ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<arabic_to_roman>:
  endbr64
  cmp    $0x32,%edi
  jg     L25
  xor    %eax,%eax
  test   %edi,%edi
  jle    L77
  cmp    $0x32,%edi
  ja     L3
  lea    D35(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  lea    D112(%rip),%rax
  cmp    $0x64,%edi
  je     L77
  cmp    $0x190,%edi
  jne    L66
  lea    D132(%rip),%rax
L77:
  ret
  nopl   0x0(%rax)
L25:
  lea    D115(%rip),%rax
  cmp    $0x1f4,%edi
  je     L77
  jle    L49
  lea    D32(%rip),%rax
  cmp    $0x384,%edi
  je     L77
  cmp    $0x3e8,%edi
  mov    $0x0,%edx
  lea    D31(%rip),%rax
  cmovne %rdx,%rax
  ret
L66:
  cmp    $0x5a,%edi
  mov    $0x0,%edx
  lea    D81(%rip),%rax
  cmovne %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D5(%rip),%rax
  ret
  lea    D87(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D61(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D126(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D123(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D105(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D25(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D112
datatype: string
name: disassemble_data
arguments: data_label: D132
datatype: string
name: disassemble_data
arguments: data_label: D115
datatype: string
name: disassemble_data
arguments: data_label: D32
datatype: string
name: disassemble_data
arguments: data_label: D31
datatype: string
name: disassemble_data
arguments: data_label: D81
datatype: string
name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D87
datatype: string
name: disassemble_data
arguments: data_label: D61
datatype: string
name: disassemble_data
arguments: data_label: D126
datatype: string
name: disassemble_data
arguments: data_label: D123
datatype: string
name: disassemble_data
arguments: data_label: D105
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string

tool: D112: C

tool: D132: CD

tool: D115: D

tool: D32: CM

tool: D31: M

tool: D81: XC

tool: D5: L

tool: D87: V

tool: D61: IX

tool: D126: X

tool: D123: XL

tool: D105: I

tool: D25: IV

assistant: ```c
const char *arabic_to_roman(int arabic) {
  switch (arabic) {
  case 1:
    return "I";
  case 4:
    return "IV";
  case 5:
    return "V";
  case 9:
    return "IX";
  case 10:
    return "X";
  case 40:
    return "XL";
  case 50:
    return "L";
  case 90:
    return "XC";
  case 100:
    return "C";
  case 400:
    return "CD";
  case 500:
    return "D";
  case 900:
    return "CM";
  case 1000:
    return "M";
  default:
    return NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arabic_to_roman>:
  endbr64
  cmp    $0x32,%edi
  jg     L73
  xor    %eax,%eax
  test   %edi,%edi
  jle    L54
  cmp    $0x32,%edi
  ja     L25
  lea    D68(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  lea    D78(%rip),%rax
  cmp    $0x64,%edi
  je     L54
  cmp    $0x190,%edi
  jne    L72
  lea    D80(%rip),%rax
L54:
  ret
  nopl   0x0(%rax)
L73:
  lea    D100(%rip),%rax
  cmp    $0x1f4,%edi
  je     L54
  jle    L33
  lea    D77(%rip),%rax
  cmp    $0x384,%edi
  je     L54
  cmp    $0x3e8,%edi
  mov    $0x0,%edx
  lea    D34(%rip),%rax
  cmovne %rdx,%rax
  ret
L72:
  cmp    $0x5a,%edi
  mov    $0x0,%edx
  lea    D133(%rip),%rax
  cmovne %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D54(%rip),%rax
  ret
  lea    D26(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D139(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D28(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D71(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D53(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D30(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D78
type_infered: string
name: disassemble_data
arguments: data_label: D80
type_infered: string
name: disassemble_data
arguments: data_label: D100
type_infered: string
name: disassemble_data
arguments: data_label: D77
type_infered: string
name: disassemble_data
arguments: data_label: D34
type_infered: string
name: disassemble_data
arguments: data_label: D133
type_infered: string
name: disassemble_data
arguments: data_label: D54
type_infered: string
name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D139
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string
name: disassemble_data
arguments: data_label: D71
type_infered: string
name: disassemble_data
arguments: data_label: D53
type_infered: string
name: disassemble_data
arguments: data_label: D30
type_infered: string

