ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ceil>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edi,%eax
  sub    %edx,%esi
  add    %edi,%esi
  test   %edx,%edx
  cmovne %esi,%eax
  ret
```

assistant: ```c
uint64_t ceil(const uint64_t x, const uint64_t y) {
  if (x % y == 0) {
    return x;
  }
  return x + (y - (x % y));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ceil>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edi,%eax
  sub    %edx,%esi
  add    %edi,%esi
  test   %edx,%edx
  cmovne %esi,%eax
  ret
```

assistant: ```c
uint64_t ceil(const uint64_t x, const uint64_t y) {
  if (x % y == 0) {
    return x;
  }
  return x + (y - (x % y));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pathconf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L17
  mov    $0xffffffffffffffff,%rax
  jmp    L0
L17:
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fpathconf@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
long pathconf(const char *path, int name) {
  int fd;
  long val;
  if ((fd = open(path, O_RDONLY)) < 0)
    return (-1L);
  val = fpathconf(fd, name);
  close(fd);
  return (val);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pathconf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L0
  mov    %eax,%ebx
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <fpathconf@plt>
  mov    %rax,%rbp
  mov    %ebx,%edi
  call   <close@plt>
L7:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0xffffffffffffffff,%rbp
  jmp    L7
```

assistant: ```c
long pathconf(const char *path, int name) {
  int fd;
  long val;
  if ((fd = open(path, O_RDONLY)) < 0)
    return (-1L);
  val = fpathconf(fd, name);
  close(fd);
  return (val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pathconf>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L0
  mov    %eax,%ebp
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <fpathconf@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <close@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffffffffffff,%r12
  jmp    L7
```

assistant: ```c
long pathconf(const char *path, int name) {
  int fd;
  long val;
  if ((fd = open(path, O_RDONLY)) < 0)
    return (-1L);
  val = fpathconf(fd, name);
  close(fd);
  return (val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pathconf>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L1
  mov    %eax,%ebp
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <fpathconf@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <close@plt>
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    $0xffffffffffffffff,%r12
  jmp    L11
```

assistant: ```c
long pathconf(const char *path, int name) {
  int fd;
  long val;
  if ((fd = open(path, O_RDONLY)) < 0)
    return (-1L);
  val = fpathconf(fd, name);
  close(fd);
  return (val);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<min_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L48
  movl   $0x0,-0x10(%rbp)
  jmp    L35
L34:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L16
L45:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L50
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L50:
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L45
  nop
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x10(%rbp)
L35:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L34
  jmp    L15
L48:
  nop
L15:
  leave
  ret
```

assistant: ```c
void min_sort(int t[], int n) {
  int i, j;
  int mi, mv;
  if (n <= 0)
    return;
  for (i = 0; i < n - 1; i++) {
    mv = t[i];
    mi = i;
    for (j = i + 1; j < n; j++) {
      if (t[j] < mv) {
        mi = j;
        mv = t[j];
      }
    }
  L:
    swap(t, i, mi);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<min_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L35
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%r13d
  mov    $0x1,%r12d
  jmp    L45
L76:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jle    L1
L43:
  mov    (%rbx,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L76
  mov    %edx,%ecx
  mov    %eax,%esi
  jmp    L76
L52:
  mov    %edi,%esi
L1:
  mov    %esi,%edx
  mov    %edi,%esi
  mov    %rbx,%rdi
  call   <swap@plt>
  add    $0x1,%r12
  cmp    %r13,%r12
  je     L14
L45:
  lea    -0x1(%r12),%edi
  mov    -0x4(%rbx,%r12,4),%ecx
  cmp    %r12d,%ebp
  jle    L52
  mov    %r12,%rax
  mov    %edi,%esi
  jmp    L43
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  ret
```

assistant: ```c
void min_sort(int t[], int n) {
  int i, j;
  int mi, mv;
  if (n <= 0)
    return;
  for (i = 0; i < n - 1; i++) {
    mv = t[i];
    mi = i;
    for (j = i + 1; j < n; j++) {
      if (t[j] < mv) {
        mi = j;
        mv = t[j];
      }
    }
  L:
    swap(t, i, mi);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<min_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L31
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L28:
  mov    -0x4(%rbx,%r13,4),%ecx
  lea    -0x1(%r13),%esi
  cmp    %r13d,%ebp
  jle    L24
  mov    %r13,%rax
  mov    %esi,%r8d
  nopl   0x0(%rax)
L38:
  mov    (%rbx,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L11
  mov    %edx,%ecx
  mov    %eax,%r8d
L11:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L38
L3:
  mov    %r8d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r13
  call   <swap@plt>
  cmp    %r12,%r13
  jne    L28
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %esi,%r8d
  jmp    L3
L31:
  ret
```

