ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D24(%rip),%rsi
  lea    D3(%rip),%rdi
  push   %r13
  lea    D90(%rip),%r14
  lea    D52(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  lea    D70(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D83(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D59(%rip),%rsi
  call   <fprintf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  lea    D61(%rip),%r14
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <make_readme@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <make_readme@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %r13,%rsi
  lea    D107(%rip),%r13
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <make_readme@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D24
type_guessed: string
name: read_data
arguments: label: D3
type_guessed: string
name: read_data
arguments: label: D90
type_guessed: string
name: read_data
arguments: label: D52
type_guessed: string
name: read_data
arguments: label: D70
type_guessed: string
name: read_data
arguments: label: D83
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: string
name: read_data
arguments: label: D59
type_guessed: string
name: read_data
arguments: label: D61
type_guessed: string
name: read_data
arguments: label: D107
type_guessed: string

tool: D24: w

tool: D3: readme

tool: D90: put_token.c

tool: D52: r

tool: D70: Okay, you can use this code -- "keys".


tool: D83: You can know how to use it by these commets:



tool: D11: Warning!!


tool: D10: 	If you use "make clean" to uninstall this code,


tool: D59: 	you will delete "token.txt" and "data.txt".



tool: D61: put.c

tool: D107: get.c

assistant: ```c
int main() {
  FILE *in, *out = fopen("readme", "w");
  fprintf(out, "Okay, you can use this code -- \"keys\".\n");
  fprintf(out, "You can know how to use it by these commets:\n\n");
  fprintf(out, "Warning!!\n");
  fprintf(out, "\tIf you use \"make clean\" to uninstall this code,\n");
  fprintf(out, "\tyou will delete \"token.txt\" and \"data.txt\".\n\n");
  in = fopen("put_token.c", "r");
  make_readme(in, out, "put_token.c");
  fclose(in);
  in = fopen("put.c", "r");
  make_readme(in, out, "put.c");
  fclose(in);
  in = fopen("get.c", "r");
  make_readme(in, out, "get.c");
  fclose(in);
  fclose(out);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L11
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L20
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L20:
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L3
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(int *A, int p, int r) {
  int x = *(A + r);
  int i = p - 1;
  int temp;
  for (int j = p; j < r; j++) {
    if (*(A + j) <= x) {
      i++;
      temp = *(A + i);
      *(A + i) = *(A + j);
      *(A + j) = temp;
    }
  }
  temp = *(A + (i + 1));
  *(A + (i + 1)) = *(A + r);
  *(A + r) = temp;
  return i + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<partition>:
  endbr64
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r11
  mov    (%r11),%r8d
  lea    -0x1(%rsi),%eax
  cmp    %esi,%edx
  jle    L7
  movslq %esi,%r9
  lea    (%rdi,%r9,4),%rcx
  sub    %esi,%edx
  lea    -0x1(%rdx),%edx
  add    %r9,%rdx
  lea    0x4(%rdi,%rdx,4),%r9
  jmp    L10
L34:
  add    $0x4,%rcx
  cmp    %r9,%rcx
  je     L7
L10:
  mov    (%rcx),%edx
  cmp    %r8d,%edx
  jg     L34
  add    $0x1,%eax
  movslq %eax,%rsi
  lea    (%rdi,%rsi,4),%rsi
  mov    (%rsi),%r10d
  mov    %edx,(%rsi)
  mov    %r10d,(%rcx)
  jmp    L34
L7:
  movslq %eax,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
  mov    (%rdx),%ecx
  mov    (%r11),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%r11)
  add    $0x1,%eax
  ret
```

assistant: ```c
int partition(int *A, int p, int r) {
  int x = *(A + r);
  int i = p - 1;
  int temp;
  for (int j = p; j < r; j++) {
    if (*(A + j) <= x) {
      i++;
      temp = *(A + i);
      *(A + i) = *(A + j);
      *(A + j) = temp;
    }
  }
  temp = *(A + (i + 1));
  *(A + (i + 1)) = *(A + r);
  *(A + r) = temp;
  return i + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<partition>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%r9
  lea    (%rdi,%rax,4),%r11
  lea    -0x1(%rsi),%edi
  mov    (%r11),%r8d
  cmp    %esi,%edx
  jle    L39
  sub    %esi,%edx
  movslq %esi,%r10
  lea    -0x1(%rdx),%eax
  lea    (%r9,%r10,4),%rcx
  add    %r10,%rax
  lea    0x4(%r9,%rax,4),%rsi
  nopl   0x0(%rax)
L37:
  mov    (%rcx),%eax
  cmp    %r8d,%eax
  jg     L16
  add    $0x1,%edi
  movslq %edi,%rdx
  lea    (%r9,%rdx,4),%rdx
  mov    (%rdx),%r10d
  mov    %eax,(%rdx)
  mov    %r10d,(%rcx)
L16:
  add    $0x4,%rcx
  cmp    %rcx,%rsi
  jne    L37
  mov    (%r11),%r8d
  lea    0x1(%rdi),%eax
L7:
  movslq %edi,%rdi
  lea    0x4(%r9,%rdi,4),%rdx
  mov    (%rdx),%ecx
  mov    %r8d,(%rdx)
  mov    %ecx,(%r11)
  ret
  nopl   0x0(%rax)
L39:
  mov    %esi,%eax
  jmp    L7
```

