ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<inputChecker>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %edi,%r12
  imul   $0x66666667,%r12,%r12
  sar    $0x22,%r12
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%r12d
  lea    (%r12,%r12,4),%eax
  add    %eax,%eax
  mov    %edi,%r12d
  sub    %eax,%r12d
  je     L86
  mov    %edi,%r13d
  mov    %edi,%r15d
  mov    $0x1,%r14d
L75:
  mov    %r15d,%ebx
  mov    $0x1,%ebp
L63:
  mov    %r13d,%edi
  call   <numberLength@plt>
  sub    %r14d,%eax
  cmp    %ebp,%eax
  jl     L7
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%ebx
  sub    %ebx,%edx
  mov    %edx,%ebx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %r12d,%eax
  je     L65
  test   %eax,%eax
  je     L65
  add    $0x1,%ebp
  jmp    L63
L7:
  movslq %r15d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%r15d
  sub    %r15d,%eax
  mov    %eax,%r15d
  add    $0x1,%r14d
  cmp    $0x4,%r14d
  je     L68
  movslq %eax,%r12
  imul   $0x66666667,%r12,%r12
  sar    $0x22,%r12
  cltd
  sub    %edx,%r12d
  lea    (%r12,%r12,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%r12d
  jne    L75
  mov    $0xffffffff,%eax
  jmp    L14
L68:
  mov    $0x0,%eax
  jmp    L14
L86:
  mov    $0xffffffff,%eax
  jmp    L14
L65:
  mov    $0xffffffff,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int inputChecker(int n) {
  int n1 = n, nd, test, tester, i, j;
  for (i = 1; i < 4; i++) {
    test = n1 % 10;
    nd = n1;
    if (test == 0)
      return -1;
    for (j = 1; j <= numberLength(n) - i; j++) {
      nd /= 10;
      tester = nd % 10;
      if (test == tester || tester == 0)
        return -1;
    }
    n1 /= 10;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<inputChecker>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
L58:
  movslq %r13d,%rax
  imul   $0x66666667,%rax,%rbx
  mov    %rax,0x8(%rsp)
  mov    %r13d,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %r13d,%ebx
  add    %eax,%eax
  sub    %eax,%ebx
  je     L39
  mov    %r13d,%r15d
  mov    $0x1,%r14d
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L46:
  movslq %r15d,%rax
  mov    %r15d,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%r15d
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %r15d,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %r15d,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  cmp    %eax,%ebx
  je     L39
  test   %eax,%eax
  je     L39
  add    $0x1,%r14d
L18:
  mov    %ebp,%edi
  call   <numberLength@plt>
  sub    %r12d,%eax
  cmp    %r14d,%eax
  jge    L46
  imul   $0x66666667,0x8(%rsp),%r14
  mov    %r13d,%eax
  add    $0x1,%r12d
  sar    $0x1f,%eax
  sar    $0x22,%r14
  sub    %eax,%r14d
  mov    %r14d,%r13d
  cmp    $0x4,%r12d
  jne    L58
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int inputChecker(int n) {
  int n1 = n, nd, test, tester, i, j;
  for (i = 1; i < 4; i++) {
    test = n1 % 10;
    nd = n1;
    if (test == 0)
      return -1;
    for (j = 1; j <= numberLength(n) - i; j++) {
      nd /= 10;
      tester = nd % 10;
      if (test == tester || tester == 0)
        return -1;
    }
    n1 /= 10;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inputChecker>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
L59:
  movslq %r13d,%rax
  imul   $0x66666667,%rax,%rbx
  mov    %rax,0x8(%rsp)
  mov    %r13d,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %r13d,%ebx
  add    %eax,%eax
  sub    %eax,%ebx
  je     L21
  mov    %r13d,%r15d
  mov    $0x1,%r14d
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %r15d,%rax
  mov    %r15d,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%r15d
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %r15d,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %r15d,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  cmp    %eax,%ebx
  je     L21
  test   %eax,%eax
  je     L21
  add    $0x1,%r14d
L6:
  mov    %ebp,%edi
  call   <numberLength@plt>
  sub    %r12d,%eax
  cmp    %r14d,%eax
  jge    L13
  imul   $0x66666667,0x8(%rsp),%r14
  mov    %r13d,%eax
  add    $0x1,%r12d
  sar    $0x1f,%eax
  sar    $0x22,%r14
  sub    %eax,%r14d
  mov    %r14d,%r13d
  cmp    $0x4,%r12d
  jne    L59
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int inputChecker(int n) {
  int n1 = n, nd, test, tester, i, j;
  for (i = 1; i < 4; i++) {
    test = n1 % 10;
    nd = n1;
    if (test == 0)
      return -1;
    for (j = 1; j <= numberLength(n) - i; j++) {
      nd /= 10;
      tester = nd % 10;
      if (test == tester || tester == 0)
        return -1;
    }
    n1 /= 10;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %edi,-0x224(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L5
L23:
  mov    -0x21c(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x218(%rbp)
  cmpq   $0x0,-0x218(%rbp)
  je     L1
  mov    -0x218(%rbp),%rax
  add    $0x1,%rax
  lea    -0x210(%rbp),%rdx
  sub    %rdx,%rax
  mov    %eax,-0x21c(%rbp)
  mov    -0x21c(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  jmp    L27
L1:
  mov    -0x21c(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L5:
  lea    -0x210(%rbp),%rax
  mov    $0x200,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x21c(%rbp)
  cmpl   $0x0,-0x21c(%rbp)
  jg     L23
  mov    -0x21c(%rbp),%eax
  mov    %eax,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%eax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D6: 


