ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<ship_destroyed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <end_of_time@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: The Enterprise has been destroyed. The Federation will be conquered.


assistant: ```c
void ship_destroyed(void) {
  puts("The Enterprise has been destroyed. "
       "The Federation will be conquered.\n");
  end_of_time();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ship_destroyed>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <end_of_time@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: The Enterprise has been destroyed. The Federation will be conquered.


assistant: ```c
void ship_destroyed(void) {
  puts("The Enterprise has been destroyed. "
       "The Federation will be conquered.\n");
  end_of_time();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ship_destroyed>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <end_of_time@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: The Enterprise has been destroyed. The Federation will be conquered.


assistant: ```c
void ship_destroyed(void) {
  puts("The Enterprise has been destroyed. "
       "The Federation will be conquered.\n");
  end_of_time();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ship_destroyed>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <end_of_time@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: The Enterprise has been destroyed. The Federation will be conquered.


assistant: ```c
void ship_destroyed(void) {
  puts("The Enterprise has been destroyed. "
       "The Federation will be conquered.\n");
  end_of_time();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readlines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  mov    %rsp,%r14
  jmp    L56
L41:
  add    $0x1,%r13
  lea    0x1(%rbx),%eax
  cltd
  idiv   %ebp
  mov    %edx,%ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,8),%r15
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%r15)
  mov    %r14,%rsi
  call   <strcpy@plt>
L56:
  mov    $0x3e8,%esi
  mov    %r14,%rdi
  call   <mygetline@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jg     L41
  mov    %ebp,%edx
  mov    %r13,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebp,%rax
  cmp    %r13,%rax
  jge    L67
  movslq %ebx,%rbx
  mov    %ebp,%r14d
  add    %rbx,%r14
  lea    D23(%rip),%r15
  test   %ebp,%ebp
  jle    L71
L88:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%eax
  cltd
  idiv   %ebp
  movslq %edx,%rdx
  mov    (%r12,%rdx,8),%rsi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L88
  jmp    L71
L67:
  test   %r13,%r13
  jle    L71
  mov    %r13,%r14
  mov    $0x0,%ebx
  lea    D31(%rip),%rbp
L32:
  mov    (%r12,%rbx,8),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L32
L71:
  mov    %r13d,%eax
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D25
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D31
type: string

tool: D25: Found lines %d || %d


tool: D23: ***i is[%d]: (((%s)))


tool: D31: %s

assistant: ```c
int readlines(char *lines[], int numlines) {
  int i = 0;
  int min = 0;
  int j;
  int len = 0;
  char line[1000];
  long lineno = 0;
  while ((len = mygetline(line, 1000)) > 0) {
    lineno++;
    i = (i + 1) % numlines;
    lines[i] = malloc(len);
    strcpy(lines[i], line);
  }
  printf("Found lines %d || %d\n", lineno, numlines);
  if (lineno <= numlines) {
    for (i = 0; i < lineno; i++) {
      printf("%s", lines[i]);
    }
  } else {
    j = numlines;
    while (j-- > 0) {
      printf("***i is[%d]: (((%s)))\n", i, lines[i]);
      printf("%s", lines[++i % numlines]);
    }
  }
  return lineno;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readlines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  jmp    L4
  nopl   0x0(%rax)
L74:
  lea    0x1(%rbx),%eax
  add    $0x1,%r12
  cltd
  idiv   %ebp
  movslq %edx,%rax
  lea    0x0(%r13,%rax,8),%r15
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %r14,%rsi
  mov    %rax,(%r15)
  mov    %rax,%rdi
  call   <strcpy@plt>
L4:
  mov    %r14,%rdi
  mov    $0x3e8,%esi
  call   <mygetline@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jg     L74
  mov    %ebp,%edx
  mov    %r12,%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebp,%rax
  cmp    %r12,%rax
  jge    L53
  movslq %ebx,%r15
  lea    D6(%rip),%r14
  lea    D13(%rip),%rbx
  add    %r15,%rax
  mov    %rax,0x8(%rsp)
  test   %ebp,%ebp
  jle    L9
  nopw   0x0(%rax,%rax,1)
L20:
  mov    0x0(%r13,%r15,8),%rdx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%r15),%eax
  mov    %r14,%rdi
  add    $0x1,%r15
  cltd
  idiv   %ebp
  xor    %eax,%eax
  movslq %edx,%rdx
  mov    0x0(%r13,%rdx,8),%rsi
  call   <printf@plt>
  cmp    0x8(%rsp),%r15
  jne    L20
L9:
  mov    %r12d,%eax
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x408,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L53:
  test   %r12,%r12
  je     L9
  xor    %ebx,%ebx
  lea    D6(%rip),%r14
  xchg   %ax,%ax
L12:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L12
  jmp    L9
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D24
type: string
name: read_data
arguments: label: D6
type: string
name: read_data
arguments: label: D13
type: string

