ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<anorm2>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L35
  lea    -0x1(%rsi),%eax
  mov    $0x8,%ecx
  pxor   %xmm1,%xmm1
  lea    0x10(%rdi,%rax,8),%r8
  lea    0x10(,%rax,8),%r9
  add    $0x8,%rdi
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L21:
  mov    (%rax),%rdx
  add    $0x8,%rax
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L21
  add    $0x8,%rcx
  cmp    %r9,%rcx
  jne    L6
L28:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cltd
  idiv   %ebx
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
L35:
  pxor   %xmm1,%xmm1
  jmp    L28
```

assistant: ```c
double anorm2(double **a, int n) {
  int i, j;
  double sum = 0.0;
  for (j = 1; j <= n; j++)
    for (i = 1; i <= n; i++)
      sum += a[i][j] * a[i][j];
  return sqrt(sum) / n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<anorm2>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  mov    $0x8,%ecx
  pxor   %xmm1,%xmm1
  lea    0x10(%rdi,%rax,8),%r8
  lea    0x10(,%rax,8),%r9
  add    $0x8,%rdi
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rax),%rdx
  add    $0x8,%rax
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L2
  add    $0x8,%rcx
  cmp    %rcx,%r9
  jne    L33
L36:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cltd
  idiv   %ebx
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
L10:
  pxor   %xmm1,%xmm1
  jmp    L36
```

assistant: ```c
double anorm2(double **a, int n) {
  int i, j;
  double sum = 0.0;
  for (j = 1; j <= n; j++)
    for (i = 1; i <= n; i++)
      sum += a[i][j] * a[i][j];
  return sqrt(sum) / n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L7
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L7:
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long gcd(unsigned long long n1, unsigned long long n2) {
  unsigned long long tmp;
  while (n1 != 0) {
    tmp = n1;
    n1 = n2 % n1;
    n2 = tmp;
  }
  return n2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  jne    L29
  mov    %rsi,%rdi
  jmp    L15
L22:
  mov    %rdx,%rdi
L29:
  mov    $0x0,%edx
  div    %rdi
  mov    %rdi,%rax
  test   %rdx,%rdx
  jne    L22
L15:
  mov    %rdi,%rax
  ret
```

assistant: ```c
unsigned long long gcd(unsigned long long n1, unsigned long long n2) {
  unsigned long long tmp;
  while (n1 != 0) {
    tmp = n1;
    n1 = n2 % n1;
    n2 = tmp;
  }
  return n2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gcd>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  test   %rdi,%rdi
  jne    L11
  jmp    L3
  nopl   0x0(%rax)
L10:
  mov    %rdx,%r8
L11:
  xor    %edx,%edx
  div    %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L10
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L3:
  mov    %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long long gcd(unsigned long long n1, unsigned long long n2) {
  unsigned long long tmp;
  while (n1 != 0) {
    tmp = n1;
    n1 = n2 % n1;
    n2 = tmp;
  }
  return n2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  test   %rdi,%rdi
  jne    L11
  jmp    L27
  nopl   0x0(%rax)
L10:
  mov    %rdx,%r8
L11:
  xor    %edx,%edx
  div    %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L10
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L27:
  mov    %rsi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long long gcd(unsigned long long n1, unsigned long long n2) {
  unsigned long long tmp;
  while (n1 != 0) {
    tmp = n1;
    n1 = n2 % n1;
    n2 = tmp;
  }
  return n2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L4
L17:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L13
  mov    $0x0,%eax
  jmp    L31
L13:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  mov    $0x1,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int isprime(int n) {
  int i;
  for (i = 2; i < n; ++i)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isprime>:
  endbr64
  cmp    $0x2,%edi
  jle    L16
  test   $0x1,%dil
  je     L43
  mov    $0x2,%ecx
L2:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L3
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L2
L25:
  ret
L3:
  mov    $0x1,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
L43:
  mov    $0x0,%eax
  jmp    L25
```

assistant: ```c
int isprime(int n) {
  int i;
  for (i = 2; i < n; ++i)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isprime>:
  endbr64
  cmp    $0x2,%edi
  jle    L51
  test   $0x1,%dil
  je     L33
  mov    $0x2,%ecx
  jmp    L47
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L14
L47:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L41
L51:
  mov    $0x1,%edx
L14:
  mov    %edx,%eax
  ret
L33:
  xor    %edx,%edx
  jmp    L14
```

assistant: ```c
int isprime(int n) {
  int i;
  for (i = 2; i < n; ++i)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isprime>:
  endbr64
  cmp    $0x2,%edi
  jle    L26
  test   $0x1,%dil
  je     L22
  mov    $0x2,%ecx
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L8
L19:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L44
L26:
  mov    $0x1,%edx
L8:
  mov    %edx,%eax
  ret
L22:
  xor    %edx,%edx
  jmp    L8
```

