ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmpstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L0
  mov    $0xffffffff,%eax
  jmp    L40
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L58
  mov    $0x1,%eax
  jmp    L40
L58:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cmpstr>
  jmp    L40
L10:
  mov    $0x0,%eax
L40:
  leave
  ret
```

assistant: ```c
int cmpstr(char *s1, char *s2) {
  if (*s1 > *s2)
    return (-1);
  if (*s1 < *s2)
    return (+1);
  if (*s1)
    return (cmpstr(++s1, ++s2));
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmpstr>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jg     L22
  mov    $0x1,%eax
  jl     L0
  mov    $0x0,%eax
  test   %dl,%dl
  jne    L8
L0:
  ret
L8:
  sub    $0x8,%rsp
  add    $0x1,%rsi
  add    $0x1,%rdi
  call   <cmpstr>
  add    $0x8,%rsp
  ret
L22:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cmpstr(char *s1, char *s2) {
  if (*s1 > *s2)
    return (-1);
  if (*s1 < *s2)
    return (+1);
  if (*s1)
    return (cmpstr(++s1, ++s2));
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmpstr>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  cmp    %al,%cl
  jl     L38
  mov    $0x1,%edx
  jmp    L10
  nopl   (%rax)
L44:
  test   %al,%al
  je     L40
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  jg     L38
L10:
  cmp    %al,%cl
  jle    L44
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmpstr(char *s1, char *s2) {
  if (*s1 > *s2)
    return (-1);
  if (*s1 < *s2)
    return (+1);
  if (*s1)
    return (cmpstr(++s1, ++s2));
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmpstr>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  cmp    %al,%cl
  jl     L12
  mov    $0x1,%edx
  jmp    L13
  nopl   (%rax)
L21:
  test   %al,%al
  je     L44
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  jg     L12
L13:
  cmp    %al,%cl
  jle    L21
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmpstr(char *s1, char *s2) {
  if (*s1 > *s2)
    return (-1);
  if (*s1 < *s2)
    return (+1);
  if (*s1)
    return (cmpstr(++s1, ++s2));
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<selectf_algo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L35
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L33
L35:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L50
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L33
L50:
  mov    -0x24(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L62
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <selectf_algo>
  jmp    L33
L62:
  mov    -0x24(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L78
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <selectf_algo>
  jmp    L33
L78:
  mov    $0xffffffff,%eax
L33:
  leave
  ret
```