tool: D24: Found lines %d || %d


tool: D6: %s

tool: D13: ***i is[%d]: (((%s)))


assistant: ```c
int readlines(char *lines[], int numlines) {
  int i = 0;
  int min = 0;
  int j;
  int len = 0;
  char line[1000];
  long lineno = 0;
  while ((len = mygetline(line, 1000)) > 0) {
    lineno++;
    i = (i + 1) % numlines;
    lines[i] = malloc(len);
    strcpy(lines[i], line);
  }
  printf("Found lines %d || %d\n", lineno, numlines);
  if (lineno <= numlines) {
    for (i = 0; i < lineno; i++) {
      printf("%s", lines[i]);
    }
  } else {
    j = numlines;
    while (j-- > 0) {
      printf("***i is[%d]: (((%s)))\n", i, lines[i]);
      printf("%s", lines[++i % numlines]);
    }
  }
  return lineno;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readlines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  jmp    L56
  nopl   0x0(%rax)
L47:
  lea    0x1(%rbx),%eax
  add    $0x1,%r12
  cltd
  idiv   %ebp
  movslq %edx,%rax
  lea    0x0(%r13,%rax,8),%r15
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %r14,%rsi
  mov    %rax,(%r15)
  mov    %rax,%rdi
  call   <strcpy@plt>
L56:
  mov    %r14,%rdi
  mov    $0x3e8,%esi
  call   <mygetline@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jg     L47
  mov    %ebp,%edx
  mov    %r12,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebp,%rax
  cmp    %r12,%rax
  jge    L32
  movslq %ebx,%r15
  lea    D28(%rip),%r14
  lea    D11(%rip),%rbx
  add    %r15,%rax
  mov    %rax,0x8(%rsp)
  test   %ebp,%ebp
  jle    L72
  nopw   0x0(%rax,%rax,1)
L43:
  mov    0x0(%r13,%r15,8),%rdx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%r15),%eax
  mov    %r14,%rdi
  add    $0x1,%r15
  cltd
  idiv   %ebp
  xor    %eax,%eax
  movslq %edx,%rdx
  mov    0x0(%r13,%rdx,8),%rsi
  call   <printf@plt>
  cmp    %r15,0x8(%rsp)
  jne    L43
L72:
  mov    %r12d,%eax
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x408,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L32:
  test   %r12,%r12
  je     L72
  xor    %ebx,%ebx
  lea    D28(%rip),%r14
  xchg   %ax,%ax
L34:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L34
  jmp    L72
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string

tool: D15: Found lines %d || %d


tool: D28: %s

tool: D11: ***i is[%d]: (((%s)))


assistant: ```c
int readlines(char *lines[], int numlines) {
  int i = 0;
  int min = 0;
  int j;
  int len = 0;
  char line[1000];
  long lineno = 0;
  while ((len = mygetline(line, 1000)) > 0) {
    lineno++;
    i = (i + 1) % numlines;
    lines[i] = malloc(len);
    strcpy(lines[i], line);
  }
  printf("Found lines %d || %d\n", lineno, numlines);
  if (lineno <= numlines) {
    for (i = 0; i < lineno; i++) {
      printf("%s", lines[i]);
    }
  } else {
    j = numlines;
    while (j-- > 0) {
      printf("***i is[%d]: (((%s)))\n", i, lines[i]);
      printf("%s", lines[++i % numlines]);
    }
  }
  return lineno;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xfffffff0,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int *i = (int *)0xfffffff0;
  return *i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  movabs 0xfffffff0,%eax
  ret
```

assistant: ```c
int main(void) {
  int *i = (int *)0xfffffff0;
  return *i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  movabs 0xfffffff0,%eax
  ret
```

