ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atomac>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rcx
  lea    0x14(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  lea    D1(%rip),%rsi
  call   <sscanf@plt>
  mov    %eax,%edx
  add    $0x10,%rsp
  mov    $0x1,%eax
  cmp    $0x6,%edx
  jne    L20
  mov    $0x0,%eax
L43:
  mov    (%rsp,%rax,4),%edx
  cmp    $0xff,%edx
  ja     L21
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0x6,%rax
  jne    L43
  mov    $0x0,%eax
L20:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x20,%rsp
  pop    %rbx
  ret
L21:
  mov    $0x1,%eax
  jmp    L20
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string

tool: D1: %2x:%2x:%2x:%2x:%2x:%2x

assistant: ```c
int atomac(char *str, unsigned char macAddr[6]) {
  unsigned mac[6];
  if (sscanf(str, "%2x:%2x:%2x:%2x:%2x:%2x", &mac[0], &mac[1], &mac[2], &mac[3], &mac[4], &mac[5]) != 6)
    return 1;
  int i;
  for (i = 0; i < 6; i++) {
    if (mac[i] > 0xff)
      return 1;
    macAddr[i] = (unsigned char)mac[i];
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atomac>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D9(%rip),%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%rcx
  push   %rax
  mov    %rbp,%rdx
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <sscanf@plt>
  mov    %rbp,%rsp
  cmp    $0x6,%eax
  jne    L24
  xor    %eax,%eax
L26:
  mov    0x0(%rbp,%rax,4),%edx
  cmp    $0xff,%edx
  ja     L24
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0x6,%rax
  jne    L26
  xor    %eax,%eax
  jmp    L5
  nopl   0x0(%rax)
L24:
  mov    $0x1,%eax
L5:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D9: %2x:%2x:%2x:%2x:%2x:%2x

assistant: ```c
int atomac(char *str, unsigned char macAddr[6]) {
  unsigned mac[6];
  if (sscanf(str, "%2x:%2x:%2x:%2x:%2x:%2x", &mac[0], &mac[1], &mac[2], &mac[3], &mac[4], &mac[5]) != 6)
    return 1;
  int i;
  for (i = 0; i < 6; i++) {
    if (mac[i] > 0xff)
      return 1;
    macAddr[i] = (unsigned char)mac[i];
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<atomac>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  lea    D9(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rcx
  push   %rax
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <sscanf@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0x6,%eax
  jne    L2
  mov    (%rsp),%eax
  cmp    $0xff,%eax
  ja     L2
  mov    %al,(%rbx)
  mov    0x4(%rsp),%eax
  cmp    $0xff,%eax
  ja     L2
  mov    %al,0x1(%rbx)
  mov    0x8(%rsp),%eax
  cmp    $0xff,%eax
  ja     L2
  mov    %al,0x2(%rbx)
  mov    0xc(%rsp),%eax
  cmp    $0xff,%eax
  ja     L2
  mov    %al,0x3(%rbx)
  mov    0x10(%rsp),%eax
  cmp    $0xff,%eax
  ja     L2
  mov    %al,0x4(%rbx)
  mov    0x14(%rsp),%eax
  cmp    $0xff,%eax
  ja     L2
  mov    %al,0x5(%rbx)
  xor    %eax,%eax
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%eax
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x20,%rsp
  pop    %rbx
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D9: %2x:%2x:%2x:%2x:%2x:%2x

assistant: ```c
int atomac(char *str, unsigned char macAddr[6]) {
  unsigned mac[6];
  if (sscanf(str, "%2x:%2x:%2x:%2x:%2x:%2x", &mac[0], &mac[1], &mac[2], &mac[3], &mac[4], &mac[5]) != 6)
    return 1;
  int i;
  for (i = 0; i < 6; i++) {
    if (mac[i] > 0xff)
      return 1;
    macAddr[i] = (unsigned char)mac[i];
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<receiveMessages>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x8,%esi
  mov    $0x100,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
L3:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rcx
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: re_1:%s

