ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%r15
  test   %r15,%r15
  je     L74
  mov    %rsi,%rbp
  mov    $0x0,%r12d
  cmpb   $0x2d,(%r15)
  je     L49
L54:
  add    $0x10,%rbp
  lea    D31(%rip),%r13
  lea    D41(%rip),%r14
  jmp    L80
L49:
  lea    D6(%rip),%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L40
  add    $0x8,%rbp
  mov    $0x1,%r12d
L17:
  mov    0x8(%rbp),%r15
  mov    $0x0,%eax
  test   %r15,%r15
  jne    L54
  jmp    L120
L40:
  lea    D45(%rip),%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L47
  mov    $0x0,%r12d
  jmp    L54
L47:
  lea    D40(%rip),%rdi
  call   <puts@plt>
  jmp    L17
L71:
  add    $0x8,%rbp
  mov    -0x8(%rbp),%r15
  test   %r15,%r15
  je     L88
L80:
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %r15,%rdi
  call   <fnv_hash@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  je     L71
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x19,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x7f,%esi
  sub    %eax,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L71
L88:
  mov    $0x0,%eax
L120:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  mov    $0x1,%eax
  jmp    L120
```

tool_calls: name: disassemble_data
arguments: label: D31
type_guessed: string
name: disassemble_data
arguments: label: D41
type_guessed: string
name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D45
type_guessed: string
name: disassemble_data
arguments: label: D40
type_guessed: string

tool: D31: %#0lx 

tool: D41: bucket number %d/128


tool: D6: -i

tool: D45: -h

tool: D40: fnv_hash -ih [string]*
-i = interactive, print extra information

assistant: ```c
int main(int argc, char *argv[]) {
  int interactive = 0;
  if (!argv[1]) {
    return 1;
  } else if (argv[1][0] == '-') {
    if (!(strcmp(argv[1], "-i"))) {
      interactive = 1;
      argv = argv + 1;
    } else if (!strcmp(argv[1], "-h")) {
      puts("fnv_hash -ih [string]*\n-i = interactive, print extra information");
    }
  }
  char *data = argv[1];
  int i = 1, len;
  uint64_t hashv;
  while (data) {
    len = strlen(data);
    hashv = fnv_hash(data, len);
    printf("%#0lx ", hashv);
    if (interactive) {
      puts(data);
      printf("bucket number %d/128\n", hashv % 128);
    }
    data = argv[++i];
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%r14
  test   %r14,%r14
  je     L124
  xor    %ebp,%ebp
  cmpb   $0x2d,(%r14)
  mov    %rsi,%r15
  je     L94
L48:
  add    $0x10,%r15
  lea    D32(%rip),%r12
  lea    D35(%rip),%r13
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L63:
  mov    (%r15),%r14
  add    $0x8,%r15
  test   %r14,%r14
  je     L79
L41:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <fnv_hash@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebx
  call   <printf@plt>
  test   %ebp,%ebp
  je     L63
  mov    %r14,%rdi
  add    $0x8,%r15
  call   <puts@plt>
  mov    %ebx,%eax
  mov    %r13,%rdi
  sar    $0x1f,%eax
  shr    $0x19,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x7f,%esi
  sub    %eax,%esi
  call   <printf@plt>
  mov    -0x8(%r15),%r14
  test   %r14,%r14
  jne    L41
L79:
  xor    %eax,%eax
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L94:
  lea    D48(%rip),%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L52
  add    $0x8,%r15
  mov    $0x1,%ebp
L0:
  mov    0x8(%r15),%r14
  test   %r14,%r14
  jne    L48
  jmp    L79
L52:
  lea    D11(%rip),%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L123
  xor    %ebp,%ebp
  jmp    L48
L124:
  mov    $0x1,%eax
  jmp    L43
L123:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: tag: D32
type: string
name: parse_data
arguments: tag: D35
type: string
name: parse_data
arguments: tag: D48
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D23
type: string

tool: D32: %#0lx 

tool: D35: bucket number %d/128


tool: D48: -i

tool: D11: -h

tool: D23: fnv_hash -ih [string]*
-i = interactive, print extra information

assistant: ```c
int main(int argc, char *argv[]) {
  int interactive = 0;
  if (!argv[1]) {
    return 1;
  } else if (argv[1][0] == '-') {
    if (!(strcmp(argv[1], "-i"))) {
      interactive = 1;
      argv = argv + 1;
    } else if (!strcmp(argv[1], "-h")) {
      puts("fnv_hash -ih [string]*\n-i = interactive, print extra information");
    }
  }
  char *data = argv[1];
  int i = 1, len;
  uint64_t hashv;
  while (data) {
    len = strlen(data);
    hashv = fnv_hash(data, len);
    printf("%#0lx ", hashv);
    if (interactive) {
      puts(data);
      printf("bucket number %d/128\n", hashv % 128);
    }
    data = argv[++i];
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%r12
  test   %r12,%r12
  je     L88
  cmpb   $0x2d,(%r12)
  mov    %rsi,%rbx
  je     L42
L106:
  add    $0x10,%rbx
  lea    D59(%rip),%rbp
  xchg   %ax,%ax
L61:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <fnv_hash@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    -0x8(%rbx),%r12
  test   %r12,%r12
  jne    L61
L49:
  xor    %eax,%eax
L93:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  lea    D32(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L34
  mov    0x10(%rbx),%r14
  test   %r14,%r14
  je     L49
  lea    0x18(%rbx),%r13
  lea    D59(%rip),%rbp
  lea    D50(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r14,%rdi
  add    $0x8,%r13
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <fnv_hash@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    %eax,%ebx
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %ebx,%eax
  mov    %r12,%rdi
  sar    $0x1f,%eax
  shr    $0x19,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x7f,%esi
  sub    %eax,%esi
  call   <printf@plt>
  mov    -0x8(%r13),%r14
  test   %r14,%r14
  jne    L16
  jmp    L49
L34:
  lea    D35(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L106
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rbx),%r12
  test   %r12,%r12
  jne    L106
  jmp    L49
L88:
  mov    $0x1,%eax
  jmp    L93
```

