ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_dmvec_trid_axpy_backward>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edx,%r15d
  lea    -0x1(%r9),%eax
  mov    %eax,%edx
  imul   %r8d,%edx
  imul   %ecx,%eax
  cltq
  lea    (%rdi,%rax,8),%rbx
  test   %r9d,%r9d
  jle    L1
  mov    %ecx,%r13d
  mov    %r9d,%r14d
  movslq %edx,%rdx
  movslq %ecx,%rax
  shl    $0x3,%rax
  mov    %rax,0x8(%rsp)
  neg    %rax
  mov    %rax,0x10(%rsp)
  movslq %r8d,%r8
  shl    $0x3,%r8
  mov    $0xfffffffffffffff8,%rax
  sub    %r8,%rax
  mov    %rax,0x18(%rsp)
  movslq %r9d,%rax
  add    %rdx,%rax
  lea    (%rsi,%rax,8),%r12
  mov    $0x0,%ebp
  jmp    L40
L33:
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  add    0x10(%rsp),%rbx
  add    $0x1,%ebp
  add    0x18(%rsp),%r12
  cmp    %r14d,%ebp
  je     L1
L40:
  mov    0x8(%rsp),%rax
  lea    (%rbx,%rax,1),%rdi
  mov    %ebp,%r9d
  mov    D15(%rip),%rax
  movq   %rax,%xmm0
  mov    %r13d,%r8d
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %r13d,%esi
  call   <_inner_vec_daxpy@plt>
  movsd  (%rbx),%xmm0
  movsd  D15(%rip),%xmm1
  test   %r15d,%r15d
  jne    L33
  movsd  -0x8(%r12),%xmm1
  jmp    L33
L1:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
type: f64

tool: D15: 1

assistant: ```c
void _dmvec_trid_axpy_backward(double *Xc, const double *Ac, int unit, int incX, int ldA, int nRE) {
  register int i;
  register double *xr, xtmp;
  register const double *Ar, *Acl;
  Acl = Ac + (nRE - 1) * ldA;
  xr = Xc + (nRE - 1) * incX;
  for (i = nRE; i > 0; i--) {
    Ar = Acl + i - 1;
    _inner_vec_daxpy(xr + incX, incX, Ar + 1, xr, incX, 1.0, nRE - i);
    xr[0] *= unit ? 1.0 : Ar[0];
    xr -= incX;
    Acl -= ldA;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_dmvec_trid_axpy_backward>:
  endbr64
  push   %r15
  lea    -0x1(%r9),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,(%rsp)
  mov    %eax,%edx
  imul   %ecx,%eax
  mov    %r9d,0x4(%rsp)
  imul   %r8d,%edx
  cltq
  lea    (%rdi,%rax,8),%rbx
  movslq %r9d,%rax
  test   %eax,%eax
  jle    L11
  movslq %ecx,%r12
  mov    %rsi,%rdi
  movslq %edx,%rdx
  movslq %r8d,%r8
  shl    $0x3,%r12
  shl    $0x3,%r8
  add    %rdx,%rax
  xor    %r15d,%r15d
  mov    %r12,%rsi
  mov    $0xfffffffffffffff8,%r14
  lea    (%rdi,%rax,8),%r13
  neg    %rsi
  sub    %r8,%r14
  mov    %rsi,0x8(%rsp)
  nopl   (%rax)
L10:
  mov    D5(%rip),%rax
  lea    (%rbx,%r12,1),%rdi
  mov    %r15d,%r9d
  mov    %ebp,%esi
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    %r13,%rdx
  movq   %rax,%xmm0
  call   <_inner_vec_daxpy@plt>
  mov    (%rsp),%eax
  movsd  (%rbx),%xmm0
  test   %eax,%eax
  jne    L1
  mulsd  -0x8(%r13),%xmm0
L1:
  movsd  %xmm0,(%rbx)
  add    $0x1,%r15d
  add    0x8(%rsp),%rbx
  add    %r14,%r13
  cmp    0x4(%rsp),%r15d
  jne    L10
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: f64

