ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Unique>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0x144(%rsp),%r8
  mov    %r15,%rcx
L105:
  mov    %rdi,%rsi
  mov    $0x0,%eax
L12:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0x24,%rax
  jne    L12
  add    $0x24,%rdi
  add    $0x24,%rcx
  cmp    %r8,%rcx
  jne    L105
  mov    $0x0,%r12d
  mov    %rsp,%rbp
L39:
  mov    $0x0,%ebx
L6:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <Unique_Row@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Unique_Col@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <Unique_Blk@plt>
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L6
  add    $0x1,%r12d
  cmp    $0x9,%r12d
  jne    L39
  mov    $0x0,%r14d
  lea    D1(%rip),%r12
  jmp    L46
L17:
  mov    $0x20,%edi
  call   <putchar@plt>
L144:
  add    $0x1,%rbx
L7:
  mov    %ebx,%ebp
  movslq %ebx,%rax
  imul   $0x38e38e39,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,8),%eax
  cmp    %ebx,%eax
  je     L83
L0:
  cmp    $0x9,%rbx
  je     L75
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  movslq %ebp,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebp
  jne    L144
  jmp    L17
L83:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L0
L75:
  add    $0x1,%r14d
  movslq %r14d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %r14d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%r14d
  je     L33
L131:
  add    $0x24,%r15
  cmp    $0x9,%r14d
  je     L31
L46:
  mov    %r15,%r13
  mov    (%r15),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  jmp    L7
L33:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L131
L31:
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L112
  add    $0x158,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L112:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: %d 

assistant: ```c
void Unique(int a[9][9]) {
  int i, j;
  int temp[9][9];
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++)
      temp[i][j] = a[i][j];
  }
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      Unique_Row(temp, i);
      Unique_Col(temp, j);
      Unique_Blk(temp, i, j);
    }
  }
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      printf("%d ", temp[i][j]);
      if ((j + 1) % 3 == 0)
        printf(" ");
      if ((j + 1) % 9 == 0)
        printf("\n");
    }
    if ((i + 1) % 3 == 0)
      printf("\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<Unique>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  mov    $0x28,%ecx
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  nopl   (%rax)
L92:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <Unique_Row@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <Unique_Col@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <Unique_Blk@plt>
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L31
  add    $0x1,%ebp
  cmp    $0x9,%ebp
  jne    L92
  xor    %r14d,%r14d
  lea    D6(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L38:
  mov    (%r12),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <printf@plt>
  jmp    L40
  nopl   (%rax)
L90:
  cmp    $0x9,%rbx
  je     L106
L108:
  add    $0x1,%ebp
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  imul   $0xaaaaaaab,%ebp,%ebp
  call   <printf@plt>
  cmp    $0x55555555,%ebp
  ja     L81
  mov    $0x20,%edi
  call   <putchar@plt>
L81:
  add    $0x1,%rbx
L40:
  imul   $0x38e38e39,%ebx,%eax
  mov    %ebx,%ebp
  cmp    $0x1c71c71c,%eax
  ja     L90
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x9,%rbx
  jne    L108
L106:
  add    $0x1,%r14d
  imul   $0xaaaaaaab,%r14d,%eax
  cmp    $0x55555555,%eax
  jbe    L72
L29:
  add    $0x24,%r12
  cmp    $0x9,%r14d
  jne    L38
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L91
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L72:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L29
L91:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string

