ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<Strncmp>:
  endbr64
  mov    $0x5f,%r9d
  sub    $0x1,%edx
  jns    L101
  mov    $0x0,%eax
  ret
L72:
  cmp    $0x2d,%al
  cmove  %r9d,%eax
  jmp    L57
L98:
  cmp    $0x2d,%cl
  cmove  %r9d,%ecx
L50:
  cmp    %cl,%al
  jne    L40
L56:
  add    $0x1,%rdi
  add    $0x1,%rsi
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  je     L92
L101:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L93
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L93
  cmp    %cl,%al
  je     L56
  lea    -0x41(%rax),%r8d
  cmp    $0x19,%r8b
  ja     L72
  add    $0x20,%eax
L57:
  lea    -0x41(%rcx),%r8d
  cmp    $0x19,%r8b
  ja     L98
  add    $0x20,%ecx
  jmp    L50
L40:
  movsbl %al,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
L93:
  test   %edx,%edx
  js     L5
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
L92:
  mov    $0x0,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Strncmp(cp1, cp2, n)
char *cp1, *cp2;
int n;
{
  char c1, c2;
  for (; --n >= 0 && *cp1 && *cp2; cp1++, cp2++) {
    if (*cp1 != *cp2) {
      c1 = *cp1;
      c2 = *cp2;
      if (c1 >= 'A' && c1 <= 'Z')
        c1 += 'a' - 'A';
      else if (c1 == '-')
        c1 = '_';
      if (c2 >= 'A' && c2 <= 'Z')
        c2 += 'a' - 'A';
      else if (c2 == '-')
        c2 = '_';
      if (c1 != c2)
        return (int)c1 - (int)c2;
    }
  }
  if (n < 0)
    return 0;
  return (int)*cp1 - (int)*cp2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Strncmp>:
  endbr64
  test   %edx,%edx
  jle    L0
  lea    -0x1(%rdx),%r9d
  xor    %ecx,%ecx
  mov    $0x5f,%r10d
  jmp    L94
  nopw   0x0(%rax,%rax,1)
L44:
  lea    -0x41(%rdx),%r8d
  add    $0x20,%eax
  cmp    $0x19,%r8b
  ja     L28
L33:
  add    $0x20,%edx
  cmp    %dl,%al
  jne    L14
L45:
  lea    0x1(%rcx),%rax
  cmp    %rcx,%r9
  je     L0
  mov    %rax,%rcx
L94:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%edx
  test   %al,%al
  je     L27
  test   %dl,%dl
  je     L27
  cmp    %dl,%al
  je     L45
  lea    -0x41(%rax),%r8d
  cmp    $0x19,%r8b
  jbe    L44
  cmp    $0x2d,%al
  lea    -0x41(%rdx),%r8d
  cmove  %r10d,%eax
  cmp    $0x19,%r8b
  jbe    L33
L28:
  cmp    $0x2d,%dl
  cmove  %r10d,%edx
  cmp    %dl,%al
  je     L45
L14:
  movsbl %dl,%edx
  movsbl %al,%eax
  sub    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Strncmp(cp1, cp2, n)
char *cp1, *cp2;
int n;
{
  char c1, c2;
  for (; --n >= 0 && *cp1 && *cp2; cp1++, cp2++) {
    if (*cp1 != *cp2) {
      c1 = *cp1;
      c2 = *cp2;
      if (c1 >= 'A' && c1 <= 'Z')
        c1 += 'a' - 'A';
      else if (c1 == '-')
        c1 = '_';
      if (c2 >= 'A' && c2 <= 'Z')
        c2 += 'a' - 'A';
      else if (c2 == '-')
        c2 = '_';
      if (c1 != c2)
        return (int)c1 - (int)c2;
    }
  }
  if (n < 0)
    return 0;
  return (int)*cp1 - (int)*cp2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Strncmp>:
  endbr64
  test   %edx,%edx
  jle    L78
  lea    -0x1(%rdx),%r9d
  xor    %ecx,%ecx
  mov    $0x5f,%r10d
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L16:
  lea    -0x41(%rdx),%r8d
  add    $0x20,%eax
  cmp    $0x19,%r8b
  ja     L89
L72:
  add    $0x20,%edx
  cmp    %dl,%al
  jne    L26
L74:
  lea    0x1(%rcx),%rax
  cmp    %rcx,%r9
  je     L78
  mov    %rax,%rcx
L98:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%edx
  test   %al,%al
  je     L9
  test   %dl,%dl
  je     L9
  cmp    %dl,%al
  je     L74
  lea    -0x41(%rax),%r8d
  cmp    $0x19,%r8b
  jbe    L16
  cmp    $0x2d,%al
  lea    -0x41(%rdx),%r8d
  cmove  %r10d,%eax
  cmp    $0x19,%r8b
  jbe    L72
L89:
  cmp    $0x2d,%dl
  cmove  %r10d,%edx
  cmp    %dl,%al
  je     L74
L26:
  movsbl %dl,%edx
  movsbl %al,%eax
  sub    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Strncmp(cp1, cp2, n)
char *cp1, *cp2;
int n;
{
  char c1, c2;
  for (; --n >= 0 && *cp1 && *cp2; cp1++, cp2++) {
    if (*cp1 != *cp2) {
      c1 = *cp1;
      c2 = *cp2;
      if (c1 >= 'A' && c1 <= 'Z')
        c1 += 'a' - 'A';
      else if (c1 == '-')
        c1 = '_';
      if (c2 >= 'A' && c2 <= 'Z')
        c2 += 'a' - 'A';
      else if (c2 == '-')
        c2 = '_';
      if (c1 != c2)
        return (int)c1 - (int)c2;
    }
  }
  if (n < 0)
    return 0;
  return (int)*cp1 - (int)*cp2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<abs_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L11
  movsd  -0x8(%rbp),%xmm0
  movq   D0(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  jmp    L17
L11:
  movsd  -0x8(%rbp),%xmm0
L17:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double abs_double(double x) {
  if (x < 0) {
    return -x;
  }
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<abs_double>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L16
L2:
  ret
L16:
  xorpd  D3(%rip),%xmm0
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D3
type: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double abs_double(double x) {
  if (x < 0) {
    return -x;
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<abs_double>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L3
  ret
  nop
L3:
  xorpd  D4(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: byte[16]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double abs_double(double x) {
  if (x < 0) {
    return -x;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<abs_double>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L2
  ret
  nop
L2:
  xorpd  D9(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double abs_double(double x) {
  if (x < 0) {
    return -x;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<abort_if_null>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: %s

