ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<cpu_has_pku>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__cpuid@plt>
  mov    -0x10(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L9
  mov    $0x0,%edi
  call   <fflush@plt>
  mov    $0x0,%eax
  jmp    L37
L9:
  mov    -0x10(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  jne    L31
  mov    $0x0,%edi
  call   <fflush@plt>
  mov    $0x0,%eax
  jmp    L37
L31:
  mov    $0x1,%eax
L37:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int cpu_has_pku(void) {
  unsigned int eax;
  unsigned int ebx;
  unsigned int ecx;
  unsigned int edx;
  eax = 0x7;
  ecx = 0x0;
  __cpuid(&eax, &ebx, &ecx, &edx);
  if (!(ecx & (1 << 3))) {
    do {
      if (2 <= 0)
        sigsafe_printf("cpu does not have PKU\n");
      fflush(NULL);
    } while (0);
    return 0;
  }
  if (!(ecx & (1 << 4))) {
    do {
      if (2 <= 0)
        sigsafe_printf("cpu does not have OSPKE\n");
      fflush(NULL);
    } while (0);
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpu_has_pku>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x7,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <__cpuid@plt>
  mov    0x10(%rsp),%eax
  test   $0x8,%al
  je     L19
  mov    $0x1,%edx
  test   $0x10,%al
  je     L25
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %edx,%eax
  add    $0x28,%rsp
  ret
L19:
  mov    $0x0,%edi
  call   <fflush@plt>
  mov    $0x0,%edx
  jmp    L2
L25:
  mov    $0x0,%edi
  call   <fflush@plt>
  mov    $0x0,%edx
  jmp    L2
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpu_has_pku(void) {
  unsigned int eax;
  unsigned int ebx;
  unsigned int ecx;
  unsigned int edx;
  eax = 0x7;
  ecx = 0x0;
  __cpuid(&eax, &ebx, &ecx, &edx);
  if (!(ecx & (1 << 3))) {
    do {
      if (2 <= 0)
        sigsafe_printf("cpu does not have PKU\n");
      fflush(NULL);
    } while (0);
    return 0;
  }
  if (!(ecx & (1 << 4))) {
    do {
      if (2 <= 0)
        sigsafe_printf("cpu does not have OSPKE\n");
      fflush(NULL);
    } while (0);
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cpu_has_pku>:
  endbr64
  sub    $0x28,%rsp
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movl   $0x7,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  call   <__cpuid@plt>
  mov    0x10(%rsp),%eax
  test   $0x8,%al
  je     L15
  test   $0x10,%al
  je     L15
  mov    $0x1,%eax
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %edi,%edi
  call   <fflush@plt>
  xor    %eax,%eax
  jmp    L10
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpu_has_pku(void) {
  unsigned int eax;
  unsigned int ebx;
  unsigned int ecx;
  unsigned int edx;
  eax = 0x7;
  ecx = 0x0;
  __cpuid(&eax, &ebx, &ecx, &edx);
  if (!(ecx & (1 << 3))) {
    do {
      if (2 <= 0)
        sigsafe_printf("cpu does not have PKU\n");
      fflush(NULL);
    } while (0);
    return 0;
  }
  if (!(ecx & (1 << 4))) {
    do {
      if (2 <= 0)
        sigsafe_printf("cpu does not have OSPKE\n");
      fflush(NULL);
    } while (0);
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cpu_has_pku>:
  endbr64
  sub    $0x28,%rsp
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movl   $0x7,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  call   <__cpuid@plt>
  mov    0x10(%rsp),%eax
  test   $0x8,%al
  je     L31
  test   $0x10,%al
  je     L31
  mov    $0x1,%eax
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %edi,%edi
  call   <fflush@plt>
  xor    %eax,%eax
  jmp    L9
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpu_has_pku(void) {
  unsigned int eax;
  unsigned int ebx;
  unsigned int ecx;
  unsigned int edx;
  eax = 0x7;
  ecx = 0x0;
  __cpuid(&eax, &ebx, &ecx, &edx);
  if (!(ecx & (1 << 3))) {
    do {
      if (2 <= 0)
        sigsafe_printf("cpu does not have PKU\n");
      fflush(NULL);
    } while (0);
    return 0;
  }
  if (!(ecx & (1 << 4))) {
    do {
      if (2 <= 0)
        sigsafe_printf("cpu does not have OSPKE\n");
      fflush(NULL);
    } while (0);
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<symexpres>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getsym@plt>
  mov    $0x0,%eax
  call   <expres@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void symexpres(void) {
