ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bubbleSort>:
  endbr64
  lea    0x4(%rdi),%r9
  sub    $0x1,%esi
  js     L10
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jle    L9
  nopl   (%rax)
L35:
  mov    %r8d,%eax
  mov    %rdi,%rdx
  lea    (%r9,%rax,4),%rsi
  nopw   0x0(%rax,%rax,1)
L44:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L18
  movq   %xmm1,(%rdx)
L18:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L44
L3:
  mov    %r8d,%esi
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jg     L35
L9:
  test   %r8d,%r8d
  jns    L3
  ret
L10:
  ret
```

assistant: ```c
void bubbleSort(int numbers[], int array_size) {
  int i, j, temp;
  for (i = (array_size - 1); i >= 0; i--) {
    for (j = 1; j <= i; j++) {
      if (numbers[j - 1] > numbers[j]) {
        temp = numbers[j - 1];
        numbers[j - 1] = numbers[j];
        numbers[j] = temp;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fork1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  call   <fork@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L9
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  cmpl   $0x0,-0x8(%rbp)
  jne    L19
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D23
type_guessed: string
name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D35
type_guessed: string

tool: D15: Parent PID: %i 


tool: D23: [%i] parent of [%i]


tool: D28: [%i] child


tool: D35:  PID= %i 


assistant: ```c
int fork1(void) {
  pid_t pid = getpid();
  pid_t cpid, mypid;
  printf("Parent PID: %i \n", pid);
  cpid = fork();
  if (cpid > 0) {
    mypid = getpid();
    printf("[%i] parent of [%i]\n", mypid, cpid);
  }
  if (cpid == 0) {
    mypid = getpid();
    printf("[%i] child\n", mypid);
  }
  printf(" PID= %i \n", cpid);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fork1>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  call   <fork@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L23
  jne    L22
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L23:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  mov    %ebx,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D17
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string

tool: D5: Parent PID: %i 


tool: D17: [%i] child


tool: D21: [%i] parent of [%i]


tool: D6:  PID= %i 


assistant: ```c
int fork1(void) {
  pid_t pid = getpid();
  pid_t cpid, mypid;
  printf("Parent PID: %i \n", pid);
  cpid = fork();
  if (cpid > 0) {
    mypid = getpid();
    printf("[%i] parent of [%i]\n", mypid, cpid);
  }
  if (cpid == 0) {
    mypid = getpid();
    printf("[%i] child\n", mypid);
  }
  printf(" PID= %i \n", cpid);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<fork1>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D31(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jg     L12
  jne    L15
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D35(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L15:
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebp,%edx
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D31
type_infered: string
name: unpack_data
arguments: tag: D35
type_infered: string
name: unpack_data
arguments: tag: D24
type_infered: string
name: unpack_data
arguments: tag: D19
type_infered: string

tool: D31: Parent PID: %i 


tool: D35: [%i] child


tool: D24:  PID= %i 


tool: D19: [%i] parent of [%i]


assistant: ```c
int fork1(void) {
  pid_t pid = getpid();
  pid_t cpid, mypid;
  printf("Parent PID: %i \n", pid);
  cpid = fork();
  if (cpid > 0) {
    mypid = getpid();
