user: 下面的汇编指令对应的C源代码是什么：

```asm
<maxSubSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jne    L31
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L54
L31:
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <maxSubSum>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <maxSubSum>
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L41
L40:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L44
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L44:
  subl   $0x1,-0x10(%rbp)
L41:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L40
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L64
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L35
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L35:
  addl   $0x1,-0x10(%rbp)
L64:
  mov    -0x10(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L12
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
L54:
  leave
  ret
```

assistant: ```c
int maxSubSum(const int *src, int left, int right) {
  int maxLeftSum, maxRightSum;
  int maxLeftBorderSum = 0, maxRightBorderSum = 0;
  int leftBorderSum = 0, rightBorderSum = 0;
  int center, i;
  if (left == right) {
    return *(src + left);
  }
  center = (right + left) / 2;
  maxLeftSum = maxSubSum(src, left, center);
  maxRightSum = maxSubSum(src, center + 1, right);
  maxLeftBorderSum = *(src + center);
  for (i = center; i >= left; --i) {
    if ((leftBorderSum += *(src + i)) > maxLeftBorderSum)
      maxLeftBorderSum = leftBorderSum;
  }
  maxRightBorderSum = *(src + center + 1);
  for (i = center + 1; i <= right; ++i) {
    if ((rightBorderSum += *(src + i)) > maxRightBorderSum)
      maxRightBorderSum = rightBorderSum;
  }
  return ((((maxLeftBorderSum + maxRightBorderSum)) > ((((maxLeftSum) > (maxRightSum)) ? (maxLeftSum) : (maxRightSum)))) ? ((maxLeftBorderSum + maxRightBorderSum)) : ((((maxLeftSum) > (maxRightSum)) ? (maxLeftSum) : (maxRightSum))));
}
```