ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<WalkSum2>:
  endbr64
  test   %esi,%esi
  je     L16
  push   %r13
  lea    (%rdx,%rdx,1),%eax
  mov    %esi,%r9d
  mov    %rdi,%rcx
  push   %r12
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  lea    (%rax,%rdx,1),%esi
  push   %rbp
  push   %rbx
L13:
  lea    (%rdx,%r11,1),%r13d
  lea    (%rdx,%rax,1),%r12d
  mov    (%rcx,%rax,4),%eax
  lea    (%rsi,%r13,1),%ebp
  lea    (%rsi,%r12,1),%ebx
  add    (%rcx,%r13,4),%eax
  add    (%rcx,%r11,4),%eax
  lea    (%rdx,%rbp,1),%r8d
  lea    (%rdx,%rbx,1),%edi
  add    (%rcx,%r12,4),%eax
  add    (%rcx,%rbp,4),%eax
  mov    %r8d,%r11d
  add    (%rcx,%r11,4),%eax
  mov    %edi,%r11d
  add    (%rcx,%rbx,4),%eax
  add    (%rcx,%r11,4),%eax
  lea    (%rsi,%r8,1),%r11d
  add    %eax,%r10d
  lea    (%rsi,%rdi,1),%eax
  cmp    %r11d,%r9d
  ja     L13
  pop    %rbx
  mov    %r10d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned WalkSum2(const unsigned *p, unsigned num, unsigned step) {
  unsigned b = 0;
  unsigned i;
  for (i = 0; i < num;) {
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
  }
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<WalkSum2>:
  endbr64
  test   %esi,%esi
  je     L4
  push   %r13
  lea    (%rdx,%rdx,1),%eax
  mov    %esi,%r9d
  mov    %rdi,%rcx
  push   %r12
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  lea    (%rax,%rdx,1),%esi
  push   %rbp
  push   %rbx
L6:
  lea    (%rdx,%r11,1),%r13d
  lea    (%rdx,%rax,1),%r12d
  mov    (%rcx,%rax,4),%eax
  lea    (%rsi,%r13,1),%ebp
  lea    (%rsi,%r12,1),%ebx
  add    (%rcx,%r13,4),%eax
  add    (%rcx,%r11,4),%eax
  lea    (%rdx,%rbp,1),%r8d
  lea    (%rdx,%rbx,1),%edi
  add    (%rcx,%r12,4),%eax
  add    (%rcx,%rbp,4),%eax
  mov    %r8d,%r11d
  add    (%rcx,%r11,4),%eax
  mov    %edi,%r11d
  add    (%rcx,%rbx,4),%eax
  add    (%rcx,%r11,4),%eax
  lea    (%rsi,%r8,1),%r11d
  add    %eax,%r10d
  lea    (%rsi,%rdi,1),%eax
  cmp    %r11d,%r9d
  ja     L6
  pop    %rbx
  mov    %r10d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned WalkSum2(const unsigned *p, unsigned num, unsigned step) {
  unsigned b = 0;
  unsigned i;
  for (i = 0; i < num;) {
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
    b += p[i];
    i += step;
  }
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<loop1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x27000(%rsp),%r11
L32:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L32
  sub    $0x130,%rsp
  mov    %edi,-0x27124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x27124(%rbp),%eax
  mov    %eax,-0x27110(%rbp)
  mov    -0x27124(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x27104(%rbp)
  mov    -0x27124(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1388c(%rbp)
  movl   $0x2,-0x27114(%rbp)
  jmp    L12
L25:
  mov    -0x27124(%rbp),%eax
  imul   -0x27114(%rbp),%eax
  mov    %eax,%edx
  mov    -0x27114(%rbp),%eax
  mov    %edx,-0x27110(%rbp,%rax,4)
  mov    -0x27114(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%eax
  mov    -0x27110(%rbp,%rax,4),%edx
  mov    -0x27124(%rbp),%eax
  add    %eax,%edx
  mov    -0x27114(%rbp),%eax
  mov    %edx,-0x1d4d0(%rbp,%rax,4)
  mov    -0x27114(%rbp),%eax
  mov    -0x1d4d0(%rbp,%rax,4),%edx
  mov    -0x27114(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  mov    -0x27110(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x27114(%rbp),%eax
  mov    %edx,-0x13890(%rbp,%rax,4)
  mov    -0x27114(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  mov    -0x13890(%rbp,%rax,4),%edx
  mov    -0x27124(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x27114(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x27114(%rbp),%eax
  mov    %edx,-0x9c50(%rbp,%rax,4)
