ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<nibble_sort_word_ref>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x0,%r13d
  lea    0x8(%rsp),%r15
  jmp    L37
L11:
  mov    %r13d,%esi
  mov    0x8(%rsp),%rdi
  call   <read_nibble@plt>
  mov    %eax,%ebx
  mov    %r12d,%esi
  mov    0x8(%rsp),%rdi
  call   <read_nibble@plt>
  mov    %eax,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  call   <write_nibble@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <write_nibble@plt>
L39:
  mov    %r14d,%r13d
L37:
  lea    0x1(%r13),%r14d
  cmp    $0xf,%r14d
  jg     L3
  mov    %r14d,%ebx
  mov    %r13d,%r12d
L0:
  mov    %ebx,%esi
  mov    0x8(%rsp),%rdi
  call   <read_nibble@plt>
  mov    %eax,%ebp
  mov    %r12d,%esi
  mov    0x8(%rsp),%rdi
  call   <read_nibble@plt>
  cmp    %eax,%ebp
  cmovl  %ebx,%r12d
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L0
  cmp    %r13d,%r12d
  jne    L11
  jmp    L39
L3:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long nibble_sort_word_ref(unsigned long arg) {
  for (int i = 0; i < 16; ++i) {
    int min = i;
    for (int j = i + 1; j < 16; ++j) {
      if (read_nibble(arg, j) < read_nibble(arg, min))
        min = j;
    }
    if (min != i) {
      int tmp = read_nibble(arg, i);
      write_nibble(&arg, i, read_nibble(arg, min));
      write_nibble(&arg, min, tmp);
    }
  }
  return arg;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<nibble_sort_word_ref>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    0x1(%r13),%r14d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%r15
  cmp    $0xf,%r13d
  je     L33
  nopl   (%rax)
L31:
  mov    %r14d,%ebx
  mov    %r13d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    %ebx,%esi
  call   <read_nibble@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12d,%esi
  mov    %eax,%ebp
  call   <read_nibble@plt>
  mov    0x8(%rsp),%rdi
  cmp    %eax,%ebp
  cmovl  %ebx,%r12d
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L20
  cmp    %r13d,%r12d
  je     L12
  mov    %r13d,%esi
  call   <read_nibble@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12d,%esi
  mov    %eax,%ebx
  call   <read_nibble@plt>
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    %eax,%edx
  call   <write_nibble@plt>
  mov    %r15,%rdi
  mov    %ebx,%edx
  mov    %r12d,%esi
  call   <write_nibble@plt>
  mov    0x8(%rsp),%rdi
L12:
  mov    %r14d,%r13d
  lea    0x1(%r13),%r14d
  cmp    $0xf,%r13d
  jne    L31
L33:
  add    $0x18,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long nibble_sort_word_ref(unsigned long arg) {
  for (int i = 0; i < 16; ++i) {
    int min = i;
    for (int j = i + 1; j < 16; ++j) {
      if (read_nibble(arg, j) < read_nibble(arg, min))
        min = j;
    }
    if (min != i) {
      int tmp = read_nibble(arg, i);
      write_nibble(&arg, i, read_nibble(arg, min));
      write_nibble(&arg, min, tmp);
    }
  }
  return arg;
}
```
user: What is the c source code of the assembly code below:

```asm
<nibble_sort_word_ref>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    0x1(%r13),%r14d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%r15
  cmp    $0xf,%r13d
  je     L21
  nopl   (%rax)
L36:
  mov    %r14d,%ebx
  mov    %r13d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %ebx,%esi
  call   <read_nibble@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12d,%esi
  mov    %eax,%ebp
  call   <read_nibble@plt>
  mov    0x8(%rsp),%rdi
  cmp    %eax,%ebp
  cmovl  %ebx,%r12d
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L16
  cmp    %r13d,%r12d
  je     L1
  mov    %r13d,%esi
  call   <read_nibble@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12d,%esi
  mov    %eax,%ebx
  call   <read_nibble@plt>
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    %eax,%edx
  call   <write_nibble@plt>
  mov    %r15,%rdi
  mov    %ebx,%edx
  mov    %r12d,%esi
  call   <write_nibble@plt>
  mov    0x8(%rsp),%rdi
L1:
  mov    %r14d,%r13d
  lea    0x1(%r13),%r14d
  cmp    $0xf,%r13d
  jne    L36
L21:
  add    $0x18,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long nibble_sort_word_ref(unsigned long arg) {
  for (int i = 0; i < 16; ++i) {
    int min = i;
    for (int j = i + 1; j < 16; ++j) {
      if (read_nibble(arg, j) < read_nibble(arg, min))
        min = j;
    }
    if (min != i) {
      int tmp = read_nibble(arg, i);
      write_nibble(&arg, i, read_nibble(arg, min));
      write_nibble(&arg, min, tmp);
    }
  }
  return arg;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  test   %eax,%eax
  jle    L40
  lea    0x10(%rsp),%rbx
  lea    -0x1(%rax),%eax
  lea    0x14(%rsp,%rax,4),%r12
  lea    D0(%rip),%r13
  lea    D26(%rip),%rbp
  jmp    L86
  mov    $0x41,%edi
  call   <putchar@plt>
L77:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L40
L86:
  mov    (%rbx),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x5,%eax
  ja     L85
  mov    %eax,%eax
  movslq 0x0(%rbp,%rax,4),%rax
  add    %rbp,%rax
  notrack jmp *%rax
  mov    $0x42,%edi
  call   <putchar@plt>
  jmp    L77
  mov    $0x43,%edi
  call   <putchar@plt>
  jmp    L77
  mov    $0x44,%edi
  call   <putchar@plt>
  jmp    L77
  mov    $0x45,%edi
  call   <putchar@plt>
  jmp    L77
  mov    $0x46,%edi
  call   <putchar@plt>
  jmp    L77
L85:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L77
L40:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L92:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: %d

assistant: ```c
int main() {
  int input;
  int count = 0, hex[10], i, rev, temp;
  scanf("%d", &input);
  for (; count != i / 2; input++) {
    temp = input;
    for (count = 0; temp > 0; count++) {
      hex[count] = temp % 16;
      temp /= 16;
    }
    i = count;
    rev = i - 1;
    for (count = 0; count < i / 2; count++, rev--) {
      if (hex[count] != hex[rev]) {
        break;
      }
    }
  }
  for (count = 0; count < i; count++) {
    switch (hex[count]) {
    case 10:
      printf("A");
      break;
    case 11:
      printf("B");
      break;
    case 12:
      printf("C");
      break;
    case 13:
      printf("D");
      break;
    case 14:
      printf("E");
      break;
    case 15:
      printf("F");
      break;
    default:
      printf("%d", hex[count]);
      break;
    }
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  test   %eax,%eax
  je     L49
  sub    $0x1,%eax
  lea    0x10(%rsp),%rbx
  lea    D6(%rip),%r13
  lea    0x14(%rsp,%rax,4),%rbp
  nopl   0x0(%rax)
L5:
  mov    (%rbx),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x5,%eax
  ja     L1
  movslq 0x0(%r13,%rax,4),%rax
  add    %r13,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  mov    $0x45,%edi
  call   <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L62:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L5
L49:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  mov    $0x44,%edi
  call   <putchar@plt>
  jmp    L62
  nopl   0x0(%rax)
  mov    $0x43,%edi
  call   <putchar@plt>
  jmp    L62
  nopl   0x0(%rax)
  mov    $0x42,%edi
  call   <putchar@plt>
  jmp    L62
  nopl   0x0(%rax)
  mov    $0x41,%edi
  call   <putchar@plt>
  jmp    L62
  nopl   0x0(%rax)
  mov    $0x46,%edi
  call   <putchar@plt>
  jmp    L62
L1:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L62
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: %d

