ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ts_packet_get_pcr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ts_packet_get_pcr_ex@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
uint64_t ts_packet_get_pcr(uint8_t *ts_packet) {
  uint64_t pcr_base;
  uint16_t pcr_ext;
  return ts_packet_get_pcr_ex(ts_packet, &pcr_base, &pcr_ext);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ts_packet_get_pcr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <ts_packet_get_pcr_ex@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t ts_packet_get_pcr(uint8_t *ts_packet) {
  uint64_t pcr_base;
  uint16_t pcr_ext;
  return ts_packet_get_pcr_ex(ts_packet, &pcr_base, &pcr_ext);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ts_packet_get_pcr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <ts_packet_get_pcr_ex@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t ts_packet_get_pcr(uint8_t *ts_packet) {
  uint64_t pcr_base;
  uint16_t pcr_ext;
  return ts_packet_get_pcr_ex(ts_packet, &pcr_base, &pcr_ext);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ts_packet_get_pcr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <ts_packet_get_pcr_ex@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t ts_packet_get_pcr(uint8_t *ts_packet) {
  uint64_t pcr_base;
  uint16_t pcr_ext;
  return ts_packet_get_pcr_ex(ts_packet, &pcr_base, &pcr_ext);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L23:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L23
  sub    $0xe40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L59
L104:
  lea    -0x4e30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4e34(%rbp)
  movl   $0x0,-0x4e38(%rbp)
  movl   $0x0,-0x4e3c(%rbp)
  jmp    L92
L18:
  mov    -0x4e3c(%rbp),%eax
  cltq
  movzbl -0x4e30(%rbp,%rax,1),%eax
  cmp    $0x40,%al
  jle    L11
  mov    -0x4e3c(%rbp),%eax
  cltq
  movzbl -0x4e30(%rbp,%rax,1),%eax
  cmp    $0x5a,%al
  jle    L71
L11:
  mov    -0x4e3c(%rbp),%eax
  cltq
  movzbl -0x4e30(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  jle    L45
  mov    -0x4e3c(%rbp),%eax
  cltq
  movzbl -0x4e30(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L45
L71:
  mov    -0x4e3c(%rbp),%eax
  cltq
  movzbl -0x4e30(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x4e38(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x2720(%rbp,%rdx,1)
  addl   $0x1,-0x4e38(%rbp)
L45:
  addl   $0x1,-0x4e3c(%rbp)
L92:
  mov    -0x4e3c(%rbp),%eax
  cmp    -0x4e34(%rbp),%eax
  jl     L18
  mov    -0x4e38(%rbp),%eax
  cltq
  movb   $0x0,-0x2720(%rbp,%rax,1)
  lea    -0x4e30(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L96
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <ispalindrome@plt>
  test   %rax,%rax
  je     L14
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L59
L14:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L59:
  lea    -0x4e30(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L104
  jmp    L91
L96:
  nop
L91:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string
name: unpack_data
arguments: tag: D28
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string

tool: D4: DONE

tool: D28: You won't be eaten!


tool: D17: Uh oh..


assistant: ```c
int main() {
  char in[10000], a[10000];
  int i, j, len;
  while (gets(in)) {
    len = strlen(in);
    j = 0;
    for (i = 0; i < len; i++) {
      if (in[i] >= 'A' && in[i] <= 'Z' || in[i] >= 'a' && in[i] <= 'z') {
        a[j] = tolower(in[i]);
        j++;
      }
    }
    a[j] = '\0';
    if (strcasecmp(in, "DONE") == 0)
      break;
    else if (ispalindrome(a))
      printf("You won't be eaten!\n");
    else
      printf("Uh oh..\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L39:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L39
  sub    $0xe38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    D1(%rip),%r14
  lea    D29(%rip),%r15
  jmp    L48
L100:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L38
L105:
  movzbl (%rbx),%edi
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L100
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  movslq %ebp,%rax
  mov    %dl,0x2710(%rsp,%rax,1)
  add    $0x1,%ebp
  jmp    L100
L43:
  mov    $0x0,%ebp
L38:
  movslq %ebp,%rbp
  movb   $0x0,0x2710(%rsp,%rbp,1)
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L57
  lea    0x2710(%rsp),%rdi
  call   <ispalindrome@plt>
  test   %rax,%rax
  je     L78
  lea    D25(%rip),%rdi
  call   <printf@plt>
L48:
  mov    %r13,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L57
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L43
  mov    %rsp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rsp,%rax,1),%r12
  mov    $0x0,%ebp
  jmp    L105
L78:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L48
L57:
  mov    0x4e28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x4e38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D29
type_infered: string
name: read_data
arguments: data_label: D25
type_infered: string