  addl   $0x1,-0x27114(%rbp)
L12:
  cmpl   $0x270e,-0x27114(%rbp)
  jbe    L25
  mov    -0x1d4d8(%rbp),%edx
  mov    -0x13894(%rbp),%eax
  add    %eax,%edx
  mov    -0x9c58(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
int loop1(int k) {
  unsigned int i;
  int a[10000], b[10000], c[10000], d[10000];
  a[0] = k;
  a[3] = k * 2;
  c[1] = k + 1;
  for (i = 2; i < (10000 - 1); i++) {
    a[i] = k * i;
    b[i] = a[i - 2] + k;
    c[i] = b[i] + a[i + 1];
    d[i] = c[i - 1] + k + i;
  }
  return a[10000 - 2] + b[10000 - 1] + c[10000 - 2] + d[10000 - 2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loop1>:
  endbr64
  lea    -0x27000(%rsp),%r11
L20:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L20
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x27108(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  lea    (%rdi,%rdi,1),%esi
  mov    %esi,0xc(%rsp)
  lea    0x1(%rdi),%eax
  mov    %eax,0x13884(%rsp)
  mov    %rsp,%rdx
  mov    $0x2,%eax
L16:
  mov    %esi,0x8(%rdx)
  mov    %edi,%ecx
  add    (%rdx),%ecx
  mov    %ecx,0x9c40(%rsp,%rax,4)
  add    0xc(%rdx),%ecx
  mov    %ecx,0x13880(%rsp,%rax,4)
  mov    %edi,%ecx
  add    0x1387c(%rsp,%rax,4),%ecx
  add    %eax,%ecx
  mov    %ecx,0x1d4c0(%rsp,%rax,4)
  add    $0x1,%rax
  add    %edi,%esi
  add    $0x4,%rdx
  cmp    $0x270f,%rax
  jne    L16
  mov    0x1387c(%rsp),%eax
  add    0x9c38(%rsp),%eax
  add    0x1d4b8(%rsp),%eax
  add    0x270f8(%rsp),%eax
  mov    0x27108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x27118,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int loop1(int k) {
  unsigned int i;
  int a[10000], b[10000], c[10000], d[10000];
  a[0] = k;
  a[3] = k * 2;
  c[1] = k + 1;
  for (i = 2; i < (10000 - 1); i++) {
    a[i] = k * i;
    b[i] = a[i - 2] + k;
    c[i] = b[i] + a[i + 1];
    d[i] = c[i - 1] + k + i;
  }
  return a[10000 - 2] + b[10000 - 1] + c[10000 - 2] + d[10000 - 2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<loop1>:
  endbr64
  lea    -0x27000(%rsp),%r11
L5:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L5
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x27108(%rsp)
  xor    %eax,%eax
  lea    (%rdi,%rdi,1),%esi
  mov    %edi,(%rsp)
  lea    0x1(%rdi),%eax
  mov    %esi,0xc(%rsp)
  mov    %rsp,%rdx
  lea    0x9c40(%rsp),%r10
  lea    0x13880(%rsp),%r8
  mov    %eax,0x13884(%rsp)
  lea    0x1d4c0(%rsp),%r9
  mov    $0x2,%eax
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rdx),%ecx
  mov    %esi,0x8(%rdx)
  add    %edi,%esi
  add    $0x4,%rdx
  add    %edi,%ecx
  mov    %ecx,(%r10,%rax,4)
  add    0x8(%rdx),%ecx
  mov    %ecx,(%r8,%rax,4)
  mov    -0x4(%r8,%rax,4),%ecx
  add    %edi,%ecx
  add    %eax,%ecx
  mov    %ecx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    $0x270f,%rax
  jne    L18
  mov    0x1387c(%rsp),%eax
  add    0x9c38(%rsp),%eax
  add    0x1d4b8(%rsp),%eax
  add    0x270f8(%rsp),%eax
  mov    0x27108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x27118,%rsp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int loop1(int k) {
  unsigned int i;
  int a[10000], b[10000], c[10000], d[10000];
  a[0] = k;
  a[3] = k * 2;
  c[1] = k + 1;
  for (i = 2; i < (10000 - 1); i++) {
    a[i] = k * i;
    b[i] = a[i - 2] + k;
    c[i] = b[i] + a[i + 1];
    d[i] = c[i - 1] + k + i;
  }
  return a[10000 - 2] + b[10000 - 1] + c[10000 - 2] + d[10000 - 2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<loop1>:
  endbr64
  lea    -0x27000(%rsp),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0x118,%rsp
  mov    0x4(%rsp),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x27108(%rsp)
  xor    %eax,%eax
  lea    (%rdi,%rdi,1),%r8d
  lea    0x1(%rdi),%eax
  mov    %edi,(%rsp)
