ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<partition_memory>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rax,%rbp
  lea    0x4(,%rax,4),%rax
  push   %rbx
  lea    (%rdi,%rax,1),%rsi
  lea    0x4(%rdi,%rax,1),%rcx
  mov    %rdi,%rbx
  lea    -0x4(%rbx,%rax,1),%r8
  sub    $0x28,%rsp
  mov    (%rsi),%edx
  mov    (%rcx),%r15d
  mov    %rsi,0x18(%rsp)
  mov    %edx,0x14(%rsp)
  mov    -0x8(%rdi,%rax,1),%edx
  mov    %rcx,0x8(%rsp)
  test   %edx,%edx
  mov    %r8,(%rsp)
  sete   %dil
  xor    %r13d,%r13d
  cmp    $0x4,%ebp
  setne  %r13b
  xor    %eax,%eax
  and    %edi,%r13d
  mov    (%r8),%edi
  call   <get_size@plt>
  lea    0x0(%r13,%r12,2),%edi
  mov    (%rsp),%r8
  test   %r14d,%r14d
  lea    0x1(%rdi,%rdi,1),%r10d
  movslq %r15d,%rdi
  mov    0x8(%rsp),%rcx
  lea    -0x1(%rbp,%rax,1),%eax
  mov    0x18(%rsp),%rsi
  lea    0x4(%rbx,%rdi,4),%r9
  mov    %r10d,(%r8)
  cltq
  movslq 0x14(%rsp),%rdi
  movl   $0x0,(%rsi)
  mov    %rdi,%rdx
  movl   $0x0,(%rcx)
  lea    0x8(%rbx,%rdi,4),%rdi
  je     L7
  add    %r12d,%ebp
  lea    (%rbx,%rax,4),%rax
  movd   %edx,%xmm1
  sub    %r12d,(%rax)
  mov    %ebp,(%r9)
  mov    %ebp,(%rdi)
  mov    (%rax),%eax
  movslq %ebp,%rbp
  mov    %r15d,0x8(%rbx,%rbp,4)
  lea    0x2(,%rax,4),%eax
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rbx,%rbp,4)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  movl   $0x0,(%rbx,%rax,4)
  mov    %edx,(%r9)
  mov    %r15d,(%rdi)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void partition_memory(int *mem, int fpart, int psize, int split) {
  int old_f_link = mem[fpart + 1];
  int old_b_link = mem[fpart + 2];
  int preuse_bit = ((mem[fpart - 1] == 0) && ((fpart - 1) != 3)) ? 1 : 0;
  int size_index = fpart + get_size(mem[fpart]) - 1;
  if (split) {
    mem[fpart] = 4 * psize + 2 * preuse_bit + 1;
    mem[fpart + 1] = 0;
    mem[fpart + 2] = 0;
    mem[size_index] -= psize;
    mem[old_b_link + 1] = fpart + psize;
    mem[old_f_link + 2] = fpart + psize;
    mem[fpart + psize] = 4 * (mem[size_index]) + 2 * 1 + 0;
    mem[fpart + psize + 1] = old_f_link;
    mem[fpart + psize + 2] = old_b_link;
  } else {
    mem[fpart] = 4 * psize + 2 * preuse_bit + 1;
    mem[fpart + 1] = 0;
    mem[fpart + 2] = 0;
    mem[size_index] = 0;
    mem[old_b_link + 1] = old_f_link;
    mem[old_f_link + 2] = old_b_link;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<busyloop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %edi,0x4(%rsp)
  mov    %esi,%ebp
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%r13
  mov    %r8,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,(%rsp)
  test   %ebx,%ebx
  jle    L68
  movslq %ebp,%rbx
  shl    $0x3,%rbx
  jmp    L88
L53:
  mov    %eax,%r11d
  cltq
  lea    (%r12,%rax,8),%r8
  mov    %r13,%rcx
  add    %r15,%rax
  lea    (%r14,%rax,8),%r9
L24:
  mov    %r8,%rdx
  movq   $0x0,(%r8)
  mov    $0x0,%eax
L12:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L12
  add    $0x8,%r8
  add    %rbx,%rcx
  cmp    %r9,%r8
  jne    L24
  lea    0x0(%rbp,%r11,1),%eax
  add    $0x1,%r10d
  add    %rbx,%rsi
  cmp    %r10d,%ebp
  jne    L53
L40:
  lea    0x14(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%eax
  lea    0xf4240(%rax),%edx
  mov    (%rsp),%edi
  cmp    %eax,%edi
  cmovg  %edx,%eax
