ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memory_not_equal_display_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L3
L40:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movzbl -0xe(%rbp),%eax
  cmp    -0xd(%rbp),%al
  jne    L24
  addl   $0x1,-0xc(%rbp)
L24:
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L40
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jne    L11
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <print_error@plt>
  mov    $0x0,%eax
  jmp    L19
L11:
  mov    $0x1,%eax
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d bytes of 0x%08x and 0x%08x the same


assistant: ```c
int memory_not_equal_display_error(const char *const a, const char *const b, const size_t size) {
  int same = 0;
  size_t i;
  for (i = 0; i < size; i++) {
    const char l = a[i];
    const char r = b[i];
    if (l == r) {
      same++;
    }
  }
  if (same == size) {
    print_error("%d bytes of 0x%08x and 0x%08x the same\n", same, a, b);
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memory_not_equal_display_error>:
  endbr64
  test   %rdx,%rdx
  je     L5
  mov    $0x0,%eax
  mov    $0x0,%r8d
L0:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  sete   %r9b
  movzbl %r9b,%r9d
  add    %r9d,%r8d
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L0
  movslq %r8d,%rdx
  cmp    %rax,%rdx
  je     L6
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%r8d
L6:
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  mov    %r8d,%esi
  lea    D2(%rip),%rdi
  call   <print_error@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: %d bytes of 0x%08x and 0x%08x the same


assistant: ```c
int memory_not_equal_display_error(const char *const a, const char *const b, const size_t size) {
  int same = 0;
  size_t i;
  for (i = 0; i < size; i++) {
    const char l = a[i];
    const char r = b[i];
    if (l == r) {
      same++;
    }
  }
  if (same == size) {
    print_error("%d bytes of 0x%08x and 0x%08x the same\n", same, a, b);
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memory_not_equal_display_error>:
  endbr64
  mov    %rsi,%rcx
  test   %rdx,%rdx
  je     L17
  xor    %eax,%eax
  xor    %esi,%esi
L4:
  movzbl (%rcx,%rax,1),%r8d
  xor    %r9d,%r9d
  cmp    %r8b,(%rdi,%rax,1)
  sete   %r9b
  add    $0x1,%rax
  add    %r9d,%esi
  cmp    %rax,%rdx
  jne    L4
  movslq %esi,%rax
  cmp    %rdx,%rax
  je     L14
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %esi,%esi
L14:
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D7(%rip),%rdi
  call   <print_error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: %d bytes of 0x%08x and 0x%08x the same


assistant: ```c
int memory_not_equal_display_error(const char *const a, const char *const b, const size_t size) {
  int same = 0;
  size_t i;
  for (i = 0; i < size; i++) {
    const char l = a[i];
    const char r = b[i];
    if (l == r) {
      same++;
    }
  }
  if (same == size) {
    print_error("%d bytes of 0x%08x and 0x%08x the same\n", same, a, b);
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isNaN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x7ff00000,%eax
  cmp    $0x7ff00000,%rax
  je     L5
  mov    $0x0,%eax
  jmp    L11
L5:
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edi
  movq   %rax,%xmm0
  call   <isInf@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int isNaN(double d) {
  union {
    double d;
    long x[2];
  } a;
  a.d = d;
  if ((a.x[1] & (2047 << 20)) != (2047 << 20))
    return 0;
  return !isInf(d, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isNaN>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isNaN(double d) {
  union {
    double d;
    long x[2];
  } a;
  a.d = d;
  if ((a.x[1] & (2047 << 20)) != (2047 << 20))
    return 0;
  return !isInf(d, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isNaN>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int isNaN(double d) {
  union {
    double d;
