ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<double_array_argmin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L14
L22:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L29
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L29:
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int double_array_argmin(double *array, int size) {
  int i;
  int argmin = 0;
  double min = array[0];
  for (i = 1; i < size; i++)
    if (array[i] < min) {
      argmin = i;
      min = array[i];
    }
  return argmin;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<double_array_argmin>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L28
  mov    %esi,%esi
  mov    $0x1,%eax
  mov    $0x0,%edx
L13:
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm1,%xmm0
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmova  %eax,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L13
L11:
  mov    %edx,%eax
  ret
L28:
  mov    $0x0,%edx
  jmp    L11
```

assistant: ```c
int double_array_argmin(double *array, int size) {
  int i;
  int argmin = 0;
  double min = array[0];
  for (i = 1; i < size; i++)
    if (array[i] < min) {
      argmin = i;
      min = array[i];
    }
  return argmin;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<double_array_argmin>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L6
  movslq %esi,%rsi
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L4:
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm1,%xmm0
  minsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L4
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int double_array_argmin(double *array, int size) {
  int i;
  int argmin = 0;
  double min = array[0];
  for (i = 1; i < size; i++)
    if (array[i] < min) {
      argmin = i;
      min = array[i];
    }
  return argmin;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<double_array_argmin>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L5
  movslq %esi,%rsi
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L9:
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm1,%xmm0
  minsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L9
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int double_array_argmin(double *array, int size) {
  int i;
  int argmin = 0;
  double min = array[0];
  for (i = 1; i < size; i++)
    if (array[i] < min) {
      argmin = i;
      min = array[i];
    }
  return argmin;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<DoYouWantToContinueShopping>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D27
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string

tool: D11: Do you want to continue shopping?

tool: D27: 1 - no ; 2 - yes

tool: D0: %d

assistant: ```c
int DoYouWantToContinueShopping() {
  int choice;
  puts("Do you want to continue shopping?");
  puts("1 - no ; 2 - yes");
  scanf("%d", &choice);
  return choice == 1 ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DoYouWantToContinueShopping>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D29
data_type: string
name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D16
data_type: string

tool: D29: Do you want to continue shopping?

tool: D9: 1 - no ; 2 - yes

tool: D16: %d

assistant: ```c
int DoYouWantToContinueShopping() {
  int choice;
  puts("Do you want to continue shopping?");
  puts("1 - no ; 2 - yes");
  scanf("%d", &choice);
  return choice == 1 ? 1 : 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<DoYouWantToContinueShopping>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string
name: extract_symbolic_data
arguments: data_tag: D26
type: string
name: extract_symbolic_data
arguments: data_tag: D22
type: string

tool: D6: Do you want to continue shopping?

tool: D26: 1 - no ; 2 - yes

tool: D22: %d

assistant: ```c
int DoYouWantToContinueShopping() {
  int choice;
  puts("Do you want to continue shopping?");
  puts("1 - no ; 2 - yes");
  scanf("%d", &choice);
  return choice == 1 ? 1 : 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<DoYouWantToContinueShopping>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
type: string
name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D15
type: string

tool: D10: Do you want to continue shopping?

