ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x338(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x338(%rbp),%xmm0
  movsd  %xmm0,-0x330(%rbp)
  movl   $0x1,-0x33c(%rbp)
  jmp    L19
L29:
  mov    -0x33c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movsd  -0x330(%rbp,%rax,8),%xmm0
  movsd  D19(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x33c(%rbp),%eax
  cltq
  movsd  %xmm0,-0x330(%rbp,%rax,8)
  addl   $0x1,-0x33c(%rbp)
L19:
  cmpl   $0x63,-0x33c(%rbp)
  jle    L29
  movl   $0x0,-0x33c(%rbp)
  jmp    L13
L40:
  mov    -0x33c(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,8),%rdx
  mov    -0x33c(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x33c(%rbp)
L13:
  cmpl   $0x63,-0x33c(%rbp)
  jle    L40
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D19
datatype: byte[8]
name: read_data
arguments: data_tag: D9
datatype: string

tool: D13: %lf

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D9: N[%d] = %.4f


assistant: ```c
int main() {
  int i;
  double x, N[100];
  scanf("%lf", &x);
  N[0] = x;
  for (i = 1; i < 100; i++)
    N[i] = N[i - 1] / 2;
  for (i = 0; i < 100; i++)
    printf("N[%d] = %.4f\n", i, N[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x10(%rsp)
  lea    0x10(%rsp),%rax
  lea    0x328(%rsp),%rdx
  movsd  D15(%rip),%xmm1
L23:
  movapd %xmm1,%xmm0
  mulsd  (%rax),%xmm0
  movsd  %xmm0,0x8(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L23
  mov    $0x0,%ebx
  lea    D9(%rip),%rbp
L17:
  movsd  0x10(%rsp,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  jne    L17
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x348,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: byte[8]
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D26: %lf

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D9: N[%d] = %.4f


assistant: ```c
int main() {
  int i;
  double x, N[100];
  scanf("%lf", &x);
  N[0] = x;
  for (i = 1; i < 100; i++)
    N[i] = N[i - 1] / 2;
  for (i = 0; i < 100; i++)
    printf("N[%d] = %.4f\n", i, N[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  D6(%rip),%xmm2
  lea    0x18(%rsp),%rax
  lea    0x328(%rsp),%rdx
  movsd  %xmm1,0x10(%rsp)
  movapd %xmm1,%xmm0
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x8,%rax
L32:
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rax)
  cmp    %rdx,%rax
  jne    L31
  xor    %ebx,%ebx
  lea    D11(%rip),%rbp
  jmp    L35
  nopl   0x0(%rax)
L49:
  movsd  0x10(%rsp,%rbx,8),%xmm1
L35:
  mov    %ebx,%esi
  movapd %xmm1,%xmm0
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L49
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x348,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D29
type: string
name: disassemble_data
arguments: label: D6
type: byte[8]
name: disassemble_data
arguments: label: D11
type: string

tool: D29: %lf

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D11: N[%d] = %.4f


assistant: ```c
int main() {
  int i;
  double x, N[100];
  scanf("%lf", &x);
  N[0] = x;
  for (i = 1; i < 100; i++)
    N[i] = N[i - 1] / 2;
  for (i = 0; i < 100; i++)
    printf("N[%d] = %.4f\n", i, N[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  D23(%rip),%xmm1
  lea    0x18(%rsp),%rax
  lea    0x330(%rsp),%rdx
  movsd  %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L4:
  mulsd  %xmm1,%xmm0
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rdx,%rax
  jne    L4
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  lea    D15(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L5
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D23
type_infered: byte[8]
name: unpack_data
arguments: data_label: D15
type_infered: string

