ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<new_float_array>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x2,%rdi
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <malloc@plt>
  test   %rax,%rax
  je     L44
  test   %rbx,%rbx
  je     L44
  lea    -0x1(%rbx),%rdx
  movss  0xc(%rsp),%xmm0
  cmp    $0x2,%rdx
  jbe    L60
  mov    %rbx,%rcx
  movaps %xmm0,%xmm1
  mov    %rax,%rdx
  shr    $0x2,%rcx
  shufps $0x0,%xmm1,%xmm1
  shl    $0x4,%rcx
  add    %rax,%rcx
  nopl   (%rax)
L20:
  movups %xmm1,(%rdx)
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jne    L20
  mov    %rbx,%rdx
  and    $0xfffffffffffffffc,%rdx
  test   $0x3,%bl
  je     L44
L62:
  lea    0x1(%rdx),%rsi
  lea    0x0(,%rdx,4),%rcx
  movss  %xmm0,(%rax,%rdx,4)
  cmp    %rsi,%rbx
  jbe    L44
  add    $0x2,%rdx
  movss  %xmm0,0x4(%rax,%rcx,1)
  cmp    %rdx,%rbx
  jbe    L44
  movss  %xmm0,0x8(%rax,%rcx,1)
L44:
  add    $0x10,%rsp
  pop    %rbx
  ret
L60:
  xor    %edx,%edx
  jmp    L62
```

assistant: ```c
float *new_float_array(size_t n, float default_value) {
  float *array;
  array = (float *)malloc(n * sizeof(float));
  if (array == NULL)
    return NULL;
  for (size_t i = 0; i < n; i++) {
    *(array + i) = default_value;
  }
  return array;
}
```
user: What is the c source code of the assembly code below:

```asm
<din>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L55
  mov    $0x0,%eax
  jmp    L49
L55:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jne    L54
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <equalizza@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <autoUpdateSolution@plt>
  mov    $0x0,%eax
  jmp    L49
L54:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L41
L21:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <equalizza@plt>
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%esi
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r9
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <din>
  mov    -0x4(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <autoUpdateSolution@plt>
  addl   $0x2,-0x8(%rbp)
L41:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jle    L21
  mov    -0x4(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getCosto@plt>
L49:
  leave
  ret
```

assistant: ```c
int din(int *f, int l, int r, int pos, int *sol, int *bestSol) {
  int i;
  int n = r + 1;
  if (l >= r)
    return 0;
  if ((r - l) == 1) {
    equalizza(sol, l, r);
    autoUpdateSolution(f, sol, bestSol, n);
    return 0;
  }
  for (i = l; i < r + 2; i += 2) {
    equalizza(sol, l, i + 1);
    din(f, i + 2, r, 0, sol, bestSol);
    autoUpdateSolution(f, sol, bestSol, n);
  }
  return getCosto(f, bestSol, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<din>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r9,0x8(%rsp)
  mov    $0x0,%eax
  cmp    %esi,%edx
  jle    L6
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%r14d
  mov    %r8,%rbp
  lea    0x1(%rdx),%r15d
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0x1,%eax
  je     L4
  mov    %esi,%ebx
  cmp    %esi,%r15d
  jl     L16
L0:
  lea    0x1(%rbx),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <equalizza@plt>
  add    $0x2,%ebx
  mov    0x8(%rsp),%r9
  mov    %rbp,%r8
  mov    $0x0,%ecx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <din>
  mov    %r15d,%ecx
  mov    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <autoUpdateSolution@plt>
  cmp    %r15d,%ebx
  jle    L0
L16:
  mov    %r15d,%edx
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <getCosto@plt>
L6:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %r8,%rdi
  call   <equalizza@plt>
  mov    %r15d,%ecx
  mov    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <autoUpdateSolution@plt>
  mov    $0x0,%eax
  jmp    L6
```

assistant: ```c
