ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<set>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <rewind@plt>
  mov    %ebx,%edx
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    $0x7f,%edx
  lea    D2(%rip),%rsi
  test   %rax,%rax
  js     L3
  mov    %rbp,%rdi
  call   <get@plt>
  cmp    %eax,%ebx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x83,%edx
  lea    D4(%rip),%rsi
L3:
  add    $0x8,%rsp
  mov    $0x5,%edi
  pop    %rbx
  pop    %rbp
  jmp    1080 <shutdown@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D2
type: string
name: disassemble_data
arguments: data_tag: D4
type: string

tool: D8: %d

tool: D2: Failed writing to /proc file

tool: D4: We didn't get what we wrote to /proc back

assistant: ```c
void set(FILE *stream, int value) {
  int new_value;
  rewind(stream);
  if (fprintf(stream, "%d", value) < 0)
    return shutdown(5, "Failed writing to /proc file", 128 - 1);
  new_value = get(stream);
  if (new_value != value)
    return shutdown(5, "We didn't get what we wrote to /proc back", 132 - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <rewind@plt>
  mov    %ebx,%edx
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    $0x7f,%edx
  lea    D4(%rip),%rsi
  test   %rax,%rax
  js     L15
  mov    %rbp,%rdi
  call   <get@plt>
  cmp    %eax,%ebx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  mov    $0x83,%edx
  lea    D28(%rip),%rsi
L15:
  add    $0x8,%rsp
  mov    $0x5,%edi
  pop    %rbx
  pop    %rbp
  jmp    1080 <shutdown@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D28
type: string

tool: D16: %d

tool: D4: Failed writing to /proc file

tool: D28: We didn't get what we wrote to /proc back

assistant: ```c
void set(FILE *stream, int value) {
  int new_value;
  rewind(stream);
  if (fprintf(stream, "%d", value) < 0)
    return shutdown(5, "Failed writing to /proc file", 128 - 1);
  new_value = get(stream);
  if (new_value != value)
    return shutdown(5, "We didn't get what we wrote to /proc back", 132 - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L3:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0xff,-0x4(%rbp)
  jle    L3
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: %d-->%c 


assistant: ```c
void main(void) {
  int i = 0;
  for (; i <= 255; i++) {
    printf("%d-->%c \n", i, i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
L0:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: %d-->%c 


assistant: ```c
void main(void) {
  int i = 0;
  for (; i <= 255; i++) {
    printf("%d-->%c \n", i, i);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D0: %d-->%c 


assistant: ```c
void main(void) {
  int i = 0;
  for (; i <= 255; i++) {
    printf("%d-->%c \n", i, i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: %d-->%c 


