ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<util_test>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x4,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x40000000,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0x1e,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x80000000,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0x1f,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xc,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x1,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x2,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x4,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x3,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x8,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x40000000,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x1f,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  mov    %rax,%r8
  mov    $0x80000000,%eax
  cmp    %rax,%r8
  sete   %dil
  add    $0x8,%rsp
  jmp    10b0 <assert@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D0: Testing log_2


tool: D5: Testing pow_2


assistant: ```c
void util_test() {
  printf("Testing log_2\n");
  assert(log_2(1UL) == 0);
  assert(log_2(2UL) == 1);
  assert(log_2(4UL) == 2);
  assert(log_2(1073741824UL) == 30);
  assert(log_2(2147483648UL) == 31);
  assert(log_2(3) == -1);
  assert(log_2(12) == -1);
  printf("Testing pow_2\n");
  assert(pow_2(0) == 1UL);
  assert(pow_2(1) == 2UL);
  assert(pow_2(2) == 4UL);
  assert(pow_2(3) == 8UL);
  assert(pow_2(30) == 1073741824UL);
  assert(pow_2(31) == 2147483648UL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<util_test>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x4,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x40000000,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0x1e,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x80000000,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0x1f,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xc,%edi
  call   <log_2@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x1,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x2,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x4,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x3,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x8,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  cmp    $0x40000000,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x1f,%edi
  call   <pow_2@plt>
  xor    %edi,%edi
  mov    %rax,%r8
  mov    $0x80000000,%eax
  cmp    %rax,%r8
  sete   %dil
  add    $0x8,%rsp
  jmp    10b0 <assert@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string

tool: D4: Testing log_2


tool: D18: Testing pow_2


assistant: ```c
void util_test() {
  printf("Testing log_2\n");
  assert(log_2(1UL) == 0);
  assert(log_2(2UL) == 1);
  assert(log_2(4UL) == 2);
  assert(log_2(1073741824UL) == 30);
  assert(log_2(2147483648UL) == 31);
  assert(log_2(3) == -1);
  assert(log_2(12) == -1);
  printf("Testing pow_2\n");
  assert(pow_2(0) == 1UL);
  assert(pow_2(1) == 2UL);
  assert(pow_2(2) == 4UL);
  assert(pow_2(3) == 8UL);
  assert(pow_2(30) == 1073741824UL);
  assert(pow_2(31) == 2147483648UL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L107:
  cmp    %rcx,%rsp
  je     L27
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L107
L27:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L55
  orq    $0x0,-0x8(%rsp,%rax,1)
L55:
  mov    %rsp,%r12
  test   %edx,%edx
  jle    L53
  mov    $0x0,%ebx
  lea    D1(%rip),%r13
L37:
  movslq %ebx,%r14
  lea    (%r12,%r14,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%r12,%r14,4),%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebx
  cmp    -0x2c(%rbp),%ebx
  jl     L37
L53:
  mov    -0x2c(%rbp),%ecx
  cmp    $0x1,%ecx
  jle    L101
  mov    $0x0,%ebx
  lea    D35(%rip),%r13
L49:
  sub    $0x1,%ecx
  movslq %ecx,%rcx
  mov    (%r12,%rbx,4),%esi
  sub    (%r12,%rcx,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  mov    %edx,%eax
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jg     L49
L72:
  test   $0x1,%cl
  jne    L96
L79:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L101:
  mov    $0x2,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  jmp    L72
L96:
  cltq
  mov    (%r12,%rax,4),%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L79
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D35
data_type: string

