ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<lookup_cmd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D77(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L2
L64:
  pop    %rbx
  ret
L2:
  lea    D52(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  je     L64
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  je     L64
  lea    D54(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x3,%eax
  test   %rdx,%rdx
  je     L64
  lea    D26(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x3,%eax
  test   %rdx,%rdx
  je     L64
  lea    D65(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x4,%eax
  test   %rdx,%rdx
  je     L64
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x4,%eax
  test   %rdx,%rdx
  je     L64
  lea    D59(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x5,%eax
  test   %rdx,%rdx
  je     L64
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x5,%eax
  jmp    L64
```

tool_calls: name: unpack_data
arguments: data_tag: D77
type: string
name: unpack_data
arguments: data_tag: D52
type: string
name: unpack_data
arguments: data_tag: D4
type: string
name: unpack_data
arguments: data_tag: D54
type: string
name: unpack_data
arguments: data_tag: D26
type: string
name: unpack_data
arguments: data_tag: D65
type: string
name: unpack_data
arguments: data_tag: D47
type: string
name: unpack_data
arguments: data_tag: D59
type: string
name: unpack_data
arguments: data_tag: D9
type: string

tool: D77: ANN1

tool: D52: CTM1

tool: D4: CTMR

tool: D54: MRS1

tool: D26: MARS

tool: D65: PPR1

tool: D47: PRPR

tool: D59: KNN1

tool: D9: K-NN

assistant: ```c
int lookup_cmd(char *cmd) {
  if (strcmp(cmd, "ANN1") == 0)
    return 1;
  if (strcmp(cmd, "CTM1") == 0)
    return 2;
  if (strcmp(cmd, "CTMR") == 0)
    return 2;
  if (strcmp(cmd, "MRS1") == 0)
    return 3;
  if (strcmp(cmd, "MARS") == 0)
    return 3;
  if (strcmp(cmd, "PPR1") == 0)
    return 4;
  if (strcmp(cmd, "PRPR") == 0)
    return 4;
  if (strcmp(cmd, "KNN1") == 0)
    return 5;
  if (strcmp(cmd, "K-NN") == 0)
    return 5;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lookup_cmd>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L7
L71:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D55(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L10
  lea    D74(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L10
  lea    D58(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L79
  lea    D68(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L79
  lea    D75(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L73
  lea    D69(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L73
  lea    D89(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L44
  lea    D78(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L71
L44:
  mov    $0x5,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x2,%eax
  pop    %rbp
  ret
  nop
L79:
  mov    $0x3,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  mov    $0x4,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D55
type_guessed: string
name: disassemble_data
arguments: data_label: D74
type_guessed: string
name: disassemble_data
arguments: data_label: D58
type_guessed: string
name: disassemble_data
arguments: data_label: D68
type_guessed: string
name: disassemble_data
arguments: data_label: D75
type_guessed: string
name: disassemble_data
arguments: data_label: D69
type_guessed: string
name: disassemble_data
arguments: data_label: D89
type_guessed: string
name: disassemble_data
arguments: data_label: D78
type_guessed: string

tool: D18: ANN1

tool: D55: CTM1

tool: D74: CTMR

tool: D58: MRS1

tool: D68: MARS

tool: D75: PPR1

tool: D69: PRPR

tool: D89: KNN1

tool: D78: K-NN

assistant: ```c
int lookup_cmd(char *cmd) {
  if (strcmp(cmd, "ANN1") == 0)
    return 1;
  if (strcmp(cmd, "CTM1") == 0)
    return 2;
  if (strcmp(cmd, "CTMR") == 0)
    return 2;
  if (strcmp(cmd, "MRS1") == 0)
    return 3;
  if (strcmp(cmd, "MARS") == 0)
    return 3;
  if (strcmp(cmd, "PPR1") == 0)
    return 4;
  if (strcmp(cmd, "PRPR") == 0)
    return 4;
  if (strcmp(cmd, "KNN1") == 0)
    return 5;
  if (strcmp(cmd, "K-NN") == 0)
    return 5;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lookup_cmd>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L47
L42:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  lea    D67(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L49
  lea    D51(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L49
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L4
  lea    D56(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L4
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
  lea    D34(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
  lea    D66(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L78
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L42
L78:
  mov    $0x5,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L49:
  mov    $0x2,%eax
  pop    %rbp
  ret
  nop
L4:
  mov    $0x3,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L82:
  mov    $0x4,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D67
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D51
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D56
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D66
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: string

tool: D38: ANN1

tool: D67: CTM1

tool: D51: CTMR

tool: D25: MRS1

tool: D56: MARS

tool: D11: PPR1

tool: D34: PRPR

tool: D66: KNN1

tool: D37: K-NN

assistant: ```c
int lookup_cmd(char *cmd) {
  if (strcmp(cmd, "ANN1") == 0)
    return 1;
  if (strcmp(cmd, "CTM1") == 0)
    return 2;
  if (strcmp(cmd, "CTMR") == 0)
    return 2;
  if (strcmp(cmd, "MRS1") == 0)
    return 3;
  if (strcmp(cmd, "MARS") == 0)
    return 3;
  if (strcmp(cmd, "PPR1") == 0)
    return 4;
  if (strcmp(cmd, "PRPR") == 0)
    return 4;
  if (strcmp(cmd, "KNN1") == 0)
    return 5;
  if (strcmp(cmd, "K-NN") == 0)
    return 5;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x44332211,%edi
  call   <to_and_from_long@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <to_and_from_long@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  to_and_from_long(0x8877665544332211);
  to_and_from_long(ULONG_MAX);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x44332211,%edi
  call   <to_and_from_long@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <to_and_from_long@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  to_and_from_long(0x8877665544332211);
  to_and_from_long(ULONG_MAX);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x44332211,%edi
  call   <to_and_from_long@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <to_and_from_long@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  to_and_from_long(0x8877665544332211);
  to_and_from_long(ULONG_MAX);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x44332211,%edi
  call   <to_and_from_long@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <to_and_from_long@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  to_and_from_long(0x8877665544332211);
  to_and_from_long(ULONG_MAX);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ichash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  imul   $0x446f8657,%rax,%rax
  shr    $0x20,%rax
  mov    %rax,%rcx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  leave
  ret
```

