ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<binary_search_recursive>:
  endbr64
  mov    %ecx,%r8d
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %esi,%eax
  cmp    %edx,%esi
  jg     L7
L18:
  movslq %eax,%rcx
  cmp    %r8d,(%rdi,%rcx,4)
  je     L45
  jle    L0
  lea    -0x1(%rax),%edx
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %esi,%eax
  cmp    %esi,%edx
  jge    L18
L7:
  mov    $0xffffffff,%eax
L45:
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    0x1(%rax),%esi
  jmp    L30
```

assistant: ```c
int binary_search_recursive(int arr[], int low, int high, int n) {
  int mid = low + (high - low) / 2;
  if (low <= high) {
    if (n == arr[mid]) {
      return mid;
    } else if (n < arr[mid]) {
      return binary_search_recursive(arr, low, mid - 1, n);
    } else {
      return binary_search_recursive(arr, mid + 1, high, n);
    }
  } else {
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<muggle_output_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L5:
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L39:
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jb     L39
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %u 

assistant: ```c
void muggle_output_bin(const unsigned char *bytes, unsigned int row, unsigned int col) {
  unsigned int val = 0;
  for (unsigned int i = 0; i < row; ++i) {
    for (unsigned int j = 0; j < col; ++j) {
      val = (0x01 << j) & bytes[i];
      printf("%u ", val == 0 ? 0 : 1);
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<muggle_output_bin>:
  endbr64
  test   %esi,%esi
  je     L13
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r12d
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r14
  lea    D3(%rip),%r13
  jmp    L27
L19:
  mov    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  movzbl 0x0(%rbp),%edx
  test   %edx,%eax
  setne  %sil
  movzbl %sil,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L19
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%rbp
  cmp    %r14,%rbp
  je     L20
L27:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jne    L19
  jmp    L3
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: %u 

assistant: ```c
void muggle_output_bin(const unsigned char *bytes, unsigned int row, unsigned int col) {
  unsigned int val = 0;
  for (unsigned int i = 0; i < row; ++i) {
    for (unsigned int j = 0; j < col; ++j) {
      val = (0x01 << j) & bytes[i];
      printf("%u ", val == 0 ? 0 : 1);
    }
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<muggle_output_bin>:
  endbr64
  test   %esi,%esi
  je     L24
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  lea    0x1(%rdi,%rax,1),%r15
  lea    D9(%rip),%r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %ebx,%ebx
  mov    $0x1,%r13d
  test   %r12d,%r12d
  je     L26
  nopl   (%rax)
L36:
  movzbl 0x0(%rbp),%eax
  mov    %ebx,%ecx
  mov    %r13d,%edx
  xor    %esi,%esi
  shl    %cl,%edx
  mov    %r14,%rdi
  test   %eax,%edx
  setne  %sil
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L36
L26:
  mov    $0xa,%edi
  add    $0x1,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r15
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: %u 

assistant: ```c
void muggle_output_bin(const unsigned char *bytes, unsigned int row, unsigned int col) {
  unsigned int val = 0;
  for (unsigned int i = 0; i < row; ++i) {
    for (unsigned int j = 0; j < col; ++j) {
      val = (0x01 << j) & bytes[i];
      printf("%u ", val == 0 ? 0 : 1);
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<muggle_output_bin>:
  endbr64
  test   %esi,%esi
  je     L7
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  lea    0x1(%rdi,%rax,1),%r15
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %ebx,%ebx
  mov    $0x1,%r13d
  test   %r12d,%r12d
  je     L19
  nopl   (%rax)
L16:
  movzbl 0x0(%rbp),%eax
  mov    %ebx,%ecx
  mov    %r13d,%edx
  xor    %esi,%esi
  shl    %cl,%edx
  mov    %r14,%rdi
  test   %eax,%edx
  setne  %sil
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L16
L19:
  mov    $0xa,%edi
  add    $0x1,%rbp
  call   <putchar@plt>
  cmp    %r15,%rbp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: %u 

assistant: ```c
void muggle_output_bin(const unsigned char *bytes, unsigned int row, unsigned int col) {
