ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L17
L26:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L46
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L17
L46:
  mov    -0x10(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0xc(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L17:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D21
type: string
name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D38
type: string
name: read_data
arguments: tag: D31
type: string

tool: D21: %d


tool: D0: %d %d


tool: D38: divisao impossivel

tool: D31: %.1f


assistant: ```c
int main(void) {
  int n, x, y;
  scanf("%d\n", &n);
  while (n-- > 0) {
    scanf("%d %d\n", &x, &y);
    if (y == 0) {
      printf("divisao impossivel\n");
    } else {
      printf("%.1f\n", (double)x / y);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L35
  lea    0x14(%rsp),%rbp
  lea    D16(%rip),%rbx
  lea    D37(%rip),%r13
  lea    D25(%rip),%r12
  jmp    L41
L47:
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L49:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L35
L41:
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L47
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L49
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D37
type: string
name: read_data
arguments: label: D25
type: string

tool: D19: %d


tool: D16: %d %d


tool: D37: %.1f


tool: D25: divisao impossivel

assistant: ```c
int main(void) {
  int n, x, y;
  scanf("%d\n", &n);
  while (n-- > 0) {
    scanf("%d %d\n", &x, &y);
    if (y == 0) {
      printf("divisao impossivel\n");
    } else {
      printf("%.1f\n", (double)x / y);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L51
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    D16(%rip),%rbx
  lea    D12(%rip),%r14
  lea    D8(%rip),%r13
  jmp    L43
  nopl   (%rax)
L10:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L51
L43:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L10
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %r14,%rdi
  cvtsi2sd %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2sdl 0x10(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L43
L51:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D16
type_infered: string
name: disassemble_data
arguments: data_label: D12
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D10: %d


tool: D16: %d %d


tool: D12: %.1f


tool: D8: divisao impossivel

assistant: ```c
int main(void) {
  int n, x, y;
  scanf("%d\n", &n);
  while (n-- > 0) {
    scanf("%d %d\n", &x, &y);
    if (y == 0) {
      printf("divisao impossivel\n");
    } else {
      printf("%.1f\n", (double)x / y);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L24
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    D13(%rip),%rbx
  lea    D18(%rip),%r14
  lea    D0(%rip),%r13
  jmp    L22
  nopl   (%rax)
L30:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L24
L22:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L30
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %r14,%rdi
  cvtsi2sd %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2sdl 0x10(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L22
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string

tool: D5: %d


tool: D13: %d %d


tool: D18: %.1f


tool: D0: divisao impossivel

assistant: ```c
int main(void) {
  int n, x, y;
  scanf("%d\n", &n);
  while (n-- > 0) {
    scanf("%d %d\n", &x, &y);
    if (y == 0) {
      printf("divisao impossivel\n");
    } else {
      printf("%.1f\n", (double)x / y);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%edi
  push   %r12
  push   %rbp
  lea    D41(%rip),%rbp
  sub    $0x10,%rsp
  movsd  D37(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %rsp,%r12
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <ecvt@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  movsd  D26(%rip),%xmm0
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x5,%edi
  call   <ecvt@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x5,%edi
  movsd  D36(%rip),%xmm0
  call   <ecvt@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x5,%edi
  movsd  D23(%rip),%xmm0
  call   <ecvt@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  pxor   %xmm0,%xmm0
  mov    $0x2,%edi
  call   <ecvt@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D41
datatype: string
name: disassemble_data
arguments: data_label: D37
datatype: f64
name: disassemble_data
arguments: data_label: D26
datatype: f64
name: disassemble_data
arguments: data_label: D36
datatype: byte[8]
name: disassemble_data
arguments: data_label: D23
datatype: f64