assistant: ```c
unsigned ichash(char *s) {
  unsigned hashval;
  for (hashval = 0; *s != '\0'; s++)
    hashval = tolower(*s) + 31 * hashval;
  return hashval % 101;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ichash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
  mov    $0x0,%ebp
L19:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebp,%eax
  shl    $0x5,%eax
  sub    %ebp,%eax
  lea    (%rdx,%rax,1),%ebp
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L4:
  mov    %ebp,%edx
  imul   $0x446f8657,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %ebp,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x0,%ebp
  jmp    L4
```

assistant: ```c
unsigned ichash(char *s) {
  unsigned hashval;
  for (hashval = 0; *s != '\0'; s++)
    hashval = tolower(*s) + 31 * hashval;
  return hashval % 101;
}
```
user: What is the c source code of the assembly code below?

```asm
<ichash>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L1:
  call   <tolower@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  mov    %eax,%r8d
  mov    %ebp,%eax
  shl    $0x5,%eax
  sub    %ebp,%eax
  lea    (%r8,%rax,1),%ebp
  test   %dil,%dil
  jne    L1
  mov    %ebp,%edx
  mov    %ebp,%eax
  add    $0x8,%rsp
  imul   $0x446f8657,%rdx,%rdx
  pop    %rbx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%edx
  mov    %ebp,%eax
  pop    %rbp
  sub    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned ichash(char *s) {
  unsigned hashval;
  for (hashval = 0; *s != '\0'; s++)
    hashval = tolower(*s) + 31 * hashval;
  return hashval % 101;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ichash>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L18
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L12:
  call   <tolower@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  mov    %eax,%r8d
  mov    %ebp,%eax
  shl    $0x5,%eax
  sub    %ebp,%eax
  lea    (%r8,%rax,1),%ebp
  test   %dil,%dil
  jne    L12
  mov    %ebp,%edx
  mov    %ebp,%eax
  add    $0x8,%rsp
  imul   $0x446f8657,%rdx,%rdx
  pop    %rbx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%edx
  mov    %ebp,%eax
  pop    %rbp
  sub    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned ichash(char *s) {
  unsigned hashval;
  for (hashval = 0; *s != '\0'; s++)
    hashval = tolower(*s) + 31 * hashval;
  return hashval % 101;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<time_micros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    -0x20(%rbp),%rax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movsd  D2(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: f64

tool: D2: 1e-06

assistant: ```c
double time_micros() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  double result = (double)tv.tv_sec + 0.000001 * (double)tv.tv_usec;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<time_micros>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq (%rsp),%xmm0
  mulsd  D5(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: f64

tool: D5: 1e-06

assistant: ```c
double time_micros() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  double result = (double)tv.tv_sec + 0.000001 * (double)tv.tv_usec;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<time_micros>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rsp),%xmm0
  mulsd  D1(%rip),%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: f64

tool: D1: 1e-06

assistant: ```c
double time_micros() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  double result = (double)tv.tv_sec + 0.000001 * (double)tv.tv_usec;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<time_micros>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rsp),%xmm0
  mulsd  D0(%rip),%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: f64

tool: D0: 1e-06

assistant: ```c
double time_micros() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  double result = (double)tv.tv_sec + 0.000001 * (double)tv.tv_usec;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<keyHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x3,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L15:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  and    $0x3ff,%eax
  add    %edx,%eax
  add    $0x1,%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%ecx
  mov    %rcx,%rax
  shl    $0xd,%rax
  add    %rcx,%rax
  shr    $0x20,%rax
  mov    %rax,%rcx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x12,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x13,%eax
  sub    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L15
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned keyHash(const unsigned char *key, unsigned keylen) {
  unsigned x = 3;
  unsigned ctr;
  for (ctr = 0; ctr < keylen; ctr++) {
    x = (x * (key[ctr] + (ctr & 1023) + 1)) % ((1 << 19) - 1);
  }
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<keyHash>:
  endbr64
  test   %esi,%esi
  je     L7
  mov    %esi,%r8d
  mov    $0x0,%esi
  mov    $0x3,%eax
L14:
  movzbl (%rdi,%rsi,1),%ecx
  mov    %esi,%edx
  and    $0x3ff,%edx
  lea    0x1(%rcx,%rdx,1),%ecx
  imul   %eax,%ecx
  mov    %ecx,%eax
  mov    %rax,%rdx
  shl    $0xd,%rdx
  add    %rax,%rdx
  shr    $0x20,%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x12,%eax
  mov    %eax,%edx
  shl    $0x13,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  add    $0x1,%rsi
  cmp    %r8,%rsi
  jne    L14
  ret
L7:
  mov    $0x3,%eax
  ret
```

