ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movabs $0x7469543b656d614e,%rax
  movabs $0x6373694d3b656c,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x3b,-0x22(%rbp)
  lea    -0x38(%rbp),%rdx
  lea    -0x22(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtok_r@plt>
  mov    %rax,-0x30(%rbp)
  jmp    L25
L22:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rdx
  lea    -0x22(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok_r@plt>
  mov    %rax,-0x30(%rbp)
L25:
  cmpq   $0x0,-0x30(%rbp)
  jne    L22
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string

tool: D6: Seperating using strtok_r

tool: D16: Word (%s)


assistant: ```c
int main() {
  printf("Seperating using strtok_r\n");
  char csv[] = "Name;Title;Misc";
  char delimiter[] = ";";
  char *aux;
  char *word = strtok_r(csv, delimiter, &aux);
  while (word) {
    printf("Word (%s)\n", word);
    word = strtok_r(NULL, delimiter, &aux);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <puts@plt>
  movabs $0x7469543b656d614e,%rax
  movabs $0x6373694d3b656c,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movw   $0x3b,0xe(%rsp)
  mov    %rsp,%rdx
  lea    0xe(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <strtok_r@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rsi
  lea    D18(%rip),%rbx
L25:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rdx
  lea    0xe(%rsp),%rsi
  mov    $0x0,%edi
  call   <strtok_r@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L25
L7:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string

tool: D6: Seperating using strtok_r

tool: D18: Word (%s)


assistant: ```c
int main() {
  printf("Seperating using strtok_r\n");
  char csv[] = "Name;Title;Misc";
  char delimiter[] = ";";
  char *aux;
  char *word = strtok_r(csv, delimiter, &aux);
  while (word) {
    printf("Word (%s)\n", word);
    word = strtok_r(NULL, delimiter, &aux);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xe(%rsp),%rbx
  call   <puts@plt>
  mov    $0x3b,%eax
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  movdqa D5(%rip),%xmm0
  lea    0x10(%rsp),%rdi
  mov    %ax,0xe(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <strtok_r@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rsi
  lea    D12(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdx
  xor    %edi,%edi
  call   <strtok_r@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L14
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: byte[16]
name: read_data
arguments: data_label: D12
type_infered: string

tool: D7: Seperating using strtok_r

tool: {"D5": [0x4e,0x61,0x6d,0x65,0x3b,0x54,0x69,0x74,0x6c,0x65,0x3b,0x4d,0x69,0x73,0x63,0x00]}

tool: D12: Word (%s)


assistant: ```c
int main() {
  printf("Seperating using strtok_r\n");
  char csv[] = "Name;Title;Misc";
  char delimiter[] = ";";
  char *aux;
  char *word = strtok_r(csv, delimiter, &aux);
  while (word) {
    printf("Word (%s)\n", word);
    word = strtok_r(NULL, delimiter, &aux);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xe(%rsp),%rbx
  call   <puts@plt>
  mov    $0x3b,%eax
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  movdqa D13(%rip),%xmm0
  lea    0x10(%rsp),%rdi
  mov    %ax,0xe(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <strtok_r@plt>
  test   %rax,%rax
  je     L29
  mov    %rax,%rsi
  lea    D19(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdx
  xor    %edi,%edi
  call   <strtok_r@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L13
L29:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D13
datatype: byte[16]
name: parse_data
arguments: data_label: D19
datatype: string

tool: D1: Seperating using strtok_r

tool: {"D13": [0x4e,0x61,0x6d,0x65,0x3b,0x54,0x69,0x74,0x6c,0x65,0x3b,0x4d,0x69,0x73,0x63,0x00]}

tool: D19: Word (%s)


assistant: ```c
int main() {
  printf("Seperating using strtok_r\n");
  char csv[] = "Name;Title;Misc";
  char delimiter[] = ";";
  char *aux;
  char *word = strtok_r(csv, delimiter, &aux);
  while (word) {
    printf("Word (%s)\n", word);
    word = strtok_r(NULL, delimiter, &aux);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<timedif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rsi,%rax
  mov    %rdi,%r8
  mov    %r8,%rsi
  mov    %r9,%rdi
  mov    %rax,%rdi
  mov    %rsi,-0x20(%rbp)
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%ebx
  movslq %ebx,%rax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  sar    $0x6,%eax
  sar    $0x1f,%ebx
  mov    %ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%r12d
  imul   $0x3e8,%r12d,%r12d
  lea    (%r12,%rbx,1),%eax
  cltq
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
long int timedif(struct timeval a, struct timeval b) {
  register int us, s;
  us = (int)(a.tv_usec - b.tv_usec);
  us /= 1000;
  s = (int)(a.tv_sec - b.tv_sec);
  s *= 1000;
  return s + us;
}
```
user: What is the c source code of the assembly code below:

```asm
<timedif>:
  endbr64
  sub    %ecx,%esi
  sub    %edx,%edi
  movslq %esi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  imul   $0x3e8,%edi,%edi
  add    %edi,%eax
  cltq
  ret
```

assistant: ```c
long int timedif(struct timeval a, struct timeval b) {
  register int us, s;
  us = (int)(a.tv_usec - b.tv_usec);
  us /= 1000;
  s = (int)(a.tv_sec - b.tv_sec);
  s *= 1000;
  return s + us;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timedif>:
  endbr64
  sub    %ecx,%esi
  sub    %edx,%edi
  movslq %esi,%rax
  imul   $0x3e8,%edi,%edi
  sar    $0x1f,%esi
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %esi,%eax
  add    %edi,%eax
  cltq
  ret
```

assistant: ```c
long int timedif(struct timeval a, struct timeval b) {
  register int us, s;
  us = (int)(a.tv_usec - b.tv_usec);
  us /= 1000;
  s = (int)(a.tv_sec - b.tv_sec);
  s *= 1000;
  return s + us;
}
```
user: What is the c source code of the assembly code below?

```asm
<timedif>:
  endbr64
  sub    %ecx,%esi
  sub    %edx,%edi
  movslq %esi,%rax
  imul   $0x3e8,%edi,%edi
  sar    $0x1f,%esi
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %esi,%eax
  add    %edi,%eax
  cltq
  ret
```

assistant: ```c
long int timedif(struct timeval a, struct timeval b) {
  register int us, s;
  us = (int)(a.tv_usec - b.tv_usec);
  us /= 1000;
  s = (int)(a.tv_sec - b.tv_sec);
  s *= 1000;
  return s + us;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <hack@plt>
  leave
  ret
```

assistant: ```c
void *test2(struct dummy *t) {
  struct dummy *tt;
  const enum dummy_enum *e;
  tt = t;
  return hack(t, e);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  call   <hack@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *test2(struct dummy *t) {
  struct dummy *tt;
  const enum dummy_enum *e;
  tt = t;
  return hack(t, e);
}
```
user: What is the c source code of the assembly code below:

```asm
<test2>:
  endbr64
  xor    %esi,%esi
  jmp    1050 <hack@plt>
```

assistant: ```c
void *test2(struct dummy *t) {
  struct dummy *tt;
  const enum dummy_enum *e;
  tt = t;
  return hack(t, e);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test2>:
  endbr64
  xor    %esi,%esi
  jmp    1050 <hack@plt>
```

assistant: ```c
void *test2(struct dummy *t) {
  struct dummy *tt;
  const enum dummy_enum *e;
  tt = t;
  return hack(t, e);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_putnbr_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x80000000,-0x14(%rbp)
  jne    L12
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <ft_putstr_fd@plt>
  jmp    L20
L12:
  cmpl   $0x0,-0x14(%rbp)
  jns    L8
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  negl   -0x14(%rbp)
  jmp    L8
L3:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  cmp    $0x9,%eax
  jg     L3
  jmp    L22
L44:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    $0x30,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <ft_putchar_fd@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L22:
  cmpl   $0x0,-0x4(%rbp)
  jg     L44
L20:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D7: -2147483648

