ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<resettable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edi
  call   <emulcommand@plt>
  lea    D1(%rip),%rsi
  mov    $0xfe,%edi
  add    $0x8,%rsp
  jmp    1070 <testemul@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: no table reset ACK

assistant: ```c
void resettable() {
  emulcommand(7);
  testemul(254, "no table reset ACK");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<partition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r15
  mov    %edx,%r14d
  mov    %ecx,%r12d
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %r14d,%edi
  movslq %r14d,%r14
  shl    $0x2,%r14
  mov    %rbx,%rsi
  lea    (%rbx,%r14,1),%rbp
  movslq %r12d,%r13
  shl    $0x2,%r13
  lea    (%rbx,%r13,1),%rbx
  add    %r15,%r14
  add    %r15,%r13
  sub    %edi,%r12d
  lea    0x1(%r12),%ecx
  cltd
  idiv   %ecx
  lea    (%rdx,%rdi,1),%eax
  cltq
  mov    (%rsi,%rax,4),%r12d
  mov    (%r15,%rax,4),%r15d
  cmp    %rbx,%rbp
  jb     L130
  jmp    L137
L25:
  add    $0x4,%rbp
  add    $0x4,%r14
L130:
  mov    0x0(%rbp),%eax
  cmp    %r12d,%eax
  jl     L25
  jne    L70
  cmp    %r15d,(%r14)
  jl     L25
  jmp    L70
L95:
  sub    $0x4,%rbx
  sub    $0x4,%r13
L70:
  mov    (%rbx),%eax
  cmp    %r12d,%eax
  jg     L95
  jne    L68
  cmp    %r15d,0x0(%r13)
  jg     L95
L68:
  cmp    %rbx,%rbp
  jb     L128
L123:
  cmp    %r15d,(%r14)
  je     L64
L84:
  cmp    %r15d,0x0(%r13)
  je     L152
L16:
  cmp    %rbx,%rbp
  jb     L130
L137:
  mov    %rbx,%rax
  sub    0x8(%rsp),%rax
  sar    $0x2,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L128:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <swap@plt>
  jmp    L123
L64:
  sub    $0x4,%rbx
  sub    $0x4,%r13
  jmp    L84
L152:
  add    $0x4,%rbp
  add    $0x4,%r14
  jmp    L16
```

assistant: ```c
int partition(int *a, int *b, int left, int right) {
  int pivotMan = 0, *firstMan = NULL, *lastMan = NULL;
  int pivotPos = 0, pivotWoman = 0, *firstWoman = NULL, *lastWoman = NULL;
  pivotPos = left + rand() % (right - left + 1);
  firstMan = a + left;
  lastMan = a + right;
  firstWoman = b + left;
  lastWoman = b + right;
  pivotMan = *(a + pivotPos);
  pivotWoman = *(b + pivotPos);
  while (firstMan < lastMan) {
    while (*firstMan < pivotMan || (*firstMan == pivotMan && *firstWoman < pivotWoman)) {
      firstMan++;
      firstWoman++;
    }
    while (*lastMan > pivotMan || (*lastMan == pivotMan && *lastWoman > pivotWoman)) {
      lastMan--;
      lastWoman--;
    }
    if (firstMan < lastMan) {
      swap(firstMan, lastMan);
      swap(firstWoman, lastWoman);
    }
    if (*firstWoman == pivotWoman) {
      lastMan--;
      lastWoman--;
    }
    if (*lastWoman == pivotWoman) {
      firstMan++;
      firstWoman++;
    }
  }
  return lastMan - a;
}
```
user: What is the c source code of the assembly code below?

```asm
<partition>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  mov    %r12,%r15
  shl    $0x2,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %edx,0xc(%rsp)
  call   <rand@plt>
  movslq 0xc(%rsp),%r13
  mov    %rbx,%rsi
  cltd
  mov    %r13,%rdi
  shl    $0x2,%r13
  sub    %edi,%r15d
  lea    (%rbx,%r13,1),%rbp
  add    %r12,%rbx
  add    %r14,%r13
  lea    0x1(%r15),%ecx
  add    %r14,%r12
  idiv   %ecx
  lea    (%rdx,%rdi,1),%eax
  cltq
  mov    (%rsi,%rax,4),%r15d
  mov    (%r14,%rax,4),%r14d
  cmp    %rbx,%rbp
  jb     L85
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L67:
  cmp    %r14d,0x0(%r13)
  jge    L122
L40:
  add    $0x4,%rbp
  add    $0x4,%r13
L85:
  cmp    %r15d,0x0(%rbp)
  jl     L40
  je     L67
  jmp    L122
  nopl   0x0(%rax,%rax,1)
L33:
  cmp    %r14d,(%r12)
  jle    L23
L123:
  sub    $0x4,%rbx
  sub    $0x4,%r12
L122:
  cmp    %r15d,(%rbx)
  jg     L123
  je     L33
L23:
  cmp    %rbx,%rbp
  jb     L112
L38:
  cmp    %r14d,0x0(%r13)
  jne    L20
  sub    $0x4,%rbx
  sub    $0x4,%r12
L20:
  cmp    %r14d,(%r12)
  jne    L21
  add    $0x4,%rbp
  add    $0x4,%r13
L21:
  cmp    %rbx,%rbp
  jb     L85
L24:
  mov    %rbx,%rax
  sub    (%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  sar    $0x2,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L112:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  jmp    L38
```

