ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Separa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L9
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L25
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L25:
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L18
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Separa(int p, int r, int v[]) {
  int c, j, k, t;
  c = v[r];
  j = p;
  for (k = p; k < r; k++)
    if (v[k] <= c) {
      t = v[j], v[j] = v[k], v[k] = t;
      j++;
    }
  v[r] = v[j], v[j] = c;
  return (j);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Separa>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  movslq %esi,%rdx
  lea    (%rdi,%rdx,4),%r11
  mov    (%r11),%r8d
  cmp    %eax,%esi
  jle    L44
  movslq %eax,%r9
  lea    (%rdi,%r9,4),%rdx
  sub    %eax,%esi
  lea    -0x1(%rsi),%ecx
  add    %r9,%rcx
  lea    0x4(%rdi,%rcx,4),%r9
  jmp    L42
L41:
  add    $0x4,%rdx
  cmp    %r9,%rdx
  je     L44
L42:
  mov    (%rdx),%ecx
  cmp    %r8d,%ecx
  jg     L41
  movslq %eax,%rsi
  lea    (%rdi,%rsi,4),%rsi
  mov    (%rsi),%r10d
  mov    %ecx,(%rsi)
  mov    %r10d,(%rdx)
  add    $0x1,%eax
  jmp    L41
L44:
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%r11)
  mov    %r8d,(%rdx)
  ret
```

assistant: ```c
int Separa(int p, int r, int v[]) {
  int c, j, k, t;
  c = v[r];
  j = p;
  for (k = p; k < r; k++)
    if (v[k] <= c) {
      t = v[j], v[j] = v[k], v[k] = t;
      j++;
    }
  v[r] = v[j], v[j] = c;
  return (j);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Separa>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  movslq %esi,%rdx
  lea    (%rdi,%rdx,4),%r11
  mov    (%r11),%r8d
  cmp    %eax,%esi
  jle    L3
  sub    %eax,%esi
  movslq %eax,%r9
  lea    -0x1(%rsi),%ecx
  lea    (%rdi,%r9,4),%rdx
  add    %r9,%rcx
  lea    0x4(%rdi,%rcx,4),%r9
  nopl   0x0(%rax,%rax,1)
L15:
  mov    (%rdx),%ecx
  cmp    %r8d,%ecx
  jg     L29
  movslq %eax,%rsi
  add    $0x1,%eax
  lea    (%rdi,%rsi,4),%rsi
  mov    (%rsi),%r10d
  mov    %ecx,(%rsi)
  mov    %r10d,(%rdx)
L29:
  add    $0x4,%rdx
  cmp    %r9,%rdx
  jne    L15
L3:
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%r11)
  mov    %r8d,(%rdx)
  ret
```

assistant: ```c
int Separa(int p, int r, int v[]) {
  int c, j, k, t;
  c = v[r];
  j = p;
  for (k = p; k < r; k++)
    if (v[k] <= c) {
      t = v[j], v[j] = v[k], v[k] = t;
      j++;
    }
  v[r] = v[j], v[j] = c;
  return (j);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Separa>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  movslq %esi,%rdx
  lea    (%rdi,%rdx,4),%r11
  mov    (%r11),%r8d
  cmp    %eax,%esi
  jle    L23
  sub    %eax,%esi
  movslq %eax,%r9
  lea    -0x1(%rsi),%ecx
  lea    (%rdi,%r9,4),%rdx
  add    %r9,%rcx
  lea    0x4(%rdi,%rcx,4),%r9
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%rdx),%ecx
  cmp    %r8d,%ecx
  jg     L9
  movslq %eax,%rsi
  add    $0x1,%eax
  lea    (%rdi,%rsi,4),%rsi
  mov    (%rsi),%r10d
  mov    %ecx,(%rsi)
  mov    %r10d,(%rdx)
L9:
  add    $0x4,%rdx
  cmp    %rdx,%r9
  jne    L14
L23:
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%r11)
  mov    %r8d,(%rdx)
  ret
```

assistant: ```c
int Separa(int p, int r, int v[]) {
  int c, j, k, t;
  c = v[r];
  j = p;
  for (k = p; k < r; k++)
    if (v[k] <= c) {
      t = v[j], v[j] = v[k], v[k] = t;
      j++;
    }
  v[r] = v[j], v[j] = c;
  return (j);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void delay(const unsigned int nanosecs) {
  struct timespec t;
  t.tv_sec = 0;
  t.tv_nsec = nanosecs;
  nanosleep(&t, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delay>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void delay(const unsigned int nanosecs) {
  struct timespec t;
  t.tv_sec = 0;
  t.tv_nsec = nanosecs;
  nanosleep(&t, NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<delay>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  movq   $0x0,0x8(%rsp)
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void delay(const unsigned int nanosecs) {
  struct timespec t;
  t.tv_sec = 0;
  t.tv_nsec = nanosecs;
