ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D51
type: string
name: read_data
arguments: tag: D67
type: string
name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D77
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D57
type: string
name: read_data
arguments: tag: D73
type: string
name: read_data
arguments: tag: D78
type: string

tool: D51: ***** MENU *****


tool: D67: 1........INSERIR


tool: D4: 2........REMOVER


tool: D77: 3........MOSTRAR


tool: D15: 4...........SAIR


tool: D57: Escolha uma opcao: 

tool: D73: %d

tool: D78: 


assistant: ```c
int menu() {
  int op;
  printf("***** MENU *****\n");
  printf("1........INSERIR\n");
  printf("2........REMOVER\n");
  printf("3........MOSTRAR\n");
  printf("4...........SAIR\n");
  printf("Escolha uma opcao: ");
  scanf("%d", &op);
  printf("\n");
  return (op);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D72(%rip),%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  lea    D79(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D55
type_guessed: string
name: read_data
arguments: tag: D34
type_guessed: string
name: read_data
arguments: tag: D56
type_guessed: string
name: read_data
arguments: tag: D72
type_guessed: string
name: read_data
arguments: tag: D73
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D22
type_guessed: string
name: read_data
arguments: tag: D79
type_guessed: string

tool: D55: ***** MENU *****


tool: D34: 1........INSERIR


tool: D56: 2........REMOVER


tool: D72: 3........MOSTRAR


tool: D73: 4...........SAIR


tool: D1: Escolha uma opcao: 

tool: D22: %d

tool: D79: 


assistant: ```c
int menu() {
  int op;
  printf("***** MENU *****\n");
  printf("1........INSERIR\n");
  printf("2........REMOVER\n");
  printf("3........MOSTRAR\n");
  printf("4...........SAIR\n");
  printf("Escolha uma opcao: ");
  scanf("%d", &op);
  printf("\n");
  return (op);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D52(%rip),%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D42
type: string
name: unpack_data
arguments: label: D54
type: string
name: unpack_data
arguments: label: D35
type: string
name: unpack_data
arguments: label: D57
type: string
name: unpack_data
arguments: label: D14
type: string
name: unpack_data
arguments: label: D52
type: string
name: unpack_data
arguments: label: D10
type: string

tool: D12: ***** MENU *****


tool: D42: 1........INSERIR


tool: D54: 2........REMOVER


tool: D35: 3........MOSTRAR


tool: D57: 4...........SAIR


tool: D14: Escolha uma opcao: 

tool: D52: %d

tool: D10: 


