ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<BetterMaxSum>:
  endbr64
  test   %edi,%edi
  jle    L17
  push   %rbx
  mov    %edi,%r9d
  lea    0x1(%rdi),%ebx
  mov    $0x1,%r10d
  mov    $0xffffffff,%r8d
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r10d,%r11d
  mov    %r10,%rax
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L35:
  add    (%rsi,%rax,4),%edi
  cmp    %r8d,%edi
  jle    L25
  mov    %r11d,(%rdx)
  mov    %edi,%r8d
  mov    %eax,(%rcx)
L25:
  add    $0x1,%rax
  cmp    %eax,%r9d
  jge    L35
  add    $0x1,%r10
  cmp    %rbx,%r10
  jne    L29
  mov    %r8d,%eax
  pop    %rbx
  ret
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int BetterMaxSum(int size, int data[], int *besti, int *bestj) {
  int sum = -1;
  for (int i = 1; i <= size; ++i) {
    int thissum = 0;
    for (int j = i; j <= size; ++j) {
      thissum += data[j];
      if (thissum > sum) {
        sum = thissum;
        *besti = i, *bestj = j;
      }
    }
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BetterMaxSum>:
  endbr64
  test   %edi,%edi
  jle    L38
  push   %rbx
  mov    %edi,%r9d
  lea    0x1(%rdi),%ebx
  mov    $0x1,%r10d
  mov    $0xffffffff,%r8d
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r10d,%r11d
  mov    %r10,%rax
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L33:
  add    (%rsi,%rax,4),%edi
  cmp    %r8d,%edi
  jle    L0
  mov    %r11d,(%rdx)
  mov    %edi,%r8d
  mov    %eax,(%rcx)
L0:
  add    $0x1,%rax
  cmp    %eax,%r9d
  jge    L33
  add    $0x1,%r10
  cmp    %r10,%rbx
  jne    L29
  mov    %r8d,%eax
  pop    %rbx
  ret
L38:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int BetterMaxSum(int size, int data[], int *besti, int *bestj) {
  int sum = -1;
  for (int i = 1; i <= size; ++i) {
    int thissum = 0;
    for (int j = i; j <= size; ++j) {
      thissum += data[j];
      if (thissum > sum) {
        sum = thissum;
        *besti = i, *bestj = j;
      }
    }
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wcsrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <_DIAGASSERT@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L26:
  addq   $0x8,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
  jmp    L1
L45:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x20(%rbp)
  jne    L10
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__UNCONST@plt>
  jmp    L24
L10:
  subq   $0x8,-0x8(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L45
  mov    $0x0,%eax
L24:
  leave
  ret
```

assistant: ```c
wchar_t *wcsrchr(const wchar_t *s, wchar_t c) {
  const wchar_t *p;
  _DIAGASSERT(s != NULL);
  p = s;
  while (*p)
    p++;
  while (s <= p) {
    if (*p == c)
      return __UNCONST(p);
    p--;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wcsrchr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <_DIAGASSERT@plt>
  cmpq   $0x0,(%rbx)
  je     L34
  mov    %rbx,%rdi
L48:
  add    $0x8,%rdi
  cmpq   $0x0,(%rdi)
  jne    L48
  cmp    %rdi,%rbx
  ja     L60
L8:
  cmp    %rbp,(%rdi)
  je     L23
  sub    $0x8,%rdi
  cmp    %rdi,%rbx
  jbe    L8
  mov    $0x0,%eax
  jmp    L39
L34:
  mov    %rbx,%rdi
  jmp    L8
L23:
  call   <__UNCONST@plt>
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L60:
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
wchar_t *wcsrchr(const wchar_t *s, wchar_t c) {
  const wchar_t *p;
  _DIAGASSERT(s != NULL);
  p = s;
  while (*p)
    p++;
  while (s <= p) {
    if (*p == c)
      return __UNCONST(p);
    p--;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<wcsrchr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <_DIAGASSERT@plt>
  cmpq   $0x0,(%rbx)
  mov    %rbx,%rdi
  je     L16
  nopl   0x0(%rax)
L32:
  add    $0x8,%rdi
  cmpq   $0x0,(%rdi)
  jne    L32
L16:
  xor    %eax,%eax
  jmp    L48
  xchg   %ax,%ax
L14:
  mov    (%rdi),%rax
L48:
  cmp    %rax,%rbp
  je     L49
  sub    $0x8,%rdi
  cmp    %rdi,%rbx
  jbe    L14
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <__UNCONST@plt>
```

