ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<loc_segments>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %r13,%rsi
  sub    $0x8,%rsp
  call   <strtok@plt>
  xor    %r8d,%r8d
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L16
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    $0x1,%r8d
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L16
  xor    %edi,%edi
  mov    %r13,%rsi
  call   <strtok@plt>
  mov    $0x2,%r8d
  mov    %rax,(%r12)
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r8d
L16:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: /

assistant: ```c
int loc_segments(char *text, char **a, char **b, char **c) {
  *a = strtok(text, "/");
  if (!*a)
    return 0;
  *b = strtok(NULL, "/");
  if (!*b)
    return 1;
  *c = strtok(NULL, "/");
  if (!*c)
    return 2;
  return 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loc_segments>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %r13,%rsi
  sub    $0x8,%rsp
  call   <strtok@plt>
  xor    %r8d,%r8d
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L19
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    $0x1,%r8d
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L19
  xor    %edi,%edi
  mov    %r13,%rsi
  call   <strtok@plt>
  mov    $0x2,%r8d
  mov    %rax,(%r12)
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r8d
L19:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: /

assistant: ```c
int loc_segments(char *text, char **a, char **b, char **c) {
  *a = strtok(text, "/");
  if (!*a)
    return 0;
  *b = strtok(NULL, "/");
  if (!*b)
    return 1;
  *c = strtok(NULL, "/");
  if (!*c)
    return 2;
  return 3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x10(%rbp)
L38:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x11(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x2,-0xc(%rbp)
  jne    L23
  movzbl -0x11(%rbp),%eax
  cmp    $0xa,%al
  je     L27
L23:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  jmp    L59
L27:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jle    L6
  mov    -0x10(%rbp),%eax
  cmp    $0x400,%eax
  jle    L77
L6:
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L22
L77:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srandom@plt>
  jmp    L54
L43:
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0xffffffffac769185,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5f,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    0x20(%rdx),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L54:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jg     L43
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  jmp    L38
L59:
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D26
type: string
name: parse_data
arguments: data_tag: D11
type: string
name: parse_data
arguments: data_tag: D32
type: string
name: parse_data
arguments: data_tag: D40
type: string
name: parse_data
arguments: data_tag: D45
type: string

tool: D26: Length of the password (1-1024): 

tool: D11: %d%c

tool: D32: Enter numbers only


tool: D40: Please enter a number between 1 and 1024


tool: D45: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int length = 10;
  char term;
  int op;
  while (1) {
    printf("Length of the password (1-1024): ");
    op = scanf("%d%c", &length, &term);
    if (op != 2 || term != '\n') {
      printf("Enter numbers only\n");
      return -1;
    }
    if (length < 1 || length > 1024) {
      printf("Please enter a number between 1 and 1024\n");
      continue;
    }
    srandom((unsigned)time(NULL));
    for (; length > 0; length--) {
      putchar(random() % 95 + 32);
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  lea    D49(%rip),%rbp
  lea    D9(%rip),%rbx
  lea    D47(%rip),%r13
  lea    D36(%rip),%r12
  jmp    L79
L63:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    $0xffffffff,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srandom@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L35
L7:
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0xffffffffac769185,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5f,%edx,%edx
  sub    %edx,%eax
  lea    0x20(%rax),%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L7
L35:
  mov    %r13,%rdi
  call   <printf@plt>
L79:
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x3(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L63
  cmpb   $0xa,0x3(%rsp)
  jne    L63
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x3ff,%eax
  jbe    L36
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L79
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D49
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D47
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string
name: parse_data
arguments: data_tag: D38
type_guessed: string

tool: D49: Length of the password (1-1024): 

tool: D9: %d%c

tool: D47: 


