ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ptriproj>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r13
  mov    %r8,%r15
  mov    %r9d,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <lmoutr@plt>
  add    $0x10,%rsp
  test   %r14d,%r14d
  je     L16
  movsd  (%rsp),%xmm0
  comisd D18(%rip),%xmm0
  jb     L60
  movsd  0x8(%rsp),%xmm1
  comisd D18(%rip),%xmm1
  jb     L60
  movsd  D9(%rip),%xmm3
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  comisd %xmm2,%xmm3
  jae    L43
L60:
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L10
  pxor   %xmm0,%xmm0
  comisd 0x8(%rsp),%xmm0
  ja     L95
  mov    %r14d,%r8d
  mov    %r15,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <plinproj@plt>
  movsd  %xmm0,0x10(%rsp)
  jmp    L81
L43:
  mov    %r15,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <routlm@plt>
  jmp    L81
L10:
  mov    %r14d,%r8d
  mov    %r15,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <plinproj@plt>
  movsd  %xmm0,0x10(%rsp)
  jmp    L81
L95:
  mov    %r14d,%r8d
  mov    %r15,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <plinproj@plt>
  movsd  %xmm0,0x10(%rsp)
  jmp    L81
L16:
  mov    %r15,%rcx
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <routlm@plt>
L81:
  movsd  0x10(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D18
type_guessed: byte[16]
name: parse_data
arguments: data_label: D9
type_guessed: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double ptriproj(double *v1, double *v2, double *v3, double *r, double *proj, int flag) {
  double la, mu, d;
  lmoutr(v1, v2, v3, r, &la, &mu, &d);
  if (flag) {
    if (la >= 0 && mu >= 0 && (la + mu) <= 1)
      routlm(v1, v2, v3, la, mu, proj);
    else if (la < 0)
      d = plinproj(v1, v3, r, proj, flag);
    else if (mu < 0)
      d = plinproj(v1, v2, r, proj, flag);
    else
      d = plinproj(v2, v3, r, proj, flag);
  } else {
    routlm(v1, v2, v3, la, mu, proj);
  }
  return d;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ptriproj>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <lmoutr@plt>
  pop    %rax
  pop    %rdx
  test   %ebx,%ebx
  je     L26
  movsd  (%rsp),%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm0,%xmm2
  jb     L0
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm1
  jb     L0
  movapd %xmm2,%xmm3
  movsd  D1(%rip),%xmm4
  addsd  %xmm1,%xmm3
  comisd %xmm3,%xmm4
  jae    L75
L0:
  comisd %xmm2,%xmm0
  mov    %ebx,%r8d
  mov    %r15,%rcx
  mov    %r14,%rdx
  ja     L51
  comisd 0x8(%rsp),%xmm0
  ja     L82
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <plinproj@plt>
L97:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L26:
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    %r15,%rcx
L60:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <routlm@plt>
  movsd  0x10(%rsp),%xmm0
  jmp    L97
  nopl   0x0(%rax)
L51:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <plinproj@plt>
  jmp    L97
  nopl   (%rax)
L75:
  mov    %r15,%rcx
  movapd %xmm2,%xmm0
  jmp    L60
  nopl   0x0(%rax)
L82:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <plinproj@plt>
  jmp    L97
L95:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double ptriproj(double *v1, double *v2, double *v3, double *r, double *proj, int flag) {
  double la, mu, d;
  lmoutr(v1, v2, v3, r, &la, &mu, &d);
  if (flag) {
    if (la >= 0 && mu >= 0 && (la + mu) <= 1)
      routlm(v1, v2, v3, la, mu, proj);
    else if (la < 0)
      d = plinproj(v1, v3, r, proj, flag);
    else if (mu < 0)
      d = plinproj(v1, v2, r, proj, flag);
    else
      d = plinproj(v2, v3, r, proj, flag);
  } else {
    routlm(v1, v2, v3, la, mu, proj);
  }
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ptriproj>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <lmoutr@plt>
  pop    %rax
  pop    %rdx
  test   %ebx,%ebx
  je     L48
  movsd  (%rsp),%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm0,%xmm2
  jb     L105
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm1
  jb     L105
  movapd %xmm2,%xmm3
  movsd  D6(%rip),%xmm4
  addsd  %xmm1,%xmm3
  comisd %xmm3,%xmm4
  jae    L26
L105:
  comisd %xmm2,%xmm0
  mov    %ebx,%r8d
  mov    %r15,%rcx
  mov    %r14,%rdx
  ja     L104
  comisd 0x8(%rsp),%xmm0
  ja     L109
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <plinproj@plt>
L65:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L48:
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    %r15,%rcx
L38:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <routlm@plt>
  movsd  0x10(%rsp),%xmm0
  jmp    L65
  nopl   0x0(%rax)
L104:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <plinproj@plt>
  jmp    L65
  nopl   (%rax)
L26:
  mov    %r15,%rcx
  movapd %xmm2,%xmm0
  jmp    L38
  nopl   0x0(%rax)
