ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x14(%rdi),%r12
  lea    D9(%rip),%rbp
L5:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: %3d

assistant: ```c
void print(int *p) {
  int i;
  for (i = 0; i < 5; i++) {
    printf("%3d", *p++);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print>:
  endbr64
  push   %r12
  lea    0x14(%rdi),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L0:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string

tool: D7: %3d

assistant: ```c
void print(int *p) {
  int i;
  for (i = 0; i < 5; i++) {
    printf("%3d", *p++);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print>:
  endbr64
  push   %r12
  lea    0x14(%rdi),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L9:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: %3d

assistant: ```c
void print(int *p) {
  int i;
  for (i = 0; i < 5; i++) {
    printf("%3d", *p++);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L37:
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  je     L44
  cmp    $0x2,%eax
  je     L34
  jmp    L64
L44:
  mov    $0x0,%eax
  call   <exe01@plt>
  jmp    L64
L34:
  mov    $0x0,%eax
  call   <exe02@plt>
  nop
L64:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L37
  mov    -0xc(%rbp),%eax
  cmp    $0xa,%eax
  jg     L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D44
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D2
data_type: string

tool: D44: ---------------------------------------------------------


tool: D29: EXERCICIO 01 - EM SEGUNDOS


tool: D6: EXERCICIO 02 - QUEDA LIVRE


tool: D2: %d

assistant: ```c
int main(void) {
  int opc;
  do {
    printf("---------------------------------------------------------\n");
    printf("EXERCICIO 01 - EM SEGUNDOS\n");
    printf("EXERCICIO 02 - QUEDA LIVRE\n");
    printf("---------------------------------------------------------\n");
    scanf("%d", &opc);
    switch (opc) {
    case 1: {
      exe01();
      break;
    }
    case 2: {
      exe02();
      break;
    }
    }
  } while ((opc < 1) || (opc > 10));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rbx
  lea    D19(%rip),%r13
  lea    D21(%rip),%r12
  lea    D7(%rip),%rbp
  jmp    L47
L9:
  mov    $0x0,%eax
  call   <exe01@plt>
L40:
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x9,%eax
  jbe    L43
L47:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L9
  cmp    $0x2,%eax
  jne    L40
  mov    $0x0,%eax
  call   <exe02@plt>
  jmp    L40
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string

tool: D18: ---------------------------------------------------------


tool: D19: EXERCICIO 01 - EM SEGUNDOS


tool: D21: EXERCICIO 02 - QUEDA LIVRE


tool: D7: %d

assistant: ```c
int main(void) {
  int opc;
  do {
    printf("---------------------------------------------------------\n");
    printf("EXERCICIO 01 - EM SEGUNDOS\n");
    printf("EXERCICIO 02 - QUEDA LIVRE\n");
    printf("---------------------------------------------------------\n");
    scanf("%d", &opc);
    switch (opc) {
    case 1: {
      exe01();
      break;
    }
    case 2: {
      exe02();
      break;
    }
    }
  } while ((opc < 1) || (opc > 10));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D31(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  lea    D37(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L22:
  cmp    $0x2,%eax
  jne    L21
  xor    %eax,%eax
  call   <exe02@plt>
  mov    0x4(%rsp),%eax
L21:
  sub    $0x1,%eax
  cmp    $0x9,%eax
  jbe    L28
L46:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jne    L22
  xor    %eax,%eax
  call   <exe01@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x9,%eax
  ja     L46
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D31
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string
name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D37
data_type: string

tool: D31: EXERCICIO 01 - EM SEGUNDOS


tool: D19: EXERCICIO 02 - QUEDA LIVRE


tool: D7: %d

tool: D37: ---------------------------------------------------------


assistant: ```c
int main(void) {
  int opc;
  do {
    printf("---------------------------------------------------------\n");
    printf("EXERCICIO 01 - EM SEGUNDOS\n");
    printf("EXERCICIO 02 - QUEDA LIVRE\n");
    printf("---------------------------------------------------------\n");
    scanf("%d", &opc);
    switch (opc) {
    case 1: {
      exe01();
      break;
    }
    case 2: {
      exe02();
      break;
    }
    }
  } while ((opc < 1) || (opc > 10));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D39(%rip),%r13
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L2:
  cmp    $0x2,%eax
  jne    L32
  xor    %eax,%eax
  call   <exe02@plt>
  mov    0x4(%rsp),%eax
L32:
  sub    $0x1,%eax
  cmp    $0x9,%eax
  jbe    L42
L58:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jne    L2
  xor    %eax,%eax
  call   <exe01@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x9,%eax
  ja     L58
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D39
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string
name: unpack_data
arguments: label: D33
type_guessed: string

tool: D7: EXERCICIO 01 - EM SEGUNDOS


tool: D39: EXERCICIO 02 - QUEDA LIVRE


tool: D14: %d

tool: D33: ---------------------------------------------------------


assistant: ```c
int main(void) {
  int opc;
  do {
    printf("---------------------------------------------------------\n");
    printf("EXERCICIO 01 - EM SEGUNDOS\n");
    printf("EXERCICIO 02 - QUEDA LIVRE\n");
    printf("---------------------------------------------------------\n");
    scanf("%d", &opc);
    switch (opc) {
    case 1: {
      exe01();
      break;
    }
    case 2: {
      exe02();
      break;
    }
    }
  } while ((opc < 1) || (opc > 10));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__strptime_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
char *__strptime_l(buf, format, tm, locale)
int buf;
int format;
int tm;
int locale;
{}
```
user: What is the c source code of the assembly code below?

