ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_Nios2_MPU_Set_region_registers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_Nios2_Set_ctlreg_mpubase@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <_Nios2_Set_ctlreg_mpuacc@plt>
  mov    $0x0,%eax
  call   <_Nios2_Flush_pipeline@plt>
  nop
  leave
  ret
```

assistant: ```c
void _Nios2_MPU_Set_region_registers(uint32_t mpubase, uint32_t mpuacc) {
  _Nios2_Set_ctlreg_mpubase(mpubase);
  _Nios2_Set_ctlreg_mpuacc(mpuacc);
  _Nios2_Flush_pipeline();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_Nios2_MPU_Set_region_registers>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <_Nios2_Set_ctlreg_mpubase@plt>
  mov    %ebx,%edi
  call   <_Nios2_Set_ctlreg_mpuacc@plt>
  mov    $0x0,%eax
  call   <_Nios2_Flush_pipeline@plt>
  pop    %rbx
  ret
```

assistant: ```c
void _Nios2_MPU_Set_region_registers(uint32_t mpubase, uint32_t mpuacc) {
  _Nios2_Set_ctlreg_mpubase(mpubase);
  _Nios2_Set_ctlreg_mpuacc(mpuacc);
  _Nios2_Flush_pipeline();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_Nios2_MPU_Set_region_registers>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <_Nios2_Set_ctlreg_mpubase@plt>
  mov    %ebp,%edi
  call   <_Nios2_Set_ctlreg_mpuacc@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <_Nios2_Flush_pipeline@plt>
```

assistant: ```c
void _Nios2_MPU_Set_region_registers(uint32_t mpubase, uint32_t mpuacc) {
  _Nios2_Set_ctlreg_mpubase(mpubase);
  _Nios2_Set_ctlreg_mpuacc(mpuacc);
  _Nios2_Flush_pipeline();
}
```
user: Translate the below assembly code into C programming language:

```asm
<_Nios2_MPU_Set_region_registers>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <_Nios2_Set_ctlreg_mpubase@plt>
  mov    %ebp,%edi
  call   <_Nios2_Set_ctlreg_mpuacc@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <_Nios2_Flush_pipeline@plt>
```

assistant: ```c
void _Nios2_MPU_Set_region_registers(uint32_t mpubase, uint32_t mpuacc) {
  _Nios2_Set_ctlreg_mpubase(mpubase);
  _Nios2_Set_ctlreg_mpuacc(mpuacc);
  _Nios2_Flush_pipeline();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<internetPackIp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L5:
  shll   $0x8,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L4:
  cmpl   $0x3,-0x8(%rbp)
  jle    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned internetPackIp(unsigned char unpacked[4]) {
  int i;
  unsigned packed = 0;
  for (i = 0; i <= 3; ++i) {
    packed <<= 8;
    packed |= unpacked[i];
  }
  return packed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<internetPackIp>:
  endbr64
  lea    0x4(%rdi),%rcx
  mov    $0x0,%eax
L4:
  shl    $0x8,%eax
  movzbl (%rdi),%edx
  or     %edx,%eax
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L4
  ret
```

assistant: ```c
unsigned internetPackIp(unsigned char unpacked[4]) {
  int i;
  unsigned packed = 0;
  for (i = 0; i <= 3; ++i) {
    packed <<= 8;
    packed |= unpacked[i];
  }
  return packed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<internetPackIp>:
  endbr64
  lea    0x4(%rdi),%rcx
  xor    %eax,%eax
L6:
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    $0x1,%rdi
  or     %edx,%eax
  cmp    %rcx,%rdi
  jne    L6
  ret
```

