ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<debug_malloc_police>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void debug_malloc_police(const char *file, int line) {
  file = file;
  line = line;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<debug_malloc_police>:
  endbr64
  ret
```

assistant: ```c
void debug_malloc_police(const char *file, int line) {
  file = file;
  line = line;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<debug_malloc_police>:
  endbr64
  ret
```

assistant: ```c
void debug_malloc_police(const char *file, int line) {
  file = file;
  line = line;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<debug_malloc_police>:
  endbr64
  ret
```

assistant: ```c
void debug_malloc_police(const char *file, int line) {
  file = file;
  line = line;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fn_al_sq_qtg_1_4294967295_cl_48_57>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fn_sq_qtg_1_4294967295_cl_48_57@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L2
  mov    -0x4(%rbp),%eax
  jmp    L16
L2:
  mov    $0xffffffff,%eax
L16:
  leave
  ret
```

assistant: ```c
int fn_al_sq_qtg_1_4294967295_cl_48_57(const char *text) {
  int pos = 0;
  pos = fn_sq_qtg_1_4294967295_cl_48_57(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn_al_sq_qtg_1_4294967295_cl_48_57>:
  endbr64
  sub    $0x8,%rsp
  call   <fn_sq_qtg_1_4294967295_cl_48_57@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fn_al_sq_qtg_1_4294967295_cl_48_57(const char *text) {
  int pos = 0;
  pos = fn_sq_qtg_1_4294967295_cl_48_57(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn_al_sq_qtg_1_4294967295_cl_48_57>:
  endbr64
  jmp    1050 <fn_sq_qtg_1_4294967295_cl_48_57@plt>
```

assistant: ```c
int fn_al_sq_qtg_1_4294967295_cl_48_57(const char *text) {
  int pos = 0;
  pos = fn_sq_qtg_1_4294967295_cl_48_57(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn_al_sq_qtg_1_4294967295_cl_48_57>:
  endbr64
  jmp    1050 <fn_sq_qtg_1_4294967295_cl_48_57@plt>
```

