ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<BG_StringHashValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L43
  mov    $0xffffffffffffffff,%rax
  jmp    L14
L43:
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L62:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <Q_isupper@plt>
  test   %eax,%eax
  je     L20
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x20,%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  add    $0x77,%eax
  cltq
  imul   %rdx,%rax
  add    %rax,-0x8(%rbp)
  jmp    L30
L20:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rdx
  mov    -0xc(%rbp),%eax
  add    $0x77,%eax
  cltq
  imul   %rdx,%rax
  add    %rax,-0x8(%rbp)
L30:
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L32
  movq   $0x0,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
long BG_StringHashValue(const char *fname) {
  int i;
  long hash;
  if (!fname) {
    return -1;
  }
  hash = 0;
  i = 0;
  while (fname[i] != '\0') {
    if (Q_isupper(fname[i])) {
      hash += (long)(fname[i] + ('a' - 'A')) * (i + 119);
    } else {
      hash += (long)(fname[i]) * (i + 119);
    }
    i++;
  }
  if (hash == -1) {
    hash = 0;
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BG_StringHashValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L37
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L45
  mov    $0x77,%ebp
  mov    $0x0,%r12d
  jmp    L58
L35:
  movsbq (%rbx),%rax
  movslq %ebp,%rdx
  imul   %rdx,%rax
  add    %rax,%r12
L36:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  add    $0x1,%ebp
  test   %dil,%dil
  je     L64
L58:
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <Q_isupper@plt>
  test   %eax,%eax
  je     L35
  movsbl (%rbx),%eax
  add    $0x20,%eax
  cltq
  movslq %ebp,%rdx
  imul   %rdx,%rax
  add    %rax,%r12
  jmp    L36
L64:
  cmp    $0xffffffffffffffff,%r12
  mov    $0x0,%eax
  cmove  %rax,%r12
L66:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    $0xffffffffffffffff,%r12
  jmp    L66
L45:
  mov    $0x0,%r12d
  jmp    L66
```

assistant: ```c
long BG_StringHashValue(const char *fname) {
  int i;
  long hash;
  if (!fname) {
    return -1;
  }
  hash = 0;
  i = 0;
  while (fname[i] != '\0') {
    if (Q_isupper(fname[i])) {
      hash += (long)(fname[i] + ('a' - 'A')) * (i + 119);
    } else {
      hash += (long)(fname[i]) * (i + 119);
    }
    i++;
  }
  if (hash == -1) {
    hash = 0;
  }
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BG_StringHashValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L33
  mov    %rdi,%rbp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
  mov    $0x77,%ebx
  xor    %r12d,%r12d
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L57:
  movsbl -0x77(%rbp,%rbx,1),%eax
  add    $0x20,%eax
  cltq
  imul   %rbx,%rax
  add    $0x1,%rbx
  movsbl -0x77(%rbp,%rbx,1),%edi
  add    %rax,%r12
  test   %dil,%dil
  je     L64
L15:
  xor    %eax,%eax
  call   <Q_isupper@plt>
  test   %eax,%eax
  jne    L57
  movsbq -0x77(%rbp,%rbx,1),%rax
  imul   %rbx,%rax
  add    $0x1,%rbx
  movsbl -0x77(%rbp,%rbx,1),%edi
  add    %rax,%r12
  test   %dil,%dil
  jne    L15
L64:
  xor    %eax,%eax
  cmp    $0xffffffffffffffff,%r12
  cmove  %rax,%r12
L11:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L6:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
L33:
  mov    $0xffffffffffffffff,%r12
  jmp    L11
```

