ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IceUnlockAuthFile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x820,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x3fe,%eax
  jle    L1
L7:
  mov    0x818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x820,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %rsp,%r12
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %r12,%rax
  movw   $0x632d,(%rax)
  movb   $0x0,0x2(%rax)
  lea    0x410(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %rbp,%rax
  movw   $0x6c2d,(%rax)
  movb   $0x0,0x2(%rax)
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <unlink@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <unlink@plt>
  jmp    L7
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void IceUnlockAuthFile(file_name) char *file_name;
{
  char creat_name[1025];
  char link_name[1025];
  if ((int)strlen(file_name) > 1022)
    return;
  strcpy(creat_name, file_name);
  strcat(creat_name, "-c");
  strcpy(link_name, file_name);
  strcat(link_name, "-l");
  unlink(creat_name);
  unlink(link_name);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<IceUnlockAuthFile>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x828,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x3fe,%eax
  jg     L12
  mov    %rsp,%r13
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  lea    0x410(%rsp),%r12
  call   <memcpy@plt>
  lea    0x0(%r13,%rbx,1),%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x632d,%edx
  movb   $0x0,0x2(%rax)
  mov    %dx,(%rax)
  mov    %rbx,%rdx
  add    %r12,%rbx
  call   <memcpy@plt>
  mov    $0x6c2d,%ecx
  movb   $0x0,0x2(%rbx)
  xor    %eax,%eax
  mov    %cx,(%rbx)
  mov    %r13,%rdi
  call   <unlink@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <unlink@plt>
L12:
  mov    0x818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x828,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void IceUnlockAuthFile(file_name) char *file_name;
{
  char creat_name[1025];
  char link_name[1025];
  if ((int)strlen(file_name) > 1022)
    return;
  strcpy(creat_name, file_name);
  strcat(creat_name, "-c");
  strcpy(link_name, file_name);
  strcat(link_name, "-l");
  unlink(creat_name);
  unlink(link_name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IceUnlockAuthFile>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x828,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x3fe,%eax
  jg     L8
  mov    %rsp,%r13
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  lea    0x410(%rsp),%r12
  call   <memcpy@plt>
  lea    0x0(%r13,%rbx,1),%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x632d,%edx
  movb   $0x0,0x2(%rax)
  mov    %dx,(%rax)
  mov    %rbx,%rdx
  add    %r12,%rbx
  call   <memcpy@plt>
  mov    $0x6c2d,%ecx
  movb   $0x0,0x2(%rbx)
  xor    %eax,%eax
  mov    %cx,(%rbx)
  mov    %r13,%rdi
  call   <unlink@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <unlink@plt>
L8:
  mov    0x818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x828,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void IceUnlockAuthFile(file_name) char *file_name;
{
  char creat_name[1025];
  char link_name[1025];
  if ((int)strlen(file_name) > 1022)
    return;
  strcpy(creat_name, file_name);
  strcat(creat_name, "-c");
  strcpy(link_name, file_name);
  strcat(link_name, "-l");
  unlink(creat_name);
  unlink(link_name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setup_frame_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xc1400000,%eax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L2:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1,(%rax)
  addl   $0x1,-0x10(%rbp)
L16:
  cmpl   $0x3ff,-0x10(%rbp)
  jle    L2
  movl   $0x400,-0xc(%rbp)
  jmp    L12
L5:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0xfffff,-0xc(%rbp)
  jle    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setup_frame_alloc() {
  unsigned char *frames_ptr = (void *)0xC1400000;
  for (int i = 0; i < 0x400; i++) {
    frames_ptr[i] = 1;
  }
  for (int i = 0x400; i < 0x100000; i++) {
    frames_ptr[i] = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setup_frame_alloc>:
  endbr64
  mov    $0xc1400000,%eax
  mov    $0xc1400400,%edx
L0:
  movb   $0x1,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
  mov    $0xc1500000,%edx
L19:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
  ret
```

assistant: ```c
void setup_frame_alloc() {
  unsigned char *frames_ptr = (void *)0xC1400000;
  for (int i = 0; i < 0x400; i++) {
    frames_ptr[i] = 1;
  }
  for (int i = 0x400; i < 0x100000; i++) {
    frames_ptr[i] = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<setup_frame_alloc>:
  endbr64
  mov    $0xc1400000,%edx
  mov    $0x80,%ecx
  xor    %esi,%esi
  movabs $0x101010101010101,%rax
  mov    %rdx,%rdi
  mov    $0xffc00,%edx
  rep stos %rax,%es:(%rdi)
  jmp    1050 <memset@plt>
```

