ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_request_len>:
  endbr64
  test   %esi,%esi
  jle    L22
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L62
  nopl   0x0(%rax)
L105:
  cmp    $0xd,%al
  je     L90
  cmp    $0xa,%al
  je     L131
  test   %al,%al
  jns    L12
L61:
  cmp    %ebp,%r13d
  jle    L136
L47:
  add    $0x1,%rbx
  add    $0x1,%ebp
  add    $0x1,%r12d
L62:
  movzbl (%rbx),%edi
  call   <isprint@plt>
  test   %eax,%eax
  movzbl (%rbx),%eax
  je     L105
L90:
  cmp    $0xa,%al
  jne    L61
L131:
  mov    %r12d,%r8d
  cmp    %ebp,%r13d
  jle    L126
  movzbl 0x1(%rbx),%eax
  cmp    $0xa,%al
  je     L59
  cmp    %r12d,%r13d
  jle    L47
  cmp    $0xd,%al
  jne    L47
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L126:
  cmp    %r12d,%r13d
  jle    L136
  cmpb   $0xd,0x1(%rbx)
  jne    L136
L17:
  cmpb   $0xa,0x2(%rbx)
  jne    L61
  lea    0x2(%rbp),%r8d
L59:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L136:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_request_len(const char *s, int buf_len) {
  const unsigned char *buf = (unsigned char *)s;
  int i;
  for (i = 0; i < buf_len; i++) {
    if (!isprint(buf[i]) && buf[i] != '\r' && buf[i] != '\n' && buf[i] < 128) {
      return -1;
    } else if (buf[i] == '\n' && i + 1 < buf_len && buf[i + 1] == '\n') {
      return i + 2;
    } else if (buf[i] == '\n' && i + 2 < buf_len && buf[i + 1] == '\r' && buf[i + 2] == '\n') {
      return i + 3;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_request_len>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L88
  nopl   0x0(%rax)
L51:
  cmp    $0xd,%al
  je     L2
  cmp    $0xa,%al
  je     L107
  test   %al,%al
  jns    L97
L74:
  cmp    %ebp,%r13d
  jle    L24
L82:
  add    $0x1,%rbx
  add    $0x1,%ebp
  add    $0x1,%r12d
L88:
  movzbl (%rbx),%edi
  call   <isprint@plt>
  test   %eax,%eax
  movzbl (%rbx),%eax
  je     L51
L2:
  cmp    $0xa,%al
  jne    L74
L107:
  mov    %r12d,%r8d
  cmp    %ebp,%r13d
  jle    L121
  movzbl 0x1(%rbx),%eax
  cmp    $0xa,%al
  je     L120
  cmp    %r12d,%r13d
  jle    L82
  cmp    $0xd,%al
  jne    L82
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L121:
  cmp    %r12d,%r13d
  jle    L24
  cmpb   $0xd,0x1(%rbx)
  jne    L24
L9:
  cmpb   $0xa,0x2(%rbx)
  jne    L74
  lea    0x2(%rbp),%r8d
L120:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L97:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_request_len(const char *s, int buf_len) {
  const unsigned char *buf = (unsigned char *)s;
  int i;
  for (i = 0; i < buf_len; i++) {
    if (!isprint(buf[i]) && buf[i] != '\r' && buf[i] != '\n' && buf[i] < 128) {
      return -1;
    } else if (buf[i] == '\n' && i + 1 < buf_len && buf[i + 1] == '\n') {
      return i + 2;
    } else if (buf[i] == '\n' && i + 2 < buf_len && buf[i + 1] == '\r' && buf[i + 2] == '\n') {
      return i + 3;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L96:
  cmp    %rdx,%rsp
  je     L41
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L96
L41:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L12
  orq    $0x0,-0x8(%rsp,%rax,1)
L12:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L13
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,4),%r15
L99:
  mov    $0x0,%eax
  call   <rand_float@plt>
  mulss  D25(%rip),%xmm0
  subss  D37(%rip),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %r15,%rbx
  jne    L99
L13:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L63
  mov    $0x0,%ebx
L25:
  mov    $0x1,%edx
  mov    %r14,%rsi
  movss  D20(%rip),%xmm0
  mov    %r12d,%edi
  call   <stdlib_strided_snanstdev@plt>
  ucomiss %xmm0,%xmm0
  jp     L15
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L25
L63:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L2:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L15:
  lea    D28(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L2
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D25
type_guessed: byte[4]
name: parse_data
arguments: label: D37
type_guessed: byte[4]
name: parse_data
arguments: label: D20
type_guessed: byte[4]
name: parse_data
arguments: label: D28
type_guessed: string

