ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<minDistance>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%r8d
  mov    $0x0,%eax
  jmp    L24
L26:
  add    $0x1,%rax
  cmp    $0x9,%rax
  je     L47
L24:
  cmpl   $0x0,(%rsi,%rax,4)
  jne    L26
  mov    (%rdi,%rax,4),%edx
  cmp    %r8d,%edx
  jg     L26
  mov    %eax,%r9d
  mov    %edx,%r8d
  jmp    L26
L47:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int minDistance(int distance[], int shortest[]) {
  int minV = INT_MAX;
  int min_index;
  int i;
  for (i = 0; i < 9; i++)
    if (shortest[i] == 0 && distance[i] <= minV) {
      minV = distance[i];
      min_index = i;
    }
  return min_index;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minDistance>:
  endbr64
  mov    D8(%rip),%rax
  xor    %r8d,%r8d
  mov    (%rax),%ecx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rsi,%rax,4),%edx
  test   %edx,%edx
  jne    L29
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L29
  mov    %eax,%r8d
  mov    %edx,%ecx
L29:
  add    $0x1,%rax
  cmp    $0x9,%rax
  jne    L17
  mov    %r8d,%eax
  ret
```

assistant: ```c
int minDistance(int distance[], int shortest[]) {
  int minV = INT_MAX;
  int min_index;
  int i;
  for (i = 0; i < 9; i++)
    if (shortest[i] == 0 && distance[i] <= minV) {
      minV = distance[i];
      min_index = i;
    }
  return min_index;
}
```
user: Translate the below assembly code into C programming language:

```asm
<minDistance>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rsi),%r8d
  mov    (%rax),%eax
  test   %r8d,%r8d
  jne    L68
  mov    (%rdi),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L68:
  mov    0x4(%rsi),%r8d
  test   %r8d,%r8d
  jne    L14
  mov    0x4(%rdi),%edx
  cmp    %edx,%eax
  jge    L171
L88:
  mov    0x8(%rsi),%ecx
  test   %ecx,%ecx
  jne    L0
  mov    0x8(%rdi),%edx
  cmp    %edx,%eax
  jge    L116
L0:
  mov    0xc(%rsi),%edx
  test   %edx,%edx
  jne    L5
  mov    0xc(%rdi),%edx
  cmp    %edx,%eax
  jge    L9
L5:
  mov    0x10(%rsi),%r11d
  test   %r11d,%r11d
  jne    L72
  mov    0x10(%rdi),%edx
  cmp    %edx,%eax
  jge    L38
L72:
  mov    0x14(%rsi),%r10d
  test   %r10d,%r10d
  jne    L8
  mov    0x14(%rdi),%edx
  cmp    %edx,%eax
  jge    L21
L8:
  mov    0x18(%rsi),%r9d
  test   %r9d,%r9d
  jne    L6
  mov    0x18(%rdi),%edx
  cmp    %edx,%eax
  jge    L201
L6:
  mov    0x1c(%rsi),%ecx
  test   %ecx,%ecx
  jne    L37
  mov    0x1c(%rdi),%edx
  cmp    %edx,%eax
  jge    L71
L37:
  mov    0x20(%rsi),%edx
  test   %edx,%edx
  jne    L94
  cmp    %eax,0x20(%rdi)
  mov    $0x8,%eax
  cmovle %eax,%r8d
L94:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L14:
  xor    %r8d,%r8d
  jmp    L88
L71:
  mov    %edx,%eax
  mov    $0x7,%r8d
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L201:
  mov    %edx,%eax
  mov    $0x6,%r8d
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %edx,%eax
  mov    $0x5,%r8d
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %edx,%eax
  mov    $0x4,%r8d
  jmp    L72
  nopl   (%rax)
L9:
  mov    %edx,%eax
  mov    $0x3,%r8d
  jmp    L5
  nopl   (%rax)
L116:
  mov    %edx,%eax
  mov    $0x2,%r8d
  jmp    L0
  nopl   (%rax)
L171:
  mov    %edx,%eax
  mov    $0x1,%r8d
  jmp    L88
```

