ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_tree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L10
  movl   $0x0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L26
L5:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  imul   %rdx,%rax
  sub    %rax,-0x30(%rbp)
  addl   $0x1,-0x18(%rbp)
  subl   $0x1,-0x14(%rbp)
L26:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  imul   %rdx,%rax
  cmp    %rax,-0x30(%rbp)
  jg     L5
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rsi
  cqto
  idiv   %rsi
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jle    L23
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <print_tree>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0x14(%rbp)
  jle    L45
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <print_tree>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L10:
  nop
L45:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D39
type_guessed: string

tool: D8: (

tool: D13: )

tool: D39: X

assistant: ```c
void print_tree(int node_num, long kth, long *tree_num) {
  if (node_num == 0) {
    return;
  }
  int left_num = 0;
  int right_num = node_num - 1;
  while (tree_num[left_num] * tree_num[right_num] < kth) {
    kth -= tree_num[left_num] * tree_num[right_num];
    left_num++;
    right_num--;
  }
  long left_state = (kth - 1) / tree_num[right_num] + 1;
  long right_state = ((kth - 1) % tree_num[right_num]) + 1;
  if (left_num > 0) {
    printf("(");
    print_tree(left_num, left_state, tree_num);
    printf(")");
  }
  printf("X");
  if (right_num > 0) {
    printf("(");
    print_tree(right_num, right_state, tree_num);
    printf(")");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_tree>:
  endbr64
  test   %edi,%edi
  je     L64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  lea    -0x1(%rdi),%r12d
  movslq %r12d,%rax
  mov    (%rdx,%rax,8),%r8
  mov    %r8,%rcx
  imul   (%rdx),%rcx
  cmp    %rcx,%rsi
  jle    L37
  sub    $0x2,%edi
  movslq %edi,%rdx
  mov    $0x1,%eax
L56:
  sub    %rcx,%rsi
  mov    %eax,%r13d
  mov    %edx,%r12d
  mov    (%rbx,%rdx,8),%rbp
  mov    %rbp,%rcx
  imul   (%rbx,%rax,8),%rcx
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %rsi,%rcx
  jl     L56
  lea    -0x1(%rsi),%r14
  mov    %r14,%rax
  cqto
  idiv   %rbp
  lea    0x1(%rdx),%r15
  test   %r13d,%r13d
  jg     L0
L48:
  lea    D40(%rip),%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  jg     L68
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rax
  cqto
  idiv   %rbp
  lea    0x1(%rax),%rsi
  mov    %rbx,%rdx
  mov    %r13d,%edi
  call   <print_tree>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  jmp    L48
L68:
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r12d,%edi
  call   <print_tree>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L37:
  lea    -0x1(%rsi),%rax
  cqto
  idiv   %r8
  lea    0x1(%rdx),%r15
  jmp    L48
L64:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D40
data_type: string
name: retrieve_data
arguments: label: D42
data_type: string
name: retrieve_data
arguments: label: D47
data_type: string

tool: D40: X

tool: D42: (

tool: D47: )