tool: D5: 1

assistant: ```c
void _dmvec_trid_axpy_backward(double *Xc, const double *Ac, int unit, int incX, int ldA, int nRE) {
  register int i;
  register double *xr, xtmp;
  register const double *Ar, *Acl;
  Acl = Ac + (nRE - 1) * ldA;
  xr = Xc + (nRE - 1) * incX;
  for (i = nRE; i > 0; i--) {
    Ar = Acl + i - 1;
    _inner_vec_daxpy(xr + incX, incX, Ar + 1, xr, incX, 1.0, nRE - i);
    xr[0] *= unit ? 1.0 : Ar[0];
    xr -= incX;
    Acl -= ldA;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_dmvec_trid_axpy_backward>:
  endbr64
  lea    -0x1(%r9),%eax
  push   %r15
  mov    %ecx,%r15d
  mov    %eax,%ecx
  imul   %r15d,%eax
  push   %r14
  imul   %r8d,%ecx
  push   %r13
  push   %r12
  push   %rbp
  cltq
  push   %rbx
  movslq %ecx,%rcx
  lea    (%rdi,%rax,8),%rbx
  lea    (%rsi,%rcx,8),%rcx
  sub    $0x28,%rsp
  test   %r9d,%r9d
  jle    L5
  movslq %r15d,%r12
  movslq %r8d,%r8
  mov    $0xfffffffffffffff8,%r14
  movslq %r9d,%rax
  shl    $0x3,%r12
  shl    $0x3,%r8
  mov    %r9d,%ebp
  mov    %r12,%r13
  sub    %r8,%r14
  neg    %r13
  test   %edx,%edx
  mov    %r14,0x18(%rsp)
  lea    (%rcx,%rax,8),%rdx
  mov    $0x0,%r14d
  je     L32
  movsd  D0(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
  xchg   %ax,%ax
L11:
  movsd  0x8(%rsp),%xmm0
  lea    (%rbx,%r12,1),%rdi
  mov    %r14d,%r9d
  mov    %rbx,%rcx
  mov    %r15d,%r8d
  mov    %r15d,%esi
  add    $0x1,%r14d
  mov    %rdx,0x10(%rsp)
  call   <_inner_vec_daxpy@plt>
  add    %r13,%rbx
  mov    0x10(%rsp),%rdx
  add    0x18(%rsp),%rdx
  cmp    %ebp,%r14d
  jne    L11
L5:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L32:
  movsd  D0(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L20:
  movsd  0x8(%rsp),%xmm0
  lea    (%rbx,%r12,1),%rdi
  mov    %r14d,%r9d
  mov    %rbx,%rcx
  mov    %r15d,%r8d
  mov    %r15d,%esi
  mov    %rdx,0x10(%rsp)
  add    $0x1,%r14d
  call   <_inner_vec_daxpy@plt>
  mov    0x10(%rsp),%rdx
  movsd  (%rbx),%xmm0
  mulsd  -0x8(%rdx),%xmm0
  add    0x18(%rsp),%rdx
  movsd  %xmm0,(%rbx)
  add    %r13,%rbx
  cmp    %ebp,%r14d
  jne    L20
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: f64

tool: D0: 1

assistant: ```c
void _dmvec_trid_axpy_backward(double *Xc, const double *Ac, int unit, int incX, int ldA, int nRE) {
  register int i;
  register double *xr, xtmp;
  register const double *Ar, *Acl;
  Acl = Ac + (nRE - 1) * ldA;
  xr = Xc + (nRE - 1) * incX;
  for (i = nRE; i > 0; i--) {
    Ar = Acl + i - 1;
    _inner_vec_daxpy(xr + incX, incX, Ar + 1, xr, incX, 1.0, nRE - i);
    xr[0] *= unit ? 1.0 : Ar[0];
    xr -= incX;
    Acl -= ldA;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffffffea,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: %d


assistant: ```c
int main(void) {
  printf("%d\n", 15 - 37);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffea,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int main(void) {
  printf("%d\n", 15 - 37);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffea,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: %d


