ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<QuickSorting>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%r10
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <Sort.0>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void QuickSorting(int *m, int size) {
  void Sort(int l, int r) {
    int i = l;
    int j = r;
    int k = (l + r) / 2;
    int x = m[k];
    do {
      while (m[i] < x) {
        i++;
      }
      while (m[j] > x) {
        j--;
      }
      if (i <= j) {
        int temp = m[i];
        m[i] = m[j];
        m[j] = temp;
        i++;
        j--;
      }
    } while (i <= j);
    if (i < r) {
      Sort(i, r);
    }
    if (j > l) {
      Sort(l, j);
    }
  }
  Sort(0, size - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<QuickSorting>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %rdi,(%rsp)
  sub    $0x1,%esi
  mov    %rsp,%r10
  mov    $0x0,%edi
  call   <Sort.0>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void QuickSorting(int *m, int size) {
  void Sort(int l, int r) {
    int i = l;
    int j = r;
    int k = (l + r) / 2;
    int x = m[k];
    do {
      while (m[i] < x) {
        i++;
      }
      while (m[j] > x) {
        j--;
      }
      if (i <= j) {
        int temp = m[i];
        m[i] = m[j];
        m[j] = temp;
        i++;
        j--;
      }
    } while (i <= j);
    if (i < r) {
      Sort(i, r);
    }
    if (j > l) {
      Sort(l, j);
    }
  }
  Sort(0, size - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<QuickSorting>:
  endbr64
  sub    $0x28,%rsp
  sub    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r10
  lea    0x30(%rsp),%rax
  mov    %rdi,(%rsp)
  xor    %edi,%edi
  mov    %rax,0x8(%rsp)
  call   <Sort.0>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void QuickSorting(int *m, int size) {
  void Sort(int l, int r) {
    int i = l;
    int j = r;
    int k = (l + r) / 2;
    int x = m[k];
    do {
      while (m[i] < x) {
        i++;
      }
      while (m[j] > x) {
        j--;
      }
      if (i <= j) {
        int temp = m[i];
        m[i] = m[j];
        m[j] = temp;
        i++;
        j--;
      }
    } while (i <= j);
    if (i < r) {
      Sort(i, r);
    }
    if (j > l) {
      Sort(l, j);
    }
  }
  Sort(0, size - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<QuickSorting>:
  endbr64
  sub    $0x28,%rsp
  movq   %rdi,%xmm0
  sub    $0x1,%esi
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rsp,%r10
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <Sort.0>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void QuickSorting(int *m, int size) {
  void Sort(int l, int r) {
    int i = l;
    int j = r;
    int k = (l + r) / 2;
    int x = m[k];
    do {
      while (m[i] < x) {
        i++;
      }
      while (m[j] > x) {
        j--;
      }
      if (i <= j) {
        int temp = m[i];
        m[i] = m[j];
        m[j] = temp;
        i++;
        j--;
      }
    } while (i <= j);
    if (i < r) {
      Sort(i, r);
    }
    if (j > l) {
      Sort(l, j);
    }
  }
  Sort(0, size - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<det33>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x68(%rbp)
  mov    -0x78(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  mov    -0x78(%rbp),%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x18,%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x18,%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x30,%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x30,%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x48(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  movsd  -0x40(%rbp),%xmm1
  mulsd  -0x30(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  movsd  -0x50(%rbp),%xmm1
  mulsd  -0x28(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x50(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movsd  -0x48(%rbp),%xmm1
  mulsd  -0x38(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x68(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movsd  -0x60(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x58(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double det33(double m[3][3]) {
