ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<isFartherThan_l2_double>:
  endbr64
  mulsd  %xmm0,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %edx,%edx
  jle    L42
  mov    %rdi,%r13
  mov    %rsi,%r12
  movslq %edx,%rbp
  xor    %ebx,%ebx
  pxor   %xmm1,%xmm1
  jmp    L25
  nopl   0x0(%rax)
L52:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L57
L25:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  comisd 0x8(%rsp),%xmm1
  jbe    L52
  mov    D2(%rip),%rax
  movsd  (%rax),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L57:
  pxor   %xmm3,%xmm3
  ucomisd %xmm1,%xmm3
  ja     L7
L2:
  sqrtsd %xmm1,%xmm1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  movapd %xmm1,%xmm0
  ret
L42:
  pxor   %xmm1,%xmm1
  jmp    L2
L7:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double isFartherThan_l2_double(double *p1, double *p2, int len, double dist) {
  double ret = 0;
  double dist2 = dist * dist;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
    if (ret > dist2)
      return NAN;
  }
  return sqrt(ret);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<homedir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    (%rax),%rax
  jmp    L16
L4:
  mov    -0x8(%rbp),%rax
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: HOME

assistant: ```c
const char *homedir(void) {
  const char *home = getenv("HOME");
  return home ? home : getpwuid(getuid())->pw_dir;
}
```
user: What is the c source code of the assembly code below:

```asm
<homedir>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L15
L16:
  add    $0x8,%rsp
  ret
L15:
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    (%rax),%rax
  jmp    L16
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: HOME

assistant: ```c
const char *homedir(void) {
  const char *home = getenv("HOME");
  return home ? home : getpwuid(getuid())->pw_dir;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<homedir>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L2:
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    (%rax),%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: HOME

assistant: ```c
const char *homedir(void) {
  const char *home = getenv("HOME");
  return home ? home : getpwuid(getuid())->pw_dir;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<homedir>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L0:
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    (%rax),%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: HOME

