ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memXcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L77
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L79
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x20,%eax
  jmp    L70
L42:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
L70:
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  cmp    %edx,%eax
  je     L79
  mov    $0xffffffff,%eax
  jmp    L20
L79:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L77:
  cmpl   $0x0,-0x14(%rbp)
  jg     L26
  mov    $0x0,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int memXcmp(char *m1, char *M2, int len) {
  while (len > 0) {
    if (*m1 != *M2 && (((*m1) >= 'a' && (*m1) <= 'z') ? ((*m1) - 'a' + 'A') : (*m1)) != *M2)
      return -1;
    ++m1;
    ++M2;
    --len;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memXcmp>:
  endbr64
  mov    %rdi,%r10
  test   %edx,%edx
  jle    L18
  mov    %edx,%edx
  mov    $0x0,%ecx
  jmp    L5
L38:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L29
L5:
  movzbl (%r10,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%edi
  cmp    %dil,%al
  je     L38
  lea    -0x61(%rax),%r9d
  movsbl %al,%r8d
  sub    $0x20,%r8d
  movsbl %al,%eax
  cmp    $0x19,%r9b
  cmovbe %r8d,%eax
  movsbl %dil,%edi
  cmp    %eax,%edi
  je     L38
  mov    $0xffffffff,%eax
  ret
L29:
  mov    $0x0,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memXcmp(char *m1, char *M2, int len) {
  while (len > 0) {
    if (*m1 != *M2 && (((*m1) >= 'a' && (*m1) <= 'z') ? ((*m1) - 'a' + 'A') : (*m1)) != *M2)
      return -1;
    ++m1;
    ++M2;
    --len;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memXcmp>:
  endbr64
  mov    %rdi,%r10
  test   %edx,%edx
  jle    L17
  movslq %edx,%rdx
  xor    %ecx,%ecx
L10:
  movsbl (%r10,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%edi
  cmp    %dil,%al
  je     L21
  lea    -0x61(%rax),%r9d
  lea    -0x20(%rax),%r8d
  movsbl %r8b,%r8d
  cmp    $0x19,%r9b
  cmovbe %r8d,%eax
  cmp    %eax,%edi
  jne    L39
L21:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L10
L17:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int memXcmp(char *m1, char *M2, int len) {
  while (len > 0) {
    if (*m1 != *M2 && (((*m1) >= 'a' && (*m1) <= 'z') ? ((*m1) - 'a' + 'A') : (*m1)) != *M2)
      return -1;
    ++m1;
    ++M2;
    --len;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memXcmp>:
  endbr64
  mov    %rdi,%r10
  test   %edx,%edx
  jle    L30
  movslq %edx,%rdx
  xor    %ecx,%ecx
L34:
  movsbl (%r10,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%edi
  cmp    %dil,%al
  je     L4
  lea    -0x61(%rax),%r9d
  lea    -0x20(%rax),%r8d
  movsbl %r8b,%r8d
  cmp    $0x19,%r9b
  cmovbe %r8d,%eax
  cmp    %eax,%edi
  jne    L26
L4:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L34
L30:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int memXcmp(char *m1, char *M2, int len) {
  while (len > 0) {
    if (*m1 != *M2 && (((*m1) >= 'a' && (*m1) <= 'z') ? ((*m1) - 'a' + 'A') : (*m1)) != *M2)
      return -1;
    ++m1;
    ++M2;
    --len;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void write_int(unsigned char *buf, int value) {
  buf[0] = 0xFF & value;
  buf[1] = 0xFF & (value >> 8);
  buf[2] = 0xFF & (value >> 16);
  buf[3] = 0xFF & (value >> 24);
}
```
user: What is the c source code of the assembly code below:

```asm
<write_int>:
  endbr64
  mov    %esi,%eax
  mov    %sil,(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %dl,0x2(%rdi)
  shr    $0x18,%eax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void write_int(unsigned char *buf, int value) {
  buf[0] = 0xFF & value;
  buf[1] = 0xFF & (value >> 8);
  buf[2] = 0xFF & (value >> 16);
  buf[3] = 0xFF & (value >> 24);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_int>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void write_int(unsigned char *buf, int value) {
  buf[0] = 0xFF & value;
  buf[1] = 0xFF & (value >> 8);
  buf[2] = 0xFF & (value >> 16);
