ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<VIM_MARB_SetThumbbufMem>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movzbl %dil,%esi
  mov    $0x240c,%edi
  call   <VIM_HIF_SetReg8@plt>
  movzbl %bh,%esi
  mov    $0x240b,%edi
  call   <VIM_HIF_SetReg8@plt>
  mov    %rbx,%rsi
  shr    $0x10,%rsi
  movzbl %sil,%esi
  mov    $0x240a,%edi
  call   <VIM_HIF_SetReg8@plt>
  lea    (%rbx,%rbp,1),%esi
  movzbl %sil,%esi
  mov    $0x240f,%edi
  call   <VIM_HIF_SetReg8@plt>
  add    %rbp,%rbx
  movzbl %bh,%esi
  mov    $0x240e,%edi
  call   <VIM_HIF_SetReg8@plt>
  shr    $0x10,%rbx
  movzbl %bl,%esi
  mov    $0x240d,%edi
  call   <VIM_HIF_SetReg8@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void VIM_MARB_SetThumbbufMem(unsigned long StartAdd, unsigned long Size) {
  VIM_HIF_SetReg8((0x2400 + 0x00C), (unsigned char)StartAdd);
  VIM_HIF_SetReg8((0x2400 + 0x00B), (unsigned char)(StartAdd >> 8));
  VIM_HIF_SetReg8((0x2400 + 0x00A), (unsigned char)(StartAdd >> 16));
  VIM_HIF_SetReg8((0x2400 + 0x00F), (unsigned char)(StartAdd + Size));
  VIM_HIF_SetReg8((0x2400 + 0x00E), (unsigned char)((StartAdd + Size) >> 8));
  VIM_HIF_SetReg8((0x2400 + 0x00D), (unsigned char)((StartAdd + Size) >> 16));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VIM_MARB_SetThumbbufMem>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  movzbl %dil,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x240c,%edi
  sub    $0x8,%rsp
  call   <VIM_HIF_SetReg8@plt>
  movzbl %bh,%esi
  mov    $0x240b,%edi
  call   <VIM_HIF_SetReg8@plt>
  mov    %rbx,%rsi
  mov    $0x240a,%edi
  shr    $0x10,%rsi
  movzbl %sil,%esi
  call   <VIM_HIF_SetReg8@plt>
  lea    (%rbx,%rbp,1),%esi
  mov    $0x240f,%edi
  add    %rbp,%rbx
  movzbl %sil,%esi
  call   <VIM_HIF_SetReg8@plt>
  movzbl %bh,%esi
  mov    $0x240e,%edi
  shr    $0x10,%rbx
  call   <VIM_HIF_SetReg8@plt>
  add    $0x8,%rsp
  movzbl %bl,%esi
  mov    $0x240d,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <VIM_HIF_SetReg8@plt>
```

assistant: ```c
void VIM_MARB_SetThumbbufMem(unsigned long StartAdd, unsigned long Size) {
  VIM_HIF_SetReg8((0x2400 + 0x00C), (unsigned char)StartAdd);
  VIM_HIF_SetReg8((0x2400 + 0x00B), (unsigned char)(StartAdd >> 8));
  VIM_HIF_SetReg8((0x2400 + 0x00A), (unsigned char)(StartAdd >> 16));
  VIM_HIF_SetReg8((0x2400 + 0x00F), (unsigned char)(StartAdd + Size));
  VIM_HIF_SetReg8((0x2400 + 0x00E), (unsigned char)((StartAdd + Size) >> 8));
  VIM_HIF_SetReg8((0x2400 + 0x00D), (unsigned char)((StartAdd + Size) >> 16));
}
```
user: Translate the below assembly code into C programming language:

```asm
<VIM_MARB_SetThumbbufMem>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  movzbl %dil,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x240c,%edi
  sub    $0x8,%rsp
  call   <VIM_HIF_SetReg8@plt>
  movzbl %bh,%esi
  mov    $0x240b,%edi
  call   <VIM_HIF_SetReg8@plt>
  mov    %rbx,%rsi
  mov    $0x240a,%edi
  shr    $0x10,%rsi
  movzbl %sil,%esi
  call   <VIM_HIF_SetReg8@plt>
  lea    (%rbx,%rbp,1),%esi
  mov    $0x240f,%edi
  add    %rbp,%rbx
  movzbl %sil,%esi
  call   <VIM_HIF_SetReg8@plt>
  movzbl %bh,%esi
  mov    $0x240e,%edi
  shr    $0x10,%rbx
  call   <VIM_HIF_SetReg8@plt>
  add    $0x8,%rsp
  movzbl %bl,%esi
  mov    $0x240d,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <VIM_HIF_SetReg8@plt>
```

