ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<menu_help_get_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    -0x38(%rbp),%rax
  jmp    L32
L16:
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  jns    L79
  movl   $0x0,-0x30(%rbp)
L79:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L55
L6:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L19
L77:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L44
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x38(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
L44:
  subl   $0x1,-0x30(%rbp)
L55:
  cmpl   $0x0,-0x30(%rbp)
  jg     L6
L19:
  movq   $0x46,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  cmovle %rdx,%rax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rcx
  lea    D9(%rip),%rdx
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  lea    D21(%rip),%rax
L32:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string

tool: D9: %s

assistant: ```c
char *menu_help_get_line(const char *help, int line) {
  char *p = strchr(help, '\n');
  if (!p)
    return (char *)help;
  static char buf[70];
  int i = line;
  if (i < 0)
    i = 0;
  char *start = (char *)help;
  char *end = p;
  while (i > 0) {
    if (*end == 0) {
      start = (char *)help;
      end = p;
      break;
    }
    start = end + 1;
    end = strchr(start + 1, '\n');
    if (!end)
      end = (char *)help + strlen(help);
    i--;
  }
  int len = ({
    __typeof__(((int)sizeof(buf)) + (end - start + 1)) _a = ((int)sizeof(buf));
    __typeof__(((int)sizeof(buf)) + (end - start + 1)) _b = (end - start + 1);
    _a < _b ? _a : _b;
  });
  snprintf(buf, len, "%s", start);
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<menu_help_get_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%r13
  test   %ebp,%ebp
  mov    $0x0,%ebx
  cmovns %ebp,%ebx
  jle    L69
  mov    %rax,%rbp
  jmp    L79
L34:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L77
  mov    %rax,%rbp
L79:
  cmpb   $0x0,0x0(%rbp)
  je     L69
  lea    0x2(%rbp),%rdi
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L34
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %r12,%rax
  jmp    L34
L77:
  lea    0x1(%rbp),%r12
  mov    %rax,%r13
L69:
  sub    %r12,%r13
  add    $0x1,%r13
  mov    $0x46,%eax
  cmp    %rax,%r13
  cmovg  %rax,%r13
  movslq %r13d,%rsi
  mov    %r12,%rcx
  lea    D12(%rip),%rdx
  lea    D10(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %r12,%rax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    %r12,%rax
  jmp    L31
```

tool_calls: name: unpack_data
arguments: data_tag: D12
datatype: string

tool: D12: %s

assistant: ```c
char *menu_help_get_line(const char *help, int line) {
  char *p = strchr(help, '\n');
  if (!p)
    return (char *)help;
  static char buf[70];
  int i = line;
  if (i < 0)
    i = 0;
  char *start = (char *)help;
  char *end = p;
  while (i > 0) {
    if (*end == 0) {
      start = (char *)help;
      end = p;
      break;
    }
    start = end + 1;
    end = strchr(start + 1, '\n');
    if (!end)
      end = (char *)help + strlen(help);
    i--;
  }
  int len = ({
    __typeof__(((int)sizeof(buf)) + (end - start + 1)) _a = ((int)sizeof(buf));
    __typeof__(((int)sizeof(buf)) + (end - start + 1)) _b = (end - start + 1);
    _a < _b ? _a : _b;
  });
  snprintf(buf, len, "%s", start);
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<menu_help_get_line>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0xa,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L28
  xor    %ebx,%ebx
  test   %r13d,%r13d
  mov    %rax,%rbp
  cmovns %r13d,%ebx
  jle    L49
  mov    %rax,%r13
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L42:
  sub    $0x1,%ebx
  je     L51
L35:
  mov    %rax,%r13
L56:
  cmpb   $0x0,0x0(%r13)
  je     L49
  lea    0x2(%r13),%rdi
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L42
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %r12,%rax
  sub    $0x1,%ebx
  jne    L35
L51:
  lea    0x1(%r13),%r12
  mov    %rax,%rbp
L49:
  sub    %r12,%rbp
  mov    $0x46,%eax
  mov    %r12,%rcx
  add    $0x1,%rbp
