ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_addrport>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  mov    $0x3a,%esi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L83
  movb   $0x0,(%rax)
L83:
  lea    0x4(%rsp),%r15
  mov    %rbp,%rdi
  mov    %r15,%rsi
  call   <inet_aton@plt>
  test   %rax,%rax
  je     L76
  mov    0x4(%rsp),%eax
L9:
  mov    %eax,(%r14)
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L64
  lea    0x1(%rbx),%rbp
  mov    $0xffff,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <string_to_number@plt>
  mov    %rax,%rdi
  cmp    $0xffffffffffffffff,%rax
  je     L36
L31:
  call   <htons@plt>
  mov    %eax,(%r12)
  mov    $0x2,%eax
L64:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %rbp,%rdi
  mov    %r13d,%esi
  call   <service_to_port@plt>
  mov    %rax,%rdi
  cmp    $0xffffffffffffffff,%rax
  jne    L31
  xor    %eax,%eax
  jmp    L64
L76:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <host_to_addr@plt>
  mov    %eax,%r8d
  mov    0x4(%rsp),%eax
  cmp    $0xffffffff,%r8d
  jne    L9
  xor    %eax,%eax
  jmp    L64
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_addrport(char *buf, u_int16_t proto, u_int32_t *addr, u_int16_t *port) {
  char *pp;
  long prt;
  struct in_addr inaddr;
  pp = strchr(buf, ':');
  if (pp)
    *pp = '\0';
  if (inet_aton(buf, &inaddr) != 0)
    *addr = inaddr.s_addr;
  else if (host_to_addr(buf, &inaddr) != -1)
    *addr = inaddr.s_addr;
  else
    return 0;
  if (pp == NULL)
    return 1;
  if ((prt = string_to_number(pp + 1, 0, 65535)) != -1)
    *port = htons(prt);
  else if ((prt = service_to_port(pp + 1, proto)) != -1)
    *port = htons(prt);
  else
    return 0;
  return 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_addrport>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  mov    $0x3a,%esi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L30
  movb   $0x0,(%rax)
L30:
  lea    0x4(%rsp),%r15
  mov    %rbp,%rdi
  mov    %r15,%rsi
  call   <inet_aton@plt>
  test   %rax,%rax
  je     L33
  mov    0x4(%rsp),%eax
L51:
  mov    %eax,(%r14)
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L28
  lea    0x1(%rbx),%rbp
  mov    $0xffff,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <string_to_number@plt>
  mov    %rax,%rdi
  cmp    $0xffffffffffffffff,%rax
  je     L6
L77:
  call   <htons@plt>
  mov    %eax,(%r12)
  mov    $0x2,%eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  mov    %r13d,%esi
  call   <service_to_port@plt>
  mov    %rax,%rdi
  cmp    $0xffffffffffffffff,%rax
  jne    L77
  xor    %eax,%eax
  jmp    L28
L33:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <host_to_addr@plt>
  mov    %eax,%r8d
  mov    0x4(%rsp),%eax
  cmp    $0xffffffff,%r8d
  jne    L51
  xor    %eax,%eax
  jmp    L28
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_addrport(char *buf, u_int16_t proto, u_int32_t *addr, u_int16_t *port) {
  char *pp;
  long prt;
  struct in_addr inaddr;
  pp = strchr(buf, ':');
  if (pp)
    *pp = '\0';
  if (inet_aton(buf, &inaddr) != 0)
    *addr = inaddr.s_addr;
  else if (host_to_addr(buf, &inaddr) != -1)
    *addr = inaddr.s_addr;
  else
    return 0;
  if (pp == NULL)
    return 1;
  if ((prt = string_to_number(pp + 1, 0, 65535)) != -1)
    *port = htons(prt);
  else if ((prt = service_to_port(pp + 1, proto)) != -1)
    *port = htons(prt);
  else
    return 0;
  return 2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L28
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L28
  cmpl   $0xa,-0x8(%rbp)
  jne    L25
L28:
  cmpl   $0xa,-0x8(%rbp)
  jne    L43
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L43:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getln(char s[], int maxlen) {
  int c, i;
  for (i = 0; i < maxlen - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n')
    s[i++] = c;
  s[i] = '\0';
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<getln>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L22
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L41
  cmp    $0xa,%eax