assistant: ```c
void abort_if_null(void *ptr, const char str[]) {
  if (ptr == NULL) {
    printf("%s", str);
    abort();
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<abort_if_null>:
  endbr64
  test   %rdi,%rdi
  je     L9
  ret
L9:
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: %s

assistant: ```c
void abort_if_null(void *ptr, const char str[]) {
  if (ptr == NULL) {
    printf("%s", str);
    abort();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<abort_if_null>:
  endbr64
  test   %rdi,%rdi
  je     L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: %s

assistant: ```c
void abort_if_null(void *ptr, const char str[]) {
  if (ptr == NULL) {
    printf("%s", str);
    abort();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<abort_if_null>:
  endbr64
  test   %rdi,%rdi
  je     L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: %s

assistant: ```c
void abort_if_null(void *ptr, const char str[]) {
  if (ptr == NULL) {
    printf("%s", str);
    abort();
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<validname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  lea    D19(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    D7(%rip),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_guessed: string

tool: D19: valid-%d

assistant: ```c
const char *validname(int a) {
  static char rv[32];
  snprintf(rv, sizeof(rv), "valid-%d", a);
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<validname>:
  endbr64
  push   %rbx
  mov    %edi,%ecx
  lea    D10(%rip),%rdx
  mov    $0x20,%esi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
data_type: string

tool: D10: valid-%d

assistant: ```c
const char *validname(int a) {
  static char rv[32];
  snprintf(rv, sizeof(rv), "valid-%d", a);
  return rv;
}
```
user: What is the c source code of the assembly code below:

```asm
<validname>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  mov    %edi,%ecx
  mov    $0x20,%esi
  mov    %r12,%rdi
  lea    D18(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_infered: string

tool: D18: valid-%d

assistant: ```c
const char *validname(int a) {
  static char rv[32];
  snprintf(rv, sizeof(rv), "valid-%d", a);
  return rv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<validname>:
  endbr64
  push   %r12
  lea    D12(%rip),%r12
  mov    %edi,%ecx
  mov    $0x20,%esi
  mov    %r12,%rdi
  lea    D14(%rip),%rdx
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_infered: string

