ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  mov    $0x46,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x4746454443,%rax
  mov    %rsp,%rdi
  mov    %rdx,0x8(%rsp)
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  mov    %rax,(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <any@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  char s1[100] = "CDEFG";
  char s2 = 'F';
  printf("%d\n", any(s1, s2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  mov    $0x46,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x4746454443,%rax
  mov    %rsp,%rdi
  mov    %rdx,0x8(%rsp)
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  mov    %rax,(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <any@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: %d


assistant: ```c
int main() {
  char s1[100] = "CDEFG";
  char s2 = 'F';
  printf("%d\n", any(s1, s2));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<posix_spawnattr_setsigmask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int posix_spawnattr_setsigmask(posix_spawnattr_t *attr, const sigset_t *sigmask) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<posix_spawnattr_setsigmask>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int posix_spawnattr_setsigmask(posix_spawnattr_t *attr, const sigset_t *sigmask) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<posix_spawnattr_setsigmask>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int posix_spawnattr_setsigmask(posix_spawnattr_t *attr, const sigset_t *sigmask) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<posix_spawnattr_setsigmask>:
  endbr64
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int posix_spawnattr_setsigmask(posix_spawnattr_t *attr, const sigset_t *sigmask) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L34
  mov    -0x1c(%rbp),%eax
  jmp    L29
L34:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L17
L1:
  subl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L1
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L37
  addl   $0x1,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L37:
  mov    -0x1c(%rbp),%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int str_rtrim(char *const buf, int len) {
  int i, last_char_pos = len - 1;
  if (len == 0)
    return len;
  for (i = last_char_pos; buf[i] == ' ';)
    i--;
  if (i != last_char_pos) {
    i = i + 1;
    buf[i] = buf[len];
    len = i;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_rtrim>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  je     L26
  lea    -0x1(%rsi),%eax
  cltq
  cmpb   $0x20,(%rdi,%rax,1)
  jne    L26
L15:
  mov    %eax,%edx
  sub    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  je     L15
  cmp    %edx,%esi
  je     L26
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%ecx
  movslq %edx,%rax
  mov    %cl,(%rdi,%rax,1)
L26:
  mov    %edx,%eax
  ret
```

assistant: ```c
int str_rtrim(char *const buf, int len) {
  int i, last_char_pos = len - 1;
  if (len == 0)
    return len;
  for (i = last_char_pos; buf[i] == ' ';)
    i--;
  if (i != last_char_pos) {
    i = i + 1;
    buf[i] = buf[len];
    len = i;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_rtrim>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L23
  lea    -0x1(%rsi),%eax
  cltq
  cmpb   $0x20,(%rdi,%rax,1)
  jne    L10
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %eax,%r8d
  sub    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  je     L4
  cmp    %r8d,%esi
  je     L23
  movslq %esi,%rsi
  movslq %r8d,%rax
  movzbl (%rdi,%rsi,1),%edx
  mov    %dl,(%rdi,%rax,1)
L23:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %esi,%r8d
  jmp    L23
```

