ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<r3d_decrypt_ecb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x640,%rsp
  mov    %rdi,-0x628(%rbp)
  mov    %rsi,-0x630(%rbp)
  mov    %rdx,-0x638(%rbp)
  mov    %ecx,-0x63c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x63c(%rbp),%eax
  lea    0x1ff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x9,%eax
  mov    %eax,-0x614(%rbp)
  mov    -0x630(%rbp),%rcx
  lea    -0x210(%rbp),%rax
  mov    $0x200,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x618(%rbp)
  jmp    L7
L15:
  mov    -0x618(%rbp),%eax
  shl    $0x9,%eax
  movslq %eax,%rdx
  mov    -0x628(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x610(%rbp),%rax
  mov    $0x200,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x410(%rbp),%rdx
  lea    -0x210(%rbp),%rcx
  lea    -0x610(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <r3d_decrypt_block@plt>
  mov    -0x618(%rbp),%eax
  shl    $0x9,%eax
  movslq %eax,%rdx
  mov    -0x638(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x410(%rbp),%rax
  mov    $0x200,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x618(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x618(%rbp)
L7:
  mov    -0x618(%rbp),%eax
  cmp    -0x614(%rbp),%eax
  jl     L15
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: %d


assistant: ```c
void r3d_decrypt_ecb(unsigned char *ciphertext, unsigned char *key, unsigned char *plaintext, int size) {
  int block_num = (size / 512);
  unsigned char ciphertext_block[512];
  unsigned char plaintext_block[512];
  unsigned char key_block[512];
  memcpy(key_block, key, 512);
  int i;
  for (i = 0; i < block_num; i++) {
    memcpy(ciphertext_block, ciphertext + (i * 512), 512);
    r3d_decrypt_block(ciphertext_block, key_block, plaintext_block);
    memcpy(plaintext + (i * 512), plaintext_block, 512);
    printf("%d\n", i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<r3d_decrypt_ecb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x618,%rsp
  mov    %rdi,%r12
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x608(%rsp)
  xor    %eax,%eax
  lea    0x1ff(%rcx),%r15d
  test   %ecx,%ecx
  cmovns %ecx,%r15d
  sar    $0x9,%r15d
  lea    0x400(%rsp),%rdi
  mov    $0x200,%edx
  call   <memcpy@plt>
  cmp    $0x1ff,%ebx
  jle    L2
  mov    $0x0,%ebx
L20:
  mov    %rsp,%r14
  mov    $0x200,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  lea    0x200(%rsp),%r13
  lea    0x400(%rsp),%rsi
  mov    %r13,%rdx
  mov    %r14,%rdi
  call   <r3d_decrypt_block@plt>
  mov    $0x200,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x200,%r12
  add    $0x200,%rbp
  cmp    %ebx,%r15d
  jg     L20
L2:
  mov    0x608(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x618,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: %d


assistant: ```c
void r3d_decrypt_ecb(unsigned char *ciphertext, unsigned char *key, unsigned char *plaintext, int size) {
  int block_num = (size / 512);
  unsigned char ciphertext_block[512];
  unsigned char plaintext_block[512];
  unsigned char key_block[512];
  memcpy(key_block, key, 512);
  int i;
  for (i = 0; i < block_num; i++) {
    memcpy(ciphertext_block, ciphertext + (i * 512), 512);
    r3d_decrypt_block(ciphertext_block, key_block, plaintext_block);
    memcpy(plaintext + (i * 512), plaintext_block, 512);
