ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_trans_len>:
  endbr64
  test   $0x3f,%dil
  jne    L3
  mov    $0x40,%edi
  jmp    1050 <min@plt>
  nopl   0x0(%rax)
L3:
  lea    0x3f(%rdi),%r8d
  and    $0xffffffc0,%r8d
  sub    %edi,%r8d
  mov    %r8d,%edi
  jmp    1050 <min@plt>
```

assistant: ```c
int get_trans_len(uint32_t offset, uint32_t len) {
  if (!(0 == ((offset) & (64 - 1)))) {
    return min((((offset) + (64 - 1)) & ~(64 - 1)) - offset, len);
  }
  return min(64, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<change_bit_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L21:
  mov    -0x4(%rbp),%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L20
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <set_bit@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L10
L20:
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <clear_bit@plt>
  mov    %eax,-0x14(%rbp)
L10:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L21
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t change_bit_val(uint32_t reg_val, uint32_t new_val, int bit, int bit_size) {
  int i;
  for (i = 0; i < bit_size; i++) {
    if (new_val & (uint32_t)(1 << i))
      reg_val = set_bit(reg_val, bit - i);
    else
      reg_val = clear_bit(reg_val, bit - i);
  }
  return reg_val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<change_bit_val>:
  endbr64
  test   %ecx,%ecx
  jle    L34
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %edx,%r13d
  sub    %ecx,%r13d
  mov    %edx,%ebx
  jmp    L45
L31:
  mov    %ebx,%esi
  call   <clear_bit@plt>
  mov    %eax,%edi
L11:
  sub    $0x1,%ebx
  cmp    %r13d,%ebx
  je     L21
L45:
  mov    %ebp,%eax
  sub    %ebx,%eax
  bt     %eax,%r12d
  jae    L31
  mov    %ebx,%esi
  call   <set_bit@plt>
  mov    %eax,%edi
  jmp    L11
L21:
  mov    %edi,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t change_bit_val(uint32_t reg_val, uint32_t new_val, int bit, int bit_size) {
  int i;
  for (i = 0; i < bit_size; i++) {
    if (new_val & (uint32_t)(1 << i))
      reg_val = set_bit(reg_val, bit - i);
    else
      reg_val = clear_bit(reg_val, bit - i);
  }
  return reg_val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<change_bit_val>:
  endbr64
  test   %ecx,%ecx
  jle    L35
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L19
  xchg   %ax,%ax
L49:
  call   <set_bit@plt>
  add    $0x1,%ebx
  mov    %eax,%edi
  cmp    %ebx,%ebp
  je     L8
L19:
  mov    %r13d,%esi
  sub    %ebx,%esi
  bt     %ebx,%r12d
  jb     L49
  call   <clear_bit@plt>
  add    $0x1,%ebx
  mov    %eax,%edi
  cmp    %ebx,%ebp
  jne    L19
L8:
  add    $0x8,%rsp
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L35:
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t change_bit_val(uint32_t reg_val, uint32_t new_val, int bit, int bit_size) {
  int i;
  for (i = 0; i < bit_size; i++) {
    if (new_val & (uint32_t)(1 << i))
      reg_val = set_bit(reg_val, bit - i);
    else
      reg_val = clear_bit(reg_val, bit - i);
  }
  return reg_val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<change_bit_val>:
  endbr64
  test   %ecx,%ecx
  jle    L16
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L37
  xchg   %ax,%ax
L23:
  call   <set_bit@plt>
  add    $0x1,%ebx
  mov    %eax,%edi
  cmp    %ebx,%ebp
  je     L11
L37:
  mov    %r13d,%esi
  sub    %ebx,%esi
  bt     %ebx,%r12d
  jb     L23
  call   <clear_bit@plt>
  add    $0x1,%ebx
  mov    %eax,%edi
  cmp    %ebx,%ebp
  jne    L37
L11:
  add    $0x8,%rsp
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L16:
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t change_bit_val(uint32_t reg_val, uint32_t new_val, int bit, int bit_size) {
  int i;
  for (i = 0; i < bit_size; i++) {
    if (new_val & (uint32_t)(1 << i))
      reg_val = set_bit(reg_val, bit - i);
    else
      reg_val = clear_bit(reg_val, bit - i);
  }
  return reg_val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %ax,-0x38(%rbp)
  mov    %edx,%eax
  mov    %al,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  cmpw   $0x24,-0x38(%rbp)
  ja     L17
  cmpw   $0x1,-0x38(%rbp)
  ja     L100
L17:
  mov    $0x0,%eax
  jmp    L72
L100:
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L42
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x2d,(%rax)
L42:
  cmpl   $0x9,-0x34(%rbp)
  jg     L98
  cmpb   $0x0,-0x44(%rbp)
  je     L98
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x30,(%rax)
  jmp    L98
L22:
  movzwl -0x38(%rbp),%ecx
  mov    -0x34(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0x2c(%rbp)
  movzwl -0x38(%rbp),%esi
  mov    -0x34(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,-0x34(%rbp)
  cmpl   $0x9,-0x2c(%rbp)
  jg     L74
  mov    -0x2c(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L98
L74:
  mov    -0x2c(%rbp),%eax
  lea    0x57(%rax),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L98:
  cmpl   $0x0,-0x34(%rbp)
  jne    L22
  lea    -0x14(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  je     L22
  jmp    L30
L106:
  subq   $0x1,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x28(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L30:
  lea    -0x14(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  ja     L106
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
L72:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
char *itoa(signed int value, char *string, unsigned short radix, unsigned char pad) {
  char tmp[12];
  char *tp = tmp;
  int i;
  char *sp;
  if (radix > 36 || radix <= 1) {
    return 0;
  }
  sp = string;
  if (value < 0) {
    *sp++ = '-';
  }
  if ((value < 10) && pad) {
    *sp++ = '0';
  }
  while (value || tp == tmp) {
    i = value % radix;
    value = value / radix;
    if (i < 10) {
      *tp++ = i + '0';
    } else {
      *tp++ = i + 'a' - 10;
    }
  }
  while (tp > tmp) {
    *sp++ = *--tp;
  }
  *sp = 0;
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<itoa>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%r9
  mov    %edx,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  sub    $0x2,%edx
  cmp    $0x22,%dx
  ja     L115
  mov    %r9,%r10
  test   %edi,%edi
  js     L22
L58:
  cmp    $0x9,%edi
  jg     L78
  test   %cl,%cl
  je     L78
  movb   $0x30,(%r10)
  lea    0x1(%r10),%r10
L78:
  lea    0xd(%rsp),%rcx
  movzwl %si,%esi
  lea    0xc(%rsp),%r11
L38:
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%edi
  cmp    $0x9,%edx
  jg     L16
  mov    %rcx,%r8
  add    $0x30,%edx
L7:
  mov    %dl,-0x1(%rcx)
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L38
  cmp    %r11,%r8
  je     L38
  lea    0xc(%rsp),%rax
  cmp    %rax,%r8
  jbe    L26
  mov    %r10,%rdx
  mov    %r8,%rax
  lea    0xc(%rsp),%rsi
L4:
  sub    $0x1,%rax
  add    $0x1,%rdx
  movzbl (%rax),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rax
  jne    L4
  lea    0x20(%rsp),%rax
  sub    %rax,%r8
  lea    0x14(%r8,%r10,1),%r10
L26:
  movb   $0x0,(%r10)
  mov    %r9,%rax
L113:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L102
  add    $0x28,%rsp
  ret
L22:
  lea    0x1(%r9),%r10
  movb   $0x2d,(%r9)
  jmp    L58
L16:
  mov    %rcx,%r8
  add    $0x57,%edx
  jmp    L7
L115:
  mov    $0x0,%eax