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[512];
  char *e;
  int l;
  while ((l = read(0, buf, 512)) > 0) {
    e = memchr(buf, '\n', l);
    if (e) {
      l = e + 1 - buf;
      write(1, buf, l);
      return 0;
    }
    write(1, buf, l);
  }
  write(1, "\n", l);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L12
L28:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L12:
  mov    $0x200,%edx
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L25
  mov    %ebx,%edx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L28
  lea    0x1(%rax),%rdx
  mov    %rsp,%rsi
  sub    %esi,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  jmp    L41
L25:
  mov    %eax,%edx
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%eax
L41:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: 


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[512];
  char *e;
  int l;
  while ((l = read(0, buf, 512)) > 0) {
    e = memchr(buf, '\n', l);
    if (e) {
      l = e + 1 - buf;
      write(1, buf, l);
      return 0;
    }
    write(1, buf, l);
  }
  write(1, "\n", l);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L42
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  jne    L22
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L42:
  mov    $0x200,%edx
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %eax,%r12d
  mov    %eax,%edx
  test   %eax,%eax
  jg     L15
  lea    D6(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%eax
L21:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x218,%rsp
  pop    %rbp
  pop    %r12
  ret
L22:
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  sub    %ebp,%edx
  call   <write@plt>
  xor    %eax,%eax
  jmp    L21
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string

tool: D6: 


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[512];
  char *e;
  int l;
  while ((l = read(0, buf, 512)) > 0) {
    e = memchr(buf, '\n', l);
    if (e) {
      l = e + 1 - buf;
      write(1, buf, l);
      return 0;
    }
    write(1, buf, l);
  }
  write(1, "\n", l);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  jne    L28
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L1:
  mov    $0x200,%edx
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %eax,%r12d
  mov    %eax,%edx
  test   %eax,%eax
  jg     L12
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%eax
L43:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x218,%rsp
  pop    %rbp
  pop    %r12
  ret
L28:
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  sub    %ebp,%edx
  call   <write@plt>
  xor    %eax,%eax
  jmp    L43
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string

tool: D1: 