    long x[2];
  } a;
  a.d = d;
  if ((a.x[1] & (2047 << 20)) != (2047 << 20))
    return 0;
  return !isInf(d, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isNaN>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int isNaN(double d) {
  union {
    double d;
    long x[2];
  } a;
  a.d = d;
  if ((a.x[1] & (2047 << 20)) != (2047 << 20))
    return 0;
  return !isInf(d, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<med3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %dl,-0x14(%rbp)
  mov    %ecx,%edx
  mov    %dl,-0x18(%rbp)
  mov    %al,-0x1c(%rbp)
  movzbl -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%al
  jbe    L8
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x18(%rbp),%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x1(%rbp),%eax
  mov    %al,-0x18(%rbp)
L8:
  movzbl -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%al
  jbe    L12
  movzbl -0x18(%rbp),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  mov    %al,-0x18(%rbp)
  movzbl -0x1(%rbp),%eax
  mov    %al,-0x1c(%rbp)
L12:
  movzbl -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%al
  jbe    L11
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x18(%rbp)
L11:
  movzbl -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char med3(unsigned char a, unsigned char b, unsigned char c) {
  unsigned char t;
  if (a > b) {
    t = a;
    a = b;
    b = t;
  };
  if (b > c) {
    t = b;
    b = c;
    c = t;
  };
  if (a > b)
    b = a;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<med3>:
  endbr64
  mov    %esi,%eax
  cmp    %sil,%dil
  cmovbe %edi,%eax
  cmovbe %esi,%edi
  cmp    %dl,%dil
  cmova  %edx,%edi
  cmp    %al,%dil
  cmovae %edi,%eax
  ret
```

assistant: ```c
unsigned char med3(unsigned char a, unsigned char b, unsigned char c) {
  unsigned char t;
  if (a > b) {
    t = a;
    a = b;
    b = t;
  };
  if (b > c) {
    t = b;
    b = c;
    c = t;
  };
  if (a > b)
    b = a;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<med3>:
  endbr64
  cmp    %sil,%dil
  mov    %edi,%eax
  cmovbe %esi,%edi
  cmova  %esi,%eax
  cmp    %dl,%dil
  cmova  %edx,%edi
  cmp    %al,%dil
  cmovae %edi,%eax
  ret
```

assistant: ```c
unsigned char med3(unsigned char a, unsigned char b, unsigned char c) {
  unsigned char t;
  if (a > b) {
    t = a;
    a = b;
    b = t;
  };
  if (b > c) {
    t = b;
    b = c;
    c = t;
  };
  if (a > b)
    b = a;
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<med3>:
  endbr64
  cmp    %sil,%dil
  mov    %edi,%eax
  cmovbe %esi,%edi
  cmova  %esi,%eax
  cmp    %dl,%dil
  cmova  %edx,%edi
  cmp    %al,%dil
  cmovae %edi,%eax
  ret
```

assistant: ```c
unsigned char med3(unsigned char a, unsigned char b, unsigned char c) {
  unsigned char t;
  if (a > b) {
    t = a;
    a = b;
    b = t;
  };
  if (b > c) {
    t = b;
    b = c;
    c = t;
  };
  if (a > b)
    b = a;
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<H5Gopen2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0xa,%edi
  call   <__coverity_alloc__@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__coverity_mark_as_afm_allocated__@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: H5Gclose

assistant: ```c
void *H5Gopen2(void *loc_id, const char *name, void *gapl_id) {
  void *id = __coverity_alloc__(10);
  __coverity_mark_as_afm_allocated__(id, "H5Gclose");
  return id;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<H5Gopen2>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <__coverity_alloc__@plt>
  mov    %rax,%rbx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <__coverity_mark_as_afm_allocated__@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: H5Gclose

assistant: ```c
void *H5Gopen2(void *loc_id, const char *name, void *gapl_id) {
  void *id = __coverity_alloc__(10);
  __coverity_mark_as_afm_allocated__(id, "H5Gclose");
  return id;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<H5Gopen2>:
  endbr64
