ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x636261,0x4(%rsp)
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  lea    0x3(%rsp),%rdi
  movb   $0x0,0x3(%rsp)
  call   <reverse@plt>
  xor    %edi,%edi
  cmpb   $0x0,0x3(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: cba

assistant: ```c
int main(int argc, char *argv[]) {
  char s1[4] = {'a', 'b', 'c', '\0'};
  reverse(s1);
  assert(!strcmp("cba", s1));
  char s2[1] = {'\0'};
  reverse(s2);
  assert(!strcmp("", s2));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x636261,0x4(%rsp)
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  lea    0x3(%rsp),%rdi
  movb   $0x0,0x3(%rsp)
  call   <reverse@plt>
  xor    %edi,%edi
  cmpb   $0x0,0x3(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: cba

assistant: ```c
int main(int argc, char *argv[]) {
  char s1[4] = {'a', 'b', 'c', '\0'};
  reverse(s1);
  assert(!strcmp("cba", s1));
  char s2[1] = {'\0'};
  reverse(s2);
  assert(!strcmp("", s2));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dev_from_part>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void dev_from_part(char *dev_name) {
  int i;
  for (i = strlen(dev_name) - 1; isdigit(dev_name[i]); i--)
    dev_name[i] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dev_from_part>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  jmp    L3
L2:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L3:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
void dev_from_part(char *dev_name) {
  int i;
  for (i = strlen(dev_name) - 1; isdigit(dev_name[i]); i--)
    dev_name[i] = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dev_from_part>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L12:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L13:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L12
  pop    %rbx
  ret
```

assistant: ```c
void dev_from_part(char *dev_name) {
  int i;
  for (i = strlen(dev_name) - 1; isdigit(dev_name[i]); i--)
    dev_name[i] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dev_from_part>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L6:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L3:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
void dev_from_part(char *dev_name) {
  int i;
  for (i = strlen(dev_name) - 1; isdigit(dev_name[i]); i--)
    dev_name[i] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FreeFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <DisposePtr@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void FreeFile(char *fptr) {
  if (fptr)
    DisposePtr(fptr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<FreeFile>:
  endbr64
  test   %rdi,%rdi
  je     L2
  sub    $0x8,%rsp
  call   <DisposePtr@plt>
  add    $0x8,%rsp
  ret
L2:
  ret
```

assistant: ```c
void FreeFile(char *fptr) {
  if (fptr)
    DisposePtr(fptr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<FreeFile>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <DisposePtr@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void FreeFile(char *fptr) {
  if (fptr)
    DisposePtr(fptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FreeFile>:
  endbr64
  test   %rdi,%rdi
  je     L2
  jmp    1050 <DisposePtr@plt>
  xchg   %ax,%ax
L2:
  ret
```

assistant: ```c
void FreeFile(char *fptr) {
  if (fptr)
    DisposePtr(fptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<scan_ra>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dms_to_degrees@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L3
L29:
  movsd  -0x10(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L36
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <deb_printf@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   D12(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L36:
  movsd  -0x10(%rbp),%xmm0
  comisd D16(%rip),%xmm0
  jbe    L1
  lea    D32(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <deb_printf@plt>
  mov    $0xffffffff,%eax
  jmp    L3
L1:
  movsd  -0x10(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    $0x0,%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: byte[8]
name: parse_data
arguments: data_label: D16
type_guessed: f64
name: parse_data
arguments: data_label: D32
type_guessed: string

