ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<getD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L36:
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L52:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L46
L41:
  mov    -0x14(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L41
  mov    -0xc(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L52
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getD(int nbf, int nocc, double *orbs, double *D) {
  int iorb, ibf, jbf;
  double val;
  for (ibf = 0; ibf < nbf; ibf++) {
    for (jbf = 0; jbf < nbf; jbf++) {
      val = 0;
      for (iorb = 0; iorb < nocc; iorb++)
        val += orbs[ibf + iorb * nbf] * orbs[jbf + iorb * nbf];
      D[ibf + jbf * nbf] = val;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getD>:
  endbr64
  mov    %edi,%r11d
  test   %edi,%edi
  jle    L23
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%edi
  mov    %rdx,%r10
  mov    %rcx,%rbp
  lea    -0x1(%r11),%r12d
  not    %r12
  movslq %r11d,%rsi
  shl    $0x3,%rsi
  mov    $0x0,%ebx
  jmp    L17
L33:
  mov    %r10,%rax
  pxor   %xmm1,%xmm1
  mov    $0x0,%edx
L5:
  movsd  (%rax),%xmm0
  mulsd  (%rax,%rcx,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%edx
  add    %rsi,%rax
  cmp    %edx,%edi
  jne    L5
L62:
  movsd  %xmm1,(%r9)
  add    $0x1,%r8d
  add    %rsi,%r9
  add    $0x1,%rcx
  cmp    %r8d,%r11d
  je     L66
L34:
  pxor   %xmm1,%xmm1
  test   %edi,%edi
  jg     L33
  jmp    L62
L66:
  add    $0x8,%rbp
  sub    $0x1,%rbx
  add    $0x8,%r10
  cmp    %r12,%rbx
  je     L42
L17:
  mov    %rbx,%rcx
  mov    %rbp,%r9
  mov    $0x0,%r8d
  jmp    L34
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  ret
```

assistant: ```c
void getD(int nbf, int nocc, double *orbs, double *D) {
  int iorb, ibf, jbf;
  double val;
  for (ibf = 0; ibf < nbf; ibf++) {
    for (jbf = 0; jbf < nbf; jbf++) {
      val = 0;
      for (iorb = 0; iorb < nocc; iorb++)
        val += orbs[ibf + iorb * nbf] * orbs[jbf + iorb * nbf];
      D[ibf + jbf * nbf] = val;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getD>:
  endbr64
  mov    %edi,%r11d
  test   %edi,%edi
  jle    L35
  push   %r12
  mov    %esi,%edi
  lea    -0x1(%r11),%r12d
  movslq %r11d,%rsi
  push   %rbp
  mov    %rdx,%r10
  mov    %rcx,%rbp
  not    %r12
  push   %rbx
  shl    $0x3,%rsi
  xor    %ebx,%ebx
  pxor   %xmm2,%xmm2
  nop
L17:
  mov    %rbx,%rcx
  mov    %rbp,%r9
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L7:
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  xor    %edx,%edx
  test   %edi,%edi
  jle    L30
  nopl   (%rax)
L44:
  movsd  (%rax),%xmm0
  mulsd  (%rax,%rcx,8),%xmm0
  add    $0x1,%edx
  add    %rsi,%rax
  addsd  %xmm0,%xmm1
  cmp    %edx,%edi
  jne    L44
L30:
  add    $0x1,%r8d
  movsd  %xmm1,(%r9)
  add    $0x1,%rcx
  add    %rsi,%r9
  cmp    %r8d,%r11d
  jne    L7
  sub    $0x1,%rbx
  add    $0x8,%rbp
  add    $0x8,%r10
  cmp    %r12,%rbx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  ret
```

assistant: ```c
void getD(int nbf, int nocc, double *orbs, double *D) {
  int iorb, ibf, jbf;
  double val;
  for (ibf = 0; ibf < nbf; ibf++) {
    for (jbf = 0; jbf < nbf; jbf++) {
      val = 0;
      for (iorb = 0; iorb < nocc; iorb++)
        val += orbs[ibf + iorb * nbf] * orbs[jbf + iorb * nbf];