assistant: ```c
long BG_StringHashValue(const char *fname) {
  int i;
  long hash;
  if (!fname) {
    return -1;
  }
  hash = 0;
  i = 0;
  while (fname[i] != '\0') {
    if (Q_isupper(fname[i])) {
      hash += (long)(fname[i] + ('a' - 'A')) * (i + 119);
    } else {
      hash += (long)(fname[i]) * (i + 119);
    }
    i++;
  }
  if (hash == -1) {
    hash = 0;
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<BG_StringHashValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L65
  mov    %rdi,%rbp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L47
  mov    $0x77,%ebx
  xor    %r12d,%r12d
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L66:
  movsbl -0x77(%rbp,%rbx,1),%eax
  add    $0x20,%eax
  cltq
  imul   %rbx,%rax
  add    $0x1,%rbx
  movsbl -0x77(%rbp,%rbx,1),%edi
  add    %rax,%r12
  test   %dil,%dil
  je     L31
L55:
  xor    %eax,%eax
  call   <Q_isupper@plt>
  test   %eax,%eax
  jne    L66
  movsbq -0x77(%rbp,%rbx,1),%rax
  imul   %rbx,%rax
  add    $0x1,%rbx
  movsbl -0x77(%rbp,%rbx,1),%edi
  add    %rax,%r12
  test   %dil,%dil
  jne    L55
L31:
  xor    %eax,%eax
  cmp    $0xffffffffffffffff,%r12
  cmove  %rax,%r12
L48:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L47:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
L65:
  mov    $0xffffffffffffffff,%r12
  jmp    L48
```

assistant: ```c
long BG_StringHashValue(const char *fname) {
  int i;
  long hash;
  if (!fname) {
    return -1;
  }
  hash = 0;
  i = 0;
  while (fname[i] != '\0') {
    if (Q_isupper(fname[i])) {
      hash += (long)(fname[i] + ('a' - 'A')) * (i + 119);
    } else {
      hash += (long)(fname[i]) * (i + 119);
    }
    i++;
  }
  if (hash == -1) {
    hash = 0;
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_put_nbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
  negl   -0x4(%rbp)
  mov    $0x2d,%edi
  call   <my_putchar@plt>
L12:
  cmpl   $0x9,-0x4(%rbp)
  jle    L11
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <my_put_nbr>
L11:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x30(%rdx),%eax
  mov    %eax,%edi
  call   <my_putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int my_put_nbr(int nb) {
  if (nb < 0) {
    nb = -nb;
    my_putchar('-');
  }
  if (nb >= 10)
    my_put_nbr(nb / 10);
  my_putchar(nb % 10 + '0');
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_put_nbr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  js     L25
L20:
  cmp    $0x9,%ebx
  jg     L29
L36:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  call   <my_putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L25:
  neg    %ebx
  mov    $0x2d,%edi
  call   <my_putchar@plt>
  jmp    L20
L29:
  movslq %ebx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <my_put_nbr>
  jmp    L36
```

assistant: ```c
int my_put_nbr(int nb) {
  if (nb < 0) {
    nb = -nb;
    my_putchar('-');
  }
  if (nb >= 10)
    my_put_nbr(nb / 10);
  my_putchar(nb % 10 + '0');
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_put_nbr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L49
L79:
  mov    %ebx,%r12d
  cmp    $0x9,%ebx
  jg     L51
L38:
  mov    $0xcccccccd,%eax
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  call   <my_putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L51:
  mov    $0xcccccccd,%edi
  mov    %r12,%rbp
  imul   %rdi,%rbp
  shr    $0x23,%rbp
  mov    %ebp,%r15d
  cmp    $0x63,%ebx
  jg     L9
L70:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  call   <my_putchar@plt>
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L49:
  mov    $0x2d,%edi
  neg    %ebx
  call   <my_putchar@plt>
  jmp    L79
  nopl   0x0(%rax)
L9:
  mov    %r15,%r13
  imul   %rdi,%r13
  shr    $0x23,%r13
  mov    %r13d,%r14d
  cmp    $0x3e7,%ebx
  jg     L27
L58:
  mov    $0xcccccccd,%eax
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  call   <my_putchar@plt>
  jmp    L70
  xchg   %ax,%ax
L27:
  imul   %r14,%rdi
  shr    $0x23,%rdi
  call   <my_put_nbr>
  jmp    L58
```

assistant: ```c
int my_put_nbr(int nb) {
  if (nb < 0) {
    nb = -nb;
    my_putchar('-');
  }
  if (nb >= 10)
    my_put_nbr(nb / 10);
  my_putchar(nb % 10 + '0');
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_put_nbr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L53
L68:
  mov    %ebx,%r12d
  cmp    $0x9,%ebx
  jg     L20
L63:
  mov    $0xcccccccd,%eax
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  call   <my_putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L20:
  mov    $0xcccccccd,%edi
  mov    %r12,%rbp
  imul   %rdi,%rbp
  shr    $0x23,%rbp
  mov    %ebp,%r15d
  cmp    $0x63,%ebx
  jg     L12
L15:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  call   <my_putchar@plt>
  jmp    L63
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    $0x2d,%edi
  neg    %ebx
  call   <my_putchar@plt>
  jmp    L68
  nopl   0x0(%rax)
L12:
  mov    %r15,%r13
  imul   %rdi,%r13
  shr    $0x23,%r13
  mov    %r13d,%r14d
  cmp    $0x3e7,%ebx
  jg     L31
L59:
  mov    $0xcccccccd,%eax
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  call   <my_putchar@plt>
  jmp    L15
  xchg   %ax,%ax
L31:
  imul   %r14,%rdi
  shr    $0x23,%rdi
  call   <my_put_nbr>
  jmp    L59
```

