ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x368,%rsp
  mov    $0x64,%ecx
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x358(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rdx
  movaps %xmm0,(%rsp)
  mov    %rsp,%r8
  mov    %rdx,%rdi
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  rep stos %rax,%es:(%rdi)
  nopw   0x0(%rax,%rax,1)
L93:
  mov    %eax,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L93
  mov    %rdx,%rdi
  mov    %rdx,%rsi
  mov    $0x14,%ecx
  nopl   0x0(%rax)
L98:
  lea    -0x14(%rcx),%eax
  mov    %rsi,%rdx
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L16
  add    $0x50,%rsi
  lea    0xa(%rax),%ecx
  cmp    $0x6e,%eax
  jne    L98
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L81:
  cmp    %eax,(%r8,%rax,4)
  jne    L112
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L81
  xor    %esi,%esi
  mov    $0x14,%ecx
L118:
  mov    %esi,%eax
  mov    %rdi,%rdx
  jmp    L8
  xchg   %ax,%ax
L41:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%ecx
  je     L111
L8:
  cmp    %eax,(%rdx)
  je     L41
  mov    $0x2,%eax
L21:
  mov    0x358(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L115
  add    $0x368,%rsp
  ret
L111:
  add    $0xa,%ecx
  add    $0xa,%esi
  add    $0x50,%rdi
  cmp    $0x78,%ecx
  jne    L118
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L21
L112:
  mov    $0x1,%eax
  jmp    L21
L115:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: PASS


assistant: ```c
int main() {
  int array_1d[10];
  int array_2d[10][20];
  int i, j;
  for (i = 0; i < 10; i++) {
    array_1d[i] = 0;
    for (j = 0; j < 20; j++) {
      array_2d[i][j] = 0;
    }
  }
#pragma acc data copyin(array_1d, array_2d)
  {
#pragma acc parallel loop
    for (i = 0; i < 10; i++)
      array_1d[i] = i;
#pragma acc update host(array_1d) async
#pragma acc parallel loop collapse(2)
    for (i = 0; i < 10; i++) {
      for (j = 0; j < 20; j++) {
        array_2d[i][j] = i * 10 + j;
      }
    }
#pragma acc update host(array_2d) async(4)
#pragma acc wait
  }
  for (i = 0; i < 10; i++) {
    if (array_1d[i] != i)
      return 1;
  }
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 20; j++) {
      if (array_2d[i][j] != i * 10 + j)
        return 2;
    }
  }
  printf("PASS\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stm_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L17:
  nop
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x31,-0x4(%rbp)
  jle    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stm_wait(void) {
  int i;
  for (i = 0; i < 50; i++) {
    asm("nop" ::: "memory");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<stm_wait>:
  endbr64
  mov    $0x32,%eax
L6:
  nop
  sub    $0x1,%eax
  jne    L6
  ret
```

assistant: ```c
void stm_wait(void) {
  int i;
  for (i = 0; i < 50; i++) {
    asm("nop" ::: "memory");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stm_wait>:
  endbr64
  mov    $0x32,%eax
  nopl   0x0(%rax)
L9:
  nop
  sub    $0x1,%eax
  jne    L9
  ret
```

assistant: ```c
void stm_wait(void) {
  int i;
  for (i = 0; i < 50; i++) {
    asm("nop" ::: "memory");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stm_wait>:
  endbr64
  mov    $0x32,%eax
  nopl   0x0(%rax)
L4:
  nop
  sub    $0x1,%eax
  jne    L4
  ret
```

assistant: ```c
void stm_wait(void) {
  int i;
  for (i = 0; i < 50; i++) {
    asm("nop" ::: "memory");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lookup_bool_variable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_variable@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L4
L17:
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: nil

assistant: ```c
int lookup_bool_variable(char *var) {
  char *p;
  if ((p = get_variable(var)) != NULL)
    return strcmp(p, "nil") != 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lookup_bool_variable>:
  endbr64
  sub    $0x8,%rsp
  call   <get_variable@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  jne    L12
L8:
  add    $0x8,%rsp
  ret
L12:
  lea    D5(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L8
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D5: nil

assistant: ```c
int lookup_bool_variable(char *var) {
  char *p;
  if ((p = get_variable(var)) != NULL)
    return strcmp(p, "nil") != 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lookup_bool_variable>:
