ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D38
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string

tool: D19: 1: %d


tool: D30: 1 & 0xff: %d


tool: D38: (1<<1) & 0xff: %d


tool: D25: (1<<3) & 0xff: %d


assistant: ```c
int main() {
  printf("1: %d\n", 1);
  printf("1 & 0xff: %d\n", 1 & 0xff);
  printf("(1<<1) & 0xff: %d\n", (1 << 1) & 0xff);
  printf("(1<<3) & 0xff: %d\n", (1 << 3) & 0xff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D39
type: string
name: retrieve_data
arguments: data_label: D23
type: string
name: retrieve_data
arguments: data_label: D14
type: string
name: retrieve_data
arguments: data_label: D28
type: string

tool: D39: 1: %d


tool: D23: 1 & 0xff: %d


tool: D14: (1<<1) & 0xff: %d


tool: D28: (1<<3) & 0xff: %d


assistant: ```c
int main() {
  printf("1: %d\n", 1);
  printf("1 & 0xff: %d\n", 1 & 0xff);
  printf("(1<<1) & 0xff: %d\n", (1 << 1) & 0xff);
  printf("(1<<3) & 0xff: %d\n", (1 << 3) & 0xff);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D39
type: string
name: parse_data
arguments: data_label: D13
type: string
name: parse_data
arguments: data_label: D12
type: string

tool: D20: 1: %d


tool: D39: 1 & 0xff: %d


tool: D13: (1<<1) & 0xff: %d


tool: D12: (1<<3) & 0xff: %d


assistant: ```c
int main() {
  printf("1: %d\n", 1);
  printf("1 & 0xff: %d\n", 1 & 0xff);
  printf("(1<<1) & 0xff: %d\n", (1 << 1) & 0xff);
  printf("(1<<3) & 0xff: %d\n", (1 << 3) & 0xff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vrrp_timer_fires>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <now_usec@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L1
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L20
L1:
  mov    $0x1,%eax
  jmp    L16
L20:
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int vrrp_timer_fires(uint32_t value, uint32_t upbound) {
  int delta = value - now_usec();
  if (0 > delta || delta > upbound)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vrrp_timer_fires>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <now_usec@plt>
  sub    %eax,%ebx
  mov    %ebx,%edx
  shr    $0x1f,%edx
  cmp    %ebp,%ebx
  setg   %al
  movzbl %al,%eax
  or     %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int vrrp_timer_fires(uint32_t value, uint32_t upbound) {
  int delta = value - now_usec();
  if (0 > delta || delta > upbound)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vrrp_timer_fires>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <now_usec@plt>
  sub    %eax,%ebx
  xor    %eax,%eax
  mov    %ebx,%edx
  shr    $0x1f,%edx
  cmp    %ebp,%ebx
  setg   %al
  add    $0x8,%rsp
  or     %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int vrrp_timer_fires(uint32_t value, uint32_t upbound) {
  int delta = value - now_usec();
  if (0 > delta || delta > upbound)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vrrp_timer_fires>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <now_usec@plt>
  sub    %eax,%ebx
  xor    %eax,%eax
  mov    %ebx,%edx
  shr    $0x1f,%edx
  cmp    %ebp,%ebx
  setg   %al
  add    $0x8,%rsp
  or     %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int vrrp_timer_fires(uint32_t value, uint32_t upbound) {
  int delta = value - now_usec();
  if (0 > delta || delta > upbound)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<expmod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L22
  mov    $0x1,%eax
  jmp    L18
L22:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L24
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,%rsi
  mov    -0x18(%rbp),%rax
  imul   %rax,%rax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,%rcx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <expmod>
  jmp    L18
L24:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <expmod>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x8(%rbp),%rax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,%rax
L18:
  leave
  ret
```

assistant: ```c
long expmod(long x, long n, long m) {
  if (0 == n) {
    return 1;
  } else if (((n) % (2)) == 0) {
    return expmod(((((x) * (x))) % (m)), ((n) / (2)), m);
  } else {
    long tmp = expmod(x, n - 1, m);
    return ((((x) * (tmp))) % (m));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<expmod>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  mov    $0x1,%edx
  test   %rsi,%rsi
  je     L26
  mov    %rdi,%rbx
  test   $0x1,%sil
  jne    L1
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  sar    %rsi
  mov    %rdi,%rax
  imul   %rdi,%rax
  cqto
  idiv   %rbp
  mov    %rdx,%rdi
  mov    %rbp,%rdx
  call   <expmod>
  mov    %rax,%rdx
L26:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  sub    $0x1,%rsi
  mov    %rbp,%rdx
  call   <expmod>
  imul   %rbx,%rax
  cqto
  idiv   %rbp
  jmp    L26
```

