ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x18(%rbp)
  jmp    L27
L7:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    $0x40,%eax
  jg     L21
  addl   $0x1,-0x10(%rbp)
L21:
  addl   $0x1,-0x18(%rbp)
L27:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L7
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  mov    -0x20(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
datatype: string
name: retrieve_data
arguments: data_label: D37
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D42
datatype: string
name: retrieve_data
arguments: data_label: D50
datatype: string

tool: D16: Cuantas calificaciones desea ingresar? 

tool: D37: %i

tool: D26: Introduzca la calificacion #%i 

tool: D42: 
Calificacion promedio = %.2f


tool: D50: Numero de reprobados = %i


assistant: ```c
int main(void) {
  int numeroDeCalificaciones, i, calificacion;
  int calTotal = 0, numeroReprobados = 0;
  float promedio;
  printf("Cuantas calificaciones desea ingresar? ");
  scanf("%i", &numeroDeCalificaciones);
  for (i = 1; i <= numeroDeCalificaciones; i++) {
    printf("Introduzca la calificacion #%i ", i);
    scanf("%i", &calificacion);
    calTotal += calificacion;
    if (calificacion < 65) {
      numeroReprobados++;
    }
  }
  promedio = (float)calTotal / numeroDeCalificaciones;
  printf("\nCalificacion promedio = %.2f\n", promedio);
  printf("Numero de reprobados = %i\n", numeroReprobados);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D48(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L21
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  lea    D17(%rip),%r15
  lea    0x4(%rsp),%r14
  lea    D48(%rip),%r13
L15:
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  movzbl %al,%eax
  add    %eax,%ebp
  add    $0x1,%ebx
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L15
L26:
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L26
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D55
type_infered: string
name: read_data
arguments: data_tag: D48
type_infered: string
name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D10
type_infered: string

tool: D55: Cuantas calificaciones desea ingresar? 

tool: D48: %i

tool: D17: Introduzca la calificacion #%i 

tool: D24: 
Calificacion promedio = %.2f


tool: D10: Numero de reprobados = %i


assistant: ```c
int main(void) {
  int numeroDeCalificaciones, i, calificacion;
  int calTotal = 0, numeroReprobados = 0;
  float promedio;
  printf("Cuantas calificaciones desea ingresar? ");
  scanf("%i", &numeroDeCalificaciones);
  for (i = 1; i <= numeroDeCalificaciones; i++) {
    printf("Introduzca la calificacion #%i ", i);
    scanf("%i", &calificacion);
    calTotal += calificacion;
    if (calificacion < 65) {
      numeroReprobados++;
    }
  }
  promedio = (float)calTotal / numeroDeCalificaciones;
  printf("\nCalificacion promedio = %.2f\n", promedio);
  printf("Numero de reprobados = %i\n", numeroReprobados);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D14(%rip),%rdi
  push   %r14
  push   %r13
  lea    D46(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L4
  mov    $0x1,%ebx
  lea    D45(%rip),%r15
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L15:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L15
L4:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D48(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D46
type_guessed: string
name: parse_data
arguments: data_label: D45
type_guessed: string
name: parse_data
arguments: data_label: D48
type_guessed: string
name: parse_data
arguments: data_label: D29
type_guessed: string

tool: D14: Cuantas calificaciones desea ingresar? 

tool: D46: %i

tool: D45: Introduzca la calificacion #%i 

tool: D48: 
Calificacion promedio = %.2f


tool: D29: Numero de reprobados = %i


assistant: ```c
int main(void) {
  int numeroDeCalificaciones, i, calificacion;
  int calTotal = 0, numeroReprobados = 0;
  float promedio;
  printf("Cuantas calificaciones desea ingresar? ");
  scanf("%i", &numeroDeCalificaciones);
  for (i = 1; i <= numeroDeCalificaciones; i++) {
    printf("Introduzca la calificacion #%i ", i);
    scanf("%i", &calificacion);
    calTotal += calificacion;
    if (calificacion < 65) {
      numeroReprobados++;
    }
  }
  promedio = (float)calTotal / numeroDeCalificaciones;
  printf("\nCalificacion promedio = %.2f\n", promedio);
  printf("Numero de reprobados = %i\n", numeroReprobados);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D31(%rip),%rdi
  push   %r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L3
  mov    $0x1,%ebx
  lea    D11(%rip),%r15
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L6:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L6
L3:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D49(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D31
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D49
datatype: string
name: retrieve_data
arguments: label: D40
datatype: string

tool: D31: Cuantas calificaciones desea ingresar? 

