ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<aes_cbc_block_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x5c(%rbp)
  mov    %r8d,-0x60(%rbp)
  mov    %r9,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L7:
  cmp    %rdx,%rsp
  je     L37
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L37:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L19
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L19:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x5c(%rbp),%edx
  mov    -0x50(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x5c(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  lea    -0x3c(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <AES_set_encrypt_key@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%r8d
  mov    -0x30(%rbp),%rdi
  lea    -0x3c(%rbp),%rcx
  mov    -0x60(%rbp),%edx
  mov    -0x68(%rbp),%rsi
  mov    -0x58(%rbp),%rax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <AES_cbc_encrypt@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void aes_cbc_block_encrypt(const unsigned char *key, const unsigned char *iv, const unsigned char *text, int blen, int tlen, unsigned char *cipher) {
  unsigned char iv_cpy[blen];
  memcpy(iv_cpy, iv, blen);
  AES_KEY key_ctx;
  AES_set_encrypt_key(key, blen * 8, &key_ctx);
  AES_cbc_encrypt(text, cipher, tlen, &key_ctx, iv_cpy, AES_ENCRYPT);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aes_cbc_block_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,%ebx
  mov    %r8d,%r13d
  mov    %r9,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L2:
  cmp    %rdx,%rsp
  je     L17
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L2
L17:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L9
  orq    $0x0,-0x8(%rsp,%rax,1)
L9:
  mov    %ebx,%edx
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    -0x3c(%rbp),%r15
  lea    0x0(,%rbx,8),%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  call   <AES_set_encrypt_key@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%r9d
  mov    %rsp,%r8
  mov    %r15,%rcx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    -0x48(%rbp),%rdi
  call   <AES_cbc_encrypt@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_cbc_block_encrypt(const unsigned char *key, const unsigned char *iv, const unsigned char *text, int blen, int tlen, unsigned char *cipher) {
  unsigned char iv_cpy[blen];
  memcpy(iv_cpy, iv, blen);
  AES_KEY key_ctx;
  AES_set_encrypt_key(key, blen * 8, &key_ctx);
  AES_cbc_encrypt(text, cipher, tlen, &key_ctx, iv_cpy, AES_ENCRYPT);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aes_cbc_block_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L22
L1:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L1
L22:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L17
L13:
  mov    %ebx,%edx
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    -0x3c(%rbp),%rcx
  lea    0x0(,%rbx,8),%esi
  mov    %r15,%rdi
  mov    %rcx,%rdx
  mov    %rcx,-0x48(%rbp)
  call   <AES_set_encrypt_key@plt>
  mov    -0x48(%rbp),%rcx
  mov    %rsp,%r8
  mov    %r14d,%edx
  mov    D9(%rip),%rax
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    (%rax),%r9d
  call   <AES_cbc_encrypt@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L17:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L13
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_cbc_block_encrypt(const unsigned char *key, const unsigned char *iv, const unsigned char *text, int blen, int tlen, unsigned char *cipher) {
  unsigned char iv_cpy[blen];
  memcpy(iv_cpy, iv, blen);
  AES_KEY key_ctx;
  AES_set_encrypt_key(key, blen * 8, &key_ctx);
  AES_cbc_encrypt(text, cipher, tlen, &key_ctx, iv_cpy, AES_ENCRYPT);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aes_cbc_block_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L21
L39:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L39
L21:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L30
L17:
  mov    %ebx,%edx
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    -0x3c(%rbp),%rcx
  lea    0x0(,%rbx,8),%esi
  mov    %r15,%rdi
  mov    %rcx,%rdx
  mov    %rcx,-0x48(%rbp)
