user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SelfWithRowColumnConvert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L52
L48:
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L22:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L17
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
L17:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x7c,(%rax)
  addl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L47:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L9:
  cmpl   $0x3,-0xc(%rbp)
  jle    L47
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  jmp    L14
L75:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L37:
  cmpl   $0x9,-0x10(%rbp)
  jle    L22
L14:
  addl   $0x1,-0x14(%rbp)
L52:
  cmpl   $0x3,-0x14(%rbp)
  jle    L48
  mov    -0x8(%rbp),%rax
  add    $0x27,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *SelfWithRowColumnConvert(char *buffer) {
  char *matrix = (char *)malloc((strlen(buffer) + 1) * 2 * sizeof(char));
  for (int row = 0; row < 4; row++) {
    for (int col = 0; col < 5 * 2; col++) {
      if ((buffer[row * 5 + col] == '\n') || (buffer[row * 5 + col] == '\0')) {
        matrix[row * 5 * 2 + col] = '|';
        col++;
        for (int i = 0; i < 5 - 1; i++, col++) {
          matrix[row * 5 * 2 + col] = buffer[i * 5 + row];
        }
        matrix[row * 5 * 2 + col] = '\n';
        break;
      }
      matrix[row * 5 * 2 + col] = buffer[row * 5 + col];
    }
  }
  matrix[4 * 5 * 2 - 1] = '\0';
  free(buffer);
  return matrix;
}
```