ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<update_crc>:
  endbr64
  movsbl %dil,%edi
  shl    $0x8,%edi
  xor    %esi,%edi
  lea    (%rdi,%rdi,1),%eax
  mov    %eax,%edx
  xor    $0x1021,%edx
  and    $0x8000,%edi
  cmovne %edx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x1021,%ecx
  test   $0x80,%ah
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x1021,%ecx
  test   $0x80,%ah
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x1021,%ecx
  test   $0x80,%ah
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%r8d
  mov    %r8d,%edx
  xor    $0x1021,%edx
  test   $0x80,%ah
  cmovne %edx,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int16_t update_crc(char data, int16_t crc) {
  char i;
  int16_t tmp;
  tmp = (int16_t)(data);
  crc = crc ^ (tmp << 8);
  for (i = 0; i < 8; i++) {
    if (crc & 0x8000)
      crc = crc << 1 ^ 0x1021;
    else
      crc = crc << 1;
  }
  return crc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ftrace_peek_registers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D23(%rip),%rax
  movq   $0x0,(%rax)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <ptrace@plt>
  test   %rax,%rax
  je     L28
  mov    D23(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L28
  mov    $0xffffffff,%eax
  jmp    L9
L28:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int ftrace_peek_registers(pid_t child, struct user_regs_struct *regs) {
  assert(child != 0);
  assert(regs != NULL);
  errno = 0;
  if (ptrace(PTRACE_GETREGS, child, 0, regs) && errno)
    return (-1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ftrace_peek_registers>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D24(%rip),%rax
  movq   $0x0,(%rax)
  mov    %rbp,%rcx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <ptrace@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L2
  mov    D24(%rip),%rax
  mov    (%rax),%rax
  neg    %rax
  sbb    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ftrace_peek_registers(pid_t child, struct user_regs_struct *regs) {
  assert(child != 0);
  assert(regs != NULL);
  errno = 0;
  if (ptrace(PTRACE_GETREGS, child, 0, regs) && errno)
    return (-1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ftrace_peek_registers>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  setne  %dil
  push   %rbx
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rcx
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    D16(%rip),%rax
  mov    D0(%rip),%rbx
  mov    (%rax),%edi
  movq   $0x0,(%rbx)
  call   <ptrace@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L0
  mov    (%rbx),%rax
  neg    %rax
  sbb    %eax,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ftrace_peek_registers(pid_t child, struct user_regs_struct *regs) {
  assert(child != 0);
  assert(regs != NULL);
  errno = 0;
  if (ptrace(PTRACE_GETREGS, child, 0, regs) && errno)
    return (-1);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ftrace_peek_registers>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  setne  %dil
  push   %rbx
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rcx
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    D10(%rip),%rax
  mov    D2(%rip),%rbx
  mov    (%rax),%edi
  movq   $0x0,(%rbx)
  call   <ptrace@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L7
  mov    (%rbx),%rax
  neg    %rax
  sbb    %eax,%eax
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ftrace_peek_registers(pid_t child, struct user_regs_struct *regs) {
  assert(child != 0);
  assert(regs != NULL);
  errno = 0;
  if (ptrace(PTRACE_GETREGS, child, 0, regs) && errno)
    return (-1);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L23
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <charatatime@plt>
  jmp    L23
L27:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <charatatime@plt>
L23:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D18: output from child


tool: D6: output from parent


assistant: ```c
int main() {
  pid_t pid;
  if ((pid = fork()) < 0) {
  } else if (pid == 0) {
    charatatime("output from child\n");
  } else {
    charatatime("output from parent\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L19
  jne    L18
  lea    D9(%rip),%rdi
  call   <charatatime@plt>
L19:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L18:
  lea    D11(%rip),%rdi
  call   <charatatime@plt>
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D11
datatype: string

tool: D9: output from child


tool: D11: output from parent


assistant: ```c
int main() {
  pid_t pid;
  if ((pid = fork()) < 0) {
  } else if (pid == 0) {
    charatatime("output from child\n");
  } else {
    charatatime("output from parent\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L28
  jne    L16
  lea    D15(%rip),%rdi
  call   <charatatime@plt>
L28:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L16:
  lea    D3(%rip),%rdi
  call   <charatatime@plt>
  jmp    L28
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D3
type: string

