ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    $0x1e,%r12d
  movsd  D17(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  movsd  D42(%rip),%xmm4
  movsd  %xmm4,(%rsp)
  lea    D57(%rip),%r13
  lea    D1(%rip),%r14
  jmp    L11
L28:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %rbp,0x8(%rsp)
  jmp    L9
L32:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbp,(%rsp)
L9:
  sub    $0x1,%r12d
  je     L17
L11:
  movsd  (%rsp),%xmm1
  movapd %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  mulsd  D32(%rip),%xmm0
  movq   %xmm0,%rbp
  movapd %xmm1,%xmm0
  call   <f@plt>
  mov    %eax,%ebx
  movq   %rbp,%xmm0
  call   <f@plt>
  imul   %eax,%ebx
  test   %ebx,%ebx
  js     L28
  movsd  (%rsp),%xmm0
  call   <f@plt>
  mov    %eax,%ebx
  movq   %rbp,%xmm0
  call   <f@plt>
  imul   %eax,%ebx
  test   %ebx,%ebx
  jg     L32
  movq   %rbp,%xmm0
  lea    D31(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D42
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D57
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D32
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D31
type_infered: string

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D57: x

tool: D1: 1

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D31: %lf


assistant: ```c
int main() {
  double a, b, c, ea;
  a = -2;
  b = -1;
  int n, i;
  n = 30;
  for (i = 0; i < n; i++) {
    c = (a + b) / 2;
    if (f(a) * f(c) < 0) {
      printf("1\n");
      b = c;
    } else if (f(a) * f(c) > 0) {
      printf("x\n");
      a = c;
    } else {
      printf("%lf\n", c);
      return 0;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  mov    $0x1e,%ebp
  push   %rbx
  sub    $0x28,%rsp
  movsd  D7(%rip),%xmm3
  movsd  D25(%rip),%xmm1
  movsd  %xmm3,0x18(%rsp)
  jmp    L1
  nopl   0x0(%rax)
L4:
  movapd %xmm1,%xmm0
  call   <f@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  call   <f@plt>
  imul   %eax,%ebx
  test   %ebx,%ebx
  jle    L29
  mov    %r12,%rdi
  call   <puts@plt>
  movsd  0x8(%rsp),%xmm1
  sub    $0x1,%ebp
  je     L32
L1:
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm1,0x10(%rsp)
  addsd  %xmm1,%xmm0
  mulsd  D5(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <f@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  call   <f@plt>
  movsd  0x10(%rsp),%xmm1
  imul   %eax,%ebx
  test   %ebx,%ebx
  jns    L4
  mov    %r13,%rdi
  call   <puts@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm2,0x18(%rsp)
  sub    $0x1,%ebp
  jne    L1
L32:
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  movsd  0x8(%rsp),%xmm0
  lea    D43(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L32
```

tool_calls: name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D21
type: string
name: parse_data
arguments: label: D7
type: byte[8]
name: parse_data
arguments: label: D25
type: byte[8]
name: parse_data
arguments: label: D5
type: byte[8]
name: parse_data
arguments: label: D43
type: string

tool: D17: 1

tool: D21: x

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D43: %lf


assistant: ```c
int main() {
  double a, b, c, ea;
  a = -2;
  b = -1;
  int n, i;
  n = 30;
  for (i = 0; i < n; i++) {
    c = (a + b) / 2;
    if (f(a) * f(c) < 0) {
      printf("1\n");
      b = c;
    } else if (f(a) * f(c) > 0) {
      printf("x\n");
      a = c;
    } else {
      printf("%lf\n", c);
      return 0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  lea    D58(%rip),%r12
