ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  lea    D24(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L5:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %ebx,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D21
type: string
name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D3
type: string

tool: D21: No	 Square

tool: D24: %d	%d


tool: D3: -----------------

assistant: ```c
int main() {
  int n;
  printf("No\t Square\n");
  printf("-----------------\n");
  for (n = 1; n <= 10; n++) {
    printf("%d\t%d\n", n, n * n);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D61(%rip),%r13
  lea    D55(%rip),%r12
  lea    D27(%rip),%rbp
  lea    D11(%rip),%rbx
L18:
  mov    %r13,%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <fnRightRot@plt>
  mov    %eax,%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D82(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  je     L18
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D18
type: string
name: parse_data
arguments: data_label: D63
type: string
name: parse_data
arguments: data_label: D47
type: string
name: parse_data
arguments: data_label: D61
type: string
name: parse_data
arguments: data_label: D55
type: string
name: parse_data
arguments: data_label: D27
type: string
name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D82
type: string
name: parse_data
arguments: data_label: D7
type: string

tool: D18: 
*********************************************************

tool: D63: 
*	PROGRAM TO IMPLEMENT CIRCULAR RIGHT SHIFT	*

tool: D47: *********************************************************

tool: D61: 
Enter the value to be rotated

tool: D55: %u

tool: D27: 
Enter the number of positions by which the value has to be rotated

tool: D11: %d

tool: D82: 
The value %u after right rotation by %d bits = %u


tool: D7: 
Press 1 to continue or any other key to exit....

assistant: ```c
int main(void) {
  unsigned int iVal, iNewVal;
  int iNum, iChoice;
  printf("\n*********************************************************");
  printf("\n*\tPROGRAM TO IMPLEMENT CIRCULAR RIGHT SHIFT\t*\n");
  printf("*********************************************************");
  do {
    printf("\nEnter the value to be rotated\n");
    scanf("%u", &iVal);
    printf("\nEnter the number of positions by which the value has to be rotated\n");
    scanf("%d", &iNum);
    iNewVal = fnRightRot(iVal, iNum);
    printf("\nThe value %u after right rotation by %d bits = %u\n", iVal, iNum, iNewVal);
    printf("\nPress 1 to continue or any other key to exit....\n");
    scanf("%d", &iChoice);
  } while (1 == iChoice);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L9
  mov    $0x0,%eax
  call   <link_error@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void test1(void) {
  unsigned int l = 3 * 4 - 5 / 2;
  if (l != 10)
    link_error();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test1>:
  endbr64
  ret
```

assistant: ```c
void test1(void) {
  unsigned int l = 3 * 4 - 5 / 2;
  if (l != 10)
    link_error();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test1>:
  endbr64
  ret
```

assistant: ```c
void test1(void) {
  unsigned int l = 3 * 4 - 5 / 2;
  if (l != 10)
    link_error();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test1>:
  endbr64
  ret
```

assistant: ```c
void test1(void) {
  unsigned int l = 3 * 4 - 5 / 2;
  if (l != 10)
    link_error();
}
```
user: What is the c source code of the assembly code below:

```asm
<trim_newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L4:
  nop
  leave
  ret
```

assistant: ```c
void trim_newline(char *str) {
  char *pos = strrchr(str, '\n');
  if (pos)
    *pos = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim_newline>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax)
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void trim_newline(char *str) {
  char *pos = strrchr(str, '\n');
  if (pos)
    *pos = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trim_newline>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L3
  movb   $0x0,(%rax)
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void trim_newline(char *str) {
  char *pos = strrchr(str, '\n');
  if (pos)
    *pos = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trim_newline>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax)
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void trim_newline(char *str) {
  char *pos = strrchr(str, '\n');
  if (pos)
    *pos = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_print_modified_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D11
type_guessed: string

tool: D1: 


tool: D11: %s

assistant: ```c
int _print_modified_time(struct stat file_stat) {
  char *m_time = ctime(&(file_stat.st_mtime));
  m_time[strcspn(m_time, "\n")] = 0;
  printf("%s", m_time);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_print_modified_time>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <ctime@plt>
  mov    %rax,%rbx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string
name: read_data
arguments: tag: D12
datatype: string

tool: D7: 


tool: D12: %s

assistant: ```c
int _print_modified_time(struct stat file_stat) {
  char *m_time = ctime(&(file_stat.st_mtime));
  m_time[strcspn(m_time, "\n")] = 0;
  printf("%s", m_time);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_print_modified_time>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <ctime@plt>
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcspn@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  movb   $0x0,0x0(%rbp,%rax,1)
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D10
type_infered: string
name: read_data
arguments: label: D6
type_infered: string

tool: D10: 


