ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  movslq %ebp,%rbp
  add    %r12,%rbp
  jmp    L1
  nopl   (%rax)
L15:
  movzbl (%r12,%rbx,1),%eax
  movzbl 0x0(%rbp),%edx
  sub    $0x1,%rbp
  mov    %dl,(%r12,%rbx,1)
  add    $0x1,%rbx
  mov    %al,0x1(%rbp)
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L15
  pop    %rbx
  mov    %r12,%rsi
  lea    D3(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: the reversed string is = %s

assistant: ```c
void reverse(char s[]) {
  char temp;
  int i, len;
  len = strlen(s) - 1;
  for (i = 0; i < strlen(s) / 2; i++) {
    temp = s[i];
    s[i] = s[len];
    s[len] = temp;
    len--;
  }
  printf("the reversed string is = %s", s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  movslq %ebp,%rbp
  add    %r12,%rbp
  jmp    L5
  nopl   (%rax)
L17:
  movzbl (%r12,%rbx,1),%eax
  movzbl 0x0(%rbp),%edx
  sub    $0x1,%rbp
  mov    %dl,(%r12,%rbx,1)
  add    $0x1,%rbx
  mov    %al,0x1(%rbp)
L5:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L17
  pop    %rbx
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: the reversed string is = %s

assistant: ```c
void reverse(char s[]) {
  char temp;
  int i, len;
  len = strlen(s) - 1;
  for (i = 0; i < strlen(s) / 2; i++) {
    temp = s[i];
    s[i] = s[len];
    s[len] = temp;
    len--;
  }
  printf("the reversed string is = %s", s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x2a,%eax
  mov    $0x29,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2a,-0x4(%rbp)
  je     L2
  call   <abort@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int f = 0;
  asm("{movl $42, %%eax | mov eax, 42}" : :);
  asm("{movl $41, %0||mov %0, 43}" : "=r"(f));
  if (f != 42)
    abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  mov    $0x29,%eax
  cmp    $0x2a,%eax
  jne    L4
  mov    $0x0,%eax
  ret
L4:
  sub    $0x8,%rsp
  call   <abort@plt>
```

assistant: ```c
int main(void) {
  int f = 0;
  asm("{movl $42, %%eax | mov eax, 42}" : :);
  asm("{movl $41, %0||mov %0, 43}" : "=r"(f));
  if (f != 42)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  mov    $0x29,%eax
  cmp    $0x2a,%eax
  jne    1060 <main.cold>
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int f = 0;
  asm("{movl $42, %%eax | mov eax, 42}" : :);
  asm("{movl $41, %0||mov %0, 43}" : "=r"(f));
  if (f != 42)
    abort();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  mov    $0x29,%eax
  cmp    $0x2a,%eax
  jne    1060 <main.cold>
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int f = 0;
  asm("{movl $42, %%eax | mov eax, 42}" : :);
  asm("{movl $41, %0||mov %0, 43}" : "=r"(f));
  if (f != 42)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tickTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type: string

tool: D2: hello %lld


assistant: ```c
int tickTest(struct aeEventLoop *eventLoop, long long id, void *clientData) {
  ((void)eventLoop);
  ((void)clientData);
  printf("hello %lld\n", id);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tickTest>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: hello %lld


assistant: ```c
int tickTest(struct aeEventLoop *eventLoop, long long id, void *clientData) {
  ((void)eventLoop);
  ((void)clientData);
  printf("hello %lld\n", id);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tickTest>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string

tool: D1: hello %lld


assistant: ```c
int tickTest(struct aeEventLoop *eventLoop, long long id, void *clientData) {
  ((void)eventLoop);
  ((void)clientData);
  printf("hello %lld\n", id);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tickTest>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: hello %lld


assistant: ```c
int tickTest(struct aeEventLoop *eventLoop, long long id, void *clientData) {
  ((void)eventLoop);
  ((void)clientData);
  printf("hello %lld\n", id);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%r8
  movzwl (%rdi),%eax
  lea    0x7296(%rax),%edx
  mov    %edx,%eax
  cmpw   $0x0,0x2(%rdi)
  je     L28
  test   %dx,%dx
  je     L27
  mov    %edx,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%dx
  mov    %edx,%ecx
  shr    $0x2,%cx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %edx,%eax
  rol    %cl,%ax
L16:
  test   %ax,%ax
  je     L28
  movzwl %ax,%edx
  imul   %edx,%edx
  shl    $0x4,%edx
  and    $0x3f0,%dx
  or     %edx,%eax
L28:
  imul   $0x274,%ax,%ax
  mov    %ax,(%r8)
  ret
L27:
  movsbl %dh,%ecx
  mov    %cl,%al
  mov    %dl,%ah
  movzwl %ax,%edi
  mov    %eax,%esi
  shr    $0x2,%si
  and    $0xe,%esi
  or     $0x1,%esi
