ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  lea    D13(%rip),%r12
L2:
  mov    %rsp,%rdi
  mov    %r13,%rcx
  mov    $0x20,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  test   %rax,%rax
  je     L36
  mov    %rsp,%rbx
  lea    (%rax,%rbx,1),%rbp
L26:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L2
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string

tool: D3: r

tool: D13: %3u, 

assistant: ```c
int main(int argc, const char **argv) {
  FILE *f = fopen(argv[1], "r");
  unsigned char buffer[32];
  size_t s = 0;
  do {
    size_t a = 0;
    s = fread(buffer, sizeof(unsigned char), 32, f);
    for (a = 0; a < s; ++a) {
      printf("%3u, ", buffer[a]);
    }
    printf("\n");
  } while (s > 0);
  fclose(f);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    0x8(%rsi),%rdi
  lea    D18(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <fopen@plt>
  mov    %rax,%r14
  nopl   (%rax)
L4:
  mov    %r14,%rcx
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  test   %rax,%rax
  je     L0
  mov    %r13,%rbx
  lea    0x0(%r13,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L24:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L24
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
type: string
name: unpack_data
arguments: data_label: D18
type: string

tool: D12: %3u, 

tool: D18: r

assistant: ```c
int main(int argc, const char **argv) {
  FILE *f = fopen(argv[1], "r");
  unsigned char buffer[32];
  size_t s = 0;
  do {
    size_t a = 0;
    s = fread(buffer, sizeof(unsigned char), 32, f);
    for (a = 0; a < s; ++a) {
      printf("%3u, ", buffer[a]);
    }
    printf("\n");
  } while (s > 0);
  fclose(f);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    0x8(%rsi),%rdi
  lea    D12(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <fopen@plt>
  mov    %rax,%r14
  nopl   (%rax)
L34:
  mov    %r14,%rcx
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  test   %rax,%rax
  je     L11
  mov    %r13,%rbx
  lea    0x0(%r13,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L36:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L36
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type: string
name: parse_data
arguments: label: D12
type: string