tool: D36: Please enter a number between 1 and 1024


tool: D38: Enter numbers only


assistant: ```c
int main(int argc, const char *argv[]) {
  int length = 10;
  char term;
  int op;
  while (1) {
    printf("Length of the password (1-1024): ");
    op = scanf("%d%c", &length, &term);
    if (op != 2 || term != '\n') {
      printf("Enter numbers only\n");
      return -1;
    }
    if (length < 1 || length > 1024) {
      printf("Please enter a number between 1 and 1024\n");
      continue;
    }
    srandom((unsigned)time(NULL));
    for (; length > 0; length--) {
      putchar(random() % 95 + 32);
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  lea    D32(%rip),%r15
  push   %r14
  lea    D40(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D23(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  lea    0x3(%rsp),%r12
  lea    0x4(%rsp),%rbp
L64:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L41
  cmpb   $0xa,0x3(%rsp)
  jne    L41
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x3ff,%eax
  jbe    L61
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L61:
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srandom@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L59
  xchg   %ax,%ax
L67:
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffffac769185,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  sub    %ecx,%edx
  imul   $0x5f,%edx,%edx
  sub    %edx,%eax
  lea    0x20(%rax),%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L67
L59:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L41:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D32
datatype: string
name: parse_data
arguments: tag: D40
datatype: string
name: parse_data
arguments: tag: D15
datatype: string
name: parse_data
arguments: tag: D23
datatype: string
name: parse_data
arguments: tag: D25
datatype: string

tool: D32: 


tool: D40: Please enter a number between 1 and 1024


tool: D15: Length of the password (1-1024): 

tool: D23: %d%c

tool: D25: Enter numbers only


assistant: ```c
int main(int argc, const char *argv[]) {
  int length = 10;
  char term;
  int op;
  while (1) {
    printf("Length of the password (1-1024): ");
    op = scanf("%d%c", &length, &term);
    if (op != 2 || term != '\n') {
      printf("Enter numbers only\n");
      return -1;
    }
    if (length < 1 || length > 1024) {
      printf("Please enter a number between 1 and 1024\n");
      continue;
    }
    srandom((unsigned)time(NULL));
    for (; length > 0; length--) {
      putchar(random() % 95 + 32);
    }
    printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%r15
  push   %r14
  lea    D30(%rip),%r14
  push   %r13
  lea    D46(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  lea    0x3(%rsp),%r12
  lea    0x4(%rsp),%rbp
L17:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L16
  cmpb   $0xa,0x3(%rsp)
  jne    L16
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x3ff,%eax
  jbe    L5
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srandom@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L49
  xchg   %ax,%ax
L37:
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffffac769185,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  sub    %ecx,%edx
  imul   $0x5f,%edx,%edx
  sub    %edx,%eax
  lea    0x20(%rax),%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L37
L49:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L16:
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D30
type: string
name: extract_symbolic_data
arguments: label: D46
type: string
name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D47
type: string

tool: D0: 


tool: D30: Please enter a number between 1 and 1024


tool: D46: Length of the password (1-1024): 

