ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ucShift>:
  endbr64
  movslq %edx,%rax
  push   %r12
  test   %eax,%eax
  je     L134
  test   %esi,%esi
  je     L134
  cmp    %eax,%esi
  jle    L97
  mov    %eax,%ecx
  neg    %ecx
  cmp    %ecx,%esi
  jle    L97
  cmp    $0x1,%eax
  je     L35
  cmp    $0xffffffff,%eax
  je     L100
  lea    -0x1(%rsi),%edx
  xor    %r12d,%r12d
  test   %eax,%eax
  jle    L126
L122:
  test   %edx,%edx
  js     L79
  sub    $0x1,%edx
  mov    $0x1,%esi
  movslq %edx,%rdx
  sub    %eax,%esi
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L139:
  lea    (%rsi,%rdx,1),%ecx
  movslq %ecx,%rcx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,0x1(%rdi,%rdx,1)
L48:
  sub    $0x1,%rdx
L76:
  lea    0x1(%rdx),%ecx
  cmp    %eax,%ecx
  jge    L139
  movb   $0x0,0x1(%rdi,%rdx,1)
  test   %edx,%edx
  jns    L48
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L97:
  cmp    $0x1,%eax
  je     L87
  xor    %r12d,%r12d
  cmp    $0xffffffff,%eax
  je     L146
L21:
  call   <vSetZero@plt>
L79:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L134:
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L35:
  lea    -0x1(%rsi),%ecx
  movzbl (%rdi,%rcx,1),%r12d
  mov    %rcx,%rdx
  jmp    L122
L146:
  movzbl (%rdi),%r12d
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L87:
  lea    -0x1(%rsi),%eax
  movzbl (%rdi,%rax,1),%r12d
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L100:
  movzbl (%rdi),%r12d
L126:
  test   %esi,%esi
  jle    L79
  movslq %ecx,%rcx
  mov    %esi,%r8d
  mov    %rcx,%rdx
  add    %rcx,%rdi
  sub    %eax,%r8d
  nopw   0x0(%rax,%rax,1)
L75:
  xor    %ecx,%ecx
  cmp    %edx,%esi
  jle    L16
  movzbl (%rdi),%ecx
L16:
  add    $0x1,%edx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rdi
  cmp    %r8d,%edx
  jne    L75
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned char ucShift(unsigned char *psA, unsigned int uiLen, int iShift) {
  unsigned char ucRet;
  int i;
  if (iShift == 0 || uiLen == 0)
    return (0);
  if (iShift >= (int)uiLen || -iShift >= (int)uiLen) {
    if (iShift == 1)
      ucRet = psA[uiLen - 1];
    else if (iShift == -1)
      ucRet = psA[0];
    else
      ucRet = 0;
    vSetZero(psA, uiLen);
    return (ucRet);
  }
  if (iShift == 1)
    ucRet = psA[uiLen - 1];
  else if (iShift == -1)
    ucRet = psA[0];
  else
    ucRet = 0;
  if (iShift > 0) {
    for (i = uiLen - 1; i >= 0; i--) {
      if (i >= iShift)
        psA[i] = psA[i - iShift];
      else
        psA[i] = 0;
    }
  } else {
    iShift = -iShift;
    for (i = 0; i < (int)uiLen; i++) {
      if (i + iShift < (int)uiLen)
        psA[i] = psA[i + iShift];
      else
        psA[i] = 0;
    }
  }
  return (ucRet);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ucShift>:
  endbr64
  movslq %edx,%rax
  push   %r12
  test   %eax,%eax
  je     L33
  test   %esi,%esi
  je     L33
  cmp    %eax,%esi
  jle    L166
  mov    %eax,%ecx
  neg    %ecx
  cmp    %ecx,%esi
  jle    L166
  cmp    $0x1,%eax
  je     L116
  cmp    $0xffffffff,%eax
  je     L67
  lea    -0x1(%rsi),%edx
  xor    %r12d,%r12d
  test   %eax,%eax
  jle    L160
L17:
  test   %edx,%edx
  js     L70
  sub    $0x1,%edx
  mov    $0x1,%esi
  movslq %edx,%rdx
  sub    %eax,%esi
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L113:
  lea    (%rsi,%rdx,1),%ecx
  movslq %ecx,%rcx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,0x1(%rdi,%rdx,1)
L57:
  sub    $0x1,%rdx
L13:
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%eax
  jle    L113
  movb   $0x0,0x1(%rdi,%rdx,1)
  test   %edx,%edx
  jns    L57
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L166:
  cmp    $0x1,%eax
  je     L32
  xor    %r12d,%r12d
  cmp    $0xffffffff,%eax
  je     L58
L28:
  call   <vSetZero@plt>
L70:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L116:
  lea    -0x1(%rsi),%ecx
  movzbl (%rdi,%rcx,1),%r12d
  mov    %rcx,%rdx
  jmp    L17
L58:
  movzbl (%rdi),%r12d
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L32:
  lea    -0x1(%rsi),%eax
  movzbl (%rdi,%rax,1),%r12d
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L67:
  movzbl (%rdi),%r12d
L160:
  test   %esi,%esi
  jle    L70
  movslq %ecx,%rcx
  mov    %rcx,%rdx
  add    %rcx,%rdi
