ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  cmp    %rsi,%rdi
  je     L5
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  ret
```

assistant: ```c
void swap(void *a, void *b, size_t size) {
  if (a == b)
    return;
  void *tmp = malloc(size);
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
  free(tmp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap>:
  endbr64
  cmp    %rsi,%rdi
  je     L7
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <free@plt>
  nopl   (%rax)
L7:
  ret
```

assistant: ```c
void swap(void *a, void *b, size_t size) {
  if (a == b)
    return;
  void *tmp = malloc(size);
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
  free(tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  cmp    %rsi,%rdi
  je     L4
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <free@plt>
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
void swap(void *a, void *b, size_t size) {
  if (a == b)
    return;
  void *tmp = malloc(size);
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
  free(tmp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fact_wrapper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L6
L19:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x1,-0x4(%rbp)
  jg     L19
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double fact_wrapper(double *arg_list) {
  int result = 1;
  int n = (int)arg_list[0];
  while (n > 1) {
    result = result * n;
    n--;
  }
  return (double)result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fact_wrapper>:
  endbr64
  cvttsd2si (%rdi),%eax
  cmp    $0x1,%eax
  jle    L21
  mov    $0x1,%edx
L20:
  imul   %eax,%edx
  sub    $0x1,%eax
  cmp    $0x1,%eax
  jne    L20
L28:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  ret
L21:
  mov    $0x1,%edx
  jmp    L28
```

assistant: ```c
double fact_wrapper(double *arg_list) {
  int result = 1;
  int n = (int)arg_list[0];
  while (n > 1) {
    result = result * n;
    n--;
  }
  return (double)result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fact_wrapper>:
  endbr64
  cvttsd2si (%rdi),%eax
  cmp    $0x1,%eax
  jle    L8
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L1:
  imul   %eax,%edx
  sub    $0x1,%eax
  cmp    $0x1,%eax
  jne    L1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  ret
  nopl   0x0(%rax)
L8:
  movsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double fact_wrapper(double *arg_list) {
  int result = 1;
  int n = (int)arg_list[0];
  while (n > 1) {
    result = result * n;
    n--;
  }
  return (double)result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fact_wrapper>:
  endbr64
  cvttsd2si (%rdi),%eax
  cmp    $0x1,%eax
  jle    L5
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L4:
  imul   %eax,%edx
  sub    $0x1,%eax
  cmp    $0x1,%eax
  jne    L4
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  ret
  nopl   0x0(%rax)
L5:
  movsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double fact_wrapper(double *arg_list) {
  int result = 1;
  int n = (int)arg_list[0];
  while (n > 1) {
    result = result * n;
    n--;
  }
  return (double)result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<listprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: Titel: %s


assistant: ```c
void listprint(char **list, int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("Titel: %s\n", list[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<listprint>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D3(%rip),%rbp
L18:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: Titel: %s


assistant: ```c
void listprint(char **list, int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("Titel: %s\n", list[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<listprint>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string

tool: D1: Titel: %s


assistant: ```c
void listprint(char **list, int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("Titel: %s\n", list[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<listprint>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L12:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: Titel: %s


assistant: ```c
void listprint(char **list, int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("Titel: %s\n", list[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L4:
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x64(%rbp),%eax
  cltq
  mov    %rdx,-0x60(%rbp,%rax,8)
  mov    -0x64(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x64(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x64(%rbp)
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  subl   $0x1,-0x64(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <reorder@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L10
L20:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  mov    -0x68(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L10:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string
name: unpack_data
arguments: tag: D25
datatype: string
name: unpack_data
arguments: tag: D63
datatype: string
name: unpack_data
arguments: tag: D30
datatype: string
name: unpack_data
arguments: tag: D39
datatype: string
name: unpack_data
arguments: tag: D28
datatype: string

tool: D3: Enter each string on a separate line below


tool: D1: Type 'END' when finished


tool: D25: string %d: 

tool: D63: %s

tool: D30: END

tool: D39: 

Reorder List of Strings: 

tool: D28: 
string %d: %s

assistant: ```c
int main(void) {
  int i, n = 0;
  char *x[10];
  printf("Enter each string on a separate line below\n\n");
  printf("Type \'END\' when finished\n\n");
  do {
    x[n] = (char *)malloc(12 * sizeof(char));
    printf("string %d: ", n + 1);
    scanf("%s", x[n]);
  } while (strcmp(x[n++], "END"));
  reorder(--n, x);
  printf("\n\nReorder List of Strings: \n");
  for (i = 0; i < n; ++i)
    printf("\nstring %d: %s", i + 1, x[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    $0x0,%ebp
