ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<stage_cu>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x50001004,%edi
  call   <Xil_Out32@plt>
  mov    $0xbf0b0004,%esi
  mov    $0x50001000,%edi
  call   <Xil_Out32@plt>
  mov    $0x4,%esi
  mov    $0x50001004,%edi
  call   <Xil_Out32@plt>
  mov    $0xbf810000,%esi
  mov    $0x50001000,%edi
  call   <Xil_Out32@plt>
  xor    %esi,%esi
  mov    $0x50002004,%edi
  call   <Xil_Out32@plt>
  mov    $0xc,%esi
  mov    $0x50002008,%edi
  call   <Xil_Out32@plt>
  mov    $0x8,%esi
  mov    $0x5000200c,%edi
  call   <Xil_Out32@plt>
  mov    $0x9,%esi
  mov    $0x50002010,%edi
  call   <Xil_Out32@plt>
  mov    $0xf,%esi
  mov    $0x50002014,%edi
  call   <Xil_Out32@plt>
  mov    $0x1,%esi
  mov    $0x50002000,%edi
  call   <Xil_Out32@plt>
  mov    $0x10,%esi
  mov    $0x50002004,%edi
  call   <Xil_Out32@plt>
  mov    $0x1,%esi
  mov    $0x50002008,%edi
  call   <Xil_Out32@plt>
  mov    $0x21,%esi
  mov    $0x5000200c,%edi
  call   <Xil_Out32@plt>
  mov    $0x29,%esi
  mov    $0x50002010,%edi
  call   <Xil_Out32@plt>
  mov    $0x2c,%esi
  mov    $0x50002014,%edi
  call   <Xil_Out32@plt>
  mov    $0x1,%esi
  mov    $0x50002000,%edi
  call   <Xil_Out32@plt>
  mov    $0x20,%esi
  mov    $0x50002004,%edi
  call   <Xil_Out32@plt>
  mov    $0x23,%esi
  mov    $0x50002008,%edi
  call   <Xil_Out32@plt>
  mov    $0x2d,%esi
  mov    $0x5000200c,%edi
  call   <Xil_Out32@plt>
  xor    %esi,%esi
  mov    $0x50002010,%edi
  call   <Xil_Out32@plt>
  xor    %esi,%esi
  mov    $0x50002014,%edi
  call   <Xil_Out32@plt>
  mov    $0x1,%esi
  mov    $0x50002000,%edi
  add    $0x8,%rsp
  jmp    1050 <Xil_Out32@plt>
```

assistant: ```c
void stage_cu() {
  Xil_Out32(0x50001004, 0);
  Xil_Out32(0x50001000, 0xBF0B0004);
  Xil_Out32(0x50001004, 4);
  Xil_Out32(0x50001000, 0xBF810000);
  Xil_Out32(0x50002004, 0);
  Xil_Out32(0x50002008, 0xC);
  Xil_Out32(0x5000200C, 0x8);
  Xil_Out32(0x50002010, 0x9);
  Xil_Out32(0x50002014, 0xF);
  Xil_Out32(0x50002000, 1);
  Xil_Out32(0x50002004, 16);
  Xil_Out32(0x50002008, 0x1);
  Xil_Out32(0x5000200C, 0x21);
  Xil_Out32(0x50002010, 0x29);
  Xil_Out32(0x50002014, 0x2C);
  Xil_Out32(0x50002000, 1);
  Xil_Out32(0x50002004, 32);
  Xil_Out32(0x50002008, 0x23);
  Xil_Out32(0x5000200C, 0x2D);
  Xil_Out32(0x50002010, 0x0);
  Xil_Out32(0x50002014, 0x0);
  Xil_Out32(0x50002000, 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<LZ4_freeMC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int LZ4_freeMC(void *LZ4MC_Data) {
  free(LZ4MC_Data);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LZ4_freeMC>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int LZ4_freeMC(void *LZ4MC_Data) {
  free(LZ4MC_Data);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LZ4_freeMC>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int LZ4_freeMC(void *LZ4MC_Data) {
  free(LZ4MC_Data);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LZ4_freeMC>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int LZ4_freeMC(void *LZ4MC_Data) {
  free(LZ4MC_Data);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<selection_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L36:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L4
L27:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L22
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L22:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void selection_sort(int arr[], int len) {
  int i, j;
  int tmp;
  for (i = 0; i < len; i++)
    for (j = i; j < len; j++)
      if (arr[j] < arr[i]) {
        tmp = arr[j];
        arr[j] = arr[i];
        arr[i] = tmp;
      }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<selection_sort>:
  endbr64
  test   %esi,%esi
  jle    L56
  push   %rbx
  lea    -0x1(%rsi),%ebx
  mov    %esi,%r11d
  mov    %rdi,%r8
  mov    $0x0,%r9d
  lea    0x4(%rdi),%r10
  jmp    L8
L38:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L31
L11:
  mov    (%rax),%edx
  mov    (%r8),%ecx
  cmp    %ecx,%edx
  jge    L38
  mov    %ecx,(%rax)
  mov    %edx,(%r8)
  jmp    L38
L31:
  add    $0x1,%r9
  add    $0x4,%r8
  cmp    %r11,%r9
  je     L60
L8:
  cmp    %r9d,%esi
  jle    L31
  mov    %ebx,%eax
  sub    %r9d,%eax
  add    %r9,%rax
  lea    (%r10,%rax,4),%rdi
  mov    %r8,%rax
  jmp    L11
L60:
  pop    %rbx
  ret
L56:
  ret
```

