ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<swapper>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swapper(int *a, int *b) {
  int temp = *a;
  memcpy(a, b, sizeof(temp));
  memcpy(b, &temp, sizeof(temp));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L33
L39:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L5
  mov    $0x0,%eax
  jmp    L17
L5:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L39
  mov    $0x1,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int isprime(int n) {
  int i = 2;
  while (i * i <= n) {
    if (n % i == 0) {
      return 0;
    }
    ++i;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isprime>:
  endbr64
  cmp    $0x3,%edi
  jle    L34
  test   $0x1,%dil
  je     L43
  mov    $0x2,%ecx
L25:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jg     L24
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L25
L39:
  ret
L24:
  mov    $0x1,%eax
  ret
L34:
  mov    $0x1,%eax
  ret
L43:
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
int isprime(int n) {
  int i = 2;
  while (i * i <= n) {
    if (n % i == 0) {
      return 0;
    }
    ++i;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isprime>:
  endbr64
  cmp    $0x3,%edi
  jle    L8
  test   $0x1,%dil
  je     L41
  mov    $0x2,%ecx
  jmp    L50
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L16
L50:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L38
L8:
  mov    $0x1,%edx
L16:
  mov    %edx,%eax
  ret
L41:
  xor    %edx,%edx
  jmp    L16
```

assistant: ```c
int isprime(int n) {
  int i = 2;
  while (i * i <= n) {
    if (n % i == 0) {
      return 0;
    }
    ++i;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isprime>:
  endbr64
  cmp    $0x3,%edi
  jle    L50
  test   $0x1,%dil
  je     L41
  mov    $0x2,%ecx
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L11
L32:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L0
L50:
  mov    $0x1,%edx
L11:
  mov    %edx,%eax
  ret
L41:
  xor    %edx,%edx
  jmp    L11
```

assistant: ```c
int isprime(int n) {
  int i = 2;
  while (i * i <= n) {
    if (n % i == 0) {
      return 0;
    }
    ++i;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  add    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  lea    0x1(%rdx),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x18(%rbp)
  lea    (%rdx,%rax,1),%ecx
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type_infered: string
name: retrieve_data
arguments: data_label: D4
type_infered: string
name: retrieve_data
arguments: data_label: D27
type_infered: string

tool: D22: %u

tool: D4: %d	%d


tool: D27: i=%d j=%d
k=%d m=%d


assistant: ```c
void main() {
  unsigned kk, n;
  scanf("%u", &n);
  kk = n % 10 * 10 + n / 10;
  printf("%d\t%d\n", n, kk);
  int i, j, k, m, l = 5;
  i = j = 6;
  l = i + j + (++i);
  k = (++i) + (++i) + (++i) + (++i);
  m = j++ + j++ + j++;
  printf("i=%d j=%d\nk=%d m=%d\n", i, j, k, m);
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %esi,%ecx
  sub    %edx,%ecx
  lea    (%rcx,%rcx,4),%edx
  lea    (%rax,%rdx,2),%edx
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x15,%r8d
  mov    $0x27,%ecx
  mov    $0x9,%edx
  mov    $0xb,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D28
type: string
name: unpack_data
arguments: data_label: D18
type: string

tool: D0: %u

tool: D28: %d	%d


tool: D18: i=%d j=%d
k=%d m=%d


assistant: ```c
void main() {
  unsigned kk, n;
  scanf("%u", &n);
  kk = n % 10 * 10 + n / 10;
  printf("%d\t%d\n", n, kk);
  int i, j, k, m, l = 5;
  i = j = 6;
  l = i + j + (++i);
  k = (++i) + (++i) + (++i) + (++i);
  m = j++ + j++ + j++;
  printf("i=%d j=%d\nk=%d m=%d\n", i, j, k, m);
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    $0xcccccccd,%edx
  lea    D25(%rip),%rdi
  mov    %rax,%rsi
  imul   %rdx,%rax
  mov    %esi,%ecx
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  lea    (%rcx,%rcx,4),%edx
  lea    (%rax,%rdx,2),%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x15,%r8d
  mov    $0x27,%ecx
  mov    $0x9,%edx
  mov    $0xb,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D19
type: string

