ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<mergesort>:
  endbr64
  cmp    %esi,%edi
  jl     L41
  ret
  nopl   0x0(%rax)
L41:
  lea    (%rdi,%rsi,1),%eax
  push   %r15
  push   %r14
  push   %r13
  mov    %eax,%r13d
  push   %r12
  shr    $0x1f,%r13d
  mov    %esi,%r12d
  push   %rbp
  add    %eax,%r13d
  mov    %edi,%ebp
  push   %rbx
  sar    %r13d
  sub    $0x18,%rsp
  cmp    %r13d,%edi
  jl     L83
  lea    0x1(%r13),%r14d
  cmp    %r12d,%r14d
  jl     L36
L17:
  add    $0x18,%rsp
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <merge@plt>
  nopl   0x0(%rax)
L83:
  lea    (%rdi,%r13,1),%eax
  mov    %eax,%r14d
  shr    $0x1f,%r14d
  add    %eax,%r14d
  sar    %r14d
  cmp    %r14d,%edi
  jl     L8
L9:
  lea    0x1(%r14),%r15d
  cmp    %r15d,%r13d
  jg     L18
L85:
  mov    %r14d,%esi
  mov    %r13d,%edx
  lea    0x1(%r13),%r14d
  mov    %ebp,%edi
  call   <merge@plt>
  cmp    %r12d,%r14d
  jge    L17
L36:
  lea    (%r14,%r12,1),%eax
  mov    %eax,%r15d
  shr    $0x1f,%r15d
  add    %eax,%r15d
  sar    %r15d
  cmp    %r15d,%r14d
  jl     L70
L22:
  lea    0x1(%r15),%ebx
  cmp    %ebx,%r12d
  jg     L125
L3:
  mov    %r12d,%edx
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <merge@plt>
  jmp    L17
  nop
L8:
  lea    (%rdi,%r14,1),%eax
  mov    %eax,%r15d
  shr    $0x1f,%r15d
  add    %eax,%r15d
  sar    %r15d
  mov    %r15d,%esi
  call   <mergesort>
  lea    0x1(%r15),%edi
  mov    %r14d,%esi
  call   <mergesort>
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <merge@plt>
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L125:
  lea    (%r12,%rbx,1),%eax
  mov    %ebx,%edi
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  mov    %r8d,%esi
  mov    %r8d,0xc(%rsp)
  call   <mergesort>
  mov    0xc(%rsp),%r8d
  mov    %r12d,%esi
  lea    0x1(%r8),%edi
  call   <mergesort>
  mov    0xc(%rsp),%esi
  mov    %r12d,%edx
  mov    %ebx,%edi
  call   <merge@plt>
  jmp    L3
  nopl   0x0(%rax)
L70:
  lea    (%r14,%r15,1),%eax
  mov    %r14d,%edi
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,%esi
  call   <mergesort>
  lea    0x1(%rbx),%edi
  mov    %r15d,%esi
  call   <mergesort>
  mov    %r15d,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <merge@plt>
  jmp    L22
  nopl   0x0(%rax)
L18:
  lea    0x0(%r13,%r15,1),%eax
  mov    %r15d,%edi
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,%esi
  call   <mergesort>
  lea    0x1(%rbx),%edi
  mov    %r13d,%esi
  call   <mergesort>
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r15d,%edi
  call   <merge@plt>
  jmp    L85
```

assistant: ```c
void mergesort(int low, int high) {
  int mid;
  if (low < high) {
    mid = (low + high) / 2;
#pragma omp task
    { mergesort(low, mid); }
#pragma omp task
    { mergesort(mid + 1, high); }
    merge(low, mid, high);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rcu_read_lock_bh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <__rcu_read_lock_bh@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rcu_read_lock_bh(void) {
  __rcu_read_lock_bh();
  (void)0;
  do {
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rcu_read_lock_bh>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__rcu_read_lock_bh@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void rcu_read_lock_bh(void) {
  __rcu_read_lock_bh();
  (void)0;
  do {
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rcu_read_lock_bh>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <__rcu_read_lock_bh@plt>
```

assistant: ```c
void rcu_read_lock_bh(void) {
  __rcu_read_lock_bh();
  (void)0;
  do {
  } while (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rcu_read_lock_bh>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <__rcu_read_lock_bh@plt>
```

assistant: ```c
void rcu_read_lock_bh(void) {
  __rcu_read_lock_bh();
  (void)0;
  do {
  } while (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<iov_byte_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L18:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L18
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t iov_byte_length(struct iovec *iov, size_t iov_len) {
  size_t len = 0;
  size_t i;
  for (i = 0; i < iov_len; ++i)
    len += iov[i].iov_len;
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<iov_byte_length>:
  endbr64
  test   %rsi,%rsi
  je     L11
  mov    %rdi,%rdx
  lea    (%rdi,%rsi,8),%rcx
  mov    $0x0,%eax
L16:
  add    (%rdx),%rax
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L16
  ret
L11:
  mov    %rsi,%rax
  ret
```