tool: D15: output from child


tool: D3: output from parent


assistant: ```c
int main() {
  pid_t pid;
  if ((pid = fork()) < 0) {
  } else if (pid == 0) {
    charatatime("output from child\n");
  } else {
    charatatime("output from parent\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L0
  jne    L12
  lea    D7(%rip),%rdi
  call   <charatatime@plt>
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L12:
  lea    D1(%rip),%rdi
  call   <charatatime@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D7: output from child


tool: D1: output from parent


assistant: ```c
int main() {
  pid_t pid;
  if ((pid = fork()) < 0) {
  } else if (pid == 0) {
    charatatime("output from child\n");
  } else {
    charatatime("output from parent\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printDeadEnds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <move@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L3:
  mov    -0x20(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    $0x23,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void printDeadEnds(int startX, int startY, int xIncrement, int yIncrement, int randNum) {
  move((startY), (startX));
  for (int i = 0; i < randNum; i++) {
    startY = startY + yIncrement;
    startX = startX + xIncrement;
    mvaddch((startY), (startX), '#');
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printDeadEnds>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %ecx,%r15d
  mov    %r8d,%r13d
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <move@plt>
  test   %r13d,%r13d
  jle    L5
  mov    $0x0,%r12d
L12:
  add    %r15d,%ebp
  add    %r14d,%ebx
  mov    $0x23,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mvaddch@plt>
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  jne    L12
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void printDeadEnds(int startX, int startY, int xIncrement, int yIncrement, int randNum) {
  move((startY), (startX));
  for (int i = 0; i < randNum; i++) {
    startY = startY + yIncrement;
    startX = startX + xIncrement;
    mvaddch((startY), (startX), '#');
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printDeadEnds>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <move@plt>
  test   %r13d,%r13d
  jle    L11
  xor    %r12d,%r12d
L5:
  add    %r15d,%ebp
  add    %r14d,%ebx
  mov    $0x23,%edx
  add    $0x1,%r12d
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mvaddch@plt>
  cmp    %r12d,%r13d
  jne    L5
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void printDeadEnds(int startX, int startY, int xIncrement, int yIncrement, int randNum) {
  move((startY), (startX));
  for (int i = 0; i < randNum; i++) {
    startY = startY + yIncrement;
    startX = startX + xIncrement;
    mvaddch((startY), (startX), '#');
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printDeadEnds>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <move@plt>
  test   %r13d,%r13d
  jle    L4
  xor    %r12d,%r12d
L9:
  add    %r15d,%ebp
  add    %r14d,%ebx
  mov    $0x23,%edx
  add    $0x1,%r12d
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mvaddch@plt>
  cmp    %r12d,%r13d
  jne    L9
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void printDeadEnds(int startX, int startY, int xIncrement, int yIncrement, int randNum) {
  move((startY), (startX));
  for (int i = 0; i < randNum; i++) {
    startY = startY + yIncrement;
    startX = startX + xIncrement;
    mvaddch((startY), (startX), '#');
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SHA1_force_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L19:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L9:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L19
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *SHA1_force_memset(void *s, int v, size_t n) {
  volatile unsigned char *p = (volatile unsigned char *)s;
  while (n--)
    *p++ = v;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SHA1_force_memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L10
  add    %rdi,%rdx
  mov    %rdi,%rcx
L0:
  mov    %rcx,%r8
  add    $0x1,%rcx
  mov    %sil,(%r8)
  cmp    %rcx,%rdx
  jne    L0
L10:
  ret
```

assistant: ```c
void *SHA1_force_memset(void *s, int v, size_t n) {
  volatile unsigned char *p = (volatile unsigned char *)s;
  while (n--)
    *p++ = v;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SHA1_force_memset>:
  endbr64
  mov    %rdi,%rax
  lea    (%rdi,%rdx,1),%r8
  mov    %rdi,%rcx
  test   %rdx,%rdx
  je     L18
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rcx,%rdx
  add    $0x1,%rcx
  mov    %sil,(%rdx)
  cmp    %r8,%rcx
  jne    L1
L18:
  ret
```