assistant: ```c
void min_sort(int t[], int n) {
  int i, j;
  int mi, mv;
  if (n <= 0)
    return;
  for (i = 0; i < n - 1; i++) {
    mv = t[i];
    mi = i;
    for (j = i + 1; j < n; j++) {
      if (t[j] < mv) {
        mi = j;
        mv = t[j];
      }
    }
  L:
    swap(t, i, mi);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<min_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L31
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L21:
  mov    -0x4(%rbx,%r13,4),%ecx
  lea    -0x1(%r13),%esi
  cmp    %r13d,%ebp
  jle    L6
  mov    %r13,%rax
  mov    %esi,%r8d
  nopl   0x0(%rax)
L18:
  mov    (%rbx,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L56
  mov    %edx,%ecx
  mov    %eax,%r8d
L56:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L18
L25:
  mov    %r8d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r13
  call   <swap@plt>
  cmp    %r12,%r13
  jne    L21
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %esi,%r8d
  jmp    L25
L31:
  ret
```

assistant: ```c
void min_sort(int t[], int n) {
  int i, j;
  int mi, mv;
  if (n <= 0)
    return;
  for (i = 0; i < n - 1; i++) {
    mv = t[i];
    mi = i;
    for (j = i + 1; j < n; j++) {
      if (t[j] < mv) {
        mi = j;
        mv = t[j];
      }
    }
  L:
    swap(t, i, mi);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_module>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <printme@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int init_module(void) {
  printme();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_module>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <printme@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int init_module(void) {
  printme();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<init_module>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <printme@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int init_module(void) {
  printme();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init_module>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <printme@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int init_module(void) {
  printme();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unmask_rgba8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L14
L2:
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movb   $0xff,(%rax)
  addq   $0x4,-0x8(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unmask_rgba8(unsigned char *row, int w) {
  while (w--) {
    row[3] = 255;
    row += 4;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<unmask_rgba8>:
  endbr64
  test   %esi,%esi
  je     L3
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
L9:
  movb   $0xff,0x3(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L9
L3:
  ret
```

assistant: ```c
void unmask_rgba8(unsigned char *row, int w) {
  while (w--) {
    row[3] = 255;
    row += 4;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<unmask_rgba8>:
  endbr64
  test   %esi,%esi
  je     L1
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
  xchg   %ax,%ax
L11:
  movb   $0xff,0x3(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L11
L1:
  ret
```

assistant: ```c
void unmask_rgba8(unsigned char *row, int w) {
  while (w--) {
    row[3] = 255;
    row += 4;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unmask_rgba8>:
  endbr64
  test   %esi,%esi
  je     L13
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
  xchg   %ax,%ax
L8:
  movb   $0xff,0x3(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L8
L13:
  ret
```

assistant: ```c
void unmask_rgba8(unsigned char *row, int w) {
  while (w--) {
    row[3] = 255;
    row += 4;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compute_auth_path_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L19:
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L24
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  jmp    L6
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
L6:
  mov    -0x20(%rbp),%eax
  shr    %eax
  mov    %eax,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void compute_auth_path_id(unsigned int *auth_path_id, unsigned int const length, unsigned int block) {
  int i = 0;
  for (i = 0; i < length; ++i) {
    if ((block & 1) == 0) {
      auth_path_id[i] = block + 1;
    } else {
      auth_path_id[i] = block - 1;
    }
    block /= 2;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compute_auth_path_id>:
  endbr64
  test   %esi,%esi
  je     L25
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rcx
  jmp    L22
L49:
  lea    -0x1(%rdx),%esi
  mov    %esi,(%rax)
L11:
  shr    %edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L25
L22:
  test   $0x1,%dl
  jne    L49
  lea    0x1(%rdx),%esi
  mov    %esi,(%rax)
  jmp    L11
L25:
  ret
```

assistant: ```c
void compute_auth_path_id(unsigned int *auth_path_id, unsigned int const length, unsigned int block) {
  int i = 0;
  for (i = 0; i < length; ++i) {
    if ((block & 1) == 0) {
      auth_path_id[i] = block + 1;
    } else {
      auth_path_id[i] = block - 1;
    }
    block /= 2;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compute_auth_path_id>:
  endbr64
  test   %esi,%esi
  je     L4
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L15:
  test   $0x1,%dl
  lea    0x1(%rdx),%ecx
  lea    -0x1(%rdx),%eax
  cmove  %ecx,%eax
  add    $0x4,%rdi
  shr    %edx
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%rsi
  jne    L15
L4:
  ret
```