tool: D1: DONE

tool: D29: Uh oh..


tool: D25: You won't be eaten!


assistant: ```c
int main() {
  char in[10000], a[10000];
  int i, j, len;
  while (gets(in)) {
    len = strlen(in);
    j = 0;
    for (i = 0; i < len; i++) {
      if (in[i] >= 'A' && in[i] <= 'Z' || in[i] >= 'a' && in[i] <= 'z') {
        a[j] = tolower(in[i]);
        j++;
      }
    }
    a[j] = '\0';
    if (strcasecmp(in, "DONE") == 0)
      break;
    else if (ispalindrome(a))
      printf("You won't be eaten!\n");
    else
      printf("Uh oh..\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L7:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L7
  sub    $0xe38,%rsp
  lea    D19(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x4e28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1(%rsp),%r13
L40:
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L5
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L48
  lea    -0x1(%rax),%ecx
  mov    %rbp,%rbx
  xor    %r14d,%r14d
  lea    (%rcx,%r13,1),%r15
  jmp    L60
L102:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L32
L60:
  movsbl (%rbx),%edi
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L102
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %eax,%r8d
  movslq %r14d,%rax
  add    $0x1,%r14d
  mov    %r8b,0x2710(%rsp,%rax,1)
  cmp    %r15,%rbx
  jne    L60
L32:
  movslq %r14d,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x2710(%rsp,%rdx,1)
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L5
  lea    0x2710(%rsp),%rdi
  call   <ispalindrome@plt>
  test   %rax,%rax
  je     L9
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L15
L5:
  mov    0x4e28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x4e38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L9:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L40
  nopl   0x0(%rax)
L48:
  xor    %r14d,%r14d
  jmp    L32
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type: string
name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D28
type: string

tool: D19: DONE

tool: D1: You won't be eaten!


tool: D28: Uh oh..


assistant: ```c
int main() {
  char in[10000], a[10000];
  int i, j, len;
  while (gets(in)) {
    len = strlen(in);
    j = 0;
    for (i = 0; i < len; i++) {
      if (in[i] >= 'A' && in[i] <= 'Z' || in[i] >= 'a' && in[i] <= 'z') {
        a[j] = tolower(in[i]);
        j++;
      }
    }
    a[j] = '\0';
    if (strcasecmp(in, "DONE") == 0)
      break;
    else if (ispalindrome(a))
      printf("You won't be eaten!\n");
    else
      printf("Uh oh..\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L128:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L128
  sub    $0xe38,%rsp
  lea    D17(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x4e28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1(%rsp),%r13
L19:
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L66
L60:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L123
  lea    -0x1(%rax),%ecx
  mov    %rbp,%rbx
  xor    %r14d,%r14d
  lea    (%rcx,%r13,1),%r15
  jmp    L13
L125:
  add    $0x1,%rbx
  cmp    %rbx,%r15
  je     L41
L13:
  movsbl (%rbx),%edi
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L125
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %eax,%r8d
  movslq %r14d,%rax
  add    $0x1,%r14d
  mov    %r8b,0x2710(%rsp,%rax,1)
  cmp    %rbx,%r15
  jne    L13
L41:
  movslq %r14d,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x2710(%rsp,%rdx,1)
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L66
  lea    0x2710(%rsp),%rdi
  call   <ispalindrome@plt>
  test   %rax,%rax
  je     L31
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L60
L66:
  mov    0x4e28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x4e38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L31:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L19
  nopl   0x0(%rax)
L123:
  xor    %r14d,%r14d
  jmp    L41
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
data_type: string
name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D26
data_type: string

tool: D17: DONE

tool: D14: You won't be eaten!


