ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<test_vector>:
  endbr64
  push   %r14
  lea    -0x1(%rdx),%eax
  push   %r13
  lea    0x4(,%rax,4),%r14
  mov    %r9,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  nop
L39:
  xor    %ebx,%ebx
L46:
  test   %r12d,%r12d
  jle    L0
L22:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    %r14,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  movl   $0x0,0x0(,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jle    L39
  test   %r12d,%r12d
  jg     L22
L0:
  movl   $0x0,0x0(,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jle    L39
  jmp    L46
```

assistant: ```c
double test_vector(float **data, int rows, int cols, int vqrows, double epsilon, int maxiter, int **mean, int *map) {
  int i, j, r, it;
  double sqerr, prev_sqerr = 0, t;
  unsigned int *sel;
  int *count;
  for (it = 0;; it++) {
    if ((sqerr == 0.0) || (it >= maxiter - 1) || ((it > 0) && (((prev_sqerr - sqerr) / prev_sqerr) < epsilon)))
      for (i = 0; i < vqrows; i++) {
        for (j = 0; j < cols; j++)
          mean[i][j] = 0.0;
        count[i] = 0;
      }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f6c6c6568,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L19
L29:
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x14(%rbp,%rax,1)
  addl   $0x1,-0x24(%rbp)
L19:
  cmpl   $0x3,-0x24(%rbp)
  jle    L29
  movzbl -0x11(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %al,-0x25(%rbp)
  movsbl -0x25(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D17
type_infered: string
name: read_data
arguments: data_label: D9
type_infered: string

tool: D8: 
%c

tool: D17: manish

tool: D9: 
%d

assistant: ```c
main() {
  char ch, c[12] = "hello";
  char ch2[12];
  int i;
  for (i = 0; i < 4; i++) {
    ch2[i] = c[i];
  }
  printf("\n%c", ch2[3]);
  ch = puts("manish");
  printf("\n%d", ch);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x6c,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  movsbl %al,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type: string
name: disassemble_data
arguments: data_label: D13
type: string
name: disassemble_data
arguments: data_label: D22
type: string

tool: D26: 
%c

tool: D13: manish

tool: D22: 
%d

assistant: ```c
main() {
  char ch, c[12] = "hello";
  char ch2[12];
  int i;
  for (i = 0; i < 4; i++) {
    ch2[i] = c[i];
  }
  printf("\n%c", ch2[3]);
  ch = puts("manish");
  printf("\n%d", ch);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6c,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  movsbl %al,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D1
type_infered: string

tool: D5: 
%c

tool: D9: manish

tool: D1: 
%d

assistant: ```c
main() {
  char ch, c[12] = "hello";
  char ch2[12];
  int i;
  for (i = 0; i < 4; i++) {
    ch2[i] = c[i];
  }
  printf("\n%c", ch2[3]);
  ch = puts("manish");
  printf("\n%d", ch);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6c,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D2(%rip),%rdi
  movsbl %al,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_infered: string
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string
name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D14: 
%c

tool: D16: manish

tool: D2: 
%d

assistant: ```c
main() {
  char ch, c[12] = "hello";
  char ch2[12];
  int i;
  for (i = 0; i < 4; i++) {
    ch2[i] = c[i];
  }
  printf("\n%c", ch2[3]);
  ch = puts("manish");
  printf("\n%d", ch);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_alphabet_x10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x61,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L28:
  movb   $0x61,-0x5(%rbp)
  jmp    L5
L9:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <_putchar@plt>
  movzbl -0x5(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
L5:
  cmpb   $0x7a,-0x5(%rbp)
  jle    L9
  addl   $0x1,-0x4(%rbp)
  mov    $0xa,%edi
  call   <_putchar@plt>
L3:
  cmpl   $0x9,-0x4(%rbp)
  jle    L28
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_alphabet_x10(void) {
  char a = 'a';
  int temp = 0;
  while (temp <= 9) {
    a = 'a';
    while (a <= 'z') {
      _putchar(a);
      a++;
    }
    temp++;
    _putchar('\n');
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_alphabet_x10>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%ebp
L16:
  mov    $0x61,%ebx
L1:
  mov    %ebx,%edi
  call   <_putchar@plt>
  add    $0x1,%ebx
  cmp    $0x7b,%ebx
  jne    L1
  mov    $0xa,%edi
  call   <_putchar@plt>
  sub    $0x1,%ebp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void print_alphabet_x10(void) {
  char a = 'a';
  int temp = 0;
  while (temp <= 9) {
    a = 'a';
    while (a <= 'z') {
      _putchar(a);
      a++;
    }
    temp++;
    _putchar('\n');
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_alphabet_x10>:
  endbr64
  push   %rbp
  mov    $0xa,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nop
L12:
  mov    $0x61,%ebx
  nopl   (%rax)
L4:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <_putchar@plt>
  cmp    $0x7b,%ebx
  jne    L4
  mov    $0xa,%edi
  call   <_putchar@plt>
  sub    $0x1,%ebp
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void print_alphabet_x10(void) {
  char a = 'a';
  int temp = 0;
  while (temp <= 9) {
    a = 'a';
    while (a <= 'z') {
      _putchar(a);
      a++;
    }
    temp++;
    _putchar('\n');
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_alphabet_x10>:
  endbr64
  push   %rbp
  mov    $0xa,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nop
L1:
  mov    $0x61,%ebx
  nopl   (%rax)
L4:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <_putchar@plt>
  cmp    $0x7b,%ebx
  jne    L4
  mov    $0xa,%edi
  call   <_putchar@plt>
  sub    $0x1,%ebp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void print_alphabet_x10(void) {
  char a = 'a';
  int temp = 0;
  while (temp <= 9) {
    a = 'a';
    while (a <= 'z') {
      _putchar(a);
      a++;
    }
    temp++;
    _putchar('\n');
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<files_get_filename_in_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L26
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L26:
  mov    -0x18(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L37
  mov    -0x18(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L37:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *files_get_filename_in_path(char *path) {
  char *filename;
  if (strrchr(path, '/')) {
    filename = strrchr(path, '/') + 1;
  } else if (strrchr(path, '\\')) {
    filename = strrchr(path, '\\') + 1;
  } else {
    filename = path;
  }
  return filename;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<files_get_filename_in_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L19
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  add    $0x1,%rax
L6:
  pop    %rbx
  ret
L19:
  mov    $0x5c,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  test   %rdx,%rdx
  je     L6
  mov    $0x5c,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  add    $0x1,%rax
  jmp    L6
```