tool_calls: name: unpack_data
arguments: tag: D59
type: string
name: unpack_data
arguments: tag: D32
type: string
name: unpack_data
arguments: tag: D50
type: string
name: unpack_data
arguments: tag: D35
type: string
name: unpack_data
arguments: tag: D16
type: string

tool: D59: %#0lx 

tool: D32: -i

tool: D50: bucket number %d/128


tool: D35: -h

tool: D16: fnv_hash -ih [string]*
-i = interactive, print extra information

assistant: ```c
int main(int argc, char *argv[]) {
  int interactive = 0;
  if (!argv[1]) {
    return 1;
  } else if (argv[1][0] == '-') {
    if (!(strcmp(argv[1], "-i"))) {
      interactive = 1;
      argv = argv + 1;
    } else if (!strcmp(argv[1], "-h")) {
      puts("fnv_hash -ih [string]*\n-i = interactive, print extra information");
    }
  }
  char *data = argv[1];
  int i = 1, len;
  uint64_t hashv;
  while (data) {
    len = strlen(data);
    hashv = fnv_hash(data, len);
    printf("%#0lx ", hashv);
    if (interactive) {
      puts(data);
      printf("bucket number %d/128\n", hashv % 128);
    }
    data = argv[++i];
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0xffff,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    $0x10,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  shrl   %cl,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    $0x10,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  shll   %cl,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string

tool: D18: %d

assistant: ```c
void main() {
  int x = 10, a, b, n;
  unsigned c;
  scanf("%d", &n);
  a = x >> n;
  c = 0xffff;
  c = c >> (16 - n);
  b = x & c;
  b = b << (16 - n);
  printf("%d", a | b);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x10,%edx
  sub    0x4(%rsp),%edx
  mov    $0xffff,%eax
  mov    %edx,%ecx
  shr    %cl,%eax
  and    $0xa,%eax
  mov    $0xa,%esi
  movzbl 0x4(%rsp),%ecx
  sar    %cl,%esi
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string

tool: D6: %d

assistant: ```c
void main() {
  int x = 10, a, b, n;
  unsigned c;
  scanf("%d", &n);
  a = x >> n;
  c = 0xffff;
  c = c >> (16 - n);
  b = x & c;
  b = b << (16 - n);
  printf("%d", a | b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x10,%edx
  mov    $0xffff,%eax
  mov    $0xa,%esi
  sub    %edi,%edx
  mov    %edx,%ecx
  shr    %cl,%eax
  mov    %edi,%ecx
  mov    %rbp,%rdi
  sar    %cl,%esi
  and    $0xa,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string

tool: D9: %d

assistant: ```c
void main() {
  int x = 10, a, b, n;
  unsigned c;
  scanf("%d", &n);
  a = x >> n;
  c = 0xffff;
  c = c >> (16 - n);
  b = x & c;
  b = b << (16 - n);
  printf("%d", a | b);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x10,%edx
  mov    $0xffff,%eax
  mov    $0xa,%esi
  sub    %edi,%edx
  mov    %edx,%ecx
  shr    %cl,%eax
  mov    %edi,%ecx
  mov    %rbp,%rdi
  sar    %cl,%esi
  and    $0xa,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string

