ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<ft_atoi>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %r12
  lea    D4(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strcmp@plt>
  test   %rax,%rax
  jne    L92
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rbx
L92:
  movzbl (%rbx),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L11
  cmp    $0x20,%al
  je     L11
  mov    $0x1,%r12d
  cmp    $0x2d,%al
  je     L113
L74:
  movsbl (%rbx),%edi
  cmp    $0x2b,%dil
  je     L49
L87:
  xor    %ebp,%ebp
  jmp    L120
  nopw   0x0(%rax,%rax,1)
L19:
  movsbl (%rbx),%eax
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
L120:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L19
  mov    %ebp,%eax
  imul   %r12d,%eax
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  jmp    L87
  nopw   0x0(%rax,%rax,1)
L113:
  movsbl 0x1(%rbx),%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  je     L97
  add    $0x1,%rbx
  mov    $0xffffffff,%r12d
  jmp    L74
L97:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
L64:
  mov    $0x80000000,%eax
  jmp    L52
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: -2147483648

assistant: ```c
int ft_atoi(const char *str) {
  int result;
  int sign;
  result = 0;
  sign = 1;
  if (!str)
    return (0);
  if (ft_strcmp(str, "-2147483648") == 0)
    return (-2147483648);
  while (*str == 32 || (*str >= 9 && *str <= 13))
    str++;
  if (*str == '-') {
    sign = -1;
    str++;
    if (ft_isdigit(*str) == 0)
      return (0);
  }
  if (*str == '+')
    str++;
  while (ft_isdigit(*str))
    result = result * 10 + *str++ - 48;
  return (sign * result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_atoi>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %r12
  lea    D8(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strcmp@plt>
  test   %rax,%rax
  jne    L74
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rbx
L74:
  movzbl (%rbx),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L25
  cmp    $0x20,%al
  je     L25
  mov    $0x1,%r12d
  cmp    $0x2d,%al
  je     L6
L100:
  cmp    $0x2b,%al
  sete   %al
  xor    %ebp,%ebp
  movzbl %al,%eax
  add    %rax,%rbx
  jmp    L17
  nopl   0x0(%rax)
L28:
  movsbl (%rbx),%eax
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
L17:
  movsbl (%rbx),%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L28
  mov    %ebp,%eax
  imul   %r12d,%eax
L95:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl 0x1(%rbx),%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  je     L79
  movzbl 0x1(%rbx),%eax
  mov    $0xffffffff,%r12d
  add    $0x1,%rbx
  jmp    L100
L79:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L21:
  xor    %eax,%eax
  ret
L32:
  mov    $0x80000000,%eax
  jmp    L95
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string

tool: D8: -2147483648

assistant: ```c
int ft_atoi(const char *str) {
  int result;
  int sign;
  result = 0;
  sign = 1;
  if (!str)
    return (0);
  if (ft_strcmp(str, "-2147483648") == 0)
    return (-2147483648);
  while (*str == 32 || (*str >= 9 && *str <= 13))
    str++;
  if (*str == '-') {
    sign = -1;
    str++;
    if (ft_isdigit(*str) == 0)
      return (0);
  }
  if (*str == '+')
    str++;
  while (ft_isdigit(*str))
    result = result * 10 + *str++ - 48;
  return (sign * result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  movq   $0x2,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L8
L9:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    %rax,-0x8(%rbp)
  addl   $0x2,-0x14(%rbp)
L8:
  cmpl   $0x63,-0x14(%rbp)
  jle    L9
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1: %llu
%llu


assistant: ```c
int main() {
  int i = 0;
  unsigned long long f1 = 2;
  unsigned long long f2 = 1;
  while (i < 100) {
    printf("%llu\n%llu\n", f1, f2);
    f1 = f1 + f2;
    f2 = f1 + f2;
    i += 2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x32,%r12d
  mov    $0x1,%ebp
  mov    $0x2,%ebx
  lea    D4(%rip),%r13
L7:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  add    %rbp,%rbx
  add    %rbx,%rbp
  sub    $0x1,%r12d
  jne    L7
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: %llu
%llu


