ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L143
L43:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  addl   $0x1,-0x4(%rbp)
L143:
  cmpl   $0x9,-0x4(%rbp)
  jle    L43
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L161
L68:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  addl   $0x4,-0x4(%rbp)
L161:
  cmpl   $0xa,-0x4(%rbp)
  jle    L68
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L41
L156:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  subl   $0x1,-0x4(%rbp)
L41:
  cmpl   $0x0,-0x4(%rbp)
  jg     L156
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L87:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  subl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L87
  movl   $0x0,-0x4(%rbp)
  jmp    L154
L48:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  addl   $0x1,-0x4(%rbp)
L154:
  cmpl   $0x9,-0x4(%rbp)
  jle    L48
  movl   $0x0,-0x4(%rbp)
L28:
  cmpl   $0x9,-0x4(%rbp)
  jg     L79
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  subl   $0x1,-0x4(%rbp)
  jmp    L28
L79:
  nop
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L71:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  subl   $0x3,-0x4(%rbp)
L4:
  cmpl   $0x9,-0x4(%rbp)
  jg     L109
  cmpl   $0x4,-0x14(%rbp)
  jg     L71
L109:
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L47:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  subl   $0x3,-0x4(%rbp)
  addl   $0x2,-0x14(%rbp)
L23:
  cmpl   $0x9,-0x4(%rbp)
  jle    L47
  nop
  nop
  leave
  ret
```

assistant: ```c
void foo(int j, int k) {
  int i;
#pragma omp for
  for (i = 0; i < 10; i++)
    baz(i);
#pragma omp for
  for (i = j; i <= 10; i += 4)
    baz(i);
#pragma omp for
  for (i = j; i > 0; i = i - 1)
    baz(j);
#pragma omp for
  for (i = j; i >= k; i--)
    baz(i);
#pragma omp for
  i = 0;
  for (; i < 10;) {
    baz(i);
    i++;
  }
#pragma omp for
  for (i = 0;; i--) {
    if (i >= 10)
      break;
    baz(i);
  }
#pragma omp for
  for (i = 0; i < 10 && j > 4; i -= 3)
    baz(i);
#pragma omp for
  for (i = 0; i < 10; i -= 3, j += 2)
    baz(i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    $0x0,%ebp
L42:
  mov    %ebp,%edi
  call   <baz@plt>
  add    $0x1,%ebp
  cmp    $0xa,%ebp
  jne    L42
  cmp    $0xa,%ebx
  jg     L58
  mov    %ebx,%ebp
L29:
  mov    %ebp,%edi
  call   <baz@plt>
  add    $0x4,%ebp
  cmp    $0xa,%ebp
  jle    L29
L58:
  test   %ebx,%ebx
  jle    L10
  mov    %ebx,%ebp
L22:
  mov    %ebx,%edi
  call   <baz@plt>
  sub    $0x1,%ebp
  jne    L22
L10:
  cmp    %r12d,%ebx
  jl     L39
L66:
  mov    %ebx,%edi
  call   <baz@plt>
  sub    $0x1,%ebx
  cmp    %ebx,%r12d
  jle    L66
L39:
  mov    $0x0,%ebx
L26:
  mov    %ebx,%edi
  call   <baz@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L26
  mov    $0x0,%ebx
L80:
  mov    %ebx,%edi
  call   <baz@plt>
  sub    $0x1,%ebx
  jmp    L80
```

