ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_privilege>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L11
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <setgid@plt>
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <setgroups@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <setuid@plt>
  jmp    L26
L11:
  nop
L26:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
void set_privilege(char *path) {
  struct stat result;
  if (stat(path, &result) != 0) {
    return;
  }
  setgid(result.st_gid);
  setgroups(1, &(result.st_gid));
  setuid(result.st_uid);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<set_privilege>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L8
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  ret
L8:
  mov    0x4(%rsp),%edi
  call   <setgid@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edi
  call   <setgroups@plt>
  mov    (%rsp),%edi
  call   <setuid@plt>
  jmp    L1
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void set_privilege(char *path) {
  struct stat result;
  if (stat(path, &result) != 0) {
    return;
  }
  setgid(result.st_gid);
  setgroups(1, &(result.st_gid));
  setuid(result.st_uid);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_privilege>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L3
  mov    0x4(%rsp),%edi
  call   <setgid@plt>
  mov    $0x1,%edi
  lea    0x4(%rsp),%rsi
  call   <setgroups@plt>
  mov    (%rsp),%edi
  call   <setuid@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void set_privilege(char *path) {
  struct stat result;
  if (stat(path, &result) != 0) {
    return;
  }
  setgid(result.st_gid);
  setgroups(1, &(result.st_gid));
  setuid(result.st_uid);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_privilege>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L7
  mov    0x4(%rsp),%edi
  call   <setgid@plt>
  mov    $0x1,%edi
  lea    0x4(%rsp),%rsi
  call   <setgroups@plt>
  mov    (%rsp),%edi
  call   <setuid@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void set_privilege(char *path) {
  struct stat result;
  if (stat(path, &result) != 0) {
    return;
  }
  setgid(result.st_gid);
  setgroups(1, &(result.st_gid));
  setuid(result.st_uid);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<visiGeneBodyPart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %esi,-0x11c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x11c(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    %edx,%ecx
  lea    D5(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <sqlSafef@plt>
  lea    -0x110(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sqlQuickString@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: select bodyPart.name from image,specimen,bodyPart where image.id = %d and image.specimen = specimen.id and specimen.bodyPart = bodyPart.id

assistant: ```c
char *visiGeneBodyPart(struct sqlConnection *conn, int id) {
  char query[256];
  sqlSafef(query, sizeof(query),
           "select bodyPart.name from image,specimen,bodyPart "
           "where image.id = %d "
           "and image.specimen = specimen.id "
           "and specimen.bodyPart = bodyPart.id",
           id);
  return sqlQuickString(conn, query);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<visiGeneBodyPart>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D6(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <sqlSafef@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sqlQuickString@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: select bodyPart.name from image,specimen,bodyPart where image.id = %d and image.specimen = specimen.id and specimen.bodyPart = bodyPart.id

assistant: ```c
char *visiGeneBodyPart(struct sqlConnection *conn, int id) {
  char query[256];
  sqlSafef(query, sizeof(query),
