ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<problem1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0xc,-0x30(%rbp)
  movl   $0xf,-0x2c(%rbp)
  movl   $0x16,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0x7,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x12,-0x18(%rbp)
  movl   $0x17,-0x14(%rbp)
  movl   $0x1b,-0x10(%rbp)
  movl   $0x9,-0x3c(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L41
L13:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x40(%rbp)
L41:
  mov    -0x40(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x3c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <findNextGreater@plt>
  mov    %rax,-0x38(%rbp)
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L39
L19:
  mov    -0x40(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x40(%rbp)
L39:
  mov    -0x40(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L19
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type_infered: string
name: parse_data
arguments: tag: D28
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D52
type_infered: string
name: parse_data
arguments: tag: D12
type_infered: string

tool: D16: ###### Problem 1 ######


tool: D28: Input:	

tool: D1: %i	

tool: D52: Output:	

tool: D12: 


assistant: ```c
void problem1() {
  printf("###### Problem 1 ######\n\n");
  int findNextGreaterInput[] = {12, 15, 22, 9, 7, 2, 18, 23, 27};
  int findNextGreaterLength = 9;
  int i;
  printf("Input:\t");
  for (i = 0; i < findNextGreaterLength; i++) {
    printf("%i\t", findNextGreaterInput[i]);
  }
  printf("\n");
  int *findNextGreaterOutput = findNextGreater(findNextGreaterInput, findNextGreaterLength);
  printf("Output:\t");
  for (i = 0; i < findNextGreaterLength; i++) {
    printf("%i\t", findNextGreaterOutput[i]);
  }
  free(findNextGreaterOutput);
  printf("\n\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<problem1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  movl   $0xc,(%rsp)
  movl   $0xf,0x4(%rsp)
  movl   $0x16,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x7,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x12,0x18(%rsp)
  movl   $0x17,0x1c(%rsp)
  movl   $0x1b,0x20(%rsp)
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x24(%rsp),%r12
  lea    D44(%rip),%rbp
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  mov    $0x9,%esi
  call   <findNextGreater@plt>
  mov    %rax,%r13
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rbx
  lea    0x24(%r13),%r12
  lea    D44(%rip),%rbp
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L7
  mov    %r13,%rdi
  call   <free@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string
name: disassemble_data
arguments: data_tag: D37
type_guessed: string
name: disassemble_data
arguments: data_tag: D44
type_guessed: string
name: disassemble_data
arguments: data_tag: D34
type_guessed: string
name: disassemble_data
arguments: data_tag: D58
type_guessed: string

tool: D5: ###### Problem 1 ######


tool: D37: Input:	

tool: D44: %i	

tool: D34: Output:	

tool: D58: 


assistant: ```c
void problem1() {
  printf("###### Problem 1 ######\n\n");
  int findNextGreaterInput[] = {12, 15, 22, 9, 7, 2, 18, 23, 27};
  int findNextGreaterLength = 9;
  int i;
  printf("Input:\t");
  for (i = 0; i < findNextGreaterLength; i++) {
    printf("%i\t", findNextGreaterInput[i]);
  }
  printf("\n");
  int *findNextGreaterOutput = findNextGreater(findNextGreaterInput, findNextGreaterLength);
  printf("Output:\t");
  for (i = 0; i < findNextGreaterLength; i++) {
    printf("%i\t", findNextGreaterOutput[i]);
  }
  free(findNextGreaterOutput);
  printf("\n\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<problem1>:
  endbr64
  push   %r13
  lea    D25(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D35(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x24(%rsp),%r12
  call   <puts@plt>
  lea    D8(%rip),%rdi
  mov    %r13,%rbx
  movabs $0xf0000000c,%rax
  mov    %rax,(%rsp)
  movabs $0x900000016,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x200000007,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x1700000012,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1b,0x20(%rsp)
  call   <printf@plt>
  nopl   (%rax)
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  mov    $0x9,%esi
  call   <findNextGreater@plt>
  lea    D38(%rip),%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rbx
  lea    0x24(%r13),%r12
  nopl   0x0(%rax)
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L11
  mov    %r13,%rdi
  call   <free@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D25
data_type: string
name: disassemble_data
arguments: data_label: D35
data_type: string
name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D38
data_type: string
name: disassemble_data
arguments: data_label: D10
data_type: string

