ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<closetty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void closetty(int fd) {
  close(fd);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<closetty>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void closetty(int fd) {
  close(fd);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<closetty>:
  endbr64
  jmp    1050 <close@plt>
```

assistant: ```c
void closetty(int fd) {
  close(fd);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<closetty>:
  endbr64
  jmp    1050 <close@plt>
```

assistant: ```c
void closetty(int fd) {
  close(fd);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lerrif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %rdi,-0x818(%rbp)
  mov    %esi,-0x81c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x81c(%rbp),%edx
  mov    -0x818(%rbp),%rcx
  lea    -0x810(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <flexerror@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void lerrif(const char *msg, int arg) {
  char errmsg[2048];
  (void)sprintf(errmsg, msg, arg);
  flexerror(errmsg);
}
```
user: What is the c source code of the assembly code below?

```asm
<lerrif>:
  endbr64
  push   %rbx
  sub    $0x810,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <flexerror@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x810,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void lerrif(const char *msg, int arg) {
  char errmsg[2048];
  (void)sprintf(errmsg, msg, arg);
  flexerror(errmsg);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lerrif>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <flexerror@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x810,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void lerrif(const char *msg, int arg) {
  char errmsg[2048];
  (void)sprintf(errmsg, msg, arg);
  flexerror(errmsg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lerrif>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <flexerror@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x810,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void lerrif(const char *msg, int arg) {
  char errmsg[2048];
  (void)sprintf(errmsg, msg, arg);
  flexerror(errmsg);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xfffffffe,-0x4(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: Hello CLLL


assistant: ```c
int main(int argc, char *argv[]) {
  int x = -2;
  printf("Hello CLLL\n");
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffffe,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string

tool: D8: Hello CLLL


assistant: ```c
int main(int argc, char *argv[]) {
  int x = -2;
  printf("Hello CLLL\n");
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffffe,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: Hello CLLL


assistant: ```c
int main(int argc, char *argv[]) {
  int x = -2;
  printf("Hello CLLL\n");
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffffe,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Hello CLLL


assistant: ```c
int main(int argc, char *argv[]) {
  int x = -2;
  printf("Hello CLLL\n");
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_types>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  xorl   $0x10203040,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L10
L3:
  mov    -0x24(%rbp),%eax
  mov    %al,-0x1a(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %ax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %ax,-0x16(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  movzbl -0x1a(%rbp),%edx
  movsbl -0x19(%rbp),%eax
  add    %eax,%edx
  movzwl -0x18(%rbp),%eax
  add    %eax,%edx
  movswl -0x16(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  addl   $0x1,-0x14(%rbp)
L10:
  cmpl   $0x9,-0x14(%rbp)
  jle    L3
  mov    -0x24(%rbp),%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
signed long test_types(int i) {
  unsigned char uc;
  signed char sc;
  unsigned short us;
  signed short ss;
  unsigned long ul;
  signed long sl;
  int j;
  i ^= 0x10203040;
  for (j = 0; j < 10; j++) {
    uc = i;
    sc = i;
    us = i;
    ss = i;
    ul = i;
    sl = i;
    i = uc + sc + us + ss + ul + sl;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_types>:
  endbr64
  xor    $0x10203040,%edi
  mov    $0xa,%eax
L3:
  movzbl %dil,%edx
  movsbl %dil,%ecx
  add    %ecx,%edx
  movzwl %di,%ecx
  add    %ecx,%edx
  movswl %di,%ecx
  add    %ecx,%edx
  lea    (%rdx,%rdi,2),%edi
  sub    $0x1,%eax
  jne    L3
  movslq %edi,%rax
  ret
```

assistant: ```c
signed long test_types(int i) {
  unsigned char uc;
  signed char sc;
  unsigned short us;
  signed short ss;
  unsigned long ul;
  signed long sl;
  int j;
  i ^= 0x10203040;
  for (j = 0; j < 10; j++) {
    uc = i;
    sc = i;
    us = i;
    ss = i;
    ul = i;
    sl = i;
    i = uc + sc + us + ss + ul + sl;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_types>:
  endbr64
  xor    $0x10203040,%edi
  mov    $0xa,%eax
  nop
L6:
  movsbl %dil,%ecx
  movzbl %dil,%edx
  add    %ecx,%edx
  movzwl %di,%ecx
  add    %ecx,%edx
  movswl %di,%ecx
  add    %ecx,%edx
  lea    (%rdx,%rdi,2),%edi
  sub    $0x1,%eax
  jne    L6
  movslq %edi,%rax
  ret
```