  getsym();
  expres();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<symexpres>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getsym@plt>
  mov    $0x0,%eax
  call   <expres@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void symexpres(void) {
  getsym();
  expres();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<symexpres>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getsym@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <expres@plt>
```

assistant: ```c
void symexpres(void) {
  getsym();
  expres();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<symexpres>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getsym@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <expres@plt>
```

assistant: ```c
void symexpres(void) {
  getsym();
  expres();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ntlibc_stricmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L88
L68:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ntlibc_toupper@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ntlibc_toupper@plt>
  cmp    %rax,%rbx
  je     L86
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L62
  mov    $0xffffffff,%eax
  jmp    L85
L62:
  mov    $0x1,%eax
  jmp    L85
L86:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L88:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L13
  mov    $0x0,%eax
  jmp    L85
L13:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L98
  mov    $0xffffffff,%eax
  jmp    L85
L98:
  mov    $0x1,%eax
L85:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int ntlibc_stricmp(const char *s1, const char *s2) {
  char *p1 = (char *)s1;
  char *p2 = (char *)s2;
  while (*p1 || *p2) {
    if (ntlibc_toupper(*p1) != ntlibc_toupper(*p2)) {
      return (*p1 < *p2) ? -1 : 1;
    }
    p1++;
    p2++;
  }
  if (*p1 == *p2) {
    return 0;
  } else {
    return (*p1 < *p2) ? -1 : 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ntlibc_stricmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  jmp    L29
L13:
  movsbl %dil,%edi
  call   <ntlibc_toupper@plt>
  mov    %rax,%rbx
  movsbl 0x0(%rbp),%edi
  call   <ntlibc_toupper@plt>
  cmp    %rax,%rbx
  jne    L15
  add    $0x1,%r12
  add    $0x1,%rbp
L29:
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L13
  cmpb   $0x0,0x0(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L2
L15:
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%r12)
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ntlibc_stricmp(const char *s1, const char *s2) {
  char *p1 = (char *)s1;
  char *p2 = (char *)s2;
  while (*p1 || *p2) {
    if (ntlibc_toupper(*p1) != ntlibc_toupper(*p2)) {
      return (*p1 < *p2) ? -1 : 1;
    }
    p1++;
    p2++;
  }
  if (*p1 == *p2) {
    return 0;
  } else {
    return (*p1 < *p2) ? -1 : 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ntlibc_stricmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L8
L39:
  add    $0x1,%r12
  add    $0x1,%rbp
L8:
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L33
  cmpb   $0x0,0x0(%rbp)
  je     L22
L33:
  call   <ntlibc_toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%rbx
  call   <ntlibc_toupper@plt>
  cmp    %rax,%rbx
  je     L39
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%r12)
  setge  %al
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopl   (%rax)
L22:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ntlibc_stricmp(const char *s1, const char *s2) {
  char *p1 = (char *)s1;
  char *p2 = (char *)s2;
  while (*p1 || *p2) {
    if (ntlibc_toupper(*p1) != ntlibc_toupper(*p2)) {
      return (*p1 < *p2) ? -1 : 1;
    }
    p1++;
    p2++;
  }
  if (*p1 == *p2) {
    return 0;
  } else {
    return (*p1 < *p2) ? -1 : 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ntlibc_stricmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L11
L7:
  add    $0x1,%r12
  add    $0x1,%rbp
L11:
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L31
  cmpb   $0x0,0x0(%rbp)
  je     L20
L31:
  call   <ntlibc_toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%rbx
  call   <ntlibc_toupper@plt>
  cmp    %rax,%rbx
  je     L7
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%r12)
  setge  %al
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopl   (%rax)
