user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jg     L24
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L41
L24:
  mov    -0x1c(%rbp),%eax
  cmp    $0x2d,%eax
  jle    L41
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L41:
  movl   $0x0,-0xc(%rbp)
  jmp    L27
L30:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L30
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D38
datatype: string
name: read_data
arguments: tag: D16
datatype: string
name: read_data
arguments: tag: D74
datatype: string
name: read_data
arguments: tag: D51
datatype: string
name: read_data
arguments: tag: D89
datatype: string
name: read_data
arguments: tag: D62
datatype: string
name: read_data
arguments: tag: D49
datatype: string

tool: D38: How many times do I have to do the Fibonacci?

tool: D16: %d

tool: D74: You can`t set 0 or a negative number, please write a new number: 

tool: D51: For now Fibonaccis doesn`t support more than 45 times, please write a new number: 

tool: D89: 
%d

tool: D62: 
 Fibonaccis ran %d times,

tool: D49:  the last number of the sequence was %d 


assistant: ```c
int main() {
  int prec1 = 1;
  int prec2 = 0;
  int r, i, howmanyt = 0;
  printf("How many times do I have to do the Fibonacci?\n");
  scanf("%d", &howmanyt);
  if (howmanyt < 1) {
    printf("You can`t set 0 or a negative number, please write a new number: ");
    scanf("%d", &howmanyt);
  } else if (howmanyt > 45) {
    printf("For now Fibonaccis doesn`t support more than 45 times, please write a new number: ");
    scanf("%d", &howmanyt);
  }
  for (i = 0; i <= howmanyt; i++) {
    r = prec1 + prec2;
    printf("\n"
           "%d",
           r);
    prec1 = prec2;
    prec2 = r;
  }
  printf("\n Fibonaccis ran %d times,", howmanyt);
  printf(" the last number of the sequence was %d \n", r);
}
```