ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_station_ifname>:
  endbr64
  push   %rbx
  lea    D18(%rip),%rdi
  call   <if_nametoindex@plt>
  mov    %rax,%rdx
  lea    D18(%rip),%rax
  test   %rdx,%rdx
  jle    L19
L4:
  pop    %rbx
  ret
L19:
  lea    D13(%rip),%rdi
  call   <if_nametoindex@plt>
  mov    %rax,%rdx
  lea    D28(%rip),%rax
  test   %rdx,%rdx
  jle    L4
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <if_nametoindex@plt>
  mov    %rbx,%rax
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D13
type_guessed: string
name: unpack_data
arguments: data_label: D28
type_guessed: string

tool: D18: eth1

tool: D13: wlan1

tool: D28: wlan0

assistant: ```c
char *get_station_ifname(void) {
  if (if_nametoindex("eth1") > 0)
    return "eth1";
  if (if_nametoindex("wlan1") > 0 && if_nametoindex("wlan0") > 0)
    return "wlan0";
  return "wlan0";
}
```
user: What is the c source code of the assembly code below:

```asm
<get_station_ifname>:
  endbr64
  push   %r12
  lea    D26(%rip),%r12
  mov    %r12,%rdi
  call   <if_nametoindex@plt>
  test   %rax,%rax
  jle    L5
L13:
  mov    %r12,%rax
  pop    %r12
  ret
L5:
  lea    D8(%rip),%rdi
  lea    D13(%rip),%r12
  call   <if_nametoindex@plt>
  test   %rax,%rax
  jle    L13
  mov    %r12,%rdi
  call   <if_nametoindex@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
data_type: string
name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string

tool: D26: eth1

tool: D8: wlan1

tool: D13: wlan0

assistant: ```c
char *get_station_ifname(void) {
  if (if_nametoindex("eth1") > 0)
    return "eth1";
  if (if_nametoindex("wlan1") > 0 && if_nametoindex("wlan0") > 0)
    return "wlan0";
  return "wlan0";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_station_ifname>:
  endbr64
  push   %r12
  lea    D27(%rip),%r12
  mov    %r12,%rdi
  call   <if_nametoindex@plt>
  test   %rax,%rax
  jle    L13
L10:
  mov    %r12,%rax
  pop    %r12
  ret
L13:
  lea    D14(%rip),%rdi
  lea    D20(%rip),%r12
  call   <if_nametoindex@plt>
  test   %rax,%rax
  jle    L10
  mov    %r12,%rdi
  call   <if_nametoindex@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D20
type_guessed: string

tool: D27: eth1

tool: D14: wlan1

tool: D20: wlan0

assistant: ```c
char *get_station_ifname(void) {
  if (if_nametoindex("eth1") > 0)
    return "eth1";
  if (if_nametoindex("wlan1") > 0 && if_nametoindex("wlan0") > 0)
    return "wlan0";
  return "wlan0";
}
```
user: Translate the below assembly code into C programming language:

```asm
<prefix_increment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L35:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L2
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L35
  jmp    L29
L2:
  nop
L29:
  pop    %rbp
  ret
```

assistant: ```c
void prefix_increment(uint8_t *prefix) {
  uint8_t i;
  for (i = 0; i < 32; ++i) {
    prefix[i] += 1;
    if (prefix[i] != 0)
      return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prefix_increment>:
  endbr64
  lea    0x80(%rdi),%rdx
L10:
  mov    (%rdi),%eax
  add    $0x1,%eax
  mov    %eax,(%rdi)
  jne    L18
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L10
L18:
  ret
```

assistant: ```c
void prefix_increment(uint8_t *prefix) {
  uint8_t i;
  for (i = 0; i < 32; ++i) {
    prefix[i] += 1;
    if (prefix[i] != 0)
      return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prefix_increment>:
  endbr64
  lea    0x80(%rdi),%rdx
  jmp    L14
  nopl   (%rax)
L2:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L3
L14:
  addl   $0x1,(%rdi)
  je     L2
L3:
  ret
```

assistant: ```c
void prefix_increment(uint8_t *prefix) {
  uint8_t i;
  for (i = 0; i < 32; ++i) {
    prefix[i] += 1;
    if (prefix[i] != 0)
      return;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<prefix_increment>:
  endbr64
  lea    0x80(%rdi),%rdx
  jmp    L25
  nopl   (%rax)
L22:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L28
L25:
  addl   $0x1,(%rdi)
  je     L22
L28:
  ret
```