assistant: ```c
unsigned internetPackIp(unsigned char unpacked[4]) {
  int i;
  unsigned packed = 0;
  for (i = 0; i <= 3; ++i) {
    packed <<= 8;
    packed |= unpacked[i];
  }
  return packed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<internetPackIp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%edx
  or     %edx,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  or     %eax,%edx
  movzbl 0x3(%rdi),%eax
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned internetPackIp(unsigned char unpacked[4]) {
  int i;
  unsigned packed = 0;
  for (i = 0; i <= 3; ++i) {
    packed <<= 8;
    packed |= unpacked[i];
  }
  return packed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x21c(%rbp),%rdx
  lea    -0x220(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x218(%rbp)
  jmp    L8
L56:
  lea    -0x210(%rbp),%rdx
  mov    -0x218(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x218(%rbp)
L8:
  mov    -0x21c(%rbp),%eax
  cmp    %eax,-0x218(%rbp)
  jl     L56
  movl   $0x1,-0x218(%rbp)
  jmp    L48
L61:
  mov    -0x218(%rbp),%eax
  cltq
  mov    -0x210(%rbp,%rax,4),%edx
  mov    -0x218(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x210(%rbp,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x214(%rbp)
  mov    -0x214(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0x220(%rbp),%eax
  cmp    %eax,%edx
  jle    L49
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L9
L49:
  addl   $0x1,-0x218(%rbp)
L48:
  mov    -0x21c(%rbp),%eax
  cmp    %eax,-0x218(%rbp)
  jl     L61
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D38
datatype: string
name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D32
datatype: string
name: parse_data
arguments: tag: D4
datatype: string

tool: D38: %d %d

tool: D13: %d

tool: D32: GAME OVER


tool: D4: YOU WIN


assistant: ```c
int main(void) {
  int alturaDoPuloDoSapo, quantidadeDeCanos, diferenca, canos[128], i;
  scanf("%d %d", &alturaDoPuloDoSapo, &quantidadeDeCanos);
  for (i = 0; i < quantidadeDeCanos; i++) {
    scanf("%d", &canos[i]);
  }
  for (i = 1; i < quantidadeDeCanos; i++) {
    diferenca = canos[i] - canos[i - 1];
    if (((diferenca) < 0 ? -(diferenca) : (diferenca)) > alturaDoPuloDoSapo) {
      printf("GAME OVER\n");
      return 0;
    }
  }
  printf("YOU WIN\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L9
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D37(%rip),%r12
L7:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L7
L9:
  cmp    $0x1,%eax
  jle    L38
  mov    0x8(%rsp),%esi
  lea    0x10(%rsp),%rdx
  lea    -0x2(%rax),%eax
  lea    0x14(%rsp,%rax,4),%rdi
L1:
  mov    0x4(%rdx),%eax
  sub    (%rdx),%eax
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  cmp    %esi,%eax
  jg     L55
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L1
L38:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L60:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x220,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L60
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D36
type_guessed: string
name: extract_symbolic_data
arguments: tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string

tool: D36: %d %d

tool: D37: %d

tool: D5: YOU WIN


tool: D15: GAME OVER


assistant: ```c
int main(void) {
  int alturaDoPuloDoSapo, quantidadeDeCanos, diferenca, canos[128], i;
  scanf("%d %d", &alturaDoPuloDoSapo, &quantidadeDeCanos);
  for (i = 0; i < quantidadeDeCanos; i++) {
    scanf("%d", &canos[i]);
  }
  for (i = 1; i < quantidadeDeCanos; i++) {
    diferenca = canos[i] - canos[i - 1];
    if (((diferenca) < 0 ? -(diferenca) : (diferenca)) > alturaDoPuloDoSapo) {
      printf("GAME OVER\n");
      return 0;
    }
  }
  printf("YOU WIN\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L60
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D25(%rip),%r13
  mov    %rbx,%r12
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  add    $0x4,%r12
  cmp    %ebp,%eax
  jg     L3
  cmp    $0x1,%eax
  jle    L60
  sub    $0x2,%eax
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdx
  lea    0x14(%rsp,%rax,4),%rdi
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L60
L6:
  mov    0x4(%rdx),%eax
  sub    (%rdx),%eax
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  cmp    %esi,%eax
  jle    L5
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L60:
  lea    D31(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D25
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D31
datatype: string