  push   %r12
  mov    $0xa,%edi
  call   <__coverity_alloc__@plt>
  lea    D4(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <__coverity_mark_as_afm_allocated__@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: H5Gclose

assistant: ```c
void *H5Gopen2(void *loc_id, const char *name, void *gapl_id) {
  void *id = __coverity_alloc__(10);
  __coverity_mark_as_afm_allocated__(id, "H5Gclose");
  return id;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<H5Gopen2>:
  endbr64
  push   %r12
  mov    $0xa,%edi
  call   <__coverity_alloc__@plt>
  lea    D3(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <__coverity_mark_as_afm_allocated__@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: H5Gclose

assistant: ```c
void *H5Gopen2(void *loc_id, const char *name, void *gapl_id) {
  void *id = __coverity_alloc__(10);
  __coverity_mark_as_afm_allocated__(id, "H5Gclose");
  return id;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_filename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L3
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  mov    -0x10(%rbp),%rax
  jmp    L35
L21:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L14:
  mov    -0x10(%rbp),%rax
L35:
  leave
  ret
```

assistant: ```c
char *get_filename(const char *path) {
  char *result = NULL;
  char *delpos = NULL;
  delpos = strrchr(path, '/');
  if (delpos == NULL) {
    if ((result = (char *)malloc(strlen(path) + 1)) != NULL) {
      strcpy(result, path);
    }
    return result;
  }
  if ((result = (char *)malloc(strlen(delpos) + 1)) != NULL) {
    strcpy(result, delpos + 1);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_filename>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L28
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L35
L30:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L30
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L30
L35:
  lea    0x1(%rbx),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L30
```

assistant: ```c
char *get_filename(const char *path) {
  char *result = NULL;
  char *delpos = NULL;
  delpos = strrchr(path, '/');
  if (delpos == NULL) {
    if ((result = (char *)malloc(strlen(path) + 1)) != NULL) {
      strcpy(result, path);
    }
    return result;
  }
  if ((result = (char *)malloc(strlen(delpos) + 1)) != NULL) {
    strcpy(result, delpos + 1);
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_filename>:
  endbr64
  push   %r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L1
L0:
  xor    %r12d,%r12d
L31:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  lea    0x1(%rbx),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L31
```

assistant: ```c
char *get_filename(const char *path) {
  char *result = NULL;
  char *delpos = NULL;
  delpos = strrchr(path, '/');
  if (delpos == NULL) {
    if ((result = (char *)malloc(strlen(path) + 1)) != NULL) {
      strcpy(result, path);
    }
    return result;
  }
  if ((result = (char *)malloc(strlen(delpos) + 1)) != NULL) {
    strcpy(result, delpos + 1);
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_filename>:
  endbr64
  push   %r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L24
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L15
L16:
  xor    %r12d,%r12d
L27:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  lea    0x1(%rbx),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L27
```

assistant: ```c
char *get_filename(const char *path) {
  char *result = NULL;
  char *delpos = NULL;
  delpos = strrchr(path, '/');
  if (delpos == NULL) {
    if ((result = (char *)malloc(strlen(path) + 1)) != NULL) {
      strcpy(result, path);
    }
    return result;
  }
  if ((result = (char *)malloc(strlen(delpos) + 1)) != NULL) {
    strcpy(result, delpos + 1);
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<median>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%r9d
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  movslq %edx,%rdi