    printf("[%i] parent of [%i]\n", mypid, cpid);
  }
  if (cpid == 0) {
    mypid = getpid();
    printf("[%i] child\n", mypid);
  }
  printf(" PID= %i \n", cpid);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fork1>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jg     L11
  jne    L23
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L23:
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebp,%edx
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D5
type: string
name: parse_data
arguments: data_label: D35
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: D11: Parent PID: %i 


tool: D5: [%i] child


tool: D35:  PID= %i 


tool: D0: [%i] parent of [%i]


assistant: ```c
int fork1(void) {
  pid_t pid = getpid();
  pid_t cpid, mypid;
  printf("Parent PID: %i \n", pid);
  cpid = fork();
  if (cpid > 0) {
    mypid = getpid();
    printf("[%i] parent of [%i]\n", mypid, cpid);
  }
  if (cpid == 0) {
    mypid = getpid();
    printf("[%i] child\n", mypid);
  }
  printf(" PID= %i \n", cpid);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<io_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L24
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L24
  mov    $0xffffffffffffffff,%rax
  jmp    L4
L24:
  mov    -0x8(%rbp),%rax
L4:
  leave
  ret
```

assistant: ```c
long io_write(const void *buf, size_t bytes, void *uptr) {
  size_t sz = fwrite(buf, 1, bytes, uptr);
  if (sz < bytes && errno)
    return -1;
  return sz;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<io_write>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    %rax,%rbx
  jbe    L19
  mov    D2(%rip),%rdx
  cmpq   $0x0,(%rdx)
  jne    L8
L19:
  pop    %rbx
  ret
L8:
  mov    $0xffffffffffffffff,%rax
  jmp    L19
```

assistant: ```c
long io_write(const void *buf, size_t bytes, void *uptr) {
  size_t sz = fwrite(buf, 1, bytes, uptr);
  if (sz < bytes && errno)
    return -1;
  return sz;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<io_write>:
  endbr64
  push   %rbx
  mov    %rdx,%rcx
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    %rax,%rbx
  jbe    L16
  mov    D1(%rip),%rdx
  cmpq   $0x0,(%rdx)
  jne    L10
L16:
  pop    %rbx
  ret
L10:
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  ret
```

assistant: ```c
long io_write(const void *buf, size_t bytes, void *uptr) {
  size_t sz = fwrite(buf, 1, bytes, uptr);
  if (sz < bytes && errno)
    return -1;
  return sz;
}
```
user: Translate the below assembly code into C programming language:

```asm
<io_write>:
  endbr64
  push   %rbx
  mov    %rdx,%rcx
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    %rax,%rbx
  jbe    L10
  mov    D9(%rip),%rdx
  cmpq   $0x0,(%rdx)
  jne    L7
L10:
  pop    %rbx
  ret
L7:
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  ret
```

assistant: ```c
long io_write(const void *buf, size_t bytes, void *uptr) {
  size_t sz = fwrite(buf, 1, bytes, uptr);
  if (sz < bytes && errno)
    return -1;
  return sz;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<daxpy>:
  endbr64
  mov    %rsi,%r9
  mov    %rcx,%rsi
  test   %edi,%edi
  jle    L111
  ucomisd D8(%rip),%xmm0
  setnp  %al
  mov    $0x0,%ecx
  cmovne %ecx,%eax
  test   %al,%al
  jne    L111
  cmp    $0x1,%edx
  jne    L100
  cmp    $0x1,%r8d
  jne    L100
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  lea    (%rdi,%rax,1),%r8d
  and    $0x3,%r8d
  sub    %eax,%r8d
  test   $0x3,%dil
  je     L149
  test   %r8d,%r8d
  jle    L6
  mov    $0x0,%eax
L56:
  movapd %xmm0,%xmm1
  mulsd  (%r9,%rax,8),%xmm1
  addsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L56
L6:
  cmp    $0x3,%edi
  jle    L111
L149:
  cmp    %r8d,%edi
  jle    L111
  movslq %r8d,%r10
  lea    0x0(,%r10,8),%rdx
  lea    (%rsi,%rdx,1),%rax
  add    %r9,%rdx
  lea    -0x1(%rdi),%ecx
  sub    %r8d,%ecx
  shr    $0x2,%ecx
  mov    %ecx,%ecx
  lea    (%r10,%rcx,4),%rcx
  lea    0x20(%rsi,%rcx,8),%rcx
L82:
  movapd %xmm0,%xmm1
  mulsd  (%rdx),%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  movapd %xmm0,%xmm1
  mulsd  0x8(%rdx),%xmm1
  addsd  0x8(%rax),%xmm1
  movsd  %xmm1,0x8(%rax)
  movapd %xmm0,%xmm1
  mulsd  0x10(%rdx),%xmm1
  addsd  0x10(%rax),%xmm1
  movsd  %xmm1,0x10(%rax)
  movapd %xmm0,%xmm1
  mulsd  0x18(%rdx),%xmm1
  addsd  0x18(%rax),%xmm1
  movsd  %xmm1,0x18(%rax)
  add    $0x20,%rax
  add    $0x20,%rdx
  cmp    %rcx,%rax
  jne    L82
L111:
  ret
L100:
  mov    $0x0,%ecx
  test   %edx,%edx
  js     L117
L35:
  mov    $0x0,%eax
  test   %r8d,%r8d
  js     L137
L53:
  movslq %r8d,%r8
  shl    $0x3,%r8
  cltq
  lea    (%rsi,%rax,8),%rax
  movslq %edx,%rsi
  shl    $0x3,%rsi
  movslq %ecx,%rcx
  lea    (%r9,%rcx,8),%rcx
  mov    $0x0,%edx
L60:
  movapd %xmm0,%xmm1
  mulsd  (%rcx),%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x1,%edx
  add    %r8,%rax
  add    %rsi,%rcx
  cmp    %edx,%edi
  jg     L60
  ret
L117:
  mov    $0x1,%ecx
  sub    %edi,%ecx
  imul   %edx,%ecx
  jmp    L35
L137:
  mov    $0x1,%eax
  sub    %edi,%eax
  imul   %r8d,%eax
  jmp    L53
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: f64

tool: D8: 0

assistant: ```c
void daxpy(int n, double da, double dx[], int incx, double dy[], int incy) {
  int i, ix, iy, m, mp1;
  mp1 = 0;
  m = 0;
  if (n <= 0)
    return;
  if (da == 0.0e0)
    return;
  if (incx != 1 || incy != 1) {
    ix = 0;
    iy = 0;
    if (incx < 0)
      ix = (-n + 1) * incx;
    if (incy < 0)
      iy = (-n + 1) * incy;
    for (i = 0; i < n; i++) {
      dy[iy] = dy[iy] + da * dx[ix];
      ix = ix + incx;
      iy = iy + incy;
    }
    return;
  }
  m = n % 4;
  if (m != 0) {
    for (i = 0; i < m; i++)
      dy[i] = dy[i] + da * dx[i];
    if (n < 4)
      return;
  }
  for (i = m; i < n; i = i + 4) {
    dy[i] = dy[i] + da * dx[i];
    dy[i + 1] = dy[i + 1] + da * dx[i + 1];
    dy[i + 2] = dy[i + 2] + da * dx[i + 2];
    dy[i + 3] = dy[i + 3] + da * dx[i + 3];
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<daxpy>:
  endbr64
  test   %edi,%edi
  mov    %rcx,%r9
  mov    %rsi,%r10
  setle  %cl
  jle    L93
  ucomisd D4(%rip),%xmm0
  setnp  %al
  cmovne %ecx,%eax
  test   %al,%al
  jne    L93
  cmp    $0x1,%edx
  jne    L97
  cmp    $0x1,%r8d
  jne    L97
  mov    %edi,%esi
  and    $0x3,%esi
  jne    L11
L43:
  cmp    %esi,%edi
  jle    L64
  lea    -0x1(%rdi),%ecx
  movslq %esi,%r8
  sub    %rsi,%rcx
  lea    0x0(,%r8,8),%rdx
  and    $0xfffffffc,%ecx
  lea    (%r9,%rdx,1),%rax
  add    %r10,%rdx
  add    %r8,%rcx
  lea    0x20(%r9,%rcx,8),%rcx
  nopl   0x0(%rax)
L19:
  movsd  (%rdx),%xmm1
  add    $0x20,%rax
  add    $0x20,%rdx
  mulsd  %xmm0,%xmm1
  addsd  -0x20(%rax),%xmm1
  movsd  %xmm1,-0x20(%rax)
  movsd  -0x18(%rdx),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  -0x18(%rax),%xmm1
  movsd  %xmm1,-0x18(%rax)
  movsd  -0x10(%rdx),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  -0x10(%rax),%xmm1
  movsd  %xmm1,-0x10(%rax)
  movsd  -0x8(%rdx),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  -0x8(%rax),%xmm1
  movsd  %xmm1,-0x8(%rax)
  cmp    %rax,%rcx
  jne    L19
L93:
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
