ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<factoriel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jbe    L8
  movss  -0x4(%rbp),%xmm0
  movss  D3(%rip),%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <factoriel>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x4(%rbp),%xmm0
  jmp    L12
L8:
  movss  D3(%rip),%xmm0
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float factoriel(float a) {
  if (a > 0)
    return a * factoriel(a - 1);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<factoriel>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  comiss D18(%rip),%xmm0
  ja     L19
  movss  D8(%rip),%xmm0
L10:
  add    $0x18,%rsp
  ret
L19:
  subss  D8(%rip),%xmm0
  call   <factoriel>
  mulss  0xc(%rsp),%xmm0
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D18
type_infered: byte[4]
name: parse_data
arguments: data_label: D8
type_infered: byte[4]

tool: {"D18": [0x00,0x00,0x00,0x00]}

tool: {"D8": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float factoriel(float a) {
  if (a > 0)
    return a * factoriel(a - 1);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<factoriel>:
  endbr64
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm0,%xmm1
  ja     L13
  movss  D2(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L13:
  movss  D2(%rip),%xmm3
  movaps %xmm1,%xmm2
  subss  %xmm3,%xmm2
  comiss %xmm0,%xmm2
  ja     L14
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movaps %xmm2,%xmm0
  sub    $0x18,%rsp
  subss  %xmm3,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <factoriel>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  add    $0x18,%rsp
  mulss  %xmm0,%xmm2
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: byte[4]

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float factoriel(float a) {
  if (a > 0)
    return a * factoriel(a - 1);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<factoriel>:
  endbr64
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm0,%xmm1
  ja     L11
  movss  D4(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L11:
  movss  D4(%rip),%xmm3
  movaps %xmm1,%xmm2
  subss  %xmm3,%xmm2
  comiss %xmm0,%xmm2
  ja     L3
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movaps %xmm2,%xmm0
  sub    $0x18,%rsp
  subss  %xmm3,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <factoriel>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  add    $0x18,%rsp
  mulss  %xmm0,%xmm2
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float factoriel(float a) {
  if (a > 0)
    return a * factoriel(a - 1);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L46
L41:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L40
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L17
L40:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L36
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    if ((unsigned char)*s1 != (unsigned char)*s2)
      return ((int)((unsigned char)*s1 - (unsigned char)*s2));
    s1++;
    s2++;
  }
  return ((int)((unsigned char)*s1 - (unsigned char)*s2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
L30:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L33
  cmp    %al,%dl
  jne    L19
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L30
L33:
  movzbl %al,%eax
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
L19:
  movzbl %al,%eax
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    if ((unsigned char)*s1 != (unsigned char)*s2)
      return ((int)((unsigned char)*s1 - (unsigned char)*s2));
    s1++;
    s2++;
  }
  return ((int)((unsigned char)*s1 - (unsigned char)*s2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L55
  jmp    L0
  nopl   (%rax)
L36:
  cmp    %al,%dl
  jne    L37
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L19
  mov    %rdx,%rsi
L55:
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L36
L37:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L19:
  movzbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L0:
  movzbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L37
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    if ((unsigned char)*s1 != (unsigned char)*s2)
      return ((int)((unsigned char)*s1 - (unsigned char)*s2));
    s1++;
    s2++;
  }
  return ((int)((unsigned char)*s1 - (unsigned char)*s2));
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L40
  jmp    L12
  nopl   (%rax)
L27:
  cmp    %al,%dl
  jne    L10
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L39
  mov    %rdx,%rsi
L40:
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L27
L10:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L39:
  movzbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L12:
  movzbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L10
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    if ((unsigned char)*s1 != (unsigned char)*s2)
      return ((int)((unsigned char)*s1 - (unsigned char)*s2));
    s1++;
    s2++;
  }
  return ((int)((unsigned char)*s1 - (unsigned char)*s2));
}
```
user: What is the c source code of the assembly code below:

```asm
<Config_UART1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2580,%edi
  call   <UART1_Init@plt>
  mov    $0x64,%edi
  call   <Delay_ms@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <UART1_Write_Text@plt>
  mov    $0xd,%edi
  call   <UART1_Write@plt>
  mov    $0xa,%edi
  call   <UART1_Write@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <Lcd_Out@plt>
  mov    $0x7d0,%edi
  call   <delay_ms@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string

tool: D2: Inicio

tool: D1: Inicia UART1

assistant: ```c
void Config_UART1(void) {
  UART1_Init(9600);
  Delay_ms(100);
  UART1_Write_Text("Inicio");
  UART1_Write(13);
  UART1_Write(10);
  Lcd_Out(1, 1, "Inicia UART1");
  delay_ms(2000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Config_UART1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2580,%edi
  call   <UART1_Init@plt>
  mov    $0x64,%edi
  call   <Delay_ms@plt>
  lea    D10(%rip),%rdi
  call   <UART1_Write_Text@plt>
  mov    $0xd,%edi
  call   <UART1_Write@plt>
  mov    $0xa,%edi
  call   <UART1_Write@plt>
  lea    D17(%rip),%rdx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <Lcd_Out@plt>
  mov    $0x7d0,%edi
  call   <delay_ms@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D17
datatype: string

tool: D10: Inicio

tool: D17: Inicia UART1

assistant: ```c
void Config_UART1(void) {
  UART1_Init(9600);
  Delay_ms(100);
  UART1_Write_Text("Inicio");
  UART1_Write(13);
  UART1_Write(10);
  Lcd_Out(1, 1, "Inicia UART1");
  delay_ms(2000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Config_UART1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2580,%edi
  call   <UART1_Init@plt>
  mov    $0x64,%edi
  call   <Delay_ms@plt>
  lea    D8(%rip),%rdi
  call   <UART1_Write_Text@plt>
  mov    $0xd,%edi
  call   <UART1_Write@plt>
  mov    $0xa,%edi
  call   <UART1_Write@plt>
  mov    $0x1,%edi
  mov    $0x1,%esi
  lea    D9(%rip),%rdx
  call   <Lcd_Out@plt>
  mov    $0x7d0,%edi
  add    $0x8,%rsp
  jmp    10c0 <delay_ms@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string
name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D8: Inicio

tool: D9: Inicia UART1

assistant: ```c
void Config_UART1(void) {
  UART1_Init(9600);
  Delay_ms(100);
  UART1_Write_Text("Inicio");
  UART1_Write(13);
  UART1_Write(10);
  Lcd_Out(1, 1, "Inicia UART1");
  delay_ms(2000);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Config_UART1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2580,%edi
  call   <UART1_Init@plt>
  mov    $0x64,%edi
  call   <Delay_ms@plt>
  lea    D8(%rip),%rdi
  call   <UART1_Write_Text@plt>
  mov    $0xd,%edi
  call   <UART1_Write@plt>
  mov    $0xa,%edi
  call   <UART1_Write@plt>
  mov    $0x1,%edi
  mov    $0x1,%esi
  lea    D13(%rip),%rdx
  call   <Lcd_Out@plt>
  mov    $0x7d0,%edi
  add    $0x8,%rsp
  jmp    10c0 <delay_ms@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D8: Inicio

tool: D13: Inicia UART1

assistant: ```c
void Config_UART1(void) {
  UART1_Init(9600);
  Delay_ms(100);
  UART1_Write_Text("Inicio");
  UART1_Write(13);
  UART1_Write(10);
  Lcd_Out(1, 1, "Inicia UART1");
  delay_ms(2000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<homo_cr_join>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L47
L16:
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movsd  (%rcx,%rax,8),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x2,-0x8(%rbp)
  jle    L4
  addl   $0x1,-0x4(%rbp)
L47:
  cmpl   $0x2,-0x4(%rbp)
  jle    L16
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L34:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,0x18(%rax)
  addl   $0x1,-0x8(%rbp)
L57:
  cmpl   $0x2,-0x8(%rbp)
  jle    L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void homo_cr_join(double H[3][4], double R[3][3], double d[3]) {
  int i, j;
  for (j = 0; j < 3; j++)
    for (i = 0; i < 3; i++)
      H[j][i] = R[j][i];
  for (i = 0; i < 3; i++)
    H[i][3] = d[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<homo_cr_join>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rcx
  add    $0x48,%rsi
L2:
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rcx)
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,0x8(%rcx)
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,0x10(%rcx)
  add    $0x18,%rax
  add    $0x20,%rcx
  cmp    %rsi,%rax
  jne    L2
  movsd  (%rdx),%xmm0
  movsd  %xmm0,0x18(%rdi)
  movsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x38(%rdi)
  movsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x58(%rdi)
  ret
```

assistant: ```c
void homo_cr_join(double H[3][4], double R[3][3], double d[3]) {
  int i, j;
  for (j = 0; j < 3; j++)
    for (i = 0; i < 3; i++)
      H[j][i] = R[j][i];
  for (i = 0; i < 3; i++)
    H[i][3] = d[i];
}
```
user: What is the c source code of the assembly code below?

```asm
<homo_cr_join>:
  endbr64
  mov    %rdi,%rax
  lea    0x48(%rsi),%rcx
L6:
  movsd  (%rsi),%xmm0
  add    $0x18,%rsi
  add    $0x20,%rax
  movsd  %xmm0,-0x20(%rax)
  movsd  -0x10(%rsi),%xmm0
  movsd  %xmm0,-0x18(%rax)
  movsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,-0x10(%rax)
  cmp    %rsi,%rcx
  jne    L6
  movsd  (%rdx),%xmm0
  movsd  %xmm0,0x18(%rdi)
  movsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x38(%rdi)
  movsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x58(%rdi)
  ret
```