  call   <AES_set_encrypt_key@plt>
  mov    -0x48(%rbp),%rcx
  mov    %rsp,%r8
  mov    %r14d,%edx
  mov    D3(%rip),%rax
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    (%rax),%r9d
  call   <AES_cbc_encrypt@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L30:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L17
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_cbc_block_encrypt(const unsigned char *key, const unsigned char *iv, const unsigned char *text, int blen, int tlen, unsigned char *cipher) {
  unsigned char iv_cpy[blen];
  memcpy(iv_cpy, iv, blen);
  AES_KEY key_ctx;
  AES_set_encrypt_key(key, blen * 8, &key_ctx);
  AES_cbc_encrypt(text, cipher, tlen, &key_ctx, iv_cpy, AES_ENCRYPT);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x5,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x9,%eax
  leave
  ret
```

assistant: ```c
int foo(int a, int b) {
  assert(a == 3);
  assert(b == 5);
  return 9;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x3,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x5,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x9,%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo(int a, int b) {
  assert(a == 3);
  assert(b == 5);
  return 9;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbx
  cmp    $0x3,%edi
  mov    %esi,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x5,%ebx
  sete   %dil
  call   <assert@plt>
  mov    $0x9,%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo(int a, int b) {
  assert(a == 3);
  assert(b == 5);
  return 9;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %rbx
  cmp    $0x3,%edi
  mov    %esi,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x5,%ebx
  sete   %dil
  call   <assert@plt>
  mov    $0x9,%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo(int a, int b) {
  assert(a == 3);
  assert(b == 5);
  return 9;
}
```
user: What is the c source code of the assembly code below:

```asm
<socket_listen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <w5100_readSnSR@plt>
  cmp    $0x13,%eax
  je     L16
  mov    $0x0,%eax
  jmp    L4
L16:
  mov    -0x4(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <w5100_socket_cmd@plt>
  mov    $0x1,%eax
L4:
  leave
  ret
```

assistant: ```c
unsigned socket_listen(unsigned sock) {
  if (w5100_readSnSR(sock) != 0x13)
    return 0;
  w5100_socket_cmd(sock, 0x02);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<socket_listen>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <w5100_readSnSR@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x13,%edx
  je     L4
L12:
  pop    %rbx
  ret
L4:
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <w5100_socket_cmd@plt>
  mov    $0x1,%eax
  jmp    L12
```

assistant: ```c
unsigned socket_listen(unsigned sock) {
  if (w5100_readSnSR(sock) != 0x13)
    return 0;
  w5100_socket_cmd(sock, 0x02);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<socket_listen>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <w5100_readSnSR@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x13,%r8d
  je     L8
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  mov    %ebp,%edi
  mov    $0x2,%esi
  call   <w5100_socket_cmd@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned socket_listen(unsigned sock) {
  if (w5100_readSnSR(sock) != 0x13)
    return 0;
  w5100_socket_cmd(sock, 0x02);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<socket_listen>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <w5100_readSnSR@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x13,%r8d
  je     L0
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  mov    %ebp,%edi
  mov    $0x2,%esi
  call   <w5100_socket_cmd@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned socket_listen(unsigned sock) {
  if (w5100_readSnSR(sock) != 0x13)
    return 0;
  w5100_socket_cmd(sock, 0x02);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<set_ticker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x40(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x3e8,%rax,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <setitimer@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int set_ticker(int n_msec) {
