ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isconsonant>:
  endbr64
  or     $0x20,%edi
  xor    %eax,%eax
  lea    -0x61(%rdi),%ecx
  cmp    $0x1f,%ecx
  setbe  %al
  shl    %cl,%eax
  and    $0x3efbeee,%eax
  ret
```

assistant: ```c
int isconsonant(int c) {
  const unsigned letter_mask = (1 << ('b' - 'a')) | (1 << ('c' - 'a')) | (1 << ('d' - 'a')) | (1 << ('f' - 'a')) | (1 << ('g' - 'a')) | (1 << ('h' - 'a')) | (1 << ('j' - 'a')) | (1 << ('k' - 'a')) | (1 << ('l' - 'a')) | (1 << ('m' - 'a')) | (1 << ('n' - 'a')) | (1 << ('p' - 'a')) | (1 << ('q' - 'a')) | (1 << ('r' - 'a')) | (1 << ('s' - 'a')) | (1 << ('t' - 'a')) | (1 << ('v' - 'a')) | (1 << ('w' - 'a')) | (1 << ('x' - 'a')) | (1 << ('y' - 'a')) | (1 << ('z' - 'a'));
  unsigned x = (c | 32) - 'a';
  return ((x < 32) << (x & 31)) & letter_mask;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isconsonant>:
  endbr64
  or     $0x20,%edi
  xor    %eax,%eax
  lea    -0x61(%rdi),%ecx
  cmp    $0x1f,%ecx
  setbe  %al
  shl    %cl,%eax
  and    $0x3efbeee,%eax
  ret
```

assistant: ```c
int isconsonant(int c) {
  const unsigned letter_mask = (1 << ('b' - 'a')) | (1 << ('c' - 'a')) | (1 << ('d' - 'a')) | (1 << ('f' - 'a')) | (1 << ('g' - 'a')) | (1 << ('h' - 'a')) | (1 << ('j' - 'a')) | (1 << ('k' - 'a')) | (1 << ('l' - 'a')) | (1 << ('m' - 'a')) | (1 << ('n' - 'a')) | (1 << ('p' - 'a')) | (1 << ('q' - 'a')) | (1 << ('r' - 'a')) | (1 << ('s' - 'a')) | (1 << ('t' - 'a')) | (1 << ('v' - 'a')) | (1 << ('w' - 'a')) | (1 << ('x' - 'a')) | (1 << ('y' - 'a')) | (1 << ('z' - 'a'));
  unsigned x = (c | 32) - 'a';
  return ((x < 32) << (x & 31)) & letter_mask;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<append_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L2
  cmpl   $0x1,-0x18(%rbp)
  jne    L3
L2:
  mov    $0x1,%eax
  jmp    L29
L3:
  mov    $0x0,%eax
L29:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int append_bit(int n, int bit) {
  assert(bit == 0 || bit == 1);
  int new_n = n << 1;
  new_n = new_n | bit;
  return new_n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<append_bit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  cmp    $0x1,%esi
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    %ebp,%ebp
  mov    %ebx,%eax
  or     %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int append_bit(int n, int bit) {
  assert(bit == 0 || bit == 1);
  int new_n = n << 1;
  new_n = new_n | bit;
  return new_n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<append_bit>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  setbe  %dil
  add    %ebp,%ebp
  call   <assert@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  or     %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int append_bit(int n, int bit) {
  assert(bit == 0 || bit == 1);
  int new_n = n << 1;
  new_n = new_n | bit;
  return new_n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<append_bit>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  setbe  %dil
  add    %ebp,%ebp
  call   <assert@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  or     %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int append_bit(int n, int bit) {
  assert(bit == 0 || bit == 1);
  int new_n = n << 1;
  new_n = new_n | bit;
  return new_n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<EPIDMATxCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x400d0000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x400,-0x8(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x208,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void EPIDMATxCount(uint32_t ui32Base, uint32_t ui32Count) {
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32Count <= 1024);
  (*((volatile uint32_t *)(ui32Base + 0x00000208))) = ui32Count & 0xffff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EPIDMATxCount>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0x400d0000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  cmp    $0x400,%ebp
  setle  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x208,%ebx
  movslq %ebx,%rbx
  movzwl %bp,%ebp
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIDMATxCount(uint32_t ui32Base, uint32_t ui32Count) {
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32Count <= 1024);
  (*((volatile uint32_t *)(ui32Base + 0x00000208))) = ui32Count & 0xffff;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<EPIDMATxCount>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400d0000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x400,%ebp
  movzwl %bp,%ebp
  setle  %dil
  add    $0x208,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIDMATxCount(uint32_t ui32Base, uint32_t ui32Count) {
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32Count <= 1024);
  (*((volatile uint32_t *)(ui32Base + 0x00000208))) = ui32Count & 0xffff;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<EPIDMATxCount>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400d0000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x400,%ebp
  movzwl %bp,%ebp
  setle  %dil
  add    $0x208,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIDMATxCount(uint32_t ui32Base, uint32_t ui32Count) {
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32Count <= 1024);
  (*((volatile uint32_t *)(ui32Base + 0x00000208))) = ui32Count & 0xffff;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<esc_str_overhead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L5
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_char_width_esc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1b,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t esc_str_overhead(const char str[]) {
