ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D54
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D46
type_infered: string
name: retrieve_data
arguments: data_tag: D53
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string

tool: D1: Type int has a size of %zd bytes.


tool: D54: Type cahr has a size of %zd bytes.


tool: D29: Type long has a size of %zd bytes.


tool: D46: Type long long has a size of %zd bytes.


tool: D53: Type double has a size of %zd bytes.


tool: D14: Type long  double has a size of %zd bytes.


assistant: ```c
main(void) {
  printf("Type int has a size of %zd bytes.\n", sizeof(int));
  printf("Type cahr has a size of %zd bytes.\n", sizeof(char));
  printf("Type long has a size of %zd bytes.\n", sizeof(long));
  printf("Type long long has a size of %zd bytes.\n", sizeof(long long));
  printf("Type double has a size of %zd bytes.\n", sizeof(double));
  printf("Type long  double has a size of %zd bytes.\n", sizeof(long double));
  getch();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L30:
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L27:
  addl   $0x1,-0x4(%rbp)
L38:
  cmpl   $0x1f3,-0x4(%rbp)
  jle    L27
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x4c4b3f,-0x8(%rbp)
  jle    L30
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_guessed: string
name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D17: >>>>> I have been count until 5000000 <<<<<

tool: D1: %s


assistant: ```c
int main() {
  for (int i = 0; i < 5000000; ++i) {
    for (int j = 0; j < 500; ++j) {
    }
  }
  printf("%s\n", ">>>>> I have been count until 5000000 <<<<<");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4c4b40,%edx
L19:
  mov    $0x1f4,%eax
L5:
  sub    $0x1,%eax
  jne    L5
  sub    $0x1,%edx
  jne    L19
  lea    D9(%rip),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string
name: read_data
arguments: tag: D2
data_type: string

tool: D9: >>>>> I have been count until 5000000 <<<<<

tool: D2: %s


assistant: ```c
int main() {
  for (int i = 0; i < 5000000; ++i) {
    for (int j = 0; j < 500; ++j) {
    }
  }
  printf("%s\n", ">>>>> I have been count until 5000000 <<<<<");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string
name: unpack_data
arguments: data_label: D1
type: string

tool: D5: >>>>> I have been count until 5000000 <<<<<

tool: D1: %s


assistant: ```c
int main() {
  for (int i = 0; i < 5000000; ++i) {
    for (int j = 0; j < 500; ++j) {
    }
  }
  printf("%s\n", ">>>>> I have been count until 5000000 <<<<<");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string

tool: D1: >>>>> I have been count until 5000000 <<<<<

tool: D15: %s


assistant: ```c
int main() {
  for (int i = 0; i < 5000000; ++i) {
    for (int j = 0; j < 500; ++j) {
    }
  }
  printf("%s\n", ">>>>> I have been count until 5000000 <<<<<");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D47(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    0x10(%rsp),%esi
  test   %esi,%esi
  jle    L26
  mov    %rax,%rbx
  mov    %rax,%r12
  mov    $0x0,%ebp
  lea    D67(%rip),%r15
  lea    0x14(%rsp),%r14
  lea    D47(%rip),%r13
L43:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,(%r12)
  add    $0x1,%ebp
  mov    0x10(%rsp),%esi
  add    $0x4,%r12
  cmp    %ebp,%esi
  jg     L43
  test   %esi,%esi
  jle    L26
  mov    $0x0,%ebp
  lea    D46(%rip),%r14
  lea    D35(%rip),%r13
  lea    D24(%rip),%r12
L57:
  sub    $0x1,%esi
  cmp    %ebp,%esi
  mov    %r13,%rdx
  cmove  %r14,%rdx
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  mov    0x10(%rsp),%esi
  add    $0x4,%rbx
  cmp    %ebp,%esi
  jg     L57
L26:
  mov    0x8(%rsp),%rbp
  mov    %rbp,%rdi
  call   <insertion_sort@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L54
  mov    $0x0,%ebx
  lea    D46(%rip),%r14
  lea    D35(%rip),%r13
  lea    D24(%rip),%r12
L42:
  sub    $0x1,%eax
  cmp    %ebx,%eax
  mov    %r13,%rdx
  cmove  %r14,%rdx
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0x10(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L42
L54:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D66
type_infered: string
name: disassemble_data
arguments: data_label: D47
type_infered: string
name: disassemble_data
arguments: data_label: D67
type_infered: string
name: disassemble_data
arguments: data_label: D46
type_infered: string
name: disassemble_data
arguments: data_label: D35
type_infered: string
name: disassemble_data
arguments: data_label: D24
type_infered: string

