ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x7,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D9
type: string

tool: D0: This is true

tool: D9: c is %d


assistant: ```c
int main(int argc, char **argv) {
  int a = 7;
  int b = 0;
  if (a) {
    puts("This is true");
  } else if (b) {
    puts("This is false");
  } else {
    puts("Not true at all");
  }
  int c = (a == 7) ? (7) : (9);
  printf("c is %d\n", c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0x7,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D15: This is true

tool: D2: c is %d


assistant: ```c
int main(int argc, char **argv) {
  int a = 7;
  int b = 0;
  if (a) {
    puts("This is true");
  } else if (b) {
    puts("This is false");
  } else {
    puts("Not true at all");
  }
  int c = (a == 7) ? (7) : (9);
  printf("c is %d\n", c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<HTMemory_outofmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  leave
  ret
```

assistant: ```c
void HTMemory_outofmem(const char *name, const char *file, unsigned long line) {

  ;
  abort();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<HTMemory_outofmem>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void HTMemory_outofmem(const char *name, const char *file, unsigned long line) {

  ;
  abort();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<HTMemory_outofmem>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void HTMemory_outofmem(const char *name, const char *file, unsigned long line) {

  ;
  abort();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<HTMemory_outofmem>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void HTMemory_outofmem(const char *name, const char *file, unsigned long line) {

  ;
  abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L4:
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned string_hash(const void *key) {
  const char *string = key;
  unsigned int result = 0;
  while (*string)
    result = result << 1 ^ *string++;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<string_hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
  mov    $0x0,%eax
L7:
  add    %eax,%eax
  add    $0x1,%rdi
  movsbl %dl,%edx
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L7
  ret
L14:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned string_hash(const void *key) {
  const char *string = key;
  unsigned int result = 0;
  while (*string)
    result = result << 1 ^ *string++;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<string_hash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L13
  nopl   (%rax)
L14:
  add    %eax,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  ret
L13:
  ret
```

assistant: ```c
unsigned string_hash(const void *key) {
  const char *string = key;
  unsigned int result = 0;
  while (*string)
    result = result << 1 ^ *string++;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<string_hash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L2
  nopl   (%rax)
L8:
  add    %eax,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L8
  ret
L2:
  ret
```

assistant: ```c
unsigned string_hash(const void *key) {
  const char *string = key;
  unsigned int result = 0;
  while (*string)
    result = result << 1 ^ *string++;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UARTCharGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  nop
L2:
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  and    $0x10,%eax
  test   %rax,%rax
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
long UARTCharGet(unsigned long ulBase) {
  ;
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) & 0x00000010) {
  }
  return ((*((volatile unsigned long *)(ulBase + 0x00000000))));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<UARTCharGet>:
  endbr64
L3:
  mov    0x18(%rdi),%rax
  test   $0x10,%al
  jne    L3
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long UARTCharGet(unsigned long ulBase) {
  ;
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) & 0x00000010) {
  }
  return ((*((volatile unsigned long *)(ulBase + 0x00000000))));
}
```
user: What is the c source code of the assembly code below?

```asm
<UARTCharGet>:
  endbr64
  lea    0x18(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rdx),%rax
  test   $0x10,%al
  jne    L1
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long UARTCharGet(unsigned long ulBase) {
  ;
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) & 0x00000010) {
  }
  return ((*((volatile unsigned long *)(ulBase + 0x00000000))));
}
```
user: Translate the below assembly code into C programming language:

```asm
<UARTCharGet>:
  endbr64
  lea    0x18(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rdx),%rax
  test   $0x10,%al
  jne    L6
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long UARTCharGet(unsigned long ulBase) {
  ;
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) & 0x00000010) {
  }
  return ((*((volatile unsigned long *)(ulBase + 0x00000000))));
}
```
user: What is the c source code of the assembly code below?