assistant: ```c
int main() {
  int i = 0;
  unsigned long long f1 = 2;
  unsigned long long f2 = 1;
  while (i < 100) {
    printf("%llu\n%llu\n", f1, f2);
    f1 = f1 + f2;
    f2 = f1 + f2;
    i += 2;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    $0x32,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L1:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    %rbp,%rbx
  call   <printf@plt>
  add    %rbx,%rbp
  sub    $0x1,%r12d
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: %llu
%llu


assistant: ```c
int main() {
  int i = 0;
  unsigned long long f1 = 2;
  unsigned long long f2 = 1;
  while (i < 100) {
    printf("%llu\n%llu\n", f1, f2);
    f1 = f1 + f2;
    f2 = f1 + f2;
    i += 2;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    $0x32,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L6:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    %rbp,%rbx
  call   <printf@plt>
  add    %rbx,%rbp
  sub    $0x1,%r12d
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9: %llu
%llu


assistant: ```c
int main() {
  int i = 0;
  unsigned long long f1 = 2;
  unsigned long long f2 = 1;
  while (i < 100) {
    printf("%llu\n%llu\n", f1, f2);
    f1 = f1 + f2;
    f2 = f1 + f2;
    i += 2;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jle    L6
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <f@plt>
  jmp    L0
L6:
  nop
L0:
  leave
  ret
```

assistant: ```c
void f2(int n) {
  if (n < 3)
    return;
  n--;
  f(n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f2>:
  endbr64
  cmp    $0x2,%edi
  jg     L0
  ret
L0:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  call   <f@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f2(int n) {
  if (n < 3)
    return;
  n--;
  f(n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f2>:
  endbr64
  cmp    $0x2,%edi
  jg     L9
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%edi
  jmp    1050 <f@plt>
```

assistant: ```c
void f2(int n) {
  if (n < 3)
    return;
  n--;
  f(n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f2>:
  endbr64
  cmp    $0x2,%edi
  jg     L3
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  sub    $0x1,%edi
  jmp    1050 <f@plt>
```

assistant: ```c
void f2(int n) {
  if (n < 3)
    return;
  n--;
  f(n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<oml_lock_persistent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L6
L4:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <logwarn@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
L6:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <oml_lock@plt>
  test   %rax,%rax
  jne    L4
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
datatype: string

tool: D8: Cannot get lock in %s; will try again soon.


assistant: ```c
void oml_lock_persistent(pthread_mutex_t *mutexP, const char *mutexName) {
  while (oml_lock(mutexP, mutexName)) {
    logwarn("Cannot get lock in %s; will try again soon.\n", mutexName);
    sleep(1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<oml_lock_persistent>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D7(%rip),%r12
  jmp    L10
L16:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <logwarn@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
L10:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <oml_lock@plt>
  test   %rax,%rax
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
data_type: string

tool: D7: Cannot get lock in %s; will try again soon.


assistant: ```c
void oml_lock_persistent(pthread_mutex_t *mutexP, const char *mutexName) {
  while (oml_lock(mutexP, mutexName)) {
    logwarn("Cannot get lock in %s; will try again soon.\n", mutexName);
    sleep(1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<oml_lock_persistent>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <logwarn@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
L0:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <oml_lock@plt>
  test   %rax,%rax
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: Cannot get lock in %s; will try again soon.


assistant: ```c
void oml_lock_persistent(pthread_mutex_t *mutexP, const char *mutexName) {
  while (oml_lock(mutexP, mutexName)) {
    logwarn("Cannot get lock in %s; will try again soon.\n", mutexName);
    sleep(1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<oml_lock_persistent>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <logwarn@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
L14:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <oml_lock@plt>
  test   %rax,%rax
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: Cannot get lock in %s; will try again soon.


assistant: ```c
void oml_lock_persistent(pthread_mutex_t *mutexP, const char *mutexName) {
  while (oml_lock(mutexP, mutexName)) {
    logwarn("Cannot get lock in %s; will try again soon.\n", mutexName);
    sleep(1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sys_execve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <decode_execve@plt>
  mov    $0x40,%eax
  leave
  ret
```