      D[ibf + jbf * nbf] = val;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getD>:
  endbr64
  mov    %edi,%r11d
  test   %edi,%edi
  jle    L40
  push   %r12
  mov    %esi,%edi
  lea    -0x1(%r11),%r12d
  movslq %r11d,%rsi
  push   %rbp
  mov    %rdx,%r10
  mov    %rcx,%rbp
  not    %r12
  push   %rbx
  shl    $0x3,%rsi
  xor    %ebx,%ebx
  pxor   %xmm2,%xmm2
  nop
L32:
  mov    %rbx,%rcx
  mov    %rbp,%r9
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L6:
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  xor    %edx,%edx
  test   %edi,%edi
  jle    L21
  nopl   (%rax)
L47:
  movsd  (%rax),%xmm0
  mulsd  (%rax,%rcx,8),%xmm0
  add    $0x1,%edx
  add    %rsi,%rax
  addsd  %xmm0,%xmm1
  cmp    %edx,%edi
  jne    L47
L21:
  add    $0x1,%r8d
  movsd  %xmm1,(%r9)
  add    $0x1,%rcx
  add    %rsi,%r9
  cmp    %r8d,%r11d
  jne    L6
  sub    $0x1,%rbx
  add    $0x8,%rbp
  add    $0x8,%r10
  cmp    %rbx,%r12
  jne    L32
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  ret
```

assistant: ```c
void getD(int nbf, int nocc, double *orbs, double *D) {
  int iorb, ibf, jbf;
  double val;
  for (ibf = 0; ibf < nbf; ibf++) {
    for (jbf = 0; jbf < nbf; jbf++) {
      val = 0;
      for (iorb = 0; iorb < nocc; iorb++)
        val += orbs[ibf + iorb * nbf] * orbs[jbf + iorb * nbf];
      D[ibf + jbf * nbf] = val;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<challenge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L115
L34:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubbleSort@plt>
  cmpl   $0x0,-0x10(%rbp)
  jle    L29
  movl   $0x0,-0xc(%rbp)
  jmp    L45
L125:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L38
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L10
L38:
  addl   $0x1,-0xc(%rbp)
L45:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L125
L29:
  addl   $0x1,-0x10(%rbp)
L115:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  movl   $0x0,-0x8(%rbp)
  jmp    L119
L92:
  movl   $0x0,-0x4(%rbp)
  jmp    L81
L68:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L83
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L10
L83:
  addl   $0x1,-0x4(%rbp)
L81:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L68
  addl   $0x1,-0x8(%rbp)
L119:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L92
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D21
type: string

tool: D19: NO


tool: D21: YES


assistant: ```c
void challenge(char **matrix, int n) {
  for (int i = 0; i < n; i++) {
    bubbleSort(matrix[i], n);
    if (i > 0) {
      for (int j = 0; j < n; j++) {
        if (matrix[i - 1][j] > matrix[i][j]) {
          printf("NO\n");
          return;
        }
      }
    }
  }
  for (int j = 0; j < n; j++) {
    for (int i = 0; i < n - 1; i++) {
      if (matrix[i][j] > matrix[i + 1][j]) {
        printf("NO\n");
        return;
      }
    }
  }
  printf("YES\n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<challenge>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L76
  mov    %rdi,%r14
  mov    %esi,%ebp
  mov    (%rdi),%rdi
  call   <bubbleSort@plt>
  lea    0x8(%r14),%r12
  mov    $0x1,%r13d
  mov    %ebp,%ebx
  jmp    L84
L130:
  lea    D7(%rip),%rdi
  call   <printf@plt>
L75:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L105:
  add    $0x1,%r13d
  add    $0x8,%r12
L84:
  cmp    %ebp,%r13d
  je     L114
  mov    %ebp,%esi
  mov    (%r12),%rdi
  call   <bubbleSort@plt>
  test   %r13d,%r13d
  jle    L105
  mov    -0x8(%r12),%rcx
  mov    (%r12),%rdx
  mov    $0x0,%eax
L142:
  movzbl (%rdx,%rax,1),%edi
  cmp    %dil,(%rcx,%rax,1)
  jg     L130
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L142
  jmp    L105
L114:
  mov    %ebp,%r8d
  lea    -0x2(%rbp),%eax
  lea    0x8(%r14,%rax,8),%rdi
  mov    $0x0,%edx
  jmp    L137
L4:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L75
L5:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L76
L137:
  mov    %r14,%rax
  cmp    $0x1,%ebp
  jle    L5
L104:
  mov    (%rax),%rsi
  mov    0x8(%rax),%rcx
  movzbl (%rcx,%rdx,1),%ebx
  cmp    %bl,(%rsi,%rdx,1)
  jg     L4
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L104
  jmp    L5
L76:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L75
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D7: NO


tool: D3: YES


assistant: ```c
void challenge(char **matrix, int n) {
  for (int i = 0; i < n; i++) {
    bubbleSort(matrix[i], n);
    if (i > 0) {
      for (int j = 0; j < n; j++) {
        if (matrix[i - 1][j] > matrix[i][j]) {
          printf("NO\n");
          return;
        }
      }
    }
  }
  for (int j = 0; j < n; j++) {
    for (int i = 0; i < n - 1; i++) {
      if (matrix[i][j] > matrix[i + 1][j]) {
        printf("NO\n");
        return;
      }
    }
  }
  printf("YES\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<challenge>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r15d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x8(%rbx),%r13
  mov    %r13,%r12
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <bubbleSort@plt>
  lea    -0x1(%r15),%eax
  lea    0x0(%r13,%rax,8),%rbp
  cmp    %rbp,%r13
  je     L27
L88:
  mov    0x0(%r13),%rdi
  mov    %r15d,%esi
  call   <bubbleSort@plt>
  mov    -0x8(%r13),%rcx
  mov    0x0(%r13),%rdx
  xor    %eax,%eax
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L71:
  add    $0x1,%rax
  cmp    %r14,%rax
  je     L123
L45:
  movzbl (%rdx,%rax,1),%edi
  cmp    %dil,(%rcx,%rax,1)
  jle    L71
L99:
  lea    D6(%rip),%rdi
L116:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
  nopl   (%rax)
L123:
  add    $0x8,%r13
  cmp    %rbp,%r13
  jne    L88
L27:
  lea    -0x2(%r15),%eax
  xor    %edx,%edx
  lea    (%r12,%rax,8),%rdi
L17:
  mov    %rbx,%rax
  cmp    $0x1,%r15d
  jne    L81
  jmp    L96
  xchg   %ax,%ax
L127:
  add    $0x8,%rax
  cmp    %rax,%rdi
  je     L96
L81:
  mov    0x8(%rax),%rcx
  mov    (%rax),%rsi
  movzbl (%rcx,%rdx,1),%ecx
  cmp    %cl,(%rsi,%rdx,1)
  jle    L127
  jmp    L99
  nopl   0x0(%rax,%rax,1)
L96:
  add    $0x1,%rdx
  cmp    %rdx,%r14
  jne    L17
  lea    D13(%rip),%rdi
  jmp    L116
L1:
  lea    D13(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string
name: parse_data
arguments: data_tag: D13
data_type: string

tool: D6: NO


tool: D13: YES


assistant: ```c
void challenge(char **matrix, int n) {
  for (int i = 0; i < n; i++) {
    bubbleSort(matrix[i], n);
    if (i > 0) {
      for (int j = 0; j < n; j++) {
        if (matrix[i - 1][j] > matrix[i][j]) {
          printf("NO\n");
          return;
        }
      }
    }
  }
  for (int j = 0; j < n; j++) {
    for (int i = 0; i < n - 1; i++) {
      if (matrix[i][j] > matrix[i + 1][j]) {
