user: 请从给定的汇编指令推导出C源代码:

```asm
<editDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%r14d
  mov    %eax,-0x4c(%rbp)
  call   <strlen@plt>
  mov    %rsp,%rdi
  lea    0x1(%rax),%ecx
  mov    %eax,%ebx
  lea    0x1(%r14),%eax
  movslq %ecx,%rdx
  cltq
  imul   %rdx,%rax
  lea    0x0(,%rdx,4),%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rdi,%rsp
  je     L11
L118:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L118
L11:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L27
L88:
  mov    -0x4c(%rbp),%edx
  shr    $0x2,%rsi
  mov    %rsp,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  test   %edx,%edx
  js     L26
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L121:
  movslq %eax,%rdx
  imul   -0x60(%rbp),%rdx
  mov    -0x58(%rbp),%rdi
  mov    %eax,(%rdi,%rdx,4)
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %edx,-0x4c(%rbp)
  jne    L121
  test   %ebx,%ebx
  js     L14
L12:
  cmp    $0x2,%ebx
  jle    L201
  mov    %ecx,%edx
  mov    -0x58(%rbp),%rdi
  movdqa D16(%rip),%xmm0
  shr    $0x2,%edx
  movdqa D9(%rip),%xmm2
  sub    $0x1,%edx
  mov    %rdi,%rax
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  xchg   %ax,%ax
L117:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L117
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  and    $0x3,%ecx
  je     L14
L35:
  mov    -0x58(%rbp),%rcx
  movslq %eax,%rdx
  lea    (%rcx,%rdx,4),%rdx
  lea    0x1(%rax),%ecx
  mov    %eax,(%rdx)
  cmp    %ecx,%ebx
  jl     L14
  add    $0x2,%eax
  mov    %ecx,0x4(%rdx)
  cmp    %ebx,%eax
  jg     L14
  mov    %eax,0x8(%rdx)
L14:
  mov    -0x4c(%rbp),%eax
  test   %eax,%eax
  jle    L87
  test   %ebx,%ebx
  jle    L87
  mov    -0x60(%rbp),%rax
  mov    -0x58(%rbp),%r14
  mov    %r12,-0x48(%rbp)
  shl    $0x2,%rax
  mov    %r14,%r13
  mov    %rax,-0x68(%rbp)
  add    %rax,%r13
  mov    $0x1,%eax
  sub    %r12d,%eax
  mov    %eax,-0x50(%rbp)
L42:
  mov    $0x1,%r12d
L15:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
L228:
  mov    -0x4(%r14,%r12,4),%edx
  cmp    -0x1(%r15,%r12,1),%al
  je     L68
  mov    (%r14,%r12,4),%esi
  mov    -0x4(%r13,%r12,4),%edi
  call   <min@plt>
  add    $0x1,%eax
  mov    %eax,0x0(%r13,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,%ebx
  jge    L15
L167:
  mov    -0x68(%rbp),%rax
  addq   $0x1,-0x48(%rbp)
  mov    -0x48(%rbp),%rcx
  add    %rax,%r13
  add    %rax,%r14
  mov    -0x50(%rbp),%eax
  add    %ecx,%eax
  cmp    %eax,-0x4c(%rbp)
  jge    L42
L87:
  movslq -0x4c(%rbp),%r13
  imul   -0x60(%rbp),%r13
  movslq %ebx,%rax
  mov    -0x58(%rbp),%rcx
  add    %r13,%rax
  mov    (%rcx,%rax,4),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L68:
  mov    %edx,0x0(%r13,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,%ebx
  jge    L228
  jmp    L167
L27:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L88
L26:
  test   %ebx,%ebx
  jns    L12
  jmp    L87
L201:
  xor    %eax,%eax
  jmp    L35
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
datatype: byte[16]
name: retrieve_data
arguments: tag: D9
datatype: byte[16]

tool: {"D16": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D9": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int editDistance(char a[], char b[]) {
  int aLength = strlen(a), bLength = strlen(b);
  int dp[aLength + 1][bLength + 1];
  int i, j;
  for (i = 0; i <= aLength; ++i) {
    dp[i][0] = i;
  }
  for (j = 0; j <= bLength; ++j) {
    dp[0][j] = j;
  }
  for (i = 1; i <= aLength; ++i) {
    for (j = 1; j <= bLength; ++j) {
      if (a[i - 1] == b[j - 1]) {
        dp[i][j] = dp[i - 1][j - 1];
      } else {
        dp[i][j] = 1 + min(dp[i][j - 1], dp[i - 1][j], dp[i - 1][j - 1]);
      }
    }
  }
  return dp[aLength][bLength];
}
```