ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<test_htpass_authenticate_user_fred_invalid3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D44(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D91(%rip),%rax
  mov    %rax,%rdx
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <htpass_authenticate_user@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D44(%rip),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x2,-0x4(%rbp)
  je     L5
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <test_fail@plt>
L5:
  lea    D44(%rip),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D44
type_infered: string
name: read_data
arguments: tag: D13
type_infered: string
name: read_data
arguments: tag: D91
type_infered: string
name: read_data
arguments: tag: D28
type_infered: string
name: read_data
arguments: tag: D76
type_infered: string
name: read_data
arguments: tag: D59
type_infered: string
name: read_data
arguments: tag: D32
type_infered: string

tool: D44: test_htpass_authenticate_user_fred_invalid3

tool: D13: === RUN: %s


tool: D91: clearlywrong

tool: D28: fred

tool: D76: ./src/htpass_test.htpasswd

tool: D59: %s: fred - %d


tool: D32: --- PASS: %s


assistant: ```c
void test_htpass_authenticate_user_fred_invalid3() {
  printf("=== RUN: %s\n", __func__);
  int rc = htpass_authenticate_user("./src/htpass_test.htpasswd", "fred", "clearlywrong");
  printf("%s: fred - %d\n", __func__, rc);
  if (rc != 2)
    test_fail(__func__);
  printf("--- PASS: %s\n", __func__);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_htpass_authenticate_user_fred_invalid3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D38(%rip),%rbp
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D69(%rip),%rdx
  lea    D58(%rip),%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <htpass_authenticate_user@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x2,%ebx
  jne    L14
L11:
  lea    D38(%rip),%rsi
  lea    D66(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <test_fail@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: tag: D38
type_infered: string
name: disassemble_data
arguments: tag: D3
type_infered: string
name: disassemble_data
arguments: tag: D69
type_infered: string
name: disassemble_data
arguments: tag: D58
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D66
type_infered: string

tool: D38: test_htpass_authenticate_user_fred_invalid3

tool: D3: === RUN: %s


tool: D69: clearlywrong

tool: D58: fred

tool: D14: ./src/htpass_test.htpasswd

tool: D9: %s: fred - %d


tool: D66: --- PASS: %s


assistant: ```c
void test_htpass_authenticate_user_fred_invalid3() {
  printf("=== RUN: %s\n", __func__);
  int rc = htpass_authenticate_user("./src/htpass_test.htpasswd", "fred", "clearlywrong");
  printf("%s: fred - %d\n", __func__, rc);
  if (rc != 2)
    test_fail(__func__);
  printf("--- PASS: %s\n", __func__);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_htpass_authenticate_user_fred_invalid3>:
  endbr64
  push   %rbp
  lea    D69(%rip),%rbp
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D52(%rip),%rdx
  lea    D15(%rip),%rsi
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <htpass_authenticate_user@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x2,%ebx
  je     L8
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <test_fail@plt>
L8:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1080 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D69
data_type: string
name: unpack_data
arguments: tag: D34
data_type: string
name: unpack_data
arguments: tag: D52
data_type: string
name: unpack_data
arguments: tag: D15
data_type: string
name: unpack_data
arguments: tag: D14
data_type: string
name: unpack_data
arguments: tag: D35
data_type: string
name: unpack_data
arguments: tag: D11
data_type: string

tool: D69: test_htpass_authenticate_user_fred_invalid3

tool: D34: === RUN: %s


tool: D52: clearlywrong

tool: D15: fred

tool: D14: ./src/htpass_test.htpasswd

tool: D35: %s: fred - %d


tool: D11: --- PASS: %s


assistant: ```c
void test_htpass_authenticate_user_fred_invalid3() {
  printf("=== RUN: %s\n", __func__);
  int rc = htpass_authenticate_user("./src/htpass_test.htpasswd", "fred", "clearlywrong");
  printf("%s: fred - %d\n", __func__, rc);
  if (rc != 2)
    test_fail(__func__);
  printf("--- PASS: %s\n", __func__);
}
```
user: What is the c source code of the assembly code below?