L4:
  movsd  (%r10,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%r9,%rax,8),%xmm1
  movsd  %xmm1,(%r9,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L4
  cmp    $0x3,%edi
  jg     L43
  ret
  nopw   0x0(%rax,%rax,1)
L97:
  xor    %ecx,%ecx
  test   %edx,%edx
  jns    L0
  mov    $0x1,%ecx
  sub    %edi,%ecx
  imul   %edx,%ecx
L0:
  xor    %eax,%eax
  test   %r8d,%r8d
  jns    L61
  mov    $0x1,%eax
  sub    %edi,%eax
  imul   %r8d,%eax
L61:
  movslq %edx,%rsi
  movslq %r8d,%r8
  cltq
  movslq %ecx,%rcx
  shl    $0x3,%r8
  lea    (%r9,%rax,8),%rax
  shl    $0x3,%rsi
  lea    (%r10,%rcx,8),%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L26:
  movsd  (%rcx),%xmm1
  add    $0x1,%edx
  add    %rsi,%rcx
  mulsd  %xmm0,%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    %r8,%rax
  cmp    %edx,%edi
  jg     L26
  ret
  xchg   %ax,%ax
L64:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: f64

tool: D4: 0

assistant: ```c
void daxpy(int n, double da, double dx[], int incx, double dy[], int incy) {
  int i, ix, iy, m, mp1;
  mp1 = 0;
  m = 0;
  if (n <= 0)
    return;
  if (da == 0.0e0)
    return;
  if (incx != 1 || incy != 1) {
    ix = 0;
    iy = 0;
    if (incx < 0)
      ix = (-n + 1) * incx;
    if (incy < 0)
      iy = (-n + 1) * incy;
    for (i = 0; i < n; i++) {
      dy[iy] = dy[iy] + da * dx[ix];
      ix = ix + incx;
      iy = iy + incy;
    }
    return;
  }
  m = n % 4;
  if (m != 0) {
    for (i = 0; i < m; i++)
      dy[i] = dy[i] + da * dx[i];
    if (n < 4)
      return;
  }
  for (i = m; i < n; i = i + 4) {
    dy[i] = dy[i] + da * dx[i];
    dy[i + 1] = dy[i + 1] + da * dx[i + 1];
    dy[i + 2] = dy[i + 2] + da * dx[i + 2];
    dy[i + 3] = dy[i + 3] + da * dx[i + 3];
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<avg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L33
L10:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L10
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  js     L27
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L31
L27:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L31:
  movss  -0xc(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float avg(float *Buf, size_t Cnt) {
  float Avg = 0;
  size_t n;
  for (n = 0; n < Cnt; n++) {
    Avg += Buf[n];
  }
  Avg /= Cnt;
  return Avg;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<avg>:
  endbr64
  test   %rsi,%rsi
  je     L36
  mov    %rdi,%rax
  lea    (%rdi,%rsi,4),%rdx
  pxor   %xmm0,%xmm0
L13:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L13
L35:
  test   %rsi,%rsi
  js     L24
  pxor   %xmm1,%xmm1
  cvtsi2ss %rsi,%xmm1
L8:
  divss  %xmm1,%xmm0
  ret
L36:
  pxor   %xmm0,%xmm0
  jmp    L35
L24:
  mov    %rsi,%rax
  shr    %rax
  and    $0x1,%esi
  or     %rsi,%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm1
  jmp    L8
```

assistant: ```c
float avg(float *Buf, size_t Cnt) {
  float Avg = 0;
  size_t n;
  for (n = 0; n < Cnt; n++) {
    Avg += Buf[n];
  }
  Avg /= Cnt;
  return Avg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<avg>:
  endbr64
  test   %rsi,%rsi
  je     L1
  lea    (%rdi,%rsi,4),%rax
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax)
L12:
  addss  (%rdi),%xmm0
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L12
  pxor   %xmm1,%xmm1
  cvtsi2ss %rsi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %rsi,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float avg(float *Buf, size_t Cnt) {
  float Avg = 0;
  size_t n;
  for (n = 0; n < Cnt; n++) {
    Avg += Buf[n];
  }
  Avg /= Cnt;