tool: D6: %lf

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D15: N[%d] = %.4f


assistant: ```c
int main() {
  int i;
  double x, N[100];
  scanf("%lf", &x);
  N[0] = x;
  for (i = 1; i < 100; i++)
    N[i] = N[i - 1] / 2;
  for (i = 0; i < 100; i++)
    printf("N[%d] = %.4f\n", i, N[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x4,%esi
  mov    $0x1312d00,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    $0x4,%esi
  mov    $0x1312d00,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  lea    0x4c4b400(%rax),%rcx
  mov    %rbp,%rdx
  sub    %rax,%rdx
L23:
  movl   $0x1,(%rax)
  movl   $0x1,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L23
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%r14
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%r13d
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  test   %r13d,%r13d
  je     L21
  imul   $0x1312d00,%r13d,%esi
  mov    %esi,%eax
  cltd
  idiv   %r12d
  mov    %eax,%ecx
  lea    -0x1(%r12),%edx
  mov    $0x1312d00,%eax
  cmp    %r13d,%edx
  je     L1
  lea    0x1312d00(%rsi),%eax
  cltd
  idiv   %r12d
L1:
  cmp    %ecx,%eax
  jle    L53
L72:
  movslq %ecx,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
  sub    %rbp,%rbx
L6:
  mov    (%rbx,%rdx,1),%esi
  add    %esi,(%rdx)
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %eax,%ecx
  jl     L6
L53:
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %r14,%xmm1
  subsd  %xmm1,%xmm0
  mov    $0x1312d00,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1312d00,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%r12d
  je     L30
  mov    $0x1312d00,%eax
  cltd
  idiv   %r12d
  mov    %r13d,%ecx
  jmp    L1
L30:
  mov    %r13d,%ecx
  mov    $0x1312d00,%eax
  jmp    L72
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string

tool: D12: Soma de %d numeros em tempo: %.4f segundos.


tool: D11: Soma de %d numeros com %d threads


assistant: ```c
int main(void) {
  int N = 20000000;
  double t0, t1, tdelta;
  int *a, *b;
  int i;
  a = (int *)calloc(20000000, sizeof(int));
  b = (int *)calloc(20000000, sizeof(int));
  for (i = 0; i < N; i++) {
    a[i] = b[i] = 1;
  }
  t0 = omp_get_wtime();
#pragma omp parallel
  {
    int id, i, nthreads, istart, iend;
    id = omp_get_thread_num();
    nthreads = omp_get_num_threads();
    if (id == 0)
      printf("Soma de %d numeros com %d threads\n", N, nthreads);
    istart = id * N / nthreads;
    iend = (id + 1) * N / nthreads;
    if (id == nthreads - 1)
      iend = N;
    for (i = istart; i < iend; i++)
      a[i] = a[i] + b[i];
  }
  t1 = omp_get_wtime();
  tdelta = t1 - t0;
  printf("Soma de %d numeros em tempo: %.4f segundos.\n", N, tdelta);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x4,%esi
  mov    $0x1312d00,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <calloc@plt>
  mov    $0x4,%esi
  mov    $0x1312d00,%edi
  mov    %rax,%rbx
  call   <calloc@plt>
  mov    %rbx,%rdx
  mov    %rax,%rbp
  lea    0x4c4b400(%rax),%rcx
  sub    %rax,%rdx
  nop
L50:
  movl   $0x1,(%rax)
  movl   $0x1,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L50
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <omp_get_thread_num@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  test   %r13d,%r13d
  je     L54
  imul   $0x1312d00,%r13d,%esi
  mov    %esi,%eax
  cltd
  idiv   %r12d
  lea    -0x1(%r12),%edx
  mov    %eax,%ecx
  mov    $0x1312d00,%eax
  cmp    %r13d,%edx
  je     L10
  lea    0x1312d00(%rsi),%eax
  cltd
  idiv   %r12d
L10:
  cmp    %ecx,%eax
  jle    L1
L66:
  movslq %ecx,%rdx
  mov    %rbp,%rdi
  lea    (%rbx,%rdx,4),%rdx
  sub    %rbx,%rdi
  nopl   (%rax)
L53:
  add    $0x1,%ecx
  mov    (%rdi,%rdx,1),%esi
  add    %esi,(%rdx)
  add    $0x4,%rdx
  cmp    %eax,%ecx
  jl     L53
L1:
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  subsd  0x8(%rsp),%xmm0
  mov    $0x1312d00,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  pxor   %xmm0,%xmm0
  mov    $0x1312d00,%esi
  lea    D11(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  call   <printf@plt>
  cmp    $0x1,%r12d
  je     L35
  mov    $0x1312d00,%eax
  xor    %ecx,%ecx
  cltd
  idiv   %r12d
  jmp    L10
L35:
  xor    %ecx,%ecx
  mov    $0x1312d00,%eax
  jmp    L66
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type_guessed: string
name: retrieve_data
arguments: data_tag: D11
type_guessed: string

tool: D16: Soma de %d numeros em tempo: %.4f segundos.