assistant: ```c
void setup_frame_alloc() {
  unsigned char *frames_ptr = (void *)0xC1400000;
  for (int i = 0; i < 0x400; i++) {
    frames_ptr[i] = 1;
  }
  for (int i = 0x400; i < 0x100000; i++) {
    frames_ptr[i] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setup_frame_alloc>:
  endbr64
  mov    $0xc1400000,%edx
  mov    $0x80,%ecx
  xor    %esi,%esi
  movabs $0x101010101010101,%rax
  mov    %rdx,%rdi
  mov    $0xffc00,%edx
  rep stos %rax,%es:(%rdi)
  jmp    1050 <memset@plt>
```

assistant: ```c
void setup_frame_alloc() {
  unsigned char *frames_ptr = (void *)0xC1400000;
  for (int i = 0; i < 0x400; i++) {
    frames_ptr[i] = 1;
  }
  for (int i = 0x400; i < 0x100000; i++) {
    frames_ptr[i] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dec_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xf,-0x4(%rbp)
  ja     L144
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D6(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D6(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x30,%eax
  jmp    L32
  mov    $0x31,%eax
  jmp    L32
  mov    $0x32,%eax
  jmp    L32
  mov    $0x33,%eax
  jmp    L32
  mov    $0x34,%eax
  jmp    L32
  mov    $0x35,%eax
  jmp    L32
  mov    $0x36,%eax
  jmp    L32
  mov    $0x37,%eax
  jmp    L32
  mov    $0x38,%eax
  jmp    L32
  mov    $0x39,%eax
  jmp    L32
  mov    $0x41,%eax
  jmp    L32
  mov    $0x42,%eax
  jmp    L32
  mov    $0x43,%eax
  jmp    L32
  mov    $0x44,%eax
  jmp    L32
  mov    $0x45,%eax
  jmp    L32
  mov    $0x46,%eax
  jmp    L32
L144:
  mov    $0x2d,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
char dec_to_hex(int num) {
  switch (num) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'A';
    break;
  case 11:
    return 'B';
    break;
  case 12:
    return 'C';
    break;
  case 13:
    return 'D';
    break;
  case 14:
    return 'E';
    break;
  case 15:
    return 'F';
    break;
  default:
    return '-';
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dec_to_hex>:
  endbr64
  cmp    $0xf,%edi
  ja     L0
  mov    %edi,%edi
  lea    D3(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x31,%eax
  ret
  mov    $0x32,%eax
  ret
  mov    $0x33,%eax
  ret
  mov    $0x34,%eax
  ret
  mov    $0x35,%eax
  ret
  mov    $0x36,%eax
  ret
  mov    $0x37,%eax
  ret
  mov    $0x38,%eax
  ret
  mov    $0x39,%eax
  ret
  mov    $0x41,%eax
  ret
  mov    $0x42,%eax
  ret
  mov    $0x43,%eax
  ret
  mov    $0x44,%eax
  ret
  mov    $0x45,%eax
  ret
  mov    $0x46,%eax
  ret
L0:
  mov    $0x2d,%eax
  ret
  mov    $0x30,%eax
  ret
```

assistant: ```c
char dec_to_hex(int num) {
  switch (num) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'A';
    break;
  case 11:
    return 'B';
    break;
  case 12:
    return 'C';
    break;
  case 13:
    return 'D';
    break;
  case 14:
    return 'E';
    break;
  case 15:
    return 'F';
    break;
  default:
    return '-';
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dec_to_hex>:
  endbr64
  mov    $0x2d,%eax
  cmp    $0xf,%edi
  ja     L9
  mov    %edi,%edi
  lea    D2(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L9:
  ret
```

assistant: ```c
char dec_to_hex(int num) {
  switch (num) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'A';
    break;
  case 11:
    return 'B';
    break;
  case 12:
    return 'C';
    break;
  case 13:
    return 'D';
    break;
  case 14:
    return 'E';
    break;
  case 15:
    return 'F';
    break;
  default:
    return '-';
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dec_to_hex>:
  endbr64
  mov    $0x2d,%eax
  cmp    $0xf,%edi
  ja     L7
  mov    %edi,%edi
  lea    D9(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L7:
  ret
```

