ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<sg_scsi_sense_desc_find>:
  endbr64
  cmp    $0x7,%esi
  jle    L83
  movzbl 0x7(%rdi),%r8d
  test   %r8d,%r8d
  je     L61
  movzbl (%rdi),%eax
  sub    $0x72,%eax
  mov    $0x0,%ecx
  cmp    $0x1,%al
  ja     L84
  sub    $0x8,%esi
  cmp    %r8d,%esi
  cmovle %esi,%r8d
  lea    0x8(%rdi),%rcx
  test   %r8d,%r8d
  jle    L106
  mov    $0x0,%esi
  mov    $0x0,%eax
  lea    -0x1(%r8),%edi
  jmp    L65
L9:
  movzbl (%rcx),%eax
  cmp    %edx,%eax
  mov    $0x0,%eax
  cmovne %rax,%rcx
L84:
  mov    %rcx,%rax
  ret
L17:
  add    %eax,%esi
  cmp    %esi,%r8d
  jle    L16
L65:
  cltq
  add    %rax,%rcx
  cmp    %esi,%edi
  jle    L9
  movzbl 0x1(%rcx),%eax
  add    $0x2,%eax
  movzbl (%rcx),%r9d
  cmp    %r9d,%edx
  jne    L17
  jmp    L84
L16:
  mov    $0x0,%ecx
  jmp    L84
L83:
  mov    $0x0,%ecx
  jmp    L84
L61:
  mov    $0x0,%ecx
  jmp    L84
L106:
  mov    $0x0,%ecx
  jmp    L84
```

assistant: ```c
const unsigned char *sg_scsi_sense_desc_find(const unsigned char *sensep, int sense_len, int desc_type) {
  int add_sb_len, add_d_len, desc_len, k;
  const unsigned char *descp;
  if ((sense_len < 8) || (0 == (add_sb_len = sensep[7])))
    return NULL;
  if ((sensep[0] < 0x72) || (sensep[0] > 0x73))
    return NULL;
  add_sb_len = (add_sb_len < (sense_len - 8)) ? add_sb_len : (sense_len - 8);
  descp = &sensep[8];
  for (desc_len = 0, k = 0; k < add_sb_len; k += desc_len) {
    descp += desc_len;
    add_d_len = (k < (add_sb_len - 1)) ? descp[1] : -1;
    desc_len = add_d_len + 2;
    if (descp[0] == desc_type)
      return descp;
    if (add_d_len < 0)
      break;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sg_scsi_sense_desc_find>:
  endbr64
  cmp    $0x7,%esi
  jle    L57
  movzbl 0x7(%rdi),%ecx
  test   %ecx,%ecx
  je     L57
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x72,%eax
  cmp    $0x1,%al
  ja     L71
  sub    $0x8,%esi
  lea    0x8(%rdi),%r8
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  test   %esi,%esi
  je     L57
  mov    %esi,%edi
  sub    $0x1,%edi
  je     L65
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl 0x1(%r8),%eax
  movzbl (%r8),%r9d
  add    $0x2,%eax
  cmp    %edx,%r9d
  je     L71
  add    %eax,%ecx
  cmp    %ecx,%esi
  jle    L57
  cltq
  add    %rax,%r8
  cmp    %edi,%ecx
  jl     L38
L65:
  movzbl (%r8),%eax
  cmp    %eax,%edx
  mov    $0x0,%eax
  cmovne %rax,%r8
L71:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
const unsigned char *sg_scsi_sense_desc_find(const unsigned char *sensep, int sense_len, int desc_type) {
  int add_sb_len, add_d_len, desc_len, k;
  const unsigned char *descp;
  if ((sense_len < 8) || (0 == (add_sb_len = sensep[7])))
    return NULL;
  if ((sensep[0] < 0x72) || (sensep[0] > 0x73))
    return NULL;
  add_sb_len = (add_sb_len < (sense_len - 8)) ? add_sb_len : (sense_len - 8);
  descp = &sensep[8];
  for (desc_len = 0, k = 0; k < add_sb_len; k += desc_len) {
    descp += desc_len;
    add_d_len = (k < (add_sb_len - 1)) ? descp[1] : -1;
    desc_len = add_d_len + 2;
    if (descp[0] == desc_type)
      return descp;
    if (add_d_len < 0)
      break;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sg_scsi_sense_desc_find>:
  endbr64
  cmp    $0x7,%esi
  jle    L60
  movzbl 0x7(%rdi),%ecx
  test   %ecx,%ecx
  je     L60
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x72,%eax
  cmp    $0x1,%al
  ja     L16
  sub    $0x8,%esi
  lea    0x8(%rdi),%r8
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  test   %esi,%esi
  je     L60
  mov    %esi,%edi
  sub    $0x1,%edi
  je     L57
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L40:
  movzbl 0x1(%r8),%eax
  movzbl (%r8),%r9d
  add    $0x2,%eax
  cmp    %edx,%r9d
  je     L16
  add    %eax,%ecx
  cmp    %ecx,%esi
  jle    L60
  cltq
  add    %rax,%r8
  cmp    %edi,%ecx
  jl     L40
L57:
  movzbl (%r8),%eax
  cmp    %eax,%edx
  mov    $0x0,%eax
  cmovne %rax,%r8
L16:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
const unsigned char *sg_scsi_sense_desc_find(const unsigned char *sensep, int sense_len, int desc_type) {
  int add_sb_len, add_d_len, desc_len, k;
  const unsigned char *descp;
  if ((sense_len < 8) || (0 == (add_sb_len = sensep[7])))
    return NULL;
  if ((sensep[0] < 0x72) || (sensep[0] > 0x73))
    return NULL;
  add_sb_len = (add_sb_len < (sense_len - 8)) ? add_sb_len : (sense_len - 8);
