ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<serial_write_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %ax,-0x4(%rbp)
  jmp    L1
L4:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  movzwl -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <outb@plt>
  addq   $0x1,-0x10(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void serial_write_text(unsigned short com, char *buffer, int length) {
  while (length--) {
    outb((com), *buffer);
    buffer++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<serial_write_text>:
  endbr64
  test   %edx,%edx
  je     L12
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%edx
  lea    (%rsi,%rdx,1),%rbp
  movzwl %di,%r12d
L19:
  movsbl (%rbx),%esi
  mov    %r12d,%edi
  call   <outb@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  ret
```

assistant: ```c
void serial_write_text(unsigned short com, char *buffer, int length) {
  while (length--) {
    outb((com), *buffer);
    buffer++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<serial_write_text>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  add    %rsi,%rbp
  test   %edx,%edx
  je     L14
  mov    %rsi,%rbx
  movzwl %di,%r12d
  nopl   0x0(%rax,%rax,1)
L0:
  movsbl (%rbx),%esi
  mov    %r12d,%edi
  add    $0x1,%rbx
  call   <outb@plt>
  cmp    %rbp,%rbx
  jne    L0
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void serial_write_text(unsigned short com, char *buffer, int length) {
  while (length--) {
    outb((com), *buffer);
    buffer++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<serial_write_text>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  add    %rsi,%rbp
  test   %edx,%edx
  je     L17
  mov    %rsi,%rbx
  movzwl %di,%r12d
  nopl   0x0(%rax,%rax,1)
L13:
  movsbl (%rbx),%esi
  mov    %r12d,%edi
  add    $0x1,%rbx
  call   <outb@plt>
  cmp    %rbx,%rbp
  jne    L13
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void serial_write_text(unsigned short com, char *buffer, int length) {
  while (length--) {
    outb((com), *buffer);
    buffer++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<get_orthonormal_basis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xc0(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat_transpose_matrix_d3@plt>
  lea    -0x50(%rbp),%rdx
  lea    -0xa0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat_copy_vector_d3@plt>
  lea    -0x50(%rbp),%rax
  lea    0x18(%rax),%rdx
  lea    -0x50(%rbp),%rax
  lea    -0xa0(%rbp),%rcx
  add    $0x30,%rcx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <mat_cross_product_d3@plt>
  lea    -0x50(%rbp),%rax
  lea    -0xa0(%rbp),%rdx
  lea    0x30(%rdx),%rsi
  lea    -0xa0(%rbp),%rdx
  lea    0x18(%rdx),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <mat_cross_product_d3@plt>
  movl   $0x0,-0xb0(%rbp)
  jmp    L7
L2:
  lea    -0xa0(%rbp),%rcx
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rcx,%rax
  mov    %rax,%rdi
  call   <mat_norm_squared_d3@plt>
  mov    %eax,%edi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0xa8(%rbp)
  movl   $0x0,-0xac(%rbp)
  jmp    L19
L1:
  mov    -0xac(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movsd  -0xa0(%rbp,%rax,8),%xmm0
  divsd  -0xa8(%rbp),%xmm0
  mov    -0xac(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movsd  %xmm0,-0xa0(%rbp,%rax,8)
  addl   $0x1,-0xac(%rbp)
L19:
  cmpl   $0x2,-0xac(%rbp)
  jle    L1
  addl   $0x1,-0xb0(%rbp)
L7:
  cmpl   $0x2,-0xb0(%rbp)
  jle    L2
  lea    -0xa0(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat_transpose_matrix_d3@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void get_orthonormal_basis(double basis[3][3], double lattice[3][3]) {
  int i, j;
  double length;
  double basis_T[3][3], lattice_T[3][3];
  mat_transpose_matrix_d3(lattice_T, lattice);
  mat_copy_vector_d3(basis_T[0], lattice_T[0]);
  mat_cross_product_d3(basis_T[2], lattice_T[0], lattice_T[1]);
  mat_cross_product_d3(basis_T[1], basis_T[2], lattice_T[0]);
  for (i = 0; i < 3; i++) {
    length = sqrt(mat_norm_squared_d3(basis_T[i]));
    for (j = 0; j < 3; j++) {
      basis_T[i][j] /= length;
    }
  }
  mat_transpose_matrix_d3(basis, basis_T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_orthonormal_basis>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rbp
  mov    %rbp,%rdi
  call   <mat_transpose_matrix_d3@plt>
  mov    %rsp,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mat_copy_vector_d3@plt>
  lea    0x68(%rsp),%rdx
  lea    0x30(%rsp),%r13
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <mat_cross_product_d3@plt>
  lea    0x18(%rsp),%rdi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  call   <mat_cross_product_d3@plt>
  lea    0x48(%rsp),%rbp
L7:
  mov    %rbx,%rdi
  call   <mat_norm_squared_d3@plt>
  mov    %eax,%edi
  call   <sqrt@plt>
  movsd  (%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbx)
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbx)
  add    $0x18,%rbx
  cmp    %rbp,%rbx
  jne    L7
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <mat_transpose_matrix_d3@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_orthonormal_basis(double basis[3][3], double lattice[3][3]) {
  int i, j;
  double length;
  double basis_T[3][3], lattice_T[3][3];
  mat_transpose_matrix_d3(lattice_T, lattice);
  mat_copy_vector_d3(basis_T[0], lattice_T[0]);
  mat_cross_product_d3(basis_T[2], lattice_T[0], lattice_T[1]);
  mat_cross_product_d3(basis_T[1], basis_T[2], lattice_T[0]);
  for (i = 0; i < 3; i++) {
    length = sqrt(mat_norm_squared_d3(basis_T[i]));
    for (j = 0; j < 3; j++) {
      basis_T[i][j] /= length;
    }
  }
  mat_transpose_matrix_d3(basis, basis_T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_orthonormal_basis>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%r14
  mov    %rsp,%r13
  lea    0x30(%rsp),%rbp
  mov    %r14,%rdi
  mov    %r13,%rbx
  call   <mat_transpose_matrix_d3@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <mat_copy_vector_d3@plt>
  mov    %rbp,%rdi
  lea    0x68(%rsp),%rdx
  mov    %r14,%rsi
  call   <mat_cross_product_d3@plt>
  mov    %rbp,%rsi
  lea    0x18(%rsp),%rdi
  mov    %r14,%rdx
  call   <mat_cross_product_d3@plt>
  lea    0x48(%rsp),%rbp
L10:
  mov    %rbx,%rdi
  add    $0x18,%rbx
  call   <mat_norm_squared_d3@plt>
  mov    %eax,%edi
  call   <sqrt@plt>
  movsd  -0x18(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x18(%rbx)
  movsd  -0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x10(%rbx)
  movsd  -0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L10
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <mat_transpose_matrix_d3@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_orthonormal_basis(double basis[3][3], double lattice[3][3]) {
  int i, j;
  double length;
  double basis_T[3][3], lattice_T[3][3];
  mat_transpose_matrix_d3(lattice_T, lattice);
  mat_copy_vector_d3(basis_T[0], lattice_T[0]);
  mat_cross_product_d3(basis_T[2], lattice_T[0], lattice_T[1]);
  mat_cross_product_d3(basis_T[1], basis_T[2], lattice_T[0]);
  for (i = 0; i < 3; i++) {
    length = sqrt(mat_norm_squared_d3(basis_T[i]));
    for (j = 0; j < 3; j++) {
      basis_T[i][j] /= length;
    }
  }
  mat_transpose_matrix_d3(basis, basis_T);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_orthonormal_basis>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%r14
  mov    %rsp,%r13
  lea    0x30(%rsp),%rbp
  mov    %r14,%rdi
  mov    %r13,%rbx
  call   <mat_transpose_matrix_d3@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <mat_copy_vector_d3@plt>
  mov    %rbp,%rdi
  lea    0x68(%rsp),%rdx
  mov    %r14,%rsi
  call   <mat_cross_product_d3@plt>
  mov    %rbp,%rsi
  lea    0x18(%rsp),%rdi
  mov    %r14,%rdx
  call   <mat_cross_product_d3@plt>
  lea    0x48(%rsp),%rbp
L10:
  mov    %rbx,%rdi
  add    $0x18,%rbx
  call   <mat_norm_squared_d3@plt>
  mov    %eax,%edi
  call   <sqrt@plt>
  movupd -0x18(%rbx),%xmm1
  movapd %xmm0,%xmm2
  unpcklpd %xmm2,%xmm2
  divpd  %xmm2,%xmm1
  movups %xmm1,-0x18(%rbx)
  movsd  -0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L10
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <mat_transpose_matrix_d3@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_orthonormal_basis(double basis[3][3], double lattice[3][3]) {
  int i, j;
  double length;
  double basis_T[3][3], lattice_T[3][3];
  mat_transpose_matrix_d3(lattice_T, lattice);
  mat_copy_vector_d3(basis_T[0], lattice_T[0]);
  mat_cross_product_d3(basis_T[2], lattice_T[0], lattice_T[1]);
  mat_cross_product_d3(basis_T[1], basis_T[2], lattice_T[0]);
  for (i = 0; i < 3; i++) {
    length = sqrt(mat_norm_squared_d3(basis_T[i]));
    for (j = 0; j < 3; j++) {
      basis_T[i][j] /= length;
    }
  }
  mat_transpose_matrix_d3(basis, basis_T);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Log_compareEntries>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x7(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    $0x7,%rax
  mov    $0x13,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  mov    %eax,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Log_compareEntries(char *entry1, char *entry2) {
  int comp = strncmp(&entry1[7], &entry2[7], 19);
  if (comp == 0)
    comp = strncmp(&entry1[1], &entry2[1], 4);
  return comp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Log_compareEntries>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x7(%rsi),%rsi
  lea    0x7(%rdi),%rdi
  mov    $0x13,%edx
  call   <strncmp@plt>
  test   %eax,%eax
  je     L1
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    0x1(%rbp),%rsi
  lea    0x1(%rbx),%rdi
  mov    $0x4,%edx
  call   <strncmp@plt>
  jmp    L17
```