L109:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <plinproj@plt>
  jmp    L65
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double ptriproj(double *v1, double *v2, double *v3, double *r, double *proj, int flag) {
  double la, mu, d;
  lmoutr(v1, v2, v3, r, &la, &mu, &d);
  if (flag) {
    if (la >= 0 && mu >= 0 && (la + mu) <= 1)
      routlm(v1, v2, v3, la, mu, proj);
    else if (la < 0)
      d = plinproj(v1, v3, r, proj, flag);
    else if (mu < 0)
      d = plinproj(v1, v2, r, proj, flag);
    else
      d = plinproj(v2, v3, r, proj, flag);
  } else {
    routlm(v1, v2, v3, la, mu, proj);
  }
  return d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<exponent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %esi,-0x22c(%rbp)
  mov    %edx,-0x230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x228(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x228(%rbp)
  mov    -0x230(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0x0,-0x22c(%rbp)
  jns    L43
  negl   -0x22c(%rbp)
  mov    -0x228(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x228(%rbp)
  movb   $0x2d,(%rax)
  jmp    L71
L43:
  mov    -0x228(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x228(%rbp)
  movb   $0x2b,(%rax)
L71:
  lea    -0x210(%rbp),%rax
  add    $0x200,%rax
  mov    %rax,-0x218(%rbp)
  cmpl   $0x9,-0x22c(%rbp)
  jle    L56
L42:
  mov    -0x22c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x218(%rbp)
  mov    %eax,%edx
  mov    -0x218(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x22c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x22c(%rbp)
  cmpl   $0x9,-0x22c(%rbp)
  jg     L42
  mov    -0x22c(%rbp),%eax
  add    $0x30,%eax
  subq   $0x1,-0x218(%rbp)
  mov    %eax,%edx
  mov    -0x218(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L30
L76:
  mov    -0x218(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x218(%rbp)
  mov    -0x228(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x228(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L30:
  lea    -0x210(%rbp),%rax
  add    $0x200,%rax
  cmp    %rax,-0x218(%rbp)
  jb     L76
  jmp    L3
L56:
  mov    -0x228(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x228(%rbp)
  movb   $0x30,(%rax)
  mov    -0x22c(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x228(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x228(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L3:
  mov    -0x228(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
char *exponent(char *p, int exp, int fmtch) {
  char *t;
  char expbuf[512];
  *p++ = fmtch;
  if (exp < 0) {
    exp = -exp;
    *p++ = '-';
  } else
    *p++ = '+';
  t = expbuf + 512;
  if (exp > 9) {
    do {
      *--t = ((exp % 10) + '0');
    } while ((exp /= 10) > 9);
    *--t = ((exp) + '0');
    for (; t < expbuf + 512; *p++ = *t++)
      ;
  } else {
    *p++ = '0';
    *p++ = ((exp) + '0');
  }
  return (p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exponent>:
  endbr64
  sub    $0x218,%rsp
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %dl,(%rdi)
  lea    0x2(%rdi),%r8
  mov    $0x2b,%eax
  test   %esi,%esi
  js     L89
L77:
  mov    %al,0x1(%rdi)
  cmp    $0x9,%ecx
  jle    L81
  lea    0x200(%rsp),%rdx
L59:
  mov    %rdx,%r9
  sub    $0x1,%rdx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  mov    %ecx,%esi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%rdx)
  mov    %ecx,%esi
  mov    %eax,%ecx
  cmp    $0x63,%esi
  jg     L59
  lea    -0x2(%r9),%rax
  add    $0x30,%ecx
  mov    %cl,-0x1(%rdx)
  lea    0x200(%rsp),%rdx
  cmp    %rdx,%rax
  jae    L27
  mov    %r8,%rdx
  lea    0x200(%rsp),%rsi
L87:
  add    $0x1,%rax
  add    $0x1,%rdx
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rax
  jne    L87
  lea    0x202(%rsp),%rax
  sub    %r9,%rax
  add    %r8,%rax
  jmp    L58
L89:
  neg    %ecx
  mov    $0x2d,%eax
  jmp    L77
L81:
  movb   $0x30,(%r8)
  lea    0x2(%r8),%rax
  add    $0x30,%ecx
  mov    %cl,0x1(%r8)
L58:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x218,%rsp
  ret
L27:
  mov    %r8,%rax
  jmp    L58
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *exponent(char *p, int exp, int fmtch) {
  char *t;
  char expbuf[512];
  *p++ = fmtch;
  if (exp < 0) {
    exp = -exp;
    *p++ = '-';
  } else
    *p++ = '+';
  t = expbuf + 512;
  if (exp > 9) {
    do {
      *--t = ((exp % 10) + '0');
    } while ((exp /= 10) > 9);
    *--t = ((exp) + '0');
    for (; t < expbuf + 512; *p++ = *t++)
      ;
  } else {
    *p++ = '0';
    *p++ = ((exp) + '0');
  }
  return (p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exponent>:
  endbr64
  sub    $0x218,%rsp
  mov    %esi,%ecx
  lea    0x2(%rdi),%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %dl,(%rdi)
  mov    $0x2b,%eax
