ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<crypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: crypt=====


assistant: ```c
char *crypt(const char *key, const char *salt) {
  printf("crypt=====\n");
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<crypt>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: crypt=====


assistant: ```c
char *crypt(const char *key, const char *salt) {
  printf("crypt=====\n");
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crypt>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: crypt=====


assistant: ```c
char *crypt(const char *key, const char *salt) {
  printf("crypt=====\n");
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crypt>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string

tool: D7: crypt=====


assistant: ```c
char *crypt(const char *key, const char *salt) {
  printf("crypt=====\n");
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_self_policy_priority>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sched_setscheduler@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int set_self_policy_priority(int policy, int priority) {
  struct sched_param params;
  params.sched_priority = priority;
  return sched_setscheduler(0, policy, &params);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_self_policy_priority>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    %edi,%esi
  mov    $0x0,%edi
  call   <sched_setscheduler@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_self_policy_priority(int policy, int priority) {
  struct sched_param params;
  params.sched_priority = priority;
  return sched_setscheduler(0, policy, &params);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<set_self_policy_priority>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %esi,0x4(%rsp)
  mov    %edi,%esi
  xor    %edi,%edi
  call   <sched_setscheduler@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_self_policy_priority(int policy, int priority) {
  struct sched_param params;
  params.sched_priority = priority;
  return sched_setscheduler(0, policy, &params);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_self_policy_priority>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %esi,0x4(%rsp)
  mov    %edi,%esi
  xor    %edi,%edi
  call   <sched_setscheduler@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_self_policy_priority(int policy, int priority) {
  struct sched_param params;
  params.sched_priority = priority;
  return sched_setscheduler(0, policy, &params);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L14
L1:
  shll   -0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
u_int hash_size(u_int s) {
  u_int i = 1;
  while (i < s)
    i <<= 1;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hash_size>:
  endbr64
  cmp    $0x1,%edi
  jle    L15
  mov    $0x1,%eax
L5:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L5
  ret
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
u_int hash_size(u_int s) {
  u_int i = 1;
  while (i < s)
    i <<= 1;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_size>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L9
  xchg   %ax,%ax
L17:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L17
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
u_int hash_size(u_int s) {
  u_int i = 1;
  while (i < s)
    i <<= 1;
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash_size>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L13
  xchg   %ax,%ax
L9:
  add    %eax,%eax
  cmp    %eax,%edi
  jg     L9
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
u_int hash_size(u_int s) {
  u_int i = 1;
  while (i < s)
    i <<= 1;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<QSsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <QSpartition@plt>
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L2
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <QSsort>
L2:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L14
  mov    -0x10(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <QSsort>
L14:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void QSsort(char *string, int left, int right) {
  int i, j;
  i = left;
  j = right;
  QSpartition(string, &i, &j);
  if (left < j)
    QSsort(string, left, j);
  if (i < right)
    QSsort(string, i, right);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<QSsort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <QSpartition@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebp,%edx
  jg     L48
L18:
  mov    (%rsp),%esi
  cmp    %ebx,%esi
  jl     L24
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <QSsort>
  jmp    L18
L24:
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <QSsort>
  jmp    L1
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void QSsort(char *string, int left, int right) {
  int i, j;
  i = left;
  j = right;
  QSpartition(string, &i, &j);
  if (left < j)
    QSsort(string, left, j);
  if (i < right)
    QSsort(string, i, right);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<QSsort>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %rsp,%rsi
  mov    %edx,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  call   <QSpartition@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebp,%edx
  jg     L28
  mov    (%rsp),%esi
  cmp    %r12d,%esi
  jl     L1
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <QSsort>
  mov    (%rsp),%esi
  cmp    %r12d,%esi
  jge    L25
L1:
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <QSsort>
  jmp    L25
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void QSsort(char *string, int left, int right) {
  int i, j;
  i = left;
  j = right;
  QSpartition(string, &i, &j);
  if (left < j)
    QSsort(string, left, j);
  if (i < right)
    QSsort(string, i, right);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L16
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L16:
  movsd  -0x18(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L14
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D43
datatype: string
name: unpack_data
arguments: label: D31
datatype: string
name: unpack_data
arguments: label: D8
datatype: string
name: unpack_data
arguments: label: D32
datatype: string
name: unpack_data
arguments: label: D66
datatype: string