assistant: ```c
void foo(int j, int k) {
  int i;
#pragma omp for
  for (i = 0; i < 10; i++)
    baz(i);
#pragma omp for
  for (i = j; i <= 10; i += 4)
    baz(i);
#pragma omp for
  for (i = j; i > 0; i = i - 1)
    baz(j);
#pragma omp for
  for (i = j; i >= k; i--)
    baz(i);
#pragma omp for
  i = 0;
  for (; i < 10;) {
    baz(i);
    i++;
  }
#pragma omp for
  for (i = 0;; i--) {
    if (i >= 10)
      break;
    baz(i);
  }
#pragma omp for
  for (i = 0; i < 10 && j > 4; i -= 3)
    baz(i);
#pragma omp for
  for (i = 0; i < 10; i -= 3, j += 2)
    baz(i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %edi,%ebx
  nop
L73:
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <baz@plt>
  cmp    $0xa,%ebp
  jne    L73
  cmp    $0xa,%ebx
  jg     L39
  mov    %ebx,%ebp
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %ebp,%edi
  add    $0x4,%ebp
  call   <baz@plt>
  cmp    $0xa,%ebp
  jle    L27
  test   %ebx,%ebx
  jle    L31
L39:
  mov    %ebx,%ebp
  nopl   (%rax)
L1:
  mov    %ebx,%edi
  call   <baz@plt>
  sub    $0x1,%ebp
  jne    L1
L31:
  cmp    %r12d,%ebx
  jl     L77
  nopl   0x0(%rax)
L79:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <baz@plt>
  cmp    %ebx,%r12d
  jle    L79
L77:
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L82:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <baz@plt>
  cmp    $0xa,%ebx
  jne    L82
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L16:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <baz@plt>
  jmp    L16
```

assistant: ```c
void foo(int j, int k) {
  int i;
#pragma omp for
  for (i = 0; i < 10; i++)
    baz(i);
#pragma omp for
  for (i = j; i <= 10; i += 4)
    baz(i);
#pragma omp for
  for (i = j; i > 0; i = i - 1)
    baz(j);
#pragma omp for
  for (i = j; i >= k; i--)
    baz(i);
#pragma omp for
  i = 0;
  for (; i < 10;) {
    baz(i);
    i++;
  }
#pragma omp for
  for (i = 0;; i--) {
    if (i >= 10)
      break;
    baz(i);
  }
#pragma omp for
  for (i = 0; i < 10 && j > 4; i -= 3)
    baz(i);
#pragma omp for
  for (i = 0; i < 10; i -= 3, j += 2)
    baz(i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %edi,%ebx
  nop
L63:
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <baz@plt>
  cmp    $0xa,%ebp
  jne    L63
  cmp    $0xa,%ebx
  jg     L46
  mov    %ebx,%ebp
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    %ebp,%edi
  add    $0x4,%ebp
  call   <baz@plt>
  cmp    $0xa,%ebp
  jle    L12
  test   %ebx,%ebx
  jle    L13
L46:
  mov    %ebx,%ebp
  nopl   (%rax)
L58:
  mov    %ebx,%edi
  call   <baz@plt>
  sub    $0x1,%ebp
  jne    L58
L13:
  cmp    %r12d,%ebx
  jl     L20
  nopl   0x0(%rax)
L30:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <baz@plt>
  cmp    %ebx,%r12d
  jle    L30
L20:
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L72:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <baz@plt>
  cmp    $0xa,%ebx
  jne    L72
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L89:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <baz@plt>
  jmp    L89
```

assistant: ```c
void foo(int j, int k) {
  int i;
#pragma omp for
  for (i = 0; i < 10; i++)
    baz(i);
#pragma omp for
  for (i = j; i <= 10; i += 4)
    baz(i);
#pragma omp for
  for (i = j; i > 0; i = i - 1)
    baz(j);
#pragma omp for
  for (i = j; i >= k; i--)
    baz(i);
#pragma omp for
  i = 0;
  for (; i < 10;) {
    baz(i);
    i++;
  }
#pragma omp for
  for (i = 0;; i--) {
    if (i >= 10)
      break;
    baz(i);
  }
#pragma omp for
  for (i = 0; i < 10 && j > 4; i -= 3)
    baz(i);
#pragma omp for
  for (i = 0; i < 10; i -= 3, j += 2)
    baz(i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_to_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x20,%eax
  jne    L103
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L48
  mov    $0x1,%eax
  jmp    L71
L48:
  mov    $0x0,%eax
  jmp    L71
L103:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x40,%eax
  jne    L61
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L117
  mov    -0x8(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L117
  mov    $0x2,%eax
  jmp    L71
L117:
  mov    $0x0,%eax
  jmp    L71
L61:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x41,%eax
  jne    L76
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L116
  mov    -0x8(%rbp),%rax
  lea    0x21(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L116
  mov    $0x2,%eax
  jmp    L71
L116:
  mov    $0x0,%eax
  jmp    L71
L76:
  mov    $0x0,%eax
L71:
  leave
  ret
```

assistant: ```c
int string_to_hash(const char *string, uint8_t first[16], uint8_t second[16]) {
  memset(first, 0, 16);
  memset(second, 0, 16);
  if (strlen(string) == 32) {
    if (single_string_to_hash(string, first))
      return 1;
    return 0;
  }
  if (strlen(string) == 64) {
    if (single_string_to_hash(string, first) && single_string_to_hash(string + 32, second))
      return 2;
    return 0;
  }
  if (strlen(string) == 65) {
    if (single_string_to_hash(string, first) && single_string_to_hash(string + 33, second))
      return 2;
    return 0;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_to_hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x20,%eax
  je     L10
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x40,%eax
  je     L41
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x41,%edx
  je     L77
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L2
L41:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <single_string_to_hash@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L2
  lea    0x20(%rbx),%rdi
  mov    %r12,%rsi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  jmp    L2
L77:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <single_string_to_hash@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L2
  lea    0x21(%rbx),%rdi
  mov    %r12,%rsi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  jmp    L2
```