assistant: ```c
int partition(int *a, int *b, int left, int right) {
  int pivotMan = 0, *firstMan = NULL, *lastMan = NULL;
  int pivotPos = 0, pivotWoman = 0, *firstWoman = NULL, *lastWoman = NULL;
  pivotPos = left + rand() % (right - left + 1);
  firstMan = a + left;
  lastMan = a + right;
  firstWoman = b + left;
  lastWoman = b + right;
  pivotMan = *(a + pivotPos);
  pivotWoman = *(b + pivotPos);
  while (firstMan < lastMan) {
    while (*firstMan < pivotMan || (*firstMan == pivotMan && *firstWoman < pivotWoman)) {
      firstMan++;
      firstWoman++;
    }
    while (*lastMan > pivotMan || (*lastMan == pivotMan && *lastWoman > pivotWoman)) {
      lastMan--;
      lastWoman--;
    }
    if (firstMan < lastMan) {
      swap(firstMan, lastMan);
      swap(firstWoman, lastWoman);
    }
    if (*firstWoman == pivotWoman) {
      lastMan--;
      lastWoman--;
    }
    if (*lastWoman == pivotWoman) {
      firstMan++;
      firstWoman++;
    }
  }
  return lastMan - a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<partition>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  mov    %r12,%r15
  shl    $0x2,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %edx,0xc(%rsp)
  call   <rand@plt>
  movslq 0xc(%rsp),%r13
  mov    %rbx,%rsi
  cltd
  mov    %r13,%rdi
  shl    $0x2,%r13
  sub    %edi,%r15d
  lea    (%rbx,%r13,1),%rbp
  add    %r12,%rbx
  add    %r14,%r13
  lea    0x1(%r15),%ecx
  add    %r14,%r12
  idiv   %ecx
  lea    (%rdx,%rdi,1),%eax
  cltq
  mov    (%rsi,%rax,4),%r15d
  mov    (%r14,%rax,4),%r14d
  cmp    %rbx,%rbp
  jb     L21
  jmp    L136
  nopl   0x0(%rax,%rax,1)
L120:
  cmp    %r14d,0x0(%r13)
  jge    L155
L114:
  add    $0x4,%rbp
  add    $0x4,%r13
L21:
  cmp    %r15d,0x0(%rbp)
  jl     L114
  je     L120
  jmp    L155
  nopl   0x0(%rax,%rax,1)
L46:
  cmp    %r14d,(%r12)
  jle    L67
L61:
  sub    $0x4,%rbx
  sub    $0x4,%r12
L155:
  cmp    %r15d,(%rbx)
  jg     L61
  je     L46
L67:
  cmp    %rbx,%rbp
  jb     L11
L34:
  cmp    %r14d,0x0(%r13)
  jne    L107
  sub    $0x4,%rbx
  sub    $0x4,%r12
L107:
  cmp    %r14d,(%r12)
  je     L97
  cmp    %rbx,%rbp
  jb     L21
L136:
  mov    %rbx,%rax
  sub    (%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  sar    $0x2,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L97:
  add    $0x4,%rbp
  add    $0x4,%r13
  cmp    %rbp,%rbx
  ja     L21
  jmp    L136
  nop
L11:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  jmp    L34
```

assistant: ```c
int partition(int *a, int *b, int left, int right) {
  int pivotMan = 0, *firstMan = NULL, *lastMan = NULL;
  int pivotPos = 0, pivotWoman = 0, *firstWoman = NULL, *lastWoman = NULL;
  pivotPos = left + rand() % (right - left + 1);
  firstMan = a + left;
  lastMan = a + right;
  firstWoman = b + left;
  lastWoman = b + right;
  pivotMan = *(a + pivotPos);
  pivotWoman = *(b + pivotPos);
  while (firstMan < lastMan) {
    while (*firstMan < pivotMan || (*firstMan == pivotMan && *firstWoman < pivotWoman)) {
      firstMan++;
      firstWoman++;
    }
    while (*lastMan > pivotMan || (*lastMan == pivotMan && *lastWoman > pivotWoman)) {
      lastMan--;
      lastWoman--;
    }
    if (firstMan < lastMan) {
      swap(firstMan, lastMan);
      swap(firstWoman, lastWoman);
    }
    if (*firstWoman == pivotWoman) {
      lastMan--;
      lastWoman--;
    }
    if (*lastWoman == pivotWoman) {
      firstMan++;
      firstWoman++;
    }
  }
  return lastMan - a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<readtreturn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <readtrapno@plt>
  cmp    $0x3,%eax
  jne    L12
  mov    $0x80001108,%eax
  mov    (%rax),%eax
  jmp    L8
L12:
  mov    $0x80001108,%eax
  mov    (%rax),%eax
  sub    $0x4,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
uint readtreturn() {
  switch (readtrapno()) {
  case 3:
    return *(int *)0x80001108;
  default:
    return *(int *)0x80001108 - 4;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readtreturn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <readtrapno@plt>
  cmp    $0x3,%eax
  je     L4
  movabs 0x80001108,%eax
  sub    $0x4,%eax
L0:
  add    $0x8,%rsp
  ret
L4:
  movabs 0x80001108,%eax
  jmp    L0
```

