ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<print_decimal>:
  endbr64
  comisd D29(%rip),%xmm0
  push   %r12
  movapd %xmm0,%xmm1
  jae    L19
  xorpd  D113(%rip),%xmm1
L19:
  comisd D23(%rip),%xmm1
  jae    L34
  comisd D104(%rip),%xmm1
  jae    L9
  comisd D75(%rip),%xmm1
  jae    L25
  comisd D82(%rip),%xmm1
  jb     L39
  lea    D53(%rip),%r12
  lea    D48(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  lea    D53(%rip),%r12
  lea    D140(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L34:
  lea    D53(%rip),%r12
  lea    D131(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  lea    D53(%rip),%r12
  lea    D36(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  lea    D53(%rip),%r12
  lea    D114(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
data_type: f64[2]
name: extract_symbolic_data
arguments: data_tag: D113
data_type: byte[16]
name: extract_symbolic_data
arguments: data_tag: D23
data_type: f64[2]
name: extract_symbolic_data
arguments: data_tag: D104
data_type: f64[2]
name: extract_symbolic_data
arguments: data_tag: D75
data_type: f64[2]
name: extract_symbolic_data
arguments: data_tag: D82
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D48
data_type: string
name: extract_symbolic_data
arguments: data_tag: D140
data_type: string
name: extract_symbolic_data
arguments: data_tag: D131
data_type: string
name: extract_symbolic_data
arguments: data_tag: D36
data_type: string
name: extract_symbolic_data
arguments: data_tag: D114
data_type: string

tool: {"D29": [0.0,9.95]}

tool: {"D113": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D23": [9.95,0.95]}

tool: {"D104": [0.95,0.001]}

tool: {"D75": [0.001,0.0005]}

tool: D82: 0.0005

tool: D48: %.3f

tool: D140: %.1f

tool: D131: %.0f

tool: D36: 0

tool: D114: %.1g

assistant: ```c
const char *print_decimal(double number) {
  static char buf[32];
  double n = number >= 0 ? number : -number;
  if (n >= 9.95)
    snprintf(buf, sizeof buf, "%.0f", number);
  else if (n >= 0.95)
    snprintf(buf, sizeof buf, "%.1f", number);
  else if (n >= 0.001)
    snprintf(buf, sizeof buf, "%.1g", number);
  else if (n >= 0.0005)
    snprintf(buf, sizeof buf, "%.3f", number);
  else
    strcpy(buf, "0");
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_decimal>:
  endbr64
  comisd D136(%rip),%xmm0
  push   %r12
  movapd %xmm0,%xmm1
  jae    L42
  xorpd  D67(%rip),%xmm1
L42:
  comisd D101(%rip),%xmm1
  jae    L40
  comisd D6(%rip),%xmm1
  jae    L49
  comisd D69(%rip),%xmm1
  jae    L2
  comisd D37(%rip),%xmm1
  jb     L17
  lea    D106(%rip),%r12
  lea    D105(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L49:
  lea    D106(%rip),%r12
  lea    D81(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L40:
  lea    D106(%rip),%r12
  lea    D111(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  lea    D106(%rip),%r12
  lea    D107(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D106(%rip),%r12
  lea    D89(%rip),%rdx
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D136
type_infered: f64[2]
name: unpack_data
arguments: label: D67
type_infered: byte[16]
name: unpack_data
arguments: label: D101
type_infered: f64[2]
name: unpack_data
arguments: label: D6
type_infered: f64[2]
name: unpack_data
arguments: label: D69
type_infered: f64[2]
name: unpack_data
arguments: label: D37
type_infered: f64
name: unpack_data
arguments: label: D105
type_infered: string
name: unpack_data
arguments: label: D81
type_infered: string
name: unpack_data
arguments: label: D111
type_infered: string
name: unpack_data
arguments: label: D107
type_infered: string
name: unpack_data
arguments: label: D89
type_infered: string

tool: {"D136": [0.0,9.95]}

tool: {"D67": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D101": [9.95,0.95]}