tool: D22: 1 - no ; 2 - yes

tool: D15: %d

assistant: ```c
int DoYouWantToContinueShopping() {
  int choice;
  puts("Do you want to continue shopping?");
  puts("1 - no ; 2 - yes");
  scanf("%d", &choice);
  return choice == 1 ? 1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printf1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%ebx
  mov    -0x18(%rbp),%r12
  jmp    L4
L22:
  add    $0x1,%ebx
L4:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  test   %ebx,%ebx
  je     L20
  mov    -0x18(%rbp),%rax
  mov    %ebx,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
L20:
  nop
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
printf1(s) char *s;
{
  register int i = 0;
  register char *s1 = s;
  while (*s1++)
    i++;
  if (i)
    write(1, s, i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printf1>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  lea    0x1(%rdi),%rcx
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L23:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L23
  test   %ecx,%ecx
  jne    L5
L1:
  ret
L5:
  sub    $0x8,%rsp
  mov    %ecx,%edx
  mov    %rdi,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
printf1(s) char *s;
{
  register int i = 0;
  register char *s1 = s;
  while (*s1++)
    i++;
  if (i)
    write(1, s, i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printf1>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rsi
  lea    0x1(%rdi),%rax
  je     L17
  mov    $0x1,%edx
  sub    %eax,%edx
  nopw   0x0(%rax,%rax,1)
L14:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L14
  mov    %r8d,%edx
  mov    $0x1,%edi
  xor    %eax,%eax
  jmp    1050 <write@plt>
  nopl   (%rax)
L17:
  ret
```

assistant: ```c
printf1(s) char *s;
{
  register int i = 0;
  register char *s1 = s;
  while (*s1++)
    i++;
  if (i)
    write(1, s, i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printf1>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rsi
  lea    0x1(%rdi),%rax
  je     L15
  mov    $0x1,%edx
  sub    %eax,%edx
  nopw   0x0(%rax,%rax,1)
L2:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L2
  mov    %r8d,%edx
  mov    $0x1,%edi
  xor    %eax,%eax
  jmp    1050 <write@plt>
  nopl   (%rax)
L15:
  ret
```

assistant: ```c
printf1(s) char *s;
{
  register int i = 0;
  register char *s1 = s;
  while (*s1++)
    i++;
  if (i)
    write(1, s, i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<currentTimeMillis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%rax
  imul   $0x3e8,%rax,%rsi
  mov    -0x18(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  add    %rsi,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
long long currentTimeMillis() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((tv.tv_sec * 1000LL) + (tv.tv_usec / 1000LL));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<currentTimeMillis>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%rsi
  mov    0x8(%rsp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0x7,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long currentTimeMillis() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((tv.tv_sec * 1000LL) + (tv.tv_usec / 1000LL));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<currentTimeMillis>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   $0x3e8,(%rsp),%rsi
  mov    %rcx,%rax
  sar    $0x3f,%rcx
  imul   %rdx
  sar    $0x7,%rdx
  sub    %rcx,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long currentTimeMillis() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((tv.tv_sec * 1000LL) + (tv.tv_usec / 1000LL));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<currentTimeMillis>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  imul   $0x3e8,(%rsp),%rsi
  mov    %rcx,%rax
  sar    $0x3f,%rcx
  imul   %rdx
  sar    $0x7,%rdx
  sub    %rcx,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long currentTimeMillis() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((tv.tv_sec * 1000LL) + (tv.tv_usec / 1000LL));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D19
type_guessed: string

tool: D18: 
%c

tool: D19: 
done


assistant: ```c
int main() {
  char c;
  c = getch();
  printf("\n%c", c);
  ungetch(c);
  c = getch();
  printf("\n%c", c);
  printf("\ndone\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getch@plt>
  movsbl %al,%ebx
  mov    %ebx,%esi
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  movsbl %al,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D10
data_type: string

tool: D14: 
%c

tool: D10: 
done


assistant: ```c
int main() {
  char c;
  c = getch();
  printf("\n%c", c);
  ungetch(c);
  c = getch();
  printf("\n%c", c);
  printf("\ndone\n\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D5(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <getch@plt>
  mov    %r12,%rdi