tool: D6: %s

assistant: ```c
int _print_modified_time(struct stat file_stat) {
  char *m_time = ctime(&(file_stat.st_mtime));
  m_time[strcspn(m_time, "\n")] = 0;
  printf("%s", m_time);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_print_modified_time>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <ctime@plt>
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcspn@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  movb   $0x0,0x0(%rbp,%rax,1)
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D6
type: string

tool: D11: 


tool: D6: %s

assistant: ```c
int _print_modified_time(struct stat file_stat) {
  char *m_time = ctime(&(file_stat.st_mtime));
  m_time[strcspn(m_time, "\n")] = 0;
  printf("%s", m_time);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<populateValTbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0xfffffc19,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void populateValTbl(int *valTbl, int size) {
  int i = 0;
  for (i = 0; i < size; i++)
    valTbl[i] = -999;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<populateValTbl>:
  endbr64
  test   %esi,%esi
  jle    L14
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L16:
  movl   $0xfffffc19,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L16
L14:
  ret
```

assistant: ```c
void populateValTbl(int *valTbl, int size) {
  int i = 0;
  for (i = 0; i < size; i++)
    valTbl[i] = -999;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<populateValTbl>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
L14:
  movl   $0xfffffc19,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L14
L8:
  ret
```

assistant: ```c
void populateValTbl(int *valTbl, int size) {
  int i = 0;
  for (i = 0; i < size; i++)
    valTbl[i] = -999;
}
```
user: What is the c source code of the assembly code below:

```asm
<populateValTbl>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L21
  mov    %esi,%edx
  movdqa D1(%rip),%xmm0
  mov    %rdi,%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L30:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L30
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L49
L69:
  movslq %eax,%rdx
  movl   $0xfffffc19,(%rdi,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%esi
  jle    L13
  add    $0x2,%eax
  movl   $0xfffffc19,0x4(%rdi,%rcx,1)
  cmp    %eax,%esi
  jle    L13
  movl   $0xfffffc19,0x8(%rdi,%rcx,1)
L13:
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  ret
L21:
  xor    %eax,%eax
  jmp    L69
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: byte[16]

tool: {"D1": [0x19,0xfc,0xff,0xff,0x19,0xfc,0xff,0xff,0x19,0xfc,0xff,0xff,0x19,0xfc,0xff,0xff]}

assistant: ```c
void populateValTbl(int *valTbl, int size) {
  int i = 0;
  for (i = 0; i < size; i++)
    valTbl[i] = -999;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matrix_pprint_int_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L5:
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L24:
  mov    -0xc(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L24
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string

tool: D26: %s=[


tool: D21: %d 

tool: D19: ]

assistant: ```c
void matrix_pprint_int_2(const char *name, const int *a, const int rows, const int cols) {
  printf("%s=[\n", name);
  for (int r = 0; r < rows; r++) {
    for (int c = 0; c < cols; c++) {
      const int pos = (r * cols) + c;
      printf("%d ", a[pos]);
    }
    printf("\n");
  }
  printf("]\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix_pprint_int_2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,%ebx
  mov    %edx,0x4(%rsp)
  mov    %ecx,%r13d
  mov    %rdi,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L51
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  lea    D3(%rip),%r12
  jmp    L37
L27:
  movslq %r15d,%rdx
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rdx,4),%rbx
  lea    -0x1(%r13),%eax
  add    %rdx,%rax
  lea    0x4(%rcx,%rax,4),%rbp
L14:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L14
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r14d
  add    %r13d,%r15d
  cmp    %r14d,0x4(%rsp)
  je     L51
L37:
  test   %r13d,%r13d
  jg     L27
  jmp    L4
L51:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D29
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D29: %s=[


tool: D3: %d 

tool: D8: ]

assistant: ```c
void matrix_pprint_int_2(const char *name, const int *a, const int rows, const int cols) {
  printf("%s=[\n", name);
  for (int r = 0; r < rows; r++) {
    for (int c = 0; c < cols; c++) {
      const int pos = (r * cols) + c;
      printf("%d ", a[pos]);
    }
    printf("\n");
  }
  printf("]\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matrix_pprint_int_2>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  mov    %edx,0x4(%rsp)
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L12
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    D9(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L30:
  test   %r12d,%r12d
  jle    L7
  mov    0x8(%rsp),%rdx
  movslq %r14d,%rcx
  lea    -0x1(%r12),%eax
  add    %rcx,%rax
  lea    (%rdx,%rcx,4),%r15
  lea    0x4(%rdx,%rax,4),%rbx
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    (%r15),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L22
L7:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    %r12d,%r14d
  call   <putchar@plt>
  cmp    %r13d,0x4(%rsp)
  jne    L30
L12:
  add    $0x18,%rsp
  lea    D29(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D9
datatype: string
name: parse_data
arguments: label: D29
datatype: string

