ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<big_or_little_endian_int>:
  endbr64
  test   %esi,%esi
  jne    L9
  jmp    1060 <mus_char_to_bint@plt>
  nopl   (%rax)
L9:
  jmp    1070 <mus_char_to_lint@plt>
```

assistant: ```c
int big_or_little_endian_int(const unsigned char *n, int little) {
  if (little)
    return (mus_char_to_lint(n));
  return (mus_char_to_bint(n));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x68(%rbp)
  jmp    L75
L5:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x68(%rbp)
L75:
  cmpl   $0x9,-0x68(%rbp)
  jle    L5
  movl   $0x0,-0x64(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L44
L34:
  mov    -0x68(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L37
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  mov    -0x64(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x64(%rbp)
L37:
  addl   $0x1,-0x68(%rbp)
L44:
  cmpl   $0x9,-0x68(%rbp)
  jle    L34
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L72
L18:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L72:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
data_type: string
name: parse_data
arguments: data_label: D37
data_type: string
name: parse_data
arguments: data_label: D33
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string

tool: D16: Inserisci un numero: 

tool: D37: %d

tool: D33: I numeri pari sono: 

tool: D4: %d 

assistant: ```c
int main() {
  int I;
  int vet[10];
  int pari[10];
  int K;
  for (I = 0; I < 10; I++) {
    printf("Inserisci un numero: ");
    scanf("%d", &vet[I]);
  }
  K = 0;
  for (I = 0; I < 10; I++) {
    pari[I] = 0;
    if (vet[I] % 2 == 0) {
      pari[K] = vet[I];
      K++;
    }
  }
  printf("I numeri pari sono: ");
  for (I = 0; I < K; I++) {
    printf("%d ", pari[I]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r13
  lea    D26(%rip),%r12
  lea    D37(%rip),%rbp
L31:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L31
  mov    $0x0,%eax
  mov    $0x0,%ebp
  jmp    L60
L51:
  add    $0x4,%rax
  cmp    $0x28,%rax
  je     L15
L60:
  movl   $0x0,0x30(%rsp,%rax,1)
  mov    (%rsp,%rax,1),%edx
  test   $0x1,%dl
  jne    L51
  movslq %ebp,%rcx
  mov    %edx,0x30(%rsp,%rcx,4)
  add    $0x1,%ebp
  jmp    L51
L15:
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L16
  lea    0x30(%rsp),%rbx
  lea    -0x1(%rbp),%eax
  lea    0x34(%rsp,%rax,4),%r12
  lea    D14(%rip),%rbp
L12:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L12
L16:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D26
datatype: string
name: disassemble_data
arguments: data_label: D37
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: string
name: disassemble_data
arguments: data_label: D14
datatype: string

tool: D26: Inserisci un numero: 

tool: D37: %d

tool: D27: I numeri pari sono: 

tool: D14: %d 

assistant: ```c
int main() {
  int I;
  int vet[10];
  int pari[10];
  int K;
  for (I = 0; I < 10; I++) {
    printf("Inserisci un numero: ");
    scanf("%d", &vet[I]);
  }
  K = 0;
  for (I = 0; I < 10; I++) {
    pari[I] = 0;
    if (vet[I] % 2 == 0) {
      pari[K] = vet[I];
      K++;
    }
  }
  printf("I numeri pari sono: ");
  for (I = 0; I < K; I++) {
    printf("%d ", pari[I]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  lea    D33(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x28(%rsp),%r14
  mov    %r12,%rbx
  nopl   0x0(%rax)
L18:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r14,%rbx
  jne    L18
  xor    %eax,%eax
  xor    %ebp,%ebp
  lea    0x30(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L23:
  mov    (%r12,%rax,1),%edx
  movl   $0x0,(%rax,%rbx,1)
  test   $0x1,%dl
  jne    L24
  movslq %ebp,%rcx
