ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L24
  lea    D11(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L24:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2bbffeea,%esi
  je     L19
L36:
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L36
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string

tool: D11: Call this program with %i arguments


tool: D25: %u


tool: D29: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 734002922U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L11
  lea    D10(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L11:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2bbffeea,%esi
  je     L14
L10:
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L10
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type_guessed: string
name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D21
type_guessed: string

tool: D10: Call this program with %i arguments


tool: D0: %u


tool: D21: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 734002922U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<for_loop_no_brackets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L17:
  addl   $0x1,-0x8(%rbp)
L1:
  cmpl   $0x0,-0x8(%rbp)
  jle    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void for_loop_no_brackets() {
  int j = 0;
  for (int i = 0; i < 1; i++)
    j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<for_loop_no_brackets>:
  endbr64
  ret
```

assistant: ```c
void for_loop_no_brackets() {
  int j = 0;
  for (int i = 0; i < 1; i++)
    j;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<for_loop_no_brackets>:
  endbr64
  ret
```

assistant: ```c
void for_loop_no_brackets() {
  int j = 0;
  for (int i = 0; i < 1; i++)
    j;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<for_loop_no_brackets>:
  endbr64
  ret
```

assistant: ```c
void for_loop_no_brackets() {
  int j = 0;
  for (int i = 0; i < 1; i++)
    j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alloc_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: C: mallocing bytes...


assistant: ```c
void *alloc_buffer(int size) {
  printf("C: mallocing bytes...\n");
  return malloc(size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_buffer>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <malloc@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: C: mallocing bytes...


assistant: ```c
void *alloc_buffer(int size) {
  printf("C: mallocing bytes...\n");
  return malloc(size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<alloc_buffer>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <malloc@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2: C: mallocing bytes...


assistant: ```c
void *alloc_buffer(int size) {
  printf("C: mallocing bytes...\n");
  return malloc(size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<alloc_buffer>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <malloc@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: C: mallocing bytes...


assistant: ```c
void *alloc_buffer(int size) {
  printf("C: mallocing bytes...\n");
  return malloc(size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_serial_bits_to_baudrate>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x1a,%edi
  ja     L8
  mov    %edi,%edi
  lea    D1(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x32,%eax
  ret
  mov    $0x4b,%eax
  ret
  mov    $0x6e,%eax
  ret
  mov    $0x86,%eax
  ret
  mov    $0x96,%eax
  ret
  mov    $0xc8,%eax
  ret
  mov    $0x12c,%eax
  ret
  mov    $0x258,%eax
  ret
  mov    $0x4b0,%eax
  ret
  mov    $0x708,%eax
  ret
  mov    $0x960,%eax
  ret
  mov    $0x12c0,%eax
  ret
  mov    $0x2580,%eax
  ret
  mov    $0x4b00,%eax
  ret
  mov    $0x9600,%eax
  ret
  mov    $0xe100,%eax
  ret
  mov    $0x1c200,%eax
  ret
  mov    $0x38400,%eax
  ret
  mov    $0x70800,%eax
  ret
  mov    $0x7a120,%eax
  ret
  mov    $0x8ca00,%eax
  ret
  mov    $0xe1000,%eax
  ret
  mov    $0xf4240,%eax
  ret
  mov    $0x119400,%eax
  ret
  mov    $0x16e360,%eax
  ret
  mov    $0x1e8480,%eax
  ret
L8:
  mov    $0xffffffff,%eax
  ret
  mov    $0x0,%eax
  ret
```

assistant: ```c
int _serial_bits_to_baudrate(uint32_t bits) {
  switch (bits) {
  case B0:
    return 0;
  case B50:
    return 50;
  case B75:
    return 75;
  case B110:
    return 110;
  case B134:
    return 134;
  case B150:
    return 150;
  case B200:
    return 200;
  case B300:
    return 300;
  case B600:
    return 600;
  case B1200:
    return 1200;
  case B1800:
    return 1800;
  case B2400:
    return 2400;
  case B4800:
    return 4800;
  case B9600:
    return 9600;
  case B19200:
    return 19200;
  case B38400:
    return 38400;
  case B57600:
    return 57600;
  case B115200:
    return 115200;
  case B230400:
    return 230400;
  case B460800:
    return 460800;
  case B500000:
    return 500000;
  case B576000:
    return 576000;
  case B921600:
    return 921600;
  case B1000000:
    return 1000000;
  case B1152000:
    return 1152000;
  case B1500000:
    return 1500000;
  case B2000000:
    return 2000000;
  default:
    return -1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nolinger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x8,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  mov    -0x4(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%r8d
  lea    D7(%rip),%rcx
  mov    %eax,%edi
  call   <setsockopt@plt>
  nop
  leave
  ret
```

assistant: ```c
void nolinger(int sock) {
  static struct linger linger = {0, 0};
  int lsize = sizeof(struct linger);
  setsockopt(sock, SOL_SOCKET, SO_LINGER, (void *)&linger, lsize);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nolinger>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%r8d
  lea    D13(%rip),%rcx
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void nolinger(int sock) {
  static struct linger linger = {0, 0};
  int lsize = sizeof(struct linger);
  setsockopt(sock, SOL_SOCKET, SO_LINGER, (void *)&linger, lsize);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nolinger>:
  endbr64
  mov    D21(%rip),%rax
  mov    $0x8,%r8d
  lea    D12(%rip),%rcx
  mov    (%rax),%edx
  mov    D20(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <setsockopt@plt>
```