tool: D26: Uh oh..


assistant: ```c
int main() {
  char in[10000], a[10000];
  int i, j, len;
  while (gets(in)) {
    len = strlen(in);
    j = 0;
    for (i = 0; i < len; i++) {
      if (in[i] >= 'A' && in[i] <= 'Z' || in[i] >= 'a' && in[i] <= 'z') {
        a[j] = tolower(in[i]);
        j++;
      }
    }
    a[j] = '\0';
    if (strcasecmp(in, "DONE") == 0)
      break;
    else if (ispalindrome(a))
      printf("You won't be eaten!\n");
    else
      printf("Uh oh..\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_time_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <gmtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0xc(%rax),%edi
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%ecx
  mov    -0x10(%rbp),%rax
  mov    0x14(%rax),%r9d
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%r8d
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x76c(%rax),%esi
  mov    -0x28(%rbp),%rax
  push   %rdi
  push   %rcx
  mov    %edx,%ecx
  mov    %esi,%edx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: %04d%02d%02d%02d%02d%02d00

assistant: ```c
void get_time_string(char *str) {
  struct tm *current;
  time_t timestamp = time(NULL);
  current = gmtime(&timestamp);
  sprintf(str, "%04d%02d%02d%02d%02d%02d00", current->tm_year + 1900, current->tm_mon, current->tm_mday, current->tm_hour, current->tm_min, current->tm_sec);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_time_string>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  mov    0x14(%rax),%r9d
  mov    0x8(%rax),%r8d
  mov    0x4(%rax),%ecx
  mov    (%rax),%edx
  add    $0x76c,%edx
  mov    0xc(%rax),%esi
  push   %rsi
  mov    0x10(%rax),%eax
  push   %rax
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: %04d%02d%02d%02d%02d%02d00

assistant: ```c
void get_time_string(char *str) {
  struct tm *current;
  time_t timestamp = time(NULL);
  current = gmtime(&timestamp);
  sprintf(str, "%04d%02d%02d%02d%02d%02d00", current->tm_year + 1900, current->tm_mon, current->tm_mday, current->tm_hour, current->tm_min, current->tm_sec);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_time_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  mov    %rbp,%rdi
  mov    0xc(%rax),%esi
  mov    (%rax),%edx
  mov    0x14(%rax),%r9d
  mov    0x8(%rax),%r8d
  mov    0x4(%rax),%ecx
  push   %rsi
  add    $0x76c,%edx
  lea    D4(%rip),%rsi
  mov    0x10(%rax),%eax
  push   %rax
  call   <sprintf@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string

tool: D4: %04d%02d%02d%02d%02d%02d00

assistant: ```c
void get_time_string(char *str) {
  struct tm *current;
  time_t timestamp = time(NULL);
  current = gmtime(&timestamp);
  sprintf(str, "%04d%02d%02d%02d%02d%02d00", current->tm_year + 1900, current->tm_mon, current->tm_mday, current->tm_hour, current->tm_min, current->tm_sec);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_time_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  mov    %rbp,%rdi
  mov    0xc(%rax),%esi
  mov    (%rax),%edx
  mov    0x14(%rax),%r9d
  mov    0x8(%rax),%r8d
  mov    0x4(%rax),%ecx
  push   %rsi
  add    $0x76c,%edx
  lea    D8(%rip),%rsi
  mov    0x10(%rax),%eax
  push   %rax
  call   <sprintf@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: %04d%02d%02d%02d%02d%02d00

