ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  lea    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x80(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x7c(%rbp)
  jmp    L64
L88:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x82(%rbp)
  mov    -0x7c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x78(%rbp)
  jmp    L71
L68:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,-0x82(%rbp)
  jge    L67
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x81(%rbp)
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x81(%rbp),%edx
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x74(%rbp)
  jmp    L27
L67:
  subl   $0x1,-0x78(%rbp)
L71:
  cmpl   $0x0,-0x78(%rbp)
  jns    L68
L27:
  cmpl   $0x0,-0x74(%rbp)
  jne    L85
  subl   $0x1,-0x7c(%rbp)
L64:
  cmpl   $0x0,-0x7c(%rbp)
  jg     L88
  jmp    L3
L85:
  nop
L3:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
data_type: string
name: extract_symbolic_data
arguments: label: D14
data_type: string

tool: D7: %d


tool: D14: %s

assistant: ```c
int main() {
  int i, n, j, count = 0;
  char str[100], ch, ch1;
  scanf("%d\n", &n);
  scanf("%s", str);
  for (i = n - 1; i > 0; i--) {
    ch = str[i];
    for (j = i - 1; j >= 0; j--) {
      if (str[j] > ch) {
        ch1 = str[j];
        str[j] = str[i];
        str[i] = ch1;
        count++;
        break;
      }
    }
    if (count != 0)
      break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%esi
  movslq %esi,%rsi
L0:
  test   %esi,%esi
  jle    L23
  movzbl 0x10(%rsp,%rsi,1),%ecx
  lea    -0x1(%rsi),%rax
  lea    0x10(%rsp),%rdx
L43:
  cmp    %cl,(%rax,%rdx,1)
  jg     L23
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L43
  sub    $0x1,%rsi
  jmp    L0
L23:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x88,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D3: %d


tool: D7: %s

assistant: ```c
int main() {
  int i, n, j, count = 0;
  char str[100], ch, ch1;
  scanf("%d\n", &n);
  scanf("%s", str);
  for (i = n - 1; i > 0; i--) {
    ch = str[i];
    for (j = i - 1; j >= 0; j--) {
      if (str[j] > ch) {
        ch1 = str[j];
        str[j] = str[i];
        str[i] = ch1;
        count++;
        break;
      }
    }
    if (count != 0)
      break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x88,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D8: %d


tool: D5: %s

assistant: ```c
int main() {
  int i, n, j, count = 0;
  char str[100], ch, ch1;
  scanf("%d\n", &n);
  scanf("%s", str);
  for (i = n - 1; i > 0; i--) {
    ch = str[i];
    for (j = i - 1; j >= 0; j--) {
      if (str[j] > ch) {
        ch1 = str[j];
        str[j] = str[i];
        str[i] = ch1;
        count++;
        break;
      }
    }
    if (count != 0)
      break;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x88,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x88,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D7
data_type: string

tool: D11: %d


tool: D7: %s

assistant: ```c
int main() {
  int i, n, j, count = 0;
  char str[100], ch, ch1;
  scanf("%d\n", &n);
  scanf("%s", str);
  for (i = n - 1; i > 0; i--) {
    ch = str[i];
    for (j = i - 1; j >= 0; j--) {
      if (str[j] > ch) {
        ch1 = str[j];
        str[j] = str[i];
        str[i] = ch1;
        count++;
        break;
      }
    }
    if (count != 0)
      break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ehrpwm_2_pinmux_setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%esi
  mov    $0x820,%edi
  call   <GpioPinMuxSetup@plt>
  mov    $0x4,%esi
  mov    $0x824,%edi
  call   <GpioPinMuxSetup@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ehrpwm_2_pinmux_setup(void) {
  GpioPinMuxSetup((0x0820), (4));
  GpioPinMuxSetup((0x0824), (4));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ehrpwm_2_pinmux_setup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x820,%edi
  call   <GpioPinMuxSetup@plt>
  mov    $0x4,%esi
  mov    $0x824,%edi
  call   <GpioPinMuxSetup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ehrpwm_2_pinmux_setup(void) {
  GpioPinMuxSetup((0x0820), (4));
  GpioPinMuxSetup((0x0824), (4));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ehrpwm_2_pinmux_setup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x820,%edi
  call   <GpioPinMuxSetup@plt>
  mov    $0x4,%esi
  mov    $0x824,%edi
  add    $0x8,%rsp
  jmp    1050 <GpioPinMuxSetup@plt>
```

assistant: ```c
void ehrpwm_2_pinmux_setup(void) {
  GpioPinMuxSetup((0x0820), (4));
  GpioPinMuxSetup((0x0824), (4));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ehrpwm_2_pinmux_setup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x820,%edi
  call   <GpioPinMuxSetup@plt>
  mov    $0x4,%esi
  mov    $0x824,%edi
  add    $0x8,%rsp
  jmp    1050 <GpioPinMuxSetup@plt>
```

