ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<category_to_name>:
  endbr64
  cmp    $0x6c1,%edi
  lea    D2(%rip),%rdx
  lea    D14(%rip),%rax
  cmovne %rdx,%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: string

tool: D2: LC_XXX

tool: D14: LC_MESSAGES

assistant: ```c
const char *category_to_name(category)
int category;
{
  const char *retval;
  switch (category) {
  case 1729:
    retval = "LC_MESSAGES";
    break;
  default:
    retval = "LC_XXX";
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binarySearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L38
  mov    -0x20(%rbp),%eax
  neg    %eax
  jmp    L35
L38:
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L51
  mov    -0x4(%rbp),%eax
  jmp    L35
L51:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L30
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binarySearch>
  jmp    L35
L30:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L35
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <binarySearch>
  jmp    L35
L35:
  leave
  ret
```

assistant: ```c
int binarySearch(int arr[], int x, int left, int right) {
  if (left > right) {
    return -left;
  }
  int mid = left + (right - left) / 2;
  if (arr[mid] == x) {
    return mid;
  } else if (arr[mid] > x) {
    return binarySearch(arr, x, left, mid - 1);
  } else if (arr[mid] < x) {
    return binarySearch(arr, x, mid + 1, right);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<binarySearch>:
  endbr64
  cmp    %ecx,%edx
  jg     L4
  sub    $0x8,%rsp
  mov    %ecx,%r8d
  sub    %edx,%r8d
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r8d
  cmp    %esi,%r8d
  je     L34
  jg     L10
  jl     L40
L34:
  add    $0x8,%rsp
  ret
L4:
  mov    %edx,%eax
  neg    %eax
  ret
L10:
  lea    -0x1(%rax),%ecx
  call   <binarySearch>
  jmp    L34
L40:
  lea    0x1(%rax),%edx
  call   <binarySearch>
  jmp    L34
```

assistant: ```c
int binarySearch(int arr[], int x, int left, int right) {
  if (left > right) {
    return -left;
  }
  int mid = left + (right - left) / 2;
  if (arr[mid] == x) {
    return mid;
  } else if (arr[mid] > x) {
    return binarySearch(arr, x, left, mid - 1);
  } else if (arr[mid] < x) {
    return binarySearch(arr, x, mid + 1, right);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binarySearch>:
  endbr64
  cmp    %ecx,%edx
  jle    L17
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L18:
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jl     L57
L17:
  mov    %ecx,%eax
  sub    %edx,%eax
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r8
  cmp    %esi,(%rdi,%r8,4)
  je     L48
  jg     L18
  jge    L48
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jge    L17
L57:
  mov    %edx,%eax
  neg    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  ret
```

assistant: ```c
int binarySearch(int arr[], int x, int left, int right) {
  if (left > right) {
    return -left;
  }
  int mid = left + (right - left) / 2;
  if (arr[mid] == x) {
    return mid;
  } else if (arr[mid] > x) {
    return binarySearch(arr, x, left, mid - 1);
  } else if (arr[mid] < x) {
    return binarySearch(arr, x, mid + 1, right);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<binarySearch>:
  endbr64
  cmp    %ecx,%edx
  jle    L40
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L34:
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jl     L0
L40:
  mov    %ecx,%eax
  sub    %edx,%eax
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r8
  cmp    %esi,(%rdi,%r8,4)
  je     L48
  jg     L34
  jge    L48
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jge    L40
L0:
  mov    %edx,%eax
  neg    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  ret
```