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L25
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L9
  mov    -0x8(%rbp),%rax
  jmp    L12
L9:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *str, int ch) {
  while (*str != '\0') {
    if (*str == ch)
      return (char *)str;
    str++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L12
L25:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L17
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L25
  mov    $0x0,%eax
  ret
L12:
  mov    $0x0,%eax
  ret
L17:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *str, int ch) {
  while (*str != '\0') {
    if (*str == ch)
      return (char *)str;
    str++;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strchr>:
  endbr64
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L14:
  cmp    %esi,%edx
  je     L0
  add    $0x1,%rdi
L6:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *str, int ch) {
  while (*str != '\0') {
    if (*str == ch)
      return (char *)str;
    str++;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<strchr>:
  endbr64
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmp    %esi,%edx
  je     L27
  add    $0x1,%rdi
L7:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L0
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *str, int ch) {
  while (*str != '\0') {
    if (*str == ch)
      return (char *)str;
    str++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xe4(%rbp)
  movl   $0x0,-0xe8(%rbp)
  jmp    L47
L58:
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%edx
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L0
  movl   $0x1,-0xe8(%rbp)
L0:
  addl   $0x1,-0xe4(%rbp)
L47:
  cmpl   $0x0,-0xe8(%rbp)
  jne    L15
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L58
  mov    -0xe4(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L58
L15:
  cmpl   $0x0,-0xe8(%rbp)
  jne    L53
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L46
L53:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L46:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D36
datatype: string
name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D51
datatype: string
name: read_data
arguments: label: D3
datatype: string
name: read_data
arguments: label: D35
datatype: string

tool: D2: inserisci una parola: 

tool: D36: %s

tool: D8: 
inserisci una seconda parola per il confronto: 

tool: D51: 
le due parole sono uguali


tool: D3: 
le due parole non sono uguali


tool: D35: PAUSE

assistant: ```c
int main() {
  char Parola1[100];
  char Parola2[100];
  int Flag;
  int I;
  printf("inserisci una parola: ");
  scanf("%s", Parola1);
  printf("\ninserisci una seconda parola per il confronto: ");
  scanf("%s", Parola2);
  I = 0;
  Flag = 0;
  while (Flag == 0 && (Parola1[I] != '\0' || Parola2[I] != '\0')) {
    if (Parola1[I] != Parola2[I]) {
      Flag = 1;
    }
    I++;
  }
  if (Flag == 0) {
    printf("\nle due parole sono uguali\n");
  } else {
    printf("\nle due parole non sono uguali\n");
  }
  system("PAUSE");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x70(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  lea    0x6f(%rsp),%rsi
  jmp    L15
L46:
  add    $0x1,%rax
  cmp    %dl,(%rsi,%rax,1)
  jne    L52
L15:
  movzbl (%rsp,%rax,1),%edx
  test   %dl,%dl
  jne    L46
  movslq %eax,%rcx
  cmpb   $0x0,0x70(%rsp,%rcx,1)
  je     L35
L52:
  lea    D30(%rip),%rdi
  call   <printf@plt>
L3:
  lea    D46(%rip),%rdi
  call   <system@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  ret
L35:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D52
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: string
name: parse_data
arguments: data_tag: D1
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string
name: parse_data
arguments: data_tag: D46
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D52: inserisci una parola: 

tool: D0: %s

tool: D1: 
inserisci una seconda parola per il confronto: 

tool: D30: 
le due parole non sono uguali


tool: D46: PAUSE

tool: D14: 
le due parole sono uguali


assistant: ```c
int main() {
  char Parola1[100];
  char Parola2[100];
  int Flag;
  int I;
  printf("inserisci una parola: ");
  scanf("%s", Parola1);
  printf("\ninserisci una seconda parola per il confronto: ");
  scanf("%s", Parola2);
  I = 0;
  Flag = 0;
  while (Flag == 0 && (Parola1[I] != '\0' || Parola2[I] != '\0')) {
    if (Parola1[I] != Parola2[I]) {
      Flag = 1;
    }
    I++;
  }
  if (Flag == 0) {
    printf("\nle due parole sono uguali\n");
  } else {
    printf("\nle due parole non sono uguali\n");
  }
  system("PAUSE");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D40(%rip),%rdi
  lea    D42(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%rbx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
L54:
  movzbl 0x0(%rbp,%rax,1),%edx
  movzbl (%rbx,%rax,1),%ecx
  test   %dl,%dl
  jne    L5
  test   %cl,%cl
  je     L59
L20:
  lea    D13(%rip),%rdi
  call   <printf@plt>
L19:
  lea    D17(%rip),%rdi
  call   <system@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L54
  jmp    L20
L59:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D40
data_type: string
name: parse_data
arguments: data_label: D42
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D17
data_type: string
name: parse_data
arguments: data_label: D41
data_type: string

