ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_ttime_hour>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <_ttime_number@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L17
  imul   $0xe10,0x4(%rsp),%eax
  add    %eax,(%rbx)
  xor    %eax,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _ttime_hour(char **p, time_t *time) {
  time_t res;
  if (_ttime_number(p, &res) != 0)
    return 1;
  *time += res * 60 * 60;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_ttime_hour>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <_ttime_number@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L7
  imul   $0xe10,0x4(%rsp),%eax
  add    %eax,(%rbx)
  xor    %eax,%eax
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _ttime_hour(char **p, time_t *time) {
  time_t res;
  if (_ttime_number(p, &res) != 0)
    return 1;
  *time += res * 60 * 60;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<ht_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  add    $0x1,%edx
  imul   %edx,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x20(%rbp),%rax
  cmp    %eax,-0x4(%rbp)
  jl     L2
  mov    -0x28(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ht_hash(void *key, size_t keylen, size_t hashtab_size) {
  int sum = 0;
  int i;
  for (i = 0; i < (int)keylen; i++) {
    sum += ((unsigned char *)key)[i] * (i + 1);
  }
  return (sum % (int)hashtab_size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ht_hash>:
  endbr64
  mov    %rdx,%r9
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%r8d
  add    $0x2,%r8
  mov    $0x1,%ecx
  mov    $0x0,%eax
L17:
  movzbl -0x1(%rdi,%rcx,1),%esi
  imul   %ecx,%esi
  add    %esi,%eax
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L17
L4:
  cltd
  idiv   %r9d
  mov    %edx,%eax
  ret
L21:
  mov    $0x0,%eax
  jmp    L4
```

assistant: ```c
int ht_hash(void *key, size_t keylen, size_t hashtab_size) {
  int sum = 0;
  int i;
  for (i = 0; i < (int)keylen; i++) {
    sum += ((unsigned char *)key)[i] * (i + 1);
  }
  return (sum % (int)hashtab_size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ht_hash>:
  endbr64
  mov    %edx,%r9d
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%r8d
  mov    $0x1,%ecx
  xor    %eax,%eax
  add    $0x2,%r8
  nopw   0x0(%rax,%rax,1)
L1:
  movzbl -0x1(%rdi,%rcx,1),%esi
  imul   %ecx,%esi
  add    $0x1,%rcx
  add    %esi,%eax
  cmp    %rcx,%r8
  jne    L1
  cltd
  idiv   %r9d
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ht_hash(void *key, size_t keylen, size_t hashtab_size) {
  int sum = 0;
  int i;
  for (i = 0; i < (int)keylen; i++) {
    sum += ((unsigned char *)key)[i] * (i + 1);
  }
  return (sum % (int)hashtab_size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rob1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L30
L4:
  cmpl   $0x1,-0x1c(%rbp)
  jne    L22
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  jmp    L30
L22:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rob0@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rob0@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
L30:
  leave
  ret
```

assistant: ```c
int rob1(int *nums, int size) {
  if (size == 0)
    return 0;
  if (size == 1)
    return nums[0];
  int profit0 = rob0(nums, size - 1);
  int profit1 = rob0(nums + 1, size - 1);
  return profit0 > profit1 ? profit0 : profit1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rob1>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L5
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  cmp    $0x1,%esi
  je     L12
  lea    -0x1(%rsi),%ebx
  mov    %ebx,%esi
  call   <rob0@plt>
  mov    %eax,%r12d
  lea    0x4(%rbp),%rdi
  mov    %ebx,%esi
  call   <rob0@plt>
  cmp    %eax,%r12d
  cmovge %r12d,%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    (%rdi),%eax
  jmp    L20
L5:
  ret
```

assistant: ```c
int rob1(int *nums, int size) {
  if (size == 0)
    return 0;
  if (size == 1)
    return nums[0];
  int profit0 = rob0(nums, size - 1);
  int profit1 = rob0(nums + 1, size - 1);
  return profit0 > profit1 ? profit0 : profit1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rob1>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L19
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0x1,%esi
  je     L3
  lea    -0x1(%rsi),%ebp
  mov    %ebp,%esi
  call   <rob0@plt>
  lea    0x4(%rbx),%rdi
  mov    %ebp,%esi
  mov    %eax,%r12d
  call   <rob0@plt>
  pop    %rbx
  pop    %rbp
  cmp    %eax,%r12d
  cmovge %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  pop    %rbx
  mov    (%rdi),%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
int rob1(int *nums, int size) {
  if (size == 0)
    return 0;
  if (size == 1)
    return nums[0];
  int profit0 = rob0(nums, size - 1);
  int profit1 = rob0(nums + 1, size - 1);
  return profit0 > profit1 ? profit0 : profit1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rob1>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L9
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0x1,%esi
  je     L5
  lea    -0x1(%rsi),%ebp
  mov    %ebp,%esi
  call   <rob0@plt>
  lea    0x4(%rbx),%rdi
  mov    %ebp,%esi
  mov    %eax,%r12d
  call   <rob0@plt>
  pop    %rbx
  pop    %rbp
  cmp    %eax,%r12d
  cmovge %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  pop    %rbx
  mov    (%rdi),%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
int rob1(int *nums, int size) {
  if (size == 0)
    return 0;
  if (size == 1)
    return nums[0];
  int profit0 = rob0(nums, size - 1);
  int profit1 = rob0(nums + 1, size - 1);
  return profit0 > profit1 ? profit0 : profit1;
}
```
user: What is the c source code of the assembly code below?

