ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<dump_ustat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L16
  mov    %esi,%ebx
  mov    %rcx,%r12
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rdx
  mov    %rax,%rsi
  mov    %ebx,%edi
  call   <dump_int_from_mem@plt>
  add    %eax,0x4(%rsp)
  lea    0x8(%rbp),%rsi
  lea    0x4(%rbx),%edi
  mov    %r12,%rdx
  call   <dump_long_unsigned_int_from_mem@plt>
  add    %eax,0x4(%rsp)
  lea    0x10(%rbp),%rsi
  lea    0x8(%rbx),%edi
  mov    %r12,%rdx
  call   <dump_char_from_mem@plt>
  add    %eax,0x4(%rsp)
  lea    0x18(%rbp),%rsi
  lea    0xe(%rbx),%edi
  mov    %r12,%rdx
  call   <dump_char_from_mem@plt>
  add    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <copy_params@plt>
  mov    %rax,0x0(%r13)
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L6
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_ustat(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_f_tfree = addr;
  unsigned int arm_tracing_f_tinode = addr + 4;
  unsigned int arm_tracing_f_fname = addr + 8;
  unsigned int arm_tracing_f_fpack = addr + 14;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(4 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_int_from_mem(arm_tracing_f_tfree, &dumped_type_params[0], target);
    len += dump_long_unsigned_int_from_mem(arm_tracing_f_tinode, &dumped_type_params[1], target);
    len += dump_char_from_mem(arm_tracing_f_fname, &dumped_type_params[2], target);
    len += dump_char_from_mem(arm_tracing_f_fpack, &dumped_type_params[3], target);
  }
  *dumped_params = copy_params(dumped_type_params, 4, &len);
  free_dumped_params(dumped_type_params, 4);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_ustat>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L24
  mov    $0x20,%edi
  mov    %rcx,%r12
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %ebx,%edi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <dump_int_from_mem@plt>
  lea    0x8(%rbp),%rsi
  lea    0x4(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_long_unsigned_int_from_mem@plt>
  lea    0x10(%rbp),%rsi
  lea    0x8(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_char_from_mem@plt>
  lea    0x18(%rbp),%rsi
  lea    0xe(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_char_from_mem@plt>
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %eax,0x4(%rsp)
  mov    $0x4,%esi
  call   <copy_params@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L24:
  xor    %edi,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L2
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_ustat(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_f_tfree = addr;
  unsigned int arm_tracing_f_tinode = addr + 4;
  unsigned int arm_tracing_f_fname = addr + 8;
  unsigned int arm_tracing_f_fpack = addr + 14;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(4 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_int_from_mem(arm_tracing_f_tfree, &dumped_type_params[0], target);
    len += dump_long_unsigned_int_from_mem(arm_tracing_f_tinode, &dumped_type_params[1], target);
    len += dump_char_from_mem(arm_tracing_f_fname, &dumped_type_params[2], target);
    len += dump_char_from_mem(arm_tracing_f_fpack, &dumped_type_params[3], target);
  }
  *dumped_params = copy_params(dumped_type_params, 4, &len);
  free_dumped_params(dumped_type_params, 4);
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dump_ustat>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L14
  mov    $0x20,%edi
  mov    %rcx,%r12
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %ebx,%edi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <dump_int_from_mem@plt>
  lea    0x8(%rbp),%rsi
  lea    0x4(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_long_unsigned_int_from_mem@plt>
  lea    0x10(%rbp),%rsi
  lea    0x8(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_char_from_mem@plt>
  lea    0x18(%rbp),%rsi
  lea    0xe(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_char_from_mem@plt>
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %eax,0x4(%rsp)
  mov    $0x4,%esi
  call   <copy_params@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L14:
  xor    %edi,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L5
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_ustat(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_f_tfree = addr;
  unsigned int arm_tracing_f_tinode = addr + 4;
  unsigned int arm_tracing_f_fname = addr + 8;
  unsigned int arm_tracing_f_fpack = addr + 14;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(4 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_int_from_mem(arm_tracing_f_tfree, &dumped_type_params[0], target);
    len += dump_long_unsigned_int_from_mem(arm_tracing_f_tinode, &dumped_type_params[1], target);
    len += dump_char_from_mem(arm_tracing_f_fname, &dumped_type_params[2], target);
    len += dump_char_from_mem(arm_tracing_f_fpack, &dumped_type_params[3], target);
  }
  *dumped_params = copy_params(dumped_type_params, 4, &len);
  free_dumped_params(dumped_type_params, 4);
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<jason_Hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x16c7,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L6
L13:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  shl    $0x5,%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L13
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t jason_Hash(char *key, size_t bytes) {
  uint32_t hash = 5831;
  for (uint32_t i = 0; i < bytes; ++i) {
    hash = 33 * hash + key[i];
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<jason_Hash>:
  endbr64
  test   %rsi,%rsi
  je     L1
  mov    %rdi,%rdx
  add    %rsi,%rdi
  mov    $0x16c7,%eax
L2:
  mov    %rax,%rcx
  shl    $0x5,%rcx
  add    %rcx,%rax
  movsbq (%rdx),%rcx
  add    %rcx,%rax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L2
  ret
L1:
  mov    $0x16c7,%eax
  ret
```

assistant: ```c
uint32_t jason_Hash(char *key, size_t bytes) {
  uint32_t hash = 5831;
  for (uint32_t i = 0; i < bytes; ++i) {
    hash = 33 * hash + key[i];
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jason_Hash>:
  endbr64
  test   %rsi,%rsi
  je     L0
  add    %rdi,%rsi
  mov    $0x16c7,%eax
  nopl   0x0(%rax)
L14:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  add    %rdx,%rax
  cmp    %rsi,%rdi
  jne    L14
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x16c7,%eax
  ret
```

