ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<inflate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <inflate_entry@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int inflate() {
  int status;
  status = inflate_entry();
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inflate>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <inflate_entry@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int inflate() {
  int status;
  status = inflate_entry();
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<inflate>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <inflate_entry@plt>
```

assistant: ```c
int inflate() {
  int status;
  status = inflate_entry();
  return status;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inflate>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <inflate_entry@plt>
```

assistant: ```c
int inflate() {
  int status;
  status = inflate_entry();
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ata_pause>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ata_altstatus@plt>
  mov    $0x7d0,%edi
  call   <__const_udelay@plt>
  nop
  leave
  ret
```

assistant: ```c
void(ata_pause)(struct ata_port *ap) {
  {
    ata_altstatus(ap);
    __const_udelay(2000UL);
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ata_pause>:
  endbr64
  sub    $0x8,%rsp
  call   <ata_altstatus@plt>
  mov    $0x7d0,%edi
  call   <__const_udelay@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void(ata_pause)(struct ata_port *ap) {
  {
    ata_altstatus(ap);
    __const_udelay(2000UL);
    return;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ata_pause>:
  endbr64
  sub    $0x8,%rsp
  call   <ata_altstatus@plt>
  mov    $0x7d0,%edi
  add    $0x8,%rsp
  jmp    1070 <__const_udelay@plt>
```

assistant: ```c
void(ata_pause)(struct ata_port *ap) {
  {
    ata_altstatus(ap);
    __const_udelay(2000UL);
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ata_pause>:
  endbr64
  sub    $0x8,%rsp
  call   <ata_altstatus@plt>
  mov    $0x7d0,%edi
  add    $0x8,%rsp
  jmp    1070 <__const_udelay@plt>
```

assistant: ```c
void(ata_pause)(struct ata_port *ap) {
  {
    ata_altstatus(ap);
    __const_udelay(2000UL);
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(int *array, int numTrees) {
  int total = 0;
  for (int i = 0; i < numTrees; i++) {
    total = total + array[i];
  }
  return total;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L29
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L19:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L19
L4:
  mov    %edx,%eax
  ret
L29:
  mov    $0x0,%edx
  jmp    L4
```

assistant: ```c
int sum(int *array, int numTrees) {
  int total = 0;
  for (int i = 0; i < numTrees; i++) {
    total = total + array[i];
  }
  return total;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L15:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L15
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum(int *array, int numTrees) {
  int total = 0;
  for (int i = 0; i < numTrees; i++) {
    total = total + array[i];
  }
  return total;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L1
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L36:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L36
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L67
L32:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L69
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L69
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
L69:
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  ret
L1:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L32
```

assistant: ```c
int sum(int *array, int numTrees) {
  int total = 0;
  for (int i = 0; i < numTrees; i++) {
    total = total + array[i];
  }
  return total;
}
```
user: What is the c source code of the assembly code below?

```asm
<subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <get@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <get@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string

tool: D11: Enter your first number

tool: D18: Enter your second number

tool: D17: Result: %f

assistant: ```c
void subtract() {
  float firstNum = get("Enter your first number");
  float secondNum = get("Enter your second number");
  float result = firstNum - secondNum;
  printf("Result: %f", result);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<subtract>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  call   <get@plt>
  movss  %xmm0,0xc(%rsp)
  lea    D28(%rip),%rdi
  call   <get@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  subss  %xmm1,%xmm0
  lea    D29(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D28
type_infered: string
name: unpack_data
arguments: data_tag: D29
type_infered: string

tool: D7: Enter your first number

tool: D28: Enter your second number

tool: D29: Result: %f

assistant: ```c
void subtract() {
  float firstNum = get("Enter your first number");
  float secondNum = get("Enter your second number");
  float result = firstNum - secondNum;
  printf("Result: %f", result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<subtract>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  call   <get@plt>
  lea    D28(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <get@plt>
  movss  0xc(%rsp),%xmm1
  add    $0x18,%rsp
  lea    D20(%rip),%rdi
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: string

tool: D15: Enter your first number

tool: D28: Enter your second number

tool: D20: Result: %f

assistant: ```c
void subtract() {
  float firstNum = get("Enter your first number");
  float secondNum = get("Enter your second number");
  float result = firstNum - secondNum;
  printf("Result: %f", result);
}
```
user: What is the c source code of the assembly code below?

```asm
<subtract>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  call   <get@plt>
  lea    D4(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <get@plt>
  movss  0xc(%rsp),%xmm1
  add    $0x18,%rsp
  lea    D6(%rip),%rdi
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D12: Enter your first number

tool: D4: Enter your second number

tool: D6: Result: %f

assistant: ```c
void subtract() {
  float firstNum = get("Enter your first number");
  float secondNum = get("Enter your second number");
  float result = firstNum - secondNum;
  printf("Result: %f", result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strchrnul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L13
L16:
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L16
L15:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strchrnul(const char *s, int c) {
  while (*s && (*s != c))
    s++;
  return (char *)s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strchrnul>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
L27:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L7
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L27
L7:
  ret
L14:
  ret
```