  buf[3] = 0xFF & (value >> 24);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_int>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void write_int(unsigned char *buf, int value) {
  buf[0] = 0xFF & value;
  buf[1] = 0xFF & (value >> 8);
  buf[2] = 0xFF & (value >> 16);
  buf[3] = 0xFF & (value >> 24);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    $0x1e,%esi
  mov    $0x2,%edi
  call   <power@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L5
L23:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <X@plt>
  test   %rax,%rax
  jne    L7
  addq   $0x1,-0x18(%rbp)
L7:
  addq   $0x1,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L23
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D5: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long c = 0;
  unsigned long n;
  unsigned long upper_limit = power(2, 30) + 1;
  for (n = 1; n < upper_limit; n++) {
    if (X(n, 2 * n, 3 * n) == 0) {
      c++;
    }
  }
  printf("%lu\n", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1e,%esi
  mov    $0x2,%edi
  call   <power@plt>
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    $0x1,%rdx
  jbe    L22
  movslq %eax,%r12
  mov    $0x1,%ebx
  mov    $0x0,%ebp
  jmp    L3
L33:
  mov    %rax,%rbx
L3:
  lea    (%rbx,%rbx,1),%esi
  lea    (%rsi,%rbx,1),%edx
  mov    %rbx,%rdi
  call   <X@plt>
  cmp    $0x1,%rax
  adc    $0x0,%rbp
  lea    0x1(%rbx),%rax
  cmp    %rbx,%r12
  jne    L33
L13:
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    $0x0,%ebp
  jmp    L13
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long c = 0;
  unsigned long n;
  unsigned long upper_limit = power(2, 30) + 1;
  for (n = 1; n < upper_limit; n++) {
    if (X(n, 2 * n, 3 * n) == 0) {
      c++;
    }
  }
  printf("%lu\n", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1e,%esi
  mov    $0x2,%edi
  push   %rbp
  push   %rbx
  call   <power@plt>
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    $0x1,%rdx
  jbe    L32
  movslq %eax,%r12
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  jmp    L29
  nop
L20:
  mov    %rax,%rbx
L29:
  lea    (%rbx,%rbx,1),%esi
  mov    %rbx,%rdi
  lea    (%rsi,%rbx,1),%edx
  call   <X@plt>
  cmp    $0x1,%rax
  lea    0x1(%rbx),%rax
  adc    $0x0,%rbp
  cmp    %rbx,%r12
  jne    L20
L2:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L32:
  xor    %ebp,%ebp
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string

tool: D9: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long c = 0;
  unsigned long n;
  unsigned long upper_limit = power(2, 30) + 1;
  for (n = 1; n < upper_limit; n++) {
    if (X(n, 2 * n, 3 * n) == 0) {
      c++;
    }
  }
  printf("%lu\n", c);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1e,%esi
  mov    $0x2,%edi
  push   %rbp
  push   %rbx
  call   <power@plt>
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    $0x1,%rdx
  jbe    L6
  movslq %eax,%r12
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  jmp    L23
  nop
L31:
  mov    %rax,%rbx
L23:
  lea    (%rbx,%rbx,1),%esi
  mov    %rbx,%rdi
  lea    (%rsi,%rbx,1),%edx
  call   <X@plt>
  cmp    $0x1,%rax
  lea    0x1(%rbx),%rax
  adc    $0x0,%rbp
  cmp    %rbx,%r12
  jne    L31
L15:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  xor    %ebp,%ebp
  jmp    L15
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long c = 0;
  unsigned long n;
  unsigned long upper_limit = power(2, 30) + 1;
  for (n = 1; n < upper_limit; n++) {
    if (X(n, 2 * n, 3 * n) == 0) {
      c++;
    }
  }
  printf("%lu\n", c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x90(%rbp)
  movl   $0x2,-0x8c(%rbp)
  movl   $0x3,-0x88(%rbp)
  movl   $0x4,-0x84(%rbp)
  movl   $0x5,-0x80(%rbp)
  movl   $0x6,-0x7c(%rbp)
  movl   $0x7,-0x78(%rbp)
  movl   $0x8,-0x74(%rbp)
  movl   $0x9,-0x70(%rbp)
  movl   $0xa,-0x6c(%rbp)
  lea    -0x60(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <i_scan_plus@plt>
  lea    -0x30(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <e_scan_plus@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <printResult@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <printResult@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int in[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int out[10];
