ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %edi,-0x404(%rbp)
  mov    %rsi,-0x410(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <seteuid@plt>
  mov    $0x0,%edi
  call   <setuid@plt>
  movabs $0x636f6c2f7273752f,%rax
  movabs $0x742f6e69622f6c61,%rdx
  mov    %rax,-0x3f0(%rbp)
  mov    %rdx,-0x3e8(%rbp)
  movabs $0x702e73706f747079,%rax
  mov    $0x79,%edx
  mov    %rax,-0x3e0(%rbp)
  mov    %rdx,-0x3d8(%rbp)
  lea    -0x3d0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x79,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x3f4(%rbp)
  movl   $0x1,-0x3f8(%rbp)
  jmp    L22
L24:
  mov    -0x3f8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x410(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x3f4(%rbp),%edx
  add    %edx,%eax
  cmp    $0x3e8,%eax
  jg     L0
  mov    -0x3f8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x410(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  lea    -0x3f0(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  addl   $0x1,-0x3f8(%rbp)
L22:
  mov    -0x3f8(%rbp),%eax
  cmp    -0x404(%rbp),%eax
  jl     L24
  jmp    L15
L0:
  nop
L15:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: %s %s

assistant: ```c
int main(int argc, char *argv[]) {
  seteuid(0);
  setuid(0);
  char cmd[1000] = "/usr/local/bin/typtops.py";
  int i;
  int lim = strlen(cmd);
  for (i = 1; i < argc; i++) {
    if ((lim + strlen(argv[i])) > 1000)
      break;
    sprintf(cmd, "%s %s", cmd, argv[i]);
  }
  system(cmd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <seteuid@plt>
  mov    $0x0,%edi
  call   <setuid@plt>
  movabs $0x636f6c2f7273752f,%rax
  movabs $0x742f6e69622f6c61,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x702e73706f747079,%rax
  mov    $0x79,%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  lea    0x20(%rsp),%rdi
  mov    $0x79,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%r12d
  jle    L39
  mov    %eax,%ebp
  lea    0x8(%r13),%rbx
  lea    -0x2(%r12),%eax
  lea    0x10(%r13,%rax,8),%r13
  lea    D3(%rip),%r12
L20:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  add    %ebp,%eax
  cmp    $0x3e8,%eax
  jg     L39
  mov    %rsp,%rdi
  mov    (%rbx),%rcx
  mov    %rdi,%rdx
  mov    %r12,%rsi
  call   <sprintf@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L20
L39:
  mov    %rsp,%rdi
  call   <system@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: %s %s

assistant: ```c
int main(int argc, char *argv[]) {
  seteuid(0);
  setuid(0);
  char cmd[1000] = "/usr/local/bin/typtops.py";
  int i;
  int lim = strlen(cmd);
  for (i = 1; i < argc; i++) {
    if ((lim + strlen(argv[i])) > 1000)
      break;
    sprintf(cmd, "%s %s", cmd, argv[i]);
  }
  system(cmd);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <seteuid@plt>
  xor    %edi,%edi
  call   <setuid@plt>
  movdqa D24(%rip),%xmm0
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    $0x79,%ecx
  rep stos %rax,%es:(%rdi)
  movaps %xmm0,(%rsp)
  movdqa D22(%rip),%xmm0
  mov    %r14,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <strlen@plt>
  cmp    $0x1,%r12d
  jle    L28
  mov    %eax,%ebp
  lea    -0x2(%r12),%eax
  lea    0x8(%r13),%rbx
  lea    D11(%rip),%r12
  lea    0x10(%r13,%rax,8),%r13
  jmp    L36
  nopl   0x0(%rax)
L19:
  mov    (%rbx),%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x8,%rbx
  call   <sprintf@plt>
  cmp    %r13,%rbx
  je     L28
L36:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  add    %ebp,%eax
  cmp    $0x3e8,%eax
  jle    L19
L28:
  mov    %r14,%rdi
  call   <system@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D24
datatype: byte[16]
name: parse_data
arguments: tag: D22
datatype: byte[16]
name: parse_data
arguments: tag: D11
datatype: string

