ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strnstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x28(%rbp),%rax
  jmp    L9
L35:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L67
L43:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
L67:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L43
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x18(%rbp),%rax
  jmp    L9
L24:
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x34(%rbp)
L46:
  cmpl   $0x0,-0x34(%rbp)
  jg     L35
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
char *strnstr(const char *str1, const char *str2, int n) {
  char *cp = (char *)str1;
  char *s1, *s2;
  if (!*str2)
    return (char *)str1;
  while (n > 0) {
    s1 = cp;
    s2 = (char *)str2;
    int n2 = n;
    while (n2 > 0 && *s2 && !(*s1 - *s2))
      s1++, s2++, --n2;
    if (!*s2)
      return cp;
    cp++;
    --n;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strnstr>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L48
  test   %edx,%edx
  jg     L45
  mov    $0x0,%eax
  ret
L34:
  cmpb   $0x0,(%r8)
  je     L48
L56:
  add    $0x1,%rax
  sub    $0x1,%edx
  je     L55
L45:
  test   %edx,%edx
  jle    L56
  mov    %edx,%r10d
  add    %rax,%r10
  mov    %rsi,%r8
  mov    %rax,%rcx
  mov    %edi,%r9d
L20:
  cmp    %r9b,(%rcx)
  jne    L56
  add    $0x1,%rcx
  add    $0x1,%r8
  cmp    %r10,%rcx
  je     L34
  movzbl (%r8),%r9d
  test   %r9b,%r9b
  jne    L20
L48:
  ret
L55:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strnstr(const char *str1, const char *str2, int n) {
  char *cp = (char *)str1;
  char *s1, *s2;
  if (!*str2)
    return (char *)str1;
  while (n > 0) {
    s1 = cp;
    s2 = (char *)str2;
    int n2 = n;
    while (n2 > 0 && *s2 && !(*s1 - *s2))
      s1++, s2++, --n2;
    if (!*s2)
      return cp;
    cp++;
    --n;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnstr>:
  endbr64
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
  test   %r9b,%r9b
  je     L74
  test   %edx,%edx
  jle    L54
  nopl   0x0(%rax)
L67:
  lea    -0x1(%rdx),%edi
  mov    %r9d,%r8d
  xor    %ecx,%ecx
  mov    %rdi,%rdx
  jmp    L30
  nopl   (%rax)
L18:
  add    $0x1,%rcx
  test   %r8b,%r8b
  je     L74
L30:
  cmp    %r8b,(%rax,%rcx,1)
  jne    L57
  movzbl 0x1(%rsi,%rcx,1),%r8d
  cmp    %rdi,%rcx
  jne    L18
  test   %r8b,%r8b
  je     L74
L57:
  add    $0x1,%rax
  test   %edx,%edx
  jne    L67
L54:
  xor    %eax,%eax
L74:
  ret
```

assistant: ```c
char *strnstr(const char *str1, const char *str2, int n) {
  char *cp = (char *)str1;
  char *s1, *s2;
  if (!*str2)
    return (char *)str1;
  while (n > 0) {
    s1 = cp;
    s2 = (char *)str2;
    int n2 = n;
    while (n2 > 0 && *s2 && !(*s1 - *s2))
      s1++, s2++, --n2;
    if (!*s2)
      return cp;
    cp++;
    --n;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnstr>:
  endbr64
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
  test   %r9b,%r9b
  je     L48
  test   %edx,%edx
  jle    L47
  nopl   0x0(%rax)
L7:
  lea    -0x1(%rdx),%edi
  mov    %r9d,%r8d
  xor    %ecx,%ecx
  mov    %rdi,%rdx
  jmp    L59
  nopl   (%rax)
L66:
  add    $0x1,%rcx
  test   %r8b,%r8b
  je     L48
L59:
  cmp    %r8b,(%rax,%rcx,1)
  jne    L57
  movzbl 0x1(%rsi,%rcx,1),%r8d
  cmp    %rdi,%rcx
  jne    L66
  test   %r8b,%r8b
  je     L48
L57:
  add    $0x1,%rax
  test   %edx,%edx
  jne    L7
L47:
  xor    %eax,%eax
L48:
  ret
```

assistant: ```c
char *strnstr(const char *str1, const char *str2, int n) {
  char *cp = (char *)str1;
  char *s1, *s2;
  if (!*str2)
    return (char *)str1;
  while (n > 0) {
    s1 = cp;
    s2 = (char *)str2;
    int n2 = n;
    while (n2 > 0 && *s2 && !(*s1 - *s2))
      s1++, s2++, --n2;
    if (!*s2)
      return cp;
    cp++;
    --n;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rcx
  mov    %rdx,%rdi
  call   *0x100020
  mov    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long b_input(unsigned char *str, unsigned long nbr) {
  unsigned long len;
  asm volatile("call *0x00100020" : "=c"(len) : "c"(nbr), "D"(str));
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<b_input>:
  endbr64
  mov    %rsi,%rcx
  call   *0x100020
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_input(unsigned char *str, unsigned long nbr) {
  unsigned long len;
