ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_strnconcat>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L41
  mov    %rdi,%rbp
  test   %rsi,%rsi
  jne    L82
  test   %rdi,%rdi
  je     L41
  xor    %eax,%eax
  call   <my_strdup@plt>
  movslq %eax,%r8
L42:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  xor    %r8d,%r8d
  test   %rbx,%rbx
  je     L42
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <my_strlen@plt>
  cmp    %r12d,%eax
  cmovbe %eax,%r12d
  xor    %eax,%eax
  mov    %r12d,%edi
  add    $0x1,%rdi
  call   <xmalloc@plt>
  movslq %eax,%r8
  test   %r12d,%r12d
  je     L42
  lea    -0x1(%r12),%eax
  sub    %r8,%rbx
  lea    0x1(%r8,%rax,1),%rsi
  mov    %rbx,%rdx
  mov    %r8,%rax
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L25
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L82:
  xor    %eax,%eax
  call   <my_strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <my_strlen@plt>
  cmp    %r12d,%eax
  cmovbe %eax,%r12d
  xor    %eax,%eax
  lea    0x0(%r13,%r12,1),%edi
  add    $0x1,%rdi
  call   <xmalloc@plt>
  movzbl 0x0(%rbp),%ecx
  cltq
  mov    %rax,%r8
  test   %cl,%cl
  je     L32
  mov    $0x1,%edx
  nopl   (%rax)
L11:
  mov    %cl,-0x1(%rdx,%rax,1)
  movslq %edx,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rbp,%rdx,1),%ecx
  test   %cl,%cl
  jne    L11
L91:
  test   %r12d,%r12d
  je     L42
  lea    -0x1(%r12),%edx
  lea    0x1(%rdx,%rax,1),%rdi
  add    %rsi,%rax
  sub    %rax,%rbx
  add    %rsi,%rdi
  mov    %rbx,%rdx
  nopl   0x0(%rax,%rax,1)
L90:
  movzbl (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    %rdi,%rax
  jne    L90
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  xor    %esi,%esi
  jmp    L91
```

assistant: ```c
char *my_strnconcat(char *s1, char *s2, unsigned int n) {
  int l1;
  int l2;
  char *s3 = ((void *)0);
  int i;
  int j;
  if (s1 && s2) {
    l1 = my_strlen(s1);
    l2 = my_strlen(s2);
    if (n > l2)
      n = l2;
    s3 = (char *)xmalloc((l1 + n) * sizeof(char) + 1);
    for (i = 0; s1[i]; i++)
      s3[i] = s1[i];
    for (j = 0; j < n; i++, j++)
      s3[i] = s2[j];
    return s3;
  } else if (s1)
    return my_strdup(s1);
  else if (s2) {
    l2 = my_strlen(s2);
    if (n > l2)
      n = l2;
    s3 = xmalloc(n * sizeof(char) + 1);
    for (i = 0; i < n; ++i)
      s3[i] = s2[i];
    return s3;
  } else
    return ((void *)0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x88(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x84(%rbp)
  movl   $0x1,-0x8c(%rbp)
  movl   $0x0,-0x94(%rbp)
  jmp    L28
L71:
  mov    -0x94(%rbp),%eax
  mov    %eax,-0x90(%rbp)
  jmp    L41
L27:
  mov    -0x94(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%edx
  mov    -0x90(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L53
  movl   $0x0,-0x8c(%rbp)
  jmp    L18
L53:
  addl   $0x1,-0x90(%rbp)
L41:
  mov    -0x94(%rbp),%edx
  mov    -0x84(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x90(%rbp)
  jl     L27
L18:
  cmpl   $0x1,-0x8c(%rbp)
  je     L34
  addl   $0x1,-0x94(%rbp)
L28:
  mov    -0x88(%rbp),%eax
  sub    -0x84(%rbp),%eax
  cmp    %eax,-0x94(%rbp)
  jl     L71
  jmp    L50
L34:
  nop
L50:
  mov    -0x88(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x84(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x1,-0x8c(%rbp)
  jne    L44
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L106
L44:
  cmpl   $0x0,-0x8c(%rbp)
  jne    L106
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L106:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D49
datatype: string
name: retrieve_data
arguments: data_label: D35
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D58
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string

tool: D49: %s


tool: D35: %s

tool: D6: %d


tool: D58: Yes

tool: D12: No

assistant: ```c
int main() {
  char str[50];
  char str1[50];
  scanf("%s\n", str);
  scanf("%s", str1);
  int count = length(str);
  int count1 = length(str1);
  int i, j;
  int num = 1;
  for (i = 0; i < (count - count1); i++) {
    for (j = i; j < (i + count1); j++) {
      if (str[i] != str1[j]) {
        num = 0;
        break;