  test   %esi,%esi
  jns    L61
  neg    %ecx
  mov    $0x2d,%eax
L61:
  mov    %al,0x1(%rdi)
  cmp    $0x9,%ecx
  jle    L58
  lea    0x200(%rsp),%r10
  mov    %r10,%r8
  nopl   (%rax)
L10:
  movslq %ecx,%rax
  mov    %ecx,%edx
  mov    %r8,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  lea    -0x1(%r8),%r8
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %ecx,%edx
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,-0x1(%rdi)
  mov    %ecx,%edx
  mov    %eax,%ecx
  cmp    $0x63,%edx
  jg     L10
  add    $0x30,%ecx
  lea    -0x2(%rdi),%rax
  mov    %cl,-0x1(%r8)
  cmp    %r10,%rax
  jae    L76
  mov    %r9,%rdx
  jmp    L49
  nopl   0x0(%rax)
L40:
  movzbl (%rax),%ecx
L49:
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %r10,%rax
  jne    L40
  lea    0x202(%rsp),%rax
  sub    %rdi,%rax
  add    %rax,%r9
L76:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  mov    %r9,%rax
  add    $0x218,%rsp
  ret
  nop
L58:
  add    $0x30,%ecx
  movb   $0x30,0x2(%rdi)
  lea    0x4(%rdi),%r9
  mov    %cl,0x3(%rdi)
  jmp    L76
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *exponent(char *p, int exp, int fmtch) {
  char *t;
  char expbuf[512];
  *p++ = fmtch;
  if (exp < 0) {
    exp = -exp;
    *p++ = '-';
  } else
    *p++ = '+';
  t = expbuf + 512;
  if (exp > 9) {
    do {
      *--t = ((exp % 10) + '0');
    } while ((exp /= 10) > 9);
    *--t = ((exp) + '0');
    for (; t < expbuf + 512; *p++ = *t++)
      ;
  } else {
    *p++ = '0';
    *p++ = ((exp) + '0');
  }
  return (p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<exponent>:
  endbr64
  push   %rbx
  mov    %esi,%ecx
  lea    0x2(%rdi),%r8
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %dl,(%rdi)
  mov    $0x2b,%eax
  test   %esi,%esi
  jns    L27
  neg    %ecx
  mov    $0x2d,%eax
L27:
  mov    %al,0x1(%rdi)
  cmp    $0x9,%ecx
  jle    L26
  lea    0x200(%rsp),%r10
  mov    %r10,%rdx
  xchg   %ax,%ax
L34:
  movslq %ecx,%rax
  mov    %ecx,%esi
  mov    %rdx,%r9
  sub    $0x1,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  mov    %ecx,%esi
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%rdx)
  mov    %ecx,%esi
  mov    %eax,%ecx
  cmp    $0x63,%esi
  jg     L34
  add    $0x30,%ecx
  lea    -0x2(%r9),%rsi
  mov    %cl,-0x1(%rdx)
  cmp    %r10,%rsi
  jae    L40
  lea    0x202(%rsp),%rbx
  mov    %r8,%rdi
  sub    %r9,%rbx
  mov    %rbx,%rdx
  call   <memcpy@plt>
  mov    %rax,%r8
  add    %rbx,%r8
L40:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x210,%rsp
  mov    %r8,%rax
  pop    %rbx
  ret
  xchg   %ax,%ax
L26:
  add    $0x30,%ecx
  movb   $0x30,0x2(%rdi)
  lea    0x4(%rdi),%r8
  mov    %cl,0x3(%rdi)
  jmp    L40
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *exponent(char *p, int exp, int fmtch) {
  char *t;
  char expbuf[512];
  *p++ = fmtch;
  if (exp < 0) {
    exp = -exp;
    *p++ = '-';
  } else
    *p++ = '+';
  t = expbuf + 512;
  if (exp > 9) {
    do {
      *--t = ((exp % 10) + '0');
    } while ((exp /= 10) > 9);
    *--t = ((exp) + '0');
    for (; t < expbuf + 512; *p++ = *t++)
      ;
  } else {
    *p++ = '0';
    *p++ = ((exp) + '0');
  }
  return (p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_get_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L2
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x3c,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  add    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L7
L2:
  movl   $0x30,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char _get_digit(uint64_t *fr, int *digit_count) {
  int rval;
  if (*digit_count > 0) {
    *digit_count -= 1;
    *fr = *fr * 10;
    rval = ((*fr >> 60) & 0xF) + '0';
    *fr &= 0x0FFFFFFFFFFFFFFFull;
  } else
    rval = '0';
  return (char)(rval);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_get_digit>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x30,%eax
  test   %edx,%edx
  jle    L7
  sub    $0x1,%edx
  mov    %edx,(%rsi)
  mov    (%rdi),%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  mov    $0x3c,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  add    $0x30,%eax
L7:
  ret
```

assistant: ```c
char _get_digit(uint64_t *fr, int *digit_count) {
  int rval;
  if (*digit_count > 0) {
    *digit_count -= 1;
    *fr = *fr * 10;
    rval = ((*fr >> 60) & 0xF) + '0';
    *fr &= 0x0FFFFFFFFFFFFFFFull;
  } else
    rval = '0';
  return (char)(rval);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_get_digit>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x30,%eax
  test   %edx,%edx
  jle    L7
  sub    $0x1,%edx
  mov    $0x3c,%ecx
  mov    %edx,(%rsi)
  mov    (%rdi),%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  sar    %cl,%eax
  and    $0xf,%eax
  add    $0x30,%eax
L7:
  ret
```

