ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_unescape>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  je     L54
  lea    D5(%rip),%r8
  jmp    L143
  xchg   %ax,%ax
L44:
  mov    %dl,-0x1(%rcx)
  mov    %rdi,%rbx
  mov    %esi,%edx
L110:
  test   %dl,%dl
  je     L54
L143:
  movzbl 0x1(%rbx),%esi
  add    $0x1,%rcx
  lea    0x1(%rbx),%rdi
  cmp    $0x5c,%dl
  jne    L44
  lea    -0x30(%rsi),%edx
  cmp    $0x46,%dl
  ja     L82
  movzbl %dl,%edx
  movslq (%r8,%rdx,4),%rdx
  add    %r8,%rdx
  notrack jmp *%rdx
  nopw   0x0(%rax,%rax,1)
L54:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
  nopl   (%rax)
L82:
  movzbl 0x2(%rbx),%edx
  mov    %sil,-0x1(%rcx)
  add    $0x2,%rbx
  jmp    L110
  xchg   %ax,%ax
  lea    0x4(%rbx),%r9
  movb   $0x0,-0x1(%rcx)
  cmp    %r9,%rdi
  jae    L62
  mov    %r9,%rbx
  mov    %esi,%edx
L182:
  lea    -0x30(%rdx),%esi
  cmp    $0x7,%sil
  ja     L28
  movzbl -0x1(%rcx),%esi
  add    $0x1,%rdi
  lea    -0x30(%rdx,%rsi,8),%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rdi),%edx
  cmp    %rdi,%r9
  jne    L182
  jmp    L110
  movzbl 0x2(%rbx),%edx
  movb   $0x7,-0x1(%rcx)
  add    $0x2,%rbx
  jmp    L110
  movzbl 0x2(%rbx),%edx
  movb   $0xc,-0x1(%rcx)
  add    $0x2,%rbx
  jmp    L110
  movzbl 0x2(%rbx),%edx
  movb   $0x8,-0x1(%rcx)
  add    $0x2,%rbx
  jmp    L110
  movzbl 0x2(%rbx),%edx
  movb   $0xb,-0x1(%rcx)
  add    $0x2,%rbx
  jmp    L110
  movzbl 0x2(%rbx),%edx
  movb   $0x9,-0x1(%rcx)
  add    $0x2,%rbx
  jmp    L110
  movzbl 0x2(%rbx),%edx
  movb   $0xd,-0x1(%rcx)
  add    $0x2,%rbx
  jmp    L110
  movzbl 0x2(%rbx),%edx
  movb   $0xa,-0x1(%rcx)
  add    $0x2,%rbx
  jmp    L110
L62:
  mov    %rdi,%rbx
  mov    %esi,%edx
  jmp    L143
L28:
  mov    %rdi,%rbx
  jmp    L110
```

assistant: ```c
char *str_unescape(const char *source) {
  const char *p = source;
  const char *octal;
  char *dest = calloc(strlen(source) + 1, sizeof(char));
  char *q = dest;
  while (*p) {
    if (*p == '\\') {
      p++;
      switch (*p) {
      case '0' ... '7':
        *q = 0;
        octal = p;
        while ((p < octal + 3) && (*p >= '0') && (*p <= '7')) {
          *q = (*q * 8) + (*p - '0');
          p++;
        }
        q++;
        p--;
        break;
      case 'a':
        *q++ = '\a';
        break;
      case 'b':
        *q++ = '\b';
        break;
      case 'f':
        *q++ = '\f';
        break;
      case 'n':
        *q++ = '\n';
        break;
      case 'r':
        *q++ = '\r';
        break;
      case 't':
        *q++ = '\t';
        break;
      case 'v':
        *q++ = '\v';
        break;
      default:
        *q++ = *p;
        break;
      }
    } else {
      *q++ = *p;
    }
    p++;
  }
  *q = 0;
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_unescape>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r8
  movzbl (%rbx),%eax
  mov    %r8,%rdx
  test   %al,%al
  je     L43
  lea    D8(%rip),%rdi
  jmp    L89
  nopl   0x0(%rax)
L160:
  mov    %al,-0x1(%rdx)
  mov    %rsi,%rbx
  mov    %ecx,%eax
L37:
  test   %al,%al
  je     L43
L89:
  movzbl 0x1(%rbx),%ecx
  add    $0x1,%rdx
  lea    0x1(%rbx),%rsi
  cmp    $0x5c,%al
  jne    L160
  lea    -0x30(%rcx),%esi
  movzbl 0x2(%rbx),%eax
  cmp    $0x46,%sil
  ja     L100
  movzbl %sil,%esi
  movslq (%rdi,%rsi,4),%rsi
  add    %rdi,%rsi
  notrack jmp *%rsi
  nop
L43:
  movb   $0x0,(%rdx)
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L100:
  mov    %cl,-0x1(%rdx)
  add    $0x2,%rbx
  jmp    L37
  nopl   0x0(%rax)
  lea    -0x30(%rax),%esi
  lea    0x4(%rbx),%r9
  sub    $0x30,%ecx
  cmp    $0x7,%sil
  ja     L100
  movzbl 0x3(%rbx),%eax
  lea    (%rsi,%rcx,8),%ecx
  mov    %cl,-0x1(%rdx)
  lea    -0x30(%rax),%esi
  cmp    $0x7,%sil
  ja     L158
  lea    (%rsi,%rcx,8),%ecx
  movzbl 0x4(%rbx),%eax
  mov    %r9,%rbx
  mov    %cl,-0x1(%rdx)
  jmp    L37
  movb   $0x7,-0x1(%rdx)
  add    $0x2,%rbx
  jmp    L37
  movb   $0xc,-0x1(%rdx)
  add    $0x2,%rbx
  jmp    L37
  movb   $0x8,-0x1(%rdx)
  add    $0x2,%rbx
  jmp    L37
  movb   $0xb,-0x1(%rdx)
  add    $0x2,%rbx
  jmp    L37
  movb   $0x9,-0x1(%rdx)
  add    $0x2,%rbx
  jmp    L37
  movb   $0xd,-0x1(%rdx)
  add    $0x2,%rbx
  jmp    L37
  movb   $0xa,-0x1(%rdx)
  add    $0x2,%rbx
  jmp    L37
L158:
  add    $0x3,%rbx
  jmp    L37
```

