ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calculateSpan>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <createStack@plt>
  mov    %rax,%rbx
  movslq %ebp,%rax
  mov    %rax,0x8(%rsp)
  test   %ebp,%ebp
  jle    L32
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %r13d,%r15d
  mov    $0x1,%ebp
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdi
  call   <peek@plt>
  mov    (%r12,%r13,4),%ecx
  cmp    %ecx,(%r12,%rax,4)
  jge    L4
  mov    %rbx,%rdi
  call   <peek@plt>
  mov    %rbx,%rdi
  add    (%r14,%rax,4),%ebp
  call   <pop@plt>
L25:
  mov    %rbx,%rdi
  call   <isEmpty@plt>
  test   %eax,%eax
  je     L9
L4:
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    %ebp,(%r14,%r13,4)
  add    $0x1,%r13
  cmp    0x8(%rsp),%r13
  jne    L26
L32:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void calculateSpan(int price[], int n, int span[]) {
  struct stack *stack = createStack(n);
  for (int i = 0; i < n; i++) {
    int cnt = 1;
    while (!isEmpty(stack) && price[peek(stack)] < price[i]) {
      cnt += span[peek(stack)];
      pop(stack);
    }
    push(stack, i);
    span[i] = cnt;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ASAP_PutLittleEndian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x3(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ASAP_PutLittleEndian(unsigned char *buffer, int offset, int value) {
  buffer[offset] = (unsigned char)value;
  buffer[offset + 1] = (unsigned char)(value >> 8);
  buffer[offset + 2] = (unsigned char)(value >> 16);
  buffer[offset + 3] = (unsigned char)(value >> 24);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ASAP_PutLittleEndian>:
  endbr64
  movslq %esi,%rsi
  mov    %dl,(%rdi,%rsi,1)
  movzbl %dh,%eax
  mov    %al,0x1(%rdi,%rsi,1)
  mov    %edx,%eax
  sar    $0x10,%eax
  mov    %al,0x2(%rdi,%rsi,1)
  sar    $0x18,%edx
  mov    %dl,0x3(%rdi,%rsi,1)
  ret
```

assistant: ```c
void ASAP_PutLittleEndian(unsigned char *buffer, int offset, int value) {
  buffer[offset] = (unsigned char)value;
  buffer[offset + 1] = (unsigned char)(value >> 8);
  buffer[offset + 2] = (unsigned char)(value >> 16);
  buffer[offset + 3] = (unsigned char)(value >> 24);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ASAP_PutLittleEndian>:
  endbr64
  movslq %esi,%rsi
  mov    %edx,%eax
  mov    %dl,(%rdi,%rsi,1)
  sar    $0x10,%eax
  mov    %dh,0x1(%rdi,%rsi,1)
  sar    $0x18,%edx
  mov    %al,0x2(%rdi,%rsi,1)
  mov    %dl,0x3(%rdi,%rsi,1)
  ret
```

assistant: ```c
void ASAP_PutLittleEndian(unsigned char *buffer, int offset, int value) {
  buffer[offset] = (unsigned char)value;
  buffer[offset + 1] = (unsigned char)(value >> 8);
  buffer[offset + 2] = (unsigned char)(value >> 16);
  buffer[offset + 3] = (unsigned char)(value >> 24);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ASAP_PutLittleEndian>:
  endbr64
  movslq %esi,%rsi
  mov    %edx,%eax
  mov    %dl,(%rdi,%rsi,1)
  sar    $0x10,%eax
  mov    %dh,0x1(%rdi,%rsi,1)
  sar    $0x18,%edx
  mov    %al,0x2(%rdi,%rsi,1)
  mov    %dl,0x3(%rdi,%rsi,1)
  ret
```

assistant: ```c
void ASAP_PutLittleEndian(unsigned char *buffer, int offset, int value) {
  buffer[offset] = (unsigned char)value;
  buffer[offset + 1] = (unsigned char)(value >> 8);
  buffer[offset + 2] = (unsigned char)(value >> 16);
  buffer[offset + 3] = (unsigned char)(value >> 24);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movsd  -0x40(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jbe    L0
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L44
L0:
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
L44:
  movsd  -0x30(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L21
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L21:
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L5
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
L5:
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D35
type: string
name: unpack_data
arguments: data_label: D41
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D29
