ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<genrand_res53>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <genrand_int32@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <genrand_int32@plt>
  sar    $0x5,%ebx
  movslq %ebx,%rdx
  test   %rdx,%rdx
  js     L12
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
L23:
  mulsd  D19(%rip),%xmm0
  sar    $0x6,%eax
  cltq
  test   %rax,%rax
  js     L25
  pxor   %xmm1,%xmm1
  pop    %rbx
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D27(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rdx,%rcx
  and    $0x1,%edx
  pxor   %xmm0,%xmm0
  shr    %rcx
  or     %rdx,%rcx
  cvtsi2sd %rcx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm1,%xmm1
  pop    %rbx
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm1
  addsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D27(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
data_type: f64
name: unpack_data
arguments: label: D27
data_type: byte[8]

tool: D19: 67108864

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0xa0,0x3c]}

assistant: ```c
double genrand_res53(void) {
  unsigned long a = genrand_int32() >> 5, b = genrand_int32() >> 6;
  return (a * 67108864.0 + b) * (1.0 / 9007199254740992.0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_next_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %rsi,-0xf0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L43:
  lea    -0xd0(%rbp),%rax
  mov    %rax,-0xd8(%rbp)
  mov    -0xe8(%rbp),%rdx
  mov    -0xd8(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L3
  mov    -0xd8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xdc(%rbp)
  jmp    L46
L6:
  subl   $0x1,-0xdc(%rbp)
  mov    -0xdc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xd8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L46:
  cmpl   $0x0,-0xdc(%rbp)
  jle    L48
  mov    -0xdc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0xd8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
  jmp    L48
L55:
  addq   $0x1,-0xd8(%rbp)
L48:
  mov    -0xd8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L55
  mov    -0xd8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L43
  mov    -0xd8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  je     L43
  mov    -0xd8(%rbp),%rdx
  mov    -0xf0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L92
L3:
  nop
  mov    $0x0,%eax
L92:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

