user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_anonymous_aligned_wide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x40,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x40,%esi
  mov    %eax,%edi
  call   <print_binary@plt>
  movzbl -0x10(%rbp),%eax
  or     $0x1,%eax
  mov    %al,-0x10(%rbp)
  movzbl -0x10(%rbp),%eax
  or     $0x4,%eax
  mov    %al,-0x10(%rbp)
  movzbl -0x10(%rbp),%eax
  or     $0x8,%eax
  mov    %al,-0x10(%rbp)
  movzbl -0xc(%rbp),%eax
  or     $0x3,%eax
  mov    %al,-0xc(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x40,%esi
  mov    %eax,%edi
  call   <print_binary@plt>
  movzbl -0x10(%rbp),%eax
  and    $0xfffffffe,%eax
  mov    %al,-0x10(%rbp)
  movzbl -0x10(%rbp),%eax
  and    $0xfffffffb,%eax
  mov    %al,-0x10(%rbp)
  movzbl -0x10(%rbp),%eax
  and    $0xfffffff7,%eax
  mov    %al,-0x10(%rbp)
  movzbl -0xc(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %al,-0xc(%rbp)
  movzbl -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzbl -0x10(%rbp),%eax
  and    $0x4,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzbl -0x10(%rbp),%eax
  and    $0x8,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzbl -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x40,%esi
  mov    %eax,%edi
  call   <print_binary@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D44
data_type: string
name: parse_data
arguments: label: D43
data_type: string
name: parse_data
arguments: label: D38
data_type: string
name: parse_data
arguments: label: D39
data_type: string
name: parse_data
arguments: label: D40
data_type: string

tool: D44: 
===== test_anonymous_aligned_wide

tool: D43: Memory size occupied by bitfield : %lu bits


tool: D38: Memory contents (initial): 

tool: D39: Memory contents (set)    : 

tool: D40: Memory contents (cleared): 

assistant: ```c
void test_anonymous_aligned_wide() {
  printf("\n===== test_anonymous_aligned_wide\n");
  struct {
    uint8_t a : 1;
    uint8_t : 1;
    uint8_t b : 1;
    uint8_t c : 1;
    uint8_t : 0;
    uint8_t opcode : 2;
  } bitfield;
  printf("Memory size occupied by bitfield : %lu bits\n", sizeof(bitfield) * 8);
  printf("Memory contents (initial): ");
  print_binary(*(uint32_t *)&bitfield, sizeof(bitfield) * 8);
  bitfield.a = 1;
  bitfield.b = 1;
  bitfield.c = 1;
  bitfield.opcode = 0b11;
  assert(bitfield.a == 1);
  assert(bitfield.b == 1);
  assert(bitfield.c == 1);
  assert(bitfield.opcode == 3);
  printf("Memory contents (set)    : ");
  print_binary(*(uint32_t *)&bitfield, sizeof(bitfield) * 8);
  bitfield.a = 0;
  bitfield.b = 0;
  bitfield.c = 0;
  bitfield.opcode = 0;
  assert(bitfield.a == 0);
  assert(bitfield.b == 0);
  assert(bitfield.c == 0);
  assert(bitfield.opcode == 0);
  printf("Memory contents (cleared): ");
  print_binary(*(uint32_t *)&bitfield, sizeof(bitfield) * 8);
}
```