ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D19(%rip),%r15
  jmp    L10
L1:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L8
L10:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L33:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L33
  jmp    L1
L8:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_infered: string
name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D20
type_infered: string

tool: D19: dmin

tool: D28: # c::%s:len=%d


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmin", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D9(%rip),%r15
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L7:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L2:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L2
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L7
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string
name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D11
type_infered: string

tool: D9: dmin

tool: D13: # c::%s:len=%d


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmin", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D8(%rip),%r15
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L3:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L16:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L16
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L3
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D15
type_guessed: string

tool: D8: dmin

tool: D18: # c::%s:len=%d


tool: D15: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmin", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x34(%rbp)
  jg     L15
  mov    $0x1,%eax
  jmp    L35
L15:
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <load_file@plt>
  test   %eax,%eax
  jne    L9
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x2,%eax
  jmp    L35
L9:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <b64_get_ascii_wc@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L55
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x2,%eax
  jmp    L35
L55:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <b64_decode@plt>
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%rsi
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <xor_decode@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char *encdata, *decdata;
  size_t b64encdatalen, encdatalen;
  if (argc < 3)
    return 0x1;
  if (!load_file(argv[1], (char **)&encdata, &b64encdatalen)) {
    free(encdata);
    return 0x2;
  }
  encdatalen = 1 + b64_get_ascii_wc(b64encdatalen);
  decdata = malloc(encdatalen * sizeof(*encdata));
  if (NULL == decdata) {
    free(encdata);
    return 0x2;
  }
  memset(decdata, 0, encdatalen * sizeof(*encdata));
  b64_decode((char *)decdata, (char *)encdata, b64encdatalen);
  memcpy(encdata, decdata, (encdatalen - 1) * sizeof(*encdata));
  encdata[encdatalen] = '\0';
  memset(decdata, 0, encdatalen * sizeof(*encdata));
  xor_decode(decdata, encdata, encdatalen, (unsigned char *)argv[2], strlen(argv[2]));
  write(1, decdata, encdatalen);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jg     L42
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  mov    %rsi,%r12
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    0x8(%r12),%rdi
  call   <load_file@plt>
  test   %eax,%eax
  je     L66
  mov    0x10(%rsp),%rdi
  call   <b64_get_ascii_wc@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <b64_decode@plt>
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax,%rbx,1)
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    0x10(%r12),%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    0x10(%r12),%rcx
  mov    %rbx,%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <xor_decode@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  jmp    L9
L66:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    $0x2,%eax
  jmp    L9
L7:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    $0x2,%eax
  jmp    L9
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char *encdata, *decdata;
  size_t b64encdatalen, encdatalen;
  if (argc < 3)
    return 0x1;
  if (!load_file(argv[1], (char **)&encdata, &b64encdatalen)) {
    free(encdata);
    return 0x2;
  }
  encdatalen = 1 + b64_get_ascii_wc(b64encdatalen);
  decdata = malloc(encdatalen * sizeof(*encdata));
  if (NULL == decdata) {
    free(encdata);
    return 0x2;
  }