assistant: ```c
long expmod(long x, long n, long m) {
  if (0 == n) {
    return 1;
  } else if (((n) % (2)) == 0) {
    return expmod(((((x) * (x))) % (m)), ((n) / (2)), m);
  } else {
    long tmp = expmod(x, n - 1, m);
    return ((((x) * (tmp))) % (m));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<expmod>:
  endbr64
  test   %rsi,%rsi
  je     L73
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   $0x1,%sil
  je     L140
  jmp    L143
  nopl   0x0(%rax,%rax,1)
L216:
  test   $0x1,%sil
  jne    L143
L140:
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %rbx,%rax
  imul   %rbx,%rax
  cqto
  idiv   %rbp
  sar    %rsi
  mov    %rdx,%rbx
  jne    L216
  mov    $0x1,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L143:
  sub    $0x1,%rsi
  je     L99
  mov    %rbx,%r12
  test   $0x1,%sil
  je     L194
  jmp    L64
  nopl   0x0(%rax)
L212:
  test   $0x1,%sil
  jne    L64
L194:
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %r12,%rax
  imul   %r12,%rax
  cqto
  idiv   %rbp
  sar    %rsi
  mov    %rdx,%r12
  jne    L212
L99:
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  mov    %rdx,%r8
L59:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  sub    $0x1,%rsi
  je     L44
  mov    %r12,%r13
  test   $0x1,%sil
  je     L141
  jmp    L157
  nopl   0x0(%rax)
L154:
  test   $0x1,%sil
  jne    L157
L141:
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %r13,%rax
  imul   %r13,%rax
  cqto
  idiv   %rbp
  sar    %rsi
  mov    %rdx,%r13
  jne    L154
L44:
  mov    %r12,%rax
  cqto
  idiv   %rbp
  imul   %rdx,%rbx
L118:
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  mov    %rdx,%r8
  jmp    L59
  nopl   (%rax)
L157:
  sub    $0x1,%rsi
  je     L39
  mov    %r13,%r14
  test   $0x1,%sil
  je     L150
  jmp    L166
  nopl   0x0(%rax)
L104:
  test   $0x1,%sil
  jne    L166
L150:
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %r14,%rax
  imul   %r14,%rax
  cqto
  idiv   %rbp
  sar    %rsi
  mov    %rdx,%r14
  jne    L104
L39:
  mov    %r13,%rax
  cqto
  idiv   %rbp
  imul   %rdx,%r12
  mov    %r12,%rax
  cqto
  idiv   %rbp
  imul   %rdx,%rbx
  jmp    L118
L166:
  mov    %rbp,%rdx
  sub    $0x1,%rsi
  mov    %r14,%rdi
  call   <expmod>
  imul   %r14,%rax
  cqto
  idiv   %rbp
  imul   %rdx,%r13
  jmp    L39
L73:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long expmod(long x, long n, long m) {
  if (0 == n) {
    return 1;
  } else if (((n) % (2)) == 0) {
    return expmod(((((x) * (x))) % (m)), ((n) / (2)), m);
  } else {
    long tmp = expmod(x, n - 1, m);
    return ((((x) * (tmp))) % (m));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<expmod>:
  endbr64
  test   %rsi,%rsi
  je     L11
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   $0x1,%sil
  je     L201
  jmp    L107
  nopl   0x0(%rax,%rax,1)
L117:
  test   $0x1,%sil