tool: D6: %d 

assistant: ```c
void Unique(int a[9][9]) {
  int i, j;
  int temp[9][9];
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++)
      temp[i][j] = a[i][j];
  }
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      Unique_Row(temp, i);
      Unique_Col(temp, j);
      Unique_Blk(temp, i, j);
    }
  }
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      printf("%d ", temp[i][j]);
      if ((j + 1) % 3 == 0)
        printf(" ");
      if ((j + 1) % 9 == 0)
        printf("\n");
    }
    if ((i + 1) % 3 == 0)
      printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ltoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L33:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,-0x10(%rbp)
  addl   $0x1,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L33
  mov    -0x20(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  subl   $0x1,-0x20(%rbp)
L32:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,-0x10(%rbp)
  cmpq   $0x9,-0x10(%rbp)
  ja     L17
  mov    -0x10(%rbp),%rax
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L12
L17:
  mov    -0x10(%rbp),%rax
  lea    0x37(%rax),%ecx
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L12:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rdi
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L32
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ltoa(unsigned long num, int base) {
  unsigned long sum;
  unsigned long digit;
  int len = 0, tot = 0;
  char *buf;
  sum = num;
  do {
    digit = sum % base;
    len++;
    sum /= base;
  } while (sum);
  buf = (char *)malloc(len + 2);
  tot = len;
  sum = num;
  len--;
  do {
    digit = sum % base;
    if (digit < 0xA)
      buf[len--] = '0' + digit;
    else
      buf[len--] = 'A' + digit - 0xA;
    sum /= base;
  } while (sum);
  buf[tot] = '\0';
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ltoa>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rax
  mov    $0x0,%r12d
  movslq %esi,%rbx
L16:
  mov    %r12d,%r13d
  add    $0x1,%r12d
  mov    %rax,%rcx
  mov    $0x0,%edx
  div    %rbx
  cmp    %rcx,%rbx
  jbe    L16
  lea    0x3(%r13),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  movslq %r13d,%rcx
  add    %rax,%rcx
  jmp    L48
L35:
  add    $0x30,%edx
  mov    %dl,(%rcx)
L22:
  mov    %rbp,%rax
  mov    $0x0,%edx
  div    %rbx
  sub    $0x1,%rcx
  cmp    %rbp,%rbx
  ja     L49
  mov    %rax,%rbp
L48:
  mov    %rbp,%rax
  mov    $0x0,%edx
  div    %rbx
  cmp    $0x9,%rdx
  jbe    L35
  add    $0x37,%edx
  mov    %dl,(%rcx)
  jmp    L22
L49:
  movslq %r12d,%r12
  movb   $0x0,(%rsi,%r12,1)
  mov    %rsi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ltoa(unsigned long num, int base) {
  unsigned long sum;
  unsigned long digit;
  int len = 0, tot = 0;
  char *buf;
  sum = num;
  do {
    digit = sum % base;
    len++;
    sum /= base;
  } while (sum);
  buf = (char *)malloc(len + 2);
  tot = len;
  sum = num;
  len--;
  do {
    digit = sum % base;
    if (digit < 0xA)
      buf[len--] = '0' + digit;
    else
      buf[len--] = 'A' + digit - 0xA;
    sum /= base;
  } while (sum);
  buf[tot] = '\0';
  return buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<ltoa>:
  endbr64
  push   %r13
  mov    %rdi,%rax
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rax,%rcx
  xor    %edx,%edx
  mov    %r13d,%ebp
  add    $0x1,%r13d
  div    %rbx
  cmp    %rbx,%rcx
  jae    L2
  lea    0x3(%rbp),%edi
  call   <malloc@plt>
  movslq %ebp,%rcx
  mov    %rax,%r8
  add    %rax,%rcx
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rax,%r12
L22:
  xor    %edx,%edx
  mov    %r12,%rax
  div    %rbx
  cmp    $0x9,%rdx
  lea    0x30(%rdx),%edi
  lea    0x37(%rdx),%esi
  cmovbe %edi,%esi
  sub    $0x1,%rcx
  mov    %sil,0x1(%rcx)
  cmp    %rbx,%r12
  jae    L25
  movslq %r13d,%r13
  mov    %r8,%rax
  movb   $0x0,(%r8,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ltoa(unsigned long num, int base) {
  unsigned long sum;
  unsigned long digit;
  int len = 0, tot = 0;
  char *buf;
  sum = num;
  do {
    digit = sum % base;
    len++;
    sum /= base;
  } while (sum);
  buf = (char *)malloc(len + 2);
  tot = len;
  sum = num;
  len--;
  do {
    digit = sum % base;
    if (digit < 0xA)
      buf[len--] = '0' + digit;
