ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<two_sum_direct>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%ebx
  test   %ebx,%ebx
  jle    L54
  mov    $0x0,%ebp
  jmp    L31
L69:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %ebp,(%rax)
  mov    %ebx,0x4(%rax)
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  sub    $0x1,%ebx
L3:
  cmp    %ebx,%ebp
  jge    L1
L31:
  movslq %ebp,%rcx
  movslq %ebx,%rax
  mov    (%rdi,%rax,4),%eax
  add    (%rdi,%rcx,4),%eax
  cmp    %edx,%eax
  je     L69
  jge    L67
  add    $0x1,%ebp
  jmp    L3
L1:
  mov    $0x0,%eax
  jmp    L39
L54:
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
int *two_sum_direct(int *numbers, int numbers_size, int target) {
  int start = 0;
  int end = numbers_size - 1;
  int tmp;
  while (start < end) {
    tmp = numbers[start] + numbers[end];
    if (tmp == target) {
      int *ret = (int *)malloc(2 * sizeof(int));
      ret[0] = start;
      ret[1] = end;
      return ret;
    } else if (tmp < target)
      start++;
    else
      end--;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<two_sum_direct>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L53
  xor    %ebp,%ebp
  jmp    L1
  nopl   (%rax)
L3:
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jle    L53
L1:
  movslq %ebp,%rcx
  movslq %ebx,%rax
  mov    (%rdi,%rax,4),%eax
  add    (%rdi,%rcx,4),%eax
  cmp    %edx,%eax
  je     L34
  jl     L3
  sub    $0x1,%ebx
  cmp    %ebp,%ebx
  jg     L1
L53:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L34:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %ebp,(%rax)
  mov    %ebx,0x4(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *two_sum_direct(int *numbers, int numbers_size, int target) {
  int start = 0;
  int end = numbers_size - 1;
  int tmp;
  while (start < end) {
    tmp = numbers[start] + numbers[end];
    if (tmp == target) {
      int *ret = (int *)malloc(2 * sizeof(int));
      ret[0] = start;
      ret[1] = end;
      return ret;
    } else if (tmp < target)
      start++;
    else
      end--;
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<two_sum_direct>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L21
  xor    %ecx,%ecx
  xor    %r9d,%r9d
L47:
  movslq %esi,%r8
  mov    (%rdi,%r8,4),%eax
  add    (%rdi,%r9,4),%eax
  cmp    %edx,%eax
  je     L25
L55:
  jge    L59
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jge    L21
  movslq %ecx,%r9
  mov    (%rdi,%r8,4),%eax
  add    (%rdi,%r9,4),%eax
  cmp    %edx,%eax
  jne    L55
L25:
  movd   %ecx,%xmm0
  movd   %esi,%xmm1
  sub    $0x18,%rsp
  mov    $0x8,%edi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x8(%rsp)
  call   <malloc@plt>
  movq   0x8(%rsp),%xmm0
  movq   %xmm0,(%rax)
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L59:
  sub    $0x1,%esi
  cmp    %ecx,%esi
  jg     L47
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int *two_sum_direct(int *numbers, int numbers_size, int target) {
  int start = 0;
  int end = numbers_size - 1;
  int tmp;
  while (start < end) {
    tmp = numbers[start] + numbers[end];
    if (tmp == target) {
      int *ret = (int *)malloc(2 * sizeof(int));
      ret[0] = start;
      ret[1] = end;
      return ret;
    } else if (tmp < target)
      start++;
    else
      end--;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<ln_get_saturn_equ_sdiam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <ln_get_saturn_earth_dist@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: f64

tool: D8: 82.73

assistant: ```c
double ln_get_saturn_equ_sdiam(double JD) {
  double So = 82.73;
  double dist;
  dist = ln_get_saturn_earth_dist(JD);
  return So / dist;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ln_get_saturn_equ_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_saturn_earth_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D3(%rip),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: f64