assistant: ```c
int isprime(int n) {
  int i;
  for (i = 2; i < n; ++i)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<regc_max_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L10:
  mov    -0x8(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L24
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <arch_regc_size@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jbe    L24
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L24:
  addl   $0x1,-0x8(%rbp)
L15:
  cmpl   $0xd,-0x8(%rbp)
  jle    L10
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned regc_max_size(struct compile_state *state, int classes) {
  unsigned max_size;
  int i;
  max_size = 0;
  for (i = 0; i < 14; i++) {
    if (classes & (1 << i)) {
      unsigned size;
      size = arch_regc_size(state, i);
      if (size > max_size) {
        max_size = size;
      }
    }
  }
  return max_size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<regc_max_size>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L17
L16:
  add    $0x1,%ebx
  cmp    $0xe,%ebx
  je     L12
L17:
  bt     %ebx,%ebp
  jae    L16
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  jmp    L16
L12:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned regc_max_size(struct compile_state *state, int classes) {
  unsigned max_size;
  int i;
  max_size = 0;
  for (i = 0; i < 14; i++) {
    if (classes & (1 << i)) {
      unsigned size;
      size = arch_regc_size(state, i);
      if (size > max_size) {
        max_size = size;
      }
    }
  }
  return max_size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<regc_max_size>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x1,%ebx
  cmp    $0xe,%ebx
  je     L2
L17:
  bt     %ebx,%ebp
  jae    L28
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  add    $0x1,%ebx
  cmp    $0xe,%ebx
  jne    L17
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned regc_max_size(struct compile_state *state, int classes) {
  unsigned max_size;
  int i;
  max_size = 0;
  for (i = 0; i < 14; i++) {
    if (classes & (1 << i)) {
      unsigned size;
      size = arch_regc_size(state, i);
      if (size > max_size) {
        max_size = size;
      }
    }
  }
  return max_size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<regc_max_size>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  and    $0x1,%esi
  jne    L105
  xor    %r12d,%r12d
  test   $0x2,%bl
  jne    L42
L52:
  test   $0x4,%bl
  jne    L173
L152:
  test   $0x8,%bl
  jne    L135
L164:
  test   $0x10,%bl
  jne    L26
L188:
  test   $0x20,%bl
  jne    L49
L119:
  test   $0x40,%bl
  jne    L249
L37:
  test   $0x80,%bl
  jne    L111
L19:
  test   $0x1,%bh
  jne    L44
L180:
  test   $0x2,%bh
  jne    L169
L215:
  test   $0x4,%bh
  jne    L93
L235:
  test   $0x8,%bh
  jne    L100
L16:
  test   $0x10,%bh
  jne    L265
L244:
  and    $0x20,%bh
  jne    L64
L203:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L105:
  xor    %esi,%esi
  call   <arch_regc_size@plt>
  mov    %eax,%r12d
  test   $0x2,%bl
  je     L52
L42:
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x4,%bl
  je     L152
L173:
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x8,%bl
  je     L164
L135:
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x10,%bl
  je     L188
L26:
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x20,%bl
  je     L119
L49:
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x40,%bl
  je     L37
L249:
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x80,%bl
  je     L19
L111:
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x1,%bh
  je     L180
L44:
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x2,%bh
  je     L215
L169:
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x4,%bh
  je     L235
L93:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x8,%bh
  je     L16
L100:
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  test   $0x10,%bh
  je     L244
L265:
  mov    $0xc,%esi
  mov    %rbp,%rdi
  call   <arch_regc_size@plt>
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  and    $0x20,%bh
  je     L203
L64:
  mov    %rbp,%rdi
  mov    $0xd,%esi
  call   <arch_regc_size@plt>
  pop    %rbx
  pop    %rbp
  cmp    %eax,%r12d
  cmovb  %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned regc_max_size(struct compile_state *state, int classes) {
  unsigned max_size;
  int i;
  max_size = 0;
  for (i = 0; i < 14; i++) {
    if (classes & (1 << i)) {
      unsigned size;
      size = arch_regc_size(state, i);
      if (size > max_size) {
        max_size = size;
      }
    }
  }
  return max_size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adds2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int adds2(long long x, int y) {
  long long t = x + ((long long)y << 3);
  return !!t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adds2>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int adds2(long long x, int y) {
  long long t = x + ((long long)y << 3);
  return !!t;
}
```
user: What is the c source code of the assembly code below?

