ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<getFileNameFromCommand>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  movslq %eax,%rbx
L3:
  mov    %ebx,%r12d
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  mov    %eax,%edx
  test   %ebx,%ebx
  sete   %al
  test   %edx,%edx
  sete   %dl
  mov    %rbx,%r13
  sub    $0x1,%rbx
  or     %dl,%al
  jne    L3
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r13,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *getFileNameFromCommand(char *command) {
  int i = strlen(command);
  while (!isspace(command[i]) || i == 0) {
    i--;
  }
  char *nomeFile = malloc(i + 1);
  memcpy(nomeFile, command, i);
  nomeFile[i] = '\0';
  return nomeFile;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getFileNameFromCommand>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %ebx,%r12d
  mov    %rbx,%r13
  call   <isspace@plt>
  test   %eax,%eax
  sete   %al
  test   %ebx,%ebx
  sete   %dl
  sub    $0x1,%rbx
  or     %dl,%al
  jne    L6
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r14,%r13,1)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *getFileNameFromCommand(char *command) {
  int i = strlen(command);
  while (!isspace(command[i]) || i == 0) {
    i--;
  }
  char *nomeFile = malloc(i + 1);
  memcpy(nomeFile, command, i);
  nomeFile[i] = '\0';
  return nomeFile;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getFileNameFromCommand>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %ebx,%r12d
  mov    %rbx,%r13
  call   <isspace@plt>
  test   %eax,%eax
  sete   %al
  test   %ebx,%ebx
  sete   %dl
  sub    $0x1,%rbx
  or     %dl,%al
  jne    L6
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r14,%r13,1)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *getFileNameFromCommand(char *command) {
  int i = strlen(command);
  while (!isspace(command[i]) || i == 0) {
    i--;
  }
  char *nomeFile = malloc(i + 1);
  memcpy(nomeFile, command, i);
  nomeFile[i] = '\0';
  return nomeFile;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jne    L4
  movl   $0xf,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <fibo@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: Fibonacci of %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 2) {
    int n = 15;
    int res = fibo(n);
    printf("Fibonacci of %d is %d\n", n, res);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L0
  mov    $0x0,%eax
  ret
L0:
  sub    $0x8,%rsp
  mov    $0xf,%edi
  call   <fibo@plt>
  mov    %eax,%edx
  mov    $0xf,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D4: Fibonacci of %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 2) {
    int n = 15;
    int res = fibo(n);
    printf("Fibonacci of %d is %d\n", n, res);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L6
  xor    %eax,%eax
  ret
L6:
  push   %rax
  mov    $0xf,%edi
  call   <fibo@plt>
  mov    $0xf,%esi
  lea    D5(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5: Fibonacci of %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 2) {
    int n = 15;
    int res = fibo(n);
    printf("Fibonacci of %d is %d\n", n, res);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L9
  xor    %eax,%eax
  ret
L9:
  push   %rax
  mov    $0xf,%edi
  call   <fibo@plt>
  mov    $0xf,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6: Fibonacci of %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 2) {
    int n = 15;
    int res = fibo(n);
    printf("Fibonacci of %d is %d\n", n, res);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L66
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L53
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L12
L53:
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L12
L66:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L52
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L12
L52:
  mov    -0xc(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D13
datatype: string

tool: D9: %d

tool: D13: %d


assistant: ```c
main() {
  int i;
  scanf("%d", &i);
  if (i < 0) {
    if (i % 2 == 0)
      i *= 2;
    else
      i *= 4;
  } else {
    if (i % 2 == 0)
      i *= 8;
    else
      i *= 16;
  }
  printf("%d\n", i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L47
  test   $0x1,%sil
  jne    L28
  shl    $0x3,%esi
L63:
  mov    %esi,0x4(%rsp)
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L47:
  test   $0x1,%sil
  jne    L4
  add    %esi,%esi
  jmp    L63
L4:
  shl    $0x2,%esi
  jmp    L63
L28:
  shl    $0x4,%esi
  jmp    L63
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D15
type: string

