ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0x14(%rbp)
  jmp    L2
L16:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L36
  mov    -0x14(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L36
  addl   $0x1,-0x10(%rbp)
L36:
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L16
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: %d

assistant: ```c
int main() {
  int j, n, c;
  int count = 0;
  scanf("%d", &n);
  for (j = 2; j <= n; j++) {
    c = check_prime(j);
    if (c == 1) {
      c = check_prime(j + 2);
      if (c == 1) {
        count = count + 1;
      }
    }
  }
  printf("%d", count);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L7
  mov    $0x0,%ebp
  mov    $0x2,%ebx
  jmp    L18
L28:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L38
L18:
  mov    %ebx,%edi
  call   <check_prime@plt>
  cmp    $0x1,%eax
  jne    L28
  lea    0x2(%rbx),%edi
  call   <check_prime@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebp
  jmp    L28
L7:
  mov    $0x0,%ebp
L38:
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type: string

tool: D13: %d

assistant: ```c
int main() {
  int j, n, c;
  int count = 0;
  scanf("%d", &n);
  for (j = 2; j <= n; j++) {
    c = check_prime(j);
    if (c == 1) {
      c = check_prime(j + 2);
      if (c == 1) {
        count = count + 1;
      }
    }
  }
  printf("%d", count);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L53
  mov    $0x2,%ebx
  jmp    L58
L12:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L53
L58:
  mov    %ebx,%edi
  call   <check_prime@plt>
  cmp    $0x1,%eax
  jne    L12
  lea    0x2(%rbx),%edi
  call   <check_prime@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  cmp    %ebx,0x4(%rsp)
  jge    L58
  nopl   0x0(%rax)
L53:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int main() {
  int j, n, c;
  int count = 0;
  scanf("%d", &n);
  for (j = 2; j <= n; j++) {
    c = check_prime(j);
    if (c == 1) {
      c = check_prime(j + 2);
      if (c == 1) {
        count = count + 1;
      }
    }
  }
  printf("%d", count);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L9
  mov    $0x2,%ebx
  jmp    L30
L28:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L9
L30:
  mov    %ebx,%edi
  call   <check_prime@plt>
  cmp    $0x1,%eax
  jne    L28
  lea    0x2(%rbx),%edi
  call   <check_prime@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  cmp    %ebx,0x4(%rsp)
  jge    L30
  nopl   0x0(%rax)
L9:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int main() {
  int j, n, c;
  int count = 0;
  scanf("%d", &n);
  for (j = 2; j <= n; j++) {
    c = check_prime(j);
    if (c == 1) {
      c = check_prime(j + 2);
      if (c == 1) {
        count = count + 1;
      }
    }
  }
  printf("%d", count);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reduce>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L10:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L10
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int reduce(char **in, char op) {
  int i;
  for (i = 0; (*in)[i] == op; i++)
    ;
  *in += i - 1;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reduce>:
  endbr64
  mov    %esi,%r8d
  mov    (%rdi),%rdx
  cmp    (%rdx),%sil
  jne    L5
  mov    $0x1,%eax
L3:
  mov    %eax,%ecx
  mov    %rax,%rsi
  add    $0x1,%rax
  cmp    %r8b,-0x1(%rdx,%rax,1)
  je     L3
L29:
  lea    -0x1(%rdx,%rsi,1),%rax
  mov    %rax,(%rdi)
  mov    %ecx,%eax
  ret
L5:
  mov    $0x0,%ecx
  mov    $0x0,%esi
  jmp    L29
```

assistant: ```c
int reduce(char **in, char op) {
  int i;
  for (i = 0; (*in)[i] == op; i++)
    ;
  *in += i - 1;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reduce>:
  endbr64
  mov    (%rdi),%rdx
  mov    %esi,%r9d
  cmp    (%rdx),%sil
  jne    L8
  mov    $0x1,%eax
  nopl   0x0(%rax)
L14:
  mov    %eax,%r8d
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %r9b,-0x1(%rdx,%rax,1)
  je     L14
  sub    $0x1,%rcx
  mov    %r8d,%eax
  add    %rcx,%rdx
  mov    %rdx,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffffffffffff,%rcx
  xor    %r8d,%r8d
  add    %rcx,%rdx
  mov    %r8d,%eax
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
int reduce(char **in, char op) {
  int i;
  for (i = 0; (*in)[i] == op; i++)
    ;
  *in += i - 1;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reduce>:
  endbr64
  mov    (%rdi),%rdx
  mov    %esi,%r9d
  cmp    (%rdx),%sil
  jne    L7
  mov    $0x1,%eax
  nopl   0x0(%rax)
L2:
  mov    %eax,%r8d
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %r9b,-0x1(%rdx,%rax,1)
  je     L2
  sub    $0x1,%rcx
  mov    %r8d,%eax
  add    %rcx,%rdx
  mov    %rdx,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffffffffffff,%rcx
  xor    %r8d,%r8d
  add    %rcx,%rdx