tool: D23: %u

tool: D25: %d	%d


tool: D19: i=%d j=%d
k=%d m=%d


assistant: ```c
void main() {
  unsigned kk, n;
  scanf("%u", &n);
  kk = n % 10 * 10 + n / 10;
  printf("%d\t%d\n", n, kk);
  int i, j, k, m, l = 5;
  i = j = 6;
  l = i + j + (++i);
  k = (++i) + (++i) + (++i) + (++i);
  m = j++ + j++ + j++;
  printf("i=%d j=%d\nk=%d m=%d\n", i, j, k, m);
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    $0xcccccccd,%edx
  lea    D4(%rip),%rdi
  mov    %rax,%rsi
  imul   %rdx,%rax
  mov    %esi,%ecx
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  lea    (%rcx,%rcx,4),%edx
  lea    (%rax,%rdx,2),%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x15,%r8d
  mov    $0x27,%ecx
  mov    $0x9,%edx
  mov    $0xb,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D7
datatype: string

tool: D15: %u

tool: D4: %d	%d


tool: D7: i=%d j=%d
k=%d m=%d


assistant: ```c
void main() {
  unsigned kk, n;
  scanf("%u", &n);
  kk = n % 10 * 10 + n / 10;
  printf("%d\t%d\n", n, kk);
  int i, j, k, m, l = 5;
  i = j = 6;
  l = i + j + (++i);
  k = (++i) + (++i) + (++i) + (++i);
  m = j++ + j++ + j++;
  printf("i=%d j=%d\nk=%d m=%d\n", i, j, k, m);
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getCommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L86
  cmpl   $0x0,-0x1c(%rbp)
  jne    L78
  movb   $0x84,-0x2(%rbp)
  jmp    L61
L78:
  movb   $0x88,-0x2(%rbp)
  jmp    L61
L86:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L117
  movb   $0x44,-0x2(%rbp)
  jmp    L61
L117:
  movb   $0x48,-0x2(%rbp)
L61:
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  mov    %al,-0x1(%rbp)
  cmpl   $0x3,-0x1c(%rbp)
  je     L40
  cmpl   $0x3,-0x1c(%rbp)
  jg     L70
  cmpl   $0x1,-0x1c(%rbp)
  je     L84
  cmpl   $0x2,-0x1c(%rbp)
  je     L32
  jmp    L70
L84:
  orb    $0x4,-0x1(%rbp)
  jmp    L70
L32:
  orb    $0x2,-0x1(%rbp)
  jmp    L70
L40:
  orb    $0x4,-0x1(%rbp)
  orb    $0x2,-0x1(%rbp)
  nop
L70:
  mov    -0x28(%rbp),%rax
  movzbl -0x2(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  movb   $0x5,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getCommand(bool state, int device, int index, char *c) {
  char commandByte, addressByte;
  if (state) {
    if (index == 0) {
      commandByte = 0x84;
    } else {
      commandByte = 0x88;
    }
  } else {
    if (index == 0) {
      commandByte = 0x44;
    } else {
      commandByte = 0x48;
    }
  }
  addressByte = (char)(device << 3);
  switch (index) {
  case 1:
    (1 ? ((addressByte) |= (1UL << (2))) : ((addressByte) &= ~(1UL << (2))));
    break;
  case 2:
    (1 ? ((addressByte) |= (1UL << (1))) : ((addressByte) &= ~(1UL << (1))));
    break;
  case 3:
    (1 ? ((addressByte) |= (1UL << (2))) : ((addressByte) &= ~(1UL << (2))));
    (1 ? ((addressByte) |= (1UL << (1))) : ((addressByte) &= ~(1UL << (1))));
    break;
  }
  c[0] = commandByte;
  c[1] = addressByte;
  c[2] = 5;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getCommand>:
  endbr64
  test   %edi,%edi
  je     L6
  mov    $0xffffff88,%edi
  test   %edx,%edx
  jne    L4
  mov    $0xffffff84,%edi
L83:
  lea    0x0(,%rsi,8),%eax
  jmp    L10
L6:
  test   %edx,%edx
  je     L78
  mov    $0x48,%edi
L4:
  shl    $0x3,%esi
  mov    %esi,%eax
  cmp    $0x2,%edx
  je     L48
  cmp    $0x3,%edx
  jne    L39
  or     $0x6,%eax
  jmp    L10
L39:
  or     $0x4,%esi
  cmp    $0x1,%edx
  cmove  %esi,%eax
L10:
  mov    %dil,(%rcx)
  mov    %al,0x1(%rcx)
  movb   $0x5,0x2(%rcx)
  ret
L48:
  or     $0x2,%eax
  jmp    L10
L78:
  mov    $0x44,%edi
  jmp    L83
```

assistant: ```c
void getCommand(bool state, int device, int index, char *c) {
  char commandByte, addressByte;
  if (state) {
    if (index == 0) {
      commandByte = 0x84;
    } else {
      commandByte = 0x88;
    }
  } else {
    if (index == 0) {
      commandByte = 0x44;
    } else {
      commandByte = 0x48;
    }
  }
  addressByte = (char)(device << 3);
  switch (index) {
  case 1:
    (1 ? ((addressByte) |= (1UL << (2))) : ((addressByte) &= ~(1UL << (2))));
    break;
  case 2:
    (1 ? ((addressByte) |= (1UL << (1))) : ((addressByte) &= ~(1UL << (1))));
    break;
  case 3:
    (1 ? ((addressByte) |= (1UL << (2))) : ((addressByte) &= ~(1UL << (2))));
    (1 ? ((addressByte) |= (1UL << (1))) : ((addressByte) &= ~(1UL << (1))));
    break;
  }
  c[0] = commandByte;
  c[1] = addressByte;
  c[2] = 5;
}
```
user: What is the c source code of the assembly code below?

```asm
<getCommand>:
  endbr64
  test   %edi,%edi
  je     L47
  mov    $0xffffff88,%edi
  test   %edx,%edx
  jne    L31
  mov    $0xffffff84,%edi
L36:
  lea    0x0(,%rsi,8),%eax
  mov    %dil,(%rcx)
  mov    %al,0x1(%rcx)
  movb   $0x5,0x2(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  test   %edx,%edx
  je     L24
  mov    $0x48,%edi
L31:
  shl    $0x3,%esi
  mov    %esi,%eax
  cmp    $0x2,%edx
  je     L43
  cmp    $0x3,%edx
  jne    L58
  or     $0x6,%eax
  mov    %dil,(%rcx)
  mov    %al,0x1(%rcx)
  movb   $0x5,0x2(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L58:
  or     $0x4,%esi
  cmp    $0x1,%edx
  mov    %dil,(%rcx)
  cmove  %esi,%eax
  movb   $0x5,0x2(%rcx)
  mov    %al,0x1(%rcx)
  ret
  nopl   0x0(%rax)
L43:
  or     $0x2,%eax
  mov    %dil,(%rcx)
  mov    %al,0x1(%rcx)
  movb   $0x5,0x2(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    $0x44,%edi
  jmp    L36
```