tool: {"D24": [0x2f,0x75,0x73,0x72,0x2f,0x6c,0x6f,0x63,0x61,0x6c,0x2f,0x62,0x69,0x6e,0x2f,0x74]}

tool: {"D22": [0x79,0x70,0x74,0x6f,0x70,0x73,0x2e,0x70,0x79,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D11: %s %s

assistant: ```c
int main(int argc, char *argv[]) {
  seteuid(0);
  setuid(0);
  char cmd[1000] = "/usr/local/bin/typtops.py";
  int i;
  int lim = strlen(cmd);
  for (i = 1; i < argc; i++) {
    if ((lim + strlen(argv[i])) > 1000)
      break;
    sprintf(cmd, "%s %s", cmd, argv[i]);
  }
  system(cmd);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <seteuid@plt>
  xor    %edi,%edi
  call   <setuid@plt>
  movdqa D22(%rip),%xmm0
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    $0x79,%ecx
  rep stos %rax,%es:(%rdi)
  movaps %xmm0,(%rsp)
  movdqa D4(%rip),%xmm0
  mov    %r14,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <strlen@plt>
  cmp    $0x1,%r12d
  jle    L9
  mov    %eax,%ebp
  lea    -0x2(%r12),%eax
  lea    0x8(%r13),%rbx
  lea    D19(%rip),%r12
  lea    0x10(%r13,%rax,8),%r13
  jmp    L49
  nopl   0x0(%rax)
L46:
  mov    (%rbx),%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x8,%rbx
  call   <sprintf@plt>
  cmp    %r13,%rbx
  je     L9
L49:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  add    %ebp,%eax
  cmp    $0x3e8,%eax
  jle    L46
L9:
  mov    %r14,%rdi
  call   <system@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D22
datatype: byte[16]
name: parse_data
arguments: tag: D4
datatype: byte[16]
name: parse_data
arguments: tag: D19
datatype: string

tool: {"D22": [0x2f,0x75,0x73,0x72,0x2f,0x6c,0x6f,0x63,0x61,0x6c,0x2f,0x62,0x69,0x6e,0x2f,0x74]}

tool: {"D4": [0x79,0x70,0x74,0x6f,0x70,0x73,0x2e,0x70,0x79,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D19: %s %s

assistant: ```c
int main(int argc, char *argv[]) {
  seteuid(0);
  setuid(0);
  char cmd[1000] = "/usr/local/bin/typtops.py";
  int i;
  int lim = strlen(cmd);
  for (i = 1; i < argc; i++) {
    if ((lim + strlen(argv[i])) > 1000)
      break;
    sprintf(cmd, "%s %s", cmd, argv[i]);
  }
  system(cmd);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L35
L14:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0x989680,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L29
L28:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L29:
  cmpl   $0x2,-0x14(%rbp)
  jle    L28
  addl   $0x1,-0x18(%rbp)
L35:
  cmpl   $0x6,-0x18(%rbp)
  jle    L14
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D20
type_guessed: string

tool: D11: sscal

tool: D12: # c::%s:len=%d


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sscal", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D16(%rip),%r15
  jmp    L21
L23:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L35
L21:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0x989680,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L0:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L0
  jmp    L23
L35:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
data_type: string
name: read_data
arguments: data_tag: D29
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string

tool: D16: sscal

tool: D29: # c::%s:len=%d


tool: D1: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sscal", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D15(%rip),%r15
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L12:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L1:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L1
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L12
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
datatype: string
name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D19
datatype: string

tool: D15: sscal

tool: D12: # c::%s:len=%d


tool: D19: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sscal", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D4(%rip),%r15
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L11:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L7:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L7
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L11
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string

