ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_id_list>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L66
L105:
  mov    $0x0,%r12d
  mov    %rsp,%rbx
  lea    D2(%rip),%r14
  lea    D7(%rip),%r15
  jmp    L48
L66:
  lea    D25(%rip),%rdi
  call   <error1@plt>
  jmp    L105
L100:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  jmp    L103
L2:
  add    $0x8,%rbp
L48:
  mov    %r13,%rdx
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L19
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L48
  cmp    $0x23,%al
  je     L48
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L19
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmpb   $0xa,(%rsp,%rax,1)
  je     L100
L103:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x1,%r12d
  cmp    $0x78,%r12d
  jle    L2
  mov    %r15,%rdi
  call   <error1@plt>
  jmp    L2
L19:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  mov    %r12d,%eax
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L110:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D25
type_infered: string

tool: D23: rb

tool: D2: $END

tool: D7: Number of ID is too large

tool: D25: Can't open idlist.txt

assistant: ```c
int read_id_list(char id[][8], char fname[]) {
  FILE *fp_list;
  char linebuf[200];
  int n = 0;
  if ((fp_list = fopen(fname, "rb")) == NULL)
    error1("Can't open idlist.txt");
  n = 0;
  while (fgets(linebuf, sizeof(linebuf), fp_list) != NULL) {
    if (linebuf[0] == '#')
      continue;
    else if (linebuf[0] == '\n')
      continue;
    else if (strncmp(linebuf, "$END", strlen("$END")) == 0) {
      break;
    }
    if (linebuf[strlen(linebuf) - 1] == '\n')
      linebuf[strlen(linebuf) - 1] = '\0';
    strcpy(id[n], linebuf);
    n++;
    if (n >= 121)
      error1("Number of ID is too large");
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_id_list>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  lea    D4(%rip),%rsi
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L60
L91:
  xor    %r12d,%r12d
  mov    %rsp,%rbx
  lea    D10(%rip),%r14
  lea    D35(%rip),%r15
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r13,%rdx
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L80
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L51
  cmp    $0x23,%al
  je     L51
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  je     L80
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmpb   $0xa,(%rsp,%rax,1)
  je     L70
L95:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <strcpy@plt>
  cmp    $0x78,%r12d
  jg     L12
L33:
  add    $0x8,%rbp
  jmp    L51
  nopl   (%rax)
L12:
  mov    %r15,%rdi
  call   <error1@plt>
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L70:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  jmp    L95
  nopl   0x0(%rax,%rax,1)
L80:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0xd8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  lea    D12(%rip),%rdi
  call   <error1@plt>
  jmp    L91
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string
name: disassemble_data
arguments: label: D35
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string

tool: D4: rb

tool: D10: $END

tool: D35: Number of ID is too large

tool: D12: Can't open idlist.txt

assistant: ```c
int read_id_list(char id[][8], char fname[]) {
  FILE *fp_list;
  char linebuf[200];
  int n = 0;
  if ((fp_list = fopen(fname, "rb")) == NULL)
    error1("Can't open idlist.txt");
  n = 0;
  while (fgets(linebuf, sizeof(linebuf), fp_list) != NULL) {
    if (linebuf[0] == '#')
      continue;
    else if (linebuf[0] == '\n')
      continue;
    else if (strncmp(linebuf, "$END", strlen("$END")) == 0) {
      break;
    }
    if (linebuf[strlen(linebuf) - 1] == '\n')
      linebuf[strlen(linebuf) - 1] = '\0';
    strcpy(id[n], linebuf);
    n++;
    if (n >= 121)
      error1("Number of ID is too large");
  }
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_id_list>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  lea    D33(%rip),%rsi
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L59
L102:
  xor    %r12d,%r12d
  mov    %rsp,%rbx
  lea    D1(%rip),%r14
  lea    D38(%rip),%r15
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r13,%rdx
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L17
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L39
  cmp    $0x23,%al
  je     L39
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  je     L17
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmpb   $0xa,(%rsp,%rax,1)
  je     L57
L74:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <strcpy@plt>
  cmp    $0x78,%r12d
  jg     L29
L22:
  add    $0x8,%rbp
  jmp    L39
  nopl   (%rax)
L29:
  mov    %r15,%rdi
  call   <error1@plt>
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0xd8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  lea    D29(%rip),%rdi
  call   <error1@plt>
  jmp    L102
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D33
type_guessed: string
name: read_data
arguments: label: D1
type_guessed: string
name: read_data
arguments: label: D38
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string

