ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<date_stamp>:
  endbr64
  push   %r12
  mov    $0x19,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <MALLOC@plt>
  xor    %edi,%edi
  mov    %rax,%r12
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  lea    D9(%rip),%rdx
  mov    $0xc,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: %d-%b-%Y

assistant: ```c
char *date_stamp(void) {
  time_t t;
  char *t_stamp;
  t_stamp = (char *)MALLOC(25 * sizeof(char));
  t = time(NULL);
  strftime(t_stamp, 12, "%d-%b-%Y", localtime(&t));
  return t_stamp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<date_stamp>:
  endbr64
  push   %r12
  mov    $0x19,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <MALLOC@plt>
  xor    %edi,%edi
  mov    %rax,%r12
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  lea    D7(%rip),%rdx
  mov    $0xc,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: %d-%b-%Y

assistant: ```c
char *date_stamp(void) {
  time_t t;
  char *t_stamp;
  t_stamp = (char *)MALLOC(25 * sizeof(char));
  t = time(NULL);
  strftime(t_stamp, 12, "%d-%b-%Y", localtime(&t));
  return t_stamp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CntBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L17:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  add    %eax,-0x4(%rbp)
  sarl   -0x14(%rbp)
L4:
  cmpl   $0x0,-0x14(%rbp)
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int CntBits(uint16_t x) {
  int nbits = 0;
  while (x != 0) {
    nbits += x & 1;
    x >>= 1;
  }
  return nbits;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CntBits>:
  endbr64
  test   %edi,%edi
  je     L9
  mov    $0x0,%eax
L3:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  sar    %edi
  jne    L3
  ret
L9:
  mov    %edi,%eax
  ret
```

assistant: ```c
int CntBits(uint16_t x) {
  int nbits = 0;
  while (x != 0) {
    nbits += x & 1;
    x >>= 1;
  }
  return nbits;
}
```
user: What is the c source code of the assembly code below?

```asm
<CntBits>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L17
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  sar    %edi
  jne    L7
  ret
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
int CntBits(uint16_t x) {
  int nbits = 0;
  while (x != 0) {
    nbits += x & 1;
    x >>= 1;
  }
  return nbits;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CntBits>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L1
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  sar    %edi
  jne    L12
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
int CntBits(uint16_t x) {
  int nbits = 0;
  while (x != 0) {
    nbits += x & 1;
    x >>= 1;
  }
  return nbits;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D24
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: byte[8]
name: read_data
arguments: data_label: D38
type_guessed: string

tool: D24: Enter the value in Degrees Fahrenheit >

tool: D9: %lf

tool: {"D7": [0xb8,0x1e,0x85,0xeb,0x51,0x38,0x31,0xc0]}

tool: D38: That equals to %.2f Degrees Celsius


assistant: ```c
int main() {
  double celsius, fahrenheit;
  printf("Enter the value in Degrees Fahrenheit >\n");
  scanf("%lf", &fahrenheit);
  celsius = -17.22 * fahrenheit;
  printf("That equals to %.2f Degrees Celsius\n", celsius);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  movsd  D22(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  lea    D38(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D37
type: string
name: unpack_data
arguments: label: D33
type: string
name: unpack_data
arguments: label: D22
type: byte[8]
name: unpack_data
arguments: label: D38
type: string

tool: D37: Enter the value in Degrees Fahrenheit >

tool: D33: %lf

tool: {"D22": [0xb8,0x1e,0x85,0xeb,0x51,0x38,0x31,0xc0]}

tool: D38: That equals to %.2f Degrees Celsius


assistant: ```c
int main() {
  double celsius, fahrenheit;
  printf("Enter the value in Degrees Fahrenheit >\n");
  scanf("%lf", &fahrenheit);
  celsius = -17.22 * fahrenheit;
  printf("That equals to %.2f Degrees Celsius\n", celsius);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D34(%rip),%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  D9(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  lea    D0(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D31
type: string
name: unpack_data
arguments: tag: D34
type: string
name: unpack_data
arguments: tag: D9
type: byte[8]
name: unpack_data
arguments: tag: D0
type: string

tool: D31: Enter the value in Degrees Fahrenheit >

tool: D34: %lf

tool: {"D9": [0xb8,0x1e,0x85,0xeb,0x51,0x38,0x31,0xc0]}

tool: D0: That equals to %.2f Degrees Celsius


assistant: ```c
int main() {
  double celsius, fahrenheit;
  printf("Enter the value in Degrees Fahrenheit >\n");
  scanf("%lf", &fahrenheit);
  celsius = -17.22 * fahrenheit;
  printf("That equals to %.2f Degrees Celsius\n", celsius);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D27(%rip),%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  D14(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  lea    D5(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D23
data_type: string
name: parse_data
arguments: label: D27
data_type: string
name: parse_data
arguments: label: D14
data_type: byte[8]
name: parse_data
arguments: label: D5
data_type: string

tool: D23: Enter the value in Degrees Fahrenheit >

tool: D27: %lf

tool: {"D14": [0xb8,0x1e,0x85,0xeb,0x51,0x38,0x31,0xc0]}

tool: D5: That equals to %.2f Degrees Celsius


assistant: ```c
int main() {
  double celsius, fahrenheit;
  printf("Enter the value in Degrees Fahrenheit >\n");
  scanf("%lf", &fahrenheit);
  celsius = -17.22 * fahrenheit;
  printf("That equals to %.2f Degrees Celsius\n", celsius);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nlat2nlon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x24(%rbp)
  jne    L44
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <cdoAbort@plt>
L44:
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <fac@plt>
  jmp    L8
L33:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L57
L55:
  addl   $0x1,-0xc(%rbp)
L57:
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L55
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <fac@plt>
L8:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L33
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
data_type: string

tool: D7: nlat = 0!