  movsbl %al,%ebp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <ungetch@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    %r12,%rdi
  movsbl %al,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string

tool: D5: 
%c

tool: D19: 
done


assistant: ```c
int main() {
  char c;
  c = getch();
  printf("\n%c", c);
  ungetch(c);
  c = getch();
  printf("\n%c", c);
  printf("\ndone\n\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D12(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <getch@plt>
  mov    %r12,%rdi
  movsbl %al,%ebp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <ungetch@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    %r12,%rdi
  movsbl %al,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
type_infered: string
name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D12: 
%c

tool: D8: 
done


assistant: ```c
int main() {
  char c;
  c = getch();
  printf("\n%c", c);
  ungetch(c);
  c = getch();
  printf("\n%c", c);
  printf("\ndone\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L72
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L18
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L18
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L39
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jg     L39
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x57,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L39:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L25
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L25
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x37,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L25:
  addl   $0x1,-0x8(%rbp)
L72:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L31
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i, n;
  n = 0;
  while (s[i] != '\n') {
    if (s[i] >= '0' && s[i] <= '9')
      n = 16 * n + (s[i] - '0');
    else if (s[i] >= 'a' && s[i] <= 'f')
      n = 16 * n + (s[i] - 'a' + 10);
    else if (s[i] >= 'A' && s[i] <= 'F')
      n = 16 * n + (s[i] - 'A' + 10);
    ++i;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<htoi>:
  endbr64
  cmpb   $0xa,(%rdi)
  je     L2
  add    $0x1,%rdi
L1:
  add    $0x1,%rdi
  cmpb   $0xa,-0x1(%rdi)
  jne    L1
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i, n;
  n = 0;
  while (s[i] != '\n') {
    if (s[i] >= '0' && s[i] <= '9')
      n = 16 * n + (s[i] - '0');
    else if (s[i] >= 'a' && s[i] <= 'f')
      n = 16 * n + (s[i] - 'a' + 10);
    else if (s[i] >= 'A' && s[i] <= 'F')
      n = 16 * n + (s[i] - 'A' + 10);
    ++i;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<htoi>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i, n;
  n = 0;
  while (s[i] != '\n') {
    if (s[i] >= '0' && s[i] <= '9')
      n = 16 * n + (s[i] - '0');
    else if (s[i] >= 'a' && s[i] <= 'f')
      n = 16 * n + (s[i] - 'a' + 10);
    else if (s[i] >= 'A' && s[i] <= 'F')
      n = 16 * n + (s[i] - 'A' + 10);
    ++i;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<htoi>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i, n;
  n = 0;
  while (s[i] != '\n') {
    if (s[i] >= '0' && s[i] <= '9')
      n = 16 * n + (s[i] - '0');
    else if (s[i] >= 'a' && s[i] <= 'f')
      n = 16 * n + (s[i] - 'a' + 10);
    else if (s[i] >= 'A' && s[i] <= 'F')
      n = 16 * n + (s[i] - 'A' + 10);
    ++i;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<KMP_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4143424141434241,%rax
  mov    $0x0,%edx
  mov    %rax,-0xd0(%rbp)
  mov    %rdx,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movl   $0x0,-0x70(%rbp)
  movabs $0x4241414141,%rax
  mov    $0x0,%edx
  mov    %rax,-0x6c(%rbp)
  mov    %rdx,-0x64(%rbp)
  movq   $0x0,-0x5c(%rbp)
  movq   $0x0,-0x54(%rbp)
  movq   $0x0,-0x4c(%rbp)
  movq   $0x0,-0x44(%rbp)
  movq   $0x0,-0x3c(%rbp)
  movq   $0x0,-0x34(%rbp)
  movq   $0x0,-0x2c(%rbp)
  movq   $0x0,-0x24(%rbp)
  movq   $0x0,-0x1c(%rbp)
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x2,-0xd4(%rbp)
  movl   $0x0,-0xd8(%rbp)
  jmp    L13
L14:
  lea    -0xd0(%rbp),%rcx
  mov    -0xd8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <isRepeat@plt>
  cmp    $0x1,%eax
  jne    L4
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L3
L4:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L3:
  addl   $0x1,-0xd8(%rbp)
L13:
  mov    -0xd8(%rbp),%eax
  cmp    -0xd4(%rbp),%eax
  jl     L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
data_type: string
name: retrieve_data
arguments: data_label: D11
data_type: string

tool: D15: TRUE

tool: D11: FALSE

assistant: ```c
int KMP_test(void) {
  char txt[][100] = {"ABCAABCA", "AAAAB"};
  int n = sizeof(txt) / sizeof(txt[0]);
  for (int i = 0; i < n; i++) {
    if (isRepeat(txt[i]) == 1) {
      printf("TRUE\n");
    } else {
      printf("FALSE\n");
    }
  }
  return 0;
}
```