ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmp>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <keytoid@plt>
  lea    0x4(%rsp),%rdi
  mov    %rbx,%rsi
  call   <keytoid@plt>
  mov    (%rsp),%eax
  sub    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmp(unsigned char *a, unsigned char *b) {
  unsigned int na, nb;
  keytoid(&na, a);
  keytoid(&nb, b);
  return na - nb;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rbp
  mov    %r8,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <keytoid@plt>
  lea    0x4(%rsp),%rdi
  mov    %rbp,%rsi
  call   <keytoid@plt>
  mov    (%rsp),%eax
  sub    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmp(unsigned char *a, unsigned char *b) {
  unsigned int na, nb;
  keytoid(&na, a);
  keytoid(&nb, b);
  return na - nb;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rbp
  mov    %r8,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <keytoid@plt>
  lea    0x4(%rsp),%rdi
  mov    %rbp,%rsi
  call   <keytoid@plt>
  mov    (%rsp),%eax
  sub    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmp(unsigned char *a, unsigned char *b) {
  unsigned int na, nb;
  keytoid(&na, a);
  keytoid(&nb, b);
  return na - nb;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<recupererNomRace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *recupererNomRace(const unsigned int indexRace) {
  static const char *baseTypeRace[6] = {"Humain", "Alien", "Nain", "Sorcier", "Guerrier", "Ogre"};
  return baseTypeRace[indexRace];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<recupererNomRace>:
  endbr64
  mov    %edi,%edi
  lea    D0(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
const char *recupererNomRace(const unsigned int indexRace) {
  static const char *baseTypeRace[6] = {"Humain", "Alien", "Nain", "Sorcier", "Guerrier", "Ogre"};
  return baseTypeRace[indexRace];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<recupererNomRace>:
  endbr64
  mov    %edi,%edi
  lea    D5(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
const char *recupererNomRace(const unsigned int indexRace) {
  static const char *baseTypeRace[6] = {"Humain", "Alien", "Nain", "Sorcier", "Guerrier", "Ogre"};
  return baseTypeRace[indexRace];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<recupererNomRace>:
  endbr64
  mov    %edi,%edi
  lea    D4(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
const char *recupererNomRace(const unsigned int indexRace) {
  static const char *baseTypeRace[6] = {"Humain", "Alien", "Nain", "Sorcier", "Guerrier", "Ogre"};
  return baseTypeRace[indexRace];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<s4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <rand@plt>
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L31:
  mov    -0x10(%rbp),%eax
  mov    %al,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %al,-0xb(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %al,-0xa(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    0x1(%rdx),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L11
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %eax,%eax
  je     L31
L11:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void s4(FILE *out, int count) {
  int i;
  int c = (unsigned char)rand();
  for (i = 0; i < count && !ferror(out); i++) {
    char s[4] = {c, c, c, c};
    fwrite(s, 1, 4, out);
    c += 1 + (rand() % 255);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s4>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  movzbl %al,%ebx
  mov    $0x0,%ebp
  lea    0x4(%rsp),%r14
  test   %r13d,%r13d
  jle    L7
L0:
  mov    %r12,%rdi
  call   <ferror@plt>
  test   %eax,%eax
  jne    L7
  mov    %bl,0x4(%rsp)
  mov    %bl,0x5(%rsp)
  mov    %bl,0x6(%rsp)
  mov    %bl,0x7(%rsp)
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <fwrite@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  lea    0x1(%rbx,%rax,1),%ebx
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L0
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void s4(FILE *out, int count) {
  int i;
  int c = (unsigned char)rand();
  for (i = 0; i < count && !ferror(out); i++) {
    char s[4] = {c, c, c, c};
    fwrite(s, 1, 4, out);
    c += 1 + (rand() % 255);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<s4>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <rand@plt>
  movzbl %al,%r14d
  test   %r12d,%r12d
  jg     L25
  jmp    L13
  nopl   (%rax)
L46:
  mov    %rbp,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    %r14b,0x4(%rsp)
  add    $0x1,%ebx
  mov    %r14b,0x5(%rsp)
  mov    %r14b,0x6(%rsp)
  mov    %r14b,0x7(%rsp)
  call   <fwrite@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  lea    0x1(%r14,%rax,1),%r14d
  cmp    %ebx,%r12d
  je     L13
L25:
  mov    %rbp,%rdi
  call   <ferror@plt>
  test   %eax,%eax
  je     L46
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void s4(FILE *out, int count) {
  int i;
  int c = (unsigned char)rand();
  for (i = 0; i < count && !ferror(out); i++) {
    char s[4] = {c, c, c, c};
    fwrite(s, 1, 4, out);
    c += 1 + (rand() % 255);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<s4>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <rand@plt>
  movzbl %al,%r14d
  test   %r12d,%r12d
  jg     L42
  jmp    L11
  nopl   (%rax)
L2:
  xor    %eax,%eax
  mov    %r14d,%ecx
  movzbl %r14b,%edx
  mov    $0x1,%esi
  mov    %r14b,%al
  mov    %r13,%rdi
  add    $0x1,%ebx
  mov    %cl,%ah
  mov    %edx,%ecx
  shl    $0x18,%edx
  shl    $0x10,%ecx
  movzwl %ax,%eax
  or     %ecx,%eax
  mov    %rbp,%rcx
  or     %edx,%eax
  mov    $0x4,%edx
  mov    %eax,0x4(%rsp)
  call   <fwrite@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80808081,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  lea    0x1(%r14,%rax,1),%r14d
  cmp    %ebx,%r12d
  je     L11
L42:
  mov    %rbp,%rdi
  call   <ferror@plt>
  test   %eax,%eax
  je     L2
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void s4(FILE *out, int count) {
  int i;
  int c = (unsigned char)rand();
  for (i = 0; i < count && !ferror(out); i++) {
    char s[4] = {c, c, c, c};
    fwrite(s, 1, 4, out);
    c += 1 + (rand() % 255);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x32(%rsp),%rbp
  mov    %rbp,%r12
  mov    $0x0,%r13d
  mov    $0x31,%r14d
  jmp    L22
L52:
  add    $0x1,%r13d
  add    $0x32,%r12
  cmp    $0x32,%r13d
  je     L87
L22:
  lea    -0x32(%r12),%rax
L60:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L60
  pxor   %xmm0,%xmm0
  cvtsi2ss %r13d,%xmm0
  divss  D7(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    $0x1,%eax
  call   <f@plt>
  imul   $0x32,%eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  comiss D10(%rip),%xmm0
  jbe    L52
  movss  D7(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L52
  cvtss2sd %xmm0,%xmm0
  mov    $0x1,%eax
  call   <C@plt>
  mov    %eax,%edx
  mov    %r14d,%eax
  sub    %edx,%eax
  cltq
  movslq %r13d,%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    0xa10(%rsp,%rdx,2),%rdx
  movb   $0x91,-0xa10(%rax,%rdx,1)
  jmp    L52
L87:
  lea    0xa02(%rsp),%r12
L83:
  lea    0x9d0(%rsp),%rax
  mov    %rbx,%rdx
L88:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  add    $0x32,%rdx
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L88
  lea    0x9d0(%rsp),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  mov    $0xa,%edi
  mov    $0x0,%eax
  call   <print@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L83
  mov    0xa08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0xa10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type: byte[4]
name: disassemble_data
arguments: label: D10
type: byte[4]

