ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<memmove>:
  endbr64
  cmp    %rsi,%rdi
  jbe    L7
  jmp    1060 <__memmove_up@plt>
  xchg   %ax,%ax
L7:
  jmp    1070 <__memmove_down@plt>
```

assistant: ```c
void *(memmove)(void *__dest, __const void *__src, size_t __n) {
  if (__dest > __src)
    return __memmove_up(__dest, __src, __n);
  else
    return __memmove_down(__dest, __src, __n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x10,%eax
  test   %rax,%rax
  je     L38
  mov    -0x10(%rbp),%rax
  and    $0x10,%eax
  test   %rax,%rax
  je     L31
  mov    -0x10(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L63
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L30
L63:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L30
L31:
  mov    -0x10(%rbp),%rax
  and    $0x2,%eax
  test   %rax,%rax
  jne    L30
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L30
L38:
  mov    -0x10(%rbp),%rax
  and    $0x10,%eax
  test   %rax,%rax
  jne    L30
  lea    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0x10(%rbp),%rdx
  add    $0x1,%rdx
  lea    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
L30:
  mov    -0x10(%rbp),%rax
  lea    0x5c2969f6(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy13;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else if (!((state[0UL] >> 1UL) & 1UL)) {
        state[0UL] += state[0UL];
      }
    } else if (!((state[0UL] >> 4UL) & 1UL)) {
      copy13 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = (state[0UL] + 245604622UL) + 1300613352UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  test   $0x10,%al
  je     L13
  lea    (%rax,%rax,1),%rdx
L12:
  add    $0x5c2969f6,%rdx
  mov    %rdx,(%rsi)
  ret
L13:
  movzbl %ah,%ecx
  shl    $0x18,%rcx
  movabs $0xffffffff00ffffff,%rdx
  and    %rax,%rdx
  or     %rcx,%rdx
  sar    $0x18,%eax
  mov    %al,%dh
  jmp    L12
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy13;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else if (!((state[0UL] >> 1UL) & 1UL)) {
        state[0UL] += state[0UL];
      }
    } else if (!((state[0UL] >> 4UL) & 1UL)) {
      copy13 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = (state[0UL] + 245604622UL) + 1300613352UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  sub    $0x99f4bb,%rdx
  test   $0x10,%dl
  je     L3
  lea    (%rdx,%rdx,1),%rax
  add    $0x5c2969f6,%rax
  mov    %rax,(%rsi)
  ret
  nopl   0x0(%rax)
L3:
  movabs $0xffffffff00ffffff,%rax
  movzbl %dh,%ecx
  and    %rdx,%rax
  shl    $0x18,%rcx
  or     %rcx,%rax
  sar    $0x18,%edx
  mov    %dl,%ah
  add    $0x5c2969f6,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy13;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else if (!((state[0UL] >> 1UL) & 1UL)) {
        state[0UL] += state[0UL];
      }
    } else if (!((state[0UL] >> 4UL) & 1UL)) {
      copy13 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = (state[0UL] + 245604622UL) + 1300613352UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  sub    $0x99f4bb,%rdx
  test   $0x10,%dl
  je     L7
  lea    (%rdx,%rdx,1),%rax
  add    $0x5c2969f6,%rax
  mov    %rax,(%rsi)
  ret
  nopl   0x0(%rax)
L7:
  movabs $0xffffffff00ffffff,%rax
  movzbl %dh,%ecx
  and    %rdx,%rax
  shl    $0x18,%rcx
  or     %rcx,%rax
  sar    $0x18,%edx
  mov    %dl,%ah
  add    $0x5c2969f6,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy13;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else if (!((state[0UL] >> 1UL) & 1UL)) {
        state[0UL] += state[0UL];
      }
    } else if (!((state[0UL] >> 4UL) & 1UL)) {
      copy13 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = (state[0UL] + 245604622UL) + 1300613352UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<free_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void free_vector(double *v) {
  if (v) {
    free(v);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_vector>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
void free_vector(double *v) {
  if (v) {
    free(v);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_vector>:
  endbr64
  test   %rdi,%rdi
  je     L8
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void free_vector(double *v) {
  if (v) {
    free(v);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<free_vector>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L3:
  ret
```

assistant: ```c
void free_vector(double *v) {
  if (v) {
    free(v);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Blue2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string

tool: D7:  Hello from Blue2: one = %d, two = %d!
 

assistant: ```c
extern int Blue2(int one, int two) {
  printf(" Hello from Blue2: one = %d, two = %d!\n ", one, two);
  return one + two;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Blue2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4:  Hello from Blue2: one = %d, two = %d!
 

assistant: ```c
extern int Blue2(int one, int two) {
  printf(" Hello from Blue2: one = %d, two = %d!\n ", one, two);
  return one + two;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Blue2>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %esi,%ebp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  lea    D8(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8:  Hello from Blue2: one = %d, two = %d!
 