tool: D11: Soma de %d numeros com %d threads


assistant: ```c
int main(void) {
  int N = 20000000;
  double t0, t1, tdelta;
  int *a, *b;
  int i;
  a = (int *)calloc(20000000, sizeof(int));
  b = (int *)calloc(20000000, sizeof(int));
  for (i = 0; i < N; i++) {
    a[i] = b[i] = 1;
  }
  t0 = omp_get_wtime();
#pragma omp parallel
  {
    int id, i, nthreads, istart, iend;
    id = omp_get_thread_num();
    nthreads = omp_get_num_threads();
    if (id == 0)
      printf("Soma de %d numeros com %d threads\n", N, nthreads);
    istart = id * N / nthreads;
    iend = (id + 1) * N / nthreads;
    if (id == nthreads - 1)
      iend = N;
    for (i = istart; i < iend; i++)
      a[i] = a[i] + b[i];
  }
  t1 = omp_get_wtime();
  tdelta = t1 - t0;
  printf("Soma de %d numeros em tempo: %.4f segundos.\n", N, tdelta);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string

tool: D0: Built with Hoedown 3.0.5.


assistant: ```c
void print_version() {
  printf("Built with Hoedown "
         "3.0.5"
         ".\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_version>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: Built with Hoedown 3.0.5.


assistant: ```c
void print_version() {
  printf("Built with Hoedown "
         "3.0.5"
         ".\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_version>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: Built with Hoedown 3.0.5.


assistant: ```c
void print_version() {
  printf("Built with Hoedown "
         "3.0.5"
         ".\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_version>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: Built with Hoedown 3.0.5.


assistant: ```c
void print_version() {
  printf("Built with Hoedown "
         "3.0.5"
         ".\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nios_lms6_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nios_8x8_read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int nios_lms6_read(struct bladerf *dev, uint8_t addr, uint8_t *data) {
  int status = nios_8x8_read(dev, 0x00, addr, data);
  if (status == 0) {
    do {
      do {
      } while (0);
    } while (0);
  }
  return status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nios_lms6_read>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x0,%esi
  call   <nios_8x8_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int nios_lms6_read(struct bladerf *dev, uint8_t addr, uint8_t *data) {
  int status = nios_8x8_read(dev, 0x00, addr, data);
  if (status == 0) {
    do {
      do {
      } while (0);
    } while (0);
  }
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nios_lms6_read>:
  endbr64
  mov    %rdx,%rcx
  mov    %esi,%edx
  xor    %esi,%esi
  jmp    1050 <nios_8x8_read@plt>
```

assistant: ```c
int nios_lms6_read(struct bladerf *dev, uint8_t addr, uint8_t *data) {
  int status = nios_8x8_read(dev, 0x00, addr, data);
  if (status == 0) {
    do {
      do {
      } while (0);
    } while (0);
  }
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nios_lms6_read>:
  endbr64
  mov    %rdx,%rcx
  mov    %esi,%edx
  xor    %esi,%esi
  jmp    1050 <nios_8x8_read@plt>
```

assistant: ```c
int nios_lms6_read(struct bladerf *dev, uint8_t addr, uint8_t *data) {
  int status = nios_8x8_read(dev, 0x00, addr, data);
  if (status == 0) {
    do {
      do {
      } while (0);
    } while (0);
  }
  return status;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<corextent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <parxtent@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  leave
  ret
```

assistant: ```c
unsigned long int corextent(void) {
  unsigned long l;
  l = parxtent();
  return l << 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<corextent>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <parxtent@plt>
  shl    $0x4,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long int corextent(void) {
  unsigned long l;
  l = parxtent();
  return l << 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<corextent>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <parxtent@plt>
  add    $0x8,%rsp
  shl    $0x4,%rax
  ret
```

