ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_path>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  movslq %edx,%rdx
  mov    %rdi,%r8
  mov    0x8(%rsi,%rdx,8),%rdi
  mov    %r8,%rsi
  mov    (%rax),%edx
  call   <fnmatch@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int check_path(const char *file_name, const char *const *parms, int parm_pos) {
  if (fnmatch(parms[parm_pos + 1], file_name, FNM_NOESCAPE) == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ctos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movw   $0x0,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  movzwl -0x2(%rbp),%eax
  add    %edx,%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x2(%rbp),%eax
  add    %edx,%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short ctos(unsigned char *buffer) {
  short temp = 0;
  temp += buffer[0];
  temp += buffer[1] << 8;
  return temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ctos>:
  endbr64
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl (%rdi),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
short ctos(unsigned char *buffer) {
  short temp = 0;
  temp += buffer[0];
  temp += buffer[1] << 8;
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ctos>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
short ctos(unsigned char *buffer) {
  short temp = 0;
  temp += buffer[0];
  temp += buffer[1] << 8;
  return temp;
}
```
user: What is the c source code of the assembly code below?

```asm
<ctos>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
short ctos(unsigned char *buffer) {
  short temp = 0;
  temp += buffer[0];
  temp += buffer[1] << 8;
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add_root>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x4,%eax
  mov    %eax,%edi
  call   <space@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x28,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: R)

assistant: ```c
char *add_root(const char *structure) {
  char *xS;
  xS = (char *)space(sizeof(char) * (strlen(structure) + 4));
  xS[0] = '(';
  strcat(xS, structure);
  strcat(xS, "R)");
  return xS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_root>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x4(%rax),%edi
  call   <space@plt>
  mov    %rax,%rbx
  movb   $0x28,(%rax)
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: R)

assistant: ```c
char *add_root(const char *structure) {
  char *xS;
  xS = (char *)space(sizeof(char) * (strlen(structure) + 4));
  xS[0] = '(';
  strcat(xS, structure);
  strcat(xS, "R)");
  return xS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add_root>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x4(%rax),%edi
  call   <space@plt>
  mov    %rbp,%rsi
  movb   $0x28,(%rax)
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D2(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: R)

assistant: ```c
char *add_root(const char *structure) {
  char *xS;
  xS = (char *)space(sizeof(char) * (strlen(structure) + 4));
  xS[0] = '(';
  strcat(xS, structure);
  strcat(xS, "R)");
  return xS;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<add_root>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x4(%rax),%edi
  call   <space@plt>
  mov    %rbp,%rsi
  movb   $0x28,(%rax)
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D7(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string

tool: D7: R)

assistant: ```c
char *add_root(const char *structure) {
  char *xS;
  xS = (char *)space(sizeof(char) * (strlen(structure) + 4));
  xS[0] = '(';
  strcat(xS, structure);
  strcat(xS, "R)");
  return xS;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shr    $0x3,%rax
  or     $0xffffffb5,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L26
L28:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L11
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L15
L11:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    %al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  or     %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
L15:
  addb   $0x2,-0xa(%rbp)
L26:
  cmpb   $0x0,-0xa(%rbp)
  je     L28
  movzbl -0x9(%rbp),%eax
  or     $0xffffffc5,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        state[0UL] = state[local1] << (((state[local1] >> (unsigned char)3) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 745448133UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%eax
  or     $0xb5,%al
  and    $0x6,%ecx
  or     $0x5,%ecx
  sar    %cl,%eax
  mov    %eax,%ecx
  shr    $0x3,%cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  or     $0xffffffc5,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        state[0UL] = state[local1] << (((state[local1] >> (unsigned char)3) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 745448133UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%eax
  and    $0x6,%ecx
  or     $0xb5,%al
  or     $0x5,%ecx
  sar    %cl,%eax
  add    %eax,%eax
  or     $0xffffffc5,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        state[0UL] = state[local1] << (((state[local1] >> (unsigned char)3) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 745448133UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%eax
  and    $0x6,%ecx
  or     $0xb5,%al
  or     $0x5,%ecx
  sar    %cl,%eax
  add    %eax,%eax
  or     $0xffffffc5,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        state[0UL] = state[local1] << (((state[local1] >> (unsigned char)3) & (unsigned char)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] | 745448133UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_data(double *data0, double *data1, int n) {
  int j;
  for (j = 0; j < n; j++) {
    double d = data0[j];
    data0[j] = data1[j];
    data1[j] = d;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap_data>:
  endbr64
  test   %edx,%edx
  jle    L1
  mov    %edx,%edx
  mov    $0x0,%eax
L18:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
L1:
  ret
```

assistant: ```c
void swap_data(double *data0, double *data1, int n) {
  int j;
  for (j = 0; j < n; j++) {
    double d = data0[j];
    data0[j] = data1[j];
    data1[j] = d;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap_data>:
  endbr64
  test   %edx,%edx
  jle    L1
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L4:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L1:
  ret
```

