ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x190,%edi
  push   %r13
  push   %r12
  lea    D36(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <malloc@plt>
  lea    0x14(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %rax,%rbp
  lea    0x8(%rsp),%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L17:
  mov    0x10(%rsp),%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
L22:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L17
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <mostra@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <polinomio@plt>
  pxor   %xmm1,%xmm1
  movss  0x14(%rsp),%xmm0
  mov    0xc(%rsp),%edx
  cvtsi2sd %ebx,%xmm1
  mov    0x8(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  movss  0x14(%rsp),%xmm0
  call   <pcd@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D39(%rip),%rdi
  movapd %xmm0,%xmm1
  movss  0x14(%rsp),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D36
data_type: string
name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D39
data_type: string

tool: D36: %d 

tool: D5: %d %d %f


tool: D7: Dados> a: %d, b: %d, x: %0.2f, tam: %d


tool: D39: p_%d,%d(%0.2f) = %0.2f 


assistant: ```c
int main() {
  int *v = NULL, tam = 0, a = 0, b = 0;
  int lido = 0;
  float x = 0;
  v = malloc(sizeof(int) * 100);
  scanf("%d %d %f\n", &a, &b, &x);
  while (scanf("%d ", &lido) == 1) {
    v[tam] = lido;
    tam++;
  }
  if (1) {
    mostra(v, tam);
    polinomio(v, a, b);
    printf("Dados> a: %d, b: %d, x: %0.2f, tam: %d\n", a, b, x, tam);
  }
  printf("p_%d,%d(%0.2f) = %0.2f \n", a, b, x, pcd(v, a, b, x));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x190,%edi
  push   %r13
  push   %r12
  lea    D35(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <malloc@plt>
  lea    0x14(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %rax,%rbp
  lea    0x8(%rsp),%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L24:
  mov    0x10(%rsp),%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
L27:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L24
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <mostra@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <polinomio@plt>
  pxor   %xmm1,%xmm1
  movss  0x14(%rsp),%xmm0
  mov    0xc(%rsp),%edx
  cvtsi2sd %ebx,%xmm1
  mov    0x8(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  movss  0x14(%rsp),%xmm0
  call   <pcd@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D28(%rip),%rdi
  movapd %xmm0,%xmm1
  movss  0x14(%rsp),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D35
type_infered: string
name: read_data
arguments: label: D30
type_infered: string
name: read_data
arguments: label: D2
type_infered: string
name: read_data
arguments: label: D28
type_infered: string

tool: D35: %d 

tool: D30: %d %d %f


tool: D2: Dados> a: %d, b: %d, x: %0.2f, tam: %d


tool: D28: p_%d,%d(%0.2f) = %0.2f 


assistant: ```c
int main() {
  int *v = NULL, tam = 0, a = 0, b = 0;
  int lido = 0;
  float x = 0;
  v = malloc(sizeof(int) * 100);
  scanf("%d %d %f\n", &a, &b, &x);
  while (scanf("%d ", &lido) == 1) {
    v[tam] = lido;
    tam++;
  }
  if (1) {
    mostra(v, tam);
    polinomio(v, a, b);
    printf("Dados> a: %d, b: %d, x: %0.2f, tam: %d\n", a, b, x, tam);
  }
  printf("p_%d,%d(%0.2f) = %0.2f \n", a, b, x, pcd(v, a, b, x));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <check_serial@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L12
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L12:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string
name: unpack_data
arguments: data_tag: D13
type_infered: string

tool: D3: Success!


tool: D13: Fail!


assistant: ```c
int main(int argc, char *argv[]) {
  int rv;
  char *password = argv[1];
  rv = check_serial(password);
  if (rv == 0x1) {
    printf("Success!\n");
  } else {
    printf("Fail!\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <check_serial@plt>
  cmp    $0x1,%eax
  je     L6
  lea    D8(%rip),%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L6:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string
name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D8: Fail!


tool: D9: Success!


assistant: ```c
int main(int argc, char *argv[]) {
  int rv;
  char *password = argv[1];
  rv = check_serial(password);
  if (rv == 0x1) {
    printf("Success!\n");
  } else {
    printf("Fail!\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <check_serial@plt>
  cmp    $0x1,%eax
  je     L2
  lea    D18(%rip),%rdi
  call   <printf@plt>
L6:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L2:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: tag: D18
type: string
name: parse_data
arguments: tag: D3
type: string

tool: D18: Fail!


tool: D3: Success!


assistant: ```c
int main(int argc, char *argv[]) {
  int rv;
  char *password = argv[1];
  rv = check_serial(password);
  if (rv == 0x1) {
    printf("Success!\n");
  } else {
    printf("Fail!\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <check_serial@plt>
  cmp    $0x1,%eax
  je     L3
  lea    D14(%rip),%rdi
  call   <printf@plt>
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L3:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
datatype: string
name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D14: Fail!


tool: D1: Success!


