ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_getnbr>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L47
L52:
  xor    %eax,%eax
L57:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L47:
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  movl   $0x1,0xc(%rsp)
  mov    %rdi,%rbp
  lea    0xc(%rsp),%rcx
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  call   <my_getnbr_parse@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%edx
  cmp    $0xffffffff,%esi
  je     L5
  cmp    $0xffffffff,%edx
  jne    L5
  mov    %eax,0x14(%rsp)
  mov    %eax,%edx
L5:
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0xa,%eax
  jg     L52
  mov    0xc(%rsp),%ecx
  mov    %rbp,%rdi
  call   <my_getnbr_add@plt>
  jmp    L57
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int my_getnbr(char *str) {
  int sign;
  int nb_start;
  int nb_end;
  int n;
  int l;
  if (str[0] == '\0') {
    return (0);
  }
  sign = 1;
  nb_start = -1;
  nb_end = -1;
  l = my_getnbr_parse(str, &nb_start, &nb_end, &sign);
  if (nb_start != -1 && nb_end == -1) {
    nb_end = l;
  }
  if (nb_end - nb_start > 10) {
    return (0);
  }
  n = my_getnbr_add(str, nb_start, nb_end, sign);
  return (n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D88(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rbp
  lea    D58(%rip),%r14
  lea    D48(%rip),%r13
  lea    D80(%rip),%r12
  jmp    L56
L106:
  lea    D85(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L7:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L35
L51:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L35
L49:
  mov    %rbp,%rdi
  call   <printf@plt>
L35:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L35
  lea    D60(%rip),%rdi
  call   <printf@plt>
L56:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x23,%al
  je     L77
  cmp    $0xa,%bl
  je     L56
  movsbl %bl,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L49
  cmp    $0x62,%bl
  je     L7
  cmp    $0x63,%bl
  je     L51
  cmp    $0x61,%bl
  je     L106
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L35
L77:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D88
data_type: string
name: parse_data
arguments: tag: D2
data_type: string
name: parse_data
arguments: tag: D3
data_type: string
name: parse_data
arguments: tag: D23
data_type: string
name: parse_data
arguments: tag: D58
data_type: string
name: parse_data
arguments: tag: D48
data_type: string
name: parse_data
arguments: tag: D80
data_type: string
name: parse_data
arguments: tag: D85
data_type: string
name: parse_data
arguments: tag: D60
data_type: string

tool: D88: Give me a letter of the alphabet, and I will give 

tool: D2: an animal name 
beginning with that letter.


tool: D3: Please type in a letter ;type # to end my act.


tool: D23: I recognize only lowercase letters.


tool: D58: babirusa, a wild pig of Malay


tool: D48: coati, racoonlike mammal


tool: D80: That's a stumper!


tool: D85: argali, a wild sheep of Asia


tool: D60: Please type another letter or a #.


