ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<vecAxpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vecAxpy(double *x, double *y, int size, double alpha) {
  int i;
#pragma omp parallel for schedule(static)
  for (i = 0; i < size; i++) {
    y[i] = y[i] + alpha * x[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vecAxpy>:
  endbr64
  test   %edx,%edx
  jle    L18
  mov    %edx,%edx
  mov    $0x0,%eax
L4:
  movapd %xmm0,%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L18:
  ret
```

assistant: ```c
void vecAxpy(double *x, double *y, int size, double alpha) {
  int i;
#pragma omp parallel for schedule(static)
  for (i = 0; i < size; i++) {
    y[i] = y[i] + alpha * x[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vecAxpy>:
  endbr64
  test   %edx,%edx
  jle    L9
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L5:
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L5
L9:
  ret
```

assistant: ```c
void vecAxpy(double *x, double *y, int size, double alpha) {
  int i;
#pragma omp parallel for schedule(static)
  for (i = 0; i < size; i++) {
    y[i] = y[i] + alpha * x[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vecAxpy>:
  endbr64
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L43
  lea    0x8(%rdi),%rax
  cmp    %rax,%rsi
  je     L17
  cmp    $0x1,%edx
  je     L17
  mov    %edx,%esi
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  shr    %esi
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rsi
  nop
L38:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm3
  mulpd  %xmm2,%xmm1
  addpd  %xmm3,%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L38
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L43
  mulsd  (%rdi,%rax,8),%xmm0
  lea    (%rcx,%rax,8),%rdx
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L30:
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rcx,%rax,8),%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L30
L43:
  ret
```

assistant: ```c
void vecAxpy(double *x, double *y, int size, double alpha) {
  int i;
#pragma omp parallel for schedule(static)
  for (i = 0; i < size; i++) {
    y[i] = y[i] + alpha * x[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mach64_ext_inl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x56ec,-0x14(%rbp)
  je     L46
  cmpl   $0x5aec,-0x14(%rbp)
  je     L48
  jmp    L10
L46:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x4b4,%edi
  call   <mach64_ext_readl@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L42
L48:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x4b8,%edi
  call   <mach64_ext_readl@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L42
L10:
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mach64_ext_inw@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <mach64_ext_inw@plt>
  shl    $0x10,%eax
  or     %eax,-0x4(%rbp)
  nop
L42:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t mach64_ext_inl(uint16_t port, void *p) {
  uint32_t ret;
  switch (port) {
  case 0x56ec:
    ret = mach64_ext_readl(0x400 | 0xb4, p);
    break;
  case 0x5aec:
    ret = mach64_ext_readl(0x400 | 0xb8, p);
    break;
  default:
    ret = mach64_ext_inw(port, p);
    ret |= (mach64_ext_inw(port + 2, p) << 16);
    break;
  };
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mach64_ext_inl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  cmp    $0x56ec,%edi
  je     L28
  mov    %edi,%ebx
  cmp    $0x5aec,%edi
  je     L39
  call   <mach64_ext_inw@plt>
  mov    %eax,%r12d
  lea    0x2(%rbx),%edi
  mov    %rbp,%rsi
  call   <mach64_ext_inw@plt>
  shl    $0x10,%eax
  or     %r12d,%eax
  jmp    L26
L28:
  mov    $0x4b4,%edi
  call   <mach64_ext_readl@plt>
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  mov    $0x4b8,%edi
  call   <mach64_ext_readl@plt>
  jmp    L26
```

assistant: ```c
uint32_t mach64_ext_inl(uint16_t port, void *p) {
  uint32_t ret;
  switch (port) {