assistant: ```c
int selectf_algo(int *array, int l, int h, int i) {
  int m = 0;
  if (l == h) {
    return array[l];
  }
  m = partition(array, l, h);
  if (i == m) {
    return array[m];
  } else if (i < m) {
    return selectf_algo(array, l, m - 1, i);
  } else if (i > m) {
    return selectf_algo(array, m + 1, h, i);
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<selectf_algo>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  cmp    %edx,%esi
  je     L78
  mov    %edx,%r12d
  mov    %ecx,%ebp
  call   <partition@plt>
  cmp    %ebp,%eax
  je     L15
  jg     L59
  jge    L47
  lea    0x1(%rax),%esi
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <selectf_algo>
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L78:
  movslq %esi,%rbx
  mov    (%rdi,%rbx,4),%eax
  jmp    L29
L15:
  movslq %ebp,%rbp
  mov    0x0(%r13,%rbp,4),%eax
  jmp    L29
L59:
  lea    -0x1(%rax),%edx
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <selectf_algo>
  jmp    L29
L47:
  mov    $0xffffffff,%eax
  jmp    L29
```

assistant: ```c
int selectf_algo(int *array, int l, int h, int i) {
  int m = 0;
  if (l == h) {
    return array[l];
  }
  m = partition(array, l, h);
  if (i == m) {
    return array[m];
  } else if (i < m) {
    return selectf_algo(array, l, m - 1, i);
  } else if (i > m) {
    return selectf_algo(array, m + 1, h, i);
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<selectf_algo>:
  endbr64
  push   %r13
  movslq %ecx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jne    L7
  jmp    L15
  nop
L39:
  lea    -0x1(%rax),%r12d
  cmp    %ebx,%r12d
  je     L15
L7:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <partition@plt>
  cmp    %r13d,%eax
  je     L49
  jg     L39
  jge    L42
  lea    0x1(%rax),%ebx
  cmp    %ebx,%r12d
  jne    L7
L15:
  movslq %ebx,%rbx
  mov    0x0(%rbp,%rbx,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L49:
  mov    0x0(%rbp,%r13,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int selectf_algo(int *array, int l, int h, int i) {
  int m = 0;
  if (l == h) {
    return array[l];
  }
  m = partition(array, l, h);
  if (i == m) {
    return array[m];
  } else if (i < m) {
    return selectf_algo(array, l, m - 1, i);
  } else if (i > m) {
    return selectf_algo(array, m + 1, h, i);
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<selectf_algo>:
  endbr64
  push   %r13
  movslq %ecx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jne    L16
  jmp    L27
  nop
L45:
  lea    -0x1(%rax),%r12d
  cmp    %ebx,%r12d
  je     L27
L16:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <partition@plt>
  cmp    %r13d,%eax
  je     L47
  jg     L45
  jge    L40
  lea    0x1(%rax),%ebx
  cmp    %ebx,%r12d
  jne    L16
L27:
  movslq %ebx,%rbx
  mov    0x0(%rbp,%rbx,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L47:
  mov    0x0(%rbp,%r13,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int selectf_algo(int *array, int l, int h, int i) {
  int m = 0;
  if (l == h) {
    return array[l];
  }
  m = partition(array, l, h);
  if (i == m) {
    return array[m];
  } else if (i < m) {
    return selectf_algo(array, l, m - 1, i);
  } else if (i > m) {
    return selectf_algo(array, m + 1, h, i);
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L3:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L3
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int stoi(char string[], int n) {
  int num = 0;
  for (int i = 0; i < n; i++) {
    num += (string[i] - '0') * ((int)pow(10, i));
  }
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stoi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L12
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L11:
  movsbl (%r14,%rbp,1),%ebx
  sub    $0x30,%ebx
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   %eax,%ebx
  add    %ebx,%r12d
  add    $0x1,%rbp
  cmp    %r13,%rbp
  jne    L11
L2:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    $0x0,%r12d
  jmp    L2
```

assistant: ```c
int stoi(char string[], int n) {
  int num = 0;
  for (int i = 0; i < n; i++) {
    num += (string[i] - '0') * ((int)pow(10, i));
  }
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stoi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L2
  mov    %rdi,%r14
  movslq %esi,%r13
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl (%r14,%rbp,1),%ebx
  mov    %ebp,%esi
  mov    $0xa,%edi
  add    $0x1,%rbp
  call   <pow@plt>
  sub    $0x30,%ebx
  imul   %eax,%ebx
  add    %ebx,%r12d
  cmp    %rbp,%r13
  jne    L9
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L2:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int stoi(char string[], int n) {
  int num = 0;
  for (int i = 0; i < n; i++) {
    num += (string[i] - '0') * ((int)pow(10, i));
  }
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stoi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L17
  mov    %rdi,%r14
  movslq %esi,%r13
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L8:
  movsbl (%r14,%rbp,1),%ebx
  mov    %ebp,%esi
  mov    $0xa,%edi
  add    $0x1,%rbp
  call   <pow@plt>
  sub    $0x30,%ebx
  imul   %eax,%ebx
  add    %ebx,%r12d
  cmp    %rbp,%r13
  jne    L8
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L17:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int stoi(char string[], int n) {
  int num = 0;
  for (int i = 0; i < n; i++) {
    num += (string[i] - '0') * ((int)pow(10, i));
  }
  return num;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<make_bf_salt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x16,-0x18(%rbp)
  jle    L15
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L15:
  mov    -0x14(%rbp),%edx
  lea    -0xb(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0xb(%rbp),%rax
  mov    %rax,%rdx
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <generate_random_salt@plt>
  mov    -0x18(%rbp),%eax
  add    $0x7,%eax
  cltq
  lea    D17(%rip),%rdx
  movb   $0x24,(%rax,%rdx,1)
  mov    -0x18(%rbp),%eax
  add    $0x8,%eax
  cltq
  lea    D17(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D17(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D62
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D20
type_guessed: string

