user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  cmpl   $0x1,-0x64(%rbp)
  jg     L40
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L18
L40:
  mov    -0x64(%rbp),%eax
  mov    %eax,-0x5c(%rbp)
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x58(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L26:
  cmp    %rdx,%rsp
  je     L125
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L26
L125:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L65
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L65:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L114:
  cmp    %rdx,%rsp
  je     L25
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L114
L25:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L13
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L13:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x60(%rbp)
  movl   $0x0,-0x60(%rbp)
  jmp    L12
L122:
  mov    -0x60(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    -0x50(%rbp),%rdx
  mov    -0x60(%rbp),%ecx
  movslq %ecx,%rcx
  mov    %rax,(%rdx,%rcx,8)
  mov    -0x50(%rbp),%rax
  mov    -0x60(%rbp),%edx
  movslq %edx,%rdx
  movsd  (%rax,%rdx,8),%xmm0
  movsd  D29(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  D47(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x40(%rbp),%rax
  mov    -0x60(%rbp),%edx
  movslq %edx,%rdx
  movsd  %xmm0,(%rax,%rdx,8)
  addl   $0x1,-0x60(%rbp)
L12:
  mov    -0x60(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L122
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x60(%rbp)
  jmp    L47
L101:
  mov    -0x40(%rbp),%rax
  mov    -0x60(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x60(%rbp)
L47:
  mov    -0x60(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L101
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
L18:
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D31
data_type: string
name: parse_data
arguments: label: D29
data_type: byte[8]
name: parse_data
arguments: label: D47
data_type: f64
name: parse_data
arguments: label: D21
data_type: string
name: parse_data
arguments: label: D3
data_type: string

tool: D31: no values given

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: D47: 1.8

tool: D21: Temperatures in degree Celsius:
	

tool: D3: %f, 

assistant: ```c
int main(int args, char **argv) {
  if (args < 2) {
    printf("no values given\n");
    return -1;
  }
  int elements = args;
  double temp_f[elements];
  double temp_c[elements];
  int ctr = 0;
  for (ctr = 0; ctr < elements; ctr++) {
    temp_f[ctr] = atof(argv[ctr]);
    temp_c[ctr] = (temp_f[ctr] - 32) / 1.8;
  }
  printf("Temperatures in degree Celsius:\n\t");
  for (ctr = 1; ctr < elements; ctr++) {
    printf("%f, ", temp_c[ctr]);
  }
  printf("\n");
  return 0;
}
```