  jne    L107
L201:
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %rbx,%rax
  imul   %rbx,%rax
  cqto
  idiv   %rbp
  sar    %rsi
  mov    %rdx,%rbx
  jne    L117
  mov    $0x1,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L107:
  sub    $0x1,%rsi
  je     L213
  mov    %rbx,%r12
  test   $0x1,%sil
  je     L22
  jmp    L34
  nopl   0x0(%rax)
L94:
  test   $0x1,%sil
  jne    L34
L22:
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %r12,%rax
  imul   %r12,%rax
  cqto
  idiv   %rbp
  sar    %rsi
  mov    %rdx,%r12
  jne    L94
L213:
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  mov    %rdx,%r8
L80:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  sub    $0x1,%rsi
  je     L225
  mov    %r12,%r13
  test   $0x1,%sil
  je     L37
  jmp    L100
  nopl   0x0(%rax)
L205:
  test   $0x1,%sil
  jne    L100
L37:
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %r13,%rax
  imul   %r13,%rax
  cqto
  idiv   %rbp
  sar    %rsi
  mov    %rdx,%r13
  jne    L205
L225:
  mov    %r12,%rax
  cqto
  idiv   %rbp
  imul   %rdx,%rbx
L179:
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  mov    %rdx,%r8
  jmp    L80
  nopl   (%rax)
L100:
  sub    $0x1,%rsi
  je     L183
  mov    %r13,%r14
  test   $0x1,%sil
  je     L83
  jmp    L212
  nopl   0x0(%rax)
L101:
  test   $0x1,%sil
  jne    L212
L83:
  mov    %rsi,%rax
  shr    $0x3f,%rax
  add    %rax,%rsi
  mov    %r14,%rax
  imul   %r14,%rax
  cqto
  idiv   %rbp
  sar    %rsi
  mov    %rdx,%r14
  jne    L101
L183:
  mov    %r13,%rax
  cqto
  idiv   %rbp
  imul   %rdx,%r12
  mov    %r12,%rax
  cqto
  idiv   %rbp
  imul   %rdx,%rbx
  jmp    L179
L212:
  mov    %rbp,%rdx
  sub    $0x1,%rsi
  mov    %r14,%rdi
  call   <expmod>
  imul   %r14,%rax
  cqto
  idiv   %rbp
  imul   %rdx,%r13
  jmp    L183
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long expmod(long x, long n, long m) {
  if (0 == n) {
    return 1;
  } else if (((n) % (2)) == 0) {
    return expmod(((((x) * (x))) % (m)), ((n) / (2)), m);
  } else {
    long tmp = expmod(x, n - 1, m);
    return ((((x) * (tmp))) % (m));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<in_triangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  %xmm6,-0x48(%rbp)
  movsd  %xmm7,-0x50(%rbp)
  movl   $0x0,-0x4(%rbp)
  movsd  -0x30(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  seta   %dl
  movsd  -0x40(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  seta   %al
  xor    %edx,%eax
  test   %al,%al
  je     L86
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x40(%rbp),%xmm1
  subsd  -0x30(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  addsd  -0x28(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L86
  mov    $0x1,%eax
  jmp    L2
L86:
  mov    $0x0,%eax
L2:
  add    %eax,-0x4(%rbp)
  movsd  -0x40(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  seta   %dl