  mov    (%rax,%rdi,4),%edi
  cmp    %edi,%esi
  jle    L73
  movslq %ecx,%r8
  mov    (%rax,%r8,4),%eax
  mov    %r9d,%r8d
  cmp    %eax,%esi
  jl     L71
  setg   %r11b
  cmp    %eax,%edi
  setl   %r9b
  setg   %r10b
  cmp    %edi,%esi
  jle    L55
  mov    %edx,%r8d
  test   %r10b,%r10b
  jne    L71
  jmp    L55
L73:
  movslq %ecx,%r10
  mov    (%rax,%r10,4),%eax
  setl   %r10b
  cmp    %eax,%esi
  setg   %r11b
  test   %r10b,%r10b
  je     L127
  mov    %r9d,%r8d
  test   %r11b,%r11b
  je     L127
L71:
  mov    %r8d,%eax
  ret
L127:
  cmp    %eax,%edi
  setl   %r9b
  test   %r10b,%r10b
  je     L104
  mov    %edx,%r8d
  test   %r9b,%r9b
  jne    L71
L104:
  cmp    %eax,%edi
  setg   %r10b
L55:
  cmp    %eax,%esi
  jge    L4
  mov    %ecx,%r8d
  test   %r10b,%r10b
  jne    L71
L4:
  test   %r9b,%r9b
  je     L71
  test   %r11b,%r11b
  cmovne %ecx,%r8d
  jmp    L71
```

assistant: ```c
int median(int *arr, int a, int b, int c) {
  int m;
  if (arr[a] > arr[b] && arr[a] < arr[c] || arr[a] > arr[c] && arr[a] < arr[b]) {
    m = a;
  } else if (arr[b] > arr[a] && arr[b] < arr[c] || arr[b] < arr[a] && arr[b] > arr[c]) {
    m = b;
  } else if (arr[c] > arr[a] && arr[c] < arr[b] || arr[c]<arr[a] & arr[c]> arr[b]) {
    m = c;
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<median>:
  endbr64
  mov    %rdi,%rax
  movslq %edx,%r8
  movslq %esi,%rdi
  movslq %ecx,%r10
  mov    (%rax,%rdi,4),%edi
  mov    (%rax,%r8,4),%r8d
  mov    (%rax,%r10,4),%eax
  cmp    %r8d,%edi
  jle    L31
  mov    %esi,%r9d
  cmp    %eax,%edi
  jge    L61
L17:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  cmp    %eax,%edi
  setg   %r10b
  cmp    %r8d,%edi
  jge    L47
  mov    %esi,%r9d
  test   %r10b,%r10b
  jne    L17
  cmp    %r8d,%edi
  jge    L47
  mov    %edx,%r9d
  cmp    %eax,%r8d
  jl     L17
  cmp    %eax,%edi
  jge    L17
L6:
  cmp    %eax,%r8d
  cmovg  %ecx,%r9d
  mov    %r9d,%eax
  ret
  nop
L61:
  setg   %r10b
  cmp    %eax,%r8d
  jle    L97
  mov    %edx,%r9d
  mov    %r9d,%eax
  ret
L47:
  cmp    %eax,%edi
  jl     L6
  nopl   0x0(%rax)
L97:
  cmp    %eax,%r8d
  jge    L17
  test   %r10b,%r10b
  cmovne %ecx,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int median(int *arr, int a, int b, int c) {
  int m;
  if (arr[a] > arr[b] && arr[a] < arr[c] || arr[a] > arr[c] && arr[a] < arr[b]) {
    m = a;
  } else if (arr[b] > arr[a] && arr[b] < arr[c] || arr[b] < arr[a] && arr[b] > arr[c]) {
    m = b;
  } else if (arr[c] > arr[a] && arr[c] < arr[b] || arr[c]<arr[a] & arr[c]> arr[b]) {
    m = c;
  }
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<median>:
  endbr64
  mov    %rdi,%rax
  movslq %edx,%r8
  movslq %esi,%rdi
  movslq %ecx,%r10
  mov    (%rax,%rdi,4),%edi
  mov    (%rax,%r8,4),%r8d
  mov    (%rax,%r10,4),%eax
  cmp    %r8d,%edi
  jle    L44
  mov    %esi,%r9d
  cmp    %eax,%edi
  jge    L69
L45:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  cmp    %eax,%edi
  setg   %r10b
  cmp    %r8d,%edi
  jge    L59
  mov    %esi,%r9d
  test   %r10b,%r10b
  jne    L45
  cmp    %r8d,%edi
  jge    L59
  mov    %edx,%r9d
  cmp    %eax,%r8d
  jl     L45
  cmp    %eax,%edi
  jge    L45
L66:
  cmp    %eax,%r8d
  cmovg  %ecx,%r9d
  mov    %r9d,%eax
  ret
  nop
L69:
  setg   %r10b
  cmp    %eax,%r8d
  jle    L86
  mov    %edx,%r9d
  mov    %r9d,%eax
  ret
L59:
  cmp    %eax,%edi
  jl     L66
  nopl   0x0(%rax)
L86:
  cmp    %eax,%r8d
  jge    L45
  test   %r10b,%r10b
  cmovne %ecx,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int median(int *arr, int a, int b, int c) {
  int m;
  if (arr[a] > arr[b] && arr[a] < arr[c] || arr[a] > arr[c] && arr[a] < arr[b]) {
    m = a;
  } else if (arr[b] > arr[a] && arr[b] < arr[c] || arr[b] < arr[a] && arr[b] > arr[c]) {
    m = b;
  } else if (arr[c] > arr[a] && arr[c] < arr[b] || arr[c]<arr[a] & arr[c]> arr[b]) {
    m = c;
  }
  return m;
}
```
user: What is the c source code of the assembly code below?

