ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<s_get_nrc_block_index>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x1d1c1514130c0b0a,%rax
  mov    %rax,(%rsp)
  movb   $0x1e,0x8(%rsp)
  movabs $0x2120191817100f0e,%rax
  mov    %rax,0x9(%rsp)
  movb   $0x22,0x11(%rsp)
  movabs $0x4140393837302f2e,%rax
  mov    %rax,0x12(%rsp)
  movb   $0x42,0x1a(%rsp)
  movabs $0x45443d3c3b343332,%rax
  mov    %rax,0x1b(%rsp)
  movb   $0x46,0x23(%rsp)
  lea    0x9(%rsp),%rdx
  mov    $0x0,%ecx
L22:
  lea    -0x9(%rdx),%rax
L11:
  cmp    %dil,(%rax)
  je     L13
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L11
  add    $0x1,%ecx
  add    $0x9,%rdx
  cmp    $0x4,%cl
  jne    L22
  mov    $0xffffffff,%ecx
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    %ecx,%eax
  add    $0x38,%rsp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char s_get_nrc_block_index(char i) {
  char blocks[4][9] = {{10, 11, 12, 19, 20, 21, 28, 29, 30}, {14, 15, 16, 23, 24, 25, 32, 33, 34}, {46, 47, 48, 55, 56, 57, 64, 65, 66}, {50, 51, 52, 59, 60, 61, 68, 69, 70}};
  for (char j = 0; j < 4; j++) {
    for (char k = 0; k < 9; k++) {
      if (i == blocks[j][k]) {
        return j;
      }
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<s_get_nrc_block_index>:
  endbr64
  sub    $0x38,%rsp
  movdqa D1(%rip),%xmm0
  mov    $0xa,%edx
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x4645443d,0x20(%rsp)
  lea    0x9(%rsp),%rcx
  movaps %xmm0,(%rsp)
  movdqa D10(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
L16:
  lea    -0x8(%rcx),%rax
  jmp    L24
  nopl   0x0(%rax)
L17:
  movzbl (%rax),%edx
  add    $0x1,%rax
L24:
  cmp    %dl,%dil
  je     L13
  cmp    %rcx,%rax
  jne    L17
  add    $0x1,%r8d
  cmp    $0x4,%r8b
  je     L39
  movzbl (%rcx),%edx
  add    $0x9,%rcx
  jmp    L16
  nopl   0x0(%rax)
L39:
  mov    $0xffffffff,%r8d
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    %r8d,%eax
  add    $0x38,%rsp
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: byte[16]
name: unpack_data
arguments: data_label: D10
type: byte[16]

tool: {"D1": [0x0a,0x0b,0x0c,0x13,0x14,0x15,0x1c,0x1d,0x1e,0x0e,0x0f,0x10,0x17,0x18,0x19,0x20]}

tool: {"D10": [0x21,0x22,0x2e,0x2f,0x30,0x37,0x38,0x39,0x40,0x41,0x42,0x32,0x33,0x34,0x3b,0x3c]}

assistant: ```c
char s_get_nrc_block_index(char i) {
  char blocks[4][9] = {{10, 11, 12, 19, 20, 21, 28, 29, 30}, {14, 15, 16, 23, 24, 25, 32, 33, 34}, {46, 47, 48, 55, 56, 57, 64, 65, 66}, {50, 51, 52, 59, 60, 61, 68, 69, 70}};
  for (char j = 0; j < 4; j++) {
    for (char k = 0; k < 9; k++) {
      if (i == blocks[j][k]) {
        return j;
      }
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s_get_nrc_block_index>:
  endbr64
  cmp    $0xa,%dil
  je     L249
  cmp    $0xb,%dil
  je     L249
  cmp    $0xc,%dil
  je     L249
  cmp    $0x13,%dil
  je     L249
  cmp    $0x14,%dil
  je     L249
  cmp    $0x15,%dil
  je     L249
  cmp    $0x1c,%dil
  je     L249
  cmp    $0x1d,%dil
  je     L249
  cmp    $0x1e,%dil
  je     L249
  cmp    $0xe,%dil
  je     L112
  cmp    $0xf,%dil
  je     L112
  cmp    $0x10,%dil
  je     L112
  cmp    $0x17,%dil
  je     L112
  cmp    $0x18,%dil
  je     L112
  cmp    $0x19,%dil
  je     L112
  cmp    $0x20,%dil
  je     L112
  cmp    $0x21,%dil
  je     L112
  cmp    $0x22,%dil
  je     L112
  cmp    $0x2e,%dil
  je     L7
  cmp    $0x2f,%dil
  je     L7
  cmp    $0x30,%dil
  je     L7
  cmp    $0x37,%dil
  je     L7
  cmp    $0x38,%dil
  je     L7
  cmp    $0x39,%dil
  je     L7
  cmp    $0x40,%dil
  je     L7
  cmp    $0x41,%dil
  je     L7
  cmp    $0x42,%dil
  je     L7
  cmp    $0x32,%dil
  je     L204
  cmp    $0x33,%dil
  je     L204
  cmp    $0x34,%dil
  je     L204
  cmp    $0x3b,%dil
  je     L204
  cmp    $0x3c,%dil
  je     L204
  cmp    $0x3d,%dil
  je     L204
  cmp    $0x44,%dil
  je     L204
  cmp    $0x45,%dil
  je     L204
  cmp    $0x46,%dil
  sete   %al
  lea    -0x1(,%rax,4),%eax
  ret
  nopl   (%rax)
L112:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L249:
  xor    %eax,%eax
  ret
L204:
  mov    $0x3,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x2,%eax
  ret
```

assistant: ```c
char s_get_nrc_block_index(char i) {
  char blocks[4][9] = {{10, 11, 12, 19, 20, 21, 28, 29, 30}, {14, 15, 16, 23, 24, 25, 32, 33, 34}, {46, 47, 48, 55, 56, 57, 64, 65, 66}, {50, 51, 52, 59, 60, 61, 68, 69, 70}};
  for (char j = 0; j < 4; j++) {
    for (char k = 0; k < 9; k++) {
      if (i == blocks[j][k]) {
        return j;
      }
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_omp_nested>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_omp_nested() {
  int counter = 0;
#pragma omp parallel shared(counter)
  {
#pragma omp critical
    counter++;
#pragma omp parallel
    {
#pragma omp critical
      counter--;
    }
  }
  return (counter != 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_omp_nested>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int test_omp_nested() {
  int counter = 0;
#pragma omp parallel shared(counter)
  {
#pragma omp critical
    counter++;
#pragma omp parallel
    {
#pragma omp critical
      counter--;
    }
  }
  return (counter != 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_omp_nested>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test_omp_nested() {
  int counter = 0;
#pragma omp parallel shared(counter)
  {
#pragma omp critical
    counter++;
#pragma omp parallel
    {
#pragma omp critical
      counter--;
    }
  }
  return (counter != 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MatchFinder_CheckAndMoveAndRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <MatchFinder_NeedMove@plt>
  test   %rax,%rax
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <MatchFinder_MoveBlock@plt>
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <MatchFinder_ReadBlock@plt>
  nop
  leave
  ret
```

assistant: ```c
void MatchFinder_CheckAndMoveAndRead(struct CMatchFinder *p) {
  if (MatchFinder_NeedMove(p))
    MatchFinder_MoveBlock(p);
  MatchFinder_ReadBlock(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MatchFinder_CheckAndMoveAndRead>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <MatchFinder_NeedMove@plt>
  test   %rax,%rax
  jne    L18
L1:
  mov    %rbx,%rdi
  call   <MatchFinder_ReadBlock@plt>
  pop    %rbx
  ret
L18:
  mov    %rbx,%rdi
  call   <MatchFinder_MoveBlock@plt>
  jmp    L1
```

assistant: ```c
void MatchFinder_CheckAndMoveAndRead(struct CMatchFinder *p) {
  if (MatchFinder_NeedMove(p))
    MatchFinder_MoveBlock(p);
  MatchFinder_ReadBlock(p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MatchFinder_CheckAndMoveAndRead>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <MatchFinder_NeedMove@plt>
  test   %rax,%rax
  jne    L6
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <MatchFinder_ReadBlock@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  call   <MatchFinder_MoveBlock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <MatchFinder_ReadBlock@plt>
```

assistant: ```c
void MatchFinder_CheckAndMoveAndRead(struct CMatchFinder *p) {
  if (MatchFinder_NeedMove(p))
    MatchFinder_MoveBlock(p);
  MatchFinder_ReadBlock(p);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MatchFinder_CheckAndMoveAndRead>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <MatchFinder_NeedMove@plt>
  test   %rax,%rax
  jne    L1
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <MatchFinder_ReadBlock@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  call   <MatchFinder_MoveBlock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <MatchFinder_ReadBlock@plt>
```

assistant: ```c
void MatchFinder_CheckAndMoveAndRead(struct CMatchFinder *p) {
  if (MatchFinder_NeedMove(p))
    MatchFinder_MoveBlock(p);
  MatchFinder_ReadBlock(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0xa,-0x5(%rbp)
  je     L20
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  jmp    L20
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L20:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0xa,-0x5(%rbp)