assistant: ```c
int binarySearch(int arr[], int x, int left, int right) {
  if (left > right) {
    return -left;
  }
  int mid = left + (right - left) / 2;
  if (arr[mid] == x) {
    return mid;
  } else if (arr[mid] > x) {
    return binarySearch(arr, x, left, mid - 1);
  } else if (arr[mid] < x) {
    return binarySearch(arr, x, mid + 1, right);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  cmpl   $0x5,-0x1c(%rbp)
  ja     L6
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D18(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D18(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <expand1@plt>
  jmp    L51
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <expand2@plt>
  jmp    L51
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <expand3@plt>
  jmp    L51
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <expand4@plt>
  jmp    L51
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <expand5@plt>
  jmp    L51
L6:
  nop
L51:
  nop
  leave
  ret
```

assistant: ```c
void expand(char *str, const char *fmt, char **args, int len, int out) {
  switch (len) {
  case 1:
    expand1(str, fmt, args, out);
    break;
  case 2:
    expand2(str, fmt, args, out);
    break;
  case 3:
    expand3(str, fmt, args, out);
    break;
  case 4:
    expand4(str, fmt, args, out);
    break;
  case 5:
    expand5(str, fmt, args, out);
    break;
  default:
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<expand>:
  endbr64
  mov    %ecx,%eax
  cmp    $0x5,%ecx
  ja     L40
  sub    $0x8,%rsp
  mov    %r8d,%ecx
  mov    %eax,%eax
  lea    D9(%rip),%r8
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  call   <expand1@plt>
L9:
  add    $0x8,%rsp
  ret
  call   <expand2@plt>
  jmp    L9
  call   <expand3@plt>
  jmp    L9
  call   <expand4@plt>
  jmp    L9
  call   <expand5@plt>
  jmp    L9
L40:
  ret
```

assistant: ```c
void expand(char *str, const char *fmt, char **args, int len, int out) {
  switch (len) {
  case 1:
    expand1(str, fmt, args, out);
    break;
  case 2:
    expand2(str, fmt, args, out);
    break;
  case 3:
    expand3(str, fmt, args, out);
    break;
  case 4:
    expand4(str, fmt, args, out);
    break;
  case 5:
    expand5(str, fmt, args, out);
    break;
  default:
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<expand>:
  endbr64
  mov    %ecx,%eax
  mov    %r8d,%ecx
  cmp    $0x5,%eax
  ja     L3
  lea    D0(%rip),%r8
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  nop
  jmp    10a0 <expand5@plt>
  nopl   (%rax)
  jmp    10b0 <expand1@plt>
  nopl   (%rax)
  jmp    10d0 <expand2@plt>
  nopl   (%rax)
  jmp    1090 <expand3@plt>
  nopl   (%rax)
  jmp    10c0 <expand4@plt>
L3:
  ret
```

assistant: ```c
void expand(char *str, const char *fmt, char **args, int len, int out) {
  switch (len) {
  case 1:
    expand1(str, fmt, args, out);
    break;
  case 2:
    expand2(str, fmt, args, out);
    break;
  case 3:
    expand3(str, fmt, args, out);
    break;
  case 4:
    expand4(str, fmt, args, out);
    break;
  case 5:
    expand5(str, fmt, args, out);
    break;
  default:
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<expand>:
  endbr64
  mov    %ecx,%eax
  mov    %r8d,%ecx
  cmp    $0x5,%eax
  ja     L6
  lea    D4(%rip),%r8
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  nop
  jmp    10a0 <expand5@plt>
  nopl   (%rax)
  jmp    10b0 <expand1@plt>
  nopl   (%rax)
  jmp    10d0 <expand2@plt>
  nopl   (%rax)
  jmp    1090 <expand3@plt>
  nopl   (%rax)
  jmp    10c0 <expand4@plt>
L6:
  ret
```

assistant: ```c
void expand(char *str, const char *fmt, char **args, int len, int out) {
  switch (len) {
  case 1:
    expand1(str, fmt, args, out);
    break;
  case 2:
    expand2(str, fmt, args, out);
    break;
  case 3:
    expand3(str, fmt, args, out);
    break;
  case 4:
    expand4(str, fmt, args, out);
    break;
  case 5:
    expand5(str, fmt, args, out);
    break;
  default:
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0xa,-0x14(%rbp)
  jmp    L10
L2:
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    %edx,%ecx
  lea    D39(%rip),%rdx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x10(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L20
  mov    -0x14(%rbp),%eax
  lea    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rdi
  mov    %eax,%ecx
  lea    D31(%rip),%rax
  mov    %rax,%rdx
  mov    $0x4,%esi
  call   <snprintf@plt>
  lea    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmpany@plt>
  lea    D41(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  lea    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rcx
  lea    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
L20:
  nop
L38:
  addl   $0x1,-0x14(%rbp)
L10:
  cmpl   $0x63,-0x14(%rbp)
  jle    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D33
data_type: string
name: extract_symbolic_data
arguments: data_tag: D39
data_type: string
name: extract_symbolic_data
arguments: data_tag: D22
data_type: string
name: extract_symbolic_data
arguments: data_tag: D31
data_type: string
name: extract_symbolic_data
arguments: data_tag: D41
data_type: string
name: extract_symbolic_data
arguments: data_tag: D36
data_type: string