tool: D6: %s=[


tool: D9: %d 

tool: D29: ]

assistant: ```c
void matrix_pprint_int_2(const char *name, const int *a, const int rows, const int cols) {
  printf("%s=[\n", name);
  for (int r = 0; r < rows; r++) {
    for (int c = 0; c < cols; c++) {
      const int pos = (r * cols) + c;
      printf("%d ", a[pos]);
    }
    printf("\n");
  }
  printf("]\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrix_pprint_int_2>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  mov    %edx,0x4(%rsp)
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L4
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    D25(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L29:
  test   %r12d,%r12d
  jle    L32
  mov    0x8(%rsp),%rdx
  movslq %r14d,%rcx
  lea    -0x1(%r12),%eax
  add    %rcx,%rax
  lea    (%rdx,%rcx,4),%r15
  lea    0x4(%rdx,%rax,4),%rbx
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    (%r15),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L26
L32:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    %r12d,%r14d
  call   <putchar@plt>
  cmp    %r13d,0x4(%rsp)
  jne    L29
L4:
  add    $0x18,%rsp
  lea    D27(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D25
type: string
name: retrieve_data
arguments: data_label: D27
type: string

tool: D6: %s=[


tool: D25: %d 

tool: D27: ]

assistant: ```c
void matrix_pprint_int_2(const char *name, const int *a, const int rows, const int cols) {
  printf("%s=[\n", name);
  for (int r = 0; r < rows; r++) {
    for (int c = 0; c < cols; c++) {
      const int pos = (r * cols) + c;
      printf("%d ", a[pos]);
    }
    printf("\n");
  }
  printf("]\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ignoreErrno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x1,%eax
  ja     L3
  mov    $0x1,%eax
  jmp    L16
L3:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int ignoreErrno(int ierrno) {
  switch (ierrno) {
  case EAGAIN:
  case EINTR:
    return 1;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ignoreErrno>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x1,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ignoreErrno(int ierrno) {
  switch (ierrno) {
  case EAGAIN:
  case EINTR:
    return 1;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ignoreErrno>:
  endbr64
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x1,%edi
  setbe  %al
  ret
```

assistant: ```c
int ignoreErrno(int ierrno) {
  switch (ierrno) {
  case EAGAIN:
  case EINTR:
    return 1;
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ignoreErrno>:
  endbr64
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x1,%edi
  setbe  %al
  ret
```

assistant: ```c
int ignoreErrno(int ierrno) {
  switch (ierrno) {
  case EAGAIN:
  case EINTR:
    return 1;
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crStrncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <crStrlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jbe    L8
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crMemcpy@plt>
  jmp    L9
L8:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crMemcpy@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void crStrncpy(char *dest, const char *src, unsigned int len) {
  const unsigned int str_len = crStrlen(src);
  if (str_len > len - 1) {
    crMemcpy(dest, src, len);
  } else {
    crMemcpy(dest, src, str_len + 1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crStrncpy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %rsi,%rdi
  call   <crStrlen@plt>
  lea    -0x1(%rbp),%edx
  cmp    %eax,%edx
  jae    L8
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <crMemcpy@plt>
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  lea    0x1(%rax),%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <crMemcpy@plt>
  jmp    L18
```

assistant: ```c
void crStrncpy(char *dest, const char *src, unsigned int len) {
  const unsigned int str_len = crStrlen(src);
  if (str_len > len - 1) {
    crMemcpy(dest, src, len);
  } else {
    crMemcpy(dest, src, str_len + 1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crStrncpy>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  call   <crStrlen@plt>
  lea    -0x1(%r12),%edx
  cmp    %eax,%edx
  jae    L3
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <crMemcpy@plt>
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  lea    0x1(%rax),%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <crMemcpy@plt>
```

assistant: ```c
void crStrncpy(char *dest, const char *src, unsigned int len) {
  const unsigned int str_len = crStrlen(src);
  if (str_len > len - 1) {
    crMemcpy(dest, src, len);
  } else {
    crMemcpy(dest, src, str_len + 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<crStrncpy>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  call   <crStrlen@plt>
  lea    -0x1(%r12),%edx
  cmp    %eax,%edx
  jae    L0
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <crMemcpy@plt>
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  lea    0x1(%rax),%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <crMemcpy@plt>
```

assistant: ```c
void crStrncpy(char *dest, const char *src, unsigned int len) {
  const unsigned int str_len = crStrlen(src);
  if (str_len > len - 1) {
    crMemcpy(dest, src, len);
  } else {
    crMemcpy(dest, src, str_len + 1);
  }
}
```