tool: D43: a = 

tool: D31: %lf

tool: D8: b = 

tool: D32: c = 

tool: D66: Biggest num is %.2f

assistant: ```c
int main() {
  double a, b, c;
  printf("a = ");
  scanf("%lf", &a);
  printf("b = ");
  scanf("%lf", &b);
  printf("c = ");
  scanf("%lf", &c);
  double biggest = a;
  if (b > biggest) {
    biggest = b;
  }
  if (c > biggest) {
    biggest = c;
  }
  printf("Biggest num is %.2f", biggest);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  maxsd  (%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D20
type_guessed: string
name: disassemble_data
arguments: data_tag: D21
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D17: a = 

tool: D15: %lf

tool: D20: b = 

tool: D21: c = 

tool: D6: Biggest num is %.2f

assistant: ```c
int main() {
  double a, b, c;
  printf("a = ");
  scanf("%lf", &a);
  printf("b = ");
  scanf("%lf", &b);
  printf("c = ");
  scanf("%lf", &c);
  double biggest = a;
  if (b > biggest) {
    biggest = b;
  }
  if (c > biggest) {
    biggest = c;
  }
  printf("Biggest num is %.2f", biggest);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  lea    D10(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  maxsd  (%rsp),%xmm0
  lea    D35(%rip),%rdi
  movsd  0x10(%rsp),%xmm1
  mov    $0x1,%eax
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D39
type_guessed: string
name: disassemble_data
arguments: data_label: D10
type_guessed: string
name: disassemble_data
arguments: data_label: D49
type_guessed: string
name: disassemble_data
arguments: data_label: D34
type_guessed: string
name: disassemble_data
arguments: data_label: D35
type_guessed: string

tool: D39: a = 

tool: D10: %lf

tool: D49: b = 

tool: D34: c = 

tool: D35: Biggest num is %.2f

assistant: ```c
int main() {
  double a, b, c;
  printf("a = ");
  scanf("%lf", &a);
  printf("b = ");
  scanf("%lf", &b);
  printf("c = ");
  scanf("%lf", &c);
  double biggest = a;
  if (b > biggest) {
    biggest = b;
  }
  if (c > biggest) {
    biggest = c;
  }
  printf("Biggest num is %.2f", biggest);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  lea    D19(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  maxsd  (%rsp),%xmm0
  lea    D28(%rip),%rdi
  movsd  0x10(%rsp),%xmm1
  mov    $0x1,%eax
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string
name: extract_symbolic_data
arguments: tag: D49
data_type: string
name: extract_symbolic_data
arguments: tag: D28
data_type: string

tool: D34: a = 

tool: D19: %lf

tool: D33: b = 

tool: D49: c = 

tool: D28: Biggest num is %.2f

assistant: ```c
int main() {
  double a, b, c;
  printf("a = ");
  scanf("%lf", &a);
  printf("b = ");
  scanf("%lf", &b);
  printf("c = ");
  scanf("%lf", &c);
  double biggest = a;
  if (b > biggest) {
    biggest = b;
  }
  if (c > biggest) {
    biggest = c;
  }
  printf("Biggest num is %.2f", biggest);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movb   $0x61,-0x11(%rbp)
  movl   $0x19,-0x10(%rbp)
  movss  D31(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movsd  D41(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsbl -0x11(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x10(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm3,%xmm3
  cvtss2sd -0xc(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D31
type_guessed: byte[4]
name: read_data
arguments: data_tag: D41
type_guessed: f64
name: read_data
arguments: data_tag: D18
type_guessed: string
name: read_data
arguments: data_tag: D59
type_guessed: string
name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string

tool: {"D31": [0xf9,0x0f,0x49,0x40]}

tool: D41: 2.7172

tool: D18: c vale %c


tool: D59: i vale %d


tool: D5: f vale %f


tool: D11: d vale %f


assistant: ```c
main() {
  char c;
  int i;
  float f;
  double d;
  c = 'a';
  i = 25;
  f = 3.1416F;
  d = 2.7172;
  printf("c vale %c\n", c);
  printf("i vale %d\n", i);
  printf("f vale %f\n", f);
  printf("d vale %f\n", d);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D30(%rip),%xmm0
  lea    D11(%rip),%rdi
  call   <printf@plt>
  movsd  D48(%rip),%xmm0
  lea    D47(%rip),%rdi
  call   <printf@plt>
  movsd  D75(%rip),%xmm0
  lea    D27(%rip),%rdi
  call   <printf@plt>
  movsd  D16(%rip),%xmm0
  lea    D72(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D48
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D47
type_infered: string
name: extract_symbolic_data
arguments: tag: D75
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D27
type_infered: string
name: extract_symbolic_data
arguments: tag: D16
type_infered: f64
name: extract_symbolic_data
arguments: tag: D72
type_infered: string