```asm
<test_htpass_authenticate_user_fred_invalid3>:
  endbr64
  push   %rbp
  lea    D64(%rip),%rbp
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D11(%rip),%rdx
  lea    D20(%rip),%rsi
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <htpass_authenticate_user@plt>
  mov    %rbp,%rsi
  lea    D55(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x2,%ebx
  je     L0
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <test_fail@plt>
L0:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1080 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D64
data_type: string
name: retrieve_data
arguments: label: D10
data_type: string
name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D38
data_type: string
name: retrieve_data
arguments: label: D55
data_type: string
name: retrieve_data
arguments: label: D68
data_type: string

tool: D64: test_htpass_authenticate_user_fred_invalid3

tool: D10: === RUN: %s


tool: D11: clearlywrong

tool: D20: fred

tool: D38: ./src/htpass_test.htpasswd

tool: D55: %s: fred - %d


tool: D68: --- PASS: %s


assistant: ```c
void test_htpass_authenticate_user_fred_invalid3() {
  printf("=== RUN: %s\n", __func__);
  int rc = htpass_authenticate_user("./src/htpass_test.htpasswd", "fred", "clearlywrong");
  printf("%s: fred - %d\n", __func__, rc);
  if (rc != 2)
    test_fail(__func__);
  printf("--- PASS: %s\n", __func__);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  add    $0x4,%rax
  lea    -0x30(%rbp),%rdx
  movl   $0xfa1e0ff3,(%rax)
  movw   $0xbb49,0x4(%rax)
  lea    -0x67(%rip),%rcx        # 1139 <f2.0>
  mov    %rcx,0x6(%rax)
  movw   $0xba49,0xe(%rax)
  mov    %rdx,0x10(%rax)
  movl   $0x90e3ff49,0x18(%rax)
  mov    $0x0,%eax
  mov    %eax,-0x30(%rbp)
  lea    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <f0@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int f1(void) {
  int i = 0;
  int f2(int *p) {
    i = 1;
    return *p + 1;
  }
  return f0(f2, &i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f1>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rax
  mov    %rax,0x20(%rsp)
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  movl   $0xfa1e0ff3,0x4(%rsp)
  movw   $0xbb49,0x8(%rsp)
  lea    -0x51(%rip),%rax        # 1139 <f2.0>
  mov    %rax,0xa(%rsp)
  movw   $0xba49,0x12(%rsp)
  mov    %rsi,0x14(%rsp)
  movl   $0x90e3ff49,0x1c(%rsp)
  movl   $0x0,(%rsp)
  mov    $0x0,%eax
  call   <f0@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f1(void) {
  int i = 0;
  int f2(int *p) {
    i = 1;
    return *p + 1;
  }
  return f0(f2, &i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f1>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xffffba49,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  mov    %rax,0x20(%rsp)
  mov    $0xffffbb49,%eax
  mov    %ax,0x8(%rsp)
  lea    -0x60(%rip),%rax        # 1140 <f2.0>
  mov    %rax,0xa(%rsp)
  xor    %eax,%eax
  mov    %dx,0x12(%rsp)
  movl   $0xfa1e0ff3,0x4(%rsp)
  mov    %rsi,0x14(%rsp)
  movl   $0x90e3ff49,0x1c(%rsp)
  movl   $0x0,(%rsp)
  call   <f0@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f1(void) {
  int i = 0;
  int f2(int *p) {
    i = 1;
    return *p + 1;
  }
  return f0(f2, &i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f1>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xffffba49,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  mov    %rax,0x20(%rsp)
  mov    $0xffffbb49,%eax
  mov    %ax,0x8(%rsp)
  lea    -0x60(%rip),%rax        # 1140 <f2.0>
  mov    %rax,0xa(%rsp)
  xor    %eax,%eax
  mov    %dx,0x12(%rsp)
  movl   $0xfa1e0ff3,0x4(%rsp)
  mov    %rsi,0x14(%rsp)
  movl   $0x90e3ff49,0x1c(%rsp)
  movl   $0x0,(%rsp)
  call   <f0@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f1(void) {
  int i = 0;
  int f2(int *p) {
    i = 1;
    return *p + 1;
  }
  return f0(f2, &i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lpamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  movsd  %xmm0,-0x58(%rbp)
  movsd  %xmm1,-0x60(%rbp)
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x60(%rbp),%xmm0
  jp     L44
  pxor   %xmm0,%xmm0
  ucomisd -0x60(%rbp),%xmm0
  jne    L44
  pxor   %xmm0,%xmm0
  jmp    L5
L44:
  mov    -0x58(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x58(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  addq   $0x8,-0x68(%rbp)
  movl   $0x1,-0x44(%rbp)
  jmp    L94
L19:
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  mulsd  -0x10(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x68(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x40(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x68(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  addl   $0x1,-0x44(%rbp)
  addq   $0x8,-0x68(%rbp)
L94:
  mov    -0x44(%rbp),%eax
  cmp    -0x6c(%rbp),%eax
  jle    L19
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jp     L34
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jne    L34
  pxor   %xmm0,%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jp     L34
  pxor   %xmm0,%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jne    L34
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L8
L34:
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x60(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
L8:
  movsd  -0x20(%rbp),%xmm0
L5:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: f64