  mov    %esi,%ecx
  sub    %eax,%ecx
  nopl   (%rax)
L87:
  cmp    %edx,%esi
  jle    L29
L48:
  movzbl (%rdi),%r8d
  add    $0x1,%edx
  add    $0x1,%rdi
  mov    %r8b,-0x1(%rdi,%rax,1)
  cmp    %ecx,%edx
  je     L70
  cmp    %edx,%esi
  jg     L48
L29:
  add    $0x1,%edx
  movb   $0x0,(%rdi,%rax,1)
  add    $0x1,%rdi
  cmp    %ecx,%edx
  jne    L87
  jmp    L70
```

assistant: ```c
unsigned char ucShift(unsigned char *psA, unsigned int uiLen, int iShift) {
  unsigned char ucRet;
  int i;
  if (iShift == 0 || uiLen == 0)
    return (0);
  if (iShift >= (int)uiLen || -iShift >= (int)uiLen) {
    if (iShift == 1)
      ucRet = psA[uiLen - 1];
    else if (iShift == -1)
      ucRet = psA[0];
    else
      ucRet = 0;
    vSetZero(psA, uiLen);
    return (ucRet);
  }
  if (iShift == 1)
    ucRet = psA[uiLen - 1];
  else if (iShift == -1)
    ucRet = psA[0];
  else
    ucRet = 0;
  if (iShift > 0) {
    for (i = uiLen - 1; i >= 0; i--) {
      if (i >= iShift)
        psA[i] = psA[i - iShift];
      else
        psA[i] = 0;
    }
  } else {
    iShift = -iShift;
    for (i = 0; i < (int)uiLen; i++) {
      if (i + iShift < (int)uiLen)
        psA[i] = psA[i + iShift];
      else
        psA[i] = 0;
    }
  }
  return (ucRet);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bson_next>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L47
  mov    $0x0,%eax
  jmp    L100
L47:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <bson_skip_field_name@plt>
  mov    %rax,-0x18(%rbp)
  movzbl -0x5(%rbp),%eax
  cmp    $0x7f,%eax
  jg     L175
  test   %eax,%eax
  jle    L121
  cmp    $0x7f,%eax
  ja     L121
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D11(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L175:
  cmp    $0xff,%eax
  je     L171
  jmp    L121
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  jmp    L100
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L100
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L100
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x5(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L100
L171:
  mov    -0x18(%rbp),%rax
  jmp    L100
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  jmp    L100
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  jmp    L100
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  jmp    L100
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  add    $0x1,%eax
  cltq
  jmp    L100
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x10(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L100
  mov    $0xfffffffd,%edi
  call   <exit@plt>
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  jmp    L100
L121:
  mov    $0x0,%eax
L100:
  leave
  ret
```

assistant: ```c
char *bson_next(char *data) {
  unsigned char type = data[0];
  int32_t length;
  if (type == 0) {
    return NULL;
  }
  data = bson_skip_field_name(data + 1);
  switch (type) {
  case 0x01:
    return data + sizeof(double);
  case 0x02:
  case 0x0D:
  case 0x0E:
    length = (*(int *)data);
    return data + sizeof(int32_t) + length;
  case 0x03:
  case 0x04:
    length = (*(int *)data);
    return data + length;
  case 0x05:
    length = (*(int *)data);
    return data + sizeof(int32_t) + 1 + length;
  case 0x06:
  case 0x0A:
  case 0xFF:
  case 0x7F:
    return data;
  case 0x07:
    return data + 12;
  case 0x08:
    return data + 1;
  case 0x09:
  case 0x11:
  case 0x12:
    return data + sizeof(int64_t);
  case 0x0B:
    return strchr(data, '\0') + 1;
  case 0x0C:
    length = (*(int *)data);
    return data + sizeof(int32_t) + length + 12;
  case 0x0F:
    exit(-3);
  case 0x10:
    return data + sizeof(int32_t);
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bson_next>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L2
  add    $0x1,%rdi
  call   <bson_skip_field_name@plt>
  mov    %rax,%r12
  test   %bl,%bl
  js     L0
  cmp    $0x7f,%bl
  ja     L23
  lea    D6(%rip),%rdx
  movslq (%rdx,%rbx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %r12d,%r12d
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  cmp    $0xff,%bl
  cmovne %rax,%r12
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %r12
  ret
  mov    $0xfffffffd,%edi
  call   <exit@plt>
  add    $0x4,%r12