tool: D14: valid-%d

assistant: ```c
const char *validname(int a) {
  static char rv[32];
  snprintf(rv, sizeof(rv), "valid-%d", a);
  return rv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zstrnicmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%r13d
  jmp    L24
L95:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L97
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  movsbl %al,%r14d
  jmp    L25
L97:
  movzbl (%rbx),%eax
  movsbl %al,%r14d
L25:
  movzbl (%r12),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L45
  movzbl (%r12),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  movsbl %al,%eax
  jmp    L84
L45:
  movzbl (%r12),%eax
  movsbl %al,%eax
L84:
  cmp    %eax,%r14d
  je     L42
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L114
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  movsbl %al,%ebx
  jmp    L73
L114:
  movzbl (%rbx),%eax
  movsbl %al,%ebx
L73:
  movzbl (%r12),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L41
  movzbl (%r12),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  movsbl %al,%eax
  jmp    L131
L41:
  movzbl (%r12),%eax
  movsbl %al,%eax
L131:
  cmp    %eax,%ebx
  jge    L118
  mov    $0xffffffff,%eax
  jmp    L40
L118:
  mov    $0x1,%eax
  jmp    L40
L42:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L140
  mov    $0x0,%eax
  jmp    L40
L140:
  sub    $0x1,%r13d
  add    $0x1,%rbx
  add    $0x1,%r12
L24:
  test   %r13d,%r13d
  jne    L95
  mov    $0x0,%eax
L40:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int zstrnicmp(s1, s2, n)
register const char *s1, *s2;
register unsigned n;
{
  for (; n > 0; --n, ++s1, ++s2) {
    if (((char)(isupper((int)*s1) ? tolower((int)*s1) : *s1)) != ((char)(isupper((int)*s2) ? tolower((int)*s2) : *s2)))
      return (((char)(isupper((int)*s1) ? tolower((int)*s1) : *s1)) < ((char)(isupper((int)*s2) ? tolower((int)*s2) : *s2))) ? -1 : 1;
    if (*s1 == '\0')
      return 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zstrnicmp>:
  endbr64
  test   %edx,%edx
  je     L57
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%r15
  jmp    L83
L18:
  cmp    %ebx,%ebp
  jne    L72
  test   %r14b,%r14b
  je     L74
  add    $0x1,%r12
  add    $0x1,%r13
  cmp    %r15,%r12
  je     L11
L83:
  movzbl (%r12),%r14d
  movsbl %r14b,%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L43
  mov    %ebp,%edi
  call   <tolower@plt>
  movsbl %al,%ebp
L43:
  movsbl 0x0(%r13),%ebx
  mov    %ebx,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L18
  mov    %ebx,%edi
  call   <tolower@plt>
  movsbl %al,%ebx
  jmp    L18
L72:
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    $0x0,%eax
  jmp    L14
L57:
  mov    $0x0,%eax
  ret
L74:
  mov    $0x0,%eax
  jmp    L14
```

assistant: ```c
int zstrnicmp(s1, s2, n)
register const char *s1, *s2;
register unsigned n;
{
  for (; n > 0; --n, ++s1, ++s2) {
    if (((char)(isupper((int)*s1) ? tolower((int)*s1) : *s1)) != ((char)(isupper((int)*s2) ? tolower((int)*s2) : *s2)))
      return (((char)(isupper((int)*s1) ? tolower((int)*s1) : *s1)) < ((char)(isupper((int)*s2) ? tolower((int)*s2) : *s2))) ? -1 : 1;
    if (*s1 == '\0')
      return 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<zstrnicmp>:
  endbr64
  test   %edx,%edx
  je     L57
  push   %r15
  mov    %edx,%edx
  push   %r14
  lea    (%rdi,%rdx,1),%r15
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L42:
  test   %r14b,%r14b
  je     L21
  add    $0x1,%rbx
  add    $0x1,%r13
  cmp    %r15,%rbx
  je     L21
L65:
  movsbl (%rbx),%r12d
  mov    %r12d,%edi
  mov    %r12d,%r14d
  call   <isupper@plt>
  test   %eax,%eax
  je     L25
  mov    %r12d,%edi
  call   <tolower@plt>
  movsbl %al,%r12d
L25:
  movsbl 0x0(%r13),%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L44
  mov    %ebp,%edi
  call   <tolower@plt>
  movsbl %al,%ebp
L44:
  cmp    %ebp,%r12d
  je     L42
  setge  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  lea    -0x1(%rax,%rax,1),%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  xor    %eax,%eax
  ret
```