    printf("%d\n", i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<r3d_decrypt_ecb>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  lea    0x1ff(%rcx),%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x200,%edx
  sub    $0x628,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x618(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  lea    0x410(%rsp),%r14
  cmovns %ecx,%r13d
  mov    %r14,%rdi
  sar    $0x9,%r13d
  mov    %r13d,0xc(%rsp)
  call   <memcpy@plt>
  cmp    $0x1ff,%r12d
  jle    L22
  xor    %r13d,%r13d
  lea    0x10(%rsp),%r12
  lea    0x210(%rsp),%rbp
  nopl   (%rax)
L13:
  mov    %r15,%rsi
  mov    $0x200,%edx
  mov    %r12,%rdi
  add    $0x200,%r15
  call   <memcpy@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <r3d_decrypt_block@plt>
  mov    %rbx,%rdi
  mov    $0x200,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %r13d,%esi
  add    $0x1,%r13d
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x200,%rbx
  cmp    %r13d,0xc(%rsp)
  jg     L13
L22:
  mov    0x618(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x628,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string

tool: D0: %d


assistant: ```c
void r3d_decrypt_ecb(unsigned char *ciphertext, unsigned char *key, unsigned char *plaintext, int size) {
  int block_num = (size / 512);
  unsigned char ciphertext_block[512];
  unsigned char plaintext_block[512];
  unsigned char key_block[512];
  memcpy(key_block, key, 512);
  int i;
  for (i = 0; i < block_num; i++) {
    memcpy(ciphertext_block, ciphertext + (i * 512), 512);
    r3d_decrypt_block(ciphertext_block, key_block, plaintext_block);
    memcpy(plaintext + (i * 512), plaintext_block, 512);
    printf("%d\n", i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<r3d_decrypt_ecb>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  lea    0x1ff(%rcx),%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x200,%edx
  sub    $0x628,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x618(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  lea    0x410(%rsp),%r14
  cmovns %ecx,%r13d
  mov    %r14,%rdi
  sar    $0x9,%r13d
  mov    %r13d,0xc(%rsp)
  call   <memcpy@plt>
  cmp    $0x1ff,%r12d
  jle    L22
  xor    %r13d,%r13d
  lea    0x10(%rsp),%r12
  lea    0x210(%rsp),%rbp
  nopl   (%rax)
L5:
  mov    %r15,%rsi
  mov    $0x200,%edx
  mov    %r12,%rdi
  add    $0x200,%r15
  call   <memcpy@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <r3d_decrypt_block@plt>
  mov    %rbx,%rdi
  mov    $0x200,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %r13d,%esi
  add    $0x1,%r13d
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x200,%rbx
  cmp    %r13d,0xc(%rsp)
  jg     L5
L22:
  mov    0x618(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x628,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
void r3d_decrypt_ecb(unsigned char *ciphertext, unsigned char *key, unsigned char *plaintext, int size) {
  int block_num = (size / 512);
  unsigned char ciphertext_block[512];
  unsigned char plaintext_block[512];
  unsigned char key_block[512];
  memcpy(key_block, key, 512);
  int i;
  for (i = 0; i < block_num; i++) {
    memcpy(ciphertext_block, ciphertext + (i * 512), 512);
    r3d_decrypt_block(ciphertext_block, key_block, plaintext_block);
    memcpy(plaintext + (i * 512), plaintext_block, 512);
    printf("%d\n", i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quick_sort_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L6
