ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<test_major_second>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D92(%rip),%rax
  mov    %rax,-0x80(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,-0x78(%rbp)
  lea    D63(%rip),%rax
  mov    %rax,-0x70(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,-0x68(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,-0x60(%rbp)
  lea    D66(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D81(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D99(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D108(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D103(%rip),%rax
  mov    %rax,%rdi
  call   <start_test@plt>
  movl   $0x0,-0x84(%rbp)
  jmp    L22
L13:
  mov    -0x84(%rbp),%eax
  cltq
  mov    -0x80(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <str_to_note@plt>
  mov    %eax,%ebx
  mov    -0x84(%rbp),%eax
  cltq
  mov    -0x80(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <str_to_note@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <diatonic_interval@plt>
  mov    %eax,%edx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <note_to_str@plt>
  mov    -0x84(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,8),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x84(%rbp)
L22:
  cmpl   $0x4,-0x84(%rbp)
  jle    L13
  mov    $0x0,%eax
  call   <end_test@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D92
type: string
name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D63
type: string
name: disassemble_data
arguments: label: D29
type: string
name: disassemble_data
arguments: label: D30
type: string
name: disassemble_data
arguments: label: D66
type: string
name: disassemble_data
arguments: label: D81
type: string
name: disassemble_data
arguments: label: D99
type: string
name: disassemble_data
arguments: label: D108
type: string
name: disassemble_data
arguments: label: D103
type: string

tool: D92: C

tool: D25: E

tool: D63: F

tool: D29: G

tool: D30: A#

tool: D66: D

tool: D81: F#

tool: D99: A

tool: D108: B#

tool: D103: major_second

assistant: ```c
void test_major_second() {
  char result[12];
  char *notes[] = {"C", "E", "F", "G", "A#"};
  char *answers[] = {"D", "F#", "G", "A", "B#"};
  int i;
  start_test("major_second");
  for (i = 0; i < 5; i++) {
    note_to_str(((diatonic_interval((str_to_note(notes[i])), (str_to_note(notes[i])), 1))), result);
    assert(strcmp(result, answers[i]) == 0);
  }
  end_test();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_major_second>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D65(%rip),%rax
  mov    %rax,(%rsp)
  lea    D66(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D54(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D37(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D38(%rip),%rcx
  mov    %rcx,0x20(%rsp)
  lea    D42(%rip),%rcx
  mov    %rcx,0x30(%rsp)
  lea    D39(%rip),%rcx
  mov    %rcx,0x38(%rsp)
  mov    %rax,0x40(%rsp)
  lea    D89(%rip),%rax
  mov    %rax,0x48(%rsp)
  lea    D92(%rip),%rax
  mov    %rax,0x50(%rsp)
  lea    D53(%rip),%rdi
  call   <start_test@plt>
  mov    $0x0,%ebx
  lea    0x5c(%rsp),%rbp
L11:
  mov    (%rsp,%rbx,1),%r13
  mov    %r13,%rdi
  call   <str_to_note@plt>
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <str_to_note@plt>
  mov    %eax,%edi
  mov    $0x1,%edx
  mov    %r12d,%esi
  call   <diatonic_interval@plt>
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <note_to_str@plt>
  mov    0x30(%rsp,%rbx,1),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rbx
  cmp    $0x28,%rbx
  jne    L11
  mov    $0x0,%eax
  call   <end_test@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D65
datatype: string
name: parse_data
arguments: label: D66
datatype: string
name: parse_data
arguments: label: D54
datatype: string
name: parse_data
arguments: label: D37
datatype: string
name: parse_data
arguments: label: D38
datatype: string
name: parse_data
arguments: label: D42
datatype: string
name: parse_data
arguments: label: D39
datatype: string
name: parse_data
arguments: label: D89
datatype: string
name: parse_data
arguments: label: D92
datatype: string
name: parse_data
arguments: label: D53
datatype: string

tool: D65: C

tool: D66: E

tool: D54: F

tool: D37: G

tool: D38: A#

tool: D42: D

tool: D39: F#

tool: D89: A

tool: D92: B#

tool: D53: major_second

assistant: ```c
void test_major_second() {
  char result[12];
  char *notes[] = {"C", "E", "F", "G", "A#"};
  char *answers[] = {"D", "F#", "G", "A", "B#"};
  int i;
  start_test("major_second");
  for (i = 0; i < 5; i++) {
    note_to_str(((diatonic_interval((str_to_note(notes[i])), (str_to_note(notes[i])), 1))), result);
    assert(strcmp(result, answers[i]) == 0);
  }
  end_test();
}
```
user: What is the c source code of the assembly code below?

