ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<bad_arg>:
  endbr64
  add    $0x1,%esi
  cmp    %ecx,%esi
  je     L25
  ret
  nopl   0x0(%rax)
L25:
  push   %r12
  mov    %rdi,%r12
  lea    D0(%rip),%rdi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  call   <printf@plt>
  test   %ebp,%ebp
  js     L10
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <free@plt>
  cmp    %ebx,%ebp
  jge    L3
L10:
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0:  not enough args


assistant: ```c
void bad_arg(char **arguments, int c, int d, int argcc) {
  int e = 0;
  if (c + 1 == argcc) {
    printf(" not enough args\n");
    while (e < d + 1)
      free(arguments[e++]);
    exit(0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bad_arg>:
  endbr64
  add    $0x1,%esi
  cmp    %ecx,%esi
  je     L28
  ret
  nopl   0x0(%rax)
L28:
  push   %r12
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  call   <printf@plt>
  test   %ebp,%ebp
  js     L16
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L15:
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <free@plt>
  cmp    %ebx,%ebp
  jge    L15
L16:
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7:  not enough args


assistant: ```c
void bad_arg(char **arguments, int c, int d, int argcc) {
  int e = 0;
  if (c + 1 == argcc) {
    printf(" not enough args\n");
    while (e < d + 1)
      free(arguments[e++]);
    exit(0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverseASentence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <reverseAWord@plt>
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L23
L28:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L3
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
L3:
  mov    -0x20(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <reverseAWord@plt>
  addq   $0x1,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L4
L15:
  addl   $0x1,-0x20(%rbp)
L4:
  addl   $0x1,-0x24(%rbp)
  addq   $0x1,-0x18(%rbp)
L23:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L28
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverseASentence(char *string) {
  int strLen = strlen(string);
  char *end = string;
  char *start = string;
  char *traversePtr = string;
  end = end + (strLen - 1);
  reverseAWord(start, end);
  int count = 0;
  int singleWordLen = 0;
  while (count < strLen) {
    if (*(traversePtr + 1) == ' ' || *(traversePtr + 1) == '\0') {
      reverseAWord(traversePtr - singleWordLen, traversePtr);
      traversePtr++;
      singleWordLen = 0;
    } else {
      singleWordLen++;
    }
    count++;
    traversePtr++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverseASentence>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  cltq
  lea    -0x1(%rbx,%rax,1),%rsi
  mov    %rbx,%rdi
  call   <reverseAWord@plt>
  test   %r12d,%r12d
  jle    L45
  mov    $0x0,%eax
  mov    $0x0,%ebp
  jmp    L11
L46:
  add    $0x1,%eax
L1:
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r12d
  je     L45
L11:
  testb  $0xdf,0x1(%rbx)
  jne    L46
  cltq
  mov    %rbx,%rdi
  sub    %rax,%rdi
  mov    %rbx,%rsi
  call   <reverseAWord@plt>
  add    $0x1,%rbx
  mov    $0x0,%eax
  jmp    L1
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void reverseASentence(char *string) {
  int strLen = strlen(string);
  char *end = string;
  char *start = string;
  char *traversePtr = string;
  end = end + (strLen - 1);
  reverseAWord(start, end);
  int count = 0;
  int singleWordLen = 0;
  while (count < strLen) {
    if (*(traversePtr + 1) == ' ' || *(traversePtr + 1) == '\0') {
      reverseAWord(traversePtr - singleWordLen, traversePtr);
      traversePtr++;
      singleWordLen = 0;
    } else {
      singleWordLen++;
    }
    count++;
    traversePtr++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverseASentence>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  cltq
  lea    -0x1(%rbp,%rax,1),%rsi
  call   <reverseAWord@plt>
  test   %r12d,%r12d
  jle    L32
  xor    %eax,%eax
  xor    %ebx,%ebx
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%ebx
  add    $0x1,%eax
  add    $0x1,%rbp
  cmp    %ebx,%r12d
  je     L32
L46:
  testb  $0xdf,0x1(%rbp)
  jne    L28
  cltq
  mov    %rbp,%rdi
  lea    0x1(%rbp),%r13
  mov    %rbp,%rsi
  sub    %rax,%rdi
  mov    %r13,%rbp
  add    $0x1,%ebx
  call   <reverseAWord@plt>
  add    $0x1,%rbp
  xor    %eax,%eax
  cmp    %ebx,%r12d
  jne    L46
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void reverseASentence(char *string) {
  int strLen = strlen(string);
  char *end = string;
  char *start = string;
  char *traversePtr = string;
  end = end + (strLen - 1);
  reverseAWord(start, end);
  int count = 0;
  int singleWordLen = 0;
  while (count < strLen) {
    if (*(traversePtr + 1) == ' ' || *(traversePtr + 1) == '\0') {
      reverseAWord(traversePtr - singleWordLen, traversePtr);
      traversePtr++;
      singleWordLen = 0;
    } else {
      singleWordLen++;
    }
    count++;
    traversePtr++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverseASentence>:
  endbr64
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  cltq
  lea    -0x1(%rbx,%rax,1),%rsi
  call   <reverseAWord@plt>
  xor    %eax,%eax
  test   %r12d,%r12d
  jle    L12
  nopl   0x0(%rax,%rax,1)
L48:
  testb  $0xdf,0x1(%rbx)
  je     L32
  add    $0x1,%ebp
  add    $0x1,%eax
  add    $0x1,%rbx
  cmp    %ebp,%r12d
  jne    L48
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  cltq
  mov    %rbx,%rdi
  mov    %rbx,%rsi
  add    $0x1,%ebp
  sub    %rax,%rdi
  add    $0x2,%rbx
  call   <reverseAWord@plt>
  cmp    %ebp,%r12d
  je     L12
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
void reverseASentence(char *string) {
  int strLen = strlen(string);
  char *end = string;
  char *start = string;
  char *traversePtr = string;
  end = end + (strLen - 1);
  reverseAWord(start, end);
  int count = 0;
  int singleWordLen = 0;
  while (count < strLen) {
    if (*(traversePtr + 1) == ' ' || *(traversePtr + 1) == '\0') {
      reverseAWord(traversePtr - singleWordLen, traversePtr);
      traversePtr++;
      singleWordLen = 0;
    } else {
      singleWordLen++;
    }
    count++;
    traversePtr++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  D41(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L3
L14:
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movsd  D62(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  D6(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L3:
  movsd  D25(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  ja     L14
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D41
type: f64
name: disassemble_data
arguments: tag: D56
type: string
name: disassemble_data
arguments: tag: D17
type: f64
name: disassemble_data
arguments: tag: D62
type: f64
name: disassemble_data
arguments: tag: D78
type: string
name: disassemble_data
arguments: tag: D6
type: byte[8]
name: disassemble_data
arguments: tag: D25
type: f64
name: disassemble_data
arguments: tag: D65
type: string