  lea    D58(%rip),%r15
  lea    D29(%rip),%r14
  lea    D8(%rip),%r13
L22:
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %ebp,%r12d
  add    $0x1,%ebp
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  add    $0x8,%rbx
  test   %rax,%rax
  jne    L22
  mov    %rsp,%rsi
  mov    %r12d,%edi
  call   <reorder@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L34
  lea    0x1(%r12),%r12d
  mov    $0x1,%ebx
  lea    D56(%rip),%rbp
L9:
  mov    -0x8(%rsp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L9
L34:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D58
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D8
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D56
type_guessed: string

tool: D5: Enter each string on a separate line below


tool: D11: Type 'END' when finished


tool: D58: string %d: 

tool: D29: %s

tool: D8: END

tool: D12: 

Reorder List of Strings: 

tool: D56: 
string %d: %s

assistant: ```c
int main(void) {
  int i, n = 0;
  char *x[10];
  printf("Enter each string on a separate line below\n\n");
  printf("Type \'END\' when finished\n\n");
  do {
    x[n] = (char *)malloc(12 * sizeof(char));
    printf("string %d: ", n + 1);
    scanf("%s", x[n]);
  } while (strcmp(x[n++], "END"));
  reorder(--n, x);
  printf("\n\nReorder List of Strings: \n");
  for (i = 0; i < n; ++i)
    printf("\nstring %d: %s", i + 1, x[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D49(%rip),%rdi
  lea    D37(%rip),%r15
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    D19(%rip),%rdi
  mov    %r12,%rbx
  call   <puts@plt>
  nopl   0x0(%rax)
L19:
  mov    $0xc,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %ebp,0xc(%rsp)
  add    $0x1,%ebp
  mov    %r15,%rdi
  mov    %rax,-0x8(%rbx)
  mov    %ebp,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x8(%rbx),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbx),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  mov    0xc(%rsp),%ebx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <reorder@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  je     L38
  lea    0x1(%rbx),%r13d
  lea    D11(%rip),%rbp
  mov    $0x1,%ebx
L23:
  mov    -0x8(%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L23
L38:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D49
type_guessed: string
name: parse_data
arguments: data_label: D37
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D11
type_guessed: string

tool: D49: Enter each string on a separate line below


tool: D37: string %d: 

tool: D6: %s

tool: D8: END

tool: D19: Type 'END' when finished


tool: D13: 

Reorder List of Strings: 

tool: D11: 
string %d: %s

assistant: ```c
int main(void) {
  int i, n = 0;
  char *x[10];
  printf("Enter each string on a separate line below\n\n");
  printf("Type \'END\' when finished\n\n");
  do {
    x[n] = (char *)malloc(12 * sizeof(char));
    printf("string %d: ", n + 1);
    scanf("%s", x[n]);
  } while (strcmp(x[n++], "END"));
  reorder(--n, x);
  printf("\n\nReorder List of Strings: \n");
  for (i = 0; i < n; ++i)
    printf("\nstring %d: %s", i + 1, x[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D35(%rip),%rdi
  lea    D32(%rip),%r15
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  lea    D45(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    D4(%rip),%rdi
  mov    %r12,%rbx
  call   <puts@plt>
  nopl   0x0(%rax)
L34:
  mov    $0xc,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %ebp,0xc(%rsp)
  add    $0x1,%ebp
  mov    %r15,%rdi
  mov    %rax,-0x8(%rbx)
  mov    %ebp,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x8(%rbx),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbx),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L34
  mov    0xc(%rsp),%ebx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <reorder@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  je     L33
  lea    0x1(%rbx),%r13d
  lea    D25(%rip),%rbp
  mov    $0x1,%ebx
L16:
  mov    -0x8(%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L16
L33:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D35
datatype: string
name: disassemble_data
arguments: tag: D32
datatype: string
name: disassemble_data
arguments: tag: D11
datatype: string
name: disassemble_data
arguments: tag: D45
datatype: string
name: disassemble_data
arguments: tag: D4
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string
name: disassemble_data
arguments: tag: D25
datatype: string

tool: D35: Enter each string on a separate line below


tool: D32: string %d: 

tool: D11: %s

tool: D45: END

tool: D4: Type 'END' when finished


tool: D14: 

Reorder List of Strings: 

tool: D25: 
string %d: %s

assistant: ```c
int main(void) {
  int i, n = 0;
  char *x[10];
  printf("Enter each string on a separate line below\n\n");
  printf("Type \'END\' when finished\n\n");
  do {
    x[n] = (char *)malloc(12 * sizeof(char));
    printf("string %d: ", n + 1);
    scanf("%s", x[n]);
  } while (strcmp(x[n++], "END"));
  reorder(--n, x);
  printf("\n\nReorder List of Strings: \n");
  for (i = 0; i < n; ++i)
    printf("\nstring %d: %s", i + 1, x[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L2:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L28
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jb     L2
L28:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_strncmp(char *s1, char *s2, unsigned int n) {
  unsigned int i;
  i = 0;
  while (s1[i] != '\0' && s1[i] == s2[i] && i < (n - 1))
    i++;
  return (s1[i] - s2[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strncmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  sub    $0x1,%edx
  mov    $0x0,%ecx
  mov    $0x0,%r8d
L1:
  cmp    %al,(%rsi,%r8,1)
  jne    L35
  cmp    %edx,%ecx
  je     L35
  add    $0x1,%ecx
  mov    %ecx,%r8d
  movzbl (%rdi,%r8,1),%eax
  test   %al,%al
  jne    L1
L35:
  movsbl %al,%eax
  movsbl (%rsi,%r8,1),%edx
  sub    %edx,%eax
  ret
L12:
  mov    $0x0,%r8d
  jmp    L35
```