assistant: ```c
unsigned long int corextent(void) {
  unsigned long l;
  l = parxtent();
  return l << 4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<corextent>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <parxtent@plt>
  add    $0x8,%rsp
  shl    $0x4,%rax
  ret
```

assistant: ```c
unsigned long int corextent(void) {
  unsigned long l;
  l = parxtent();
  return l << 4;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_ident_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L14
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L14:
  movl   $0x0,-0x4(%rbp)
  nop
L16:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_ident_digit(int c) {
  int result;
  switch (c) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    result = 1;
    break;
  default:
    result = 0;
    break;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_ident_digit>:
  endbr64
  sub    $0x30,%edi
  cmp    $0x9,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_ident_digit(int c) {
  int result;
  switch (c) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    result = 1;
    break;
  default:
    result = 0;
    break;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_ident_digit>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  ret
```

assistant: ```c
int is_ident_digit(int c) {
  int result;
  switch (c) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    result = 1;
    break;
  default:
    result = 0;
    break;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_ident_digit>:
  endbr64
  sub    $0x30,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  ret
```

assistant: ```c
int is_ident_digit(int c) {
  int result;
  switch (c) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    result = 1;
    break;
  default:
    result = 0;
    break;
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L2
  cmpq   $0x0,-0x18(%rbp)
  je     L40
L2:
  mov    $0x1,%eax
  jmp    L50
L40:
  cmpl   $0x200,-0x24(%rbp)
  jle    L20
  movl   $0x1fe,-0x24(%rbp)
L20:
  mov    $0x428,%edi
  call   <SPI_Read@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x429,%edi
  call   <SPI_Read@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  cltq
  movzwl %ax,%eax
  add    %rdx,%rax
  mov    %eax,-0xc(%rbp)
  jmp    L42
L25:
  subl   $0x1,-0x24(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x7ff,%eax
  add    $0x6000,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <SPI_Read@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  addl   $0x1,-0xc(%rbp)
  addq   $0x8,-0x20(%rbp)
L42:
  cmpl   $0x0,-0x24(%rbp)
  jne    L25
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x428,%edi
  call   <SPI_Write@plt>
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x429,%edi
  call   <SPI_Write@plt>
  mov    $0x40,%esi
  mov    $0x401,%edi
  call   <SPI_Write@plt>
  mov    $0x5,%edi
  call   <delay_us@plt>
  mov    $0x1,%eax
L50:
  leave
  ret
```

