ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L34:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %r13,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <kbhit@plt>
  test   %rax,%rax
  jne    L12
  lea    0x1(%rbp),%r12d
  cmp    $0x4f,%ebp
  je     L34
  xor    %ebx,%ebx
  nop
L26:
  mov    $0x20,%edi
  call   <putch@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L26
  mov    %r12d,%ebp
  jmp    L35
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <getch@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: -

assistant: ```c
main() {
  int i, j;
  for (;;) {
    for (i = 0; i < 80; i++) {
      for (j = 0; j < i; j++)
        putch(' ');
      puts("-");
      for (j = 0; j < 32000; j++)
        ;
      if (kbhit()) {
        getch();
        return;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L32:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r13,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <kbhit@plt>
  test   %rax,%rax
  jne    L8
  lea    0x1(%rbp),%r12d
  cmp    $0x4f,%ebp
  je     L32
  xor    %ebx,%ebx
  nop
L23:
  mov    $0x20,%edi
  call   <putch@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L23
  mov    %r12d,%ebp
  jmp    L3
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <getch@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: -

assistant: ```c
main() {
  int i, j;
  for (;;) {
    for (i = 0; i < 80; i++) {
      for (j = 0; j < i; j++)
        putch(' ');
      puts("-");
      for (j = 0; j < 32000; j++)
        ;
      if (kbhit()) {
        getch();
        return;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_samplerate_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x16770,-0x4(%rbp)
  jle    L8
  mov    $0x0,%eax
  jmp    L27
L8:
  cmpl   $0x1257b,-0x4(%rbp)
  jle    L11
  mov    $0x1,%eax
  jmp    L27
L11:
  cmpl   $0xd881,-0x4(%rbp)
  jle    L159
  mov    $0x2,%eax
  jmp    L27
L159:
  cmpl   $0xb3b8,-0x4(%rbp)
  jle    L147
  mov    $0x3,%eax
  jmp    L27
L147:
  cmpl   $0x92bd,-0x4(%rbp)
  jle    L121
  mov    $0x4,%eax
  jmp    L27
L121:
  cmpl   $0x6c40,-0x4(%rbp)
  jle    L148
  mov    $0x5,%eax
  jmp    L27
L148:
  cmpl   $0x59db,-0x4(%rbp)
  jle    L213
  mov    $0x6,%eax
  jmp    L27
L213:
  cmpl   $0x495e,-0x4(%rbp)
  jle    L36
  mov    $0x7,%eax
  jmp    L27
L36:
  cmpl   $0x361f,-0x4(%rbp)
  jle    L212
  mov    $0x8,%eax
  jmp    L27
L212:
  cmpl   $0x2ced,-0x4(%rbp)
  jle    L190
  mov    $0x9,%eax
  jmp    L27
L190:
  cmpl   $0x24ae,-0x4(%rbp)
  jle    L193
  mov    $0xa,%eax
  jmp    L27
L193:
  mov    $0xb,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int get_samplerate_index(int sample_rate) {
  if (92017 <= sample_rate)
    return 0;
  if (75132 <= sample_rate)
    return 1;
  if (55426 <= sample_rate)
    return 2;
  if (46009 <= sample_rate)
    return 3;
  if (37566 <= sample_rate)
    return 4;
  if (27713 <= sample_rate)
    return 5;
  if (23004 <= sample_rate)
    return 6;
  if (18783 <= sample_rate)
    return 7;
  if (13856 <= sample_rate)
    return 8;
  if (11502 <= sample_rate)
    return 9;
  if (9391 <= sample_rate)
    return 10;
  return 11;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_samplerate_index>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x16770,%edi
  jg     L95
  mov    $0x1,%eax
  cmp    $0x1257b,%edi
  jg     L95
  mov    $0x2,%eax
  cmp    $0xd881,%edi
  jg     L95
  mov    $0x3,%eax
  cmp    $0xb3b8,%edi
  jg     L95
  mov    $0x4,%eax
  cmp    $0x92bd,%edi
  jg     L95
  mov    $0x5,%eax
  cmp    $0x6c40,%edi
  jg     L95
  mov    $0x6,%eax
  cmp    $0x59db,%edi
  jg     L95
  mov    $0x7,%eax
  cmp    $0x495e,%edi
  jg     L95
  mov    $0x8,%eax
  cmp    $0x361f,%edi
  jg     L95
  mov    $0x9,%eax
  cmp    $0x2ced,%edi
  jg     L95
  cmp    $0x24af,%edi
  setl   %al
  movzbl %al,%eax
  add    $0xa,%eax
L95:
  ret
```

assistant: ```c
int get_samplerate_index(int sample_rate) {
  if (92017 <= sample_rate)
    return 0;
  if (75132 <= sample_rate)
    return 1;
  if (55426 <= sample_rate)
    return 2;
  if (46009 <= sample_rate)
    return 3;
  if (37566 <= sample_rate)
    return 4;
  if (27713 <= sample_rate)
    return 5;
  if (23004 <= sample_rate)
    return 6;
  if (18783 <= sample_rate)
    return 7;
  if (13856 <= sample_rate)
    return 8;
  if (11502 <= sample_rate)
    return 9;
  if (9391 <= sample_rate)
    return 10;
