ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Connect>:
  endbr64
  sub    $0x8,%rsp
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L18
L11:
  add    $0x8,%rsp
  ret
L18:
  lea    D0(%rip),%rdi
  call   <Sys_failure@plt>
  jmp    L11
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: connect

assistant: ```c
void Connect(int sockfd, const struct sockaddr *serv_addr, socklen_t addrlen) {
  int retval;
  retval = connect(sockfd, serv_addr, addrlen);
  if (retval == -1)
    Sys_failure("connect");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Connect>:
  endbr64
  sub    $0x8,%rsp
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L6
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <Sys_failure@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: connect

assistant: ```c
void Connect(int sockfd, const struct sockaddr *serv_addr, socklen_t addrlen) {
  int retval;
  retval = connect(sockfd, serv_addr, addrlen);
  if (retval == -1)
    Sys_failure("connect");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Connect>:
  endbr64
  sub    $0x8,%rsp
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L8
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <Sys_failure@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: connect

assistant: ```c
void Connect(int sockfd, const struct sockaddr *serv_addr, socklen_t addrlen) {
  int retval;
  retval = connect(sockfd, serv_addr, addrlen);
  if (retval == -1)
    Sys_failure("connect");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__md5_Encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L5:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
  addl   $0x4,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __md5_Encode(unsigned char *output, u_int32_t *input, unsigned int len) {
  unsigned int i, j;
  for (i = 0, j = 0; j < len; i++, j += 4) {
    output[j] = (unsigned char)(input[i] & 0xff);
    output[j + 1] = (unsigned char)((input[i] >> 8) & 0xff);
    output[j + 2] = (unsigned char)((input[i] >> 16) & 0xff);
    output[j + 3] = (unsigned char)((input[i] >> 24) & 0xff);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__md5_Encode>:
  endbr64
  test   %edx,%edx
  je     L3
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%r9
  mov    %edx,%r10d
  mov    $0x0,%eax
  mov    $0x0,%edi
L18:
  mov    %edi,%edx
  lea    (%r9,%rdx,4),%rdx
  mov    %eax,%esi
  mov    (%rdx),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  lea    0x1(%rax),%esi
  mov    (%rdx),%ebx
  movzbl %bh,%ebx
  mov    %bl,(%rcx,%rsi,1)
  lea    0x2(%rax),%r8d
  mov    (%rdx),%esi
  sar    $0x10,%esi
  mov    %sil,(%rcx,%r8,1)
  lea    0x3(%rax),%esi
  mov    (%rdx),%edx
  sar    $0x18,%edx
  mov    %dl,(%rcx,%rsi,1)
  add    $0x1,%edi
  add    $0x4,%eax
  cmp    %eax,%r10d
  ja     L18
  pop    %rbx
  ret
L3:
  ret
```

assistant: ```c
void __md5_Encode(unsigned char *output, u_int32_t *input, unsigned int len) {
  unsigned int i, j;
  for (i = 0, j = 0; j < len; i++, j += 4) {
    output[j] = (unsigned char)(input[i] & 0xff);
    output[j + 1] = (unsigned char)((input[i] >> 8) & 0xff);
    output[j + 2] = (unsigned char)((input[i] >> 16) & 0xff);
    output[j + 3] = (unsigned char)((input[i] >> 24) & 0xff);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__md5_Encode>:
  endbr64
  test   %edx,%edx
  je     L19
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%r9
  mov    %edx,%r10d
  xor    %eax,%eax
  xor    %edi,%edi
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %edi,%edx
  mov    %eax,%esi
  add    $0x1,%edi
  lea    (%r9,%rdx,4),%rdx
  mov    (%rdx),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  mov    (%rdx),%ebx
  lea    0x1(%rax),%esi
  lea    0x2(%rax),%r8d
  mov    %bh,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  sar    $0x10,%esi
  mov    %sil,(%rcx,%r8,1)
  mov    (%rdx),%edx
  lea    0x3(%rax),%esi
  add    $0x4,%eax
  sar    $0x18,%edx
  mov    %dl,(%rcx,%rsi,1)
  cmp    %eax,%r10d
  ja     L1
  pop    %rbx
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
