ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<createServerSocket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    (%rax),%ecx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L43
  mov    -0x1c(%rbp),%eax
  jmp    L9
L43:
  lea    -0x14(%rbp),%rax
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L11
  mov    -0x18(%rbp),%eax
  jmp    L9
L11:
  mov    -0x1c(%rbp),%eax
  mov    $0xf,%esi
  mov    %eax,%edi
  call   <listen@plt>
  mov    -0x1c(%rbp),%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int createServerSocket(int port) {
  struct sockaddr_in serv_addr;
  int sockfd = socket(AF_INET, SOCK_STREAM, 0);
  if (sockfd < 0)
    return sockfd;
  bzero((char *)&serv_addr, sizeof(serv_addr));
  serv_addr.sin_family = AF_INET;
  serv_addr.sin_addr.s_addr = INADDR_ANY;
  serv_addr.sin_port = htons(port);
  int res = bind(sockfd, (struct sockaddr *)&serv_addr, sizeof(serv_addr));
  if (res < 0)
    return res;
  listen(sockfd, 15);
  return sockfd;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<createServerSocket>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L13
  lea    0xc(%rsp),%r12
  mov    $0xc,%esi
  mov    %r12,%rdi
  call   <bzero@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  mov    %ebp,%edi
  call   <htons@plt>
  mov    %eax,0xc(%rsp)
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  test   %eax,%eax
  js     L10
  mov    $0xf,%esi
  mov    %ebx,%edi
  call   <listen@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %eax,%ebx
  jmp    L13
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int createServerSocket(int port) {
  struct sockaddr_in serv_addr;
  int sockfd = socket(AF_INET, SOCK_STREAM, 0);
  if (sockfd < 0)
    return sockfd;
  bzero((char *)&serv_addr, sizeof(serv_addr));
  serv_addr.sin_family = AF_INET;
  serv_addr.sin_addr.s_addr = INADDR_ANY;
  serv_addr.sin_port = htons(port);
  int res = bind(sockfd, (struct sockaddr *)&serv_addr, sizeof(serv_addr));
  if (res < 0)
    return res;
  listen(sockfd, 15);
  return sockfd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<createServerSocket>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    D16(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D27(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L2
  lea    0xc(%rsp),%r13
  mov    $0xc,%esi
  mov    %r13,%rdi
  call   <bzero@plt>
  mov    (%rbx),%eax
  mov    %ebp,%edi
  mov    %eax,0x14(%rsp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  test   %eax,%eax
  js     L39
  mov    $0xf,%esi
  mov    %r12d,%edi
  call   <listen@plt>
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L39:
  mov    %eax,%r12d
  jmp    L2
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int createServerSocket(int port) {
  struct sockaddr_in serv_addr;
  int sockfd = socket(AF_INET, SOCK_STREAM, 0);
  if (sockfd < 0)
    return sockfd;
  bzero((char *)&serv_addr, sizeof(serv_addr));
  serv_addr.sin_family = AF_INET;
  serv_addr.sin_addr.s_addr = INADDR_ANY;
  serv_addr.sin_port = htons(port);
  int res = bind(sockfd, (struct sockaddr *)&serv_addr, sizeof(serv_addr));
  if (res < 0)
    return res;
  listen(sockfd, 15);
  return sockfd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<createServerSocket>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    D4(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L26
  lea    0x8(%rsp),%r13
  mov    $0xc,%esi
  mov    %r13,%rdi
  call   <bzero@plt>
  mov    D11(%rip),%rdx
  mov    (%rbx),%eax
  mov    %ebp,%edi
  movd   (%rdx),%xmm0
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0xc(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  mov    %eax,0x8(%rsp)
  call   <bind@plt>
  test   %eax,%eax
  js     L27
  mov    $0xf,%esi
  mov    %r12d,%edi
  call   <listen@plt>
L26:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %eax,%r12d
  jmp    L26
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int createServerSocket(int port) {
  struct sockaddr_in serv_addr;
  int sockfd = socket(AF_INET, SOCK_STREAM, 0);
  if (sockfd < 0)
    return sockfd;
  bzero((char *)&serv_addr, sizeof(serv_addr));