tool: D41: 0.333

tool: D56: Shoe size (men's)	foot length

tool: D17: 3

tool: D62: 7.31

tool: D78: %10.1f %18.2f inches


tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D25: 18.5

tool: D65: If the shoe fits, wear it.

assistant: ```c
int main(void) {
  const double SCALE = 0.333;
  double shoe, foot;
  printf("Shoe size (men's)	foot length\n");
  shoe = 3.0;
  while (shoe < 18.5) {
    foot = SCALE * shoe + 7.31;
    printf("%10.1f %18.2f inches\n", shoe, foot);
    shoe = shoe + 1;
  }
  printf("If the shoe fits, wear it.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x10,%ebx
  movsd  D57(%rip),%xmm4
  movsd  %xmm4,0x8(%rsp)
  lea    D43(%rip),%rbp
L4:
  movsd  D31(%rip),%xmm1
  movsd  0x8(%rsp),%xmm2
  mulsd  %xmm2,%xmm1
  addsd  D13(%rip),%xmm1
  movapd %xmm2,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  D55(%rip),%xmm3
  addsd  0x8(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L4
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D57
data_type: f64
name: unpack_data
arguments: data_tag: D43
data_type: string
name: unpack_data
arguments: data_tag: D31
data_type: f64
name: unpack_data
arguments: data_tag: D13
data_type: f64
name: unpack_data
arguments: data_tag: D55
data_type: byte[8]
name: unpack_data
arguments: data_tag: D38
data_type: string

tool: D10: Shoe size (men's)	foot length

tool: D57: 3

tool: D43: %10.1f %18.2f inches


tool: D31: 0.333

tool: D13: 7.31

tool: {"D55": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D38: If the shoe fits, wear it.