assistant: ```c
const char *homedir(void) {
  const char *home = getenv("HOME");
  return home ? home : getpwuid(getuid())->pw_dir;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    $0x0,%eax
  call   <sll_create@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%eax
  call   <sll_create@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L52
L4:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sll_push@plt>
  addl   $0x1,-0x28(%rbp)
L52:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x28(%rbp)
  jl     L4
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x28(%rbp)
  jmp    L47
L73:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sll_push@plt>
  subl   $0x1,-0x28(%rbp)
L47:
  cmpl   $0x0,-0x28(%rbp)
  jg     L73
  movl   $0x0,-0x28(%rbp)
  jmp    L79
L55:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sll_pop@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sll_pop@plt>
  cmp    %rax,%rbx
  je     L54
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sll_free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sll_free@plt>
  mov    -0x24(%rbp),%eax
  jmp    L42
L54:
  addl   $0x1,-0x28(%rbp)
L79:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x28(%rbp)
  jl     L55
  movl   $0x1,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sll_free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sll_free@plt>
  mov    -0x24(%rbp),%eax
L42:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int isPalindrome(char *string) {
  int result = 0;
  int i;
  struct sll *newLink1 = sll_create();
  struct sll *newLink2 = sll_create();
  for (i = 0; i < (int)strlen(string); i++) {
    sll_push(newLink1, string[i]);
  }
  for (i = (int)strlen(string); i > 0; i--) {
    sll_push(newLink2, string[i]);
  }
  for (i = 0; i < (int)strlen(string); i++) {
    if (sll_pop(newLink1) != sll_pop(newLink2)) {
      sll_free(newLink1);
      sll_free(newLink2);
      return result;
    }
  }
  result = 1;
  sll_free(newLink1);
  sll_free(newLink2);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isPalindrome>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <sll_create@plt>
  mov    %rax,%r13
  mov    $0x0,%eax
  call   <sll_create@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  jmp    L61
L54:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r13,%rdi
  call   <sll_push@plt>
  add    $0x1,%rbx
L61:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L54
  test   %eax,%eax
  jle    L20
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,1),%rbx
  lea    -0x1(%rbp,%rdx,1),%r14
  lea    -0x1(%rax),%eax
  sub    %rax,%r14
L10:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <sll_push@plt>
  sub    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L10
  mov    $0x0,%r14d
  jmp    L37
L43:
  add    $0x1,%r14d
L37:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,%r14d
  jge    L20
  mov    %r13,%rdi
  call   <sll_pop@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <sll_pop@plt>
  cmp    %rax,%rbx
  je     L43
  mov    %r13,%rdi
  call   <sll_free@plt>
  mov    %r12,%rdi
  call   <sll_free@plt>
  mov    $0x0,%eax
  jmp    L30
L20:
  mov    %r13,%rdi
  call   <sll_free@plt>
  mov    %r12,%rdi
  call   <sll_free@plt>
  mov    $0x1,%eax
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int isPalindrome(char *string) {
  int result = 0;
  int i;
  struct sll *newLink1 = sll_create();
  struct sll *newLink2 = sll_create();
  for (i = 0; i < (int)strlen(string); i++) {
    sll_push(newLink1, string[i]);
  }
  for (i = (int)strlen(string); i > 0; i--) {
    sll_push(newLink2, string[i]);
  }
  for (i = 0; i < (int)strlen(string); i++) {
    if (sll_pop(newLink1) != sll_pop(newLink2)) {
      sll_free(newLink1);
      sll_free(newLink2);
      return result;
    }
  }
  result = 1;
  sll_free(newLink1);
  sll_free(newLink2);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isPalindrome>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <sll_create@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <sll_create@plt>
  mov    %rax,%r13
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <sll_push@plt>
L44:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  cmp    %ebx,%eax
  jg     L27
  test   %edx,%edx
  jle    L35
  lea    -0x1(%rbp,%rdx,1),%r14
  sub    $0x1,%eax
  lea    0x0(%rbp,%rdx,1),%rbx
  sub    %rax,%r14
  nopl   0x0(%rax)
L46:
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  sub    $0x1,%rbx
  call   <sll_push@plt>
  cmp    %r14,%rbx
  jne    L46
  xor    %r14d,%r14d
  jmp    L58
  nopl   0x0(%rax)
L16:
  add    $0x1,%r14d
L58:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,%r14d
  jge    L35
  mov    %r12,%rdi
  call   <sll_pop@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <sll_pop@plt>
  cmp    %rax,%rbx
  je     L16
  mov    %r12,%rdi
  call   <sll_free@plt>
  mov    %r13,%rdi
  call   <sll_free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L35:
  mov    %r12,%rdi
  call   <sll_free@plt>
  mov    %r13,%rdi
  call   <sll_free@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int isPalindrome(char *string) {
  int result = 0;
  int i;
  struct sll *newLink1 = sll_create();
  struct sll *newLink2 = sll_create();
  for (i = 0; i < (int)strlen(string); i++) {
    sll_push(newLink1, string[i]);
  }
  for (i = (int)strlen(string); i > 0; i--) {
    sll_push(newLink2, string[i]);
  }
  for (i = 0; i < (int)strlen(string); i++) {
    if (sll_pop(newLink1) != sll_pop(newLink2)) {
      sll_free(newLink1);
      sll_free(newLink2);
      return result;
    }
  }
  result = 1;
  sll_free(newLink1);
  sll_free(newLink2);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPalindrome>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <sll_create@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <sll_create@plt>
  mov    %rax,%r13
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L39:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <sll_push@plt>
L48:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  cmp    %ebx,%eax
  jg     L39
  test   %edx,%edx
  jle    L11
  lea    -0x1(%rbp,%rdx,1),%r14
  sub    $0x1,%eax
  lea    0x0(%rbp,%rdx,1),%rbx
  sub    %rax,%r14
  nopl   0x0(%rax)
L19:
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  sub    $0x1,%rbx
  call   <sll_push@plt>
  cmp    %rbx,%r14
  jne    L19
  xor    %r14d,%r14d
  jmp    L20
  nopl   0x0(%rax)
L5:
  add    $0x1,%r14d
L20:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,%r14d
  jge    L11
  mov    %r12,%rdi
  call   <sll_pop@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <sll_pop@plt>
  cmp    %rax,%rbx
  je     L5
  mov    %r12,%rdi
  call   <sll_free@plt>
  mov    %r13,%rdi
  call   <sll_free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  mov    %r12,%rdi
  call   <sll_free@plt>
  mov    %r13,%rdi
  call   <sll_free@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int isPalindrome(char *string) {
  int result = 0;
  int i;
  struct sll *newLink1 = sll_create();
  struct sll *newLink2 = sll_create();
  for (i = 0; i < (int)strlen(string); i++) {
    sll_push(newLink1, string[i]);
  }
  for (i = (int)strlen(string); i > 0; i--) {
    sll_push(newLink2, string[i]);
  }
  for (i = 0; i < (int)strlen(string); i++) {
    if (sll_pop(newLink1) != sll_pop(newLink2)) {
      sll_free(newLink1);
      sll_free(newLink2);
      return result;
    }
  }
  result = 1;
  sll_free(newLink1);
  sll_free(newLink2);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printw@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: Hello World