assistant: ```c
void selection_sort(int arr[], int len) {
  int i, j;
  int tmp;
  for (i = 0; i < len; i++)
    for (j = i; j < len; j++)
      if (arr[j] < arr[i]) {
        tmp = arr[j];
        arr[j] = arr[i];
        arr[i] = tmp;
      }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<selection_sort>:
  endbr64
  test   %esi,%esi
  jle    L1
  mov    %rdi,%r8
  movslq %esi,%r10
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L3:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L7:
  mov    (%rdi,%rax,4),%edx
  mov    (%r8),%ecx
  cmp    %ecx,%edx
  jge    L35
  mov    %ecx,(%rdi,%rax,4)
  mov    %edx,(%r8)
L35:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L7
  add    $0x1,%r9
  add    $0x4,%r8
  cmp    %r10,%r9
  jne    L3
L1:
  ret
```

assistant: ```c
void selection_sort(int arr[], int len) {
  int i, j;
  int tmp;
  for (i = 0; i < len; i++)
    for (j = i; j < len; j++)
      if (arr[j] < arr[i]) {
        tmp = arr[j];
        arr[j] = arr[i];
        arr[i] = tmp;
      }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<selection_sort>:
  endbr64
  movslq %esi,%r9
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L0
  xchg   %ax,%ax
L30:
  mov    (%rdi,%r8,4),%ecx
  mov    %r8,%rax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L31
  mov    %ecx,(%rdi,%rax,4)
  mov    %edx,%ecx
  mov    %edx,(%rdi,%r8,4)
L31:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L6
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L30
L0:
  ret
```

assistant: ```c
void selection_sort(int arr[], int len) {
  int i, j;
  int tmp;
  for (i = 0; i < len; i++)
    for (j = i; j < len; j++)
      if (arr[j] < arr[i]) {
        tmp = arr[j];
        arr[j] = arr[i];
        arr[i] = tmp;
      }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *ax(q) {
  void *s = malloc(q);
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ax>:
  endbr64
  sub    $0x8,%rsp
  movslq %edi,%rdi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *ax(q) {
  void *s = malloc(q);
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ax>:
  endbr64
  movslq %edi,%rdi
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *ax(q) {
  void *s = malloc(q);
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ax>:
  endbr64
  movslq %edi,%rdi
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *ax(q) {
  void *s = malloc(q);
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<duration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x3c,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  imul   $0xffffffff88888889,%rcx,%rcx
  shr    $0x20,%rcx
  add    %edx,%ecx
  sar    $0x5,%ecx
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  mov    %eax,%ecx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D0(%rip),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string

tool: D25: %2d:%02d

assistant: ```c
const char *duration(time_t start) {
  static char buf[16];
  int t = (int)(time(NULL) - start);
  sprintf(buf, "%2d:%02d", t / 60, t % 60);
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<duration>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <time@plt>
  sub    %ebx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3c,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  lea    D18(%rip),%rsi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
data_type: string

tool: D18: %2d:%02d

assistant: ```c
const char *duration(time_t start) {
  static char buf[16];
  int t = (int)(time(NULL) - start);
  sprintf(buf, "%2d:%02d", t / 60, t % 60);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<duration>:
  endbr64
  push   %r12
  lea    D15(%rip),%r12
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %r12,%rdi
  sub    %ebx,%eax
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sub    %ecx,%edx
  imul   $0x3c,%edx,%esi
  sub    %esi,%eax
  lea    D10(%rip),%rsi
  mov    %eax,%ecx
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: string