assistant: ```c
int zstrnicmp(s1, s2, n)
register const char *s1, *s2;
register unsigned n;
{
  for (; n > 0; --n, ++s1, ++s2) {
    if (((char)(isupper((int)*s1) ? tolower((int)*s1) : *s1)) != ((char)(isupper((int)*s2) ? tolower((int)*s2) : *s2)))
      return (((char)(isupper((int)*s1) ? tolower((int)*s1) : *s1)) < ((char)(isupper((int)*s2) ? tolower((int)*s2) : *s2))) ? -1 : 1;
    if (*s1 == '\0')
      return 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<zstrnicmp>:
  endbr64
  test   %edx,%edx
  je     L53
  push   %r15
  mov    %edx,%edx
  push   %r14
  lea    (%rdi,%rdx,1),%r15
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L7:
  test   %r14b,%r14b
  je     L14
  add    $0x1,%rbx
  add    $0x1,%r13
  cmp    %rbx,%r15
  je     L14
L15:
  movsbl (%rbx),%r12d
  mov    %r12d,%edi
  mov    %r12d,%r14d
  call   <isupper@plt>
  test   %eax,%eax
  je     L44
  mov    %r12d,%edi
  call   <tolower@plt>
  movsbl %al,%r12d
L44:
  movsbl 0x0(%r13),%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L4
  mov    %ebp,%edi
  call   <tolower@plt>
  movsbl %al,%ebp
L4:
  cmp    %ebp,%r12d
  je     L7
  setge  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  lea    -0x1(%rax,%rax,1),%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  xor    %eax,%eax
  ret
```

assistant: ```c
int zstrnicmp(s1, s2, n)
register const char *s1, *s2;
register unsigned n;
{
  for (; n > 0; --n, ++s1, ++s2) {
    if (((char)(isupper((int)*s1) ? tolower((int)*s1) : *s1)) != ((char)(isupper((int)*s2) ? tolower((int)*s2) : *s2)))
      return (((char)(isupper((int)*s1) ? tolower((int)*s1) : *s1)) < ((char)(isupper((int)*s2) ? tolower((int)*s2) : *s2))) ? -1 : 1;
    if (*s1 == '\0')
      return 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<blPadterm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L17
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void blPadterm(char *string, int length) {
  int i;
  for (i = strlen(string); i < length; i++)
    string[i] = ' ';
  string[length] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<blPadterm>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L8
  movslq %eax,%rcx
  lea    0x0(%rbp,%rcx,1),%rdx
  lea    0x1(%rbp,%rcx,1),%rcx
  lea    -0x1(%rbx),%esi
  sub    %eax,%esi
  lea    (%rcx,%rsi,1),%rax
L18:
  movb   $0x20,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L18
L8:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void blPadterm(char *string, int length) {
  int i;
  for (i = strlen(string); i < length; i++)
    string[i] = ' ';
  string[length] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<blPadterm>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L4
  lea    -0x1(%rbx),%edx
  mov    $0x20,%esi
  sub    %eax,%edx
  cltq
  add    $0x1,%rdx
  lea    0x0(%rbp,%rax,1),%rdi
  call   <memset@plt>
L4:
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void blPadterm(char *string, int length) {
  int i;
  for (i = strlen(string); i < length; i++)
    string[i] = ' ';
  string[length] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<blPadterm>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L4
  lea    -0x1(%rbx),%edx
  mov    $0x20,%esi
  sub    %eax,%edx
  cltq
  add    $0x1,%rdx
  lea    0x0(%rbp,%rax,1),%rdi
  call   <memset@plt>
L4:
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void blPadterm(char *string, int length) {
  int i;
  for (i = strlen(string); i < length; i++)
    string[i] = ' ';
  string[length] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<changeIntValues>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string

tool: D1: 
Valor 1 = %d
Valor 2 = %d

assistant: ```c
void changeIntValues(int value1, int value2) {
  int aux;
  aux = value1;
  value1 = value2;
  value2 = aux;
  printf("\nValor 1 = %d\nValor 2 = %d", value1, value2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<changeIntValues>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: 
Valor 1 = %d
Valor 2 = %d

assistant: ```c
void changeIntValues(int value1, int value2) {
  int aux;
  aux = value1;
  value1 = value2;
  value2 = aux;
  printf("\nValor 1 = %d\nValor 2 = %d", value1, value2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<changeIntValues>:
  endbr64
  mov    %edi,%edx
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: 
Valor 1 = %d
Valor 2 = %d

assistant: ```c
void changeIntValues(int value1, int value2) {
  int aux;
  aux = value1;
  value1 = value2;
  value2 = aux;
  printf("\nValor 1 = %d\nValor 2 = %d", value1, value2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<changeIntValues>:
  endbr64
  mov    %edi,%edx
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: 
Valor 1 = %d
Valor 2 = %d

assistant: ```c
void changeIntValues(int value1, int value2) {
  int aux;
  aux = value1;
  value1 = value2;
  value2 = aux;
  printf("\nValor 1 = %d\nValor 2 = %d", value1, value2);
}
```