ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  cmp    $0x2,%edi
  jle    L13
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  mov    0x8(%rsi),%rsi
  mov    $0xa,%edx
  mov    %r12d,%edi
  xor    %r13d,%r13d
  call   <mpz_init_set_str@plt>
  mov    0x10(%rbx),%rsi
  mov    $0xa,%edx
  mov    %r13d,%edi
  call   <mpz_init_set_str@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %r12d,%edi
  call   <mpz_add@plt>
  mov    %r12d,%edx
  mov    $0xa,%esi
  xor    %edi,%edi
  call   <mpz_get_str@plt>
  mov    0x10(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  lea    D3(%rip),%rdi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L4:
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
L13:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D3: %s + %s => %s


tool: D2: Please supply two numbers to add.

assistant: ```c
int main(int argc, char *argv[]) {
  mpz_t a, b;
  if (argc < 3) {
    printf("Please supply two numbers to add.\n");
    return 1;
  }
  mpz_init_set_str(a, argv[1], 10);
  mpz_init_set_str(b, argv[2], 10);
  mpz_add(a, a, b);
  printf("%s + %s => %s\n", argv[1], argv[2], mpz_get_str(NULL, 10, a));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: %lld


assistant: ```c
int main(void) {
  printf("%lld\n", rdtsc());
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: %lld


assistant: ```c
int main(void) {
  printf("%lld\n", rdtsc());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rdtsc@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: %lld


assistant: ```c
int main(void) {
  printf("%lld\n", rdtsc());
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rdtsc@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: %lld


assistant: ```c
int main(void) {
  printf("%lld\n", rdtsc());
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cosine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  addl   $0x2000000,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x11,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isin_S4@plt>
  shl    $0x11,%eax
  leave
  ret
```

assistant: ```c
int32_t Cosine(uint32_t phase) {
  phase += 0x2000000;
  int32_t P = phase >> 17;
  return isin_S4(P) << 17;
}
```
user: What is the c source code of the assembly code below?

```asm
<Cosine>:
  endbr64
  sub    $0x8,%rsp
  add    $0x2000000,%edi
  sar    $0x11,%edi
  call   <isin_S4@plt>
  shl    $0x11,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int32_t Cosine(uint32_t phase) {
  phase += 0x2000000;
  int32_t P = phase >> 17;
  return isin_S4(P) << 17;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Cosine>:
  endbr64
  add    $0x2000000,%edi
  sub    $0x8,%rsp
  sar    $0x11,%edi
  call   <isin_S4@plt>
  add    $0x8,%rsp
  shl    $0x11,%eax
  ret
```

