ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<_syscall_poll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x30(%rbp)
  js     L35
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0xf4240,%rax,%rax
  mov    %rax,-0x18(%rbp)
L35:
  cmpl   $0x0,-0x30(%rbp)
  js     L15
  lea    -0x20(%rbp),%rax
  jmp    L26
L15:
  mov    $0x0,%eax
L26:
  mov    D4(%rip),%rdx
  mov    (%rdx),%edi
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rsi
  mov    $0x0,%r8d
  mov    %rax,%rcx
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int _syscall_poll(struct pollfd fds[], nfds_t nfds, int timeout) {
  struct timespec tmo;
  if (timeout > -1) {
    tmo.tv_sec = timeout / 1000;
    tmo.tv_nsec = 1000000L * (timeout % 1000);
  }
  return syscall(__NR_ppoll, fds, nfds, ((timeout > -1) ? (&tmo) : 0), 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_syscall_poll>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ecx
  test   %edx,%edx
  js     L10
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edx
  movslq %edx,%rdx
  imul   $0xf4240,%rdx,%rdx
  mov    %rdx,0x8(%rsp)
  mov    %rsp,%rcx
L10:
  mov    $0x0,%r8d
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int _syscall_poll(struct pollfd fds[], nfds_t nfds, int timeout) {
  struct timespec tmo;
  if (timeout > -1) {
    tmo.tv_sec = timeout / 1000;
    tmo.tv_nsec = 1000000L * (timeout % 1000);
  }
  return syscall(__NR_ppoll, fds, nfds, ((timeout > -1) ? (&tmo) : 0), 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_syscall_poll>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r9
  mov    %esi,%r10d
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  js     L17
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  mov    %rsp,%rcx
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edx
  movslq %edx,%rdx
  imul   $0xf4240,%rdx,%rdx
  mov    %rdx,0x8(%rsp)
L17:
  mov    D4(%rip),%rax
  xor    %r8d,%r8d
  mov    %r10d,%edx
  mov    %r9,%rsi
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int _syscall_poll(struct pollfd fds[], nfds_t nfds, int timeout) {
  struct timespec tmo;
  if (timeout > -1) {
    tmo.tv_sec = timeout / 1000;
    tmo.tv_nsec = 1000000L * (timeout % 1000);
  }
  return syscall(__NR_ppoll, fds, nfds, ((timeout > -1) ? (&tmo) : 0), 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_syscall_poll>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r9
  mov    %esi,%r10d
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  js     L17
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  mov    %rsp,%rcx
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edx
  movslq %edx,%rdx
  imul   $0xf4240,%rdx,%rdx
  mov    %rdx,0x8(%rsp)
L17:
  mov    D2(%rip),%rax
  xor    %r8d,%r8d
  mov    %r10d,%edx
  mov    %r9,%rsi
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int _syscall_poll(struct pollfd fds[], nfds_t nfds, int timeout) {
  struct timespec tmo;
  if (timeout > -1) {
    tmo.tv_sec = timeout / 1000;
    tmo.tv_nsec = 1000000L * (timeout % 1000);
  }
  return syscall(__NR_ppoll, fds, nfds, ((timeout > -1) ? (&tmo) : 0), 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kore_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0xe0(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L21
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L21:
  mov    -0xe0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xe0(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpl   $0xffffffff,-0xb4(%rbp)
  je     L34
  mov    -0xb4(%rbp),%eax
  cltq
  cmp    %rax,-0xd0(%rbp)
  ja     L48
L34:
  mov    $0x0,%eax
  jmp    L6
L48:
  cmpq   $0x0,-0xd8(%rbp)
  je     L23
  mov    -0xd8(%rbp),%rax
  mov    -0xb4(%rbp),%edx
  mov    %edx,(%rax)
L23:
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int kore_snprintf(char *str, size_t size, int *len, const char *fmt, ...) {
  int l;
  va_list args;
  va_start(args, fmt);
  l = vsnprintf(str, size, fmt, args);
  va_end(args);
  if (l == -1 || (size_t)l >= size)
    return (0);
  if (len != NULL)
    *len = l;
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<kore_snprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%rbx
