ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D10(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  ja     L69
  lea    D8(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D47(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D108(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D42(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D87(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D84(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D116(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
type_guessed: string
name: unpack_data
arguments: tag: D47
type_guessed: string
name: unpack_data
arguments: tag: D54
type_guessed: string
name: unpack_data
arguments: tag: D108
type_guessed: string
name: unpack_data
arguments: tag: D42
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D87
type_guessed: string
name: unpack_data
arguments: tag: D84
type_guessed: string
name: unpack_data
arguments: tag: D56
type_guessed: string
name: unpack_data
arguments: tag: D46
type_guessed: string
name: unpack_data
arguments: tag: D116
type_guessed: string

tool: D10: %d

tool: D47: 
 nine


tool: D54: 
 one


tool: D108: 
 two


tool: D42: 
 three


tool: D17: 
 four


tool: D87: 
 five


tool: D84: 
 six


tool: D56: 
 seven


tool: D46: 
 eight


tool: D116: 
 zero


assistant: ```c
int main() {
  int a;
  do {
    scanf("%d", &a);
  } while (a < 0 || a > 9);
  switch (a) {
  case 0:
    printf("\n zero\n");
    break;
  case 1:
    printf("\n one\n");
    break;
  case 2:
    printf("\n two\n");
    break;
  case 3:
    printf("\n three\n");
    break;
  case 4:
    printf("\n four\n");
    break;
  case 5:
    printf("\n five\n");
    break;
  case 6:
    printf("\n six\n");
    break;
  case 7:
    printf("\n seven\n");
    break;
  case 8:
    printf("\n eight\n");
    break;
  case 9:
    printf("\n nine\n");
    break;
  case 10:
    printf("\n ten\n");
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D94(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  ja     L4
  lea    D33(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L52:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L52
  lea    D78(%rip),%rdi
  call   <printf@plt>
  jmp    L52
  lea    D65(%rip),%rdi
  call   <printf@plt>
  jmp    L52
  lea    D100(%rip),%rdi
  call   <printf@plt>
  jmp    L52
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L52
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L52
  lea    D73(%rip),%rdi
  call   <printf@plt>
  jmp    L52
  lea    D103(%rip),%rdi
  call   <printf@plt>
  jmp    L52
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D94
type: string
name: retrieve_data
arguments: data_label: D26
type: string
name: retrieve_data
arguments: data_label: D45
type: string
name: retrieve_data
arguments: data_label: D78
type: string
name: retrieve_data
arguments: data_label: D65
type: string
name: retrieve_data
arguments: data_label: D100
type: string
name: retrieve_data
arguments: data_label: D46
type: string
name: retrieve_data
arguments: data_label: D51
type: string
name: retrieve_data
arguments: data_label: D73
type: string
name: retrieve_data
arguments: data_label: D103
type: string
name: retrieve_data
arguments: data_label: D43
type: string

tool: D94: %d

tool: D26: 
 nine


tool: D45: 
 one


tool: D78: 
 two


tool: D65: 
 three


tool: D100: 
 four


tool: D46: 
 five


tool: D51: 
 six


tool: D73: 
 seven


tool: D103: 
 eight


tool: D43: 
 zero


assistant: ```c
int main() {
  int a;
  do {
    scanf("%d", &a);
  } while (a < 0 || a > 9);
  switch (a) {
  case 0:
    printf("\n zero\n");
    break;
  case 1:
    printf("\n one\n");
    break;
  case 2:
    printf("\n two\n");
    break;
  case 3:
    printf("\n three\n");
    break;
  case 4:
    printf("\n four\n");
    break;
  case 5:
    printf("\n five\n");
    break;
  case 6:
    printf("\n six\n");
    break;
  case 7:
    printf("\n seven\n");
    break;
  case 8:
    printf("\n eight\n");
    break;
  case 9:
    printf("\n nine\n");
    break;
  case 10:
    printf("\n ten\n");
    break;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x4(%rbp)
  nop
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L0
  movzbl -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
char readchar(char letter) {
  letter = getchar();
  while (getchar() != '\n')
    ;
  return letter;
}
```
user: What is the c source code of the assembly code below?

