ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<hypot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L20
  movsd  -0x18(%rbp),%xmm0
  movq   D25(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L20:
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L42
  movsd  -0x20(%rbp),%xmm0
  movq   D25(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
L42:
  movsd  -0x20(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L34
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L34:
  pxor   %xmm0,%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jp     L9
  pxor   %xmm0,%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jne    L9
  movsd  -0x18(%rbp),%xmm0
  jmp    L44
L9:
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D17(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
L44:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
datatype: f32[2]
name: retrieve_data
arguments: data_tag: D17
datatype: f64

tool: {"D25": [0.0,-0.0]}

tool: D17: 1

assistant: ```c
double hypot(double x, double y) {
  if (x < 0)
    x = -x;
  if (y < 0)
    y = -y;
  if (x < y) {
    double tmp = x;
    x = y;
    y = tmp;
  }
  if (y == 0.0)
    return x;
  y /= x;
  return x * sqrt(1.0 + y * y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hypot>:
  endbr64
  sub    $0x18,%rsp
  movapd %xmm0,%xmm2
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  ja     L84
L50:
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L74
L61:
  movsd  0x8(%rsp),%xmm3
  comisd %xmm3,%xmm1
  jbe    L6
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm3,%xmm1
L6:
  ucomisd D37(%rip),%xmm1
  jp     L7
  jne    L7
L36:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
L84:
  xorpd  D18(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
  jmp    L50
L74:
  xorpd  D18(%rip),%xmm1
  jmp    L61
L7:
  divsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  D36(%rip),%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L0
  sqrtsd %xmm1,%xmm1
L56:
  mulsd  0x8(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
  jmp    L36
L0:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L56
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D37
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D18
datatype: byte[16]
name: extract_symbolic_data
arguments: data_tag: D36
datatype: f64

tool: D37: 0

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D36: 1

assistant: ```c
double hypot(double x, double y) {
  if (x < 0)
    x = -x;
  if (y < 0)
    y = -y;
  if (x < y) {
    double tmp = x;
    x = y;
    y = tmp;
  }
  if (y == 0.0)
    return x;
  y /= x;
  return x * sqrt(1.0 + y * y);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hypot>:
  endbr64
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  jbe    L50
  xorpd  D8(%rip),%xmm0
L50:
  comisd %xmm1,%xmm2
  jbe    L26
  xorpd  D8(%rip),%xmm1
L26:
  comisd %xmm0,%xmm1
  movapd %xmm0,%xmm3
  jbe    L25
  movapd %xmm1,%xmm3
  movapd %xmm0,%xmm1
L25:
  ucomisd %xmm2,%xmm1
  jp     L43
  jne    L43
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  divsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  D22(%rip),%xmm1
  ucomisd %xmm1,%xmm2
  ja     L0
  sqrtsd %xmm1,%xmm1
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  ret
L0:
  sub    $0x18,%rsp
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  add    $0x18,%rsp
  mulsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: f32[4]
name: disassemble_data
arguments: data_tag: D22
datatype: f64

tool: {"D8": [0.0,-0.0,0.0,0.0]}

tool: D22: 1

assistant: ```c
double hypot(double x, double y) {
  if (x < 0)
    x = -x;
  if (y < 0)
    y = -y;
  if (x < y) {
    double tmp = x;
    x = y;
    y = tmp;
  }
  if (y == 0.0)
    return x;
  y /= x;
  return x * sqrt(1.0 + y * y);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hypot>:
  endbr64
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  jbe    L51
  xorpd  D25(%rip),%xmm0
L51:
  comisd %xmm1,%xmm2
  jbe    L5
  xorpd  D25(%rip),%xmm1
L5:
  comisd %xmm0,%xmm1
  movapd %xmm0,%xmm3
  jbe    L3
  movapd %xmm1,%xmm3
  movapd %xmm0,%xmm1
L3:
  ucomisd %xmm2,%xmm1
  jp     L49
  jne    L49
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  divsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  D23(%rip),%xmm1
  ucomisd %xmm1,%xmm2
  ja     L7
  sqrtsd %xmm1,%xmm1
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  ret
L7:
  sub    $0x18,%rsp
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  add    $0x18,%rsp
  mulsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type: f32[4]
name: retrieve_data
arguments: data_tag: D23
type: f64

