ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skip_format>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L5
  xor    %eax,%eax
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    $0x23,%dl
  je     L97
  test   %eax,%eax
  je     L148
  movzbl 0x1(%rdi),%ecx
  cmp    $0x5d,%dl
  je     L93
  mov    %ecx,%edx
  nopl   0x0(%rax)
L83:
  add    $0x1,%rdi
  test   %dl,%dl
  je     L5
L0:
  cmp    $0x5b,%dl
  jne    L8
  movzbl 0x1(%rdi),%edx
  add    $0x1,%eax
  jmp    L83
  cs nopw 0x0(%rax,%rax,1)
L97:
  cmpb   $0x0,0x1(%rdi)
  je     L14
  movzbl 0x2(%rdi),%edx
  add    $0x1,%rdi
  jmp    L83
L148:
  cmp    $0x26,%dl
  sete   %al
  cmp    $0x7c,%dl
  sete   %cl
  or     %cl,%al
  jne    L5
  cmp    $0x5d,%dl
  je     L5
L94:
  movzbl 0x1(%rdi),%edx
  xor    %eax,%eax
  jmp    L83
  nopl   (%rax)
L14:
  test   %eax,%eax
  je     L94
  lea    0x1(%rdi),%rax
  ret
  nopl   0x0(%rax)
L93:
  sub    $0x1,%eax
  mov    %ecx,%edx
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
__attribute__((pure)) const char *skip_format(const char *p) {
  unsigned stack = 0;
  while (*p != '\0') {
    if (*p == '[')
      stack++;
    else if (*p == '#' && p[1] != '\0')
      ++p;
    else if (stack > 0) {
      if (*p == ']')
        --stack;
    } else if (*p == '&' || *p == '|' || *p == ']')
      break;
    ++p;
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  movl   $0x1,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    D10(%rip),%rax
  mov    (%rax),%r8
  mov    0x8(%rbx),%rdi
  lea    0x4(%rsp),%rax
  push   %rax
  push   %r8
  lea    0x10(%rsp),%r9
  mov    $0x1,%ecx
  mov    $0x1,%edx
  call   <callrpc@plt>
  add    $0x10,%rsp
  mov    D12(%rip),%rdx
  cmp    (%rdx),%eax
  jne    L28
L4:
  mov    0x4(%rsp),%eax
  cmp    %eax,(%rsp)
  setne  %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  mov    %eax,%edi
  call   <clnt_perrno@plt>
  jmp    L4
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int progNum = atoi(argc[2]);
  enum clnt_stat cs;
  int varSnd = 1;
  int varRcv = 0;
  if (run_mode == 1) {
    printf("progNum : %d\n", progNum);
  }
  cs = callrpc(argc[1], progNum, 1, 1, (xdrproc_t)xdr_int, (char *)&varSnd, (xdrproc_t)xdr_int, (char *)&varRcv);
  if (cs != RPC_SUCCESS)
    clnt_perrno(cs);
  if (varSnd == varRcv)
    test_status = 0;
  return test_status;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    0x10(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <atoi@plt>
  movl   $0x1,(%rsp)
  mov    0x8(%rbx),%rdi
  mov    $0x1,%edx
  mov    %eax,%esi
  mov    D11(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    $0x1,%ecx
  mov    (%rax),%r8
  lea    0x4(%rsp),%rax
  push   %rax
  push   %r8
  lea    0x10(%rsp),%r9
  call   <callrpc@plt>
  mov    %eax,%edi
  pop    %rax
  mov    D8(%rip),%rax
  pop    %rdx
  cmp    (%rax),%edi
  je     L19
  call   <clnt_perrno@plt>
L19:
  mov    0x4(%rsp),%eax
  cmp    %eax,(%rsp)
  setne  %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int progNum = atoi(argc[2]);
  enum clnt_stat cs;
  int varSnd = 1;
  int varRcv = 0;
  if (run_mode == 1) {
    printf("progNum : %d\n", progNum);
  }
  cs = callrpc(argc[1], progNum, 1, 1, (xdrproc_t)xdr_int, (char *)&varSnd, (xdrproc_t)xdr_int, (char *)&varRcv);
  if (cs != RPC_SUCCESS)
    clnt_perrno(cs);
  if (varSnd == varRcv)
    test_status = 0;
  return test_status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    0x10(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <atoi@plt>
  movl   $0x1,(%rsp)
  mov    0x8(%rbx),%rdi
  mov    $0x1,%edx
  mov    %eax,%esi
  mov    D15(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    $0x1,%ecx
  mov    (%rax),%r8
  lea    0x4(%rsp),%rax
  push   %rax
  push   %r8
  lea    0x10(%rsp),%r9
  call   <callrpc@plt>
  mov    %eax,%edi
  pop    %rax
  mov    D11(%rip),%rax
  pop    %rdx
  cmp    (%rax),%edi
  je     L11
  call   <clnt_perrno@plt>
L11:
  mov    0x4(%rsp),%eax
  cmp    %eax,(%rsp)
  setne  %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int progNum = atoi(argc[2]);
  enum clnt_stat cs;
  int varSnd = 1;
  int varRcv = 0;
  if (run_mode == 1) {
    printf("progNum : %d\n", progNum);
  }
  cs = callrpc(argc[1], progNum, 1, 1, (xdrproc_t)xdr_int, (char *)&varSnd, (xdrproc_t)xdr_int, (char *)&varRcv);
  if (cs != RPC_SUCCESS)
    clnt_perrno(cs);
  if (varSnd == varRcv)
    test_status = 0;
  return test_status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<subvf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  subsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void subvf(double *result, const double s1) {
  result[0] -= s1;
  result[1] -= s1;
  result[2] -= s1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<subvf>:
  endbr64
  movsd  (%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  movsd  0x8(%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rdi)
  movsd  0x10(%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rdi)
  ret
```

assistant: ```c
void subvf(double *result, const double s1) {
  result[0] -= s1;
  result[1] -= s1;
  result[2] -= s1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<subvf>:
  endbr64
  movsd  (%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  movsd  0x8(%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rdi)
  movsd  0x10(%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rdi)
  ret
```

assistant: ```c
void subvf(double *result, const double s1) {
  result[0] -= s1;
  result[1] -= s1;