assistant: ```c
char _get_digit(uint64_t *fr, int *digit_count) {
  int rval;
  if (*digit_count > 0) {
    *digit_count -= 1;
    *fr = *fr * 10;
    rval = ((*fr >> 60) & 0xF) + '0';
    *fr &= 0x0FFFFFFFFFFFFFFFull;
  } else
    rval = '0';
  return (char)(rval);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_get_digit>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x30,%eax
  test   %edx,%edx
  jle    L0
  sub    $0x1,%edx
  mov    $0x3c,%ecx
  mov    %edx,(%rsi)
  mov    (%rdi),%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  sar    %cl,%eax
  and    $0xf,%eax
  add    $0x30,%eax
L0:
  ret
```

assistant: ```c
char _get_digit(uint64_t *fr, int *digit_count) {
  int rval;
  if (*digit_count > 0) {
    *digit_count -= 1;
    *fr = *fr * 10;
    rval = ((*fr >> 60) & 0xF) + '0';
    *fr &= 0x0FFFFFFFFFFFFFFFull;
  } else
    rval = '0';
  return (char)(rval);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SC68calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <SC68alloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L26
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L4
L7:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L4:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L7
L26:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *SC68calloc(unsigned int n) {
  void *buffer = SC68alloc(n);
  if (buffer) {
    char *b = buffer;
    while (n--) {
      *b++ = 0;
    }
  }
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SC68calloc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <SC68alloc@plt>
  test   %rax,%rax
  je     L3
  lea    -0x1(%rbx),%edx
  test   %ebx,%ebx
  je     L3
  mov    %edx,%edx
  lea    0x1(%rax,%rdx,1),%rcx
  mov    %rax,%rdx
L21:
  add    $0x1,%rdx
  movb   $0x0,-0x1(%rdx)
  cmp    %rdx,%rcx
  jne    L21
L3:
  pop    %rbx
  ret
```

