ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compute_centroids_uint8>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8d,%r12d
  imul   %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  lea    0x0(,%r12,8),%edi
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  mov    %r8d,0x8(%rsp)
  call   <malloc@plt>
  mov    %r12d,%edi
  mov    $0x4,%esi
  mov    %rax,%r15
  call   <calloc@plt>
  mov    0x8(%rsp),%edi
  mov    $0x4,%esi
  mov    %rax,%r14
  call   <calloc@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%r8d
  mov    %rax,%r12
  test   %edx,%edx
  jle    L28
  lea    -0x1(%rdx),%eax
  mov    %rbp,%rdi
  lea    0x4(%r14),%r11
  xor    %r9d,%r9d
  lea    0x4(%rbp,%rax,4),%r10
  lea    -0x1(%rbx),%ebp
  nopl   (%rax)
L76:
  movslq (%rdi),%rsi
  test   %ebx,%ebx
  jle    L74
  mov    %ebx,%ecx
  mov    %esi,0x8(%rsp)
  movslq %r9d,%rdx
  imul   %esi,%ecx
  lea    0x0(%r13,%rdx,8),%rdx
  movslq %ecx,%rcx
  lea    (%r14,%rcx,4),%rax
  add    %rbp,%rcx
  lea    (%r11,%rcx,4),%rcx
  cs nopw 0x0(%rax,%rax,1)
L80:
  mov    (%rdx),%esi
  add    %esi,(%rax)
  add    $0x4,%rax
  add    $0x8,%rdx
  cmp    %rax,%rcx
  jne    L80
  movslq 0x8(%rsp),%rsi
L74:
  add    $0x4,%rdi
  addl   $0x1,(%r12,%rsi,4)
  add    %ebx,%r9d
  cmp    %r10,%rdi
  jne    L76
L28:
  test   %r8d,%r8d
  jle    L109
  mov    %r12,%rdi
  lea    (%r12,%r8,4),%rbp
  lea    -0x1(%rbx),%r11d
  xor    %r10d,%r10d
  jmp    L34
  nopl   0x0(%rax)
L87:
  add    $0x4,%rdi
  add    %ebx,%r10d
  cmp    %rdi,%rbp
  je     L109
L34:
  mov    (%rdi),%esi
  test   %esi,%esi
  je     L87
  test   %ebx,%ebx
  jle    L87
  movslq %r10d,%rax
  xor    %ecx,%ecx
  lea    (%r14,%rax,4),%r9
  lea    (%r15,%rax,8),%r8
  nopl   0x0(%rax,%rax,1)
L62:
  mov    (%r9,%rcx,4),%eax
  cltd
  idiv   %esi
  cltq
  mov    %rax,(%r8,%rcx,8)
  mov    %rcx,%rax
  add    $0x1,%rcx
  cmp    %r11,%rax
  jne    L62
  add    $0x4,%rdi
  add    %ebx,%r10d
  cmp    %rdi,%rbp
  jne    L34
L109:
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint8_t *compute_centroids_uint8(uint8_t *space, int *cluster_map, int points, int dim, int k) {
  uint8_t *centroids = malloc(k * dim * sizeof(uint8_t));
  uint32_t *sums = calloc(k * dim, sizeof(uint32_t));
  int *cluster_points = calloc(k, sizeof(int));
  for (int i = 0; i < points; ++i) {
    int n = cluster_map[i];
    for (int j = 0; j < dim; ++j)
      sums[n * dim + j] = sums[n * dim + j] + (uint32_t)space[i * dim + j];
    ++cluster_points[n];
  }
  for (int n = 0; n < k; ++n) {
    if (cluster_points[n]) {
      for (int i = 0; i < dim; ++i)
        centroids[n * dim + i] = (uint8_t)(sums[n * dim + i] / cluster_points[n]);
    }
  }
  free(sums);
  free(cluster_points);
  return centroids;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tun_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb0(%rbp),%rcx
  mov    -0xa8(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rcx,%r9
  mov    %rdx,%r8
  lea    D3(%rip),%rdx
  mov    %rdx,%rcx
  lea    D21(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x8,%edi
  call   <jlog@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    %eax,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string
name: disassemble_data
arguments: data_tag: D21
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D3: ifconfig