assistant: ```c
void print_tree(int node_num, long kth, long *tree_num) {
  if (node_num == 0) {
    return;
  }
  int left_num = 0;
  int right_num = node_num - 1;
  while (tree_num[left_num] * tree_num[right_num] < kth) {
    kth -= tree_num[left_num] * tree_num[right_num];
    left_num++;
    right_num--;
  }
  long left_state = (kth - 1) / tree_num[right_num] + 1;
  long right_state = ((kth - 1) % tree_num[right_num]) + 1;
  if (left_num > 0) {
    printf("(");
    print_tree(left_num, left_state, tree_num);
    printf(")");
  }
  printf("X");
  if (right_num > 0) {
    printf("(");
    print_tree(right_num, right_state, tree_num);
    printf(")");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_tree>:
  endbr64
  test   %edi,%edi
  je     L3
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    -0x1(%rdi),%ebp
  movslq %ebp,%rax
  push   %rbx
  mov    (%rdx,%rax,8),%rcx
  mov    (%rdx),%rax
  imul   %rcx,%rax
  cmp    %rax,%rsi
  jle    L6
  sub    $0x2,%edi
  mov    $0x1,%ecx
  movslq %edi,%rdx
  nopl   0x0(%rax)
L35:
  mov    (%r12,%rdx,8),%rdi
  sub    %rax,%rsi
  mov    (%r12,%rcx,8),%rax
  mov    %ecx,%r13d
  mov    %edx,%ebp
  add    $0x1,%rcx
  sub    $0x1,%rdx
  imul   %rdi,%rax
  cmp    %rsi,%rax
  jl     L35
  lea    -0x1(%rsi),%rax
  cqto
  idiv   %rdi
  lea    D6(%rip),%rdi
  mov    %rax,%rbx
  lea    0x1(%rdx),%r14
  call   <printf@plt>
  mov    %r13d,%edi
  lea    0x1(%rbx),%rsi
  mov    %r12,%rdx
  call   <print_tree>
  lea    D37(%rip),%rdi
  call   <printf@plt>
L1:
  lea    D40(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jg     L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L5:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <print_tree>
  pop    %rbx
  lea    D37(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopl   (%rax)
L3:
  ret
  nopl   0x0(%rax)
L6:
  lea    -0x1(%rsi),%rax
  cqto
  idiv   %rcx
  lea    0x1(%rdx),%r14
  jmp    L1
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D37
datatype: string
name: parse_data
arguments: data_label: D40
datatype: string

tool: D6: (

tool: D37: )

tool: D40: X

assistant: ```c
void print_tree(int node_num, long kth, long *tree_num) {
  if (node_num == 0) {
    return;
  }
  int left_num = 0;
  int right_num = node_num - 1;
  while (tree_num[left_num] * tree_num[right_num] < kth) {
    kth -= tree_num[left_num] * tree_num[right_num];
    left_num++;
    right_num--;
  }
  long left_state = (kth - 1) / tree_num[right_num] + 1;
  long right_state = ((kth - 1) % tree_num[right_num]) + 1;
  if (left_num > 0) {
    printf("(");
    print_tree(left_num, left_state, tree_num);
    printf(")");
  }
  printf("X");
  if (right_num > 0) {
    printf("(");
    print_tree(right_num, right_state, tree_num);
    printf(")");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_tree>:
  endbr64
  test   %edi,%edi
  je     L40
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    -0x1(%rdi),%ebp
  movslq %ebp,%rax
  push   %rbx
  mov    (%rdx,%rax,8),%rcx
  mov    (%rdx),%rax
  imul   %rcx,%rax
  cmp    %rax,%rsi
  jle    L5
  sub    $0x2,%edi
  mov    $0x1,%ecx
  movslq %edi,%rdx
  nopl   0x0(%rax)
L46:
  mov    (%r12,%rdx,8),%rdi
  sub    %rax,%rsi
  mov    (%r12,%rcx,8),%rax
  mov    %ecx,%r13d
  mov    %edx,%ebp
  add    $0x1,%rcx
  sub    $0x1,%rdx
  imul   %rdi,%rax
  cmp    %rsi,%rax
  jl     L46
  lea    -0x1(%rsi),%rax
  cqto
  idiv   %rdi
  lea    D15(%rip),%rdi
  mov    %rax,%rbx
  lea    0x1(%rdx),%r14
  call   <printf@plt>
  mov    %r13d,%edi
  lea    0x1(%rbx),%rsi
  mov    %r12,%rdx
  call   <print_tree>
  lea    D0(%rip),%rdi
  call   <printf@plt>
L18:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jg     L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <print_tree>
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopl   (%rax)
L40:
  ret
  nopl   0x0(%rax)
L5:
  lea    -0x1(%rsi),%rax
  cqto
  idiv   %rcx
  lea    0x1(%rdx),%r14
  jmp    L18
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D32
type_guessed: string