assistant: ```c
void *SHA1_force_memset(void *s, int v, size_t n) {
  volatile unsigned char *p = (volatile unsigned char *)s;
  while (n--)
    *p++ = v;
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SHA1_force_memset>:
  endbr64
  mov    %rdi,%rax
  lea    (%rdi,%rdx,1),%r8
  mov    %rdi,%rcx
  test   %rdx,%rdx
  je     L9
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rcx,%rdx
  add    $0x1,%rcx
  mov    %sil,(%rdx)
  cmp    %r8,%rcx
  jne    L8
L9:
  ret
```

assistant: ```c
void *SHA1_force_memset(void *s, int v, size_t n) {
  volatile unsigned char *p = (volatile unsigned char *)s;
  while (n--)
    *p++ = v;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unwanghash32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sar    $0x10,%eax
  xor    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  imul   $0xffbff7ff,%eax,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x6,%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0xc,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x12,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x18,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x1e,%eax
  xor    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  imul   $0x38e38e39,%eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0xa,%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x14,%eax
  xor    %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x1e,%eax
  xor    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  imul   $0xbfff7fff,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t unwanghash32(uint32_t hashval) {
  uint32_t k6 = hashval;
  uint32_t k5 = k6 ^ (k6 >> 16);
  uint32_t k4 = 4290770943 * ~k5;
  uint32_t k3 = k4 ^ (k4 >> 6) ^ (k4 >> 12) ^ (k4 >> 18) ^ (k4 >> 24) ^ (k4 >> 30);
  uint32_t k2 = 954437177 * k3;
  uint32_t k1 = k2 ^ (k2 >> 10) ^ (k2 >> 20) ^ (k2 >> 30);
  uint32_t k0 = 3221192703 * ~k1;
  return k0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unwanghash32>:
  endbr64
  mov    %edi,%eax
  sar    $0x10,%eax
  xor    %edi,%eax
  not    %eax
  imul   $0xffbff7ff,%eax,%eax
  mov    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0xc,%ecx
  xor    %ecx,%edx
  xor    %eax,%edx
  mov    %eax,%ecx
  sar    $0x12,%ecx
  xor    %ecx,%edx
  mov    %eax,%ecx
  sar    $0x18,%ecx
  xor    %ecx,%edx
  sar    $0x1e,%eax
  xor    %eax,%edx
  imul   $0x38e38e39,%edx,%edx
  mov    %edx,%eax
  sar    $0xa,%eax
  mov    %edx,%ecx
  sar    $0x14,%ecx
  xor    %ecx,%eax
  xor    %edx,%eax
  sar    $0x1e,%edx
  xor    %edx,%eax
  not    %eax
  imul   $0xbfff7fff,%eax,%eax
  ret
```

assistant: ```c
uint32_t unwanghash32(uint32_t hashval) {
  uint32_t k6 = hashval;
  uint32_t k5 = k6 ^ (k6 >> 16);
  uint32_t k4 = 4290770943 * ~k5;
  uint32_t k3 = k4 ^ (k4 >> 6) ^ (k4 >> 12) ^ (k4 >> 18) ^ (k4 >> 24) ^ (k4 >> 30);
  uint32_t k2 = 954437177 * k3;
  uint32_t k1 = k2 ^ (k2 >> 10) ^ (k2 >> 20) ^ (k2 >> 30);
  uint32_t k0 = 3221192703 * ~k1;
  return k0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unwanghash32>:
  endbr64
  mov    %edi,%eax
  sar    $0x10,%eax
  xor    %edi,%eax
  not    %eax
  imul   $0xffbff7ff,%eax,%eax
  mov    %eax,%edx
  mov    %eax,%ecx
  sar    $0xc,%ecx
  sar    $0x6,%edx
  xor    %ecx,%edx
  mov    %eax,%ecx
  xor    %eax,%edx
  sar    $0x12,%ecx
  xor    %ecx,%edx
  mov    %eax,%ecx
  sar    $0x1e,%eax
  sar    $0x18,%ecx
  xor    %ecx,%edx
  xor    %eax,%edx
  imul   $0x38e38e39,%edx,%edx
  mov    %edx,%eax
  mov    %edx,%ecx
  sar    $0xa,%eax
  sar    $0x14,%ecx
  xor    %ecx,%eax
  xor    %edx,%eax
  sar    $0x1e,%edx
  xor    %edx,%eax
  not    %eax
  imul   $0xbfff7fff,%eax,%eax
  ret
```

assistant: ```c
uint32_t unwanghash32(uint32_t hashval) {
  uint32_t k6 = hashval;
  uint32_t k5 = k6 ^ (k6 >> 16);
  uint32_t k4 = 4290770943 * ~k5;
  uint32_t k3 = k4 ^ (k4 >> 6) ^ (k4 >> 12) ^ (k4 >> 18) ^ (k4 >> 24) ^ (k4 >> 30);
  uint32_t k2 = 954437177 * k3;
  uint32_t k1 = k2 ^ (k2 >> 10) ^ (k2 >> 20) ^ (k2 >> 30);
  uint32_t k0 = 3221192703 * ~k1;
  return k0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RmatIdentity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L57
L22:
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  D8(%rip),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  jmp    L51
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
L51:
  addl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x2,-0x8(%rbp)
  jle    L17
  addl   $0x1,-0x4(%rbp)
L57:
  cmpl   $0x2,-0x4(%rbp)
  jle    L22
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: f32

tool: D8: 1

assistant: ```c
void RmatIdentity(float (*rmat)[3l]) {
  signed int i;
  signed int j = 0;
  while (j < 3) {
    i = 0;
    while (i < 3) {
      if (i == j)
        rmat[(signed long int)j][(signed long int)i] = (float)1.000000;
      else
        rmat[(signed long int)j][(signed long int)i] = (float)0.000000;
      i = i + 1;
    }
    j = j + 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RmatIdentity>:
  endbr64
  movss  D2(%rip),%xmm0
  movss  %xmm0,(%rdi)
  movl   $0x0,0x4(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0x0,0xc(%rdi)
  movss  %xmm0,0x10(%rdi)
  movl   $0x0,0x14(%rdi)
  movl   $0x0,0x18(%rdi)
  movl   $0x0,0x1c(%rdi)
  movss  %xmm0,0x20(%rdi)
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: f32

tool: D2: 1

assistant: ```c
void RmatIdentity(float (*rmat)[3l]) {
  signed int i;
  signed int j = 0;
  while (j < 3) {
    i = 0;
    while (i < 3) {
      if (i == j)
        rmat[(signed long int)j][(signed long int)i] = (float)1.000000;
      else
        rmat[(signed long int)j][(signed long int)i] = (float)0.000000;
      i = i + 1;
    }
    j = j + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RmatIdentity>:
  endbr64
  movq   $0x3f800000,(%rdi)
  movq   $0x0,0x8(%rdi)
  movq   $0x3f800000,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movl   $0x3f800000,0x20(%rdi)
  ret
```