assistant: ```c
char *files_get_filename_in_path(char *path) {
  char *filename;
  if (strrchr(path, '/')) {
    filename = strrchr(path, '/') + 1;
  } else if (strrchr(path, '\\')) {
    filename = strrchr(path, '\\') + 1;
  } else {
    filename = path;
  }
  return filename;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<files_get_filename_in_path>:
  endbr64
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L2
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  add    $0x1,%rax
L10:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x5c,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  mov    %rax,%r8
  mov    %rbp,%rax
  test   %r8,%r8
  je     L10
  mov    %rbp,%rdi
  mov    $0x5c,%esi
  call   <strrchr@plt>
  pop    %rbp
  add    $0x1,%rax
  ret
```

assistant: ```c
char *files_get_filename_in_path(char *path) {
  char *filename;
  if (strrchr(path, '/')) {
    filename = strrchr(path, '/') + 1;
  } else if (strrchr(path, '\\')) {
    filename = strrchr(path, '\\') + 1;
  } else {
    filename = path;
  }
  return filename;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<files_get_filename_in_path>:
  endbr64
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L19
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  add    $0x1,%rax
L5:
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0x5c,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  mov    %rax,%r8
  mov    %rbp,%rax
  test   %r8,%r8
  je     L5
  mov    %rbp,%rdi
  mov    $0x5c,%esi
  call   <strrchr@plt>
  pop    %rbp
  add    $0x1,%rax
  ret
```

assistant: ```c
char *files_get_filename_in_path(char *path) {
  char *filename;
  if (strrchr(path, '/')) {
    filename = strrchr(path, '/') + 1;
  } else if (strrchr(path, '\\')) {
    filename = strrchr(path, '\\') + 1;
  } else {
    filename = path;
  }
  return filename;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dollar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x1,%edx
  mov    $0x30,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fexpect@plt>
  movl   $0x2,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x2,%edx
  mov    $0x32,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fexpect@plt>
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x3,%edx
  mov    $0x34,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fexpect@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c