  unsigned int val = 0;
  for (unsigned int i = 0; i < row; ++i) {
    for (unsigned int j = 0; j < col; ++j) {
      val = (0x01 << j) & bytes[i];
      printf("%u ", val == 0 ? 0 : 1);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<digging_verb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <__BNF_trans_string@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <__BNF_trans_string@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L14
L4:
  nop
L14:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
type_guessed: string
name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D11: dig

tool: D2: excavate

assistant: ```c
int digging_verb(void) {
  int state;
  do {
    state = __BNF_trans_string("dig");
    if (!state)
      break;
    state = __BNF_trans_string("excavate");
  } while (0);
  return state;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<digging_verb>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <__BNF_trans_string@plt>
  test   %eax,%eax
  jne    L4
L17:
  add    $0x8,%rsp
  ret
L4:
  lea    D3(%rip),%rdi
  call   <__BNF_trans_string@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D3
datatype: string

tool: D12: dig

tool: D3: excavate

assistant: ```c
int digging_verb(void) {
  int state;
  do {
    state = __BNF_trans_string("dig");
    if (!state)
      break;
    state = __BNF_trans_string("excavate");
  } while (0);
  return state;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<digging_verb>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <__BNF_trans_string@plt>
  test   %eax,%eax
  jne    L2
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L2:
  lea    D13(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <__BNF_trans_string@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string

tool: D0: dig

tool: D13: excavate

assistant: ```c
int digging_verb(void) {
  int state;
  do {
    state = __BNF_trans_string("dig");
    if (!state)
      break;
    state = __BNF_trans_string("excavate");
  } while (0);
  return state;
}
```
user: What is the c source code of the assembly code below?

```asm
<digging_verb>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <__BNF_trans_string@plt>
  test   %eax,%eax
  jne    L7
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L7:
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <__BNF_trans_string@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D14
type: string

tool: D12: dig

tool: D14: excavate

assistant: ```c
int digging_verb(void) {
  int state;
  do {
    state = __BNF_trans_string("dig");
    if (!state)
      break;
    state = __BNF_trans_string("excavate");
  } while (0);
  return state;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <unctrl@plt>
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0xff,-0x4(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2: 0x%02x: %s


assistant: ```c
int main() {
  int ch;
  for (ch = 0; ch < 256; ch++) {
    printf("0x%02x: %s\n", ch, unctrl(ch));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L6:
  mov    %ebx,%edi
  call   <unctrl@plt>
  mov    %rax,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L6
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: 0x%02x: %s


assistant: ```c
int main() {
  int ch;
  for (ch = 0; ch < 256; ch++) {
    printf("0x%02x: %s\n", ch, unctrl(ch));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  call   <unctrl@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: 0x%02x: %s


assistant: ```c
int main() {
  int ch;
  for (ch = 0; ch < 256; ch++) {
    printf("0x%02x: %s\n", ch, unctrl(ch));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  call   <unctrl@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %rax,%rdx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string

tool: D8: 0x%02x: %s


assistant: ```c
int main() {
  int ch;
  for (ch = 0; ch < 256; ch++) {
    printf("0x%02x: %s\n", ch, unctrl(ch));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gffRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gffFileNew@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <gffFileAdd@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct gffFile *gffRead(char *fileName) {
  struct gffFile *gff = gffFileNew(fileName);
  gffFileAdd(gff, fileName, 0);