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort_int>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort_int>
L6:
  nop
  leave
  ret
```

assistant: ```c
void quick_sort_int(int *unsorted, int p, int r) {
  int q;
  if (p < r) {
    q = partition(unsorted, p, r);
    quick_sort_int(unsorted, p, q - 1);
    quick_sort_int(unsorted, q + 1, r);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quick_sort_int>:
  endbr64
  cmp    %edx,%esi
  jl     L4
  ret
L4:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quick_sort_int>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quick_sort_int>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quick_sort_int(int *unsorted, int p, int r) {
  int q;
  if (p < r) {
    q = partition(unsorted, p, r);
    quick_sort_int(unsorted, p, q - 1);
    quick_sort_int(unsorted, q + 1, r);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rotate_right>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x13(%rdi),%r10
  lea    0x5b(%rdi),%r9
  mov    $0x2,%r11d
  mov    $0x1,%edi
  mov    $0x9,%r8d
  jmp    L24
L18:
  lea    -0x5a(%r9),%rsi
  lea    -0x9(%r10),%rcx
  mov    $0x0,%edx
L54:
  movzbl (%rsi),%ebp
  movzbl (%rcx),%r14d
  mov    %r14b,(%rsi)
  mov    %bpl,(%rcx)
  add    $0x1,%edx
  add    $0x9,%rsi
  sub    $0x9,%rcx
  mov    %edi,%ebp
  sub    %edx,%ebp
  cmp    %ebp,%edx
  jl     L54
L63:
  cmp    $0x8,%eax
  jg     L8
  mov    %r9,%rcx
  mov    %r10,%rdx
L35:
  movzbl (%rdx),%esi
  movzbl (%rcx),%ebp
  mov    %bpl,(%rdx)
  mov    %sil,(%rcx)
  add    $0x1,%eax
  add    $0x9,%rdx
  sub    $0x9,%rcx
  mov    %r8d,%esi
  sub    %eax,%esi
  add    %edi,%esi
  cmp    %esi,%eax
  jl     L35
L13:
  add    $0x1,%edi
  add    $0x1,%r11d
  add    $0xa,%r10
  add    $0x1,%r9
L24:
  mov    %edi,%eax
  test   %edi,%edi
  jg     L18
  jmp    L63
L8:
  cmp    $0x9,%r11d
  jle    L13
  mov    %rbx,%rbp
  add    $0x64,%rbx
L34:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <reverse@plt>
  add    $0xa,%rbp
  cmp    %rbp,%rbx
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
void rotate_right(char m[10][10]) {
  int i, j, k;
  char tmp = 0;
  for (k = 1; k < 10; k++) {
    for (i = 0, j = k; i < j; i++, j--) {
      tmp = m[i][j];
      m[i][j] = m[j][i];
      m[j][i] = tmp;
    }
    for (i = k, j = 10 - 1; i < j; i++, j--) {
      tmp = m[i][j];
      m[i][j] = m[j][i];
      m[j][i] = tmp;
    }
  }
  for (k = 0; k < 10; k++) {
    reverse(&m[k][0], 10);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rotate_right>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  lea    0xa(%rdi),%r11
  mov    $0x1,%r10d
  push   %rbx
  mov    $0x9,%r9d
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  mov    %r10d,%edi
  mov    %r11,%rcx
  mov    %rbx,%rdx
  xor    %eax,%eax
L11:
  movzbl (%rdx),%esi
  movzbl (%rcx),%ebp
  add    $0x1,%eax
  add    $0x9,%rdx
  sub    $0x9,%rcx
  mov    %bpl,-0x9(%rdx)
  mov    %sil,0x9(%rcx)
  mov    %edi,%esi
  sub    %eax,%esi
  cmp    %esi,%eax
  jl     L11
  cmp    $0x8,%r10
  ja     L53
  mov    %rbx,%rcx
  mov    %r11,%rdx
  mov    $0x9,%eax
L21:
  movzbl 0x9(%rdx),%esi
  movzbl 0x5a(%rcx),%ebp
  sub    $0x1,%eax
  add    $0x9,%rdx
  sub    $0x9,%rcx
  mov    %bpl,(%rdx)
  mov    %sil,0x63(%rcx)
  mov    %r9d,%esi
  sub    %eax,%esi
  add    %edi,%esi
  cmp    %eax,%esi
  jl     L21
L58:
  add    $0x1,%rbx
  add    $0xa,%r11
  add    $0x1,%r10
