ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x4,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  movl   $0x6,0x28(%rsp)
  movl   $0x7,0x2c(%rsp)
  movl   $0x8,0x30(%rsp)
  movl   $0x8,0x34(%rsp)
  movl   $0xa,0x38(%rsp)
  movl   $0xa,0x3c(%rsp)
  movl   $0xb,0x40(%rsp)
  movl   $0xc,0x44(%rsp)
  movl   $0x10,0x48(%rsp)
  lea    D59(%rip),%rsi
  lea    D61(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D36(%rip),%r12
  lea    D51(%rip),%rbp
L26:
  mov    -0x4(%rsp,%rbx,4),%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%rbx
  cmp    $0x13,%rbx
  jne    L26
  cltq
  mov    (%rsp,%rax,4),%esi
  lea    D60(%rip),%rdx
  lea    D51(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D25(%rip),%rbp
L13:
  mov    %rsp,%rdi
  mov    %ebx,%edx
  mov    $0x13,%esi
  call   <firstOccurrence@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L13
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D59
type: string
name: retrieve_data
arguments: data_tag: D61
type: string
name: retrieve_data
arguments: data_tag: D36
type: string
name: retrieve_data
arguments: data_tag: D51
type: string
name: retrieve_data
arguments: data_tag: D60
type: string
name: retrieve_data
arguments: data_tag: D25
type: string

tool: D59: Array [

tool: D61: %s

tool: D36: , 

tool: D51: %d%s

tool: D60: ]


tool: D25: %d found at %d


assistant: ```c
int main(int argc, char **argv) {
  int nums[] = {1, 1, 1, 2, 2, 2, 2, 3, 4, 5, 6, 7, 8, 8, 10, 10, 11, 12, 16};
  int length = sizeof(nums) / sizeof(int);
  int i, k;
  printf("%s", "Array [");
  for (i = 0; i < length; i++) {
    printf("%d%s", nums[i], i != length - 1 ? ", " : "]\n");
  }
  for (k = 0; k < 20; k++) {
    printf("%d found at %d\n", k, firstOccurrence(nums, length, k));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  lea    D41(%rip),%rsi
  lea    D57(%rip),%rdi
  push   %r13
  lea    D20(%rip),%r14
  lea    D28(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x100000001,%rax
  mov    %rsp,%rbp
  movl   $0x10,0x48(%rsp)
  mov    %rax,(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x8(%rsp)
  add    $0x1,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x800000008,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xa0000000a,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xc0000000b,%rax
  mov    %rax,0x40(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  nopl   (%rax)
L19:
  cmp    $0x12,%rbx
  mov    %r12,%rdx
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r14,%rdi
  cmove  %r13,%rdx
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x13,%rbx
  jne    L19
  xor    %ebx,%ebx
  lea    D43(%rip),%r12
  nopl   0x0(%rax)
L7:
  mov    %ebx,%edx
  mov    $0x13,%esi
  mov    %rbp,%rdi
  call   <firstOccurrence@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x14,%ebx
  jne    L7
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D41
type: string
name: parse_data
arguments: data_tag: D57
type: string
name: parse_data
arguments: data_tag: D20
type: string
name: parse_data
arguments: data_tag: D28
type: string
name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D43
type: string

tool: D41: Array [

tool: D57: %s

tool: D20: %d%s

tool: D28: ]


tool: D15: , 

tool: D43: %d found at %d


assistant: ```c
int main(int argc, char **argv) {
  int nums[] = {1, 1, 1, 2, 2, 2, 2, 3, 4, 5, 6, 7, 8, 8, 10, 10, 11, 12, 16};
  int length = sizeof(nums) / sizeof(int);
  int i, k;
  printf("%s", "Array [");
  for (i = 0; i < length; i++) {
    printf("%d%s", nums[i], i != length - 1 ? ", " : "]\n");
  }
  for (k = 0; k < 20; k++) {
    printf("%d found at %d\n", k, firstOccurrence(nums, length, k));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L0
L13:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L8:
  addl   $0x1,-0x10(%rbp)
L0:
  cmpl   $0x6,-0xc(%rbp)
  jle    L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string
name: disassemble_data
arguments: label: D5
type_infered: string