  size_t overhead = 0U;
  while (*str != '\0') {
    const size_t char_width_esc = get_char_width_esc(str);
    if (*str == '\033') {
      overhead += char_width_esc;
    }
    str += char_width_esc;
  }
  return overhead;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<esc_str_overhead>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L20
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L21:
  mov    %rbx,%rdi
  call   <get_char_width_esc@plt>
  lea    0x0(%rbp,%rax,1),%rdx
  cmpb   $0x1b,(%rbx)
  cmove  %rdx,%rbp
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L21
L0:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x0,%ebp
  jmp    L0
```

assistant: ```c
size_t esc_str_overhead(const char str[]) {
  size_t overhead = 0U;
  while (*str != '\0') {
    const size_t char_width_esc = get_char_width_esc(str);
    if (*str == '\033') {
      overhead += char_width_esc;
    }
    str += char_width_esc;
  }
  return overhead;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<esc_str_overhead>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L2
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %rbx,%rdi
  call   <get_char_width_esc@plt>
  cmpb   $0x1b,(%rbx)
  lea    (%r12,%rax,1),%rdx
  cmove  %rdx,%r12
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L7
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
size_t esc_str_overhead(const char str[]) {
  size_t overhead = 0U;
  while (*str != '\0') {
    const size_t char_width_esc = get_char_width_esc(str);
    if (*str == '\033') {
      overhead += char_width_esc;
    }
    str += char_width_esc;
  }
  return overhead;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<esc_str_overhead>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L0
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %rbx,%rdi
  call   <get_char_width_esc@plt>
  cmpb   $0x1b,(%rbx)
  lea    (%r12,%rax,1),%rdx
  cmove  %rdx,%r12
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L10
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
size_t esc_str_overhead(const char str[]) {
  size_t overhead = 0U;
  while (*str != '\0') {
    const size_t char_width_esc = get_char_width_esc(str);
    if (*str == '\033') {
      overhead += char_width_esc;
    }
    str += char_width_esc;
  }
  return overhead;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  struct {
    int x;
  } s = {0};
  return s.x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  struct {
    int x;
  } s = {0};
  return s.x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct {
    int x;
  } s = {0};
  return s.x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct {
    int x;
  } s = {0};
  return s.x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<base64_encode_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    %rax
  shl    $0x2,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L21
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L16
L21:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L28
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <base64_encode@plt>
L28:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
L16:
  leave
  ret
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (*out)
    base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base64_encode_alloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  lea    0x2(%rsi),%rdx
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%rbx
  lea    0x1(%rbx),%r14
  cmp    %r14,%rsi
  jbe    L3
  movq   $0x0,(%r12)
  mov    $0x0,%ebx
L4:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L4
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  jmp    L4
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (*out)
    base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<base64_encode_alloc>:
  endbr64
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  lea    0x2(%rsi),%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%r12
  lea    0x1(%r12),%r14
  cmp    %r14,%rsi
  jbe    L7
  movq   $0x0,(%rbx)
  xor    %r12d,%r12d
L5:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L7:
  mov    %rdi,%r13
  mov    %r14,%rdi
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdx
  test   %rax,%rax
  je     L5
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (*out)
    base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<base64_encode_alloc>:
  endbr64
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  lea    0x2(%rsi),%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%r12
  lea    0x1(%r12),%r14
  cmp    %r14,%rsi
  jbe    L11
  movq   $0x0,(%rbx)
  xor    %r12d,%r12d
L4:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L11:
  mov    %rdi,%r13
  mov    %r14,%rdi
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdx
  test   %rax,%rax
  je     L4
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (*out)
    base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eval_zinb_dfdp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edi,-0x24(%rbp)
  movsd  %xmm2,-0x30(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  test   %rax,%rax
  js     L0
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L13
L0:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L13:
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D56(%rip),%xmm0
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  movsd  D56(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D56(%rip),%xmm1
  subsd  -0x8(%rbp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x20(%rbp),%xmm2
  movsd  D56(%rip),%xmm1