```asm
<__strptime_l>:
  endbr64
  ret
```

assistant: ```c
char *__strptime_l(buf, format, tm, locale)
int buf;
int format;
int tm;
int locale;
{}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__strptime_l>:
  endbr64
  ret
```

assistant: ```c
char *__strptime_l(buf, format, tm, locale)
int buf;
int format;
int tm;
int locale;
{}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__strptime_l>:
  endbr64
  ret
```

assistant: ```c
char *__strptime_l(buf, format, tm, locale)
int buf;
int format;
int tm;
int locale;
{}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SPIEnble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  or     $0x40,%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SPIEnble(unsigned long ulBase) {

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000040;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SPIEnble>:
  endbr64
  mov    (%rdi),%rax
  or     $0x40,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void SPIEnble(unsigned long ulBase) {

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000040;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SPIEnble>:
  endbr64
  mov    (%rdi),%rax
  or     $0x40,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void SPIEnble(unsigned long ulBase) {

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000040;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SPIEnble>:
  endbr64
  mov    (%rdi),%rax
  or     $0x40,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void SPIEnble(unsigned long ulBase) {

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000040;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<deltaT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L1
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0xf4240,%rax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movsd  D10(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L13
L1:
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  sub    %eax,%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdq -0x8(%rbp),%xmm2
  movsd  D10(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L13:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: byte[8]

tool: {"D10": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double deltaT(struct timeval *tin, struct timeval *tout) {
  long usec;
  double sec;
  usec = tout->tv_usec - tin->tv_usec;
  if (usec < 0) {
    sec = tout->tv_sec - tin->tv_sec - 1 + ((double)(usec + 1000000)) * 1e-6;
  } else {
    sec = tout->tv_sec - tin->tv_sec + ((double)usec) * 1e-6;
  }
  return sec;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<deltaT>:
  endbr64
  mov    (%rsi),%rax
  sub    (%rdi),%rax
  js     L8
  mov    0x8(%rsi),%edx
  sub    0x8(%rdi),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mulsd  D10(%rip),%xmm1
  addsd  %xmm1,%xmm0
  ret
L8:
  mov    0x8(%rsi),%edx
  sub    0x8(%rdi),%edx
  sub    $0x1,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  add    $0xf4240,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mulsd  D10(%rip),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: byte[8]

tool: {"D10": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double deltaT(struct timeval *tin, struct timeval *tout) {
  long usec;
  double sec;
  usec = tout->tv_usec - tin->tv_usec;
  if (usec < 0) {
    sec = tout->tv_sec - tin->tv_sec - 1 + ((double)(usec + 1000000)) * 1e-6;
  } else {
    sec = tout->tv_sec - tin->tv_sec + ((double)usec) * 1e-6;
  }
  return sec;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<deltaT>:
  endbr64
  mov    0x8(%rsi),%edx
  mov    (%rsi),%rax
  sub    0x8(%rdi),%edx
  sub    (%rdi),%rax
  js     L6
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm0
  mulsd  D7(%rip),%xmm0
  cvtsi2sd %edx,%xmm1
  addsd  %xmm1,%xmm0
  ret
L6:
  add    $0xf4240,%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  sub    $0x1,%edx
  cvtsi2sd %rax,%xmm0
  mulsd  D7(%rip),%xmm0
  cvtsi2sd %edx,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: byte[8]

tool: {"D7": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double deltaT(struct timeval *tin, struct timeval *tout) {
  long usec;
  double sec;
  usec = tout->tv_usec - tin->tv_usec;
  if (usec < 0) {
    sec = tout->tv_sec - tin->tv_sec - 1 + ((double)(usec + 1000000)) * 1e-6;
  } else {
    sec = tout->tv_sec - tin->tv_sec + ((double)usec) * 1e-6;
  }
  return sec;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<deltaT>:
  endbr64
  mov    0x8(%rsi),%edx
  mov    (%rsi),%rax
  sub    0x8(%rdi),%edx
  sub    (%rdi),%rax
  js     L1
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm0
  mulsd  D16(%rip),%xmm0
  cvtsi2sd %edx,%xmm1
  addsd  %xmm1,%xmm0
  ret
L1:
  add    $0xf4240,%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  sub    $0x1,%edx
  cvtsi2sd %rax,%xmm0
  mulsd  D16(%rip),%xmm0
  cvtsi2sd %edx,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type: byte[8]

tool: {"D16": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double deltaT(struct timeval *tin, struct timeval *tout) {
  long usec;
  double sec;
  usec = tout->tv_usec - tin->tv_usec;
  if (usec < 0) {
    sec = tout->tv_sec - tin->tv_sec - 1 + ((double)(usec + 1000000)) * 1e-6;
  } else {
    sec = tout->tv_sec - tin->tv_sec + ((double)usec) * 1e-6;
  }
  return sec;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<choicer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string

tool: D6: 
What do you want to do?
1: Insert a value at beginning
2: Insert a value at end
3: Delete a value at beginning
4: Delete a value at end