      }
    }
    if (num == 1)
      break;
  }
  printf("%d\n", count);
  printf("%d\n", count1);
  if (num == 1) {
    printf("Yes");
  } else if (num == 0) {
    printf("No");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  lea    0x40(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <length@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <length@plt>
  mov    %eax,%ebx
  mov    %ebp,%r9d
  sub    %eax,%r9d
  test   %r9d,%r9d
  jle    L55
  mov    %eax,%edi
  lea    -0x1(%rax),%r10d
  lea    0x41(%rsp,%r10,1),%rdx
  mov    %r9d,%r9d
  mov    $0x0,%esi
  mov    $0x1,%r8d
  mov    $0x0,%r11d
  jmp    L42
L14:
  add    $0x1,%rsi
  add    $0x1,%edi
  add    $0x1,%rdx
  mov    %r11d,%r8d
  cmp    %r9,%rsi
  je     L31
L42:
  cmp    %esi,%edi
  jle    L81
  movzbl (%rsp,%rsi,1),%ecx
  mov    %rdx,%rax
  sub    %r10,%rax
  sub    $0x1,%rax
L20:
  cmp    (%rax),%cl
  jne    L14
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L20
L81:
  cmp    $0x1,%r8d
  jne    L14
L55:
  mov    %ebp,%esi
  lea    D27(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L31:
  mov    %ebp,%esi
  lea    D27(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_guessed: string
name: parse_data
arguments: data_tag: D38
type_guessed: string
name: parse_data
arguments: data_tag: D27
type_guessed: string
name: parse_data
arguments: data_tag: D7
type_guessed: string
name: parse_data
arguments: data_tag: D43
type_guessed: string

tool: D26: %s


tool: D38: %s

tool: D27: %d


tool: D7: Yes

tool: D43: No

assistant: ```c
int main() {
  char str[50];
  char str1[50];
  scanf("%s\n", str);
  scanf("%s", str1);
  int count = length(str);
  int count1 = length(str1);
  int i, j;
  int num = 1;
  for (i = 0; i < (count - count1); i++) {
    for (j = i; j < (i + count1); j++) {
      if (str[i] != str1[j]) {
        num = 0;
        break;
      }
    }
    if (num == 1)
      break;
  }
  printf("%d\n", count);
  printf("%d\n", count1);
  if (num == 1) {
    printf("Yes");
  } else if (num == 0) {
    printf("No");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D27(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x40(%rsp),%rbx
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <length@plt>
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <length@plt>
  mov    %r13d,%r8d
  sub    %eax,%r8d
  mov    %eax,%r12d
  test   %r8d,%r8d
  jle    L8
  test   %eax,%eax
  jle    L8
  lea    -0x1(%r12),%eax
  movslq %r8d,%r8
  xor    %esi,%esi
  mov    $0x1,%edi
  lea    0x41(%rsp,%rax,1),%rdx
  nopl   0x0(%rax,%rax,1)
L53:
  movzbl 0x0(%rbp,%rsi,1),%ecx
  lea    (%rbx,%rsi,1),%rax
  jmp    L70
  nopl   0x0(%rax,%rax,1)
L68:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L20
L70:
  cmp    (%rax),%cl
  je     L68
L22:
  add    $0x1,%rsi
  add    $0x1,%rdx
  xor    %edi,%edi
  cmp    %r8,%rsi
  jne    L53
  lea    D49(%rip),%rbp
  mov    %r13d,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L0:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    $0x1,%edi
  jne    L22
L8:
  lea    D49(%rip),%rbp
  mov    %r13d,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D27
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D49
type_guessed: string
name: parse_data
arguments: data_tag: D26
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D27: %s


tool: D16: %s

tool: D49: %d


tool: D26: No

tool: D0: Yes

assistant: ```c
int main() {
  char str[50];
  char str1[50];
  scanf("%s\n", str);
  scanf("%s", str1);
  int count = length(str);
  int count1 = length(str1);
  int i, j;
  int num = 1;
  for (i = 0; i < (count - count1); i++) {
    for (j = i; j < (i + count1); j++) {
      if (str[i] != str1[j]) {
        num = 0;
        break;
      }
    }
    if (num == 1)
      break;
  }
  printf("%d\n", count);
  printf("%d\n", count1);
  if (num == 1) {
    printf("Yes");
  } else if (num == 0) {
    printf("No");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D33(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x40(%rsp),%rbx
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <length@plt>
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <length@plt>