tool: D33: rb

tool: D1: $END

tool: D38: Number of ID is too large

tool: D29: Can't open idlist.txt

assistant: ```c
int read_id_list(char id[][8], char fname[]) {
  FILE *fp_list;
  char linebuf[200];
  int n = 0;
  if ((fp_list = fopen(fname, "rb")) == NULL)
    error1("Can't open idlist.txt");
  n = 0;
  while (fgets(linebuf, sizeof(linebuf), fp_list) != NULL) {
    if (linebuf[0] == '#')
      continue;
    else if (linebuf[0] == '\n')
      continue;
    else if (strncmp(linebuf, "$END", strlen("$END")) == 0) {
      break;
    }
    if (linebuf[strlen(linebuf) - 1] == '\n')
      linebuf[strlen(linebuf) - 1] = '\0';
    strcpy(id[n], linebuf);
    n++;
    if (n >= 121)
      error1("Number of ID is too large");
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dmp_set_tap_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpb   $0x0,-0x14(%rbp)
  jne    L21
  movb   $0x1,-0x14(%rbp)
  jmp    L38
L21:
  cmpb   $0x4,-0x14(%rbp)
  jbe    L38
  movb   $0x4,-0x14(%rbp)
L38:
  movzbl -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x9(%rbp)
  lea    -0x9(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x14f,%edi
  call   <mpu_write_mem@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int dmp_set_tap_count(unsigned char min_taps) {
  unsigned char tmp;
  if (min_taps < 1)
    min_taps = 1;
  else if (min_taps > 4)
    min_taps = 4;
  tmp = min_taps - 1;
  return mpu_write_mem((256 + 79), 1, &tmp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dmp_set_tap_count>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%eax
  cmp    %al,%dil
  cmova  %eax,%edi
  test   %dil,%dil
  mov    $0x1,%eax
  cmove  %eax,%edi
  sub    $0x1,%edi
  mov    %dil,0x7(%rsp)
  lea    0x7(%rsp),%rdx
  mov    $0x1,%esi
  mov    $0x14f,%edi
  call   <mpu_write_mem@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dmp_set_tap_count(unsigned char min_taps) {
  unsigned char tmp;
  if (min_taps < 1)
    min_taps = 1;
  else if (min_taps > 4)
    min_taps = 4;
  tmp = min_taps - 1;
  return mpu_write_mem((256 + 79), 1, &tmp);
}
```
user: What is the c source code of the assembly code below?

```asm
<dmp_set_tap_count>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%eax
  lea    0x7(%rsp),%rdx
  cmp    %al,%dil
  cmova  %eax,%edi
  mov    $0x1,%eax
  test   %dil,%dil
  cmove  %eax,%edi
  sub    $0x1,%edi
  mov    %dil,0x7(%rsp)
  mov    $0x14f,%edi
  call   <mpu_write_mem@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dmp_set_tap_count(unsigned char min_taps) {
  unsigned char tmp;
  if (min_taps < 1)
    min_taps = 1;
  else if (min_taps > 4)
    min_taps = 4;
  tmp = min_taps - 1;
  return mpu_write_mem((256 + 79), 1, &tmp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dmp_set_tap_count>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%eax
  lea    0x7(%rsp),%rdx
  cmp    %al,%dil
  cmova  %eax,%edi
  mov    $0x1,%eax
  test   %dil,%dil
  cmove  %eax,%edi
  sub    $0x1,%edi
  mov    %dil,0x7(%rsp)
  mov    $0x14f,%edi
  call   <mpu_write_mem@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dmp_set_tap_count(unsigned char min_taps) {
  unsigned char tmp;
  if (min_taps < 1)
    min_taps = 1;
  else if (min_taps > 4)
    min_taps = 4;
  tmp = min_taps - 1;
  return mpu_write_mem((256 + 79), 1, &tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<arriba>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    -0xc(%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rsi,%rax,4),%edx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %edx,(%rcx,%rax,4)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    -0xc(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void arriba(int x, int y, int mat[3][3]) {
  mat[x][y] = mat[x - 1][y];
  mat[x - 1][y] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<arriba>:
  endbr64
  movslq %edi,%rdi
  lea    (%rdi,%rdi,2),%rax
  shl    $0x2,%rax
  lea    -0xc(%rdx,%rax,1),%rcx
  movslq %esi,%rsi
  mov    (%rcx,%rsi,4),%edi
  lea    (%rdx,%rsi,4),%rdx
  mov    %edi,(%rdx,%rax,1)
  movl   $0x0,(%rcx,%rsi,4)
  ret
```

assistant: ```c
void arriba(int x, int y, int mat[3][3]) {
  mat[x][y] = mat[x - 1][y];
  mat[x - 1][y] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arriba>:
  endbr64
  movslq %edi,%rdi
  movslq %esi,%rsi
  lea    (%rdi,%rdi,2),%rax
  shl    $0x2,%rax
  lea    -0xc(%rdx,%rax,1),%rcx
  lea    (%rdx,%rsi,4),%rdx
  mov    (%rcx,%rsi,4),%edi
  mov    %edi,(%rdx,%rax,1)
  movl   $0x0,(%rcx,%rsi,4)
  ret
```