assistant: ```c
wchar_t *wcsrchr(const wchar_t *s, wchar_t c) {
  const wchar_t *p;
  _DIAGASSERT(s != NULL);
  p = s;
  while (*p)
    p++;
  while (s <= p) {
    if (*p == c)
      return __UNCONST(p);
    p--;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wcsrchr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <_DIAGASSERT@plt>
  cmpq   $0x0,(%rbx)
  mov    %rbx,%rdi
  je     L27
  nopl   0x0(%rax)
L1:
  add    $0x8,%rdi
  cmpq   $0x0,(%rdi)
  jne    L1
  nopw   0x0(%rax,%rax,1)
L27:
  cmp    %rbp,(%rdi)
  je     L2
  sub    $0x8,%rdi
  cmp    %rdi,%rbx
  jbe    L27
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <__UNCONST@plt>
```

assistant: ```c
wchar_t *wcsrchr(const wchar_t *s, wchar_t c) {
  const wchar_t *p;
  _DIAGASSERT(s != NULL);
  p = s;
  while (*p)
    p++;
  while (s <= p) {
    if (*p == c)
      return __UNCONST(p);
    p--;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L0:
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  cmpl   $0x2,-0xc(%rbp)
  jle    L0
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D18
type: string

tool: D19: sqrt

tool: D15: # c::cephes::%s


tool: D18: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "sqrt");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D23(%rip),%r13
  lea    D26(%rip),%r12
  lea    D27(%rip),%rbp
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L2
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D23
type_guessed: string
name: parse_data
arguments: tag: D26
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: string

tool: D23: sqrt

tool: D26: # c::cephes::%s


tool: D27: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "sqrt");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D12(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L0:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L0
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D21
type_infered: string

tool: D12: sqrt

tool: D1: # c::cephes::%s


tool: D21: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "sqrt");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D14(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L9
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D10
type_guessed: string

tool: D14: sqrt

tool: D13: # c::cephes::%s


tool: D10: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "sqrt");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_dos_header_and_stub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x300905a4d,%rax
  movabs $0xffff00000004,%rdx
  mov    %rax,-0x90(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    $0xb8,%eax
  mov    $0x40,%edx
  mov    %rax,-0x80(%rbp)
  mov    %rdx,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  mov    $0x0,%eax
  movabs $0x8000000000,%rdx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movabs $0xcd09b4000eba1f0e,%rax
  movabs $0x685421cd4c01b821,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x72676f7270207369,%rax
  movabs $0x6f6e6e6163206d61,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x6e75722065622074,%rax
  movabs $0x20534f44206e6920,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0xa0d0d2e65646f6d,%rax
  mov    $0x24,%edx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x98(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x80,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void write_dos_header_and_stub(FILE *file) {
  char buffer[128] = {0x4d, 0x5a, 0x90, 0x00, 0x03, 0x00, 0x00, 0x00, 0x04, 0x00, 0x00, 0x00, 0xFF, 0xFF, 0x00, 0x00, 0xb8, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x40, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x80, 0x00, 0x00, 0x00, 0x0e, 0x1f, 0xba, 0x0e, 0x00, 0xb4, 0x09, 0xcd, 0x21, 0xb8, 0x01, 0x4c, 0xcd, 0x21, 0x54, 0x68, 0x69, 0x73, 0x20, 0x70, 0x72, 0x6f, 0x67, 0x72, 0x61, 0x6d, 0x20, 0x63, 0x61, 0x6e, 0x6e, 0x6f, 0x74, 0x20, 0x62, 0x65, 0x20, 0x72, 0x75, 0x6e, 0x20, 0x69, 0x6e, 0x20, 0x44, 0x4f, 0x53, 0x20, 0x6d, 0x6f, 0x64, 0x65, 0x2e, 0x0d, 0x0d, 0x0a, 0x24, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00};