type: string
name: unpack_data
arguments: data_label: D48
type: string
name: unpack_data
arguments: data_label: D18
type: string

tool: D35: Wprowadz trzy liczby calkowite: 

tool: D41: %lf%lf%lf

tool: D15: Suma wynosi: %.2lf


tool: D29: Iloczyn wynosi: %.2lf


tool: D48: Najmniejsza liczba to: %.2lf


tool: D18: Najwieksza liczba to: %.2lf


assistant: ```c
int main() {
  double num1, num2, num3;
  double sum, product, min, max;
  printf("Wprowadz trzy liczby calkowite: ");
  scanf("%lf%lf%lf", &num1, &num2, &num3);
  sum = num1 + num2 + num3;
  printf("Suma wynosi: %.2lf\n", sum);
  product = num1 * num2 * num3;
  printf("Iloczyn wynosi: %.2lf\n", product);
  max = num1;
  min = num1;
  if (num2 > num1)
    max = num2;
  else
    min = num2;
  if (num3 > max)
    max = num3;
  if (num3 < min)
    min = num3;
  printf("Najmniejsza liczba to: %.2lf\n", min);
  printf("Najwieksza liczba to: %.2lf\n", max);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rbx
  movq   %rbx,%xmm3
  comisd %xmm0,%xmm3
  ja     L8
  movq   %xmm0,%rax
  movq   %rbx,%xmm0
  mov    %rax,%rbx
L8:
  movsd  0x10(%rsp),%xmm1
  movapd %xmm1,%xmm2
  movq   %rbx,%xmm4
  maxsd  %xmm4,%xmm2
  movq   %xmm2,%rbx
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movq   %rbx,%xmm0
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D53
data_type: string
name: read_data
arguments: data_tag: D36
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string
name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D21
data_type: string
name: read_data
arguments: data_tag: D30
data_type: string

tool: D53: Wprowadz trzy liczby calkowite: 

tool: D36: %lf%lf%lf

tool: D6: Suma wynosi: %.2lf


tool: D17: Iloczyn wynosi: %.2lf


tool: D21: Najmniejsza liczba to: %.2lf


tool: D30: Najwieksza liczba to: %.2lf


assistant: ```c
int main() {
  double num1, num2, num3;
  double sum, product, min, max;
  printf("Wprowadz trzy liczby calkowite: ");
  scanf("%lf%lf%lf", &num1, &num2, &num3);
  sum = num1 + num2 + num3;
  printf("Suma wynosi: %.2lf\n", sum);
  product = num1 * num2 * num3;
  printf("Iloczyn wynosi: %.2lf\n", product);
  max = num1;
  min = num1;
  if (num2 > num1)
    max = num2;
  else
    min = num2;
  if (num3 > max)
    max = num3;
  if (num3 < min)
    min = num3;
  printf("Najmniejsza liczba to: %.2lf\n", min);
  printf("Najwieksza liczba to: %.2lf\n", max);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D55(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  lea    D14(%rip),%rdi
  addsd  0x20(%rsp),%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm0
  lea    D44(%rip),%rdi
  mulsd  0x20(%rsp),%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm1
  comisd %xmm0,%xmm1
  ja     L16
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L16:
  movsd  0x20(%rsp),%xmm2
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  movapd %xmm2,%xmm3
  minsd  %xmm0,%xmm2
  maxsd  %xmm1,%xmm3
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x1,%eax
  lea    D6(%rip),%rdi
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D55
data_type: string
name: unpack_data
arguments: data_label: D54
data_type: string
name: unpack_data
arguments: data_label: D14
data_type: string
name: unpack_data
arguments: data_label: D44
data_type: string
name: unpack_data
arguments: data_label: D22
data_type: string
name: unpack_data
arguments: data_label: D6
data_type: string

tool: D55: Wprowadz trzy liczby calkowite: 

tool: D54: %lf%lf%lf

tool: D14: Suma wynosi: %.2lf


tool: D44: Iloczyn wynosi: %.2lf


tool: D22: Najmniejsza liczba to: %.2lf


tool: D6: Najwieksza liczba to: %.2lf


assistant: ```c
int main() {
  double num1, num2, num3;
  double sum, product, min, max;
  printf("Wprowadz trzy liczby calkowite: ");
  scanf("%lf%lf%lf", &num1, &num2, &num3);
  sum = num1 + num2 + num3;
  printf("Suma wynosi: %.2lf\n", sum);
  product = num1 * num2 * num3;
  printf("Iloczyn wynosi: %.2lf\n", product);
  max = num1;
  min = num1;
  if (num2 > num1)