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
  movslq (%r12),%rax
  lea    0x4(%r12,%rax,1),%r12
  jmp    L2
  nopl   0x0(%rax,%rax,1)
  movslq (%r12),%rax
  add    %rax,%r12
  jmp    L2
  add    $0x1,%r12
  jmp    L2
  add    $0xc,%r12
  jmp    L2
  movslq (%r12),%rax
  lea    0x5(%r12,%rax,1),%r12
  jmp    L2
  add    $0x8,%r12
  jmp    L2
  movslq (%r12),%rax
  lea    0x10(%r12,%rax,1),%r12
  jmp    L2
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <strchr@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  jmp    L2
```

assistant: ```c
char *bson_next(char *data) {
  unsigned char type = data[0];
  int32_t length;
  if (type == 0) {
    return NULL;
  }
  data = bson_skip_field_name(data + 1);
  switch (type) {
  case 0x01:
    return data + sizeof(double);
  case 0x02:
  case 0x0D:
  case 0x0E:
    length = (*(int *)data);
    return data + sizeof(int32_t) + length;
  case 0x03:
  case 0x04:
    length = (*(int *)data);
    return data + length;
  case 0x05:
    length = (*(int *)data);
    return data + sizeof(int32_t) + 1 + length;
  case 0x06:
  case 0x0A:
  case 0xFF:
  case 0x7F:
    return data;
  case 0x07:
    return data + 12;
  case 0x08:
    return data + 1;
  case 0x09:
  case 0x11:
  case 0x12:
    return data + sizeof(int64_t);
  case 0x0B:
    return strchr(data, '\0') + 1;
  case 0x0C:
    length = (*(int *)data);
    return data + sizeof(int32_t) + length + 12;
  case 0x0F:
    exit(-3);
  case 0x10:
    return data + sizeof(int32_t);
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bson_next>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L108
  add    $0x1,%rdi
  call   <bson_skip_field_name@plt>
  mov    %rax,%r12
  test   %bl,%bl
  js     L42
  cmp    $0x7f,%bl
  ja     L68
  lea    D2(%rip),%rdx
  movslq (%rdx,%rbx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
L68:
  xor    %r12d,%r12d
L108:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L42:
  xor    %eax,%eax
  cmp    $0xff,%bl
  cmovne %rax,%r12
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %r12
  ret
  mov    $0xfffffffd,%edi
  call   <exit@plt>
  add    $0x4,%r12
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
  movslq (%r12),%rax
  lea    0x4(%r12,%rax,1),%r12
  jmp    L108
  nopl   0x0(%rax,%rax,1)
  movslq (%r12),%rax
  add    %rax,%r12
  jmp    L108
  add    $0x1,%r12
  jmp    L108
  add    $0xc,%r12
  jmp    L108
  movslq (%r12),%rax
  lea    0x5(%r12,%rax,1),%r12
  jmp    L108
  add    $0x8,%r12
  jmp    L108
  movslq (%r12),%rax
  lea    0x10(%r12,%rax,1),%r12
  jmp    L108
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <strchr@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  jmp    L108
```

assistant: ```c
char *bson_next(char *data) {
  unsigned char type = data[0];
  int32_t length;
  if (type == 0) {
    return NULL;
  }
  data = bson_skip_field_name(data + 1);
  switch (type) {
  case 0x01:
    return data + sizeof(double);
  case 0x02:
  case 0x0D:
  case 0x0E:
    length = (*(int *)data);
    return data + sizeof(int32_t) + length;
  case 0x03:
  case 0x04:
    length = (*(int *)data);
    return data + length;
  case 0x05:
    length = (*(int *)data);
    return data + sizeof(int32_t) + 1 + length;
  case 0x06:
  case 0x0A:
  case 0xFF:
  case 0x7F:
    return data;
  case 0x07:
    return data + 12;
  case 0x08:
    return data + 1;
  case 0x09:
  case 0x11:
  case 0x12:
    return data + sizeof(int64_t);
  case 0x0B:
    return strchr(data, '\0') + 1;
  case 0x0C:
    length = (*(int *)data);
    return data + sizeof(int32_t) + length + 12;
  case 0x0F:
    exit(-3);
  case 0x10:
    return data + sizeof(int32_t);
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<occupied>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L49:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L36
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <equal@plt>
  test   %rax,%rax
  je     L36
  mov    $0x1,%eax
  jmp    L28
L36:
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0xa,-0x4(%rbp)
  jle    L49
  mov    $0x0,%eax
L28:
  leave
  ret
```

assistant: ```c
int occupied(int ptrA) {
  for (int ptrB = 0; ptrB < 11; ptrB++) {