  je     L41
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L2
  mov    %r12d,%ebx
  jmp    L13
L22:
  mov    $0x0,%ebx
L41:
  cmp    $0xa,%eax
  je     L47
L13:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  lea    0x1(%rbx),%ebx
  jmp    L13
```

assistant: ```c
int getln(char s[], int maxlen) {
  int c, i;
  for (i = 0; i < maxlen - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n')
    s[i++] = c;
  s[i] = '\0';
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getln>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L4
  mov    D1(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L49:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L22
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L3
  mov    %edx,%r14d
L56:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L49
  cmp    $0xa,%eax
  je     L17
L4:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  lea    0x1(%r14),%edx
L22:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L3:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getln(char s[], int maxlen) {
  int c, i;
  for (i = 0; i < maxlen - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n')
    s[i++] = c;
  s[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getln>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L37
  mov    D9(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L1:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L52
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %edx,%ebp
  je     L28
  mov    %edx,%r14d
L23:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L1
  cmp    $0xa,%eax
  je     L44
L37:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  lea    0x1(%r14),%edx
L52:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L28:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getln(char s[], int maxlen) {
  int c, i;
  for (i = 0; i < maxlen - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
    s[i] = c;
  if (c == '\n')
    s[i++] = c;
  s[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<std_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x1,-0x9(%rbp)
  jmp    L16
L4:
  cmpb   $0xa,-0x9(%rbp)
  jle    L6
  mov    $0xffffffff,%edi
  call   <exit@plt>
L6:
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  add    $0x1,%edx
  mov    %dl,-0x9(%rbp)
  movsbl %al,%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,%edi
  call   <sleep@plt>
L16:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *std_realloc(void *ptr, size_t newsize) {
  void *mem;
  char inter_multi = 1;
  while ((mem = realloc(ptr, newsize)) == NULL) {
    if (inter_multi > 10)
      exit(-1);
    sleep(1000 * inter_multi++);
  }
  return mem;
}
```
user: What is the c source code of the assembly code below?

```asm
<std_realloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x1,%r12d
L13:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L32
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  cmp    $0xa,%r12b
  jg     L6
L35:
  lea    0x1(%r12),%r13d
  movsbl %r12b,%edi
  imul   $0x3e8,%edi,%edi
  call   <sleep@plt>
  mov    %r13d,%r12d
  jmp    L13
L6:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L35
```

assistant: ```c
void *std_realloc(void *ptr, size_t newsize) {
  void *mem;
  char inter_multi = 1;
  while ((mem = realloc(ptr, newsize)) == NULL) {
    if (inter_multi > 10)
      exit(-1);
    sleep(1000 * inter_multi++);
  }
  return mem;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<std_realloc>:
  endbr64
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
L29:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L34
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  cmp    $0xa,%r12b
  jg     L15
L14:
  movsbl %r12b,%edi
  lea    0x1(%r12),%r13d
  imul   $0x3e8,%edi,%edi
  mov    %r13d,%r12d
  call   <sleep@plt>
  jmp    L29
L15:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L14
```

assistant: ```c
void *std_realloc(void *ptr, size_t newsize) {
  void *mem;
  char inter_multi = 1;
  while ((mem = realloc(ptr, newsize)) == NULL) {