assistant: ```c
char *str_unescape(const char *source) {
  const char *p = source;
  const char *octal;
  char *dest = calloc(strlen(source) + 1, sizeof(char));
  char *q = dest;
  while (*p) {
    if (*p == '\\') {
      p++;
      switch (*p) {
      case '0' ... '7':
        *q = 0;
        octal = p;
        while ((p < octal + 3) && (*p >= '0') && (*p <= '7')) {
          *q = (*q * 8) + (*p - '0');
          p++;
        }
        q++;
        p--;
        break;
      case 'a':
        *q++ = '\a';
        break;
      case 'b':
        *q++ = '\b';
        break;
      case 'f':
        *q++ = '\f';
        break;
      case 'n':
        *q++ = '\n';
        break;
      case 'r':
        *q++ = '\r';
        break;
      case 't':
        *q++ = '\t';
        break;
      case 'v':
        *q++ = '\v';
        break;
      default:
        *q++ = *p;
        break;
      }
    } else {
      *q++ = *p;
    }
    p++;
  }
  *q = 0;
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dead_result7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dead_result7(int *data) {
  int j = data[2];
  data[j] = 2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dead_result7>:
  endbr64
  movslq 0x8(%rdi),%rax
  movl   $0x2,(%rdi,%rax,4)
  ret
```

assistant: ```c
void dead_result7(int *data) {
  int j = data[2];
  data[j] = 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dead_result7>:
  endbr64
  movslq 0x8(%rdi),%rax
  movl   $0x2,(%rdi,%rax,4)
  ret
```

assistant: ```c
void dead_result7(int *data) {
  int j = data[2];
  data[j] = 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<realloc_usvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L8:
  mov    -0x10(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string

tool: D8: allocation failure in realloc usvector()

assistant: ```c
ushort *realloc_usvector(ushort *v, long nl, long nh, long n) {
  v += nl;
  v -= 0;
  v = (ushort *)realloc(v, (size_t)((nh - nl + 1 + n + 0) * sizeof(ushort)));
  if (!v)
    nrerror("allocation failure in realloc usvector()");
  return v - nl + 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<realloc_usvector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x0(,%rsi,4),%rbp
  sub    %rsi,%rdx
  lea    0x1(%rdx,%rcx,1),%rsi
  shl    $0x2,%rsi
  add    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
L4:
  mov    %rbx,%rax
  sub    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  lea    D1(%rip),%rdi
  call   <nrerror@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string