  asm volatile("call *0x00100020" : "=c"(len) : "c"(nbr), "D"(str));
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<b_input>:
  endbr64
  mov    %rsi,%rcx
  call   *0x100020
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_input(unsigned char *str, unsigned long nbr) {
  unsigned long len;
  asm volatile("call *0x00100020" : "=c"(len) : "c"(nbr), "D"(str));
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<b_input>:
  endbr64
  mov    %rsi,%rcx
  call   *0x100020
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_input(unsigned char *str, unsigned long nbr) {
  unsigned long len;
  asm volatile("call *0x00100020" : "=c"(len) : "c"(nbr), "D"(str));
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fnv32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L18:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  xor    %eax,-0x20(%rbp)
  mov    $0x1000193,%edi
  call   <UINT32_C@plt>
  mov    -0x20(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x20(%rbp)
  addq   $0x8,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L18
  mov    -0x20(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t fnv32(const uint8_t *buf, uint32_t len, uint32_t hash) {
  const uint8_t *bufend = buf + len;
  while (buf < bufend) {
    hash ^= (uint32_t)buf[0];
    hash *= UINT32_C(0x01000193);
    buf++;
  }
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fnv32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%ebp
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%r12
  cmp    %r12,%rdi
  jae    L9
L16:
  xor    (%rbx),%ebp
  mov    $0x1000193,%edi
  call   <UINT32_C@plt>
  imul   %eax,%ebp
  add    $0x8,%rbx
  cmp    %rbx,%r12
  ja     L16
L9:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t fnv32(const uint8_t *buf, uint32_t len, uint32_t hash) {
  const uint8_t *bufend = buf + len;
  while (buf < bufend) {
    hash ^= (uint32_t)buf[0];
    hash *= UINT32_C(0x01000193);
    buf++;
  }
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<fnv32>:
  endbr64
  movslq %esi,%rsi
  push   %r12
  lea    (%rdi,%rsi,8),%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  cmp    %r12,%rdi
  jae    L7
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L6:
  mov    $0x1000193,%edi
  xor    (%rbx),%ebp
  add    $0x8,%rbx
  call   <UINT32_C@plt>
  imul   %eax,%ebp
  cmp    %rbx,%r12
  ja     L6
L7:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t fnv32(const uint8_t *buf, uint32_t len, uint32_t hash) {
  const uint8_t *bufend = buf + len;
  while (buf < bufend) {
    hash ^= (uint32_t)buf[0];
    hash *= UINT32_C(0x01000193);
    buf++;
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fnv32>:
  endbr64
  movslq %esi,%rsi
  push   %r12
  lea    (%rdi,%rsi,8),%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  cmp    %r12,%rdi
  jae    L11
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L2:
  mov    $0x1000193,%edi
  xor    (%rbx),%ebp
  add    $0x8,%rbx
  call   <UINT32_C@plt>
  imul   %eax,%ebp
  cmp    %rbx,%r12
  ja     L2
L11:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t fnv32(const uint8_t *buf, uint32_t len, uint32_t hash) {
  const uint8_t *bufend = buf + len;
  while (buf < bufend) {
    hash ^= (uint32_t)buf[0];
    hash *= UINT32_C(0x01000193);
    buf++;
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<maxarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L5
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L5:
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int maxarray(double *A, int l) {
  int i;
  int maxind = 0;
  for (i = 0; i < l; i++) {
    if (A[i] > A[maxind]) {
      maxind = i;
    }
  }
  return maxind;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<maxarray>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %esi,%esi
  mov    $0x0,%eax
  mov    $0x0,%edx
L12:
  movslq %edx,%rcx
  movsd  (%rdi,%rax,8),%xmm0
  ucomisd (%rdi,%rcx,8),%xmm0
  cmova  %eax,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L12
L20:
  mov    %edx,%eax
  ret
L3:
  mov    $0x0,%edx
  jmp    L20
```

assistant: ```c
int maxarray(double *A, int l) {
  int i;
  int maxind = 0;
  for (i = 0; i < l; i++) {
    if (A[i] > A[maxind]) {
      maxind = i;
    }
  }
  return maxind;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maxarray>:
  endbr64