tool: D3: %d%c

tool: D47: Enter numbers only


assistant: ```c
int main(int argc, const char *argv[]) {
  int length = 10;
  char term;
  int op;
  while (1) {
    printf("Length of the password (1-1024): ");
    op = scanf("%d%c", &length, &term);
    if (op != 2 || term != '\n') {
      printf("Enter numbers only\n");
      return -1;
    }
    if (length < 1 || length > 1024) {
      printf("Please enter a number between 1 and 1024\n");
      continue;
    }
    srandom((unsigned)time(NULL));
    for (; length > 0; length--) {
      putchar(random() % 95 + 32);
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xreadv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <readv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L2
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L30
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L2
  jmp    L30
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t xreadv(int fd, const struct iovec *iov, int iovcnt) {
  ssize_t nr;
restart:
  nr = readv(fd, iov, iovcnt);
  if ((nr < 0) && ((errno == EAGAIN) || (errno == EINTR)))
    goto restart;
  return nr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xreadv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
L21:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <readv@plt>
  test   %rax,%rax
  jns    L18
  mov    D28(%rip),%rdx
  mov    (%rdx),%rdx
  mov    D25(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L21
  mov    D12(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L21
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t xreadv(int fd, const struct iovec *iov, int iovcnt) {
  ssize_t nr;
restart:
  nr = readv(fd, iov, iovcnt);
  if ((nr < 0) && ((errno == EAGAIN) || (errno == EINTR)))
    goto restart;
  return nr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xreadv>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
L14:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <readv@plt>
  test   %rax,%rax
  jns    L21
  mov    D19(%rip),%rdx
  mov    D9(%rip),%rcx
  mov    (%rdx),%rdx
  cmp    (%rcx),%rdx
  je     L14
  mov    D2(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L14
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t xreadv(int fd, const struct iovec *iov, int iovcnt) {
  ssize_t nr;
restart:
  nr = readv(fd, iov, iovcnt);
  if ((nr < 0) && ((errno == EAGAIN) || (errno == EINTR)))
    goto restart;
  return nr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xreadv>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
L28:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <readv@plt>
  test   %rax,%rax
  jns    L20
  mov    D17(%rip),%rdx
  mov    D18(%rip),%rcx
  mov    (%rdx),%rdx
  cmp    (%rcx),%rdx
  je     L28
  mov    D21(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L28
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t xreadv(int fd, const struct iovec *iov, int iovcnt) {
  ssize_t nr;
restart:
  nr = readv(fd, iov, iovcnt);
  if ((nr < 0) && ((errno == EAGAIN) || (errno == EINTR)))
    goto restart;
  return nr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initmultiplayersparms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int initmultiplayersparms(int argc, char const *const argv[]) {
  argc = argc;
  argv = argv;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<initmultiplayersparms>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int initmultiplayersparms(int argc, char const *const argv[]) {
  argc = argc;
  argv = argv;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<initmultiplayersparms>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int initmultiplayersparms(int argc, char const *const argv[]) {
  argc = argc;
  argv = argv;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<initmultiplayersparms>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int initmultiplayersparms(int argc, char const *const argv[]) {
  argc = argc;
  argv = argv;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kern>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D36(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <cos@plt>
  movsd  D38(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_infered: f64
name: disassemble_data
arguments: data_tag: D36
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D38
type_infered: f64
name: disassemble_data
arguments: data_tag: D0
type_infered: f64

tool: D15: 3.141592653589793

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x80,0x4e,0x40]}

tool: D38: 1

tool: D0: 0.5

assistant: ```c
double kern(int i) {
  if (1) {
    return 0.5 * (cos(i * 3.14159265358979323846 / 61) + 1.0);
  } else {
    return 1.;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kern>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D2(%rip),%xmm0
  divsd  D1(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  addsd  D0(%rip),%xmm0
  mulsd  D27(%rip),%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: f64
name: read_data
arguments: data_tag: D1
datatype: byte[8]
name: read_data
arguments: data_tag: D0
datatype: f64
name: read_data
arguments: data_tag: D27
datatype: f64

tool: D2: 3.141592653589793

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x80,0x4e,0x40]}

tool: D0: 1

tool: D27: 0.5

assistant: ```c
double kern(int i) {
  if (1) {
    return 0.5 * (cos(i * 3.14159265358979323846 / 61) + 1.0);
  } else {
    return 1.;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kern>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  cvtsi2sd %edi,%xmm0
  mulsd  D37(%rip),%xmm0
  divsd  D38(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  addsd  D15(%rip),%xmm0
  mulsd  D21(%rip),%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D37
type: f64
name: parse_data
arguments: data_tag: D38
type: byte[8]
name: parse_data
arguments: data_tag: D15
type: f64
name: parse_data
arguments: data_tag: D21
type: f64