assistant: ```c
void ehrpwm_2_pinmux_setup(void) {
  GpioPinMuxSetup((0x0820), (4));
  GpioPinMuxSetup((0x0824), (4));
}
```
user: What is the c source code of the assembly code below?

```asm
<KtoR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D20(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D32(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D23(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D16(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D20
type: f64
name: parse_data
arguments: data_label: D32
type: f64
name: parse_data
arguments: data_label: D23
type: f64
name: parse_data
arguments: data_label: D16
type: f64

tool: D20: 273.15

tool: D32: 1.8

tool: D23: 32

tool: D16: 459.69

assistant: ```c
double KtoR(double K) {
  double r = (1.8 * (K - 273.15) + 32) + 459.69;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<KtoR>:
  endbr64
  subsd  D6(%rip),%xmm0
  mulsd  D29(%rip),%xmm0
  addsd  D25(%rip),%xmm0
  addsd  D33(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: f64
name: parse_data
arguments: data_label: D29
type_guessed: f64
name: parse_data
arguments: data_label: D25
type_guessed: f64
name: parse_data
arguments: data_label: D33
type_guessed: f64

tool: D6: 273.15

tool: D29: 1.8

tool: D25: 32

tool: D33: 459.69

assistant: ```c
double KtoR(double K) {
  double r = (1.8 * (K - 273.15) + 32) + 459.69;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<KtoR>:
  endbr64
  subsd  D36(%rip),%xmm0
  mulsd  D23(%rip),%xmm0
  addsd  D30(%rip),%xmm0
  addsd  D24(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D36
type_guessed: f64
name: retrieve_data
arguments: data_tag: D23
type_guessed: f64
name: retrieve_data
arguments: data_tag: D30
type_guessed: f64
name: retrieve_data
arguments: data_tag: D24
type_guessed: f64

tool: D36: 273.15

tool: D23: 1.8

tool: D30: 32

tool: D24: 459.69

assistant: ```c
double KtoR(double K) {
  double r = (1.8 * (K - 273.15) + 32) + 459.69;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<KtoR>:
  endbr64
  subsd  D39(%rip),%xmm0
  mulsd  D7(%rip),%xmm0
  addsd  D14(%rip),%xmm0
  addsd  D28(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D39
data_type: f64
name: extract_symbolic_data
arguments: tag: D7
data_type: f64
name: extract_symbolic_data
arguments: tag: D14
data_type: f64
name: extract_symbolic_data
arguments: tag: D28
data_type: f64