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[512];
  char *e;
  int l;
  while ((l = read(0, buf, 512)) > 0) {
    e = memchr(buf, '\n', l);
    if (e) {
      l = e + 1 - buf;
      write(1, buf, l);
      return 0;
    }
    write(1, buf, l);
  }
  write(1, "\n", l);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L19
  mov    $0x2d,%edi
  call   <putch@plt>
  negl   -0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L16
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <print_int>
L16:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x30(%rdx),%eax
  mov    %eax,%edi
  call   <putch@plt>
  nop
  leave
  ret
```

assistant: ```c
void print_int(int i) {
  if (i < 0) {
    putch('-');
    i = -i;
  }
  if (i / 10 != 0) {
    print_int(i / 10);
  }
  putch('0' + (i % 10));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_int>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  js     L10
L34:
  lea    0x9(%rbx),%eax
  cmp    $0x12,%eax
  ja     L0
L24:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  call   <putch@plt>
  pop    %rbx
  ret
L10:
  mov    $0x2d,%edi
  call   <putch@plt>
  neg    %ebx
  jmp    L34
L0:
  movslq %ebx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <print_int>
  jmp    L24
```

assistant: ```c
void print_int(int i) {
  if (i < 0) {
    putch('-');
    i = -i;
  }
  if (i / 10 != 0) {
    print_int(i / 10);
  }
  putch('0' + (i % 10));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L2
L10:
  lea    0x9(%rbx),%eax
  mov    %ebx,%r12d
  cmp    $0x12,%eax
  ja     L69
L8:
  mov    $0xcccccccd,%eax
  add    $0x8,%rsp
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putch@plt>
  nopl   (%rax)
L69:
  mov    $0xcccccccd,%edi
  mov    %r12,%rbp
  imul   %rdi,%rbp
  shr    $0x23,%rbp
  lea    0x9(%rbp),%eax
  mov    %ebp,%r15d
  cmp    $0x12,%eax
  ja     L33
L9:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  call   <putch@plt>
  jmp    L8
  nopl   0x0(%rax)
L2:
  mov    $0x2d,%edi
  neg    %ebx
  call   <putch@plt>
  jmp    L10
  nopl   0x0(%rax)
L33:
  mov    %r15,%r13
  imul   %rdi,%r13
  shr    $0x23,%r13
  lea    0x9(%r13),%eax
  mov    %r13d,%r14d
  cmp    $0x12,%eax
  ja     L70
L52:
  mov    $0xcccccccd,%eax
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  call   <putch@plt>
  jmp    L9
  nop
L70:
  imul   %r14,%rdi
  shr    $0x23,%rdi
  call   <print_int>
  jmp    L52
```

assistant: ```c
void print_int(int i) {
  if (i < 0) {
    putch('-');
    i = -i;
  }
  if (i / 10 != 0) {
    print_int(i / 10);
  }
  putch('0' + (i % 10));
}
```
user: What is the c source code of the assembly code below?

```asm
<print_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L43
L17:
  lea    0x9(%rbx),%eax
  mov    %ebx,%r12d
  cmp    $0x12,%eax
  ja     L30
L49:
  mov    $0xcccccccd,%eax
  add    $0x8,%rsp
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putch@plt>
  nopl   (%rax)
L30:
  mov    $0xcccccccd,%edi
  mov    %r12,%rbp
  imul   %rdi,%rbp
  shr    $0x23,%rbp
  lea    0x9(%rbp),%eax
  mov    %ebp,%r15d
  cmp    $0x12,%eax
  ja     L48
L37:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  call   <putch@plt>
  jmp    L49
  nopl   0x0(%rax)
L43:
  mov    $0x2d,%edi
  neg    %ebx
  call   <putch@plt>
  jmp    L17
  nopl   0x0(%rax)
L48:
  mov    %r15,%r13
  imul   %rdi,%r13
  shr    $0x23,%r13
  lea    0x9(%r13),%eax
  mov    %r13d,%r14d
  cmp    $0x12,%eax
  ja     L18
L76:
  mov    $0xcccccccd,%eax
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  call   <putch@plt>
  jmp    L37
  nop
L18:
  imul   %r14,%rdi
  shr    $0x23,%rdi
  call   <print_int>
  jmp    L76
```

