ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<maximum>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  xor    %esi,%esi
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%rcx
  nopw   0x0(%rax,%rax,1)
L33:
  test   %edx,%edx
  jle    L85
  mov    (%rdi),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    $0x1,%edx
  je     L85
  mov    0x4(%rdi),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    $0x2,%edx
  je     L85
  mov    0x8(%rdi),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    $0x3,%edx
  je     L85
  mov    0xc(%rdi),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    $0x4,%edx
  je     L85
  mov    0x10(%rdi),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    $0x5,%edx
  je     L85
  mov    $0x5,%eax
L34:
  mov    (%rdi,%rax,4),%r8d
  cmp    %r8d,%esi
  cmovl  %r8d,%esi
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L34
  nopl   0x0(%rax)
L85:
  add    $0x10,%rdi
  cmp    %rcx,%rdi
  jne    L33
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
L15:
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: A maior nota: %i


assistant: ```c
void maximum(const int grades[][4], int pupils, int tests) {
  int i;
  int j;
  int highGrade = 0;
  for (i = 0; i < pupils; i++) {
    for (j = 0; j < tests; j++) {
      if (grades[i][j] > highGrade) {
        highGrade = grades[i][j];
      }
    }
  }
  printf("A maior nota: %i\n", highGrade);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffffff80,%edi
  call   <div1@plt>
  cmp    $0x80,%eax
  je     L68
  mov    $0x0,%eax
  call   <abort@plt>
L68:
  mov    $0xffffffff,%esi
  mov    $0xffffff80,%edi
  call   <div3@plt>
  cmp    $0x80,%eax
  je     L24
  mov    $0x0,%eax
  call   <abort@plt>
L24:
  mov    $0xffffff80,%edi
  call   <mod1@plt>
  test   %rax,%rax
  je     L62
  mov    $0x0,%eax
  call   <abort@plt>
L62:
  mov    $0xffffffff,%esi
  mov    $0xffffff80,%edi
  call   <mod3@plt>
  test   %rax,%rax
  je     L48
  mov    $0x0,%eax
  call   <abort@plt>
L48:
  mov    $0xffff8000,%edi
  call   <div2@plt>
  cmp    $0x8000,%eax
  je     L98
  mov    $0x0,%eax
  call   <abort@plt>
L98:
  mov    $0xffffffff,%esi
  mov    $0xffff8000,%edi
  call   <div4@plt>
  cmp    $0x8000,%eax
  je     L93
  mov    $0x0,%eax
  call   <abort@plt>
L93:
  mov    $0xffff8000,%edi
  call   <mod2@plt>
  test   %rax,%rax
  je     L84
  mov    $0x0,%eax
  call   <abort@plt>
L84:
  mov    $0xffffffff,%esi
  mov    $0xffff8000,%edi
  call   <mod4@plt>
  test   %rax,%rax
  je     L82
  mov    $0x0,%eax
  call   <abort@plt>
L82:
  mov    $0x2,%esi
  mov    $0x50000000,%edi
  call   <mod5@plt>
  test   %rax,%rax
  je     L35
  mov    $0x0,%eax
  call   <abort@plt>
L35:
  mov    $0x2,%esi
  mov    $0x50000000,%edi
  call   <mod6@plt>
  test   %rax,%rax
  je     L66
  mov    $0x0,%eax
  call   <abort@plt>
L66:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  if (div1(-(1 << 7)) != 1 << 7)
    abort();
  if (div3(-(1 << 7), -1) != 1 << 7)
    abort();
  if (mod1(-(1 << 7)) != 0)
    abort();
  if (mod3(-(1 << 7), -1) != 0)
    abort();
  if (div2(-(1 << 15)) != 1 << 15)
    abort();
  if (div4(-(1 << 15), -1) != 1 << 15)
    abort();
  if (mod2(-(1 << 15)) != 0)
    abort();
  if (mod4(-(1 << 15), -1) != 0)
    abort();
  if (mod5(0x50000000, 2) != 0)
    abort();
  if (mod6(0x50000000, 2) != 0)
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff80,%edi
  call   <div1@plt>
  cmp    $0x80,%eax
  jne    L13
