ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x350,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x348(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L40
  lea    0x14(%rsp),%rbp
  mov    $0x1,%ebx
  lea    D18(%rip),%r12
L86:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jge    L86
  test   %ecx,%ecx
  jle    L40
  lea    0x1(%rcx),%edi
  mov    $0x1,%eax
  mov    $0x0,%esi
L62:
  lea    0x1(%rax),%edx
  cmp    %eax,%ecx
  cmove  %esi,%edx
  mov    %edx,0x1b0(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L62
L40:
  lea    0x1(%rcx),%ebx
  movslq %ebx,%rbp
  lea    0x10(%rsp,%rbp,4),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp,%rbp,4),%esi
  mov    $0x1,%eax
L75:
  mov    %eax,%ecx
  cltq
  mov    0x1b0(%rsp,%rax,4),%eax
  movslq %eax,%rdx
  cmp    %esi,0x10(%rsp,%rdx,4)
  jg     L8
  test   %eax,%eax
  jne    L75
L24:
  mov    $0x1,%eax
  lea    D34(%rip),%rbp
L30:
  movslq %eax,%rbx
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x1b0(%rsp,%rbx,4),%eax
  test   %eax,%eax
  jne    L30
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x348(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  mov    $0x0,%eax
  add    $0x350,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  movslq %ebx,%rdx
  mov    %eax,0x1b0(%rsp,%rdx,4)
  movslq %ecx,%rcx
  mov    %ebx,0x1b0(%rsp,%rcx,4)
  jmp    L24
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
type: string
name: unpack_data
arguments: tag: D34
type: string

tool: D18: %d

tool: D34: %d 

assistant: ```c
int main() {
  int data[101], right[101];
  int i, n, t, len;
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    scanf("%d", &data[i]);
  len = n;
  for (i = 1; i <= n; i++) {
    if (i != n)
      right[i] = i + 1;
    else
      right[i] = 0;
  }
  len++;
  scanf("%d", &data[len]);
  t = 1;
  while (t != 0) {
    if (data[right[t]] > data[len]) {
      right[len] = right[t];
      right[t] = len;
      break;
    }
    t = right[t];
  }
  t = 1;
  while (t != 0) {
    printf("%d ", data[t]);
    t = right[t];
  }
  getchar();
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x350,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x348(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L35
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  cmp    %ebx,%ecx
  jge    L3
  test   %ecx,%ecx
  jle    L35
  lea    0x1(%rcx),%r8d
  mov    $0x1,%eax
  lea    0x1b0(%rsp),%rdi
  xor    %esi,%esi
  mov    %r8,%rbx
  nopl   0x0(%rax,%rax,1)
L0:
  lea    0x1(%rax),%edx
  cmp    %eax,%ecx
  cmove  %esi,%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L0
L58:
  movslq %ebx,%rbp
  mov    %r12,%rdi
  lea    0x10(%rsp,%rbp,4),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp,%rbp,4),%esi
  mov    $0x1,%eax
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L1:
  movslq 0x1b0(%rsp,%rdx,4),%rdx
  movslq %eax,%rcx
  mov    %rdx,%rax
  cmp    %esi,0x10(%rsp,%rdx,4)
  jg     L38
  test   %edx,%edx
  jne    L1
L15:
  mov    $0x1,%eax
  lea    D8(%rip),%rbp
  nopl   0x0(%rax)
L83:
  movslq %eax,%rbx
  mov    %rbp,%rdi
  mov    0x10(%rsp,%rbx,4),%esi
  call   <printf@plt>
  mov    0x1b0(%rsp,%rbx,4),%eax
  test   %eax,%eax
  jne    L83
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x348(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x350,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  mov    %edx,0x1b0(%rsp,%rbp,4)
  mov    %ebx,0x1b0(%rsp,%rcx,4)
  jmp    L15
L35:
  lea    0x1(%rcx),%ebx
  jmp    L58
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
datatype: string
name: parse_data
arguments: label: D8
datatype: string