tool: D25: ###### Problem 1 ######


tool: D35: %i	

tool: D8: Input:	

tool: D38: Output:	

tool: D10: 


assistant: ```c
void problem1() {
  printf("###### Problem 1 ######\n\n");
  int findNextGreaterInput[] = {12, 15, 22, 9, 7, 2, 18, 23, 27};
  int findNextGreaterLength = 9;
  int i;
  printf("Input:\t");
  for (i = 0; i < findNextGreaterLength; i++) {
    printf("%i\t", findNextGreaterInput[i]);
  }
  printf("\n");
  int *findNextGreaterOutput = findNextGreater(findNextGreaterInput, findNextGreaterLength);
  printf("Output:\t");
  for (i = 0; i < findNextGreaterLength; i++) {
    printf("%i\t", findNextGreaterOutput[i]);
  }
  free(findNextGreaterOutput);
  printf("\n\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<problem1>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D34(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x24(%rsp),%r12
  call   <puts@plt>
  movdqa D32(%rip),%xmm0
  xor    %eax,%eax
  mov    %r13,%rbx
  lea    D44(%rip),%rdi
  movl   $0x1b,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D42(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L20:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  mov    $0x9,%esi
  call   <findNextGreater@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rbx
  lea    0x24(%r13),%r12
  nopl   0x0(%rax)
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    %r13,%rdi
  call   <free@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D34
type: string
name: unpack_data
arguments: label: D32
type: byte[16]
name: unpack_data
arguments: label: D44
type: string
name: unpack_data
arguments: label: D42
type: byte[16]
name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D33
type: string

tool: D22: ###### Problem 1 ######


tool: D34: %i	

tool: {"D32": [0x0c,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x16,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: D44: Input:	

tool: {"D42": [0x07,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x12,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

tool: D7: Output:	

tool: D33: 


assistant: ```c
void problem1() {
  printf("###### Problem 1 ######\n\n");
  int findNextGreaterInput[] = {12, 15, 22, 9, 7, 2, 18, 23, 27};
  int findNextGreaterLength = 9;
  int i;
  printf("Input:\t");
  for (i = 0; i < findNextGreaterLength; i++) {
    printf("%i\t", findNextGreaterInput[i]);
  }
  printf("\n");
  int *findNextGreaterOutput = findNextGreater(findNextGreaterInput, findNextGreaterLength);
  printf("Output:\t");
  for (i = 0; i < findNextGreaterLength; i++) {
    printf("%i\t", findNextGreaterOutput[i]);
  }
  free(findNextGreaterOutput);
  printf("\n\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<path_remove_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1d(%rbp)
  movsbl -0x1d(%rbp),%eax
  mov    %eax,%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  je     L5
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_front_of_slashes@plt>
  mov    %rax,-0x18(%rbp)
L5:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  subq   $0x1,-0x18(%rbp)
  jmp    L89
L71:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1d(%rbp)
  movsbl -0x1d(%rbp),%eax
  mov    %eax,%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L102
  cmpb   $0x2e,-0x1d(%rbp)
  jne    L13
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  je     L80
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1d(%rbp)
  movsbl -0x1d(%rbp),%eax
  mov    %eax,%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L70
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  jmp    L81
L13:
  nop
  subq   $0x1,-0x18(%rbp)
L89:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L71
  jmp    L0
L102:
  nop
  jmp    L0
L80:
  nop
  jmp    L0
L70:
  nop
L0:
  mov    -0x2c(%rbp),%eax
L81:
  leave
  ret
```

assistant: ```c
uint64_t path_remove_extension(const char *__attribute__((nonnull)) const path, const uint64_t length) {
  const char *const back = path + (length - 1);
  const char *iter = back;
  char ch = *iter;
  if (ch_is_slash(ch)) {
    iter = get_front_of_slashes(path, iter);
  }
  const char *const rev_end = path - 1;
  for (--iter; iter != rev_end; --iter) {
    ch = *iter;
    if (ch_is_slash(ch)) {
      break;
    }
    if (ch != '.') {
      continue;
    }
    if (iter == path) {
      break;
    }
    ch = iter[-1];
    if (ch_is_slash(ch)) {
      break;
    }
    const uint64_t new_length = (uint64_t)(iter - path);
    return new_length;
  }
  return length;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<path_remove_extension>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  movslq %esi,%rax
  lea    -0x1(%rdi,%rax,1),%rbx
  movsbl (%rbx),%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L73
L9:
  lea    -0x1(%rbp),%r14
  sub    $0x1,%rbx
  cmp    %rbx,%r14
  je     L12
L38:
  movzbl (%rbx),%r13d
  movsbl %r13b,%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L12
  cmp    $0x2e,%r13b
  jne    L72
  cmp    %rbx,%rbp
  je     L12
  movsbl -0x1(%rbx),%edi
  call   <ch_is_slash@plt>
  sub    %rbp,%rbx
  test   %rax,%rax
  cmove  %ebx,%r12d
L12:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L73:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <get_front_of_slashes@plt>
  mov    %rax,%rbx
  jmp    L9
L72:
  sub    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L38
  jmp    L12
```

