ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_le_int32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <fputc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  shr    $0x18,%ebx
  sar    $0x10,%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <fputc@plt>
```

assistant: ```c
void write_le_int32(struct _IO_FILE$link44 *dfile, signed int num) {
  fputc(num & 255, dfile);
  fputc(num >> 8 & 255, dfile);
  fputc(num >> 16 & 255, dfile);
  fputc(num >> 24 & 255, dfile);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <biggest_suffix@plt>
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D44
type: string
name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D15
type: string

tool: D1: Give first string:

tool: D44: %s

tool: D14: Give second string:

tool: D15: Biggest suffix is: %s


assistant: ```c
int main(void) {
  char s1[100];
  char s2[100];
  printf("Give first string:\n");
  scanf("%s", s1);
  printf("Give second string:\n");
  scanf("%s", s2);
  printf("Biggest suffix is: %s\n", biggest_suffix(s1, s2));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D32(%rip),%r12
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    0x70(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <biggest_suffix@plt>
  mov    %rax,%rsi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D34
type_infered: string
name: read_data
arguments: data_tag: D32
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D20
type_infered: string

tool: D34: Give first string:

tool: D32: %s

tool: D15: Give second string:

tool: D20: Biggest suffix is: %s


assistant: ```c
int main(void) {
  char s1[100];
  char s2[100];
  printf("Give first string:\n");
  scanf("%s", s1);
  printf("Give second string:\n");
  scanf("%s", s2);
  printf("Biggest suffix is: %s\n", biggest_suffix(s1, s2));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D20(%rip),%rdi
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <biggest_suffix@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D20
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D32
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string

tool: D20: Give first string:

tool: D7: %s

tool: D32: Give second string:

tool: D9: Biggest suffix is: %s


assistant: ```c
int main(void) {
  char s1[100];
  char s2[100];
  printf("Give first string:\n");
  scanf("%s", s1);
  printf("Give second string:\n");
  scanf("%s", s2);
  printf("Biggest suffix is: %s\n", biggest_suffix(s1, s2));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D29(%rip),%rdi
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <biggest_suffix@plt>
  lea    D26(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D32
type_guessed: string
name: unpack_data
arguments: label: D26
type_guessed: string

tool: D29: Give first string:

tool: D15: %s

tool: D32: Give second string:

tool: D26: Biggest suffix is: %s


assistant: ```c
int main(void) {
  char s1[100];
  char s2[100];
  printf("Give first string:\n");
  scanf("%s", s1);
  printf("Give second string:\n");
  scanf("%s", s2);
  printf("Biggest suffix is: %s\n", biggest_suffix(s1, s2));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L12
L28:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L17
  mov    -0x14(%rbp),%eax
  cltq
  imul   -0x8(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  cqto
  idiv   %rcx
  mov    %rdx,-0x8(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  imul   %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x18(%rbp)
L12:
  cmpl   $0x0,-0x18(%rbp)
  jg     L28
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long calc_power(int a, int b, int mod) {
  long long result = 1;
  while (b > 0) {
    if (b & 1) {
      result = (result * (long long)a) % mod;
    }
    a = ((long long)a * a) % mod;
    b /= 2;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calc_power>:
  endbr64
  test   %esi,%esi
  jle    L9
  mov    $0x1,%r9d
  movslq %edx,%r8
  jmp    L46
L37:
  movslq %edi,%rax
  imul   %rax,%rax
  cqto
  idiv   %r8
  mov    %edx,%edi
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  cmp    $0x1,%esi
  jle    L31
  mov    %ecx,%esi
L46:
  test   $0x1,%sil
  je     L37
  movslq %edi,%rax
  imul   %r9,%rax
  cqto
  idiv   %r8
  mov    %rdx,%r9
  jmp    L37
L9:
  mov    $0x1,%r9d
L31:
  mov    %r9,%rax
  ret
```

assistant: ```c
long long calc_power(int a, int b, int mod) {
  long long result = 1;
  while (b > 0) {
    if (b & 1) {
      result = (result * (long long)a) % mod;
    }
    a = ((long long)a * a) % mod;
    b /= 2;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calc_power>:
  endbr64
  test   %esi,%esi
  jle    L0
  movslq %edx,%rcx
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L4:
  movslq %edi,%rdi
  test   $0x1,%sil
  je     L1
  mov    %r8,%rax
  imul   %rdi,%rax
  cqto
  idiv   %rcx
  mov    %rdx,%r8
L1:
  mov    %rdi,%rax
  imul   %rdi,%rax
  cqto
  idiv   %rcx
  sar    %esi
  mov    %rdx,%rdi
  jne    L4
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long long calc_power(int a, int b, int mod) {
  long long result = 1;
  while (b > 0) {
    if (b & 1) {
      result = (result * (long long)a) % mod;
    }
    a = ((long long)a * a) % mod;
    b /= 2;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calc_power>:
  endbr64
  test   %esi,%esi
  jle    L16
  movslq %edx,%rcx
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L26:
  movslq %edi,%rdi
  test   $0x1,%sil
  je     L23
  mov    %r8,%rax
  imul   %rdi,%rax
  cqto
  idiv   %rcx
  mov    %rdx,%r8
L23:
  mov    %rdi,%rax
  imul   %rdi,%rax
  cqto
  idiv   %rcx
  sar    %esi
  mov    %rdx,%rdi
  jne    L26
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long long calc_power(int a, int b, int mod) {
  long long result = 1;
  while (b > 0) {
    if (b & 1) {
      result = (result * (long long)a) % mod;
    }
    a = ((long long)a * a) % mod;
    b /= 2;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn_ch_41>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <next_utf8@plt>
  cmp    $0x29,%eax
  jne    L6
  mov    -0xc(%rbp),%eax
  jmp    L25
L6:
  mov    $0xffffffff,%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int fn_ch_41(const char *text) {
  int pos = 0;
  if (next_utf8(text, &pos) == 41)
    return pos;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn_ch_41>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <next_utf8@plt>