  mov    %r8d,%eax
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
int reduce(char **in, char op) {
  int i;
  for (i = 0; (*in)[i] == op; i++)
    ;
  *in += i - 1;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0xa,-0x44(%rbp)
  jg     L12
  mov    $0x1,%eax
  jmp    L8
L12:
  movl   $0x1,-0x34(%rbp)
  jmp    L9
L59:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    -0x34(%rbp),%edx
  lea    -0x1(%rdx),%ecx
  movsbl %al,%edx
  movslq %ecx,%rax
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L9:
  mov    -0x34(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L59
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L33
L47:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L33:
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x34(%rbp)
  jl     L47
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D7
type_infered: string

tool: D3: After merge sorting elements are: 

tool: D7: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 11)
    return 1;
  int merge[10], i;
  for (i = 1; i < argc; i++)
    merge[i - 1] = argv[i][0];
  partition(merge, 0, argc - 1);
  printf("After merge sorting elements are: ");
  for (i = 0; i < argc - 1; i++) {
    printf("%d ", merge[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0xa,%edi
  jle    L2
  lea    -0x2(%rdi),%ebp
  mov    %edi,%edx
  mov    $0x1,%eax
L22:
  mov    (%rsi,%rax,8),%rcx
  movsbl (%rcx),%ecx
  mov    %ecx,-0x4(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L22
  lea    -0x1(%rdi),%edx
  mov    %rsp,%rbx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <partition@plt>
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp,%rbp,4),%r12
  lea    D17(%rip),%rbp
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L19
  mov    $0x0,%eax
L2:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string

tool: D10: After merge sorting elements are: 

tool: D17: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 11)
    return 1;
  int merge[10], i;
  for (i = 1; i < argc; i++)
    merge[i - 1] = argv[i][0];
  partition(merge, 0, argc - 1);
  printf("After merge sorting elements are: ");
  for (i = 0; i < argc - 1; i++) {
    printf("%d ", merge[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0xa,%edi
  jle    L36
  movslq %edi,%rdi
  mov    $0x1,%eax
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L17:
  mov    (%rsi,%rax,8),%rdx
  movsbl (%rdx),%edx
  mov    %edx,-0x4(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L17
  mov    $0xa,%edx
  xor    %esi,%esi
  lea    0x28(%rsp),%r12
  mov    %rbx,%rdi
  call   <partition@plt>
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  lea    D16(%rip),%rbp
  call   <printf@plt>
  nopl   (%rax)
L31:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L31
  xor    %eax,%eax
L36:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D16
datatype: string

tool: D1: After merge sorting elements are: 

tool: D16: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 11)
    return 1;
  int merge[10], i;
  for (i = 1; i < argc; i++)
    merge[i - 1] = argv[i][0];
  partition(merge, 0, argc - 1);
  printf("After merge sorting elements are: ");
  for (i = 0; i < argc - 1; i++) {
    printf("%d ", merge[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%r8d
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  cmp    $0xa,%edi
  jle    L2
  mov    0x8(%rsi),%rdx
  mov    0x50(%rsi),%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rdi
  lea    D14(%rip),%rbp
  movsbl (%rdx),%edx
  mov    %edx,(%rsp)
  mov    0x10(%rsi),%rdx
  movsbl (%rdx),%edx
  mov    %edx,0x4(%rsp)
  mov    0x18(%rsi),%rdx
  movsbl (%rdx),%edx
  mov    %edx,0x8(%rsp)
  mov    0x20(%rsi),%rdx
  movsbl (%rdx),%edx
  mov    %edx,0xc(%rsp)
  mov    0x28(%rsi),%rdx
  movsbl (%rdx),%edx
  mov    %edx,0x10(%rsp)
  mov    0x30(%rsi),%rdx
  movsbl (%rdx),%edx
  mov    %edx,0x14(%rsp)
  mov    0x38(%rsi),%rdx
  movsbl (%rdx),%edx
  mov    %edx,0x18(%rsp)
  mov    0x40(%rsi),%rdx
  movsbl (%rdx),%edx
  mov    %edx,0x1c(%rsp)
  mov    0x48(%rsi),%rdx
  xor    %esi,%esi
  movsbl (%rdx),%edx
  mov    %edx,0x20(%rsp)
  movsbl (%rax),%eax
  mov    $0xa,%edx
  mov    %eax,0x24(%rsp)
  call   <partition@plt>
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L0
  xor    %r8d,%r8d
L2:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D11
type: string

tool: D14: %d 

tool: D11: After merge sorting elements are: 

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 11)
    return 1;
  int merge[10], i;
  for (i = 1; i < argc; i++)
    merge[i - 1] = argv[i][0];
  partition(merge, 0, argc - 1);
  printf("After merge sorting elements are: ");
  for (i = 0; i < argc - 1; i++) {
