ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<j0g2_vec_malloc>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpw   $0x0,(%rcx)
  mov    (%rdi),%edi
  je     L3
  lea    0x1(%rdi),%esi
  mov    %rcx,%rax
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x4,%rax
  mov    %esi,%edi
  lea    0x1(%rsi),%esi
  cmpw   $0x0,(%rax)
  jne    L8
  mov    %edi,(%rbx)
L3:
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    (%rbx),%esi
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <j0g2_vec@plt>
```

assistant: ```c
int j0g2_vec_malloc(unsigned *c, float **v, const char *jason, unsigned short *index) {
  unsigned short *i;
  for (i = index; (*i); ++(*c), i += 2)
    ;
  (*v) = malloc(sizeof(float) * (*c));
  return j0g2_vec((*v), (*c), jason, index);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<j0g2_vec_malloc>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpw   $0x0,(%rcx)
  mov    (%rdi),%edi
  je     L6
  lea    0x1(%rdi),%esi
  mov    %rcx,%rax
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x4,%rax
  mov    %esi,%edi
  lea    0x1(%rsi),%esi
  cmpw   $0x0,(%rax)
  jne    L7
  mov    %edi,(%rbx)
L6:
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    (%rbx),%esi
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <j0g2_vec@plt>
```

assistant: ```c
int j0g2_vec_malloc(unsigned *c, float **v, const char *jason, unsigned short *index) {
  unsigned short *i;
  for (i = index; (*i); ++(*c), i += 2)
    ;
  (*v) = malloc(sizeof(float) * (*c));
  return j0g2_vec((*v), (*c), jason, index);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_power_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L12
  addq   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L42
L29:
  nop
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L29
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L46
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <is_exponent@plt>
  jmp    L39
L46:
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int is_power_float(s)
char *s;
{
  char *x;
  if (*s == '-')
    s++;
  for (x = s; isdigit(*s); s++)
    continue;
  return (s > x ? is_exponent(s) : 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_power_float>:
  endbr64
  cmpb   $0x2d,(%rdi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  movsbl (%rdi),%edx
  sub    $0x30,%edx
  mov    $0x0,%eax
  cmp    $0x9,%edx
  jbe    L0
  ret
L0:
  mov    %rdi,%rax
L10:
  add    $0x1,%rax
  movsbl (%rax),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L10
  cmp    %rax,%rdi
  jae    L23
  sub    $0x8,%rsp
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <is_exponent@plt>
  add    $0x8,%rsp
  ret
L23:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_power_float(s)
char *s;
{
  char *x;
  if (*s == '-')
    s++;
  for (x = s; isdigit(*s); s++)
    continue;
  return (s > x ? is_exponent(s) : 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_power_float>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0x2d,%al
  jne    L17
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L17:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L35
L0:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L35:
  mov    %rdi,%r8
L22:
  movsbl 0x1(%r8),%eax
  add    $0x1,%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L22
  cmp    %r8,%rdi
  jae    L0
  mov    %r8,%rdi
  xor    %eax,%eax
  jmp    1050 <is_exponent@plt>
```

assistant: ```c
int is_power_float(s)
char *s;
{
  char *x;
  if (*s == '-')
    s++;
  for (x = s; isdigit(*s); s++)
    continue;
  return (s > x ? is_exponent(s) : 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_power_float>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0x2d,%al
  jne    L37
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L37:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L38
L33:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L38:
  mov    %rdi,%r8
L34:
  movsbl 0x1(%r8),%eax
  add    $0x1,%r8
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L34
  cmp    %r8,%rdi
  jae    L33
  mov    %r8,%rdi
  xor    %eax,%eax
  jmp    1050 <is_exponent@plt>
```

assistant: ```c
int is_power_float(s)
char *s;
{
  char *x;
  if (*s == '-')
    s++;
  for (x = s; isdigit(*s); s++)
    continue;
  return (s > x ? is_exponent(s) : 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printInputThenLoop1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <loopForever@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D9: 
a: %lu, b: %lu


assistant: ```c
void printInputThenLoop1(unsigned long a, unsigned long b) {
  printf("\na: %lu, b: %lu\n", a, b);
  loopForever(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printInputThenLoop1>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <loopForever@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: 
a: %lu, b: %lu


assistant: ```c
void printInputThenLoop1(unsigned long a, unsigned long b) {
  printf("\na: %lu, b: %lu\n", a, b);
  loopForever(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printInputThenLoop1>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <loopForever@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: 
a: %lu, b: %lu


assistant: ```c
void printInputThenLoop1(unsigned long a, unsigned long b) {
  printf("\na: %lu, b: %lu\n", a, b);
  loopForever(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printInputThenLoop1>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <loopForever@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: 
a: %lu, b: %lu


