ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%r12
  push   %rbp
  lea    D35(%rip),%rbp
  push   %rbx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  lea    0x8(%rsp),%rbx
  nopl   (%rax)
L6:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x4e,%eax
  ja     L6
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <leVETOR@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <encontrakVETOR@plt>
  mov    0xc(%rsp),%esi
  lea    D30(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x160,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D35
type_guessed: string
name: extract_symbolic_data
arguments: label: D27
type_guessed: string
name: extract_symbolic_data
arguments: label: D30
type_guessed: string

tool: D29: Introduza o n de inteiros a ler: 

tool: D35: %d

tool: D27: Introduza o k a procurar: 

tool: D30: Existe %d na posicao %d


assistant: ```c
int main() {
  int vetor[80], n = 0, k;
  do {
    printf("Introduza o n de inteiros a ler: ");
    scanf("%d", &n);
  } while (n < 1 || n >= 80);
  printf("Introduza o k a procurar: ");
  scanf("%d", &k);
  leVETOR(vetor, n);
  printf("Existe %d na posicao %d\n", k, encontrakVETOR(vetor, n, k));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  lea    D33(%rip),%rbp
  push   %rbx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  lea    0x8(%rsp),%rbx
  nopl   (%rax)
L11:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x4e,%eax
  ja     L11
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <leVETOR@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <encontrakVETOR@plt>
  mov    0xc(%rsp),%esi
  lea    D34(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x160,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D33
type_infered: string
name: parse_data
arguments: data_label: D26
type_infered: string
name: parse_data
arguments: data_label: D34
type_infered: string

tool: D14: Introduza o n de inteiros a ler: 

tool: D33: %d

tool: D26: Introduza o k a procurar: 

tool: D34: Existe %d na posicao %d


assistant: ```c
int main() {
  int vetor[80], n = 0, k;
  do {
    printf("Introduza o n de inteiros a ler: ");
    scanf("%d", &n);
  } while (n < 1 || n >= 80);
  printf("Introduza o k a procurar: ");
  scanf("%d", &k);
  leVETOR(vetor, n);
  printf("Existe %d na posicao %d\n", k, encontrakVETOR(vetor, n, k));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_scaling_basis_TRI>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,%r13d
  movq   %xmm0,%r15
  mov    %rdx,%r14
  mov    %rcx,%r12
  mov    %r8,%rbp
  mov    %edi,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,(%rsp)
  addsd  %xmm0,%xmm0
  addsd  D36(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mulsd  D46(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  call   <sqrt@plt>
  movsd  %xmm0,(%r14)
  movsd  0x8(%rsp),%xmm1
  movsd  D24(%rip),%xmm0
  call   <pow@plt>
  lea    (%rbx,%r13,1),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  D36(%rip),%xmm0
  mov    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rdi
  call   <sqrt@plt>
  movsd  %xmm0,(%r12)
  movsd  D36(%rip),%xmm0
  movq   %r15,%xmm3
  subsd  %xmm3,%xmm0
  movsd  (%rsp),%xmm1
  call   <pow@plt>
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D36
type_infered: f64
name: read_data
arguments: data_label: D46
type_infered: byte[8]
name: read_data
arguments: data_label: D24
type_infered: f64

tool: D36: 1

tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D24: 2

assistant: ```c
void get_scaling_basis_TRI(const unsigned int i, const unsigned int j, const double b, double *con_i, double *con_j, double *con_b) {
  *con_i = sqrt((2.0 * i + 1.0) / 2.0);
  *con_j = sqrt((i + j + 1.0) / pow(2.0, 2.0 * i + 1.0));
  *con_b = pow(1.0 - b, (double)i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_scaling_basis_TRI>:
  endbr64
  mov    %edi,%eax
  pxor   %xmm2,%xmm2
  push   %r14
  mov    %rdx,%r14
  cvtsi2sd %rax,%xmm2
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rax,%rbx
  movapd %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  sub    $0x20,%rsp
  addsd  D22(%rip),%xmm1
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm3
  movsd  %xmm1,0x10(%rsp)
  mulsd  D35(%rip),%xmm3
  cvttsd2si %xmm3,%rdi
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm0,(%r14)
  movsd  D43(%rip),%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  lea    (%rbx,%r13,1),%edx
  pxor   %xmm0,%xmm0
  mov    %eax,%eax
  cvtsi2sd %rdx,%xmm0
  addsd  D22(%rip),%xmm0
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rdi
  call   <sqrt@plt>
  movsd  D22(%rip),%xmm4
  subsd  0x8(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm2
  movsd  %xmm0,(%r12)
  movapd %xmm2,%xmm1
  movapd %xmm4,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  mov    %eax,%eax
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D35
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D43
type_guessed: f64

