ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<base64_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %rdx,0x8(%rsp)
  test   %esi,%esi
  jle    L21
L58:
  mov    $0x0,%r15d
  test   $0x3,%r13b
  jne    L45
  lea    0x0(%r13,%r13,2),%eax
  lea    0x3(%rax),%edi
  test   %eax,%eax
  cmovns %eax,%edi
  sar    $0x2,%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L52
  mov    %rax,%r12
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  test   %r13d,%r13d
  jle    L70
L80:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <base64_423@plt>
  test   %eax,%eax
  js     L30
  cmp    $0x3,%eax
  jne    L25
  add    $0x4,%rbx
  add    $0x3,%r12
  add    $0x4,%ebp
  add    $0x3,%r14d
  cmp    %ebp,%r13d
  jg     L80
  jmp    L70
L21:
  call   <strlen@plt>
  mov    %eax,%r13d
  jmp    L58
L52:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    D4(%rip),%rdx
  mov    %eax,(%rdx)
  jmp    L45
L30:
  mov    %r15,%rdi
  call   <free@plt>
  mov    $0x0,%r15d
  jmp    L45
L25:
  add    %eax,%r14d
L70:
  cmp    %ebp,%r13d
  je     L145
  sub    $0x4,%r13d
  cmp    %ebp,%r13d
  jne    L8
L145:
  movslq %r14d,%rax
  movb   $0x0,(%r15,%rax,1)
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L45
  mov    %r14d,(%rax)
L45:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    %r15,%rdi
  call   <free@plt>
  mov    $0x0,%r15d
  jmp    L45
```

assistant: ```c
const char *base64_decode(const char *str, int length, int *retlen) {
  int len, i, ret, reslen;
  unsigned char *retval, *pret;
  const char *pstr;
  len = length > 0 ? length : strlen(str);
  if (len % 4 != 0)
    return NULL;
  retval = malloc(len * 3 / 4 + 1);
  if (!retval) {
    errno = -ENOMEM;
    return NULL;
  }
  for (pstr = str, pret = retval, i = 0, reslen = 0; i < len; pstr += 4, pret += 3, i += 4, reslen += 3) {
    ret = base64_423(pstr, pret);
    if (ret < 0) {
      free(retval);
      return NULL;
    } else if (ret != 3) {
      reslen += ret;
      break;
    }
  }
  if (i != len && i != len - 4) {
    free(retval);
    return NULL;
  }
  retval[reslen] = '\0';
  if (retlen) {
    *retlen = reslen;
  }
  return (const char *)retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<base64_decode>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %esi,%esi
  jle    L125
L129:
  xor    %r12d,%r12d
  test   $0x3,%bl
  jne    L108
  lea    (%rbx,%rbx,2),%eax
  test   %eax,%eax
  lea    0x3(%rax),%edi
  cmovns %eax,%edi
  sar    $0x2,%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
  mov    %rax,%r13
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  test   %ebx,%ebx
  jg     L22
  jmp    L91
  nopl   0x0(%rax)
L21:
  cmp    $0x3,%eax
  jne    L76
  add    $0x4,%r15d
  add    $0x4,%r14
  add    $0x3,%r13
  add    $0x3,%ebp
  cmp    %r15d,%ebx
  jle    L91
L22:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <base64_423@plt>
  test   %eax,%eax
  jns    L21
L1:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
L108:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L125:
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L129
  nopl   0x0(%rax)
L91:
  cmp    %r15d,%ebx
  jne    L81
L66:
  movslq %ebp,%rax
  movb   $0x0,(%r12,%rax,1)
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L108
  mov    %ebp,(%rax)
  jmp    L108
  nopl   0x0(%rax,%rax,1)
L76:
  add    %eax,%ebp
L81:
  sub    $0x4,%ebx
  cmp    %r15d,%ebx
  je     L66
  jmp    L1
L27:
  mov    D11(%rip),%rax
  mov    D6(%rip),%rdx
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,(%rdx)
  jmp    L108
```

assistant: ```c
const char *base64_decode(const char *str, int length, int *retlen) {
  int len, i, ret, reslen;
  unsigned char *retval, *pret;
  const char *pstr;
  len = length > 0 ? length : strlen(str);
  if (len % 4 != 0)
    return NULL;
  retval = malloc(len * 3 / 4 + 1);
  if (!retval) {
    errno = -ENOMEM;