assistant: ```c
void ft_putnbr_fd(int n, int fd) {
  int i;
  i = 1;
  if (n == -2147483648) {
    ft_putstr_fd("-2147483648", fd);
    return;
  }
  if (n < 0) {
    ft_putchar_fd('-', fd);
    n = n * -1;
  }
  while (n / i >= 10) {
    i = i * 10;
  }
  while (i > 0) {
    ft_putchar_fd((n / i) % 10 + '0', fd);
    i = i / 10;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  cmp    $0x80000000,%edi
  je     L81
  mov    %edi,%ebp
  test   %edi,%edi
  js     L50
L10:
  mov    $0x1,%ebx
  cmp    $0x9,%ebp
  jle    L80
L29:
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  cmp    $0x9,%eax
  jg     L29
  test   %ebx,%ebx
  jle    L77
L54:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x30(%rax),%edi
  mov    %r12d,%esi
  call   <ft_putchar_fd@plt>
  mov    %ebx,%edx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebx
  cmp    $0x9,%edx
  jg     L54
L77:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L81:
  lea    D5(%rip),%rdi
  call   <ft_putstr_fd@plt>
  jmp    L77
L50:
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  neg    %ebp
  jmp    L10
L80:
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  mov    %r12d,%esi
  call   <ft_putchar_fd@plt>
  jmp    L77
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: -2147483648

assistant: ```c
void ft_putnbr_fd(int n, int fd) {
  int i;
  i = 1;
  if (n == -2147483648) {
    ft_putstr_fd("-2147483648", fd);
    return;
  }
  if (n < 0) {
    ft_putchar_fd('-', fd);
    n = n * -1;
  }
  while (n / i >= 10) {
    i = i * 10;
  }
  while (i > 0) {
    ft_putchar_fd((n / i) % 10 + '0', fd);
    i = i / 10;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x80000000,%edi
  je     L46
  mov    %edi,%ebp
  test   %edi,%edi
  js     L43
L14:
  mov    $0x1,%ebx
  cmp    $0x9,%ebp
  jle    L21
  nopl   0x0(%rax)
L51:
  mov    %ebp,%eax
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  cltd
  idiv   %ebx
  cmp    $0x9,%eax
  jg     L51
  mov    $0xcccccccd,%r12d
  nopl   (%rax)
L45:
  mov    %ebp,%eax
  mov    %r13d,%esi
  cltd
  idiv   %ebx
  mov    %ebx,%ebx
  imul   %r12,%rbx
  shr    $0x23,%rbx
  mov    %eax,%edx
  imul   %r12,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x30(%rax),%edi
  call   <ft_putchar_fd@plt>
  test   %ebx,%ebx
  jne    L45
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  mov    $0x2d,%edi
  neg    %ebp
  call   <ft_putchar_fd@plt>
  jmp    L14
  xchg   %ax,%ax
L46:
  add    $0x8,%rsp
  lea    D5(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <ft_putstr_fd@plt>
  cs nopw 0x0(%rax,%rax,1)
L21:
  add    $0x8,%rsp
  lea    0x30(%rbp),%edi
  mov    %r13d,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <ft_putchar_fd@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: -2147483648

assistant: ```c
void ft_putnbr_fd(int n, int fd) {
  int i;
  i = 1;
  if (n == -2147483648) {
    ft_putstr_fd("-2147483648", fd);
    return;
  }
  if (n < 0) {
    ft_putchar_fd('-', fd);
    n = n * -1;
  }
  while (n / i >= 10) {
    i = i * 10;
  }
  while (i > 0) {
    ft_putchar_fd((n / i) % 10 + '0', fd);
    i = i / 10;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x80000000,%edi
  je     L9
  mov    %edi,%ebp
  test   %edi,%edi
  js     L34
L44:
  mov    $0x1,%ebx
  cmp    $0x9,%ebp
  jle    L30
  nopl   0x0(%rax)
L6:
  mov    %ebp,%eax
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  cltd
  idiv   %ebx
  cmp    $0x9,%eax
  jg     L6
  mov    $0xcccccccd,%r12d
  nopl   (%rax)
L26:
  mov    %ebp,%eax
  mov    %r13d,%esi
  cltd
  idiv   %ebx
  mov    %ebx,%ebx
  imul   %r12,%rbx
  shr    $0x23,%rbx
  mov    %eax,%edx
  imul   %r12,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x30(%rax),%edi
  call   <ft_putchar_fd@plt>
  test   %ebx,%ebx
  jne    L26
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    $0x2d,%edi
  neg    %ebp
  call   <ft_putchar_fd@plt>
  jmp    L44
  xchg   %ax,%ax
L9:
  add    $0x8,%rsp
  lea    D7(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <ft_putstr_fd@plt>
  cs nopw 0x0(%rax,%rax,1)
L30:
  add    $0x8,%rsp
  lea    0x30(%rbp),%edi
  mov    %r13d,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <ft_putchar_fd@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: -2147483648

