ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x78(%rbp)
  mov    -0x78(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x7c(%rbp)
  movl   $0x0,-0x80(%rbp)
  jmp    L16
L4:
  mov    -0x80(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,-0x74(%rbp)
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x80(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x74(%rbp),%eax
  mov    %eax,%edx
  mov    -0x7c(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  subl   $0x1,-0x7c(%rbp)
  addl   $0x1,-0x80(%rbp)
L16:
  mov    -0x80(%rbp),%eax
  cmp    -0x7c(%rbp),%eax
  jl     L4
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int main() {
  char niz[100];
  int l;
  int x;
  int i;
  int b;
  gets(niz);
  l = strlen(niz);
  for (i = l - 1, x = 0; x < i; i--, x++) {
    b = niz[x];
    niz[x] = niz[i];
    niz[i] = b;
  }
  puts(niz);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L13
  mov    %rsp,%rsi
  movslq %eax,%rdx
  add    %rbx,%rdx
L4:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rsi)
  mov    %dil,-0x1(%rdx)
  mov    %ecx,%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %eax,%edi
  sub    %r8d,%edi
  cmp    %edi,%ecx
  jg     L4
L13:
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char niz[100];
  int l;
  int x;
  int i;
  int b;
  gets(niz);
  l = strlen(niz);
  for (i = l - 1, x = 0; x < i; i--, x++) {
    b = niz[x];
    niz[x] = niz[i];
    niz[i] = b;
  }
  puts(niz);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L29
  movslq %eax,%rdx
  mov    %rbp,%rsi
  add    %rbp,%rdx
  nopl   0x0(%rax)
L7:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jg     L7
L29:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char niz[100];
  int l;
  int x;
  int i;
  int b;
  gets(niz);
  l = strlen(niz);
  for (i = l - 1, x = 0; x < i; i--, x++) {
    b = niz[x];
    niz[x] = niz[i];
    niz[i] = b;
  }
  puts(niz);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L15
  movslq %eax,%rdx
  mov    %rbp,%rsi
  add    %rbp,%rdx
  nopl   0x0(%rax)
L21:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jg     L21
L15:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char niz[100];
  int l;
  int x;
  int i;
  int b;
  gets(niz);
  l = strlen(niz);
  for (i = l - 1, x = 0; x < i; i--, x++) {
    b = niz[x];
    niz[x] = niz[i];
    niz[i] = b;
  }
  puts(niz);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pathcon_nm4_name_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  cmpl   $0x1,-0x4(%rbp)
  je     L49
  jmp    L46
L13:
  lea    D1(%rip),%rax
  jmp    L20
L49:
  lea    D0(%rip),%rax
  jmp    L20
L46:
  mov    $0x0,%eax
L20:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string

tool: D1: o0

tool: D0: o1

assistant: ```c
const char *pathcon_nm4_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pathcon_nm4_name_out>:
  endbr64
  lea    D1(%rip),%rax
  test   %edi,%edi
  je     L0
  cmp    $0x1,%edi
  lea    D15(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D15
datatype: string

tool: D1: o0

tool: D15: o1

assistant: ```c
const char *pathcon_nm4_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pathcon_nm4_name_out>:
  endbr64
  lea    D11(%rip),%rax
  test   %edi,%edi
  je     L0
  cmp    $0x1,%edi
  lea    D10(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
datatype: string
name: retrieve_data
arguments: data_label: D10
datatype: string

tool: D11: o0

tool: D10: o1

assistant: ```c
const char *pathcon_nm4_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pathcon_nm4_name_out>:
  endbr64
  lea    D10(%rip),%rax
  test   %edi,%edi
  je     L0
  cmp    $0x1,%edi
  lea    D4(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type: string
name: read_data
arguments: data_tag: D4
type: string