assistant: ```c
int get_next_line(FILE *f, char *c) {
  char *str, string[200];
  int len;
  do {
    str = string;
    if (!fgets(str, 200, f)) {
      ;
      goto error;
    }
    len = strlen(str);
    while (len >= 1 && isspace(str[len - 1]))
      str[--len] = 0;
    while (isspace(*str))
      str++;
  } while (strlen(str) == 0 || *str == '#');
  strcpy(c, str);
  return 1;
error:
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_next_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L76
L97:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L76
  cmpb   $0x23,(%rbx)
  jne    L50
L76:
  mov    %r12,%rdx
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L98
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L18
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,1),%rbx
  lea    -0x1(%rsp,%rdx,1),%r14
  lea    -0x1(%rax),%eax
  sub    %rax,%r14
L73:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L18
  movb   $0x0,-0x1(%rbx)
  sub    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L73
L18:
  mov    %rsp,%rbx
L61:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L97
  add    $0x1,%rbx
  jmp    L61
L50:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
L98:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L80
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_next_line(FILE *f, char *c) {
  char *str, string[200];
  int len;
  do {
    str = string;
    if (!fgets(str, 200, f)) {
      ;
      goto error;
    }
    len = strlen(str);
    while (len >= 1 && isspace(str[len - 1]))
      str[--len] = 0;
    while (isspace(*str))
      str++;
  } while (strlen(str) == 0 || *str == '#');
  strcpy(c, str);
  return 1;
error:
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_next_line>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    -0x1(%rsp),%r13
  cs nopw 0x0(%rax,%rax,1)
L68:
  mov    %r12,%rdx
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L5
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L34
  movslq %eax,%r15
  sub    $0x1,%eax
  lea    0x0(%rbp,%r15,1),%rbx
  add    %r13,%r15
  sub    %rax,%r15
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L9:
  movb   $0x0,-0x1(%rbx)
  sub    $0x1,%rbx
  cmp    %r15,%rbx
  je     L34
L32:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
L34:
  mov    %rbp,%r15
  jmp    L51
L14:
  add    $0x1,%r15
L51:
  movsbl (%r15),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    %r15,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L68
  cmpb   $0x23,(%r15)
  je     L68
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
L5:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_next_line(FILE *f, char *c) {
  char *str, string[200];
  int len;
  do {
    str = string;
    if (!fgets(str, 200, f)) {
      ;
      goto error;
    }
    len = strlen(str);
    while (len >= 1 && isspace(str[len - 1]))
      str[--len] = 0;
    while (isspace(*str))
      str++;
  } while (strlen(str) == 0 || *str == '#');
  strcpy(c, str);
  return 1;
error:
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_next_line>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    -0x1(%rsp),%r13
  cs nopw 0x0(%rax,%rax,1)
L67:
  mov    %r12,%rdx
  mov    $0xc8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L35
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  movslq %eax,%r15
  sub    $0x1,%eax
  lea    0x0(%rbp,%r15,1),%rbx
  add    %r13,%r15
  sub    %rax,%r15
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L52:
  movb   $0x0,-0x1(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%r15
  je     L4
L38:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L52
L4:
  mov    %rbp,%r15
  jmp    L8
L16:
  add    $0x1,%r15
L8:
  movsbl (%r15),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L16
  mov    %r15,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L67
  cmpb   $0x23,(%r15)
  je     L67
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
L35:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_next_line(FILE *f, char *c) {
  char *str, string[200];
  int len;
  do {
    str = string;
    if (!fgets(str, 200, f)) {
      ;
      goto error;
    }
    len = strlen(str);
    while (len >= 1 && isspace(str[len - 1]))
      str[--len] = 0;
    while (isspace(*str))
      str++;
  } while (strlen(str) == 0 || *str == '#');
  strcpy(c, str);
  return 1;
error:
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rdtsc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  rdtsc
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int64_t rdtsc() {
  int64_t ret;
  __asm__ volatile("rdtsc" : "=A"(ret) : :);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rdtsc>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
int64_t rdtsc() {
  int64_t ret;
  __asm__ volatile("rdtsc" : "=A"(ret) : :);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rdtsc>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
int64_t rdtsc() {
  int64_t ret;
  __asm__ volatile("rdtsc" : "=A"(ret) : :);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rdtsc>:
  endbr64
  rdtsc
  ret
```

assistant: ```c
int64_t rdtsc() {
  int64_t ret;
  __asm__ volatile("rdtsc" : "=A"(ret) : :);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <cbrtl@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  D11(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  cmp    $0x3,%eax
  je     L3
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: f64
name: parse_data
arguments: tag: D11
data_type: f64

tool: D9: 27

tool: D11: 0.5

assistant: ```c
main() {
  if ((int)(cbrtl(27.0) + 0.5) != 3)
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D3(%rip),%xmm0
  call   <cbrtl@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  D1(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  cmp    $0x3,%eax
  jne    L11
L18:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L11:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: f64
name: parse_data
arguments: data_label: D1
data_type: f64

tool: D3: 27

tool: D1: 0.5

assistant: ```c
main() {
  if ((int)(cbrtl(27.0) + 0.5) != 3)
    abort();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D9(%rip),%xmm0
  call   <cbrtl@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  D17(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  cmp    $0x3,%eax
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: f64
name: disassemble_data
arguments: data_tag: D17
data_type: f64

tool: D9: 27

tool: D17: 0.5

assistant: ```c
main() {
  if ((int)(cbrtl(27.0) + 0.5) != 3)
    abort();
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D15(%rip),%xmm0
  call   <cbrtl@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  cmp    $0x3,%eax
  je     L6
  xor    %eax,%eax
  call   <abort@plt>
L6:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
type_infered: f64
name: parse_data
arguments: data_label: D6
type_infered: f64

tool: D15: 27

tool: D6: 0.5

assistant: ```c
main() {
  if ((int)(cbrtl(27.0) + 0.5) != 3)
    abort();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stringlength2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L8:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int stringlength2(char *s) {
  char *p = s;
  while (*(++p) != '\0')
    ;
  return p - s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stringlength2>:
  endbr64
  mov    %rdi,%rax
L2:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L2
  sub    %edi,%eax
  ret
```