assistant: ```c
int32_t Cosine(uint32_t phase) {
  phase += 0x2000000;
  int32_t P = phase >> 17;
  return isin_S4(P) << 17;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Cosine>:
  endbr64
  add    $0x2000000,%edi
  sub    $0x8,%rsp
  sar    $0x11,%edi
  call   <isin_S4@plt>
  add    $0x8,%rsp
  shl    $0x11,%eax
  ret
```

assistant: ```c
int32_t Cosine(uint32_t phase) {
  phase += 0x2000000;
  int32_t P = phase >> 17;
  return isin_S4(P) << 17;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xorStrings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movb   $0x0,-0xb(%rbp)
  movb   $0x0,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <asciiToHex@plt>
  mov    %al,-0xb(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <asciiToHex@plt>
  mov    %al,-0xa(%rbp)
  movzbl -0xb(%rbp),%eax
  xor    -0xa(%rbp),%al
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <hexToAscii@plt>
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void xorStrings(char *dest, const char *src1, const char *src2) {
  char valSrc1 = 0;
  char valSrc2 = 0;
  char xorVal = 0;
  int len = strlen(src1);
  int i = 0;
  for (i = 0; i < len; i++) {
    valSrc1 = asciiToHex(*(src1 + i));
    valSrc2 = asciiToHex(*(src2 + i));
    xorVal = valSrc1 ^ valSrc2;
    xorVal = hexToAscii(xorVal);
    dest[i] = xorVal;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xorStrings>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%r15
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L13
  mov    %eax,%r12d
  mov    $0x0,%ebp
L10:
  movsbl 0x0(%r13,%rbp,1),%edi
  call   <asciiToHex@plt>
  mov    %eax,%ebx
  movsbl (%r15,%rbp,1),%edi
  call   <asciiToHex@plt>
  xor    %eax,%ebx
  movsbl %bl,%edi
  call   <hexToAscii@plt>
  mov    %al,(%r14,%rbp,1)
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L10
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void xorStrings(char *dest, const char *src1, const char *src2) {
  char valSrc1 = 0;
  char valSrc2 = 0;
  char xorVal = 0;
  int len = strlen(src1);
  int i = 0;
  for (i = 0; i < len; i++) {
    valSrc1 = asciiToHex(*(src1 + i));
    valSrc2 = asciiToHex(*(src2 + i));
    xorVal = valSrc1 ^ valSrc2;
    xorVal = hexToAscii(xorVal);
    dest[i] = xorVal;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xorStrings>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  movslq %eax,%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L15:
  movsbl 0x0(%r13,%rbp,1),%edi
  call   <asciiToHex@plt>
  movsbl (%r15,%rbp,1),%edi
  mov    %eax,%ebx
  call   <asciiToHex@plt>
  xor    %eax,%ebx
  movsbl %bl,%edi
  call   <hexToAscii@plt>
  mov    %al,(%r14,%rbp,1)
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L15
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void xorStrings(char *dest, const char *src1, const char *src2) {
  char valSrc1 = 0;
  char valSrc2 = 0;
  char xorVal = 0;
  int len = strlen(src1);
  int i = 0;
  for (i = 0; i < len; i++) {
    valSrc1 = asciiToHex(*(src1 + i));
    valSrc2 = asciiToHex(*(src2 + i));
    xorVal = valSrc1 ^ valSrc2;
    xorVal = hexToAscii(xorVal);
    dest[i] = xorVal;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xorStrings>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  movslq %eax,%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L16:
  movsbl 0x0(%r13,%rbp,1),%edi
  call   <asciiToHex@plt>
  movsbl (%r15,%rbp,1),%edi
  mov    %eax,%ebx
  call   <asciiToHex@plt>
  xor    %eax,%ebx
  movsbl %bl,%edi
  call   <hexToAscii@plt>
  mov    %al,(%r14,%rbp,1)
  add    $0x1,%rbp
  cmp    %rbp,%r12
  jne    L16
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void xorStrings(char *dest, const char *src1, const char *src2) {
  char valSrc1 = 0;
  char valSrc2 = 0;
  char xorVal = 0;
  int len = strlen(src1);
  int i = 0;
  for (i = 0; i < len; i++) {
    valSrc1 = asciiToHex(*(src1 + i));
    valSrc2 = asciiToHex(*(src2 + i));
    xorVal = valSrc1 ^ valSrc2;
    xorVal = hexToAscii(xorVal);
    dest[i] = xorVal;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<procstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdupe@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L6
L8:
  addq   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L68
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L68:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L64
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <process@plt>
  mov    -0x10(%rbp),%rax
  movb   $0x20,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L79
L74:
  addq   $0x1,-0x18(%rbp)
L79:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L40
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L74
  jmp    L40
L64:
  nop
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void procstr(char *s) {
  char *h = strdupe(s);
  char *g, *gg;
  g = h;
  for (;;) {
    gg = g;
    while (!isspace((int)gg[0]) && gg[0])
      gg++;
    if (!gg[0])
      break;
    gg[0] = 0;
    process(g);
    gg[0] = ' ';
    g = gg;
    while (isspace((int)g[0]) && g[0])
      g++;
  }
  free(h);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<procstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <strdupe@plt>
  mov    %rax,%r12
  mov    %rax,%rbp
  jmp    L5
L69:
  cmpb   $0x0,(%rbx)
  je     L39
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <process@plt>
  movb   $0x20,(%rbx)
  mov    %rbx,%rbp
  jmp    L12
L6:
  add    $0x1,%rbp
L12:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L5
  cmpb   $0x0,0x0(%rbp)
  jne    L6
L5:
  mov    %rbp,%rbx
L45:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L69
  cmpb   $0x0,(%rbx)
  je     L39
  add    $0x1,%rbx
  jmp    L45
L39:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void procstr(char *s) {
  char *h = strdupe(s);
  char *g, *gg;
  g = h;
  for (;;) {
    gg = g;
    while (!isspace((int)gg[0]) && gg[0])
      gg++;
    if (!gg[0])
      break;
    gg[0] = 0;
    process(g);
    gg[0] = ' ';
    g = gg;
    while (isspace((int)g[0]) && g[0])
      g++;
  }
  free(h);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<procstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <strdupe@plt>
  movsbl (%rax),%edi
  mov    %rax,%rbp
  mov    %rax,%r12
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    %r12,%rbx
  jmp    L13
  nopl   (%rax)
L79:
  cmpb   $0x0,(%rbx)
  je     L41
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L13:
  call   <isspace@plt>
  test   %rax,%rax
  je     L79
  cmpb   $0x0,(%rbx)
  je     L41
  movb   $0x0,(%rbx)
  mov    %r12,%rdi
  call   <process@plt>
  movb   $0x20,(%rbx)
  mov    $0x20,%edi
  jmp    L49
  nopl   0x0(%rax)
L72:
  test   %dil,%dil
  je     L51
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L49:
  call   <isspace@plt>
  movsbl (%rbx),%edi
  test   %rax,%rax
  jne    L72
L51:
  mov    %rbx,%r12
  jmp    L32
  nop
L41:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
```

