ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  mov    $0x39,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <mymove@plt>
  mov    %ebx,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movabs $0x6867666564636261,%rax
  movabs $0x706f6e6d6c6b6a69,%rdx
  mov    %rax,0x70(%rsp)
  mov    %rdx,0x78(%rsp)
  movabs $0x7877767574737271,%rax
  mov    $0x7a79,%edx
  mov    %rax,0x80(%rsp)
  mov    %rdx,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movl   $0x0,0xd0(%rsp)
  lea    0x70(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    0x1(%rax),%edx
  lea    0xa2(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <mymove@plt>
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string

tool: D13: src %s len %d


tool: D8: src %s, dst(+8) %s %d


tool: D28: src2 %s, dst(+8) %s %d


assistant: ```c
int main(int argc, char *argv[]) {
  char src[100] = {"123456789"};
  char *dst;
  int len = strlen(src);
  printf("src %s len %d\n", src, len);
  dst = ((char *)src + 8);
  mymove((void *)dst, (void *)(src), len);
  printf("src %s, dst(+8) %s %d\n", src, dst, len);
  char src2[100] = {"abcdefghijklmnopqrstuvwxyz"};
  len = strlen(src2);
  dst = ((char *)src2 + 50);
  mymove((void *)dst, (void *)(src2), len + 1);
  printf("src2 %s, dst(+8) %s %d\n", src2, dst, len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%edx
  lea    D13(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  movdqa D37(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x8(%rsp),%r12
  movl   $0x0,0x60(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x9,%edx
  xor    %eax,%eax
  call   <mymove@plt>
  mov    $0x9,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  lea    0x70(%rsp),%rbp
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1b,%edx
  xor    %eax,%eax
  movdqa D27(%rip),%xmm1
  mov    %rbp,%rsi
  lea    0xa2(%rsp),%r12
  movl   $0x0,0xd0(%rsp)
  mov    %r12,%rdi
  movaps %xmm0,0x90(%rsp)
  movaps %xmm1,0x70(%rsp)
  movdqa D58(%rip),%xmm1
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm1,0x80(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  call   <mymove@plt>
  xor    %eax,%eax
  mov    $0x1a,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D37
type_infered: byte[16]
name: parse_data
arguments: data_tag: D21
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: byte[16]
name: parse_data
arguments: data_tag: D58
type_infered: byte[16]
name: parse_data
arguments: data_tag: D36
type_infered: string

tool: D13: src %s len %d


tool: {"D37": [0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D21: src %s, dst(+8) %s %d


tool: {"D27": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70]}

tool: {"D58": [0x71,0x72,0x73,0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D36: src2 %s, dst(+8) %s %d


assistant: ```c
int main(int argc, char *argv[]) {
  char src[100] = {"123456789"};
  char *dst;
  int len = strlen(src);
  printf("src %s len %d\n", src, len);
  dst = ((char *)src + 8);
  mymove((void *)dst, (void *)(src), len);
  printf("src %s, dst(+8) %s %d\n", src, dst, len);
  char src2[100] = {"abcdefghijklmnopqrstuvwxyz"};
  len = strlen(src2);
  dst = ((char *)src2 + 50);
  mymove((void *)dst, (void *)(src2), len + 1);
  printf("src2 %s, dst(+8) %s %d\n", src2, dst, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%edx
  lea    D52(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  movdqa D46(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x8(%rsp),%r12
  movl   $0x0,0x60(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x9,%edx
  xor    %eax,%eax
  call   <mymove@plt>
  mov    $0x9,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  lea    0x70(%rsp),%rbp
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1b,%edx
  xor    %eax,%eax
  movdqa D13(%rip),%xmm1
  mov    %rbp,%rsi
  lea    0xa2(%rsp),%r12
  movl   $0x0,0xd0(%rsp)
  mov    %r12,%rdi
  movaps %xmm0,0x90(%rsp)
  movaps %xmm1,0x70(%rsp)
  movdqa D38(%rip),%xmm1
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm1,0x80(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  call   <mymove@plt>
  xor    %eax,%eax
  mov    $0x1a,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D52
data_type: string
name: parse_data
arguments: data_label: D46
data_type: byte[16]
name: parse_data
arguments: data_label: D33
data_type: string
name: parse_data
arguments: data_label: D13
data_type: byte[16]
name: parse_data
arguments: data_label: D38
data_type: byte[16]
name: parse_data
arguments: data_label: D0
data_type: string

tool: D52: src %s len %d


tool: {"D46": [0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D33: src %s, dst(+8) %s %d


tool: {"D13": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70]}

tool: {"D38": [0x71,0x72,0x73,0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D0: src2 %s, dst(+8) %s %d


assistant: ```c
int main(int argc, char *argv[]) {
  char src[100] = {"123456789"};
  char *dst;
  int len = strlen(src);
  printf("src %s len %d\n", src, len);
  dst = ((char *)src + 8);
  mymove((void *)dst, (void *)(src), len);
  printf("src %s, dst(+8) %s %d\n", src, dst, len);
  char src2[100] = {"abcdefghijklmnopqrstuvwxyz"};
  len = strlen(src2);
  dst = ((char *)src2 + 50);
  mymove((void *)dst, (void *)(src2), len + 1);
  printf("src2 %s, dst(+8) %s %d\n", src2, dst, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<problemUsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
type_infered: string
name: retrieve_data
arguments: data_tag: D30
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D20
type_infered: string
name: retrieve_data
arguments: data_tag: D21
type_infered: string

tool: D31:    -a declares that the array should be sorted ascending for worst case behavior. Incompatible with -d


tool: D30:    -d declares that the array should be sorted ascending for worst case behavior. Incompatible with -a


tool: D11:    -g define the groupings size for worst-case linear kth selection algorithm.


