ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L2
  mov    0x8(%rsi),%rdi
  call   <dump@plt>
  xor    %eax,%eax
L19:
  add    $0x8,%rsp
  ret
L2:
  mov    (%rsi),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: Usage: %s filename


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage: %s filename\n", argv[0]);
    return -1;
  }
  dump(argv[1]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L6
  mov    0x8(%rsi),%rdi
  call   <dump@plt>
  xor    %eax,%eax
L10:
  add    $0x8,%rsp
  ret
L6:
  mov    (%rsi),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: Usage: %s filename


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage: %s filename\n", argv[0]);
    return -1;
  }
  dump(argv[1]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<atmoC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <atmoT@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  D2(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: f64

tool: D2: 20.05

assistant: ```c
double atmoC(double h) {
  double c;
  double T;
  T = atmoT(h);
  c = 20.05 * sqrt(T);
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atmoC>:
  endbr64
  sub    $0x8,%rsp
  call   <atmoT@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L3
  sqrtsd %xmm0,%xmm0
L9:
  mulsd  D9(%rip),%xmm0
  add    $0x8,%rsp
  ret
L3:
  call   <sqrt@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: f64

tool: D9: 20.05

assistant: ```c
double atmoC(double h) {
  double c;
  double T;
  T = atmoT(h);
  c = 20.05 * sqrt(T);
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<atmoC>:
  endbr64
  sub    $0x8,%rsp
  call   <atmoT@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L1
  sqrtsd %xmm0,%xmm0
L4:
  mulsd  D3(%rip),%xmm0
  add    $0x8,%rsp
  ret
L1:
  call   <sqrt@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: f64

tool: D3: 20.05

assistant: ```c
double atmoC(double h) {
  double c;
  double T;
  T = atmoT(h);
  c = 20.05 * sqrt(T);
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atmoC>:
  endbr64
  sub    $0x8,%rsp
  call   <atmoT@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L13
  sqrtsd %xmm0,%xmm0
L14:
  mulsd  D4(%rip),%xmm0
  add    $0x8,%rsp
  ret
L13:
  call   <sqrt@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: f64