  mov    %rcx,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  cmp    $0xffffffff,%ebx
  je     L19
  movslq %ebx,%rdx
  cmp    %rbp,%rdx
  jae    L19
  mov    $0x1,%eax
  test   %r13,%r13
  je     L19
  mov    %ebx,0x0(%r13)
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int kore_snprintf(char *str, size_t size, int *len, const char *fmt, ...) {
  int l;
  va_list args;
  va_start(args, fmt);
  l = vsnprintf(str, size, fmt, args);
  va_end(args);
  if (l == -1 || (size_t)l >= size)
    return (0);
  if (len != NULL)
    *len = l;
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<kore_snprintf>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %r14d,%edi
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rcx,%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  mov    %eax,%ebx
  call   <va_end@plt>
  xor    %eax,%eax
  cmp    $0xffffffff,%ebx
  je     L15
  movslq %ebx,%rdx
  cmp    %rbp,%rdx
  jae    L15
  mov    $0x1,%eax
  test   %r13,%r13
  je     L15
  mov    %ebx,0x0(%r13)
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int kore_snprintf(char *str, size_t size, int *len, const char *fmt, ...) {
  int l;
  va_list args;
  va_start(args, fmt);
  l = vsnprintf(str, size, fmt, args);
  va_end(args);
  if (l == -1 || (size_t)l >= size)
    return (0);
  if (len != NULL)
    *len = l;
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kore_snprintf>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %r14d,%edi
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rcx,%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  mov    %eax,%ebx
  call   <va_end@plt>
  xor    %eax,%eax
  cmp    $0xffffffff,%ebx
  je     L29
  movslq %ebx,%rdx
  cmp    %rbp,%rdx
  jae    L29
  mov    $0x1,%eax
  test   %r13,%r13
  je     L29
  mov    %ebx,0x0(%r13)
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int kore_snprintf(char *str, size_t size, int *len, const char *fmt, ...) {
  int l;
  va_list args;
  va_start(args, fmt);
  l = vsnprintf(str, size, fmt, args);
  va_end(args);
  if (l == -1 || (size_t)l >= size)
    return (0);
  if (len != NULL)
    *len = l;
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<new_str_pad_to_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x4(%rbp)
L7:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L18
  jmp    L50
L2:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x2c(%rbp),%edx
  mov    %dl,(%rax)
L50:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jg     L2
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L18:
  subl   $0x1,-0x4(%rbp)
L9:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  subq   $0x1,-0x18(%rbp)
  jmp    L19
L48:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x2c(%rbp),%edx
  mov    %dl,(%rax)
L19:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jns    L48
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void new_str_pad_to_l(char *dst, const char *src, size_t width, unsigned char pad) {
  int i = (int)width;
  do {
    if (*src == '\n') {
      while (i-- > 0)
        *dst++ = pad;
      i = (int)width;
    } else {
      i--;
    }
  } while ((*dst++ = *src++));
  dst--;
  while (i-- >= 0)
    *dst++ = pad;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<new_str_pad_to_l>:
  endbr64
  mov    %ecx,%r8d
  mov    %edx,%r10d
  add    $0x1,%rsi
  jmp    L15
L43:
  test   %edx,%edx
  jle    L87
  mov    %edx,%r9d
  add    %rdi,%r9
  mov    %rdi,%rax
L58:
  add    $0x1,%rax
  mov    %r8b,-0x1(%rax)
  cmp    %r9,%rax
  jne    L58
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%rax
  mov    %r10d,%edx
L75:
  lea    0x1(%rax),%rdi
  movzbl -0x1(%rcx),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  je     L31
L23:
  add    $0x1,%rsi
L15:
  mov    %rsi,%rcx
  cmpb   $0xa,-0x1(%rsi)
  je     L43
  sub    $0x1,%edx
  mov    %rdi,%rax
  jmp    L75
L31:
  test   %edx,%edx
  js     L2
  lea    0x1(%rdx),%edx
  add    %rax,%rdx
L77:
  add    $0x1,%rax
  mov    %r8b,-0x1(%rax)
  cmp    %rdx,%rax
  jne    L77
  ret
L87:
  movb   $0xa,(%rdi)
  lea    0x1(%rdi),%rdi
  mov    %r10d,%edx
  jmp    L23
L2:
  ret
```

assistant: ```c
void new_str_pad_to_l(char *dst, const char *src, size_t width, unsigned char pad) {