assistant: ```c
void *receiveMessages(void *arg) {
  char *input;
  int ssize;
  input = calloc(256, sizeof(char *));
  while (1) {
    read(*((int *)arg), &ssize, sizeof(ssize));
    read(*((int *)arg), input, (ssize + 1) * sizeof(char));
    printf("re_1:%s", input);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<receiveMessages>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x8,%esi
  mov    $0x100,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  lea    D3(%rip),%r12
L2:
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    0x0(%rbp),%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  mov    %rbx,%rsi
  mov    0x0(%rbp),%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: re_1:%s

assistant: ```c
void *receiveMessages(void *arg) {
  char *input;
  int ssize;
  input = calloc(256, sizeof(char *));
  while (1) {
    read(*((int *)arg), &ssize, sizeof(ssize));
    read(*((int *)arg), input, (ssize + 1) * sizeof(char));
    printf("re_1:%s", input);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<receiveMessages>:
  endbr64
  push   %r13
  mov    $0x8,%esi
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x100,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <calloc@plt>
  mov    %rax,%rbx
  nop
L6:
  mov    0x0(%rbp),%edi
  mov    %r13,%rsi
  mov    $0x4,%edx
  xor    %eax,%eax
  call   <read@plt>
  mov    0x4(%rsp),%eax
  mov    0x0(%rbp),%edi
  mov    %rbx,%rsi
  lea    0x1(%rax),%edx
  xor    %eax,%eax
  movslq %edx,%rdx
  call   <read@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: re_1:%s

assistant: ```c
void *receiveMessages(void *arg) {
  char *input;
  int ssize;
  input = calloc(256, sizeof(char *));
  while (1) {
    read(*((int *)arg), &ssize, sizeof(ssize));
    read(*((int *)arg), input, (ssize + 1) * sizeof(char));
    printf("re_1:%s", input);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<receiveMessages>:
  endbr64
  push   %r13
  mov    $0x8,%esi
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x100,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <calloc@plt>
  mov    %rax,%rbx
  nop
L8:
  mov    0x0(%rbp),%edi
  mov    %r13,%rsi
  mov    $0x4,%edx
  xor    %eax,%eax
  call   <read@plt>
  mov    0x4(%rsp),%eax
  mov    0x0(%rbp),%edi
  mov    %rbx,%rsi
  lea    0x1(%rax),%edx
  xor    %eax,%eax
  movslq %edx,%rdx
  call   <read@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D8: re_1:%s

assistant: ```c
void *receiveMessages(void *arg) {
  char *input;
  int ssize;
  input = calloc(256, sizeof(char *));
  while (1) {
    read(*((int *)arg), &ssize, sizeof(ssize));
    read(*((int *)arg), input, (ssize + 1) * sizeof(char));
    printf("re_1:%s", input);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msglog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xe4(%rbp)
  mov    %rsi,-0xf0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L35
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L35:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  lea    -0xd8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  lea    -0xd8(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %eax,%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%ecx
  lea    D38(%rip),%rdx
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  cmpl   $0x0,-0xe4(%rbp)
  je     L39
  lea    D6(%rip),%rax
  jmp    L14
L39:
  lea    D15(%rip),%rax
L14:
  mov    -0xd8(%rbp),%edx
  movslq %edx,%rcx
  imul   $0x10624dd3,%rcx,%rcx
  shr    $0x20,%rcx
  sar    $0x6,%ecx
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%ecx
  mov    %ecx,%edx
  lea    -0xd0(%rbp),%rsi
  mov    %rax,%rcx
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xf0(%rbp),%rdx
  mov    -0xdc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xdc(%rbp),%edx
  mov    -0xf0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xdc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D38
type: string
name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D23
type: string