assistant: ```c
int nlat2nlon(int nlat) {
  int nlon, m, ierr;
  if (nlat == 0)
    cdoAbort("nlat = 0!");
  nlon = 2 * nlat;
  fac(nlon, &m, &ierr);
  while (ierr != 0) {
    nlon = m;
    while (nlon % 4 != 0)
      nlon++;
    fac(nlon, &m, &ierr);
  }
  return (nlon);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nlat2nlon>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L10
L55:
  add    %ebx,%ebx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %ebx,%edi
  call   <fac@plt>
  cmpl   $0x0,0x4(%rsp)
  je     L26
  lea    0x4(%rsp),%rbp
L57:
  mov    (%rsp),%ebx
  test   $0x3,%bl
  je     L22
L46:
  add    $0x1,%ebx
  test   $0x3,%bl
  jne    L46
L22:
  mov    %rsp,%rsi
  mov    %rbp,%rdx
  mov    %ebx,%edi
  call   <fac@plt>
  cmpl   $0x0,0x4(%rsp)
  jne    L57
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  lea    D7(%rip),%rdi
  call   <cdoAbort@plt>
  jmp    L55
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: nlat = 0!

assistant: ```c
int nlat2nlon(int nlat) {
  int nlon, m, ierr;
  if (nlat == 0)
    cdoAbort("nlat = 0!");
  nlon = 2 * nlat;
  fac(nlon, &m, &ierr);
  while (ierr != 0) {
    nlon = m;
    while (nlon % 4 != 0)
      nlon++;
    fac(nlon, &m, &ierr);
  }
  return (nlon);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nlat2nlon>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L62
L4:
  add    %r12d,%r12d
  lea    0x4(%rsp),%rbp
  mov    %rsp,%rbx
  xchg   %ax,%ax
L12:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <fac@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L48
  mov    (%rsp),%r12d
  test   $0x3,%r12b
  je     L12
L52:
  add    $0x1,%r12d
  test   $0x3,%r12b
  jne    L52
  jmp    L12
  nopl   0x0(%rax)
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L62:
  lea    D4(%rip),%rdi
  call   <cdoAbort@plt>
  jmp    L4
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: nlat = 0!

assistant: ```c
int nlat2nlon(int nlat) {
  int nlon, m, ierr;
  if (nlat == 0)
    cdoAbort("nlat = 0!");
  nlon = 2 * nlat;
  fac(nlon, &m, &ierr);
  while (ierr != 0) {
    nlon = m;
    while (nlon % 4 != 0)
      nlon++;
    fac(nlon, &m, &ierr);
  }
  return (nlon);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nlat2nlon>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L42
L58:
  add    %r12d,%r12d
  lea    0x4(%rsp),%rbp
  mov    %rsp,%rbx
  xchg   %ax,%ax
L21:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <fac@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L41
  mov    (%rsp),%r12d
  test   $0x3,%r12b
  je     L21
L65:
  add    $0x1,%r12d
  test   $0x3,%r12b
  jne    L65
  jmp    L21
  nopl   0x0(%rax)
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  lea    D3(%rip),%rdi
  call   <cdoAbort@plt>
  jmp    L58
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D3: nlat = 0!

assistant: ```c
int nlat2nlon(int nlat) {
  int nlon, m, ierr;
  if (nlat == 0)
    cdoAbort("nlat = 0!");
  nlon = 2 * nlat;
  fac(nlon, &m, &ierr);
  while (ierr != 0) {
    nlon = m;
    while (nlon % 4 != 0)
      nlon++;
    fac(nlon, &m, &ierr);
  }
  return (nlon);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tm_get_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
unsigned long tm_get_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return 1000000 * tv.tv_sec + tv.tv_usec;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tm_get_time>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long tm_get_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return 1000000 * tv.tv_sec + tv.tv_usec;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tm_get_time>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long tm_get_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return 1000000 * tv.tv_sec + tv.tv_usec;
}
```
user: What is the c source code of the assembly code below?