```asm
<readchar>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L2
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char readchar(char letter) {
  letter = getchar();
  while (getchar() != '\n')
    ;
  return letter;
}
```
user: What is the c source code of the assembly code below:

```asm
<readchar>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L2
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char readchar(char letter) {
  letter = getchar();
  while (getchar() != '\n')
    ;
  return letter;
}
```
user: What is the c source code of the assembly code below?

```asm
<readchar>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L9
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char readchar(char letter) {
  letter = getchar();
  while (getchar() != '\n')
    ;
  return letter;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_utils>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <ti2s@plt>
  mov    $0x1869f,%edi
  call   <ti2s@plt>
  mov    $0xffffffff,%eax
  mov    %rax,%rdi
  call   <ti2s@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_utils() {
  ti2s(0);
  ti2s(99999);
  ti2s(4294967295L);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_utils>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <ti2s@plt>
  mov    $0x1869f,%edi
  call   <ti2s@plt>
  mov    $0xffffffff,%edi
  call   <ti2s@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_utils() {
  ti2s(0);
  ti2s(99999);
  ti2s(4294967295L);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_utils>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <ti2s@plt>
  mov    $0x1869f,%edi
  call   <ti2s@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1050 <ti2s@plt>
```

assistant: ```c
void test_utils() {
  ti2s(0);
  ti2s(99999);
  ti2s(4294967295L);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_utils>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <ti2s@plt>
  mov    $0x1869f,%edi
  call   <ti2s@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1050 <ti2s@plt>
```

assistant: ```c
void test_utils() {
  ti2s(0);
  ti2s(99999);
  ti2s(4294967295L);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcscspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L19
L49:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L24
L50:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  cmp    %rax,%rcx
  jne    L24
  mov    -0x10(%rbp),%rax
  jmp    L36
L24:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L50
  addq   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L49
  mov    -0x10(%rbp),%rax
L36:
  pop    %rbp
  ret
```

assistant: ```c
size_t wcscspn(const wchar_t *s1, const wchar_t *s2) {
  size_t len = 0;
  const wchar_t *p;
  while (s1[len]) {
    p = s2;
    while (*p) {
      if (s1[len] == *p++) {
        return len;
      }
    }
    ++len;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wcscspn>:
  endbr64
  mov    (%rdi),%rcx
  mov    $0x0,%r8d
  test   %rcx,%rcx
  je     L15
L32:
  mov    %rsi,%rax
L24:
  mov    (%rax),%rdx
  test   %rdx,%rdx
  je     L9
  add    $0x8,%rax
  cmp    %rcx,%rdx
  jne    L24
L15:
  mov    %r8,%rax
  ret
L9:
  add    $0x1,%r8
  mov    (%rdi,%r8,8),%rcx
  test   %rcx,%rcx
  jne    L32
  jmp    L15
```

assistant: ```c
size_t wcscspn(const wchar_t *s1, const wchar_t *s2) {
  size_t len = 0;
  const wchar_t *p;
  while (s1[len]) {
    p = s2;
    while (*p) {
      if (s1[len] == *p++) {
        return len;
      }
    }
    ++len;
  }
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcscspn>:
  endbr64
  mov    (%rdi),%rcx
  xor    %r8d,%r8d
  test   %rcx,%rcx
  je     L25
L37:
  mov    %rsi,%rax
  jmp    L40
  nopl   0x0(%rax)
L30:
  add    $0x8,%rax
  cmp    %rcx,%rdx
  je     L25
L40:
  mov    (%rax),%rdx
  test   %rdx,%rdx
  jne    L30
  add    $0x1,%r8
  mov    (%rdi,%r8,8),%rcx
  test   %rcx,%rcx
  jne    L37
L25:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t wcscspn(const wchar_t *s1, const wchar_t *s2) {
  size_t len = 0;
  const wchar_t *p;
  while (s1[len]) {
    p = s2;
    while (*p) {
      if (s1[len] == *p++) {
        return len;
      }
    }
    ++len;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wcscspn>:
  endbr64
  mov    (%rdi),%rcx
  xor    %r8d,%r8d
  test   %rcx,%rcx
  je     L21
L9:
  mov    %rsi,%rax
  jmp    L11
  nopl   0x0(%rax)
L37:
  add    $0x8,%rax
  cmp    %rcx,%rdx
  je     L21
L11:
  mov    (%rax),%rdx
  test   %rdx,%rdx
  jne    L37
  add    $0x1,%r8
  mov    (%rdi,%r8,8),%rcx
  test   %rcx,%rcx
  jne    L9
L21:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t wcscspn(const wchar_t *s1, const wchar_t *s2) {
  size_t len = 0;
  const wchar_t *p;
  while (s1[len]) {
    p = s2;
    while (*p) {
      if (s1[len] == *p++) {
        return len;
      }
    }
    ++len;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ex6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %eax,%edx
  mov    %edx,%r8d
  mov    -0x10(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%esi
  movd   %esi,%xmm0
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D23
type: string
name: retrieve_data
arguments: label: D46
type: string
name: retrieve_data
arguments: label: D24
type: string
name: retrieve_data
arguments: label: D35
type: string
name: retrieve_data
arguments: label: D75
type: string
name: retrieve_data
arguments: label: D45
type: string