  jmp    L113
L102:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *itoa(signed int value, char *string, unsigned short radix, unsigned char pad) {
  char tmp[12];
  char *tp = tmp;
  int i;
  char *sp;
  if (radix > 36 || radix <= 1) {
    return 0;
  }
  sp = string;
  if (value < 0) {
    *sp++ = '-';
  }
  if ((value < 10) && pad) {
    *sp++ = '0';
  }
  while (value || tp == tmp) {
    i = value % radix;
    value = value / radix;
    if (i < 10) {
      *tp++ = i + '0';
    } else {
      *tp++ = i + 'a' - 10;
    }
  }
  while (tp > tmp) {
    *sp++ = *--tp;
  }
  *sp = 0;
  return string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itoa>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%r9
  mov    %fs:0x28,%rsi
  mov    %rsi,0x18(%rsp)
  xor    %esi,%esi
  lea    -0x2(%rdx),%esi
  cmp    $0x22,%si
  ja     L91
  mov    %edi,%eax
  mov    %r9,%r11
  test   %edi,%edi
  js     L50
L67:
  cmp    $0x9,%eax
  jg     L61
  test   %cl,%cl
  je     L61
  movb   $0x30,(%r11)
  add    $0x1,%r11
L61:
  lea    0xc(%rsp),%r10
  movzwl %dx,%edi
  mov    %r10,%rsi
  nopl   0x0(%rax)
L96:
  cltd
  add    $0x1,%rsi
  idiv   %edi
  lea    0x30(%rdx),%r8d
  lea    0x57(%rdx),%ecx
  cmp    $0x9,%edx
  mov    %r8d,%edx
  cmovg  %ecx,%edx
  mov    %dl,-0x1(%rsi)
  cmp    %r10,%rsi
  je     L96
  test   %eax,%eax
  jne    L96
  cmp    %r10,%rsi
  jbe    L86
  mov    %r11,%rcx
  mov    %rsi,%rax
  jmp    L81
  nopl   0x0(%rax,%rax,1)
L102:
  movzbl -0x1(%rax),%edx
L81:
  sub    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  cmp    %r10,%rax
  jne    L102
  sub    %rax,%rsi
  add    %rsi,%r11
L86:
  movb   $0x0,(%r11)
  mov    %r9,%rax
L23:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L110
  add    $0x28,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L50:
  movb   $0x2d,(%r9)
  lea    0x1(%r9),%r11
  jmp    L67
  nopl   (%rax)
L91:
  xor    %eax,%eax
  jmp    L23
L110:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *itoa(signed int value, char *string, unsigned short radix, unsigned char pad) {
  char tmp[12];
  char *tp = tmp;
  int i;
  char *sp;
  if (radix > 36 || radix <= 1) {
    return 0;
  }
  sp = string;
  if (value < 0) {
    *sp++ = '-';
  }
  if ((value < 10) && pad) {
    *sp++ = '0';
  }
  while (value || tp == tmp) {
    i = value % radix;
    value = value / radix;
    if (i < 10) {
      *tp++ = i + '0';
    } else {
      *tp++ = i + 'a' - 10;
    }
  }
  while (tp > tmp) {
    *sp++ = *--tp;
  }
  *sp = 0;
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<itoa>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%eax
  mov    %rsi,%rdi
  mov    %fs:0x28,%rsi
  mov    %rsi,0x18(%rsp)
  xor    %esi,%esi
  lea    -0x2(%rdx),%esi
  cmp    $0x22,%si
  ja     L54
  mov    %rdi,%r9
  test   %eax,%eax
  js     L136
L66:
  cmp    $0x9,%eax
  jg     L127
  test   %cl,%cl
  je     L127
  movb   $0x30,(%r9)
  add    $0x1,%r9
L127:
  lea    0xc(%rsp),%r8
  movzwl %dx,%esi
  mov    %r8,%rcx
  nopl   0x0(%rax)
L9:
  cltd
  add    $0x1,%rcx
  idiv   %esi
  cmp    $0x9,%edx
  jg     L55
  add    $0x30,%edx
  mov    %dl,-0x1(%rcx)
  test   %eax,%eax
  jne    L9
  cmp    %r8,%rcx
  je     L9
L27:
  cmp    %r8,%rcx
  jbe    L44
  mov    %r9,%rdx
  mov    %rcx,%rax
  xchg   %ax,%ax
L101:
  movzbl -0x1(%rax),%esi
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  cmp    %r8,%rax
  jne    L101
  sub    %rax,%rcx
  add    %rcx,%r9
L44:
  movb   $0x0,(%r9)
  mov    %rdi,%rax
L52:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  add    $0x57,%edx
  mov    %dl,-0x1(%rcx)
  cmp    %r8,%rcx