assistant: ```c
int ft_strncmp(char *s1, char *s2, unsigned int n) {
  unsigned int i;
  i = 0;
  while (s1[i] != '\0' && s1[i] == s2[i] && i < (n - 1))
    i++;
  return (s1[i] - s2[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_strncmp>:
  endbr64
  movsbl (%rdi),%eax
  sub    $0x1,%edx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  test   %al,%al
  jne    L16
  jmp    L52
  nopl   (%rax)
L8:
  cmp    %ecx,%edx
  je     L31
  lea    0x1(%rcx),%r8d
  movsbl (%rdi,%r8,1),%eax
  mov    %r8,%rcx
  test   %al,%al
  je     L27
L16:
  movsbl (%rsi,%r8,1),%r8d
  cmp    %al,%r8b
  je     L8
L31:
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl (%rsi,%r8,1),%r8d
  xor    %eax,%eax
  sub    %r8d,%eax
  ret
L52:
  movsbl (%rsi),%r8d
  xor    %eax,%eax
  jmp    L31
```

assistant: ```c
int ft_strncmp(char *s1, char *s2, unsigned int n) {
  unsigned int i;
  i = 0;
  while (s1[i] != '\0' && s1[i] == s2[i] && i < (n - 1))
    i++;
  return (s1[i] - s2[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strncmp>:
  endbr64
  movsbl (%rdi),%eax
  sub    $0x1,%edx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  test   %al,%al
  jne    L6
  jmp    L59
  nopl   (%rax)
L13:
  cmp    %edx,%ecx
  je     L32
  lea    0x1(%rcx),%r8d
  movsbl (%rdi,%r8,1),%eax
  mov    %r8,%rcx
  test   %al,%al
  je     L41
L6:
  movsbl (%rsi,%r8,1),%r8d
  cmp    %al,%r8b
  je     L13
L32:
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  movsbl (%rsi,%r8,1),%r8d
  xor    %eax,%eax
  sub    %r8d,%eax
  ret
L59:
  movsbl (%rsi),%r8d
  xor    %eax,%eax
  jmp    L32
```

assistant: ```c
int ft_strncmp(char *s1, char *s2, unsigned int n) {
  unsigned int i;
  i = 0;
  while (s1[i] != '\0' && s1[i] == s2[i] && i < (n - 1))
    i++;
  return (s1[i] - s2[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L2:
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x2,-0xc(%rbp)
  jle    L2
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D3
datatype: string
name: retrieve_data
arguments: tag: D22
datatype: string

tool: D10: ldexp

tool: D3: # c::cephes::%s


tool: D22: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "ldexp");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```