tool: D22: 1

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D43: 2

assistant: ```c
void get_scaling_basis_TRI(const unsigned int i, const unsigned int j, const double b, double *con_i, double *con_j, double *con_b) {
  *con_i = sqrt((2.0 * i + 1.0) / 2.0);
  *con_j = sqrt((i + j + 1.0) / pow(2.0, 2.0 * i + 1.0));
  *con_b = pow(1.0 - b, (double)i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_scaling_basis_TRI>:
  endbr64
  mov    %edi,%eax
  pxor   %xmm2,%xmm2
  push   %r14
  mov    %rdx,%r14
  cvtsi2sd %rax,%xmm2
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rax,%rbx
  movapd %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  sub    $0x20,%rsp
  addsd  D8(%rip),%xmm1
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm3
  movsd  %xmm1,0x10(%rsp)
  mulsd  D37(%rip),%xmm3
  cvttsd2si %xmm3,%rdi
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm0,(%r14)
  movsd  D32(%rip),%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  lea    (%rbx,%r13,1),%edx
  pxor   %xmm0,%xmm0
  mov    %eax,%eax
  cvtsi2sd %rdx,%xmm0
  addsd  D8(%rip),%xmm0
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rdi
  call   <sqrt@plt>
  movsd  D8(%rip),%xmm4
  subsd  0x8(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm2
  movsd  %xmm0,(%r12)
  movapd %xmm2,%xmm1
  movapd %xmm4,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  mov    %eax,%eax
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: f64
name: read_data
arguments: data_label: D37
type_guessed: byte[8]
name: read_data
arguments: data_label: D32
type_guessed: f64

tool: D8: 1

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D32: 2

assistant: ```c
void get_scaling_basis_TRI(const unsigned int i, const unsigned int j, const double b, double *con_i, double *con_j, double *con_b) {
  *con_i = sqrt((2.0 * i + 1.0) / 2.0);
  *con_j = sqrt((i + j + 1.0) / pow(2.0, 2.0 * i + 1.0));
  *con_b = pow(1.0 - b, (double)i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L10:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %ebx,%ecx
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L8:
  cmpl   $0x9,-0x14(%rbp)
  jle    L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: %d %d %d 


assistant: ```c
main() {
  int i;
  for (i = 0; i < 10; i++)
    printf("%d %d %d \n", i, power(2, i), power(-3, i));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L8:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %eax,%ebp
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,%edx
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L8
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: %d %d %d 


assistant: ```c
main() {
  int i;
  for (i = 0; i < 10; i++)
    printf("%d %d %d \n", i, power(2, i), power(-3, i));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L7:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %ebx,%esi
  mov    $0x2,%edi
  mov    %eax,%r12d
  call   <power@plt>
  mov    %ebx,%esi
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: %d %d %d 


assistant: ```c
main() {
  int i;
  for (i = 0; i < 10; i++)
    printf("%d %d %d \n", i, power(2, i), power(-3, i));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L4:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %ebx,%esi
  mov    $0x2,%edi
  mov    %eax,%r12d
  call   <power@plt>
  mov    %ebx,%esi
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: %d %d %d 


assistant: ```c
main() {
  int i;
  for (i = 0; i < 10; i++)
    printf("%d %d %d \n", i, power(2, i), power(-3, i));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: 


assistant: ```c
void foo(int y) {
  print_int(y);
  print_string("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  call   <print_int@plt>
  lea    D4(%rip),%rdi
  call   <print_string@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: 


assistant: ```c
void foo(int y) {
  print_int(y);
  print_string("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  call   <print_int@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <print_string@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: 


assistant: ```c
void foo(int y) {
  print_int(y);
  print_string("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  call   <print_int@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <print_string@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: 