```asm
<test_major_second>:
  endbr64
  push   %r14
  lea    D61(%rip),%rcx
  lea    D82(%rip),%rdi
  push   %r13
  lea    D52(%rip),%r14
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  lea    D41(%rip),%rax
  mov    %rcx,0x20(%rsp)
  lea    0x5c(%rsp),%rbp
  lea    D91(%rip),%rcx
  mov    %rcx,0x30(%rsp)
  lea    D35(%rip),%rcx
  lea    0x30(%rsp),%r12
  mov    %rcx,0x38(%rsp)
  mov    %rax,0x8(%rsp)
  lea    D65(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D51(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    %rax,0x40(%rsp)
  lea    D57(%rip),%rax
  mov    %rax,0x48(%rsp)
  lea    D88(%rip),%rax
  mov    %rax,0x50(%rsp)
  call   <start_test@plt>
L25:
  mov    %r14,%rdi
  call   <str_to_note@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <str_to_note@plt>
  mov    $0x1,%edx
  mov    %r13d,%esi
  mov    %eax,%edi
  call   <diatonic_interval@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <note_to_str@plt>
  mov    (%r12,%rbx,1),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  add    $0x8,%rbx
  call   <assert@plt>
  cmp    $0x28,%rbx
  je     L24
  mov    (%rsp,%rbx,1),%r14
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  call   <end_test@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D61
type_infered: string
name: disassemble_data
arguments: data_tag: D82
type_infered: string
name: disassemble_data
arguments: data_tag: D52
type_infered: string
name: disassemble_data
arguments: data_tag: D41
type_infered: string
name: disassemble_data
arguments: data_tag: D91
type_infered: string
name: disassemble_data
arguments: data_tag: D35
type_infered: string
name: disassemble_data
arguments: data_tag: D65
type_infered: string
name: disassemble_data
arguments: data_tag: D51
type_infered: string
name: disassemble_data
arguments: data_tag: D57
type_infered: string
name: disassemble_data
arguments: data_tag: D88
type_infered: string

tool: D61: A#

tool: D82: major_second

tool: D52: C

tool: D41: E

tool: D91: D

tool: D35: F#

tool: D65: F

tool: D51: G

tool: D57: A

tool: D88: B#

assistant: ```c
void test_major_second() {
  char result[12];
  char *notes[] = {"C", "E", "F", "G", "A#"};
  char *answers[] = {"D", "F#", "G", "A", "B#"};
  int i;
  start_test("major_second");
  for (i = 0; i < 5; i++) {
    note_to_str(((diatonic_interval((str_to_note(notes[i])), (str_to_note(notes[i])), 1))), result);
    assert(strcmp(result, answers[i]) == 0);
  }
  end_test();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_major_second>:
  endbr64
  push   %r15
  lea    D10(%rip),%rcx
  lea    D60(%rip),%rdi
  push   %r14
  movq   %rcx,%xmm1
  lea    D79(%rip),%rcx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  lea    D81(%rip),%rax
  mov    %rsp,%r13
  lea    0x5c(%rsp),%rbp
  lea    0x30(%rsp),%r12
  movq   %rax,%xmm0
  lea    D90(%rip),%rax
  movq   %rax,%xmm2
  lea    D72(%rip),%rax
  punpcklqdq %xmm2,%xmm1
  movaps %xmm1,(%rsp)
  movq   %rax,%xmm1
  lea    D87(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D73(%rip),%rax
  punpcklqdq %xmm0,%xmm1
  movq   %rax,%xmm3
  lea    D50(%rip),%rax
  movaps %xmm1,0x10(%rsp)
  movq   %rcx,%xmm1
  movq   %rax,%xmm4
  punpcklqdq %xmm3,%xmm1
  lea    D83(%rip),%rax
  punpcklqdq %xmm4,%xmm0
  mov    %rax,0x50(%rsp)
  movaps %xmm1,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <start_test@plt>
L11:
  mov    0x0(%r13,%rbx,1),%r15
  mov    %r15,%rdi
  call   <str_to_note@plt>
  mov    %r15,%rdi
  mov    %eax,%r14d
  call   <str_to_note@plt>
  mov    $0x1,%edx
  mov    %r14d,%esi
  mov    %eax,%edi
  call   <diatonic_interval@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <note_to_str@plt>
  mov    (%r12,%rbx,1),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  add    $0x8,%rbx
  call   <assert@plt>
  cmp    $0x28,%rbx
  jne    L11
  xor    %eax,%eax
  call   <end_test@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_infered: string
name: disassemble_data
arguments: label: D60
type_infered: string
name: disassemble_data
arguments: label: D79
type_infered: string
name: disassemble_data
arguments: label: D81
type_infered: string
name: disassemble_data
arguments: label: D90
type_infered: string
name: disassemble_data
arguments: label: D72
type_infered: string
name: disassemble_data
arguments: label: D87
type_infered: string
name: disassemble_data
arguments: label: D73
type_infered: string
name: disassemble_data
arguments: label: D50
type_infered: string
name: disassemble_data
arguments: label: D83
type_infered: string