tool: D5: %d

tool: D15: %d


assistant: ```c
main() {
  int i;
  scanf("%d", &i);
  if (i < 0) {
    if (i % 2 == 0)
      i *= 2;
    else
      i *= 4;
  } else {
    if (i % 2 == 0)
      i *= 8;
    else
      i *= 16;
  }
  printf("%d\n", i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L36
  test   $0x1,%sil
  je     L14
  shl    $0x4,%esi
L15:
  lea    D14(%rip),%rdi
  mov    %esi,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L14:
  shl    $0x3,%esi
  jmp    L15
L36:
  test   $0x1,%sil
  jne    L54
  add    %esi,%esi
  jmp    L15
L54:
  shl    $0x2,%esi
  jmp    L15
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string
name: retrieve_data
arguments: data_tag: D14
type: string

tool: D3: %d

tool: D14: %d


assistant: ```c
main() {
  int i;
  scanf("%d", &i);
  if (i < 0) {
    if (i % 2 == 0)
      i *= 2;
    else
      i *= 4;
  } else {
    if (i % 2 == 0)
      i *= 8;
    else
      i *= 16;
  }
  printf("%d\n", i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L4
  test   $0x1,%sil
  je     L51
  shl    $0x4,%esi
L48:
  lea    D9(%rip),%rdi
  mov    %esi,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L51:
  shl    $0x3,%esi
  jmp    L48
L4:
  test   $0x1,%sil
  jne    L15
  add    %esi,%esi
  jmp    L48
L15:
  shl    $0x2,%esi
  jmp    L48
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D2: %d

tool: D9: %d


assistant: ```c
main() {
  int i;
  scanf("%d", &i);
  if (i < 0) {
    if (i % 2 == 0)
      i *= 2;
    else
      i *= 4;
  } else {
    if (i % 2 == 0)
      i *= 8;
    else
      i *= 16;
  }
  printf("%d\n", i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%ecx
  mov    $0x1000,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <merge_flash@plt>
  mov    $0x0,%ecx
  mov    $0x8000,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <merge_flash@plt>
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0x0,%ecx
  mov    $0x10000,%edx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <merge_flash@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D61
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D20
type_infered: string
name: disassemble_data
arguments: data_label: D41
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D61: dd if=/dev/zero bs=1M count=4  | tr "\000" "\377" >  esp32flash.bin

tool: D8: esp32flash.bin

tool: D20: build/bootloader/bootloader.bin

tool: D41: build/partitions_singleapp.bin

tool: D9: cp esp32flash.bin ~/qemu_esp32

assistant: ```c
int main(int argc, char *argv[]) {
  system("dd if=/dev/zero bs=1M count=4  | tr \"\\000\" \"\\377\" >  esp32flash.bin");
  merge_flash("build/bootloader/bootloader.bin", "esp32flash.bin", 0x1000, 0);
  merge_flash("build/partitions_singleapp.bin", "esp32flash.bin", 0x8000, 0);
  merge_flash(argv[1], "esp32flash.bin", 0x10000, 0);
  system("cp esp32flash.bin ~/qemu_esp32");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    D41(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%ecx
  mov    $0x1000,%edx
  lea    D30(%rip),%rbx
  mov    %rbx,%rsi
  lea    D40(%rip),%rdi
  call   <merge_flash@plt>
  mov    $0x0,%ecx
  mov    $0x8000,%edx
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  call   <merge_flash@plt>
  mov    0x8(%rbp),%rdi
  mov    $0x0,%ecx
  mov    $0x10000,%edx
  mov    %rbx,%rsi
  call   <merge_flash@plt>
  lea    D46(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D41
datatype: string
name: parse_data
arguments: data_tag: D30
datatype: string
name: parse_data
arguments: data_tag: D40
datatype: string
name: parse_data
arguments: data_tag: D17
datatype: string
name: parse_data
arguments: data_tag: D46
datatype: string