void __md5_Encode(unsigned char *output, u_int32_t *input, unsigned int len) {
  unsigned int i, j;
  for (i = 0, j = 0; j < len; i++, j += 4) {
    output[j] = (unsigned char)(input[i] & 0xff);
    output[j + 1] = (unsigned char)((input[i] >> 8) & 0xff);
    output[j + 2] = (unsigned char)((input[i] >> 16) & 0xff);
    output[j + 3] = (unsigned char)((input[i] >> 24) & 0xff);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__md5_Encode>:
  endbr64
  test   %edx,%edx
  je     L9
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%r9
  mov    %edx,%r10d
  xor    %eax,%eax
  xor    %edi,%edi
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %edi,%edx
  mov    %eax,%esi
  add    $0x1,%edi
  lea    (%r9,%rdx,4),%rdx
  mov    (%rdx),%r8d
  mov    %r8b,(%rcx,%rsi,1)
  mov    (%rdx),%ebx
  lea    0x1(%rax),%esi
  lea    0x2(%rax),%r8d
  mov    %bh,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  sar    $0x10,%esi
  mov    %sil,(%rcx,%r8,1)
  mov    (%rdx),%edx
  lea    0x3(%rax),%esi
  add    $0x4,%eax
  sar    $0x18,%edx
  mov    %dl,(%rcx,%rsi,1)
  cmp    %eax,%r10d
  ja     L3
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void __md5_Encode(unsigned char *output, u_int32_t *input, unsigned int len) {
  unsigned int i, j;
  for (i = 0, j = 0; j < len; i++, j += 4) {
    output[j] = (unsigned char)(input[i] & 0xff);
    output[j + 1] = (unsigned char)((input[i] >> 8) & 0xff);
    output[j + 2] = (unsigned char)((input[i] >> 16) & 0xff);
    output[j + 3] = (unsigned char)((input[i] >> 24) & 0xff);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bcd2_add>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <bin_bcd2@plt>
  mov    0x8(%rsp),%r12
  mov    0x10(%rsp),%r11
  mov    $0xffffffe4,%edi
  mov    $0x0,%esi
  mov    $0x1,%r8d
  mov    $0x0,%edx
  mov    $0xf,%r10d
  movabs $0x6666666666666667,%r9
  jmp    L6
L26:
  mov    %r10d,%r13d
  mov    %esi,%ecx
  shl    %cl,%r13d
  movslq %r13d,%rax
  mov    %rax,%r14
  and    0x0(%rbp),%r14
  sar    %cl,%r14
  and    %r12,%rax
  sar    %cl,%rax
  lea    (%r14,%rax,1),%rcx
  add    %rdx,%rcx
  mov    %rcx,%rax
  imul   %r9
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  xor    $0xfffffff,%r13d
  movslq %r13d,%rax
  and    0x0(%rbp),%rax
  lea    (%rdx,%rdx,4),%r14
  add    %r14,%r14
  sub    %r14,%rcx
  mov    %rcx,%r13
  mov    %esi,%ecx
  shl    %cl,%r13
  or     %r13,%rax
  mov    %rax,0x0(%rbp)
L11:
  add    $0x1,%r8d
  add    $0x4,%esi
  add    $0x4,%edi
L6:
  lea    -0x1(%r8),%eax
  cmp    $0x6,%eax
  jle    L26
  mov    %r10d,%r13d
  mov    %edi,%ecx
  shl    %cl,%r13d
  movslq %r13d,%rax
  mov    %rax,%r14
  and    (%rbx),%r14
  sar    %cl,%r14
  and    %r11,%rax
  sar    %cl,%rax
  lea    (%r14,%rax,1),%rcx
  add    %rdx,%rcx
  mov    %rcx,%rax
  imul   %r9
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  xor    $0xfffffff,%r13d
  movslq %r13d,%rax
  and    (%rbx),%rax
  lea    (%rdx,%rdx,4),%r14
  add    %r14,%r14
  sub    %r14,%rcx
  mov    %rcx,%r13
  mov    %edi,%ecx
  shl    %cl,%r13
  or     %r13,%rax
  mov    %rax,(%rbx)
  cmp    $0xd,%r8d
  jle    L11
  mov    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bcd2_add(long *bcd_low, long *bcd_high, long addend) {
  long tmp_lo, tmp_hi, carry, res;
  int digit;
  bin_bcd2(addend, &tmp_lo, &tmp_hi);
  carry = 0;
  for (digit = 0; digit < 14; digit++) {
    res = ((digit) >= 7) ? (*bcd_high & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (*bcd_low & (0xF << (4 * (digit)))) >> ((digit)*4);
    res += ((digit) >= 7) ? (tmp_hi & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (tmp_lo & (0xF << (4 * (digit)))) >> ((digit)*4);
    res += carry;
    carry = res / 10;
    res %= 10;
    if ((digit) >= 7) {
      *bcd_high &= (0xFFFFFFF ^ (0xF << (4 * ((digit)-7))));
      *bcd_high |= (res << (4 * ((digit)-7)));
    } else {
      *bcd_low = (*bcd_low & (0xFFFFFFF ^ (0xF << (4 * (digit)))));
      *bcd_low |= (res << (4 * (digit)));
    };
  }
  return (carry);
}
```
user: What is the c source code of the assembly code below?