  nanosleep(&t, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delay>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  movq   $0x0,0x8(%rsp)
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void delay(const unsigned int nanosecs) {
  struct timespec t;
  t.tv_sec = 0;
  t.tv_nsec = nanosecs;
  nanosleep(&t, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L2
L19:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <wputchar@plt>
L2:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void wputs(struct Window *win, char *msg) {
  while (*msg) {
    wputchar(win, *msg++);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wputs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L17
L2:
  add    $0x1,%rbx
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <wputchar@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L2
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void wputs(struct Window *win, char *msg) {
  while (*msg) {
    wputchar(win, *msg++);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wputs>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L16
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rbx
  mov    %rbp,%rdi
  call   <wputchar@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L5
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void wputs(struct Window *win, char *msg) {
  while (*msg) {
    wputchar(win, *msg++);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wputs>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L18
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rbx
  mov    %rbp,%rdi
  call   <wputchar@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L16
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void wputs(struct Window *win, char *msg) {
  while (*msg) {
    wputchar(win, *msg++);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cmpl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    $0x1,%eax
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    $0x3,%eax
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    $0x1,%eax
  cmpl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  cmpl   $0x3,-0x4(%rbp)
  ja     L8
  nop
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test7() {
  enum { A = 1, B } a;
  switch (a) {
  case A:
    break;
  }
  switch (a) {
  case B:
  case A:
    break;
  }
  switch (a) {
  case A:
  case B:
  case 3:
    break;
  }
  switch (a) {
  case A:
  case B:
  case 3 ... 4:
    break;
  }
  switch (a) {
  case 1 ... 2:
    break;
  }
  switch (a) {
  case 0 ... 2:
    break;
  }
  switch (a) {
  case 1 ... 3:
    break;
  }
  switch (a) {
  case 0 ... 3:
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test7>:
  endbr64
  ret
```

assistant: ```c
void test7() {
  enum { A = 1, B } a;
  switch (a) {
  case A:
    break;
  }
  switch (a) {
  case B:
  case A:
    break;
  }
  switch (a) {
  case A:
  case B:
  case 3:
    break;
  }
  switch (a) {
  case A:
  case B:
  case 3 ... 4:
    break;
  }
  switch (a) {
  case 1 ... 2:
    break;
  }
  switch (a) {
  case 0 ... 2:
    break;
  }
  switch (a) {
  case 1 ... 3:
    break;
  }
  switch (a) {
  case 0 ... 3:
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test7>:
  endbr64
  ret
```

assistant: ```c
void test7() {
  enum { A = 1, B } a;
  switch (a) {
  case A:
    break;
  }
  switch (a) {
  case B:
  case A:
    break;
  }
  switch (a) {
  case A:
  case B:
  case 3:
    break;
  }
  switch (a) {
  case A:
  case B:
  case 3 ... 4:
    break;
  }
  switch (a) {
  case 1 ... 2:
    break;
  }
  switch (a) {
  case 0 ... 2:
    break;
  }
  switch (a) {
  case 1 ... 3:
    break;
  }
  switch (a) {
  case 0 ... 3:
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test7>:
  endbr64
  ret
```

assistant: ```c
void test7() {
  enum { A = 1, B } a;
  switch (a) {
  case A:
    break;
  }
  switch (a) {
  case B:
  case A:
    break;
  }
  switch (a) {
  case A:
  case B:
  case 3:
    break;
  }
  switch (a) {
  case A:
  case B:
  case 3 ... 4:
    break;
  }
  switch (a) {
  case 1 ... 2:
    break;
  }
  switch (a) {
  case 0 ... 2:
    break;
  }
  switch (a) {
  case 1 ... 3:
    break;
  }
  switch (a) {