  push   %rbp
  mov    $0x1e,%ebp
  push   %rbx
  sub    $0x28,%rsp
  movsd  D17(%rip),%xmm3
  movsd  D45(%rip),%xmm1
  movsd  %xmm3,0x18(%rsp)
  jmp    L2
  nopl   0x0(%rax)
L47:
  movapd %xmm1,%xmm0
  call   <f@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  call   <f@plt>
  imul   %eax,%ebx
  test   %ebx,%ebx
  jle    L0
  mov    %r12,%rdi
  call   <puts@plt>
  movsd  0x8(%rsp),%xmm1
  sub    $0x1,%ebp
  je     L58
L2:
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm1,0x10(%rsp)
  addsd  %xmm1,%xmm0
  mulsd  D11(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <f@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  call   <f@plt>
  movsd  0x10(%rsp),%xmm1
  imul   %eax,%ebx
  test   %ebx,%ebx
  jns    L47
  mov    %r13,%rdi
  call   <puts@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm2,0x18(%rsp)
  sub    $0x1,%ebp
  jne    L2
L58:
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  movsd  0x8(%rsp),%xmm0
  lea    D46(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L58
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D58
datatype: string
name: read_data
arguments: data_tag: D17
datatype: byte[8]
name: read_data
arguments: data_tag: D45
datatype: byte[8]
name: read_data
arguments: data_tag: D11
datatype: byte[8]
name: read_data
arguments: data_tag: D46
datatype: string

tool: D14: 1

tool: D58: x

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D46: %lf


assistant: ```c
int main() {
  double a, b, c, ea;
  a = -2;
  b = -1;
  int n, i;
  n = 30;
  for (i = 0; i < n; i++) {
    c = (a + b) / 2;
    if (f(a) * f(c) < 0) {
      printf("1\n");
      b = c;
    } else if (f(a) * f(c) > 0) {
      printf("x\n");
      a = c;
    } else {
      printf("%lf\n", c);
      return 0;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<vp9_blit_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %ecx,%eax
  mov    %r8,%r14
  mov    %r9d,%r15d
  mov    %ecx,%edx
  sub    %r12d,%edx
  mov    %edx,%edi
  neg    %edi
  cmovs  %edx,%edi
  mov    %esi,%ecx
  sub    %ebx,%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  cmp    %edx,%edi
  jle    L46
  mov    %eax,%r13d
  mov    %esi,%eax
  mov    %ebx,%ecx
  mov    %r12d,%ebx
  mov    %ecx,%r12d
L46:
  cmp    %r13d,%ebx
  jle    L25
  mov    %r12d,%ecx
  mov    %eax,%r12d
  mov    %ecx,%eax
  mov    %ebx,%ecx
  mov    %r13d,%ebx
  mov    %ecx,%r13d
L25:
  mov    %r13d,%r10d
  sub    %ebx,%r10d
  mov    %r10d,0xc(%rsp)
  mov    %eax,%ecx
  sub    %r12d,%ecx
  mov    %ecx,%esi
  neg    %esi
  cmovns %esi,%ecx
  mov    %ecx,0x4(%rsp)
  mov    %r10d,%ebp
  shr    $0x1f,%ebp
  add    %r10d,%ebp
  sar    %ebp
  cmp    %eax,%r12d
  setl   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  mov    %eax,0x8(%rsp)
  cmp    %edx,%edi
  jg     L77
  cmp    %r13d,%ebx
  jle    L108
L69:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L77:
  cmp    %r13d,%ebx
  jle    L40
  jmp    L69
L12:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jl     L69
L40:
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <plot@plt>
  sub    0x4(%rsp),%ebp
  jns    L12
  add    0x8(%rsp),%r12d
  add    0xc(%rsp),%ebp
  jmp    L12
L68:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jl     L69
L108:
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <plot@plt>
  sub    0x4(%rsp),%ebp
  jns    L68
  add    0x8(%rsp),%r12d
  add    0xc(%rsp),%ebp
  jmp    L68
```