assistant: ```c
void swap_data(double *data0, double *data1, int n) {
  int j;
  for (j = 0; j < n; j++) {
    double d = data0[j];
    data0[j] = data1[j];
    data1[j] = d;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<swap_data>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L36
  lea    0xf(%rdi),%rax
  sub    %rsi,%rax
  cmp    $0x1e,%rax
  jbe    L11
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L11
  mov    %edx,%edi
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  xchg   %ax,%ax
L1:
  movupd (%rcx,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm2
  movups %xmm2,(%rcx,%rax,1)
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L1
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L36
  shl    $0x3,%rax
  add    %rax,%rcx
  add    %rsi,%rax
  movsd  (%rcx),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rcx)
  movsd  %xmm0,(%rax)
  ret
L11:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L35:
  movsd  (%rcx,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L35
L36:
  ret
```

assistant: ```c
void swap_data(double *data0, double *data1, int n) {
  int j;
  for (j = 0; j < n; j++) {
    double d = data0[j];
    data0[j] = data1[j];
    data1[j] = d;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmd_def_prog_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L4
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    $0x0,%eax
  call   <def_prog_mode@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L17
L4:
  nop
L17:
  leave
  ret
```

assistant: ```c
void cmd_def_prog_mode(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(def_prog_mode());
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmd_def_prog_mode>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L8
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    $0x0,%eax
  call   <def_prog_mode@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_def_prog_mode(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(def_prog_mode());
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd_def_prog_mode>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L5
  mov    $0x1,%edi
  call   <report_count@plt>
  xor    %eax,%eax
  call   <def_prog_mode@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_def_prog_mode(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(def_prog_mode());
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmd_def_prog_mode>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L3
  mov    $0x1,%edi
  call   <report_count@plt>
  xor    %eax,%eax
  call   <def_prog_mode@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_def_prog_mode(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(def_prog_mode());
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L30
L25:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <fixDown@plt>
  subl   $0x1,-0x4(%rbp)
L30:
  cmpl   $0x0,-0x4(%rbp)
  jns    L25
  jmp    L3
L39:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  subl   $0x1,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <fixDown@plt>
L3:
  cmpl   $0x1,-0x8(%rbp)
  jg     L39
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapSort(int *a, int l, int r) {
  int size = r - l + 1;
  for (int k = size / 2; k >= 0; k--)
    fixDown(a + l, size, k);
  while (size > 1) {
    swap(a + l, a + l + size - 1);
    fixDown(a + l, --size, 0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<heapSort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%r12d
  sub    %esi,%edx
  lea    0x1(%rdx),%ebx
  mov    %ebx,%ebp
  shr    $0x1f,%ebp
  add    %ebx,%ebp
  sar    %ebp
  cmp    $0xffffffff,%ebx
  jl     L6
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r14
L30:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <fixDown@plt>
  sub    $0x1,%ebp
  jns    L30
L6:
  cmp    $0x1,%ebx
  jle    L37
  movslq %r12d,%rax
  lea    0x0(%r13,%rax,4),%r12
  movslq %ebx,%rdx
  add    %rdx,%rax
  lea    -0x4(%r13,%rax,4),%rbp
L36:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  sub    $0x1,%ebx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <fixDown@plt>
