ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dsc_copy_section>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rcx,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  test   %r9,%r9
  je     L40
  mov    %r9,%rdi
  mov    %rdx,0x8(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rsi
  mov    %eax,%r12d
L40:
  test   %rsi,%rsi
  js     L51
  xor    %edx,%edx
  mov    %rbp,%rdi
  call   <fseek@plt>
L51:
  lea    0x7(%rbx),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L96:
  mov    %rbp,%rdi
  call   <ftell@plt>
  cmp    %r13,%rax
  jge    L54
L8:
  mov    %rbp,%rdx
  mov    $0x102,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %r12d,%r12d
  je     L33
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L100
L33:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
  cmpb   $0x25,(%rbx)
  jne    L96
  cmpb   $0x25,0x1(%rbx)
  jne    L96
  mov    $0x5,%edx
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L96
  mov    0x8(%rsp),%rdi
  mov    $0x7,%edx
  lea    D10(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L38
  mov    %r14,%rdi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <copy_binary@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  cmp    %r13,%rax
  jl     L8
L54:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L100:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L38:
  mov    0x8(%rsp),%rdi
  mov    $0x5,%edx
  lea    D11(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L96
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <copy_data@plt>
  jmp    L96
```

tool_calls: name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D14: Begin

tool: D10: Binary:

tool: D11: Data:

assistant: ```c
int dsc_copy_section(FILE *from, FILE *to, long start, long end, char *line, const char *sentinel) {
  int sent_len = (sentinel == 0 ? 0 : strlen(sentinel));
  if (start >= 0)
    fseek(from, start, 0);
  while (ftell(from) < end) {
    long count;
    fgets(line, 258, from);
    if (sent_len) {
      if (!strncmp(line, sentinel, sent_len))
        return 1;
    }
    fputs(line, to);
    if (!(((line)[0] == '%' && (line)[1] == '%') && !strncmp(line, "Begin", sizeof("Begin") - 1)))
      ;
    else if (!strncmp(line + 7, "Binary:", sizeof("Binary:") - 1))
      copy_binary(to, from, line);
    else if (!strncmp(line + 7, "Data:", sizeof("Data:") - 1))
      copy_data(to, from, line);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x15(%rsp),%rbx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdx
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L37
  lea    0x15(%rsp),%rdi
  lea    D56(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L47
  lea    0x15(%rsp),%rdi
  lea    D42(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L100
  lea    0x15(%rsp),%rdi
  lea    D89(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L60
  lea    0x15(%rsp),%rdi
  lea    D110(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L53
  mov    0xc(%rsp),%eax
  cltd
  idivl  0x10(%rsp)
  mov    %edx,%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L37:
  mov    0x10(%rsp),%esi
  add    0xc(%rsp),%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L47:
  mov    0xc(%rsp),%esi
  sub    0x10(%rsp),%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L100:
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L60:
  mov    0xc(%rsp),%eax
  cltd
  idivl  0x10(%rsp)
  mov    %eax,%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L53:
  lea    D105(%rip),%rdi
  call   <puts@plt>
  jmp    L18
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D36
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D56
data_type: string
name: parse_data
arguments: data_tag: D42
data_type: string
name: parse_data
arguments: data_tag: D89
data_type: string
name: parse_data