  double d;
  double c00, c01, c02;
  double m00, m01, m02, m10, m11, m12, m20, m21, m22;
  m00 = m[0][0];
  m01 = m[0][1];
  m02 = m[0][2];
  m10 = m[1][0];
  m11 = m[1][1];
  m12 = m[1][2];
  m20 = m[2][0];
  m21 = m[2][1];
  m22 = m[2][2];
  c00 = m11 * m22 - m12 * m21;
  c01 = m12 * m20 - m10 * m22;
  c02 = m10 * m21 - m11 * m20;
  d = m00 * c00 + m01 * c01 + m02 * c02;
  return d;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<det33>:
  endbr64
  movsd  0x18(%rdi),%xmm1
  movsd  0x20(%rdi),%xmm3
  movsd  0x28(%rdi),%xmm2
  movsd  0x30(%rdi),%xmm5
  movsd  0x38(%rdi),%xmm6
  movsd  0x40(%rdi),%xmm4
  movapd %xmm3,%xmm0
  mulsd  %xmm4,%xmm0
  movapd %xmm2,%xmm7
  mulsd  %xmm6,%xmm7
  subsd  %xmm7,%xmm0
  mulsd  (%rdi),%xmm0
  mulsd  %xmm5,%xmm2
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm2
  mulsd  0x8(%rdi),%xmm2
  addsd  %xmm2,%xmm0
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm3
  subsd  %xmm3,%xmm1
  mulsd  0x10(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double det33(double m[3][3]) {
  double d;
  double c00, c01, c02;
  double m00, m01, m02, m10, m11, m12, m20, m21, m22;
  m00 = m[0][0];
  m01 = m[0][1];
  m02 = m[0][2];
  m10 = m[1][0];
  m11 = m[1][1];
  m12 = m[1][2];
  m20 = m[2][0];
  m21 = m[2][1];
  m22 = m[2][2];
  c00 = m11 * m22 - m12 * m21;
  c01 = m12 * m20 - m10 * m22;
  c02 = m10 * m21 - m11 * m20;
  d = m00 * c00 + m01 * c01 + m02 * c02;
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<det33>:
  endbr64
  movsd  0x20(%rdi),%xmm3
  movsd  0x28(%rdi),%xmm2
  movsd  0x18(%rdi),%xmm1
  movsd  0x30(%rdi),%xmm5
  movsd  0x38(%rdi),%xmm6
  movsd  0x40(%rdi),%xmm4
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm7
  mulsd  %xmm5,%xmm2
  mulsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm7
  mulsd  %xmm1,%xmm4
  mulsd  %xmm5,%xmm3
  mulsd  %xmm6,%xmm1
  subsd  %xmm7,%xmm0
  mulsd  (%rdi),%xmm0
  subsd  %xmm4,%xmm2
  mulsd  0x8(%rdi),%xmm2
  subsd  %xmm3,%xmm1
  mulsd  0x10(%rdi),%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double det33(double m[3][3]) {
  double d;
  double c00, c01, c02;
  double m00, m01, m02, m10, m11, m12, m20, m21, m22;
  m00 = m[0][0];
  m01 = m[0][1];
  m02 = m[0][2];
  m10 = m[1][0];
  m11 = m[1][1];
  m12 = m[1][2];
  m20 = m[2][0];
  m21 = m[2][1];
  m22 = m[2][2];
  c00 = m11 * m22 - m12 * m21;
  c01 = m12 * m20 - m10 * m22;
  c02 = m10 * m21 - m11 * m20;
  d = m00 * c00 + m01 * c01 + m02 * c02;
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<det33>:
  endbr64
  movsd  0x20(%rdi),%xmm3
  movsd  0x28(%rdi),%xmm2
  movsd  0x18(%rdi),%xmm1
  movsd  0x30(%rdi),%xmm5
  movsd  0x38(%rdi),%xmm6
  movsd  0x40(%rdi),%xmm4
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm7
  mulsd  %xmm5,%xmm2
  mulsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm7
  mulsd  %xmm1,%xmm4
  mulsd  %xmm5,%xmm3
  mulsd  %xmm6,%xmm1
  subsd  %xmm7,%xmm0
  mulsd  (%rdi),%xmm0
  subsd  %xmm4,%xmm2
  mulsd  0x8(%rdi),%xmm2
  subsd  %xmm3,%xmm1
  mulsd  0x10(%rdi),%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double det33(double m[3][3]) {
  double d;
  double c00, c01, c02;
  double m00, m01, m02, m10, m11, m12, m20, m21, m22;
  m00 = m[0][0];
  m01 = m[0][1];
  m02 = m[0][2];
  m10 = m[1][0];
  m11 = m[1][1];
  m12 = m[1][2];
  m20 = m[2][0];
  m21 = m[2][1];
  m22 = m[2][2];
  c00 = m11 * m22 - m12 * m21;
  c01 = m12 * m20 - m10 * m22;
  c02 = m10 * m21 - m11 * m20;
  d = m00 * c00 + m01 * c01 + m02 * c02;
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L37
L35:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D43(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  cmp    $0x9,%eax
  jle    L25
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  mov    -0x14(%rbp),%eax
  cmp    $0xfffffff7,%eax
  jl     L32
  mov    -0x14(%rbp),%eax
  cmp    $0x9,%eax
  jg     L32
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L32:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L37:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D20
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string
name: read_data
arguments: label: D43
type_guessed: f64
name: read_data
arguments: label: D30
type_guessed: string

