ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<tablenameid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D50(%rip),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,D11(%rip)
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rdx
  lea    D11(%rip),%rax
  lea    (%rax,%rdx,4),%r15
  movzbl (%rdi),%eax
  test   %al,%al
  je     L48
  mov    %rdi,%r14
  mov    %r15,%r12
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  jmp    L59
L5:
  mov    %ebp,%r13d
  mov    %al,(%r12)
L26:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl (%r14,%rax,1),%eax
  add    $0x1,%ebp
  add    $0x1,%r12
  test   %al,%al
  je     L6
L59:
  lea    -0x1(%rbp),%r13d
  cmp    $0x5f,%al
  jne    L5
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl (%r14,%rax,1),%edi
  test   %dil,%dil
  je     L6
  mov    %ebp,%r13d
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %al,(%r12)
  jmp    L26
L48:
  mov    $0x0,%r13d
L6:
  movslq %r13d,%r13
  movb   $0x0,(%r15,%r13,1)
  lea    D1(%rip),%rsi
  mov    %r15,%rdi
  call   <strcat@plt>
  movslq D11(%rip),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rdx
  lea    D11(%rip),%rax
  lea    (%rax,%rdx,4),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Id

assistant: ```c
const char *tablenameid(const char *tablename) {
  static char buf[4][100];
  static int s = 0;
  ++s, s %= 4;
  char *result = buf[s];
  int c = 0;
  for (int i = 0; tablename[i] != '\0'; ++i) {
    if (tablename[i] == '_') {
      if (tablename[++i] == '\0') {
        break;
      }
      result[c++] = (toupper((int)(tablename[i])));
    } else {
      result[c++] = tablename[i];
    }
  }
  result[c] = 0;
  strcat(result, "Id");
  return buf[s];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tablenameid>:
  endbr64
  push   %r15
  lea    D0(%rip),%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D37(%rip),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,D21(%rip)
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rsi,%rax,4),%r12
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  mov    %rdi,%r15
  mov    %r12,%rbp
  mov    $0x1,%r14d
  xor    %ebx,%ebx
  jmp    L5
  nopl   0x0(%rax)
L0:
  add    $0x1,%ebx
  mov    %al,0x0(%rbp)
  add    $0x1,%r14d
  add    $0x1,%rbp
  movslq %ebx,%rax
  movzbl (%r15,%rax,1),%eax
  test   %al,%al
  je     L22
L5:
  mov    %rbp,%rcx
  mov    %r14d,%r13d
  cmp    $0x5f,%al
  jne    L0
  add    $0x1,%ebx
  movslq %ebx,%rax
  movsbl (%r15,%rax,1),%edi
  test   %dil,%dil
  je     L17
  call   <toupper@plt>
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L22:
  movslq %r13d,%rdx
  lea    (%r12,%rdx,1),%rcx
L17:
  movb   $0x0,(%rcx)
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  movslq D21(%rip),%rax
  add    $0x8,%rsp
  lea    D0(%rip),%rsi
  pop    %rbx
  pop    %rbp
  lea    (%rax,%rax,4),%rax
  pop    %r12
  pop    %r13
  lea    (%rax,%rax,4),%rax
  pop    %r14
  pop    %r15
  lea    (%rsi,%rax,4),%rax
  ret
L16:
  mov    %r12,%rcx
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: label: D21
datatype: string