assistant: ```c
int menu() {
  int op;
  printf("***** MENU *****\n");
  printf("1........INSERIR\n");
  printf("2........REMOVER\n");
  printf("3........MOSTRAR\n");
  printf("4...........SAIR\n");
  printf("Escolha uma opcao: ");
  scanf("%d", &op);
  printf("\n");
  return (op);
}
```
user: Translate the below assembly code into C programming language:

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  lea    D64(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  lea    D74(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D64
data_type: string
name: disassemble_data
arguments: data_label: D66
data_type: string
name: disassemble_data
arguments: data_label: D21
data_type: string
name: disassemble_data
arguments: data_label: D10
data_type: string
name: disassemble_data
arguments: data_label: D51
data_type: string
name: disassemble_data
arguments: data_label: D32
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string
name: disassemble_data
arguments: data_label: D74
data_type: string

tool: D64: ***** MENU *****


tool: D66: 1........INSERIR


tool: D21: 2........REMOVER


tool: D10: 3........MOSTRAR


tool: D51: 4...........SAIR


tool: D32: Escolha uma opcao: 

tool: D15: %d

tool: D74: 


assistant: ```c
int menu() {
  int op;
  printf("***** MENU *****\n");
  printf("1........INSERIR\n");
  printf("2........REMOVER\n");
  printf("3........MOSTRAR\n");
  printf("4...........SAIR\n");
  printf("Escolha uma opcao: ");
  scanf("%d", &op);
  printf("\n");
  return (op);
}
```
user: What is the c source code of the assembly code below:

```asm
<multi_rectv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  lea    D1(%rip),%r8
  mov    $0x2b,%ecx
  lea    D6(%rip),%rdx
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <u_calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L17
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L26
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L9
  mov    0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D6
type: string

tool: D1: v_r

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/prool/ccx_prool/refs/heads/master/CalculiX/ccx_2.16/src/multi_rectv.c

assistant: ```c
void multi_rectv(double *au_1, int *irow_1, int *jq_1, int n_1, int m_1, double *b, double **v_rp) {
  int irow, i, j;
  double *v_r = NULL, value;
  v_r = (double *)u_calloc((m_1), sizeof(double), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/prool/ccx_prool/refs/heads/master/CalculiX/ccx_2.16/src/multi_rectv.c", 43, "v_r");
  for (j = 0; j < m_1; j++) {
    for (i = jq_1[j] - 1; i < jq_1[j + 1] - 1; i++) {
      v_r[j] += au_1[i] * b[irow_1[i] - 1];
    }
  }
  *v_rp = v_r;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multi_rectv>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %r8d,%r13d
  mov    %r9,%r12
  lea    D17(%rip),%r8
  mov    $0x2b,%ecx
  lea    D16(%rip),%rdx
  mov    $0x8,%esi
  mov    %r13d,%edi
  call   <u_calloc@plt>
  mov    %rax,%r8
  test   %r13d,%r13d
  jle    L29
  mov    %rax,%rdi
  lea    0x4(%r14),%rsi
  lea    -0x1(%r13),%eax
  lea    0x8(%r14,%rax,4),%r10
L25:
  mov    %rsi,%r9
  mov    -0x4(%rsi),%edx
  lea    -0x1(%rdx),%eax
  cmp    (%rsi),%edx
  jge    L3
  mov    %rdi,%rcx
  cltq
L15:
  movslq 0x0(%rbp,%rax,4),%rdx
  movsd  -0x8(%r12,%rdx,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x1,%rax
  mov    (%r9),%edx
  sub    $0x1,%edx
  cmp    %eax,%edx
  jg     L15
L3:
  add    $0x8,%rdi
  add    $0x4,%rsi
  cmp    %r10,%rsi
  jne    L25
L29:
  mov    0x30(%rsp),%rax
  mov    %r8,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D17: v_r

tool: D16: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/prool/ccx_prool/refs/heads/master/CalculiX/ccx_2.16/src/multi_rectv.c

assistant: ```c