tool: D16: %d

tool: D8: %d 

assistant: ```c
int main() {
  int data[101], right[101];
  int i, n, t, len;
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    scanf("%d", &data[i]);
  len = n;
  for (i = 1; i <= n; i++) {
    if (i != n)
      right[i] = i + 1;
    else
      right[i] = 0;
  }
  len++;
  scanf("%d", &data[len]);
  t = 1;
  while (t != 0) {
    if (data[right[t]] > data[len]) {
      right[len] = right[t];
      right[t] = len;
      break;
    }
    t = right[t];
  }
  t = 1;
  while (t != 0) {
    printf("%d ", data[t]);
    t = right[t];
  }
  getchar();
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GetResponse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
L11:
  mov    -0x428(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,-0x418(%rbp)
  jmp    L32
L46:
  addq   $0x1,-0x418(%rbp)
L32:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L46
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L11
L48:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %eax,-0x41c(%rbp)
  mov    -0x41c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int GetResponse(FILE *ps) {
  char szLine[1024];
  char *psz;
  int hr;
  fflush(ps);
  do {
    fgets(szLine, sizeof(szLine), ps);
    for (psz = szLine; isdigit(*psz); psz++)
      ;
  } while (*psz != '\0' && *psz != ' ');
  hr = atol(szLine);
  return hr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GetResponse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fflush@plt>
  mov    %rsp,%rbp
  jmp    L36
L13:
  add    $0x1,%rbx
L2:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L13
  testb  $0xdf,(%rbx)
  je     L0
L36:
  mov    %r12,%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rbx
  jmp    L2
L0:
  mov    %rsp,%rdi
  call   <atol@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetResponse(FILE *ps) {
  char szLine[1024];
  char *psz;
  int hr;
  fflush(ps);
  do {
    fgets(szLine, sizeof(szLine), ps);
    for (psz = szLine; isdigit(*psz); psz++)
      ;
  } while (*psz != '\0' && *psz != ' ');
  hr = atol(szLine);
  return hr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GetResponse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <fflush@plt>
  nopl   (%rax)
L6:
  mov    %r12,%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  mov    %rbp,%rbx
  call   <fgets@plt>
  jmp    L29
  nopl   (%rax)
L5:
  add    $0x1,%rbx
L29:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L5
  testb  $0xdf,(%rbx)
  jne    L6
  mov    %rbp,%rdi
  call   <atol@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetResponse(FILE *ps) {
  char szLine[1024];
  char *psz;
  int hr;
  fflush(ps);
  do {
    fgets(szLine, sizeof(szLine), ps);
    for (psz = szLine; isdigit(*psz); psz++)
      ;
  } while (*psz != '\0' && *psz != ' ');
  hr = atol(szLine);
  return hr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GetResponse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <fflush@plt>
  nopl   (%rax)
L33:
  mov    %r12,%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  mov    %rbp,%rbx
  call   <fgets@plt>
  jmp    L3
  nopl   (%rax)
L26:
  add    $0x1,%rbx
L3:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L26
  testb  $0xdf,(%rbx)
  jne    L33
  mov    %rbp,%rdi
  call   <atol@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetResponse(FILE *ps) {
  char szLine[1024];
  char *psz;
  int hr;
  fflush(ps);
  do {
    fgets(szLine, sizeof(szLine), ps);
    for (psz = szLine; isdigit(*psz); psz++)
      ;
  } while (*psz != '\0' && *psz != ' ');
  hr = atol(szLine);
  return hr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe4(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xdc(%rbp)
  jmp    L122
L123:
  movl   $0x0,-0xd8(%rbp)
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xd4(%rbp)
  movl   $0x0,-0xe0(%rbp)
  jmp    L38
L45:
  mov    -0xe0(%rbp),%eax
  cltq
  movzbl -0x90(%rbp,%rax,1),%eax
  cmp    $0x29,%al
  jne    L113
  mov    -0xd8(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  cmp    $0x28,%al
  jne    L113
  subl   $0x1,-0xd8(%rbp)
  jmp    L88
L113:
  mov    -0xe0(%rbp),%eax
  cltq
  movzbl -0x90(%rbp,%rax,1),%eax
  cmp    $0x5d,%al
  jne    L54
  mov    -0xd8(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  cmp    $0x5b,%al
  jne    L54
  subl   $0x1,-0xd8(%rbp)
  jmp    L88
L54:
  mov    -0xd8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xd8(%rbp)
  mov    -0xe0(%rbp),%edx
  movslq %edx,%rdx
  movzbl -0x90(%rbp,%rdx,1),%edx
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
L88:
  addl   $0x1,-0xe0(%rbp)
L38:
  mov    -0xe0(%rbp),%eax
  cmp    -0xd4(%rbp),%eax
  jl     L45
  cmpl   $0x0,-0xd8(%rbp)
  jne    L6
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L81
L6:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L81:
  addl   $0x1,-0xdc(%rbp)
L122:
  mov    -0xe4(%rbp),%eax
  cmp    %eax,-0xdc(%rbp)
  jl     L123
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string