assistant: ```c
void run() {
  attrset(COLOR_PAIR(1));
  printw("Hello World");
  getch();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<run>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  lea    D7(%rip),%rdi
  call   <printw@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: Hello World

assistant: ```c
void run() {
  attrset(COLOR_PAIR(1));
  printw("Hello World");
  getch();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<run>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  lea    D1(%rip),%rdi
  call   <printw@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <getch@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: Hello World

assistant: ```c
void run() {
  attrset(COLOR_PAIR(1));
  printw("Hello World");
  getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<run>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  lea    D3(%rip),%rdi
  call   <printw@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <getch@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string

tool: D3: Hello World

assistant: ```c
void run() {
  attrset(COLOR_PAIR(1));
  printw("Hello World");
  getch();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<thr1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L9:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x4,%eax
  ja     L9
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D19(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D19(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edi
  call   <rdma_addr_unregister_client@plt>
  jmp    L18
  mov    $0x0,%eax
  call   <queue_req@plt>
  jmp    L18
  mov    $0x0,%eax
  call   <process_req@plt>
  jmp    L18
  mov    $0x0,%eax
  call   <rdma_resolve_ip@plt>
  jmp    L18
  mov    $0x0,%eax
  call   <rdma_addr_cancel@plt>
  nop
L18:
  jmp    L9
```

assistant: ```c
void *thr1(void *arg) {
  while (1)
    switch (__VERIFIER_nondet_int()) {
    case 0:
      rdma_addr_unregister_client(__VERIFIER_nondet_int());
      break;
    case 1:
      queue_req();
      break;
    case 2:
      process_req();
      break;
    case 3:
      rdma_resolve_ip();
      break;
    case 4:
      rdma_addr_cancel();
      break;
    }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<thr1>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  jmp    L10
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edi
  call   <rdma_addr_unregister_client@plt>
L10:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x4,%eax
  ja     L10
  mov    %eax,%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <queue_req@plt>
  jmp    L10
  mov    $0x0,%eax
  call   <process_req@plt>
  jmp    L10
  mov    $0x0,%eax
  call   <rdma_resolve_ip@plt>
  jmp    L10
  mov    $0x0,%eax
  call   <rdma_addr_cancel@plt>
  jmp    L10
```

assistant: ```c
void *thr1(void *arg) {
  while (1)
    switch (__VERIFIER_nondet_int()) {
    case 0:
      rdma_addr_unregister_client(__VERIFIER_nondet_int());
      break;
    case 1:
      queue_req();
      break;
    case 2:
      process_req();
      break;
    case 3:
      rdma_resolve_ip();
      break;
    case 4:
      rdma_addr_cancel();
      break;
    }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Ex6_Pointers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <GetInt@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <ChangeIntWithPointer@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D16: Give input: 