tool: D66: Enter number of elements: 

tool: D47: %d

tool: D67: > 

tool: D46: 


tool: D35:  

tool: D24: %d%s

assistant: ```c
int main() {
  int n, m;
  int *array;
  printf("Enter number of elements: ");
  scanf("%d", &n);
  array = (int *)malloc(sizeof(int) * n);
  int j;
  for (j = 0; j < n; j++) {
    printf("> ");
    scanf("%d", &m);
    array[j] = m;
  }
  int i;
  for (i = 0; i < n; i++)
    printf("%d%s", array[i], i == n - 1 ? "\n" : " ");
  insertion_sort(array, n);
  for (i = 0; i < n; i++)
    printf("%d%s", array[i], i == n - 1 ? "\n" : " ");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D47(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D80(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%esi
  mov    %rax,0x8(%rsp)
  test   %esi,%esi
  jle    L36
  mov    %rax,%rbp
  mov    %rax,%rbx
  lea    D34(%rip),%r14
  xor    %r15d,%r15d
  lea    0x14(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  add    $0x4,%rbx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,-0x4(%rbx)
  mov    0x10(%rsp),%esi
  cmp    %r15d,%esi
  jg     L52
  test   %esi,%esi
  jle    L36
  xor    %r15d,%r15d
  lea    D11(%rip),%r12
  lea    D8(%rip),%r14
  lea    D0(%rip),%r13
  nopl   0x0(%rax)
L42:
  sub    $0x1,%esi
  mov    %r13,%rdx
  mov    %r12,%rdi
  cmp    %r15d,%esi
  mov    0x0(%rbp),%esi
  cmove  %r14,%rdx
  xor    %eax,%eax
  add    $0x1,%r15d
  add    $0x4,%rbp
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  cmp    %r15d,%esi
  jg     L42
L36:
  mov    0x8(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D11(%rip),%r12
  lea    D8(%rip),%r14
  lea    D0(%rip),%r13
  mov    %rbx,%rdi
  call   <insertion_sort@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L6
  nopw   0x0(%rax,%rax,1)
L68:
  sub    $0x1,%eax
  mov    %r13,%rdx
  mov    (%rbx),%esi
  mov    %r12,%rdi
  cmp    %ebp,%eax
  cmove  %r14,%rdx
  xor    %eax,%eax
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  cmp    %ebp,%eax
  jg     L68
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D47
type_infered: string
name: parse_data
arguments: label: D80
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D0
type_infered: string

tool: D47: Enter number of elements: 

tool: D80: %d

tool: D34: > 

tool: D11: %d%s

tool: D8: 


tool: D0:  

