ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<multiply282>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L94
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L0:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L23
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L23
  nopl   0x0(%rax)
L50:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L50
  cmp    -0x24(%rsp),%r11d
  je     L46
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L46
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L46
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L46:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L0
L94:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L43:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L43
  mov    -0x18(%rsp),%r8
  jmp    L46
```

assistant: ```c
void multiply282(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_asc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  subl   $0x1,-0x1c(%rbp)
L35:
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L3
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L15
L3:
  mov    $0x2e,%eax
L15:
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string

tool: D6: %c

assistant: ```c
void print_asc(const char *buf, int len) {
  int i;
  if (buf[len - 1] == 0)
    len--;
  for (i = 0; i < len; i++)
    printf("%c", isprint(buf[i]) ? buf[i] : '.');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_asc>:
  endbr64
  movslq %esi,%rax
  cmpb   $0x1,-0x1(%rax,%rdi,1)
  sbb    $0x0,%esi
  test   %esi,%esi
  jle    L3
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D7(%rip),%rbp
  jmp    L5
L43:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L2
L5:
  movsbl (%rbx),%edi
  call   <isprint@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  je     L43
  movsbl (%rbx),%esi
  jmp    L43
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string

tool: D7: %c

assistant: ```c
void print_asc(const char *buf, int len) {
  int i;
  if (buf[len - 1] == 0)
    len--;
  for (i = 0; i < len; i++)
    printf("%c", isprint(buf[i]) ? buf[i] : '.');
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_asc>:
  endbr64
  movslq %esi,%rax
  cmpb   $0x1,-0x1(%rax,%rdi,1)
  sbb    $0x0,%esi
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L21:
  movsbl (%rbx),%edi
  call   <isprint@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  je     L6
  movsbl (%rbx),%esi
L6:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: %c

assistant: ```c
void print_asc(const char *buf, int len) {
  int i;
  if (buf[len - 1] == 0)
    len--;
  for (i = 0; i < len; i++)
    printf("%c", isprint(buf[i]) ? buf[i] : '.');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_asc>:
  endbr64
  movslq %esi,%rax
  cmpb   $0x1,-0x1(%rax,%rdi,1)
  sbb    $0x0,%esi
  test   %esi,%esi
  jle    L27
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L29:
  movsbl (%rbx),%edi
  call   <isprint@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  je     L1
  movsbl (%rbx),%esi
L1:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L29
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: %c

assistant: ```c
void print_asc(const char *buf, int len) {
  int i;
  if (buf[len - 1] == 0)
    len--;
  for (i = 0; i < len; i++)
    printf("%c", isprint(buf[i]) ? buf[i] : '.');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_freetab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L29
L2:
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L14
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L14:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L22
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
int ft_freetab(char **tab) {
  int i;
  if (!tab)
    return (0);
  i = -1;
  while (tab[++i])
    free(tab[i]);
  free(tab);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_freetab>:
  endbr64
  test   %rdi,%rdi
  je     L29
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L19
  lea    0x8(%rbp),%rbx
L23:
  call   <free@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L23
L19:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_freetab(char **tab) {
  int i;
  if (!tab)
    return (0);
  i = -1;
  while (tab[++i])
    free(tab[i]);
  free(tab);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_freetab>:
  endbr64
  test   %rdi,%rdi
  je     L13
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
  lea    0x8(%rbp),%rbx
  xchg   %ax,%ax
L29:
  call   <free@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L29
L8:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_freetab(char **tab) {
  int i;
  if (!tab)
    return (0);
  i = -1;
  while (tab[++i])
    free(tab[i]);
  free(tab);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_freetab>:
  endbr64
  test   %rdi,%rdi
  je     L15
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L19
  lea    0x8(%rbp),%rbx
  xchg   %ax,%ax
L1:
  call   <free@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L1
L19:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_freetab(char **tab) {
  int i;
  if (!tab)
    return (0);
  i = -1;
  while (tab[++i])
    free(tab[i]);
  free(tab);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<NumPBinString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%eax
  mov    %ax,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x11,%edi
  call   <calloc@plt>
  mov    %rax,-0x48(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  jne    L14
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <parser_Error@plt>
L14:
  movw   $0xf,-0x4a(%rbp)
  movw   $0x0,-0x4a(%rbp)
  jmp    L31
L36:
  movzwl -0x4a(%rbp),%edx
  movzwl -0x54(%rbp),%eax
  movzwl %ax,%eax
  movzwl -0x4a(%rbp),%ecx
  mov    $0xf,%esi
  mov    %esi,%ebx
  sub    %ecx,%ebx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <GetBit@plt>
  movslq %ebx,%rdx
  mov    %ax,-0x40(%rbp,%rdx,2)
  movzwl -0x4a(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4a(%rbp)
L31:
  cmpw   $0xf,-0x4a(%rbp)
  jbe    L36
  movw   $0x0,-0x4a(%rbp)
  jmp    L21
L38:
  movzwl -0x4a(%rbp),%eax
  cltq
  movzwl -0x40(%rbp,%rax,2),%eax
  cmp    $0x1,%ax
  jne    L32
  mov    $0x31,%edx
  jmp    L79
L32:
  mov    $0x30,%edx
L79:
  movzwl -0x4a(%rbp),%ecx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  movzwl -0x4a(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4a(%rbp)
L21:
  cmpw   $0xf,-0x4a(%rbp)
  jbe    L38
  mov    -0x48(%rbp),%rax
  add    $0x10,%rax
  movb   $0x0,(%rax)
  mov    -0x48(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: Memoria insuficiente para alocacao!