  memset(decdata, 0, encdatalen * sizeof(*encdata));
  b64_decode((char *)decdata, (char *)encdata, b64encdatalen);
  memcpy(encdata, decdata, (encdatalen - 1) * sizeof(*encdata));
  encdata[encdatalen] = '\0';
  memset(decdata, 0, encdatalen * sizeof(*encdata));
  xor_decode(decdata, encdata, encdatalen, (unsigned char *)argv[2], strlen(argv[2]));
  write(1, decdata, encdatalen);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jg     L4
L25:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %rsi,%rbx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    0x8(%rbx),%rdi
  call   <load_file@plt>
  test   %eax,%eax
  je     L34
  mov    0x10(%rsp),%rdi
  call   <b64_get_ascii_wc@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L34
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <b64_decode@plt>
  mov    0x8(%rsp),%rdi
  lea    -0x1(%r12),%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movb   $0x0,(%rax,%r12,1)
  call   <memset@plt>
  mov    0x10(%rbx),%rdi
  call   <strlen@plt>
  mov    0x10(%rbx),%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    0x8(%rsp),%rsi
  mov    %eax,%r8d
  call   <xor_decode@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  jmp    L25
L34:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    $0x2,%eax
  jmp    L25
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char *encdata, *decdata;
  size_t b64encdatalen, encdatalen;
  if (argc < 3)
    return 0x1;
  if (!load_file(argv[1], (char **)&encdata, &b64encdatalen)) {
    free(encdata);
    return 0x2;
  }
  encdatalen = 1 + b64_get_ascii_wc(b64encdatalen);
  decdata = malloc(encdatalen * sizeof(*encdata));
  if (NULL == decdata) {
    free(encdata);
    return 0x2;
  }
  memset(decdata, 0, encdatalen * sizeof(*encdata));
  b64_decode((char *)decdata, (char *)encdata, b64encdatalen);
  memcpy(encdata, decdata, (encdatalen - 1) * sizeof(*encdata));
  encdata[encdatalen] = '\0';
  memset(decdata, 0, encdatalen * sizeof(*encdata));
  xor_decode(decdata, encdata, encdatalen, (unsigned char *)argv[2], strlen(argv[2]));
  write(1, decdata, encdatalen);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jg     L9
L47:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %rsi,%rbx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    0x8(%rbx),%rdi
  call   <load_file@plt>
  test   %eax,%eax
  je     L27
  mov    0x10(%rsp),%rdi
  call   <b64_get_ascii_wc@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <b64_decode@plt>
  mov    0x8(%rsp),%rdi
  lea    -0x1(%r12),%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movb   $0x0,(%rax,%r12,1)
  call   <memset@plt>
  mov    0x10(%rbx),%rdi
  call   <strlen@plt>
  mov    0x10(%rbx),%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    0x8(%rsp),%rsi
  mov    %eax,%r8d
  call   <xor_decode@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  xor    %eax,%eax
  jmp    L47
L27:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    $0x2,%eax
  jmp    L47
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char *encdata, *decdata;
  size_t b64encdatalen, encdatalen;
  if (argc < 3)
    return 0x1;
  if (!load_file(argv[1], (char **)&encdata, &b64encdatalen)) {
    free(encdata);
    return 0x2;
  }
  encdatalen = 1 + b64_get_ascii_wc(b64encdatalen);
  decdata = malloc(encdatalen * sizeof(*encdata));
  if (NULL == decdata) {
    free(encdata);
    return 0x2;
  }
  memset(decdata, 0, encdatalen * sizeof(*encdata));
  b64_decode((char *)decdata, (char *)encdata, b64encdatalen);
  memcpy(encdata, decdata, (encdatalen - 1) * sizeof(*encdata));
  encdata[encdatalen] = '\0';
  memset(decdata, 0, encdatalen * sizeof(*encdata));
  xor_decode(decdata, encdata, encdatalen, (unsigned char *)argv[2], strlen(argv[2]));
  write(1, decdata, encdatalen);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<generateFindingMaxElement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x740,%rsp
  mov    %edi,-0x2734(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2734(%rbp),%edx
  lea    -0x2720(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fillArray@plt>
  mov    -0x2734(%rbp),%edx
  lea    -0x2720(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getTimeForFindMaxElement@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x2724(%rbp)
  mov    -0x2724(%rbp),%eax
  movd   %eax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: %-10.3f