assistant: ```c
uint64_t path_remove_extension(const char *__attribute__((nonnull)) const path, const uint64_t length) {
  const char *const back = path + (length - 1);
  const char *iter = back;
  char ch = *iter;
  if (ch_is_slash(ch)) {
    iter = get_front_of_slashes(path, iter);
  }
  const char *const rev_end = path - 1;
  for (--iter; iter != rev_end; --iter) {
    ch = *iter;
    if (ch_is_slash(ch)) {
      break;
    }
    if (ch != '.') {
      continue;
    }
    if (iter == path) {
      break;
    }
    ch = iter[-1];
    if (ch_is_slash(ch)) {
      break;
    }
    const uint64_t new_length = (uint64_t)(iter - path);
    return new_length;
  }
  return length;
}
```
user: Translate the below assembly code into C programming language:

```asm
<path_remove_extension>:
  endbr64
  movslq %esi,%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  lea    -0x1(%rdi,%rax,1),%rbp
  push   %rbx
  movsbl 0x0(%rbp),%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L65
L27:
  lea    -0x1(%r13),%r14
  lea    -0x1(%rbp),%rbx
  cmp    %rbx,%r14
  je     L74
L17:
  movsbl (%rbx),%edi
  mov    %edi,%ebp
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L74
  cmp    $0x2e,%bpl
  je     L7
  sub    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L17
L74:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L7:
  cmp    %rbx,%r13
  je     L74
  movsbl -0x1(%rbx),%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L74
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L65:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <get_front_of_slashes@plt>
  mov    %rax,%rbp
  jmp    L27
```

assistant: ```c
uint64_t path_remove_extension(const char *__attribute__((nonnull)) const path, const uint64_t length) {
  const char *const back = path + (length - 1);
  const char *iter = back;
  char ch = *iter;
  if (ch_is_slash(ch)) {
    iter = get_front_of_slashes(path, iter);
  }
  const char *const rev_end = path - 1;
  for (--iter; iter != rev_end; --iter) {
    ch = *iter;
    if (ch_is_slash(ch)) {
      break;
    }
    if (ch != '.') {
      continue;
    }
    if (iter == path) {
      break;
    }
    ch = iter[-1];
    if (ch_is_slash(ch)) {
      break;
    }
    const uint64_t new_length = (uint64_t)(iter - path);
    return new_length;
  }
  return length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<path_remove_extension>:
  endbr64
  movslq %esi,%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  lea    -0x1(%rdi,%rax,1),%rbp
  push   %rbx
  movsbl 0x0(%rbp),%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L19
L16:
  lea    -0x1(%r13),%r14
  lea    -0x1(%rbp),%rbx
  cmp    %rbx,%r14
  je     L39
L78:
  movsbl (%rbx),%edi
  mov    %edi,%ebp
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L39
  cmp    $0x2e,%bpl
  je     L77
  sub    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L78
L39:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L77:
  cmp    %rbx,%r13
  je     L39
  movsbl -0x1(%rbx),%edi
  call   <ch_is_slash@plt>
  test   %rax,%rax
  jne    L39
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L19:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <get_front_of_slashes@plt>
  mov    %rax,%rbp
  jmp    L16
```

