ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <FD_SET@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  call   <FD_SET@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <FD_SET@plt>
  mov    %rbp,%rsi
  mov    $0x7,%edi
  call   <FD_SET@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <FD_ISSET@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <FD_CLR@plt>
  mov    $0x4,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <FD_ISSET@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D18: fdset sizeof is %ld


tool: D13: isset = %d


assistant: ```c
int main() {
  fd_set fdset;
  FD_ZERO(&fdset);
  FD_SET(1, &fdset);
  FD_SET(2, &fdset);
  FD_SET(3, &fdset);
  FD_SET(7, &fdset);
  int isset = FD_ISSET(3, &fdset);
  printf("isset = %d\n", isset);
  printf("fdset sizeof is %ld\n", sizeof(fdset));
  FD_CLR(3, &fdset);
  printf("fdset sizeof is %ld\n", sizeof(fdset));
  isset = FD_ISSET(3, &fdset);
  printf("isset = %d\n", isset);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <FD_SET@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  call   <FD_SET@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <FD_SET@plt>
  mov    %rbp,%rsi
  mov    $0x7,%edi
  call   <FD_SET@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <FD_ISSET@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <FD_CLR@plt>
  mov    $0x4,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <FD_ISSET@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D14
type_guessed: string

tool: D16: fdset sizeof is %ld


tool: D14: isset = %d


assistant: ```c
int main() {
  fd_set fdset;
  FD_ZERO(&fdset);
  FD_SET(1, &fdset);
  FD_SET(2, &fdset);
  FD_SET(3, &fdset);
  FD_SET(7, &fdset);
  int isset = FD_ISSET(3, &fdset);
  printf("isset = %d\n", isset);
  printf("fdset sizeof is %ld\n", sizeof(fdset));
  FD_CLR(3, &fdset);
  printf("fdset sizeof is %ld\n", sizeof(fdset));
  isset = FD_ISSET(3, &fdset);
  printf("isset = %d\n", isset);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x0,-0x2(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x2(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  movzbl -0x2(%rbp),%eax
  mov    %al,-0x1(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  sub    $0x60,%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: a + b = %d

assistant: ```c
int main() {
  char a = 0;
  a = getchar();
  getchar();
  char b;
  b = a;
  b = getchar();
  printf("a + b = %d", (a - '0') + (b - '0'));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    -0x60(%rbx,%rax,1),%esi
  movsbl %sil,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string

tool: D1: a + b = %d

assistant: ```c
int main() {
  char a = 0;
  a = getchar();
  getchar();
  char b;
  b = a;
  b = getchar();
  printf("a + b = %d", (a - '0') + (b - '0'));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D5(%rip),%rdi
  lea    -0x60(%rbx,%rax,1),%esi
  movsbl %sil,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: a + b = %d

assistant: ```c
int main() {
  char a = 0;
  a = getchar();
  getchar();
  char b;
  b = a;
  b = getchar();
  printf("a + b = %d", (a - '0') + (b - '0'));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D1(%rip),%rdi
  lea    -0x60(%rbx,%rax,1),%esi
  movsbl %sil,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: a + b = %d

assistant: ```c
int main() {
  char a = 0;
  a = getchar();
  getchar();
  char b;
  b = a;
  b = getchar();
  printf("a + b = %d", (a - '0') + (b - '0'));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6d616441,-0x65(%rbp)
  movb   $0x0,-0x61(%rbp)
  movabs $0x2073692073696854,%rax
  movabs $0x6e65746e65732061,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x6120646e61206563,%rax
  movabs $0x666f207473657420,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x20676e6972747320,%rax
  movabs $0x6e65736572706572,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movabs $0x2e6e6f69746174,%rax
  mov    %rax,-0x10(%rbp)
  movzbl -0x65(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x65(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D31
datatype: string
name: disassemble_data
arguments: data_tag: D28
datatype: string
name: disassemble_data
arguments: data_tag: D36
datatype: string

tool: D0: %c


tool: D31: Please enter your name: 

tool: D28: %s

tool: D36: Nice to meet you %s.