tool: D40: inserisci una parola: 

tool: D42: %s

tool: D12: 
inserisci una seconda parola per il confronto: 

tool: D13: 
le due parole non sono uguali


tool: D17: PAUSE

tool: D41: 
le due parole sono uguali


assistant: ```c
int main() {
  char Parola1[100];
  char Parola2[100];
  int Flag;
  int I;
  printf("inserisci una parola: ");
  scanf("%s", Parola1);
  printf("\ninserisci una seconda parola per il confronto: ");
  scanf("%s", Parola2);
  I = 0;
  Flag = 0;
  while (Flag == 0 && (Parola1[I] != '\0' || Parola2[I] != '\0')) {
    if (Parola1[I] != Parola2[I]) {
      Flag = 1;
    }
    I++;
  }
  if (Flag == 0) {
    printf("\nle due parole sono uguali\n");
  } else {
    printf("\nle due parole non sono uguali\n");
  }
  system("PAUSE");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D21(%rip),%rdi
  lea    D24(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%rbx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
L57:
  movzbl 0x0(%rbp,%rax,1),%edx
  movzbl (%rbx,%rax,1),%ecx
  test   %dl,%dl
  jne    L30
  test   %cl,%cl
  je     L6
L17:
  lea    D27(%rip),%rdi
  call   <printf@plt>
L26:
  lea    D45(%rip),%rdi
  call   <system@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L57
  jmp    L17
L6:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
data_type: string
name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D42
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D45
data_type: string
name: parse_data
arguments: data_tag: D2
data_type: string

tool: D21: inserisci una parola: 

tool: D24: %s

tool: D42: 
inserisci una seconda parola per il confronto: 

tool: D27: 
le due parole non sono uguali


tool: D45: PAUSE

tool: D2: 
le due parole sono uguali


assistant: ```c
int main() {
  char Parola1[100];
  char Parola2[100];
  int Flag;
  int I;
  printf("inserisci una parola: ");
  scanf("%s", Parola1);
  printf("\ninserisci una seconda parola per il confronto: ");
  scanf("%s", Parola2);
  I = 0;
  Flag = 0;
  while (Flag == 0 && (Parola1[I] != '\0' || Parola2[I] != '\0')) {
    if (Parola1[I] != Parola2[I]) {
      Flag = 1;
    }
    I++;
  }
  if (Flag == 0) {
    printf("\nle due parole sono uguali\n");
  } else {
    printf("\nle due parole non sono uguali\n");
  }
  system("PAUSE");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<h265sei_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <h265nal_init@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L9
  mov    $0x27,%edx
  jmp    L15
L9:
  mov    $0x28,%edx
L15:
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <h265nal_set_type@plt>
  nop
  leave
  ret
```

assistant: ```c
void h265sei_init(uint8_t *p_h265sei, bool b_prefix) {
  h265nal_init(p_h265sei);
  h265nal_set_type(p_h265sei, b_prefix ? 39 : 40);
}
```
user: What is the c source code of the assembly code below:

```asm
<h265sei_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <h265nal_init@plt>
  cmp    $0x1,%ebp
  mov    $0x27,%esi
  adc    $0x0,%esi
  mov    %rbx,%rdi
  call   <h265nal_set_type@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void h265sei_init(uint8_t *p_h265sei, bool b_prefix) {
  h265nal_init(p_h265sei);
  h265nal_set_type(p_h265sei, b_prefix ? 39 : 40);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<h265sei_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <h265nal_init@plt>
  cmp    $0x1,%ebx
  mov    $0x27,%esi
  mov    %rbp,%rdi
  adc    $0x0,%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <h265nal_set_type@plt>
```