tool: D78: C

tool: D80: CD

tool: D100: D

tool: D77: CM

tool: D34: M

tool: D133: XC

tool: D54: L

tool: D26: V

tool: D139: IX

tool: D28: X

tool: D71: XL

tool: D53: I

tool: D30: IV

assistant: ```c
const char *arabic_to_roman(int arabic) {
  switch (arabic) {
  case 1:
    return "I";
  case 4:
    return "IV";
  case 5:
    return "V";
  case 9:
    return "IX";
  case 10:
    return "X";
  case 40:
    return "XL";
  case 50:
    return "L";
  case 90:
    return "XC";
  case 100:
    return "C";
  case 400:
    return "CD";
  case 500:
    return "D";
  case 900:
    return "CM";
  case 1000:
    return "M";
  default:
    return NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_shmem_attach>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <shmctl@plt>
  test   %rax,%rax
  jne    L12
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  jmp    L17
L12:
  mov    $0x0,%eax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int get_shmem_attach(int shmid) {
  struct shmid_ds smem_ds;
  smem_ds.shm_nattch = 0;
  if (shmctl(shmid, IPC_STAT, &smem_ds) == 0)
    return smem_ds.shm_nattch - 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_shmem_attach>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <shmctl@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L22
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L22:
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  jmp    L2
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_shmem_attach(int shmid) {
  struct shmid_ds smem_ds;
  smem_ds.shm_nattch = 0;
  if (shmctl(shmid, IPC_STAT, &smem_ds) == 0)
    return smem_ds.shm_nattch - 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_shmem_attach>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%esi
  call   <shmctl@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L1
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_shmem_attach(int shmid) {
  struct shmid_ds smem_ds;
  smem_ds.shm_nattch = 0;
  if (shmctl(shmid, IPC_STAT, &smem_ds) == 0)
    return smem_ds.shm_nattch - 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_shmem_attach>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%esi
  call   <shmctl@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L14
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_shmem_attach(int shmid) {
  struct shmid_ds smem_ds;
  smem_ds.shm_nattch = 0;
  if (shmctl(shmid, IPC_STAT, &smem_ds) == 0)
    return smem_ds.shm_nattch - 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  subl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x0,-0x4(%rbp)
  jg     L3
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int index;
  index = argc - 1;
  while (index > 0) {
    ft_putstr(argv[index]);
    ft_putchar('\n');
    index--;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%ebx
  test   %ebx,%ebx
  jle    L17
  mov    %rsi,%rbp
  movslq %ebx,%rbx
L1:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <ft_putstr@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L1
L17:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int index;
  index = argc - 1;
  while (index > 0) {
    ft_putstr(argv[index]);
    ft_putchar('\n');
    index--;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L0
  mov    %rsi,%rbp
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <ft_putstr@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  test   %ebx,%ebx
  jg     L2
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int index;
  index = argc - 1;
  while (index > 0) {
    ft_putstr(argv[index]);
    ft_putchar('\n');
    index--;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L5
  mov    %rsi,%rbp
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L16:
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <ft_putstr@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  test   %ebx,%ebx
  jg     L16
L5:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int index;
  index = argc - 1;
  while (index > 0) {
    ft_putstr(argv[index]);
    ft_putchar('\n');
    index--;
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L19
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  jmp    L11
L19:
  nop
L11:
  leave
  ret
```

assistant: ```c
void rotate(int *nums, int numsSize, int k) {
  k %= numsSize;
  if (k == 0) {
    return;
  }
  reverse(nums, 0, numsSize - 1 - k);
  reverse(nums, numsSize - k, numsSize - 1);
  reverse(nums, 0, numsSize - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rotate>:
  endbr64
  mov    %edx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L8
  ret
L8:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  lea    -0x1(%rsi),%r13d
  mov    %r13d,%edx
  sub    %r12d,%edx
  mov    $0x0,%esi
  call   <reverse@plt>
  sub    %r12d,%ebx
  mov    %ebx,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <reverse@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rotate(int *nums, int numsSize, int k) {
  k %= numsSize;
  if (k == 0) {
    return;
  }
  reverse(nums, 0, numsSize - 1 - k);
  reverse(nums, numsSize - k, numsSize - 1);
  reverse(nums, 0, numsSize - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rotate>:
  endbr64
  mov    %edx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L5
  ret
  xchg   %ax,%ax
L5:
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %edx,%r12d
  mov    %r13d,%edx
  push   %rbp
  sub    %r12d,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    %r12d,%ebx
  sub    $0x8,%rsp
  call   <reverse@plt>
  mov    %ebx,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <reverse@plt>
  add    $0x8,%rsp
  mov    %r13d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <reverse@plt>
```

assistant: ```c
void rotate(int *nums, int numsSize, int k) {
  k %= numsSize;
  if (k == 0) {
    return;
  }
  reverse(nums, 0, numsSize - 1 - k);
  reverse(nums, numsSize - k, numsSize - 1);
  reverse(nums, 0, numsSize - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotate>:
  endbr64
  mov    %edx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L0
  ret
  xchg   %ax,%ax
L0:
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %edx,%r12d
  mov    %r13d,%edx
  push   %rbp
  sub    %r12d,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    %r12d,%ebx
  sub    $0x8,%rsp
  call   <reverse@plt>
  mov    %ebx,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <reverse@plt>
  add    $0x8,%rsp
  mov    %r13d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <reverse@plt>
```

assistant: ```c
void rotate(int *nums, int numsSize, int k) {
  k %= numsSize;
  if (k == 0) {
    return;
  }
  reverse(nums, 0, numsSize - 1 - k);
  reverse(nums, numsSize - k, numsSize - 1);
  reverse(nums, 0, numsSize - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bintol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5f,%eax
  je     L29
  cmp    $0x5f,%eax
  jg     L59
  cmp    $0x30,%eax
  je     L53
  cmp    $0x31,%eax
  jne    L59
  shlq   -0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L16
L53:
  shlq   -0x8(%rbp)
  jmp    L16
L59:
  mov    -0x8(%rbp),%rax
  jmp    L89
L29:
  nop
L16:
  addq   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rax
L89:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long bintol(const char *str) {
  unsigned long sum = 0L;
  while (*str) {
    switch (*str) {
    case '1':
      sum <<= 1;
      ++sum;
      break;
    case '0':
      sum <<= 1;
      break;
    case '_':
      break;
    default:
      return sum;
    }
    ++str;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bintol>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
  mov    $0x0,%edx
  jmp    L5
L39:
  lea    0x1(%rdx,%rdx,1),%rdx
L68:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L41
L5:
  cmp    $0x31,%al
  je     L39
  cmp    $0x5f,%al
  je     L68
  cmp    $0x30,%al
  je     L13
L41:
  mov    %rdx,%rax
  ret
L13:
  add    %rdx,%rdx
  jmp    L68
L20:
  mov    $0x0,%edx
  jmp    L41
```