assistant: ```c
char *strchrnul(const char *s, int c) {
  while (*s && (*s != c))
    s++;
  return (char *)s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strchrnul>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L22
  jmp    L1
L9:
  movsbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L16
L22:
  cmp    %esi,%edx
  jne    L9
L16:
  ret
L1:
  ret
```

assistant: ```c
char *strchrnul(const char *s, int c) {
  while (*s && (*s != c))
    s++;
  return (char *)s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strchrnul>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L32
  jmp    L17
L7:
  movsbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L35
L32:
  cmp    %esi,%edx
  jne    L7
L35:
  ret
L17:
  ret
```

assistant: ```c
char *strchrnul(const char *s, int c) {
  while (*s && (*s != c))
    s++;
  return (char *)s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xb8(%rbp)
  movl   $0x0,-0xc0(%rbp)
  jmp    L55
L15:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xbc(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc0(%rbp),%eax
  cltq
  mov    %dl,-0xb0(%rbp,%rax,1)
  addl   $0x1,-0xc0(%rbp)
L55:
  cmpl   $0xa,-0xbc(%rbp)
  je     L24
  cmpl   $0x9f,-0xc0(%rbp)
  jle    L15
L24:
  mov    -0xc0(%rbp),%eax
  mov    %eax,-0xb4(%rbp)
  movl   $0x0,-0xc0(%rbp)
  jmp    L0
L53:
  mov    -0xc0(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <click_counter@plt>
  mov    %eax,%edx
  mov    -0xb8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xb8(%rbp)
  addl   $0x1,-0xc0(%rbp)
L0:
  mov    -0xc0(%rbp),%eax
  cmp    -0xb4(%rbp),%eax
  jl     L53
  mov    -0xb8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: %d


assistant: ```c
int main() {
  char input[160];
  int count, CurentChar, sum = 0, SymbCount;
  for (count = 0; CurentChar != '\n' && count < 160; count++) {
    CurentChar = getchar();
    input[count] = CurentChar;
  }
  SymbCount = count;
  for (count = 0; count < SymbCount; count++) {
    sum += click_counter(input[count]);
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%ebx
L54:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,0x0(%rbp)
  mov    %ebx,%r12d
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    $0xa,%eax
  je     L6
  cmp    $0x9f,%ebx
  jle    L54
L6:
  test   %ebx,%ebx
  jle    L31
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    %rsp,%r13
L4:
  movsbl (%rbx,%r13,1),%edi
  call   <click_counter@plt>
  add    %eax,%ebp
  add    $0x1,%rbx
  lea    -0x1(%rbx),%eax
  cmp    %r12d,%eax
  jl     L4
L33:
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  mov    $0x0,%ebp
  jmp    L33
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D0: %d