assistant: ```c
void nolinger(int sock) {
  static struct linger linger = {0, 0};
  int lsize = sizeof(struct linger);
  setsockopt(sock, SOL_SOCKET, SO_LINGER, (void *)&linger, lsize);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nolinger>:
  endbr64
  mov    D24(%rip),%rax
  mov    $0x8,%r8d
  lea    D0(%rip),%rcx
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <setsockopt@plt>
```

assistant: ```c
void nolinger(int sock) {
  static struct linger linger = {0, 0};
  int lsize = sizeof(struct linger);
  setsockopt(sock, SOL_SOCKET, SO_LINGER, (void *)&linger, lsize);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2,-0x38(%rbp)
  movl   $0x3,-0x34(%rbp)
  mov    -0x38(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  mov    -0x30(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    -0x28(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x1fa400,-0x24(%rbp)
  je     L123
  mov    $0x1,%eax
  jmp    L66
L123:
  movl   $0x5,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  cmpl   $0xfa,-0x18(%rbp)
  je     L68
  mov    $0x2,%eax
  jmp    L66
L68:
  mov    -0x18(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x20(%rbp)
  cmp    %eax,-0x1c(%rbp)
  je     L70
  mov    $0x3,%eax
  jmp    L66
L70:
  movl   $0xffffffff,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  cmp    $0x1,%eax
  je     L15
  mov    $0x5,%eax
  jmp    L66
L15:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  imul   %edx,%eax
  cmp    $0x4,%eax
  je     L54
  mov    $0x6,%eax
  jmp    L66
L54:
  mov    $0x80000000,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x8(%rbp),%rax
  movabs $0x7fffffff80000000,%rdx
  cmp    %rdx,%rax
  je     L55
  mov    $0x7,%eax
  jmp    L66
L55:
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cmp    $0x1,%eax
  je     L117
  mov    $0x8,%eax
  jmp    L66
L117:
  mov    $0x0,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 2, b = 3;
  int c = a * b;
  int d = c * 5;
  int e = 2 * 4;
  int f = c * d * e;
  f = f * f;
  if (f != 2073600)
    return 1;
  unsigned int g = 5, h = g * 10;
  unsigned int i;
  h = 10 * g;
  i = g * h;
  if (i != 250)
    return 2;
  if (i / g != h)
    return 3;
  if (3 + 2 * 3 != 9)
    return 4;
  unsigned int j = 4294967295;
  if (j * j != 1)
    return 5;
  if ((j - 1) * (j - 1) != 4)
    return 6;
  long k = 2147483648;
  if (k * j != 9223372034707292160)
    return 7;
  unsigned int l = 4294967295;
  unsigned int m = 4294967295;
  if (l * m != (unsigned int)4294967295 * (unsigned int)4294967295)
    return 8;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 2, b = 3;
  int c = a * b;
  int d = c * 5;
  int e = 2 * 4;
  int f = c * d * e;
  f = f * f;
  if (f != 2073600)
    return 1;
  unsigned int g = 5, h = g * 10;
  unsigned int i;
  h = 10 * g;
  i = g * h;
  if (i != 250)
    return 2;
  if (i / g != h)
    return 3;
  if (3 + 2 * 3 != 9)
    return 4;
  unsigned int j = 4294967295;
  if (j * j != 1)
    return 5;
  if ((j - 1) * (j - 1) != 4)
    return 6;
  long k = 2147483648;
  if (k * j != 9223372034707292160)
    return 7;
  unsigned int l = 4294967295;
  unsigned int m = 4294967295;
  if (l * m != (unsigned int)4294967295 * (unsigned int)4294967295)
    return 8;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 2, b = 3;
  int c = a * b;
  int d = c * 5;
  int e = 2 * 4;
  int f = c * d * e;
  f = f * f;
  if (f != 2073600)
    return 1;
  unsigned int g = 5, h = g * 10;
  unsigned int i;
  h = 10 * g;
  i = g * h;
  if (i != 250)
    return 2;
  if (i / g != h)
    return 3;
  if (3 + 2 * 3 != 9)
    return 4;
  unsigned int j = 4294967295;
  if (j * j != 1)
    return 5;
  if ((j - 1) * (j - 1) != 4)
    return 6;
  long k = 2147483648;
  if (k * j != 9223372034707292160)
    return 7;
  unsigned int l = 4294967295;
  unsigned int m = 4294967295;
  if (l * m != (unsigned int)4294967295 * (unsigned int)4294967295)
    return 8;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ushort2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    $0x5,%edx
  lea    D20(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ushort2sbuf@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    D20(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D20(%rip),%rax
  leave
  ret
```

