user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<date2yyyymm>:
  endbr64
  mov    %rdi,%rdx
  movzbl (%rdi),%eax
  mov    %eax,%esi
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L135
  cmp    $0x20,%al
  jne    L94
L135:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  mov    %eax,%esi
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L135
  cmp    $0x20,%al
  je     L135
L94:
  mov    $0x0,%ecx
  test   %al,%al
  je     L199
  sub    $0x20,%esi
  cmp    $0x60,%al
  cmovg  %esi,%eax
  movzbl 0x1(%rdx),%esi
  test   %sil,%sil
  je     L199
  lea    -0x20(%rsi),%ecx
  cmp    $0x60,%sil
  cmovg  %ecx,%esi
  movzbl 0x2(%rdx),%edi
  mov    $0x0,%ecx
  test   %dil,%dil
  je     L199
  lea    -0x20(%rdi),%ecx
  cmp    $0x60,%dil
  cmovg  %ecx,%edi
  sub    $0x41,%eax
  cmp    $0x12,%al
  ja     L343
  movzbl %al,%eax
  lea    D3(%rip),%rcx
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  cmp    $0x41,%sil
  jne    L347
  mov    $0x1,%r8d
  cmp    $0x4e,%dil
  je     L437
L347:
  mov    $0x0,%ecx
  cmp    $0x55,%sil
  jne    L199
  cmp    $0x4e,%dil
  je     L215
  cmp    $0x4c,%dil
  jne    L199
  mov    $0x7,%r8d
  jmp    L437
  cmp    $0x45,%sil
  jne    L260
  mov    $0x2,%r8d
  cmp    $0x42,%dil
  je     L437
L260:
  mov    $0x0,%ecx
  jmp    L199
  cmp    $0x50,%sil
  jne    L223
  mov    $0x4,%r8d
  cmp    $0x52,%dil
  je     L437
L223:
  cmp    $0x55,%sil
  jne    L354
  mov    $0x8,%r8d
  cmp    $0x47,%dil
  je     L437
L354:
  mov    $0x0,%ecx
  jmp    L199
  mov    $0x0,%ecx
  cmp    $0x41,%sil
  jne    L199
  cmp    $0x52,%dil
  je     L425
  cmp    $0x59,%dil
  jne    L199
  mov    $0x5,%r8d
  jmp    L437
  cmp    $0x45,%sil
  jne    L263
  mov    $0x9,%r8d
  cmp    $0x50,%dil
  je     L437
L263:
  mov    $0x0,%ecx
  jmp    L199
  cmp    $0x43,%sil
  jne    L228
  mov    $0xa,%r8d
  cmp    $0x54,%dil
  je     L437
L228:
  mov    $0x0,%ecx
  jmp    L199
  cmp    $0x4f,%sil
  jne    L95
  mov    $0xb,%r8d
  cmp    $0x56,%dil
  je     L437
L95:
  mov    $0x0,%ecx
  jmp    L199
  cmp    $0x45,%sil
  jne    L133
  cmp    $0x43,%dil
  jne    L133
  mov    $0xc,%r8d
L437:
  mov    $0x0,%ecx
  cmpb   $0x20,0x3(%rdx)
  jne    L199
  lea    0x5(%rdx),%rsi
  movzbl 0x4(%rdx),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L233
L110:
  lea    (%rcx,%rcx,4),%edx
  movzbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%ecx
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L110
  test   %ecx,%ecx
  je     L199
  imul   $0x64,%ecx,%ecx
  add    %r8d,%ecx
  jmp    L199
L215:
  mov    $0x6,%r8d
  jmp    L437
L425:
  mov    $0x3,%r8d
  jmp    L437
L343:
  mov    $0x0,%ecx
L199:
  mov    %ecx,%eax
  ret
L133:
  mov    $0x0,%ecx
  jmp    L199
L233:
  mov    $0x0,%ecx
  jmp    L199
```

assistant: ```c
unsigned int date2yyyymm(const char *s) {
  unsigned int mo;
  unsigned int year;
  char ch, ch1, ch2;
  for (;; s++) {
    ch = *s;
    if (ch != ' ' && (ch < '0' || ch > '9'))
      break;
  }
  mo = 0;
  if (!(ch = *(s++)))
    return 0;
  if (ch >= 'a')
    ch -= ('a' - 'A');
  if (!(ch1 = *(s++)))
    return 0;
  if (ch1 >= 'a')
    ch1 -= ('a' - 'A');
  if (!(ch2 = *(s++)))
    return 0;
  if (ch2 >= 'a')
    ch2 -= ('a' - 'A');
  switch (ch) {
  case 'J':
    if (ch1 == 'A' && ch2 == 'N') {
      mo = 1;
      break;
    }
    if (ch1 == 'U') {
      if (ch2 == 'N')
        mo = 6;
      else if (ch2 == 'L')
        mo = 7;
    }
    break;
  case 'F':
    if (ch1 == 'E' && ch2 == 'B')
      mo = 2;
    break;
  case 'A':
    if (ch1 == 'P' && ch2 == 'R')
      mo = 4;
    else if (ch1 == 'U' && ch2 == 'G')
      mo = 8;
    break;
  case 'M':
    if (ch1 != 'A')
      break;
    if (ch2 == 'R')
      mo = 3;
    else if (ch2 == 'Y')
      mo = 5;
    break;
  case 'S':
    if (ch1 == 'E' && ch2 == 'P')
      mo = 9;
    break;
  case 'O':
    if (ch1 == 'C' && ch2 == 'T')
      mo = 10;
    break;
  case 'N':
    if (ch1 == 'O' && ch2 == 'V')
      mo = 11;
    break;
  case 'D':
    if (ch1 == 'E' && ch2 == 'C')
      mo = 12;
    break;
  default:
    break;
  }
  if (!mo || *(s++) != ' ')
    return 0L;
  year = 0L;
  for (;;) {
    unsigned char chy;
    chy = (unsigned char)*(s++);
    if (chy < '0' || chy > '9') {
      if (year)
        break;
      else
        return 0;
    }
    year = year * 10 + (chy - '0');
  }
  return year * 100 + mo;
}
```