ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<scan_c_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  lea    D21(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
L40:
  mov    %rsp,%rbx
  lea    D19(%rip),%r12
  lea    0x6(%rsp),%r15
  lea    D15(%rip),%r14
  nopl   0x0(%rax)
L32:
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L66
  mov    $0x7,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L32
  mov    %r15,%rdi
  mov    %r14,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L32
  mov    %r13d,%esi
  call   <located_function@plt>
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x118,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L16:
  mov    %r12,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L40
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D21
datatype: string
name: disassemble_data
arguments: label: D19
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string

tool: D21: r

tool: D19: arg_t _

tool: D15:  (	


assistant: ```c
int scan_c_file(const char *name, int code) {
  char buf[256];
  char *t;
  FILE *f = fopen(name, "r");
  if (!f) {
    perror(name);
    exit(1);
  }
  while (fgets(buf, 256, f)) {
    if (memcmp(buf, "arg_t _", 7))
      continue;
    t = strtok(buf + 6, " (\t\n");
    if (t == NULL)
      continue;
    located_function(t, code);
  }
  fclose(f);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %edi,-0x1024(%rbp)
  mov    %rsi,-0x1030(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <init_hotplug_sock@plt>
  mov    %eax,-0x1014(%rbp)
L1:
  movq   $0x0,-0x1010(%rbp)
  movq   $0x0,-0x1008(%rbp)
  lea    -0x1000(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1fe,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x1010(%rbp),%rsi
  mov    -0x1014(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1000,%edx
  mov    %eax,%edi
  call   <recv@plt>
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: SnoTest---------------%s


assistant: ```c
int main(int argc, char *argv[]) {
  int hotplug_sock = init_hotplug_sock();
  while (1) {
    char buf[2048 * 2] = {0};
    recv(hotplug_sock, &buf, sizeof(buf), 0);
    printf("SnoTest---------------%s\n", buf);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  call   <init_hotplug_sock@plt>
  mov    %eax,%ebp
  lea    D4(%rip),%r12
L2:
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x1fe,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbx
  mov    $0x1000,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: SnoTest---------------%s


assistant: ```c
int main(int argc, char *argv[]) {
  int hotplug_sock = init_hotplug_sock();
  while (1) {
    char buf[2048 * 2] = {0};
    recv(hotplug_sock, &buf, sizeof(buf), 0);
    printf("SnoTest---------------%s\n", buf);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  lea    D1(%rip),%r14
  xor    %r13d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rsp,%rbx
  call   <init_hotplug_sock@plt>
  mov    %eax,%r12d
  nopl   0x0(%rax)
L1:
  mov    %r13,%rax
  mov    %rbp,%rdi
  mov    $0x1fe,%ecx
  mov    %rbx,%rsi
  rep stos %rax,%es:(%rdi)
  pxor   %xmm0,%xmm0
  mov    %r12d,%edi
  mov    $0x1000,%edx
  movaps %xmm0,(%rsp)
  call   <recv@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: SnoTest---------------%s


assistant: ```c
int main(int argc, char *argv[]) {
  int hotplug_sock = init_hotplug_sock();
  while (1) {
    char buf[2048 * 2] = {0};
    recv(hotplug_sock, &buf, sizeof(buf), 0);
    printf("SnoTest---------------%s\n", buf);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  lea    D2(%rip),%r14
  xor    %r13d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rsp,%rbx
  call   <init_hotplug_sock@plt>
  mov    %eax,%r12d
  nopl   0x0(%rax)
L9:
  mov    %r13,%rax
  mov    %rbp,%rdi
  mov    $0x1fe,%ecx
  mov    %rbx,%rsi
  rep stos %rax,%es:(%rdi)
  pxor   %xmm0,%xmm0
  mov    %r12d,%edi
  mov    $0x1000,%edx
  movaps %xmm0,(%rsp)
  call   <recv@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string

tool: D2: SnoTest---------------%s


assistant: ```c
int main(int argc, char *argv[]) {
  int hotplug_sock = init_hotplug_sock();
  while (1) {
    char buf[2048 * 2] = {0};
    recv(hotplug_sock, &buf, sizeof(buf), 0);
    printf("SnoTest---------------%s\n", buf);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Dbl2Stg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %esi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x34(%rbp)
  je     L12
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L22
L12:
  movl   $0x10,-0x14(%rbp)
L22:
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rsi
  mov    -0x14(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  mov    %ecx,%edi
  movq   %rax,%xmm0
  call   <ecvt@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%edi
  mov    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <Buffer2Stg@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void Dbl2Stg(char *lps, double factor, int prec) {
  int decimal, sign, precision;
  char *buffer;
  if (prec)
    precision = prec;
  else
    precision = 16;
  buffer = ecvt(factor, precision, &decimal, &sign);
  Buffer2Stg(lps, buffer, decimal, sign, precision);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Dbl2Stg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  mov    $0x10,%eax
  cmove  %eax,%ebx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %ebx,%edi
  call   <ecvt@plt>
  mov    %rax,%rsi
  mov    %ebx,%r8d
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  mov    %rbp,%rdi
  call   <Buffer2Stg@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Dbl2Stg(char *lps, double factor, int prec) {
  int decimal, sign, precision;
  char *buffer;
  if (prec)
    precision = prec;
  else
    precision = 16;
  buffer = ecvt(factor, precision, &decimal, &sign);
  Buffer2Stg(lps, buffer, decimal, sign, precision);
}
```
user: What is the c source code of the assembly code below:

```asm
<Dbl2Stg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  mov    $0x10,%eax
  lea    0x4(%rsp),%rdx
  cmove  %eax,%ebx
  mov    %rsp,%rsi
  mov    %ebx,%edi
  call   <ecvt@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  mov    %ebx,%r8d
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <Buffer2Stg@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Dbl2Stg(char *lps, double factor, int prec) {
  int decimal, sign, precision;
  char *buffer;
  if (prec)
    precision = prec;
  else
    precision = 16;
  buffer = ecvt(factor, precision, &decimal, &sign);
  Buffer2Stg(lps, buffer, decimal, sign, precision);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Dbl2Stg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  mov    $0x10,%eax
  lea    0x4(%rsp),%rdx
  cmove  %eax,%ebx
  mov    %rsp,%rsi
  mov    %ebx,%edi
  call   <ecvt@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  mov    %ebx,%r8d
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <Buffer2Stg@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Dbl2Stg(char *lps, double factor, int prec) {
  int decimal, sign, precision;
  char *buffer;
  if (prec)
    precision = prec;
  else
    precision = 16;
  buffer = ecvt(factor, precision, &decimal, &sign);
  Buffer2Stg(lps, buffer, decimal, sign, precision);
}
```
user: Translate the below assembly code into C programming language:

```asm
<msleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0xf4240,%edx,%eax
  mov    %eax,-0xc(%rbp)
  nop
L4:
  lea    -0x10(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  test   %rax,%rax
  jne    L4
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void msleep(uint32_t msec) {
  struct timespec req = {msec / 1000, 1000000 * (msec % 1000)};
  while (nanosleep(&req, &req))
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<msleep>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rbx
L11:
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  test   %rax,%rax
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msleep(uint32_t msec) {
  struct timespec req = {msec / 1000, 1000000 * (msec % 1000)};
  while (nanosleep(&req, &req))
    ;
}
```
user: What is the c source code of the assembly code below:

```asm
<msleep>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rbx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  test   %rax,%rax
  jne    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msleep(uint32_t msec) {
  struct timespec req = {msec / 1000, 1000000 * (msec % 1000)};
  while (nanosleep(&req, &req))
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msleep>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rbx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%edi
  imul   $0xf4240,%edi,%edi
  movd   %edi,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
L4:
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  test   %rax,%rax
  jne    L4
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msleep(uint32_t msec) {
  struct timespec req = {msec / 1000, 1000000 * (msec % 1000)};
  while (nanosleep(&req, &req))
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sal_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L33
L7:
  addq   $0x8,-0x10(%rbp)
L33:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1010101(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  not    %rax
  and    %rdx,%rax
  and    $0x80808080,%eax
  test   %rax,%rax
  je     L7
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L6
L21:
  addq   $0x1,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sal_strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *sal_strcat(char *s1, const char *s2) {
  char *s = s1;
  if ((((long)s1 & (sizeof(long) - 1)) == 0)) {
    unsigned long *aligned_s1 = (unsigned long *)s1;
    while (!(((*aligned_s1) - 0x01010101) & ~(*aligned_s1) & 0x80808080))
      aligned_s1++;
    s1 = (char *)aligned_s1;
  }
  while (*s1)
    s1++;
  sal_strcpy(s1, s2);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sal_strcat>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   $0x7,%dil
  je     L26
L35:
  cmpb   $0x0,(%rdi)
  je     L18
L64:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L64
L18:
  call   <sal_strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
L21:
  mov    %rbx,%rdi
  jmp    L35
L26:
  mov    (%rdi),%rax
  lea    -0x1010101(%rax),%rdx
  not    %rax
  and    %rdx,%rax
  test   $0x80808080,%eax
  jne    L21
L8:
  add    $0x8,%rdi
  mov    (%rdi),%rax
  lea    -0x1010101(%rax),%rdx
  not    %rax
  and    %rdx,%rax
  test   $0x80808080,%eax
  je     L8
  jmp    L35
```

assistant: ```c
char *sal_strcat(char *s1, const char *s2) {
  char *s = s1;
  if ((((long)s1 & (sizeof(long) - 1)) == 0)) {
    unsigned long *aligned_s1 = (unsigned long *)s1;
    while (!(((*aligned_s1) - 0x01010101) & ~(*aligned_s1) & 0x80808080))
      aligned_s1++;
    s1 = (char *)aligned_s1;
  }
  while (*s1)
    s1++;
  sal_strcpy(s1, s2);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<sal_strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   $0x7,%dil
  jne    L42
  mov    (%rdi),%rax
  jmp    L1
  nopl   0x0(%rax)
L18:
  mov    0x8(%rdi),%rax
  add    $0x8,%rdi
L1:
  lea    -0x1010101(%rax),%rdx
  not    %rax
  and    %rdx,%rax
  test   $0x80808080,%eax
  je     L18
  cmpb   $0x0,(%rdi)
  je     L25
  nopl   0x0(%rax)
L20:
  add    $0x1,%rdi
L42:
  cmpb   $0x0,(%rdi)
  jne    L20
L25:
  call   <sal_strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *sal_strcat(char *s1, const char *s2) {
  char *s = s1;
  if ((((long)s1 & (sizeof(long) - 1)) == 0)) {
    unsigned long *aligned_s1 = (unsigned long *)s1;
    while (!(((*aligned_s1) - 0x01010101) & ~(*aligned_s1) & 0x80808080))
      aligned_s1++;
    s1 = (char *)aligned_s1;
  }
  while (*s1)
    s1++;
  sal_strcpy(s1, s2);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<sal_strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   $0x7,%dil
  jne    L20
  mov    (%rdi),%rax
  jmp    L4
  nopl   0x0(%rax)
L25:
  mov    0x8(%rdi),%rax
  add    $0x8,%rdi
L4:
  lea    -0x1010101(%rax),%rdx
  not    %rax
  and    %rdx,%rax
  test   $0x80808080,%eax
  je     L25
  cmpb   $0x0,(%rdi)
  je     L37
  nopl   0x0(%rax)
L26:
  add    $0x1,%rdi
L20:
  cmpb   $0x0,(%rdi)
  jne    L26
L37:
  call   <sal_strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *sal_strcat(char *s1, const char *s2) {
  char *s = s1;
  if ((((long)s1 & (sizeof(long) - 1)) == 0)) {
    unsigned long *aligned_s1 = (unsigned long *)s1;
    while (!(((*aligned_s1) - 0x01010101) & ~(*aligned_s1) & 0x80808080))
      aligned_s1++;
    s1 = (char *)aligned_s1;
  }
  while (*s1)
    s1++;
  sal_strcpy(s1, s2);
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <usage_command_usagestr@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void usage(const char *const *usagestr) {
  usage_command_usagestr(usagestr, NULL, 1, 1);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <usage_command_usagestr@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void usage(const char *const *usagestr) {
  usage_command_usagestr(usagestr, NULL, 1, 1);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  call   <usage_command_usagestr@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void usage(const char *const *usagestr) {
  usage_command_usagestr(usagestr, NULL, 1, 1);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  call   <usage_command_usagestr@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void usage(const char *const *usagestr) {
  usage_command_usagestr(usagestr, NULL, 1, 1);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D80(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rcx
  lea    0x15(%rsp),%rbx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdx
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L75
L79:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L75:
  mov    %rbx,%rdi
  lea    D66(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L79
  mov    %rbx,%rdi
  lea    D23(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L79
  mov    %rbx,%rdi
  lea    D25(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L91
  cmpl   $0x0,0x10(%rsp)
  jne    L79
  lea    D82(%rip),%rdi
  call   <puts@plt>
  jmp    L79
L91:
  lea    0x15(%rsp),%rdi
  lea    D42(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L71
  cmpl   $0x0,0x10(%rsp)
  jne    L79
  lea    D82(%rip),%rdi
  call   <puts@plt>
  jmp    L79
L71:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L79
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D80
data_type: string
name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D13
data_type: string
name: read_data
arguments: data_tag: D66
data_type: string
name: read_data
arguments: data_tag: D23
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string
name: read_data
arguments: data_tag: D82
data_type: string
name: read_data
arguments: data_tag: D42
data_type: string
name: read_data
arguments: data_tag: D3
data_type: string

tool: D80: Calculator


tool: D2: %d %s %d

tool: D13: add

tool: D66: sub

tool: D23: mul

tool: D25: div

tool: D82: Do not divide by 0.

tool: D42: mod

tool: D3: error

assistant: ```c
int main() {
  int a, b, c, r;
  char op[3];
  printf("Calculator\n\n");
  scanf("%d %s %d", &a, op, &b);
  if (strcmp(op, "add") == 0) {
    c = a + b;
  } else if (strcmp(op, "sub") == 0) {
    c = a - b;
  } else if (strcmp(op, "mul") == 0) {
    c = a * b;
  } else if (strcmp(op, "div") == 0) {
    c = a / b;
    if (b == 0) {
      printf("Do not divide by 0.\n");
      r = 1;
    }
  } else if (strcmp(op, "mod") == 0) {
    c = a % b;
    if (b == 0) {
      printf("Do not divide by 0.\n");
      r = 1;
    }
  } else {
    printf("error\n");
    r = 1;
  }
  if (r == 0) {
    printf("%d\n", c);
  }
  return 0;
}
```