ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itoaa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L18
  negl   -0x14(%rbp)
L18:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L18
  cmpl   $0x0,-0x4(%rbp)
  jns    L24
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x2d,(%rax)
L24:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reversee@plt>
  nop
  leave
  ret
```

assistant: ```c
void itoaa(int n, char *s) {
  int sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    *s++ = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    *s++ = '-';
  *s = '\0';
  reversee(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<itoaa>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%r8d
  mov    %rsi,%rdi
  mov    %r8d,%edx
  neg    %edx
  cmovs  %r8d,%edx
L14:
  mov    %rdi,%r9
  add    $0x1,%rdi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%rdi)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L14
  test   %r8d,%r8d
  js     L16
L2:
  movb   $0x0,(%rdi)
  call   <reversee@plt>
  add    $0x8,%rsp
  ret
L16:
  movb   $0x2d,(%rdi)
  lea    0x2(%r9),%rdi
  jmp    L2
```

assistant: ```c
void itoaa(int n, char *s) {
  int sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    *s++ = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    *s++ = '-';
  *s = '\0';
  reversee(s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoaa>:
  endbr64
  mov    %edi,%r9d
  mov    $0xcccccccd,%r8d
  mov    %rsi,%rdi
  mov    %r9d,%edx
  neg    %edx
  cmovs  %r9d,%edx
  nopl   0x0(%rax)
L11:
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %rdi,%r10
  imul   %r8,%rax
  add    $0x1,%rdi
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%rdi)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L11
  test   %r9d,%r9d
  jns    L18
  movb   $0x2d,(%rdi)
  lea    0x2(%r10),%rdi
L18:
  movb   $0x0,(%rdi)
  jmp    1050 <reversee@plt>
```

assistant: ```c
void itoaa(int n, char *s) {
  int sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    *s++ = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    *s++ = '-';
  *s = '\0';
  reversee(s);
}
```
user: What is the c source code of the assembly code below?

```asm
<itoaa>:
  endbr64
  mov    %edi,%r9d
  mov    $0xcccccccd,%r8d
  mov    %rsi,%rdi
  mov    %r9d,%edx
  neg    %edx
  cmovs  %r9d,%edx
  nopl   0x0(%rax)
L19:
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %rdi,%r10
  imul   %r8,%rax
  add    $0x1,%rdi
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%rdi)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L19
  test   %r9d,%r9d
  jns    L6
  movb   $0x2d,(%rdi)
  lea    0x2(%r10),%rdi
L6:
  movb   $0x0,(%rdi)
  jmp    1050 <reversee@plt>
```

