ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<div2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L20:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    $0x1,%eax
  test   %al,%al
  je     L29
  movl   $0x5,-0x8(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int div2(char *numantes, char *numdepois) {
  int prox_val = 0, val_atual;
  while (*numantes != '\0') {
    val_atual = prox_val;
    prox_val = 0;
    if (*numantes % 2)
      prox_val = 5;
    *numdepois = (*numantes - '0') / 2 + val_atual + '0';
    ++numantes;
    ++numdepois;
  }
  *numdepois = '\0';
  return (prox_val / 5);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<div2>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  mov    $0x0,%r8d
  jmp    L17
L20:
  mov    %edx,%r8d
L17:
  mov    %eax,%edx
  shl    $0x1f,%edx
  sar    $0x1f,%edx
  and    $0x5,%edx
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  lea    0x30(%r8,%rax,1),%eax
  mov    %al,(%rsi)
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L20
L25:
  movb   $0x0,(%rsi)
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  ret
L24:
  mov    $0x0,%edx
  jmp    L25
```

assistant: ```c
int div2(char *numantes, char *numdepois) {
  int prox_val = 0, val_atual;
  while (*numantes != '\0') {
    val_atual = prox_val;
    prox_val = 0;
    if (*numantes % 2)
      prox_val = 5;
    *numdepois = (*numantes - '0') / 2 + val_atual + '0';
    ++numantes;
    ++numdepois;
  }
  *numdepois = '\0';
  return (prox_val / 5);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<div2>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L12
  xor    %r8d,%r8d
  jmp    L13
L16:
  mov    %edx,%r8d
L13:
  mov    %eax,%edx
  sub    $0x30,%eax
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %eax,%ecx
  shl    $0x1f,%edx
  shr    $0x1f,%ecx
  sar    $0x1f,%edx
  add    %ecx,%eax
  and    $0x5,%edx
  sar    %eax
  lea    0x30(%r8,%rax,1),%eax
  mov    %al,-0x1(%rsi)
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L16
  mov    %edx,%eax
  mov    $0xcccccccd,%edx
  movb   $0x0,(%rsi)
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax)
L12:
  movb   $0x0,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int div2(char *numantes, char *numdepois) {
  int prox_val = 0, val_atual;
  while (*numantes != '\0') {
    val_atual = prox_val;
    prox_val = 0;
    if (*numantes % 2)
      prox_val = 5;
    *numdepois = (*numantes - '0') / 2 + val_atual + '0';
    ++numantes;
    ++numdepois;
  }
  *numdepois = '\0';
  return (prox_val / 5);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<div2>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L10
  xor    %r8d,%r8d
  jmp    L13
L2:
  mov    %ecx,%r8d
L13:
  mov    %eax,%r9d
  mov    %eax,%ecx
  sub    $0x30,%eax
  add    $0x1,%rdi
  mov    %eax,%edx
  shl    $0x1f,%ecx
  and    $0x1,%r9d
  add    $0x1,%rsi
  shr    $0x1f,%edx
  sar    $0x1f,%ecx
  add    %edx,%eax
  and    $0x5,%ecx
  sar    %eax
  lea    0x30(%r8,%rax,1),%eax
  mov    %al,-0x1(%rsi)
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L2
  movb   $0x0,(%rsi)
  mov    %r9d,%eax
  ret
  nop
L10:
  xor    %r9d,%r9d
  movb   $0x0,(%rsi)
  mov    %r9d,%eax
  ret
```

assistant: ```c
int div2(char *numantes, char *numdepois) {
  int prox_val = 0, val_atual;
  while (*numantes != '\0') {
    val_atual = prox_val;
    prox_val = 0;
    if (*numantes % 2)
      prox_val = 5;
    *numdepois = (*numantes - '0') / 2 + val_atual + '0';
    ++numantes;
    ++numdepois;
  }
  *numdepois = '\0';
  return (prox_val / 5);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<spacer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L7
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L7:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x2c(%rbp),%edi
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <spacer>
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x2c(%rbp),%edi
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <spacer>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: %s