assistant: ```c
int my_put_nbr(int nb) {
  if (nb < 0) {
    nb = -nb;
    my_putchar('-');
  }
  if (nb >= 10)
    my_put_nbr(nb / 10);
  my_putchar(nb % 10 + '0');
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<precedence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x2f,%eax
  seta   %dl
  test   %dl,%dl
  jne    L14
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  movabs $0x840000000000,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L26
  movabs $0x280000000000,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L62
  movabs $0x20000000001,%rdx
  and    %rdx,%rax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L14
  mov    $0x0,%eax
  jmp    L14
L62:
  mov    $0x1,%eax
  jmp    L14
L26:
  mov    $0x2,%eax
  jmp    L14
L14:
  pop    %rbp
  ret
```

assistant: ```c
int precedence(char operator) {
  switch (operator) {
  case 0:
  case ')':
    return 0;
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<precedence>:
  endbr64
  cmp    $0x2f,%dil
  ja     L25
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%rax
  movabs $0x20000000001,%rdx
  test   %rdx,%rax
  jne    L11
  movabs $0x280000000000,%rdx
  test   %rdx,%rax
  jne    L10
  movabs $0x840000000000,%rdx
  test   %rdx,%rax
  jne    L28
L25:
  ret
L11:
  mov    $0x0,%eax
  ret
L10:
  mov    $0x1,%eax
  ret
L28:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int precedence(char operator) {
  switch (operator) {
  case 0:
  case ')':
    return 0;
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<precedence>:
  endbr64
  cmp    $0x2f,%dil
  ja     L35
  mov    $0x1,%eax
  mov    %edi,%ecx
  movabs $0x20000000001,%rdx
  shl    %cl,%rax
  test   %rdx,%rax
  jne    L15
  movabs $0x280000000000,%rdx
  test   %rdx,%rax
  jne    L2
  movabs $0x840000000000,%rdx
  test   %rdx,%rax
  jne    L5
L35:
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x2,%eax
  ret
  xchg   %ax,%ax
L2:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int precedence(char operator) {
  switch (operator) {
  case 0:
  case ')':
    return 0;
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<precedence>:
  endbr64
  cmp    $0x2f,%dil
  ja     L24
  mov    $0x1,%eax
  mov    %edi,%ecx
  movabs $0x20000000001,%rdx
  shl    %cl,%rax
  test   %rdx,%rax
  jne    L23
  movabs $0x280000000000,%rdx
  test   %rdx,%rax
  jne    L33
  movabs $0x840000000000,%rdx
  test   %rdx,%rax
  jne    L20
L24:
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x2,%eax
  ret
  xchg   %ax,%ax
L33:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int precedence(char operator) {
  switch (operator) {
  case 0:
  case ')':
    return 0;
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nseel_asm_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  fabs
  fistpl (%esi)
  fabs
  fistpl 0x4(%esi)
  xor    %edx,%edx
  cmpl   $0x0,(%esi)
  je     L8
  mov    0x4(%esi),%eax
  divl   (%esi)
L8:
  mov    %edx,(%esi)
  fildl  (%esi)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nseel_asm_mod(void) {
  __asm__("fabs\n"
          "fistpl (%esi)\n"
          "fabs\n"
          "fistpl 4(%esi)\n"
          "xorl %edx, %edx\n"
          "cmpl $0, (%esi)\n"
          "je 0f\n"
          "movl 4(%esi), %eax\n"
          "divl (%esi)\n"
          "0:\n"
          "movl %edx, (%esi)\n"
          "fildl (%esi)\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nseel_asm_mod>:
  endbr64
  fabs
  fistpl (%esi)
  fabs
  fistpl 0x4(%esi)
  xor    %edx,%edx
  cmpl   $0x0,(%esi)
  je     L4
  mov    0x4(%esi),%eax
  divl   (%esi)
L4:
  mov    %edx,(%esi)
  fildl  (%esi)
  ret
```