assistant: ```c
void itoaa(int n, char *s) {
  int sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    *s++ = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    *s++ = '-';
  *s = '\0';
  reversee(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x63616548,-0x12(%rbp)
  movb   $0x0,-0xe(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  char word[] = {'H', 'e', 'a', 'c', '\0'};
  return 0;
  char *str = "Hello";
  char woord[] = "Hello";
  char wrd[10] = "Hello";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  char word[] = {'H', 'e', 'a', 'c', '\0'};
  return 0;
  char *str = "Hello";
  char woord[] = "Hello";
  char wrd[10] = "Hello";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char word[] = {'H', 'e', 'a', 'c', '\0'};
  return 0;
  char *str = "Hello";
  char woord[] = "Hello";
  char wrd[10] = "Hello";
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_46_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_46_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D ^ T;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_46_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  xor    $0xff,%al
  or     %edi,%eax
  xor    %esi,%eax
  mov    %esi,%edx
  not    %edx
  or     %edi,%edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_46_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D ^ T;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_46_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  mov    %esi,%edx
  xor    $0xff,%al
  not    %edx
  or     %edi,%eax
  or     %edi,%edx
  not    %edi
  xor    %esi,%eax
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_46_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D ^ T;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_46_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  mov    %esi,%edx
  xor    $0xff,%al
  not    %edx
  or     %edi,%eax
  or     %edi,%edx
  not    %edi
  xor    %esi,%eax
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_46_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D ^ T;
  stk2 = S | stk3;
  stk1 = T ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What is the c source code of the assembly code below:

```asm
<mp3_trim_tag_v1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L30
L26:
  subq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L10
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L26
L10:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t mp3_trim_tag_v1(const char *str, size_t max) {
  const char *end;
  end = memchr(str, '\0', max);
  if (end == NULL) {
    end = str + max;
  }
  while (isspace(end[-1]) && end != str)
    end--;
  return end - str;
}
```
user: What is the c source code of the assembly code below:

```asm
<mp3_trim_tag_v1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <memchr@plt>
  mov    %rax,%rbx
  add    %rbp,%r12
  test   %rax,%rax
  cmove  %r12,%rbx
L14:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  cmp    %rbp,%rbx
  je     L5
  test   %rax,%rax
  je     L5
  sub    $0x1,%rbx
  jmp    L14
L5:
  mov    %rbx,%rax
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t mp3_trim_tag_v1(const char *str, size_t max) {
  const char *end;
  end = memchr(str, '\0', max);
  if (end == NULL) {
    end = str + max;
  }
  while (isspace(end[-1]) && end != str)
    end--;
  return end - str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mp3_trim_tag_v1>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  add    %rbp,%r12
  call   <memchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  cmove  %r12,%rbx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L28:
  cmp    %rbp,%rbx
  je     L2
  sub    $0x1,%rbx
L9:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
L2:
  mov    %rbx,%rax
  pop    %rbx
  sub    %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t mp3_trim_tag_v1(const char *str, size_t max) {
  const char *end;
  end = memchr(str, '\0', max);
  if (end == NULL) {
    end = str + max;
  }
  while (isspace(end[-1]) && end != str)
    end--;
  return end - str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mp3_trim_tag_v1>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  add    %rbp,%r12
  call   <memchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  cmove  %r12,%rbx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L4:
  cmp    %rbp,%rbx
  je     L10
  sub    $0x1,%rbx
L2:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
L10:
  mov    %rbx,%rax
  pop    %rbx
  sub    %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t mp3_trim_tag_v1(const char *str, size_t max) {
  const char *end;
  end = memchr(str, '\0', max);
  if (end == NULL) {
    end = str + max;
  }
  while (isspace(end[-1]) && end != str)
    end--;
  return end - str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L6
  negl   -0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int abs(int n) {
  if (n < 0)
    n = 0 - n;
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int n) {
  if (n < 0)
    n = 0 - n;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int n) {
  if (n < 0)
    n = 0 - n;
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_has_item_returns_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <dynamic_array_create@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <has_item@plt>
  cmp    $0xffffffff,%eax
  je     L24
  lea    D2(%rip),%rax
  jmp    L4
L24:
  mov    -0x8(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <append_item@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <has_item@plt>
  test   %eax,%eax
  je     L8
  lea    D8(%rip),%rax
  jmp    L4
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_dynamic_array@plt>
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D2: has_item does not detect item 5

tool: D8: has_item returns index of item 5

assistant: ```c
char *test_has_item_returns_index(void) {
  struct Dynamic_Array *da = dynamic_array_create(2, 2);
  do {
    if (!(has_item(da, 5) == -1))
      return "has_item does not detect item 5";
  } while (0);
  append_item(da, 5);
  do {
    if (!(has_item(da, 5) == 0))
      return "has_item returns index of item 5";
  } while (0);
  free_dynamic_array(da);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_has_item_returns_index>:
  endbr64
  push   %rbx
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <dynamic_array_create@plt>
  mov    %rax,%rbx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <has_item@plt>
  mov    %eax,%edx
  lea    D17(%rip),%rax
  cmp    $0xffffffff,%edx
  je     L18
L21:
  pop    %rbx
  ret
L18:
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <append_item@plt>
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <has_item@plt>
  mov    %eax,%edx
  lea    D8(%rip),%rax
  test   %edx,%edx
  jne    L21
  mov    %rbx,%rdi
  call   <free_dynamic_array@plt>
  mov    $0x0,%eax
  jmp    L21
```

tool_calls: name: parse_data
arguments: tag: D17
data_type: string
name: parse_data
arguments: tag: D8
data_type: string

tool: D17: has_item does not detect item 5

tool: D8: has_item returns index of item 5

assistant: ```c
char *test_has_item_returns_index(void) {
  struct Dynamic_Array *da = dynamic_array_create(2, 2);
  do {
    if (!(has_item(da, 5) == -1))
      return "has_item does not detect item 5";
  } while (0);
  append_item(da, 5);
  do {
    if (!(has_item(da, 5) == 0))
      return "has_item returns index of item 5";
  } while (0);
  free_dynamic_array(da);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_has_item_returns_index>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <dynamic_array_create@plt>
  mov    $0x5,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <has_item@plt>
  mov    %eax,%r8d
  lea    D14(%rip),%rax
  cmp    $0xffffffff,%r8d
  je     L12
L1:
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <append_item@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <has_item@plt>
  mov    %eax,%r8d
  lea    D18(%rip),%rax
  test   %r8d,%r8d
  jne    L1
  mov    %rbp,%rdi
  call   <free_dynamic_array@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string