tool: D41: %d


tool: D37: 12.2223

tool: D26: 110.01

tool: {"D36": [0xd7,0xa3,0x70,0x3d,0x0a,0x5c,0x91,0xc0]}

tool: D23: 0.01

assistant: ```c
int main() {
  double d = 12.2223;
  int decpt, sign;
  char *rs = ecvt(d, 10, &decpt, &sign);
  if (rs) {
    printf("%s\n", rs);
    printf("%d\n", decpt);
    printf("%d\n", sign);
  }
  rs = ecvt(110.01, 5, &decpt, &sign);
  printf("%s\n", rs);
  printf("%d\n", decpt);
  printf("%d\n", sign);
  rs = ecvt(-1111.01, 5, &decpt, &sign);
  printf("%s\n", rs);
  printf("%d\n", decpt);
  printf("%d\n", sign);
  rs = ecvt(0.01, 5, &decpt, &sign);
  printf("%s\n", rs);
  printf("%d\n", decpt);
  printf("%d\n", sign);
  rs = ecvt(0.0, 2, &decpt, &sign);
  printf("%s\n", rs);
  printf("%d\n", decpt);
  printf("%d\n", sign);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%edi
  push   %r12
  push   %rbp
  lea    D49(%rip),%rbp
  sub    $0x10,%rsp
  movsd  D46(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %rsp,%r12
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <ecvt@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L1:
  movsd  D17(%rip),%xmm0
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x5,%edi
  call   <ecvt@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x5,%edi
  movsd  D31(%rip),%xmm0
  call   <ecvt@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x5,%edi
  movsd  D42(%rip),%xmm0
  call   <ecvt@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  pxor   %xmm0,%xmm0
  mov    $0x2,%edi
  call   <ecvt@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D49
type_guessed: string
name: disassemble_data
arguments: label: D46
type_guessed: f64
name: disassemble_data
arguments: label: D17
type_guessed: f64
name: disassemble_data
arguments: label: D31
type_guessed: byte[8]
name: disassemble_data
arguments: label: D42
type_guessed: f64

tool: D49: %d


tool: D46: 12.2223

tool: D17: 110.01

tool: {"D31": [0xd7,0xa3,0x70,0x3d,0x0a,0x5c,0x91,0xc0]}

tool: D42: 0.01

assistant: ```c
int main() {
  double d = 12.2223;
  int decpt, sign;
  char *rs = ecvt(d, 10, &decpt, &sign);
  if (rs) {
    printf("%s\n", rs);
    printf("%d\n", decpt);
    printf("%d\n", sign);
  }
  rs = ecvt(110.01, 5, &decpt, &sign);
  printf("%s\n", rs);
  printf("%d\n", decpt);
  printf("%d\n", sign);
  rs = ecvt(-1111.01, 5, &decpt, &sign);
  printf("%s\n", rs);
  printf("%d\n", decpt);
  printf("%d\n", sign);
  rs = ecvt(0.01, 5, &decpt, &sign);
  printf("%s\n", rs);
  printf("%d\n", decpt);
  printf("%d\n", sign);
  rs = ecvt(0.0, 2, &decpt, &sign);
  printf("%s\n", rs);
  printf("%d\n", decpt);
  printf("%d\n", sign);
}
```
user: Translate the below assembly code into C programming language:

```asm
<oo_xirrResult_Deriv1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x50(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L18
L4:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  D2(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  D29(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  -0x58(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L18:
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L4
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
datatype: f64
name: retrieve_data
arguments: tag: D2
datatype: f64
name: retrieve_data
arguments: tag: D29
datatype: f64

tool: D18: 1

tool: D2: 86400

tool: D29: 365

assistant: ```c
double oo_xirrResult_Deriv1(const double *rValues, const double *rDates, const int nCount, double fRate) {
  double D_0 = rDates[0];
  double r = fRate + 1.0;
  double fResult = 0.0;
  int i;
  for (i = 1; i < nCount; ++i) {
    double E_i = ((rDates[i] - D_0) / 86400.0) / 365.0;
    fResult -= E_i * rValues[i] / pow(r, E_i + 1.0);
  }
  return fResult;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<oo_xirrResult_Deriv1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm5
  movsd  %xmm5,0x8(%rsp)
  addsd  D23(%rip),%xmm0
  cmp    $0x1,%edx
  jle    L14
  mov    %rdi,%r14
  mov    %rsi,%r13
  movq   %xmm0,%r15
  mov    %edx,%r12d
  mov    $0x1,%ebx
  mov    D25(%rip),%rbp
L16:
  movsd  0x0(%r13,%rbx,8),%xmm1
  subsd  0x8(%rsp),%xmm1
  divsd  D28(%rip),%xmm1
  divsd  D43(%rip),%xmm1
  movapd %xmm1,%xmm2
  mulsd  (%r14,%rbx,8),%xmm2
  movsd  %xmm2,(%rsp)
  addsd  D23(%rip),%xmm1
  movq   %r15,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %rbp,%xmm3
  subsd  %xmm0,%xmm3
  movq   %xmm3,%rbp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L16
L22:
  movq   %rbp,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  mov    D25(%rip),%rbp
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
type: f64
name: disassemble_data
arguments: data_tag: D25
type: f64
name: disassemble_data
arguments: data_tag: D28
type: f64
name: disassemble_data
arguments: data_tag: D43
type: f64