assistant: ```c
int string_to_hash(const char *string, uint8_t first[16], uint8_t second[16]) {
  memset(first, 0, 16);
  memset(second, 0, 16);
  if (strlen(string) == 32) {
    if (single_string_to_hash(string, first))
      return 1;
    return 0;
  }
  if (strlen(string) == 64) {
    if (single_string_to_hash(string, first) && single_string_to_hash(string + 32, second))
      return 2;
    return 0;
  }
  if (strlen(string) == 65) {
    if (single_string_to_hash(string, first) && single_string_to_hash(string + 33, second))
      return 2;
    return 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_to_hash>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    $0x10,%edx
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  call   <memset@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    $0x10,%edx
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x20,%eax
  je     L19
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x40,%eax
  je     L8
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x41,%eax
  je     L15
L12:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nop
L8:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L12
  lea    0x20(%rbp),%rdi
L10:
  mov    %r13,%rsi
  call   <single_string_to_hash@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
  nopl   (%rax)
L19:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <single_string_to_hash@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  setne  %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L12
  lea    0x21(%rbp),%rdi
  jmp    L10
```

assistant: ```c
int string_to_hash(const char *string, uint8_t first[16], uint8_t second[16]) {
  memset(first, 0, 16);
  memset(second, 0, 16);
  if (strlen(string) == 32) {
    if (single_string_to_hash(string, first))
      return 1;
    return 0;
  }
  if (strlen(string) == 64) {
    if (single_string_to_hash(string, first) && single_string_to_hash(string + 32, second))
      return 2;
    return 0;
  }
  if (strlen(string) == 65) {
    if (single_string_to_hash(string, first) && single_string_to_hash(string + 33, second))
      return 2;
    return 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<string_to_hash>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    $0x10,%edx
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  call   <memset@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    $0x10,%edx
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x20,%eax
  je     L44
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x40,%eax
  je     L31
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x41,%eax
  je     L27
L23:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nop
L31:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L23
  lea    0x20(%rbp),%rdi
L39:
  mov    %r13,%rsi
  call   <single_string_to_hash@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
  nopl   (%rax)
L44:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <single_string_to_hash@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  setne  %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <single_string_to_hash@plt>
  test   %rax,%rax
  je     L23
  lea    0x21(%rbp),%rdi
  jmp    L39
```

assistant: ```c
int string_to_hash(const char *string, uint8_t first[16], uint8_t second[16]) {
  memset(first, 0, 16);
  memset(second, 0, 16);
  if (strlen(string) == 32) {
    if (single_string_to_hash(string, first))
      return 1;
    return 0;
  }
  if (strlen(string) == 64) {
    if (single_string_to_hash(string, first) && single_string_to_hash(string + 32, second))
      return 2;
    return 0;
  }
  if (strlen(string) == 65) {
    if (single_string_to_hash(string, first) && single_string_to_hash(string + 33, second))
      return 2;
    return 0;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x94(%rbp)
  movl   $0x0,-0x9c(%rbp)
  jmp    L108
L73:
  movl   $0x0,-0x98(%rbp)
  jmp    L109
L1:
  lea    -0x90(%rbp),%rdx
  mov    -0x98(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x9c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x98(%rbp)
L109:
  mov    -0x98(%rbp),%eax
  cmp    -0x94(%rbp),%eax
  jl     L1
  addl   $0x1,-0x9c(%rbp)
L108:
  mov    -0x9c(%rbp),%eax
  cmp    -0x94(%rbp),%eax
  jl     L73
  movl   $0x0,-0x9c(%rbp)
  jmp    L122
L11:
  movl   $0x0,-0x98(%rbp)
  jmp    L100
L116:
  mov    -0x9c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x98(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x9c(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    %eax,-0x50(%rbp,%rdx,4)
  addl   $0x1,-0x98(%rbp)
L100:
  mov    -0x98(%rbp),%eax
  cmp    -0x94(%rbp),%eax
  jl     L116
  addl   $0x1,-0x9c(%rbp)
L122:
  mov    -0x9c(%rbp),%eax
  cmp    -0x94(%rbp),%eax
  jl     L11
  movl   $0x0,-0x9c(%rbp)
  jmp    L76
L57:
  movl   $0x0,-0x98(%rbp)
  jmp    L119
L30:
  mov    -0x98(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x9c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x98(%rbp)
L119:
  mov    -0x98(%rbp),%eax
  cmp    -0x94(%rbp),%eax
  jl     L30
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x9c(%rbp)
L76:
  mov    -0x9c(%rbp),%eax
  cmp    -0x94(%rbp),%eax
  jl     L57
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L111
  call   <__stack_chk_fail@plt>
L111:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D12
datatype: string