  movsd  -0x50(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  seta   %al
  xor    %edx,%eax
  test   %al,%al
  je     L33
  movsd  -0x48(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x38(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x50(%rbp),%xmm1
  subsd  -0x40(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  addsd  -0x38(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L33
  mov    $0x1,%eax
  jmp    L48
L33:
  mov    $0x0,%eax
L48:
  add    %eax,-0x4(%rbp)
  movsd  -0x50(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  seta   %dl
  movsd  -0x30(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  seta   %al
  xor    %edx,%eax
  test   %al,%al
  je     L37
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x48(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x50(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x30(%rbp),%xmm1
  subsd  -0x50(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  addsd  -0x48(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L37
  mov    $0x1,%eax
  jmp    L34
L37:
  mov    $0x0,%eax
L34:
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int in_triangle(double x, double y, double x1, double y1, double x2, double y2, double x3, double y3) {
  int c;
  c = 0;
  c += ((y1 > y) != (y2 > y)) && (x < (x2 - x1) * (y - y1) / (y2 - y1) + x1);
  c += ((y2 > y) != (y3 > y)) && (x < (x3 - x2) * (y - y2) / (y3 - y2) + x2);
  c += ((y3 > y) != (y1 > y)) && (x < (x1 - x3) * (y - y3) / (y1 - y3) + x3);
  return c % 2 == 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<in_triangle>:
  endbr64
  comisd %xmm1,%xmm3
  seta   %sil
  comisd %xmm1,%xmm5
  seta   %dl
  mov    $0x0,%eax
  cmp    %dl,%sil
  je     L26
  movapd %xmm1,%xmm9
  subsd  %xmm3,%xmm9
  movapd %xmm4,%xmm8
  subsd  %xmm2,%xmm8
  mulsd  %xmm9,%xmm8
  movapd %xmm5,%xmm9
  subsd  %xmm3,%xmm9
  divsd  %xmm9,%xmm8
  addsd  %xmm2,%xmm8
  comisd %xmm0,%xmm8
  seta   %al
  movzbl %al,%eax
L26:
  comisd %xmm1,%xmm7
  seta   %cl
  mov    $0x0,%edi
  cmp    %cl,%dl
  je     L29
  movapd %xmm6,%xmm8
  subsd  %xmm4,%xmm8
  movapd %xmm1,%xmm9
  subsd  %xmm5,%xmm9
  mulsd  %xmm9,%xmm8
  movapd %xmm7,%xmm9
  subsd  %xmm5,%xmm9
  movapd %xmm8,%xmm5
  divsd  %xmm9,%xmm5
  addsd  %xmm4,%xmm5
  comisd %xmm0,%xmm5
  seta   %dil
  movzbl %dil,%edi
L29:
  lea    (%rax,%rdi,1),%edx
  mov    $0x0,%eax
  cmp    %cl,%sil
  je     L20
  subsd  %xmm6,%xmm2
  subsd  %xmm7,%xmm1
  mulsd  %xmm1,%xmm2
  subsd  %xmm7,%xmm3
  divsd  %xmm3,%xmm2
  addsd  %xmm6,%xmm2
  comisd %xmm0,%xmm2
  seta   %al
  movzbl %al,%eax
L20:
  add    %edx,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int in_triangle(double x, double y, double x1, double y1, double x2, double y2, double x3, double y3) {
  int c;
  c = 0;
