ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x20(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  mov    $0x0,%edx
  mov    $0x0,%eax
  jmp    L55
L5:
  add    $0x1,%edx
  mov    %edi,%r9d
  mov    %r8d,%ecx
L37:
  mov    %ecx,(%rsi)
  add    $0x1,%edi
  add    $0x4,%rsi
  cmp    $0x2,%eax
  jg     L30
  cmp    $0x2,%edx
  jg     L30
L55:
  movslq %eax,%rcx
  mov    0x8(%rsp,%rcx,4),%ecx
  movslq %edx,%r8
  mov    0x14(%rsp,%r8,4),%r8d
  cmp    %r8d,%ecx
  jge    L5
  add    $0x1,%eax
  mov    %edi,%r9d
  jmp    L37
L30:
  cmp    $0x2,%eax
  jg     L6
  cltq
  movslq %r9d,%r9
  sub    %rax,%r9
  lea    0x20(%rsp,%r9,4),%rcx
L85:
  mov    0x8(%rsp,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    $0x2,%eax
  jle    L85
L45:
  lea    0x34(%rsp),%rbp
  lea    D7(%rip),%r12
L119:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x4,%rbp
  cmp    %rbx,%rbp
  jne    L119
  mov    0x20(%rsp),%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  cmp    $0x2,%edx
  jg     L45
  movslq %edx,%rdx
  movslq %r9d,%r9
  sub    %rdx,%r9
  lea    0x20(%rsp,%r9,4),%rcx
L21:
  mov    0x14(%rsp,%rdx,4),%eax
  mov    %eax,(%rcx,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x2,%edx
  jle    L21
  jmp    L45
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D26
type_infered: string

tool: D10: %d %d %d

tool: D7: %d 

tool: D26: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int x[3];
  int y[3];
  int answer[6];
  int i = 0;
  int j = 0;
  int k = 0;
  scanf("%d %d %d", x, (x + 1), (x + 2));
  scanf("%d %d %d", y, (y + 1), (y + 2));
  while (i < 3 && j < 3) {
    if (x[i] < y[j]) {
      answer[k] = x[i];
      i++;
      k++;
    } else {
      answer[k] = y[j];
      j++;
      k++;
    }
  }
  for (; i < 3; i++) {
    answer[k] = x[i];
    k++;
  }
  for (; j < 3; j++) {
    answer[k] = y[j];
    k++;
  }
  for (i = 5; i > 0; i--)
    printf("%d ", answer[i]);
  printf("%d\n", answer[0]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
unsigned int sleep(unsigned int secs) {
  struct timespec t;
  t.tv_sec = secs;
  t.tv_nsec = 0;
  nanosleep(&t, &t);
  return secs - t.tv_sec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sleep>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rdi
  mov    %rdi,%rsi
  call   <nanosleep@plt>
  mov    %ebx,%eax
  sub    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int sleep(unsigned int secs) {
  struct timespec t;
  t.tv_sec = secs;
  t.tv_nsec = 0;
  nanosleep(&t, &t);
  return secs - t.tv_sec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sleep>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  movq   $0x0,0x8(%rsp)
  mov    %rdi,%rsi
  call   <nanosleep@plt>
  mov    %ebx,%eax
  sub    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int sleep(unsigned int secs) {
  struct timespec t;
  t.tv_sec = secs;
  t.tv_nsec = 0;
  nanosleep(&t, &t);
  return secs - t.tv_sec;
}
```
user: What is the c source code of the assembly code below?