tool: D14: %d


tool: D7: Yes


tool: D2: No


assistant: ```c
int main(void) {
  char c, x[128], t[64];
  int i, j, n, l, k;
  scanf("%d\n", &n);
  for (j = 0; j < n; j++) {
    k = 0;
    gets(x);
    l = strlen(x);
    for (i = 0; i < l; i++) {
      if (x[i] == ')' && t[k - 1] == '(')
        k--;
      else if (x[i] == ']' && t[k - 1] == '[')
        k--;
      else
        t[k++] = x[i];
    }
    if (k == 0)
      printf("Yes\n");
    else
      printf("No\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L96
  mov    $0x0,%ebx
  lea    0x50(%rsp),%rbp
  lea    D17(%rip),%r14
  lea    0x51(%rsp),%r12
  lea    D19(%rip),%r13
  jmp    L22
L74:
  lea    -0x1(%rcx),%esi
  movslq %esi,%r8
  cmpb   $0x28,0x10(%rsp,%r8,1)
  je     L125
L5:
  movslq %ecx,%rsi
  mov    %al,0x10(%rsp,%rsi,1)
  lea    0x1(%rcx),%ecx
L140:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L21
L69:
  movzbl (%rdx),%eax
  cmp    $0x29,%al
  je     L74
  cmp    $0x5d,%al
  jne    L5
  lea    -0x1(%rcx),%esi
  movslq %esi,%r8
  cmpb   $0x5b,0x10(%rsp,%r8,1)
  jne    L5
  mov    %esi,%ecx
  jmp    L140
L125:
  mov    %esi,%ecx
  jmp    L140
L21:
  test   %ecx,%ecx
  je     L24
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L7
L24:
  mov    %r14,%rdi
  call   <printf@plt>
L7:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L96
L22:
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L24
  lea    0x50(%rsp),%rdx
  lea    -0x1(%rax),%edi
  add    %r12,%rdi
  mov    $0x0,%ecx
  jmp    L69
L96:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L111
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L111:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D25
type_guessed: string
name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D19
type_guessed: string