  struct itimerval timeset;
  long n_sec, n_usec;
  n_sec = n_msec / 1000;
  n_usec = (n_msec % 1000) * 1000L;
  timeset.it_interval.tv_sec = n_sec;
  timeset.it_interval.tv_usec = n_usec;
  timeset.it_value.tv_sec = n_sec;
  timeset.it_value.tv_usec = n_usec;
  return setitimer(ITIMER_REAL, &timeset, NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<set_ticker>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rdi
  imul   $0x3e8,%rdi,%rdi
  mov    %rdx,0x10(%rsp)
  mov    %rdi,0x18(%rsp)
  mov    %rdx,(%rsp)
  mov    %rdi,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_ticker(int n_msec) {
  struct itimerval timeset;
  long n_sec, n_usec;
  n_sec = n_msec / 1000;
  n_usec = (n_msec % 1000) * 1000L;
  timeset.it_interval.tv_sec = n_sec;
  timeset.it_interval.tv_usec = n_usec;
  timeset.it_value.tv_sec = n_sec;
  timeset.it_value.tv_usec = n_usec;
  return setitimer(ITIMER_REAL, &timeset, NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_ticker>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  mov    %rsp,%rsi
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x3e8,%eax,%eax
  mov    %rdx,0x10(%rsp)
  mov    %rdx,(%rsp)
  xor    %edx,%edx
  sub    %eax,%edi
  mov    D2(%rip),%rax
  movslq %edi,%rdi
  imul   $0x3e8,%rdi,%rdi
  mov    %rdi,0x18(%rsp)
  mov    %rdi,0x8(%rsp)
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_ticker(int n_msec) {
  struct itimerval timeset;
  long n_sec, n_usec;
  n_sec = n_msec / 1000;
  n_usec = (n_msec % 1000) * 1000L;
  timeset.it_interval.tv_sec = n_sec;
  timeset.it_interval.tv_usec = n_usec;
  timeset.it_value.tv_sec = n_sec;
  timeset.it_value.tv_usec = n_usec;
  return setitimer(ITIMER_REAL, &timeset, NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_ticker>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  mov    %rsp,%rsi
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  xor    %edx,%edx
  movslq %eax,%rcx
  imul   $0x3e8,%eax,%eax
  movq   %rcx,%xmm0
  sub    %eax,%edi
  mov    D6(%rip),%rax
  movslq %edi,%rdi
  imul   $0x3e8,%rdi,%rdi
  movq   %rdi,%xmm1
  mov    (%rax),%edi
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <setitimer@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_ticker(int n_msec) {
  struct itimerval timeset;
  long n_sec, n_usec;
  n_sec = n_msec / 1000;
  n_usec = (n_msec % 1000) * 1000L;
  timeset.it_interval.tv_sec = n_sec;
  timeset.it_interval.tv_usec = n_usec;
  timeset.it_value.tv_sec = n_sec;
  timeset.it_value.tv_usec = n_usec;
  return setitimer(ITIMER_REAL, &timeset, NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_twiddle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  mov    %rax,(%rdx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  add    $0x10,%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movq   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movq   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movq   $0x3,(%rax)
  nop
  leave
  ret
```

assistant: ```c
extern void array_twiddle(long **arr) {
  arr[0] = (long *)malloc(sizeof(long));
  arr[1] = (long *)malloc(sizeof(long));
  arr[2] = (long *)malloc(sizeof(long));
  *arr[0] = 1;
  *arr[1] = 2;
  *arr[2] = 3;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<array_twiddle>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rbx)
  mov    (%rbx),%rax
  movq   $0x1,(%rax)
  mov    0x8(%rbx),%rax
  movq   $0x2,(%rax)
  mov    0x10(%rbx),%rax
  movq   $0x3,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
extern void array_twiddle(long **arr) {
  arr[0] = (long *)malloc(sizeof(long));
  arr[1] = (long *)malloc(sizeof(long));
  arr[2] = (long *)malloc(sizeof(long));
  *arr[0] = 1;
  *arr[1] = 2;
  *arr[2] = 3;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<array_twiddle>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,(%rbx)
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,0x8(%rbx)
  call   <malloc@plt>
  mov    (%rbx),%rdx
  mov    %rax,0x10(%rbx)
  movq   $0x1,(%rdx)
  mov    0x8(%rbx),%rdx
  movq   $0x2,(%rdx)
