ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<int64_to_byte>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void int64_to_byte(long long i, unsigned char *bytes) {
  int size = 8;
  memset(bytes, 0, sizeof(unsigned char) * size);
  bytes[0] = (unsigned char)(0xff & i);
  bytes[1] = (unsigned char)((0xff00 & i) >> 8);
  bytes[2] = (unsigned char)((0xff0000 & i) >> 16);
  bytes[3] = (unsigned char)((0xff000000 & i) >> 24);
  bytes[4] = (unsigned char)((0xff00000000 & i) >> 32);
  bytes[5] = (unsigned char)((0xff0000000000 & i) >> 40);
  bytes[6] = (unsigned char)((0xff000000000000 & i) >> 48);
  bytes[7] = (unsigned char)((0xff00000000000000 & i) >> 56);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<int64_to_byte>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void int64_to_byte(long long i, unsigned char *bytes) {
  int size = 8;
  memset(bytes, 0, sizeof(unsigned char) * size);
  bytes[0] = (unsigned char)(0xff & i);
  bytes[1] = (unsigned char)((0xff00 & i) >> 8);
  bytes[2] = (unsigned char)((0xff0000 & i) >> 16);
  bytes[3] = (unsigned char)((0xff000000 & i) >> 24);
  bytes[4] = (unsigned char)((0xff00000000 & i) >> 32);
  bytes[5] = (unsigned char)((0xff0000000000 & i) >> 40);
  bytes[6] = (unsigned char)((0xff000000000000 & i) >> 48);
  bytes[7] = (unsigned char)((0xff00000000000000 & i) >> 56);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SWAP8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SWAP8(uint8_t *const x, uint8_t *const y) {
  uint8_t _x = *x;
  *x = *y;
  *y = _x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SWAP8>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void SWAP8(uint8_t *const x, uint8_t *const y) {
  uint8_t _x = *x;
  *x = *y;
  *y = _x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SWAP8>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void SWAP8(uint8_t *const x, uint8_t *const y) {
  uint8_t _x = *x;
  *x = *y;
  *y = _x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SWAP8>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void SWAP8(uint8_t *const x, uint8_t *const y) {
  uint8_t _x = *x;
  *x = *y;
  *y = _x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<doublecmp0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    $0x1,%eax
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jp     L19
  mov    $0x0,%eax
L19:
  movzbl %al,%eax
  mov    $0x1,%edx
  movsd  -0x18(%rbp),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L13
  mov    $0x0,%edx
L13:
  movzbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L36
  mov    -0xc(%rbp),%eax
  jmp    L34
L36:
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int doublecmp0(double a, double b) {
  double x;
  int r = (b != b) - (a != a);
  if (r)
    return r;
  x = a - b;
  return (x > 0) - (x < 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<doublecmp0>:
  endbr64
  ucomisd %xmm1,%xmm1
  setp   %al
  movzbl %al,%eax
  ucomisd %xmm0,%xmm0
  setp   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  jne    L4
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  comisd %xmm0,%xmm1
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
L4:
  ret
```

assistant: ```c
int doublecmp0(double a, double b) {
  double x;
  int r = (b != b) - (a != a);
  if (r)
    return r;
  x = a - b;
  return (x > 0) - (x < 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<doublecmp0>:
  endbr64
  xor    %eax,%eax
  ucomisd %xmm1,%xmm1
  setp   %al
  xor    %edx,%edx
  ucomisd %xmm0,%xmm0
  setp   %dl
  sub    %edx,%eax
  jne    L6
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
L6:
  ret
```

assistant: ```c
int doublecmp0(double a, double b) {
  double x;
  int r = (b != b) - (a != a);
  if (r)
    return r;
  x = a - b;
  return (x > 0) - (x < 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<doublecmp0>:
  endbr64
  xor    %eax,%eax
  ucomisd %xmm1,%xmm1
  setp   %al
  xor    %edx,%edx
  ucomisd %xmm0,%xmm0
  setp   %dl
  sub    %edx,%eax
  jne    L8
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
L8:
  ret
```

assistant: ```c
int doublecmp0(double a, double b) {
  double x;
  int r = (b != b) - (a != a);
  if (r)
    return r;
  x = a - b;
  return (x > 0) - (x < 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ConverterRNA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x54,%eax
  je     L6
  cmp    $0x54,%eax
  jg     L75
  cmp    $0x47,%eax
  je     L0
  cmp    $0x47,%eax
  jg     L75
  cmp    $0x41,%eax
  je     L108
  cmp    $0x43,%eax
  je     L28
  jmp    L75
L108:
  mov    $0x55,%eax
  jmp    L98
L6:
  mov    $0x41,%eax
  jmp    L98
L28:
  mov    $0x47,%eax
  jmp    L98
L0:
  mov    $0x43,%eax
  jmp    L98
L75:
  mov    $0x0,%eax
L98:
  pop    %rbp
  ret
```