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L53:
  cmp    $0x9,%r10
  jne    L58
  mov    %r8,%rbx
  lea    0x64(%r8),%rbp
  nopl   (%rax)
L36:
  mov    %rbx,%rdi
  mov    $0xa,%esi
  add    $0xa,%rbx
  call   <reverse@plt>
  cmp    %rbx,%rbp
  jne    L36
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotate_right(char m[10][10]) {
  int i, j, k;
  char tmp = 0;
  for (k = 1; k < 10; k++) {
    for (i = 0, j = k; i < j; i++, j--) {
      tmp = m[i][j];
      m[i][j] = m[j][i];
      m[j][i] = tmp;
    }
    for (i = k, j = 10 - 1; i < j; i++, j--) {
      tmp = m[i][j];
      m[i][j] = m[j][i];
      m[j][i] = tmp;
    }
  }
  for (k = 0; k < 10; k++) {
    reverse(&m[k][0], 10);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rotate_right>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%rax
  mov    $0x4,%esi
  mov    $0x1,%ecx
  push   %rbx
  mov    %rax,%rdx
  mov    %rdi,%rbx
  mov    $0x3,%edi
  sub    $0x8,%rsp
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl 0x12(%rdx),%r8d
  movzbl 0x5a(%rax),%r9d
  mov    %r9b,0x12(%rdx)
  mov    %r8b,0x5a(%rax)
  cmp    $0x7,%ecx
  jg     L78
  movzbl 0x1b(%rdx),%r8d
  movzbl 0x51(%rax),%r9d
  mov    %r9b,0x1b(%rdx)
  mov    %r8b,0x51(%rax)
  cmp    $0x6,%edi
  ja     L78
  movslq %edi,%r8
  lea    (%r8,%r8,4),%r9
  movzbl 0x46(%rbx,%r8,1),%r11d
  lea    (%rbx,%r9,2),%r9
  movzbl 0x7(%r9),%r10d
  mov    %r11b,0x7(%r9)
  mov    %r10b,0x46(%rbx,%r8,1)
  cmp    $0x5,%esi
  ja     L78
  movslq %esi,%r8
  lea    (%r8,%r8,4),%r9
  movzbl 0x3c(%rbx,%r8,1),%r11d
  lea    (%rbx,%r9,2),%r9
  movzbl 0x6(%r9),%r10d
  mov    %r11b,0x6(%r9)
  mov    %r10b,0x3c(%rbx,%r8,1)
L78:
  add    $0x1,%rax
  add    $0xa,%rdx
  add    $0x1,%esi
  add    $0x1,%edi
L37:
  movzbl (%rax),%r8d
  movzbl 0x9(%rdx),%r9d
  mov    %r9b,(%rax)
  mov    %r8b,0x9(%rdx)
  lea    -0x1(%rcx),%r8d
  cmp    $0x1,%r8d
  jbe    L20
  movzbl 0x9(%rax),%r8d
  movzbl (%rdx),%r9d
  mov    %r9b,0x9(%rax)
  mov    %r8b,(%rdx)
  lea    -0x2(%rcx),%r8d
  cmp    $0x2,%r8d
  jle    L20
  movzbl 0x12(%rax),%r8d
  movzbl -0x9(%rdx),%r9d
  mov    %r9b,0x12(%rax)
  mov    %r8b,-0x9(%rdx)
  lea    -0x3(%rcx),%r8d
  cmp    $0x3,%r8d
  jle    L20
  movzbl 0x1b(%rax),%r8d
  movzbl -0x12(%rdx),%r9d
  mov    %r9b,0x1b(%rax)
  mov    %r8b,-0x12(%rdx)
  lea    -0x4(%rcx),%r8d
  cmp    $0x4,%r8d
  jle    L20
  movzbl 0x24(%rax),%r8d
  movzbl -0x1b(%rdx),%r9d
  mov    %r9b,0x24(%rax)
  mov    %r8b,-0x1b(%rdx)
L20:
  lea    -0x3(%rsi),%r8d
  add    $0x1,%ecx
  cmp    $0x8,%r8d
  jbe    L12
  cmp    $0xa,%ecx
  jne    L78
  lea    0x64(%rbx),%rbp
  nopl   0x0(%rax,%rax,1)
L53:
  mov    %rbx,%rdi
  mov    $0xa,%esi
  add    $0xa,%rbx
  call   <reverse@plt>
  cmp    %rbp,%rbx
  jne    L53
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotate_right(char m[10][10]) {
  int i, j, k;
  char tmp = 0;
  for (k = 1; k < 10; k++) {
    for (i = 0, j = k; i < j; i++, j--) {
      tmp = m[i][j];
      m[i][j] = m[j][i];
      m[j][i] = tmp;
    }
    for (i = k, j = 10 - 1; i < j; i++, j--) {
      tmp = m[i][j];
      m[i][j] = m[j][i];
      m[j][i] = tmp;
    }
  }
  for (k = 0; k < 10; k++) {
    reverse(&m[k][0], 10);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<backmove1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rcx
  mov    %edx,%eax
  movslq %eax,%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  add    %rdx,%rsi