```asm
<sleep>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  movq   $0x0,0x8(%rsp)
  mov    %rdi,%rsi
  call   <nanosleep@plt>
  mov    %ebx,%eax
  sub    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int sleep(unsigned int secs) {
  struct timespec t;
  t.tv_sec = secs;
  t.tv_nsec = 0;
  nanosleep(&t, &t);
  return secs - t.tv_sec;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ReadBase16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L30
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L26
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  jmp    L21
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x37,%eax
L21:
  mov    -0x1c(%rbp),%edx
  shl    $0x2,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  addq   $0x1,-0x18(%rbp)
L30:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L19
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ReadBase16(char *c, int num_chars) {
  uint32_t val = 0;
  while (num_chars--) {
    val += (*c <= '9' ? *c - '0' : *c - 'A' + 10) << (num_chars * 4);
    c++;
  }
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ReadBase16>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L46
  shl    $0x2,%ecx
  mov    $0x0,%edx
  jmp    L16
L14:
  movsbl %al,%eax
  sub    $0x37,%eax
L29:
  shl    %cl,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  sub    $0x4,%ecx
  cmp    $0xfffffffc,%ecx
  je     L21
L16:
  movzbl (%rdi),%eax
  cmp    $0x39,%al
  jg     L14
  movsbl %al,%eax
  sub    $0x30,%eax
  jmp    L29
L46:
  mov    $0x0,%edx
L21:
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t ReadBase16(char *c, int num_chars) {
  uint32_t val = 0;
  while (num_chars--) {
    val += (*c <= '9' ? *c - '0' : *c - 'A' + 10) << (num_chars * 4);
    c++;
  }
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ReadBase16>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L3
  shl    $0x2,%ecx
  xor    %r8d,%r8d
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L44:
  sub    $0x30,%eax
L15:
  shl    %cl,%eax
  sub    $0x4,%ecx
  add    $0x1,%rdi
  add    %eax,%r8d
  cmp    $0xfffffffc,%ecx
  je     L30
L42:
  movsbl (%rdi),%eax
  cmp    $0x39,%al
  jle    L44
  sub    $0x37,%eax
  movsbl %al,%eax
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
L30:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t ReadBase16(char *c, int num_chars) {
  uint32_t val = 0;
  while (num_chars--) {
    val += (*c <= '9' ? *c - '0' : *c - 'A' + 10) << (num_chars * 4);
    c++;
  }
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<ReadBase16>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L35
  shl    $0x2,%ecx
  xor    %r8d,%r8d
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L12:
  sub    $0x30,%eax
L29:
  shl    %cl,%eax
  sub    $0x4,%ecx
  add    $0x1,%rdi
  add    %eax,%r8d
  cmp    $0xfffffffc,%ecx
  je     L18
L40:
  movsbl (%rdi),%eax
  cmp    $0x39,%al
  jle    L12
  sub    $0x37,%eax
  movsbl %al,%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L35:
  xor    %r8d,%r8d
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t ReadBase16(char *c, int num_chars) {
  uint32_t val = 0;
  while (num_chars--) {
    val += (*c <= '9' ? *c - '0' : *c - 'A' + 10) << (num_chars * 4);
    c++;
  }
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((noreturn)) die(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  fflush(stdout);
  fflush(stderr);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<die>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D18(%rip),%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    (%r12),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    (%r12),%edi
  call   <fflush@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void __attribute__((noreturn)) die(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  fflush(stdout);
  fflush(stderr);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D6(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void __attribute__((noreturn)) die(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  fflush(stdout);
  fflush(stderr);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D14(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void __attribute__((noreturn)) die(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  fflush(stdout);
  fflush(stderr);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<decode_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L98
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  je     L134
  nop
  jmp    L26
L86:
  nop
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L126
L134:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L86
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L86
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L86
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L86
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L144
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L144
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
  jmp    L116
L144:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  sub    $0x37,%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
L116:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L17
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L17
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  jmp    L12
L17:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  sub    $0x37,%eax
L12:
  add    %ebx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x2,-0x18(%rbp)
L126:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L98:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void decode_string(char *s) {
  char *t = s;
  char *h = s;
  for (; *h; h++, t++) {
    if (*h != '%') {
    copychar:
      *t = *h;
    } else {
      if (!*(h + 1) || !*(h + 2) || !(isxdigit(*(h + 1)) && isxdigit(*(h + 2))))
        goto copychar;
      *t = ((((*(h + 1)) >= '0' && (*(h + 1)) <= '9') ? ((*(h + 1)) - '0') : (toupper(*(h + 1)) - 'A' + 10)) << 4) + (((*(h + 2)) >= '0' && (*(h + 2)) <= '9') ? ((*(h + 2)) - '0') : (toupper(*(h + 2)) - 'A' + 10));
      h += 2;
    }
  }
  *t = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decode_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
  mov    %rdi,%rbx
  jmp    L30
L45:
  movzbl (%rbx),%edx
  mov    %rbx,%rax
L6:
  mov    %dl,0x0(%rbp)
  lea    0x1(%rax),%rbx
  add    $0x1,%rbp
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L20
L30:
  cmp    $0x25,%al
  jne    L45
  movzbl 0x1(%rbx),%edi
  test   %dil,%dil
  je     L45
  cmpb   $0x0,0x2(%rbx)
  je     L45
  movsbl %dil,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L45
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L45
  movzbl 0x1(%rbx),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L105
  shl    $0x4,%edx
  mov    %edx,%r12d
L26:
  movzbl 0x2(%rbx),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L59
L36:
  lea    (%r12,%rax,1),%edx
  lea    0x2(%rbx),%rax
  jmp    L6
L105:
  movsbl %al,%edi
  call   <toupper@plt>
  lea    -0x37(%rax),%edx
  shl    $0x4,%edx
  mov    %edx,%r12d
  jmp    L26
L59:
  movsbl %dl,%edi
  call   <toupper@plt>
  sub    $0x37,%eax
  jmp    L36
L20:
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decode_string(char *s) {
  char *t = s;
  char *h = s;
  for (; *h; h++, t++) {
    if (*h != '%') {
    copychar:
      *t = *h;
    } else {
      if (!*(h + 1) || !*(h + 2) || !(isxdigit(*(h + 1)) && isxdigit(*(h + 2))))
        goto copychar;
      *t = ((((*(h + 1)) >= '0' && (*(h + 1)) <= '9') ? ((*(h + 1)) - '0') : (toupper(*(h + 1)) - 'A' + 10)) << 4) + (((*(h + 2)) >= '0' && (*(h + 2)) <= '9') ? ((*(h + 2)) - '0') : (toupper(*(h + 2)) - 'A' + 10));
      h += 2;
    }
  }
  *t = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decode_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  mov    %rdi,%rbx
  test   %al,%al
  jne    L40
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl (%rbx),%edx
  mov    %rbx,%rax
L32:
  mov    %dl,0x0(%rbp)
  lea    0x1(%rax),%rbx
  movzbl 0x1(%rax),%eax
  add    $0x1,%rbp
  test   %al,%al
  je     L30
L40:
  cmp    $0x25,%al
  jne    L18
  movsbl 0x1(%rbx),%edi
  test   %dil,%dil
  je     L18
  cmpb   $0x0,0x2(%rbx)
  je     L18
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L18
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L18
  movzbl 0x1(%rbx),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L50
L8:
  shl    $0x4,%edx
  mov    %edx,%r12d
  movzbl 0x2(%rbx),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L108
L11:
  lea    (%r12,%rax,1),%edx
  lea    0x2(%rbx),%rax
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L30:
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L108:
  movsbl %dl,%edi
  call   <toupper@plt>
  sub    $0x37,%eax
  jmp    L11
  nopl   (%rax)
L50:
  movsbl %al,%edi
  call   <toupper@plt>
  lea    -0x37(%rax),%edx
  jmp    L8
```

assistant: ```c
void decode_string(char *s) {
  char *t = s;
  char *h = s;
  for (; *h; h++, t++) {
    if (*h != '%') {
    copychar:
      *t = *h;
    } else {
      if (!*(h + 1) || !*(h + 2) || !(isxdigit(*(h + 1)) && isxdigit(*(h + 2))))
        goto copychar;
      *t = ((((*(h + 1)) >= '0' && (*(h + 1)) <= '9') ? ((*(h + 1)) - '0') : (toupper(*(h + 1)) - 'A' + 10)) << 4) + (((*(h + 2)) >= '0' && (*(h + 2)) <= '9') ? ((*(h + 2)) - '0') : (toupper(*(h + 2)) - 'A' + 10));
      h += 2;
    }
  }
  *t = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<decode_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L105
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdx
L79:
  mov    %al,(%r12)
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%rbp
  add    $0x1,%r12
  test   %al,%al
  je     L3
L105:
  cmp    $0x25,%al
  jne    L14
  movsbl 0x1(%rbp),%edi
  test   %dil,%dil
  je     L14
  cmpb   $0x0,0x2(%rbp)
  je     L14
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L129
L113:
  movzbl 0x0(%rbp),%eax
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L3:
  movb   $0x0,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L129:
  movsbl 0x2(%rbp),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L113
  movzbl 0x1(%rbp),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L31
L27:
  movzbl 0x2(%rbp),%edx
  shl    $0x4,%eax
  mov    %eax,%ebx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L17
L76:
  add    %ebx,%eax
  lea    0x2(%rbp),%rdx
  jmp    L79
  nopl   0x0(%rax)
L17:
  movsbl %dl,%edi
  call   <toupper@plt>
  sub    $0x37,%eax
  jmp    L76
  nopl   (%rax)
L31:
  movsbl %dl,%edi
  call   <toupper@plt>
  sub    $0x37,%eax
  jmp    L27
```