  return Avg;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<avg>:
  endbr64
  test   %rsi,%rsi
  je     L53
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L28
  mov    %rsi,%rdx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
L56:
  movups (%rax),%xmm1
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L56
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%sil
  je     L63
L5:
  lea    0x1(%rax),%rcx
  addss  (%rdi,%rax,4),%xmm0
  lea    0x0(,%rax,4),%rdx
  cmp    %rcx,%rsi
  jbe    L63
  add    $0x2,%rax
  addss  0x4(%rdi,%rdx,1),%xmm0
  cmp    %rax,%rsi
  jbe    L63
  addss  0x8(%rdi,%rdx,1),%xmm0
L63:
  pxor   %xmm1,%xmm1
  cvtsi2ss %rsi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %rsi,%xmm1
  divss  %xmm1,%xmm0
  ret
L28:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L5
```

assistant: ```c
float avg(float *Buf, size_t Cnt) {
  float Avg = 0;
  size_t n;
  for (n = 0; n < Cnt; n++) {
    Avg += Buf[n];
  }
  Avg /= Cnt;
  return Avg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<relacao_02>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x323052,0x34(%rsp)
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  call   <ehReflexiva@plt>
  cmp    $0x1,%eax
  jne    L62
L37:
  mov    $0x0,%eax
  call   <ehSimetrica@plt>
  cmp    $0x1,%eax
  jne    L71
L55:
  mov    $0x0,%eax
  call   <ehTransitiva@plt>
  cmp    $0x1,%eax
  jne    L65
L4:
  mov    $0x0,%eax
  call   <ehAntiSimetrica@plt>
  test   %eax,%eax
  jne    L66
L98:
  mov    $0x0,%eax
  call   <ehEquivalencia@plt>
  cmp    $0x1,%eax
  jne    L69
L97:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  ret
L62:
  lea    0x34(%rsp),%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L71:
  lea    0x34(%rsp),%rsi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L55
L65:
  lea    0x34(%rsp),%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L4
L66:
  lea    0x34(%rsp),%rsi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L98
L69:
  lea    0x34(%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L97
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D36
type: string
name: disassemble_data
arguments: data_tag: D32
type: string
name: disassemble_data
arguments: data_tag: D11
type: string
name: disassemble_data
arguments: data_tag: D43
type: string
name: disassemble_data
arguments: data_tag: D22
type: string

tool: D36: ERRO: [%s] - Problema na propriedade reflexiva!


tool: D32: ERRO: [%s] - Problema na propriedade simetrica!


tool: D11: ERRO: [%s] - Problema na propriedade transitiva!


tool: D43: ERRO: [%s] - Problema na propriedade anti-simetrica!


tool: D22: ERRO: [%s] - Problema na verifiacao da equivalencia!


assistant: ```c
void relacao_02() {
  char nome[4] = "R02";
  int conjS[3] = {1, 2, 3};
  int rho[5][2] = {{1, 1}, {1, 2}, {2, 1}, {2, 2}, {3, 3}};
  int reflexiva = 1;
  int simetrica = 1;
  int transitiva = 1;
  int anti_simetrica = 0;
  int equivalencia = 1;
  printf("\n");
  if (ehReflexiva(rho) != reflexiva) {
    printf("ERRO: [%s] - Problema na propriedade reflexiva!\n", nome);
  }
  if (ehSimetrica() != simetrica) {
    printf("ERRO: [%s] - Problema na propriedade simetrica!\n", nome);
  }
  if (ehTransitiva() != transitiva) {
    printf("ERRO: [%s] - Problema na propriedade transitiva!\n", nome);
  }
  if (ehAntiSimetrica() != anti_simetrica) {
    printf("ERRO: [%s] - Problema na propriedade anti-simetrica!\n", nome);
  }
  if (ehEquivalencia() != equivalencia) {
    printf("ERRO: [%s] - Problema na verifiacao da equivalencia!\n", nome);
  }
}
```