ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_matrix>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %edi,%r13d
  lea    D17(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L3
  movslq %r13d,%r15
  mov    $0xfffffffffffffff8,%r14
  xor    %r12d,%r12d
  lea    0x0(,%r15,8),%rax
  lea    D5(%rip),%rbp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r13),%eax
  shl    $0x3,%rax
  lea    0x8(%rbx,%rax,1),%rbx
  sub    %rax,%r14
  nopl   0x0(%rax)
L13:
  lea    (%r14,%rbx,1),%r15
  nopl   0x0(%rax)
L8:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L8
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r13d
  jne    L13
L3:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D5
datatype: string

tool: D17: 
Matrix %s


tool: D5: %8g	

assistant: ```c
void print_matrix(int N, char *name, double *matrix) {
  printf("\nMatrix %s\n", name);
  for (int i = 0; i < N; i++) {
    for (int j = 0; j < N; j++) {
      printf("%8g\t", matrix[N * i + j]);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_half_a_memory_stage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L19:
  mov    -0x30(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <catf@plt>
  test   %rax,%rax
  js     L62
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L19
  movl   $0x0,-0x14(%rbp)
  jmp    L23
L25:
  mov    -0x38(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <catf@plt>
  test   %rax,%rax
  js     L76
  addl   $0x1,-0x14(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L25
  mov    -0x10(%rbp),%rax
  jmp    L85
L62:
  nop
  jmp    L61
L76:
  nop
L61:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L85:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D4:         in_%1$d_%2$s <= `in_data(%1$d);
        addr_%1$d_%2$s <= `write_addr;


tool: D6:         addr_%1$d_%2$s <= `read_addr(%1$d);


assistant: ```c
char *create_half_a_memory_stage(unsigned inputs, char *write_to, char *read_from) {
  char *str = NULL;
  unsigned i;
  for (i = 0; i < inputs; ++i) {
    if (catf(&str,
             "        in_%1$d_%2$s <= `in_data(%1$d);\n"
             "        addr_%1$d_%2$s <= `write_addr;\n",
             i, write_to) < 0)
      goto error;
  }
  for (i = 0; i < inputs; ++i) {
    if (catf(&str, "        addr_%1$d_%2$s <= `read_addr(%1$d);\n", i, read_from) < 0)
      goto error;
  }
  return str;
error:
  free(str);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<create_half_a_memory_stage>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %edi,%edi
  je     L13
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    $0x0,%ebx
  lea    D16(%rip),%r13
  jmp    L27
L20:
  mov    %eax,%ebx
L27:
  mov    %rsp,%rdi
  mov    %r12,%rcx
  mov    %ebx,%edx
  mov    %r13,%rsi
  call   <catf@plt>
  test   %rax,%rax
  js     L55
  lea    0x1(%rbx),%eax
  cmp    %eax,%ebp
  jne    L20
  mov    $0x0,%ebp
  lea    D19(%rip),%r12
  jmp    L75
L22:
  mov    %eax,%ebp
L75:
  mov    %rsp,%rdi
  mov    %r14,%rcx
  mov    %ebp,%edx
  mov    %r12,%rsi
  call   <catf@plt>
  test   %rax,%rax
  js     L55
  lea    0x1(%rbp),%eax
  cmp    %ebp,%ebx
  jne    L22
L13:
  mov    (%rsp),%rax
  jmp    L6
L55:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D19
type_guessed: string

tool: D16:         in_%1$d_%2$s <= `in_data(%1$d);
        addr_%1$d_%2$s <= `write_addr;


tool: D19:         addr_%1$d_%2$s <= `read_addr(%1$d);


assistant: ```c
char *create_half_a_memory_stage(unsigned inputs, char *write_to, char *read_from) {
  char *str = NULL;
  unsigned i;
  for (i = 0; i < inputs; ++i) {
    if (catf(&str,
             "        in_%1$d_%2$s <= `in_data(%1$d);\n"
             "        addr_%1$d_%2$s <= `write_addr;\n",
             i, write_to) < 0)
      goto error;
  }
  for (i = 0; i < inputs; ++i) {
    if (catf(&str, "        addr_%1$d_%2$s <= `read_addr(%1$d);\n", i, read_from) < 0)
      goto error;
  }
  return str;
error:
  free(str);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<create_half_a_memory_stage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %edi,%edi
  je     L83
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%r15
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  lea    D16(%rip),%r14
  jmp    L15
  nopl   (%rax)
L13:
  lea    0x1(%rbx),%eax
  cmp    %eax,%r12d
  je     L94
  mov    %eax,%ebx
L15:
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <catf@plt>
  test   %rax,%rax
  jns    L13
L0:
  mov    (%rsp),%rdi
  call   <free@plt>
L83:
  xor    %eax,%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L94:
  xor    %r12d,%r12d
  lea    D18(%rip),%r13
  jmp    L26
  nopl   0x0(%rax)
L25:
  lea    0x1(%r12),%eax
  cmp    %r12d,%ebx
  je     L8
  mov    %eax,%r12d
L26:
  mov    %r15,%rcx
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <catf@plt>
  test   %rax,%rax
  jns    L25
  jmp    L0
  nopl   (%rax)
L8:
  mov    (%rsp),%rax
  jmp    L3
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string