  je     L30
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_string(char *string, int read_length) {
  char read_char;
  int i = 0;
  if ((read_char = getchar()) != '\n') {
    string[i] = read_char;
    i++;
  }
  while ((read_char = getchar()) != '\n' && i < read_length) {
    string[i] = read_char;
    i++;
  }
  string[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%ebx
  cmp    $0xa,%al
  je     L24
  mov    %al,0x0(%rbp)
  mov    $0x1,%ebx
L24:
  movslq %ebx,%rbx
L15:
  mov    %ebx,%r13d
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    %ebx,%r12d
  jle    L29
  cmp    $0xa,%al
  je     L29
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L15
L29:
  movslq %r13d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int read_string(char *string, int read_length) {
  char read_char;
  int i = 0;
  if ((read_char = getchar()) != '\n') {
    string[i] = read_char;
    i++;
  }
  while ((read_char = getchar()) != '\n' && i < read_length) {
    string[i] = read_char;
    i++;
  }
  string[i] = '\0';
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_string>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L4
  mov    %al,(%rbx)
  mov    $0x1,%r12d
L4:
  movslq %r12d,%rax
  add    %rax,%rbx
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L35:
  cmp    $0xa,%al
  je     L11
  mov    %al,(%rbx)
  add    $0x1,%r12d
  add    $0x1,%rbx
L39:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %ebp,%r12d
  jl     L35
L11:
  movb   $0x0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int read_string(char *string, int read_length) {
  char read_char;
  int i = 0;
  if ((read_char = getchar()) != '\n') {
    string[i] = read_char;
    i++;
  }
  while ((read_char = getchar()) != '\n' && i < read_length) {
    string[i] = read_char;
    i++;
  }
  string[i] = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_string>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L6
  mov    %al,(%rbx)
  mov    $0x1,%r12d
L6:
  movslq %r12d,%rax
  add    %rax,%rbx
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L19:
  cmp    $0xa,%al
  je     L28
  mov    %al,(%rbx)
  add    $0x1,%r12d
  add    $0x1,%rbx
L4:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %ebp,%r12d
  jl     L19
L28:
  movb   $0x0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int read_string(char *string, int read_length) {
  char read_char;
  int i = 0;
  if ((read_char = getchar()) != '\n') {
    string[i] = read_char;
    i++;
  }
  while ((read_char = getchar()) != '\n' && i < read_length) {
    string[i] = read_char;
    i++;
  }
  string[i] = '\0';
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  jmp    L2
L23:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x24(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x24(%rbp)
L2:
  cmpl   $0x4,-0x24(%rbp)
  jle    L23
  movl   $0x0,-0x24(%rbp)
  jmp    L31
L8:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L31:
  cmpl   $0x4,-0x24(%rbp)
  jle    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main(void) {
  int a[5];
  int i;
  for (i = 0; i < 5; i++) {
    i[a] = i;
  }
  for (i = 0; i < 5; i++) {
    printf("%d\n", a[i]);
  };
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  lea    D6(%rip),%rbp
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main(void) {
  int a[5];
  int i;
  for (i = 0; i < 5; i++) {
    i[a] = i;
  }
  for (i = 0; i < 5; i++) {
    printf("%d\n", a[i]);
  };
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  mov    %rax,0x4(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0xc(%rsp)
L17:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  je     L7
  mov    (%rbx),%esi
  jmp    L17
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main(void) {
  int a[5];
  int i;
  for (i = 0; i < 5; i++) {
    i[a] = i;
  }
  for (i = 0; i < 5; i++) {
    printf("%d\n", a[i]);
  };
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  movaps %xmm0,(%rsp)
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L3
