ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L31
  cmpq   $0x0,-0x30(%rbp)
  jne    L19
L31:
  mov    $0x0,%eax
  jmp    L11
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L11
L28:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
const char *str_add(const char *const a, const char *const b) {
  if (!a || !b) {
    return NULL;
  }
  size_t len_a = strlen(a);
  size_t len_b = strlen(b);
  char *result = (char *)malloc(sizeof(char) * (len_a + len_b + 1));
  if (!result) {
    return NULL;
  }
  memcpy(result, a, len_a);
  memcpy(result + len_a, b, len_b + 1);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_add>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L32
  mov    %rdi,%rbp
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L32
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  lea    0x1(%r15,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%r14d
  test   %rax,%rax
  je     L2
  mov    %rax,%r14
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%r12),%rdx
  lea    (%rbx,%r15,1),%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
L2:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    $0x0,%r14d
  jmp    L2
```

assistant: ```c
const char *str_add(const char *const a, const char *const b) {
  if (!a || !b) {
    return NULL;
  }
  size_t len_a = strlen(a);
  size_t len_b = strlen(b);
  char *result = (char *)malloc(sizeof(char) * (len_a + len_b + 1));
  if (!result) {
    return NULL;
  }
  memcpy(result, a, len_a);
  memcpy(result + len_a, b, len_b + 1);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_add>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L18
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
  lea    0x1(%r13),%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
const char *str_add(const char *const a, const char *const b) {
  if (!a || !b) {
    return NULL;
  }
  size_t len_a = strlen(a);
  size_t len_b = strlen(b);
  char *result = (char *)malloc(sizeof(char) * (len_a + len_b + 1));
  if (!result) {
    return NULL;
  }
  memcpy(result, a, len_a);
  memcpy(result + len_a, b, len_b + 1);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_add>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L24
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L24
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L24
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
  lea    0x1(%r13),%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
const char *str_add(const char *const a, const char *const b) {
  if (!a || !b) {
    return NULL;
  }
  size_t len_a = strlen(a);
  size_t len_b = strlen(b);
  char *result = (char *)malloc(sizeof(char) * (len_a + len_b + 1));
  if (!result) {
    return NULL;
  }
  memcpy(result, a, len_a);
  memcpy(result + len_a, b, len_b + 1);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strdupcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdupcat(const char *string1, const char *string2) {
  size_t l1 = strlen(string1), l2 = strlen(string2);
  char *string = malloc(l1 + l2 + 1);
  memcpy(string, string1, l1);
  memcpy(string + l1, string2, l2);
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strdupcat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strdupcat(const char *string1, const char *string2) {
  size_t l1 = strlen(string1), l2 = strlen(string2);
  char *string = malloc(l1 + l2 + 1);
  memcpy(string, string1, l1);
  memcpy(string + l1, string2, l2);
  return string;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strdupcat>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strdupcat(const char *string1, const char *string2) {
  size_t l1 = strlen(string1), l2 = strlen(string2);
  char *string = malloc(l1 + l2 + 1);
  memcpy(string, string1, l1);
  memcpy(string + l1, string2, l2);
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strdupcat>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strdupcat(const char *string1, const char *string2) {
  size_t l1 = strlen(string1), l2 = strlen(string2);
  char *string = malloc(l1 + l2 + 1);
  memcpy(string, string1, l1);
  memcpy(string + l1, string2, l2);
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(float p) {
  int w;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(float p) {
  int w;
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(float p) {
  int w;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(float p) {
  int w;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L10:
  mov    -0x20(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzwl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  movswl -0x24(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L10
  nop
  pop    %rbp
  ret
```

assistant: ```c
sum(to, from, count) short *to, *from;
short count;
{
  int i;
  for (i = 0; i != count; ++i)
    *to += *from++;
}
```
user: What is the c source code of the assembly code below?