assistant: ```c
uint readtreturn() {
  switch (readtrapno()) {
  case 3:
    return *(int *)0x80001108;
  default:
    return *(int *)0x80001108 - 4;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readtreturn>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <readtrapno@plt>
  cmp    $0x3,%eax
  movabs 0x80001108,%eax
  je     L9
  sub    $0x4,%eax
L9:
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint readtreturn() {
  switch (readtrapno()) {
  case 3:
    return *(int *)0x80001108;
  default:
    return *(int *)0x80001108 - 4;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readtreturn>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <readtrapno@plt>
  cmp    $0x3,%eax
  movabs 0x80001108,%eax
  je     L6
  sub    $0x4,%eax
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint readtreturn() {
  switch (readtrapno()) {
  case 3:
    return *(int *)0x80001108;
  default:
    return *(int *)0x80001108 - 4;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x1,-0x18(%rbp)
  jmp    L4
L3:
  addl   $0x1,-0x24(%rbp)
  shlq   -0x18(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jle    L3
  movl   $0x1,-0x28(%rbp)
  jmp    L47
L13:
  mov    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <fun@plt>
  add    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x28(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L51
  mov    -0x18(%rbp),%rax
  not    %rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rdi
  and    %rax,%rdi
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x24(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%ecx
  mov    %rdi,%rdx
  mov    %eax,%edi
  call   <fun@plt>
  add    %rax,-0x10(%rbp)
L51:
  addl   $0x1,-0x28(%rbp)
L47:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  mov    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x24(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <fun@plt>
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D19
type_infered: string

