ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_cmd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x20(%rdi),%rbp
  jmp    L23
L18:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L24
L23:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L18
  call   <free@plt>
  movq   $0x0,(%rbx)
  jmp    L18
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_cmd(char **argv) {
  int i;
  for (i = 0; i < 4; i++) {
    if (argv[i]) {
      free(argv[i]);
      argv[i] = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_cmd>:
  endbr64
  push   %rbp
  lea    0x20(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L6:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L19
  call   <free@plt>
  movq   $0x0,(%rbx)
L19:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_cmd(char **argv) {
  int i;
  for (i = 0; i < 4; i++) {
    if (argv[i]) {
      free(argv[i]);
      argv[i] = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_cmd>:
  endbr64
  push   %rbp
  lea    0x20(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L9:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L15
  call   <free@plt>
  movq   $0x0,(%rbx)
L15:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_cmd(char **argv) {
  int i;
  for (i = 0; i < 4; i++) {
    if (argv[i]) {
      free(argv[i]);
      argv[i] = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<plat_cpu_clock_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L1
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L1:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D15: r

tool: D10: /proc/pandora/cpu_mhz_max

tool: D0: %d

assistant: ```c
int plat_cpu_clock_get(void) {
  FILE *f;
  int ret = 0;
  f = fopen("/proc/pandora/cpu_mhz_max", "r");
  if (f) {
    fscanf(f, "%d", &ret);
    fclose(f);
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<plat_cpu_clock_get>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D3(%rip),%rsi
  lea    D5(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbx
  lea    0x4(%rsp),%rdx
  lea    D17(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L2:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string
name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D17
type: string

tool: D3: r

tool: D5: /proc/pandora/cpu_mhz_max

tool: D17: %d

assistant: ```c
int plat_cpu_clock_get(void) {
  FILE *f;
  int ret = 0;
  f = fopen("/proc/pandora/cpu_mhz_max", "r");
  if (f) {
    fscanf(f, "%d", &ret);
    fclose(f);
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<plat_cpu_clock_get>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rsi
  lea    D10(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rbp
  mov    %rax,%rdi
  lea    0x4(%rsp),%rdx
  lea    D17(%rip),%rsi
  call   <fscanf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L19:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D18: r

tool: D10: /proc/pandora/cpu_mhz_max

tool: D17: %d

assistant: ```c
int plat_cpu_clock_get(void) {
  FILE *f;
  int ret = 0;
  f = fopen("/proc/pandora/cpu_mhz_max", "r");
  if (f) {
    fscanf(f, "%d", &ret);
    fclose(f);
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<plat_cpu_clock_get>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rsi
  lea    D26(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbp
  mov    %rax,%rdi
  lea    0x4(%rsp),%rdx
  lea    D27(%rip),%rsi
  call   <fscanf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L6:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D26
type: string
name: retrieve_data
arguments: tag: D27
type: string

tool: D18: r

tool: D26: /proc/pandora/cpu_mhz_max

tool: D27: %d

assistant: ```c
int plat_cpu_clock_get(void) {
  FILE *f;
  int ret = 0;
  f = fopen("/proc/pandora/cpu_mhz_max", "r");
  if (f) {
    fscanf(f, "%d", &ret);
    fclose(f);
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<sendCmdStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  test   %rax,%rax
  jns    L5
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffff9d,%eax
  jmp    L19
L5:
  mov    $0x0,%eax
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: send

assistant: ```c
int sendCmdStr(int soc, char *sdCmd) {
  if (send(soc, sdCmd, strlen(sdCmd) + 1, 0) < 0) {
    perror("send");
    return -99;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sendCmdStr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send@plt>
  test   %rax,%rax
  js     L2
  mov    $0x0,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffff9d,%eax
  jmp    L16
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: send

assistant: ```c
int sendCmdStr(int soc, char *sdCmd) {
  if (send(soc, sdCmd, strlen(sdCmd) + 1, 0) < 0) {
    perror("send");
    return -99;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<sendCmdStr>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  lea    0x1(%rax),%rdx
  call   <send@plt>
  test   %rax,%rax
  js     L4
  xor    %eax,%eax
L18:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffff9d,%eax
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D4: send

assistant: ```c
int sendCmdStr(int soc, char *sdCmd) {
  if (send(soc, sdCmd, strlen(sdCmd) + 1, 0) < 0) {
    perror("send");
    return -99;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sendCmdStr>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %ecx,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  lea    0x1(%rax),%rdx
  call   <send@plt>
  test   %rax,%rax
  js     L18
  xor    %eax,%eax
L7:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L18:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffff9d,%eax
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: send

assistant: ```c
int sendCmdStr(int soc, char *sdCmd) {
  if (send(soc, sdCmd, strlen(sdCmd) + 1, 0) < 0) {
    perror("send");
    return -99;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L5
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void mergeSort(int *list, int low, int high) {
  int mid;
  if (low < high) {
    mid = (low + high) / 2;
    mergeSort(list, low, mid);
    mergeSort(list, mid + 1, high);
    merge(list, low, mid, high);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mergeSort>:
  endbr64
  cmp    %edx,%esi
  jl     L0
  ret
L0:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <mergeSort>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <mergeSort>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mergeSort(int *list, int low, int high) {
  int mid;
  if (low < high) {
    mid = (low + high) / 2;
    mergeSort(list, low, mid);
    mergeSort(list, mid + 1, high);
    merge(list, low, mid, high);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ADCC0_IrqHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L4:
  jmp    L4
```

assistant: ```c
__attribute__((weak)) void ADCC0_IrqHandler(void) {
  while (1)
    ;
}
```
user: What is the c source code of the assembly code below:

```asm
<ADCC0_IrqHandler>:
  endbr64
L0:
  jmp    L0
```