assistant: ```c
size_t iov_byte_length(struct iovec *iov, size_t iov_len) {
  size_t len = 0;
  size_t i;
  for (i = 0; i < iov_len; ++i)
    len += iov[i].iov_len;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<iov_byte_length>:
  endbr64
  test   %rsi,%rsi
  je     L10
  lea    (%rdi,%rsi,8),%rdx
  xor    %eax,%eax
  nop
L13:
  add    (%rdi),%rax
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L13
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t iov_byte_length(struct iovec *iov, size_t iov_len) {
  size_t len = 0;
  size_t i;
  for (i = 0; i < iov_len; ++i)
    len += iov[i].iov_len;
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<iov_byte_length>:
  endbr64
  test   %rsi,%rsi
  je     L34
  cmp    $0x1,%rsi
  je     L16
  mov    %rsi,%rdx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L14:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddq  %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L14
  movdqa %xmm0,%xmm1
  mov    %rsi,%rdx
  psrldq $0x8,%xmm1
  and    $0xfffffffffffffffe,%rdx
  and    $0x1,%esi
  paddq  %xmm1,%xmm0
  movq   %xmm0,%rax
  je     L39
L41:
  add    (%rdi,%rdx,8),%rax
  ret
  nopl   0x0(%rax)
L39:
  ret
  nopl   0x0(%rax)
L34:
  xor    %eax,%eax
  ret
L16:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L41
```

assistant: ```c
size_t iov_byte_length(struct iovec *iov, size_t iov_len) {
  size_t len = 0;
  size_t i;
  for (i = 0; i < iov_len; ++i)
    len += iov[i].iov_len;
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L14
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L16
L14:
  mov    $0x0,%eax
L16:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string
name: read_data
arguments: data_label: D10
type_infered: string

tool: D6: write_entry

tool: D10: ERROR: %s: write returned %i


assistant: ```c
int write_entry(int fd, char *buf, int len) {
  int ret;
  do {
  } while (0);
  ret = write(fd, buf, len);
  if (ret != len) {
    printf("ERROR: %s: write returned %i\n", __func__, ret);
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_entry>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  mov    $0x0,%eax
  call   <write@plt>
  cmp    %eax,%ebx
  jne    L13
  mov    $0x0,%eax
L14:
  pop    %rbx
  ret
L13:
  mov    %eax,%edx
  lea    D17(%rip),%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L14
```

tool_calls: name: unpack_data
arguments: data_tag: D17
datatype: string
name: unpack_data
arguments: data_tag: D12
datatype: string

tool: D17: write_entry

tool: D12: ERROR: %s: write returned %i


assistant: ```c
int write_entry(int fd, char *buf, int len) {
  int ret;
  do {
  } while (0);
  ret = write(fd, buf, len);
  if (ret != len) {
    printf("ERROR: %s: write returned %i\n", __func__, ret);
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<write_entry>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edx,%ebx
  call   <write@plt>
  cmp    %eax,%ebx
  jne    L7
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  mov    %eax,%edx
  lea    D6(%rip),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string

tool: D6: write_entry

tool: D19: ERROR: %s: write returned %i


assistant: ```c
int write_entry(int fd, char *buf, int len) {
  int ret;
  do {
  } while (0);
  ret = write(fd, buf, len);
  if (ret != len) {
    printf("ERROR: %s: write returned %i\n", __func__, ret);
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_entry>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edx,%ebx
  call   <write@plt>
  cmp    %eax,%ebx
  jne    L9
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  mov    %eax,%edx
  lea    D14(%rip),%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
data_type: string
name: parse_data
arguments: data_label: D11
data_type: string