assistant: ```c
int main() {
  int input;
  int count = 0, hex[10], i, rev, temp;
  scanf("%d", &input);
  for (; count != i / 2; input++) {
    temp = input;
    for (count = 0; temp > 0; count++) {
      hex[count] = temp % 16;
      temp /= 16;
    }
    i = count;
    rev = i - 1;
    for (count = 0; count < i / 2; count++, rev--) {
      if (hex[count] != hex[rev]) {
        break;
      }
    }
  }
  for (count = 0; count < i; count++) {
    switch (hex[count]) {
    case 10:
      printf("A");
      break;
    case 11:
      printf("B");
      break;
    case 12:
      printf("C");
      break;
    case 13:
      printf("D");
      break;
    case 14:
      printf("E");
      break;
    case 15:
      printf("F");
      break;
    default:
      printf("%d", hex[count]);
      break;
    }
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  test   %eax,%eax
  je     L74
  sub    $0x1,%eax
  lea    0x10(%rsp),%rbx
  lea    D0(%rip),%r13
  lea    0x14(%rsp,%rax,4),%rbp
  nopl   0x0(%rax)
L41:
  mov    (%rbx),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x5,%eax
  ja     L88
  movslq 0x0(%r13,%rax,4),%rax
  add    %r13,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  mov    $0x45,%edi
  call   <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L73:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L41
L74:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  mov    $0x44,%edi
  call   <putchar@plt>
  jmp    L73
  nopl   0x0(%rax)
  mov    $0x43,%edi
  call   <putchar@plt>
  jmp    L73
  nopl   0x0(%rax)
  mov    $0x42,%edi
  call   <putchar@plt>
  jmp    L73
  nopl   0x0(%rax)
  mov    $0x41,%edi
  call   <putchar@plt>
  jmp    L73
  nopl   0x0(%rax)
  mov    $0x46,%edi
  call   <putchar@plt>
  jmp    L73
L88:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L73
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
datatype: string