assistant: ```c
void procstr(char *s) {
  char *h = strdupe(s);
  char *g, *gg;
  g = h;
  for (;;) {
    gg = g;
    while (!isspace((int)gg[0]) && gg[0])
      gg++;
    if (!gg[0])
      break;
    gg[0] = 0;
    process(g);
    gg[0] = ' ';
    g = gg;
    while (isspace((int)g[0]) && g[0])
      g++;
  }
  free(h);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<procstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <strdupe@plt>
  mov    %rax,%r12
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %rbp,%rbx
  jmp    L3
  nopl   (%rax)
L70:
  cmpb   $0x0,(%rbx)
  je     L23
  add    $0x1,%rbx
L3:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L70
  cmpb   $0x0,(%rbx)
  je     L23
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  mov    %rbx,%rbp
  call   <process@plt>
  movb   $0x20,(%rbx)
  jmp    L34
  xchg   %ax,%ax
L37:
  cmpb   $0x0,0x0(%rbp)
  je     L43
  add    $0x1,%rbp
L34:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L23:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
```

assistant: ```c
void procstr(char *s) {
  char *h = strdupe(s);
  char *g, *gg;
  g = h;
  for (;;) {
    gg = g;
    while (!isspace((int)gg[0]) && gg[0])
      gg++;
    if (!gg[0])
      break;
    gg[0] = 0;
    process(g);
    gg[0] = ' ';
    g = gg;
    while (isspace((int)g[0]) && g[0])
      g++;
  }
  free(h);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x20(%rbp),%rdx
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    -0x18(%rbp),%rdx
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  movq   $0x0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    $0x1,%rax
  jne    L37
  movq   $0x1,-0x10(%rbp)
  movq   $0x2,-0x20(%rbp)
L37:
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x24(%rbp)
  jmp    L32
L24:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <getTotient@plt>
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x24(%rbp)
L32:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jle    L24
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rcx
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D3
type_infered: string

tool: D16: %ld

tool: D3: Sum of Totients between [%ld..%ld] is %ld 


assistant: ```c
int main(int argc, char **argv) {
  long lower, upper;
  sscanf(argv[1], "%ld", &lower);
  sscanf(argv[2], "%ld", &upper);
  int i;
  long result = 0.0;
  if (lower == 1) {
    result = 1.0;
    lower = 2;
  }
#pragma omp parallel for default(shared) private(i) schedule(auto) reduction(+ : result) num_threads(12)
  for (i = lower; i <= upper; i++) {
    result = result + getTotient(i);
  }
  printf("Sum of Totients between [%ld..%ld] is %ld \n", lower, upper, result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  mov    0x8(%rsi),%rdi
  lea    D16(%rip),%rbp
  mov    %rbp,%rsi
  call   <sscanf@plt>
  lea    0x10(%rsp),%rdx
  mov    0x10(%rbx),%rdi
  mov    %rbp,%rsi
  call   <sscanf@plt>
  mov    0x8(%rsp),%rbp
  cmp    $0x1,%rbp
  je     L11
  mov    $0x0,%ebp
L3:
  movslq 0x8(%rsp),%rbx
  mov    0x10(%rsp),%rdx
  cmp    %rdx,%rbx
  jg     L42
  add    $0x1,%rbx
L18:
  lea    -0x1(%rbx),%edi
  call   <getTotient@plt>
  add    %rax,%rbp
  mov    0x10(%rsp),%rdx
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rdx
  jge    L18
L42:
  mov    %rbp,%rcx
  mov    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  movq   $0x2,0x8(%rsp)
  jmp    L3
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string

tool: D16: %ld

tool: D15: Sum of Totients between [%ld..%ld] is %ld 


assistant: ```c
int main(int argc, char **argv) {
  long lower, upper;
  sscanf(argv[1], "%ld", &lower);
  sscanf(argv[2], "%ld", &upper);
  int i;
  long result = 0.0;
  if (lower == 1) {
    result = 1.0;
    lower = 2;
  }
#pragma omp parallel for default(shared) private(i) schedule(auto) reduction(+ : result) num_threads(12)
  for (i = lower; i <= upper; i++) {
    result = result + getTotient(i);
  }
  printf("Sum of Totients between [%ld..%ld] is %ld \n", lower, upper, result);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    0x8(%rsi),%rdi
  mov    %r12,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x10(%rbx),%rdi
  mov    %r12,%rsi
  lea    0x10(%rsp),%rdx
  xor    %r12d,%r12d
  call   <sscanf@plt>