assistant: ```c
extern int Blue2(int one, int two) {
  printf(" Hello from Blue2: one = %d, two = %d!\n ", one, two);
  return one + two;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Blue2>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %esi,%ebp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  lea    D3(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3:  Hello from Blue2: one = %d, two = %d!
 

assistant: ```c
extern int Blue2(int one, int two) {
  printf(" Hello from Blue2: one = %d, two = %d!\n ", one, two);
  return one + two;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readLine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %edi,(%rsp)
  mov    %rsi,%r14
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r13d
  movl   $0x0,0x4(%rsp)
  mov    $0x0,%ebp
  lea    0x10(%rsp),%r12
  lea    D4(%rip),%r15
  jmp    L73
L72:
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  call   <contains@plt>
  mov    %eax,0x4(%rsp)
  jmp    L43
L44:
  add    $0x1,%r13d
L73:
  mov    $0x0,%ecx
  mov    $0x8b,%edx
  mov    %r12,%rsi
  mov    (%rsp),%edi
  call   <recv@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L103
  mov    %r15,%rdi
  call   <printf@plt>
  movslq %ebp,%rdi
  add    %r14,%rdi
  mov    %ebx,%edx
  mov    %r12,%rsi
  call   <strncpy@plt>
  add    %ebx,%ebp
  test   %r13d,%r13d
  je     L72
L43:
  lea    D31(%rip),%rsi
  mov    %r12,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L103
  movslq %ebp,%rax
  cmpb   $0xa,-0x1(%r14,%rax,1)
  jne    L44
  cmpb   $0xd,-0x2(%r14,%rax,1)
  sete   %al
  cmpl   $0x0,0x4(%rsp)
  jne    L86
  test   %al,%al
  jne    L103
L86:
  cmpl   $0x0,0x4(%rsp)
  je     L44
  test   %al,%al
  je     L44
L103:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  mov    %ebp,(%rax)
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  mov    $0x0,%eax
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D21
type_infered: string
name: extract_symbolic_data
arguments: label: D31
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D4: READ LOOP


tool: D21: POST

tool: D31: www-form-urlencoded

tool: D18: ENDED READ LOOP


assistant: ```c
int readLine(int s, char *line, int *result_size) {
  int acum = 0, size;
  char buffer[139];
  char *post = "POST";
  int flag = 0;
  int i = 0;
  int cont = 0;
  int temp_size;
  while ((size = recv(s, buffer, 139, 0)) > 0) {
    printf("READ LOOP\n");
    if (size < 0)
      break;
    strncpy(line + acum, buffer, size);
    acum += size;
    if (i == 0) {
      flag = contains(buffer, post);
    }
    if (contains(buffer, "www-form-urlencoded")) {
      break;
    }
    if (line[acum - 1] == '\n' && line[acum - 2] == '\r' && !flag) {
      break;
    } else if (line[acum - 1] == '\n' && line[acum - 2] == '\r' && flag) {
      cont = 1;
      temp_size = size;
    }
    if (cont) {
      if (size > temp_size) {
      } else {
        break;
      }
      temp_size = size;
    }
    i++;
  }
  printf("ENDED READ LOOP\n");
  *result_size = acum;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readLine>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xb8,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L98:
  add    $0x1,%r12d
L41:
  xor    %ecx,%ecx
  mov    $0x8b,%edx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  call   <recv@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jle    L55
  lea    D34(%rip),%rdi
  call   <printf@plt>
  movslq %ebx,%rdi
  mov    %r15d,%edx
  mov    %rbp,%rsi
  add    %r13,%rdi
  add    %r15d,%ebx
  call   <strncpy@plt>
  test   %r12d,%r12d
  je     L79
L50:
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L55
  movslq %ebx,%rax
  cmpb   $0xa,-0x1(%r13,%rax,1)
  jne    L98
  mov    0x4(%rsp),%ecx
  cmpb   $0xd,-0x2(%r13,%rax,1)
  sete   %al
  test   %ecx,%ecx
  jne    L31
  test   %al,%al
  jne    L55
  test   %ecx,%ecx
  je     L98
  nopl   (%rax)
L31:
  test   %al,%al
  je     L98
  nopl   0x0(%rax,%rax,1)
L55:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  mov    %ebx,(%rax)
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <contains@plt>
  mov    %eax,0x4(%rsp)
  jmp    L50
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D34
type: string
name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D34: READ LOOP


