user: Demonstrate the C code that generates the assembly output below:

```asm
<transfer_to_pdu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,%eax
  mov    %edi,%edx
  mov    %dl,-0x24(%rbp)
  mov    %ax,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movzwl -0x28(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cmp    $0x5d6,%eax
  jle    L29
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L23
L29:
  cmpw   $0x1fb,-0x28(%rbp)
  jbe    L1
  movzwl -0x28(%rbp),%ebx
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <gettext@plt>
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <printf@plt>
  movw   $0x1fb,-0x28(%rbp)
L1:
  movzwl -0x28(%rbp),%eax
  add    $0x4,%eax
  or     $0xfe,%ah
  mov    %eax,%edi
  call   <htons@plt>
  mov    %ax,-0x1a(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x1a(%rbp),%rax
  mov    $0x2,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0xcc,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x3(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x4d,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x4(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x55,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x5(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x24(%rbp),%eax
  mov    %al,(%rdx)
  movzwl -0x28(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x6(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x6(%rax),%edx
  movzwl -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
L23:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D11
type_guessed: string

tool: D9: Maximum of 1500 Bytes in LAN-Beacon frame exceeded, not all information will be transmitted. Please include less information.

tool: D11: Warning, TLV is %i Bytes long, exceeding maximum of 507 characters in String. End of string will be cut off.

assistant: ```c
void transfer_to_pdu(unsigned char subtype, void *source, char *combinedBeacon, int *currentByte, unsigned short int currentTLVlength) {
  if (1500 < (currentTLVlength + *currentByte + 6)) {
    puts(gettext("Maximum of 1500 Bytes in LAN-Beacon frame exceeded, not all information "
                 "will be transmitted. Please include less information."));
    return;
  }
  if (currentTLVlength > 507) {
    printf(gettext("Warning, TLV is %i Bytes long, exceeding maximum of 507 characters "
                   "in String. End of string will be cut off."),
           currentTLVlength);
    currentTLVlength = 507;
  }
  unsigned short int TLVheader_combined = htons((127 * 0b1000000000) | (currentTLVlength + 4));
  memcpy(&combinedBeacon[*currentByte], &TLVheader_combined, 2);
  combinedBeacon[*currentByte + 2] = 'L' | 0b10000000;
  combinedBeacon[*currentByte + 3] = 'M';
  combinedBeacon[*currentByte + 4] = 'U';
  combinedBeacon[*currentByte + 5] = subtype;
  memcpy(&combinedBeacon[*currentByte + 6], source, currentTLVlength);
  *currentByte = *currentByte + 6 + currentTLVlength;
}
```