```asm
<uDMAChannelAttributeDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xffe0,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x8(%rbp),%eax
  and    $0xfffffff0,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  andl   $0x1f,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  mov    $0x400ff01c,%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
L9:
  mov    -0x8(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L37
  mov    $0x400ff034,%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
L37:
  mov    -0x8(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L1
  mov    $0x400ff03c,%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
L1:
  mov    -0x8(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L23
  mov    $0x400ff024,%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
L23:
  nop
  leave
  ret
```

assistant: ```c
void uDMAChannelAttributeDisable(uint32_t ui32ChannelNum, uint32_t ui32Attr) {
  ASSERT((ui32ChannelNum & 0xffff) < 32);
  ASSERT((ui32Attr & ~(0x00000001 | 0x00000002 | 0x00000004 | 0x00000008)) == 0);
  ui32ChannelNum &= 0x1f;
  if (ui32Attr & 0x00000001) {
    (*((volatile uint32_t *)(0x400FF01C))) = 1 << ui32ChannelNum;
  }
  if (ui32Attr & 0x00000002) {
    (*((volatile uint32_t *)(0x400FF034))) = 1 << ui32ChannelNum;
  }
  if (ui32Attr & 0x00000004) {
    (*((volatile uint32_t *)(0x400FF03C))) = 1 << ui32ChannelNum;
  }
  if (ui32Attr & 0x00000008) {
    (*((volatile uint32_t *)(0x400FF024))) = 1 << ui32ChannelNum;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uDMAChannelAttributeDisable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  test   $0xffe0,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  test   $0xfffffff0,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  mov    %ebx,%ecx
  and    $0x1f,%ecx
  test   $0x1,%bpl
  je     L30
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,0x400ff01c
L30:
  test   $0x2,%bpl
  je     L4
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,0x400ff034
L4:
  test   $0x4,%bpl
  je     L38
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,0x400ff03c
L38:
  test   $0x8,%bpl
  je     L5
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,0x400ff024
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uDMAChannelAttributeDisable(uint32_t ui32ChannelNum, uint32_t ui32Attr) {
  ASSERT((ui32ChannelNum & 0xffff) < 32);
  ASSERT((ui32Attr & ~(0x00000001 | 0x00000002 | 0x00000004 | 0x00000008)) == 0);
  ui32ChannelNum &= 0x1f;
  if (ui32Attr & 0x00000001) {
    (*((volatile uint32_t *)(0x400FF01C))) = 1 << ui32ChannelNum;
  }
  if (ui32Attr & 0x00000002) {
    (*((volatile uint32_t *)(0x400FF034))) = 1 << ui32ChannelNum;
  }
  if (ui32Attr & 0x00000004) {
    (*((volatile uint32_t *)(0x400FF03C))) = 1 << ui32ChannelNum;
  }
  if (ui32Attr & 0x00000008) {
    (*((volatile uint32_t *)(0x400FF024))) = 1 << ui32ChannelNum;
  }
}
```