ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clamp>:
  endbr64
  cmp    %edx,%esi
  cmovle %esi,%edx
  cmp    %edi,%esi
  mov    %edi,%eax
  cmovge %edx,%eax
  ret
```

assistant: ```c
int clamp(int min, int val, int max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clamp>:
  endbr64
  cmp    %edx,%esi
  mov    %edi,%eax
  cmovle %esi,%edx
  cmp    %edi,%esi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int clamp(int min, int val, int max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clamp>:
  endbr64
  cmp    %edx,%esi
  mov    %edi,%eax
  cmovle %esi,%edx
  cmp    %edi,%esi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int clamp(int min, int val, int max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<short2net>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %ax,-0x4(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzwl -0x4(%rbp),%edx
  mov    %dl,(%rax)
  shrw   $0x8,-0x4(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movzwl -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void short2net(unsigned short int i, unsigned char **bufp) {
  *(*bufp + 1) = (unsigned char)i;
  i >>= 8;
  **bufp = (unsigned char)i;
  *bufp += 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<short2net>:
  endbr64
  mov    %edi,%eax
  mov    (%rsi),%rdx
  mov    %dil,0x1(%rdx)
  mov    (%rsi),%rdx
  movzbl %ah,%eax
  mov    %al,(%rdx)
  addq   $0x2,(%rsi)
  ret
```

assistant: ```c
void short2net(unsigned short int i, unsigned char **bufp) {
  *(*bufp + 1) = (unsigned char)i;
  i >>= 8;
  **bufp = (unsigned char)i;
  *bufp += 2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<short2net>:
  endbr64
  mov    (%rsi),%rdx
  mov    %edi,%eax
  mov    %dil,0x1(%rdx)
  mov    (%rsi),%rdx
  mov    %ah,(%rdx)
  addq   $0x2,(%rsi)
  ret
```

assistant: ```c
void short2net(unsigned short int i, unsigned char **bufp) {
  *(*bufp + 1) = (unsigned char)i;
  i >>= 8;
  **bufp = (unsigned char)i;
  *bufp += 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<short2net>:
  endbr64
  mov    (%rsi),%rdx
  mov    %edi,%eax
  mov    %dil,0x1(%rdx)
  mov    (%rsi),%rdx
  mov    %ah,(%rdx)
  addq   $0x2,(%rsi)
  ret
```

assistant: ```c
void short2net(unsigned short int i, unsigned char **bufp) {
  *(*bufp + 1) = (unsigned char)i;
  i >>= 8;
  **bufp = (unsigned char)i;
  *bufp += 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__cxa_pure_virtual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L2:
  jmp    L2
```

assistant: ```c
void __cxa_pure_virtual(void) {
  while (1) {
    ;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__cxa_pure_virtual>:
  endbr64
L0:
  jmp    L0
```

assistant: ```c
void __cxa_pure_virtual(void) {
  while (1) {
    ;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__cxa_pure_virtual>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
void __cxa_pure_virtual(void) {
  while (1) {
    ;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__cxa_pure_virtual>:
  endbr64
  nopl   0x0(%rax)
L1:
  jmp    L1
```

assistant: ```c
void __cxa_pure_virtual(void) {
  while (1) {
    ;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<i2c_smbus_process_call>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  lea    -0xc(%rbp),%rdi
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <i2c_smbus_access@plt>
  test   %rax,%rax
  je     L12
  mov    $0xffffffff,%eax
  jmp    L15
L12:
  mov    -0xc(%rbp),%eax
  movzwl %ax,%eax
L15:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
__s32 i2c_smbus_process_call(int file, __u8 command, __u16 value) {
  union i2c_smbus_data data;
  data.word = value;
  if (i2c_smbus_access(file, I2C_SMBUS_WRITE, command, I2C_SMBUS_PROC_CALL, &data))
    return -1;
  else
    return 0x0FFFF & data.word;
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2c_smbus_process_call>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edx,0x4(%rsp)
  lea    0x4(%rsp),%r8
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    %esi,%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <i2c_smbus_access@plt>
  test   %rax,%rax
  jne    L12
  movzwl 0x4(%rsp),%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L2
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_process_call(int file, __u8 command, __u16 value) {
  union i2c_smbus_data data;
  data.word = value;
  if (i2c_smbus_access(file, I2C_SMBUS_WRITE, command, I2C_SMBUS_PROC_CALL, &data))
    return -1;
  else
    return 0x0FFFF & data.word;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<i2c_smbus_process_call>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %edx,0x4(%rsp)
  mov    %esi,%edx
  lea    0x4(%rsp),%r8
  mov    (%rax),%ecx
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <i2c_smbus_access@plt>
  test   %rax,%rax
  jne    L24
  movzwl 0x4(%rsp),%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L24:
  mov    $0xffffffff,%eax
  jmp    L10
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_process_call(int file, __u8 command, __u16 value) {
  union i2c_smbus_data data;