arguments: data_tag: D110
data_type: string
name: parse_data
arguments: data_tag: D46
data_type: string
name: parse_data
arguments: data_tag: D105
data_type: string

tool: D36: %d %s %d

tool: D16: add

tool: D56: sub

tool: D42: mul

tool: D89: div

tool: D110: mod

tool: D46: rezultatut e %d


tool: D105: error

assistant: ```c
int main() {
  char str[3];
  int a, b, result;
  scanf("%d %s %d", &a, str, &b);
  if (!strcmp(str, "add")) {
    result = a + b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "sub")) {
    result = a - b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "mul")) {
    result = a * b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "div")) {
    result = a / b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "mod")) {
    result = a % b;
    printf("rezultatut e %d\n", result);
  } else
    printf("error\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x15(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D10
data_type: string

tool: D15: %d %s %d

tool: D10: error

assistant: ```c
int main() {
  char str[3];
  int a, b, result;
  scanf("%d %s %d", &a, str, &b);
  if (!strcmp(str, "add")) {
    result = a + b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "sub")) {
    result = a - b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "mul")) {
    result = a * b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "div")) {
    result = a / b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "mod")) {
    result = a % b;
    printf("rezultatut e %d\n", result);
  } else
    printf("error\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x15(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D14
type: string

tool: D2: %d %s %d

tool: D14: error

assistant: ```c
int main() {
  char str[3];
  int a, b, result;
  scanf("%d %s %d", &a, str, &b);
  if (!strcmp(str, "add")) {
    result = a + b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "sub")) {
    result = a - b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "mul")) {
    result = a * b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "div")) {
    result = a / b;
    printf("rezultatut e %d\n", result);
  } else if (!strcmp(str, "mod")) {
    result = a % b;
    printf("rezultatut e %d\n", result);
  } else
    printf("error\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8clen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0xbf,-0x1(%rbp)
  jbe    L5
  mov    $0x2,%edx
  jmp    L17
L5:
  mov    $0x1,%edx
L17:
  cmpb   $0xdf,-0x1(%rbp)
  seta   %al
  movzbl %al,%eax
  add    %eax,%edx
  cmpb   $0xef,-0x1(%rbp)
  seta   %al
  movzbl %al,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int utf8clen(const char *s) {
  unsigned char c = *s;
  return 1 + (c >= 0xC0) + (c >= 0xE0) + (c >= 0xF0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8clen>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0xbf,%dl
  seta   %cl
  movzbl %cl,%ecx
  cmp    $0xdf,%dl
  seta   %al
  movzbl %al,%eax
  lea    0x1(%rcx,%rax,1),%eax
  cmp    $0xef,%dl
  seta   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int utf8clen(const char *s) {
  unsigned char c = *s;
  return 1 + (c >= 0xC0) + (c >= 0xE0) + (c >= 0xF0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utf8clen>:
  endbr64
  movzbl (%rdi),%edx
  xor    %ecx,%ecx
  cmp    $0xbf,%dl
  seta   %cl
  xor    %eax,%eax
  cmp    $0xdf,%dl
  seta   %al
  cmp    $0xef,%dl
  seta   %dl
  lea    0x1(%rcx,%rax,1),%eax
  movzbl %dl,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int utf8clen(const char *s) {
  unsigned char c = *s;
  return 1 + (c >= 0xC0) + (c >= 0xE0) + (c >= 0xF0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8clen>:
  endbr64
  movzbl (%rdi),%edx
  xor    %ecx,%ecx
  cmp    $0xbf,%dl
  seta   %cl
  xor    %eax,%eax