    else
      buf[len--] = 'A' + digit - 0xA;
    sum /= base;
  } while (sum);
  buf[tot] = '\0';
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ltoa>:
  endbr64
  push   %r13
  mov    %rdi,%rax
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rax,%rcx
  xor    %edx,%edx
  mov    %r13d,%ebp
  add    $0x1,%r13d
  div    %rbx
  cmp    %rbx,%rcx
  jae    L6
  lea    0x3(%rbp),%edi
  call   <malloc@plt>
  movslq %ebp,%rcx
  mov    %rax,%r8
  add    %rax,%rcx
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x30,%edx
  sub    $0x1,%rcx
  mov    %dl,0x1(%rcx)
  cmp    %r12,%rbx
  ja     L9
L46:
  mov    %rax,%r12
L33:
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbx
  cmp    $0x9,%rdx
  jbe    L39
  add    $0x37,%edx
  sub    $0x1,%rcx
  mov    %dl,0x1(%rcx)
  cmp    %r12,%rbx
  jbe    L46
L9:
  movslq %r13d,%r13
  mov    %r8,%rax
  movb   $0x0,(%r8,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ltoa(unsigned long num, int base) {
  unsigned long sum;
  unsigned long digit;
  int len = 0, tot = 0;
  char *buf;
  sum = num;
  do {
    digit = sum % base;
    len++;
    sum /= base;
  } while (sum);
  buf = (char *)malloc(len + 2);
  tot = len;
  sum = num;
  len--;
  do {
    digit = sum % base;
    if (digit < 0xA)
      buf[len--] = '0' + digit;
    else
      buf[len--] = 'A' + digit - 0xA;
    sum /= base;
  } while (sum);
  buf[tot] = '\0';
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dgetvectors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %edx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rcx
  mov    -0x50(%rbp),%edx
  mov    -0x4c(%rbp),%esi
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <vector_positions@plt>
  movq   $0x0,-0x38(%rbp)
  jmp    L16
L2:
  mov    -0x38(%rbp),%rax
  mov    -0x30(%rbp,%rax,8),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    -0x58(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x38(%rbp)
L16:
  cmpq   $0x3,-0x38(%rbp)
  jbe    L2
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void dgetvectors(const int dims[3], int i, int j, const double *field, const double *v[]) {
  size_t p, start[4];
  vector_positions(dims, i, j, start);
  for (p = 0; p < 4; p++) {
    v[p] = field + start[p];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dgetvectors>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rcx,%rbp
  mov    %r8,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <vector_positions@plt>
  mov    $0x0,%eax
L9:
  mov    (%rsp,%rax,8),%rdx
  lea    0x0(%rbp,%rdx,8),%rdx
  mov    %rdx,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L9
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dgetvectors(const int dims[3], int i, int j, const double *field, const double *v[]) {
  size_t p, start[4];
  vector_positions(dims, i, j, start);
  for (p = 0; p < 4; p++) {
    v[p] = field + start[p];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dgetvectors>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rcx
  call   <vector_positions@plt>
  xor    %eax,%eax
L10:
  mov    (%r12,%rax,8),%rdx
  lea    0x0(%rbp,%rdx,8),%rdx
  mov    %rdx,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L10
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dgetvectors(const int dims[3], int i, int j, const double *field, const double *v[]) {
  size_t p, start[4];
  vector_positions(dims, i, j, start);
  for (p = 0; p < 4; p++) {
    v[p] = field + start[p];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dgetvectors>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <vector_positions@plt>
  mov    (%rsp),%rax
  lea    0x0(%rbp,%rax,8),%rax
  mov    %rax,(%rbx)
  mov    0x8(%rsp),%rax
  lea    0x0(%rbp,%rax,8),%rax
  mov    %rax,0x8(%rbx)
  mov    0x10(%rsp),%rax
  lea    0x0(%rbp,%rax,8),%rax
  mov    %rax,0x10(%rbx)
  mov    0x18(%rsp),%rax
  lea    0x0(%rbp,%rax,8),%rax
  mov    %rax,0x18(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dgetvectors(const int dims[3], int i, int j, const double *field, const double *v[]) {
  size_t p, start[4];
  vector_positions(dims, i, j, start);
  for (p = 0; p < 4; p++) {
    v[p] = field + start[p];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stbi__high_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L44