assistant: ```c
void VIM_MARB_SetThumbbufMem(unsigned long StartAdd, unsigned long Size) {
  VIM_HIF_SetReg8((0x2400 + 0x00C), (unsigned char)StartAdd);
  VIM_HIF_SetReg8((0x2400 + 0x00B), (unsigned char)(StartAdd >> 8));
  VIM_HIF_SetReg8((0x2400 + 0x00A), (unsigned char)(StartAdd >> 16));
  VIM_HIF_SetReg8((0x2400 + 0x00F), (unsigned char)(StartAdd + Size));
  VIM_HIF_SetReg8((0x2400 + 0x00E), (unsigned char)((StartAdd + Size) >> 8));
  VIM_HIF_SetReg8((0x2400 + 0x00D), (unsigned char)((StartAdd + Size) >> 16));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x0,%r12d
  mov    -0x20(%rbp),%ebx
  cmpq   $0x0,-0x18(%rbp)
  je     L34
  cmpl   $0x0,-0x1c(%rbp)
  jne    L36
L34:
  mov    %ebx,%eax
  jmp    L2
L3:
  mov    %r12d,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %ebx,%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %eax,%ebx
  add    $0x1,%r12d
L36:
  cmp    -0x1c(%rbp),%r12d
  jb     L3
  mov    %ebx,%eax
L2:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
uint8_t _checksum(const void *buf, unsigned int buflen, uint8_t checksum_initial) {
  register unsigned int i = 0;
  register int8_t checksum = checksum_initial;
  if (buf == NULL || buflen == 0)
    return (checksum);
  for (; i < buflen; i++)
    checksum = (checksum + ((uint8_t *)buf)[i]) % 256;
  return (checksum);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_checksum>:
  endbr64
  mov    %edx,%eax
  test   %rdi,%rdi
  je     L8
  test   %esi,%esi
  je     L8
  mov    $0x0,%ecx
L20:
  add    (%rdi,%rcx,4),%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  add    $0x1,%rcx
  cmp    %ecx,%esi
  ja     L20
L8:
  ret
```

assistant: ```c
uint8_t _checksum(const void *buf, unsigned int buflen, uint8_t checksum_initial) {
  register unsigned int i = 0;
  register int8_t checksum = checksum_initial;
  if (buf == NULL || buflen == 0)
    return (checksum);
  for (; i < buflen; i++)
    checksum = (checksum + ((uint8_t *)buf)[i]) % 256;
  return (checksum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_checksum>:
  endbr64
  mov    %edx,%eax
  test   %rdi,%rdi
  je     L11
  test   %esi,%esi
  je     L11
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L26:
  add    (%rdi,%rcx,4),%eax
  add    $0x1,%rcx
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  cmp    %ecx,%esi
  ja     L26
L11:
  ret
```

assistant: ```c
uint8_t _checksum(const void *buf, unsigned int buflen, uint8_t checksum_initial) {
  register unsigned int i = 0;
  register int8_t checksum = checksum_initial;
  if (buf == NULL || buflen == 0)
    return (checksum);
  for (; i < buflen; i++)
    checksum = (checksum + ((uint8_t *)buf)[i]) % 256;
  return (checksum);
}
```
user: What is the c source code of the assembly code below:

```asm
<_checksum>:
  endbr64
  mov    %edx,%eax
  test   %rdi,%rdi
  je     L17
  test   %esi,%esi
  je     L17
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L16:
  add    (%rdi,%rcx,4),%eax
  add    $0x1,%rcx
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  cmp    %ecx,%esi
  ja     L16
L17:
  ret
```

assistant: ```c
uint8_t _checksum(const void *buf, unsigned int buflen, uint8_t checksum_initial) {
  register unsigned int i = 0;
  register int8_t checksum = checksum_initial;
  if (buf == NULL || buflen == 0)
    return (checksum);
  for (; i < buflen; i++)
    checksum = (checksum + ((uint8_t *)buf)[i]) % 256;
  return (checksum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<count_unique_factors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x2,D30(%rip)
  jmp    L4
L36:
  mov    D30(%rip),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L0
  mov    D30(%rip),%esi
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,-0x14(%rbp)
  mov    D30(%rip),%eax
  cmp    %eax,-0x4(%rbp)
  je     L9
  mov    D30(%rip),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L9:
  mov    D30(%rip),%eax
  sub    $0x1,%eax
  mov    %eax,D98(%rip)
L0:
  mov    D98(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D98(%rip)
L4:
  mov    D98(%rip),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L36
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_unique_factors(int m) {
  int n = 0, last = 0;
  static int i;
  for (i = 2; i <= m; i++) {
    if (m % i == 0) {
      m /= i;
      if (last != i)
        last = i, n++;
      i--;
    }
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_unique_factors>:
  endbr64
  movl   $0x2,D19(%rip)
  cmp    $0x1,%edi
  jle    L47
  mov    $0x0,%r8d
  mov    $0x0,%esi
  mov    $0x2,%ecx
  jmp    L5
L44:
  add    $0x1,%ecx
  cmp    %edi,%ecx
  jg     L4
L5:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L44
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  cmp    %r8d,%ecx
  setne  %al
  movzbl %al,%eax
  add    %eax,%esi
  mov    %ecx,%r8d
  lea    -0x1(%rcx),%ecx
  jmp    L44
L4:
  mov    %ecx,D10(%rip)
L0:
  mov    %esi,%eax
  ret
L47:
  mov    $0x0,%esi
  jmp    L0
```