  mov    %r8d,0xc(%rsp)
  mov    %edi,%edx
  lea    0x8(%rsp),%rsi
  lea    0x9c48(%rsp),%r9
  mov    %eax,0x13884(%rsp)
  lea    0x13880(%rsp),%r10
  mov    %edi,%eax
  mov    $0x5,%edi
L5:
  add    %edx,%eax
  mov    %r8d,(%rsi)
  add    %edx,%ecx
  add    $0xc,%rsi
  mov    %eax,(%r9)
  add    -0x8(%rsi),%eax
  add    $0xc,%r9
  mov    %eax,-0xc(%r10,%rdi,4)
  lea    (%r8,%rdx,1),%eax
  mov    (%rsi),%r8d
  mov    %ecx,-0x8(%r9)
  add    -0x4(%rsi),%ecx
  add    %eax,%r8d
  mov    %ecx,-0x8(%r10,%rdi,4)
  lea    (%rdx,%rax,1),%ecx
  mov    %r8d,-0x4(%r10,%rdi,4)
  add    $0x3,%rdi
  lea    (%rdx,%rcx,1),%r8d
  mov    %eax,-0x8(%rsi)
  mov    %ecx,-0x4(%rsi)
  mov    %eax,-0x4(%r9)
  cmp    $0x2711,%rdi
  jne    L5
  mov    0x9c30(%rsp),%esi
  imul   $0x270e,%edx,%eax
  movd   %edx,%xmm5
  movdqa D19(%rip),%xmm1
  movdqa D4(%rip),%xmm3
  pshufd $0x0,%xmm5,%xmm4
  xor    %ecx,%ecx
  lea    0x13884(%rsp),%r8
  add    %edx,%esi
  add    0x9c3c(%rsp),%esi
  lea    0x1d4c8(%rsp),%rdi
  mov    %esi,0x1d4b8(%rsp)
  nopw   0x0(%rax,%rax,1)
L38:
  movdqu (%r8,%rcx,1),%xmm0
  movdqa %xmm1,%xmm2
  paddd  %xmm3,%xmm1
  paddd  %xmm4,%xmm0
  paddd  %xmm2,%xmm0
  movups %xmm0,(%rdi,%rcx,1)
  add    $0x10,%rcx
  cmp    $0x9c30,%rcx
  jne    L38
  add    0x1387c(%rsp),%eax
  add    0x1d4b4(%rsp),%edx
  add    %esi,%eax
  lea    0x270e(%rax,%rdx,1),%eax
  mov    0x27108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x27118,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: byte[16]
name: disassemble_data
arguments: data_label: D4
type: byte[16]

tool: {"D19": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D4": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int loop1(int k) {
  unsigned int i;
  int a[10000], b[10000], c[10000], d[10000];
  a[0] = k;
  a[3] = k * 2;
  c[1] = k + 1;
  for (i = 2; i < (10000 - 1); i++) {
    a[i] = k * i;
    b[i] = a[i - 2] + k;
    c[i] = b[i] + a[i + 1];
    d[i] = c[i - 1] + k + i;
  }
  return a[10000 - 2] + b[10000 - 1] + c[10000 - 2] + d[10000 - 2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dotprod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float dotprod(float B[], float C[], int n) {
  int i;
  float sum = 0;
#pragma omp target map(to : B [0:n], C [0:n]) map(tofrom : sum)
#pragma omp teams num_teams(8) thread_limit(16) reduction(+ : sum)
#pragma omp distribute parallel for reduction(+ : sum) dist_schedule(static, 1024) schedule(static, 64)
  for (i = 0; i < n; i++)
    sum += B[i] * C[i];
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dotprod>:
  endbr64
  test   %edx,%edx
  jle    L28
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L6:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L1:
  movaps %xmm1,%xmm0
  ret
L28:
  pxor   %xmm1,%xmm1
  jmp    L1
```

assistant: ```c
float dotprod(float B[], float C[], int n) {
  int i;
  float sum = 0;
#pragma omp target map(to : B [0:n], C [0:n]) map(tofrom : sum)
#pragma omp teams num_teams(8) thread_limit(16) reduction(+ : sum)
#pragma omp distribute parallel for reduction(+ : sum) dist_schedule(static, 1024) schedule(static, 64)
  for (i = 0; i < n; i++)
    sum += B[i] * C[i];
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dotprod>:
  endbr64
  test   %edx,%edx
  jle    L7
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L11:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L11
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float dotprod(float B[], float C[], int n) {
  int i;
  float sum = 0;
#pragma omp target map(to : B [0:n], C [0:n]) map(tofrom : sum)
#pragma omp teams num_teams(8) thread_limit(16) reduction(+ : sum)
#pragma omp distribute parallel for reduction(+ : sum) dist_schedule(static, 1024) schedule(static, 64)