assistant: ```c
unsigned keyHash(const unsigned char *key, unsigned keylen) {
  unsigned x = 3;
  unsigned ctr;
  for (ctr = 0; ctr < keylen; ctr++) {
    x = (x * (key[ctr] + (ctr & 1023) + 1)) % ((1 << 19) - 1);
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<keyHash>:
  endbr64
  test   %esi,%esi
  je     L4
  mov    %esi,%r8d
  mov    $0x3,%eax
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L11:
  movzbl (%rdi,%rsi,1),%ecx
  mov    %esi,%edx
  add    $0x1,%rsi
  and    $0x3ff,%edx
  lea    0x1(%rcx,%rdx,1),%ecx
  imul   %eax,%ecx
  mov    %ecx,%eax
  mov    %rax,%rdx
  shl    $0xd,%rdx
  add    %rax,%rdx
  mov    %ecx,%eax
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x12,%eax
  mov    %eax,%edx
  shl    $0x13,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    %rsi,%r8
  jne    L11
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x3,%eax
  ret
```

assistant: ```c
unsigned keyHash(const unsigned char *key, unsigned keylen) {
  unsigned x = 3;
  unsigned ctr;
  for (ctr = 0; ctr < keylen; ctr++) {
    x = (x * (key[ctr] + (ctr & 1023) + 1)) % ((1 << 19) - 1);
  }
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<keyHash>:
  endbr64
  test   %esi,%esi
  je     L19
  mov    %esi,%r8d
  mov    $0x3,%eax
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl (%rdi,%rsi,1),%ecx
  mov    %esi,%edx
  add    $0x1,%rsi
  and    $0x3ff,%edx
  lea    0x1(%rcx,%rdx,1),%ecx
  imul   %eax,%ecx
  mov    %ecx,%eax
  mov    %rax,%rdx
  shl    $0xd,%rdx
  add    %rax,%rdx
  mov    %ecx,%eax
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x12,%eax
  mov    %eax,%edx
  shl    $0x13,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    %r8,%rsi
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0x3,%eax
  ret
```