tool: D1: allocation failure in realloc usvector()

assistant: ```c
ushort *realloc_usvector(ushort *v, long nl, long nh, long n) {
  v += nl;
  v -= 0;
  v = (ushort *)realloc(v, (size_t)((nh - nl + 1 + n + 0) * sizeof(ushort)));
  if (!v)
    nrerror("allocation failure in realloc usvector()");
  return v - nl + 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<realloc_usvector>:
  endbr64
  push   %rbp
  sub    %rsi,%rdx
  lea    0x0(,%rsi,4),%rbp
  push   %rbx
  lea    0x1(%rdx,%rcx,1),%rsi
  add    %rbp,%rdi
  shl    $0x2,%rsi
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %rbx,%rax
  add    $0x8,%rsp
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D9(%rip),%rdi
  call   <nrerror@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: allocation failure in realloc usvector()

assistant: ```c
ushort *realloc_usvector(ushort *v, long nl, long nh, long n) {
  v += nl;
  v -= 0;
  v = (ushort *)realloc(v, (size_t)((nh - nl + 1 + n + 0) * sizeof(ushort)));
  if (!v)
    nrerror("allocation failure in realloc usvector()");
  return v - nl + 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<realloc_usvector>:
  endbr64
  push   %rbp
  sub    %rsi,%rdx
  lea    0x0(,%rsi,4),%rbp
  push   %rbx
  lea    0x1(%rdx,%rcx,1),%rsi
  add    %rbp,%rdi
  shl    $0x2,%rsi
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %rbx,%rax
  add    $0x8,%rsp
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  lea    D1(%rip),%rdi
  call   <nrerror@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: allocation failure in realloc usvector()

assistant: ```c
ushort *realloc_usvector(ushort *v, long nl, long nh, long n) {
  v += nl;
  v -= 0;
  v = (ushort *)realloc(v, (size_t)((nh - nl + 1 + n + 0) * sizeof(ushort)));
  if (!v)
    nrerror("allocation failure in realloc usvector()");
  return v - nl + 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<encshare1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4d4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <encshare2@plt>
  jmp    L28
L22:
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  cmp    $0x3f,%rax
  jne    L5
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <encshare2@plt>
L5:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  xor    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x10(%rbp)
L28:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L22
  nop
  nop
  leave
  ret
```

assistant: ```c
void encshare1(unsigned int *tbuff, unsigned char *datap, int len) {
  unsigned char *p, *s;
  p = s = (unsigned char *)(tbuff + 309);
  encshare2(tbuff, (unsigned int *)p, 16);
  while (len--) {
    if ((p - s) == 63) {
      p = s;
      encshare2(tbuff, (unsigned int *)p, 16);
    }
    *datap ^= *p;
    datap++;
    p++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<encshare1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %edx,%ebp
  lea    0x4d4(%rdi),%r12
  mov    $0x10,%edx
  mov    %r12,%rsi
  call   <encshare2@plt>
  test   %ebp,%ebp
  je     L48
  mov    %ebp,%ebp
  add    %rbx,%rbp
  mov    %r12,%rax
  jmp    L40
L11:
  mov    $0x10,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <encshare2@plt>
  mov    %r12,%rax
L40:
  movzbl (%rax),%edx
  xor    %dl,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%rax
  cmp    %rbx,%rbp
  je     L48
  mov    %rax,%rdx
  sub    %r12,%rdx
  cmp    $0x3f,%rdx
  jne    L40
  jmp    L11
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void encshare1(unsigned int *tbuff, unsigned char *datap, int len) {
  unsigned char *p, *s;
  p = s = (unsigned char *)(tbuff + 309);
  encshare2(tbuff, (unsigned int *)p, 16);
  while (len--) {
    if ((p - s) == 63) {
      p = s;
      encshare2(tbuff, (unsigned int *)p, 16);
    }
    *datap ^= *p;
    datap++;
    p++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<encshare1>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x4d4(%rdi),%r12
  push   %rbp
  mov    %edx,%ebp
  mov    $0x10,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %r12,%rsi
  sub    $0x8,%rsp
  call   <encshare2@plt>
  test   %ebp,%ebp
  je     L30
  add    %rbx,%rbp
  mov    %r12,%rax
  nopl   0x0(%rax)
L29:
  movzbl (%rax),%edx
  xor    %dl,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%rax
  cmp    %rbx,%rbp
  je     L30
  mov    %rax,%rdx
  sub    %r12,%rdx
  cmp    $0x3f,%rdx
  jne    L29
  mov    $0x10,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <encshare2@plt>
  mov    %r12,%rax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void encshare1(unsigned int *tbuff, unsigned char *datap, int len) {
  unsigned char *p, *s;
  p = s = (unsigned char *)(tbuff + 309);
  encshare2(tbuff, (unsigned int *)p, 16);
  while (len--) {
    if ((p - s) == 63) {
      p = s;
      encshare2(tbuff, (unsigned int *)p, 16);
    }
    *datap ^= *p;
    datap++;
    p++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<encshare1>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  mov    $0x10,%edx
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    0x4d4(%rdi),%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %r13,%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <encshare2@plt>
  test   %r15d,%r15d
  je     L8
  movzbl 0x4d4(%r14),%eax
  lea    0x4d5(%r14),%r12
  xor    %al,0x0(%rbp)
  mov    %r15d,%eax
  lea    0x1(%rbp),%rbx
  add    %rax,%rbp
  mov    %r12,%rax
  cmp    $0x1,%r15d
  je     L8
  nopl   0x0(%rax)
L6:
  mov    %rax,%rdx
  sub    %r13,%rdx
  cmp    $0x3f,%rdx
  je     L37
  movzbl (%rax),%edx
  xor    %dl,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%rax
  cmp    %rbx,%rbp
  jne    L6
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L37:
  mov    $0x10,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <encshare2@plt>
  movzbl 0x4d4(%r14),%eax
  xor    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L8
  mov    %r12,%rax
  jmp    L6
```

