ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<shake128>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x188,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0xc8(%rsp),%rsi
L23:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L23
  mov    %rsp,%r13
  mov    $0x1f,%r8d
  mov    $0xa8,%esi
  mov    %r13,%rdi
  call   <keccak_absorb@plt>
  mov    %rbp,%rbx
  shr    $0x3,%rbx
  movabs $0xc30c30c30c30c31,%rdx
  mov    %rbx,%rax
  mul    %rdx
  mov    %rdx,%rbx
  mov    $0xa8,%ecx
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <keccak_squeezeblocks@plt>
  lea    (%rbx,%rbx,4),%rax
  lea    (%rbx,%rax,4),%rax
  shl    $0x3,%rax
  sub    %rax,%rbp
  jne    L27
L34:
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x188,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  lea    (%rbx,%rbx,4),%rax
  lea    (%rbx,%rax,4),%rbx
  shl    $0x3,%rbx
  mov    %rsp,%rdx
  lea    0xd0(%rsp),%rdi
  mov    $0xa8,%ecx
  mov    $0x1,%esi
  call   <keccak_squeezeblocks@plt>
  mov    $0x0,%eax
  add    %rbx,%r12
L41:
  movzbl 0xd0(%rsp,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rbp
  jne    L41
  jmp    L34
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void shake128(unsigned char *out, unsigned long long outlen, const unsigned char *in, unsigned long long inlen) {
  unsigned long long i;
  uint64_t s[25];
  unsigned char d[168];
  for (i = 0; i < 25; i++) {
    s[i] = 0;
  }
  keccak_absorb(s, 168, in, inlen, 0x1F);
  keccak_squeezeblocks(out, outlen / 168, s, 168);
  out += (outlen / 168) * 168;
  if (outlen % 168) {
    keccak_squeezeblocks(d, 1, s, 168);
    for (i = 0; i < outlen % 168; i++) {
      out[i] = d[i];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shake128>:
  endbr64
  push   %r14
  mov    %rcx,%r9
  mov    $0x19,%ecx
  mov    $0x1f,%r8d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xa8,%esi
  mov    %rbx,%rbp
  shr    $0x3,%rbp
  sub    $0x180,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r9,%rcx
  mov    %r13,%rdi
  call   <keccak_absorb@plt>
  mov    %rbp,%rax
  mov    $0xa8,%ecx
  mov    %r12,%rdi
  movabs $0xc30c30c30c30c31,%rdx
  mul    %rdx
  mov    %rdx,%rbp
  mov    %r13,%rdx
  mov    %ebp,%esi
  call   <keccak_squeezeblocks@plt>
  lea    0x0(%rbp,%rbp,4),%rax
  lea    0x0(%rbp,%rax,4),%rbp
  shl    $0x3,%rbp
  sub    %rbp,%rbx
  jne    L59
L15:
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0x180,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L59:
  mov    $0xa8,%ecx
  mov    %r13,%rdx
  mov    $0x1,%esi
  add    %rbp,%r12
  lea    0xd0(%rsp),%r14
  mov    %r14,%rdi
  call   <keccak_squeezeblocks@plt>
  cmp    $0x8,%ebx
  jae    L5
  test   $0x4,%bl
  jne    L23
  test   %ebx,%ebx
  je     L15
  movzbl 0xd0(%rsp),%eax
  mov    %al,(%r12)
  test   $0x2,%bl
  je     L15
  mov    %ebx,%ebx
  movzwl -0x2(%r14,%rbx,1),%eax
  mov    %ax,-0x2(%r12,%rbx,1)
  jmp    L15
  nop
L5:
  mov    0xd0(%rsp),%rax
  lea    0x8(%r12),%rdi
  mov    %r14,%rsi
  and    $0xfffffffffffffff8,%rdi
  mov    %rax,(%r12)
  mov    %ebx,%eax
  mov    -0x8(%r14,%rax,1),%rdx
  mov    %rdx,-0x8(%r12,%rax,1)
  sub    %rdi,%r12
  add    %r12d,%ebx
  sub    %r12,%rsi
  shr    $0x3,%ebx
  mov    %ebx,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  jmp    L15
L23:
  mov    0xd0(%rsp),%eax
  mov    %ebx,%ebx
  mov    %eax,(%r12)
  mov    -0x4(%r14,%rbx,1),%eax
  mov    %eax,-0x4(%r12,%rbx,1)
  jmp    L15
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void shake128(unsigned char *out, unsigned long long outlen, const unsigned char *in, unsigned long long inlen) {