assistant: ```c
signed long test_types(int i) {
  unsigned char uc;
  signed char sc;
  unsigned short us;
  signed short ss;
  unsigned long ul;
  signed long sl;
  int j;
  i ^= 0x10203040;
  for (j = 0; j < 10; j++) {
    uc = i;
    sc = i;
    us = i;
    ss = i;
    ul = i;
    sl = i;
    i = uc + sc + us + ss + ul + sl;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_types>:
  endbr64
  xor    $0x10203040,%edi
  movsbl %dil,%edx
  movzbl %dil,%eax
  add    %edx,%eax
  movzwl %di,%edx
  add    %edx,%eax
  movswl %di,%edx
  add    %edx,%eax
  lea    (%rax,%rdi,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%edx
  movsbl %dl,%ecx
  movzbl %dl,%eax
  add    %ecx,%eax
  movzwl %dx,%ecx
  add    %ecx,%eax
  movswl %dx,%ecx
  add    %ecx,%eax
  lea    (%rax,%rdx,2),%eax
  cltq
  ret
```

assistant: ```c
signed long test_types(int i) {
  unsigned char uc;
  signed char sc;
  unsigned short us;
  signed short ss;
  unsigned long ul;
  signed long sl;
  int j;
  i ^= 0x10203040;
  for (j = 0; j < 10; j++) {
    uc = i;
    sc = i;
    us = i;
    ss = i;
    ul = i;
    sl = i;
    i = uc + sc + us + ss + ul + sl;
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<quadBez>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  movss  %xmm1,-0x10(%rbp)
  movss  %xmm2,-0x14(%rbp)
  movss  %xmm3,-0x18(%rbp)
  movss  %xmm4,-0x1c(%rbp)
  movss  %xmm5,-0x20(%rbp)
  movss  -0x20(%rbp),%xmm4
  movss  -0x1c(%rbp),%xmm3
  movss  -0x18(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  movaps %xmm4,%xmm5
  movaps %xmm3,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <quadBezRec@plt>
  movss  -0x20(%rbp),%xmm0
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <svgPathPoint@plt>
  nop
  leave
  ret
```

assistant: ```c
void quadBez(struct SVGParser *p, float x1, float y1, float cx, float cy, float x2, float y2) {
  quadBezRec(p, x1, y1, cx, cy, x2, y2, 0);
  svgPathPoint(p, x2, y2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quadBez>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%esi
  movss  %xmm5,0xc(%rsp)
  movss  %xmm4,0x8(%rsp)
  call   <quadBezRec@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <svgPathPoint@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void quadBez(struct SVGParser *p, float x1, float y1, float cx, float cy, float x2, float y2) {
  quadBezRec(p, x1, y1, cx, cy, x2, y2, 0);
  svgPathPoint(p, x2, y2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quadBez>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  movss  %xmm5,0xc(%rsp)
  movss  %xmm4,0x8(%rsp)
  call   <quadBezRec@plt>
  movss  0xc(%rsp),%xmm5
  movss  0x8(%rsp),%xmm4
  add    $0x10,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  movaps %xmm5,%xmm1
  movaps %xmm4,%xmm0
  jmp    1070 <svgPathPoint@plt>
```

assistant: ```c
void quadBez(struct SVGParser *p, float x1, float y1, float cx, float cy, float x2, float y2) {
  quadBezRec(p, x1, y1, cx, cy, x2, y2, 0);
  svgPathPoint(p, x2, y2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quadBez>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  movss  %xmm5,0xc(%rsp)
  movss  %xmm4,0x8(%rsp)
  call   <quadBezRec@plt>
  movss  0xc(%rsp),%xmm5
  movss  0x8(%rsp),%xmm4
  add    $0x10,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  movaps %xmm5,%xmm1
  movaps %xmm4,%xmm0
  jmp    1070 <svgPathPoint@plt>
```

