ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_32_0_0>:
  endbr64
  and    (%rdi),%dl
  not    %esi
  and    %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_32_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_32_0_0>:
  endbr64
  and    (%rdi),%dl
  not    %esi
  and    %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_32_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L8
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void mergeSort(int *A, int p, int r) {
  if (p < r) {
    int q = (p + r) / 2;
    mergeSort(A, p, q);
    mergeSort(A, (q + 1), r);
    merge(A, p, q, r);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mergeSort>:
  endbr64
  cmp    %edx,%esi
  jl     L7
  ret
L7:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <mergeSort>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <mergeSort>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mergeSort(int *A, int p, int r) {
  if (p < r) {
    int q = (p + r) / 2;
    mergeSort(A, p, q);
    mergeSort(A, (q + 1), r);
    merge(A, p, q, r);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <newchunk@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  cmpl   $0x0,-0xc(%rbp)
  jle    L0
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *sdup(s)
register const char *s;
{
  int n = strlen(s) + 1;
  char *cp = newchunk(n);
  (strncpy((cp), (s), (n)), ((n) <= 0 ? 0 : ((cp)[(n)-1] = '\0')), strlen((s)));
  return (cp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <newchunk@plt>
  movslq %eax,%rbp
  movslq %ebx,%r13
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  test   %ebx,%ebx
  jle    L2
  movb   $0x0,-0x1(%rbp,%r13,1)
L2:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *sdup(s)
register const char *s;
{
  int n = strlen(s) + 1;
  char *cp = newchunk(n);
  (strncpy((cp), (s), (n)), ((n) <= 0 ? 0 : ((cp)[(n)-1] = '\0')), strlen((s)));
  return (cp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  xor    %eax,%eax
  mov    %ebx,%edi
  movslq %ebx,%r12
  call   <newchunk@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <strncpy@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L5
  movb   $0x0,-0x1(%rax,%r12,1)
L5:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *sdup(s)
register const char *s;
{
  int n = strlen(s) + 1;
  char *cp = newchunk(n);
  (strncpy((cp), (s), (n)), ((n) <= 0 ? 0 : ((cp)[(n)-1] = '\0')), strlen((s)));
  return (cp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  xor    %eax,%eax
  mov    %ebx,%edi
  movslq %ebx,%r12
  call   <newchunk@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <strncpy@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L4
  movb   $0x0,-0x1(%rax,%r12,1)
L4:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *sdup(s)
register const char *s;
{
  int n = strlen(s) + 1;
  char *cp = newchunk(n);
  (strncpy((cp), (s), (n)), ((n) <= 0 ? 0 : ((cp)[(n)-1] = '\0')), strlen((s)));
  return (cp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SKP_Silk_resampler_private_AR2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzwl (%rax),%eax
  cwtl
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  shll   $0x2,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  movzwl (%rax),%eax
  cwtl
  mov    %edx,%esi
  imul   %eax,%esi
  mov    -0x4(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x30(%rbp),%rax
  movzwl (%rax),%eax
  cwtl
  imul   %edx,%eax
  sar    $0x10,%eax
  add    %esi,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cwtl
  mov    %edx,%ecx
  imul   %eax,%ecx