           "select bodyPart.name from image,specimen,bodyPart "
           "where image.id = %d "
           "and image.specimen = specimen.id "
           "and specimen.bodyPart = bodyPart.id",
           id);
  return sqlQuickString(conn, query);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<visiGeneBodyPart>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  lea    D8(%rip),%rdx
  mov    $0x100,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sqlSafef@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sqlQuickString@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: select bodyPart.name from image,specimen,bodyPart where image.id = %d and image.specimen = specimen.id and specimen.bodyPart = bodyPart.id

assistant: ```c
char *visiGeneBodyPart(struct sqlConnection *conn, int id) {
  char query[256];
  sqlSafef(query, sizeof(query),
           "select bodyPart.name from image,specimen,bodyPart "
           "where image.id = %d "
           "and image.specimen = specimen.id "
           "and specimen.bodyPart = bodyPart.id",
           id);
  return sqlQuickString(conn, query);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<visiGeneBodyPart>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  lea    D2(%rip),%rdx
  mov    $0x100,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sqlSafef@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sqlQuickString@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: select bodyPart.name from image,specimen,bodyPart where image.id = %d and image.specimen = specimen.id and specimen.bodyPart = bodyPart.id

assistant: ```c
char *visiGeneBodyPart(struct sqlConnection *conn, int id) {
  char query[256];
  sqlSafef(query, sizeof(query),
           "select bodyPart.name from image,specimen,bodyPart "
           "where image.id = %d "
           "and image.specimen = specimen.id "
           "and specimen.bodyPart = bodyPart.id",
           id);
  return sqlQuickString(conn, query);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nextpath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rax,%rbx
  jmp    L36
L6:
  add    $0x1,%rbx
L36:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L31
  movzbl (%rbx),%eax
  cmp    $0x3a,%al
  jne    L6
L31:
  movzbl (%rbx),%eax
  cmp    $0x3a,%al
  jne    L59
  add    $0x1,%rbx
L59:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L12
  mov    %rbx,%rax
  jmp    L54
L12:
  mov    $0x0,%eax
L54:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *nextpath(path)
register char *path;
{
  register char *scanp = path;
  while (*scanp && *scanp != ':')
    scanp++;
  if (*scanp == ':')
    scanp++;
  return (*scanp ? scanp : 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nextpath>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L25
  cmp    $0x3a,%dl
  je     L25
L5:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L25
  cmp    $0x3a,%dl
  jne    L5
L25:
  cmp    $0x3a,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  cmpb   $0x0,(%rax)
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
```

assistant: ```c
char *nextpath(path)
register char *path;
{
  register char *scanp = path;
  while (*scanp && *scanp != ':')
    scanp++;
  if (*scanp == ':')
    scanp++;
  return (*scanp ? scanp : 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nextpath>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x3a,%dl
  je     L14
  test   %dl,%dl
  je     L14
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L14
  cmp    $0x3a,%dl
  jne    L18
L14:
  cmp    $0x3a,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  xor    %edx,%edx
  cmpb   $0x0,(%rax)
  cmove  %rdx,%rax
  ret
```

assistant: ```c
char *nextpath(path)
register char *path;
{
  register char *scanp = path;
  while (*scanp && *scanp != ':')
    scanp++;
  if (*scanp == ':')
    scanp++;