assistant: ```c
int stringlength2(char *s) {
  char *p = s;
  while (*(++p) != '\0')
    ;
  return p - s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stringlength2>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L1
  sub    %edi,%eax
  ret
```

assistant: ```c
int stringlength2(char *s) {
  char *p = s;
  while (*(++p) != '\0')
    ;
  return p - s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stringlength2>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L6
  sub    %edi,%eax
  ret
```

assistant: ```c
int stringlength2(char *s) {
  char *p = s;
  while (*(++p) != '\0')
    ;
  return p - s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setIzena>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L3
L8:
  subl   $0x1,-0xc(%rbp)
L3:
  cmpl   $0x0,-0xc(%rbp)
  je     L38
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L8
L38:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L14
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  leave
  ret
```

assistant: ```c
void setIzena(char **izena, char *helbidea) {
  int end_ind = (int)strlen(helbidea);
  int start_ind = end_ind;
  while ((start_ind != 0) && (helbidea[start_ind] != '/')) {
    start_ind--;
  }
  int luzera = (end_ind - start_ind) + 1;
  (*izena) = (char *)malloc(sizeof(char) * luzera);
  if (helbidea[start_ind] == '/') {
    start_ind++;
  }
  sprintf(*izena, helbidea + start_ind);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setIzena>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L20
  movslq %eax,%rdx
L31:
  mov    %edx,%ebx
  cmpb   $0x2f,0x0(%rbp,%rdx,1)
  je     L19
  sub    $0x1,%rdx
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L31
L19:
  sub    %ebx,%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%r12)
  movslq %ebx,%rax
  cmpb   $0x2f,0x0(%rbp,%rax,1)
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rsi
  call   <sprintf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    %eax,%ebx
  jmp    L19
```

assistant: ```c
void setIzena(char **izena, char *helbidea) {
  int end_ind = (int)strlen(helbidea);
  int start_ind = end_ind;
  while ((start_ind != 0) && (helbidea[start_ind] != '/')) {
    start_ind--;
  }
  int luzera = (end_ind - start_ind) + 1;
  (*izena) = (char *)malloc(sizeof(char) * luzera);
  if (helbidea[start_ind] == '/') {
    start_ind++;
  }
  sprintf(*izena, helbidea + start_ind);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setIzena>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  test   %eax,%eax
  je     L14
  movslq %eax,%rdx
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L17:
  sub    $0x1,%rdx
  mov    %edx,%ebp
  test   %edx,%edx
  je     L34
L28:
  cmpb   $0x2f,(%rbx,%rdx,1)
  mov    %edx,%ebp
  lea    (%rbx,%rdx,1),%r12
  jne    L17
  mov    %eax,%edi
  sub    %edx,%edi
L46:
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  cmpb   $0x2f,(%r12)
  mov    %rax,%rdi
  jne    L37
  add    $0x1,%ebp
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%r12
L37:
  add    $0x8,%rsp
  mov    %r12,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <sprintf@plt>
  nopl   0x0(%rax)
L34:
  mov    %rbx,%r12
  jmp    L46
L14:
  mov    %rbx,%r12
  xor    %ebp,%ebp
  jmp    L46
```

assistant: ```c
void setIzena(char **izena, char *helbidea) {
  int end_ind = (int)strlen(helbidea);
  int start_ind = end_ind;
  while ((start_ind != 0) && (helbidea[start_ind] != '/')) {
    start_ind--;
  }
  int luzera = (end_ind - start_ind) + 1;
  (*izena) = (char *)malloc(sizeof(char) * luzera);
  if (helbidea[start_ind] == '/') {
    start_ind++;
  }
  sprintf(*izena, helbidea + start_ind);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setIzena>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  test   %eax,%eax
  je     L35
  movslq %eax,%rdx
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L63:
  sub    $0x1,%rdx
  mov    %edx,%ebp
  test   %edx,%edx
  je     L42
L58:
  cmpb   $0x2f,(%rbx,%rdx,1)
  mov    %edx,%ebp
  lea    (%rbx,%rdx,1),%r12
  jne    L63
  mov    %eax,%edi
  sub    %edx,%edi
L4:
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  cmpb   $0x2f,(%r12)
  mov    %rax,%rdi
  jne    L3
  add    $0x1,%ebp
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%r12
L3:
  add    $0x8,%rsp
  mov    %r12,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <sprintf@plt>
  nopl   0x0(%rax)
L42:
  mov    %rbx,%r12
  jmp    L4
L35:
  mov    %rbx,%r12
  xor    %ebp,%ebp
  jmp    L4
```