assistant: ```c
int main(void) {
  printf("%d\n", 15 - 37);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffea,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(void) {
  printf("%d\n", 15 - 37);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<philo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
L8:
  mov    $0x0,%eax
  call   <think@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <take_fork@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <take_fork@plt>
  mov    $0x0,%eax
  call   <eat@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <put_fork@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <put_fork@plt>
  jmp    L8
```

assistant: ```c
void philo(int i) {
  while (1) {
    think();
    take_fork(i);
    take_fork((i + 1) % 5);
    eat();
    put_fork(i);
    put_fork((i + 1) % 5);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<philo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  lea    0x1(%rdi),%eax
  movslq %eax,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x21,%rbx
  cltd
  sub    %edx,%ebx
  lea    (%rbx,%rbx,4),%edx
  sub    %edx,%eax
  mov    %eax,%ebx
L1:
  mov    $0x0,%eax
  call   <think@plt>
  mov    %ebp,%edi
  call   <take_fork@plt>
  mov    %ebx,%edi
  call   <take_fork@plt>
  mov    $0x0,%eax
  call   <eat@plt>
  mov    %ebp,%edi
  call   <put_fork@plt>
  mov    %ebx,%edi
  call   <put_fork@plt>
  jmp    L1
```

assistant: ```c
void philo(int i) {
  while (1) {
    think();
    take_fork(i);
    take_fork((i + 1) % 5);
    eat();
    put_fork(i);
    put_fork((i + 1) % 5);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<philo>:
  endbr64
  lea    0x1(%rdi),%eax
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  movslq %eax,%rbx
  cltd
  imul   $0x66666667,%rbx,%rbx
  sub    $0x8,%rsp
  sar    $0x21,%rbx
  sub    %edx,%ebx
  lea    (%rbx,%rbx,4),%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <think@plt>
  mov    %ebp,%edi
  call   <take_fork@plt>
  mov    %ebx,%edi
  call   <take_fork@plt>
  xor    %eax,%eax
  call   <eat@plt>
  mov    %ebp,%edi
  call   <put_fork@plt>
  mov    %ebx,%edi
  call   <put_fork@plt>
  jmp    L5
```

assistant: ```c
void philo(int i) {
  while (1) {
    think();
    take_fork(i);
    take_fork((i + 1) % 5);
    eat();
    put_fork(i);
    put_fork((i + 1) % 5);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<philo>:
  endbr64
  lea    0x1(%rdi),%eax
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  movslq %eax,%rbx
  cltd
  imul   $0x66666667,%rbx,%rbx
  sub    $0x8,%rsp
  sar    $0x21,%rbx
  sub    %edx,%ebx
  lea    (%rbx,%rbx,4),%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <think@plt>
  mov    %ebp,%edi
  call   <take_fork@plt>
  mov    %ebx,%edi
  call   <take_fork@plt>
  xor    %eax,%eax
  call   <eat@plt>
  mov    %ebp,%edi
  call   <put_fork@plt>
  mov    %ebx,%edi
  call   <put_fork@plt>
  jmp    L5
```

assistant: ```c
void philo(int i) {
  while (1) {
    think();
    take_fork(i);
    take_fork((i + 1) % 5);
    eat();
    put_fork(i);
    put_fork((i + 1) % 5);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stringcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L7:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stringcpy(char *s, char *t) {
  while (((*s++) = (*t++)) != '\0')
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stringcpy>:
  endbr64
  mov    $0x0,%eax
L9:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L9
  ret
```

assistant: ```c
void stringcpy(char *s, char *t) {
  while (((*s++) = (*t++)) != '\0')
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<stringcpy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L2
  ret
```

