ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<_ConvertSMVer2Cores>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  mov    %esi,%edx
  mov    $0x10,%r12d
  shl    $0x4,%ecx
  add    %esi,%ecx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x8,0x4(%rsp)
  movabs $0x800000011,%rax
  mov    %rax,0x8(%rsp)
  add    $0x1,%rax
  mov    %rax,0x10(%rsp)
  add    $0x1,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2000000020,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x3000000021,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,0x30(%rsp)
  jmp    L43
  nopl   (%rax)
L33:
  add    $0x1,%rax
  mov    (%rsp,%rax,8),%r12d
  cmp    $0xffffffff,%r12d
  je     L46
L43:
  movslq %eax,%r8
  cmp    %r12d,%ecx
  jne    L33
  mov    0x4(%rsp,%r8,8),%r12d
  jmp    L25
  nopl   (%rax)
L46:
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
L25:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x40,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: MapSMtoCores undefined SMversion %d.%d!


assistant: ```c
int _ConvertSMVer2Cores(int major, int minor) {
  typedef struct {
    int SM;
    int Cores;
  } sSMtoCores;
  sSMtoCores nGpuArchCoresPerSM[] = {{0x10, 8}, {0x11, 8}, {0x12, 8}, {0x13, 8}, {0x20, 32}, {0x21, 48}, {-1, -1}};
  int index = 0;
  while (nGpuArchCoresPerSM[index].SM != -1) {
    if (nGpuArchCoresPerSM[index].SM == ((major << 4) + minor)) {
      return nGpuArchCoresPerSM[index].Cores;
    }
    index++;
  }
  printf("MapSMtoCores undefined SMversion %d.%d!\n", major, minor);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_ConvertSMVer2Cores>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  movl   $0x8,0x4(%rsp)
  shl    $0x4,%eax
  movl   $0x8,0xc(%rsp)
  add    %esi,%eax
  movl   $0x8,0x14(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x20,0x24(%rsp)
  movl   $0x30,0x2c(%rsp)
  cmp    $0x10,%eax
  je     L5
  cmp    $0x11,%eax
  je     L127
  cmp    $0x12,%eax
  je     L11
  cmp    $0x13,%eax
  je     L105
  cmp    $0x20,%eax
  je     L75
  cmp    $0x21,%eax
  je     L32
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
L91:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x48,%rsp
  ret
L5:
  xor    %eax,%eax
L69:
  mov    0x4(%rsp,%rax,8),%eax
  jmp    L91
L127:
  mov    $0x1,%eax
  jmp    L69
L11:
  mov    $0x2,%eax
  jmp    L69
L105:
  mov    $0x3,%eax
  jmp    L69
L75:
  mov    $0x4,%eax
  jmp    L69
L32:
  mov    $0x5,%eax
  jmp    L69
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: MapSMtoCores undefined SMversion %d.%d!


assistant: ```c
int _ConvertSMVer2Cores(int major, int minor) {
  typedef struct {
    int SM;
    int Cores;
  } sSMtoCores;
  sSMtoCores nGpuArchCoresPerSM[] = {{0x10, 8}, {0x11, 8}, {0x12, 8}, {0x13, 8}, {0x20, 32}, {0x21, 48}, {-1, -1}};
  int index = 0;
  while (nGpuArchCoresPerSM[index].SM != -1) {
    if (nGpuArchCoresPerSM[index].SM == ((major << 4) + minor)) {
      return nGpuArchCoresPerSM[index].Cores;
    }
    index++;
  }
  printf("MapSMtoCores undefined SMversion %d.%d!\n", major, minor);
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<safe_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <errorf@plt>
  mov    $0x7f,%edi
  call   <exit@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string

tool: D3: Failed to allocate %i bytes.


assistant: ```c
void *safe_malloc(size_t size) {
  void *result = malloc(size);
  if (result == NULL) {
    errorf("Failed to allocate %i bytes.\n", size);
    exit(127);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<safe_malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <errorf@plt>
  mov    $0x7f,%edi
  call   <exit@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string

tool: D7: Failed to allocate %i bytes.


assistant: ```c
void *safe_malloc(size_t size) {
  void *result = malloc(size);
  if (result == NULL) {
    errorf("Failed to allocate %i bytes.\n", size);
    exit(127);
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<safe_malloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <errorf@plt>
  mov    $0x7f,%edi
  call   <exit@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: Failed to allocate %i bytes.