tool: D3: 82.73

assistant: ```c
double ln_get_saturn_equ_sdiam(double JD) {
  double So = 82.73;
  double dist;
  dist = ln_get_saturn_earth_dist(JD);
  return So / dist;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ln_get_saturn_equ_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_saturn_earth_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  add    $0x8,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type: f64

tool: D2: 82.73

assistant: ```c
double ln_get_saturn_equ_sdiam(double JD) {
  double So = 82.73;
  double dist;
  dist = ln_get_saturn_earth_dist(JD);
  return So / dist;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ln_get_saturn_equ_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_saturn_earth_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D1(%rip),%xmm0
  add    $0x8,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: f64

tool: D1: 82.73

assistant: ```c
double ln_get_saturn_equ_sdiam(double JD) {
  double So = 82.73;
  double dist;
  dist = ln_get_saturn_earth_dist(JD);
  return So / dist;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SVCall_Handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L8:
  jmp    L8
```

assistant: ```c
void SVCall_Handler(void) {
  while (1) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SVCall_Handler>:
  endbr64
L1:
  jmp    L1
```

assistant: ```c
void SVCall_Handler(void) {
  while (1) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SVCall_Handler>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void SVCall_Handler(void) {
  while (1) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SVCall_Handler>:
  endbr64
  nopl   0x0(%rax)
L2:
  jmp    L2
```

assistant: ```c
void SVCall_Handler(void) {
  while (1) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kasai_lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x50(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L54:
  cmp    %rdx,%rsp
  je     L134
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L54
L134:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L131
  orq    $0x0,-0x8(%rsp,%rax,1)
L131:
  mov    %rsp,%r12
  test   %ecx,%ecx
  jle    L80
  mov    %ecx,%ebx
  mov    $0x0,%eax
L109:
  movslq 0x0(%r13,%rax,4),%rdx
  mov    %eax,(%r12,%rdx,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L109
  mov    $0x0,%r11d
  mov    $0x0,%eax
  lea    -0x1(%rcx),%r15d
  jmp    L6
L138:
  mov    -0x48(%rbp),%rdi
  mov    %eax,-0x4(%rdi,%r14,1)
  test   %eax,%eax
  setg   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
L119:
  add    $0x1,%r11
  cmp    %rbx,%r11
  je     L80
L6:
  mov    %r11d,%r9d
  mov    (%r12,%r11,4),%edx
  cmp    %r15d,%edx
  je     L110
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%r14
  mov    0x0(%r13,%rdx,4),%r10d
  lea    (%rax,%r11,1),%edi
  cmp    %edi,%ecx
  jle    L138
  lea    (%r10,%rax,1),%r8d