  test   %esi,%esi
  jle    L7
  movslq %esi,%rsi
  xor    %eax,%eax
  xor    %r8d,%r8d
L1:
  movslq %r8d,%rdx
  movsd  (%rdi,%rax,8),%xmm0
  ucomisd (%rdi,%rdx,8),%xmm0
  cmova  %eax,%r8d
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L1
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxarray(double *A, int l) {
  int i;
  int maxind = 0;
  for (i = 0; i < l; i++) {
    if (A[i] > A[maxind]) {
      maxind = i;
    }
  }
  return maxind;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<maxarray>:
  endbr64
  test   %esi,%esi
  jle    L9
  movsd  (%rdi),%xmm0
  movslq %esi,%rsi
  xor    %eax,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L1:
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L1
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxarray(double *A, int l) {
  int i;
  int maxind = 0;
  for (i = 0; i < l; i++) {
    if (A[i] > A[maxind]) {
      maxind = i;
    }
  }
  return maxind;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<kp_sprintfv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *kp_sprintfv(const char *fmt, va_list argp) {
  char *msg = malloc(128);
  vsprintf(msg, fmt, argp);
  return msg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kp_sprintfv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *kp_sprintfv(const char *fmt, va_list argp) {
  char *msg = malloc(128);
  vsprintf(msg, fmt, argp);
  return msg;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kp_sprintfv>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
const char *kp_sprintfv(const char *fmt, va_list argp) {
  char *msg = malloc(128);
  vsprintf(msg, fmt, argp);
  return msg;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kp_sprintfv>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
const char *kp_sprintfv(const char *fmt, va_list argp) {
  char *msg = malloc(128);
  vsprintf(msg, fmt, argp);
  return msg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_int4_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <flip4@plt>
  mov    -0x28(%rbp),%rax
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <flip4@plt>
  cmpl   $0x0,-0x4(%rbp)
  jg     L17
  mov    $0x0,%eax
  jmp    L12
L17:
  mov    -0x4(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
L12:
  leave
  ret
```

assistant: ```c
ssize_t write_int4_array(int f, const int *i, size_t n) {
  ssize_t nwritten;
  flip4((const unsigned int *)i, (unsigned int *)i, n);
  nwritten = write(f, i, 4 * n);
  flip4((const unsigned int *)i, (unsigned int *)i, n);
  if (nwritten <= 0)
    return 0;
  else
    return nwritten / 4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_int4_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rsi,%rdi
  call   <flip4@plt>
  lea    0x0(,%rbp,4),%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <flip4@plt>
  mov    $0x0,%eax
  test   %r12d,%r12d
  jle    L1
  lea    0x3(%r12),%eax
  cmovns %r12d,%eax
  sar    $0x2,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t write_int4_array(int f, const int *i, size_t n) {
  ssize_t nwritten;
  flip4((const unsigned int *)i, (unsigned int *)i, n);
  nwritten = write(f, i, 4 * n);
  flip4((const unsigned int *)i, (unsigned int *)i, n);
  if (nwritten <= 0)
    return 0;
  else
    return nwritten / 4;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_int4_array>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %rsi,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <flip4@plt>
  lea    0x0(,%r12,4),%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <flip4@plt>
  mov    %ebx,%eax
  xor    %edx,%edx
  sar    $0x2,%eax
  test   %ebx,%ebx
  cmovle %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_int4_array(int f, const int *i, size_t n) {
  ssize_t nwritten;
  flip4((const unsigned int *)i, (unsigned int *)i, n);
  nwritten = write(f, i, 4 * n);
  flip4((const unsigned int *)i, (unsigned int *)i, n);
  if (nwritten <= 0)
    return 0;
  else
    return nwritten / 4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_int4_array>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %rsi,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <flip4@plt>
  lea    0x0(,%r12,4),%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <flip4@plt>
  mov    %ebx,%eax
  xor    %edx,%edx
  sar    $0x2,%eax
  test   %ebx,%ebx
