user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x3fffc,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L34
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L34:
  mov    -0x10(%rbp),%rax
  mov    $0x3fffc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movq   $0x1,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
L60:
  addl   $0x1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  cmpl   $0x17,-0x20(%rbp)
  jg     L41
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
L41:
  cmpl   $0x18,-0x20(%rbp)
  jne    L33
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L33:
  movl   $0x0,-0x1c(%rbp)
  jmp    L80
L90:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <lfsr_calculate@plt>
  addl   $0x1,-0x1c(%rbp)
L80:
  cmpl   $0x1f,-0x1c(%rbp)
  jle    L90
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L60
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0xffff,-0x20(%rbp)
  jne    L53
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L72
L53:
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L72:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D42
type_guessed: string
name: retrieve_data
arguments: data_tag: D50
type_guessed: string
name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D38
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D48
type_guessed: string

tool: D42: Memory allocation failed!

tool: D50: My number is: %u


tool: D25:  ... etc etc ... 

tool: D38: Got %u numbers before cycling!


tool: D12: Congratulations! It works!

tool: D48: Did I miss something?

assistant: ```c
int main() {
  int8_t *numbers = (int8_t *)malloc(sizeof(int8_t) * 65535);
  if (numbers == NULL) {
    printf("Memory allocation failed!");
    exit(1);
  }
  memset(numbers, 0, sizeof(int8_t) * 65535);
  uint16_t reg = 0x1;
  uint32_t count = 0;
  int i;
  do {
    count++;
    numbers[reg] = 1;
    if (count < 24) {
      printf("My number is: %u\n", reg);
    } else if (count == 24) {
      printf(" ... etc etc ... \n");
    }
    for (i = 0; i < 32; i++)
      lfsr_calculate(&reg);
  } while (numbers[reg] != 1);
  printf("Got %u numbers before cycling!\n", count);
  if (count == 65535) {
    printf("Congratulations! It works!\n");
  } else {
    printf("Did I miss something?\n");
  }
  free(numbers);
  return 0;
}
```