user: 这段汇编代码用C语言表示是什么样的？

```asm
<tokenize>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  mov    $0x3e8,%edi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    $0x1f40,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  jmp    L36
  nopl   (%rax)
L86:
  movslq %ebp,%rdx
  add    %r13,%rdx
  cmp    $0x1,%r12d
  je     L38
  lea    -0x9(%rax),%esi
  cmp    $0x1,%sil
  jbe    L54
  cmp    $0x20,%al
  jne    L38
L54:
  movb   $0x0,(%rdx)
  test   %ebp,%ebp
  jne    L20
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L107:
  add    $0x1,%rbx
L36:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L148
  movzbl (%r14,%rbx,1),%eax
  cmp    $0x22,%al
  jne    L86
  lea    0x1(%r12),%eax
  mov    %eax,%r12d
  and    $0x1,%r12d
  cmp    $0x1,%eax
  je     L107
  movslq %ebp,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  test   %ebp,%ebp
  je     L107
  mov    $0x8,%edi
  xor    %ebp,%ebp
  call   <malloc@plt>
  mov    0x8(%rsp),%rcx
  mov    %r13,%rsi
  mov    %rax,%rdi
  movslq %r15d,%rax
  add    $0x1,%r15d
  mov    %rdi,(%rcx,%rax,8)
  call   <strcpy@plt>
  jmp    L107
L38:
  mov    %al,(%rdx)
  add    $0x1,%ebp
  jmp    L107
  nopw   0x0(%rax,%rax,1)
L148:
  cmp    $0x1,%r12d
  je     L122
L6:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x8,%edi
  mov    %r12d,%ebp
  call   <malloc@plt>
  mov    0x8(%rsp),%rcx
  mov    %r13,%rsi
  mov    %rax,%rdi
  movslq %r15d,%rax
  add    $0x1,%r15d
  mov    %rdi,(%rcx,%rax,8)
  call   <strcpy@plt>
  jmp    L107
  nopl   (%rax)
L122:
  movslq %ebp,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  test   %ebp,%ebp
  je     L6
  mov    $0x8,%edi
  movslq %r15d,%r15
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    0x8(%rsp),%rax
  mov    %rdi,(%rax,%r15,8)
  call   <strcpy@plt>
  jmp    L6
```

assistant: ```c
char **tokenize(char *input) {
  int i;
  int doubleQuotes = 0;
  char *token = (char *)malloc(1000 * sizeof(char));
  int tokenIndex = 0;
  char **tokens;
  tokens = (char **)malloc(1000 * sizeof(char **));
  int tokenNo = 0;
  for (i = 0; i < strlen(input); i++) {
    char readChar = input[i];
    if (readChar == '"') {
      doubleQuotes = (doubleQuotes + 1) % 2;
      if (doubleQuotes == 0) {
        token[tokenIndex] = '\0';
        if (tokenIndex != 0) {
          tokens[tokenNo] = (char *)malloc(sizeof(token));
          strcpy(tokens[tokenNo++], token);
          tokenIndex = 0;
        }
      }
    } else if (doubleQuotes == 1) {
      token[tokenIndex++] = readChar;
    } else if (readChar == ' ' || readChar == '\n' || readChar == '\t') {
      token[tokenIndex] = '\0';
      if (tokenIndex != 0) {
        tokens[tokenNo] = (char *)malloc(sizeof(token));
        strcpy(tokens[tokenNo++], token);
        tokenIndex = 0;
      }
    } else {
      token[tokenIndex++] = readChar;
    }
  }
  if (doubleQuotes == 1) {
    token[tokenIndex] = '\0';
    if (tokenIndex != 0) {
      tokens[tokenNo] = (char *)malloc(sizeof(token));
      strcpy(tokens[tokenNo++], token);
    }
  }
  return tokens;
}
```