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x40,0x58,0x40]}

tool: D11: c vale %c


tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D47: i vale %d


tool: {"D75": [0x00,0x00,0x00,0x20,0xff,0x21,0x09,0x40]}

tool: D27: f vale %f


tool: D16: 2.7172

tool: D72: d vale %f


assistant: ```c
main() {
  char c;
  int i;
  float f;
  double d;
  c = 'a';
  i = 25;
  f = 3.1416F;
  d = 2.7172;
  printf("c vale %c\n", c);
  printf("i vale %d\n", i);
  printf("f vale %f\n", f);
  printf("d vale %f\n", d);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D18(%rip),%xmm0
  lea    D31(%rip),%rdi
  call   <printf@plt>
  movsd  D50(%rip),%xmm0
  lea    D22(%rip),%rdi
  call   <printf@plt>
  movsd  D10(%rip),%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  movsd  D27(%rip),%xmm0
  lea    D71(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
type_guessed: byte[8]
name: retrieve_data
arguments: label: D31
type_guessed: string
name: retrieve_data
arguments: label: D50
type_guessed: byte[8]
name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: byte[8]
name: retrieve_data
arguments: label: D8
type_guessed: string
name: retrieve_data
arguments: label: D27
type_guessed: f64
name: retrieve_data
arguments: label: D71
type_guessed: string

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x40,0x58,0x40]}

tool: D31: c vale %c


tool: {"D50": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D22: i vale %d


tool: {"D10": [0x00,0x00,0x00,0x20,0xff,0x21,0x09,0x40]}

tool: D8: f vale %f


tool: D27: 2.7172

tool: D71: d vale %f


assistant: ```c
main() {
  char c;
  int i;
  float f;
  double d;
  c = 'a';
  i = 25;
  f = 3.1416F;
  d = 2.7172;
  printf("c vale %c\n", c);
  printf("i vale %d\n", i);
  printf("f vale %f\n", f);
  printf("d vale %f\n", d);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D78(%rip),%xmm0
  lea    D75(%rip),%rdi
  call   <printf@plt>
  movsd  D37(%rip),%xmm0
  lea    D22(%rip),%rdi
  call   <printf@plt>
  movsd  D40(%rip),%xmm0
  lea    D47(%rip),%rdi
  call   <printf@plt>
  movsd  D31(%rip),%xmm0
  lea    D72(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D78
type_guessed: byte[8]
name: unpack_data
arguments: label: D75
type_guessed: string
name: unpack_data
arguments: label: D37
type_guessed: byte[8]
name: unpack_data
arguments: label: D22
type_guessed: string
name: unpack_data
arguments: label: D40
type_guessed: byte[8]
name: unpack_data
arguments: label: D47
type_guessed: string
name: unpack_data
arguments: label: D31
type_guessed: f64
name: unpack_data
arguments: label: D72
type_guessed: string

tool: {"D78": [0x00,0x00,0x00,0x00,0x00,0x40,0x58,0x40]}

tool: D75: c vale %c


tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D22: i vale %d


tool: {"D40": [0x00,0x00,0x00,0x20,0xff,0x21,0x09,0x40]}

tool: D47: f vale %f


tool: D31: 2.7172

tool: D72: d vale %f


assistant: ```c
main() {
  char c;
  int i;
  float f;
  double d;
  c = 'a';
  i = 25;
  f = 3.1416F;
  d = 2.7172;
  printf("c vale %c\n", c);
  printf("i vale %d\n", i);
  printf("f vale %f\n", f);
  printf("d vale %f\n", d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x7e4(%rbp)
  jmp    L12
L21:
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7e4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7e4(%rbp)
L12:
  mov    -0x7f0(%rbp),%eax
  cmp    %eax,-0x7e4(%rbp)
  jl     L21
  mov    -0x7f0(%rbp),%esi
  lea    -0x7e8(%rbp),%rcx
  lea    -0x7ec(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <minimax@plt>
  mov    -0x7ec(%rbp),%edx
  mov    -0x7e8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: D13: %d

assistant: ```c
int main() {
  int i, num, ar[500], mn, mx;
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    scanf("%d", &ar[i]);
  }
  minimax(ar, num, &mn, &mx);
  printf("%d", mn + mx);
  return 0;
}
```