ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L17
L69:
  mov    -0x74(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x1,-0x74(%rbp)
  jle    L19
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L19
  mov    -0x74(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  jne    L19
  mov    -0x74(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x7c(%rbp)
L58:
  mov    -0x7c(%rbp),%eax
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  je     L53
  mov    -0x7c(%rbp),%eax
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x9,%al
  jne    L19
L53:
  mov    -0x7c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x7c(%rbp),%eax
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x7c(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x7c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %ecx,%eax
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %edx,%edx
  mov    %al,-0x70(%rbp,%rdx,1)
  subl   $0x1,-0x7c(%rbp)
  jmp    L58
L19:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L17:
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <my_getline@plt>
  mov    %eax,-0x74(%rbp)
  cmpl   $0x0,-0x74(%rbp)
  jne    L69
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string
name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D1: len : %d


tool: D6: After line : %s strlen(line): %d


assistant: ```c
int main() {
  char line[100] = {0};
  int max = 0, len;
  unsigned int tmp;
  while (len = my_getline(line, 100)) {
    printf("len : %d\n", len);
    if (len > 1) {
      if ((line[len] == '\0') && (line[len - 1] == '\n')) {
        tmp = len - 2;
        while (tmp >= 0) {
          if (line[tmp] == ' ' || line[tmp] == '\t') {
            line[tmp] = line[tmp + 1];
            line[tmp + 1] = line[tmp + 2];
          } else
            break;
          tmp--;
        }
      }
    }
    printf("After line : %s strlen(line): %d\n", line, strlen(line));
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rbp
  lea    D7(%rip),%r13
  lea    D14(%rip),%r12
  jmp    L51
L69:
  lea    0x1(%rbx),%eax
  movzbl (%rsp,%rax,1),%ecx
  mov    %ebx,%edx
  mov    %cl,(%rsp,%rdx,1)
  lea    0x2(%rbx),%edx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,(%rsp,%rax,1)
  sub    $0x1,%ebx
  mov    %ebx,%eax
  movzbl (%rsp,%rax,1),%eax
  cmp    $0x20,%al
  je     L69
  cmp    $0x9,%al
  je     L69
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L51:
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <my_getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L13
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x1,%ebx
  jle    L8
  movslq %ebx,%rax
  cmpb   $0x0,(%rsp,%rax,1)
  jne    L8
  lea    -0x1(%rbx),%eax
  cltq
  cmpb   $0xa,(%rsp,%rax,1)
  jne    L8
  sub    $0x2,%ebx
  mov    %ebx,%eax
  movzbl (%rsp,%rax,1),%eax
  cmp    $0x20,%al
  je     L69
  cmp    $0x9,%al
  je     L69
  jmp    L8
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L100
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L100:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string

tool: D7: len : %d


tool: D14: After line : %s strlen(line): %d


assistant: ```c
int main() {
  char line[100] = {0};
  int max = 0, len;
  unsigned int tmp;
  while (len = my_getline(line, 100)) {
    printf("len : %d\n", len);
    if (len > 1) {
      if ((line[len] == '\0') && (line[len - 1] == '\n')) {
        tmp = len - 2;
        while (tmp >= 0) {
          if (line[tmp] == ' ' || line[tmp] == '\t') {
            line[tmp] = line[tmp + 1];
            line[tmp + 1] = line[tmp + 2];
          } else
            break;
          tmp--;
        }
      }
    }
    printf("After line : %s strlen(line): %d\n", line, strlen(line));
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  lea    D8(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L50:
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jle    L46
  movslq %ebx,%rax
  cmpb   $0x0,(%rsp,%rax,1)
  jne    L46
  lea    -0x1(%rbx),%eax
  cltq
  cmpb   $0xa,(%rsp,%rax,1)
  je     L10
L46:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
L37:
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <my_getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L50
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  lea    -0x2(%rbx),%eax
  movzbl (%rsp,%rax,1),%edx
  mov    %rax,%rbx
  cmp    $0x20,%dl
  jne    L44
  nopl   (%rax)
L98:
  lea    0x1(%rbx),%edx
  movzbl (%rsp,%rdx,1),%ecx
  mov    %cl,(%rsp,%rax,1)
  lea    0x2(%rbx),%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,(%rsp,%rdx,1)
  lea    -0x1(%rbx),%eax
  movzbl (%rsp,%rax,1),%edx
  mov    %rax,%rbx
  cmp    $0x20,%dl
  je     L98
L44:
  cmp    $0x9,%dl
  je     L98
  jmp    L46
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D8: len : %d


