ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<indexof_featuremap_coeff>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  not    %edi
  mov    %esi,%ebp
  push   %rbx
  shr    $0x1f,%edi
  mov    %edx,%ebx
  call   <assert@plt>
  mov    %ebx,%edi
  imul   %r12d,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int indexof_featuremap_coeff(int num_detector, int detector, int pos) {
  assert(detector >= 0);
  assert(pos >= 0);
  return detector + num_detector * pos;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7e8(%rbp)
  jmp    L27
L52:
  mov    -0x7e4(%rbp),%eax
  cmp    -0x7e8(%rbp),%eax
  jle    L33
  mov    -0x7e4(%rbp),%eax
  mov    %eax,-0x7e8(%rbp)
  lea    -0x7e0(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
L33:
  cmpl   $0x50,-0x7e4(%rbp)
  jle    L27
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7e4(%rbp),%eax
  mov    %rdx,%r8
  lea    D15(%rip),%rdx
  mov    %rdx,%rcx
  mov    %eax,%edx
  lea    D52(%rip),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  lea    -0x7e0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getaline@plt>
  mov    %eax,-0x7e4(%rbp)
  cmpl   $0x0,-0x7e4(%rbp)
  jg     L52
  cmpl   $0x0,-0x7e8(%rbp)
  jle    L29
  cmpl   $0x50,-0x7e8(%rbp)
  jle    L29
  lea    -0x3f0(%rbp),%rdx
  mov    -0x7e8(%rbp),%eax
  mov    %rdx,%r8
  lea    D37(%rip),%rdx
  mov    %rdx,%rcx
  mov    %eax,%edx
  lea    D52(%rip),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D15
datatype: string
name: unpack_data
arguments: label: D52
datatype: string
name: unpack_data
arguments: label: D39
datatype: string
name: unpack_data
arguments: label: D37
datatype: string

tool: D15: Line

tool: D52: Chars

tool: D39: %s: %3d  %s: %s

tool: D37: Long

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getaline(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
    if (len > 80) {
      printf("%s: %3d  %s: %s", "Chars", len, "Line", line);
    }
  }
  if (max > 0 && max > 80) {
    printf("%s: %3d  %s: %s", "Chars", max, "Long", longest);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  mov    %rsp,%rbp
  lea    D34(%rip),%r15
  lea    D27(%rip),%r14
  lea    D44(%rip),%r13
L76:
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <getaline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L17
  cmp    %ebx,%r12d
  jl     L19
L26:
  cmp    $0x50,%ebx
  jle    L76
  mov    %rbp,%r8
  mov    %r15,%rcx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L76
L19:
  lea    0x3f0(%rsp),%rdi
  mov    %rbp,%rsi
  call   <copy@plt>
  mov    %ebx,%r12d
  jmp    L26
L17:
  cmp    $0x50,%r12d
  jg     L51
L23:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    $0x0,%eax
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  lea    0x3f0(%rsp),%r8
  lea    D10(%rip),%rcx
  mov    %r12d,%edx
  lea    D27(%rip),%rsi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D34
type_infered: string
name: disassemble_data
arguments: tag: D27
type_infered: string
name: disassemble_data
arguments: tag: D44
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D34: Line

tool: D27: Chars

tool: D44: %s: %3d  %s: %s

tool: D10: Long

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getaline(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
    if (len > 80) {
      printf("%s: %3d  %s: %s", "Chars", len, "Line", line);
    }
  }
  if (max > 0 && max > 80) {
    printf("%s: %3d  %s: %s", "Chars", max, "Long", longest);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D51(%rip),%r14
  push   %r13
  lea    D58(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x400(%rsp),%r15
  nopl   (%rax)
L1:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getaline@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jle    L23
  cmp    %edx,%r12d
  jl     L63
L0:
  cmp    $0x50,%edx
  jle    L1
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L1
L63:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  mov    %edx,0xc(%rsp)
  call   <copy@plt>
  mov    0xc(%rsp),%edx
  mov    %edx,%r12d
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L23:
  cmp    $0x50,%r12d
  jg     L19
L13:
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  lea    0x400(%rsp),%r8
  lea    D17(%rip),%rcx
  mov    %r12d,%edx
  lea    D58(%rip),%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D51
data_type: string
name: unpack_data
arguments: data_label: D58
data_type: string
name: unpack_data
arguments: data_label: D25
data_type: string
name: unpack_data
arguments: data_label: D17
data_type: string

