ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__map_file>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    D36(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D59(%rip),%rax
  mov    0x0(%rbp),%r12
  mov    (%rax),%esi
  mov    D5(%rip),%rax
  or     (%rax),%esi
  mov    D16(%rip),%rax
  or     (%rax),%esi
  call   <__sys_open@plt>
  test   %eax,%eax
  js     L16
  mov    %eax,%r13d
  mov    %eax,%esi
  mov    %rsp,%rdx
  xor    %eax,%eax
  mov    $0x6c,%edi
  call   <__syscall@plt>
  test   %eax,%eax
  je     L27
L0:
  mov    %r13d,%esi
  mov    $0x6,%edi
  xor    %eax,%eax
  call   <__syscall@plt>
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  cmp    %r12,0x0(%rbp)
  je     L16
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r12d,%r12d
  jmp    L3
  nopl   (%rax)
L27:
  mov    D7(%rip),%rax
  mov    (%rsp),%rsi
  xor    %r9d,%r9d
  xor    %edi,%edi
  mov    %r13d,%r8d
  mov    (%rax),%ecx
  mov    D34(%rip),%rax
  mov    (%rax),%edx
  call   <__mmap@plt>
  mov    %rax,%r12
  jmp    L0
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char unsigned *__map_file(const char *pathname, size_t *size) {
  struct stat st;
  const unsigned char *map = MAP_FAILED;
  int fd = __sys_open(pathname, O_RDONLY | O_CLOEXEC | O_NONBLOCK);
  if (fd < 0)
    return 0;
  if (!__syscall(108, fd, &st))
    map = __mmap(0, st.st_size, PROT_READ, MAP_SHARED, fd, 0);
  __syscall(6, fd);
  *size = st.st_size;
  return map == MAP_FAILED ? 0 : map;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__map_file>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    D14(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D25(%rip),%rax
  mov    0x0(%rbp),%r12
  mov    (%rax),%esi
  mov    D47(%rip),%rax
  or     (%rax),%esi
  mov    D18(%rip),%rax
  or     (%rax),%esi
  call   <__sys_open@plt>
  test   %eax,%eax
  js     L45
  mov    %eax,%r13d
  mov    %eax,%esi
  mov    %rsp,%rdx
  xor    %eax,%eax
  mov    $0x6c,%edi
  call   <__syscall@plt>
  test   %eax,%eax
  je     L58
L11:
  mov    %r13d,%esi
  mov    $0x6,%edi
  xor    %eax,%eax
  call   <__syscall@plt>
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  cmp    %r12,0x0(%rbp)
  je     L45
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %r12d,%r12d
  jmp    L33
  nopl   (%rax)
L58:
  mov    D3(%rip),%rax
  mov    (%rsp),%rsi
  xor    %r9d,%r9d
  xor    %edi,%edi
  mov    %r13d,%r8d
  mov    (%rax),%ecx
  mov    D55(%rip),%rax
  mov    (%rax),%edx
  call   <__mmap@plt>
  mov    %rax,%r12
  jmp    L11
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char unsigned *__map_file(const char *pathname, size_t *size) {
  struct stat st;
  const unsigned char *map = MAP_FAILED;
  int fd = __sys_open(pathname, O_RDONLY | O_CLOEXEC | O_NONBLOCK);
  if (fd < 0)
    return 0;
  if (!__syscall(108, fd, &st))
    map = __mmap(0, st.st_size, PROT_READ, MAP_SHARED, fd, 0);
  __syscall(6, fd);
  *size = st.st_size;
  return map == MAP_FAILED ? 0 : map;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L24
L31:
  lea    -0x30(%rbp),%rcx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    $0x8,%rax
  add    %rax,%rcx
  lea    -0x30(%rbp),%rsi
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    $0x4,%rax
  lea    (%rsi,%rax,1),%rdx
  lea    -0x30(%rbp),%rdi
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rsi
  mov    %rsi,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rdi,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x3c(%rbp)
L24:
  cmpl   $0x2,-0x3c(%rbp)
  jle    L31
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <move1@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L4
L16:
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x28,%rax
  mov    (%rax),%ecx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x2c,%rax
  mov    (%rax),%edx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rsi
  mov    %rsi,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x30,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L4:
  cmpl   $0x2,-0x3c(%rbp)
  jle    L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D22: input matrix:

tool: D0: %d %d %d

tool: D37: now,matrix:

tool: D6: %d %d %d


assistant: ```c
int main() {
  void move1(int *);
  int a[3][3];
  int *p;
  int i;
  printf("input matrix:\n");
  for (i = 0; i < 3; i++)
    scanf("%d %d %d", &a[i][0], &a[i][1], &a[i][2]);
  p = &a[0][0];
  move1(p);
  printf("now,matrix:\n");
  for (i = 0; i < 3; i++)
    printf("%d %d %d\n", a[i][0], a[i][1], a[i][2]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rbx,%rsi
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x20(%rsp),%rcx
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <move1@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    0x24(%rsp),%r12
  lea    D32(%rip),%rbp
L4:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0xc,%rbx
  cmp    %r12,%rbx
  jne    L4
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D7
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D32
type_guessed: string

tool: D37: input matrix:

tool: D7: %d %d %d

tool: D29: now,matrix:

tool: D32: %d %d %d


assistant: ```c
int main() {
  void move1(int *);
  int a[3][3];
  int *p;
  int i;
  printf("input matrix:\n");
  for (i = 0; i < 3; i++)
    scanf("%d %d %d", &a[i][0], &a[i][1], &a[i][2]);
  p = &a[0][0];
  move1(p);
  printf("now,matrix:\n");
  for (i = 0; i < 3; i++)
    printf("%d %d %d\n", a[i][0], a[i][1], a[i][2]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  lea    D2(%rip),%rdi
  lea    D4(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x24(%rsp),%r12
  call   <puts@plt>
  mov    %r13,%rbx
  mov    %r13,%rbp
L24:
  lea    0x8(%rbp),%rcx
  lea    0x4(%rbp),%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0xc,%rbp
  cmp    %r12,%rbp
  jne    L24
  mov    %r13,%rdi
  lea    D10(%rip),%rbp
  call   <move1@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
L11:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    (%rbx),%esi
  add    $0xc,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string

tool: D2: input matrix:

tool: D4: %d %d %d

tool: D10: %d %d %d


tool: D1: now,matrix:

assistant: ```c
int main() {
  void move1(int *);
  int a[3][3];
  int *p;
  int i;
  printf("input matrix:\n");
  for (i = 0; i < 3; i++)
    scanf("%d %d %d", &a[i][0], &a[i][1], &a[i][2]);
  p = &a[0][0];
  move1(p);
  printf("now,matrix:\n");
  for (i = 0; i < 3; i++)
    printf("%d %d %d\n", a[i][0], a[i][1], a[i][2]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  lea    D23(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x24(%rsp),%r12
  call   <puts@plt>
  mov    %r13,%rbx
  mov    %r13,%rbp
L26:
  lea    0x8(%rbp),%rcx
  lea    0x4(%rbp),%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0xc,%rbp
  cmp    %r12,%rbp
  jne    L26
  mov    %r13,%rdi
  lea    D10(%rip),%rbp
  call   <move1@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
L8:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    (%rbx),%esi
  add    $0xc,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D10
type_guessed: string
name: unpack_data
arguments: data_tag: D26
type_guessed: string

tool: D0: input matrix:

tool: D23: %d %d %d

tool: D10: %d %d %d


tool: D26: now,matrix:

assistant: ```c
int main() {
  void move1(int *);
  int a[3][3];
  int *p;
  int i;
  printf("input matrix:\n");
  for (i = 0; i < 3; i++)
    scanf("%d %d %d", &a[i][0], &a[i][1], &a[i][2]);
  p = &a[0][0];
  move1(p);
  printf("now,matrix:\n");
  for (i = 0; i < 3; i++)
    printf("%d %d %d\n", a[i][0], a[i][1], a[i][2]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<od_rsqrt_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x10,-0x4(%rbp)
  jg     L10
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D4(%rip),%rax
  movsd  (%rdx,%rax,1),%xmm0
  jmp    L11
L10:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D3(%rip),%xmm0
  divsd  %xmm1,%xmm0
L11:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: f64