assistant: ```c
uint32_t jason_Hash(char *key, size_t bytes) {
  uint32_t hash = 5831;
  for (uint32_t i = 0; i < bytes; ++i) {
    hash = 33 * hash + key[i];
  }
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<jason_Hash>:
  endbr64
  test   %rsi,%rsi
  je     L5
  add    %rdi,%rsi
  mov    $0x16c7,%eax
  nopl   0x0(%rax)
L13:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  add    %rdx,%rax
  cmp    %rdi,%rsi
  jne    L13
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x16c7,%eax
  ret
```

assistant: ```c
uint32_t jason_Hash(char *key, size_t bytes) {
  uint32_t hash = 5831;
  for (uint32_t i = 0; i < bytes; ++i) {
    hash = 33 * hash + key[i];
  }
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x3,%rax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L11
L16:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  shr    %eax
  cmp    %eax,-0x10(%rbp)
  jb     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(double *begin, double *end) {
  double temp = 0;
  unsigned elements = end - begin;
  unsigned i = 0;
  for (i; i < elements / 2; ++i) {
    temp = *(begin + i);
    *(begin + i) = *(begin + (elements - 1 - i));
    *(begin + (elements - 1 - i)) = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  sub    %rdi,%rsi
  sar    $0x3,%rsi
  mov    %esi,%ecx
  mov    %esi,%r8d
  shr    %r8d
  cmp    $0x1,%esi
  jbe    L8
  mov    $0x0,%eax
  sub    $0x1,%ecx
L0:
  movsd  (%rdi,%rax,8),%xmm0
  mov    %ecx,%edx
  sub    %eax,%edx
  lea    (%rdi,%rdx,8),%rdx
  movsd  (%rdx),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %eax,%r8d
  ja     L0
L8:
  ret
```