assistant: ```c
void print_int(int i) {
  if (i < 0) {
    putch('-');
    i = -i;
  }
  if (i / 10 != 0) {
    print_int(i / 10);
  }
  putch('0' + (i % 10));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  lea    D1(%rip),%rdx
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <safe_strcat@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <resolve_tilde@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: /

assistant: ```c
char *get_file(char *home, char *file) {
  char *path = safe_strcat(3, home, "/", file);
  char *resolved_path = resolve_tilde(path);
  free(path);
  return resolved_path;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  lea    D0(%rip),%rdx
  mov    %rdi,%rsi
  mov    $0x3,%edi
  call   <safe_strcat@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <resolve_tilde@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: /

assistant: ```c
char *get_file(char *home, char *file) {
  char *path = safe_strcat(3, home, "/", file);
  char *resolved_path = resolve_tilde(path);
  free(path);
  return resolved_path;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_file>:
  endbr64
  push   %r12
  mov    %rsi,%rcx
  lea    D0(%rip),%rdx
  mov    %rdi,%rsi
  push   %rbp
  mov    $0x3,%edi
  sub    $0x8,%rsp
  call   <safe_strcat@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <resolve_tilde@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string

tool: D0: /

assistant: ```c
char *get_file(char *home, char *file) {
  char *path = safe_strcat(3, home, "/", file);
  char *resolved_path = resolve_tilde(path);
  free(path);
  return resolved_path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_file>:
  endbr64
  push   %r12
  mov    %rsi,%rcx
  lea    D1(%rip),%rdx
  mov    %rdi,%rsi
  push   %rbp
  mov    $0x3,%edi
  sub    $0x8,%rsp
  call   <safe_strcat@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <resolve_tilde@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: /

assistant: ```c
char *get_file(char *home, char *file) {
  char *path = safe_strcat(3, home, "/", file);
  char *resolved_path = resolve_tilde(path);
  free(path);
  return resolved_path;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<feupdateenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fetestexcept@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fesetenv@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <feraiseexcept@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int feupdateenv(const fenv_t *envp) {
  int ex = fetestexcept(FE_ALL_EXCEPT);
  fesetenv(envp);
  feraiseexcept(ex);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<feupdateenv>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <fetestexcept@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <fesetenv@plt>
  mov    %ebx,%edi
  call   <feraiseexcept@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int feupdateenv(const fenv_t *envp) {
  int ex = fetestexcept(FE_ALL_EXCEPT);
  fesetenv(envp);
  feraiseexcept(ex);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<feupdateenv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <fetestexcept@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <fesetenv@plt>
  mov    %ebp,%edi
  call   <feraiseexcept@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int feupdateenv(const fenv_t *envp) {
  int ex = fetestexcept(FE_ALL_EXCEPT);
  fesetenv(envp);
  feraiseexcept(ex);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<feupdateenv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <fetestexcept@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <fesetenv@plt>
  mov    %ebp,%edi
  call   <feraiseexcept@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int feupdateenv(const fenv_t *envp) {
  int ex = fetestexcept(FE_ALL_EXCEPT);
  fesetenv(envp);
  feraiseexcept(ex);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D27
type_guessed: string

tool: D27: 


assistant: ```c
int main(int argc, char const *argv[]) {
  printf(argv[0]);
  printf("\n");
  printf(argv[1]);
  printf("\n");
  printf(argv[2]);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    (%rsi),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rbx),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x10(%rbx),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: 


assistant: ```c
int main(int argc, char const *argv[]) {
  printf(argv[0]);
  printf("\n");
  printf(argv[1]);
  printf("\n");
  printf(argv[2]);
  printf("\n");
  return 0;
}
```