L177:
  mov    $0xffffffff,%esi
  mov    $0xffffff80,%edi
  call   <div3@plt>
  cmp    $0x80,%eax
  jne    L126
L52:
  mov    $0xffffff80,%edi
  call   <mod1@plt>
  test   %rax,%rax
  jne    L12
L159:
  mov    $0xffffffff,%esi
  mov    $0xffffff80,%edi
  call   <mod3@plt>
  test   %rax,%rax
  jne    L10
L57:
  mov    $0xffff8000,%edi
  call   <div2@plt>
  cmp    $0x8000,%eax
  jne    L171
L137:
  mov    $0xffffffff,%esi
  mov    $0xffff8000,%edi
  call   <div4@plt>
  cmp    $0x8000,%eax
  jne    L172
L175:
  mov    $0xffff8000,%edi
  call   <mod2@plt>
  test   %rax,%rax
  jne    L196
L51:
  mov    $0xffffffff,%esi
  mov    $0xffff8000,%edi
  call   <mod4@plt>
  test   %rax,%rax
  jne    L5
L53:
  mov    $0x2,%esi
  mov    $0x50000000,%edi
  call   <mod5@plt>
  test   %rax,%rax
  jne    L140
L70:
  mov    $0x2,%esi
  mov    $0x50000000,%edi
  call   <mod6@plt>
  test   %rax,%rax
  jne    L31
L83:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L13:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L177
L126:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L52
L12:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L159
L10:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L57
L171:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L137
L172:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L175
L196:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L51
L5:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L53
L140:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L70
L31:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L83
```

assistant: ```c
main() {
  if (div1(-(1 << 7)) != 1 << 7)
    abort();
  if (div3(-(1 << 7), -1) != 1 << 7)
    abort();
  if (mod1(-(1 << 7)) != 0)
    abort();
  if (mod3(-(1 << 7), -1) != 0)
    abort();
  if (div2(-(1 << 15)) != 1 << 15)
    abort();
  if (div4(-(1 << 15), -1) != 1 << 15)
    abort();
  if (mod2(-(1 << 15)) != 0)
    abort();
  if (mod4(-(1 << 15), -1) != 0)
    abort();
  if (mod5(0x50000000, 2) != 0)
    abort();
  if (mod6(0x50000000, 2) != 0)
    abort();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff80,%edi
  call   <div1@plt>
  cmp    $0x80,%eax
  je     L95
  xor    %eax,%eax
  call   <abort@plt>
L95:
  mov    $0xffffffff,%esi
  mov    $0xffffff80,%edi
  call   <div3@plt>
  cmp    $0x80,%eax
  je     L19
  xor    %eax,%eax
  call   <abort@plt>
L19:
  mov    $0xffffff80,%edi
  call   <mod1@plt>
  test   %rax,%rax
  jne    L111
L132:
  mov    $0xffffffff,%esi
  mov    $0xffffff80,%edi
  call   <mod3@plt>
  test   %rax,%rax
  jne    L114
L38:
  mov    $0xffff8000,%edi
  call   <div2@plt>
  cmp    $0x8000,%eax
  je     L56
  xor    %eax,%eax
  call   <abort@plt>
L56:
  mov    $0xffffffff,%esi
  mov    $0xffff8000,%edi
  call   <div4@plt>
  cmp    $0x8000,%eax
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  mov    $0xffff8000,%edi
  call   <mod2@plt>
  test   %rax,%rax
  jne    L113
L142:
  mov    $0xffffffff,%esi
  mov    $0xffff8000,%edi
  call   <mod4@plt>
  test   %rax,%rax
  jne    L146
L100:
  mov    $0x2,%esi
  mov    $0x50000000,%edi
  call   <mod5@plt>
  test   %rax,%rax
  jne    L30
L10:
  mov    $0x2,%esi
  mov    $0x50000000,%edi
  call   <mod6@plt>
  test   %rax,%rax
  jne    L33
L18:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L114:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L38
L111:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L132