tool: D13: After line : %s strlen(line): %d


assistant: ```c
int main() {
  char line[100] = {0};
  int max = 0, len;
  unsigned int tmp;
  while (len = my_getline(line, 100)) {
    printf("len : %d\n", len);
    if (len > 1) {
      if ((line[len] == '\0') && (line[len - 1] == '\n')) {
        tmp = len - 2;
        while (tmp >= 0) {
          if (line[tmp] == ' ' || line[tmp] == '\t') {
            line[tmp] = line[tmp + 1];
            line[tmp + 1] = line[tmp + 2];
          } else
            break;
          tmp--;
        }
      }
    }
    printf("After line : %s strlen(line): %d\n", line, strlen(line));
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  lea    D14(%rip),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L67:
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jle    L30
  movslq %ebx,%rax
  cmpb   $0x0,(%rsp,%rax,1)
  jne    L30
  lea    -0x1(%rbx),%eax
  cltq
  cmpb   $0xa,(%rsp,%rax,1)
  je     L7
L30:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
L36:
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <my_getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L67
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  lea    -0x2(%rbx),%eax
  movzbl (%rsp,%rax,1),%edx
  mov    %rax,%rbx
  cmp    $0x20,%dl
  jne    L91
  nopl   (%rax)
L4:
  lea    0x1(%rbx),%edx
  movzbl (%rsp,%rdx,1),%ecx
  mov    %cl,(%rsp,%rax,1)
  lea    0x2(%rbx),%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,(%rsp,%rdx,1)
  lea    -0x1(%rbx),%eax
  movzbl (%rsp,%rax,1),%edx
  mov    %rax,%rbx
  cmp    $0x20,%dl
  je     L4
L91:
  cmp    $0x9,%dl
  je     L4
  jmp    L30
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
data_type: string
name: read_data
arguments: data_tag: D7
data_type: string

tool: D14: len : %d


tool: D7: After line : %s strlen(line): %d


assistant: ```c
int main() {
  char line[100] = {0};
  int max = 0, len;
  unsigned int tmp;
  while (len = my_getline(line, 100)) {
    printf("len : %d\n", len);
    if (len > 1) {
      if ((line[len] == '\0') && (line[len - 1] == '\n')) {
        tmp = len - 2;
        while (tmp >= 0) {
          if (line[tmp] == ' ' || line[tmp] == '\t') {
            line[tmp] = line[tmp + 1];
            line[tmp + 1] = line[tmp + 2];
          } else
            break;
          tmp--;
        }
      }
    }
    printf("After line : %s strlen(line): %d\n", line, strlen(line));
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<myrand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rcx
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xf,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rcx
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xf,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  imul   $0x1f31d,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  imul   $0x41a7,%rax,%rdx
  mov    -0x18(%rbp),%rax
  imul   $0xfffffffffffff4ec,%rax,%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jle    L7
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L6
L7:
  mov    -0x8(%rbp),%rax
  lea    0x7fffffff(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L6:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: byte[8]

tool: {"D4": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

assistant: ```c
double myrand(long *rand_seed) {
  long lo;
  long hi;
  long test;
  hi = *rand_seed / 127773L;
  lo = *rand_seed % 127773L;
  test = 16807L * lo - 2836L * hi;
  if (test > 0) {
    *rand_seed = test;
  } else {
    *rand_seed = test + 2147483647L;
  }
  return ((double)*rand_seed / 2147483647L);
}
```
user: Translate the below assembly code into C programming language:

```asm
<myrand>:
  endbr64
  mov    (%rdi),%rcx
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0xf,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x1f31d,%rdx,%rax
  sub    %rax,%rcx
  imul   $0x41a7,%rcx,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  mov    %rax,(%rdi)
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type: byte[8]

tool: {"D7": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

assistant: ```c
double myrand(long *rand_seed) {
  long lo;
  long hi;
  long test;
  hi = *rand_seed / 127773L;
  lo = *rand_seed % 127773L;
  test = 16807L * lo - 2836L * hi;
  if (test > 0) {
    *rand_seed = test;
  } else {
    *rand_seed = test + 2147483647L;
  }
  return ((double)*rand_seed / 2147483647L);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<myrand>:
  endbr64
  mov    (%rdi),%rcx
  pxor   %xmm0,%xmm0
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0xf,%rdx
  sub    %rax,%rdx
  imul   $0x1f31d,%rdx,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  sub    %rax,%rcx
  imul   $0x41a7,%rcx,%rax
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  cvtsi2sd %rax,%xmm0
  mov    %rax,(%rdi)
  divsd  D3(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: byte[8]

tool: {"D3": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

assistant: ```c
double myrand(long *rand_seed) {
  long lo;
  long hi;
  long test;
  hi = *rand_seed / 127773L;
  lo = *rand_seed % 127773L;
  test = 16807L * lo - 2836L * hi;
  if (test > 0) {
    *rand_seed = test;
  } else {
    *rand_seed = test + 2147483647L;
  }
  return ((double)*rand_seed / 2147483647L);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<myrand>:
  endbr64
  mov    (%rdi),%rcx
  pxor   %xmm0,%xmm0
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0xf,%rdx
  sub    %rax,%rdx
  imul   $0x1f31d,%rdx,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  sub    %rax,%rcx
  imul   $0x41a7,%rcx,%rax
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  cvtsi2sd %rax,%xmm0
  mov    %rax,(%rdi)
  divsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: byte[8]

tool: {"D4": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

assistant: ```c
double myrand(long *rand_seed) {
  long lo;
  long hi;
  long test;
  hi = *rand_seed / 127773L;
  lo = *rand_seed % 127773L;
  test = 16807L * lo - 2836L * hi;
  if (test > 0) {
    *rand_seed = test;
  } else {
    *rand_seed = test + 2147483647L;
  }
  return ((double)*rand_seed / 2147483647L);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%r12d
  mov    $0x0,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movw   $0x0,-0x22(%rbp)
  jmp    L10
L15:
  mov    -0x20(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%ebx
  sub    $0x2,%r12d
L10:
  cmp    $0x1,%r12d
  jg     L15
  cmp    $0x1,%r12d
  jne    L14
  lea    -0x22(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzwl -0x22(%rbp),%eax
  cwtl
  add    %eax,%ebx
L14:
  mov    %ebx,%edx
  sar    $0x10,%edx
  movzwl %bx,%eax
  lea    (%rdx,%rax,1),%ebx
  mov    %ebx,%eax
  sar    $0x10,%eax
  add    %eax,%ebx
  mov    %ebx,%eax
  not    %eax
  mov    %ax,-0x22(%rbp)
  movzwl -0x22(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned short check_sum(unsigned short *addr, int len) {
  register int nleft = len;
  register int sum = 0;
  unsigned short *w = addr;
  short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_sum>:
  endbr64
  mov    $0x0,%r9d
  cmp    $0x1,%esi
  jle    L11
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L38:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L38
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L7:
  cmp    $0x1,%esi
  je     L6
L45:
  mov    %eax,%edx
  sar    $0x10,%edx
  movzwl %ax,%eax
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
L11:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L7
L6:
  mov    (%rcx),%r9b
  movswl %r9w,%r9d
  add    %r9d,%eax
  jmp    L45
```

assistant: ```c
unsigned short check_sum(unsigned short *addr, int len) {
  register int nleft = len;
  register int sum = 0;
  unsigned short *w = addr;
  short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_sum>:
  endbr64
  xor    %r9d,%r9d
  cmp    $0x1,%esi
  jle    L20
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nop
L8:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L8
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L39:
  cmp    $0x1,%esi
  jne    L24
  mov    (%rcx),%r9b
  movswl %r9w,%r9d
  add    %r9d,%eax
L24:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L39
```

