ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<nc_match>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  mov    $0x1,%r14d
  jmp    L48
L203:
  mov    D67(%rip),%rax
  mov    (%rax),%eax
L140:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L146:
  mov    $0x2,%r13d
L86:
  add    $0x1,%ebx
L48:
  mov    0x4(%rbp),%edi
  call   <sk_GENERAL_SUBTREE_num@plt>
  cmp    %ebx,%eax
  jle    L74
  mov    0x4(%rbp),%edi
  mov    %ebx,%esi
  call   <sk_GENERAL_SUBTREE_value@plt>
  mov    (%rax),%rsi
  mov    (%rsi),%rcx
  cmp    %rcx,(%r12)
  jne    L86
  cmpq   $0x0,0x10(%rax)
  jne    L203
  cmpq   $0x0,0x8(%rax)
  jne    L203
  cmp    $0x2,%r13d
  je     L86
  test   %r13d,%r13d
  cmove  %r14d,%r13d
  mov    %r12,%rdi
  call   <nc_match_single@plt>
  mov    D45(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L146
  mov    D88(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L86
  jmp    L140
L74:
  mov    $0x0,%ebx
  cmp    $0x1,%r13d
  jne    L37
  mov    D88(%rip),%rax
  mov    (%rax),%eax
  jmp    L140
L115:
  mov    D67(%rip),%rax
  mov    (%rax),%eax
  jmp    L140
L56:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L140
L95:
  add    $0x1,%ebx
L37:
  mov    0x0(%rbp),%edi
  call   <sk_GENERAL_SUBTREE_num@plt>
  cmp    %ebx,%eax
  jle    L176
  mov    %ebx,%esi
  mov    0x0(%rbp),%edi
  call   <sk_GENERAL_SUBTREE_value@plt>
  mov    (%rax),%rsi
  mov    (%rsi),%rdx
  cmp    %rdx,(%r12)
  jne    L95
  cmpq   $0x0,0x10(%rax)
  jne    L115
  cmpq   $0x0,0x8(%rax)
  jne    L115
  mov    %r12,%rdi
  call   <nc_match_single@plt>
  mov    D45(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L56
  mov    D88(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L95
  jmp    L140
L176:
  mov    D45(%rip),%rax
  mov    (%rax),%eax
  jmp    L140
```

assistant: ```c
int nc_match(GENERAL_NAME *gen, NAME_CONSTRAINTS *nc) {
  GENERAL_SUBTREE *sub;
  int i, r, match = 0;
  for (i = 0; i < sk_GENERAL_SUBTREE_num(nc->permittedSubtrees); i++) {
    sub = sk_GENERAL_SUBTREE_value(nc->permittedSubtrees, i);
    if (gen->type != sub->base->type)
      continue;
    if (sub->minimum || sub->maximum)
      return X509_V_ERR_SUBTREE_MINMAX;
    if (match == 2)
      continue;
    if (match == 0)
      match = 1;
    r = nc_match_single(gen, sub->base);
    if (r == X509_V_OK)
      match = 2;
    else if (r != X509_V_ERR_PERMITTED_VIOLATION)
      return r;
  }
  if (match == 1)
    return X509_V_ERR_PERMITTED_VIOLATION;
  for (i = 0; i < sk_GENERAL_SUBTREE_num(nc->excludedSubtrees); i++) {
    sub = sk_GENERAL_SUBTREE_value(nc->excludedSubtrees, i);
    if (gen->type != sub->base->type)
      continue;
    if (sub->minimum || sub->maximum)
      return X509_V_ERR_SUBTREE_MINMAX;
    r = nc_match_single(gen, sub->base);
    if (r == X509_V_OK)
      return X509_V_ERR_EXCLUDED_VIOLATION;
    else if (r != X509_V_ERR_PERMITTED_VIOLATION)
      return r;
  }
  return X509_V_OK;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nc_match>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L163
  nopl   0x0(%rax,%rax,1)
L121:
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L90
  mov    $0x1,%r13d
L160:
  add    $0x1,%ebx
L163:
  mov    0x4(%rbp),%edi
  call   <sk_GENERAL_SUBTREE_num@plt>
  cmp    %ebx,%eax
  jle    L129
  mov    0x4(%rbp),%edi
  mov    %ebx,%esi
  call   <sk_GENERAL_SUBTREE_value@plt>
  mov    (%rax),%rsi
  mov    (%rsi),%rcx
  cmp    %rcx,(%r12)
  jne    L160
  cmpq   $0x0,0x10(%rax)
  jne    L185
  cmpq   $0x0,0x8(%rax)
  jne    L185
  cmp    $0x2,%r13d
  je     L167
  mov    %r12,%rdi
  call   <nc_match_single@plt>
  mov    D56(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L121
L167:
  mov    $0x2,%r13d
  jmp    L160
