user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D5(%rip),%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x78742e7475706e69,%rax
  lea    0x2e(%rsp),%rdi
  mov    %rax,0x2e(%rsp)
  mov    $0x74,%eax
  mov    %ax,0x36(%rsp)
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <fgetc@plt>
  movzbl %al,%ebx
  lea    -0x30(%rbx),%ebp
  mov    %ebx,0x14(%rsp)
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %ebp,%ebp
  jle    L84
  lea    -0x31(%rbx),%ecx
  lea    0x0(,%rbp,4),%r14d
  mov    %rax,%r15
  mov    %rax,%rbx
  mov    %rcx,0x18(%rsp)
  lea    0x8(%rax,%rcx,8),%r12
  nop
L94:
  mov    %r14d,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L94
  mov    0x18(%rsp),%rax
  lea    0x4(,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L87:
  mov    (%r15),%rdi
  mov    %r14,%rdx
  xor    %esi,%esi
  add    $0x8,%r15
  call   <memset@plt>
  cmp    %r12,%r15
  jne    L87
L84:
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L10:
  mov    %r13,%rdi
  call   <fgetc@plt>
  cmp    $0x20,%al
  je     L46
  cmp    $0xa,%al
  je     L46
  mov    0x8(%rsp),%rcx
  movslq %r14d,%rdx
  movslq %r12d,%rsi
  mov    (%rcx,%rdx,8),%rdx
  movzbl %al,%ecx
  lea    0x1(%r12),%eax
  sub    $0x30,%ecx
  mov    %ecx,(%rdx,%rsi,4)
  cltd
  idiv   %ebp
  add    %eax,%r14d
  mov    %edx,%r12d
L46:
  cmp    %r12d,%r14d
  mov    %r12d,%eax
  cmovge %r14d,%eax
  cmp    %eax,%ebp
  jg     L10
  test   %ebp,%ebp
  jle    L20
  mov    0x14(%rsp),%eax
  mov    0x8(%rsp),%rbx
  lea    D11(%rip),%r12
  sub    $0x31,%eax
  lea    0x8(%rbx,%rax,8),%r15
  lea    0x4(,%rax,4),%r14
L23:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L98:
  mov    (%rbx),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbp,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbp,%r14
  jne    L98
  mov    $0xa,%edi
  add    $0x8,%rbx
  call   <putchar@plt>
  cmp    %rbx,%r15
  jne    L23
L20:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string

tool: D5: r

tool: D11: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  unsigned char ch;
  int **C;
  int N, i, j;
  char filenamein[] = "input.txt";
  fp = fopen(filenamein, "r");
  N = (ch = fgetc(fp)) - '0';
  C = malloc(N * sizeof(int *));
  for (i = 0; i < N; i++)
    C[i] = malloc(N * sizeof(int));
  for (i = 0; i < N; i++)
    for (j = 0; j < N; j++)
      C[i][j] = 0;
  i = 0;
  j = 0;
  do {
    ch = fgetc(fp);
    if (ch != ' ' && ch != '\n') {
      C[i][j] = ch - '0';
      j++;
      i += j / N;
      j %= N;
    }
  } while (i < N && j < N);
  for (i = 0; i < N; i++) {
    for (j = 0; j < N; j++)
      printf("%d ", C[i][j]);
    printf("\n");
  }
  fclose(fp);
}
```