user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x2c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2b8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0xc(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x54,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  lea    D19(%rip),%r12
  lea    0xc(%rsp),%rbp
  lea    D1(%rip),%rbx
L12:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xc,%edx
  ja     L12
  test   $0x1,%al
  je     L12
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %edx,%r9d
  movslq %edx,%rdx
  movl   $0x1,0x10(%rsp,%rdx,4)
  mov    %eax,%ebx
  imul   %eax,%ebx
  cmp    $0x1,%ebx
  jle    L58
  add    $0x1,%ebx
  mov    $0x2,%edi
  mov    $0x0,%edx
  mov    $0x0,%r11d
  lea    -0x1(%rax),%r10d
  lea    0x10(%rsp),%rbp
  jmp    L128
L25:
  cmp    %r9d,%eax
  cmovle %r11d,%r9d
  add    $0x1,%edx
  cmovs  %r10d,%edx
  movslq %edx,%rcx
  movslq %r9d,%rsi
  lea    (%rcx,%rcx,2),%r8
  lea    (%rcx,%r8,4),%rcx
  add    %rsi,%rcx
  mov    %edi,0x10(%rsp,%rcx,4)
L60:
  add    $0x1,%edi
  cmp    %ebx,%edi
  je     L58
L128:
  lea    0x1(%r9),%ecx
  cmp    %ecx,%eax
  cmovle %r11d,%ecx
  mov    %edx,%esi
  sub    $0x1,%esi
  cmovs  %r10d,%esi
  movslq %esi,%r8
  lea    (%r8,%r8,2),%r12
  lea    (%r8,%r12,4),%r8
  movslq %ecx,%r12
  add    %r12,%r8
  lea    0x0(%rbp,%r8,4),%r8
  cmpl   $0x0,(%r8)
  jne    L25
  mov    %edi,(%r8)
  mov    %ecx,%r9d
  mov    %esi,%edx
  jmp    L60
L58:
  lea    0x10(%rsp),%rbp
  mov    $0x0,%r13d
  lea    D4(%rip),%r12
  lea    D30(%rip),%r14
  jmp    L115
L10:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L10
L104:
  mov    %r14,%rdi
  call   <puts@plt>
  add    $0x1,%r13
  add    $0x34,%rbp
  cmp    %r13d,0xc(%rsp)
  jle    L92
L115:
  mov    $0x0,%ebx
  cmpl   $0x0,0xc(%rsp)
  jg     L10
  jmp    L104
L92:
  mov    0x2b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L107
  mov    $0x0,%eax
  add    $0x2c0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L107:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D4
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string

tool: D19: Please enter an odd positive integer between 1 and 13 (size of magic square):

tool: D1: %d

tool: D4: %6d 

tool: D30: 


assistant: ```c
int main(void) {
  int n = -1;
  int row = 0, column = 0, oldcol = 0, oldrow = 0;
  int msquare[13][13] = {0};
  while ((n < 1) || (n > 13) || (n % 2 == 0)) {
    printf("Please enter an odd positive integer between 1 and 13 (size of magic square):");
    scanf("%d", &n);
  }
  row = 0;
  column = n / 2;
  *((*(msquare + row)) + column) = 1;
  for (int i = 2; i <= (n * n); i++) {
    oldcol = column;
    oldrow = row;
    column++;
    row--;
    if (column >= n) {
      column = 0;
    }
    if (row < 0) {
      row = (n - 1);
    }
    if ((*((*(msquare + row)) + column)) == 0) {
      *((*(msquare + row)) + column) = i;
    } else {
      row = oldrow + 1;
      column = oldcol;
      if (column >= n) {
        column = 0;
      }
      if (row < 0) {
        row = (n - 1);
      }
      *((*(msquare + row)) + column) = i;
    }
  }
  for (int a = 0; a < n; a++) {
    for (int b = 0; b < n; b++) {
      printf("%6d ", *((*(msquare + a)) + b));
    }
    printf("\n\n");
  }
  return 0;
}
```