tool: {"D6": [0.95,0.001]}

tool: {"D69": [0.001,0.0005]}

tool: D37: 0.0005

tool: D105: %.3f

tool: D81: %.1f

tool: D111: %.0f

tool: D107: 0

tool: D89: %.1g

assistant: ```c
const char *print_decimal(double number) {
  static char buf[32];
  double n = number >= 0 ? number : -number;
  if (n >= 9.95)
    snprintf(buf, sizeof buf, "%.0f", number);
  else if (n >= 0.95)
    snprintf(buf, sizeof buf, "%.1f", number);
  else if (n >= 0.001)
    snprintf(buf, sizeof buf, "%.1g", number);
  else if (n >= 0.0005)
    snprintf(buf, sizeof buf, "%.3f", number);
  else
    strcpy(buf, "0");
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_syslog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  je     L42
  mov    $0x0,%eax
  jmp    L28
L42:
  mov    -0x18(%rbp),%rax
  lea    -0x18(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xbf,-0x4(%rbp)
  ja     L49
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  je     L19
L49:
  mov    $0x0,%eax
  jmp    L28
L19:
  mov    -0x4(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
L28:
  leave
  ret
```

assistant: ```c
const char *parse_syslog(const char *line, unsigned *facility, unsigned *priority) {
  unsigned num;
  if (*line++ != '<')
    return 0;
  num = strtoul(line, (char **)&line, 10);
  if (num >= 8 * 24 || *line++ != '>')
    return 0;
  *facility = num >> 3;
  *priority = num & 7;
  return line;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_syslog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%rbx
  lea    0x1(%rdi),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%edx
  cmpb   $0x3c,(%rdi)
  jne    L47
  mov    %rsi,%rbp
  lea    0x8(%rsp),%rsi
  mov    $0xa,%edx
  mov    %rax,%rdi
  call   <strtoul@plt>
  cmp    $0xbf,%eax
  ja     L23
  mov    0x8(%rsp),%rcx
  lea    0x1(%rcx),%rdx
  mov    %rdx,0x8(%rsp)
  cmpb   $0x3e,(%rcx)
  jne    L9
  mov    %eax,%ecx
  shr    $0x3,%ecx
  mov    %ecx,0x0(%rbp)
  and    $0x7,%eax
  mov    %eax,(%rbx)
L47:
  mov    %rdx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  mov    $0x0,%edx
  jmp    L47
L9:
  mov    $0x0,%edx
  jmp    L47
```

assistant: ```c
const char *parse_syslog(const char *line, unsigned *facility, unsigned *priority) {
  unsigned num;
  if (*line++ != '<')
    return 0;
  num = strtoul(line, (char **)&line, 10);
  if (num >= 8 * 24 || *line++ != '>')
    return 0;
  *facility = num >> 3;
  *priority = num & 7;
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_syslog>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%r8
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8,0x8(%rsp)
  cmpb   $0x3c,(%rdi)
  jne    L21
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  lea    0x8(%rsp),%rsi
  mov    $0xa,%edx
  mov    %r8,%rdi
  call   <strtoul@plt>
  cmp    $0xbf,%eax
  ja     L21
  mov    0x8(%rsp),%rdx
  lea    0x1(%rdx),%r8
  mov    %r8,0x8(%rsp)
  cmpb   $0x3e,(%rdx)
  jne    L21
  mov    %eax,%edx
  and    $0x7,%eax
  shr    $0x3,%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,(%rbx)
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L21:
  add    $0x18,%rsp
  xor    %r8d,%r8d
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *parse_syslog(const char *line, unsigned *facility, unsigned *priority) {
  unsigned num;
  if (*line++ != '<')
    return 0;
  num = strtoul(line, (char **)&line, 10);
  if (num >= 8 * 24 || *line++ != '>')
    return 0;
  *facility = num >> 3;
  *priority = num & 7;
  return line;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_syslog>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%r8
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8,0x8(%rsp)
  cmpb   $0x3c,(%rdi)
  jne    L22
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  lea    0x8(%rsp),%rsi
  mov    $0xa,%edx
  mov    %r8,%rdi
  call   <strtoul@plt>
  cmp    $0xbf,%eax
  ja     L22
  mov    0x8(%rsp),%rdx
  lea    0x1(%rdx),%r8
  mov    %r8,0x8(%rsp)
  cmpb   $0x3e,(%rdx)
  jne    L22
  mov    %eax,%edx
  and    $0x7,%eax
  shr    $0x3,%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,(%rbx)
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L22:
  add    $0x18,%rsp
  xor    %r8d,%r8d
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *parse_syslog(const char *line, unsigned *facility, unsigned *priority) {
  unsigned num;
  if (*line++ != '<')
    return 0;
  num = strtoul(line, (char **)&line, 10);
  if (num >= 8 * 24 || *line++ != '>')
    return 0;
  *facility = num >> 3;
  *priority = num & 7;
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7e8(%rbp)
  jmp    L2
L11:
  mov    -0x7e4(%rbp),%eax
  cmp    -0x7e8(%rbp),%eax
  jle    L2
  mov    -0x7e4(%rbp),%eax
  mov    %eax,-0x7e8(%rbp)
  lea    -0x7e0(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
L2:
  lea    -0x7e0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x7e4(%rbp)
  cmpl   $0x0,-0x7e4(%rbp)
  jg     L11
  cmpl   $0x0,-0x7e8(%rbp)
  jle    L20
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: %s