tool: D21: Id

assistant: ```c
const char *tablenameid(const char *tablename) {
  static char buf[4][100];
  static int s = 0;
  ++s, s %= 4;
  char *result = buf[s];
  int c = 0;
  for (int i = 0; tablename[i] != '\0'; ++i) {
    if (tablename[i] == '_') {
      if (tablename[++i] == '\0') {
        break;
      }
      result[c++] = (toupper((int)(tablename[i])));
    } else {
      result[c++] = tablename[i];
    }
  }
  result[c] = 0;
  strcat(result, "Id");
  return buf[s];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tablenameid>:
  endbr64
  push   %r15
  lea    D35(%rip),%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D52(%rip),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,D1(%rip)
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rsi,%rax,4),%r12
  movzbl (%rdi),%eax
  test   %al,%al
  je     L62
  mov    %rdi,%r15
  mov    %r12,%rbp
  mov    $0x1,%r14d
  xor    %ebx,%ebx
  jmp    L40
  nopl   0x0(%rax)
L43:
  add    $0x1,%ebx
  mov    %al,0x0(%rbp)
  add    $0x1,%r14d
  add    $0x1,%rbp
  movslq %ebx,%rax
  movzbl (%r15,%rax,1),%eax
  test   %al,%al
  je     L63
L40:
  mov    %rbp,%rcx
  mov    %r14d,%r13d
  cmp    $0x5f,%al
  jne    L43
  add    $0x1,%ebx
  movslq %ebx,%rax
  movsbl (%r15,%rax,1),%edi
  test   %dil,%dil
  je     L8
  call   <toupper@plt>
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L63:
  movslq %r13d,%rdx
  lea    (%r12,%rdx,1),%rcx
L8:
  movb   $0x0,(%rcx)
  lea    D1(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  movslq D1(%rip),%rax
  add    $0x8,%rsp
  lea    D35(%rip),%rsi
  pop    %rbx
  pop    %rbp
  lea    (%rax,%rax,4),%rax
  pop    %r12
  pop    %r13
  lea    (%rax,%rax,4),%rax
  pop    %r14
  pop    %r15
  lea    (%rsi,%rax,4),%rax
  ret
L62:
  mov    %r12,%rcx
  jmp    L8
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: Id

assistant: ```c
const char *tablenameid(const char *tablename) {
  static char buf[4][100];
  static int s = 0;
  ++s, s %= 4;
  char *result = buf[s];
  int c = 0;
  for (int i = 0; tablename[i] != '\0'; ++i) {
    if (tablename[i] == '_') {
      if (tablename[++i] == '\0') {
        break;
      }
      result[c++] = (toupper((int)(tablename[i])));
    } else {
      result[c++] = tablename[i];
    }
  }
  result[c] = 0;
  strcat(result, "Id");
  return buf[s];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <SCK@plt>
  mov    $0x1,%edi
  call   <CE@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init() {
  SCK(0);
  CE(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <SCK@plt>
  mov    $0x1,%edi
  call   <CE@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init() {
  SCK(0);
  CE(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <SCK@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <CE@plt>
```

assistant: ```c
void init() {
  SCK(0);
  CE(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <SCK@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <CE@plt>
```

