ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<c_postgresql_copy_escape_bytea>:
  endbr64
  mov    %rdi,%rcx
  mov    %rdx,%rax
  test   %rsi,%rsi
  je     L47
  add    %rdi,%rsi
  jmp    L21
L55:
  movb   $0x5c,(%rax)
  movb   $0x5c,0x1(%rax)
  movb   $0x5c,0x2(%rax)
  movb   $0x5c,0x3(%rax)
  lea    0x4(%rax),%rax
L45:
  cmp    %rsi,%rcx
  je     L47
L21:
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  cmp    $0x5c,%dl
  je     L55
  lea    -0x20(%rdx),%edi
  cmp    $0x5e,%dil
  ja     L17
  mov    %dl,(%rax)
  lea    0x1(%rax),%rax
  jmp    L45
L17:
  movb   $0x5c,(%rax)
  movb   $0x5c,0x1(%rax)
  mov    %edx,%edi
  shr    $0x6,%dil
  add    $0x30,%edi
  mov    %dil,0x2(%rax)
  mov    %edx,%edi
  shr    $0x3,%dil
  and    $0x7,%edi
  add    $0x30,%edi
  mov    %dil,0x3(%rax)
  and    $0x7,%edx
  add    $0x30,%edx
  mov    %dl,0x4(%rax)
  lea    0x5(%rax),%rax
  jmp    L45
L47:
  ret
```

assistant: ```c
unsigned char *c_postgresql_copy_escape_bytea(const unsigned char *in, size_t in_size, unsigned char *out) {
  while (in_size-- > 0) {
    unsigned char c = *in++;
    if (c == '\\') {
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '\\';
    } else if (c >= 32 && c <= 126) {
      *out++ = c;
    } else {
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '0' + ((c >> 6) & 0x7);
      *out++ = '0' + ((c >> 3) & 0x7);
      *out++ = '0' + (c & 0x7);
    }
  }
  return out;
}
```
user: What is the c source code of the assembly code below:

```asm
<c_postgresql_copy_escape_bytea>:
  endbr64
  mov    %rdx,%rax
  test   %rsi,%rsi
  je     L54
  add    %rdi,%rsi
  jmp    L58
  nopl   0x0(%rax)
L17:
  lea    -0x20(%rcx),%edx
  cmp    $0x5e,%dl
  ja     L22
  mov    %cl,(%rax)
  add    $0x1,%rax
L55:
  cmp    %rdi,%rsi
  je     L54
L58:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  cmp    $0x5c,%cl
  jne    L17
  movl   $0x5c5c5c5c,(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rsi
  jne    L58
L54:
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    $0x5c5c,%edx
  add    $0x5,%rax
  mov    %dx,-0x5(%rax)
  mov    %ecx,%edx
  shr    $0x6,%dl
  add    $0x30,%edx
  mov    %dl,-0x3(%rax)
  mov    %ecx,%edx
  and    $0x7,%ecx
  shr    $0x3,%dl
  add    $0x30,%ecx
  and    $0x7,%edx
  mov    %cl,-0x1(%rax)
  add    $0x30,%edx
  mov    %dl,-0x2(%rax)
  jmp    L55
```

assistant: ```c
unsigned char *c_postgresql_copy_escape_bytea(const unsigned char *in, size_t in_size, unsigned char *out) {
  while (in_size-- > 0) {
    unsigned char c = *in++;
    if (c == '\\') {
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '\\';
    } else if (c >= 32 && c <= 126) {
      *out++ = c;
    } else {
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '0' + ((c >> 6) & 0x7);
      *out++ = '0' + ((c >> 3) & 0x7);
      *out++ = '0' + (c & 0x7);
    }
  }
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<c_postgresql_copy_escape_bytea>:
  endbr64
  mov    %rdx,%rax
  test   %rsi,%rsi
  je     L30
  add    %rdi,%rsi
  jmp    L58
  nopl   0x0(%rax)
L9:
  lea    -0x20(%rcx),%edx
  cmp    $0x5e,%dl
  ja     L25
  mov    %cl,(%rax)
  add    $0x1,%rax
L33:
  cmp    %rsi,%rdi
  je     L30
L58:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  cmp    $0x5c,%cl
  jne    L9
  movl   $0x5c5c5c5c,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rdi
  jne    L58
L30:
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x5c5c,%edx
  add    $0x5,%rax
  mov    %dx,-0x5(%rax)
  mov    %ecx,%edx
  shr    $0x6,%dl
  add    $0x30,%edx
  mov    %dl,-0x3(%rax)
  mov    %ecx,%edx
  and    $0x7,%ecx
  shr    $0x3,%dl
  add    $0x30,%ecx
  and    $0x7,%edx
  mov    %cl,-0x1(%rax)
  add    $0x30,%edx
  mov    %dl,-0x2(%rax)
  jmp    L33
```

assistant: ```c
unsigned char *c_postgresql_copy_escape_bytea(const unsigned char *in, size_t in_size, unsigned char *out) {
  while (in_size-- > 0) {
    unsigned char c = *in++;
    if (c == '\\') {
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '\\';
    } else if (c >= 32 && c <= 126) {
      *out++ = c;
    } else {
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '0' + ((c >> 6) & 0x7);
      *out++ = '0' + ((c >> 3) & 0x7);
      *out++ = '0' + (c & 0x7);
    }
  }
  return out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jbe    L4
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x38(%rbp)
  jbe    L53
L4:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L52:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L52
L25:
  nop
  jmp    L28
L53:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  ja     L49