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L1
L4:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  mov    -0x4(%rbp),%edi
  movslq %edi,%rdi
  add    %rsi,%rdi
  movzbl (%rdx),%edx
  mov    %dl,(%rdi)
  subl   $0x1,-0x4(%rbp)
L1:
  mov    %eax,%edx
  neg    %edx
  cmp    %edx,-0x4(%rbp)
  jge    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void backmove1(register char *from, register char *to, register int length) {
  int i;
  from += length;
  to += length;
  i = -1;
  while (i >= -length) {
    to[i] = from[i];
    i--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<backmove1>:
  endbr64
  movslq %edx,%r8
  mov    %edx,%ecx
  neg    %ecx
  test   %edx,%edx
  jle    L11
  mov    $0xffffffffffffffff,%rax
  add    %r8,%rdi
  add    %r8,%rsi
L8:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%ecx
  jle    L8
L11:
  ret
```

assistant: ```c
void backmove1(register char *from, register char *to, register int length) {
  int i;
  from += length;
  to += length;
  i = -1;
  while (i >= -length) {
    to[i] = from[i];
    i--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<backmove1>:
  endbr64
  mov    %edx,%ecx
  movslq %edx,%r8
  neg    %ecx
  test   %edx,%edx
  jle    L9
  mov    $0xffffffffffffffff,%rax
  add    %r8,%rdi
  add    %r8,%rsi
  nopl   0x0(%rax)
L1:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%ecx
  jle    L1
L9:
  ret
```

assistant: ```c
void backmove1(register char *from, register char *to, register int length) {
  int i;
  from += length;
  to += length;
  i = -1;
  while (i >= -length) {
    to[i] = from[i];
    i--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<backmove1>:
  endbr64
  mov    %edx,%ecx
  movslq %edx,%r8
  neg    %ecx
  test   %edx,%edx
  jle    L2
  mov    $0xffffffffffffffff,%rax
  add    %r8,%rdi
  add    %r8,%rsi
  nopl   0x0(%rax)
L13:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%ecx
  jle    L13
L2:
  ret
```

assistant: ```c
void backmove1(register char *from, register char *to, register int length) {
  int i;
  from += length;
  to += length;
  i = -1;
  while (i >= -length) {
    to[i] = from[i];
    i--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<delay_m>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x50,-0x8(%rbp)
  movl   $0x5dc,-0x4(%rbp)
  jmp    L0
L5:
  movl   $0x0,-0x10(%rbp)
  jmp    L36
L29:
  addl   $0x1,-0x10(%rbp)
L36:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jb     L29
  subl   $0x1,-0x14(%rbp)
L0:
  cmpl   $0x0,-0x14(%rbp)
  jg     L5
  movl   $0x0,-0xc(%rbp)
  jmp    L56
L59:
  addl   $0x1,-0xc(%rbp)
L56:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L59
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay_m(int m) {
  unsigned int a, b, i, j;
  a = 80;
  b = 1500;
  for (; m > 0; m--)
    for (i = 0; i < a; i++)
      ;
  for (j = 0; j < b; j++)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<delay_m>:
  endbr64
  mov    %edi,%edx
  mov    $0x5dc,%eax
  test   %edi,%edi
  jle    L24
L22:
  mov    $0x50,%eax
L32:
  sub    $0x1,%eax
  jne    L32
  sub    $0x1,%edx
  jne    L22
  mov    $0x5dc,%eax
L24:
  sub    $0x1,%eax
  jne    L24
  ret
```

assistant: ```c
void delay_m(int m) {
  unsigned int a, b, i, j;
  a = 80;
  b = 1500;
  for (; m > 0; m--)
    for (i = 0; i < a; i++)
      ;
  for (j = 0; j < b; j++)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<delay_m>:
  endbr64
  ret
```

assistant: ```c