  c += ((y1 > y) != (y2 > y)) && (x < (x2 - x1) * (y - y1) / (y2 - y1) + x1);
  c += ((y2 > y) != (y3 > y)) && (x < (x3 - x2) * (y - y2) / (y3 - y2) + x2);
  c += ((y3 > y) != (y1 > y)) && (x < (x1 - x3) * (y - y3) / (y1 - y3) + x3);
  return c % 2 == 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<in_triangle>:
  endbr64
  comisd %xmm1,%xmm3
  seta   %cl
  comisd %xmm1,%xmm5
  seta   %sil
  xor    %eax,%eax
  cmp    %sil,%cl
  je     L18
  movapd %xmm1,%xmm9
  movapd %xmm4,%xmm8
  xor    %eax,%eax
  subsd  %xmm3,%xmm9
  subsd  %xmm2,%xmm8
  mulsd  %xmm9,%xmm8
  movapd %xmm5,%xmm9
  subsd  %xmm3,%xmm9
  divsd  %xmm9,%xmm8
  addsd  %xmm2,%xmm8
  comisd %xmm0,%xmm8
  seta   %al
L18:
  comisd %xmm1,%xmm7
  seta   %dl
  cmp    %dl,%sil
  je     L14
  movapd %xmm6,%xmm8
  movapd %xmm1,%xmm9
  xor    %esi,%esi
  subsd  %xmm5,%xmm9
  subsd  %xmm4,%xmm8
  mulsd  %xmm9,%xmm8
  movapd %xmm7,%xmm9
  subsd  %xmm5,%xmm9
  movapd %xmm8,%xmm5
  divsd  %xmm9,%xmm5
  addsd  %xmm4,%xmm5
  comisd %xmm0,%xmm5
  seta   %sil
  add    %esi,%eax
L14:
  cmp    %dl,%cl
  je     L8
  subsd  %xmm6,%xmm2
  subsd  %xmm7,%xmm1
  xor    %edx,%edx
  subsd  %xmm7,%xmm3
  mulsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  addsd  %xmm6,%xmm2
  comisd %xmm0,%xmm2
  seta   %dl
  add    %edx,%eax
L8:
  and    $0x1,%eax
  ret
```

assistant: ```c
int in_triangle(double x, double y, double x1, double y1, double x2, double y2, double x3, double y3) {
  int c;
  c = 0;
  c += ((y1 > y) != (y2 > y)) && (x < (x2 - x1) * (y - y1) / (y2 - y1) + x1);
  c += ((y2 > y) != (y3 > y)) && (x < (x3 - x2) * (y - y2) / (y3 - y2) + x2);
  c += ((y3 > y) != (y1 > y)) && (x < (x1 - x3) * (y - y3) / (y1 - y3) + x3);
  return c % 2 == 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<in_triangle>:
  endbr64
  comisd %xmm1,%xmm3
  seta   %cl
  comisd %xmm1,%xmm5
  seta   %sil
  cmp    %sil,%cl
  je     L27
  movapd %xmm1,%xmm9
  movapd %xmm4,%xmm8
  subsd  %xmm3,%xmm9
  subsd  %xmm2,%xmm8
  mulsd  %xmm9,%xmm8
  movapd %xmm5,%xmm9
  subsd  %xmm3,%xmm9
  divsd  %xmm9,%xmm8
  addsd  %xmm2,%xmm8
  comisd %xmm0,%xmm8
  seta   %dil
  seta   %al
  movzbl %dil,%edi
  movzbl %al,%eax
  add    $0x1,%edi
L37:
  comisd %xmm1,%xmm7
  seta   %dl
  cmp    %dl,%sil
  je     L14
  movapd %xmm6,%xmm8
  movapd %xmm1,%xmm9
  subsd  %xmm5,%xmm9
  subsd  %xmm4,%xmm8
  mulsd  %xmm9,%xmm8
  movapd %xmm7,%xmm9
  subsd  %xmm5,%xmm9
  movapd %xmm8,%xmm5
  divsd  %xmm9,%xmm5
  addsd  %xmm4,%xmm5
  ucomisd %xmm0,%xmm5
  cmova  %edi,%eax
L14:
  cmp    %dl,%cl
  je     L22
  subsd  %xmm6,%xmm2
  subsd  %xmm7,%xmm1
  xor    %edx,%edx
  subsd  %xmm7,%xmm3
  mulsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  addsd  %xmm6,%xmm2
  comisd %xmm0,%xmm2
  seta   %dl
  add    %edx,%eax
L22:
  and    $0x1,%eax
  ret
  xchg   %ax,%ax
L27:
  mov    $0x1,%edi
  xor    %eax,%eax
  jmp    L37
```

