ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<do_field>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  cmp    %ecx,%edx
  jne    L18
L13:
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %edx,%esi
  sub    %ecx,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D0: %8d %-30s %3u


tool: D10: 	(padding %d bytes?)


assistant: ```c
int do_field(const char *field, size_t size, int offset, int cur_offset) {
  if (offset != cur_offset) {
    printf("\t(padding %d bytes?)\n", offset - cur_offset);
  }
  printf("%8d %-30s %3u\n", offset, field, (unsigned)size);
  return offset + size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_field>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  cmp    %ecx,%edx
  je     L5
  mov    %edx,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  sub    %ecx,%esi
  call   <printf@plt>
L5:
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
datatype: string
name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D11: 	(padding %d bytes?)


tool: D2: %8d %-30s %3u


assistant: ```c
int do_field(const char *field, size_t size, int offset, int cur_offset) {
  if (offset != cur_offset) {
    printf("\t(padding %d bytes?)\n", offset - cur_offset);
  }
  printf("%8d %-30s %3u\n", offset, field, (unsigned)size);
  return offset + size;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_field>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  cmp    %ecx,%edx
  je     L3
  mov    %edx,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  sub    %ecx,%esi
  call   <printf@plt>
L3:
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D12
datatype: string
name: read_data
arguments: label: D2
datatype: string

tool: D12: 	(padding %d bytes?)


tool: D2: %8d %-30s %3u


assistant: ```c
int do_field(const char *field, size_t size, int offset, int cur_offset) {
  if (offset != cur_offset) {
    printf("\t(padding %d bytes?)\n", offset - cur_offset);
  }
  printf("%8d %-30s %3u\n", offset, field, (unsigned)size);
  return offset + size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <writer@plt>
  mov    $0x0,%edi
  call   <write_reader@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_1:
  writer(0);
__CPROVER_ASYNC_2:
  write_reader(0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <writer@plt>
  mov    $0x0,%edi
  call   <write_reader@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_1:
  writer(0);
__CPROVER_ASYNC_2:
  write_reader(0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <writer@plt>
  xor    %edi,%edi
  call   <write_reader@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_1:
  writer(0);
__CPROVER_ASYNC_2:
  write_reader(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <writer@plt>
  xor    %edi,%edi
  call   <write_reader@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_1:
  writer(0);
__CPROVER_ASYNC_2:
  write_reader(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *foo(void) {
  int *i = malloc(sizeof *i);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *foo(void) {
  int *i = malloc(sizeof *i);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  mov    $0x4,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
int *foo(void) {
  int *i = malloc(sizeof *i);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  mov    $0x4,%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
int *foo(void) {
  int *i = malloc(sizeof *i);
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<buzz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <random@plt>
  and    $0xffff,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L13:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void buzz(int n) {
  volatile int i;
  int m = random() & 0x0ffff;
  for (i = 0; i < m; i++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<buzz>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  movzwl %ax,%eax
  movl   $0x0,0xc(%rsp)
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  jle    L14
L4:
  mov    0xc(%rsp),%edx
  add    $0x1,%edx
  mov    %edx,0xc(%rsp)
  mov    0xc(%rsp),%edx
  cmp    %eax,%edx
  jl     L4
L14:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void buzz(int n) {
  volatile int i;
  int m = random() & 0x0ffff;
  for (i = 0; i < m; i++)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<buzz>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <random@plt>
  movl   $0x0,0xc(%rsp)
  mov    0xc(%rsp),%edx
  movzwl %ax,%eax
  cmp    %edx,%eax
  jle    L2
  nopw   0x0(%rax,%rax,1)
L15:
  mov    0xc(%rsp),%edx
  add    $0x1,%edx
  mov    %edx,0xc(%rsp)
  mov    0xc(%rsp),%edx
  cmp    %eax,%edx
  jl     L15
L2:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void buzz(int n) {
  volatile int i;
  int m = random() & 0x0ffff;
  for (i = 0; i < m; i++)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<buzz>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <random@plt>
  movl   $0x0,0xc(%rsp)
  mov    0xc(%rsp),%edx
  movzwl %ax,%eax
  cmp    %edx,%eax
  jle    L17
  nopw   0x0(%rax,%rax,1)
L16:
  mov    0xc(%rsp),%edx
  add    $0x1,%edx
  mov    %edx,0xc(%rsp)
  mov    0xc(%rsp),%edx
  cmp    %eax,%edx
  jl     L16
L17:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void buzz(int n) {
  volatile int i;
  int m = random() & 0x0ffff;
  for (i = 0; i < m; i++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x10(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  lea    D8(%rip),%rdx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: %Y%m%d

