ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L22:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L22
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D47
type_infered: string

tool: D2: %d

tool: D47: %d %d %d

assistant: ```c
int main() {
  int a, b, c, counter;
  int times;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &times);
  for (counter = 0; counter < times; counter++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L3
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rbp
L23:
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  call   <rotr@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jg     L23
L3:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D2
datatype: string

tool: D3: %d

tool: D2: %d %d %d

assistant: ```c
int main() {
  int a, b, c, counter;
  int times;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &times);
  for (counter = 0; counter < times; counter++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%r13
  mov    %r12,%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L20
  xor    %ebx,%ebx
  xchg   %ax,%ax
L9:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L9
L20:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D4(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D5: %d

tool: D4: %d %d %d

assistant: ```c
int main() {
  int a, b, c, counter;
  int times;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &times);
  for (counter = 0; counter < times; counter++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%r13
  mov    %r12,%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L3
  xor    %ebx,%ebx
  xchg   %ax,%ax
L20:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L20
L3:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D10(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D10
datatype: string

tool: D17: %d

tool: D10: %d %d %d

assistant: ```c
int main() {
  int a, b, c, counter;
  int times;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &times);
  for (counter = 0; counter < times; counter++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
L7:
  mov    $0x0,%eax
  call   <run@plt>
  jmp    L7
```

assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    run();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L0:
  mov    $0x0,%eax
  call   <run@plt>
  jmp    L0
```

assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    run();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <run@plt>
  jmp    L3
```

assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    run();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <run@plt>
  jmp    L3
```

assistant: ```c
int main(int argc, char *argv[]) {
  while (1) {
    run();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x98(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x94(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x94(%rbp),%edx
  mov    -0x98(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D59
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D68
datatype: string
name: unpack_data
arguments: data_tag: D24
datatype: string
name: unpack_data
arguments: data_tag: D2
datatype: string

tool: D59: Dame el valor de un entero: 

tool: D5: %d

tool: D19: Introduce ahora una frase: 

tool: D68: Y ahora dame el valor de otro entero:

tool: D24: Enteros Ledos: %d, %d. 


tool: D2: Frase leida: %s. 


assistant: ```c
int main(void) {
  int a, b;
  char frase[40 + 1];
  char linea[80 + 1];
  printf("Dame el valor de un entero: ");
  gets(linea);
  sscanf(linea, "%d", &a);
  printf("Introduce ahora una frase: ");
  gets(frase);
  printf("Y ahora dame el valor de otro entero:");
  gets(linea);
  sscanf(linea, "%d", &b);
  printf("Enteros Ledos: %d, %d. \n", a, b);
  printf("Frase leida: %s. \n", frase);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x40(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    0x8(%rsp),%rdx
  lea    D36(%rip),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    0xc(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D36
data_type: string
name: unpack_data
arguments: data_tag: D31
data_type: string
name: unpack_data
arguments: data_tag: D54
data_type: string
name: unpack_data
arguments: data_tag: D50
data_type: string
name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D5: Dame el valor de un entero: 

tool: D36: %d

tool: D31: Introduce ahora una frase: 

tool: D54: Y ahora dame el valor de otro entero:

tool: D50: Enteros Ledos: %d, %d. 


tool: D6: Frase leida: %s. 


assistant: ```c
int main(void) {
  int a, b;
  char frase[40 + 1];
  char linea[80 + 1];
  printf("Dame el valor de un entero: ");
  gets(linea);
  sscanf(linea, "%d", &a);
  printf("Introduce ahora una frase: ");
  gets(frase);
  printf("Y ahora dame el valor de otro entero:");
  gets(linea);
  sscanf(linea, "%d", &b);
  printf("Enteros Ledos: %d, %d. \n", a, b);
  printf("Frase leida: %s. \n", frase);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D40(%rip),%rdi
  lea    D35(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbp
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    0x8(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    0xc(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rsi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D40
type_infered: string
name: retrieve_data
arguments: label: D35
type_infered: string
name: retrieve_data
arguments: label: D44
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string
name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D31
type_infered: string

tool: D40: Dame el valor de un entero: 

tool: D35: %d

tool: D44: Introduce ahora una frase: 

tool: D6: Y ahora dame el valor de otro entero:

tool: D2: Enteros Ledos: %d, %d. 


tool: D31: Frase leida: %s. 


assistant: ```c
int main(void) {
  int a, b;
  char frase[40 + 1];
  char linea[80 + 1];
  printf("Dame el valor de un entero: ");
  gets(linea);
  sscanf(linea, "%d", &a);
  printf("Introduce ahora una frase: ");
  gets(frase);
  printf("Y ahora dame el valor de otro entero:");
  gets(linea);
  sscanf(linea, "%d", &b);
  printf("Enteros Ledos: %d, %d. \n", a, b);
  printf("Frase leida: %s. \n", frase);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D26(%rip),%rdi
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbp
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    0x8(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    0xc(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rsi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D11
data_type: string
name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D43
data_type: string
name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D54
data_type: string

tool: D26: Dame el valor de un entero: 

tool: D11: %d

tool: D23: Introduce ahora una frase: 

tool: D43: Y ahora dame el valor de otro entero:

tool: D6: Enteros Ledos: %d, %d. 


tool: D54: Frase leida: %s. 