assistant: ```c
int Log_compareEntries(char *entry1, char *entry2) {
  int comp = strncmp(&entry1[7], &entry2[7], 19);
  if (comp == 0)
    comp = strncmp(&entry1[1], &entry2[1], 4);
  return comp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Log_compareEntries>:
  endbr64
  push   %rbp
  mov    $0x13,%edx
  mov    %rsi,%rbp
  add    $0x7,%rsi
  push   %rbx
  mov    %rdi,%rbx
  add    $0x7,%rdi
  sub    $0x8,%rsp
  call   <strncmp@plt>
  test   %eax,%eax
  je     L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  add    $0x8,%rsp
  lea    0x1(%rbp),%rsi
  lea    0x1(%rbx),%rdi
  mov    $0x4,%edx
  pop    %rbx
  pop    %rbp
  jmp    1050 <strncmp@plt>
```

assistant: ```c
int Log_compareEntries(char *entry1, char *entry2) {
  int comp = strncmp(&entry1[7], &entry2[7], 19);
  if (comp == 0)
    comp = strncmp(&entry1[1], &entry2[1], 4);
  return comp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Log_compareEntries>:
  endbr64
  push   %rbp
  mov    $0x13,%edx
  mov    %rsi,%rbp
  add    $0x7,%rsi
  push   %rbx
  mov    %rdi,%rbx
  add    $0x7,%rdi
  sub    $0x8,%rsp
  call   <strncmp@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L6:
  add    $0x8,%rsp
  lea    0x1(%rbp),%rsi
  lea    0x1(%rbx),%rdi
  mov    $0x4,%edx
  pop    %rbx
  pop    %rbp
  jmp    1050 <strncmp@plt>
```