assistant: ```c
int main() {
  char name[] = "Adam";
  char sentence[] = "This is a sentence and a test of string representation.";
  char nameInput[20];
  printf("%c\n", name[0]);
  printf("%s\n", name);
  printf("%s\n", sentence);
  printf("Please enter your name: ");
  scanf("%s", &nameInput);
  printf("Nice to meet you %s.", nameInput);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x6d616441,0xb(%rsp)
  movb   $0x0,0xf(%rsp)
  movabs $0x2073692073696854,%rax
  movabs $0x6e65746e65732061,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x6120646e61206563,%rax
  movabs $0x666f207473657420,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x20676e6972747320,%rax
  movabs $0x6e65736572706572,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movabs $0x2e6e6f69746174,%rax
  mov    %rax,0x60(%rsp)
  mov    $0x41,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xb(%rsp),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rdi
  call   <puts@plt>
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D33
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D7
type_infered: string

tool: D11: %c


tool: D33: Please enter your name: 

tool: D12: %s

tool: D7: Nice to meet you %s.

assistant: ```c
int main() {
  char name[] = "Adam";
  char sentence[] = "This is a sentence and a test of string representation.";
  char nameInput[20];
  printf("%c\n", name[0]);
  printf("%s\n", name);
  printf("%s\n", sentence);
  printf("Please enter your name: ");
  scanf("%s", &nameInput);
  printf("Nice to meet you %s.", nameInput);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x41,%esi
  lea    D55(%rip),%rdi
  sub    $0x70,%rsp
  movdqa D41(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x6d616441,0xb(%rsp)
  lea    0x10(%rsp),%rbp
  movabs $0x2e6e6f69746174,%rax
  movaps %xmm0,0x30(%rsp)
  movdqa D37(%rip),%xmm0
  mov    %rax,0x60(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x40(%rsp)
  movdqa D10(%rip),%xmm0
  movb   $0x0,0xf(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <printf@plt>
  lea    0xb(%rsp),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rdi
  call   <puts@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D55
data_type: string
name: retrieve_data
arguments: label: D41
data_type: byte[16]
name: retrieve_data
arguments: label: D37
data_type: byte[16]
name: retrieve_data
arguments: label: D10
data_type: byte[16]
name: retrieve_data
arguments: label: D32
data_type: string
name: retrieve_data
arguments: label: D54
data_type: string
name: retrieve_data
arguments: label: D64
data_type: string

tool: D55: %c


tool: {"D41": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x73,0x65,0x6e,0x74,0x65,0x6e]}

tool: {"D37": [0x63,0x65,0x20,0x61,0x6e,0x64,0x20,0x61,0x20,0x74,0x65,0x73,0x74,0x20,0x6f,0x66]}

tool: {"D10": [0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x20,0x72,0x65,0x70,0x72,0x65,0x73,0x65,0x6e]}

tool: D32: Please enter your name: 

tool: D54: %s

tool: D64: Nice to meet you %s.

assistant: ```c
int main() {
  char name[] = "Adam";
  char sentence[] = "This is a sentence and a test of string representation.";
  char nameInput[20];
  printf("%c\n", name[0]);
  printf("%s\n", name);
  printf("%s\n", sentence);
  printf("Please enter your name: ");
  scanf("%s", &nameInput);
  printf("Nice to meet you %s.", nameInput);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x41,%esi
  lea    D42(%rip),%rdi
  sub    $0x70,%rsp
  movdqa D66(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x6d616441,0xb(%rsp)
  lea    0x10(%rsp),%rbp
  movabs $0x2e6e6f69746174,%rax
  movaps %xmm0,0x30(%rsp)
  movdqa D3(%rip),%xmm0
  mov    %rax,0x60(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x40(%rsp)
  movdqa D9(%rip),%xmm0
  movb   $0x0,0xf(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <printf@plt>
  lea    0xb(%rsp),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rdi
  call   <puts@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D42
data_type: string
name: extract_symbolic_data
arguments: label: D66
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D3
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D9
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D43
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string

tool: D42: %c


tool: {"D66": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x73,0x65,0x6e,0x74,0x65,0x6e]}

tool: {"D3": [0x63,0x65,0x20,0x61,0x6e,0x64,0x20,0x61,0x20,0x74,0x65,0x73,0x74,0x20,0x6f,0x66]}

tool: {"D9": [0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x20,0x72,0x65,0x70,0x72,0x65,0x73,0x65,0x6e]}

tool: D43: Please enter your name: 

tool: D2: %s

tool: D12: Nice to meet you %s.