int din(int *f, int l, int r, int pos, int *sol, int *bestSol) {
  int i;
  int n = r + 1;
  if (l >= r)
    return 0;
  if ((r - l) == 1) {
    equalizza(sol, l, r);
    autoUpdateSolution(f, sol, bestSol, n);
    return 0;
  }
  for (i = l; i < r + 2; i += 2) {
    equalizza(sol, l, i + 1);
    din(f, i + 2, r, 0, sol, bestSol);
    autoUpdateSolution(f, sol, bestSol, n);
  }
  return getCosto(f, bestSol, n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<din>:
  endbr64
  cmp    %esi,%edx
  jle    L20
  push   %r15
  mov    %edx,%eax
  mov    %esi,%r10d
  lea    0x1(%rdx),%r15d
  push   %r14
  sub    %esi,%eax
  mov    %edx,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%eax
  je     L31
  mov    %esi,%ebx
  cmp    %esi,%r15d
  jl     L30
L4:
  mov    %r10d,%esi
  lea    0x1(%rbx),%edx
  mov    %rbp,%rdi
  add    $0x2,%ebx
  mov    %r10d,0xc(%rsp)
  call   <equalizza@plt>
  xor    %ecx,%ecx
  mov    %r13,%r9
  mov    %rbp,%r8
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <din>
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <autoUpdateSolution@plt>
  cmp    %r15d,%ebx
  mov    0xc(%rsp),%r10d
  jle    L4
L30:
  add    $0x18,%rsp
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <getCosto@plt>
  nop
L20:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %r8,%rdi
  call   <equalizza@plt>
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <autoUpdateSolution@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int din(int *f, int l, int r, int pos, int *sol, int *bestSol) {
  int i;
  int n = r + 1;
  if (l >= r)
    return 0;
  if ((r - l) == 1) {
    equalizza(sol, l, r);
    autoUpdateSolution(f, sol, bestSol, n);
    return 0;
  }
  for (i = l; i < r + 2; i += 2) {
    equalizza(sol, l, i + 1);
    din(f, i + 2, r, 0, sol, bestSol);
    autoUpdateSolution(f, sol, bestSol, n);
  }
  return getCosto(f, bestSol, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<din>:
  endbr64
  cmp    %esi,%edx
  jle    L20
  push   %r15
  mov    %edx,%eax
  mov    %esi,%r10d
  lea    0x1(%rdx),%r15d
  push   %r14
  sub    %esi,%eax
  mov    %edx,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%eax
  je     L14
  mov    %esi,%ebx
  cmp    %esi,%r15d
  jl     L11
L3:
  mov    %r10d,%esi
  lea    0x1(%rbx),%edx
  mov    %rbp,%rdi
  add    $0x2,%ebx
  mov    %r10d,0xc(%rsp)
  call   <equalizza@plt>
  xor    %ecx,%ecx
  mov    %r13,%r9
  mov    %rbp,%r8
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <din>
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <autoUpdateSolution@plt>
  cmp    %r15d,%ebx
  mov    0xc(%rsp),%r10d
  jle    L3
L11:
  add    $0x18,%rsp
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <getCosto@plt>
  nop
L20:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %r8,%rdi
  call   <equalizza@plt>
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <autoUpdateSolution@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int din(int *f, int l, int r, int pos, int *sol, int *bestSol) {
  int i;
  int n = r + 1;
  if (l >= r)
    return 0;
  if ((r - l) == 1) {
    equalizza(sol, l, r);
    autoUpdateSolution(f, sol, bestSol, n);
    return 0;
  }
  for (i = l; i < r + 2; i += 2) {
    equalizza(sol, l, i + 1);
    din(f, i + 2, r, 0, sol, bestSol);
    autoUpdateSolution(f, sol, bestSol, n);
  }
  return getCosto(f, bestSol, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<randum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  movl   $0x60d,-0x2c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  and    $0xfff,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0xfff,%eax
  mov    %eax,-0x20(%rbp)
  sarl   $0xc,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  sar    $0xc,%eax
  and    $0xfff,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x196,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   -0x28(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0xfff,%eax