assistant: ```c
void get_time_string(char *str) {
  struct tm *current;
  time_t timestamp = time(NULL);
  current = gmtime(&timestamp);
  sprintf(str, "%04d%02d%02d%02d%02d%02d00", current->tm_year + 1900, current->tm_mon, current->tm_mday, current->tm_hour, current->tm_min, current->tm_sec);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L0
L5:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strxcmp@plt>
  test   %eax,%eax
  jne    L19
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,-0x18(%rbp)
  jmp    L32
L19:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L32:
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jg     L23
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L23:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void replace(char s[], char str[], char new[]) {
  int i, j, n = strlen(s), n1 = strlen(str), n2 = strlen(new);
  char *o = malloc(strlen(s) + 1);
  strcpy(o, s);
  for (i = j = 0; n - i >= n1 && o[i]; i++, j++)
    if (!strxcmp(o + i, str, n1)) {
      i += n1 - 1;
      strcpy(s + j, new);
      j += n2 - 1;
    } else
      s[j] = o[i];
  free(o);
}
```
user: Translate the below assembly code into C programming language:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%rbx
  mov    %rdx,0x10(%rsp)
  call   <strlen@plt>
  mov    %eax,%r15d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,0x18(%rsp)
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    -0x1(%r13),%eax
  mov    %eax,0x1c(%rsp)
  cmp    %r13d,%r15d
  jge    L21
L10:
  mov    (%rsp),%rdi
  call   <free@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  add    0x1c(%rsp),%ebp
  movslq %r12d,%rdi
  add    %r14,%rdi
  mov    0x10(%rsp),%rsi
  call   <strcpy@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax,%r12,1),%r12d
L31:
  add    $0x1,%ebp
  add    $0x1,%r12d
  mov    %r15d,%eax
  sub    %ebp,%eax
  cmp    %r13d,%eax
  jl     L10
L21:
  movslq %ebp,%rbx
  add    (%rsp),%rbx
  cmpb   $0x0,(%rbx)
  je     L10
  mov    %r13d,%edx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strxcmp@plt>
  test   %eax,%eax
  je     L32
  movzbl (%rbx),%edx
  movslq %r12d,%rax
  mov    %dl,(%r14,%rax,1)
  jmp    L31
```

assistant: ```c
void replace(char s[], char str[], char new[]) {
  int i, j, n = strlen(s), n1 = strlen(str), n2 = strlen(new);
  char *o = malloc(strlen(s) + 1);
  strcpy(o, s);
  for (i = j = 0; n - i >= n1 && o[i]; i++, j++)
    if (!strxcmp(o + i, str, n1)) {
      i += n1 - 1;
      strcpy(s + j, new);
      j += n2 - 1;
    } else
      s[j] = o[i];
  free(o);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<replace>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,0x10(%rsp)
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,0xc(%rsp)
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r15,%rdi
  xor    %r15d,%r15d
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0x18(%rsp)
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <strcpy@plt>
  lea    -0x1(%rbx),%eax
  mov    %eax,0x1c(%rsp)
  cmp    %ebx,%r12d
  jge    L11
  jmp    L8
  nopl   (%rax)
L25:
  movzbl (%r12),%eax
  mov    %al,(%rdi)
L1:
  mov    0xc(%rsp),%eax
  add    $0x1,%r15d
  add    $0x1,%r13d
  sub    %r15d,%eax
  cmp    %ebx,%eax
  jl     L8
L11:
  mov    (%rsp),%rax
  movslq %r15d,%rcx
  lea    (%rax,%rcx,1),%r12
  cmpb   $0x0,(%r12)
  je     L8
  mov    %r12,%rdi
  mov    %ebx,%edx
  mov    %r14,%rsi
  call   <strxcmp@plt>
  movslq %r13d,%rdi
  add    %rbp,%rdi
  test   %eax,%eax
  jne    L25
  mov    0x10(%rsp),%rsi
  add    0x1c(%rsp),%r15d
  call   <strcpy@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax,%r13,1),%r13d
  jmp    L1
  nopl   (%rax)
L8:
  mov    (%rsp),%rdi
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
```

assistant: ```c
void replace(char s[], char str[], char new[]) {
  int i, j, n = strlen(s), n1 = strlen(str), n2 = strlen(new);
  char *o = malloc(strlen(s) + 1);
  strcpy(o, s);
  for (i = j = 0; n - i >= n1 && o[i]; i++, j++)
    if (!strxcmp(o + i, str, n1)) {
      i += n1 - 1;
      strcpy(s + j, new);
      j += n2 - 1;
    } else
      s[j] = o[i];
  free(o);
}
```