  mov    -0x4(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x30(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cwtl
  imul   %edx,%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SKP_Silk_resampler_private_AR2(int S[], int out_Q8[], const short in[], const short A_Q14[], int len) {
  int k;
  int out32;
  for (k = 0; k < len; k++) {
    out32 = (((S[0])) + (((((int)in[k])) << ((8)))));
    out_Q8[k] = out32;
    out32 = ((out32) << (2));
    S[0] = ((S[1]) + ((((out32) >> 16) * (int)((short)(A_Q14[0]))) + ((((out32)&0x0000FFFF) * (int)((short)(A_Q14[0]))) >> 16)));
    S[1] = ((((out32) >> 16) * (int)((short)(A_Q14[1]))) + ((((out32)&0x0000FFFF) * (int)((short)(A_Q14[1]))) >> 16));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SKP_Silk_resampler_private_AR2>:
  endbr64
  test   %r8d,%r8d
  jle    L11
  push   %rbx
  mov    %rdx,%r9
  mov    %rcx,%r10
  mov    %r8d,%r8d
  mov    $0x0,%ecx
L0:
  movswl (%r9,%rcx,2),%eax
  shl    $0x8,%eax
  add    (%rdi),%eax
  mov    %eax,(%rsi,%rcx,4)
  shl    $0x2,%eax
  mov    %eax,%r11d
  sar    $0x10,%r11d
  movswl (%r10),%ebx
  movzwl %ax,%eax
  mov    %ebx,%edx
  imul   %eax,%edx
  sar    $0x10,%edx
  imul   %r11d,%ebx
  add    %ebx,%edx
  add    0x4(%rdi),%edx
  mov    %edx,(%rdi)
  movswl 0x2(%r10),%edx
  imul   %edx,%eax
  sar    $0x10,%eax
  imul   %edx,%r11d
  add    %r11d,%eax
  mov    %eax,0x4(%rdi)
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L0
  pop    %rbx
  ret
L11:
  ret
```

assistant: ```c
void SKP_Silk_resampler_private_AR2(int S[], int out_Q8[], const short in[], const short A_Q14[], int len) {
  int k;
  int out32;
  for (k = 0; k < len; k++) {
    out32 = (((S[0])) + (((((int)in[k])) << ((8)))));
    out_Q8[k] = out32;
    out32 = ((out32) << (2));
    S[0] = ((S[1]) + ((((out32) >> 16) * (int)((short)(A_Q14[0]))) + ((((out32)&0x0000FFFF) * (int)((short)(A_Q14[0]))) >> 16)));
    S[1] = ((((out32) >> 16) * (int)((short)(A_Q14[1]))) + ((((out32)&0x0000FFFF) * (int)((short)(A_Q14[1]))) >> 16));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SKP_Silk_resampler_private_AR2>:
  endbr64
  test   %r8d,%r8d
  jle    L19
  push   %rbp
  mov    (%rdi),%r11d
  mov    %rdx,%r9
  movslq %r8d,%r8
  push   %rbx
  movswl (%rcx),%r10d
  xor    %edx,%edx
  movswl 0x2(%rcx),%ecx
  xchg   %ax,%ax
L3:
  movswl (%r9,%rdx,2),%eax
  shl    $0x8,%eax
  add    %r11d,%eax
  mov    %r10d,%r11d
  mov    %eax,(%rsi,%rdx,4)
  shl    $0x2,%eax
  add    $0x1,%rdx
  mov    %eax,%ebx
  movzwl %ax,%eax
  imul   %eax,%r11d
  sar    $0x10,%ebx
  imul   %ecx,%eax
  mov    %ebx,%ebp
  imul   %ecx,%ebx
  imul   %r10d,%ebp
  sar    $0x10,%r11d
  sar    $0x10,%eax
  add    %ebx,%eax
  add    %ebp,%r11d
  add    0x4(%rdi),%r11d
  mov    %eax,0x4(%rdi)
  cmp    %rdx,%r8
  jne    L3
  pop    %rbx
  pop    %rbp
  mov    %r11d,(%rdi)
  ret
  xchg   %ax,%ax
L19:
  ret
```

assistant: ```c
void SKP_Silk_resampler_private_AR2(int S[], int out_Q8[], const short in[], const short A_Q14[], int len) {
  int k;
  int out32;
  for (k = 0; k < len; k++) {
    out32 = (((S[0])) + (((((int)in[k])) << ((8)))));
    out_Q8[k] = out32;
    out32 = ((out32) << (2));
    S[0] = ((S[1]) + ((((out32) >> 16) * (int)((short)(A_Q14[0]))) + ((((out32)&0x0000FFFF) * (int)((short)(A_Q14[0]))) >> 16)));
    S[1] = ((((out32) >> 16) * (int)((short)(A_Q14[1]))) + ((((out32)&0x0000FFFF) * (int)((short)(A_Q14[1]))) >> 16));
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<SKP_Silk_resampler_private_AR2>:
  endbr64
  test   %r8d,%r8d
  jle    L2
