user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<recu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r9d
  mov    %edx,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
L85:
  mov    %eax,0xc(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L85
  movslq %r9d,%rax
  lea    0x0(,%rax,8),%r14
  movslq %r10d,%r12
  shl    $0x2,%r12
  mov    0x0(%rbp,%rax,8),%r11
  mov    $0x0,%edi
  lea    0x34(%rsp),%rbx
  jmp    L3
L138:
  movl   $0xffffffff,(%rax)
L172:
  add    $0x4,%rax
  cmp    %rbx,%rax
  je     L60
L147:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  je     L138
  mov    0x0(%rbp,%rdi,2),%rcx
  cmp    (%rcx,%r12,1),%edx
  jne    L172
  movl   $0xffffffff,(%rax)
  jmp    L172
L60:
  add    $0x4,%rdi
  cmp    $0x24,%rdi
  je     L137
L3:
  mov    (%r11,%rdi,1),%r8d
  lea    0x10(%rsp),%r13
  mov    %r13,%rax
  jmp    L147
L137:
  movslq %r9d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  lea    (%rax,%rax,2),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%r9d
  movslq %r9d,%r9
  lea    0x3(%r9),%rax
  mov    %rax,0x8(%rsp)
  movslq %r10d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r10d
  sub    %r10d,%eax
  lea    (%rax,%rax,2),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%r15d
  movslq %r15d,%r15
  shl    $0x2,%r15
  lea    0xc(%r15),%r11
  mov    $0xffffffff,%edi
  jmp    L2
L162:
  mov    %edx,(%rcx)
  add    $0x4,%rax
  cmp    %rbx,%rax
  je     L83
L23:
  mov    %rax,%rcx
  mov    %edi,%edx
  cmp    (%rax),%esi
  je     L162
  mov    (%rax),%edx
  jmp    L162
L83:
  add    $0x4,%r8
  cmp    %r11,%r8
  je     L48
L43:
  mov    (%r10,%r8,1),%esi
  mov    %r13,%rax
  jmp    L23
L48:
  add    $0x1,%r9
  cmp    0x8(%rsp),%r9
  je     L61
L2:
  mov    0x0(%rbp,%r9,8),%r10
  mov    %r15,%r8
  jmp    L43
L123:
  add    $0x4,%r13
  cmp    %rbx,%r13
  je     L102
L61:
  mov    0x0(%r13),%r15d
  cmp    $0xffffffff,%r15d
  je     L123
  mov    %rbp,%rdi
  call   <copy@plt>
  mov    %rax,%rdi
  mov    (%rax,%r14,1),%rax
  mov    %r15d,(%rax,%r12,1)
  call   <solve@plt>
  test   %rax,%rax
  je     L123
  jmp    L116
L102:
  mov    $0x0,%eax
L116:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L156
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L156:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int **recu(int **a, int ci, int cj) {
  int i, j, istart, iend, jstart, jend, table[9];
  for (i = 0; i < 9; i++)
    table[i] = i + 1;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9; j++)
      if (a[ci][i] == table[j])
        table[j] = -1;
      else if (a[i][cj] == table[j])
        table[j] = -1;
  istart = ((ci - (ci % 3)) / 3) * 3;
  iend = istart + 3;
  jstart = ((cj - cj % 3) / 3) * 3;
  jend = jstart + 3;
  for (; istart < iend; istart++) {
    for (j = jstart; j < jend; j++)
      for (i = 0; i < 9; i++) {
        if (a[istart][j] == table[i])
          table[i] = -1;
      }
  }
  int **m;
  for (i = 0; i < 9; i++) {
    if (table[i] == -1)
      continue;
    m = copy(a);
    m[ci][cj] = table[i];
    m = solve(m);
    if (m != NULL)
      return m;
  }
  return NULL;
}
```