ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ReadLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movb   $0x0,-0x1d(%rbp)
  movq   $0x0,-0x10(%rbp)
L94:
  lea    -0x1e(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  je     L92
  cmpl   $0x1,-0x14(%rbp)
  jg     L70
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L138
  cmpl   $0x0,-0x14(%rbp)
  je     L79
  jmp    L70
L138:
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L73
  movl   $0xffffffff,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L73
L79:
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L70
L92:
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1e(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L113
  movl   $0x1,-0x1c(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
L113:
  movzbl -0x1e(%rbp),%eax
  cmp    $0xa,%al
  jne    L49
  cmpb   $0xd,-0x1d(%rbp)
  jne    L49
  movl   $0x1,-0x1c(%rbp)
L49:
  movzbl -0x1e(%rbp),%eax
  mov    %al,-0x1d(%rbp)
  jmp    L70
L73:
  nop
L70:
  cmpl   $0x0,-0x1c(%rbp)
  je     L94
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L114
  call   <__stack_chk_fail@plt>
L114:
  leave
  ret
```

assistant: ```c
int ReadLine(const int sock, char *const buffer, const size_t buflen, size_t *const bytesRead) {
  int done = 0, retval = 0;
  char c, lastC = 0;
  size_t bytesSoFar = 0;
  ssize_t readResult;
  do {
    readResult = recv(sock, &c, 1, 0);
    switch (readResult) {
    case -1:
      if (errno != EINTR) {
        retval = -1;
        done = 1;
      }
      break;
    case 0:
      retval = 0;
      done = 1;
      break;
    case 1:
      buffer[bytesSoFar] = c;
      bytesSoFar += readResult;
      if (bytesSoFar >= buflen) {
        done = 1;
        retval = -1;
      }
      if ((c == '\n') && (lastC == '\r'))
        done = 1;
      lastC = c;
      break;
    }
  } while (!done);
  buffer[bytesSoFar] = 0;
  *bytesRead = bytesSoFar;
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ReadLine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  lea    0x17(%rsp),%r12
L12:
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  test   %eax,%eax
  je     L114
  cmp    $0x1,%eax
  je     L86
  cmp    $0xffffffff,%eax
  jne    L12
  mov    D12(%rip),%rcx
  mov    D7(%rip),%rdx
  mov    (%rdx),%esi
  cmp    %esi,(%rcx)
  je     L12
  jmp    L114
L86:
  movzbl 0x17(%rsp),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jae    L100
  cmp    $0xd,%r15b
  jne    L127
  cmp    $0xa,%al
  jne    L127
  mov    $0x0,%eax
  jmp    L114
L100:
  cmp    $0xd,%r15b
  jne    L15
  cmp    $0xa,%al
  jne    L15
  mov    $0xffffffff,%eax
L114:
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    0x8(%rsp),%rdi
  mov    %rbx,(%rdi)
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L101
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L114
L127:
  mov    %eax,%r15d
  jmp    L12
L101:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadLine(const int sock, char *const buffer, const size_t buflen, size_t *const bytesRead) {
  int done = 0, retval = 0;
  char c, lastC = 0;
  size_t bytesSoFar = 0;
  ssize_t readResult;
  do {
    readResult = recv(sock, &c, 1, 0);
    switch (readResult) {
    case -1:
      if (errno != EINTR) {
        retval = -1;
        done = 1;
      }
      break;
    case 0:
      retval = 0;
      done = 1;
      break;
    case 1:
      buffer[bytesSoFar] = c;
      bytesSoFar += readResult;
      if (bytesSoFar >= buflen) {
        done = 1;
        retval = -1;
      }
      if ((c == '\n') && (lastC == '\r'))
        done = 1;
      lastC = c;
      break;
    }
  } while (!done);
  buffer[bytesSoFar] = 0;
  *bytesRead = bytesSoFar;
  return retval;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ReadLine>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  lea    0x17(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L101:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  test   %eax,%eax
  je     L36
  cmp    $0x1,%eax
  je     L15
  cmp    $0xffffffff,%eax
  jne    L101
  mov    D7(%rip),%rdx
  mov    D9(%rip),%rcx
  mov    (%rdx),%esi
  cmp    %esi,(%rcx)
  je     L101
L36:
  mov    0x8(%rsp),%rdi
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    %rbx,(%rdi)
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  movzbl 0x17(%rsp),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jb     L86
  mov    $0xffffffff,%eax
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L86:
  cmp    $0xa,%al
  je     L37
  mov    %eax,%r15d
  jmp    L101
L7:
  call   <__stack_chk_fail@plt>
L37:
  cmp    $0xd,%r15b
  je     L13
  mov    $0xa,%r15d
  jmp    L101
L13:
  xor    %eax,%eax
  jmp    L36
```

assistant: ```c
int ReadLine(const int sock, char *const buffer, const size_t buflen, size_t *const bytesRead) {
  int done = 0, retval = 0;
  char c, lastC = 0;
  size_t bytesSoFar = 0;
  ssize_t readResult;
  do {
    readResult = recv(sock, &c, 1, 0);
    switch (readResult) {
    case -1:
      if (errno != EINTR) {
        retval = -1;
        done = 1;
      }
      break;
    case 0:
      retval = 0;
      done = 1;
      break;
    case 1:
      buffer[bytesSoFar] = c;
      bytesSoFar += readResult;
      if (bytesSoFar >= buflen) {
        done = 1;
        retval = -1;
      }
      if ((c == '\n') && (lastC == '\r'))
        done = 1;
      lastC = c;
      break;
    }
  } while (!done);
  buffer[bytesSoFar] = 0;
  *bytesRead = bytesSoFar;
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ReadLine>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  lea    0x17(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L62:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  test   %eax,%eax
  je     L118
  cmp    $0x1,%eax
  je     L107
  cmp    $0xffffffff,%eax
  jne    L62
  mov    D16(%rip),%rdx
  mov    D0(%rip),%rcx
  mov    (%rdx),%esi
  cmp    %esi,(%rcx)
  je     L62
L118:
  mov    0x8(%rsp),%rdi
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    %rbx,(%rdi)
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L107:
  movzbl 0x17(%rsp),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jb     L32
  mov    $0xffffffff,%eax
  jmp    L118
  nopw   0x0(%rax,%rax,1)
L32:
  cmp    $0xa,%al
  je     L81
  mov    %eax,%r15d
  jmp    L62
L49:
  call   <__stack_chk_fail@plt>
L81:
  cmp    $0xd,%r15b
  je     L76
  mov    $0xa,%r15d
  jmp    L62
L76:
  xor    %eax,%eax
  jmp    L118
```

assistant: ```c
int ReadLine(const int sock, char *const buffer, const size_t buflen, size_t *const bytesRead) {
  int done = 0, retval = 0;
  char c, lastC = 0;
  size_t bytesSoFar = 0;
  ssize_t readResult;
  do {
    readResult = recv(sock, &c, 1, 0);
    switch (readResult) {
    case -1:
      if (errno != EINTR) {
        retval = -1;
        done = 1;
      }
      break;
    case 0:
      retval = 0;
      done = 1;
      break;
    case 1:
      buffer[bytesSoFar] = c;
      bytesSoFar += readResult;
      if (bytesSoFar >= buflen) {
        done = 1;
        retval = -1;
      }
      if ((c == '\n') && (lastC == '\r'))
        done = 1;
      lastC = c;
      break;
    }
  } while (!done);
  buffer[bytesSoFar] = 0;
  *bytesRead = bytesSoFar;
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<testshort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x4(%rbp)
  mov    %ax,-0x8(%rbp)
  movzwl -0x4(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzwl -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzwl -0x4(%rbp),%edx
  movzwl -0x8(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D16: %d


tool: D11: %u


assistant: ```c
short testshort(short a, unsigned short b) {
  printf("%d\n", a);
  printf("%u\n", b);
  return a + b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testshort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  movzwl %di,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  movzwl %bx,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D18: %d


tool: D10: %u


assistant: ```c
short testshort(short a, unsigned short b) {
  printf("%d\n", a);
  printf("%u\n", b);
  return a + b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testshort>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  movzwl %di,%esi
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  movzwl %bx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D9: %d


tool: D1: %u


assistant: ```c
short testshort(short a, unsigned short b) {
  printf("%d\n", a);
  printf("%u\n", b);
  return a + b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testshort>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  movzwl %di,%esi
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  movzwl %bx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D7
type: string

tool: D6: %d


tool: D7: %u


assistant: ```c
short testshort(short a, unsigned short b) {
  printf("%d\n", a);
  printf("%u\n", b);
