ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<EaseCircInOut>:
  endbr64
  sub    $0x18,%rsp
  movss  D20(%rip),%xmm5
  movss  D59(%rip),%xmm4
  mulss  %xmm5,%xmm3
  divss  %xmm3,%xmm0
  comiss %xmm0,%xmm4
  ja     L47
  subss  D18(%rip),%xmm0
  mulss  %xmm5,%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm0,%xmm0
  subss  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  ucomiss %xmm3,%xmm0
  ja     L28
  sqrtss %xmm3,%xmm3
L38:
  addss  %xmm4,%xmm3
  add    $0x18,%rsp
  mulss  %xmm2,%xmm3
  movaps %xmm3,%xmm0
  addss  %xmm1,%xmm0
  ret
  nopl   (%rax)
L47:
  mulss  %xmm0,%xmm0
  movaps %xmm4,%xmm3
  xorps  D41(%rip),%xmm2
  mulss  %xmm5,%xmm2
  subss  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  ucomiss %xmm3,%xmm0
  ja     L9
  sqrtss %xmm3,%xmm3
L33:
  subss  %xmm4,%xmm3
  add    $0x18,%rsp
  mulss  %xmm2,%xmm3
  addss  %xmm1,%xmm3
  movaps %xmm3,%xmm0
  ret
L28:
  movaps %xmm3,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <sqrtf@plt>
  movss  D59(%rip),%xmm4
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  movaps %xmm0,%xmm3
  jmp    L38
L9:
  movaps %xmm3,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <sqrtf@plt>
  movss  D59(%rip),%xmm4
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  movaps %xmm0,%xmm3
  jmp    L33
```

tool_calls: name: unpack_data
arguments: label: D20
data_type: byte[4]
name: unpack_data
arguments: label: D59
data_type: byte[4]
name: unpack_data
arguments: label: D18
data_type: byte[4]
name: unpack_data
arguments: label: D41
data_type: byte[16]

tool: {"D20": [0x00,0x00,0x00,0x3f]}

tool: {"D59": [0x00,0x00,0x80,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x40]}

tool: {"D41": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float EaseCircInOut(float t, float b, float c, float d) {
  if ((t /= d / 2.0f) < 1.0f)
    return (-c / 2.0f * (sqrtf(1.0f - t * t) - 1.0f) + b);
  t -= 2.0f;
  return (c / 2.0f * (sqrtf(1.0f - t * t) + 1.0f) + b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EaseCircInOut>:
  endbr64
  sub    $0x18,%rsp
  movss  D33(%rip),%xmm5
  movss  D20(%rip),%xmm4
  mulss  %xmm5,%xmm3
  divss  %xmm3,%xmm0
  comiss %xmm0,%xmm4
  ja     L22
  subss  D2(%rip),%xmm0
  mulss  %xmm5,%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm0,%xmm0
  subss  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  ucomiss %xmm3,%xmm0
  ja     L36
  sqrtss %xmm3,%xmm3
L27:
  addss  %xmm4,%xmm3
  add    $0x18,%rsp
  mulss  %xmm2,%xmm3
  movaps %xmm3,%xmm0
  addss  %xmm1,%xmm0
  ret
  nopl   (%rax)
L22:
  mulss  %xmm0,%xmm0
  movaps %xmm4,%xmm3
  xorps  D38(%rip),%xmm2
  mulss  %xmm5,%xmm2
  subss  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  ucomiss %xmm3,%xmm0
  ja     L25
  sqrtss %xmm3,%xmm3
L32:
  subss  %xmm4,%xmm3
  add    $0x18,%rsp
  mulss  %xmm2,%xmm3
  addss  %xmm1,%xmm3
  movaps %xmm3,%xmm0
  ret
L36:
  movaps %xmm3,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <sqrtf@plt>
  movss  D20(%rip),%xmm4
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  movaps %xmm0,%xmm3
  jmp    L27
L25:
  movaps %xmm3,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <sqrtf@plt>
  movss  D20(%rip),%xmm4
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  movaps %xmm0,%xmm3
  jmp    L32
```

tool_calls: name: unpack_data
arguments: label: D33
type_guessed: byte[4]
name: unpack_data
arguments: label: D20
type_guessed: byte[4]
name: unpack_data
arguments: label: D2
type_guessed: byte[4]
name: unpack_data
arguments: label: D38
type_guessed: byte[16]

