user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4d8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    D81(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  lea    0x1c(%rsp),%r12
  mov    $0x0,%r14d
  lea    D79(%rip),%r13
L98:
  lea    -0xc(%r12),%rbx
L6:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  add    $0xa,%r14
  add    $0x28,%r12
  cmp    $0x1e,%r14
  jne    L98
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1a0(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x1ac(%rsp),%r13
  mov    %r13,%r12
  mov    $0x0,%r15d
  lea    D79(%rip),%r14
L8:
  lea    -0xc(%r12),%rbx
L63:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L63
  add    $0xa,%r15
  add    $0x28,%r12
  cmp    $0x1e,%r15
  jne    L8
  lea    D82(%rip),%rdi
  call   <puts@plt>
  lea    0x78(%rbp),%r14
  mov    %rbp,%rbx
  lea    D95(%rip),%r12
L41:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rbx
  cmp    %rbx,%r14
  jne    L41
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rbx
  lea    0x78(%rbx),%r15
  lea    D95(%rip),%r12
L39:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rbx
  cmp    %r15,%rbx
  jne    L39
  lea    0x330(%rsp),%rbx
  mov    %rbx,%r10
L76:
  mov    0x0(%rbp),%r9d
  mov    0x4(%rbp),%r8d
  mov    0x8(%rbp),%edi
  mov    %r10,%rsi
  mov    0x8(%rsp),%rax
L27:
  mov    %r9d,%ecx
  imul   (%rax),%ecx
  mov    %r8d,%edx
  imul   0x28(%rax),%edx
  add    %edx,%ecx
  mov    %edi,%edx
  imul   0x50(%rax),%edx
  add    %ecx,%edx
  mov    %edx,(%rsi)
  add    $0x4,%rax
  add    $0x4,%rsi
  cmp    %r13,%rax
  jne    L27
  add    $0x28,%r10
  add    $0x28,%rbp
  cmp    %r14,%rbp
  jne    L76
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0x78(%rbx),%r12
  lea    D95(%rip),%rbp
L33:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rbx
  cmp    %r12,%rbx
  jne    L33
  mov    0x4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x4d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D81
data_type: string
name: extract_symbolic_data
arguments: data_tag: D79
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string
name: extract_symbolic_data
arguments: data_tag: D82
data_type: string
name: extract_symbolic_data
arguments: data_tag: D95
data_type: string
name: extract_symbolic_data
arguments: data_tag: D24
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D81: 
Enter First Matrix : n

tool: D79: %d

tool: D6: 
Enter Second Matrix:n

tool: D82: The First Matrix is: 

tool: D95:  %d 

tool: D24: The Second Matrix is : 

tool: D5: 
Multiplication Of Two Matrices : 

assistant: ```c
int main() {
  int a[10][10], b[10][10], c[10][10], i, j, k;
  int sum = 0;
  printf("\nEnter First Matrix : n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%d", &a[i][j]);
    }
  }
  printf("\nEnter Second Matrix:n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      scanf("%d", &b[i][j]);
    }
  }
  printf("The First Matrix is: \n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf(" %d ", a[i][j]);
    }
    printf("\n");
  }
  printf("The Second Matrix is : \n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf(" %d ", b[i][j]);
    }
    printf("\n");
  }
  for (i = 0; i <= 2; i++) {
    for (j = 0; j <= 2; j++) {
      sum = 0;
      for (k = 0; k <= 2; k++) {
        sum = sum + a[i][k] * b[k][j];
      }
      c[i][j] = sum;
    }
  }
  printf("\nMultiplication Of Two Matrices : \n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      printf(" %d ", c[i][j]);
    }
    printf("\n");
  }
  return (0);
}
```