assistant: ```c
void *safe_malloc(size_t size) {
  void *result = malloc(size);
  if (result == NULL) {
    errorf("Failed to allocate %i bytes.\n", size);
    exit(127);
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<safe_malloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L19:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <errorf@plt>
  mov    $0x7f,%edi
  call   <exit@plt>
  jmp    L19
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: Failed to allocate %i bytes.


assistant: ```c
void *safe_malloc(size_t size) {
  void *result = malloc(size);
  if (result == NULL) {
    errorf("Failed to allocate %i bytes.\n", size);
    exit(127);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fast_irandom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x10000,-0x24(%rbp)
  ja     L16
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <fast_random@plt>
  jmp    L1
L16:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  shr    $0x10,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <fast_random@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L18
  mov    -0x24(%rbp),%eax
  movzwl %ax,%eax
  jmp    L12
L18:
  mov    $0x10000,%eax
L12:
  mov    %eax,%edi
  call   <fast_random@plt>
  or     %ebx,%eax
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint32_t fast_irandom(unsigned int max) {
  if (max <= 65536)
    return fast_random(max);
  int himax = (max - 1) / 65536;
  uint16_t hi = fast_random(himax + 1);
  return ((uint32_t)hi << 16) | fast_random(hi < himax ? 65536 : max % 65536);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fast_irandom>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x10000,%edi
  jbe    L5
  lea    -0x1(%rdi),%r12d
  shr    $0x10,%r12d
  lea    0x1(%r12),%edi
  call   <fast_random@plt>
  mov    %eax,%ebp
  shl    $0x10,%ebp
  movzwl %bx,%edi
  cmp    %eax,%r12d
  mov    $0x10000,%eax
  cmovg  %eax,%edi
  call   <fast_random@plt>
  or     %ebp,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <fast_random@plt>
  jmp    L9
```

assistant: ```c
uint32_t fast_irandom(unsigned int max) {
  if (max <= 65536)
    return fast_random(max);
  int himax = (max - 1) / 65536;
  uint16_t hi = fast_random(himax + 1);
  return ((uint32_t)hi << 16) | fast_random(hi < himax ? 65536 : max % 65536);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fast_irandom>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  cmp    $0x10000,%edi
  jbe    L6
  lea    -0x1(%rdi),%ebx
  shr    $0x10,%ebx
  lea    0x1(%rbx),%edi
  call   <fast_random@plt>
  movzwl %bp,%edi
  mov    %eax,%r12d
  shl    $0x10,%r12d
  cmp    %eax,%ebx
  mov    $0x10000,%eax
  cmovg  %eax,%edi
  call   <fast_random@plt>
  pop    %rbx
  pop    %rbp
  or     %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <fast_random@plt>
```

assistant: ```c
uint32_t fast_irandom(unsigned int max) {
  if (max <= 65536)
    return fast_random(max);
  int himax = (max - 1) / 65536;
  uint16_t hi = fast_random(himax + 1);
  return ((uint32_t)hi << 16) | fast_random(hi < himax ? 65536 : max % 65536);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fast_irandom>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  cmp    $0x10000,%edi
  jbe    L8
  lea    -0x1(%rdi),%ebx
  shr    $0x10,%ebx
  lea    0x1(%rbx),%edi
  call   <fast_random@plt>
  movzwl %bp,%edi
  mov    %eax,%r12d
  shl    $0x10,%r12d
  cmp    %eax,%ebx
  mov    $0x10000,%eax
  cmovg  %eax,%edi
  call   <fast_random@plt>
  pop    %rbx
  pop    %rbp
  or     %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <fast_random@plt>
```

assistant: ```c
uint32_t fast_irandom(unsigned int max) {
  if (max <= 65536)
    return fast_random(max);
  int himax = (max - 1) / 65536;
  uint16_t hi = fast_random(himax + 1);
  return ((uint32_t)hi << 16) | fast_random(hi < himax ? 65536 : max % 65536);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initialize_graph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x7b,%edi
  call   <srand@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L57:
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L49
  mov    -0x8(%rbp),%eax
  shl    $0xa,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  jmp    L59
L49:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0xa,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%edx
  mov    %edx,%ecx
  shl    $0xa,%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L59:
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L9
  addl   $0x1,-0x8(%rbp)
L39:
  cmpl   $0x3ff,-0x8(%rbp)
  jle    L57
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L71:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x3ff,-0x8(%rbp)
  jle    L71
  nop
  nop
  leave
  ret
```