assistant: ```c
void vp9_blit_line(int x0, int x1, int y0, int y1, unsigned char *image, int pitch) {
  int steep = abs(y1 - y0) > abs(x1 - x0);
  int deltax, deltay;
  int error, ystep, y, x;
  if (steep) {
    int t;
    t = x0;
    x0 = y0;
    y0 = t;
    t = x1;
    x1 = y1;
    y1 = t;
  }
  if (x0 > x1) {
    int t;
    t = x0;
    x0 = x1;
    x1 = t;
    t = y0;
    y0 = y1;
    y1 = t;
  }
  deltax = x1 - x0;
  deltay = abs(y1 - y0);
  error = deltax / 2;
  y = y0;
  if (y0 < y1)
    ystep = 1;
  else
    ystep = -1;
  if (steep) {
    for (x = x0; x <= x1; x++) {
      plot(y, x, image, pitch);
      error = error - deltay;
      if (error < 0) {
        y = y + ystep;
        error = error + deltax;
      }
    }
  } else {
    for (x = x0; x <= x1; x++) {
      plot(x, y, image, pitch);
      error = error - deltay;
      if (error < 0) {
        y = y + ystep;
        error = error + deltax;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vp9_blit_line>:
  endbr64
  push   %r15
  mov    %ecx,%eax
  mov    %edi,%r15d
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  mov    %ecx,%edx
  sub    %ebx,%edx
  mov    %edx,%ecx
  sub    $0x18,%rsp
  neg    %ecx
  cmovs  %edx,%ecx
  sub    %edi,%esi
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  cmp    %edx,%ecx
  jle    L1
  mov    %ebp,%esi
  mov    %ebx,%r15d
  mov    %eax,%ebp
  mov    %edi,%ebx
  mov    %esi,%eax
L1:
  cmp    %ebp,%r15d
  jle    L49
  mov    %ebx,%esi
  mov    %eax,%ebx
  mov    %esi,%eax
  mov    %r15d,%esi
  mov    %ebp,%r15d
  mov    %esi,%ebp
L49:
  mov    %eax,%esi
  mov    %ebp,%r10d
  sub    %ebx,%esi
  sub    %r15d,%r10d
  mov    %esi,%edi
  mov    %r10d,%r8d
  mov    %r10d,0xc(%rsp)
  neg    %edi
  cmovns %edi,%esi
  shr    $0x1f,%r8d
  add    %r10d,%r8d
  sar    %r8d
  cmp    %eax,%ebx
  mov    %esi,0x4(%rsp)
  setl   %al
  mov    %r8d,%r14d
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  mov    %eax,0x8(%rsp)
  cmp    %edx,%ecx
  jg     L59
  cmp    %ebp,%r15d
  jg     L3
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r15d,%edi
  call   <plot@plt>
  sub    0x4(%rsp),%r14d
  jns    L80
  add    0x8(%rsp),%ebx
  add    0xc(%rsp),%r14d
L80:
  add    $0x1,%r15d
  cmp    %r15d,%ebp
  jge    L40
L3:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  cmp    %ebp,%r15d
  jg     L3
  nopl   (%rax)
L64:
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r15d,%esi
  mov    %ebx,%edi
  call   <plot@plt>
  sub    0x4(%rsp),%r14d
  jns    L32
  add    0x8(%rsp),%ebx
  add    0xc(%rsp),%r14d
L32:
  add    $0x1,%r15d
  cmp    %r15d,%ebp
  jge    L64
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void vp9_blit_line(int x0, int x1, int y0, int y1, unsigned char *image, int pitch) {
  int steep = abs(y1 - y0) > abs(x1 - x0);
  int deltax, deltay;
  int error, ystep, y, x;
  if (steep) {
    int t;
    t = x0;
    x0 = y0;
    y0 = t;
    t = x1;
    x1 = y1;
    y1 = t;
  }
  if (x0 > x1) {
    int t;
    t = x0;
    x0 = x1;
    x1 = t;
    t = y0;
    y0 = y1;
    y1 = t;
  }
  deltax = x1 - x0;
  deltay = abs(y1 - y0);
  error = deltax / 2;
  y = y0;
  if (y0 < y1)
    ystep = 1;
  else
    ystep = -1;
  if (steep) {
    for (x = x0; x <= x1; x++) {
      plot(y, x, image, pitch);
      error = error - deltay;
      if (error < 0) {
        y = y + ystep;
        error = error + deltax;
      }
    }
  } else {
    for (x = x0; x <= x1; x++) {
      plot(x, y, image, pitch);
      error = error - deltay;
      if (error < 0) {
        y = y + ystep;
        error = error + deltax;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vp9_blit_line>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  mov    %ecx,%eax
