ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  lea    D58(%rip),%r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
L60:
  lea    D61(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L57:
  xor    %eax,%eax
  call   <get_menu_choice@plt>
  cmp    $0x1,%eax
  je     L47
L56:
  cmp    $0x2,%eax
  je     L77
  cmp    $0x3,%eax
  je     L79
  cmp    $0x4,%eax
  jne    L57
  mov    0x14(%rsp),%edx
  movss  0x10(%rsp),%xmm0
  lea    D49(%rip),%rdi
  mov    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L77:
  mov    %r13,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <get_menu_choice@plt>
  cmp    $0x1,%eax
  jne    L56
L47:
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  jmp    L57
  nop
L79:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  jmp    L60
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
type_guessed: string
name: retrieve_data
arguments: data_label: D58
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D61
type_guessed: string
name: retrieve_data
arguments: data_label: D49
type_guessed: string
name: retrieve_data
arguments: data_label: D43
type_guessed: string
name: retrieve_data
arguments: data_label: D18
type_guessed: string

tool: D25: 
Enter a decimal floating-point number                  (e.g. 1.23)

tool: D58: %f

tool: D15: 
Enter a signed decimal integer (i.e. -123)

tool: D61: %d

tool: D49: 
Your values are: int: %d  float: %f  unsigned: %u 


tool: D43: 
Enter an unsigned decimal integer                  (e.g. 123)

tool: D18: %u

assistant: ```c
int main(int argc, char *argv[]) {
  int choice = 0;
  int int_var = 0;
  float float_var = 0.0;
  unsigned unsigned_var = 0;
  while (choice != 4) {
    choice = get_menu_choice();
    if (choice == 1) {
      puts("\nEnter a signed decimal integer (i.e. -123)");
      scanf("%d", &int_var);
    }
    if (choice == 2) {
      puts("\nEnter a decimal floating-point number                  (e.g. 1.23)");
      scanf("%f", &float_var);
    }
    if (choice == 3) {
      puts("\nEnter an unsigned decimal integer                  (e.g. 123)");
      scanf("%u", &unsigned_var);
    }
  }
  printf("\nYour values are: int: %d  float: %f  unsigned: %u \n", int_var, float_var, unsigned_var);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <end@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(const char *str) {
  perror(str);
  end();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x0,%eax
  call   <end@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void error(const char *str) {
  perror(str);
  end();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <end@plt>
```

assistant: ```c
void error(const char *str) {
  perror(str);
  end();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <end@plt>
```

assistant: ```c
void error(const char *str) {
  perror(str);
  end();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<next>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  xor    %edx,%eax
  xor    %ah,%al
  setnp  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sar    %eax
  mov    %eax,%esi
  mov    -0x1c(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t next(uint64_t lfsr, uint64_t mask, uint8_t shift) {
  uint32_t bit;
  bit = __builtin_parity(lfsr & mask);
  lfsr = (lfsr >> 1) | (bit << shift);
  return lfsr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<next>:
  endbr64
  mov    %esi,%eax
  and    %edi,%eax
  mov    %eax,%ecx
  shr    $0x10,%ecx
  xor    %ecx,%eax
  xor    %ah,%al
  setnp  %al
  movzbl %al,%eax
  sar    %edi
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
uint64_t next(uint64_t lfsr, uint64_t mask, uint8_t shift) {
  uint32_t bit;
  bit = __builtin_parity(lfsr & mask);
  lfsr = (lfsr >> 1) | (bit << shift);
  return lfsr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<next>:
  endbr64
  mov    %esi,%eax
  and    %edi,%eax
  mov    %eax,%ecx
  shr    $0x10,%ecx
  xor    %ecx,%eax
  mov    %edx,%ecx
  xor    %ah,%al
  setnp  %al
  sar    %edi
  movzbl %al,%eax
  shl    %cl,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
uint64_t next(uint64_t lfsr, uint64_t mask, uint8_t shift) {
  uint32_t bit;
  bit = __builtin_parity(lfsr & mask);
  lfsr = (lfsr >> 1) | (bit << shift);
  return lfsr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<next>:
  endbr64
  mov    %esi,%eax
  and    %edi,%eax
  mov    %eax,%ecx
  shr    $0x10,%ecx
  xor    %ecx,%eax
  mov    %edx,%ecx
  xor    %ah,%al
  setnp  %al
  sar    %edi
  movzbl %al,%eax
  shl    %cl,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
uint64_t next(uint64_t lfsr, uint64_t mask, uint8_t shift) {
  uint32_t bit;
  bit = __builtin_parity(lfsr & mask);
  lfsr = (lfsr >> 1) | (bit << shift);
  return lfsr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L40
  lea    0x14(%rsp),%rbp
  mov    $0x1,%ebx
  lea    D51(%rip),%r13
  lea    D9(%rip),%r12
L87:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jge    L87
L40:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L26
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  lea    D55(%rip),%r13
L90:
  lea    0x10(%rsp),%rbp
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    0x0(%rbp,%rbx,4),%r12d
  mov    0xc(%rsp),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jge    L90
L94:
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D62(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L106
  lea    0x14(%rsp),%r12
  mov    $0x1,%r13d
  jmp    L111
L26:
  mov    $0x0,%r12d
  jmp    L94
L33:
  mov    $0x2a,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x0(%rbp)
  jge    L33
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    $0x4,%r12
  cmp    %r13d,0xc(%rsp)
  jl     L106
L111:
  mov    %r12,%rbp
  mov    $0x1,%ebx
  cmpl   $0x0,(%r12)
  jg     L33
  jmp    L19
L106:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type: string
name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D51
type: string
name: parse_data
arguments: data_tag: D25
type: string
name: parse_data
arguments: data_tag: D55
type: string
name: parse_data
arguments: data_tag: D62
type: string
name: parse_data
arguments: data_tag: D67
type: string

