user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x3dcccccd,0x24(%rsp)
  movl   $0x3e4ccccd,0x28(%rsp)
  movl   $0x3e99999a,0x2c(%rsp)
  movl   $0x3ecccccd,0x30(%rsp)
  movl   $0x3f000000,0x34(%rsp)
  mov    $0x1,%eax
  movsd  D88(%rip),%xmm2
L37:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movapd %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x40(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L37
  lea    0x20(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x40(%rsp),%rdi
  mov    $0x5,%ecx
  mov    $0x0,%eax
  call   <toeplz@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  mov    %rsp,%r14
  lea    D58(%rip),%r13
  lea    D76(%rip),%r12
  lea    D52(%rip),%rbp
L45:
  pxor   %xmm0,%xmm0
  cvtss2sd (%r14,%rbx,4),%xmm0
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L45
  lea    D67(%rip),%rdi
  call   <puts@plt>
  lea    D91(%rip),%rdx
  lea    D80(%rip),%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%r12
  lea    0x54(%rsp),%rbp
  lea    D71(%rip),%r13
L15:
  mov    %rsp,%rax
  lea    0x14(%rsp),%rcx
  mov    %rbp,%rdx
  pxor   %xmm0,%xmm0
L32:
  movss  (%rdx),%xmm1
  mulss  0x4(%rax),%xmm1
  addss  %xmm1,%xmm0
  sub    $0x4,%rdx
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L32
  cvtss2sd %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%r12),%xmm1
  mov    %r13,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x4,%r12
  add    $0x4,%rbp
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L15
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D88
data_type: f64
name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D58
data_type: string
name: extract_symbolic_data
arguments: label: D76
data_type: string
name: extract_symbolic_data
arguments: label: D52
data_type: string
name: extract_symbolic_data
arguments: label: D67
data_type: string
name: extract_symbolic_data
arguments: label: D91
data_type: string
name: extract_symbolic_data
arguments: label: D80
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D71
data_type: string

tool: D88: 1

tool: D9: Solution vector:

tool: D58: ] =

tool: D76: x[

tool: D52: %7s%1d%s %13f


tool: D67: 
Test of solution:

tool: D91: original

tool: D80: mtrx*soln

tool: D0: %13s %12s


tool: D71: %12.4f %12.4f


assistant: ```c
int main(void) {
  int i, j;
  float sum, r[(2 * 5) + 1], x[5 + 1], y[5 + 1];
  for (i = 1; i <= 5; i++)
    y[i] = 0.1 * i;
  for (i = 1; i < (2 * 5); i++)
    r[i] = 1.0 / i;
  toeplz(r, x, y, 5);
  printf("Solution vector:\n");
  for (i = 1; i <= 5; i++)
    printf("%7s%1d%s %13f\n", "x[", i, "] =", x[i]);
  printf("\nTest of solution:\n");
  printf("%13s %12s\n", "mtrx*soln", "original");
  for (i = 1; i <= 5; i++) {
    sum = 0.0;
    for (j = 1; j <= 5; j++)
      sum += (r[5 + i - j] * x[j]);
    printf("%12.4f %12.4f\n", sum, y[i]);
  }
  return 0;
}
```