  case 0x56ec:
    ret = mach64_ext_readl(0x400 | 0xb4, p);
    break;
  case 0x5aec:
    ret = mach64_ext_readl(0x400 | 0xb8, p);
    break;
  default:
    ret = mach64_ext_inw(port, p);
    ret |= (mach64_ext_inw(port + 2, p) << 16);
    break;
  };
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mach64_ext_inl>:
  endbr64
  cmp    $0x56ec,%edi
  je     L1
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    $0x5aec,%edi
  je     L6
  mov    %rsi,0x8(%rsp)
  call   <mach64_ext_inw@plt>
  mov    0x8(%rsp),%rsi
  lea    0x2(%rbx),%edi
  mov    %eax,%r12d
  call   <mach64_ext_inw@plt>
  add    $0x18,%rsp
  shl    $0x10,%eax
  pop    %rbx
  or     %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L1:
  mov    $0x4b4,%edi
  jmp    1070 <mach64_ext_readl@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x18,%rsp
  mov    $0x4b8,%edi
  pop    %rbx
  pop    %r12
  jmp    1070 <mach64_ext_readl@plt>
```

assistant: ```c
uint32_t mach64_ext_inl(uint16_t port, void *p) {
  uint32_t ret;
  switch (port) {
  case 0x56ec:
    ret = mach64_ext_readl(0x400 | 0xb4, p);
    break;
  case 0x5aec:
    ret = mach64_ext_readl(0x400 | 0xb8, p);
    break;
  default:
    ret = mach64_ext_inw(port, p);
    ret |= (mach64_ext_inw(port + 2, p) << 16);
    break;
  };
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<mach64_ext_inl>:
  endbr64
  cmp    $0x56ec,%edi
  je     L15
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    $0x5aec,%edi
  je     L1
  mov    %rsi,0x8(%rsp)
  call   <mach64_ext_inw@plt>
  mov    0x8(%rsp),%rsi
  lea    0x2(%rbx),%edi
  mov    %eax,%r12d
  call   <mach64_ext_inw@plt>
  add    $0x18,%rsp
  shl    $0x10,%eax
  pop    %rbx
  or     %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L15:
  mov    $0x4b4,%edi
  jmp    1070 <mach64_ext_readl@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x18,%rsp
  mov    $0x4b8,%edi
  pop    %rbx
  pop    %r12
  jmp    1070 <mach64_ext_readl@plt>
```

assistant: ```c
uint32_t mach64_ext_inl(uint16_t port, void *p) {
  uint32_t ret;
  switch (port) {
  case 0x56ec:
    ret = mach64_ext_readl(0x400 | 0xb4, p);
    break;
  case 0x5aec:
    ret = mach64_ext_readl(0x400 | 0xb8, p);
    break;
  default:
    ret = mach64_ext_inw(port, p);
    ret |= (mach64_ext_inw(port + 2, p) << 16);
    break;
  };
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_U16Fixed16Number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D40(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd D35(%rip),%xmm0
  jb     L47
  mov    $0x1,%eax
  jmp    L37
L47:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L9
  mov    $0x1,%eax
  jmp    L37
L9:
  movsd  -0x18(%rbp),%xmm0
  comisd D25(%rip),%xmm0
  jae    L6
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L6:
  movsd  -0x18(%rbp),%xmm0
  movsd  D25(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movabs $0x8000000000000000,%rax
  xor    %rax,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x18,%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x3,%rax
  mov    -0x8(%rbp),%rdx
  mov    %dl,(%rax)
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D40
datatype: f64
name: unpack_data
arguments: data_tag: D3
datatype: f64
name: unpack_data
arguments: data_tag: D35
datatype: f64[2]
name: unpack_data
arguments: data_tag: D25
datatype: f32

tool: D40: 65536

tool: D3: 0.5

tool: {"D35": [4294967296.0,9.223372036854776e18]}

tool: D25: 0

assistant: ```c
int write_U16Fixed16Number(double d, char *p) {
  unsigned long o32;
  d = d * 65536.0 + 0.5;
  if (d >= 4294967296.0)
    return 1;
  if (d < 0.0)
    return 1;
  o32 = (unsigned long)d;
  ((unsigned char *)p)[0] = (unsigned char)((o32) >> 24);
  ((unsigned char *)p)[1] = (unsigned char)((o32) >> 16);
  ((unsigned char *)p)[2] = (unsigned char)((o32) >> 8);
  ((unsigned char *)p)[3] = (unsigned char)((o32));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<write_U16Fixed16Number>:
  endbr64
  mulsd  D34(%rip),%xmm0
  addsd  D18(%rip),%xmm0
  mov    $0x1,%eax
  comisd D30(%rip),%xmm0
  jae    L3
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L3
  comisd D12(%rip),%xmm0
  jae    L15
  cvttsd2si %xmm0,%rax
L23:
  mov    %rax,%rdx
  shr    $0x18,%rdx
  mov    %dl,(%rdi)
  mov    %rax,%rdx
  shr    $0x10,%rdx
  mov    %dl,0x1(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdi)
  mov    %al,0x3(%rdi)
  mov    $0x0,%eax
L3:
  ret
L15:
  subsd  D12(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  btc    $0x3f,%rax
  jmp    L23
```

tool_calls: name: disassemble_data
arguments: data_tag: D34
type: f64
name: disassemble_data
arguments: data_tag: D18
type: f64
name: disassemble_data
arguments: data_tag: D30
type: f64[2]
name: disassemble_data
arguments: data_tag: D12
type: f32

tool: D34: 65536

tool: D18: 0.5

tool: {"D30": [4294967296.0,9.223372036854776e18]}

tool: D12: 0

assistant: ```c
int write_U16Fixed16Number(double d, char *p) {
  unsigned long o32;
  d = d * 65536.0 + 0.5;
  if (d >= 4294967296.0)
    return 1;
  if (d < 0.0)
    return 1;
  o32 = (unsigned long)d;
  ((unsigned char *)p)[0] = (unsigned char)((o32) >> 24);
  ((unsigned char *)p)[1] = (unsigned char)((o32) >> 16);
  ((unsigned char *)p)[2] = (unsigned char)((o32) >> 8);
  ((unsigned char *)p)[3] = (unsigned char)((o32));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<write_U16Fixed16Number>:
  endbr64
  mulsd  D8(%rip),%xmm0
  mov    $0x1,%eax
  addsd  D27(%rip),%xmm0
  comisd D35(%rip),%xmm0
  jae    L36
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L36
  movsd  D31(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L15
  cvttsd2si %xmm0,%rax
L9:
  bswap  %eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
L36:
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  btc    $0x3f,%rax
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D8
datatype: f64
name: parse_data
arguments: label: D27
datatype: f64
name: parse_data
arguments: label: D35
datatype: f64[2]
name: parse_data
arguments: label: D31
datatype: f32[2]

tool: D8: 65536

tool: D27: 0.5

tool: {"D35": [4294967296.0,9.223372036854776e18]}

tool: {"D31": [0.0,448.0]}

assistant: ```c
int write_U16Fixed16Number(double d, char *p) {
  unsigned long o32;
  d = d * 65536.0 + 0.5;
  if (d >= 4294967296.0)
    return 1;
  if (d < 0.0)
    return 1;
  o32 = (unsigned long)d;
  ((unsigned char *)p)[0] = (unsigned char)((o32) >> 24);
  ((unsigned char *)p)[1] = (unsigned char)((o32) >> 16);
  ((unsigned char *)p)[2] = (unsigned char)((o32) >> 8);
  ((unsigned char *)p)[3] = (unsigned char)((o32));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_U16Fixed16Number>:
  endbr64
  mulsd  D11(%rip),%xmm0
  mov    $0x1,%eax
  addsd  D8(%rip),%xmm0
  comisd D13(%rip),%xmm0
  jae    L14
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L14
  movsd  D14(%rip),%xmm1
  comisd %xmm1,%xmm0
  jae    L37
  cvttsd2si %xmm0,%rax
L36:
  bswap  %eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
L14:
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  btc    $0x3f,%rax
  jmp    L36
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
data_type: f64
name: extract_symbolic_data
arguments: label: D8
data_type: f64
name: extract_symbolic_data
arguments: label: D13
data_type: f64[2]
name: extract_symbolic_data
arguments: label: D14
data_type: f32[2]

tool: D11: 65536

tool: D8: 0.5

tool: {"D13": [4294967296.0,9.223372036854776e18]}

tool: {"D14": [0.0,448.0]}

assistant: ```c
int write_U16Fixed16Number(double d, char *p) {
  unsigned long o32;
  d = d * 65536.0 + 0.5;
  if (d >= 4294967296.0)
    return 1;
  if (d < 0.0)
    return 1;
  o32 = (unsigned long)d;
  ((unsigned char *)p)[0] = (unsigned char)((o32) >> 24);
  ((unsigned char *)p)[1] = (unsigned char)((o32) >> 16);
  ((unsigned char *)p)[2] = (unsigned char)((o32) >> 8);