  add    $0x1,%ebp
  mov    %edx,0x30(%rsp,%rcx,4)
L24:
  add    $0x4,%rax
  cmp    $0x28,%rax
  jne    L23
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L42
  lea    -0x1(%rbp),%eax
  lea    D39(%rip),%rbp
  lea    0x34(%rsp,%rax,4),%r12
  nopl   (%rax)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
L42:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D33
data_type: string
name: unpack_data
arguments: label: D37
data_type: string
name: unpack_data
arguments: label: D39
data_type: string

tool: D12: Inserisci un numero: 

tool: D33: %d

tool: D37: I numeri pari sono: 

tool: D39: %d 

assistant: ```c
int main() {
  int I;
  int vet[10];
  int pari[10];
  int K;
  for (I = 0; I < 10; I++) {
    printf("Inserisci un numero: ");
    scanf("%d", &vet[I]);
  }
  K = 0;
  for (I = 0; I < 10; I++) {
    pari[I] = 0;
    if (vet[I] % 2 == 0) {
      pari[K] = vet[I];
      K++;
    }
  }
  printf("I numeri pari sono: ");
  for (I = 0; I < K; I++) {
    printf("%d ", pari[I]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L0:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void printchar(char **str, int c) {
  extern int putchar(int c);
  if (str) {
    **str = c;
    ++(*str);
  } else
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printchar>:
  endbr64
  test   %rdi,%rdi
  je     L2
  mov    (%rdi),%rax
  mov    %sil,(%rax)
  addq   $0x1,(%rdi)
L2:
  ret
```

assistant: ```c
void printchar(char **str, int c) {
  extern int putchar(int c);
  if (str) {
    **str = c;
    ++(*str);
  } else
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printchar>:
  endbr64
  test   %rdi,%rdi
  je     L6
  mov    (%rdi),%rax
  mov    %sil,(%rax)
  addq   $0x1,(%rdi)
L6:
  ret
```

assistant: ```c
void printchar(char **str, int c) {
  extern int putchar(int c);
  if (str) {
    **str = c;
    ++(*str);
  } else
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printchar>:
  endbr64
  test   %rdi,%rdi
  je     L4
  mov    (%rdi),%rax
  mov    %sil,(%rax)
  addq   $0x1,(%rdi)
L4:
  ret
```

assistant: ```c
void printchar(char **str, int c) {
  extern int putchar(int c);
  if (str) {
    **str = c;
    ++(*str);
  } else
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<odwrocona>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x31,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x34,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movb   $0x31,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
*odwrocona(int a) {
  char *znaki = malloc(4);
  znaki[0] = '0';
  znaki[1] = '1';
  znaki[2] = '4';
  znaki[3] = '1';
  return znaki;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<odwrocona>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movb   $0x30,(%rax)
  movb   $0x31,0x1(%rax)
  movb   $0x34,0x2(%rax)
  movb   $0x31,0x3(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
*odwrocona(int a) {
  char *znaki = malloc(4);
  znaki[0] = '0';
  znaki[1] = '1';
  znaki[2] = '4';
  znaki[3] = '1';
  return znaki;
}
```
user: What is the c source code of the assembly code below:

```asm
<odwrocona>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x31343130,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
*odwrocona(int a) {
  char *znaki = malloc(4);
  znaki[0] = '0';
  znaki[1] = '1';
  znaki[2] = '4';
  znaki[3] = '1';
  return znaki;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<odwrocona>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x31343130,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
*odwrocona(int a) {
  char *znaki = malloc(4);
  znaki[0] = '0';
  znaki[1] = '1';
  znaki[2] = '4';
  znaki[3] = '1';
