ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<VDP_fadeTo>:
  endbr64
  push   %r15
  push   %r14
  movzwl %di,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x88(%rsp)
  xor    %edx,%edx
  mov    %esi,%edx
  mov    %rsp,%r15
  sub    %edi,%edx
  mov    %r15,%rsi
  mov    %r14d,%edi
  add    $0x1,%edx
  movzwl %dx,%edx
  call   <VDP_getPaletteColors@plt>
  movzwl %bx,%esi
  movzbl %r12b,%r9d
  movzwl %bp,%r8d
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    %r14d,%edi
  call   <VDP_fade@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void VDP_fadeTo(unsigned short fromcol, unsigned short tocol, const unsigned short *pal, unsigned short numframe, unsigned char async) {
  unsigned short tmp_pal[64];
  VDP_getPaletteColors(fromcol, tmp_pal, (tocol - fromcol) + 1);
  VDP_fade(fromcol, tocol, tmp_pal, pal, numframe, async);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<thr_fn2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: thread 2: ID is %u


assistant: ```c
void *thr_fn2(void *arg) {
  printf("thread 2: ID is %u\n", (unsigned int)pthread_self());
  pthread_exit((void *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<thr_fn2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string

tool: D2: thread 2: ID is %u


assistant: ```c
void *thr_fn2(void *arg) {
  printf("thread 2: ID is %u\n", (unsigned int)pthread_self());
  pthread_exit((void *)0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thr_fn2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pthread_self@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: thread 2: ID is %u


assistant: ```c
void *thr_fn2(void *arg) {
  printf("thread 2: ID is %u\n", (unsigned int)pthread_self());
  pthread_exit((void *)0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<thr_fn2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pthread_self@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: thread 2: ID is %u


assistant: ```c
void *thr_fn2(void *arg) {
  printf("thread 2: ID is %u\n", (unsigned int)pthread_self());
  pthread_exit((void *)0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FIC_DEC_SubChInfoClean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <SubChannelOrganizationClean@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int FIC_DEC_SubChInfoClean(void) {
  SubChannelOrganizationClean();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FIC_DEC_SubChInfoClean>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <SubChannelOrganizationClean@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int FIC_DEC_SubChInfoClean(void) {
  SubChannelOrganizationClean();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FIC_DEC_SubChInfoClean>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SubChannelOrganizationClean@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int FIC_DEC_SubChInfoClean(void) {
  SubChannelOrganizationClean();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FIC_DEC_SubChInfoClean>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SubChannelOrganizationClean@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int FIC_DEC_SubChInfoClean(void) {
  SubChannelOrganizationClean();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x19c,-0x18(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x1000000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1000000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  movq   $0x0,-0x20(%rbp)
  jmp    L4
L0:
  addq   $0x1,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string

tool: D7: rb

tool: D18: BPRE0.gba

assistant: ```c
int main(int argc, char **argv) {
  uint8_t *buffer;
  FILE *rom;
  size_t i = 0, totalPokemon = 412;
  rom = fopen("BPRE0.gba", "rb");
  buffer = (uint8_t *)malloc(1 << 24);
  fread(buffer, 1, 1 << 24, rom);
  fclose(rom);
  for (i = 0; i < totalPokemon; ++i) {
  }
  free(buffer);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D14(%rip),%rsi
  lea    D19(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0x1000000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rcx
  mov    $0x1000000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x19c,%eax
L5:
  sub    $0x1,%rax
  jne    L5
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D19
datatype: string

tool: D14: rb

tool: D19: BPRE0.gba

assistant: ```c
int main(int argc, char **argv) {
  uint8_t *buffer;
  FILE *rom;
  size_t i = 0, totalPokemon = 412;
  rom = fopen("BPRE0.gba", "rb");
  buffer = (uint8_t *)malloc(1 << 24);
  fread(buffer, 1, 1 << 24, rom);
  fclose(rom);
  for (i = 0; i < totalPokemon; ++i) {
  }
  free(buffer);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rsi
  lea    D11(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    $0x1000000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    $0x1000000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fread@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D11
datatype: string