tool: D41: dd if=/dev/zero bs=1M count=4  | tr "\000" "\377" >  esp32flash.bin

tool: D30: esp32flash.bin

tool: D40: build/bootloader/bootloader.bin

tool: D17: build/partitions_singleapp.bin

tool: D46: cp esp32flash.bin ~/qemu_esp32

assistant: ```c
int main(int argc, char *argv[]) {
  system("dd if=/dev/zero bs=1M count=4  | tr \"\\000\" \"\\377\" >  esp32flash.bin");
  merge_flash("build/bootloader/bootloader.bin", "esp32flash.bin", 0x1000, 0);
  merge_flash("build/partitions_singleapp.bin", "esp32flash.bin", 0x8000, 0);
  merge_flash(argv[1], "esp32flash.bin", 0x10000, 0);
  system("cp esp32flash.bin ~/qemu_esp32");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <system@plt>
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  mov    $0x1000,%edx
  lea    D46(%rip),%rdi
  call   <merge_flash@plt>
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  mov    $0x8000,%edx
  lea    D29(%rip),%rdi
  call   <merge_flash@plt>
  mov    0x8(%rbx),%rdi
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  mov    $0x10000,%edx
  call   <merge_flash@plt>
  lea    D10(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D6
datatype: string
name: read_data
arguments: label: D3
datatype: string
name: read_data
arguments: label: D46
datatype: string
name: read_data
arguments: label: D29
datatype: string
name: read_data
arguments: label: D10
datatype: string

tool: D6: dd if=/dev/zero bs=1M count=4  | tr "\000" "\377" >  esp32flash.bin

tool: D3: esp32flash.bin

tool: D46: build/bootloader/bootloader.bin

tool: D29: build/partitions_singleapp.bin

tool: D10: cp esp32flash.bin ~/qemu_esp32

assistant: ```c
int main(int argc, char *argv[]) {
  system("dd if=/dev/zero bs=1M count=4  | tr \"\\000\" \"\\377\" >  esp32flash.bin");
  merge_flash("build/bootloader/bootloader.bin", "esp32flash.bin", 0x1000, 0);
  merge_flash("build/partitions_singleapp.bin", "esp32flash.bin", 0x8000, 0);
  merge_flash(argv[1], "esp32flash.bin", 0x10000, 0);
  system("cp esp32flash.bin ~/qemu_esp32");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D43(%rip),%rdi
  lea    D10(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <system@plt>
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  mov    $0x1000,%edx
  lea    D18(%rip),%rdi
  call   <merge_flash@plt>
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  mov    $0x8000,%edx
  lea    D22(%rip),%rdi
  call   <merge_flash@plt>
  mov    0x8(%rbx),%rdi
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  mov    $0x10000,%edx
  call   <merge_flash@plt>
  lea    D3(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D43
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D22
datatype: string
name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D43: dd if=/dev/zero bs=1M count=4  | tr "\000" "\377" >  esp32flash.bin