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D10
datatype: byte[16]

tool: D16: %d


tool: {"D10": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int a[5];
  int i;
  for (i = 0; i < 5; i++) {
    i[a] = i;
  }
  for (i = 0; i < 5; i++) {
    printf("%d\n", a[i]);
  };
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <func>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string

tool: D5: %d


assistant: ```c
void func(int *index) {
  printf("%d\n", *index);
  *index++;
  func(index);
}
```
user: What is the c source code of the assembly code below?

```asm
<func>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rbx),%rdi
  call   <func>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: %d


assistant: ```c
void func(int *index) {
  printf("%d\n", *index);
  *index++;
  func(index);
}
```
user: Translate the below assembly code into C programming language:

```asm
<func>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d


assistant: ```c
void func(int *index) {
  printf("%d\n", *index);
  *index++;
  func(index);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: %d


assistant: ```c
void func(int *index) {
  printf("%d\n", *index);
  *index++;
  func(index);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_formalparmtype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L14
L9:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  je     L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
L21:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_formalparmtype(const char *arg, char *formal) {
  while (*arg != '|' && *arg != '\0')
    *formal++ = *arg++;
  *formal = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_formalparmtype>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x7c,%al
  je     L16
  test   %al,%al
  je     L16
L4:
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %al,-0x1(%rsi)
  movzbl (%rdi),%eax
  cmp    $0x7c,%al
  je     L16
  test   %al,%al
  jne    L4
L16:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void get_formalparmtype(const char *arg, char *formal) {
  while (*arg != '|' && *arg != '\0')
    *formal++ = *arg++;
  *formal = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_formalparmtype>:
  endbr64
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %al,(%rsi)
  add    $0x1,%rsi
  add    $0x1,%rdi
L16:
  movzbl (%rdi),%eax
  cmp    $0x7c,%al
  je     L11
  test   %al,%al
  jne    L1
L11:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void get_formalparmtype(const char *arg, char *formal) {
  while (*arg != '|' && *arg != '\0')
    *formal++ = *arg++;
  *formal = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_formalparmtype>:
  endbr64
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %al,(%rsi)
  add    $0x1,%rsi
  add    $0x1,%rdi
L9:
  movzbl (%rdi),%eax
  cmp    $0x7c,%al
  je     L16
  test   %al,%al
  jne    L13
L16:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void get_formalparmtype(const char *arg, char *formal) {
  while (*arg != '|' && *arg != '\0')
    *formal++ = *arg++;
  *formal = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CE_pHP_CO2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  D13(%rip),%xmm0
  subsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    D5(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x4,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   D39(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x38(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  movq   D39(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x30(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_infered: byte[8]
name: unpack_data
arguments: data_label: D5
type_infered: byte[8]
name: unpack_data
arguments: data_label: D39
type_infered: byte[8]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double CE_pHP_CO2(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -H3O * (P * H3O - Kw + H3O * H3O) / (-K1 * K2 + H3O * H3O);
  return t0;
}
```