tool: D13: www-form-urlencoded

tool: D8: ENDED READ LOOP


tool: D6: POST

assistant: ```c
int readLine(int s, char *line, int *result_size) {
  int acum = 0, size;
  char buffer[139];
  char *post = "POST";
  int flag = 0;
  int i = 0;
  int cont = 0;
  int temp_size;
  while ((size = recv(s, buffer, 139, 0)) > 0) {
    printf("READ LOOP\n");
    if (size < 0)
      break;
    strncpy(line + acum, buffer, size);
    acum += size;
    if (i == 0) {
      flag = contains(buffer, post);
    }
    if (contains(buffer, "www-form-urlencoded")) {
      break;
    }
    if (line[acum - 1] == '\n' && line[acum - 2] == '\r' && !flag) {
      break;
    } else if (line[acum - 1] == '\n' && line[acum - 2] == '\r' && flag) {
      cont = 1;
      temp_size = size;
    }
    if (cont) {
      if (size > temp_size) {
      } else {
        break;
      }
      temp_size = size;
    }
    i++;
  }
  printf("ENDED READ LOOP\n");
  *result_size = acum;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readLine>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xb8,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%r12d
L72:
  xor    %ecx,%ecx
  mov    $0x8b,%edx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  call   <recv@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jle    L33
  lea    D2(%rip),%rdi
  call   <printf@plt>
  movslq %ebx,%rdi
  mov    %r15d,%edx
  mov    %rbp,%rsi
  add    %r13,%rdi
  add    %r15d,%ebx
  call   <strncpy@plt>
  test   %r12d,%r12d
  je     L66
L98:
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L33
  movslq %ebx,%rax
  cmpb   $0xa,-0x1(%r13,%rax,1)
  jne    L39
  mov    0x4(%rsp),%ecx
  cmpb   $0xd,-0x2(%r13,%rax,1)
  sete   %al
  test   %ecx,%ecx
  jne    L94
  test   %al,%al
  jne    L33
  test   %ecx,%ecx
  je     L39
  nopl   (%rax)
L94:
  test   %al,%al
  je     L39
  nopl   0x0(%rax,%rax,1)
L33:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  mov    %ebx,(%rax)
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <contains@plt>
  mov    %eax,0x4(%rsp)
  jmp    L98
L103:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string
name: unpack_data
arguments: data_tag: D21
type: string
name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D14
type: string