  mov    %r13d,%r8d
  sub    %eax,%r8d
  mov    %eax,%r12d
  test   %r8d,%r8d
  jle    L52
  test   %eax,%eax
  jle    L52
  lea    -0x1(%r12),%eax
  movslq %r8d,%r8
  xor    %esi,%esi
  mov    $0x1,%edi
  lea    0x41(%rsp,%rax,1),%rdx
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl 0x0(%rbp,%rsi,1),%ecx
  lea    (%rbx,%rsi,1),%rax
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L25
L27:
  cmp    (%rax),%cl
  je     L36
L18:
  add    $0x1,%rsi
  add    $0x1,%rdx
  xor    %edi,%edi
  cmp    %r8,%rsi
  jne    L13
  lea    D19(%rip),%rbp
  mov    %r13d,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L75:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  cmp    $0x1,%edi
  jne    L18
L52:
  lea    D19(%rip),%rbp
  mov    %r13d,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L75
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
type: string
name: extract_symbolic_data
arguments: label: D40
type: string
name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D34
type: string

tool: D33: %s


tool: D40: %s

tool: D19: %d


tool: D8: No

tool: D34: Yes

assistant: ```c
int main() {
  char str[50];
  char str1[50];
  scanf("%s\n", str);
  scanf("%s", str1);
  int count = length(str);
  int count1 = length(str1);
  int i, j;
  int num = 1;
  for (i = 0; i < (count - count1); i++) {
    for (j = i; j < (i + count1); j++) {
      if (str[i] != str1[j]) {
        num = 0;
        break;
      }
    }
    if (num == 1)
      break;
  }
  printf("%d\n", count);
  printf("%d\n", count1);
  if (num == 1) {
    printf("Yes");
  } else if (num == 0) {
    printf("No");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copyword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L17
L3:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L17:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void copyword(char *dst, const char *src) {
  while (isalpha(*src)) {
    *dst++ = tolower(*src++);
  }
  *dst = '\0';
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copyword>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  jmp    L15
L8:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <tolower@plt>
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
L15:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L8
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void copyword(char *dst, const char *src) {
  while (isalpha(*src)) {
    *dst++ = tolower(*src++);
  }
  *dst = '\0';
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copyword>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L14:
  movsbl (%rbx),%edi
  add    $0x1,%rbp
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbp)
L8:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L14
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void copyword(char *dst, const char *src) {
  while (isalpha(*src)) {
    *dst++ = tolower(*src++);
  }
  *dst = '\0';
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copyword>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L13:
  movsbl (%rbx),%edi
  add    $0x1,%rbp
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbp)
L6:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L13
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void copyword(char *dst, const char *src) {
  while (isalpha(*src)) {
    *dst++ = tolower(*src++);
  }
  *dst = '\0';
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ajRefseqExit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ajRefseqinExit@plt>
  mov    $0x0,%eax
  call   <ajRefseqoutExit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ajRefseqExit(void) {
  ajRefseqinExit();
  ajRefseqoutExit();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ajRefseqExit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ajRefseqinExit@plt>
  mov    $0x0,%eax
  call   <ajRefseqoutExit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ajRefseqExit(void) {
  ajRefseqinExit();
  ajRefseqoutExit();
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ajRefseqExit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ajRefseqinExit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ajRefseqoutExit@plt>
```