assistant: ```c
void h265sei_init(uint8_t *p_h265sei, bool b_prefix) {
  h265nal_init(p_h265sei);
  h265nal_set_type(p_h265sei, b_prefix ? 39 : 40);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<h265sei_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <h265nal_init@plt>
  cmp    $0x1,%ebx
  mov    $0x27,%esi
  mov    %rbp,%rdi
  adc    $0x0,%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <h265nal_set_type@plt>
```

assistant: ```c
void h265sei_init(uint8_t *p_h265sei, bool b_prefix) {
  h265nal_init(p_h265sei);
  h265nal_set_type(p_h265sei, b_prefix ? 39 : 40);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<process>:
  endbr64
  mov    0x8(%rdi),%edx
  mov    %edx,-0x14(%rsp)
  mov    0x8(%rdi),%edx
  mov    -0x14(%rsp),%ecx
  movzbl %dl,%edx
  cmp    %ecx,%edx
  je     L64
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L64:
  mov    0x8(%rdi),%edx
  mov    %edx,-0x10(%rsp)
  mov    0x8(%rdi),%edx
  mov    -0x10(%rsp),%ecx
  movzwl %dx,%edx
  cmp    %ecx,%edx
  je     L42
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L42:
  mov    0x8(%rdi),%edx
  mov    0x8(%rdi),%ecx
  cmp    %edx,%ecx
  je     L25
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L25:
  mov    0x4(%rdi),%edx
  mov    %edx,-0xc(%rsp)
  mov    0x4(%rdi),%edx
  mov    -0xc(%rsp),%ecx
  movzwl %dx,%edx
  cmp    %ecx,%edx
  je     L74
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L74:
  mov    0x4(%rdi),%edx
  mov    0x4(%rdi),%ecx
  cmp    %edx,%ecx
  je     L33
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L33:
  mov    (%rdi),%edx
  mov    %edx,-0x8(%rsp)
  mov    (%rdi),%edx
  mov    -0x8(%rsp),%ecx
  movzbl %dl,%edx
  cmp    %ecx,%edx
  je     L31
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L31:
  mov    (%rdi),%edx
  mov    %edx,-0x4(%rsp)
  mov    (%rdi),%edx
  mov    -0x4(%rsp),%ecx
  movzwl %dx,%edx
  cmp    %ecx,%edx
  je     L3
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L3:
  mov    (%rdi),%edx
  mov    (%rdi),%eax
  cmp    %edx,%eax
  je     L26
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L26:
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
__attribute__((section("test1"), used)) int process(struct __sk_buff *skb) {
  {
    __u8 tmp = *(volatile __u8 *)&skb->len;
    if (tmp != ((*(volatile __u32 *)&skb->len) & 0xFF))
      return TC_ACT_SHOT;
  };
  {
    __u16 tmp = *(volatile __u16 *)&skb->len;
    if (tmp != ((*(volatile __u32 *)&skb->len) & 0xFFFF))
      return TC_ACT_SHOT;
  };
  {
    __u32 tmp = *(volatile __u32 *)&skb->len;
    if (tmp != ((*(volatile __u32 *)&skb->len) & 0xFFFFFFFF))
      return TC_ACT_SHOT;
  };
  {
    __u16 tmp = *(volatile __u16 *)&skb->protocol;
    if (tmp != ((*(volatile __u32 *)&skb->protocol) & 0xFFFF))
      return TC_ACT_SHOT;
  };
  {
    __u32 tmp = *(volatile __u32 *)&skb->protocol;
    if (tmp != ((*(volatile __u32 *)&skb->protocol) & 0xFFFFFFFF))
      return TC_ACT_SHOT;
  };
  {
    __u8 tmp = *(volatile __u8 *)&skb->hash;
    if (tmp != ((*(volatile __u32 *)&skb->hash) & 0xFF))
      return TC_ACT_SHOT;
  };
  {
    __u16 tmp = *(volatile __u16 *)&skb->hash;
    if (tmp != ((*(volatile __u32 *)&skb->hash) & 0xFFFF))
      return TC_ACT_SHOT;
  };
  {
    __u32 tmp = *(volatile __u32 *)&skb->hash;
    if (tmp != ((*(volatile __u32 *)&skb->hash) & 0xFFFFFFFF))
      return TC_ACT_SHOT;
  };
  return TC_ACT_OK;
}
```