ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gcgeodist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  D80(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D22(%rip),%xmm1
  movapd %xmm0,%xmm3
  divsd  %xmm1,%xmm3
  movsd  -0x28(%rbp),%xmm1
  movsd  D80(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D22(%rip),%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movsd  -0x20(%rbp),%xmm1
  movsd  D80(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D22(%rip),%xmm1
  movapd %xmm0,%xmm4
  divsd  %xmm1,%xmm4
  movsd  -0x18(%rbp),%xmm1
  movsd  D80(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D22(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movapd %xmm4,%xmm1
  movq   %rax,%xmm0
  mov    $0x4,%eax
  call   <gcdist@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <radtometers@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D48(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L9
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L9:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D80
datatype: f64
name: parse_data
arguments: data_label: D22
datatype: f64
name: parse_data
arguments: data_label: D48
datatype: f64

tool: D80: 3.141592653589793

tool: D22: 180

tool: D48: 0.1

assistant: ```c
double gcgeodist(const double lat1, const double lon1, const double lat2, const double lon2) {
  double res;
  res = radtometers(gcdist(((lat1)*3.14159265358979323846 / 180.0), ((lon1)*3.14159265358979323846 / 180.0), ((lat2)*3.14159265358979323846 / 180.0), ((lon2)*3.14159265358979323846 / 180.0)));
  if (res < 0.1)
    res = 0;
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gcgeodist>:
  endbr64
  sub    $0x8,%rsp
  movsd  D1(%rip),%xmm5
  mulsd  %xmm5,%xmm3
  movsd  D15(%rip),%xmm4
  mulsd  %xmm5,%xmm2
  mulsd  %xmm5,%xmm1
  mulsd  %xmm5,%xmm0
  divsd  %xmm4,%xmm0
  divsd  %xmm4,%xmm3
  divsd  %xmm4,%xmm2
  divsd  %xmm4,%xmm1
  mov    $0x4,%eax
  call   <gcdist@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <radtometers@plt>
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L3
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L3:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: f64
name: unpack_data
arguments: data_label: D15
type_guessed: f64

tool: D1: 3.141592653589793

tool: D15: 180

assistant: ```c
double gcgeodist(const double lat1, const double lon1, const double lat2, const double lon2) {
  double res;
  res = radtometers(gcdist(((lat1)*3.14159265358979323846 / 180.0), ((lon1)*3.14159265358979323846 / 180.0), ((lat2)*3.14159265358979323846 / 180.0), ((lon2)*3.14159265358979323846 / 180.0)));
  if (res < 0.1)
    res = 0;
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gcgeodist>:
  endbr64
  sub    $0x8,%rsp
  movsd  D3(%rip),%xmm5
  mov    $0x4,%eax
  movsd  D5(%rip),%xmm4
  mulsd  %xmm5,%xmm3
  mulsd  %xmm5,%xmm2
  mulsd  %xmm5,%xmm1
  mulsd  %xmm5,%xmm0
  divsd  %xmm4,%xmm3
  divsd  %xmm4,%xmm0
  divsd  %xmm4,%xmm2
  divsd  %xmm4,%xmm1
  call   <gcdist@plt>
  mov    %eax,%edi
  xor    %eax,%eax
  call   <radtometers@plt>
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L5
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L5:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: f64
name: extract_symbolic_data
arguments: label: D5
type_guessed: f64

tool: D3: 3.141592653589793

tool: D5: 180

assistant: ```c
double gcgeodist(const double lat1, const double lon1, const double lat2, const double lon2) {
  double res;
  res = radtometers(gcdist(((lat1)*3.14159265358979323846 / 180.0), ((lon1)*3.14159265358979323846 / 180.0), ((lat2)*3.14159265358979323846 / 180.0), ((lon2)*3.14159265358979323846 / 180.0)));
  if (res < 0.1)
    res = 0;
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcgeodist>:
  endbr64
  sub    $0x8,%rsp
  movsd  D5(%rip),%xmm5
  mov    $0x4,%eax
  movsd  D17(%rip),%xmm4
  mulsd  %xmm5,%xmm3
  mulsd  %xmm5,%xmm2
  mulsd  %xmm5,%xmm1
  mulsd  %xmm5,%xmm0
  divsd  %xmm4,%xmm3
  divsd  %xmm4,%xmm0
  divsd  %xmm4,%xmm2
  divsd  %xmm4,%xmm1
  call   <gcdist@plt>
  mov    %eax,%edi
  xor    %eax,%eax
  call   <radtometers@plt>
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L4
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L4:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: f64
name: disassemble_data
arguments: data_tag: D17
type_infered: f64