tool: D16: %d

assistant: ```c
int main() {
  int input;
  int count = 0, hex[10], i, rev, temp;
  scanf("%d", &input);
  for (; count != i / 2; input++) {
    temp = input;
    for (count = 0; temp > 0; count++) {
      hex[count] = temp % 16;
      temp /= 16;
    }
    i = count;
    rev = i - 1;
    for (count = 0; count < i / 2; count++, rev--) {
      if (hex[count] != hex[rev]) {
        break;
      }
    }
  }
  for (count = 0; count < i; count++) {
    switch (hex[count]) {
    case 10:
      printf("A");
      break;
    case 11:
      printf("B");
      break;
    case 12:
      printf("C");
      break;
    case 13:
      printf("D");
      break;
    case 14:
      printf("E");
      break;
    case 15:
      printf("F");
      break;
    default:
      printf("%d", hex[count]);
      break;
    }
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<writeHexAmountBE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x7,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    $0x20,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    $0x28,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    $0x30,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    $0x38,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void writeHexAmountBE(int64_t amount, unsigned char *buffer) {
  *(buffer + 7) = (amount & 0xff);
  *(buffer + 6) = ((amount >> 8) & 0xff);
  *(buffer + 5) = ((amount >> 16) & 0xff);
  *(buffer + 4) = ((amount >> 24) & 0xff);
  *(buffer + 3) = ((amount >> 32) & 0xff);
  *(buffer + 2) = ((amount >> 40) & 0xff);
  *(buffer + 1) = ((amount >> 48) & 0xff);
  *(buffer) = ((amount >> 56) & 0xff);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<writeHexAmountBE>:
  endbr64
  mov    %edi,%eax
  mov    %dil,0x7(%rsi)
  movzbl %ah,%ecx
  mov    %cl,0x6(%rsi)
  mov    %edi,%edx
  sar    $0x10,%edx
  mov    %dl,0x5(%rsi)
  mov    %edi,%edx
  shr    $0x18,%edx
  mov    %dl,0x4(%rsi)
  mov    %edi,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  mov    %dl,0x3(%rsi)
  mov    %edi,%edx
  mov    $0x28,%ecx
  sar    %cl,%edx
  mov    %dl,0x2(%rsi)
  mov    %edi,%edx
  mov    $0x30,%ecx
  sar    %cl,%edx
  mov    %dl,0x1(%rsi)
  mov    $0x38,%ecx
  sar    %cl,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void writeHexAmountBE(int64_t amount, unsigned char *buffer) {
  *(buffer + 7) = (amount & 0xff);
  *(buffer + 6) = ((amount >> 8) & 0xff);
  *(buffer + 5) = ((amount >> 16) & 0xff);
  *(buffer + 4) = ((amount >> 24) & 0xff);
  *(buffer + 3) = ((amount >> 32) & 0xff);
  *(buffer + 2) = ((amount >> 40) & 0xff);
  *(buffer + 1) = ((amount >> 48) & 0xff);
  *(buffer) = ((amount >> 56) & 0xff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<writeHexAmountBE>:
  endbr64
  mov    %edi,%eax
  mov    $0x20,%ecx
  bswap  %eax
  mov    %eax,0x4(%rsi)
  mov    %edi,%eax
  sar    %cl,%eax
  mov    $0x28,%ecx
  mov    %al,0x3(%rsi)
  mov    %edi,%eax
  sar    %cl,%eax
  mov    $0x30,%ecx
  mov    %al,0x2(%rsi)
  mov    %edi,%eax
  sar    %cl,%eax
  mov    $0x38,%ecx
  sar    %cl,%edi
  mov    %al,0x1(%rsi)
  mov    %dil,(%rsi)
  ret
```

assistant: ```c
void writeHexAmountBE(int64_t amount, unsigned char *buffer) {
  *(buffer + 7) = (amount & 0xff);
  *(buffer + 6) = ((amount >> 8) & 0xff);
  *(buffer + 5) = ((amount >> 16) & 0xff);
  *(buffer + 4) = ((amount >> 24) & 0xff);
  *(buffer + 3) = ((amount >> 32) & 0xff);
  *(buffer + 2) = ((amount >> 40) & 0xff);
  *(buffer + 1) = ((amount >> 48) & 0xff);
  *(buffer) = ((amount >> 56) & 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<writeHexAmountBE>:
  endbr64
  mov    %edi,%edx
  mov    $0x38,%ecx
  mov    %edi,%eax
  push   %r14
  sar    %cl,%edx
  mov    $0x30,%ecx
  push   %rbx
  mov    %edi,%ebx
  sar    %cl,%eax
  sar    $0x8,%ebx
  mov    %edi,%r8d
  mov    %edi,%r9d
  mov    %eax,%r14d
  movzbl %dil,%eax
  mov    %edi,%r10d
  mov    %edi,%r11d
  shl    $0x8,%rax
  movzbl %bl,%edi
  sar    $0x10,%r11d
  mov    $0x28,%ecx
  or     %rdi,%rax
  movzbl %r11b,%edi
  shr    $0x18,%r10d
  movzbl %dl,%edx
  shl    $0x8,%rax
  sar    %cl,%r8d
  mov    $0x20,%ecx
  pop    %rbx
  or     %rdi,%rax
  movzbl %r10b,%edi
  sar    %cl,%r9d
  movzbl %r14b,%ecx
  shl    $0x8,%rax
  pop    %r14
  or     %rdi,%rax
  movzbl %r9b,%edi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl %r8b,%edi
  shl    $0x8,%rax
  or     %rdi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void writeHexAmountBE(int64_t amount, unsigned char *buffer) {
  *(buffer + 7) = (amount & 0xff);
  *(buffer + 6) = ((amount >> 8) & 0xff);
  *(buffer + 5) = ((amount >> 16) & 0xff);
  *(buffer + 4) = ((amount >> 24) & 0xff);
  *(buffer + 3) = ((amount >> 32) & 0xff);
  *(buffer + 2) = ((amount >> 40) & 0xff);
  *(buffer + 1) = ((amount >> 48) & 0xff);
  *(buffer) = ((amount >> 56) & 0xff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_strdel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_memdel@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void ft_strdel(char **as) {
  if (as)
    ft_memdel((void **)as);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strdel>:
  endbr64
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  call   <ft_memdel@plt>
  add    $0x8,%rsp
  ret
L1:
  ret
```