assistant: ```c
void getCommand(bool state, int device, int index, char *c) {
  char commandByte, addressByte;
  if (state) {
    if (index == 0) {
      commandByte = 0x84;
    } else {
      commandByte = 0x88;
    }
  } else {
    if (index == 0) {
      commandByte = 0x44;
    } else {
      commandByte = 0x48;
    }
  }
  addressByte = (char)(device << 3);
  switch (index) {
  case 1:
    (1 ? ((addressByte) |= (1UL << (2))) : ((addressByte) &= ~(1UL << (2))));
    break;
  case 2:
    (1 ? ((addressByte) |= (1UL << (1))) : ((addressByte) &= ~(1UL << (1))));
    break;
  case 3:
    (1 ? ((addressByte) |= (1UL << (2))) : ((addressByte) &= ~(1UL << (2))));
    (1 ? ((addressByte) |= (1UL << (1))) : ((addressByte) &= ~(1UL << (1))));
    break;
  }
  c[0] = commandByte;
  c[1] = addressByte;
  c[2] = 5;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getCommand>:
  endbr64
  test   %edi,%edi
  je     L15
  mov    $0xffffff88,%edi
  test   %edx,%edx
  jne    L51
  mov    $0xffffff84,%edi
L0:
  lea    0x0(,%rsi,8),%eax
  mov    %dil,(%rcx)
  mov    %al,0x1(%rcx)
  movb   $0x5,0x2(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  test   %edx,%edx
  je     L22
  mov    $0x48,%edi
L51:
  shl    $0x3,%esi
  mov    %esi,%eax
  cmp    $0x2,%edx
  je     L45
  cmp    $0x3,%edx
  jne    L25
  or     $0x6,%eax
  mov    %dil,(%rcx)
  mov    %al,0x1(%rcx)
  movb   $0x5,0x2(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  or     $0x4,%esi
  cmp    $0x1,%edx
  mov    %dil,(%rcx)
  cmove  %esi,%eax
  movb   $0x5,0x2(%rcx)
  mov    %al,0x1(%rcx)
  ret
  nopl   0x0(%rax)
L45:
  or     $0x2,%eax
  mov    %dil,(%rcx)
  mov    %al,0x1(%rcx)
  movb   $0x5,0x2(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    $0x44,%edi
  jmp    L0
```

assistant: ```c
void getCommand(bool state, int device, int index, char *c) {
  char commandByte, addressByte;
  if (state) {
    if (index == 0) {
      commandByte = 0x84;
    } else {
      commandByte = 0x88;
    }
  } else {
    if (index == 0) {
      commandByte = 0x44;
    } else {
      commandByte = 0x48;
    }
  }
  addressByte = (char)(device << 3);
  switch (index) {
  case 1:
    (1 ? ((addressByte) |= (1UL << (2))) : ((addressByte) &= ~(1UL << (2))));
    break;
  case 2:
    (1 ? ((addressByte) |= (1UL << (1))) : ((addressByte) &= ~(1UL << (1))));
    break;
  case 3:
    (1 ? ((addressByte) |= (1UL << (2))) : ((addressByte) &= ~(1UL << (2))));
    (1 ? ((addressByte) |= (1UL << (1))) : ((addressByte) &= ~(1UL << (1))));
    break;
  }
  c[0] = commandByte;
  c[1] = addressByte;
  c[2] = 5;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<irc_cmd_notice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x7,%edx
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D17: NOTICE 

tool: D13:  :

tool: D0: 


assistant: ```c
void irc_cmd_notice(struct evbuffer *out, char *dest, char *message) {
  evbuffer_add(out, "NOTICE ", 7);
  evbuffer_add(out, dest, strlen(dest));
  evbuffer_add(out, " :", 2);
  evbuffer_add(out, message, strlen(message));
  evbuffer_add(out, "\n", 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<irc_cmd_notice>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x7,%edx
  lea    D13(%rip),%rsi
  call   <evbuffer_add@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <evbuffer_add@plt>
  mov    $0x2,%edx