tool: D19: %d %d

tool: D25: %d

tool: D4: GAME OVER


tool: D31: YOU WIN


assistant: ```c
int main(void) {
  int alturaDoPuloDoSapo, quantidadeDeCanos, diferenca, canos[128], i;
  scanf("%d %d", &alturaDoPuloDoSapo, &quantidadeDeCanos);
  for (i = 0; i < quantidadeDeCanos; i++) {
    scanf("%d", &canos[i]);
  }
  for (i = 1; i < quantidadeDeCanos; i++) {
    diferenca = canos[i] - canos[i - 1];
    if (((diferenca) < 0 ? -(diferenca) : (diferenca)) > alturaDoPuloDoSapo) {
      printf("GAME OVER\n");
      return 0;
    }
  }
  printf("YOU WIN\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L43
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D21(%rip),%r12
  xchg   %ax,%ax
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L6
  cmp    $0x1,%eax
  jle    L43
  sub    $0x2,%eax
  mov    0x8(%rsp),%edi
  mov    0x10(%rsp),%esi
  lea    0x14(%rsp),%rcx
  lea    0x18(%rsp,%rax,4),%r8
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x4,%rcx
  cmp    %rcx,%r8
  je     L43
L72:
  mov    %esi,%eax
  mov    (%rcx),%esi
  mov    %esi,%edx
  sub    %eax,%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  cmp    %edi,%eax
  jle    L41
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L75
L43:
  lea    D22(%rip),%rdi
  call   <printf@plt>
L75:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x220,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
data_type: string
name: read_data
arguments: data_label: D21
data_type: string
name: read_data
arguments: data_label: D31
data_type: string
name: read_data
arguments: data_label: D22
data_type: string

tool: D12: %d %d

tool: D21: %d

tool: D31: GAME OVER


tool: D22: YOU WIN


assistant: ```c
int main(void) {
  int alturaDoPuloDoSapo, quantidadeDeCanos, diferenca, canos[128], i;
  scanf("%d %d", &alturaDoPuloDoSapo, &quantidadeDeCanos);
  for (i = 0; i < quantidadeDeCanos; i++) {
    scanf("%d", &canos[i]);
  }
  for (i = 1; i < quantidadeDeCanos; i++) {
    diferenca = canos[i] - canos[i - 1];
    if (((diferenca) < 0 ? -(diferenca) : (diferenca)) > alturaDoPuloDoSapo) {
      printf("GAME OVER\n");
      return 0;
    }
  }
  printf("YOU WIN\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<show_oemsdr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0x5,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2880,-0x14(%rbp)
  jne    L62
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
L62:
  cmpl   $0x157,-0x14(%rbp)
  jne    L19
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
L19:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L38:
  movl   $0x8,-0xc(%rbp)
  jmp    L27
L15:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
L2:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string

tool: D8: Fujitsu: 

tool: D23: Intel: 

tool: D10: manuf=%d: 

tool: D18: %02x 

assistant: ```c
int show_oemsdr(int vend, unsigned char *sdr) {
  int rv = -1;
  int i, len;
  if (rv != 0) {
    len = sdr[4] + 5;
    if (vend == 0x002880)
      printf("Fujitsu: ");
    else if (vend == 0x000157)
      printf("Intel: ");
    else
      printf("manuf=%d: ", vend);
    for (i = 8; i < len; i++)
      printf("%02x ", sdr[i]);
    printf("\n");
  }
  return (rv);
}
```
user: Translate the below assembly code into C programming language:

```asm
<show_oemsdr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  movzbl 0x4(%rsi),%r12d
  cmp    $0x2880,%edi
  je     L37
  cmp    $0x157,%edi
  je     L28
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  cmp    $0x3,%r12b
  jbe    L13
  lea    0x8(%rbp),%rbx
  movzbl %r12b,%r12d
  lea    -0x4(%r12),%eax
  lea    0x9(%rbp,%rax,1),%r12
  lea    D17(%rip),%rbp
L31:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L31
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L28:
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D2: manuf=%d: 

tool: D17: %02x 

tool: D20: Fujitsu: 

tool: D3: Intel: 

assistant: ```c
int show_oemsdr(int vend, unsigned char *sdr) {
  int rv = -1;
  int i, len;
  if (rv != 0) {
    len = sdr[4] + 5;
    if (vend == 0x002880)
      printf("Fujitsu: ");
    else if (vend == 0x000157)
      printf("Intel: ");
    else
      printf("manuf=%d: ", vend);
    for (i = 8; i < len; i++)
      printf("%02x ", sdr[i]);
    printf("\n");
  }
  return (rv);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<show_oemsdr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl 0x4(%rsi),%r12d
  cmp    $0x2880,%edi
  je     L15
  cmp    $0x157,%edi
  je     L10
  mov    %edi,%esi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
L59:
  cmp    $0x3,%r12b
  jbe    L38
  lea    -0x4(%r12),%eax
  lea    0x8(%rbp),%rbx
  lea    0x9(%rbp,%rax,1),%r12
  lea    D0(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L39:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L39
L38:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L59
L15:
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L59
```

tool_calls: name: parse_data
arguments: data_tag: D19
type: string
name: parse_data
arguments: data_tag: D0
type: string
name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D20
type: string

tool: D19: manuf=%d: 

tool: D0: %02x 

tool: D9: Intel: 

tool: D20: Fujitsu: 

assistant: ```c
int show_oemsdr(int vend, unsigned char *sdr) {
  int rv = -1;
  int i, len;
  if (rv != 0) {
    len = sdr[4] + 5;
    if (vend == 0x002880)
      printf("Fujitsu: ");
    else if (vend == 0x000157)
      printf("Intel: ");
    else
      printf("manuf=%d: ", vend);
    for (i = 8; i < len; i++)
      printf("%02x ", sdr[i]);
    printf("\n");
  }
  return (rv);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<show_oemsdr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl 0x4(%rsi),%r12d
  cmp    $0x2880,%edi
  je     L44
  cmp    $0x157,%edi
  je     L3
  mov    %edi,%esi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
L57:
  cmp    $0x3,%r12b
  jbe    L39
  lea    -0x4(%r12),%eax
  lea    0x8(%rbp),%rbx
  lea    0x9(%rbp,%rax,1),%r12
  lea    D29(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L45:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L45
L39:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L57
L44:
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L57
```