  return znaki;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<child_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movl   $0x186a0,-0x30(%rbp)
L8:
  mov    D3(%rip),%rax
  mov    (%rax),%ebx
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <kill@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  jmp    L8
```

assistant: ```c
void child_main() {
  struct timespec ts;
  ts.tv_sec = 0;
  ts.tv_nsec = 100000;
  while (1) {
    kill(getppid(), SIGUSR1);
    nanosleep(&ts, NULL);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<child_main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movl   $0x186a0,(%rsp)
  mov    D8(%rip),%rbp
L1:
  mov    0x0(%rbp),%ebx
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <kill@plt>
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  jmp    L1
```

assistant: ```c
void child_main() {
  struct timespec ts;
  ts.tv_sec = 0;
  ts.tv_nsec = 100000;
  while (1) {
    kill(getppid(), SIGUSR1);
    nanosleep(&ts, NULL);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<child_main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    D1(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x186a0,(%rsp)
  mov    %rsp,%rbx
  movq   $0x0,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    (%r12),%ebp
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <kill@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  jmp    L8
```

assistant: ```c
void child_main() {
  struct timespec ts;
  ts.tv_sec = 0;
  ts.tv_nsec = 100000;
  while (1) {
    kill(getppid(), SIGUSR1);
    nanosleep(&ts, NULL);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<child_main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    D8(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x186a0,(%rsp)
  mov    %rsp,%rbx
  movq   $0x0,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    (%r12),%ebp
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <kill@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  jmp    L6
```

assistant: ```c
void child_main() {
  struct timespec ts;
  ts.tv_sec = 0;
  ts.tv_nsec = 100000;
  while (1) {
    kill(getppid(), SIGUSR1);
    nanosleep(&ts, NULL);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L13
L40:
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L40
L22:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chomp(char *s) {
  while (*s && *s != '\n' && *s != '\r' && *s != '_' && *s != '"' && *s != '\'')
    s++;
  *s = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<chomp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
  movabs $0x2000000000000021,%rdx
  cmp    $0xa,%al
  jne    L50
L15:
  movb   $0x0,(%rdi)
  ret
L28:
  bt     %rax,%rdx
  jb     L15
L61:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
  cmp    $0xa,%al
  je     L15
L50:
  cmp    $0xd,%al
  je     L15
  sub    $0x22,%eax
  cmp    $0x3d,%al
  jbe    L28
  jmp    L61
```

assistant: ```c
void chomp(char *s) {
  while (*s && *s != '\n' && *s != '\r' && *s != '_' && *s != '"' && *s != '\'')
    s++;
  *s = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<chomp>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xa,%al
  je     L57
  movabs $0x2000000000000021,%rdx
  test   %al,%al
  jne    L6
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L34:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L57
  cmp    $0xa,%al
  je     L57
L6:
  cmp    $0xd,%al
  je     L57
  sub    $0x22,%eax
  cmp    $0x3d,%al
  ja     L34
  bt     %rax,%rdx
  jae    L34
L57:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void chomp(char *s) {
  while (*s && *s != '\n' && *s != '\r' && *s != '_' && *s != '"' && *s != '\'')
    s++;