  serv_addr.sin_family = AF_INET;
  serv_addr.sin_addr.s_addr = INADDR_ANY;
  serv_addr.sin_port = htons(port);
  int res = bind(sockfd, (struct sockaddr *)&serv_addr, sizeof(serv_addr));
  if (res < 0)
    return res;
  listen(sockfd, 15);
  return sockfd;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L32
L26:
  cmpq   $0x1,-0x18(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L32
L13:
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <fibonacci>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  sub    $0x2,%rax
  mov    %rax,%rdi
  call   <fibonacci>
  add    %rbx,%rax
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long int fibonacci(long int n) {
  if (n == 0)
    return 0;
  else if (n == 1)
    return 1;
  else
    return fibonacci(n - 1) + fibonacci(n - 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fibonacci>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L7
  cmp    $0x1,%rdi
  jne    L12
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    -0x1(%rdi),%rdi
  call   <fibonacci>
  mov    %rax,%rbp
  lea    -0x2(%rbx),%rdi
  call   <fibonacci>
  lea    0x0(%rbp,%rax,1),%rbx
  jmp    L7
```

assistant: ```c
long int fibonacci(long int n) {
  if (n == 0)
    return 0;
  else if (n == 1)
    return 1;
  else
    return fibonacci(n - 1) + fibonacci(n - 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   $0x2
  push   $0x9
  mov    $0xffffffff,%r9d
  mov    $0x0,%r8d
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x0,%esi
  mov    $0xfffffffd,%edi
  call   <computeArea@plt>
  add    $0x10,%rsp
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  push   $0x1
  push   $0x59682f01
  mov    $0x0,%r9d
  mov    $0x59682f00,%r8d
  mov    $0x1,%ecx
  mov    $0xa697d100,%edx
  mov    $0x0,%esi
  mov    $0xa697d0ff,%edi
  call   <computeArea@plt>
  add    $0x10,%rsp
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: %d


assistant: ```c
int main(void) {
  printf("%d\n", computeArea(-3, 0, 3, 4, 0, -1, 9, 2));
  printf("%d\n", computeArea(-1500000001, 0, -1500000000, 1, 1500000000, 0, 1500000001, 1));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  push   $0x2
  push   $0x9
  mov    $0xffffffff,%r9d
  mov    $0x0,%r8d
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x0,%esi
  mov    $0xfffffffd,%edi
  call   <computeArea@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  push   $0x1
  push   $0x59682f01
  mov    $0x0,%r9d
  mov    $0x59682f00,%r8d
  mov    $0x1,%ecx
  mov    $0xa697d100,%edx
  mov    $0x0,%esi
  mov    $0xa697d0ff,%edi
  call   <computeArea@plt>
  mov    %eax,%esi
  add    $0x20,%rsp
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main(void) {
  printf("%d\n", computeArea(-3, 0, 3, 4, 0, -1, 9, 2));
  printf("%d\n", computeArea(-1500000001, 0, -1500000000, 1, 1500000000, 0, 1500000001, 1));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xffffffff,%r9d
  xor    %r8d,%r8d
  mov    $0x4,%ecx
  push   $0x2
  mov    $0x3,%edx
  xor    %esi,%esi
  mov    $0xfffffffd,%edi
  push   $0x9
  lea    D5(%rip),%rbp
  call   <computeArea@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  push   $0x1
  xor    %r9d,%r9d
  mov    $0x59682f00,%r8d
  push   $0x59682f01
  mov    $0x1,%ecx
  mov    $0xa697d100,%edx
  xor    %esi,%esi
  mov    $0xa697d0ff,%edi
  call   <computeArea@plt>
  add    $0x20,%rsp
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main(void) {
  printf("%d\n", computeArea(-3, 0, 3, 4, 0, -1, 9, 2));
  printf("%d\n", computeArea(-1500000001, 0, -1500000000, 1, 1500000000, 0, 1500000001, 1));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xffffffff,%r9d
  xor    %r8d,%r8d
  mov    $0x4,%ecx
  push   $0x2
  mov    $0x3,%edx
  xor    %esi,%esi
  mov    $0xfffffffd,%edi
  push   $0x9
  lea    D5(%rip),%rbp
  call   <computeArea@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  push   $0x1
  xor    %r9d,%r9d
  mov    $0x59682f00,%r8d
  push   $0x59682f01
  mov    $0x1,%ecx
  mov    $0xa697d100,%edx
  xor    %esi,%esi
  mov    $0xa697d0ff,%edi
  call   <computeArea@plt>
  add    $0x20,%rsp
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main(void) {
