ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GetValueFromString>:
  endbr64
  mov    %esi,%eax
  test   %rdi,%rdi
  je     L7
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  test   %rbx,%rbx
  je     L62
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L62
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L73
  mov    %rbx,%rdi
  call   <atoi@plt>
  movzbl (%rbx),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L73
  xchg   %ax,%ax
L1:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L1
  test   $0xdf,%dl
  je     L16
  nopl   (%rax)
L35:
  sub    $0x30,%edx
  cmp    $0x9,%dl
  jbe    L16
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
L73:
  test   $0xdf,%dl
  jne    L35
L16:
  mov    %rbx,0x0(%rbp)
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
int GetValueFromString(const char **string, int def_num) {
  int value = def_num;
  if (string != 0 && *string != 0 && **string != '\0') {
    const char *str = *string;
    if ('0' <= *str && *str <= '9')
      value = atoi(str);
    while ('0' <= *str && *str <= '9')
      str++;
    while (*str != ' ' && *str != '\0' && (*str < '0' || *str > '9'))
      str++;
    *string = str;
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetValueFromString>:
  endbr64
  mov    %esi,%eax
  test   %rdi,%rdi
  je     L48
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  test   %rbx,%rbx
  je     L46
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L46
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L42
  mov    %rbx,%rdi
  call   <atoi@plt>
  movzbl (%rbx),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L42
  xchg   %ax,%ax
L45:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L45
  test   $0xdf,%dl
  je     L59
  nopl   (%rax)
L38:
  sub    $0x30,%edx
  cmp    $0x9,%dl
  jbe    L59
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
L42:
  test   $0xdf,%dl
  jne    L38
L59:
  mov    %rbx,0x0(%rbp)
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  ret
```

assistant: ```c
int GetValueFromString(const char **string, int def_num) {
  int value = def_num;
  if (string != 0 && *string != 0 && **string != '\0') {
    const char *str = *string;
    if ('0' <= *str && *str <= '9')
      value = atoi(str);
    while ('0' <= *str && *str <= '9')
      str++;
    while (*str != ' ' && *str != '\0' && (*str < '0' || *str > '9'))
      str++;
    *string = str;
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L33:
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L39:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%eax
  imul   %ecx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x1,-0x8(%rbp)
  jle    L39
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L33
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(int *x, int *y, int n) {
  int i, j;
  int dot = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < 2; j++)
      dot += *(x++) * *(y++);
  return dot;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  test   %edx,%edx
  jle    L15
  mov    %edx,%edx
  lea    (%rdi,%rdx,8),%rcx
  mov    $0x0,%eax
L10:
  mov    (%rdi),%edx
  imul   (%rsi),%edx
  add    %edx,%eax
  mov    0x4(%rdi),%edx
  imul   0x4(%rsi),%edx
  add    %edx,%eax
  add    $0x8,%rdi
  add    $0x8,%rsi
  cmp    %rdi,%rcx
  jne    L10
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int foo(int *x, int *y, int n) {
  int i, j;
  int dot = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < 2; j++)
      dot += *(x++) * *(y++);
  return dot;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  test   %edx,%edx
  jle    L14
  movslq %edx,%rdx
  xor    %eax,%eax
  lea    (%rdi,%rdx,8),%rcx
  nopl   0x0(%rax)
L7:
  mov    (%rdi),%edx
  imul   (%rsi),%edx
  add    $0x8,%rdi
  add    $0x8,%rsi
  add    %edx,%eax
  mov    -0x4(%rdi),%edx
  imul   -0x4(%rsi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L7
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo(int *x, int *y, int n) {
  int i, j;
  int dot = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < 2; j++)
      dot += *(x++) * *(y++);
  return dot;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L47
  cmp    $0x1,%edx
  je     L25
  mov    %edx,%edi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  shr    %edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L49:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm3
  movdqu (%rcx,%rax,1),%xmm2
  movdqu (%rsi,%rax,1),%xmm4
  add    $0x10,%rax
  psrlq  $0x20,%xmm0
  psrlq  $0x20,%xmm3
  pmuludq %xmm4,%xmm2