assistant: ```c
uint64_t path_remove_extension(const char *__attribute__((nonnull)) const path, const uint64_t length) {
  const char *const back = path + (length - 1);
  const char *iter = back;
  char ch = *iter;
  if (ch_is_slash(ch)) {
    iter = get_front_of_slashes(path, iter);
  }
  const char *const rev_end = path - 1;
  for (--iter; iter != rev_end; --iter) {
    ch = *iter;
    if (ch_is_slash(ch)) {
      break;
    }
    if (ch != '.') {
      continue;
    }
    if (iter == path) {
      break;
    }
    ch = iter[-1];
    if (ch_is_slash(ch)) {
      break;
    }
    const uint64_t new_length = (uint64_t)(iter - path);
    return new_length;
  }
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<out_err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0xe0(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xe0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edi
  mov    -0xe0(%rbp),%rcx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %edi,%r9d
  mov    %rcx,%r8
  lea    D1(%rip),%rcx
  mov    %rax,%rdi
  call   <out_error@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: 


assistant: ```c
void out_err(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  out_error(file, line, func, "\n", fmt, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<out_err>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%r14
  mov    %rcx,%rbx
  mov    %rcx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r9d
  mov    %rbx,%r8
  lea    D3(%rip),%rcx
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <out_error@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: 


assistant: ```c
void out_err(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  out_error(file, line, func, "\n", fmt, ap);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<out_err>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  mov    %rcx,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %rcx,%rbx
  call   <va_start@plt>
  mov    %ebp,%r9d
  mov    %rbx,%r8
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  lea    D3(%rip),%rcx
  call   <out_error@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string

tool: D3: 


assistant: ```c
void out_err(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  out_error(file, line, func, "\n", fmt, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below:

```asm
<out_err>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  mov    %rcx,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %rcx,%rbx
  call   <va_start@plt>
  mov    %ebp,%r9d
  mov    %rbx,%r8
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  lea    D3(%rip),%rcx
  call   <out_error@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: 


assistant: ```c
void out_err(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  out_error(file, line, func, "\n", fmt, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ccr2cl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <emit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type_guessed: string
name: parse_data
arguments: data_label: D61
type_guessed: string
name: parse_data
arguments: data_label: D69
type_guessed: string
name: parse_data
arguments: data_label: D70
type_guessed: string
name: parse_data
arguments: data_label: D58
type_guessed: string
name: parse_data
arguments: data_label: D41
type_guessed: string
name: parse_data
arguments: data_label: D68
type_guessed: string
name: parse_data
arguments: data_label: D55
type_guessed: string

tool: D17: mov ch,[__xflag]


tool: D61: mov cl,ah


tool: D69: shr cx,6


tool: D70: add cl,cl


tool: D58: or cl,al


tool: D41: mov ch,ah


tool: D68: shl ch,8


tool: D55: adc cl,cl


assistant: ```c
void ccr2cl(void) {
  emit("mov ch,[__xflag]\n");
  emit("mov cl,ah\n");
  emit("shr cx,6\n");
  emit("add cl,cl\n");
  emit("or cl,al\n");
  emit("mov ch,ah\n");
  emit("shl ch,8\n");
  emit("adc cl,cl\n");
}
```