  data.word = value;
  if (i2c_smbus_access(file, I2C_SMBUS_WRITE, command, I2C_SMBUS_PROC_CALL, &data))
    return -1;
  else
    return 0x0FFFF & data.word;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<i2c_smbus_process_call>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D14(%rip),%rax
  mov    %edx,0x4(%rsp)
  mov    %esi,%edx
  lea    0x4(%rsp),%r8
  mov    (%rax),%ecx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <i2c_smbus_access@plt>
  test   %rax,%rax
  jne    L4
  movzwl 0x4(%rsp),%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%eax
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_process_call(int file, __u8 command, __u16 value) {
  union i2c_smbus_data data;
  data.word = value;
  if (i2c_smbus_access(file, I2C_SMBUS_WRITE, command, I2C_SMBUS_PROC_CALL, &data))
    return -1;
  else
    return 0x0FFFF & data.word;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L11:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string

tool: D9: %s 

tool: D10:  -> 

assistant: ```c
void do_one(char *name, double (*f)(double), double *args, int nargs, char *argfmt, char *resfmt) {
  int i;
  double a, r;
  printf("\n");
  for (i = 0; i < nargs; i++) {
    a = args[i];
    r = f(a);
    printf("%s ", name);
    printf(argfmt, a);
    printf(" -> ");
    printf(resfmt, r);
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<do_one>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %ecx,%r13d
  mov    %r8,0x18(%rsp)
  mov    %r9,%r12
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %r13d,%r13d
  jle    L16
  mov    %r14,%rbx
  lea    -0x1(%r13),%eax
  lea    0x8(%r14,%rax,8),%r15
  lea    D3(%rip),%r14
  lea    D13(%rip),%r13
L12:
  movsd  (%rbx),%xmm1
  movsd  %xmm1,(%rsp)
  movapd %xmm1,%xmm0
  call   *%rbp
  movsd  %xmm0,0x8(%rsp)
  mov    0x10(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L12
L16:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string
name: read_data
arguments: tag: D13
type_infered: string

tool: D3: %s 

tool: D13:  -> 

assistant: ```c
void do_one(char *name, double (*f)(double), double *args, int nargs, char *argfmt, char *resfmt) {
  int i;
  double a, r;
  printf("\n");
  for (i = 0; i < nargs; i++) {
    a = args[i];
    r = f(a);
    printf("%s ", name);
    printf(argfmt, a);
    printf(" -> ");
    printf(resfmt, r);
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_one>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  sub    $0x28,%rsp
  mov    %rsi,0x10(%rsp)
  call   <putchar@plt>
  test   %r15d,%r15d
  jle    L4
  lea    -0x1(%r15),%eax
  lea    D12(%rip),%r14
  lea    0x8(%rbp,%rax,8),%rax
  lea    D11(%rip),%r15
  mov    %rax,0x18(%rsp)
  nopl   (%rax)
L19:
  movsd  0x0(%rbp),%xmm2
  mov    0x10(%rsp),%rax
  add    $0x8,%rbp
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   *%rax
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %r12,%rdi
  mov    $0x1,%eax
  movapd %xmm2,%xmm0
  call   <printf@plt>
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  (%rsp),%xmm1
  mov    %r13,%rdi
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    0x18(%rsp),%rbp
  jne    L19
L4:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D11
type: string

tool: D12:  -> 

tool: D11: %s 

assistant: ```c
void do_one(char *name, double (*f)(double), double *args, int nargs, char *argfmt, char *resfmt) {
  int i;
  double a, r;
  printf("\n");
  for (i = 0; i < nargs; i++) {
    a = args[i];
    r = f(a);
    printf("%s ", name);
    printf(argfmt, a);
    printf(" -> ");
    printf(resfmt, r);
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_one>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  sub    $0x28,%rsp
  mov    %rsi,0x10(%rsp)
  call   <putchar@plt>
  test   %r15d,%r15d
  jle    L2
  lea    -0x1(%r15),%eax
  lea    D11(%rip),%r14
  lea    0x8(%rbp,%rax,8),%rax
  lea    D0(%rip),%r15
  mov    %rax,0x18(%rsp)
  nopl   (%rax)
L14:
  movsd  0x0(%rbp),%xmm2
  mov    0x10(%rsp),%rax
  add    $0x8,%rbp
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   *%rax
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %r12,%rdi
  mov    $0x1,%eax
  movapd %xmm2,%xmm0
  call   <printf@plt>
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  (%rsp),%xmm1
  mov    %r13,%rdi
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    0x18(%rsp),%rbp
  jne    L14
L2:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D0
type: string

tool: D11:  -> 

tool: D0: %s 

assistant: ```c
void do_one(char *name, double (*f)(double), double *args, int nargs, char *argfmt, char *resfmt) {
  int i;
  double a, r;
  printf("\n");
  for (i = 0; i < nargs; i++) {
    a = args[i];
    r = f(a);
    printf("%s ", name);
    printf(argfmt, a);
    printf(" -> ");
    printf(resfmt, r);
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<suma_resta2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: suma=%d y resta=%d


assistant: ```c
void suma_resta2(int a, int b, int *s, int *r) {
  *s = a + b;
  *r = a - b;