assistant: ```c
char ConverterRNA(char Nucleotide) {
  switch (Nucleotide) {
  case 'A':
    return 'U';
  case 'T':
    return 'A';
  case 'C':
    return 'G';
  case 'G':
    return 'C';
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ConverterRNA>:
  endbr64
  cmp    $0x47,%dil
  je     L19
  jg     L25
  mov    $0x55,%eax
  cmp    $0x41,%dil
  je     L5
  cmp    $0x43,%dil
  mov    $0x0,%eax
  mov    $0x47,%edx
  cmove  %edx,%eax
  ret
L25:
  cmp    $0x54,%dil
  mov    $0x0,%eax
  mov    $0x41,%edx
  cmove  %edx,%eax
  ret
L19:
  mov    $0x43,%eax
L5:
  ret
```

assistant: ```c
char ConverterRNA(char Nucleotide) {
  switch (Nucleotide) {
  case 'A':
    return 'U';
  case 'T':
    return 'A';
  case 'C':
    return 'G';
  case 'G':
    return 'C';
  default:
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ConverterRNA>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x13,%dil
  ja     L8
  movzbl %dil,%edi
  lea    D4(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L8:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: U

assistant: ```c
char ConverterRNA(char Nucleotide) {
  switch (Nucleotide) {
  case 'A':
    return 'U';
  case 'T':
    return 'A';
  case 'C':
    return 'G';
  case 'G':
    return 'C';
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ConverterRNA>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x13,%dil
  ja     L6
  movzbl %dil,%edi
  lea    D2(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L6:
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string

tool: D2: U

assistant: ```c
char ConverterRNA(char Nucleotide) {
  switch (Nucleotide) {
  case 'A':
    return 'U';
  case 'T':
    return 'A';
  case 'C':
    return 'G';
  case 'G':
    return 'C';
  default:
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(int x) {
  x = x + 1;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  lea    0x1(%rdi),%eax
  ret
```

assistant: ```c
int foo(int x) {
  x = x + 1;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  lea    0x1(%rdi),%eax
  ret
```

assistant: ```c
int foo(int x) {
  x = x + 1;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  lea    0x1(%rdi),%eax
  ret
```

assistant: ```c
int foo(int x) {
  x = x + 1;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x64,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L4:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x8(%rbp)
  jg     L4
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: Value %d


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 100;
  int i = 0;
  while (x > 0) {
    x = x / 2;
    i = i + 1;
  }
  printf("Value %d\n", i);
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string

tool: D9: Value %d


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 100;
  int i = 0;
  while (x > 0) {
    x = x / 2;
    i = i + 1;
  }
  printf("Value %d\n", i);
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: Value %d


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 100;
  int i = 0;
  while (x > 0) {
    x = x / 2;
    i = i + 1;
  }
  printf("Value %d\n", i);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string