assistant: ```c
int fn_al_sq_qtg_1_4294967295_cl_48_57(const char *text) {
  int pos = 0;
  pos = fn_sq_qtg_1_4294967295_cl_48_57(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solcon_retrieve_next_standard_initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x114,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int solcon_retrieve_next_standard_initialize(void) {
  int a, *b, fail;
  double *c;
  a = 0;
  fail = _ada_use_c2phc(276, &a, b, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<solcon_retrieve_next_standard_initialize>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x114,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_retrieve_next_standard_initialize(void) {
  int a, *b, fail;
  double *c;
  a = 0;
  fail = _ada_use_c2phc(276, &a, b, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solcon_retrieve_next_standard_initialize>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x114,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_retrieve_next_standard_initialize(void) {
  int a, *b, fail;
  double *c;
  a = 0;
  fail = _ada_use_c2phc(276, &a, b, c);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solcon_retrieve_next_standard_initialize>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x114,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_retrieve_next_standard_initialize(void) {
  int a, *b, fail;
  double *c;
  a = 0;
  fail = _ada_use_c2phc(276, &a, b, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clFlush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x41b,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
cl_int clFlush(cl_command_queue command_queue) {
  unsigned int sys_args[1];
  sys_args[0] = (unsigned int)command_queue;
  return (cl_int)syscall(325, 1051, sys_args);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clFlush>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0x41b,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clFlush(cl_command_queue command_queue) {
  unsigned int sys_args[1];
  sys_args[0] = (unsigned int)command_queue;
  return (cl_int)syscall(325, 1051, sys_args);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clFlush>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x41b,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %edi,0x4(%rsp)
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clFlush(cl_command_queue command_queue) {
  unsigned int sys_args[1];
  sys_args[0] = (unsigned int)command_queue;
  return (cl_int)syscall(325, 1051, sys_args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clFlush>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x41b,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %edi,0x4(%rsp)
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clFlush(cl_command_queue command_queue) {
  unsigned int sys_args[1];
  sys_args[0] = (unsigned int)command_queue;
  return (cl_int)syscall(325, 1051, sys_args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_x86_detect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D4(%rip),%eax
  test   %eax,%eax
  jne    L12
  mov    $0x0,%eax
  call   <_x86_detect_cpu@plt>
  movl   $0x1,D4(%rip)
  jmp    L4
L12:
  nop
L4:
  pop    %rbp
  ret
```

assistant: ```c
void _x86_detect(void) {
  static int flag = 0;
  if (flag)
    return;
  _x86_detect_cpu();
  flag = 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_x86_detect>:
  endbr64
  cmpl   $0x0,D16(%rip)
  je     L8
  ret
L8:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <_x86_detect_cpu@plt>
  movl   $0x1,D16(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _x86_detect(void) {
  static int flag = 0;
  if (flag)
    return;
  _x86_detect_cpu();
  flag = 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_x86_detect>:
  endbr64
  mov    D9(%rip),%eax
  test   %eax,%eax
  je     L7
  ret
  nop
L7:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_x86_detect_cpu@plt>
  movl   $0x1,D9(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _x86_detect(void) {
  static int flag = 0;
  if (flag)
    return;
  _x86_detect_cpu();
  flag = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_x86_detect>:
  endbr64
  mov    D4(%rip),%eax
  test   %eax,%eax
  je     L2
  ret
  nop
L2:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_x86_detect_cpu@plt>
  movl   $0x1,D4(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _x86_detect(void) {
  static int flag = 0;
  if (flag)
    return;
  _x86_detect_cpu();
  flag = 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<maxPathSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L23
L19:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <helper@plt>
  mov    -0xc(%rbp),%eax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int maxPathSum(struct TreeNode *root) {
  if (!root)
    return 0;
  int maxSum = INT_MIN;
  helper(root, &maxSum);
  return maxSum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maxPathSum>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L13
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <helper@plt>
  mov    0x4(%rsp),%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maxPathSum(struct TreeNode *root) {
  if (!root)
    return 0;
  int maxSum = INT_MIN;
  helper(root, &maxSum);
  return maxSum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<maxPathSum>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L5
  mov    D8(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  call   <helper@plt>
  mov    0x4(%rsp),%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maxPathSum(struct TreeNode *root) {
  if (!root)
    return 0;
  int maxSum = INT_MIN;
  helper(root, &maxSum);
  return maxSum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<maxPathSum>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  mov    D0(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  call   <helper@plt>
  mov    0x4(%rsp),%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maxPathSum(struct TreeNode *root) {
  if (!root)
    return 0;
  int maxSum = INT_MIN;
  helper(root, &maxSum);
  return maxSum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initialize_llc_occu_resctrl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <get_resource_id@plt>
  test   %rax,%rax
  jns    L29
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L12
L29:
  mov    -0x30(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <set_cqm_path@plt>
L12:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
datatype: string
name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D11: # Unable to resource_id

tool: D6: cqm

assistant: ```c
void initialize_llc_occu_resctrl(const char *ctrlgrp, const char *mongrp, int cpu_no, char *resctrl_val) {
  int resource_id;
  if (get_resource_id(cpu_no, &resource_id) < 0) {
    perror("# Unable to resource_id");
    return;
  }
  if (strcmp(resctrl_val, "cqm") == 0)
    set_cqm_path(ctrlgrp, mongrp, resource_id);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<initialize_llc_occu_resctrl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%edi
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <get_resource_id@plt>
  test   %rax,%rax
  js     L49
  lea    D11(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L6
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  jmp    L46
L6:
  mov    0x4(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <set_cqm_path@plt>
  jmp    L46
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D6
type_infered: string

tool: D11: cqm

tool: D6: # Unable to resource_id

assistant: ```c
void initialize_llc_occu_resctrl(const char *ctrlgrp, const char *mongrp, int cpu_no, char *resctrl_val) {
  int resource_id;
  if (get_resource_id(cpu_no, &resource_id) < 0) {
    perror("# Unable to resource_id");
    return;
  }
  if (strcmp(resctrl_val, "cqm") == 0)
    set_cqm_path(ctrlgrp, mongrp, resource_id);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<initialize_llc_occu_resctrl>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %edx,%edi
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <get_resource_id@plt>
  test   %rax,%rax
  js     L8
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L21
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L21:
  mov    0x4(%rsp),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <set_cqm_path@plt>
  jmp    L45
  nopl   0x0(%rax)
L8:
  lea    D8(%rip),%rdi
  call   <perror@plt>
  jmp    L45
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D18: cqm

tool: D8: # Unable to resource_id

assistant: ```c
void initialize_llc_occu_resctrl(const char *ctrlgrp, const char *mongrp, int cpu_no, char *resctrl_val) {
  int resource_id;
  if (get_resource_id(cpu_no, &resource_id) < 0) {
    perror("# Unable to resource_id");
    return;
  }
  if (strcmp(resctrl_val, "cqm") == 0)
    set_cqm_path(ctrlgrp, mongrp, resource_id);
}
```
user: What is the c source code of the assembly code below:

```asm
<initialize_llc_occu_resctrl>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %edx,%edi
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <get_resource_id@plt>
  test   %rax,%rax
  js     L10
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L22:
  mov    0x4(%rsp),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <set_cqm_path@plt>
  jmp    L26
  nopl   0x0(%rax)
L10:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  jmp    L26
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D4: cqm

tool: D9: # Unable to resource_id

assistant: ```c
void initialize_llc_occu_resctrl(const char *ctrlgrp, const char *mongrp, int cpu_no, char *resctrl_val) {
  int resource_id;
  if (get_resource_id(cpu_no, &resource_id) < 0) {
    perror("# Unable to resource_id");
    return;
  }
  if (strcmp(resctrl_val, "cqm") == 0)
    set_cqm_path(ctrlgrp, mongrp, resource_id);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getInverCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L22
L23:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L43
L10:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jbe    L17
  addq   $0x1,-0x18(%rbp)
L17:
  addq   $0x1,-0x8(%rbp)
L43:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L10
  addq   $0x1,-0x10(%rbp)
L22:
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L23
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long int getInverCount(unsigned long int inputArray[], unsigned long n) {
  unsigned long int invCount = 0;
  unsigned long int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++)
      if (inputArray[i] > inputArray[j])
        invCount++;
  return invCount;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getInverCount>:
  endbr64
  mov    %rsi,%r10
  sub    $0x1,%r10
  je     L20
  lea    0x8(%rdi),%r9
  lea    (%rdi,%rsi,8),%rdi
  mov    $0x0,%r8d
  mov    $0x0,%edx
L24:
  add    $0x1,%r8
  cmp    %r8,%rsi
  jbe    L47
  mov    -0x8(%r9),%rcx
  mov    %r9,%rax
L22:
  cmp    %rcx,(%rax)
  adc    $0x0,%rdx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L22
L47:
  add    $0x8,%r9
  cmp    %r10,%r8
  jne    L24
L3:
  mov    %rdx,%rax
  ret
L20:
  mov    %r10,%rdx
  jmp    L3
```