assistant: ```c
void prefix_increment(uint8_t *prefix) {
  uint8_t i;
  for (i = 0; i < 32; ++i) {
    prefix[i] += 1;
    if (prefix[i] != 0)
      return;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<keccak_squeezeblocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  jmp    L0
L39:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <KeccakF1600_StatePermute@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L7:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  shl    $0x3,%edx
  mov    %edx,%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <store64@plt>
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x2c(%rbp),%eax
  shr    $0x3,%eax
  cmp    %eax,-0x4(%rbp)
  jb     L7
  mov    -0x2c(%rbp),%eax
  add    %rax,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L0:
  cmpq   $0x0,-0x20(%rbp)
  jne    L39
  nop
  nop
  leave
  ret
```

assistant: ```c
void keccak_squeezeblocks(unsigned char *h, unsigned long long int nblocks, uint64_t *s, unsigned int r) {
  unsigned int i;
  while (nblocks > 0) {
    KeccakF1600_StatePermute(s);
    for (i = 0; i < (r >> 3); i++) {
      store64(h + 8 * i, s[i]);
    }
    h += r;
    nblocks--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<keccak_squeezeblocks>:
  endbr64
  test   %rsi,%rsi
  je     L16
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%r15
  mov    %ecx,%eax
  shr    $0x3,%eax
  mov    %eax,0x4(%rsp)
  mov    %ecx,%edx
  mov    %rdx,0x8(%rsp)
  lea    -0x1(%rax),%eax
  lea    0x8(%rdi,%rax,8),%r12
L29:
  mov    %r15,%rdi
  call   <KeccakF1600_StatePermute@plt>
  cmpl   $0x0,0x4(%rsp)
  je     L9
  mov    %r15,%rbp
  mov    %r14,%rbx
L18:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <store64@plt>
  add    $0x4,%rbp
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L18
L9:
  mov    0x8(%rsp),%rax
  add    %rax,%r14
  add    %rax,%r12
  sub    $0x1,%r13
  jne    L29
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  ret
```