tool: D8: %lld

tool: D19: %lld


assistant: ```c
int main(void) {
  long long n, pos, res = 0;
  int i, j, L = 0;
  scanf("%lld", &n);
  for (pos = 1; pos <= n; pos <<= 1)
    L++;
  for (i = 1; i < L; i++) {
    res += fun(i, 1, n, L);
    pos = 1LL << (L - 1 - i);
    if (n & pos)
      res += fun(L, i + 1, n & ~pos, L);
  }
  res += fun(L, L, n, L);
  printf("%lld\n", res);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  jle    L7
  mov    $0x0,%ebp
  mov    $0x1,%eax
L10:
  mov    %ebp,%r12d
  add    $0x1,%ebp
  add    %rax,%rax
  cmp    %rdx,%rax
  jle    L10
  cmp    $0x1,%ebp
  jle    L5
  mov    $0x1,%ebx
  mov    $0x0,%r13d
  mov    $0x1,%r14d
  jmp    L24
L54:
  lea    0x1(%rbx),%eax
  cmp    %r12d,%ebx
  jge    L39
  mov    %eax,%ebx
L24:
  mov    %ebp,%ecx
  mov    (%rsp),%rdx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <fun@plt>
  add    %rax,%r13
  mov    %r12d,%ecx
  sub    %ebx,%ecx
  mov    %r14,%rdx
  shl    %cl,%rdx
  mov    (%rsp),%rax
  test   %rdx,%rax
  je     L54
  not    %rdx
  and    %rax,%rdx
  lea    0x1(%rbx),%esi
  mov    %ebp,%ecx
  mov    %ebp,%edi
  call   <fun@plt>
  add    %rax,%r13
  jmp    L54
L7:
  mov    $0x0,%ebp
  mov    $0x0,%r13d
L39:
  mov    %ebp,%ecx
  mov    (%rsp),%rdx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <fun@plt>
  lea    (%rax,%r13,1),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    $0x0,%r13d
  jmp    L39
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D10
type: string

tool: D12: %lld

tool: D10: %lld


assistant: ```c
int main(void) {
  long long n, pos, res = 0;
  int i, j, L = 0;
  scanf("%lld", &n);
  for (pos = 1; pos <= n; pos <<= 1)
    L++;
  for (i = 1; i < L; i++) {
    res += fun(i, 1, n, L);
    pos = 1LL << (L - 1 - i);
    if (n & pos)
      res += fun(L, i + 1, n & ~pos, L);
  }
  res += fun(L, L, n, L);
  printf("%lld\n", res);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D3(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  jle    L41
  mov    $0x1,%eax
  nopl   (%rax)
L44:
  add    %rax,%rax
  mov    %ebp,%r14d
  add    $0x1,%ebp
  cmp    %rdx,%rax
  jle    L44
  cmp    $0x1,%ebp
  je     L41
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  mov    $0x1,%r13d
  jmp    L82
  nop
L31:
  cmp    %r14d,%r15d
  jge    L28
L82:
  mov    %ebp,%ecx
  mov    %ebx,%edi
  mov    $0x1,%esi
  mov    %ebx,%r15d
  call   <fun@plt>
  mov    %r14d,%ecx
  mov    (%rsp),%rdx
  sub    %ebx,%ecx
  add    %rax,%r12
  mov    %r13,%rax
  add    $0x1,%ebx
  shl    %cl,%rax
  test   %rax,%rdx
  je     L31
  not    %rax
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %ebp,%edi
  and    %rax,%rdx
  call   <fun@plt>
  mov    (%rsp),%rdx
  add    %rax,%r12
  cmp    %r14d,%r15d
  jl     L82
L28:
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %ebp,%ecx
  call   <fun@plt>
  lea    D6(%rip),%rdi
  lea    (%rax,%r12,1),%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  xor    %r12d,%r12d
  jmp    L28
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D6
data_type: string