  unsigned long long i;
  uint64_t s[25];
  unsigned char d[168];
  for (i = 0; i < 25; i++) {
    s[i] = 0;
  }
  keccak_absorb(s, 168, in, inlen, 0x1F);
  keccak_squeezeblocks(out, outlen / 168, s, 168);
  out += (outlen / 168) * 168;
  if (outlen % 168) {
    keccak_squeezeblocks(d, 1, s, 168);
    for (i = 0; i < outlen % 168; i++) {
      out[i] = d[i];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shake128>:
  endbr64
  push   %r14
  mov    %rcx,%r9
  mov    $0x19,%ecx
  mov    $0x1f,%r8d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xa8,%esi
  mov    %rbx,%rbp
  shr    $0x3,%rbp
  sub    $0x180,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r9,%rcx
  mov    %r13,%rdi
  call   <keccak_absorb@plt>
  mov    %rbp,%rax
  mov    $0xa8,%ecx
  mov    %r12,%rdi
  movabs $0xc30c30c30c30c31,%rdx
  mul    %rdx
  mov    %rdx,%rbp
  mov    %r13,%rdx
  mov    %ebp,%esi
  call   <keccak_squeezeblocks@plt>
  lea    0x0(%rbp,%rbp,4),%rax
  lea    0x0(%rbp,%rax,4),%rbp
  shl    $0x3,%rbp
  sub    %rbp,%rbx
  jne    L84
L57:
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x180,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L84:
  mov    $0xa8,%ecx
  mov    %r13,%rdx
  mov    $0x1,%esi
  add    %rbp,%r12
  lea    0xd0(%rsp),%r14
  mov    %r14,%rdi
  call   <keccak_squeezeblocks@plt>
  cmp    $0x8,%ebx
  jae    L63
  test   $0x4,%bl
  jne    L20
  test   %ebx,%ebx
  je     L57
  movzbl 0xd0(%rsp),%eax
  mov    %al,(%r12)
  test   $0x2,%bl
  je     L57
  mov    %ebx,%ebx
  movzwl -0x2(%r14,%rbx,1),%eax
  mov    %ax,-0x2(%r12,%rbx,1)
  jmp    L57
  nop
L63:
  mov    0xd0(%rsp),%rax
  lea    0x8(%r12),%rdi
  mov    %r14,%rsi
  and    $0xfffffffffffffff8,%rdi
  mov    %rax,(%r12)
  mov    %ebx,%eax
  mov    -0x8(%r14,%rax,1),%rdx
  mov    %rdx,-0x8(%r12,%rax,1)
  sub    %rdi,%r12
  add    %r12d,%ebx
  sub    %r12,%rsi
  shr    $0x3,%ebx
  mov    %ebx,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  jmp    L57
L20:
  mov    0xd0(%rsp),%eax
  mov    %ebx,%ebx
  mov    %eax,(%r12)
  mov    -0x4(%r14,%rbx,1),%eax
  mov    %eax,-0x4(%r12,%rbx,1)
  jmp    L57
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void shake128(unsigned char *out, unsigned long long outlen, const unsigned char *in, unsigned long long inlen) {
  unsigned long long i;
  uint64_t s[25];
  unsigned char d[168];
  for (i = 0; i < 25; i++) {
    s[i] = 0;
  }
  keccak_absorb(s, 168, in, inlen, 0x1F);
  keccak_squeezeblocks(out, outlen / 168, s, 168);
  out += (outlen / 168) * 168;
  if (outlen % 168) {
    keccak_squeezeblocks(d, 1, s, 168);
    for (i = 0; i < outlen % 168; i++) {
      out[i] = d[i];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<v4l_format_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void v4l_format_init(struct v4l2_format *fmt, unsigned type) {
  memset(fmt, 0, sizeof(*fmt));
  fmt->type = type;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<v4l_format_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x4,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void v4l_format_init(struct v4l2_format *fmt, unsigned type) {
  memset(fmt, 0, sizeof(*fmt));
  fmt->type = type;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<v4l_format_init>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void v4l_format_init(struct v4l2_format *fmt, unsigned type) {
  memset(fmt, 0, sizeof(*fmt));
  fmt->type = type;
}
```
user: What is the c source code of the assembly code below:

```asm
<v4l_format_init>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void v4l_format_init(struct v4l2_format *fmt, unsigned type) {
  memset(fmt, 0, sizeof(*fmt));
  fmt->type = type;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_charset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <nl_langinfo@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *get_charset(void) {
  const char *codeset = nl_langinfo(CODESET);
  return codeset;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_charset>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <nl_langinfo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
const char *get_charset(void) {
  const char *codeset = nl_langinfo(CODESET);
  return codeset;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_charset>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <nl_langinfo@plt>
```

assistant: ```c
const char *get_charset(void) {
  const char *codeset = nl_langinfo(CODESET);
  return codeset;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_charset>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <nl_langinfo@plt>
```

assistant: ```c
const char *get_charset(void) {
  const char *codeset = nl_langinfo(CODESET);
  return codeset;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<AONBatMonNewBatteryMeasureReady>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4009502c,%eax
  mov    (%rax),%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L0
  mov    $0x4009502c,%eax
  movq   $0x1,(%rax)
L0:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
bool AONBatMonNewBatteryMeasureReady(void) {
  bool bStatus;
  bStatus = (*((volatile unsigned long *)(0x40095000 + 0x0000002C))) & 0x00000001 ? true : false;
  if (bStatus) {
    (*((volatile unsigned long *)(0x40095000 + 0x0000002C))) = 1;
  }
  return (bStatus);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<AONBatMonNewBatteryMeasureReady>:
  endbr64
  mov    0x4009502c,%rax
  test   $0x1,%al
  setne  %al
  movzbl %al,%eax
  je     L7
  movq   $0x1,0x4009502c
L7:
  ret
```

assistant: ```c
bool AONBatMonNewBatteryMeasureReady(void) {
  bool bStatus;
  bStatus = (*((volatile unsigned long *)(0x40095000 + 0x0000002C))) & 0x00000001 ? true : false;
  if (bStatus) {
    (*((volatile unsigned long *)(0x40095000 + 0x0000002C))) = 1;
  }
  return (bStatus);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<AONBatMonNewBatteryMeasureReady>:
  endbr64
  mov    0x4009502c,%rax
  and    $0x1,%eax
  mov    %eax,%r8d
  je     L9
  movq   $0x1,0x4009502c
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool AONBatMonNewBatteryMeasureReady(void) {
  bool bStatus;
  bStatus = (*((volatile unsigned long *)(0x40095000 + 0x0000002C))) & 0x00000001 ? true : false;
  if (bStatus) {
    (*((volatile unsigned long *)(0x40095000 + 0x0000002C))) = 1;
  }
  return (bStatus);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AONBatMonNewBatteryMeasureReady>:
  endbr64
  mov    0x4009502c,%rax
  and    $0x1,%eax
  mov    %eax,%r8d
  je     L4
  movq   $0x1,0x4009502c
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool AONBatMonNewBatteryMeasureReady(void) {
  bool bStatus;
  bStatus = (*((volatile unsigned long *)(0x40095000 + 0x0000002C))) & 0x00000001 ? true : false;
  if (bStatus) {
    (*((volatile unsigned long *)(0x40095000 + 0x0000002C))) = 1;
  }
  return (bStatus);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x6,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L53
  mov    -0x1c(%rbp),%eax
  jmp    L34
L53:
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x5,%eax
  jle    L14
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movb   $0x0,(%rax)
L14:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L7
  mov    -0x1c(%rbp),%eax
  jmp    L34
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L8
  mov    -0x20(%rbp),%eax
  jmp    L34
L8:
  mov    -0xc(%rbp),%eax
L34:
  leave
  ret
```

assistant: ```c
int getInt(char *s, int low, int high) {
  int ival;
  char *temp = malloc(6);
  if (s == NULL)
    return low;
  strncpy(temp, s, 5);
  if (strlen(s) > 5)
    *(temp + 5) = '\0';
  ival = atoi(temp);
  free(temp);
  if (ival < low)
    return low;
  if (ival > high)
    return high;
  return ival;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    $0x6,%edi
  call   <malloc@plt>
  test   %r13,%r13
  je     L18
  mov    %rax,%r12
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x5,%eax
  jle    L14
  movb   $0x0,0x5(%r12)
L14:
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  mov    %r12,%rdi
  call   <free@plt>
  cmp    %ebp,%r13d
  cmovle %r13d,%ebp
  cmp    %ebx,%r13d
  cmovge %ebp,%ebx
L18:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getInt(char *s, int low, int high) {
  int ival;
  char *temp = malloc(6);
  if (s == NULL)
    return low;
  strncpy(temp, s, 5);
  if (strlen(s) > 5)
    *(temp + 5) = '\0';
  ival = atoi(temp);
  free(temp);
  if (ival < low)
    return low;
  if (ival > high)
    return high;
  return ival;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getInt>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    $0x6,%edi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %r12,%r12
  je     L8
  mov    %rax,%rdi
  mov    $0x5,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    $0x5,%eax
  jle    L20
  movb   $0x0,0x5(%rbp)
L20:
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  cmp    %ebx,%r12d
  jl     L8
  cmp    %r13d,%r12d
  mov    %r13d,%eax
  cmovle %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getInt(char *s, int low, int high) {
  int ival;
  char *temp = malloc(6);
  if (s == NULL)
    return low;
  strncpy(temp, s, 5);
  if (strlen(s) > 5)
    *(temp + 5) = '\0';
  ival = atoi(temp);
  free(temp);
  if (ival < low)
    return low;
  if (ival > high)
    return high;
  return ival;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getInt>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    $0x6,%edi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %r12,%r12
  je     L6
  mov    %rax,%rdi
  mov    $0x5,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    $0x5,%eax
  jle    L0
  movb   $0x0,0x5(%rbp)
L0:
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  cmp    %ebx,%r12d
  jl     L6
  cmp    %r13d,%r12d
  mov    %r13d,%eax
  cmovle %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getInt(char *s, int low, int high) {
  int ival;
  char *temp = malloc(6);
  if (s == NULL)
    return low;
  strncpy(temp, s, 5);
  if (strlen(s) > 5)
    *(temp + 5) = '\0';
  ival = atoi(temp);
  free(temp);
  if (ival < low)
    return low;
  if (ival > high)
    return high;
  return ival;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x2625000(%rsp),%r11
L45:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L45
  sub    $0xa20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x2625a14(%rbp)
  jmp    L48
L25:
  lea    -0x2625a10(%rbp),%rdx
  mov    -0x2625a14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x2625a14(%rbp)
L48:
  cmpl   $0x98967f,-0x2625a14(%rbp)
  jle    L25
  lea    -0x2625a10(%rbp),%rax
  mov    $0x98967f,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <quick_sort@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x2625a14(%rbp)
  jmp    L36
L18:
  mov    -0x2625a14(%rbp),%eax
  cltq
  mov    -0x2625a10(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x2625a14(%rbp)
L36:
  cmpl   $0x98967f,-0x2625a14(%rbp)
  jle    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string
name: parse_data
arguments: label: D23
type_infered: string