L20:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ntlibc_stricmp(const char *s1, const char *s2) {
  char *p1 = (char *)s1;
  char *p2 = (char *)s2;
  while (*p1 || *p2) {
    if (ntlibc_toupper(*p1) != ntlibc_toupper(*p2)) {
      return (*p1 < *p2) ? -1 : 1;
    }
    p1++;
    p2++;
  }
  if (*p1 == *p2) {
    return 0;
  } else {
    return (*p1 < *p2) ? -1 : 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<basSpeedMusic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <speedmusic@plt>
  mov    %eax,%edi
  call   <pushNumber@plt>
  nop
  leave
  ret
```

assistant: ```c
void basSpeedMusic() {
  int v;
  v = popNumber();
  pushNumber(speedmusic(v));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<basSpeedMusic>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%edi
  call   <speedmusic@plt>
  mov    %eax,%edi
  call   <pushNumber@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void basSpeedMusic() {
  int v;
  v = popNumber();
  pushNumber(speedmusic(v));
}
```
user: Translate the below assembly code into C programming language:

```asm
<basSpeedMusic>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%edi
  call   <speedmusic@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1080 <pushNumber@plt>
```

assistant: ```c
void basSpeedMusic() {
  int v;
  v = popNumber();
  pushNumber(speedmusic(v));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basSpeedMusic>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%edi
  call   <speedmusic@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1080 <pushNumber@plt>
```

assistant: ```c
void basSpeedMusic() {
  int v;
  v = popNumber();
  pushNumber(speedmusic(v));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nand_cmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    $0x4e000008,%edx
  movzbl -0x14(%rbp),%eax
  mov    %al,(%rdx)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L8:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    $0x9,%eax
  jle    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nand_cmd(unsigned char cmd) {
  volatile int i;
  (*((volatile unsigned char *)0x4E000008)) = cmd;
  for (i = 0; i < 10; i++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nand_cmd>:
  endbr64
  mov    %dil,0x4e000008
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x9,%eax
  jg     L12
L1:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x9,%eax
  jle    L1
L12:
  ret
```

assistant: ```c
void nand_cmd(unsigned char cmd) {
  volatile int i;
  (*((volatile unsigned char *)0x4E000008)) = cmd;
  for (i = 0; i < 10; i++)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nand_cmd>:
  endbr64
  mov    %dil,0x4e000008
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x9,%eax
  jg     L13
  nopl   (%rax)
L0:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x9,%eax
  jle    L0
L13:
  ret
```

assistant: ```c
void nand_cmd(unsigned char cmd) {
  volatile int i;
  (*((volatile unsigned char *)0x4E000008)) = cmd;
  for (i = 0; i < 10; i++)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nand_cmd>:
  endbr64
  mov    %dil,0x4e000008
  movl   $0x0,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x9,%eax
  jg     L1
  nopl   (%rax)
L6:
  mov    -0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  cmp    $0x9,%eax
  jle    L6
L1:
  ret
```

assistant: ```c
void nand_cmd(unsigned char cmd) {
  volatile int i;
  (*((volatile unsigned char *)0x4E000008)) = cmd;
  for (i = 0; i < 10; i++)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<StatMaxFloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L6
L21:
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L3
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
L3:
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float StatMaxFloat(float a[], int n, int s) {
  int i;
  float maxa = a[0];
  for (i = 1; i < n; i++) {
    if (a[i * s] > maxa) {
      maxa = a[i * s];
    }
  }
  return maxa;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<StatMaxFloat>:
  endbr64
  movss  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L13
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rdx,%rdi
  mov    $0x1,%eax
L2:
  movss  (%rdi),%xmm1
  maxss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  add    $0x1,%eax