tool: D17: %i

tool: D11: Introduzca la calificacion #%i 

tool: D49: 
Calificacion promedio = %.2f


tool: D40: Numero de reprobados = %i


assistant: ```c
int main(void) {
  int numeroDeCalificaciones, i, calificacion;
  int calTotal = 0, numeroReprobados = 0;
  float promedio;
  printf("Cuantas calificaciones desea ingresar? ");
  scanf("%i", &numeroDeCalificaciones);
  for (i = 1; i <= numeroDeCalificaciones; i++) {
    printf("Introduzca la calificacion #%i ", i);
    scanf("%i", &calificacion);
    calTotal += calificacion;
    if (calificacion < 65) {
      numeroReprobados++;
    }
  }
  promedio = (float)calTotal / numeroDeCalificaciones;
  printf("\nCalificacion promedio = %.2f\n", promedio);
  printf("Numero de reprobados = %i\n", numeroReprobados);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_rchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L29
L36:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L38
L29:
  cmpl   $0x0,-0xc(%rbp)
  jne    L36
  jmp    L32
L38:
  nop
L32:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7f,%al
  jne    L55
L18:
  movq   $0x0,-0x8(%rbp)
L55:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_rchr(const char *s) {
  char *p;
  int ilen;
  ilen = strlen(s);
  while (ilen) {
    --ilen;
    if (!isspace((int)s[ilen])) {
      break;
    }
  }
  p = (char *)s + ilen;
  if (*p < 33 || *p > 126) {
    p = NULL;
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_rchr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  cltq
  lea    -0x1(%r12,%rax,1),%rbp
L11:
  test   %ebx,%ebx
  je     L16
  sub    $0x1,%ebx
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  sub    $0x1,%rbp
  test   %eax,%eax
  jne    L11
L16:
  movslq %ebx,%rbx
  movzbl (%r12,%rbx,1),%eax
  lea    -0x21(%rax),%edx
  lea    (%r12,%rbx,1),%rax
  cmp    $0x5e,%dl
  mov    $0x0,%edx
  cmovae %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_rchr(const char *s) {
  char *p;
  int ilen;
  ilen = strlen(s);
  while (ilen) {
    --ilen;
    if (!isspace((int)s[ilen])) {
      break;
    }
  }
  p = (char *)s + ilen;
  if (*p < 33 || *p > 126) {
    p = NULL;
  }
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_rchr>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    %eax,%eax
  lea    -0x1(%r14,%rdx,1),%rbx
  mov    %rbx,%r13
  sub    %rax,%r13
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L17:
  movsbl (%rbx),%edi
  mov    %rbx,%r12
  sub    $0x1,%rbx
  mov    %edi,%ebp
  call   <isspace@plt>
  test   %eax,%eax
  je     L16
L25:
  cmp    %r13,%rbx
  jne    L17
  movzbl (%r14),%ebp
  mov    %r14,%r12
L16:
  sub    $0x21,%ebp
  xor    %eax,%eax
  pop    %rbx
  cmp    $0x5e,%bpl
  pop    %rbp
  cmovae %rax,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *str_rchr(const char *s) {
  char *p;
  int ilen;
  ilen = strlen(s);
  while (ilen) {
    --ilen;
    if (!isspace((int)s[ilen])) {
      break;
    }
  }
  p = (char *)s + ilen;
  if (*p < 33 || *p > 126) {
    p = NULL;
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_rchr>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    %eax,%eax
  lea    -0x1(%r14,%rdx,1),%rbx
  mov    %rbx,%r13
  sub    %rax,%r13
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L29:
  movsbl (%rbx),%edi
  mov    %rbx,%r12
  sub    $0x1,%rbx
  mov    %edi,%ebp
  call   <isspace@plt>
  test   %eax,%eax
  je     L14
L0:
  cmp    %r13,%rbx
  jne    L29
  movzbl (%r14),%ebp
  mov    %r14,%r12
L14:
  sub    $0x21,%ebp
  xor    %eax,%eax
  pop    %rbx
  cmp    $0x5e,%bpl
  pop    %rbp
  cmovae %rax,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *str_rchr(const char *s) {
  char *p;
  int ilen;
  ilen = strlen(s);
  while (ilen) {
    --ilen;
    if (!isspace((int)s[ilen])) {
      break;
    }
  }
  p = (char *)s + ilen;
  if (*p < 33 || *p > 126) {
    p = NULL;
  }
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  nop
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: The result is %d


assistant: ```c
int main() {
  int a = 10;
  int b = 20;
  int result;
  result = a * b;
  __asm__("nop");
  printf("The result is %d\n", result);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nop
  mov    $0xc8,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: The result is %d


assistant: ```c
int main() {
  int a = 10;
  int b = 20;
  int result;
  result = a * b;
  __asm__("nop");
  printf("The result is %d\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nop
  mov    $0xc8,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2: The result is %d


assistant: ```c
int main() {
  int a = 10;
  int b = 20;
  int result;
  result = a * b;
  __asm__("nop");
  printf("The result is %d\n", result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nop
  mov    $0xc8,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: The result is %d