assistant: ```c
void arriba(int x, int y, int mat[3][3]) {
  mat[x][y] = mat[x - 1][y];
  mat[x - 1][y] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arriba>:
  endbr64
  movslq %edi,%rdi
  movslq %esi,%rsi
  lea    (%rdi,%rdi,2),%rax
  shl    $0x2,%rax
  lea    -0xc(%rdx,%rax,1),%rcx
  lea    (%rdx,%rsi,4),%rdx
  mov    (%rcx,%rsi,4),%edi
  mov    %edi,(%rdx,%rax,1)
  movl   $0x0,(%rcx,%rsi,4)
  ret
```

assistant: ```c
void arriba(int x, int y, int mat[3][3]) {
  mat[x][y] = mat[x - 1][y];
  mat[x - 1][y] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<old_int_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L14
  negl   -0x1c(%rbp)
  movsd  D16(%rip),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L14:
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L32
L16:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L9:
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  sarl   -0x1c(%rbp)
L32:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L16
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D16
type_infered: f64

tool: D16: 1

assistant: ```c
double old_int_power(double x, int y) {
  double value;
  if (y < 0) {
    y = -y;
    x = 1.0 / x;
  }
  value = 1.0;
  while (y) {
    if (y & 1) {
      value *= x;
    }
    x = x * x;
    y >>= 1;
  }
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<old_int_power>:
  endbr64
  test   %edi,%edi
  js     L31
  je     L16
L1:
  movsd  D18(%rip),%xmm1
  jmp    L54
L31:
  neg    %edi
  movsd  D18(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  jmp    L1
L51:
  mulsd  %xmm0,%xmm0
  sar    %edi
  je     L13
L54:
  test   $0x1,%dil
  je     L51
  mulsd  %xmm0,%xmm1
  jmp    L51
L16:
  movsd  D18(%rip),%xmm1
L13:
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: f64

tool: D18: 1

assistant: ```c
double old_int_power(double x, int y) {
  double value;
  if (y < 0) {
    y = -y;
    x = 1.0 / x;
  }
  value = 1.0;
  while (y) {
    if (y & 1) {
      value *= x;
    }
    x = x * x;
    y >>= 1;
  }
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<old_int_power>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  js     L24
  movsd  D12(%rip),%xmm0
  je     L11
  cs nopw 0x0(%rax,%rax,1)
L36:
  test   $0x1,%dil
  je     L47
  mulsd  %xmm1,%xmm0
L47:
  mulsd  %xmm1,%xmm1
  sar    %edi
  jne    L36
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  movsd  D12(%rip),%xmm0
  neg    %edi
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm1
  jmp    L36
L11:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: f64

tool: D12: 1

assistant: ```c
double old_int_power(double x, int y) {
  double value;
  if (y < 0) {
    y = -y;
    x = 1.0 / x;
  }
  value = 1.0;
  while (y) {
    if (y & 1) {
      value *= x;
    }
    x = x * x;
    y >>= 1;
  }
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<old_int_power>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  js     L37
  movsd  D9(%rip),%xmm0
  je     L46
  cs nopw 0x0(%rax,%rax,1)
L27:
  test   $0x1,%dil
  je     L25
  mulsd  %xmm1,%xmm0
L25:
  mulsd  %xmm1,%xmm1
  sar    %edi
  jne    L27
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  movsd  D9(%rip),%xmm0
  neg    %edi
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm1
  jmp    L27
L46:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: f64

tool: D9: 1

assistant: ```c
double old_int_power(double x, int y) {
  double value;
  if (y < 0) {
    y = -y;
    x = 1.0 / x;
  }
  value = 1.0;
  while (y) {
    if (y & 1) {
      value *= x;
    }
    x = x * x;
    y >>= 1;
  }
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *why) {
  perror(why);
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die(const char *why) {
  perror(why);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void die(const char *why) {
  perror(why);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void die(const char *why) {
  perror(why);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<factor_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L41
L23:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L5
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L32:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L32
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L5:
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L23
