ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<rtrim>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  call   <xstrdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %r12,%rbx
  jae    L6
  jmp    L10
  nopl   0x0(%rax)
L12:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jb     L10
L6:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L12
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *rtrim(const char *str) {
  int i;
  char *copy;
  char *tail;
  copy = xstrdup(str);
  for (tail = copy + strlen(copy) - 1; (unsigned long)copy <= (unsigned long)tail; tail--) {
    if (!isspace(*tail))
      break;
    *tail = '\0';
  }
  return copy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtrim>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  call   <xstrdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %r12,%rbx
  jae    L13
  jmp    L7
  nopl   0x0(%rax)
L22:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jb     L7
L13:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L22
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *rtrim(const char *str) {
  int i;
  char *copy;
  char *tail;
  copy = xstrdup(str);
  for (tail = copy + strlen(copy) - 1; (unsigned long)copy <= (unsigned long)tail; tail--) {
    if (!isspace(*tail))
      break;
    *tail = '\0';
  }
  return copy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mce_ring_add@plt>
  test   %rax,%rax
  js     L13
  addq   $0x1,-0x8(%rbp)
  jmp    L13
```

assistant: ```c
void *thread(void *arg) {
  long i = 0;
  for (;;) {
    if (mce_ring_add(i) >= 0)
      i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<thread>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L9:
  mov    %rbx,%rdi
  call   <mce_ring_add@plt>
  not    %rax
  shr    $0x3f,%rax
  add    %rax,%rbx
  jmp    L9
```

assistant: ```c
void *thread(void *arg) {
  long i = 0;
  for (;;) {
    if (mce_ring_add(i) >= 0)
      i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<thread>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rbx,%rdi
  call   <mce_ring_add@plt>
  not    %rax
  shr    $0x3f,%rax
  add    %rax,%rbx
  jmp    L7
```

assistant: ```c
void *thread(void *arg) {
  long i = 0;
  for (;;) {
    if (mce_ring_add(i) >= 0)
      i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<thread>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rdi
  call   <mce_ring_add@plt>
  not    %rax
  shr    $0x3f,%rax
  add    %rax,%rbx
  jmp    L6
```

assistant: ```c
void *thread(void *arg) {
  long i = 0;
  for (;;) {
    if (mce_ring_add(i) >= 0)
      i++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ET>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L10:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jb     L10
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ET(char *resBinary, char *mask) {
  char *res;
  unsigned int i;
  res = malloc(sizeof(*res) * (strlen(mask) + 1));
  for (i = 0; i < strlen(mask); i++) {
    res[i] = resBinary[i] & mask[i];
  }
  res[i] = '\0';
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ET>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  jmp    L1
L2:
  mov    %ebx,%eax
  movzbl 0x0(%r13,%rax,1),%edx
  and    0x0(%rbp,%rax,1),%dl
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%ebx
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L2
  mov    %ebx,%ebx
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ET(char *resBinary, char *mask) {
  char *res;
  unsigned int i;
  res = malloc(sizeof(*res) * (strlen(mask) + 1));
  for (i = 0; i < strlen(mask); i++) {
    res[i] = resBinary[i] & mask[i];
  }
  res[i] = '\0';