tool: D3: 1

assistant: ```c
double od_rsqrt_table(int i) {
  static double table[16] = {1.000000, 0.707107, 0.577350, 0.500000, 0.447214, 0.408248, 0.377964, 0.353553, 0.333333, 0.316228, 0.301511, 0.288675, 0.277350, 0.267261, 0.258199, 0.250000};
  if (i <= 16)
    return table[i - 1];
  else
    return 1. / sqrt(i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<od_rsqrt_table>:
  endbr64
  cmp    $0x10,%edi
  jg     L9
  sub    $0x1,%edi
  movslq %edi,%rdi
  lea    D4(%rip),%rax
  movsd  (%rax,%rdi,8),%xmm0
  ret
L9:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D13(%rip),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: f64
name: parse_data
arguments: data_label: D13
datatype: f64

tool: D4: 1

tool: D13: 1

assistant: ```c
double od_rsqrt_table(int i) {
  static double table[16] = {1.000000, 0.707107, 0.577350, 0.500000, 0.447214, 0.408248, 0.377964, 0.353553, 0.333333, 0.316228, 0.301511, 0.288675, 0.277350, 0.267261, 0.258199, 0.250000};
  if (i <= 16)
    return table[i - 1];
  else
    return 1. / sqrt(i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<od_rsqrt_table>:
  endbr64
  cmp    $0x10,%edi
  jg     L9
  sub    $0x1,%edi
  lea    D18(%rip),%rax
  movslq %edi,%rdi
  movsd  (%rax,%rdi,8),%xmm0
  ret
  nopl   0x0(%rax)
L9:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movsd  D0(%rip),%xmm0
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
data_type: f64
name: disassemble_data
arguments: tag: D0
data_type: f64

tool: D18: 1

tool: D0: 1

assistant: ```c
double od_rsqrt_table(int i) {
  static double table[16] = {1.000000, 0.707107, 0.577350, 0.500000, 0.447214, 0.408248, 0.377964, 0.353553, 0.333333, 0.316228, 0.301511, 0.288675, 0.277350, 0.267261, 0.258199, 0.250000};
  if (i <= 16)
    return table[i - 1];
  else
    return 1. / sqrt(i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<od_rsqrt_table>:
  endbr64
  cmp    $0x10,%edi
  jg     L4
  sub    $0x1,%edi
  lea    D9(%rip),%rax
  movslq %edi,%rdi
  movsd  (%rax,%rdi,8),%xmm0
  ret
  nopl   0x0(%rax)
L4:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movsd  D17(%rip),%xmm0
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: f64
name: retrieve_data
arguments: data_label: D17
type: f64