assistant: ```c
int main() {
  char ch;
  printf("Give me a letter of the alphabet, and I will give ");
  printf("an animal name \nbeginning with that letter.\n");
  printf("Please type in a letter ;type # to end my act.\n");
  while ((ch = getchar()) != '#') {
    if ('\n' == ch)
      continue;
    if (islower(ch))
      switch (ch) {
      case 'a':
        printf("argali, a wild sheep of Asia\n");
        break;
      case 'b':
        printf("babirusa, a wild pig of Malay\n");
        break;
      case 'c':
        printf("coati, racoonlike mammal\n");
        break;
      default:
        printf("That's a stumper!\n");
      }
    else
      printf("I recognize only lowercase letters.\n");
    while (getchar() != '\n')
      continue;
    printf("Please type another letter or a #.\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D82(%rip),%rdi
  lea    D10(%rip),%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D70(%rip),%rbp
  push   %rbx
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L95:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x23,%al
  je     L85
L116:
  cmp    $0xa,%bl
  je     L95
  movsbl %bl,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L106
  cmp    $0x62,%bl
  je     L110
  cmp    $0x63,%bl
  je     L86
  cmp    $0x61,%bl
  je     L105
  mov    %r12,%rdi
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L84:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L84
  lea    D30(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x23,%al
  jne    L116
L85:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L106:
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L84
L105:
  lea    D75(%rip),%rdi
  call   <printf@plt>
  jmp    L84
L86:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L84
L110:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L84
```

tool_calls: name: disassemble_data
arguments: tag: D82
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string
name: disassemble_data
arguments: tag: D6
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string
name: disassemble_data
arguments: tag: D70
type_infered: string
name: disassemble_data
arguments: tag: D62
type_infered: string
name: disassemble_data
arguments: tag: D57
type_infered: string
name: disassemble_data
arguments: tag: D30
type_infered: string
name: disassemble_data
arguments: tag: D75
type_infered: string

tool: D82: Give me a letter of the alphabet, and I will give 

tool: D10: babirusa, a wild pig of Malay


tool: D6: coati, racoonlike mammal


tool: D2: That's a stumper!


tool: D70: I recognize only lowercase letters.


tool: D62: an animal name 
beginning with that letter.


tool: D57: Please type in a letter ;type # to end my act.


tool: D30: Please type another letter or a #.


tool: D75: argali, a wild sheep of Asia


assistant: ```c
int main() {
  char ch;
  printf("Give me a letter of the alphabet, and I will give ");
  printf("an animal name \nbeginning with that letter.\n");
  printf("Please type in a letter ;type # to end my act.\n");
  while ((ch = getchar()) != '#') {
    if ('\n' == ch)
      continue;
    if (islower(ch))
      switch (ch) {
      case 'a':
        printf("argali, a wild sheep of Asia\n");
        break;
      case 'b':
        printf("babirusa, a wild pig of Malay\n");
        break;
      case 'c':
        printf("coati, racoonlike mammal\n");
        break;
      default:
        printf("That's a stumper!\n");
      }
    else
      printf("I recognize only lowercase letters.\n");
    while (getchar() != '\n')
      continue;
    printf("Please type another letter or a #.\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D4(%rip),%rdi
  lea    D70(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  lea    D85(%rip),%rbp
  push   %rbx
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L57:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x23,%al
  je     L100
L87:
  cmp    $0xa,%bl
  je     L57
  movsbl %bl,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L7
  cmp    $0x62,%bl
  je     L96
  cmp    $0x63,%bl
  je     L55
  cmp    $0x61,%bl
  je     L88
  mov    %r12,%rdi
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L0
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x23,%al
  jne    L87
L100:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L7:
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L0
L88:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L55:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L0
L96:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D70
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string
name: parse_data
arguments: data_tag: D85
data_type: string
name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string

tool: D4: Give me a letter of the alphabet, and I will give 

tool: D70: babirusa, a wild pig of Malay


tool: D0: coati, racoonlike mammal


tool: D19: That's a stumper!


tool: D85: I recognize only lowercase letters.


tool: D28: an animal name 
beginning with that letter.


tool: D5: Please type in a letter ;type # to end my act.


tool: D17: Please type another letter or a #.


tool: D27: argali, a wild sheep of Asia


assistant: ```c
int main() {
  char ch;
  printf("Give me a letter of the alphabet, and I will give ");
  printf("an animal name \nbeginning with that letter.\n");
  printf("Please type in a letter ;type # to end my act.\n");
  while ((ch = getchar()) != '#') {
    if ('\n' == ch)
      continue;
    if (islower(ch))
      switch (ch) {
      case 'a':
        printf("argali, a wild sheep of Asia\n");
        break;
      case 'b':
        printf("babirusa, a wild pig of Malay\n");
        break;
      case 'c':
        printf("coati, racoonlike mammal\n");
        break;
      default:
        printf("That's a stumper!\n");
      }
    else
      printf("I recognize only lowercase letters.\n");
    while (getchar() != '\n')
      continue;
    printf("Please type another letter or a #.\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<adagain_more>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    D7(%rip),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int adagain_more(int input) {
  static int one = 1;
  int two = 2;
  two += input;
  two += one;
  return two;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<adagain_more>:
  endbr64
  lea    0x3(%rdi),%eax
  ret
```

assistant: ```c
int adagain_more(int input) {
  static int one = 1;
  int two = 2;
  two += input;
  two += one;
  return two;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<adagain_more>:
  endbr64
  lea    0x3(%rdi),%eax
  ret
```

assistant: ```c
int adagain_more(int input) {
  static int one = 1;
  int two = 2;
  two += input;
  two += one;
  return two;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adagain_more>:
  endbr64
  lea    0x3(%rdi),%eax
  ret
```

