ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D19(%rip),%r13
  lea    D16(%rip),%r12
  lea    D26(%rip),%rbp
L5:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L5
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string
name: unpack_data
arguments: data_tag: D26
type_guessed: string

tool: D19: iteration-order

tool: D16: # c::native::%s


tool: D26: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "iteration-order");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D25(%rip),%r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L4
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D25
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D15
data_type: string

tool: D25: iteration-order

tool: D28: # c::native::%s


tool: D15: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "iteration-order");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D14(%rip),%r13
  push   %r12
  lea    D22(%rip),%r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L9
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
datatype: string
name: parse_data
arguments: tag: D22
datatype: string
name: parse_data
arguments: tag: D13
datatype: string

tool: D14: iteration-order

tool: D22: # c::native::%s


tool: D13: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "iteration-order");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printVectorInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int printVectorInt(int *ma, int dim) {
  int i;
  for (i = 0; i < dim; i++) {
    printf("%d", ma[i]);
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printVectorInt>:
  endbr64
  test   %esi,%esi
  jle    L13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D4(%rip),%rbp
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    $0x0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: %d

assistant: ```c
int printVectorInt(int *ma, int dim) {
  int i;
  for (i = 0; i < dim; i++) {
    printf("%d", ma[i]);
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printVectorInt>:
  endbr64
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12,%rbx
  jne    L10
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D9: %d

assistant: ```c
int printVectorInt(int *ma, int dim) {
  int i;
  for (i = 0; i < dim; i++) {
    printf("%d", ma[i]);
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printVectorInt>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: %d

assistant: ```c
int printVectorInt(int *ma, int dim) {
  int i;
  for (i = 0; i < dim; i++) {
    printf("%d", ma[i]);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_single_positive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <max_sum_brute@plt>
  cmp    $0x5,%eax
  jne    L12
  lea    -0xc(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <max_sum@plt>
  cmp    $0x5,%eax
  jne    L12
  mov    $0x1,%eax
  jmp    L0
L12:
  mov    $0x0,%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int test_single_positive() {
  int input[] = {5};
  return 5 == max_sum_brute(input, 1) && 5 == max_sum(input, 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<test_single_positive>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x1,%esi
  call   <max_sum_brute@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x5,%edx
  je     L2
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L2:
  lea    0x4(%rsp),%rdi
  mov    $0x1,%esi
  call   <max_sum@plt>
  cmp    $0x5,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L5
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_single_positive() {
  int input[] = {5};
  return 5 == max_sum_brute(input, 1) && 5 == max_sum(input, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_single_positive>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x5,0x4(%rsp)
  mov    %rbp,%rdi
  call   <max_sum_brute@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x5,%r8d
  je     L20
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <max_sum@plt>
  cmp    $0x5,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L28
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_single_positive() {
  int input[] = {5};
  return 5 == max_sum_brute(input, 1) && 5 == max_sum(input, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_single_positive>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x5,0x4(%rsp)
  mov    %rbp,%rdi
  call   <max_sum_brute@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x5,%r8d
  je     L20
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <max_sum@plt>
  cmp    $0x5,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L28
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_single_positive() {
  int input[] = {5};
  return 5 == max_sum_brute(input, 1) && 5 == max_sum(input, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string

tool: D12: %s [-h -n number] sequence file


tool: D11: -h print a detailed help
-n print n sequences from the file
-a print the output in fasta format (the default is fastq)

assistant: ```c
void print_usage(char *name) {
  printf("%s [-h -n number] sequence file\n", name);
  printf("-h print a detailed help\n"
         "-n print n sequences from the file\n"
         "-a print the output in fasta format (the default is fastq)\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string

tool: D5: %s [-h -n number] sequence file


tool: D14: -h print a detailed help
-n print n sequences from the file
-a print the output in fasta format (the default is fastq)

assistant: ```c
void print_usage(char *name) {
  printf("%s [-h -n number] sequence file\n", name);
  printf("-h print a detailed help\n"
         "-n print n sequences from the file\n"
         "-a print the output in fasta format (the default is fastq)\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type: string
name: disassemble_data
arguments: data_tag: D17
type: string