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    %ecx,%esi
  push   %rbx
  sub    %edx,%esi
  mov    %edx,%ebx
  mov    %ebp,%edi
  mov    %esi,%edx
  sub    $0x18,%rsp
  neg    %edx
  cmovs  %esi,%edx
  sub    %r15d,%edi
  mov    %edi,%ecx
  mov    %edi,0x8(%rsp)
  neg    %ecx
  mov    %edx,0x4(%rsp)
  cmovs  %edi,%ecx
  cmp    %ecx,%edx
  jle    L79
  mov    %esi,0x8(%rsp)
  mov    %ebp,%esi
  mov    %eax,%ebp
  mov    %ecx,0x4(%rsp)
  mov    %esi,%eax
  mov    %r15d,%esi
  mov    %ebx,%r15d
  mov    %esi,%ebx
L79:
  cmp    %ebp,%r15d
  jle    L64
  mov    %r15d,%edi
  mov    %ebx,%esi
  sub    %ebp,%edi
  sub    %eax,%esi
  mov    %edi,0x8(%rsp)
  mov    %esi,%edi
  neg    %edi
  cmovns %edi,%esi
  mov    %esi,0x4(%rsp)
  mov    %ebx,%esi
  mov    %eax,%ebx
  mov    %esi,%eax
  mov    %r15d,%esi
  mov    %ebp,%r15d
  mov    %esi,%ebp
L64:
  mov    0x8(%rsp),%esi
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    %eax,%ebx
  setl   %al
  mov    %r8d,%r14d
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  mov    %eax,0xc(%rsp)
  cmp    %ecx,%edx
  jg     L86
  cmp    %ebp,%r15d
  jg     L5
  nopw   0x0(%rax,%rax,1)
L73:
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r15d,%edi
  call   <plot@plt>
  sub    0x4(%rsp),%r14d
  jns    L46
  add    0xc(%rsp),%ebx
  add    0x8(%rsp),%r14d
L46:
  add    $0x1,%r15d
  cmp    %r15d,%ebp
  jge    L73
L5:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L86:
  cmp    %ebp,%r15d
  jg     L5
  nopl   (%rax)
L2:
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r15d,%esi
  mov    %ebx,%edi
  call   <plot@plt>
  sub    0x4(%rsp),%r14d
  jns    L15
  add    0xc(%rsp),%ebx
  add    0x8(%rsp),%r14d
L15:
  add    $0x1,%r15d
  cmp    %r15d,%ebp
  jge    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void vp9_blit_line(int x0, int x1, int y0, int y1, unsigned char *image, int pitch) {
  int steep = abs(y1 - y0) > abs(x1 - x0);
  int deltax, deltay;
  int error, ystep, y, x;
  if (steep) {
    int t;
    t = x0;
    x0 = y0;
    y0 = t;
    t = x1;
    x1 = y1;
    y1 = t;
  }
  if (x0 > x1) {
    int t;
    t = x0;
    x0 = x1;
    x1 = t;
    t = y0;
    y0 = y1;
    y1 = t;
  }
  deltax = x1 - x0;
  deltay = abs(y1 - y0);
  error = deltax / 2;
  y = y0;
  if (y0 < y1)
    ystep = 1;
  else
    ystep = -1;
  if (steep) {
    for (x = x0; x <= x1; x++) {
      plot(y, x, image, pitch);
      error = error - deltay;
      if (error < 0) {
        y = y + ystep;
        error = error + deltax;
      }
    }
  } else {
    for (x = x0; x <= x1; x++) {
      plot(x, y, image, pitch);
      error = error - deltay;
      if (error < 0) {
        y = y + ystep;
        error = error + deltax;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glClear@plt>
  mov    $0x0,%eax
  call   <glutSwapBuffers@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void display(void) {
  glClear(GL_COLOR_BUFFER_BIT);
  glutSwapBuffers();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <glClear@plt>
  mov    $0x0,%eax
  call   <glutSwapBuffers@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void display(void) {
  glClear(GL_COLOR_BUFFER_BIT);
  glutSwapBuffers();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <glClear@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <glutSwapBuffers@plt>
```

assistant: ```c
void display(void) {
  glClear(GL_COLOR_BUFFER_BIT);
  glutSwapBuffers();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <glClear@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <glutSwapBuffers@plt>
```

