ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ZellerWeek>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%esi
  cmp    $0x2,%ecx
  jg     L8
  sub    $0x1,%edi
  add    $0xc,%ecx
L8:
  movslq %edi,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  mov    %rdx,%rax
  sar    $0x25,%rax
  mov    %rax,%r8
  mov    %edi,%r10d
  sar    $0x1f,%r10d
  mov    %eax,%r9d
  sub    %r10d,%r9d
  imul   $0x64,%r9d,%eax
  sub    %eax,%edi
  lea    0x3(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x2,%eax
  add    %edi,%eax
  sar    $0x27,%rdx
  sub    %r10d,%edx
  add    %edx,%eax
  sub    %r10d,%r8d
  add    %r8d,%r8d
  sub    %r8d,%eax
  add    $0x1,%ecx
  lea    (%rcx,%rcx,2),%edx
  lea    (%rcx,%rdx,4),%ecx
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  lea    -0x1(%rsi,%rax,1),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x7(%rax),%edx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int ZellerWeek(int year, int month, int day) {
  int m = month;
  int d = day;
  if (month <= 2) {
    year--;
    m = month + 12;
  }
  int y = year % 100;
  int c = year / 100;
  int w = (y + y / 4 + c / 4 - 2 * c + (13 * (m + 1) / 5) + d - 1) % 7;
  if (w < 0)
    w += 7;
  return w;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ZellerWeek>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%esi
  cmp    $0x2,%ecx
  jg     L0
  sub    $0x1,%edi
  add    $0xc,%ecx
L0:
  movslq %edi,%rdx
  mov    %edi,%r10d
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%r10d
  mov    %rdx,%rax
  sar    $0x25,%rax
  mov    %eax,%r9d
  mov    %rax,%r8
  sub    %r10d,%r9d
  imul   $0x64,%r9d,%eax
  sub    %eax,%edi
  lea    0x3(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x27,%rdx
  add    $0x1,%ecx
  sub    %r10d,%r8d
  sub    %r10d,%edx
  add    %r8d,%r8d
  sar    $0x2,%eax
  add    %edi,%eax
  add    %edx,%eax
  lea    (%rcx,%rcx,2),%edx
  lea    (%rcx,%rdx,4),%ecx
  sub    %r8d,%eax
  movslq %ecx,%rdx
  sar    $0x1f,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  lea    -0x1(%rsi,%rax,1),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x7(%rax),%edx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int ZellerWeek(int year, int month, int day) {
  int m = month;
  int d = day;
  if (month <= 2) {
    year--;
    m = month + 12;
  }
  int y = year % 100;
  int c = year / 100;
  int w = (y + y / 4 + c / 4 - 2 * c + (13 * (m + 1) / 5) + d - 1) % 7;
  if (w < 0)
    w += 7;
  return w;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ZellerWeek>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%esi
  cmp    $0x2,%ecx
  jg     L7
  sub    $0x1,%edi
  add    $0xc,%ecx
L7:
  movslq %edi,%rdx
  mov    %edi,%r10d
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%r10d
  mov    %rdx,%rax
  sar    $0x25,%rax
  mov    %eax,%r9d
  mov    %rax,%r8
  sub    %r10d,%r9d
  imul   $0x64,%r9d,%eax
  sub    %eax,%edi
  lea    0x3(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x27,%rdx
  add    $0x1,%ecx
  sub    %r10d,%r8d
  sub    %r10d,%edx
  add    %r8d,%r8d
  sar    $0x2,%eax
  add    %edi,%eax
  add    %edx,%eax
  lea    (%rcx,%rcx,2),%edx
  lea    (%rcx,%rdx,4),%ecx
  sub    %r8d,%eax
  movslq %ecx,%rdx
  sar    $0x1f,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  lea    -0x1(%rsi,%rax,1),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x7(%rax),%edx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int ZellerWeek(int year, int month, int day) {
  int m = month;
  int d = day;
  if (month <= 2) {
    year--;
    m = month + 12;
  }
  int y = year % 100;
  int c = year / 100;
  int w = (y + y / 4 + c / 4 - 2 * c + (13 * (m + 1) / 5) + d - 1) % 7;
  if (w < 0)
    w += 7;
  return w;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L7
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <try@plt>
  cmp    %eax,-0x4(%rbp)
  je     L10
  mov    $0x0,%eax
  call   <abort@plt>
L10:
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x6,-0x4(%rbp)
  jle    L14
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int i;
  for (i = 1; i <= 6; i++) {
    if (try(i) != i)
      abort();
  }
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  jmp    L19
L30:
  add    $0x1,%ebx
  cmp    $0x7,%ebx
  je     L34
L19:
  mov    %ebx,%edi
  call   <try@plt>
  cmp    %ebx,%eax
  je     L30
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L30
L34:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  int i;