    printf("%d ", merge[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vlprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x5b,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L14:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L4
  lea    D24(%rip),%rax
  jmp    L26
L4:
  lea    D17(%rip),%rax
L26:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rdx
  mov    %rax,%rsi
  movq   %rdx,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D24
type_guessed: string
name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D29
type_guessed: string

tool: D24: ]


tool: D17: ;

tool: D29: %lf%s

assistant: ```c
void vlprint(int l, double v[l]) {
  printf("[");
  for (int i = 0; i < l; i++) {
    printf("%lf%s", v[i], (i == (l - 1)) ? "]\n" : ";");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<vlprint>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    $0x5b,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L1
  mov    %ebp,%r15d
  mov    $0x0,%ebx
  sub    $0x1,%ebp
  lea    D13(%rip),%r14
  lea    D22(%rip),%r13
L11:
  cmp    %ebx,%ebp
  mov    %r13,%rsi
  cmove  %r14,%rsi
  movsd  (%r12,%rbx,8),%xmm0
  lea    D1(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L11
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D22
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string

tool: D13: ]


tool: D22: ;

tool: D1: %lf%s

assistant: ```c
void vlprint(int l, double v[l]) {
  printf("[");
  for (int i = 0; i < l; i++) {
    printf("%lf%s", v[i], (i == (l - 1)) ? "]\n" : ";");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vlprint>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edi,%rbx
  mov    $0x5b,%edi
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %ebx,%ebx
  jle    L11
  lea    -0x1(%rbx),%r15d
  xor    %r12d,%r12d
  lea    D4(%rip),%r14
  lea    D29(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L17:
  cmp    %r12d,%r15d
  lea    D16(%rip),%rsi
  mov    %r14,%rdi
  mov    $0x1,%eax
  cmovne %r13,%rsi
  movsd  0x0(%rbp,%r12,8),%xmm0
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L17
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D29
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string

tool: D4: %lf%s

tool: D29: ;

tool: D16: ]


assistant: ```c
void vlprint(int l, double v[l]) {
  printf("[");
  for (int i = 0; i < l; i++) {
    printf("%lf%s", v[i], (i == (l - 1)) ? "]\n" : ";");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vlprint>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edi,%rbx
  mov    $0x5b,%edi
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %ebx,%ebx
  jle    L28
  lea    -0x1(%rbx),%r13d
  xor    %r15d,%r15d
  lea    D7(%rip),%r12
  lea    D10(%rip),%r14
  jmp    L30
  nopl   (%rax)
L27:
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  je     L28
L30:
  movsd  0x0(%rbp,%r15,8),%xmm0
  mov    %r14,%rsi
  cmp    %r15d,%r13d
  jne    L27
  lea    D18(%rip),%rsi
  jmp    L27
  xchg   %ax,%ax
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string
name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D18
datatype: string

tool: D7: %lf%s

tool: D10: ;

tool: D18: ]


assistant: ```c
void vlprint(int l, double v[l]) {
  printf("[");
  for (int i = 0; i < l; i++) {
    printf("%lf%s", v[i], (i == (l - 1)) ? "]\n" : ";");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D5
datatype: string

tool: D0: Hello argv!

tool: D2: argc len = %d


tool: D5: argv[ %d ] = %s


assistant: ```c
int main(int argc, char **argv) {
  printf("Hello argv!\n");
  printf("argc len = %d\n", argc);
  for (int i = 0; i < argc; ++i) {
    printf("argv[ %d ] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L15
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D21(%rip),%r13
L19:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L19
L15:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D13
type_infered: string
name: parse_data
arguments: tag: D21
type_infered: string

tool: D8: Hello argv!

tool: D13: argc len = %d


tool: D21: argv[ %d ] = %s


assistant: ```c
int main(int argc, char **argv) {
  printf("Hello argv!\n");
  printf("argc len = %d\n", argc);
  for (int i = 0; i < argc; ++i) {
    printf("argv[ %d ] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D7(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L15
  xor    %ebx,%ebx
  lea    D17(%rip),%r13
  nopl   (%rax)
L6:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L6
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: string

tool: D7: Hello argv!

tool: D16: argc len = %d


tool: D17: argv[ %d ] = %s


assistant: ```c
int main(int argc, char **argv) {
  printf("Hello argv!\n");
  printf("argc len = %d\n", argc);
  for (int i = 0; i < argc; ++i) {
    printf("argv[ %d ] = %s\n", i, argv[i]);
  }
  return 0;
}
```