ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<bug_w>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    $0x10,%edi
  lea    D60(%rip),%rbp
  push   %rbx
  mov    $0x4f,%ebx
  sub    $0x8,%rsp
  call   <cup@plt>
  lea    D74(%rip),%rdi
  call   <println@plt>
  lea    D77(%rip),%rdi
  call   <println@plt>
  lea    D43(%rip),%rdi
  call   <println@plt>
  lea    D48(%rip),%rdi
  call   <println@plt>
  lea    D52(%rip),%rdi
  call   <println@plt>
  lea    D22(%rip),%rdi
  call   <println@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <cup@plt>
  nopl   0x0(%rax)
L16:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L16
  mov    $0x1,%ebx
  lea    D71(%rip),%rbp
  nopl   0x0(%rax)
L12:
  mov    %ebx,%edi
  mov    $0x50,%esi
  add    $0x1,%ebx
  call   <hvp@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x19,%ebx
  jne    L12
  mov    $0x1,%esi
  mov    $0x18,%edi
  call   <cup@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    10d0 <holdit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D60
datatype: string
name: retrieve_data
arguments: label: D74
datatype: string
name: retrieve_data
arguments: label: D77
datatype: string
name: retrieve_data
arguments: label: D43
datatype: string
name: retrieve_data
arguments: label: D48
datatype: string
name: retrieve_data
arguments: label: D52
datatype: string
name: retrieve_data
arguments: label: D22
datatype: string
name: retrieve_data
arguments: label: D71
datatype: string

tool: D60: +

tool: D74:    This illustrates the "wrap around bug" which exists on a

tool: D77:    standard VT100. At the top of the screen there should be

tool: D43:    a row of +'s, and the rightmost column should be filled

tool: D48:    with *'s. But if the bug is present, some of the *'s may

tool: D52:    be placed in other places, e.g. in the leftmost column,

tool: D22:    and the top line of +'s may be scrolled away.

tool: D71: *

assistant: ```c
bug_w() {
  int row, col;
  cup(16, 1);
  println("   This illustrates the \"wrap around bug\" which exists on a");
  println("   standard VT100. At the top of the screen there should be");
  println("   a row of +'s, and the rightmost column should be filled");
  println("   with *'s. But if the bug is present, some of the *'s may");
  println("   be placed in other places, e.g. in the leftmost column,");
  println("   and the top line of +'s may be scrolled away.");
  cup(1, 1);
  for (col = 1; col <= 79; col++)
    printf("+");
  for (row = 1; row <= 24; row++) {
    hvp(row, 80);
    printf("*");
  }
  cup(24, 1);
  holdit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <foo@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a[6] = {};
  int ret = foo(3, a);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rsi
  mov    $0x3,%edi
  call   <foo@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a[6] = {};
  int ret = foo(3, a);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x3,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <foo@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a[6] = {};
  int ret = foo(3, a);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x3,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <foo@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a[6] = {};
  int ret = foo(3, a);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%edi
  movslq %edi,%rax
  lea    0x0(,%rax,4),%rcx
  imul   %rax,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L32:
  cmp    %rdx,%rsp
  je     L23
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L32
L23:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L4
  orq    $0x0,-0x8(%rsp,%rax,1)
L4:
  mov    %rsp,-0x48(%rbp)
  test   %edi,%edi
  jle    L89
  shr    $0x2,%rcx
  mov    %rcx,-0x50(%rbp)
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  lea    D6(%rip),%r13
  jmp    L12
L14:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x3c(%rbp)
  jg     L14
L37:
  add    $0x1,%r14d
  mov    -0x3c(%rbp),%edi
  add    -0x50(%rbp),%r15
  cmp    %r14d,%edi
  jle    L89
L12:
  mov    -0x48(%rbp),%rax
  lea    (%rax,%r15,4),%r12
  mov    $0x0,%ebx
  cmpl   $0x0,-0x3c(%rbp)
  jg     L14
  jmp    L37
L89:
  mov    -0x48(%rbp),%rsi
  call   <isMagic@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int square[n][n];
  for (int i = 0; i < n; i++)
    for (int j = 0; j < n; j++)
      scanf("%d", &square[i][j]);
  printf("%d", isMagic(n, square));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  lea    D4(%rip),%r15
  push   %r14
  mov    %r15,%rdi
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdi
  lea    0x0(,%rax,4),%r14
  imul   %rax,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L61
L25:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L25
L61:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L88
L24:
  mov    %rsp,-0x48(%rbp)
  test   %edi,%edi
  jle    L35
  shr    $0x2,%r14
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  mov    %r14,-0x50(%rbp)
  nopw   0x0(%rax,%rax,1)
L62:
  mov    -0x48(%rbp),%rax
  xor    %ebx,%ebx
  lea    (%rax,%r13,4),%r14
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %r14,%rsi
  mov    %r15,%rdi
  add    $0x1,%ebx
  add    $0x4,%r14
  call   <scanf@plt>
  mov    -0x3c(%rbp),%edi
  cmp    %ebx,%edi
  jg     L60
  add    $0x1,%r12d
  add    -0x50(%rbp),%r13
  cmp    %r12d,%edi
  jle    L35
  test   %edi,%edi
  jg     L62
L35:
  mov    -0x48(%rbp),%rsi
  call   <isMagic@plt>
  mov    %r15,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L88:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L24
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int square[n][n];
  for (int i = 0; i < n; i++)
    for (int j = 0; j < n; j++)
      scanf("%d", &square[i][j]);
  printf("%d", isMagic(n, square));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    D9(%rip),%r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdi
  lea    0x0(,%rax,4),%rsi
  imul   %rax,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L7
L11:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L11
L7:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L64
L5:
  mov    %rsp,-0x48(%rbp)
  test   %edi,%edi
  jle    L3
  shr    $0x2,%rsi
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  mov    %rsi,-0x50(%rbp)
  nopw   0x0(%rax,%rax,1)
L35:
  mov    -0x48(%rbp),%rax
  xor    %ebx,%ebx
  lea    (%rax,%r12,4),%r15
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r15
  call   <scanf@plt>
  mov    -0x3c(%rbp),%edi
  cmp    %ebx,%edi
  jg     L55
  add    $0x1,%r13d
  cmp    %r13d,%edi
  jle    L3
  add    -0x50(%rbp),%r12
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L3:
  mov    -0x48(%rbp),%rsi
  call   <isMagic@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L64:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L5
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int square[n][n];
  for (int i = 0; i < n; i++)
    for (int j = 0; j < n; j++)
      scanf("%d", &square[i][j]);
  printf("%d", isMagic(n, square));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getLines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strCount@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getStringArray@plt>
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: 


