user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D36(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D54(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%edi
  test   %edi,%edi
  jle    L85
  lea    0xac(%rsp),%r14
  mov    $0x1,%r13d
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r14,%rbp
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  movslq 0x18(%rsp),%rax
  cmp    %ebx,%eax
  jge    L40
  add    $0x1,%r13d
  add    $0x28,%r14
  cmp    %r13d,%eax
  jge    L5
  test   %eax,%eax
  jle    L85
  lea    0x0(,%rax,4),%rdx
  lea    0x24(%rsp),%rdi
  xor    %esi,%esi
  call   <memset@plt>
L85:
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %r12,%rdi
  lea    D41(%rip),%r13
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  movslq 0x1c(%rsp),%rax
  mov    %r13,%rdi
  mov    %eax,%esi
  movl   $0x1,0x20(%rsp,%rax,4)
  mov    %rax,%rbx
  mov    %eax,0x50(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%esi
  mov    $0x1,%eax
  lea    0x80(%rsp),%rcx
  mov    %rcx,0x8(%rsp)
  test   %esi,%esi
  jle    L62
  cs nopw 0x0(%rax,%rax,1)
L81:
  movslq %ebx,%rdx
  mov    0x8(%rsp),%rcx
  mov    $0x1,%ebx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rcx,%rdx,8),%r15
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L94:
  add    %r12d,%ebp
  add    $0x1,%rbx
  cmp    %ebx,0x18(%rsp)
  jl     L92
L1:
  mov    (%r15,%rbx,4),%ecx
  mov    %ebx,%ebp
  test   %ecx,%ecx
  je     L94
  mov    (%r14,%rbx,4),%edx
  test   %edx,%edx
  jne    L94
  mov    %ebx,0x50(%rsp,%rax,4)
  lea    0x1(%rax),%ecx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  movl   $0x1,(%r14,%rbx,4)
  add    %r12d,%ebp
  add    $0x1,%rbx
  mov    %ecx,0x4(%rsp)
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  cmp    %ebx,0x18(%rsp)
  jge    L1
L92:
  cmp    %eax,%ebp
  je     L100
L126:
  mov    0x18(%rsp),%esi
  movslq %ebp,%rdx
  mov    %ebp,%r12d
  mov    0x50(%rsp,%rdx,4),%ebx
  test   %esi,%esi
  jg     L81
L62:
  mov    %r12d,%ebp
  cmp    %eax,%ebp
  jne    L126
  nopl   0x0(%rax)
L100:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D36
data_type: string
name: extract_symbolic_data
arguments: data_tag: D54
data_type: string
name: extract_symbolic_data
arguments: data_tag: D40
data_type: string
name: extract_symbolic_data
arguments: data_tag: D20
data_type: string
name: extract_symbolic_data
arguments: data_tag: D41
data_type: string
name: extract_symbolic_data
arguments: data_tag: D25
data_type: string

tool: D36: Enter the number of vertices in the graph: 

tool: D54: %d

tool: D40: Enter the adjacency matrix:

tool: D20: Enter the source of the graph: 

tool: D41: %d 

tool: D25: The BFS traversal of graph is: 

assistant: ```c
int main() {
  int n, adj[10][10], i, j, visited[10], source, queue[10], front, rear, root;
  printf("Enter the number of vertices in the graph: ");
  scanf("%d", &n);
  printf("Enter the adjacency matrix:\n");
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      scanf("%d", &adj[i][j]);
    }
  }
  for (i = 1; i <= n; i++)
    visited[i] = 0;
  printf("Enter the source of the graph: ");
  scanf("%d", &source);
  printf("The BFS traversal of graph is: ");
  front = rear = 0;
  visited[source] = 1;
  queue[rear++] = source;
  printf("%d ", source);
  while (front != rear) {
    root = queue[front];
    for (i = 1; i <= n; i++) {
      if (adj[root][i] && !visited[i]) {
        visited[i] = 1;
        queue[rear++] = i;
        printf("%d ", i);
      }
      front++;
    }
  }
  return 0;
}
```