ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x350,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2b0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x54,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  lea    -0x340(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x12,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    %eax,-0x348(%rbp)
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    %eax,-0x344(%rbp)
  lea    -0x2b0(%rbp),%rax
  mov    %rax,%rdi
  call   <initialiseMazeArray@plt>
  mov    -0x344(%rbp),%ecx
  mov    -0x348(%rbp),%edx
  lea    -0x340(%rbp),%rsi
  lea    -0x2b0(%rbp),%rax
  mov    %rax,%rdi
  call   <removeWalls@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    -0x2b0(%rbp),%rax
  mov    %rax,%rdi
  call   <drawMaze@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D10: cls

tool: D0: pause

assistant: ```c
int main() {
  int maze[13][13] = {{0}};
  int visited[13 / 2][13 / 2] = {{0}};
  srand(time(NULL));
  int startRow = getRandomNumber(13 / 2);
  int startCol = getRandomNumber(13 / 2);
  initialiseMazeArray(maze);
  removeWalls(maze, visited, startRow, startCol);
  system("cls");
  drawMaze(maze);
  system("pause");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0x90(%rsp),%rdi
  mov    $0x54,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  mov    %rsp,%rdi
  mov    $0x12,%ecx
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    %eax,%ebp
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    %eax,%r12d
  lea    0x90(%rsp),%rbx
  mov    %rbx,%rdi
  call   <initialiseMazeArray@plt>
  mov    %rsp,%rsi
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %rbx,%rdi
  call   <removeWalls@plt>
  lea    D18(%rip),%rdi
  call   <system@plt>
  mov    %rbx,%rdi
  call   <drawMaze@plt>
  lea    D4(%rip),%rdi
  call   <system@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x340,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D18: cls

tool: D4: pause

assistant: ```c
int main() {
  int maze[13][13] = {{0}};
  int visited[13 / 2][13 / 2] = {{0}};
  srand(time(NULL));
  int startRow = getRandomNumber(13 / 2);
  int startCol = getRandomNumber(13 / 2);
  initialiseMazeArray(maze);
  removeWalls(maze, visited, startRow, startCol);
  system("cls");
  drawMaze(maze);
  system("pause");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x54,%ecx
  push   %r12
  push   %rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0x90(%rsp),%rdi
  lea    0x90(%rsp),%rbp
  rep stos %rax,%es:(%rdi)
  mov    $0x12,%ecx
  movl   $0x0,(%rdi)
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    $0x6,%edi
  mov    %eax,%r12d
  call   <getRandomNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <initialiseMazeArray@plt>
  mov    %rsp,%rsi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <removeWalls@plt>
  lea    D11(%rip),%rdi
  call   <system@plt>
  mov    %rbp,%rdi
  call   <drawMaze@plt>
  lea    D14(%rip),%rdi
  call   <system@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string

tool: D11: cls

tool: D14: pause

assistant: ```c
int main() {
  int maze[13][13] = {{0}};
  int visited[13 / 2][13 / 2] = {{0}};
  srand(time(NULL));
  int startRow = getRandomNumber(13 / 2);
  int startCol = getRandomNumber(13 / 2);
  initialiseMazeArray(maze);
  removeWalls(maze, visited, startRow, startCol);
  system("cls");
  drawMaze(maze);
  system("pause");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x54,%ecx
  push   %r12
  push   %rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0x90(%rsp),%rdi
  lea    0x90(%rsp),%rbp
  rep stos %rax,%es:(%rdi)
  mov    $0x12,%ecx
  movl   $0x0,(%rdi)
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    $0x6,%edi
  mov    %eax,%r12d
  call   <getRandomNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <initialiseMazeArray@plt>
  mov    %rsp,%rsi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <removeWalls@plt>
  lea    D3(%rip),%rdi
  call   <system@plt>
  mov    %rbp,%rdi
  call   <drawMaze@plt>
  lea    D5(%rip),%rdi
  call   <system@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D3: cls