tool: D1: 1

assistant: ```c
double lpamp(double omega, double a0, double *coef, int M) {
  double wpr, wpi, wr, wi, re, im, temp, lp;
  int i;
  if (a0 == 0.)
    return (0.);
  wpr = cos(omega);
  wpi = sin(omega);
  re = wr = 1.;
  im = wi = 0.;
  for (coef++, i = 1; i <= M; i++, coef++) {
    wr = (temp = wr) * wpr - wi * wpi;
    wi = wi * wpr + temp * wpi;
    re += *coef * wr;
    im += *coef * wi;
  }
  if (re == 0. && im == 0.)
    lp = 0.;
  else
    lp = sqrt(a0 / (re * re + im * im));
  return (lp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lpamp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm1,%rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  ucomisd D10(%rip),%xmm1
  jp     L8
  pxor   %xmm1,%xmm1
  je     L80
L8:
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  (%rsp),%xmm5
  movsd  0x8(%rsp),%xmm6
  lea    0x8(%rbp),%rax
  test   %r12d,%r12d
  jle    L25
  lea    0x1(%r12),%edx
  lea    0x0(%rbp,%rdx,8),%rdx
  pxor   %xmm4,%xmm4
  movsd  D4(%rip),%xmm3
  movapd %xmm4,%xmm0
  movapd %xmm3,%xmm2
L20:
  movapd %xmm5,%xmm8
  mulsd  %xmm2,%xmm8
  movapd %xmm2,%xmm1
  movapd %xmm6,%xmm7
  mulsd  %xmm0,%xmm7
  movapd %xmm8,%xmm2
  subsd  %xmm7,%xmm2
  mulsd  %xmm5,%xmm0
  mulsd  %xmm6,%xmm1
  addsd  %xmm1,%xmm0
  movsd  (%rax),%xmm1
  movapd %xmm1,%xmm7
  mulsd  %xmm2,%xmm7
  addsd  %xmm7,%xmm3
  mulsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm4
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L20
  ucomisd D10(%rip),%xmm3
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  test   %al,%al
  je     L64
  ucomisd D10(%rip),%xmm4
  setnp  %al
  cmovne %edx,%eax
  pxor   %xmm1,%xmm1
  test   %al,%al
  je     L64
L80:
  movapd %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  pxor   %xmm4,%xmm4
  movsd  D4(%rip),%xmm3
L64:
  mulsd  %xmm3,%xmm3
  mulsd  %xmm4,%xmm4
  addsd  %xmm4,%xmm3
  movq   %rbx,%xmm1
  divsd  %xmm3,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L77
  sqrtsd %xmm1,%xmm1
  jmp    L80
L77:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L80
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_guessed: f64
name: extract_symbolic_data
arguments: label: D4
type_guessed: f64