tool: D4:    -k declares that the array should be prepared according to the median-of-3 killer algorithm, Musser (1997)


tool: D20:    -u #,# determines number of pairs out of order, if sorted, and distance with which to swap.


tool: D21:    -w instead of random permutations of alphabet string, draw words from 160,136 English word dictionary


assistant: ```c
void problemUsage() {
  printf("   -a declares that the array should be sorted ascending for worst case behavior. Incompatible with -d\n");
  printf("   -d declares that the array should be sorted ascending for worst case behavior. Incompatible with -a\n");
  printf("   -g define the groupings size for worst-case linear kth selection algorithm.\n");
  printf("   -k declares that the array should be prepared according to the median-of-3 killer algorithm, Musser (1997)\n");
  printf("   -u #,# determines number of pairs out of order, if sorted, and distance with which to swap.\n");
  printf("   -w instead of random permutations of alphabet string, draw words from 160,136 English word dictionary\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<problemUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string
name: extract_symbolic_data
arguments: label: D39
type: string
name: extract_symbolic_data
arguments: label: D11
type: string
name: extract_symbolic_data
arguments: label: D34
type: string
name: extract_symbolic_data
arguments: label: D52
type: string
name: extract_symbolic_data
arguments: label: D32
type: string

tool: D6:    -a declares that the array should be sorted ascending for worst case behavior. Incompatible with -d


tool: D39:    -d declares that the array should be sorted ascending for worst case behavior. Incompatible with -a


tool: D11:    -g define the groupings size for worst-case linear kth selection algorithm.


tool: D34:    -k declares that the array should be prepared according to the median-of-3 killer algorithm, Musser (1997)


tool: D52:    -u #,# determines number of pairs out of order, if sorted, and distance with which to swap.


tool: D32:    -w instead of random permutations of alphabet string, draw words from 160,136 English word dictionary


assistant: ```c
void problemUsage() {
  printf("   -a declares that the array should be sorted ascending for worst case behavior. Incompatible with -d\n");
  printf("   -d declares that the array should be sorted ascending for worst case behavior. Incompatible with -a\n");
  printf("   -g define the groupings size for worst-case linear kth selection algorithm.\n");
  printf("   -k declares that the array should be prepared according to the median-of-3 killer algorithm, Musser (1997)\n");
  printf("   -u #,# determines number of pairs out of order, if sorted, and distance with which to swap.\n");
  printf("   -w instead of random permutations of alphabet string, draw words from 160,136 English word dictionary\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<problemUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D52
datatype: string
name: parse_data
arguments: tag: D41
datatype: string
name: parse_data
arguments: tag: D45
datatype: string
name: parse_data
arguments: tag: D50
datatype: string
name: parse_data
arguments: tag: D33
datatype: string

tool: D5:    -a declares that the array should be sorted ascending for worst case behavior. Incompatible with -d


tool: D52:    -d declares that the array should be sorted ascending for worst case behavior. Incompatible with -a


tool: D41:    -g define the groupings size for worst-case linear kth selection algorithm.


tool: D45:    -k declares that the array should be prepared according to the median-of-3 killer algorithm, Musser (1997)


tool: D50:    -u #,# determines number of pairs out of order, if sorted, and distance with which to swap.


tool: D33:    -w instead of random permutations of alphabet string, draw words from 160,136 English word dictionary


assistant: ```c
void problemUsage() {
  printf("   -a declares that the array should be sorted ascending for worst case behavior. Incompatible with -d\n");
  printf("   -d declares that the array should be sorted ascending for worst case behavior. Incompatible with -a\n");
  printf("   -g define the groupings size for worst-case linear kth selection algorithm.\n");
  printf("   -k declares that the array should be prepared according to the median-of-3 killer algorithm, Musser (1997)\n");
  printf("   -u #,# determines number of pairs out of order, if sorted, and distance with which to swap.\n");
  printf("   -w instead of random permutations of alphabet string, draw words from 160,136 English word dictionary\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<problemUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D52
datatype: string
name: retrieve_data
arguments: data_label: D47
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D51
datatype: string
name: retrieve_data
arguments: data_label: D58
datatype: string
name: retrieve_data
arguments: data_label: D37
datatype: string

tool: D52:    -a declares that the array should be sorted ascending for worst case behavior. Incompatible with -d


tool: D47:    -d declares that the array should be sorted ascending for worst case behavior. Incompatible with -a


tool: D23:    -g define the groupings size for worst-case linear kth selection algorithm.


