ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<train>:
  endbr64
  lea    0x7(%rdx),%r8d
  mov    %ecx,%r9d
  and    $0xfffffff8,%r8d
  jle    L18
  movslq %r8d,%r8
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L16:
  movswl (%rdi,%rdx,2),%eax
  movswl (%rsi,%rdx,2),%ecx
  imul   %r9d,%eax
  add    %eax,%eax
  sar    $0x10,%eax
  add    $0x1,%eax
  sar    %eax
  add    %ecx,%eax
  mov    $0x7fff,%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    $0xffff8000,%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  mov    %ax,(%rsi,%rdx,2)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L16
L18:
  ret
```

assistant: ```c
void train(short *t, short *w, int n, int err) {
  n = (n + 7) & -8;
  for (int i = 0; i < n; ++i) {
    int wt = w[i] + ((t[i] * err * 2 >> 16) + 1 >> 1);
    if (wt < -32768)
      wt = -32768;
    if (wt > 32767)
      wt = 32767;
    w[i] = wt;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L10:
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(const char *str) {
  const char *cstr;
  int i;
  for (i = 0, cstr = str; *cstr != 0; cstr++, i++)
    ;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x0,%eax
L3:
  add    $0x1,%rdi
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L3
  ret
L1:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strlen(const char *str) {
  const char *cstr;
  int i;
  for (i = 0, cstr = str; *cstr != 0; cstr++, i++)
    ;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L6
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rdi
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L11
  ret
  nopl   (%rax)
L6:
  ret
```

assistant: ```c
int strlen(const char *str) {
  const char *cstr;
  int i;
  for (i = 0, cstr = str; *cstr != 0; cstr++, i++)
    ;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L4
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rdi
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L1
  ret
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
int strlen(const char *str) {
  const char *cstr;
  int i;
  for (i = 0, cstr = str; *cstr != 0; cstr++, i++)
    ;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D43(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D43(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D43(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D36(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x3,-0x34(%rbp)
  lea    -0x30(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rsi
  lea    -0x34(%rbp),%rax
  mov    %rax,%rdi
  call   <dscal_@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L6
L4:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L6:
  cmpl   $0x2,-0x2c(%rbp)
  jle    L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D43
datatype: byte[8]
name: unpack_data
arguments: data_tag: D36
datatype: f64
name: unpack_data
arguments: data_tag: D46
datatype: string

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D36: 4.323

tool: D46: %f


assistant: ```c
int main() {
  int i, n, one;
  double coefficient;
  double x[] = {1, 1, 1};
  coefficient = 4.323;
  one = 1;
  n = 3;
  dscal_(&n, &coefficient, &x[0], &one);
  for (i = 0; i < 3; ++i)
    printf("%f\n", x[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm0,0x20(%rsp)
  mov    D27(%rip),%rax
  mov    %rax,0x8(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x3,(%rsp)
  lea    0x4(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  call   <dscal_@plt>
  movsd  0x10(%rsp),%xmm0
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movsd  0x18(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  movsd  0x20(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: byte[8]
name: retrieve_data
arguments: label: D27
type_guessed: f64
name: retrieve_data
arguments: label: D5
type_guessed: string

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D27: 4.323

tool: D5: %f


assistant: ```c
int main() {
  int i, n, one;
  double coefficient;
  double x[] = {1, 1, 1};
  coefficient = 4.323;
  one = 1;
  n = 3;
  dscal_(&n, &coefficient, &x[0], &one);
  for (i = 0; i < 3; ++i)
    printf("%f\n", x[i]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  sub    $0x30,%rsp
  movsd  D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rdi
  mov    D13(%rip),%rax
  lea    0x8(%rsp),%rsi
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm0,0x20(%rsp)
  mov    %rax,0x8(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x3,(%rsp)
  call   <dscal_@plt>
  movsd  0x10(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  0x18(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  0x20(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string
name: read_data
arguments: data_label: D17
type_infered: byte[8]
name: read_data
arguments: data_label: D13
type_infered: f64

tool: D4: %f


tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D13: 4.323

assistant: ```c
int main() {
  int i, n, one;
  double coefficient;
  double x[] = {1, 1, 1};
  coefficient = 4.323;
  one = 1;
  n = 3;
  dscal_(&n, &coefficient, &x[0], &one);
  for (i = 0; i < 3; ++i)
    printf("%f\n", x[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rbp
  sub    $0x30,%rsp
  movapd D36(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rdi
  mov    D36(%rip),%rax
  lea    0x8(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  movl   $0x1,0x4(%rsp)
  mov    %rax,0x20(%rsp)
  mov    D21(%rip),%rax
  movl   $0x3,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <dscal_@plt>
  movsd  0x10(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  0x18(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  0x20(%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D36
type: byte[16]
name: disassemble_data
arguments: data_tag: D21
type: f64

