user: 这段汇编代码用C语言表示是什么样的？

```asm
<redirecting_number_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %ecx,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x78(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  movzbl %al,%eax
  and    $0x1,%eax
  mov    %eax,-0x54(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x78(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  movzbl %al,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x7,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  lea    D18(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  shr    $0x2,%al
  movzbl %al,%eax
  and    $0x3,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x78(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x3,%eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x70(%rbp),%eax
  lea    -0x2(%rax),%edi
  mov    -0x78(%rbp),%rax
  lea    0x2(%rax),%rsi
  mov    -0x54(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <isup_get_number@plt>
  lea    -0x50(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  lea    D48(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ss7_message@plt>
  mov    -0x70(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D18
type_guessed: string
name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string
name: disassemble_data
arguments: data_tag: D48
type_guessed: string

tool: D10: 			Nature of address: %x


tool: D9: 			NI: %x


tool: D18: 			Numbering plan: %x


tool: D7: 			Presentation: %x


tool: D6: 			Screening: %x


tool: D48: 			Address signals: %s


assistant: ```c
int((redirecting_number_dump))(struct ss7 *ss7, int messagetype, unsigned char *parm, int len) {
  int oddeven = (parm[0] >> 7) & 0x1;
  char numbuf[64] = "";
  ss7_message(ss7, "\t\t\tNature of address: %x\n", parm[0] & 0x7f);
  ss7_message(ss7, "\t\t\tNI: %x\n", (parm[1] >> 7) & 0x1);
  ss7_message(ss7, "\t\t\tNumbering plan: %x\n", (parm[1] >> 4) & 0x7);
  ss7_message(ss7, "\t\t\tPresentation: %x\n", (parm[1] >> 2) & 0x3);
  ss7_message(ss7, "\t\t\tScreening: %x\n", parm[1] & 0x3);
  isup_get_number(numbuf, &parm[2], len - 2, oddeven);
  ss7_message(ss7, "\t\t\tAddress signals: %s\n", numbuf);
  return len;
}
```