assistant: ```c
char *ushort2str(unsigned short u) {
  static char buf[(5 + 1)];
  int len;
  len = ushort2sbuf(u, buf, sizeof(buf) - 1);
  buf[len] = 0;
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ushort2str>:
  endbr64
  push   %rbx
  movzwl %di,%edi
  mov    $0x5,%edx
  lea    D1(%rip),%rbx
  mov    %rbx,%rsi
  call   <ushort2sbuf@plt>
  cltq
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ushort2str(unsigned short u) {
  static char buf[(5 + 1)];
  int len;
  len = ushort2sbuf(u, buf, sizeof(buf) - 1);
  buf[len] = 0;
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ushort2str>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  movzwl %di,%edi
  mov    $0x5,%edx
  mov    %r12,%rsi
  call   <ushort2sbuf@plt>
  cltq
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ushort2str(unsigned short u) {
  static char buf[(5 + 1)];
  int len;
  len = ushort2sbuf(u, buf, sizeof(buf) - 1);
  buf[len] = 0;
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ushort2str>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  movzwl %di,%edi
  mov    $0x5,%edx
  mov    %r12,%rsi
  call   <ushort2sbuf@plt>
  cltq
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ushort2str(unsigned short u) {
  static char buf[(5 + 1)];
  int len;
  len = ushort2sbuf(u, buf, sizeof(buf) - 1);
  buf[len] = 0;
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<random_permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L2
L0:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <random_uniform@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0x0,-0x8(%rbp)
  jg     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void random_permute(char *str, size_t len) {
  for (int i = len - 1; i >= 1; i--) {
    int j = random_uniform(i + 1);
    char t = str[j];
    str[j] = str[i];
    str[i] = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<random_permute>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%ebx
  test   %ebx,%ebx
  jle    L8
  mov    %rdi,%rbp
  movslq %ebx,%rbx
L4:
  lea    0x1(%rbx),%edi
  call   <random_uniform@plt>
  cltq
  add    %rbp,%rax
  movzbl (%rax),%edx
  movzbl 0x0(%rbp,%rbx,1),%ecx
  mov    %cl,(%rax)
  mov    %dl,0x0(%rbp,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L4
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void random_permute(char *str, size_t len) {
  for (int i = len - 1; i >= 1; i--) {
    int j = random_uniform(i + 1);
    char t = str[j];
    str[j] = str[i];
    str[i] = t;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<random_permute>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L6
  mov    %rdi,%rbp
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  lea    0x1(%rbx),%edi
  call   <random_uniform@plt>
  movzbl 0x0(%rbp,%rbx,1),%ecx
  cltq
  add    %rbp,%rax
  movzbl (%rax),%edx
  mov    %cl,(%rax)
  mov    %dl,0x0(%rbp,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L2
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void random_permute(char *str, size_t len) {
  for (int i = len - 1; i >= 1; i--) {
    int j = random_uniform(i + 1);
    char t = str[j];
    str[j] = str[i];
    str[i] = t;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<random_permute>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L6
  mov    %rdi,%rbp
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  lea    0x1(%rbx),%edi
  call   <random_uniform@plt>
  movzbl 0x0(%rbp,%rbx,1),%ecx
  cltq
  add    %rbp,%rax
  movzbl (%rax),%edx
  mov    %cl,(%rax)
  mov    %dl,0x0(%rbp,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L11
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void random_permute(char *str, size_t len) {
  for (int i = len - 1; i >= 1; i--) {
    int j = random_uniform(i + 1);
    char t = str[j];
    str[j] = str[i];
    str[i] = t;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: %f


assistant: ```c
int main() {
  const int x;
  printf("%f\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %f


assistant: ```c
int main() {
  const int x;
  printf("%f\n", x);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: %f


assistant: ```c
int main() {
  const int x;
  printf("%f\n", x);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: %f


assistant: ```c
int main() {
  const int x;
  printf("%f\n", x);
  return 0;
}
```