assistant: ```c
int main() {
  char input[160];
  int count, CurentChar, sum = 0, SymbCount;
  for (count = 0; CurentChar != '\n' && count < 160; count++) {
    CurentChar = getchar();
    input[count] = CurentChar;
  }
  SymbCount = count;
  for (count = 0; count < SymbCount; count++) {
    sum += click_counter(input[count]);
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <getchar@plt>
  mov    %ebx,%edx
  add    $0x1,%ebx
  mov    %al,-0x1(%rbp)
  cmp    $0xa,%eax
  je     L43
  cmp    $0x9f,%ebx
  jle    L6
L43:
  lea    0x1(%r12),%rbx
  movslq %edx,%rbp
  xor    %r13d,%r13d
  add    %rbx,%rbp
  jmp    L44
L7:
  add    $0x1,%rbx
L44:
  movsbl (%r12),%edi
  mov    %rbx,%r12
  call   <click_counter@plt>
  add    %eax,%r13d
  cmp    %rbx,%rbp
  jne    L7
  mov    %r13d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: %d


assistant: ```c
int main() {
  char input[160];
  int count, CurentChar, sum = 0, SymbCount;
  for (count = 0; CurentChar != '\n' && count < 160; count++) {
    CurentChar = getchar();
    input[count] = CurentChar;
  }
  SymbCount = count;
  for (count = 0; count < SymbCount; count++) {
    sum += click_counter(input[count]);
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
  nopl   0x0(%rax)
L44:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <getchar@plt>
  mov    %ebx,%edx
  add    $0x1,%ebx
  mov    %al,-0x1(%rbp)
  cmp    $0xa,%eax
  je     L14
  cmp    $0x9f,%ebx
  jle    L44
L14:
  lea    0x1(%r12),%rbx
  movslq %edx,%rbp
  xor    %r13d,%r13d
  add    %rbx,%rbp
  jmp    L20
L0:
  add    $0x1,%rbx
L20:
  movsbl (%r12),%edi
  mov    %rbx,%r12
  call   <click_counter@plt>
  add    %eax,%r13d
  cmp    %rbp,%rbx
  jne    L0
  mov    %r13d,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main() {
  char input[160];
  int count, CurentChar, sum = 0, SymbCount;
  for (count = 0; CurentChar != '\n' && count < 160; count++) {
    CurentChar = getchar();
    input[count] = CurentChar;
  }
  SymbCount = count;
  for (count = 0; count < SymbCount; count++) {
    sum += click_counter(input[count]);
  }
  printf("%d\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<coinChange>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%r13d
  lea    0x1(%rdx),%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r9
  movl   $0x0,(%rax)
  cmp    $0x1,%ebx
  jle    L136
  lea    0x4(%rax),%rax
  lea    -0x1(%r13),%edx
  lea    0x8(%r9,%rdx,4),%rdx
L90:
  mov    %ebx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L90
L136:
  test   %ebp,%ebp
  jle    L19
  mov    %r12,%rax
  lea    -0x1(%rbp),%edx
  lea    0x4(%r12,%rdx,4),%rcx
  jmp    L79
L1:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L19
L79:
  mov    (%rax),%edx
  cmp    %ebx,%edx
  jge    L1
  movslq %edx,%rdx
  movl   $0x1,(%r9,%rdx,4)
  jmp    L1
L19:
  test   %r13d,%r13d
  jle    L124
  lea    0x4(%r9),%r10
  lea    0x1(%r13),%r11d
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r8