  for (i = 0; i < n; i++)
    sum += B[i] * C[i];
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dotprod>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L27
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L63
  mov    %edx,%edi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L49:
  movups (%rcx,%rax,1),%xmm1
  movups (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulps  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L49
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L25
L42:
  movslq %eax,%r8
  movss  (%rcx,%r8,4),%xmm1
  mulss  (%rsi,%r8,4),%xmm1
  lea    0x0(,%r8,4),%rdi
  lea    0x1(%rax),%r8d
  addss  %xmm1,%xmm0
  cmp    %r8d,%edx
  jle    L16
  movss  0x4(%rcx,%rdi,1),%xmm1
  mulss  0x4(%rsi,%rdi,1),%xmm1
  add    $0x2,%eax
  addss  %xmm1,%xmm0
  cmp    %eax,%edx
  jle    L16
  movss  0x8(%rsi,%rdi,1),%xmm1
  mulss  0x8(%rcx,%rdi,1),%xmm1
  addss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  pxor   %xmm0,%xmm0
L16:
  ret
  nopl   (%rax)
L25:
  ret
L63:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L42
```

assistant: ```c
float dotprod(float B[], float C[], int n) {
  int i;
  float sum = 0;
#pragma omp target map(to : B [0:n], C [0:n]) map(tofrom : sum)
#pragma omp teams num_teams(8) thread_limit(16) reduction(+ : sum)
#pragma omp distribute parallel for reduction(+ : sum) dist_schedule(static, 1024) schedule(static, 64)
  for (i = 0; i < n; i++)
    sum += B[i] * C[i];
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L43
L7:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L26
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L26:
  addq   $0x1,-0x10(%rbp)
L43:
  cmpq   $0xffff,-0x10(%rbp)
  jbe    L7
  movq   $0x0,-0x10(%rbp)
  jmp    L18
L47:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputc@plt>
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L47
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t write_bin(uint8_t *code, FILE *stream) {
  size_t i;
  size_t last = 0;
  for (i = 0; i < 65536; i++) {
    if (code[i] != 0)
      last = i;
  }
  for (i = 0; i <= last; i++)
    fputc(code[i], stream);
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    $0x0,%ebx
  mov    $0x0,%eax
L11:
  cmpq   $0x0,0x0(%rbp,%rax,8)
  cmovne %rax,%rbx
  add    $0x1,%rax
  cmp    $0x10000,%rax
  jne    L11
  mov    $0x0,%r12d
L18:
  mov    0x0(%rbp,%r12,8),%rdi
  mov    %r13,%rsi
  call   <fputc@plt>
  add    $0x1,%r12
  cmp    %r12,%rbx
  jae    L18
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t write_bin(uint8_t *code, FILE *stream) {
  size_t i;
  size_t last = 0;
  for (i = 0; i < 65536; i++) {
    if (code[i] != 0)
      last = i;
  }
  for (i = 0; i <= last; i++)
    fputc(code[i], stream);
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_bin>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmpq   $0x0,0x0(%rbp,%rax,8)
  cmovne %rax,%rbx
  add    $0x1,%rax
  cmp    $0x10000,%rax
  jne    L0
  lea    0x1(%rbx),%r14
  xor    %r12d,%r12d
  nopl   (%rax)
L13:
  mov    0x0(%rbp,%r12,8),%rdi
  mov    %r13,%rsi
  call   <fputc@plt>
  mov    %r12,%rax
  add    $0x1,%r12
  cmp    %rax,%rbx
  jne    L13
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t write_bin(uint8_t *code, FILE *stream) {
  size_t i;
  size_t last = 0;
  for (i = 0; i < 65536; i++) {
    if (code[i] != 0)
      last = i;
  }
  for (i = 0; i <= last; i++)
    fputc(code[i], stream);
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_bin>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmpq   $0x0,0x0(%rbp,%rax,8)
  cmovne %rax,%rbx
  add    $0x1,%rax
  cmp    $0x10000,%rax
  jne    L0
  lea    0x1(%rbx),%r14
  xor    %r12d,%r12d
  nopl   (%rax)
L1:
  mov    0x0(%rbp,%r12,8),%rdi
  mov    %r13,%rsi
  call   <fputc@plt>
  mov    %r12,%rax
  add    $0x1,%r12
  cmp    %rax,%rbx
  jne    L1
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
size_t write_bin(uint8_t *code, FILE *stream) {
  size_t i;
  size_t last = 0;
  for (i = 0; i < 65536; i++) {
    if (code[i] != 0)
      last = i;
  }
  for (i = 0; i <= last; i++)
    fputc(code[i], stream);
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zero_padding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L57:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L57
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x24(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L38
L14:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L25
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  jmp    L34
L25:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L34:
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zero_padding(double *sig, double *pad, int sig_length, int pad_length, int methode) {
  int i = 0;
  double mean = 0.0;
  for (i = 0; i < sig_length; i++) {
    mean += (double)sig[i];
    pad[i] = (double)sig[i];
  }
  mean /= ((double)sig_length);
  for (i = sig_length; i < pad_length; i++) {
    if (methode == 0) {
      pad[i] = 0.0;
    } else {
      pad[i] = mean;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zero_padding>:
  endbr64
  test   %edx,%edx
  jle    L62
  mov    %edx,%r9d
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L60:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L60
L32:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  %xmm0,%xmm1
  cmp    %ecx,%edx
  jge    L4
  movslq %edx,%rdi
  lea    (%rsi,%rdi,8),%rax
  sub    $0x1,%ecx
  sub    %edx,%ecx
  add    %rdi,%rcx
  lea    0x8(%rsi,%rcx,8),%rdx
  jmp    L31
L62:
  pxor   %xmm1,%xmm1
  jmp    L32
L18:
  movsd  %xmm1,(%rax)
L75:
  add    $0x8,%rax
  cmp    %rdx,%rax
  je     L4
L31:
  test   %r8d,%r8d
  jne    L18
  movq   $0x0,(%rax)
  jmp    L75
L4:
  ret
```

assistant: ```c
void zero_padding(double *sig, double *pad, int sig_length, int pad_length, int methode) {
  int i = 0;
  double mean = 0.0;
  for (i = 0; i < sig_length; i++) {
    mean += (double)sig[i];
    pad[i] = (double)sig[i];
  }
  mean /= ((double)sig_length);
  for (i = sig_length; i < pad_length; i++) {
    if (methode == 0) {
      pad[i] = 0.0;
    } else {
      pad[i] = mean;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zero_padding>:
  endbr64
  test   %edx,%edx
  jle    L10
  pxor   %xmm2,%xmm2
  movslq %edx,%r9
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  nopl   0x0(%rax)
L74:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %r9,%rax
  jne    L74
L43:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  %xmm0,%xmm1
  cmp    %ecx,%edx
  jge    L79
  sub    $0x1,%ecx
  movslq %edx,%rdi
  sub    %edx,%ecx
  lea    (%rsi,%rdi,8),%rax
  add    %rdi,%rcx
  lea    0x8(%rsi,%rcx,8),%rdx
  test   %r8d,%r8d
  jne    L68
L24:
  movsd  %xmm2,(%rax)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L24
L79:
  ret
  xchg   %ax,%ax
L68:
  movapd %xmm1,%xmm2
  add    $0x8,%rax
  movsd  %xmm2,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L24
  jmp    L79
  nopl   0x0(%rax)
L10:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm1
  jmp    L43
```

assistant: ```c
void zero_padding(double *sig, double *pad, int sig_length, int pad_length, int methode) {
  int i = 0;
  double mean = 0.0;
  for (i = 0; i < sig_length; i++) {
    mean += (double)sig[i];
    pad[i] = (double)sig[i];
  }
  mean /= ((double)sig_length);
  for (i = sig_length; i < pad_length; i++) {
    if (methode == 0) {
      pad[i] = 0.0;
    } else {
      pad[i] = mean;
    }
  }
}
```