  printf("%d\n", computeArea(-3, 0, 3, 4, 0, -1, 9, 2));
  printf("%d\n", computeArea(-1500000001, 0, -1500000000, 1, 1500000000, 0, 1500000001, 1));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<contains_tok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x8000(%rsp),%r11
L17:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L17
  sub    $0x40,%rsp
  mov    %rdi,-0x8028(%rbp)
  mov    %rsi,-0x8030(%rbp)
  mov    %rdx,-0x8038(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x8028(%rbp),%rdx
  lea    -0x8010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8038(%rbp),%rdx
  lea    -0x8010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8018(%rbp)
  movl   $0x0,-0x801c(%rbp)
  jmp    L14
L54:
  mov    -0x8030(%rbp),%rdx
  mov    -0x8018(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L44
  mov    -0x801c(%rbp),%eax
  jmp    L1
L44:
  addl   $0x1,-0x801c(%rbp)
  mov    -0x8038(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8018(%rbp)
L14:
  cmpq   $0x0,-0x8018(%rbp)
  jne    L54
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int contains_tok(char *s1, char *s2, char *delims) {
  char *p;
  char tempstr[(4 * 8192)];
  int i;
  strcpy(tempstr, s1);
  p = strtok(tempstr, delims);
  i = 0;
  while (p != NULL) {
    if (!strcmp(p, s2)) {
      return (i);
    }
    i++;
    p = strtok(NULL, delims);
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<contains_tok>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x8000(%rsp),%r11
L22:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L22
  sub    $0x10,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  mov    $0x0,%ebx
L39:
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L20
  add    $0x1,%ebx
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L39
  mov    $0x0,%ebx
L20:
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    %ebx,%eax
  add    $0x8010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0x0,%ebx
  jmp    L20
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int contains_tok(char *s1, char *s2, char *delims) {
  char *p;
  char tempstr[(4 * 8192)];
  int i;
  strcpy(tempstr, s1);
  p = strtok(tempstr, delims);
  i = 0;
  while (p != NULL) {
    if (!strcmp(p, s2)) {
      return (i);
    }
    i++;
    p = strtok(NULL, delims);
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<contains_tok>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x8000(%rsp),%r11
L48:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L48
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdx,%rbx
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L21
  mov    %rax,%rdi
  xor    %r12d,%r12d
  jmp    L9
  nopl   0x0(%rax)
L16:
  xor    %edi,%edi
  mov    %rbx,%rsi
  add    $0x1,%r12d
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L21
L9:
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L16
L58:
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x8010,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  xor    %r12d,%r12d
  jmp    L58
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int contains_tok(char *s1, char *s2, char *delims) {
  char *p;
  char tempstr[(4 * 8192)];
  int i;
  strcpy(tempstr, s1);
  p = strtok(tempstr, delims);
  i = 0;
  while (p != NULL) {
    if (!strcmp(p, s2)) {
      return (i);
    }
    i++;
    p = strtok(NULL, delims);
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<contains_tok>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x8000(%rsp),%r11
L28:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L28
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdx,%rbx
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L46
  mov    %rax,%rdi
  xor    %r12d,%r12d
  jmp    L9
  nopl   0x0(%rax)
L35:
  xor    %edi,%edi
  mov    %rbx,%rsi
  add    $0x1,%r12d
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L46
L9:
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L35
L66:
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x8010,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L46:
  xor    %r12d,%r12d
  jmp    L66