```asm
<_isatty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jns    L15
  mov    D37(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L7
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISCHR@plt>
  test   %rax,%rax
  je     L42
  mov    $0x1,%eax
  jmp    L7
L42:
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
int _isatty(int fd) {
  struct stat buf;
  if (fstat(fd, &buf) < 0) {
    errno = EBADF;
    return 0;
  }
  if (S_ISCHR(buf.st_mode))
    return 1;
  errno = ENOTTY;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_isatty>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %rax,%rax
  js     L2
  mov    0x4(%rsp),%edi
  call   <S_ISCHR@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L17
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L17
L2:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _isatty(int fd) {
  struct stat buf;
  if (fstat(fd, &buf) < 0) {
    errno = EBADF;
    return 0;
  }
  if (S_ISCHR(buf.st_mode))
    return 1;
  errno = ENOTTY;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_isatty>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %rax,%rax
  js     L24
  mov    0x4(%rsp),%edi
  call   <S_ISCHR@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L27
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  jmp    L27
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _isatty(int fd) {
  struct stat buf;
  if (fstat(fd, &buf) < 0) {
    errno = EBADF;
    return 0;
  }
  if (S_ISCHR(buf.st_mode))
    return 1;
  errno = ENOTTY;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_isatty>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %rax,%rax
  js     L23
  mov    0x4(%rsp),%edi
  call   <S_ISCHR@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L4
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  jmp    L4
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _isatty(int fd) {
  struct stat buf;
  if (fstat(fd, &buf) < 0) {
    errno = EBADF;
    return 0;
  }
  if (S_ISCHR(buf.st_mode))
    return 1;
  errno = ENOTTY;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fci_i2c_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x30(%rbp)
  mov    %r9d,%edi
  mov    %esi,%ecx
  mov    %cl,-0x1c(%rbp)
  mov    %dl,-0x20(%rbp)
  mov    %al,-0x24(%rbp)
  mov    %edi,%eax
  mov    %al,-0x28(%rbp)
  movzbl -0x28(%rbp),%esi
  movzbl -0x24(%rbp),%edi
  movzbl -0x1c(%rbp),%eax
  add    %eax,%eax
  movzbl %al,%edx
  mov    -0x30(%rbp),%r8
  lea    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   %rsi
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fci_i2c_transfer@plt>
  add    $0x10,%rsp
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%esi
  movzbl -0x20(%rbp),%eax
  movzbl %al,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %esi,%r8d
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <print_log@plt>
  mov    -0x4(%rbp),%eax
  jmp    L12
L6:
  mov    -0x4(%rbp),%eax
L12:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: fci_i2c_read() result=%d, addr = %x, data=%x


assistant: ```c
signed int fci_i2c_read(void *handle, unsigned char chip, unsigned char addr, unsigned char alen, unsigned char *data, unsigned char len) {
  signed int ret;
  ret = fci_i2c_transfer(handle, 1, chip << 1, &addr, alen, data, len);
  if (ret != 0) {
    print_log(handle, "fci_i2c_read() result=%d, addr = %x, data=%x\n", ret, addr, *data);
    return ret;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fci_i2c_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %ecx,%eax
  mov    %r8,%r12
  mov    %dl,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  add    %esi,%esi
  movzbl %sil,%edx
  sub    $0x8,%rsp
  movzbl %r9b,%r9d
  push   %r9
  mov    %r8,%r9
  movzbl %al,%r8d
  mov    $0x1,%esi
  call   <fci_i2c_transfer@plt>
  mov    %eax,%ebx
  add    $0x10,%rsp
  test   %eax,%eax
  jne    L2
L16:
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  movzbl 0xc(%rsp),%ecx
  movzbl (%r12),%r8d
  mov    %eax,%edx
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <print_log@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: fci_i2c_read() result=%d, addr = %x, data=%x


assistant: ```c