tool: D25: %d


tool: D17: Yes


tool: D19: No


assistant: ```c
int main(void) {
  char c, x[128], t[64];
  int i, j, n, l, k;
  scanf("%d\n", &n);
  for (j = 0; j < n; j++) {
    k = 0;
    gets(x);
    l = strlen(x);
    for (i = 0; i < l; i++) {
      if (x[i] == ')' && t[k - 1] == '(')
        k--;
      else if (x[i] == ']' && t[k - 1] == '[')
        k--;
      else
        t[k++] = x[i];
    }
    if (k == 0)
      printf("Yes\n");
    else
      printf("No\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  lea    D27(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L24
  xor    %ebx,%ebx
  lea    0x50(%rsp),%rbp
  lea    D2(%rip),%r14
  lea    0x51(%rsp),%r12
  lea    D16(%rip),%r13
  nopl   (%rax)
L89:
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L116
  lea    -0x1(%rax),%edi
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  add    %r12,%rdi
  jmp    L61
  nopl   (%rax)
L46:
  cmp    $0x5d,%al
  je     L65
L26:
  movslq %ecx,%rsi
  add    $0x1,%rdx
  add    $0x1,%ecx
  mov    %al,0x10(%rsp,%rsi,1)
  cmp    %rdx,%rdi
  je     L86
L61:
  movzbl (%rdx),%eax
  cmp    $0x29,%al
  jne    L46
  lea    -0x1(%rcx),%esi
  movslq %esi,%r8
  cmpb   $0x28,0x10(%rsp,%r8,1)
  jne    L26
  mov    %esi,%ecx
L111:
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L61
L86:
  test   %ecx,%ecx
  je     L116
  mov    %r13,%rdi
  call   <printf@plt>
L21:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L89
L24:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L65:
  lea    -0x1(%rcx),%esi
  movslq %esi,%r8
  cmpb   $0x5b,0x10(%rsp,%r8,1)
  jne    L26
  mov    %esi,%ecx
  jmp    L111
  cs nopw 0x0(%rax,%rax,1)
L116:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L21
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D27
type: string
name: unpack_data
arguments: data_tag: D2
type: string
name: unpack_data
arguments: data_tag: D16
type: string

tool: D27: %d


tool: D2: Yes


tool: D16: No


assistant: ```c
int main(void) {
  char c, x[128], t[64];
  int i, j, n, l, k;
  scanf("%d\n", &n);
  for (j = 0; j < n; j++) {
    k = 0;
    gets(x);
    l = strlen(x);
    for (i = 0; i < l; i++) {
      if (x[i] == ')' && t[k - 1] == '(')
        k--;
      else if (x[i] == ']' && t[k - 1] == '[')
        k--;
      else
        t[k++] = x[i];
    }
    if (k == 0)
      printf("Yes\n");
    else
      printf("No\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L130
  xor    %ebx,%ebx
  lea    0x50(%rsp),%rbp
  lea    D18(%rip),%r14
  lea    0x51(%rsp),%r12
  lea    D27(%rip),%r13
  nopl   (%rax)
L116:
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L128
  lea    -0x1(%rax),%edi
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  add    %r12,%rdi
  jmp    L107
  nopl   (%rax)
L133:
  cmp    $0x5d,%al
  je     L102
L38:
  movslq %ecx,%rsi
  add    $0x1,%rdx
  add    $0x1,%ecx
  mov    %al,0x10(%rsp,%rsi,1)
  cmp    %rdx,%rdi
  je     L53
L107:
  movzbl (%rdx),%eax
  cmp    $0x29,%al
  jne    L133
  lea    -0x1(%rcx),%esi
  movslq %esi,%r8
  cmpb   $0x28,0x10(%rsp,%r8,1)
  jne    L38
  mov    %esi,%ecx
L24:
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L107
L53:
  test   %ecx,%ecx
  je     L128
  mov    %r13,%rdi
  call   <printf@plt>
L108:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L116
L130:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L102:
  lea    -0x1(%rcx),%esi
  movslq %esi,%r8
  cmpb   $0x5b,0x10(%rsp,%r8,1)
  jne    L38
  mov    %esi,%ecx
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L128:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L108
L109:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D18
type: string
name: disassemble_data
arguments: data_label: D27
type: string

