ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cwebsocket_create_key_challenge_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    D3(%rip),%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x70(%rbp)
  mov    -0x70(%rbp),%eax
  add    $0x24,%eax
  mov    %eax,-0x6c(%rbp)
  mov    -0x6c(%rbp),%eax
  cltq
  sub    $0x1,%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x6c(%rbp),%eax
  cltq
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    -0x6c(%rbp),%eax
  cltq
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x6c(%rbp),%eax
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L11:
  cmp    %rdx,%rsp
  je     L37
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L11
L37:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L26
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L26:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x70(%rbp),%edx
  mov    -0x78(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x70(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x68(%rbp),%rax
  mov    $0x24,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  lea    -0x50(%rbp),%rdx
  mov    -0x6c(%rbp),%ecx
  mov    -0x58(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <SHA1@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <cwebsocket_base64_encode@plt>
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: 258EAFA5-E914-47DA-95CA-C5AB0DC85B11

assistant: ```c
char *cwebsocket_create_key_challenge_response(const char *seckey) {
  const char *GUID = "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
  const int seckey_len = strlen(seckey);
  const int total_len = seckey_len + 36;
  char sha1buf[total_len];
  memcpy(sha1buf, seckey, seckey_len);
  memcpy(&sha1buf[seckey_len], GUID, 36);
  unsigned char sha1_bytes[20];
  SHA1((const unsigned char *)sha1buf, total_len, sha1_bytes);
  return cwebsocket_base64_encode((const unsigned char *)sha1_bytes, sizeof(sha1_bytes));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cwebsocket_create_key_challenge_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x24(%rax),%r13d
  movslq %r13d,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L37:
  cmp    %rdx,%rsp
  je     L24
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L37
L24:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L21
  orq    $0x0,-0x8(%rsp,%rax,1)
L21:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rdi
  add    %rsp,%rdi
  mov    $0x24,%edx
  lea    D5(%rip),%rsi
  call   <memcpy@plt>
  lea    -0x40(%rbp),%rbx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %rsp,%rdi
  call   <SHA1@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <cwebsocket_base64_encode@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D5: 258EAFA5-E914-47DA-95CA-C5AB0DC85B11

assistant: ```c
char *cwebsocket_create_key_challenge_response(const char *seckey) {
  const char *GUID = "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
  const int seckey_len = strlen(seckey);
  const int total_len = seckey_len + 36;
  char sha1buf[total_len];
  memcpy(sha1buf, seckey, seckey_len);
  memcpy(&sha1buf[seckey_len], GUID, 36);
  unsigned char sha1_bytes[20];
  SHA1((const unsigned char *)sha1buf, total_len, sha1_bytes);
  return cwebsocket_base64_encode((const unsigned char *)sha1_bytes, sizeof(sha1_bytes));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cwebsocket_create_key_challenge_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x24(%rax),%r13d
  mov    %eax,%ebx
  movslq %r13d,%rdx
  add    $0xf,%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L26
L23:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L23
L26:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L12
L0:
  mov    %r12,%rsi
  mov    %ebx,%edx
  lea    -0x40(%rbp),%r12
  mov    %rsp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rdi
  mov    $0x24,%edx
  lea    D8(%rip),%rsi
  add    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rsp,%rdi
  call   <SHA1@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  call   <cwebsocket_base64_encode@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L12:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L0
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string

tool: D8: 258EAFA5-E914-47DA-95CA-C5AB0DC85B11

assistant: ```c
char *cwebsocket_create_key_challenge_response(const char *seckey) {
  const char *GUID = "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
  const int seckey_len = strlen(seckey);
  const int total_len = seckey_len + 36;
  char sha1buf[total_len];
  memcpy(sha1buf, seckey, seckey_len);
  memcpy(&sha1buf[seckey_len], GUID, 36);
  unsigned char sha1_bytes[20];
  SHA1((const unsigned char *)sha1buf, total_len, sha1_bytes);
  return cwebsocket_base64_encode((const unsigned char *)sha1_bytes, sizeof(sha1_bytes));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cwebsocket_create_key_challenge_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x24(%rax),%r13d
  mov    %eax,%ebx
  movslq %r13d,%rdx
  add    $0xf,%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L24
L49:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L49
L24:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L3
L48:
  mov    %r12,%rsi
  mov    %ebx,%edx
  lea    -0x40(%rbp),%r12
  mov    %rsp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rdi
  mov    $0x24,%edx
  lea    D5(%rip),%rsi
  add    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rsp,%rdi
  call   <SHA1@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  call   <cwebsocket_base64_encode@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L48
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5: 258EAFA5-E914-47DA-95CA-C5AB0DC85B11