  cmp    %r8d,%ecx
  jle    L138
  movslq %edi,%rdi
  mov    -0x50(%rbp),%rdx
  add    %rdi,%rdx
  movslq %r8d,%r8
L52:
  mov    %rdx,%rsi
  sub    %rdi,%rsi
  movzbl (%rsi,%r8,1),%esi
  cmp    %sil,(%rdx)
  jne    L138
  add    $0x1,%eax
  lea    (%rax,%r9,1),%esi
  cmp    %esi,%ecx
  jle    L138
  add    $0x1,%rdx
  lea    (%r10,%rax,1),%esi
  cmp    %esi,%ecx
  jg     L52
  jmp    L138
L110:
  mov    $0x0,%eax
  jmp    L119
L80:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void kasai_lcp(char *text, int *lcp, int *suffArr, int n) {
  int i;
  int invSuff[n];
  for (i = 0; i < n; i++) {
    invSuff[suffArr[i]] = i;
  }
  int k = 0;
  for (i = 0; i < n; i++) {
    if (invSuff[i] == n - 1) {
      k = 0;
      continue;
    }
    int j = suffArr[invSuff[i] + 1];
    while (i + k < n && j + k < n && text[i + k] == text[j + k]) {
      k++;
    }
    lcp[invSuff[i]] = k;
    if (k > 0) {
      k--;
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kasai_lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  movslq %ecx,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,-0x50(%rbp)
  mov    %r12,%rsi
  mov    %rdi,-0x58(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r12,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L118
L129:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L129
L118:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L61
L120:
  mov    %rsp,%r13
  xor    %eax,%eax
  test   %esi,%esi
  jle    L165
  nopl   0x0(%rax)
L81:
  movslq (%r14,%rax,4),%rdx
  mov    %eax,0x0(%r13,%rdx,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L81
  lea    -0x1(%rsi),%eax
  xor    %ebx,%ebx
  xor    %ecx,%ecx
  mov    %eax,-0x44(%rbp)
  nopl   0x0(%rax)
L119:
  movslq 0x0(%r13,%rbx,4),%rax
  mov    %ebx,%r10d
  cmp    -0x44(%rbp),%eax
  je     L22
  add    $0x1,%rax
  lea    (%rcx,%rbx,1),%r8d
  mov    (%r14,%rax,4),%r11d
  lea    0x0(,%rax,4),%r15
  cmp    %r8d,%esi
  jle    L17
  lea    (%r11,%rcx,1),%r9d
  cmp    %r9d,%esi
  jle    L17
  mov    -0x58(%rbp),%rax
  movslq %r8d,%r8
  movslq %r9d,%r9
  add    %r8,%rax
  jmp    L94
  xchg   %ax,%ax
L114:
  lea    0x1(%rcx),%edx
  lea    (%rdx,%r10,1),%edi
  cmp    %edi,%esi
  jle    L7
  lea    (%r11,%rdx,1),%edi
  add    $0x1,%rax
  cmp    %edi,%esi
  jle    L7
  mov    %edx,%ecx
L94:
  mov    %rax,%rdx
  sub    %r8,%rdx
  movzbl (%rdx,%r9,1),%edi
  cmp    %dil,(%rax)
  je     L114
L17:
  mov    -0x50(%rbp),%rax
  mov    %ecx,-0x4(%rax,%r15,1)
  test   %ecx,%ecx
  jne    L102
L22:
  xor    %ecx,%ecx
L88:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L119
L165:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    -0x50(%rbp),%rax
  mov    %edx,-0x4(%rax,%r15,1)
  jmp    L88
L61:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L120
L27:
  call   <__stack_chk_fail@plt>
L102:
  sub    $0x1,%ecx
  jmp    L88
```