  descp = &sensep[8];
  for (desc_len = 0, k = 0; k < add_sb_len; k += desc_len) {
    descp += desc_len;
    add_d_len = (k < (add_sb_len - 1)) ? descp[1] : -1;
    desc_len = add_d_len + 2;
    if (descp[0] == desc_type)
      return descp;
    if (add_d_len < 0)
      break;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <newNode@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <numComponents@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  mov    $0x0,%esi
  mov    $0x3,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <newNode@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x2c(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <numComponents@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  struct ListNode *l1;
  int G[] = {0, 3, 1, 4};
  l1 = newNode(0, newNode(1, newNode(2, newNode(3, newNode(4, NULL)))));
  printf("%d\n", numComponents(l1, G, 4));
  int G1[] = {0, 3, 1};
  l1 = newNode(0, newNode(1, newNode(2, newNode(3, NULL))));
  printf("%d\n", numComponents(l1, G1, 4));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x4,0x1c(%rsp)
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <newNode@plt>
  mov    %rax,%rdi
  lea    0x10(%rsp),%rsi
  mov    $0x4,%edx
  call   <numComponents@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movl   $0x0,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  mov    $0x0,%esi
  mov    $0x3,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <newNode@plt>
  mov    %rax,%rdi
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  call   <numComponents@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main() {
  struct ListNode *l1;
  int G[] = {0, 3, 1, 4};
  l1 = newNode(0, newNode(1, newNode(2, newNode(3, newNode(4, NULL)))));
  printf("%d\n", numComponents(l1, G, 4));
  int G1[] = {0, 3, 1};
  l1 = newNode(0, newNode(1, newNode(2, newNode(3, NULL))));
  printf("%d\n", numComponents(l1, G1, 4));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x4,%edi
  lea    D1(%rip),%rbp
  push   %rbx
  movabs $0x300000000,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rbx,0x10(%rsp)
  movabs $0x400000001,%rax
  mov    %rax,0x18(%rsp)
  call   <newNode@plt>
  mov    $0x3,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0x2,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0x1,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  xor    %edi,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0x4,%edx
  lea    0x10(%rsp),%rsi
  mov    %rax,%rdi
  call   <numComponents@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x3,%edi
  mov    %rbx,0x4(%rsp)
  movl   $0x1,0xc(%rsp)
  call   <newNode@plt>
  mov    $0x2,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0x1,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  xor    %edi,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <numComponents@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: %d


assistant: ```c
int main() {
  struct ListNode *l1;
  int G[] = {0, 3, 1, 4};
  l1 = newNode(0, newNode(1, newNode(2, newNode(3, newNode(4, NULL)))));
  printf("%d\n", numComponents(l1, G, 4));
  int G1[] = {0, 3, 1};
  l1 = newNode(0, newNode(1, newNode(2, newNode(3, NULL))));
  printf("%d\n", numComponents(l1, G1, 4));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x4,%edi
  lea    D8(%rip),%rbp
  sub    $0x30,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <newNode@plt>
  mov    $0x3,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0x2,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0x1,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  xor    %edi,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0x4,%edx
  lea    0x10(%rsp),%rsi
  mov    %rax,%rdi
  call   <numComponents@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    D26(%rip),%rax
  xor    %esi,%esi
  mov    $0x3,%edi
  movl   $0x1,0x8(%rsp)
  mov    %rax,(%rsp)
  call   <newNode@plt>
  mov    $0x2,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0x1,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  xor    %edi,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    %rsp,%rsi
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <numComponents@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: byte[16]

tool: D8: %d


tool: {"D26": [0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int main() {
  struct ListNode *l1;
  int G[] = {0, 3, 1, 4};