  int eout[10];
  i_scan_plus(10, in, out);
  e_scan_plus(10, in, eout);
  printResult(10, out);
  printResult(10, eout);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  lea    0x30(%rsp),%rbp
  mov    %rsp,%r12
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <i_scan_plus@plt>
  lea    0x60(%rsp),%rbx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <e_scan_plus@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <printResult@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <printResult@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int in[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int out[10];
  int eout[10];
  i_scan_plus(10, in, out);
  e_scan_plus(10, in, eout);
  printResult(10, out);
  printResult(10, eout);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%edi
  push   %r12
  push   %rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  movabs $0x200000001,%rax
  lea    0x30(%rsp),%r12
  mov    %rsp,%r13
  lea    0x60(%rsp),%rbp
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x20(%rsp)
  call   <i_scan_plus@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    $0xa,%edi
  call   <e_scan_plus@plt>
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <printResult@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <printResult@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int in[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int out[10];
  int eout[10];
  i_scan_plus(10, in, out);
  e_scan_plus(10, in, eout);
  printResult(10, out);
  printResult(10, eout);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%edi
  push   %r12
  push   %rbp
  sub    $0x90,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r12
  mov    %rsp,%r13
  lea    0x60(%rsp),%rbp
  mov    D10(%rip),%rax
  movaps %xmm0,(%rsp)
  mov    %r12,%rdx
  mov    %r13,%rsi
  movdqa D18(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <i_scan_plus@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    $0xa,%edi
  call   <e_scan_plus@plt>
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <printResult@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <printResult@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: byte[16]
name: retrieve_data
arguments: tag: D10
datatype: byte[8]
name: retrieve_data
arguments: tag: D18
datatype: byte[16]

tool: {"D0": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D10": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D18": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  int in[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int out[10];
  int eout[10];
  i_scan_plus(10, in, out);
  e_scan_plus(10, in, eout);
  printResult(10, out);
  printResult(10, eout);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_time_raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x18(%rbp),%rax
  imul   $0x3b9aca00,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int64_t get_time_raw(void) {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return (int64_t)ts.tv_sec * 1000000000LL + (int64_t)ts.tv_nsec;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_time_raw>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t get_time_raw(void) {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return (int64_t)ts.tv_sec * 1000000000LL + (int64_t)ts.tv_nsec;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_time_raw>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t get_time_raw(void) {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return (int64_t)ts.tv_sec * 1000000000LL + (int64_t)ts.tv_nsec;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_time_raw>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t get_time_raw(void) {
  struct timespec ts;
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return (int64_t)ts.tv_sec * 1000000000LL + (int64_t)ts.tv_nsec;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x404(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L75