  case 0 ... 3:
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L1:
  cmp    %rdx,%rsp
  je     L3
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L1
L3:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L18
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L18:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0xa,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <b@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void a(int x) {
  char arry[x];
  arry[0] = 10;
  b(arry);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rdi
  add    $0xf,%rdi
  mov    %rdi,%rdx
  and    $0xfffffffffffffff0,%rdx
  and    $0xfffffffffffff000,%rdi
  mov    %rsp,%rax
  sub    %rdi,%rax
L6:
  cmp    %rax,%rsp
  je     L14
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L14:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L35
  orq    $0x0,-0x8(%rsp,%rax,1)
L35:
  movb   $0xa,(%rsp)
  mov    %rsp,%rdi
  call   <b@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  leave
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void a(int x) {
  char arry[x];
  arry[0] = 10;
  b(arry);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<a>:
  endbr64
  push   %rbp
  movslq %edi,%rdi
  add    $0xf,%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %rdi,%rax
  and    $0xfffffffffffff000,%rdi
  sub    %rdi,%rdx
  and    $0xfffffffffffffff0,%rax
  cmp    %rdx,%rsp
  je     L0
L22:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L22
L0:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L14
L21:
  mov    %rsp,%rdi
  movb   $0xa,(%rsp)
  call   <b@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L21
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void a(int x) {
  char arry[x];
  arry[0] = 10;
  b(arry);
}
```
user: Translate the below assembly code into C programming language:

```asm
<a>:
  endbr64
  push   %rbp
  movslq %edi,%rdi
  add    $0xf,%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %rdi,%rax
  and    $0xfffffffffffff000,%rdi
  sub    %rdi,%rdx
  and    $0xfffffffffffffff0,%rax
  cmp    %rdx,%rsp
  je     L45
L3:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L3
L45:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L39
L47:
  mov    %rsp,%rdi
  movb   $0xa,(%rsp)
  call   <b@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L47
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void a(int x) {
  char arry[x];
  arry[0] = 10;
  b(arry);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L17:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L1:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L17
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(destaddr, srcaddr, len) void *destaddr;
const void *srcaddr;
unsigned int len;
{
  char *dest = (char *)destaddr;
  const char *src = srcaddr;
  while (len-- > 0)
    *dest++ = *src++;
  return destaddr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edi
  test   %edx,%edx
  je     L12
  mov    %edi,%edi
  mov    $0x0,%edx
L16:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  jne    L16
L12:
  ret
```

assistant: ```c
void *memcpy(destaddr, srcaddr, len) void *destaddr;
const void *srcaddr;
unsigned int len;
{
  char *dest = (char *)destaddr;
  const char *src = srcaddr;
  while (len-- > 0)
    *dest++ = *src++;
  return destaddr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L15
  mov    %edx,%edx
  xor    %ecx,%ecx
  nop
L14:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L14
L15:
  ret
```

assistant: ```c
void *memcpy(destaddr, srcaddr, len) void *destaddr;
const void *srcaddr;
unsigned int len;
{
  char *dest = (char *)destaddr;
  const char *src = srcaddr;
  while (len-- > 0)
    *dest++ = *src++;
  return destaddr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%r10d
  test   %edx,%edx
  je     L65
  lea    0x1(%rsi),%rsi
  mov    %rdi,%rax
  sub    %rsi,%rax
  cmp    $0xe,%rax
  jbe    L30
  cmp    $0x6,%r10d
  jbe    L30
  cmp    $0xe,%r10d
  jbe    L76
  mov    %edx,%esi
  xor    %eax,%eax
  shr    $0x4,%esi
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L108:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L108
  mov    %edx,%r9d