tool: D10: C

tool: D60: major_second

tool: D79: D

tool: D81: G

tool: D90: E

tool: D72: F

tool: D87: A#

tool: D73: F#

tool: D50: A

tool: D83: B#

assistant: ```c
void test_major_second() {
  char result[12];
  char *notes[] = {"C", "E", "F", "G", "A#"};
  char *answers[] = {"D", "F#", "G", "A", "B#"};
  int i;
  start_test("major_second");
  for (i = 0; i < 5; i++) {
    note_to_str(((diatonic_interval((str_to_note(notes[i])), (str_to_note(notes[i])), 1))), result);
    assert(strcmp(result, answers[i]) == 0);
  }
  end_test();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_getWorkGroupThreadId>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L27:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L17:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L17
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L27
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int _getWorkGroupThreadId(unsigned int numDimensions, unsigned int *localSizes, unsigned int *localIds) {
  unsigned int threadId = 0;
  for (unsigned int dim = 0; dim < numDimensions; ++dim) {
    unsigned int dimId = localIds[dim];
    for (unsigned int dim2 = dim + 1; dim2 < numDimensions; ++dim2) {
      dimId *= localSizes[dim2];
    }
    threadId += dimId;
  }
  return threadId;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_getWorkGroupThreadId>:
  endbr64
  test   %edi,%edi
  je     L7
  push   %rbx
  lea    0x4(%rsi),%r8
  lea    -0x1(%rdi),%ebx
  mov    %edi,%r11d
  mov    $0x1,%edi
  mov    $0x0,%r9d
  mov    %r8,%r10
L21:
  mov    -0x4(%rdx,%rdi,4),%ecx
  cmp    %r11,%rdi
  je     L16
  mov    %ebx,%eax
  sub    %edi,%eax
  add    %rdi,%rax
  lea    (%r10,%rax,4),%rsi
  mov    %r8,%rax
L36:
  imul   (%rax),%ecx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L36
  add    %ecx,%r9d
  add    $0x4,%r8
  add    $0x1,%rdi
  jmp    L21
L7:
  mov    %edi,%eax
  ret
L16:
  lea    (%rcx,%r9,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int _getWorkGroupThreadId(unsigned int numDimensions, unsigned int *localSizes, unsigned int *localIds) {
  unsigned int threadId = 0;
  for (unsigned int dim = 0; dim < numDimensions; ++dim) {
    unsigned int dimId = localIds[dim];
    for (unsigned int dim2 = dim + 1; dim2 < numDimensions; ++dim2) {
      dimId *= localSizes[dim2];
    }
    threadId += dimId;
  }
  return threadId;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_getWorkGroupThreadId>:
  endbr64
  test   %edi,%edi
  je     L9
  push   %rbx
  lea    0x4(%rsi),%r11
  lea    -0x1(%rdi),%ebx
  mov    %edi,%r10d
  mov    $0x1,%edi
  mov    %r11,%r8
  xor    %r9d,%r9d
  mov    -0x4(%rdx,%rdi,4),%ecx
  cmp    %r10,%rdi
  je     L13
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%eax
  sub    %edi,%eax
  add    %rdi,%rax
  lea    (%r11,%rax,4),%rsi
  mov    %r8,%rax
  xchg   %ax,%ax
L33:
  imul   (%rax),%ecx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L33
  add    $0x1,%rdi
  add    %ecx,%r9d
  add    $0x4,%r8
  mov    -0x4(%rdx,%rdi,4),%ecx
  cmp    %r10,%rdi
  jne    L8
L13:
  lea    (%rcx,%r9,1),%eax
  pop    %rbx
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int _getWorkGroupThreadId(unsigned int numDimensions, unsigned int *localSizes, unsigned int *localIds) {
  unsigned int threadId = 0;
  for (unsigned int dim = 0; dim < numDimensions; ++dim) {
    unsigned int dimId = localIds[dim];
    for (unsigned int dim2 = dim + 1; dim2 < numDimensions; ++dim2) {
      dimId *= localSizes[dim2];
    }
    threadId += dimId;
  }