assistant: ```c
void RmatIdentity(float (*rmat)[3l]) {
  signed int i;
  signed int j = 0;
  while (j < 3) {
    i = 0;
    while (i < 3) {
      if (i == j)
        rmat[(signed long int)j][(signed long int)i] = (float)1.000000;
      else
        rmat[(signed long int)j][(signed long int)i] = (float)0.000000;
      i = i + 1;
    }
    j = j + 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RmatIdentity>:
  endbr64
  movss  D2(%rip),%xmm0
  movl   $0x3f800000,0x20(%rdi)
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: f32

tool: D2: 1

assistant: ```c
void RmatIdentity(float (*rmat)[3l]) {
  signed int i;
  signed int j = 0;
  while (j < 3) {
    i = 0;
    while (i < 3) {
      if (i == j)
        rmat[(signed long int)j][(signed long int)i] = (float)1.000000;
      else
        rmat[(signed long int)j][(signed long int)i] = (float)0.000000;
      i = i + 1;
    }
    j = j + 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<newpixgrid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%r9
  lea    -0x1c(%rbp),%r8
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  mov    -0x3c(%rbp),%esi
  mov    -0x38(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0xc(%rbp),%rdi
  push   %rdi
  lea    -0x10(%rbp),%rdi
  push   %rdi
  lea    -0x14(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <XGetGeometry@plt>
  add    $0x20,%rsp
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <updiv@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned char *newpixgrid(Display *dpy, Drawable d) {
  Window _0;
  int _1, _2;
  unsigned int width, height;
  unsigned int _3, _4;
  XGetGeometry(dpy, d, &_0, &_1, &_2, &width, &height, &_3, &_4);
  return malloc(updiv(width * height, 8));
}
```
user: Translate the below assembly code into C programming language:

```asm
<newpixgrid>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  sub    $0x8,%rsp
  lea    0x2c(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%rax
  push   %rax
  lea    0x34(%rsp),%rax
  push   %rax
  lea    0x38(%rsp),%r9
  lea    0x34(%rsp),%r8
  call   <XGetGeometry@plt>
  add    $0x20,%rsp
  mov    0x18(%rsp),%edi
  imul   0x1c(%rsp),%edi
  mov    $0x8,%esi
  call   <updiv@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *newpixgrid(Display *dpy, Drawable d) {
  Window _0;
  int _1, _2;
  unsigned int width, height;
  unsigned int _3, _4;
  XGetGeometry(dpy, d, &_0, &_1, &_2, &width, &height, &_3, &_4);
  return malloc(updiv(width * height, 8));
}
```