ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x5,0x1c(%rsp)
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  mov    %rbx,%rbp
  lea    D14(%rip),%r13
L29:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdx
  mov    $0x2,%esi
  mov    $0x4,%edi
  call   <union_sets@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D0: Parent array before union: 

tool: D14: %d 

tool: D6: Parent array after union: 

assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 3, 6, 2, 7, 5, 0, 4};
  int a_length = sizeof(a) / sizeof(a[0]);
  int parent_array[] = {1, 1, 1, 2, 5, 5, 5, 5};
  printf("%s\n", "Parent array before union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  union_sets(4, 2, parent_array);
  printf("%s\n", "Parent array after union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D24(%rip),%rdi
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x100000001,%rax
  mov    %rsp,%r14
  lea    0x20(%rsp),%r12
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000005,%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  call   <puts@plt>
L29:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x4,%edi
  mov    %r14,%rdx
  mov    $0x2,%esi
  call   <union_sets@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L1:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D24
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D24: Parent array before union: 

tool: D21: %d 

tool: D9: Parent array after union: 

assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 3, 6, 2, 7, 5, 0, 4};
  int a_length = sizeof(a) / sizeof(a[0]);
  int parent_array[] = {1, 1, 1, 2, 5, 5, 5, 5};
  printf("%s\n", "Parent array before union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  union_sets(4, 2, parent_array);
  printf("%s\n", "Parent array after union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D41(%rip),%rdi
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D32(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x20(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D20(%rip),%xmm0
  mov    %r14,%rbx
  mov    %r14,%rbp
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x4,%edi
  mov    %r14,%rdx
  mov    $0x2,%esi
  call   <union_sets@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L14:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D41
data_type: string
name: retrieve_data
arguments: data_label: D26
data_type: string
name: retrieve_data
arguments: data_label: D32
data_type: byte[16]
name: retrieve_data
arguments: data_label: D20
data_type: byte[16]
name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D41: Parent array before union: 

tool: D26: %d 

tool: {"D32": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D20": [0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: D4: Parent array after union: 

assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 3, 6, 2, 7, 5, 0, 4};
  int a_length = sizeof(a) / sizeof(a[0]);
  int parent_array[] = {1, 1, 1, 2, 5, 5, 5, 5};
  printf("%s\n", "Parent array before union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  union_sets(4, 2, parent_array);
  printf("%s\n", "Parent array after union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <call@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  call(1, 2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <call@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  call(1, 2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <call@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  call(1, 2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <call@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  call(1, 2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<insertAtBottom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <isEmpty@plt>
  test   %rax,%rax
  je     L8
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <push@plt>
  jmp    L7
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insertAtBottom>
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <push@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void insertAtBottom(struct sNode **top_ref, int item) {
  if (isEmpty(*top_ref))
    push(top_ref, item);
  else {
    int temp = pop(top_ref);
    insertAtBottom(top_ref, item);
    push(top_ref, temp);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertAtBottom>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    (%rdi),%rdi
  call   <isEmpty@plt>
  test   %rax,%rax
  je     L16
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <push@plt>
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %rbx,%rdi
  call   <pop@plt>
  mov    %eax,%r12d
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <insertAtBottom>
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  jmp    L12
```

assistant: ```c
void insertAtBottom(struct sNode **top_ref, int item) {
  if (isEmpty(*top_ref))
    push(top_ref, item);
  else {
    int temp = pop(top_ref);
    insertAtBottom(top_ref, item);
    push(top_ref, temp);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<insertAtBottom>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <isEmpty@plt>
  mov    %r12d,%esi
  test   %rax,%rax
  jne    L4
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <insertAtBottom>
  mov    %r13d,%esi
L4:
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <push@plt>
```