    return NULL;
  }
  for (pstr = str, pret = retval, i = 0, reslen = 0; i < len; pstr += 4, pret += 3, i += 4, reslen += 3) {
    ret = base64_423(pstr, pret);
    if (ret < 0) {
      free(retval);
      return NULL;
    } else if (ret != 3) {
      reslen += ret;
      break;
    }
  }
  if (i != len && i != len - 4) {
    free(retval);
    return NULL;
  }
  retval[reslen] = '\0';
  if (retlen) {
    *retlen = reslen;
  }
  return (const char *)retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<base64_decode>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %esi,%esi
  jle    L101
L24:
  xor    %r12d,%r12d
  test   $0x3,%bl
  jne    L61
  lea    (%rbx,%rbx,2),%eax
  test   %eax,%eax
  lea    0x3(%rax),%edi
  cmovns %eax,%edi
  sar    $0x2,%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L138
  mov    %rax,%r13
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  test   %ebx,%ebx
  jg     L122
  jmp    L82
  nopl   0x0(%rax)
L97:
  cmp    $0x3,%eax
  jne    L144
  add    $0x4,%r15d
  add    $0x4,%r14
  add    $0x3,%r13
  add    $0x3,%ebp
  cmp    %r15d,%ebx
  jle    L82
L122:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <base64_423@plt>
  test   %eax,%eax
  jns    L97
L64:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
L61:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L101:
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L24
  nopl   0x0(%rax)
L82:
  cmp    %r15d,%ebx
  jne    L4
L120:
  movslq %ebp,%rax
  movb   $0x0,(%r12,%rax,1)
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L61
  mov    %ebp,(%rax)
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L144:
  add    %eax,%ebp
L4:
  sub    $0x4,%ebx
  cmp    %r15d,%ebx
  je     L120
  jmp    L64
L138:
  mov    D7(%rip),%rax
  mov    D4(%rip),%rdx
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,(%rdx)
  jmp    L61
```

assistant: ```c
const char *base64_decode(const char *str, int length, int *retlen) {
  int len, i, ret, reslen;
  unsigned char *retval, *pret;
  const char *pstr;
  len = length > 0 ? length : strlen(str);
  if (len % 4 != 0)
    return NULL;
  retval = malloc(len * 3 / 4 + 1);
  if (!retval) {
    errno = -ENOMEM;
    return NULL;
  }
  for (pstr = str, pret = retval, i = 0, reslen = 0; i < len; pstr += 4, pret += 3, i += 4, reslen += 3) {
    ret = base64_423(pstr, pret);
    if (ret < 0) {
      free(retval);
      return NULL;
    } else if (ret != 3) {
      reslen += ret;
      break;
    }
  }
  if (i != len && i != len - 4) {
    free(retval);
    return NULL;
  }
  retval[reslen] = '\0';
  if (retlen) {
    *retlen = reslen;
  }
  return (const char *)retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_value_ADS123X>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L4
L5:
  mov    -0x18(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <read_byte_ADS123X@plt>
  or     %rbx,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L4:
  cmpl   $0x3,-0x1c(%rbp)
  jle    L5
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long read_value_ADS123X() {
  long read = 0;
  for (int i = 0; i <= 3; i++)
    read = (read << 8) | read_byte_ADS123X();
  return read;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_value_ADS123X>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4,%ebp
  mov    $0x0,%ebx
L3:
  shl    $0x8,%rbx
  mov    $0x0,%eax
  call   <read_byte_ADS123X@plt>
  or     %rax,%rbx
  sub    $0x1,%ebp
  jne    L3
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long read_value_ADS123X() {
  long read = 0;
  for (int i = 0; i <= 3; i++)
    read = (read << 8) | read_byte_ADS123X();
  return read;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_value_ADS123X>:
  endbr64
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L5:
  xor    %eax,%eax
  shl    $0x8,%rbx
  call   <read_byte_ADS123X@plt>
  or     %rax,%rbx
  sub    $0x1,%ebp