tool: D26: Kac sayi:

tool: D9: %d

tool: D51: Sayi girin: 

tool: D25: Girilen sayilar:

tool: D55: %d


tool: D62: Ortalama:%f


tool: D67: Bar graph:

assistant: ```c
int main() {
  int sayi_sayisi, i, j;
  int sayilar[100];
  int tmp = 0;
  float ortalama;
  printf("Kac sayi:");
  scanf("%d", &sayi_sayisi);
  for (i = 1; i <= sayi_sayisi; i++) {
    printf("Sayi girin: ");
    scanf("%d", &sayilar[i]);
  }
  printf("Girilen sayilar:\n");
  for (i = 1; i <= sayi_sayisi; i++) {
    printf("%d\n", sayilar[i]);
    tmp += sayilar[i];
  }
  ortalama = (float)tmp / sayi_sayisi;
  printf("Ortalama:%f\n", ortalama);
  printf("Bar graph:\n");
  for (i = 1; i <= sayi_sayisi; i++) {
    for (j = 1; j <= sayilar[i]; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hex_distanceBetween>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hexMagnitude@plt>
  leave
  ret
```

assistant: ```c
unsigned int hex_distanceBetween(signed int ax, signed int ay, signed int bx, signed int by) {
  signed int x = ax - bx, y = ay - by;
  return hexMagnitude(x, y);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex_distanceBetween>:
  endbr64
  sub    $0x8,%rsp
  sub    %ecx,%esi
  sub    %edx,%edi
  call   <hexMagnitude@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int hex_distanceBetween(signed int ax, signed int ay, signed int bx, signed int by) {
  signed int x = ax - bx, y = ay - by;
  return hexMagnitude(x, y);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hex_distanceBetween>:
  endbr64
  sub    %ecx,%esi
  sub    %edx,%edi
  jmp    1050 <hexMagnitude@plt>
```

assistant: ```c
unsigned int hex_distanceBetween(signed int ax, signed int ay, signed int bx, signed int by) {
  signed int x = ax - bx, y = ay - by;
  return hexMagnitude(x, y);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hex_distanceBetween>:
  endbr64
  sub    %ecx,%esi
  sub    %edx,%edi
  jmp    1050 <hexMagnitude@plt>
```

assistant: ```c
unsigned int hex_distanceBetween(signed int ax, signed int ay, signed int bx, signed int by) {
  signed int x = ax - bx, y = ay - by;
  return hexMagnitude(x, y);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<disunion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <fabs@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <fabs@plt>
  cmp    %rax,%rbx
  jle    L13
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L10
L13:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
L10:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void disunion(long long int nfs[], long long int r1, long long int r2) {
  if (fabs(nfs[r1]) > fabs(nfs[r2])) {
    nfs[r2] = nfs[r1] + nfs[r2];
    nfs[r1] = r2;
  } else {
    nfs[r1] = nfs[r1] + nfs[r2];
    nfs[r2] = r1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<disunion>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  lea    (%rdi,%rsi,8),%r13
  mov    0x0(%r13),%rdi
  call   <fabs@plt>
  mov    %rax,%r14
  lea    (%rbx,%r12,8),%rbx
  mov    (%rbx),%rdi
  call   <fabs@plt>
  cmp    %rax,%r14
  jle    L4
  mov    0x0(%r13),%rax
  add    %rax,(%rbx)
  mov    %r12,0x0(%r13)
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    (%rbx),%rax
  add    %rax,0x0(%r13)
  mov    %rbp,(%rbx)
  jmp    L13
```