assistant: ```c
void *SC68calloc(unsigned int n) {
  void *buffer = SC68alloc(n);
  if (buffer) {
    char *b = buffer;
    while (n--) {
      *b++ = 0;
    }
  }
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SC68calloc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <SC68alloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L5
  test   %ebx,%ebx
  je     L5
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L5:
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *SC68calloc(unsigned int n) {
  void *buffer = SC68alloc(n);
  if (buffer) {
    char *b = buffer;
    while (n--) {
      *b++ = 0;
    }
  }
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SC68calloc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <SC68alloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L2
  test   %ebx,%ebx
  je     L2
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L2:
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *SC68calloc(unsigned int n) {
  void *buffer = SC68alloc(n);
  if (buffer) {
    char *b = buffer;
    while (n--) {
      *b++ = 0;
    }
  }
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D2(%rip),%rax
  movq   %rax,%xmm0
  call   <func@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: f64

tool: D2: 1

assistant: ```c
int main() {
  func((double)1.00);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D4(%rip),%xmm0
  call   <func@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: f64

tool: D4: 1

assistant: ```c
int main() {
  func((double)1.00);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D7(%rip),%xmm0
  call   <func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: f64

tool: D7: 1

assistant: ```c
int main() {
  func((double)1.00);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D1(%rip),%xmm0
  call   <func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: f64

tool: D1: 1

assistant: ```c
int main() {
  func((double)1.00);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <execve@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
datatype: string

tool: D15: /usr/lib/cgi-bin/cricket/mini-graph-real.cgi

assistant: ```c
int main(int argn, char **argv, char **envp) {
  argv[0] = "/usr/lib/cgi-bin/cricket/mini-graph-real.cgi";
  execve("/usr/lib/cgi-bin/cricket/mini-graph-real.cgi", argv, envp);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  mov    %rdi,(%rsi)
  call   <execve@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: /usr/lib/cgi-bin/cricket/mini-graph-real.cgi

assistant: ```c
int main(int argn, char **argv, char **envp) {
  argv[0] = "/usr/lib/cgi-bin/cricket/mini-graph-real.cgi";
  execve("/usr/lib/cgi-bin/cricket/mini-graph-real.cgi", argv, envp);
}
```