tool: {"D7": [0x00,0x00,0x48,0x42]}

tool: {"D10": [0x00,0x00,0x80,0xbf]}

assistant: ```c
void main() {
  char ekr[50][50], t[50];
  int i, j, y;
  float x;
  for (i = 0; i < 50; i++) {
    for (j = 0; j < 50; j++)
      ekr[i][j] = ' ';
    x = i;
    x = f(x / 50) * 50;
    if ((x > -1) && (x < 50)) {
      y = 50 - 1 - C(x);
      ekr[i][y] = 'ё';
    }
  }
  for (i = 0; i < 50; i++) {
    for (j = 0; j < 50; j++)
      t[j] = ekr[j][i];
    print(t);
    print('\n');
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    $0x31,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa08(%rsp)
  xor    %eax,%eax
  lea    0x32(%rsp),%rbp
  mov    %rsp,%rbx
  mov    %rbp,%r12
  nopw   0x0(%rax,%rax,1)
L71:
  lea    -0x32(%r12),%rax
  nopl   (%rax)
L59:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L59
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtsi2ss %r14d,%xmm0
  divss  D22(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <f@plt>
  pxor   %xmm0,%xmm0
  imul   $0x32,%eax,%eax
  cvtsi2ss %eax,%xmm0
  comiss D12(%rip),%xmm0
  jbe    L8
  movss  D22(%rip),%xmm1
  comiss %xmm0,%xmm1
  ja     L66
L8:
  add    $0x1,%r14d
  add    $0x32,%r12
  cmp    $0x32,%r14d
  jne    L71
  lea    0x9d0(%rsp),%r13
  lea    0xa02(%rsp),%r12
  cs nopw 0x0(%rax,%rax,1)
L64:
  mov    %r13,%rax
  mov    %rbx,%rdx
  cs nopw 0x0(%rax,%rax,1)
L5:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  add    $0x32,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rax,%r12
  jne    L5
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <print@plt>
  mov    $0xa,%edi
  xor    %eax,%eax
  call   <print@plt>
  cmp    %rbp,%rbx
  jne    L64
  mov    0xa08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xa10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L66:
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <C@plt>
  movslq %r14d,%rdx
  mov    %eax,%r8d
  lea    (%rdx,%rdx,4),%rdx
  mov    %r13d,%eax
  sub    %r8d,%eax
  lea    (%rdx,%rdx,4),%rdx
  cltq
  lea    0xa10(%rsp,%rdx,2),%rdx
  movb   $0x91,-0xa10(%rax,%rdx,1)
  jmp    L8
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D12
type_guessed: byte[4]