assistant: ```c
void stringcpy(char *s, char *t) {
  while (((*s++) = (*t++)) != '\0')
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stringcpy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L4
  ret
```

assistant: ```c
void stringcpy(char *s, char *t) {
  while (((*s++) = (*t++)) != '\0')
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strrev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %esi,-0x41c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x408(%rbp)
  mov    -0x41c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x404(%rbp)
  jmp    L27
L21:
  mov    -0x404(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x418(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x408(%rbp),%eax
  cltq
  mov    %dl,-0x400(%rbp,%rax,1)
  addl   $0x1,-0x408(%rbp)
  subl   $0x1,-0x404(%rbp)
L27:
  cmpl   $0x0,-0x404(%rbp)
  jns    L21
  mov    -0x408(%rbp),%eax
  cltq
  movb   $0x0,-0x400(%rbp,%rax,1)
  lea    -0x400(%rbp),%rdx
  mov    -0x418(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void strrev(char *palavra, int tam) {
  int cont2 = 0, cont;
  char invert[1001];
  for (cont = tam - 1; cont > -1; cont--) {
    invert[cont2] = palavra[cont];
    cont2++;
  }
  invert[cont2] = '\0';
  strcpy(palavra, invert);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strrev>:
  endbr64
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %esi,%edx
  sub    $0x1,%edx
  js     L37
  movslq %edx,%rdx
  add    %rdi,%rdx
  mov    %rsp,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x1(%rsp,%rcx,1),%r8
L17:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L17
L39:
  movslq %esi,%rsi
  movb   $0x0,(%rsp,%rsi,1)
  mov    %rsp,%rsi
  call   <strcpy@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x408,%rsp
  ret
L37:
  mov    $0x0,%esi
  jmp    L39
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strrev(char *palavra, int tam) {
  int cont2 = 0, cont;
  char invert[1001];
  for (cont = tam - 1; cont > -1; cont--) {
    invert[cont2] = palavra[cont];
    cont2++;
  }
  invert[cont2] = '\0';
  strcpy(palavra, invert);
}
```
user: What is the c source code of the assembly code below:

```asm
<strrev>:
  endbr64
  sub    $0x408,%rsp
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  sub    $0x1,%ecx
  js     L14
  movslq %ecx,%rdx
  mov    %rsp,%r9
  mov    %ecx,%ecx
  add    %rdi,%rdx
  mov    %r9,%rax
  lea    0x1(%rsp,%rcx,1),%r8
  nopl   0x0(%rax,%rax,1)
L35:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %r8,%rax
  jne    L35
L4:
  movslq %esi,%rsi
  movb   $0x0,(%rsp,%rsi,1)
  mov    %r9,%rsi
  call   <strcpy@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x408,%rsp
  ret
  nopl   (%rax)
L14:
  xor    %esi,%esi
  mov    %rsp,%r9
  jmp    L4
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strrev(char *palavra, int tam) {
  int cont2 = 0, cont;
  char invert[1001];
  for (cont = tam - 1; cont > -1; cont--) {
    invert[cont2] = palavra[cont];
    cont2++;
  }
  invert[cont2] = '\0';
  strcpy(palavra, invert);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrev>:
  endbr64
  sub    $0x408,%rsp
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  sub    $0x1,%ecx
  js     L17
  movslq %ecx,%rdx
  mov    %rsp,%r9
  mov    %ecx,%ecx
  add    %rdi,%rdx
  mov    %r9,%rax
  lea    0x1(%rsp,%rcx,1),%r8
  nopl   0x0(%rax,%rax,1)
L27:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %r8,%rax
  jne    L27
L20:
  movslq %esi,%rsi
  movb   $0x0,(%rsp,%rsi,1)
  mov    %r9,%rsi
  call   <strcpy@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x408,%rsp
  ret
  nopl   (%rax)
L17:
  xor    %esi,%esi
  mov    %rsp,%r9
  jmp    L20
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strrev(char *palavra, int tam) {
  int cont2 = 0, cont;
  char invert[1001];
  for (cont = tam - 1; cont > -1; cont--) {
    invert[cont2] = palavra[cont];
    cont2++;
  }
  invert[cont2] = '\0';
  strcpy(palavra, invert);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str$round_not>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x248054,%eax
  leave
  ret
```