tool: D38: %H:%M:%S

tool: D6: <--

tool: D15: -->

tool: D23: %s.%03lu %s 

assistant: ```c
void msglog(int is_inbound, const char *format, ...) {
  char outstr[20];
  struct timeval tv;
  va_list args;
  gettimeofday(&tv, 0);
  strftime(outstr, sizeof(outstr), "%H:%M:%S", localtime(&tv.tv_sec));
  printf("%s.%03lu %s ", outstr, tv.tv_usec / 1000, is_inbound ? "<--" : "-->");
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<msglog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    %eax,%ecx
  lea    0x10(%rsp),%rdi
  lea    D25(%rip),%rdx
  mov    $0x14,%esi
  call   <strftime@plt>
  test   %ebp,%ebp
  lea    D8(%rip),%rcx
  lea    D20(%rip),%rax
  cmove  %rax,%rcx
  mov    0x8(%rsp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    0x10(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D30
type_infered: string

tool: D25: %H:%M:%S

tool: D8: <--

tool: D20: -->

tool: D30: %s.%03lu %s 

assistant: ```c
void msglog(int is_inbound, const char *format, ...) {
  char outstr[20];
  struct timeval tv;
  va_list args;
  gettimeofday(&tv, 0);
  strftime(outstr, sizeof(outstr), "%H:%M:%S", localtime(&tv.tv_sec));
  printf("%s.%03lu %s ", outstr, tv.tv_usec / 1000, is_inbound ? "<--" : "-->");
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<msglog>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r13
  call   <gettimeofday@plt>
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  lea    D39(%rip),%rdx
  mov    $0x14,%esi
  mov    %r13,%rdi
  mov    %eax,%ecx
  call   <strftime@plt>
  movslq 0x8(%rsp),%rdx
  test   %r12d,%r12d
  mov    %r13,%rsi
  lea    D36(%rip),%rax
  lea    D19(%rip),%rcx
  cmove  %rax,%rcx
  mov    %rdx,%rax
  xor    %r12d,%r12d
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%eax
  lea    D2(%rip),%rdi
  sar    $0x26,%rdx
  sub    %eax,%edx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_guessed: string
name: unpack_data
arguments: data_label: D36
type_guessed: string
name: unpack_data
arguments: data_label: D19
type_guessed: string
name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D39: %H:%M:%S

tool: D36: -->

tool: D19: <--

tool: D2: %s.%03lu %s 

assistant: ```c
void msglog(int is_inbound, const char *format, ...) {
  char outstr[20];
  struct timeval tv;
  va_list args;
  gettimeofday(&tv, 0);
  strftime(outstr, sizeof(outstr), "%H:%M:%S", localtime(&tv.tv_sec));
  printf("%s.%03lu %s ", outstr, tv.tv_usec / 1000, is_inbound ? "<--" : "-->");
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<msglog>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r13
  call   <gettimeofday@plt>
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  lea    D8(%rip),%rdx
  mov    $0x14,%esi
  mov    %r13,%rdi
  mov    %eax,%ecx
  call   <strftime@plt>
  movslq 0x8(%rsp),%rdx
  test   %r12d,%r12d
  mov    %r13,%rsi
  lea    D10(%rip),%rax
  lea    D38(%rip),%rcx
  cmove  %rax,%rcx
  mov    %rdx,%rax
  xor    %r12d,%r12d
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%eax
  lea    D3(%rip),%rdi
  sar    $0x26,%rdx
  sub    %eax,%edx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D3
data_type: string