assistant: ```c
void encshare1(unsigned int *tbuff, unsigned char *datap, int len) {
  unsigned char *p, *s;
  p = s = (unsigned char *)(tbuff + 309);
  encshare2(tbuff, (unsigned int *)p, 16);
  while (len--) {
    if ((p - s) == 63) {
      p = s;
      encshare2(tbuff, (unsigned int *)p, 16);
    }
    *datap ^= *p;
    datap++;
    p++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m7_setParams>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L7
  mov    $0x0,%eax
  call   <ppuSetNameTblSingleUpper@plt>
  jmp    L3
L7:
  mov    $0x0,%eax
  call   <ppuSetNameTblSingleLower@plt>
L3:
  mov    -0x8(%rbp),%eax
  shl    $0xf,%eax
  and    $0x38000,%eax
  mov    %eax,%edi
  call   <prg32setBank0@plt>
  nop
  leave
  ret
```

assistant: ```c
void m7_setParams(uint16_t addr, uint8_t val) {
  (void)addr;
  if (val & (1 << 4))
    ppuSetNameTblSingleUpper();
  else
    ppuSetNameTblSingleLower();
  prg32setBank0((val & 7) << 15);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<m7_setParams>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  test   $0x10,%sil
  je     L2
  mov    $0x0,%eax
  call   <ppuSetNameTblSingleUpper@plt>
L4:
  shl    $0xf,%ebx
  mov    %ebx,%edi
  and    $0x38000,%edi
  call   <prg32setBank0@plt>
  pop    %rbx
  ret
L2:
  mov    $0x0,%eax
  call   <ppuSetNameTblSingleLower@plt>
  jmp    L4
```

assistant: ```c
void m7_setParams(uint16_t addr, uint8_t val) {
  (void)addr;
  if (val & (1 << 4))
    ppuSetNameTblSingleUpper();
  else
    ppuSetNameTblSingleLower();
  prg32setBank0((val & 7) << 15);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<m7_setParams>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %esi,%ebx
  and    $0x10,%esi
  je     L6
  call   <ppuSetNameTblSingleUpper@plt>
L4:
  shl    $0xf,%ebx
  mov    %ebx,%edi
  pop    %rbx
  and    $0x38000,%edi
  jmp    1090 <prg32setBank0@plt>
  nopl   0x0(%rax)
L6:
  call   <ppuSetNameTblSingleLower@plt>
  jmp    L4
```

assistant: ```c
void m7_setParams(uint16_t addr, uint8_t val) {
  (void)addr;
  if (val & (1 << 4))
    ppuSetNameTblSingleUpper();
  else
    ppuSetNameTblSingleLower();
  prg32setBank0((val & 7) << 15);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m7_setParams>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %esi,%ebx
  and    $0x10,%esi
  je     L9
  call   <ppuSetNameTblSingleUpper@plt>
L5:
  shl    $0xf,%ebx
  mov    %ebx,%edi
  pop    %rbx
  and    $0x38000,%edi
  jmp    1090 <prg32setBank0@plt>
  nopl   0x0(%rax)
L9:
  call   <ppuSetNameTblSingleLower@plt>
  jmp    L5
```