tool: D4: sscal

tool: D17: # c::%s:len=%d


tool: D12: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sscal", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<syncint_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  or     %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x7,%eax
  or     %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0xe,%eax
  or     %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x15,%eax
  or     %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int syncint_decode(int value) {
  unsigned int a, b, c, d, result = 0x0;
  a = value & 0xFF;
  b = (value >> 8) & 0xFF;
  c = (value >> 16) & 0xFF;
  d = (value >> 24) & 0xFF;
  result = result | a;
  result = result | (b << 7);
  result = result | (c << 14);
  result = result | (d << 21);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<syncint_decode>:
  endbr64
  mov    %edi,%eax
  shr    $0x18,%eax
  shl    $0x15,%eax
  movzbl %dil,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shr    %edx
  and    $0x7f80,%edx
  or     %edx,%eax
  shr    $0x2,%edi
  and    $0x3fc000,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
int syncint_decode(int value) {
  unsigned int a, b, c, d, result = 0x0;
  a = value & 0xFF;
  b = (value >> 8) & 0xFF;
  c = (value >> 16) & 0xFF;
  d = (value >> 24) & 0xFF;
  result = result | a;
  result = result | (b << 7);
  result = result | (c << 14);
  result = result | (d << 21);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<syncint_decode>:
  endbr64
  mov    %edi,%eax
  movzbl %dil,%edx
  shr    $0x18,%eax
  shl    $0x15,%eax
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0x2,%edi
  shr    %edx
  and    $0x3fc000,%edi
  and    $0x7f80,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int syncint_decode(int value) {
  unsigned int a, b, c, d, result = 0x0;
  a = value & 0xFF;
  b = (value >> 8) & 0xFF;
  c = (value >> 16) & 0xFF;
  d = (value >> 24) & 0xFF;
  result = result | a;
  result = result | (b << 7);
  result = result | (c << 14);
  result = result | (d << 21);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<syncint_decode>:
  endbr64
  mov    %edi,%eax
  movzbl %dil,%edx
  shr    $0x18,%eax
  shl    $0x15,%eax
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0x2,%edi
  shr    %edx
  and    $0x3fc000,%edi
  and    $0x7f80,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int syncint_decode(int value) {
  unsigned int a, b, c, d, result = 0x0;
  a = value & 0xFF;
  b = (value >> 8) & 0xFF;
  c = (value >> 16) & 0xFF;
  d = (value >> 24) & 0xFF;
  result = result | a;
  result = result | (b << 7);
  result = result | (c << 14);
  result = result | (d << 21);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D21(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movsd  D21(%rip),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movsd  D21(%rip),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type_infered: byte[8]

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double f(double x) {
  double y;
  y = (x - 1) * (x - 1) * (x - 1);
  return y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  movapd %xmm0,%xmm1
  subsd  D8(%rip),%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double f(double x) {
  double y;
  y = (x - 1) * (x - 1) * (x - 1);
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  movapd %xmm0,%xmm1
  subsd  D6(%rip),%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double f(double x) {
  double y;
  y = (x - 1) * (x - 1) * (x - 1);
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  movapd %xmm0,%xmm1
  subsd  D0(%rip),%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double f(double x) {
  double y;
  y = (x - 1) * (x - 1) * (x - 1);
  return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_clear_standard_solutions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x25,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solcon_clear_standard_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(37, a, b, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<solcon_clear_standard_solutions>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x25,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int solcon_clear_standard_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(37, a, b, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<solcon_clear_standard_solutions>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x25,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int solcon_clear_standard_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(37, a, b, c);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solcon_clear_standard_solutions>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x25,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int solcon_clear_standard_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(37, a, b, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<malloc_stub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void malloc_stub(void) {
  void *p = malloc(1);
  free(p);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<malloc_stub>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void malloc_stub(void) {
  void *p = malloc(1);
  free(p);
}
```