tool: D21: %s %s %s

tool: D6: tunnel]> %s

assistant: ```c
extern int tun_up(char *devname, char *addr) {
  char sys[128];
  int ret;
  snprintf(sys, 128, "%s %s %s", "ifconfig", devname, addr);
  jlog(0x08, "tunnel]> %s", sys);
  ret = system(sys);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tun_up>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D12(%rip),%rcx
  lea    D29(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdx
  lea    D28(%rip),%rsi
  mov    $0x8,%edi
  call   <jlog@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x90,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
datatype: string
name: parse_data
arguments: tag: D29
datatype: string
name: parse_data
arguments: tag: D28
datatype: string

tool: D12: ifconfig

tool: D29: %s %s %s

tool: D28: tunnel]> %s

assistant: ```c
extern int tun_up(char *devname, char *addr) {
  char sys[128];
  int ret;
  snprintf(sys, 128, "%s %s %s", "ifconfig", devname, addr);
  jlog(0x08, "tunnel]> %s", sys);
  ret = system(sys);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tun_up>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%r9
  lea    D3(%rip),%rcx
  lea    D23(%rip),%rdx
  mov    $0x80,%esi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdx
  mov    $0x8,%edi
  lea    D22(%rip),%rsi
  call   <jlog@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x90,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string

tool: D3: ifconfig

tool: D23: %s %s %s

tool: D22: tunnel]> %s

assistant: ```c
extern int tun_up(char *devname, char *addr) {
  char sys[128];
  int ret;
  snprintf(sys, 128, "%s %s %s", "ifconfig", devname, addr);
  jlog(0x08, "tunnel]> %s", sys);
  ret = system(sys);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<tun_up>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%r9
  lea    D4(%rip),%rcx
  lea    D17(%rip),%rdx
  mov    $0x80,%esi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdx
  mov    $0x8,%edi
  lea    D7(%rip),%rsi
  call   <jlog@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x90,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D4: ifconfig

tool: D17: %s %s %s

tool: D7: tunnel]> %s

assistant: ```c
extern int tun_up(char *devname, char *addr) {
  char sys[128];
  int ret;
  snprintf(sys, 128, "%s %s %s", "ifconfig", devname, addr);
  jlog(0x08, "tunnel]> %s", sys);
  ret = system(sys);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ResetISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe000ed88,%eax
  mov    (%rax),%edx
  mov    $0xe000ed88,%eax
  or     $0xf00000,%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ResetISR>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ResetISR>:
  endbr64
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_line_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %rdx,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rdx
  mov    -0x120(%rbp),%rcx
  mov    -0x118(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <next_line_str@plt>
  test   %rax,%rax
  je     L17
  mov    -0x128(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L17
  mov    $0x1,%eax
  jmp    L6
L17:
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: %d

assistant: ```c
int next_line_int(FILE *f, char *tag, int *out) {
  char str[256];
  if (next_line_str(f, tag, str) && sscanf(str, "%d", out) == 1)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<next_line_int>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <next_line_str@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L11
L0:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x110,%rsp
  pop    %rbx
  ret
L11:
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  lea    D5(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L0
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: %d

assistant: ```c
int next_line_int(FILE *f, char *tag, int *out) {
  char str[256];
  if (next_line_str(f, tag, str) && sscanf(str, "%d", out) == 1)
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<next_line_int>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <next_line_str@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L14
  mov    %r12,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L14:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d

assistant: ```c
int next_line_int(FILE *f, char *tag, int *out) {
  char str[256];
  if (next_line_str(f, tag, str) && sscanf(str, "%d", out) == 1)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<next_line_int>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <next_line_str@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L14
  mov    %r12,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L14:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: %d

assistant: ```c
int next_line_int(FILE *f, char *tag, int *out) {
  char str[256];
  if (next_line_str(f, tag, str) && sscanf(str, "%d", out) == 1)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dct64_486>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %rdx,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x114(%rbp)
  jmp    L18
L2:
  mov    -0x114(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x138(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x114(%rbp),%eax
  add    $0x20,%eax
  cvttsd2si %xmm0,%edx
  cltq
  mov    %edx,-0x110(%rbp,%rax,4)
  addl   $0x1,-0x114(%rbp)
L18:
  cmpl   $0x1f,-0x114(%rbp)
  jle    L2
  lea    -0x110(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  lea    -0x110(%rbp),%rdx
  mov    -0x130(%rbp),%rsi
  mov    -0x128(%rbp),%rdi
  mov    %rax,%rcx
  mov    $0x0,%eax
  call   <dct64_1_486@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: f64