  mov    $0x1,%esi
  jmp    L110
L165:
  add    $0x4,%rax
  cmp    %rax,%r8
  je     L45
L119:
  mov    %esi,%edx
  sub    (%rax),%edx
  test   %edx,%edx
  jle    L165
  movslq %edx,%rdx
  mov    (%r9,%rdx,4),%ecx
  mov    (%rdi),%edx
  lea    0x1(%rcx),%r14d
  cmp    %edx,%ecx
  cmovl  %r14d,%edx
  mov    %edx,(%rdi)
  jmp    L165
L45:
  add    $0x1,%esi
  add    $0x4,%r10
  cmp    %r11d,%esi
  je     L124
L110:
  mov    %r10,%rdi
  mov    %r12,%rax
  test   %ebp,%ebp
  jg     L119
  jmp    L45
L124:
  movslq %r13d,%r13
  mov    (%r9,%r13,4),%eax
  cmp    %ebx,%eax
  je     L97
L132:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L97:
  mov    $0xffffffff,%eax
  jmp    L132
```

assistant: ```c
int coinChange(int *coins, int coinsSize, int amount) {
  int max = amount + 1;
  int *cnts = (int *)malloc(max * sizeof(int));
  cnts[0] = 0;
  for (int i = 1; i < max; i++) {
    cnts[i] = max;
  }
  int n = coinsSize;
  for (int i = 0; i < n; i++) {
    if (coins[i] < max) {
      cnts[coins[i]] = 1;
    }
  }
  for (int i = 1; i <= amount; i++) {
    for (int j = 0; j < n; j++) {
      int prev = i - coins[j];
      if (prev >= 1) {
        cnts[i] = (cnts[i] < cnts[prev] + 1 ? cnts[i] : cnts[prev] + 1);
      }
    }
  }
  if (cnts[amount] == max)
    return -1;
  return cnts[amount];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<coinChange>:
  endbr64
  push   %r13
  movslq %edx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%r13),%ebx
  lea    0x0(,%rbx,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  movl   $0x0,(%rax)
  mov    %rax,%r10
  cmp    $0x1,%ebx
  jle    L3
  lea    -0x1(%r13),%edx
  lea    0x4(%rax),%rax
  lea    0x8(%r10,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %ebx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L40
L3:
  test   %r12d,%r12d
  jle    L98
  lea    -0x1(%r12),%edx
  mov    %rbp,%rax
  lea    0x4(%rbp,%rdx,4),%rcx
  nopl   (%rax)
L28:
  movslq (%rax),%rdx
  cmp    %ebx,%edx
  jge    L84
  movl   $0x1,(%r10,%rdx,4)
L84:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L28
L98:
  test   %r13d,%r13d
  jle    L52
  lea    -0x1(%r12),%eax
  lea    0x4(%r10),%rsi
  mov    $0x1,%edi
  lea    0x4(%rbp,%rax,4),%r9
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %rbp,%rax
  test   %r12d,%r12d
  jle    L13
  nopl   0x0(%rax,%rax,1)
L116:
  mov    %edi,%edx
  sub    (%rax),%edx
  test   %edx,%edx
  jle    L76
  movslq %edx,%rdx
  mov    (%r10,%rdx,4),%ecx
  mov    (%rsi),%edx
  lea    0x1(%rcx),%r8d
  cmp    %edx,%ecx
  cmovl  %r8d,%edx
  mov    %edx,(%rsi)
L76:
  add    $0x4,%rax
  cmp    %rax,%r9
  jne    L116
L13:
  lea    0x1(%rdi),%eax
  add    $0x4,%rsi
  cmp    %edi,%r13d
  je     L52
  mov    %eax,%edi
  jmp    L73
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    (%r10,%r13,4),%eax
  cmp    %ebx,%eax
  je     L126
L104:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L126:
  mov    $0xffffffff,%eax
  jmp    L104
```