tool: D39: 273.15

tool: D7: 1.8

tool: D14: 32

tool: D28: 459.69

assistant: ```c
double KtoR(double K) {
  double r = (1.8 * (K - 273.15) + 32) + 459.69;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ifft>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %edi,%ebp
  shr    $0x1f,%ebp
  add    %edi,%ebp
  sar    %ebp
  mov    %rbx,%rdx
  call   <fft@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  movsd  (%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbx)
  movslq %ebp,%rax
  shl    $0x4,%rax
  add    %rbx,%rax
  movsd  (%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax)
  movsd  0x8(%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rax)
  cmp    $0x3,%r12d
  jle    L4
  lea    0x10(%rbx),%rdx
  movslq %r12d,%r12
  shl    $0x4,%r12
  lea    (%rbx,%r12,1),%rax
  mov    $0x1,%ecx
L14:
  movsd  (%rdx),%xmm1
  movapd %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  movsd  0x8(%rdx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x10(%rax),%xmm3
  divsd  %xmm0,%xmm3
  movsd  %xmm3,(%rdx)
  movsd  -0x8(%rax),%xmm3
  divsd  %xmm0,%xmm3
  movsd  %xmm3,0x8(%rdx)
  movsd  %xmm2,-0x10(%rax)
  movsd  %xmm1,-0x8(%rax)
  add    $0x1,%ecx
  add    $0x10,%rdx
  sub    $0x10,%rax
  cmp    %ecx,%ebp
  jg     L14
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ifft(int N, double (*x)[2], double (*X)[2]) {
  int N2 = N / 2;
  int i;
  double tmp0, tmp1;
  fft(N, X, x);
  x[0][0] = x[0][0] / N;
  x[0][1] = x[0][1] / N;
  x[N2][0] = x[N2][0] / N;
  x[N2][1] = x[N2][1] / N;
  for (i = 1; i < N2; i++) {
    tmp0 = x[i][0] / N;
    tmp1 = x[i][1] / N;
    x[i][0] = x[N - i][0] / N;
    x[i][1] = x[N - i][1] / N;
    x[N - i][0] = tmp0;
    x[N - i][1] = tmp1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ifft>:
  endbr64
  push   %r12
  movslq %edi,%r12
  push   %rbp
  mov    %r12d,%edi
  mov    %r12d,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  shr    $0x1f,%ebp
  mov    %rbx,%rdx
  add    %r12d,%ebp
  sar    %ebp
  call   <fft@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rbx),%xmm1
  movslq %ebp,%rax
  cvtsi2sd %r12d,%xmm0
  shl    $0x4,%rax
  add    %rbx,%rax
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbx)
  movsd  (%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax)
  movsd  0x8(%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rax)
  cmp    $0x3,%r12d
  jle    L17
  shl    $0x4,%r12
  lea    0x10(%rbx),%rdx
  mov    $0x1,%ecx
  lea    (%rbx,%r12,1),%rax
  nopl   (%rax)
L16:
  movsd  -0x10(%rax),%xmm3
  movsd  (%rdx),%xmm1
  add    $0x1,%ecx
  add    $0x10,%rdx
  sub    $0x10,%rax
  divsd  %xmm0,%xmm3
  movapd %xmm1,%xmm2
  movsd  -0x8(%rdx),%xmm1
  divsd  %xmm0,%xmm2
  movsd  %xmm3,-0x10(%rdx)
  movsd  0x8(%rax),%xmm3
  divsd  %xmm0,%xmm1
  divsd  %xmm0,%xmm3
  movsd  %xmm3,-0x8(%rdx)
  movsd  %xmm2,(%rax)
  movsd  %xmm1,0x8(%rax)
  cmp    %ecx,%ebp
  jg     L16
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ifft(int N, double (*x)[2], double (*X)[2]) {
  int N2 = N / 2;
  int i;
  double tmp0, tmp1;
  fft(N, X, x);
  x[0][0] = x[0][0] / N;
  x[0][1] = x[0][1] / N;
  x[N2][0] = x[N2][0] / N;
  x[N2][1] = x[N2][1] / N;
  for (i = 1; i < N2; i++) {
    tmp0 = x[i][0] / N;
    tmp1 = x[i][1] / N;
    x[i][0] = x[N - i][0] / N;
    x[i][1] = x[N - i][1] / N;
    x[N - i][0] = tmp0;
    x[N - i][1] = tmp1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ifft>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  shr    $0x1f,%r12d
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  add    %edi,%r12d
  mov    %rbx,%rdx
  sar    %r12d
  call   <fft@plt>
  pxor   %xmm3,%xmm3
  movupd (%rbx),%xmm0
  movslq %r12d,%rax
  cvtsi2sd %ebp,%xmm3
  shl    $0x4,%rax
  add    %rbx,%rax
  movapd %xmm3,%xmm2
  unpcklpd %xmm2,%xmm2
  divpd  %xmm2,%xmm0
  movups %xmm0,(%rbx)
  movupd (%rax),%xmm0
  divpd  %xmm2,%xmm0
  movups %xmm0,(%rax)
  cmp    $0x3,%ebp
  jle    L41
  lea    -0x1(%r12),%edi
  movslq %ebp,%rsi
  lea    0x10(%rbx),%rax
  shl    $0x4,%rsi
  lea    0x1(%rdi),%r9
  mov    %rdi,%r8
  shl    $0x4,%rdi
  lea    (%rbx,%rsi,1),%rcx
  lea    -0x10(%rsi),%rdx
  shl    $0x4,%r9
  sub    %rdi,%rsi
  cmp    %rsi,%r9
  jle    L18
  cmp    %rcx,%rax
  jb     L19
L18:
  mov    $0x1,%ecx
  add    %rbx,%rdx
  cmp    $0x3,%ebp
  cmovle %ecx,%r8d
  lea    -0x1(%r8),%ecx
  shl    $0x4,%rcx
  lea    0x20(%rbx,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L9:
  movupd (%rdx),%xmm1
  movupd (%rax),%xmm0
  add    $0x10,%rax
  sub    $0x10,%rdx
  divpd  %xmm2,%xmm1
  divpd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  movups %xmm0,0x10(%rdx)
  cmp    %rcx,%rax
  jne    L9
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rcx,%rdx
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L32:
  movsd  -0x10(%rdx),%xmm1
  movupd (%rax),%xmm0
  add    $0x1,%ecx
  add    $0x10,%rax
  sub    $0x10,%rdx
  divsd  %xmm3,%xmm1
  divpd  %xmm2,%xmm0
  movsd  %xmm1,-0x10(%rax)
  movsd  0x8(%rdx),%xmm1
  divsd  %xmm3,%xmm1
  movsd  %xmm1,-0x8(%rax)
  movups %xmm0,(%rdx)
  cmp    %ecx,%r12d
  jg     L32
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ifft(int N, double (*x)[2], double (*X)[2]) {
  int N2 = N / 2;
  int i;
  double tmp0, tmp1;
  fft(N, X, x);
  x[0][0] = x[0][0] / N;
  x[0][1] = x[0][1] / N;
  x[N2][0] = x[N2][0] / N;
  x[N2][1] = x[N2][1] / N;
  for (i = 1; i < N2; i++) {
    tmp0 = x[i][0] / N;
    tmp1 = x[i][1] / N;
    x[i][0] = x[N - i][0] / N;
    x[i][1] = x[N - i][1] / N;
    x[N - i][0] = tmp0;
    x[N - i][1] = tmp1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<para_cronometro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movabs $0x8888888888888889,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x5,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rcx
  movabs $0x8888888888888889,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movabs $0x8888888888888889,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x5,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x8888888888888889,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x4,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string