assistant: ```c
void disunion(long long int nfs[], long long int r1, long long int r2) {
  if (fabs(nfs[r1]) > fabs(nfs[r2])) {
    nfs[r2] = nfs[r1] + nfs[r2];
    nfs[r1] = r2;
  } else {
    nfs[r1] = nfs[r1] + nfs[r2];
    nfs[r2] = r1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<disunion>:
  endbr64
  push   %r14
  push   %r13
  lea    (%rdi,%rsi,8),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    0x0(%r13),%rdi
  lea    (%rbx,%r12,8),%rbx
  call   <fabs@plt>
  mov    (%rbx),%rdi
  mov    %rax,%r14
  call   <fabs@plt>
  cmp    %rax,%r14
  jle    L5
  mov    0x0(%r13),%rax
  add    %rax,(%rbx)
  mov    %r12,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%rax
  add    %rax,0x0(%r13)
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void disunion(long long int nfs[], long long int r1, long long int r2) {
  if (fabs(nfs[r1]) > fabs(nfs[r2])) {
    nfs[r2] = nfs[r1] + nfs[r2];
    nfs[r1] = r2;
  } else {
    nfs[r1] = nfs[r1] + nfs[r2];
    nfs[r2] = r1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<disunion>:
  endbr64
  push   %r14
  push   %r13
  lea    (%rdi,%rsi,8),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    0x0(%r13),%rdi
  lea    (%rbx,%r12,8),%rbx
  call   <fabs@plt>
  mov    (%rbx),%rdi
  mov    %rax,%r14
  call   <fabs@plt>
  cmp    %rax,%r14
  jle    L7
  mov    0x0(%r13),%rax
  add    %rax,(%rbx)
  mov    %r12,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%rax
  add    %rax,0x0(%r13)
  mov    %rbp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void disunion(long long int nfs[], long long int r1, long long int r2) {
  if (fabs(nfs[r1]) > fabs(nfs[r2])) {
    nfs[r2] = nfs[r1] + nfs[r2];
    nfs[r1] = r2;
  } else {
    nfs[r1] = nfs[r1] + nfs[r2];
    nfs[r2] = r1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<personalIdentifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L8:
  mov    -0x4(%rbp),%eax
  add    $0x16,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x9,-0x4(%rbp)
  jle    L8
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int personalIdentifier(char fascn[40], char PI[10]) {
  int index;
  for (index = 0; index < 10; index++) {
    PI[index] = fascn[22 + index];
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<personalIdentifier>:
  endbr64
  mov    $0x0,%eax
L8:
  movzbl 0x16(%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L8
  mov    $0x0,%eax
  ret
```

assistant: ```c
int personalIdentifier(char fascn[40], char PI[10]) {
  int index;
  for (index = 0; index < 10; index++) {
    PI[index] = fascn[22 + index];
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<personalIdentifier>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzbl 0x16(%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L4
  xor    %eax,%eax
  ret
```