  return 11;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_samplerate_index>:
  endbr64
  xor    %eax,%eax
  cmp    $0x16770,%edi
  jg     L84
  mov    $0x1,%eax
  cmp    $0x1257b,%edi
  jg     L84
  mov    $0x2,%eax
  cmp    $0xd881,%edi
  jg     L84
  mov    $0x3,%eax
  cmp    $0xb3b8,%edi
  jg     L84
  mov    $0x4,%eax
  cmp    $0x92bd,%edi
  jg     L84
  mov    $0x5,%eax
  cmp    $0x6c40,%edi
  jg     L84
  mov    $0x6,%eax
  cmp    $0x59db,%edi
  jg     L84
  mov    $0x7,%eax
  cmp    $0x495e,%edi
  jg     L84
  mov    $0x8,%eax
  cmp    $0x361f,%edi
  jg     L84
  mov    $0x9,%eax
  cmp    $0x2ced,%edi
  jg     L84
  xor    %eax,%eax
  cmp    $0x24af,%edi
  setl   %al
  add    $0xa,%eax
L84:
  ret
```

assistant: ```c
int get_samplerate_index(int sample_rate) {
  if (92017 <= sample_rate)
    return 0;
  if (75132 <= sample_rate)
    return 1;
  if (55426 <= sample_rate)
    return 2;
  if (46009 <= sample_rate)
    return 3;
  if (37566 <= sample_rate)
    return 4;
  if (27713 <= sample_rate)
    return 5;
  if (23004 <= sample_rate)
    return 6;
  if (18783 <= sample_rate)
    return 7;
  if (13856 <= sample_rate)
    return 8;
  if (11502 <= sample_rate)
    return 9;
  if (9391 <= sample_rate)
    return 10;
  return 11;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_samplerate_index>:
  endbr64
  xor    %eax,%eax
  cmp    $0x16770,%edi
  jg     L41
  mov    $0x1,%eax
  cmp    $0x1257b,%edi
  jg     L41
  mov    $0x2,%eax
  cmp    $0xd881,%edi
  jg     L41
  mov    $0x3,%eax
  cmp    $0xb3b8,%edi
  jg     L41
  mov    $0x4,%eax
  cmp    $0x92bd,%edi
  jg     L41
  mov    $0x5,%eax
  cmp    $0x6c40,%edi
  jg     L41
  mov    $0x6,%eax
  cmp    $0x59db,%edi
  jg     L41
  mov    $0x7,%eax
  cmp    $0x495e,%edi
  jg     L41
  mov    $0x8,%eax
  cmp    $0x361f,%edi
  jg     L41
  mov    $0x9,%eax
  cmp    $0x2ced,%edi
  jg     L41
  xor    %eax,%eax
  cmp    $0x24af,%edi
  setl   %al
  add    $0xa,%eax
L41:
  ret
```

assistant: ```c
int get_samplerate_index(int sample_rate) {
  if (92017 <= sample_rate)
    return 0;
  if (75132 <= sample_rate)
    return 1;
  if (55426 <= sample_rate)
    return 2;
  if (46009 <= sample_rate)
    return 3;
  if (37566 <= sample_rate)
    return 4;
  if (27713 <= sample_rate)
    return 5;
  if (23004 <= sample_rate)
    return 6;
  if (18783 <= sample_rate)
    return 7;
  if (13856 <= sample_rate)
    return 8;
  if (11502 <= sample_rate)
    return 9;
  if (9391 <= sample_rate)
    return 10;
  return 11;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<handle_connection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xe4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe0(%rbp),%rax
  mov    $0xc9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0xe0(%rbp),%rcx
  mov    -0xe4(%rbp),%eax
  mov    $0xc8,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  lea    -0xe0(%rbp),%rdx
  mov    -0xe4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <string_modificator@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  lea    -0xe0(%rbp),%rcx
  mov    -0xe4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  lea    -0xe0(%rbp),%rdx
  mov    -0xe4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string

tool: D6: message received (fd = %d): %s


tool: D17: message send (fd = %d): %s


assistant: ```c
void handle_connection(int cfd) {
  char string[200 + 1];
  memset(string, '\0', sizeof(string));
  read(cfd, string, sizeof(string) - 1);
  printf("message received (fd = %d): %s\n", cfd, string);
  string_modificator(string);
  write(cfd, string, strlen(string) + 1);
  printf("message send (fd = %d): %s\n", cfd, string);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<handle_connection>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0xc9,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0xc8,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %rbx,%rdx
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <string_modificator@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    %rbx,%rdx
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string
name: parse_data
arguments: data_tag: D14
datatype: string

tool: D1: message received (fd = %d): %s


tool: D14: message send (fd = %d): %s


assistant: ```c
void handle_connection(int cfd) {
  char string[200 + 1];
  memset(string, '\0', sizeof(string));
  read(cfd, string, sizeof(string) - 1);