assistant: ```c
unsigned long str$round_not(const long *places, unsigned long *flags, const unsigned long *asign, const long *aexp, const struct dsc$descriptor_s *adigits, const unsigned long *bsign, const long *bexp, const struct dsc$descriptor_s *bdigits, unsigned long *csign, long *cexp, struct dsc$descriptor_s *cdigits) {
  assert(0);
  return 2392148;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str$round_not>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x248054,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long str$round_not(const long *places, unsigned long *flags, const unsigned long *asign, const long *aexp, const struct dsc$descriptor_s *adigits, const unsigned long *bsign, const long *bexp, const struct dsc$descriptor_s *bdigits, unsigned long *csign, long *cexp, struct dsc$descriptor_s *cdigits) {
  assert(0);
  return 2392148;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str$round_not>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x248054,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long str$round_not(const long *places, unsigned long *flags, const unsigned long *asign, const long *aexp, const struct dsc$descriptor_s *adigits, const unsigned long *bsign, const long *bexp, const struct dsc$descriptor_s *bdigits, unsigned long *csign, long *cexp, struct dsc$descriptor_s *cdigits) {
  assert(0);
  return 2392148;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str$round_not>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x248054,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long str$round_not(const long *places, unsigned long *flags, const unsigned long *asign, const long *aexp, const struct dsc$descriptor_s *adigits, const unsigned long *bsign, const long *bexp, const struct dsc$descriptor_s *bdigits, unsigned long *csign, long *cexp, struct dsc$descriptor_s *cdigits) {
  assert(0);
  return 2392148;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<supported>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,-0x70(%rbp)
  lea    D76(%rip),%rax
  mov    %rax,-0x68(%rbp)
  lea    D80(%rip),%rax
  mov    %rax,-0x60(%rbp)
  lea    D58(%rip),%rax
  mov    %rax,-0x58(%rbp)
  lea    D87(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D90(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D36(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D100(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D64(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D56(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L26
L49:
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,8),%rax
  mov    -0x88(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L6
  mov    $0x1,%eax
  jmp    L35
L6:
  addl   $0x1,-0x74(%rbp)
L26:
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,8),%rax
  test   %rax,%rax
  jne    L49
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D76
datatype: string
name: unpack_data
arguments: data_tag: D80
datatype: string
name: unpack_data
arguments: data_tag: D58
datatype: string
name: unpack_data
arguments: data_tag: D87
datatype: string
name: unpack_data
arguments: data_tag: D90
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string
name: unpack_data
arguments: data_tag: D36
datatype: string
name: unpack_data
arguments: data_tag: D100
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string
name: unpack_data
arguments: data_tag: D64
datatype: string
name: unpack_data
arguments: data_tag: D56
datatype: string

tool: D25: :STRIPS

tool: D76: :NEGATION

tool: D80: :NEGATIVE-PRECONDITIONS

tool: D58: :EQUALITY

tool: D87: :TYPING

tool: D90: :CONDITIONAL-EFFECTS

tool: D3: :DISJUNCTIVE-PRECONDITIONS

tool: D36: :EXISTENTIAL-PRECONDITIONS

tool: D100: :UNIVERSAL-PRECONDITIONS

tool: D28: :QUANTIFIED-PRECONDITIONS

tool: D64: :ADL

tool: D56: :DERIVED-PREDICATES

assistant: ```c
int supported(char *str) {
  int i;
  char *sup[] = {":STRIPS", ":NEGATION", ":NEGATIVE-PRECONDITIONS", ":EQUALITY", ":TYPING", ":CONDITIONAL-EFFECTS", ":DISJUNCTIVE-PRECONDITIONS", ":EXISTENTIAL-PRECONDITIONS", ":UNIVERSAL-PRECONDITIONS", ":QUANTIFIED-PRECONDITIONS", ":ADL", ":DERIVED-PREDICATES", NULL};
  for (i = 0; NULL != sup[i]; i++) {
    if (0 == strcmp(sup[i], str)) {
      return 1;
    }
  }
  return 0;
}
```