ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<atl>:
  endbr64
  test   %r8d,%r8d
  jle    L17
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rdx,%r11
  mov    %ecx,%ebx
  mov    %rsi,%rbp
  mov    %r8d,%r12d
  movslq %r9d,%r9
  lea    0x0(,%r9,8),%rsi
  lea    -0x1(%rcx),%eax
  lea    0x8(%rdx,%rax,8),%rdi
  mov    $0x0,%r8d
L33:
  mov    %r10,%rcx
  movq   $0x0,(%r10)
  test   %ebx,%ebx
  jle    L8
  mov    %r11,%rax
  mov    %rbp,%rdx
L14:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    %rsi,%rdx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L14
L8:
  add    $0x1,%r8
  add    $0x8,%r10
  add    $0x8,%rbp
  cmp    %r12,%r8
  jne    L33
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  ret
```

assistant: ```c
void atl(double *u, double *a, double *l, int m, int n, int n_large) {
  int i, k;
  for (i = 0; i < n; i++) {
    *(u + i) = 0.0;
    for (k = 0; k < m; k++)
      *(u + i) += *(a + k * n_large + i) * *(l + k);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atl>:
  endbr64
  test   %r8d,%r8d
  jle    L37
  mov    %ecx,%r11d
  movslq %r9d,%r9
  push   %rbx
  mov    %rdi,%rcx
  lea    -0x1(%r11),%eax
  movslq %r8d,%rbx
  pxor   %xmm2,%xmm2
  mov    %rdx,%r10
  lea    0x0(,%r9,8),%rdi
  lea    0x8(%rdx,%rax,8),%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L27:
  movq   $0x0,(%rcx)
  mov    %r10,%rax
  mov    %rsi,%rdx
  movapd %xmm2,%xmm1
  test   %r11d,%r11d
  jle    L23
  xchg   %ax,%ax
L6:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%r8
  jne    L6
L23:
  add    $0x1,%r9
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %rbx,%r9
  jne    L27
  pop    %rbx
  ret
L37:
  ret
```

assistant: ```c
void atl(double *u, double *a, double *l, int m, int n, int n_large) {
  int i, k;
  for (i = 0; i < n; i++) {
    *(u + i) = 0.0;
    for (k = 0; k < m; k++)
      *(u + i) += *(a + k * n_large + i) * *(l + k);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<atl>:
  endbr64
  test   %r8d,%r8d
  jle    L17
  mov    %ecx,%r11d
  movslq %r9d,%r9
  push   %rbx
  mov    %rdi,%rcx
  lea    -0x1(%r11),%eax
  movslq %r8d,%rbx
  pxor   %xmm2,%xmm2
  mov    %rdx,%r10
  lea    0x0(,%r9,8),%rdi
  lea    0x8(%rdx,%rax,8),%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L36:
  movq   $0x0,(%rcx)
  mov    %r10,%rax
  mov    %rsi,%rdx
  movapd %xmm2,%xmm1
  test   %r11d,%r11d
  jle    L37
  xchg   %ax,%ax
L2:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%r8
  jne    L2
L37:
  add    $0x1,%r9
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %rbx,%r9
  jne    L36
  pop    %rbx
  ret
L17:
  ret
```

assistant: ```c
void atl(double *u, double *a, double *l, int m, int n, int n_large) {
  int i, k;
  for (i = 0; i < n; i++) {
    *(u + i) = 0.0;
    for (k = 0; k < m; k++)
      *(u + i) += *(a + k * n_large + i) * *(l + k);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex_to_unsigned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_spaces@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L55
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L55
  addq   $0x2,-0x10(%rbp)
  jmp    L55
L86:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L45
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L45
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L45:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L29
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jg     L29
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  add    %rdx,%rax
  add    $0xa,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L29:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L54
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L54
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  add    %rdx,%rax