  je     L9
  test   %eax,%eax
  jne    L9
  jmp    L27
  nopl   0x0(%rax)
L136:
  movb   $0x2d,(%rdi)
  lea    0x1(%rdi),%r9
  jmp    L66
  nopl   0x0(%rax)
L54:
  xor    %eax,%eax
  jmp    L52
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *itoa(signed int value, char *string, unsigned short radix, unsigned char pad) {
  char tmp[12];
  char *tp = tmp;
  int i;
  char *sp;
  if (radix > 36 || radix <= 1) {
    return 0;
  }
  sp = string;
  if (value < 0) {
    *sp++ = '-';
  }
  if ((value < 10) && pad) {
    *sp++ = '0';
  }
  while (value || tp == tmp) {
    i = value % radix;
    value = value / radix;
    if (i < 10) {
      *tp++ = i + '0';
    } else {
      *tp++ = i + 'a' - 10;
    }
  }
  while (tp > tmp) {
    *sp++ = *--tp;
  }
  *sp = 0;
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x400,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    D37(%rip),%rdx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <set_value@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L32
L14:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L32:
  cmpl   $0x9,-0x14(%rbp)
  jle    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xc(%rbp),%eax
  sub    $0xa,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L86
L22:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L86:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L22
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L27
L11:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  D3(%rip),%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jle    L62
  movl   $0x1,-0x10(%rbp)
L62:
  addl   $0x1,-0x14(%rbp)
L27:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L11
  cmpl   $0x0,-0x10(%rbp)
  je     L81
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L84
L81:
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L84:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D37
data_type: f64
name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D3
data_type: byte[4]
name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D49
data_type: string

tool: D37: 11

tool: D15: %f	

tool: {"D3": [0x00,0x00,0x30,0x41]}

tool: D13: FAILED !!

tool: D49: PASSED !!

assistant: ```c
int main() {
  int i, failed = 0;
  int N = 1024;
  float *ptr;
  ptr = malloc(sizeof(float) * N);
  set_value(ptr, 11.0, N);
  for (i = 0; i < 10; i++)
    printf("%f\t", ptr[i]);
  printf("\n");
  for (i = N - 10; i < N; i++)
    printf("%f\t", ptr[i]);
  printf("\n");
  for (i = 0; i < N; i++) {
    if (fabs(ptr[i] - 11.0) > 1e-8) {
      failed = 1;
    }
  }
  if (failed) {
    printf("FAILED !!\n");
  } else {
    printf("PASSED !!\n");
  }
  free(ptr);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x400,%esi
  movsd  D28(%rip),%xmm0
  mov    %rax,%rdi
  call   <set_value@plt>
  mov    %r13,%rbx
  lea    0x28(%r13),%r14
  mov    %r13,%rbp
  lea    D18(%rip),%r12
L33:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r14,%rbp
  jne    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0xfd8(%r13),%rbp
  lea    0x1000(%r13),%r12
  lea    D18(%rip),%r14
L47:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L47
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebp
L8:
  movss  (%rbx),%xmm0
  subss  D10(%rip),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  mov    $0x1,%eax
  cmovg  %eax,%ebp
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L8
  test   %ebp,%ebp
  je     L43
  lea    D26(%rip),%rdi
  call   <puts@plt>
L18:
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  lea    D45(%rip),%rdi
  call   <puts@plt>
  jmp    L18
```