  l1 = newNode(0, newNode(1, newNode(2, newNode(3, newNode(4, NULL)))));
  printf("%d\n", numComponents(l1, G, 4));
  int G1[] = {0, 3, 1};
  l1 = newNode(0, newNode(1, newNode(2, newNode(3, NULL))));
  printf("%d\n", numComponents(l1, G1, 4));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fprint_uint16_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L44
L38:
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L30
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L50
L30:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
L50:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  addl   $0x1,-0x4(%rbp)
L44:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L38
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L56
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L57
L56:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
L57:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string
name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D1: 
%s

tool: D9: 0x%04x,

tool: D13: 0x%04x

assistant: ```c
void fprint_uint16_table(FILE *outfile, uint16_t *table, uint64_t length, char *header, char *footer, char *begin_line) {
  int i;
  fprintf(outfile, "%s", header);
  for (i = 0; i < length - 1; i++) {
    if ((i & 7) == 0)
      fprintf(outfile, "\n%s", begin_line);
    else
      fprintf(outfile, " ");
    fprintf(outfile, "0x%04x,", table[i]);
  }
  if ((i & 7) == 0)
    fprintf(outfile, "\n%s", begin_line);
  else
    fprintf(outfile, " ");
  fprintf(outfile, "0x%04x", table[i]);
  fprintf(outfile, "%s", footer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fprint_uint16_table>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %edx,0xc(%rsp)
  mov    %rcx,%rdi
  mov    %r8,(%rsp)
  mov    %r9,%r15
  mov    %rbp,%rsi
  call   <fputs@plt>
  cmp    $0x1,%ebx
  jle    L16
  lea    -0x2(%rbx),%r14d
  mov    $0x0,%ebx
  lea    D26(%rip),%r13
  jmp    L23
L39:
  mov    %rbp,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
L10:
  mov    (%r12,%rbx,4),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  lea    0x1(%rbx),%rax
  cmp    %r14,%rbx
  je     L32
  mov    %rax,%rbx
L23:
  test   $0x7,%bl
  jne    L39
  mov    %r15,%rdx
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L10
L32:
  mov    0xc(%rsp),%ebx
  sub    $0x1,%ebx
  test   $0x7,%bl
  je     L27
  mov    %rbp,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
  jmp    L30
L16:
  mov    $0x0,%ebx
L27:
  mov    %r15,%rdx
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L30:
  movslq %ebx,%rbx
  mov    (%r12,%rbx,4),%edx
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   <fputs@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D26
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string

tool: D26: 0x%04x,

tool: D25: 
%s

tool: D27: 0x%04x

assistant: ```c
void fprint_uint16_table(FILE *outfile, uint16_t *table, uint64_t length, char *header, char *footer, char *begin_line) {
  int i;
  fprintf(outfile, "%s", header);
  for (i = 0; i < length - 1; i++) {
    if ((i & 7) == 0)
      fprintf(outfile, "\n%s", begin_line);
    else
      fprintf(outfile, " ");
    fprintf(outfile, "0x%04x,", table[i]);
  }
  if ((i & 7) == 0)
    fprintf(outfile, "\n%s", begin_line);
  else
    fprintf(outfile, " ");
  fprintf(outfile, "0x%04x", table[i]);
  fprintf(outfile, "%s", footer);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fprint_uint16_table>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %rcx,%rdi
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %r15,%rsi
  sub    $0x28,%rsp
  mov    %r8,0x10(%rsp)
  call   <fputs@plt>
  lea    -0x1(%rbp),%eax
  mov    %eax,0x1c(%rsp)
  test   %eax,%eax
  jle    L61
  lea    -0x2(%rbp),%eax
  xor    %r12d,%r12d
  lea    D29(%rip),%rbp
  mov    %rax,0x8(%rsp)
  lea    D0(%rip),%r14
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L25:
  mov    (%rbx,%r12,4),%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  lea    0x1(%r12),%rax
  cmp    %r12,0x8(%rsp)
  je     L19
  mov    %rax,%r12
L59:
  test   $0x7,%r12b
  je     L65
  mov    %r15,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
  jmp    L25
  nopl   (%rax)
L19:
  movslq 0x1c(%rsp),%rax
  mov    %rax,%rcx
  lea    (%rbx,%rax,4),%rbx
  and    $0x7,%ecx
  je     L61
  mov    %r15,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
L15:
  mov    (%rbx),%edx
  mov    %r15,%rdi