    if (ptrA != ptrB && equal(ptrA, ptrB)) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<occupied>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
  jmp    L49
L34:
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  je     L44
L49:
  cmp    %ebx,%ebp
  je     L34
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <equal@plt>
  test   %rax,%rax
  je     L34
  mov    $0x1,%eax
  jmp    L12
L44:
  mov    $0x0,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int occupied(int ptrA) {
  for (int ptrB = 0; ptrB < 11; ptrB++) {
    if (ptrA != ptrB && equal(ptrA, ptrB)) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<occupied>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L10:
  cmp    %ebx,%ebp
  je     L27
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <equal@plt>
  test   %rax,%rax
  jne    L19
L27:
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L10
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int occupied(int ptrA) {
  for (int ptrB = 0; ptrB < 11; ptrB++) {
    if (ptrA != ptrB && equal(ptrA, ptrB)) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<occupied>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L16:
  cmp    %ebx,%ebp
  je     L10
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <equal@plt>
  test   %rax,%rax
  jne    L12
L10:
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L16
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int occupied(int ptrA) {
  for (int ptrB = 0; ptrB < 11; ptrB++) {
    if (ptrA != ptrB && equal(ptrA, ptrB)) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inverse_mod26>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1a,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x19,-0x4(%rbp)
  ja     L120
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D17(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  jmp    L40
  mov    $0x9,%eax
  jmp    L40
  mov    $0x15,%eax
  jmp    L40
  mov    $0xf,%eax
  jmp    L40
  mov    $0x3,%eax
  jmp    L40
  mov    $0x13,%eax
  jmp    L40
  mov    $0x7,%eax
  jmp    L40
  mov    $0x17,%eax
  jmp    L40
  mov    $0xb,%eax
  jmp    L40
  mov    $0x5,%eax
  jmp    L40
  mov    $0x11,%eax
  jmp    L40
  mov    $0x19,%eax
  jmp    L40
L120:
  mov    $0x0,%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int inverse_mod26(int d) {
  d = (d + 26) % 26;
  switch (d) {
  case 1:
    return 1;
  case 3:
    return 9;
  case 5:
    return 21;
  case 7:
    return 15;
  case 9:
    return 3;
  case 11:
    return 19;
  case 15:
    return 7;
  case 17:
    return 23;
  case 19:
    return 11;
  case 21:
    return 5;
  case 23:
    return 17;
  case 25:
    return 25;
  default:
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<inverse_mod26>:
  endbr64
  add    $0x1a,%edi
  movslq %edi,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x23,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x1a,%eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  cmp    $0x19,%eax
  ja     L2
  mov    %eax,%edx
  lea    D4(%rip),%rcx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0x9,%eax
  ret
  mov    $0x15,%eax
  ret
  mov    $0xf,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x13,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x17,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x11,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int inverse_mod26(int d) {
  d = (d + 26) % 26;
  switch (d) {
  case 1:
    return 1;
  case 3:
    return 9;
  case 5:
    return 21;
  case 7:
    return 15;
  case 9:
    return 3;
  case 11:
    return 19;
  case 15:
    return 7;
  case 17:
    return 23;
  case 19:
    return 11;
  case 21:
    return 5;
  case 23:
    return 17;
  case 25:
    return 25;
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inverse_mod26>:
  endbr64
  add    $0x1a,%edi
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%edi
  xor    %eax,%eax
  sub    $0x1,%edi
  cmp    $0x18,%edi
  ja     L9
  lea    D6(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L9:
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: 

assistant: ```c
int inverse_mod26(int d) {
  d = (d + 26) % 26;
  switch (d) {
  case 1:
    return 1;
  case 3:
    return 9;
  case 5:
    return 21;
  case 7:
    return 15;
  case 9:
    return 3;
  case 11:
    return 19;
  case 15:
    return 7;
  case 17:
    return 23;
  case 19:
    return 11;
  case 21:
    return 5;
  case 23:
    return 17;
  case 25:
    return 25;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inverse_mod26>:
  endbr64
  add    $0x1a,%edi
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%edi
  xor    %eax,%eax
  sub    $0x1,%edi
  cmp    $0x18,%edi
  ja     L5
  lea    D1(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D1: 

assistant: ```c
int inverse_mod26(int d) {
  d = (d + 26) % 26;
  switch (d) {
  case 1:
    return 1;
  case 3:
    return 9;
  case 5:
    return 21;
  case 7:
    return 15;
  case 9:
    return 3;
  case 11:
    return 19;
  case 15:
    return 7;
  case 17:
    return 23;
  case 19:
    return 11;
  case 21:
    return 5;
  case 23:
    return 17;
  case 25:
    return 25;
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<get_cpu_speed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <system_time@plt>
  mov    %rax,-0x20(%rbp)
L13:
  mov    $0x0,%eax
  call   <system_time@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L13
  mov    $0x0,%eax
  call   <read_rdtsc@plt>
  mov    %rax,-0x10(%rbp)
L15:
  mov    $0x0,%eax
  call   <system_time@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    $0x3d08f,%rax
  jle    L15
  mov    $0x0,%eax
  call   <read_rdtsc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  shl    $0x2,%rax
  leave
  ret
```

assistant: ```c
long long get_cpu_speed() {
  long long a, b, start, end;
  a = system_time();
  do {
    b = system_time();
  } while (a == b);
  start = read_rdtsc();
  do {
    a = system_time();
  } while (a - b < 1000000 / 4);
  end = read_rdtsc();
  return (end - start) * 4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_cpu_speed>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <system_time@plt>
  mov    %rax,%rbp
L13:
  mov    $0x0,%eax
  call   <system_time@plt>
  mov    %rax,%rbx
  cmp    %rax,%rbp
  je     L13
  mov    $0x0,%eax
  call   <read_rdtsc@plt>
  mov    %rax,%rbp
L3:
  mov    $0x0,%eax
  call   <system_time@plt>
  sub    %rbx,%rax
  cmp    $0x3d08f,%rax
  jle    L3
  mov    $0x0,%eax
  call   <read_rdtsc@plt>
  sub    %rbp,%rax
  shl    $0x2,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long get_cpu_speed() {
  long long a, b, start, end;
  a = system_time();
  do {
    b = system_time();
  } while (a == b);
  start = read_rdtsc();
  do {
    a = system_time();
  } while (a - b < 1000000 / 4);
  end = read_rdtsc();
  return (end - start) * 4;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_cpu_speed>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <system_time@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <system_time@plt>
  mov    %rax,%rbx
  cmp    %rax,%rbp
  je     L8
  xor    %eax,%eax
  call   <read_rdtsc@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  call   <system_time@plt>
  sub    %rbx,%rax
  cmp    $0x3d08f,%rax
  jle    L4
  xor    %eax,%eax
  call   <read_rdtsc@plt>
  add    $0x8,%rsp
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  shl    $0x2,%rax
  ret
```

assistant: ```c
long long get_cpu_speed() {
  long long a, b, start, end;
  a = system_time();
  do {
    b = system_time();
  } while (a == b);
  start = read_rdtsc();
  do {
    a = system_time();
  } while (a - b < 1000000 / 4);
  end = read_rdtsc();
  return (end - start) * 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_cpu_speed>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <system_time@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  call   <system_time@plt>
  mov    %rax,%rbx
  cmp    %rax,%rbp
  je     L19
  xor    %eax,%eax
  call   <read_rdtsc@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  call   <system_time@plt>
  sub    %rbx,%rax
  cmp    $0x3d08f,%rax
  jle    L14
  xor    %eax,%eax
  call   <read_rdtsc@plt>
  add    $0x8,%rsp
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  shl    $0x2,%rax
  ret
```

assistant: ```c
long long get_cpu_speed() {
  long long a, b, start, end;
  a = system_time();
  do {
    b = system_time();
  } while (a == b);
  start = read_rdtsc();
  do {
    a = system_time();
  } while (a - b < 1000000 / 4);
  end = read_rdtsc();
  return (end - start) * 4;
}
```