assistant: ```c
void nseel_asm_mod(void) {
  __asm__("fabs\n"
          "fistpl (%esi)\n"
          "fabs\n"
          "fistpl 4(%esi)\n"
          "xorl %edx, %edx\n"
          "cmpl $0, (%esi)\n"
          "je 0f\n"
          "movl 4(%esi), %eax\n"
          "divl (%esi)\n"
          "0:\n"
          "movl %edx, (%esi)\n"
          "fildl (%esi)\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nseel_asm_mod>:
  endbr64
  fabs
  fistpl (%esi)
  fabs
  fistpl 0x4(%esi)
  xor    %edx,%edx
  cmpl   $0x0,(%esi)
  je     L0
  mov    0x4(%esi),%eax
  divl   (%esi)
L0:
  mov    %edx,(%esi)
  fildl  (%esi)
  ret
```

assistant: ```c
void nseel_asm_mod(void) {
  __asm__("fabs\n"
          "fistpl (%esi)\n"
          "fabs\n"
          "fistpl 4(%esi)\n"
          "xorl %edx, %edx\n"
          "cmpl $0, (%esi)\n"
          "je 0f\n"
          "movl 4(%esi), %eax\n"
          "divl (%esi)\n"
          "0:\n"
          "movl %edx, (%esi)\n"
          "fildl (%esi)\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nseel_asm_mod>:
  endbr64
  fabs
  fistpl (%esi)
  fabs
  fistpl 0x4(%esi)
  xor    %edx,%edx
  cmpl   $0x0,(%esi)
  je     L5
  mov    0x4(%esi),%eax
  divl   (%esi)
L5:
  mov    %edx,(%esi)
  fildl  (%esi)
  ret
```

assistant: ```c
void nseel_asm_mod(void) {
  __asm__("fabs\n"
          "fistpl (%esi)\n"
          "fabs\n"
          "fistpl 4(%esi)\n"
          "xorl %edx, %edx\n"
          "cmpl $0, (%esi)\n"
          "je 0f\n"
          "movl 4(%esi), %eax\n"
          "divl (%esi)\n"
          "0:\n"
          "movl %edx, (%esi)\n"
          "fildl (%esi)\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Cipher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L53
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x5a,-0x1(%rbp)
  jbe    L20
  cmpb   $0x60,-0x1(%rbp)
  ja     L20
  movzbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <GetWrapAround@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  jmp    L67
L20:
  cmpb   $0x7a,-0x1(%rbp)
  ja     L35
  cmpb   $0x40,-0x1(%rbp)
  ja     L63
L35:
  movzbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <GetWrapAround@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  jmp    L67
L63:
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L67:
  addq   $0x1,-0x18(%rbp)
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: Before Cipher: 