assistant: ```c
void main(void) {
  int i = 0;
  for (; i <= 255; i++) {
    printf("%d-->%c \n", i, i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<handle_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%edi
  call   <irc_reconnect@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int handle_error(int type, struct irc_handler_info *info) {
  irc_reconnect(NULL);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<handle_error>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <irc_reconnect@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int handle_error(int type, struct irc_handler_info *info) {
  irc_reconnect(NULL);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_error>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <irc_reconnect@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int handle_error(int type, struct irc_handler_info *info) {
  irc_reconnect(NULL);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<handle_error>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <irc_reconnect@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int handle_error(int type, struct irc_handler_info *info) {
  irc_reconnect(NULL);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    -0x8(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rcx
  mov    D10(%rip),%rdx
  mov    D2(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_scn@plt>
  leave
  ret
```

assistant: ```c
int sscanf(line, format)
char *line, *format;
{
  int _sgetc(), _sungetc();
  return _scn(&format, &_sgetc, &_sungetc, &line);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sscanf>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,(%rsp)
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rdi
  mov    D14(%rip),%rdx
  mov    D7(%rip),%rsi
  mov    $0x0,%eax
  call   <_scn@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int sscanf(line, format)
char *line, *format;
{
  int _sgetc(), _sungetc();
  return _scn(&format, &_sgetc, &_sungetc, &line);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sscanf>:
  endbr64
  sub    $0x18,%rsp
  mov    D2(%rip),%rdx
  xor    %eax,%eax
  mov    %rsi,(%rsp)
  mov    D18(%rip),%rsi
  lea    0x8(%rsp),%rcx
  mov    %rdi,0x8(%rsp)
  mov    %rsp,%rdi
  call   <_scn@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int sscanf(line, format)
char *line, *format;
{
  int _sgetc(), _sungetc();
  return _scn(&format, &_sgetc, &_sungetc, &line);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sscanf>:
  endbr64
  sub    $0x18,%rsp
  mov    D2(%rip),%rdx
  xor    %eax,%eax
  mov    %rsi,(%rsp)
  mov    D6(%rip),%rsi
  lea    0x8(%rsp),%rcx
  mov    %rdi,0x8(%rsp)
  mov    %rsp,%rdi
  call   <_scn@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int sscanf(line, format)
char *line, *format;
{
  int _sgetc(), _sungetc();
  return _scn(&format, &_sgetc, &_sungetc, &line);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_argument_value>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%r15
  mov    %edx,%ebp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsbl %dl,%edx
  call   <argument_is_set@plt>
  test   %eax,%eax
  je     L43
  cltq
  shl    $0x3,%rax
  mov    %rax,0x8(%rsp)
  lea    (%r15,%rax,1),%r13
  mov    0x0(%r13),%rdx
  cmp    0x1(%rdx),%bpl
  je     L52
  mov    $0x1,%ebp
L59:
  add    $0x1,%ebp
  movsbq %bpl,%rax
  cmp    %bl,(%rdx,%rax,1)
  jne    L59
L75:
  mov    $0x0,%ebx
  movsbq %bpl,%rbp
  add    $0x1,%rbp
  jmp    L87
L52:
  mov    $0x1,%ebp
  jmp    L75
L74:
  mov    0x0(%r13),%rax
  movzbl (%rax,%r12,1),%eax
  mov    %al,0x1e(%rsp,%rbx,1)
  add    $0x1,%rbx
L87:
  mov    %ebx,%r14d
  lea    0x0(%rbp,%rbx,1),%r12
  mov    0x0(%r13),%rax
  movsbl (%rax,%r12,1),%edi
  call   <char_to_int@plt>
  cmp    $0xffffffff,%eax
  jne    L74
  test   %ebx,%ebx
  jne    L13
  mov    0x8(%rsp),%rax
  lea    0x8(%r15,%rax,1),%rbp
  mov    $0x0,%ebx
L18:
  mov    %ebx,%r14d
  mov    0x0(%rbp),%rax
  movsbl (%rax,%rbx,1),%edi
  call   <char_to_int@plt>
  cmp    $0xffffffff,%eax
  je     L94
  mov    0x0(%rbp),%rax
  movzbl (%rax,%rbx,1),%eax
  mov    %al,0x1e(%rsp,%rbx,1)
  add    $0x1,%rbx
  jmp    L18
L94:
  test   %ebx,%ebx
  je     L76
L13:
  movslq %r14d,%r14
  movb   $0x0,0x1e(%rsp,%r14,1)
  lea    0x1e(%rsp),%rdi
  call   <atoi@plt>
L76:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  mov    $0xffffffff,%eax
  jmp    L76
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_argument_value(int args_count, char *args[], char arg) {
  int index_arg_value_str = (0);
  int arg_value;
  char arg_value_str[(10)];
  char char_pos = 1;
  int arg_pos = argument_is_set(args_count, args, arg);
  if (arg_pos == (0)) {
    return (-1);
  }
  while (args[arg_pos][char_pos] != arg) {
    char_pos++;
  }
  while (char_to_int(args[arg_pos][(index_arg_value_str + (char_pos + 1))]) != (-1)) {
    arg_value_str[index_arg_value_str] = args[arg_pos][(index_arg_value_str + (char_pos + 1))];
    index_arg_value_str++;
  }
  if (index_arg_value_str == (0)) {
    while (char_to_int(args[(arg_pos + 1)][index_arg_value_str]) != (-1)) {
      arg_value_str[index_arg_value_str] = args[(arg_pos + 1)][index_arg_value_str];
      index_arg_value_str++;
    }
  }
  if (index_arg_value_str == (0))
    return (-1);
  arg_value_str[index_arg_value_str] = ('\0');
  arg_value = atoi(arg_value_str);
  return arg_value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_argument_value>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edx,%ebx
  movsbl %dl,%edx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <argument_is_set@plt>
  test   %eax,%eax
  je     L93
  cltq
  shl    $0x3,%rax
  lea    (%r15,%rax,1),%r13
  mov    %rax,0x8(%rsp)
  mov    0x0(%r13),%rax
  cmp    %bpl,0x1(%rax)
  je     L1
  mov    $0x1,%ebp
  nopl   0x0(%rax,%rax,1)
L97:
  add    $0x1,%ebp
  movsbq %bpl,%rdx
  cmp    %bl,(%rax,%rdx,1)
  jne    L97
  movsbl %bpl,%ebp
  add    $0x1,%ebp
L43:
  xor    %ebx,%ebx
  movslq %ebp,%rbp
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L96:
  mov    0x0(%r13),%rax
  movzbl (%rax,%r14,1),%edx
  mov    %dl,0x1e(%rsp,%rbx,1)
  add    $0x1,%rbx
L22:
  lea    0x0(%rbp,%rbx,1),%r14
  movslq %ebx,%r12
  movsbl (%rax,%r14,1),%edi
  call   <char_to_int@plt>
  cmp    $0xffffffff,%eax
  jne    L96
  test   %r12d,%r12d
  jne    L25
  mov    0x8(%rsp),%rax
  xor    %ebx,%ebx
  lea    0x8(%r15,%rax,1),%rbp
  mov    0x0(%rbp),%rax