  for (i = 1; i <= 6; i++) {
    if (try(i) != i)
      abort();
  }
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  call   <try@plt>
  cmp    %ebx,%eax
  je     L18
  xor    %eax,%eax
  call   <abort@plt>
L18:
  add    $0x1,%ebx
  cmp    $0x7,%ebx
  jne    L3
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  int i;
  for (i = 1; i <= 6; i++) {
    if (try(i) != i)
      abort();
  }
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %ebx,%edi
  call   <try@plt>
  cmp    %ebx,%eax
  je     L0
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <abort@plt>
  cmp    $0x7,%ebx
  jne    L27
L36:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L0:
  add    $0x1,%ebx
  cmp    $0x7,%ebx
  jne    L27
  jmp    L36
```

assistant: ```c
main() {
  int i;
  for (i = 1; i <= 6; i++) {
    if (try(i) != i)
      abort();
  }
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char *a;
  char *b;
  const char *x = 0 ? (char *)a : (const char *)b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  char *a;
  char *b;
  const char *x = 0 ? (char *)a : (const char *)b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char *a;
  char *b;
  const char *x = 0 ? (char *)a : (const char *)b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char *a;
  char *b;
  const char *x = 0 ? (char *)a : (const char *)b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <initCountTable@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L34
L3:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L10
  addl   $0x1,-0x8(%rbp)
  jmp    L20
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
L20:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void getCount(int *s, int *p, int n, int nip) {
  int bit = 0;
  initCountTable(p, nip);
  for (int i = 1; i < n; i++) {
    if (s[i - 1] != s[i]) {
      bit++;
    } else {
      p[bit] += 1;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getCount>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %ecx,%esi
  mov    %rbx,%rdi
  call   <initCountTable@plt>
  cmp    $0x1,%ebp
  jle    L29
  mov    %r12,%rax
  lea    -0x2(%rbp),%edx
  lea    0x4(%r12,%rdx,4),%rcx
  mov    $0x0,%edx
  jmp    L24
L32:
  movslq %edx,%rsi
  addl   $0x1,(%rbx,%rsi,4)
L5:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L29
L24:
  mov    0x4(%rax),%edi
  cmp    %edi,(%rax)
  je     L32
  add    $0x1,%edx
  jmp    L5
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void getCount(int *s, int *p, int n, int nip) {
  int bit = 0;
  initCountTable(p, nip);
  for (int i = 1; i < n; i++) {
    if (s[i - 1] != s[i]) {
      bit++;
    } else {
      p[bit] += 1;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getCount>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %ecx,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  call   <initCountTable@plt>
  cmp    $0x1,%r12d
  jle    L33
  lea    -0x2(%r12),%edx
  mov    %rbx,%rax
  lea    0x4(%rbx,%rdx,4),%rcx
  xor    %edx,%edx
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x4,%rax
  add    $0x1,%edx
  cmp    %rcx,%rax
  je     L33
L39:
  mov    0x4(%rax),%ebx
  cmp    %ebx,(%rax)
  jne    L10
  movslq %edx,%rsi
  add    $0x4,%rax
  addl   $0x1,0x0(%rbp,%rsi,4)
  cmp    %rcx,%rax
  jne    L39
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void getCount(int *s, int *p, int n, int nip) {
  int bit = 0;
  initCountTable(p, nip);
  for (int i = 1; i < n; i++) {
    if (s[i - 1] != s[i]) {
      bit++;
    } else {
      p[bit] += 1;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getCount>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %ecx,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  call   <initCountTable@plt>
  cmp    $0x1,%r12d
  jle    L12
  lea    -0x2(%r12),%edx
  mov    %rbx,%rax
  lea    0x4(%rbx,%rdx,4),%rcx
  xor    %edx,%edx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x4,%rax
  add    $0x1,%edx
  cmp    %rax,%rcx
  je     L12
L9:
  mov    0x4(%rax),%ebx
  cmp    %ebx,(%rax)
  jne    L30
  movslq %edx,%rsi
  add    $0x4,%rax
  addl   $0x1,0x0(%rbp,%rsi,4)
  cmp    %rax,%rcx
  jne    L9
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void getCount(int *s, int *p, int n, int nip) {
  int bit = 0;
  initCountTable(p, nip);
  for (int i = 1; i < n; i++) {
    if (s[i - 1] != s[i]) {
      bit++;
    } else {
      p[bit] += 1;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
```