assistant: ```c
int personalIdentifier(char fascn[40], char PI[10]) {
  int index;
  for (index = 0; index < 10; index++) {
    PI[index] = fascn[22 + index];
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<personalIdentifier>:
  endbr64
  lea    0x17(%rdi),%rcx
  mov    %rsi,%rdx
  sub    %rcx,%rdx
  cmp    $0x6,%rdx
  jbe    L3
  mov    0x16(%rdi),%rdx
  xor    %eax,%eax
  mov    %rdx,(%rsi)
  movzbl 0x1e(%rdi),%edx
  mov    %dl,0x8(%rsi)
  movzbl 0x1f(%rdi),%edx
  mov    %dl,0x9(%rsi)
  ret
  nopl   0x0(%rax)
L3:
  movzbl 0x16(%rdi),%edx
  xor    %eax,%eax
  mov    %dl,(%rsi)
  movzbl 0x17(%rdi),%edx
  mov    %dl,0x1(%rsi)
  movzbl 0x18(%rdi),%edx
  mov    %dl,0x2(%rsi)
  movzbl 0x19(%rdi),%edx
  mov    %dl,0x3(%rsi)
  movzbl 0x1a(%rdi),%edx
  mov    %dl,0x4(%rsi)
  movzbl 0x1b(%rdi),%edx
  mov    %dl,0x5(%rsi)
  movzbl 0x1c(%rdi),%edx
  mov    %dl,0x6(%rsi)
  movzbl 0x1d(%rdi),%edx
  mov    %dl,0x7(%rsi)
  movzbl 0x1e(%rdi),%edx
  mov    %dl,0x8(%rsi)
  movzbl 0x1f(%rdi),%edx
  mov    %dl,0x9(%rsi)
  ret
```

assistant: ```c
int personalIdentifier(char fascn[40], char PI[10]) {
  int index;
  for (index = 0; index < 10; index++) {
    PI[index] = fascn[22 + index];
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_texture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L15:
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L31:
  mov    -0x10(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x3,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  and    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L31
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L15
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
GLfloat *make_texture(int maxs, int maxt) {
  int s, t;
  GLfloat *texture;
  texture = (GLfloat *)malloc(maxs * maxt * sizeof(GLfloat));
  for (t = 0; t < maxt; t++) {
    for (s = 0; s < maxs; s++) {
      texture[s + maxs * t] = ((s >> 3) & 0x1) ^ ((t >> 3) & 0x1);
    }
  }
  return texture;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<make_texture>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  imul   %esi,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L13
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  jmp    L17
L12:
  mov    %r8d,%edi
  sar    $0x3,%edi
  movslq %r9d,%rdx
  lea    (%rax,%rdx,4),%rsi
  mov    $0x0,%ecx
L39:
  mov    %ecx,%edx
  sar    $0x3,%edx
  xor    %edi,%edx
  and    $0x1,%edx
  mov    %edx,(%rsi)
  add    $0x1,%ecx
  add    $0x4,%rsi
  cmp    %ecx,%ebx
  jne    L39
L44:
  add    $0x1,%r8d
  add    %ebx,%r9d
  cmp    %r8d,%ebp
  je     L13
L17:
  test   %ebx,%ebx
  jg     L12
  jmp    L44
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
GLfloat *make_texture(int maxs, int maxt) {
  int s, t;
  GLfloat *texture;
  texture = (GLfloat *)malloc(maxs * maxt * sizeof(GLfloat));
  for (t = 0; t < maxt; t++) {
    for (s = 0; s < maxs; s++) {
      texture[s + maxs * t] = ((s >> 3) & 0x1) ^ ((t >> 3) & 0x1);
    }
  }
  return texture;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<make_texture>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  imul   %esi,%edi
  sub    $0x8,%rsp
  shl    $0x2,%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L17
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L11:
  test   %ebx,%ebx
  jle    L22
  mov    %r8d,%edi
  movslq %r9d,%rdx
  xor    %ecx,%ecx
  sar    $0x3,%edi
  lea    (%rax,%rdx,4),%rsi
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ecx,%edx
  add    $0x1,%ecx
  add    $0x4,%rsi
  sar    $0x3,%edx
  xor    %edi,%edx
  and    $0x1,%edx
  mov    %edx,-0x4(%rsi)
  cmp    %ecx,%ebx
  jne    L1
L22:
  add    $0x1,%r8d
  add    %ebx,%r9d
  cmp    %r8d,%ebp
  jne    L11
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
GLfloat *make_texture(int maxs, int maxt) {
  int s, t;
  GLfloat *texture;
  texture = (GLfloat *)malloc(maxs * maxt * sizeof(GLfloat));
  for (t = 0; t < maxt; t++) {
    for (s = 0; s < maxs; s++) {
      texture[s + maxs * t] = ((s >> 3) & 0x1) ^ ((t >> 3) & 0x1);
    }
  }
  return texture;
}
```