assistant: ```c
int sys_execve(struct tcb *tcp) {
  decode_execve(tcp, 0);
  return 0100;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sys_execve>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  call   <decode_execve@plt>
  mov    $0x40,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sys_execve(struct tcb *tcp) {
  decode_execve(tcp, 0);
  return 0100;
}
```
user: What is the c source code of the assembly code below:

```asm
<sys_execve>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <decode_execve@plt>
  mov    $0x40,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sys_execve(struct tcb *tcp) {
  decode_execve(tcp, 0);
  return 0100;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sys_execve>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <decode_execve@plt>
  mov    $0x40,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sys_execve(struct tcb *tcp) {
  decode_execve(tcp, 0);
  return 0100;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nowhite_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L5
L29:
  addq   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L29
  jmp    L44
L17:
  addq   $0x1,-0x20(%rbp)
L44:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L100
L33:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  jmp    L3
L100:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L14:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L14
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L95:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L95
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
L3:
  leave
  ret
```

assistant: ```c
int nowhite_strcmp(char *s, char *t) {
  char *p;
  while (iswhite(*s))
    s++;
  while (iswhite(*t))
    t++;
  if ((*s == 0) || (*t == 0))
    return strcmp(s, t);
  p = s + strlen(s) - 1;
  while (iswhite(*p))
    *(p--) = 0;
  p = t + strlen(t) - 1;
  while (iswhite(*p))
    *(p--) = 0;
  return strcmp(s, t);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<nowhite_strcmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  jmp    L13
L106:
  add    $0x1,%rbx
L13:
  movsbl (%rbx),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L106
  jmp    L82
L99:
  add    $0x1,%rbp
L82:
  movsbl 0x0(%rbp),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L99
  cmpb   $0x0,(%rbx)
  je     L100
  cmpb   $0x0,0x0(%rbp)
  jne    L75
L100:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L75:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%r12
  jmp    L108
L78:
  sub    $0x1,%r12
  movb   $0x0,0x1(%r12)
L108:
  movsbl (%r12),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L78
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%r12
  jmp    L56
L102:
  sub    $0x1,%r12
  movb   $0x0,0x1(%r12)
L56:
  movsbl (%r12),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L102
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  jmp    L52
```

assistant: ```c
int nowhite_strcmp(char *s, char *t) {
  char *p;
  while (iswhite(*s))
    s++;
  while (iswhite(*t))
    t++;
  if ((*s == 0) || (*t == 0))
    return strcmp(s, t);
  p = s + strlen(s) - 1;
  while (iswhite(*p))
    *(p--) = 0;
  p = t + strlen(t) - 1;
  while (iswhite(*p))
    *(p--) = 0;
  return strcmp(s, t);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nowhite_strcmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L25
L98:
  add    $0x1,%rbp
L25:
  movsbl 0x0(%rbp),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L98
  movsbl (%r12),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  je     L40
  nopl   0x0(%rax)
L17:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L17
L40:
  cmpb   $0x0,0x0(%rbp)
  je     L34
  cmpb   $0x0,(%r12)
  jne    L44
L34:
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strcmp@plt>
  nopl   0x0(%rax,%rax,1)
L44:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  jmp    L8
  nopl   0x0(%rax)
L77:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L8:
  movsbl (%rbx),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L77
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L54
  nopl   (%rax)
L18:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L54:
  movsbl (%rbx),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L18
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strcmp@plt>
```

assistant: ```c
int nowhite_strcmp(char *s, char *t) {
  char *p;
  while (iswhite(*s))
    s++;
  while (iswhite(*t))
    t++;
  if ((*s == 0) || (*t == 0))
    return strcmp(s, t);
  p = s + strlen(s) - 1;
  while (iswhite(*p))
    *(p--) = 0;
  p = t + strlen(t) - 1;
  while (iswhite(*p))
    *(p--) = 0;
  return strcmp(s, t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nowhite_strcmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L97
L82:
  add    $0x1,%rbp
L97:
  movsbl 0x0(%rbp),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L82
  movsbl (%r12),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  je     L66
  nopl   0x0(%rax)
L39:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L39
L66:
  cmpb   $0x0,0x0(%rbp)
  je     L48
  cmpb   $0x0,(%r12)
  jne    L84
L48:
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strcmp@plt>
  nopl   0x0(%rax,%rax,1)
L84:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  jmp    L76
  nopl   0x0(%rax)
L69:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L76:
  movsbl (%rbx),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L69
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L86
  nopl   (%rax)
L87:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L86:
  movsbl (%rbx),%edi
  call   <iswhite@plt>
  test   %rax,%rax
  jne    L87
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strcmp@plt>
```