assistant: ```c
void dollar() {
  int $ = 1;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 48, 1, $);
  ;
  int $2 = 2;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 50, 2, $2);
  ;
  int a$ = 3;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 52, 3, a$);
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dollar>:
  endbr64
  push   %rbx
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x30,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fexpect@plt>
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0x32,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fexpect@plt>
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x34,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fexpect@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c

assistant: ```c
void dollar() {
  int $ = 1;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 48, 1, $);
  ;
  int $2 = 2;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 50, 2, $2);
  ;
  int a$ = 3;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 52, 3, a$);
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dollar>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0x1,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x30,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x2,%ecx
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    $0x32,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x3,%ecx
  xor    %eax,%eax
  mov    $0x3,%edx
  mov    $0x34,%esi
  pop    %rbp
  jmp    1050 <fexpect@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c

assistant: ```c
void dollar() {
  int $ = 1;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 48, 1, $);
  ;
  int $2 = 2;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 50, 2, $2);
  ;
  int a$ = 3;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 52, 3, a$);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dollar>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    $0x1,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x30,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x2,%ecx
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    $0x32,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x3,%ecx
  xor    %eax,%eax
  mov    $0x3,%edx
  mov    $0x34,%esi
  pop    %rbp
  jmp    1050 <fexpect@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c

assistant: ```c
void dollar() {
  int $ = 1;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 48, 1, $);
  ;
  int $2 = 2;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 50, 2, $2);
  ;
  int a$ = 3;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 52, 3, a$);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  mov    $0x1,%eax
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jnp    L30
  mov    $0x0,%eax
L30:
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%eax
  movss  -0x8(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jnp    L3
  mov    $0x0,%eax
L3:
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jb     L39
  movss  -0x4(%rbp),%xmm0
  jmp    L23
L39:
  movss  -0x8(%rbp),%xmm0
L23:
  leave
  ret
```

assistant: ```c
float max(float x, float y) {
  assert(x == x);
  assert(y == y);
  return (x >= y) ? x : y;
}
```
user: What is the c source code of the assembly code below:

```asm
<max>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm0,0xc(%rsp)
  ucomiss %xmm0,%xmm0
  setnp  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movss  0x8(%rsp),%xmm5
  ucomiss %xmm5,%xmm5
  setnp  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movss  0x8(%rsp),%xmm3
  movaps %xmm3,%xmm4
  movss  0xc(%rsp),%xmm2
  cmpless %xmm2,%xmm4
  movaps %xmm4,%xmm0
  movaps %xmm2,%xmm1
  andps  %xmm4,%xmm1
  andnps %xmm3,%xmm0
  orps   %xmm1,%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
float max(float x, float y) {
  assert(x == x);
  assert(y == y);
  return (x >= y) ? x : y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max>:
  endbr64
  sub    $0x18,%rsp
  ucomiss %xmm0,%xmm0
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  setnp  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movss  0x8(%rsp),%xmm1
  xor    %edi,%edi
  ucomiss %xmm1,%xmm1
  setnp  %dil
  call   <assert@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  movaps %xmm1,%xmm2
  cmpless %xmm0,%xmm2
  andps  %xmm2,%xmm0
  andnps %xmm1,%xmm2
  orps   %xmm2,%xmm0
  ret
```