assistant: ```c
unsigned long bintol(const char *str) {
  unsigned long sum = 0L;
  while (*str) {
    switch (*str) {
    case '1':
      sum <<= 1;
      ++sum;
      break;
    case '0':
      sum <<= 1;
      break;
    case '_':
      break;
    default:
      return sum;
    }
    ++str;
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bintol>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L21
  cmp    $0x31,%al
  je     L54
L15:
  cmp    $0x5f,%al
  je     L61
  cmp    $0x30,%al
  je     L6
L21:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L6:
  add    %r8,%r8
L61:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L21
L9:
  cmp    $0x31,%al
  jne    L15
L54:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%r8,%r8,1),%r8
  test   %al,%al
  jne    L9
  jmp    L21
```

assistant: ```c
unsigned long bintol(const char *str) {
  unsigned long sum = 0L;
  while (*str) {
    switch (*str) {
    case '1':
      sum <<= 1;
      ++sum;
      break;
    case '0':
      sum <<= 1;
      break;
    case '_':
      break;
    default:
      return sum;
    }
    ++str;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bintol>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L14
  cmp    $0x31,%al
  je     L26
L61:
  cmp    $0x5f,%al
  je     L32
  cmp    $0x30,%al
  je     L75
L14:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L75:
  add    %r8,%r8
L32:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L14
L66:
  cmp    $0x31,%al
  jne    L61
L26:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%r8,%r8,1),%r8
  test   %al,%al
  jne    L66
  jmp    L14
```

assistant: ```c
unsigned long bintol(const char *str) {
  unsigned long sum = 0L;
  while (*str) {
    switch (*str) {
    case '1':
      sum <<= 1;
      ++sum;
      break;
    case '0':
      sum <<= 1;
      break;
    case '_':
      break;
    default:
      return sum;
    }
    ++str;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jge    L3
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L3:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D22
type_guessed: string
name: unpack_data
arguments: tag: D14
type_guessed: string

tool: D22: %d %d

tool: D14: 
%d,%d


assistant: ```c
void main() {
  int a, b;
  int *pointer_1, *pointer_2;
  scanf("%d %d", &a, &b);
  pointer_1 = &a;
  pointer_2 = &b;
  if (a < b)
    swap(pointer_1, pointer_2);
  printf("\n%d,%d\n", *pointer_1, *pointer_2);
  printf("\n%d,%d\n", a, b);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,(%rsp)
  jl     L11
L28:
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  jmp    L28
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string

tool: D2: %d %d

tool: D16: 
%d,%d


assistant: ```c
void main() {
  int a, b;
  int *pointer_1, *pointer_2;
  scanf("%d %d", &a, &b);
  pointer_1 = &a;
  pointer_2 = &b;
  if (a < b)
    swap(pointer_1, pointer_2);
  printf("\n%d,%d\n", *pointer_1, *pointer_2);
  printf("\n%d,%d\n", a, b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  jl     L9
L23:
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  jmp    L23
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type: string
name: retrieve_data
arguments: label: D12
type: string

tool: D19: %d %d

tool: D12: 
%d,%d


assistant: ```c
void main() {
  int a, b;
  int *pointer_1, *pointer_2;
  scanf("%d %d", &a, &b);
  pointer_1 = &a;
  pointer_2 = &b;
  if (a < b)
    swap(pointer_1, pointer_2);
  printf("\n%d,%d\n", *pointer_1, *pointer_2);
  printf("\n%d,%d\n", a, b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  jl     L28
L3:
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  jmp    L3
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D5: %d %d

tool: D6: 
%d,%d


assistant: ```c
void main() {
  int a, b;
  int *pointer_1, *pointer_2;
  scanf("%d %d", &a, &b);
  pointer_1 = &a;
  pointer_2 = &b;
  if (a < b)
    swap(pointer_1, pointer_2);
  printf("\n%d,%d\n", *pointer_1, *pointer_2);
  printf("\n%d,%d\n", a, b);
}
```