assistant: ```c
int minDistance(int distance[], int shortest[]) {
  int minV = INT_MAX;
  int min_index;
  int i;
  for (i = 0; i < 9; i++)
    if (shortest[i] == 0 && distance[i] <= minV) {
      minV = distance[i];
      min_index = i;
    }
  return min_index;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L32
  cmpl   $0x0,-0x8(%rbp)
  jle    L32
  cmpl   $0x0,-0xc(%rbp)
  jle    L32
  mov    $0x0,%eax
  jmp    L5
L32:
  mov    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int t(int a, int b, int c) {
  if (a > 0 && b > 0 && c > 0)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t>:
  endbr64
  test   %esi,%esi
  setg   %al
  test   %edx,%edx
  setg   %dl
  and    %edx,%eax
  test   %edi,%edi
  setg   %dl
  and    %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int t(int a, int b, int c) {
  if (a > 0 && b > 0 && c > 0)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<t>:
  endbr64
  test   %esi,%esi
  setg   %al
  test   %edx,%edx
  setg   %dl
  and    %edx,%eax
  test   %edi,%edi
  setg   %dl
  and    %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int t(int a, int b, int c) {
  if (a > 0 && b > 0 && c > 0)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<t>:
  endbr64
  test   %esi,%esi
  setg   %al
  test   %edx,%edx
  setg   %dl
  and    %edx,%eax
  test   %edi,%edi
  setg   %dl
  and    %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int t(int a, int b, int c) {
  if (a > 0 && b > 0 && c > 0)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pxgstrf_resetrep_col>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%ebx
  jmp    L7
L18:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%r12d
  movslq %r12d,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  add    $0x1,%ebx
L7:
  cmp    -0x14(%rbp),%ebx
  jl     L18
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void pxgstrf_resetrep_col(const int nseg, const int *segrep, int *repfnz) {
  register int i, irep;
  for (i = 0; i < nseg; ++i) {
    irep = segrep[i];
    repfnz[irep] = (-1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pxgstrf_resetrep_col>:
  endbr64
  test   %edi,%edi
  jle    L2
  mov    %rsi,%rax
  lea    -0x1(%rdi),%ecx
  lea    0x4(%rsi,%rcx,4),%rsi
L9:
  movslq (%rax),%rcx
  movl   $0xffffffff,(%rdx,%rcx,4)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L9
L2:
  ret
```

assistant: ```c
void pxgstrf_resetrep_col(const int nseg, const int *segrep, int *repfnz) {
  register int i, irep;
  for (i = 0; i < nseg; ++i) {
    irep = segrep[i];
    repfnz[irep] = (-1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pxgstrf_resetrep_col>:
  endbr64
  test   %edi,%edi
  jle    L16
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rcx
L7:
  movslq (%rsi),%rax
  add    $0x4,%rsi
  movl   $0xffffffff,(%rdx,%rax,4)
  cmp    %rcx,%rsi
  jne    L7
L16:
  ret
```

assistant: ```c
void pxgstrf_resetrep_col(const int nseg, const int *segrep, int *repfnz) {
  register int i, irep;
  for (i = 0; i < nseg; ++i) {
    irep = segrep[i];
    repfnz[irep] = (-1);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<pxgstrf_resetrep_col>:
  endbr64
  test   %edi,%edi
  jle    L15
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rcx
L0:
  movslq (%rsi),%rax
  add    $0x4,%rsi
  movl   $0xffffffff,(%rdx,%rax,4)
  cmp    %rsi,%rcx
  jne    L0
L15:
  ret
```

assistant: ```c
void pxgstrf_resetrep_col(const int nseg, const int *segrep, int *repfnz) {
  register int i, irep;
  for (i = 0; i < nseg; ++i) {
    irep = segrep[i];
    repfnz[irep] = (-1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_fnv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x811c9dc5,-0x4(%rbp)
  jmp    L13
L10:
  mov    -0x4(%rbp),%eax
  imul   $0x1000193,%eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L13:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L10
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash_fnv(char *in, size_t len) {
  unsigned hashv = 2166136261UL;
  while (len--)
    hashv = (hashv * 16777619) ^ *in++;
  return hashv;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash_fnv>:
  endbr64
  test   %rsi,%rsi
  je     L16
  add    %rdi,%rsi
  mov    $0x811c9dc5,%eax
L12:
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdi
  movsbl -0x1(%rdi),%edx
  xor    %edx,%eax
  cmp    %rdi,%rsi
  jne    L12
  ret
L16:
  mov    $0x811c9dc5,%eax
  ret
```