```asm
<sum>:
  endbr64
  test   %dx,%dx
  je     L3
  movswl %dx,%edx
  lea    (%rsi,%rdx,2),%rdx
L15:
  add    $0x2,%rsi
  movzwl -0x2(%rsi),%eax
  add    %ax,(%rdi)
  cmp    %rdx,%rsi
  jne    L15
L3:
  ret
```

assistant: ```c
sum(to, from, count) short *to, *from;
short count;
{
  int i;
  for (i = 0; i != count; ++i)
    *to += *from++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum>:
  endbr64
  test   %dx,%dx
  je     L13
  movswl %dx,%edx
  movzwl (%rdi),%eax
  lea    (%rsi,%rdx,2),%rdx
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x2,%rsi
  add    -0x2(%rsi),%ax
  mov    %ax,(%rdi)
  cmp    %rdx,%rsi
  jne    L16
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
sum(to, from, count) short *to, *from;
short count;
{
  int i;
  for (i = 0; i != count; ++i)
    *to += *from++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  test   %dx,%dx
  je     L11
  movswl %dx,%edx
  movzwl (%rdi),%eax
  lea    (%rsi,%rdx,2),%rdx
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x2,%rsi
  add    -0x2(%rsi),%ax
  mov    %ax,(%rdi)
  cmp    %rdx,%rsi
  jne    L7
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
sum(to, from, count) short *to, *from;
short count;
{
  int i;
  for (i = 0; i != count; ++i)
    *to += *from++;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hexToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L15
L28:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hex@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L30
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x4,%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L15:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  jmp    L0
L30:
  nop
L0:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int hexToInt(char **ptr, int *intValue) {
  int numChars = 0;
  int hexValue;
  *intValue = 0;
  while (**ptr) {
    hexValue = hex(**ptr);
    if (hexValue < 0)
      break;
    *intValue = (*intValue << 4) | hexValue;
    numChars++;
    (*ptr)++;
  }
  return (numChars);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hexToInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  mov    (%rdi),%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L4
  mov    %rsi,%rbp
  mov    $0x0,%r12d
L39:
  movsbl %dil,%edi
  call   <hex@plt>
  mov    %eax,%edx
  test   %eax,%eax
  js     L12
  mov    0x0(%rbp),%eax
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %eax,0x0(%rbp)
  add    $0x1,%r12d
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  jne    L39
L12:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x0,%r12d
  jmp    L12
```

assistant: ```c
unsigned int hexToInt(char **ptr, int *intValue) {
  int numChars = 0;
  int hexValue;
  *intValue = 0;
  while (**ptr) {
    hexValue = hex(**ptr);
    if (hexValue < 0)
      break;
    *intValue = (*intValue << 4) | hexValue;
    numChars++;
    (*ptr)++;
  }
  return (numChars);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hexToInt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%rax
  movl   $0x0,(%rsi)
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L9
  mov    %rsi,%r12
  xor    %ebx,%ebx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L24:
  mov    (%r12),%eax
  add    $0x1,%ebx
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %eax,(%r12)
  mov    0x0(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x0(%rbp)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L33
L20:
  call   <hex@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L24
L33:
  mov    %ebx,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  xor    %eax,%eax
  jmp    L26
```

assistant: ```c
unsigned int hexToInt(char **ptr, int *intValue) {
  int numChars = 0;
  int hexValue;
  *intValue = 0;
  while (**ptr) {
    hexValue = hex(**ptr);
    if (hexValue < 0)
      break;
    *intValue = (*intValue << 4) | hexValue;
    numChars++;
    (*ptr)++;
  }
  return (numChars);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hexToInt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%rax
  movl   $0x0,(%rsi)
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L11
  mov    %rsi,%r12
  xor    %ebx,%ebx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L40:
  mov    (%r12),%eax
  add    $0x1,%ebx
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %eax,(%r12)
  mov    0x0(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x0(%rbp)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L9
L15:
  call   <hex@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L40
L9:
  mov    %ebx,%eax
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  xor    %eax,%eax
  jmp    L25
```

assistant: ```c
unsigned int hexToInt(char **ptr, int *intValue) {
  int numChars = 0;
  int hexValue;
  *intValue = 0;
  while (**ptr) {
    hexValue = hex(**ptr);
    if (hexValue < 0)
      break;
    *intValue = (*intValue << 4) | hexValue;
    numChars++;
    (*ptr)++;
  }
  return (numChars);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WatchdogUnlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xc00,%rax
  movq   $0x1acce551,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void WatchdogUnlock(uint32_t ui32Base) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000C00))) = 0x1ACCE551;
}
```
user: Translate the below assembly code into C programming language:

```asm
<WatchdogUnlock>:
  endbr64
  movq   $0x1acce551,0xc00(%rdi)
  ret
```

assistant: ```c
void WatchdogUnlock(uint32_t ui32Base) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000C00))) = 0x1ACCE551;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<WatchdogUnlock>:
  endbr64
  movq   $0x1acce551,0xc00(%rdi)
  ret
```

assistant: ```c
void WatchdogUnlock(uint32_t ui32Base) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000C00))) = 0x1ACCE551;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<WatchdogUnlock>:
  endbr64
  movq   $0x1acce551,0xc00(%rdi)
  ret
```

assistant: ```c
void WatchdogUnlock(uint32_t ui32Base) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000C00))) = 0x1ACCE551;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x35,%al
  jg     L41
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x33,%al
  jle    L51
  mov    -0x8(%rbp),%eax
  lea    -0x28(%rax),%esi
  mov    -0x4(%rbp),%eax
  lea    0x7d0(%rax),%ecx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%edi
  call   <check_date@plt>
  jmp    L3
L51:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x32,%al
  jle    L46
  mov    -0x8(%rbp),%eax
  lea    -0x14(%rax),%esi
  mov    -0x4(%rbp),%eax
  lea    0x708(%rax),%ecx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%edi
  call   <check_date@plt>
  jmp    L3
L46:
  mov    -0x4(%rbp),%eax
  lea    0x76c(%rax),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <check_date@plt>
  jmp    L3
L41:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int check_year(char *id) {
  int day = (id[5] + (id[4] - '0') * 10) - '0';
  int month = (id[3] + (id[2] - '0') * 10) - '0';
  int year = (id[1] + (id[0] - '0') * 10) - '0';
  if (id[2] <= '5') {
    if (id[2] >= '4') {
      return check_date(2000 + year, month - 40, day);
    } else if (id[2] >= '3') {
      return check_date(1800 + year, month - 20, day);
    } else {
      return check_date(1900 + year, month, day);
    }
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_year>:
  endbr64
  movzbl 0x2(%rdi),%edx
  mov    $0x0,%eax
  cmp    $0x35,%dl
  jg     L19
  sub    $0x8,%rsp
  movsbl 0x4(%rdi),%eax
  lea    -0xf0(%rax,%rax,4),%ecx
  movsbl 0x5(%rdi),%eax
  lea    -0x30(%rax,%rcx,2),%r8d
  movsbl %dl,%eax
  lea    -0xf0(%rax,%rax,4),%ecx
  movsbl 0x3(%rdi),%eax
  lea    (%rax,%rcx,2),%esi
  movsbl (%rdi),%eax
  lea    -0xf0(%rax,%rax,4),%ecx
  movsbl 0x1(%rdi),%eax
  lea    (%rax,%rcx,2),%edi
  cmp    $0x33,%dl
  jg     L0
  jne    L41
  sub    $0x44,%esi
  add    $0x6d8,%edi
  mov    %r8d,%edx
  call   <check_date@plt>
L34:
  add    $0x8,%rsp
  ret
L0:
  sub    $0x58,%esi
  add    $0x7a0,%edi
  mov    %r8d,%edx
  call   <check_date@plt>
  jmp    L34
L41:
  sub    $0x30,%esi
  add    $0x73c,%edi
  mov    %r8d,%edx
  call   <check_date@plt>
  jmp    L34
L19:
  ret
```