  add    $0xa,%rax
  mov    %rax,-0x8(%rbp)
L19:
  movl   $0x0,-0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L55:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L86
L54:
  cmpl   $0x0,-0x14(%rbp)
  je     L12
  mov    -0x28(%rbp),%rax
  jmp    L22
L12:
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
char *hex_to_unsigned(const char *str, unsigned long *out) {
  const char *cur = skip_spaces(str);
  unsigned long value = 0;
  int isempty = 1;
  if (cur[0] == '0' && cur[1] == 'x') {
    cur += 2;
  }
  while (*cur != '\0') {
    if (*cur >= '0' && *cur <= '9') {
      value = (value * 16) + (*cur - '0');
    } else if (*cur >= 'a' && *cur <= 'f') {
      value = (value * 16) + 10 + (*cur - 'a');
    } else if (*cur >= 'A' && *cur <= 'F') {
      value = (value * 16) + 10 + (*cur - 'A');
    } else {
      break;
    }
    isempty = 0;
    ++cur;
  }
  if (isempty) {
    return (char *)str;
  }
  *out = value;
  return (char *)cur;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex_to_unsigned>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <skip_spaces@plt>
  mov    %rax,%rcx
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L114
L64:
  movzbl (%rcx),%eax
  test   %al,%al
  je     L52
L50:
  mov    $0x1,%r9d
  mov    $0x0,%edx
  mov    $0x0,%esi
  jmp    L110
L114:
  cmpb   $0x78,0x1(%rcx)
  jne    L50
  add    $0x2,%rcx
  jmp    L64
L4:
  lea    -0x61(%rax),%edi
  cmp    $0x5,%dil
  ja     L39
  shl    $0x4,%rdx
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  lea    0xa(%rdx,%rax,1),%rdx
L42:
  add    $0x1,%rcx
  movzbl (%rcx),%eax
  mov    %esi,%r9d
  test   %al,%al
  je     L93
L110:
  mov    %eax,%r8d
  lea    -0x30(%rax),%edi
  cmp    $0x9,%dil
  ja     L4
  shl    $0x4,%rdx
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rax,%rdx
  jmp    L42
L39:
  sub    $0x41,%r8d
  cmp    $0x5,%r8b
  ja     L32
  shl    $0x4,%rdx
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  lea    0xa(%rdx,%rax,1),%rdx
  jmp    L42
L32:
  test   %r9d,%r9d
  je     L93
  mov    %rbx,%rcx
  jmp    L101
L93:
  mov    %rdx,0x0(%rbp)
L101:
  mov    %rcx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L52:
  mov    %rbx,%rcx
  jmp    L101
```

assistant: ```c
char *hex_to_unsigned(const char *str, unsigned long *out) {
  const char *cur = skip_spaces(str);
  unsigned long value = 0;
  int isempty = 1;
  if (cur[0] == '0' && cur[1] == 'x') {
    cur += 2;
  }
  while (*cur != '\0') {
    if (*cur >= '0' && *cur <= '9') {
      value = (value * 16) + (*cur - '0');
    } else if (*cur >= 'a' && *cur <= 'f') {
      value = (value * 16) + 10 + (*cur - 'a');
    } else if (*cur >= 'A' && *cur <= 'F') {
      value = (value * 16) + 10 + (*cur - 'A');
    } else {
      break;
    }
    isempty = 0;
    ++cur;
  }
  if (isempty) {
    return (char *)str;
  }
  *out = value;
  return (char *)cur;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex_to_unsigned>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <skip_spaces@plt>
  mov    %rax,%r8
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L76
  test   %al,%al
  je     L61
L117:
  mov    $0x1,%esi
  xor    %edx,%edx
  jmp    L58
  nopl   0x0(%rax)
L36:
  shl    $0x4,%rdx
  movsbq %cl,%rcx
  add    %rcx,%rdx
L89:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  xor    %esi,%esi
  test   %al,%al
  je     L100
L58:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L36
  lea    -0x61(%rax),%ecx
  cmp    $0x5,%cl
  ja     L70
  movzbl 0x1(%r8),%eax
  shl    $0x4,%rdx
  movsbq %cl,%rcx
  xor    %esi,%esi
  add    $0x1,%r8
  lea    0xa(%rdx,%rcx,1),%rdx
  test   %al,%al
  jne    L58
L100:
  mov    %rdx,(%rbx)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  sub    $0x41,%eax
  cmp    $0x5,%al
  ja     L57
  shl    $0x4,%rdx
  movsbq %al,%rax
  lea    0xa(%rdx,%rax,1),%rdx
  jmp    L89
  cs nopw 0x0(%rax,%rax,1)
L76:
  cmpb   $0x78,0x1(%r8)
  jne    L117
  movzbl 0x2(%r8),%eax
  lea    0x2(%r8),%rdx
  test   %al,%al
  je     L61
  mov    %rdx,%r8
  jmp    L117
L57:
  test   %esi,%esi
  je     L100
L61:
  mov    %rbp,%r8
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *hex_to_unsigned(const char *str, unsigned long *out) {
  const char *cur = skip_spaces(str);
  unsigned long value = 0;
  int isempty = 1;
  if (cur[0] == '0' && cur[1] == 'x') {
    cur += 2;
  }
  while (*cur != '\0') {
    if (*cur >= '0' && *cur <= '9') {
      value = (value * 16) + (*cur - '0');
    } else if (*cur >= 'a' && *cur <= 'f') {
      value = (value * 16) + 10 + (*cur - 'a');
    } else if (*cur >= 'A' && *cur <= 'F') {
      value = (value * 16) + 10 + (*cur - 'A');
    } else {
      break;
    }
    isempty = 0;
    ++cur;
  }
  if (isempty) {
    return (char *)str;
  }
  *out = value;
  return (char *)cur;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex_to_unsigned>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <skip_spaces@plt>
  mov    %rax,%r8
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L11
  test   %al,%al
  je     L16
L43:
  mov    $0x1,%esi
  xor    %edx,%edx
  jmp    L84
  nopl   0x0(%rax)
L15:
  shl    $0x4,%rdx
  movsbq %cl,%rcx
  add    %rcx,%rdx
L100:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  xor    %esi,%esi
  test   %al,%al
  je     L10
L84:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L15
  lea    -0x61(%rax),%ecx
  cmp    $0x5,%cl
  ja     L78
  movzbl 0x1(%r8),%eax
  shl    $0x4,%rdx
  movsbq %cl,%rcx
  xor    %esi,%esi
  add    $0x1,%r8
  lea    0xa(%rdx,%rcx,1),%rdx
  test   %al,%al
  jne    L84
L10:
  mov    %rdx,(%rbx)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  sub    $0x41,%eax
  cmp    $0x5,%al
  ja     L117
  shl    $0x4,%rdx
  movsbq %al,%rax
  lea    0xa(%rdx,%rax,1),%rdx
  jmp    L100
  cs nopw 0x0(%rax,%rax,1)
L11:
  cmpb   $0x78,0x1(%r8)
  jne    L43
  movzbl 0x2(%r8),%eax
  lea    0x2(%r8),%rdx
  test   %al,%al
  je     L16
  mov    %rdx,%r8
  jmp    L43
L117:
  test   %esi,%esi
  je     L10
L16:
  mov    %rbp,%r8
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *hex_to_unsigned(const char *str, unsigned long *out) {
  const char *cur = skip_spaces(str);
  unsigned long value = 0;
  int isempty = 1;
  if (cur[0] == '0' && cur[1] == 'x') {
    cur += 2;
  }
  while (*cur != '\0') {
    if (*cur >= '0' && *cur <= '9') {
      value = (value * 16) + (*cur - '0');
    } else if (*cur >= 'a' && *cur <= 'f') {
      value = (value * 16) + 10 + (*cur - 'a');
    } else if (*cur >= 'A' && *cur <= 'F') {
      value = (value * 16) + 10 + (*cur - 'A');
    } else {
      break;
    }
    isempty = 0;
    ++cur;
  }
  if (isempty) {
    return (char *)str;
  }
  *out = value;
  return (char *)cur;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ultoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  jle    L65
  cmpl   $0x24,-0x34(%rbp)
  jle    L36
L65:
  mov    $0x0,%eax
  jmp    L3
L36:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L74
  mov    -0x18(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  jmp    L3
L29:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  cmp    $0x9,%rax
  ja     L56
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L55
L56:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x57,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L55:
  addq   $0x1,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L74:
  cmpq   $0x0,-0x28(%rbp)