tool: D1: %d

assistant: ```c
void main() {
  int x = 10, a, b, n;
  unsigned c;
  scanf("%d", &n);
  a = x >> n;
  c = 0xffff;
  c = c >> (16 - n);
  b = x & c;
  b = b << (16 - n);
  printf("%d", a | b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<soar_ecPrintReteStatistics>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <print_node_count_statistics@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void soar_ecPrintReteStatistics(void) {
  print_node_count_statistics();
  {};
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<soar_ecPrintReteStatistics>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <print_node_count_statistics@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void soar_ecPrintReteStatistics(void) {
  print_node_count_statistics();
  {};
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<soar_ecPrintReteStatistics>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <print_node_count_statistics@plt>
```

assistant: ```c
void soar_ecPrintReteStatistics(void) {
  print_node_count_statistics();
  {};
}
```
user: Translate the below assembly code into C programming language:

```asm
<soar_ecPrintReteStatistics>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <print_node_count_statistics@plt>
```

assistant: ```c
void soar_ecPrintReteStatistics(void) {
  print_node_count_statistics();
  {};
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_sip_dip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  xor    %edx,%eax
  mov    %ax,-0x10(%rbp)
  movzwl -0x10(%rbp),%eax
  mov    %ax,-0xe(%rbp)
  movzwl -0x10(%rbp),%eax
  mov    %ax,-0xc(%rbp)
  movzwl -0xe(%rbp),%eax
  xor    -0xc(%rbp),%ax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  and    $0xf000,%ax
  mov    %ax,-0x8(%rbp)
  movzwl -0xa(%rbp),%eax
  and    $0xf00,%ax
  mov    %ax,-0x6(%rbp)
  movzwl -0x8(%rbp),%eax
  xor    -0x6(%rbp),%ax
  mov    %ax,-0x4(%rbp)
  movzwl -0xa(%rbp),%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%edx
  movzwl -0x4(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  shr    $0x2,%ax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short hash_sip_dip(unsigned int sip, unsigned int dip) {
  unsigned short ht = dip ^ sip;
  unsigned short ht_l16 = (ht & 0xFFFF0000 >> 16);
  unsigned short ht_h16 = (ht & 0xFFFF);
  unsigned short ht16 = ht_l16 ^ ht_h16;
  unsigned short ht16_h4 = (ht16 & 0xF000);
  unsigned short ht16_m4 = (ht16 & 0x0F00);
  unsigned short ht4 = ht16_h4 ^ ht16_m4;
  unsigned char ht_l8 = ht16 & 0xFF;
  unsigned short ht12 = ht_l8 | (ht4 << 8);
  return ht12 >> 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash_sip_dip>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned short hash_sip_dip(unsigned int sip, unsigned int dip) {
  unsigned short ht = dip ^ sip;
  unsigned short ht_l16 = (ht & 0xFFFF0000 >> 16);
  unsigned short ht_h16 = (ht & 0xFFFF);
  unsigned short ht16 = ht_l16 ^ ht_h16;
  unsigned short ht16_h4 = (ht16 & 0xF000);
  unsigned short ht16_m4 = (ht16 & 0x0F00);
  unsigned short ht4 = ht16_h4 ^ ht16_m4;
  unsigned char ht_l8 = ht16 & 0xFF;
  unsigned short ht12 = ht_l8 | (ht4 << 8);
  return ht12 >> 2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash_sip_dip>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned short hash_sip_dip(unsigned int sip, unsigned int dip) {
  unsigned short ht = dip ^ sip;
  unsigned short ht_l16 = (ht & 0xFFFF0000 >> 16);
  unsigned short ht_h16 = (ht & 0xFFFF);
  unsigned short ht16 = ht_l16 ^ ht_h16;
  unsigned short ht16_h4 = (ht16 & 0xF000);
  unsigned short ht16_m4 = (ht16 & 0x0F00);
  unsigned short ht4 = ht16_h4 ^ ht16_m4;
  unsigned char ht_l8 = ht16 & 0xFF;
  unsigned short ht12 = ht_l8 | (ht4 << 8);
  return ht12 >> 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash_sip_dip>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned short hash_sip_dip(unsigned int sip, unsigned int dip) {
  unsigned short ht = dip ^ sip;
  unsigned short ht_l16 = (ht & 0xFFFF0000 >> 16);
  unsigned short ht_h16 = (ht & 0xFFFF);
  unsigned short ht16 = ht_l16 ^ ht_h16;
  unsigned short ht16_h4 = (ht16 & 0xF000);
  unsigned short ht16_m4 = (ht16 & 0x0F00);
  unsigned short ht4 = ht16_h4 ^ ht16_m4;
  unsigned char ht_l8 = ht16 & 0xFF;
  unsigned short ht12 = ht_l8 | (ht4 << 8);
  return ht12 >> 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<to_millis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long to_millis(struct timeval tv) {
  long ret = 0;
  ret += tv.tv_sec * 1000;
  ret += tv.tv_usec / 1000;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<to_millis>:
  endbr64
  imul   $0x3e8,%edi,%eax
  cltq
  mov    %rdi,%rcx
  sar    $0x20,%rcx
  imul   $0x10624dd3,%rcx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  ret
```

assistant: ```c
long to_millis(struct timeval tv) {
  long ret = 0;
  ret += tv.tv_sec * 1000;
  ret += tv.tv_usec / 1000;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_millis>:
  endbr64
  mov    %rdi,%rdx
  imul   $0x3e8,%edi,%eax
  sar    $0x3f,%rdi
  sar    $0x20,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  cltq
  sar    $0x26,%rdx
  sub    %edi,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  ret
```