```asm
<tm_get_time>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long tm_get_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return 1000000 * tv.tv_sec + tv.tv_usec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: MBEDTLS_BIGNUM_C and/or MBEDTLS_FS_IO not defined.


assistant: ```c
int main(void) {
  printf("MBEDTLS_BIGNUM_C and/or MBEDTLS_FS_IO not defined.\n");
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: MBEDTLS_BIGNUM_C and/or MBEDTLS_FS_IO not defined.


assistant: ```c
int main(void) {
  printf("MBEDTLS_BIGNUM_C and/or MBEDTLS_FS_IO not defined.\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: MBEDTLS_BIGNUM_C and/or MBEDTLS_FS_IO not defined.


assistant: ```c
int main(void) {
  printf("MBEDTLS_BIGNUM_C and/or MBEDTLS_FS_IO not defined.\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D5: MBEDTLS_BIGNUM_C and/or MBEDTLS_FS_IO not defined.


assistant: ```c
int main(void) {
  printf("MBEDTLS_BIGNUM_C and/or MBEDTLS_FS_IO not defined.\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<e8back>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L15
L99:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0xf,-0xc(%rbp)
  jne    L22
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  cmp    $0x80,%eax
  jne    L22
  addl   $0x1,-0x10(%rbp)
  movl   $0xe8,-0xc(%rbp)
L22:
  andl   $0xfe,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  cmpl   $0xe8,-0xc(%rbp)
  jne    L15
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  neg    %edx
  cmp    %edx,%eax
  jl     L84
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L84
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L1
L84:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L1
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L1
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L1:
  addl   $0x4,-0x10(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  sub    $0x5,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L99
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void e8back(uint8_t *buf, int32_t n) {
  int32_t i;
  int32_t *op;
  for (i = 0; i < n - 5;) {
    uint8_t b = buf[i];
    if ((b == 0xF) && (buf[i + 1] & 0xF0) == 0x80) {
      i++;
      b = 0xe8;
    }
    b &= 0xFE;
    i++;
    if (b == 0xe8) {
      op = (int32_t *)(buf + i);
      if (*op >= -i && *op < 0) {
        *op += n;
      } else if (*op >= 0 && *op < n) {
        *op -= i;
      }
      i += 4;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<e8back>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%r11d
  mov    $0x0,%eax
  lea    -0x5(%rsi),%r8d
L126:
  mov    %eax,%edx
  lea    0x1(%rax),%esi
  cltq
  lea    (%r10,%rax,4),%rcx
  jmp    L83
L76:
  mov    %esi,%r9d
  and    $0xfe,%eax
  cmp    $0xe8,%eax
  je     L85
L6:
  add    $0x1,%edx
  add    $0x1,%esi
  add    $0x4,%rcx
L83:
  mov    %edx,%edi
  cmp    %edx,%r8d
  jle    L109
  mov    (%rcx),%eax
  cmp    $0xf,%eax
  jne    L76
  mov    0x4(%rcx),%eax
  and    $0xf0,%eax
  cmp    $0x80,%eax
  jne    L6
  lea    0x1(%rdi),%eax
  lea    0x2(%rdi),%r9d
L64:
  movslq %r9d,%rdx
  lea    (%r10,%rdx,4),%rcx
  mov    (%rcx),%edx
  mov    %eax,%esi
  not    %esi
  cmp    %esi,%edx
  jl     L41
  test   %edx,%edx
  js     L82
L41:
  cmp    %r11d,%edx
  jge    L102
  test   %edx,%edx
  jns    L72
L102:
  add    $0x5,%eax
  jmp    L126
L85:
  mov    %edi,%eax
  jmp    L64
L82:
  add    %r11d,%edx
  mov    %edx,(%rcx)
  jmp    L102
L72:
  sub    %r9d,%edx
  mov    %edx,(%rcx)
  jmp    L102
L109:
  ret
```

assistant: ```c
void e8back(uint8_t *buf, int32_t n) {
  int32_t i;
  int32_t *op;
  for (i = 0; i < n - 5;) {
    uint8_t b = buf[i];
    if ((b == 0xF) && (buf[i + 1] & 0xF0) == 0x80) {
      i++;
      b = 0xe8;
    }
    b &= 0xFE;
    i++;
    if (b == 0xe8) {
      op = (int32_t *)(buf + i);
      if (*op >= -i && *op < 0) {
        *op += n;
      } else if (*op >= 0 && *op < n) {
        *op -= i;
      }
      i += 4;
    }
  }
}
```