tool: D16:         in_%1$d_%2$s <= `in_data(%1$d);
        addr_%1$d_%2$s <= `write_addr;


tool: D18:         addr_%1$d_%2$s <= `read_addr(%1$d);


assistant: ```c
char *create_half_a_memory_stage(unsigned inputs, char *write_to, char *read_from) {
  char *str = NULL;
  unsigned i;
  for (i = 0; i < inputs; ++i) {
    if (catf(&str,
             "        in_%1$d_%2$s <= `in_data(%1$d);\n"
             "        addr_%1$d_%2$s <= `write_addr;\n",
             i, write_to) < 0)
      goto error;
  }
  for (i = 0; i < inputs; ++i) {
    if (catf(&str, "        addr_%1$d_%2$s <= `read_addr(%1$d);\n", i, read_from) < 0)
      goto error;
  }
  return str;
error:
  free(str);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<create_half_a_memory_stage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %edi,%edi
  je     L40
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%r15
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  lea    D16(%rip),%r14
  jmp    L58
  nopl   (%rax)
L60:
  lea    0x1(%rbx),%eax
  cmp    %eax,%r12d
  je     L0
  mov    %eax,%ebx
L58:
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <catf@plt>
  test   %rax,%rax
  jns    L60
L50:
  mov    (%rsp),%rdi
  call   <free@plt>
L40:
  xor    %eax,%eax
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L0:
  xor    %r12d,%r12d
  lea    D3(%rip),%r13
  jmp    L75
  nopl   0x0(%rax)
L10:
  lea    0x1(%r12),%eax
  cmp    %r12d,%ebx
  je     L92
  mov    %eax,%r12d
L75:
  mov    %r15,%rcx
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <catf@plt>
  test   %rax,%rax
  jns    L10
  jmp    L50
  nopl   (%rax)
L92:
  mov    (%rsp),%rax
  jmp    L41
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D3
type: string

tool: D16:         in_%1$d_%2$s <= `in_data(%1$d);
        addr_%1$d_%2$s <= `write_addr;


tool: D3:         addr_%1$d_%2$s <= `read_addr(%1$d);


assistant: ```c
char *create_half_a_memory_stage(unsigned inputs, char *write_to, char *read_from) {
  char *str = NULL;
  unsigned i;
  for (i = 0; i < inputs; ++i) {
    if (catf(&str,
             "        in_%1$d_%2$s <= `in_data(%1$d);\n"
             "        addr_%1$d_%2$s <= `write_addr;\n",
             i, write_to) < 0)
      goto error;
  }
  for (i = 0; i < inputs; ++i) {
    if (catf(&str, "        addr_%1$d_%2$s <= `read_addr(%1$d);\n", i, read_from) < 0)
      goto error;
  }
  return str;
error:
  free(str);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <assessSpaceshipCapacity@plt>
  mov    $0x0,%eax
  call   <estimateWaitingVisitors@plt>
  mov    $0x0,%eax
  call   <processData@plt>
  mov    $0x0,%eax
  call   <generateReport@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  assessSpaceshipCapacity();
  estimateWaitingVisitors();
  processData();
  generateReport();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <assessSpaceshipCapacity@plt>
  mov    $0x0,%eax
  call   <estimateWaitingVisitors@plt>
  mov    $0x0,%eax
  call   <processData@plt>
  mov    $0x0,%eax
  call   <generateReport@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assessSpaceshipCapacity();
  estimateWaitingVisitors();
  processData();
  generateReport();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <assessSpaceshipCapacity@plt>
  xor    %eax,%eax
  call   <estimateWaitingVisitors@plt>
  xor    %eax,%eax
  call   <processData@plt>
  xor    %eax,%eax
  call   <generateReport@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assessSpaceshipCapacity();
  estimateWaitingVisitors();
  processData();
  generateReport();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <assessSpaceshipCapacity@plt>
  xor    %eax,%eax
  call   <estimateWaitingVisitors@plt>
  xor    %eax,%eax
  call   <processData@plt>
  xor    %eax,%eax
  call   <generateReport@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  assessSpaceshipCapacity();
  estimateWaitingVisitors();
  processData();
  generateReport();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<connect_retry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x20(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L55
L67:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L28
  mov    $0xffffffff,%eax
  jmp    L37
L28:
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x4(%rbp),%eax
  jmp    L37
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  cmpl   $0x40,-0x8(%rbp)
  jg     L65
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
L65:
  shll   -0x8(%rbp)
L55:
  cmpl   $0x80,-0x8(%rbp)
  jle    L67
  mov    $0xffffffff,%eax
L37:
  leave
  ret
```

assistant: ```c
int connect_retry(int domain, int type, int protocol, const struct sockaddr *addr, socklen_t alen) {
  int numsec, fd;
  for (numsec = 1; numsec <= 128; numsec <<= 1) {
    if ((fd = socket(domain, type, protocol)) < 0) {
      return -1;
    }
    if (connect(fd, addr, alen) == 0) {
      return fd;
    }
    close(fd);
    if (numsec <= 128 / 2) {
      sleep(numsec);
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<connect_retry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %rcx,%r15
  mov    %r8d,0xc(%rsp)
  mov    $0x1,%ebp
  jmp    L11
L68:
  add    %ebp,%ebp
  cmp    $0x80,%ebp
  jg     L56
L11:
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <socket@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L10
  mov    0xc(%rsp),%edx
  mov    %r15,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  test   %rax,%rax
  je     L14
  mov    %ebx,%edi
  call   <close@plt>
  cmp    $0x40,%ebp
  jg     L68
  mov    %ebp,%edi
  call   <sleep@plt>
  jmp    L68
L56:
  mov    $0xffffffff,%ebx
L14:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    $0xffffffff,%ebx
  jmp    L14
```