tool: {"D25": [0.0,-0.0,0.0,0.0]}

tool: D23: 1

assistant: ```c
double hypot(double x, double y) {
  if (x < 0)
    x = -x;
  if (y < 0)
    y = -y;
  if (x < y) {
    double tmp = x;
    x = y;
    y = tmp;
  }
  if (y == 0.0)
    return x;
  y /= x;
  return x * sqrt(1.0 + y * y);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<worleyFF_F>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %esi,-0xac(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x98(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x90(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,-0x88(%rbp)
  mov    -0x98(%rbp),%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x60(%rbp)
  mov    -0x90(%rbp),%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  lea    -0x70(%rbp),%rsi
  lea    -0x40(%rbp),%rcx
  lea    -0x80(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rsi,%r8
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <Worley@plt>
  movsd  -0x80(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x88(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int worleyFF_F(void *initdata, int argc, void **argv) {
  float *x = (float *)argv[1];
  float *y = (float *)argv[2];
  float *f1 = (float *)argv[3];
  double at[3];
  at[0] = *x;
  at[1] = *y;
  at[2] = 0.0;
  double F[2];
  double delta[2][3];
  unsigned long ID[2];
  Worley(at, 2, F, delta, ID);
  *f1 = (float)F[0];
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<worleyFF_F>:
  endbr64
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    0x10(%rdx),%rax
  mov    0x18(%rdx),%rbx
  mov    0x8(%rdx),%rdx
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdx),%xmm0
  movsd  %xmm0,0x20(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax),%xmm0
  movsd  %xmm0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    0x40(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r8
  mov    $0x2,%esi
  call   <Worley@plt>
  pxor   %xmm0,%xmm0
  cvtsd2ss (%rsp),%xmm0
  movss  %xmm0,(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int worleyFF_F(void *initdata, int argc, void **argv) {
  float *x = (float *)argv[1];
  float *y = (float *)argv[2];
  float *f1 = (float *)argv[3];
  double at[3];
  at[0] = *x;
  at[1] = *y;
  at[2] = 0.0;
  double F[2];
  double delta[2][3];
  unsigned long ID[2];
  Worley(at, 2, F, delta, ID);
  *f1 = (float)F[0];
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<worleyFF_F>:
  endbr64
  push   %rbx
  pxor   %xmm0,%xmm0
  mov    $0x2,%esi
  add    $0xffffffffffffff80,%rsp
  mov    0x18(%rdx),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  mov    0x10(%rdx),%rax
  mov    0x8(%rdx),%rdx
  lea    0x40(%rsp),%rcx
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r8
  cvtss2sd (%rdx),%xmm0
  mov    %rsp,%rdx
  movsd  %xmm0,0x20(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax),%xmm0
  movsd  %xmm0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  call   <Worley@plt>
  pxor   %xmm0,%xmm0
  cvtsd2ss (%rsp),%xmm0
  movss  %xmm0,(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int worleyFF_F(void *initdata, int argc, void **argv) {
  float *x = (float *)argv[1];
  float *y = (float *)argv[2];
  float *f1 = (float *)argv[3];
  double at[3];
  at[0] = *x;
  at[1] = *y;
  at[2] = 0.0;
  double F[2];
  double delta[2][3];
  unsigned long ID[2];
  Worley(at, 2, F, delta, ID);
  *f1 = (float)F[0];
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<worleyFF_F>:
  endbr64
  push   %rbx
  mov    $0x2,%esi
  add    $0xffffffffffffff80,%rsp
  mov    0x18(%rdx),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    0x8(%rdx),%rax
  mov    0x10(%rdx),%rdx
  lea    0x40(%rsp),%rcx
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r8
  movss  (%rdx),%xmm1
  movss  (%rax),%xmm0
  mov    %rsp,%rdx
  movq   $0x0,0x30(%rsp)
  unpcklps %xmm1,%xmm0
  cvtps2pd %xmm0,%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <Worley@plt>
  pxor   %xmm0,%xmm0
  cvtsd2ss (%rsp),%xmm0
  movss  %xmm0,(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int worleyFF_F(void *initdata, int argc, void **argv) {
  float *x = (float *)argv[1];
  float *y = (float *)argv[2];
  float *f1 = (float *)argv[3];
  double at[3];
  at[0] = *x;
  at[1] = *y;
  at[2] = 0.0;
  double F[2];
  double delta[2][3];
  unsigned long ID[2];
  Worley(at, 2, F, delta, ID);
  *f1 = (float)F[0];
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_putnchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L7
L17:
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <my_putchar@plt>
L7:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void my_putnchar(char c, int nb) {
  int i;
  i = -1;
  while (++i < nb)
    my_putchar(c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_putnchar>:
  endbr64
  test   %esi,%esi
  jle    L2
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    $0x0,%ebx
  movsbl %dil,%ebp
L18:
  mov    %ebp,%edi
  call   <my_putchar@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  ret
```

assistant: ```c
void my_putnchar(char c, int nb) {
  int i;
  i = -1;
  while (++i < nb)
    my_putchar(c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_putnchar>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %r12
  movsbl %dil,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L4:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <my_putchar@plt>
  cmp    %ebp,%ebx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void my_putnchar(char c, int nb) {
  int i;
  i = -1;
  while (++i < nb)
    my_putchar(c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_putnchar>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %r12
  movsbl %dil,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L5:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <my_putchar@plt>
  cmp    %ebp,%ebx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
void my_putnchar(char c, int nb) {
  int i;
  i = -1;
  while (++i < nb)
    my_putchar(c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pix2ang_nest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pix2ang_nest_z_phi@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <acos@plt>
  movq   %xmm0,%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void pix2ang_nest(long nside, long ipix, double *theta, double *phi) {
  double z;
  pix2ang_nest_z_phi(nside, ipix, &z, phi);
  *theta = acos(z);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pix2ang_nest>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <pix2ang_nest_z_phi@plt>
  movsd  (%rsp),%xmm0
  call   <acos@plt>
  movsd  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void pix2ang_nest(long nside, long ipix, double *theta, double *phi) {
  double z;
  pix2ang_nest_z_phi(nside, ipix, &z, phi);
  *theta = acos(z);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pix2ang_nest>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <pix2ang_nest_z_phi@plt>
  movsd  (%rsp),%xmm0
  call   <acos@plt>
  movsd  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void pix2ang_nest(long nside, long ipix, double *theta, double *phi) {
  double z;
  pix2ang_nest_z_phi(nside, ipix, &z, phi);
  *theta = acos(z);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pix2ang_nest>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <pix2ang_nest_z_phi@plt>
  movsd  (%rsp),%xmm0
  call   <acos@plt>
  movsd  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void pix2ang_nest(long nside, long ipix, double *theta, double *phi) {
  double z;
  pix2ang_nest_z_phi(nside, ipix, &z, phi);
  *theta = acos(z);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putlong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x9,-0x8(%rbp)
  jle    L9
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <putlong>
L9:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  add    $0x30,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <ft_putchar_fd@plt>
  nop
  leave
  ret
```