assistant: ```c
int str_rtrim(char *const buf, int len) {
  int i, last_char_pos = len - 1;
  if (len == 0)
    return len;
  for (i = last_char_pos; buf[i] == ' ';)
    i--;
  if (i != last_char_pos) {
    i = i + 1;
    buf[i] = buf[len];
    len = i;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_rtrim>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L27
  lea    -0x1(%rsi),%eax
  cltq
  cmpb   $0x20,(%rdi,%rax,1)
  jne    L14
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %eax,%r8d
  sub    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  je     L19
  cmp    %r8d,%esi
  je     L27
  movslq %esi,%rsi
  movslq %r8d,%rax
  movzbl (%rdi,%rsi,1),%edx
  mov    %dl,(%rdi,%rax,1)
L27:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %esi,%r8d
  jmp    L27
```

assistant: ```c
int str_rtrim(char *const buf, int len) {
  int i, last_char_pos = len - 1;
  if (len == 0)
    return len;
  for (i = last_char_pos; buf[i] == ' ';)
    i--;
  if (i != last_char_pos) {
    i = i + 1;
    buf[i] = buf[len];
    len = i;
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x62,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <write_fmt@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <write_fmt@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D32
type: string
name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D23
type: string

tool: D25: Linkerist

tool: D32: named %s integer : %d


tool: D2: Heracles

tool: D23: named %s, real %s


assistant: ```c
int main() {
  write_fmt("named %s integer : %d\n", "Linkerist", 98);
  write_fmt("named %s, real %s\n", "Linkerist", "Heracles");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x62,%edx
  lea    D39(%rip),%rbx
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <write_fmt@plt>
  lea    D35(%rip),%rdx
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <write_fmt@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D39
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string
name: disassemble_data
arguments: data_label: D35
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string

tool: D39: Linkerist

tool: D5: named %s integer : %d


tool: D35: Heracles

tool: D28: named %s, real %s


assistant: ```c
int main() {
  write_fmt("named %s integer : %d\n", "Linkerist", 98);
  write_fmt("named %s, real %s\n", "Linkerist", "Heracles");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    $0x62,%edx
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <write_fmt@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdx
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <write_fmt@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D14
datatype: string

tool: D5: Linkerist

tool: D1: named %s integer : %d


tool: D2: Heracles

tool: D14: named %s, real %s


assistant: ```c
int main() {
  write_fmt("named %s integer : %d\n", "Linkerist", 98);
  write_fmt("named %s, real %s\n", "Linkerist", "Heracles");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    $0x62,%edx
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <write_fmt@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdx
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <write_fmt@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D4: Linkerist

tool: D6: named %s integer : %d


tool: D9: Heracles

tool: D5: named %s, real %s


assistant: ```c
int main() {
  write_fmt("named %s integer : %d\n", "Linkerist", 98);
  write_fmt("named %s, real %s\n", "Linkerist", "Heracles");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_exename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <readlink@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L0
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L8
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L8:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: /proc/self/exe

assistant: ```c
char *get_exename(char *exename, int size) {
  int res;
  if ((res = readlink("/proc/self/exe", exename, size - 1)) == -1) {
    exename[0] = '\0';
  } else {
    exename[res] = '\0';
  }
  return (exename);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_exename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  je     L17
  cltq
  movb   $0x0,(%rbx,%rax,1)
L6:
  mov    %rbx,%rax
  pop    %rbx
  ret
L17:
  movb   $0x0,(%rbx)
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string

tool: D0: /proc/self/exe

assistant: ```c
char *get_exename(char *exename, int size) {
  int res;
  if ((res = readlink("/proc/self/exe", exename, size - 1)) == -1) {
    exename[0] = '\0';
  } else {
    exename[res] = '\0';
  }
  return (exename);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_exename>:
  endbr64
  push   %r12
  lea    -0x1(%rsi),%edx
  mov    %rdi,%r12
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  je     L7
  cltq
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L7:
  mov    %r12,%rax
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: /proc/self/exe

assistant: ```c
char *get_exename(char *exename, int size) {
  int res;
  if ((res = readlink("/proc/self/exe", exename, size - 1)) == -1) {
    exename[0] = '\0';
  } else {
    exename[res] = '\0';
  }
  return (exename);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_exename>:
  endbr64
  push   %r12
  lea    -0x1(%rsi),%edx
  mov    %rdi,%r12
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  je     L1
  cltq
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L1:
  mov    %r12,%rax
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: /proc/self/exe

assistant: ```c
char *get_exename(char *exename, int size) {
  int res;
  if ((res = readlink("/proc/self/exe", exename, size - 1)) == -1) {
    exename[0] = '\0';
  } else {
    exename[res] = '\0';
  }
  return (exename);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CameraCaptureStart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0x40,%rdx
  and    $0xfffffffffffffff0,%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0x40,%rdx
  or     $0x10000,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CameraCaptureStart(unsigned long ulBase) {
  (*((volatile unsigned long *)(ulBase + 0x00000040))) &= ~0xF;
  (*((volatile unsigned long *)(ulBase + 0x00000040))) |= 0x00010000;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CameraCaptureStart>:
  endbr64
  mov    0x40(%rdi),%rax
  and    $0xfffffffffffffff0,%rax
  mov    %rax,0x40(%rdi)
  mov    0x40(%rdi),%rax
  or     $0x10000,%rax
  mov    %rax,0x40(%rdi)
  ret
```

