user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0xab8,%rsp
  lea    D14(%rip),%rbx
  xor    %r12d,%r12d
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x61aa8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  lea    0x20(%rsp),%r13
  call   <scanf@plt>
  mov    0x18(%rsp),%edx
  lea    0x1c(%rsp),%rax
  mov    %rax,0x8(%rsp)
  test   %edx,%edx
  jle    L125
  nopl   0x0(%rax,%rax,1)
L86:
  lea    0x1(%r12),%ebp
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L43
  mov    %r13,%r15
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L91:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r14d
  add    $0x4,%r15
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  cmp    %r14d,%edx
  jg     L91
  mov    0x20(%rsp),%eax
  test   %edx,%edx
  jle    L97
  lea    0x1(%rdx),%ecx
  lea    0x24(%rsp),%rsi
  mov    %eax,%r8d
  mov    $0x2,%edx
  mov    $0x1,%edi
  mov    $0x1,%r10d
  mov    $0x1,%r9d
  jmp    L112
  nopl   0x0(%rax,%rax,1)
L68:
  add    (%rsi),%eax
  cmp    %eax,%r8d
  jge    L67
  mov    %edx,%r10d
  mov    %edi,%r9d
  mov    %eax,%r8d
L67:
  add    $0x1,%edx
  add    $0x4,%rsi
L112:
  test   %eax,%eax
  jns    L188
  mov    %edx,%edi
  xor    %eax,%eax
L188:
  cmp    %ecx,%edx
  jne    L68
  test   %r8d,%r8d
  js     L33
L150:
  mov    %r9d,%edx
  mov    %r10d,%ecx
  mov    %r8d,%esi
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %r12d,%edx
  je     L130
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    0x18(%rsp),%ebp
  jge    L125
L148:
  mov    %ebp,%r12d
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L130:
  cmp    %eax,%ebp
  jl     L148
L125:
  mov    0x61aa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x61ab8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    $0x1,%eax
  jmp    L25
  nop
L10:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L150
L25:
  cmp    %r8d,-0x4(%r13,%rax,4)
  jne    L10
  mov    %eax,%r10d
  mov    %eax,%r9d
  jmp    L150
  nop
L43:
  mov    0x20(%rsp),%eax
L97:
  mov    %eax,%r8d
  mov    $0x1,%r10d
  mov    $0x1,%r9d
  jmp    L150
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D27
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D14: %d

tool: D27: Case %d:


tool: D16: %d %d %d


assistant: ```c
int main() {
  int T, test, num[100000], i, max, maxstart, maxtail, numofnum, sum, hold;
  scanf("%d", &T);
  for (test = 0; test < T; test++) {
    printf("Case %d:\n", test + 1);
    scanf("%d", &numofnum);
    for (i = 0; i < numofnum; i++)
      scanf("%d", &num[i]);
    max = num[0];
    hold = maxtail = maxstart = 1;
    for (i = 0, sum = 0; i < numofnum; i++) {
      sum += num[i];
      if (sum > max) {
        max = sum;
        maxtail = i + 1;
        maxstart = hold;
      }
      if (sum < 0) {
        sum = 0;
        hold = i + 2;
      }
    }
    if (max < 0) {
      for (i = 0; i < numofnum; i++) {
        if (num[i] == max) {
          max = num[i];
          maxtail = i + 1;
          maxstart = maxtail;
          goto l1;
        }
      }
    }
  l1:
    printf("%d %d %d\n", max, maxstart, maxtail);
    if (test != T - 1)
      printf("\n");
  }
  return 0;
}
```