  *s = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<chomp>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xa,%al
  je     L22
  movabs $0x2000000000000021,%rdx
  test   %al,%al
  jne    L57
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L10:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L22
  cmp    $0xa,%al
  je     L22
L57:
  cmp    $0xd,%al
  je     L22
  sub    $0x22,%eax
  cmp    $0x3d,%al
  ja     L10
  bt     %rax,%rdx
  jae    L10
L22:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void chomp(char *s) {
  while (*s && *s != '\n' && *s != '\r' && *s != '_' && *s != '"' && *s != '\'')
    s++;
  *s = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<u64_to_le>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    $0x20,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    $0x28,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    $0x30,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    $0x38,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void u64_to_le(unsigned char *x, const uint64_t u) {
  x[0] = (unsigned char)u;
  x[1] = (unsigned char)(u >> 8);
  x[2] = (unsigned char)(u >> 16);
  x[3] = (unsigned char)(u >> 24);
  x[4] = (unsigned char)(u >> 32);
  x[5] = (unsigned char)(u >> 40);
  x[6] = (unsigned char)(u >> 48);
  x[7] = (unsigned char)(u >> 56);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<u64_to_le>:
  endbr64
  mov    %esi,%eax
  mov    %sil,(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %dl,0x2(%rdi)
  mov    %esi,%edx
  sar    $0x18,%edx
  mov    %dl,0x3(%rdi)
  mov    %esi,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  mov    %dl,0x4(%rdi)
  mov    %esi,%edx
  mov    $0x28,%ecx
  sar    %cl,%edx
  mov    %dl,0x5(%rdi)
  mov    %esi,%edx
  mov    $0x30,%ecx
  sar    %cl,%edx
  mov    %dl,0x6(%rdi)
  mov    $0x38,%ecx
  sar    %cl,%eax
  mov    %al,0x7(%rdi)
  ret
```

assistant: ```c
void u64_to_le(unsigned char *x, const uint64_t u) {
  x[0] = (unsigned char)u;
  x[1] = (unsigned char)(u >> 8);
  x[2] = (unsigned char)(u >> 16);
  x[3] = (unsigned char)(u >> 24);
  x[4] = (unsigned char)(u >> 32);
  x[5] = (unsigned char)(u >> 40);
  x[6] = (unsigned char)(u >> 48);
  x[7] = (unsigned char)(u >> 56);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<u64_to_le>:
  endbr64
  mov    %esi,%eax
  mov    $0x20,%ecx
  mov    %esi,(%rdi)
  sar    %cl,%eax
  mov    $0x28,%ecx
  mov    %al,0x4(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x30,%ecx
  mov    %al,0x5(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x38,%ecx
  sar    %cl,%esi
  mov    %al,0x6(%rdi)
  mov    %sil,0x7(%rdi)
  ret
```

assistant: ```c
void u64_to_le(unsigned char *x, const uint64_t u) {
  x[0] = (unsigned char)u;
  x[1] = (unsigned char)(u >> 8);
  x[2] = (unsigned char)(u >> 16);
  x[3] = (unsigned char)(u >> 24);
  x[4] = (unsigned char)(u >> 32);
  x[5] = (unsigned char)(u >> 40);
  x[6] = (unsigned char)(u >> 48);
  x[7] = (unsigned char)(u >> 56);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<u64_to_le>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%edx
  push   %rbx
  sar    $0x10,%esi
  sar    $0x8,%ecx
  mov    %edx,%r9d
  mov    %edx,%r10d
  mov    %edx,%r11d
  mov    %ecx,%ebx
  mov    $0x20,%ecx
  mov    %edx,%eax
  mov    %edx,%r8d
  sar    %cl,%r9d
  mov    $0x28,%ecx
  sar    $0x18,%r8d
  movzbl %sil,%esi
  sar    %cl,%r10d
  mov    $0x30,%ecx
  movzbl %r9b,%r9d
  movzbl %r8b,%r8d
  sar    %cl,%r11d
  mov    $0x38,%ecx
  movzbl %r10b,%r10d
  movzbl %dl,%edx
  sar    %cl,%eax
  movzbl %r11b,%r11d
  movzbl %bl,%ecx
  pop    %rbx
  movzbl %al,%eax
  shl    $0x8,%rax
  or     %r11,%rax
  shl    $0x8,%rax
  or     %r10,%rax