  mov    %eax,-0x14(%rbp)
  sarl   $0xc,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  shl    $0xc,%eax
  or     %edx,%eax
  or     -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x14(%rbp),%xmm2
  pxor   %xmm3,%xmm3
  cvtsi2sdl -0x20(%rbp),%xmm3
  movsd  D3(%rip),%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm2
  movsd  D3(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  D22(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: f64
name: extract_symbolic_data
arguments: label: D22
type_infered: f64

tool: D3: 0.000244140625

tool: D22: 0.00390625

assistant: ```c
double randum(int64_t *seed) {
  int64_t sum, mult0, mult1, seed0, seed1, seed2, newseed0, newseed1, newseed2;
  double res;
  mult0 = 1549;
  seed0 = *seed & 4095;
  sum = mult0 * seed0;
  newseed0 = sum & 4095;
  sum >>= 12;
  seed1 = (*seed >> 12) & 4095;
  mult1 = 406;
  sum += mult0 * seed1 + mult1 * seed0;
  newseed1 = sum & 4095;
  sum >>= 12;
  seed2 = (*seed >> 24) & 255;
  sum += mult0 * seed2 + mult1 * seed1;
  newseed2 = sum & 255;
  *seed = newseed2 << 24 | newseed1 << 12 | newseed0;
  res = 0.00390625 * (newseed2 + 0.000244140625 * (newseed1 + 0.000244140625 * newseed0));
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<randum>:
  endbr64
  mov    %rdi,%rsi
  mov    (%rdi),%eax
  mov    %eax,%r9d
  and    $0xfff,%r9d
  imul   $0x60d,%r9d,%edx
  mov    %edx,%edi
  and    $0xfff,%edi
  sar    $0xc,%edx
  mov    %edx,%r8d
  mov    %eax,%ecx
  sar    $0xc,%ecx
  and    $0xfff,%ecx
  imul   $0x60d,%ecx,%edx
  imul   $0x196,%r9d,%r9d
  add    %r9d,%edx
  add    %r8d,%edx
  mov    %edx,%r8d
  and    $0xfff,%r8d
  sar    $0xc,%edx
  shr    $0x18,%eax
  imul   $0x60d,%eax,%eax
  imul   $0x196,%ecx,%ecx
  add    %ecx,%eax
  add    %edx,%eax
  movzbl %al,%ecx
  mov    %r8d,%edx
  shl    $0xc,%edx
  or     %edi,%edx
  shl    $0x18,%eax
  or     %edx,%eax
  mov    %eax,(%rsi)
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  movsd  D3(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %r8d,%xmm2
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: f64
name: parse_data
arguments: tag: D7
type_guessed: f64

tool: D3: 0.000244140625

tool: D7: 0.00390625

assistant: ```c
double randum(int64_t *seed) {
  int64_t sum, mult0, mult1, seed0, seed1, seed2, newseed0, newseed1, newseed2;
  double res;
  mult0 = 1549;
  seed0 = *seed & 4095;
  sum = mult0 * seed0;
  newseed0 = sum & 4095;
  sum >>= 12;
  seed1 = (*seed >> 12) & 4095;
  mult1 = 406;
  sum += mult0 * seed1 + mult1 * seed0;
  newseed1 = sum & 4095;
  sum >>= 12;
  seed2 = (*seed >> 24) & 255;
  sum += mult0 * seed2 + mult1 * seed1;
  newseed2 = sum & 255;
  *seed = newseed2 << 24 | newseed1 << 12 | newseed0;
  res = 0.00390625 * (newseed2 + 0.000244140625 * (newseed1 + 0.000244140625 * newseed0));
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<randum>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rsi
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  movsd  D19(%rip),%xmm1
  mov    %eax,%r9d
  mov    %eax,%ecx
  shr    $0x18,%eax
  and    $0xfff,%r9d
  sar    $0xc,%ecx
  imul   $0x60d,%eax,%eax
  imul   $0x60d,%r9d,%edx
  and    $0xfff,%ecx
  imul   $0x196,%r9d,%r9d
  mov    %edx,%edi
  sar    $0xc,%edx
  mov    %edx,%r8d
  imul   $0x60d,%ecx,%edx
  and    $0xfff,%edi
  cvtsi2sd %edi,%xmm0
  imul   $0x196,%ecx,%ecx
  add    %r9d,%edx
  add    %r8d,%edx
  mulsd  %xmm1,%xmm0
  mov    %edx,%r8d
  add    %ecx,%eax
  sar    $0xc,%edx
  and    $0xfff,%r8d
  add    %edx,%eax
  cvtsi2sd %r8d,%xmm2
  movzbl %al,%ecx
  mov    %r8d,%edx
  shl    $0x18,%eax
  shl    $0xc,%edx
  or     %edi,%edx
  or     %edx,%eax
  addsd  %xmm2,%xmm0
  mov    %eax,(%rsi)
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
datatype: f64
name: unpack_data
arguments: data_tag: D7