  sub    $0x4,%rbp
  cmp    $0x1,%ebx
  jne    L36
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void heapSort(int *a, int l, int r) {
  int size = r - l + 1;
  for (int k = size / 2; k >= 0; k--)
    fixDown(a + l, size, k);
  while (size > 1) {
    swap(a + l, a + l + size - 1);
    fixDown(a + l, --size, 0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<heapSort>:
  endbr64
  sub    %esi,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdx),%ebx
  mov    %ebx,%ebp
  shr    $0x1f,%ebp
  add    %ebx,%ebp
  sar    %ebp
  cmp    $0xffffffff,%ebx
  jl     L19
  movslq %esi,%r14
  mov    %rdi,%r13
  lea    (%rdi,%r14,4),%r12
  nopl   0x0(%rax)
L39:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <fixDown@plt>
  sub    $0x1,%ebp
  jae    L39
  cmp    $0x1,%ebx
  jle    L19
  movslq %ebx,%rax
  lea    0x0(%r13,%r14,4),%r12
  add    %r14,%rax
  lea    -0x4(%r13,%rax,4),%rbp
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    $0x1,%ebx
  sub    $0x4,%rbp
  call   <swap@plt>
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <fixDown@plt>
  cmp    $0x1,%ebx
  jne    L30
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void heapSort(int *a, int l, int r) {
  int size = r - l + 1;
  for (int k = size / 2; k >= 0; k--)
    fixDown(a + l, size, k);
  while (size > 1) {
    swap(a + l, a + l + size - 1);
    fixDown(a + l, --size, 0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heapSort>:
  endbr64
  sub    %esi,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdx),%ebx
  mov    %ebx,%ebp
  shr    $0x1f,%ebp
  add    %ebx,%ebp
  sar    %ebp
  cmp    $0xffffffff,%ebx
  jl     L13
  movslq %esi,%r14
  mov    %rdi,%r13
  lea    (%rdi,%r14,4),%r12
  nopl   0x0(%rax)
L31:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <fixDown@plt>
  sub    $0x1,%ebp
  jae    L31
  cmp    $0x1,%ebx
  jle    L13
  movslq %ebx,%rax
  lea    0x0(%r13,%r14,4),%r12
  add    %r14,%rax
  lea    -0x4(%r13,%rax,4),%rbp
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    $0x1,%ebx
  sub    $0x4,%rbp
  call   <swap@plt>
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <fixDown@plt>
  cmp    $0x1,%ebx
  jne    L19
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void heapSort(int *a, int l, int r) {
  int size = r - l + 1;
  for (int k = size / 2; k >= 0; k--)
    fixDown(a + l, size, k);
  while (size > 1) {
    swap(a + l, a + l + size - 1);
    fixDown(a + l, --size, 0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xec(%rbp)
  movl   $0x0,-0xe8(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  lea    -0xed(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xed(%rbp),%eax
  cmp    $0x31,%al
  jne    L52
  mov    -0xec(%rbp),%eax
  cltq
  movl   $0x1,-0xe0(%rbp,%rax,4)
  jmp    L45
L52:
  movzbl -0xed(%rbp),%eax
  cmp    $0x30,%al
  jne    L59
  mov    -0xec(%rbp),%eax
  cltq
  movl   $0x0,-0xe0(%rbp,%rax,4)
L45:
  addl   $0x1,-0xec(%rbp)
  jmp    L23
L59:
  nop
  mov    -0xec(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xe4(%rbp)
  jmp    L62
L67:
  mov    -0xe4(%rbp),%eax
  cltq
  mov    -0xe0(%rbp,%rax,4),%ebx
  mov    -0xe4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,-0xe8(%rbp)
  subl   $0x1,-0xe4(%rbp)
L62:
  cmpl   $0x0,-0xe4(%rbp)
  jns    L67
  mov    -0xe8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
type_infered: string
name: read_data
arguments: data_label: D27
type_infered: string
name: read_data
arguments: data_label: D2
type_infered: string

tool: D15: Entre com um binario: 

tool: D27: %c

tool: D2: O decimal eh: %d


assistant: ```c
int main() {
  int bin[50];
  int binSize = 0;
  char binChar;
  int dec = 0;
  printf("Entre com um binario: ");
  while (1) {
    scanf("%c", &binChar);
    if (binChar == '1')
      bin[binSize] = 1;
    else if (binChar == '0')
      bin[binSize] = 0;
    else
      break;
    binSize++;
  }
  int i;
  for (i = binSize - 1; i >= 0; i--) {
    dec += ((int)bin[i] * pow(2, i + 1));
  }
  printf("O decimal eh: %d\n", dec);
  return 0;
}
```