  return gff;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gffRead>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <gffFileNew@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <gffFileAdd@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct gffFile *gffRead(char *fileName) {
  struct gffFile *gff = gffFileNew(fileName);
  gffFileAdd(gff, fileName, 0);
  return gff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gffRead>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <gffFileNew@plt>
  mov    %rbp,%rsi
  xor    %edx,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <gffFileAdd@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct gffFile *gffRead(char *fileName) {
  struct gffFile *gff = gffFileNew(fileName);
  gffFileAdd(gff, fileName, 0);
  return gff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gffRead>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <gffFileNew@plt>
  mov    %rbp,%rsi
  xor    %edx,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <gffFileAdd@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct gffFile *gffRead(char *fileName) {
  struct gffFile *gff = gffFileNew(fileName);
  gffFileAdd(gff, fileName, 0);
  return gff;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L19
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <lmalloc@plt>
  jmp    L13
L19:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <lmalloc_oom@plt>
L24:
  mov    -0x8(%rbp),%rax
L13:
  leave
  ret
```

assistant: ```c
void *lrealloc(void *ptr, size_t size) {
  void *newptr;
  if (ptr == NULL)
    return lmalloc(size);
  newptr = realloc(ptr, size);
  if (!newptr)
    lmalloc_oom(size);
  return newptr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lrealloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L29
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L36
L39:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    %rsi,%rdi
  call   <lmalloc@plt>
  mov    %rax,%rbx
  jmp    L39
L36:
  mov    %rbp,%rdi
  call   <lmalloc_oom@plt>
  jmp    L39
```

assistant: ```c
void *lrealloc(void *ptr, size_t size) {
  void *newptr;
  if (ptr == NULL)
    return lmalloc(size);
  newptr = realloc(ptr, size);
  if (!newptr)
    lmalloc_oom(size);
  return newptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lrealloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L24
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  add    $0x8,%rsp
  mov    %rsi,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <lmalloc@plt>
L6:
  mov    %rbp,%rdi
  call   <lmalloc_oom@plt>
  jmp    L2
```

assistant: ```c
void *lrealloc(void *ptr, size_t size) {
  void *newptr;
  if (ptr == NULL)
    return lmalloc(size);
  newptr = realloc(ptr, size);
  if (!newptr)
    lmalloc_oom(size);
  return newptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lrealloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L27
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x8,%rsp
  mov    %rsi,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <lmalloc@plt>
L18:
  mov    %rbp,%rdi
  call   <lmalloc_oom@plt>
  jmp    L12
```

assistant: ```c
void *lrealloc(void *ptr, size_t size) {
  void *newptr;
  if (ptr == NULL)
    return lmalloc(size);
  newptr = realloc(ptr, size);
  if (!newptr)
    lmalloc_oom(size);
  return newptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<loop_g_5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x103c(%rbp)
  jmp    L98
L74:
  mov    -0x103c(%rbp),%eax
  cltq
  mov    -0x103c(%rbp),%edx
  mov    %edx,-0x1010(%rbp,%rax,4)
  addl   $0x1,-0x103c(%rbp)
L98:
  cmpl   $0x3ff,-0x103c(%rbp)
  jle    L74
  movl   $0x0,-0x103c(%rbp)
  jmp    L4
L81:
  movl   $0x0,-0x1038(%rbp)
  jmp    L17
L61:
  mov    -0x1038(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x1038(%rbp),%eax
  cltq
  mov    %edx,-0x1030(%rbp,%rax,4)
  addl   $0x1,-0x1038(%rbp)
L17:
  cmpl   $0x7,-0x1038(%rbp)
  jle    L61
  movl   $0x0,-0x1034(%rbp)
  jmp    L70
L28:
  mov    -0x103c(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x1034(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%ecx
  mov    -0x1034(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cltq
  mov    -0x1030(%rbp,%rax,4),%edx
  mov    -0x103c(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%esi
  mov    -0x1034(%rbp),%eax