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ET>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl 0x0(%rbp,%rax,1),%edx
  and    0x0(%r13,%rax,1),%dl
  add    $0x1,%ebx
  mov    %dl,(%rcx)
L19:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  lea    (%r12,%rax,1),%rcx
  cmp    %ebx,%r8d
  ja     L11
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ET(char *resBinary, char *mask) {
  char *res;
  unsigned int i;
  res = malloc(sizeof(*res) * (strlen(mask) + 1));
  for (i = 0; i < strlen(mask); i++) {
    res[i] = resBinary[i] & mask[i];
  }
  res[i] = '\0';
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ET>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl 0x0(%rbp,%rax,1),%edx
  and    0x0(%r13,%rax,1),%dl
  add    $0x1,%ebx
  mov    %dl,(%rcx)
L12:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  lea    (%r12,%rax,1),%rcx
  cmp    %ebx,%r8d
  ja     L3
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ET(char *resBinary, char *mask) {
  char *res;
  unsigned int i;
  res = malloc(sizeof(*res) * (strlen(mask) + 1));
  for (i = 0; i < strlen(mask); i++) {
    res[i] = resBinary[i] & mask[i];
  }
  res[i] = '\0';
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L27
L22:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L27
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x10(%rbp),%rdx
  sub    $0x1,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  sub    %edx,%eax
  jmp    L3
L27:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L22
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *strn1, const char *strn2, size_t number) {
  while (number--)
    if (*strn1++ != *strn2++)
      return *(unsigned char *)(strn1 - 1) - *(unsigned char *)(strn2 - 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strncmp>:
  endbr64
  mov    $0x0,%eax
L14:
  cmp    %rax,%rdx
  je     L8
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L14
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strncmp(const char *strn1, const char *strn2, size_t number) {
  while (number--)
    if (*strn1++ != *strn2++)
      return *(unsigned char *)(strn1 - 1) - *(unsigned char *)(strn2 - 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L26:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L6
L28:
  cmp    %rax,%rdx
  jne    L26
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *strn1, const char *strn2, size_t number) {
  while (number--)
    if (*strn1++ != *strn2++)
      return *(unsigned char *)(strn1 - 1) - *(unsigned char *)(strn2 - 1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L19:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L21
L29:
  cmp    %rax,%rdx
  jne    L19
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *strn1, const char *strn2, size_t number) {
  while (number--)
    if (*strn1++ != *strn2++)
      return *(unsigned char *)(strn1 - 1) - *(unsigned char *)(strn2 - 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<star_bar_plot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  movsd  %xmm0,-0x80(%rbp)
  movsd  %xmm1,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x50,-0x64(%rbp)
  movl   $0x1,-0x6c(%rbp)
  jmp    L67
L98:
  mov    -0x6c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L38
  mov    -0x6c(%rbp),%eax
  cltq
  movb   $0x2e,-0x60(%rbp,%rax,1)
  jmp    L6
L38:
  mov    -0x6c(%rbp),%eax
  cltq
  movb   $0x7c,-0x60(%rbp,%rax,1)
L6:
  addl   $0x1,-0x6c(%rbp)
L67:
  mov    -0x6c(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jle    L98
  mov    -0x64(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x80(%rbp),%xmm0
  divsd  -0x88(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  add    $0x1,%eax