tool: D10: %3u, 

tool: D12: r

assistant: ```c
int main(int argc, const char **argv) {
  FILE *f = fopen(argv[1], "r");
  unsigned char buffer[32];
  size_t s = 0;
  do {
    size_t a = 0;
    s = fread(buffer, sizeof(unsigned char), 32, f);
    for (a = 0; a < s; ++a) {
      printf("%3u, ", buffer[a]);
    }
    printf("\n");
  } while (s > 0);
  fclose(f);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<toUpperCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_strdup@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L14:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L28
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L28
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L28:
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *toUpperCase(char *str) {
  char *orgStr = _strdup(str);
  char *startStr = orgStr;
  while (*orgStr != '\0') {
    if ('a' <= *orgStr && *orgStr <= 'z') {
      *orgStr = 'A' + (*orgStr - 'a');
    }
    orgStr++;
  }
  return startStr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<toUpperCase>:
  endbr64
  sub    $0x8,%rsp
  call   <_strdup@plt>
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L14
  mov    %rax,%rcx
  jmp    L11
L39:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L14
L11:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L39
  sub    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L39
L14:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *toUpperCase(char *str) {
  char *orgStr = _strdup(str);
  char *startStr = orgStr;
  while (*orgStr != '\0') {
    if ('a' <= *orgStr && *orgStr <= 'z') {
      *orgStr = 'A' + (*orgStr - 'a');
    }
    orgStr++;
  }
  return startStr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<toUpperCase>:
  endbr64
  sub    $0x8,%rsp
  call   <_strdup@plt>
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L29
  mov    %rax,%rcx
  nopw   0x0(%rax,%rax,1)
L14:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L22
  sub    $0x20,%edx
  mov    %dl,(%rcx)
L22:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L14
L29:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *toUpperCase(char *str) {
  char *orgStr = _strdup(str);
  char *startStr = orgStr;
  while (*orgStr != '\0') {
    if ('a' <= *orgStr && *orgStr <= 'z') {
      *orgStr = 'A' + (*orgStr - 'a');
    }
    orgStr++;
  }
  return startStr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<toUpperCase>:
  endbr64
  sub    $0x8,%rsp
  call   <_strdup@plt>
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L25
  mov    %rax,%rcx
  nopw   0x0(%rax,%rax,1)
L2:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L11
  sub    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L2
L25:
  add    $0x8,%rsp
  ret
  nop
L11:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L2
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *toUpperCase(char *str) {
  char *orgStr = _strdup(str);
  char *startStr = orgStr;
  while (*orgStr != '\0') {
    if ('a' <= *orgStr && *orgStr <= 'z') {
      *orgStr = 'A' + (*orgStr - 'a');
    }
    orgStr++;
  }
  return startStr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<op_ED_0xa0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%esi
  mov    $0x4,%edi
  call   <LDI@plt>
  mov    $0xc,%edi
  call   <T_WAIT_UNTIL@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void op_ED_0xa0(void) {
  LDI(4, 7);
  T_WAIT_UNTIL(12);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<op_ED_0xa0>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x4,%edi
  call   <LDI@plt>
  mov    $0xc,%edi
  call   <T_WAIT_UNTIL@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void op_ED_0xa0(void) {
  LDI(4, 7);
  T_WAIT_UNTIL(12);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<op_ED_0xa0>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x7,%esi
  call   <LDI@plt>
  mov    $0xc,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_ED_0xa0(void) {
  LDI(4, 7);
  T_WAIT_UNTIL(12);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<op_ED_0xa0>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x7,%esi
  call   <LDI@plt>
  mov    $0xc,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_ED_0xa0(void) {
  LDI(4, 7);
  T_WAIT_UNTIL(12);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L25:
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x3,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x3(%rax),%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x2,-0x10(%rbp)
L14:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L25
  mov    -0xc(%rbp),%eax
  lea    -0xbc590a7(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      state[0UL] = state[local1] + state[0UL];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 792485636UL) + 594988637U;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x136ff696(%rax),%edx
  mov    %edx,%eax
  cmpl   $0x0,0x4(%rdi)
  je     L2
  mov    %edx,%ecx
  sar    $0x18,%ecx
  mov    %cl,%al
  shl    $0x18,%edx
  and    $0xffffff,%eax
  or     %edx,%eax
  add    %eax,%eax
L2:
  sub    $0xbc590a7,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      state[0UL] = state[local1] + state[0UL];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 792485636UL) + 594988637U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%ecx
  add    $0x136ff696,%eax
  mov    %eax,%edx
  test   %ecx,%ecx
  je     L5
  mov    %eax,%ecx
  shl    $0x18,%eax
  sar    $0x18,%ecx
  mov    %cl,%dl
  and    $0xffffff,%edx
  or     %eax,%edx
  lea    (%rdx,%rdx,1),%eax
L5:
  sub    $0xbc590a7,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      state[0UL] = state[local1] + state[0UL];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 792485636UL) + 594988637U;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%ecx
  add    $0x136ff696,%eax
  mov    %eax,%edx
  test   %ecx,%ecx
  je     L5
  mov    %eax,%ecx
  shl    $0x18,%eax
  sar    $0x18,%ecx
  mov    %cl,%dl
  and    $0xffffff,%edx
  or     %eax,%edx
  lea    (%rdx,%rdx,1),%eax
L5:
  sub    $0xbc590a7,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      state[0UL] = state[local1] + state[0UL];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 792485636UL) + 594988637U;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1b4(%rbp)
  movl   $0x64,-0x1b0(%rbp)
  lea    -0x1b8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1ac(%rbp)
  jmp    L26
L40:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1ac(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,-0x1b4(%rbp)
  jge    L9
  mov    -0x1ac(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1a8(%rbp)
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x1b4(%rbp)
L9:
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,-0x1b0(%rbp)
  jl     L43
  mov    -0x1ac(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1a4(%rbp)
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x1b0(%rbp)
L43:
  addl   $0x1,-0x1ac(%rbp)
L26:
  mov    -0x1b8(%rbp),%eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L40
  mov    -0x1a4(%rbp),%eax
  cmp    -0x1a8(%rbp),%eax
  jge    L19
  addl   $0x1,-0x1a4(%rbp)
L19:
  mov    -0x1a8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1b8(%rbp),%eax
  add    %edx,%eax
  sub    -0x1a4(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type: string
name: read_data
arguments: data_label: D18
type: string

tool: D6: %d

tool: D18: %d


assistant: ```c
int main() {
  int a[101], t, max = 0, min = 100, i, imax, imin;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &a[i]);
    if (a[i] > max) {
      imax = i + 1;
      max = a[i];
    }
    if (a[i] <= min) {
      imin = i + 1;
      min = a[i];
    }
  }
  if (imin < imax)
    imin++;
  printf("%d\n", imax - 1 + t - imin);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L14
  lea    0x20(%rsp),%rbp
  mov    $0x1,%ebx
  mov    $0x64,%r13d
  mov    $0x0,%r12d
  lea    D18(%rip),%r14
  jmp    L46
L19:
  mov    0x1c(%rsp),%eax
  add    $0x1,%rbx
  add    $0x4,%rbp
  lea    -0x1(%rbx),%edx
  cmp    %edx,%eax
  jle    L14
L46:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  cmp    %r12d,%eax
  jle    L12
  mov    %ebx,0xc(%rsp)
  mov    %eax,%r12d
L12:
  cmp    %r13d,%eax
  jg     L19
  mov    %ebx,%r15d
  mov    %eax,%r13d
  jmp    L19
L14:
  mov    0xc(%rsp),%ecx
  cmp    %r15d,%ecx
  setg   %dl
  movzbl %dl,%edx
  add    %edx,%r15d
  lea    -0x1(%rax,%rcx,1),%esi
  sub    %r15d,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D22
datatype: string