assistant: ```c
char *cwebsocket_create_key_challenge_response(const char *seckey) {
  const char *GUID = "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
  const int seckey_len = strlen(seckey);
  const int total_len = seckey_len + 36;
  char sha1buf[total_len];
  memcpy(sha1buf, seckey, seckey_len);
  memcpy(&sha1buf[seckey_len], GUID, 36);
  unsigned char sha1_bytes[20];
  SHA1((const unsigned char *)sha1buf, total_len, sha1_bytes);
  return cwebsocket_base64_encode((const unsigned char *)sha1_bytes, sizeof(sha1_bytes));
}
```
user: What is the c source code of the assembly code below:

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L5
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L5:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L3
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strndup(const char *s, size_t size) {
  char *r;
  char *end = memchr(s, 0, size);
  if (end)
    size = end - s + 1;
  r = malloc(size);
  if (size) {
    memcpy(r, s, size - 1);
    r[size - 1] = '\0';
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    $0x1,%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  jne    L10
L11:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  jmp    L11
```

assistant: ```c
char *strndup(const char *s, size_t size) {
  char *r;
  char *end = memchr(s, 0, size);
  if (end)
    size = end - s + 1;
  r = malloc(size);
  if (size) {
    memcpy(r, s, size - 1);
    r[size - 1] = '\0';
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strndup>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    $0x1,%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  jne    L5
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t size) {
  char *r;
  char *end = memchr(s, 0, size);
  if (end)
    size = end - s + 1;
  r = malloc(size);
  if (size) {
    memcpy(r, s, size - 1);
    r[size - 1] = '\0';
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strndup>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    $0x1,%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  jne    L5
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t size) {
  char *r;
  char *end = memchr(s, 0, size);
  if (end)
    size = end - s + 1;
  r = malloc(size);
  if (size) {
    memcpy(r, s, size - 1);
    r[size - 1] = '\0';
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  %xmm3,-0x20(%rbp)
  movsd  %xmm4,-0x28(%rbp)
  movsd  %xmm5,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  movsd  -0x30(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <set_line_gwt@plt>
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <rect1@plt>
  mov    $0x0,%eax
  call   <default_line_gwt@plt>
  nop
  leave
  ret
```

assistant: ```c
void rect(double x1, double y1, double x2, double y2, double g, double w, int it) {
  set_line_gwt(g, w, it);
  rect1(x1, y1, x2, y2);
  default_line_gwt();
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rect>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  movq   %xmm2,%r12
  movq   %xmm3,%r13
  movapd %xmm4,%xmm0
  movapd %xmm5,%xmm1
  call   <set_line_gwt@plt>
  movq   %r13,%xmm3
  movq   %r12,%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <rect1@plt>
  mov    $0x0,%eax
  call   <default_line_gwt@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rect(double x1, double y1, double x2, double y2, double g, double w, int it) {
  set_line_gwt(g, w, it);
  rect1(x1, y1, x2, y2);
  default_line_gwt();
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rect>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm4,%xmm0
  movsd  %xmm1,0x10(%rsp)
  movapd %xmm5,%xmm1
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <set_line_gwt@plt>
  movsd  0x10(%rsp),%xmm7
  movsd  (%rsp),%xmm3
  movsd  0x18(%rsp),%xmm6
  movsd  0x8(%rsp),%xmm2
  movapd %xmm7,%xmm1
  movapd %xmm6,%xmm0
  call   <rect1@plt>
  xor    %eax,%eax
  add    $0x28,%rsp
  jmp    1080 <default_line_gwt@plt>
```