tool: D4: %d


assistant: ```c
void Ex6_Pointers() {
  int a = GetInt("Give input: ");
  ChangeIntWithPointer(&a, 5);
  printf("%d\n", a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Ex6_Pointers>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <GetInt@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x5,%esi
  call   <ChangeIntWithPointer@plt>
  mov    0x4(%rsp),%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string

tool: D9: Give input: 

tool: D12: %d


assistant: ```c
void Ex6_Pointers() {
  int a = GetInt("Give input: ");
  ChangeIntWithPointer(&a, 5);
  printf("%d\n", a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Ex6_Pointers>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <GetInt@plt>
  lea    0x4(%rsp),%rdi
  mov    $0x5,%esi
  mov    %eax,0x4(%rsp)
  call   <ChangeIntWithPointer@plt>
  mov    0x4(%rsp),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D9
data_type: string

tool: D12: Give input: 

tool: D9: %d


assistant: ```c
void Ex6_Pointers() {
  int a = GetInt("Give input: ");
  ChangeIntWithPointer(&a, 5);
  printf("%d\n", a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Ex6_Pointers>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <GetInt@plt>
  lea    0x4(%rsp),%rdi
  mov    $0x5,%esi
  mov    %eax,0x4(%rsp)
  call   <ChangeIntWithPointer@plt>
  mov    0x4(%rsp),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D11: Give input: 

tool: D6: %d


assistant: ```c
void Ex6_Pointers() {
  int a = GetInt("Give input: ");
  ChangeIntWithPointer(&a, 5);
  printf("%d\n", a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RKMath_Set_Vec_Equal_To_A_Const>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %esi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void RKMath_Set_Vec_Equal_To_A_Const(float vec[], const float const__, const int size) {
  int i = 0;
  while (i < size) {
    vec[i] = const__;
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RKMath_Set_Vec_Equal_To_A_Const>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L14:
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L14
L6:
  ret
```

assistant: ```c
void RKMath_Set_Vec_Equal_To_A_Const(float vec[], const float const__, const int size) {
  int i = 0;
  while (i < size) {
    vec[i] = const__;
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RKMath_Set_Vec_Equal_To_A_Const>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
L15:
  movss  %xmm0,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L15
L7:
  ret
```

assistant: ```c
void RKMath_Set_Vec_Equal_To_A_Const(float vec[], const float const__, const int size) {
  int i = 0;
  while (i < size) {
    vec[i] = const__;
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RKMath_Set_Vec_Equal_To_A_Const>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L29
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L55
  mov    %esi,%ecx
  movaps %xmm0,%xmm1
  mov    %rdi,%rax
  shr    $0x2,%ecx
  shufps $0x0,%xmm1,%xmm1
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  xchg   %ax,%ax
L50:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L50
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L63
L48:
  movslq %eax,%rcx
  lea    0x0(,%rcx,4),%rdi
  movss  %xmm0,(%rdx,%rcx,4)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jle    L29
  add    $0x2,%eax
  movss  %xmm0,0x4(%rdx,%rdi,1)
  cmp    %eax,%esi
  jle    L29
  movss  %xmm0,0x8(%rdx,%rdi,1)
L29:
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  ret
L55:
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
void RKMath_Set_Vec_Equal_To_A_Const(float vec[], const float const__, const int size) {
  int i = 0;
  while (i < size) {
    vec[i] = const__;
    i++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L37
L27:
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L32
  addl   $0x1,-0xc(%rbp)
L32:
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L27
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string

tool: D18: %d %d %d

tool: D3: %d

assistant: ```c
int main() {
  int i, l, r, k, count = 0;
  scanf("%d %d %d", &l, &r, &k);
  for (i = l; i <= r; i++) {
    if (i % k == 0)
      count++;
  }
  printf("%d", count);
  return 0;
}
```