assistant: ```c
void reverse(double *begin, double *end) {
  double temp = 0;
  unsigned elements = end - begin;
  unsigned i = 0;
  for (i; i < elements / 2; ++i) {
    temp = *(begin + i);
    *(begin + i) = *(begin + (elements - 1 - i));
    *(begin + (elements - 1 - i)) = temp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reverse>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rdx
  sub    %rdi,%rax
  sar    $0x3,%rax
  mov    %eax,%ecx
  sub    $0x1,%eax
  shr    %ecx
  mov    %eax,%esi
  sub    %ecx,%esi
  test   %ecx,%ecx
  je     L14
L10:
  mov    %eax,%ecx
  movsd  (%rdx),%xmm0
  sub    $0x1,%eax
  add    $0x8,%rdx
  lea    (%rdi,%rcx,8),%rcx
  movsd  (%rcx),%xmm1
  movsd  %xmm1,-0x8(%rdx)
  movsd  %xmm0,(%rcx)
  cmp    %eax,%esi
  jne    L10
L14:
  ret
```

assistant: ```c
void reverse(double *begin, double *end) {
  double temp = 0;
  unsigned elements = end - begin;
  unsigned i = 0;
  for (i; i < elements / 2; ++i) {
    temp = *(begin + i);
    *(begin + i) = *(begin + (elements - 1 - i));
    *(begin + (elements - 1 - i)) = temp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rdx
  sub    %rdi,%rax
  sar    $0x3,%rax
  mov    %eax,%ecx
  sub    $0x1,%eax
  shr    %ecx
  mov    %eax,%esi
  sub    %ecx,%esi
  test   %ecx,%ecx
  je     L12
L11:
  mov    %eax,%ecx
  movsd  (%rdx),%xmm0
  sub    $0x1,%eax
  add    $0x8,%rdx
  lea    (%rdi,%rcx,8),%rcx
  movsd  (%rcx),%xmm1
  movsd  %xmm1,-0x8(%rdx)
  movsd  %xmm0,(%rcx)
  cmp    %eax,%esi
  jne    L11
L12:
  ret
```

assistant: ```c
void reverse(double *begin, double *end) {
  double temp = 0;
  unsigned elements = end - begin;
  unsigned i = 0;
  for (i; i < elements / 2; ++i) {
    temp = *(begin + i);
    *(begin + i) = *(begin + (elements - 1 - i));
    *(begin + (elements - 1 - i)) = temp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x6c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x60(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L33:
  cmp    %rdx,%rsp
  je     L53
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L33
L53:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L26
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L26:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x58(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L15
L98:
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x68(%rbp)
L15:
  mov    -0x6c(%rbp),%eax
  cmp    %eax,-0x68(%rbp)
  jl     L98
  movl   $0x0,-0x68(%rbp)
  jmp    L47
L64:
  mov    -0x58(%rbp),%rax
  mov    -0x68(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,-0x74(%rbp)
  fildl  -0x74(%rbp)
  fstpt  -0x50(%rbp)
  movl   $0x1,-0x64(%rbp)
  jmp    L46
L36:
  fildl  -0x64(%rbp)
  fldt   -0x50(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x50(%rbp)
  addl   $0x1,-0x64(%rbp)
L46:
  mov    -0x58(%rbp),%rax
  mov    -0x68(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  cmp    %eax,-0x64(%rbp)
  jl     L36
  push   -0x48(%rbp)
  push   -0x50(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  addl   $0x1,-0x68(%rbp)
L47:
  mov    -0x6c(%rbp),%eax
  cmp    %eax,-0x68(%rbp)
  jl     L64
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string
name: unpack_data
arguments: label: D2
data_type: string

tool: D3: %d

tool: D2: %0.0Lf


assistant: ```c
int main() {
  int n;
  long double x;
  scanf("%d", &n);
  int i, j;
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n; i++) {
    x = a[i];
    for (j = 1; j < a[i]; j++)
      x = j * x;
    printf("%0.0Lf\n", x);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L49:
  cmp    %rcx,%rsp
  je     L71
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L49
L71:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L24
  orq    $0x0,-0x8(%rsp,%rax,1)
L24:
  mov    %rsp,%r12
  test   %edx,%edx
  jle    L42
  mov    %r12,%r13
  mov    $0x0,%ebx
  lea    D14(%rip),%r14
L92:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%eax
  add    $0x4,%r13
  cmp    %ebx,%eax
  jg     L92
  test   %eax,%eax
  jle    L42
  mov    $0x0,%ebx
  lea    D16(%rip),%r13
L39:
  mov    (%r12,%rbx,4),%edx
  mov    %edx,-0x34(%rbp)
  fildl  -0x34(%rbp)
  cmp    $0x1,%edx
  jle    L2
  mov    $0x1,%eax
L93:
  mov    %eax,-0x34(%rbp)
  fildl  -0x34(%rbp)
  fmulp  %st,%st(1)
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L93
L2:
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  add    $0x10,%rsp
  cmp    %ebx,-0x2c(%rbp)
  jg     L39
L42:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D16
type: string