tool: D5: pause

assistant: ```c
int main() {
  int maze[13][13] = {{0}};
  int visited[13 / 2][13 / 2] = {{0}};
  srand(time(NULL));
  int startRow = getRandomNumber(13 / 2);
  int startCol = getRandomNumber(13 / 2);
  initialiseMazeArray(maze);
  removeWalls(maze, visited, startRow, startCol);
  system("cls");
  drawMaze(maze);
  system("pause");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ivec_sort_by_permutation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L13
L37:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L37
  movl   $0x0,-0x18(%rbp)
  jmp    L10
L45:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
L32:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jne    L45
  addl   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L32
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void ivec_sort_by_permutation(int *v, const int *order, int n) {
  int i, newpos, a, b;
  int *o = malloc(n * sizeof(*o));
  for (i = 0; i < n; i++)
    o[order[i]] = i;
  for (i = 0; i < n; i++)
    while (o[i] != i) {
      newpos = o[i];
      a = v[i];
      v[i] = v[newpos];
      v[newpos] = a;
      b = o[newpos];
      o[newpos] = o[i];
      o[i] = b;
    }
  free(o);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ivec_sort_by_permutation>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  lea    0x0(,%rdx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r10
  test   %ebp,%ebp
  jle    L40
  mov    %ebp,%ecx
  mov    $0x0,%eax
L35:
  movslq (%r12,%rax,4),%rdx
  mov    %eax,(%r10,%rdx,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L35
  mov    %r10,%r11
  mov    %rbx,%rcx
  mov    $0x0,%r9d
  jmp    L68
L53:
  mov    (%rcx),%edi
  cltq
  shl    $0x2,%rax
  lea    (%rbx,%rax,1),%rdx
  mov    (%rdx),%r8d
  mov    %r8d,(%rcx)
  mov    %edi,(%rdx)
  lea    (%r10,%rax,1),%rdx
  mov    (%rdx),%eax
  mov    (%rsi),%edi
  mov    %edi,(%rdx)
  mov    %eax,(%rsi)
  cmp    %r9d,%eax
  jne    L53
L63:
  add    $0x1,%r9d
  add    $0x4,%r11
  add    $0x4,%rcx
  cmp    %r9d,%ebp
  je     L40
L68:
  mov    %r11,%rsi
  mov    (%r11),%eax
  cmp    %r9d,%eax
  jne    L53
  jmp    L63
L40:
  mov    %r10,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ivec_sort_by_permutation(int *v, const int *order, int n) {
  int i, newpos, a, b;
  int *o = malloc(n * sizeof(*o));
  for (i = 0; i < n; i++)
    o[order[i]] = i;
  for (i = 0; i < n; i++)
    while (o[i] != i) {
      newpos = o[i];
      a = v[i];
      v[i] = v[newpos];
      v[newpos] = a;
      b = o[newpos];
      o[newpos] = o[i];
      o[i] = b;
    }
  free(o);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ivec_sort_by_permutation>:
  endbr64
  push   %r13
  movslq %edx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%r13,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r10
  test   %r13d,%r13d
  jle    L39
  mov    %r13,%rbp
  xor    %eax,%eax
  nopl   0x0(%rax)
L13:
  movslq (%r12,%rax,4),%rdx
  mov    %eax,(%r10,%rdx,4)
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L13
  mov    %r10,%rcx
  mov    %rbx,%rsi
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L30:
  movslq (%rcx),%rax
  cmp    %r9d,%eax
  je     L6
L4:
  shl    $0x2,%rax
  mov    (%rsi),%edi
  lea    (%rbx,%rax,1),%rdx
  mov    (%rdx),%r8d
  mov    %r8d,(%rsi)
  mov    %edi,(%rdx)
  lea    (%r10,%rax,1),%rdx
  mov    (%rcx),%edi
  movslq (%rdx),%rax
  mov    %edi,(%rdx)
  mov    %eax,(%rcx)
  cmp    %r9d,%eax
  jne    L4
L6:
  add    $0x1,%r9d
  add    $0x4,%rcx
  add    $0x4,%rsi
  cmp    %r9d,%ebp
  jne    L30
L39:
  add    $0x8,%rsp
  mov    %r10,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <free@plt>
```

assistant: ```c
void ivec_sort_by_permutation(int *v, const int *order, int n) {
  int i, newpos, a, b;
  int *o = malloc(n * sizeof(*o));
  for (i = 0; i < n; i++)
    o[order[i]] = i;
  for (i = 0; i < n; i++)
    while (o[i] != i) {
      newpos = o[i];
      a = v[i];
      v[i] = v[newpos];
      v[newpos] = a;
      b = o[newpos];
      o[newpos] = o[i];
      o[i] = b;
    }
  free(o);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ivec_sort_by_permutation>:
  endbr64
  push   %r13
  movslq %edx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%r13,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r10
  test   %r13d,%r13d
  jle    L27
  mov    %r13,%rbp
  xor    %eax,%eax
  nopl   0x0(%rax)
L7:
  movslq (%r12,%rax,4),%rdx
  mov    %eax,(%r10,%rdx,4)
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L7
  mov    %r10,%rcx
  mov    %rbx,%rsi
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L10:
  movslq (%rcx),%rax
  cmp    %r9d,%eax
  je     L35
L6:
  shl    $0x2,%rax
  mov    (%rsi),%edi
  lea    (%rbx,%rax,1),%rdx
  mov    (%rdx),%r8d
  mov    %r8d,(%rsi)
  mov    %edi,(%rdx)
  lea    (%r10,%rax,1),%rdx
  mov    (%rcx),%edi
  movslq (%rdx),%rax
  mov    %edi,(%rdx)
  mov    %eax,(%rcx)
  cmp    %r9d,%eax
  jne    L6
L35:
  add    $0x1,%r9d
  add    $0x4,%rcx
  add    $0x4,%rsi
  cmp    %r9d,%ebp
  jne    L10
L27:
  add    $0x8,%rsp
  mov    %r10,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <free@plt>
```