tool: {"D33": [0x00,0x00,0x00,0x3f]}

tool: {"D20": [0x00,0x00,0x80,0x3f]}

tool: {"D2": [0x00,0x00,0x00,0x40]}

tool: {"D38": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float EaseCircInOut(float t, float b, float c, float d) {
  if ((t /= d / 2.0f) < 1.0f)
    return (-c / 2.0f * (sqrtf(1.0f - t * t) - 1.0f) + b);
  t -= 2.0f;
  return (c / 2.0f * (sqrtf(1.0f - t * t) + 1.0f) + b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jg     L11
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(char b[]) {
  int i, sum;
  i = 0;
  sum = 0;
  while (b[i] > 0) {
    sum = sum + b[i];
    i = i + 1;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sum>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jle    L27
  add    $0x1,%rdi
  mov    $0x0,%edx
L23:
  movsbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jg     L23
L18:
  mov    %edx,%eax
  ret
L27:
  mov    $0x0,%edx
  jmp    L18
```

assistant: ```c
int sum(char b[]) {
  int i, sum;
  i = 0;
  sum = 0;
  while (b[i] > 0) {
    sum = sum + b[i];
    i = i + 1;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sum>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  jle    L12
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jg     L8
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum(char b[]) {
  int i, sum;
  i = 0;
  sum = 0;
  while (b[i] > 0) {
    sum = sum + b[i];
    i = i + 1;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  jle    L16
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jg     L7
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum(char b[]) {
  int i, sum;
  i = 0;
  sum = 0;
  while (b[i] > 0) {
    sum = sum + b[i];
    i = i + 1;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<evbuffer_add_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L12
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L12:
  movl   $0xffffffff,-0xc0(%rbp)
  mov    -0xd0(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x1000,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  lea    D15(%rip),%rax
  mov    %rax,-0xb8(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc0(%rbp)
  mov    -0xc0(%rbp),%edx
  mov    -0xb8(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  movl   $0xffffffff,-0xc0(%rbp)
L8:
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc0(%rbp),%eax
  leave
  ret
```

assistant: ```c
int evbuffer_add_printf(struct evbuffer *buf, char *fmt, ...) {
  int res = -1;
  char *msg;
  static char buffer[4096];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buffer, sizeof(buffer), fmt, ap);
  msg = buffer;
  res = strlen(msg);
  if (evbuffer_add(buf, msg, res) == -1)
    res = -1;
  va_end(ap);
  return (res);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<evbuffer_add_printf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x1000,%esi
  lea    D5(%rip),%r13
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <evbuffer_add@plt>
  cmp    $0xffffffff,%eax
  cmove  %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int evbuffer_add_printf(struct evbuffer *buf, char *fmt, ...) {
  int res = -1;
  char *msg;
  static char buffer[4096];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buffer, sizeof(buffer), fmt, ap);
  msg = buffer;
  res = strlen(msg);
  if (evbuffer_add(buf, msg, res) == -1)
    res = -1;
  va_end(ap);
  return (res);
}
```
user: What is the c source code of the assembly code below:

```asm
<evbuffer_add_printf>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x1000,%esi
  mov    %r14,%rdi
  call   <vsnprintf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %eax,%edx
  mov    %eax,%r12d
  call   <evbuffer_add@plt>
  mov    %ebp,%edi
  cmp    $0xffffffff,%eax
  mov    $0xffffffff,%eax
  cmove  %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int evbuffer_add_printf(struct evbuffer *buf, char *fmt, ...) {
  int res = -1;
  char *msg;
  static char buffer[4096];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buffer, sizeof(buffer), fmt, ap);
  msg = buffer;
  res = strlen(msg);
  if (evbuffer_add(buf, msg, res) == -1)
    res = -1;
  va_end(ap);
  return (res);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<evbuffer_add_printf>:
  endbr64
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x1000,%esi
  mov    %r14,%rdi
  call   <vsnprintf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %eax,%edx
  mov    %eax,%r12d
  call   <evbuffer_add@plt>
  mov    %ebp,%edi
  cmp    $0xffffffff,%eax
  mov    $0xffffffff,%eax
  cmove  %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int evbuffer_add_printf(struct evbuffer *buf, char *fmt, ...) {
  int res = -1;
  char *msg;
  static char buffer[4096];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buffer, sizeof(buffer), fmt, ap);
  msg = buffer;
  res = strlen(msg);
  if (evbuffer_add(buf, msg, res) == -1)
    res = -1;
  va_end(ap);
  return (res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D39(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D32(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L15
L18:
  movsd  D45(%rip),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D32(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L15:
  movsd  D54(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  ja     L18
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movq   D30(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D39
type_guessed: byte[8]
name: read_data
arguments: label: D32
type_guessed: f32[2]
name: read_data
arguments: label: D45
type_guessed: f32[2]
name: read_data
arguments: label: D54
type_guessed: f32[2]
name: read_data
arguments: label: D30
type_guessed: qword