tool: D3: %lld

tool: D6: %lld


assistant: ```c
int main(void) {
  long long n, pos, res = 0;
  int i, j, L = 0;
  scanf("%lld", &n);
  for (pos = 1; pos <= n; pos <<= 1)
    L++;
  for (i = 1; i < L; i++) {
    res += fun(i, 1, n, L);
    pos = 1LL << (L - 1 - i);
    if (n & pos)
      res += fun(L, i + 1, n & ~pos, L);
  }
  res += fun(L, L, n, L);
  printf("%lld\n", res);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D6(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  jle    L37
  mov    $0x1,%eax
  nopl   (%rax)
L63:
  add    %rax,%rax
  mov    %ebp,%r14d
  add    $0x1,%ebp
  cmp    %rdx,%rax
  jle    L63
  cmp    $0x1,%ebp
  je     L37
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  mov    $0x1,%r13d
  jmp    L27
  nop
L73:
  cmp    %r14d,%r15d
  jge    L31
L27:
  mov    %ebp,%ecx
  mov    %ebx,%edi
  mov    $0x1,%esi
  mov    %ebx,%r15d
  call   <fun@plt>
  mov    %r14d,%ecx
  mov    (%rsp),%rdx
  sub    %ebx,%ecx
  add    %rax,%r12
  mov    %r13,%rax
  add    $0x1,%ebx
  shl    %cl,%rax
  test   %rax,%rdx
  je     L73
  not    %rax
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %ebp,%edi
  and    %rax,%rdx
  call   <fun@plt>
  mov    (%rsp),%rdx
  add    %rax,%r12
  cmp    %r14d,%r15d
  jl     L27
L31:
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %ebp,%ecx
  call   <fun@plt>
  lea    D12(%rip),%rdi
  lea    (%rax,%r12,1),%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  xor    %r12d,%r12d
  jmp    L31
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string

tool: D6: %lld

tool: D12: %lld


assistant: ```c
int main(void) {
  long long n, pos, res = 0;
  int i, j, L = 0;
  scanf("%lld", &n);
  for (pos = 1; pos <= n; pos <<= 1)
    L++;
  for (i = 1; i < L; i++) {
    res += fun(i, 1, n, L);
    pos = 1LL << (L - 1 - i);
    if (n & pos)
      res += fun(L, i + 1, n & ~pos, L);
  }
  res += fun(L, L, n, L);
  printf("%lld\n", res);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<SHT1x_CalcDewpoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  movss  D49(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D2(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x18(%rbp),%xmm0
  jbe    L7
  movss  D33(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D14(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
L7:
  movss  -0x14(%rbp),%xmm0
  movss  D7(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <log@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  -0x18(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  -0x18(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x8(%rbp),%xmm0
  addss  -0x4(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  subss  -0x8(%rbp),%xmm1
  subss  -0x4(%rbp),%xmm1
  divss  %xmm1,%xmm0
  mulss  -0x10(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D49
type_infered: f32
name: parse_data
arguments: data_tag: D2
type_infered: f32
name: parse_data
arguments: data_tag: D33
type_infered: f32
name: parse_data
arguments: data_tag: D14
type_infered: f32
name: parse_data
arguments: data_tag: D7
type_infered: f32