assistant: ```c
main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getline(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    %rsp,%r12
L54:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L26
  cmp    %ebx,%ebp
  jge    L54
  lea    0x3f0(%rsp),%rdi
  mov    %r12,%rsi
  call   <copy@plt>
  mov    %ebx,%ebp
  jmp    L54
L26:
  test   %ebp,%ebp
  jg     L35
L0:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  lea    0x3f0(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: %s

assistant: ```c
main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getline(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x3f0(%rsp),%r13
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    %ebx,%ebp
  jl     L58
L4:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L0
  test   %ebp,%ebp
  jne    L6
L30:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %ebx,%ebp
  call   <copy@plt>
  jmp    L4
L6:
  lea    0x3f0(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: %s

assistant: ```c
main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getline(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x3f0(%rsp),%r13
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L51:
  cmp    %ebx,%ebp
  jl     L69
L42:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L51
  test   %ebp,%ebp
  jne    L54
L12:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %ebx,%ebp
  call   <copy@plt>
  jmp    L42
L54:
  lea    0x3f0(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string

tool: D8: %s

assistant: ```c
main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getline(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  sub    $0x96a,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L8
L21:
  addw   $0x2,-0xc(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L21
  movzwl -0xa(%rbp),%eax
  lea    -0x409f(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned short)48993;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  movzwl 0x2(%rdi),%edx
  test   %dx,%dx
  je     L10
  mov    $0x0,%eax
L18:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L18
L10:
  lea    -0x4a09(%rcx),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned short)48993;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movzwl 0x2(%rdi),%edx
  movzwl (%rdi),%ecx
  test   %dx,%dx
  je     L8
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L10
L8:
  lea    -0x4a09(%rcx),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned short)48993;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl 0x2(%rdi),%edx
  movzwl (%rdi),%ecx
  test   %dx,%dx
  je     L4
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L14
L4:
  lea    -0x4a09(%rcx),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned short)48993;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D36(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0xd(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rcx
  lea    -0xf(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0xf(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
datatype: string
name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string

tool: D36: Adam

tool: D15: Adam is the greatest

tool: D19: %s


assistant: ```c
int main() {
  char *source = "Adam";
  char *source2 = "Adam is the greatest";
  char dest[5];
  char dest2[2];
  strcpy(dest, source);
  printf("%s\n", dest);
  strncpy(dest2, source2, 2);
  printf("%s\n", dest2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x1(%rsp),%rbp
  mov    $0x2,%edx
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string
name: parse_data
arguments: tag: D24
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D8: Adam

tool: D24: %s


tool: D4: Adam is the greatest

assistant: ```c
int main() {
  char *source = "Adam";
  char *source2 = "Adam is the greatest";
  char dest[5];
  char dest2[2];
  strcpy(dest, source);
  printf("%s\n", dest);
  strncpy(dest2, source2, 2);
  printf("%s\n", dest2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rsi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  lea    0x1(%rsp),%r12
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x2,%edx
  call   <strncpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D23
datatype: string
name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D20
datatype: string

tool: D23: Adam

tool: D16: %s


tool: D20: Adam is the greatest

assistant: ```c
int main() {
  char *source = "Adam";
  char *source2 = "Adam is the greatest";
  char dest[5];
  char dest2[2];
  strcpy(dest, source);
  printf("%s\n", dest);
  strncpy(dest2, source2, 2);
  printf("%s\n", dest2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rsi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  lea    0x1(%rsp),%r12
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x2,%edx
  call   <strncpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D23
type_guessed: string

tool: D11: Adam

tool: D8: %s


tool: D23: Adam is the greatest

assistant: ```c
int main() {
  char *source = "Adam";
  char *source2 = "Adam is the greatest";
  char dest[5];
  char dest2[2];
  strcpy(dest, source);
  printf("%s\n", dest);
  strncpy(dest2, source2, 2);
  printf("%s\n", dest2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_binary_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L3:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x0,-0x4(%rbp)
  jns    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D13
data_type: string

tool: D7: 0b

tool: D13: %d

assistant: ```c
void print_binary_digits(uint8_t number, uint8_t digits) {
  printf("0b");
  for (int p = digits - 1; p >= 0; --p) {
    printf("%d", 1 & (number >> p));
  }
  printf("\n");
}
```