  ((unsigned char *)p)[3] = (unsigned char)((o32));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_fillin_sync>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  add    0x4(%rsp),%eax
  cltq
  movb   $0xff,(%rbx)
  movb   $0xff,0x1(%rbx)
  movb   $0x43,0x2(%rbx)
  movb   $0x4b,0x3(%rbx)
  movb   $0x5d,0x4(%rbx)
  movb   $0x72,0x5(%rbx)
  movb   $0xfb,0x6(%rbx)
  movb   $0x43,0x7(%rbx)
  mov    %bpl,0x8(%rbx)
  movb   $0x0,0x9(%rbx)
  movb   $0x0,0xa(%rbx)
  movb   $0x0,0xb(%rbx)
  lea    0xc(,%rbp,8),%edx
  movslq %edx,%rdx
  mov    %rax,%rcx
  shr    $0x38,%rcx
  mov    %cl,(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x30,%rcx
  mov    %cl,0x1(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x28,%rcx
  mov    %cl,0x2(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x20,%rcx
  mov    %cl,0x3(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x18,%rcx
  mov    %cl,0x4(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x10,%rcx
  mov    %cl,0x5(%rbx,%rdx,1)
  movzbl %ah,%ecx
  mov    %cl,0x6(%rbx,%rdx,1)
  mov    %al,0x7(%rbx,%rdx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _fillin_sync(unsigned char *buf, int count) {
  int offset = 12 + (8 * count);
  struct timeval tv = {0, 0};
  unsigned long long ts;
  gettimeofday(&tv, NULL);
  ts = tv.tv_sec * 1000 + tv.tv_usec;
  buf[0] = 0xff;
  buf[1] = 0xff;
  buf[2] = 'C';
  buf[3] = 'K';
  buf[4] = 0xff & (0x5d72fb43 >> 24);
  buf[5] = 0xff & (0x5d72fb43 >> 16);
  buf[6] = 0xff & (0x5d72fb43 >> 8);
  buf[7] = 0xff & 0x5d72fb43;
  buf[8] = count;
  buf[9] = 0;
  buf[10] = 0;
  buf[11] = 0;
  buf[offset + 0] = (ts >> 56) & 0xff;
  buf[offset + 1] = (ts >> 48) & 0xff;
  buf[offset + 2] = (ts >> 40) & 0xff;
  buf[offset + 3] = (ts >> 32) & 0xff;
  buf[offset + 4] = (ts >> 24) & 0xff;
  buf[offset + 5] = (ts >> 16) & 0xff;
  buf[offset + 6] = (ts >> 8) & 0xff;
  buf[offset + 7] = ts & 0xff;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_fillin_sync>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  add    0x4(%rsp),%eax
  xor    %edx,%edx
  movabs $0x43fb725d4b43ffff,%rsi
  cltq
  mov    %dx,0x9(%rbx)
  lea    0xc(,%rbp,8),%edx
  mov    %rax,%rcx
  movslq %edx,%rdx
  mov    %rsi,(%rbx)
  shr    $0x38,%rcx
  mov    %bpl,0x8(%rbx)
  movb   $0x0,0xb(%rbx)
  mov    %cl,(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x30,%rcx
  mov    %ah,0x6(%rbx,%rdx,1)
  mov    %cl,0x1(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x28,%rcx
  mov    %al,0x7(%rbx,%rdx,1)
  mov    %cl,0x2(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x20,%rcx
  mov    %cl,0x3(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x18,%rcx
  mov    %cl,0x4(%rbx,%rdx,1)
  mov    %rax,%rcx
  shr    $0x10,%rcx
  mov    %cl,0x5(%rbx,%rdx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _fillin_sync(unsigned char *buf, int count) {
  int offset = 12 + (8 * count);
  struct timeval tv = {0, 0};
  unsigned long long ts;
  gettimeofday(&tv, NULL);
  ts = tv.tv_sec * 1000 + tv.tv_usec;
  buf[0] = 0xff;
  buf[1] = 0xff;
  buf[2] = 'C';
  buf[3] = 'K';
  buf[4] = 0xff & (0x5d72fb43 >> 24);
  buf[5] = 0xff & (0x5d72fb43 >> 16);
  buf[6] = 0xff & (0x5d72fb43 >> 8);
  buf[7] = 0xff & 0x5d72fb43;
  buf[8] = count;
  buf[9] = 0;
  buf[10] = 0;
  buf[11] = 0;
  buf[offset + 0] = (ts >> 56) & 0xff;
  buf[offset + 1] = (ts >> 48) & 0xff;
  buf[offset + 2] = (ts >> 40) & 0xff;
  buf[offset + 3] = (ts >> 32) & 0xff;
  buf[offset + 4] = (ts >> 24) & 0xff;
  buf[offset + 5] = (ts >> 16) & 0xff;
  buf[offset + 6] = (ts >> 8) & 0xff;
  buf[offset + 7] = ts & 0xff;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<_fillin_sync>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <gettimeofday@plt>
  mov    D7(%rip),%rax
  imul   $0x3e8,(%rsp),%edx
  mov    %bpl,0x8(%rbx)
  add    0x4(%rsp),%edx
  movb   $0x0,0xb(%rbx)
  movslq %edx,%rdx
  mov    %rax,(%rbx)
  xor    %eax,%eax