tool: D10: o0

tool: D4: o1

assistant: ```c
const char *pathcon_nm4_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<distance_l2_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L17:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double distance_l2_double(double *p1, double *p2, int len) {
  double ret = 0;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
  }
  return sqrt(ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<distance_l2_double>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  jle    L48
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
L20:
  movsd  (%r12,%rbx,8),%xmm0
  subsd  0x0(%r13,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L20
  pxor   %xmm0,%xmm0
  ucomisd 0x8(%rsp),%xmm0
  ja     L32
L2:
  movsd  0x8(%rsp),%xmm0
  sqrtsd %xmm0,%xmm0
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L2
L32:
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L7
```

assistant: ```c
double distance_l2_double(double *p1, double *p2, int len) {
  double ret = 0;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
  }
  return sqrt(ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<distance_l2_double>:
  endbr64
  test   %edx,%edx
  jle    L9
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L27:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  add    $0x1,%rbx
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L27
  pxor   %xmm2,%xmm2
  ucomisd %xmm1,%xmm2
  ja     L26
  sqrtsd %xmm1,%xmm1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  movapd %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L9:
  pxor   %xmm1,%xmm1
  sqrtsd %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
L26:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double distance_l2_double(double *p1, double *p2, int len) {
  double ret = 0;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
  }
  return sqrt(ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<distance_l2_double>:
  endbr64
  test   %edx,%edx
  jle    L3
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L25:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  add    $0x1,%rbx
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L25
  pxor   %xmm2,%xmm2
  ucomisd %xmm1,%xmm2
  ja     L17
  sqrtsd %xmm1,%xmm1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  movapd %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L3:
  pxor   %xmm1,%xmm1
  sqrtsd %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
L17:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double distance_l2_double(double *p1, double *p2, int len) {
  double ret = 0;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
  }
  return sqrt(ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fs_parent_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fs_basepath@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fs_mode@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: %s, %s, %d


assistant: ```c
int fs_parent_mode(const char *restrict filename) {
  int returnValue = 0;
  char *restrict basepath = fs_basepath(filename);
  printf("%s, %s, %d\n", basepath, filename, returnValue);
  returnValue = fs_mode(basepath);
  free(basepath);
  return returnValue;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fs_parent_mode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <fs_basepath@plt>
  mov    %rax,%rbx
  mov    $0x0,%ecx
  mov    %rbp,%rdx
  mov    %rax,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <fs_mode@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string

tool: D6: %s, %s, %d


assistant: ```c
int fs_parent_mode(const char *restrict filename) {
  int returnValue = 0;
  char *restrict basepath = fs_basepath(filename);
  printf("%s, %s, %d\n", basepath, filename, returnValue);
  returnValue = fs_mode(basepath);
  free(basepath);
  return returnValue;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fs_parent_mode>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <fs_basepath@plt>
  mov    %r12,%rdx
  xor    %ecx,%ecx
  lea    D9(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fs_mode@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: %s, %s, %d


assistant: ```c
int fs_parent_mode(const char *restrict filename) {
  int returnValue = 0;
  char *restrict basepath = fs_basepath(filename);
  printf("%s, %s, %d\n", basepath, filename, returnValue);
  returnValue = fs_mode(basepath);
  free(basepath);
  return returnValue;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fs_parent_mode>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <fs_basepath@plt>
  mov    %r12,%rdx
  xor    %ecx,%ecx
  lea    D3(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fs_mode@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: %s, %s, %d


assistant: ```c
int fs_parent_mode(const char *restrict filename) {
  int returnValue = 0;
  char *restrict basepath = fs_basepath(filename);
  printf("%s, %s, %d\n", basepath, filename, returnValue);
  returnValue = fs_mode(basepath);
  free(basepath);
  return returnValue;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CPLNaN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7fc00000,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movss  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
float CPLNaN(void) {
  float fNan;
  int nNan = 0x7FC00000;
  memcpy(&fNan, &nNan, 4);
  return fNan;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CPLNaN>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x7fc00000,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  movss  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float CPLNaN(void) {
  float fNan;
  int nNan = 0x7FC00000;
  memcpy(&fNan, &nNan, 4);
  return fNan;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CPLNaN>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x7fc00000,0x4(%rsp)
  call   <memcpy@plt>
  movss  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float CPLNaN(void) {
  float fNan;
  int nNan = 0x7FC00000;
  memcpy(&fNan, &nNan, 4);
  return fNan;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CPLNaN>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x7fc00000,0x4(%rsp)
  call   <memcpy@plt>
  movss  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float CPLNaN(void) {
  float fNan;
  int nNan = 0x7FC00000;
  memcpy(&fNan, &nNan, 4);
  return fNan;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <inarray@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L8
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
L8:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void delete (char **array, int *len, const char *string) {
  int pos = inarray((const char **)array, *len, string);
  int last = *len - 1;
  if (pos != last) {
    array[pos] = array[last];
  }
  (*len)--;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<delete>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    (%rsi),%esi
  call   <inarray@plt>
  mov    (%rbx),%ecx
  lea    -0x1(%rcx),%edx
  cmp    %edx,%eax
  je     L2
  movslq %edx,%rdx
  mov    0x0(%rbp,%rdx,8),%rdx
  cltq
  mov    %rdx,0x0(%rbp,%rax,8)
L2:
  subl   $0x1,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void delete (char **array, int *len, const char *string) {
  int pos = inarray((const char **)array, *len, string);
  int last = *len - 1;
  if (pos != last) {
    array[pos] = array[last];
  }
  (*len)--;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delete>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%esi
  call   <inarray@plt>
  mov    (%rbx),%ecx
  lea    -0x1(%rcx),%edx
  cmp    %edx,%eax
  je     L4
  movslq %edx,%rcx
  cltq
  mov    0x0(%rbp,%rcx,8),%rcx
  mov    %rcx,0x0(%rbp,%rax,8)
L4:
  mov    %edx,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void delete (char **array, int *len, const char *string) {
  int pos = inarray((const char **)array, *len, string);
  int last = *len - 1;
  if (pos != last) {
    array[pos] = array[last];
  }
  (*len)--;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<delete>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%esi
  call   <inarray@plt>
  mov    (%rbx),%ecx
  lea    -0x1(%rcx),%edx
  cmp    %edx,%eax
  je     L7
  movslq %edx,%rcx
  cltq
  mov    0x0(%rbp,%rcx,8),%rcx
  mov    %rcx,0x0(%rbp,%rax,8)
L7:
  mov    %edx,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void delete (char **array, int *len, const char *string) {
  int pos = inarray((const char **)array, *len, string);
  int last = *len - 1;
  if (pos != last) {
    array[pos] = array[last];
  }
  (*len)--;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_160_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_160_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = *D & T;
  *D = stk1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rop3_160_0_0>:
  endbr64
  and    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_160_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = *D & T;
  *D = stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rop3_160_0_0>:
  endbr64
  and    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_160_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = *D & T;
  *D = stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rop3_160_0_0>:
  endbr64
  and    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_160_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = *D & T;
  *D = stk1;
}
```