  mov    $0xffffffff,%eax
  jmp    L35
L44:
  cmpl   $0xffff,-0x14(%rbp)
  jbe    L66
  addl   $0x10,-0x4(%rbp)
  shrl   $0x10,-0x14(%rbp)
L66:
  cmpl   $0xff,-0x14(%rbp)
  jbe    L34
  addl   $0x8,-0x4(%rbp)
  shrl   $0x8,-0x14(%rbp)
L34:
  cmpl   $0xf,-0x14(%rbp)
  jbe    L37
  addl   $0x4,-0x4(%rbp)
  shrl   $0x4,-0x14(%rbp)
L37:
  cmpl   $0x3,-0x14(%rbp)
  jbe    L39
  addl   $0x2,-0x4(%rbp)
  shrl   $0x2,-0x14(%rbp)
L39:
  cmpl   $0x1,-0x14(%rbp)
  jbe    L19
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int stbi__high_bit(unsigned int z) {
  int n = 0;
  if (z == 0)
    return -1;
  if (z >= 0x10000) {
    n += 16;
    z >>= 16;
  }
  if (z >= 0x00100) {
    n += 8;
    z >>= 8;
  }
  if (z >= 0x00010) {
    n += 4;
    z >>= 4;
  }
  if (z >= 0x00004) {
    n += 2;
    z >>= 2;
  }
  if (z >= 0x00002) {
    n += 1;
  }
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<stbi__high_bit>:
  endbr64
  test   %edi,%edi
  je     L39
  mov    $0x0,%eax
  cmp    $0xffff,%edi
  jbe    L20
  shr    $0x10,%edi
  mov    $0x10,%eax
L20:
  cmp    $0xff,%edi
  jbe    L10
  add    $0x8,%eax
  shr    $0x8,%edi
L10:
  cmp    $0xf,%edi
  jbe    L45
  add    $0x4,%eax
  shr    $0x4,%edi
L45:
  cmp    $0x3,%edi
  jbe    L14
  add    $0x2,%eax
  shr    $0x2,%edi
L14:
  cmp    $0x2,%edi
  sbb    $0xffffffff,%eax
  ret
L39:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int stbi__high_bit(unsigned int z) {
  int n = 0;
  if (z == 0)
    return -1;
  if (z >= 0x10000) {
    n += 16;
    z >>= 16;
  }
  if (z >= 0x00100) {
    n += 8;
    z >>= 8;
  }
  if (z >= 0x00010) {
    n += 4;
    z >>= 4;
  }
  if (z >= 0x00004) {
    n += 2;
    z >>= 2;
  }
  if (z >= 0x00002) {
    n += 1;
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stbi__high_bit>:
  endbr64
  test   %edi,%edi
  je     L46
  xor    %eax,%eax
  cmp    $0xffff,%edi
  jbe    L37
  shr    $0x10,%edi
  mov    $0x10,%eax
L37:
  cmp    $0xff,%edi
  jbe    L10
  add    $0x8,%eax
  shr    $0x8,%edi
L10:
  cmp    $0xf,%edi
  jbe    L5
  add    $0x4,%eax
  shr    $0x4,%edi
L5:
  cmp    $0x3,%edi
  jbe    L14
  add    $0x2,%eax
  shr    $0x2,%edi
L14:
  xor    %edx,%edx
  cmp    $0x1,%edi
  setne  %dl
  add    %edx,%eax
  ret
  nopl   0x0(%rax)
L46:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int stbi__high_bit(unsigned int z) {
  int n = 0;
  if (z == 0)
    return -1;
  if (z >= 0x10000) {
    n += 16;
    z >>= 16;
  }
  if (z >= 0x00100) {
    n += 8;
    z >>= 8;
  }
  if (z >= 0x00010) {
    n += 4;
    z >>= 4;
  }
  if (z >= 0x00004) {
    n += 2;
    z >>= 2;
  }
  if (z >= 0x00002) {
    n += 1;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi__high_bit>:
  endbr64
  test   %edi,%edi
  je     L21
  cmp    $0xffff,%edi
  ja     L40
  mov    $0x8,%edx
  xor    %eax,%eax
L45:
  cmp    $0xff,%edi
  jbe    L37
  shr    $0x8,%edi
  mov    %edx,%eax
L37:
  cmp    $0xf,%edi
  jbe    L34
  add    $0x4,%eax
  shr    $0x4,%edi
L34:
  cmp    $0x3,%edi
  jbe    L20
  add    $0x2,%eax
  shr    $0x2,%edi
L20:
  xor    %edx,%edx
  cmp    $0x1,%edi
  setne  %dl
  add    %edx,%eax
  ret
  nopl   (%rax)
L40:
  shr    $0x10,%edi
  mov    $0x18,%edx
  mov    $0x10,%eax
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L21:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int stbi__high_bit(unsigned int z) {
  int n = 0;
  if (z == 0)
    return -1;
  if (z >= 0x10000) {
    n += 16;
    z >>= 16;
  }
  if (z >= 0x00100) {
    n += 8;
    z >>= 8;
  }
  if (z >= 0x00010) {
    n += 4;
    z >>= 4;
  }
  if (z >= 0x00004) {
    n += 2;
    z >>= 2;
  }
  if (z >= 0x00002) {
    n += 1;
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L47
L15:
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x28(%rbp)
L47:
  cmpl   $0x5,-0x28(%rbp)
  jle    L15
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x28(%rbp)
  jmp    L31
L20:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x2c(%rbp),%eax
  cmp    %eax,%edx
  jne    L4
  addl   $0x1,-0x24(%rbp)
L4:
  addl   $0x1,-0x28(%rbp)
L31:
  cmpl   $0x5,-0x28(%rbp)
  jle    L20
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type: string
name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D4
type: string
name: parse_data
arguments: data_tag: D8
type: string