L33:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L18
L30:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L10
L146:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L100
L113:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L142
```

assistant: ```c
main() {
  if (div1(-(1 << 7)) != 1 << 7)
    abort();
  if (div3(-(1 << 7), -1) != 1 << 7)
    abort();
  if (mod1(-(1 << 7)) != 0)
    abort();
  if (mod3(-(1 << 7), -1) != 0)
    abort();
  if (div2(-(1 << 15)) != 1 << 15)
    abort();
  if (div4(-(1 << 15), -1) != 1 << 15)
    abort();
  if (mod2(-(1 << 15)) != 0)
    abort();
  if (mod4(-(1 << 15), -1) != 0)
    abort();
  if (mod5(0x50000000, 2) != 0)
    abort();
  if (mod6(0x50000000, 2) != 0)
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff80,%edi
  call   <div1@plt>
  cmp    $0x80,%eax
  je     L99
  xor    %eax,%eax
  call   <abort@plt>
L99:
  mov    $0xffffffff,%esi
  mov    $0xffffff80,%edi
  call   <div3@plt>
  cmp    $0x80,%eax
  je     L112
  xor    %eax,%eax
  call   <abort@plt>
L112:
  mov    $0xffffff80,%edi
  call   <mod1@plt>
  test   %rax,%rax
  jne    L147
L83:
  mov    $0xffffffff,%esi
  mov    $0xffffff80,%edi
  call   <mod3@plt>
  test   %rax,%rax
  jne    L13
L36:
  mov    $0xffff8000,%edi
  call   <div2@plt>
  cmp    $0x8000,%eax
  je     L82
  xor    %eax,%eax
  call   <abort@plt>
L82:
  mov    $0xffffffff,%esi
  mov    $0xffff8000,%edi
  call   <div4@plt>
  cmp    $0x8000,%eax
  je     L38
  xor    %eax,%eax
  call   <abort@plt>
L38:
  mov    $0xffff8000,%edi
  call   <mod2@plt>
  test   %rax,%rax
  jne    L136
L35:
  mov    $0xffffffff,%esi
  mov    $0xffff8000,%edi
  call   <mod4@plt>
  test   %rax,%rax
  jne    L70
L9:
  mov    $0x2,%esi
  mov    $0x50000000,%edi
  call   <mod5@plt>
  test   %rax,%rax
  jne    L111
L45:
  mov    $0x2,%esi
  mov    $0x50000000,%edi
  call   <mod6@plt>
  test   %rax,%rax
  jne    L42
L154:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L13:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L36
L147:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L83
L42:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L154
L111:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L45
L70:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L9
L136:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L35
```

assistant: ```c
main() {
  if (div1(-(1 << 7)) != 1 << 7)
    abort();
  if (div3(-(1 << 7), -1) != 1 << 7)
    abort();
  if (mod1(-(1 << 7)) != 0)
    abort();
  if (mod3(-(1 << 7), -1) != 0)
    abort();
  if (div2(-(1 << 15)) != 1 << 15)
    abort();
  if (div4(-(1 << 15), -1) != 1 << 15)
    abort();
  if (mod2(-(1 << 15)) != 0)
    abort();
  if (mod4(-(1 << 15), -1) != 0)
    abort();
  if (mod5(0x50000000, 2) != 0)
    abort();
  if (mod6(0x50000000, 2) != 0)
    abort();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L47:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L47
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    $0x0,%eax
  jmp    L7
L44:
  mov    $0x1,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int is_path(char *str) {
  int i = 0;
  while (str[i] != '\0' && str[i] != '/') {
    i++;
  }
  if (str[i] == '\0')
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_path>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  cmp    $0x2f,%al
  je     L5
  add    $0x1,%rdi
L13:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L5
  cmp    $0x2f,%al
  jne    L13
L5:
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_path(char *str) {
  int i = 0;
  while (str[i] != '\0' && str[i] != '/') {
    i++;
  }
  if (str[i] == '\0')
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_path>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  setne  %cl
  mov    %ecx,%eax
  cmp    $0x2f,%dl
  je     L35
  test   %cl,%cl
  je     L35
  add    $0x1,%rdi
  nopl   0x0(%rax,%rax,1)
L31:
  movzbl (%rdi),%edx
  test   %dl,%dl
  setne  %al
  add    $0x1,%rdi
  cmp    $0x2f,%dl
  je     L35
  test   %al,%al
  jne    L31
L35:
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_path(char *str) {
  int i = 0;
  while (str[i] != '\0' && str[i] != '/') {
    i++;
  }
  if (str[i] == '\0')
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_path>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  setne  %cl
  mov    %ecx,%eax
  cmp    $0x2f,%dl
  je     L9
  test   %cl,%cl
  je     L9
  add    $0x1,%rdi
  nopl   0x0(%rax,%rax,1)
L38:
  movzbl (%rdi),%edx
  test   %dl,%dl
  setne  %al
  add    $0x1,%rdi
  cmp    $0x2f,%dl
  je     L9
  test   %al,%al
  jne    L38
L9:
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_path(char *str) {
  int i = 0;
  while (str[i] != '\0' && str[i] != '/') {
    i++;
  }
  if (str[i] == '\0')
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse_factorial@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string
name: unpack_data
arguments: data_label: D11
type: string

tool: D7: Reverse Factorial > 

tool: D11: %lli

assistant: ```c
int main() {
  long long int factorial;
  printf("Reverse Factorial > ");
  scanf("%lli", &factorial);
  reverse_factorial(factorial);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  call   <reverse_factorial@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D6
type: string

tool: D14: Reverse Factorial > 

tool: D6: %lli

assistant: ```c
int main() {
  long long int factorial;
  printf("Reverse Factorial > ");
  scanf("%lli", &factorial);
  reverse_factorial(factorial);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  call   <reverse_factorial@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string

tool: D0: Reverse Factorial > 

tool: D12: %lli

assistant: ```c
int main() {
  long long int factorial;
  printf("Reverse Factorial > ");
  scanf("%lli", &factorial);
  reverse_factorial(factorial);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  call   <reverse_factorial@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D12: Reverse Factorial > 

tool: D0: %lli

assistant: ```c
int main() {
  long long int factorial;
  printf("Reverse Factorial > ");
  scanf("%lli", &factorial);
  reverse_factorial(factorial);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<e2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  sub    $0xc1,%eax
  cmp    $0x38,%eax
  ja     L214
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D1(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x30,%eax
  jmp    L196
  mov    $0x31,%eax
  jmp    L196
  mov    $0x32,%eax
  jmp    L196
  mov    $0x33,%eax
  jmp    L196
  mov    $0x34,%eax
  jmp    L196
  mov    $0x35,%eax
  jmp    L196
  mov    $0x36,%eax
  jmp    L196
  mov    $0x37,%eax
  jmp    L196
  mov    $0x38,%eax
  jmp    L196
  mov    $0x39,%eax
  jmp    L196
  mov    $0x41,%eax
  jmp    L196
  mov    $0x42,%eax
  jmp    L196
  mov    $0x43,%eax
  jmp    L196
  mov    $0x44,%eax
  jmp    L196
  mov    $0x45,%eax
  jmp    L196
  mov    $0x46,%eax
  jmp    L196