tool: D15: (

tool: D0: )

tool: D32: X

assistant: ```c
void print_tree(int node_num, long kth, long *tree_num) {
  if (node_num == 0) {
    return;
  }
  int left_num = 0;
  int right_num = node_num - 1;
  while (tree_num[left_num] * tree_num[right_num] < kth) {
    kth -= tree_num[left_num] * tree_num[right_num];
    left_num++;
    right_num--;
  }
  long left_state = (kth - 1) / tree_num[right_num] + 1;
  long right_state = ((kth - 1) % tree_num[right_num]) + 1;
  if (left_num > 0) {
    printf("(");
    print_tree(left_num, left_state, tree_num);
    printf(")");
  }
  printf("X");
  if (right_num > 0) {
    printf("(");
    print_tree(right_num, right_state, tree_num);
    printf(")");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_commands>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: uorb start
muorb_test start


assistant: ```c
const char *get_commands() {
  static const char *commands = "uorb start\n"
                                "muorb_test start\n";
  return commands;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_commands>:
  endbr64
  lea    D5(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string

tool: D5: uorb start
muorb_test start


assistant: ```c
const char *get_commands() {
  static const char *commands = "uorb start\n"
                                "muorb_test start\n";
  return commands;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_commands>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: uorb start
muorb_test start


assistant: ```c
const char *get_commands() {
  static const char *commands = "uorb start\n"
                                "muorb_test start\n";
  return commands;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xa8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_get_RAND@plt>
  mov    %rax,-0x98(%rbp)
  cmpq   $0x0,-0x98(%rbp)
  jne    L37
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L20
L37:
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <RAND_set_rand_method@plt>
  mov    %eax,-0x9c(%rbp)
  cmpl   $0x1,-0x9c(%rbp)
  je     L22
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L20
L22:
  lea    -0x90(%rbp),%rax
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x4,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <RAND_seed@plt>
  lea    -0x90(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <RAND_bytes@plt>
  lea    -0x90(%rbp),%rax
  mov    $0x80,%edx
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <hexdump@plt>
  mov    $0x0,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D37
type: string
name: parse_data
arguments: tag: D34
type: string
name: parse_data
arguments: tag: D20
type: string
name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D45
type: string

tool: D37: Testing Random Generator


tool: D34: Failed to get random method


tool: D20: Failed to set random method


tool: D8: test

tool: D45: Random Buffer

assistant: ```c
int test_rand(ENGINE *eg) {
  unsigned char buf[128];
  const RAND_METHOD *m;
  int r;
  printf("Testing Random Generator\n");
  m = ENGINE_get_RAND(eg);
  if (!m) {
    printf("Failed to get random method\n");
    return -1;
  }
  r = RAND_set_rand_method(m);
  if (r != 1) {
    printf("Failed to set random method\n");
    return -1;
  }
  memset(buf, 0, sizeof(buf));
  RAND_seed("test", 4);
  RAND_bytes(buf, sizeof(buf));
  hexdump("Random Buffer", buf, sizeof(buf));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_rand>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <ENGINE_get_RAND@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rdi
  call   <RAND_set_rand_method@plt>
  cmp    $0x1,%eax
  jne    L7
  mov    %rsp,%rbx
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x4,%esi
  lea    D14(%rip),%rdi
  call   <RAND_seed@plt>
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <RAND_bytes@plt>
  mov    $0x80,%edx
  mov    %rbx,%rsi
  lea    D36(%rip),%rdi
  call   <hexdump@plt>
  mov    $0x0,%eax
L32:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x90,%rsp
  pop    %rbx
  ret
L11:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L32
L7:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L32
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string
name: disassemble_data
arguments: label: D36
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D13
type_infered: string