tool: D49: 243.12

tool: D2: 17.62

tool: D33: 272.62

tool: D14: 22.46

tool: D7: 100

assistant: ```c
void SHT1x_CalcDewpoint(float fRH, float fTemp, float *fDP) {
  float Tn = 243.12;
  float m = 17.62;
  if (fTemp < 0) {
    Tn = 272.62;
    m = 22.46;
  }
  float lnRH = log(fRH / 100);
  float mTTnT = (m * fTemp) / (Tn + fTemp);
  *fDP = Tn * ((lnRH + mTTnT) / (m - lnRH - mTTnT));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SHT1x_CalcDewpoint>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movaps %xmm1,%xmm4
  movss  %xmm1,0xc(%rsp)
  mov    %rdi,%rbp
  pxor   %xmm1,%xmm1
  comiss %xmm4,%xmm1
  ja     L2
  mov    D35(%rip),%ebx
  mov    D42(%rip),%r12d
L19:
  divss  D14(%rip),%xmm0
  call   <log@plt>
  movaps %xmm0,%xmm3
  movd   %ebx,%xmm2
  movss  0xc(%rsp),%xmm5
  mulss  %xmm5,%xmm2
  movd   %r12d,%xmm1
  addss  %xmm5,%xmm1
  divss  %xmm1,%xmm2
  movaps %xmm0,%xmm1
  addss  %xmm2,%xmm1
  movd   %ebx,%xmm0
  subss  %xmm3,%xmm0
  subss  %xmm2,%xmm0
  divss  %xmm0,%xmm1
  movd   %r12d,%xmm6
  mulss  %xmm6,%xmm1
  movss  %xmm1,0x0(%rbp)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    D22(%rip),%ebx
  mov    D18(%rip),%r12d
  jmp    L19
```

tool_calls: name: read_data
arguments: data_label: D35
type_guessed: f32
name: read_data
arguments: data_label: D42
type_guessed: f32
name: read_data
arguments: data_label: D14
type_guessed: f32
name: read_data
arguments: data_label: D22
type_guessed: f32
name: read_data
arguments: data_label: D18
type_guessed: f32

tool: D35: 17.62

tool: D42: 243.12

tool: D14: 100

tool: D22: 22.46

tool: D18: 272.62

assistant: ```c
void SHT1x_CalcDewpoint(float fRH, float fTemp, float *fDP) {
  float Tn = 243.12;
  float m = 17.62;
  if (fTemp < 0) {
    Tn = 272.62;
    m = 22.46;
  }
  float lnRH = log(fRH / 100);
  float mTTnT = (m * fTemp) / (Tn + fTemp);
  *fDP = Tn * ((lnRH + mTTnT) / (m - lnRH - mTTnT));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SHT1x_CalcDewpoint>:
  endbr64
  push   %rbx
  pxor   %xmm2,%xmm2
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  comiss %xmm1,%xmm2
  ja     L9
  movss  D16(%rip),%xmm2
  movss  D18(%rip),%xmm5
L15:
  movss  %xmm1,0xc(%rsp)
  divss  D45(%rip),%xmm0
  movss  %xmm2,0x8(%rsp)
  movss  %xmm5,0x4(%rsp)
  call   <log@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  movss  0x4(%rsp),%xmm5
  movaps %xmm0,%xmm4
  movaps %xmm2,%xmm3
  subss  %xmm4,%xmm2
  mulss  %xmm1,%xmm3
  addss  %xmm5,%xmm1
  divss  %xmm1,%xmm3
  addss  %xmm3,%xmm0
  subss  %xmm3,%xmm2
  divss  %xmm2,%xmm0
  mulss  %xmm5,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  movss  D48(%rip),%xmm2
  movss  D5(%rip),%xmm5
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_guessed: f32
name: disassemble_data
arguments: data_tag: D18
type_guessed: f32
name: disassemble_data
arguments: data_tag: D45
type_guessed: f32
name: disassemble_data
arguments: data_tag: D48
type_guessed: f32
name: disassemble_data
arguments: data_tag: D5
type_guessed: f32

tool: D16: 17.62

tool: D18: 243.12

tool: D45: 100

tool: D48: 22.46

tool: D5: 272.62

assistant: ```c
void SHT1x_CalcDewpoint(float fRH, float fTemp, float *fDP) {
  float Tn = 243.12;
  float m = 17.62;
  if (fTemp < 0) {
    Tn = 272.62;
    m = 22.46;
  }
  float lnRH = log(fRH / 100);
  float mTTnT = (m * fTemp) / (Tn + fTemp);
  *fDP = Tn * ((lnRH + mTTnT) / (m - lnRH - mTTnT));
}
```