assistant: ```c
int connect_retry(int domain, int type, int protocol, const struct sockaddr *addr, socklen_t alen) {
  int numsec, fd;
  for (numsec = 1; numsec <= 128; numsec <<= 1) {
    if ((fd = socket(domain, type, protocol)) < 0) {
      return -1;
    }
    if (connect(fd, addr, alen) == 0) {
      return fd;
    }
    close(fd);
    if (numsec <= 128 / 2) {
      sleep(numsec);
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<connect_retry>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  nopl   (%rax)
L13:
  mov    %r13d,%edi
  mov    %ebx,%edx
  mov    %r12d,%esi
  call   <socket@plt>
  mov    %eax,%edi
  test   %eax,%eax
  js     L22
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %eax,0xc(%rsp)
  call   <connect@plt>
  mov    0xc(%rsp),%edi
  test   %rax,%rax
  je     L58
  call   <close@plt>
  lea    0x0(%rbp,%rbp,1),%edx
  cmp    $0x40,%ebp
  jle    L46
  cmp    $0x80,%edx
  jg     L22
  mov    %edx,%ebp
  jmp    L13
  nopl   (%rax)
L22:
  mov    $0xffffffff,%edi
L58:
  add    $0x18,%rsp
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    %ebp,%edi
  mov    %edx,0xc(%rsp)
  call   <sleep@plt>
  mov    0xc(%rsp),%edx
  mov    %edx,%ebp
  jmp    L13
```

assistant: ```c
int connect_retry(int domain, int type, int protocol, const struct sockaddr *addr, socklen_t alen) {
  int numsec, fd;
  for (numsec = 1; numsec <= 128; numsec <<= 1) {
    if ((fd = socket(domain, type, protocol)) < 0) {
      return -1;
    }
    if (connect(fd, addr, alen) == 0) {
      return fd;
    }
    close(fd);
    if (numsec <= 128 / 2) {
      sleep(numsec);
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<connect_retry>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  nopl   (%rax)
L31:
  mov    %r13d,%edi
  mov    %ebx,%edx
  mov    %r12d,%esi
  call   <socket@plt>
  mov    %eax,%edi
  test   %eax,%eax
  js     L49
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %eax,0xc(%rsp)
  call   <connect@plt>
  mov    0xc(%rsp),%edi
  test   %rax,%rax
  je     L47
  call   <close@plt>
  lea    0x0(%rbp,%rbp,1),%edx
  cmp    $0x40,%ebp
  jle    L30
  cmp    $0x80,%edx
  jg     L49
  mov    %edx,%ebp
  jmp    L31
  nopl   (%rax)
L49:
  mov    $0xffffffff,%edi
L47:
  add    $0x18,%rsp
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    %ebp,%edi
  mov    %edx,0xc(%rsp)
  call   <sleep@plt>
  mov    0xc(%rsp),%edx
  mov    %edx,%ebp
  jmp    L31
```