tool: {"D25": [0x00,0x40,0x9c,0x46]}

tool: {"D37": [0x00,0x40,0x1c,0x46]}

tool: {"D20": [0x00,0x00,0x80,0x3f]}

tool: D28: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_snanstdev(len, 1.0f, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L58
L91:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L91
L58:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L70
L113:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L51
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,4),%r14
  nopl   0x0(%rax)
L112:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand_float@plt>
  mulss  D37(%rip),%xmm0
  subss  D26(%rip),%xmm0
  movss  %xmm0,-0x4(%r15)
  cmp    %r14,%r15
  jne    L112
L51:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L0
  xor    %r14d,%r14d
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L0
L67:
  movss  D1(%rip),%xmm0
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_snanstdev@plt>
  ucomiss %xmm0,%xmm0
  jnp    L2
  lea    D28(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L30:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L0:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L30
  xchg   %ax,%ax
L70:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L113
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D37
type_infered: byte[4]
name: read_data
arguments: tag: D26
type_infered: byte[4]
name: read_data
arguments: tag: D1
type_infered: byte[4]
name: read_data
arguments: tag: D28
type_infered: string

tool: {"D37": [0x00,0x40,0x9c,0x46]}

tool: {"D26": [0x00,0x40,0x1c,0x46]}

tool: {"D1": [0x00,0x00,0x80,0x3f]}

tool: D28: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_snanstdev(len, 1.0f, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L2
L64:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L64
L2:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L94
L44:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L18
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,4),%r14
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand_float@plt>
  mulss  D12(%rip),%xmm0
  subss  D28(%rip),%xmm0
  movss  %xmm0,-0x4(%r15)
  cmp    %r14,%r15
  jne    L45
L18:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L101
  xor    %r14d,%r14d
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L54:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L101
L36:
  movss  D20(%rip),%xmm0
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_snanstdev@plt>
  ucomiss %xmm0,%xmm0
  jnp    L54
  lea    D1(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L63:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L101:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L63
  xchg   %ax,%ax
L94:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L44
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D28
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D20
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: {"D12": [0x00,0x40,0x9c,0x46]}

tool: {"D28": [0x00,0x40,0x1c,0x46]}

tool: {"D20": [0x00,0x00,0x80,0x3f]}

tool: D1: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_snanstdev(len, 1.0f, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<make_message_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    $0x20,%eax
  mov    %eax,%ecx
  shll   %cl,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t make_message_tag(uint32_t msg_counter, uint32_t time) {
  uint64_t id = 0;
  id |= time;
  id = id << 32;
  id |= msg_counter;
  return id;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<make_message_tag>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint64_t make_message_tag(uint32_t msg_counter, uint32_t time) {
  uint64_t id = 0;
  id |= time;
  id = id << 32;
  id |= msg_counter;
  return id;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_message_tag>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint64_t make_message_tag(uint32_t msg_counter, uint32_t time) {
  uint64_t id = 0;
  id |= time;
  id = id << 32;
  id |= msg_counter;
  return id;
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_message_tag>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint64_t make_message_tag(uint32_t msg_counter, uint32_t time) {
  uint64_t id = 0;
  id |= time;
  id = id << 32;
  id |= msg_counter;
  return id;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<change>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  imul   $0xffffffe7,%eax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  imul   $0xfffffff6,%eax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  neg    %eax
  add    %eax,-0x4(%rbp)
  mov    -0x38(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: f64

tool: D9: 100.01

assistant: ```c
int change(float num1, int *quarters, int *dimes, int *nickels, int *pennies) {
  int num2 = (int)(num1 * 100.01);
  *quarters = num2 / 25;
  num2 = num2 - (*quarters * 25);
  *dimes = num2 / 10;
  num2 = num2 - (*dimes * 10);
  *nickels = num2 / 5;
  num2 = num2 - (*nickels * 5);
  *pennies = num2;
  ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<change>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  cvtss2sd %xmm0,%xmm0
  mulsd  D0(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%edx
  mov    %edx,(%r8)
  imul   $0xffffffe7,%edx,%edx
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  mov    %eax,(%rdi)
  imul   $0xfffffff6,%eax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  mov    %edx,(%rsi)
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  mov    %eax,(%rcx)
  mov    $0x0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: f64

tool: D0: 100.01

assistant: ```c
int change(float num1, int *quarters, int *dimes, int *nickels, int *pennies) {
  int num2 = (int)(num1 * 100.01);
  *quarters = num2 / 25;
  num2 = num2 - (*quarters * 25);
  *dimes = num2 / 10;
  num2 = num2 - (*dimes * 10);
  *nickels = num2 / 5;
  num2 = num2 - (*nickels * 5);
  *pennies = num2;
  ;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<change>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  mulsd  D3(%rip),%xmm0
  mov    %rdx,%r8
  cvttsd2si %xmm0,%eax
  movslq %eax,%rdx
  mov    %eax,%r9d
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%r9d
  sar    $0x23,%rdx
  sub    %r9d,%edx
  mov    %edx,(%rdi)
  imul   $0xffffffe7,%edx,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edi
  sar    $0x22,%rax
  sub    %edi,%eax
  mov    %eax,(%rsi)
  imul   $0xfffffff6,%eax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x21,%rdx
  sub    %esi,%edx
  mov    %edx,(%r8)
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  mov    %eax,(%rcx)
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: f64