tool: {"D22": [0x00,0x00,0x48,0x42]}

tool: {"D12": [0x00,0x00,0x80,0xbf]}

assistant: ```c
void main() {
  char ekr[50][50], t[50];
  int i, j, y;
  float x;
  for (i = 0; i < 50; i++) {
    for (j = 0; j < 50; j++)
      ekr[i][j] = ' ';
    x = i;
    x = f(x / 50) * 50;
    if ((x > -1) && (x < 50)) {
      y = 50 - 1 - C(x);
      ekr[i][y] = 'ё';
    }
  }
  for (i = 0; i < 50; i++) {
    for (j = 0; j < 50; j++)
      t[j] = ekr[j][i];
    print(t);
    print('\n');
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *dvector(const size_t n) {
  double *v = (double *)calloc(n, sizeof(double));
  assert(v);
  return v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dvector>:
  endbr64
  push   %rbx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
double *dvector(const size_t n) {
  double *v = (double *)calloc(n, sizeof(double));
  assert(v);
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dvector>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
double *dvector(const size_t n) {
  double *v = (double *)calloc(n, sizeof(double));
  assert(v);
  return v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dvector>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
double *dvector(const size_t n) {
  double *v = (double *)calloc(n, sizeof(double));
  assert(v);
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<levdurb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  movl   $0x3f800000,(%rdi)
  movss  (%rdx),%xmm0
  movss  D28(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L47
  test   %ecx,%ecx
  jle    L104
  mov    %ecx,%ebx
  mov    $0x0,%eax
L20:
  movl   $0x0,(%rsi,%rax,4)
  movl   $0x0,0x4(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L20
L104:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  movss  0x4(%rdx),%xmm4
  xorps  D22(%rip),%xmm4
  divss  %xmm0,%xmm4
  movss  %xmm4,(%rsi)
  movss  %xmm4,0x4(%rdi)
  mulss  0x4(%rdx),%xmm4
  addss  (%rdx),%xmm4
  cmp    $0x1,%ecx
  jle    L104
  lea    0x4(%rsi),%r9
  lea    0x8(%rdi),%rcx
  lea    0x4(%rdx),%r10
  mov    $0x2,%r11d
  mov    $0x1,%ebp
  movss  D22(%rip),%xmm5
  jmp    L108
L107:
  mov    %r9,%rsi
  movaps %xmm1,%xmm0
  xorps  D22(%rip),%xmm0
  divss  %xmm4,%xmm0
  movss  %xmm0,(%r9)
  mulss  %xmm1,%xmm0
  addss  %xmm0,%xmm4
  mov    %r11d,%r12d
  mov    %r11d,%r8d
  sar    %r8d
  test   %r8d,%r8d
  jle    L90
L51:
  lea    -0x4(%rcx),%rdx
  mov    $0x0,%eax
L101:
  movss  0x4(%rdi,%rax,4),%xmm2
  movss  (%rsi),%xmm3
  movss  (%rdx),%xmm0
  movaps %xmm2,%xmm1
  mulss  %xmm3,%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  mulss  %xmm3,%xmm0
  addss  %xmm2,%xmm0
  movss  %xmm0,0x4(%rdi,%rax,4)
  add    $0x1,%rax
  sub    $0x4,%rdx
  cmp    %eax,%r8d
  jg     L101
L90:
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x1,%ebp
  add    $0x4,%r9
  add    $0x1,%r11d
  add    $0x4,%rcx
  add    $0x4,%r10
  cmp    %r12d,%ebx
  jle    L104
L108:
  movss  0x4(%r10),%xmm1
  test   %ebp,%ebp
  jle    L107
  lea    0x4(%rdi),%rax
  mov    %r10,%rdx
L63:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  addss  %xmm0,%xmm1
  add    $0x4,%rax
  sub    $0x4,%rdx
  cmp    %rcx,%rax
  jne    L63
  mov    %r9,%rsi
  movaps %xmm1,%xmm0
  xorps  %xmm5,%xmm0
  divss  %xmm4,%xmm0
  movss  %xmm0,(%r9)
  mulss  %xmm1,%xmm0
  addss  %xmm0,%xmm4
  mov    %r11d,%r12d
  mov    %r11d,%r8d
  sar    %r8d
  jmp    L51
```

tool_calls: name: parse_data
arguments: tag: D28
type_infered: byte[4]
name: parse_data
arguments: tag: D22
type_infered: byte[16]

tool: {"D28": [0x00,0x00,0x80,0x25]}

tool: {"D22": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void levdurb(float *a, float *k, float *r, int order) {
  float sum, alpha;
  int m, m_h, i;
  a[0] = 1.0;
  if (r[0] < (float)2.220446049250313e-016) {
    for (i = 0; i < order; i++) {
      k[i] = 0;
      a[i + 1] = 0;
    }
  } else {
    a[1] = k[0] = -r[1] / r[0];
    alpha = r[0] + r[1] * k[0];
    for (m = 1; m < order; m++) {
      sum = r[m + 1];
      for (i = 0; i < m; i++) {
        sum += a[i + 1] * r[m - i];
      }
      k[m] = -sum / alpha;
      alpha += k[m] * sum;
      m_h = (m + 1) >> 1;
      for (i = 0; i < m_h; i++) {
        sum = a[i + 1] + k[m] * a[m - i];
        a[m - i] += k[m] * a[i + 1];
        a[i + 1] = sum;
      }
      a[m + 1] = k[m];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  mov    $0x15,%edi
  call   <__get_cpuid@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int eax = 0, ebx = 0, ecx = 0, edx = 0;
  return __get_cpuid(0x15, &eax, &ebx, &ecx, &edx);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    $0x15,%edi
  call   <__get_cpuid@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  unsigned int eax = 0, ebx = 0, ecx = 0, edx = 0;
  return __get_cpuid(0x15, &eax, &ebx, &ecx, &edx);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x15,%edi
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <__get_cpuid@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  unsigned int eax = 0, ebx = 0, ecx = 0, edx = 0;
  return __get_cpuid(0x15, &eax, &ebx, &ecx, &edx);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x15,%edi
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <__get_cpuid@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  unsigned int eax = 0, ebx = 0, ecx = 0, edx = 0;
  return __get_cpuid(0x15, &eax, &ebx, &ecx, &edx);
}
```
user: What is the c source code of the assembly code below?

```asm
<ADCIntUnregister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x40038000,-0x18(%rbp)
  je     L44
  cmpq   $0x40039000,-0x18(%rbp)
  jne    L23
L44:
  mov    $0x1,%eax
  jmp    L12
L23:
  mov    $0x0,%eax
L12:
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmpq   $0x3,-0x20(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmpq   $0x40038000,-0x18(%rbp)
  jne    L49
  mov    -0x20(%rbp),%rax
  add    $0x1e,%rax
  jmp    L39
L49:
  mov    -0x20(%rbp),%rax
  add    $0x40,%rax
L39:
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntUnregister@plt>
  nop
  leave
  ret
```