  sub    %edi,%eax
  cmp    %eax,0x4(%rsp)
  jle    L74
L88:
  mov    0x8(%rsp),%rsi
  mov    $0x0,%eax
  mov    $0x0,%r10d
  lea    -0x1(%rbp),%r15d
  lea    0x8(%r12),%r14
  mov    %ebp,%edi
  test   %ebp,%ebp
  jg     L53
  jmp    L40
L68:
  mov    $0x0,%eax
L74:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int busyloop(int burn, int nxny, double *m1, double *m2, double *m1m2) {
  int i, j, k;
  int iters = 0;
  struct timeval tv;
  gettimeofday(&tv, NULL);
  int loopstart = tv.tv_usec;
  int curtime = tv.tv_usec;
  int busy = 0;
  int nxny_x, ioff, joff;
  while (busy < burn) {
    iters++;
    nxny_x = 0;
    for (i = 0; i < nxny; i++) {
      ioff = i * nxny;
      for (j = 0; j < nxny; j++) {
        joff = j * nxny;
        m1m2[nxny_x] = 0;
        for (k = 0; k < nxny; k++) {
          m1m2[nxny_x] += m1[ioff + k] * m2[k + joff];
        }
        nxny_x++;
      }
    }
    gettimeofday(&tv, NULL);
    curtime = tv.tv_usec;
    if (curtime < loopstart)
      curtime += 1000000;
    busy = (curtime - loopstart);
  }
  return busy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<busyloop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  mov    %edi,0x4(%rsp)
  lea    0x14(%rsp),%r14
  mov    %rdx,0x8(%rsp)
  mov    %r14,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,(%rsp)
  test   %ebx,%ebx
  jle    L14
  movslq %ebp,%rbx
  pxor   %xmm2,%xmm2
  shl    $0x3,%rbx
L28:
  test   %ebp,%ebp
  jle    L48
  mov    0x8(%rsp),%rsi
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  lea    0x8(%r13),%r15
  mov    %ebp,%edi
  lea    -0x1(%rbp),%r11d
  nopw   0x0(%rax,%rax,1)
L46:
  movslq %r10d,%rax
  mov    %r12,%rcx
  lea    0x0(%r13,%rax,8),%rdx
  add    %r11,%rax
  lea    (%r15,%rax,8),%r8
  nopw   0x0(%rax,%rax,1)
L58:
  movq   $0x0,(%rdx)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L60:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %rax,%rdi
  jne    L60
  add    $0x8,%rdx
  add    %rbx,%rcx
  cmp    %r8,%rdx
  jne    L58
  add    $0x1,%r9d
  add    %ebp,%r10d
  add    %rbx,%rsi
  cmp    %r9d,%ebp
  jne    L46
L48:
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%eax
  mov    (%rsp),%edi
  pxor   %xmm2,%xmm2
  cmp    %eax,%edi
  lea    0xf4240(%rax),%edx
  cmovg  %edx,%eax
  sub    %edi,%eax
  cmp    %eax,0x4(%rsp)
  jg     L28
L62:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  xor    %eax,%eax
  jmp    L62
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int busyloop(int burn, int nxny, double *m1, double *m2, double *m1m2) {
  int i, j, k;
  int iters = 0;
  struct timeval tv;
  gettimeofday(&tv, NULL);
  int loopstart = tv.tv_usec;
  int curtime = tv.tv_usec;
  int busy = 0;
  int nxny_x, ioff, joff;
  while (busy < burn) {
    iters++;
    nxny_x = 0;
    for (i = 0; i < nxny; i++) {
      ioff = i * nxny;
      for (j = 0; j < nxny; j++) {
        joff = j * nxny;
        m1m2[nxny_x] = 0;
        for (k = 0; k < nxny; k++) {
          m1m2[nxny_x] += m1[ioff + k] * m2[k + joff];
        }
        nxny_x++;
      }
    }
    gettimeofday(&tv, NULL);
    curtime = tv.tv_usec;
    if (curtime < loopstart)
      curtime += 1000000;
    busy = (curtime - loopstart);
  }
  return busy;
}
```
user: What is the c source code of the assembly code below?