assistant: ```c
char *NumPBinString(short num) {
  char *ret = calloc(17, sizeof(char));
  unsigned short digitos[16];
  if (ret == NULL)
    parser_Error("Memoria insuficiente para alocacao!");
  unsigned short i = 15;
  for (i = 0; i < 16; i++) {
    digitos[15 - i] = GetBit((unsigned short)num, i);
  }
  for (i = 0; i < 16; i++) {
    ret[i] = (digitos[i] == 1) ? '1' : '0';
  }
  ret[16] = '\0';
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<NumPBinString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x11,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
L8:
  mov    $0x0,%ebx
  movzwl %r12w,%r12d
L24:
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <GetBit@plt>
  mov    %eax,%edx
  mov    %rbx,%rax
  neg    %rax
  mov    %dx,0x1e(%rsp,%rax,2)
  add    $0x1,%rbx
  cmp    $0x10,%rbx
  jne    L24
  mov    $0x0,%eax
  mov    %rsp,%rcx
L38:
  cmpw   $0x1,(%rcx,%rax,2)
  sete   %dl
  add    $0x30,%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L38
  movb   $0x0,0x10(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    %rbp,%rax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  lea    D3(%rip),%rdi
  call   <parser_Error@plt>
  jmp    L8
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: Memoria insuficiente para alocacao!

assistant: ```c
char *NumPBinString(short num) {
  char *ret = calloc(17, sizeof(char));
  unsigned short digitos[16];
  if (ret == NULL)
    parser_Error("Memoria insuficiente para alocacao!");
  unsigned short i = 15;
  for (i = 0; i < 16; i++) {
    digitos[15 - i] = GetBit((unsigned short)num, i);
  }
  for (i = 0; i < 16; i++) {
    ret[i] = (digitos[i] == 1) ? '1' : '0';
  }
  ret[16] = '\0';
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<NumPBinString>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x11,%edi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
L33:
  movzwl %bp,%ebp
  xor    %ebx,%ebx
  lea    0x1e(%rsp),%r13
  nopl   0x0(%rax)
L14:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <GetBit@plt>
  mov    %eax,%r8d
  mov    %rbx,%rax
  add    $0x1,%rbx
  neg    %rax
  mov    %r8w,0x0(%r13,%rax,2)
  cmp    $0x10,%rbx
  jne    L14
  xor    %eax,%eax
  mov    %rsp,%rcx
  nop
L46:
  cmpw   $0x1,(%rcx,%rax,2)
  sete   %dl
  add    $0x30,%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L46
  movb   $0x0,0x10(%r12)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  lea    D0(%rip),%rdi
  call   <parser_Error@plt>
  jmp    L33
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: Memoria insuficiente para alocacao!

assistant: ```c
char *NumPBinString(short num) {
  char *ret = calloc(17, sizeof(char));
  unsigned short digitos[16];
  if (ret == NULL)
    parser_Error("Memoria insuficiente para alocacao!");
  unsigned short i = 15;
  for (i = 0; i < 16; i++) {
    digitos[15 - i] = GetBit((unsigned short)num, i);
  }
  for (i = 0; i < 16; i++) {
    ret[i] = (digitos[i] == 1) ? '1' : '0';
  }
  ret[16] = '\0';
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NumPBinString>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x11,%edi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L27
L26:
  movzwl %bp,%ebp
  xor    %ebx,%ebx
  lea    0x1e(%rsp),%r12
  nopl   (%rax)
L39:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <GetBit@plt>
  mov    %eax,%r8d
  mov    %rbx,%rax
  add    $0x1,%rbx
  neg    %rax
  mov    %r8w,(%r12,%rax,2)
  cmp    $0x10,%rbx
  jne    L39
  movdqa D20(%rip),%xmm1
  movdqa D7(%rip),%xmm2
  movb   $0x0,0x10(%r13)
  movdqa D19(%rip),%xmm3
  movdqa %xmm1,%xmm0
  pcmpeqw 0x10(%rsp),%xmm1
  movdqa %xmm2,%xmm4
  pcmpeqw (%rsp),%xmm0
  pand   %xmm1,%xmm2
  pandn  %xmm3,%xmm1
  pand   %xmm0,%xmm4
  por    %xmm2,%xmm1
  pandn  %xmm3,%xmm0
  movdqa D30(%rip),%xmm2
  por    %xmm4,%xmm0
  pand   %xmm2,%xmm0
  pand   %xmm1,%xmm2
  packuswb %xmm2,%xmm0
  movups %xmm0,0x0(%r13)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x38,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  lea    D21(%rip),%rdi
  call   <parser_Error@plt>
  jmp    L26
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D20
type: byte[16]
name: read_data
arguments: tag: D7
type: byte[16]
name: read_data
arguments: tag: D19
type: byte[16]
name: read_data
arguments: tag: D30
type: byte[16]
name: read_data
arguments: tag: D21
type: string

tool: {"D20": [0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00]}

tool: {"D7": [0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00]}

tool: {"D19": [0x30,0x00,0x30,0x00,0x30,0x00,0x30,0x00,0x30,0x00,0x30,0x00,0x30,0x00,0x30,0x00]}

tool: {"D30": [0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00]}

tool: D21: Memoria insuficiente para alocacao!