  cmp    $0xdf,%dl
  seta   %al
  cmp    $0xef,%dl
  seta   %dl
  lea    0x1(%rcx,%rax,1),%eax
  movzbl %dl,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int utf8clen(const char *s) {
  unsigned char c = *s;
  return 1 + (c >= 0xC0) + (c >= 0xE0) + (c >= 0xF0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x9,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0x8,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0xd,-0x18(%rbp)
  movl   $0x11,-0x14(%rbp)
  movl   $0x17,-0x10(%rbp)
  movl   $0x30,-0xc(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L25:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%esi
  lea    -0x30(%rbp),%rax
  mov    $0xa,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <linear_search@plt>
  cmp    %eax,-0x34(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x34(%rbp)
L7:
  cmpl   $0x9,-0x34(%rbp)
  jle    L25
  lea    -0x30(%rbp),%rax
  mov    $0xa,%ecx
  mov    $0x0,%edx
  mov    $0x51,%esi
  mov    %rax,%rdi
  call   <linear_search@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int main() {
  int test_array[10] = {9, 2, 3, 5, 8, 7, 13, 17, 23, 48};
  for (int i = 0; i < 10; i++) {
    assert(i == linear_search(test_array, test_array[i], 0, 10));
  }
  assert(-1 == linear_search(test_array, 81, 0, 10));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x9,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x8,0x10(%rsp)
  movl   $0x7,0x14(%rsp)
  movl   $0xd,0x18(%rsp)
  movl   $0x11,0x1c(%rsp)
  movl   $0x17,0x20(%rsp)
  movl   $0x30,0x24(%rsp)
  mov    $0x0,%ebx
  mov    %rsp,%rbp
L16:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    $0xa,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <linear_search@plt>
  cmp    %ebx,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L16
  mov    %rsp,%rdi
  mov    $0xa,%ecx
  mov    $0x0,%edx
  mov    $0x51,%esi
  call   <linear_search@plt>
  cmp    $0xffffffff,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int test_array[10] = {9, 2, 3, 5, 8, 7, 13, 17, 23, 48};
  for (int i = 0; i < 10; i++) {
    assert(i == linear_search(test_array, test_array[i], 0, 10));
  }
  assert(-1 == linear_search(test_array, 81, 0, 10));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x9,%esi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000009,%rax
  mov    %rsp,%rbp
  mov    %rax,(%rsp)
  movabs $0x500000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x700000008,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x110000000d,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3000000017,%rax
  mov    %rax,0x20(%rsp)
  jmp    L27
  xchg   %ax,%ax
L3:
  mov    0x0(%rbp,%rbx,4),%esi
L27:
  xor    %edx,%edx
  mov    $0xa,%ecx
  mov    %rbp,%rdi
  call   <linear_search@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  sete   %dil
  add    $0x1,%rbx
  call   <assert@plt>
  cmp    $0xa,%rbx
  jne    L3
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    $0xa,%ecx
  mov    $0x51,%esi
  call   <linear_search@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int test_array[10] = {9, 2, 3, 5, 8, 7, 13, 17, 23, 48};
  for (int i = 0; i < 10; i++) {
    assert(i == linear_search(test_array, test_array[i], 0, 10));
  }
  assert(-1 == linear_search(test_array, 81, 0, 10));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movdqa D19(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L18:
  mov    0x0(%rbp,%rbx,4),%esi
  xor    %edx,%edx
  mov    $0xa,%ecx
  mov    %rbp,%rdi
  call   <linear_search@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  sete   %dil
  add    $0x1,%rbx
  call   <assert@plt>
  cmp    $0xa,%rbx
  jne    L18
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    $0xa,%ecx
  mov    $0x51,%esi
  call   <linear_search@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_guessed: byte[16]
