ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dt_get_virtual_reg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  lea    0x0(,%rax,4),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <getprop@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L66
  mov    -0x14(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  jmp    L6
L66:
  movl   $0x0,-0x14(%rbp)
  jmp    L28
L30:
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <dt_xlate_reg@plt>
  test   %eax,%eax
  je     L3
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L28:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L30
  jmp    L8
L3:
  nop
L8:
  mov    -0x14(%rbp),%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: virtual-reg

assistant: ```c
int dt_get_virtual_reg(void *node, void **addr, int nres) {
  unsigned long xaddr;
  int n;
  n = getprop(node, "virtual-reg", addr, nres * 4);
  if (n > 0) {
    return n / 4;
  }
  for (n = 0; n < nres; n++) {
    if (!dt_xlate_reg(node, n, &xaddr, NULL)) {
      break;
    }
    addr[n] = (void *)xaddr;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dt_get_virtual_reg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rdx,4),%ecx
  mov    %rsi,%rdx
  lea    D6(%rip),%rsi
  call   <getprop@plt>
  test   %eax,%eax
  jg     L12
  mov    $0x0,%ebx
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L6
L33:
  mov    $0x0,%ecx
  mov    %r14,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <dt_xlate_reg@plt>
  test   %eax,%eax
  je     L6
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,%r12d
  jne    L33
  mov    %r12d,%ebx
  jmp    L6
L12:
  lea    0x3(%rax),%ebx
  cmovns %eax,%ebx
  sar    $0x2,%ebx
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: virtual-reg

assistant: ```c
int dt_get_virtual_reg(void *node, void **addr, int nres) {
  unsigned long xaddr;
  int n;
  n = getprop(node, "virtual-reg", addr, nres * 4);
  if (n > 0) {
    return n / 4;
  }
  for (n = 0; n < nres; n++) {
    if (!dt_xlate_reg(node, n, &xaddr, NULL)) {
      break;
    }
    addr[n] = (void *)xaddr;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dt_get_virtual_reg>:
  endbr64
  push   %r14
  lea    0x0(,%rdx,4),%ecx
  push   %r13
  mov    %edx,%r13d
  mov    %rsi,%rdx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D4(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <getprop@plt>
  mov    %eax,%r12d
  sar    $0x2,%r12d
  test   %eax,%eax
  jg     L56
  xor    %r12d,%r12d
  mov    %rsp,%r14
  test   %r13d,%r13d
  jg     L11
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%rsp),%rax
  add    $0x1,%r12d
  add    $0x8,%rbx
  mov    %rax,-0x8(%rbx)
  cmp    %r12d,%r13d
  je     L56
L11:
  xor    %ecx,%ecx
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <dt_xlate_reg@plt>
  test   %eax,%eax
  jne    L18
L56:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: D4: virtual-reg

assistant: ```c
int dt_get_virtual_reg(void *node, void **addr, int nres) {
  unsigned long xaddr;
  int n;
  n = getprop(node, "virtual-reg", addr, nres * 4);
  if (n > 0) {
    return n / 4;
  }
  for (n = 0; n < nres; n++) {
    if (!dt_xlate_reg(node, n, &xaddr, NULL)) {
      break;
    }
    addr[n] = (void *)xaddr;
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dt_get_virtual_reg>:
  endbr64
  push   %r14
  lea    0x0(,%rdx,4),%ecx
  push   %r13
  mov    %edx,%r13d
  mov    %rsi,%rdx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D1(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <getprop@plt>
  mov    %eax,%r12d
  sar    $0x2,%r12d
  test   %eax,%eax
  jg     L26
  xor    %r12d,%r12d
  mov    %rsp,%r14
  test   %r13d,%r13d
  jg     L12
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%rsp),%rax
  add    $0x1,%r12d
  add    $0x8,%rbx
  mov    %rax,-0x8(%rbx)
  cmp    %r12d,%r13d
  je     L26
L12:
  xor    %ecx,%ecx
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <dt_xlate_reg@plt>
  test   %eax,%eax
  jne    L16
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: virtual-reg