  jne    L5
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long read_value_ADS123X() {
  long read = 0;
  for (int i = 0; i <= 3; i++)
    read = (read << 8) | read_byte_ADS123X();
  return read;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_value_ADS123X>:
  endbr64
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L6:
  xor    %eax,%eax
  shl    $0x8,%rbx
  call   <read_byte_ADS123X@plt>
  or     %rax,%rbx
  sub    $0x1,%ebp
  jne    L6
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long read_value_ADS123X() {
  long read = 0;
  for (int i = 0; i <= 3; i++)
    read = (read << 8) | read_byte_ADS123X();
  return read;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movl   $0x1,-0x20(%rbp)
  jmp    L38
L84:
  mov    -0x20(%rbp),%eax
  shl    $0x2,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  shl    $0x3,%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L11
L86:
  mov    -0x24(%rbp),%eax
  not    %eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L49
L3:
  mov    -0x28(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L78
  movl   $0x50,-0x2c(%rbp)
  addl   $0x1,-0x1c(%rbp)
  jmp    L15
L78:
  movl   $0x4c,-0x2c(%rbp)
  addl   $0x1,-0x18(%rbp)
L15:
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L62
  mov    $0x20,%edi
  call   <putchar@plt>
L62:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  subl   $0x1,-0x28(%rbp)
L49:
  cmpl   $0x0,-0x28(%rbp)
  jns    L3
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L11:
  mov    -0x24(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L86
  addl   $0x1,-0x20(%rbp)
L38:
  cmpl   $0x2,-0x20(%rbp)
  jle    L84
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4:  Pn:%d Ln:%d


assistant: ```c
int main() {
  int bar, c, i, l, p, w, mask, bitl, shift, pn, ln;
  for (w = 1; w <= 2; w++) {
    mask = (1 << 4 * w) - 1;
    shift = 4 * w;
    bitl = (8 * w) - 1;
    for (l = 0; l <= mask; l++) {
      p = (~l) & mask;
      bar = (l << shift) | p;
      pn = ln = 0;
      for (i = bitl; i >= 0; i--) {
        if ((1 << i) & bar) {
          c = 'P';
          pn++;
        } else {
          c = 'L';
          ln++;
        }
        if ((i + 1) % 4 == 0) {
          putchar(' ');
        }
        putchar(c);
      }
      printf(" Pn:%d Ln:%d\n", pn, ln);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r15d
  jmp    L159
L116:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L0
L63:
  add    $0x1,%r13d
  mov    $0x50,%ebp
L137:
  lea    0x1(%rbx),%eax
  test   $0x3,%al
  je     L116
L0:
  mov    %ebp,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L153
L25:
  bt     %ebx,%r12d
  jb     L63
  add    $0x1,%r14d
  mov    $0x4c,%ebp
  jmp    L137
L153:
  mov    %r14d,%edx
  mov    %r13d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r15d
  cmp    $0x10,%r15d
  je     L10
L159:
  mov    %r15d,%r12d
  not    %r12d
  and    $0xf,%r12d
  mov    %r15d,%eax
  shl    $0x4,%eax
  or     %eax,%r12d
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x7,%ebx
  jmp    L25
L10:
  mov    $0x0,%r15d
  jmp    L60
L77:
  add    $0x1,%r14d
  mov    $0x4c,%ebp
L119:
  lea    0x1(%rbx),%eax
  test   $0x3,%al
  je     L121
L123:
  mov    %ebp,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L76
L140:
  bt     %ebx,%r12d
  jae    L77
  add    $0x1,%r13d
  mov    $0x50,%ebp
  jmp    L119
L121:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L123
L76:
  mov    %r14d,%edx
  mov    %r13d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r15d
  cmp    $0x100,%r15d
  je     L131
L60:
  mov    %r15d,%r12d
  not    %r12d
  movzbl %r12b,%r12d
  mov    %r15d,%eax
  shl    $0x8,%eax
  or     %eax,%r12d
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0xf,%ebx
  jmp    L140
L131:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9:  Pn:%d Ln:%d


assistant: ```c
int main() {