assistant: ```c
int main() {
  char name[] = "Adam";
  char sentence[] = "This is a sentence and a test of string representation.";
  char nameInput[20];
  printf("%c\n", name[0]);
  printf("%s\n", name);
  printf("%s\n", sentence);
  printf("Please enter your name: ");
  scanf("%s", &nameInput);
  printf("Nice to meet you %s.", nameInput);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<file_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%r13d
  test   %rsi,%rsi
  je     L28
  mov    %rsi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jle    L44
  movslq %eax,%rbx
L7:
  mov    %r12,%rdi
  call   <strlen@plt>
  movzbl -0x1(%rbp,%rbx,1),%edx
  add    %rbp,%rax
  mov    %dl,(%rax,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L7
L44:
  mov    %r12,%rdi
  call   <strlen@plt>
  movb   $0x2f,0x0(%rbp,%rax,1)
  mov    $0x0,%ebx
  jmp    L24
L49:
  movzbl (%r12,%rbx,1),%eax
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L24:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  ja     L49
L28:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    D1(%rip),%rcx
  movslq %r13d,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %r13d,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  movslq %edx,%rsi
  movzbl (%rcx,%rsi,1),%esi
  mov    %sil,0x0(%rbp,%rax,1)
  imul   $0x64,%edx,%edx
  sub    %edx,%r13d
  movslq %r13d,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %r13d,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  movslq %edx,%rsi
  movzbl (%rcx,%rsi,1),%esi
  mov    %sil,0x1(%rbp,%rax,1)
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%r13d
  movslq %r13d,%r13
  movzbl (%rcx,%r13,1),%edx
  mov    %dl,0x2(%rbp,%rax,1)
  movb   $0x2e,0x3(%rbp,%rax,1)
  movb   $0x6f,0x4(%rbp,%rax,1)
  movb   $0x64,0x5(%rbp,%rax,1)
  movb   $0x73,0x6(%rbp,%rax,1)
  movb   $0x0,0x7(%rbp,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void file_name(char *name, char *work_dir, int task_number) {
  static char name0[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
  int index;
  if (work_dir != '\0') {
    for (index = strlen(name); index > 0; index--)
      name[index + strlen(work_dir)] = name[index - 1];
    name[strlen(work_dir)] = '/';
    for (index = 0; index < strlen(work_dir); index++)
      name[index] = work_dir[index];
  }
  index = strlen(name);
  name[index] = name0[task_number / 100];
  task_number %= 100;
  name[index + 1] = name0[task_number / 10];
  task_number %= 10;
  name[index + 2] = name0[task_number];
  name[index + 3] = '.';
  name[index + 4] = 'o';
  name[index + 5] = 'd';
  name[index + 6] = 's';
  name[index + 7] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<file_name>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L11
  mov    %rsi,%r13
  call   <strlen@plt>
  movslq %eax,%rbp
  test   %eax,%eax
  jle    L18
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r13,%rdi
  call   <strlen@plt>
  movzbl -0x1(%rbx,%rbp,1),%edx
  add    %rbx,%rax
  mov    %dl,(%rax,%rbp,1)
  sub    $0x1,%rbp
  jne    L6
L18:
  mov    %r13,%rdi
  xor    %ebp,%ebp
  call   <strlen@plt>
  movb   $0x2f,(%rbx,%rax,1)
  jmp    L42
  nopl   0x0(%rax)
L20:
  movzbl 0x0(%r13,%rbp,1),%eax
  mov    %al,(%rbx,%rbp,1)
  add    $0x1,%rbp
L42:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %rbp,%rax
  ja     L20
L11:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %r12d,%rdx
  mov    %r12d,%esi
  lea    D9(%rip),%rcx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%esi
  cltq
  movb   $0x2e,0x3(%rbx,%rax,1)
  movb   $0x6f,0x4(%rbx,%rax,1)
  sar    $0x25,%rdx
  movb   $0x64,0x5(%rbx,%rax,1)
  sub    %esi,%edx
  movb   $0x73,0x6(%rbx,%rax,1)
  movslq %edx,%rsi
  imul   $0x64,%edx,%edx
  movb   $0x0,0x7(%rbx,%rax,1)
  movzbl (%rcx,%rsi,1),%esi
  sub    %edx,%r12d
  mov    %sil,(%rbx,%rax,1)
  movslq %r12d,%rdx
  mov    %r12d,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  movslq %edx,%rsi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  movzbl (%rcx,%rsi,1),%esi
  sub    %edx,%r12d
  movslq %r12d,%r12
  mov    %sil,0x1(%rbx,%rax,1)
  movzbl (%rcx,%r12,1),%edx