assistant: ```c
char *NumPBinString(short num) {
  char *ret = calloc(17, sizeof(char));
  unsigned short digitos[16];
  if (ret == NULL)
    parser_Error("Memoria insuficiente para alocacao!");
  unsigned short i = 15;
  for (i = 0; i < 16; i++) {
    digitos[15 - i] = GetBit((unsigned short)num, i);
  }
  for (i = 0; i < 16; i++) {
    ret[i] = (digitos[i] == 1) ? '1' : '0';
  }
  ret[16] = '\0';
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdx
  mov    $0x3,%esi
  mov    $0x0,%edi
  call   <kPrintString@plt>
L0:
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: C Language Kernel Started~!!!

assistant: ```c
void Main(void) {
  kPrintString(0, 3, "C Language Kernel Started~!!!");
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdx
  mov    $0x3,%esi
  mov    $0x0,%edi
  call   <kPrintString@plt>
L3:
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: C Language Kernel Started~!!!

assistant: ```c
void Main(void) {
  kPrintString(0, 3, "C Language Kernel Started~!!!");
  while (1)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdx
  mov    $0x3,%esi
  xor    %edi,%edi
  call   <kPrintString@plt>
L4:
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D8: C Language Kernel Started~!!!

assistant: ```c
void Main(void) {
  kPrintString(0, 3, "C Language Kernel Started~!!!");
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdx
  mov    $0x3,%esi
  xor    %edi,%edi
  call   <kPrintString@plt>
L7:
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: C Language Kernel Started~!!!

assistant: ```c
void Main(void) {
  kPrintString(0, 3, "C Language Kernel Started~!!!");
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<match_path_absolute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L14
L19:
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x73,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <match_xset_enc@plt>
L14:
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x2f,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <match_char@plt>
  test   %rax,%rax
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void match_path_absolute(char const **str, char const *end) {
  while (match_char(str, end, '/')) {
    match_xset_enc(str, end, (1 | 2 | 16 | 32 | 64));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<match_path_absolute>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  jmp    L9
L7:
  mov    $0x73,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match_xset_enc@plt>
L9:
  mov    $0x2f,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match_char@plt>
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void match_path_absolute(char const **str, char const *end) {
  while (match_char(str, end, '/')) {
    match_xset_enc(str, end, (1 | 2 | 16 | 32 | 64));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<match_path_absolute>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x73,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match_xset_enc@plt>
L3:
  mov    $0x2f,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match_char@plt>
  test   %rax,%rax
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void match_path_absolute(char const **str, char const *end) {
  while (match_char(str, end, '/')) {
    match_xset_enc(str, end, (1 | 2 | 16 | 32 | 64));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<match_path_absolute>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0x73,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match_xset_enc@plt>
L5:
  mov    $0x2f,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <match_char@plt>
  test   %rax,%rax
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void match_path_absolute(char const **str, char const *end) {
  while (match_char(str, end, '/')) {
    match_xset_enc(str, end, (1 | 2 | 16 | 32 | 64));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bcdtobin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
char bcdtobin(char val) {
  char high = (val & 0xF0) >> 4;
  char low = val & 0x0F;
  return (high * 10) + low;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bcdtobin>:
  endbr64
  mov    %edi,%eax
  shr    $0x4,%al
  lea    (%rax,%rax,4),%eax
  and    $0xf,%edi
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
char bcdtobin(char val) {
  char high = (val & 0xF0) >> 4;
  char low = val & 0x0F;
  return (high * 10) + low;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bcdtobin>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%edi
  shr    $0x4,%al
  lea    (%rax,%rax,4),%eax
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
char bcdtobin(char val) {
  char high = (val & 0xF0) >> 4;
  char low = val & 0x0F;
  return (high * 10) + low;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bcdtobin>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%edi
  shr    $0x4,%al
  lea    (%rax,%rax,4),%eax
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
char bcdtobin(char val) {
  char high = (val & 0xF0) >> 4;
  char low = val & 0x0F;
  return (high * 10) + low;
}
```