tool: D7: RA value is negative, ignoring sign


tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D16: 24

tool: D32: RA value is too large, ignoring


assistant: ```c
int scan_ra(double *d, char *val) {
  int ret;
  double v;
  ret = dms_to_degrees(val, &v);
  if (!ret) {
    return -1;
  }
  if (v < 0) {
    deb_printf(0, "RA value is negative, ignoring sign\n");
    v = -v;
  }
  if (v > 24.0) {
    deb_printf(0, "RA value is too large, ignoring\n");
    return -1;
  }
  *d = v;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scan_ra>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <dms_to_degrees@plt>
  test   %eax,%eax
  je     L57
  pxor   %xmm0,%xmm0
  comisd (%rsp),%xmm0
  ja     L38
L0:
  movsd  (%rsp),%xmm0
  comisd D7(%rip),%xmm0
  ja     L52
  movsd  %xmm0,(%rbx)
  mov    $0x0,%eax
L59:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L38:
  lea    D21(%rip),%rsi
  mov    $0x0,%edi
  call   <deb_printf@plt>
  movsd  (%rsp),%xmm0
  xorpd  D1(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  jmp    L0
L52:
  lea    D34(%rip),%rsi
  mov    $0x0,%edi
  call   <deb_printf@plt>
  mov    $0xffffffff,%eax
  jmp    L59
L57:
  mov    $0xffffffff,%eax
  jmp    L59
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: f64
name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: byte[16]
name: disassemble_data
arguments: data_label: D34
datatype: string

tool: D7: 24

tool: D21: RA value is negative, ignoring sign


tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D34: RA value is too large, ignoring


assistant: ```c
int scan_ra(double *d, char *val) {
  int ret;
  double v;
  ret = dms_to_degrees(val, &v);
  if (!ret) {
    return -1;
  }
  if (v < 0) {
    deb_printf(0, "RA value is negative, ignoring sign\n");
    v = -v;
  }
  if (v > 24.0) {
    deb_printf(0, "RA value is too large, ignoring\n");
    return -1;
  }
  *d = v;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scan_ra>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <dms_to_degrees@plt>
  test   %eax,%eax
  je     L28
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L65
L67:
  comisd D23(%rip),%xmm0
  ja     L16
  movsd  %xmm0,(%rbx)
  xor    %eax,%eax
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x10,%rsp
  pop    %rbx
  ret
L65:
  lea    D4(%rip),%rsi
  xor    %edi,%edi
  call   <deb_printf@plt>
  movsd  (%rsp),%xmm0
  xorpd  D27(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0xffffffff,%eax
  jmp    L48
L16:
  lea    D20(%rip),%rsi
  xor    %edi,%edi
  call   <deb_printf@plt>
  mov    $0xffffffff,%eax
  jmp    L48
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
type: f64
name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D27
type: byte[16]
name: unpack_data
arguments: label: D20
type: string

tool: D23: 24

tool: D4: RA value is negative, ignoring sign


tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D20: RA value is too large, ignoring


assistant: ```c
int scan_ra(double *d, char *val) {
  int ret;
  double v;
  ret = dms_to_degrees(val, &v);
  if (!ret) {
    return -1;
  }
  if (v < 0) {
    deb_printf(0, "RA value is negative, ignoring sign\n");
    v = -v;
  }
  if (v > 24.0) {
    deb_printf(0, "RA value is too large, ignoring\n");
    return -1;
  }
  *d = v;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scan_ra>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <dms_to_degrees@plt>
  test   %eax,%eax
  je     L62
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L54
L57:
  comisd D14(%rip),%xmm0
  ja     L29
  movsd  %xmm0,(%rbx)
  xor    %eax,%eax
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L54:
  lea    D3(%rip),%rsi
  xor    %edi,%edi
  call   <deb_printf@plt>
  movsd  (%rsp),%xmm0
  xorpd  D25(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L62:
  mov    $0xffffffff,%eax
  jmp    L41
L29:
  lea    D29(%rip),%rsi
  xor    %edi,%edi
  call   <deb_printf@plt>
  mov    $0xffffffff,%eax
  jmp    L41
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D29
type_infered: string

tool: D14: 24

tool: D3: RA value is negative, ignoring sign


tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D29: RA value is too large, ignoring


assistant: ```c
int scan_ra(double *d, char *val) {
  int ret;
  double v;