tool: D12: rb

tool: D11: BPRE0.gba

assistant: ```c
int main(int argc, char **argv) {
  uint8_t *buffer;
  FILE *rom;
  size_t i = 0, totalPokemon = 412;
  rom = fopen("BPRE0.gba", "rb");
  buffer = (uint8_t *)malloc(1 << 24);
  fread(buffer, 1, 1 << 24, rom);
  fclose(rom);
  for (i = 0; i < totalPokemon; ++i) {
  }
  free(buffer);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%rsi
  lea    D8(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    $0x1000000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    $0x1000000,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fread@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D1: rb

tool: D8: BPRE0.gba

assistant: ```c
int main(int argc, char **argv) {
  uint8_t *buffer;
  FILE *rom;
  size_t i = 0, totalPokemon = 412;
  rom = fopen("BPRE0.gba", "rb");
  buffer = (uint8_t *)malloc(1 << 24);
  fread(buffer, 1, 1 << 24, rom);
  fclose(rom);
  for (i = 0; i < totalPokemon; ++i) {
  }
  free(buffer);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iupStrDupUntil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %al,-0x2c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L57
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L84
L57:
  mov    $0x0,%eax
  jmp    L67
L84:
  movsbl -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L56
  mov    $0x0,%eax
  jmp    L67
L56:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L67
L38:
  movl   $0x0,-0x18(%rbp)
  jmp    L34
L0:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L34:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
L67:
  leave
  ret
```

assistant: ```c
char *iupStrDupUntil(const char **str, char c) {
  const char *p_str;
  char *new_str;
  if (!str || str[0] == 0)
    return NULL;
  p_str = strchr(*str, c);
  if (!p_str)
    return NULL;
  else {
    int i;
    int sl = (int)(p_str - (*str));
    new_str = (char *)malloc(sl + 1);
    if (!new_str)
      return NULL;
    for (i = 0; i < sl; ++i)
      new_str[i] = (*str)[i];
    new_str[sl] = 0;
    *str = p_str + 1;
    return new_str;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<iupStrDupUntil>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L43
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L43
  movsbl %sil,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L47
  mov    %rax,%r12
  sub    (%rbx),%r12
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    $0x0,%edi
  test   %rax,%rax
  je     L43
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L68
  lea    -0x1(%r12),%esi
  mov    $0x0,%edx
L44:
  mov    (%rbx),%rcx
  movzbl (%rcx,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rsi,%rcx
  jne    L44
L68:
  movslq %r12d,%r12
  movb   $0x0,(%rax,%r12,1)
  add    $0x1,%rbp
  mov    %rbp,(%rbx)
L43:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    %rax,%rdi
  jmp    L43
```