assistant: ```c
char *get_date(char *strBuf) {
  time_t now = time(NULL);
  struct tm tm_now;
  localtime_r(&now, &tm_now);
  strftime(strBuf, sizeof("20140101"), "%Y%m%d", &tm_now);
  return strBuf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_date>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rsp),%rbp
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <localtime_r@plt>
  mov    %rbp,%rcx
  lea    D8(%rip),%rdx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %Y%m%d

assistant: ```c
char *get_date(char *strBuf) {
  time_t now = time(NULL);
  struct tm tm_now;
  localtime_r(&now, &tm_now);
  strftime(strBuf, sizeof("20140101"), "%Y%m%d", &tm_now);
  return strBuf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_date>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <time@plt>
  mov    %rsp,%rdi
  mov    %r13,%rsi
  mov    %eax,(%rsp)
  call   <localtime_r@plt>
  mov    %r13,%rcx
  mov    $0x9,%esi
  mov    %r12,%rdi
  lea    D5(%rip),%rdx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: %Y%m%d

assistant: ```c
char *get_date(char *strBuf) {
  time_t now = time(NULL);
  struct tm tm_now;
  localtime_r(&now, &tm_now);
  strftime(strBuf, sizeof("20140101"), "%Y%m%d", &tm_now);
  return strBuf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_date>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <time@plt>
  mov    %rsp,%rdi
  mov    %r13,%rsi
  mov    %eax,(%rsp)
  call   <localtime_r@plt>
  mov    %r13,%rcx
  mov    $0x9,%esi
  mov    %r12,%rdi
  lea    D1(%rip),%rdx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: %Y%m%d