assistant: ```c
unsigned long int getInverCount(unsigned long int inputArray[], unsigned long n) {
  unsigned long int invCount = 0;
  unsigned long int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++)
      if (inputArray[i] > inputArray[j])
        invCount++;
  return invCount;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getInverCount>:
  endbr64
  mov    %rsi,%r10
  sub    $0x1,%r10
  je     L29
  lea    0x8(%rdi),%r9
  lea    (%rdi,%rsi,8),%rcx
  xor    %r8d,%r8d
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jbe    L24
  mov    -0x8(%r9),%rdx
  mov    %r9,%rax
L5:
  cmp    %rdx,(%rax)
  adc    $0x0,%r8
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L5
L24:
  add    $0x8,%r9
  cmp    %r10,%rdi
  jne    L15
  mov    %r8,%rax
  ret
L29:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long int getInverCount(unsigned long int inputArray[], unsigned long n) {
  unsigned long int invCount = 0;
  unsigned long int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++)
      if (inputArray[i] > inputArray[j])
        invCount++;
  return invCount;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getInverCount>:
  endbr64
  mov    %rsi,%r10
  sub    $0x1,%r10
  je     L25
  lea    0x8(%rdi),%r9
  lea    (%rdi,%rsi,8),%rcx
  xor    %r8d,%r8d
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jbe    L31
  mov    -0x8(%r9),%rdx
  mov    %r9,%rax
L0:
  cmp    %rdx,(%rax)
  adc    $0x0,%r8
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L0
L31:
  add    $0x8,%r9
  cmp    %r10,%rdi
  jne    L19
  mov    %r8,%rax
  ret
L25:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long int getInverCount(unsigned long int inputArray[], unsigned long n) {
  unsigned long int invCount = 0;
  unsigned long int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++)
      if (inputArray[i] > inputArray[j])
        invCount++;
  return invCount;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strip_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L53
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L14
L45:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L56
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L56
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L14
L56:
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L53:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strip_copy(const char *s) {
  char *p = malloc(strlen(s) + 1);
  if (p) {
    char *p2 = p;
    while (*s != '\0') {
      if (*s != '\r' && *s != '\n') {
        *p2++ = *s++;
      } else {
        ++s;
      }
    }
    *p2 = '\0';
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strip_copy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L2
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L42
  lea    0x1(%rbx),%rdi
  mov    %rax,%rsi
  jmp    L55
L21:
  mov    %rdi,%rcx
  mov    %dl,(%rsi)
  lea    0x1(%rsi),%rsi
L26:
  movzbl (%rcx),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  je     L49
L55:
  cmp    $0xd,%dl
  je     L1
  cmp    $0xa,%dl
  jne    L21
L1:
  mov    %rdi,%rcx
  jmp    L26
L42:
  mov    %rax,%rsi
L49:
  movb   $0x0,(%rsi)
L2:
  pop    %rbx
  ret
```

assistant: ```c
char *strip_copy(const char *s) {
  char *p = malloc(strlen(s) + 1);
  if (p) {
    char *p2 = p;
    while (*s != '\0') {
      if (*s != '\r' && *s != '\n') {
        *p2++ = *s++;
      } else {
        ++s;
      }
    }
    *p2 = '\0';
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strip_copy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  movzbl (%rbx),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  je     L14
  nopl   (%rax)
L32:
  add    $0x1,%rbx
  cmp    $0xd,%dl
  je     L9
  cmp    $0xa,%dl
  je     L9
  mov    %dl,(%rcx)
  add    $0x1,%rcx
L9:
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L32
L14:
  movb   $0x0,(%rcx)
L0:
  pop    %rbx
  ret
```

assistant: ```c
char *strip_copy(const char *s) {
  char *p = malloc(strlen(s) + 1);
  if (p) {
    char *p2 = p;
    while (*s != '\0') {
      if (*s != '\r' && *s != '\n') {
        *p2++ = *s++;
      } else {
        ++s;
      }
    }
    *p2 = '\0';
  }
  return p;
}
```