    max = num2;
  else
    min = num2;
  if (num3 > max)
    max = num3;
  if (num3 < min)
    min = num3;
  printf("Najmniejsza liczba to: %.2lf\n", min);
  printf("Najwieksza liczba to: %.2lf\n", max);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D45(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  lea    D36(%rip),%rdi
  addsd  0x20(%rsp),%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm0
  lea    D0(%rip),%rdi
  mulsd  0x20(%rsp),%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm1
  comisd %xmm0,%xmm1
  ja     L2
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L2:
  movsd  0x20(%rsp),%xmm2
  lea    D10(%rip),%rdi
  mov    $0x1,%eax
  movapd %xmm2,%xmm3
  minsd  %xmm0,%xmm2
  maxsd  %xmm1,%xmm3
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x1,%eax
  lea    D16(%rip),%rdi
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D45
datatype: string
name: extract_symbolic_data
arguments: data_tag: D42
datatype: string
name: extract_symbolic_data
arguments: data_tag: D36
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D16
datatype: string

tool: D45: Wprowadz trzy liczby calkowite: 

tool: D42: %lf%lf%lf

tool: D36: Suma wynosi: %.2lf


tool: D0: Iloczyn wynosi: %.2lf


tool: D10: Najmniejsza liczba to: %.2lf


tool: D16: Najwieksza liczba to: %.2lf


assistant: ```c
int main() {
  double num1, num2, num3;
  double sum, product, min, max;
  printf("Wprowadz trzy liczby calkowite: ");
  scanf("%lf%lf%lf", &num1, &num2, &num3);
  sum = num1 + num2 + num3;
  printf("Suma wynosi: %.2lf\n", sum);
  product = num1 * num2 * num3;
  printf("Iloczyn wynosi: %.2lf\n", product);
  max = num1;
  min = num1;
  if (num2 > num1)
    max = num2;
  else
    min = num2;
  if (num3 > max)
    max = num3;
  if (num3 < min)
    min = num3;
  printf("Najmniejsza liczba to: %.2lf\n", min);
  printf("Najwieksza liczba to: %.2lf\n", max);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int set_random(void *dst, size_t len) {
  int ret = 0;
  memset(dst, 0, len);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_random>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int set_random(void *dst, size_t len) {
  int ret = 0;
  memset(dst, 0, len);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_random>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int set_random(void *dst, size_t len) {
  int ret = 0;
  memset(dst, 0, len);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_random>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int set_random(void *dst, size_t len) {
  int ret = 0;
  memset(dst, 0, len);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eulerf_from_mat4f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat3f_from_mat4f@plt>
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <eulerf_from_mat3f@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void eulerf_from_mat4f(float angles[3], const float m[16], const char order[3]) {
  float tmpMat[9];
  mat3f_from_mat4f(tmpMat, m);
  eulerf_from_mat3f(angles, tmpMat, order);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eulerf_from_mat4f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <mat3f_from_mat4f@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <eulerf_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eulerf_from_mat4f(float angles[3], const float m[16], const char order[3]) {
  float tmpMat[9];
  mat3f_from_mat4f(tmpMat, m);
  eulerf_from_mat3f(angles, tmpMat, order);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eulerf_from_mat4f>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <mat3f_from_mat4f@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <eulerf_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eulerf_from_mat4f(float angles[3], const float m[16], const char order[3]) {
  float tmpMat[9];
  mat3f_from_mat4f(tmpMat, m);