tool: D10: esp32flash.bin

tool: D18: build/bootloader/bootloader.bin

tool: D22: build/partitions_singleapp.bin

tool: D3: cp esp32flash.bin ~/qemu_esp32

assistant: ```c
int main(int argc, char *argv[]) {
  system("dd if=/dev/zero bs=1M count=4  | tr \"\\000\" \"\\377\" >  esp32flash.bin");
  merge_flash("build/bootloader/bootloader.bin", "esp32flash.bin", 0x1000, 0);
  merge_flash("build/partitions_singleapp.bin", "esp32flash.bin", 0x8000, 0);
  merge_flash(argv[1], "esp32flash.bin", 0x10000, 0);
  system("cp esp32flash.bin ~/qemu_esp32");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<freeze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <FS460_image_request_freeze@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L7
  movl   $0x0,-0x10(%rbp)
  jmp    L33
L37:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <FS460_image_is_frozen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L33:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  je     L7
  cmpl   $0x0,-0xc(%rbp)
  je     L37
L7:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int freeze(int freeze_mode) {
  int err;
  int frozen;
  err = FS460_image_request_freeze(freeze_mode, freeze_mode, 0);
  if (!err) {
    frozen = 0;
    while ((frozen != freeze_mode) && !err) {
      err = FS460_image_is_frozen(&frozen);
      frozen &= freeze_mode;
    }
  }
  return err;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<freeze>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    %edi,%esi
  call   <FS460_image_request_freeze@plt>
  test   %eax,%eax
  jne    L12
  movl   $0x0,0x4(%rsp)
  test   %ebx,%ebx
  je     L30
  lea    0x4(%rsp),%rbp
L49:
  mov    %rbp,%rdi
  call   <FS460_image_is_frozen@plt>
  mov    %ebx,%edx
  and    0x4(%rsp),%edx
  mov    %edx,0x4(%rsp)
  cmp    %ebx,%edx
  je     L12
  test   %eax,%eax
  je     L49
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  mov    %ebx,%eax
  jmp    L12
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int freeze(int freeze_mode) {
  int err;
  int frozen;
  err = FS460_image_request_freeze(freeze_mode, freeze_mode, 0);
  if (!err) {
    frozen = 0;
    while ((frozen != freeze_mode) && !err) {
      err = FS460_image_is_frozen(&frozen);
      frozen &= freeze_mode;
    }
  }
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<freeze>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <FS460_image_request_freeze@plt>
  test   %eax,%eax
  jne    L8
  movl   $0x0,0x4(%rsp)
  test   %ebx,%ebx
  je     L8
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rdi
  call   <FS460_image_is_frozen@plt>
  mov    0x4(%rsp),%edx
  and    %ebx,%edx
  mov    %edx,0x4(%rsp)
  cmp    %ebx,%edx
  je     L8
  test   %eax,%eax
  je     L29
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int freeze(int freeze_mode) {
  int err;
  int frozen;
  err = FS460_image_request_freeze(freeze_mode, freeze_mode, 0);
  if (!err) {
    frozen = 0;
    while ((frozen != freeze_mode) && !err) {
      err = FS460_image_is_frozen(&frozen);
      frozen &= freeze_mode;
    }
  }
  return err;
}
```
user: What is the c source code of the assembly code below?

```asm
<freeze>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <FS460_image_request_freeze@plt>
  test   %eax,%eax
  jne    L24
  movl   $0x0,0x4(%rsp)
  test   %ebx,%ebx
  je     L24
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %rbp,%rdi
  call   <FS460_image_is_frozen@plt>
  mov    0x4(%rsp),%edx
  and    %ebx,%edx
  mov    %edx,0x4(%rsp)
  cmp    %ebx,%edx
  je     L24
  test   %eax,%eax
  je     L43
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int freeze(int freeze_mode) {
  int err;
  int frozen;
  err = FS460_image_request_freeze(freeze_mode, freeze_mode, 0);
  if (!err) {
    frozen = 0;
    while ((frozen != freeze_mode) && !err) {
      err = FS460_image_is_frozen(&frozen);
      frozen &= freeze_mode;
    }
  }
  return err;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L12
L28:
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L22
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  int j = strlen(haystack);
  for (int i = 0; i < j; i++) {
    if (needle == haystack[i]) {
      return &haystack[i];
    }
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L17
  mov    %rbp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rcx
L1:
  mov    %rdx,%rax
  cmp    %bl,(%rdx)
  je     L37
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L1
  mov    $0x0,%eax
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x0,%eax
  jmp    L37
```

assistant: ```c
char *find(char *haystack, char needle) {
  int j = strlen(haystack);
  for (int i = 0; i < j; i++) {
    if (needle == haystack[i]) {
      return &haystack[i];
    }
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<find>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L12
  mov    %eax,%edx
  mov    %rbx,%rax
  sub    $0x1,%edx
  lea    0x1(%rbx,%rdx,1),%rdx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L12
L2:
  cmp    %bpl,(%rax)
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  int j = strlen(haystack);
  for (int i = 0; i < j; i++) {
    if (needle == haystack[i]) {
      return &haystack[i];
    }
  }
  return NULL;
}
```