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm2,%xmm2
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm2
  paddd  %xmm2,%xmm1
  cmp    %rax,%rdi
  jne    L49
  movdqa %xmm1,%xmm0
  mov    %edx,%r8d
  psrldq $0x8,%xmm0
  and    $0xfffffffe,%r8d
  paddd  %xmm0,%xmm1
  mov    %r8d,%edi
  movdqa %xmm1,%xmm0
  shl    $0x3,%rdi
  psrldq $0x4,%xmm0
  add    %rdi,%rcx
  add    %rdi,%rsi
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %r8d,%edx
  je     L34
L23:
  mov    (%rsi),%edx
  imul   (%rcx),%edx
  add    %edx,%eax
  mov    0x4(%rsi),%edx
  imul   0x4(%rcx),%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax)
L34:
  ret
L47:
  xor    %eax,%eax
  ret
L25:
  xor    %eax,%eax
  jmp    L23
```

assistant: ```c
int foo(int *x, int *y, int n) {
  int i, j;
  int dot = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < 2; j++)
      dot += *(x++) * *(y++);
  return dot;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CCutil_our_gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L10
  negl   -0x14(%rbp)
L10:
  cmpl   $0x0,-0x18(%rbp)
  jns    L32
  negl   -0x18(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L8
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L8
L12:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L8:
  cmpl   $0x0,-0x14(%rbp)
  jne    L12
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int CCutil_our_gcd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (a > b)
    (((c) = (a)), ((a) = (b)), ((b) = (c)));
  while (a) {
    c = b % a;
    b = a;
    a = c;
  }
  return b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CCutil_our_gcd>:
  endbr64
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  cmp    %eax,%ecx
  jle    L12
  mov    %ecx,%edx
  mov    %eax,%ecx
  mov    %edx,%eax
L12:
  test   %ecx,%ecx
  jne    L5
  mov    %eax,%ecx
  jmp    L2
L22:
  mov    %edx,%ecx
L5:
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L22
L2:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int CCutil_our_gcd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (a > b)
    (((c) = (a)), ((a) = (b)), ((b) = (c)));
  while (a) {
    c = b % a;
    b = a;
    a = c;
  }
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CCutil_our_gcd>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%eax
  neg    %r8d
  cmovs  %edi,%r8d
  neg    %eax
  cmovs  %esi,%eax
  cmp    %r8d,%eax
  jge    L13
  mov    %r8d,%edx
  mov    %eax,%r8d
  mov    %edx,%eax
L13:
  test   %r8d,%r8d
  jne    L29
  jmp    L12
  nopl   0x0(%rax)
L20:
  mov    %edx,%r8d
L29:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L20
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int CCutil_our_gcd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (a > b)
    (((c) = (a)), ((a) = (b)), ((b) = (c)));
  while (a) {
    c = b % a;
    b = a;
    a = c;
  }
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CCutil_our_gcd>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%eax
  neg    %r8d
  cmovs  %edi,%r8d
  neg    %eax
  cmovs  %esi,%eax
  cmp    %r8d,%eax
  jge    L30
  mov    %r8d,%edx
  mov    %eax,%r8d
  mov    %edx,%eax
L30:
  test   %r8d,%r8d
  jne    L17
  jmp    L5
  nopl   0x0(%rax)
L20:
  mov    %edx,%r8d
L17:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L20
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int CCutil_our_gcd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (a > b)
    (((c) = (a)), ((a) = (b)), ((b) = (c)));
  while (a) {
    c = b % a;
    b = a;
    a = c;
  }
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lin_reg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L17:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L17
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L49:
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L51:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L51
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L49
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lin_reg(double *p, double *xx, int n_coef, int dim2, int s, double *pred) {
  int i, k;
  for (i = 0; i < dim2; i++)
    pred[i] = 0.0;
  for (k = 0; k < n_coef; k++) {
    for (i = 0; i < dim2; i++) {
      pred[i] += p[k * dim2 + i] * xx[s + k * dim2 + i];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lin_reg>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %edx,%ebx
  mov    %ecx,%ebp
  test   %ecx,%ecx
  jle    L61
  mov    %r9,%rax
  lea    -0x1(%rcx),%edx
  lea    0x8(%r9,%rdx,8),%rdx
L49:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L49
L61:
  test   %ebx,%ebx
  jle    L30