tool: D10: %f


tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D21: 4.323

assistant: ```c
int main() {
  int i, n, one;
  double coefficient;
  double x[] = {1, 1, 1};
  coefficient = 4.323;
  one = 1;
  n = 3;
  dscal_(&n, &coefficient, &x[0], &one);
  for (i = 0; i < 3; ++i)
    printf("%f\n", x[i]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func4(int i) {
  typeof(i = 0, 1) j;
  typeof(int *) pi;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func4>:
  endbr64
  ret
```

assistant: ```c
void func4(int i) {
  typeof(i = 0, 1) j;
  typeof(int *) pi;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func4>:
  endbr64
  ret
```

assistant: ```c
void func4(int i) {
  typeof(i = 0, 1) j;
  typeof(int *) pi;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<func4>:
  endbr64
  ret
```

assistant: ```c
void func4(int i) {
  typeof(i = 0, 1) j;
  typeof(int *) pi;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gffi_get_int_64_swapped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  add    $0x5,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  add    $0x6,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  add    $0x7,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int64_t gffi_get_int_64_swapped(int8_t *location, int offset) {
  int8_t buf[8];
  buf[7] = location[offset];
  buf[6] = location[offset + 1];
  buf[5] = location[offset + 2];
  buf[4] = location[offset + 3];
  buf[3] = location[offset + 4];
  buf[2] = location[offset + 5];
  buf[1] = location[offset + 6];
  buf[0] = location[offset + 7];
  return *(int64_t *)buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gffi_get_int_64_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0x1c(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int64_t gffi_get_int_64_swapped(int8_t *location, int offset) {
  int8_t buf[8];
  buf[7] = location[offset];
  buf[6] = location[offset + 1];
  buf[5] = location[offset + 2];
  buf[4] = location[offset + 3];
  buf[3] = location[offset + 4];
  buf[2] = location[offset + 5];
  buf[1] = location[offset + 6];
  buf[0] = location[offset + 7];
  return *(int64_t *)buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gffi_get_int_64_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0x1c(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int64_t gffi_get_int_64_swapped(int8_t *location, int offset) {
  int8_t buf[8];
  buf[7] = location[offset];
  buf[6] = location[offset + 1];
  buf[5] = location[offset + 2];
  buf[4] = location[offset + 3];
  buf[3] = location[offset + 4];
  buf[2] = location[offset + 5];
  buf[1] = location[offset + 6];
  buf[0] = location[offset + 7];
  return *(int64_t *)buf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gffi_get_int_64_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0x1c(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int64_t gffi_get_int_64_swapped(int8_t *location, int offset) {
  int8_t buf[8];
  buf[7] = location[offset];
  buf[6] = location[offset + 1];
  buf[5] = location[offset + 2];
  buf[4] = location[offset + 3];
  buf[3] = location[offset + 4];
  buf[2] = location[offset + 5];
  buf[1] = location[offset + 6];
  buf[0] = location[offset + 7];
  return *(int64_t *)buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rInnerproduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L17:
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x28,-0x4(%rbp)
  jle    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rInnerproduct(float *result, float a[40 + 1][40 + 1], float b[40 + 1][40 + 1], int row, int column) {
  int i;
  *result = 0.0f;
  for (i = 1; i <= 40; i++)
    *result = *result + a[row][i] * b[i][column];
}
```
user: What is the c source code of the assembly code below?

```asm
<rInnerproduct>:
  endbr64
  movl   $0x0,(%rdi)
  movslq %ecx,%rcx
  lea    (%rcx,%rcx,4),%rax
  lea    (%rcx,%rax,8),%rax
  lea    0x4(%rsi,%rax,4),%rcx
  movslq %r8d,%r8
  lea    0xa4(,%r8,4),%rsi
  lea    (%rdx,%rsi,1),%rax
  lea    0x19a0(%rdx,%rsi,1),%rdx
L2:
  movss  (%rcx),%xmm0
  mulss  (%rax),%xmm0
  addss  (%rdi),%xmm0
  movss  %xmm0,(%rdi)
  add    $0x4,%rcx
  add    $0xa4,%rax
  cmp    %rdx,%rax
  jne    L2
  ret
```

assistant: ```c
void rInnerproduct(float *result, float a[40 + 1][40 + 1], float b[40 + 1][40 + 1], int row, int column) {
  int i;
  *result = 0.0f;
  for (i = 1; i <= 40; i++)
    *result = *result + a[row][i] * b[i][column];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rInnerproduct>:
  endbr64
  movslq %ecx,%rcx
  movslq %r8d,%r8
  movl   $0x0,(%rdi)
  pxor   %xmm1,%xmm1
  lea    (%rcx,%rcx,4),%rax
  lea    (%rcx,%rax,8),%rax
  lea    0x4(%rsi,%rax,4),%rcx
  lea    0xa4(,%r8,4),%rsi
  lea    (%rdx,%rsi,1),%rax
  lea    0x19a0(%rdx,%rsi,1),%rdx
  nopl   (%rax)
L3:
  movss  (%rcx),%xmm0
  mulss  (%rax),%xmm0
  add    $0xa4,%rax
  add    $0x4,%rcx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  cmp    %rdx,%rax
  jne    L3
  ret
```

assistant: ```c
void rInnerproduct(float *result, float a[40 + 1][40 + 1], float b[40 + 1][40 + 1], int row, int column) {
  int i;
  *result = 0.0f;
  for (i = 1; i <= 40; i++)
    *result = *result + a[row][i] * b[i][column];
}
```
user: Translate the below assembly code into C programming language:

```asm
<rInnerproduct>:
  endbr64
  movslq %ecx,%rcx
  movslq %r8d,%r8
  movl   $0x0,(%rdi)
  pxor   %xmm1,%xmm1
  lea    (%rcx,%rcx,4),%rax
  lea    (%rcx,%rax,8),%rax
  lea    0x4(%rsi,%rax,4),%rcx
  lea    0xa4(,%r8,4),%rsi
  lea    (%rdx,%rsi,1),%rax
  lea    0x19a0(%rdx,%rsi,1),%rdx
  nopl   (%rax)
L1:
  movss  (%rcx),%xmm0
  mulss  (%rax),%xmm0
  add    $0xa4,%rax
  add    $0x4,%rcx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  cmp    %rdx,%rax
  jne    L1
  ret
```