  return a + b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<threeSumClosest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x270f,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quick_sort@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L76:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L58
L63:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  sub    -0x30(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  cmp    %eax,%edx
  jge    L53
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L53:
  cmpl   $0x0,-0x4(%rbp)
  jle    L22
  subl   $0x1,-0xc(%rbp)
  jmp    L58
L22:
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  addl   $0x1,-0x10(%rbp)
  jmp    L58
L14:
  mov    -0x30(%rbp),%eax
  jmp    L40
L58:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L63
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x2c(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L76
  mov    -0x30(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
L40:
  leave
  ret
```

assistant: ```c
int threeSumClosest(int *nums, int numsSize, int target) {
  int tmp = 0;
  int closest = 9999;
  int left = 0;
  int right = 0;
  quick_sort(nums, 0, numsSize - 1);
  for (int i = 0; i < numsSize - 2; i++) {
    left = i + 1;
    right = numsSize - 1;
    while (left < right) {
      tmp = nums[i] + nums[left] + nums[right] - target;
      if (((tmp) > 0 ? (tmp) : -(tmp)) < ((closest) > 0 ? (closest) : -(closest))) {
        closest = tmp;
      }
      if (tmp > 0) {
        right--;
      } else if (tmp < 0) {
        left++;
      } else {
        return target;
      }
    }
  }
  return target + closest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<threeSumClosest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %edx,%ebp
  lea    -0x1(%rsi),%r12d
  mov    %r12d,%edx
  mov    $0x0,%esi
  call   <quick_sort@plt>
  cmp    $0x2,%r13d
  jle    L18
  lea    -0x3(%r13),%r11d
  add    $0x2,%r11
  mov    $0x1,%r10d
  mov    $0x270f,%edx
  jmp    L72
L52:
  sub    $0x1,%edi
L31:
  cmp    %r8d,%edi
  jle    L24
L63:
  movslq %r8d,%rax
  mov    %r9d,%esi
  add    (%rbx,%rax,4),%esi
  mov    %esi,%eax
  movslq %edi,%rcx
  add    (%rbx,%rcx,4),%eax
  sub    %ebp,%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    %edx,%ecx
  neg    %ecx
  cmovs  %edx,%ecx
  cmp    %ecx,%esi
  cmovl  %eax,%edx
  test   %eax,%eax
  jg     L52
  jns    L2
  add    $0x1,%r8d
  jmp    L31
L24:
  add    $0x1,%r10
  cmp    %r11,%r10
  je     L15
L72:
  mov    %r10d,%r8d
  cmp    %r10d,%r12d
  jle    L24
  mov    -0x4(%rbx,%r10,4),%r9d
  mov    %r12d,%edi
  jmp    L63
L18:
  mov    $0x270f,%edx
L15:
  add    %edx,%ebp
L2:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int threeSumClosest(int *nums, int numsSize, int target) {
  int tmp = 0;
  int closest = 9999;
  int left = 0;
  int right = 0;
  quick_sort(nums, 0, numsSize - 1);
  for (int i = 0; i < numsSize - 2; i++) {
    left = i + 1;
    right = numsSize - 1;
    while (left < right) {
      tmp = nums[i] + nums[left] + nums[right] - target;
      if (((tmp) > 0 ? (tmp) : -(tmp)) < ((closest) > 0 ? (closest) : -(closest))) {
        closest = tmp;
      }
      if (tmp > 0) {
        right--;
      } else if (tmp < 0) {
        left++;
      } else {
        return target;
      }
    }
  }
  return target + closest;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<threeSumClosest>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %ebp,%edx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <quick_sort@plt>
  cmp    $0x2,%r13d
  jle    L15
  lea    -0x3(%r13),%r11d
  mov    $0x1,%r10d
  mov    $0x270f,%edx
  add    $0x2,%r11
L29:
  mov    %r10d,%r8d
  cmp    %r10d,%ebp
  jle    L67
  mov    -0x4(%rbx,%r10,4),%r9d
  mov    %ebp,%edi
  jmp    L79
  nopl   (%rax)
L75:
  sub    $0x1,%edi
  cmp    %edi,%r8d
  jge    L67
L79:
  movslq %r8d,%rax
  movslq %edi,%rcx
  mov    (%rbx,%rax,4),%esi
  add    %r9d,%esi
  mov    %esi,%eax
  add    (%rbx,%rcx,4),%eax
  mov    %edx,%ecx
  sub    %r12d,%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  neg    %ecx
  cmovs  %edx,%ecx
  cmp    %ecx,%esi
  cmovl  %eax,%edx
  test   %eax,%eax
  jg     L75
  je     L36
  add    $0x1,%r8d
  cmp    %edi,%r8d
  jl     L79
L67:
  add    $0x1,%r10
  cmp    %r10,%r11
  jne    L29
L83:
  add    %edx,%r12d
L36:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0x270f,%edx
  jmp    L83
```

assistant: ```c
int threeSumClosest(int *nums, int numsSize, int target) {