  movq   $0x3,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
extern void array_twiddle(long **arr) {
  arr[0] = (long *)malloc(sizeof(long));
  arr[1] = (long *)malloc(sizeof(long));
  arr[2] = (long *)malloc(sizeof(long));
  *arr[0] = 1;
  *arr[1] = 2;
  *arr[2] = 3;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<array_twiddle>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,(%rbx)
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,0x8(%rbx)
  call   <malloc@plt>
  mov    (%rbx),%rdx
  mov    %rax,0x10(%rbx)
  movq   $0x1,(%rdx)
  mov    0x8(%rbx),%rdx
  movq   $0x2,(%rdx)
  movq   $0x3,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
extern void array_twiddle(long **arr) {
  arr[0] = (long *)malloc(sizeof(long));
  arr[1] = (long *)malloc(sizeof(long));
  arr[2] = (long *)malloc(sizeof(long));
  *arr[0] = 1;
  *arr[1] = 2;
  *arr[2] = 3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_msec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    D27(%rip),%rax
  test   %rax,%rax
  jne    L1
  mov    D34(%rip),%rax
  mov    D55(%rip),%rdx
  mov    %rax,D22(%rip)
  mov    %rdx,D22(%rip)
  mov    $0x0,%eax
  jmp    L7
L1:
  mov    D34(%rip),%rax
  mov    D22(%rip),%rdx
  sub    %rdx,%rax
  imul   $0x3e8,%eax,%ecx
  mov    D55(%rip),%eax
  mov    D22(%rip),%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int get_msec(void) {
  static struct timeval timeval, first_timeval;
  gettimeofday(&timeval, 0);
  if (first_timeval.tv_sec == 0) {
    first_timeval = timeval;
    return 0;
  }
  return (timeval.tv_sec - first_timeval.tv_sec) * 1000 + (timeval.tv_usec - first_timeval.tv_usec) / 1000;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_msec>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D14(%rip),%rdi
  call   <gettimeofday@plt>
  mov    D26(%rip),%rcx
  test   %rcx,%rcx
  je     L5
  mov    D49(%rip),%edx
  sub    D58(%rip),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    D14(%rip),%rdx
  sub    %rcx,%rdx
  imul   $0x3e8,%edx,%edx
  add    %edx,%eax
L10:
  add    $0x8,%rsp
  ret
L5:
  movdqa D14(%rip),%xmm0
  movaps %xmm0,D66(%rip)
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
unsigned int get_msec(void) {
  static struct timeval timeval, first_timeval;
  gettimeofday(&timeval, 0);
  if (first_timeval.tv_sec == 0) {
    first_timeval = timeval;
    return 0;
  }
  return (timeval.tv_sec - first_timeval.tv_sec) * 1000 + (timeval.tv_usec - first_timeval.tv_usec) / 1000;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_msec>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D27(%rip),%rdi
  call   <gettimeofday@plt>
  mov    D57(%rip),%rcx
  test   %rcx,%rcx
  je     L6
  mov    D11(%rip),%edx
  sub    D42(%rip),%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    D27(%rip),%rdx
  add    $0x8,%rsp
  sub    %rcx,%rdx
  imul   $0x3e8,%edx,%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movdqa D27(%rip),%xmm0
  xor    %eax,%eax
  movaps %xmm0,D53(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int get_msec(void) {
  static struct timeval timeval, first_timeval;
  gettimeofday(&timeval, 0);
  if (first_timeval.tv_sec == 0) {
    first_timeval = timeval;
    return 0;
  }
  return (timeval.tv_sec - first_timeval.tv_sec) * 1000 + (timeval.tv_usec - first_timeval.tv_usec) / 1000;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_msec>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D40(%rip),%rdi
  call   <gettimeofday@plt>
  mov    D7(%rip),%rcx
  test   %rcx,%rcx
  je     L4
  mov    D29(%rip),%edx
  sub    D18(%rip),%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    D40(%rip),%rdx
  add    $0x8,%rsp
  sub    %rcx,%rdx
  imul   $0x3e8,%edx,%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  movdqa D40(%rip),%xmm0
  xor    %eax,%eax
  movaps %xmm0,D19(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int get_msec(void) {
  static struct timeval timeval, first_timeval;
  gettimeofday(&timeval, 0);
  if (first_timeval.tv_sec == 0) {
    first_timeval = timeval;
    return 0;
  }
  return (timeval.tv_sec - first_timeval.tv_sec) * 1000 + (timeval.tv_usec - first_timeval.tv_usec) / 1000;
}
```