  mov    $0x10,%ecx
  sub    %esi,%ecx
  mov    %edi,%edx
  sar    %cl,%edx
  mov    %esi,%ecx
  shl    %cl,%edi
  or     %edi,%edx
  shl    $0x4,%edx
  and    $0x3f0,%dx
  or     %edx,%eax
  jmp    L16
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = (state[local1] >> ((state[local1] & (unsigned short)15) | 1UL)) | (state[local1] << (16 - ((state[local1] & (unsigned short)15) | 1UL)));
        state[0UL] = (state[local1] << (((state[local1] >> (unsigned short)2) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[local1] >> (unsigned short)2) & (unsigned short)15) | 1UL)));
      } else {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        state[local1] |= (((state[local1] << (((state[0UL] >> (unsigned short)2) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[0UL] >> (unsigned short)2) & (unsigned short)15) | 1UL)))) & (unsigned short)63) << 4UL;
      }
      if (state[0UL] == local1) {
        state[local1] |= ((state[local1] + state[local1]) & (unsigned short)15) << 2UL;
      } else {
        state[local1] |= (state[local1] * state[local1] & (unsigned short)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 1062470260UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  cmpw   $0x0,0x2(%rdi)
  je     L15
  test   %ax,%ax
  je     L18
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%ax
  mov    %eax,%ecx
  shr    $0x2,%cx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%ax
L18:
  movzwl %ax,%edx
  test   %ax,%ax
  je     L15
  imul   %edx,%edx
  shl    $0x4,%edx
  and    $0x3f0,%dx
  or     %edx,%eax
L15:
  imul   $0x274,%ax,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = (state[local1] >> ((state[local1] & (unsigned short)15) | 1UL)) | (state[local1] << (16 - ((state[local1] & (unsigned short)15) | 1UL)));
        state[0UL] = (state[local1] << (((state[local1] >> (unsigned short)2) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[local1] >> (unsigned short)2) & (unsigned short)15) | 1UL)));
      } else {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        state[local1] |= (((state[local1] << (((state[0UL] >> (unsigned short)2) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[0UL] >> (unsigned short)2) & (unsigned short)15) | 1UL)))) & (unsigned short)63) << 4UL;
      }
      if (state[0UL] == local1) {
        state[local1] |= ((state[local1] + state[local1]) & (unsigned short)15) << 2UL;
      } else {
        state[local1] |= (state[local1] * state[local1] & (unsigned short)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 1062470260UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  cmpw   $0x0,0x2(%rdi)
  je     L3
  test   %ax,%ax
  jne    L26
L3:
  imul   $0x274,%ax,%ax
  mov    %ax,(%rsi)
  ret
L26:
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%ax
  mov    %eax,%ecx
  shr    $0x2,%cx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%ax
  movzwl %ax,%edx
  test   %ax,%ax
  je     L3
  imul   %edx,%edx
  shl    $0x4,%edx
  and    $0x3f0,%dx
  or     %edx,%eax
  imul   $0x274,%ax,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = (state[local1] >> ((state[local1] & (unsigned short)15) | 1UL)) | (state[local1] << (16 - ((state[local1] & (unsigned short)15) | 1UL)));
        state[0UL] = (state[local1] << (((state[local1] >> (unsigned short)2) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[local1] >> (unsigned short)2) & (unsigned short)15) | 1UL)));
      } else {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        state[local1] |= (((state[local1] << (((state[0UL] >> (unsigned short)2) & (unsigned short)15) | 1UL)) | (state[local1] >> (16 - (((state[0UL] >> (unsigned short)2) & (unsigned short)15) | 1UL)))) & (unsigned short)63) << 4UL;
      }
      if (state[0UL] == local1) {
        state[local1] |= ((state[local1] + state[local1]) & (unsigned short)15) << 2UL;
      } else {
        state[local1] |= (state[local1] * state[local1] & (unsigned short)63) << 4UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 1062470260UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rectangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L26
L5:
  movl   $0x1,-0xc(%rbp)
  jmp    L38
L4:
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L4
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L5
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D20
type: string
name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D41
type: string
name: parse_data
arguments: tag: D25
type: string

tool: D20: ===============================================


tool: D12: rectangle!