tool: D51: Line

tool: D58: Chars

tool: D25: %s: %3d  %s: %s

tool: D17: Long

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getaline(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
    if (len > 80) {
      printf("%s: %3d  %s: %s", "Chars", len, "Line", line);
    }
  }
  if (max > 0 && max > 80) {
    printf("%s: %3d  %s: %s", "Chars", max, "Long", longest);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D57(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D51(%rip),%rbp
  push   %rbx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x400(%rsp),%r15
  nopl   (%rax)
L60:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getaline@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jle    L46
  cmp    %edx,%r12d
  jl     L27
L12:
  cmp    $0x50,%edx
  jle    L60
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L60
L27:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  mov    %edx,0xc(%rsp)
  call   <copy@plt>
  mov    0xc(%rsp),%edx
  mov    %edx,%r12d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L46:
  cmp    $0x50,%r12d
  jg     L39
L33:
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  lea    0x400(%rsp),%r8
  lea    D27(%rip),%rcx
  mov    %r12d,%edx
  lea    D57(%rip),%rsi
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D57
data_type: string
name: extract_symbolic_data
arguments: data_tag: D51
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string

tool: D0: Line

tool: D57: Chars

tool: D51: %s: %3d  %s: %s

tool: D27: Long

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getaline(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
    if (len > 80) {
      printf("%s: %3d  %s: %s", "Chars", len, "Line", line);
    }
  }
  if (max > 0 && max > 80) {
    printf("%s: %3d  %s: %s", "Chars", max, "Long", longest);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<simplePow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L10
L17:
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L17
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double simplePow(double number, unsigned int exponent) {
  double result = number;
  for (unsigned int i = 1; i < exponent; i++)
    result *= number;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<simplePow>:
  endbr64
  movapd %xmm0,%xmm1
  cmp    $0x1,%edi
  jbe    L13
  mov    $0x1,%eax
L7:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L7
  ret
L13:
  ret
```

assistant: ```c
double simplePow(double number, unsigned int exponent) {
  double result = number;
  for (unsigned int i = 1; i < exponent; i++)
    result *= number;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simplePow>:
  endbr64
  movapd %xmm0,%xmm1
  cmp    $0x1,%edi
  jbe    L17
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L8
  ret
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
double simplePow(double number, unsigned int exponent) {
  double result = number;
  for (unsigned int i = 1; i < exponent; i++)
    result *= number;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simplePow>:
  endbr64
  movapd %xmm0,%xmm1
  cmp    $0x1,%edi
  jbe    L19
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L0
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
double simplePow(double number, unsigned int exponent) {
  double result = number;
  for (unsigned int i = 1; i < exponent; i++)
    result *= number;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clean_client_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <epoll_ctl@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void clean_client_fd(int cli_fd, int epoll_fd) {
  epoll_ctl(epoll_fd, EPOLL_CTL_DEL, cli_fd, 0);
  close(cli_fd);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clean_client_fd>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <epoll_ctl@plt>
  mov    %ebx,%edi
  call   <close@plt>
  pop    %rbx
  ret
```

assistant: ```c
void clean_client_fd(int cli_fd, int epoll_fd) {
  epoll_ctl(epoll_fd, EPOLL_CTL_DEL, cli_fd, 0);
  close(cli_fd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clean_client_fd>:
  endbr64
  mov    D8(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  mov    %ebp,%edx
  xor    %ecx,%ecx
  mov    (%rax),%esi
  call   <epoll_ctl@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <close@plt>
```

assistant: ```c
void clean_client_fd(int cli_fd, int epoll_fd) {
  epoll_ctl(epoll_fd, EPOLL_CTL_DEL, cli_fd, 0);
  close(cli_fd);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clean_client_fd>:
  endbr64
  mov    D2(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  mov    %ebp,%edx
  xor    %ecx,%ecx
  mov    (%rax),%esi
  call   <epoll_ctl@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <close@plt>
```

assistant: ```c
void clean_client_fd(int cli_fd, int epoll_fd) {
  epoll_ctl(epoll_fd, EPOLL_CTL_DEL, cli_fd, 0);
  close(cli_fd);
}
```
user: What is the c source code of the assembly code below:

```asm
<GET_PROMPT_CHR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <GET_CHR@plt>
  nop
  leave
  ret
```

assistant: ```c
void GET_PROMPT_CHR(c, s) int *c;
char *s;
{
  puts((char *)s);
  GET_CHR(c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GET_PROMPT_CHR>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <GET_CHR@plt>
  pop    %rbx
  ret
```

assistant: ```c
void GET_PROMPT_CHR(c, s) int *c;
char *s;
{
  puts((char *)s);
  GET_CHR(c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GET_PROMPT_CHR>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <GET_CHR@plt>
```

assistant: ```c
void GET_PROMPT_CHR(c, s) int *c;
char *s;
{
  puts((char *)s);
  GET_CHR(c);
}
```
user: What is the c source code of the assembly code below?

```asm
<GET_PROMPT_CHR>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <GET_CHR@plt>
```

assistant: ```c
void GET_PROMPT_CHR(c, s) int *c;
char *s;
{
  puts((char *)s);
  GET_CHR(c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7e8(%rbp)
  movl   $0x0,-0x7e4(%rbp)
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x7e8(%rbp)
  jmp    L51
L31:
  mov    -0x7e8(%rbp),%edx
  lea    -0x1(%rdx),%eax
  mov    %eax,-0x7e8(%rbp)
  mov    -0x7e4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x7e4(%rbp)
  movslq %edx,%rdx
  movzbl -0x7e0(%rbp,%rdx,1),%edx
  cltq
  mov    %dl,-0x3f0(%rbp,%rax,1)
L51:
  cmpl   $0x0,-0x7e8(%rbp)
  jns    L31
  mov    -0x7e4(%rbp),%eax
  cltq
  movb   $0x0,-0x3f0(%rbp,%rax,1)
  movl   $0x0,-0x7e8(%rbp)
  jmp    L42
L33:
  mov    -0x7e8(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%edx
  mov    -0x7e8(%rbp),%eax
  cltq
  movzbl -0x7e0(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L12
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  addl   $0x1,-0x7e8(%rbp)
L42:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x7e8(%rbp)
  jl     L33
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string

tool: D27: %s

tool: D9: 0

tool: D24: 1

assistant: ```c
int main() {
  char str[1000];
  char rev[1000];
  int i = 0, j = 0;
  scanf("%s", str);
  i = strlen(str) - 1;
  while (i >= 0) {
    rev[j++] = str[i--];
  }
  rev[j] = '\0';
  for (i = 0; i < strlen(rev); i++) {
    if (rev[i] != str[i]) {
      printf("0");
    }
  }
  printf("1");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L1
  movslq %eax,%rdx
  lea    (%rsp,%rdx,1),%rcx
  lea    0x3f0(%rsp),%rdx
  lea    -0x1(%rax),%esi
  lea    0x3f1(%rsp,%rsi,1),%rdi
L27:
  movzbl -0x1(%rcx),%esi
  mov    %sil,(%rdx)
  sub    $0x1,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L27
L52:
  cltq
  movb   $0x0,0x3f0(%rsp,%rax,1)
  mov    $0x0,%ebx
  lea    D14(%rip),%rbp
  jmp    L34
L1:
  mov    $0x0,%eax
  jmp    L52
L76:
  add    $0x1,%rbx
L34:
  lea    0x3f0(%rsp),%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L61
  movzbl (%rsp,%rbx,1),%eax
  cmp    %al,0x3f0(%rsp,%rbx,1)
  je     L76
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L76
L61:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  mov    $0x0,%eax
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string
name: read_data
arguments: data_tag: D14
type: string
name: read_data
arguments: data_tag: D20
type: string

