ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L29
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L29:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x3e18c5a9,%esi
  je     L12
L28:
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L28
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D15
type: string
name: extract_symbolic_data
arguments: label: D21
type: string

tool: D24: Call this program with %i arguments


tool: D15: %u


tool: D21: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1041810857U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string

tool: D14: before swap: a = %d, b = %d


tool: D11: after swap: a = %d, b = %d


assistant: ```c
int main(void) {
  int a = 5;
  int b = 4;
  printf("before swap: a = %d, b = %d\n", a, b);
  swap(&a, &b);
  printf("after swap: a = %d, b = %d\n", a, b);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x4,0x4(%rsp)
  mov    $0x4,%edx
  mov    $0x5,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string

tool: D4: before swap: a = %d, b = %d


tool: D14: after swap: a = %d, b = %d


assistant: ```c
int main(void) {
  int a = 5;
  int b = 4;
  printf("before swap: a = %d, b = %d\n", a, b);
  swap(&a, &b);
  printf("after swap: a = %d, b = %d\n", a, b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  movl   $0x5,(%rsp)
  movl   $0x4,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
datatype: string
name: parse_data
arguments: data_label: D11
datatype: string

tool: D14: before swap: a = %d, b = %d


tool: D11: after swap: a = %d, b = %d


assistant: ```c
int main(void) {
  int a = 5;
  int b = 4;
  printf("before swap: a = %d, b = %d\n", a, b);
  swap(&a, &b);
  printf("after swap: a = %d, b = %d\n", a, b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  movl   $0x5,(%rsp)
  movl   $0x4,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string

tool: D9: before swap: a = %d, b = %d


tool: D10: after swap: a = %d, b = %d


assistant: ```c
int main(void) {
  int a = 5;
  int b = 4;
  printf("before swap: a = %d, b = %d\n", a, b);
  swap(&a, &b);
  printf("after swap: a = %d, b = %d\n", a, b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    D99(%rip),%rdi
  call   <puts@plt>
  lea    D38(%rip),%rsi
  lea    D101(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D65(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  add    (%rsp),%edx
  lea    D13(%rip),%rsi
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  imul   0x4(%rsp),%edx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  sub    0x4(%rsp),%edx
  lea    D69(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%edx
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  cltd
  idivl  0x4(%rsp)
  lea    D30(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D99
type_guessed: string
name: disassemble_data
arguments: tag: D38
type_guessed: string
name: disassemble_data
arguments: tag: D101
type_guessed: string
name: disassemble_data
arguments: tag: D65
type_guessed: string
name: disassemble_data
arguments: tag: D44
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D20
type_guessed: string
name: disassemble_data
arguments: tag: D9
type_guessed: string
name: disassemble_data
arguments: tag: D69
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D30
type_guessed: string

tool: D99: Input two integers

tool: D38: Give the First integer: 

tool: D101: %s

tool: D65: %d

tool: D44: Give the Second integer: 

tool: D13: sum: 

tool: D20: %s %d 


tool: D9: product: 

tool: D69: difference: 

tool: D28: quotient: 

tool: D30: remainder: 

assistant: ```c
int main() {
  int integerA = 0;
  int integerB = 0;
  puts("Input two integers");
  printf("%s", "Give the First integer: ");
  scanf("%d", &integerA);
  printf("%s", "Give the Second integer: ");
  scanf("%d", &integerB);
  printf("%s %d \n", "sum: ", (integerA + integerB));
  printf("%s %d \n", "product: ", (integerA * integerB));
  printf("%s %d \n", "difference: ", (integerA - integerB));
  printf("%s %d \n", "quotient: ", (integerA / integerB));
  printf("%s %d \n", "remainder: ", (integerA % integerB));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D89(%rip),%rdi
  lea    D77(%rip),%r12
  push   %rbp
  lea    D49(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    D10(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  lea    D107(%rip),%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    %rbp,%rdi
  add    (%rsp),%edx
  lea    D38(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  imul   0x4(%rsp),%edx
  mov    %rbp,%rdi
  lea    D48(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  mov    %rbp,%rdi
  sub    0x4(%rsp),%edx
  lea    D43(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    D60(%rip),%rsi
  mov    %rbp,%rdi
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    D106(%rip),%rsi
  mov    %rbp,%rdi
  cltd
  idivl  0x4(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D89
type_guessed: string
name: unpack_data
arguments: label: D77
type_guessed: string
name: unpack_data
arguments: label: D49
type_guessed: string
name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D21
type_guessed: string
name: unpack_data
arguments: label: D107
type_guessed: string
name: unpack_data
arguments: label: D38
type_guessed: string
name: unpack_data
arguments: label: D48
type_guessed: string
name: unpack_data
arguments: label: D43
type_guessed: string
name: unpack_data
arguments: label: D60
type_guessed: string
name: unpack_data
arguments: label: D106
type_guessed: string