  mov    %eax,-0x68(%rbp)
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jle    L42
  mov    -0x64(%rbp),%eax
  mov    %eax,-0x68(%rbp)
L42:
  cmpl   $0x0,-0x68(%rbp)
  jg     L79
  movl   $0x1,-0x68(%rbp)
L79:
  mov    -0x64(%rbp),%eax
  sub    -0x68(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x68(%rbp)
  movl   $0x1,-0x6c(%rbp)
  jmp    L17
L95:
  mov    -0x6c(%rbp),%eax
  cltq
  movb   $0x2a,-0x60(%rbp,%rax,1)
  addl   $0x1,-0x6c(%rbp)
L17:
  mov    -0x6c(%rbp),%eax
  cmp    -0x68(%rbp),%eax
  jle    L95
  movl   $0x1,-0x6c(%rbp)
  jmp    L2
L49:
  mov    -0x6c(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    -0x78(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  addl   $0x1,-0x6c(%rbp)
L2:
  mov    -0x6c(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jle    L49
  mov    -0x78(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L80
  call   <__stack_chk_fail@plt>
L80:
  leave
  ret
```

assistant: ```c
void star_bar_plot(FILE *pfile, double y, double yscale) {
  int jj, ypos;
  int columns = 80;
  char matrix[80 + 1];
  for (jj = 1; jj <= columns; jj++) {
    if (jj % 5 != 0)
      matrix[jj] = '.';
    else
      matrix[jj] = '|';
  }
  ypos = 1 + (int)((double)(columns - 1) * y / yscale);
  if (ypos > columns)
    ypos = columns;
  if (ypos < 1)
    ypos = 1;
  ypos = columns - ypos + 1;
  for (jj = 1; jj <= ypos; jj++)
    matrix[jj] = '*';
  for (jj = 1; jj <= columns; jj++)
    fprintf(pfile, "%c", matrix[jj]);
  fprintf(pfile, "\n");
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<star_bar_plot>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    $0x2e,%eax
  lea    -0x1(%rsp),%rsi
L47:
  mov    %al,(%rsi,%rdx,1)
  cmp    $0x51,%rdx
  je     L7
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x4e,%eax
  add    $0x2e,%eax
  add    $0x1,%rdx
  jmp    L47
L7:
  mov    %rsp,%r12
  lea    0x1(%rsp),%rbp
  mulsd  D8(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  add    $0x1,%eax
  test   %eax,%eax
  mov    $0x1,%edx
  cmovle %edx,%eax
  mov    $0x50,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  sub    %eax,%edx
  lea    0x2(%rsp,%rdx,1),%rdx
  mov    %rbp,%rax
L16:
  movb   $0x2a,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
  add    $0x51,%r12
L15:
  movsbl 0x0(%rbp),%edi
  mov    %rbx,%rsi
  call   <fputc@plt>
  add    $0x1,%rbp
  cmp    %rbp,%r12
  jne    L15
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0xc0,0x53,0x40]}

assistant: ```c
void star_bar_plot(FILE *pfile, double y, double yscale) {
  int jj, ypos;
  int columns = 80;
  char matrix[80 + 1];
  for (jj = 1; jj <= columns; jj++) {
    if (jj % 5 != 0)
      matrix[jj] = '.';
    else
      matrix[jj] = '|';
  }
  ypos = 1 + (int)((double)(columns - 1) * y / yscale);
  if (ypos > columns)
    ypos = columns;
  if (ypos < 1)
    ypos = 1;
  ypos = columns - ypos + 1;
  for (jj = 1; jj <= ypos; jj++)
    matrix[jj] = '*';
  for (jj = 1; jj <= columns; jj++)
    fprintf(pfile, "%c", matrix[jj]);
  fprintf(pfile, "\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<star_bar_plot>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rsp),%rcx
  mov    $0x2e,%eax
  jmp    L48
L35:
  imul   $0xcccccccd,%edx,%eax
  cmp    $0x33333334,%eax
  sbb    %eax,%eax
  add    $0x1,%rdx
  and    $0x4e,%eax
  add    $0x2e,%eax
L48:
  mov    %al,(%rcx,%rdx,1)
  cmp    $0x51,%rdx
  jne    L35
  mulsd  D3(%rip),%xmm0
  mov    $0x1,%edx
  lea    0x1(%rsp),%rbx
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  add    $0x1,%eax
  test   %eax,%eax
  cmovle %edx,%eax