assistant: ```c
unsigned hash_fnv(char *in, size_t len) {
  unsigned hashv = 2166136261UL;
  while (len--)
    hashv = (hashv * 16777619) ^ *in++;
  return hashv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash_fnv>:
  endbr64
  test   %rsi,%rsi
  je     L2
  add    %rdi,%rsi
  mov    $0x811c9dc5,%eax
  nopl   0x0(%rax)
L3:
  imul   $0x1000193,%eax,%eax
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %edx,%eax
  cmp    %rdi,%rsi
  jne    L3
  ret
  nopl   (%rax)
L2:
  mov    $0x811c9dc5,%eax
  ret
```

assistant: ```c
unsigned hash_fnv(char *in, size_t len) {
  unsigned hashv = 2166136261UL;
  while (len--)
    hashv = (hashv * 16777619) ^ *in++;
  return hashv;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash_fnv>:
  endbr64
  test   %rsi,%rsi
  je     L17
  add    %rdi,%rsi
  mov    $0x811c9dc5,%eax
  nopl   0x0(%rax)
L4:
  imul   $0x1000193,%eax,%eax
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %edx,%eax
  cmp    %rsi,%rdi
  jne    L4
  ret
  nopl   (%rax)
L17:
  mov    $0x811c9dc5,%eax
  ret
```