assistant: ```c
void init() {
  SCK(0);
  CE(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tm_getisoweek>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rcx
  mov    %rdi,%rax
  sar    $0x20,%rax
  add    $0x6,%eax
  movslq %eax,%rbp
  imul   $0xffffffff92492493,%rbp,%rbp
  shr    $0x20,%rbp
  add    %eax,%ebp
  sar    $0x2,%ebp
  cltd
  sub    %edx,%ebp
  lea    0x0(,%rbp,8),%edx
  sub    %ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  mov    %edi,%esi
  sub    %eax,%esi
  lea    0xa(%rsi),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sar    $0x1f,%edx
  sub    %edx,%eax
  je     L39
  mov    %eax,%ebx
  cmp    $0x168,%esi
  jg     L7
L8:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  lea    0x76b(%rcx),%rdi
  call   <tm_isleapyear@plt>
  sub    %ebp,%eax
  lea    0x177(%rax,%r12,1),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  jmp    L8
L7:
  sub    $0x16d,%r12d
  lea    0x76c(%rcx),%r13
  mov    %r13,%rdi
  call   <tm_isleapyear@plt>
  mov    %eax,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  sub    %ebp,%eax
  cmp    $0xfffffffd,%eax
  jl     L8
  mov    %r13,%rdi
  call   <tm_isleapyear@plt>
  sub    %eax,%r12d
  sub    %ebp,%r12d
  add    $0xa,%r12d
  movslq %r12d,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %r12d,%eax
  sar    $0x2,%eax
  sar    $0x1f,%r12d
  sub    %r12d,%eax
  mov    %eax,%ebx
  jmp    L8
```

assistant: ```c
int tm_getisoweek(struct tm date) {
  int week = (date.tm_yday - (date.tm_wday + 6) % 7 + 10) / 7;
  if (week == 0)
    return (date.tm_yday + 365 + tm_isleapyear(date.tm_year + 1900 - 1) - (date.tm_wday + 6) % 7 + 10) / 7;
  else if (week > 52 && ((date.tm_yday - 365 - tm_isleapyear(date.tm_year + 1900) - (date.tm_wday + 6) % 7 + 10) / 7) > 0)
    return (date.tm_yday - 365 - tm_isleapyear(date.tm_year + 1900) - (date.tm_wday + 6) % 7 + 10) / 7;
  else
    return week;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tm_getisoweek>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rbp,%rax
  push   %rbx
  mov    %ebp,%ecx
  sar    $0x20,%rax
  add    $0x6,%eax
  movslq %eax,%rbx
  cltd
  sub    $0x8,%rsp
  imul   $0xffffffff92492493,%rbx,%rbx
  shr    $0x20,%rbx
  add    %eax,%ebx
  sar    $0x2,%ebx
  sub    %edx,%ebx
  lea    0x0(,%rbx,8),%edx
  sub    %ebx,%edx
  sub    %edx,%eax
  sub    %eax,%ecx
  mov    %eax,%ebx
  lea    0xa(%rcx),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x1f,%edx
  sar    $0x2,%eax
  sub    %edx,%eax
  je     L26
  mov    %eax,%r12d
  cmp    $0x168,%ecx
  jg     L13
L15:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  lea    0x76c(%rsi),%r13
  sub    $0x16d,%ebp
  mov    %r13,%rdi
  call   <tm_isleapyear@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  sub    %r8d,%eax
  sub    %ebx,%eax
  cmp    $0xfffffffd,%eax
  jl     L15
  mov    %r13,%rdi
  call   <tm_isleapyear@plt>
  add    $0x8,%rsp
  sub    %eax,%ebp
  sub    %ebx,%ebp
  pop    %rbx
  add    $0xa,%ebp
  movslq %ebp,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ebp,%eax
  sar    $0x1f,%ebp
  sar    $0x2,%eax
  sub    %ebp,%eax
  pop    %rbp
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  add    $0x76b,%rdi
  call   <tm_isleapyear@plt>
  add    $0x8,%rsp
  sub    %ebx,%eax
  pop    %rbx
  lea    0x177(%rax,%rbp,1),%edx
  pop    %rbp
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x1f,%edx
  sar    $0x2,%eax
  sub    %edx,%eax
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int tm_getisoweek(struct tm date) {
  int week = (date.tm_yday - (date.tm_wday + 6) % 7 + 10) / 7;
  if (week == 0)
    return (date.tm_yday + 365 + tm_isleapyear(date.tm_year + 1900 - 1) - (date.tm_wday + 6) % 7 + 10) / 7;
  else if (week > 52 && ((date.tm_yday - 365 - tm_isleapyear(date.tm_year + 1900) - (date.tm_wday + 6) % 7 + 10) / 7) > 0)
    return (date.tm_yday - 365 - tm_isleapyear(date.tm_year + 1900) - (date.tm_wday + 6) % 7 + 10) / 7;
  else
    return week;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tm_getisoweek>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rbp,%rax
  push   %rbx
  mov    %ebp,%ecx
  sar    $0x20,%rax
  add    $0x6,%eax
  movslq %eax,%rbx
  cltd
  sub    $0x8,%rsp
  imul   $0xffffffff92492493,%rbx,%rbx
  shr    $0x20,%rbx
  add    %eax,%ebx
  sar    $0x2,%ebx
  sub    %edx,%ebx
  lea    0x0(,%rbx,8),%edx
  sub    %ebx,%edx
  sub    %edx,%eax
  sub    %eax,%ecx
  mov    %eax,%ebx
  lea    0xa(%rcx),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x1f,%edx
  sar    $0x2,%eax
  sub    %edx,%eax
  je     L28
  mov    %eax,%r12d
  cmp    $0x168,%ecx
  jg     L17
L3:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  lea    0x76c(%rsi),%r13
  sub    $0x16d,%ebp
  mov    %r13,%rdi
  call   <tm_isleapyear@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  sub    %r8d,%eax
  sub    %ebx,%eax
  cmp    $0xfffffffd,%eax
  jl     L3
  mov    %r13,%rdi
  call   <tm_isleapyear@plt>
  add    $0x8,%rsp
  sub    %eax,%ebp
  sub    %ebx,%ebp
  pop    %rbx
  add    $0xa,%ebp
  movslq %ebp,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ebp,%eax
  sar    $0x1f,%ebp
  sar    $0x2,%eax
  sub    %ebp,%eax
  pop    %rbp
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L28:
  add    $0x76b,%rdi
  call   <tm_isleapyear@plt>
  add    $0x8,%rsp
  sub    %ebx,%eax
  pop    %rbx
  lea    0x177(%rax,%rbp,1),%edx
  pop    %rbp
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x1f,%edx
  sar    $0x2,%eax
  sub    %edx,%eax
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int tm_getisoweek(struct tm date) {
  int week = (date.tm_yday - (date.tm_wday + 6) % 7 + 10) / 7;
  if (week == 0)
    return (date.tm_yday + 365 + tm_isleapyear(date.tm_year + 1900 - 1) - (date.tm_wday + 6) % 7 + 10) / 7;
  else if (week > 52 && ((date.tm_yday - 365 - tm_isleapyear(date.tm_year + 1900) - (date.tm_wday + 6) % 7 + 10) / 7) > 0)
    return (date.tm_yday - 365 - tm_isleapyear(date.tm_year + 1900) - (date.tm_wday + 6) % 7 + 10) / 7;
  else
    return week;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crypto_box_curve25519xsalsa20poly1305_tweet_keypair>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <randombytes@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypto_scalarmult_curve25519_tweet_base@plt>
  leave
  ret
```