tool: D8: 
time elapsed: %lu days, %lu hours, %lu minutes, %lu seconds

assistant: ```c
void para_cronometro(time_t *medidor) {
  time_t tms;
  unsigned long int horas, minutos, segundos, dias;
  tms = time(NULL);
  segundos = (unsigned long int)difftime(tms, *medidor);
  minutos = (segundos / 60);
  segundos = (unsigned long int)(segundos % 60);
  horas = minutos / 60;
  minutos = (unsigned long int)(minutos % 60);
  dias = horas / 24;
  horas = (unsigned long int)(horas % 24);
  printf("\ntime elapsed: %lu days, %lu hours, %lu minutes, %lu seconds", dias, horas, minutos, segundos);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<para_cronometro>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  mov    (%rbx),%esi
  call   <difftime@plt>
  mov    %rax,%r8
  movabs $0x8888888888888889,%rdi
  mul    %rdi
  mov    %rdx,%rcx
  shr    $0x5,%rcx
  mov    %rcx,%rax
  mul    %rdi
  mov    %rdx,%rdi
  shr    $0x5,%rdi
  mov    %rcx,%r9
  shl    $0x4,%r9
  sub    %rcx,%r9
  shl    $0x2,%r9
  mov    %rdi,%rdx
  shl    $0x4,%rdx
  sub    %rdi,%rdx
  shl    $0x2,%rdx
  sub    %rdx,%rcx
  movabs $0xaaaaaaaaaaaaaaab,%rsi
  mov    %rdi,%rax
  mul    %rsi
  mov    %rdx,%rsi
  shr    $0x4,%rsi
  lea    (%rsi,%rsi,2),%rax
  shl    $0x3,%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  sub    %r9,%r8
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: 
time elapsed: %lu days, %lu hours, %lu minutes, %lu seconds

