ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <S@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <P@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D58
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D26
type_guessed: string

tool: D28: Inserire il primo numero:

tool: D13: %d

tool: D58: Inserire il secondo numero:

tool: D3: La somma e':%d

tool: D26: Il prodotto e':%d

assistant: ```c
int main() {
  int a;
  int b;
  int somma;
  int prodotto;
  printf("Inserire il primo numero:");
  scanf("%d", &a);
  printf("Inserire il secondo numero:");
  scanf("%d", &b);
  somma = S(a, b);
  prodotto = P(a, b);
  printf("La somma e':%d", somma);
  printf("\n");
  printf("Il prodotto e':%d", prodotto);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <S@plt>
  mov    %eax,%ebp
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <P@plt>
  mov    %eax,%ebx
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
type_guessed: string
name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D38
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string

tool: D35: Inserire il primo numero:

tool: D18: %d

tool: D38: Inserire il secondo numero:

tool: D8: La somma e':%d

tool: D11: Il prodotto e':%d

assistant: ```c
int main() {
  int a;
  int b;
  int somma;
  int prodotto;
  printf("Inserire il primo numero:");
  scanf("%d", &a);
  printf("Inserire il secondo numero:");
  scanf("%d", &b);
  somma = S(a, b);
  prodotto = P(a, b);
  printf("La somma e':%d", somma);
  printf("\n");
  printf("Il prodotto e':%d", prodotto);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D48(%rip),%rdi
  push   %rbp
  lea    D10(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <S@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  mov    %eax,%r12d
  call   <P@plt>
  mov    %r12d,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D48
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D41
datatype: string
name: unpack_data
arguments: data_tag: D11
datatype: string
name: unpack_data
arguments: data_tag: D38
datatype: string

tool: D48: Inserire il primo numero:

tool: D10: %d

tool: D41: Inserire il secondo numero:

tool: D11: La somma e':%d

tool: D38: Il prodotto e':%d

assistant: ```c
int main() {
  int a;
  int b;
  int somma;
  int prodotto;
  printf("Inserire il primo numero:");
  scanf("%d", &a);
  printf("Inserire il secondo numero:");
  scanf("%d", &b);
  somma = S(a, b);
  prodotto = P(a, b);
  printf("La somma e':%d", somma);
  printf("\n");
  printf("Il prodotto e':%d", prodotto);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D21(%rip),%rdi
  push   %rbp
  lea    D39(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <S@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  mov    %eax,%r12d
  call   <P@plt>
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D39
type: string
name: parse_data
arguments: data_tag: D47
type: string
name: parse_data
arguments: data_tag: D19
type: string
name: parse_data
arguments: data_tag: D43
type: string

tool: D21: Inserire il primo numero:

tool: D39: %d

tool: D47: Inserire il secondo numero:

tool: D19: La somma e':%d

tool: D43: Il prodotto e':%d

assistant: ```c
int main() {
  int a;
  int b;
  int somma;
  int prodotto;
  printf("Inserire il primo numero:");
  scanf("%d", &a);
  printf("Inserire il secondo numero:");
  scanf("%d", &b);
  somma = S(a, b);
  prodotto = P(a, b);
  printf("La somma e':%d", somma);
  printf("\n");
  printf("Il prodotto e':%d", prodotto);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Sum@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D18
datatype: string

tool: D7: Enter two ints

tool: D14: %ld%ld

tool: D18: The sum is %ld


assistant: ```c
int main(void) {
  long a, b, c;
  printf("Enter two ints\n");
  scanf("%ld%ld", &a, &b);
  c = Sum(a, b);
  printf("The sum is %ld\n", c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <Sum@plt>
  mov    %rax,%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D23
type_guessed: string

tool: D17: Enter two ints

tool: D6: %ld%ld

tool: D23: The sum is %ld


assistant: ```c
int main(void) {
  long a, b, c;
  printf("Enter two ints\n");
  scanf("%ld%ld", &a, &b);
  c = Sum(a, b);
  printf("The sum is %ld\n", c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <Sum@plt>
  lea    D11(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D22
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D17: Enter two ints

tool: D22: %ld%ld

tool: D11: The sum is %ld


assistant: ```c
int main(void) {
  long a, b, c;
  printf("Enter two ints\n");
  scanf("%ld%ld", &a, &b);
  c = Sum(a, b);
  printf("The sum is %ld\n", c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <Sum@plt>
  lea    D1(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: string