assistant: ```c
int partition(int *A, int p, int r) {
  int x = *(A + r);
  int i = p - 1;
  int temp;
  for (int j = p; j < r; j++) {
    if (*(A + j) <= x) {
      i++;
      temp = *(A + i);
      *(A + i) = *(A + j);
      *(A + j) = temp;
    }
  }
  temp = *(A + (i + 1));
  *(A + (i + 1)) = *(A + r);
  *(A + r) = temp;
  return i + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<partition>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%r9
  lea    (%rdi,%rax,4),%r11
  lea    -0x1(%rsi),%edi
  mov    (%r11),%r8d
  cmp    %esi,%edx
  jle    L22
  sub    %esi,%edx
  movslq %esi,%r10
  lea    -0x1(%rdx),%eax
  lea    (%r9,%r10,4),%rcx
  add    %r10,%rax
  lea    0x4(%r9,%rax,4),%rsi
  nopl   0x0(%rax)
L39:
  mov    (%rcx),%eax
  cmp    %r8d,%eax
  jg     L27
  add    $0x1,%edi
  movslq %edi,%rdx
  lea    (%r9,%rdx,4),%rdx
  mov    (%rdx),%r10d
  mov    %eax,(%rdx)
  mov    %r10d,(%rcx)
L27:
  add    $0x4,%rcx
  cmp    %rcx,%rsi
  jne    L39
  mov    (%r11),%r8d
  lea    0x1(%rdi),%eax
L36:
  movslq %edi,%rdi
  lea    0x4(%r9,%rdi,4),%rdx
  mov    (%rdx),%ecx
  mov    %r8d,(%rdx)
  mov    %ecx,(%r11)
  ret
  nopl   0x0(%rax)
L22:
  mov    %esi,%eax
  jmp    L36
```

assistant: ```c
int partition(int *A, int p, int r) {
  int x = *(A + r);
  int i = p - 1;
  int temp;
  for (int j = p; j < r; j++) {
    if (*(A + j) <= x) {
      i++;
      temp = *(A + i);
      *(A + i) = *(A + j);
      *(A + j) = temp;
    }
  }
  temp = *(A + (i + 1));
  *(A + (i + 1)) = *(A + r);
  *(A + r) = temp;
  return i + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_row_euc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xa0,-0x4(%rbp)
  jle    L23
  cmpl   $0xfe,-0x4(%rbp)
  jg     L23
  mov    -0x4(%rbp),%eax
  sub    $0xa1,%eax
  jmp    L19
L23:
  cmpl   $0x8fa0,-0x4(%rbp)
  jle    L26
  cmpl   $0x8ffe,-0x4(%rbp)
  jg     L26
  mov    -0x4(%rbp),%eax
  sub    $0x8fa1,%eax
  jmp    L19
L26:
  mov    $0xffffffff,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int byte_row_euc(int byte) {
  if (byte >= 0xa1 && byte < 0xff)
    return byte - 0xa1;
  else if (byte >= 0x8fa1 && byte < 0x8fff)
    return byte - 0x8fa1;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byte_row_euc>:
  endbr64
  lea    -0xa1(%rdi),%eax
  cmp    $0x5d,%eax
  jbe    L7
  lea    -0x8fa1(%rdi),%eax
  cmp    $0x5d,%eax
  ja     L0
L7:
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int byte_row_euc(int byte) {
  if (byte >= 0xa1 && byte < 0xff)
    return byte - 0xa1;
  else if (byte >= 0x8fa1 && byte < 0x8fff)
    return byte - 0x8fa1;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<byte_row_euc>:
  endbr64
  lea    -0xa1(%rdi),%eax
  cmp    $0x5d,%eax
  jbe    L9
  sub    $0x8fa1,%edi
  mov    $0xffffffff,%eax
  cmp    $0x5d,%edi
  cmovbe %edi,%eax
L9:
  ret
```

