ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<af_from_dB>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  test   %rsi,%rsi
  je     L39
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L39
  test   %edi,%edi
  jle    L18
  mov    %rsi,%r12
  movd   %xmm1,%r14d
  movslq %edi,%rbp
  xor    %ebx,%ebx
  jmp    L46
  nopl   0x0(%rax)
L30:
  movd   %r14d,%xmm6
  maxss  %xmm1,%xmm6
  movaps %xmm6,%xmm1
L11:
  mov    D6(%rip),%rax
  divss  0xc(%rsp),%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
L71:
  movss  %xmm0,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L18
L46:
  movss  (%r12,%rbx,4),%xmm1
  movss  D0(%rip),%xmm3
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm3
  jae    L71
  comiss 0x8(%rsp),%xmm1
  jbe    L30
  movss  0x8(%rsp),%xmm1
  jmp    L11
  nopl   0x0(%rax)
L18:
  mov    $0x1,%eax
L51:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  mov    $0xfffffffe,%eax
  jmp    L51
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: f64
name: retrieve_data
arguments: label: D0
type_infered: byte[4]

tool: D6: 10

tool: {"D0": [0x00,0x00,0x48,0xc3]}

assistant: ```c
int af_from_dB(int n, float *in, float *out, float k, float mi, float ma) {
  int i = 0;
  if (!in || !out)
    return -2;
  for (i = 0; i < n; i++) {
    if (in[i] <= -200)
      out[i] = 0.0;
    else
      out[i] = pow(10.0, (((in[i]) > (ma)) ? (ma) : (((in[i]) < (mi)) ? (mi) : (in[i]))) / k);
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<conv4FromNativeToEco>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <write4ToEco@plt>
  nop
  leave
  ret
```

assistant: ```c
void conv4FromNativeToEco(unsigned char *p) {
  unsigned int data;
  data = *(unsigned int *)p;
  write4ToEco(p, data);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<conv4FromNativeToEco>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%esi
  call   <write4ToEco@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void conv4FromNativeToEco(unsigned char *p) {
  unsigned int data;
  data = *(unsigned int *)p;
  write4ToEco(p, data);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<conv4FromNativeToEco>:
  endbr64
  mov    (%rdi),%esi
  jmp    1050 <write4ToEco@plt>
```