tool: D19: intput array, a[6]

tool: D1: %d

tool: D4: input number to count in array ,

tool: D8: %d 

assistant: ```c
int main(void) {
  int array[6] = {};
  int i, count = 0, num;
  printf("intput array, a[6]\n");
  for (i = 0; i < 6; i++) {
    scanf("%d", &array[i]);
  }
  printf("input number to count in array ,\n");
  scanf("%d", &num);
  for (i = 1; i < 6; i++) {
    if (num == array[i])
      count += 1;
  }
  printf("%d ", count);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbp
  lea    0x28(%rsp),%r13
  mov    %rbp,%rbx
  lea    D3(%rip),%r12
L22:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L22
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  lea    0x14(%rbp),%rdx
  mov    $0x0,%esi
L7:
  cmp    %ecx,0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  add    %eax,%esi
  add    $0x4,%rbp
  cmp    %rdx,%rbp
  jne    L7
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D23
type: string

tool: D30: intput array, a[6]

tool: D3: %d

tool: D12: input number to count in array ,

tool: D23: %d 

assistant: ```c
int main(void) {
  int array[6] = {};
  int i, count = 0, num;
  printf("intput array, a[6]\n");
  for (i = 0; i < 6; i++) {
    scanf("%d", &array[i]);
  }
  printf("input number to count in array ,\n");
  scanf("%d", &num);
  for (i = 1; i < 6; i++) {
    if (num == array[i])
      count += 1;
  }
  printf("%d ", count);
  return 0;
}
```