ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<next_generation>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %edx,%r14d
  lea    D4(%rip),%rdi
  call   <printf@plt>
  test   %r14d,%r14d
  jle    L82
  mov    %r14d,%r12d
  mov    $0x0,%ebx
  sub    $0x1,%r14d
  lea    D5(%rip),%r15
  jmp    L29
L33:
  mov    %r15,%rdi
  call   <printf@plt>
L59:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L9
L29:
  test   %ebx,%ebx
  je     L33
  cmp    %ebx,%r14d
  je     L50
  mov    0x4(%rbp,%rbx,4),%eax
  cmp    %eax,-0x4(%rbp,%rbx,4)
  je     L46
  movl   $0x1,0x0(%r13,%rbx,4)
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L50:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L59
L46:
  movl   $0x0,0x0(%r13,%rbx,4)
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L59
L9:
  mov    $0x0,%eax
L92:
  mov    0x0(%r13,%rax,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L92
L82:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D2
type: string

tool: D4: 


tool: D5: .

tool: D2: *

assistant: ```c
void next_generation(int *current, int *next, int length) {
  int i;
  printf("\n");
  for (i = 0; i < length; i++) {
    if (i == 0) {
      printf(".");
    } else if (i == length - 1) {
      printf(".");
    } else if (current[i - 1] != current[i + 1]) {
      next[i] = 1;
      printf("*");
    } else {
      next[i] = 0;
      printf(".");
    }
  }
  for (i = 0; i < length; i++) {
    current[i] = next[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<next_generation>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D12(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  call   <printf@plt>
  movslq 0xc(%rsp),%r12
  lea    -0x1(%r12),%eax
  mov    %eax,0xc(%rsp)
  test   %r12d,%r12d
  jle    L7
  xor    %ebx,%ebx
  lea    D21(%rip),%r14
  lea    D14(%rip),%r15
  jmp    L33
  nopl   (%rax)
L31:
  cmp    %ebx,0xc(%rsp)
  je     L75
  mov    0x4(%rbp,%rbx,4),%eax
  cmp    %eax,-0x4(%rbp,%rbx,4)
  je     L28
  movl   $0x1,0x0(%r13,%rbx,4)
  mov    %r15,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L53
L33:
  test   %rbx,%rbx
  jne    L31
L75:
  mov    %r14,%rdi
  call   <printf@plt>
L81:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L33
L53:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L69:
  mov    0x0(%r13,%rax,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L69
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L28:
  movl   $0x0,0x0(%r13,%rbx,4)
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L81
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D21
datatype: string
name: retrieve_data
arguments: label: D14
datatype: string

tool: D12: 


tool: D21: .

tool: D14: *

assistant: ```c
void next_generation(int *current, int *next, int length) {
  int i;
  printf("\n");
  for (i = 0; i < length; i++) {
    if (i == 0) {
      printf(".");
    } else if (i == length - 1) {
      printf(".");
    } else if (current[i - 1] != current[i + 1]) {
      next[i] = 1;
      printf("*");
    } else {
      next[i] = 0;
      printf(".");
    }
  }
  for (i = 0; i < length; i++) {
    current[i] = next[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<next_generation>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  lea    D12(%rip),%rdi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %ebx,%ebp
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L56
  lea    -0x1(%rbp),%r13d
  xor    %ebx,%ebx
  lea    D15(%rip),%r14
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L98:
  cmp    %ebx,%r13d
  je     L68
  mov    0x4(%r12,%rbx,4),%eax
  cmp    %eax,-0x4(%r12,%rbx,4)
  je     L21
  movl   $0x1,(%r15,%rbx,4)
  lea    D6(%rip),%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L2
L5:
  test   %rbx,%rbx
  jne    L98
L68:
  mov    %r14,%rdi
  call   <printf@plt>
L42:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L5
L2:
  lea    0x4(%r15),%rdx
  mov    %r12,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L99
  cmp    $0x2,%r13d
  jbe    L99
  mov    0xc(%rsp),%edx
  xor    %eax,%eax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  nopl   0x0(%rax,%rax,1)
L139:
  movdqu (%r15,%rax,1),%xmm0
  movups %xmm0,(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L139
  mov    0xc(%rsp),%ecx
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%cl
  je     L56
  mov    %eax,%edi
  mov    (%r15,%rdi,4),%r8d
  lea    0x0(,%rdi,4),%rdx
  mov    %r8d,(%r12,%rdi,4)
  lea    0x1(%rax),%edi
  cmp    %edi,%ecx
  jle    L56
  mov    0x4(%r15,%rdx,1),%edi
  add    $0x2,%eax
  mov    %edi,0x4(%r12,%rdx,1)
  cmp    %eax,%ecx
  jle    L56
  mov    0x8(%r15,%rdx,1),%eax
  mov    %eax,0x8(%r12,%rdx,1)
L56:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L21:
  movl   $0x0,(%r15,%rbx,4)
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L42
  nopl   (%rax)
L99:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L142:
  mov    (%r15,%rax,4),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L142
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type_infered: string
name: disassemble_data
arguments: label: D15
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string

tool: D12: 


tool: D15: .