tool: {"D39": [0x00,0x00,0x00,0x40,0x32,0x52,0x78,0x41]}

tool: {"D32": [0.0,1.875]}

tool: {"D45": [0.0,2.0]}

tool: {"D54": [0.0,3.39453125]}

tool: D30: 9223372036854775807

assistant: ```c
double solution() {
  double x;
  double sum_of_naturals_squared = 0;
  double square_of_the_sum;
  square_of_the_sum = pow((double)(100 * (100 + 1)) / 2, (double)2);
  for (x = 1; x < 101; x++) {
    sum_of_naturals_squared += pow(x, (double)2);
  }
  return fabs(sum_of_naturals_squared - square_of_the_sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solution>:
  endbr64
  mov    $0x64,%eax
  pxor   %xmm0,%xmm0
  movsd  D13(%rip),%xmm1
  movapd %xmm1,%xmm3
L9:
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm1
  sub    $0x1,%eax
  jne    L9
  subsd  D21(%rip),%xmm0
  andpd  D23(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
data_type: f32[2]
name: disassemble_data
arguments: label: D21
data_type: byte[8]
name: disassemble_data
arguments: label: D23
data_type: qword[2]

tool: {"D13": [0.0,1.875]}

tool: {"D21": [0x00,0x00,0x00,0x40,0x32,0x52,0x78,0x41]}

tool: {"D23": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double solution() {
  double x;
  double sum_of_naturals_squared = 0;
  double square_of_the_sum;
  square_of_the_sum = pow((double)(100 * (100 + 1)) / 2, (double)2);
  for (x = 1; x < 101; x++) {
    sum_of_naturals_squared += pow(x, (double)2);
  }
  return fabs(sum_of_naturals_squared - square_of_the_sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solution>:
  endbr64
  movsd  D6(%rip),%xmm3
  mov    $0x64,%eax
  pxor   %xmm0,%xmm0
  movapd %xmm3,%xmm1
  nopl   0x0(%rax)
L9:
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm0
  sub    $0x1,%eax
  jne    L9
  subsd  D17(%rip),%xmm0
  andpd  D7(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: f32[2]
name: unpack_data
arguments: tag: D17
type_guessed: byte[8]
name: unpack_data
arguments: tag: D7
type_guessed: qword[2]

tool: {"D6": [0.0,1.875]}

tool: {"D17": [0x00,0x00,0x00,0x40,0x32,0x52,0x78,0x41]}

tool: {"D7": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double solution() {
  double x;
  double sum_of_naturals_squared = 0;
  double square_of_the_sum;
  square_of_the_sum = pow((double)(100 * (100 + 1)) / 2, (double)2);
  for (x = 1; x < 101; x++) {
    sum_of_naturals_squared += pow(x, (double)2);
  }
  return fabs(sum_of_naturals_squared - square_of_the_sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<solution>:
  endbr64
  movsd  D25(%rip),%xmm3
  mov    $0x64,%eax
  pxor   %xmm0,%xmm0
  movapd %xmm3,%xmm1
  nopl   0x0(%rax)
L4:
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm0
  sub    $0x1,%eax
  jne    L4
  subsd  D6(%rip),%xmm0
  andpd  D19(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D25
data_type: f32[2]
name: read_data
arguments: label: D6
data_type: byte[8]
name: read_data
arguments: label: D19
data_type: qword[2]

tool: {"D25": [0.0,1.875]}

tool: {"D6": [0x00,0x00,0x00,0x40,0x32,0x52,0x78,0x41]}

tool: {"D19": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double solution() {
  double x;
  double sum_of_naturals_squared = 0;
  double square_of_the_sum;
  square_of_the_sum = pow((double)(100 * (100 + 1)) / 2, (double)2);
  for (x = 1; x < 101; x++) {
    sum_of_naturals_squared += pow(x, (double)2);
  }
  return fabs(sum_of_naturals_squared - square_of_the_sum);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<max_dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L16
L6:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dmax@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jle    L6
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: byte[8]