assistant: ```c
void decode_string(char *s) {
  char *t = s;
  char *h = s;
  for (; *h; h++, t++) {
    if (*h != '%') {
    copychar:
      *t = *h;
    } else {
      if (!*(h + 1) || !*(h + 2) || !(isxdigit(*(h + 1)) && isxdigit(*(h + 2))))
        goto copychar;
      *t = ((((*(h + 1)) >= '0' && (*(h + 1)) <= '9') ? ((*(h + 1)) - '0') : (toupper(*(h + 1)) - 'A' + 10)) << 4) + (((*(h + 2)) >= '0' && (*(h + 2)) <= '9') ? ((*(h + 2)) - '0') : (toupper(*(h + 2)) - 'A' + 10));
      h += 2;
    }
  }
  *t = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x20(%rbp),%eax
  sub    $0x2,%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L30
L25:
  movl   $0x0,-0x18(%rbp)
  jmp    L6
L42:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L42
  mov    $0x2a,%edi
  call   <putchar@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L80
L69:
  mov    $0x23,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L80:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L69
  cmpl   $0x0,-0x1c(%rbp)
  jle    L96
  mov    $0x2a,%edi
  call   <putchar@plt>
L96:
  subl   $0x1,-0x10(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x1c(%rbp)
L30:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L25
  movl   $0x0,-0xc(%rbp)
  jmp    L97
L86:
  mov    $0x2a,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L97:
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L86
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D15
type_guessed: string

tool: D14: %d

tool: D15: %d 


assistant: ```c
int main() {
  int i, k, t, a, space;
  scanf("%d", &a);
  printf("%d \n", (a - 2) * (a - 2));
  space = a - 1;
  for (i = 0; i < a - 1; i++) {
    for (k = 0; k < space; k++) {
      printf(" ");
    }
    printf("*");
    for (t = 1; t < i * 2; t++) {
      printf("#");
    }
    if (i > 0)
      printf("*");
    space--;
    printf("\n");
  }
  for (int z = 0; z < a * 2 - 1; z++)
    printf("*");
  printf("\n");
}
```