tool: D10: 0

tool: D4: 1

assistant: ```c
double lpamp(double omega, double a0, double *coef, int M) {
  double wpr, wpi, wr, wi, re, im, temp, lp;
  int i;
  if (a0 == 0.)
    return (0.);
  wpr = cos(omega);
  wpi = sin(omega);
  re = wr = 1.;
  im = wi = 0.;
  for (coef++, i = 1; i <= M; i++, coef++) {
    wr = (temp = wr) * wpr - wi * wpi;
    wi = wi * wpr + temp * wpi;
    re += *coef * wr;
    im += *coef * wi;
  }
  if (re == 0. && im == 0.)
    lp = 0.;
  else
    lp = sqrt(a0 / (re * re + im * im));
  return (lp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lpamp>:
  endbr64
  push   %rbp
  pxor   %xmm7,%xmm7
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  ucomisd %xmm7,%xmm1
  jp     L2
  je     L29
L2:
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movsd  %xmm1,0x8(%rsp)
  call   <sincos@plt>
  test   %ebp,%ebp
  lea    0x8(%rbx),%rax
  pxor   %xmm7,%xmm7
  movsd  0x10(%rsp),%xmm6
  movsd  0x18(%rsp),%xmm8
  movsd  0x8(%rsp),%xmm1
  jle    L65
  movsd  D9(%rip),%xmm4
  lea    0x1(%rbp),%edx
  movapd %xmm7,%xmm5
  movapd %xmm7,%xmm0
  lea    (%rbx,%rdx,8),%rdx
  movapd %xmm4,%xmm3
  nopw   0x0(%rax,%rax,1)
L7:
  movapd %xmm6,%xmm10
  movapd %xmm3,%xmm2
  movapd %xmm8,%xmm9
  add    $0x8,%rax
  mulsd  %xmm3,%xmm10
  mulsd  %xmm0,%xmm9
  mulsd  %xmm8,%xmm2
  mulsd  %xmm6,%xmm0
  movapd %xmm10,%xmm3
  subsd  %xmm9,%xmm3
  addsd  %xmm2,%xmm0
  movsd  -0x8(%rax),%xmm2
  movapd %xmm2,%xmm9
  mulsd  %xmm3,%xmm9
  mulsd  %xmm0,%xmm2
  addsd  %xmm9,%xmm4
  addsd  %xmm2,%xmm5
  cmp    %rdx,%rax
  jne    L7
  ucomisd %xmm7,%xmm4
  mov    $0x0,%edx
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L37
  ucomisd %xmm7,%xmm5
  movapd %xmm7,%xmm0
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L37
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x28,%rsp
  movapd %xmm7,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mulsd  %xmm4,%xmm4
  mulsd  %xmm5,%xmm5
  addsd  %xmm5,%xmm4
  divsd  %xmm4,%xmm1
L65:
  ucomisd %xmm1,%xmm7
  ja     L19
  sqrtsd %xmm1,%xmm1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  movapd %xmm1,%xmm0
  ret
L19:
  add    $0x28,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  jmp    1060 <sqrt@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: f64