tool: D8: %d

tool: D5: %d


assistant: ```c
int main(void) {
  int contador, i = 1, valor;
  scanf("%d", &valor);
  contador = valor;
  while (i <= 6) {
    if (contador % 2 != 0) {
      printf("%d\n", contador);
      i++;
    }
    contador++;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  mov    $0x1,%ebp
  lea    D13(%rip),%r12
  jmp    L3
L34:
  add    $0x1,%ebx
  cmp    $0x6,%ebp
  jg     L32
L3:
  test   $0x1,%bl
  je     L34
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  jmp    L34
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D3: %d

tool: D13: %d


assistant: ```c
int main(void) {
  int contador, i = 1, valor;
  scanf("%d", &valor);
  contador = valor;
  while (i <= 6) {
    if (contador % 2 != 0) {
      printf("%d\n", contador);
      i++;
    }
    contador++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  lea    D7(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  jmp    L39
  nop
L37:
  add    $0x1,%ebx
  cmp    $0x7,%ebp
  je     L26
L39:
  test   $0x1,%bl
  je     L37
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebp
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7,%ebp
  jne    L39
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D5: %d

tool: D7: %d


assistant: ```c
int main(void) {
  int contador, i = 1, valor;
  scanf("%d", &valor);
  contador = valor;
  while (i <= 6) {
    if (contador % 2 != 0) {
      printf("%d\n", contador);
      i++;
    }
    contador++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  lea    D11(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  nopl   (%rax)
L4:
  test   $0x1,%bl
  jne    L11
  add    $0x1,%ebx
  cmp    $0x7,%ebp
  jne    L4
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebp
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7,%ebp
  jne    L4
  jmp    L38
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string