  int bar, c, i, l, p, w, mask, bitl, shift, pn, ln;
  for (w = 1; w <= 2; w++) {
    mask = (1 << 4 * w) - 1;
    shift = 4 * w;
    bitl = (8 * w) - 1;
    for (l = 0; l <= mask; l++) {
      p = (~l) & mask;
      bar = (l << shift) | p;
      pn = ln = 0;
      for (i = bitl; i >= 0; i--) {
        if ((1 << i) & bar) {
          c = 'P';
          pn++;
        } else {
          c = 'L';
          ln++;
        }
        if ((i + 1) % 4 == 0) {
          putchar(' ');
        }
        putchar(c);
      }
      printf(" Pn:%d Ln:%d\n", pn, ln);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L79:
  mov    %r15d,%ebp
  mov    %r15d,%eax
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  xor    $0xf,%ebp
  shl    $0x4,%eax
  mov    $0x7,%ebx
  or     %eax,%ebp
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L115:
  lea    0x1(%rbx),%eax
  add    $0x1,%r13d
  mov    $0x50,%r14d
  test   $0x3,%al
  je     L92
L50:
  mov    %r14d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jb     L135
L78:
  bt     %ebx,%ebp
  jb     L115
  lea    0x1(%rbx),%eax
  add    $0x1,%r12d
  mov    $0x4c,%r14d
  test   $0x3,%al
  jne    L50
L92:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %r14d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L78
L135:
  mov    %r12d,%edx
  mov    %r13d,%esi
  lea    D8(%rip),%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    $0x10,%r15d
  jne    L79
  xor    %r15d,%r15d
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %r15d,%ebp
  mov    %r15d,%eax
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  xor    $0xff,%bpl
  shl    $0x8,%eax
  mov    $0xf,%ebx
  or     %eax,%ebp
  jmp    L72
  nopl   0x0(%rax)
L103:
  lea    0x1(%rbx),%eax
  add    $0x1,%r13d
  mov    $0x50,%r14d
  test   $0x3,%al
  je     L1
L109:
  mov    %r14d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jb     L100
L72:
  bt     %ebx,%ebp
  jb     L103
  lea    0x1(%rbx),%eax
  add    $0x1,%r12d
  mov    $0x4c,%r14d
  test   $0x3,%al
  jne    L109
L1:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %r14d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L72
L100:
  mov    %r12d,%edx
  mov    %r13d,%esi
  lea    D8(%rip),%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    $0x100,%r15d
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8:  Pn:%d Ln:%d


assistant: ```c
int main() {
  int bar, c, i, l, p, w, mask, bitl, shift, pn, ln;
  for (w = 1; w <= 2; w++) {
    mask = (1 << 4 * w) - 1;
    shift = 4 * w;
    bitl = (8 * w) - 1;
    for (l = 0; l <= mask; l++) {
      p = (~l) & mask;
      bar = (l << shift) | p;
      pn = ln = 0;
      for (i = bitl; i >= 0; i--) {
        if ((1 << i) & bar) {
          c = 'P';
          pn++;
        } else {
          c = 'L';
          ln++;
        }
        if ((i + 1) % 4 == 0) {
          putchar(' ');
        }
        putchar(c);
      }
      printf(" Pn:%d Ln:%d\n", pn, ln);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L81:
  mov    %r15d,%ebp
  mov    %r15d,%eax
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  xor    $0xf,%ebp
  shl    $0x4,%eax
  mov    $0x7,%ebx
  or     %eax,%ebp
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L11:
  lea    0x1(%rbx),%eax
  add    $0x1,%r13d
  mov    $0x50,%r14d
  test   $0x3,%al
  je     L118
L89:
  mov    %r14d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jb     L59
L94:
  bt     %ebx,%ebp
  jb     L11
  lea    0x1(%rbx),%eax
  add    $0x1,%r12d
  mov    $0x4c,%r14d
  test   $0x3,%al
  jne    L89
L118:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %r14d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L94
L59:
  mov    %r12d,%edx
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    $0x10,%r15d
  jne    L81
  xor    %r15d,%r15d
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    %r15d,%ebp
  mov    %r15d,%eax