  mov    $0x47,%eax
  jmp    L196
  mov    $0x48,%eax
  jmp    L196
  mov    $0x49,%eax
  jmp    L196
  mov    $0x4a,%eax
  jmp    L196
  mov    $0x4b,%eax
  jmp    L196
  mov    $0x4c,%eax
  jmp    L196
  mov    $0x4d,%eax
  jmp    L196
  mov    $0x4e,%eax
  jmp    L196
  mov    $0x4f,%eax
  jmp    L196
  mov    $0x50,%eax
  jmp    L196
  mov    $0x51,%eax
  jmp    L196
  mov    $0x52,%eax
  jmp    L196
  mov    $0x53,%eax
  jmp    L196
  mov    $0x54,%eax
  jmp    L196
  mov    $0x55,%eax
  jmp    L196
  mov    $0x56,%eax
  jmp    L196
  mov    $0x57,%eax
  jmp    L196
  mov    $0x58,%eax
  jmp    L196
  mov    $0x59,%eax
  jmp    L196
  mov    $0x5a,%eax
  jmp    L196
L214:
  mov    $0x20,%eax
L196:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char e2a(unsigned char x) {
  switch (x) {
  case 0xF0:
    return '0';
  case 0xF1:
    return '1';
  case 0xF2:
    return '2';
  case 0xF3:
    return '3';
  case 0xF4:
    return '4';
  case 0xF5:
    return '5';
  case 0xF6:
    return '6';
  case 0xF7:
    return '7';
  case 0xF8:
    return '8';
  case 0xF9:
    return '9';
  case 0xC1:
    return 'A';
  case 0xC2:
    return 'B';
  case 0xC3:
    return 'C';
  case 0xC4:
    return 'D';
  case 0xC5:
    return 'E';
  case 0xC6:
    return 'F';
  case 0xC7:
    return 'G';
  case 0xC8:
    return 'H';
  case 0xC9:
    return 'I';
  case 0xD1:
    return 'J';
  case 0xD2:
    return 'K';
  case 0xD3:
    return 'L';
  case 0xD4:
    return 'M';
  case 0xD5:
    return 'N';
  case 0xD6:
    return 'O';
  case 0xD7:
    return 'P';
  case 0xD8:
    return 'Q';
  case 0xD9:
    return 'R';
  case 0xE2:
    return 'S';
  case 0xE3:
    return 'T';
  case 0xE4:
    return 'U';
  case 0xE5:
    return 'V';
  case 0xE6:
    return 'W';
  case 0xE7:
    return 'X';
  case 0xE8:
    return 'Y';
  case 0xE9:
    return 'Z';
  }
  return ' ';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<e2a>:
  endbr64
  add    $0x3f,%edi
  cmp    $0x38,%dil
  ja     L0
  movzbl %dil,%edi
  lea    D0(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x31,%eax
  ret
  mov    $0x32,%eax
  ret
  mov    $0x33,%eax
  ret
  mov    $0x34,%eax
  ret
  mov    $0x35,%eax
  ret
  mov    $0x36,%eax
  ret
  mov    $0x37,%eax
  ret
  mov    $0x38,%eax
  ret
  mov    $0x39,%eax
  ret
  mov    $0x41,%eax
  ret
  mov    $0x42,%eax
  ret
  mov    $0x43,%eax
  ret
  mov    $0x44,%eax
  ret
  mov    $0x45,%eax
  ret
  mov    $0x46,%eax
  ret
  mov    $0x47,%eax
  ret
  mov    $0x48,%eax
  ret
  mov    $0x49,%eax
  ret
  mov    $0x4a,%eax
  ret
  mov    $0x4b,%eax
  ret
  mov    $0x4c,%eax
  ret
  mov    $0x4d,%eax
  ret
  mov    $0x4e,%eax
  ret
  mov    $0x4f,%eax
  ret
  mov    $0x50,%eax
  ret
  mov    $0x51,%eax
  ret
  mov    $0x52,%eax
  ret
  mov    $0x53,%eax
  ret
  mov    $0x54,%eax
  ret
  mov    $0x55,%eax
  ret
  mov    $0x56,%eax
  ret
  mov    $0x57,%eax
  ret
  mov    $0x58,%eax
  ret
  mov    $0x59,%eax
  ret
  mov    $0x5a,%eax
  ret
L0:
  mov    $0x20,%eax
  ret
  mov    $0x30,%eax
  ret
```

assistant: ```c
unsigned char e2a(unsigned char x) {
  switch (x) {
  case 0xF0:
    return '0';
  case 0xF1:
    return '1';
  case 0xF2:
    return '2';
  case 0xF3:
    return '3';
  case 0xF4:
    return '4';
  case 0xF5:
    return '5';
  case 0xF6:
    return '6';
  case 0xF7:
    return '7';
  case 0xF8:
    return '8';
  case 0xF9:
    return '9';
  case 0xC1:
    return 'A';
  case 0xC2:
    return 'B';