        printf("NO\n");
        return;
      }
    }
  }
  printf("YES\n");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<challenge>:
  endbr64
  test   %esi,%esi
  jle    L65
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r15d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x8(%rbx),%rbp
  mov    %rbp,%r13
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <bubbleSort@plt>
  lea    -0x1(%r15),%eax
  lea    0x0(%rbp,%rax,8),%r12
  cmp    %r12,%r13
  je     L47
L112:
  mov    0x0(%r13),%rdi
  mov    %r15d,%esi
  call   <bubbleSort@plt>
  mov    -0x8(%r13),%rcx
  mov    0x0(%r13),%rdx
  xor    %eax,%eax
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L127:
  add    $0x1,%rax
  cmp    %rax,%r14
  je     L66
L76:
  movzbl (%rdx,%rax,1),%edi
  cmp    %dil,(%rcx,%rax,1)
  jle    L127
L71:
  lea    D19(%rip),%rdi
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
  nopl   (%rax)
L66:
  add    $0x8,%r13
  cmp    %r12,%r13
  jne    L112
L47:
  lea    -0x2(%r15),%eax
  xor    %ecx,%ecx
  lea    0x10(%rbx,%rax,8),%rdi
L97:
  cmp    $0x1,%r15d
  je     L68
  mov    (%rbx),%rdx
  mov    %rbp,%rax
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L121:
  add    $0x8,%rax
  cmp    %rax,%rdi
  je     L68
L61:
  movzbl (%rdx,%rcx,1),%esi
  mov    (%rax),%rdx
  cmp    (%rdx,%rcx,1),%sil
  jle    L121
  jmp    L71
L68:
  add    $0x1,%rcx
  cmp    %rcx,%r14
  jne    L97
  lea    D20(%rip),%rdi
  jmp    L50
L65:
  lea    D20(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string

tool: D19: NO


tool: D20: YES


assistant: ```c
void challenge(char **matrix, int n) {
  for (int i = 0; i < n; i++) {
    bubbleSort(matrix[i], n);
    if (i > 0) {
      for (int j = 0; j < n; j++) {
        if (matrix[i - 1][j] > matrix[i][j]) {
          printf("NO\n");
          return;
        }
      }
    }
  }
  for (int j = 0; j < n; j++) {
    for (int i = 0; i < n - 1; i++) {
      if (matrix[i][j] > matrix[i + 1][j]) {
        printf("NO\n");
        return;
      }
    }
  }
  printf("YES\n");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hiusb_ohci_disable_clk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x120401a0,%edi
  call   <readl@plt>
  mov    %eax,-0x4(%rbp)
  orl    $0xb00,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x120401a0,%esi
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    $0x120401a0,%edi
  call   <readl@plt>
  mov    %eax,-0x4(%rbp)
  andl   $0xfffefffe,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x120401a0,%esi
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0x12c,%edi
  call   <udelay@plt>
  mov    $0x1204019c,%edi
  call   <readl@plt>
  mov    %eax,-0x4(%rbp)
  andl   $0xffffff88,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1204019c,%esi
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0xc8,%edi
  call   <udelay@plt>
  nop
  leave
  ret
```

assistant: ```c
void hiusb_ohci_disable_clk(void) {
  int reg;
  reg = readl((0x12040000 + 0x1a0));
  reg |= ((1 << 8) | (1 << 9) | (1 << 11));
  writel(reg, (0x12040000 + 0x1a0));
  udelay(100);
  reg = readl((0x12040000 + 0x1a0));
  reg &= ~((1 << 16) | (1 << 0));
  writel(reg, (0x12040000 + 0x1a0));
  udelay(300);
  reg = readl((0x12040000 + 0x19c));
  reg &= ~((1 << 0) | (1 << 1) | (1 << 2) | (1 << 4) | (1 << 5) | (1 << 6));