tool: D14: write_entry

tool: D11: ERROR: %s: write returned %i


assistant: ```c
int write_entry(int fd, char *buf, int len) {
  int ret;
  do {
  } while (0);
  ret = write(fd, buf, len);
  if (ret != len) {
    printf("ERROR: %s: write returned %i\n", __func__, ret);
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quickLog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L11:
  addl   $0x1,-0x4(%rbp)
L19:
  shrl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L11
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned quickLog2(unsigned power_of_two) {
  unsigned res = 0;
  while (power_of_two >>= 1) {
    res++;
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quickLog2>:
  endbr64
  shr    %edi
  je     L19
  mov    $0x0,%eax
L0:
  add    $0x1,%eax
  shr    %edi
  jne    L0
  ret
L19:
  mov    %edi,%eax
  ret
```

assistant: ```c
unsigned quickLog2(unsigned power_of_two) {
  unsigned res = 0;
  while (power_of_two >>= 1) {
    res++;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quickLog2>:
  endbr64
  xor    %eax,%eax
  shr    %edi
  je     L10
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%eax
  shr    %edi
  jne    L11
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
unsigned quickLog2(unsigned power_of_two) {
  unsigned res = 0;
  while (power_of_two >>= 1) {
    res++;
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quickLog2>:
  endbr64
  xor    %eax,%eax
  shr    %edi
  je     L19
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%eax
  shr    %edi
  jne    L8
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
unsigned quickLog2(unsigned power_of_two) {
  unsigned res = 0;
  while (power_of_two >>= 1) {
    res++;
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L29
L17:
  mov    $0x0,%eax
  call   <test_case@plt>
L29:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: %d

assistant: ```c
int main() {
  int tc;
  scanf("%d", &tc);
  while (tc--)
    test_case();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L16
L10:
  mov    $0x0,%eax
  call   <test_case@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L10
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: %d

assistant: ```c
int main() {
  int tc;
  scanf("%d", &tc);
  while (tc--)
    test_case();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <test_case@plt>
L9:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main() {
  int tc;
  scanf("%d", &tc);
  while (tc--)
    test_case();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  call   <test_case@plt>
L9:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L21
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4: %d

assistant: ```c
int main() {
  int tc;
  scanf("%d", &tc);
  while (tc--)
    test_case();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CHEW>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L16:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x12,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x10000,%esi
  mov    %rcx,%rdi
  call   <CRUSH@plt>
  neg    %eax
  mov    %eax,%edi
  call   <expf@plt>
  add    $0x1,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  add    $0x10000,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    $0xffffffff,%esi
  mov    %eax,%edi
  call   <powf@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  mov    -0x14(%rbp),%eax
  add    $0x10000,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mov    -0x14(%rbp),%eax
  add    $0x10000,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movsd  D15(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  lea    0x180000(%rax),%rdx
  mov    -0x14(%rbp),%eax
  add    $0x32,%eax
  cvtsd2ss %xmm0,%xmm0
  cltq
  movss  %xmm0,(%rdx,%rax,4)
  addl   $0x1,-0x14(%rbp)
L12:
  cmpl   $0x5,-0x14(%rbp)
  jle    L16
  mov    -0x30(%rbp),%rax
  lea    0x180000(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    $0x40000,%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <CRUSH@plt>
  neg    %eax
  mov    %eax,%edi
  call   <expf@plt>
  lea    0x1(%rax),%ebx
  mov    $0x1,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  add    $0x180000,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  movss  %xmm0,0x144(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x180000,%rax
  movss  0x144(%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x180000,%rax
  movss  0x144(%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movsd  D15(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  add    $0x180000,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x148(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x180000,%rax
  movss  0x144(%rax),%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
datatype: f64

tool: D15: 1

assistant: ```c
float CHEW(float *GUT, float BONE[][1 << 16]) {
  int GRR;
  for (GRR = 0; GRR < 6; ++GRR) {