```asm
<busyloop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  mov    %edi,0x4(%rsp)
  lea    0x14(%rsp),%r14
  mov    %rdx,0x8(%rsp)
  mov    %r14,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%eax
  mov    %eax,(%rsp)
  test   %ebx,%ebx
  jle    L65
  movslq %ebp,%rbx
  pxor   %xmm2,%xmm2
  shl    $0x3,%rbx
L16:
  test   %ebp,%ebp
  jle    L11
  mov    0x8(%rsp),%rsi
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  lea    0x8(%r13),%r15
  mov    %ebp,%edi
  lea    -0x1(%rbp),%r11d
  nopw   0x0(%rax,%rax,1)
L55:
  movslq %r10d,%rax
  mov    %r12,%rcx
  lea    0x0(%r13,%rax,8),%rdx
  add    %r11,%rax
  lea    (%r15,%rax,8),%r8
  nopw   0x0(%rax,%rax,1)
L56:
  movq   $0x0,(%rdx)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L60:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %rax,%rdi
  jne    L60
  add    $0x8,%rdx
  add    %rbx,%rcx
  cmp    %r8,%rdx
  jne    L56
  add    $0x1,%r9d
  add    %ebp,%r10d
  add    %rbx,%rsi
  cmp    %r9d,%ebp
  jne    L55
L11:
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%eax
  mov    (%rsp),%edi
  pxor   %xmm2,%xmm2
  cmp    %eax,%edi
  lea    0xf4240(%rax),%edx
  cmovg  %edx,%eax
  sub    %edi,%eax
  cmp    %eax,0x4(%rsp)
  jg     L16
L71:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L65:
  xor    %eax,%eax
  jmp    L71
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int busyloop(int burn, int nxny, double *m1, double *m2, double *m1m2) {
  int i, j, k;
  int iters = 0;
  struct timeval tv;
  gettimeofday(&tv, NULL);
  int loopstart = tv.tv_usec;
  int curtime = tv.tv_usec;
  int busy = 0;
  int nxny_x, ioff, joff;
  while (busy < burn) {
    iters++;
    nxny_x = 0;
    for (i = 0; i < nxny; i++) {
      ioff = i * nxny;
      for (j = 0; j < nxny; j++) {
        joff = j * nxny;
        m1m2[nxny_x] = 0;
        for (k = 0; k < nxny; k++) {
          m1m2[nxny_x] += m1[ioff + k] * m2[k + joff];
        }
        nxny_x++;
      }
    }
    gettimeofday(&tv, NULL);
    curtime = tv.tv_usec;
    if (curtime < loopstart)
      curtime += 1000000;
    busy = (curtime - loopstart);
  }
  return busy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x20,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movabs $0x807060504030201,%rax
  movabs $0x100f0e0d0c0b0a09,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movabs $0x7766554433221100,%rax
  movabs $0xffeeddccbbaa9988,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x504323e2caac3aae,%rax
  movabs $0x22335f42a43b9088,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0xd1f4dc24342775d9,%rax
  movabs $0xb85070bd6e75cc20,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movabs $0xc577d622e27efbb8,%rax
  movabs $0x9f37df14c520a13b,%rdx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  lea    -0x30(%rbp),%r8
  mov    -0x80(%rbp),%rdi
  lea    -0x50(%rbp),%rcx
  mov    -0x78(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x60(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <run_test@plt>
  add    $0x10,%rsp
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int test7() {
  unsigned long long mlen = 2 * 16;
  const unsigned long long hlen = 0;
  const unsigned char k[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char m[2 * 16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char c[2 * 16] = {0xae, 0x3a, 0xac, 0xca, 0xe2, 0x23, 0x43, 0x50, 0x88, 0x90, 0x3b, 0xa4, 0x42, 0x5f, 0x33, 0x22, 0xd9, 0x75, 0x27, 0x34, 0x24, 0xdc, 0xf4, 0xd1, 0x20, 0xcc, 0x75, 0x6e, 0xbd, 0x70, 0x50, 0xb8};
  const unsigned char t[16] = {0xb8, 0xfb, 0x7e, 0xe2, 0x22, 0xd6, 0x77, 0xc5, 0x3b, 0xa1, 0x20, 0xc5, 0x14, 0xdf, 0x37, 0x9f};
  return run_test(k, NULL, hlen, m, mlen, c, t);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test7>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movabs $0x807060504030201,%rax
  movabs $0x100f0e0d0c0b0a09,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x7766554433221100,%rax
  movabs $0xffeeddccbbaa9988,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x504323e2caac3aae,%rax
  movabs $0x22335f42a43b9088,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0xd1f4dc24342775d9,%rax
  movabs $0xb85070bd6e75cc20,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movabs $0xc577d622e27efbb8,%rax
  movabs $0x9f37df14c520a13b,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  lea    0x20(%rsp),%rcx
  mov    %rsp,%rdi
  sub    $0x8,%rsp
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%r9
  mov    $0x20,%r8d
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <run_test@plt>
  add    $0x10,%rsp
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x78,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test7() {
  unsigned long long mlen = 2 * 16;
  const unsigned long long hlen = 0;
  const unsigned char k[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char m[2 * 16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char c[2 * 16] = {0xae, 0x3a, 0xac, 0xca, 0xe2, 0x23, 0x43, 0x50, 0x88, 0x90, 0x3b, 0xa4, 0x42, 0x5f, 0x33, 0x22, 0xd9, 0x75, 0x27, 0x34, 0x24, 0xdc, 0xf4, 0xd1, 0x20, 0xcc, 0x75, 0x6e, 0xbd, 0x70, 0x50, 0xb8};
  const unsigned char t[16] = {0xb8, 0xfb, 0x7e, 0xe2, 0x22, 0xd6, 0x77, 0xc5, 0x3b, 0xa1, 0x20, 0xc5, 0x14, 0xdf, 0x37, 0x9f};
  return run_test(k, NULL, hlen, m, mlen, c, t);
}
```
user: What is the c source code of the assembly code below:

```asm
<test7>:
  endbr64
  sub    $0x78,%rsp
  movdqa D5(%rip),%xmm0
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  mov    %rsp,%rdi
  sub    $0x8,%rsp
  movaps %xmm0,0x8(%rsp)
  movdqa D31(%rip),%xmm0
  mov    $0x20,%r8d
  movaps %xmm0,0x28(%rsp)
  movaps %xmm0,0x38(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x48(%rsp)
  movdqa D29(%rip),%xmm0
  movaps %xmm0,0x58(%rsp)
  movdqa D14(%rip),%xmm0
  movaps %xmm0,0x18(%rsp)
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%r9
  call   <run_test@plt>
  pop    %rdx
  pop    %rcx
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x78,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: byte[16]
name: retrieve_data
arguments: tag: D31
data_type: byte[16]
name: retrieve_data
arguments: tag: D2
data_type: byte[16]
name: retrieve_data
arguments: tag: D29
data_type: byte[16]
name: retrieve_data
arguments: tag: D14
data_type: byte[16]

tool: {"D5": [0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,0x10]}

tool: {"D31": [0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x88,0x99,0xaa,0xbb,0xcc,0xdd,0xee,0xff]}

tool: {"D2": [0xae,0x3a,0xac,0xca,0xe2,0x23,0x43,0x50,0x88,0x90,0x3b,0xa4,0x42,0x5f,0x33,0x22]}

tool: {"D29": [0xd9,0x75,0x27,0x34,0x24,0xdc,0xf4,0xd1,0x20,0xcc,0x75,0x6e,0xbd,0x70,0x50,0xb8]}

tool: {"D14": [0xb8,0xfb,0x7e,0xe2,0x22,0xd6,0x77,0xc5,0x3b,0xa1,0x20,0xc5,0x14,0xdf,0x37,0x9f]}

assistant: ```c
int test7() {
  unsigned long long mlen = 2 * 16;
  const unsigned long long hlen = 0;
  const unsigned char k[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char m[2 * 16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char c[2 * 16] = {0xae, 0x3a, 0xac, 0xca, 0xe2, 0x23, 0x43, 0x50, 0x88, 0x90, 0x3b, 0xa4, 0x42, 0x5f, 0x33, 0x22, 0xd9, 0x75, 0x27, 0x34, 0x24, 0xdc, 0xf4, 0xd1, 0x20, 0xcc, 0x75, 0x6e, 0xbd, 0x70, 0x50, 0xb8};
  const unsigned char t[16] = {0xb8, 0xfb, 0x7e, 0xe2, 0x22, 0xd6, 0x77, 0xc5, 0x3b, 0xa1, 0x20, 0xc5, 0x14, 0xdf, 0x37, 0x9f};
  return run_test(k, NULL, hlen, m, mlen, c, t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test7>:
  endbr64
  sub    $0x78,%rsp
  movdqa D13(%rip),%xmm0
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  mov    %rsp,%rdi
  sub    $0x8,%rsp
  movaps %xmm0,0x8(%rsp)
  movdqa D4(%rip),%xmm0
  mov    $0x20,%r8d
  movaps %xmm0,0x28(%rsp)
  movaps %xmm0,0x38(%rsp)
  movdqa D0(%rip),%xmm0
  movaps %xmm0,0x48(%rsp)
  movdqa D38(%rip),%xmm0
  movaps %xmm0,0x58(%rsp)
  movdqa D24(%rip),%xmm0
  movaps %xmm0,0x18(%rsp)
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%r9
  call   <run_test@plt>
  pop    %rdx
  pop    %rcx
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x78,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D4
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D0
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D38
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D24
type_guessed: byte[16]