tool: D6: *

assistant: ```c
void next_generation(int *current, int *next, int length) {
  int i;
  printf("\n");
  for (i = 0; i < length; i++) {
    if (i == 0) {
      printf(".");
    } else if (i == length - 1) {
      printf(".");
    } else if (current[i - 1] != current[i + 1]) {
      next[i] = 1;
      printf("*");
    } else {
      next[i] = 0;
      printf(".");
    }
  }
  for (i = 0; i < length; i++) {
    current[i] = next[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<NUM_print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L21:
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L24:
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L24
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D1: % .5e 

assistant: ```c
int NUM_print_matrix(double *matrix, int neq) {
  int i = 0;
  int j = 0;
  for (i = 0; i < neq; i++) {
    for (j = 0; j <= neq; j++)
      printf("% .5e ", matrix[i + neq * j]);
    printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<NUM_print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  test   %esi,%esi
  jle    L9
  mov    %esi,%r12d
  mov    %esi,%eax
  mov    %rax,0x8(%rsp)
  movslq %esi,%r13
  shl    $0x3,%r13
  mov    $0x0,%r15d
  lea    D7(%rip),%r14
L3:
  mov    (%rsp),%rax
  lea    (%rax,%r15,8),%rbp
  mov    $0x0,%ebx
L23:
  movsd  0x0(%rbp),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r13,%rbp
  cmp    %ebx,%r12d
  jge    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r15
  cmp    0x8(%rsp),%r15
  jne    L3
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: % .5e 

assistant: ```c
int NUM_print_matrix(double *matrix, int neq) {
  int i = 0;
  int j = 0;
  for (i = 0; i < neq; i++) {
    for (j = 0; j <= neq; j++)
      printf("% .5e ", matrix[i + neq * j]);
    printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<NUM_print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  test   %esi,%esi
  jle    L11
  movslq %esi,%rax
  mov    %esi,%ebx
  lea    D4(%rip),%rbp
  xor    %r13d,%r13d
  mov    %rax,0x8(%rsp)
  lea    0x0(,%rax,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    (%rsp),%rax
  xor    %r15d,%r15d
  lea    (%rax,%r13,8),%r14
  nopl   0x0(%rax,%rax,1)
L7:
  movsd  (%r14),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x1,%r15d
  add    %r12,%r14
  call   <printf@plt>
  cmp    %r15d,%ebx
  jge    L7
  mov    $0xa,%edi
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    0x8(%rsp),%r13
  jne    L12
L11:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: % .5e 

assistant: ```c
int NUM_print_matrix(double *matrix, int neq) {
  int i = 0;
  int j = 0;
  for (i = 0; i < neq; i++) {
    for (j = 0; j <= neq; j++)
      printf("% .5e ", matrix[i + neq * j]);
    printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<NUM_print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  test   %esi,%esi
  jle    L15
  movslq %esi,%rax
  mov    %esi,%ebx
  lea    D0(%rip),%rbp
  xor    %r13d,%r13d
  mov    %rax,0x8(%rsp)
  lea    0x0(,%rax,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    (%rsp),%rax
  xor    %r15d,%r15d
  lea    (%rax,%r13,8),%r14
  nopl   0x0(%rax,%rax,1)
L25:
  movsd  (%r14),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x1,%r15d
  add    %r12,%r14
  call   <printf@plt>
  cmp    %r15d,%ebx
  jge    L25
  mov    $0xa,%edi
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    %r13,0x8(%rsp)
  jne    L11
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0: % .5e 