tool: D1: %d

tool: D35: 
%d

assistant: ```c
int main() {
  int n, i, k;
  scanf("%d", &n);
  i = 0;
  int masiv[n];
  while (i < n) {
    scanf("%d", &masiv[i]);
    if (masiv[i] % 2 != 0)
      i++;
  }
  for (i = 0; i < n / 2; i++) {
    k = masiv[i] - masiv[n - 1];
    printf("\n%d", k);
  }
  if (n % 2 != 0) {
    printf("\n%d", masiv[n / 2]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  lea    D29(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L14
L78:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L78
L14:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L66
L75:
  mov    %rsp,%r13
  test   %ecx,%ecx
  jle    L100
  xor    %ebx,%ebx
L114:
  movslq %ebx,%r14
  mov    %r12,%rdi
  lea    0x0(%r13,%r14,4),%rsi
  call   <scanf@plt>
  mov    0x0(%r13,%r14,4),%eax
  mov    -0x2c(%rbp),%ecx
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebx
  cmp    %ecx,%ebx
  jl     L114
  cmp    $0x1,%ecx
  jle    L100
  xor    %r12d,%r12d
  lea    D19(%rip),%rbx
  nopl   0x0(%rax)
L94:
  sub    $0x1,%ecx
  mov    0x0(%r13,%r12,4),%esi
  mov    %rbx,%rdi
  add    $0x1,%r12
  movslq %ecx,%rcx
  sub    0x0(%r13,%rcx,4),%esi
  call   <printf@plt>
  mov    -0x2c(%rbp),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jg     L94
L54:
  and    $0x1,%ecx
  jne    L29
L46:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L29:
  cltq
  lea    D19(%rip),%rdi
  mov    0x0(%r13,%rax,4),%esi
  call   <printf@plt>
  jmp    L46
L66:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L75
L100:
  mov    %ecx,%eax
  mov    $0x2,%esi
  cltd
  idiv   %esi
  jmp    L54
L110:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
type_infered: string
name: unpack_data
arguments: tag: D19
type_infered: string

tool: D29: %d

tool: D19: 
%d

assistant: ```c
int main() {
  int n, i, k;
  scanf("%d", &n);
  i = 0;
  int masiv[n];
  while (i < n) {
    scanf("%d", &masiv[i]);
    if (masiv[i] % 2 != 0)
      i++;
  }
  for (i = 0; i < n / 2; i++) {
    k = masiv[i] - masiv[n - 1];
    printf("\n%d", k);
  }
  if (n % 2 != 0) {
    printf("\n%d", masiv[n / 2]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  lea    D5(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L41
L47:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L47
L41:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L27
L24:
  mov    %rsp,%r13
  test   %ecx,%ecx
  jle    L82
  xor    %ebx,%ebx
L96:
  movslq %ebx,%r14
  mov    %r12,%rdi
  lea    0x0(%r13,%r14,4),%rsi
  call   <scanf@plt>
  mov    0x0(%r13,%r14,4),%eax
  mov    -0x2c(%rbp),%ecx
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebx
  cmp    %ecx,%ebx
  jl     L96
  cmp    $0x1,%ecx
  jle    L82
  xor    %r12d,%r12d
  lea    D8(%rip),%rbx
  nopl   0x0(%rax)
L91:
  sub    $0x1,%ecx
  mov    0x0(%r13,%r12,4),%esi
  mov    %rbx,%rdi
  add    $0x1,%r12
  movslq %ecx,%rcx
  sub    0x0(%r13,%rcx,4),%esi
  call   <printf@plt>
  mov    -0x2c(%rbp),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jg     L91
L77:
  and    $0x1,%ecx
  jne    L88
L17:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L88:
  cltq
  lea    D8(%rip),%rdi
  mov    0x0(%r13,%rax,4),%esi
  call   <printf@plt>
  jmp    L17
L27:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L24
L82:
  mov    %ecx,%eax
  mov    $0x2,%esi
  cltd
  idiv   %esi
  jmp    L77
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string
name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D5: %d