tool: D16: %d

tool: D11: %d


assistant: ```c
int main(void) {
  int contador, i = 1, valor;
  scanf("%d", &valor);
  contador = valor;
  while (i <= 6) {
    if (contador % 2 != 0) {
      printf("%d\n", contador);
      i++;
    }
    contador++;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_220_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_220_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = T & stk3;
  stk1 = S | stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_220_0_1>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%ecx
  movzbl (%rdi),%r8d
  mov    %r8d,%esi
  not    %esi
  and    %edx,%esi
  or     %eax,%esi
  not    %edx
  and    %edx,%esi
  mov    %eax,%edx
  not    %edx
  and    %ecx,%edx
  and    %r8d,%edx
  or     %eax,%edx
  or     %edx,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_220_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = T & stk3;
  stk1 = S | stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_220_0_1>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %esi,%eax
  mov    %edx,%ecx
  mov    %r8d,%esi
  not    %esi
  and    %edx,%esi
  not    %edx
  or     %eax,%esi
  and    %edx,%esi
  mov    %eax,%edx
  not    %edx
  and    %ecx,%edx
  and    %r8d,%edx
  or     %eax,%edx
  or     %edx,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_220_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = T & stk3;
  stk1 = S | stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rop3_220_0_1>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %esi,%eax
  mov    %edx,%ecx
  mov    %r8d,%esi
  not    %esi
  and    %edx,%esi
  not    %edx
  or     %eax,%esi
  and    %edx,%esi
  mov    %eax,%edx
  not    %edx
  and    %ecx,%edx
  and    %r8d,%edx
  or     %eax,%edx
  or     %edx,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_220_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = T & stk3;
  stk1 = S | stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int puts(const char *s) {
  __puts(s);
  putchar('\n');
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<puts>:
  endbr64
  sub    $0x8,%rsp
  call   <__puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int puts(const char *s) {
  __puts(s);
  putchar('\n');
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<puts>:
  endbr64
  sub    $0x8,%rsp
  call   <__puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int puts(const char *s) {
  __puts(s);
  putchar('\n');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<puts>:
  endbr64
  sub    $0x8,%rsp
  call   <__puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int puts(const char *s) {
  __puts(s);
  putchar('\n');
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L13:
  cmpl   $0x20,-0x4(%rbp)
  jne    L2
  movl   $0x1,-0x8(%rbp)
  jmp    L3
L2:
  cmpl   $0x1,-0x8(%rbp)
  jne    L1
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L13
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c;
  int state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ')
      state = 1;
    else if (state == 1) {
      putchar(' ');
      putchar(c);
      state = 0;
    } else
      putchar(c);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%r12d
L48:
  mov    $0x0,%ebp
L59:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D1(%rip),%rax
  cmp    %ebx,(%rax)
  je     L15
  cmp    $0x20,%ebx
  jne    L44
  mov    %r12d,%ebp
  jmp    L59
L44:
  cmp    $0x1,%ebp
  je     L19
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L48
L19:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L48
L15:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int c;
  int state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ')
      state = 1;
    else if (state == 1) {
      putchar(' ');
      putchar(c);
      state = 0;
    } else
      putchar(c);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    D2(%rip),%rbx
L15:
  xor    %r12d,%r12d
  jmp    L28
  nopl   0x0(%rax)
L55:
  cmp    $0x20,%ebp
  jne    L24
  mov    $0x1,%r12d
L28:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%rbx)
  jne    L55
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  cmp    $0x1,%r12d
  je     L40
  mov    %ebp,%edi
  call   <putchar@plt>
  jmp    L15
L40:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %ebp,%edi
  call   <putchar@plt>
  jmp    L15
```

assistant: ```c
int main() {
  int c;
  int state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ')
      state = 1;
    else if (state == 1) {
      putchar(' ');
      putchar(c);
      state = 0;
    } else
      putchar(c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    D4(%rip),%rbx
L56:
  xor    %r12d,%r12d
  jmp    L59
  nopl   0x0(%rax)
L3:
  cmp    $0x20,%ebp
  jne    L7
  mov    $0x1,%r12d
L59:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%rbx)
  jne    L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  cmp    $0x1,%r12d
  je     L4
  mov    %ebp,%edi
  call   <putchar@plt>
  jmp    L56
L4:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %ebp,%edi
  call   <putchar@plt>
  jmp    L56
```

assistant: ```c
int main() {
  int c;
  int state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ')
      state = 1;
    else if (state == 1) {
      putchar(' ');
      putchar(c);
      state = 0;
    } else
      putchar(c);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x28(%rbp),%xmm1
  movsd  D39(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movd   %xmm0,%ebx
  mov    D77(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movaps %xmm0,%xmm1
  movd   %ebx,%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x24(%rbp),%xmm1
  movsd  D53(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L50
  pxor   %xmm0,%xmm0
  jmp    L44
L50:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x24(%rbp),%xmm0
  comisd D12(%rip),%xmm0
  jbe    L13
  movss  D4(%rip),%xmm0
  jmp    L44
L13:
  movss  D11(%rip),%xmm0
  comiss -0x24(%rbp),%xmm0
  jbe    L1
  movss  -0x24(%rbp),%xmm0
  addss  %xmm0,%xmm0
  cvttss2si %xmm0,%eax
  mov    -0x14(%rbp),%edx
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  jmp    L44
L1:
  pxor   %xmm1,%xmm1
  cvtss2sd -0x24(%rbp),%xmm1
  movsd  D39(%rip),%xmm0
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%eax
  mov    -0x14(%rbp),%edx
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D39(%rip),%xmm0
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
L44:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D39
data_type: f64
name: unpack_data
arguments: data_label: D77
data_type: f64
name: unpack_data
arguments: data_label: D53
data_type: byte[8]
name: unpack_data
arguments: data_label: D12
data_type: byte[16]
name: unpack_data
arguments: data_label: D4
data_type: byte[4]
name: unpack_data
arguments: data_label: D11
data_type: byte[4]