assistant: ```c
void CameraCaptureStart(unsigned long ulBase) {
  (*((volatile unsigned long *)(ulBase + 0x00000040))) &= ~0xF;
  (*((volatile unsigned long *)(ulBase + 0x00000040))) |= 0x00010000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CameraCaptureStart>:
  endbr64
  mov    0x40(%rdi),%rax
  and    $0xfffffffffffffff0,%rax
  mov    %rax,0x40(%rdi)
  mov    0x40(%rdi),%rax
  or     $0x10000,%rax
  mov    %rax,0x40(%rdi)
  ret
```

assistant: ```c
void CameraCaptureStart(unsigned long ulBase) {
  (*((volatile unsigned long *)(ulBase + 0x00000040))) &= ~0xF;
  (*((volatile unsigned long *)(ulBase + 0x00000040))) |= 0x00010000;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CameraCaptureStart>:
  endbr64
  mov    0x40(%rdi),%rax
  and    $0xfffffffffffffff0,%rax
  mov    %rax,0x40(%rdi)
  mov    0x40(%rdi),%rax
  or     $0x10000,%rax
  mov    %rax,0x40(%rdi)
  ret
```

assistant: ```c
void CameraCaptureStart(unsigned long ulBase) {
  (*((volatile unsigned long *)(ulBase + 0x00000040))) &= ~0xF;
  (*((volatile unsigned long *)(ulBase + 0x00000040))) |= 0x00010000;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<show_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string
name: retrieve_data
arguments: data_label: D17
type: string

tool: D1: network socket usage: %s [ -o <filename> ] [ -s <src-ip> ]


tool: D17: pcap capture usage:   %s -p -i <interface> [ -o <filename> ]  [ -s <src-ip> ] 


assistant: ```c
void show_usage(FILE *fp, char *arg) {
  fprintf(fp, "network socket usage: %s [ -o <filename> ] [ -s <src-ip> ]\n", arg);
  fprintf(fp, "pcap capture usage:   %s -p -i <interface> [ -o <filename> ]  [ -s <src-ip> ] \n", arg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<show_usage>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdx
  lea    D19(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdx
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D19
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D19: network socket usage: %s [ -o <filename> ] [ -s <src-ip> ]


tool: D13: pcap capture usage:   %s -p -i <interface> [ -o <filename> ]  [ -s <src-ip> ] 


assistant: ```c
void show_usage(FILE *fp, char *arg) {
  fprintf(fp, "network socket usage: %s [ -o <filename> ] [ -s <src-ip> ]\n", arg);
  fprintf(fp, "pcap capture usage:   %s -p -i <interface> [ -o <filename> ]  [ -s <src-ip> ] \n", arg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show_usage>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D12(%rip),%rsi
  pop    %rbp
  pop    %r12
  jmp    1050 <fprintf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D4: network socket usage: %s [ -o <filename> ] [ -s <src-ip> ]


tool: D12: pcap capture usage:   %s -p -i <interface> [ -o <filename> ]  [ -s <src-ip> ] 


assistant: ```c
void show_usage(FILE *fp, char *arg) {
  fprintf(fp, "network socket usage: %s [ -o <filename> ] [ -s <src-ip> ]\n", arg);
  fprintf(fp, "pcap capture usage:   %s -p -i <interface> [ -o <filename> ]  [ -s <src-ip> ] \n", arg);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<show_usage>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  lea    D17(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D3(%rip),%rsi
  pop    %rbp
  pop    %r12
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D17: network socket usage: %s [ -o <filename> ] [ -s <src-ip> ]