signed int fci_i2c_read(void *handle, unsigned char chip, unsigned char addr, unsigned char alen, unsigned char *data, unsigned char len) {
  signed int ret;
  ret = fci_i2c_transfer(handle, 1, chip << 1, &addr, alen, data, len);
  if (ret != 0) {
    print_log(handle, "fci_i2c_read() result=%d, addr = %x, data=%x\n", ret, addr, *data);
    return ret;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fci_i2c_read>:
  endbr64
  push   %r12
  mov    %ecx,%r10d
  movzbl %r9b,%r9d
  add    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x10,%rsp
  mov    %dl,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  sub    $0x8,%rsp
  movzbl %sil,%edx
  push   %r9
  mov    $0x1,%esi
  mov    %r8,%r9
  movzbl %r10b,%r8d
  call   <fci_i2c_transfer@plt>
  pop    %rdx
  pop    %rcx
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L8
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  movzbl 0xc(%rsp),%ecx
  movzbl (%rbx),%r8d
  mov    %rbp,%rdi
  mov    %eax,%edx
  lea    D3(%rip),%rsi
  call   <print_log@plt>
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: fci_i2c_read() result=%d, addr = %x, data=%x


assistant: ```c
signed int fci_i2c_read(void *handle, unsigned char chip, unsigned char addr, unsigned char alen, unsigned char *data, unsigned char len) {
  signed int ret;
  ret = fci_i2c_transfer(handle, 1, chip << 1, &addr, alen, data, len);
  if (ret != 0) {
    print_log(handle, "fci_i2c_read() result=%d, addr = %x, data=%x\n", ret, addr, *data);
    return ret;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fci_i2c_read>:
  endbr64
  push   %r12
  mov    %ecx,%r10d
  movzbl %r9b,%r9d
  add    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x10,%rsp
  mov    %dl,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  sub    $0x8,%rsp
  movzbl %sil,%edx
  push   %r9
  mov    $0x1,%esi
  mov    %r8,%r9
  movzbl %r10b,%r8d
  call   <fci_i2c_transfer@plt>
  pop    %rdx
  pop    %rcx
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L3
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  movzbl 0xc(%rsp),%ecx
  movzbl (%rbx),%r8d
  mov    %rbp,%rdi
  mov    %eax,%edx
  lea    D9(%rip),%rsi
  call   <print_log@plt>
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: fci_i2c_read() result=%d, addr = %x, data=%x


assistant: ```c
signed int fci_i2c_read(void *handle, unsigned char chip, unsigned char addr, unsigned char alen, unsigned char *data, unsigned char len) {
  signed int ret;
  ret = fci_i2c_transfer(handle, 1, chip << 1, &addr, alen, data, len);
  if (ret != 0) {
    print_log(handle, "fci_i2c_read() result=%d, addr = %x, data=%x\n", ret, addr, *data);
    return ret;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AL_evaluatePitch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x15,-0x4(%rbp)
  nop
L5:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x3ff,%eax
  jg     L5
  mov    $0x14,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: f64

tool: D6: 50000

assistant: ```c
void AL_evaluatePitch(int pitch, int *exponent, int *mantissa) {
  int shift = 21;
  while ((*mantissa = (int)((float)pitch * (1 << --shift) / 50000.0)) > 0X3FF)
    ;
  *exponent = 20 - shift;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<AL_evaluatePitch>:
  endbr64
  mov    %edi,%eax
  mov    $0x15,%ecx
  mov    $0x1,%edi
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movsd  D1(%rip),%xmm1
L2:
  sub    $0x1,%ecx
  mov    %edi,%eax
  shl    %cl,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  cmp    $0x3ff,%eax
  jg     L2
  mov    %eax,(%rdx)
  mov    $0x14,%eax
  sub    %ecx,%eax
  mov    %eax,(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: f64

tool: D1: 50000

assistant: ```c
void AL_evaluatePitch(int pitch, int *exponent, int *mantissa) {
  int shift = 21;
  while ((*mantissa = (int)((float)pitch * (1 << --shift) / 50000.0)) > 0X3FF)
    ;
  *exponent = 20 - shift;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<AL_evaluatePitch>:
  endbr64
  mov    %edi,%r8d
  pxor   %xmm2,%xmm2
  mov    %rsi,%rdi
  mov    $0x15,%ecx
  cvtsi2ss %r8d,%xmm2
  movsd  D6(%rip),%xmm1
  mov    $0x1,%esi
  nopl   (%rax)
L9:
  sub    $0x1,%ecx