  lea    D9(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    0x10(%rsp),%rdi
  add    $0x28,%rsp
  mov    %r15,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <fputs@plt>
  nopl   0x0(%rax)
L61:
  mov    %r13,%rdx
  lea    D0(%rip),%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_label: D29
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D29: 0x%04x,

tool: D0: 
%s

tool: D9: 0x%04x

assistant: ```c
void fprint_uint16_table(FILE *outfile, uint16_t *table, uint64_t length, char *header, char *footer, char *begin_line) {
  int i;
  fprintf(outfile, "%s", header);
  for (i = 0; i < length - 1; i++) {
    if ((i & 7) == 0)
      fprintf(outfile, "\n%s", begin_line);
    else
      fprintf(outfile, " ");
    fprintf(outfile, "0x%04x,", table[i]);
  }
  if ((i & 7) == 0)
    fprintf(outfile, "\n%s", begin_line);
  else
    fprintf(outfile, " ");
  fprintf(outfile, "0x%04x", table[i]);
  fprintf(outfile, "%s", footer);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fprint_uint16_table>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %rcx,%rdi
  push   %r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %r15,%rsi
  sub    $0x28,%rsp
  mov    %r8,0x10(%rsp)
  call   <fputs@plt>
  lea    -0x1(%rbp),%eax
  mov    %eax,0x1c(%rsp)
  test   %eax,%eax
  jle    L9
  lea    -0x2(%rbp),%eax
  xor    %r12d,%r12d
  lea    D37(%rip),%rbp
  mov    %rax,0x8(%rsp)
  lea    D28(%rip),%r14
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L39:
  mov    (%rbx,%r12,4),%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  lea    0x1(%r12),%rax
  cmp    %r12,0x8(%rsp)
  je     L50
  mov    %rax,%r12
L46:
  test   $0x7,%r12b
  je     L66
  mov    %r15,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
  jmp    L39
  nopl   (%rax)
L50:
  movslq 0x1c(%rsp),%rax
  mov    %rax,%rcx
  lea    (%rbx,%rax,4),%rbx
  and    $0x7,%ecx
  je     L9
  mov    %r15,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
L11:
  mov    (%rbx),%edx
  mov    %r15,%rdi
  lea    D21(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    0x10(%rsp),%rdi
  add    $0x28,%rsp
  mov    %r15,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <fputs@plt>
  nopl   0x0(%rax)
L9:
  mov    %r13,%rdx
  lea    D28(%rip),%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_tag: D37
type: string
name: disassemble_data
arguments: data_tag: D28
type: string
name: disassemble_data
arguments: data_tag: D21
type: string

tool: D37: 0x%04x,

tool: D28: 
%s

tool: D21: 0x%04x

assistant: ```c
void fprint_uint16_table(FILE *outfile, uint16_t *table, uint64_t length, char *header, char *footer, char *begin_line) {
  int i;
  fprintf(outfile, "%s", header);
  for (i = 0; i < length - 1; i++) {
    if ((i & 7) == 0)
      fprintf(outfile, "\n%s", begin_line);
    else
      fprintf(outfile, " ");
    fprintf(outfile, "0x%04x,", table[i]);
  }
  if ((i & 7) == 0)
    fprintf(outfile, "\n%s", begin_line);
  else
    fprintf(outfile, " ");
  fprintf(outfile, "0x%04x", table[i]);
  fprintf(outfile, "%s", footer);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ne_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L5
L7:
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
L5:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ne_token(char **str, char separator) {
  char *ret = *str, *pnt = strchr(*str, separator);
  if (pnt) {
    *pnt = '\0';
    *str = pnt + 1;
  } else {
    *str = NULL;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ne_token>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%rbp
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  movb   $0x0,(%rax)
  add    $0x1,%rax
L1:
  mov    %rax,(%rbx)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *ne_token(char **str, char separator) {
  char *ret = *str, *pnt = strchr(*str, separator);
  if (pnt) {
    *pnt = '\0';
    *str = pnt + 1;
  } else {
    *str = NULL;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ne_token>:
  endbr64
  push   %r12
  movsbl %sil,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r12
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax)
  add    $0x1,%rax
L8:
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *ne_token(char **str, char separator) {
  char *ret = *str, *pnt = strchr(*str, separator);
  if (pnt) {
    *pnt = '\0';
    *str = pnt + 1;
  } else {
    *str = NULL;
  }
  return ret;
}
```