assistant: ```c
void putlong(long n, int fd) {
  if (n >= 10)
    putlong(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<putlong>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  cmp    $0x9,%rdi
  jg     L5
L11:
  movabs $0x6666666666666667,%rdx
  mov    %rbx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  mov    %ebp,%esi
  call   <ft_putchar_fd@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  movabs $0x6666666666666667,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdx,%rdi
  sar    $0x2,%rdi
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdi
  call   <putlong>
  jmp    L11
```

assistant: ```c
void putlong(long n, int fd) {
  if (n >= 10)
    putlong(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<putlong>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x9,%rdi
  jg     L2
L31:
  mov    %rbx,%rax
  add    $0x8,%rsp
  mov    %ebp,%esi
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <ft_putchar_fd@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  movabs $0x6666666666666667,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  mov    %rdx,%r12
  cmp    $0x63,%rdi
  jg     L5
L7:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r12,%rax
  mov    %ebp,%esi
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r12
  lea    0x30(%r12),%rdi
  call   <ft_putchar_fd@plt>
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L5:
  movabs $0xcccccccccccccccd,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%r13
  cmp    $0x3e7,%rdi
  jg     L42
L0:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r13,%rax
  mov    %ebp,%esi
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r13
  lea    0x30(%r13),%rdi
  call   <ft_putchar_fd@plt>
  jmp    L7
  xchg   %ax,%ax
L42:
  mov    %rdx,%rax
  mul    %rcx
  mov    %rdx,%rdi
  shr    $0x3,%rdi
  call   <putlong>
  jmp    L0
```

