ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x50,%esi
  lea    D10(%rip),%rdi
  call   <FXNew@plt>
  lea    D32(%rip),%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <FXPrint@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <FXClose@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D32
type_infered: string
name: retrieve_data
arguments: data_label: D22
type_infered: string

tool: D9: initializing

tool: D10: 127.0.0.1

tool: D32: GET /

tool: D22: %d


assistant: ```c
int main() {
  printf("initializing\n");
  int s = FXNew("127.0.0.1", 80);
  printf("%d\n", FXPrint(s, "GET /"));
  FXClose(s);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x50,%esi
  lea    D14(%rip),%rdi
  call   <FXNew@plt>
  lea    D24(%rip),%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <FXPrint@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <FXClose@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D21
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D3
datatype: string

tool: D21: initializing

tool: D14: 127.0.0.1

tool: D24: GET /

tool: D3: %d


assistant: ```c
int main() {
  printf("initializing\n");
  int s = FXNew("127.0.0.1", 80);
  printf("%d\n", FXPrint(s, "GET /"));
  FXClose(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_sock_uncork>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <set_udp_uncork@plt>
  jmp    L8
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <set_tcp_uncork@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void set_sock_uncork(int fd, int udp) {
  if (!!udp)
    set_udp_uncork(fd);
  else
    set_tcp_uncork(fd);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set_sock_uncork>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L4
  call   <set_udp_uncork@plt>
L2:
  add    $0x8,%rsp
  ret
L4:
  call   <set_tcp_uncork@plt>
  jmp    L2
```

assistant: ```c
void set_sock_uncork(int fd, int udp) {
  if (!!udp)
    set_udp_uncork(fd);
  else
    set_tcp_uncork(fd);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_sock_uncork>:
  endbr64
  test   %esi,%esi
  je     L9
  jmp    1060 <set_udp_uncork@plt>
  nopl   (%rax)
L9:
  jmp    1070 <set_tcp_uncork@plt>
```

assistant: ```c
void set_sock_uncork(int fd, int udp) {
  if (!!udp)
    set_udp_uncork(fd);
  else
    set_tcp_uncork(fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_sock_uncork>:
  endbr64
  test   %esi,%esi
  je     L0
  jmp    1060 <set_udp_uncork@plt>
  nopl   (%rax)
L0:
  jmp    1070 <set_tcp_uncork@plt>
```

assistant: ```c
void set_sock_uncork(int fd, int udp) {
  if (!!udp)
    set_udp_uncork(fd);
  else
    set_tcp_uncork(fd);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<store_htonll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  shr    $0x8,%rax
  and    $0xff000000,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  shr    $0x18,%rax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  shr    $0x28,%rax
  and    $0xff00,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  shr    $0x38,%rax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
u_int64_t store_htonll(u_int64_t v) {
  v = (v & 0xff) << 56 | (v & 0xff00ULL) << 40 | (v & 0xff0000ULL) << 24 | (v & 0xff000000ULL) << 8 | (v & 0xff00000000ULL) >> 8 | (v & 0xff0000000000ULL) >> 24 | (v & 0xff000000000000ULL) >> 40 | (v & 0xff00000000000000ULL) >> 56;
  return (v);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<store_htonll>:
  endbr64
  movslq %edi,%rdi
  mov    %rdi,%rax
  shr    $0x8,%rax
  and    $0xff000000,%eax
  mov    %rdi,%rdx
  shr    $0x18,%rdx
  and    $0xff0000,%edx
  or     %edx,%eax
  mov    %rdi,%rdx
  shr    $0x38,%rdx
  or     %edx,%eax
  shr    $0x28,%rdi
  and    $0xff00,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
u_int64_t store_htonll(u_int64_t v) {
  v = (v & 0xff) << 56 | (v & 0xff00ULL) << 40 | (v & 0xff0000ULL) << 24 | (v & 0xff000000ULL) << 8 | (v & 0xff00000000ULL) >> 8 | (v & 0xff0000000000ULL) >> 24 | (v & 0xff000000000000ULL) >> 40 | (v & 0xff00000000000000ULL) >> 56;
  return (v);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<store_htonll>:
  endbr64
  movslq %edi,%rdi
  mov    %rdi,%rax
  mov    %rdi,%rdx
  shr    $0x8,%rax
  shr    $0x18,%rdx
  and    $0xff0000,%edx
  and    $0xff000000,%eax
  or     %edx,%eax
  mov    %rdi,%rdx
  shr    $0x28,%rdi
  shr    $0x38,%rdx
  and    $0xff00,%edi
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
u_int64_t store_htonll(u_int64_t v) {
  v = (v & 0xff) << 56 | (v & 0xff00ULL) << 40 | (v & 0xff0000ULL) << 24 | (v & 0xff000000ULL) << 8 | (v & 0xff00000000ULL) >> 8 | (v & 0xff0000000000ULL) >> 24 | (v & 0xff000000000000ULL) >> 40 | (v & 0xff00000000000000ULL) >> 56;
  return (v);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<store_htonll>:
  endbr64
  movslq %edi,%rdi
  mov    %rdi,%rax
  mov    %rdi,%rdx
  shr    $0x8,%rax
  shr    $0x18,%rdx
  and    $0xff0000,%edx
  and    $0xff000000,%eax
  or     %edx,%eax
  mov    %rdi,%rdx
  shr    $0x28,%rdi
  shr    $0x38,%rdx
  and    $0xff00,%edi
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
u_int64_t store_htonll(u_int64_t v) {
  v = (v & 0xff) << 56 | (v & 0xff00ULL) << 40 | (v & 0xff0000ULL) << 24 | (v & 0xff000000ULL) << 8 | (v & 0xff00000000ULL) >> 8 | (v & 0xff0000000000ULL) >> 24 | (v & 0xff000000000000ULL) >> 40 | (v & 0xff00000000000000ULL) >> 56;
  return (v);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2a(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t foo(uint32_t *x) {
  uint32_t tmp = *x + 1;
  *x += 42;
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  mov    (%rdi),%rax
  lea    0x2a(%rax),%rdx
  mov    %rdx,(%rdi)
  add    $0x1,%rax
  ret
```