assistant: ```c
float max(float x, float y) {
  assert(x == x);
  assert(y == y);
  return (x >= y) ? x : y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<max>:
  endbr64
  sub    $0x18,%rsp
  ucomiss %xmm0,%xmm0
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  setnp  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movss  0x8(%rsp),%xmm1
  xor    %edi,%edi
  ucomiss %xmm1,%xmm1
  setnp  %dil
  call   <assert@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  movaps %xmm1,%xmm2
  cmpless %xmm0,%xmm2
  andps  %xmm2,%xmm0
  andnps %xmm1,%xmm2
  orps   %xmm2,%xmm0
  ret
```

assistant: ```c
float max(float x, float y) {
  assert(x == x);
  assert(y == y);
  return (x >= y) ? x : y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swi10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L17:
  cmpl   $0x9,-0x4(%rbp)
  ja     L124
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D8(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
  addl   $0x1,-0x14(%rbp)
  jmp    L120
L124:
  subl   $0x1,-0x14(%rbp)
  nop
L120:
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x9,-0x4(%rbp)
  jle    L17
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int swi10(int c) {
  int i;
  for (i = 0; i < 10; i++) {
    switch (i) {
    case 0:
      c++;
      break;
    case 1:
      c++;
      break;
    case 2:
      c++;
      break;
    case 3:
      c++;
      break;
    case 4:
      c++;
      break;
    case 5:
      c++;
      break;
    case 6:
      c++;
      break;
    case 7:
      c++;
      break;
    case 8:
      c++;
      break;
    case 9:
      c++;
      break;
    default:
      c--;
      break;
    }
  }
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swi10>:
  endbr64
  mov    $0x1,%ecx
  lea    D2(%rip),%rax
  jmp    L114
  add    $0x1,%edi
  jmp    L115
  add    $0x1,%edi
  jmp    L115
  add    $0x1,%edi
  jmp    L115
  add    $0x1,%edi
  jmp    L115
  add    $0x1,%edi
  jmp    L115
  add    $0x1,%edi
  jmp    L115
  add    $0x1,%edi
  jmp    L115
  add    $0x1,%edi
  jmp    L115
  add    $0x1,%edi
  jmp    L115
  lea    0x1(%rdi),%eax
  ret
L105:
  sub    $0x1,%edi
  cmp    $0x9,%ecx
  jg     L62
L115:
  add    $0x1,%ecx
L114:
  lea    -0x1(%rcx),%edx
  cmp    $0x9,%edx
  ja     L105
  mov    %edx,%edx
  movslq (%rax,%rdx,4),%rdx
  add    %rax,%rdx
  notrack jmp *%rdx
L62:
  mov    %edi,%eax
  ret
```

assistant: ```c
int swi10(int c) {
  int i;
  for (i = 0; i < 10; i++) {
    switch (i) {
    case 0:
      c++;
      break;
    case 1:
      c++;
      break;
    case 2:
      c++;
      break;
    case 3:
      c++;
      break;
    case 4:
      c++;
      break;
    case 5:
      c++;
      break;
    case 6:
      c++;
      break;
    case 7:
      c++;
      break;
    case 8:
      c++;
      break;
    case 9:
      c++;
      break;
    default:
      c--;
      break;
    }
  }
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swi10>:
  endbr64
  lea    0x1(%rdi),%r8d
  mov    $0x1,%edx
  jmp    L20
  nop
L1:
  add    $0x1,%r8d
  add    $0x1,%edx
L20:
  lea    -0x1(%rdx),%eax
  cmp    $0x8,%eax
  ja     L28
  test   %eax,%eax
  jne    L1
L32:
  cmp    $0xa,%edx
  jne    L1
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L28:
  cmp    $0x9,%eax
  jne    L32
L50:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int swi10(int c) {
  int i;
  for (i = 0; i < 10; i++) {
    switch (i) {
    case 0:
      c++;
      break;
    case 1:
      c++;
      break;
    case 2:
      c++;
      break;
    case 3:
      c++;
      break;
    case 4:
      c++;
      break;
    case 5:
      c++;
      break;
    case 6:
      c++;
      break;
    case 7:
      c++;
      break;
    case 8:
      c++;
      break;
    case 9:
      c++;
      break;
    default:
      c--;
      break;
    }
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swi10>:
  endbr64
  lea    0xa(%rdi),%eax
  ret
```

assistant: ```c
int swi10(int c) {
  int i;
  for (i = 0; i < 10; i++) {
    switch (i) {
    case 0:
      c++;
      break;
    case 1:
      c++;
      break;
    case 2:
      c++;
      break;
    case 3:
      c++;
      break;
    case 4:
      c++;
      break;
    case 5:
      c++;
      break;
    case 6:
      c++;
      break;
    case 7:
      c++;
      break;
    case 8:
      c++;
      break;
    case 9:
      c++;
      break;
    default:
      c--;
      break;
    }
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    -0x20(%rbp),%rcx
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%rcx
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int process(int a, int b, int (*fun)(int a, int b)) {
  int result;
  result = (*fun)(a, b);
  return result;
}
```