ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_scaling_basis_TET>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%r13d
  movq   %xmm1,%r14
  mov    %rcx,%rdx
  mov    %r8,%rcx
  mov    %r9,%rbx
  mov    0x40(%rsp),%r8
  call   <get_scaling_basis_TRI@plt>
  add    %r12d,%ebp
  mov    %ebp,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  %xmm1,0x8(%rsp)
  addsd  %xmm1,%xmm1
  addsd  D35(%rip),%xmm1
  movsd  D11(%rip),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  lea    0x0(%rbp,%r13,1),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  addsd  D35(%rip),%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L18
  sqrtsd %xmm0,%xmm0
L4:
  movsd  %xmm0,(%rbx)
  movsd  D39(%rip),%xmm0
  movq   %r14,%xmm3
  subsd  %xmm3,%xmm0
  movsd  0x8(%rsp),%xmm1
  call   <pow@plt>
  mov    0x48(%rsp),%rax
  movsd  %xmm0,(%rax)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <sqrt@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: tag: D35
type_infered: f64
name: extract_symbolic_data
arguments: tag: D11
type_infered: f64
name: extract_symbolic_data
arguments: tag: D39
type_infered: f64

tool: D35: 3

tool: D11: 2

tool: D39: 1

assistant: ```c
void get_scaling_basis_TET(const unsigned int i, const unsigned int j, const unsigned int k, const double b, const double c, double *con_i, double *con_j, double *con_k, double *con_b, double *con_c) {
  get_scaling_basis_TRI(i, j, b, con_i, con_j, con_b);
  *con_k = sqrt((2.0 * (i + j + k) + 3.0) / pow(2.0, 2.0 * (i + j) + 3.0));
  *con_c = pow(1.0 - c, (double)(i + j));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_scaling_basis_TET>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  mov    %rcx,%rdx
  mov    %r8,%rcx
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    0x40(%rsp),%r8
  movsd  %xmm1,(%rsp)
  call   <get_scaling_basis_TRI@plt>
  lea    (%rbx,%r12,1),%eax
  pxor   %xmm2,%xmm2
  movsd  D7(%rip),%xmm0
  cvtsi2sd %rax,%xmm2
  mov    %rax,%rbx
  movapd %xmm2,%xmm1
  movsd  %xmm2,0x8(%rsp)
  addsd  %xmm2,%xmm1
  addsd  D36(%rip),%xmm1
  call   <pow@plt>
  lea    (%rbx,%r13,1),%eax
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  addsd  D36(%rip),%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L10
  sqrtsd %xmm0,%xmm0
L7:
  movsd  %xmm0,0x0(%rbp)
  movsd  D34(%rip),%xmm0
  subsd  (%rsp),%xmm0
  movapd %xmm2,%xmm1
  call   <pow@plt>
  mov    0x48(%rsp),%rax
  movsd  %xmm0,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: f64
name: disassemble_data
arguments: label: D36
datatype: f64
name: disassemble_data
arguments: label: D34
datatype: f64

tool: D7: 2

tool: D36: 3

tool: D34: 1

assistant: ```c
void get_scaling_basis_TET(const unsigned int i, const unsigned int j, const unsigned int k, const double b, const double c, double *con_i, double *con_j, double *con_k, double *con_b, double *con_c) {
  get_scaling_basis_TRI(i, j, b, con_i, con_j, con_b);
  *con_k = sqrt((2.0 * (i + j + k) + 3.0) / pow(2.0, 2.0 * (i + j) + 3.0));
  *con_c = pow(1.0 - c, (double)(i + j));
}
```
user: What is the c source code of the assembly code below?

```asm
<get_scaling_basis_TET>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  mov    %rcx,%rdx
  mov    %r8,%rcx
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    0x40(%rsp),%r8
  movsd  %xmm1,(%rsp)
  call   <get_scaling_basis_TRI@plt>
  lea    (%rbx,%r12,1),%eax
  pxor   %xmm2,%xmm2
  movsd  D34(%rip),%xmm0
  cvtsi2sd %rax,%xmm2
  mov    %rax,%rbx
  movapd %xmm2,%xmm1
  movsd  %xmm2,0x8(%rsp)
  addsd  %xmm2,%xmm1
  addsd  D1(%rip),%xmm1
  call   <pow@plt>
  lea    (%rbx,%r13,1),%eax
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  addsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L10
  sqrtsd %xmm0,%xmm0
L15:
  movsd  %xmm0,0x0(%rbp)
  movsd  D13(%rip),%xmm0
  subsd  (%rsp),%xmm0
  movapd %xmm2,%xmm1
  call   <pow@plt>
  mov    0x48(%rsp),%rax
  movsd  %xmm0,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D34
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: f64

tool: D34: 2

tool: D1: 3

tool: D13: 1

assistant: ```c
void get_scaling_basis_TET(const unsigned int i, const unsigned int j, const unsigned int k, const double b, const double c, double *con_i, double *con_j, double *con_k, double *con_b, double *con_c) {
  get_scaling_basis_TRI(i, j, b, con_i, con_j, con_b);
  *con_k = sqrt((2.0 * (i + j + k) + 3.0) / pow(2.0, 2.0 * (i + j) + 3.0));
  *con_c = pow(1.0 - c, (double)(i + j));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D14(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string

tool: D14: Usage: jail-cmd [command] [args]
run jail command.
press CTRL+] to exit.