```asm
<bcd2_add>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <bin_bcd2@plt>
  mov    0x8(%rsp),%r13
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    0x10(%rsp),%r12
  xor    %edx,%edx
  mov    $0xf,%r11d
  movabs $0xcccccccccccccccd,%r10
  jmp    L33
  nopl   0x0(%rax)
L28:
  lea    -0x1c(%r8),%ecx
  mov    %r11d,%edi
  mov    (%rbx),%rsi
  shl    %cl,%edi
  movslq %edi,%rax
  xor    $0xfffffff,%edi
  and    %rax,%rsi
  and    %r12,%rax
  movslq %edi,%rdi
  and    (%rbx),%rdi
  sar    %cl,%rax
  sar    %cl,%rsi
  add    %rax,%rsi
  add    %rdx,%rsi
  mov    %rsi,%rax
  mul    %r10
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rsi
  shl    %cl,%rsi
  or     %rsi,%rdi
  mov    %rdi,(%rbx)
  cmp    $0xe,%r9d
  je     L22
L31:
  add    $0x4,%r8d
  mov    %r9d,%eax
L33:
  lea    0x1(%rax),%r9d
  cmp    $0x6,%eax
  ja     L28
  mov    %r8d,%ecx
  mov    %r11d,%esi
  mov    0x0(%rbp),%rdi
  shl    %cl,%esi
  movslq %esi,%rax
  xor    $0xfffffff,%esi
  and    %rax,%rdi
  and    %r13,%rax
  movslq %esi,%rsi
  and    0x0(%rbp),%rsi
  sar    %cl,%rdi
  sar    %cl,%rax
  lea    (%rdi,%rax,1),%rcx
  add    %rdx,%rcx
  mov    %rcx,%rax
  mul    %r10
  mov    %rcx,%rax
  mov    %r8d,%ecx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rdi
  add    %rdi,%rdi
  sub    %rdi,%rax
  shl    %cl,%rax
  or     %rax,%rsi
  mov    %rsi,0x0(%rbp)
  jmp    L31
  nopl   (%rax)
L22:
  mov    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bcd2_add(long *bcd_low, long *bcd_high, long addend) {
  long tmp_lo, tmp_hi, carry, res;
  int digit;
  bin_bcd2(addend, &tmp_lo, &tmp_hi);
  carry = 0;
  for (digit = 0; digit < 14; digit++) {
    res = ((digit) >= 7) ? (*bcd_high & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (*bcd_low & (0xF << (4 * (digit)))) >> ((digit)*4);
    res += ((digit) >= 7) ? (tmp_hi & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (tmp_lo & (0xF << (4 * (digit)))) >> ((digit)*4);
    res += carry;
    carry = res / 10;
    res %= 10;
    if ((digit) >= 7) {
      *bcd_high &= (0xFFFFFFF ^ (0xF << (4 * ((digit)-7))));
      *bcd_high |= (res << (4 * ((digit)-7)));
    } else {
      *bcd_low = (*bcd_low & (0xFFFFFFF ^ (0xF << (4 * (digit)))));
      *bcd_low |= (res << (4 * (digit)));
    };
  }
  return (carry);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bcd2_add>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <bin_bcd2@plt>
  mov    0x8(%rsp),%r13
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    0x10(%rsp),%r12
  xor    %edx,%edx
  mov    $0xf,%r11d
  movabs $0xcccccccccccccccd,%r10
  jmp    L26
  nopl   0x0(%rax)
L30:
  lea    -0x1c(%r8),%ecx
  mov    %r11d,%edi
  mov    (%rbx),%rsi
  shl    %cl,%edi
  movslq %edi,%rax
  xor    $0xfffffff,%edi
  and    %rax,%rsi
  and    %r12,%rax
  movslq %edi,%rdi
  and    (%rbx),%rdi
  sar    %cl,%rax
  sar    %cl,%rsi
  add    %rax,%rsi
  add    %rdx,%rsi
  mov    %rsi,%rax
  mul    %r10
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rsi
  shl    %cl,%rsi
  or     %rsi,%rdi
  mov    %rdi,(%rbx)
  cmp    $0xe,%r9d
  je     L33
L16:
  add    $0x4,%r8d
  mov    %r9d,%eax
L26:
  lea    0x1(%rax),%r9d
  cmp    $0x6,%eax
  ja     L30
  mov    %r8d,%ecx
  mov    %r11d,%esi
  mov    0x0(%rbp),%rdi
  shl    %cl,%esi
  movslq %esi,%rax
  xor    $0xfffffff,%esi
  and    %rax,%rdi
  and    %r13,%rax
  movslq %esi,%rsi
  and    0x0(%rbp),%rsi
  sar    %cl,%rdi
  sar    %cl,%rax
  lea    (%rdi,%rax,1),%rcx
  add    %rdx,%rcx
  mov    %rcx,%rax
  mul    %r10
  mov    %rcx,%rax
