ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fig09_07>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x3039,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D24
type: string
name: unpack_data
arguments: data_tag: D17
type: string

tool: D6: The value of ptr is %p


tool: D24: The address of x is %p


tool: D17: Printing a % in a format control string

assistant: ```c
void fig09_07() {
  int *ptr;
  int x = 12345;
  ptr = &x;
  printf("The value of ptr is %p\n", ptr);
  printf("The address of x is %p\n", &x);
  puts("Printing a % in a format control string");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fig09_07>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x3039,0x4(%rsp)
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D11
type: string
name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D2
type: string

tool: D11: The value of ptr is %p


tool: D3: The address of x is %p


tool: D2: Printing a % in a format control string

assistant: ```c
void fig09_07() {
  int *ptr;
  int x = 12345;
  ptr = &x;
  printf("The value of ptr is %p\n", ptr);
  printf("The address of x is %p\n", &x);
  puts("Printing a % in a format control string");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fig09_07>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x3039,0x4(%rsp)
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string
name: extract_symbolic_data
arguments: label: D20
type_infered: string

tool: D4: The value of ptr is %p


tool: D18: The address of x is %p


tool: D20: Printing a % in a format control string

assistant: ```c
void fig09_07() {
  int *ptr;
  int x = 12345;
  ptr = &x;
  printf("The value of ptr is %p\n", ptr);
  printf("The address of x is %p\n", &x);
  puts("Printing a % in a format control string");
}
```
user: What is the c source code of the assembly code below:

```asm
<fac_tailrec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
L24:
  cmpl   $0x1,-0x8(%rbp)
  ja     L23
  mov    -0x4(%rbp),%eax
  jmp    L22
L23:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
  jmp    L24
L22:
  pop    %rbp
  ret
```

assistant: ```c
unsigned fac_tailrec(unsigned acc, unsigned n) {
TOP:
  if (n < 2)
    return acc;
  acc = n * acc;
  n = n - 1;
  goto TOP;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fac_tailrec>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%esi
  jbe    L19
L10:
  imul   %esi,%eax
  sub    $0x1,%esi
  cmp    $0x1,%esi
  jne    L10
L19:
  ret
```

assistant: ```c
unsigned fac_tailrec(unsigned acc, unsigned n) {
TOP:
  if (n < 2)
    return acc;
  acc = n * acc;
  n = n - 1;
  goto TOP;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fac_tailrec>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%esi
  jbe    L16
  nopl   0x0(%rax,%rax,1)
L3:
  imul   %esi,%eax
  sub    $0x1,%esi
  cmp    $0x1,%esi
  jne    L3
L16:
  ret
```

assistant: ```c
unsigned fac_tailrec(unsigned acc, unsigned n) {
TOP:
  if (n < 2)
    return acc;
  acc = n * acc;
  n = n - 1;
  goto TOP;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fac_tailrec>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%esi
  jbe    L5
  nopl   0x0(%rax,%rax,1)
L10:
  imul   %esi,%eax
  sub    $0x1,%esi
  cmp    $0x1,%esi
  jne    L10
L5:
  ret
```

assistant: ```c
unsigned fac_tailrec(unsigned acc, unsigned n) {
TOP:
  if (n < 2)
    return acc;
  acc = n * acc;
  n = n - 1;
  goto TOP;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2a2a2a2a2a2a2a2a,%rax
  movabs $0x2a2a2a2a2a2a2a2a,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x2a2a2a2a2a2a2a2a,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x2a2a2a2a,-0x18(%rbp)
  movw   $0x2a2a,-0x14(%rbp)
  movb   $0x0,-0x12(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L59
L56:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L9
L20:
  movl   $0x1,-0x38(%rbp)
  jmp    L5
L30:
  mov    -0x3c(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  imul   %eax,%edx
  mov    -0x3c(%rbp),%eax
  mov    %edx,%ecx
  imul   %eax,%ecx
  mov    -0x3c(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  imul   %eax,%edx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x3c(%rbp)
L5:
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%eax
  cmp    %eax,%edx
  jle    L30
  addl   $0x1,-0x34(%rbp)
L9:
  mov    -0x40(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L20
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L59:
  lea    -0x40(%rbp),%rdx
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L56
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type: string
name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D33
type: string
name: disassemble_data
arguments: label: D34
type: string
name: disassemble_data
arguments: label: D8
type: string

tool: D2: Enter Lower and Upper limit:

tool: D3: number    square     cube      

tool: D23: |%-10d|%-10d|%-10d


tool: D33: %s

tool: D34: 
Enter Lower and Upper limit:

tool: D8: %d %d

assistant: ```c
int main(void) {
  int upper, lower, i, row;
  char ch[] = "******************************";
  printf("Enter Lower and Upper limit:\n");
  while (scanf("%d %d", &lower, &upper) == 2) {
    printf("number    square     cube      \n");
    for (row = lower; row < upper; row++)
      for (i = 1; i <= 3, lower <= upper; i++, lower++)
        printf("|%-10d|%-10d|%-10d\n", lower, lower * lower, lower * lower * lower);
    printf("%s", ch);
    printf("\nEnter Lower and Upper limit:\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x2a2a2a2a2a2a2a2a,%rax
  movabs $0x2a2a2a2a2a2a2a2a,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x2a2a2a2a2a2a2a2a,%rax
  mov    %rax,0x20(%rsp)
  movl   $0x2a2a2a2a,0x28(%rsp)
  movw   $0x2a2a,0x2c(%rsp)
  movb   $0x0,0x2e(%rsp)
  lea    D6(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%r12
  lea    D9(%rip),%r13
  lea    D22(%rip),%rbx
  jmp    L68
L82:
  mov    %esi,%edx
  imul   %esi,%edx
  mov    %edx,%ecx
  imul   %esi,%ecx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,0xc(%rsp)
  cmp    0x8(%rsp),%esi
  jle    L82
L56:
  add    $0x1,%ebp
  cmp    %ebp,0x8(%rsp)
  jle    L88
L51:
  mov    0xc(%rsp),%esi
  cmp    0x8(%rsp),%esi
  jle    L82
  jmp    L56
L88:
  lea    0x10(%rsp),%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
L68:
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L8
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%ebp
  cmp    0x8(%rsp),%ebp
  jl     L51
  jmp    L88
L8:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D22
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D16
type_infered: string

tool: D6: Enter Lower and Upper limit:

tool: D1: %d %d

tool: D9: number    square     cube      

tool: D22: |%-10d|%-10d|%-10d


tool: D5: %s

tool: D16: 
Enter Lower and Upper limit:

assistant: ```c
int main(void) {
  int upper, lower, i, row;
  char ch[] = "******************************";
  printf("Enter Lower and Upper limit:\n");
  while (scanf("%d %d", &lower, &upper) == 2) {
    printf("number    square     cube      \n");
    for (row = lower; row < upper; row++)
      for (i = 1; i <= 3, lower <= upper; i++, lower++)
        printf("|%-10d|%-10d|%-10d\n", lower, lower * lower, lower * lower * lower);
    printf("%s", ch);
    printf("\nEnter Lower and Upper limit:\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  lea    D30(%rip),%rdi
  lea    D15(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D69(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D47(%rip),%rbx
  sub    $0x48,%rsp
  movdqa D55(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r14
  movl   $0x2a2a2a2a,0x28(%rsp)
  movabs $0x2a2a2a2a2a2a2a2a,%rax
  mov    %rax,0x20(%rsp)
  mov    $0x2a2a,%eax
  lea    0xc(%rsp),%r13
  mov    %ax,0x2c(%rsp)
  movb   $0x0,0x2e(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
L42:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L14
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%eax
  mov    %esi,%ebp
  cmp    %eax,%esi
  jge    L17
  nopl   (%rax)
L37:
  mov    %esi,%edx
  mov    %rbx,%rdi
  xor    %eax,%eax
  imul   %esi,%edx
  mov    %edx,%ecx
  imul   %esi,%ecx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    0x8(%rsp),%eax
  mov    %esi,0xc(%rsp)
  cmp    %eax,%esi
  jle    L37
  add    $0x1,%ebp
  cmp    %eax,%ebp
  jge    L17
L51:
  mov    0xc(%rsp),%esi
  cmp    %eax,%esi
  jle    L37
  add    $0x1,%ebp
  cmp    %eax,%ebp
  jl     L51
  nopl   (%rax)
L17:
  lea    0x10(%rsp),%rsi
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <puts@plt>
  jmp    L42
L14:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D30
datatype: string
name: disassemble_data
arguments: tag: D15
datatype: string
name: disassemble_data
arguments: tag: D69
datatype: string
name: disassemble_data
arguments: tag: D47
datatype: string
name: disassemble_data
arguments: tag: D55
datatype: byte[16]
name: disassemble_data
arguments: tag: D50
datatype: string
name: disassemble_data
arguments: tag: D61
datatype: string

tool: D30: Enter Lower and Upper limit:

tool: D15: number    square     cube      

tool: D69: %d %d

tool: D47: |%-10d|%-10d|%-10d


tool: {"D55": [0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a]}

tool: D50: %s

tool: D61: 
Enter Lower and Upper limit:

assistant: ```c
int main(void) {
  int upper, lower, i, row;
  char ch[] = "******************************";
  printf("Enter Lower and Upper limit:\n");
  while (scanf("%d %d", &lower, &upper) == 2) {
    printf("number    square     cube      \n");
    for (row = lower; row < upper; row++)
      for (i = 1; i <= 3, lower <= upper; i++, lower++)
        printf("|%-10d|%-10d|%-10d\n", lower, lower * lower, lower * lower * lower);
    printf("%s", ch);
    printf("\nEnter Lower and Upper limit:\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  lea    D53(%rip),%rdi
  lea    D46(%rip),%r15
  push   %r14
  lea    D57(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D49(%rip),%rbp
  push   %rbx
  lea    D54(%rip),%rbx
  sub    $0x48,%rsp
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  movl   $0x2a2a2a2a,0x28(%rsp)
  movabs $0x2a2a2a2a2a2a2a2a,%rax
  mov    %rax,0x20(%rsp)
  mov    $0x2a2a,%eax
  lea    0xc(%rsp),%r12
  mov    %ax,0x2c(%rsp)
  movb   $0x0,0x2e(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L31
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%esi
  cmp    0x8(%rsp),%esi
  jge    L13
  nopl   (%rax)
L8:
  mov    %esi,%edx
  mov    %rbx,%rdi
  xor    %eax,%eax
  imul   %esi,%edx
  mov    %edx,%ecx
  imul   %esi,%ecx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,0xc(%rsp)
  cmp    0x8(%rsp),%esi
  jle    L8
L13:
  mov    %r14,%rdi
  lea    0x10(%rsp),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  jmp    L16
L31:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D53
type: string
name: parse_data
arguments: label: D46
type: string
name: parse_data
arguments: label: D57
type: string
name: parse_data
arguments: label: D49
type: string
name: parse_data
arguments: label: D54
type: string
name: parse_data
arguments: label: D13
type: byte[16]
name: parse_data
arguments: label: D20
type: string

tool: D53: Enter Lower and Upper limit:

tool: D46: number    square     cube      

tool: D57: %s

tool: D49: %d %d

tool: D54: |%-10d|%-10d|%-10d


tool: {"D13": [0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a]}

tool: D20: 
Enter Lower and Upper limit:

assistant: ```c
int main(void) {
  int upper, lower, i, row;
  char ch[] = "******************************";
  printf("Enter Lower and Upper limit:\n");
  while (scanf("%d %d", &lower, &upper) == 2) {
    printf("number    square     cube      \n");
    for (row = lower; row < upper; row++)
      for (i = 1; i <= 3, lower <= upper; i++, lower++)
        printf("|%-10d|%-10d|%-10d\n", lower, lower * lower, lower * lower * lower);
    printf("%s", ch);
    printf("\nEnter Lower and Upper limit:\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fclose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <dp_disklock@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose_orig@plt>
  leave
  ret
```

assistant: ```c
int fclose(FILE *stream) {
  dp_disklock();
  return (fclose_orig(stream));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fclose>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <dp_disklock@plt>
  mov    %rbx,%rdi
  call   <fclose_orig@plt>
  pop    %rbx
  ret
```

assistant: ```c
int fclose(FILE *stream) {
  dp_disklock();
  return (fclose_orig(stream));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fclose>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <dp_disklock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose_orig@plt>
```

assistant: ```c
int fclose(FILE *stream) {
  dp_disklock();
  return (fclose_orig(stream));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fclose>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <dp_disklock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose_orig@plt>
```