  jne    L29
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <str_reverse@plt>
  mov    -0x30(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
char *ultoa(unsigned long a, char *buffer, uint8_t radix) {
  if (radix < 2 || radix > 36) {
    return NULL;
  }
  char *ptr = buffer;
  div_t result;
  if (a == 0) {
    ptr[0] = '0';
    ptr[1] = '\0';
    return buffer;
  }
  while (a) {
    result.quot = a / radix;
    result.rem = a % radix;
    *ptr = result.rem;
    if (result.rem < 10) {
      *ptr += '0';
    } else {
      *ptr += 'a' - 10;
    }
    ++ptr;
    a = result.quot;
  }
  *ptr = '\0';
  str_reverse(buffer);
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ultoa>:
  endbr64
  lea    -0x2(%rdx),%eax
  cmp    $0x22,%eax
  ja     L15
  push   %rbx
  mov    %rsi,%rbx
  mov    %rsi,%r8
  movslq %edx,%rcx
  test   %rdi,%rdi
  je     L20
L38:
  mov    %rdi,%rsi
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,%rdi
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  lea    0x30(%rdx),%r9d
  lea    0x57(%rdx),%eax
  cmp    $0x9,%rdx
  cmovbe %r9d,%eax
  mov    %al,(%r8)
  add    $0x1,%r8
  cmp    %rsi,%rcx
  jbe    L38
  movb   $0x0,(%r8)
  mov    %rbx,%rdi
  call   <str_reverse@plt>
  mov    %rbx,%rax
L12:
  pop    %rbx
  ret
L20:
  movb   $0x30,(%rsi)
  movb   $0x0,0x1(%rsi)
  mov    %rsi,%rax
  jmp    L12
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *ultoa(unsigned long a, char *buffer, uint8_t radix) {
  if (radix < 2 || radix > 36) {
    return NULL;
  }
  char *ptr = buffer;
  div_t result;
  if (a == 0) {
    ptr[0] = '0';
    ptr[1] = '\0';
    return buffer;
  }
  while (a) {
    result.quot = a / radix;
    result.rem = a % radix;
    *ptr = result.rem;
    if (result.rem < 10) {
      *ptr += '0';
    } else {
      *ptr += 'a' - 10;
    }
    ++ptr;
    a = result.quot;
  }
  *ptr = '\0';
  str_reverse(buffer);
  return buffer;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ultoa>:
  endbr64
  lea    -0x2(%rdx),%ecx
  cmp    $0x22,%ecx
  ja     L10
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rbx
  movslq %edx,%rcx
  mov    %rsi,%r8
  test   %rdi,%rdi
  je     L16
  xchg   %ax,%ax
L7:
  xor    %edx,%edx
  mov    %rax,%r9
  div    %rcx
  cmp    $0x9,%rdx
  lea    0x30(%rdx),%r10d
  lea    0x57(%rdx),%edi
  cmovbe %r10d,%edi
  add    $0x1,%r8
  mov    %dil,-0x1(%r8)
  cmp    %r9,%rcx
  jbe    L7
  movb   $0x0,(%r8)
  mov    %rbx,%rdi
  call   <str_reverse@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L16:
  mov    $0x30,%eax
  pop    %rbx
  mov    %ax,(%rsi)
  mov    %rsi,%rax
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ultoa(unsigned long a, char *buffer, uint8_t radix) {
  if (radix < 2 || radix > 36) {
    return NULL;
  }
  char *ptr = buffer;
  div_t result;
  if (a == 0) {
    ptr[0] = '0';
    ptr[1] = '\0';
    return buffer;
  }
  while (a) {
    result.quot = a / radix;
    result.rem = a % radix;
    *ptr = result.rem;
    if (result.rem < 10) {
      *ptr += '0';
    } else {
      *ptr += 'a' - 10;
    }
    ++ptr;
    a = result.quot;
  }
  *ptr = '\0';
  str_reverse(buffer);
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ultoa>:
  endbr64
  lea    -0x2(%rdx),%eax
  cmp    $0x22,%eax
  ja     L34
  push   %rbx
  movslq %edx,%rcx
  mov    %rsi,%rbx
  mov    %rsi,%r8
  test   %rdi,%rdi
  jne    L24
  jmp    L25
  nopl   (%rax)
L51:
  add    $0x30,%edx
  add    $0x1,%r8
  mov    %dl,-0x1(%r8)
  cmp    %rcx,%rdi
  jb     L42
L57:
  mov    %rax,%rdi
L24:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rcx
  cmp    $0x9,%rdx
  jbe    L51
  add    $0x57,%edx
  add    $0x1,%r8
  mov    %dl,-0x1(%r8)
  cmp    %rcx,%rdi
  jae    L57
L42:
  movb   $0x0,(%r8)
  mov    %rbx,%rdi
  call   <str_reverse@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x30,%eax
  pop    %rbx
  mov    %ax,(%rsi)
  mov    %rsi,%rax
  ret
  nopl   (%rax)
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ultoa(unsigned long a, char *buffer, uint8_t radix) {
  if (radix < 2 || radix > 36) {
    return NULL;
  }
  char *ptr = buffer;
  div_t result;
  if (a == 0) {
    ptr[0] = '0';
    ptr[1] = '\0';
    return buffer;
  }
  while (a) {
    result.quot = a / radix;
    result.rem = a % radix;
    *ptr = result.rem;
    if (result.rem < 10) {
      *ptr += '0';
    } else {
      *ptr += 'a' - 10;
    }
    ++ptr;
    a = result.quot;
  }
  *ptr = '\0';
  str_reverse(buffer);
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<longitud>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L13:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int longitud(char cadena[]) {
  int indice = 0;
  while (cadena[indice] != '\0')
    indice++;
  return indice;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<longitud>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  mov    $0x1,%eax
L18:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L18
L23:
  mov    %edx,%eax
  ret
L4:
  mov    $0x0,%edx
  jmp    L23
```

assistant: ```c
int longitud(char cadena[]) {
  int indice = 0;
  while (cadena[indice] != '\0')
    indice++;
  return indice;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<longitud>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  mov    $0x1,%eax
  xchg   %ax,%ax
L11:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L11
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int longitud(char cadena[]) {
  int indice = 0;
  while (cadena[indice] != '\0')
    indice++;
  return indice;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<longitud>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  mov    $0x1,%eax
  xchg   %ax,%ax
L0:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L0
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int longitud(char cadena[]) {
  int indice = 0;
  while (cadena[indice] != '\0')
    indice++;
  return indice;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <func@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  func(NULL);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <func@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  func(NULL);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  func(NULL);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  func(NULL);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<kmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <getNext@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L11
L51:
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L3
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L50
L3:
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L11
  mov    -0x18(%rbp),%eax
  sub    -0xc(%rbp),%eax
  jmp    L26
L50:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L11:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L51
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
  mov    $0xffffffff,%eax
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string

tool: D0: %d %d


assistant: ```c
int kmp(char *s, char *p, int pos) {
  int i = pos;
  int j = 0;
  int slen = strlen(s);
  int plen = strlen(p);
  int *next = getNext(p);
  while (i < slen) {
    if (j == -1 || s[i] == p[j]) {
      i++, j++;
      if (j == plen) {
        return i - plen;
      }
    } else {
      j = next[j];
      printf("%s\n", s);
      printf("%s\n", p);
      printf("%d %d\n", i, j);
      printf("\n");
    }
  }
  free(next);
  next = NULL;
  return -1;
}
```