 Please input length and width:


tool: D29: (Type-in format as:length,width)


tool: D2: %d, %d

tool: D41: *

tool: D25: 


assistant: ```c
void rectangle() {
  int length, width;
  int row, colume;
  printf("===============================================\n");
  printf("rectangle!\n Please input length and width:\n");
  printf("(Type-in format as:length,width)\n");
  scanf("%d, %d", &length, &width);
  for (row = 1; row <= width; row++) {
    for (colume = 1; colume <= length; colume++) {
      printf("*");
    }
    printf("\n");
  }
  printf("===============================================\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rectangle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D49(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%r12d
  lea    D17(%rip),%rbp
  lea    D46(%rip),%r13
  cmpl   $0x0,0x4(%rsp)
  jg     L27
L39:
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L26
L19:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jl     L39
L27:
  mov    $0x1,%ebx
  cmpl   $0x0,(%rsp)
  jg     L26
  jmp    L19
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D64
type: string
name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D68
type: string
name: read_data
arguments: data_tag: D49
type: string
name: read_data
arguments: data_tag: D17
type: string
name: read_data
arguments: data_tag: D46
type: string

tool: D64: ===============================================


tool: D30: rectangle!
 Please input length and width:


tool: D68: (Type-in format as:length,width)


tool: D49: %d, %d

tool: D17: *

tool: D46: 


assistant: ```c
void rectangle() {
  int length, width;
  int row, colume;
  printf("===============================================\n");
  printf("rectangle!\n Please input length and width:\n");
  printf("(Type-in format as:length,width)\n");
  scanf("%d, %d", &length, &width);
  for (row = 1; row <= width; row++) {
    for (colume = 1; colume <= length; colume++) {
      printf("*");
    }
    printf("\n");
  }
  printf("===============================================\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rectangle>:
  endbr64
  push   %r14
  lea    D34(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  lea    D48(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L9
  nopw   0x0(%rax,%rax,1)
L49:
  mov    (%rsp),%eax
  mov    $0x1,%ebx
  test   %eax,%eax
  jle    L21
  nopl   0x0(%rax)
L11:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L11
L21:
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jge    L49
L9:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D34
type_guessed: string
name: unpack_data
arguments: label: D48
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string
name: unpack_data
arguments: label: D36
type_guessed: string

tool: D34: ===============================================


tool: D48: 


tool: D15: *

tool: D17: rectangle!