assistant: ```c
int Log_compareEntries(char *entry1, char *entry2) {
  int comp = strncmp(&entry1[7], &entry2[7], 19);
  if (comp == 0)
    comp = strncmp(&entry1[1], &entry2[1], 4);
  return comp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <init@plt>
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
  lea    D10(%rip),%r13
L40:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L40
  lea    D30(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rbp
  lea    D4(%rip),%r13
  jmp    L42
L67:
  mov    $0x100,%edx
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L50:
  add    $0x4,%rbp
  cmp    %r12,%rbp
  je     L63
L42:
  mov    0x0(%rbp),%edi
  call   <lsearch@plt>
  cmp    $0x100,%eax
  je     L67
  lea    0x1(%rax),%edx
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L50
L63:
  mov    $0x0,%eax
  call   <sort@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D4(%rip),%rbp
L41:
  mov    (%rbx),%edi
  call   <bsearch@plt>
  mov    %eax,%edx
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L41
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D30
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D52
data_type: string

tool: D23: 
Enter the 10 no.s to be searched 

tool: D10: %d

tool: D30: 
No. of comparisons for linear search

tool: D4: 
For %d comparisons are %d

tool: D52: 
No. of comparisons for binary search

assistant: ```c
int main() {
  int b[10], ans, i;
  init();
  printf("\nEnter the 10 no.s to be searched ");
  for (i = 0; i < 10; i++)
    scanf("%d", &b[i]);
  printf("\nNo. of comparisons for linear search\n");
  for (i = 0; i < 10; i++) {
    ans = lsearch(b[i]);
    if (ans != 256)
      printf("\nFor %d comparisons are %d", b[i], ans + 1);
    else
      printf("\nFor %d comparisons are %d", b[i], ans);
  }
  sort();
  printf("\nNo. of comparisons for binary search\n");
  for (i = 0; i < 10; i++) {
    ans = bsearch(b[i]);
    printf("\nFor %d comparisons are %d", b[i], ans);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%r12
  call   <init@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %rbp,%r12
  jne    L23
  lea    D29(%rip),%rdi
  mov    %rbx,%r13
  lea    D43(%rip),%r12
  call   <puts@plt>
  jmp    L15
  nopl   0x0(%rax)
L3:
  mov    0x0(%r13),%esi
  lea    0x1(%rax),%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  je     L36
L15:
  mov    0x0(%r13),%edi
  call   <lsearch@plt>
  cmp    $0x100,%eax
  jne    L3
  mov    0x0(%r13),%esi
  mov    $0x100,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L15
L36:
  xor    %eax,%eax
  call   <sort@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L69:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <bsearch@plt>
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L69
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D41
type_guessed: string
name: unpack_data
arguments: data_label: D29
type_guessed: string
name: unpack_data
arguments: data_label: D43
type_guessed: string
name: unpack_data
arguments: data_label: D23
type_guessed: string