assistant: ```c
int byte_row_euc(int byte) {
  if (byte >= 0xa1 && byte < 0xff)
    return byte - 0xa1;
  else if (byte >= 0x8fa1 && byte < 0x8fff)
    return byte - 0x8fa1;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<byte_row_euc>:
  endbr64
  lea    -0xa1(%rdi),%eax
  cmp    $0x5d,%eax
  jbe    L7
  sub    $0x8fa1,%edi
  mov    $0xffffffff,%eax
  cmp    $0x5d,%edi
  cmovbe %edi,%eax
L7:
  ret
```

assistant: ```c
int byte_row_euc(int byte) {
  if (byte >= 0xa1 && byte < 0xff)
    return byte - 0xa1;
  else if (byte >= 0x8fa1 && byte < 0x8fff)
    return byte - 0x8fa1;
  else
    return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<ADCInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0xe4e1c0,%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  sub    $0x1,%eax
  shl    $0x8,%eax
  or     $0x210001,%eax
  mov    %eax,%edx
  mov    $0xe0034000,%eax
  mov    %edx,%edx
  mov    %rdx,(%rax)
  mov    $0xe4e1c0,%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  sub    $0x1,%eax
  shl    $0x8,%eax
  or     $0x200001,%eax
  mov    %eax,%edx
  mov    $0xe0060000,%eax
  mov    %edx,%edx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ADCInit(unsigned int ADC_Clk) {
  (*(volatile unsigned long *)(0xE0034000 + 0x00)) = (0x01) | ((((12000000 * 5) / 4) * 1 / ADC_Clk - 1) << 8) | (1 << 16) | (0 << 17) | (1 << 21) | (0 << 22) | (0 << 24) | (0 << 27);
  (*(volatile unsigned long *)(0xE0060000 + 0x00)) = (0x01 << 0) | ((((12000000 * 5) / 4) * 1 / ADC_Clk - 1) << 8) | (0 << 16) | (0 << 17) | (1 << 21) | (0 << 22) | (0 << 24) | (0 << 27);
  return ((1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ADCInit>:
  endbr64
  mov    $0xe4e1c0,%eax
  mov    $0x0,%edx
  div    %edi
  lea    -0x1(%rax),%edx
  shl    $0x8,%edx
  mov    %edx,%eax
  or     $0x210001,%eax
  movabs %rax,0xe0034000
  mov    %edx,%eax
  or     $0x200001,%eax
  movabs %rax,0xe0060000
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int ADCInit(unsigned int ADC_Clk) {
  (*(volatile unsigned long *)(0xE0034000 + 0x00)) = (0x01) | ((((12000000 * 5) / 4) * 1 / ADC_Clk - 1) << 8) | (1 << 16) | (0 << 17) | (1 << 21) | (0 << 22) | (0 << 24) | (0 << 27);
  (*(volatile unsigned long *)(0xE0060000 + 0x00)) = (0x01 << 0) | ((((12000000 * 5) / 4) * 1 / ADC_Clk - 1) << 8) | (0 << 16) | (0 << 17) | (1 << 21) | (0 << 22) | (0 << 24) | (0 << 27);
  return ((1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ADCInit>:
  endbr64
  xor    %edx,%edx
  mov    $0xe4e1c0,%eax
  div    %edi
  lea    -0x1(%rax),%edx
  shl    $0x8,%edx
  mov    %edx,%eax
  or     $0x210001,%eax
  movabs %rax,0xe0034000
  mov    %edx,%eax
  or     $0x200001,%eax
  movabs %rax,0xe0060000
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int ADCInit(unsigned int ADC_Clk) {
  (*(volatile unsigned long *)(0xE0034000 + 0x00)) = (0x01) | ((((12000000 * 5) / 4) * 1 / ADC_Clk - 1) << 8) | (1 << 16) | (0 << 17) | (1 << 21) | (0 << 22) | (0 << 24) | (0 << 27);
  (*(volatile unsigned long *)(0xE0060000 + 0x00)) = (0x01 << 0) | ((((12000000 * 5) / 4) * 1 / ADC_Clk - 1) << 8) | (0 << 16) | (0 << 17) | (1 << 21) | (0 << 22) | (0 << 24) | (0 << 27);
  return ((1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ADCInit>:
  endbr64
  xor    %edx,%edx
  mov    $0xe4e1c0,%eax
  div    %edi
  lea    -0x1(%rax),%edx