assistant: ```c
void compute_auth_path_id(unsigned int *auth_path_id, unsigned int const length, unsigned int block) {
  int i = 0;
  for (i = 0; i < length; ++i) {
    if ((block & 1) == 0) {
      auth_path_id[i] = block + 1;
    } else {
      auth_path_id[i] = block - 1;
    }
    block /= 2;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compute_auth_path_id>:
  endbr64
  test   %esi,%esi
  je     L6
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L11:
  test   $0x1,%dl
  lea    0x1(%rdx),%ecx
  lea    -0x1(%rdx),%eax
  cmove  %ecx,%eax
  add    $0x4,%rdi
  shr    %edx
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%rsi
  jne    L11
L6:
  ret
```

assistant: ```c
void compute_auth_path_id(unsigned int *auth_path_id, unsigned int const length, unsigned int block) {
  int i = 0;
  for (i = 0; i < length; ++i) {
    if ((block & 1) == 0) {
      auth_path_id[i] = block + 1;
    } else {
      auth_path_id[i] = block - 1;
    }
    block /= 2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<i_gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L3
  negq   -0x18(%rbp)
L3:
  cmpq   $0x0,-0x20(%rbp)
  jns    L32
  negq   -0x20(%rbp)
L32:
  cmpq   $0x0,-0x18(%rbp)
  jne    L66
  mov    -0x20(%rbp),%rax
  jmp    L59
L66:
  cmpq   $0x0,-0x20(%rbp)
  jne    L58
  mov    -0x18(%rbp),%rax
  jmp    L59
L37:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  cqto
  idivq  -0x18(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L58:
  cmpq   $0x0,-0x18(%rbp)
  jg     L37
  mov    -0x20(%rbp),%rax
L59:
  pop    %rbp
  ret
```

assistant: ```c
long i_gcd(long x, long y) {
  if (x < 0)
    x = -x;
  if (y < 0)
    y = -y;
  if (x == 0)
    return y;
  if (y == 0)
    return x;
  while (x > 0) {
    long t = x;
    x = y % x;
    y = t;
  }
  return y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<i_gcd>:
  endbr64
  mov    %rsi,%rax
  neg    %rax
  cmovs  %rsi,%rax
  mov    %rax,%rcx
  test   %rdi,%rdi
  je     L38
  mov    %rdi,%rcx
  neg    %rcx
  cmovs  %rdi,%rcx
  test   %rsi,%rsi
  jne    L35
  jmp    L38
L8:
  mov    %rdx,%rcx
L35:
  cqto
  idiv   %rcx
  mov    %rcx,%rax
  test   %rdx,%rdx
  jg     L8
L38:
  mov    %rcx,%rax
  ret
```

assistant: ```c
long i_gcd(long x, long y) {
  if (x < 0)
    x = -x;
  if (y < 0)
    y = -y;
  if (x == 0)
    return y;
  if (y == 0)
    return x;
  while (x > 0) {
    long t = x;
    x = y % x;
    y = t;
  }
  return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<i_gcd>:
  endbr64
  mov    %rsi,%rax
  neg    %rax
  cmovs  %rsi,%rax
  mov    %rax,%r8
  test   %rdi,%rdi
  je     L17
  mov    %rdi,%r8
  neg    %r8
  cmovs  %rdi,%r8
  test   %rsi,%rsi
  jne    L28
L17:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L1:
  mov    %rdx,%r8
L28:
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L1
  mov    %r8,%rax
  ret
```