assistant: ```c
char **getLines(char *string) {
  int nLines = strCount(string, '\n') + 1;
  char **lines = malloc(sizeof(char *) * (nLines + 1));
  getStringArray(string, lines, "\n\r");
  lines[nLines] = NULL;
  return lines;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getLines>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0xa,%esi
  call   <strCount@plt>
  mov    %eax,%ebx
  lea    0x10(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D2(%rip),%rdx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <getStringArray@plt>
  add    $0x1,%ebx
  movslq %ebx,%rbx
  movq   $0x0,0x0(%rbp,%rbx,8)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: 


assistant: ```c
char **getLines(char *string) {
  int nLines = strCount(string, '\n') + 1;
  char **lines = malloc(sizeof(char *) * (nLines + 1));
  getStringArray(string, lines, "\n\r");
  lines[nLines] = NULL;
  return lines;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getLines>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strCount@plt>
  mov    %eax,%ebx
  lea    0x10(,%rax,8),%edi
  call   <malloc@plt>
  add    $0x1,%ebx
  mov    %rbp,%rdi
  lea    D0(%rip),%rdx
  mov    %rax,%r12
  movslq %ebx,%rbx
  mov    %rax,%rsi
  call   <getStringArray@plt>
  movq   $0x0,(%r12,%rbx,8)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: 


assistant: ```c
char **getLines(char *string) {
  int nLines = strCount(string, '\n') + 1;
  char **lines = malloc(sizeof(char *) * (nLines + 1));
  getStringArray(string, lines, "\n\r");
  lines[nLines] = NULL;
  return lines;
}
```
user: What is the c source code of the assembly code below:

```asm
<getLines>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strCount@plt>
  mov    %eax,%ebx
  lea    0x10(,%rax,8),%edi
  call   <malloc@plt>
  add    $0x1,%ebx
  mov    %rbp,%rdi
  lea    D2(%rip),%rdx
  mov    %rax,%r12
  movslq %ebx,%rbx
  mov    %rax,%rsi
  call   <getStringArray@plt>
  movq   $0x0,(%r12,%rbx,8)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string

tool: D2: 