  int i = (int)width;
  do {
    if (*src == '\n') {
      while (i-- > 0)
        *dst++ = pad;
      i = (int)width;
    } else {
      i--;
    }
  } while ((*dst++ = *src++));
  dst--;
  while (i-- >= 0)
    *dst++ = pad;
}
```
user: What is the c source code of the assembly code below:

```asm
<new_str_pad_to_l>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  jmp    L15
  nopl   0x0(%rax)
L26:
  mov    %al,(%rdi)
  lea    0x1(%rdi),%rsi
  test   %al,%al
  je     L57
L47:
  mov    %ecx,%edx
  mov    %rsi,%rdi
L15:
  movzbl 0x0(%r13),%eax
  lea    -0x1(%rdx),%ecx
  add    $0x1,%r13
  cmp    $0xa,%al
  jne    L26
  test   %edx,%edx
  jle    L48
  lea    0x1(%rcx),%rbx
  movsbl %r12b,%esi
  mov    %rbx,%rdx
  call   <memset@plt>
  mov    %ebp,%ecx
  mov    %rax,%rdi
  movzbl -0x1(%r13),%eax
  add    %rbx,%rdi
  mov    %al,(%rdi)
  lea    0x1(%rdi),%rsi
  test   %al,%al
  jne    L47
  nopw   0x0(%rax,%rax,1)
L57:
  test   %ecx,%ecx
  js     L55
  movslq %ecx,%rdx
  pop    %rbx
  movsbl %r14b,%esi
  pop    %rbp
  add    $0x1,%rdx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <memset@plt>
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L48:
  movb   $0xa,(%rdi)
  lea    0x1(%rdi),%rsi
  mov    %ebp,%ecx
  jmp    L47
```

assistant: ```c
void new_str_pad_to_l(char *dst, const char *src, size_t width, unsigned char pad) {
  int i = (int)width;
  do {
    if (*src == '\n') {
      while (i-- > 0)
        *dst++ = pad;
      i = (int)width;
    } else {
      i--;
    }
  } while ((*dst++ = *src++));
  dst--;
  while (i-- >= 0)
    *dst++ = pad;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<new_str_pad_to_l>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  jmp    L23
  nopl   0x0(%rax)
L48:
  mov    %al,(%rdi)
  lea    0x1(%rdi),%rsi
  test   %al,%al
  je     L54
L13:
  mov    %ecx,%edx
  mov    %rsi,%rdi
L23:
  movzbl 0x0(%r13),%eax
  lea    -0x1(%rdx),%ecx
  add    $0x1,%r13
  cmp    $0xa,%al
  jne    L48
  test   %edx,%edx
  jle    L43
  lea    0x1(%rcx),%rbx
  movsbl %r12b,%esi
  mov    %rbx,%rdx
  call   <memset@plt>
  mov    %ebp,%ecx
  mov    %rax,%rdi
  movzbl -0x1(%r13),%eax
  add    %rbx,%rdi
  mov    %al,(%rdi)
  lea    0x1(%rdi),%rsi
  test   %al,%al
  jne    L13
  nopw   0x0(%rax,%rax,1)
L54:
  test   %ecx,%ecx
  js     L65
  movslq %ecx,%rdx
  pop    %rbx
  movsbl %r14b,%esi
  pop    %rbp
  add    $0x1,%rdx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <memset@plt>
L65:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L43:
  movb   $0xa,(%rdi)
  lea    0x1(%rdi),%rsi
  mov    %ebp,%ecx
  jmp    L13
```

assistant: ```c
void new_str_pad_to_l(char *dst, const char *src, size_t width, unsigned char pad) {
  int i = (int)width;
  do {
    if (*src == '\n') {
      while (i-- > 0)
        *dst++ = pad;
      i = (int)width;
    } else {
      i--;
    }
  } while ((*dst++ = *src++));
  dst--;
  while (i-- >= 0)
    *dst++ = pad;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  jmp    L41
L6:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jne    L10
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  je     L40
L10:
  addq   $0x1,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  imul   %rdx,%rax
  shr    %rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  imul   %rdx,%rax
  shr    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L41:
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L6
  jmp    L54
L40:
  nop
L54:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string

tool: D3: Case %llu: %llu


tool: D17: %llu%llu

assistant: ```c
main() {
  unsigned long long a, b, c, d, reg = 0;
  while (scanf("%llu%llu", &a, &b) == 2) {
    if (a == b && b == 0)
      break;
    reg++;
    c = a * (a - 1) / 2;
    d = b * (b - 1) / 2;
    printf("Case %llu: %llu\n", reg, c * d);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  lea    D15(%rip),%rbp
  lea    D9(%rip),%r14
  jmp    L17
L21:
  add    $0x1,%rbx
  lea    -0x1(%rax),%rdx
  imul   %rax,%rdx
  shr    %rdx
  lea    -0x1(%rcx),%rax
  imul   %rcx,%rax
  shr    %rax
  imul   %rax,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