  shl    $0x8,%edx
  mov    %edx,%eax
  or     $0x210001,%eax
  movabs %rax,0xe0034000
  mov    %edx,%eax
  or     $0x200001,%eax
  movabs %rax,0xe0060000
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int ADCInit(unsigned int ADC_Clk) {
  (*(volatile unsigned long *)(0xE0034000 + 0x00)) = (0x01) | ((((12000000 * 5) / 4) * 1 / ADC_Clk - 1) << 8) | (1 << 16) | (0 << 17) | (1 << 21) | (0 << 22) | (0 << 24) | (0 << 27);
  (*(volatile unsigned long *)(0xE0060000 + 0x00)) = (0x01 << 0) | ((((12000000 * 5) / 4) * 1 / ADC_Clk - 1) << 8) | (0 << 16) | (0 << 17) | (1 << 21) | (0 << 22) | (0 << 24) | (0 << 27);
  return ((1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<nh_print_trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %edx,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movq   $0x64,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    -0x40(%rbp),%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L10:
  cmp    %rdx,%rsp
  je     L54
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L10
L54:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L19
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L19:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <backtrace@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <backtrace_symbols@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x64(%rbp),%ecx
  mov    -0x60(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  movq   $0x1,-0x48(%rbp)
  jmp    L24
L32:
  mov    -0x48(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x58(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  addq   $0x1,-0x48(%rbp)
L24:
  mov    -0x48(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L32
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string

tool: D2: Call stack from %s:%d:


tool: D6:     %s


assistant: ```c
void nh_print_trace(FILE *out, const char *file, int line) {
  const size_t max_depth = 100;
  size_t stack_depth;
  void *stack_addrs[max_depth];
  char **stack_strings;
  stack_depth = backtrace(stack_addrs, max_depth);
  stack_strings = backtrace_symbols(stack_addrs, stack_depth);
  fprintf(out, "Call stack from %s:%d:\n", file, line);
  size_t i;
  for (i = 1; i < stack_depth; i++) {
    fprintf(out, "    %s\n", stack_strings[i]);
  }
  free(stack_strings);
  fflush(out);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nh_print_trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
L45:
  cmp    %rax,%rsp
  je     L30
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L45
L30:
  sub    $0x320,%rsp
  orq    $0x0,0x318(%rsp)
  mov    %rsp,%r13
  mov    $0x64,%esi
  mov    %r13,%rdi
  call   <backtrace@plt>
  mov    %rax,%r14
  mov    %rax,%rsi
  mov    %r13,%rdi
  call   <backtrace_symbols@plt>
  mov    %rax,%r13
  mov    %r15d,%ecx
  mov    %rbx,%rdx
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  cmp    $0x1,%r14
  jbe    L34
  mov    $0x1,%ebx
  lea    D1(%rip),%r15
L38:
  mov    0x0(%r13,%rbx,8),%rdx
  mov    %r15,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L38
L34:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <fflush@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D1
type: string

tool: D16: Call stack from %s:%d:


tool: D1:     %s


assistant: ```c
void nh_print_trace(FILE *out, const char *file, int line) {
  const size_t max_depth = 100;