  jmp    L20
  nop
L53:
  mov    0x0(%rbp),%rax
  movzbl (%rax,%rbx,1),%edx
  mov    %dl,0x1e(%rsp,%rbx,1)
  add    $0x1,%rbx
L20:
  movsbl (%rax,%rbx,1),%edi
  movslq %ebx,%r12
  call   <char_to_int@plt>
  cmp    $0xffffffff,%eax
  jne    L53
  test   %r12d,%r12d
  je     L93
L25:
  lea    0x1e(%rsp),%rdi
  movb   $0x0,0x1e(%rsp,%r12,1)
  call   <atoi@plt>
L94:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L1:
  mov    $0x2,%ebp
  jmp    L43
L93:
  mov    $0xffffffff,%eax
  jmp    L94
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_argument_value(int args_count, char *args[], char arg) {
  int index_arg_value_str = (0);
  int arg_value;
  char arg_value_str[(10)];
  char char_pos = 1;
  int arg_pos = argument_is_set(args_count, args, arg);
  if (arg_pos == (0)) {
    return (-1);
  }
  while (args[arg_pos][char_pos] != arg) {
    char_pos++;
  }
  while (char_to_int(args[arg_pos][(index_arg_value_str + (char_pos + 1))]) != (-1)) {
    arg_value_str[index_arg_value_str] = args[arg_pos][(index_arg_value_str + (char_pos + 1))];
    index_arg_value_str++;
  }
  if (index_arg_value_str == (0)) {
    while (char_to_int(args[(arg_pos + 1)][index_arg_value_str]) != (-1)) {
      arg_value_str[index_arg_value_str] = args[(arg_pos + 1)][index_arg_value_str];
      index_arg_value_str++;
    }
  }
  if (index_arg_value_str == (0))
    return (-1);
  arg_value_str[index_arg_value_str] = ('\0');
  arg_value = atoi(arg_value_str);
  return arg_value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_argument_value>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edx,%ebx
  movsbl %dl,%edx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <argument_is_set@plt>
  test   %eax,%eax
  je     L13
  cltq
  shl    $0x3,%rax
  lea    (%r15,%rax,1),%r13
  mov    %rax,0x8(%rsp)
  mov    0x0(%r13),%rax
  cmp    %bpl,0x1(%rax)
  je     L77
  mov    $0x1,%ebp
  nopl   0x0(%rax,%rax,1)
L87:
  add    $0x1,%ebp
  movsbq %bpl,%rdx
  cmp    %bl,(%rax,%rdx,1)
  jne    L87
  movsbl %bpl,%ebp
  add    $0x1,%ebp
L24:
  xor    %ebx,%ebx
  movslq %ebp,%rbp
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L107:
  mov    0x0(%r13),%rax
  movzbl (%rax,%r14,1),%edx
  mov    %dl,0x1e(%rsp,%rbx,1)
  add    $0x1,%rbx
L20:
  lea    0x0(%rbp,%rbx,1),%r14
  movslq %ebx,%r12
  movsbl (%rax,%r14,1),%edi
  call   <char_to_int@plt>
  cmp    $0xffffffff,%eax
  jne    L107
  test   %r12d,%r12d
  jne    L52
  mov    0x8(%rsp),%rax
  xor    %ebx,%ebx
  lea    0x8(%r15,%rax,1),%rbp
  mov    0x0(%rbp),%rax
  jmp    L6
  nop
L89:
  mov    0x0(%rbp),%rax
  movzbl (%rax,%rbx,1),%edx
  mov    %dl,0x1e(%rsp,%rbx,1)
  add    $0x1,%rbx
L6:
  movsbl (%rax,%rbx,1),%edi
  movslq %ebx,%r12
  call   <char_to_int@plt>
  cmp    $0xffffffff,%eax
  jne    L89
  test   %r12d,%r12d
  je     L13
L52:
  lea    0x1e(%rsp),%rdi
  movb   $0x0,0x1e(%rsp,%r12,1)
  call   <atoi@plt>
L106:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L77:
  mov    $0x2,%ebp
  jmp    L24
L13:
  mov    $0xffffffff,%eax
  jmp    L106
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_argument_value(int args_count, char *args[], char arg) {
  int index_arg_value_str = (0);
  int arg_value;
  char arg_value_str[(10)];
  char char_pos = 1;
  int arg_pos = argument_is_set(args_count, args, arg);
  if (arg_pos == (0)) {
    return (-1);
  }
  while (args[arg_pos][char_pos] != arg) {
    char_pos++;
  }
  while (char_to_int(args[arg_pos][(index_arg_value_str + (char_pos + 1))]) != (-1)) {
    arg_value_str[index_arg_value_str] = args[arg_pos][(index_arg_value_str + (char_pos + 1))];
    index_arg_value_str++;
  }
  if (index_arg_value_str == (0)) {
    while (char_to_int(args[(arg_pos + 1)][index_arg_value_str]) != (-1)) {
      arg_value_str[index_arg_value_str] = args[(arg_pos + 1)][index_arg_value_str];
      index_arg_value_str++;
    }
  }
  if (index_arg_value_str == (0))
    return (-1);
  arg_value_str[index_arg_value_str] = ('\0');
  arg_value = atoi(arg_value_str);
  return arg_value;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string

tool: D8: %d,%d


assistant: ```c
main() {
  int i = 0;
  int j = 1;
  ({
    int tmp;
    tmp = i, i = j, j = tmp;
  });
  printf("%d,%d\n", i, j);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: %d,%d


assistant: ```c
main() {
  int i = 0;
  int j = 1;
  ({
    int tmp;
    tmp = i, i = j, j = tmp;
  });
  printf("%d,%d\n", i, j);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string

tool: D1: %d,%d


assistant: ```c
main() {
  int i = 0;
  int j = 1;
  ({
    int tmp;
    tmp = i, i = j, j = tmp;
  });
  printf("%d,%d\n", i, j);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D5: %d,%d


assistant: ```c
main() {
  int i = 0;
  int j = 1;
  ({
    int tmp;
    tmp = i, i = j, j = tmp;
  });
  printf("%d,%d\n", i, j);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  je     L6
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <recurse>
  jmp    L4
L6:
  nop
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string

tool: D6: I am learning recursion.


assistant: ```c
void recurse(int count) {
  if (count == 5) {
    return;
  }
  printf("I am learning recursion.\n");
  recurse(count + 1);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<recurse>:
  endbr64
  cmp    $0x5,%edi
  je     L2
  push   %rbx
  mov    %edi,%ebx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x1(%rbx),%edi
  call   <recurse>
  pop    %rbx
  ret
L2:
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: I am learning recursion.


assistant: ```c
void recurse(int count) {
  if (count == 5) {
    return;
  }
  printf("I am learning recursion.\n");
  recurse(count + 1);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<recurse>:
  endbr64
  cmp    $0x5,%edi
  je     L0
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: I am learning recursion.


assistant: ```c
void recurse(int count) {
  if (count == 5) {
    return;
  }
  printf("I am learning recursion.\n");
  recurse(count + 1);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recurse>:
  endbr64
  cmp    $0x5,%edi
  je     L6
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: I am learning recursion.


assistant: ```c
void recurse(int count) {
  if (count == 5) {
    return;
  }
  printf("I am learning recursion.\n");
  recurse(count + 1);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__sys_exit@plt>
  int3
  jmp    L1
```