L28:
  mov    -0x38(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcpy(char *destination, const char *source) {
  int sourceLen = strlen(source);
  if ((destination <= source) || (destination > (source + sourceLen))) {
    char *d = destination;
    const char *s = source;
    while (true) {
      *d = *s;
      if (*s == '\0') {
        break;
      } else {
        s++;
        d++;
      }
    }
  } else {
    char *d = destination + sourceLen;
    const char *s = source + sourceLen;
    do {
      *d = *s;
      d--;
      s--;
    } while (d > destination);
  }
  return destination;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rbp
  jb     L33
L43:
  movzbl 0x0(%rbp),%eax
  mov    %al,(%rbx)
  test   %al,%al
  je     L54
  mov    $0x1,%eax
L32:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L32
L54:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  cltq
  lea    0x0(%rbp,%rax,1),%rdx
  cmp    %rbx,%rdx
  jb     L43
  add    %rbx,%rax
L49:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  sub    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %rax,%rbx
  jb     L49
  jmp    L54
```

assistant: ```c
char *strcpy(char *destination, const char *source) {
  int sourceLen = strlen(source);
  if ((destination <= source) || (destination > (source + sourceLen))) {
    char *d = destination;
    const char *s = source;
    while (true) {
      *d = *s;
      if (*s == '\0') {
        break;
      } else {
        s++;
        d++;
      }
    }
  } else {
    char *d = destination + sourceLen;
    const char *s = source + sourceLen;
    do {
      *d = *s;
      d--;
      s--;
    } while (d > destination);
  }
  return destination;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %r12,%rbx
  jae    L49
  cltq
  lea    (%rbx,%rax,1),%rdx
  cmp    %r12,%rdx
  jae    L36
L49:
  movzbl (%rbx),%eax
  mov    %al,(%r12)
  test   %al,%al
  je     L34
  mov    $0x1,%eax
  nopl   0x0(%rax)
L5:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L5
L34:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  add    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L0:
  movzbl (%rdx),%ecx
  sub    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,0x1(%rax)
  cmp    %rax,%r12
  jb     L0
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *destination, const char *source) {
  int sourceLen = strlen(source);
  if ((destination <= source) || (destination > (source + sourceLen))) {
    char *d = destination;
    const char *s = source;
    while (true) {
      *d = *s;
      if (*s == '\0') {
        break;
      } else {
        s++;
        d++;
      }
    }
  } else {
    char *d = destination + sourceLen;
    const char *s = source + sourceLen;
    do {
      *d = *s;
      d--;
      s--;
    } while (d > destination);
  }
  return destination;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %r12,%rbx
  jae    L1
  cltq
  lea    (%rbx,%rax,1),%rdx
  cmp    %r12,%rdx
  jae    L19
L1:
  movzbl (%rbx),%eax
  mov    %al,(%r12)
  test   %al,%al
  je     L33
  mov    $0x1,%eax
  nopl   0x0(%rax)
L49:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L49
L33:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  add    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl (%rdx),%ecx
  sub    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,0x1(%rax)
  cmp    %rax,%r12
  jb     L21
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *destination, const char *source) {
  int sourceLen = strlen(source);
  if ((destination <= source) || (destination > (source + sourceLen))) {
    char *d = destination;
    const char *s = source;
    while (true) {
      *d = *s;
      if (*s == '\0') {
        break;
      } else {
        s++;
        d++;
      }
    }
  } else {
    char *d = destination + sourceLen;
    const char *s = source + sourceLen;
    do {
      *d = *s;
      d--;
      s--;
    } while (d > destination);
  }
  return destination;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<put2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int put2(const char *string) {
  int count = 0;
  while (*string) {
    putchar(*string++);
    count++;
  }
  putchar('\n');
  return (count);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<put2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L1
  mov    $0x0,%ebp
L15:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L15
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x0,%ebp
  jmp    L3
```

assistant: ```c
int put2(const char *string) {