  lea    D12(%rip),%r12
  lea    D1(%rip),%rdx
  cmp    %rax,%rbp
  mov    %r12,%rdi
  cmovg  %rax,%rbp
  xor    %eax,%eax
  movslq %ebp,%rsi
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: %s

assistant: ```c
char *menu_help_get_line(const char *help, int line) {
  char *p = strchr(help, '\n');
  if (!p)
    return (char *)help;
  static char buf[70];
  int i = line;
  if (i < 0)
    i = 0;
  char *start = (char *)help;
  char *end = p;
  while (i > 0) {
    if (*end == 0) {
      start = (char *)help;
      end = p;
      break;
    }
    start = end + 1;
    end = strchr(start + 1, '\n');
    if (!end)
      end = (char *)help + strlen(help);
    i--;
  }
  int len = ({
    __typeof__(((int)sizeof(buf)) + (end - start + 1)) _a = ((int)sizeof(buf));
    __typeof__(((int)sizeof(buf)) + (end - start + 1)) _b = (end - start + 1);
    _a < _b ? _a : _b;
  });
  snprintf(buf, len, "%s", start);
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<menu_help_get_line>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0xa,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L23
  xor    %ebx,%ebx
  test   %r13d,%r13d
  mov    %rax,%rbp
  cmovns %r13d,%ebx
  jle    L62
  mov    %rax,%r13
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L56:
  sub    $0x1,%ebx
  je     L64
L19:
  mov    %rax,%r13
L57:
  cmpb   $0x0,0x0(%r13)
  je     L62
  lea    0x2(%r13),%rdi
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L56
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %r12,%rax
  sub    $0x1,%ebx
  jne    L19
L64:
  lea    0x1(%r13),%r12
  mov    %rax,%rbp
L62:
  sub    %r12,%rbp
  mov    $0x46,%eax
  mov    %r12,%rcx
  add    $0x1,%rbp
  lea    D10(%rip),%r12
  lea    D17(%rip),%rdx
  cmp    %rax,%rbp
  mov    %r12,%rdi
  cmovg  %rax,%rbp
  xor    %eax,%eax
  movslq %ebp,%rsi
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D17
datatype: string

tool: D17: %s

assistant: ```c
char *menu_help_get_line(const char *help, int line) {
  char *p = strchr(help, '\n');
  if (!p)
    return (char *)help;
  static char buf[70];
  int i = line;
  if (i < 0)
    i = 0;
  char *start = (char *)help;
  char *end = p;
  while (i > 0) {
    if (*end == 0) {
      start = (char *)help;
      end = p;
      break;
    }
    start = end + 1;
    end = strchr(start + 1, '\n');
    if (!end)
      end = (char *)help + strlen(help);
    i--;
  }
  int len = ({
    __typeof__(((int)sizeof(buf)) + (end - start + 1)) _a = ((int)sizeof(buf));
    __typeof__(((int)sizeof(buf)) + (end - start + 1)) _b = (end - start + 1);
    _a < _b ? _a : _b;
  });
  snprintf(buf, len, "%s", start);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<deltat_longterm_morrison_stephenson>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D43(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  D18(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D52(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  D46(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D48(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D43
type: f64
name: unpack_data
arguments: data_label: D18
type: f64
name: unpack_data
arguments: data_label: D52
type: f64
name: unpack_data
arguments: data_label: D46
type: f64
name: unpack_data
arguments: data_label: D4
type: f64
name: unpack_data
arguments: data_label: D48
type: byte[8]
name: unpack_data
arguments: data_label: D9
type: byte[8]

tool: D43: 2451545

tool: D18: 365.2425

tool: D52: 2000

tool: D46: 1820

tool: D4: 100

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

assistant: ```c
double deltat_longterm_morrison_stephenson(double tjd) {
  double Ygreg = 2000.0 + (tjd - 2451545.0) / 365.2425;
  double u = (Ygreg - 1820) / 100.0;
  return (-20 + 32 * u * u);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deltat_longterm_morrison_stephenson>:
  endbr64
  subsd  D2(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  D52(%rip),%xmm1
  addsd  D51(%rip),%xmm1
  subsd  D19(%rip),%xmm1
  divsd  D30(%rip),%xmm1
  movapd %xmm1,%xmm0
  mulsd  D54(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  subsd  D29(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: f64