tool: D20: Enter an integer > 

tool: D26: %d

tool: D43: 10

tool: D30: %d


assistant: ```c
int main() {
  int X, Num, NewNum;
  printf("Enter an integer > \n");
  scanf("%d", &Num);
  while (Num) {
    X = Num % 10;
    NewNum = (Num - X) / 10.0;
    if (abs(Num) >= 10) {
      printf("%d\n", abs(X));
    }
    if (abs(Num) < 10) {
      printf("%d\n", X);
    }
    Num = NewNum;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  je     L75
  lea    D5(%rip),%r12
  jmp    L63
L56:
  mov    %ebx,%esi
  neg    %esi
  cmovs  %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L44
L36:
  mov    %ebp,0x4(%rsp)
  test   %ebp,%ebp
  je     L75
L63:
  movslq %ebp,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %ebp,%ebx
  sub    %eax,%ebx
  mov    %ebp,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D15(%rip),%xmm0
  cvttsd2si %xmm0,%ebp
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  cmp    $0x9,%eax
  jg     L56
L44:
  mov    0x4(%rsp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L36
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L75:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D5
data_type: string
name: retrieve_data
arguments: tag: D15
data_type: f64

tool: D3: Enter an integer > 

tool: D1: %d

tool: D5: %d


tool: D15: 10

assistant: ```c
int main() {
  int X, Num, NewNum;
  printf("Enter an integer > \n");
  scanf("%d", &Num);
  while (Num) {
    X = Num % 10;
    NewNum = (Num - X) / 10.0;
    if (abs(Num) >= 10) {
      printf("%d\n", abs(X));
    }
    if (abs(Num) < 10) {
      printf("%d\n", X);
    }
    Num = NewNum;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L63
  lea    D20(%rip),%r12
  jmp    L2
  xchg   %ax,%ax
L10:
  mov    0x4(%rsp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L75
L37:
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  je     L63
L2:
  movslq %ebx,%rbp
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%edx
  imul   $0x66666667,%rbp,%rbp
  sar    $0x1f,%eax
  sar    $0x22,%rbp
  sub    %eax,%ebp
  lea    0x0(%rbp,%rbp,4),%eax
  mov    %ebx,%ebp
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  sub    %eax,%ebp
  mov    %edx,%eax
  divsd  D14(%rip),%xmm0
  neg    %eax
  cvttsd2si %xmm0,%ebx
  cmovs  %edx,%eax
  cmp    $0x9,%eax
  jle    L10
  mov    %ebp,%esi
  mov    %r12,%rdi
  neg    %esi
  cmovs  %ebp,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L37
L75:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  jne    L2
L63:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type_guessed: string
name: retrieve_data
arguments: label: D24
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: f64

tool: D10: Enter an integer > 

tool: D24: %d

tool: D20: %d


tool: D14: 10

assistant: ```c
int main() {
  int X, Num, NewNum;
  printf("Enter an integer > \n");
  scanf("%d", &Num);
  while (Num) {
    X = Num % 10;
    NewNum = (Num - X) / 10.0;
    if (abs(Num) >= 10) {
      printf("%d\n", abs(X));
    }
    if (abs(Num) < 10) {
      printf("%d\n", X);
    }
    Num = NewNum;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D32(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L65
  jmp    L70
  nopl   (%rax)
L67:
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L52
L77:
  mov    %r12d,0x4(%rsp)
  test   %r12d,%r12d
  je     L70
L66:
  mov    %r12d,%eax
L65:
  movslq %eax,%rbp
  cltd
  pxor   %xmm0,%xmm0
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,4),%edx
  mov    %eax,%ebp
  add    %edx,%edx
  cvtsi2sd %edx,%xmm0
  sub    %edx,%ebp
  mov    %eax,%edx
  divsd  D24(%rip),%xmm0
  neg    %edx
  cvttsd2si %xmm0,%r12d
  cmovs  %eax,%edx
  cmp    $0x9,%edx
  jle    L67
  mov    %ebp,%esi
  mov    %rbx,%rdi
  neg    %esi
  cmovs  %ebp,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L77
L52:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,0x4(%rsp)
  test   %r12d,%r12d
  jne    L66
L70:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D32
datatype: string
name: extract_symbolic_data
arguments: data_label: D8
datatype: string
name: extract_symbolic_data
arguments: data_label: D14
datatype: string
name: extract_symbolic_data
arguments: data_label: D24
datatype: f64