tool: {"D13": [0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,0x10]}

tool: {"D4": [0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x88,0x99,0xaa,0xbb,0xcc,0xdd,0xee,0xff]}

tool: {"D0": [0xae,0x3a,0xac,0xca,0xe2,0x23,0x43,0x50,0x88,0x90,0x3b,0xa4,0x42,0x5f,0x33,0x22]}

tool: {"D38": [0xd9,0x75,0x27,0x34,0x24,0xdc,0xf4,0xd1,0x20,0xcc,0x75,0x6e,0xbd,0x70,0x50,0xb8]}

tool: {"D24": [0xb8,0xfb,0x7e,0xe2,0x22,0xd6,0x77,0xc5,0x3b,0xa1,0x20,0xc5,0x14,0xdf,0x37,0x9f]}

assistant: ```c
int test7() {
  unsigned long long mlen = 2 * 16;
  const unsigned long long hlen = 0;
  const unsigned char k[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char m[2 * 16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char c[2 * 16] = {0xae, 0x3a, 0xac, 0xca, 0xe2, 0x23, 0x43, 0x50, 0x88, 0x90, 0x3b, 0xa4, 0x42, 0x5f, 0x33, 0x22, 0xd9, 0x75, 0x27, 0x34, 0x24, 0xdc, 0xf4, 0xd1, 0x20, 0xcc, 0x75, 0x6e, 0xbd, 0x70, 0x50, 0xb8};
  const unsigned char t[16] = {0xb8, 0xfb, 0x7e, 0xe2, 0x22, 0xd6, 0x77, 0xc5, 0x3b, 0xa1, 0x20, 0xc5, 0x14, 0xdf, 0x37, 0x9f};
  return run_test(k, NULL, hlen, m, mlen, c, t);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fact_while>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L7
L15:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x14(%rbp)
L7:
  cmpl   $0x1,-0x14(%rbp)
  jg     L15
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fact_while(int n) {
  int result = 1;
  while (n > 1) {
    result *= n;
    n -= 1;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fact_while>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  mov    $0x1,%eax
L16:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L16
  ret
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fact_while(int n) {
  int result = 1;
  while (n > 1) {
    result *= n;
    n -= 1;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fact_while>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L8
  xchg   %ax,%ax
L6:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L6
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
int fact_while(int n) {
  int result = 1;
  while (n > 1) {
    result *= n;
    n -= 1;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fact_while>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L18
  xchg   %ax,%ax
L11:
  imul   %edi,%eax
  sub    $0x1,%edi
  cmp    $0x1,%edi
  jne    L11
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
int fact_while(int n) {
  int result = 1;
  while (n > 1) {
    result *= n;
    n -= 1;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7e0,%edx
  mov    $0xb,%esi
  mov    $0x11,%edi
  call   <data@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  data(17, 11, 2016);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7e0,%edx
  mov    $0xb,%esi
  mov    $0x11,%edi
  call   <data@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  data(17, 11, 2016);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7e0,%edx
  mov    $0xb,%esi
  mov    $0x11,%edi
  call   <data@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  data(17, 11, 2016);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7e0,%edx
  mov    $0xb,%esi
  mov    $0x11,%edi
  call   <data@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  data(17, 11, 2016);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<disconnect_server>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  test   %rax,%rax
  je     L9
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D5: ERROR. Failed to close connection

assistant: ```c
void disconnect_server(int sockfd) {
  if (close(sockfd) != 0)
    perror("ERROR. Failed to close connection");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<disconnect_server>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  test   %rax,%rax
  jne    L12
L19:
  add    $0x8,%rsp
  ret
L12:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D3: ERROR. Failed to close connection

assistant: ```c
void disconnect_server(int sockfd) {
  if (close(sockfd) != 0)
    perror("ERROR. Failed to close connection");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<disconnect_server>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  test   %rax,%rax
  jne    L2
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <perror@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: ERROR. Failed to close connection

assistant: ```c
void disconnect_server(int sockfd) {
  if (close(sockfd) != 0)
    perror("ERROR. Failed to close connection");
}
```