void multi_rectv(double *au_1, int *irow_1, int *jq_1, int n_1, int m_1, double *b, double **v_rp) {
  int irow, i, j;
  double *v_r = NULL, value;
  v_r = (double *)u_calloc((m_1), sizeof(double), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/prool/ccx_prool/refs/heads/master/CalculiX/ccx_2.16/src/multi_rectv.c", 43, "v_r");
  for (j = 0; j < m_1; j++) {
    for (i = jq_1[j] - 1; i < jq_1[j + 1] - 1; i++) {
      v_r[j] += au_1[i] * b[irow_1[i] - 1];
    }
  }
  *v_rp = v_r;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multi_rectv>:
  endbr64
  push   %r14
  mov    %r8d,%r14d
  mov    $0x2b,%ecx
  lea    D11(%rip),%r8
  push   %r13
  mov    %rdx,%r13
  lea    D15(%rip),%rdx
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14d,%edi
  call   <u_calloc@plt>
  mov    %rax,%r10
  test   %r14d,%r14d
  jle    L13
  mov    %rax,%rcx
  lea    -0x1(%r14),%eax
  mov    %r13,%rdi
  lea    0x4(%r13,%rax,4),%r9
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%rdi),%r8d
  mov    0x4(%rdi),%edx
  lea    -0x1(%r8),%eax
  lea    -0x1(%rdx),%esi
  cmp    %edx,%r8d
  jge    L7
  movsd  (%rcx),%xmm1
  cltq
L2:
  movslq 0x0(%rbp,%rax,4),%rdx
  movsd  -0x8(%r12,%rdx,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %eax,%esi
  jg     L2
L7:
  add    $0x4,%rdi
  add    $0x8,%rcx
  cmp    %rdi,%r9
  jne    L21
L13:
  mov    0x30(%rsp),%rax
  mov    %r10,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D11
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string

tool: D11: v_r

tool: D15: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/prool/ccx_prool/refs/heads/master/CalculiX/ccx_2.16/src/multi_rectv.c

assistant: ```c
void multi_rectv(double *au_1, int *irow_1, int *jq_1, int n_1, int m_1, double *b, double **v_rp) {
  int irow, i, j;
  double *v_r = NULL, value;
  v_r = (double *)u_calloc((m_1), sizeof(double), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/prool/ccx_prool/refs/heads/master/CalculiX/ccx_2.16/src/multi_rectv.c", 43, "v_r");
  for (j = 0; j < m_1; j++) {
    for (i = jq_1[j] - 1; i < jq_1[j + 1] - 1; i++) {
      v_r[j] += au_1[i] * b[irow_1[i] - 1];
    }
  }
  *v_rp = v_r;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<multi_rectv>:
  endbr64
  push   %r14
  mov    %r8d,%r14d
  mov    $0x2b,%ecx
  lea    D3(%rip),%r8
  push   %r13
  mov    %rdx,%r13
  lea    D9(%rip),%rdx
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14d,%edi
  call   <u_calloc@plt>
  mov    %rax,%r10
  test   %r14d,%r14d
  jle    L2
  mov    %rax,%rcx
  lea    -0x1(%r14),%eax
  mov    %r13,%rdi
  lea    0x4(%r13,%rax,4),%r9
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rdi),%r8d
  mov    0x4(%rdi),%edx
  lea    -0x1(%r8),%eax
  lea    -0x1(%rdx),%esi
  cmp    %edx,%r8d
  jge    L12
  movsd  (%rcx),%xmm1
  cltq
L29:
  movslq 0x0(%rbp,%rax,4),%rdx
  movsd  -0x8(%r12,%rdx,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %eax,%esi
  jg     L29
L12:
  add    $0x4,%rdi
  add    $0x8,%rcx
  cmp    %rdi,%r9
  jne    L19
L2:
  mov    0x30(%rsp),%rax
  mov    %r10,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D3: v_r

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/prool/ccx_prool/refs/heads/master/CalculiX/ccx_2.16/src/multi_rectv.c

assistant: ```c
void multi_rectv(double *au_1, int *irow_1, int *jq_1, int n_1, int m_1, double *b, double **v_rp) {
  int irow, i, j;
  double *v_r = NULL, value;
  v_r = (double *)u_calloc((m_1), sizeof(double), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/prool/ccx_prool/refs/heads/master/CalculiX/ccx_2.16/src/multi_rectv.c", 43, "v_r");
  for (j = 0; j < m_1; j++) {
    for (i = jq_1[j] - 1; i < jq_1[j + 1] - 1; i++) {
      v_r[j] += au_1[i] * b[irow_1[i] - 1];
    }
  }