  cmp    $0x29,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_ch_41(const char *text) {
  int pos = 0;
  if (next_utf8(text, &pos) == 41)
    return pos;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn_ch_41>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <next_utf8@plt>
  cmp    $0x29,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_ch_41(const char *text) {
  int pos = 0;
  if (next_utf8(text, &pos) == 41)
    return pos;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn_ch_41>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <next_utf8@plt>
  cmp    $0x29,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_ch_41(const char *text) {
  int pos = 0;
  if (next_utf8(text, &pos) == 41)
    return pos;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L35
L59:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L49
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L31
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L16
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L16
L49:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L16:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lcase(char *cp) {
  {
    while (*cp) {
      if ((int)*cp >= 65) {
        if ((int)*cp <= 90) {
          *cp = (char)((int)*cp + 32);
        } else {
          *cp = *cp;
        }
      } else {
        *cp = *cp;
      }
      cp++;
    }
    return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lcase>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L12
L24:
  ret
L18:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
L12:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L18
  add    $0x20,%eax
  mov    %al,(%rdi)
  jmp    L18
```

assistant: ```c
void lcase(char *cp) {
  {
    while (*cp) {
      if ((int)*cp >= 65) {
        if ((int)*cp <= 90) {
          *cp = (char)((int)*cp + 32);
        } else {
          *cp = *cp;
        }
      } else {
        *cp = *cp;
      }
      cp++;
    }
    return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lcase>:
  endbr64
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L39:
  add    $0x1,%rdi
L2:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L39
  add    $0x20,%eax
  mov    %al,(%rdi)
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L21:
  ret
```

assistant: ```c
void lcase(char *cp) {
  {
    while (*cp) {
      if ((int)*cp >= 65) {
        if ((int)*cp <= 90) {
          *cp = (char)((int)*cp + 32);
        } else {
          *cp = *cp;
        }
      } else {
        *cp = *cp;
      }
      cp++;
    }
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lcase>:
  endbr64
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L34:
  add    $0x1,%rdi
L4:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
L32:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L34
  add    $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L32
  ret
  nopl   (%rax)
L36:
  ret
```

assistant: ```c
void lcase(char *cp) {
  {
    while (*cp) {
      if ((int)*cp >= 65) {
        if ((int)*cp <= 90) {
          *cp = (char)((int)*cp + 32);
        } else {
          *cp = *cp;
        }
      } else {
        *cp = *cp;
      }
      cp++;
    }
    return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x30,-0x4(%rbp)
  je     L4
  cmpl   $0x31,-0x4(%rbp)
  jne    L24
L4:
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L49
L24:
  cmpl   $0x23,-0x4(%rbp)
  je     L5
  cmpl   $0x3b,-0x4(%rbp)
  jne    L33
L5:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <line_Comment@plt>
L33:
  mov    $0xffffffff,%eax
L49:
  leave
  ret
```

assistant: ```c
int binary(int c, FILE *source_file) {
  if (c == '0' || c == '1')
    return (c - 48);
  else if (c == '#' || c == ';')
    line_Comment(source_file);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binary>:
  endbr64
  lea    -0x30(%rdi),%edx
  cmp    $0x1,%edx
  jbe    L19
  cmp    $0x23,%edi
  je     L3
  mov    $0xffffffff,%edx
  cmp    $0x3b,%edi
  je     L3
L19:
  mov    %edx,%eax
  ret
L3:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <line_Comment@plt>
  mov    $0xffffffff,%edx
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int binary(int c, FILE *source_file) {
  if (c == '0' || c == '1')
    return (c - 48);
  else if (c == '#' || c == ';')
    line_Comment(source_file);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binary>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L2
  cmp    $0x23,%edi
  je     L17
  mov    $0xffffffff,%eax
  cmp    $0x3b,%edi
  je     L17
L2:
  ret
  nopl   0x0(%rax)
L17:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <line_Comment@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int binary(int c, FILE *source_file) {
  if (c == '0' || c == '1')
    return (c - 48);
  else if (c == '#' || c == ';')
    line_Comment(source_file);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<binary>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L13
  cmp    $0x23,%edi
  je     L1
  mov    $0xffffffff,%eax
  cmp    $0x3b,%edi
  je     L1
L13:
  ret
  nopl   0x0(%rax)
L1:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <line_Comment@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int binary(int c, FILE *source_file) {
  if (c == '0' || c == '1')
    return (c - 48);
  else if (c == '#' || c == ';')
    line_Comment(source_file);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RGB24PackedToPlanarHelper_SSE2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rcx
  lea    0x4(%rcx),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rcx
  lea    0x8(%rcx),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rcx
  lea    0xc(%rcx),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rcx
  lea    0x10(%rcx),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rcx
  lea    0x14(%rcx),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void RGB24PackedToPlanarHelper_SSE2(const __m128i *const in, __m128i *const out) {
  out[0] = _mm_unpacklo_epi8(in[0], in[3]);
  out[1] = _mm_unpackhi_epi8(in[0], in[3]);
  out[2] = _mm_unpacklo_epi8(in[1], in[4]);
  out[3] = _mm_unpackhi_epi8(in[1], in[4]);
  out[4] = _mm_unpacklo_epi8(in[2], in[5]);
  out[5] = _mm_unpackhi_epi8(in[2], in[5]);
}
```
user: What is the c source code of the assembly code below?