tool: D14: %d

tool: D12: %d 

assistant: ```c
int main() {
  int matrix1[4][4];
  int matrix2[4][4];
  int m = 4, i, a;
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      scanf("%d", &matrix1[i][a]);
    }
  }
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      matrix2[i][a] = matrix1[a][i];
    }
  }
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      printf("%d ", matrix2[i][a]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x10(%rsp),%rbp
  mov    $0x0,%r14d
  lea    D12(%rip),%r13
L28:
  lea    -0x10(%rbp),%rbx
L39:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L39
  add    $0x4,%r14
  add    $0x10,%rbp
  cmp    $0x10,%r14
  jne    L28
  lea    0x40(%rsp),%r13
  lea    0x80(%rsp),%rcx
  mov    %r13,%rax
L33:
  mov    (%r12),%edx
  mov    %edx,(%rax)
  mov    0x10(%r12),%edx
  mov    %edx,0x4(%rax)
  mov    0x20(%r12),%edx
  mov    %edx,0x8(%rax)
  mov    0x30(%r12),%edx
  mov    %edx,0xc(%rax)
  add    $0x4,%r12
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L33
  lea    0x10(%r13),%rbp
  add    $0x50,%r13
  lea    D14(%rip),%r12
L10:
  lea    -0x10(%rbp),%rbx
L2:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x10,%rbp
  cmp    %rbp,%r13
  jne    L10
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D14
type: string

tool: D12: %d

tool: D14: %d 

assistant: ```c
int main() {
  int matrix1[4][4];
  int matrix2[4][4];
  int m = 4, i, a;
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      scanf("%d", &matrix1[i][a]);
    }
  }
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      matrix2[i][a] = matrix1[a][i];
    }
  }
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      printf("%d ", matrix2[i][a]);
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%r12
L30:
  lea    -0x10(%r12),%rbx
L24:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L24
  add    $0x4,%r14
  lea    0x10(%rbx),%r12
  cmp    $0x10,%r14
  jne    L30
  lea    0x40(%rsp),%r13
  lea    0x80(%rsp),%rcx
  mov    %r13,%rax
L21:
  mov    0x0(%rbp),%edx
  add    $0x10,%rax
  add    $0x4,%rbp
  mov    %edx,-0x10(%rax)
  mov    0xc(%rbp),%edx
  mov    %edx,-0xc(%rax)
  mov    0x1c(%rbp),%edx
  mov    %edx,-0x8(%rax)
  mov    0x2c(%rbp),%edx
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L21
  lea    0x10(%r13),%rbp
  lea    D13(%rip),%r12
  add    $0x50,%r13
L35:
  lea    -0x10(%rbp),%rbx
L33:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L33
  mov    $0xa,%edi
  lea    0x10(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L35
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D13
datatype: string

tool: D5: %d

tool: D13: %d 

assistant: ```c
int main() {
  int matrix1[4][4];
  int matrix2[4][4];
  int m = 4, i, a;
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      scanf("%d", &matrix1[i][a]);
    }
  }
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      matrix2[i][a] = matrix1[a][i];
    }
  }
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      printf("%d ", matrix2[i][a]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
L8:
  lea    -0x10(%rbp),%rbx
L0:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %rbx,%rbp
  jne    L0
  add    $0x4,%r13
  add    $0x10,%rbp
  cmp    $0x10,%r13
  jne    L8
  movdqa (%rsp),%xmm0
  movdqa 0x10(%rsp),%xmm1
  lea    0x50(%rsp),%rbp
  lea    0x90(%rsp),%r13
  lea    D19(%rip),%r12
  movdqa %xmm0,%xmm2
  movdqa %xmm1,%xmm3
  punpckldq 0x20(%rsp),%xmm2
  punpckldq 0x30(%rsp),%xmm3
  punpckhdq 0x20(%rsp),%xmm0
  punpckhdq 0x30(%rsp),%xmm1
  movdqa %xmm2,%xmm4
  punpckhdq %xmm3,%xmm2
  punpckldq %xmm3,%xmm4
  movaps %xmm2,0x50(%rsp)
  movdqa %xmm0,%xmm2
  punpckhdq %xmm1,%xmm0
  punpckldq %xmm1,%xmm2
  movaps %xmm4,0x40(%rsp)
  movaps %xmm2,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
L9:
  lea    -0x10(%rbp),%rbx
L20:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L20
  mov    $0xa,%edi
  lea    0x10(%rbx),%rbp
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L9
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D7: %d

tool: D19: %d 

assistant: ```c
int main() {
  int matrix1[4][4];
  int matrix2[4][4];
  int m = 4, i, a;
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      scanf("%d", &matrix1[i][a]);
    }
  }
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      matrix2[i][a] = matrix1[a][i];
    }
  }
  for (i = 0; i < m; i++) {
    for (a = 0; a < m; a++) {
      printf("%d ", matrix2[i][a]);
    }
    printf("\n");
  }
  return 0;
}
```