  nopl   (%rax)
L185:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
L90:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L129:
  xor    %ebx,%ebx
  cmp    $0x1,%r13d
  jne    L143
  jmp    L174
  nopw   0x0(%rax,%rax,1)
L172:
  mov    0x0(%rbp),%edi
  mov    %ebx,%esi
  call   <sk_GENERAL_SUBTREE_value@plt>
  mov    (%rax),%rsi
  mov    (%rsi),%rdx
  cmp    %rdx,(%r12)
  jne    L35
  cmpq   $0x0,0x10(%rax)
  jne    L185
  cmpq   $0x0,0x8(%rax)
  jne    L185
  mov    %r12,%rdi
  call   <nc_match_single@plt>
  mov    D56(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L157
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L90
L35:
  add    $0x1,%ebx
L143:
  mov    0x0(%rbp),%edi
  call   <sk_GENERAL_SUBTREE_num@plt>
  cmp    %ebx,%eax
  jg     L172
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L174:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L90
L157:
  mov    D77(%rip),%rax
  mov    (%rax),%eax
  jmp    L90
```

assistant: ```c
int nc_match(GENERAL_NAME *gen, NAME_CONSTRAINTS *nc) {
  GENERAL_SUBTREE *sub;
  int i, r, match = 0;
  for (i = 0; i < sk_GENERAL_SUBTREE_num(nc->permittedSubtrees); i++) {
    sub = sk_GENERAL_SUBTREE_value(nc->permittedSubtrees, i);
    if (gen->type != sub->base->type)
      continue;
    if (sub->minimum || sub->maximum)
      return X509_V_ERR_SUBTREE_MINMAX;
    if (match == 2)
      continue;
    if (match == 0)
      match = 1;
    r = nc_match_single(gen, sub->base);
    if (r == X509_V_OK)
      match = 2;
    else if (r != X509_V_ERR_PERMITTED_VIOLATION)
      return r;
  }
  if (match == 1)
    return X509_V_ERR_PERMITTED_VIOLATION;
  for (i = 0; i < sk_GENERAL_SUBTREE_num(nc->excludedSubtrees); i++) {
    sub = sk_GENERAL_SUBTREE_value(nc->excludedSubtrees, i);
    if (gen->type != sub->base->type)
      continue;
    if (sub->minimum || sub->maximum)
      return X509_V_ERR_SUBTREE_MINMAX;
    r = nc_match_single(gen, sub->base);
    if (r == X509_V_OK)
      return X509_V_ERR_EXCLUDED_VIOLATION;
    else if (r != X509_V_ERR_PERMITTED_VIOLATION)
      return r;
  }
  return X509_V_OK;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nc_match>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L13:
  mov    D55(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L1
  mov    $0x1,%r13d
L14:
  add    $0x1,%ebx
L33:
  mov    0x4(%rbp),%edi
  call   <sk_GENERAL_SUBTREE_num@plt>
  cmp    %ebx,%eax
  jle    L0
  mov    0x4(%rbp),%edi
  mov    %ebx,%esi
  call   <sk_GENERAL_SUBTREE_value@plt>
  mov    (%rax),%rsi
  mov    (%rsi),%rcx
  cmp    %rcx,(%r12)
  jne    L14
  cmpq   $0x0,0x10(%rax)
  jne    L75
  cmpq   $0x0,0x8(%rax)
  jne    L75
  cmp    $0x2,%r13d
  je     L105
  mov    %r12,%rdi
  call   <nc_match_single@plt>
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L13
L105:
  mov    $0x2,%r13d
  jmp    L14
  nopl   (%rax)
L75:
  mov    D53(%rip),%rax
  mov    (%rax),%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  xor    %ebx,%ebx
  cmp    $0x1,%r13d
  jne    L18
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L85:
  mov    0x0(%rbp),%edi
  mov    %ebx,%esi
  call   <sk_GENERAL_SUBTREE_value@plt>
  mov    (%rax),%rsi
  mov    (%rsi),%rdx
  cmp    %rdx,(%r12)
  jne    L148
  cmpq   $0x0,0x10(%rax)
  jne    L75
  cmpq   $0x0,0x8(%rax)
  jne    L75
  mov    %r12,%rdi
  call   <nc_match_single@plt>
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L95
  mov    D55(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L1
L148:
  add    $0x1,%ebx
L18:
  mov    0x0(%rbp),%edi
  call   <sk_GENERAL_SUBTREE_num@plt>
  cmp    %ebx,%eax
  jg     L85
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L62:
  mov    D55(%rip),%rax
  mov    (%rax),%eax
  jmp    L1
L95:
  mov    D72(%rip),%rax
  mov    (%rax),%eax
  jmp    L1
```

assistant: ```c
int nc_match(GENERAL_NAME *gen, NAME_CONSTRAINTS *nc) {
  GENERAL_SUBTREE *sub;
  int i, r, match = 0;
  for (i = 0; i < sk_GENERAL_SUBTREE_num(nc->permittedSubtrees); i++) {
    sub = sk_GENERAL_SUBTREE_value(nc->permittedSubtrees, i);
    if (gen->type != sub->base->type)
      continue;
    if (sub->minimum || sub->maximum)
      return X509_V_ERR_SUBTREE_MINMAX;
    if (match == 2)
      continue;
    if (match == 0)
      match = 1;
    r = nc_match_single(gen, sub->base);
    if (r == X509_V_OK)
      match = 2;
    else if (r != X509_V_ERR_PERMITTED_VIOLATION)
      return r;
  }
  if (match == 1)
    return X509_V_ERR_PERMITTED_VIOLATION;
  for (i = 0; i < sk_GENERAL_SUBTREE_num(nc->excludedSubtrees); i++) {
    sub = sk_GENERAL_SUBTREE_value(nc->excludedSubtrees, i);
    if (gen->type != sub->base->type)
      continue;
    if (sub->minimum || sub->maximum)
      return X509_V_ERR_SUBTREE_MINMAX;
    r = nc_match_single(gen, sub->base);
    if (r == X509_V_OK)
      return X509_V_ERR_EXCLUDED_VIOLATION;
    else if (r != X509_V_ERR_PERMITTED_VIOLATION)
      return r;
  }
  return X509_V_OK;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aes_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L41
L38:
  mov    -0x2c(%rbp),%eax
  mov    -0x50(%rbp),%rdx
  shr    $0x4,%rdx
  cmp    %rdx,%rax
  jne    L22
  mov    -0x50(%rbp),%rax
  and    $0xf,%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L40
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L31
L22:
  movl   $0x10,-0x24(%rbp)
L31:
  mov    -0x24(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x40(%rbp),%rax
  add    %rax,%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L86
L2:
  mov    -0x2c(%rbp),%eax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%eax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x28(%rbp),%eax
  mov    %dl,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x28(%rbp)
L86:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L2
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <encrypt@plt>
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x2c(%rbp),%eax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x2c(%rbp)
L41:
  mov    -0x2c(%rbp),%eax
  mov    -0x50(%rbp),%rdx
  shr    $0x4,%rdx
  cmp    %rdx,%rax
  jbe    L38
  jmp    L47
L40:
  nop
L47:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

assistant: ```c
void aes_encrypt(unsigned char *iv, unsigned char *inbuf, unsigned char *outbuf, unsigned long long len) {
  unsigned char block[16];
  unsigned int blockno = 0, i;
  for (blockno = 0; blockno <= (len / sizeof(block)); blockno++) {
    unsigned int fraction;
    if (blockno == (len / sizeof(block))) {
      fraction = len % sizeof(block);
      if (fraction == 0)
        break;
      memset(block, 0, sizeof(block));
    } else
      fraction = 16;
    memcpy(block, inbuf + blockno * sizeof(block), fraction);
    for (i = 0; i < fraction; i++)
      block[i] = inbuf[blockno * sizeof(block) + i] ^ iv[i];
    encrypt((char *)block);
    memcpy(iv, block, sizeof(block));
    memcpy(outbuf + blockno * sizeof(block), block, sizeof(block));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<aes_encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%r12
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rcx,%r15
  shr    $0x4,%r15
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  mov    $0x10,%r14d
  jmp    L8
L44:
  mov    %r14d,%ebx
L51:
  shl    $0x4,%rbp
  mov    %rbp,%rax
  mov    %rbp,(%rsp)
  mov    0x10(%rsp),%rbp
  add    %rax,%rbp
  lea    0x20(%rsp),%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    $0x0,%eax
L37:
  movzbl 0x0(%rbp,%rax,1),%edx
  xor    (%r12,%rax,1),%dl
  mov    %dl,0x20(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ebx
  ja     L37
  lea    0x20(%rsp),%rbx
  mov    %rbx,%rdi
  call   <encrypt@plt>
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%rdi
  add    0x8(%rsp),%rdi
  mov    %r14d,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  add    $0x1,%r13d
  mov    %r13d,%ebp
  cmp    %r15,%rbp
  ja     L6
L8:
  cmp    %rbp,%r15
  jne    L44
  mov    0x18(%rsp),%ebx
  and    $0xf,%ebx
  je     L6
  lea    0x20(%rsp),%rdi
  mov    %r14d,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  jmp    L51
L6:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_encrypt(unsigned char *iv, unsigned char *inbuf, unsigned char *outbuf, unsigned long long len) {
  unsigned char block[16];
  unsigned int blockno = 0, i;
  for (blockno = 0; blockno <= (len / sizeof(block)); blockno++) {
    unsigned int fraction;
    if (blockno == (len / sizeof(block))) {
      fraction = len % sizeof(block);
      if (fraction == 0)
        break;
      memset(block, 0, sizeof(block));
    } else
      fraction = 16;
    memcpy(block, inbuf + blockno * sizeof(block), fraction);
    for (i = 0; i < fraction; i++)
      block[i] = inbuf[blockno * sizeof(block) + i] ^ iv[i];
    encrypt((char *)block);
    memcpy(iv, block, sizeof(block));
    memcpy(outbuf + blockno * sizeof(block), block, sizeof(block));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<aes_encrypt>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x20(%rsp),%r15
  mov    %rdx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  mov    %rcx,%rax
  shr    $0x4,%rax
  mov    %rax,(%rsp)
  mov    %ecx,%eax
  and    $0xf,%eax
  mov    %eax,0x1c(%rsp)
  nopl   0x0(%rax,%rax,1)
L39:
  cmp    (%rsp),%rbp
  jne    L33
  mov    0x1c(%rsp),%r13d
  mov    %r13d,%ebx
  test   %r13d,%r13d
  je     L44
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  mov    %r13d,%edx
L13:
  mov    0x8(%rsp),%rax
  shl    $0x4,%rbp
  mov    %r15,%rdi
  lea    (%rax,%rbp,1),%r13
  mov    %r13,%rsi
  call   <memcpy@plt>
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L46:
  movzbl 0x0(%r13,%rax,1),%edx
  xor    (%r14,%rax,1),%dl
  mov    %dl,(%r15,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L46
  mov    %r15,%rdi
  call   <encrypt@plt>
  mov    $0x10,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    0x10(%rsp),%rax
  mov    $0x10,%edx
  mov    %r15,%rsi
  lea    (%rax,%rbp,1),%rdi
  lea    0x1(%r12),%ebp
  call   <memcpy@plt>
  mov    %rbp,%r12
  cmp    (%rsp),%rbp
  jbe    L39
L44:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    $0x10,%edx
  mov    $0x10,%ebx
  jmp    L13
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_encrypt(unsigned char *iv, unsigned char *inbuf, unsigned char *outbuf, unsigned long long len) {
  unsigned char block[16];
  unsigned int blockno = 0, i;
  for (blockno = 0; blockno <= (len / sizeof(block)); blockno++) {
    unsigned int fraction;
    if (blockno == (len / sizeof(block))) {
      fraction = len % sizeof(block);
      if (fraction == 0)
        break;
      memset(block, 0, sizeof(block));
    } else
      fraction = 16;
    memcpy(block, inbuf + blockno * sizeof(block), fraction);
    for (i = 0; i < fraction; i++)
      block[i] = inbuf[blockno * sizeof(block) + i] ^ iv[i];
    encrypt((char *)block);
    memcpy(iv, block, sizeof(block));
    memcpy(outbuf + blockno * sizeof(block), block, sizeof(block));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void sort(int a[], int n) {
  int *temp = malloc(n * sizeof(int));
  assert(temp);
  merge_sort(a, n, temp);
  free(temp);
}
```
user: What is the c source code of the assembly code below?