  endbr64
  sub    $0x8,%rsp
  call   <get_variable@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L7
  lea    D4(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L7:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: nil

assistant: ```c
int lookup_bool_variable(char *var) {
  char *p;
  if ((p = get_variable(var)) != NULL)
    return strcmp(p, "nil") != 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lookup_bool_variable>:
  endbr64
  sub    $0x8,%rsp
  call   <get_variable@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  lea    D0(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L6:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D0: nil

assistant: ```c
int lookup_bool_variable(char *var) {
  char *p;
  if ((p = get_variable(var)) != NULL)
    return strcmp(p, "nil") != 0;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_protocol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L26
  mov    $0x1,%eax
  jmp    L3
L26:
  mov    -0x8(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L21
  mov    $0x2,%eax
  jmp    L3
L21:
  mov    $0x0,%eax
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string
name: read_data
arguments: data_tag: D19
type: string

tool: D8: tcp

tool: D19: udp

assistant: ```c
int parse_protocol(char *line) {
  if (!strcmp(line, "tcp"))
    return 1;
  if (!strcmp(line, "udp"))
    return 2;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_protocol>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D3(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L0
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L0:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string
name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D3: tcp

tool: D8: udp

assistant: ```c
int parse_protocol(char *line) {
  if (!strcmp(line, "tcp"))
    return 1;
  if (!strcmp(line, "udp"))
    return 2;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parse_protocol>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L0
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L0:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D0: tcp

tool: D9: udp

assistant: ```c
int parse_protocol(char *line) {
  if (!strcmp(line, "tcp"))
    return 1;
  if (!strcmp(line, "udp"))
    return 2;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_protocol>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L6
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L6:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string
name: parse_data
arguments: label: D17
type_guessed: string

tool: D3: tcp

tool: D17: udp

assistant: ```c
int parse_protocol(char *line) {
  if (!strcmp(line, "tcp"))
    return 1;
  if (!strcmp(line, "udp"))
    return 2;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i386_cpuid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <__get_cpuid@plt>
  test   %eax,%eax
  jne    L7
  mov    $0x0,%eax
  jmp    L28
L7:
  mov    -0xc(%rbp),%eax
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  unsigned int eax, ebx, ecx, edx;
  if (!__get_cpuid(1, &eax, &ebx, &ecx, &edx))
    return 0;
  return edx;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<i386_cpuid>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    $0x1,%edi
  call   <__get_cpuid@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmovne 0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  unsigned int eax, ebx, ecx, edx;
  if (!__get_cpuid(1, &eax, &ebx, &ecx, &edx))
    return 0;
  return edx;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<i386_cpuid>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <__get_cpuid@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmovne 0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  unsigned int eax, ebx, ecx, edx;
  if (!__get_cpuid(1, &eax, &ebx, &ecx, &edx))
    return 0;
  return edx;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<i386_cpuid>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <__get_cpuid@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmovne 0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int __attribute__((no)) i386_cpuid(void) {
  unsigned int eax, ebx, ecx, edx;
  if (!__get_cpuid(1, &eax, &ebx, &ecx, &edx))
    return 0;