assistant: ```c
int adagain_more(int input) {
  static int one = 1;
  int two = 2;
  two += input;
  two += one;
  return two;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cmpl   $0x0,-0xc(%rbp)
  je     L16
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  je     L16
  mov    -0xc(%rbp),%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L16:
  movl   $0x0,-0x8(%rbp)
L14:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  if (a && (b + a)) {
    c = -a;
  } else {
    b = 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  if (a && (b + a)) {
    c = -a;
  } else {
    b = 0;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  if (a && (b + a)) {
    c = -a;
  } else {
    b = 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  if (a && (b + a)) {
    c = -a;
  } else {
    b = 0;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scale_plus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x30(%rbp)
  mov    %esi,-0x34(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    %r9d,-0x48(%rbp)
  movsd  %xmm0,-0x50(%rbp)
  movsd  %xmm1,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x50(%rbp),%xmm0
  setnp  %al
  mov    $0x0,%edx
  pxor   %xmm0,%xmm0
  ucomisd -0x50(%rbp),%xmm0
  cmovne %edx,%eax
  movzbl %al,%r13d
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x0,%r15d
  jmp    L4
L108:
  mov    %rdi,%rbx
  mov    %rdx,%r12
  mov    $0x0,%r14d
  jmp    L60
L20:
  test   %r13d,%r13d
  je     L69
  movsd  (%r12),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  jmp    L72
L69:
  movsd  (%rbx),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x50(%rbp),%xmm1
  movsd  (%r12),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm1,%xmm0
L72:
  movsd  %xmm0,(%rbx)
  test   %r13d,%r13d
  je     L29
  lea    0x8(%r12),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  jmp    L85
L29:
  lea    0x8(%rbx),%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x50(%rbp),%xmm1
  lea    0x8(%r12),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm1,%xmm0
L85:
  lea    0x8(%rbx),%rax
  movsd  %xmm0,(%rax)
  add    $0x10,%rbx
  add    $0x10,%r12
  add    $0x2,%r14d
L60:
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,%r14d
  jl     L20
  cmp    -0x44(%rbp),%r14d
  jge    L91
  test   %r13d,%r13d
  je     L53
  movsd  (%r12),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  jmp    L5
L53:
  movsd  (%rbx),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x50(%rbp),%xmm1
  movsd  (%r12),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm1,%xmm0
L5:
  movsd  %xmm0,(%rbx)
L91:
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  mov    %rdi,%rcx
  add    %rax,%rcx
  mov    %rcx,%rdi
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x3,%rax
  mov    %rdx,%rsi
  add    %rax,%rsi
  mov    %rsi,%rdx
  add    $0x1,%r15d
L4:
  cmp    -0x48(%rbp),%r15d
  jl     L108
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void scale_plus(double *__restrict dst, int ldD, const double *__restrict src, int ldS, int nR, int nC, double alpha, double beta) {
  register double *Dc, *Dr;
  register const double *Sc, *Sr;
  register int j, i;
  register int zero;
  zero = alpha == 0.0;
  Dc = dst;
  Sc = src;
  for (j = 0; j < nC; j++) {
    Dr = Dc;
    Sr = Sc;
    for (i = 0; i < nR - 1; i += 2) {
      Dr[0] = zero ? beta * Sr[0] : alpha * Dr[0] + beta * Sr[0];
      Dr[1] = zero ? beta * Sr[1] : alpha * Dr[1] + beta * Sr[1];
      Dr += 2;
      Sr += 2;
    }
    if (i < nR) {
      Dr[0] = zero ? beta * Sr[0] : alpha * Dr[0] + beta * Sr[0];
    }
    Dc += ldD;
    Sc += ldS;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scale_plus>:
  endbr64
  test   %r9d,%r9d
  jle    L93
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    %ecx,%eax
  mov    %r9d,%r12d