assistant: ```c
int crypto_box_curve25519xsalsa20poly1305_tweet_keypair(unsigned char *y, unsigned char *x) {
  randombytes(x, 32);
  return crypto_scalarmult_curve25519_tweet_base(y, x);
}
```
user: What is the c source code of the assembly code below:

```asm
<crypto_box_curve25519xsalsa20poly1305_tweet_keypair>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <randombytes@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <crypto_scalarmult_curve25519_tweet_base@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int crypto_box_curve25519xsalsa20poly1305_tweet_keypair(unsigned char *y, unsigned char *x) {
  randombytes(x, 32);
  return crypto_scalarmult_curve25519_tweet_base(y, x);
}
```
user: What is the c source code of the assembly code below?

```asm
<crypto_box_curve25519xsalsa20poly1305_tweet_keypair>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x20,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <randombytes@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <crypto_scalarmult_curve25519_tweet_base@plt>
```

assistant: ```c
int crypto_box_curve25519xsalsa20poly1305_tweet_keypair(unsigned char *y, unsigned char *x) {
  randombytes(x, 32);
  return crypto_scalarmult_curve25519_tweet_base(y, x);
}
```
user: What is the c source code of the assembly code below:

```asm
<crypto_box_curve25519xsalsa20poly1305_tweet_keypair>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x20,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <randombytes@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <crypto_scalarmult_curve25519_tweet_base@plt>
```

assistant: ```c
int crypto_box_curve25519xsalsa20poly1305_tweet_keypair(unsigned char *y, unsigned char *x) {
  randombytes(x, 32);
  return crypto_scalarmult_curve25519_tweet_base(y, x);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L15:
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L0:
  cmpl   $0x3e7,-0xc(%rbp)
  jle    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type: string
name: disassemble_data
arguments: label: D18
type: string

tool: D15: %d

tool: D18: N[%d] = %d


assistant: ```c
int main(void) {
  int i, n;
  scanf("%d", &n);
  for (i = 0; i < 1000; i++) {
    printf("N[%d] = %d\n", i, i % n);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L7:
  mov    %ebx,%eax
  cltd
  idivl  0x4(%rsp)
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  jne    L7
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string
name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D4: %d