assistant: ```c
void spacer(char str[], char dstr[], int strI, int dstrI, int len) {
  int i = 0;
  if (strI == len) {
    dstr[dstrI] = '\0';
    printf("%s\n", dstr);
    return;
  }
  dstr[dstrI] = str[strI];
  spacer(str, dstr, strI + 1, dstrI + 1, len);
  dstr[dstrI] = ' ';
  dstr[dstrI + 1] = str[strI];
  spacer(str, dstr, strI + 1, dstrI + 2, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<spacer>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,%rbp
  mov    %ecx,%ebx
  cmp    %r8d,%edx
  je     L7
  mov    %r8d,%r12d
  movslq %edx,%r13
  mov    (%rsp),%rdi
  add    %rdi,%r13
  movslq %ecx,%r14
  lea    (%rsi,%r14,1),%r15
  movzbl 0x0(%r13),%eax
  mov    %al,(%r15)
  lea    0x1(%rdx),%eax
  lea    0x1(%rcx),%ecx
  mov    %eax,0xc(%rsp)
  mov    %eax,%edx
  call   <spacer>
  movb   $0x20,(%r15)
  movzbl 0x0(%r13),%eax
  mov    %al,0x1(%rbp,%r14,1)
  lea    0x2(%rbx),%ecx
  mov    %r12d,%r8d
  mov    0xc(%rsp),%edx
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   <spacer>
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  movslq %ecx,%rbx
  movb   $0x0,(%rsi,%rbx,1)
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L13
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: %s


assistant: ```c
void spacer(char str[], char dstr[], int strI, int dstrI, int len) {
  int i = 0;
  if (strI == len) {
    dstr[dstrI] = '\0';
    printf("%s\n", dstr);
    return;
  }
  dstr[dstrI] = str[strI];
  spacer(str, dstr, strI + 1, dstrI + 1, len);
  dstr[dstrI] = ' ';
  dstr[dstrI + 1] = str[strI];
  spacer(str, dstr, strI + 1, dstrI + 2, len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<spacer>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r8d,%edx
  je     L4
  lea    -0x1(%r8),%eax
  lea    0x1(%rdx),%ebx
  movslq %ecx,%rbp
  mov    %rdi,%r15
  sub    %edx,%eax
  movslq %edx,%rdx
  mov    %r8d,%r14d
  movslq %ebx,%rbx
  mov    %eax,%ecx
  mov    %eax,0xc(%rsp)
  lea    0x2(%rdx,%rcx,1),%rax
  mov    %rax,(%rsp)
L16:
  movzbl -0x1(%r15,%rbx,1),%edx
  lea    0x1(%rbp),%ecx
  mov    %r14d,%r8d
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %dl,(%r12,%rbp,1)
  mov    %ebx,%edx
  call   <spacer>
  movb   $0x20,(%r12,%rbp,1)
  movzbl -0x1(%r15,%rbx,1),%edx
  add    $0x1,%rbx
  mov    %dl,0x1(%r12,%rbp,1)
  add    $0x2,%rbp
  cmp    (%rsp),%rbx
  jne    L16
  mov    0xc(%rsp),%eax
  lea    0x2(%r13,%rax,2),%r13d
L4:
  movslq %r13d,%r13
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  movb   $0x0,(%r12,%r13,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: %s


assistant: ```c
void spacer(char str[], char dstr[], int strI, int dstrI, int len) {
  int i = 0;
  if (strI == len) {
    dstr[dstrI] = '\0';
    printf("%s\n", dstr);
    return;
  }
  dstr[dstrI] = str[strI];
  spacer(str, dstr, strI + 1, dstrI + 1, len);
  dstr[dstrI] = ' ';
  dstr[dstrI + 1] = str[strI];
  spacer(str, dstr, strI + 1, dstrI + 2, len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bug_after_abduction_bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x2a,(%rax)
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x2a,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bug_after_abduction_bad(int *x) {
  *x = 42;
  int *y = NULL;
  *y = 42;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bug_after_abduction_bad>:
  endbr64
  movl   $0x2a,(%rdi)
  movl   $0x2a,0x0
  ret
```

assistant: ```c
void bug_after_abduction_bad(int *x) {
  *x = 42;
  int *y = NULL;
  *y = 42;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bug_after_abduction_bad>:
  endbr64
  movl   $0x2a,(%rdi)
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void bug_after_abduction_bad(int *x) {
  *x = 42;
  int *y = NULL;
  *y = 42;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bug_after_abduction_bad>:
  endbr64
  movl   $0x2a,(%rdi)
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void bug_after_abduction_bad(int *x) {
  *x = 42;
  int *y = NULL;
  *y = 42;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<buscaBinaria>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L59
L49:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jne    L5
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x2c(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  jmp    L58
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jge    L27
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L59
L27:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L59:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L49
  mov    $0xffffffff,%eax
L58:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: f32[2]
name: read_data
arguments: label: D22
data_type: string
name: read_data
arguments: label: D24
data_type: string

tool: {"D9": [0.0,1.875]}

tool: D22: Tamanho: %d


tool: D24: Quant. de Comparacoes: %.0f


assistant: ```c
int buscaBinaria(int *vetor, int tam, int valor) {
  double comparacoes = 0;
  int inicio = 0;
  int fim = tam - 1;
  int meio;
  while (inicio <= fim) {
    meio = (inicio + fim) / 2;
    comparacoes++;
    if (valor == vetor[meio]) {
      printf("Tamanho: %d\n", tam);
      printf("Quant. de Comparacoes: %.0f\n", comparacoes);
      return meio;
    }
    if (valor < vetor[meio])
      fim = meio - 1;
    else
      inicio = meio + 1;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<buscaBinaria>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r9
  mov    %esi,%edi
  sub    $0x1,%edi
  js     L33
  mov    $0x0,%r8d
  mov    D29(%rip),%rbx
  movsd  D7(%rip),%xmm0
  jmp    L26
L24:
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  lea    D12(%rip),%rdi
  call   <printf@plt>
  movq   %rbx,%xmm0
  lea    D28(%rip),%rdi
  call   <printf@plt>
L27:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  lea    0x1(%rax),%r8d
L78:
  cmp    %edi,%r8d
  jg     L10
L26:
  lea    (%r8,%rdi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%ebp
  movq   %rbx,%xmm1
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rbx
  movslq %eax,%rcx
  mov    (%r9,%rcx,4),%ecx
  cmp    %edx,%ecx
  je     L24
  jle    L3
  lea    -0x1(%rax),%edi
  jmp    L78
L10:
  mov    $0xffffffff,%ebp
  jmp    L27
L33:
  mov    $0xffffffff,%ebp
  jmp    L27
```