tool: D62: BlowFish salt length too long


tool: D3: %02d

tool: D20: $2a$%s$

assistant: ```c
char *make_bf_salt(int rounds, int length) {
  static char salt[31];
  char tbuf[3];
  if (length > 22) {
    printf("BlowFish salt length too long\n");
    exit(0);
  }
  sprintf(tbuf, "%02d", rounds);
  sprintf(salt, "$2a$%s$", tbuf);
  generate_random_salt(&salt[7], length);
  salt[length + 7] = '$';
  salt[length + 8] = '\0';
  return salt;
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_bf_salt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x16,%esi
  jg     L26
L27:
  lea    0x5(%rsp),%r12
  mov    %ebp,%edx
  lea    D36(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r12,%rdx
  lea    D23(%rip),%rsi
  lea    D30(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %ebx,%esi
  lea    0x7(%rbp),%rdi
  call   <generate_random_salt@plt>
  lea    0x7(%rbx),%eax
  cltq
  movb   $0x24,0x0(%rbp,%rax,1)
  add    $0x8,%ebx
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L27
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D36
type_infered: string
name: unpack_data
arguments: tag: D23
type_infered: string
name: unpack_data
arguments: tag: D37
type_infered: string

tool: D36: %02d

tool: D23: $2a$%s$

tool: D37: BlowFish salt length too long


assistant: ```c
char *make_bf_salt(int rounds, int length) {
  static char salt[31];
  char tbuf[3];
  if (length > 22) {
    printf("BlowFish salt length too long\n");
    exit(0);
  }
  sprintf(tbuf, "%02d", rounds);
  sprintf(salt, "$2a$%s$", tbuf);
  generate_random_salt(&salt[7], length);
  salt[length + 7] = '$';
  salt[length + 8] = '\0';
  return salt;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<make_bf_salt>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x16,%esi
  jg     L2
L1:
  lea    0x5(%rsp),%r13
  mov    %r12d,%edx
  lea    D14(%rip),%rsi
  xor    %eax,%eax
  lea    D5(%rip),%r12
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    D16(%rip),%rsi
  call   <sprintf@plt>
  mov    %ebx,%esi
  lea    0x7(%r12),%rdi
  call   <generate_random_salt@plt>
  lea    0x7(%rbx),%eax
  add    $0x8,%ebx
  cltq
  movslq %ebx,%rbx
  movb   $0x24,(%r12,%rax,1)
  movb   $0x0,(%r12,%rbx,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L1
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D38
datatype: string

tool: D14: %02d

tool: D16: $2a$%s$

tool: D38: BlowFish salt length too long


assistant: ```c
char *make_bf_salt(int rounds, int length) {
  static char salt[31];
  char tbuf[3];
  if (length > 22) {
    printf("BlowFish salt length too long\n");
    exit(0);
  }
  sprintf(tbuf, "%02d", rounds);
  sprintf(salt, "$2a$%s$", tbuf);
  generate_random_salt(&salt[7], length);
  salt[length + 7] = '$';
  salt[length + 8] = '\0';
  return salt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<make_bf_salt>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x16,%esi
  jg     L22
L28:
  lea    0x5(%rsp),%r13
  mov    %r12d,%edx
  lea    D14(%rip),%rsi
  xor    %eax,%eax
  lea    D37(%rip),%r12
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    D23(%rip),%rsi
  call   <sprintf@plt>
  mov    %ebx,%esi
  lea    0x7(%r12),%rdi
  call   <generate_random_salt@plt>
  lea    0x7(%rbx),%eax
  add    $0x8,%ebx
  cltq
  movslq %ebx,%rbx
  movb   $0x24,(%r12,%rax,1)
  movb   $0x0,(%r12,%rbx,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L28
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D14: %02d