  return (*scanp ? scanp : 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<nextpath>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x3a,%dl
  je     L39
  test   %dl,%dl
  je     L8
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L8
  cmp    $0x3a,%dl
  jne    L2
L39:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
  nopl   (%rax)
L8:
  cmp    $0x3a,%dl
  je     L39
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
```

assistant: ```c
char *nextpath(path)
register char *path;
{
  register char *scanp = path;
  while (*scanp && *scanp != ':')
    scanp++;
  if (*scanp == ':')
    scanp++;
  return (*scanp ? scanp : 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mpqs_sqrt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %esi,%ebx
  test   $0x2,%sil
  jne    L49
  mov    %edx,%ebp
  mov    %esi,%r13d
  and    $0x4,%r13d
  jne    L83
  lea    -0x1(%rsi),%esi
  mov    %esi,%r12d
  and    $0x1,%r12d
  jne    L119
L91:
  add    $0x1,%r12d
  sar    %esi
  test   $0x1,%sil
  je     L91
L96:
  sar    %esi
  mov    %ebx,%edx
  mov    %r14d,%edi
  call   <mpqs_powmod@plt>
  mov    %eax,%ecx
  imul   %eax,%eax
  cltd
  idiv   %ebx
  mov    %edx,%eax
  imul   %r14d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r8d
  mov    %edx,%esi
  mov    %r14d,%eax
  imul   %ecx,%eax
  cltd
  idiv   %ebx
  mov    %edx,%edi
  cmp    $0x1,%r8d
  jne    L22
  jmp    L114
L49:
  lea    0x1(%rsi),%esi
  sar    $0x2,%esi
  mov    %ebx,%edx
  call   <mpqs_powmod@plt>
  mov    %eax,%edi
L114:
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L83:
  lea    0x3(%rsi),%esi
  sar    $0x3,%esi
  mov    %ebx,%edx
  call   <mpqs_powmod@plt>
  mov    %eax,%edi
  imul   %eax,%eax
  cltd
  idiv   %ebx
  cmp    %edx,%r14d
  je     L114
  mov    %ebp,%eax
  imul   %edi,%eax
  cltd
  idiv   %ebx
  mov    %edx,%edi
  jmp    L114
L119:
  mov    %r13d,%r12d
  jmp    L96
L90:
  mov    %r13d,%ecx
L12:
  lea    0x1(%rcx),%r8d
  cmp    %r12d,%r8d
  jge    L122
L46:
  mov    %ebp,%eax
  imul   %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%ebp
  add    $0x1,%r8d
  cmp    %r12d,%r8d
  jne    L46
L122:
  mov    %edi,%eax
  imul   %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%edi
  imul   %ebp,%ebp
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%ebp
  mov    %edx,%eax
  imul   %esi,%eax
  cltd
  idiv   %ebx
  mov    %edx,%esi
  cmp    $0x1,%edx
  je     L114
  mov    %ecx,%r12d
L22:
  test   %r12d,%r12d
  jle    L90
  mov    %esi,%eax
  mov    %r13d,%ecx
  cmp    $0x1,%esi
  je     L90
L162:
  imul   %eax,%eax
  cltd
  idiv   %ebx
  mov    %edx,%eax
  add    $0x1,%ecx
  cmp    %r12d,%ecx
  jge    L12
  cmp    $0x1,%edx
  jne    L162
  jmp    L12
```

assistant: ```c
ushort mpqs_sqrt(ushort a, ushort p, ushort help) {
  ushort e, u, i, l;
  ulong b, g, r, k;
  if (p & 2)
    return mpqs_powmod(a, (p + 1) >> 2, p);
  if (p & 4) {
    b = mpqs_powmod(a, (p + 3) >> 3, p);
    g = b * b;
    g %= (ulong)p;
    if (g == a)
      return b;
    b *= (ulong)help;
    b %= (ulong)p;
    return b;
  }
  e = 0;
  u = p - 1;
  while (!(u & 1)) {
    e++;
    u >>= 1;
  }
  g = help;
  r = mpqs_powmod(a, u >> 1, p);
  k = r * r;
  k %= (ulong)p;
  k *= a;
  k %= (ulong)p;
  r *= a;
  r %= (ulong)p;
  while (k != 1) {
    b = k;
    for (i = 0; i < e && b != 1; i++) {
      b *= b;
      b %= (ulong)p;
    }
    for (l = i + 1; l < e; l++) {
      g *= g;
      g %= (ulong)p;
    }
    r *= g;
    r %= (ulong)p;
    g *= g;
    g %= (ulong)p;
    k *= g;
    k %= (ulong)p;
    e = i;
  }
  return (ushort)r;
}
```
user: What is the c source code of the assembly code below:

```asm
<mpqs_sqrt>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  and    $0x2,%esi
  jne    L84
  mov    %edx,%ebx
  test   $0x4,%r12b
  jne    L8
  lea    -0x1(%r12),%esi