tool: D4: %s

tool: D14: 0

tool: D20: 1

assistant: ```c
int main() {
  char str[1000];
  char rev[1000];
  int i = 0, j = 0;
  scanf("%s", str);
  i = strlen(str) - 1;
  while (i >= 0) {
    rev[j++] = str[i--];
  }
  rev[j] = '\0';
  for (i = 0; i < strlen(rev); i++) {
    if (rev[i] != str[i]) {
      printf("0");
    }
  }
  printf("1");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L17
  movslq %eax,%rdi
  lea    0x3f0(%rsp),%rbp
  sub    $0x1,%eax
  lea    (%r12,%rdi,1),%rcx
  mov    %rbp,%rdx
  lea    0x3f1(%rsp,%rax,1),%rsi
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl -0x1(%rcx),%eax
  add    $0x1,%rdx
  sub    $0x1,%rcx
  mov    %al,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L21
L55:
  movb   $0x0,0x3f0(%rsp,%rdi,1)
  xor    %ebx,%ebx
  lea    D15(%rip),%r13
  jmp    L42
  nop
L47:
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  je     L61
  mov    %r13,%rdi
  call   <printf@plt>
L61:
  add    $0x1,%rbx
L42:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L47
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  xor    %edi,%edi
  lea    0x3f0(%rsp),%rbp
  jmp    L55
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
datatype: string
name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D26
datatype: string

tool: D14: %s

tool: D15: 0

tool: D26: 1

assistant: ```c
int main() {
  char str[1000];
  char rev[1000];
  int i = 0, j = 0;
  scanf("%s", str);
  i = strlen(str) - 1;
  while (i >= 0) {
    rev[j++] = str[i--];
  }
  rev[j] = '\0';
  for (i = 0; i < strlen(rev); i++) {
    if (rev[i] != str[i]) {
      printf("0");
    }
  }
  printf("1");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  lea    D23(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L51
  movslq %eax,%rdi
  lea    0x3f0(%rsp),%rbp
  sub    $0x1,%eax
  lea    (%r12,%rdi,1),%rcx
  mov    %rbp,%rdx
  lea    0x3f1(%rsp,%rax,1),%rsi
  nopl   0x0(%rax,%rax,1)
L22:
  movzbl -0x1(%rcx),%eax
  add    $0x1,%rdx
  sub    $0x1,%rcx
  mov    %al,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L22
L49:
  movb   $0x0,0x3f0(%rsp,%rdi,1)
  xor    %ebx,%ebx
  lea    D6(%rip),%r13
  jmp    L26
  nop
L41:
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  je     L5
  mov    %r13,%rdi
  call   <printf@plt>
L5:
  add    $0x1,%rbx
L26:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L41
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  xor    %edi,%edi
  lea    0x3f0(%rsp),%rbp
  jmp    L49
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
type_guessed: string
name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D23: %s

tool: D6: 0

tool: D7: 1

assistant: ```c
int main() {
  char str[1000];
  char rev[1000];
  int i = 0, j = 0;
  scanf("%s", str);
  i = strlen(str) - 1;
  while (i >= 0) {
    rev[j++] = str[i--];
  }
  rev[j] = '\0';
  for (i = 0; i < strlen(rev); i++) {
    if (rev[i] != str[i]) {
      printf("0");
    }
  }
  printf("1");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L23:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  add    %eax,-0x8(%rbp)
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L25
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L23
L25:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ungetc@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int value = 0;
  int ch;
  while ((ch = getchar()) != EOF && isdigit(ch)) {
    value *= 10;
    value += ch - '0';
  }
  ungetc(ch, stdin);
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  jmp    L25
L4:
  lea    0x0(%rbp,%rbp,4),%eax
  lea    -0x30(%rbx,%rax,2),%ebp
L25:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D9(%rip),%rax
  cmp    %ebx,(%rax)
  je     L3
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L4
L3:
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <ungetc@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int value = 0;
  int ch;
  while ((ch = getchar()) != EOF && isdigit(ch)) {
    value *= 10;
    value += ch - '0';
  }
  ungetc(ch, stdin);
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    D19(%rip),%rbx
  jmp    L20
  nopl   0x0(%rax)
L18:
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L22
  lea    (%r12,%r12,4),%eax
  lea    -0x30(%rbp,%rax,2),%r12d
L20:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%rbx)
  jne    L18
L22:
  mov    D8(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ungetc@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(void) {
  int value = 0;
  int ch;
  while ((ch = getchar()) != EOF && isdigit(ch)) {
    value *= 10;
    value += ch - '0';
  }
  ungetc(ch, stdin);
  return value;
}
```