tool: D89: Input two integers

tool: D77: %s

tool: D49: %d

tool: D10: Give the First integer: 

tool: D21: Give the Second integer: 

tool: D107: %s %d 


tool: D38: sum: 

tool: D48: product: 

tool: D43: difference: 

tool: D60: quotient: 

tool: D106: remainder: 

assistant: ```c
int main() {
  int integerA = 0;
  int integerB = 0;
  puts("Input two integers");
  printf("%s", "Give the First integer: ");
  scanf("%d", &integerA);
  printf("%s", "Give the Second integer: ");
  scanf("%d", &integerB);
  printf("%s %d \n", "sum: ", (integerA + integerB));
  printf("%s %d \n", "product: ", (integerA * integerB));
  printf("%s %d \n", "difference: ", (integerA - integerB));
  printf("%s %d \n", "quotient: ", (integerA / integerB));
  printf("%s %d \n", "remainder: ", (integerA % integerB));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D101(%rip),%rdi
  lea    D36(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    D17(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    D73(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  lea    D56(%rip),%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    %rbp,%rdi
  add    (%rsp),%edx
  lea    D96(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  imul   0x4(%rsp),%edx
  mov    %rbp,%rdi
  lea    D71(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  mov    %rbp,%rdi
  sub    0x4(%rsp),%edx
  lea    D13(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    D50(%rip),%rsi
  mov    %rbp,%rdi
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    D51(%rip),%rsi
  mov    %rbp,%rdi
  cltd
  idivl  0x4(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D101
type: string
name: read_data
arguments: data_label: D36
type: string
name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D17
type: string
name: read_data
arguments: data_label: D73
type: string
name: read_data
arguments: data_label: D56
type: string
name: read_data
arguments: data_label: D96
type: string
name: read_data
arguments: data_label: D71
type: string
name: read_data
arguments: data_label: D13
type: string
name: read_data
arguments: data_label: D50
type: string
name: read_data
arguments: data_label: D51
type: string

tool: D101: Input two integers

tool: D36: %s

tool: D16: %d

tool: D17: Give the First integer: 

tool: D73: Give the Second integer: 

tool: D56: %s %d 


tool: D96: sum: 

tool: D71: product: 

tool: D13: difference: 

tool: D50: quotient: 

tool: D51: remainder: 