assistant: ```c
void setIzena(char **izena, char *helbidea) {
  int end_ind = (int)strlen(helbidea);
  int start_ind = end_ind;
  while ((start_ind != 0) && (helbidea[start_ind] != '/')) {
    start_ind--;
  }
  int luzera = (end_ind - start_ind) + 1;
  (*izena) = (char *)malloc(sizeof(char) * luzera);
  if (helbidea[start_ind] == '/') {
    start_ind++;
  }
  sprintf(*izena, helbidea + start_ind);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L13:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D20(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <errorfun@plt>
  movq   %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D20(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x4,-0x4(%rbp)
  jle    L13
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D20
type_infered: f64
name: read_data
arguments: tag: D11
type_infered: string

tool: D20: 0.05

tool: D11: 
errorfun(%4.2f)=%2.5f

assistant: ```c
main() {
  int i;
  for (i = 0; i < 5; i++) {
    printf("\nerrorfun(%4.2f)=%2.5f", i * 0.05, errorfun(i * 0.05));
  }
  getch();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L2:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%ebp
  mov    %ebp,%edi
  call   <errorfun@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L2
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: f64

tool: D4: 
errorfun(%4.2f)=%2.5f

tool: D3: 0.05

assistant: ```c
main() {
  int i;
  for (i = 0; i < 5; i++) {
    printf("\nerrorfun(%4.2f)=%2.5f", i * 0.05, errorfun(i * 0.05));
  }
  getch();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
L7:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D3(%rip),%xmm0
  add    $0x1,%ebx
  cvttsd2si %xmm0,%r12d
  mov    %r12d,%edi
  call   <errorfun@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L7
  xor    %eax,%eax
  call   <getch@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string
name: retrieve_data
arguments: data_label: D3
data_type: f64

tool: D8: 
errorfun(%4.2f)=%2.5f

tool: D3: 0.05

assistant: ```c
main() {
  int i;
  for (i = 0; i < 5; i++) {
    printf("\nerrorfun(%4.2f)=%2.5f", i * 0.05, errorfun(i * 0.05));
  }
  getch();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
L2:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D7(%rip),%xmm0
  add    $0x1,%ebx
  cvttsd2si %xmm0,%r12d
  mov    %r12d,%edi
  call   <errorfun@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L2
  xor    %eax,%eax
  call   <getch@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
datatype: string
name: disassemble_data
arguments: data_tag: D7
datatype: f64

tool: D18: 
errorfun(%4.2f)=%2.5f

tool: D7: 0.05

assistant: ```c
main() {
  int i;
  for (i = 0; i < 5; i++) {
    printf("\nerrorfun(%4.2f)=%2.5f", i * 0.05, errorfun(i * 0.05));
  }
  getch();
}
```
user: What is the c source code of the assembly code below?

```asm
<dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x5(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
L0:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
datatype: string
name: unpack_data
arguments: label: D16
datatype: string

tool: D12: memory dump of %d bytes from address 0x%x


tool: D16: 0x%02X 

assistant: ```c
void dump(const void *buff, int count) {
  int i = 0;
  printf("memory dump of %d bytes from address 0x%x\n", count, buff);
  for (i = 0; i < count; i++) {
    unsigned char ch = *(const unsigned char *)buff;
    printf("0x%02X ", ch);
    if ((i + 1) % 16 == 0)
      printf("\n");
    buff = (const char *)buff + 1;
  }
  printf("\n");
}
```