tool: D33: hex dec

tool: D39: %x

tool: D22: abcdef

tool: D31: %d

tool: D41: -#

tool: D36: %c %s %s


assistant: ```c
main() {
  printf("hex dec\n");
  for (int i = 10; i < 100; i++) {
    char buf[2][4];
    snprintf(buf[0], sizeof buf[0], "%x", i);
    if (strpbrk(buf[0], "abcdef"))
      continue;
    snprintf(buf[1], sizeof buf[1], "%d", i);
    printf("%c %s %s\n", "-#"[strcmpany(buf[0], buf[1])], buf[0], buf[1]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D43(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%ebx
  lea    D56(%rip),%r14
  lea    D40(%rip),%r13
  lea    D34(%rip),%r15
  jmp    L36
L31:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L25
L36:
  mov    %rsp,%rbp
  mov    %ebx,%ecx
  mov    %r14,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L31
  mov    %rsp,%r12
  lea    0x4(%rsp),%rbp
  mov    %ebx,%ecx
  lea    D44(%rip),%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmpany@plt>
  movsbl (%r15,%rax,1),%esi
  mov    %rbp,%rcx
  mov    %r12,%rdx
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D43
datatype: string
name: read_data
arguments: label: D56
datatype: string
name: read_data
arguments: label: D40
datatype: string
name: read_data
arguments: label: D34
datatype: string
name: read_data
arguments: label: D44
datatype: string
name: read_data
arguments: label: D39
datatype: string

tool: D43: hex dec

tool: D56: %x

tool: D40: abcdef

tool: D34: -#

tool: D44: %d

tool: D39: %c %s %s


assistant: ```c
main() {
  printf("hex dec\n");
  for (int i = 10; i < 100; i++) {
    char buf[2][4];
    snprintf(buf[0], sizeof buf[0], "%x", i);
    if (strpbrk(buf[0], "abcdef"))
      continue;
    snprintf(buf[1], sizeof buf[1], "%d", i);
    printf("%c %s %s\n", "-#"[strcmpany(buf[0], buf[1])], buf[0], buf[1]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D7(%rip),%rdi
  lea    D24(%rip),%r15
  push   %r14
  mov    $0xa,%r14d
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L9:
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  call   <snprintf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L10
  mov    %r14d,%ecx
  mov    %r15,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmpany@plt>
  lea    D26(%rip),%rdx
  mov    %rbp,%rcx
  lea    D58(%rip),%rdi
  movsbl (%rdx,%rax,1),%esi
  mov    %rbx,%rdx
  xor    %eax,%eax
  call   <printf@plt>
L10:
  add    $0x1,%r14d
  cmp    $0x64,%r14d
  jne    L9
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string
name: retrieve_data
arguments: data_tag: D24
data_type: string
name: retrieve_data
arguments: data_tag: D3
data_type: string
name: retrieve_data
arguments: data_tag: D34
data_type: string
name: retrieve_data
arguments: data_tag: D26
data_type: string
name: retrieve_data
arguments: data_tag: D58
data_type: string

tool: D7: hex dec

tool: D24: %d

tool: D3: %x

tool: D34: abcdef

tool: D26: -#

tool: D58: %c %s %s


assistant: ```c
main() {
  printf("hex dec\n");
  for (int i = 10; i < 100; i++) {
    char buf[2][4];
    snprintf(buf[0], sizeof buf[0], "%x", i);
    if (strpbrk(buf[0], "abcdef"))
      continue;
    snprintf(buf[1], sizeof buf[1], "%d", i);
    printf("%c %s %s\n", "-#"[strcmpany(buf[0], buf[1])], buf[0], buf[1]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  lea    D29(%rip),%rdi
  lea    D16(%rip),%r15
  push   %r14
  mov    $0xa,%r14d
  push   %r13
  lea    D52(%rip),%r13
  push   %r12
  lea    D54(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L29:
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  call   <snprintf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L39
  mov    %r14d,%ecx
  mov    %r15,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r14d
  call   <strcmpany@plt>
  lea    D14(%rip),%rdx
  mov    %rbp,%rcx
  lea    D43(%rip),%rdi
  movsbl (%rdx,%rax,1),%esi
  mov    %rbx,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x64,%r14d
  jne    L29
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x1,%r14d
  cmp    $0x64,%r14d
  jne    L29
  jmp    L46
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D29
type_infered: string
name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D52
type_infered: string
name: parse_data
arguments: data_label: D54
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D43
type_infered: string