tool: D23: 
------------------------------


tool: D46: 6. Elaborar um algoritmo para ler a base e a altura de um triangulo e imprimir sua area dada por: area = 1/2 * base * altura

tool: D24: Digite o valor da base do triangulo:

tool: D35: %d

tool: D75: Digite o valor da altura do triangulo:

tool: D45: Base: %d
Altura: %d
Area: (%d * %d) / 2 = %d / 2 = %.2f

assistant: ```c
void ex6() {
  print("\n------------------------------\n");
  print("6. Elaborar um algoritmo para ler a base e a altura de um triangulo e imprimir sua area dada por: area = 1/2 * base * altura");
  int base, altura;
  float area;
  print("Digite o valor da base do triangulo:");
  scanf("%d", &base);
  print("Digite o valor da altura do triangulo:");
  scanf("%d", &altura);
  area = (base * altura) / 2;
  printf("Base: %d\nAltura: %d\nArea: (%d * %d) / 2 = %d / 2 = %.2f", base, altura, base, altura, base * altura, area);
  print("\n------------------------------\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<ex6>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <print@plt>
  lea    D53(%rip),%rdi
  call   <print@plt>
  lea    D25(%rip),%rdi
  call   <print@plt>
  mov    %rsp,%rsi
  lea    D21(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D30(%rip),%rdi
  call   <print@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  mov    %esi,%r9d
  imul   %edx,%r9d
  mov    %r9d,%eax
  shr    $0x1f,%eax
  add    %r9d,%eax
  sar    %eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    %edx,%r8d
  mov    %esi,%ecx
  lea    D55(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D53
type: string
name: parse_data
arguments: tag: D25
type: string
name: parse_data
arguments: tag: D21
type: string
name: parse_data
arguments: tag: D30
type: string
name: parse_data
arguments: tag: D55
type: string

tool: D11: 
------------------------------


tool: D53: 6. Elaborar um algoritmo para ler a base e a altura de um triangulo e imprimir sua area dada por: area = 1/2 * base * altura

tool: D25: Digite o valor da base do triangulo:

tool: D21: %d

tool: D30: Digite o valor da altura do triangulo:

tool: D55: Base: %d
Altura: %d
Area: (%d * %d) / 2 = %d / 2 = %.2f

assistant: ```c
void ex6() {
  print("\n------------------------------\n");
  print("6. Elaborar um algoritmo para ler a base e a altura de um triangulo e imprimir sua area dada por: area = 1/2 * base * altura");
  int base, altura;
  float area;
  print("Digite o valor da base do triangulo:");
  scanf("%d", &base);
  print("Digite o valor da altura do triangulo:");
  scanf("%d", &altura);
  area = (base * altura) / 2;
  printf("Base: %d\nAltura: %d\nArea: (%d * %d) / 2 = %d / 2 = %.2f", base, altura, base, altura, base * altura, area);
  print("\n------------------------------\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ex6>:
  endbr64
  push   %r12
  lea    D46(%rip),%r12
  push   %rbp
  lea    D36(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <print@plt>
  lea    D31(%rip),%rdi
  call   <print@plt>
  lea    D58(%rip),%rdi
  call   <print@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  call   <print@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  lea    D56(%rip),%rdi
  mov    %esi,%r9d
  mov    %edx,%r8d
  mov    %esi,%ecx
  imul   %edx,%r9d
  mov    %r9d,%eax
  shr    $0x1f,%eax
  add    %r9d,%eax
  sar    %eax
  cvtsi2ss %eax,%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D46
type_infered: string
name: parse_data
arguments: label: D36
type_infered: string
name: parse_data
arguments: label: D31
type_infered: string
name: parse_data
arguments: label: D58
type_infered: string
name: parse_data
arguments: label: D38
type_infered: string
name: parse_data
arguments: label: D56
type_infered: string