assistant: ```c
uint32_t foo(uint32_t *x) {
  uint32_t tmp = *x + 1;
  *x += 42;
  return tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  mov    (%rdi),%rax
  lea    0x2a(%rax),%rdx
  add    $0x1,%rax
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
uint32_t foo(uint32_t *x) {
  uint32_t tmp = *x + 1;
  *x += 42;
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  mov    (%rdi),%rax
  lea    0x2a(%rax),%rdx
  add    $0x1,%rax
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
uint32_t foo(uint32_t *x) {
  uint32_t tmp = *x + 1;
  *x += 42;
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<a_thread_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xa,%edi
  call   <sleep@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: Could not send cancel request correctly


assistant: ```c
void *a_thread_func() {
  sleep(10);
  perror("Could not send cancel request correctly\n");
  pthread_exit(0);
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<a_thread_func>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sleep@plt>
  lea    D8(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: Could not send cancel request correctly


assistant: ```c
void *a_thread_func() {
  sleep(10);
  perror("Could not send cancel request correctly\n");
  pthread_exit(0);
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<a_thread_func>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sleep@plt>
  lea    D2(%rip),%rdi
  call   <perror@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: Could not send cancel request correctly


assistant: ```c
void *a_thread_func() {
  sleep(10);
  perror("Could not send cancel request correctly\n");
  pthread_exit(0);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<a_thread_func>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sleep@plt>
  lea    D8(%rip),%rdi
  call   <perror@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string