tool: D12: Enter two ints

tool: D6: %ld%ld

tool: D1: The sum is %ld


assistant: ```c
int main(void) {
  long a, b, c;
  printf("Enter two ints\n");
  scanf("%ld%ld", &a, &b);
  c = Sum(a, b);
  printf("The sum is %ld\n", c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L25
L15:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L25:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L22
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L15
L22:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long atos(char s[]) {
  long i, j;
  j = 0;
  for (i = 0; s[i] >= '0' && s[i] <= '9'; ++i)
    j = 10 * j + s[i] - '0';
  return (j);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<atos>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L8
  add    $0x1,%rdi
  mov    $0x0,%edx
L0:
  lea    (%rdx,%rdx,4),%rdx
  movsbq %al,%rax
  lea    -0x30(%rax,%rdx,2),%rdx
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L0
L2:
  mov    %rdx,%rax
  ret
L8:
  mov    $0x0,%edx
  jmp    L2
```

assistant: ```c
long atos(char s[]) {
  long i, j;
  j = 0;
  for (i = 0; s[i] >= '0' && s[i] <= '9'; ++i)
    j = 10 * j + s[i] - '0';
  return (j);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atos>:
  endbr64
  movsbq (%rdi),%rax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L5
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L10:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8
  movsbq -0x1(%rdi),%rax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L10
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L5:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long atos(char s[]) {
  long i, j;
  j = 0;
  for (i = 0; s[i] >= '0' && s[i] <= '9'; ++i)
    j = 10 * j + s[i] - '0';
  return (j);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atos>:
  endbr64
  movsbq (%rdi),%rax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L0
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L16:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8
  movsbq -0x1(%rdi),%rax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L16
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L0:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long atos(char s[]) {
  long i, j;
  j = 0;
  for (i = 0; s[i] >= '0' && s[i] <= '9'; ++i)
    j = 10 * j + s[i] - '0';
  return (j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<kernel_dtrsm_nn_ll_diag_4x4_lib4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x8(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    -0x8(%rbp),%edi
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  push   0x18(%rbp)
  push   0x10(%rbp)
  push   -0x28(%rbp)
  mov    -0x1c(%rbp),%ecx
  push   %rcx
  mov    %edi,%r9d
  mov    %rsi,%r8
  mov    %rdx,%rcx
  mov    %eax,%edx
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <kernel_dtrsm_nn_ll_diag_4x4_vs_lib4@plt>
  add    $0x20,%rsp
  nop
  leave
  ret
```

assistant: ```c
void kernel_dtrsm_nn_ll_diag_4x4_lib4(int kmax, double *A, double *B, int sdb, int alg, double *C, double *D, double *E) {
  kernel_dtrsm_nn_ll_diag_4x4_vs_lib4(4, 4, kmax, A, B, sdb, alg, C, D, E);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kernel_dtrsm_nn_ll_diag_4x4_lib4>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  push   %r9
  push   %r8
  mov    %ecx,%r9d
  mov    %rdx,%r8
  mov    %rsi,%rcx
  mov    %edi,%edx
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <kernel_dtrsm_nn_ll_diag_4x4_vs_lib4@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void kernel_dtrsm_nn_ll_diag_4x4_lib4(int kmax, double *A, double *B, int sdb, int alg, double *C, double *D, double *E) {
  kernel_dtrsm_nn_ll_diag_4x4_vs_lib4(4, 4, kmax, A, B, sdb, alg, C, D, E);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kernel_dtrsm_nn_ll_diag_4x4_lib4>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  push   %r9
  mov    %ecx,%r9d
  mov    %rsi,%rcx
  mov    $0x4,%esi
  push   %r8
  mov    %rdx,%r8
  mov    %edi,%edx
  mov    $0x4,%edi
  call   <kernel_dtrsm_nn_ll_diag_4x4_vs_lib4@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void kernel_dtrsm_nn_ll_diag_4x4_lib4(int kmax, double *A, double *B, int sdb, int alg, double *C, double *D, double *E) {
  kernel_dtrsm_nn_ll_diag_4x4_vs_lib4(4, 4, kmax, A, B, sdb, alg, C, D, E);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kernel_dtrsm_nn_ll_diag_4x4_lib4>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  push   %r9
  mov    %ecx,%r9d
  mov    %rsi,%rcx
  mov    $0x4,%esi
  push   %r8
  mov    %rdx,%r8
  mov    %edi,%edx
  mov    $0x4,%edi
  call   <kernel_dtrsm_nn_ll_diag_4x4_vs_lib4@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void kernel_dtrsm_nn_ll_diag_4x4_lib4(int kmax, double *A, double *B, int sdb, int alg, double *C, double *D, double *E) {
  kernel_dtrsm_nn_ll_diag_4x4_vs_lib4(4, 4, kmax, A, B, sdb, alg, C, D, E);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<netif_wake_subqueue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x1,%edi
  call   <WARN_ON@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <netif_wake_queue@plt>
  nop
  leave
  ret
```

assistant: ```c
void netif_wake_subqueue(struct net_device *dev, int fifo_no) {
  WARN_ON(1);
  netif_wake_queue(dev);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<netif_wake_subqueue>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <WARN_ON@plt>
  mov    %rbx,%rdi
  call   <netif_wake_queue@plt>
  pop    %rbx
  ret
```