tool: D5: 3.141592653589793

tool: D17: 180

assistant: ```c
double gcgeodist(const double lat1, const double lon1, const double lat2, const double lon2) {
  double res;
  res = radtometers(gcdist(((lat1)*3.14159265358979323846 / 180.0), ((lon1)*3.14159265358979323846 / 180.0), ((lat2)*3.14159265358979323846 / 180.0), ((lon2)*3.14159265358979323846 / 180.0)));
  if (res < 0.1)
    res = 0;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sort_coefs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L53
L66:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L63
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L4
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L60
L4:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L60
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L60:
  addl   $0x1,-0x10(%rbp)
L63:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L19
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L42
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %ax,-0x12(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzwl -0x12(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movzwl -0x12(%rbp),%eax
  mov    %ax,(%rdx)
L42:
  addl   $0x1,-0xc(%rbp)
L53:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L66
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort_coefs(int *order, unsigned short *soln, int len) {
  int cnt, start_cnt, least_ord, least_cnt;
  unsigned short tmp0;
  for (start_cnt = 0; start_cnt < len; start_cnt++) {
    for (cnt = start_cnt; cnt < len; cnt++) {
      if (cnt == start_cnt) {
        least_ord = order[cnt];
        least_cnt = start_cnt;
      } else {
        if (least_ord > order[cnt]) {
          least_ord = order[cnt];
          least_cnt = cnt;
        }
      }
    }
    if (least_cnt != start_cnt) {
      tmp0 = order[least_cnt];
      order[least_cnt] = order[start_cnt];
      order[start_cnt] = tmp0;
      tmp0 = soln[least_cnt];
      soln[least_cnt] = soln[start_cnt];
      soln[start_cnt] = tmp0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sort_coefs>:
  endbr64
  test   %edx,%edx
  jle    L40
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %edx,%r10d
  mov    %edx,%r12d
  mov    $0x0,%r9d
  jmp    L9
L58:
  mov    (%rdi,%rax,4),%ecx
  mov    %ebx,%r11d
L43:
  add    $0x1,%rax
  cmp    %eax,%r10d
  jle    L4
L22:
  cmp    %eax,%r8d
  je     L58
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L43
  mov    %eax,%r11d
  mov    %edx,%ecx
  jmp    L43
L4:
  cmp    %r11d,%r8d
  je     L64
  movslq %r11d,%rdx
  lea    (%rdi,%rdx,4),%rsi
  mov    (%rsi),%eax
  mov    (%rdi,%r9,4),%r8d
  mov    %r8d,(%rsi)
  and    $0xffff,%eax
  mov    %eax,(%rdi,%r9,4)
  lea    0x0(%rbp,%rdx,2),%rax
  movzwl (%rax),%edx
  movzwl 0x0(%rbp,%r9,2),%esi
  mov    %si,(%rax)
  mov    %dx,0x0(%rbp,%r9,2)
L64:
  add    $0x1,%r9
  cmp    %r12,%r9
  je     L12
L9:
  mov    %r9d,%ebx
  mov    %r9d,%r8d
  mov    %r9,%rax
  cmp    %r9d,%r10d
  jg     L22
  jmp    L4
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  ret
```

assistant: ```c
void sort_coefs(int *order, unsigned short *soln, int len) {
  int cnt, start_cnt, least_ord, least_cnt;
  unsigned short tmp0;
  for (start_cnt = 0; start_cnt < len; start_cnt++) {
    for (cnt = start_cnt; cnt < len; cnt++) {
      if (cnt == start_cnt) {
        least_ord = order[cnt];
        least_cnt = start_cnt;
      } else {
        if (least_ord > order[cnt]) {
          least_ord = order[cnt];
          least_cnt = cnt;
        }
      }
    }
    if (least_cnt != start_cnt) {
      tmp0 = order[least_cnt];
      order[least_cnt] = order[start_cnt];
      order[start_cnt] = tmp0;
      tmp0 = soln[least_cnt];
      soln[least_cnt] = soln[start_cnt];
      soln[start_cnt] = tmp0;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sort_coefs>:
  endbr64
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L58
  mov    %rsi,%r11
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  nopl   (%rax)
L35:
  mov    %ecx,%r10d
  mov    %rcx,%rax
  mov    %ecx,%ebx
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    %r8d,%edx
  jge    L21
  mov    %eax,%r9d
  mov    %edx,%r8d
L21:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L74
L63:
  mov    (%rdi,%rax,4),%edx
  cmp    %eax,%ecx
  jne    L10
  add    $0x1,%rax
  mov    %r10d,%r9d
  mov    %edx,%r8d
  cmp    %eax,%esi
  jg     L63
L74:
  cmp    %ebx,%r9d
  je     L75
  movslq %r9d,%rdx
  mov    (%rdi,%rcx,4),%ebx
  lea    (%rdi,%rdx,4),%r10
  mov    (%r10),%eax
  mov    %ebx,(%r10)
  movzwl (%r11,%rcx,2),%r10d
  and    $0xffff,%eax
  mov    %eax,(%rdi,%rcx,4)
  lea    (%r11,%rdx,2),%rax
  movzwl (%rax),%edx
  mov    %r10w,(%rax)
  mov    %dx,(%r11,%rcx,2)
L75:
  add    $0x1,%rcx
  cmp    %rcx,%rbp
  jne    L35
L58:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sort_coefs(int *order, unsigned short *soln, int len) {
  int cnt, start_cnt, least_ord, least_cnt;
  unsigned short tmp0;
  for (start_cnt = 0; start_cnt < len; start_cnt++) {
    for (cnt = start_cnt; cnt < len; cnt++) {
      if (cnt == start_cnt) {
        least_ord = order[cnt];
        least_cnt = start_cnt;
      } else {
        if (least_ord > order[cnt]) {
          least_ord = order[cnt];
          least_cnt = cnt;
        }
      }
    }
    if (least_cnt != start_cnt) {
      tmp0 = order[least_cnt];
      order[least_cnt] = order[start_cnt];
      order[start_cnt] = tmp0;
      tmp0 = soln[least_cnt];
      soln[least_cnt] = soln[start_cnt];
      soln[start_cnt] = tmp0;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sort_coefs>:
  endbr64
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L31
  mov    %rsi,%r11
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  nopl   (%rax)
L45:
  mov    %ecx,%r10d
  mov    %rcx,%rax
  mov    %ecx,%ebx
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L11:
  cmp    %r8d,%edx
  jge    L35
  mov    %eax,%r9d
  mov    %edx,%r8d
L35:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L16
L75:
  mov    (%rdi,%rax,4),%edx
  cmp    %eax,%ecx
  jne    L11
  add    $0x1,%rax
  mov    %r10d,%r9d
  mov    %edx,%r8d
  cmp    %eax,%esi
  jg     L75
L16:
  cmp    %r9d,%ebx
  je     L63
  movslq %r9d,%rdx
  mov    (%rdi,%rcx,4),%ebx
  lea    (%rdi,%rdx,4),%r10
  mov    (%r10),%eax
  mov    %ebx,(%r10)
  movzwl (%r11,%rcx,2),%r10d
  and    $0xffff,%eax
  mov    %eax,(%rdi,%rcx,4)
  lea    (%r11,%rdx,2),%rax
  movzwl (%rax),%edx
  mov    %r10w,(%rax)
  mov    %dx,(%r11,%rcx,2)
L63:
  add    $0x1,%rcx
  cmp    %rcx,%rbp
  jne    L45
L31:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sort_coefs(int *order, unsigned short *soln, int len) {
  int cnt, start_cnt, least_ord, least_cnt;
  unsigned short tmp0;
  for (start_cnt = 0; start_cnt < len; start_cnt++) {
    for (cnt = start_cnt; cnt < len; cnt++) {
      if (cnt == start_cnt) {
        least_ord = order[cnt];
        least_cnt = start_cnt;
      } else {
        if (least_ord > order[cnt]) {
          least_ord = order[cnt];
          least_cnt = cnt;
        }
      }
    }
    if (least_cnt != start_cnt) {
      tmp0 = order[least_cnt];
      order[least_cnt] = order[start_cnt];
      order[start_cnt] = tmp0;
      tmp0 = soln[least_cnt];
      soln[least_cnt] = soln[start_cnt];
      soln[start_cnt] = tmp0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<u_mmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  cmpq   $0x0,-0xb8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc0(%rbp),%rax
  and    $0xfff,%eax
  test   %rax,%rax
  je     L15
  mov    -0xc0(%rbp),%rax
  shr    $0xc,%rax
  add    $0x1,%rax
  shl    $0xc,%rax
  mov    %rax,-0xc0(%rbp)
L15:
  mov    -0xc0(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1000,%edi
  call   <ummap_addr_alloc@plt>
  leave
  ret
```

