ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dnorm_log>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <log@plt>
  test   %ebx,%ebx
  jle    L5
  movapd %xmm0,%xmm3
  mov    %rbp,%rax
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
  movsd  D3(%rip),%xmm4
L19:
  movsd  (%rax),%xmm1
  subsd  (%rsp),%xmm1
  divsd  0x8(%rsp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  %xmm4,%xmm2
  mulsd  %xmm2,%xmm1
  subsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L19
L28:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  pxor   %xmm0,%xmm0
  jmp    L28
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: f32[2]

tool: {"D3": [0.0,-1.75]}

assistant: ```c
double dnorm_log(double *x, int n, double location, double scale) {
  int i;
  double logDensity = 0, z, logScale;
  logScale = log(scale);
  for (i = 0; i < n; i++) {
    z = (x[i] - location) / scale;
    logDensity += -0.5 * z * z - logScale;
  }
  return logDensity;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dnorm_log>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  test   %ebp,%ebp
  jle    L17
  lea    -0x1(%rbp),%eax
  movsd  0x8(%rsp),%xmm5
  movapd %xmm0,%xmm4
  mov    %rbx,%rdi
  movsd  (%rsp),%xmm1
  movsd  D6(%rip),%xmm6
  lea    0x8(%rbx,%rax,8),%rax
  pxor   %xmm0,%xmm0
  nopl   (%rax)
L8:
  movsd  (%rdi),%xmm2
  add    $0x8,%rdi
  subsd  %xmm5,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm3
  mulsd  %xmm6,%xmm3
  mulsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %rdi,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  add    $0x18,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type: f32[2]

tool: {"D6": [0.0,-1.75]}

assistant: ```c
double dnorm_log(double *x, int n, double location, double scale) {
  int i;
  double logDensity = 0, z, logScale;
  logScale = log(scale);
  for (i = 0; i < n; i++) {
    z = (x[i] - location) / scale;
    logDensity += -0.5 * z * z - logScale;
  }
  return logDensity;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dnorm_log>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  test   %ebp,%ebp
  jle    L21
  cmp    $0x1,%ebp
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm5
  movapd %xmm0,%xmm4
  je     L45
  mov    %ebp,%edx
  movapd %xmm5,%xmm9
  movapd %xmm1,%xmm8
  mov    %rbx,%rax
  movapd %xmm0,%xmm7
  shr    %edx
  unpcklpd %xmm9,%xmm9
  unpcklpd %xmm8,%xmm8
  sub    $0x1,%edx
  movapd D19(%rip),%xmm6
  unpcklpd %xmm7,%xmm7
  pxor   %xmm3,%xmm3
  shl    $0x4,%rdx
  lea    0x10(%rbx,%rdx,1),%rdx
  xchg   %ax,%ax
L33:
  movupd (%rax),%xmm2
  add    $0x10,%rax
  subpd  %xmm9,%xmm2
  divpd  %xmm8,%xmm2
  movapd %xmm2,%xmm0
  mulpd  %xmm6,%xmm0
  mulpd  %xmm2,%xmm0
  subpd  %xmm7,%xmm0
  movapd %xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  addsd  %xmm3,%xmm2
  movapd %xmm0,%xmm3
  addsd  %xmm2,%xmm3
  cmp    %rax,%rdx
  jne    L33
  mov    %ebp,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ebp
  je     L36
L43:
  cltq
  movsd  (%rbx,%rax,8),%xmm0
  subsd  %xmm5,%xmm0
  divsd  %xmm1,%xmm0
  movsd  D19(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  subsd  %xmm4,%xmm0
  addsd  %xmm0,%xmm3
L36:
  add    $0x18,%rsp
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x18,%rsp
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  ret
L45:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  jmp    L43
```

tool_calls: name: parse_data
arguments: data_label: D19
datatype: f32[4]

tool: {"D19": [0.0,-1.75,0.0,-1.75]}

assistant: ```c
double dnorm_log(double *x, int n, double location, double scale) {
  int i;
  double logDensity = 0, z, logScale;
  logScale = log(scale);
  for (i = 0; i < n; i++) {
    z = (x[i] - location) / scale;
    logDensity += -0.5 * z * z - logScale;
  }
  return logDensity;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_magic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0xfa,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0xd3,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void write_magic(const void *addr) {
  *(unsigned char *)addr = (unsigned char)(0xFAU);
  *((unsigned char *)addr + 1) = (unsigned char)(0xD3U);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_magic>:
  endbr64
  movb   $0xfa,(%rdi)
  movb   $0xd3,0x1(%rdi)
  ret
```