tool: D14: %d

tool: D16: %0.0Lf


assistant: ```c
int main() {
  int n;
  long double x;
  scanf("%d", &n);
  int i, j;
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n; i++) {
    x = a[i];
    for (j = 1; j < a[i]; j++)
      x = j * x;
    printf("%0.0Lf\n", x);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L28
L59:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L59
L28:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L53
L68:
  mov    %rsp,%r12
  xor    %ebx,%ebx
  mov    %r12,%r13
  test   %ecx,%ecx
  jle    L52
  nop
L47:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L47
  test   %eax,%eax
  jle    L52
  xor    %ebx,%ebx
  lea    D5(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    (%r12,%rbx,4),%edx
  mov    %edx,-0x34(%rbp)
  fildl  -0x34(%rbp)
  cmp    $0x1,%edx
  jle    L39
  mov    $0x1,%eax
  nopl   0x0(%rax)
L30:
  mov    %eax,-0x34(%rbp)
  fildl  -0x34(%rbp)
  add    $0x1,%eax
  fmulp  %st,%st(1)
  cmp    %eax,%edx
  jne    L30
L39:
  sub    $0x10,%rsp
  mov    %r13,%rdi
  add    $0x1,%rbx
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    %ebx,-0x2c(%rbp)
  jg     L37
L52:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L53:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L68
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D5
type_infered: string

tool: D3: %d

tool: D5: %0.0Lf


assistant: ```c
int main() {
  int n;
  long double x;
  scanf("%d", &n);
  int i, j;
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n; i++) {
    x = a[i];
    for (j = 1; j < a[i]; j++)
      x = j * x;
    printf("%0.0Lf\n", x);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L102
L51:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L51
L102:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L55
L5:
  mov    %rsp,%r12
  xor    %ebx,%ebx
  mov    %r12,%r13
  test   %ecx,%ecx
  jle    L93
  nop
L60:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L60
  test   %eax,%eax
  jle    L93
  xor    %ebx,%ebx
  lea    D11(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L96:
  mov    (%r12,%rbx,4),%edx
  mov    %edx,-0x34(%rbp)
  fildl  -0x34(%rbp)
  cmp    $0x1,%edx
  jle    L92
  mov    $0x1,%eax
  nopl   0x0(%rax)
L35:
  mov    %eax,-0x34(%rbp)
  fildl  -0x34(%rbp)
  add    $0x1,%eax
  fmulp  %st,%st(1)
  cmp    %eax,%edx
  jne    L35
L92:
  sub    $0x10,%rsp
  mov    %r13,%rdi
  add    $0x1,%rbx
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    %ebx,-0x2c(%rbp)
  jg     L96
L93:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L55:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L5
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D0: %d

tool: D11: %0.0Lf


assistant: ```c
int main() {
  int n;
  long double x;
  scanf("%d", &n);
  int i, j;
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n; i++) {
    x = a[i];
    for (j = 1; j < a[i]; j++)
      x = j * x;
    printf("%0.0Lf\n", x);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L2:
  mov    $0x0,%eax
  call   <bar@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void foo(char *dst) {
  char *const end = dst;
  do {
    bar();
    dst += 2;
  } while (dst < end);
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo(char *dst) {
  char *const end = dst;
  do {
    bar();
    dst += 2;
  } while (dst < end);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <bar@plt>
```

assistant: ```c
void foo(char *dst) {
  char *const end = dst;
  do {
    bar();
    dst += 2;
  } while (dst < end);
}
```