assistant: ```c
int in_triangle(double x, double y, double x1, double y1, double x2, double y2, double x3, double y3) {
  int c;
  c = 0;
  c += ((y1 > y) != (y2 > y)) && (x < (x2 - x1) * (y - y1) / (y2 - y1) + x1);
  c += ((y2 > y) != (y3 > y)) && (x < (x3 - x2) * (y - y2) / (y3 - y2) + x2);
  c += ((y3 > y) != (y1 > y)) && (x < (x1 - x3) * (y - y3) / (y1 - y3) + x3);
  return c % 2 == 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<print_graph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L96:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L63
  movl   $0x0,-0x8(%rbp)
  jmp    L61
L4:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  je     L28
  mov    $0x7c,%ecx
  jmp    L89
L28:
  mov    $0x20,%ecx
L89:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  cmpl   $0x0,-0x4(%rbp)
  je     L17
  addl   $0x1,-0x8(%rbp)
L61:
  cmpl   $0x7,-0x8(%rbp)
  jle    L4
  jmp    L83
L63:
  nop
  jmp    L83
L17:
  nop
L83:
  addl   $0x1,-0xc(%rbp)
L55:
  cmpl   $0x7,-0xc(%rbp)
  jle    L96
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void print_graph(int *A, int A_lengt, char graph[][8]) {
  int i, j, temp;
  for (i = 0; i < 8; i++) {
    temp = A[i];
    if (temp == 0)
      continue;
    for (j = 0; j < 8; j++) {
      graph[j][i] = (temp--) ? ('|') : (' ');
      if (temp == 0)
        break;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_graph>:
  endbr64
  mov    $0x0,%r8d
  jmp    L30
L19:
  ret
L8:
  movb   $0x20,(%rcx)
L33:
  add    $0x8,%rcx
  cmp    %r9d,%eax
  je     L48
L13:
  mov    %eax,%esi
  sub    $0x1,%eax
  test   %esi,%esi
  je     L8
  movb   $0x7c,(%rcx)
  test   %eax,%eax
  jne    L33
L48:
  add    $0x1,%r8
  cmp    $0x8,%r8
  je     L19
L30:
  mov    (%rdi,%r8,4),%eax
  test   %eax,%eax
  je     L48
  lea    (%rdx,%r8,1),%rcx
  lea    -0x8(%rax),%r9d
  jmp    L13
```

assistant: ```c
void print_graph(int *A, int A_lengt, char graph[][8]) {
  int i, j, temp;
  for (i = 0; i < 8; i++) {
    temp = A[i];
    if (temp == 0)
      continue;
    for (j = 0; j < 8; j++) {
      graph[j][i] = (temp--) ? ('|') : (' ');
      if (temp == 0)
        break;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_graph>:
  endbr64
  lea    0x40(%rdx),%rcx
  lea    0x8(%rdx),%r8
  jmp    L10
  xchg   %ax,%ax
L31:
  add    $0x1,%rdx
  add    $0x4,%rdi
  add    $0x1,%rcx
  cmp    %r8,%rdx
  je     L58
L10:
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L31
  sub    $0x1,%eax
  lea    (%rdx,%rax,8),%rsi
  mov    %rdx,%rax
  nopl   0x0(%rax)
L27:
  movb   $0x7c,(%rax)
  cmp    %rsi,%rax
  je     L31
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L27
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L58:
  ret
```

assistant: ```c
void print_graph(int *A, int A_lengt, char graph[][8]) {
  int i, j, temp;
  for (i = 0; i < 8; i++) {
    temp = A[i];
    if (temp == 0)
      continue;
    for (j = 0; j < 8; j++) {
      graph[j][i] = (temp--) ? ('|') : (' ');
      if (temp == 0)
        break;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm1
  movsd  D35(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D42
data_type: string
name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D35
data_type: f64
name: parse_data
arguments: label: D37
data_type: string

tool: D42: This is a circle area calculation program.

tool: D11: Radius? 

tool: D1: %lf

tool: D35: 3.14159

tool: D37: The anwser is: %g


assistant: ```c
int main(int argc, const char *argv[]) {
  double radius;
  printf("This is a circle area calculation program.\n");
  printf("Radius? ");
  scanf("%lf", &radius);
  printf("The anwser is: %g\n", 3.14159 * radius * radius);
  return 0;
}
```