assistant: ```c
void rInnerproduct(float *result, float a[40 + 1][40 + 1], float b[40 + 1][40 + 1], int row, int column) {
  int i;
  *result = 0.0f;
  for (i = 1; i <= 40; i++)
    *result = *result + a[row][i] * b[i][column];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L13
L19:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  while (*src) {
    *dest++ = *src++;
  }
  *dest = '\0';
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L2
L5:
  add    $0x1,%rsi
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L5
L2:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  while (*src) {
    *dest++ = *src++;
  }
  *dest = '\0';
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L3
  xchg   %ax,%ax
L7:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L7
L3:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  while (*src) {
    *dest++ = *src++;
  }
  *dest = '\0';
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L10
  xchg   %ax,%ax
L9:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L9
L10:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  while (*src) {
    *dest++ = *src++;
  }
  *dest = '\0';
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aml_array_dbl_1d_load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <aml_array_dbl_1d_new@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: %lf

assistant: ```c
double *aml_array_dbl_1d_load(FILE *file, int s1) {
  int i;
  double *arr = aml_array_dbl_1d_new(s1, 0);
  for (i = 0; i < s1; i++)
    fscanf(file, "%lf", &arr[i]);
  return arr;
}
```
user: What is the c source code of the assembly code below?

```asm
<aml_array_dbl_1d_load>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <aml_array_dbl_1d_new@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L17
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r13
  lea    D6(%rip),%r12
L10:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L10
L17:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %lf

assistant: ```c
double *aml_array_dbl_1d_load(FILE *file, int s1) {
  int i;
  double *arr = aml_array_dbl_1d_new(s1, 0);
  for (i = 0; i < s1; i++)
    fscanf(file, "%lf", &arr[i]);
  return arr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aml_array_dbl_1d_load>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <aml_array_dbl_1d_new@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L8
  lea    (%rax,%r12,8),%r13
  mov    %rax,%rbx
  lea    D1(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <fscanf@plt>
  cmp    %r13,%rbx
  jne    L4
L8:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %lf

assistant: ```c
double *aml_array_dbl_1d_load(FILE *file, int s1) {
  int i;
  double *arr = aml_array_dbl_1d_new(s1, 0);
  for (i = 0; i < s1; i++)
    fscanf(file, "%lf", &arr[i]);
  return arr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aml_array_dbl_1d_load>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <aml_array_dbl_1d_new@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L0
  lea    (%rax,%r12,8),%r13
  mov    %rax,%rbx
  lea    D1(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <fscanf@plt>
  cmp    %r13,%rbx
  jne    L8
L0:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %lf

assistant: ```c
double *aml_array_dbl_1d_load(FILE *file, int s1) {
  int i;
  double *arr = aml_array_dbl_1d_new(s1, 0);
  for (i = 0; i < s1; i++)
    fscanf(file, "%lf", &arr[i]);
  return arr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x1,-0x8(%rbp)
  ja     L7
  mov    $0x1,%eax
  jmp    L6
L7:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <factorial>
  imul   -0x8(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
unsigned long factorial(unsigned long n) {
  if (n <= 1)
    return 1;
  return n * factorial(n - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%rdi
  jbe    L3
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rdi),%rdi
  call   <factorial>
  imul   %rbx,%rax
  pop    %rbx
  ret
L3:
  ret
```

assistant: ```c
unsigned long factorial(unsigned long n) {
  if (n <= 1)
    return 1;
  return n * factorial(n - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%rdi
  jbe    L4
  nop
L19:
  mov    %rdi,%rdx
  sub    $0x1,%rdi
  imul   %rdx,%rax
  cmp    $0x1,%rdi
  jne    L19
L4:
  ret
```

assistant: ```c
unsigned long factorial(unsigned long n) {
  if (n <= 1)
    return 1;
  return n * factorial(n - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%rdi
  jbe    L18
  nop
L9:
  mov    %rdi,%rdx
  sub    $0x1,%rdi
  imul   %rdx,%rax
  cmp    $0x1,%rdi
  jne    L9
L18:
  ret
```

assistant: ```c
unsigned long factorial(unsigned long n) {
  if (n <= 1)
    return 1;
  return n * factorial(n - 1);
}
```