datatype: f64

tool: D19: 0.000244140625

tool: D7: 0.00390625

assistant: ```c
double randum(int64_t *seed) {
  int64_t sum, mult0, mult1, seed0, seed1, seed2, newseed0, newseed1, newseed2;
  double res;
  mult0 = 1549;
  seed0 = *seed & 4095;
  sum = mult0 * seed0;
  newseed0 = sum & 4095;
  sum >>= 12;
  seed1 = (*seed >> 12) & 4095;
  mult1 = 406;
  sum += mult0 * seed1 + mult1 * seed0;
  newseed1 = sum & 4095;
  sum >>= 12;
  seed2 = (*seed >> 24) & 255;
  sum += mult0 * seed2 + mult1 * seed1;
  newseed2 = sum & 255;
  *seed = newseed2 << 24 | newseed1 << 12 | newseed0;
  res = 0.00390625 * (newseed2 + 0.000244140625 * (newseed1 + 0.000244140625 * newseed0));
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<randum>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rsi
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  movsd  D15(%rip),%xmm1
  mov    %eax,%r9d
  mov    %eax,%ecx
  shr    $0x18,%eax
  and    $0xfff,%r9d
  sar    $0xc,%ecx
  imul   $0x60d,%eax,%eax
  imul   $0x60d,%r9d,%edx
  and    $0xfff,%ecx
  imul   $0x196,%r9d,%r9d
  mov    %edx,%edi
  sar    $0xc,%edx
  mov    %edx,%r8d
  imul   $0x60d,%ecx,%edx
  and    $0xfff,%edi
  cvtsi2sd %edi,%xmm0
  imul   $0x196,%ecx,%ecx
  add    %r9d,%edx
  add    %r8d,%edx
  mulsd  %xmm1,%xmm0
  mov    %edx,%r8d
  add    %ecx,%eax
  sar    $0xc,%edx
  and    $0xfff,%r8d
  add    %edx,%eax
  cvtsi2sd %r8d,%xmm2
  movzbl %al,%ecx
  mov    %r8d,%edx
  shl    $0x18,%eax
  shl    $0xc,%edx
  or     %edi,%edx
  or     %edx,%eax
  addsd  %xmm2,%xmm0
  mov    %eax,(%rsi)
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D11(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
data_type: f64
name: unpack_data
arguments: data_tag: D11
data_type: f64

tool: D15: 0.000244140625

tool: D11: 0.00390625

assistant: ```c
double randum(int64_t *seed) {
  int64_t sum, mult0, mult1, seed0, seed1, seed2, newseed0, newseed1, newseed2;
  double res;
  mult0 = 1549;
  seed0 = *seed & 4095;
  sum = mult0 * seed0;
  newseed0 = sum & 4095;
  sum >>= 12;
  seed1 = (*seed >> 12) & 4095;
  mult1 = 406;
  sum += mult0 * seed1 + mult1 * seed0;
  newseed1 = sum & 4095;
  sum >>= 12;
  seed2 = (*seed >> 24) & 255;
  sum += mult0 * seed2 + mult1 * seed1;
  newseed2 = sum & 255;
  *seed = newseed2 << 24 | newseed1 << 12 | newseed0;
  res = 0.00390625 * (newseed2 + 0.000244140625 * (newseed1 + 0.000244140625 * newseed0));
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<reg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D7(%rip),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  lea    D23(%rip),%rdx
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    D7(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D18(%rip)
  mov    D18(%rip),%eax
  cmp    $0x4,%eax
  jne    L21
  movl   $0x0,D18(%rip)
L21:
  cmpl   $0x1,-0x14(%rbp)
  je     L15
  cmpl   $0x2,-0x14(%rbp)
  je     L44
  jmp    L23
L15:
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L25
L44:
  mov    -0x8(%rbp),%rax
  lea    D58(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L25
L23:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D55(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
L25:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D58
data_type: string
name: parse_data
arguments: data_tag: D55
data_type: string

tool: D18: $PC

tool: D58: $DPC

tool: D55: $%d

assistant: ```c
const char *reg(int R) {
  static char buffer[4][10];
  static int timer = 0;
  char *bp = buffer[timer];
  if (++timer == 4)
    timer = 0;
  switch (R) {
  case 1:
    strcpy(bp, "$PC");
    break;
  case 2:
    strcpy(bp, "$DPC");
    break;
  default:
    sprintf(bp, "$%d", R);
    break;
  }
  return bp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reg>:
  endbr64
  push   %rbx
  mov    D13(%rip),%ecx
  movslq %ecx,%rax
  lea    (%rax,%rax,4),%rsi