tool: D4: Value %d


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 100;
  int i = 0;
  while (x > 0) {
    x = x / 2;
    i = i + 1;
  }
  printf("Value %d\n", i);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trio_to_unsigned_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  cmpl   $0x1,-0x14(%rbp)
  jle    L15
  cmpl   $0x24,-0x14(%rbp)
  jg     L15
  mov    $0x1,%eax
  jmp    L9
L15:
  mov    $0x0,%eax
L9:
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <strtoul@plt>
  cltq
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) unsigned long trio_to_unsigned_long(const char *string, char **endp, int base) {
  assert(string);
  assert((base >= 2) && (base <= 36));
  return strtoul(string, endp, base);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trio_to_unsigned_long>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x0,%eax
  call   <assert@plt>
  lea    -0x2(%rbp),%eax
  cmp    $0x22,%eax
  setbe  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <strtoul@plt>
  cltq
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((visibility("default"))) unsigned long trio_to_unsigned_long(const char *string, char **endp, int base) {
  assert(string);
  assert((base >= 2) && (base <= 36));
  return strtoul(string, endp, base);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trio_to_unsigned_long>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  lea    -0x2(%r12),%eax
  xor    %edi,%edi
  cmp    $0x22,%eax
  setbe  %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <strtoul@plt>
  pop    %rbp
  pop    %r12
  cltq
  pop    %r13
  ret
```

assistant: ```c
__attribute__((visibility("default"))) unsigned long trio_to_unsigned_long(const char *string, char **endp, int base) {
  assert(string);
  assert((base >= 2) && (base <= 36));
  return strtoul(string, endp, base);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trio_to_unsigned_long>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  lea    -0x2(%r12),%eax
  xor    %edi,%edi
  cmp    $0x22,%eax
  setbe  %dil
  xor    %eax,%eax
  call   <assert@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <strtoul@plt>
  pop    %rbp
  pop    %r12
  cltq
  pop    %r13
  ret
```

assistant: ```c
__attribute__((visibility("default"))) unsigned long trio_to_unsigned_long(const char *string, char **endp, int base) {
  assert(string);
  assert((base >= 2) && (base <= 36));
  return strtoul(string, endp, base);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x61000(%rsp),%r11
L98:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L98
  sub    $0xab0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L76:
  movl   $0x0,-0x61a98(%rbp)
  mov    -0x61a98(%rbp),%eax
  mov    %eax,-0x61a9c(%rbp)
  lea    -0x61aa4(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x61aa4(%rbp),%eax
  cmp    $0xffffffff,%eax
  je     L64
  movl   $0x0,-0x61aa0(%rbp)
  jmp    L9
L68:
  lea    -0x61a90(%rbp),%rdx
  mov    -0x61aa0(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x61aa0(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  add    %eax,-0x61a9c(%rbp)
  addl   $0x1,-0x61aa0(%rbp)
L9:
  mov    -0x61aa4(%rbp),%eax
  cmp    %eax,-0x61aa0(%rbp)
  jl     L68
  mov    -0x61aa4(%rbp),%ecx
  mov    -0x61a9c(%rbp),%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x61a9c(%rbp),%xmm1
  mov    -0x61aa4(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  divss  %xmm2,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L78
  ucomiss %xmm1,%xmm0
  je     L44
L78:
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L22
L44:
  mov    -0x61aa4(%rbp),%ecx
  mov    -0x61a9c(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x61a94(%rbp)
  movl   $0x0,-0x61aa0(%rbp)
  jmp    L73
L75:
  mov    -0x61aa0(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  sub    -0x61a94(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  add    %eax,-0x61a98(%rbp)
  addl   $0x1,-0x61aa0(%rbp)
L73:
  mov    -0x61aa4(%rbp),%eax
  cmp    %eax,-0x61aa0(%rbp)
  jl     L75
  mov    -0x61a98(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  jmp    L76
L64:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D23
datatype: string
name: read_data
arguments: data_label: D30
datatype: string
name: read_data
arguments: data_label: D36
datatype: string

tool: D23: %d

tool: D30: -1

tool: D36: %d


assistant: ```c
int main() {
  int i, j, c, len, num, temp, t, res;
  int arr[100001];
  while (1) {
    c = len = 0;
    scanf("%d", &num);
    if (num == -1)
      break;
    for (i = 0; i < num; i++) {
      scanf("%d", &arr[i]);
      c += arr[i];
    }
    if (c / num != (float)c / num) {
      printf("-1\n");
      continue;
    }
    temp = c / num;
    for (i = 0; i < num; i++)
      len += ((arr[i] - temp) >= 0 ? (arr[i] - temp) : -(arr[i] - temp));
    printf("%d\n", len / 2);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L101:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L101
  sub    $0xaa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%r12
  lea    D34(%rip),%r13
  jmp    L62
L73:
  mov    $0x0,%edi
  jmp    L146
L8:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  jmp    L62
L94:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L142
  mov    $0x0,%eax
  add    $0x61aa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L111:
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  pxor   %xmm0,%xmm0
  divss  %xmm1,%xmm0
  ucomiss D31(%rip),%xmm0
  jp     L8
  mov    $0x0,%edi
  jne    L8
L146:
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L62:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L94
  test   %eax,%eax
  jle    L111
  mov    $0x0,%ebp
  mov    $0x0,%r14d
L51:
  lea    0x10(%rsp),%rbx
  lea    (%rbx,%rbp,4),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    (%rbx,%rbp,4),%r14d
  mov    0xc(%rsp),%ecx
  add    $0x1,%rbp
  cmp    %ebp,%ecx
  jg     L51
  mov    %r14d,%eax
  cltd
  idiv   %ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %r14d,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2ss %ecx,%xmm2
  divss  %xmm2,%xmm0
  ucomiss %xmm0,%xmm1
  jp     L8
  jne    L8
  test   %ecx,%ecx
  jle    L73
  lea    -0x1(%rcx),%edx
  lea    0x4(%rbx,%rdx,4),%rsi
  mov    $0x0,%edi
L0:
  mov    (%rbx),%edx
  sub    %eax,%edx
  mov    %edx,%ecx
  neg    %ecx
  cmovns %ecx,%edx
  add    %edx,%edi
  add    $0x4,%rbx
  cmp    %rsi,%rbx
  jne    L0
  jmp    L146
L142:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D13
type: string
name: read_data
arguments: label: D34
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D31
type: byte[4]