assistant: ```c
long to_millis(struct timeval tv) {
  long ret = 0;
  ret += tv.tv_sec * 1000;
  ret += tv.tv_usec / 1000;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<to_millis>:
  endbr64
  mov    %rdi,%rdx
  imul   $0x3e8,%edi,%eax
  sar    $0x3f,%rdi
  sar    $0x20,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  cltq
  sar    $0x26,%rdx
  sub    %edi,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  ret
```

assistant: ```c
long to_millis(struct timeval tv) {
  long ret = 0;
  ret += tv.tv_sec * 1000;
  ret += tv.tv_usec / 1000;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bcm4751_serial_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L25
  cmpl   $0x0,-0x18(%rbp)
  jle    L25
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int bcm4751_serial_read(int fd, void *data, int length, struct timeval *timeout) {
  fd_set fds;
  int rc = -1;
  FD_ZERO(&fds);
  FD_SET(fd, &fds);
  rc = select(fd + 1, &fds, NULL, NULL, timeout);
  if (rc > 0 && length > 0) {
    rc = read(fd, data, length);
  }
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bcm4751_serial_read>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r13
  mov    %edx,%r12d
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  lea    0x1(%rbx),%edi
  mov    %r14,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  call   <select@plt>
  test   %eax,%eax
  jle    L25
  test   %r12d,%r12d
  jg     L23
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  jmp    L25
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bcm4751_serial_read(int fd, void *data, int length, struct timeval *timeout) {
  fd_set fds;
  int rc = -1;
  FD_ZERO(&fds);
  FD_SET(fd, &fds);
  rc = select(fd + 1, &fds, NULL, NULL, timeout);
  if (rc > 0 && length > 0) {
    rc = read(fd, data, length);
  }
  return rc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bcm4751_serial_read>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbp),%edi
  mov    %rbx,%r8
  mov    %r12,%rsi
  call   <select@plt>
  test   %eax,%eax
  jle    L1
  test   %r14d,%r14d
  jg     L36
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  jmp    L1
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bcm4751_serial_read(int fd, void *data, int length, struct timeval *timeout) {
  fd_set fds;
  int rc = -1;
  FD_ZERO(&fds);
  FD_SET(fd, &fds);
  rc = select(fd + 1, &fds, NULL, NULL, timeout);
  if (rc > 0 && length > 0) {
    rc = read(fd, data, length);
  }
  return rc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bcm4751_serial_read>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  lea    0x1(%rbp),%edi
  mov    %rbx,%r8
  mov    %r12,%rsi
  call   <select@plt>
  test   %eax,%eax
  jle    L35
  test   %r14d,%r14d
  jg     L0
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  jmp    L35
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bcm4751_serial_read(int fd, void *data, int length, struct timeval *timeout) {
  fd_set fds;
  int rc = -1;
  FD_ZERO(&fds);
  FD_SET(fd, &fds);
  rc = select(fd + 1, &fds, NULL, NULL, timeout);
  if (rc > 0 && length > 0) {
    rc = read(fd, data, length);
  }
  return rc;
}
```