tool: D14: has_item does not detect item 5

tool: D18: has_item returns index of item 5

assistant: ```c
char *test_has_item_returns_index(void) {
  struct Dynamic_Array *da = dynamic_array_create(2, 2);
  do {
    if (!(has_item(da, 5) == -1))
      return "has_item does not detect item 5";
  } while (0);
  append_item(da, 5);
  do {
    if (!(has_item(da, 5) == 0))
      return "has_item returns index of item 5";
  } while (0);
  free_dynamic_array(da);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_has_item_returns_index>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <dynamic_array_create@plt>
  mov    $0x5,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <has_item@plt>
  mov    %eax,%r8d
  lea    D1(%rip),%rax
  cmp    $0xffffffff,%r8d
  je     L6
L11:
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <append_item@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <has_item@plt>
  mov    %eax,%r8d
  lea    D0(%rip),%rax
  test   %r8d,%r8d
  jne    L11
  mov    %rbp,%rdi
  call   <free_dynamic_array@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string
name: disassemble_data
arguments: data_tag: D0
type: string

tool: D1: has_item does not detect item 5

tool: D0: has_item returns index of item 5

assistant: ```c
char *test_has_item_returns_index(void) {
  struct Dynamic_Array *da = dynamic_array_create(2, 2);
  do {
    if (!(has_item(da, 5) == -1))
      return "has_item does not detect item 5";
  } while (0);
  append_item(da, 5);
  do {
    if (!(has_item(da, 5) == 0))
      return "has_item returns index of item 5";
  } while (0);
  free_dynamic_array(da);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jle    L9
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L3
L9:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L3:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string
name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D4: hello

tool: D3: world

assistant: ```c
int main() {
  int x;
  x = 10;
  x > 10 ? puts("hello") : puts("world");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: world

assistant: ```c
int main() {
  int x;
  x = 10;
  x > 10 ? puts("hello") : puts("world");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: string

tool: D6: world

assistant: ```c
int main() {
  int x;
  x = 10;
  x > 10 ? puts("hello") : puts("world");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D7: world

assistant: ```c
int main() {
  int x;
  x = 10;
  x > 10 ? puts("hello") : puts("world");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L108
  cmpl   $0x2,-0xc(%rbp)
  jne    L92
L108:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L92:
  cmpl   $0x3,-0xc(%rbp)
  je     L106
  cmpl   $0x4,-0xc(%rbp)
  jne    L31
L106:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  cmpl   $0x5,-0xc(%rbp)
  je     L9
  cmpl   $0x6,-0xc(%rbp)
  jne    L85
L9:
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L85:
  cmpl   $0x7,-0xc(%rbp)
  je     L8
  cmpl   $0x8,-0xc(%rbp)
  jne    L83
L8:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L83:
  cmpl   $0x9,-0xc(%rbp)
  je     L18
  cmpl   $0x0,-0xc(%rbp)
  jne    L87
L18:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L87:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D59
type_infered: string
name: extract_symbolic_data
arguments: tag: D38
type_infered: string
name: extract_symbolic_data
arguments: tag: D43
type_infered: string
name: extract_symbolic_data
arguments: tag: D52
type_infered: string
name: extract_symbolic_data
arguments: tag: D27
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string

tool: D59: %d

tool: D38: Segunda-feira


tool: D43: Terca-feira


tool: D52: Quarta-feira


tool: D27: Quinta-feira


tool: D11: Sexta-feira


assistant: ```c
int main() {
  int n, d;
  scanf("%d", &n);
  d = n % 10;
  if (d == 1 || d == 2)
    printf("Segunda-feira\n");
  if (d == 3 || d == 4)
    printf("Terca-feira\n");
  if (d == 5 || d == 6)
    printf("Quarta-feira\n");
  if (d == 7 || d == 8)
    printf("Quinta-feira\n");
  if (d == 9 || d == 0)
    printf("Sexta-feira\n");
  return 0;
}
```