```asm
<RGB24PackedToPlanarHelper_SSE2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    0xc(%rdi),%esi
  mov    (%rdi),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x0(%rbp)
  mov    0xc(%rbx),%esi
  mov    (%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0x4(%rbp)
  mov    0x10(%rbx),%esi
  mov    0x4(%rbx),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x8(%rbp)
  mov    0x10(%rbx),%esi
  mov    0x4(%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0xc(%rbp)
  mov    0x14(%rbx),%esi
  mov    0x8(%rbx),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x10(%rbp)
  mov    0x14(%rbx),%esi
  mov    0x8(%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0x14(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void RGB24PackedToPlanarHelper_SSE2(const __m128i *const in, __m128i *const out) {
  out[0] = _mm_unpacklo_epi8(in[0], in[3]);
  out[1] = _mm_unpackhi_epi8(in[0], in[3]);
  out[2] = _mm_unpacklo_epi8(in[1], in[4]);
  out[3] = _mm_unpackhi_epi8(in[1], in[4]);
  out[4] = _mm_unpacklo_epi8(in[2], in[5]);
  out[5] = _mm_unpackhi_epi8(in[2], in[5]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RGB24PackedToPlanarHelper_SSE2>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0xc(%rdi),%esi
  mov    (%rdi),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x0(%rbp)
  mov    0xc(%rbx),%esi
  mov    (%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0x4(%rbp)
  mov    0x10(%rbx),%esi
  mov    0x4(%rbx),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x8(%rbp)
  mov    0x10(%rbx),%esi
  mov    0x4(%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0xc(%rbp)
  mov    0x14(%rbx),%esi
  mov    0x8(%rbx),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x10(%rbp)
  mov    0x14(%rbx),%esi
  mov    0x8(%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0x14(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void RGB24PackedToPlanarHelper_SSE2(const __m128i *const in, __m128i *const out) {
  out[0] = _mm_unpacklo_epi8(in[0], in[3]);
  out[1] = _mm_unpackhi_epi8(in[0], in[3]);
  out[2] = _mm_unpacklo_epi8(in[1], in[4]);
  out[3] = _mm_unpackhi_epi8(in[1], in[4]);
  out[4] = _mm_unpacklo_epi8(in[2], in[5]);
  out[5] = _mm_unpackhi_epi8(in[2], in[5]);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RGB24PackedToPlanarHelper_SSE2>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0xc(%rdi),%esi
  mov    (%rdi),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x0(%rbp)
  mov    0xc(%rbx),%esi
  mov    (%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0x4(%rbp)
  mov    0x10(%rbx),%esi
  mov    0x4(%rbx),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x8(%rbp)
  mov    0x10(%rbx),%esi
  mov    0x4(%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0xc(%rbp)
  mov    0x14(%rbx),%esi
  mov    0x8(%rbx),%edi
  call   <_mm_unpacklo_epi8@plt>
  mov    %eax,0x10(%rbp)
  mov    0x14(%rbx),%esi
  mov    0x8(%rbx),%edi
  call   <_mm_unpackhi_epi8@plt>
  mov    %eax,0x14(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void RGB24PackedToPlanarHelper_SSE2(const __m128i *const in, __m128i *const out) {
  out[0] = _mm_unpacklo_epi8(in[0], in[3]);
  out[1] = _mm_unpackhi_epi8(in[0], in[3]);
  out[2] = _mm_unpacklo_epi8(in[1], in[4]);
  out[3] = _mm_unpackhi_epi8(in[1], in[4]);
  out[4] = _mm_unpacklo_epi8(in[2], in[5]);
  out[5] = _mm_unpackhi_epi8(in[2], in[5]);
}
```