tool: D9: 1

tool: D17: 1

assistant: ```c
double od_rsqrt_table(int i) {
  static double table[16] = {1.000000, 0.707107, 0.577350, 0.500000, 0.447214, 0.408248, 0.377964, 0.353553, 0.333333, 0.316228, 0.301511, 0.288675, 0.277350, 0.267261, 0.258199, 0.250000};
  if (i <= 16)
    return table[i - 1];
  else
    return 1. / sqrt(i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movl   $0x40,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L7
L5:
  mov    $0x0,%eax
  call   <random@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  mov    $0x0,%eax
  call   <random@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  addl   $0x1,-0x2c(%rbp)
L7:
  mov    -0x2c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L5
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%rdi
  mov    -0x20(%rbp),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x1c(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <add@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  const int size = 64;
  int sizeBytes = size * sizeof(int32_t);
  int32_t *x = malloc(sizeBytes);
  int32_t *y = malloc(sizeBytes);
  int32_t *s = malloc(sizeBytes);
  int scalar = 3;
  for (int i = 0; i < size; ++i) {
    x[i] = random() % 100;
    y[i] = random() % 100;
  }
  int ticks = size;
  add(ticks, x, y, scalar, s);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ebx
L6:
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%rbx,1)
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%r12,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x100,%rbx
  jne    L6
  mov    %r13,%r8
  mov    $0x3,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x40,%edi
  call   <add@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(void) {
  const int size = 64;
  int sizeBytes = size * sizeof(int32_t);
  int32_t *x = malloc(sizeBytes);
  int32_t *y = malloc(sizeBytes);
  int32_t *s = malloc(sizeBytes);
  int scalar = 3;
  for (int i = 0; i < size; ++i) {
    x[i] = random() % 100;
    y[i] = random() % 100;
  }
  int ticks = size;
  add(ticks, x, y, scalar, s);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x100,%edi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%r13,1)
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%r12,%r13,1)
  add    $0x4,%r13
  cmp    $0x100,%r13
  jne    L9
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%ecx
  mov    $0x40,%edi
  call   <add@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(void) {
  const int size = 64;
  int sizeBytes = size * sizeof(int32_t);
  int32_t *x = malloc(sizeBytes);
  int32_t *y = malloc(sizeBytes);
  int32_t *s = malloc(sizeBytes);
  int scalar = 3;
  for (int i = 0; i < size; ++i) {
    x[i] = random() % 100;
    y[i] = random() % 100;
  }
  int ticks = size;
  add(ticks, x, y, scalar, s);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x100,%edi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%r13,1)
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%r12,%r13,1)
  add    $0x4,%r13
  cmp    $0x100,%r13
  jne    L1
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%ecx
  mov    $0x40,%edi
  call   <add@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(void) {
  const int size = 64;
  int sizeBytes = size * sizeof(int32_t);
  int32_t *x = malloc(sizeBytes);
  int32_t *y = malloc(sizeBytes);
  int32_t *s = malloc(sizeBytes);
  int scalar = 3;
  for (int i = 0; i < size; ++i) {
    x[i] = random() % 100;
    y[i] = random() % 100;
  }
  int ticks = size;
  add(ticks, x, y, scalar, s);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<middle_trsp_blk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    -0x70(%rbp),%rbx
  lea    -0x1(%rbx),%rax
  mov    %rax,-0x50(%rbp)
  mov    %rbx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movq   $0x0,-0x60(%rbp)
  jmp    L21
L9:
  movq   $0x0,-0x58(%rbp)
  jmp    L1
L4:
  mov    -0x70(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    %rbx,%rdx
  mov    -0x58(%rbp),%rax
  imul   %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x60(%rbp),%rax
  shl    $0x4,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x70(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    %rbx,%rdx
  mov    -0x60(%rbp),%rax
  imul   %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x58(%rbp),%rax
  shl    $0x4,%rax
  add    %rax,%rdx
  mov    -0x70(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <micro_trsp_swap@plt>
  addq   $0x4,-0x58(%rbp)
L1:
  mov    -0x58(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  jl     L4
  mov    -0x70(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  mov    %rax,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  mov    %rbx,%rdx
  mov    -0x60(%rbp),%rax
  imul   %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  mov    -0x60(%rbp),%rax
  shl    $0x4,%rax
  add    %rax,%rdx
  mov    -0x70(%rbp),%rcx
  mov    -0x68(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <micro_trsp_blk@plt>
  addq   $0x4,-0x60(%rbp)
L21:
  cmpq   $0x7,-0x60(%rbp)
  jle    L9
  nop
  nop
  add    $0x68,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void middle_trsp_blk(long N, long N_SQRT, double _Complex data[N_SQRT][N_SQRT]) {
  long i, j;
  for (i = 0; i < 8; i += 4) {
    for (j = 0; j < i; j += 4) {
      micro_trsp_swap(N, N_SQRT, (double _Complex(*)[N_SQRT]) & data[i][j], (double _Complex(*)[N_SQRT]) & data[j][i]);
    }
    micro_trsp_blk(N, N_SQRT, (double _Complex(*)[N_SQRT]) & data[i][i]);
  }
}
```