tool: {"D1": [0x00,0xc8,0x4e,0x67,0x6d,0xc1,0xab,0xc3]}

assistant: ```c
double max_dvector(double *d, long n) {
  double maxdv = -1.0e+18;
  long i;
  for (i = 1; i <= n; i++)
    maxdv = dmax(maxdv, d[i]);
  return maxdv;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max_dvector>:
  endbr64
  test   %rsi,%rsi
  jle    L15
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x1,%ebx
  movsd  D13(%rip),%xmm0
L18:
  movsd  (%r12,%rbx,8),%xmm1
  call   <dmax@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jge    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  movsd  D13(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: byte[8]

tool: {"D13": [0x00,0xc8,0x4e,0x67,0x6d,0xc1,0xab,0xc3]}

assistant: ```c
double max_dvector(double *d, long n) {
  double maxdv = -1.0e+18;
  long i;
  for (i = 1; i <= n; i++)
    maxdv = dmax(maxdv, d[i]);
  return maxdv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<max_dvector>:
  endbr64
  test   %rsi,%rsi
  jle    L8
  movsd  D14(%rip),%xmm0
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x1,%ebx
L4:
  movsd  (%r12,%rbx,8),%xmm1
  add    $0x1,%rbx
  call   <dmax@plt>
  cmp    %rbx,%rbp
  jge    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  movsd  D14(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
type_infered: byte[8]

tool: {"D14": [0x00,0xc8,0x4e,0x67,0x6d,0xc1,0xab,0xc3]}

assistant: ```c
double max_dvector(double *d, long n) {
  double maxdv = -1.0e+18;
  long i;
  for (i = 1; i <= n; i++)
    maxdv = dmax(maxdv, d[i]);
  return maxdv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<max_dvector>:
  endbr64
  test   %rsi,%rsi
  jle    L6
  movsd  D1(%rip),%xmm0
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x1,%ebx
L9:
  movsd  (%r12,%rbx,8),%xmm1
  add    $0x1,%rbx
  call   <dmax@plt>
  cmp    %rbx,%rbp
  jge    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  movsd  D1(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0xc8,0x4e,0x67,0x6d,0xc1,0xab,0xc3]}

assistant: ```c
double max_dvector(double *d, long n) {
  double maxdv = -1.0e+18;
  long i;
  for (i = 1; i <= n; i++)
    maxdv = dmax(maxdv, d[i]);
  return maxdv;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ss2ltt_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_s2_f2cstr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ss2ltt@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int ss2ltt_(char *cmd, float *aspect, long int textlen) {
  char *ttex = _s2_f2cstr(cmd, textlen);
  unsigned int result = ss2ltt(ttex, aspect);
  free(ttex);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ss2ltt_>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  call   <_s2_f2cstr@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ss2ltt@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ss2ltt_(char *cmd, float *aspect, long int textlen) {
  char *ttex = _s2_f2cstr(cmd, textlen);
  unsigned int result = ss2ltt(ttex, aspect);
  free(ttex);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ss2ltt_>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <_s2_f2cstr@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <ss2ltt@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int ss2ltt_(char *cmd, float *aspect, long int textlen) {
  char *ttex = _s2_f2cstr(cmd, textlen);
  unsigned int result = ss2ltt(ttex, aspect);
  free(ttex);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ss2ltt_>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <_s2_f2cstr@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <ss2ltt@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int ss2ltt_(char *cmd, float *aspect, long int textlen) {
  char *ttex = _s2_f2cstr(cmd, textlen);
  unsigned int result = ss2ltt(ttex, aspect);
  free(ttex);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<cal_cksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movw   $0x0,-0x16(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movw   $0x0,-0x18(%rbp)
  jmp    L19
L31:
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzwl (%rax),%eax
  add    %ax,-0x16(%rbp)
  subl   $0x2,-0x14(%rbp)
L19:
  cmpl   $0x1,-0x14(%rbp)
  jg     L31
  cmpl   $0x1,-0x14(%rbp)
  jne    L23
  lea    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzwl -0x18(%rbp),%eax
  add    %ax,-0x16(%rbp)
L23:
  movzwl -0x16(%rbp),%eax
  sar    $0x10,%eax
  add    %ax,-0x16(%rbp)
  movzwl -0x16(%rbp),%eax
  sar    $0x10,%eax
  add    %ax,-0x16(%rbp)
  movzwl -0x16(%rbp),%eax
  not    %eax
  mov    %ax,-0x18(%rbp)
  movzwl -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
unsigned short cal_cksum(unsigned short *addr, int len) {
  int nleft = len;
  uint32_t sum = 0;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```