  push   %rbp
  mov    (%rdi),%r11d
  mov    %rdx,%r9
  movslq %r8d,%r8
  push   %rbx
  movswl (%rcx),%r10d
  xor    %edx,%edx
  movswl 0x2(%rcx),%ecx
  xchg   %ax,%ax
L15:
  movswl (%r9,%rdx,2),%eax
  shl    $0x8,%eax
  add    %r11d,%eax
  mov    %r10d,%r11d
  mov    %eax,(%rsi,%rdx,4)
  shl    $0x2,%eax
  add    $0x1,%rdx
  mov    %eax,%ebx
  movzwl %ax,%eax
  sar    $0x10,%ebx
  imul   %eax,%r11d
  mov    %ebx,%ebp
  imul   %ecx,%eax
  imul   %r10d,%ebp
  imul   %ecx,%ebx
  sar    $0x10,%r11d
  sar    $0x10,%eax
  add    %ebp,%r11d
  add    0x4(%rdi),%r11d
  add    %ebx,%eax
  movd   %r11d,%xmm0
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  cmp    %rdx,%r8
  jne    L15
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void SKP_Silk_resampler_private_AR2(int S[], int out_Q8[], const short in[], const short A_Q14[], int len) {
  int k;
  int out32;
  for (k = 0; k < len; k++) {
    out32 = (((S[0])) + (((((int)in[k])) << ((8)))));
    out_Q8[k] = out32;
    out32 = ((out32) << (2));
    S[0] = ((S[1]) + ((((out32) >> 16) * (int)((short)(A_Q14[0]))) + ((((out32)&0x0000FFFF) * (int)((short)(A_Q14[0]))) >> 16)));
    S[1] = ((((out32) >> 16) * (int)((short)(A_Q14[1]))) + ((((out32)&0x0000FFFF) * (int)((short)(A_Q14[1]))) >> 16));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<speclog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %edi,-0x3c(%rbp)
  mov    %esi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x50(%rbp),%r12
  mov    -0x58(%rbp),%r13
  mov    -0x60(%rbp),%rbx
  mov    $0x0,%r14d
  jmp    L12
L34:
  movsd  (%r12),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L4
  mov    (%r12),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  mov    %rax,0x0(%r13)
  mov    %rbx,%rax
  lea    0x4(%rax),%rbx
  movl   $0x0,(%rax)
  jmp    L35
L4:
  mov    %rbx,%rax
  lea    0x4(%rax),%rbx
  movl   $0x1,(%rax)
  movl   $0x4,-0x24(%rbp)
L35:
  mov    -0x40(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%r12
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%r13
  add    $0x1,%r14d
L12:
  cmp    -0x3c(%rbp),%r14d
  jl     L34
  mov    -0x24(%rbp),%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int speclog(dummy, nspec, sspec, sloge, spec, loge, stat)
double dummy;
int nspec, sspec, sloge;
const double spec[];
double loge[];
int stat[];
{
  int status = 0;
  register int ispec, *statp;
  register const double *specp;
  register double *logep;
  specp = spec;
  logep = loge;
  statp = stat;
  for (ispec = 0; ispec < nspec; ispec++) {
    if (*specp > 0.0) {
      *logep = log(*specp);
      *(statp++) = 0;
    } else {
      *(statp++) = 1;
      status = 4;
    }
    specp += sspec;
    logep += sloge;
  }
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<speclog>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L20
  mov    %rcx,%rbp
  mov    %r8,%r12
  movslq %esi,%rsi
  lea    0x0(,%rsi,8),%r14
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%r13
  lea    0x4(%r9),%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%r9,%rax,4),%r15
  movl   $0x0,0xc(%rsp)
  jmp    L3
L28:
  call   <log@plt>
  movsd  %xmm0,(%r12)
  mov    $0x0,%eax
L49:
  mov    %eax,-0x4(%rbx)
  add    %r14,%rbp
  add    %r13,%r12
  add    $0x4,%rbx
  cmp    %r15,%rbx
  je     L44
L3:
  movsd  0x0(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L28
  mov    $0x1,%eax
  movl   $0x4,0xc(%rsp)
  jmp    L49
L20:
  movl   $0x0,0xc(%rsp)
L44:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int speclog(dummy, nspec, sspec, sloge, spec, loge, stat)