tool: D8: 
%d

assistant: ```c
int main() {
  int n, i, k;
  scanf("%d", &n);
  i = 0;
  int masiv[n];
  while (i < n) {
    scanf("%d", &masiv[i]);
    if (masiv[i] % 2 != 0)
      i++;
  }
  for (i = 0; i < n / 2; i++) {
    k = masiv[i] - masiv[n - 1];
    printf("\n%d", k);
  }
  if (n % 2 != 0) {
    printf("\n%d", masiv[n / 2]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<minifySelect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <glTexParameterf@plt>
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  nop
  leave
  ret
```

assistant: ```c
void minifySelect(int value) {
  glTexParameterf(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, value);
  glutPostRedisplay();
}
```
user: Translate the below assembly code into C programming language:

```asm
<minifySelect>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <glTexParameterf@plt>
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void minifySelect(int value) {
  glTexParameterf(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, value);
  glutPostRedisplay();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<minifySelect>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    %edi,%edx
  mov    (%rax),%esi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <glTexParameterf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <glutPostRedisplay@plt>
```

assistant: ```c
void minifySelect(int value) {
  glTexParameterf(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, value);
  glutPostRedisplay();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<minifySelect>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    %edi,%edx
  mov    (%rax),%esi
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  call   <glTexParameterf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <glutPostRedisplay@plt>
```

assistant: ```c
void minifySelect(int value) {
  glTexParameterf(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, value);
  glutPostRedisplay();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jg     L78
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L53
L78:
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L31:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  jns    L66
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L53
L66:
  addl   $0x1,-0x14(%rbp)
L13:
  cmpl   $0x3f,-0x14(%rbp)
  jle    L31
  mov    -0x8(%rbp),%rax
  mov    $0x1a4,%esi
  mov    %rax,%rdi
  call   <creat@plt>
  test   %rax,%rax
  jns    L27
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L53
L27:
  mov    D35(%rip),%rax
  mov    (%rax),%eax
L53:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *long_dir, *fname;
  if (3 > argc)
    return EXIT_FAILURE;
  else {
    long_dir = argv[1];
    fname = argv[2];
  }
  for (int i = 0; i < 64; i++) {
    if (0 > chdir(long_dir))
      return EXIT_FAILURE;
  }
  if (0 > creat(fname, 0644))
    return EXIT_FAILURE;
  else
    return EXIT_SUCCESS;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  jle    L26
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%r12
  mov    $0x40,%ebx
L15:
  mov    %rbp,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  js     L3
  sub    $0x1,%ebx
  jne    L15
  mov    $0x1a4,%esi
  mov    %r12,%rdi
  call   <creat@plt>
  test   %rax,%rax
  js     L21
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L11
L26:
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  ret
L3:
  mov    D28(%rip),%rax
  mov    (%rax),%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  jmp    L11
```

assistant: ```c
int main(int argc, char **argv) {
  char *long_dir, *fname;
  if (3 > argc)
    return EXIT_FAILURE;
  else {
    long_dir = argv[1];
    fname = argv[2];
  }
  for (int i = 0; i < 64; i++) {
    if (0 > chdir(long_dir))
      return EXIT_FAILURE;
  }
  if (0 > creat(fname, 0644))
    return EXIT_FAILURE;
  else
    return EXIT_SUCCESS;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  jle    L39
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x40,%ebx
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%r12
  jmp    L13
  nopl   0x0(%rax)
L23:
  sub    $0x1,%ebx
  je     L59
L13:
  mov    %rbp,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  jns    L23
L14:
  mov    D13(%rip),%rax
  mov    (%rax),%eax
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  ret
L59:
  mov    $0x1a4,%esi
  mov    %r12,%rdi
  call   <creat@plt>
  test   %rax,%rax
  js     L14
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L17
```

assistant: ```c
int main(int argc, char **argv) {
  char *long_dir, *fname;
  if (3 > argc)
    return EXIT_FAILURE;
  else {
    long_dir = argv[1];
    fname = argv[2];
  }
  for (int i = 0; i < 64; i++) {
    if (0 > chdir(long_dir))
      return EXIT_FAILURE;
  }
  if (0 > creat(fname, 0644))
    return EXIT_FAILURE;
  else
    return EXIT_SUCCESS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  jle    L12
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x40,%ebx
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%r12
  jmp    L45
  nopl   0x0(%rax)
L38:
  sub    $0x1,%ebx
  je     L26
L45:
  mov    %rbp,%rdi
  call   <chdir@plt>
  test   %rax,%rax
  jns    L38
L19:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  ret
L26:
  mov    $0x1a4,%esi
  mov    %r12,%rdi
  call   <creat@plt>
  test   %rax,%rax
  js     L19
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  jmp    L20
```