  return edx;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gwxrevflag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <getenv@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L22
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L8
L10:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L22:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D7: XPLOT11_BACKGROUND

tool: D5: white

assistant: ```c
void gwxrevflag(revflag) int *revflag;
{
  char *bufp, *tmp;
  *revflag = 1;
  bufp = getenv("XPLOT11_BACKGROUND");
  if (bufp) {
    for (tmp = bufp; *tmp; tmp++)
      *tmp = tolower((int)*tmp);
    *revflag = (strcmp(bufp, "white") != 0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gwxrevflag>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movl   $0x1,(%rdi)
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <getenv@plt>
  test   %eax,%eax
  je     L9
  movslq %eax,%r12
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L0
  mov    %r12,%rbx
L21:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L21
L0:
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,0x0(%rbp)
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string
name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D8: XPLOT11_BACKGROUND

tool: D5: white

assistant: ```c
void gwxrevflag(revflag) int *revflag;
{
  char *bufp, *tmp;
  *revflag = 1;
  bufp = getenv("XPLOT11_BACKGROUND");
  if (bufp) {
    for (tmp = bufp; *tmp; tmp++)
      *tmp = tolower((int)*tmp);
    *revflag = (strcmp(bufp, "white") != 0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gwxrevflag>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movl   $0x1,(%rdi)
  lea    D12(%rip),%rdi
  call   <getenv@plt>
  test   %eax,%eax
  je     L20
  movslq %eax,%r12
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L4
  mov    %r12,%rbx
  nopl   0x0(%rax,%rax,1)
L21:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L21
L4:
  lea    D6(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,0x0(%rbp)
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string

tool: D12: XPLOT11_BACKGROUND

tool: D6: white

assistant: ```c
void gwxrevflag(revflag) int *revflag;
{
  char *bufp, *tmp;
  *revflag = 1;
  bufp = getenv("XPLOT11_BACKGROUND");
  if (bufp) {
    for (tmp = bufp; *tmp; tmp++)
      *tmp = tolower((int)*tmp);
    *revflag = (strcmp(bufp, "white") != 0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gwxrevflag>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movl   $0x1,(%rdi)
  lea    D10(%rip),%rdi
  call   <getenv@plt>
  test   %eax,%eax
  je     L24
  movslq %eax,%r12
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L12
  mov    %r12,%rbx
  nopl   0x0(%rax,%rax,1)
L25:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L25
L12:
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,0x0(%rbp)
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D10
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string

tool: D10: XPLOT11_BACKGROUND

tool: D14: white

assistant: ```c
void gwxrevflag(revflag) int *revflag;
{
  char *bufp, *tmp;
  *revflag = 1;
  bufp = getenv("XPLOT11_BACKGROUND");
  if (bufp) {
    for (tmp = bufp; *tmp; tmp++)
      *tmp = tolower((int)*tmp);
    *revflag = (strcmp(bufp, "white") != 0);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<acceptance_ratio>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %rcx,%r15
  mov    %r8,%r14
  mov    %r9,%r13
  mov    %edi,%eax
  imul   %edx,%eax
  add    %esi,%eax
  cltq
  movsd  (%rcx,%rax,8),%xmm7
  movsd  %xmm7,0x10(%rsp)
  movsd  (%r8,%rax,8),%xmm3
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm0,0x8(%rsp)
  addsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  call   <log@plt>
  movsd  %xmm0,0x20(%rsp)
  movsd  0x18(%rsp),%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movsd  0x20(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x28(%rsp)
  movslq %ebp,%rax
  movsd  0x0(%r13,%rax,8),%xmm2
  movsd  %xmm2,0x10(%rsp)
  mov    0x70(%rsp),%rdx
  movsd  (%rdx,%rax,8),%xmm5
  movsd  %xmm5,0x18(%rsp)
  movapd %xmm5,%xmm0
  call   <log@plt>
  movsd  %xmm0,0x20(%rsp)
  movsd  0x18(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movsd  0x20(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x10(%rsp)
  cmp    %ebx,%ebp
  je     L14
  mov    %r12d,%eax
  imul   %ebx,%eax
  add    %ebp,%eax
  cltq
  mov    (%r15,%rax,8),%r12