assistant: ```c
void homo_cr_join(double H[3][4], double R[3][3], double d[3]) {
  int i, j;
  for (j = 0; j < 3; j++)
    for (i = 0; i < 3; i++)
      H[j][i] = R[j][i];
  for (i = 0; i < 3; i++)
    H[i][3] = d[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<homo_cr_join>:
  endbr64
  movsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x20(%rdi)
  movsd  0x20(%rsi),%xmm0
  movsd  %xmm0,0x28(%rdi)
  movsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x30(%rdi)
  movsd  0x30(%rsi),%xmm0
  movsd  %xmm0,0x40(%rdi)
  movsd  0x38(%rsi),%xmm0
  movsd  %xmm0,0x48(%rdi)
  movsd  0x40(%rsi),%xmm0
  movsd  %xmm0,0x50(%rdi)
  movsd  (%rdx),%xmm0
  movsd  %xmm0,0x18(%rdi)
  movsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x38(%rdi)
  movsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x58(%rdi)
  ret
```

assistant: ```c
void homo_cr_join(double H[3][4], double R[3][3], double d[3]) {
  int i, j;
  for (j = 0; j < 3; j++)
    for (i = 0; i < 3; i++)
      H[j][i] = R[j][i];
  for (i = 0; i < 3; i++)
    H[i][3] = d[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_lms_string_array_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  cmpq   $0x0,-0x18(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L29
L20:
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L15:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    0x9(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %ecx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L15
  cmpl   $0x0,-0x8(%rbp)
  je     L5
  addl   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L5:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  and    $0x7,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L55
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  sub    %edx,%eax
  add    $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L55:
  mov    -0x8(%rbp),%eax
L29:
  leave
  ret
```

