ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<place_pivot>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %edx,%r12d
  jg     L26
  mov    %rdi,%rbp
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    %r12d,%ebx
  xchg   %ax,%ax
L11:
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   *%r14
  test   %eax,%eax
  je     L24
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   *%r15
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   *%r15
  add    $0x1,%r13d
  add    $0x1,%r12d
L24:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jge    L11
L26:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int place_pivot(void *array, int low, int high, int Compare(void *, int, int), void Swap(void *, int, int)) {
  int pivot = low;
  int switch_i;
  int i;
  for (switch_i = low + 1, i = low + 1; i <= high; i++) {
    if (Compare(array, i, pivot)) {
      Swap(array, i, switch_i);
      Swap(array, pivot, switch_i);
      pivot++;
      switch_i++;
    }
  }
  return pivot;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<split_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %esi,-0x68(%rbp)
  mov    %rdx,-0x70(%rbp)
  mov    %rcx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L0:
  cmp    %rdx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L0
L15:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L59
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L59:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x50(%rbp)
  mov    -0x64(%rbp),%eax
  mov    %eax,-0x54(%rbp)
  jmp    L20
L1:
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  addl   $0x1,-0x50(%rbp)
  addl   $0x1,-0x54(%rbp)
L20:
  mov    -0x54(%rbp),%eax
  cmp    -0x68(%rbp),%eax
  jle    L1
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x40(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int split_str(int start, int end, char *input, char *output) {
  int len = strlen(input);
  int i, j;
  char buffer[len + 1];
  j = 0;
  for (i = start; i <= end; i++) {
    buffer[j] = input[i];
    j++;
  }
  buffer[j] = '\0';
  strcpy(output, buffer);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<split_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rdx,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L68:
  cmp    %rdx,%rsp
  je     L51
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L68
L51:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L60
  orq    $0x0,-0x8(%rsp,%rax,1)
L60:
  mov    %rsp,%rsi
  cmp    %ebx,%r13d
  jg     L21
  movslq %r13d,%rdx
  mov    %rdx,%rax
  mov    %rsi,%rcx
  sub    %rdx,%rcx
L48:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jge    L48
  sub    %r13d,%ebx
  add    $0x1,%ebx
L64:
  movslq %ebx,%rbx
  movb   $0x0,(%rsi,%rbx,1)
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L21:
  mov    $0x0,%ebx
  jmp    L64
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int split_str(int start, int end, char *input, char *output) {
  int len = strlen(input);
  int i, j;
  char buffer[len + 1];
  j = 0;
  for (i = start; i <= end; i++) {
    buffer[j] = input[i];
    j++;
  }
  buffer[j] = '\0';
  strcpy(output, buffer);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<split_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  movslq %edi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L10
L55:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L55
L10:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L26
L40:
  mov    %rsp,%r15
  cmp    %ebx,%r13d
  jg     L0
  sub    %r13d,%ebx
  lea    (%r14,%r13,1),%rsi
  mov    %rsp,%rdi
  mov    %ebx,%edx
  add    $0x1,%ebx
  add    $0x1,%rdx
  call   <memcpy@plt>
L32:
  movslq %ebx,%rbx
  mov    %r15,%rsi
  mov    %r12,%rdi
  movb   $0x0,(%r15,%rbx,1)
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  xchg   %ax,%ax
L26:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L0:
  xor    %ebx,%ebx
  jmp    L32
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int split_str(int start, int end, char *input, char *output) {
  int len = strlen(input);
  int i, j;
  char buffer[len + 1];
  j = 0;
  for (i = start; i <= end; i++) {
    buffer[j] = input[i];
    j++;
  }
  buffer[j] = '\0';
  strcpy(output, buffer);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<split_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  movslq %edi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L19
L54:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L54
L19:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L28
L4:
  mov    %rsp,%r15
  cmp    %ebx,%r13d
  jg     L55
  sub    %r13d,%ebx
  lea    (%r14,%r13,1),%rsi
  mov    %rsp,%rdi
  mov    %ebx,%edx
  add    $0x1,%ebx
  add    $0x1,%rdx
  call   <memcpy@plt>
L60:
  movslq %ebx,%rbx
  mov    %r15,%rsi
  mov    %r12,%rdi
  movb   $0x0,(%r15,%rbx,1)
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  xchg   %ax,%ax
L28:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L4
L55:
  xor    %ebx,%ebx
  jmp    L60
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int split_str(int start, int end, char *input, char *output) {
  int len = strlen(input);
  int i, j;
  char buffer[len + 1];
  j = 0;
  for (i = start; i <= end; i++) {
    buffer[j] = input[i];
    j++;
  }
  buffer[j] = '\0';
  strcpy(output, buffer);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tableleg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    $0x0,%eax
  call   <glPushMatrix@plt>
  movsd  -0x10(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  mov    $0x0,%esi
  movq   %rax,%xmm0
  mov    $0x0,%edi
  call   <glTranslated@plt>
  movsd  -0x8(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <glScaled@plt>
  mov    D16(%rip),%rax
  movq   %rax,%xmm0
  call   <glutSolidCube@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D16
type_infered: f64