tool: D23: $2a$%s$

tool: D19: BlowFish salt length too long


assistant: ```c
char *make_bf_salt(int rounds, int length) {
  static char salt[31];
  char tbuf[3];
  if (length > 22) {
    printf("BlowFish salt length too long\n");
    exit(0);
  }
  sprintf(tbuf, "%02d", rounds);
  sprintf(salt, "$2a$%s$", tbuf);
  generate_random_salt(&salt[7], length);
  salt[length + 7] = '$';
  salt[length + 8] = '\0';
  return salt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<byteSwap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  je     L22
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L30:
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  shl    $0x10,%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x10(%rbp)
  subl   $0x1,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L30
  jmp    L19
L22:
  nop
L19:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void byteSwap(unsigned int *buf, unsigned words) {
  unsigned char *p;
  int i = 1;
  if (*(char *)&i == 1)
    return;
  p = (unsigned char *)buf;
  do {
    *buf++ = (unsigned int)((unsigned)p[3] << 8 | p[2]) << 16 | ((unsigned)p[1] << 8 | p[0]);
    p += 4;
  } while (--words);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<byteSwap>:
  endbr64
  ret
```

assistant: ```c
void byteSwap(unsigned int *buf, unsigned words) {
  unsigned char *p;
  int i = 1;
  if (*(char *)&i == 1)
    return;
  p = (unsigned char *)buf;
  do {
    *buf++ = (unsigned int)((unsigned)p[3] << 8 | p[2]) << 16 | ((unsigned)p[1] << 8 | p[0]);
    p += 4;
  } while (--words);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byteSwap>:
  endbr64
  ret
```

assistant: ```c
void byteSwap(unsigned int *buf, unsigned words) {
  unsigned char *p;
  int i = 1;
  if (*(char *)&i == 1)
    return;
  p = (unsigned char *)buf;
  do {
    *buf++ = (unsigned int)((unsigned)p[3] << 8 | p[2]) << 16 | ((unsigned)p[1] << 8 | p[0]);
    p += 4;
  } while (--words);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<byteSwap>:
  endbr64
  ret
```

assistant: ```c
void byteSwap(unsigned int *buf, unsigned words) {
  unsigned char *p;
  int i = 1;
  if (*(char *)&i == 1)
    return;
  p = (unsigned char *)buf;
  do {
    *buf++ = (unsigned int)((unsigned)p[3] << 8 | p[2]) << 16 | ((unsigned)p[1] << 8 | p[0]);
    p += 4;
  } while (--words);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<DefaultExtension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L41:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L3
  subq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L49
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L41
L49:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L28
L3:
  nop
L28:
  leave
  ret
```

assistant: ```c
void DefaultExtension(char *path, char *extension) {
  char *src;
  src = path + strlen(path) - 1;
  while (*src != '\\' && src != path) {
    if (*src == '.')
      return;
    src--;
  }
  strcat(path, extension);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<DefaultExtension>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  movzbl (%rax),%edx
  cmp    %rax,%rbx
  je     L40
  cmp    $0x5c,%dl
  je     L40
L24:
  cmp    $0x2e,%dl
  je     L34
  sub    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %rax,%rbx
  je     L40
  cmp    $0x5c,%dl
  jne    L24
L40:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void DefaultExtension(char *path, char *extension) {
  char *src;
  src = path + strlen(path) - 1;
  while (*src != '\\' && src != path) {
    if (*src == '.')
      return;
    src--;
  }
  strcat(path, extension);
}
```
user: What is the c source code of the assembly code below?

```asm
<DefaultExtension>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  movzbl (%rax),%edx
  cmp    %rax,%rbp
  je     L22
  cmp    $0x5c,%dl
  jne    L7
  jmp    L22
  nopl   0x0(%rax)
L29:
  movzbl -0x1(%rax),%edx
  sub    $0x1,%rax
  cmp    $0x5c,%dl
  je     L22
  cmp    %rax,%rbp
  je     L22
L7:
  cmp    $0x2e,%dl
  jne    L29
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L22:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcat@plt>
```

assistant: ```c
void DefaultExtension(char *path, char *extension) {
  char *src;
  src = path + strlen(path) - 1;
  while (*src != '\\' && src != path) {
    if (*src == '.')
      return;
    src--;
  }
  strcat(path, extension);
}
```