assistant: ```c
unsigned keyHash(const unsigned char *key, unsigned keylen) {
  unsigned x = 3;
  unsigned ctr;
  for (ctr = 0; ctr < keylen; ctr++) {
    x = (x * (key[ctr] + (ctr & 1023) + 1)) % ((1 << 19) - 1);
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <str_cpy@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <str_trim@plt>
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <str_len@plt>
  cmp    $0x3,%eax
  je     L7
  mov    $0xcf,%edi
  call   <fail_test@plt>
L7:
  mov    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <str_cmp@plt>
  test   %rax,%rax
  je     L19
  mov    $0xd2,%edi
  call   <fail_test@plt>
L19:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D7:    
 	  abc			

tool: D10: abc

assistant: ```c
void test_trim() {
  char s[64];
  str_cpy(s, " \r  \n \t  abc\t\t\t\r\r");
  char *res = str_trim(s);
  if (str_len(res) != 3)
    fail_test(207);
  ;
  if (str_cmp("abc", res) != 0)
    fail_test(210);
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_trim>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <str_cpy@plt>
  mov    %rbx,%rdi
  call   <str_trim@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <str_len@plt>
  cmp    $0x3,%eax
  jne    L13
L23:
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  call   <str_cmp@plt>
  test   %rax,%rax
  jne    L27
L24:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x50,%rsp
  pop    %rbx
  ret
L13:
  mov    $0xcf,%edi
  call   <fail_test@plt>
  jmp    L23
L27:
  mov    $0xd2,%edi
  call   <fail_test@plt>
  jmp    L24
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D17
datatype: string

tool: D6:    
 	  abc			

tool: D17: abc

assistant: ```c
void test_trim() {
  char s[64];
  str_cpy(s, " \r  \n \t  abc\t\t\t\r\r");
  char *res = str_trim(s);
  if (str_len(res) != 3)
    fail_test(207);
  ;
  if (str_cmp("abc", res) != 0)
    fail_test(210);
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_trim>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rsi
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <str_cpy@plt>
  mov    %rbp,%rdi
  call   <str_trim@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <str_len@plt>
  cmp    $0x3,%eax
  je     L15
  mov    $0xcf,%edi
  call   <fail_test@plt>
L15:
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <str_cmp@plt>
  test   %rax,%rax
  jne    L16
L5:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x50,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0xd2,%edi
  call   <fail_test@plt>
  jmp    L5
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
datatype: string
name: read_data
arguments: data_tag: D8
datatype: string

tool: D10:    
 	  abc			

tool: D8: abc

assistant: ```c
void test_trim() {
  char s[64];
  str_cpy(s, " \r  \n \t  abc\t\t\t\r\r");
  char *res = str_trim(s);
  if (str_len(res) != 3)
    fail_test(207);
  ;
  if (str_cmp("abc", res) != 0)
    fail_test(210);
  ;
}
```