  ret = dms_to_degrees(val, &v);
  if (!ret) {
    return -1;
  }
  if (v < 0) {
    deb_printf(0, "RA value is negative, ignoring sign\n");
    v = -v;
  }
  if (v > 24.0) {
    deb_printf(0, "RA value is too large, ignoring\n");
    return -1;
  }
  *d = v;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<repeat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    0x3c(%rax),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L22:
  cmp    %rdx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L22
L18:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L31
  orq    $0x0,-0x8(%rsp,%rax,1)
L31:
  mov    %rsp,-0x48(%rbp)
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  movslq %r14d,%rdi
  add    %rsp,%rdi
  mov    $0x3c,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  mov    %r12,%rdi
  call   <fputs@plt>
  test   %r13d,%r13d
  jle    L56
  mov    $0x0,%ebx
  mov    D24(%rip),%r15
L29:
  mov    $0x3c,%r12d
  cmp    %r12d,%r13d
  cmovle %r13d,%r12d
  movslq %ebx,%rdi
  add    -0x48(%rbp),%rdi
  mov    (%r15),%ecx
  mov    $0x1,%edx
  mov    %r12d,%esi
  call   <fwrite@plt>
  add    %r12d,%ebx
  mov    %ebx,%eax
  sub    %r14d,%eax
  cmp    %ebx,%r14d
  cmovl  %eax,%ebx
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  sub    %r12d,%r13d
  test   %r13d,%r13d
  jg     L29
L56:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void repeat(const char *alu, const char *title, int n) {
  int len = strlen(alu);
  char buffer[len + 60];
  int pos = 0;
  memcpy(buffer, alu, len);
  memcpy(buffer + len, alu, 60);
  fputs(title, stdout);
  while (n > 0) {
    int bytes = n > 60 ? 60 : n;
    fwrite(buffer + pos, bytes, 1, stdout);
    pos += bytes;
    if (pos > len) {
      pos -= len;
    }
    fputc('\n', stdout);
    n -= bytes;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<repeat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  mov    %eax,%r13d
  lea    0x3c(%rax),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L60
L1:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L1
L60:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L29
L4:
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %rsp,%rdi
  mov    %rsp,-0x48(%rbp)
  call   <memcpy@plt>
  movslq %r13d,%rdi
  mov    %r14,%rsi
  mov    $0x3c,%edx
  add    %rsp,%rdi
  call   <memcpy@plt>
  mov    D1(%rip),%r14
  mov    %r12,%rdi
  mov    (%r14),%esi
  call   <fputs@plt>
  test   %r15d,%r15d
  jle    L17
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L57:
  mov    $0x3c,%r12d
  mov    (%r14),%ecx
  movslq %ebx,%rdi
  mov    $0x1,%edx
  cmp    %r12d,%r15d
  cmovle %r15d,%r12d
  add    -0x48(%rbp),%rdi
  add    %r12d,%ebx
  mov    %r12d,%esi
  call   <fwrite@plt>
  mov    %ebx,%eax
  mov    (%r14),%esi
  mov    $0xa,%edi
  sub    %r13d,%eax
  cmp    %ebx,%r13d
  cmovl  %eax,%ebx
  sub    %r12d,%r15d
  call   <fputc@plt>
  test   %r15d,%r15d
  jg     L57
L17:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L29:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L4
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void repeat(const char *alu, const char *title, int n) {
  int len = strlen(alu);
  char buffer[len + 60];
  int pos = 0;
  memcpy(buffer, alu, len);
  memcpy(buffer + len, alu, 60);
  fputs(title, stdout);
  while (n > 0) {
    int bytes = n > 60 ? 60 : n;
    fwrite(buffer + pos, bytes, 1, stdout);
    pos += bytes;
    if (pos > len) {
      pos -= len;
    }
    fputc('\n', stdout);
    n -= bytes;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<repeat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  mov    %eax,%r13d
  lea    0x3c(%rax),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L39
L40:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L40
L39:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L12
L29:
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %rsp,%rdi
  mov    %rsp,-0x48(%rbp)
  call   <memcpy@plt>
  movslq %r13d,%rdi
  mov    %r14,%rsi
  mov    $0x3c,%edx
  add    %rsp,%rdi
  call   <memcpy@plt>
  mov    D7(%rip),%r14
  mov    %r12,%rdi
  mov    (%r14),%esi
  call   <fputs@plt>
  test   %r15d,%r15d
  jle    L44
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L51:
  mov    $0x3c,%r12d
  mov    (%r14),%ecx