assistant: ```c
int main(int argc, char **argv) {
  char *long_dir, *fname;
  if (3 > argc)
    return EXIT_FAILURE;
  else {
    long_dir = argv[1];
    fname = argv[2];
  }
  for (int i = 0; i < 64; i++) {
    if (0 > chdir(long_dir))
      return EXIT_FAILURE;
  }
  if (0 > creat(fname, 0644))
    return EXIT_FAILURE;
  else
    return EXIT_SUCCESS;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<igf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  movsd  %xmm0,-0x58(%rbp)
  movsd  %xmm1,-0x60(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x60(%rbp),%xmm0
  jbe    L37
  pxor   %xmm0,%xmm0
  jmp    L25
L37:
  movsd  D26(%rip),%xmm0
  divsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x68(%rbp)
  fldl   -0x68(%rbp)
  fstpt  -0x10(%rbp)
  movsd  -0x58(%rbp),%xmm0
  mov    -0x60(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <powl@plt>
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x10(%rbp)
  movsd  -0x60(%rbp),%xmm0
  movq   D25(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <expl@plt>
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x10(%rbp)
  fld1
  fstpt  -0x40(%rbp)
  fld1
  fstpt  -0x30(%rbp)
  fld1
  fstpt  -0x20(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L18
L22:
  fldl   -0x60(%rbp)
  fldt   -0x30(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x30(%rbp)
  movsd  -0x58(%rbp),%xmm1
  movsd  D26(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  fldl   -0x58(%rbp)
  fldt   -0x20(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x20(%rbp)
  fldt   -0x30(%rbp)
  fldt   -0x20(%rbp)
  fdivrp %st,%st(1)
  fldt   -0x40(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x40(%rbp)
  addl   $0x1,-0x44(%rbp)
L18:
  cmpl   $0xc7,-0x44(%rbp)
  jle    L22
  fldt   -0x40(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  fstpl  -0x68(%rbp)
  movsd  -0x68(%rbp),%xmm0
L25:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D26
type_infered: f64
name: disassemble_data
arguments: label: D25
type_infered: f32[2]