tool: D8: %H:%M:%S

tool: D10: -->

tool: D38: <--

tool: D3: %s.%03lu %s 

assistant: ```c
void msglog(int is_inbound, const char *format, ...) {
  char outstr[20];
  struct timeval tv;
  va_list args;
  gettimeofday(&tv, 0);
  strftime(outstr, sizeof(outstr), "%H:%M:%S", localtime(&tv.tv_sec));
  printf("%s.%03lu %s ", outstr, tv.tv_usec / 1000, is_inbound ? "<--" : "-->");
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mat_cria>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  subl   $0x1,-0x24(%rbp)
  jmp    L0
L6:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  subl   $0x1,-0x24(%rbp)
L0:
  cmpl   $0xffffffff,-0x24(%rbp)
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double **mat_cria(int m, int n) {
  double **mat = calloc(sizeof(double *), m);
  for (m -= 1; m + 1; m--) {
    mat[m] = calloc(sizeof(double), n);
  }
  return mat;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mat_cria>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %edi,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %r13d,%r13d
  je     L19
  lea    -0x1(%r13),%ebx
  movslq %ebx,%rbx
L4:
  mov    %r12d,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  jne    L4
L19:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **mat_cria(int m, int n) {
  double **mat = calloc(sizeof(double *), m);
  for (m -= 1; m + 1; m--) {
    mat[m] = calloc(sizeof(double), n);
  }
  return mat;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mat_cria>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  mov    $0x8,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  je     L16
  lea    -0x1(%r13),%ebx
  movslq %ebx,%rbx
  xchg   %ax,%ax
L2:
  mov    %ebp,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,(%r12,%rbx,8)
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  jne    L2
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **mat_cria(int m, int n) {
  double **mat = calloc(sizeof(double *), m);
  for (m -= 1; m + 1; m--) {
    mat[m] = calloc(sizeof(double), n);
  }
  return mat;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mat_cria>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  mov    $0x8,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  je     L8
  lea    -0x1(%r13),%ebx
  movslq %ebx,%rbx
  xchg   %ax,%ax
L18:
  mov    %ebp,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,(%r12,%rbx,8)
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  jne    L18
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **mat_cria(int m, int n) {
  double **mat = calloc(sizeof(double *), m);
  for (m -= 1; m + 1; m--) {
    mat[m] = calloc(sizeof(double), n);
  }
  return mat;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<until>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L34:
  addl   $0x1,-0x4(%rbp)
L6:
  cmpq   $0x0,-0x20(%rbp)
  je     L4
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  test   %eax,%eax
  je     L34
L4:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int until(int (*test)(char), char *s) {
  int i = 0;
  while (s && s[i] && !test(s[i]))
    ++i;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<until>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L20:
  mov    %ebx,%r13d
  movzbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  je     L12
  movsbl %dil,%edi
  call   *%r12
  add    $0x1,%rbx
  test   %eax,%eax
  je     L20
L12:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    $0x0,%r13d
  jmp    L12
```

assistant: ```c
int until(int (*test)(char), char *s) {
  int i = 0;
  while (s && s[i] && !test(s[i]))
    ++i;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<until>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L6
  mov    %rdi,%r12
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  jmp    L16
  nopl   (%rax)
L11:
  call   *%r12
  add    $0x1,%rbx
  test   %eax,%eax
  jne    L3
L16:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %ebx,%r13d
  test   %dil,%dil
  jne    L11
L3:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  xor    %r13d,%r13d
  jmp    L3
```

assistant: ```c
int until(int (*test)(char), char *s) {
  int i = 0;
  while (s && s[i] && !test(s[i]))
    ++i;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<until>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L22
  mov    %rdi,%r12
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  jmp    L15
  nopl   (%rax)
L14:
  call   *%r12
  add    $0x1,%rbx
  test   %eax,%eax
  jne    L46
L15:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %ebx,%r13d
  test   %dil,%dil
  jne    L14
L46:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  xor    %r13d,%r13d
  jmp    L46
```

assistant: ```c
int until(int (*test)(char), char *s) {
  int i = 0;
  while (s && s[i] && !test(s[i]))
    ++i;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hashsg_closer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L36:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L11
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  xor    %edx,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  xor    %edx,%eax
  cmp    %al,%sil
  setb   %al
  movzbl %al,%eax
  jmp    L18
L11:
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x13,-0x4(%rbp)
  jbe    L36
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int hashsg_closer(const char *target, const char *s1, const char *s2) {
  unsigned int i;
  for (i = 0; i < 20; i++) {
    if (s1[i] != s2[i]) {
      return (unsigned char)(s1[i] ^ target[i]) < (unsigned char)(s2[i] ^ target[i]);
    }
  }
  return 0;
}
```