tool: D17: Testing Random Generator


tool: D14: test

tool: D36: Random Buffer

tool: D18: Failed to get random method


tool: D13: Failed to set random method


assistant: ```c
int test_rand(ENGINE *eg) {
  unsigned char buf[128];
  const RAND_METHOD *m;
  int r;
  printf("Testing Random Generator\n");
  m = ENGINE_get_RAND(eg);
  if (!m) {
    printf("Failed to get random method\n");
    return -1;
  }
  r = RAND_set_rand_method(m);
  if (r != 1) {
    printf("Failed to set random method\n");
    return -1;
  }
  memset(buf, 0, sizeof(buf));
  RAND_seed("test", 4);
  RAND_bytes(buf, sizeof(buf));
  hexdump("Random Buffer", buf, sizeof(buf));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_rand>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D33(%rip),%rdi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <ENGINE_get_RAND@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  call   <RAND_set_rand_method@plt>
  cmp    $0x1,%eax
  jne    L13
  mov    %rsp,%rbp
  mov    $0x80,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x4,%esi
  lea    D7(%rip),%rdi
  call   <RAND_seed@plt>
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <RAND_bytes@plt>
  mov    $0x80,%edx
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  call   <hexdump@plt>
  xor    %eax,%eax
L17:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x90,%rsp
  pop    %rbp
  ret
  xchg   %ax,%ax
L13:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L17
L9:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L17
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D33
type_guessed: string
name: parse_data
arguments: label: D7
type_guessed: string
name: parse_data
arguments: label: D25
type_guessed: string
name: parse_data
arguments: label: D21
type_guessed: string
name: parse_data
arguments: label: D11
type_guessed: string

tool: D33: Testing Random Generator


tool: D7: test

tool: D25: Random Buffer

tool: D21: Failed to set random method


tool: D11: Failed to get random method


assistant: ```c
int test_rand(ENGINE *eg) {
  unsigned char buf[128];
  const RAND_METHOD *m;
  int r;
  printf("Testing Random Generator\n");
  m = ENGINE_get_RAND(eg);
  if (!m) {
    printf("Failed to get random method\n");
    return -1;
  }
  r = RAND_set_rand_method(m);
  if (r != 1) {
    printf("Failed to set random method\n");
    return -1;
  }
  memset(buf, 0, sizeof(buf));
  RAND_seed("test", 4);
  RAND_bytes(buf, sizeof(buf));
  hexdump("Random Buffer", buf, sizeof(buf));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_rand>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <ENGINE_get_RAND@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  call   <RAND_set_rand_method@plt>
  cmp    $0x1,%eax
  jne    L44
  mov    %rsp,%rbp
  mov    $0x80,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x4,%esi
  lea    D12(%rip),%rdi
  call   <RAND_seed@plt>
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <RAND_bytes@plt>
  mov    $0x80,%edx
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  call   <hexdump@plt>
  xor    %eax,%eax
L43:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x90,%rsp
  pop    %rbp
  ret
  xchg   %ax,%ax
L44:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L43
L14:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L43
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D23
type_guessed: string
name: retrieve_data
arguments: data_label: D45
type_guessed: string
name: retrieve_data
arguments: data_label: D33
type_guessed: string