name: read_data
arguments: tag: D52
type_infered: f64
name: read_data
arguments: tag: D51
type_infered: f64
name: read_data
arguments: tag: D19
type_infered: f64
name: read_data
arguments: tag: D30
type_infered: f64
name: read_data
arguments: tag: D54
type_infered: byte[8]
name: read_data
arguments: tag: D29
type_infered: byte[8]

tool: D2: 2451545

tool: D52: 365.2425

tool: D51: 2000

tool: D19: 1820

tool: D30: 100

tool: {"D54": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

assistant: ```c
double deltat_longterm_morrison_stephenson(double tjd) {
  double Ygreg = 2000.0 + (tjd - 2451545.0) / 365.2425;
  double u = (Ygreg - 1820) / 100.0;
  return (-20 + 32 * u * u);
}
```
user: Translate the below assembly code into C programming language:

```asm
<deltat_longterm_morrison_stephenson>:
  endbr64
  subsd  D9(%rip),%xmm0
  movapd %xmm0,%xmm1
  movsd  D53(%rip),%xmm0
  divsd  D68(%rip),%xmm1
  addsd  D38(%rip),%xmm1
  subsd  D11(%rip),%xmm1
  divsd  D34(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  D41(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: f64
name: unpack_data
arguments: data_label: D53
data_type: byte[8]
name: unpack_data
arguments: data_label: D68
data_type: f64
name: unpack_data
arguments: data_label: D38
data_type: f64
name: unpack_data
arguments: data_label: D11
data_type: f64
name: unpack_data
arguments: data_label: D34
data_type: f64
name: unpack_data
arguments: data_label: D41
data_type: byte[8]

tool: D9: 2451545

tool: {"D53": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: D68: 365.2425

tool: D38: 2000

tool: D11: 1820

tool: D34: 100

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

assistant: ```c
double deltat_longterm_morrison_stephenson(double tjd) {
  double Ygreg = 2000.0 + (tjd - 2451545.0) / 365.2425;
  double u = (Ygreg - 1820) / 100.0;
  return (-20 + 32 * u * u);
}
```
user: What is the c source code of the assembly code below?

```asm
<deltat_longterm_morrison_stephenson>:
  endbr64
  subsd  D33(%rip),%xmm0
  movapd %xmm0,%xmm1
  movsd  D38(%rip),%xmm0
  divsd  D39(%rip),%xmm1
  addsd  D27(%rip),%xmm1
  subsd  D13(%rip),%xmm1
  divsd  D34(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  D35(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D33
data_type: f64
name: disassemble_data
arguments: tag: D38
data_type: byte[8]
name: disassemble_data
arguments: tag: D39
data_type: f64
name: disassemble_data
arguments: tag: D27
data_type: f64
name: disassemble_data
arguments: tag: D13
data_type: f64
name: disassemble_data
arguments: tag: D34
data_type: f64
name: disassemble_data
arguments: tag: D35
data_type: byte[8]

tool: D33: 2451545

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: D39: 365.2425

tool: D27: 2000

tool: D13: 1820

tool: D34: 100

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

assistant: ```c
double deltat_longterm_morrison_stephenson(double tjd) {
  double Ygreg = 2000.0 + (tjd - 2451545.0) / 365.2425;
  double u = (Ygreg - 1820) / 100.0;
  return (-20 + 32 * u * u);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<val_t_tilde>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <log@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: byte[8]
name: read_data
arguments: data_label: D9
type_guessed: byte[8]

tool: {"D15": [0x55,0x55,0x55,0x55,0x55,0x55,0xe5,0xbf]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double val_t_tilde(double r) {
  double r_sq = sqrt(r);
  return -2. / 3. * pow(r_sq, 3) - 2 * r_sq + 2 * log(1 + r_sq);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<val_t_tilde>:
  endbr64
  sub    $0x18,%rsp
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L11
  sqrtsd %xmm0,%xmm0
  movsd  %xmm0,0x8(%rsp)
L6:
  mov    $0x3,%edi
  movsd  0x8(%rsp),%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D10(%rip),%xmm0
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  addsd  D13(%rip),%xmm2
  cvttsd2si %xmm2,%edi
  call   <log@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
L11:
  call   <sqrt@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L6
```