assistant: ```c
int NUM_print_matrix(double *matrix, int neq) {
  int i = 0;
  int j = 0;
  for (i = 0; i < neq; i++) {
    for (j = 0; j <= neq; j++)
      printf("% .5e ", matrix[i + neq * j]);
    printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<my_getScreenResolution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x400,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x300,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void my_getScreenResolution(int *out_width, int *out_height) {
  *out_width = 1024;
  *out_height = 768;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_getScreenResolution>:
  endbr64
  movl   $0x400,(%rdi)
  movl   $0x300,(%rsi)
  ret
```

assistant: ```c
void my_getScreenResolution(int *out_width, int *out_height) {
  *out_width = 1024;
  *out_height = 768;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_getScreenResolution>:
  endbr64
  movl   $0x400,(%rdi)
  movl   $0x300,(%rsi)
  ret
```

assistant: ```c
void my_getScreenResolution(int *out_width, int *out_height) {
  *out_width = 1024;
  *out_height = 768;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quatfromaxisangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movss  %xmm0,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <normalize3d@plt>
  movss  -0x34(%rbp),%xmm0
  movss  D0(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x18(%rbp)
  movss  -0x34(%rbp),%xmm0
  movss  D0(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <cos@plt>
  movd   %xmm0,%eax
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  movss  -0x14(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mulss  -0x18(%rbp),%xmm0
  movss  %xmm0,(%rax)
  movss  -0x10(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mulss  -0x18(%rbp),%xmm0
  movss  %xmm0,(%rax)
  movss  -0xc(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  mulss  -0x18(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <quatnormalize@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x40]}

assistant: ```c
void quatfromaxisangle(float *q, const float *axis, float radians) {
  float v[3];
  normalize3d(v, axis);
  float sn = sin(radians / 2.0f);
  q[0] = cos(radians / 2.0f);
  q[1] = sn * v[0];
  q[2] = sn * v[1];
  q[3] = sn * v[2];
  quatnormalize(q, q);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quatfromaxisangle>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  movss  %xmm0,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdi
  call   <normalize3d@plt>
  movss  0xc(%rsp),%xmm2
  mulss  D9(%rip),%xmm2
  movd   %xmm2,%r14d
  movaps %xmm2,%xmm0
  call   <sin@plt>
  movss  %xmm0,0xc(%rsp)
  movd   %r14d,%xmm0
  call   <cos@plt>
  movss  %xmm0,(%rbx)
  movss  0xc(%rsp),%xmm1
  movaps %xmm1,%xmm0
  mulss  0x1c(%rsp),%xmm0
  movss  %xmm0,0x4(%rbx)
  movaps %xmm1,%xmm0
  mulss  0x20(%rsp),%xmm0
  movss  %xmm0,0x8(%rbx)
  mulss  0x24(%rsp),%xmm1
  movss  %xmm1,0xc(%rbx)
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <quatnormalize@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void quatfromaxisangle(float *q, const float *axis, float radians) {
  float v[3];
  normalize3d(v, axis);
  float sn = sin(radians / 2.0f);
  q[0] = cos(radians / 2.0f);
  q[1] = sn * v[0];
  q[2] = sn * v[1];
  q[3] = sn * v[2];
  quatnormalize(q, q);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quatfromaxisangle>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  lea    0x1c(%rsp),%rdi
  movss  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <normalize3d@plt>
  movss  0x8(%rsp),%xmm2
  mulss  D1(%rip),%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <sin@plt>
  movss  0xc(%rsp),%xmm2
  movss  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  call   <cos@plt>
  movss  0x8(%rsp),%xmm1
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  movss  %xmm0,0x0(%rbp)
  movss  0x1c(%rsp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rbp)
  movss  0x20(%rsp),%xmm0
  mulss  %xmm1,%xmm0
  mulss  0x24(%rsp),%xmm1
  movss  %xmm0,0x8(%rbp)
  movss  %xmm1,0xc(%rbp)
  call   <quatnormalize@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void quatfromaxisangle(float *q, const float *axis, float radians) {
  float v[3];
  normalize3d(v, axis);
  float sn = sin(radians / 2.0f);
  q[0] = cos(radians / 2.0f);
  q[1] = sn * v[0];
  q[2] = sn * v[1];
  q[3] = sn * v[2];
  quatnormalize(q, q);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quatfromaxisangle>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  lea    0x1c(%rsp),%rdi
  movss  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <normalize3d@plt>
  movss  0x8(%rsp),%xmm2
  mulss  D9(%rip),%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <sin@plt>
  movss  0xc(%rsp),%xmm2
  movss  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  call   <cos@plt>
  movss  0x8(%rsp),%xmm1
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  movss  0x1c(%rsp),%xmm3
  movss  0x20(%rsp),%xmm2
  mulss  %xmm1,%xmm3
  mulss  %xmm1,%xmm2
  mulss  0x24(%rsp),%xmm1
  unpcklps %xmm3,%xmm0
  unpcklps %xmm1,%xmm2
  movlhps %xmm2,%xmm0
  movups %xmm0,0x0(%rbp)
  call   <quatnormalize@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void quatfromaxisangle(float *q, const float *axis, float radians) {
  float v[3];
  normalize3d(v, axis);
  float sn = sin(radians / 2.0f);
  q[0] = cos(radians / 2.0f);
  q[1] = sn * v[0];
  q[2] = sn * v[1];
  q[3] = sn * v[2];
  quatnormalize(q, q);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EndString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L29
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L60
  mov    $0x0,%eax
  jmp    L29
L60:
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L40
L37:
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L72
  mov    $0x0,%eax
  jmp    L29
L72:
  addl   $0x1,-0x10(%rbp)
L40:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L37
  mov    $0x1,%eax
L29:
  leave
  ret
```

assistant: ```c
int EndString(char *thisString, char *endString) {
  int thisLength;
  int endLength;
  int diff, i;
  if (!thisString)
    return 0;
  thisLength = strlen(thisString);
  endLength = strlen(endString);
  if (thisLength < endLength)
    return 0;
  diff = thisLength - endLength;
  for (i = 0; i < endLength; i++) {
    if (thisString[diff + i] != endString[i])
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EndString>:
  endbr64
  mov    $0x0,%edx
  test   %rdi,%rdi
  je     L47
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%r12d
  jl     L8
  sub    %eax,%r12d
  test   %eax,%eax
  jle    L52
  lea    -0x1(%rax),%esi
  mov    $0x0,%edx
  movslq %r12d,%r12
  lea    (%rbx,%r12,1),%rax
  jmp    L36
L5:
  mov    %rcx,%rdx
L36:
  movzbl 0x0(%rbp,%rdx,1),%ebx
  cmp    %bl,(%rax,%rdx,1)
  jne    L79
  lea    0x1(%rdx),%rcx
  cmp    %rsi,%rdx
  jne    L5
  mov    $0x1,%edx
  jmp    L8
L52:
  mov    $0x1,%edx
  jmp    L8
L79:
  mov    $0x0,%edx
L8:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    %edx,%eax
  ret
```