tool: D51:    -k declares that the array should be prepared according to the median-of-3 killer algorithm, Musser (1997)


tool: D58:    -u #,# determines number of pairs out of order, if sorted, and distance with which to swap.


tool: D37:    -w instead of random permutations of alphabet string, draw words from 160,136 English word dictionary


assistant: ```c
void problemUsage() {
  printf("   -a declares that the array should be sorted ascending for worst case behavior. Incompatible with -d\n");
  printf("   -d declares that the array should be sorted ascending for worst case behavior. Incompatible with -a\n");
  printf("   -g define the groupings size for worst-case linear kth selection algorithm.\n");
  printf("   -k declares that the array should be prepared according to the median-of-3 killer algorithm, Musser (1997)\n");
  printf("   -u #,# determines number of pairs out of order, if sorted, and distance with which to swap.\n");
  printf("   -w instead of random permutations of alphabet string, draw words from 160,136 English word dictionary\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jw_strcase_hashcode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L10
L2:
  mov    -0x28(%rbp),%rax
  shl    $0x5,%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  add    %rbx,%rax
  mov    %rax,-0x28(%rbp)
  addq   $0x1,-0x20(%rbp)
L10:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int jw_strcase_hashcode(const void *key) {
  const char *s = (const char *)key;
  unsigned long h = 0;
  const char *p;
  assert(s);
  for (p = (const char *)s; *p != '\0'; p += 1) {
    h = (h << 5) - h + (unsigned long)tolower(*p);
  }
  return (unsigned int)h;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<jw_strcase_hashcode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <assert@plt>
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L10
  mov    $0x0,%eax
L22:
  mov    %rax,%rbx
  shl    $0x5,%rbx
  sub    %rax,%rbx
  movsbl %dil,%edi
  call   <tolower@plt>
  add    %rbx,%rax
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L22
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x0,%eax
  jmp    L19
```

assistant: ```c
unsigned int jw_strcase_hashcode(const void *key) {
  const char *s = (const char *)key;
  unsigned long h = 0;
  const char *p;
  assert(s);
  for (p = (const char *)s; *p != '\0'; p += 1) {
    h = (h << 5) - h + (unsigned long)tolower(*p);
  }
  return (unsigned int)h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jw_strcase_hashcode>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L8
  xor    %eax,%eax
  nopl   (%rax)
L15:
  mov    %rax,%rbx
  add    $0x1,%rbp
  shl    $0x5,%rbx
  sub    %rax,%rbx
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  add    %rbx,%rax
  test   %dil,%dil
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int jw_strcase_hashcode(const void *key) {
  const char *s = (const char *)key;
  unsigned long h = 0;
  const char *p;
  assert(s);
  for (p = (const char *)s; *p != '\0'; p += 1) {
    h = (h << 5) - h + (unsigned long)tolower(*p);
  }
  return (unsigned int)h;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jw_strcase_hashcode>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L14
  xor    %eax,%eax
  nopl   (%rax)
L12:
  mov    %rax,%rbx
  add    $0x1,%rbp
  shl    $0x5,%rbx
  sub    %rax,%rbx
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  add    %rbx,%rax
  test   %dil,%dil
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int jw_strcase_hashcode(const void *key) {
  const char *s = (const char *)key;
  unsigned long h = 0;
  const char *p;
  assert(s);
  for (p = (const char *)s; *p != '\0'; p += 1) {
    h = (h << 5) - h + (unsigned long)tolower(*p);
  }
  return (unsigned int)h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<seqprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    $0x31,%eax
  jmp    L5
L10:
  mov    $0x30,%eax
L5:
  mov    %eax,%edi
  call   <putchar@plt>
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L38
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void seqprint(unsigned char *s, int len) {
  int i;
  for (i = 0; i < len; ++s, ++i)
    putchar(*s ? '1' : '0');
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<seqprint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L19
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rbp
L18:
  cmpb   $0x1,(%rbx)
  mov    $0x30,%edi
  sbb    $0xffffffff,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L18
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void seqprint(unsigned char *s, int len) {
  int i;
  for (i = 0; i < len; ++s, ++i)
    putchar(*s ? '1' : '0');
  putchar('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<seqprint>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %rbp
  movslq %esi,%rsi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L17:
  cmpb   $0x1,(%rbx)
  mov    $0x30,%edi
  sbb    $0xffffffff,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax)
L19:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void seqprint(unsigned char *s, int len) {
  int i;
  for (i = 0; i < len; ++s, ++i)
    putchar(*s ? '1' : '0');
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<seqprint>:
  endbr64
  test   %esi,%esi
  jle    L7
  push   %rbp
  movslq %esi,%rsi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L35:
  cmpb   $0x0,(%rbx)
  je     L10
  mov    $0x31,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L35
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x30,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L35
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void seqprint(unsigned char *s, int len) {
  int i;
  for (i = 0; i < len; ++s, ++i)
    putchar(*s ? '1' : '0');
  putchar('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getRandom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getRandom() {
  srand((unsigned)time(NULL));
  int r = rand();
  return r;
}
```