tool: D7: Testing Random Generator


tool: D12: test

tool: D23: Random Buffer

tool: D45: Failed to set random method


tool: D33: Failed to get random method


assistant: ```c
int test_rand(ENGINE *eg) {
  unsigned char buf[128];
  const RAND_METHOD *m;
  int r;
  printf("Testing Random Generator\n");
  m = ENGINE_get_RAND(eg);
  if (!m) {
    printf("Failed to get random method\n");
    return -1;
  }
  r = RAND_set_rand_method(m);
  if (r != 1) {
    printf("Failed to set random method\n");
    return -1;
  }
  memset(buf, 0, sizeof(buf));
  RAND_seed("test", 4);
  RAND_bytes(buf, sizeof(buf));
  hexdump("Random Buffer", buf, sizeof(buf));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buildNewBoard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x3,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x4,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movb   $0x5,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movb   $0x6,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movb   $0x4,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  movb   $0x3,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  movb   $0x2,(%rax)
  movl   $0x0,-0x10(%rbp)
  movl   $0x8,-0xc(%rbp)
  jmp    L12
L21:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1,(%rax)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x7,-0x10(%rbp)
  jle    L21
  movl   $0x10,-0xc(%rbp)
  jmp    L41
L8:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L41:
  cmpl   $0x2f,-0xc(%rbp)
  jle    L8
  movl   $0x0,-0x10(%rbp)
  movl   $0x30,-0xc(%rbp)
  jmp    L20
L22:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x33,(%rax)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L20:
  cmpl   $0x7,-0x10(%rbp)
  jle    L22
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  movb   $0x34,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x39,%rax
  movb   $0x35,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3a,%rax
  movb   $0x36,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3b,%rax
  movb   $0x37,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3c,%rax
  movb   $0x38,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3d,%rax
  movb   $0x36,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3e,%rax
  movb   $0x35,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3f,%rax
  movb   $0x34,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *buildNewBoard() {
  int i, idx;
  char *board = (char *)malloc(64);
  board[0] = 2;
  board[1] = 3;
  board[2] = 4;
  board[3] = 5;
  board[4] = 6;
  board[5] = 4;
  board[6] = 3;
  board[7] = 2;
  for (i = 0, idx = 8; i < 8; i++, idx++)
    board[idx] = 1;
  for (idx = 16; idx < 48; idx++)
    board[idx] = 0;
  for (i = 0, idx = 48; i < 8; i++, idx++)
    board[idx] = 1 + 50;
  board[56] = 2 + 50;
  board[57] = 3 + 50;
  board[58] = 4 + 50;
  board[59] = 5 + 50;
  board[60] = 6 + 50;
  board[61] = 4 + 50;
  board[62] = 3 + 50;
  board[63] = 2 + 50;
  return board;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<buildNewBoard>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40,%edi
  call   <malloc@plt>
  movb   $0x2,(%rax)
  movb   $0x3,0x1(%rax)
  movb   $0x4,0x2(%rax)
  movb   $0x5,0x3(%rax)
  movb   $0x6,0x4(%rax)
  movb   $0x4,0x5(%rax)
  movb   $0x3,0x6(%rax)
  movb   $0x2,0x7(%rax)
  lea    0x8(%rax),%rcx
  lea    0x10(%rax),%rdx
L29:
  movb   $0x1,(%rcx)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L29
  lea    0x30(%rax),%rcx
L6:
  movb   $0x0,(%rdx)
  add    $0x1,%rdx
  cmp    %rdx,%rcx
  jne    L6
  lea    0x38(%rax),%rdx
L0:
  movb   $0x33,(%rcx)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L0
  movb   $0x34,0x38(%rax)
  movb   $0x35,0x39(%rax)
  movb   $0x36,0x3a(%rax)
  movb   $0x37,0x3b(%rax)
  movb   $0x38,0x3c(%rax)
  movb   $0x36,0x3d(%rax)
  movb   $0x35,0x3e(%rax)
  movb   $0x34,0x3f(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *buildNewBoard() {
  int i, idx;
  char *board = (char *)malloc(64);
  board[0] = 2;
  board[1] = 3;
  board[2] = 4;
  board[3] = 5;
  board[4] = 6;
  board[5] = 4;
  board[6] = 3;
  board[7] = 2;
  for (i = 0, idx = 8; i < 8; i++, idx++)
    board[idx] = 1;
  for (idx = 16; idx < 48; idx++)
    board[idx] = 0;
  for (i = 0, idx = 48; i < 8; i++, idx++)
    board[idx] = 1 + 50;
  board[56] = 2 + 50;
  board[57] = 3 + 50;
  board[58] = 4 + 50;
  board[59] = 5 + 50;
  board[60] = 6 + 50;
  board[61] = 4 + 50;
  board[62] = 3 + 50;
  board[63] = 2 + 50;
  return board;
}
```