assistant: ```c
int main(int argc, char *argv[]) {
  int rv;
  char *password = argv[1];
  rv = check_serial(password);
  if (rv == 0x1) {
    printf("Success!\n");
  } else {
    printf("Fail!\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <for_asm@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  for_asm();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <for_asm@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  for_asm();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <for_asm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  for_asm();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <for_asm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  for_asm();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *arr, int i, int j) {
  int t;
  t = arr[i];
  arr[i] = arr[j];
  arr[j] = t;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *arr, int i, int j) {
  int t;
  t = arr[i];
  arr[i] = arr[j];
  arr[j] = t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *arr, int i, int j) {
  int t;
  t = arr[i];
  arr[i] = arr[j];
  arr[j] = t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *arr, int i, int j) {
  int t;
  t = arr[i];
  arr[i] = arr[j];
  arr[j] = t;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<h2o_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L29
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L28
L29:
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <h2o__fatal@plt>
L6:
  mov    -0x8(%rbp),%rax
L28:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/lkwg82/h2o/refs/heads/master/lib/common/h2o/memory.h:333:null pointer passed to memcpy

assistant: ```c
void *h2o_memcpy(void *dst, const void *src, size_t n) {
  if (src != NULL)
    return memcpy(dst, src, n);
  else if (n != 0)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/lkwg82/h2o/refs/heads/master/lib/common/h2o/memory.h"
               ":"
               "333"
               ":"
               "null pointer passed to memcpy");
  return dst;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<h2o_memcpy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rsi,%rsi
  jne    L21
  test   %rdx,%rdx
  jne    L1
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
L21:
  call   <memcpy@plt>
  jmp    L9
L1:
  lea    D3(%rip),%rdi
  call   <h2o__fatal@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/lkwg82/h2o/refs/heads/master/lib/common/h2o/memory.h:333:null pointer passed to memcpy

assistant: ```c
void *h2o_memcpy(void *dst, const void *src, size_t n) {
  if (src != NULL)
    return memcpy(dst, src, n);
  else if (n != 0)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/lkwg82/h2o/refs/heads/master/lib/common/h2o/memory.h"
               ":"
               "333"
               ":"
               "null pointer passed to memcpy");
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<h2o_memcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rsi,%rsi
  jne    L10
  test   %rdx,%rdx
  jne    L15
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  lea    D0(%rip),%rdi
  call   <h2o__fatal@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  pop    %r12
  jmp    1070 <memcpy@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/lkwg82/h2o/refs/heads/master/lib/common/h2o/memory.h:333:null pointer passed to memcpy

assistant: ```c
void *h2o_memcpy(void *dst, const void *src, size_t n) {
  if (src != NULL)
    return memcpy(dst, src, n);
  else if (n != 0)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/lkwg82/h2o/refs/heads/master/lib/common/h2o/memory.h"
               ":"
               "333"
               ":"
               "null pointer passed to memcpy");
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<h2o_memcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rsi,%rsi
  jne    L14
  test   %rdx,%rdx
  jne    L2
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D8(%rip),%rdi
  call   <h2o__fatal@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  pop    %r12
  jmp    1070 <memcpy@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/lkwg82/h2o/refs/heads/master/lib/common/h2o/memory.h:333:null pointer passed to memcpy