assistant: ```c
void conv4FromNativeToEco(unsigned char *p) {
  unsigned int data;
  data = *(unsigned int *)p;
  write4ToEco(p, data);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<conv4FromNativeToEco>:
  endbr64
  mov    (%rdi),%esi
  jmp    1050 <write4ToEco@plt>
```

assistant: ```c
void conv4FromNativeToEco(unsigned char *p) {
  unsigned int data;
  data = *(unsigned int *)p;
  write4ToEco(p, data);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FFTABLEOUT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void FFTABLEOUT(unsigned char *data, unsigned char *tab, int g) {
  *((int *)data) = *(((int *)tab) + 2 * g);
  *(((int *)data) + 1) = *(((int *)tab) + 2 * g + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FFTABLEOUT>:
  endbr64
  add    %edx,%edx
  movslq %edx,%rdx
  mov    (%rsi,%rdx,4),%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi,%rdx,4),%eax
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void FFTABLEOUT(unsigned char *data, unsigned char *tab, int g) {
  *((int *)data) = *(((int *)tab) + 2 * g);
  *(((int *)data) + 1) = *(((int *)tab) + 2 * g + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<FFTABLEOUT>:
  endbr64
  add    %edx,%edx
  movslq %edx,%rdx
  mov    (%rsi,%rdx,4),%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi,%rdx,4),%eax
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void FFTABLEOUT(unsigned char *data, unsigned char *tab, int g) {
  *((int *)data) = *(((int *)tab) + 2 * g);
  *(((int *)data) + 1) = *(((int *)tab) + 2 * g + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<FFTABLEOUT>:
  endbr64
  add    %edx,%edx
  movslq %edx,%rdx
  mov    (%rsi,%rdx,4),%eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi,%rdx,4),%eax
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void FFTABLEOUT(unsigned char *data, unsigned char *tab, int g) {
  *((int *)data) = *(((int *)tab) + 2 * g);
  *(((int *)data) + 1) = *(((int *)tab) + 2 * g + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L29
L34:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D31(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D22(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x10(%rbp),%xmm0
  setp   %al
  movzbl %al,%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L53
  cmpl   $0x1,-0x20(%rbp)
  je     L53
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L53:
  addl   $0x1,-0x1c(%rbp)
L29:
  cmpl   $0xf423f,-0x1c(%rbp)
  jle    L34
L12:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L47
  cmpl   $0x1,-0x20(%rbp)
  je     L47
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L47:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D31
type_infered: f64
name: parse_data
arguments: tag: D22
type_infered: f64
name: parse_data
arguments: tag: D4
type_infered: string

tool: D31: 10000000

tool: D22: 5000000

tool: D4: should return 0 or 1


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double t;
  int y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1.0e7 * rand_double()) - 5.0e6;
    y = isnan(x);
    if (y != 0 && y != 1) {
      printf("should return 0 or 1\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != 0 && y != 1) {
    printf("should return 0 or 1\n");
  }
  return elapsed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<benchmark>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r14
  mov    $0xf4240,%ebx
L2:
  mov    $0x0,%eax
  call   <rand_double@plt>
  sub    $0x1,%ebx
  jne    L2
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r14,%xmm1
  subsd  %xmm1,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double t;
  int y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1.0e7 * rand_double()) - 5.0e6;
    y = isnan(x);
    if (y != 0 && y != 1) {
      printf("should return 0 or 1\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != 0 && y != 1) {
    printf("should return 0 or 1\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0xf4240,%ebx
  sub    $0x10,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <rand_double@plt>
  sub    $0x1,%ebx
  jne    L8
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double t;
  int y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1.0e7 * rand_double()) - 5.0e6;
    y = isnan(x);
    if (y != 0 && y != 1) {
      printf("should return 0 or 1\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != 0 && y != 1) {
    printf("should return 0 or 1\n");
  }
  return elapsed;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<benchmark>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0xf4240,%ebx
  sub    $0x10,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <rand_double@plt>
  sub    $0x1,%ebx
  jne    L4
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double t;
  int y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1.0e7 * rand_double()) - 5.0e6;
    y = isnan(x);
    if (y != 0 && y != 1) {
      printf("should return 0 or 1\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != 0 && y != 1) {
    printf("should return 0 or 1\n");
  }
  return elapsed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<PIOA_IrqHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L3:
  jmp    L3
```

assistant: ```c
__attribute__((weak)) void PIOA_IrqHandler(void) {
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PIOA_IrqHandler>:
  endbr64
L6:
  jmp    L6
```

assistant: ```c
__attribute__((weak)) void PIOA_IrqHandler(void) {
  while (1)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PIOA_IrqHandler>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
__attribute__((weak)) void PIOA_IrqHandler(void) {
  while (1)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<PIOA_IrqHandler>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
__attribute__((weak)) void PIOA_IrqHandler(void) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<interleave>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L29:
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movss  (%rcx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L29
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void interleave(float *dest, float **src, int channels, int samples) {
  for (int i = 0; i < samples; i++) {
    for (int c = 0; c < channels; c++) {
      *dest++ = src[c][i];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<interleave>:
  endbr64
  mov    %rsi,%r8
  test   %ecx,%ecx
  jle    L53
  mov    %ecx,%ecx
  lea    0x0(,%rcx,4),%r10
  lea    -0x1(%rdx),%r9d
  lea    0x4(,%r9,4),%r11
  mov    $0x0,%esi
  jmp    L32
L39:
  mov    (%r8,%rax,8),%rcx
  movss  (%rcx,%rsi,1),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %rcx,%r9
  jne    L39
  add    %r11,%rdi
L26:
  add    $0x4,%rsi
  cmp    %r10,%rsi
  je     L53
L32:
  mov    $0x0,%eax
  test   %edx,%edx
  jg     L39
  jmp    L26
L53:
  ret
```