assistant: ```c
int main() {
  int n, m;
  int *array;
  printf("Enter number of elements: ");
  scanf("%d", &n);
  array = (int *)malloc(sizeof(int) * n);
  int j;
  for (j = 0; j < n; j++) {
    printf("> ");
    scanf("%d", &m);
    array[j] = m;
  }
  int i;
  for (i = 0; i < n; i++)
    printf("%d%s", array[i], i == n - 1 ? "\n" : " ");
  insertion_sort(array, n);
  for (i = 0; i < n; i++)
    printf("%d%s", array[i], i == n - 1 ? "\n" : " ");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mskbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %ax,-0x1a(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpw   $0x0,-0x1a(%rbp)
  je     L16
  jmp    L55
L8:
  shrw   -0x1a(%rbp)
L55:
  movzwl -0x1a(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L8
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0xc(%rbp)
  jne    L83
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
L83:
  movl   $0x0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L22
L74:
  movzwl -0x1a(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L88
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0x8(%rbp)
L88:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
  shrw   -0x1a(%rbp)
  addl   $0x1,-0x18(%rbp)
L22:
  mov    $0x10,%eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L74
  cmpl   $0x1,-0x10(%rbp)
  jne    L18
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  cmpl   $0x0,-0x4(%rbp)
  jle    L91
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L91
L18:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
L91:
  mov    -0x38(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mskbits(int *mask, int *ibits, int *ndash) {
  int i, ic, ibit, ibitold;
  int nbits, nshft;
  unsigned short lmask;
  lmask = *mask;
  nshft = 0;
  if (lmask != 0) {
    while (!(ibitold = (lmask & 0x01)))
      lmask >>= 1;
    nshft++;
  }
  if (ibitold == 0) {
    *ndash = 0;
    exit;
  }
  nbits = ic = 0;
  for (i = 0; i < (16 - nshft); ++i) {
    ibit = (lmask & 0x01);
    if (ibit != ibitold) {
      ibits[ic++] = nbits;
      nbits = 0;
    }
    ibitold = ibit;
    nbits++;
    lmask >>= 1;
  }
  if (ibit == 1) {
    ibits[ic++] = nbits;
    if (nshft > 0)
      ibits[ic++] = nshft;
  } else
    ibits[ic++] = nbits + nshft;
  *ndash = ic;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mskbits>:
  endbr64
  push   %rbx
  mov    %rsi,%r10
  mov    %rdx,%rbx
  mov    (%rdi),%edx
  mov    %edx,%eax
  mov    $0x0,%r11d
  test   %dx,%dx
  je     L24
  test   $0x1,%dl
  jne    L43
L4:
  shr    %ax
  test   $0x1,%al
  je     L4
  mov    $0x1,%r11d
L24:
  mov    $0x10,%r9d
  sub    %r11d,%r9d
  mov    $0x0,%edx
  mov    $0x1,%ecx
  mov    $0x0,%edi
  mov    $0x0,%esi
  jmp    L13
L43:
  mov    $0x1,%r11d
  jmp    L24
L75:
  add    $0x1,%edx
  shr    %ax
  add    $0x1,%esi
  cmp    %r9d,%esi
  je     L92
L13:
  mov    %ecx,%r8d
  mov    %eax,%ecx
  and    $0x1,%ecx
  cmp    %r8d,%ecx
  je     L75
  movslq %edi,%r8
  mov    %edx,(%r10,%r8,4)
  lea    0x1(%rdi),%edi
  mov    $0x0,%edx
  jmp    L75
L92:
  cmp    $0x1,%ecx
  je     L48
  lea    0x1(%rdi),%eax
  movslq %edi,%rdi
  add    %edx,%r11d
  mov    %r11d,(%r10,%rdi,4)
L18:
  mov    %eax,(%rbx)
  pop    %rbx
  ret
L48:
  lea    0x1(%rdi),%eax
  movslq %edi,%rcx
  lea    0x0(,%rcx,4),%rsi
  mov    %edx,(%r10,%rcx,4)
  test   %r11d,%r11d
  jle    L18
  lea    0x2(%rdi),%eax
  movl   $0x1,0x4(%r10,%rsi,1)
  jmp    L18
```

assistant: ```c
void mskbits(int *mask, int *ibits, int *ndash) {
  int i, ic, ibit, ibitold;
  int nbits, nshft;
  unsigned short lmask;
  lmask = *mask;
  nshft = 0;
  if (lmask != 0) {
    while (!(ibitold = (lmask & 0x01)))
      lmask >>= 1;
    nshft++;
  }
  if (ibitold == 0) {
    *ndash = 0;
    exit;
  }
  nbits = ic = 0;
  for (i = 0; i < (16 - nshft); ++i) {
    ibit = (lmask & 0x01);
    if (ibit != ibitold) {
      ibits[ic++] = nbits;
      nbits = 0;
    }
    ibitold = ibit;
    nbits++;
    lmask >>= 1;
  }
  if (ibit == 1) {
    ibits[ic++] = nbits;
    if (nshft > 0)
      ibits[ic++] = nshft;
  } else
    ibits[ic++] = nbits + nshft;
  *ndash = ic;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mskbits>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    (%rdi),%edx
  mov    %rsi,%r10
  xor    %r11d,%r11d
  mov    %edx,%eax
  test   %dx,%dx
  je     L55
  and    $0x1,%edx
  jne    L51
  nopl   0x0(%rax)
L81:
  shr    %ax
  test   $0x1,%al
  je     L81
L51:
  mov    $0x1,%r11d
L55:
  mov    %r11d,%r9d
  xor    %edi,%edi
  mov    $0x1,%edx
  xor    %esi,%esi
  neg    %r9d
  xor    %ecx,%ecx
  add    $0x10,%r9d
  jmp    L62
  nopl   0x0(%rax)
L25:
  movslq %esi,%r8
  add    $0x1,%ecx
  add    $0x1,%esi
  shr    %ax
  mov    %edi,(%r10,%r8,4)
  mov    $0x1,%edi
  cmp    %r9d,%ecx
  je     L3
L62:
  mov    %edx,%r8d
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    %r8d,%edx
  jne    L25
  add    $0x1,%ecx
  add    $0x1,%edi
  shr    %ax
  cmp    %r9d,%ecx
  jne    L62
L3:
  movslq %esi,%rax
  lea    0x1(%rsi),%ecx
  shl    $0x2,%rax
  lea    (%r10,%rax,1),%r8
  cmp    $0x1,%edx
  je     L48
  add    %edi,%r11d
  mov    %r11d,(%r8)
L22:
  mov    %ecx,(%rbx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %edi,(%r8)
  cmp    $0x1,%r11d
  jne    L22
  movl   $0x1,0x4(%r10,%rax,1)
  lea    0x2(%rsi),%ecx
  mov    %ecx,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void mskbits(int *mask, int *ibits, int *ndash) {
  int i, ic, ibit, ibitold;
  int nbits, nshft;
  unsigned short lmask;
  lmask = *mask;
  nshft = 0;
  if (lmask != 0) {
    while (!(ibitold = (lmask & 0x01)))
      lmask >>= 1;
    nshft++;
  }
  if (ibitold == 0) {
    *ndash = 0;
    exit;
  }
  nbits = ic = 0;
  for (i = 0; i < (16 - nshft); ++i) {
    ibit = (lmask & 0x01);
    if (ibit != ibitold) {
      ibits[ic++] = nbits;
      nbits = 0;
    }
    ibitold = ibit;
    nbits++;
    lmask >>= 1;
  }
  if (ibit == 1) {
    ibits[ic++] = nbits;
    if (nshft > 0)
      ibits[ic++] = nshft;
  } else
    ibits[ic++] = nbits + nshft;
  *ndash = ic;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<replace_zeroes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L0
L8:
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  movb   $0x1a,(%rax)
L0:
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void replace_zeroes(char *restrict current_char, char const *restrict char_end) {
  while (current_char != NULL) {
    current_char = memchr(current_char, '\0', char_end - current_char);
    if (current_char != NULL) {
      *current_char = '\x1a';
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<replace_zeroes>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  jne    L4
  jmp    L24
L15:
  movb   $0x1a,(%rax)
L4:
  mov    %ebx,%edx
  sub    %edi,%edx
  mov    $0x0,%esi
  call   <memchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L15
L24:
  pop    %rbx
  ret
```