assistant: ```c
void putlong(long n, int fd) {
  if (n >= 10)
    putlong(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: What is the c source code of the assembly code below:

```asm
<putlong>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x9,%rdi
  jg     L29
L24:
  mov    %rbx,%rax
  add    $0x8,%rsp
  mov    %ebp,%esi
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <ft_putchar_fd@plt>
  cs nopw 0x0(%rax,%rax,1)
L29:
  movabs $0x6666666666666667,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  mov    %rdx,%r12
  cmp    $0x63,%rdi
  jg     L32
L27:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r12,%rax
  mov    %ebp,%esi
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r12
  lea    0x30(%r12),%rdi
  call   <ft_putchar_fd@plt>
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L32:
  movabs $0xcccccccccccccccd,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%r13
  cmp    $0x3e7,%rdi
  jg     L53
L48:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r13,%rax
  mov    %ebp,%esi
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r13
  lea    0x30(%r13),%rdi
  call   <ft_putchar_fd@plt>
  jmp    L27
  xchg   %ax,%ax
L53:
  mov    %rdx,%rax
  mul    %rcx
  mov    %rdx,%rdi
  shr    $0x3,%rdi
  call   <putlong>
  jmp    L48
```

assistant: ```c
void putlong(long n, int fd) {
  if (n >= 10)
    putlong(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Rename_REV_SEQ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L15:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <Rename_SWP_SEQ@plt>
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void Rename_REV_SEQ(ii, jj) int ii, jj;
{
  int i, j;
  i = ii;
  j = jj;
  while (i < j) {
    Rename_SWP_SEQ(i, j);
    i = i + 1;
    j = j - 1;
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Rename_REV_SEQ>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  cmp    %esi,%edi
  jge    L19
L9:
  mov    %ebx,%esi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <Rename_SWP_SEQ@plt>
  add    $0x1,%ebp
  sub    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L9
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Rename_REV_SEQ(ii, jj) int ii, jj;
{
  int i, j;
  i = ii;
  j = jj;
  while (i < j) {
    Rename_SWP_SEQ(i, j);
    i = i + 1;
    j = j - 1;
  };
}
```
user: What is the c source code of the assembly code below:

```asm
<Rename_REV_SEQ>:
  endbr64
  cmp    %esi,%edi
  jge    L7
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%esi
  mov    %ebp,%edi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <Rename_SWP_SEQ@plt>
  sub    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
void Rename_REV_SEQ(ii, jj) int ii, jj;
{
  int i, j;
  i = ii;
  j = jj;
  while (i < j) {
    Rename_SWP_SEQ(i, j);
    i = i + 1;
    j = j - 1;
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Rename_REV_SEQ>:
  endbr64
  cmp    %esi,%edi
  jge    L8
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%esi
  mov    %ebp,%edi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <Rename_SWP_SEQ@plt>
  sub    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
void Rename_REV_SEQ(ii, jj) int ii, jj;
{
  int i, j;
  i = ii;
  j = jj;
  while (i < j) {
    Rename_SWP_SEQ(i, j);
    i = i + 1;
    j = j - 1;
  };
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<true_or_false>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L19
  lea    D13(%rip),%rax
  jmp    L18
L19:
  lea    D1(%rip),%rax
L18:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D13
data_type: string
name: read_data
arguments: label: D1
data_type: string

tool: D13: True

tool: D1: False

assistant: ```c
char *true_or_false(int flag) {
  if (flag) {
    return ("True");
  } else {
    return ("False");
  }
}
```