tool: D8: %s

assistant: ```c
void help(void) {
  char *help = ""
               "Usage: jail-cmd [command] [args]\n"
               "run jail command.\n"
               "press CTRL+] to exit.\n";
  printf("%s", help);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D10
data_type: string

tool: D0: Usage: jail-cmd [command] [args]
run jail command.
press CTRL+] to exit.


tool: D10: %s

assistant: ```c
void help(void) {
  char *help = ""
               "Usage: jail-cmd [command] [args]\n"
               "run jail command.\n"
               "press CTRL+] to exit.\n";
  printf("%s", help);
}
```
user: Translate the below assembly code into C programming language:

```asm
<help>:
  endbr64
  lea    D19(%rip),%rsi
  lea    D12(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D12
type: string

tool: D19: Usage: jail-cmd [command] [args]
run jail command.
press CTRL+] to exit.


tool: D12: %s

assistant: ```c
void help(void) {
  char *help = ""
               "Usage: jail-cmd [command] [args]\n"
               "run jail command.\n"
               "press CTRL+] to exit.\n";
  printf("%s", help);
}
```
user: What is the c source code of the assembly code below:

```asm
<help>:
  endbr64
  lea    D12(%rip),%rsi
  lea    D10(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string

tool: D12: Usage: jail-cmd [command] [args]
run jail command.
press CTRL+] to exit.


tool: D10: %s

assistant: ```c
void help(void) {
  char *help = ""
               "Usage: jail-cmd [command] [args]\n"
               "run jail command.\n"
               "press CTRL+] to exit.\n";
  printf("%s", help);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <title_to_number@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string
name: disassemble_data
arguments: label: D13
data_type: string

tool: D3: ABA

tool: D13: %s --> %d


assistant: ```c
int main(void) {
  const char *s = "ABA";
  printf("%s --> %d\n", s, title_to_number(s));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  call   <title_to_number@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
datatype: string
name: unpack_data
arguments: label: D15
datatype: string

tool: D10: ABA

tool: D15: %s --> %d


assistant: ```c
int main(void) {
  const char *s = "ABA";
  printf("%s --> %d\n", s, title_to_number(s));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  call   <title_to_number@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D18
type_infered: string

tool: D19: ABA

tool: D18: %s --> %d


assistant: ```c
int main(void) {
  const char *s = "ABA";
  printf("%s --> %d\n", s, title_to_number(s));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rbp
  mov    %rbp,%rdi
  call   <title_to_number@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type: string
name: disassemble_data
arguments: data_tag: D10
type: string

tool: D11: ABA

tool: D10: %s --> %d


assistant: ```c
int main(void) {
  const char *s = "ABA";
  printf("%s --> %d\n", s, title_to_number(s));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jRead_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L11:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L3
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L11
L3:
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *jRead_atoi(char *p, unsigned int *result) {
  unsigned int x = 0;
  while (*p >= '0' && *p <= '9') {
    x = (x * 10) + (*p - '0');
    ++p;
  }
  *result = x;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jRead_atoi>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L13
  mov    $0x0,%ecx
L6:
  lea    (%rcx,%rcx,4),%ecx
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rcx,2),%ecx
  add    $0x1,%rax
  movzbl (%rax),%edx
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  jbe    L6
L26:
  mov    %ecx,(%rsi)
  ret
L13:
  mov    $0x0,%ecx
  jmp    L26
```

assistant: ```c
char *jRead_atoi(char *p, unsigned int *result) {
  unsigned int x = 0;
  while (*p >= '0' && *p <= '9') {
    x = (x * 10) + (*p - '0');
    ++p;
  }
  *result = x;
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jRead_atoi>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  mov    $0x0,%ecx
  ja     L19
  nopw   0x0(%rax,%rax,1)
L12:
  lea    (%rcx,%rcx,4),%ecx
  add    $0x1,%rax
  lea    -0x30(%rdx,%rcx,2),%ecx
  movsbl (%rax),%edx
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  jbe    L12
L19:
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
char *jRead_atoi(char *p, unsigned int *result) {
  unsigned int x = 0;
  while (*p >= '0' && *p <= '9') {
    x = (x * 10) + (*p - '0');
    ++p;
  }
  *result = x;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jRead_atoi>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  mov    $0x0,%ecx
  ja     L14
  nopw   0x0(%rax,%rax,1)
L15:
  lea    (%rcx,%rcx,4),%ecx
  add    $0x1,%rax
  lea    -0x30(%rdx,%rcx,2),%ecx
  movsbl (%rax),%edx
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  jbe    L15
L14:
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
char *jRead_atoi(char *p, unsigned int *result) {
  unsigned int x = 0;
  while (*p >= '0' && *p <= '9') {
    x = (x * 10) + (*p - '0');
    ++p;
  }
  *result = x;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <proc@plt>
  cmp    $0x1,%eax
  jne    L6
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L6:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L21:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
datatype: string
name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D23
datatype: string

tool: D24: %s

tool: D17: Yes


tool: D23: No


assistant: ```c
int main() {
  char s[100];
  scanf("%s", s);
  if (proc(s, 1) == 1)
    printf("Yes\n");
  else
    printf("No\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <proc@plt>
  cmp    $0x1,%eax
  je     L26
  lea    D1(%rip),%rdi
  call   <printf@plt>
L28:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L26:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D15: %s

tool: D1: No


tool: D16: Yes


assistant: ```c
int main() {
  char s[100];
  scanf("%s", s);
  if (proc(s, 1) == 1)
    printf("Yes\n");
  else
    printf("No\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <proc@plt>
  cmp    $0x1,%eax
  je     L2
  lea    D25(%rip),%rdi
  call   <printf@plt>
L16:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D25
type_guessed: string
name: unpack_data
arguments: label: D20
type_guessed: string

tool: D10: %s

tool: D25: No


tool: D20: Yes


assistant: ```c
int main() {
  char s[100];
  scanf("%s", s);
  if (proc(s, 1) == 1)
    printf("Yes\n");
  else
    printf("No\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <proc@plt>
  cmp    $0x1,%eax
  je     L14
  lea    D26(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L14:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D22
data_type: string

tool: D28: %s

tool: D26: No


tool: D22: Yes


assistant: ```c
int main() {
  char s[100];
  scanf("%s", s);
  if (proc(s, 1) == 1)
    printf("Yes\n");
  else
    printf("No\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<jx_iterate_keys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <advance_object_iter@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <jx_get_key@plt>
  leave
  ret
```