assistant: ```c
int count_unique_factors(int m) {
  int n = 0, last = 0;
  static int i;
  for (i = 2; i <= m; i++) {
    if (m % i == 0) {
      m /= i;
      if (last != i)
        last = i, n++;
      i--;
    }
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_unique_factors>:
  endbr64
  movl   $0x2,D2(%rip)
  cmp    $0x1,%edi
  jle    L22
  xor    %esi,%esi
  xor    %r8d,%r8d
  mov    $0x2,%ecx
  jmp    L3
  nop
L15:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jl     L0
L3:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L15
  mov    %eax,%edi
  xor    %eax,%eax
  cmp    %esi,%ecx
  mov    %ecx,%esi
  setne  %al
  add    %eax,%r8d
  cmp    %ecx,%edi
  jge    L3
L0:
  mov    %ecx,D17(%rip)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L22:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_unique_factors(int m) {
  int n = 0, last = 0;
  static int i;
  for (i = 2; i <= m; i++) {
    if (m % i == 0) {
      m /= i;
      if (last != i)
        last = i, n++;
      i--;
    }
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<count_unique_factors>:
  endbr64
  movl   $0x2,D15(%rip)
  cmp    $0x1,%edi
  jle    L29
  xor    %esi,%esi
  xor    %r8d,%r8d
  mov    $0x2,%ecx
  jmp    L38
  nop
L39:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jl     L33
L38:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L39
  mov    %eax,%edi
  xor    %eax,%eax
  cmp    %esi,%ecx
  mov    %ecx,%esi
  setne  %al
  add    %eax,%r8d
  cmp    %ecx,%edi
  jge    L38
L33:
  mov    %ecx,D17(%rip)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L29:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_unique_factors(int m) {
  int n = 0, last = 0;
  static int i;
  for (i = 2; i <= m; i++) {
    if (m % i == 0) {
      m /= i;
      if (last != i)
        last = i, n++;
      i--;
    }
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  jmp    L39
L26:
  lea    D16(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L23
L47:
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L28:
  shll   -0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  sar    $0x7,%eax
  or     %eax,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
L9:
  cmpl   $0x7,-0x1c(%rbp)
  jle    L28
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  lea    D51(%rip),%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rcx,%rdx,1)
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L47
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x1,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
L39:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  mov    $0x2000,%edx
  mov    $0x8,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L26
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  static uint8_t inbuf[8192 * 8];
  static uint8_t outbuf[8192];
  size_t n;
  while ((n = fread(inbuf, 8, 8192, stdin))) {
    uint8_t *p = inbuf;
    for (size_t i = 0; i < n; i++) {
      uint8_t pack = 0;
      for (int j = 0; j < 8; j++) {
        pack <<= 1;
        pack |= (*p++) >> 7;
      }
      outbuf[i] = pack;
    }
    fwrite(outbuf, 1, n, stdout);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbp
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
  jmp    L57
L45:
  mov    %edx,(%r8)
  add    $0x20,%rdi
  add    $0x4,%r8
  cmp    %r9,%r8
  je     L51
L6:
  lea    -0x20(%rdi),%rcx
  mov    %ebx,%edx
L30:
  add    %edx,%edx
  add    $0x4,%rcx
  mov    -0x4(%rcx),%esi
  sar    $0x7,%esi
  or     %esi,%edx
  cmp    %rdi,%rcx
  jne    L30
  jmp    L45
L51:
  mov    D55(%rip),%rdx
  mov    (%rdx),%ecx
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
L57:
  mov    D36(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x2000,%edx
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  test   %rax,%rax
  je     L32
  lea    D56(%rip),%rdi
  lea    D2(%rip),%r8
  lea    (%r8,%rax,4),%r9
  jmp    L6
L32:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(void) {
  static uint8_t inbuf[8192 * 8];
  static uint8_t outbuf[8192];
  size_t n;
  while ((n = fread(inbuf, 8, 8192, stdin))) {
    uint8_t *p = inbuf;
    for (size_t i = 0; i < n; i++) {
      uint8_t pack = 0;
      for (int j = 0; j < 8; j++) {
        pack <<= 1;
        pack |= (*p++) >> 7;
      }
      outbuf[i] = pack;
    }
    fwrite(outbuf, 1, n, stdout);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D46(%rip),%rbp
  push   %rbx
  lea    0x20(%rbp),%r13
  lea    D44(%rip),%rbx
  sub    $0x8,%rsp
  mov    D35(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%r12),%ecx
  mov    $0x2000,%edx
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  test   %rax,%rax
  je     L1
  mov    %r13,%rdi
  lea    D44(%rip),%r8
  lea    (%rbx,%rax,4),%r9
  nopl   0x0(%rax)
L33:
  lea    -0x20(%rdi),%rcx
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    (%rcx),%esi
  add    %edx,%edx
  add    $0x4,%rcx
  sar    $0x7,%esi
  or     %esi,%edx
  cmp    %rdi,%rcx
  jne    L16
  mov    %edx,(%r8)
  add    $0x4,%r8
  lea    0x20(%rcx),%rdi
  cmp    %r9,%r8
  jne    L33
  mov    D6(%rip),%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    (%rdx),%ecx
  mov    %rax,%rdx
  call   <fwrite@plt>
  jmp    L11
L1:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(void) {
  static uint8_t inbuf[8192 * 8];
  static uint8_t outbuf[8192];
  size_t n;
  while ((n = fread(inbuf, 8, 8192, stdin))) {
    uint8_t *p = inbuf;
    for (size_t i = 0; i < n; i++) {
      uint8_t pack = 0;
      for (int j = 0; j < 8; j++) {
        pack <<= 1;
        pack |= (*p++) >> 7;
      }
      outbuf[i] = pack;
    }
    fwrite(outbuf, 1, n, stdout);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <recurse>
  jmp    L18
L6:
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string