assistant: ```c
void keccak_squeezeblocks(unsigned char *h, unsigned long long int nblocks, uint64_t *s, unsigned int r) {
  unsigned int i;
  while (nblocks > 0) {
    KeccakF1600_StatePermute(s);
    for (i = 0; i < (r >> 3); i++) {
      store64(h + 8 * i, s[i]);
    }
    h += r;
    nblocks--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<keccak_squeezeblocks>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  test   %rsi,%rsi
  je     L14
  mov    %ecx,%eax
  mov    %rdi,%r12
  mov    %rdx,%r14
  mov    %ecx,%r13d
  shr    $0x3,%eax
  mov    %eax,0xc(%rsp)
  sub    $0x1,%eax
  lea    0x8(%rdi,%rax,8),%rbx
  nopl   (%rax)
L8:
  mov    %r14,%rdi
  mov    %r14,%rbp
  mov    %r12,%r15
  call   <KeccakF1600_StatePermute@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L25
  xchg   %ax,%ax
L38:
  mov    0x0(%rbp),%esi
  mov    %r15,%rdi
  add    $0x8,%r15
  add    $0x4,%rbp
  call   <store64@plt>
  cmp    %rbx,%r15
  jne    L38
L25:
  add    %r13,%r12
  add    %r13,%rbx
  subq   $0x1,(%rsp)
  jne    L8
L14:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void keccak_squeezeblocks(unsigned char *h, unsigned long long int nblocks, uint64_t *s, unsigned int r) {
  unsigned int i;
  while (nblocks > 0) {
    KeccakF1600_StatePermute(s);
    for (i = 0; i < (r >> 3); i++) {
      store64(h + 8 * i, s[i]);
    }
    h += r;
    nblocks--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<keccak_squeezeblocks>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  test   %rsi,%rsi
  je     L38
  mov    %ecx,%eax
  mov    %rdi,%r12
  mov    %rdx,%r14
  mov    %ecx,%r13d
  shr    $0x3,%eax
  mov    %eax,0xc(%rsp)
  sub    $0x1,%eax
  lea    0x8(%rdi,%rax,8),%rbx
  nopl   (%rax)
L32:
  mov    %r14,%rdi
  mov    %r14,%rbp
  mov    %r12,%r15
  call   <KeccakF1600_StatePermute@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L39
  xchg   %ax,%ax
L10:
  mov    0x0(%rbp),%esi
  mov    %r15,%rdi
  add    $0x8,%r15
  add    $0x4,%rbp
  call   <store64@plt>
  cmp    %rbx,%r15
  jne    L10
L39:
  add    %r13,%r12
  add    %r13,%rbx
  subq   $0x1,(%rsp)
  jne    L32
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void keccak_squeezeblocks(unsigned char *h, unsigned long long int nblocks, uint64_t *s, unsigned int r) {
  unsigned int i;
  while (nblocks > 0) {
    KeccakF1600_StatePermute(s);
    for (i = 0; i < (r >> 3); i++) {
      store64(h + 8 * i, s[i]);
    }
    h += r;
    nblocks--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<softcrc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L8:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <crc_ccitt_update@plt>
  mov    %rax,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L8
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint16_t softcrc(uint16_t seed, uint8_t *data, uint16_t datalen) {
  for (uint16_t i = 0; i < datalen; i++) {
    seed = crc_ccitt_update(seed, data[i]);
  }
  return seed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<softcrc>:
  endbr64
  test   %rdx,%rdx
  je     L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x0,%ebx
L16:
  mov    (%r12,%rbx,4),%esi
  call   <crc_ccitt_update@plt>
  mov    %rax,%rdi
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %rdi,%rax
  ret
```

assistant: ```c
uint16_t softcrc(uint16_t seed, uint8_t *data, uint16_t datalen) {
  for (uint16_t i = 0; i < datalen; i++) {
    seed = crc_ccitt_update(seed, data[i]);
  }
  return seed;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<softcrc>:
  endbr64
  test   %rdx,%rdx
  je     L6
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L13:
  mov    (%r12,%rbx,4),%esi
  add    $0x1,%rbx
  call   <crc_ccitt_update@plt>
  mov    %rax,%rdi
  cmp    %rbx,%rbp
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
uint16_t softcrc(uint16_t seed, uint8_t *data, uint16_t datalen) {
  for (uint16_t i = 0; i < datalen; i++) {
    seed = crc_ccitt_update(seed, data[i]);
  }
  return seed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<softcrc>:
  endbr64
  test   %rdx,%rdx
  je     L3
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L11:
  mov    (%r12,%rbx,4),%esi
  add    $0x1,%rbx
  call   <crc_ccitt_update@plt>
  mov    %rax,%rdi
  cmp    %rbx,%rbp
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rdi,%rax
  ret
```

assistant: ```c
uint16_t softcrc(uint16_t seed, uint8_t *data, uint16_t datalen) {
  for (uint16_t i = 0; i < datalen; i++) {
    seed = crc_ccitt_update(seed, data[i]);
  }
  return seed;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <create_init_state@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  create_init_state();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <create_init_state@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  create_init_state();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <create_init_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  create_init_state();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <create_init_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  create_init_state();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<displayNames>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x3,-0x4(%rbp)
  jle    L15
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: Name[%d] = %s


assistant: ```c
void displayNames(char **names) {
  int i;
  for (i = 0; i < 4; i++)
    printf("Name[%d] = %s\n", i, names[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<displayNames>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D8(%rip),%r12
L4:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: Name[%d] = %s


assistant: ```c
void displayNames(char **names) {
  int i;
  for (i = 0; i < 4; i++)
    printf("Name[%d] = %s\n", i, names[i]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<displayNames>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L3:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: Name[%d] = %s


assistant: ```c
void displayNames(char **names) {
  int i;
  for (i = 0; i < 4; i++)
    printf("Name[%d] = %s\n", i, names[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<displayNames>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L5:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D7: Name[%d] = %s