tool: D4: %d

tool: D41: 
Enter the 10 no.s to be searched 

tool: D29: 
No. of comparisons for linear search

tool: D43: 
For %d comparisons are %d

tool: D23: 
No. of comparisons for binary search

assistant: ```c
int main() {
  int b[10], ans, i;
  init();
  printf("\nEnter the 10 no.s to be searched ");
  for (i = 0; i < 10; i++)
    scanf("%d", &b[i]);
  printf("\nNo. of comparisons for linear search\n");
  for (i = 0; i < 10; i++) {
    ans = lsearch(b[i]);
    if (ans != 256)
      printf("\nFor %d comparisons are %d", b[i], ans + 1);
    else
      printf("\nFor %d comparisons are %d", b[i], ans);
  }
  sort();
  printf("\nNo. of comparisons for binary search\n");
  for (i = 0; i < 10; i++) {
    ans = bsearch(b[i]);
    printf("\nFor %d comparisons are %d", b[i], ans);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%r12
  call   <init@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %rbp,%r12
  jne    L59
  lea    D16(%rip),%rdi
  mov    %rbx,%r13
  lea    D11(%rip),%r12
  call   <puts@plt>
  jmp    L5
  nopl   0x0(%rax)
L55:
  mov    0x0(%r13),%esi
  lea    0x1(%rax),%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  je     L66
L5:
  mov    0x0(%r13),%edi
  call   <lsearch@plt>
  cmp    $0x100,%eax
  jne    L55
  mov    0x0(%r13),%esi
  mov    $0x100,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L5
L66:
  xor    %eax,%eax
  call   <sort@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L27:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <bsearch@plt>
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L27
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string
name: disassemble_data
arguments: data_tag: D35
type_guessed: string

tool: D15: %d

tool: D9: 
Enter the 10 no.s to be searched 

tool: D16: 
No. of comparisons for linear search

tool: D11: 
For %d comparisons are %d

tool: D35: 
No. of comparisons for binary search

assistant: ```c
int main() {
  int b[10], ans, i;
  init();
  printf("\nEnter the 10 no.s to be searched ");
  for (i = 0; i < 10; i++)
    scanf("%d", &b[i]);
  printf("\nNo. of comparisons for linear search\n");
  for (i = 0; i < 10; i++) {
    ans = lsearch(b[i]);
    if (ans != 256)
      printf("\nFor %d comparisons are %d", b[i], ans + 1);
    else
      printf("\nFor %d comparisons are %d", b[i], ans);
  }
  sort();
  printf("\nNo. of comparisons for binary search\n");
  for (i = 0; i < 10; i++) {
    ans = bsearch(b[i]);
    printf("\nFor %d comparisons are %d", b[i], ans);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sendGameBoard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %esi,-0x8c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L0
L14:
  mov    -0x74(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x74(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x74(%rbp)
L0:
  mov    -0x74(%rbp),%eax
  cmp    -0x8c(%rbp),%eax
  jl     L14
  mov    $0x0,%eax
  call   <tx_Handshake@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L10
L46:
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <sendSerialMessage@plt>
  addl   $0x1,-0x74(%rbp)
L10:
  mov    -0x74(%rbp),%eax
  cmp    -0x8c(%rbp),%eax
  jl     L46
  mov    $0xa,%edi
  call   <sendSerialMessage@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: tx_Handshake established!


assistant: ```c
int sendGameBoard(volatile int gameBoard[], int length) {
  int i = 0;
  char charGameBoard[101];
  for (i = 0; i < length; i++) {
    charGameBoard[i] = (char)(((int)'0') + gameBoard[i]);
  }
  tx_Handshake();
  printf("tx_Handshake established!\n");
  for (i = 0; i < length; i++) {
    sendSerialMessage(charGameBoard[i]);
  }
  sendSerialMessage('\n');
  return 0;
}
```