  mov    $0x50,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    $0x51,%edx
  sub    %eax,%edx
  movabs $0x2a2a2a2a2a2a2a2a,%rax
  cmp    $0x8,%edx
  jae    L56
  test   $0x4,%dl
  jne    L9
  test   %edx,%edx
  je     L86
  movb   $0x2a,0x1(%rsp)
  test   $0x2,%dl
  je     L86
  mov    $0x2a2a,%eax
  mov    %ax,-0x2(%rbx,%rdx,1)
  jmp    L86
  nopl   (%rax)
L56:
  mov    %edx,%ecx
  mov    %rax,0x1(%rsp)
  lea    0x8(%rsp),%rdi
  mov    %rax,-0x8(%rbx,%rcx,1)
  mov    %rbx,%rcx
  sub    %rdi,%rcx
  add    %ecx,%edx
  shr    $0x3,%edx
  mov    %edx,%ecx
  rep stos %rax,%es:(%rdi)
L86:
  lea    0x51(%rsp),%r12
  xchg   %ax,%ax
L72:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %rbx,%r12
  jne    L72
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x60,%rsp
  mov    %rbp,%rsi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <fputc@plt>
L9:
  movl   $0x2a2a2a2a,0x1(%rsp)
  movl   $0x2a2a2a2a,-0x4(%rbx,%rdx,1)
  jmp    L86
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0xc0,0x53,0x40]}

assistant: ```c
void star_bar_plot(FILE *pfile, double y, double yscale) {
  int jj, ypos;
  int columns = 80;
  char matrix[80 + 1];
  for (jj = 1; jj <= columns; jj++) {
    if (jj % 5 != 0)
      matrix[jj] = '.';
    else
      matrix[jj] = '|';
  }
  ypos = 1 + (int)((double)(columns - 1) * y / yscale);
  if (ypos > columns)
    ypos = columns;
  if (ypos < 1)
    ypos = 1;
  ypos = columns - ypos + 1;
  for (jj = 1; jj <= ypos; jj++)
    matrix[jj] = '*';
  for (jj = 1; jj <= columns; jj++)
    fprintf(pfile, "%c", matrix[jj]);
  fprintf(pfile, "\n");
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_args_24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L97
  cmpl   $0x1,-0x8(%rbp)
  jne    L97
  cmpl   $0x2,-0xc(%rbp)
  jne    L97
  cmpl   $0x3,-0x10(%rbp)
  jne    L97
  cmpl   $0x4,-0x14(%rbp)
  jne    L97
  cmpl   $0x5,-0x18(%rbp)
  jne    L97
  cmpl   $0x6,0x10(%rbp)
  jne    L97
  cmpl   $0x7,0x18(%rbp)
  jne    L97
  cmpl   $0x8,0x20(%rbp)
  jne    L97
  cmpl   $0x9,0x28(%rbp)
  jne    L97
  cmpl   $0xa,0x30(%rbp)
  je     L81
L97:
  mov    $0x0,%eax
  call   <abort@plt>
L81:
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((no)) check_args_24(int a0, int a1, int a2, int a3, int a4, int a5, int a6, int a7, int a8, int a9, int a10) {
  if (a0 != 0 || a1 != 1 || a2 != 2 || a3 != 3 || a4 != 4 || a5 != 5 || a6 != 6 || a7 != 7 || a8 != 8 || a9 != 9 || a10 != 10)
    abort();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_args_24>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L56
  cmp    $0x1,%esi
  jne    L56
  cmp    $0x2,%edx
  jne    L56
  cmp    $0x3,%ecx
  jne    L56
  cmp    $0x4,%r8d
  jne    L56
  cmp    $0x5,%r9d
  jne    L56
  cmpl   $0x6,0x10(%rsp)
  jne    L56
  cmpl   $0x7,0x18(%rsp)
  jne    L56
  cmpl   $0x8,0x20(%rsp)
  setne  %al
  cmpl   $0x9,0x28(%rsp)
  setne  %dl
  or     %dl,%al
  jne    L56
  cmpl   $0xa,0x30(%rsp)
  je     L71
L56:
  mov    $0x0,%eax
  call   <abort@plt>
L71:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __attribute__((no)) check_args_24(int a0, int a1, int a2, int a3, int a4, int a5, int a6, int a7, int a8, int a9, int a10) {
  if (a0 != 0 || a1 != 1 || a2 != 2 || a3 != 3 || a4 != 4 || a5 != 5 || a6 != 6 || a7 != 7 || a8 != 8 || a9 != 9 || a10 != 10)
    abort();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_args_24>:
  endbr64
  push   %rbp
  push   %rbx
  mov    0x18(%rsp),%eax
  mov    0x20(%rsp),%r10d
  mov    0x28(%rsp),%ebx
  mov    0x30(%rsp),%r11d
  mov    0x38(%rsp),%ebp
  test   %edi,%edi
  jne    L59
  cmp    $0x1,%esi
  jne    L59
  cmp    $0x2,%edx
  jne    L59
  cmp    $0x3,%ecx
  jne    L59