assistant: ```c
int check_year(char *id) {
  int day = (id[5] + (id[4] - '0') * 10) - '0';
  int month = (id[3] + (id[2] - '0') * 10) - '0';
  int year = (id[1] + (id[0] - '0') * 10) - '0';
  if (id[2] <= '5') {
    if (id[2] >= '4') {
      return check_date(2000 + year, month - 40, day);
    } else if (id[2] >= '3') {
      return check_date(1800 + year, month - 20, day);
    } else {
      return check_date(1900 + year, month, day);
    }
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_year>:
  endbr64
  movzbl 0x2(%rdi),%eax
  cmp    $0x35,%al
  jg     L18
  movsbl 0x4(%rdi),%edx
  lea    -0xf0(%rdx,%rdx,4),%ecx
  movsbl 0x5(%rdi),%edx
  lea    -0x30(%rdx,%rcx,2),%r8d
  movsbl %al,%edx
  lea    -0xf0(%rdx,%rdx,4),%ecx
  movsbl 0x3(%rdi),%edx
  lea    (%rdx,%rcx,2),%esi
  movsbl (%rdi),%edx
  lea    -0xf0(%rdx,%rdx,4),%ecx
  movsbl 0x1(%rdi),%edx
  lea    (%rdx,%rcx,2),%edi
  cmp    $0x33,%al
  jg     L10
  je     L24
  sub    $0x30,%esi
  add    $0x73c,%edi
  mov    %r8d,%edx
  jmp    1050 <check_date@plt>
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  sub    $0x44,%esi
  add    $0x6d8,%edi
  mov    %r8d,%edx
  jmp    1050 <check_date@plt>
  nopl   0x0(%rax)
L10:
  sub    $0x58,%esi
  add    $0x7a0,%edi
  mov    %r8d,%edx
  jmp    1050 <check_date@plt>
```

assistant: ```c
int check_year(char *id) {
  int day = (id[5] + (id[4] - '0') * 10) - '0';
  int month = (id[3] + (id[2] - '0') * 10) - '0';
  int year = (id[1] + (id[0] - '0') * 10) - '0';
  if (id[2] <= '5') {
    if (id[2] >= '4') {
      return check_date(2000 + year, month - 40, day);
    } else if (id[2] >= '3') {
      return check_date(1800 + year, month - 20, day);
    } else {
      return check_date(1900 + year, month, day);
    }
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_year>:
  endbr64
  movzbl 0x2(%rdi),%eax
  cmp    $0x35,%al
  jg     L21
  movsbl 0x4(%rdi),%edx
  lea    -0xf0(%rdx,%rdx,4),%ecx
  movsbl 0x5(%rdi),%edx
  lea    -0x30(%rdx,%rcx,2),%r8d
  movsbl %al,%edx
  lea    -0xf0(%rdx,%rdx,4),%ecx
  movsbl 0x3(%rdi),%edx
  lea    (%rdx,%rcx,2),%esi
  movsbl (%rdi),%edx
  lea    -0xf0(%rdx,%rdx,4),%ecx
  movsbl 0x1(%rdi),%edx
  lea    (%rdx,%rcx,2),%edi
  cmp    $0x33,%al
  jg     L9
  je     L29
  sub    $0x30,%esi
  add    $0x73c,%edi
  mov    %r8d,%edx
  jmp    1050 <check_date@plt>
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  sub    $0x44,%esi
  add    $0x6d8,%edi
  mov    %r8d,%edx
  jmp    1050 <check_date@plt>
  nopl   0x0(%rax)
L9:
  sub    $0x58,%esi
  add    $0x7a0,%edi
  mov    %r8d,%edx
  jmp    1050 <check_date@plt>
```

assistant: ```c
int check_year(char *id) {
  int day = (id[5] + (id[4] - '0') * 10) - '0';
  int month = (id[3] + (id[2] - '0') * 10) - '0';
  int year = (id[1] + (id[0] - '0') * 10) - '0';
  if (id[2] <= '5') {
    if (id[2] >= '4') {
      return check_date(2000 + year, month - 40, day);
    } else if (id[2] >= '3') {
      return check_date(1800 + year, month - 20, day);
    } else {
      return check_date(1900 + year, month, day);
    }
  } else {
    return 0;
  }
}
```