tool: D10: %2d:%02d

assistant: ```c
const char *duration(time_t start) {
  static char buf[16];
  int t = (int)(time(NULL) - start);
  sprintf(buf, "%2d:%02d", t / 60, t % 60);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<duration>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %r12,%rdi
  sub    %ebx,%eax
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sub    %ecx,%edx
  imul   $0x3c,%edx,%esi
  sub    %esi,%eax
  lea    D19(%rip),%rsi
  mov    %eax,%ecx
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type: string

tool: D19: %2d:%02d

assistant: ```c
const char *duration(time_t start) {
  static char buf[16];
  int t = (int)(time(NULL) - start);
  sprintf(buf, "%2d:%02d", t / 60, t % 60);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_openssl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <SSL_load_error_strings@plt>
  mov    $0x0,%eax
  call   <OpenSSL_add_ssl_algorithms@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: 2


assistant: ```c
void init_openssl() {
  printf("2\n");
  SSL_load_error_strings();
  OpenSSL_add_ssl_algorithms();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_openssl>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <SSL_load_error_strings@plt>
  mov    $0x0,%eax
  call   <OpenSSL_add_ssl_algorithms@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: 2


assistant: ```c
void init_openssl() {
  printf("2\n");
  SSL_load_error_strings();
  OpenSSL_add_ssl_algorithms();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<init_openssl>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <SSL_load_error_strings@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <OpenSSL_add_ssl_algorithms@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: 2


assistant: ```c
void init_openssl() {
  printf("2\n");
  SSL_load_error_strings();
  OpenSSL_add_ssl_algorithms();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<init_openssl>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <SSL_load_error_strings@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <OpenSSL_add_ssl_algorithms@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: 2