  cmp    $0x4,%r8d
  jne    L59
  cmp    $0x5,%r9d
  jne    L59
  cmp    $0x6,%eax
  jne    L59
  cmp    $0x7,%r10d
  jne    L59
  cmp    $0x8,%ebx
  setne  %al
  cmp    $0x9,%r11d
  setne  %dl
  or     %dl,%al
  jne    L59
  cmp    $0xa,%ebp
  jne    L59
  pop    %rbx
  pop    %rbp
  ret
  nop
L59:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no)) check_args_24(int a0, int a1, int a2, int a3, int a4, int a5, int a6, int a7, int a8, int a9, int a10) {
  if (a0 != 0 || a1 != 1 || a2 != 2 || a3 != 3 || a4 != 4 || a5 != 5 || a6 != 6 || a7 != 7 || a8 != 8 || a9 != 9 || a10 != 10)
    abort();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_args_24>:
  endbr64
  push   %rbp
  push   %rbx
  mov    0x18(%rsp),%eax
  mov    0x20(%rsp),%r10d
  mov    0x28(%rsp),%ebx
  mov    0x30(%rsp),%r11d
  mov    0x38(%rsp),%ebp
  test   %edi,%edi
  jne    L64
  cmp    $0x1,%esi
  jne    L64
  cmp    $0x2,%edx
  jne    L64
  cmp    $0x3,%ecx
  jne    L64
  cmp    $0x4,%r8d
  jne    L64
  cmp    $0x5,%r9d
  jne    L64
  cmp    $0x6,%eax
  jne    L64
  cmp    $0x7,%r10d
  jne    L64
  cmp    $0x8,%ebx
  setne  %al
  cmp    $0x9,%r11d
  setne  %dl
  or     %dl,%al
  jne    L64
  cmp    $0xa,%ebp
  jne    L64
  pop    %rbx
  pop    %rbp
  ret
  nop
L64:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no)) check_args_24(int a0, int a1, int a2, int a3, int a4, int a5, int a6, int a7, int a8, int a9, int a10) {
  if (a0 != 0 || a1 != 1 || a2 != 2 || a3 != 3 || a4 != 4 || a5 != 5 || a6 != 6 || a7 != 7 || a8 != 8 || a9 != 9 || a10 != 10)
    abort();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<after_first>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L14
L19:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L14:
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *after_first(const char str[], char c) {
  const char *result = strchr(str, c);
  result = (result == NULL) ? (str + strlen(str)) : (result + 1);
  return (char *)result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<after_first>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl %sil,%esi
  call   <strchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  je     L9
L10:
  mov    %rdx,%rax
  pop    %rbx
  ret
L9:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  add    %rbx,%rdx
  jmp    L10
```

assistant: ```c
char *after_first(const char str[], char c) {
  const char *result = strchr(str, c);
  result = (result == NULL) ? (str + strlen(str)) : (result + 1);
  return (char *)result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<after_first>:
  endbr64
  push   %rbx
  movsbl %sil,%esi
  mov    %rdi,%rbx
  call   <strchr@plt>
  lea    0x1(%rax),%r8
  test   %rax,%rax
  je     L8
  mov    %r8,%rax
  pop    %rbx
  ret
  nop
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%r8
  add    %rbx,%r8
  pop    %rbx
  mov    %r8,%rax
  ret
```

assistant: ```c
char *after_first(const char str[], char c) {
  const char *result = strchr(str, c);
  result = (result == NULL) ? (str + strlen(str)) : (result + 1);
  return (char *)result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<after_first>:
  endbr64
  push   %rbx
  movsbl %sil,%esi
  mov    %rdi,%rbx
  call   <strchr@plt>
  lea    0x1(%rax),%r8
  test   %rax,%rax
  je     L5
  mov    %r8,%rax
  pop    %rbx
  ret
  nop
L5:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%r8
  add    %rbx,%r8
  pop    %rbx
  mov    %r8,%rax
  ret
```

assistant: ```c
char *after_first(const char str[], char c) {
  const char *result = strchr(str, c);
  result = (result == NULL) ? (str + strlen(str)) : (result + 1);
  return (char *)result;
}
```