user: 请从给定的汇编指令推导出C源代码:

```asm
<writePgmPictureASCII>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  mov    %r8,%r15
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    %r15,%rdx
  xor    %eax,%eax
  lea    D3(%rip),%rsi
  call   <fprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D16(%rip),%rsi
  lea    D22(%rip),%r12
  call   <fprintf@plt>
  mov    %rbp,%rcx
  mov    $0x41,%edx
  mov    $0x1,%esi
  lea    D48(%rip),%rdi
  call   <fwrite@plt>
  mov    0x70(%rsp),%ecx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  lea    D39(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    0x78(%rsp),%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  test   %r13d,%r13d
  jle    L51
  lea    -0x1(%r13),%eax
  mov    %rbx,%r15
  lea    0x8(%rbx,%rax,8),%rax
  lea    0x10(%rsp),%rbx
  mov    %rax,0x8(%rsp)
  mov    0x70(%rsp),%eax
  sub    $0x1,%eax
  lea    0x4(,%rax,4),%r13
  nopl   0x0(%rax)
L41:
  mov    0x70(%rsp),%eax
  xor    %r14d,%r14d
  test   %eax,%eax
  jle    L46
  nopl   0x0(%rax,%rax,1)
L28:
  mov    (%r15),%rax
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    (%rax,%r14,1),%edx
  add    $0x4,%r14
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
  cmp    %r14,%r13
  jne    L28
L46:
  add    $0x8,%r15
  cmp    0x8(%rsp),%r15
  jne    L41
L51:
  mov    %rbp,%rdi
  call   <fclose@plt>
L17:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D22
type_guessed: string
name: unpack_data
arguments: tag: D48
type_guessed: string
name: unpack_data
arguments: tag: D39
type_guessed: string

tool: D3: %s@n

tool: D16: # This a binary image from %s@n

tool: D22: %d@n

tool: D48: # It is automatic created by Delmas Pierre Binarisation Program@n

tool: D39: %d %d@n

assistant: ```c
void writePgmPictureASCII(char *fileNameBase, char *nameFile, char *mode, int **imageMatrix, char *magicNumber, int idim, int jdim, int dynamic) {
  int row = 0;
  int column = 0;
  char buffer[16] = {0};
  FILE *file;
  file = fopen(nameFile, mode);
  if (file != NULL) {
    fprintf(file, "%s@n", magicNumber);
    fprintf(file, "# This a binary image from %s@n", fileNameBase);
    fprintf(file, "# It is automatic created by Delmas Pierre Binarisation Program@n");
    fprintf(file, "%d %d@n", idim, jdim);
    fprintf(file, "%d@n", dynamic);
    for (row = 0; row < idim; row++) {
      for (column = 0; column < jdim; column++) {
        sprintf(buffer, "%d@n", imageMatrix[row][column]);
        fputs(buffer, file);
      }
    }
    fclose(file);
  }
}
```