assistant: ```c
int main(void) {
  const double SCALE = 0.333;
  double shoe, foot;
  printf("Shoe size (men's)	foot length\n");
  shoe = 3.0;
  while (shoe < 18.5) {
    foot = SCALE * shoe + 7.31;
    printf("%10.1f %18.2f inches\n", shoe, foot);
    shoe = shoe + 1;
  }
  printf("If the shoe fits, wear it.\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  lea    D39(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  movsd  D25(%rip),%xmm0
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  D55(%rip),%xmm1
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm1
  addsd  D66(%rip),%xmm1
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  addsd  D8(%rip),%xmm0
  sub    $0x1,%ebx
  jne    L2
  lea    D19(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D38
type_infered: string
name: disassemble_data
arguments: tag: D39
type_infered: string
name: disassemble_data
arguments: tag: D25
type_infered: f64
name: disassemble_data
arguments: tag: D55
type_infered: f64
name: disassemble_data
arguments: tag: D66
type_infered: f64
name: disassemble_data
arguments: tag: D8
type_infered: byte[8]
name: disassemble_data
arguments: tag: D19
type_infered: string

tool: D38: Shoe size (men's)	foot length

tool: D39: %10.1f %18.2f inches


tool: D25: 3

tool: D55: 0.333

tool: D66: 7.31

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D19: If the shoe fits, wear it.

assistant: ```c
int main(void) {
  const double SCALE = 0.333;
  double shoe, foot;
  printf("Shoe size (men's)	foot length\n");
  shoe = 3.0;
  while (shoe < 18.5) {
    foot = SCALE * shoe + 7.31;
    printf("%10.1f %18.2f inches\n", shoe, foot);
    shoe = shoe + 1;
  }
  printf("If the shoe fits, wear it.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D66(%rip),%rdi
  lea    D58(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  movsd  D13(%rip),%xmm0
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  D52(%rip),%xmm1
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm1
  addsd  D56(%rip),%xmm1
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  addsd  D57(%rip),%xmm0
  sub    $0x1,%ebx
  jne    L2
  lea    D27(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D66
type_infered: string
name: parse_data
arguments: tag: D58
type_infered: string
name: parse_data
arguments: tag: D13
type_infered: f64
name: parse_data
arguments: tag: D52
type_infered: f64
name: parse_data
arguments: tag: D56
type_infered: f64
name: parse_data
arguments: tag: D57
type_infered: byte[8]
name: parse_data
arguments: tag: D27
type_infered: string

tool: D66: Shoe size (men's)	foot length

tool: D58: %10.1f %18.2f inches


tool: D13: 3

tool: D52: 0.333

tool: D56: 7.31

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D27: If the shoe fits, wear it.

assistant: ```c
int main(void) {
  const double SCALE = 0.333;
  double shoe, foot;
  printf("Shoe size (men's)	foot length\n");
  shoe = 3.0;
  while (shoe < 18.5) {
    foot = SCALE * shoe + 7.31;
    printf("%10.1f %18.2f inches\n", shoe, foot);
    shoe = shoe + 1;
  }
  printf("If the shoe fits, wear it.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writememb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <wait@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <writememb_common@plt>
  nop
  leave
  ret
```

assistant: ```c
void writememb(uint32_t s, uint32_t a, uint8_t v) {
  wait(4, 1);
  writememb_common(s + a, v);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<writememb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <wait@plt>
  lea    (%rbx,%r12,1),%rdi
  mov    %ebp,%esi
  call   <writememb_common@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void writememb(uint32_t s, uint32_t a, uint8_t v) {
  wait(4, 1);
  writememb_common(s + a, v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<writememb>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x1,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <wait@plt>
  lea    (%rbx,%r12,1),%rdi
  mov    %ebp,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <writememb_common@plt>
```