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D16: 1

assistant: ```c
void tableleg(double thick, double len) {
  glPushMatrix();
  glTranslated(0, .5 * len, 0);
  glScaled(thick, len, thick);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tableleg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  mov    $0x0,%eax
  call   <glPushMatrix@plt>
  movq   %rbp,%xmm0
  mulsd  D17(%rip),%xmm0
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <glTranslated@plt>
  movq   %rbx,%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <glScaled@plt>
  movsd  D5(%rip),%xmm0
  call   <glutSolidCube@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: byte[8]
name: parse_data
arguments: data_tag: D5
datatype: f64

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D5: 1

assistant: ```c
void tableleg(double thick, double len) {
  glPushMatrix();
  glTranslated(0, .5 * len, 0);
  glScaled(thick, len, thick);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tableleg>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <glPushMatrix@plt>
  movsd  (%rsp),%xmm1
  xor    %esi,%esi
  xor    %edi,%edi
  movsd  D10(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  call   <glTranslated@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm1
  movapd %xmm2,%xmm0
  call   <glScaled@plt>
  movsd  D3(%rip),%xmm0
  call   <glutSolidCube@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  jmp    10c0 <glPopMatrix@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D3
type_infered: f64

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D3: 1

assistant: ```c
void tableleg(double thick, double len) {
  glPushMatrix();
  glTranslated(0, .5 * len, 0);
  glScaled(thick, len, thick);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tableleg>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <glPushMatrix@plt>
  movsd  (%rsp),%xmm1
  xor    %esi,%esi
  xor    %edi,%edi
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  call   <glTranslated@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm1
  movapd %xmm2,%xmm0
  call   <glScaled@plt>
  movsd  D13(%rip),%xmm0
  call   <glutSolidCube@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  jmp    10c0 <glPopMatrix@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D13
type: f64

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D13: 1

assistant: ```c
void tableleg(double thick, double len) {
  glPushMatrix();
  glTranslated(0, .5 * len, 0);
  glScaled(thick, len, thick);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L15
L20:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x1,-0x18(%rbp)
  je     L23
  mov    $0x78,%edi
  call   <putchar@plt>
L23:
  subq   $0x1,-0x18(%rbp)
L15:
  cmpq   $0x0,-0x18(%rbp)
  jg     L20
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
datatype: string
name: extract_symbolic_data
arguments: data_label: D22
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string

tool: D25: Please input a number: 

tool: D22: %ld

tool: D12: x1=%ld


assistant: ```c
int main() {
  long i, n, f;
  printf("Please input a number: ");
  scanf("%ld", &n);
  f = n;
  for (i = n - 1; i > 0; i--) {
    printf("%ld", i + 1);
    f = f * i;
    if (i != 1)
      printf("x");
  }
  printf("x1=%ld\n", f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rbp
  lea    -0x1(%rbp),%rbx
  test   %rbx,%rbx
  jle    L18
  lea    D27(%rip),%r12
  jmp    L44
L42:
  mov    $0x78,%edi
  call   <putchar@plt>
  sub    $0x1,%rbx
  je     L18
L44:
  lea    0x1(%rbx),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  imul   %rbx,%rbp
  cmp    $0x1,%rbx
  jne    L42
L18:
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string
name: extract_symbolic_data
arguments: data_tag: D27
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string

tool: D3: Please input a number: 

tool: D27: %ld

tool: D19: x1=%ld


assistant: ```c
int main() {
  long i, n, f;
  printf("Please input a number: ");
  scanf("%ld", &n);
  f = n;
  for (i = n - 1; i > 0; i--) {
    printf("%ld", i + 1);
    f = f * i;
    if (i != 1)
      printf("x");
  }
  printf("x1=%ld\n", f);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rdi
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%rbp
  lea    -0x1(%rbp),%rbx
  test   %rbx,%rbx
  jg     L14
  jmp    L5
  nopl   0x0(%rax)
L10:
  mov    $0x78,%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
L14:
  mov    %r12,%rdi
  imul   %rbx,%rbp
  lea    0x1(%rbx),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%rbx
  jne    L10
L5:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D19
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string

tool: D12: Please input a number: 

tool: D19: %ld

tool: D8: x1=%ld


assistant: ```c
int main() {
  long i, n, f;
  printf("Please input a number: ");
  scanf("%ld", &n);
  f = n;
  for (i = n - 1; i > 0; i--) {
    printf("%ld", i + 1);
    f = f * i;
    if (i != 1)
      printf("x");
  }
  printf("x1=%ld\n", f);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdi
  lea    D25(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%rbp
  lea    -0x1(%rbp),%rbx
  test   %rbx,%rbx
  jg     L12
  jmp    L9
  nopl   0x0(%rax)
L3:
  mov    $0x78,%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
L12:
  mov    %r12,%rdi
  imul   %rbx,%rbp
  lea    0x1(%rbx),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%rbx
  jne    L3
L9:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_guessed: string
name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D29
type_guessed: string