assistant: ```c
void Cipher(char *input, unsigned offset) {
  printf("Before Cipher: ");
  while (*input != '\0') {
    printf("%c", *input);
    unsigned char nextChar = *input + offset;
    if (nextChar > 'Z' && nextChar < 'a') {
      *input = GetWrapAround(nextChar);
    } else if (nextChar > 'z' || nextChar < 'A') {
      *input = GetWrapAround(nextChar);
    } else {
      *input = nextChar;
    }
    input += 1;
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<Cipher>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L3
L30:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  movzbl %dil,%edi
  call   <GetWrapAround@plt>
L33:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L30
L3:
  movsbl %dil,%edi
  call   <putchar@plt>
  mov    %ebp,%edi
  add    (%rbx),%dil
  lea    -0x5b(%rdi),%eax
  cmp    $0x5,%al
  jbe    L44
  lea    -0x41(%rdi),%edx
  mov    %edi,%eax
  cmp    $0x39,%dl
  jbe    L33
  movzbl %dil,%edi
  call   <GetWrapAround@plt>
  jmp    L33
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: Before Cipher: 

assistant: ```c
void Cipher(char *input, unsigned offset) {
  printf("Before Cipher: ");
  while (*input != '\0') {
    printf("%c", *input);
    unsigned char nextChar = *input + offset;
    if (nextChar > 'Z' && nextChar < 'a') {
      *input = GetWrapAround(nextChar);
    } else if (nextChar > 'z' || nextChar < 'A') {
      *input = GetWrapAround(nextChar);
    } else {
      *input = nextChar;
    }
    input += 1;
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cipher>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D5(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L55
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L38:
  lea    -0x41(%rax),%edx
  cmp    $0x39,%dl
  ja     L36
  mov    %al,0x0(%rbp)
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L15
L55:
  call   <putchar@plt>
  movzbl 0x0(%rbp),%eax
  add    %ebx,%eax
  lea    -0x5b(%rax),%edx
  cmp    $0x5,%dl
  ja     L38
L36:
  movzbl %al,%edi
  add    $0x1,%rbp
  call   <GetWrapAround@plt>
  mov    %al,-0x1(%rbp)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L55
L15:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: Before Cipher: 

assistant: ```c
void Cipher(char *input, unsigned offset) {
  printf("Before Cipher: ");
  while (*input != '\0') {
    printf("%c", *input);
    unsigned char nextChar = *input + offset;
    if (nextChar > 'Z' && nextChar < 'a') {
      *input = GetWrapAround(nextChar);
    } else if (nextChar > 'z' || nextChar < 'A') {
      *input = GetWrapAround(nextChar);
    } else {
      *input = nextChar;
    }
    input += 1;
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cipher>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L59
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L17:
  lea    -0x41(%rax),%edx
  cmp    $0x39,%dl
  ja     L34
  mov    %al,0x0(%rbp)
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L18
L59:
  call   <putchar@plt>
  movzbl 0x0(%rbp),%eax
  add    %ebx,%eax
  lea    -0x5b(%rax),%edx
  cmp    $0x5,%dl
  ja     L17
L34:
  movzbl %al,%edi
  add    $0x1,%rbp
  call   <GetWrapAround@plt>
  mov    %al,-0x1(%rbp)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L59
L18:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: Before Cipher: 

assistant: ```c
void Cipher(char *input, unsigned offset) {
  printf("Before Cipher: ");
  while (*input != '\0') {
    printf("%c", *input);
    unsigned char nextChar = *input + offset;
    if (nextChar > 'Z' && nextChar < 'a') {
      *input = GetWrapAround(nextChar);
    } else if (nextChar > 'z' || nextChar < 'A') {
      *input = GetWrapAround(nextChar);
    } else {
      *input = nextChar;
    }
    input += 1;
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<Object_Destruct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void Object_Destruct(void *data) {
  free(data);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Object_Destruct>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Object_Destruct(void *data) {
  free(data);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Object_Destruct>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void Object_Destruct(void *data) {
  free(data);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<Object_Destruct>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void Object_Destruct(void *data) {
  free(data);
  return;
}
```