assistant: ```c
void init_openssl() {
  printf("2\n");
  SSL_load_error_strings();
  OpenSSL_add_ssl_algorithms();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pencil_dtrmv_n_nun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  shl    $0x3,%rax
  mov    %rax,-0x48(%rbp)
  test   %edi,%edi
  jle    L3
  mov    %edi,%r12d
  mov    %rdx,%r10
  movslq %ecx,%rcx
  shl    $0x3,%rcx
  mov    %r8,%r9
  lea    0x8(%rax),%rbx
  mov    %rbx,-0x50(%rbp)
  mov    %rdx,%r11
  lea    0x1(%rdi),%r15d
  mov    $0x1,%edi
  lea    0xf(%rax),%r14
  mov    %r14,%rax
  and    $0xfffffffffffff000,%rax
  mov    %rax,-0x58(%rbp)
  and    $0xff0,%r14d
  lea    -0x8(%r14),%rax
  mov    %rax,-0x60(%rbp)
  jmp    L89
L82:
  sub    %r14,%rsp
  test   %r14,%r14
  je     L84
  mov    -0x60(%rbp),%rax
  orq    $0x0,(%rsp,%rax,1)
L84:
  mov    %rsp,%rbx
  movslq %r8d,%rax
  movq   $0x0,(%rbx,%rax,8)
  mov    %r12d,%eax
  sub    %edx,%eax
  js     L40
  mov    %eax,%eax
  lea    -0x1(%rdi,%rax,1),%rax
  lea    0x8(%r10,%rax,8),%rsi
  mov    %r9,%rdx
  mov    %r11,%rax
  pxor   %xmm1,%xmm1
L85:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  add    %rcx,%rdx
  cmp    %rsi,%rax
  jne    L85
  movslq %r8d,%rax
  movsd  %xmm1,(%rbx,%rax,8)
L40:
  movslq %r8d,%r8
  movsd  (%rbx,%r8,8),%xmm0
  movsd  %xmm0,(%r9)
  mov    %r13,%rsp
  add    $0x1,%rdi
  add    %rcx,%r9
  add    -0x50(%rbp),%r11
  add    -0x48(%rbp),%r10
  cmp    %r15,%rdi
  je     L3
L89:
  mov    %edi,%edx
  lea    -0x1(%rdi),%r8d
  mov    %rsp,%r13
  mov    %rsp,%rax
  sub    -0x58(%rbp),%rax
L59:
  cmp    %rax,%rsp
  je     L82
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L59
L3:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void pencil_dtrmv_n_nun(int n_8292_8308, int ldAT_8293_8309, double AT_8294_8310[restrict const n_8292_8308][n_8292_8308], int incX_8295_8311, double X_8296_8312[restrict const n_8292_8308][incX_8295_8311]) {
#pragma scop
  {
    for (int i_2447_1705_4072_10751 = 0; i_2447_1705_4072_10751 <= (n_8292_8308 - 1); i_2447_1705_4072_10751 += 1) {
      double accum_2449_1707_4073_10750[n_8292_8308];
      accum_2449_1707_4073_10750[i_2447_1705_4072_10751] = 0.0;
      for (int i_2450_1708_4074_10752 = 0; i_2450_1708_4074_10752 <= ((((n_8292_8308 - 1) - i_2447_1705_4072_10751) + 1) - 1); i_2450_1708_4074_10752 += 1) {
        accum_2449_1707_4073_10750[i_2447_1705_4072_10751] = (accum_2449_1707_4073_10750[i_2447_1705_4072_10751] + (AT_8294_8310[i_2447_1705_4072_10751][(i_2447_1705_4072_10751 + i_2450_1708_4074_10752)] * X_8296_8312[(i_2447_1705_4072_10751 + i_2450_1708_4074_10752)][0]));
      }
      X_8296_8312[i_2447_1705_4072_10751][0] = accum_2449_1707_4073_10750[i_2447_1705_4072_10751];
    }
  }
#pragma endscop
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pencil_dtrmv_n_nun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  movslq %edi,%r13
  push   %r12
  shl    $0x3,%r13
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L43
  lea    0xf(%r13),%rax
  movslq %ecx,%rcx
  mov    %rdx,%r11
  sub    $0x1,%edi
  mov    %rax,%rsi
  and    $0xff0,%eax
  shl    $0x3,%rcx
  mov    %r8,%r9
  mov    %rax,-0x50(%rbp)
  sub    $0x8,%rax
  lea    0x8(%r13),%r15
  mov    %rdx,%rbx
  and    $0xfffffffffffff000,%rsi
  mov    %rax,-0x58(%rbp)
  xor    %r10d,%r10d
  mov    %rsi,-0x48(%rbp)
L21:
  mov    %rsp,%rax
  sub    -0x48(%rbp),%rax
  movslq %r10d,%r8
  mov    %rsp,%r12
  cmp    %rax,%rsp
  je     L9
L50:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L50
L9:
  mov    -0x50(%rbp),%rax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L41
  mov    -0x58(%rbp),%rax
  orq    $0x0,(%rsp,%rax,1)
L41:
  mov    %edi,%eax
  mov    %rsp,%r14
  pxor   %xmm1,%xmm1
  mov    %r9,%rdx
  add    %r10,%rax
  lea    0x8(%rbx,%rax,8),%rsi
  mov    %r11,%rax
  nopl   0x0(%rax,%rax,1)
L22:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rcx,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L22
  sub    $0x1,%edi
  movsd  %xmm1,(%r9)
  add    $0x1,%r10
  add    %rcx,%r9
  movsd  %xmm1,(%r14,%r8,8)
  add    %r15,%r11
  add    %r13,%rbx
  mov    %r12,%rsp
  cmp    $0xffffffff,%edi
  jne    L21
L43:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void pencil_dtrmv_n_nun(int n_8292_8308, int ldAT_8293_8309, double AT_8294_8310[restrict const n_8292_8308][n_8292_8308], int incX_8295_8311, double X_8296_8312[restrict const n_8292_8308][incX_8295_8311]) {