assistant: ```c
void ft_strdel(char **as) {
  if (as)
    ft_memdel((void **)as);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strdel>:
  endbr64
  test   %rdi,%rdi
  je     L9
  jmp    1050 <ft_memdel@plt>
  xchg   %ax,%ax
L9:
  ret
```

assistant: ```c
void ft_strdel(char **as) {
  if (as)
    ft_memdel((void **)as);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strdel>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <ft_memdel@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void ft_strdel(char **as) {
  if (as)
    ft_memdel((void **)as);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dbgHashMake>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L4:
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  shr    $0x7,%eax
  and    $0x1,%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%esi
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%esi
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  andl   $0xff,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D28: %d hash int %d, hex 0x%x


tool: D0: final value hash %d 0x%x


assistant: ```c
unsigned dbgHashMake(const char *Name) {
  unsigned hash = 0;
  int i = 0;
  while (*Name) {
    hash = (hash << 1) | (1 & (hash >> (8 - 1)));
    printf("%d hash int %d, hex 0x%x\n", i++, hash, hash);
    hash ^= *Name++;
    printf("%d hash int %d, hex 0x%x\n", i++, hash, hash);
  }
  hash &= ((1 << 8) - 1);
  printf("final value hash %d 0x%x\n", hash, hash);
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dbgHashMake>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L15
  mov    %rdi,%r12
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  lea    D0(%rip),%r14
L26:
  lea    (%rbx,%rbx,1),%ebp
  shr    $0x7,%ebx
  and    $0x1,%ebx
  or     %ebx,%ebp
  mov    %ebp,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r12
  movsbl -0x1(%r12),%ebx
  xor    %ebp,%ebx
  mov    %r13d,%esi
  add    $0x2,%r13d
  add    $0x1,%esi
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpb   $0x0,(%r12)
  jne    L26
L28:
  movzbl %bl,%ebx
  mov    %ebx,%edx
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0x0,%ebx
  jmp    L28
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D5
type: string

tool: D0: %d hash int %d, hex 0x%x


tool: D5: final value hash %d 0x%x


assistant: ```c
unsigned dbgHashMake(const char *Name) {
  unsigned hash = 0;
  int i = 0;
  while (*Name) {
    hash = (hash << 1) | (1 & (hash >> (8 - 1)));
    printf("%d hash int %d, hex 0x%x\n", i++, hash, hash);
    hash ^= *Name++;
    printf("%d hash int %d, hex 0x%x\n", i++, hash, hash);
  }
  hash &= ((1 << 8) - 1);
  printf("final value hash %d 0x%x\n", hash, hash);
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<dbgHashMake>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L12
  mov    %rdi,%r12
  xor    %r14d,%r14d
  lea    D10(%rip),%rbp
  xor    %ebx,%ebx
L19:
  lea    (%rbx,%rbx,1),%r13d
  shr    $0x7,%ebx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  and    $0x1,%ebx
  xor    %eax,%eax
  add    $0x1,%r12
  or     %ebx,%r13d
  mov    %r13d,%ecx
  mov    %r13d,%edx
  call   <printf@plt>
  movsbl -0x1(%r12),%ebx
  mov    %r14d,%esi
  xor    %eax,%eax
  add    $0x1,%esi
  mov    %rbp,%rdi
  add    $0x2,%r14d
  xor    %r13d,%ebx
  mov    %ebx,%ecx
  mov    %ebx,%edx
  call   <printf@plt>
  cmpb   $0x0,(%r12)
  jne    L19
  movzbl %bl,%r12d
L10:
  mov    %r12d,%edx
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  xor    %r12d,%r12d
  jmp    L10
```

tool_calls: name: read_data
arguments: tag: D10
type: string
name: read_data
arguments: tag: D6
type: string

tool: D10: %d hash int %d, hex 0x%x


tool: D6: final value hash %d 0x%x


assistant: ```c
unsigned dbgHashMake(const char *Name) {
  unsigned hash = 0;
  int i = 0;
  while (*Name) {
    hash = (hash << 1) | (1 & (hash >> (8 - 1)));
    printf("%d hash int %d, hex 0x%x\n", i++, hash, hash);
    hash ^= *Name++;
    printf("%d hash int %d, hex 0x%x\n", i++, hash, hash);
  }
  hash &= ((1 << 8) - 1);
  printf("final value hash %d 0x%x\n", hash, hash);
  return hash;
}
```