ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x12,-0x14(%rbp)
  ja     L62
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D36(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D36(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  jmp    L108
  mov    $0x2,%eax
  jmp    L108
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3,%eax
  jmp    L108
  movl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L108
  mov    $0x5,%eax
  jmp    L108
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x6,%eax
  jmp    L108
  movl   $0x7,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  jmp    L108
  mov    $0x8,%eax
  jmp    L108
  mov    $0x9,%eax
  jmp    L108
  mov    $0xa,%eax
  jmp    L108
  mov    $0xb,%eax
  jmp    L108
  mov    $0xc,%eax
  jmp    L108
  mov    $0xd,%eax
  jmp    L108
  mov    $0xe,%eax
  jmp    L108
  mov    $0xf,%eax
  jmp    L108
  mov    $0x10,%eax
  jmp    L108
  mov    $0x11,%eax
  jmp    L108
  mov    $0x12,%eax
  jmp    L108
  mov    $0x13,%eax
  jmp    L108
L62:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
L108:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D22
data_type: string

tool: D22: Hello world!


assistant: ```c
int foo(int arg) {
  switch (arg) {
  case 0:
    return 1;
  case 1:
    return 2;
  case 2:
    printf("Hello world!\n");
    return 3;
  case 3: {
    int a = 4;
    return a;
  }
  case 4:
    return 5;
  case 5:
    printf("Hello world!\n");
    return 6;
  case 6: {
    int a = 7;
    return a;
  }
  case 7:
    return 8;
  case 8:
    return 9;
  case 9:
    return 10;
  case 10:
    return 11;
  case 11:
    return 12;
  case 12:
    return 13;
  case 13:
    return 14;
  case 14:
    return 15;
  case 15:
    return 16;
  case 16:
    return 17;
  case 17:
    return 18;
  case 18:
    return 19;
  default:
    return arg++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  cmp    $0x12,%edi
  ja     L18
  sub    $0x8,%rsp
  mov    %edi,%edi
  lea    D7(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
L3:
  add    $0x8,%rsp
  ret
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%eax
  jmp    L3
  mov    $0x4,%eax
  jmp    L3
  mov    $0x5,%eax
  jmp    L3
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%eax
  jmp    L3
  mov    $0x7,%eax
  jmp    L3
  mov    $0x8,%eax
  jmp    L3
  mov    $0x9,%eax
  jmp    L3
  mov    $0xa,%eax
  jmp    L3
  mov    $0xb,%eax
  jmp    L3
  mov    $0xc,%eax
  jmp    L3
  mov    $0xd,%eax
  jmp    L3
  mov    $0xe,%eax
  jmp    L3
  mov    $0xf,%eax
  jmp    L3
  mov    $0x10,%eax
  jmp    L3
  mov    $0x11,%eax
  jmp    L3
  mov    $0x12,%eax
  jmp    L3
  mov    $0x13,%eax
  jmp    L3
L18:
  mov    %edi,%eax
  ret
  mov    $0x1,%eax
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: Hello world!


assistant: ```c
int foo(int arg) {
  switch (arg) {
  case 0:
    return 1;
  case 1:
    return 2;
  case 2:
    printf("Hello world!\n");
    return 3;
  case 3: {
    int a = 4;
    return a;
  }
  case 4:
    return 5;
  case 5:
    printf("Hello world!\n");
    return 6;
  case 6: {
    int a = 7;
    return a;
  }
  case 7:
    return 8;
  case 8:
    return 9;
  case 9:
    return 10;
  case 10:
    return 11;
  case 11:
    return 12;
  case 12:
    return 13;
  case 13:
    return 14;
  case 14:
    return 15;
  case 15:
    return 16;
  case 16:
    return 17;
  case 17:
    return 18;
  case 18:
    return 19;
  default:
    return arg++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<testIntegerToString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <integerToString@plt>
  mov    %eax,%edx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <test@plt>
  mov    $0x12d687,%edi
  call   <integerToString@plt>
  mov    %eax,%edx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <test@plt>
  mov    $0xffffffef,%edi
  call   <integerToString@plt>
  mov    %eax,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <test@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D17: 0