assistant: ```c
unsigned hash_fnv(char *in, size_t len) {
  unsigned hashv = 2166136261UL;
  while (len--)
    hashv = (hashv * 16777619) ^ *in++;
  return hashv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<diffmonths>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <tmcpy@plt>
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x5,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movq   $0x0,0x18(%rax)
  mov    -0x38(%rbp),%rax
  movq   $0x0,0x10(%rax)
  mov    -0x38(%rbp),%rax
  movl   $0x5,(%rax)
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%ecx
  mov    -0x38(%rbp),%rax
  mov    0x4(%rax),%esi
  mov    -0x38(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  lea    (%rsi,%rax,1),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int diffmonths(const time_t *startDate, const time_t *endDate) {
  struct tm ref, *current;
  current = localtime(endDate);
  tmcpy(&ref, current);
  ref.tm_sec = 0;
  ref.tm_min = 0;
  ref.tm_hour = 5;
  current = localtime(startDate);
  current->tm_sec = 0;
  current->tm_min = 0;
  current->tm_hour = 5;
  return (ref.tm_mon + 12 * ref.tm_year) - (current->tm_mon + 12 * current->tm_year);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<diffmonths>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <localtime@plt>
  mov    %rax,%rsi
  mov    %rsp,%rdi
  call   <tmcpy@plt>
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x5,(%rsp)
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    %rax,%rdx
  movq   $0x0,0x18(%rax)
  movq   $0x0,0x10(%rax)
  movl   $0x5,(%rax)
  mov    0x8(%rsp),%eax
  lea    (%rax,%rax,2),%ecx
  mov    0x4(%rsp),%eax
  lea    (%rax,%rcx,4),%eax
  mov    0x8(%rdx),%ecx
  lea    (%rcx,%rcx,2),%ecx
  mov    0x4(%rdx),%edx
  lea    (%rdx,%rcx,4),%edx
  sub    %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x30,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int diffmonths(const time_t *startDate, const time_t *endDate) {
  struct tm ref, *current;
  current = localtime(endDate);
  tmcpy(&ref, current);
  ref.tm_sec = 0;
  ref.tm_min = 0;
  ref.tm_hour = 5;
  current = localtime(startDate);
  current->tm_sec = 0;
  current->tm_min = 0;
  current->tm_hour = 5;
  return (ref.tm_mon + 12 * ref.tm_year) - (current->tm_mon + 12 * current->tm_year);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<diffmonths>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <localtime@plt>
  mov    %rsp,%rdi
  mov    %rax,%rsi
  call   <tmcpy@plt>
  mov    %rbp,%rdi
  movl   $0x5,(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <localtime@plt>
  mov    %rax,%rdx
  movq   $0x0,0x18(%rax)
  movq   $0x0,0x10(%rax)
  movl   $0x5,(%rax)
  mov    0x8(%rsp),%eax
  lea    (%rax,%rax,2),%ecx
  mov    0x4(%rsp),%eax
  lea    (%rax,%rcx,4),%eax
  mov    0x8(%rdx),%ecx
  mov    0x4(%rdx),%edx
  lea    (%rcx,%rcx,2),%ecx
  lea    (%rdx,%rcx,4),%edx
  sub    %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int diffmonths(const time_t *startDate, const time_t *endDate) {
  struct tm ref, *current;
  current = localtime(endDate);
  tmcpy(&ref, current);
  ref.tm_sec = 0;
  ref.tm_min = 0;
  ref.tm_hour = 5;
  current = localtime(startDate);
  current->tm_sec = 0;
  current->tm_min = 0;
  current->tm_hour = 5;
  return (ref.tm_mon + 12 * ref.tm_year) - (current->tm_mon + 12 * current->tm_year);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<diffmonths>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <localtime@plt>
  mov    %rsp,%rdi
  mov    %rax,%rsi
  call   <tmcpy@plt>
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  movl   $0x5,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  mov    %rax,%rdx
  movl   $0x5,(%rax)
  movups %xmm0,0x10(%rax)
  mov    0x8(%rsp),%eax
  lea    (%rax,%rax,2),%ecx
  mov    0x4(%rsp),%eax
  lea    (%rax,%rcx,4),%eax
  mov    0x8(%rdx),%ecx
  mov    0x4(%rdx),%edx
  lea    (%rcx,%rcx,2),%ecx
  lea    (%rdx,%rcx,4),%edx
  sub    %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int diffmonths(const time_t *startDate, const time_t *endDate) {
  struct tm ref, *current;
  current = localtime(endDate);
  tmcpy(&ref, current);
  ref.tm_sec = 0;
  ref.tm_min = 0;
  ref.tm_hour = 5;
  current = localtime(startDate);
  current->tm_sec = 0;
  current->tm_min = 0;
  current->tm_hour = 5;
  return (ref.tm_mon + 12 * ref.tm_year) - (current->tm_mon + 12 * current->tm_year);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L31
L7:
  cmpl   $0x1,-0x14(%rbp)
  jne    L3
  mov    $0x1,%eax
  jmp    L31
L3:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L31:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 0) {
    return 0;
  }
  if (n == 1) {
    return 1;
  }
  return fib(n - 1) + fib(n - 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  je     L4
  cmp    $0x1,%edi
  je     L4
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  lea    0x0(%rbp,%rax,1),%ebx
L4:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 0) {
    return 0;
  }
  if (n == 1) {
    return 1;
  }
  return fib(n - 1) + fib(n - 2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L16
L8:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L36
L1:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L36:
  cmpl   $0x2,-0x14(%rbp)
  jle    L1
  addl   $0x1,-0x18(%rbp)
L16:
  cmpl   $0x6,-0x18(%rbp)
  jle    L8
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D16
type_infered: string

tool: D19: dnanstdev

tool: D7: # c::%s:len=%d


tool: D16: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanstdev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D26(%rip),%r15
  jmp    L8
L27:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L4
L8:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L23:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L23
  jmp    L27
L4:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: string

tool: D26: dnanstdev

tool: D14: # c::%s:len=%d


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanstdev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D27(%rip),%r15
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L3:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L11:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L11
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L3
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D27
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D20
type_infered: string

tool: D27: dnanstdev

tool: D5: # c::%s:len=%d


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanstdev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```