assistant: ```c
void kasai_lcp(char *text, int *lcp, int *suffArr, int n) {
  int i;
  int invSuff[n];
  for (i = 0; i < n; i++) {
    invSuff[suffArr[i]] = i;
  }
  int k = 0;
  for (i = 0; i < n; i++) {
    if (invSuff[i] == n - 1) {
      k = 0;
      continue;
    }
    int j = suffArr[invSuff[i] + 1];
    while (i + k < n && j + k < n && text[i + k] == text[j + k]) {
      k++;
    }
    lcp[invSuff[i]] = k;
    if (k > 0) {
      k--;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kasai_lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  movslq %ecx,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,-0x50(%rbp)
  mov    %r12,%rsi
  mov    %rdi,-0x58(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r12,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L121
L93:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L93
L121:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L68
L111:
  mov    %rsp,%r13
  xor    %eax,%eax
  test   %esi,%esi
  jle    L79
  nopl   0x0(%rax)
L92:
  movslq (%r14,%rax,4),%rdx
  mov    %eax,0x0(%r13,%rdx,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L92
  lea    -0x1(%rsi),%eax
  xor    %ebx,%ebx
  xor    %ecx,%ecx
  mov    %eax,-0x44(%rbp)
  nopl   0x0(%rax)
L147:
  movslq 0x0(%r13,%rbx,4),%rax
  mov    %ebx,%r10d
  cmp    -0x44(%rbp),%eax
  je     L170
  add    $0x1,%rax
  lea    (%rcx,%rbx,1),%r8d
  mov    (%r14,%rax,4),%r11d
  lea    0x0(,%rax,4),%r15
  cmp    %r8d,%esi
  jle    L154
  lea    (%r11,%rcx,1),%r9d
  cmp    %r9d,%esi
  jle    L154
  mov    -0x58(%rbp),%rax
  movslq %r8d,%r8
  movslq %r9d,%r9
  add    %r8,%rax
  jmp    L146
  xchg   %ax,%ax
L82:
  lea    0x1(%rcx),%edx
  lea    (%r10,%rdx,1),%edi
  cmp    %edi,%esi
  jle    L30
  lea    (%r11,%rdx,1),%edi
  add    $0x1,%rax
  cmp    %edi,%esi
  jle    L30
  mov    %edx,%ecx
L146:
  mov    %rax,%rdx
  sub    %r8,%rdx
  movzbl (%rdx,%r9,1),%edi
  cmp    %dil,(%rax)
  je     L82
L154:
  mov    -0x50(%rbp),%rax
  mov    %ecx,-0x4(%rax,%r15,1)
  test   %ecx,%ecx
  jne    L69
L170:
  xor    %ecx,%ecx
L144:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L147
L79:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  mov    -0x50(%rbp),%rax
  mov    %edx,-0x4(%rax,%r15,1)
  jmp    L144
L68:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L111
L70:
  call   <__stack_chk_fail@plt>
L69:
  sub    $0x1,%ecx
  jmp    L144
```

assistant: ```c
void kasai_lcp(char *text, int *lcp, int *suffArr, int n) {
  int i;
  int invSuff[n];
  for (i = 0; i < n; i++) {
    invSuff[suffArr[i]] = i;
  }
  int k = 0;
  for (i = 0; i < n; i++) {
    if (invSuff[i] == n - 1) {
      k = 0;
      continue;
    }
    int j = suffArr[invSuff[i] + 1];
    while (i + k < n && j + k < n && text[i + k] == text[j + k]) {
      k++;
    }
    lcp[invSuff[i]] = k;
    if (k > 0) {
      k--;
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D14: Hello world.

tool: D19: %d


assistant: ```c
int main() {
  int x;
  x = puts("Hello world.");
  printf("%d\n", x);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
data_type: string
name: retrieve_data
arguments: label: D12
data_type: string

tool: D10: Hello world.

tool: D12: %d


assistant: ```c
int main() {
  int x;
  x = puts("Hello world.");
  printf("%d\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D16
datatype: string
name: parse_data
arguments: label: D14
datatype: string

tool: D16: Hello world.

tool: D14: %d


assistant: ```c
int main() {
  int x;
  x = puts("Hello world.");
  printf("%d\n", x);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D15
type_infered: string

tool: D13: Hello world.

tool: D15: %d


assistant: ```c
int main() {
  int x;
  x = puts("Hello world.");
  printf("%d\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checkDramData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L0:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    -0x1c(%rbp),%eax
  movzwl %ax,%eax
  test   %eax,%eax
  je     L34
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L34:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    -0x1c(%rbp),%eax
  mov    $0x0,%ax
  test   %eax,%eax
  je     L10
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L10:
  addl   $0x1,-0x4(%rbp)
L30:
  cmpl   $0xffff,-0x4(%rbp)
  jbe    L0
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string

tool: D0: 0x%8.8X 0


tool: D11: 0x%8.8X 1


assistant: ```c
int checkDramData(volatile unsigned int *pBaseAddress, const unsigned int pExpectedValue) {
  unsigned int index;
  for (index = 0; index < (0x10000 * 1); index += 1) {
    if ((pBaseAddress[index] & 0xFFFF) != (pExpectedValue & 0xFFFF))
      printf("0x%8.8X 0\n\r", (unsigned int)&pBaseAddress[index]);
    if ((pBaseAddress[index] & 0xFFFF0000) != (pExpectedValue & 0xFFFF0000))
      printf("0x%8.8X 1\n\r", (unsigned int)&pBaseAddress[index]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkDramData>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %rdi,%rbx
  lea    0x40000(%rdi),%r12
  lea    D12(%rip),%r14
  lea    D19(%rip),%r13
  jmp    L1
L40:
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
L37:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L2
L1:
  mov    %rbx,%r15
  mov    (%rbx),%eax
  xor    %ebp,%eax
  test   %ax,%ax
  jne    L40
L8:
  mov    (%r15),%eax
  xor    %ebp,%eax
  test   $0xffff0000,%eax
  je     L37
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L2:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D12: 0x%8.8X 0


tool: D19: 0x%8.8X 1


assistant: ```c
int checkDramData(volatile unsigned int *pBaseAddress, const unsigned int pExpectedValue) {
  unsigned int index;
  for (index = 0; index < (0x10000 * 1); index += 1) {
    if ((pBaseAddress[index] & 0xFFFF) != (pExpectedValue & 0xFFFF))
      printf("0x%8.8X 0\n\r", (unsigned int)&pBaseAddress[index]);
    if ((pBaseAddress[index] & 0xFFFF0000) != (pExpectedValue & 0xFFFF0000))
      printf("0x%8.8X 1\n\r", (unsigned int)&pBaseAddress[index]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<checkDramData>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  lea    0x40000(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L9
  nopl   0x0(%rax)
L18:
  mov    (%rbx),%eax
  xor    %r14d,%eax
  test   $0xffff0000,%eax
  jne    L44
L7:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L49
L9:
  mov    (%rbx),%eax
  xor    %r14d,%eax
  test   %ax,%ax
  je     L18
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%eax
  xor    %r14d,%eax
  test   $0xffff0000,%eax
  je     L7
L44:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L9
L49:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D12
type_infered: string

tool: D14: 0x%8.8X 0


tool: D12: 0x%8.8X 1


assistant: ```c
int checkDramData(volatile unsigned int *pBaseAddress, const unsigned int pExpectedValue) {
  unsigned int index;
  for (index = 0; index < (0x10000 * 1); index += 1) {
    if ((pBaseAddress[index] & 0xFFFF) != (pExpectedValue & 0xFFFF))
      printf("0x%8.8X 0\n\r", (unsigned int)&pBaseAddress[index]);
    if ((pBaseAddress[index] & 0xFFFF0000) != (pExpectedValue & 0xFFFF0000))
      printf("0x%8.8X 1\n\r", (unsigned int)&pBaseAddress[index]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<checkDramData>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  lea    0x40000(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L24
  nopl   0x0(%rax)
L50:
  mov    (%rbx),%eax
  xor    %r14d,%eax
  test   $0xffff0000,%eax
  jne    L38
L23:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L47
L24:
  mov    (%rbx),%eax
  xor    %r14d,%eax
  test   %ax,%ax
  je     L50
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%eax
  xor    %r14d,%eax
  test   $0xffff0000,%eax
  je     L23
L38:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L24
L47:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D0: 0x%8.8X 0


tool: D6: 0x%8.8X 1


assistant: ```c
int checkDramData(volatile unsigned int *pBaseAddress, const unsigned int pExpectedValue) {
  unsigned int index;
  for (index = 0; index < (0x10000 * 1); index += 1) {
    if ((pBaseAddress[index] & 0xFFFF) != (pExpectedValue & 0xFFFF))
      printf("0x%8.8X 0\n\r", (unsigned int)&pBaseAddress[index]);
    if ((pBaseAddress[index] & 0xFFFF0000) != (pExpectedValue & 0xFFFF0000))
      printf("0x%8.8X 1\n\r", (unsigned int)&pBaseAddress[index]);
  }
  return 0;
}
```