assistant: ```c
void writememb(uint32_t s, uint32_t a, uint8_t v) {
  wait(4, 1);
  writememb_common(s + a, v);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<writememb>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x1,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <wait@plt>
  lea    (%rbx,%r12,1),%rdi
  mov    %ebp,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <writememb_common@plt>
```

assistant: ```c
void writememb(uint32_t s, uint32_t a, uint8_t v) {
  wait(4, 1);
  writememb_common(s + a, v);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fa_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fa_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L12:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *fa_strdup(const char *s) {
  char *ptr = NULL;
  if (s) {
    int len = strlen(s) + 1;
    ptr = fa_malloc(len);
    if (ptr)
      memcpy(ptr, s, len);
  }
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fa_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L17
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <fa_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L17
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L17:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *fa_strdup(const char *s) {
  char *ptr = NULL;
  if (s) {
    int len = strlen(s) + 1;
    ptr = fa_malloc(len);
    if (ptr)
      memcpy(ptr, s, len);
  }
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fa_strdup>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  test   %rdi,%rdi
  je     L17
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <fa_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L17:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *fa_strdup(const char *s) {
  char *ptr = NULL;
  if (s) {
    int len = strlen(s) + 1;
    ptr = fa_malloc(len);
    if (ptr)
      memcpy(ptr, s, len);
  }
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fa_strdup>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  test   %rdi,%rdi
  je     L8
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <fa_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L8:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *fa_strdup(const char *s) {
  char *ptr = NULL;
  if (s) {
    int len = strlen(s) + 1;
    ptr = fa_malloc(len);
    if (ptr)
      memcpy(ptr, s, len);
  }
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mk20dx256_uart0_put_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  nop
L7:
  mov    $0x4006a004,%eax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L7
  mov    $0x4006a007,%edx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mk20dx256_uart0_put_char(unsigned char c) {
  while (!(*((volatile unsigned char *)0x4006A004) & (1 << 7)))
    ;
  *((volatile unsigned char *)0x4006A007) = c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mk20dx256_uart0_put_char>:
  endbr64
L4:
  movzbl 0x4006a004,%eax
  test   %al,%al
  jns    L4
  mov    %dil,0x4006a007
  ret
```

assistant: ```c
void mk20dx256_uart0_put_char(unsigned char c) {
  while (!(*((volatile unsigned char *)0x4006A004) & (1 << 7)))
    ;
  *((volatile unsigned char *)0x4006A007) = c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mk20dx256_uart0_put_char>:
  endbr64
  nopl   0x0(%rax)
L5:
  movzbl 0x4006a004,%eax
  test   %al,%al
  jns    L5
  mov    %dil,0x4006a007
  ret
```

assistant: ```c
void mk20dx256_uart0_put_char(unsigned char c) {
  while (!(*((volatile unsigned char *)0x4006A004) & (1 << 7)))
    ;
  *((volatile unsigned char *)0x4006A007) = c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mk20dx256_uart0_put_char>:
  endbr64
  nopl   0x0(%rax)
L0:
  movzbl 0x4006a004,%eax
  test   %al,%al
  jns    L0
  mov    %dil,0x4006a007
  ret
```

assistant: ```c
void mk20dx256_uart0_put_char(unsigned char c) {
  while (!(*((volatile unsigned char *)0x4006A004) & (1 << 7)))
    ;
  *((volatile unsigned char *)0x4006A007) = c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_indent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  mov    $0x20,%edx
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: %*c

assistant: ```c
void print_indent(int depth) {
  if (depth > 0) {
    printf("%*c", depth * 2, ' ');
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_indent>:
  endbr64
  test   %edi,%edi
  jg     L9
  ret
L9:
  sub    $0x8,%rsp
  lea    (%rdi,%rdi,1),%esi
  mov    $0x20,%edx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: %*c

assistant: ```c
void print_indent(int depth) {
  if (depth > 0) {
    printf("%*c", depth * 2, ' ');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_indent>:
  endbr64
  test   %edi,%edi
  jg     L2
  ret
  nopl   0x0(%rax)
L2:
  lea    (%rdi,%rdi,1),%esi
  mov    $0x20,%edx
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: %*c

assistant: ```c
void print_indent(int depth) {
  if (depth > 0) {
    printf("%*c", depth * 2, ' ');
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_indent>:
  endbr64
  test   %edi,%edi
  jg     L7
  ret
  nopl   0x0(%rax)
L7:
  lea    (%rdi,%rdi,1),%esi
  mov    $0x20,%edx
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: %*c

assistant: ```c
void print_indent(int depth) {
  if (depth > 0) {
    printf("%*c", depth * 2, ' ');
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_uri_scheme_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x3a,%eax
  seta   %dl
  test   %dl,%dl
  jne    L21
  movabs $0x400680000000000,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L21
  mov    $0x1,%eax
  jmp    L2
L21:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_alpha@plt>
  test   %eax,%eax
  jne    L24
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_digit@plt>
  test   %eax,%eax
  je     L40
L24:
  mov    $0x1,%eax
  jmp    L2
L40:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
bool is_uri_scheme_char(const int c) {
  switch (c) {
  case ':':
  case '+':
  case '-':
  case '.':
    return true;
  default:
    return is_alpha(c) || is_digit(c);
  }
}
```