  printf("suma=%d y resta=%d\n", *s, *r);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<suma_resta2>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rax
  lea    (%rdi,%rsi,1),%edx
  mov    %edx,(%rax)
  mov    %edi,%edx
  sub    %esi,%edx
  mov    %edx,(%rcx)
  mov    (%rax),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: suma=%d y resta=%d


assistant: ```c
void suma_resta2(int a, int b, int *s, int *r) {
  *s = a + b;
  *r = a - b;
  printf("suma=%d y resta=%d\n", *s, *r);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<suma_resta2>:
  endbr64
  mov    %rdx,%rax
  lea    (%rdi,%rsi,1),%edx
  mov    %edx,(%rax)
  mov    %edi,%edx
  lea    D3(%rip),%rdi
  sub    %esi,%edx
  mov    %edx,(%rcx)
  mov    (%rax),%esi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: suma=%d y resta=%d


assistant: ```c
void suma_resta2(int a, int b, int *s, int *r) {
  *s = a + b;
  *r = a - b;
  printf("suma=%d y resta=%d\n", *s, *r);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<suma_resta2>:
  endbr64
  mov    %rdx,%rax
  lea    (%rdi,%rsi,1),%edx
  mov    %edx,(%rax)
  mov    %edi,%edx
  lea    D6(%rip),%rdi
  sub    %esi,%edx
  mov    %edx,(%rcx)
  mov    (%rax),%esi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: suma=%d y resta=%d


assistant: ```c
void suma_resta2(int a, int b, int *s, int *r) {
  *s = a + b;
  *r = a - b;
  printf("suma=%d y resta=%d\n", *s, *r);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<waitpid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
pid_t waitpid(pid_t pid, int *stat_loc, int options) {
  errno = ENOSYS;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<waitpid>:
  endbr64
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t waitpid(pid_t pid, int *stat_loc, int options) {
  errno = ENOSYS;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<waitpid>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t waitpid(pid_t pid, int *stat_loc, int options) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<waitpid>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t waitpid(pid_t pid, int *stat_loc, int options) {
  errno = ENOSYS;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L21
  movl   $0xfffff,-0x10(%rbp)
  jmp    L14
L11:
  subl   $0x1,-0x10(%rbp)
L14:
  cmpl   $0x0,-0x10(%rbp)
  jg     L11
  mov    $0x0,%edi
  call   <exit@plt>
L21:
  mov    D27(%rip),%rax
  mov    (%rax),%edx
  lea    -0x14(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <wait4@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <syscall@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <syscall@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int main() {
  pid_t child;
  int status;
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, &status, WNOHANG, NULL);
  syscall(__NR_getpid);
  getppid();
  syscall(__NR_gettid);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L23
  mov    $0xfffff,%eax
L28:
  sub    $0x1,%eax
  jne    L28
  mov    $0x0,%edi
  call   <exit@plt>
L23:
  lea    0x4(%rsp),%rsi
  mov    $0x0,%ecx
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    %ebx,%edi
  call   <wait4@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  pid_t child;
  int status;
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, &status, WNOHANG, NULL);
  syscall(__NR_getpid);
  getppid();
  syscall(__NR_gettid);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L11
L13:
  mov    D25(%rip),%rax
  xor    %ecx,%ecx
  lea    0x4(%rsp),%rsi
  mov    %ebp,%edi
  mov    (%rax),%edx
  call   <wait4@plt>
  mov    D29(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L11:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L13
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  pid_t child;
  int status;
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, &status, WNOHANG, NULL);
  syscall(__NR_getpid);
  getppid();
  syscall(__NR_gettid);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L14
L15:
  mov    D15(%rip),%rax
  xor    %ecx,%ecx
  lea    0x4(%rsp),%rsi
  mov    %ebp,%edi
  mov    (%rax),%edx
  call   <wait4@plt>
  mov    D22(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L14:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L15
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  pid_t child;
  int status;
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, &status, WNOHANG, NULL);
  syscall(__NR_getpid);
  getppid();
  syscall(__NR_gettid);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<normalMV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L19:
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L17:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0xc,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L32:
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L17
  addl   $0x1,-0x8(%rbp)
L29:
  cmpl   $0x3ff,-0x8(%rbp)
  jle    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void normalMV(float c[1024][1024], float a[1024], float b[1024]) {
  int i, j;
  for (i = 0; i < 1024; i++)
    for (j = 0; j < 1024; j++)
      a[i] = a[i] + c[j][i] * b[j];
}
```