assistant: ```c
unsigned short check_sum(unsigned short *addr, int len) {
  register int nleft = len;
  register int sum = 0;
  unsigned short *w = addr;
  short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_sum>:
  endbr64
  mov    %rdi,%rdx
  xor    %r10d,%r10d
  cmp    $0x1,%esi
  jle    L32
  lea    -0x2(%rsi),%r9d
  mov    %r9d,%r11d
  shr    %r11d
  lea    0x1(%r11),%ecx
  cmp    $0xd,%r9d
  jbe    L43
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L10:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm3
  punpckhwd %xmm2,%xmm1
  punpcklwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L10
  movdqa %xmm0,%xmm1
  mov    %ecx,%r8d
  psrldq $0x8,%xmm1
  and    $0xfffffff8,%r8d
  paddd  %xmm1,%xmm0
  mov    %r8d,%edi
  movdqa %xmm0,%xmm1
  neg    %edi
  psrldq $0x4,%xmm1
  lea    (%rsi,%rdi,2),%esi
  mov    %r8d,%edi
  paddd  %xmm1,%xmm0
  lea    (%rdx,%rdi,2),%rdi
  movd   %xmm0,%eax
  cmp    %r8d,%ecx
  je     L125
L17:
  movzwl (%rdi),%r8d
  add    %r8d,%eax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L125
  movzwl 0x2(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L125
  movzwl 0x4(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L125
  movzwl 0x6(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L125
  movzwl 0x8(%rdi),%r8d
  add    %r8d,%eax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L125
  movzwl 0xa(%rdi),%r8d
  add    %r8d,%eax
  cmp    $0xd,%esi
  jle    L125
  movzwl 0xc(%rdi),%esi
  add    %esi,%eax
L125:
  mov    %ecx,%esi
  mov    %r11d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r9,%rcx,2),%esi
L19:
  cmp    $0x1,%esi
  jne    L76
  mov    (%rdx),%r10b
  movswl %r10w,%edx
  add    %edx,%eax
L76:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  jmp    L19
L43:
  xor    %eax,%eax
  jmp    L17
```

assistant: ```c
unsigned short check_sum(unsigned short *addr, int len) {
  register int nleft = len;
  register int sum = 0;
  unsigned short *w = addr;
  short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fw_del_allow_mac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %rsi,-0x220(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x220(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <do_iptables_cmd@plt>
  mov    -0x220(%rbp),%rcx
  mov    -0x218(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <do_iptables_cmd@plt>
  mov    -0x218(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  lea    D23(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <do_iptables_cmd@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D23
type_guessed: string

tool: D8: -t nat -D FW_ALLOW_MAC -m mac --mac-source %s -j ACCEPT

tool: D13: -t mangle -D FW_USER_OUT  -p all -s %s -m mac --mac-source %s -j MARK --set-mark 110

tool: D23: -t mangle -D FW_USER_IN  -d %s -j ACCEPT

assistant: ```c
void fw_del_allow_mac(char *ip, char *mac) {
  char cmd[512];
  sprintf(cmd,
          "-t nat -D "
          "FW_ALLOW_MAC"
          " -m mac --mac-source %s -j ACCEPT",
          mac);
  do_iptables_cmd(cmd);
  sprintf(cmd,
          "-t mangle -D "
          "FW_USER_OUT"
          "  -p all -s %s -m mac --mac-source %s -j MARK --set-mark 110",
          ip, mac);
  do_iptables_cmd(cmd);
  sprintf(cmd,
          "-t mangle -D "
          "FW_USER_IN"
          "  -d %s -j ACCEPT",
          ip);
  do_iptables_cmd(cmd);
}
```