  mov    %r8d,%ecx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rdi
  add    %rdi,%rdi
  sub    %rdi,%rax
  shl    %cl,%rax
  or     %rax,%rsi
  mov    %rsi,0x0(%rbp)
  jmp    L16
  nopl   (%rax)
L33:
  mov    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bcd2_add(long *bcd_low, long *bcd_high, long addend) {
  long tmp_lo, tmp_hi, carry, res;
  int digit;
  bin_bcd2(addend, &tmp_lo, &tmp_hi);
  carry = 0;
  for (digit = 0; digit < 14; digit++) {
    res = ((digit) >= 7) ? (*bcd_high & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (*bcd_low & (0xF << (4 * (digit)))) >> ((digit)*4);
    res += ((digit) >= 7) ? (tmp_hi & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (tmp_lo & (0xF << (4 * (digit)))) >> ((digit)*4);
    res += carry;
    carry = res / 10;
    res %= 10;
    if ((digit) >= 7) {
      *bcd_high &= (0xFFFFFFF ^ (0xF << (4 * ((digit)-7))));
      *bcd_high |= (res << (4 * ((digit)-7)));
    } else {
      *bcd_low = (*bcd_low & (0xFFFFFFF ^ (0xF << (4 * (digit)))));
      *bcd_low |= (res << (4 * (digit)));
    };
  }
  return (carry);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<recv_wrapper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <set_socket_blocking_enabled@plt>
  nop
L2:
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L2
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <set_socket_blocking_enabled@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int recv_wrapper(int sock, void *recv_data, int len, int flag) {
  int rv = -1;
  set_socket_blocking_enabled(sock, 0);
  while ((rv = recv(sock, recv_data, len, flag)) < 0)
    ;
  set_socket_blocking_enabled(sock, 1);
  return rv;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<recv_wrapper>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %ecx,%r12d
  mov    $0x0,%esi
  call   <set_socket_blocking_enabled@plt>
L2:
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L2
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <set_socket_blocking_enabled@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int recv_wrapper(int sock, void *recv_data, int len, int flag) {
  int rv = -1;
  set_socket_blocking_enabled(sock, 0);
  while ((rv = recv(sock, recv_data, len, flag)) < 0)
    ;
  set_socket_blocking_enabled(sock, 1);
  return rv;
}
```
user: What is the c source code of the assembly code below:

```asm
<recv_wrapper>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  xor    %esi,%esi
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <set_socket_blocking_enabled@plt>
  nopl   (%rax)
L7:
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L7
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <set_socket_blocking_enabled@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int recv_wrapper(int sock, void *recv_data, int len, int flag) {
  int rv = -1;
  set_socket_blocking_enabled(sock, 0);
  while ((rv = recv(sock, recv_data, len, flag)) < 0)
    ;
  set_socket_blocking_enabled(sock, 1);
  return rv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recv_wrapper>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  xor    %esi,%esi
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <set_socket_blocking_enabled@plt>
  nopl   (%rax)
L1:
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L1
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <set_socket_blocking_enabled@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int recv_wrapper(int sock, void *recv_data, int len, int flag) {
  int rv = -1;
  set_socket_blocking_enabled(sock, 0);