tool: D4: 20.05

assistant: ```c
double atmoC(double h) {
  double c;
  double T;
  T = atmoT(h);
  c = 20.05 * sqrt(T);
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L29:
  cmp    %rdx,%rsp
  je     L56
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L29
L56:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L41
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L41:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x38(%rbp)
  jmp    L9
L66:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x38(%rbp)
L9:
  mov    -0x38(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jb     L66
  movl   $0x0,-0x3c(%rbp)
  movq   $0x0,-0x30(%rbp)
  jmp    L46
L48:
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x3c(%rbp)
  addq   $0x1,-0x30(%rbp)
L46:
  mov    -0x30(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jb     L48
  mov    -0x3c(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int f(unsigned long bytes) {
  char buf[bytes];
  for (unsigned long i = 0; i < bytes; i++)
    buf[i] = rand() % 256;
  int sum = 0;
  for (unsigned long i = 0; i < bytes; i++)
    sum += buf[i];
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdi),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L39:
  cmp    %rdx,%rsp
  je     L29
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L39
L29:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L57
  orq    $0x0,-0x8(%rsp,%rax,1)
L57:
  mov    %rsp,%rbx
  test   %rdi,%rdi
  je     L22
  mov    %rbx,%r12
  lea    (%rbx,%rdi,1),%r13
L7:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L7
  mov    $0x0,%eax
L17:
  movsbl (%r12),%edx
  add    %edx,%eax
  add    $0x1,%r12
  cmp    %r13,%r12
  jne    L17
L30:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L22:
  mov    $0x0,%eax
  jmp    L30
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f(unsigned long bytes) {
  char buf[bytes];
  for (unsigned long i = 0; i < bytes; i++)
    buf[i] = rand() % 256;
  int sum = 0;
  for (unsigned long i = 0; i < bytes; i++)
    sum += buf[i];
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdi),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L13
L82:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L82
L13:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L79
L41:
  test   %rdi,%rdi
  je     L14
  mov    %rsp,%r12
  lea    (%rsp,%rdi,1),%rbx
  mov    %rsp,%r13
  xchg   %ax,%ax
L89:
  xor    %eax,%eax
  add    $0x1,%r13
  call   <rand@plt>
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %al,-0x1(%r13)
  cmp    %rbx,%r13
  jne    L89
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  movsbl (%r12),%edx
  add    $0x1,%r12
  add    %edx,%eax
  cmp    %rbx,%r12
  jne    L1
L32:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L41
L14:
  xor    %eax,%eax
  jmp    L32
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f(unsigned long bytes) {
  char buf[bytes];
  for (unsigned long i = 0; i < bytes; i++)
    buf[i] = rand() % 256;
  int sum = 0;
  for (unsigned long i = 0; i < bytes; i++)
    sum += buf[i];
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<destroy_unix_stream_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
bool destroy_unix_stream_socket(int sock) {
  close(sock);
  return true;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<destroy_unix_stream_socket>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool destroy_unix_stream_socket(int sock) {
  close(sock);
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<destroy_unix_stream_socket>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool destroy_unix_stream_socket(int sock) {
  close(sock);
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<destroy_unix_stream_socket>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool destroy_unix_stream_socket(int sock) {
  close(sock);
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  assert(~1 == -2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(~1 == -2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(~1 == -2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(~1 == -2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stou>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L45
L18:
  mov    $0x0,%eax
  jmp    L21
L45:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0xc(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
unsigned stou(const char *s) {
  char *p = s;
  unsigned r = 0;
  while (*p) {
    if (*p < '0' || *p > '9') {
      return 0;
    }
    r *= 10;
    r += *p - '0';
    p++;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stou>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  mov    $0x0,%edx
L48:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L31
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L48
  jmp    L43
L9:
  mov    $0x0,%edx
  jmp    L43
L31:
  mov    $0x0,%edx
L43:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned stou(const char *s) {
  char *p = s;
  unsigned r = 0;
  while (*p) {
    if (*p < '0' || *p > '9') {
      return 0;
    }
    r *= 10;
    r += *p - '0';
    p++;
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stou>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L20
  jmp    L8
L21:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  je     L8
L20:
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L21
  xor    %r8d,%r8d
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned stou(const char *s) {
  char *p = s;
  unsigned r = 0;
  while (*p) {
    if (*p < '0' || *p > '9') {
      return 0;
    }
    r *= 10;
    r += *p - '0';
    p++;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stou>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L30
  jmp    L24
L38:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  je     L24
L30:
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L38
  xor    %r8d,%r8d
L24:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned stou(const char *s) {
  char *p = s;
  unsigned r = 0;
  while (*p) {
    if (*p < '0' || *p > '9') {
      return 0;
    }
    r *= 10;
    r += *p - '0';
    p++;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tvSubtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rsi,%rax
  mov    %rdi,%r8
  mov    %r8,%rsi
  mov    %r9,%rdi
  mov    %rax,%rdi
  mov    %rsi,-0x20(%rbp)
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  cmp    %rax,%rdx
  jl     L15
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  cmp    %rax,%rdx
  jne    L27
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jg     L27
L15:
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L47
L27:
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jge    L24
  mov    -0x18(%rbp),%rax
  add    $0xf4240,%rax
  mov    -0x28(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L47
L24:
  mov    -0x18(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L47:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
struct timeval tvSubtract(struct timeval time1, struct timeval time2) {
  struct timeval result;
  if ((time1.tv_sec < time2.tv_sec) || ((time1.tv_sec == time2.tv_sec) && (time1.tv_usec <= time2.tv_usec))) {
    result.tv_sec = result.tv_usec = 0;
  } else {
    result.tv_sec = time1.tv_sec - time2.tv_sec;
    if (time1.tv_usec < time2.tv_usec) {
      result.tv_usec = time1.tv_usec + 1000000L - time2.tv_usec;
      result.tv_sec--;
    } else {
      result.tv_usec = time1.tv_usec - time2.tv_usec;
    }
  }
  return (result);
}
```
user: What is the c source code of the assembly code below:

```asm
<tvSubtract>:
  endbr64
  cmp    %rdx,%rdi
  jl     L5
  cmp    %rcx,%rsi
  jg     L36
  cmp    %rdx,%rdi
  je     L20
L36:
  mov    %rdi,%rax
  sub    %rdx,%rax
  mov    %rsi,%rdx
  sub    %rcx,%rdx
  cmp    %rcx,%rsi
  jge    L7
  lea    0xf4240(%rsi),%rdx
  sub    %rcx,%rdx
  sub    $0x1,%rax
  ret
L5:
  mov    $0x0,%edx
  mov    $0x0,%eax
  ret
L20:
  mov    $0x0,%edx
  mov    $0x0,%eax
L7:
  ret
```

assistant: ```c
struct timeval tvSubtract(struct timeval time1, struct timeval time2) {
  struct timeval result;
  if ((time1.tv_sec < time2.tv_sec) || ((time1.tv_sec == time2.tv_sec) && (time1.tv_usec <= time2.tv_usec))) {
    result.tv_sec = result.tv_usec = 0;
  } else {
    result.tv_sec = time1.tv_sec - time2.tv_sec;
    if (time1.tv_usec < time2.tv_usec) {
      result.tv_usec = time1.tv_usec + 1000000L - time2.tv_usec;
      result.tv_sec--;
    } else {
      result.tv_usec = time1.tv_usec - time2.tv_usec;
    }
  }
  return (result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tvSubtract>:
  endbr64
  mov    %rdi,%rax
  cmp    %rdx,%rdi
  jl     L12
  je     L34
  sub    %rdx,%rax
  cmp    %rcx,%rsi
  jge    L26
  lea    0xf4240(%rsi),%rdx
  sub    $0x1,%rax
  sub    %rcx,%rdx
  ret
  nopl   (%rax)
L34:
  xor    %eax,%eax
  cmp    %rcx,%rsi
  jg     L26
L12:
  xor    %edx,%edx
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L26:
  sub    %rcx,%rsi
  mov    %rsi,%rdx
  ret
```