tool: D19: %s [-h -n number] sequence file


tool: D17: -h print a detailed help
-n print n sequences from the file
-a print the output in fasta format (the default is fastq)

assistant: ```c
void print_usage(char *name) {
  printf("%s [-h -n number] sequence file\n", name);
  printf("-h print a detailed help\n"
         "-n print n sequences from the file\n"
         "-a print the output in fasta format (the default is fastq)\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string
name: read_data
arguments: label: D16
type_infered: string

tool: D8: %s [-h -n number] sequence file


tool: D16: -h print a detailed help
-n print n sequences from the file
-a print the output in fasta format (the default is fastq)

assistant: ```c
void print_usage(char *name) {
  printf("%s [-h -n number] sequence file\n", name);
  printf("-h print a detailed help\n"
         "-n print n sequences from the file\n"
         "-a print the output in fasta format (the default is fastq)\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<WalkDeleteEven>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <rtl_htblGetFlags@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L16
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  and    $0x1,%eax
  test   %eax,%eax
  je     L50
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rtl_htblRemove@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L50:
  mov    $0x0,%eax
  jmp    L11
L16:
  mov    -0x4(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L1
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L13
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rtl_htblRemove@plt>
L13:
  mov    $0x0,%eax
  jmp    L11
L1:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int WalkDeleteEven(void *h, char *k, void *d, void *u) {
  int f = rtl_htblGetFlags(h);
  if ((f & 1) == 1) {
    if (atoi(k) % 2 != 0) {
      rtl_htblRemove(h, k);
      free(d);
    }
    return 0;
  }
  if ((f & 2) == 2) {
    if (((size_t)k) % 2 != 0) {
      rtl_htblRemove(h, k);
    }
    return 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<WalkDeleteEven>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <rtl_htblGetFlags@plt>
  test   $0x1,%al
  jne    L35
  test   $0x2,%al
  jne    L8
L55:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    %r12,%rdi
  call   <atoi@plt>
  test   $0x1,%al
  je     L55
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <rtl_htblRemove@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L55
L8:
  test   $0x1,%r12b
  je     L55
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <rtl_htblRemove@plt>
  jmp    L55
```

assistant: ```c
int WalkDeleteEven(void *h, char *k, void *d, void *u) {
  int f = rtl_htblGetFlags(h);
  if ((f & 1) == 1) {
    if (atoi(k) % 2 != 0) {
      rtl_htblRemove(h, k);
      free(d);
    }
    return 0;
  }
  if ((f & 2) == 2) {
    if (((size_t)k) % 2 != 0) {
      rtl_htblRemove(h, k);
    }
    return 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<WalkDeleteEven>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <rtl_htblGetFlags@plt>
  test   $0x1,%al
  jne    L36
  test   $0x2,%al
  jne    L34
L46:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  test   $0x1,%r13b
  je     L46
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <rtl_htblRemove@plt>
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %r13,%rdi
  call   <atoi@plt>
  test   $0x1,%al
  je     L46
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <rtl_htblRemove@plt>
  mov    %r12,%rdi
  call   <free@plt>
  jmp    L46
```