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  call   <evbuffer_add@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <evbuffer_add@plt>
  mov    $0x1,%edx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <evbuffer_add@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D24
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string

tool: D13: NOTICE 

tool: D24:  :

tool: D6: 


assistant: ```c
void irc_cmd_notice(struct evbuffer *out, char *dest, char *message) {
  evbuffer_add(out, "NOTICE ", 7);
  evbuffer_add(out, dest, strlen(dest));
  evbuffer_add(out, " :", 2);
  evbuffer_add(out, message, strlen(message));
  evbuffer_add(out, "\n", 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<irc_cmd_notice>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  lea    D17(%rip),%rsi
  push   %r12
  mov    %rdx,%r12
  mov    $0x7,%edx
  push   %rbp
  mov    %rdi,%rbp
  call   <evbuffer_add@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <evbuffer_add@plt>
  mov    $0x2,%edx
  lea    D29(%rip),%rsi
  mov    %rbp,%rdi
  call   <evbuffer_add@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <evbuffer_add@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  mov    $0x1,%edx
  lea    D14(%rip),%rsi
  pop    %r13
  jmp    1070 <evbuffer_add@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D14
type: string

tool: D17: NOTICE 

tool: D29:  :

tool: D14: 


assistant: ```c
void irc_cmd_notice(struct evbuffer *out, char *dest, char *message) {
  evbuffer_add(out, "NOTICE ", 7);
  evbuffer_add(out, dest, strlen(dest));
  evbuffer_add(out, " :", 2);
  evbuffer_add(out, message, strlen(message));
  evbuffer_add(out, "\n", 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<irc_cmd_notice>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  lea    D21(%rip),%rsi
  push   %r12
  mov    %rdx,%r12
  mov    $0x7,%edx
  push   %rbp
  mov    %rdi,%rbp
  call   <evbuffer_add@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <evbuffer_add@plt>
  mov    $0x2,%edx
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <evbuffer_add@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <evbuffer_add@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  mov    $0x1,%edx
  lea    D15(%rip),%rsi
  pop    %r13
  jmp    1070 <evbuffer_add@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D21
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string

tool: D21: NOTICE 

tool: D13:  :

tool: D15: 


assistant: ```c
void irc_cmd_notice(struct evbuffer *out, char *dest, char *message) {
  evbuffer_add(out, "NOTICE ", 7);
  evbuffer_add(out, dest, strlen(dest));
  evbuffer_add(out, " :", 2);
  evbuffer_add(out, message, strlen(message));
  evbuffer_add(out, "\n", 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xd,%esi
  mov    $0xc,%edi
  call   <max@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xd,-0x4(%rbp)
  je     L13
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  mov    $0xc,%esi
  mov    $0xd,%edi
  call   <max@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xd,-0x4(%rbp)
  je     L19
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D5
type: string

tool: D4: Test failed


tool: D5: All tests performed - if no error all passed


assistant: ```c
int main() {
  int ret = max(12, 13);
  if (ret != 13) {
    printf("Test failed\n");
  }
  ret = max(13, 12);
  if (ret != 13) {
    printf("Test failed\n");
  }
  printf("All tests performed - if no error all passed\n");
}
```