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int factor_num(int n) {
  int i, j, sum = 1;
  for (i = 2; i <= n; i++) {
    if (n % i == 0) {
      for (j = 0; n % i == 0; j++)
        n /= i;
      sum *= j + 1;
    }
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factor_num>:
  endbr64
  cmp    $0x1,%edi
  jle    L40
  mov    $0x1,%r9d
  mov    $0x2,%ecx
  jmp    L18
L4:
  add    $0x2,%r8d
  imul   %r8d,%r9d
L36:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jl     L23
L18:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  test   %edx,%edx
  jne    L36
L9:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  mov    %esi,%r8d
  add    $0x1,%esi
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L9
  jmp    L4
L40:
  mov    $0x1,%r9d
L23:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int factor_num(int n) {
  int i, j, sum = 1;
  for (i = 2; i <= n; i++) {
    if (n % i == 0) {
      for (j = 0; n % i == 0; j++)
        n /= i;
      sum *= j + 1;
    }
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<factor_num>:
  endbr64
  mov    $0x1,%r9d
  cmp    $0x1,%edi
  jle    L10
  mov    $0x2,%ecx
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jl     L10
L31:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  test   %edx,%edx
  jne    L19
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %edi,%eax
  mov    %esi,%r8d
  add    $0x1,%esi
  cltd
  idiv   %ecx
  cltd
  mov    %eax,%edi
  idiv   %ecx
  test   %edx,%edx
  je     L35
  add    $0x2,%r8d
  add    $0x1,%ecx
  imul   %r8d,%r9d
  cmp    %ecx,%edi
  jge    L31
L10:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int factor_num(int n) {
  int i, j, sum = 1;
  for (i = 2; i <= n; i++) {
    if (n % i == 0) {
      for (j = 0; n % i == 0; j++)
        n /= i;
      sum *= j + 1;
    }
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<factor_num>:
  endbr64
  mov    $0x1,%r9d
  cmp    $0x1,%edi
  jle    L43
  mov    $0x2,%ecx
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L59:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jl     L43
L22:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  test   %edx,%edx
  jne    L59
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %edi,%eax
  mov    %esi,%r8d
  add    $0x1,%esi
  cltd
  idiv   %ecx
  cltd
  mov    %eax,%edi
  idiv   %ecx
  test   %edx,%edx
  je     L52
  add    $0x2,%r8d
  add    $0x1,%ecx
  imul   %r8d,%r9d
  cmp    %ecx,%edi
  jge    L22
L43:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int factor_num(int n) {
  int i, j, sum = 1;
  for (i = 2; i <= n; i++) {
    if (n % i == 0) {
      for (j = 0; n % i == 0; j++)
        n /= i;
      sum *= j + 1;
    }
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_dft_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <log@plt>
  movq   %xmm0,%rbx
  mov    $0x2,%edi
  call   <log@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    -0x2c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,%edx
  movsd  -0x18(%rbp),%xmm1
  movsd  D13(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    -0x28(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <range_limit@plt>
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: f64
name: unpack_data
arguments: data_tag: D13
type_guessed: f64

tool: D3: 1.77

tool: D13: 2.77

assistant: ```c
int set_dft_length(int num_taps, int min, int large) {
  double d = log((double)num_taps) / log(2.);
  return 1 << range_limit((int)(d + 2.77), min, max((int)(d + 1.77), large));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_dft_length>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  call   <log@plt>
  movq   %xmm0,%rbx
  mov    $0x2,%edi
  call   <log@plt>
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rbx
  movapd %xmm1,%xmm0
  addsd  D4(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  mov    %r12d,%esi
  call   <max@plt>
  mov    %eax,%edx
  movq   %rbx,%xmm0
  addsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  mov    %ebp,%esi
  call   <range_limit@plt>
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type: f64
name: parse_data
arguments: label: D3
type: f64

tool: D4: 1.77

tool: D3: 2.77

assistant: ```c
int set_dft_length(int num_taps, int min, int large) {
  double d = log((double)num_taps) / log(2.);
  return 1 << range_limit((int)(d + 2.77), min, max((int)(d + 1.77), large));
}
```