tool: D18: %d

tool: D22: %d


assistant: ```c
int main() {
  int a[101], t, max = 0, min = 100, i, imax, imin;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &a[i]);
    if (a[i] > max) {
      imax = i + 1;
      max = a[i];
    }
    if (a[i] <= min) {
      imin = i + 1;
      min = a[i];
    }
  }
  if (imin < imax)
    imin++;
  printf("%d\n", imax - 1 + t - imin);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L10
  lea    0x20(%rsp),%r15
  xor    %ebx,%ebx
  mov    $0x64,%r12d
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    (%r15),%eax
  cmp    %ebp,%eax
  jle    L23
  mov    %ebx,0xc(%rsp)
  mov    %eax,%ebp
L23:
  cmp    %r12d,%eax
  jg     L15
  mov    %ebx,%r14d
  mov    %eax,%r12d
L15:
  mov    0x1c(%rsp),%eax
  add    $0x4,%r15
  cmp    %ebx,%eax
  jg     L4
L10:
  mov    0xc(%rsp),%ecx
  xor    %edx,%edx
  lea    D18(%rip),%rdi
  cmp    %r14d,%ecx
  lea    -0x1(%rax,%rcx,1),%esi
  setg   %dl
  add    %edx,%r14d
  sub    %r14d,%esi
  call   <printf@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: string

tool: D5: %d

tool: D18: %d


assistant: ```c
int main() {
  int a[101], t, max = 0, min = 100, i, imax, imin;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &a[i]);
    if (a[i] > max) {
      imax = i + 1;
      max = a[i];
    }
    if (a[i] <= min) {
      imin = i + 1;
      min = a[i];
    }
  }
  if (imin < imax)
    imin++;
  printf("%d\n", imax - 1 + t - imin);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L18
  lea    0x20(%rsp),%r15
  xor    %ebx,%ebx
  mov    $0x64,%r12d
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    (%r15),%eax
  cmp    %ebp,%eax
  jle    L4
  mov    %ebx,0xc(%rsp)
  mov    %eax,%ebp
L4:
  cmp    %r12d,%eax
  jg     L8
  mov    %ebx,%r14d
  mov    %eax,%r12d
L8:
  mov    0x1c(%rsp),%eax
  add    $0x4,%r15
  cmp    %ebx,%eax
  jg     L13
L18:
  mov    0xc(%rsp),%ecx
  xor    %edx,%edx
  lea    D12(%rip),%rdi
  cmp    %r14d,%ecx
  lea    -0x1(%rax,%rcx,1),%esi
  setg   %dl
  add    %edx,%r14d
  sub    %r14d,%esi
  call   <printf@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D12
data_type: string

tool: D6: %d

tool: D12: %d


assistant: ```c
int main() {
  int a[101], t, max = 0, min = 100, i, imax, imin;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &a[i]);
    if (a[i] > max) {
      imax = i + 1;
      max = a[i];
    }
    if (a[i] <= min) {
      imin = i + 1;
      min = a[i];
    }
  }
  if (imin < imax)
    imin++;
  printf("%d\n", imax - 1 + t - imin);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bstrdup_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
L20:
  mov    $0x0,%eax
  jmp    L6
L16:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bmemdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
char *bstrdup_n(const char *str, size_t n) {
  char *dup;
  if (!str || !*str)
    return NULL;
  dup = (char *)bmemdup(str, n + 1);
  dup[n] = 0;
  return dup;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bstrdup_n>:
  endbr64
  test   %rdi,%rdi
  je     L15
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  je     L17
  lea    0x1(%rsi),%rsi
  call   <bmemdup@plt>
  movb   $0x0,(%rax,%rbx,1)
L17:
  pop    %rbx
  ret
L15:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *bstrdup_n(const char *str, size_t n) {
  char *dup;
  if (!str || !*str)
    return NULL;
  dup = (char *)bmemdup(str, n + 1);
  dup[n] = 0;
  return dup;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bstrdup_n>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L18
  cmpb   $0x0,(%rdi)
  je     L0
  push   %rbx
  mov    %rsi,%rbx
  lea    0x1(%rsi),%rsi
  call   <bmemdup@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
char *bstrdup_n(const char *str, size_t n) {
  char *dup;
  if (!str || !*str)
    return NULL;
  dup = (char *)bmemdup(str, n + 1);
  dup[n] = 0;
  return dup;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bstrdup_n>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L18
  cmpb   $0x0,(%rdi)
  je     L3
  push   %rbx
  mov    %rsi,%rbx
  lea    0x1(%rsi),%rsi
  call   <bmemdup@plt>
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
char *bstrdup_n(const char *str, size_t n) {
  char *dup;
  if (!str || !*str)
    return NULL;
  dup = (char *)bmemdup(str, n + 1);
  dup[n] = 0;
  return dup;
}
```