  return threadId;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_getWorkGroupThreadId>:
  endbr64
  test   %edi,%edi
  je     L11
  mov    (%rdx),%ecx
  cmp    $0x1,%edi
  je     L21
  mov    %edi,%r11d
  mov    $0x1,%r9d
  xor    %r10d,%r10d
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r9d,%eax
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %eax,%r8d
  add    $0x1,%eax
  imul   (%rsi,%r8,4),%ecx
  cmp    %eax,%edi
  ja     L23
  add    %ecx,%r10d
  mov    (%rdx,%r9,4),%ecx
  add    $0x1,%r9
  cmp    %r11,%r9
  jne    L34
L46:
  lea    (%r10,%rcx,1),%eax
  ret
L11:
  xor    %eax,%eax
  ret
L21:
  xor    %r10d,%r10d
  jmp    L46
```

assistant: ```c
unsigned int _getWorkGroupThreadId(unsigned int numDimensions, unsigned int *localSizes, unsigned int *localIds) {
  unsigned int threadId = 0;
  for (unsigned int dim = 0; dim < numDimensions; ++dim) {
    unsigned int dimId = localIds[dim];
    for (unsigned int dim2 = dim + 1; dim2 < numDimensions; ++dim2) {
      dimId *= localSizes[dim2];
    }
    threadId += dimId;
  }
  return threadId;
}
```
user: What is the c source code of the assembly code below:

```asm
<bmhtable_build>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0xff,-0x4(%rbp)
  jle    L27
  subq   $0x1,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%rdx
  sub    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L0
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bmhtable_build(unsigned char *pattern, size_t patlen, size_t *bmhtable) {
  int k;
  for (k = 0; k < 256; k++)
    bmhtable[k] = patlen;
  patlen--;
  for (k = 0; k < patlen; k++)
    bmhtable[pattern[k]] = (patlen - k);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bmhtable_build>:
  endbr64
  mov    %rdx,%rax
  lea    0x800(%rdx),%rcx
L28:
  mov    %rsi,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L28
  cmp    $0x1,%rsi
  je     L24
  mov    %rdi,%rax
  lea    -0x1(%rdi,%rsi,1),%rcx
L6:
  movzbl (%rax),%esi
  mov    %rcx,%rdi
  sub    %rax,%rdi
  mov    %rdi,(%rdx,%rsi,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
L24:
  ret
```

assistant: ```c
void bmhtable_build(unsigned char *pattern, size_t patlen, size_t *bmhtable) {
  int k;
  for (k = 0; k < 256; k++)
    bmhtable[k] = patlen;
  patlen--;
  for (k = 0; k < patlen; k++)
    bmhtable[pattern[k]] = (patlen - k);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bmhtable_build>:
  endbr64
  mov    %rdx,%rax
  lea    0x800(%rdx),%rcx
  xchg   %ax,%ax
L25:
  mov    %rsi,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L25
  cmp    $0x1,%rsi
  je     L5
  lea    -0x1(%rdi,%rsi,1),%rax
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl (%rdi),%ecx
  mov    %rax,%rsi
  sub    %rdi,%rsi
  add    $0x1,%rdi
  mov    %rsi,(%rdx,%rcx,8)
  cmp    %rax,%rdi
  jne    L18
L5:
  ret
```

assistant: ```c
void bmhtable_build(unsigned char *pattern, size_t patlen, size_t *bmhtable) {
  int k;
  for (k = 0; k < 256; k++)
    bmhtable[k] = patlen;
  patlen--;
  for (k = 0; k < patlen; k++)
    bmhtable[pattern[k]] = (patlen - k);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bmhtable_build>:
  endbr64
  movq   %rsi,%xmm0
  mov    %rdx,%rax
  lea    0x800(%rdx),%rcx
  punpcklqdq %xmm0,%xmm0
  nopw   0x0(%rax,%rax,1)
L27:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L27
  cmp    $0x1,%rsi
  je     L20
  lea    -0x1(%rdi,%rsi,1),%rax
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl (%rdi),%ecx
  mov    %rax,%rsi
  sub    %rdi,%rsi
  add    $0x1,%rdi
  mov    %rsi,(%rdx,%rcx,8)
  cmp    %rdi,%rax
  jne    L16
L20:
  ret
```