assistant: ```c
void *u_mmap(void *addr, size_t len, ...) {
  assert(addr == 0);
  if (len % 4096)
    len = (1 + len / 4096) * 4096;
  return ummap_addr_alloc(4096, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<u_mmap>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   $0xfff,%ebx
  je     L9
  and    $0xfffffffffffff000,%rbx
  lea    0x1000(%rbx),%rbx
L9:
  mov    %rbx,%rsi
  mov    $0x1000,%edi
  call   <ummap_addr_alloc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *u_mmap(void *addr, size_t len, ...) {
  assert(addr == 0);
  if (len % 4096)
    len = (1 + len / 4096) * 4096;
  return ummap_addr_alloc(4096, len);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<u_mmap>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  mov    %rsi,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   $0xfff,%ebp
  je     L2
  and    $0xfffffffffffff000,%rbp
  add    $0x1000,%rbp
L2:
  mov    %rbp,%rsi
  mov    $0x1000,%edi
  call   <ummap_addr_alloc@plt>
  pop    %rbp
  ret
```

assistant: ```c
void *u_mmap(void *addr, size_t len, ...) {
  assert(addr == 0);
  if (len % 4096)
    len = (1 + len / 4096) * 4096;
  return ummap_addr_alloc(4096, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<u_mmap>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  mov    %rsi,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   $0xfff,%ebp
  je     L1
  and    $0xfffffffffffff000,%rbp
  add    $0x1000,%rbp
L1:
  mov    %rbp,%rsi
  mov    $0x1000,%edi
  call   <ummap_addr_alloc@plt>
  pop    %rbp
  ret
```