  int count = 0;
  while (*string) {
    putchar(*string++);
    count++;
  }
  putchar('\n');
  return (count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<put2>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L16
  nopl   0x0(%rax)
L15:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%r12d
  test   %dil,%dil
  jne    L15
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int put2(const char *string) {
  int count = 0;
  while (*string) {
    putchar(*string++);
    count++;
  }
  putchar('\n');
  return (count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<put2>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
  nopl   0x0(%rax)
L7:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%r12d
  test   %dil,%dil
  jne    L7
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int put2(const char *string) {
  int count = 0;
  while (*string) {
    putchar(*string++);
    count++;
  }
  putchar('\n');
  return (count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa8(%rbp)
  cmpl   $0x4,-0xb4(%rbp)
  je     L26
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L26:
  mov    -0xc0(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rsi
  mov    -0xc0(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0xc0(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0xc0(%rbp),%rax
  mov    (%rax),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc0(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  je     L36
  mov    -0xc0(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rbx
  mov    -0xc0(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    -0x1(%rax),%ecx
  mov    -0xc0(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0xa0(%rbp),%rax
  mov    %rbx,%r9
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  lea    D13(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <exec@plt>
  mov    %eax,-0xa4(%rbp)
  mov    -0xc0(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  je     L36
  mov    -0xa4(%rbp),%eax
  mov    %eax,%edi
  call   <wait@plt>
  mov    %eax,-0xa8(%rbp)
L36:
  mov    -0xc0(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0xc0(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0xa8(%rbp),%ecx
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xa8(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D22
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D16
type_infered: string

tool: D22: usage: recursor <string> <depth> <waitp>

tool: D1: %s %s %s %s


tool: D13: recursor %s %d %s

tool: D16: %s %s: dying, retval=%d


assistant: ```c
int main(int argc, char *argv[]) {
  char buffer[128];
  pid_t pid;
  int retval = 0;
  if (argc != 4) {
    printf("usage: recursor <string> <depth> <waitp>\n");
    exit(1);
  }
  printf("%s %s %s %s\n", argv[0], argv[1], argv[2], argv[3]);
  if (atoi(argv[2]) != 0) {
    snprintf(buffer, sizeof buffer, "recursor %s %d %s", argv[1], atoi(argv[2]) - 1, argv[3]);
    pid = exec(buffer);
    if (atoi(argv[3]))
      retval = wait(pid);
  }
  printf("%s %s: dying, retval=%d\n", argv[1], argv[2], retval);
  exit(retval);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%edi
  jne    L46
L15:
  mov    0x10(%rbx),%rcx
  mov    0x8(%rbx),%rdx
  mov    0x18(%rbx),%r8
  mov    (%rbx),%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L22
L56:
  mov    0x10(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  mov    %ebp,%ecx
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
L22:
  mov    0x18(%rbx),%r12
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    0x8(%rbx),%rcx
  mov    %rsp,%rbp
  mov    %r12,%r9
  lea    -0x1(%rax),%r8d
  lea    D10(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <exec@plt>
  mov    %eax,%r12d
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L56
  mov    %r12d,%edi
  call   <wait@plt>
  mov    %eax,%ebp
  jmp    L56
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D36
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string

tool: D36: %s %s %s %s


tool: D3: %s %s: dying, retval=%d


tool: D13: usage: recursor <string> <depth> <waitp>

tool: D10: recursor %s %d %s

assistant: ```c
int main(int argc, char *argv[]) {
  char buffer[128];
  pid_t pid;
  int retval = 0;
  if (argc != 4) {
    printf("usage: recursor <string> <depth> <waitp>\n");
    exit(1);
  }
  printf("%s %s %s %s\n", argv[0], argv[1], argv[2], argv[3]);
  if (atoi(argv[2]) != 0) {
    snprintf(buffer, sizeof buffer, "recursor %s %d %s", argv[1], atoi(argv[2]) - 1, argv[3]);
    pid = exec(buffer);
    if (atoi(argv[3]))