  lea    D7(%rip),%rax
  lea    (%rax,%rsi,2),%rbx
  lea    0x1(%rcx),%eax
  cmp    $0x3,%ecx
  mov    $0x0,%ecx
  cmove  %ecx,%eax
  mov    %eax,D1(%rip)
  cmp    $0x1,%edi
  je     L28
  cmp    $0x2,%edi
  je     L39
  mov    %edi,%edx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  jmp    L13
L28:
  lea    D44(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
L13:
  mov    %rbx,%rax
  pop    %rbx
  ret
L39:
  lea    D57(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L13
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D44
data_type: string
name: parse_data
arguments: tag: D57
data_type: string

tool: D1: $%d

tool: D44: $PC

tool: D57: $DPC

assistant: ```c
const char *reg(int R) {
  static char buffer[4][10];
  static int timer = 0;
  char *bp = buffer[timer];
  if (++timer == 4)
    timer = 0;
  switch (R) {
  case 1:
    strcpy(bp, "$PC");
    break;
  case 2:
    strcpy(bp, "$DPC");
    break;
  default:
    sprintf(bp, "$%d", R);
    break;
  }
  return bp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reg>:
  endbr64
  movslq D8(%rip),%rax
  push   %r12
  mov    %rax,%rcx
  lea    (%rax,%rax,4),%rsi
  lea    D42(%rip),%rax
  cmp    $0x3,%ecx
  lea    (%rax,%rsi,2),%r12
  lea    0x1(%rcx),%eax
  mov    $0x0,%ecx
  cmove  %ecx,%eax
  mov    %eax,D26(%rip)
  cmp    $0x1,%edi
  je     L15
  cmp    $0x2,%edi
  je     L1
  mov    %edi,%edx
  lea    D26(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  mov    %r12,%rdi
  lea    D55(%rip),%rsi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L1:
  mov    %r12,%rdi
  lea    D4(%rip),%rsi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D55
data_type: string
name: disassemble_data
arguments: label: D4
data_type: string

tool: D26: $%d

tool: D55: $PC

tool: D4: $DPC

assistant: ```c
const char *reg(int R) {
  static char buffer[4][10];
  static int timer = 0;
  char *bp = buffer[timer];
  if (++timer == 4)
    timer = 0;
  switch (R) {
  case 1:
    strcpy(bp, "$PC");
    break;
  case 2:
    strcpy(bp, "$DPC");
    break;
  default:
    sprintf(bp, "$%d", R);
    break;
  }
  return bp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reg>:
  endbr64
  movslq D1(%rip),%rax
  push   %r12
  mov    %rax,%rcx
  lea    (%rax,%rax,4),%rsi
  lea    D52(%rip),%rax
  cmp    $0x3,%ecx
  lea    (%rax,%rsi,2),%r12
  lea    0x1(%rcx),%eax
  mov    $0x0,%ecx
  cmove  %ecx,%eax
  mov    %eax,D56(%rip)
  cmp    $0x1,%edi
  je     L19
  cmp    $0x2,%edi
  je     L2
  mov    %edi,%edx
  lea    D56(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  mov    %r12,%rdi
  lea    D31(%rip),%rsi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L2:
  mov    %r12,%rdi
  lea    D54(%rip),%rsi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D56
type_guessed: string
name: disassemble_data
arguments: data_label: D31
type_guessed: string
name: disassemble_data
arguments: data_label: D54
type_guessed: string

tool: D56: $%d

tool: D31: $PC

tool: D54: $DPC

assistant: ```c
const char *reg(int R) {
  static char buffer[4][10];
  static int timer = 0;
  char *bp = buffer[timer];
  if (++timer == 4)
    timer = 0;
  switch (R) {
  case 1:
    strcpy(bp, "$PC");
    break;
  case 2:
    strcpy(bp, "$DPC");
    break;
  default:
    sprintf(bp, "$%d", R);
    break;
  }
  return bp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L12:
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L1:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L12
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D12: %i

tool: D3: %i%f

tool: D0: %.2f

assistant: ```c
int main(int argc, char *argv[]) {
  int a, i, c = 0, m = 0;
  float n = 0.0, tol = 0.0;
  scanf("%i", &a);
  for (i = 0; i < a; i++) {
    scanf("%i%f", &m, &n);
    tol += m * n;
    c += m;
  }
  printf("%.2f", tol / c);
  return 0;
}
```