tool_calls: name: read_data
arguments: data_tag: D28
datatype: f64
name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D10
datatype: byte[4]
name: read_data
arguments: data_tag: D26
datatype: string
name: read_data
arguments: data_tag: D45
datatype: string

tool: D28: 11

tool: D18: %f	

tool: {"D10": [0x00,0x00,0x30,0x41]}

tool: D26: FAILED !!

tool: D45: PASSED !!

assistant: ```c
int main() {
  int i, failed = 0;
  int N = 1024;
  float *ptr;
  ptr = malloc(sizeof(float) * N);
  set_value(ptr, 11.0, N);
  for (i = 0; i < 10; i++)
    printf("%f\t", ptr[i]);
  printf("\n");
  for (i = N - 10; i < N; i++)
    printf("%f\t", ptr[i]);
  printf("\n");
  for (i = 0; i < N; i++) {
    if (fabs(ptr[i] - 11.0) > 1e-8) {
      failed = 1;
    }
  }
  if (failed) {
    printf("FAILED !!\n");
  } else {
    printf("PASSED !!\n");
  }
  free(ptr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1000,%edi
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  movsd  D48(%rip),%xmm0
  mov    $0x400,%esi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <set_value@plt>
  mov    %r14,%rbx
  lea    0x28(%r14),%r12
  mov    %r14,%rbp
  nop
L20:
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbp
  cvtss2sd -0x4(%rbp),%xmm0
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L20
  mov    $0xa,%edi
  lea    0xfd8(%r14),%rbp
  lea    0x1000(%r14),%r12
  call   <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbp
  cvtss2sd -0x4(%rbp),%xmm0
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L10
  mov    $0xa,%edi
  xor    %ebp,%ebp
  mov    $0x1,%r13d
  call   <putchar@plt>
  nopl   0x0(%rax)
L19:
  movss  (%rbx),%xmm0
  subss  D37(%rip),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  cmovg  %r13d,%ebp
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L19
  test   %ebp,%ebp
  je     L43
  lea    D36(%rip),%rdi
  call   <puts@plt>
L1:
  mov    %r14,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  lea    D47(%rip),%rdi
  call   <puts@plt>
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
datatype: string
name: extract_symbolic_data
arguments: tag: D48
datatype: f64
name: extract_symbolic_data
arguments: tag: D37
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D36
datatype: string
name: extract_symbolic_data
arguments: tag: D47
datatype: string

tool: D25: %f	

tool: D48: 11

tool: {"D37": [0x00,0x00,0x30,0x41]}

tool: D36: FAILED !!

tool: D47: PASSED !!

assistant: ```c
int main() {
  int i, failed = 0;
  int N = 1024;
  float *ptr;
  ptr = malloc(sizeof(float) * N);
  set_value(ptr, 11.0, N);
  for (i = 0; i < 10; i++)
    printf("%f\t", ptr[i]);
  printf("\n");
  for (i = N - 10; i < N; i++)
    printf("%f\t", ptr[i]);
  printf("\n");
  for (i = 0; i < N; i++) {
    if (fabs(ptr[i] - 11.0) > 1e-8) {
      failed = 1;
    }
  }
  if (failed) {
    printf("FAILED !!\n");
  } else {
    printf("PASSED !!\n");
  }
  free(ptr);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1000,%edi
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  movsd  D11(%rip),%xmm0
  mov    $0x400,%esi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <set_value@plt>
  mov    %r14,%rbx
  lea    0x28(%r14),%r12
  mov    %r14,%rbp
  nop
L7:
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbp
  cvtss2sd -0x4(%rbp),%xmm0
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L7
  mov    $0xa,%edi
  lea    0xfd8(%r14),%rbp
  lea    0x1000(%r14),%r12
  call   <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbp
  cvtss2sd -0x4(%rbp),%xmm0
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L26
  mov    $0xa,%edi
  xor    %ebp,%ebp
  mov    $0x1,%r13d
  call   <putchar@plt>
  nopl   0x0(%rax)
L32:
  movss  (%rbx),%xmm0
  subss  D41(%rip),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  cmovg  %r13d,%ebp
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L32
  test   %ebp,%ebp
  je     L15
  lea    D8(%rip),%rdi
  call   <puts@plt>
L0:
  mov    %r14,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: f64
name: retrieve_data
arguments: data_tag: D41
data_type: byte[4]
name: retrieve_data
arguments: data_tag: D8
data_type: string
name: retrieve_data
arguments: data_tag: D15
data_type: string

tool: D22: %f	

tool: D11: 11

tool: {"D41": [0x00,0x00,0x30,0x41]}

tool: D8: FAILED !!

tool: D15: PASSED !!

assistant: ```c
int main() {
  int i, failed = 0;
  int N = 1024;
  float *ptr;
  ptr = malloc(sizeof(float) * N);
  set_value(ptr, 11.0, N);
  for (i = 0; i < 10; i++)
    printf("%f\t", ptr[i]);
  printf("\n");
  for (i = N - 10; i < N; i++)
    printf("%f\t", ptr[i]);
  printf("\n");
  for (i = 0; i < N; i++) {
    if (fabs(ptr[i] - 11.0) > 1e-8) {
      failed = 1;
    }
  }
  if (failed) {
    printf("FAILED !!\n");
  } else {
    printf("PASSED !!\n");
  }
  free(ptr);
}
```