  *v_rp = v_r;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rc_send_servo_pulse_normalized>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movss  %xmm0,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L20
  cmpl   $0x8,-0x14(%rbp)
  jle    L45
L20:
  mov    $0x8,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L9
L45:
  movss  D52(%rip),%xmm0
  comiss -0x18(%rbp),%xmm0
  ja     L0
  movss  -0x18(%rbp),%xmm0
  comiss D26(%rip),%xmm0
  jbe    L18
L0:
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L9
L18:
  movss  -0x18(%rbp),%xmm1
  movss  D30(%rip),%xmm0
  mulss  %xmm0,%xmm1
  movss  D47(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <rc_send_servo_pulse_us@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string
name: extract_symbolic_data
arguments: tag: D52
type_infered: byte[4]
name: extract_symbolic_data
arguments: tag: D26
type_infered: f32
name: extract_symbolic_data
arguments: tag: D42
type_infered: string
name: extract_symbolic_data
arguments: tag: D30
type_infered: byte[4]
name: extract_symbolic_data
arguments: tag: D47
type_infered: f32

tool: D5: ERROR: Servo Channel must be between 1&%d


tool: {"D52": [0x00,0x00,0xc0,0xbf]}

tool: D26: 1.5

tool: D42: ERROR: normalized input must be between -1 & 1

tool: {"D30": [0x00,0x00,0x16,0x44]}

tool: D47: 1500

assistant: ```c
int rc_send_servo_pulse_normalized(int ch, float input) {
  if (ch < 1 || ch > 8) {
    printf("ERROR: Servo Channel must be between 1&%d\n", 8);
    return -1;
  }
  if (input < -1.5 || input > 1.5) {
    printf("ERROR: normalized input must be between -1 & 1\n");
    return -1;
  }
  float micros = 1500 + (input * (1200 / 2));
  return rc_send_servo_pulse_us(ch, micros);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rc_send_servo_pulse_normalized>:
  endbr64
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%eax
  cmp    $0x7,%eax
  ja     L46
  movss  D48(%rip),%xmm1
  comiss %xmm0,%xmm1
  ja     L41
  comiss D54(%rip),%xmm0
  ja     L41
  mulss  D13(%rip),%xmm0
  addss  D36(%rip),%xmm0
  call   <rc_send_servo_pulse_us@plt>
L10:
  add    $0x8,%rsp
  ret
L46:
  mov    $0x8,%esi
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L10
L41:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D48
type_infered: byte[4]
name: parse_data
arguments: data_label: D54
type_infered: f32
name: parse_data
arguments: data_label: D13
type_infered: byte[4]
name: parse_data
arguments: data_label: D36
type_infered: f32
name: parse_data
arguments: data_label: D55
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string

tool: {"D48": [0x00,0x00,0xc0,0xbf]}

tool: D54: 1.5

tool: {"D13": [0x00,0x00,0x16,0x44]}

tool: D36: 1500

tool: D55: ERROR: Servo Channel must be between 1&%d


tool: D17: ERROR: normalized input must be between -1 & 1

assistant: ```c
int rc_send_servo_pulse_normalized(int ch, float input) {
  if (ch < 1 || ch > 8) {
    printf("ERROR: Servo Channel must be between 1&%d\n", 8);
    return -1;
  }
  if (input < -1.5 || input > 1.5) {
    printf("ERROR: normalized input must be between -1 & 1\n");
    return -1;
  }
  float micros = 1500 + (input * (1200 / 2));
  return rc_send_servo_pulse_us(ch, micros);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rc_send_servo_pulse_normalized>:
  endbr64
  lea    -0x1(%rdi),%eax
  sub    $0x8,%rsp
  cmp    $0x7,%eax
  ja     L19
  movss  D18(%rip),%xmm1
  comiss %xmm0,%xmm1
  ja     L2
  comiss D29(%rip),%xmm0
  ja     L2
  mulss  D45(%rip),%xmm0
  addss  D3(%rip),%xmm0
  add    $0x8,%rsp
  jmp    1090 <rc_send_servo_pulse_us@plt>
  nop
L2:
  lea    D49(%rip),%rdi
  call   <puts@plt>
L37:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
L19:
  mov    $0x8,%esi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type: byte[4]
name: disassemble_data
arguments: data_label: D29
type: f32
name: disassemble_data