name: unpack_data
arguments: tag: D15
type_guessed: byte[8]
name: unpack_data
arguments: tag: D19
type_guessed: byte[16]

tool: {"D11": [0x09,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D15": [0x17,0x00,0x00,0x00,0x30,0x00,0x00,0x00]}

tool: {"D19": [0x08,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int test_array[10] = {9, 2, 3, 5, 8, 7, 13, 17, 23, 48};
  for (int i = 0; i < 10; i++) {
    assert(i == linear_search(test_array, test_array[i], 0, 10));
  }
  assert(-1 == linear_search(test_array, 81, 0, 10));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_asn1_get_indefinite_length_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%esi
  test   %esi,%esi
  js     L80
  mov    %rdi,%rbp
  mov    $0x0,%r13d
  mov    $0x0,%r15d
  lea    0x10(%rsp),%r14
  jmp    L164
L61:
  lea    0x8(%rsp),%rcx
  lea    0x7(%rsp),%rdx
  sub    %r15d,%esi
  mov    %r14,%r8
  call   <asn1_get_tag_der@plt>
  test   %rax,%rax
  jne    L119
  add    0x8(%rsp),%r15d
  mov    (%r12),%esi
  cmp    %esi,%r15d
  jg     L121
  lea    0xc(%rsp),%rdx
  sub    %r15d,%esi
  movslq %r15d,%rdi
  add    %rbp,%rdi
  call   <asn1_get_length_der@plt>
  mov    %eax,0x8(%rsp)
  cmp    $0xffffffff,%eax
  jl     L139
  je     L78
  add    0xc(%rsp),%eax
  add    %eax,%r15d
L12:
  mov    (%r12),%esi
  cmp    %r15d,%esi
  jl     L148
L164:
  movslq %r15d,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  cmpb   $0x0,(%rdi)
  jne    L61
  cmpb   $0x0,0x1(%rbp,%rax,1)
  jne    L61
  add    $0x2,%r15d
  sub    $0x1,%r13d
  test   %r13d,%r13d
  jg     L12
  mov    %r15d,(%r12)
  mov    $0x0,%eax
L145:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L78:
  add    $0x1,%r13d
  add    $0x1,%r15d
  jmp    L12
L80:
  mov    $0x4,%eax
  jmp    L145
L148:
  mov    $0x4,%eax
  jmp    L145
L119:
  mov    $0x4,%eax
  jmp    L145
L121:
  mov    $0x4,%eax
  jmp    L145
L139:
  mov    $0x4,%eax
  jmp    L145
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _asn1_get_indefinite_length_string(const unsigned char *der, int *len) {
  int len2, len3, counter, indefinite;
  unsigned long tag;
  unsigned char class;
  counter = indefinite = 0;
  while (1) {
    if ((*len) < counter)
      return 4;
    if ((der[counter] == 0) && (der[counter + 1] == 0)) {
      counter += 2;
      indefinite--;
      if (indefinite <= 0)
        break;
      else
        continue;
    }
    if (asn1_get_tag_der(der + counter, *len - counter, &class, &len2, &tag) != 0)
      return 4;
    if (counter + len2 > *len)
      return 4;
    counter += len2;
    len2 = asn1_get_length_der(der + counter, *len - counter, &len3);
    if (len2 < -1)
      return 4;
    if (len2 == -1) {
      indefinite++;
      counter += 1;
    } else {
      counter += len2 + len3;
    }
  }
  *len = counter;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_asn1_get_indefinite_length_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    (%rsi),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  js     L97
  mov    %rdi,%rbp
  xor    %r13d,%r13d
  lea    0x10(%rsp),%r14
  xor    %ebx,%ebx
L38:
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  cmpb   $0x0,(%rdi)
  jne    L79
  cmpb   $0x0,0x1(%rbp,%rax,1)
  jne    L79
  sub    $0x1,%r13d
  add    $0x2,%ebx
  test   %r13d,%r13d
  jg     L64
  mov    %ebx,(%r12)
  xor    %eax,%eax
L129:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L103
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L79:
  sub    %ebx,%esi
  lea    0x8(%rsp),%rcx
  lea    0x7(%rsp),%rdx
  mov    %r14,%r8
  call   <asn1_get_tag_der@plt>
  test   %rax,%rax
  jne    L97
  mov    (%r12),%esi
  add    0x8(%rsp),%ebx
  cmp    %esi,%ebx
  jg     L97
  movslq %ebx,%rdi
  lea    0xc(%rsp),%rdx
  sub    %ebx,%esi
  add    %rbp,%rdi