assistant: ```c
void para_cronometro(time_t *medidor) {
  time_t tms;
  unsigned long int horas, minutos, segundos, dias;
  tms = time(NULL);
  segundos = (unsigned long int)difftime(tms, *medidor);
  minutos = (segundos / 60);
  segundos = (unsigned long int)(segundos % 60);
  horas = minutos / 60;
  minutos = (unsigned long int)(minutos % 60);
  dias = horas / 24;
  horas = (unsigned long int)(horas % 24);
  printf("\ntime elapsed: %lu days, %lu hours, %lu minutes, %lu seconds", dias, horas, minutos, segundos);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<para_cronometro>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  call   <time@plt>
  mov    (%rbx),%esi
  mov    %eax,%edi
  call   <difftime@plt>
  pop    %rbx
  movabs $0x8888888888888889,%rdi
  movabs $0xaaaaaaaaaaaaaaab,%rsi
  mov    %rax,%r8
  mul    %rdi
  mov    %rdx,%rcx
  shr    $0x5,%rcx
  mov    %rcx,%rax
  mov    %rcx,%r9
  mul    %rdi
  shl    $0x4,%r9
  sub    %rcx,%r9
  shl    $0x2,%r9
  mov    %rdx,%rdi
  sub    %r9,%r8
  shr    $0x5,%rdi
  mov    %rdi,%rdx
  mov    %rdi,%rax
  shl    $0x4,%rdx
  sub    %rdi,%rdx
  shl    $0x2,%rdx
  sub    %rdx,%rcx
  mul    %rsi
  mov    %rdx,%rsi
  mov    %rdi,%rdx
  lea    D8(%rip),%rdi
  shr    $0x4,%rsi
  lea    (%rsi,%rsi,2),%rax
  shl    $0x3,%rax
  sub    %rax,%rdx
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D8: 
time elapsed: %lu days, %lu hours, %lu minutes, %lu seconds

assistant: ```c
void para_cronometro(time_t *medidor) {
  time_t tms;
  unsigned long int horas, minutos, segundos, dias;
  tms = time(NULL);
  segundos = (unsigned long int)difftime(tms, *medidor);
  minutos = (segundos / 60);
  segundos = (unsigned long int)(segundos % 60);
  horas = minutos / 60;
  minutos = (unsigned long int)(minutos % 60);
  dias = horas / 24;
  horas = (unsigned long int)(horas % 24);
  printf("\ntime elapsed: %lu days, %lu hours, %lu minutes, %lu seconds", dias, horas, minutos, segundos);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<para_cronometro>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  call   <time@plt>
  mov    (%rbx),%esi
  mov    %eax,%edi
  call   <difftime@plt>
  pop    %rbx
  movabs $0x8888888888888889,%rdi
  movabs $0xaaaaaaaaaaaaaaab,%rsi
  mov    %rax,%r8
  mul    %rdi
  mov    %rdx,%rcx
  shr    $0x5,%rcx
  mov    %rcx,%rax
  mov    %rcx,%r9
  mul    %rdi
  shl    $0x4,%r9
  sub    %rcx,%r9
  shl    $0x2,%r9
  mov    %rdx,%rdi
  sub    %r9,%r8
  shr    $0x5,%rdi
  mov    %rdi,%rdx
  mov    %rdi,%rax
  shl    $0x4,%rdx
  sub    %rdi,%rdx
  shl    $0x2,%rdx
  sub    %rdx,%rcx
  mul    %rsi
  mov    %rdx,%rsi
  mov    %rdi,%rdx
  lea    D2(%rip),%rdi
  shr    $0x4,%rsi
  lea    (%rsi,%rsi,2),%rax
  shl    $0x3,%rax
  sub    %rax,%rdx
  jmp    1070 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: 
time elapsed: %lu days, %lu hours, %lu minutes, %lu seconds

assistant: ```c
void para_cronometro(time_t *medidor) {
  time_t tms;
  unsigned long int horas, minutos, segundos, dias;
  tms = time(NULL);
  segundos = (unsigned long int)difftime(tms, *medidor);
  minutos = (segundos / 60);
  segundos = (unsigned long int)(segundos % 60);
  horas = minutos / 60;
  minutos = (unsigned long int)(minutos % 60);
  dias = horas / 24;
  horas = (unsigned long int)(horas % 24);
  printf("\ntime elapsed: %lu days, %lu hours, %lu minutes, %lu seconds", dias, horas, minutos, segundos);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<us_bits_set_doublet_bitfield>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <us_bits_get_doublet@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0xf,%eax
  sub    -0x24(%rbp),%eax
  mov    -0x28(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    $0xf,%eax
  sub    %edx,%eax
  mov    $0xffff,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    $0xf,%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  movzwl %ax,%eax
  and    -0x4(%rbp),%eax
  or     %esi,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <us_bits_set_doublet@plt>
  nop
  leave
  ret
```

assistant: ```c
void us_bits_set_doublet_bitfield(void *base, uint16_t offset, uint16_t msb, uint16_t lsb, uint32_t newbits) {
  uint16_t v = us_bits_get_doublet(base, offset);
  v = (((newbits) << (15 - ((lsb)))) | (((v)) & ((~(((0xffff) >> (16 - ((((lsb) - (msb) + 1))))) << (15 - ((((lsb))))))) & 0xffff)));
  us_bits_set_doublet(base, offset, v);
}
```