tool: D0: 1234567

tool: D19: -17

assistant: ```c
void testIntegerToString(void) {
  test(integerToString(0), "0");
  test(integerToString(1234567), "1234567");
  test(integerToString(-17), "-17");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testIntegerToString>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <integerToString@plt>
  mov    %eax,%edi
  lea    D15(%rip),%rsi
  call   <test@plt>
  mov    $0x12d687,%edi
  call   <integerToString@plt>
  mov    %eax,%edi
  lea    D14(%rip),%rsi
  call   <test@plt>
  mov    $0xffffffef,%edi
  call   <integerToString@plt>
  mov    %eax,%edi
  lea    D23(%rip),%rsi
  call   <test@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D23
type_guessed: string

tool: D15: 0

tool: D14: 1234567

tool: D23: -17

assistant: ```c
void testIntegerToString(void) {
  test(integerToString(0), "0");
  test(integerToString(1234567), "1234567");
  test(integerToString(-17), "-17");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testIntegerToString>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <integerToString@plt>
  lea    D8(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x12d687,%edi
  call   <integerToString@plt>
  lea    D28(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0xffffffef,%edi
  call   <integerToString@plt>
  lea    D1(%rip),%rsi
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <test@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D28
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D8: 0

tool: D28: 1234567

tool: D1: -17

assistant: ```c
void testIntegerToString(void) {
  test(integerToString(0), "0");
  test(integerToString(1234567), "1234567");
  test(integerToString(-17), "-17");
}
```
user: Translate the below assembly code into C programming language:

```asm
<testIntegerToString>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <integerToString@plt>
  lea    D2(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0x12d687,%edi
  call   <integerToString@plt>
  lea    D11(%rip),%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    $0xffffffef,%edi
  call   <integerToString@plt>
  lea    D26(%rip),%rsi
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <test@plt>
```

tool_calls: name: read_data
arguments: label: D2
type: string
name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D26
type: string

tool: D2: 0

tool: D11: 1234567

tool: D26: -17

assistant: ```c
void testIntegerToString(void) {
  test(integerToString(0), "0");
  test(integerToString(1234567), "1234567");
  test(integerToString(-17), "-17");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L23:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  movl   $0x0,-0x8(%rbp)
  jmp    L51
L20:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x18(%rbp),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L13:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  imul   -0x8(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x18(%rbp),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x3b60,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  divsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  addl   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L20
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_array(int m, int n, double A[2100 + 0][1900 + 0], double r[2100 + 0], double p[1900 + 0]) {
  int i, j;
  for (i = 0; i < m; i++)
    p[i] = (double)(i % m) / m;
  for (i = 0; i < n; i++) {
    r[i] = (double)(i % n) / n;
    for (j = 0; j < m; j++)
      A[i][j] = (double)(i * (j + 1) % n) / n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r11d
  mov    %esi,%edi
  mov    %rdx,%r9
  mov    %rcx,%rbp
  test   %r11d,%r11d
  jle    L28
  mov    %r11d,%esi
  mov    $0x0,%ecx
  pxor   %xmm1,%xmm1
  cvtsi2sd %r11d,%xmm1
L51:
  mov    %ecx,%eax
  cltd
  idiv   %r11d
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rcx,8)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L51
L28:
  test   %edi,%edi
  jle    L10
  lea    -0x1(%r11),%ebx
  lea    0x8(%r9,%rbx,8),%r9
  mov    %edi,%r12d
  mov    $0x0,%r10d
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  not    %rbx
  shl    $0x3,%rbx
L25:
  mov    %r10d,%r8d
  mov    %r10d,%eax
  cltd
  idiv   %edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp,%r10,8)
  test   %r11d,%r11d
  jle    L22
  lea    (%rbx,%r9,1),%rsi
  mov    %r10d,%ecx
L46:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  add    %r8d,%ecx
  add    $0x8,%rsi
  cmp    %r9,%rsi
  jne    L46
L22:
  add    $0x1,%r10
  add    $0x3b60,%r9
  cmp    %r12,%r10
  jne    L25
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void init_array(int m, int n, double A[2100 + 0][1900 + 0], double r[2100 + 0], double p[1900 + 0]) {
  int i, j;
  for (i = 0; i < m; i++)
    p[i] = (double)(i % m) / m;
  for (i = 0; i < n; i++) {
    r[i] = (double)(i % n) / n;
    for (j = 0; j < m; j++)
      A[i][j] = (double)(i * (j + 1) % n) / n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_array>:
  endbr64
  mov    %edi,%r11d
  push   %r12
  mov    %esi,%edi
  mov    %rdx,%r9
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  test   %r11d,%r11d
  jle    L29
  pxor   %xmm1,%xmm1
  movslq %r11d,%rsi
  xor    %ecx,%ecx
  cvtsi2sd %r11d,%xmm1
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    %ecx,%eax
  pxor   %xmm0,%xmm0
  cltd
  idiv   %r11d
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rcx,8)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L56
L29:
  test   %edi,%edi
  jle    L24
  pxor   %xmm1,%xmm1
  lea    -0x1(%r11),%eax
  movslq %edi,%r12
  xor    %r10d,%r10d
  cvtsi2sd %edi,%xmm1
  shl    $0x3,%rax
  mov    $0xfffffffffffffff8,%rbp
  lea    0x8(%r9,%rax,1),%r8
  sub    %rax,%rbp
  xchg   %ax,%ax
L17:
  mov    %r10d,%eax
  pxor   %xmm0,%xmm0
  mov    %r10d,%r9d
  mov    %r10d,%ecx
  cltd
  lea    0x0(%rbp,%r8,1),%rsi
  idiv   %edi
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx,%r10,8)
  test   %r11d,%r11d
  jle    L11
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %ecx,%eax
  pxor   %xmm0,%xmm0
  add    $0x8,%rsi
  add    %r9d,%ecx
  cltd
  idiv   %edi
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rsi)
  cmp    %r8,%rsi
  jne    L43
L11:
  add    $0x1,%r10
  add    $0x3b60,%r8
  cmp    %r12,%r10
  jne    L17
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void init_array(int m, int n, double A[2100 + 0][1900 + 0], double r[2100 + 0], double p[1900 + 0]) {
  int i, j;
  for (i = 0; i < m; i++)
    p[i] = (double)(i % m) / m;
  for (i = 0; i < n; i++) {
    r[i] = (double)(i % n) / n;
    for (j = 0; j < m; j++)
      A[i][j] = (double)(i * (j + 1) % n) / n;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_array>:
  endbr64
  mov    %edi,%r11d
  push   %r12
  mov    %esi,%edi
  mov    %rdx,%r9
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  test   %r11d,%r11d
  jle    L26
  pxor   %xmm1,%xmm1
  movslq %r11d,%rsi
  xor    %ecx,%ecx
  cvtsi2sd %r11d,%xmm1
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    %ecx,%eax
  pxor   %xmm0,%xmm0
  cltd
  idiv   %r11d
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rcx,8)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L50
L26:
  test   %edi,%edi
  jle    L9
  pxor   %xmm1,%xmm1
  lea    -0x1(%r11),%eax
  movslq %edi,%r12
  xor    %r10d,%r10d
  cvtsi2sd %edi,%xmm1
  shl    $0x3,%rax
  mov    $0xfffffffffffffff8,%rbp
  lea    0x8(%r9,%rax,1),%r8
  sub    %rax,%rbp
  xchg   %ax,%ax
L16:
  mov    %r10d,%eax
  pxor   %xmm0,%xmm0
  mov    %r10d,%r9d
  mov    %r10d,%ecx
  cltd
  lea    0x0(%rbp,%r8,1),%rsi
  idiv   %edi
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx,%r10,8)
  test   %r11d,%r11d
  jle    L45
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %ecx,%eax
  pxor   %xmm0,%xmm0
  add    $0x8,%rsi
  add    %r9d,%ecx
  cltd
  idiv   %edi
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rsi)
  cmp    %rsi,%r8
  jne    L32
L45:
  add    $0x1,%r10
  add    $0x3b60,%r8
  cmp    %r12,%r10
  jne    L16
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void init_array(int m, int n, double A[2100 + 0][1900 + 0], double r[2100 + 0], double p[1900 + 0]) {
  int i, j;
  for (i = 0; i < m; i++)
    p[i] = (double)(i % m) / m;
  for (i = 0; i < n; i++) {
    r[i] = (double)(i % n) / n;
    for (j = 0; j < m; j++)
      A[i][j] = (double)(i * (j + 1) % n) / n;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bbm_com_word_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movzwl -0x20(%rbp),%edx
  movzwl -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bbm_word_write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int bbm_com_word_write(void *handle, unsigned short addr, unsigned short data) {
  int res;
  res = bbm_word_write(handle, addr, data);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bbm_com_word_write>:
  endbr64
  sub    $0x8,%rsp
  movzwl %dx,%edx
  movzwl %si,%esi
  call   <bbm_word_write@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bbm_com_word_write(void *handle, unsigned short addr, unsigned short data) {
  int res;
  res = bbm_word_write(handle, addr, data);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bbm_com_word_write>:
  endbr64
  movzwl %dx,%edx
  movzwl %si,%esi
  jmp    1050 <bbm_word_write@plt>
```