 Please input length and width:


tool: D14: (Type-in format as:length,width)


tool: D36: %d, %d

assistant: ```c
void rectangle() {
  int length, width;
  int row, colume;
  printf("===============================================\n");
  printf("rectangle!\n Please input length and width:\n");
  printf("(Type-in format as:length,width)\n");
  scanf("%d, %d", &length, &width);
  for (row = 1; row <= width; row++) {
    for (colume = 1; colume <= length; colume++) {
      printf("*");
    }
    printf("\n");
  }
  printf("===============================================\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<rectangle>:
  endbr64
  push   %r14
  lea    D48(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  lea    D1(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L23
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rsp),%eax
  mov    $0x1,%ebx
  test   %eax,%eax
  jle    L7
  nopl   0x0(%rax)
L19:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L19
L7:
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jge    L26
L23:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D48
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string
name: extract_symbolic_data
arguments: data_label: D26
data_type: string
name: extract_symbolic_data
arguments: data_label: D36
data_type: string
name: extract_symbolic_data
arguments: data_label: D50
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D48: ===============================================


tool: D1: 


tool: D26: *

tool: D36: rectangle!
 Please input length and width:


tool: D50: (Type-in format as:length,width)


tool: D8: %d, %d

assistant: ```c
void rectangle() {
  int length, width;
  int row, colume;
  printf("===============================================\n");
  printf("rectangle!\n Please input length and width:\n");
  printf("(Type-in format as:length,width)\n");
  scanf("%d, %d", &length, &width);
  for (row = 1; row <= width; row++) {
    for (colume = 1; colume <= length; colume++) {
      printf("*");
    }
    printf("\n");
  }
  printf("===============================================\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<test02>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  mov    $0x0,%eax
  call   <foo@plt>
L4:
  mov    $0x0,%eax
  call   <foo@plt>
  nop
  leave
  ret
```

assistant: ```c
void test02(int flag) {
  if (flag)
    foo();
  foo();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test02>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L12
L16:
  mov    $0x0,%eax
  call   <foo@plt>
  add    $0x8,%rsp
  ret
L12:
  mov    $0x0,%eax
  call   <foo@plt>
  jmp    L16
```

assistant: ```c
void test02(int flag) {
  if (flag)
    foo();
  foo();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test02>:
  endbr64
  test   %edi,%edi
  jne    L5
  xor    %eax,%eax
  jmp    1050 <foo@plt>
  nop
L5:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <foo@plt>
```

assistant: ```c
void test02(int flag) {
  if (flag)
    foo();
  foo();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test02>:
  endbr64
  test   %edi,%edi
  jne    L4
  xor    %eax,%eax
  jmp    1050 <foo@plt>
  nop
L4:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <foo@plt>
```

assistant: ```c
void test02(int flag) {
  if (flag)
    foo();
  foo();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_block_used>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    $0x80,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x1(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_block_used(unsigned char *block_bitmap, int blocknum) {
  unsigned char bm;
  bm = block_bitmap[blocknum / 8];
  bm |= (0x80 >> (blocknum % 8));
  block_bitmap[blocknum / 8] = bm;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_block_used>:
  endbr64
  mov    %esi,%ecx
  lea    0x7(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x3,%eax
  cltq
  and    $0x7,%ecx
  mov    $0x80,%edx
  sar    %cl,%edx
  or     %dl,(%rdi,%rax,1)
  ret
```

assistant: ```c
void set_block_used(unsigned char *block_bitmap, int blocknum) {
  unsigned char bm;
  bm = block_bitmap[blocknum / 8];
  bm |= (0x80 >> (blocknum % 8));
  block_bitmap[blocknum / 8] = bm;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<set_block_used>:
  endbr64
  test   %esi,%esi
  lea    0x7(%rsi),%eax
  mov    %esi,%ecx
  mov    $0x80,%edx
  cmovns %esi,%eax
  and    $0x7,%ecx
  sar    %cl,%edx
  sar    $0x3,%eax
  cltq
  or     %dl,(%rdi,%rax,1)
  ret
```

assistant: ```c
void set_block_used(unsigned char *block_bitmap, int blocknum) {
  unsigned char bm;
  bm = block_bitmap[blocknum / 8];
  bm |= (0x80 >> (blocknum % 8));
  block_bitmap[blocknum / 8] = bm;
}
```