assistant: ```c
struct timeval tvSubtract(struct timeval time1, struct timeval time2) {
  struct timeval result;
  if ((time1.tv_sec < time2.tv_sec) || ((time1.tv_sec == time2.tv_sec) && (time1.tv_usec <= time2.tv_usec))) {
    result.tv_sec = result.tv_usec = 0;
  } else {
    result.tv_sec = time1.tv_sec - time2.tv_sec;
    if (time1.tv_usec < time2.tv_usec) {
      result.tv_usec = time1.tv_usec + 1000000L - time2.tv_usec;
      result.tv_sec--;
    } else {
      result.tv_usec = time1.tv_usec - time2.tv_usec;
    }
  }
  return (result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tvSubtract>:
  endbr64
  mov    %rdi,%rax
  cmp    %rdx,%rdi
  jl     L20
  je     L17
  sub    %rdx,%rax
  cmp    %rcx,%rsi
  jge    L16
  lea    0xf4240(%rsi),%rdx
  sub    $0x1,%rax
  sub    %rcx,%rdx
  ret
  nopl   (%rax)
L17:
  xor    %eax,%eax
  cmp    %rcx,%rsi
  jg     L16
L20:
  xor    %edx,%edx
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L16:
  sub    %rcx,%rsi
  mov    %rsi,%rdx
  ret
```

assistant: ```c
struct timeval tvSubtract(struct timeval time1, struct timeval time2) {
  struct timeval result;
  if ((time1.tv_sec < time2.tv_sec) || ((time1.tv_sec == time2.tv_sec) && (time1.tv_usec <= time2.tv_usec))) {
    result.tv_sec = result.tv_usec = 0;
  } else {
    result.tv_sec = time1.tv_sec - time2.tv_sec;
    if (time1.tv_usec < time2.tv_usec) {
      result.tv_usec = time1.tv_usec + 1000000L - time2.tv_usec;
      result.tv_sec--;
    } else {
      result.tv_usec = time1.tv_usec - time2.tv_usec;
    }
  }
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movabs $0x7379732f20746163,%rax
  movabs $0x736563697665642f,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6c6175747269762f,%rax
  movabs $0x6c616d726568742f,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x6c616d726568742f,%rax
  movabs $0x742f30656e6f7a5f,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movl   $0x706d65,0x50(%rsp)
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r12d
  movss  D65(%rip),%xmm3
  movss  %xmm3,0xc(%rsp)
  lea    D32(%rip),%r13
  lea    D64(%rip),%r14
  lea    D28(%rip),%r15
  jmp    L13
L58:
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
L9:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  mov    %r15,%rdi
  call   <system@plt>
  mov    $0x0,%r12d
L41:
  movss  0x8(%rsp),%xmm2
  movss  %xmm2,0xc(%rsp)
L13:
  lea    0x20(%rsp),%rdi
  mov    %r13,%rsi
  call   <popen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L58
  lea    0x18(%rsp),%rbp
  mov    %rax,%rdx
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <atoi@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  divss  D61(%rip),%xmm0
  movss  %xmm0,0x8(%rsp)
  cvtss2sd %xmm0,%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <pclose@plt>
  movss  0xc(%rsp),%xmm1
  comiss 0x8(%rsp),%xmm1
  jbe    L20
  add    $0x1,%r12d
  mov    %r15,%rdi
  call   <system@plt>
  cmp    $0x1,%r12d
  jle    L41
  mov    $0x0,%eax
  jmp    L9
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
datatype: string
name: extract_symbolic_data
arguments: tag: D65
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D32
datatype: string
name: extract_symbolic_data
arguments: tag: D64
datatype: string
name: extract_symbolic_data
arguments: tag: D28
datatype: string
name: extract_symbolic_data
arguments: tag: D31
datatype: string
name: extract_symbolic_data
arguments: tag: D61
datatype: f32

tool: D22: Practice 08

tool: {"D65": [0xcd,0xcc,0xc7,0xc2]}

tool: D32: r

tool: D64: Temp=%.1f[C]


tool: D28: sleep 1

tool: D31: ERROR

tool: D61: 1000

assistant: ```c
int main() {
  FILE *pp;
  char cmd[] = "cat /sys/devices/virtual/thermal/thermal_zone0/temp";
  int in = 0;
  float temp;
  float prev = -99.9;
  int count = 0;
  char s[8];
  printf("Practice 08\n");
  do {
    pp = popen(cmd, "r");
    if (pp == NULL) {
      printf("ERROR\n");
      return -1;
    }
    fgets(s, 8, pp);
    in = atoi(s);
    temp = (float)in / 1000.;
    printf("Temp=%.1f[C]\n", temp);
    pclose(pp);
    if (temp < prev) {
      count++;
    } else {
      count = 0;
    }
    prev = temp;
    system("sleep 1");
  } while (count < 2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<replacespaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <consecutivechar@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <consecutivechar@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int replacespaces(char aux[], int pos, int mintabs, int minblanks) {
  pos = consecutivechar(aux, '\t', pos, mintabs);
  pos = consecutivechar(aux, ' ', pos, minblanks);
  return pos;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<replacespaces>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %ecx,%ebp
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    $0x9,%esi
  call   <consecutivechar@plt>
  mov    %eax,%edx
  mov    %ebp,%ecx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <consecutivechar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int replacespaces(char aux[], int pos, int mintabs, int minblanks) {
  pos = consecutivechar(aux, '\t', pos, mintabs);
  pos = consecutivechar(aux, ' ', pos, minblanks);
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<replacespaces>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  mov    %edx,%ecx
  mov    %esi,%edx
  push   %rbp
  mov    $0x9,%esi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <consecutivechar@plt>
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  mov    $0x20,%esi
  pop    %r12
  jmp    1050 <consecutivechar@plt>
```

assistant: ```c
int replacespaces(char aux[], int pos, int mintabs, int minblanks) {
  pos = consecutivechar(aux, '\t', pos, mintabs);
  pos = consecutivechar(aux, ' ', pos, minblanks);
  return pos;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<replacespaces>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  mov    %edx,%ecx
  mov    %esi,%edx
  push   %rbp
  mov    $0x9,%esi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <consecutivechar@plt>
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  mov    $0x20,%esi
  pop    %r12
  jmp    1050 <consecutivechar@plt>
```

assistant: ```c
int replacespaces(char aux[], int pos, int mintabs, int minblanks) {
  pos = consecutivechar(aux, '\t', pos, mintabs);
  pos = consecutivechar(aux, ' ', pos, minblanks);
  return pos;
}
```