  printf("message received (fd = %d): %s\n", cfd, string);
  string_modificator(string);
  write(cfd, string, strlen(string) + 1);
  printf("message send (fd = %d): %s\n", cfd, string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<handle_connection>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0xc9,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0xc8,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <string_modificator@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  lea    0x1(%rax),%rdx
  call   <write@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xe8,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string

tool: D6: message received (fd = %d): %s


tool: D12: message send (fd = %d): %s


assistant: ```c
void handle_connection(int cfd) {
  char string[200 + 1];
  memset(string, '\0', sizeof(string));
  read(cfd, string, sizeof(string) - 1);
  printf("message received (fd = %d): %s\n", cfd, string);
  string_modificator(string);
  write(cfd, string, strlen(string) + 1);
  printf("message send (fd = %d): %s\n", cfd, string);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<handle_connection>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0xc9,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0xc8,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <string_modificator@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  lea    0x1(%rax),%rdx
  call   <write@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xe8,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D16: message received (fd = %d): %s


tool: D2: message send (fd = %d): %s


assistant: ```c
void handle_connection(int cfd) {
  char string[200 + 1];
  memset(string, '\0', sizeof(string));
  read(cfd, string, sizeof(string) - 1);
  printf("message received (fd = %d): %s\n", cfd, string);
  string_modificator(string);
  write(cfd, string, strlen(string) + 1);
  printf("message send (fd = %d): %s\n", cfd, string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_perform_operation_no_arguments>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  sub    $0x8,%rsp
  lea    -0x14(%rbp),%rax
  push   %rax
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <perform_operation@plt>
  add    $0x10,%rsp
  mov    %eax,%edi
  mov    $0xed,%ecx
  lea    D15(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  call   <_assert_int_equal@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  mov    $0xf0,%ecx
  lea    D15(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  call   <_assert_int_equal@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type_infered: string

tool: D15: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c

assistant: ```c
void test_perform_operation_no_arguments(void **state) {
  int number_of_intermediate_values;
  int *intermediate_values;
  int error_occurred;
  _assert_int_equal(((unsigned long long)((unsigned)(perform_operation(0, NULL, 0, NULL, &number_of_intermediate_values, &intermediate_values, &error_occurred)))), ((unsigned long long)((unsigned)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c", 237);
  _assert_int_equal(((unsigned long long)((unsigned)(error_occurred))), ((unsigned long long)((unsigned)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c", 240);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_perform_operation_no_arguments>:
  endbr64
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <perform_operation@plt>
  mov    %eax,%edi
  mov    $0xed,%ecx
  lea    D6(%rip),%rbx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  call   <_assert_int_equal@plt>
  mov    0x1c(%rsp),%edi
  mov    $0xf0,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  call   <_assert_int_equal@plt>
  add    $0x10,%rsp
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c

assistant: ```c
void test_perform_operation_no_arguments(void **state) {
  int number_of_intermediate_values;
  int *intermediate_values;
  int error_occurred;
  _assert_int_equal(((unsigned long long)((unsigned)(perform_operation(0, NULL, 0, NULL, &number_of_intermediate_values, &intermediate_values, &error_occurred)))), ((unsigned long long)((unsigned)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c", 237);
  _assert_int_equal(((unsigned long long)((unsigned)(error_occurred))), ((unsigned long long)((unsigned)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c", 240);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_perform_operation_no_arguments>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  lea    D9(%rip),%r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <perform_operation@plt>