tool: D3: pcap capture usage:   %s -p -i <interface> [ -o <filename> ]  [ -s <src-ip> ] 


assistant: ```c
void show_usage(FILE *fp, char *arg) {
  fprintf(fp, "network socket usage: %s [ -o <filename> ] [ -s <src-ip> ]\n", arg);
  fprintf(fp, "pcap capture usage:   %s -p -i <interface> [ -o <filename> ]  [ -s <src-ip> ] \n", arg);
}
```
user: What is the c source code of the assembly code below:

```asm
<int4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L8
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  and    $0x7f000000,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int int4(unsigned const char *p) {
  int i;
  if (p[0] & 0x80) {
    i = -(((p[0] & 0x7f) << 24) + (p[1] << 16) + (p[2] << 8) + p[3]);
  } else {
    i = (p[0] << 24) + (p[1] << 16) + (p[2] << 8) + p[3];
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int4>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  js     L2
  movzbl 0x1(%rdi),%eax
  shl    $0x10,%eax
  shl    $0x18,%edx
  add    %edx,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%edx
  add    %edx,%eax
  movzbl 0x3(%rdi),%edx
  add    %edx,%eax
  ret
L2:
  shl    $0x18,%edx
  and    $0x7f000000,%edx
  movzbl 0x1(%rdi),%eax
  shl    $0x10,%eax
  add    %eax,%edx
  movzbl 0x2(%rdi),%eax
  shl    $0x8,%eax
  add    %eax,%edx
  movzbl 0x3(%rdi),%eax
  add    %edx,%eax
  neg    %eax
  ret
```

assistant: ```c
int int4(unsigned const char *p) {
  int i;
  if (p[0] & 0x80) {
    i = -(((p[0] & 0x7f) << 24) + (p[1] << 16) + (p[2] << 8) + p[3]);
  } else {
    i = (p[0] << 24) + (p[1] << 16) + (p[2] << 8) + p[3];
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<int4>:
  endbr64
  movzbl (%rdi),%esi
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%ecx
  movzbl 0x3(%rdi),%edi
  mov    %esi,%edx
  shl    $0x10,%eax
  shl    $0x18,%edx
  shl    $0x8,%ecx
  test   %sil,%sil
  js     L9
  add    %edx,%eax
  add    %ecx,%eax
  add    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  and    $0x7f000000,%edx
  add    %edx,%eax
  add    %ecx,%eax
  add    %edi,%eax
  neg    %eax
  ret
```

assistant: ```c
int int4(unsigned const char *p) {
  int i;
  if (p[0] & 0x80) {
    i = -(((p[0] & 0x7f) << 24) + (p[1] << 16) + (p[2] << 8) + p[3]);
  } else {
    i = (p[0] << 24) + (p[1] << 16) + (p[2] << 8) + p[3];
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<int4>:
  endbr64
  movzbl (%rdi),%esi
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%ecx
  movzbl 0x3(%rdi),%edi
  mov    %esi,%edx
  shl    $0x10,%eax
  shl    $0x18,%edx
  shl    $0x8,%ecx
  test   %sil,%sil
  js     L2
  add    %edx,%eax
  add    %ecx,%eax
  add    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  and    $0x7f000000,%edx
  add    %edx,%eax
  add    %ecx,%eax
  add    %edi,%eax
  neg    %eax
  ret
```

assistant: ```c
int int4(unsigned const char *p) {
  int i;
  if (p[0] & 0x80) {
    i = -(((p[0] & 0x7f) << 24) + (p[1] << 16) + (p[2] << 8) + p[3]);
  } else {
    i = (p[0] << 24) + (p[1] << 16) + (p[2] << 8) + p[3];
  }
  return i;
}
```