  case 0xC3:
    return 'C';
  case 0xC4:
    return 'D';
  case 0xC5:
    return 'E';
  case 0xC6:
    return 'F';
  case 0xC7:
    return 'G';
  case 0xC8:
    return 'H';
  case 0xC9:
    return 'I';
  case 0xD1:
    return 'J';
  case 0xD2:
    return 'K';
  case 0xD3:
    return 'L';
  case 0xD4:
    return 'M';
  case 0xD5:
    return 'N';
  case 0xD6:
    return 'O';
  case 0xD7:
    return 'P';
  case 0xD8:
    return 'Q';
  case 0xD9:
    return 'R';
  case 0xE2:
    return 'S';
  case 0xE3:
    return 'T';
  case 0xE4:
    return 'U';
  case 0xE5:
    return 'V';
  case 0xE6:
    return 'W';
  case 0xE7:
    return 'X';
  case 0xE8:
    return 'Y';
  case 0xE9:
    return 'Z';
  }
  return ' ';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<e2a>:
  endbr64
  add    $0x3f,%edi
  mov    $0x20,%eax
  cmp    $0x38,%dil
  ja     L6
  movzbl %dil,%edi
  lea    D0(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L6:
  ret
```

assistant: ```c
unsigned char e2a(unsigned char x) {
  switch (x) {
  case 0xF0:
    return '0';
  case 0xF1:
    return '1';
  case 0xF2:
    return '2';
  case 0xF3:
    return '3';
  case 0xF4:
    return '4';
  case 0xF5:
    return '5';
  case 0xF6:
    return '6';
  case 0xF7:
    return '7';
  case 0xF8:
    return '8';
  case 0xF9:
    return '9';
  case 0xC1:
    return 'A';
  case 0xC2:
    return 'B';
  case 0xC3:
    return 'C';
  case 0xC4:
    return 'D';
  case 0xC5:
    return 'E';
  case 0xC6:
    return 'F';
  case 0xC7:
    return 'G';
  case 0xC8:
    return 'H';
  case 0xC9:
    return 'I';
  case 0xD1:
    return 'J';
  case 0xD2:
    return 'K';
  case 0xD3:
    return 'L';
  case 0xD4:
    return 'M';
  case 0xD5:
    return 'N';
  case 0xD6:
    return 'O';
  case 0xD7:
    return 'P';
  case 0xD8:
    return 'Q';
  case 0xD9:
    return 'R';
  case 0xE2:
    return 'S';
  case 0xE3:
    return 'T';
  case 0xE4:
    return 'U';
  case 0xE5:
    return 'V';
  case 0xE6:
    return 'W';
  case 0xE7:
    return 'X';
  case 0xE8:
    return 'Y';
  case 0xE9:
    return 'Z';
  }
  return ' ';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<e2a>:
  endbr64
  add    $0x3f,%edi
  mov    $0x20,%eax
  cmp    $0x38,%dil
  ja     L4
  movzbl %dil,%edi
  lea    D5(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L4:
  ret
```

assistant: ```c
unsigned char e2a(unsigned char x) {
  switch (x) {
  case 0xF0:
    return '0';
  case 0xF1:
    return '1';
  case 0xF2:
    return '2';
  case 0xF3:
    return '3';
  case 0xF4:
    return '4';
  case 0xF5:
    return '5';
  case 0xF6:
    return '6';
  case 0xF7:
    return '7';
  case 0xF8:
    return '8';
  case 0xF9:
    return '9';
  case 0xC1:
    return 'A';
  case 0xC2:
    return 'B';
  case 0xC3:
    return 'C';
  case 0xC4:
    return 'D';
  case 0xC5:
    return 'E';
  case 0xC6:
    return 'F';
  case 0xC7:
    return 'G';
  case 0xC8:
    return 'H';
  case 0xC9:
    return 'I';
  case 0xD1:
    return 'J';
  case 0xD2:
    return 'K';
  case 0xD3:
    return 'L';
  case 0xD4:
    return 'M';
  case 0xD5:
    return 'N';
  case 0xD6:
    return 'O';
  case 0xD7:
    return 'P';
  case 0xD8:
    return 'Q';
  case 0xD9:
    return 'R';
  case 0xE2:
    return 'S';
  case 0xE3:
    return 'T';
  case 0xE4:
    return 'U';
  case 0xE5:
    return 'V';
  case 0xE6:
    return 'W';
  case 0xE7:
    return 'X';
  case 0xE8:
    return 'Y';
  case 0xE9:
    return 'Z';
  }
  return ' ';
}
```