  subsd  -0x8(%rbp),%xmm1
  mulsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D56(%rip),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x20(%rbp),%xmm2
  movsd  D56(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  -0x30(%rbp),%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   D24(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D56
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D24
type_guessed: byte[8]

tool: {"D56": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double eval_zinb_dfdp(double a, double p, unsigned int nz, double m) {
  const double ppa = pow(p, a);
  return -(nz * a * (1 - (a + 1) * ppa) / ((p * (1 - ppa)) * (p * (1 - ppa))) + m / ((1 - p) * (1 - p)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eval_zinb_dfdp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movapd %xmm1,%xmm6
  mov    %edi,%ebp
  movq   %xmm2,%rbx
  movsd  %xmm0,(%rsp)
  movapd %xmm0,%xmm1
  movsd  %xmm6,0x8(%rsp)
  movapd %xmm6,%xmm0
  call   <pow@plt>
  movsd  D4(%rip),%xmm1
  movapd %xmm1,%xmm2
  subsd  %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm6
  mulsd  %xmm6,%xmm2
  movapd %xmm1,%xmm3
  subsd  %xmm6,%xmm3
  movsd  (%rsp),%xmm5
  movapd %xmm5,%xmm4
  addsd  %xmm1,%xmm4
  mulsd  %xmm4,%xmm0
  subsd  %xmm0,%xmm1
  mov    %ebp,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbp,%xmm0
  mulsd  %xmm5,%xmm0
  mulsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm2
  divsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm3
  movq   %rbx,%xmm2
  divsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm1
  xorpd  D9(%rip),%xmm1
  movapd %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: byte[8]
name: unpack_data
arguments: data_label: D9
type: byte[16]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double eval_zinb_dfdp(double a, double p, unsigned int nz, double m) {
  const double ppa = pow(p, a);
  return -(nz * a * (1 - (a + 1) * ppa) / ((p * (1 - ppa)) * (p * (1 - ppa))) + m / ((1 - p) * (1 - p)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eval_zinb_dfdp>:
  endbr64
  push   %rbx
  movapd %xmm1,%xmm6
  movapd %xmm0,%xmm1
  mov    %edi,%ebx
  sub    $0x20,%rsp
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm6,%xmm0
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm6,0x8(%rsp)
  call   <pow@plt>
  movsd  D9(%rip),%xmm3
  movsd  0x8(%rsp),%xmm6
  movsd  0x10(%rsp),%xmm5
  movsd  0x18(%rsp),%xmm2
  movapd %xmm3,%xmm4
  movapd %xmm3,%xmm1
  subsd  %xmm0,%xmm4
  subsd  %xmm6,%xmm1
  mulsd  %xmm6,%xmm4
  movapd %xmm5,%xmm6
  addsd  %xmm3,%xmm6
  mulsd  %xmm1,%xmm1
  mulsd  %xmm6,%xmm0
  mulsd  %xmm4,%xmm4
  divsd  %xmm1,%xmm2
  subsd  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  mulsd  %xmm5,%xmm0
  mulsd  %xmm0,%xmm3
  divsd  %xmm4,%xmm3
  addsd  %xmm2,%xmm3
  xorpd  D19(%rip),%xmm3
  add    $0x20,%rsp
  pop    %rbx
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D19
datatype: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double eval_zinb_dfdp(double a, double p, unsigned int nz, double m) {
  const double ppa = pow(p, a);
  return -(nz * a * (1 - (a + 1) * ppa) / ((p * (1 - ppa)) * (p * (1 - ppa))) + m / ((1 - p) * (1 - p)));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<eval_zinb_dfdp>:
  endbr64
  push   %rbx
  movapd %xmm1,%xmm6
  movapd %xmm0,%xmm1
  mov    %edi,%ebx
  sub    $0x20,%rsp
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm6,%xmm0
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm6,0x8(%rsp)
  call   <pow@plt>
  movsd  D10(%rip),%xmm3
  movsd  0x8(%rsp),%xmm6
  movsd  0x10(%rsp),%xmm5
  movsd  0x18(%rsp),%xmm2
  movapd %xmm3,%xmm4
  movapd %xmm3,%xmm1
  subsd  %xmm0,%xmm4
  subsd  %xmm6,%xmm1
  mulsd  %xmm6,%xmm4
  movapd %xmm5,%xmm6
  addsd  %xmm3,%xmm6
  mulsd  %xmm1,%xmm1
  mulsd  %xmm6,%xmm0
  mulsd  %xmm4,%xmm4
  divsd  %xmm1,%xmm2
  subsd  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  mulsd  %xmm5,%xmm0
  mulsd  %xmm0,%xmm3
  divsd  %xmm4,%xmm3
  addsd  %xmm2,%xmm3
  xorpd  D7(%rip),%xmm3
  add    $0x20,%rsp
  pop    %rbx
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
data_type: byte[8]
name: read_data
arguments: data_tag: D7
data_type: byte[16]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double eval_zinb_dfdp(double a, double p, unsigned int nz, double m) {
  const double ppa = pow(p, a);
  return -(nz * a * (1 - (a + 1) * ppa) / ((p * (1 - ppa)) * (p * (1 - ppa))) + m / ((1 - p) * (1 - p)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L0
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x18(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    -0x28(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rax,%rdi
  call   <xml_utf8_encode@plt>
  mov    %rax,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: ISO-8859-1

assistant: ```c
char *utf8_encode(const char *str) {
  char *out;
  if (strlen(str)) {
    int alen, len;
    alen = strlen(str);
    out = xml_utf8_encode(str, alen, &len, "ISO-8859-1");
  }
  return out;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utf8_encode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jne    L22
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    0x4(%rsp),%rdx
  lea    D3(%rip),%rcx
  mov    %rbx,%rdi
  call   <xml_utf8_encode@plt>
  mov    %rax,%rbp
  jmp    L13
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: ISO-8859-1

assistant: ```c
char *utf8_encode(const char *str) {
  char *out;
  if (strlen(str)) {
    int alen, len;
    alen = strlen(str);
    out = xml_utf8_encode(str, alen, &len, "ISO-8859-1");
  }
  return out;
}
```