tool: D8: N[%d] = %d


assistant: ```c
int main(void) {
  int i, n;
  scanf("%d", &n);
  for (i = 0; i < 1000; i++) {
    printf("N[%d] = %d\n", i, i % n);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %r12d,%eax
  mov    %r12d,%esi
  mov    %rbx,%rdi
  add    $0x1,%r12d
  cltd
  idivl  0x4(%rsp)
  call   <printf@plt>
  cmp    $0x3e8,%r12d
  jne    L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string

tool: D8: %d

tool: D0: N[%d] = %d


assistant: ```c
int main(void) {
  int i, n;
  scanf("%d", &n);
  for (i = 0; i < 1000; i++) {
    printf("N[%d] = %d\n", i, i % n);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %r12d,%eax
  mov    %r12d,%esi
  mov    %rbx,%rdi
  add    $0x1,%r12d
  cltd
  idivl  0x4(%rsp)
  call   <printf@plt>
  cmp    $0x3e8,%r12d
  jne    L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string

tool: D5: %d

tool: D11: N[%d] = %d


assistant: ```c
int main(void) {
  int i, n;
  scanf("%d", &n);
  for (i = 0; i < 1000; i++) {
    printf("N[%d] = %d\n", i, i % n);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<divide_array_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %ecx,-0x40(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L3
L1:
  mov    -0x18(%rbp),%eax
  imul   -0x40(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x40(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L34:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  divsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L34
  addl   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void divide_array_number(double *out, double *a, double f, int ncol, int nlns) {
  int i, j;
  double *ptr_a, *ptr_out;
  for (i = 0; i < ncol; i++) {
    ptr_out = (&(out[(i) * (nlns) + (0)]));
    ptr_a = (&(a[(i) * (nlns) + (0)]));
    for (j = 0; j < nlns; j++)
      ptr_out[j] = ptr_a[j] / f;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<divide_array_number>:
  endbr64
  test   %edx,%edx
  jle    L34
  push   %rbx
  mov    %rsi,%r8
  movslq %ecx,%r11
  lea    0x0(,%r11,8),%rbx
  lea    -0x1(%rcx),%eax
  lea    0x8(,%rax,8),%rsi
  mov    $0x0,%r10d
  mov    $0x0,%r9d
L27:
  test   %ecx,%ecx
  jle    L23
  lea    0x0(,%r10,8),%rax
L32:
  movsd  (%r8,%rax,1),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L32
L23:
  add    $0x1,%r9d
  add    %r11,%r10
  add    %rbx,%rsi
  cmp    %r9d,%edx
  jne    L27
  pop    %rbx
  ret
L34:
  ret
```

assistant: ```c
void divide_array_number(double *out, double *a, double f, int ncol, int nlns) {
  int i, j;
  double *ptr_a, *ptr_out;
  for (i = 0; i < ncol; i++) {
    ptr_out = (&(out[(i) * (nlns) + (0)]));
    ptr_a = (&(a[(i) * (nlns) + (0)]));
    for (j = 0; j < nlns; j++)
      ptr_out[j] = ptr_a[j] / f;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<divide_array_number>:
  endbr64
  test   %edx,%edx
  jle    L14
  movslq %ecx,%r11
  lea    -0x1(%rcx),%eax
  push   %rbx
  mov    %rsi,%r8
  lea    0x0(,%r11,8),%rbx
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  lea    0x8(,%rax,8),%rsi
  nopl   0x0(%rax,%rax,1)
L20:
  test   %ecx,%ecx
  jle    L8
  lea    0x0(,%r10,8),%rax
  nopl   0x0(%rax)
L12:
  movsd  (%r8,%rax,1),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L12
L8:
  add    $0x1,%r9d
  add    %r11,%r10
  add    %rbx,%rsi
  cmp    %r9d,%edx
  jne    L20
  pop    %rbx
  ret
L14:
  ret
```

assistant: ```c
void divide_array_number(double *out, double *a, double f, int ncol, int nlns) {
  int i, j;
  double *ptr_a, *ptr_out;
  for (i = 0; i < ncol; i++) {
    ptr_out = (&(out[(i) * (nlns) + (0)]));
    ptr_a = (&(a[(i) * (nlns) + (0)]));
    for (j = 0; j < nlns; j++)
      ptr_out[j] = ptr_a[j] / f;
  }
}
```