user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movq   $0x4000,-0x30(%rbp)
  mov    $0x0,%eax
  call   <endHeap@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%eax
  call   <endHeap@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x4000,%eax
  cmp    %rax,%rdx
  cmovae %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%rax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L39
  cmpq   $0x0,-0x10(%rbp)
  jne    L1
L39:
  mov    -0x30(%rbp),%rax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L1:
  mov    $0x0,%eax
  call   <endHeap@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%rax
  add    %rax,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L30
  mov    -0x30(%rbp),%rax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L30:
  mov    $0x0,%eax
  call   <endHeap@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x28(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  D15(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L32
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L40
L32:
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L40:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
data_type: string
name: extract_symbolic_data
arguments: tag: D37
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D23
data_type: string
name: extract_symbolic_data
arguments: tag: D44
data_type: string

tool: D24: -- Testing merging of deallocated large blocks ( >= %u bytes)


tool: D37: * ERROR: unable to allocate memory of size %u bytes


tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D23: * ERROR: not good enough usage of memory (probably incorrect merging of deallocated memory blocks)
Your implementation used %u bytes more than expected


tool: D44: Test passed OK

assistant: ```c
int main(int argc, char *argv[]) {
  void *p1, *p2, *oldBrk, *newBrk1, *newBrk2;
  unsigned long largeSize = 16384;
  oldBrk = endHeap();
  p1 = (void *)malloc(1);
  newBrk1 = endHeap();
  largeSize = ((unsigned long)(newBrk1 - oldBrk) > 16384 ? (unsigned long)(newBrk1 - oldBrk) : 16384);
  free(p1);
  printf("-- Testing merging of deallocated large blocks ( >= %u bytes)\n", (unsigned)largeSize);
  p1 = (void *)malloc(largeSize);
  p2 = (void *)malloc(largeSize);
  if (p1 == NULL || p2 == NULL)
    printf("* ERROR: unable to allocate memory of size %u bytes\n", (unsigned)largeSize);
  newBrk1 = endHeap();
  free(p1);
  free(p2);
  p1 = (void *)malloc(largeSize * 2);
  if (p1 == NULL)
    printf("* ERROR: unable to allocate memory of size %u bytes\n", (unsigned)largeSize);
  newBrk2 = endHeap();
  if (((double)(newBrk2 - oldBrk)) / ((double)(newBrk1 - oldBrk)) > 1)
    printf("* ERROR: not good enough usage of memory (probably incorrect merging of deallocated memory blocks)\nYour implementation used %u bytes more than expected\n", ((unsigned)(newBrk2 - newBrk1)));
  else
    printf("Test passed OK\n");
  exit(0);
}
```