  shl    $0x8,%rax
  or     %r9,%rax
  shl    $0x8,%rax
  or     %r8,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void u64_to_le(unsigned char *x, const uint64_t u) {
  x[0] = (unsigned char)u;
  x[1] = (unsigned char)(u >> 8);
  x[2] = (unsigned char)(u >> 16);
  x[3] = (unsigned char)(u >> 24);
  x[4] = (unsigned char)(u >> 32);
  x[5] = (unsigned char)(u >> 40);
  x[6] = (unsigned char)(u >> 48);
  x[7] = (unsigned char)(u >> 56);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ut_size_unicode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0xffffffffffffff80,%rax
  test   %rax,%rax
  jne    L36
  mov    $0x1,%eax
  jmp    L20
L36:
  mov    -0x8(%rbp),%rax
  and    $0xfffffffffffff800,%rax
  test   %rax,%rax
  jne    L42
  mov    $0x2,%eax
  jmp    L20
L42:
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ax
  test   %rax,%rax
  jne    L47
  mov    $0x3,%eax
  jmp    L20
L47:
  cmpq   $0x10ffff,-0x8(%rbp)
  ja     L71
  mov    $0x4,%eax
  jmp    L20
L71:
  mov    $0x0,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int ut_size_unicode(unsigned long unicode) {
  if (!(unicode & ~0x7F)) {
    return 1;
  } else if (!(unicode & ~0x7FF)) {
    return 2;
  } else if (!(unicode & ~0xFFFF)) {
    return 3;
  } else if (unicode <= 0x10FFFF) {
    return 4;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ut_size_unicode>:
  endbr64
  mov    $0x1,%eax
  test   $0xffffffffffffff80,%rdi
  je     L1
  mov    $0x2,%eax
  test   $0xfffffffffffff800,%rdi
  je     L1
  mov    $0x3,%eax
  test   $0xffffffffffff0000,%rdi
  je     L1
  cmp    $0x10ffff,%rdi
  setbe  %al
  movzbl %al,%eax
  shl    $0x2,%eax
L1:
  ret
```

assistant: ```c
int ut_size_unicode(unsigned long unicode) {
  if (!(unicode & ~0x7F)) {
    return 1;
  } else if (!(unicode & ~0x7FF)) {
    return 2;
  } else if (!(unicode & ~0xFFFF)) {
    return 3;
  } else if (unicode <= 0x10FFFF) {
    return 4;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ut_size_unicode>:
  endbr64
  mov    $0x1,%eax
  test   $0xffffffffffffff80,%rdi
  je     L26
  mov    $0x2,%eax
  test   $0xfffffffffffff800,%rdi
  je     L26
  mov    $0x3,%eax
  test   $0xffffffffffff0000,%rdi
  je     L26
  xor    %eax,%eax
  cmp    $0x10ffff,%rdi
  setbe  %al
  shl    $0x2,%eax
L26:
  ret
```

assistant: ```c
int ut_size_unicode(unsigned long unicode) {
  if (!(unicode & ~0x7F)) {
    return 1;
  } else if (!(unicode & ~0x7FF)) {
    return 2;
  } else if (!(unicode & ~0xFFFF)) {
    return 3;
  } else if (unicode <= 0x10FFFF) {
    return 4;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ut_size_unicode>:
  endbr64
  mov    $0x1,%eax
  test   $0xffffffffffffff80,%rdi
  je     L22
  mov    $0x2,%eax
  test   $0xfffffffffffff800,%rdi
  je     L22
  mov    $0x3,%eax
  test   $0xffffffffffff0000,%rdi
  je     L22
  xor    %eax,%eax
  cmp    $0x10ffff,%rdi
  setbe  %al
  shl    $0x2,%eax
L22:
  ret
```

assistant: ```c
int ut_size_unicode(unsigned long unicode) {
  if (!(unicode & ~0x7F)) {
    return 1;
  } else if (!(unicode & ~0x7FF)) {
    return 2;
  } else if (!(unicode & ~0xFFFF)) {
    return 3;
  } else if (unicode <= 0x10FFFF) {
    return 4;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<packi16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void packi16(uint8_t *buf, int16_t i) {
  uint16_t i2 = i;
  *buf++ = i2 >> 8;
  *buf++ = i2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<packi16>:
  endbr64
  mov    %esi,%eax
  sar    $0x8,%eax
  mov    %eax,(%rdi)
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void packi16(uint8_t *buf, int16_t i) {
  uint16_t i2 = i;
  *buf++ = i2 >> 8;
  *buf++ = i2;
}
```