tool_calls: name: parse_data
arguments: tag: D10
datatype: byte[8]
name: parse_data
arguments: tag: D13
datatype: byte[8]

tool: {"D10": [0x55,0x55,0x55,0x55,0x55,0x55,0xe5,0xbf]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double val_t_tilde(double r) {
  double r_sq = sqrt(r);
  return -2. / 3. * pow(r_sq, 3) - 2 * r_sq + 2 * log(1 + r_sq);
}
```
user: What is the c source code of the assembly code below:

```asm
<val_t_tilde>:
  endbr64
  pxor   %xmm1,%xmm1
  sub    $0x18,%rsp
  ucomisd %xmm0,%xmm1
  ja     L10
  sqrtsd %xmm0,%xmm0
L16:
  mov    $0x3,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  D17(%rip),%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  addsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <log@plt>
  pxor   %xmm0,%xmm0
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
L10:
  call   <sqrt@plt>
  jmp    L16
```

tool_calls: name: read_data
arguments: tag: D17
type_infered: byte[8]
name: read_data
arguments: tag: D6
type_infered: byte[8]

tool: {"D17": [0x55,0x55,0x55,0x55,0x55,0x55,0xe5,0xbf]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double val_t_tilde(double r) {
  double r_sq = sqrt(r);
  return -2. / 3. * pow(r_sq, 3) - 2 * r_sq + 2 * log(1 + r_sq);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<val_t_tilde>:
  endbr64
  pxor   %xmm1,%xmm1
  sub    $0x18,%rsp
  ucomisd %xmm0,%xmm1
  ja     L3
  sqrtsd %xmm0,%xmm0
L5:
  mov    $0x3,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  D12(%rip),%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  addsd  D13(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <log@plt>
  pxor   %xmm0,%xmm0
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
L3:
  call   <sqrt@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D13
data_type: byte[8]

tool: {"D12": [0x55,0x55,0x55,0x55,0x55,0x55,0xe5,0xbf]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double val_t_tilde(double r) {
  double r_sq = sqrt(r);
  return -2. / 3. * pow(r_sq, 3) - 2 * r_sq + 2 * log(1 + r_sq);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x31,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bar(int **aa) {
  *aa = *aa + 1;
  *aa -= 1;
  **aa = 49;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  mov    (%rdi),%rax
  movl   $0x31,(%rax)
  ret
```

assistant: ```c
void bar(int **aa) {
  *aa = *aa + 1;
  *aa -= 1;
  **aa = 49;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bar>:
  endbr64
  mov    (%rdi),%rax
  movl   $0x31,(%rax)
  ret
```

assistant: ```c
void bar(int **aa) {
  *aa = *aa + 1;
  *aa -= 1;
  **aa = 49;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L15
  mov    $0x1,%eax
  jmp    L16
L15:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fact>
  imul   -0x4(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
int fact(int n) {
  if (n <= 1)
    return 1;
  else
    return n * fact(n - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jg     L4
  ret
L4:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fact>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fact(int n) {
  if (n <= 1)
    return 1;
  else
    return n * fact(n - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L19
  xchg   %ax,%ax
L10:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L10
L19:
  ret
```

assistant: ```c
int fact(int n) {
  if (n <= 1)
    return 1;
  else
    return n * fact(n - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L19
  xchg   %ax,%ax
L18:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L18
L19:
  ret
```

assistant: ```c
int fact(int n) {
  if (n <= 1)
    return 1;
  else
    return n * fact(n - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matrix_multiplication>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L48:
  movl   $0x0,-0x8(%rbp)
  jmp    L54
L51:
  mov    -0x8(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L39:
  mov    -0x8(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L39
  addl   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jl     L51
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L48
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int matrix_multiplication(double *output, double *A, double *B, int row_a, int col_a, int row_b, int col_b) {
  int i, j, k;
  for (i = 0; i < row_a; i++) {
    for (j = 0; j < col_b; j++) {
      output[i + j * row_a] = 0;
      for (k = 0; k < col_a; k++) {
        output[i + j * row_a] = output[i + j * row_a] + (A[i + k * row_a] * B[k + j * row_b]);
      }
    }
  }
  return 0;
}
```