assistant: ```c
int dt_get_virtual_reg(void *node, void **addr, int nres) {
  unsigned long xaddr;
  int n;
  n = getprop(node, "virtual-reg", addr, nres * 4);
  if (n > 0) {
    return n / 4;
  }
  for (n = 0; n < nres; n++) {
    if (!dt_xlate_reg(node, n, &xaddr, NULL)) {
      break;
    }
    addr[n] = (void *)xaddr;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<practice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movss  D73(%rip),%xmm0
  movss  %xmm0,-0x28(%rbp)
  movss  D33(%rip),%xmm0
  movss  %xmm0,-0x24(%rbp)
  movb   $0x65,-0x32(%rbp)
  movb   $0x66,-0x31(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  cvttss2si %xmm0,%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  cvttss2si %xmm0,%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x32(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x31(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D73
type_infered: f32
name: read_data
arguments: data_tag: D33
type_infered: f32
name: read_data
arguments: data_tag: D30
type_infered: string
name: read_data
arguments: data_tag: D78
type_infered: string
name: read_data
arguments: data_tag: D52
type_infered: string

tool: D73: 3.4

tool: D33: 7.2

tool: D30: %d

tool: D78: %f

tool: D52: %c

assistant: ```c
void practice() {
  int a = 1;
  int b = 4;
  float c = 3.4;
  float d = 7.2;
  char e = 'e';
  char f = 'f';
  int *ptrA;
  float *ptrB;
  char *ptrC;
  ptrA = &a;
  printf("%d", *ptrA);
  ptrA = &b;
  printf("%d", *ptrA);
  ptrB = &c;
  printf("%f", *ptrB);
  ptrB = &d;
  printf("%f", *ptrB);
  ptrC = &e;
  printf("%c", *ptrC);
  ptrC = &f;
  printf("%c", *ptrC);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<practice>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x65,%esi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x66,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string

tool: D5: %d

tool: D17: %f

tool: D19: %c

assistant: ```c
void practice() {
  int a = 1;
  int b = 4;
  float c = 3.4;
  float d = 7.2;
  char e = 'e';
  char f = 'f';
  int *ptrA;
  float *ptrB;
  char *ptrC;
  ptrA = &a;
  printf("%d", *ptrA);
  ptrA = &b;
  printf("%d", *ptrA);
  ptrB = &c;
  printf("%f", *ptrB);
  ptrB = &d;
  printf("%f", *ptrB);
  ptrC = &e;
  printf("%c", *ptrC);
  ptrC = &f;
  printf("%c", *ptrC);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<practice>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  lea    D23(%rip),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x7,%esi
  lea    D3(%rip),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x65,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x66,%esi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D23
data_type: string
name: parse_data
arguments: label: D3
data_type: string

tool: D18: %d

tool: D23: %f

tool: D3: %c

assistant: ```c
void practice() {
  int a = 1;
  int b = 4;
  float c = 3.4;
  float d = 7.2;
  char e = 'e';
  char f = 'f';
  int *ptrA;
  float *ptrB;
  char *ptrC;
  ptrA = &a;
  printf("%d", *ptrA);
  ptrA = &b;
  printf("%d", *ptrA);
  ptrB = &c;
  printf("%f", *ptrB);
  ptrB = &d;
  printf("%f", *ptrB);
  ptrC = &e;
  printf("%c", *ptrC);
  ptrC = &f;
  printf("%c", *ptrC);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<practice>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  lea    D0(%rip),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x7,%esi
  lea    D26(%rip),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x65,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x66,%esi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D26
data_type: string

tool: D8: %d

tool: D0: %f

tool: D26: %c

assistant: ```c
void practice() {
  int a = 1;
  int b = 4;
  float c = 3.4;
  float d = 7.2;
  char e = 'e';
  char f = 'f';
  int *ptrA;
  float *ptrB;
  char *ptrC;
  ptrA = &a;
  printf("%d", *ptrA);
  ptrA = &b;
  printf("%d", *ptrA);
  ptrB = &c;
  printf("%f", *ptrB);
  ptrB = &d;
  printf("%f", *ptrB);
  ptrC = &e;
  printf("%c", *ptrC);
  ptrC = &f;
  printf("%c", *ptrC);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: usage :%s portnum filename


assistant: ```c
void usage(char *command) {
  printf("usage :%s portnum filename\n", command);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: usage :%s portnum filename


assistant: ```c
void usage(char *command) {
  printf("usage :%s portnum filename\n", command);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: usage :%s portnum filename


assistant: ```c
void usage(char *command) {
  printf("usage :%s portnum filename\n", command);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string

