user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D92(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D113(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    D60(%rip),%rdi
  call   <puts@plt>
  lea    D159(%rip),%rdi
  call   <puts@plt>
  lea    D71(%rip),%rdi
  call   <puts@plt>
  lea    D73(%rip),%rdi
  call   <puts@plt>
  lea    D32(%rip),%rdi
  call   <puts@plt>
  lea    D75(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x6,0x14(%rsp)
  je     L6
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x1,%eax
  je     L45
  cmp    $0x2,%eax
  je     L92
  cmp    $0x3,%eax
  je     L98
  cmp    $0x4,%eax
  je     L41
  cmp    $0x5,%eax
  je     L40
L6:
  lea    D154(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
L92:
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  sub    0x10(%rsp),%eax
  lea    D80(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L22:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L40:
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D63(%rip),%rdi
  cltd
  idivl  0x10(%rsp)
  mov    $0x1,%eax
  cvtsi2ss %edx,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L22
L45:
  mov    0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  add    0xc(%rsp),%eax
  lea    D169(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L22
L98:
  mov    0xc(%rsp),%eax
  imul   0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D74(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L22
L41:
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D29(%rip),%rdi
  cltd
  idivl  0x10(%rsp)
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L22
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D92
type_infered: string
name: disassemble_data
arguments: label: D113
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string
name: disassemble_data
arguments: label: D60
type_infered: string
name: disassemble_data
arguments: label: D159
type_infered: string
name: disassemble_data
arguments: label: D71
type_infered: string
name: disassemble_data
arguments: label: D73
type_infered: string
name: disassemble_data
arguments: label: D32
type_infered: string
name: disassemble_data
arguments: label: D75
type_infered: string
name: disassemble_data
arguments: label: D21
type_infered: string
name: disassemble_data
arguments: label: D24
type_infered: string
name: disassemble_data
arguments: label: D154
type_infered: string
name: disassemble_data
arguments: label: D80
type_infered: string
name: disassemble_data
arguments: label: D63
type_infered: string
name: disassemble_data
arguments: label: D169
type_infered: string
name: disassemble_data
arguments: label: D74
type_infered: string
name: disassemble_data
arguments: label: D29
type_infered: string

tool: D92: 
---------------------------------

tool: D113: %d

tool: D4: Please, choose an option of operation: 

tool: D60: * 1 = Addition 

tool: D159: * 2 = Subtraction 

tool: D71: * 3 = Multiplication 

tool: D73: * 4 = Division 

tool: D32: * 5 = MOD 

tool: D75: * 6 = Exit 

tool: D21: Please, insert the number primary: 

tool: D24: 
Please, insert the number secondary: 

tool: D154: -----BYE----- 

tool: D80: Result subtraction is: %.2f 


tool: D63: Result the mod is: %.2f 


tool: D169: Result addition is: %.2f 


tool: D74: Result multiplication is: %.2f 


tool: D29: Result division is: %.2f 


assistant: ```c
int main() {
  int numberPrimary;
  int numberSecondary;
  int option;
  float result;
  printf("\n---------------------------------\n");
  printf("Please, choose an option of operation: \n");
  printf("* 1 = Addition \n");
  printf("* 2 = Subtraction \n");
  printf("* 3 = Multiplication \n");
  printf("* 4 = Division \n");
  printf("* 5 = MOD \n");
  printf("* 6 = Exit \n");
  scanf("%d", &option);
  if (option == 6) {
    printf("-----BYE----- \n");
    exit(0);
  }
  printf("Please, insert the number primary: ");
  scanf("%d", &numberPrimary);
  printf("\nPlease, insert the number secondary: ");
  scanf("%d", &numberSecondary);
  if (option == 1) {
    result = ((numberPrimary) + (numberSecondary));
    printf("Result addition is: %.2f \n", result);
  } else if (option == 2) {
    result = ((numberPrimary) - (numberSecondary));
    printf("Result subtraction is: %.2f \n", result);
  } else if (option == 3) {
    result = ((numberPrimary) * (numberSecondary));
    printf("Result multiplication is: %.2f \n", result);
  } else if (option == 4) {
    result = ((numberPrimary) / (numberSecondary));
    printf("Result division is: %.2f \n", result);
  } else if (option == 5) {
    result = (numberPrimary % numberSecondary);
    printf("Result the mod is: %.2f \n", result);
  } else {
    printf("-----BYE----- \n");
    exit(0);
  }
  printf("\n---------------------------------\n");
}
```