assistant: ```c
int connect_retry(int domain, int type, int protocol, const struct sockaddr *addr, socklen_t alen) {
  int numsec, fd;
  for (numsec = 1; numsec <= 128; numsec <<= 1) {
    if ((fd = socket(domain, type, protocol)) < 0) {
      return -1;
    }
    if (connect(fd, addr, alen) == 0) {
      return fd;
    }
    close(fd);
    if (numsec <= 128 / 2) {
      sleep(numsec);
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0xa,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x14,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
datatype: string
name: extract_symbolic_data
arguments: tag: D6
datatype: string
name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D27: address of p1 = %p, p2 = %p, p3 = %p


tool: D6: address pointed by p1 = %p, p2 = %p, p3 = %p


tool: D5: value at address pointed by p1 = %d, p2 = %d, p3 = %d


assistant: ```c
int main() {
  int *p1 = malloc(sizeof(int));
  int *p2 = malloc(sizeof(int));
  int *p3 = malloc(sizeof(int));
  *p1 = 10;
  *p2 = 20;
  *p3 = *p1 + *p2;
  printf("address of p1 = %p, p2 = %p, p3 = %p\n", &p1, &p2, &p3);
  printf("address pointed by p1 = %p, p2 = %p, p3 = %p\n", p1, p2, p3);
  printf("value at address pointed by p1 = %d, p2 = %d, p3 = %d\n", *p1, *p2, *p3);
  free(p1);
  free(p2);
  free(p3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  mov    (%rsp),%rax
  movl   $0xa,(%rax)
  mov    0x8(%rsp),%rax
  movl   $0x14,(%rax)
  mov    0x8(%rsp),%rax
  mov    (%rax),%eax
  mov    (%rsp),%rdx
  add    (%rdx),%eax
  mov    0x10(%rsp),%rdx
  mov    %eax,(%rdx)
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    (%rax),%ecx
  mov    0x8(%rsp),%rax
  mov    (%rax),%edx
  mov    (%rsp),%rax
  mov    (%rax),%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D7: address of p1 = %p, p2 = %p, p3 = %p


tool: D24: address pointed by p1 = %p, p2 = %p, p3 = %p


tool: D9: value at address pointed by p1 = %d, p2 = %d, p3 = %d


assistant: ```c
int main() {
  int *p1 = malloc(sizeof(int));
  int *p2 = malloc(sizeof(int));
  int *p3 = malloc(sizeof(int));
  *p1 = 10;
  *p2 = 20;
  *p3 = *p1 + *p2;
  printf("address of p1 = %p, p2 = %p, p3 = %p\n", &p1, &p2, &p3);
  printf("address pointed by p1 = %p, p2 = %p, p3 = %p\n", p1, p2, p3);
  printf("value at address pointed by p1 = %d, p2 = %d, p3 = %d\n", *p1, *p2, *p3);
  free(p1);
  free(p2);
  free(p3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    (%rsp),%rdx
  mov    %rsp,%rsi
  mov    0x8(%rsp),%rcx
  mov    %rax,0x10(%rsp)
  lea    D17(%rip),%rdi
  movl   $0xa,(%rdx)
  movl   $0x14,(%rcx)
  mov    (%rdx),%edx
  lea    0x10(%rsp),%rcx
  add    $0x14,%edx
  mov    %edx,(%rax)
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rcx
  mov    (%rsp),%rsi
  xor    %eax,%eax
  mov    0x8(%rsp),%rdx
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    D1(%rip),%rdi
  mov    (%rax),%ecx
  mov    0x8(%rsp),%rax
  mov    (%rax),%edx
  mov    (%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: string
name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D1
datatype: string

tool: D17: address of p1 = %p, p2 = %p, p3 = %p


tool: D6: address pointed by p1 = %p, p2 = %p, p3 = %p


tool: D1: value at address pointed by p1 = %d, p2 = %d, p3 = %d


assistant: ```c
int main() {
  int *p1 = malloc(sizeof(int));
  int *p2 = malloc(sizeof(int));
  int *p3 = malloc(sizeof(int));
  *p1 = 10;
  *p2 = 20;
  *p3 = *p1 + *p2;
  printf("address of p1 = %p, p2 = %p, p3 = %p\n", &p1, &p2, &p3);
  printf("address pointed by p1 = %p, p2 = %p, p3 = %p\n", p1, p2, p3);
  printf("value at address pointed by p1 = %d, p2 = %d, p3 = %d\n", *p1, *p2, *p3);
  free(p1);
  free(p2);
  free(p3);
  return 0;
}
```