  fwrite(buffer, 1, 128, file);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_dos_header_and_stub>:
  endbr64
  sub    $0x98,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movabs $0x300905a4d,%rax
  movabs $0xffff00000004,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    $0xb8,%eax
  mov    $0x40,%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    $0x0,%eax
  movabs $0x8000000000,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0xcd09b4000eba1f0e,%rax
  movabs $0x685421cd4c01b821,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x72676f7270207369,%rax
  movabs $0x6f6e6e6163206d61,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movabs $0x6e75722065622074,%rax
  movabs $0x20534f44206e6920,%rdx
  mov    %rax,0x60(%rsp)
  mov    %rdx,0x68(%rsp)
  movabs $0xa0d0d2e65646f6d,%rax
  mov    $0x24,%edx
  mov    %rax,0x70(%rsp)
  mov    %rdx,0x78(%rsp)
  mov    %rsp,%rdi
  mov    $0x80,%edx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x98,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_dos_header_and_stub(FILE *file) {
  char buffer[128] = {0x4d, 0x5a, 0x90, 0x00, 0x03, 0x00, 0x00, 0x00, 0x04, 0x00, 0x00, 0x00, 0xFF, 0xFF, 0x00, 0x00, 0xb8, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x40, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x80, 0x00, 0x00, 0x00, 0x0e, 0x1f, 0xba, 0x0e, 0x00, 0xb4, 0x09, 0xcd, 0x21, 0xb8, 0x01, 0x4c, 0xcd, 0x21, 0x54, 0x68, 0x69, 0x73, 0x20, 0x70, 0x72, 0x6f, 0x67, 0x72, 0x61, 0x6d, 0x20, 0x63, 0x61, 0x6e, 0x6e, 0x6f, 0x74, 0x20, 0x62, 0x65, 0x20, 0x72, 0x75, 0x6e, 0x20, 0x69, 0x6e, 0x20, 0x44, 0x4f, 0x53, 0x20, 0x6d, 0x6f, 0x64, 0x65, 0x2e, 0x0d, 0x0d, 0x0a, 0x24, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00};
  fwrite(buffer, 1, 128, file);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_dos_header_and_stub>:
  endbr64
  sub    $0x98,%rsp
  movdqa D29(%rip),%xmm0
  mov    %rdi,%rcx
  mov    $0x80,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1,%esi
  movaps %xmm0,(%rsp)
  movdqa D49(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D23(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D42(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D30(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D1(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D52(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  call   <fwrite@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x98,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D29
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D49
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D23
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D42
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D30
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D1
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D52
type_guessed: byte[16]

tool: {"D29": [0x4d,0x5a,0x90,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0xff,0xff,0x00,0x00]}

tool: {"D49": [0xb8,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00]}

tool: {"D42": [0x0e,0x1f,0xba,0x0e,0x00,0xb4,0x09,0xcd,0x21,0xb8,0x01,0x4c,0xcd,0x21,0x54,0x68]}

tool: {"D30": [0x69,0x73,0x20,0x70,0x72,0x6f,0x67,0x72,0x61,0x6d,0x20,0x63,0x61,0x6e,0x6e,0x6f]}

tool: {"D1": [0x74,0x20,0x62,0x65,0x20,0x72,0x75,0x6e,0x20,0x69,0x6e,0x20,0x44,0x4f,0x53,0x20]}

tool: {"D52": [0x6d,0x6f,0x64,0x65,0x2e,0x0d,0x0d,0x0a,0x24,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void write_dos_header_and_stub(FILE *file) {
  char buffer[128] = {0x4d, 0x5a, 0x90, 0x00, 0x03, 0x00, 0x00, 0x00, 0x04, 0x00, 0x00, 0x00, 0xFF, 0xFF, 0x00, 0x00, 0xb8, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x40, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x80, 0x00, 0x00, 0x00, 0x0e, 0x1f, 0xba, 0x0e, 0x00, 0xb4, 0x09, 0xcd, 0x21, 0xb8, 0x01, 0x4c, 0xcd, 0x21, 0x54, 0x68, 0x69, 0x73, 0x20, 0x70, 0x72, 0x6f, 0x67, 0x72, 0x61, 0x6d, 0x20, 0x63, 0x61, 0x6e, 0x6e, 0x6f, 0x74, 0x20, 0x62, 0x65, 0x20, 0x72, 0x75, 0x6e, 0x20, 0x69, 0x6e, 0x20, 0x44, 0x4f, 0x53, 0x20, 0x6d, 0x6f, 0x64, 0x65, 0x2e, 0x0d, 0x0d, 0x0a, 0x24, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00};