void delay_m(int m) {
  unsigned int a, b, i, j;
  a = 80;
  b = 1500;
  for (; m > 0; m--)
    for (i = 0; i < a; i++)
      ;
  for (j = 0; j < b; j++)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<procbyte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L18
  addl   $0x1,-0x8(%rbp)
L18:
  addl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0x7,-0x4(%rbp)
  jle    L16
  cmpl   $0x8,-0x8(%rbp)
  jne    L12
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
L12:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void procbyte(int *secbyte) {
  int indicator = 0;
  int r;
  for (r = 0; r < 8; r++) {
    if (secbyte[r] == 1)
      indicator++;
  }
  if (indicator == 8)
    secbyte[0] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<procbyte>:
  endbr64
  mov    %rdi,%rax
  lea    0x20(%rdi),%rsi
  mov    $0x0,%edx
L17:
  cmpl   $0x1,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L17
  cmp    $0x8,%edx
  je     L25
L29:
  ret
L25:
  movl   $0x0,(%rdi)
  jmp    L29
```

assistant: ```c
void procbyte(int *secbyte) {
  int indicator = 0;
  int r;
  for (r = 0; r < 8; r++) {
    if (secbyte[r] == 1)
      indicator++;
  }
  if (indicator == 8)
    secbyte[0] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<procbyte>:
  endbr64
  mov    %rdi,%rax
  lea    0x20(%rdi),%rsi
  xor    %edx,%edx
  nopl   (%rax)
L17:
  xor    %ecx,%ecx
  cmpl   $0x1,(%rax)
  sete   %cl
  add    $0x4,%rax
  add    %ecx,%edx
  cmp    %rsi,%rax
  jne    L17
  cmp    $0x8,%edx
  je     L18
  ret
  nopl   0x0(%rax)
L18:
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void procbyte(int *secbyte) {
  int indicator = 0;
  int r;
  for (r = 0; r < 8; r++) {
    if (secbyte[r] == 1)
      indicator++;
  }
  if (indicator == 8)
    secbyte[0] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<procbyte>:
  endbr64
  movdqa D8(%rip),%xmm2
  movdqu 0x10(%rdi),%xmm0
  movdqu (%rdi),%xmm1
  pcmpeqd %xmm2,%xmm0
  pcmpeqd %xmm2,%xmm1
  pand   %xmm2,%xmm0
  psubd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    $0x8,%eax
  je     L7
  ret
  nopl   0x0(%rax)
L7:
  movl   $0x0,(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: byte[16]

tool: {"D8": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void procbyte(int *secbyte) {
  int indicator = 0;
  int r;
  for (r = 0; r < 8; r++) {
    if (secbyte[r] == 1)
      indicator++;
  }
  if (indicator == 8)
    secbyte[0] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L17
  mov    $0x1,%eax
  jmp    L4
L17:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fact>
  imul   -0x4(%rbp),%eax
L4:
  leave
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 0) {
    return 1;
  }
  return (n * fact(n - 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L2
  ret
L2:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fact>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 0) {
    return 1;
  }
  return (n * fact(n - 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L9
  nopl   (%rax)
L14:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L14
L9:
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 0) {
    return 1;
  }
  return (n * fact(n - 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L4
  nopl   (%rax)
L9:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L9
L4:
  ret
```

assistant: ```c
int fact(int n) {
  if (n == 0) {
    return 1;
  }
  return (n * fact(n - 1));
}
```