  add    %rdx,%rdi
  cmp    %eax,%esi
  jne    L2
L13:
  ret
```

assistant: ```c
float StatMaxFloat(float a[], int n, int s) {
  int i;
  float maxa = a[0];
  for (i = 1; i < n; i++) {
    if (a[i * s] > maxa) {
      maxa = a[i * s];
    }
  }
  return maxa;
}
```
user: Translate the below assembly code into C programming language:

```asm
<StatMaxFloat>:
  endbr64
  movss  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L1
  movslq %edx,%rdx
  mov    $0x1,%eax
  shl    $0x2,%rdx
  add    %rdx,%rdi
  nopl   0x0(%rax)
L5:
  movss  (%rdi),%xmm1
  add    $0x1,%eax
  add    %rdx,%rdi
  maxss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  cmp    %eax,%esi
  jne    L5
L1:
  ret
```

assistant: ```c
float StatMaxFloat(float a[], int n, int s) {
  int i;
  float maxa = a[0];
  for (i = 1; i < n; i++) {
    if (a[i * s] > maxa) {
      maxa = a[i * s];
    }
  }
  return maxa;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<StatMaxFloat>:
  endbr64
  movss  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L9
  cmp    $0x1,%edx
  jne    L10
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rdx,4),%rdx
  xchg   %ax,%ax
L23:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  maxss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L23
L9:
  ret
  nopl   (%rax)
L10:
  movslq %edx,%rdx
  mov    $0x1,%ecx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rax
  nopl   0x0(%rax,%rax,1)
L1:
  movss  (%rax),%xmm1
  add    $0x1,%ecx
  add    %rdx,%rax
  maxss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  cmp    %ecx,%esi
  jne    L1
  ret
```

assistant: ```c
float StatMaxFloat(float a[], int n, int s) {
  int i;
  float maxa = a[0];
  for (i = 1; i < n; i++) {
    if (a[i * s] > maxa) {
      maxa = a[i * s];
    }
  }
  return maxa;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x6c6148,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <string_copy@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D17
data_type: string

tool: D12: %s 


tool: D17: Hallo Welt

assistant: ```c
int main(void) {
  char string[100] = "Hal";
  printf("%s \n", string);
  string_copy(string, "Hallo Welt");
  printf("%s \n", string);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x6c6148,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <string_copy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string
name: disassemble_data
arguments: label: D9
type: string

tool: D6: %s 


tool: D9: Hallo Welt

assistant: ```c
int main(void) {
  char string[100] = "Hal";
  printf("%s \n", string);
  string_copy(string, "Hallo Welt");
  printf("%s \n", string);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  pxor   %xmm0,%xmm0
  push   %rbp
  mov    %r12,%rdi
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,0x10(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movq   $0x6c6148,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <printf@plt>
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <string_copy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D2
type: string

tool: D3: %s 


tool: D2: Hallo Welt

assistant: ```c
int main(void) {
  char string[100] = "Hal";
  printf("%s \n", string);
  string_copy(string, "Hallo Welt");
  printf("%s \n", string);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  pxor   %xmm0,%xmm0
  push   %rbp
  mov    %r12,%rdi
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,0x10(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movq   $0x6c6148,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <printf@plt>
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <string_copy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D6
data_type: string

tool: D2: %s 


tool: D6: Hallo Welt

assistant: ```c
int main(void) {
  char string[100] = "Hal";
  printf("%s \n", string);
  string_copy(string, "Hallo Welt");
  printf("%s \n", string);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L16
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  jmp    L15
L16:
  nop
L15:
  leave
  ret
```

assistant: ```c
void quicksort(int ar[][2], int l, int r) {
  int m = 0;
  if (l >= r) {
    return;
  }
  m = partition(ar, l, r);
  quicksort(ar, l, m - 1);
  quicksort(ar, m + 1, r);
}
```