tool: D26: 1

tool: {"D25": [0.0,-0.0]}

assistant: ```c
double igf(double S, double Z) {
  if (Z < 0.0) {
    return 0.0;
  }
  long double Sc = (1.0 / S);
  Sc *= powl(Z, S);
  Sc *= expl(-Z);
  long double Sum = 1.0;
  long double Nom = 1.0;
  long double Denom = 1.0;
  for (int I = 0; I < 200; I++) {
    Nom *= Z;
    S++;
    Denom *= S;
    Sum += (Nom / Denom);
  }
  return Sum * Sc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<igf>:
  endbr64
  sub    $0x28,%rsp
  movapd %xmm0,%xmm3
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L4
  movsd  D15(%rip),%xmm0
  movapd %xmm3,%xmm1
  divsd  %xmm3,%xmm0
  movsd  %xmm0,0x10(%rsp)
  fldl   0x10(%rsp)
  fstpt  0x10(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <powl@plt>
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fstpt  0x10(%rsp)
  movsd  0x8(%rsp),%xmm0
  xorpd  D26(%rip),%xmm0
  call   <expl@plt>
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  mov    $0xc8,%eax
  fld1
  fld    %st(0)
  fld    %st(1)
  fxch   %st(1)
  movsd  D15(%rip),%xmm0
  jmp    L24
L23:
  fxch   %st(2)
L24:
  fmull  0x8(%rsp)
  fxch   %st(2)
  movsd  (%rsp),%xmm2
  addsd  %xmm0,%xmm2
  movsd  %xmm2,(%rsp)
  fmull  (%rsp)
  fld    %st(2)
  fdiv   %st(1),%st
  faddp  %st,%st(2)
  sub    $0x1,%eax
  jne    L23
  fstp   %st(0)
  fstp   %st(1)
  fmulp  %st,%st(1)
  fstpl  (%rsp)
  movsd  (%rsp),%xmm0
L20:
  add    $0x28,%rsp
  ret
L4:
  pxor   %xmm0,%xmm0
  jmp    L20
```

tool_calls: name: retrieve_data
arguments: label: D15
data_type: f64
name: retrieve_data
arguments: label: D26
data_type: f32[4]

tool: D15: 1

tool: {"D26": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double igf(double S, double Z) {
  if (Z < 0.0) {
    return 0.0;
  }
  long double Sc = (1.0 / S);
  Sc *= powl(Z, S);
  Sc *= expl(-Z);
  long double Sum = 1.0;
  long double Nom = 1.0;
  long double Denom = 1.0;
  for (int I = 0; I < 200; I++) {
    Nom *= Z;
    S++;
    Denom *= S;
    Sum += (Nom / Denom);
  }
  return Sum * Sc;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<igf>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L1
  sub    $0x28,%rsp
  movsd  D1(%rip),%xmm4
  movapd %xmm1,%xmm3
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm0
  movsd  %xmm2,0x18(%rsp)
  movapd %xmm4,%xmm5
  divsd  %xmm2,%xmm5
  movsd  %xmm5,0x10(%rsp)
  fldl   0x10(%rsp)
  movsd  %xmm3,0x10(%rsp)
  fstpt  (%rsp)
  call   <powl@plt>
  fldt   (%rsp)
  movsd  0x10(%rsp),%xmm3
  movapd %xmm3,%xmm0
  xorpd  D5(%rip),%xmm0
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   <expl@plt>
  fldt   (%rsp)
  movsd  0x18(%rsp),%xmm2
  mov    $0xc8,%eax
  mov    D1(%rip),%rdx
  movq   %rdx,%xmm4
  fmulp  %st,%st(1)
  fldl   0x10(%rsp)
  fld1
  fld    %st(0)
  fld    %st(1)
  fxch   %st(1)
  nopl   0x0(%rax,%rax,1)
L12:
  addsd  %xmm4,%xmm2
  fmul   %st(3),%st
  movsd  %xmm2,0x10(%rsp)
  fldl   0x10(%rsp)
  fmulp  %st,%st(3)
  fld    %st(0)
  fdiv   %st(3),%st
  faddp  %st,%st(2)
  sub    $0x1,%eax
  jne    L12
  fstp   %st(0)
  fstp   %st(2)
  fstp   %st(0)
  fmulp  %st,%st(1)
  fstpl  0x10(%rsp)
  movsd  0x10(%rsp),%xmm0
  add    $0x28,%rsp
  ret
L1:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: f64
name: retrieve_data
arguments: label: D5
datatype: f32[4]

tool: D1: 1

tool: {"D5": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double igf(double S, double Z) {
  if (Z < 0.0) {
    return 0.0;
  }
  long double Sc = (1.0 / S);
  Sc *= powl(Z, S);
  Sc *= expl(-Z);
  long double Sum = 1.0;
  long double Nom = 1.0;
  long double Denom = 1.0;
  for (int I = 0; I < 200; I++) {
    Nom *= Z;
    S++;
    Denom *= S;
    Sum += (Nom / Denom);
  }
  return Sum * Sc;
}
```