tool: D9: %i


assistant: ```c
int recurse(int val) {
  printf("%i\n", val);
  if (val) {
    return recurse(val - 1);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<recurse>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L1
L10:
  mov    %ebx,%eax
  pop    %rbx
  ret
L1:
  lea    -0x1(%rbx),%edi
  call   <recurse>
  mov    %eax,%ebx
  jmp    L10
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: %i


assistant: ```c
int recurse(int val) {
  printf("%i\n", val);
  if (val) {
    return recurse(val - 1);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recurse>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L1
  nopl   (%rax)
L6:
  sub    $0x1,%ebx
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D6: %i


assistant: ```c
int recurse(int val) {
  printf("%i\n", val);
  if (val) {
    return recurse(val - 1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<recurse>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L10
  nopl   (%rax)
L19:
  sub    $0x1,%ebx
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L19
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: %i


assistant: ```c
int recurse(int val) {
  printf("%i\n", val);
  if (val) {
    return recurse(val - 1);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ucRcAT1608_Auth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x2525,%edx
  lea    D28(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  addl   $0x8,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  add    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L2
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <vWriteLogTxt@plt>
  mov    $0x1,%eax
  jmp    L16
L2:
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D28
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D28: %u(b008

tool: D16: )

tool: D18: _AT1608_Auth iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_Auth(unsigned char *Gc) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(b008", 9509);
  memcpy(psFunCall + uiDataLen, Gc, 8);
  uiDataLen += 8;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_Auth iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_ucRcAT1608_Auth>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x2525,%edx
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0x9(%rbx),%rdi
  mov    $0x8,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movw   $0x29,0x11(%rbx)
  mov    $0x1,%edx
  mov    $0x12,%esi
  mov    %rbx,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  test   %ebp,%ebp
  jne    L12
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <vWriteLogTxt@plt>
  mov    $0x1,%eax
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D18: %u(b008

tool: D7: _AT1608_Auth iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_Auth(unsigned char *Gc) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(b008", 9509);
  memcpy(psFunCall + uiDataLen, Gc, 8);
  uiDataLen += 8;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_Auth iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ucRcAT1608_Auth>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x64,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x2525,%edx
  lea    D9(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rsi
  lea    0x9(%rbp),%rdi
  mov    $0x8,%edx
  call   <memcpy@plt>
  mov    $0x29,%eax
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    %ax,0x11(%rbp)
  mov    $0x12,%esi
  call   <iDoRemoteFunc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  test   %r12d,%r12d
  jne    L6
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <iGetParaInt@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r12d,%esi
  lea    D8(%rip),%rdi
  call   <vWriteLogTxt@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string

tool: D9: %u(b008

tool: D8: _AT1608_Auth iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_Auth(unsigned char *Gc) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(100);
  uiDataLen = sprintf(psFunCall, "%u(b008", 9509);
  memcpy(psFunCall + uiDataLen, Gc, 8);
  uiDataLen += 8;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_Auth iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```