assistant: ```c
int main(void) {
  asm("main_label: .globl main_label");
  foo();
  asm("main_label2: .globl main_label2");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
```

assistant: ```c
int main(void) {
  asm("main_label: .globl main_label");
  foo();
  asm("main_label2: .globl main_label2");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
```

assistant: ```c
int main(void) {
  asm("main_label: .globl main_label");
  foo();
  asm("main_label2: .globl main_label2");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
```

assistant: ```c
int main(void) {
  asm("main_label: .globl main_label");
  foo();
  asm("main_label2: .globl main_label2");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<basTriangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%r8d
  mov    -0x14(%rbp),%edi
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <triangle@plt>
  mov    %eax,%edi
  call   <pushNumber@plt>
  nop
  leave
  ret
```

assistant: ```c
void basTriangle() {
  int x1, y1, x2, y2, x3, y3;
  y3 = popNumber();
  x3 = popNumber();
  y2 = popNumber();
  x2 = popNumber();
  y1 = popNumber();
  x1 = popNumber();
  pushNumber(triangle(x1, y1, x2, y2, x3, y3));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basTriangle>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%r14d
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%r13d
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%edi
  mov    %r14d,%r9d
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  call   <triangle@plt>
  mov    %eax,%edi
  call   <pushNumber@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void basTriangle() {
  int x1, y1, x2, y2, x3, y3;
  y3 = popNumber();
  x3 = popNumber();
  y2 = popNumber();
  x2 = popNumber();
  y1 = popNumber();
  x1 = popNumber();
  pushNumber(triangle(x1, y1, x2, y2, x3, y3));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basTriangle>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <popNumber@plt>
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %eax,%edi
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <triangle@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <pushNumber@plt>
```

assistant: ```c
void basTriangle() {
  int x1, y1, x2, y2, x3, y3;
  y3 = popNumber();
  x3 = popNumber();
  y2 = popNumber();
  x2 = popNumber();
  y1 = popNumber();
  x1 = popNumber();
  pushNumber(triangle(x1, y1, x2, y2, x3, y3));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<basTriangle>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <popNumber@plt>
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %eax,%edi
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <triangle@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <pushNumber@plt>
```

assistant: ```c
void basTriangle() {
  int x1, y1, x2, y2, x3, y3;
  y3 = popNumber();
  x3 = popNumber();
  y2 = popNumber();
  x2 = popNumber();
  y1 = popNumber();
  x1 = popNumber();
  pushNumber(triangle(x1, y1, x2, y2, x3, y3));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D6: Command list:


tool: D23:   /adduser (Add new user.)