assistant: ```c
void replace_zeroes(char *restrict current_char, char const *restrict char_end) {
  while (current_char != NULL) {
    current_char = memchr(current_char, '\0', char_end - current_char);
    if (current_char != NULL) {
      *current_char = '\x1a';
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<replace_zeroes>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbx
  mov    %rsi,%rbx
  nopl   (%rax)
L21:
  mov    %ebx,%edx
  xor    %esi,%esi
  sub    %edi,%edx
  call   <memchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L20
  movb   $0x1a,(%rax)
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L20:
  pop    %rbx
  ret
L8:
  ret
```

assistant: ```c
void replace_zeroes(char *restrict current_char, char const *restrict char_end) {
  while (current_char != NULL) {
    current_char = memchr(current_char, '\0', char_end - current_char);
    if (current_char != NULL) {
      *current_char = '\x1a';
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<replace_zeroes>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbx
  mov    %rsi,%rbx
  nopl   (%rax)
L17:
  mov    %ebx,%edx
  xor    %esi,%esi
  sub    %edi,%edx
  call   <memchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L23
  movb   $0x1a,(%rax)
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L23:
  pop    %rbx
  ret
L3:
  ret
```

assistant: ```c
void replace_zeroes(char *restrict current_char, char const *restrict char_end) {
  while (current_char != NULL) {
    current_char = memchr(current_char, '\0', char_end - current_char);
    if (current_char != NULL) {
      *current_char = '\x1a';
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrop3_80_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_80_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~D;
  stk1 = T & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_80_1_1>:
  endbr64
  or     %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_80_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~D;
  stk1 = T & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xrop3_80_1_1>:
  endbr64
  or     %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_80_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~D;
  stk1 = T & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_80_1_1>:
  endbr64
  or     %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_80_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~D;
  stk1 = T & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```