assistant: ```c
char *iupStrDupUntil(const char **str, char c) {
  const char *p_str;
  char *new_str;
  if (!str || str[0] == 0)
    return NULL;
  p_str = strchr(*str, c);
  if (!p_str)
    return NULL;
  else {
    int i;
    int sl = (int)(p_str - (*str));
    new_str = (char *)malloc(sl + 1);
    if (!new_str)
      return NULL;
    for (i = 0; i < sl; ++i)
      new_str[i] = (*str)[i];
    new_str[sl] = 0;
    *str = p_str + 1;
    return new_str;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<iupStrDupUntil>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L20
  movsbl %sil,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L20
  mov    %rax,%r12
  sub    (%rbx),%r12
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L20
  mov    %rax,%r8
  test   %r12d,%r12d
  jle    L10
  lea    -0x1(%r12),%esi
  xor    %edx,%edx
  nopl   0x0(%rax)
L36:
  mov    (%rbx),%rcx
  movzbl (%rcx,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rsi,%rcx
  jne    L36
L10:
  movslq %r12d,%r12
  add    $0x1,%rbp
  movb   $0x0,(%rax,%r12,1)
  mov    %r8,%rax
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L20:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *iupStrDupUntil(const char **str, char c) {
  const char *p_str;
  char *new_str;
  if (!str || str[0] == 0)
    return NULL;
  p_str = strchr(*str, c);
  if (!p_str)
    return NULL;
  else {
    int i;
    int sl = (int)(p_str - (*str));
    new_str = (char *)malloc(sl + 1);
    if (!new_str)
      return NULL;
    for (i = 0; i < sl; ++i)
      new_str[i] = (*str)[i];
    new_str[sl] = 0;
    *str = p_str + 1;
    return new_str;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iupStrDupUntil>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
  movsbl %sil,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
  mov    %rax,%r12
  sub    (%rbx),%r12
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%r8
  test   %r12d,%r12d
  jle    L39
  lea    -0x1(%r12),%esi
  xor    %edx,%edx
  nopl   0x0(%rax)
L57:
  mov    (%rbx),%rcx
  movzbl (%rcx,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rsi,%rcx
  jne    L57
L39:
  movslq %r12d,%r12
  add    $0x1,%rbp
  movb   $0x0,(%rax,%r12,1)
  mov    %r8,%rax
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L8:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *iupStrDupUntil(const char **str, char c) {
  const char *p_str;
  char *new_str;
  if (!str || str[0] == 0)
    return NULL;
  p_str = strchr(*str, c);
  if (!p_str)
    return NULL;
  else {
    int i;
    int sl = (int)(p_str - (*str));
    new_str = (char *)malloc(sl + 1);
    if (!new_str)
      return NULL;
    for (i = 0; i < sl; ++i)
      new_str[i] = (*str)[i];
    new_str[sl] = 0;
    *str = p_str + 1;
    return new_str;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<leitor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <lendo@plt>
  jmp    L2
```

assistant: ```c
void *leitor(void *ptr) {
  int indice = (int)(size_t)ptr;
  while (1) {
    lendo(indice);
  }
  pthread_exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<leitor>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
L7:
  mov    %ebx,%edi
  call   <lendo@plt>
  jmp    L7
```

assistant: ```c
void *leitor(void *ptr) {
  int indice = (int)(size_t)ptr;
  while (1) {
    lendo(indice);
  }
  pthread_exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<leitor>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  call   <lendo@plt>
  jmp    L4
```

assistant: ```c
void *leitor(void *ptr) {
  int indice = (int)(size_t)ptr;
  while (1) {
    lendo(indice);
  }
  pthread_exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<leitor>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  call   <lendo@plt>
  jmp    L9
```