tool: D29: hex dec

tool: D16: %d

tool: D52: %x

tool: D54: abcdef

tool: D14: -#

tool: D43: %c %s %s


assistant: ```c
main() {
  printf("hex dec\n");
  for (int i = 10; i < 100; i++) {
    char buf[2][4];
    snprintf(buf[0], sizeof buf[0], "%x", i);
    if (strpbrk(buf[0], "abcdef"))
      continue;
    snprintf(buf[1], sizeof buf[1], "%d", i);
    printf("%c %s %s\n", "-#"[strcmpany(buf[0], buf[1])], buf[0], buf[1]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<resolve_service>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <getservbyname@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  mov    %eax,-0x20(%rbp)
  jmp    L13
L0:
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jae    L29
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L13
L29:
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <logwarn@plt>
L13:
  mov    -0x20(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: Could not resolve service '%s', defaulting to %d


assistant: ```c
int resolve_service(const char *service, int defport) {
  struct servent *sse;
  char *endptr;
  int portnum = defport, tmpport;
  sse = getservbyname(service, NULL);
  if (sse) {
    portnum = ntohs(sse->s_port);
  } else {
    tmpport = strtol(service, &endptr, 10);
    if (endptr > service)
      portnum = tmpport;
    else
      logwarn("Could not resolve service '%s', defaulting to %d\n", service, portnum);
  }
  return portnum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<resolve_service>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  call   <getservbyname@plt>
  test   %rax,%rax
  je     L0
  mov    (%rax),%edi
  call   <ntohs@plt>
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rbx,%rdi
  call   <strtol@plt>
  cmp    %rbx,(%rsp)
  ja     L21
  mov    %ebp,%edx
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <logwarn@plt>
  mov    %ebp,%eax
  jmp    L21
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: Could not resolve service '%s', defaulting to %d


assistant: ```c
int resolve_service(const char *service, int defport) {
  struct servent *sse;
  char *endptr;
  int portnum = defport, tmpport;
  sse = getservbyname(service, NULL);
  if (sse) {
    portnum = ntohs(sse->s_port);
  } else {
    tmpport = strtol(service, &endptr, 10);
    if (endptr > service)
      portnum = tmpport;
    else
      logwarn("Could not resolve service '%s', defaulting to %d\n", service, portnum);
  }
  return portnum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<resolve_service>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <getservbyname@plt>
  test   %rax,%rax
  je     L15
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  mov    (%rax),%edi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  jmp    10d0 <ntohs@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  call   <strtol@plt>
  cmp    %rbp,(%rsp)
  jbe    L23
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L23:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <logwarn@plt>
  mov    %ebx,%eax
  jmp    L25
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: Could not resolve service '%s', defaulting to %d


assistant: ```c
int resolve_service(const char *service, int defport) {
  struct servent *sse;
  char *endptr;
  int portnum = defport, tmpport;
  sse = getservbyname(service, NULL);
  if (sse) {
    portnum = ntohs(sse->s_port);
  } else {
    tmpport = strtol(service, &endptr, 10);
    if (endptr > service)
      portnum = tmpport;
    else
      logwarn("Could not resolve service '%s', defaulting to %d\n", service, portnum);
  }
  return portnum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<resolve_service>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <getservbyname@plt>
  test   %rax,%rax
  je     L3
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  mov    (%rax),%edi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  jmp    10d0 <ntohs@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  call   <strtol@plt>
  cmp    %rbp,(%rsp)
  jbe    L20
L45:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L20:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <logwarn@plt>
  mov    %ebx,%eax
  jmp    L45
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: Could not resolve service '%s', defaulting to %d


assistant: ```c
int resolve_service(const char *service, int defport) {
  struct servent *sse;
  char *endptr;
  int portnum = defport, tmpport;
  sse = getservbyname(service, NULL);
  if (sse) {
    portnum = ntohs(sse->s_port);
  } else {
    tmpport = strtol(service, &endptr, 10);
    if (endptr > service)
      portnum = tmpport;
    else
      logwarn("Could not resolve service '%s', defaulting to %d\n", service, portnum);
  }
  return portnum;
}
```