L20:
  movl   $0x0,-0x400(%rbp)
  movl   $0x0,-0x3fc(%rbp)
  movl   $0x0,-0x3f8(%rbp)
  movl   $0x0,-0x3f4(%rbp)
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movzbl -0x3f0(%rbp),%eax
  cmp    $0x68,%al
  je     L88
  movzbl -0x3f0(%rbp),%eax
  cmp    $0x48,%al
  jne    L21
L88:
  movl   $0x1,-0x400(%rbp)
L21:
  movzbl -0x3ef(%rbp),%eax
  cmp    $0x69,%al
  je     L82
  movzbl -0x3ef(%rbp),%eax
  cmp    $0x49,%al
  jne    L36
L82:
  movl   $0x1,-0x3fc(%rbp)
L36:
  movzbl -0x3ee(%rbp),%eax
  cmp    $0x20,%al
  je     L63
  movzbl -0x3ee(%rbp),%eax
  cmp    $0x20,%al
  jne    L95
L63:
  movl   $0x1,-0x3f8(%rbp)
L95:
  movzbl -0x3ed(%rbp),%eax
  cmp    $0x64,%al
  jne    L118
  movzbl -0x3ed(%rbp),%eax
  cmp    $0x44,%al
  jne    L147
L118:
  movl   $0x1,-0x3f4(%rbp)
L147:
  cmpl   $0x1,-0x400(%rbp)
  jne    L75
  cmpl   $0x1,-0x3fc(%rbp)
  jne    L75
  cmpl   $0x1,-0x3f8(%rbp)
  jne    L75
  cmpl   $0x1,-0x3f4(%rbp)
  jne    L75
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L75:
  mov    -0x404(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x404(%rbp)
  test   %eax,%eax
  jne    L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: %d

assistant: ```c
int main() {
  int i, j, t, n;
  char str[1000];
  scanf("%d", &t);
  gets(str);
  while (t--) {
    int flag1 = 0, flag2 = 0, flag3 = 0, flag4 = 0;
    gets(str);
    if (str[0] == 'h' || str[0] == 'H')
      flag1 = 1;
    if (str[1] == 'i' || str[1] == 'I')
      flag2 = 1;
    if (str[2] == ' ' || str[2] == ' ')
      flag3 = 1;
    if (str[3] != 'd' || str[3] == 'D')
      flag4 = 1;
    if (flag1 == 1 && flag2 == 1 && flag3 == 1 && flag4 == 1)
      puts(str);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  call   <gets@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L64
  lea    0x10(%rsp),%rbx
  jmp    L16
L38:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L64
L16:
  mov    %rbx,%rdi
  call   <gets@plt>
  movzbl 0x11(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x49,%al
  jne    L38
  movzbl 0x10(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x48,%al
  jne    L38
  cmpb   $0x64,0x13(%rsp)
  je     L38
  cmpb   $0x20,0x12(%rsp)
  jne    L38
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L38
L64:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    $0x0,%eax
  add    $0x400,%rsp
  pop    %rbx
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: %d

assistant: ```c
int main() {
  int i, j, t, n;
  char str[1000];
  scanf("%d", &t);
  gets(str);
  while (t--) {
    int flag1 = 0, flag2 = 0, flag3 = 0, flag4 = 0;
    gets(str);
    if (str[0] == 'h' || str[0] == 'H')
      flag1 = 1;
    if (str[1] == 'i' || str[1] == 'I')
      flag2 = 1;
    if (str[2] == ' ' || str[2] == ' ')
      flag3 = 1;
    if (str[3] != 'd' || str[3] == 'D')
      flag4 = 1;
    if (flag1 == 1 && flag2 == 1 && flag3 == 1 && flag4 == 1)
      puts(str);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rdi
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  nopl   (%rax)
L58:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L27
L44:
  mov    %rbx,%rdi
  call   <gets@plt>
  cmpb   $0x64,0x13(%rsp)
  je     L58
  movzbl 0x11(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x49,%al
  jne    L58
  movzbl 0x10(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x48,%al
  jne    L58
  cmpb   $0x20,0x12(%rsp)
  jne    L58
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L44
  nopl   0x0(%rax)
L27:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: %d

assistant: ```c
int main() {
  int i, j, t, n;
  char str[1000];
  scanf("%d", &t);
  gets(str);
  while (t--) {
    int flag1 = 0, flag2 = 0, flag3 = 0, flag4 = 0;
    gets(str);
    if (str[0] == 'h' || str[0] == 'H')
      flag1 = 1;
    if (str[1] == 'i' || str[1] == 'I')
      flag2 = 1;
    if (str[2] == ' ' || str[2] == ' ')
      flag3 = 1;
    if (str[3] != 'd' || str[3] == 'D')
      flag4 = 1;
    if (flag1 == 1 && flag2 == 1 && flag3 == 1 && flag4 == 1)
      puts(str);
  }
  return 0;
}
```