assistant: ```c
void displayNames(char **names) {
  int i;
  for (i = 0; i < 4; i++)
    printf("Name[%d] = %s\n", i, names[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<skip_leading_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L16
L3:
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L3
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *skip_leading_spaces(const char *str) {
  while (*str == ' ') {
    str++;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skip_leading_spaces>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x20,(%rdi)
  jne    L2
L16:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L16
L2:
  ret
```

assistant: ```c
const char *skip_leading_spaces(const char *str) {
  while (*str == ' ') {
    str++;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<skip_leading_spaces>:
  endbr64
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rax
  jne    L2
  nopl   0x0(%rax)
L18:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L18
L2:
  ret
```

assistant: ```c
const char *skip_leading_spaces(const char *str) {
  while (*str == ' ') {
    str++;
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skip_leading_spaces>:
  endbr64
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rax
  jne    L17
  nopl   0x0(%rax)
L8:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L8
L17:
  ret
```

assistant: ```c
const char *skip_leading_spaces(const char *str) {
  while (*str == ' ') {
    str++;
  }
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<traverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L7:
  cmp    %rdx,%rsp
  je     L28
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L28:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L73
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L73:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x1,-0x2c(%rbp)
  jmp    L10
L76:
  mov    -0x20(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  movl   $0x0,(%rax,%rdx,4)
  addl   $0x1,-0x2c(%rbp)
L10:
  mov    -0x2c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L76
  movl   $0x1,-0x2c(%rbp)
  jmp    L66
L2:
  mov    -0x20(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  test   %eax,%eax
  jne    L41
  mov    -0x20(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x3c(%rbp),%esi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <__bfs@plt>
L41:
  addl   $0x1,-0x2c(%rbp)
L66:
  mov    -0x2c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L2
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void traverse(int (*a)[100], int n) {
  int visited[n + 1];
  int i;
  for (i = 1; i <= n; i++) {
    visited[i] = 0;
  }
  for (i = 1; i <= n; i++) {
    if (!visited[i])
      __bfs(a, n, i, visited);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<traverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L75:
  cmp    %rdx,%rsp
  je     L48
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L75
L48:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L93
  orq    $0x0,-0x8(%rsp,%rax,1)
L93:
  mov    %rsp,%r13
  test   %r12d,%r12d
  jle    L3
  lea    0x4(%r13),%rax
  lea    -0x1(%r12),%edx
  lea    0x8(%r13,%rdx,4),%rdx
L76:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L76
  mov    $0x1,%ebx
  jmp    L14
L30:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L3
L14:
  mov    %ebx,%edx
  cmpl   $0x0,0x0(%r13,%rbx,4)
  jne    L30
  mov    %r13,%rcx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <__bfs@plt>
  jmp    L30
L3:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void traverse(int (*a)[100], int n) {
  int visited[n + 1];
  int i;
  for (i = 1; i <= n; i++) {
    visited[i] = 0;
  }
  for (i = 1; i <= n; i++) {
    if (!visited[i])
      __bfs(a, n, i, visited);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<traverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  mov    %rsp,%rcx
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L13
L51:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L51
L13:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L26
L71:
  mov    %rsp,%r13
  test   %r12d,%r12d
  jle    L58
  movslq %r12d,%rdx
  lea    0x4(%r13),%rdi
  xor    %esi,%esi
  mov    $0x1,%ebx
  shl    $0x2,%rdx
  call   <memset@plt>
  jmp    L18
  nopl   0x0(%rax)
L66:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L58
L18:
  mov    0x0(%r13,%rbx,4),%eax
  mov    %ebx,%edx
  test   %eax,%eax
  jne    L66
  mov    %r13,%rcx
  mov    %r12d,%esi
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <__bfs@plt>
  cmp    %ebx,%r12d
  jge    L18
L58:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nop
L26:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L71
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void traverse(int (*a)[100], int n) {
  int visited[n + 1];
  int i;
  for (i = 1; i <= n; i++) {
    visited[i] = 0;
  }
  for (i = 1; i <= n; i++) {
    if (!visited[i])
      __bfs(a, n, i, visited);
  }
}
```