  mov    $0xed,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %eax,%edi
  call   <_assert_int_equal@plt>
  mov    0x1c(%rsp),%edi
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    $0xf0,%ecx
  call   <_assert_int_equal@plt>
  pop    %rax
  pop    %rdx
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c

assistant: ```c
void test_perform_operation_no_arguments(void **state) {
  int number_of_intermediate_values;
  int *intermediate_values;
  int error_occurred;
  _assert_int_equal(((unsigned long long)((unsigned)(perform_operation(0, NULL, 0, NULL, &number_of_intermediate_values, &intermediate_values, &error_occurred)))), ((unsigned long long)((unsigned)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c", 237);
  _assert_int_equal(((unsigned long long)((unsigned)(error_occurred))), ((unsigned long long)((unsigned)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c", 240);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_perform_operation_no_arguments>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  lea    D6(%rip),%r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <perform_operation@plt>
  mov    $0xed,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %eax,%edi
  call   <_assert_int_equal@plt>
  mov    0x1c(%rsp),%edi
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    $0xf0,%ecx
  call   <_assert_int_equal@plt>
  pop    %rax
  pop    %rdx
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c

assistant: ```c
void test_perform_operation_no_arguments(void **state) {
  int number_of_intermediate_values;
  int *intermediate_values;
  int error_occurred;
  _assert_int_equal(((unsigned long long)((unsigned)(perform_operation(0, NULL, 0, NULL, &number_of_intermediate_values, &intermediate_values, &error_occurred)))), ((unsigned long long)((unsigned)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c", 237);
  _assert_int_equal(((unsigned long long)((unsigned)(error_occurred))), ((unsigned long long)((unsigned)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/BellerophonMobile/xmp3/refs/heads/master/deps/cmockery/src/example/calculator_test.c", 240);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hash_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L8
L19:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash_new(char *str, int len) {
  int i = 0;
  unsigned long hash = 0;
  ;
  hash += str[0];
  for (i = 1; i < len; i++) {
    hash *= 11;
    hash += str[i];
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<hash_new>:
  endbr64
  movsbq (%rdi),%rax
  cmp    $0x1,%esi
  jle    L13
  lea    0x1(%rdi),%rdx
  lea    -0x2(%rsi),%ecx
  lea    0x2(%rdi,%rcx,1),%rsi
L16:
  lea    (%rax,%rax,4),%rcx
  lea    (%rax,%rcx,2),%rcx
  movsbq (%rdx),%rax
  add    %rcx,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L16
L13:
  ret
```

assistant: ```c
unsigned long hash_new(char *str, int len) {
  int i = 0;
  unsigned long hash = 0;
  ;
  hash += str[0];
  for (i = 1; i < len; i++) {
    hash *= 11;
    hash += str[i];
  }
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_new>:
  endbr64
  movsbq (%rdi),%rax
  cmp    $0x1,%esi
  jle    L9
  lea    -0x2(%rsi),%ecx
  lea    0x1(%rdi),%rdx
  lea    0x2(%rdi,%rcx,1),%rsi
  nopl   0x0(%rax)
L2:
  lea    (%rax,%rax,4),%rcx
  add    $0x1,%rdx
  lea    (%rax,%rcx,2),%rcx
  movsbq -0x1(%rdx),%rax
  add    %rcx,%rax
  cmp    %rsi,%rdx
  jne    L2
L9:
  ret
```

assistant: ```c
unsigned long hash_new(char *str, int len) {
  int i = 0;
  unsigned long hash = 0;
  ;
  hash += str[0];
  for (i = 1; i < len; i++) {
    hash *= 11;
    hash += str[i];
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_new>:
  endbr64
  movsbq (%rdi),%rax
  cmp    $0x1,%esi
  jle    L18
  lea    -0x2(%rsi),%ecx
  lea    0x1(%rdi),%rdx
  lea    0x2(%rdi,%rcx,1),%rsi
  nopl   0x0(%rax)
L16:
  lea    (%rax,%rax,4),%rcx
  add    $0x1,%rdx
  lea    (%rax,%rcx,2),%rcx
  movsbq -0x1(%rdx),%rax
  add    %rcx,%rax
  cmp    %rdx,%rsi
  jne    L16
L18:
  ret
```

assistant: ```c
unsigned long hash_new(char *str, int len) {
  int i = 0;
  unsigned long hash = 0;
  ;
  hash += str[0];
  for (i = 1; i < len; i++) {
    hash *= 11;
    hash += str[i];
  }
  return hash;
}
```