tool: D8: usage :%s portnum filename


assistant: ```c
void usage(char *command) {
  printf("usage :%s portnum filename\n", command);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assertImplementationCStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rsi,%r12
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L71
  mov    %rdi,%rbp
  call   <stdimpl_strlen@plt>
  mov    %eax,%r14d
  test   %r12,%r12
  je     L78
  mov    %r12,%rdi
  call   <stdimpl_strlen@plt>
  mov    %eax,%r13d
  cmp    $0x19,%r14d
  jle    L24
  cmp    $0x19,%eax
  jle    L26
  mov    $0x19,%r13d
  mov    $0x19,%r14d
  jmp    L35
L78:
  mov    $0x4,%r13d
  lea    D69(%rip),%r12
  cmp    $0x19,%r14d
  jle    L24
  mov    $0x4,%r13d
  lea    D69(%rip),%r12
L26:
  mov    $0x32,%eax
  sub    %r13d,%eax
  cmp    %eax,%r14d
  cmovg  %eax,%r14d
  jmp    L35
L71:
  mov    $0x4,%r14d
  lea    D69(%rip),%rbp
  test   %rsi,%rsi
  je     L78
  mov    %r12,%rdi
  call   <stdimpl_strlen@plt>
  mov    %eax,%r13d
  mov    $0x4,%r14d
  lea    D69(%rip),%rbp
L24:
  mov    $0x32,%eax
  sub    %r14d,%eax
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
L35:
  lea    0x10(%rsp),%rbx
  lea    D37(%rip),%rsi
  mov    %rbx,%rdi
  call   <stdimpl_strcpy@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <stdimpl_strncat@plt>
  lea    D21(%rip),%rsi
  mov    %rbx,%rdi
  call   <stdimpl_strcat@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <stdimpl_strncat@plt>
  lea    D63(%rip),%rsi
  mov    %rbx,%rdi
  call   <stdimpl_strcat@plt>
  mov    %r15,%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <addFailure@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D69
datatype: string
name: retrieve_data
arguments: data_label: D37
datatype: string
name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D63
datatype: string

tool: D69: null

tool: D37: exp "

tool: D21: " was "

tool: D63: "

assistant: ```c
void assertImplementationCStr(const char *expected, const char *actual, long line, const char *file) {
  char buffer[64];
  int el;
  int al;
  if (expected) {
    el = stdimpl_strlen(expected);
  } else {
    el = 4;
    expected = "null";
  }
  if (actual) {
    al = stdimpl_strlen(actual);
  } else {
    al = 4;
    actual = "null";
  }
  if (el > ((64 - 13 - 1) / 2)) {
    if (al > ((64 - 13 - 1) / 2)) {
      al = ((64 - 13 - 1) / 2);
      el = ((64 - 13 - 1) / 2);
    } else {
      int w = ((64 - 13 - 1) / 2) + (((64 - 13 - 1) / 2) - al);
      if (el > w) {
        el = w;
      }
    }
  } else {
    int w = ((64 - 13 - 1) / 2) + (((64 - 13 - 1) / 2) - el);
    if (al > w) {
      al = w;
    }
  }
  stdimpl_strcpy(buffer, "exp \"");
  stdimpl_strncat(buffer, expected, el);
  stdimpl_strcat(buffer, "\" was \"");
  stdimpl_strncat(buffer, actual, al);
  stdimpl_strcat(buffer, "\"");
  addFailure(buffer, line, file);
}
```
user: Translate the below assembly code into C programming language:

```asm
<characterCounter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L66
L10:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x30(%rbp)
  jne    L0
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L60
L1:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x18(%rbp)
L60:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x30(%rbp)
  jne    L1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L0:
  addl   $0x1,-0x1c(%rbp)
L66:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L55
L40:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x18(%rbp)
L55:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *characterCounter(char *stringIn, int numTokens, char delim) {
  int i, j, k = 0, x = 0, numChars = 0;
  int *numCharacters = (int *)calloc(numTokens + 1, sizeof(int));
  for (i = 0; stringIn[i] != '\0'; i++) {
    if (stringIn[i] == delim) {
      for (j = x; stringIn[j] != delim; j++) {
        numChars++;
      }
      numCharacters[k] = numChars;
      numChars = 0;
      x = i + 1;
      k++;
    }
  }
  for (j = x + 1; stringIn[j] != '\0'; j++) {
    numChars++;
  }
  numCharacters[k] = numChars;
  return numCharacters;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<characterCounter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %edx,%ebp
  lea    0x1(%rsi),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  movzbl (%rbx),%eax
  test   %al,%al
  je     L76
  mov    $0x1,%edx
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    $0x0,%r10d
  mov    $0x1,%r9d
  jmp    L4
L9:
  mov    %r10d,%ecx
L40:
  movslq %esi,%rax
  mov    %ecx,(%rdi,%rax,4)
  mov    %edx,%ecx
  add    $0x1,%esi
L96:
  add    $0x1,%rdx
  movzbl -0x1(%rbx,%rdx,1),%eax
  test   %al,%al
  je     L58
L4:
  cmp    %al,%bpl
  jne    L96
  movslq %ecx,%rcx
  add    %rbx,%rcx
  cmp    (%rcx),%bpl
  je     L9
  mov    %rcx,%rax
  mov    %r9d,%r8d
  sub    %ecx,%r8d
L37:
  lea    (%r8,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %bpl,(%rax)
  jne    L37
  jmp    L40
L76:
  mov    $0x0,%ecx
  mov    $0x0,%esi
L58:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rbx,%rcx,1),%rax
  cmpb   $0x0,(%rax)
  je     L43
  mov    $0x0,%edx
L82:
  add    $0x1,%edx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L82
L81:
  movslq %esi,%rsi
  mov    %edx,(%rdi,%rsi,4)
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L43:
  mov    $0x0,%edx
  jmp    L81
```

assistant: ```c
int *characterCounter(char *stringIn, int numTokens, char delim) {
  int i, j, k = 0, x = 0, numChars = 0;
  int *numCharacters = (int *)calloc(numTokens + 1, sizeof(int));
  for (i = 0; stringIn[i] != '\0'; i++) {
    if (stringIn[i] == delim) {
      for (j = x; stringIn[j] != delim; j++) {
        numChars++;
      }
      numCharacters[k] = numChars;
      numChars = 0;
      x = i + 1;
      k++;
    }
  }
  for (j = x + 1; stringIn[j] != '\0'; j++) {
    numChars++;
  }
  numCharacters[k] = numChars;
  return numCharacters;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<characterCounter>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rsi),%edi
  mov    $0x4,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  movzbl (%rbx),%ecx
  mov    %rax,%r8
  test   %cl,%cl
  je     L108
  mov    $0x1,%edx
  xor    %eax,%eax
  xor    %r9d,%r9d
  mov    $0x1,%r10d
  jmp    L78
  nopl   0x0(%rax)
L3:
  add    $0x1,%rdx
  movzbl -0x1(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  je     L98
L78:
  mov    %edx,%edi
  cmp    %cl,%bpl
  jne    L3
  add    %rbx,%rax
  cmp    (%rax),%bpl
  je     L31
  mov    %r10d,%esi
  sub    %eax,%esi
  nopl   0x0(%rax)
L93:
  lea    (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %bpl,(%rax)
  jne    L93
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %ecx,(%r8,%rax,4)
  movslq %edi,%rax
L76:
  add    $0x1,%rdx
  movzbl -0x1(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L78
  nop
L98:
  add    $0x1,%eax
  movslq %r9d,%r9
  movslq %eax,%rdx
  lea    (%r8,%r9,4),%rsi
L1:
  cmpb   $0x0,(%rbx,%rdx,1)
  je     L40
  cltq
  mov    $0x1,%edx
  add    %rbx,%rax
  sub    %eax,%edx
  nop
L19:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L19
  mov    %ecx,(%rsi)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  movslq %r9d,%rax
  xor    %ecx,%ecx
  add    $0x1,%r9d
  mov    %ecx,(%r8,%rax,4)
  movslq %edi,%rax
  jmp    L76
L40:
  xor    %ecx,%ecx
  mov    %r8,%rax
  mov    %ecx,(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L108:
  mov    %rax,%rsi
  mov    $0x1,%edx
  mov    $0x1,%eax
  jmp    L1
```

assistant: ```c
int *characterCounter(char *stringIn, int numTokens, char delim) {
  int i, j, k = 0, x = 0, numChars = 0;
  int *numCharacters = (int *)calloc(numTokens + 1, sizeof(int));
  for (i = 0; stringIn[i] != '\0'; i++) {
    if (stringIn[i] == delim) {
      for (j = x; stringIn[j] != delim; j++) {
        numChars++;
      }
      numCharacters[k] = numChars;
      numChars = 0;
      x = i + 1;
      k++;
    }
  }
  for (j = x + 1; stringIn[j] != '\0'; j++) {
    numChars++;
  }
  numCharacters[k] = numChars;
  return numCharacters;
}
```