assistant: ```c
int WalkDeleteEven(void *h, char *k, void *d, void *u) {
  int f = rtl_htblGetFlags(h);
  if ((f & 1) == 1) {
    if (atoi(k) % 2 != 0) {
      rtl_htblRemove(h, k);
      free(d);
    }
    return 0;
  }
  if ((f & 2) == 2) {
    if (((size_t)k) % 2 != 0) {
      rtl_htblRemove(h, k);
    }
    return 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WalkDeleteEven>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <rtl_htblGetFlags@plt>
  test   $0x1,%al
  jne    L26
  test   $0x2,%al
  jne    L15
L52:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  test   $0x1,%r13b
  je     L52
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <rtl_htblRemove@plt>
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %r13,%rdi
  call   <atoi@plt>
  test   $0x1,%al
  je     L52
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <rtl_htblRemove@plt>
  mov    %r12,%rdi
  call   <free@plt>
  jmp    L52
```

assistant: ```c
int WalkDeleteEven(void *h, char *k, void *d, void *u) {
  int f = rtl_htblGetFlags(h);
  if ((f & 1) == 1) {
    if (atoi(k) % 2 != 0) {
      rtl_htblRemove(h, k);
      free(d);
    }
    return 0;
  }
  if ((f & 2) == 2) {
    if (((size_t)k) % 2 != 0) {
      rtl_htblRemove(h, k);
    }
    return 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__acpi_release_global_lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x4,%ecx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__cmpxchg@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  test   %rax,%rax
  jne    L5
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int __acpi_release_global_lock(unsigned int *lock) {
  unsigned int old, new, val;
  do {
    old = *lock;
    new = old & ~0x3;
    val = ((__typeof__(*(lock)))__cmpxchg((lock), (unsigned long)(old), (unsigned long)(new), sizeof(*(lock))));
  } while (__builtin_expect(!!(val != old), 0));
  return old & 0x1;
}
```
user: What is the c source code of the assembly code below:

```asm
<__acpi_release_global_lock>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L6:
  mov    0x0(%rbp),%ebx
  mov    %ebx,%edx
  and    $0xfffffffc,%edx
  mov    %ebx,%esi
  mov    $0x4,%ecx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <__cmpxchg@plt>
  cmp    %eax,%ebx
  jne    L6
  mov    %ebx,%eax
  and    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int __acpi_release_global_lock(unsigned int *lock) {
  unsigned int old, new, val;
  do {
    old = *lock;
    new = old & ~0x3;
    val = ((__typeof__(*(lock)))__cmpxchg((lock), (unsigned long)(old), (unsigned long)(new), sizeof(*(lock))));
  } while (__builtin_expect(!!(val != old), 0));
  return old & 0x1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__acpi_release_global_lock>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L2:
  mov    0x0(%rbp),%esi
  xor    %eax,%eax
  mov    $0x4,%ecx
  mov    %rbp,%rdi
  mov    %esi,%edx
  mov    %rsi,%rbx
  and    $0xfffffffc,%edx
  call   <__cmpxchg@plt>
  cmp    %eax,%ebx
  jne    L2
  mov    %ebx,%eax
  add    $0x8,%rsp
  and    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int __acpi_release_global_lock(unsigned int *lock) {
  unsigned int old, new, val;
  do {
    old = *lock;
    new = old & ~0x3;
    val = ((__typeof__(*(lock)))__cmpxchg((lock), (unsigned long)(old), (unsigned long)(new), sizeof(*(lock))));
  } while (__builtin_expect(!!(val != old), 0));
  return old & 0x1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__acpi_release_global_lock>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L8:
  mov    0x0(%rbp),%esi
  xor    %eax,%eax
  mov    $0x4,%ecx
  mov    %rbp,%rdi
  mov    %esi,%edx
  mov    %rsi,%rbx
  and    $0xfffffffc,%edx
  call   <__cmpxchg@plt>
  cmp    %eax,%ebx
  jne    L8
  mov    %ebx,%eax
  add    $0x8,%rsp
  and    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int __acpi_release_global_lock(unsigned int *lock) {
  unsigned int old, new, val;
  do {
    old = *lock;
    new = old & ~0x3;
    val = ((__typeof__(*(lock)))__cmpxchg((lock), (unsigned long)(old), (unsigned long)(new), sizeof(*(lock))));
  } while (__builtin_expect(!!(val != old), 0));
  return old & 0x1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decodeSecondByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void decodeSecondByte(uint8_t *src, uint32_t *p32_dest) {
  uint8_t *p8_dest = (uint8_t *)p32_dest;
  *(p8_dest + 1) = *(src + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<decodeSecondByte>:
  endbr64
  mov    0x4(%rdi),%eax
  mov    %eax,0x4(%rsi)
  ret
```

assistant: ```c
void decodeSecondByte(uint8_t *src, uint32_t *p32_dest) {
  uint8_t *p8_dest = (uint8_t *)p32_dest;
  *(p8_dest + 1) = *(src + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decodeSecondByte>:
  endbr64
  mov    0x4(%rdi),%eax
  mov    %eax,0x4(%rsi)
  ret
```

assistant: ```c
void decodeSecondByte(uint8_t *src, uint32_t *p32_dest) {
  uint8_t *p8_dest = (uint8_t *)p32_dest;
  *(p8_dest + 1) = *(src + 1);
}
```