assistant: ```c
int EndString(char *thisString, char *endString) {
  int thisLength;
  int endLength;
  int diff, i;
  if (!thisString)
    return 0;
  thisLength = strlen(thisString);
  endLength = strlen(endString);
  if (thisLength < endLength)
    return 0;
  diff = thisLength - endLength;
  for (i = 0; i < endLength; i++) {
    if (thisString[diff + i] != endString[i])
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<EndString>:
  endbr64
  test   %rdi,%rdi
  je     L27
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L8
  sub    %eax,%r12d
  test   %eax,%eax
  jle    L23
  movslq %r12d,%r12
  movslq %eax,%rcx
  xor    %edx,%edx
  lea    (%rbx,%r12,1),%rdi
  jmp    L5
  nopl   (%rax)
L4:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L23
L5:
  movzbl 0x0(%rbp,%rdx,1),%eax
  cmp    %al,(%rdi,%rdx,1)
  je     L4
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int EndString(char *thisString, char *endString) {
  int thisLength;
  int endLength;
  int diff, i;
  if (!thisString)
    return 0;
  thisLength = strlen(thisString);
  endLength = strlen(endString);
  if (thisLength < endLength)
    return 0;
  diff = thisLength - endLength;
  for (i = 0; i < endLength; i++) {
    if (thisString[diff + i] != endString[i])
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<EndString>:
  endbr64
  test   %rdi,%rdi
  je     L44
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L13
  sub    %eax,%r12d
  test   %eax,%eax
  jle    L0
  movslq %r12d,%r12
  movslq %eax,%rcx
  xor    %edx,%edx
  lea    (%rbx,%r12,1),%rdi
  jmp    L8
  nopl   (%rax)
L39:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L0
L8:
  movzbl 0x0(%rbp,%rdx,1),%eax
  cmp    %al,(%rdi,%rdx,1)
  je     L39
L13:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int EndString(char *thisString, char *endString) {
  int thisLength;
  int endLength;
  int diff, i;
  if (!thisString)
    return 0;
  thisLength = strlen(thisString);
  endLength = strlen(endString);
  if (thisLength < endLength)
    return 0;
  diff = thisLength - endLength;
  for (i = 0; i < endLength; i++) {
    if (thisString[diff + i] != endString[i])
      return 0;
  }
  return 1;
}
```