  mov    0x8(%rsp),%rsi
  cmp    $0x1,%rsi
  jne    L2
  movq   $0x2,0x8(%rsp)
  mov    %rsi,%r12
  mov    $0x2,%esi
L2:
  mov    0x10(%rsp),%rdx
  movslq %esi,%rbx
  cmp    %rdx,%rbx
  jg     L12
  add    $0x1,%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  lea    -0x1(%rbx),%edi
  call   <getTotient@plt>
  mov    0x10(%rsp),%rdx
  add    %rax,%r12
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rdx
  jge    L0
  mov    0x8(%rsp),%rsi
L12:
  mov    %r12,%rcx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D7
datatype: string

tool: D17: %ld

tool: D7: Sum of Totients between [%ld..%ld] is %ld 


assistant: ```c
int main(int argc, char **argv) {
  long lower, upper;
  sscanf(argv[1], "%ld", &lower);
  sscanf(argv[2], "%ld", &upper);
  int i;
  long result = 0.0;
  if (lower == 1) {
    result = 1.0;
    lower = 2;
  }
#pragma omp parallel for default(shared) private(i) schedule(auto) reduction(+ : result) num_threads(12)
  for (i = lower; i <= upper; i++) {
    result = result + getTotient(i);
  }
  printf("Sum of Totients between [%ld..%ld] is %ld \n", lower, upper, result);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    0x8(%rsi),%rdi
  mov    %r12,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x10(%rbx),%rdi
  mov    %r12,%rsi
  lea    0x10(%rsp),%rdx
  xor    %r12d,%r12d
  call   <sscanf@plt>
  mov    0x8(%rsp),%rsi
  cmp    $0x1,%rsi
  jne    L25
  movq   $0x2,0x8(%rsp)
  mov    %rsi,%r12
  mov    $0x2,%esi
L25:
  mov    0x10(%rsp),%rdx
  movslq %esi,%rbx
  cmp    %rdx,%rbx
  jg     L15
  add    $0x1,%rbx
  nopw   0x0(%rax,%rax,1)
L8:
  lea    -0x1(%rbx),%edi
  call   <getTotient@plt>
  mov    0x10(%rsp),%rdx
  add    %rax,%r12
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rdx
  jge    L8
  mov    0x8(%rsp),%rsi
L15:
  mov    %r12,%rcx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
data_type: string
name: retrieve_data
arguments: label: D0
data_type: string

tool: D10: %ld

tool: D0: Sum of Totients between [%ld..%ld] is %ld 


assistant: ```c
int main(int argc, char **argv) {
  long lower, upper;
  sscanf(argv[1], "%ld", &lower);
  sscanf(argv[2], "%ld", &upper);
  int i;
  long result = 0.0;
  if (lower == 1) {
    result = 1.0;
    lower = 2;
  }
#pragma omp parallel for default(shared) private(i) schedule(auto) reduction(+ : result) num_threads(12)
  for (i = lower; i <= upper; i++) {
    result = result + getTotient(i);
  }
  printf("Sum of Totients between [%ld..%ld] is %ld \n", lower, upper, result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  xor    %rbp,%rbp
  pop    %rdi
  mov    %rsp,%rsi
  lea    0x8(%rsi,%rdi,8),%rdx
  push   %rbp
  push   %rbp
  and    $0xfffffffffffffff0,%rsp
  call   <_init_sblibc@plt>
  call   <_init>
  call   <main@plt>
  mov    %rax,%rdi
  call   <exit@plt>
  hlt
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _start(void) {
  __asm__ volatile("xorq %%rbp, %%rbp;"
                   "popq %%rdi;"
                   "movq %%rsp, %%rsi;"
                   "leaq 8(%%rsi,%%rdi,8), %%rdx;"
                   "pushq %%rbp;"
                   "pushq %%rbp;"
                   "andq $-16, %%rsp;"
                   "call _init_sblibc;"
                   "call _init;"
                   "call main;"
                   "movq %%rax, %%rdi;"
                   "call exit;"
                   "hlt;" ::
                       :);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_start>:
  endbr64
  xor    %rbp,%rbp
  pop    %rdi
  mov    %rsp,%rsi
  lea    0x8(%rsi,%rdi,8),%rdx
  push   %rbp
  push   %rbp
  and    $0xfffffffffffffff0,%rsp
  call   <_init_sblibc@plt>
  call   <_init>
  call   <main@plt>
  mov    %rax,%rdi
  call   <exit@plt>
  hlt
  ret
```

assistant: ```c
void _start(void) {
  __asm__ volatile("xorq %%rbp, %%rbp;"
                   "popq %%rdi;"
                   "movq %%rsp, %%rsi;"
                   "leaq 8(%%rsi,%%rdi,8), %%rdx;"
                   "pushq %%rbp;"
                   "pushq %%rbp;"
                   "andq $-16, %%rsp;"
                   "call _init_sblibc;"
                   "call _init;"
                   "call main;"
                   "movq %%rax, %%rdi;"
                   "call exit;"
                   "hlt;" ::
                       :);
}
```