assistant: ```c
void interleave(float *dest, float **src, int channels, int samples) {
  for (int i = 0; i < samples; i++) {
    for (int c = 0; c < channels; c++) {
      *dest++ = src[c][i];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interleave>:
  endbr64
  mov    %rsi,%r8
  test   %ecx,%ecx
  jle    L28
  movslq %ecx,%rcx
  lea    -0x1(%rdx),%r9d
  xor    %esi,%esi
  lea    0x0(,%rcx,4),%r10
  lea    0x4(,%r9,4),%r11
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  test   %edx,%edx
  jle    L35
  xchg   %ax,%ax
L39:
  mov    (%r8,%rax,8),%rcx
  movss  (%rcx,%rsi,1),%xmm0
  mov    %rax,%rcx
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %r9,%rcx
  jne    L39
  add    %r11,%rdi
L35:
  add    $0x4,%rsi
  cmp    %r10,%rsi
  jne    L4
L28:
  ret
```

assistant: ```c
void interleave(float *dest, float **src, int channels, int samples) {
  for (int i = 0; i < samples; i++) {
    for (int c = 0; c < channels; c++) {
      *dest++ = src[c][i];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<interleave>:
  endbr64
  test   %ecx,%ecx
  jle    L20
  test   %edx,%edx
  jle    L20
  movslq %ecx,%rcx
  movslq %edx,%r8
  lea    0x0(,%rcx,4),%r9
  lea    0x0(,%r8,4),%r10
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%rsi,%rax,8),%rdx
  movss  (%rdx,%rcx,1),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L16
  add    $0x4,%rcx
  add    %r10,%rdi
  cmp    %rcx,%r9
  jne    L24
L20:
  ret
```

assistant: ```c
void interleave(float *dest, float **src, int channels, int samples) {
  for (int i = 0; i < samples; i++) {
    for (int c = 0; c < channels; c++) {
      *dest++ = src[c][i];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subtract_roman>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <roman_to_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <roman_to_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <int_to_roman@plt>
  leave
  ret
```

assistant: ```c
char *subtract_roman(char minuend[], char subtrahend[]) {
  int x = roman_to_int(minuend);
  int y = roman_to_int(subtrahend);
  int difference = x - y;
  return int_to_roman(difference);
}
```
user: What is the c source code of the assembly code below?

```asm
<subtract_roman>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <roman_to_int@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <roman_to_int@plt>
  sub    %eax,%ebx
  mov    %ebx,%edi
  call   <int_to_roman@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *subtract_roman(char minuend[], char subtrahend[]) {
  int x = roman_to_int(minuend);
  int y = roman_to_int(subtrahend);
  int difference = x - y;
  return int_to_roman(difference);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<subtract_roman>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <roman_to_int@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <roman_to_int@plt>
  add    $0x8,%rsp
  sub    %eax,%ebx
  mov    %ebx,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <int_to_roman@plt>
```

assistant: ```c
char *subtract_roman(char minuend[], char subtrahend[]) {
  int x = roman_to_int(minuend);
  int y = roman_to_int(subtrahend);
  int difference = x - y;
  return int_to_roman(difference);
}
```
user: Translate the below assembly code into C programming language:

```asm
<subtract_roman>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <roman_to_int@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <roman_to_int@plt>
  add    $0x8,%rsp
  sub    %eax,%ebx
  mov    %ebx,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <int_to_roman@plt>
```

assistant: ```c
char *subtract_roman(char minuend[], char subtrahend[]) {
  int x = roman_to_int(minuend);
  int y = roman_to_int(subtrahend);
  int difference = x - y;
  return int_to_roman(difference);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D0: uid = %d, gid = %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("uid = %d, gid = %d\n", getuid(), getgid());
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D8: uid = %d, gid = %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("uid = %d, gid = %d\n", getuid(), getgid());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %r12d,%edx
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: uid = %d, gid = %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("uid = %d, gid = %d\n", getuid(), getgid());
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %r12d,%edx
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: uid = %d, gid = %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("uid = %d, gid = %d\n", getuid(), getgid());
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<flash_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L68
L75:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    %edx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  mov    $0x64,%edi
  call   <delay_ms@plt>
  cmpl   $0x6,-0x4(%rbp)
  jg     L50
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    %edx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
L50:
  addl   $0x1,-0x4(%rbp)
L68:
  cmpl   $0x7,-0x4(%rbp)
  jle    L75
  movl   $0x7,-0x4(%rbp)
  jmp    L73
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    %edx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  mov    $0x64,%edi
  call   <delay_ms@plt>
  cmpl   $0x0,-0x4(%rbp)
  jle    L53
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    %edx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
L53:
  subl   $0x1,-0x4(%rbp)
L73:
  cmpl   $0x0,-0x4(%rbp)
  jns    L4
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L85:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    %edx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  mov    $0x64,%edi
  call   <delay_ms@plt>
  cmpl   $0x6,-0x4(%rbp)
  jg     L30
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    %edx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
L30:
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x7,-0x4(%rbp)
  jle    L85
  nop
  nop
  leave
  ret
```