assistant: ```c
void insertAtBottom(struct sNode **top_ref, int item) {
  if (isEmpty(*top_ref))
    push(top_ref, item);
  else {
    int temp = pop(top_ref);
    insertAtBottom(top_ref, item);
    push(top_ref, temp);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<insertAtBottom>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <isEmpty@plt>
  mov    %r12d,%esi
  test   %rax,%rax
  jne    L68
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    0x0(%rbp),%rdi
  mov    %eax,%r13d
  call   <isEmpty@plt>
  test   %rax,%rax
  je     L13
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <push@plt>
L4:
  mov    %r13d,%esi
L68:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <push@plt>
  nopl   (%rax)
L13:
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    0x0(%rbp),%rdi
  mov    %eax,%r14d
  call   <isEmpty@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    0x0(%rbp),%rdi
  mov    %eax,%r15d
  call   <isEmpty@plt>
  test   %rax,%rax
  je     L8
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <push@plt>
L1:
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <push@plt>
L9:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  jmp    L4
  nopl   (%rax)
L19:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  jmp    L9
  nopl   (%rax)
L8:
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <insertAtBottom>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  jmp    L1
```

assistant: ```c
void insertAtBottom(struct sNode **top_ref, int item) {
  if (isEmpty(*top_ref))
    push(top_ref, item);
  else {
    int temp = pop(top_ref);
    insertAtBottom(top_ref, item);
    push(top_ref, temp);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<intel_pt_get_packet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <intel_pt_do_get_packet@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L47
  jmp    L13
L25:
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x7,-0x4(%rbp)
  jg     L47
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jbe    L47
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
L47:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int intel_pt_get_packet(const unsigned char *buf, size_t len, struct intel_pt_pkt *packet) {
  int ret;
  ret = intel_pt_do_get_packet(buf, len, packet);
  if (ret > 0) {
    while (ret < 8 && len > (size_t)ret && !buf[ret])
      ret += 1;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<intel_pt_get_packet>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <intel_pt_do_get_packet@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x6,%edx
  ja     L42
  movslq %eax,%rdx
  cmp    %rdx,%rbx
  jbe    L42
L24:
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  jne    L42
  add    $0x1,%eax
  cmp    $0x8,%eax
  je     L42
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  ja     L24
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int intel_pt_get_packet(const unsigned char *buf, size_t len, struct intel_pt_pkt *packet) {
  int ret;
  ret = intel_pt_do_get_packet(buf, len, packet);
  if (ret > 0) {
    while (ret < 8 && len > (size_t)ret && !buf[ret])
      ret += 1;
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<intel_pt_get_packet>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <intel_pt_do_get_packet@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x6,%edx
  ja     L37
  movslq %eax,%rdx
  cmp    %rdx,%rbx
  ja     L54
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%eax
  cmp    $0x8,%eax
  je     L37
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jbe    L37
L54:
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  je     L34
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int intel_pt_get_packet(const unsigned char *buf, size_t len, struct intel_pt_pkt *packet) {
  int ret;
  ret = intel_pt_do_get_packet(buf, len, packet);
  if (ret > 0) {
    while (ret < 8 && len > (size_t)ret && !buf[ret])
      ret += 1;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intel_pt_get_packet>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <intel_pt_do_get_packet@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x6,%edx
  ja     L76
  movslq %eax,%rdx
  cmp    %rdx,%rbx
  jbe    L76
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  jne    L76
  lea    0x1(%rax),%ecx
  cmp    $0x7,%eax
  je     L20
  movslq %ecx,%rdx
  cmp    %rdx,%rbx
  jbe    L147
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  jne    L147
  lea    0x2(%rax),%ecx
  cmp    $0x6,%eax
  je     L20
  movslq %ecx,%rdx
  cmp    %rdx,%rbx
  jbe    L147
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  jne    L147
  lea    0x3(%rax),%ecx
  cmp    $0x5,%eax
  je     L20
  movslq %ecx,%rdx
  cmp    %rdx,%rbx
  jbe    L147
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  jne    L147
  lea    0x4(%rax),%ecx
  cmp    $0x4,%eax
  je     L20
  movslq %ecx,%rdx
  cmp    %rdx,%rbx
  jbe    L147
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  jne    L147
  lea    0x5(%rax),%ecx
  cmp    $0x3,%eax
  je     L20
  movslq %ecx,%rdx
  cmp    %rdx,%rbx
  jbe    L147
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  jne    L147
  cmp    $0x1,%eax
  jne    L20
  mov    $0x7,%eax
  cmp    $0x7,%rbx
  je     L76
  cmpb   $0x1,0x7(%rbp)
  mov    $0x7,%eax
  adc    $0x0,%eax
L76:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L147:
  add    $0x8,%rsp
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x8,%eax
  jmp    L76
```

assistant: ```c
int intel_pt_get_packet(const unsigned char *buf, size_t len, struct intel_pt_pkt *packet) {
  int ret;
  ret = intel_pt_do_get_packet(buf, len, packet);
  if (ret > 0) {
    while (ret < 8 && len > (size_t)ret && !buf[ret])
      ret += 1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L28:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L25
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L4
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L4:
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L28
  nop
  pop    %rbp
  ret
```

assistant: ```c
int sort(int a[], int n) {
  int i, j, k, tmp;
  for (i = 0; i < n - 1; i++) {
    k = i;
    for (j = i + 1; j < n; j++)
      if (a[j] < a[k])
        k = j;
    tmp = a[k];
    a[k] = a[i];
    a[i] = tmp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L11
  lea    -0x2(%rsi),%r9d
  add    $0x2,%r9
  mov    $0x1,%r8d
L16:
  lea    -0x1(%r8),%edx
  cmp    %r8d,%esi
  jle    L34
  mov    %r8,%rax
L38:
  movslq %edx,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L38
L34:
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    -0x4(%rdi,%r8,4),%ecx
  mov    %ecx,(%rax)
  mov    %edx,-0x4(%rdi,%r8,4)
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L16
L11:
  ret
```