assistant: ```c
void *h2o_memcpy(void *dst, const void *src, size_t n) {
  if (src != NULL)
    return memcpy(dst, src, n);
  else if (n != 0)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/lkwg82/h2o/refs/heads/master/lib/common/h2o/memory.h"
               ":"
               "333"
               ":"
               "null pointer passed to memcpy");
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L58
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L32
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L58
L32:
  movl   $0x2,-0x14(%rbp)
  jmp    L53
L58:
  movl   $0x0,-0x14(%rbp)
L53:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L44
L19:
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <htoi_digit@plt>
  add    %ebx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L44:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L19
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int htoi(char s[]) {
  int ii, nn, ii_0;
  nn = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    ii_0 = 2;
  else
    ii_0 = 0;
  for (ii = ii_0; isxdigit(s[ii]); ++ii)
    nn = 16 * nn + htoi_digit(s[ii]);
  return nn;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<htoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  cmpb   $0x30,(%rdi)
  je     L19
L13:
  cltq
  lea    (%rdi,%rax,1),%rbx
  mov    $0x0,%ebp
  jmp    L31
L19:
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  jmp    L13
L7:
  shl    $0x4,%ebp
  movsbl (%rbx),%edi
  call   <htoi_digit@plt>
  add    %eax,%ebp
  add    $0x1,%rbx
L31:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L7
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int htoi(char s[]) {
  int ii, nn, ii_0;
  nn = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    ii_0 = 2;
  else
    ii_0 = 0;
  for (ii = ii_0; isxdigit(s[ii]); ++ii)
    nn = 16 * nn + htoi_digit(s[ii]);
  return nn;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<htoi>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  cmp    $0x30,%dil
  je     L0
L47:
  add    %rax,%rbx
  xor    %r12d,%r12d
  jmp    L49
  nopl   0x0(%rax)
L4:
  movsbl -0x1(%rbx),%edi
  shl    $0x4,%r12d
  call   <htoi_digit@plt>
  movsbl (%rbx),%edi
  add    %eax,%r12d
L49:
  call   <isxdigit@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L4
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  movzbl 0x1(%rbx),%edx
  and    $0xffffffdf,%edx
  cmp    $0x58,%dl
  jne    L47
  movsbl 0x2(%rbx),%edi
  mov    $0x2,%eax
  jmp    L47
```

assistant: ```c
int htoi(char s[]) {
  int ii, nn, ii_0;
  nn = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    ii_0 = 2;
  else
    ii_0 = 0;
  for (ii = ii_0; isxdigit(s[ii]); ++ii)
    nn = 16 * nn + htoi_digit(s[ii]);
  return nn;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<htoi>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x30,(%rdi)
  jne    L15
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L15:
  cltq
  xor    %r12d,%r12d
  lea    (%rdi,%rax,1),%rbx
  jmp    L1
  xchg   %ax,%ax
L6:
  movsbl (%rbx),%edi
  shl    $0x4,%r12d
  add    $0x1,%rbx
  call   <htoi_digit@plt>
  add    %eax,%r12d
L1:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int htoi(char s[]) {
  int ii, nn, ii_0;
  nn = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    ii_0 = 2;
  else
    ii_0 = 0;
  for (ii = ii_0; isxdigit(s[ii]); ++ii)
    nn = 16 * nn + htoi_digit(s[ii]);
  return nn;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<shift_to_gl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rcx
  mov    %esi,%edx
  jmp    L8
L19:
  mov    %rcx,%rax
  lea    0x1(%rax),%rcx
  movzbl (%rax),%esi
  and    $0x7f,%esi
  mov    %sil,(%rax)
L8:
  mov    %edx,%eax
  lea    -0x1(%rax),%edx
  test   %eax,%eax
  jg     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shift_to_gl(text, length) register char *text;
register int length;
{
  while (length-- > 0)
    *text++ &= 0x7f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shift_to_gl>:
  endbr64
  test   %esi,%esi
  jle    L12
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rax
L18:
  add    $0x1,%rdi
  andb   $0x7f,-0x1(%rdi)
  cmp    %rax,%rdi
  jne    L18
L12:
  ret
```

assistant: ```c
void shift_to_gl(text, length) register char *text;
register int length;
{
  while (length-- > 0)
    *text++ &= 0x7f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift_to_gl>:
  endbr64
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rax
  nop
L13:
  add    $0x1,%rdi
  andb   $0x7f,-0x1(%rdi)
  cmp    %rax,%rdi
  jne    L13
L0:
  ret
```

assistant: ```c
void shift_to_gl(text, length) register char *text;
register int length;
{
  while (length-- > 0)
    *text++ &= 0x7f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shift_to_gl>:
  endbr64
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  jle    L119
  mov    %rdi,%rax
  cmp    $0xe,%ecx
  jbe    L15
  mov    %esi,%edi
  movdqa D10(%rip),%xmm1
  shr    $0x4,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L40:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pand   %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdi,%rax
  jne    L40
  mov    %esi,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  sub    %edi,%ecx
  add    %rdx,%rax
  cmp    %edi,%esi
  je     L1
L10:
  sub    %edi,%esi
  lea    -0x1(%rsi),%r8d
  cmp    $0x6,%r8d
  jbe    L16
  movq   D10(%rip),%xmm1
  add    %rdi,%rdx
  movq   (%rdx),%xmm0
  pand   %xmm1,%xmm0
  movq   %xmm0,(%rdx)
  mov    %esi,%edx
  and    $0xfffffff8,%edx
  mov    %edx,%edi
  sub    %edx,%ecx
  add    %rdi,%rax
  cmp    %edx,%esi
  je     L119
L16:
  andb   $0x7f,(%rax)
  test   %ecx,%ecx
  jle    L119
  andb   $0x7f,0x1(%rax)
  cmp    $0x1,%ecx
  jle    L119
  andb   $0x7f,0x2(%rax)
  cmp    $0x2,%ecx
  jle    L119
  andb   $0x7f,0x3(%rax)
  cmp    $0x3,%ecx
  jle    L119
  andb   $0x7f,0x4(%rax)
  cmp    $0x4,%ecx
  jle    L119
  andb   $0x7f,0x5(%rax)
  cmp    $0x5,%ecx
  jle    L119
  andb   $0x7f,0x6(%rax)
L119:
  ret
L15:
  xor    %edi,%edi
  jmp    L10
L1:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D10
type: byte[16]

tool: {"D10": [0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f]}

assistant: ```c
void shift_to_gl(text, length) register char *text;
register int length;
{
  while (length-- > 0)
    *text++ &= 0x7f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ParseStreamMode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x0,%eax
  jmp    L18
L32:
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L2
  mov    $0x1,%eax
  jmp    L18
L2:
  mov    $0xffffffff,%eax
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D17: vid

tool: D8: aud

assistant: ```c
int ParseStreamMode(unsigned char *arg) {
  if (strcasecmp(arg, "vid") == 0)
    return 0;
  if (strcasecmp(arg, "aud") == 0)
    return 1;
  return -1;
}
```