      retval = wait(pid);
  }
  printf("%s %s: dying, retval=%d\n", argv[1], argv[2], retval);
  exit(retval);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%edi
  je     L30
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L30:
  mov    0x10(%rbx),%rcx
  mov    (%rbx),%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  mov    0x8(%rbx),%rdx
  mov    0x18(%rbx),%r8
  call   <printf@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jne    L1
L44:
  xor    %ebp,%ebp
L36:
  mov    0x10(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  xor    %eax,%eax
  mov    %ebp,%ecx
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    0x10(%rbx),%rdi
  mov    0x18(%rbx),%r12
  mov    %rsp,%rbp
  call   <atoi@plt>
  mov    0x8(%rbx),%rcx
  mov    %rbp,%rdi
  mov    %r12,%r9
  lea    -0x1(%rax),%r8d
  lea    D13(%rip),%rdx
  mov    $0x80,%esi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <exec@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  test   %eax,%eax
  je     L44
  mov    %ebp,%edi
  call   <wait@plt>
  mov    %eax,%ebp
  jmp    L36
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D23
datatype: string
name: parse_data
arguments: tag: D13
datatype: string

tool: D9: usage: recursor <string> <depth> <waitp>

tool: D4: %s %s %s %s


tool: D23: %s %s: dying, retval=%d


tool: D13: recursor %s %d %s

assistant: ```c
int main(int argc, char *argv[]) {
  char buffer[128];
  pid_t pid;
  int retval = 0;
  if (argc != 4) {
    printf("usage: recursor <string> <depth> <waitp>\n");
    exit(1);
  }
  printf("%s %s %s %s\n", argv[0], argv[1], argv[2], argv[3]);
  if (atoi(argv[2]) != 0) {
    snprintf(buffer, sizeof buffer, "recursor %s %d %s", argv[1], atoi(argv[2]) - 1, argv[3]);
    pid = exec(buffer);
    if (atoi(argv[3]))
      retval = wait(pid);
  }
  printf("%s %s: dying, retval=%d\n", argv[1], argv[2], retval);
  exit(retval);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%edi
  je     L22
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L22:
  mov    0x10(%rbx),%rcx
  mov    (%rbx),%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  mov    0x8(%rbx),%rdx
  mov    0x18(%rbx),%r8
  call   <printf@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jne    L44
L12:
  xor    %ebp,%ebp
L48:
  mov    0x10(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  xor    %eax,%eax
  mov    %ebp,%ecx
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    0x10(%rbx),%rdi
  mov    0x18(%rbx),%r12
  mov    %rsp,%rbp
  call   <atoi@plt>
  mov    0x8(%rbx),%rcx
  mov    %rbp,%rdi
  mov    %r12,%r9
  lea    -0x1(%rax),%r8d
  lea    D0(%rip),%rdx
  mov    $0x80,%esi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <exec@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  test   %eax,%eax
  je     L12
  mov    %ebp,%edi
  call   <wait@plt>
  mov    %eax,%ebp
  jmp    L48
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string
name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D0
type: string

tool: D8: usage: recursor <string> <depth> <waitp>

tool: D15: %s %s %s %s


tool: D29: %s %s: dying, retval=%d


tool: D0: recursor %s %d %s

assistant: ```c
int main(int argc, char *argv[]) {
  char buffer[128];
  pid_t pid;
  int retval = 0;
  if (argc != 4) {
    printf("usage: recursor <string> <depth> <waitp>\n");
    exit(1);
  }
  printf("%s %s %s %s\n", argv[0], argv[1], argv[2], argv[3]);
  if (atoi(argv[2]) != 0) {
    snprintf(buffer, sizeof buffer, "recursor %s %d %s", argv[1], atoi(argv[2]) - 1, argv[3]);
    pid = exec(buffer);
    if (atoi(argv[3]))
      retval = wait(pid);
  }
  printf("%s %s: dying, retval=%d\n", argv[1], argv[2], retval);
  exit(retval);
}
```
user: What is the c source code of the assembly code below:

```asm
<variable_test_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x14(%rbp),%edx
  bt     %edx,(%rax)
  sbb    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int variable_test_bit(int nr, const volatile unsigned long *addr) {
  int oldbit;
  __asm__ __volatile__("btl %2,%1\n\tsbbl %0,%0" : "=r"(oldbit) : "m"((*(volatile long *)addr)), "Ir"(nr));
  return oldbit;
}
```
user: Translate the below assembly code into C programming language:

```asm
<variable_test_bit>:
  endbr64
  bt     %edi,(%rsi)
  sbb    %eax,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int variable_test_bit(int nr, const volatile unsigned long *addr) {
  int oldbit;
  __asm__ __volatile__("btl %2,%1\n\tsbbl %0,%0" : "=r"(oldbit) : "m"((*(volatile long *)addr)), "Ir"(nr));
  return oldbit;
}
```