user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x30000(%rsp),%r11
L174:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L174
  sub    $0xd68,%rsp
  lea    D11(%rip),%r13
  mov    %r13,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x30d58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L55
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  mov    %rbx,%r12
  nopw   0x0(%rax,%rax,1)
L90:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  cmp    %ebp,%r8d
  jg     L90
  mov    %r8d,%edi
  lea    -0x1(%r8),%r9d
  shr    $0x1f,%edi
  movslq %r9d,%rax
  add    %r8d,%edi
  movl   $0x1,0x10(%rsp,%rax,4)
  sar    %edi
  movl   $0x1,0x10(%rsp)
  cmp    $0x1,%r8d
  jle    L74
  cmp    $0x3,%r8d
  jle    L43
  cmp    %edi,%r8d
  movslq %r8d,%rax
  lea    0x14(%rsp),%rdx
  cmovle %r8d,%edi
  lea    (%rbx,%rax,4),%rcx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L54:
  mov    -0x4(%rdx),%esi
  cmp    %esi,(%rdx)
  jle    L153
  add    $0x1,%esi
  mov    %esi,(%rdx)
L153:
  mov    -0x4(%rcx),%esi
  cmp    %esi,-0x8(%rcx)
  jle    L12
  add    $0x1,%esi
  mov    %esi,-0x8(%rcx)
L12:
  add    $0x1,%eax
  sub    $0x4,%rcx
  add    $0x4,%rdx
  cmp    %edi,%eax
  jl     L54
  cmp    %eax,%r8d
  jle    L74
L24:
  sub    %eax,%r9d
  movslq %eax,%rdx
  movslq %r9d,%r9
  lea    (%rbx,%rdx,4),%rcx
  lea    (%rbx,%r9,4),%rsi
  mov    $0x1,%r9d
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L164:
  add    $0x1,%edx
  mov    %edx,(%rsi)
  mov    (%rcx),%edi
  cmp    %edi,%edx
  cmovl  %edi,%edx
  cmp    %edx,%r9d
  cmovl  %edx,%r9d
  add    $0x1,%eax
  add    $0x4,%rcx
  sub    $0x4,%rsi
  cmp    %eax,%r8d
  jle    L47
L16:
  mov    -0x4(%rcx),%edx
  cmp    (%rcx),%edx
  jge    L13
  add    $0x1,%edx
  mov    %edx,(%rcx)
L13:
  mov    (%rsi),%edi
  mov    0x4(%rsi),%edx
  cmp    %edx,%edi
  jg     L164
  mov    (%rcx),%edx
  cmp    %edx,%edi
  cmovl  %edx,%edi
  cmp    %edi,%r9d
  cmovl  %edi,%r9d
  add    $0x1,%eax
  add    $0x4,%rcx
  sub    $0x4,%rsi
  cmp    %eax,%r8d
  jg     L16
L47:
  mov    %r9d,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x30d58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x30d68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0x1,%eax
  jmp    L24
L74:
  mov    $0x1,%r9d
  jmp    L47
L55:
  sub    $0x1,%eax
  mov    $0x1,%r9d
  cltq
  movl   $0x1,0x10(%rsp,%rax,4)
  movl   $0x1,0x10(%rsp)
  jmp    L47
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D11: %d

tool: D0: %d


assistant: ```c
int main(void) {
  int N, COLUNAS[50000], i, pelaDireita, pelaEsquerda, hN, maiorTriangulo = 1;
  scanf("%d", &N);
  for (i = 0; i < N; i++) {
    scanf("%d", COLUNAS + i);
  }
  hN = N / 2;
  COLUNAS[0] = COLUNAS[N - 1] = 1;
  for (i = 1; i < N; i++) {
    pelaDireita = i;
    pelaEsquerda = N - 1 - i;
    if (COLUNAS[pelaDireita] > COLUNAS[pelaDireita - 1]) {
      COLUNAS[pelaDireita] = COLUNAS[pelaDireita - 1] + 1;
    }
    if (COLUNAS[pelaEsquerda] > COLUNAS[pelaEsquerda + 1]) {
      COLUNAS[pelaEsquerda] = COLUNAS[pelaEsquerda + 1] + 1;
    }
    if (i >= hN) {
      if (COLUNAS[pelaDireita] > maiorTriangulo) {
        maiorTriangulo = COLUNAS[pelaDireita];
      }
      if (COLUNAS[pelaEsquerda] > maiorTriangulo) {
        maiorTriangulo = COLUNAS[pelaEsquerda];
      }
    }
  }
  printf("%d\n", maiorTriangulo);
  return 0;
}
```