assistant: ```c
void initialize_graph(unsigned *graph, unsigned *dist) {
  uint64_t i, j;
  srand(123);
  for (i = 0; i < 1024; ++i)
    for (j = 0; j <= i; ++j) {
      if (i == j)
        graph[i * 1024 + j] = -1;
      else
        graph[i * 1024 + j] = graph[j * 1024 + i] = rand() % 100;
    }
  for (i = 0; i < 1024; ++i)
    dist[i] = graph[i];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<initialize_graph>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    $0x7b,%edi
  call   <srand@plt>
  mov    $0x0,%ebp
  jmp    L4
L30:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %ebx,%eax
  shl    $0xa,%eax
  add    %r14d,%eax
  cltq
  mov    %edx,(%r12,%rax,4)
  lea    (%rbx,%r13,1),%eax
  cltq
  mov    %edx,(%r12,%rax,4)
L63:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jg     L60
L73:
  cmp    %ebx,%ebp
  jne    L30
  lea    (%rbx,%r13,1),%eax
  cltq
  movl   $0xffffffff,(%r12,%rax,4)
  jmp    L63
L60:
  add    $0x1,%ebp
  cmp    $0x400,%ebp
  je     L49
L4:
  mov    %ebp,%r14d
  mov    %ebp,%r13d
  shl    $0xa,%r13d
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jns    L73
  jmp    L60
L49:
  mov    $0x0,%eax
L62:
  mov    (%r12,%rax,1),%edx
  mov    %edx,(%r15,%rax,1)
  add    $0x4,%rax
  cmp    $0x1000,%rax
  jne    L62
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void initialize_graph(unsigned *graph, unsigned *dist) {
  uint64_t i, j;
  srand(123);
  for (i = 0; i < 1024; ++i)
    for (j = 0; j <= i; ++j) {
      if (i == j)
        graph[i * 1024 + j] = -1;
      else
        graph[i * 1024 + j] = graph[j * 1024 + i] = rand() % 100;
    }
  for (i = 0; i < 1024; ++i)
    dist[i] = graph[i];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<initialize_graph>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x7b,%edi
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %r12,%rbx
  sub    $0x8,%rsp
  call   <srand@plt>
  nopl   (%rax)
L28:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0xffffffff,%edx
  cmp    %r14d,%r15d
  je     L9
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %r14d,%eax
  shl    $0xa,%eax
  add    %r15d,%eax
  mov    %eax,%eax
  mov    %edx,(%r12,%rax,4)
L9:
  mov    %edx,(%rbx,%r14,4)
  add    $0x1,%r14
  cmp    %rbp,%r14
  jne    L32
  add    $0x1,%r15d
  add    $0x1000,%rbx
  lea    0x1(%r14),%rbp
  cmp    $0x400,%r15d
  jne    L28
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L23:
  mov    (%r12,%rax,1),%edx
  mov    %edx,0x0(%r13,%rax,1)
  add    $0x4,%rax
  cmp    $0x1000,%rax
  jne    L23
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void initialize_graph(unsigned *graph, unsigned *dist) {
  uint64_t i, j;
  srand(123);
  for (i = 0; i < 1024; ++i)
    for (j = 0; j <= i; ++j) {
      if (i == j)
        graph[i * 1024 + j] = -1;
      else
        graph[i * 1024 + j] = graph[j * 1024 + i] = rand() % 100;
    }
  for (i = 0; i < 1024; ++i)
    dist[i] = graph[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<initialize_graph>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x7b,%edi
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <srand@plt>
  nopl   (%rax)
L64:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    %r14d,%r15d
  je     L83
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %r14d,%eax
  shl    $0xa,%eax
  add    %r15d,%eax
  mov    %eax,%eax
  mov    %edx,(%r12,%rax,4)
  mov    %edx,0x0(%rbp,%r14,4)
  add    $0x1,%r14
  cmp    %rbx,%r14
  jne    L1
L42:
  add    $0x1,%r15d
  add    $0x1000,%rbp
  add    $0x1,%rbx
  cmp    $0x400,%r15d
  jne    L64
  lea    0x4(%r12),%rdx
  mov    %r13,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  mov    $0x0,%eax
  jbe    L9
  nop
L11:
  movdqu (%r12,%rax,1),%xmm0
  movups %xmm0,0x0(%r13,%rax,1)
  add    $0x10,%rax
  cmp    $0x1000,%rax
  jne    L11
L75:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%r12,%rax,1),%edx
  mov    %edx,0x0(%r13,%rax,1)
  add    $0x4,%rax
  cmp    $0x1000,%rax
  jne    L9
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L83:
  movl   $0xffffffff,0x0(%rbp,%r14,4)
  add    $0x1,%r14
  cmp    %rbx,%r14
  jne    L1
  jmp    L42
```

assistant: ```c
void initialize_graph(unsigned *graph, unsigned *dist) {
  uint64_t i, j;
  srand(123);
  for (i = 0; i < 1024; ++i)
    for (j = 0; j <= i; ++j) {
      if (i == j)
        graph[i * 1024 + j] = -1;
      else
        graph[i * 1024 + j] = graph[j * 1024 + i] = rand() % 100;
    }
  for (i = 0; i < 1024; ++i)
    dist[i] = graph[i];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bins>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L41
L12:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L56
  mov    -0x4(%rbp),%eax
  jmp    L45
L56:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L21
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L41
L21:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L12
  mov    $0xffffffff,%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int bins(int a[], int n, int num) {
  int beg, mid, end;
  beg = 0;
  end = n - 1;
  while (beg <= end) {
    mid = (beg + end) / 2;
    if (a[mid] == num)
      return mid;
    else if (num > a[mid])
      beg = mid + 1;
    else
      end = mid - 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bins>:
  endbr64
  sub    $0x1,%esi
  js     L56
  mov    $0x0,%r8d
  jmp    L5
L19:
  lea    -0x1(%rax),%esi
L50:
  cmp    %esi,%r8d
  jg     L6
L5:
  lea    (%r8,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %edx,%ecx
  je     L66
  jge    L19
  lea    0x1(%rax),%r8d
  jmp    L50
L6:
  mov    $0xffffffff,%r9d
L66:
  mov    %r9d,%eax
  ret
L56:
  mov    $0xffffffff,%r9d
  jmp    L66
```