assistant: ```c
uint16_t recv(uint8_t sock, uint8_t *buf, uint16_t buflen) {
  uint16_t ptr, offaddr, realaddr;
  if (buflen <= 0 || sock != 0)
    return 1;
  if (buflen > 512)
    buflen = 512 - 2;
  ptr = SPI_Read(0x0428);
  offaddr = (((ptr & 0x00FF) << 8) + SPI_Read(0x0428 + 1));
  while (buflen) {
    buflen--;
    realaddr = 0x6000 + (offaddr & 0x07FF);
    *buf = SPI_Read(realaddr);
    offaddr++;
    buf++;
  }
  *buf = '\0';
  SPI_Write(0x0428, (offaddr & 0xFF00) >> 8);
  SPI_Write(0x0428 + 1, (offaddr & 0x00FF));
  SPI_Write(0x0401, 0x40);
  delay_us(5);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<recv>:
  endbr64
  test   %edx,%edx
  jle    L18
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r14
  mov    %edx,%r12d
  test   %rdi,%rdi
  jne    L11
  cmp    $0x201,%edx
  mov    $0x1fe,%eax
  cmovge %eax,%r12d
  mov    $0x428,%edi
  call   <SPI_Read@plt>
  mov    %rax,%rbx
  mov    $0x429,%edi
  call   <SPI_Read@plt>
  shl    $0x8,%ebx
  and    $0xff00,%ebx
  lea    (%rax,%rbx,1),%r15
  lea    (%r12,%r15,1),%r13d
  mov    %r15d,%ebx
  mov    %r14,%rbp
L28:
  mov    %ebx,%edi
  and    $0x7ff,%edi
  add    $0x6000,%edi
  call   <SPI_Read@plt>
  mov    %rax,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %r13d,%ebx
  jne    L28
  lea    (%r12,%r15,1),%ebx
  mov    %r12d,%r12d
  movq   $0x0,(%r14,%r12,8)
  movzbl %bh,%esi
  mov    $0x428,%edi
  call   <SPI_Write@plt>
  movzbl %bl,%esi
  mov    $0x429,%edi
  call   <SPI_Write@plt>
  mov    $0x40,%esi
  mov    $0x401,%edi
  call   <SPI_Write@plt>
  mov    $0x5,%edi
  call   <delay_us@plt>
L11:
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
uint16_t recv(uint8_t sock, uint8_t *buf, uint16_t buflen) {
  uint16_t ptr, offaddr, realaddr;
  if (buflen <= 0 || sock != 0)
    return 1;
  if (buflen > 512)
    buflen = 512 - 2;
  ptr = SPI_Read(0x0428);
  offaddr = (((ptr & 0x00FF) << 8) + SPI_Read(0x0428 + 1));
  while (buflen) {
    buflen--;
    realaddr = 0x6000 + (offaddr & 0x07FF);
    *buf = SPI_Read(realaddr);
    offaddr++;
    buf++;
  }
  *buf = '\0';
  SPI_Write(0x0428, (offaddr & 0xFF00) >> 8);
  SPI_Write(0x0428 + 1, (offaddr & 0x00FF));
  SPI_Write(0x0401, 0x40);
  delay_us(5);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<recv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ebp,%ebp
  jle    L2
  test   %rdi,%rdi
  jne    L2
  cmp    $0x201,%ebp
  mov    $0x1fe,%eax
  mov    $0x428,%edi
  mov    %rsi,%r13
  cmovge %rax,%rbp
  mov    %r13,%r15
  call   <SPI_Read@plt>
  mov    $0x429,%edi
  mov    %rax,%rbx
  call   <SPI_Read@plt>
  shl    $0x8,%ebx
  and    $0xff00,%ebx
  lea    (%rax,%rbx,1),%r14
  lea    0x0(%rbp,%r14,1),%r12d
  mov    %r14d,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%edi
  add    $0x1,%ebx
  add    $0x8,%r15
  and    $0x7ff,%edi
  add    $0x6000,%edi
  call   <SPI_Read@plt>
  mov    %rax,-0x8(%r15)
  cmp    %r12d,%ebx
  jne    L12
  movq   $0x0,0x0(%r13,%rbp,8)
  lea    0x0(%rbp,%r14,1),%ebx
  mov    $0x428,%edi
  movzbl %bh,%esi
  call   <SPI_Write@plt>
  movzbl %bl,%esi
  mov    $0x429,%edi
  call   <SPI_Write@plt>
  mov    $0x401,%edi
  mov    $0x40,%esi
  call   <SPI_Write@plt>
  mov    $0x5,%edi
  call   <delay_us@plt>
L2:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint16_t recv(uint8_t sock, uint8_t *buf, uint16_t buflen) {
  uint16_t ptr, offaddr, realaddr;
  if (buflen <= 0 || sock != 0)
    return 1;
  if (buflen > 512)
    buflen = 512 - 2;
  ptr = SPI_Read(0x0428);
  offaddr = (((ptr & 0x00FF) << 8) + SPI_Read(0x0428 + 1));
  while (buflen) {
    buflen--;
    realaddr = 0x6000 + (offaddr & 0x07FF);
    *buf = SPI_Read(realaddr);
    offaddr++;
    buf++;
  }
  *buf = '\0';
  SPI_Write(0x0428, (offaddr & 0xFF00) >> 8);
  SPI_Write(0x0428 + 1, (offaddr & 0x00FF));
  SPI_Write(0x0401, 0x40);
  delay_us(5);
  return 1;
}
```