assistant: ```c
void _exit(int i) {
  while (1) {
    __sys_exit(i);
    asm("	int $3");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
L0:
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <__sys_exit@plt>
  int3
  jmp    L0
```

assistant: ```c
void _exit(int i) {
  while (1) {
    __sys_exit(i);
    asm("	int $3");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <__sys_exit@plt>
  int3
  jmp    L3
```

assistant: ```c
void _exit(int i) {
  while (1) {
    __sys_exit(i);
    asm("	int $3");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <__sys_exit@plt>
  int3
  jmp    L7
```

assistant: ```c
void _exit(int i) {
  while (1) {
    __sys_exit(i);
    asm("	int $3");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <semop@plt>
  cmp    $0xffffffff,%eax
  jne    L13
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D16
type: string

tool: D7: semop

tool: D16: p operation is fail


assistant: ```c
void p(int semid) {
  struct sembuf sem_p;
  sem_p.sem_op = -1;
  sem_p.sem_num = 0;
  sem_p.sem_flg = 0;
  if (semop(semid, &sem_p, 1) == -1) {
    perror("semop");
    printf("p operation is fail\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<p>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x1,%edx
  call   <semop@plt>
  cmp    $0xffffffff,%eax
  je     L12
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L12:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string

tool: D1: semop

tool: D15: p operation is fail


assistant: ```c
void p(int semid) {
  struct sembuf sem_p;
  sem_p.sem_op = -1;
  sem_p.sem_num = 0;
  sem_p.sem_flg = 0;
  if (semop(semid, &sem_p, 1) == -1) {
    perror("semop");
    printf("p operation is fail\n");
  }
}
```