tool: D16:   /listuser (List all user in chat.)


tool: D5:   /help (Show this message.)


assistant: ```c
int list_help() {
  printf("Command list:\n");
  printf("  /adduser (Add new user.)\n");
  printf("  /listuser (List all user in chat.)\n");
  printf("  /help (Show this message.)\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<list_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D28
data_type: string

tool: D2: Command list:


tool: D5:   /adduser (Add new user.)


tool: D13:   /listuser (List all user in chat.)


tool: D28:   /help (Show this message.)


assistant: ```c
int list_help() {
  printf("Command list:\n");
  printf("  /adduser (Add new user.)\n");
  printf("  /listuser (List all user in chat.)\n");
  printf("  /help (Show this message.)\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<list_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D14
type: string
name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D15
type: string

tool: D14: Command list:


tool: D3:   /adduser (Add new user.)


tool: D5:   /listuser (List all user in chat.)


tool: D15:   /help (Show this message.)


assistant: ```c
int list_help() {
  printf("Command list:\n");
  printf("  /adduser (Add new user.)\n");
  printf("  /listuser (List all user in chat.)\n");
  printf("  /help (Show this message.)\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<list_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D38
data_type: string
name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D26
data_type: string
name: parse_data
arguments: data_tag: D29
data_type: string

tool: D38: Command list:


tool: D7:   /adduser (Add new user.)


tool: D26:   /listuser (List all user in chat.)


tool: D29:   /help (Show this message.)


assistant: ```c
int list_help() {
  printf("Command list:\n");
  printf("  /adduser (Add new user.)\n");
  printf("  /listuser (List all user in chat.)\n");
  printf("  /help (Show this message.)\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_tool_preface>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rdx
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <outputf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D10: /* Generated by nsgenbind
 *
 * nsgenbind is published under the MIT Licence.
 * nsgenbind is similar to a compiler is a purely transformative tool which
 * explicitly makes no copyright claim on this generated output
 */


tool: D3: %s

assistant: ```c
int output_tool_preface(struct opctx *outc) {
  outputf(outc, "%s",
          "/* Generated by nsgenbind\n"
          " *\n"
          " * nsgenbind is published under the MIT Licence.\n"
          " * nsgenbind is similar to a compiler is a purely transformative tool which\n"
          " * explicitly makes no copyright claim on this generated output\n"
          " */\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<output_tool_preface>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdx
  lea    D4(%rip),%rsi
  call   <outputf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type: string
name: extract_symbolic_data
arguments: label: D4
type: string

tool: D18: /* Generated by nsgenbind
 *
 * nsgenbind is published under the MIT Licence.
 * nsgenbind is similar to a compiler is a purely transformative tool which
 * explicitly makes no copyright claim on this generated output
 */


tool: D4: %s

assistant: ```c
int output_tool_preface(struct opctx *outc) {
  outputf(outc, "%s",
          "/* Generated by nsgenbind\n"
          " *\n"
          " * nsgenbind is published under the MIT Licence.\n"
          " * nsgenbind is similar to a compiler is a purely transformative tool which\n"
          " * explicitly makes no copyright claim on this generated output\n"
          " */\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<output_tool_preface>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdx
  lea    D14(%rip),%rsi
  call   <outputf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string

tool: D11: /* Generated by nsgenbind
 *
 * nsgenbind is published under the MIT Licence.
 * nsgenbind is similar to a compiler is a purely transformative tool which
 * explicitly makes no copyright claim on this generated output
 */


tool: D14: %s

assistant: ```c
int output_tool_preface(struct opctx *outc) {
  outputf(outc, "%s",
          "/* Generated by nsgenbind\n"
          " *\n"
          " * nsgenbind is published under the MIT Licence.\n"
          " * nsgenbind is similar to a compiler is a purely transformative tool which\n"
          " * explicitly makes no copyright claim on this generated output\n"
          " */\n");
  return 0;
}
```