  mov    (%r14,%rax,8),%r14
  movq   %r14,%xmm0
  addsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movq   %xmm0,%rbp
  movq   %r14,%xmm0
  call   <log@plt>
  movq   %xmm0,%r14
  movslq %ebx,%rbx
  mov    0x0(%r13,%rbx,8),%r13
  mov    0x70(%rsp),%rax
  mov    (%rax,%rbx,8),%r15
  movq   %r15,%xmm0
  call   <log@plt>
  movq   %xmm0,%rbx
  movq   %r15,%xmm0
  addsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm2
  movq   %rbp,%xmm0
  movq   %r14,%xmm6
  subsd  %xmm6,%xmm0
  movq   %r12,%xmm7
  mulsd  %xmm7,%xmm0
  addsd  0x28(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  movq   %rbx,%xmm1
  subsd  %xmm2,%xmm1
  movq   %r13,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  call   <exp@plt>
L6:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  movsd  0x28(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  call   <exp@plt>
  jmp    L6
```

assistant: ```c
double acceptance_ratio(int i, int j, int n_states, double epsilon, const double *Z, const double *K, const double *N, const double *Q) {
  double term1, term2, term3, term4;
  term1 = Z[i * n_states + j] * (log(K[i * n_states + j] + epsilon) - log(K[i * n_states + j]));
  term3 = N[i] * (log(Q[i]) - log(Q[i] + (epsilon)));
  if (i == j)
    return exp(term1 + term3);
  term2 = Z[j * n_states + i] * (log(K[j * n_states + i] + epsilon) - log(K[j * n_states + i]));
  term4 = N[j] * (log(Q[j]) - log(Q[j] + (epsilon)));
  return exp(term1 + term2 + term3 + term4);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<acceptance_ratio>:
  endbr64
  mov    %edi,%eax
  push   %r15
  mov    %rcx,%r15
  imul   %edx,%eax
  push   %r14
  mov    %edi,%r14d
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  add    %r13d,%eax
  mov    %r9,%rbp
  push   %rbx
  cltq
  mov    %edx,%ebx
  sub    $0x48,%rsp
  movsd  (%r8,%rax,8),%xmm2
  movsd  (%rcx,%rax,8),%xmm4
  movsd  %xmm0,(%rsp)
  mov    0x80(%rsp),%r12
  addsd  %xmm2,%xmm0
  mov    %r8,0x20(%rsp)
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  call   <log@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm5
  movslq %r14d,%rax
  movsd  (%r12,%rax,8),%xmm2
  movsd  0x0(%rbp,%rax,8),%xmm6
  subsd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm6,0x8(%rsp)
  movsd  %xmm2,0x18(%rsp)
  mulsd  %xmm1,%xmm5
  movsd  %xmm5,0x28(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  (%rsp),%xmm7
  movsd  %xmm0,0x10(%rsp)
  addsd  %xmm2,%xmm7
  movapd %xmm7,%xmm0
  call   <log@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  cmp    %r13d,%r14d
  mov    0x20(%rsp),%r8
  subsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm2
  je     L0
  imul   %r13d,%ebx
  movsd  (%rsp),%xmm0
  movsd  %xmm2,0x38(%rsp)
  add    %r14d,%ebx
  movslq %ebx,%rbx
  movsd  (%r8,%rbx,8),%xmm3
  movsd  (%r15,%rbx,8),%xmm5
  addsd  %xmm3,%xmm0
  movsd  %xmm5,0x8(%rsp)
  movsd  %xmm3,0x10(%rsp)
  call   <log@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  %xmm0,0x30(%rsp)
  movapd %xmm3,%xmm0
  call   <log@plt>
  movsd  (%r12,%r13,8),%xmm3
  movsd  0x0(%rbp,%r13,8),%xmm7
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm3,%xmm0
  movsd  %xmm7,0x18(%rsp)
  movsd  %xmm3,0x20(%rsp)
  call   <log@plt>
  movsd  0x20(%rsp),%xmm3
  movq   %xmm0,%rbx
  movsd  (%rsp),%xmm0
  addsd  %xmm3,%xmm0
  call   <log@plt>
  movsd  0x30(%rsp),%xmm1
  subsd  0x10(%rsp),%xmm1
  mulsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm3
  movq   %rbx,%xmm0
  movsd  0x38(%rsp),%xmm2
  addsd  0x28(%rsp),%xmm1
  subsd  %xmm3,%xmm0
  mulsd  0x18(%rsp),%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
L6:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <exp@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  movsd  0x28(%rsp),%xmm0
  addsd  %xmm2,%xmm0
  jmp    L6
```

assistant: ```c
double acceptance_ratio(int i, int j, int n_states, double epsilon, const double *Z, const double *K, const double *N, const double *Q) {
  double term1, term2, term3, term4;
  term1 = Z[i * n_states + j] * (log(K[i * n_states + j] + epsilon) - log(K[i * n_states + j]));
  term3 = N[i] * (log(Q[i]) - log(Q[i] + (epsilon)));
  if (i == j)
    return exp(term1 + term3);
  term2 = Z[j * n_states + i] * (log(K[j * n_states + i] + epsilon) - log(K[j * n_states + i]));
  term4 = N[j] * (log(Q[j]) - log(Q[j] + (epsilon)));
  return exp(term1 + term2 + term3 + term4);
}
```