tool: D28: Please input a number: 

tool: D25: %ld

tool: D29: x1=%ld


assistant: ```c
int main() {
  long i, n, f;
  printf("Please input a number: ");
  scanf("%ld", &n);
  f = n;
  for (i = n - 1; i > 0; i--) {
    printf("%ld", i + 1);
    f = f * i;
    if (i != 1)
      printf("x");
  }
  printf("x1=%ld\n", f);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_class_gen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  jmp    L40
L74:
  addq   $0x1,-0x50(%rbp)
L40:
  mov    -0x50(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  mov    -0x50(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L74
L20:
  mov    -0x50(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L118
  mov    -0x50(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  jmp    L118
L145:
  addq   $0x1,-0x50(%rbp)
L118:
  mov    -0x50(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L120
  mov    -0x50(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L145
L120:
  mov    -0x50(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L72
  mov    -0x50(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x40(%rbp)
L72:
  cmpl   $0x3,-0x6c(%rbp)
  je     L100
  cmpl   $0x3,-0x6c(%rbp)
  jg     L59
  cmpl   $0x1,-0x6c(%rbp)
  je     L114
  cmpl   $0x2,-0x6c(%rbp)
  je     L105
  jmp    L59
L114:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x54(%rbp)
  jmp    L88
L105:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x54(%rbp)
  jmp    L88
L100:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x54(%rbp)
  jmp    L88
L59:
  movl   $0xffffffff,-0x54(%rbp)
  nop
L88:
  mov    -0x54(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L110
  call   <__stack_chk_fail@plt>
L110:
  leave
  ret
```

assistant: ```c
int get_class_gen(char *str, int num) {
  int ret;
  char stmp[32];
  char *sp;
  char *spc;
  char *spi;
  char *spf;
  strncpy(stmp, str, 32);
  spc = stmp;
  sp = stmp;
  while (*sp && (*sp != '.'))
    sp++;
  if (*sp == '.') {
    *sp = 0;
    sp++;
    spi = sp;
  }
  while (*sp && (*sp != '.'))
    sp++;
  if (*sp == '.') {
    *sp = 0;
    sp++;
    spf = sp;
  }
  switch (num) {
  case 1:
    ret = atoi(spc);
    break;
  case 2:
    ret = atoi(spi);
    break;
  case 3:
    ret = atoi(spf);
    break;
  default:
    ret = -1;
    break;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_class_gen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    $0x20,%edx
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movzbl (%rsp),%edx
  test   %dl,%dl
  je     L106
  cmp    $0x2e,%dl
  je     L106
  mov    %rsp,%rax
L47:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L62
  cmp    $0x2e,%dl
  jne    L47
L62:
  cmp    $0x2e,%dl
  jne    L38
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rbp
  movzbl 0x1(%rax),%edx
  test   %dl,%dl
  je     L89
  cmp    $0x2e,%dl
  je     L89
  mov    %rbp,%rax
L146:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L154
  cmp    $0x2e,%dl
  jne    L146
L154:
  cmp    $0x2e,%dl
  je     L24
L192:
  cmp    $0x2,%ebx
  je     L197
  cmp    $0x3,%ebx
  je     L168
  mov    $0xffffffff,%eax
  cmp    $0x1,%ebx
  je     L167
L77:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L149
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L89:
  mov    %rbp,%rax
  jmp    L154
L24:
  movb   $0x0,(%rax)
  lea    0x1(%rax),%r12
  jmp    L192
L167:
  mov    %rsp,%rdi
  call   <atoi@plt>
  jmp    L77
L197:
  mov    %rbp,%rdi
  call   <atoi@plt>
  jmp    L77
L168:
  mov    %r12,%rdi
  call   <atoi@plt>
  jmp    L77
L38:
  movzbl (%rax),%edx
  jmp    L154
L106:
  mov    %rsp,%rax
  jmp    L62
L149:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_class_gen(char *str, int num) {
  int ret;
  char stmp[32];
  char *sp;
  char *spc;
  char *spi;
  char *spf;
  strncpy(stmp, str, 32);
  spc = stmp;
  sp = stmp;
  while (*sp && (*sp != '.'))
    sp++;
  if (*sp == '.') {
    *sp = 0;
    sp++;
    spi = sp;
  }
  while (*sp && (*sp != '.'))
    sp++;
  if (*sp == '.') {
    *sp = 0;
    sp++;
    spf = sp;
  }
  switch (num) {
  case 1:
    ret = atoi(spc);
    break;
  case 2:
    ret = atoi(spi);
    break;
  case 3:
    ret = atoi(spf);
    break;
  default:
    ret = -1;
    break;
  }
  return ret;
}
```