  fwrite(buffer, 1, 128, file);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_dos_header_and_stub>:
  endbr64
  sub    $0x98,%rsp
  movdqa D18(%rip),%xmm0
  mov    %rdi,%rcx
  mov    $0x80,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1,%esi
  movaps %xmm0,(%rsp)
  movdqa D66(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D9(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D44(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D38(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D51(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D17(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  call   <fwrite@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x98,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
type_guessed: byte[16]
name: read_data
arguments: data_tag: D66
type_guessed: byte[16]
name: read_data
arguments: data_tag: D9
type_guessed: byte[16]
name: read_data
arguments: data_tag: D44
type_guessed: byte[16]
name: read_data
arguments: data_tag: D38
type_guessed: byte[16]
name: read_data
arguments: data_tag: D51
type_guessed: byte[16]
name: read_data
arguments: data_tag: D17
type_guessed: byte[16]

tool: {"D18": [0x4d,0x5a,0x90,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0xff,0xff,0x00,0x00]}

tool: {"D66": [0xb8,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00]}

tool: {"D44": [0x0e,0x1f,0xba,0x0e,0x00,0xb4,0x09,0xcd,0x21,0xb8,0x01,0x4c,0xcd,0x21,0x54,0x68]}

tool: {"D38": [0x69,0x73,0x20,0x70,0x72,0x6f,0x67,0x72,0x61,0x6d,0x20,0x63,0x61,0x6e,0x6e,0x6f]}

tool: {"D51": [0x74,0x20,0x62,0x65,0x20,0x72,0x75,0x6e,0x20,0x69,0x6e,0x20,0x44,0x4f,0x53,0x20]}

tool: {"D17": [0x6d,0x6f,0x64,0x65,0x2e,0x0d,0x0d,0x0a,0x24,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void write_dos_header_and_stub(FILE *file) {
  char buffer[128] = {0x4d, 0x5a, 0x90, 0x00, 0x03, 0x00, 0x00, 0x00, 0x04, 0x00, 0x00, 0x00, 0xFF, 0xFF, 0x00, 0x00, 0xb8, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x40, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x80, 0x00, 0x00, 0x00, 0x0e, 0x1f, 0xba, 0x0e, 0x00, 0xb4, 0x09, 0xcd, 0x21, 0xb8, 0x01, 0x4c, 0xcd, 0x21, 0x54, 0x68, 0x69, 0x73, 0x20, 0x70, 0x72, 0x6f, 0x67, 0x72, 0x61, 0x6d, 0x20, 0x63, 0x61, 0x6e, 0x6e, 0x6f, 0x74, 0x20, 0x62, 0x65, 0x20, 0x72, 0x75, 0x6e, 0x20, 0x69, 0x6e, 0x20, 0x44, 0x4f, 0x53, 0x20, 0x6d, 0x6f, 0x64, 0x65, 0x2e, 0x0d, 0x0d, 0x0a, 0x24, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00};
  fwrite(buffer, 1, 128, file);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D32(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D12
type_guessed: string
name: read_data
arguments: label: D21
type_guessed: string
name: read_data
arguments: label: D32
type_guessed: byte[8]
name: read_data
arguments: label: D36
type_guessed: string

tool: D12: Input Price

tool: D21: %d

tool: {"D32": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xf0,0x3f]}

tool: D36: Price including tax %d


assistant: ```c
int main() {
  int price;
  printf("Input Price\n");
  scanf("%d", &price);
  printf("Price including tax %d\n", (int)((price) * (1.00 + 0.05)));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x4(%rsp),%xmm0
  mulsd  D28(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
type: string
name: extract_symbolic_data
arguments: tag: D38
type: string
name: extract_symbolic_data
arguments: tag: D28
type: byte[8]
name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D24: Input Price

tool: D38: %d

tool: {"D28": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xf0,0x3f]}

tool: D8: Price including tax %d


assistant: ```c
int main() {
  int price;
  printf("Input Price\n");
  scanf("%d", &price);
  printf("Price including tax %d\n", (int)((price) * (1.00 + 0.05)));
  return 0;
}
```