assistant: ```c
void display(void) {
  glClear(GL_COLOR_BUFFER_BIT);
  glutSwapBuffers();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: current tid is 0x%lx


assistant: ```c
void *printid(void *i) {
  printf("current tid is 0x%lx\n", pthread_self());
  return (void *)0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printid>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: current tid is 0x%lx


assistant: ```c
void *printid(void *i) {
  printf("current tid is 0x%lx\n", pthread_self());
  return (void *)0;
}
```
user: What is the c source code of the assembly code below:

```asm
<printid>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pthread_self@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: current tid is 0x%lx


assistant: ```c
void *printid(void *i) {
  printf("current tid is 0x%lx\n", pthread_self());
  return (void *)0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printid>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pthread_self@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string

tool: D1: current tid is 0x%lx


assistant: ```c
void *printid(void *i) {
  printf("current tid is 0x%lx\n", pthread_self());
  return (void *)0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__rawmemchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %al,-0x31(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L34
L72:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L36
  mov    -0x30(%rbp),%rax
  jmp    L10
L36:
  addq   $0x1,-0x30(%rbp)
L34:
  mov    -0x30(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L72
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movq   $0x7efefeff,-0x20(%rbp)
  movzbl -0x31(%rbp),%edx
  movzbl -0x31(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x10,%rax
  or     %rax,-0x18(%rbp)
L18:
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%rax
  xor    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  xor    -0x10(%rbp),%rax
  or     -0x20(%rbp),%rax
  cmp    $0xffffffffffffffff,%rax
  je     L18
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  jmp    L10
L5:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L23
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L10
L23:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L45
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  jmp    L10
L45:
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
L10:
  pop    %rbp
  ret
```

assistant: ```c
void *__rawmemchr(s, c_in) const void *s;
int c_in;
{
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  if (sizeof(longword) != 4 && sizeof(longword) != 8)
    abort();
  magic_bits = 0x7efefeff;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__rawmemchr>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  test   $0x7,%al
  je     L106
L35:
  cmp    %cl,(%rax)
  je     L82
  add    $0x1,%rax
  test   $0x7,%al
  jne    L35
L106:
  movzbl %sil,%esi
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  movslq %edx,%rdx
  mov    %rdx,%r8
  shl    $0x10,%r8
  or     %rdx,%r8
L103:
  mov    %rax,%rdi
  add    $0x8,%rax
  mov    %r8,%rsi
  xor    -0x8(%rax),%rsi
  lea    0x7efefeff(%rsi),%rdx
  xor    %rsi,%rdx
  or     $0x7efefeff,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L103
  cmp    %cl,-0x8(%rax)
  je     L38
  cmp    %cl,-0x7(%rax)
  je     L49
  cmp    %cl,-0x6(%rax)
  je     L11
  cmp    %cl,-0x5(%rax)
  jne    L103
  add    $0x3,%rdi
  jmp    L38
L49:
  add    $0x1,%rdi
  jmp    L38
L11:
  add    $0x2,%rdi
  jmp    L38
L82:
  mov    %rax,%rdi
L38:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *__rawmemchr(s, c_in) const void *s;
int c_in;
{
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  if (sizeof(longword) != 4 && sizeof(longword) != 8)
    abort();
  magic_bits = 0x7efefeff;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```