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int contains_tok(char *s1, char *s2, char *delims) {
  char *p;
  char tempstr[(4 * 8192)];
  int i;
  strcpy(tempstr, s1);
  p = strtok(tempstr, delims);
  i = 0;
  while (p != NULL) {
    if (!strcmp(p, s2)) {
      return (i);
    }
    i++;
    p = strtok(NULL, delims);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stralloccopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *stralloccopy(char const *const str) {
  char *s = malloc((strlen(str) + 1) * sizeof(*s));
  if (s != NULL)
    strcpy(s, str);
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stralloccopy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *stralloccopy(char const *const str) {
  char *s = malloc((strlen(str) + 1) * sizeof(*s));
  if (s != NULL)
    strcpy(s, str);
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stralloccopy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stralloccopy(char const *const str) {
  char *s = malloc((strlen(str) + 1) * sizeof(*s));
  if (s != NULL)
    strcpy(s, str);
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stralloccopy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stralloccopy(char const *const str) {
  char *s = malloc((strlen(str) + 1) * sizeof(*s));
  if (s != NULL)
    strcpy(s, str);
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<waitLiftReady>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  jmp    L1
L5:
  mov    $0x0,%eax
  call   <abortTimeslice@plt>
L1:
  mov    $0x0,%eax
  call   <isLiftReady@plt>
  test   %eax,%eax
  je     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void waitLiftReady() {
  while (!isLiftReady()) {
    abortTimeslice();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<waitLiftReady>:
  endbr64
  sub    $0x8,%rsp
  jmp    L7
L17:
  mov    $0x0,%eax
  call   <abortTimeslice@plt>
L7:
  mov    $0x0,%eax
  call   <isLiftReady@plt>
  test   %eax,%eax
  je     L17
  add    $0x8,%rsp
  ret
```

assistant: ```c
void waitLiftReady() {
  while (!isLiftReady()) {
    abortTimeslice();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<waitLiftReady>:
  endbr64
  sub    $0x8,%rsp
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <abortTimeslice@plt>
L15:
  xor    %eax,%eax
  call   <isLiftReady@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  ret
```

assistant: ```c
void waitLiftReady() {
  while (!isLiftReady()) {
    abortTimeslice();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<waitLiftReady>:
  endbr64
  sub    $0x8,%rsp
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  call   <abortTimeslice@plt>
L11:
  xor    %eax,%eax
  call   <isLiftReady@plt>
  test   %eax,%eax
  je     L14
  add    $0x8,%rsp
  ret
```

assistant: ```c
void waitLiftReady() {
  while (!isLiftReady()) {
    abortTimeslice();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D6(%rip),%rbx
  jmp    L125
L40:
  cmp    $0x60,%al
  jg     L128
  cmp    $0x20,%al
  je     L130
L18:
  cmp    $0xa,%al
  je     L100
L125:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x70,%al
  jle    L40
  lea    -0x71(%rax),%edx
  cmp    $0x9,%dl
  ja     L125
  lea    -0x71(%rax),%edx
  cmp    $0x9,%dl
  ja     L18
  movzbl %dl,%edx
  movslq (%rbx,%rdx,4),%rdx
  add    %rbx,%rdx
  notrack jmp *%rdx
L128:
  lea    -0x61(%rax),%ecx
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   $0x9249,%edx
  jne    L130
  test   $0x4924,%edx
  jne    L75
  test   $0x2492,%edx
  je     L125
  add    $0x2,%ebp
  jmp    L18
L130:
  add    $0x1,%ebp
  jmp    L18
L75:
  add    $0x3,%ebp
  jmp    L18
  add    $0x4,%ebp
  jmp    L125
L100:
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: %d

assistant: ```c
int main() {
  int i;
  char a;
  while (a != '\n') {
    a = getchar();
    switch (a) {
    case 'a':
    case 'd':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
    case ' ':
      i++;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      i += 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      i += 3;
      break;
    case 's':
    case 'z':
      i += 4;
      break;
    }
  }
  printf("%d", i);
  return 0;
}
```