assistant: ```c
void rect(double x1, double y1, double x2, double y2, double g, double w, int it) {
  set_line_gwt(g, w, it);
  rect1(x1, y1, x2, y2);
  default_line_gwt();
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rect>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm4,%xmm0
  movsd  %xmm1,0x10(%rsp)
  movapd %xmm5,%xmm1
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <set_line_gwt@plt>
  movsd  0x10(%rsp),%xmm7
  movsd  (%rsp),%xmm3
  movsd  0x18(%rsp),%xmm6
  movsd  0x8(%rsp),%xmm2
  movapd %xmm7,%xmm1
  movapd %xmm6,%xmm0
  call   <rect1@plt>
  xor    %eax,%eax
  add    $0x28,%rsp
  jmp    1080 <default_line_gwt@plt>
```

assistant: ```c
void rect(double x1, double y1, double x2, double y2, double g, double w, int it) {
  set_line_gwt(g, w, it);
  rect1(x1, y1, x2, y2);
  default_line_gwt();
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main() {
  int x, *p, **pp;
  x = 0;
  p = &x;
  pp = &p;
  return **pp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x, *p, **pp;
  x = 0;
  p = &x;
  pp = &p;
  return **pp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x, *p, **pp;
  x = 0;
  p = &x;
  pp = &p;
  return **pp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x, *p, **pp;
  x = 0;
  p = &x;
  pp = &p;
  return **pp;
}
```
user: What is the c source code of the assembly code below:

```asm
<nsd_different_result>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L2
  cmpl   $0x0,-0x18(%rbp)
  jg     L75
L2:
  mov    $0x1,%eax
  jmp    L17
L75:
  cmpl   $0x9,-0x14(%rbp)
  jg     L6
  movl   $0xc,-0x18(%rbp)
  jmp    L66
L6:
  cmpl   $0x2c,-0x14(%rbp)
  jne    L55
  movl   $0x7c,-0x18(%rbp)
  jmp    L66
L55:
  movl   $0x457,-0x18(%rbp)
L66:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L31
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L31
L0:
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L31
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L31:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L0
  mov    -0x14(%rbp),%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) int nsd_different_result(int x, int y) {
  int pes;
  if (x <= 0 || y <= 0)
    return 1;
  if (x < 10)
    y = 12;
  else if (x == 44)
    y = 124;
  else
    y = 1111;
  if (x < y) {
    pes = x;
    x = y;
    y = pes;
  }
  while (x != y) {
    x = x - y;
    if (y > x) {
      pes = x;
      x = y;
      y = pes;
    }
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nsd_different_result>:
  endbr64
  test   %edi,%edi
  jle    L13
  test   %esi,%esi
  jle    L13
  cmp    $0x9,%edi
  jle    L72
  mov    $0x457,%eax
  cmp    $0x2c,%edi
  jne    L27
  mov    %edi,%eax
  mov    $0x7c,%edi
  jmp    L90
L72:
  mov    $0xc,%eax
L27:
  cmp    %edi,%eax
  jg     L65
L90:
  cmp    %eax,%edi
  je     L8
  sub    %eax,%edi
  cmp    %eax,%edi
  jge    L90
  mov    %edi,%edx
  mov    %eax,%edi
  mov    %edx,%eax
  jmp    L90
L65:
  mov    %edi,%edx
  mov    %eax,%edi
  mov    %edx,%eax
  jmp    L90
L8:
  ret
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
__attribute__((no)) int nsd_different_result(int x, int y) {
  int pes;
  if (x <= 0 || y <= 0)
    return 1;
  if (x < 10)
    y = 12;
  else if (x == 44)
    y = 124;
  else
    y = 1111;
  if (x < y) {
    pes = x;
    x = y;
    y = pes;
  }
  while (x != y) {
    x = x - y;
    if (y > x) {
      pes = x;
      x = y;
      y = pes;
    }
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nsd_different_result>:
  endbr64
  test   %edi,%edi
  jle    L5
  test   %esi,%esi
  jle    L5
  cmp    $0x9,%edi
  jle    L30
  mov    $0x457,%eax
  cmp    $0x2c,%edi
  jne    L82
  jmp    L33
  nopl   (%rax)
L46:
  cmp    %eax,%edi
  je     L93
L70:
  sub    %eax,%edi
L82:
  cmp    %edi,%eax
  jle    L46
  mov    %edi,%edx
  mov    %eax,%edi
  mov    %edx,%eax
  cmp    %eax,%edi
  jne    L70
L93:
  ret
  nopl   (%rax)
L30:
  mov    $0xc,%eax
  jmp    L82
  nop
L5:
  mov    $0x1,%eax
  ret
L33:
  mov    $0x2c,%eax
  mov    $0x7c,%edi
  jmp    L46
```

assistant: ```c
__attribute__((no)) int nsd_different_result(int x, int y) {
  int pes;
  if (x <= 0 || y <= 0)
    return 1;
  if (x < 10)
    y = 12;
  else if (x == 44)
    y = 124;
  else
    y = 1111;
  if (x < y) {
    pes = x;
    x = y;
    y = pes;
  }
  while (x != y) {
    x = x - y;
    if (y > x) {
      pes = x;
      x = y;
      y = pes;
    }
  }
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nsd_different_result>:
  endbr64
  test   %edi,%edi
  jle    L19
  test   %esi,%esi
  jle    L19
  cmp    $0x9,%edi
  jle    L4
  mov    $0x457,%eax
  cmp    $0x2c,%edi
  jne    L45
  jmp    L25
  nopl   (%rax)
L52:
  cmp    %eax,%edi
  je     L72
L59:
  sub    %eax,%edi
L45:
  cmp    %edi,%eax
  jle    L52
  mov    %edi,%edx
  mov    %eax,%edi
  mov    %edx,%eax
  cmp    %eax,%edi
  jne    L59
L72:
  ret
  nopl   (%rax)
L4:
  mov    $0xc,%eax
  jmp    L45
  nop
L19:
  mov    $0x1,%eax
  ret
L25:
  mov    $0x2c,%eax
  mov    $0x7c,%edi
  jmp    L52
```

assistant: ```c
__attribute__((no)) int nsd_different_result(int x, int y) {
  int pes;
  if (x <= 0 || y <= 0)
    return 1;
  if (x < 10)
    y = 12;
  else if (x == 44)
    y = 124;
  else
    y = 1111;
  if (x < y) {
    pes = x;
    x = y;
    y = pes;
  }
  while (x != y) {
    x = x - y;
    if (y > x) {
      pes = x;
      x = y;
      y = pes;
    }
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L18:
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L2:
  cmpl   $0x2,-0xc(%rbp)
  jle    L18
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string
name: disassemble_data
arguments: label: D20
type_infered: string
name: disassemble_data
arguments: label: D21
type_infered: string

tool: D3: cosh

tool: D20: # c::%s


tool: D21: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "cosh");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```