assistant: ```c
char *get_date(char *strBuf) {
  time_t now = time(NULL);
  struct tm tm_now;
  localtime_r(&now, &tm_now);
  strftime(strBuf, sizeof("20140101"), "%Y%m%d", &tm_now);
  return strBuf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<InvShiftRows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0xd(%rax),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0xd(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x9(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x9(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x5(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x5(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L34:
  mov    -0x18(%rbp),%rax
  movzbl 0xe(%rax),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0xe(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xa(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xa(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x6(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x6(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0x1,-0x4(%rbp)
  jle    L34
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L5:
  mov    -0x18(%rbp),%rax
  movzbl 0xf(%rax),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0xf(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xb(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xb(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x7(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x7(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x2,-0x4(%rbp)
  jle    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void InvShiftRows(unsigned char state[16]) {
  int i = 0;
  unsigned char temp;
  temp = state[13];
  state[13] = state[9];
  state[9] = state[5];
  state[5] = state[1];
  state[1] = temp;
  for (i = 0; i < 2; i++) {
    temp = state[14];
    state[14] = state[10];
    state[10] = state[6];
    state[6] = state[2];
    state[2] = temp;
  }
  for (i = 0; i < 3; i++) {
    temp = state[15];
    state[15] = state[11];
    state[11] = state[7];
    state[7] = state[3];
    state[3] = temp;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<InvShiftRows>:
  endbr64
  movzbl 0xd(%rdi),%eax
  movzbl 0x9(%rdi),%edx
  mov    %dl,0xd(%rdi)
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x9(%rdi)
  movzbl 0x1(%rdi),%edx
  mov    %dl,0x5(%rdi)
  mov    %al,0x1(%rdi)
  movzbl 0xe(%rdi),%edx
  movzbl 0xa(%rdi),%eax
  movzbl 0x2(%rdi),%ecx
  movzbl 0x6(%rdi),%esi
  mov    %sil,0xe(%rdi)
  mov    %cl,0xa(%rdi)
  mov    %dl,0x6(%rdi)
  mov    %al,0x2(%rdi)
  movzbl 0xf(%rdi),%ecx
  movzbl 0xb(%rdi),%edx
  movzbl 0x7(%rdi),%eax
  movzbl 0x3(%rdi),%esi
  mov    %sil,0xf(%rdi)
  mov    %cl,0xb(%rdi)
  mov    %dl,0x7(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void InvShiftRows(unsigned char state[16]) {
  int i = 0;
  unsigned char temp;
  temp = state[13];
  state[13] = state[9];
  state[9] = state[5];
  state[5] = state[1];
  state[1] = temp;
  for (i = 0; i < 2; i++) {
    temp = state[14];
    state[14] = state[10];
    state[10] = state[6];
    state[6] = state[2];
    state[2] = temp;
  }
  for (i = 0; i < 3; i++) {
    temp = state[15];
    state[15] = state[11];
    state[11] = state[7];
    state[7] = state[3];
    state[3] = temp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<InvShiftRows>:
  endbr64
  movzbl 0x9(%rdi),%edx
  movzbl 0xd(%rdi),%eax
  movzbl 0x2(%rdi),%ecx
  movzbl 0x6(%rdi),%esi
  mov    %dl,0xd(%rdi)
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x9(%rdi)
  movzbl 0x1(%rdi),%edx
  mov    %al,0x1(%rdi)
  movzbl 0xa(%rdi),%eax
  mov    %dl,0x5(%rdi)
  movzbl 0xe(%rdi),%edx
  mov    %cl,0xa(%rdi)
  movzbl 0xf(%rdi),%ecx
  mov    %sil,0xe(%rdi)
  movzbl 0x3(%rdi),%esi
  mov    %dl,0x6(%rdi)
  movzbl 0xb(%rdi),%edx
  mov    %al,0x2(%rdi)
  movzbl 0x7(%rdi),%eax
  mov    %sil,0xf(%rdi)
  mov    %cl,0xb(%rdi)
  mov    %dl,0x7(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void InvShiftRows(unsigned char state[16]) {
  int i = 0;
  unsigned char temp;
  temp = state[13];
  state[13] = state[9];
  state[9] = state[5];
  state[5] = state[1];
  state[1] = temp;
  for (i = 0; i < 2; i++) {
    temp = state[14];
    state[14] = state[10];
    state[10] = state[6];
    state[6] = state[2];
    state[2] = temp;
  }
  for (i = 0; i < 3; i++) {
    temp = state[15];
    state[15] = state[11];
    state[11] = state[7];
    state[7] = state[3];
    state[3] = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InvShiftRows>:
  endbr64
  movzbl 0x9(%rdi),%edx
  movzbl 0xd(%rdi),%eax
  movzbl 0x2(%rdi),%ecx
  movzbl 0x6(%rdi),%esi
  mov    %dl,0xd(%rdi)
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x9(%rdi)
  movzbl 0x1(%rdi),%edx
  mov    %al,0x1(%rdi)
  movzbl 0xa(%rdi),%eax
  mov    %dl,0x5(%rdi)
  movzbl 0xe(%rdi),%edx
  mov    %cl,0xa(%rdi)
  movzbl 0xf(%rdi),%ecx
  mov    %sil,0xe(%rdi)
  movzbl 0x3(%rdi),%esi
  mov    %dl,0x6(%rdi)
  movzbl 0xb(%rdi),%edx
  mov    %al,0x2(%rdi)
  movzbl 0x7(%rdi),%eax
  mov    %sil,0xf(%rdi)
  mov    %cl,0xb(%rdi)
  mov    %dl,0x7(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void InvShiftRows(unsigned char state[16]) {
  int i = 0;
  unsigned char temp;
  temp = state[13];
  state[13] = state[9];
  state[9] = state[5];
  state[5] = state[1];
  state[1] = temp;
  for (i = 0; i < 2; i++) {
    temp = state[14];
    state[14] = state[10];
    state[10] = state[6];
    state[6] = state[2];
    state[2] = temp;
  }
  for (i = 0; i < 3; i++) {
    temp = state[15];
    state[15] = state[11];
    state[11] = state[7];
    state[7] = state[3];
    state[3] = temp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CE_pHHCO3_P>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  D5(%rip),%xmm0
  subsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    D23(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x4,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movq   D27(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x38(%rbp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x28(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x28(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movq   D27(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  divsd  -0x10(%rbp),%xmm0
  divsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: byte[8]
name: parse_data
arguments: data_label: D23
type: byte[8]
name: parse_data
arguments: data_label: D27
type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double CE_pHHCO3_P(double pH, double HCO3, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -(-K2 * HCO3 * K1 + HCO3 * H3O * H3O - Kw * K1 + H3O * H3O * K1) / H3O / K1;
  return t0;
}
```
user: What is the c source code of the assembly code below:

```asm
<CE_pHHCO3_P>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movapd %xmm0,%xmm6
  movq   %xmm1,%r15
  movq   %xmm2,%r12
  movq   %xmm3,%rbx
  movq   %xmm4,%rbp
  movq   %xmm5,%r14
  movsd  D21(%rip),%xmm0
  subsd  %xmm6,%xmm0
  cvttsd2si %xmm0,%edi
  movsd  D7(%rip),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm7
  movq   %r14,%xmm0
  divsd  %xmm0,%xmm7
  movsd  %xmm7,(%rsp)
  mov    $0x2,%edi
  call   <pow@plt>
  movq   %r12,%xmm4
  divsd  %xmm0,%xmm4
  movsd  %xmm4,0x8(%rsp)
  mov    $0x4,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %rbx,%xmm3
  divsd  %xmm0,%xmm3
  movq   %xmm3,%rbx
  mov    $0x2,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm3
  movq   D26(%rip),%xmm1
  movq   %rbx,%xmm2
  xorpd  %xmm1,%xmm2
  movq   %r15,%xmm5
  mulsd  %xmm5,%xmm2
  movsd  0x8(%rsp),%xmm4
  mulsd  %xmm4,%xmm2
  movsd  (%rsp),%xmm6
  mulsd  %xmm6,%xmm5
  movapd %xmm5,%xmm0
  mulsd  %xmm6,%xmm0
  addsd  %xmm0,%xmm2
  movq   %rbp,%xmm0
  divsd  %xmm3,%xmm0
  mulsd  %xmm4,%xmm0
  subsd  %xmm0,%xmm2
  movapd %xmm6,%xmm0
  mulsd  %xmm6,%xmm0
  mulsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  xorpd  %xmm1,%xmm0
  divsd  %xmm6,%xmm0
  divsd  %xmm4,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D21
type_infered: byte[8]
name: read_data
arguments: data_tag: D7
type_infered: byte[8]
name: read_data
arguments: data_tag: D26
type_infered: byte[8]

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double CE_pHHCO3_P(double pH, double HCO3, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -(-K2 * HCO3 * K1 + HCO3 * H3O * H3O - Kw * K1 + H3O * H3O * K1) / H3O / K1;
  return t0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CE_pHHCO3_P>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm0,%xmm6
  movsd  D1(%rip),%xmm0
  movsd  %xmm1,0x38(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x30(%rsp)
  movsd  %xmm2,0x10(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D16(%rip),%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm6
  divsd  %xmm5,%xmm6
  movapd %xmm5,%xmm0
  movsd  %xmm6,0x20(%rsp)
  call   <pow@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm5
  mov    $0x4,%edi
  divsd  %xmm0,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <pow@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm5
  movq   D0(%rip),%xmm0
  movsd  0x20(%rsp),%xmm6
  divsd  %xmm5,%xmm4
  movsd  0x38(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  add    $0x48,%rsp
  xorpd  %xmm0,%xmm3
  mulsd  %xmm1,%xmm3
  mulsd  %xmm6,%xmm1
  mulsd  %xmm2,%xmm3
  mulsd  %xmm6,%xmm1
  addsd  %xmm1,%xmm3
  movapd %xmm6,%xmm1
  mulsd  %xmm6,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm4
  subsd  %xmm4,%xmm3
  addsd  %xmm1,%xmm3
  xorpd  %xmm3,%xmm0
  divsd  %xmm6,%xmm0
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: byte[8]
name: disassemble_data
arguments: data_label: D16
data_type: byte[8]
name: disassemble_data
arguments: data_label: D0
data_type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double CE_pHHCO3_P(double pH, double HCO3, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -(-K2 * HCO3 * K1 + HCO3 * H3O * H3O - Kw * K1 + H3O * H3O * K1) / H3O / K1;
  return t0;
}
```