assistant: ```c
void flash_3() {
  int i;
  for (i = 0; i < 8; i++) {
    box_apeak_xy(0, i, 0, 7, i, 7, 1, 1);
    delay_ms(100);
    if (i < 7)
      box_apeak_xy(0, i, 0, 7, i, 7, 1, 0);
  }
  for (i = 7; i >= 0; i--) {
    box_apeak_xy(0, i, 0, 7, i, 7, 1, 1);
    delay_ms(100);
    if (i > 0)
      box_apeak_xy(0, i, 0, 7, i, 7, 1, 0);
  }
  for (i = 0; i < 8; i++) {
    box_apeak_xy(0, i, 0, 7, i, 7, 1, 1);
    delay_ms(100);
    if (i < 7)
      box_apeak_xy(0, i, 0, 7, i, 7, 1, 0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<flash_3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  jmp    L36
L103:
  cmp    $0x7,%ebp
  jle    L118
  mov    $0x6,%ebp
  mov    $0x7,%ebx
  jmp    L70
L118:
  add    $0x1,%ebx
  add    $0x1,%ebp
L36:
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    %ebx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  mov    $0x64,%edi
  call   <delay_ms@plt>
  add    $0x10,%rsp
  cmp    $0x6,%ebx
  jg     L103
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    %ebx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  jmp    L118
L76:
  test   %ebp,%ebp
  jns    L73
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  jmp    L22
L73:
  sub    $0x1,%ebx
  sub    $0x1,%ebp
L70:
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    %ebx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  mov    $0x64,%edi
  call   <delay_ms@plt>
  add    $0x10,%rsp
  test   %ebx,%ebx
  jle    L76
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    %ebx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  jmp    L73
L72:
  cmp    $0x7,%ebp
  jle    L86
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L86:
  add    $0x1,%ebx
  add    $0x1,%ebp
L22:
  push   $0x1
  push   $0x1
  mov    $0x7,%r9d
  mov    %ebx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  mov    $0x64,%edi
  call   <delay_ms@plt>
  add    $0x10,%rsp
  cmp    $0x6,%ebx
  jg     L72
  push   $0x0
  push   $0x1
  mov    $0x7,%r9d
  mov    %ebx,%r8d
  mov    $0x7,%ecx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <box_apeak_xy@plt>
  add    $0x10,%rsp
  jmp    L86
```

assistant: ```c
void flash_3() {
  int i;
  for (i = 0; i < 8; i++) {
    box_apeak_xy(0, i, 0, 7, i, 7, 1, 1);
    delay_ms(100);
    if (i < 7)
      box_apeak_xy(0, i, 0, 7, i, 7, 1, 0);
  }
  for (i = 7; i >= 0; i--) {
    box_apeak_xy(0, i, 0, 7, i, 7, 1, 1);
    delay_ms(100);
    if (i > 0)
      box_apeak_xy(0, i, 0, 7, i, 7, 1, 0);
  }
  for (i = 0; i < 8; i++) {
    box_apeak_xy(0, i, 0, 7, i, 7, 1, 1);
    delay_ms(100);
    if (i < 7)
      box_apeak_xy(0, i, 0, 7, i, 7, 1, 0);
  }
}
```