  size_t stack_depth;
  void *stack_addrs[max_depth];
  char **stack_strings;
  stack_depth = backtrace(stack_addrs, max_depth);
  stack_strings = backtrace_symbols(stack_addrs, stack_depth);
  fprintf(out, "Call stack from %s:%d:\n", file, line);
  size_t i;
  for (i = 1; i < stack_depth; i++) {
    fprintf(out, "    %s\n", stack_strings[i]);
  }
  free(stack_strings);
  fflush(out);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nh_print_trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L4
L31:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L31
L4:
  sub    $0x320,%rsp
  orq    $0x0,0x318(%rsp)
  mov    $0x64,%esi
  mov    %rsp,%r15
  mov    %r15,%rdi
  call   <backtrace@plt>
  mov    %r15,%rdi
  mov    %rax,%rsi
  mov    %rax,%r13
  call   <backtrace_symbols@plt>
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %r12,%rdi
  mov    %rax,%r15
  lea    D9(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  cmp    $0x1,%r13
  jbe    L7
  mov    $0x1,%ebx
  lea    D14(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%r15,%rbx,8),%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <fprintf@plt>
  cmp    %rbx,%r13
  jne    L14
L7:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <fflush@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string

tool: D9: Call stack from %s:%d:


tool: D14:     %s


assistant: ```c
void nh_print_trace(FILE *out, const char *file, int line) {
  const size_t max_depth = 100;
  size_t stack_depth;
  void *stack_addrs[max_depth];
  char **stack_strings;
  stack_depth = backtrace(stack_addrs, max_depth);
  stack_strings = backtrace_symbols(stack_addrs, stack_depth);
  fprintf(out, "Call stack from %s:%d:\n", file, line);
  size_t i;
  for (i = 1; i < stack_depth; i++) {
    fprintf(out, "    %s\n", stack_strings[i]);
  }
  free(stack_strings);
  fflush(out);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nh_print_trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L20
L41:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L41
L20:
  sub    $0x320,%rsp
  orq    $0x0,0x318(%rsp)
  mov    $0x64,%esi
  mov    %rsp,%r15
  mov    %r15,%rdi
  call   <backtrace@plt>
  mov    %r15,%rdi
  mov    %rax,%rsi
  mov    %rax,%r13
  call   <backtrace_symbols@plt>
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %r12,%rdi
  mov    %rax,%r15
  lea    D13(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  cmp    $0x1,%r13
  jbe    L46
  mov    $0x1,%ebx
  lea    D12(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%r15,%rbx,8),%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <fprintf@plt>
  cmp    %rbx,%r13
  jne    L14
L46:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <fflush@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string

tool: D13: Call stack from %s:%d:


tool: D12:     %s


assistant: ```c
void nh_print_trace(FILE *out, const char *file, int line) {
  const size_t max_depth = 100;
  size_t stack_depth;
  void *stack_addrs[max_depth];
  char **stack_strings;
  stack_depth = backtrace(stack_addrs, max_depth);
  stack_strings = backtrace_symbols(stack_addrs, stack_depth);
  fprintf(out, "Call stack from %s:%d:\n", file, line);
  size_t i;
  for (i = 1; i < stack_depth; i++) {
    fprintf(out, "    %s\n", stack_strings[i]);
  }
  free(stack_strings);
  fflush(out);
}
```