  add    %esi,%eax
  add    %ecx,%edx
  cltq
  mov    %edx,-0x1010(%rbp,%rax,4)
  addl   $0x1,-0x1034(%rbp)
L70:
  cmpl   $0x1f,-0x1034(%rbp)
  jle    L28
  addl   $0x1,-0x103c(%rbp)
L4:
  cmpl   $0x1f,-0x103c(%rbp)
  jle    L81
  movl   $0x0,-0x103c(%rbp)
  jmp    L93
L2:
  mov    -0x103c(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%edx
  mov    -0x103c(%rbp),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  add    %ecx,%eax
  and    $0x7,%eax
  sub    %ecx,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x103c(%rbp),%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x103c(%rbp)
L93:
  cmpl   $0x3ff,-0x103c(%rbp)
  jle    L2
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
void loop_g_5() {
  int x[8], i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
#pragma acc loop gang private(x)
    for (i = 0; i < 32; i++) {
      for (int j = 0; j < 8; j++)
        x[j] = j * 2;
#pragma acc loop worker
      for (int j = 0; j < 32; j++)
        arr[i * 32 + j] += x[j % 8];
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + (i % 8) * 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loop_g_5>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1028(%rsp)
  xor    %eax,%eax
L16:
  mov    %eax,0x20(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L16
  lea    0x20(%rsp),%rsi
  lea    0x1020(%rsp),%rdi
L22:
  movl   $0x0,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x8,0x10(%rsp)
  movl   $0xa,0x14(%rsp)
  movl   $0xc,0x18(%rsp)
  movl   $0xe,0x1c(%rsp)
  mov    $0x0,%edx
L39:
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  lea    (%rcx,%rdx,1),%eax
  and    $0x7,%eax
  sub    %ecx,%eax
  cltq
  mov    (%rsp,%rax,4),%eax
  add    %eax,(%rsi,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x20,%rdx
  jne    L39
  sub    $0xffffffffffffff80,%rsi
  cmp    %rsi,%rdi
  jne    L22
  mov    $0x0,%ebx
  lea    0x20(%rsp),%rbp
L26:
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  lea    (%rdx,%rbx,1),%eax
  and    $0x7,%eax
  sub    %edx,%eax
  lea    (%rbx,%rax,2),%eax
  cmp    0x0(%rbp,%rbx,4),%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x1,%rbx
  cmp    $0x400,%rbx
  jne    L26
  mov    0x1028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x1038,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void loop_g_5() {
  int x[8], i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
#pragma acc loop gang private(x)
    for (i = 0; i < 32; i++) {
      for (int j = 0; j < 8; j++)
        x[j] = j * 2;
#pragma acc loop worker
      for (int j = 0; j < 32; j++)
        arr[i * 32 + j] += x[j % 8];
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + (i % 8) * 2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<loop_g_5>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1028(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  xchg   %ax,%ax
L0:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L0
  mov    %rbp,%rcx
  lea    0x1020(%rsp),%r10
  movabs $0x200000000,%r9
  movabs $0x600000004,%r8
  movabs $0xa00000008,%rdi
  movabs $0xe0000000c,%rsi
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %r9,(%rsp)
  mov    $0x1,%eax
  xor    %edx,%edx
  mov    %r8,0x8(%rsp)
  mov    %rdi,0x10(%rsp)
  mov    %rsi,0x18(%rsp)
  jmp    L30
  nopl   0x0(%rax)
L24:
  and    $0x7,%edx
  mov    (%rsp,%rdx,4),%edx
L30:
  add    %edx,-0x4(%rcx,%rax,4)
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    $0x21,%rax
  jne    L24
  sub    $0xffffffffffffff80,%rcx
  cmp    %r10,%rcx
  jne    L32
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L48:
  mov    %ebx,%eax
  xor    %edi,%edi
  and    $0x7,%eax
  lea    (%rbx,%rax,2),%eax
  cmp    0x0(%rbp,%rbx,4),%eax
  sete   %dil
  add    $0x1,%rbx
  call   <assert@plt>
  cmp    $0x400,%rbx
  jne    L48
  mov    0x1028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x1038,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void loop_g_5() {
  int x[8], i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
#pragma acc loop gang private(x)
    for (i = 0; i < 32; i++) {
      for (int j = 0; j < 8; j++)
        x[j] = j * 2;
#pragma acc loop worker
      for (int j = 0; j < 32; j++)
        arr[i * 32 + j] += x[j % 8];
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + (i % 8) * 2);
}
```