assistant: ```c
void ft_putnbr_fd(int n, int fd) {
  int i;
  i = 1;
  if (n == -2147483648) {
    ft_putstr_fd("-2147483648", fd);
    return;
  }
  if (n < 0) {
    ft_putchar_fd('-', fd);
    n = n * -1;
  }
  while (n / i >= 10) {
    i = i * 10;
  }
  while (i > 0) {
    ft_putchar_fd((n / i) % 10 + '0', fd);
    i = i / 10;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L4
  mov    -0x8(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
L4:
  nop
  leave
  ret
```

assistant: ```c
void quicksort(int *tab, int u, int o) {
  int p = o;
  int pn;
  if (o > u) {
    pn = partition(tab, u, o, p);
    quicksort(tab, u, pn - 1);
    quicksort(tab, pn + 1, o);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quicksort>:
  endbr64
  cmp    %esi,%edx
  jg     L5
  ret
L5:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %edx,%ecx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quicksort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quicksort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quicksort(int *tab, int u, int o) {
  int p = o;
  int pn;
  if (o > u) {
    pn = partition(tab, u, o, p);
    quicksort(tab, u, pn - 1);
    quicksort(tab, pn + 1, o);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ClearCRLF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
  jmp    L15
L12:
  add    $0x1,%rbx
L15:
  movzbl (%rbx),%eax
  cmp    $0x1f,%al
  jg     L12
  movb   $0x0,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void ClearCRLF(char *s) {
  register char *cp;
  cp = s;
  while (*cp > 31)
    cp++;
  *cp = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ClearCRLF>:
  endbr64
  cmpb   $0x1f,(%rdi)
  jle    L3
L4:
  add    $0x1,%rdi
  cmpb   $0x1f,(%rdi)
  jg     L4
L3:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void ClearCRLF(char *s) {
  register char *cp;
  cp = s;
  while (*cp > 31)
    cp++;
  *cp = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ClearCRLF>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L7:
  add    $0x1,%rdi
L0:
  cmpb   $0x1f,(%rdi)
  jg     L7
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void ClearCRLF(char *s) {
  register char *cp;
  cp = s;
  while (*cp > 31)
    cp++;
  *cp = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ClearCRLF>:
  endbr64
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L12:
  add    $0x1,%rdi
L15:
  cmpb   $0x1f,(%rdi)
  jg     L12
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void ClearCRLF(char *s) {
  register char *cp;
  cp = s;
  while (*cp > 31)
    cp++;
  *cp = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<inflateInplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <inflateCpy@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L17
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x30(%rbp)
  jae    L38
L17:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <freeDHBuf@plt>
  mov    $0xffffffff,%eax
  jmp    L28
L38:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <freeDHBuf@plt>
  mov    -0x14(%rbp),%eax
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
int inflateInplace(char *buf, unsigned buflen_comp, unsigned bufsize) {
  unsigned uncmp_sz = 0;
  char *altbuf = inflateCpy(buf, buflen_comp, bufsize, &uncmp_sz);
  if (!altbuf || uncmp_sz > bufsize) {
    freeDHBuf(altbuf);
    return -1;
  }
  memcpy(buf, altbuf, uncmp_sz);
  freeDHBuf(altbuf);
  return uncmp_sz;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inflateInplace>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  call   <inflateCpy@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
  mov    0x4(%rsp),%edx
  cmp    %ebp,%edx
  ja     L16
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <freeDHBuf@plt>
  mov    0x4(%rsp),%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %rbx,%rdi
  call   <freeDHBuf@plt>
  mov    $0xffffffff,%eax
  jmp    L5
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int inflateInplace(char *buf, unsigned buflen_comp, unsigned bufsize) {
  unsigned uncmp_sz = 0;
  char *altbuf = inflateCpy(buf, buflen_comp, bufsize, &uncmp_sz);
  if (!altbuf || uncmp_sz > bufsize) {
    freeDHBuf(altbuf);
    return -1;
  }
  memcpy(buf, altbuf, uncmp_sz);
  freeDHBuf(altbuf);
  return uncmp_sz;
}
```