assistant: ```c
void ajRefseqExit(void) {
  ajRefseqinExit();
  ajRefseqoutExit();
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ajRefseqExit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ajRefseqinExit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ajRefseqoutExit@plt>
```

assistant: ```c
void ajRefseqExit(void) {
  ajRefseqinExit();
  ajRefseqoutExit();
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm

:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *s() {
  static int i;
  return &i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm

:
  endbr64
  lea    D1(%rip),%rax
  ret
```

assistant: ```c
int *s() {
  static int i;
  return &i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm

:
  endbr64
  lea    D2(%rip),%rax
  ret
```

assistant: ```c
int *s() {
  static int i;
  return &i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm

:
  endbr64
  lea    D5(%rip),%rax
  ret
```

assistant: ```c
int *s() {
  static int i;
  return &i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  mov    %edi,-0x1014(%rbp)
  mov    %rsi,-0x1020(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <read_search_path@plt>
L4:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1010(%rbp),%rax
  mov    $0x1000,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movb   $0x0,-0x11(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  jmp    L35
L14:
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  jmp    L4
L35:
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D46
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D35
datatype: string
name: parse_data
arguments: data_tag: D23
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string

tool: D46: ***************************************

tool: D2: HINSHISTU Manufacturing Private Limited

tool: D35: Scan or type code: 

tool: D23: %4095s

tool: D21: exit

assistant: ```c
int main(int argc, char **argv) {
  char buffer[4096];
  printf("***************************************\n");
  printf("HINSHISTU Manufacturing Private Limited\n");
  printf("***************************************\n");
  printf("\n");
  printf("\n");
  read_search_path();
  while (1) {
    printf("Scan or type code: ");
    memset(buffer, 0, 4096);
    scanf("%4095s", buffer);
    buffer[4095] = '\0';
    printf("\n");
    printf("\n");
    printf("%s\n", buffer);
    if (strcmp("exit", buffer) == 0) {
      return 0;
    }
    system(buffer);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <read_search_path@plt>
  lea    D6(%rip),%r13
  mov    %rsp,%rbx
  lea    D43(%rip),%r12
  lea    D35(%rip),%rbp
  jmp    L7
L0:
  mov    %rbx,%rdi
  call   <system@plt>
L7:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1000,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movb   $0x0,0xfff(%rsp)
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L0
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D43
data_type: string
name: unpack_data
arguments: tag: D35
data_type: string

tool: D22: ***************************************

tool: D28: HINSHISTU Manufacturing Private Limited

tool: D6: Scan or type code: 

tool: D43: %4095s

tool: D35: exit

assistant: ```c
int main(int argc, char **argv) {
  char buffer[4096];
  printf("***************************************\n");
  printf("HINSHISTU Manufacturing Private Limited\n");
  printf("***************************************\n");
  printf("\n");
  printf("\n");
  read_search_path();
  while (1) {
    printf("Scan or type code: ");
    memset(buffer, 0, 4096);
    scanf("%4095s", buffer);
    buffer[4095] = '\0';
    printf("\n");
    printf("\n");
    printf("%s\n", buffer);
    if (strcmp("exit", buffer) == 0) {
      return 0;
    }
    system(buffer);
  }
}
```