assistant: ```c
char dec_to_hex(int num) {
  switch (num) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'A';
    break;
  case 11:
    return 'B';
    break;
  case 12:
    return 'C';
    break;
  case 13:
    return 'D';
    break;
  case 14:
    return 'E';
    break;
  case 15:
    return 'F';
    break;
  default:
    return '-';
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<leerNumero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L20:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L20
  cmpl   $0xdac,-0x14(%rbp)
  jg     L20
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <validarEntrada@plt>
  test   %rax,%rax
  jne    L20
  cmpl   $0x0,-0x14(%rbp)
  je     L35
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L35:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L12:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D27
type: string
name: parse_data
arguments: label: D31
type: string
name: parse_data
arguments: label: D38
type: string
name: parse_data
arguments: label: D37
type: string

tool: D27: Ingrese numero entre 1 y 3500: 

tool: D31: %s

tool: D38: El numero es: %d


tool: D37: No es un numero

assistant: ```c
int leerNumero() {
  int num;
  char stringNum[5];
  do {
    printf("Ingrese numero entre 1 y 3500: \n");
    scanf("%s", stringNum);
    num = atoi(stringNum);
  } while ((num < 1) || (num > 3500) || (validarEntrada(stringNum) != 0));
  if (num != 0) {
    printf("El numero es: %d\n", num);
  } else {
    printf("No es un numero\n");
  }
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<leerNumero>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%r13
  lea    0x3(%rsp),%rbp
  lea    D8(%rip),%r12
L18:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  lea    -0x1(%rax),%eax
  cmp    $0xdab,%eax
  ja     L18
  mov    %rbp,%rdi
  call   <validarEntrada@plt>
  test   %rax,%rax
  jne    L18
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D20: Ingrese numero entre 1 y 3500: 

tool: D8: %s

tool: D2: El numero es: %d


assistant: ```c
int leerNumero() {
  int num;
  char stringNum[5];
  do {
    printf("Ingrese numero entre 1 y 3500: \n");
    scanf("%s", stringNum);
    num = atoi(stringNum);
  } while ((num < 1) || (num > 3500) || (validarEntrada(stringNum) != 0));
  if (num != 0) {
    printf("El numero es: %d\n", num);
  } else {
    printf("No es un numero\n");
  }
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<leerNumero>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbx
  nopl   0x0(%rax)
L16:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  lea    -0x1(%rax),%eax
  cmp    $0xdab,%eax
  ja     L16
  mov    %rbx,%rdi
  call   <validarEntrada@plt>
  test   %rax,%rax
  jne    L16
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D9
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D1: Ingrese numero entre 1 y 3500: 

tool: D9: %s

tool: D4: El numero es: %d


assistant: ```c
int leerNumero() {
  int num;
  char stringNum[5];
  do {
    printf("Ingrese numero entre 1 y 3500: \n");
    scanf("%s", stringNum);
    num = atoi(stringNum);
  } while ((num < 1) || (num > 3500) || (validarEntrada(stringNum) != 0));
  if (num != 0) {
    printf("El numero es: %d\n", num);
  } else {
    printf("No es un numero\n");
  }
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<leerNumero>:
  endbr64
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbx
  nopl   0x0(%rax)
L1:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  lea    -0x1(%rax),%eax
  cmp    $0xdab,%eax
  ja     L1
  mov    %rbx,%rdi
  call   <validarEntrada@plt>
  test   %rax,%rax
  jne    L1
  mov    %r12d,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type: string
name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D11
type: string

tool: D27: Ingrese numero entre 1 y 3500: 