```asm
<sort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <merge_sort@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sort(int a[], int n) {
  int *temp = malloc(n * sizeof(int));
  assert(temp);
  merge_sort(a, n, temp);
  free(temp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    0x0(,%rsi,4),%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r13,%rdi
  mov    %rbp,%rdx
  mov    %r12d,%esi
  call   <merge_sort@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
```

assistant: ```c
void sort(int a[], int n) {
  int *temp = malloc(n * sizeof(int));
  assert(temp);
  merge_sort(a, n, temp);
  free(temp);
}
```
user: What is the c source code of the assembly code below:

```asm
<sort>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    0x0(,%rsi,4),%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r13,%rdi
  mov    %rbp,%rdx
  mov    %r12d,%esi
  call   <merge_sort@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
```

assistant: ```c
void sort(int a[], int n) {
  int *temp = malloc(n * sizeof(int));
  assert(temp);
  merge_sort(a, n, temp);
  free(temp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: Query OpenGL resource (vidmem and GPU-mapped sysmem) usage

Usage: %s -p pid
       %s -h

  -h: print this help message
  -p <pid>: select process to query


assistant: ```c
void print_help(const char *progname) {
  printf("Query OpenGL resource (vidmem and GPU-mapped sysmem) usage\n\n"
         "Usage: %s -p pid\n"
         "       %s -h\n\n"
         "  -h: print this help message\n"
         "  -p <pid>: select process to query\n",
         progname, progname);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_help>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D2: Query OpenGL resource (vidmem and GPU-mapped sysmem) usage

Usage: %s -p pid
       %s -h

  -h: print this help message
  -p <pid>: select process to query


assistant: ```c
void print_help(const char *progname) {
  printf("Query OpenGL resource (vidmem and GPU-mapped sysmem) usage\n\n"
         "Usage: %s -p pid\n"
         "       %s -h\n\n"
         "  -h: print this help message\n"
         "  -p <pid>: select process to query\n",
         progname, progname);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_help>:
  endbr64
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: Query OpenGL resource (vidmem and GPU-mapped sysmem) usage

Usage: %s -p pid
       %s -h

  -h: print this help message
  -p <pid>: select process to query


assistant: ```c
void print_help(const char *progname) {
  printf("Query OpenGL resource (vidmem and GPU-mapped sysmem) usage\n\n"
         "Usage: %s -p pid\n"
         "       %s -h\n\n"
         "  -h: print this help message\n"
         "  -p <pid>: select process to query\n",
         progname, progname);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_help>:
  endbr64
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Query OpenGL resource (vidmem and GPU-mapped sysmem) usage

Usage: %s -p pid
       %s -h

  -h: print this help message
  -p <pid>: select process to query


assistant: ```c
void print_help(const char *progname) {
  printf("Query OpenGL resource (vidmem and GPU-mapped sysmem) usage\n\n"
         "Usage: %s -p pid\n"
         "       %s -h\n\n"
         "  -h: print this help message\n"
         "  -p <pid>: select process to query\n",
         progname, progname);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  fldl   -0x8(%rbp)
  fabs
  fstpl  -0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double fabs(double x) {
  __asm__ __volatile__("fldl %0;"
                       "fabs;"
                       "fstpl %0"
                       : "+m"(x));
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fabs>:
  endbr64
  movsd  %xmm0,-0x8(%rsp)
  fldl   -0x8(%rsp)
  fabs
  fstpl  -0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  ret
```

assistant: ```c
double fabs(double x) {
  __asm__ __volatile__("fldl %0;"
                       "fabs;"
                       "fstpl %0"
                       : "+m"(x));
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fabs>:
  endbr64
  movsd  %xmm0,-0x8(%rsp)
  fldl   -0x8(%rsp)
  fabs
  fstpl  -0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  ret
```

assistant: ```c
double fabs(double x) {
  __asm__ __volatile__("fldl %0;"
                       "fabs;"
                       "fstpl %0"
                       : "+m"(x));
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fabs>:
  endbr64
  movsd  %xmm0,-0x8(%rsp)
  fldl   -0x8(%rsp)
  fabs
  fstpl  -0x8(%rsp)
  movsd  -0x8(%rsp),%xmm0
  ret
```

assistant: ```c
double fabs(double x) {
  __asm__ __volatile__("fldl %0;"
                       "fabs;"
                       "fstpl %0"
                       : "+m"(x));
  return x;
}
```