  mov    %esi,%ebp
  and    $0x1,%ebp
  jne    L107
  nopl   0x0(%rax)
L92:
  sar    %esi
  add    $0x1,%ebp
  test   $0x1,%sil
  je     L92
L121:
  mov    %r12d,%edx
  mov    %r13d,%edi
  sar    %esi
  call   <mpqs_powmod@plt>
  mov    %eax,%ecx
  imul   %eax,%eax
  cltd
  idiv   %r12d
  mov    %edx,%eax
  imul   %r13d,%eax
  cltd
  idiv   %r12d
  mov    %r13d,%eax
  imul   %ecx,%eax
  mov    %edx,%edi
  cltd
  idiv   %r12d
  mov    %edx,%r8d
  cmp    $0x1,%edi
  je     L45
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %edi,%edx
  xor    %esi,%esi
  test   %ebp,%ebp
  jle    L114
L3:
  imul   %edx,%edx
  mov    %esi,%ecx
  add    $0x1,%esi
  mov    %edx,%eax
  cltd
  idiv   %r12d
  cmp    %ebp,%esi
  jge    L113
  cmp    $0x1,%edx
  jne    L3
L113:
  add    $0x2,%ecx
L103:
  cmp    %ecx,%ebp
  jle    L123
  xchg   %ax,%ax
L0:
  mov    %ebx,%eax
  add    $0x1,%ecx
  imul   %ebx,%eax
  cltd
  idiv   %r12d
  mov    %edx,%ebx
  cmp    %ebp,%ecx
  jne    L0
L123:
  mov    %r8d,%eax
  imul   %ebx,%eax
  cltd
  idiv   %r12d
  mov    %ebx,%eax
  imul   %ebx,%eax
  mov    %edx,%r8d
  cltd
  idiv   %r12d
  mov    %edi,%eax
  imul   %edx,%eax
  mov    %edx,%ebx
  cltd
  idiv   %r12d
  mov    %edx,%edi
  cmp    $0x1,%edx
  je     L45
  mov    %esi,%ebp
  jne    L25
L114:
  xor    %esi,%esi
  mov    $0x1,%ecx
  jmp    L103
L8:
  lea    0x3(%r12),%esi
  mov    %r12d,%edx
  sar    $0x3,%esi
  call   <mpqs_powmod@plt>
  mov    %eax,%r8d
  imul   %eax,%eax
  cltd
  idiv   %r12d
  cmp    %edx,%r13d
  je     L45
  mov    %ebx,%eax
  imul   %r8d,%eax
  cltd
  idiv   %r12d
  mov    %edx,%r8d
L45:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L84:
  add    $0x8,%rsp
  lea    0x1(%r12),%esi
  mov    %r12d,%edx
  pop    %rbx
  sar    $0x2,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <mpqs_powmod@plt>
L107:
  xor    %ebp,%ebp
  jmp    L121
```

assistant: ```c
ushort mpqs_sqrt(ushort a, ushort p, ushort help) {
  ushort e, u, i, l;
  ulong b, g, r, k;
  if (p & 2)
    return mpqs_powmod(a, (p + 1) >> 2, p);
  if (p & 4) {
    b = mpqs_powmod(a, (p + 3) >> 3, p);
    g = b * b;
    g %= (ulong)p;
    if (g == a)
      return b;
    b *= (ulong)help;
    b %= (ulong)p;
    return b;
  }
  e = 0;
  u = p - 1;
  while (!(u & 1)) {
    e++;
    u >>= 1;
  }
  g = help;
  r = mpqs_powmod(a, u >> 1, p);
  k = r * r;
  k %= (ulong)p;
  k *= a;
  k %= (ulong)p;
  r *= a;
  r %= (ulong)p;
  while (k != 1) {
    b = k;
    for (i = 0; i < e && b != 1; i++) {
      b *= b;
      b %= (ulong)p;
    }
    for (l = i + 1; l < e; l++) {
      g *= g;
      g %= (ulong)p;
    }
    r *= g;
    r %= (ulong)p;
    g *= g;
    g %= (ulong)p;
    k *= g;
    k %= (ulong)p;
    e = i;
  }
  return (ushort)r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mpqs_sqrt>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  and    $0x2,%esi
  jne    L49
  mov    %edx,%ebx
  test   $0x4,%r12b
  jne    L33
  lea    -0x1(%r12),%esi
  mov    %esi,%ebp
  and    $0x1,%ebp
  jne    L147
  nopl   0x0(%rax)
L134:
  sar    %esi
  add    $0x1,%ebp
  test   $0x1,%sil
  je     L134
L19:
  mov    %r12d,%edx
  mov    %r13d,%edi
  sar    %esi
  call   <mpqs_powmod@plt>
  mov    %eax,%ecx
  imul   %eax,%eax
  cltd
  idiv   %r12d
  mov    %edx,%eax
  imul   %r13d,%eax
  cltd
  idiv   %r12d
  mov    %r13d,%eax
  imul   %ecx,%eax
  mov    %edx,%edi
  cltd
  idiv   %r12d
  mov    %edx,%r8d
  cmp    $0x1,%edi
  je     L136
  nopl   0x0(%rax,%rax,1)
L130:
  mov    %edi,%edx
  xor    %esi,%esi
  test   %ebp,%ebp
  jle    L129
L45:
  imul   %edx,%edx
  mov    %esi,%ecx
  add    $0x1,%esi
  mov    %edx,%eax
  cltd
  idiv   %r12d
  cmp    %ebp,%esi
  jge    L94
  cmp    $0x1,%edx
  jne    L45
L94:
  add    $0x2,%ecx
L143:
  cmp    %ecx,%ebp
  jle    L107
  xchg   %ax,%ax
L42:
  mov    %ebx,%eax
  add    $0x1,%ecx