tool: D4: 32768

assistant: ```c
void dct64_486(int *a, int *b, double *samples) {
  int bufs[64];
  int i;
  for (i = 0; i < 32; i++) {
    bufs[i + 32] = ((int)((samples[i]) * 32768.0));
  }
  dct64_1_486(a, b, bufs, bufs + 0x20);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dct64_486>:
  endbr64
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%r8
  movsd  D2(%rip),%xmm1
L17:
  movapd %xmm1,%xmm0
  mulsd  (%rdx,%rax,2),%xmm0
  cvttsd2si %xmm0,%ecx
  mov    %ecx,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    $0x80,%rax
  jne    L17
  mov    %rsp,%rdx
  lea    0x80(%rsp),%rcx
  mov    $0x0,%eax
  call   <dct64_1_486@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x118,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
datatype: f64

tool: D2: 32768

assistant: ```c
void dct64_486(int *a, int *b, double *samples) {
  int bufs[64];
  int i;
  for (i = 0; i < 32; i++) {
    bufs[i + 32] = ((int)((samples[i]) * 32768.0));
  }
  dct64_1_486(a, b, bufs, bufs + 0x20);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dct64_486>:
  endbr64
  sub    $0x118,%rsp
  movsd  D8(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%r8
  xchg   %ax,%ax
L5:
  movsd  (%rdx,%rax,2),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%ecx
  mov    %ecx,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    $0x80,%rax
  jne    L5
  xor    %eax,%eax
  mov    %r8,%rcx
  mov    %rsp,%rdx
  call   <dct64_1_486@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x118,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: f64

tool: D8: 32768

assistant: ```c
void dct64_486(int *a, int *b, double *samples) {
  int bufs[64];
  int i;
  for (i = 0; i < 32; i++) {
    bufs[i + 32] = ((int)((samples[i]) * 32768.0));
  }
  dct64_1_486(a, b, bufs, bufs + 0x20);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dct64_486>:
  endbr64
  sub    $0x118,%rsp
  movupd (%rdx),%xmm1
  movapd D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movupd 0x10(%rdx),%xmm2
  lea    0x80(%rsp),%rcx
  mulpd  %xmm0,%xmm1
  mulpd  %xmm0,%xmm2
  cvttpd2dq %xmm1,%xmm1
  cvttpd2dq %xmm2,%xmm2
  punpcklqdq %xmm2,%xmm1
  movupd 0x30(%rdx),%xmm2
  movaps %xmm1,0x80(%rsp)
  movupd 0x20(%rdx),%xmm1
  mulpd  %xmm0,%xmm2
  mulpd  %xmm0,%xmm1
  cvttpd2dq %xmm2,%xmm2
  cvttpd2dq %xmm1,%xmm1
  punpcklqdq %xmm2,%xmm1
  movupd 0x50(%rdx),%xmm2
  movaps %xmm1,0x90(%rsp)
  movupd 0x40(%rdx),%xmm1
  mulpd  %xmm0,%xmm2
  mulpd  %xmm0,%xmm1
  cvttpd2dq %xmm2,%xmm2
  cvttpd2dq %xmm1,%xmm1
  punpcklqdq %xmm2,%xmm1
  movupd 0x70(%rdx),%xmm2
  movaps %xmm1,0xa0(%rsp)
  movupd 0x60(%rdx),%xmm1
  mulpd  %xmm0,%xmm2
  mulpd  %xmm0,%xmm1
  cvttpd2dq %xmm2,%xmm2
  cvttpd2dq %xmm1,%xmm1
  punpcklqdq %xmm2,%xmm1
  movupd 0x90(%rdx),%xmm2
  movaps %xmm1,0xb0(%rsp)
  movupd 0x80(%rdx),%xmm1
  mulpd  %xmm0,%xmm2
  mulpd  %xmm0,%xmm1
  cvttpd2dq %xmm2,%xmm2
  cvttpd2dq %xmm1,%xmm1
  punpcklqdq %xmm2,%xmm1
  movupd 0xb0(%rdx),%xmm2
  movaps %xmm1,0xc0(%rsp)
  movupd 0xa0(%rdx),%xmm1
  mulpd  %xmm0,%xmm2
  mulpd  %xmm0,%xmm1
  cvttpd2dq %xmm2,%xmm2
  cvttpd2dq %xmm1,%xmm1
  punpcklqdq %xmm2,%xmm1
  movupd 0xd0(%rdx),%xmm2
  movaps %xmm1,0xd0(%rsp)
  movupd 0xc0(%rdx),%xmm1
  mulpd  %xmm0,%xmm2
  mulpd  %xmm0,%xmm1
  cvttpd2dq %xmm2,%xmm2
  cvttpd2dq %xmm1,%xmm1
  punpcklqdq %xmm2,%xmm1
  movupd 0xf0(%rdx),%xmm2
  movaps %xmm1,0xe0(%rsp)
  movupd 0xe0(%rdx),%xmm1
  mov    %rsp,%rdx
  mulpd  %xmm0,%xmm2
  mulpd  %xmm0,%xmm1
  cvttpd2dq %xmm1,%xmm0
  cvttpd2dq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,0xf0(%rsp)
  call   <dct64_1_486@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x118,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: f64[2]