tool: D8: Could not send cancel request correctly


assistant: ```c
void *a_thread_func() {
  sleep(10);
  perror("Could not send cancel request correctly\n");
  pthread_exit(0);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L9:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sputc@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L8:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sputs(char *s, const char *b) {
  int len = 0;
  while (*b != '\0') {
    len += sputc(s, *b);
    s++;
    b++;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sputs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L28
  mov    %rdi,%rbp
  mov    $0x0,%r12d
L9:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <sputc@plt>
  add    %eax,%r12d
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L9
L15:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    $0x0,%r12d
  jmp    L15
```

assistant: ```c
int sputs(char *s, const char *b) {
  int len = 0;
  while (*b != '\0') {
    len += sputc(s, *b);
    s++;
    b++;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sputs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L4
  mov    %rdi,%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <sputc@plt>
  movsbl (%rbx),%esi
  add    %eax,%r12d
  test   %sil,%sil
  jne    L2
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int sputs(char *s, const char *b) {
  int len = 0;
  while (*b != '\0') {
    len += sputc(s, *b);
    s++;
    b++;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sputs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L14
  mov    %rdi,%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L8:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <sputc@plt>
  movsbl (%rbx),%esi
  add    %eax,%r12d
  test   %sil,%sil
  jne    L8
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int sputs(char *s, const char *b) {
  int len = 0;
  while (*b != '\0') {
    len += sputc(s, *b);
    s++;
    b++;
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bsd_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L49
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L49
L54:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L54
  jmp    L49
L31:
  nop
L49:
  cmpq   $0x0,-0x8(%rbp)
  jne    L52
  cmpq   $0x0,-0x38(%rbp)
  je     L60
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L60:
  nop
L1:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
L52:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t bsd_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bsd_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L81
  sub    $0x1,%rdx
  je     L38
  mov    %rsi,%rax
L57:
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdi)
  test   %cl,%cl
  je     L13
  sub    $0x1,%rdx
  jne    L57
  jmp    L59
L81:
  mov    %rsi,%rax
L33:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L33
L48:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L38:
  mov    %rsi,%rax
L59:
  movb   $0x0,(%rdi)
  jmp    L33
L13:
  test   %rdx,%rdx
  jne    L48
  jmp    L59
```

assistant: ```c
size_t bsd_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bsd_strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L39
  cmp    $0x1,%rdx
  je     L78
  mov    %rdi,%rcx
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  je     L1
L79:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L58
L72:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   (%rax)
L1:
  mov    %rcx,%rdi
L78:
  movb   $0x0,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L39:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L72
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L39
  jmp    L72
```

assistant: ```c
size_t bsd_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bsd_strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L38
  cmp    $0x1,%rdx
  je     L49
  mov    %rdi,%rcx
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  je     L14
L43:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L26
L5:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   (%rax)
L14:
  mov    %rcx,%rdi
L49:
  movb   $0x0,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L38:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L5
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L38
  jmp    L5
```

assistant: ```c
size_t bsd_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1a8(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1a8(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1a4(%rbp)
  jmp    L5
L3:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1a4(%rbp)
L5:
  mov    -0x1a8(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L3
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1ac(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1a8(%rbp),%edx
  mov    -0x1ac(%rbp),%ecx
  lea    -0x1a0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
type: string
name: extract_symbolic_data
arguments: label: D26
type: string
name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D5
type: string

tool: D33: Enter the number of elements in array

tool: D26: %d

tool: D10: Enter %d integer(s)


tool: D5: Enter the number to search

assistant: ```c
int main() {
  int array[100], search_please, c, n;
  printf("Enter the number of elements in array\n");
  scanf("%d", &n);
  printf("Enter %d integer(s)\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  printf("Enter the number to search\n");
  scanf("%d", &search_please);
  search(array, search_please, n);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D48(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L15
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D54(%rip),%r12
L16:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L16
L15:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  call   <search@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D48
data_type: string
name: read_data
arguments: tag: D54
data_type: string
name: read_data
arguments: tag: D37
data_type: string
name: read_data
arguments: tag: D5
data_type: string

tool: D48: Enter the number of elements in array

tool: D54: %d

tool: D37: Enter %d integer(s)


tool: D5: Enter the number to search

assistant: ```c
int main() {
  int array[100], search_please, c, n;
  printf("Enter the number of elements in array\n");
  scanf("%d", &n);
  printf("Enter %d integer(s)\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  printf("Enter the number to search\n");
  scanf("%d", &search_please);
  search(array, search_please, n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  mov    %r13,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L29
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L19
L29:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r13,%rdi
  call   <search@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
data_type: string
name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D31
data_type: string
name: parse_data
arguments: data_tag: D36
data_type: string

tool: D19: Enter the number of elements in array

tool: D8: %d

tool: D31: Enter %d integer(s)


tool: D36: Enter the number to search

assistant: ```c
int main() {
  int array[100], search_please, c, n;
  printf("Enter the number of elements in array\n");
  scanf("%d", &n);
  printf("Enter %d integer(s)\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  printf("Enter the number to search\n");
  scanf("%d", &search_please);
  search(array, search_please, n);
  return 0;
}
```