assistant: ```c
void printInputThenLoop1(unsigned long a, unsigned long b) {
  printf("\na: %lu, b: %lu\n", a, b);
  loopForever(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<eto_log_add_entry_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x14,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <eto_log_add_entry@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: %s %i

assistant: ```c
void eto_log_add_entry_i(const char *entry, int val) {
  unsigned int size = sizeof(char) * (unsigned int)strlen(entry) + 20;
  char *txt = (char *)malloc(size);
  sprintf(txt, "%s %i", entry, val);
  eto_log_add_entry(txt);
  free(txt);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eto_log_add_entry_i>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <strlen@plt>
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <eto_log_add_entry@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D0: %s %i

assistant: ```c
void eto_log_add_entry_i(const char *entry, int val) {
  unsigned int size = sizeof(char) * (unsigned int)strlen(entry) + 20;
  char *txt = (char *)malloc(size);
  sprintf(txt, "%s %i", entry, val);
  eto_log_add_entry(txt);
  free(txt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eto_log_add_entry_i>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <strlen@plt>
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  lea    D6(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <eto_log_add_entry@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: %s %i

assistant: ```c
void eto_log_add_entry_i(const char *entry, int val) {
  unsigned int size = sizeof(char) * (unsigned int)strlen(entry) + 20;
  char *txt = (char *)malloc(size);
  sprintf(txt, "%s %i", entry, val);
  eto_log_add_entry(txt);
  free(txt);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eto_log_add_entry_i>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <strlen@plt>
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  lea    D3(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <eto_log_add_entry@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <free@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: %s %i

assistant: ```c
void eto_log_add_entry_i(const char *entry, int val) {
  unsigned int size = sizeof(char) * (unsigned int)strlen(entry) + 20;
  char *txt = (char *)malloc(size);
  sprintf(txt, "%s %i", entry, val);
  eto_log_add_entry(txt);
  free(txt);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jg     L18
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L13
L18:
  mov    -0x10(%rbp),%eax
  mov    $0x42,%ecx
  mov    $0x43,%edx
  mov    $0x41,%esi
  mov    %eax,%edi
  call   <move_disk@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D38
type_infered: string
name: unpack_data
arguments: data_label: D37
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string
name: unpack_data
arguments: data_label: D29
type_infered: string

tool: D38: Enter the number of disks = 

tool: D37: %d

tool: D4: Invalid number of disks.

tool: D29: 
Total number of steps required to solve this problem are = %d


assistant: ```c
int main() {
  printf("Enter the number of disks = ");
  int disk;
  scanf("%d", &disk);
  if (disk < 1) {
    printf("Invalid number of disks.\n");
    return 1;
  }
  int count = move_disk(disk, 'A', 'C', 'B');
  printf("\nTotal number of steps required to solve this problem are = "
         "%d\n",
         count);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L23
  mov    $0x42,%ecx
  mov    $0x43,%edx
  mov    $0x41,%esi
  call   <move_disk@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L23:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L6
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D3
type_infered: string
name: disassemble_data
arguments: data_tag: D0
type_infered: string
name: disassemble_data
arguments: data_tag: D20
type_infered: string

tool: D18: Enter the number of disks = 

tool: D3: %d

tool: D0: 
Total number of steps required to solve this problem are = %d


tool: D20: Invalid number of disks.

assistant: ```c
int main() {
  printf("Enter the number of disks = ");
  int disk;
  scanf("%d", &disk);
  if (disk < 1) {
    printf("Invalid number of disks.\n");
    return 1;
  }
  int count = move_disk(disk, 'A', 'C', 'B');
  printf("\nTotal number of steps required to solve this problem are = "
         "%d\n",
         count);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L11
  mov    $0x42,%ecx
  mov    $0x43,%edx
  mov    $0x41,%esi
  call   <move_disk@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
L11:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L12
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D38
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D34
data_type: string

tool: D38: Enter the number of disks = 

tool: D0: %d

tool: D8: 
Total number of steps required to solve this problem are = %d


tool: D34: Invalid number of disks.

assistant: ```c
int main() {
  printf("Enter the number of disks = ");
  int disk;
  scanf("%d", &disk);
  if (disk < 1) {
    printf("Invalid number of disks.\n");
    return 1;
  }
  int count = move_disk(disk, 'A', 'C', 'B');
  printf("\nTotal number of steps required to solve this problem are = "
         "%d\n",
         count);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L27
  mov    $0x42,%ecx
  mov    $0x43,%edx
  mov    $0x41,%esi
  call   <move_disk@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  ret
L27:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L19
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string

tool: D0: Enter the number of disks = 

tool: D5: %d

tool: D27: 
Total number of steps required to solve this problem are = %d


tool: D19: Invalid number of disks.