tool_calls: name: disassemble_data
arguments: label: D29
type_infered: f64
name: disassemble_data
arguments: label: D7
type_infered: byte[8]
name: disassemble_data
arguments: label: D12
type_infered: string
name: disassemble_data
arguments: label: D28
type_infered: string

tool: D29: 0

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D12: Tamanho: %d


tool: D28: Quant. de Comparacoes: %.0f


assistant: ```c
int buscaBinaria(int *vetor, int tam, int valor) {
  double comparacoes = 0;
  int inicio = 0;
  int fim = tam - 1;
  int meio;
  while (inicio <= fim) {
    meio = (inicio + fim) / 2;
    comparacoes++;
    if (valor == vetor[meio]) {
      printf("Tamanho: %d\n", tam);
      printf("Quant. de Comparacoes: %.0f\n", comparacoes);
      return meio;
    }
    if (valor < vetor[meio])
      fim = meio - 1;
    else
      inicio = meio + 1;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<buscaBinaria>:
  endbr64
  push   %r12
  mov    %esi,%eax
  sub    $0x10,%rsp
  sub    $0x1,%eax
  js     L36
  movsd  D18(%rip),%xmm0
  xor    %ecx,%ecx
  pxor   %xmm1,%xmm1
  jmp    L51
  nopl   0x0(%rax)
L48:
  lea    -0x1(%r12),%eax
  cmp    %ecx,%eax
  jl     L36
L51:
  lea    (%rax,%rcx,1),%r12d
  addsd  %xmm0,%xmm1
  sar    %r12d
  movslq %r12d,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L28
  jg     L48
  lea    0x1(%r12),%ecx
  cmp    %ecx,%eax
  jge    L51
L36:
  mov    $0xffffffff,%r12d
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L28:
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %esi,%xmm0
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  lea    D5(%rip),%rdi
  movapd %xmm1,%xmm0
  call   <printf@plt>
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
data_type: f32[2]
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: {"D18": [0.0,1.875]}

tool: D1: Tamanho: %d


tool: D5: Quant. de Comparacoes: %.0f


assistant: ```c
int buscaBinaria(int *vetor, int tam, int valor) {
  double comparacoes = 0;
  int inicio = 0;
  int fim = tam - 1;
  int meio;
  while (inicio <= fim) {
    meio = (inicio + fim) / 2;
    comparacoes++;
    if (valor == vetor[meio]) {
      printf("Tamanho: %d\n", tam);
      printf("Quant. de Comparacoes: %.0f\n", comparacoes);
      return meio;
    }
    if (valor < vetor[meio])
      fim = meio - 1;
    else
      inicio = meio + 1;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<buscaBinaria>:
  endbr64
  push   %r12
  mov    %esi,%eax
  sub    $0x10,%rsp
  sub    $0x1,%eax
  js     L10
  movsd  D28(%rip),%xmm0
  xor    %ecx,%ecx
  pxor   %xmm1,%xmm1
  nop
L35:
  lea    (%rax,%rcx,1),%r12d
  addsd  %xmm0,%xmm1
  sar    %r12d
  movslq %r12d,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L29
  jle    L31
  lea    -0x1(%r12),%eax
  cmp    %ecx,%eax
  jge    L35
L10:
  mov    $0xffffffff,%r12d
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
L31:
  lea    0x1(%r12),%ecx
  cmp    %eax,%ecx
  jle    L35
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L29:
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %esi,%xmm0
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  lea    D9(%rip),%rdi
  movapd %xmm1,%xmm0
  call   <printf@plt>
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D28
data_type: f32[2]
name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: {"D28": [0.0,1.875]}