assistant: ```c
void *leitor(void *ptr) {
  int indice = (int)(size_t)ptr;
  while (1) {
    lendo(indice);
  }
  pthread_exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CompBaseAmpMedianMethod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x44(%rbp),%eax
  add    $0x1,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x44(%rbp),%eax
  add    $0x1,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L8
L57:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x20(%rbp)
L8:
  mov    -0x44(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L57
  mov    -0x44(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <doubleBubbleSort@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L11
L24:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x24(%rbp)
  addl   $0x1,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jle    L24
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L43
L31:
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x1c(%rbp)
L43:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x1c(%rbp)
  jl     L31
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double CompBaseAmpMedianMethod(const int *SegLen, const double *SegAmp, int K) {
  int M, k, RunLen;
  double BaseAmp = 0;
  double *D;
  int *I;
  D = calloc(K + 1, sizeof(double));
  I = calloc(K + 1, sizeof(double));
  for (k = 0; k < K + 1; k++) {
    D[k] = SegAmp[k];
    I[k] = SegLen[k];
  }
  doubleBubbleSort(D, I, K + 1);
  SegAmp = D;
  SegLen = I;
  M = 0;
  for (k = 0; k <= K; k++)
    M = M + SegLen[k];
  RunLen = 0;
  k = 0;
  while (RunLen < M / 2)
    RunLen = RunLen + SegLen[k++];
  BaseAmp = SegAmp[k - 1];
  return BaseAmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CompBaseAmpMedianMethod>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%r14d
  lea    0x1(%rdx),%r15d
  mov    $0x8,%esi
  mov    %r15d,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    $0x8,%esi
  mov    %r15d,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %r14d,%r14d
  js     L63
  mov    %r14d,%r14d
  lea    0x4(,%r14,4),%rcx
  mov    $0x0,%eax
L53:
  movsd  0x0(%r13,%rax,2),%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,2)
  mov    (%r12,%rax,1),%edx
  mov    %edx,(%rbx,%rax,1)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L53
  mov    %r15d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <doubleBubbleSort@plt>
  mov    %rbx,%rax
  lea    0x4(%rbx,%r14,4),%rcx
  mov    $0x0,%edx
L37:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L37
  mov    %edx,%esi
  shr    $0x1f,%esi
  add    %edx,%esi
  sar    %esi
  cmp    $0x1,%edx
  jle    L3
  mov    $0x1,%eax
  mov    $0x0,%ecx
L43:
  mov    %eax,%edi
  add    -0x4(%rbx,%rax,4),%ecx
  add    $0x1,%rax
  cmp    %esi,%ecx
  jl     L43
L13:
  movslq %edi,%rdi
  movsd  -0x8(%rbp,%rdi,8),%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  mov    $0x0,%edi
  jmp    L13
L63:
  mov    %r15d,%edx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <doubleBubbleSort@plt>
  mov    $0x0,%edi
  jmp    L13
```

assistant: ```c
double CompBaseAmpMedianMethod(const int *SegLen, const double *SegAmp, int K) {
  int M, k, RunLen;
  double BaseAmp = 0;
  double *D;
  int *I;
  D = calloc(K + 1, sizeof(double));
  I = calloc(K + 1, sizeof(double));
  for (k = 0; k < K + 1; k++) {
    D[k] = SegAmp[k];
    I[k] = SegLen[k];
  }
  doubleBubbleSort(D, I, K + 1);
  SegAmp = D;
  SegLen = I;
  M = 0;
  for (k = 0; k <= K; k++)
    M = M + SegLen[k];
  RunLen = 0;
  k = 0;
  while (RunLen < M / 2)
    RunLen = RunLen + SegLen[k++];
  BaseAmp = SegAmp[k - 1];
  return BaseAmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CompBaseAmpMedianMethod>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  mov    $0x8,%esi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x1(%rbx),%r15d
  mov    %r15d,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    $0x8,%esi
  mov    %r15d,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  js     L0
  lea    0x4(,%rbx,4),%rbx
  xor    %eax,%eax
  nopl   0x0(%rax)
L7:
  movsd  (%r14,%rax,2),%xmm0
  mov    0x0(%r13,%rax,1),%edx
  movsd  %xmm0,(%r12,%rax,2)
  mov    %edx,0x0(%rbp,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rbx
  jne    L7
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    %rbp,%rbx
  call   <doubleBubbleSort@plt>
  mov    %rbp,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L22:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rax,%rbx
  jne    L22
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %edx,%ecx
  sar    %ecx
  cmp    $0x1,%edx
  jle    L26
  mov    $0x1,%eax
  xor    %edx,%edx
L46:
  add    -0x4(%rbp,%rax,4),%edx
  movslq %eax,%rsi
  add    $0x1,%rax
  cmp    %ecx,%edx
  jl     L46
  lea    -0x8(,%rsi,8),%rax
L33:
  movsd  (%r12,%rax,1),%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L0:
  mov    %r15d,%edx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <doubleBubbleSort@plt>
L26:
  mov    $0xfffffffffffffff8,%rax
  jmp    L33
```

assistant: ```c
double CompBaseAmpMedianMethod(const int *SegLen, const double *SegAmp, int K) {
  int M, k, RunLen;
  double BaseAmp = 0;
  double *D;
  int *I;
  D = calloc(K + 1, sizeof(double));
  I = calloc(K + 1, sizeof(double));
  for (k = 0; k < K + 1; k++) {
    D[k] = SegAmp[k];
    I[k] = SegLen[k];
  }
  doubleBubbleSort(D, I, K + 1);
  SegAmp = D;
  SegLen = I;
  M = 0;
  for (k = 0; k <= K; k++)
    M = M + SegLen[k];
  RunLen = 0;
  k = 0;
  while (RunLen < M / 2)
    RunLen = RunLen + SegLen[k++];
  BaseAmp = SegAmp[k - 1];
  return BaseAmp;
}
```