ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L1
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: %s 

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  for (int i = 1; i < argc; i++) {
    printf("%s ", argv[i]);
  }
  printf("\n");
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L9
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
  lea    D6(%rip),%rbp
L2:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L2
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %s 

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  for (int i = 1; i < argc; i++) {
    printf("%s ", argv[i]);
  }
  printf("\n");
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L8
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  lea    D9(%rip),%rbp
L15:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: %s 

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  for (int i = 1; i < argc; i++) {
    printf("%s ", argv[i]);
  }
  printf("\n");
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L3
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  lea    D3(%rip),%rbp
L5:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: %s 

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  for (int i = 1; i < argc; i++) {
    printf("%s ", argv[i]);
  }
  printf("\n");
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L1:
  cmpl   $0x9,-0x4(%rbp)
  jne    L11
  movl   $0x0,-0x8(%rbp)
  jmp    L54
L36:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L54:
  cmpl   $0x3,-0x8(%rbp)
  jle    L36
  jmp    L35
L11:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L35:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L1
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int inputChar;
  inputChar = 0;
  while ((inputChar = getchar()) != EOF) {
    if (inputChar == '\t') {
      for (int i = 0; i < 4; ++i) {
        printf(" ");
      }
    } else {
      printf("%c", inputChar);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L1
L25:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
L1:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L28
  cmp    $0x9,%eax
  je     L25
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L1
L28:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int inputChar;
  inputChar = 0;
  while ((inputChar = getchar()) != EOF) {
    if (inputChar == '\t') {
      for (int i = 0; i < 4; ++i) {
        printf(" ");
      }
    } else {
      printf("%c", inputChar);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
L35:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L39
L7:
  cmp    $0x9,%edi
  je     L14
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L7
L39:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L14:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L35
```

assistant: ```c
int main() {
  int inputChar;
  inputChar = 0;
  while ((inputChar = getchar()) != EOF) {
    if (inputChar == '\t') {
      for (int i = 0; i < 4; ++i) {
        printf(" ");
      }
    } else {
      printf("%c", inputChar);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D0(%rip),%rbx
L11:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L6
L31:
  cmp    $0x9,%edi
  je     L9
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L31
L6:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L11
```

assistant: ```c
int main() {
  int inputChar;
  inputChar = 0;
  while ((inputChar = getchar()) != EOF) {
    if (inputChar == '\t') {
      for (int i = 0; i < 4; ++i) {
        printf(" ");
      }
    } else {
      printf("%c", inputChar);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mode_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  mov    %rax,%rdi
  call   <ftypelet@plt>
  mov    -0x10(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzwl -0x4(%rbp),%eax
  and    $0x1c0,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <rwx@plt>
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzwl -0x4(%rbp),%eax
  shl    $0x3,%eax
  movzwl %ax,%eax
  and    $0x1c0,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <rwx@plt>
  mov    -0x10(%rbp),%rax
  lea    0x7(%rax),%rdx
  movzwl -0x4(%rbp),%eax
  shl    $0x6,%eax
  movzwl %ax,%eax
  and    $0x1c0,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <rwx@plt>
  movzwl -0x4(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <setst@plt>
  nop
  leave
  ret
```

assistant: ```c
void mode_string(unsigned short mode, char *str) {
  str[0] = ftypelet((long)mode);
  rwx((unsigned short)((mode & 0700) << 0), &str[1]);
  rwx((unsigned short)((mode & 0070) << 3), &str[4]);
  rwx((unsigned short)((mode & 0007) << 6), &str[7]);
  setst((unsigned short)mode, str);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mode_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  movzwl %di,%edi
  call   <ftypelet@plt>
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rsi
  mov    %ebx,%edi
  and    $0x1c0,%edi
  call   <rwx@plt>
  lea    0x4(%rbp),%rsi
  lea    0x0(,%rbx,8),%edi
  and    $0x1c0,%edi
  call   <rwx@plt>
  lea    0x7(%rbp),%rsi
  mov    %ebx,%edi
  shl    $0x6,%edi
  and    $0x1c0,%edi
  call   <rwx@plt>
  movzwl %bx,%edi
  mov    %rbp,%rsi
  call   <setst@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mode_string(unsigned short mode, char *str) {
  str[0] = ftypelet((long)mode);
  rwx((unsigned short)((mode & 0700) << 0), &str[1]);
  rwx((unsigned short)((mode & 0070) << 3), &str[4]);
  rwx((unsigned short)((mode & 0007) << 6), &str[7]);
  setst((unsigned short)mode, str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mode_string>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  movzwl %di,%edi
  sub    $0x8,%rsp
  call   <ftypelet@plt>
  mov    %ebx,%edi
  lea    0x1(%rbp),%rsi
  mov    %al,0x0(%rbp)
  and    $0x1c0,%edi
  call   <rwx@plt>
  lea    0x0(,%rbx,8),%edi
  lea    0x4(%rbp),%rsi
  and    $0x1c0,%edi
  call   <rwx@plt>
  mov    %ebx,%edi
  lea    0x7(%rbp),%rsi
  shl    $0x6,%edi
  and    $0x1c0,%edi
  call   <rwx@plt>
  add    $0x8,%rsp
  movzwl %bx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1070 <setst@plt>
```