assistant: ```c
int coinChange(int *coins, int coinsSize, int amount) {
  int max = amount + 1;
  int *cnts = (int *)malloc(max * sizeof(int));
  cnts[0] = 0;
  for (int i = 1; i < max; i++) {
    cnts[i] = max;
  }
  int n = coinsSize;
  for (int i = 0; i < n; i++) {
    if (coins[i] < max) {
      cnts[coins[i]] = 1;
    }
  }
  for (int i = 1; i <= amount; i++) {
    for (int j = 0; j < n; j++) {
      int prev = i - coins[j];
      if (prev >= 1) {
        cnts[i] = (cnts[i] < cnts[prev] + 1 ? cnts[i] : cnts[prev] + 1);
      }
    }
  }
  if (cnts[amount] == max)
    return -1;
  return cnts[amount];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<coinChange>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  lea    0x1(%rbp),%r12d
  mov    %rdi,%rbx
  lea    0x0(,%r12,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  movl   $0x0,(%rax)
  mov    %rax,%r10
  cmp    $0x1,%r12d
  jle    L68
  lea    -0x1(%rbp),%eax
  cmp    $0x2,%eax
  jbe    L159
  mov    %ebp,%edx
  movd   %r12d,%xmm1
  lea    0x4(%r10),%rax
  shr    $0x2,%edx
  pshufd $0x0,%xmm1,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x14(%r10,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L165:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L165
  mov    %ebp,%edx
  and    $0xfffffffc,%edx
  lea    0x1(%rdx),%eax
  cmp    %ebp,%edx
  je     L68
L51:
  movslq %eax,%rdx
  mov    %r12d,(%r10,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %eax,%ebp
  jle    L68
  mov    %r12d,0x4(%r10,%rcx,1)
  cmp    %edx,%ebp
  jle    L68
  mov    %r12d,0x8(%r10,%rcx,1)
L68:
  test   %r13d,%r13d
  jle    L48
  lea    -0x1(%r13),%edx
  lea    0x4(%rbx),%rdi
  mov    %rbx,%rax
  mov    %rdx,%r13
  lea    (%rdi,%rdx,4),%rcx
  nop
L108:
  movslq (%rax),%rdx
  cmp    %r12d,%edx
  jge    L89
  movl   $0x1,(%r10,%rdx,4)
L89:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L108
  test   %ebp,%ebp
  jle    L48
  lea    (%rdi,%r13,4),%r9
  lea    0x4(%r10),%rsi
  mov    $0x1,%edi
  nopw   0x0(%rax,%rax,1)
L166:
  mov    %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L86:
  mov    %edi,%edx
  sub    (%rax),%edx
  test   %edx,%edx
  jle    L155
  movslq %edx,%rdx
  mov    (%r10,%rdx,4),%ecx
  mov    (%rsi),%edx
  lea    0x1(%rcx),%r8d
  cmp    %edx,%ecx
  cmovl  %r8d,%edx
  mov    %edx,(%rsi)
L155:
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L86
  lea    0x1(%rdi),%eax
  add    $0x4,%rsi
  cmp    %edi,%ebp
  je     L48
  mov    %eax,%edi
  jmp    L166
  nopl   (%rax)
L48:
  mov    (%r10,%rbp,4),%eax
  cmp    %r12d,%eax
  je     L74
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L159:
  mov    $0x1,%eax
  jmp    L51
L74:
  mov    $0xffffffff,%eax
  jmp    L33
```

assistant: ```c
int coinChange(int *coins, int coinsSize, int amount) {
  int max = amount + 1;
  int *cnts = (int *)malloc(max * sizeof(int));
  cnts[0] = 0;
  for (int i = 1; i < max; i++) {
    cnts[i] = max;
  }
  int n = coinsSize;
  for (int i = 0; i < n; i++) {
    if (coins[i] < max) {
      cnts[coins[i]] = 1;
    }
  }
  for (int i = 1; i <= amount; i++) {
    for (int j = 0; j < n; j++) {
      int prev = i - coins[j];
      if (prev >= 1) {
        cnts[i] = (cnts[i] < cnts[prev] + 1 ? cnts[i] : cnts[prev] + 1);
      }
    }
  }
  if (cnts[amount] == max)
    return -1;
  return cnts[amount];
}
```