tool: D39: 1

tool: D77: 0.5

tool: {"D53": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: {"D12": [0x2b,0x87,0x16,0xd9,0xce,0xf7,0xef,0x3f,0x00,0x00,0x80,0x3f,0x00,0x00,0x00,0x3f]}

tool: {"D4": [0x00,0x00,0x80,0x3f]}

tool: {"D11": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float gain(float a, float b) {
  float p = log(1. - b) / log(0.5);
  if (a < .001)
    return 0.;
  else if (a > .999)
    return 1.;
  if (a < 0.5)
    return pow(2 * a, p) / 2;
  else
    return 1. - pow(2 * (1. - a), p) / 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<extract_quarter_2_epi16_sse2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpacklo_epi32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_unpackhi_epi64@plt>
  leave
  ret
```

assistant: ```c
__m128i extract_quarter_2_epi16_sse2(const __m128i *const reg) {
  __m128i tmp = _mm_unpacklo_epi32(*reg, *reg);
  return _mm_unpackhi_epi64(tmp, tmp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<extract_quarter_2_epi16_sse2>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  mov    %edi,%esi
  call   <_mm_unpacklo_epi32@plt>
  mov    %eax,%edi
  mov    %eax,%esi
  call   <_mm_unpackhi_epi64@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
__m128i extract_quarter_2_epi16_sse2(const __m128i *const reg) {
  __m128i tmp = _mm_unpacklo_epi32(*reg, *reg);
  return _mm_unpackhi_epi64(tmp, tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<extract_quarter_2_epi16_sse2>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  mov    %edi,%esi
  call   <_mm_unpacklo_epi32@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  mov    %eax,%esi
  jmp    1070 <_mm_unpackhi_epi64@plt>
```

assistant: ```c
__m128i extract_quarter_2_epi16_sse2(const __m128i *const reg) {
  __m128i tmp = _mm_unpacklo_epi32(*reg, *reg);
  return _mm_unpackhi_epi64(tmp, tmp);
}
```
user: What is the c source code of the assembly code below:

```asm
<extract_quarter_2_epi16_sse2>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  mov    %edi,%esi
  call   <_mm_unpacklo_epi32@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  mov    %eax,%esi
  jmp    1070 <_mm_unpackhi_epi64@plt>
```

assistant: ```c
__m128i extract_quarter_2_epi16_sse2(const __m128i *const reg) {
  __m128i tmp = _mm_unpacklo_epi32(*reg, *reg);
  return _mm_unpackhi_epi64(tmp, tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<setsampling0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  movsd  %xmm2,-0x50(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L86
  movl   $0x0,-0x18(%rbp)
  jmp    L42
L11:
  mov    -0x18(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L11
  jmp    L76
L86:
  movsd  -0x50(%rbp),%xmm0
  mulsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L67
L78:
  movsd  D0(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L29
  mov    $0x1,%eax
  jmp    L5
L29:
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
L5:
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L89
L31:
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L89:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jb     L31
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L67:
  mov    -0x14(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jb     L78
L76:
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void setsampling0(unsigned int *DownSmpl, unsigned int S, int continuous, unsigned int V, unsigned int J, double b0, double a0, double s0) {
  double da1;
  unsigned int s, j, v, ua1;
  if (continuous)
    for (s = 0; s < S; s++)
      DownSmpl[s] = 1;
  else {
    da1 = s0 * b0;
    for (j = 0; j < J; j++) {
      ua1 = (da1 < 1) ? 1 : (unsigned int)da1;
      for (v = 0; v < V; v++)
        *DownSmpl++ = ua1;
      da1 *= a0;
    }
  }
}
```