  mov    $0x0,%edi
  mov    $0x0,%r12d
  mov    %ebp,%esi
  jmp    L48
L32:
  movslq %edi,%rax
  lea    (%r10,%rax,8),%rcx
  lea    (%r8,%rdi,1),%eax
  cltq
  lea    (%r11,%rax,8),%rdx
  mov    $0x0,%eax
L72:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r9,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L72
L4:
  add    $0x1,%r12d
  add    %ebp,%edi
  cmp    %r12d,%ebx
  je     L30
L48:
  test   %ebp,%ebp
  jg     L32
  jmp    L4
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lin_reg(double *p, double *xx, int n_coef, int dim2, int s, double *pred) {
  int i, k;
  for (i = 0; i < dim2; i++)
    pred[i] = 0.0;
  for (k = 0; k < n_coef; k++) {
    for (i = 0; i < dim2; i++) {
      pred[i] += p[k * dim2 + i] * xx[s + k * dim2 + i];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lin_reg>:
  endbr64
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  test   %ecx,%ecx
  jle    L2
  movslq %ecx,%rdx
  mov    %r9,%rdi
  xor    %esi,%esi
  shl    $0x3,%rdx
  call   <memset@plt>
  mov    %rax,%r9
L2:
  test   %ebx,%ebx
  jle    L13
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  lea    -0x1(%r13),%edi
L40:
  test   %r13d,%r13d
  jle    L43
  movslq %r8d,%rax
  lea    0x0(%rbp,%rax,8),%rsi
  lea    (%r14,%r8,1),%eax
  cltq
  lea    (%r12,%rax,8),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L36:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  mov    %rax,%rdx
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r9,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rdx
  jne    L36
L43:
  add    $0x1,%r10d
  add    %r13d,%r8d
  cmp    %r10d,%ebx
  jne    L40
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void lin_reg(double *p, double *xx, int n_coef, int dim2, int s, double *pred) {
  int i, k;
  for (i = 0; i < dim2; i++)
    pred[i] = 0.0;
  for (k = 0; k < n_coef; k++) {
    for (i = 0; i < dim2; i++) {
      pred[i] += p[k * dim2 + i] * xx[s + k * dim2 + i];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lin_reg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  mov    %r8d,0x8(%rsp)
  test   %ecx,%ecx
  jle    L16
  movslq %ecx,%r15
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %r9,%rdi
  lea    0x0(,%r15,8),%r13
  mov    %edx,%r14d
  xor    %esi,%esi
  mov    %ecx,%r12d
  mov    %r13,%rdx
  call   <memset@plt>
  mov    %rax,%r9
  test   %r14d,%r14d
  jle    L16
  movslq 0x8(%rsp),%rax
  mov    %r12d,%edx
  mov    %rbx,%rsi
  xor    %r8d,%r8d
  and    $0xfffffffe,%edx
  xor    %r11d,%r11d
  lea    0x0(%rbp,%rax,8),%rdi
  mov    %r12d,%eax
  shr    %eax
  lea    -0x1(%rax),%r10d
  mov    %edx,%eax
  add    $0x1,%r10
  lea    (%r9,%rax,8),%rcx
  shl    $0x4,%r10
  nopl   0x0(%rax,%rax,1)
L87:
  mov    0x8(%rsp),%eax
  lea    0x8(%rsi),%r14
  add    %r8d,%eax
  cmp    %r14,%r9
  lea    0x8(%rdi),%r14
  setne  0x7(%rsp)
  cmp    %r14,%r9
  setne  %r14b
  test   %r14b,0x7(%rsp)
  je     L15
  xor    %r14d,%r14d
  cmp    $0x1,%r12d
  je     L15
  nopw   0x0(%rax,%rax,1)
L18:
  movupd (%rsi,%r14,1),%xmm0
  movupd (%rdi,%r14,1),%xmm1
  movupd (%r9,%r14,1),%xmm2
  mulpd  %xmm1,%xmm0
  addpd  %xmm2,%xmm0
  movups %xmm0,(%r9,%r14,1)
  add    $0x10,%r14
  cmp    %r10,%r14
  jne    L18
  cmp    %edx,%r12d
  je     L20
  lea    (%r8,%rdx,1),%r14d
  add    %edx,%eax
  movslq %r14d,%r14
  cltq
  movsd  (%rbx,%r14,8),%xmm0
  mulsd  0x0(%rbp,%rax,8),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
L20:
  add    $0x1,%r11d
  add    %r13,%rdi
  add    %r13,%rsi
  add    %r12d,%r8d
  cmp    %r11d,0xc(%rsp)
  jne    L87
L16:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L73:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r9,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r15
  jne    L73
  jmp    L20
```

assistant: ```c
void lin_reg(double *p, double *xx, int n_coef, int dim2, int s, double *pred) {
  int i, k;
  for (i = 0; i < dim2; i++)
    pred[i] = 0.0;
  for (k = 0; k < n_coef; k++) {
    for (i = 0; i < dim2; i++) {
      pred[i] += p[k * dim2 + i] * xx[s + k * dim2 + i];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L35
L6:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  addq   $0x1,-0x10(%rbp)
L35:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L6
  jmp    L11
L31:
  nop
L11:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t maxlen) {
  char *cc;
  size_t i;
  cc = dest;
  for (i = 0; (i < maxlen); i++) {
    *dest++ = *src;
    if (!*src++)
      break;
  }
  return cc;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L3
  mov    $0x0,%ecx