tool: D1: Tamanho: %d


tool: D9: Quant. de Comparacoes: %.0f


assistant: ```c
int buscaBinaria(int *vetor, int tam, int valor) {
  double comparacoes = 0;
  int inicio = 0;
  int fim = tam - 1;
  int meio;
  while (inicio <= fim) {
    meio = (inicio + fim) / 2;
    comparacoes++;
    if (valor == vetor[meio]) {
      printf("Tamanho: %d\n", tam);
      printf("Quant. de Comparacoes: %.0f\n", comparacoes);
      return meio;
    }
    if (valor < vetor[meio])
      fim = meio - 1;
    else
      inicio = meio + 1;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x418(%rbp)
  jmp    L74
L6:
  movl   $0x0,-0x424(%rbp)
  movl   $0x0,-0x41c(%rbp)
  jmp    L14
L28:
  mov    -0x424(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  cmp    $0x9,%al
  jne    L3
  mov    -0x418(%rbp),%edx
  mov    -0x41c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CalculateNumberOfSpaces@plt>
  mov    %eax,-0x414(%rbp)
  movl   $0x0,-0x420(%rbp)
  jmp    L61
L18:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x41c(%rbp)
  addl   $0x1,-0x420(%rbp)
L61:
  mov    -0x420(%rbp),%eax
  cmp    -0x414(%rbp),%eax
  jl     L18
  jmp    L50
L3:
  mov    -0x424(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x41c(%rbp)
L50:
  addl   $0x1,-0x424(%rbp)
L14:
  mov    -0x424(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L28
L74:
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jg     L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int main(void) {
  char Buffer[1024];
  int TabSize = 5;
  int i, j, k, l;
  while (get_line(Buffer, 1024) > 0) {
    for (i = 0, l = 0; Buffer[i] != '\0'; i++) {
      if (Buffer[i] == '\t') {
        j = CalculateNumberOfSpaces(l, TabSize);
        for (k = 0; k < j; k++) {
          putchar(' ');
          l++;
        }
      } else {
        putchar(Buffer[i]);
        l++;
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
L40:
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jle    L55
  movzbl (%rsp),%edi
  lea    0x1(%rsp),%rbp
  mov    $0x0,%r12d
  test   %dil,%dil
  jne    L56
  jmp    L40
L7:
  mov    $0x5,%esi
  mov    %r12d,%edi
  call   <CalculateNumberOfSpaces@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L77
  mov    $0x0,%ebx
L73:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jne    L73
  add    %ebx,%r12d
L77:
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edi
  test   %dil,%dil
  je     L40
L56:
  cmp    $0x9,%dil
  je     L7
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  jmp    L77
L55:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char Buffer[1024];
  int TabSize = 5;
  int i, j, k, l;
  while (get_line(Buffer, 1024) > 0) {
    for (i = 0, l = 0; Buffer[i] != '\0'; i++) {
      if (Buffer[i] == '\t') {
        j = CalculateNumberOfSpaces(l, TabSize);
        for (k = 0; k < j; k++) {
          putchar(' ');
          l++;
        }
      } else {
        putchar(Buffer[i]);
        l++;
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  nopl   0x0(%rax)
L47:
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jle    L20
  movsbl (%rsp),%edi
  lea    0x1(%rsp),%rbp
  xor    %r12d,%r12d
  test   %dil,%dil
  jne    L16
  jmp    L47
  nopl   (%rax)
L71:
  call   <putchar@plt>
  add    $0x1,%r12d
L22:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L47
L16:
  cmp    $0x9,%dil
  jne    L71
  mov    $0x5,%esi
  mov    %r12d,%edi
  call   <CalculateNumberOfSpaces@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L22
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L72:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r14d
  jne    L72
  add    %r14d,%r12d
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L20:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char Buffer[1024];
  int TabSize = 5;
  int i, j, k, l;
  while (get_line(Buffer, 1024) > 0) {
    for (i = 0, l = 0; Buffer[i] != '\0'; i++) {
      if (Buffer[i] == '\t') {
        j = CalculateNumberOfSpaces(l, TabSize);
        for (k = 0; k < j; k++) {
          putchar(' ');
          l++;
        }
      } else {
        putchar(Buffer[i]);
        l++;
      }
    }
  }
  return 0;
}
```