assistant: ```c
void mode_string(unsigned short mode, char *str) {
  str[0] = ftypelet((long)mode);
  rwx((unsigned short)((mode & 0700) << 0), &str[1]);
  rwx((unsigned short)((mode & 0070) << 3), &str[4]);
  rwx((unsigned short)((mode & 0007) << 6), &str[7]);
  setst((unsigned short)mode, str);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mode_string>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  movzwl %di,%edi
  sub    $0x8,%rsp
  call   <ftypelet@plt>
  mov    %ebx,%edi
  lea    0x1(%rbp),%rsi
  mov    %al,0x0(%rbp)
  and    $0x1c0,%edi
  call   <rwx@plt>
  lea    0x0(,%rbx,8),%edi
  lea    0x4(%rbp),%rsi
  and    $0x1c0,%edi
  call   <rwx@plt>
  mov    %ebx,%edi
  lea    0x7(%rbp),%rsi
  shl    $0x6,%edi
  and    $0x1c0,%edi
  call   <rwx@plt>
  add    $0x8,%rsp
  movzwl %bx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1070 <setst@plt>
```

assistant: ```c
void mode_string(unsigned short mode, char *str) {
  str[0] = ftypelet((long)mode);
  rwx((unsigned short)((mode & 0700) << 0), &str[1]);
  rwx((unsigned short)((mode & 0070) << 3), &str[4]);
  rwx((unsigned short)((mode & 0007) << 6), &str[7]);
  setst((unsigned short)mode, str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<logicalShift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  neg    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x20,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  shll   -0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  and    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int logicalShift(int x, int n) {
  int num = ~n + 1;
  int offset = (32 + num);
  int mask = ~0 << (offset + (~1 + 1));
  mask = mask << 1;
  mask = ~mask;
  x = x >> n;
  x = x & mask;
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<logicalShift>:
  endbr64
  mov    $0x1f,%ecx
  sub    %esi,%ecx
  mov    $0xfffffffe,%eax
  shl    %cl,%eax
  mov    %esi,%ecx
  sar    %cl,%edi
  not    %eax
  and    %edi,%eax
  ret
```

assistant: ```c
int logicalShift(int x, int n) {
  int num = ~n + 1;
  int offset = (32 + num);
  int mask = ~0 << (offset + (~1 + 1));
  mask = mask << 1;
  mask = ~mask;
  x = x >> n;
  x = x & mask;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<logicalShift>:
  endbr64
  mov    $0x1f,%ecx
  mov    $0xfffffffe,%eax
  sub    %esi,%ecx
  shl    %cl,%eax
  mov    %esi,%ecx
  sar    %cl,%edi
  not    %eax
  and    %edi,%eax
  ret
```

assistant: ```c
int logicalShift(int x, int n) {
  int num = ~n + 1;
  int offset = (32 + num);
  int mask = ~0 << (offset + (~1 + 1));
  mask = mask << 1;
  mask = ~mask;
  x = x >> n;
  x = x & mask;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<logicalShift>:
  endbr64
  mov    $0x1f,%ecx
  mov    $0xfffffffe,%eax
  sub    %esi,%ecx
  shl    %cl,%eax
  mov    %esi,%ecx
  sar    %cl,%edi
  not    %eax
  and    %edi,%eax
  ret
```