assistant: ```c
int fclose(FILE *stream) {
  dp_disklock();
  return (fclose_orig(stream));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitmap_pos_to_ord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L14
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L14
  mov    -0x18(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <test_bit@plt>
  test   %eax,%eax
  jne    L1
L14:
  mov    $0xffffffff,%eax
  jmp    L59
L1:
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_next_bit@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L29:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_next_bit@plt>
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
L59:
  leave
  ret
```

assistant: ```c
int bitmap_pos_to_ord(const unsigned long *buf, int pos, int bits) {
  int i, ord;
  if (pos < 0 || pos >= bits || !test_bit(pos, buf))
    return -1;
  i = find_next_bit(buf, bits, 0);
  ord = 0;
  while (i < pos) {
    i = find_next_bit(buf, bits, i + 1);
    ord++;
  }
  assert(i == pos);
  return ord;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bitmap_pos_to_ord>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  js     L10
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %edx,%r12d
  cmp    %edx,%esi
  jge    L10
  mov    %rdi,%rsi
  mov    %ebp,%edi
  call   <test_bit@plt>
  test   %eax,%eax
  je     L61
  mov    $0x0,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <find_next_bit@plt>
  cmp    %eax,%ebp
  jle    L62
  mov    $0x0,%ebx
L12:
  lea    0x1(%rax),%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <find_next_bit@plt>
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jg     L12
L9:
  cmp    %eax,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
L58:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L62:
  mov    $0x0,%ebx
  jmp    L9
L10:
  mov    $0xffffffff,%ebx
  jmp    L58
L61:
  mov    $0xffffffff,%ebx
  jmp    L58
```

assistant: ```c
int bitmap_pos_to_ord(const unsigned long *buf, int pos, int bits) {
  int i, ord;
  if (pos < 0 || pos >= bits || !test_bit(pos, buf))
    return -1;
  i = find_next_bit(buf, bits, 0);
  ord = 0;
  while (i < pos) {
    i = find_next_bit(buf, bits, i + 1);
    ord++;
  }
  assert(i == pos);
  return ord;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_pos_to_ord>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  js     L52
  mov    %esi,%ebx
  mov    %edx,%ebp
  cmp    %edx,%esi
  jge    L52
  mov    %rdi,%r13
  mov    %rdi,%rsi
  mov    %ebx,%edi
  call   <test_bit@plt>
  test   %eax,%eax
  je     L52
  xor    %edx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %r12d,%r12d
  call   <find_next_bit@plt>
  cmp    %eax,%ebx
  jle    L31
  xchg   %ax,%ax
L7:
  lea    0x1(%rax),%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <find_next_bit@plt>
  cmp    %eax,%ebx
  jg     L7
L31:
  xor    %edi,%edi
  cmp    %eax,%ebx
  sete   %dil
  call   <assert@plt>
L38:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  mov    $0xffffffff,%r12d
  jmp    L38
```

assistant: ```c
int bitmap_pos_to_ord(const unsigned long *buf, int pos, int bits) {
  int i, ord;
  if (pos < 0 || pos >= bits || !test_bit(pos, buf))
    return -1;
  i = find_next_bit(buf, bits, 0);
  ord = 0;
  while (i < pos) {
    i = find_next_bit(buf, bits, i + 1);
    ord++;
  }
  assert(i == pos);
  return ord;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bitmap_pos_to_ord>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  js     L36
  mov    %esi,%ebx
  mov    %edx,%ebp
  cmp    %edx,%esi
  jge    L36
  mov    %rdi,%r13
  mov    %rdi,%rsi
  mov    %ebx,%edi
  call   <test_bit@plt>
  test   %eax,%eax
  je     L36
  xor    %edx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %r12d,%r12d
  call   <find_next_bit@plt>
  cmp    %eax,%ebx
  jle    L33
  xchg   %ax,%ax
L45:
  lea    0x1(%rax),%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <find_next_bit@plt>
  cmp    %eax,%ebx
  jg     L45
L33:
  xor    %edi,%edi
  cmp    %eax,%ebx
  sete   %dil
  call   <assert@plt>
L14:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  mov    $0xffffffff,%r12d
  jmp    L14
```

assistant: ```c
int bitmap_pos_to_ord(const unsigned long *buf, int pos, int bits) {
  int i, ord;
  if (pos < 0 || pos >= bits || !test_bit(pos, buf))
    return -1;
  i = find_next_bit(buf, bits, 0);
  ord = 0;
  while (i < pos) {
    i = find_next_bit(buf, bits, i + 1);
    ord++;
  }
  assert(i == pos);
  return ord;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroyVariableHashEntry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void destroyVariableHashEntry(void *arg, char *key, char *value) {
  do {
    (void)(arg);
  } while (0);
  free(key);
  free(value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroyVariableHashEntry>:
  endbr64
  push   %rbx
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void destroyVariableHashEntry(void *arg, char *key, char *value) {
  do {
    (void)(arg);
  } while (0);
  free(key);
  free(value);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<destroyVariableHashEntry>:
  endbr64
  push   %rbp
  mov    %rsi,%rdi
  mov    %rdx,%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void destroyVariableHashEntry(void *arg, char *key, char *value) {
  do {
    (void)(arg);
  } while (0);
  free(key);
  free(value);
}
```