  writel(reg, (0x12040000 + 0x19c));
  udelay(200);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hiusb_ohci_disable_clk>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x120401a0,%edi
  call   <readl@plt>
  or     $0xb,%ah
  mov    %eax,%edi
  mov    $0x120401a0,%esi
  call   <writel@plt>
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    $0x120401a0,%edi
  call   <readl@plt>
  and    $0xfffefffe,%eax
  mov    %eax,%edi
  mov    $0x120401a0,%esi
  call   <writel@plt>
  mov    $0x12c,%edi
  call   <udelay@plt>
  mov    $0x1204019c,%edi
  call   <readl@plt>
  and    $0xffffff88,%eax
  mov    %eax,%edi
  mov    $0x1204019c,%esi
  call   <writel@plt>
  mov    $0xc8,%edi
  call   <udelay@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void hiusb_ohci_disable_clk(void) {
  int reg;
  reg = readl((0x12040000 + 0x1a0));
  reg |= ((1 << 8) | (1 << 9) | (1 << 11));
  writel(reg, (0x12040000 + 0x1a0));
  udelay(100);
  reg = readl((0x12040000 + 0x1a0));
  reg &= ~((1 << 16) | (1 << 0));
  writel(reg, (0x12040000 + 0x1a0));
  udelay(300);
  reg = readl((0x12040000 + 0x19c));
  reg &= ~((1 << 0) | (1 << 1) | (1 << 2) | (1 << 4) | (1 << 5) | (1 << 6));
  writel(reg, (0x12040000 + 0x19c));
  udelay(200);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hiusb_ohci_disable_clk>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x120401a0,%edi
  call   <readl@plt>
  mov    $0x120401a0,%esi
  or     $0xb,%ah
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    $0x120401a0,%edi
  call   <readl@plt>
  mov    $0x120401a0,%esi
  and    $0xfffefffe,%eax
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0x12c,%edi
  call   <udelay@plt>
  mov    $0x1204019c,%edi
  call   <readl@plt>
  mov    $0x1204019c,%esi
  and    $0xffffff88,%eax
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0xc8,%edi
  add    $0x8,%rsp
  jmp    1090 <udelay@plt>
```

assistant: ```c
void hiusb_ohci_disable_clk(void) {
  int reg;
  reg = readl((0x12040000 + 0x1a0));
  reg |= ((1 << 8) | (1 << 9) | (1 << 11));
  writel(reg, (0x12040000 + 0x1a0));
  udelay(100);
  reg = readl((0x12040000 + 0x1a0));
  reg &= ~((1 << 16) | (1 << 0));
  writel(reg, (0x12040000 + 0x1a0));
  udelay(300);
  reg = readl((0x12040000 + 0x19c));
  reg &= ~((1 << 0) | (1 << 1) | (1 << 2) | (1 << 4) | (1 << 5) | (1 << 6));
  writel(reg, (0x12040000 + 0x19c));
  udelay(200);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hiusb_ohci_disable_clk>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x120401a0,%edi
  call   <readl@plt>
  mov    $0x120401a0,%esi
  or     $0xb,%ah
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0x64,%edi
  call   <udelay@plt>
  mov    $0x120401a0,%edi
  call   <readl@plt>
  mov    $0x120401a0,%esi
  and    $0xfffefffe,%eax
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0x12c,%edi
  call   <udelay@plt>
  mov    $0x1204019c,%edi
  call   <readl@plt>
  mov    $0x1204019c,%esi
  and    $0xffffff88,%eax
  mov    %eax,%edi
  call   <writel@plt>
  mov    $0xc8,%edi
  add    $0x8,%rsp
  jmp    1090 <udelay@plt>
```

assistant: ```c
void hiusb_ohci_disable_clk(void) {
  int reg;
  reg = readl((0x12040000 + 0x1a0));
  reg |= ((1 << 8) | (1 << 9) | (1 << 11));
  writel(reg, (0x12040000 + 0x1a0));
  udelay(100);
  reg = readl((0x12040000 + 0x1a0));