assistant: ```c
int logicalShift(int x, int n) {
  int num = ~n + 1;
  int offset = (32 + num);
  int mask = ~0 << (offset + (~1 + 1));
  mask = mask << 1;
  mask = ~mask;
  x = x >> n;
  x = x & mask;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RegulateName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
L41:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L56
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L56
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L56
  mov    -0x8(%rbp),%rax
  movb   $0x5f,(%rax)
  jmp    L22
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L22:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  nop
  nop
  leave
  ret
```

assistant: ```c
void RegulateName(char *name) {
  char *ptr;
  for (ptr = name; *ptr != '\0'; ptr++) {
    if (!isalnum(*ptr) && (*ptr != '.') && (*ptr != '-'))
      *ptr = '_';
    else
      *ptr = (char)tolower(*ptr);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RegulateName>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L23
  mov    $0x5f,%ebp
  jmp    L2
L40:
  movsbl (%rbx),%edi
  call   <tolower@plt>
L46:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L23
L2:
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L40
  movzbl (%rbx),%eax
  lea    -0x2d(%rax),%edx
  mov    %ebp,%eax
  cmp    $0x1,%dl
  jbe    L40
  jmp    L46
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void RegulateName(char *name) {
  char *ptr;
  for (ptr = name; *ptr != '\0'; ptr++) {
    if (!isalnum(*ptr) && (*ptr != '.') && (*ptr != '-'))
      *ptr = '_';
    else
      *ptr = (char)tolower(*ptr);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RegulateName>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L23
L27:
  call   <isalnum@plt>
  movsbl (%rbx),%edi
  test   %eax,%eax
  jne    L34
  lea    -0x2d(%rdi),%edx
  mov    $0x5f,%eax
  cmp    $0x1,%dl
  ja     L4
L34:
  call   <tolower@plt>
L4:
  mov    %al,(%rbx)
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L27
L23:
  pop    %rbx
  ret
```

assistant: ```c
void RegulateName(char *name) {
  char *ptr;
  for (ptr = name; *ptr != '\0'; ptr++) {
    if (!isalnum(*ptr) && (*ptr != '.') && (*ptr != '-'))
      *ptr = '_';
    else
      *ptr = (char)tolower(*ptr);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RegulateName>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
L2:
  call   <isalnum@plt>
  movsbl (%rbx),%edi
  test   %eax,%eax
  jne    L18
  lea    -0x2d(%rdi),%edx
  mov    $0x5f,%eax
  cmp    $0x1,%dl
  ja     L25
L18:
  call   <tolower@plt>
L25:
  mov    %al,(%rbx)
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L2
L6:
  pop    %rbx
  ret
```

assistant: ```c
void RegulateName(char *name) {
  char *ptr;
  for (ptr = name; *ptr != '\0'; ptr++) {
    if (!isalnum(*ptr) && (*ptr != '.') && (*ptr != '-'))
      *ptr = '_';
    else
      *ptr = (char)tolower(*ptr);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<psf_sanitize_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
L23:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <psf_isprint@plt>
  test   %rax,%rax
  je     L21
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  jmp    L3
L21:
  mov    $0x2e,%eax
L3:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  cmpl   $0x0,-0xc(%rbp)
  jg     L23
  nop
  nop
  leave
  ret
```