assistant: ```c
void ivec_sort_by_permutation(int *v, const int *order, int n) {
  int i, newpos, a, b;
  int *o = malloc(n * sizeof(*o));
  for (i = 0; i < n; i++)
    o[order[i]] = i;
  for (i = 0; i < n; i++)
    while (o[i] != i) {
      newpos = o[i];
      a = v[i];
      v[i] = v[newpos];
      v[newpos] = a;
      b = o[newpos];
      o[newpos] = o[i];
      o[i] = b;
    }
  free(o);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clone_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <safe_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *clone_memory(void *memory, size_t size) {
  void *tmp = safe_malloc(size);
  memcpy(tmp, memory, size);
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clone_memory>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <safe_malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *clone_memory(void *memory, size_t size) {
  void *tmp = safe_malloc(size);
  memcpy(tmp, memory, size);
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clone_memory>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <safe_malloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *clone_memory(void *memory, size_t size) {
  void *tmp = safe_malloc(size);
  memcpy(tmp, memory, size);
  return tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clone_memory>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <safe_malloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *clone_memory(void *memory, size_t size) {
  void *tmp = safe_malloc(size);
  memcpy(tmp, memory, size);
  return tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<twobyte_memmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x2,-0x18(%rbp)
  subq   $0x2,-0x20(%rbp)
  jmp    L44
L59:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L4
  mov    -0x18(%rbp),%rax
  sub    $0x2,%rax
  jmp    L28
L4:
  subq   $0x1,-0x20(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %ecx,%eax
  mov    %eax,-0x8(%rbp)
L44:
  cmpq   $0x0,-0x20(%rbp)
  jne    L59
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L43
  mov    -0x18(%rbp),%rax
  sub    $0x2,%rax
  jmp    L28
L43:
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
char *twobyte_memmem(const unsigned char *h, size_t k, const unsigned char *n) {
  uint16_t nw = n[0] << 8 | n[1], hw = h[0] << 8 | h[1];
  for (h += 2, k -= 2; k; k--, hw = hw << 8 | *h++)
    if (hw == nw)
      return (char *)h - 2;
  return hw == nw ? (char *)h - 2 : 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<twobyte_memmem>:
  endbr64
  movzbl (%rdx),%r8d
  shl    $0x8,%r8d
  movzbl 0x1(%rdx),%eax
  or     %eax,%r8d
  movzbl (%rdi),%edx
  shl    $0x8,%edx
  movzbl 0x1(%rdi),%eax
  or     %eax,%edx
  lea    0x2(%rdi),%rax
  cmp    $0x2,%rsi
  je     L27
  lea    0x3(%rdi),%rcx
  add    %rsi,%rdi
  cmp    %edx,%r8d
  je     L31
L36:
  shl    $0x8,%edx
  mov    %rcx,%rax
  movzbl -0x1(%rcx),%esi
  or     %esi,%edx
  cmp    %rdi,%rcx
  je     L27
  add    $0x1,%rcx
  cmp    %edx,%r8d
  jne    L36
L31:
  sub    $0x2,%rax
  ret
L27:
  sub    $0x2,%rax
  cmp    %edx,%r8d
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *twobyte_memmem(const unsigned char *h, size_t k, const unsigned char *n) {
  uint16_t nw = n[0] << 8 | n[1], hw = h[0] << 8 | h[1];
  for (h += 2, k -= 2; k; k--, hw = hw << 8 | *h++)
    if (hw == nw)
      return (char *)h - 2;
  return hw == nw ? (char *)h - 2 : 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<twobyte_memmem>:
  endbr64
  movzwl (%rdx),%r8d
  movzwl (%rdi),%edx
  lea    0x2(%rdi),%rax
  rol    $0x8,%r8w
  rol    $0x8,%dx
  movzwl %r8w,%r8d
  movzwl %dx,%edx
  cmp    $0x2,%rsi
  je     L5
  cmp    %edx,%r8d
  je     L13
  lea    0x3(%rdi),%rcx
  add    %rsi,%rdi
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rcx
  cmp    %edx,%r8d
  je     L36
L24:
  movzbl -0x1(%rcx),%esi
  shl    $0x8,%edx
  mov    %rcx,%rax
  or     %esi,%edx
  cmp    %rdi,%rcx
  jne    L25
L5:
  sub    $0x2,%rax
  cmp    %edx,%r8d
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  sub    $0x2,%rax
  ret
L13:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *twobyte_memmem(const unsigned char *h, size_t k, const unsigned char *n) {
  uint16_t nw = n[0] << 8 | n[1], hw = h[0] << 8 | h[1];
  for (h += 2, k -= 2; k; k--, hw = hw << 8 | *h++)
    if (hw == nw)
      return (char *)h - 2;
  return hw == nw ? (char *)h - 2 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<twobyte_memmem>:
  endbr64
  movzwl (%rdx),%r8d
  movzwl (%rdi),%edx
  lea    0x2(%rdi),%rax
  rol    $0x8,%r8w
  rol    $0x8,%dx
  movzwl %r8w,%r8d
  movzwl %dx,%edx
  cmp    $0x2,%rsi
  je     L16
  cmp    %edx,%r8d
  je     L35
  lea    0x3(%rdi),%rcx
  add    %rsi,%rdi
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rcx
  cmp    %edx,%r8d
  je     L39
L48:
  movzbl -0x1(%rcx),%esi
  shl    $0x8,%edx
  mov    %rcx,%rax
  or     %esi,%edx
  cmp    %rdi,%rcx
  jne    L26
L16:
  sub    $0x2,%rax
  cmp    %edx,%r8d
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  sub    $0x2,%rax
  ret
L35:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *twobyte_memmem(const unsigned char *h, size_t k, const unsigned char *n) {
  uint16_t nw = n[0] << 8 | n[1], hw = h[0] << 8 | h[1];
  for (h += 2, k -= 2; k; k--, hw = hw << 8 | *h++)
    if (hw == nw)
      return (char *)h - 2;
  return hw == nw ? (char *)h - 2 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AntennaOn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x14,%edi
  call   <Read_MFRC522@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    $0x9,%eax
  test   %eax,%eax
  jne    L6
  movzbl -0x1(%rbp),%eax
  or     $0x9,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x14,%edi
  call   <Write_MFRC522@plt>
L6:
  mov    $0xc8,%edi
  call   <bcm2835_delay@plt>
  nop
  leave
  ret
```

assistant: ```c
void AntennaOn(void) {
  unsigned char temp = Read_MFRC522(0x14);
  if (!(temp & 0x09))
    Write_MFRC522(0x14, temp | 0x09);
  bcm2835_delay(200);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<AntennaOn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <Read_MFRC522@plt>
  test   $0x9,%al
  je     L14
L16:
  mov    $0xc8,%edi
  call   <bcm2835_delay@plt>
  add    $0x8,%rsp
  ret
L14:
  or     $0x9,%eax
  movzbl %al,%esi
  mov    $0x14,%edi
  call   <Write_MFRC522@plt>
  jmp    L16
```