assistant: ```c
int main() {
  int integerA = 0;
  int integerB = 0;
  puts("Input two integers");
  printf("%s", "Give the First integer: ");
  scanf("%d", &integerA);
  printf("%s", "Give the Second integer: ");
  scanf("%d", &integerB);
  printf("%s %d \n", "sum: ", (integerA + integerB));
  printf("%s %d \n", "product: ", (integerA * integerB));
  printf("%s %d \n", "difference: ", (integerA - integerB));
  printf("%s %d \n", "quotient: ", (integerA / integerB));
  printf("%s %d \n", "remainder: ", (integerA % integerB));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CG_StartMusic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x2,%edi
  call   <CG_ConfigString@plt>
  mov    %rax,-0x98(%rbp)
  lea    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <COM_Parse@plt>
  mov    %eax,%ecx
  lea    -0x90(%rbp),%rax
  mov    $0x40,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Q_strncpyz@plt>
  lea    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <COM_Parse@plt>
  mov    %eax,%ecx
  lea    -0x50(%rbp),%rax
  mov    $0x40,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Q_strncpyz@plt>
  lea    -0x90(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L8
  lea    -0x50(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <trap_S_StartBackgroundTrack@plt>
L8:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void CG_StartMusic(void) {
  char *s;
  char parm1[64], parm2[64];
  s = (char *)CG_ConfigString(2);
  Q_strncpyz(parm1, COM_Parse(&s), sizeof(parm1));
  Q_strncpyz(parm2, COM_Parse(&s), sizeof(parm2));
  if (strlen(parm1)) {
    trap_S_StartBackgroundTrack(parm1, parm2);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CG_StartMusic>:
  endbr64
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    $0x2,%edi
  call   <CG_ConfigString@plt>
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rbx
  mov    %rbx,%rdi
  call   <COM_Parse@plt>
  mov    %eax,%esi
  lea    0x10(%rsp),%rdi
  mov    $0x40,%edx
  call   <Q_strncpyz@plt>
  mov    %rbx,%rdi
  call   <COM_Parse@plt>
  mov    %eax,%esi
  lea    0x50(%rsp),%rdi
  mov    $0x40,%edx
  call   <Q_strncpyz@plt>
  cmpb   $0x0,0x10(%rsp)
  jne    L7
L3:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0xa0,%rsp
  pop    %rbx
  ret
L7:
  lea    0x50(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <trap_S_StartBackgroundTrack@plt>
  jmp    L3
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CG_StartMusic(void) {
  char *s;
  char parm1[64], parm2[64];
  s = (char *)CG_ConfigString(2);
  Q_strncpyz(parm1, COM_Parse(&s), sizeof(parm1));
  Q_strncpyz(parm2, COM_Parse(&s), sizeof(parm2));
  if (strlen(parm1)) {
    trap_S_StartBackgroundTrack(parm1, parm2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CG_StartMusic>:
  endbr64
  push   %r12
  mov    $0x2,%edi
  push   %rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r12
  call   <CG_ConfigString@plt>
  mov    %rbp,%rdi
  mov    %rax,0x8(%rsp)
  call   <COM_Parse@plt>
  mov    $0x40,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <Q_strncpyz@plt>
  mov    %rbp,%rdi
  lea    0x50(%rsp),%rbp
  call   <COM_Parse@plt>
  mov    $0x40,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <Q_strncpyz@plt>
  cmpb   $0x0,0x10(%rsp)
  jne    L26
L10:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0xa8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <trap_S_StartBackgroundTrack@plt>
  jmp    L10
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CG_StartMusic(void) {
  char *s;
  char parm1[64], parm2[64];
  s = (char *)CG_ConfigString(2);
  Q_strncpyz(parm1, COM_Parse(&s), sizeof(parm1));
  Q_strncpyz(parm2, COM_Parse(&s), sizeof(parm2));
  if (strlen(parm1)) {
    trap_S_StartBackgroundTrack(parm1, parm2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CG_StartMusic>:
  endbr64
  push   %r12
  mov    $0x2,%edi
  push   %rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r12
  call   <CG_ConfigString@plt>
  mov    %rbp,%rdi
  mov    %rax,0x8(%rsp)
  call   <COM_Parse@plt>
  mov    $0x40,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <Q_strncpyz@plt>
  mov    %rbp,%rdi
  lea    0x50(%rsp),%rbp
  call   <COM_Parse@plt>
  mov    $0x40,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <Q_strncpyz@plt>
  cmpb   $0x0,0x10(%rsp)
  jne    L23
L28:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xa8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <trap_S_StartBackgroundTrack@plt>
  jmp    L28
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CG_StartMusic(void) {
  char *s;
  char parm1[64], parm2[64];
  s = (char *)CG_ConfigString(2);
  Q_strncpyz(parm1, COM_Parse(&s), sizeof(parm1));
  Q_strncpyz(parm2, COM_Parse(&s), sizeof(parm2));
  if (strlen(parm1)) {
    trap_S_StartBackgroundTrack(parm1, parm2);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<UARTIntEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0xbf,%esi
  mov    %eax,%edi
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  and    $0x10,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  add    $0x8,%edx
  mov    %edx,%edx
  or     $0x10,%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  mov    $0x7f,%esi
  mov    %eax,%edi
  call   <UARTRegConfigModeEnable@plt>
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%eax
  and    $0xf0,%eax
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  or     %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  mov    $0xbf,%esi
  mov    %eax,%edi
  call   <UARTRegConfigModeEnable@plt>
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  add    $0x8,%edx
  mov    %edx,%edx
  and    $0xffffffef,%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  add    $0x8,%edx
  mov    %edx,%edx
  or     -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  or     %esi,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void UARTIntEnable(unsigned int baseAdd, unsigned int intFlag) {
  unsigned int enhanFnBitVal = 0;
  unsigned int lcrRegValue = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x00BF));
  enhanFnBitVal = (*((volatile unsigned int *)(baseAdd + (0x8)))) & (0x00000010u);
  (*((volatile unsigned int *)(baseAdd + (0x8)))) |= (0x00000010u);
  UARTRegConfigModeEnable(baseAdd, (0x007F));
  (*((volatile unsigned int *)(baseAdd + (0x4)))) |= (intFlag & 0xF0);
  UARTRegConfigModeEnable(baseAdd, (0x00BF));
  (*((volatile unsigned int *)(baseAdd + (0x8)))) &= ~((0x00000010u));
  (*((volatile unsigned int *)(baseAdd + (0x8)))) |= enhanFnBitVal;
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  (*((volatile unsigned int *)(baseAdd + (0x4)))) |= (intFlag & 0x0F);
}
```