  int tmp = 0;
  int closest = 9999;
  int left = 0;
  int right = 0;
  quick_sort(nums, 0, numsSize - 1);
  for (int i = 0; i < numsSize - 2; i++) {
    left = i + 1;
    right = numsSize - 1;
    while (left < right) {
      tmp = nums[i] + nums[left] + nums[right] - target;
      if (((tmp) > 0 ? (tmp) : -(tmp)) < ((closest) > 0 ? (closest) : -(closest))) {
        closest = tmp;
      }
      if (tmp > 0) {
        right--;
      } else if (tmp < 0) {
        left++;
      } else {
        return target;
      }
    }
  }
  return target + closest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<threeSumClosest>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %ebp,%edx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <quick_sort@plt>
  cmp    $0x2,%r13d
  jle    L72
  lea    -0x3(%r13),%r11d
  mov    $0x1,%r10d
  mov    $0x270f,%edx
  add    $0x2,%r11
L40:
  mov    %r10d,%r8d
  cmp    %r10d,%ebp
  jle    L70
  mov    -0x4(%rbx,%r10,4),%r9d
  mov    %ebp,%edi
  jmp    L80
  nopl   (%rax)
L16:
  sub    $0x1,%edi
  cmp    %edi,%r8d
  jge    L70
L80:
  movslq %r8d,%rax
  movslq %edi,%rcx
  mov    (%rbx,%rax,4),%esi
  add    %r9d,%esi
  mov    %esi,%eax
  add    (%rbx,%rcx,4),%eax
  mov    %edx,%ecx
  sub    %r12d,%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  neg    %ecx
  cmovs  %edx,%ecx
  cmp    %ecx,%esi
  cmovl  %eax,%edx
  test   %eax,%eax
  jg     L16
  je     L62
  add    $0x1,%r8d
  cmp    %edi,%r8d
  jl     L80
L70:
  add    $0x1,%r10
  cmp    %r10,%r11
  jne    L40
L83:
  add    %edx,%r12d
L62:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L72:
  mov    $0x270f,%edx
  jmp    L83
```

assistant: ```c
int threeSumClosest(int *nums, int numsSize, int target) {
  int tmp = 0;
  int closest = 9999;
  int left = 0;
  int right = 0;
  quick_sort(nums, 0, numsSize - 1);
  for (int i = 0; i < numsSize - 2; i++) {
    left = i + 1;
    right = numsSize - 1;
    while (left < right) {
      tmp = nums[i] + nums[left] + nums[right] - target;
      if (((tmp) > 0 ? (tmp) : -(tmp)) < ((closest) > 0 ? (closest) : -(closest))) {
        closest = tmp;
      }
      if (tmp > 0) {
        right--;
      } else if (tmp < 0) {
        left++;
      } else {
        return target;
      }
    }
  }
  return target + closest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decbig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L78
L68:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L78:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L68
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L62:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L54
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    $0x2710,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
L54:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L62
  jmp    L75
L10:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L75:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jle    L36
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L10
L36:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void decbig(int *x, int *y) {
  int a;
  for (a = 1; a <= y[0]; a++)
    x[a] -= y[a];
  for (a = 1; a < x[0]; a++)
    if (x[a] < 0) {
      x[a] += 10000;
      x[a + 1]--;
    }
  for (; x[0] > 1 && x[x[0]] == 0; x[0]--)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<decbig>:
  endbr64
  mov    %rdi,%rax
  cmpl   $0x0,(%rsi)
  jle    L84
  mov    $0x1,%edx
L90:
  mov    (%rsi,%rdx,4),%ecx
  sub    %ecx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,(%rsi)
  jge    L90
L84:
  cmpl   $0x1,(%rax)
  jle    L4
  mov    $0x1,%edx
  jmp    L64
L67:
  mov    (%rax),%ecx
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jle    L57
L64:
  mov    (%rax,%rdx,4),%ecx
  test   %ecx,%ecx
  jns    L67
  add    $0x2710,%ecx
  mov    %ecx,(%rax,%rdx,4)
  subl   $0x1,0x4(%rax,%rdx,4)
  jmp    L67
L57:
  cmp    $0x1,%ecx
  jle    L4
  lea    -0x1(%rcx),%edx
  movslq %edx,%rdx
  movslq %ecx,%rsi
  sub    $0x2,%rsi
  lea    -0x2(%rcx),%edi
  sub    %rdi,%rsi
  mov    %rsi,%rcx
L60:
  cmpl   $0x0,0x4(%rax,%rdx,4)
  jne    L4
  mov    %edx,(%rax)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L60
L4:
  ret
```

assistant: ```c
void decbig(int *x, int *y) {
  int a;
  for (a = 1; a <= y[0]; a++)
    x[a] -= y[a];
  for (a = 1; a < x[0]; a++)
    if (x[a] < 0) {
      x[a] += 10000;
      x[a + 1]--;
    }
  for (; x[0] > 1 && x[x[0]] == 0; x[0]--)
    ;
}
```