  movslq %r10d,%r10
  lea    0x0(,%r10,8),%rbx
  cltq
  lea    0x0(,%rax,8),%r9
  lea    -0x2(%r8),%ebp
  shr    %ebp
  add    $0x1,%ebp
  mov    %ebp,%r11d
  shl    $0x4,%r11
  add    %ebp,%ebp
  mov    $0x0,%r10d
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm4
  mov    $0x0,%r13d
  movapd %xmm3,%xmm6
  movapd %xmm3,%xmm7
  jmp    L97
L62:
  movapd %xmm0,%xmm2
  mulsd  (%rax),%xmm2
  movapd %xmm1,%xmm5
  mulsd  (%rdx),%xmm5
  addsd  %xmm5,%xmm2
  movsd  %xmm2,(%rax)
  movapd %xmm0,%xmm2
  mulsd  0x8(%rax),%xmm2
  movapd %xmm1,%xmm5
  mulsd  0x8(%rdx),%xmm5
  addsd  %xmm5,%xmm2
L0:
  movsd  %xmm2,0x8(%rax)
  add    $0x10,%rax
  add    $0x10,%rdx
  cmp    %rcx,%rax
  je     L124
L86:
  ucomisd %xmm3,%xmm0
  jp     L62
  ucomisd %xmm4,%xmm0
  jne    L62
  movapd %xmm1,%xmm2
  mulsd  (%rdx),%xmm2
  movsd  %xmm2,(%rax)
  movapd %xmm1,%xmm2
  mulsd  0x8(%rdx),%xmm2
  jmp    L0
L124:
  lea    (%rsi,%r11,1),%rdx
  mov    %ebp,%eax
L20:
  cmp    %eax,%r8d
  jle    L109
  ucomisd %xmm6,%xmm0
  jp     L95
  ucomisd %xmm7,%xmm0
  jne    L95
  movapd %xmm1,%xmm2
  mulsd  (%rdx),%xmm2
L6:
  movsd  %xmm2,(%rcx)
L109:
  add    %rbx,%rdi
  add    %r9,%rsi
  add    $0x1,%r10d
  cmp    %r10d,%r12d
  je     L30
L97:
  lea    (%rdi,%r11,1),%rcx
  mov    %rsi,%rdx
  mov    %rdi,%rax
  cmp    $0x1,%r8d
  jg     L86
  mov    %rdi,%rcx
  mov    %r13d,%eax
  jmp    L20
L95:
  movapd %xmm0,%xmm2
  mulsd  (%rcx),%xmm2
  movapd %xmm1,%xmm5
  mulsd  (%rdx),%xmm5
  addsd  %xmm5,%xmm2
  jmp    L6
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L93:
  ret
```

assistant: ```c
void scale_plus(double *__restrict dst, int ldD, const double *__restrict src, int ldS, int nR, int nC, double alpha, double beta) {
  register double *Dc, *Dr;
  register const double *Sc, *Sr;
  register int j, i;
  register int zero;
  zero = alpha == 0.0;
  Dc = dst;
  Sc = src;
  for (j = 0; j < nC; j++) {
    Dr = Dc;
    Sr = Sc;
    for (i = 0; i < nR - 1; i += 2) {
      Dr[0] = zero ? beta * Sr[0] : alpha * Dr[0] + beta * Sr[0];
      Dr[1] = zero ? beta * Sr[1] : alpha * Dr[1] + beta * Sr[1];
      Dr += 2;
      Sr += 2;
    }
    if (i < nR) {
      Dr[0] = zero ? beta * Sr[0] : alpha * Dr[0] + beta * Sr[0];
    }
    Dc += ldD;
    Sc += ldS;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<scale_plus>:
  endbr64
  test   %r9d,%r9d
  jle    L14
  push   %r12
  lea    -0x2(%r8),%r12d
  movslq %esi,%r10
  movslq %ecx,%rax
  shr    %r12d
  push   %rbp
  mov    %rdx,%rsi
  lea    0x0(,%r10,8),%rbp
  lea    0x1(%r12),%r11d
  push   %rbx
  xor    %r10d,%r10d
  mov    %r9d,%ebx
  mov    %r11,%r12
  lea    0x0(,%rax,8),%r9
  shl    $0x4,%r11
  pxor   %xmm5,%xmm5
  add    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L97:
  lea    (%rdi,%r11,1),%rcx
  mov    %rsi,%rdx
  mov    %rdi,%rax
  cmp    $0x1,%r8d
  jg     L40
  jmp    L13
  nopl   (%rax)
L76:
  movsd  %xmm4,(%rax)
L15:
  movsd  %xmm2,0x8(%rax)
  add    $0x10,%rax
  add    $0x10,%rdx
  cmp    %rcx,%rax
  je     L51
L40:
  ucomisd %xmm5,%xmm0
  movsd  (%rdx),%xmm4
  movsd  0x8(%rdx),%xmm2
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm2
  jp     L107
  je     L76
L107:
  movsd  (%rax),%xmm3
  mulsd  %xmm0,%xmm3
  addsd  %xmm4,%xmm3
  movsd  %xmm3,(%rax)
  movsd  0x8(%rax),%xmm3
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L51:
  lea    (%rsi,%r11,1),%rdx
  mov    %r12d,%eax
L100:
  cmp    %eax,%r8d
  jle    L28
  ucomisd %xmm5,%xmm0
  movsd  (%rdx),%xmm2
  mulsd  %xmm1,%xmm2
  jp     L67
  je     L109
L67:
  movsd  (%rcx),%xmm3
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
L109:
  movsd  %xmm2,(%rcx)
L28:
  add    $0x1,%r10d
  add    %rbp,%rdi
  add    %r9,%rsi
  cmp    %r10d,%ebx
  jne    L97
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L100
L14:
  ret
```