tool: D32: Enter an integer > 

tool: D8: %d


tool: D14: %d

tool: D24: 10

assistant: ```c
int main() {
  int X, Num, NewNum;
  printf("Enter an integer > \n");
  scanf("%d", &Num);
  while (Num) {
    X = Num % 10;
    NewNum = (Num - X) / 10.0;
    if (abs(Num) >= 10) {
      printf("%d\n", abs(X));
    }
    if (abs(Num) < 10) {
      printf("%d\n", X);
    }
    Num = NewNum;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bin_con_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L66
L51:
  cmpl   $0x1,-0xc(%rbp)
  jne    L5
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x76,%al
  je     L101
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  je     L101
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L5
L101:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  jne    L17
  addl   $0x1,-0xc(%rbp)
  jmp    L21
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L21
  subl   $0x1,-0xc(%rbp)
L21:
  cmpl   $0x0,-0x4(%rbp)
  jle    L74
  mov    -0x4(%rbp),%eax
  jmp    L89
L74:
  addl   $0x1,-0x8(%rbp)
L66:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L51
  mov    $0x0,%eax
L89:
  leave
  ret
```

assistant: ```c
int bin_con_pos(char *g) {
  int bin_count = 0;
  int i, j, bin_con = 0;
  for (i = 0; i < strlen(g); i++) {
    if ((bin_count == 1) && (g[i] == 'v' || g[i] == '^' || g[i] == '>')) {
      bin_con = i;
    }
    if (g[i] == '(') {
      bin_count++;
    } else if (g[i] == ')') {
      bin_count--;
    }
    if (bin_con > 0) {
      return bin_con;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bin_con_pos>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  jmp    L28
L79:
  movzbl (%r12,%rbx,1),%eax
  lea    -0x3e(%rax),%edx
  test   $0xdf,%dl
  je     L69
  cmp    $0x76,%al
  jne    L73
L69:
  mov    %r14d,%r13d
  jmp    L73
L74:
  add    $0x1,%ebp
L45:
  add    $0x1,%rbx
  test   %r13d,%r13d
  jg     L77
L28:
  mov    %ebx,%r14d
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L48
  cmp    $0x1,%ebp
  je     L79
L73:
  movzbl (%r12,%rbx,1),%eax
  cmp    $0x28,%al
  je     L74
  cmp    $0x29,%al
  sete   %al
  movzbl %al,%eax
  sub    %eax,%ebp
  jmp    L45
L48:
  mov    $0x0,%r13d
L77:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin_con_pos(char *g) {
  int bin_count = 0;
  int i, j, bin_con = 0;
  for (i = 0; i < strlen(g); i++) {
    if ((bin_count == 1) && (g[i] == 'v' || g[i] == '^' || g[i] == '>')) {
      bin_con = i;
    }
    if (g[i] == '(') {
      bin_count++;
    } else if (g[i] == ')') {
      bin_count--;
    }
    if (bin_con > 0) {
      return bin_con;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bin_con_pos>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L44:
  xor    %r12d,%r12d
L18:
  cmp    $0x28,%al
  je     L66
L75:
  cmp    $0x29,%al
  sete   %al
  add    $0x1,%rbx
  movzbl %al,%eax
  sub    %eax,%ebp
  test   %r12d,%r12d
  jne    L72
L58:
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L43
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0x1,%ebp
  jne    L44
  lea    -0x3e(%rax),%edx
  and    $0xdf,%edx
  je     L18
  cmp    $0x76,%al
  cmovne %r14d,%r12d
  cmp    $0x28,%al
  jne    L75
L66:
  add    $0x1,%ebp
  add    $0x1,%rbx
  test   %r12d,%r12d
  je     L58
L72:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L43:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin_con_pos(char *g) {
  int bin_count = 0;
  int i, j, bin_con = 0;
  for (i = 0; i < strlen(g); i++) {
    if ((bin_count == 1) && (g[i] == 'v' || g[i] == '^' || g[i] == '>')) {
      bin_con = i;
    }
    if (g[i] == '(') {
      bin_count++;
    } else if (g[i] == ')') {
      bin_count--;
    }
    if (bin_con > 0) {
      return bin_con;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bin_con_pos>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L69:
  xor    %r12d,%r12d
L25:
  cmp    $0x28,%al
  je     L9
L0:
  cmp    $0x29,%al
  sete   %al
  add    $0x1,%rbx
  movzbl %al,%eax
  sub    %eax,%ebp
  test   %r12d,%r12d
  jne    L26
L24:
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L78
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0x1,%ebp
  jne    L69
  lea    -0x3e(%rax),%edx
  and    $0xdf,%edx
  je     L25
  cmp    $0x76,%al
  cmovne %r14d,%r12d
  cmp    $0x28,%al
  jne    L0
L9:
  add    $0x1,%ebp
  add    $0x1,%rbx
  test   %r12d,%r12d
  je     L24
L26:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L78:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin_con_pos(char *g) {
  int bin_count = 0;
  int i, j, bin_con = 0;
  for (i = 0; i < strlen(g); i++) {
    if ((bin_count == 1) && (g[i] == 'v' || g[i] == '^' || g[i] == '>')) {
      bin_con = i;
    }
    if (g[i] == '(') {
      bin_count++;
    } else if (g[i] == ')') {
      bin_count--;
    }
    if (bin_con > 0) {
      return bin_con;
    }
  }
  return 0;
}
```