tool: D46: %d

tool: D36: 
------------------------------


tool: D31: 6. Elaborar um algoritmo para ler a base e a altura de um triangulo e imprimir sua area dada por: area = 1/2 * base * altura

tool: D58: Digite o valor da base do triangulo:

tool: D38: Digite o valor da altura do triangulo:

tool: D56: Base: %d
Altura: %d
Area: (%d * %d) / 2 = %d / 2 = %.2f

assistant: ```c
void ex6() {
  print("\n------------------------------\n");
  print("6. Elaborar um algoritmo para ler a base e a altura de um triangulo e imprimir sua area dada por: area = 1/2 * base * altura");
  int base, altura;
  float area;
  print("Digite o valor da base do triangulo:");
  scanf("%d", &base);
  print("Digite o valor da altura do triangulo:");
  scanf("%d", &altura);
  area = (base * altura) / 2;
  printf("Base: %d\nAltura: %d\nArea: (%d * %d) / 2 = %d / 2 = %.2f", base, altura, base, altura, base * altura, area);
  print("\n------------------------------\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<ex6>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  lea    D53(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <print@plt>
  lea    D2(%rip),%rdi
  call   <print@plt>
  lea    D11(%rip),%rdi
  call   <print@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  call   <print@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  lea    D0(%rip),%rdi
  mov    %esi,%r9d
  mov    %edx,%r8d
  mov    %esi,%ecx
  imul   %edx,%r9d
  mov    %r9d,%eax
  shr    $0x1f,%eax
  add    %r9d,%eax
  sar    %eax
  cvtsi2ss %eax,%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_guessed: string
name: unpack_data
arguments: data_label: D53
type_guessed: string
name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D19: %d

tool: D53: 
------------------------------


tool: D2: 6. Elaborar um algoritmo para ler a base e a altura de um triangulo e imprimir sua area dada por: area = 1/2 * base * altura

tool: D11: Digite o valor da base do triangulo:

tool: D27: Digite o valor da altura do triangulo:

tool: D0: Base: %d
Altura: %d
Area: (%d * %d) / 2 = %d / 2 = %.2f

assistant: ```c
void ex6() {
  print("\n------------------------------\n");
  print("6. Elaborar um algoritmo para ler a base e a altura de um triangulo e imprimir sua area dada por: area = 1/2 * base * altura");
  int base, altura;
  float area;
  print("Digite o valor da base do triangulo:");
  scanf("%d", &base);
  print("Digite o valor da altura do triangulo:");
  scanf("%d", &altura);
  area = (base * altura) / 2;
  printf("Base: %d\nAltura: %d\nArea: (%d * %d) / 2 = %d / 2 = %.2f", base, altura, base, altura, base * altura, area);
  print("\n------------------------------\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SetContrastControlRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x81,-0xa(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x9(%rbp)
  lea    -0xa(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <oled_SendCommand@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void SetContrastControlRegister(char a) {
  unsigned char d[] = {0x81, a};
  oled_SendCommand(d, sizeof(d));
}
```
user: Translate the below assembly code into C programming language:

```asm
<SetContrastControlRegister>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x81,0x6(%rsp)
  mov    %dil,0x7(%rsp)
  lea    0x6(%rsp),%rdi
  mov    $0x2,%esi
  call   <oled_SendCommand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SetContrastControlRegister(char a) {
  unsigned char d[] = {0x81, a};
  oled_SendCommand(d, sizeof(d));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SetContrastControlRegister>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x7(%rsp)
  lea    0x6(%rsp),%rdi
  movb   $0x81,0x6(%rsp)
  call   <oled_SendCommand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SetContrastControlRegister(char a) {
  unsigned char d[] = {0x81, a};
  oled_SendCommand(d, sizeof(d));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<SetContrastControlRegister>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x7(%rsp)
  lea    0x6(%rsp),%rdi
  movb   $0x81,0x6(%rsp)
  call   <oled_SendCommand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SetContrastControlRegister(char a) {
  unsigned char d[] = {0x81, a};
  oled_SendCommand(d, sizeof(d));
}
```