tool: {"D9": [32768.0,32768.0]}

assistant: ```c
void dct64_486(int *a, int *b, double *samples) {
  int bufs[64];
  int i;
  for (i = 0; i < 32; i++) {
    bufs[i + 32] = ((int)((samples[i]) * 32768.0));
  }
  dct64_1_486(a, b, bufs, bufs + 0x20);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L19
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
L19:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <listDir@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L18:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: ERROR: you must supply a directory!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("ERROR: you must supply a directory!\n");
    exit(1);
  } else {
    listDir(argv[1]);
    exit(0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L12
  mov    0x8(%rsi),%rdi
  call   <listDir@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L10:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L12:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: ERROR: you must supply a directory!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("ERROR: you must supply a directory!\n");
    exit(1);
  } else {
    listDir(argv[1]);
    exit(0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L17
  mov    0x8(%rsi),%rdi
  call   <listDir@plt>
  xor    %edi,%edi
  call   <exit@plt>
L19:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L17:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L19
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: ERROR: you must supply a directory!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("ERROR: you must supply a directory!\n");
    exit(1);
  } else {
    listDir(argv[1]);
    exit(0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L6
  mov    0x8(%rsi),%rdi
  call   <listDir@plt>
  xor    %edi,%edi
  call   <exit@plt>
L16:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L16
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D9: ERROR: you must supply a directory!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("ERROR: you must supply a directory!\n");
    exit(1);
  } else {
    listDir(argv[1]);
    exit(0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<udcReadDouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <udcMustRead@plt>
  cmpl   $0x0,-0x1c(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <byteSwapDouble@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
L6:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double udcReadDouble(struct udcFile *file, int isSwapped) {
  double val;
  udcMustRead(file, &val, sizeof(val));
  if (isSwapped)
    val = byteSwapDouble(val);
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<udcReadDouble>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x8,%edx
  call   <udcMustRead@plt>
  test   %ebx,%ebx
  jne    L25
L12:
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  ret
L25:
  movsd  (%rsp),%xmm0
  call   <byteSwapDouble@plt>
  movsd  %xmm0,(%rsp)
  jmp    L12
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double udcReadDouble(struct udcFile *file, int isSwapped) {
  double val;
  udcMustRead(file, &val, sizeof(val));
  if (isSwapped)
    val = byteSwapDouble(val);
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<udcReadDouble>:
  endbr64
  push   %rbx
  mov    $0x8,%edx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <udcMustRead@plt>
  movsd  (%rsp),%xmm0
  test   %ebx,%ebx
  jne    L6
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  call   <byteSwapDouble@plt>
  jmp    L7
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double udcReadDouble(struct udcFile *file, int isSwapped) {
  double val;
  udcMustRead(file, &val, sizeof(val));
  if (isSwapped)
    val = byteSwapDouble(val);
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<udcReadDouble>:
  endbr64
  push   %rbx
  mov    $0x8,%edx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <udcMustRead@plt>
  movsd  (%rsp),%xmm0
  test   %ebx,%ebx
  jne    L23
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  call   <byteSwapDouble@plt>
  jmp    L27
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double udcReadDouble(struct udcFile *file, int isSwapped) {
  double val;
  udcMustRead(file, &val, sizeof(val));
  if (isSwapped)
    val = byteSwapDouble(val);
  return val;
}
```