  mov    %ax,0x9(%rbx)
  movzbl %dl,%eax
  mov    %rdx,%rsi
  movzbl %dh,%edi
  shl    $0x8,%rax
  shr    $0x10,%rsi
  mov    %rdx,%rcx
  or     %rdi,%rax
  movzbl %sil,%esi
  shr    $0x18,%rcx
  shl    $0x8,%rax
  movzbl %cl,%ecx
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  mov    %rdx,%rcx
  shr    $0x38,%rcx
  shl    $0x8,%rax
  or     %rcx,%rax
  mov    %rdx,%rcx
  shr    $0x38,%rcx
  shl    $0x8,%rax
  or     %rcx,%rax
  mov    %rdx,%rcx
  lea    0xc(,%rbp,8),%edx
  shr    $0x38,%rcx
  shl    $0x8,%rax
  movslq %edx,%rdx
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  mov    %rax,(%rbx,%rdx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: byte[8]

tool: {"D7": [0xff,0xff,0x43,0x4b,0x5d,0x72,0xfb,0x43]}

assistant: ```c
int _fillin_sync(unsigned char *buf, int count) {
  int offset = 12 + (8 * count);
  struct timeval tv = {0, 0};
  unsigned long long ts;
  gettimeofday(&tv, NULL);
  ts = tv.tv_sec * 1000 + tv.tv_usec;
  buf[0] = 0xff;
  buf[1] = 0xff;
  buf[2] = 'C';
  buf[3] = 'K';
  buf[4] = 0xff & (0x5d72fb43 >> 24);
  buf[5] = 0xff & (0x5d72fb43 >> 16);
  buf[6] = 0xff & (0x5d72fb43 >> 8);
  buf[7] = 0xff & 0x5d72fb43;
  buf[8] = count;
  buf[9] = 0;
  buf[10] = 0;
  buf[11] = 0;
  buf[offset + 0] = (ts >> 56) & 0xff;
  buf[offset + 1] = (ts >> 48) & 0xff;
  buf[offset + 2] = (ts >> 40) & 0xff;
  buf[offset + 3] = (ts >> 32) & 0xff;
  buf[offset + 4] = (ts >> 24) & 0xff;
  buf[offset + 5] = (ts >> 16) & 0xff;
  buf[offset + 6] = (ts >> 8) & 0xff;
  buf[offset + 7] = ts & 0xff;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<roundfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sBoxLookup@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <per@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int roundfunc(int stateVal, int key_round) {
  stateVal = sBoxLookup(stateVal);
  stateVal = per(stateVal);
  stateVal = stateVal ^ key_round;
  return stateVal;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<roundfunc>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <sBoxLookup@plt>
  mov    %eax,%edi
  call   <per@plt>
  xor    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int roundfunc(int stateVal, int key_round) {
  stateVal = sBoxLookup(stateVal);
  stateVal = per(stateVal);
  stateVal = stateVal ^ key_round;
  return stateVal;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<roundfunc>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <sBoxLookup@plt>
  mov    %eax,%edi
  call   <per@plt>
  xor    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int roundfunc(int stateVal, int key_round) {
  stateVal = sBoxLookup(stateVal);
  stateVal = per(stateVal);
  stateVal = stateVal ^ key_round;
  return stateVal;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<roundfunc>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <sBoxLookup@plt>
  mov    %eax,%edi
  call   <per@plt>
  xor    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int roundfunc(int stateVal, int key_round) {
  stateVal = sBoxLookup(stateVal);
  stateVal = per(stateVal);
  stateVal = stateVal ^ key_round;
  return stateVal;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getRandom@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x9,-0xc(%rbp)
  jle    L13
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: *(p + [%d]) : %d


assistant: ```c
int main() {
  int *p;
  int i;
  p = getRandom();
  for (i = 0; i < 10; i++) {
    printf("*(p + [%d]) : %d\n", i, *(p + i));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <getRandom@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D6(%rip),%r12
L1:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L1
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: *(p + [%d]) : %d


assistant: ```c
int main() {
  int *p;
  int i;
  p = getRandom();
  for (i = 0; i < 10; i++) {
    printf("*(p + [%d]) : %d\n", i, *(p + i));
  }
  return 0;
}
```