  movslq %ebx,%rdi
  mov    $0x1,%edx
  cmp    %r12d,%r15d
  cmovle %r15d,%r12d
  add    -0x48(%rbp),%rdi
  add    %r12d,%ebx
  mov    %r12d,%esi
  call   <fwrite@plt>
  mov    %ebx,%eax
  mov    (%r14),%esi
  mov    $0xa,%edi
  sub    %r13d,%eax
  cmp    %ebx,%r13d
  cmovl  %eax,%ebx
  sub    %r12d,%r15d
  call   <fputc@plt>
  test   %r15d,%r15d
  jg     L51
L44:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L12:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L29
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void repeat(const char *alu, const char *title, int n) {
  int len = strlen(alu);
  char buffer[len + 60];
  int pos = 0;
  memcpy(buffer, alu, len);
  memcpy(buffer + len, alu, 60);
  fputs(title, stdout);
  while (n > 0) {
    int bytes = n > 60 ? 60 : n;
    fwrite(buffer + pos, bytes, 1, stdout);
    pos += bytes;
    if (pos > len) {
      pos -= len;
    }
    fputc('\n', stdout);
    n -= bytes;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<pcg_oneseq_64_xsh_rs_32_boundedrand_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  neg    %eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x8(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pcg_oneseq_64_xsh_rs_32_random_r@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L0
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
uint32_t pcg_oneseq_64_xsh_rs_32_boundedrand_r(struct pcg_state_64 *rng, uint32_t bound) {
  uint32_t threshold = -bound % bound;
  for (;;) {
    uint32_t r = pcg_oneseq_64_xsh_rs_32_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pcg_oneseq_64_xsh_rs_32_boundedrand_r>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %esi,%eax
  neg    %eax
  cltd
  idiv   %esi
  mov    %edx,%ebp
L0:
  mov    %rbx,%rdi
  call   <pcg_oneseq_64_xsh_rs_32_random_r@plt>
  cmp    %eax,%ebp
  jg     L0
  cltd
  idiv   %r12d
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t pcg_oneseq_64_xsh_rs_32_boundedrand_r(struct pcg_state_64 *rng, uint32_t bound) {
  uint32_t threshold = -bound % bound;
  for (;;) {
    uint32_t r = pcg_oneseq_64_xsh_rs_32_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pcg_oneseq_64_xsh_rs_32_boundedrand_r>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    %esi,%r12d
  neg    %eax
  push   %rbp
  cltd
  push   %rbx
  mov    %rdi,%rbx
  idiv   %esi
  mov    %edx,%ebp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rdi
  call   <pcg_oneseq_64_xsh_rs_32_random_r@plt>
  cmp    %eax,%ebp
  jg     L6
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  pop    %r12
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t pcg_oneseq_64_xsh_rs_32_boundedrand_r(struct pcg_state_64 *rng, uint32_t bound) {
  uint32_t threshold = -bound % bound;
  for (;;) {
    uint32_t r = pcg_oneseq_64_xsh_rs_32_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pcg_oneseq_64_xsh_rs_32_boundedrand_r>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    %esi,%r12d
  neg    %eax
  push   %rbp
  cltd
  push   %rbx
  mov    %rdi,%rbx
  idiv   %esi
  mov    %edx,%ebp
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  call   <pcg_oneseq_64_xsh_rs_32_random_r@plt>
  cmp    %eax,%ebp
  jg     L4
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  pop    %r12
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t pcg_oneseq_64_xsh_rs_32_boundedrand_r(struct pcg_state_64 *rng, uint32_t bound) {
  uint32_t threshold = -bound % bound;
  for (;;) {
    uint32_t r = pcg_oneseq_64_xsh_rs_32_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <vectInit@plt>
  jmp    L4
L6:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <show@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <increment@plt>
L4:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int main(void) {
  int V[10];
  int j;
  vectInit(V);
  for (; V[9] < 1;) {
    show(V);
    increment(V);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <vectInit@plt>
  cmpl   $0x0,0x24(%rsp)
  jg     L13
  mov    %rsp,%rbx
L1:
  mov    %rbx,%rdi
  call   <show@plt>
  mov    %rbx,%rdi
  call   <increment@plt>
  cmpl   $0x0,0x24(%rsp)
  jle    L1
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int V[10];
  int j;
  vectInit(V);
  for (; V[9] < 1;) {
    show(V);
    increment(V);
  }
}
```