user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<spiralOrder0>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  imul   %edx,%r14d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%r14,4),%edi
  sub    $0x28,%rsp
  mov    %esi,0x14(%rsp)
  mov    %r14d,0x10(%rsp)
  call   <malloc@plt>
  mov    %rax,%r11
  test   %r14d,%r14d
  jle    L88
  mov    %ebp,%eax
  lea    0x4(%r11),%rdi
  lea    -0x1(%rbp),%r13d
  xor    %esi,%esi
  lea    -0x2(%rax),%r12d
  mov    %r11,%rax
  mov    %rdi,0x8(%rsp)
  lea    -0x1(%r15),%ebp
  neg    %rax
  movslq %r12d,%r12
  mov    %ebp,%r14d
  xor    %r10d,%r10d
  add    %rax,%rax
  xor    %ecx,%ecx
  mov    %rax,(%rsp)
  movslq %r15d,%rax
  xor    %r15d,%r15d
  lea    -0x4(,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L45:
  cmp    %ebp,%r10d
  jg     L60
  movslq %ecx,%rdi
  mov    %r14d,%edx
  lea    0x0(,%rdi,4),%r8
  add    %rdi,%rdx
  mov    0x8(%rsp),%rdi
  lea    (%r11,%r8,1),%rax
  lea    (%rdi,%rdx,4),%rdi
  mov    %rsi,%rdx
  sub    %r11,%rdx
  sub    %r8,%rdx
  add    (%rbx,%rsi,2),%rdx
L82:
  mov    (%rdx,%rax,1),%r8d
  add    $0x4,%rax
  mov    %r8d,-0x4(%rax)
  cmp    %rdi,%rax
  jne    L82
  lea    0x1(%rcx,%r14,1),%ecx
L60:
  cmp    %ecx,0x10(%rsp)
  je     L88
  mov    0x14(%rsp),%eax
  add    $0x1,%r10d
  sub    %r10d,%eax
  cmp    %eax,%r10d
  jg     L18
  movslq %ecx,%rdx
  mov    0x8(%rsp),%r8
  lea    -0x1(%r13),%edi
  mov    0x18(%rsp),%r9
  add    %rdx,%rdi
  lea    (%r11,%rdx,4),%rax
  neg    %rdx
  lea    (%r8,%rdi,4),%r8
  mov    (%rsp),%rdi
  sub    %rsi,%r9
  lea    (%rdi,%rdx,8),%rdi
  add    %rbx,%rdi
  nopl   (%rax)
L90:
  mov    0x8(%rdi,%rax,2),%rdx
  add    $0x4,%rax
  mov    (%rdx,%r9,1),%edx
  mov    %edx,-0x4(%rax)
  cmp    %r8,%rax
  jne    L90
  add    %r13d,%ecx
  cmp    0x10(%rsp),%ecx
  je     L88
L18:
  sub    $0x1,%ebp
  mov    %r15d,%edi
  cmp    %r15d,%ebp
  jl     L70
  movslq %ecx,%rdx
  mov    0x8(%rbx,%r12,8),%r8
  movslq %ebp,%rax
  lea    (%r11,%rdx,4),%rdx
  nopl   0x0(%rax)
L109:
  mov    (%r8,%rax,4),%r9d
  sub    $0x1,%rax
  add    $0x4,%rdx
  mov    %r9d,-0x4(%rdx)
  cmp    %eax,%edi
  jle    L109
  add    %r14d,%ecx
L70:
  cmp    %edi,%r12d
  jle    L3
  movslq %ecx,%rdx
  movslq %r12d,%rax
  lea    (%r11,%rdx,4),%rdx
  cs nopw 0x0(%rax,%rax,1)
L78:
  mov    (%rbx,%rax,8),%r8
  sub    $0x1,%rax
  add    $0x4,%rdx
  mov    (%r8,%rsi,1),%r8d
  mov    %r8d,-0x4(%rdx)
  cmp    %eax,%edi
  jl     L78
  lea    -0x1(%rcx,%r13,1),%ecx
L3:
  add    $0x1,%r15
  sub    $0x1,%r12
  sub    $0x2,%r13d
  sub    $0x2,%r14d
  addq   $0x8,(%rsp)
  add    $0x4,%rsi
  cmp    %ecx,0x10(%rsp)
  jg     L45
L88:
  add    $0x28,%rsp
  mov    %r11,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *spiralOrder0(int **matrix, int rSize, int cSize) {
  int count = 0;
  int size = rSize * cSize;
  int *arr = (int *)malloc(sizeof(int) * size);
  int rmin = 0, rmax = rSize - 1;
  int cmin = 0, cmax = cSize - 1;
  while (count < size) {
    for (int c = cmin; c <= cmax; c++)
      arr[count++] = matrix[rmin][c];
    if (count == size)
      break;
    for (int r = rmin + 1; r <= rmax; r++)
      arr[count++] = matrix[r][cmax];
    if (count == size)
      break;
    for (int c = cmax - 1; c >= cmin; c--)
      arr[count++] = matrix[rmax][c];
    for (int r = rmax - 1; r > rmin; r--)
      arr[count++] = matrix[r][cmin];
    rmin++;
    rmax--;
    cmin++;
    cmax--;
  }
  return arr;
}
```