double dummy;
int nspec, sspec, sloge;
const double spec[];
double loge[];
int stat[];
{
  int status = 0;
  register int ispec, *statp;
  register const double *specp;
  register double *logep;
  specp = spec;
  logep = loge;
  statp = stat;
  for (ispec = 0; ispec < nspec; ispec++) {
    if (*specp > 0.0) {
      *logep = log(*specp);
      *(statp++) = 0;
    } else {
      *(statp++) = 1;
      status = 4;
    }
    specp += sspec;
    logep += sloge;
  }
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<speclog>:
  endbr64
  movslq %edi,%rax
  test   %eax,%eax
  jle    L4
  push   %r15
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%r9,%rax,4),%r15
  push   %r14
  lea    0x0(,%rsi,8),%r14
  push   %r13
  lea    0x0(,%rdx,8),%r13
  push   %r12
  mov    %r8,%r12
  xor    %r8d,%r8d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L15:
  movsd  0x0(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  add    $0x4,%rbx
  mov    %r8d,0xc(%rsp)
  mov    $0x1,%eax
  mov    $0x4,%r8d
  comisd %xmm1,%xmm0
  jbe    L24
  call   <log@plt>
  mov    0xc(%rsp),%r8d
  xor    %eax,%eax
  movsd  %xmm0,(%r12)
L24:
  mov    %eax,-0x4(%rbx)
  add    %r14,%rbp
  add    %r13,%r12
  cmp    %rbx,%r15
  jne    L15
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int speclog(dummy, nspec, sspec, sloge, spec, loge, stat)
double dummy;
int nspec, sspec, sloge;
const double spec[];
double loge[];
int stat[];
{
  int status = 0;
  register int ispec, *statp;
  register const double *specp;
  register double *logep;
  specp = spec;
  logep = loge;
  statp = stat;
  for (ispec = 0; ispec < nspec; ispec++) {
    if (*specp > 0.0) {
      *logep = log(*specp);
      *(statp++) = 0;
    } else {
      *(statp++) = 1;
      status = 4;
    }
    specp += sspec;
    logep += sloge;
  }
  return status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<speclog>:
  endbr64
  movslq %edi,%rax
  test   %eax,%eax
  jle    L34
  push   %r15
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%r9,%rax,4),%r15
  push   %r14
  xor    %eax,%eax
  lea    0x0(,%rsi,8),%r14
  push   %r13
  lea    0x0(,%rdx,8),%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L38:
  movsd  0x0(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  add    $0x4,%rbx
  mov    %eax,0xc(%rsp)
  comisd %xmm1,%xmm0
  ja     L16
  movl   $0x1,-0x4(%rbx)
  add    %r14,%rbp
  add    %r13,%r12
  mov    $0x4,%eax
  cmp    %rbx,%r15
  jne    L38
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L16:
  call   <log@plt>
  add    %r14,%rbp
  mov    0xc(%rsp),%eax
  movsd  %xmm0,(%r12)
  add    %r13,%r12
  cmp    %rbx,%r15
  movl   $0x0,-0x4(%rbx)
  jne    L38
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int speclog(dummy, nspec, sspec, sloge, spec, loge, stat)
double dummy;
int nspec, sspec, sloge;
const double spec[];
double loge[];
int stat[];
{
  int status = 0;
  register int ispec, *statp;
  register const double *specp;
  register double *logep;
  specp = spec;
  logep = loge;
  statp = stat;
  for (ispec = 0; ispec < nspec; ispec++) {
    if (*specp > 0.0) {
      *logep = log(*specp);
      *(statp++) = 0;
    } else {
      *(statp++) = 1;
      status = 4;
    }
    specp += sspec;
    logep += sloge;
  }
  return status;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L16
L10:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
char pop(char *buff, int *top) {
  if (*top == 0)
    return -1;
  return buff[--(*top)];
}
```
user: What is the c source code of the assembly code below?