assistant: ```c
void foo(int y) {
  print_int(y);
  print_string("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTFIFOLevelGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xa,%eax
  cltq
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0xb,%eax
  cltq
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTFIFOLevelGet(uint32_t ui32Base, uint32_t *pui32TxLevel, uint32_t *pui32RxLevel) {
  ;
  *pui32TxLevel = ((*((volatile uint16_t *)(ui32Base + 0xA))) & 0x1F00) >> 8;
  *pui32RxLevel = ((*((volatile uint16_t *)(ui32Base + 0xB))) & 0x1F00) >> 8;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<UARTFIFOLevelGet>:
  endbr64
  lea    0xa(%rdi),%eax
  cltq
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  mov    %eax,(%rsi)
  add    $0xb,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void UARTFIFOLevelGet(uint32_t ui32Base, uint32_t *pui32TxLevel, uint32_t *pui32RxLevel) {
  ;
  *pui32TxLevel = ((*((volatile uint16_t *)(ui32Base + 0xA))) & 0x1F00) >> 8;
  *pui32RxLevel = ((*((volatile uint16_t *)(ui32Base + 0xB))) & 0x1F00) >> 8;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<UARTFIFOLevelGet>:
  endbr64
  lea    0xa(%rdi),%eax
  add    $0xb,%edi
  cltq
  movslq %edi,%rdi
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  mov    %eax,(%rsi)
  mov    (%rdi),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void UARTFIFOLevelGet(uint32_t ui32Base, uint32_t *pui32TxLevel, uint32_t *pui32RxLevel) {
  ;
  *pui32TxLevel = ((*((volatile uint16_t *)(ui32Base + 0xA))) & 0x1F00) >> 8;
  *pui32RxLevel = ((*((volatile uint16_t *)(ui32Base + 0xB))) & 0x1F00) >> 8;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<UARTFIFOLevelGet>:
  endbr64
  lea    0xa(%rdi),%eax
  add    $0xb,%edi
  cltq
  movslq %edi,%rdi
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  mov    %eax,(%rsi)
  mov    (%rdi),%eax
  sar    $0x8,%eax
  and    $0x1f,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void UARTFIFOLevelGet(uint32_t ui32Base, uint32_t *pui32TxLevel, uint32_t *pui32RxLevel) {
  ;
  *pui32TxLevel = ((*((volatile uint16_t *)(ui32Base + 0xA))) & 0x1F00) >> 8;
  *pui32RxLevel = ((*((volatile uint16_t *)(ui32Base + 0xB))) & 0x1F00) >> 8;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L1
L25:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L25
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D23
data_type: string
name: unpack_data
arguments: tag: D24
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string

tool: D23: %d

tool: D24: %d


tool: D27: %d%d

assistant: ```c
int main() {
  int T, a, b;
  scanf("%d", &T);
  while (scanf("%d%d", &a, &b) == 2) {
    printf("%d\n", (int)(floor(sqrt(b)) - ceil(sqrt(a)) + 1));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D21(%rip),%rbp
  lea    D25(%rip),%r14
  jmp    L6
L9:
  mov    0x14(%rsp),%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %rax,%rbx
  mov    0x10(%rsp),%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  lea    0x1(%rbx),%esi
  sub    %eax,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L6:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string
name: read_data
arguments: data_tag: D21
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string

tool: D8: %d

tool: D21: %d%d

tool: D25: %d


assistant: ```c
int main() {
  int T, a, b;
  scanf("%d", &T);
  while (scanf("%d%d", &a, &b) == 2) {
    printf("%d\n", (int)(floor(sqrt(b)) - ceil(sqrt(a)) + 1));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%rdi
  lea    D17(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L26:
  mov    0x14(%rsp),%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    0x10(%rsp),%edi
  mov    %rax,%rbx
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  lea    0x1(%rbx),%esi
  mov    %r14,%rdi
  sub    %eax,%esi
  call   <printf@plt>
L0:
  xor    %eax,%eax
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L26
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string
name: unpack_data
arguments: data_label: D17
datatype: string
name: unpack_data
arguments: data_label: D29
datatype: string

tool: D9: %d

tool: D17: %d


tool: D29: %d%d

assistant: ```c
int main() {
  int T, a, b;
  scanf("%d", &T);
  while (scanf("%d%d", &a, &b) == 2) {
    printf("%d\n", (int)(floor(sqrt(b)) - ceil(sqrt(a)) + 1));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D23(%rip),%rdi
  lea    D21(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x14(%rsp),%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    0x10(%rsp),%edi
  mov    %rax,%rbx
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  lea    0x1(%rbx),%esi
  mov    %r14,%rdi
  sub    %eax,%esi
  call   <printf@plt>
L20:
  xor    %eax,%eax
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L7
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D23
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string

tool: D23: %d

tool: D21: %d


tool: D26: %d%d

assistant: ```c
int main() {
  int T, a, b;
  scanf("%d", &T);
  while (scanf("%d%d", &a, &b) == 2) {
    printf("%d\n", (int)(floor(sqrt(b)) - ceil(sqrt(a)) + 1));
  }
  return 0;
}
```