    if (inter_multi > 10)
      exit(-1);
    sleep(1000 * inter_multi++);
  }
  return mem;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<std_realloc>:
  endbr64
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
L20:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  cmp    $0xa,%r12b
  jg     L7
L3:
  movsbl %r12b,%edi
  lea    0x1(%r12),%r13d
  imul   $0x3e8,%edi,%edi
  mov    %r13d,%r12d
  call   <sleep@plt>
  jmp    L20
L7:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L3
```

assistant: ```c
void *std_realloc(void *ptr, size_t newsize) {
  void *mem;
  char inter_multi = 1;
  while ((mem = realloc(ptr, newsize)) == NULL) {
    if (inter_multi > 10)
      exit(-1);
    sleep(1000 * inter_multi++);
  }
  return mem;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L11:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L16:
  mov    $0x0,%eax
  call   <getc@plt>
  mov    %al,-0x9(%rbp)
  cmpb   $0xd,-0x9(%rbp)
  jne    L11
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *gets(char buf[]) {
  char c, *ptr = buf;
  while ((c = getc()) != '\r') {
    *ptr++ = c;
  }
  *ptr = '\0';
  return (buf);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gets>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  jmp    L16
L15:
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
L16:
  mov    $0x0,%eax
  call   <getc@plt>
  cmp    $0xd,%al
  jne    L15
  movb   $0x0,(%rbx)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *gets(char buf[]) {
  char c, *ptr = buf;
  while ((c = getc()) != '\r') {
    *ptr++ = c;
  }
  *ptr = '\0';
  return (buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gets>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %al,(%rbx)
  add    $0x1,%rbx
L19:
  xor    %eax,%eax
  call   <getc@plt>
  cmp    $0xd,%al
  jne    L18
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *gets(char buf[]) {
  char c, *ptr = buf;
  while ((c = getc()) != '\r') {
    *ptr++ = c;
  }
  *ptr = '\0';
  return (buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gets>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %al,(%rbx)
  add    $0x1,%rbx
L1:
  xor    %eax,%eax
  call   <getc@plt>
  cmp    $0xd,%al
  jne    L7
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *gets(char buf[]) {
  char c, *ptr = buf;
  while ((c = getc()) != '\r') {
    *ptr++ = c;
  }
  *ptr = '\0';
  return (buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<current_time_ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x18(%rbp),%rax
  imul   $0x3b9aca00,%rax,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
unsigned long long current_time_ns() {
  struct timespec t = {0, 0};
  clock_gettime(CLOCK_MONOTONIC, &t);
  unsigned long long s = 1000000000ULL * (unsigned long long)t.tv_sec;
  return (((unsigned long long)t.tv_nsec)) + s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<current_time_ns>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long current_time_ns() {
  struct timespec t = {0, 0};
  clock_gettime(CLOCK_MONOTONIC, &t);
  unsigned long long s = 1000000000ULL * (unsigned long long)t.tv_sec;
  return (((unsigned long long)t.tv_nsec)) + s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<current_time_ns>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long current_time_ns() {
  struct timespec t = {0, 0};
  clock_gettime(CLOCK_MONOTONIC, &t);
  unsigned long long s = 1000000000ULL * (unsigned long long)t.tv_sec;
  return (((unsigned long long)t.tv_nsec)) + s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<current_time_ns>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3b9aca00,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long current_time_ns() {
  struct timespec t = {0, 0};
  clock_gettime(CLOCK_MONOTONIC, &t);
  unsigned long long s = 1000000000ULL * (unsigned long long)t.tv_sec;
  return (((unsigned long long)t.tv_nsec)) + s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<i_uid_conv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,-0x1c(%rbp)
  jmp    L56