assistant: ```c
int nowhite_strcmp(char *s, char *t) {
  char *p;
  while (iswhite(*s))
    s++;
  while (iswhite(*t))
    t++;
  if ((*s == 0) || (*t == 0))
    return strcmp(s, t);
  p = s + strlen(s) - 1;
  while (iswhite(*p))
    *(p--) = 0;
  p = t + strlen(t) - 1;
  while (iswhite(*p))
    *(p--) = 0;
  return strcmp(s, t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_escape_display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0xc(%rbp),%eax
  add    %rax,-0x8(%rbp)
L18:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void str_escape_display(const char *str, int len) {
  const char *tmpPtr = str;
  unsigned int tmpLen = 0;
  while (len > 0) {
    tmpLen = strlen(tmpPtr) + 1;
    putchar('\t');
    puts(tmpPtr);
    len -= tmpLen;
    tmpPtr += tmpLen;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_escape_display>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L12
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12d,%eax
  sub    %ebx,%eax
  mov    %eax,%r12d
  mov    %ebx,%ebx
  add    %rbx,%rbp
  test   %eax,%eax
  jg     L11
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void str_escape_display(const char *str, int len) {
  const char *tmpPtr = str;
  unsigned int tmpLen = 0;
  while (len > 0) {
    tmpLen = strlen(tmpPtr) + 1;
    putchar('\t');
    puts(tmpPtr);
    len -= tmpLen;
    tmpPtr += tmpLen;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str_escape_display>:
  endbr64
  test   %esi,%esi
  jle    L10
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x9,%edi
  lea    0x1(%rax),%ebx
  call   <putchar@plt>
  sub    %ebx,%r12d
  mov    %rbp,%rdi
  add    %rbx,%rbp
  call   <puts@plt>
  test   %r12d,%r12d
  jg     L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L10:
  ret
```

assistant: ```c
void str_escape_display(const char *str, int len) {
  const char *tmpPtr = str;
  unsigned int tmpLen = 0;
  while (len > 0) {
    tmpLen = strlen(tmpPtr) + 1;
    putchar('\t');
    puts(tmpPtr);
    len -= tmpLen;
    tmpPtr += tmpLen;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_escape_display>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x9,%edi
  lea    0x1(%rax),%ebx
  call   <putchar@plt>
  sub    %ebx,%r12d
  mov    %rbp,%rdi
  add    %rbx,%rbp
  call   <puts@plt>
  test   %r12d,%r12d
  jg     L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L14:
  ret
```

assistant: ```c
void str_escape_display(const char *str, int len) {
  const char *tmpPtr = str;
  unsigned int tmpLen = 0;
  while (len > 0) {
    tmpLen = strlen(tmpPtr) + 1;
    putchar('\t');
    puts(tmpPtr);
    len -= tmpLen;
    tmpPtr += tmpLen;
  }
}
```