L7:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  test   %r8b,%r8b
  je     L3
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L7
L3:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t maxlen) {
  char *cc;
  size_t i;
  cc = dest;
  for (i = 0; (i < maxlen); i++) {
    *dest++ = *src;
    if (!*src++)
      break;
  }
  return cc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L22
  xor    %ecx,%ecx
  jmp    L37
L21:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L22
L37:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  test   %r8b,%r8b
  jne    L21
L22:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t maxlen) {
  char *cc;
  size_t i;
  cc = dest;
  for (i = 0; (i < maxlen); i++) {
    *dest++ = *src;
    if (!*src++)
      break;
  }
  return cc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L16
  xor    %ecx,%ecx
  jmp    L3
L6:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L16
L3:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  test   %r8b,%r8b
  jne    L6
L16:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t maxlen) {
  char *cc;
  size_t i;
  cc = dest;
  for (i = 0; (i < maxlen); i++) {
    *dest++ = *src;
    if (!*src++)
      break;
  }
  return cc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<removeemptycap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  je     L55
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L5
  mov    -0xc(%rbp),%eax
  cmp    $0x18,%eax
  jne    L26
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <remove@plt>
  jmp    L44
L55:
  nop
  jmp    L44
L5:
  nop
  jmp    L44
L26:
  nop
L44:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void removeemptycap(char *filenametoremove) {
  struct stat statinfo;
  if (filenametoremove == NULL) {
    return;
  }
  if (stat(filenametoremove, &statinfo) != 0) {
    return;
  }
  if (statinfo.st_size == 24) {
    remove(filenametoremove);
    return;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<removeemptycap>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L14
  mov    %rdi,%rbx
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L14
  cmpl   $0x18,0x4(%rsp)
  je     L25
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L25:
  mov    %rbx,%rdi
  call   <remove@plt>
  jmp    L14
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void removeemptycap(char *filenametoremove) {
  struct stat statinfo;
  if (filenametoremove == NULL) {
    return;
  }
  if (stat(filenametoremove, &statinfo) != 0) {
    return;
  }
  if (statinfo.st_size == 24) {
    remove(filenametoremove);
    return;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<removeemptycap>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L45
  lea    0x4(%rsp),%rsi
  mov    %rdi,%rbp
  call   <stat@plt>
  test   %rax,%rax
  jne    L45
  cmpl   $0x18,0x4(%rsp)
  je     L40
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L40:
  mov    %rbp,%rdi
  call   <remove@plt>
  jmp    L45
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void removeemptycap(char *filenametoremove) {
  struct stat statinfo;
  if (filenametoremove == NULL) {
    return;
  }
  if (stat(filenametoremove, &statinfo) != 0) {
    return;
  }
  if (statinfo.st_size == 24) {
    remove(filenametoremove);
    return;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<removeemptycap>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L14
  lea    0x4(%rsp),%rsi
  mov    %rdi,%rbp
  call   <stat@plt>
  test   %rax,%rax
  jne    L14
  cmpl   $0x18,0x4(%rsp)
  je     L0
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L0:
  mov    %rbp,%rdi
  call   <remove@plt>
  jmp    L14
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void removeemptycap(char *filenametoremove) {
  struct stat statinfo;
  if (filenametoremove == NULL) {
    return;
  }
  if (stat(filenametoremove, &statinfo) != 0) {
    return;
  }
  if (statinfo.st_size == 24) {
    remove(filenametoremove);
    return;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x2,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x2,-0x1c(%rbp)
  jmp    L6
L1:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L6:
  cmpl   $0x5c,-0x1c(%rbp)
  jle    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D19: %llu, %llu, 

tool: D12: , %llu

assistant: ```c
int main() {
  long long unsigned int f = 2;
  long long unsigned int s = 1;
  long long int t;
  int i;
  printf("%llu, %llu, ", f, s);
  for (i = 2; i < 93; i++) {
    t = f + s;
    printf(", %llu", t);
    f = s;
    s = t;
  }
  return 0;
}
```