assistant: ```c
const char *jx_iterate_keys(struct jx *j, void **i) {
  advance_object_iter(j, i);
  return jx_get_key(i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<jx_iterate_keys>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <advance_object_iter@plt>
  mov    %rbx,%rdi
  call   <jx_get_key@plt>
  pop    %rbx
  ret
```

assistant: ```c
const char *jx_iterate_keys(struct jx *j, void **i) {
  advance_object_iter(j, i);
  return jx_get_key(i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jx_iterate_keys>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <advance_object_iter@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <jx_get_key@plt>
```

assistant: ```c
const char *jx_iterate_keys(struct jx *j, void **i) {
  advance_object_iter(j, i);
  return jx_get_key(i);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<jx_iterate_keys>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <advance_object_iter@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <jx_get_key@plt>
```

assistant: ```c
const char *jx_iterate_keys(struct jx *j, void **i) {
  advance_object_iter(j, i);
  return jx_get_key(i);
}
```
user: What is the c source code of the assembly code below:

```asm
<__lcong48_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    -0x8(%rbp),%rcx
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  add    $0xa,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  movzwl 0xc(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dx,0x4(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x1,0x8(%rax)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int __lcong48_r(unsigned short int param[7], struct drand48_data *buffer) {
  memcpy(buffer->__x, &param[0], sizeof(buffer->__x));
  buffer->__a = ((uint64_t)param[5] << 32 | (uint32_t)param[4] << 16 | param[3]);
  buffer->__c = param[6];
  buffer->__init = 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__lcong48_r>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    0xc(%rsi),%edi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movzwl 0x8(%rbp),%eax
  shl    $0x10,%eax
  movzwl 0x6(%rbp),%edx
  or     %edx,%eax
  mov    %eax,(%rbx)
  movzwl 0xc(%rbp),%eax
  mov    %ax,0x4(%rbx)
  movl   $0x1,0x8(%rbx)
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int __lcong48_r(unsigned short int param[7], struct drand48_data *buffer) {
  memcpy(buffer->__x, &param[0], sizeof(buffer->__x));
  buffer->__a = ((uint64_t)param[5] << 32 | (uint32_t)param[4] << 16 | param[3]);
  buffer->__c = param[6];
  buffer->__init = 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__lcong48_r>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4,%edx
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0xc(%rsi),%edi
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x6(%rbp),%eax
  mov    %eax,(%rbx)
  movzwl 0xc(%rbp),%eax
  movl   $0x1,0x8(%rbx)
  mov    %ax,0x4(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int __lcong48_r(unsigned short int param[7], struct drand48_data *buffer) {
  memcpy(buffer->__x, &param[0], sizeof(buffer->__x));
  buffer->__a = ((uint64_t)param[5] << 32 | (uint32_t)param[4] << 16 | param[3]);
  buffer->__c = param[6];
  buffer->__init = 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__lcong48_r>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4,%edx
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0xc(%rsi),%edi
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x6(%rbp),%eax
  mov    %eax,(%rbx)
  movzwl 0xc(%rbp),%eax
  movl   $0x1,0x8(%rbx)
  mov    %ax,0x4(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int __lcong48_r(unsigned short int param[7], struct drand48_data *buffer) {
  memcpy(buffer->__x, &param[0], sizeof(buffer->__x));
  buffer->__a = ((uint64_t)param[5] << 32 | (uint32_t)param[4] << 16 | param[3]);
  buffer->__c = param[6];
  buffer->__init = 1;
  return 0;
}
```