  cmovle %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_int4_array(int f, const int *i, size_t n) {
  ssize_t nwritten;
  flip4((const unsigned int *)i, (unsigned int *)i, n);
  nwritten = write(f, i, 4 * n);
  flip4((const unsigned int *)i, (unsigned int *)i, n);
  if (nwritten <= 0)
    return 0;
  else
    return nwritten / 4;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <suma@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  int result = suma(x, 2);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x0,%edi
  call   <suma@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  int result = suma(x, 2);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x2,%esi
  xor    %edi,%edi
  jmp    1050 <suma@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  int result = suma(x, 2);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x2,%esi
  xor    %edi,%edi
  jmp    1050 <suma@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  int result = suma(x, 2);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<modbus_get_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movss  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
float modbus_get_float(const uint16_t *src) {
  float f = 0.0f;
  uint32_t i;
  i = (((uint32_t)src[1]) << 16) + src[0];
  memcpy(&f, &i, sizeof(float));
  return f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<modbus_get_float>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  mov    0x4(%rdi),%eax
  shl    $0x10,%eax
  add    (%rdi),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  movss  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float modbus_get_float(const uint16_t *src) {
  float f = 0.0f;
  uint32_t i;
  i = (((uint32_t)src[1]) << 16) + src[0];
  memcpy(&f, &i, sizeof(float));
  return f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modbus_get_float>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rdi),%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,(%rsp)
  shl    $0x10,%eax
  add    (%rdi),%eax
  mov    %rsp,%rdi
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  movss  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float modbus_get_float(const uint16_t *src) {
  float f = 0.0f;
  uint32_t i;
  i = (((uint32_t)src[1]) << 16) + src[0];
  memcpy(&f, &i, sizeof(float));
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<modbus_get_float>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rdi),%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,(%rsp)
  shl    $0x10,%eax
  add    (%rdi),%eax
  mov    %rsp,%rdi
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  movss  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float modbus_get_float(const uint16_t *src) {
  float f = 0.0f;
  uint32_t i;
  i = (((uint32_t)src[1]) << 16) + src[0];
  memcpy(&f, &i, sizeof(float));
  return f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ignore_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_space@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3b,%eax
  je     L62
  cmp    $0x3b,%eax
  jg     L44
  cmp    $0x2f,%eax
  je     L67
  cmp    $0x2f,%eax
  jg     L44
  test   %eax,%eax
  je     L62
  cmp    $0x23,%eax
  jne    L44
L62:
  mov    $0x1,%eax
  jmp    L52
L67:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  jmp    L52
L44:
  mov    $0x0,%eax
L52:
  leave
  ret
```

assistant: ```c
bool ignore_line(const char *line) {
  line = skip_space(line);
  switch (*line) {
  case '\0':
  case '#':
  case ';':
    return true;
  case '/':
    return *(line + 1) == '/';
  }
  return false;
}
```
user: What is the c source code of the assembly code below?

```asm
<ignore_line>:
  endbr64
  sub    $0x8,%rsp
  call   <skip_space@plt>
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  je     L6
  jg     L32
  mov    $0x1,%eax
  test   %dl,%dl
  je     L37
  cmp    $0x23,%dl
  sete   %al
  movzbl %al,%eax
L37:
  add    $0x8,%rsp
  ret
L32:
  cmp    $0x3b,%dl
  sete   %al
  movzbl %al,%eax
  jmp    L37
L6:
  cmpb   $0x2f,0x1(%rax)
  sete   %al
  movzbl %al,%eax
  jmp    L37
```

assistant: ```c
bool ignore_line(const char *line) {
  line = skip_space(line);
  switch (*line) {
  case '\0':
  case '#':
  case ';':
    return true;
  case '/':
    return *(line + 1) == '/';
  }
  return false;
}
```