tool: D23: 1

tool: D25: 0

tool: D28: 86400

tool: D43: 365

assistant: ```c
double oo_xirrResult_Deriv1(const double *rValues, const double *rDates, const int nCount, double fRate) {
  double D_0 = rDates[0];
  double r = fRate + 1.0;
  double fResult = 0.0;
  int i;
  for (i = 1; i < nCount; ++i) {
    double E_i = ((rDates[i] - D_0) / 86400.0) / 365.0;
    fResult -= E_i * rValues[i] / pow(r, E_i + 1.0);
  }
  return fResult;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<oo_xirrResult_Deriv1>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  (%rsi),%xmm5
  addsd  D29(%rip),%xmm0
  movsd  %xmm5,0x18(%rsp)
  cmp    $0x1,%edx
  jle    L19
  mov    %rdi,%r12
  mov    %rsi,%r13
  movq   %xmm0,%r14
  movslq %edx,%rbp
  mov    $0x1,%ebx
  pxor   %xmm3,%xmm3
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  (%r12,%rbx,8),%xmm2
  movsd  0x0(%r13,%rbx,8),%xmm1
  add    $0x1,%rbx
  movq   %r14,%xmm0
  subsd  0x18(%rsp),%xmm1
  divsd  D11(%rip),%xmm1
  divsd  D4(%rip),%xmm1
  movsd  %xmm3,0x10(%rsp)
  mulsd  %xmm1,%xmm2
  addsd  D29(%rip),%xmm1
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm3
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
  cmp    %rbx,%rbp
  jne    L11
L9:
  add    $0x20,%rsp
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  pxor   %xmm3,%xmm3
  jmp    L9
```

tool_calls: name: unpack_data
arguments: tag: D29
datatype: f64
name: unpack_data
arguments: tag: D11
datatype: f64
name: unpack_data
arguments: tag: D4
datatype: f64

tool: D29: 1

tool: D11: 86400

tool: D4: 365

assistant: ```c
double oo_xirrResult_Deriv1(const double *rValues, const double *rDates, const int nCount, double fRate) {
  double D_0 = rDates[0];
  double r = fRate + 1.0;
  double fResult = 0.0;
  int i;
  for (i = 1; i < nCount; ++i) {
    double E_i = ((rDates[i] - D_0) / 86400.0) / 365.0;
    fResult -= E_i * rValues[i] / pow(r, E_i + 1.0);
  }
  return fResult;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<oo_xirrResult_Deriv1>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  (%rsi),%xmm5
  addsd  D2(%rip),%xmm0
  movsd  %xmm5,0x18(%rsp)
  cmp    $0x1,%edx
  jle    L5
  mov    %rdi,%r12
  mov    %rsi,%r13
  movq   %xmm0,%r14
  movslq %edx,%rbp
  mov    $0x1,%ebx
  pxor   %xmm3,%xmm3
  nopw   0x0(%rax,%rax,1)
L27:
  movsd  (%r12,%rbx,8),%xmm2
  movsd  0x0(%r13,%rbx,8),%xmm1
  add    $0x1,%rbx
  movq   %r14,%xmm0
  subsd  0x18(%rsp),%xmm1
  divsd  D12(%rip),%xmm1
  divsd  D33(%rip),%xmm1
  movsd  %xmm3,0x10(%rsp)
  mulsd  %xmm1,%xmm2
  addsd  D2(%rip),%xmm1
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm3
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
  cmp    %rbx,%rbp
  jne    L27
L23:
  add    $0x20,%rsp
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  pxor   %xmm3,%xmm3
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: f64
name: retrieve_data
arguments: tag: D12
datatype: f64
name: retrieve_data
arguments: tag: D33
datatype: f64

tool: D2: 1

tool: D12: 86400

tool: D33: 365

assistant: ```c
double oo_xirrResult_Deriv1(const double *rValues, const double *rDates, const int nCount, double fRate) {
  double D_0 = rDates[0];
  double r = fRate + 1.0;
  double fResult = 0.0;
  int i;
  for (i = 1; i < nCount; ++i) {
    double E_i = ((rDates[i] - D_0) / 86400.0) / 365.0;
    fResult -= E_i * rValues[i] / pow(r, E_i + 1.0);
  }
  return fResult;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L10:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L10
L13:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L14
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L14:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L59
L48:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L59:
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L48
  mov    -0x50(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4c(%rbp)
  jmp    L45
L21:
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4c(%rbp)
L45:
  cmpl   $0x0,-0x4c(%rbp)
  jns    L21
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string

tool: D20: %d

tool: D18: %d


assistant: ```c
int main() {
  int size;
  scanf("%d", &size);
  int nums[size];
  int i;
  for (i = 0; i < size; i++) {
    scanf("%d", &nums[i]);
  }
  for (i = size - 1; i >= 0; i--) {
    printf("%d\n", nums[i]);
  }
  return 0;
}
```