assistant: ```c
int sort(int a[], int n) {
  int i, j, k, tmp;
  for (i = 0; i < n - 1; i++) {
    k = i;
    for (j = i + 1; j < n; j++)
      if (a[j] < a[k])
        k = j;
    tmp = a[k];
    a[k] = a[i];
    a[i] = tmp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sort>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %r13d,%r13d
  jle    L51
  mov    %rdi,%r11
  mov    %rdi,%rbx
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L79:
  mov    %r10d,%r9d
  add    $0x1,%r10d
  mov    (%rbx),%ebp
  cmp    %r10d,%esi
  jle    L8
  lea    0x4(%rbx),%r12
  mov    %ebp,%edi
  mov    %r10d,%edx
  mov    %r12,%rax
  jmp    L75
  nopl   0x0(%rax)
L76:
  movslq %r9d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%r11,%rcx,4),%r8
  cmp    %edx,%esi
  je     L23
L75:
  mov    (%rax),%ecx
  mov    %rax,%r8
  cmp    %edi,%ecx
  jge    L76
  mov    %edx,%r9d
  add    $0x1,%edx
  mov    %ecx,%edi
  add    $0x4,%rax
  cmp    %edx,%esi
  jne    L75
L23:
  mov    %ebp,(%r8)
  mov    %edi,(%rbx)
  mov    %r12,%rbx
  cmp    %r13d,%r10d
  jne    L79
L51:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  mov    %rbx,%r8
  mov    %ebp,%edi
  lea    0x4(%rbx),%r12
  mov    %ebp,(%r8)
  mov    %edi,(%rbx)
  mov    %r12,%rbx
  cmp    %r13d,%r10d
  jne    L79
  jmp    L51
```

assistant: ```c
int sort(int a[], int n) {
  int i, j, k, tmp;
  for (i = 0; i < n - 1; i++) {
    k = i;
    for (j = i + 1; j < n; j++)
      if (a[j] < a[k])
        k = j;
    tmp = a[k];
    a[k] = a[i];
    a[i] = tmp;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sort>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %r13d,%r13d
  jle    L62
  mov    %rdi,%r11
  mov    %rdi,%rbx
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L52:
  mov    %r10d,%r9d
  add    $0x1,%r10d
  mov    (%rbx),%ebp
  cmp    %r10d,%esi
  jle    L8
  lea    0x4(%rbx),%r12
  mov    %ebp,%edi
  mov    %r10d,%edx
  mov    %r12,%rax
  jmp    L84
  nopl   0x0(%rax)
L77:
  movslq %r9d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%r11,%rcx,4),%r8
  cmp    %esi,%edx
  je     L56
L84:
  mov    (%rax),%ecx
  mov    %rax,%r8
  cmp    %edi,%ecx
  jge    L77
  mov    %edx,%r9d
  add    $0x1,%edx
  mov    %ecx,%edi
  add    $0x4,%rax
  cmp    %esi,%edx
  jne    L84
L56:
  mov    %ebp,(%r8)
  mov    %edi,(%rbx)
  mov    %r12,%rbx
  cmp    %r13d,%r10d
  jne    L52
L62:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  mov    %rbx,%r8
  mov    %ebp,%edi
  lea    0x4(%rbx),%r12
  mov    %ebp,(%r8)
  mov    %edi,(%rbx)
  mov    %r12,%rbx
  cmp    %r13d,%r10d
  jne    L52
  jmp    L62
```

assistant: ```c
int sort(int a[], int n) {
  int i, j, k, tmp;
  for (i = 0; i < n - 1; i++) {
    k = i;
    for (j = i + 1; j < n; j++)
      if (a[j] < a[k])
        k = j;
    tmp = a[k];
    a[k] = a[i];
    a[i] = tmp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mem_vla_range_store_idx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  cmpl   $0x2,-0x54(%rbp)
  jle    L3
  cmpl   $0x4,-0x54(%rbp)
  jle    L31
L3:
  movl   $0x3,-0x54(%rbp)
L31:
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x50(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rcx
  movslq %eax,%rdx
  add    $0x1,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  add    $0x1,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x1(%rax),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  mov    %rsp,%rdx
  sub    %rsi,%rdx
L51:
  cmp    %rdx,%rsp
  je     L16
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L51
L16:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L24
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L24:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x48(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x48(%rbp),%rax
  movb   $0x0,(%rax,%rcx,1)
  addq   $0x1,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  movb   $0x1,(%rax)
  addq   $0x1,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  movb   $0x2,(%rax)
  mov    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sink@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void mem_vla_range_store_idx(int n) {
  if (n < 3 || 4 < n)
    n = 3;
  struct {
    char a[n], b;
  } s;
  char *p = s.a;
  s.a[0] = 0;
  s.b = 0;
  *++p = 1;
  *++p = 2;
  sink(&s, p);
}
```