  mov    %esi,%eax
  pxor   %xmm0,%xmm0
  shl    %cl,%eax
  cvtsi2ss %eax,%xmm0
  mulss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  cmp    $0x3ff,%eax
  jg     L9
  mov    %eax,(%rdx)
  mov    $0x14,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: f64

tool: D6: 50000

assistant: ```c
void AL_evaluatePitch(int pitch, int *exponent, int *mantissa) {
  int shift = 21;
  while ((*mantissa = (int)((float)pitch * (1 << --shift) / 50000.0)) > 0X3FF)
    ;
  *exponent = 20 - shift;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AL_evaluatePitch>:
  endbr64
  mov    %edi,%r8d
  pxor   %xmm2,%xmm2
  mov    %rsi,%rdi
  mov    $0x15,%ecx
  cvtsi2ss %r8d,%xmm2
  movsd  D4(%rip),%xmm1
  mov    $0x1,%esi
  nopl   (%rax)
L5:
  sub    $0x1,%ecx
  mov    %esi,%eax
  pxor   %xmm0,%xmm0
  shl    %cl,%eax
  cvtsi2ss %eax,%xmm0
  mulss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  cmp    $0x3ff,%eax
  jg     L5
  mov    %eax,(%rdx)
  mov    $0x14,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: f64

tool: D4: 50000

assistant: ```c
void AL_evaluatePitch(int pitch, int *exponent, int *mantissa) {
  int shift = 21;
  while ((*mantissa = (int)((float)pitch * (1 << --shift) / 50000.0)) > 0X3FF)
    ;
  *exponent = 20 - shift;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_field_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L92
L21:
  addq   $0x1,-0x20(%rbp)
L92:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L45
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L45
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L45
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
L45:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L27
  addq   $0x1,-0x20(%rbp)
  jmp    L27
L72:
  addq   $0x1,-0x20(%rbp)
L27:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L72
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  je     L72
  jmp    L134
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L134:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L135
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L135
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L135
  cmpl   $0xfe,-0x4(%rbp)
  jle    L17
L135:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_field_string(char *out, char *in) {
  int i = 0;
  while (in[0] != '=' && in[0] != 13 && in[0] != 10 && in[0] != 0)
    in++;
  if (in[0] == '=')
    in++;
  while (in[0] == ' ' || in[0] == '[')
    in++;
  while (in[0] != 13 && in[0] != 10 && in[0] != 0 && i < (0x100 - 1)) {
    out[i] = in[0];
    in++;
    i++;
  }
  out[i] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_field_string>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  movzbl (%rsi),%edx
  cmp    $0x3d,%dl
  ja     L53
  movabs $0x2000000000002401,%rcx
  bt     %rdx,%rcx
  jb     L80
L53:
  movabs $0x2000000000002401,%rcx
L41:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x3d,%dl
  ja     L41
  bt     %rdx,%rcx
  jae    L41
L80:
  cmp    $0x3d,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L14
  cmp    $0x5b,%dl
  jne    L31
L14:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L14
  cmp    $0x5b,%dl
  je     L14
L31:
  movzbl (%rax),%ecx
  cmp    $0xd,%cl
  ja     L17
  mov    $0x2401,%edx
  bt     %rcx,%rdx
  jb     L106
  mov    $0x1,%edx
  jmp    L144
L17:
  mov    $0x1,%edx
L144:
  mov    $0x1,%r10d
  mov    $0x2401,%r11d
  jmp    L97
L143:
  cmp    $0xfe,%edx
  setle  %dil
  add    $0x1,%rdx
  test   %sil,%dil
  je     L131
L97:
  mov    %cl,-0x1(%r8,%rdx,1)
  mov    %edx,%r9d
  movzbl (%rax,%rdx,1),%ecx
  mov    %r10d,%esi
  cmp    $0xd,%cl
  ja     L143
  mov    %r11,%rsi
  shr    %cl,%rsi
  xor    $0x1,%rsi
  and    $0x1,%esi
  jmp    L143
L106:
  mov    $0x0,%r9d
L131:
  movslq %r9d,%r9
  movb   $0x0,(%r8,%r9,1)
  ret
```

assistant: ```c
void get_field_string(char *out, char *in) {
  int i = 0;
  while (in[0] != '=' && in[0] != 13 && in[0] != 10 && in[0] != 0)
    in++;
  if (in[0] == '=')
    in++;
  while (in[0] == ' ' || in[0] == '[')
    in++;
  while (in[0] != 13 && in[0] != 10 && in[0] != 0 && i < (0x100 - 1)) {
    out[i] = in[0];
    in++;
    i++;
  }
  out[i] = 0;
}
```