assistant: ```c
int main(void) {
  int a, b;
  char frase[40 + 1];
  char linea[80 + 1];
  printf("Dame el valor de un entero: ");
  gets(linea);
  sscanf(linea, "%d", &a);
  printf("Introduce ahora una frase: ");
  gets(frase);
  printf("Y ahora dame el valor de otro entero:");
  gets(linea);
  sscanf(linea, "%d", &b);
  printf("Enteros Ledos: %d, %d. \n", a, b);
  printf("Frase leida: %s. \n", frase);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fts3PrefixCompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <UNUSED_PARAMETER@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L27:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L19
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L27
L19:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fts3PrefixCompress(const char *zPrev, int nPrev, const char *zNext, int nNext) {
  int n;
  UNUSED_PARAMETER(nNext);
  for (n = 0; n < nPrev && zPrev[n] == zNext[n]; n++)
    ;
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fts3PrefixCompress>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %ecx,%edi
  call   <UNUSED_PARAMETER@plt>
  test   %ebx,%ebx
  jle    L12
  mov    %ebx,%esi
  mov    $0x0,%eax
L30:
  mov    %eax,%edx
  movzbl (%r12,%rax,1),%ebx
  cmp    %bl,0x0(%rbp,%rax,1)
  jne    L27
  lea    0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L30
L27:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0x0,%edx
  jmp    L27
```

assistant: ```c
int fts3PrefixCompress(const char *zPrev, int nPrev, const char *zNext, int nNext) {
  int n;
  UNUSED_PARAMETER(nNext);
  for (n = 0; n < nPrev && zPrev[n] == zNext[n]; n++)
    ;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fts3PrefixCompress>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %ecx,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <UNUSED_PARAMETER@plt>
  test   %ebx,%ebx
  jle    L23
  movslq %ebx,%rsi
  xor    %eax,%eax
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L15:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L13
L48:
  movzbl (%r12,%rax,1),%ebx
  mov    %eax,%r8d
  cmp    %bl,0x0(%rbp,%rax,1)
  je     L15
L13:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L23:
  xor    %r8d,%r8d
  jmp    L13
```

assistant: ```c
int fts3PrefixCompress(const char *zPrev, int nPrev, const char *zNext, int nNext) {
  int n;
  UNUSED_PARAMETER(nNext);
  for (n = 0; n < nPrev && zPrev[n] == zNext[n]; n++)
    ;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fts3PrefixCompress>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %ecx,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <UNUSED_PARAMETER@plt>
  test   %ebx,%ebx
  jle    L35
  movslq %ebx,%rsi
  xor    %eax,%eax
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L27:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L10
L19:
  movzbl (%r12,%rax,1),%ebx
  mov    %eax,%r8d
  cmp    %bl,0x0(%rbp,%rax,1)
  je     L27
L10:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L35:
  xor    %r8d,%r8d
  jmp    L10
```

assistant: ```c
int fts3PrefixCompress(const char *zPrev, int nPrev, const char *zNext, int nNext) {
  int n;
  UNUSED_PARAMETER(nNext);
  for (n = 0; n < nPrev && zPrev[n] == zNext[n]; n++)
    ;
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<displayLinuxIoStats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%ecx
  lea    D46(%rip),%rdx
  mov    %rax,%rsi
  mov    $0xc8,%edi
  call   <sqlite3_snprintf@plt>
  lea    -0xd0(%rbp),%rax
  lea    D42(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0xd8(%rbp)
  cmpq   $0x0,-0xd8(%rbp)
  je     L39
  jmp    L20
L46:
  movl   $0x0,-0xe0(%rbp)
  jmp    L1
L87:
  mov    -0xe0(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xdc(%rbp)
  mov    -0xe0(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    -0xdc(%rbp),%edx
  lea    -0xd0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L54
  lea    -0xd0(%rbp),%rdx
  mov    -0xdc(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0xe0(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%rdx
  mov    -0xe8(%rbp),%rax
  lea    D36(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L20
L54:
  addl   $0x1,-0xe0(%rbp)
L1:
  mov    -0xe0(%rbp),%eax
  cmp    $0x6,%eax
  jbe    L87
L20:
  mov    -0xd8(%rbp),%rdx
  lea    -0xd0(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L46
  mov    -0xd8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  jmp    L22
L39:
  nop
L22:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L81
  call   <__stack_chk_fail@plt>
L81:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D46
type_infered: string
name: parse_data
arguments: data_tag: D42
type_infered: string
name: parse_data
arguments: data_tag: D36
type_infered: string

tool: D46: /proc/%d/io

tool: D42: rb

tool: D36: -- %-28s %s

assistant: ```c
void displayLinuxIoStats(FILE *out) {
  FILE *in;
  char z[200];
  sqlite3_snprintf(sizeof(z), z, "/proc/%d/io", getpid());
  in = fopen(z, "rb");
  if (in == 0)
    return;
  while (fgets(z, sizeof(z), in) != 0) {
    static const struct {
      const char *zPattern;
      const char *zDesc;
    } aTrans[] = {
        {"rchar: ", "Bytes received by read():"}, {"wchar: ", "Bytes sent to write():"}, {"syscr: ", "Read() system calls:"}, {"syscw: ", "Write() system calls:"}, {"read_bytes: ", "Bytes rcvd from storage:"}, {"write_bytes: ", "Bytes sent to storage:"}, {"cancelled_write_bytes: ", "Cancelled write bytes:"},
    };
    int i;
    for (i = 0; i < sizeof(aTrans) / sizeof(aTrans[0]); i++) {
      int n = (int)strlen(aTrans[i].zPattern);
      if (strncmp(aTrans[i].zPattern, z, n) == 0) {
        fprintf(out, "-- %-28s %s", aTrans[i].zDesc, &z[n]);
        break;
      }
    }
  }
  fclose(in);
}
```