5: Insert a value in some middle position
6: Delete a value in some middle position
7: Search for a value
8: Print your list
9: Insert a value in order
10: Sequential sort
0: Quit
Type the number corresponding your choice: 

tool: D2: %d

assistant: ```c
int choicer() {
  int choice;
  printf("\nWhat do you want to do?\n"
         "1: Insert a value at beginning\n"
         "2: Insert a value at end\n"
         "3: Delete a value at beginning\n"
         "4: Delete a value at end\n"
         "5: Insert a value in some middle position\n"
         "6: Delete a value in some middle position\n"
         "7: Search for a value\n"
         "8: Print your list\n"
         "9: Insert a value in order\n"
         "10: Sequential sort\n"
         "0: Quit\n"
         "Type the number corresponding your choice: ");
  scanf("%d", &choice);
  return choice;
}
```
user: Translate the below assembly code into C programming language:

```asm
<choicer>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
data_type: string
name: parse_data
arguments: data_label: D6
data_type: string

tool: D16: 
What do you want to do?
1: Insert a value at beginning
2: Insert a value at end
3: Delete a value at beginning
4: Delete a value at end
5: Insert a value in some middle position
6: Delete a value in some middle position
7: Search for a value
8: Print your list
9: Insert a value in order
10: Sequential sort
0: Quit
Type the number corresponding your choice: 

tool: D6: %d

assistant: ```c
int choicer() {
  int choice;
  printf("\nWhat do you want to do?\n"
         "1: Insert a value at beginning\n"
         "2: Insert a value at end\n"
         "3: Delete a value at beginning\n"
         "4: Delete a value at end\n"
         "5: Insert a value in some middle position\n"
         "6: Delete a value in some middle position\n"
         "7: Search for a value\n"
         "8: Print your list\n"
         "9: Insert a value in order\n"
         "10: Sequential sort\n"
         "0: Quit\n"
         "Type the number corresponding your choice: ");
  scanf("%d", &choice);
  return choice;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<choicer>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D8
data_type: string

tool: D1: 
What do you want to do?
1: Insert a value at beginning
2: Insert a value at end
3: Delete a value at beginning
4: Delete a value at end
5: Insert a value in some middle position
6: Delete a value in some middle position
7: Search for a value
8: Print your list
9: Insert a value in order
10: Sequential sort
0: Quit
Type the number corresponding your choice: 

tool: D8: %d

assistant: ```c
int choicer() {
  int choice;
  printf("\nWhat do you want to do?\n"
         "1: Insert a value at beginning\n"
         "2: Insert a value at end\n"
         "3: Delete a value at beginning\n"
         "4: Delete a value at end\n"
         "5: Insert a value in some middle position\n"
         "6: Delete a value in some middle position\n"
         "7: Search for a value\n"
         "8: Print your list\n"
         "9: Insert a value in order\n"
         "10: Sequential sort\n"
         "0: Quit\n"
         "Type the number corresponding your choice: ");
  scanf("%d", &choice);
  return choice;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<choicer>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string

tool: D11: 
What do you want to do?
1: Insert a value at beginning
2: Insert a value at end
3: Delete a value at beginning
4: Delete a value at end
5: Insert a value in some middle position
6: Delete a value in some middle position
7: Search for a value
8: Print your list
9: Insert a value in order
10: Sequential sort
0: Quit
Type the number corresponding your choice: 

tool: D0: %d

assistant: ```c
int choicer() {
  int choice;
  printf("\nWhat do you want to do?\n"
         "1: Insert a value at beginning\n"
         "2: Insert a value at end\n"
         "3: Delete a value at beginning\n"
         "4: Delete a value at end\n"
         "5: Insert a value in some middle position\n"
         "6: Delete a value in some middle position\n"
         "7: Search for a value\n"
         "8: Print your list\n"
         "9: Insert a value in order\n"
         "10: Sequential sort\n"
         "0: Quit\n"
         "Type the number corresponding your choice: ");
  scanf("%d", &choice);
  return choice;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bdivide_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  mov    %rdx,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L10
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  add    $0x1,%rax
  jmp    L13
L10:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
L13:
  pop    %rbp
  ret
```

assistant: ```c
size_t bdivide_up(size_t a, size_t b) {
  size_t r = a % b;
  return (r > 0 ? a / b + 1 : a / b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bdivide_up>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rsi
  test   %rdx,%rdx
  je     L8
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rsi
  add    $0x1,%rax
  ret
L8:
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rsi
  ret
```

assistant: ```c
size_t bdivide_up(size_t a, size_t b) {
  size_t r = a % b;
  return (r > 0 ? a / b + 1 : a / b);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bdivide_up>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rsi
  cmp    $0x1,%rdx
  sbb    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
size_t bdivide_up(size_t a, size_t b) {
  size_t r = a % b;
  return (r > 0 ? a / b + 1 : a / b);
}
```