arguments: data_label: D45
type: byte[4]
name: disassemble_data
arguments: data_label: D3
type: f32
name: disassemble_data
arguments: data_label: D49
type: string
name: disassemble_data
arguments: data_label: D51
type: string

tool: {"D18": [0x00,0x00,0xc0,0xbf]}

tool: D29: 1.5

tool: {"D45": [0x00,0x00,0x16,0x44]}

tool: D3: 1500

tool: D49: ERROR: normalized input must be between -1 & 1

tool: D51: ERROR: Servo Channel must be between 1&%d


assistant: ```c
int rc_send_servo_pulse_normalized(int ch, float input) {
  if (ch < 1 || ch > 8) {
    printf("ERROR: Servo Channel must be between 1&%d\n", 8);
    return -1;
  }
  if (input < -1.5 || input > 1.5) {
    printf("ERROR: normalized input must be between -1 & 1\n");
    return -1;
  }
  float micros = 1500 + (input * (1200 / 2));
  return rc_send_servo_pulse_us(ch, micros);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rc_send_servo_pulse_normalized>:
  endbr64
  lea    -0x1(%rdi),%eax
  sub    $0x8,%rsp
  cmp    $0x7,%eax
  ja     L24
  movss  D19(%rip),%xmm1
  comiss %xmm0,%xmm1
  ja     L12
  comiss D36(%rip),%xmm0
  ja     L12
  mulss  D46(%rip),%xmm0
  addss  D22(%rip),%xmm0
  add    $0x8,%rsp
  jmp    1090 <rc_send_servo_pulse_us@plt>
  nop
L12:
  lea    D2(%rip),%rdi
  call   <puts@plt>
L3:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
L24:
  mov    $0x8,%esi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: data_label: D19
datatype: byte[4]
name: disassemble_data
arguments: data_label: D36
datatype: f32
name: disassemble_data
arguments: data_label: D46
datatype: byte[4]
name: disassemble_data
arguments: data_label: D22
datatype: f32
name: disassemble_data
arguments: data_label: D2
datatype: string
name: disassemble_data
arguments: data_label: D52
datatype: string

tool: {"D19": [0x00,0x00,0xc0,0xbf]}

tool: D36: 1.5

tool: {"D46": [0x00,0x00,0x16,0x44]}

tool: D22: 1500

tool: D2: ERROR: normalized input must be between -1 & 1

tool: D52: ERROR: Servo Channel must be between 1&%d


assistant: ```c
int rc_send_servo_pulse_normalized(int ch, float input) {
  if (ch < 1 || ch > 8) {
    printf("ERROR: Servo Channel must be between 1&%d\n", 8);
    return -1;
  }
  if (input < -1.5 || input > 1.5) {
    printf("ERROR: normalized input must be between -1 & 1\n");
    return -1;
  }
  float micros = 1500 + (input * (1200 / 2));
  return rc_send_servo_pulse_us(ch, micros);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<display_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: string

tool: D7: Usage: rfdformat [OPTIONS] MTD-device
Formats NOR flash for resident flash disk

-h         --help               display this help and exit
-V         --version            output version information and exit


assistant: ```c
void display_help(void) {
  printf("Usage: "
         "rfdformat"
         " [OPTIONS] MTD-device\n"
         "Formats NOR flash for resident flash disk\n"
         "\n"
         "-h         --help               display this help and exit\n"
         "-V         --version            output version information and exit\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<display_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: string

tool: D6: Usage: rfdformat [OPTIONS] MTD-device
Formats NOR flash for resident flash disk

-h         --help               display this help and exit
-V         --version            output version information and exit


assistant: ```c
void display_help(void) {
  printf("Usage: "
         "rfdformat"
         " [OPTIONS] MTD-device\n"
         "Formats NOR flash for resident flash disk\n"
         "\n"
         "-h         --help               display this help and exit\n"
         "-V         --version            output version information and exit\n");
  exit(0);
}
```