tool: D8: %s

tool: D11: El numero es: %d


assistant: ```c
int leerNumero() {
  int num;
  char stringNum[5];
  do {
    printf("Ingrese numero entre 1 y 3500: \n");
    scanf("%s", stringNum);
    num = atoi(stringNum);
  } while ((num < 1) || (num > 3500) || (validarEntrada(stringNum) != 0));
  if (num != 0) {
    printf("El numero es: %d\n", num);
  } else {
    printf("No es un numero\n");
  }
  return num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<VecSelfAdd3fv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void VecSelfAdd3fv(float v[3], const float a[3]) {
  v[0] += a[0];
  v[1] += a[1];
  v[2] += a[2];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<VecSelfAdd3fv>:
  endbr64
  movss  (%rdi),%xmm0
  addss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  addss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  addss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void VecSelfAdd3fv(float v[3], const float a[3]) {
  v[0] += a[0];
  v[1] += a[1];
  v[2] += a[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<VecSelfAdd3fv>:
  endbr64
  movss  (%rdi),%xmm0
  addss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  addss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  addss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void VecSelfAdd3fv(float v[3], const float a[3]) {
  v[0] += a[0];
  v[1] += a[1];
  v[2] += a[2];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getNextMinForTs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  imul   $0x3c,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x3c(%rax),%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  pop    %rbp
  ret
```

assistant: ```c
time_t getNextMinForTs(time_t ts) {
  int modValue = (int)ts % 60;
  return (time_t)(ts + 60 - modValue);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getNextMinForTs>:
  endbr64
  lea    0x3c(%rdi),%rax
  movslq %edi,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %edi,%edx
  sar    $0x5,%edx
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3c,%edx,%edx
  sub    %edx,%edi
  movslq %edi,%rdi
  sub    %rdi,%rax
  ret
```

assistant: ```c
time_t getNextMinForTs(time_t ts) {
  int modValue = (int)ts % 60;
  return (time_t)(ts + 60 - modValue);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getNextMinForTs>:
  endbr64
  movslq %edi,%rdx
  mov    %edi,%ecx
  lea    0x3c(%rdi),%rax
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %edi,%edx
  sar    $0x5,%edx
  sub    %ecx,%edx
  imul   $0x3c,%edx,%edx
  sub    %edx,%edi
  movslq %edi,%rdi
  sub    %rdi,%rax
  ret
```

assistant: ```c
time_t getNextMinForTs(time_t ts) {
  int modValue = (int)ts % 60;
  return (time_t)(ts + 60 - modValue);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getNextMinForTs>:
  endbr64
  movslq %edi,%rdx
  mov    %edi,%ecx
  lea    0x3c(%rdi),%rax
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %edi,%edx
  sar    $0x5,%edx
  sub    %ecx,%edx
  imul   $0x3c,%edx,%edx
  sub    %edx,%edi
  movslq %edi,%rdi
  sub    %rdi,%rax
  ret
```

assistant: ```c
time_t getNextMinForTs(time_t ts) {
  int modValue = (int)ts % 60;
  return (time_t)(ts + 60 - modValue);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <XOpenDisplay@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <DefaultScreen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <RootWindow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%esi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  push   $0x0
  push   $0x1
  mov    $0x64,%r9d
  mov    $0x64,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <XCreateSimpleWindow@plt>
  add    $0x20,%rsp
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <XMapWindow@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <XFlush@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <XCloseDisplay@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  Display *display;
  Window window, rootwindow;
  int screen;
  display = XOpenDisplay(NULL);
  screen = DefaultScreen(display);
  rootwindow = RootWindow(display, screen);
  window = XCreateSimpleWindow(display, rootwindow, 0, 0, 100, 100, 1, 0, 0);
  XMapWindow(display, window);
  XFlush(display);
  sleep(10);
  XCloseDisplay(display);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <XOpenDisplay@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <DefaultScreen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <RootWindow@plt>
  mov    %eax,%esi
  sub    $0x8,%rsp
  push   $0x0
  push   $0x0
  push   $0x1
  mov    $0x64,%r9d
  mov    $0x64,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <XCreateSimpleWindow@plt>
  mov    %eax,%esi
  add    $0x20,%rsp
  mov    %rbx,%rdi
  call   <XMapWindow@plt>
  mov    %rbx,%rdi
  call   <XFlush@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <XCloseDisplay@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  Display *display;
  Window window, rootwindow;
  int screen;
  display = XOpenDisplay(NULL);
  screen = DefaultScreen(display);
  rootwindow = RootWindow(display, screen);
  window = XCreateSimpleWindow(display, rootwindow, 0, 0, 100, 100, 1, 0, 0);
  XMapWindow(display, window);
  XFlush(display);
  sleep(10);
  XCloseDisplay(display);
  return (0);
}
```