```asm
<adds2>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int adds2(long long x, int y) {
  long long t = x + ((long long)y << 3);
  return !!t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<adds2>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int adds2(long long x, int y) {
  long long t = x + ((long long)y << 3);
  return !!t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ZBarcode_Version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5211,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ZBarcode_Version() {
  if (9) {
    return (2 * 10000) + (10 * 100) + 0 * 10 + 9;
  }
  return (2 * 10000) + (10 * 100) + 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ZBarcode_Version>:
  endbr64
  mov    $0x5211,%eax
  ret
```

assistant: ```c
int ZBarcode_Version() {
  if (9) {
    return (2 * 10000) + (10 * 100) + 0 * 10 + 9;
  }
  return (2 * 10000) + (10 * 100) + 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ZBarcode_Version>:
  endbr64
  mov    $0x5211,%eax
  ret
```

assistant: ```c
int ZBarcode_Version() {
  if (9) {
    return (2 * 10000) + (10 * 100) + 0 * 10 + 9;
  }
  return (2 * 10000) + (10 * 100) + 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<ZBarcode_Version>:
  endbr64
  mov    $0x5211,%eax
  ret
```

assistant: ```c
int ZBarcode_Version() {
  if (9) {
    return (2 * 10000) + (10 * 100) + 0 * 10 + 9;
  }
  return (2 * 10000) + (10 * 100) + 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<znajdz_slowo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L27
L15:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gdzie_jest_cale_slowo@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L29
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x14(%rbp),%edx
  add    %edx,%eax
  add    %eax,-0x20(%rbp)
L27:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L15
  jmp    L16
L29:
  nop
L16:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *znajdz_slowo(char *slowo, char *linia) {
  int idx = 0;
  int ilosc_wystapien = 1;
  int dlugosc_linii = strlen(linia);
  int *indeksy;
  int *wystapienia = malloc(dlugosc_linii * sizeof(int));
  wystapienia[0] = 0;
  while (idx < dlugosc_linii - 1) {
    int adres = gdzie_jest_cale_slowo(slowo, linia + idx);
    if (adres < 0)
      break;
    else {
      wystapienia[ilosc_wystapien] = idx + adres;
      ilosc_wystapien++;
      idx += adres + strlen(slowo);
    }
  }
  wystapienia[0] = ilosc_wystapien - 1;
  indeksy = realloc(wystapienia, ilosc_wystapien * sizeof(int));
  return indeksy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<znajdz_slowo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rdi
  mov    %rsi,(%rsp)
  call   <strlen@plt>
  mov    %eax,%r15d
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  movl   $0x0,(%rax)
  sub    $0x1,%r15d
  test   %r15d,%r15d
  jle    L8
  lea    0x4(%rax),%r12
  mov    $0x1,%r13d
  mov    $0x0,%ebp
L12:
  movslq %ebp,%rsi
  add    (%rsp),%rsi
  mov    %r14,%rdi
  call   <gdzie_jest_cale_slowo@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L27
  lea    (%rax,%rbp,1),%eax
  mov    %eax,(%r12)
  add    $0x1,%r13d
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    %eax,%ebp
  add    $0x4,%r12
  cmp    %r15d,%ebp
  jl     L12
L27:
  lea    -0x1(%r13),%eax
  mov    0x8(%rsp),%rdi
  mov    %eax,(%rdi)
  lea    0x0(,%r13,4),%esi
  call   <realloc@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    $0x1,%r13d
  jmp    L27
```