    GUT[GRR + 256 * 256] = powf(1 + expf(-CRUSH(BONE[GRR], 1 << 16, GUT)), -1);
    BONE[6][50 + GRR] = GUT[256 * 256 + GRR] * (1. - GUT[(8 << 13) + GRR]);
  }
  BONE[6][81] = 1 / (1 + expf(-CRUSH(GUT + (1 << 16), 6, BONE[6])));
  return BONE[6][82] = BONE[6][81] * (1. - BONE[6][81]), BONE[6][81];
}
```
user: What is the c source code of the assembly code below:

```asm
<CHEW>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L7:
  mov    %rbx,%rdi
  shl    $0x10,%rdi
  add    %rbp,%rdi
  mov    %r12,%rdx
  mov    $0x10000,%esi
  call   <CRUSH@plt>
  neg    %eax
  mov    %eax,%edi
  call   <expf@plt>
  lea    0x1(%rax),%edi
  mov    $0xffffffff,%esi
  call   <powf@plt>
  movss  %xmm0,0x40000(%r12,%rbx,1)
  cvtss2sd %xmm0,%xmm0
  movsd  D13(%rip),%xmm1
  subsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x1800c8(%rbp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x18,%rbx
  jne    L7
  lea    0x180000(%rbp),%rdx
  lea    0x40000(%r12),%rdi
  mov    $0x6,%esi
  call   <CRUSH@plt>
  neg    %eax
  mov    %eax,%edi
  call   <expf@plt>
  lea    0x1(%rax),%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x180144(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  movsd  D13(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x180148(%rbp)
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_guessed: f64

tool: D13: 1

assistant: ```c
float CHEW(float *GUT, float BONE[][1 << 16]) {
  int GRR;
  for (GRR = 0; GRR < 6; ++GRR) {
    GUT[GRR + 256 * 256] = powf(1 + expf(-CRUSH(BONE[GRR], 1 << 16, GUT)), -1);
    BONE[6][50 + GRR] = GUT[256 * 256 + GRR] * (1. - GUT[(8 << 13) + GRR]);
  }
  BONE[6][81] = 1 / (1 + expf(-CRUSH(GUT + (1 << 16), 6, BONE[6])));
  return BONE[6][82] = BONE[6][81] * (1. - BONE[6][81]), BONE[6][81];
}
```
user: What is the c source code of the assembly code below:

```asm
<CHEW>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L8:
  mov    %rbx,%rdi
  mov    %r12,%rdx
  mov    $0x10000,%esi
  shl    $0x10,%rdi
  add    %rbp,%rdi
  call   <CRUSH@plt>
  neg    %eax
  mov    %eax,%edi
  call   <expf@plt>
  mov    $0xffffffff,%esi
  lea    0x1(%rax),%edi
  call   <powf@plt>
  movsd  D16(%rip),%xmm1
  movss  %xmm0,0x40000(%r12,%rbx,1)
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0x1800c8(%rbp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x18,%rbx
  jne    L8
  lea    0x180000(%rbp),%rdx
  lea    0x40000(%r12),%rdi
  mov    $0x6,%esi
  call   <CRUSH@plt>
  neg    %eax
  mov    %eax,%edi
  call   <expf@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  pop    %rbx
  lea    0x1(%rax),%ecx
  mov    $0x1,%eax
  movsd  D16(%rip),%xmm0
  cltd
  idiv   %ecx
  cvtsi2ss %eax,%xmm1
  cvtss2sd %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  movss  %xmm1,0x180144(%rbp)
  mulsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x180148(%rbp)
  movaps %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_guessed: f64

tool: D16: 1

assistant: ```c
float CHEW(float *GUT, float BONE[][1 << 16]) {
  int GRR;
  for (GRR = 0; GRR < 6; ++GRR) {
    GUT[GRR + 256 * 256] = powf(1 + expf(-CRUSH(BONE[GRR], 1 << 16, GUT)), -1);
    BONE[6][50 + GRR] = GUT[256 * 256 + GRR] * (1. - GUT[(8 << 13) + GRR]);
  }
  BONE[6][81] = 1 / (1 + expf(-CRUSH(GUT + (1 << 16), 6, BONE[6])));
  return BONE[6][82] = BONE[6][81] * (1. - BONE[6][81]), BONE[6][81];
}
```
user: Translate the below assembly code into C programming language:

```asm
<CHEW>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L1:
  mov    %rbx,%rdi
  mov    %r12,%rdx
  mov    $0x10000,%esi
  shl    $0x10,%rdi
  add    %rbp,%rdi
  call   <CRUSH@plt>
  neg    %eax
  mov    %eax,%edi
  call   <expf@plt>
  mov    $0xffffffff,%esi
  lea    0x1(%rax),%edi
  call   <powf@plt>
  movsd  D8(%rip),%xmm1
  movss  %xmm0,0x40000(%r12,%rbx,1)
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0x1800c8(%rbp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x18,%rbx
  jne    L1
  lea    0x180000(%rbp),%rdx
  lea    0x40000(%r12),%rdi
  mov    $0x6,%esi
  call   <CRUSH@plt>
  neg    %eax
  mov    %eax,%edi
  call   <expf@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  pop    %rbx
  lea    0x1(%rax),%ecx
  mov    $0x1,%eax
  movsd  D8(%rip),%xmm0
  cltd
  idiv   %ecx
  cvtsi2sd %eax,%xmm2
  cvtsi2ss %eax,%xmm1
  subsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  cvtsd2ss %xmm0,%xmm0
  unpcklps %xmm0,%xmm2
  movaps %xmm1,%xmm0
  movlps %xmm2,0x180144(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: f64

tool: D8: 1

assistant: ```c
float CHEW(float *GUT, float BONE[][1 << 16]) {
  int GRR;
  for (GRR = 0; GRR < 6; ++GRR) {
    GUT[GRR + 256 * 256] = powf(1 + expf(-CRUSH(BONE[GRR], 1 << 16, GUT)), -1);
    BONE[6][50 + GRR] = GUT[256 * 256 + GRR] * (1. - GUT[(8 << 13) + GRR]);
  }
  BONE[6][81] = 1 / (1 + expf(-CRUSH(GUT + (1 << 16), 6, BONE[6])));
  return BONE[6][82] = BONE[6][81] * (1. - BONE[6][81]), BONE[6][81];
}
```