assistant: ```c
int main(void) {
  int *i = (int *)0xfffffff0;
  return *i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  movabs 0xfffffff0,%eax
  ret
```

assistant: ```c
int main(void) {
  int *i = (int *)0xfffffff0;
  return *i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__res_dnok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
L43:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L41
  cmpl   $0x20,-0xc(%rbp)
  jle    L3
  cmpl   $0x7e,-0xc(%rbp)
  jle    L43
  mov    $0x0,%eax
  jmp    L22
L3:
  mov    $0x0,%eax
  jmp    L22
L41:
  nop
  mov    $0x1,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int __res_dnok(char const *dn) {
  int ch;
  char const *tmp;
  char __cil_tmp4;
  {
    {
      while (1) {
      while_continue:;
        tmp = dn;
        dn = dn + 1;
        __cil_tmp4 = *tmp;
        ch = (int)__cil_tmp4;
        if (ch != 0) {
        } else {
          goto while_break;
        }
        if (ch > 32) {
          if (ch < 127) {
          } else {
            return (0);
          }
        } else {
          return (0);
        }
      }
    while_break:;
    }
    return (1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__res_dnok>:
  endbr64
L16:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L0
  movsbl %al,%eax
  sub    $0x21,%eax
  cmp    $0x5d,%eax
  jbe    L16
  mov    $0x0,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int __res_dnok(char const *dn) {
  int ch;
  char const *tmp;
  char __cil_tmp4;
  {
    {
      while (1) {
      while_continue:;
        tmp = dn;
        dn = dn + 1;
        __cil_tmp4 = *tmp;
        ch = (int)__cil_tmp4;
        if (ch != 0) {
        } else {
          goto while_break;
        }
        if (ch > 32) {
          if (ch < 127) {
          } else {
            return (0);
          }
        } else {
          return (0);
        }
      }
    while_break:;
    }
    return (1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<__res_dnok>:
  endbr64
  nopl   0x0(%rax)
L1:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L10
  sub    $0x21,%eax
  cmp    $0x5d,%al
  jbe    L1
  xor    %eax,%eax
  ret
  nopl   (%rax)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int __res_dnok(char const *dn) {
  int ch;
  char const *tmp;
  char __cil_tmp4;
  {
    {
      while (1) {
      while_continue:;
        tmp = dn;
        dn = dn + 1;
        __cil_tmp4 = *tmp;
        ch = (int)__cil_tmp4;
        if (ch != 0) {
        } else {
          goto while_break;
        }
        if (ch > 32) {
          if (ch < 127) {
          } else {
            return (0);
          }
        } else {
          return (0);
        }
      }
    while_break:;
    }
    return (1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__res_dnok>:
  endbr64
  nopl   0x0(%rax)
L9:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L12
  sub    $0x21,%eax
  cmp    $0x5d,%al
  jbe    L9
  xor    %eax,%eax
  ret
  nopl   (%rax)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int __res_dnok(char const *dn) {
  int ch;
  char const *tmp;
  char __cil_tmp4;
  {
    {
      while (1) {
      while_continue:;
        tmp = dn;
        dn = dn + 1;
        __cil_tmp4 = *tmp;
        ch = (int)__cil_tmp4;
        if (ch != 0) {
        } else {
          goto while_break;
        }
        if (ch > 32) {
          if (ch < 127) {
          } else {
            return (0);
          }
        } else {
          return (0);
        }
      }
    while_break:;
    }
    return (1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ft_putstr(argv[argc * 0]);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <ft_putstr@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ft_putstr(argv[argc * 0]);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <ft_putstr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ft_putstr(argv[argc * 0]);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <ft_putstr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ft_putstr(argv[argc * 0]);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lsmIoerrBkpt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D12(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D11(%rip)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lsmIoerrBkpt() {
  static int nErr = 0;
  nErr++;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lsmIoerrBkpt>:
  endbr64
  addl   $0x1,D2(%rip)
  ret
```