L17:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L9
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%rcx
  test   %rcx,%rcx
  jne    L21
  cmp    %rcx,%rax
  jne    L21
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D15: %llu%llu

tool: D9: Case %llu: %llu


assistant: ```c
main() {
  unsigned long long a, b, c, d, reg = 0;
  while (scanf("%llu%llu", &a, &b) == 2) {
    if (a == b && b == 0)
      break;
    reg++;
    c = a * (a - 1) / 2;
    d = b * (b - 1) / 2;
    printf("Case %llu: %llu\n", reg, c * d);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  jmp    L10
  nopl   0x0(%rax)
L5:
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%rcx
  cmp    %rcx,%rax
  jne    L48
  test   %rcx,%rcx
  je     L7
L48:
  lea    -0x1(%rax),%rdx
  add    $0x1,%rbx
  mov    %r14,%rdi
  imul   %rax,%rdx
  lea    -0x1(%rcx),%rax
  mov    %rbx,%rsi
  imul   %rcx,%rax
  shr    %rdx
  shr    %rax
  imul   %rax,%rdx
  call   <printf@plt>
L10:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L5
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D12: Case %llu: %llu


tool: D8: %llu%llu

assistant: ```c
main() {
  unsigned long long a, b, c, d, reg = 0;
  while (scanf("%llu%llu", &a, &b) == 2) {
    if (a == b && b == 0)
      break;
    reg++;
    c = a * (a - 1) / 2;
    d = b * (b - 1) / 2;
    printf("Case %llu: %llu\n", reg, c * d);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  jmp    L0
  nopl   0x0(%rax)
L43:
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%rcx
  cmp    %rcx,%rax
  jne    L48
  test   %rcx,%rcx
  je     L10
L48:
  lea    -0x1(%rax),%rdx
  add    $0x1,%rbx
  mov    %r14,%rdi
  imul   %rax,%rdx
  lea    -0x1(%rcx),%rax
  mov    %rbx,%rsi
  imul   %rcx,%rax
  shr    %rdx
  shr    %rax
  imul   %rax,%rdx
  call   <printf@plt>
L0:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L43
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string

tool: D1: Case %llu: %llu


tool: D10: %llu%llu

assistant: ```c
main() {
  unsigned long long a, b, c, d, reg = 0;
  while (scanf("%llu%llu", &a, &b) == 2) {
    if (a == b && b == 0)
      break;
    reg++;
    c = a * (a - 1) / 2;
    d = b * (b - 1) / 2;
    printf("Case %llu: %llu\n", reg, c * d);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  D13(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L24
L17:
  nop
  movss  -0x4(%rbp),%xmm0
  movss  D5(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L24:
  pxor   %xmm0,%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L17
  pxor   %xmm0,%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jne    L17
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_guessed: byte[4]
name: extract_symbolic_data
arguments: tag: D5
type_guessed: f32

tool: {"D13": [0x00,0x00,0xe0,0x41]}

tool: D5: 1

assistant: ```c
void Delay(void) {
  float usdelay = 0.0;
  usdelay = (1000 / ((1.0 / 28000000) * 1000000000));
  while (usdelay != 0) {
    asm("NOP");
    usdelay--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Delay>:
  endbr64
  mov    $0x1c,%eax
L9:
  nop
  sub    $0x1,%eax
  jne    L9
  ret
```

assistant: ```c
void Delay(void) {
  float usdelay = 0.0;
  usdelay = (1000 / ((1.0 / 28000000) * 1000000000));
  while (usdelay != 0) {
    asm("NOP");
    usdelay--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Delay>:
  endbr64
  mov    $0x1c,%eax
  nopl   0x0(%rax)
L2:
  nop
  sub    $0x1,%eax
  jne    L2
  ret
```

assistant: ```c
void Delay(void) {
  float usdelay = 0.0;
  usdelay = (1000 / ((1.0 / 28000000) * 1000000000));
  while (usdelay != 0) {
    asm("NOP");
    usdelay--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Delay>:
  endbr64
  mov    $0x1c,%eax
  nopl   0x0(%rax)
L2:
  nop
  sub    $0x1,%eax
  jne    L2
  ret
```

assistant: ```c
void Delay(void) {
  float usdelay = 0.0;
  usdelay = (1000 / ((1.0 / 28000000) * 1000000000));
  while (usdelay != 0) {
    asm("NOP");
    usdelay--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decode_native_64_signed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int64_t decode_native_64_signed(char *buf) {
  int64_t rv;
  memcpy(&rv, buf, 8);
  return rv;
}
```