user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x0,%ecx
  mov    $0x4ee728,%edx
L18:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L18
  mov    %ecx,%edx
  mov    $0x4ee728,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  mov    $0x0,%ecx
  mov    $0x63427,%edx
L45:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L45
  mov    %ecx,%edx
  mov    $0x63427,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  mov    $0x0,%ecx
  mov    $0x5a06e,%edx
L34:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L34
  mov    %ecx,%edx
  mov    $0x5a06e,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    $0x0,%ecx
  mov    $0x2427e6,%edx
L33:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L33
  mov    %ecx,%edx
  mov    $0x2427e6,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    $0x0,%ecx
  mov    $0x21507d,%edx
L24:
  lea    (%rcx,%rcx,4),%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdi,2),%ecx
  mov    %eax,%edx
  sub    $0x1,%esi
  jne    L24
  mov    %ecx,%edx
  mov    $0x21507d,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D43
type_infered: string

tool: D43: %d		%d


assistant: ```c
int main() {
  int num1, num, mun1 = 0;
  num1 = 5170984;
  num = num1;
  while (num1 != 0) {
    mun1 = (mun1 * 10) + (num1 % 10);
    num1 = num1 / 10;
  }
  printf("%d\t\t%d\n", num, mun1);
  num1 = 406567;
  num = num1;
  mun1 = 0;
  while (num1 != 0) {
    mun1 = (mun1 * 10) + (num1 % 10);
    num1 = num1 / 10;
  }
  printf("%d\t\t%d\n", num, mun1);
  num1 = 368750;
  num = num1;
  mun1 = 0;
  while (num1 != 0) {
    mun1 = (mun1 * 10) + (num1 % 10);
    num1 = num1 / 10;
  }
  printf("%d\t\t%d\n", num, mun1);
  num1 = 2369510;
  num = num1;
  mun1 = 0;
  while (num1 != 0) {
    mun1 = (mun1 * 10) + (num1 % 10);
    num1 = num1 / 10;
  }
  printf("%d\t\t%d\n", num, mun1);
  num1 = 2183293;
  num = num1;
  mun1 = 0;
  while (num1 != 0) {
    mun1 = (mun1 * 10) + (num1 % 10);
    num1 = num1 / 10;
  }
  printf("%d\t\t%d\n", num, mun1);
  return 0;
}
```