assistant: ```c
void quadBez(struct SVGParser *p, float x1, float y1, float cx, float cy, float x2, float y2) {
  quadBezRec(p, x1, y1, cx, cy, x2, y2, 0);
  svgPathPoint(p, x2, y2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_isalpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L34
  cmpl   $0x7a,-0x4(%rbp)
  jle    L14
L34:
  cmpl   $0x40,-0x4(%rbp)
  jle    L40
  cmpl   $0x5a,-0x4(%rbp)
  jg     L40
L14:
  mov    $0x1,%eax
  jmp    L49
L40:
  mov    $0x0,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int _isalpha(int c) {
  if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
    return (1);
  else
    return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_isalpha>:
  endbr64
  and    $0xffffffdf,%edi
  sub    $0x41,%edi
  cmp    $0x19,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int _isalpha(int c) {
  if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
    return (1);
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_isalpha>:
  endbr64
  and    $0xffffffdf,%edi
  xor    %eax,%eax
  sub    $0x41,%edi
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int _isalpha(int c) {
  if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
    return (1);
  else
    return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_isalpha>:
  endbr64
  and    $0xffffffdf,%edi
  xor    %eax,%eax
  sub    $0x41,%edi
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int _isalpha(int c) {
  if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
    return (1);
  else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L13
L8:
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L13:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L8
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: %d %d %d

assistant: ```c
void dump(int n) {
  int a, b, c;
  while (n--)
    scanf("%d %d %d", &a, &b, &c);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dump>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L25
  mov    %edi,%ebx
  lea    D4(%rip),%rbp
L22:
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  sub    $0x1,%ebx
  jne    L22
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string

tool: D4: %d %d %d

assistant: ```c
void dump(int n) {
  int a, b, c;
  while (n--)
    scanf("%d %d %d", &a, &b, &c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L12
  mov    %edi,%ebx
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D3(%rip),%rbp
  nopl   0x0(%rax)
L18:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  sub    $0x1,%ebx
  jne    L18
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: %d %d %d

assistant: ```c
void dump(int n) {
  int a, b, c;
  while (n--)
    scanf("%d %d %d", &a, &b, &c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dump>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L6
  mov    %edi,%ebx
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D6(%rip),%rbp
  nopl   0x0(%rax)
L16:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  sub    $0x1,%ebx
  jne    L16
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6: %d %d %d

assistant: ```c
void dump(int n) {
  int a, b, c;
  while (n--)
    scanf("%d %d %d", &a, &b, &c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strerror_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L17
  cmpq   $0x0,-0x28(%rbp)
  je     L1
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L1:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  jmp    L28
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L28:
  leave
  ret
```

assistant: ```c
int strerror_r(int err, char *buf, size_t buflen) {
  char *msg = strerror(err);
  size_t l = strlen(msg);
  if (l >= buflen) {
    if (buflen) {
      memcpy(buf, msg, buflen - 1);
      buf[buflen - 1] = 0;
    }
    return ERANGE;
  }
  memcpy(buf, msg, l + 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strerror_r>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbx
  call   <strerror@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jb     L10
  test   %rbx,%rbx
  jne    L7
L26:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  jmp    L26
L10:
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  jmp    L23
```

assistant: ```c
int strerror_r(int err, char *buf, size_t buflen) {
  char *msg = strerror(err);
  size_t l = strlen(msg);
  if (l >= buflen) {
    if (buflen) {
      memcpy(buf, msg, buflen - 1);
      buf[buflen - 1] = 0;
    }
    return ERANGE;
  }
  memcpy(buf, msg, l + 1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strerror_r>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <strerror@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    %rbx,%rax
  jb     L22
  test   %rbx,%rbx
  jne    L1
L17:
  mov    D4(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <memcpy@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  lea    -0x1(%rbx),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  jmp    L17
```

assistant: ```c
int strerror_r(int err, char *buf, size_t buflen) {
  char *msg = strerror(err);
  size_t l = strlen(msg);
  if (l >= buflen) {
    if (buflen) {
      memcpy(buf, msg, buflen - 1);
      buf[buflen - 1] = 0;
    }
    return ERANGE;
  }
  memcpy(buf, msg, l + 1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strerror_r>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <strerror@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    %rbx,%rax
  jb     L22
  test   %rbx,%rbx
  jne    L10
L21:
  mov    D1(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <memcpy@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    -0x1(%rbx),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  jmp    L21
```

assistant: ```c
int strerror_r(int err, char *buf, size_t buflen) {
  char *msg = strerror(err);
  size_t l = strlen(msg);
  if (l >= buflen) {
    if (buflen) {
      memcpy(buf, msg, buflen - 1);
      buf[buflen - 1] = 0;
    }
    return ERANGE;
  }
  memcpy(buf, msg, l + 1);
  return 0;
}
```