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  xor    $0xff,%bpl
  shl    $0x8,%eax
  mov    $0xf,%ebx
  or     %eax,%ebp
  jmp    L9
  nopl   0x0(%rax)
L74:
  lea    0x1(%rbx),%eax
  add    $0x1,%r13d
  mov    $0x50,%r14d
  test   $0x3,%al
  je     L131
L84:
  mov    %r14d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jb     L60
L9:
  bt     %ebx,%ebp
  jb     L74
  lea    0x1(%rbx),%eax
  add    $0x1,%r12d
  mov    $0x4c,%r14d
  test   $0x3,%al
  jne    L84
L131:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %r14d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L9
L60:
  mov    %r12d,%edx
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    $0x100,%r15d
  jne    L57
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1:  Pn:%d Ln:%d


assistant: ```c
int main() {
  int bar, c, i, l, p, w, mask, bitl, shift, pn, ln;
  for (w = 1; w <= 2; w++) {
    mask = (1 << 4 * w) - 1;
    shift = 4 * w;
    bitl = (8 * w) - 1;
    for (l = 0; l <= mask; l++) {
      p = (~l) & mask;
      bar = (l << shift) | p;
      pn = ln = 0;
      for (i = bitl; i >= 0; i--) {
        if ((1 << i) & bar) {
          c = 'P';
          pn++;
        } else {
          c = 'L';
          ln++;
        }
        if ((i + 1) % 4 == 0) {
          putchar(' ');
        }
        putchar(c);
      }
      printf(" Pn:%d Ln:%d\n", pn, ln);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%r8
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0xc(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  add    $0x10,%rsp
  mov    -0x14(%rbp),%eax
  mov    -0x1c(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    -0x20(%rbp),%ecx
  sub    %ecx,%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    -0x1c(%rbp),%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%eax
  mov    -0x20(%rbp),%esi
  sub    %esi,%eax
  imul   %ecx,%eax
  cmp    %eax,%edx
  jne    L8
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L23
L8:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D24
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: string

tool: D24: %d%d%d%d%d%d

tool: D29: Yes

tool: D27: No

assistant: ```c
int main() {
  int x1, y1, x2, y2, x3, y3;
  scanf("%d%d%d%d%d%d", &x1, &y1, &x2, &y2, &x3, &y3);
  if ((y2 - y1) * (x3 - x1) == (y3 - y1) * (x2 - x1))
    printf("Yes");
  else
    printf("No");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  sub    0x14(%rsp),%edx
  mov    0x20(%rsp),%eax
  sub    0x10(%rsp),%eax
  imul   %eax,%edx
  mov    0x24(%rsp),%eax
  sub    0x14(%rsp),%eax
  mov    0x18(%rsp),%ecx
  sub    0x10(%rsp),%ecx
  imul   %ecx,%eax
  add    $0x10,%rsp
  cmp    %eax,%edx
  je     L29
  lea    D27(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L29:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D11: %d%d%d%d%d%d

tool: D27: No

tool: D5: Yes

assistant: ```c
int main() {
  int x1, y1, x2, y2, x3, y3;
  scanf("%d%d%d%d%d%d", &x1, &y1, &x2, &y2, &x3, &y3);
  if ((y2 - y1) * (x3 - x1) == (y3 - y1) * (x2 - x1))
    printf("Yes");
  else
    printf("No");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  mov    0x20(%rsp),%eax
  sub    0x14(%rsp),%edx
  sub    0x10(%rsp),%eax
  mov    0x18(%rsp),%ecx
  imul   %eax,%edx
  sub    0x10(%rsp),%ecx
  mov    0x24(%rsp),%eax
  sub    0x14(%rsp),%eax
  imul   %ecx,%eax
  pop    %rcx
  pop    %rsi
  cmp    %eax,%edx
  je     L21
  lea    D13(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L21:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D13
datatype: string
name: read_data
arguments: label: D1
datatype: string

tool: D26: %d%d%d%d%d%d

tool: D13: No

tool: D1: Yes

assistant: ```c
int main() {
  int x1, y1, x2, y2, x3, y3;
  scanf("%d%d%d%d%d%d", &x1, &y1, &x2, &y2, &x3, &y3);
  if ((y2 - y1) * (x3 - x1) == (y3 - y1) * (x2 - x1))
    printf("Yes");
  else
    printf("No");
  return 0;
}
```