assistant: ```c
char **getLines(char *string) {
  int nLines = strCount(string, '\n') + 1;
  char **lines = malloc(sizeof(char *) * (nLines + 1));
  getStringArray(string, lines, "\n\r");
  lines[nLines] = NULL;
  return lines;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L7
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  jmp    L22
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x20,%eax
L22:
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strupper(char *str) {
  char *p;
  for (p = str; *p != '\0'; ++p)
    *p = ((!isalpha(*p) || isupper(*p)) ? (*p) : ((*p) - 'a' + 'A'));
  return (str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strupper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L11
  mov    %rbp,%rbx
  jmp    L2
L15:
  movzbl (%rbx),%eax
L46:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L11
L2:
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L15
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L15
  movzbl (%rbx),%eax
  sub    $0x20,%eax
  jmp    L46
L11:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strupper(char *str) {
  char *p;
  for (p = str; *p != '\0'; ++p)
    *p = ((!isalpha(*p) || isupper(*p)) ? (*p) : ((*p) - 'a' + 'A'));
  return (str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strupper>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L57
  mov    %r12,%rbx
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L30:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L57
L4:
  call   <isalpha@plt>
  test   %eax,%eax
  je     L30
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L30
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  sub    $0x20,%eax
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L4
L57:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strupper(char *str) {
  char *p;
  for (p = str; *p != '\0'; ++p)
    *p = ((!isalpha(*p) || isupper(*p)) ? (*p) : ((*p) - 'a' + 'A'));
  return (str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strupper>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L37
  mov    %r12,%rbx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L38:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L37
L16:
  call   <isalpha@plt>
  test   %eax,%eax
  je     L38
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L38
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  sub    $0x20,%eax
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L16
L37:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strupper(char *str) {
  char *p;
  for (p = str; *p != '\0'; ++p)
    *p = ((!isalpha(*p) || isupper(*p)) ? (*p) : ((*p) - 'a' + 'A'));
  return (str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cosenoh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  lea    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <getNumber@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <cosh@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double cosenoh(double a) {
  getNumber(&a);
  return cosh(a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cosenoh>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <getNumber@plt>
  movsd  0x8(%rsp),%xmm0
  call   <cosh@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
double cosenoh(double a) {
  getNumber(&a);
  return cosh(a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cosenoh>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <getNumber@plt>
  movsd  0x8(%rsp),%xmm0
  call   <cosh@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
double cosenoh(double a) {
  getNumber(&a);
  return cosh(a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cosenoh>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <getNumber@plt>
  movsd  0x8(%rsp),%xmm0
  call   <cosh@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
double cosenoh(double a) {
  getNumber(&a);
  return cosh(a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<flt22>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7,-0x4(%rbp)
  jne    L39
  mov    $0xffffffff,%eax
  jmp    L22
L39:
  cmpl   $0x2,-0x8(%rbp)
  ja     L46
  mov    $0x0,%eax
  jmp    L22
L46:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jae    L8
  mov    $0x0,%eax
  call   <unreachable@plt>
L8:
  mov    $0x1,%eax
L22:
  leave
  ret
```

assistant: ```c
int flt22(int a) {
  unsigned i = a / 4;
  unsigned j = i - 2;
  if (j == 7)
    return -1;
  if (i <= 2)
    return 0;
  if (i < j)
    unreachable();
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flt22>:
  endbr64
  lea    0x3(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x2,%eax
  mov    $0xffffffff,%edx
  cmp    $0x9,%eax
  je     L9
  cmp    $0x2,%eax
  seta   %dl
  movzbl %dl,%edx
L9:
  mov    %edx,%eax
  ret
```

assistant: ```c
int flt22(int a) {
  unsigned i = a / 4;
  unsigned j = i - 2;
  if (j == 7)
    return -1;
  if (i <= 2)
    return 0;
  if (i < j)
    unreachable();
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<flt22>:
  endbr64
  test   %edi,%edi
  lea    0x3(%rdi),%eax
  mov    $0xffffffff,%r8d
  cmovns %edi,%eax
  sar    $0x2,%eax
  cmp    $0x9,%eax
  je     L1
  xor    %r8d,%r8d
  cmp    $0x2,%eax
  seta   %r8b
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int flt22(int a) {
  unsigned i = a / 4;
  unsigned j = i - 2;
  if (j == 7)
    return -1;
  if (i <= 2)
    return 0;
  if (i < j)
    unreachable();
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flt22>:
  endbr64
  test   %edi,%edi
  lea    0x3(%rdi),%eax
  mov    $0xffffffff,%r8d
  cmovns %edi,%eax
  sar    $0x2,%eax
  cmp    $0x9,%eax
  je     L2
  xor    %r8d,%r8d
  cmp    $0x2,%eax
  seta   %r8b
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int flt22(int a) {
  unsigned i = a / 4;
  unsigned j = i - 2;
  if (j == 7)
    return -1;
  if (i <= 2)
    return 0;
  if (i < j)
    unreachable();
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sporth_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1505,-0x4(%rbp)
  jmp    L10
L5:
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rdx
  shl    $0x1e,%rdx
  add    %rcx,%rdx
  shr    $0x20,%rdx
  sar    $0x1d,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  shl    $0x1f,%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t sporth_hash(const char *str) {
  uint32_t h = 5381;
  while (*str) {
    h = ((h << 5) + h) ^ str[0];
    h %= 0x7FFFFFFF;
    str++;
  }
  return h % 256;
}
```
user: What is the c source code of the assembly code below:

```asm
<sporth_hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L21
  mov    $0x1505,%eax
L3:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  add    %ecx,%eax
  movsbl %dl,%edx
  xor    %eax,%edx
  movslq %edx,%rcx
  mov    %rcx,%rax
  shl    $0x1e,%rax
  add    %rcx,%rax
  sar    $0x3d,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x1f,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
L10:
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  ret
L21:
  mov    $0x1505,%eax
  jmp    L10
```

assistant: ```c
uint32_t sporth_hash(const char *str) {
  uint32_t h = 5381;
  while (*str) {
    h = ((h << 5) + h) ^ str[0];
    h %= 0x7FFFFFFF;
    str++;
  }
  return h % 256;
}
```