tool: D3: 100.01

assistant: ```c
int change(float num1, int *quarters, int *dimes, int *nickels, int *pennies) {
  int num2 = (int)(num1 * 100.01);
  *quarters = num2 / 25;
  num2 = num2 - (*quarters * 25);
  *dimes = num2 / 10;
  num2 = num2 - (*dimes * 10);
  *nickels = num2 / 5;
  num2 = num2 - (*nickels * 5);
  *pennies = num2;
  ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<change>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  mulsd  D2(%rip),%xmm0
  mov    %rdx,%r8
  cvttsd2si %xmm0,%eax
  movslq %eax,%rdx
  mov    %eax,%r9d
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%r9d
  sar    $0x23,%rdx
  sub    %r9d,%edx
  mov    %edx,(%rdi)
  imul   $0xffffffe7,%edx,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%edi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edi
  sar    $0x22,%rax
  sub    %edi,%eax
  mov    %eax,(%rsi)
  imul   $0xfffffff6,%eax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x21,%rdx
  sub    %esi,%edx
  mov    %edx,(%r8)
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  mov    %eax,(%rcx)
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: f64

tool: D2: 100.01

assistant: ```c
int change(float num1, int *quarters, int *dimes, int *nickels, int *pennies) {
  int num2 = (int)(num1 * 100.01);
  *quarters = num2 / 25;
  num2 = num2 - (*quarters * 25);
  *dimes = num2 / 10;
  num2 = num2 - (*dimes * 10);
  *nickels = num2 / 5;
  num2 = num2 - (*nickels * 5);
  *pennies = num2;
  ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<http_send_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  jmp    L31
L23:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x18(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L24
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jg     L23
  jmp    L18
L24:
  nop
L18:
  mov    -0xc(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
long http_send_all(int socket, const void *buffer, long length, int flags) {
  int total = 0;
  int bytesleft = length;
  int n;
  while (total < length) {
    n = send(socket, buffer + total, bytesleft, flags);
    if (n == -1) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  return total;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<http_send_all>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rdx,%rdx
  jle    L32
  mov    %edi,%r14d
  mov    %rdx,%r13
  mov    %ecx,%r15d
  mov    %edx,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
L3:
  movslq %ebx,%rsi
  add    0x8(%rsp),%rsi
  mov    %r15d,%ecx
  mov    %ebp,%edx
  mov    %r14d,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  je     L28
  add    %eax,%ebx
  sub    %eax,%ebp
  movslq %ebx,%r12
  cmp    %r13,%r12
  jl     L3
L28:
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    $0x0,%r12d
  jmp    L28
```

assistant: ```c
long http_send_all(int socket, const void *buffer, long length, int flags) {
  int total = 0;
  int bytesleft = length;
  int n;
  while (total < length) {
    n = send(socket, buffer + total, bytesleft, flags);
    if (n == -1) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  return total;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<http_send_all>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rdx,%rdx
  jle    L6
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    %ecx,%r13d
  mov    %edx,%ebx
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  xor    %esi,%esi
  jmp    L26
L32:
  add    %eax,%r15d
  sub    %eax,%ebx
  movslq %r15d,%rsi
  mov    %rsi,%r14
  cmp    0x8(%rsp),%rsi
  jge    L11
L26:
  add    %r12,%rsi
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  jne    L32
L11:
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  xor    %r14d,%r14d
  jmp    L11
```

assistant: ```c
long http_send_all(int socket, const void *buffer, long length, int flags) {
  int total = 0;
  int bytesleft = length;
  int n;
  while (total < length) {
    n = send(socket, buffer + total, bytesleft, flags);
    if (n == -1) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  return total;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<http_send_all>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rdx,%rdx
  jle    L21
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    %ecx,%r13d
  mov    %edx,%ebx
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  xor    %esi,%esi
  jmp    L14
L31:
  add    %eax,%r15d
  sub    %eax,%ebx
  movslq %r15d,%rsi
  mov    %rsi,%r14
  cmp    0x8(%rsp),%rsi
  jge    L35
L14:
  add    %r12,%rsi
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  jne    L31
L35:
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  xor    %r14d,%r14d
  jmp    L35
```

assistant: ```c
long http_send_all(int socket, const void *buffer, long length, int flags) {
  int total = 0;
  int bytesleft = length;
  int n;
  while (total < length) {
    n = send(socket, buffer + total, bytesleft, flags);
    if (n == -1) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  return total;
}
```