  imul   %ebx,%eax
  cltd
  idiv   %r12d
  mov    %edx,%ebx
  cmp    %ebp,%ecx
  jne    L42
L107:
  mov    %r8d,%eax
  imul   %ebx,%eax
  cltd
  idiv   %r12d
  mov    %ebx,%eax
  imul   %ebx,%eax
  mov    %edx,%r8d
  cltd
  idiv   %r12d
  mov    %edi,%eax
  imul   %edx,%eax
  mov    %edx,%ebx
  cltd
  idiv   %r12d
  mov    %edx,%edi
  cmp    $0x1,%edx
  je     L136
  mov    %esi,%ebp
  jne    L130
L129:
  xor    %esi,%esi
  mov    $0x1,%ecx
  jmp    L143
L33:
  lea    0x3(%r12),%esi
  mov    %r12d,%edx
  sar    $0x3,%esi
  call   <mpqs_powmod@plt>
  mov    %eax,%r8d
  imul   %eax,%eax
  cltd
  idiv   %r12d
  cmp    %edx,%r13d
  je     L136
  mov    %ebx,%eax
  imul   %r8d,%eax
  cltd
  idiv   %r12d
  mov    %edx,%r8d
L136:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  add    $0x8,%rsp
  lea    0x1(%r12),%esi
  mov    %r12d,%edx
  pop    %rbx
  sar    $0x2,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <mpqs_powmod@plt>
L147:
  xor    %ebp,%ebp
  jmp    L19
```

assistant: ```c
ushort mpqs_sqrt(ushort a, ushort p, ushort help) {
  ushort e, u, i, l;
  ulong b, g, r, k;
  if (p & 2)
    return mpqs_powmod(a, (p + 1) >> 2, p);
  if (p & 4) {
    b = mpqs_powmod(a, (p + 3) >> 3, p);
    g = b * b;
    g %= (ulong)p;
    if (g == a)
      return b;
    b *= (ulong)help;
    b %= (ulong)p;
    return b;
  }
  e = 0;
  u = p - 1;
  while (!(u & 1)) {
    e++;
    u >>= 1;
  }
  g = help;
  r = mpqs_powmod(a, u >> 1, p);
  k = r * r;
  k %= (ulong)p;
  k *= a;
  k %= (ulong)p;
  r *= a;
  r %= (ulong)p;
  while (k != 1) {
    b = k;
    for (i = 0; i < e && b != 1; i++) {
      b *= b;
      b %= (ulong)p;
    }
    for (l = i + 1; l < e; l++) {
      g *= g;
      g %= (ulong)p;
    }
    r *= g;
    r %= (ulong)p;
    g *= g;
    g %= (ulong)p;
    k *= g;
    k %= (ulong)p;
    e = i;
  }
  return (ushort)r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_top_paren>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L12
  mov    $0x20,%eax
  jmp    L11
L12:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  mov    D20(%rip),%rdx
  cltq
  movzbl (%rdx,%rax,1),%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
char get_top_paren() {
  extern int paren_stack_top;
  extern char paren_stack[];
  if (paren_stack_top == 0) {
    return ' ';
  } else {
    return paren_stack[paren_stack_top - 1];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_top_paren>:
  endbr64
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    $0x20,%edx
  test   %eax,%eax
  je     L0
  sub    $0x1,%eax
  cltq
  mov    D7(%rip),%rdx
  movzbl (%rdx,%rax,1),%edx
L0:
  mov    %edx,%eax
  ret
```

assistant: ```c
char get_top_paren() {
  extern int paren_stack_top;
  extern char paren_stack[];
  if (paren_stack_top == 0) {
    return ' ';
  } else {
    return paren_stack[paren_stack_top - 1];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_top_paren>:
  endbr64
  mov    D18(%rip),%rax
  mov    $0x20,%r8d
  mov    (%rax),%eax
  test   %eax,%eax
  je     L1
  mov    D2(%rip),%rdx
  sub    $0x1,%eax
  cltq
  movzbl (%rdx,%rax,1),%r8d
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
char get_top_paren() {
  extern int paren_stack_top;
  extern char paren_stack[];
  if (paren_stack_top == 0) {
    return ' ';
  } else {
    return paren_stack[paren_stack_top - 1];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_top_paren>:
  endbr64
  mov    D1(%rip),%rax
  mov    $0x20,%r8d
  mov    (%rax),%eax
  test   %eax,%eax
  je     L7
  mov    D19(%rip),%rdx
  sub    $0x1,%eax
  cltq
  movzbl (%rdx,%rax,1),%r8d
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
char get_top_paren() {
  extern int paren_stack_top;
  extern char paren_stack[];
  if (paren_stack_top == 0) {
    return ' ';
  } else {
    return paren_stack[paren_stack_top - 1];
  }
}
```