tool: D17: %d

tool: D19: 
Final array  :

tool: D23: %d


assistant: ```c
int main() {
  int A[9999999 + 1];
  int i;
  for (i = 1; i <= 9999999; i += 1)
    scanf("%d", &A[i]);
  quick_sort(A, 1, 9999999);
  printf("\nFinal array  :\n");
  for (i = 1; i <= 9999999; i++)
    printf("%d\n", A[i]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x2625000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0xa18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2625a08(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x2625a00(%rsp),%r12
  mov    %rbx,%rbp
  lea    D7(%rip),%r13
L4:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L4
  mov    %rsp,%rdi
  mov    $0x98967f,%edx
  mov    $0x1,%esi
  call   <quick_sort@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rbp
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x2625a08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x2625a18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D22
type_infered: string

tool: D7: %d

tool: D2: 
Final array  :

tool: D22: %d


assistant: ```c
int main() {
  int A[9999999 + 1];
  int i;
  for (i = 1; i <= 9999999; i += 1)
    scanf("%d", &A[i]);
  quick_sort(A, 1, 9999999);
  printf("\nFinal array  :\n");
  for (i = 1; i <= 9999999; i++)
    printf("%d\n", A[i]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x2625000(%rsp),%r11
L7:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L7
  sub    $0xa18,%rsp
  lea    D11(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x2625a08(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x2625a00(%rsp),%r12
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L32:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L32
  mov    %rsp,%rdi
  mov    $0x98967f,%edx
  mov    $0x1,%esi
  call   <quick_sort@plt>
  lea    D13(%rip),%rdi
  lea    D23(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L29:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x2625a08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x2625a18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string

tool: D11: %d

tool: D13: 
Final array  :

tool: D23: %d


assistant: ```c
int main() {
  int A[9999999 + 1];
  int i;
  for (i = 1; i <= 9999999; i += 1)
    scanf("%d", &A[i]);
  quick_sort(A, 1, 9999999);
  printf("\nFinal array  :\n");
  for (i = 1; i <= 9999999; i++)
    printf("%d\n", A[i]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x2625000(%rsp),%r11
L37:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L37
  sub    $0xa18,%rsp
  lea    D10(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x2625a08(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x2625a00(%rsp),%r12
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L15:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L15
  mov    %rsp,%rdi
  mov    $0x98967f,%edx
  mov    $0x1,%esi
  call   <quick_sort@plt>
  lea    D18(%rip),%rdi
  lea    D8(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x2625a08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x2625a18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type: string
name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D8
type: string

tool: D10: %d

tool: D18: 
Final array  :

tool: D8: %d


assistant: ```c
int main() {
  int A[9999999 + 1];
  int i;
  for (i = 1; i <= 9999999; i += 1)
    scanf("%d", &A[i]);
  quick_sort(A, 1, 9999999);
  printf("\nFinal array  :\n");
  for (i = 1; i <= 9999999; i++)
    printf("%d\n", A[i]);
  printf("\n");
  return 0;
}
```