assistant: ```c
void generateFindingMaxElement(int arrSize) {
  int arr[2500], i;
  float time;
  fillArray(arr, arrSize);
  time = getTimeForFindMaxElement(arr, arrSize);
  printf("%-10.3f", time);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<generateFindingMaxElement>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <fillArray@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <getTimeForFindMaxElement@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x2728,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %-10.3f

assistant: ```c
void generateFindingMaxElement(int arrSize) {
  int arr[2500], i;
  float time;
  fillArray(arr, arrSize);
  time = getTimeForFindMaxElement(arr, arrSize);
  printf("%-10.3f", time);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<generateFindingMaxElement>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %edi,%esi
  mov    %edi,%ebp
  mov    %r12,%rdi
  call   <fillArray@plt>
  mov    %r12,%rdi
  mov    %ebp,%esi
  call   <getTimeForFindMaxElement@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x2728,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D6: %-10.3f

assistant: ```c
void generateFindingMaxElement(int arrSize) {
  int arr[2500], i;
  float time;
  fillArray(arr, arrSize);
  time = getTimeForFindMaxElement(arr, arrSize);
  printf("%-10.3f", time);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<generateFindingMaxElement>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %edi,%esi
  mov    %edi,%ebp
  mov    %r12,%rdi
  call   <fillArray@plt>
  mov    %r12,%rdi
  mov    %ebp,%esi
  call   <getTimeForFindMaxElement@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x2728,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: %-10.3f

assistant: ```c
void generateFindingMaxElement(int arrSize) {
  int arr[2500], i;
  float time;
  fillArray(arr, arrSize);
  time = getTimeForFindMaxElement(arr, arrSize);
  printf("%-10.3f", time);
}
```
user: Translate the below assembly code into C programming language:

```asm
<undigitize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L17
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L16:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x8(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L16
  jmp    L39
L17:
  nop
L39:
  pop    %rbp
  ret
```

assistant: ```c
void undigitize(int a[], int nx, int ny, int scale) {
  int *p;
  if (scale <= 1)
    return;
  for (p = a; p <= &a[nx * ny - 1]; p++)
    *p = (*p) * scale;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<undigitize>:
  endbr64
  cmp    $0x1,%ecx
  jle    L13
  imul   %edx,%esi
  movslq %esi,%rsi
  lea    -0x4(%rdi,%rsi,4),%rdx
  cmp    %rdx,%rdi
  ja     L13
L0:
  mov    %ecx,%eax
  imul   (%rdi),%eax
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jbe    L0
L13:
  ret
```

assistant: ```c
void undigitize(int a[], int nx, int ny, int scale) {
  int *p;
  if (scale <= 1)
    return;
  for (p = a; p <= &a[nx * ny - 1]; p++)
    *p = (*p) * scale;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<undigitize>:
  endbr64
  cmp    $0x1,%ecx
  jle    L26
  imul   %edx,%esi
  movslq %esi,%rsi
  lea    -0x4(%rdi,%rsi,4),%rdx
  cmp    %rdx,%rdi
  ja     L26
  nopl   0x0(%rax)
L22:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  imul   %ecx,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdx,%rdi
  jbe    L22
L26:
  ret
```

assistant: ```c
void undigitize(int a[], int nx, int ny, int scale) {
  int *p;
  if (scale <= 1)
    return;
  for (p = a; p <= &a[nx * ny - 1]; p++)
    *p = (*p) * scale;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<undigitize>:
  endbr64
  cmp    $0x1,%ecx
  jle    L61
  imul   %edx,%esi
  mov    %rdi,%r8
  movslq %esi,%rsi
  lea    -0x4(,%rsi,4),%rdx
  add    %rdx,%r8
  jb     L61
  mov    %rdx,%rsi
  mov    %rdi,%rax
  shr    $0x2,%rsi
  add    $0x1,%rsi
  cmp    $0xb,%rdx
  jbe    L21
  movd   %ecx,%xmm4
  mov    %rsi,%rdx
  pshufd $0x0,%xmm4,%xmm2
  shr    $0x2,%rdx
  shl    $0x4,%rdx
  movdqa %xmm2,%xmm3
  add    %rdi,%rdx
  psrlq  $0x20,%xmm3
  nopl   0x0(%rax,%rax,1)
L1:
  movdqu (%rax),%xmm0
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L1
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rax
  lea    (%rdi,%rax,4),%rdi
  cmp    %rax,%rsi
  je     L61
L21:
  mov    (%rdi),%eax
  imul   %ecx,%eax
  mov    %eax,(%rdi)
  lea    0x4(%rdi),%rax
  cmp    %rax,%r8
  jb     L61
  mov    0x4(%rdi),%eax
  imul   %ecx,%eax
  mov    %eax,0x4(%rdi)
  lea    0x8(%rdi),%rax
  cmp    %rax,%r8
  jb     L61
  imul   0x8(%rdi),%ecx
  mov    %ecx,0x8(%rdi)
L61:
  ret
```

assistant: ```c
void undigitize(int a[], int nx, int ny, int scale) {
  int *p;
  if (scale <= 1)
    return;
  for (p = a; p <= &a[nx * ny - 1]; p++)
    *p = (*p) * scale;
}
```