assistant: ```c
void m7_setParams(uint16_t addr, uint8_t val) {
  (void)addr;
  if (val & (1 << 4))
    ppuSetNameTblSingleUpper();
  else
    ppuSetNameTblSingleLower();
  prg32setBank0((val & 7) << 15);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_unnamed@plt>
  mov    $0x0,%eax
  call   <test_named@plt>
  mov    $0x0,%eax
  call   <test_named2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  test_unnamed();
  test_named();
  test_named2();
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_unnamed@plt>
  mov    $0x0,%eax
  call   <test_named@plt>
  mov    $0x0,%eax
  call   <test_named2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_unnamed();
  test_named();
  test_named2();
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_unnamed@plt>
  xor    %eax,%eax
  call   <test_named@plt>
  xor    %eax,%eax
  call   <test_named2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_unnamed();
  test_named();
  test_named2();
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_unnamed@plt>
  xor    %eax,%eax
  call   <test_named@plt>
  xor    %eax,%eax
  call   <test_named2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_unnamed();
  test_named();
  test_named2();
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<queue_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L14
L10:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_dequeue@plt>
L14:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <queue_empty@plt>
  test   %eax,%eax
  je     L10
  nop
  leave
  ret
```

assistant: ```c
void queue_clear(struct queue *theQueue) {
  while (!queue_empty(theQueue))
    queue_dequeue(theQueue);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<queue_clear>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L19
L0:
  mov    %rbx,%rdi
  call   <queue_dequeue@plt>
L19:
  mov    %rbx,%rdi
  call   <queue_empty@plt>
  test   %eax,%eax
  je     L0
  pop    %rbx
  ret
```

assistant: ```c
void queue_clear(struct queue *theQueue) {
  while (!queue_empty(theQueue))
    queue_dequeue(theQueue);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<queue_clear>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rbx,%rdi
  call   <queue_dequeue@plt>
L2:
  mov    %rbx,%rdi
  call   <queue_empty@plt>
  test   %eax,%eax
  je     L7
  pop    %rbx
  ret
```

assistant: ```c
void queue_clear(struct queue *theQueue) {
  while (!queue_empty(theQueue))
    queue_dequeue(theQueue);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<queue_clear>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  call   <queue_dequeue@plt>
L1:
  mov    %rbx,%rdi
  call   <queue_empty@plt>
  test   %eax,%eax
  je     L0
  pop    %rbx
  ret
```

assistant: ```c
void queue_clear(struct queue *theQueue) {
  while (!queue_empty(theQueue))
    queue_dequeue(theQueue);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edi
  movslq %edi,%rax
  imul   %rax,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L17:
  cmp    %rdx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L17
L15:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L22
  orq    $0x0,-0x8(%rsp,%rax,1)
L22:
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <fillMatrix@plt>
  mov    %rbx,%rsi
  mov    -0x1c(%rbp),%edi
  call   <printMatrix@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    -0x1c(%rbp),%edi
  call   <rotateMatrix@plt>
  mov    %rbx,%rsi
  mov    -0x1c(%rbp),%edi
  call   <printMatrix@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string

tool: D9: Please enter matrix's dimension: 

tool: D1: %d

tool: D7: 


assistant: ```c
int main(void) {
  void fillMatrix(int n, int matrix[n][n]);
  void printMatrix(int n, int matrix[n][n]);
  int n = 0;
  printf("Please enter matrix's dimension: ");
  scanf("%d", &n);
  int matrix[n][n];
  fillMatrix(n, matrix);
  printMatrix(n, matrix);
  printf("\n");
  rotateMatrix(n, matrix);
  printMatrix(n, matrix);
  return 0;
}
```