assistant: ```c
void bmhtable_build(unsigned char *pattern, size_t patlen, size_t *bmhtable) {
  int k;
  for (k = 0; k < 256; k++)
    bmhtable[k] = patlen;
  patlen--;
  for (k = 0; k < patlen; k++)
    bmhtable[pattern[k]] = (patlen - k);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<update_pepxml_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jg     L7
  mov    $0x0,%eax
  jmp    L3
L7:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x2c(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rdi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
L3:
  leave
  ret
```

assistant: ```c
int update_pepxml_buffer(char *buffer, char *bufpos, FILE *file_handle, int buffersize) {
  int residu, read;
  residu = strlen(bufpos);
  if (residu <= 0)
    return 0;
  memmove(buffer, bufpos, residu);
  read = fread(buffer + residu, sizeof(char), buffersize - (residu + 1), file_handle);
  buffer[residu + read + 1] = '\0';
  bufpos = buffer;
  return read;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<update_pepxml_buffer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  test   %ebx,%ebx
  jle    L4
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  lea    0x1(%rbx),%eax
  mov    %r12d,%edx
  sub    %eax,%edx
  movslq %ebx,%rdi
  add    %rbp,%rdi
  mov    %r13,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  add    %eax,%ebx
  movslq %ebx,%rbx
  movb   $0x0,0x1(%rbp,%rbx,1)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int update_pepxml_buffer(char *buffer, char *bufpos, FILE *file_handle, int buffersize) {
  int residu, read;
  residu = strlen(bufpos);
  if (residu <= 0)
    return 0;
  memmove(buffer, bufpos, residu);
  read = fread(buffer + residu, sizeof(char), buffersize - (residu + 1), file_handle);
  buffer[residu + read + 1] = '\0';
  bufpos = buffer;
  return read;
}
```
user: Translate the below assembly code into C programming language:

```asm
<update_pepxml_buffer>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  test   %ebx,%ebx
  jle    L3
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  lea    0x1(%rbx),%eax
  movslq %ebx,%rdi
  mov    %r12d,%edx
  sub    %eax,%edx
  add    %rbp,%rdi
  mov    %r14,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  add    %eax,%ebx
  movslq %ebx,%rbx
  movb   $0x0,0x1(%rbp,%rbx,1)
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int update_pepxml_buffer(char *buffer, char *bufpos, FILE *file_handle, int buffersize) {
  int residu, read;
  residu = strlen(bufpos);
  if (residu <= 0)
    return 0;
  memmove(buffer, bufpos, residu);
  read = fread(buffer + residu, sizeof(char), buffersize - (residu + 1), file_handle);
  buffer[residu + read + 1] = '\0';
  bufpos = buffer;
  return read;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<update_pepxml_buffer>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  test   %ebx,%ebx
  jle    L7
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  lea    0x1(%rbx),%eax
  movslq %ebx,%rdi
  mov    %r12d,%edx
  sub    %eax,%edx
  add    %rbp,%rdi
  mov    %r14,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  add    %eax,%ebx
  movslq %ebx,%rbx
  movb   $0x0,0x1(%rbp,%rbx,1)
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int update_pepxml_buffer(char *buffer, char *bufpos, FILE *file_handle, int buffersize) {
  int residu, read;
  residu = strlen(bufpos);
  if (residu <= 0)
    return 0;
  memmove(buffer, bufpos, residu);
  read = fread(buffer + residu, sizeof(char), buffersize - (residu + 1), file_handle);
  buffer[residu + read + 1] = '\0';
  bufpos = buffer;
  return read;
}
```