assistant: ```c
int main() {
  int a = 10;
  int b = 20;
  int result;
  result = a * b;
  __asm__("nop");
  printf("The result is %d\n", result);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  cmp    $0x1,%rax
  jbe    L14
  lea    -0x20(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rax,%rdi
  call   <split>
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rax,%rdi
  call   <split>
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%rdi
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <merge@plt>
  jmp    L8
L14:
  nop
L8:
  leave
  ret
```

assistant: ```c
void split(int64_t *a, int64_t *b, size_t begin, size_t end) {
  if (end - begin < 2)
    return;
  swap(&a, &b);
  size_t mid = (begin + end) / 2;
#pragma omp parallel shared(a, b) firstprivate(begin, mid, end)
  {
#pragma omp sections
    {
#pragma omp section
      split(a, b, begin, mid);
#pragma omp section
      split(a, b, mid, end);
    }
  }
  merge(a, b, begin, mid, end);
}
```
user: What is the c source code of the assembly code below:

```asm
<split>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,(%rsp)
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jbe    L1
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rdi
  call   <swap@plt>
  lea    0x0(%rbp,%rbx,1),%r12
  shr    %r12
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <split>
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <split>
  mov    %rbp,%r8
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <merge@plt>
L1:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void split(int64_t *a, int64_t *b, size_t begin, size_t end) {
  if (end - begin < 2)
    return;
  swap(&a, &b);
  size_t mid = (begin + end) / 2;
#pragma omp parallel shared(a, b) firstprivate(begin, mid, end)
  {
#pragma omp sections
    {
#pragma omp section
      split(a, b, begin, mid);
#pragma omp section
      split(a, b, mid, end);
    }
  }
  merge(a, b, begin, mid, end);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<split>:
  endbr64
  push   %r13
  mov    %rcx,%rax
  push   %r12
  sub    %rdx,%rax
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,(%rsp)
  cmp    $0x1,%rax
  jbe    L3
  mov    %rcx,%rbx
  mov    %rdx,%r12
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <swap@plt>
  lea    (%rbx,%r12,1),%r13
  mov    (%rsp),%rsi
  mov    %r12,%rdx
  shr    %r13
  mov    0x8(%rsp),%rdi
  mov    %r13,%rcx
  call   <split>
  mov    (%rsp),%rsi
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    0x8(%rsp),%rdi
  call   <split>
  mov    (%rsp),%rsi
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  call   <merge@plt>
L3:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void split(int64_t *a, int64_t *b, size_t begin, size_t end) {
  if (end - begin < 2)
    return;
  swap(&a, &b);
  size_t mid = (begin + end) / 2;
#pragma omp parallel shared(a, b) firstprivate(begin, mid, end)
  {
#pragma omp sections
    {
#pragma omp section
      split(a, b, begin, mid);
#pragma omp section
      split(a, b, mid, end);
    }
  }
  merge(a, b, begin, mid, end);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L12
  mov    -0x8(%rbp),%rax
  jmp    L17
L12:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
L17:
  leave
  ret
```

assistant: ```c
int fputs(const char *restrict s, FILE *restrict stream) {
  size_t len = strlen(s);
  size_t ret = fwrite(s, 1, len, stream);
  return ret == len ? (int)ret : EOF;
}
```
user: What is the c source code of the assembly code below?

```asm
<fputs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rcx
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  cmp    %rax,%rbx
  je     L5
  mov    D9(%rip),%rax
  mov    (%rax),%eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fputs(const char *restrict s, FILE *restrict stream) {
  size_t len = strlen(s);
  size_t ret = fwrite(s, 1, len, stream);
  return ret == len ? (int)ret : EOF;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fputs>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rcx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbx
  call   <fwrite@plt>
  cmp    %rax,%rbx
  je     L4
  mov    D6(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
  nopl   0x0(%rax)
L4:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fputs(const char *restrict s, FILE *restrict stream) {
  size_t len = strlen(s);
  size_t ret = fwrite(s, 1, len, stream);
  return ret == len ? (int)ret : EOF;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fputs>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rcx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbx
  call   <fwrite@plt>
  cmp    %rax,%rbx
  je     L2
  mov    D6(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fputs(const char *restrict s, FILE *restrict stream) {
  size_t len = strlen(s);
  size_t ret = fwrite(s, 1, len, stream);
  return ret == len ? (int)ret : EOF;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PunctCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ispunct@plt>
  test   %rax,%rax
  je     L20
  addl   $0x1,-0x4(%rbp)
L20:
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int PunctCount(const char *str) {
  int ct = 0;
  while (*str) {
    if (ispunct(*str)) {
      ct++;
    }
    str++;
  }
  return ct;
}
```