user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <ruspma_rand_init@plt>
  movsd  D54(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D73(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  D53(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D62(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D38(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D38(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <new_matrix_from@plt>
  mov    %rax,-0x78(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <new_matrix_from@plt>
  mov    %rax,-0x70(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <new_matrix_from@plt>
  mov    %rax,-0x68(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <new_matrix_from@plt>
  mov    %rax,-0x60(%rbp)
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0xb,%esi
  mov    $0x2,%edi
  call   <new_network@plt>
  mov    %rax,-0x58(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L19
L16:
  mov    D10(%rip),%rsi
  mov    -0x68(%rbp),%rdx
  mov    -0x78(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <backpropagate@plt>
  mov    D10(%rip),%rsi
  mov    -0x60(%rbp),%rdx
  mov    -0x70(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <backpropagate@plt>
  addl   $0x1,-0x7c(%rbp)
L19:
  cmpl   $0x5dc,-0x7c(%rbp)
  jne    L16
  mov    -0x78(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <feedforward@plt>
  mov    %eax,%edi
  call   <print_out_matrix@plt>
  mov    -0x70(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <feedforward@plt>
  mov    %eax,%edi
  call   <print_out_matrix@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <free_network@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D54
type_infered: f64
name: unpack_data
arguments: data_label: D73
type_infered: f64
name: unpack_data
arguments: data_label: D53
type_infered: f64
name: unpack_data
arguments: data_label: D62
type_infered: f64
name: unpack_data
arguments: data_label: D38
type_infered: f64
name: unpack_data
arguments: data_label: D10
type_infered: f64

tool: D54: 0.5

tool: D73: 0.4

tool: D53: 0.2

tool: D62: 0.9

tool: D38: 1

tool: D10: 6.5

assistant: ```c
int main(int args, char **argv) {
  ruspma_rand_init();
  double in1[2] = {(double)0.5, (double)0.4};
  double in2[2] = {(double)0.2, (double)0.9};
  double out1[2] = {(double)1.0, (double)0.0};
  double out2[2] = {(double)0.0, (double)1.0};
  struct ruspma_matrix *in1_m = new_matrix_from(1, 2, in1);
  struct ruspma_matrix *in2_m = new_matrix_from(1, 2, in2);
  struct ruspma_matrix *out1_m = new_matrix_from(1, 2, out1);
  struct ruspma_matrix *out2_m = new_matrix_from(1, 2, out2);
  struct ruspma_nn *k = new_network(2, 11, 2, 1);
  int mm;
  for (mm = 0; mm != 1500; ++mm) {
    backpropagate(k, in1_m, out1_m, 6.5);
    backpropagate(k, in2_m, out2_m, 6.5);
  }
  print_out_matrix(feedforward(k, in1_m));
  print_out_matrix(feedforward(k, in2_m));
  free_network(k);
}
```