  reg &= ~((1 << 16) | (1 << 0));
  writel(reg, (0x12040000 + 0x1a0));
  udelay(300);
  reg = readl((0x12040000 + 0x19c));
  reg &= ~((1 << 0) | (1 << 1) | (1 << 2) | (1 << 4) | (1 << 5) | (1 << 6));
  writel(reg, (0x12040000 + 0x19c));
  udelay(200);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<FindLineSection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x138,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %rsi,-0x140(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x140(%rbp),%rdx
  lea    -0x120(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x124(%rbp)
  movl   $0x0,-0x128(%rbp)
  jmp    L27
L46:
  mov    -0x128(%rbp),%edx
  mov    -0x138(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x124(%rbp),%edx
  lea    -0x120(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L21
  mov    -0x128(%rbp),%edx
  mov    -0x124(%rbp),%eax
  add    %edx,%eax
  jmp    L30
L21:
  addl   $0x1,-0x128(%rbp)
L27:
  mov    -0x124(%rbp),%edx
  mov    -0x128(%rbp),%eax
  lea    (%rdx,%rax,1),%ebx
  mov    -0x138(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jb     L46
  mov    $0xffffffff,%eax
L30:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2: [%s]

assistant: ```c
int FindLineSection(char ln[], char section[]) {
  unsigned int pnt, len;
  char cmp[256];
  sprintf(cmp, "[%s]", section);
  len = (int)strlen(cmp);
  pnt = 0;
  while (len + pnt < strlen(ln)) {
    if (!memcmp(ln + pnt, cmp, len))
      return (pnt + len);
    pnt++;
  }
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FindLineSection>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    $0x0,%ebx
  mov    %rsp,%r14
  jmp    L20
L33:
  add    $0x1,%ebx
L20:
  lea    (%rbx,%rbp,1),%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %eax,%r13d
  jae    L6
  mov    %ebx,%edi
  add    %r12,%rdi
  mov    %ebp,%edx
  mov    %r14,%rsi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L33
  mov    %r13d,%eax
  jmp    L23
L6:
  mov    $0xffffffff,%eax
L23:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: [%s]

assistant: ```c
int FindLineSection(char ln[], char section[]) {
  unsigned int pnt, len;
  char cmp[256];
  sprintf(cmp, "[%s]", section);
  len = (int)strlen(cmp);
  pnt = 0;
  while (len + pnt < strlen(ln)) {
    if (!memcmp(ln + pnt, cmp, len))
      return (pnt + len);
    pnt++;
  }
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<FindLineSection>:
  endbr64
  push   %r14
  mov    %rsi,%rdx
  lea    D9(%rip),%rsi
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  jmp    L49
  nopl   0x0(%rax)
L43:
  mov    %ebx,%edi
  mov    %ebp,%edx
  mov    %r14,%rsi
  add    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L18
  add    $0x1,%ebx
L49:
  mov    %r12,%rdi
  lea    (%rbx,%rbp,1),%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jb     L43
  mov    $0xffffffff,%eax
L39:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L18:
  mov    %r13d,%eax
  jmp    L39
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string

tool: D9: [%s]

assistant: ```c
int FindLineSection(char ln[], char section[]) {
  unsigned int pnt, len;
  char cmp[256];
  sprintf(cmp, "[%s]", section);
  len = (int)strlen(cmp);
  pnt = 0;
  while (len + pnt < strlen(ln)) {
    if (!memcmp(ln + pnt, cmp, len))
      return (pnt + len);
    pnt++;
  }
  return (-1);
}
```