assistant: ```c
void scale_plus(double *__restrict dst, int ldD, const double *__restrict src, int ldS, int nR, int nC, double alpha, double beta) {
  register double *Dc, *Dr;
  register const double *Sc, *Sr;
  register int j, i;
  register int zero;
  zero = alpha == 0.0;
  Dc = dst;
  Sc = src;
  for (j = 0; j < nC; j++) {
    Dr = Dc;
    Sr = Sc;
    for (i = 0; i < nR - 1; i += 2) {
      Dr[0] = zero ? beta * Sr[0] : alpha * Dr[0] + beta * Sr[0];
      Dr[1] = zero ? beta * Sr[1] : alpha * Dr[1] + beta * Sr[1];
      Dr += 2;
      Sr += 2;
    }
    if (i < nR) {
      Dr[0] = zero ? beta * Sr[0] : alpha * Dr[0] + beta * Sr[0];
    }
    Dc += ldD;
    Sc += ldS;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scale_plus>:
  endbr64
  test   %r9d,%r9d
  jle    L104
  movslq %ecx,%rax
  lea    -0x2(%r8),%ecx
  movslq %esi,%r10
  push   %r13
  shr    %ecx
  movapd %xmm0,%xmm5
  movapd %xmm1,%xmm4
  push   %r12
  lea    0x1(%rcx),%r11d
  push   %rbp
  mov    %rdx,%rsi
  mov    %r9d,%ebp
  mov    %r11,%rcx
  push   %rbx
  lea    0x0(,%rax,8),%r9
  shl    $0x4,%r11
  lea    0x0(,%r10,8),%rbx
  lea    (%rcx,%rcx,1),%r12d
  pxor   %xmm6,%xmm6
  xor    %r10d,%r10d
  unpcklpd %xmm5,%xmm5
  unpcklpd %xmm4,%xmm4
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %rsi,%r13
  mov    %rdi,%rdx
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jle    L53
  xor    %eax,%eax
  xor    %edx,%edx
  ucomisd %xmm6,%xmm0
  jp     L71
  je     L61
  nopw   0x0(%rax,%rax,1)
L71:
  movupd (%rdi,%rax,1),%xmm2
  movupd (%rsi,%rax,1),%xmm3
  add    $0x1,%edx
  mulpd  %xmm5,%xmm2
  mulpd  %xmm4,%xmm3
  addpd  %xmm3,%xmm2
  movups %xmm2,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %ecx,%edx
  jb     L71
L89:
  lea    (%rdi,%r11,1),%rdx
  lea    (%rsi,%r11,1),%r13
  mov    %r12d,%eax
L53:
  cmp    %eax,%r8d
  jle    L21
  ucomisd %xmm6,%xmm0
  movsd  0x0(%r13),%xmm2
  mulsd  %xmm1,%xmm2
  jp     L28
  je     L59
L28:
  movsd  (%rdx),%xmm3
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
L59:
  movsd  %xmm2,(%rdx)
L21:
  add    $0x1,%r10d
  add    %rbx,%rdi
  add    %r9,%rsi
  cmp    %r10d,%ebp
  jne    L68
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L61:
  movupd (%rsi,%rax,1),%xmm2
  add    $0x1,%edx
  mulpd  %xmm4,%xmm2
  movups %xmm2,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %ecx,%edx
  jb     L61
  jmp    L89
L104:
  ret
```

assistant: ```c
void scale_plus(double *__restrict dst, int ldD, const double *__restrict src, int ldS, int nR, int nC, double alpha, double beta) {
  register double *Dc, *Dr;
  register const double *Sc, *Sr;
  register int j, i;
  register int zero;
  zero = alpha == 0.0;
  Dc = dst;
  Sc = src;
  for (j = 0; j < nC; j++) {
    Dr = Dc;
    Sr = Sc;
    for (i = 0; i < nR - 1; i += 2) {
      Dr[0] = zero ? beta * Sr[0] : alpha * Dr[0] + beta * Sr[0];
      Dr[1] = zero ? beta * Sr[1] : alpha * Dr[1] + beta * Sr[1];
      Dr += 2;
      Sr += 2;
    }
    if (i < nR) {
      Dr[0] = zero ? beta * Sr[0] : alpha * Dr[0] + beta * Sr[0];
    }
    Dc += ldD;
    Sc += ldS;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rotate_180>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %edx,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x84(%rbp),%edx
  lea    -0x70(%rbp),%rcx
  mov    -0x78(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotate_90@plt>
  mov    -0x84(%rbp),%edx
  mov    -0x80(%rbp),%rcx
  lea    -0x70(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotate_90@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void rotate_180(char before[][10], char trans[][10], int n) {
  char tmp[10][10];
  memset(tmp, 0, sizeof(tmp));
  rotate_90(before, tmp, n);
  rotate_90(tmp, trans, n);
}
```