  result[2] -= s1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<subvf>:
  endbr64
  movupd (%rdi),%xmm1
  movapd %xmm0,%xmm2
  unpcklpd %xmm2,%xmm2
  subpd  %xmm2,%xmm1
  movups %xmm1,(%rdi)
  movsd  0x10(%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rdi)
  ret
```

assistant: ```c
void subvf(double *result, const double s1) {
  result[0] -= s1;
  result[1] -= s1;
  result[2] -= s1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x2,-0x4(%rbp)
L2:
  mov    -0x2c(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sum@plt>
  addl   $0x1,-0x4(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L2
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fib(int *f1, int *f2, int *f3, int size) {
  int temp = 2;
  do {
    sum(f3, f1, f2, size);
    temp++;
    copy(f1, f2, size);
    copy(f2, f3, size);
  } while (f3[0] == 0);
  return temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fib>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  mov    $0x2,%r14d
L4:
  mov    %ebx,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sum@plt>
  add    $0x1,%r14d
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <copy@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <copy@plt>
  cmpl   $0x0,0x0(%rbp)
  je     L4
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fib(int *f1, int *f2, int *f3, int size) {
  int temp = 2;
  do {
    sum(f3, f1, f2, size);
    temp++;
    copy(f1, f2, size);
    copy(f2, f3, size);
  } while (f3[0] == 0);
  return temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fib>:
  endbr64
  push   %r14
  mov    $0x2,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  nopl   (%rax)
L4:
  mov    %ebx,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sum@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <copy@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <copy@plt>
  mov    0x0(%rbp),%eax
  add    $0x1,%r14d
  test   %eax,%eax
  je     L4
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fib(int *f1, int *f2, int *f3, int size) {
  int temp = 2;
  do {
    sum(f3, f1, f2, size);
    temp++;
    copy(f1, f2, size);
    copy(f2, f3, size);
  } while (f3[0] == 0);
  return temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fib>:
  endbr64
  push   %r14
  mov    $0x2,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  nopl   (%rax)
L5:
  mov    %ebx,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sum@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <copy@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <copy@plt>
  mov    0x0(%rbp),%eax
  add    $0x1,%r14d
  test   %eax,%eax
  je     L5
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fib(int *f1, int *f2, int *f3, int size) {
  int temp = 2;
  do {
    sum(f3, f1, f2, size);
    temp++;
    copy(f1, f2, size);
    copy(f2, f3, size);
  } while (f3[0] == 0);
  return temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bgpmon_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void bgpmon_free(void **space) {
  free(*space);
  (*space) = NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bgpmon_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void bgpmon_free(void **space) {
  free(*space);
  (*space) = NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<bgpmon_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void bgpmon_free(void **space) {
  free(*space);
  (*space) = NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bgpmon_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void bgpmon_free(void **space) {
  free(*space);
  (*space) = NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<function_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L20
L45:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L43
L7:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L68
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x1,-0x8(%rbp)
L68:
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0x1c(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L7
  cmpl   $0x0,-0x8(%rbp)
  je     L29
  addl   $0x1,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L45
  jmp    L40
L29:
  nop
L40:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void function_sort(int *arr, int SIZE) {
  int i, j, temp, swapping;
  for (i = 1; i < SIZE; i++) {
    swapping = 0;
    for (j = 0; j < SIZE - i; j++) {
      if (arr[j] > arr[j + 1]) {
        temp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = temp;
        swapping = 1;
      }
    }
    if (swapping == 0) {
      break;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<function_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r10d
  mov    $0x1,%ebp
  mov    $0x0,%r11d
  mov    $0x0,%edx
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  jmp    L40
L4:
  ret
L56:
  add    $0x1,%edx
  cmp    %edx,%r10d
  jle    L46
L40:
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%rdi
  mov    (%rdi),%ecx
  lea    0x4(%r9,%rax,1),%rax
  mov    (%rax),%r8d
  cmp    %r8d,%ecx
  jle    L56
  mov    %r8d,(%rdi)
  mov    %ecx,(%rax)
  add    $0x1,%edx
  mov    %ebx,%r11d
  cmp    %edx,%r10d
  jg     L40
L39:
  add    $0x1,%ebp
  cmp    %ebp,%esi
  jle    L30
  mov    %esi,%r10d
  sub    %ebp,%r10d
  test   %r10d,%r10d
  jle    L30
  mov    %r12d,%r11d
  mov    $0x0,%edx
  jmp    L40
L46:
  test   %r11d,%r11d
  jne    L39
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void function_sort(int *arr, int SIZE) {
  int i, j, temp, swapping;
  for (i = 1; i < SIZE; i++) {