assistant: ```c
int main() {
  printf("Enter the number of disks = ");
  int disk;
  scanf("%d", &disk);
  if (disk < 1) {
    printf("Invalid number of disks.\n");
    return 1;
  }
  int count = move_disk(disk, 'A', 'C', 'B');
  printf("\nTotal number of steps required to solve this problem are = "
         "%d\n",
         count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <suma@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <f1@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: Llamada a la funcion que suma dos numeros en el main: %d


assistant: ```c
int main() {
  int n = 0;
  printf("Llamada a la funcion que suma dos numeros en el main: %d\n", suma(n, n));
  f1();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <suma@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <f1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D0: Llamada a la funcion que suma dos numeros en el main: %d


assistant: ```c
int main() {
  int n = 0;
  printf("Llamada a la funcion que suma dos numeros en el main: %d\n", suma(n, n));
  f1();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <suma@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <f1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: Llamada a la funcion que suma dos numeros en el main: %d


assistant: ```c
int main() {
  int n = 0;
  printf("Llamada a la funcion que suma dos numeros en el main: %d\n", suma(n, n));
  f1();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <suma@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <f1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: Llamada a la funcion que suma dos numeros en el main: %d


assistant: ```c
int main() {
  int n = 0;
  printf("Llamada a la funcion que suma dos numeros en el main: %d\n", suma(n, n));
  f1();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mallocWrongArraySize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *mallocWrongArraySize() {
  static const double sTable[10];
  int *table = malloc(sizeof sTable);
  return table;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mallocWrongArraySize>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x50,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *mallocWrongArraySize() {
  static const double sTable[10];
  int *table = malloc(sizeof sTable);
  return table;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mallocWrongArraySize>:
  endbr64
  mov    $0x50,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
int *mallocWrongArraySize() {
  static const double sTable[10];
  int *table = malloc(sizeof sTable);
  return table;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strnstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L76
  mov    -0x18(%rbp),%rax
  jmp    L39
L4:
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L89
  jmp    L80
L100:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L83
  addq   $0x1,-0x8(%rbp)
L80:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L98
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x28(%rbp)
  ja     L100
  jmp    L98
L83:
  nop
L98:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L89
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L39
L89:
  addq   $0x1,-0x10(%rbp)
L76:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strnstr(const char *s1, const char *s2, size_t n) {
  size_t i;
  size_t j;
  i = 0;
  if (!s2[0])
    return ((char *)s1);
  while (s1[i]) {
    j = 0;
    if (s1[i] == s2[j]) {
      while (s2[j] && (i + j) < n) {
        if (s1[i + j] == s2[j])
          j++;
        else
          break;
      }
      if (!s2[j])
        return ((char *)&(s1[i]));
    }
    i++;
  }
  return (NULL);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strnstr>:
  endbr64
  movzbl (%rsi),%r10d
  mov    %rdi,%r11
  test   %r10b,%r10b
  je     L23
  movzbl (%rdi),%eax
  test   %al,%al
  je     L53
  mov    $0x0,%ecx
  jmp    L42
L84:
  test   %r8b,%r8b
  je     L23
L113:
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L73
L42:
  lea    (%rdi,%rcx,1),%r11
  cmp    %al,%r10b
  jne    L113
  cmp    %rcx,%rdx
  jbe    L113
  mov    %rcx,%rax
  mov    %r10d,%r8d
  mov    %rsi,%r9
  sub    %rcx,%r9
L68:
  cmp    %r8b,(%rdi,%rax,1)
  jne    L84
  movzbl 0x1(%r9,%rax,1),%r8d
  test   %r8b,%r8b
  je     L23
  add    $0x1,%rax
  cmp    %rdx,%rax
  jb     L68
  jmp    L113
L73:
  mov    $0x0,%r11d
L23:
  mov    %r11,%rax
  ret
L53:
  mov    $0x0,%r11d
  jmp    L23
```

assistant: ```c
char *ft_strnstr(const char *s1, const char *s2, size_t n) {
  size_t i;
  size_t j;
  i = 0;
  if (!s2[0])
    return ((char *)s1);
  while (s1[i]) {
    j = 0;
    if (s1[i] == s2[j]) {
      while (s2[j] && (i + j) < n) {
        if (s1[i + j] == s2[j])
          j++;
        else
          break;
      }
      if (!s2[j])
        return ((char *)&(s1[i]));
    }
    i++;
  }
  return (NULL);
}
```