  while ((rv = recv(sock, recv_data, len, flag)) < 0)
    ;
  set_socket_blocking_enabled(sock, 1);
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<splitline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L6
L27:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <splitnext@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x24(%rbp)
L6:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L27
L19:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L39
  mov    $0x0,%eax
  jmp    L10
L39:
  mov    -0x24(%rbp),%eax
L10:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int splitline(char **argv, int max, char *line) {
  char *s;
  int i = 0;
  s = line;
  while (*s && i < max) {
    argv[i] = splitnext(&s);
    i++;
  }
  if (!argv[0])
    return (0);
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<splitline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdx,(%rsp)
  cmpb   $0x0,(%rdx)
  je     L39
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L39
  mov    $0x1,%ebx
  mov    %rsp,%r13
L2:
  mov    %r13,%rdi
  call   <splitnext@plt>
  mov    %rax,-0x8(%rbp,%rbx,8)
  mov    %ebx,%ecx
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  setne  %dl
  cmp    %ebx,%r12d
  setg   %al
  add    $0x1,%rbx
  test   %al,%dl
  jne    L2
L8:
  cmpq   $0x0,0x0(%rbp)
  mov    $0x0,%eax
  cmove  %eax,%ecx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    %ecx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    $0x0,%ecx
  jmp    L8
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int splitline(char **argv, int max, char *line) {
  char *s;
  int i = 0;
  s = line;
  while (*s && i < max) {
    argv[i] = splitnext(&s);
    i++;
  }
  if (!argv[0])
    return (0);
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<splitline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  mov    %rdx,(%rsp)
  je     L46
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L46
  mov    $0x1,%ebx
  mov    %rsp,%r13
  nopl   0x0(%rax)
L16:
  mov    %r13,%rdi
  call   <splitnext@plt>
  mov    %ebx,%r8d
  mov    %rax,-0x8(%rbp,%rbx,8)
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  setne  %dl
  cmp    %ebx,%r12d
  setg   %al
  add    $0x1,%rbx
  test   %al,%dl
  jne    L16
L41:
  xor    %eax,%eax
  cmpq   $0x0,0x0(%rbp)
  cmove  %eax,%r8d
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L46:
  xor    %r8d,%r8d
  jmp    L41
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int splitline(char **argv, int max, char *line) {
  char *s;
  int i = 0;
  s = line;
  while (*s && i < max) {
    argv[i] = splitnext(&s);
    i++;
  }
  if (!argv[0])
    return (0);
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<splitline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  mov    %rdx,(%rsp)
  je     L38
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L38
  mov    $0x1,%ebx
  mov    %rsp,%r13
  nopl   0x0(%rax)
L45:
  mov    %r13,%rdi
  call   <splitnext@plt>
  mov    %ebx,%r8d
  mov    %rax,-0x8(%rbp,%rbx,8)
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  setne  %dl
  cmp    %ebx,%r12d
  setg   %al
  add    $0x1,%rbx
  test   %al,%dl
  jne    L45
L36:
  xor    %eax,%eax
  cmpq   $0x0,0x0(%rbp)
  cmove  %eax,%r8d
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L38:
  xor    %r8d,%r8d
  jmp    L36
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int splitline(char **argv, int max, char *line) {
  char *s;
  int i = 0;
  s = line;
  while (*s && i < max) {
    argv[i] = splitnext(&s);
    i++;
  }
  if (!argv[0])
    return (0);
  return i;
}
```