assistant: ```c
void netif_wake_subqueue(struct net_device *dev, int fifo_no) {
  WARN_ON(1);
  netif_wake_queue(dev);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<netif_wake_subqueue>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  call   <WARN_ON@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <netif_wake_queue@plt>
```

assistant: ```c
void netif_wake_subqueue(struct net_device *dev, int fifo_no) {
  WARN_ON(1);
  netif_wake_queue(dev);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<netif_wake_subqueue>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  call   <WARN_ON@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <netif_wake_queue@plt>
```

assistant: ```c
void netif_wake_subqueue(struct net_device *dev, int fifo_no) {
  WARN_ON(1);
  netif_wake_queue(dev);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <max_num@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x5d0,%esi
  mov    $0x859,%edi
  call   <max_num@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_infered: string

tool: D15: %d


assistant: ```c
int main(void) {
  int wyj;
  max_num(3, 4, &wyj);
  printf("%d\n", wyj);
  max_num(2137, 1488, &wyj);
  printf("%d\n", wyj);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <max_num@plt>
  mov    0x4(%rsp),%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    $0x5d0,%esi
  mov    $0x859,%edi
  call   <max_num@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: %d


assistant: ```c
int main(void) {
  int wyj;
  max_num(3, 4, &wyj);
  printf("%d\n", wyj);
  max_num(2137, 1488, &wyj);
  printf("%d\n", wyj);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  mov    $0x3,%edi
  push   %rbp
  lea    D0(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  call   <max_num@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x5d0,%esi
  mov    $0x859,%edi
  mov    %r12,%rdx
  call   <max_num@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: %d


assistant: ```c
int main(void) {
  int wyj;
  max_num(3, 4, &wyj);
  printf("%d\n", wyj);
  max_num(2137, 1488, &wyj);
  printf("%d\n", wyj);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  mov    $0x3,%edi
  push   %rbp
  lea    D5(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  call   <max_num@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x5d0,%esi
  mov    $0x859,%edi
  mov    %r12,%rdx
  call   <max_num@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: %d


assistant: ```c
int main(void) {
  int wyj;
  max_num(3, 4, &wyj);
  printf("%d\n", wyj);
  max_num(2137, 1488, &wyj);
  printf("%d\n", wyj);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cs_tol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   D7(%rip),%xmm1
  andpd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: qword

tool: D7: 9223372036854775807

assistant: ```c
int cs_tol(int i, int j, double aij, void *tol) {
  (void)i;
  (void)j;
  return (fabs(aij) > *((double *)tol));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cs_tol>:
  endbr64
  andpd  D5(%rip),%xmm0
  comisd (%rdx),%xmm0
  seta   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: qword[2]

tool: {"D5": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
int cs_tol(int i, int j, double aij, void *tol) {
  (void)i;
  (void)j;
  return (fabs(aij) > *((double *)tol));
}
```
user: Translate the below assembly code into C programming language:

```asm
<cs_tol>:
  endbr64
  andpd  D1(%rip),%xmm0
  xor    %eax,%eax
  comisd (%rdx),%xmm0
  seta   %al
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: qword[2]

tool: {"D1": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
int cs_tol(int i, int j, double aij, void *tol) {
  (void)i;
  (void)j;
  return (fabs(aij) > *((double *)tol));
}
```