tool: D0: %d


tool: D18: Yes


tool: D27: No


assistant: ```c
int main(void) {
  char c, x[128], t[64];
  int i, j, n, l, k;
  scanf("%d\n", &n);
  for (j = 0; j < n; j++) {
    k = 0;
    gets(x);
    l = strlen(x);
    for (i = 0; i < l; i++) {
      if (x[i] == ')' && t[k - 1] == '(')
        k--;
      else if (x[i] == ']' && t[k - 1] == '[')
        k--;
      else
        t[k++] = x[i];
    }
    if (k == 0)
      printf("Yes\n");
    else
      printf("No\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  cmpq   $0x0,-0x20(%rbp)
  je     L19
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L24
L19:
  nop
L24:
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *a1, int *a2) {
  int temp = 0;
  if (a1 == 0 || a2 == 0)
    return;
  temp = *a1;
  *a1 = *a2;
  *a2 = temp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<swap>:
  endbr64
  test   %rdi,%rdi
  je     L7
  test   %rsi,%rsi
  je     L7
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
L7:
  ret
```

assistant: ```c
void swap(int *a1, int *a2) {
  int temp = 0;
  if (a1 == 0 || a2 == 0)
    return;
  temp = *a1;
  *a1 = *a2;
  *a2 = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  test   %rdi,%rdi
  je     L7
  test   %rsi,%rsi
  je     L7
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
L7:
  ret
```

assistant: ```c
void swap(int *a1, int *a2) {
  int temp = 0;
  if (a1 == 0 || a2 == 0)
    return;
  temp = *a1;
  *a1 = *a2;
  *a2 = temp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap>:
  endbr64
  test   %rdi,%rdi
  je     L1
  test   %rsi,%rsi
  je     L1
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
L1:
  ret
```

assistant: ```c
void swap(int *a1, int *a2) {
  int temp = 0;
  if (a1 == 0 || a2 == 0)
    return;
  temp = *a1;
  *a1 = *a2;
  *a2 = temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L36:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L36
  sub    $0xc70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9c64(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x9c5c(%rbp)
  jmp    L37
L29:
  lea    -0x9c60(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x9c58(%rbp)
  jmp    L32
L84:
  movl   $0x0,-0x9c54(%rbp)
  jmp    L76
L27:
  lea    -0x9c50(%rbp),%rcx
  mov    -0x9c54(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9c58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x9c54(%rbp)
L76:
  mov    -0x9c60(%rbp),%eax
  cmp    %eax,-0x9c54(%rbp)
  jl     L27
  addl   $0x1,-0x9c58(%rbp)
L32:
  mov    -0x9c60(%rbp),%eax
  cmp    %eax,-0x9c58(%rbp)
  jl     L84
  mov    -0x9c60(%rbp),%edx
  lea    -0x9c50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <isStableGrid@plt>
  test   %rax,%rax
  je     L17
  lea    D27(%rip),%rax
  jmp    L96
L17:
  lea    D49(%rip),%rax
L96:
  mov    -0x9c5c(%rbp),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x9c5c(%rbp)
L37:
  mov    -0x9c64(%rbp),%eax
  cmp    %eax,-0x9c5c(%rbp)
  jle    L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D28
type_infered: string
name: parse_data
arguments: tag: D27
type_infered: string
name: parse_data
arguments: tag: D49
type_infered: string
name: parse_data
arguments: tag: D52
type_infered: string

tool: D28: %d

tool: D27: yes

tool: D49: no

tool: D52: Case %d: %s


assistant: ```c
int main(void) {
  int grid[100][100], T, mSize, caseId, row, col;
  scanf("%d", &T);
  caseId = 1;
  while (caseId <= T) {
    scanf("%d", &mSize);
    for (row = 0; row < mSize; row++)
      for (col = 0; col < mSize; col++)
        scanf("%d", &grid[row][col]);
    printf("Case %d: %s\n", caseId, isStableGrid(grid, mSize) ? "yes" : "no");
    caseId++;
  }
  return 0;
}
```