assistant: ```c
__attribute__((weak)) void ADCC0_IrqHandler(void) {
  while (1)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ADCC0_IrqHandler>:
  endbr64
  nopl   0x0(%rax)
L1:
  jmp    L1
```

assistant: ```c
__attribute__((weak)) void ADCC0_IrqHandler(void) {
  while (1)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ADCC0_IrqHandler>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
__attribute__((weak)) void ADCC0_IrqHandler(void) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hex_to_nfp32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L1:
  mov    -0x14(%rbp),%eax
  shl    $0x2,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <hex_to_fp32@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L1
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void hex_to_nfp32(unsigned char *datahex, float *dataf, int n) {
  for (int i = 0; i < n; ++i) {
    dataf[i] = hex_to_fp32(&datahex[i * 4]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hex_to_nfp32>:
  endbr64
  test   %edx,%edx
  jle    L18
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    -0x1(%rdx),%eax
  lea    0x4(%rdi,%rax,4),%r12
L3:
  mov    %rbx,%rdi
  call   <hex_to_fp32@plt>
  movss  %xmm0,0x0(%rbp)
  add    $0x4,%rbx
  add    $0x4,%rbp
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  ret
```

assistant: ```c
void hex_to_nfp32(unsigned char *datahex, float *dataf, int n) {
  for (int i = 0; i < n; ++i) {
    dataf[i] = hex_to_fp32(&datahex[i * 4]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hex_to_nfp32>:
  endbr64
  test   %edx,%edx
  jle    L16
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  add    $0x4,%rbp
  call   <hex_to_fp32@plt>
  movss  %xmm0,-0x4(%rbp)
  cmp    %r12,%rbx
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L16:
  ret
```

assistant: ```c
void hex_to_nfp32(unsigned char *datahex, float *dataf, int n) {
  for (int i = 0; i < n; ++i) {
    dataf[i] = hex_to_fp32(&datahex[i * 4]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hex_to_nfp32>:
  endbr64
  test   %edx,%edx
  jle    L7
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  add    $0x4,%rbp
  call   <hex_to_fp32@plt>
  movss  %xmm0,-0x4(%rbp)
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L7:
  ret
```

assistant: ```c
void hex_to_nfp32(unsigned char *datahex, float *dataf, int n) {
  for (int i = 0; i < n; ++i) {
    dataf[i] = hex_to_fp32(&datahex[i * 4]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fn_7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bar@plt>
  test   %rax,%rax
  je     L4
  cmpl   $0x0,-0x4(%rbp)
  je     L14
  addl   $0x1,-0x8(%rbp)
L14:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int fn_7(int p, int q, int r, int s, int t) {
  if (bar(p, q)) {
    if (p)
      q++;
    r++;
    t++;
  }
  return p + q + r + s + t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn_7>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %r8d,%r12d
  call   <bar@plt>
  test   %rax,%rax
  je     L3
  cmp    $0x1,%ebp
  sbb    $0xffffffff,%ebx
  add    $0x1,%r14d
  add    $0x1,%r12d
L3:
  lea    (%rbx,%rbp,1),%eax
  add    %r14d,%eax
  add    %r13d,%eax
  add    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fn_7(int p, int q, int r, int s, int t) {
  if (bar(p, q)) {
    if (p)
      q++;
    r++;
    t++;
  }
  return p + q + r + s + t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn_7>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <bar@plt>
  test   %rax,%rax
  je     L3
  cmp    $0x1,%ebp
  sbb    $0xffffffff,%ebx
  add    $0x1,%r14d
  add    $0x1,%r12d
L3:
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  add    %r14d,%eax
  add    %r13d,%eax
  add    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fn_7(int p, int q, int r, int s, int t) {
  if (bar(p, q)) {
    if (p)
      q++;
    r++;
    t++;
  }
  return p + q + r + s + t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fn_7>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <bar@plt>
  test   %rax,%rax
  je     L8
  cmp    $0x1,%ebp
  sbb    $0xffffffff,%ebx
  add    $0x1,%r14d
  add    $0x1,%r12d
L8:
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  add    %r14d,%eax
  add    %r13d,%eax
  add    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fn_7(int p, int q, int r, int s, int t) {
  if (bar(p, q)) {
    if (p)
      q++;
    r++;
    t++;
  }
  return p + q + r + s + t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fn13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    0x14(%rcx),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1e(%rcx),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: fn13

assistant: ```c
char *fn13() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn13");
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn13>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D8: fn13

assistant: ```c
char *fn13() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn13");
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fn13>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  call   <realloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D2: fn13

assistant: ```c
char *fn13() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn13");
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn13>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  call   <realloc@plt>
  lea    D9(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: fn13

assistant: ```c
char *fn13() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn13");
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<practice_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  jmp    L58
L26:
  movl   $0x1,-0x8(%rbp)
  jmp    L61
L5:
  movl   $0x1,-0x4(%rbp)
  jmp    L39
L75:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L12
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L12
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L12
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0x4,-0x4(%rbp)
  jle    L75
  addl   $0x1,-0x8(%rbp)
L61:
  cmpl   $0x4,-0x8(%rbp)
  jle    L5
  addl   $0x1,-0xc(%rbp)
L58:
  cmpl   $0x4,-0xc(%rbp)
  jle    L26
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: %d,%d,%d


assistant: ```c
void practice_1(void) {
  int i, j, k;
  for (i = 1; i < 5; i++) {
    for (j = 1; j < 5; j++) {
      for (k = 1; k < 5; k++) {
        if (i != k && i != j && j != k) {
          printf("%d,%d,%d\n", i, j, k);
        }
      }
    }
  }
}
```