assistant: ```c
void AntennaOn(void) {
  unsigned char temp = Read_MFRC522(0x14);
  if (!(temp & 0x09))
    Write_MFRC522(0x14, temp | 0x09);
  bcm2835_delay(200);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<AntennaOn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <Read_MFRC522@plt>
  test   $0x9,%al
  je     L9
  mov    $0xc8,%edi
  add    $0x8,%rsp
  jmp    1080 <bcm2835_delay@plt>
  nopl   0x0(%rax)
L9:
  or     $0x9,%eax
  mov    $0x14,%edi
  movzbl %al,%esi
  call   <Write_MFRC522@plt>
  mov    $0xc8,%edi
  add    $0x8,%rsp
  jmp    1080 <bcm2835_delay@plt>
```

assistant: ```c
void AntennaOn(void) {
  unsigned char temp = Read_MFRC522(0x14);
  if (!(temp & 0x09))
    Write_MFRC522(0x14, temp | 0x09);
  bcm2835_delay(200);
}
```
user: What is the c source code of the assembly code below?

```asm
<AntennaOn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <Read_MFRC522@plt>
  test   $0x9,%al
  je     L0
  mov    $0xc8,%edi
  add    $0x8,%rsp
  jmp    1080 <bcm2835_delay@plt>
  nopl   0x0(%rax)
L0:
  or     $0x9,%eax
  mov    $0x14,%edi
  movzbl %al,%esi
  call   <Write_MFRC522@plt>
  mov    $0xc8,%edi
  add    $0x8,%rsp
  jmp    1080 <bcm2835_delay@plt>
```

assistant: ```c
void AntennaOn(void) {
  unsigned char temp = Read_MFRC522(0x14);
  if (!(temp & 0x09))
    Write_MFRC522(0x14, temp | 0x09);
  bcm2835_delay(200);
}
```