  call   <asn1_get_length_der@plt>
  mov    %eax,0x8(%rsp)
  cmp    $0xffffffff,%eax
  jl     L97
  je     L115
  add    0xc(%rsp),%eax
  mov    (%r12),%esi
  add    %eax,%ebx
L64:
  cmp    %ebx,%esi
  jge    L38
  nopl   0x0(%rax)
L97:
  mov    $0x4,%eax
  jmp    L129
  nopw   0x0(%rax,%rax,1)
L115:
  mov    (%r12),%esi
  add    $0x1,%ebx
  add    $0x1,%r13d
  cmp    %ebx,%esi
  jge    L38
  jmp    L97
L103:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _asn1_get_indefinite_length_string(const unsigned char *der, int *len) {
  int len2, len3, counter, indefinite;
  unsigned long tag;
  unsigned char class;
  counter = indefinite = 0;
  while (1) {
    if ((*len) < counter)
      return 4;
    if ((der[counter] == 0) && (der[counter + 1] == 0)) {
      counter += 2;
      indefinite--;
      if (indefinite <= 0)
        break;
      else
        continue;
    }
    if (asn1_get_tag_der(der + counter, *len - counter, &class, &len2, &tag) != 0)
      return 4;
    if (counter + len2 > *len)
      return 4;
    counter += len2;
    len2 = asn1_get_length_der(der + counter, *len - counter, &len3);
    if (len2 < -1)
      return 4;
    if (len2 == -1) {
      indefinite++;
      counter += 1;
    } else {
      counter += len2 + len3;
    }
  }
  *len = counter;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_asn1_get_indefinite_length_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    (%rsi),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  js     L53
  mov    %rdi,%rbp
  xor    %r13d,%r13d
  lea    0x10(%rsp),%r14
  xor    %ebx,%ebx
L6:
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  cmpb   $0x0,(%rdi)
  jne    L83
  cmpb   $0x0,0x1(%rbp,%rax,1)
  jne    L83
  sub    $0x1,%r13d
  add    $0x2,%ebx
  test   %r13d,%r13d
  jg     L126
  mov    %ebx,(%r12)
  xor    %eax,%eax
L76:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L110
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L83:
  sub    %ebx,%esi
  lea    0x8(%rsp),%rcx
  lea    0x7(%rsp),%rdx
  mov    %r14,%r8
  call   <asn1_get_tag_der@plt>
  test   %rax,%rax
  jne    L53
  mov    (%r12),%esi
  add    0x8(%rsp),%ebx
  cmp    %esi,%ebx
  jg     L53
  movslq %ebx,%rdi
  lea    0xc(%rsp),%rdx
  sub    %ebx,%esi
  add    %rbp,%rdi
  call   <asn1_get_length_der@plt>
  mov    %eax,0x8(%rsp)
  cmp    $0xffffffff,%eax
  jl     L53
  mov    (%r12),%esi
  je     L70
  add    0xc(%rsp),%eax
  add    %eax,%ebx
L126:
  cmp    %esi,%ebx
  jle    L6
  nopl   0x0(%rax)
L53:
  mov    $0x4,%eax
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L70:
  add    $0x1,%ebx
  add    $0x1,%r13d
  cmp    %esi,%ebx
  jle    L6
  jmp    L53
L110:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _asn1_get_indefinite_length_string(const unsigned char *der, int *len) {
  int len2, len3, counter, indefinite;
  unsigned long tag;
  unsigned char class;
  counter = indefinite = 0;
  while (1) {
    if ((*len) < counter)
      return 4;
    if ((der[counter] == 0) && (der[counter + 1] == 0)) {
      counter += 2;
      indefinite--;
      if (indefinite <= 0)
        break;
      else
        continue;
    }
    if (asn1_get_tag_der(der + counter, *len - counter, &class, &len2, &tag) != 0)
      return 4;
    if (counter + len2 > *len)
      return 4;
    counter += len2;
    len2 = asn1_get_length_der(der + counter, *len - counter, &len3);
    if (len2 < -1)
      return 4;
    if (len2 == -1) {
      indefinite++;
      counter += 1;
    } else {
      counter += len2 + len3;
    }
  }
  *len = counter;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cfs_stub_lgetxattr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int64_t cfs_stub_lgetxattr(const char *path, const char *name, void *data, size_t size) {
  errno = ENOSYS;
  return -1;
}
```