ret
```

assistant: ```c
void idc(void *p) {
  if (p)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<idc>:
  endbr64
  ret
```

assistant: ```c
void idc(void *p) {
  if (p)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<idc>:
  endbr64
  ret
```

assistant: ```c
void idc(void *p) {
  if (p)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<path_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L15
L11:
  mov    -0x18(%rbp),%rax
L15:
  leave
  ret
```

assistant: ```c
__attribute__((__returns_nonnull__)) __attribute__((__nonnull__)) const char *path_basename(const char *filename) {
  const char *slash = strrchr(filename, '/');
  return slash ? slash + 1 : filename;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<path_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((__returns_nonnull__)) __attribute__((__nonnull__)) const char *path_basename(const char *filename) {
  const char *slash = strrchr(filename, '/');
  return slash ? slash + 1 : filename;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<path_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
__attribute__((__returns_nonnull__)) __attribute__((__nonnull__)) const char *path_basename(const char *filename) {
  const char *slash = strrchr(filename, '/');
  return slash ? slash + 1 : filename;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<path_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
__attribute__((__returns_nonnull__)) __attribute__((__nonnull__)) const char *path_basename(const char *filename) {
  const char *slash = strrchr(filename, '/');
  return slash ? slash + 1 : filename;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<year_to_easter>:
  endbr64
  push   %rbx
  lea    0x76c(%rdi),%r11d
  movslq %r11d,%r10
  imul   $0x51eb851f,%r10,%rax
  mov    %rax,%rbx
  sar    $0x25,%rbx
  mov    %rbx,%r9
  mov    %r11d,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%r9d
  imul   $0x6bca1af3,%r10,%r10
  sar    $0x23,%r10
  sub    %r8d,%r10d
  lea    (%r10,%r10,8),%edx
  lea    (%r10,%rdx,2),%edx
  mov    %r11d,%r10d
  sub    %edx,%r10d
  sar    $0x27,%rax
  sub    %eax,%r8d
  lea    -0x11(%r9),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x23,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %r9d,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %edx,%eax
  lea    (%r8,%r9,1),%edx
  add    %edx,%eax
  lea    (%r10,%r10,8),%edx
  lea    (%r10,%rdx,2),%edx
  lea    0xf(%rax,%rdx,1),%eax
  movslq %eax,%rcx
  imul   $0xffffffff88888889,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x4,%ecx
  cltd
  sub    %edx,%ecx
  imul   $0x1e,%ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  movslq %eax,%rsi
  imul   $0xffffffff92492493,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x4,%esi
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    0x1(%rcx),%ebx
  mov    $0x1d,%eax
  cltd
  idiv   %ebx
  imul   %esi,%eax
  mov    $0x15,%ebx
  sub    %r10d,%ebx
  movslq %ebx,%rdx
  imul   $0x2e8ba2e9,%rdx,%rdx
  sar    $0x21,%rdx
  sar    $0x1f,%ebx
  sub    %ebx,%edx
  imul   %edx,%eax
  mov    $0x1,%edx
  sub    %eax,%edx
  mov    %edx,%eax
  imul   %esi,%eax
  sub    %eax,%ecx
  lea    0x76f(%rdi),%eax
  test   %r11d,%r11d
  cmovns %r11d,%eax
  sar    $0x2,%eax
  add    %r11d,%eax
  lea    0x2(%rcx,%rax,1),%edx
  sub    %r9d,%edx
  sub    %r8d,%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    0x0(,%rax,8),%esi
  sub    %eax,%esi
  sub    %esi,%edx
  sub    %edx,%ecx
  lea    0x28(%rcx),%eax
  movslq %eax,%rsi
  imul   $0x2e8ba2e9,%rsi,%rsi
  sar    $0x23,%rsi
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    0x6(%rsi),%eax
  add    $0x3,%esi
  cmovns %esi,%eax
  sar    $0x2,%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %edx,%eax
  lea    0x1c(%rcx,%rax,1),%edx
  call   <ymd_to_serial@plt>
  pop    %rbx
  ret
```

assistant: ```c
unsigned long year_to_easter(int y) {
  int c, g, k, l, i, j, m, d;
  y = y + 1900;
  c = y / 100;
  g = y % 19;
  k = (c - 17) / 25;
  i = (c - c / 4 - (c - k) / 3 + 19 * g + 15) % 30;
  i = i - (i / 28) * (1 - (i / 28) * (29 / (i + 1)) * ((21 - g) / 11));
  j = (y + y / 4 + i + 2 - c + c / 4) % 7;
  l = i - j;
  m = 3 + (l + 40) / 44;
  d = l + 28 - 31 * (m / 4);
  return ymd_to_serial(y - 1900, m, d);
}
```