assistant: ```c
int *znajdz_slowo(char *slowo, char *linia) {
  int idx = 0;
  int ilosc_wystapien = 1;
  int dlugosc_linii = strlen(linia);
  int *indeksy;
  int *wystapienia = malloc(dlugosc_linii * sizeof(int));
  wystapienia[0] = 0;
  while (idx < dlugosc_linii - 1) {
    int adres = gdzie_jest_cale_slowo(slowo, linia + idx);
    if (adres < 0)
      break;
    else {
      wystapienia[ilosc_wystapien] = idx + adres;
      ilosc_wystapien++;
      idx += adres + strlen(slowo);
    }
  }
  wystapienia[0] = ilosc_wystapien - 1;
  indeksy = realloc(wystapienia, ilosc_wystapien * sizeof(int));
  return indeksy;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<znajdz_slowo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    -0x1(%r14),%edx
  mov    %rax,0x18(%rsp)
  movl   $0x0,(%rax)
  mov    %edx,0x14(%rsp)
  test   %edx,%edx
  jle    L37
  lea    0x4(%rax),%rbx
  mov    $0x1,%r13d
  xor    %r14d,%r14d
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L25:
  lea    (%rax,%r14,1),%eax
  mov    %rbp,%rdi
  lea    0x1(%r13),%r12d
  add    $0x4,%rbx
  mov    %eax,-0x4(%rbx)
  call   <strlen@plt>
  add    %r15d,%eax
  add    %eax,%r14d
  cmp    0x14(%rsp),%r14d
  jge    L11
  mov    %r12d,%r13d
L35:
  movslq %r14d,%rsi
  mov    %rbp,%rdi
  add    0x8(%rsp),%rsi
  call   <gdzie_jest_cale_slowo@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jns    L25
  lea    -0x1(%r13),%eax
  lea    0x0(,%r13,4),%esi
L20:
  mov    0x18(%rsp),%rcx
  mov    %eax,(%rcx)
  add    $0x28,%rsp
  mov    %rcx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <realloc@plt>
  nopw   0x0(%rax,%rax,1)
L11:
  lea    0x0(,%r12,4),%esi
  mov    %r13d,%eax
  jmp    L20
L37:
  mov    $0x4,%esi
  xor    %eax,%eax
  jmp    L20
```

assistant: ```c
int *znajdz_slowo(char *slowo, char *linia) {
  int idx = 0;
  int ilosc_wystapien = 1;
  int dlugosc_linii = strlen(linia);
  int *indeksy;
  int *wystapienia = malloc(dlugosc_linii * sizeof(int));
  wystapienia[0] = 0;
  while (idx < dlugosc_linii - 1) {
    int adres = gdzie_jest_cale_slowo(slowo, linia + idx);
    if (adres < 0)
      break;
    else {
      wystapienia[ilosc_wystapien] = idx + adres;
      ilosc_wystapien++;
      idx += adres + strlen(slowo);
    }
  }
  wystapienia[0] = ilosc_wystapien - 1;
  indeksy = realloc(wystapienia, ilosc_wystapien * sizeof(int));
  return indeksy;
}
```
user: Translate the below assembly code into C programming language:

```asm
<znajdz_slowo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    -0x1(%r14),%edx
  mov    %rax,0x18(%rsp)
  movl   $0x0,(%rax)
  mov    %edx,0x14(%rsp)
  test   %edx,%edx
  jle    L52
  lea    0x4(%rax),%rbx
  mov    $0x1,%r13d
  xor    %r14d,%r14d
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L13:
  lea    (%rax,%r14,1),%eax
  mov    %rbp,%rdi
  lea    0x1(%r13),%r12d
  add    $0x4,%rbx
  mov    %eax,-0x4(%rbx)
  call   <strlen@plt>
  add    %r15d,%eax
  add    %eax,%r14d
  cmp    0x14(%rsp),%r14d
  jge    L40
  mov    %r12d,%r13d
L56:
  movslq %r14d,%rsi
  mov    %rbp,%rdi
  add    0x8(%rsp),%rsi
  call   <gdzie_jest_cale_slowo@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jns    L13
  lea    -0x1(%r13),%eax
  lea    0x0(,%r13,4),%esi
L5:
  mov    0x18(%rsp),%rcx
  mov    %eax,(%rcx)
  add    $0x28,%rsp
  mov    %rcx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <realloc@plt>
  nopw   0x0(%rax,%rax,1)
L40:
  lea    0x0(,%r12,4),%esi
  mov    %r13d,%eax
  jmp    L5
L52:
  mov    $0x4,%esi
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
int *znajdz_slowo(char *slowo, char *linia) {
  int idx = 0;
  int ilosc_wystapien = 1;
  int dlugosc_linii = strlen(linia);
  int *indeksy;
  int *wystapienia = malloc(dlugosc_linii * sizeof(int));
  wystapienia[0] = 0;
  while (idx < dlugosc_linii - 1) {
    int adres = gdzie_jest_cale_slowo(slowo, linia + idx);
    if (adres < 0)
      break;
    else {
      wystapienia[ilosc_wystapien] = idx + adres;
      ilosc_wystapien++;
      idx += adres + strlen(slowo);
    }
  }
  wystapienia[0] = ilosc_wystapien - 1;
  indeksy = realloc(wystapienia, ilosc_wystapien * sizeof(int));
  return indeksy;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mloop_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mloop__do_exit@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mloop__break_out@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) void mloop_exit(struct mloop *self) {
  mloop__do_exit(self);
  mloop__break_out(self);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mloop_exit>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mloop__do_exit@plt>
  mov    %rbx,%rdi
  call   <mloop__break_out@plt>
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((visibility("default"))) void mloop_exit(struct mloop *self) {
  mloop__do_exit(self);
  mloop__break_out(self);
}
```
user: What is the c source code of the assembly code below:

```asm
<mloop_exit>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <mloop__do_exit@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <mloop__break_out@plt>
```

assistant: ```c
__attribute__((visibility("default"))) void mloop_exit(struct mloop *self) {
  mloop__do_exit(self);
  mloop__break_out(self);
}
```