user: 这段汇编代码用C语言表示是什么样的？

```asm
<s16_encode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x758,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x748(%rsp)
  xor    %eax,%eax
  movl   $0x1c,(%rsp)
  movl   $0x15,0x4(%rsp)
  movl   $0x15,0x8(%rsp)
  movl   $0x15,0xc(%rsp)
  movl   $0xe,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0x8,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  movl   $0x5,0x28(%rsp)
  movl   $0x5,0x2c(%rsp)
  movl   $0x4,0x30(%rsp)
  movl   $0x3,0x34(%rsp)
  movl   $0x2,0x38(%rsp)
  movl   $0x1,0x3c(%rsp)
  lea    0x40(%rsp),%rdi
  lea    D9(%rip),%rsi
  mov    $0xe0,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    %rsp,%r12
  lea    0x40(%rsp),%r11
  mov    %r11,%r15
  mov    $0x0,%r14d
  jmp    L14
L25:
  cmp    %esi,%r10d
  je     L7
  add    $0x10000000,%r14d
  add    $0x4,%r12
  add    $0x70,%r11
  cmp    %r15,%r12
  je     L59
L14:
  mov    (%rbx),%rax
  mov    %r14d,(%rax)
  mov    (%r12),%r10d
  cmp    %r10d,%r13d
  cmovbe %r13d,%r10d
  test   %r10d,%r10d
  je     L30
  mov    $0x0,%edx
  mov    $0x0,%r8d
  mov    $0x0,%esi
L6:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rdx,1),%eax
  mov    (%r11,%rdx,1),%edi
  mov    %eax,%r9d
  mov    %edi,%ecx
  shr    %cl,%r9d
  test   %r9d,%r9d
  jne    L25
  mov    (%rbx),%r9
  mov    %r8d,%ecx
  shl    %cl,%eax
  add    %eax,(%r9)
  add    %edi,%r8d
  add    $0x1,%esi
  add    $0x4,%rdx
  cmp    %esi,%r10d
  jne    L6
L30:
  mov    %r10d,%eax
  shl    $0x2,%rax
  add    %rax,0x0(%rbp)
  addq   $0x4,(%rbx)
L59:
  mov    0x748(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x758,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    %esi,%r10d
  jmp    L30
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: 

assistant: ```c
void s16_encode(unsigned int **_w, unsigned int **_p, unsigned int m) {
  int cnum[16] = {28, 21, 21, 21, 14, 9, 8, 7, 6, 6, 5, 5, 4, 3, 2, 1};
  int cbits[16][28] = {{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1}, {2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}, {1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0}, {1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 0, 0, 0, 0, 0, 0, 0}, {2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {4, 3, 3, 3, 3, 3, 3, 3, 3, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {3, 4, 4, 4, 4, 3, 3, 3, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {4, 4, 4, 4, 4, 4, 4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {5, 5, 5, 5, 4, 4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {4, 4, 5, 5, 5, 5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {6, 6, 6, 5, 5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {5, 5, 6, 6, 6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {7, 7, 7, 7, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {10, 9, 9, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {14, 14, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {28, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}};
  unsigned int _k, _j, _m, _o;
  for (_k = 0; _k < 16; _k++) {
    (**_w) = _k << 28;
    _m = (cnum[_k] < m) ? cnum[_k] : m;
    for (_j = 0, _o = 0; (_j < _m) && (*((*_p) + _j) < (1 << cbits[_k][_j]));) {
      (**_w) += ((*((*_p) + _j)) << _o);
      _o += cbits[_k][_j];
      _j++;
    }
    if (_j == _m) {
      (*_p) += _m;
      (*_w)++;
      break;
    }
  }
}
```