assistant: ```c
void lsmIoerrBkpt() {
  static int nErr = 0;
  nErr++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lsmIoerrBkpt>:
  endbr64
  addl   $0x1,D3(%rip)
  ret
```

assistant: ```c
void lsmIoerrBkpt() {
  static int nErr = 0;
  nErr++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lsmIoerrBkpt>:
  endbr64
  addl   $0x1,D7(%rip)
  ret
```

assistant: ```c
void lsmIoerrBkpt() {
  static int nErr = 0;
  nErr++;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_plugin_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  nop
L2:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D7: A/D-in plugin for Julius

assistant: ```c
int get_plugin_info(int opcode, char *buf, int buflen) {
  switch (opcode) {
  case 0:
    strncpy(buf, "A/D-in plugin for Julius", buflen);
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_plugin_info>:
  endbr64
  test   %edi,%edi
  je     L9
  mov    $0x0,%eax
  ret
L9:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  lea    D5(%rip),%rsi
  call   <strncpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: A/D-in plugin for Julius

assistant: ```c
int get_plugin_info(int opcode, char *buf, int buflen) {
  switch (opcode) {
  case 0:
    strncpy(buf, "A/D-in plugin for Julius", buflen);
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_plugin_info>:
  endbr64
  test   %edi,%edi
  je     L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  lea    D9(%rip),%rsi
  call   <strncpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: A/D-in plugin for Julius

assistant: ```c
int get_plugin_info(int opcode, char *buf, int buflen) {
  switch (opcode) {
  case 0:
    strncpy(buf, "A/D-in plugin for Julius", buflen);
    break;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_plugin_info>:
  endbr64
  test   %edi,%edi
  je     L0
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  lea    D1(%rip),%rsi
  call   <strncpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: A/D-in plugin for Julius

assistant: ```c
int get_plugin_info(int opcode, char *buf, int buflen) {
  switch (opcode) {
  case 0:
    strncpy(buf, "A/D-in plugin for Julius", buflen);
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x10(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <sum@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D33
data_type: string

tool: D3: Enter the value of x:

tool: D12: %f

tool: D0: Enter the value of y:

tool: D33: The sum of x and y is %f.


assistant: ```c
main() {
  float sum(float, float);
  float x, y, a;
  printf("Enter the value of x:\n");
  scanf("%f", &x);
  printf("Enter the value of y:\n");
  scanf("%f", &y);
  a = x + y;
  a = sum(x, y);
  printf("The sum of x and y is %f.\n", a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <sum@plt>
  cvtss2sd %xmm0,%xmm0
  lea    D35(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D9
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string
name: retrieve_data
arguments: tag: D35
datatype: string

tool: D11: Enter the value of x:

tool: D9: %f

tool: D26: Enter the value of y:

tool: D35: The sum of x and y is %f.


assistant: ```c
main() {
  float sum(float, float);
  float x, y, a;
  printf("Enter the value of x:\n");
  scanf("%f", &x);
  printf("Enter the value of y:\n");
  scanf("%f", &y);
  a = x + y;
  a = sum(x, y);
  printf("The sum of x and y is %f.\n", a);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  lea    D36(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <sum@plt>
  lea    D34(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
type_guessed: string
name: disassemble_data
arguments: tag: D36
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D34
type_guessed: string

tool: D25: Enter the value of x:

tool: D36: %f

tool: D10: Enter the value of y:

tool: D34: The sum of x and y is %f.


assistant: ```c
main() {
  float sum(float, float);
  float x, y, a;
  printf("Enter the value of x:\n");
  scanf("%f", &x);
  printf("Enter the value of y:\n");
  scanf("%f", &y);
  a = x + y;
  a = sum(x, y);
  printf("The sum of x and y is %f.\n", a);
}
```