tool: D37: 3.141592653589793

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x80,0x4e,0x40]}

tool: D15: 1

tool: D21: 0.5

assistant: ```c
double kern(int i) {
  if (1) {
    return 0.5 * (cos(i * 3.14159265358979323846 / 61) + 1.0);
  } else {
    return 1.;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kern>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  cvtsi2sd %edi,%xmm0
  mulsd  D35(%rip),%xmm0
  divsd  D25(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  addsd  D38(%rip),%xmm0
  mulsd  D18(%rip),%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D35
datatype: f64
name: parse_data
arguments: data_tag: D25
datatype: byte[8]
name: parse_data
arguments: data_tag: D38
datatype: f64
name: parse_data
arguments: data_tag: D18
datatype: f64

tool: D35: 3.141592653589793

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x80,0x4e,0x40]}

tool: D38: 1

tool: D18: 0.5

assistant: ```c
double kern(int i) {
  if (1) {
    return 0.5 * (cos(i * 3.14159265358979323846 / 61) + 1.0);
  } else {
    return 1.;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matmatjik>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %r8d,-0x58(%rbp)
  mov    -0x54(%rbp),%edx
  movslq %edx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x38(%rbp)
  movslq %edx,%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    -0x54(%rbp),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x54(%rbp),%eax
  movslq %eax,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %eax,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L16
L18:
  movl   $0x0,-0x44(%rbp)
  jmp    L55
L40:
  movl   $0x0,-0x3c(%rbp)
  jmp    L39
L6:
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm1
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x68(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x70(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  movss  (%rdi,%rsi,4),%xmm0
  mov    -0x44(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x70(%rbp),%rsi
  add    %rsi,%rdi
  addss  %xmm1,%xmm0
  mov    -0x40(%rbp),%esi
  movslq %esi,%rsi
  movss  %xmm0,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L39:
  mov    -0x3c(%rbp),%esi
  cmp    -0x58(%rbp),%esi
  jl     L6
  addl   $0x1,-0x44(%rbp)
L55:
  mov    -0x44(%rbp),%esi
  cmp    -0x58(%rbp),%esi
  jl     L40
  addl   $0x1,-0x40(%rbp)
L16:
  mov    -0x40(%rbp),%esi
  cmp    -0x58(%rbp),%esi
  jl     L18
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void matmatjik(int LD, float A[][LD], float B[][LD], float C[][LD], int N) {
  int i = 0, j = 0, k = 0;
  for (j = 0; j < N; j++)
    for (i = 0; i < N; i++)
      for (k = 0; k < N; k++)
        C[i][j] += A[i][k] * B[k][j];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matmatjik>:
  endbr64
  test   %r8d,%r8d
  jle    L23
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  mov    %r8d,%r10d
  movslq %edi,%rdi
  mov    %rdx,%r9
  lea    -0x1(%r8),%eax
  shl    $0x2,%rax
  lea    0x4(%rdx,%rax,1),%r12
  shl    $0x2,%rdi
  lea    0x4(%rsi,%rax,1),%rbp
  mov    %r8d,%r11d
  neg    %r11
  shl    $0x2,%r11
L10:
  mov    %rbp,%rsi
  mov    %rbx,%rcx
  mov    $0x0,%r8d
L29:
  lea    (%r11,%rsi,1),%rax
  mov    %r9,%rdx
L14:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x4,%rax
  add    %rdi,%rdx
  cmp    %rsi,%rax
  jne    L14
  add    $0x1,%r8d
  add    %rdi,%rcx
  add    %rdi,%rsi
  cmp    %r8d,%r10d
  jne    L29
  add    $0x4,%r9
  add    $0x4,%rbx
  cmp    %r12,%r9
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  ret
```

assistant: ```c
void matmatjik(int LD, float A[][LD], float B[][LD], float C[][LD], int N) {
  int i = 0, j = 0, k = 0;
  for (j = 0; j < N; j++)
    for (i = 0; i < N; i++)
      for (k = 0; k < N; k++)
        C[i][j] += A[i][k] * B[k][j];
}
```