assistant: ```c
int bbm_com_word_write(void *handle, unsigned short addr, unsigned short data) {
  int res;
  res = bbm_word_write(handle, addr, data);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bbm_com_word_write>:
  endbr64
  movzwl %dx,%edx
  movzwl %si,%esi
  jmp    1050 <bbm_word_write@plt>
```

assistant: ```c
int bbm_com_word_write(void *handle, unsigned short addr, unsigned short data) {
  int res;
  res = bbm_word_write(handle, addr, data);
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L21
L2:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L43
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jle    L21
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L21
L43:
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D31
type_infered: string
name: read_data
arguments: data_tag: D33
type_infered: string
name: read_data
arguments: data_tag: D29
type_infered: string

tool: D31: Number: 

tool: D33: %d

tool: D29: %d = 

assistant: ```c
int main() {
  int n, d;
  printf("Number: ");
  scanf("%d", &n);
  printf("%d = ", n);
  for (d = 2; d <= n;) {
    if ((n % d) == 0) {
      printf("%d", d);
      n /= d;
      if (n > 1)
        printf("*");
    } else
      d++;
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jle    L18
  mov    $0x2,%ebx
  lea    D12(%rip),%rbp
  jmp    L7
L68:
  add    $0x1,%ebx
L8:
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  jg     L18
L7:
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L68
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ebx
  mov    %eax,0x4(%rsp)
  cmp    $0x1,%eax
  jle    L8
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L8
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D21
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D30
datatype: string

tool: D21: Number: 

tool: D12: %d

tool: D30: %d = 

assistant: ```c
int main() {
  int n, d;
  printf("Number: ");
  scanf("%d", &n);
  printf("%d = ", n);
  for (d = 2; d <= n;) {
    if ((n % d) == 0) {
      printf("%d", d);
      n /= d;
      if (n > 1)
        printf("*");
    } else
      d++;
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  cmp    $0x1,%ecx
  jg     L7
  jmp    L29
  nopl   0x0(%rax)
L53:
  add    $0x1,%ebx
L12:
  cmp    %ecx,%ebx
  jg     L29
L7:
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L53
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ebx
  mov    %eax,0x4(%rsp)
  cmp    $0x1,%eax
  jg     L11
L29:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L11:
  mov    $0x2a,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%ecx
  jmp    L12
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
datatype: string
name: parse_data
arguments: tag: D2
datatype: string
name: parse_data
arguments: tag: D10
datatype: string

tool: D15: Number: 

tool: D2: %d

tool: D10: %d = 

assistant: ```c
int main() {
  int n, d;
  printf("Number: ");
  scanf("%d", &n);
  printf("%d = ", n);
  for (d = 2; d <= n;) {
    if ((n % d) == 0) {
      printf("%d", d);
      n /= d;
      if (n > 1)
        printf("*");
    } else
      d++;
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  cmp    $0x1,%ecx
  jg     L43
  jmp    L32
  nopl   0x0(%rax)
L1:
  add    $0x1,%ebx
L4:
  cmp    %ecx,%ebx
  jg     L32
L43:
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L1
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ebx
  mov    %eax,0x4(%rsp)
  cmp    $0x1,%eax
  jg     L2
L32:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L2:
  mov    $0x2a,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%ecx
  jmp    L4
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D29
datatype: string

tool: D11: Number: 

tool: D3: %d

tool: D29: %d = 

assistant: ```c
int main() {
  int n, d;
  printf("Number: ");
  scanf("%d", &n);
  printf("%d = ", n);
  for (d = 2; d <= n;) {
    if ((n % d) == 0) {
      printf("%d", d);
      n /= d;
      if (n > 1)
        printf("*");
    } else
      d++;
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<IL_re_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    -0x18(%rbp),%edi
  mov    -0x14(%rbp),%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x14(%rbp),%ecx
  push   %rcx
  push   -0x28(%rbp)
  mov    -0x1c(%rbp),%ecx
  push   %rcx
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <IL_re_search_2@plt>
  add    $0x20,%rsp
  leave
  ret
```

assistant: ```c
int IL_re_search(bufp, string, size, startpos, range, regs)
struct re_pattern_buffer *bufp;
const char *string;
int size, startpos, range;
struct re_registers *regs;
{
  return IL_re_search_2(bufp, (void *)0, 0, string, size, startpos, range, regs, size);
}
```