L6:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <jelio_buffer_getc@plt>
  addl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,-0x1c(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <char_isspace@plt>
  test   %rax,%rax
  jne    L6
L41:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x2f,-0x1c(%rbp)
  jle    L8
  cmpl   $0x39,-0x1c(%rbp)
  jg     L8
  addl   $0x1,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <jelio_buffer_getc@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  sub    $0x30,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L41
L8:
  cmpl   $0x0,-0x18(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L38
L13:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
L38:
  leave
  ret
```

assistant: ```c
int i_uid_conv(void *value, int n, void *inbuf) {
  struct jelio_buf *jb = inbuf;
  uid_t *ival = value;
  int c, count = 0, wcount = 0;
  *ival = 0;
  for (c = jelio_buffer_peekc(jb); char_isspace(c); c = jelio_buffer_peekc(jb)) {
    jelio_buffer_getc(jb);
    wcount++;
  }
  while (1) {
    c = jelio_buffer_peekc(jb);
    if (c < '0' || c > '9')
      break;
    count++;
    jelio_buffer_getc(jb);
    *ival *= 10;
    *ival += c - '0';
  }
  if (!count)
    return 0;
  return count + wcount;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<i_uid_conv>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%rbp
  movl   $0x0,(%rdi)
  mov    %rdx,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
  mov    $0x0,%r13d
  jmp    L0
L38:
  mov    %rbp,%rdi
  call   <jelio_buffer_getc@plt>
  add    $0x1,%r13d
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
L0:
  call   <char_isspace@plt>
  test   %rax,%rax
  jne    L38
  mov    $0x0,%r14d
  jmp    L30
L27:
  add    $0x1,%r14d
  mov    %rbp,%rdi
  call   <jelio_buffer_getc@plt>
  mov    (%r12),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rbx,%rax,2),%eax
  mov    %eax,(%r12)
L30:
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%ebx
  lea    -0x30(%rax),%eax
  cmp    $0x9,%eax
  jbe    L27
  add    %r14d,%r13d
  test   %r14d,%r14d
  cmovne %r13d,%r14d
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int i_uid_conv(void *value, int n, void *inbuf) {
  struct jelio_buf *jb = inbuf;
  uid_t *ival = value;
  int c, count = 0, wcount = 0;
  *ival = 0;
  for (c = jelio_buffer_peekc(jb); char_isspace(c); c = jelio_buffer_peekc(jb)) {
    jelio_buffer_getc(jb);
    wcount++;
  }
  while (1) {
    c = jelio_buffer_peekc(jb);
    if (c < '0' || c > '9')
      break;
    count++;
    jelio_buffer_getc(jb);
    *ival *= 10;
    *ival += c - '0';
  }
  if (!count)
    return 0;
  return count + wcount;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<i_uid_conv>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  movl   $0x0,(%rdi)
  mov    %rdx,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <jelio_buffer_getc@plt>
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
L3:
  call   <char_isspace@plt>
  test   %rax,%rax
  jne    L27
  xor    %r14d,%r14d
  jmp    L23
  nopl   (%rax)
L17:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <jelio_buffer_getc@plt>
  mov    0x0(%r13),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rbx,%rax,2),%eax
  mov    %eax,0x0(%r13)
L23:
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  lea    -0x30(%rax),%ebx
  cmp    $0x9,%ebx
  jbe    L17
  add    %r14d,%r12d
  test   %r14d,%r14d
  pop    %rbx
  pop    %rbp
  cmovne %r12d,%r14d
  pop    %r12
  pop    %r13
  mov    %r14d,%eax
  pop    %r14
  ret
```

assistant: ```c
int i_uid_conv(void *value, int n, void *inbuf) {
  struct jelio_buf *jb = inbuf;
  uid_t *ival = value;
  int c, count = 0, wcount = 0;
  *ival = 0;
  for (c = jelio_buffer_peekc(jb); char_isspace(c); c = jelio_buffer_peekc(jb)) {
    jelio_buffer_getc(jb);
    wcount++;
  }
  while (1) {
    c = jelio_buffer_peekc(jb);
    if (c < '0' || c > '9')
      break;
    count++;
    jelio_buffer_getc(jb);
    *ival *= 10;
    *ival += c - '0';
  }
  if (!count)
    return 0;
  return count + wcount;
}
```