assistant: ```c
int bins(int a[], int n, int num) {
  int beg, mid, end;
  beg = 0;
  end = n - 1;
  while (beg <= end) {
    mid = (beg + end) / 2;
    if (a[mid] == num)
      return mid;
    else if (num > a[mid])
      beg = mid + 1;
    else
      end = mid - 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bins>:
  endbr64
  sub    $0x1,%esi
  js     L9
  xor    %ecx,%ecx
  jmp    L37
  nopl   (%rax)
L11:
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jl     L9
L37:
  lea    (%rsi,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L2
  jl     L11
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L37
L9:
  mov    $0xffffffff,%eax
L2:
  ret
```

assistant: ```c
int bins(int a[], int n, int num) {
  int beg, mid, end;
  beg = 0;
  end = n - 1;
  while (beg <= end) {
    mid = (beg + end) / 2;
    if (a[mid] == num)
      return mid;
    else if (num > a[mid])
      beg = mid + 1;
    else
      end = mid - 1;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bins>:
  endbr64
  sub    $0x1,%esi
  js     L36
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L8:
  lea    (%rsi,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L56
  jge    L3
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L8
L36:
  mov    $0xffffffff,%eax
L56:
  ret
  nopl   (%rax)
L3:
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L8
  mov    $0xffffffff,%eax
  jmp    L56
```

assistant: ```c
int bins(int a[], int n, int num) {
  int beg, mid, end;
  beg = 0;
  end = n - 1;
  while (beg <= end) {
    mid = (beg + end) / 2;
    if (a[mid] == num)
      return mid;
    else if (num > a[mid])
      beg = mid + 1;
    else
      end = mid - 1;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test15_head>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string

tool: D11: test15

tool: 

assistant: ```c
void test15_head() {
  do {
    printf("test15");
    puts("");
  } while (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test15_head>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string
name: parse_data
arguments: label: D16
data_type: string

tool: D0: test15

tool: 

assistant: ```c
void test15_head() {
  do {
    printf("test15");
    puts("");
  } while (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test15_head>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string

tool: D7: test15

tool: 

assistant: ```c
void test15_head() {
  do {
    printf("test15");
    puts("");
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test15_head>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D6
type: string

tool: D13: test15

tool: 

assistant: ```c
void test15_head() {
  do {
    printf("test15");
    puts("");
  } while (0);
}
```