  mov    %dl,0x2(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void file_name(char *name, char *work_dir, int task_number) {
  static char name0[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
  int index;
  if (work_dir != '\0') {
    for (index = strlen(name); index > 0; index--)
      name[index + strlen(work_dir)] = name[index - 1];
    name[strlen(work_dir)] = '/';
    for (index = 0; index < strlen(work_dir); index++)
      name[index] = work_dir[index];
  }
  index = strlen(name);
  name[index] = name0[task_number / 100];
  task_number %= 100;
  name[index + 1] = name0[task_number / 10];
  task_number %= 10;
  name[index + 2] = name0[task_number];
  name[index + 3] = '.';
  name[index + 4] = 'o';
  name[index + 5] = 'd';
  name[index + 6] = 's';
  name[index + 7] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<file_name>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L42
  mov    %rsi,%r13
  call   <strlen@plt>
  movslq %eax,%rbp
  test   %eax,%eax
  jle    L41
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r13,%rdi
  call   <strlen@plt>
  movzbl -0x1(%rbx,%rbp,1),%edx
  add    %rbx,%rax
  mov    %dl,(%rax,%rbp,1)
  sub    $0x1,%rbp
  jne    L28
L41:
  mov    %r13,%rdi
  xor    %ebp,%ebp
  call   <strlen@plt>
  movb   $0x2f,(%rbx,%rax,1)
  jmp    L32
  nopl   0x0(%rax)
L33:
  movzbl 0x0(%r13,%rbp,1),%eax
  mov    %al,(%rbx,%rbp,1)
  add    $0x1,%rbp
L32:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %rbp,%rax
  ja     L33
L42:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %r12d,%rdx
  mov    %r12d,%esi
  lea    D3(%rip),%rcx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%esi
  cltq
  movb   $0x2e,0x3(%rbx,%rax,1)
  movb   $0x6f,0x4(%rbx,%rax,1)
  sar    $0x25,%rdx
  movb   $0x64,0x5(%rbx,%rax,1)
  sub    %esi,%edx
  movb   $0x73,0x6(%rbx,%rax,1)
  movslq %edx,%rsi
  imul   $0x64,%edx,%edx
  movb   $0x0,0x7(%rbx,%rax,1)
  movzbl (%rcx,%rsi,1),%esi
  sub    %edx,%r12d
  mov    %sil,(%rbx,%rax,1)
  movslq %r12d,%rdx
  mov    %r12d,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  movslq %edx,%rsi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  movzbl (%rcx,%rsi,1),%esi
  sub    %edx,%r12d
  movslq %r12d,%r12
  mov    %sil,0x1(%rbx,%rax,1)
  movzbl (%rcx,%r12,1),%edx
  mov    %dl,0x2(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void file_name(char *name, char *work_dir, int task_number) {
  static char name0[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
  int index;
  if (work_dir != '\0') {
    for (index = strlen(name); index > 0; index--)
      name[index + strlen(work_dir)] = name[index - 1];
    name[strlen(work_dir)] = '/';
    for (index = 0; index < strlen(work_dir); index++)
      name[index] = work_dir[index];
  }
  index = strlen(name);
  name[index] = name0[task_number / 100];
  task_number %= 100;
  name[index + 1] = name0[task_number / 10];
  task_number %= 10;
  name[index + 2] = name0[task_number];
  name[index + 3] = '.';
  name[index + 4] = 'o';
  name[index + 5] = 'd';
  name[index + 6] = 's';
  name[index + 7] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<NF_Page_Erase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0xb,%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <select_chip@plt>
  mov    $0x0,%eax
  call   <clear_RnB@plt>
  mov    $0x60,%edi
  call   <send_cmd@plt>
  mov    -0x18(%rbp),%rax
  movzbl %al,%eax
  mov    %rax,%rdi
  call   <send_addr@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    %rax,%rdi
  call   <send_addr@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    %rax,%rdi
  call   <send_addr@plt>
  mov    $0xd0,%edi
  call   <send_cmd@plt>
  mov    $0x0,%eax
  call   <wait_RnB@plt>
  mov    $0x70,%edi
  call   <send_cmd@plt>
  mov    $0x70200010,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <delete_chip@plt>
  nop
  leave
  ret
```

assistant: ```c
void NF_Page_Erase(unsigned long addr) {
  int i;
  int ret;
  addr = addr / 2048;
  select_chip();
  clear_RnB();
  send_cmd(0x60);
  send_addr(addr & 0xFF);
  send_addr((addr >> 8) & (0xFF));
  send_addr((addr >> 16) & (0xFF));
  send_cmd(0xD0);
  wait_RnB();
  send_cmd(0x70);
  ret = (*(volatile unsigned char *)0x70200010);
  delete_chip();
}
```