    swapping = 0;
    for (j = 0; j < SIZE - i; j++) {
      if (arr[j] > arr[j + 1]) {
        temp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = temp;
        swapping = 1;
      }
    }
    if (swapping == 0) {
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<function_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L26
  lea    -0x2(%rsi),%r9d
  lea    0x4(%rdi),%r10
  nopl   0x0(%rax)
L4:
  mov    %r9d,%edx
  mov    %rdi,%rax
  xor    %r8d,%r8d
  lea    (%r10,%rdx,4),%rsi
  nopl   (%rax)
L23:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L16
  mov    %ecx,(%rax)
  mov    $0x1,%r8d
  mov    %edx,0x4(%rax)
L16:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L23
  test   %r8d,%r8d
  je     L26
  sub    $0x1,%r9d
  jae    L4
L26:
  ret
```

assistant: ```c
void function_sort(int *arr, int SIZE) {
  int i, j, temp, swapping;
  for (i = 1; i < SIZE; i++) {
    swapping = 0;
    for (j = 0; j < SIZE - i; j++) {
      if (arr[j] > arr[j + 1]) {
        temp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = temp;
        swapping = 1;
      }
    }
    if (swapping == 0) {
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<function_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L36
  lea    -0x2(%rsi),%r9d
  lea    0x4(%rdi),%r10
  nopl   0x0(%rax)
L7:
  mov    %r9d,%eax
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  lea    (%r10,%rax,4),%rsi
  nopl   (%rax)
L2:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L17
  movq   %xmm1,(%rdx)
  mov    $0x1,%r8d
L17:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L2
  test   %r8d,%r8d
  je     L36
  sub    $0x1,%r9d
  jae    L7
L36:
  ret
```

assistant: ```c
void function_sort(int *arr, int SIZE) {
  int i, j, temp, swapping;
  for (i = 1; i < SIZE; i++) {
    swapping = 0;
    for (j = 0; j < SIZE - i; j++) {
      if (arr[j] > arr[j + 1]) {
        temp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = temp;
        swapping = 1;
      }
    }
    if (swapping == 0) {
      break;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L23
L27:
  mov    -0x3f4(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <detab@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jg     L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string

tool: D4: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  while ((len = getline(line, 1000)) > 0) {
    detab(line, len);
    printf("%s", line);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rbp
  jmp    L20
L27:
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <detab@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L20:
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <getline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jg     L27
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D7: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  while ((len = getline(line, 1000)) > 0) {
    detab(line, len);
    printf("%s", line);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L3
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rdi
  call   <detab@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L3:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jg     L4
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string

tool: D3: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  while ((len = getline(line, 1000)) > 0) {
    detab(line, len);
    printf("%s", line);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L3
  nopl   0x0(%rax)
L23:
  mov    %rbx,%rdi
  call   <detab@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L3:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jg     L23
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string

tool: D6: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  while ((len = getline(line, 1000)) > 0) {
    detab(line, len);
    printf("%s", line);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <Load@plt>
  mov    $0x2,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <Load@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D10
type: string

tool: D6: libone.so

tool: D10: libtwo.so

assistant: ```c
int main() {
  Load("libone.so", 1);
  Load("libtwo.so", 2);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D13(%rip),%rdi
  call   <Load@plt>
  mov    $0x2,%esi
  lea    D12(%rip),%rdi
  call   <Load@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string

tool: D13: libone.so

tool: D12: libtwo.so

assistant: ```c
int main() {
  Load("libone.so", 1);
  Load("libtwo.so", 2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <Load@plt>
  mov    $0x2,%esi
  lea    D6(%rip),%rdi
  call   <Load@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
datatype: string
name: read_data
arguments: data_label: D6
datatype: string

tool: D17: libone.so

tool: D6: libtwo.so

assistant: ```c
int main() {
  Load("libone.so", 1);
  Load("libtwo.so", 2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <Load@plt>
  mov    $0x2,%esi
  lea    D14(%rip),%rdi
  call   <Load@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string
name: unpack_data
arguments: data_tag: D14
type_guessed: string

tool: D6: libone.so

tool: D14: libtwo.so

assistant: ```c
int main() {
  Load("libone.so", 1);
  Load("libtwo.so", 2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__stat_fix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __stat_fix(long p) {
  struct stat *st = (struct stat *)p;
  st->st_dev >>= 32;
  st->st_rdev >>= 32;
}
```