```asm
<pop>:
  endbr64
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L0
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  cltq
  movzbl (%rdi,%rax,1),%eax
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
char pop(char *buff, int *top) {
  if (*top == 0)
    return -1;
  return buff[--(*top)];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pop>:
  endbr64
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L7
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  cltq
  movzbl (%rdi,%rax,1),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
char pop(char *buff, int *top) {
  if (*top == 0)
    return -1;
  return buff[--(*top)];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pop>:
  endbr64
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L6
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  cltq
  movzbl (%rdi,%rax,1),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
char pop(char *buff, int *top) {
  if (*top == 0)
    return -1;
  return buff[--(*top)];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtok_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L58
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  mov    $0x0,%eax
  jmp    L103
L58:
  cmpq   $0x0,-0x10(%rbp)
  jne    L50
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L50
L40:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L35
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L108
L35:
  addq   $0x1,-0x20(%rbp)
L36:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
L108:
  addq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L50:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  jmp    L82
L64:
  nop
L82:
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
L103:
  pop    %rbp
  ret
```

assistant: ```c
char *strtok_r(char *str, const char *delim, char **saveptr) {
  char *base = str;
  const char *delim_base = delim;
  if (!str && !(**saveptr))
    return NULL;
  if (base == NULL) {
    base = *saveptr;
    str = *saveptr;
  }
  while (*str) {
    while (*delim) {
      if (*delim == *str) {
        *str = 0;
        break;
      }
      ++delim;
    }
    ++str;
    if (*delim)
      break;
    delim = delim_base;
  }
  *saveptr = str;
  return base;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtok_r>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L91
L73:
  lea    0x1(%rax),%r10
  jmp    L90
L91:
  mov    (%rdx),%rcx
  cmpb   $0x0,(%rcx)
  je     L18
  mov    %rcx,%rax
  jmp    L73
L12:
  movb   $0x0,-0x1(%r11)
  cmpb   $0x0,(%r8)
  jne    L16
L11:
  add    $0x1,%r10
L90:
  lea    -0x1(%r10),%rcx
  mov    %r10,%r11
  movzbl -0x1(%r10),%r9d
  test   %r9b,%r9b
  je     L50
  movzbl (%rsi),%ecx
  mov    %rsi,%r8
  test   %cl,%cl
  je     L11
L24:
  cmp    %cl,%r9b
  je     L12
  add    $0x1,%r8
  movzbl (%r8),%ecx
  test   %cl,%cl
  jne    L24
  jmp    L11
L16:
  mov    %r11,%rcx
L50:
  mov    %rcx,(%rdx)
L18:
  ret
```

assistant: ```c
char *strtok_r(char *str, const char *delim, char **saveptr) {
  char *base = str;
  const char *delim_base = delim;
  if (!str && !(**saveptr))
    return NULL;
  if (base == NULL) {
    base = *saveptr;
    str = *saveptr;
  }
  while (*str) {
    while (*delim) {
      if (*delim == *str) {
        *str = 0;
        break;
      }
      ++delim;
    }
    ++str;
    if (*delim)
      break;
    delim = delim_base;
  }
  *saveptr = str;
  return base;
}
```