tool: D9: 1

assistant: ```c
double lpamp(double omega, double a0, double *coef, int M) {
  double wpr, wpi, wr, wi, re, im, temp, lp;
  int i;
  if (a0 == 0.)
    return (0.);
  wpr = cos(omega);
  wpi = sin(omega);
  re = wr = 1.;
  im = wi = 0.;
  for (coef++, i = 1; i <= M; i++, coef++) {
    wr = (temp = wr) * wpr - wi * wpi;
    wi = wi * wpr + temp * wpi;
    re += *coef * wr;
    im += *coef * wi;
  }
  if (re == 0. && im == 0.)
    lp = 0.;
  else
    lp = sqrt(a0 / (re * re + im * im));
  return (lp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lpamp>:
  endbr64
  push   %rbp
  pxor   %xmm7,%xmm7
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  ucomisd %xmm7,%xmm1
  jp     L27
  je     L58
L27:
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movsd  %xmm1,0x8(%rsp)
  call   <sincos@plt>
  test   %ebp,%ebp
  lea    0x8(%rbx),%rax
  pxor   %xmm7,%xmm7
  movsd  0x10(%rsp),%xmm6
  movsd  0x18(%rsp),%xmm8
  movsd  0x8(%rsp),%xmm1
  jle    L43
  movsd  D6(%rip),%xmm4
  lea    0x1(%rbp),%edx
  movapd %xmm7,%xmm5
  movapd %xmm7,%xmm0
  lea    (%rbx,%rdx,8),%rdx
  movapd %xmm4,%xmm3
  nopw   0x0(%rax,%rax,1)
L28:
  movapd %xmm6,%xmm10
  movapd %xmm3,%xmm2
  movapd %xmm8,%xmm9
  add    $0x8,%rax
  mulsd  %xmm3,%xmm10
  mulsd  %xmm0,%xmm9
  mulsd  %xmm8,%xmm2
  mulsd  %xmm6,%xmm0
  movapd %xmm10,%xmm3
  subsd  %xmm9,%xmm3
  addsd  %xmm2,%xmm0
  movsd  -0x8(%rax),%xmm2
  movapd %xmm2,%xmm9
  mulsd  %xmm3,%xmm9
  mulsd  %xmm0,%xmm2
  addsd  %xmm9,%xmm4
  addsd  %xmm2,%xmm5
  cmp    %rdx,%rax
  jne    L28
  ucomisd %xmm7,%xmm4
  mov    $0x0,%edx
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L45
  ucomisd %xmm7,%xmm5
  movapd %xmm7,%xmm0
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L45
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  add    $0x28,%rsp
  movapd %xmm7,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  mulsd  %xmm4,%xmm4
  mulsd  %xmm5,%xmm5
  addsd  %xmm5,%xmm4
  divsd  %xmm4,%xmm1
L43:
  ucomisd %xmm1,%xmm7
  ja     L63
  sqrtsd %xmm1,%xmm1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  movapd %xmm1,%xmm0
  ret
L63:
  add    $0x28,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  jmp    1060 <sqrt@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: f64

tool: D6: 1

assistant: ```c
double lpamp(double omega, double a0, double *coef, int M) {
  double wpr, wpi, wr, wi, re, im, temp, lp;
  int i;
  if (a0 == 0.)
    return (0.);
  wpr = cos(omega);
  wpi = sin(omega);
  re = wr = 1.;
  im = wi = 0.;
  for (coef++, i = 1; i <= M; i++, coef++) {
    wr = (temp = wr) * wpr - wi * wpi;
    wi = wi * wpr + temp * wpi;
    re += *coef * wr;
    im += *coef * wi;
  }
  if (re == 0. && im == 0.)
    lp = 0.;
  else
    lp = sqrt(a0 / (re * re + im * im));
  return (lp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string

tool: D3: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int *arr;
  arr = (int *)malloc(n * sizeof(int));
  print(arr, 0, 0, n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    0x4(%rsp),%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int *arr;
  arr = (int *)malloc(n * sizeof(int));
  print(arr, 0, 0, n);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int *arr;
  arr = (int *)malloc(n * sizeof(int));
  print(arr, 0, 0, n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int *arr;
  arr = (int *)malloc(n * sizeof(int));
  print(arr, 0, 0, n);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L5
  mov    $0x0,%edi
  call   <exit@plt>
L5:
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc)
    exit(0);
  printf(argv[3]);
  exit(EXIT_FAILURE);
}
```