assistant: ```c
void psf_sanitize_string(char *cptr, int len) {
  do {
    len--;
    cptr[len] = psf_isprint(cptr[len]) ? cptr[len] : '.';
  } while (len > 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<psf_sanitize_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movslq %esi,%rbx
  mov    $0x2e,%r12d
  jmp    L38
L31:
  movzbl -0x1(%rbp,%rbx,1),%eax
L34:
  mov    %al,-0x1(%rbp,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jle    L5
L38:
  movsbl -0x1(%rbp,%rbx,1),%edi
  call   <psf_isprint@plt>
  mov    %rax,%rdx
  mov    %r12d,%eax
  test   %rdx,%rdx
  je     L34
  jmp    L31
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void psf_sanitize_string(char *cptr, int len) {
  do {
    len--;
    cptr[len] = psf_isprint(cptr[len]) ? cptr[len] : '.';
  } while (len > 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<psf_sanitize_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
L8:
  movsbl -0x1(%rbp,%rbx,1),%edi
  call   <psf_isprint@plt>
  mov    %rax,%r8
  mov    $0x2e,%eax
  test   %r8,%r8
  je     L10
  movzbl -0x1(%rbp,%rbx,1),%eax
L10:
  mov    %al,-0x1(%rbp,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void psf_sanitize_string(char *cptr, int len) {
  do {
    len--;
    cptr[len] = psf_isprint(cptr[len]) ? cptr[len] : '.';
  } while (len > 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psf_sanitize_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
L8:
  movsbl -0x1(%rbp,%rbx,1),%edi
  call   <psf_isprint@plt>
  test   %rax,%rax
  jne    L19
  movb   $0x2e,-0x1(%rbp,%rbx,1)
L19:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void psf_sanitize_string(char *cptr, int len) {
  do {
    len--;
    cptr[len] = psf_isprint(cptr[len]) ? cptr[len] : '.';
  } while (len > 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<resparse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  movl   $0x0,-0x24(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
L17:
  mov    -0x58(%rbp),%rdx
  mov    -0x50(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <readfd@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x48(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L37
  mov    -0x10(%rbp),%rdi
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <punch_hole@plt>
  test   %eax,%eax
  je     L18
L37:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jne    L7
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L17
L7:
  movl   $0x1,-0x24(%rbp)
  jmp    L32
L18:
  nop
L32:
  mov    -0x24(%rbp),%eax
  leave
  ret
```

assistant: ```c
bool resparse(int fd, off_t flen, size_t blksz, char *buf, size_t bufsz) {
  bool ret = false;
  off_t len, span = 0, offt = 0, rlen = 0;
  do {
    rlen = readfd(fd, buf, bufsz);
    if (rlen < 0)
      goto fail;
    len = rlen % blksz;
    rlen -= len;
    if (rlen > 0 && !punch_hole(fd, offt, blksz, buf, rlen))
      goto fail;
    offt += rlen + len;
  } while (rlen == bufsz && offt < flen);
  ret = true;
fail:
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<resparse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r12
  mov    %rcx,(%rsp)
  mov    %r8,%r14
  mov    $0x0,%ebp
  jmp    L18
L48:
  add    %rbx,%rbp
  cmp    %r13,%r14
  jne    L5
  cmp    0x8(%rsp),%rbp
  jae    L5
L18:
  mov    %r14,%rdx
  mov    (%rsp),%rsi
  mov    %r15d,%edi
  call   <readfd@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  div    %r12
  mov    %rbx,%r13
  sub    %rdx,%r13
  je     L48
  mov    %r13,%r8
  mov    (%rsp),%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <punch_hole@plt>
  test   %eax,%eax
  jne    L48
  jmp    L36
L5:
  mov    $0x1,%eax
L36:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
bool resparse(int fd, off_t flen, size_t blksz, char *buf, size_t bufsz) {
  bool ret = false;
  off_t len, span = 0, offt = 0, rlen = 0;
  do {
    rlen = readfd(fd, buf, bufsz);
    if (rlen < 0)
      goto fail;
    len = rlen % blksz;
    rlen -= len;
    if (rlen > 0 && !punch_hole(fd, offt, blksz, buf, rlen))
      goto fail;
    offt += rlen + len;
  } while (rlen == bufsz && offt < flen);
  ret = true;
fail:
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<resparse>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L15:
  add    %rbx,%r15
  cmp    %r8,%r12
  jne    L6
  cmp    (%rsp),%r15
  jae    L6
L21:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <readfd@plt>
  xor    %edx,%edx
  mov    %rax,%rbx
  div    %rbp
  mov    %rbx,%r8
  sub    %rdx,%r8
  je     L15
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %r14d,%edi
  mov    %r8,0x8(%rsp)
  call   <punch_hole@plt>
  mov    0x8(%rsp),%r8
  test   %eax,%eax
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
bool resparse(int fd, off_t flen, size_t blksz, char *buf, size_t bufsz) {
  bool ret = false;
  off_t len, span = 0, offt = 0, rlen = 0;
  do {
    rlen = readfd(fd, buf, bufsz);
    if (rlen < 0)
      goto fail;
    len = rlen % blksz;
    rlen -= len;
    if (rlen > 0 && !punch_hole(fd, offt, blksz, buf, rlen))
      goto fail;
    offt += rlen + len;
  } while (rlen == bufsz && offt < flen);
  ret = true;
fail:
  return ret;
}
```