assistant: ```c
void *u_mmap(void *addr, size_t len, ...) {
  assert(addr == 0);
  if (len % 4096)
    len = (1 + len / 4096) * 4096;
  return ummap_addr_alloc(4096, len);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fibseq@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string
name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D1: Enter a number:


tool: D3:  %u%*c

assistant: ```c
int main() {
  unsigned n;
  printf("Enter a number:\n");
  scanf(" %u%*c", &n);
  fibseq(n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fibseq@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string
name: retrieve_data
arguments: tag: D10
datatype: string

tool: D8: Enter a number:


tool: D10:  %u%*c

assistant: ```c
int main() {
  unsigned n;
  printf("Enter a number:\n");
  scanf(" %u%*c", &n);
  fibseq(n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fibseq@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string

tool: D6: Enter a number:


tool: D2:  %u%*c

assistant: ```c
int main() {
  unsigned n;
  printf("Enter a number:\n");
  scanf(" %u%*c", &n);
  fibseq(n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fibseq@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D14
type_guessed: string

tool: D13: Enter a number:


tool: D14:  %u%*c

assistant: ```c
int main() {
  unsigned n;
  printf("Enter a number:\n");
  scanf(" %u%*c", &n);
  fibseq(n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<field_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L10:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  test   %al,%al
  jne    L10
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int field_size(FILE *f) {
  int size = 0;
  while (getc(f) != '\0')
    size++;
  return (size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<field_size>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L15
L8:
  add    $0x1,%ebx
L15:
  mov    %rbp,%rdi
  call   <getc@plt>
  test   %al,%al
  jne    L8
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int field_size(FILE *f) {
  int size = 0;
  while (getc(f) != '\0')
    size++;
  return (size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<field_size>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%r12d
L13:
  mov    %rbx,%rdi
  call   <getc@plt>
  test   %al,%al
  jne    L2
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int field_size(FILE *f) {
  int size = 0;
  while (getc(f) != '\0')
    size++;
  return (size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<field_size>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%r12d
L8:
  mov    %rbx,%rdi
  call   <getc@plt>
  test   %al,%al
  jne    L3
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int field_size(FILE *f) {
  int size = 0;
  while (getc(f) != '\0')
    size++;
  return (size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<VFileOpen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L17
L2:
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1b6,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <VFileFromFD@plt>
L17:
  leave
  ret
```

assistant: ```c
struct VFile *VFileOpen(const char *path, int flags) {
  if (!path) {
    return 0;
  }
  int fd = open(path, flags, 0666);
  return VFileFromFD(fd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<VFileOpen>:
  endbr64
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  mov    $0x1b6,%edx
  call   <open@plt>
  mov    %eax,%edi
  call   <VFileFromFD@plt>
  add    $0x8,%rsp
  ret
L4:
  mov    %rdi,%rax
  ret
```

assistant: ```c
struct VFile *VFileOpen(const char *path, int flags) {
  if (!path) {
    return 0;
  }
  int fd = open(path, flags, 0666);
  return VFileFromFD(fd);
}
```
user: What is the c source code of the assembly code below?

```asm
<VFileOpen>:
  endbr64
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  mov    $0x1b6,%edx
  call   <open@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <VFileFromFD@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct VFile *VFileOpen(const char *path, int flags) {
  if (!path) {
    return 0;
  }
  int fd = open(path, flags, 0666);
  return VFileFromFD(fd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VFileOpen>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  mov    $0x1b6,%edx
  call   <open@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <VFileFromFD@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct VFile *VFileOpen(const char *path, int flags) {
  if (!path) {
    return 0;
  }
  int fd = open(path, flags, 0666);
  return VFileFromFD(fd);
}
```