tool: D13: %d

tool: D34: %d


tool: D14: -1

tool: {"D31": [0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int i, j, c, len, num, temp, t, res;
  int arr[100001];
  while (1) {
    c = len = 0;
    scanf("%d", &num);
    if (num == -1)
      break;
    for (i = 0; i < num; i++) {
      scanf("%d", &arr[i]);
      c += arr[i];
    }
    if (c / num != (float)c / num) {
      printf("-1\n");
      continue;
    }
    temp = c / num;
    for (i = 0; i < num; i++)
      len += ((arr[i] - temp) >= 0 ? (arr[i] - temp) : -(arr[i] - temp));
    printf("%d\n", len / 2);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L93:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L93
  sub    $0xaa8,%rsp
  lea    D9(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  nopl   (%rax)
L53:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L132
  test   %eax,%eax
  jle    L42
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  lea    0x10(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L44:
  lea    0x0(%rbp,%rbx,4),%rsi
  mov    %r12,%rdi
  mov    %rbp,%r15
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  add    0x0(%rbp,%rbx,4),%r14d
  add    $0x1,%rbx
  cmp    %ebx,%esi
  jg     L44
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  mov    %r14d,%eax
  cltd
  cvtsi2ss %r14d,%xmm0
  idiv   %esi
  cvtsi2ss %esi,%xmm2
  divss  %xmm2,%xmm0
  cvtsi2ss %eax,%xmm1
  ucomiss %xmm0,%xmm1
  jp     L129
  jne    L129
  test   %esi,%esi
  jle    L111
  lea    -0x1(%rsi),%edx
  xor    %esi,%esi
  lea    0x14(%rsp,%rdx,4),%r8
  nopl   (%rax)
L88:
  mov    (%r15),%edx
  sub    %eax,%edx
  mov    %edx,%edi
  neg    %edi
  cmovns %edi,%edx
  add    $0x4,%r15
  add    %edx,%esi
  cmp    %r8,%r15
  jne    L88
L110:
  sar    %esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L53
  nopl   0x0(%rax)
L42:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  pxor   %xmm3,%xmm3
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  ucomiss %xmm3,%xmm0
  jp     L129
  je     L111
  nopl   0x0(%rax,%rax,1)
L129:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L53
  nopl   0x0(%rax)
L132:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L119
  add    $0x61aa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L111:
  xor    %esi,%esi
  jmp    L110
L119:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string
name: disassemble_data
arguments: data_tag: D29
type_infered: string

tool: D9: %d

tool: D19: %d


tool: D29: -1

assistant: ```c
int main() {
  int i, j, c, len, num, temp, t, res;
  int arr[100001];
  while (1) {
    c = len = 0;
    scanf("%d", &num);
    if (num == -1)
      break;
    for (i = 0; i < num; i++) {
      scanf("%d", &arr[i]);
      c += arr[i];
    }
    if (c / num != (float)c / num) {
      printf("-1\n");
      continue;
    }
    temp = c / num;
    for (i = 0; i < num; i++)
      len += ((arr[i] - temp) >= 0 ? (arr[i] - temp) : -(arr[i] - temp));
    printf("%d\n", len / 2);
  }
  return 0;
}
```