  eulerf_from_mat3f(angles, tmpMat, order);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<eulerf_from_mat4f>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <mat3f_from_mat4f@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <eulerf_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eulerf_from_mat4f(float angles[3], const float m[16], const char order[3]) {
  float tmpMat[9];
  mat3f_from_mat4f(tmpMat, m);
  eulerf_from_mat3f(angles, tmpMat, order);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <sm1000_leds_switches_init@plt>
L6:
  mov    $0x0,%eax
  call   <switch_select@plt>
  mov    %eax,%edi
  call   <led_pwr@plt>
  mov    $0x0,%eax
  call   <switch_ptt@plt>
  mov    %eax,%edi
  call   <led_ptt@plt>
  mov    $0x0,%eax
  call   <switch_back@plt>
  mov    %eax,%edi
  call   <led_rt@plt>
  mov    $0x0,%eax
  call   <switch_back@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <led_err@plt>
  jmp    L6
```

assistant: ```c
int main(void) {
  sm1000_leds_switches_init();
  while (1) {
    led_pwr(switch_select());
    led_ptt(switch_ptt());
    led_rt(switch_back());
    led_err(!switch_back());
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sm1000_leds_switches_init@plt>
L9:
  mov    $0x0,%eax
  call   <switch_select@plt>
  mov    %eax,%edi
  call   <led_pwr@plt>
  mov    $0x0,%eax
  call   <switch_ptt@plt>
  mov    %eax,%edi
  call   <led_ptt@plt>
  mov    $0x0,%eax
  call   <switch_back@plt>
  mov    %eax,%edi
  call   <led_rt@plt>
  mov    $0x0,%eax
  call   <switch_back@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <led_err@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  sm1000_leds_switches_init();
  while (1) {
    led_pwr(switch_select());
    led_ptt(switch_ptt());
    led_rt(switch_back());
    led_err(!switch_back());
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sm1000_leds_switches_init@plt>
  nop
L7:
  xor    %eax,%eax
  call   <switch_select@plt>
  mov    %eax,%edi
  call   <led_pwr@plt>
  xor    %eax,%eax
  call   <switch_ptt@plt>
  mov    %eax,%edi
  call   <led_ptt@plt>
  xor    %eax,%eax
  call   <switch_back@plt>
  mov    %eax,%edi
  call   <led_rt@plt>
  xor    %eax,%eax
  call   <switch_back@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <led_err@plt>
  jmp    L7
```

assistant: ```c
int main(void) {
  sm1000_leds_switches_init();
  while (1) {
    led_pwr(switch_select());
    led_ptt(switch_ptt());
    led_rt(switch_back());
    led_err(!switch_back());
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sm1000_leds_switches_init@plt>
  nop
L9:
  xor    %eax,%eax
  call   <switch_select@plt>
  mov    %eax,%edi
  call   <led_pwr@plt>
  xor    %eax,%eax
  call   <switch_ptt@plt>
  mov    %eax,%edi
  call   <led_ptt@plt>
  xor    %eax,%eax
  call   <switch_back@plt>
  mov    %eax,%edi
  call   <led_rt@plt>
  xor    %eax,%eax
  call   <switch_back@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <led_err@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  sm1000_leds_switches_init();
  while (1) {
    led_pwr(switch_select());
    led_ptt(switch_ptt());
    led_rt(switch_back());
    led_err(!switch_back());
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1505,-0x8(%rbp)
  jmp    L6
L19:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L19
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash(const char *str) {
  unsigned long result = 5381;
  int c;
  while ((c = *str++))
    result = ((result << 5) + result) + c;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L10
  mov    $0x1505,%eax
L8:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L8
  ret
L10:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned long hash(const char *str) {
  unsigned long result = 5381;
  int c;
  while ((c = *str++))
    result = ((result << 5) + result) + c;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L4
  nopl   (%rax)
L8:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L8
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
unsigned long hash(const char *str) {
  unsigned long result = 5381;
  int c;
  while ((c = *str++))
    result = ((result << 5) + result) + c;
  return result;
}
```