assistant: ```c
long i_gcd(long x, long y) {
  if (x < 0)
    x = -x;
  if (y < 0)
    y = -y;
  if (x == 0)
    return y;
  if (y == 0)
    return x;
  while (x > 0) {
    long t = x;
    x = y % x;
    y = t;
  }
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<i_gcd>:
  endbr64
  mov    %rsi,%rax
  neg    %rax
  cmovs  %rsi,%rax
  mov    %rax,%r8
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%r8
  neg    %r8
  cmovs  %rdi,%r8
  test   %rsi,%rsi
  jne    L20
L3:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L18:
  mov    %rdx,%r8
L20:
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L18
  mov    %r8,%rax
  ret
```

assistant: ```c
long i_gcd(long x, long y) {
  if (x < 0)
    x = -x;
  if (y < 0)
    y = -y;
  if (x == 0)
    return y;
  if (y == 0)
    return x;
  while (x > 0) {
    long t = x;
    x = y % x;
    y = t;
  }
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free2d(double **p, int row) {
  int i;
  for (i = 0; i < row; i++)
    free(p[i]);
  free(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<free2d>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L17:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L17
L19:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free2d(double **p, int row) {
  int i;
  for (i = 0; i < row; i++)
    free(p[i]);
  free(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<free2d>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L1
L6:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free2d(double **p, int row) {
  int i;
  for (i = 0; i < row; i++)
    free(p[i]);
  free(p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<free2d>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L0
L8:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free2d(double **p, int row) {
  int i;
  for (i = 0; i < row; i++)
    free(p[i]);
  free(p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Montgomery>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L32
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x1c(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L37
L32:
  mov    $0xffffffff,%eax
  jmp    L28
L24:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L29
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    $0x0,%edx
  divl   -0x1c(%rbp)
  mov    %edx,-0x14(%rbp)
  shrl   -0x18(%rbp)
L37:
  cmpl   $0x1,-0x18(%rbp)
  jne    L24
  mov    -0x14(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x1c(%rbp)
  mov    %edx,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
unsigned Montgomery(unsigned n, unsigned p, unsigned m) {
  unsigned k = 1;
  if (m != 0)
    n %= m;
  else
    return -1;
  while (p != 1) {
    if (0 != (p & 1))
      k = (k * n) % m;
    n = (n * n) % m;
    p >>= 1;
  }
  return (n * k) % m;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Montgomery>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  mov    $0xffffffff,%edx
  test   %r8d,%r8d
  je     L27
  mov    $0x0,%edx
  div    %r8d
  mov    %edx,%ecx
  cmp    $0x1,%esi
  je     L24
  mov    $0x1,%edi
  jmp    L55
L22:
  mov    %ecx,%eax
  imul   %ecx,%eax
  mov    $0x0,%edx
  div    %r8d
  mov    %edx,%ecx
  shr    %esi
  cmp    $0x1,%esi
  je     L44
L55:
  test   $0x1,%sil
  je     L22
  mov    %edi,%eax
  imul   %ecx,%eax
  mov    $0x0,%edx
  div    %r8d
  mov    %edx,%edi
  jmp    L22
L24:
  mov    %esi,%edi
L44:
  mov    %ecx,%eax
  imul   %edi,%eax
  mov    $0x0,%edx
  div    %r8d
L27:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned Montgomery(unsigned n, unsigned p, unsigned m) {
  unsigned k = 1;
  if (m != 0)
    n %= m;
  else
    return -1;
  while (p != 1) {
    if (0 != (p & 1))
      k = (k * n) % m;
    n = (n * n) % m;
    p >>= 1;
  }
  return (n * k) % m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Montgomery>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%ecx
  mov    $0xffffffff,%r8d
  test   %edx,%edx
  je     L30
  xor    %edx,%edx
  div    %ecx
  mov    %edx,%r8d
  cmp    $0x1,%esi
  je     L30
  mov    $0x1,%edi
  nopl   0x0(%rax,%rax,1)
L11:
  test   $0x1,%sil
  je     L5
  mov    %edi,%eax
  xor    %edx,%edx
  imul   %r8d,%eax
  div    %ecx
  mov    %edx,%edi
L5:
  imul   %r8d,%r8d
  xor    %edx,%edx
  shr    %esi
  mov    %r8d,%eax
  div    %ecx
  mov    %edx,%r8d
  cmp    $0x1,%esi
  jne    L11
  mov    %edi,%eax
  imul   %edx,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %edx,%r8d
L30:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned Montgomery(unsigned n, unsigned p, unsigned m) {
  unsigned k = 1;
  if (m != 0)
    n %= m;
  else
    return -1;
  while (p != 1) {
    if (0 != (p & 1))
      k = (k * n) % m;
    n = (n * n) % m;
    p >>= 1;
  }
  return (n * k) % m;
}
```