tool: D2: READ LOOP


tool: D21: www-form-urlencoded

tool: D17: ENDED READ LOOP


tool: D14: POST

assistant: ```c
int readLine(int s, char *line, int *result_size) {
  int acum = 0, size;
  char buffer[139];
  char *post = "POST";
  int flag = 0;
  int i = 0;
  int cont = 0;
  int temp_size;
  while ((size = recv(s, buffer, 139, 0)) > 0) {
    printf("READ LOOP\n");
    if (size < 0)
      break;
    strncpy(line + acum, buffer, size);
    acum += size;
    if (i == 0) {
      flag = contains(buffer, post);
    }
    if (contains(buffer, "www-form-urlencoded")) {
      break;
    }
    if (line[acum - 1] == '\n' && line[acum - 2] == '\r' && !flag) {
      break;
    } else if (line[acum - 1] == '\n' && line[acum - 2] == '\r' && flag) {
      cont = 1;
      temp_size = size;
    }
    if (cont) {
      if (size > temp_size) {
      } else {
        break;
      }
      temp_size = size;
    }
    i++;
  }
  printf("ENDED READ LOOP\n");
  *result_size = acum;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %ecx,%r14d
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%r13
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rbx
  mov    %r9d,%edi
  add    0x0(%r13),%edi
  add    (%rbx),%edi
  mov    %edi,0x0(%r13)
  movslq %r8d,%r8
  lea    0x0(%rbp,%r8,4),%r12
  xor    (%r12),%edi
  mov    $0x20,%esi
  call   <rot_right64@plt>
  mov    %eax,%edi
  mov    %eax,(%r12)
  movslq %r14d,%r14
  lea    0x0(%rbp,%r14,4),%rbp
  add    0x0(%rbp),%edi
  mov    %edi,0x0(%rbp)
  xor    (%rbx),%edi
  mov    $0x18,%esi
  call   <rot_right64@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  add    0x0(%r13),%edi
  add    0x30(%rsp),%edi
  mov    %edi,0x0(%r13)
  xor    (%r12),%edi
  mov    $0x10,%esi
  call   <rot_right64@plt>
  mov    %eax,%edi
  mov    %eax,(%r12)
  add    0x0(%rbp),%edi
  mov    %edi,0x0(%rbp)
  xor    (%rbx),%edi
  mov    $0x3f,%esi
  call   <rot_right64@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mix(uint64_t *v, int a, int b, int c, int d, uint64_t x, uint64_t y) {
  v[a] = v[a] + v[b] + x;
  v[d] = rot_right64((v[d] ^ v[a]), 32);
  v[c] = v[c] + v[d];
  v[b] = rot_right64((v[b] ^ v[c]), 24);
  v[a] = v[a] + v[b] + y;
  v[d] = rot_right64((v[d] ^ v[a]), 16);
  v[c] = v[c] + v[d];
  v[b] = rot_right64((v[b] ^ v[c]), 63);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mix>:
  endbr64
  movslq %esi,%rsi
  push   %r14
  movslq %edx,%rdx
  mov    %rdi,%r14
  push   %r13
  lea    (%rdi,%rsi,4),%r13
  movslq %r8d,%r8
  mov    $0x20,%esi
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  lea    (%r14,%r8,4),%rbp
  lea    (%r14,%r12,4),%r12
  push   %rbx
  lea    (%rdi,%rdx,4),%rbx
  mov    0x0(%r13),%edi
  add    %r9d,%edi
  add    (%rbx),%edi
  mov    %edi,0x0(%r13)
  xor    0x0(%rbp),%edi
  call   <rot_right64@plt>
  mov    $0x18,%esi
  mov    %eax,0x0(%rbp)
  mov    %eax,%edi
  add    (%r12),%edi
  mov    %edi,(%r12)
  xor    (%rbx),%edi
  call   <rot_right64@plt>
  mov    $0x10,%esi
  mov    %eax,(%rbx)
  mov    %eax,%edi
  add    0x0(%r13),%edi
  add    0x30(%rsp),%edi
  mov    %edi,0x0(%r13)
  xor    0x0(%rbp),%edi
  call   <rot_right64@plt>
  mov    $0x3f,%esi
  mov    %eax,0x0(%rbp)
  mov    %eax,%edi
  add    (%r12),%edi
  mov    %edi,(%r12)
  xor    (%rbx),%edi
  call   <rot_right64@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mix(uint64_t *v, int a, int b, int c, int d, uint64_t x, uint64_t y) {
  v[a] = v[a] + v[b] + x;
  v[d] = rot_right64((v[d] ^ v[a]), 32);
  v[c] = v[c] + v[d];
  v[b] = rot_right64((v[b] ^ v[c]), 24);
  v[a] = v[a] + v[b] + y;
  v[d] = rot_right64((v[d] ^ v[a]), 16);
  v[c] = v[c] + v[d];
  v[b] = rot_right64((v[b] ^ v[c]), 63);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mix>:
  endbr64
  movslq %esi,%rsi
  push   %r14
  movslq %edx,%rdx
  mov    %rdi,%r14
  push   %r13
  lea    (%rdi,%rsi,4),%r13
  movslq %r8d,%r8
  mov    $0x20,%esi
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  lea    (%r14,%r8,4),%rbp
  lea    (%r14,%r12,4),%r12
  push   %rbx
  lea    (%rdi,%rdx,4),%rbx
  mov    0x0(%r13),%edi
  add    %r9d,%edi
  add    (%rbx),%edi
  mov    %edi,0x0(%r13)
  xor    0x0(%rbp),%edi
  call   <rot_right64@plt>
  mov    $0x18,%esi
  mov    %eax,0x0(%rbp)
  mov    %eax,%edi
  add    (%r12),%edi
  mov    %edi,(%r12)
  xor    (%rbx),%edi
  call   <rot_right64@plt>
  mov    $0x10,%esi
  mov    %eax,(%rbx)
  mov    %eax,%edi
  add    0x0(%r13),%edi
  add    0x30(%rsp),%edi
  mov    %edi,0x0(%r13)
  xor    0x0(%rbp),%edi
  call   <rot_right64@plt>
  mov    $0x3f,%esi
  mov    %eax,0x0(%rbp)
  mov    %eax,%edi
  add    (%r12),%edi
  mov    %edi,(%r12)
  xor    (%rbx),%edi
  call   <rot_right64@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mix(uint64_t *v, int a, int b, int c, int d, uint64_t x, uint64_t y) {
  v[a] = v[a] + v[b] + x;
  v[d] = rot_right64((v[d] ^ v[a]), 32);
  v[c] = v[c] + v[d];
  v[b] = rot_right64((v[b] ^ v[c]), 24);
  v[a] = v[a] + v[b] + y;
  v[d] = rot_right64((v[d] ^ v[a]), 16);
  v[c] = v[c] + v[d];
  v[b] = rot_right64((v[b] ^ v[c]), 63);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L12
L2:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L12:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L2
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *p = malloc(sizeof(int));
  while (*p >= 0) {
    (*p)--;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    (%rax),%edx
  test   %edx,%edx
  js     L6
L4:
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  jne    L4
  movl   $0xffffffff,(%rax)
L6:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int *p = malloc(sizeof(int));
  while (*p >= 0) {
    (*p)--;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    (%rax),%edx
  test   %edx,%edx
  js     L7
  movl   $0xffffffff,(%rax)
L7:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int *p = malloc(sizeof(int));
  while (*p >= 0) {
    (*p)--;
  }
  return 0;
}
```