tool_calls: name: parse_data
arguments: tag: D19
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: string
name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D27
type_infered: string

tool: D19: manuf=%d: 

tool: D29: %02x 

tool: D4: Intel: 

tool: D27: Fujitsu: 

assistant: ```c
int show_oemsdr(int vend, unsigned char *sdr) {
  int rv = -1;
  int i, len;
  if (rv != 0) {
    len = sdr[4] + 5;
    if (vend == 0x002880)
      printf("Fujitsu: ");
    else if (vend == 0x000157)
      printf("Intel: ");
    else
      printf("manuf=%d: ", vend);
    for (i = 8; i < len; i++)
      printf("%02x ", sdr[i]);
    printf("\n");
  }
  return (rv);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_assignment_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_assignment_array(int n, int *src, int *tgt) {
  for (int ii = 0; ii < n; ii++)
    tgt[ii] = src[ii];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copy_assignment_array>:
  endbr64
  test   %edi,%edi
  jle    L14
  mov    %edi,%edi
  mov    $0x0,%eax
L13:
  mov    (%rsi,%rax,4),%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L13
L14:
  ret
```

assistant: ```c
void copy_assignment_array(int n, int *src, int *tgt) {
  for (int ii = 0; ii < n; ii++)
    tgt[ii] = src[ii];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy_assignment_array>:
  endbr64
  test   %edi,%edi
  jle    L17
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L16:
  mov    (%rsi,%rax,4),%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L16
L17:
  ret
```

assistant: ```c
void copy_assignment_array(int n, int *src, int *tgt) {
  for (int ii = 0; ii < n; ii++)
    tgt[ii] = src[ii];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_assignment_array>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rcx
  test   %edi,%edi
  jle    L50
  lea    0x4(%rsi),%rsi
  mov    %rdx,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L59
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L59
  shr    $0x2,%edi
  xor    %eax,%eax
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L11:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L11
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r9b
  je     L50
  mov    %eax,%r8d
  mov    (%rcx,%r8,4),%esi
  lea    0x0(,%r8,4),%rdi
  mov    %esi,(%rdx,%r8,4)
  lea    0x1(%rax),%esi
  cmp    %esi,%r9d
  jle    L50
  mov    0x4(%rcx,%rdi,1),%esi
  add    $0x2,%eax
  mov    %esi,0x4(%rdx,%rdi,1)
  cmp    %eax,%r9d
  jle    L50
  mov    0x8(%rcx,%rdi,1),%eax
  mov    %eax,0x8(%rdx,%rdi,1)
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  mov    %r9d,%esi
  xor    %eax,%eax
  nopl   (%rax)
L30:
  mov    (%rcx,%rax,4),%edi
  mov    %edi,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L30
L50:
  ret
```

assistant: ```c
void copy_assignment_array(int n, int *src, int *tgt) {
  for (int ii = 0; ii < n; ii++)
    tgt[ii] = src[ii];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_assert_mem_eq_pass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x2,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x5,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  lea    -0x20(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <assert_mem_eq@plt>
  lea    -0x20(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <assert_mem_eq@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void test_assert_mem_eq_pass(void) {
  int a[6] = {1, 2, 3, 4, 5, 6};
  int b[6] = {1, 2, 3, 4, 5, 6};
  assert_mem_eq(a, b, 0);
  assert_mem_eq(a, b, 6);
}
```