assistant: ```c
void ADCIntUnregister(unsigned long ulBase, unsigned long ulSequenceNum) {
  unsigned long ulInt;
  DEBUG_ASSERT((ulBase == 0x40038000) || (ulBase == 0x40039000));
  DEBUG_ASSERT(ulSequenceNum < 4);
  ulInt = ((ulBase == 0x40038000) ? (30 + ulSequenceNum) : (64 + ulSequenceNum));
  IntDisable(ulInt);
  IntUnregister(ulInt);
}
```
user: What is the c source code of the assembly code below?

```asm
<ADCIntUnregister>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdi,%rax
  and    $0xef,%ah
  cmp    $0x40038000,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  cmp    $0x3,%rbx
  setbe  %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  lea    0x1e(%rbx),%rax
  add    $0x40,%rbx
  cmp    $0x40038000,%rbp
  cmove  %rax,%rbx
  mov    %rbx,%rdi
  call   <IntDisable@plt>
  mov    %rbx,%rdi
  call   <IntUnregister@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ADCIntUnregister(unsigned long ulBase, unsigned long ulSequenceNum) {
  unsigned long ulInt;
  DEBUG_ASSERT((ulBase == 0x40038000) || (ulBase == 0x40039000));
  DEBUG_ASSERT(ulSequenceNum < 4);
  ulInt = ((ulBase == 0x40038000) ? (30 + ulSequenceNum) : (64 + ulSequenceNum));
  IntDisable(ulInt);
  IntUnregister(ulInt);
}
```