#pragma scop
  {
    for (int i_2447_1705_4072_10751 = 0; i_2447_1705_4072_10751 <= (n_8292_8308 - 1); i_2447_1705_4072_10751 += 1) {
      double accum_2449_1707_4073_10750[n_8292_8308];
      accum_2449_1707_4073_10750[i_2447_1705_4072_10751] = 0.0;
      for (int i_2450_1708_4074_10752 = 0; i_2450_1708_4074_10752 <= ((((n_8292_8308 - 1) - i_2447_1705_4072_10751) + 1) - 1); i_2450_1708_4074_10752 += 1) {
        accum_2449_1707_4073_10750[i_2447_1705_4072_10751] = (accum_2449_1707_4073_10750[i_2447_1705_4072_10751] + (AT_8294_8310[i_2447_1705_4072_10751][(i_2447_1705_4072_10751 + i_2450_1708_4074_10752)] * X_8296_8312[(i_2447_1705_4072_10751 + i_2450_1708_4074_10752)][0]));
      }
      X_8296_8312[i_2447_1705_4072_10751][0] = accum_2449_1707_4073_10750[i_2447_1705_4072_10751];
    }
  }
#pragma endscop
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pencil_dtrmv_n_nun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  movslq %edi,%r13
  push   %r12
  shl    $0x3,%r13
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L7
  lea    0xf(%r13),%rax
  movslq %ecx,%rcx
  mov    %rdx,%r11
  sub    $0x1,%edi
  mov    %rax,%rsi
  and    $0xff0,%eax
  shl    $0x3,%rcx
  mov    %r8,%r9
  mov    %rax,-0x50(%rbp)
  sub    $0x8,%rax
  lea    0x8(%r13),%r15
  mov    %rdx,%rbx
  and    $0xfffffffffffff000,%rsi
  mov    %rax,-0x58(%rbp)
  xor    %r10d,%r10d
  mov    %rsi,-0x48(%rbp)
L19:
  mov    %rsp,%rax
  sub    -0x48(%rbp),%rax
  movslq %r10d,%r8
  mov    %rsp,%r12
  cmp    %rax,%rsp
  je     L37
L53:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L53
L37:
  mov    -0x50(%rbp),%rax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L58
  mov    -0x58(%rbp),%rax
  orq    $0x0,(%rsp,%rax,1)
L58:
  mov    %edi,%eax
  mov    %rsp,%r14
  pxor   %xmm1,%xmm1
  mov    %r9,%rdx
  add    %r10,%rax
  lea    0x8(%rbx,%rax,8),%rsi
  mov    %r11,%rax
  nopl   0x0(%rax,%rax,1)
L65:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rcx,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L65
  sub    $0x1,%edi
  movsd  %xmm1,(%r9)
  add    $0x1,%r10
  add    %rcx,%r9
  movsd  %xmm1,(%r14,%r8,8)
  add    %r15,%r11
  add    %r13,%rbx
  mov    %r12,%rsp
  cmp    $0xffffffff,%edi
  jne    L19
L7:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void pencil_dtrmv_n_nun(int n_8292_8308, int ldAT_8293_8309, double AT_8294_8310[restrict const n_8292_8308][n_8292_8308], int incX_8295_8311, double X_8296_8312[restrict const n_8292_8308][incX_8295_8311]) {
#pragma scop
  {
    for (int i_2447_1705_4072_10751 = 0; i_2447_1705_4072_10751 <= (n_8292_8308 - 1); i_2447_1705_4072_10751 += 1) {
      double accum_2449_1707_4073_10750[n_8292_8308];
      accum_2449_1707_4073_10750[i_2447_1705_4072_10751] = 0.0;
      for (int i_2450_1708_4074_10752 = 0; i_2450_1708_4074_10752 <= ((((n_8292_8308 - 1) - i_2447_1705_4072_10751) + 1) - 1); i_2450_1708_4074_10752 += 1) {
        accum_2449_1707_4073_10750[i_2447_1705_4072_10751] = (accum_2449_1707_4073_10750[i_2447_1705_4072_10751] + (AT_8294_8310[i_2447_1705_4072_10751][(i_2447_1705_4072_10751 + i_2450_1708_4074_10752)] * X_8296_8312[(i_2447_1705_4072_10751 + i_2450_1708_4074_10752)][0]));
      }
      X_8296_8312[i_2447_1705_4072_10751][0] = accum_2449_1707_4073_10750[i_2447_1705_4072_10751];
    }
  }
#pragma endscop
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parse_numwords>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L38
  mov    -0x4(%rbp),%eax
  jmp    L24
L38:
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x13,-0x4(%rbp)
  jle    L17
  mov    $0x14,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int parse_numwords(char **words) {
  int i;
  for (i = 0; i < 20; ++i)
    if (words[i] == NULL)
      return i;
  return 20;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_numwords>:
  endbr64
  mov    $0x0,%eax
L1:
  mov    %eax,%edx
  cmpq   $0x0,(%rdi,%rax,8)
  je     L6
  add    $0x1,%rax
  cmp    $0x14,%rax
  jne    L1
  mov    $0x14,%edx
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
int parse_numwords(char **words) {
  int i;
  for (i = 0; i < 20; ++i)
    if (words[i] == NULL)
      return i;
  return 20;
}
```