  and    $0xfffffff0,%r9d
  mov    %r9d,%edi
  sub    %r9d,%r10d
  lea    (%r8,%rdi,1),%rax
  lea    (%rcx,%rdi,1),%rsi
  cmp    %r9d,%edx
  je     L65
  sub    %r9d,%edx
  lea    -0x1(%rdx),%r9d
  cmp    $0x6,%r9d
  jbe    L81
L89:
  mov    (%rcx,%rdi,1),%rcx
  mov    %rcx,(%r8,%rdi,1)
  mov    %edx,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%edi
  sub    %ecx,%r10d
  add    %rdi,%rax
  add    %rdi,%rsi
  cmp    %ecx,%edx
  je     L65
L81:
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  test   %r10d,%r10d
  je     L65
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  cmp    $0x1,%r10d
  je     L65
  movzbl 0x2(%rsi),%edx
  mov    %dl,0x2(%rax)
  cmp    $0x2,%r10d
  je     L65
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x3(%rax)
  cmp    $0x3,%r10d
  je     L65
  movzbl 0x4(%rsi),%edx
  mov    %dl,0x4(%rax)
  cmp    $0x4,%r10d
  je     L65
  movzbl 0x5(%rsi),%edx
  mov    %dl,0x5(%rax)
  cmp    $0x5,%r10d
  je     L65
  movzbl 0x6(%rsi),%edx
  mov    %dl,0x6(%rax)
L65:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L30:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L80:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L80
  mov    %r8,%rax
  ret
L76:
  mov    %rdi,%rax
  mov    %rcx,%rsi
  xor    %edi,%edi
  jmp    L89
```

assistant: ```c
void *memcpy(destaddr, srcaddr, len) void *destaddr;
const void *srcaddr;
unsigned int len;
{
  char *dest = (char *)destaddr;
  const char *src = srcaddr;
  while (len-- > 0)
    *dest++ = *src++;
  return destaddr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isfloat2>:
  endbr64
  mov    %rdi,%rdx
  movzbl (%rdi),%eax
  mov    $0x0,%esi
  test   %al,%al
  je     L60
  sub    $0x2b,%eax
  test   $0xfd,%al
  sete   %cl
  movzbl %cl,%ecx
  sete   %al
  movzbl %al,%eax
  movzbl (%rdi,%rax,1),%esi
  lea    -0x30(%rsi),%eax
  cmp    $0x9,%al
  ja     L22
  lea    0x1(%rcx),%eax
  cltq
L40:
  mov    %eax,%ecx
  movzbl (%rdx,%rax,1),%esi
  add    $0x1,%rax
  lea    -0x30(%rsi),%edi
  cmp    $0x9,%dil
  jbe    L40
  mov    $0x1,%edi
L90:
  cmp    $0x2e,%sil
  je     L56
L123:
  movslq %ecx,%rax
  movzbl (%rdx,%rax,1),%eax
  and    $0xffffffdf,%eax
  mov    $0x1,%r8d
  cmp    $0x45,%al
  jne    L98
  lea    0x1(%rcx),%esi
  movslq %esi,%rsi
  movzbl (%rdx,%rsi,1),%eax
  sub    $0x2b,%eax
  test   $0xfd,%al
  sete   %sil
  movzbl %sil,%esi
  lea    0x1(%rsi,%rcx,1),%esi
  movslq %esi,%rax
  movzbl (%rdx,%rax,1),%ecx
  sub    $0x30,%ecx
  lea    0x1(%rsi),%eax
  cltq
  cmp    $0x9,%cl
  ja     L124
L43:
  mov    %eax,%ecx
  movzbl (%rdx,%rax,1),%esi
  sub    $0x30,%esi
  add    $0x1,%rax
  cmp    $0x9,%sil
  jbe    L43
  mov    $0x1,%r8d
L98:
  movslq %ecx,%rax
  movzbl (%rdx,%rax,1),%eax
  and    $0xffffffdf,%eax
  cmp    $0x4c,%al
  je     L10
  cmp    $0x46,%al
  jne    L81
L10:
  add    $0x1,%ecx
L81:
  movslq %ecx,%rcx
  mov    $0x0,%esi
  cmpb   $0x0,(%rdx,%rcx,1)
  jne    L60
  mov    %r8d,%esi
  and    %edi,%esi
L60:
  mov    %esi,%eax
  ret
L22:
  mov    $0x0,%edi
  jmp    L90
L56:
  lea    0x1(%rcx),%esi
  movslq %esi,%rax
  movzbl (%rdx,%rax,1),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L132
  lea    0x2(%rcx),%eax
  cltq
L1:
  mov    %eax,%ecx
  movzbl (%rdx,%rax,1),%edi
  lea    -0x30(%rdi),%esi
  add    $0x1,%rax
  cmp    $0x9,%sil
  jbe    L1
  mov    $0x1,%edi
  jmp    L123
L132:
  mov    %esi,%ecx
  jmp    L123
L124:
  mov    %esi,%ecx
  mov    $0x0,%r8d
  jmp    L98
```

assistant: ```c
int isfloat2(char *c) {
  int isnum = 0, wfe = 1;
  int i = 0;
  if (strlen(c) == 0)
    return (0);
  if ((c[i] == '+') || (c[i] == '-'))
    i++;
  while ((c[i] >= '0') && (c[i] <= '9')) {
    isnum = 1;
    i++;
  }
  if (c[i] == '.') {
    i++;
    while ((c[i] >= '0') && (c[i] <= '9')) {
      isnum = 1;
      i++;
    }
  }
  if ((c[i] == 'e') || (c[i] == 'E')) {
    wfe = 0;
    i++;
    if ((c[i] == '+') || (c[i] == '-'))
      i++;
    while ((c[i] >= '0') && (c[i] <= '9')) {
      wfe = 1;
      i++;
    }
  }
  if ((c[i] == 'f') || (c[i] == 'F') || (c[i] == 'l') || (c[i] == 'L'))
    i++;
  if ((c[i] == '\0') && isnum && wfe)
    return (1);
  else
    return (0);
}
```