assistant: ```c
int _lms_string_array_count(const char *const *array, int *size) {
  int count, align_overflow;
  *size = 0;
  if (!array)
    return 0;
  count = 0;
  for (; *array != NULL; array++) {
    *size += sizeof(char *) + strlen(*array) + 1;
    count++;
  }
  if (count) {
    count++;
    *size += sizeof(char *);
  }
  align_overflow = *size % sizeof(char *);
  if (align_overflow)
    *size += sizeof(char *) - align_overflow;
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_lms_string_array_count>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movl   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L25
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L39
  mov    $0x0,%ebp
L24:
  call   <strlen@plt>
  mov    (%r12),%edx
  lea    0x9(%rdx,%rax,1),%eax
  mov    %eax,(%r12)
  mov    %ebp,%edx
  add    $0x1,%ebp
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L24
  test   %ebp,%ebp
  je     L16
  lea    0x2(%rdx),%ebp
  add    $0x8,%eax
  mov    %eax,(%r12)
L16:
  mov    (%r12),%eax
  mov    %eax,%edx
  and    $0x7,%edx
  je     L42
  add    $0x8,%eax
  sub    %edx,%eax
  mov    %eax,(%r12)
L42:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    $0x0,%ebp
  jmp    L42
L39:
  mov    $0x0,%ebp
  jmp    L42
```

assistant: ```c
int _lms_string_array_count(const char *const *array, int *size) {
  int count, align_overflow;
  *size = 0;
  if (!array)
    return 0;
  count = 0;
  for (; *array != NULL; array++) {
    *size += sizeof(char *) + strlen(*array) + 1;
    count++;
  }
  if (count) {
    count++;
    *size += sizeof(char *);
  }
  align_overflow = *size % sizeof(char *);
  if (align_overflow)
    *size += sizeof(char *) - align_overflow;
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_lms_string_array_count>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movl   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L19
  mov    %rdi,%r12
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L19
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L29:
  call   <strlen@plt>
  mov    %ebx,%r13d
  mov    0x0(%rbp),%edx
  add    $0x1,%rbx
  mov    (%r12,%rbx,8),%rdi
  lea    0x9(%rdx,%rax,1),%eax
  mov    %eax,0x0(%rbp)
  test   %rdi,%rdi
  jne    L29
  mov    %eax,%ecx
  lea    0x8(%rax),%edx
  add    $0x10,%eax
  add    $0x2,%r13d
  and    $0x7,%ecx
  sub    %ecx,%eax
  test   %ecx,%ecx
  cmove  %edx,%eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _lms_string_array_count(const char *const *array, int *size) {
  int count, align_overflow;
  *size = 0;
  if (!array)
    return 0;
  count = 0;
  for (; *array != NULL; array++) {
    *size += sizeof(char *) + strlen(*array) + 1;
    count++;
  }
  if (count) {
    count++;
    *size += sizeof(char *);
  }
  align_overflow = *size % sizeof(char *);
  if (align_overflow)
    *size += sizeof(char *) - align_overflow;
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_lms_string_array_count>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movl   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L13
  mov    %rdi,%r12
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L13
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L6:
  call   <strlen@plt>
  mov    %ebx,%r13d
  mov    0x0(%rbp),%edx
  add    $0x1,%rbx
  mov    (%r12,%rbx,8),%rdi
  lea    0x9(%rdx,%rax,1),%eax
  mov    %eax,0x0(%rbp)
  test   %rdi,%rdi
  jne    L6
  mov    %eax,%ecx
  lea    0x8(%rax),%edx
  add    $0x10,%eax
  add    $0x2,%r13d
  and    $0x7,%ecx
  sub    %ecx,%eax
  test   %ecx,%ecx
  cmove  %edx,%eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _lms_string_array_count(const char *const *array, int *size) {
  int count, align_overflow;
  *size = 0;
  if (!array)
    return 0;
  count = 0;
  for (; *array != NULL; array++) {
    *size += sizeof(char *) + strlen(*array) + 1;
    count++;
  }
  if (count) {
    count++;
    *size += sizeof(char *);
  }
  align_overflow = *size % sizeof(char *);
  if (align_overflow)
    *size += sizeof(char *) - align_overflow;
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x70,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <new_label@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <post_label@plt>
  mov    $0x0,%eax
  call   <block@plt>
  mov    $0x65,%edi
  call   <match@plt>
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rcx
  lea    D2(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <emitln@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: BRA %s

assistant: ```c
void do_loop(void) {
  char *label;
  char brastr[32];
  match('p');
  label = new_label();
  post_label(label);
  block();
  match('e');
  snprintf(brastr, 32, "BRA %s", label);
  emitln(brastr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_loop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x70,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <new_label@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <post_label@plt>
  mov    $0x0,%eax
  call   <block@plt>
  mov    $0x65,%edi
  call   <match@plt>
  mov    %rsp,%rbp
  mov    %rbx,%rcx
  lea    D1(%rip),%rdx
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <emitln@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: BRA %s

assistant: ```c
void do_loop(void) {
  char *label;
  char brastr[32];
  match('p');
  label = new_label();
  post_label(label);
  block();
  match('e');
  snprintf(brastr, 32, "BRA %s", label);
  emitln(brastr);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<do_loop>:
  endbr64
  push   %r12
  mov    $0x70,%edi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <match@plt>
  xor    %eax,%eax
  call   <new_label@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <post_label@plt>
  xor    %eax,%eax
  call   <block@plt>
  mov    $0x65,%edi
  call   <match@plt>
  mov    %rbp,%rdi
  mov    %r12,%rcx
  mov    $0x20,%esi
  lea    D9(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <emitln@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: BRA %s

assistant: ```c
void do_loop(void) {
  char *label;
  char brastr[32];
  match('p');
  label = new_label();
  post_label(label);
  block();
  match('e');
  snprintf(brastr, 32, "BRA %s", label);
  emitln(brastr);
}
```