assistant: ```c
void write_magic(const void *addr) {
  *(unsigned char *)addr = (unsigned char)(0xFAU);
  *((unsigned char *)addr + 1) = (unsigned char)(0xD3U);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<write_magic>:
  endbr64
  mov    $0xffffd3fa,%eax
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void write_magic(const void *addr) {
  *(unsigned char *)addr = (unsigned char)(0xFAU);
  *((unsigned char *)addr + 1) = (unsigned char)(0xD3U);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_magic>:
  endbr64
  mov    $0xffffd3fa,%eax
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void write_magic(const void *addr) {
  *(unsigned char *)addr = (unsigned char)(0xFAU);
  *((unsigned char *)addr + 1) = (unsigned char)(0xD3U);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix23Rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  cmpl   $0x10e,-0x14(%rbp)
  je     L92
  cmpl   $0x10e,-0x14(%rbp)
  jg     L25
  cmpl   $0xb4,-0x14(%rbp)
  je     L41
  cmpl   $0xb4,-0x14(%rbp)
  jg     L25
  cmpl   $0x0,-0x14(%rbp)
  je     L6
  cmpl   $0x5a,-0x14(%rbp)
  je     L15
  jmp    L25
L6:
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <matrix23Set@plt>
  add    $0x10,%rsp
  jmp    L25
L15:
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0xc(%rbp),%edx
  push   %rdx
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <matrix23Set@plt>
  add    $0x10,%rsp
  jmp    L25
L41:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x10(%rbp),%ecx
  push   %rcx
  mov    $0xffffffff,%r9d
  mov    $0x0,%r8d
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <matrix23Set@plt>
  add    $0x10,%rsp
  jmp    L25
L92:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  mov    %edx,%ecx
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <matrix23Set@plt>
  add    $0x10,%rsp
  nop
L25:
  nop
  leave
  ret
```

assistant: ```c
void matrix23Rotate(struct matrix23 *m, int width, int height, int angle) {
  switch (angle) {
  case 0:
    matrix23Set(m, 1, 0, 0, 0, 1, 0);
    break;
  case 90:
    matrix23Set(m, 0, 1, 0, -1, 0, width);
    break;
  case 180:
    matrix23Set(m, -1, 0, width, 0, -1, height);
    break;
  case 270:
    matrix23Set(m, 0, -1, height, 1, 0, 0);
    break;
  default:;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix23Rotate>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xb4,%ecx
  je     L30
  jg     L29
  test   %ecx,%ecx
  je     L0
  cmp    $0x5a,%ecx
  jne    L41
  sub    $0x8,%rsp
  push   %rsi
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <matrix23Set@plt>
  add    $0x10,%rsp
  jmp    L41
L29:
  cmp    $0x10e,%ecx
  jne    L41
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  mov    %edx,%ecx
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  call   <matrix23Set@plt>
  add    $0x10,%rsp
  jmp    L41
L0:
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  call   <matrix23Set@plt>
  add    $0x10,%rsp
L41:
  add    $0x8,%rsp
  ret
L30:
  sub    $0x8,%rsp
  push   %rdx
  mov    $0xffffffff,%r9d
  mov    $0x0,%r8d
  mov    %esi,%ecx
  mov    $0x0,%edx
  mov    $0xffffffff,%esi
  call   <matrix23Set@plt>
  add    $0x10,%rsp
  jmp    L41
```

assistant: ```c
void matrix23Rotate(struct matrix23 *m, int width, int height, int angle) {
  switch (angle) {
  case 0:
    matrix23Set(m, 1, 0, 0, 0, 1, 0);
    break;
  case 90:
    matrix23Set(m, 0, 1, 0, -1, 0, width);
    break;
  case 180:
    matrix23Set(m, -1, 0, width, 0, -1, height);
    break;
  case 270:
    matrix23Set(m, 0, -1, height, 1, 0, 0);
    break;
  default:;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matrix23Rotate>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xb4,%ecx
  je     L8
  jg     L41
  test   %ecx,%ecx
  je     L38
  cmp    $0x5a,%ecx
  jne    L49
  sub    $0x8,%rsp
  mov    $0xffffffff,%r8d
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  push   %rsi
  mov    $0x1,%edx
  xor    %esi,%esi
  call   <matrix23Set@plt>
  pop    %rdi
  pop    %r8
L49:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  cmp    $0x10e,%ecx
  jne    L49
  sub    $0x8,%rsp
  mov    %edx,%ecx
  xor    %r9d,%r9d
  mov    $0xffffffff,%edx
  push   $0x0
  mov    $0x1,%r8d
  xor    %esi,%esi
  call   <matrix23Set@plt>
  pop    %rax
  pop    %rdx
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  sub    $0x8,%rsp
  mov    %esi,%ecx
  mov    $0xffffffff,%r9d
  xor    %r8d,%r8d
  push   %rdx
  mov    $0xffffffff,%esi
  xor    %edx,%edx
  call   <matrix23Set@plt>
  pop    %rcx
  pop    %rsi
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  sub    $0x8,%rsp
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   $0x0
  xor    %edx,%edx
  mov    $0x1,%esi
  call   <matrix23Set@plt>
  pop    %r9
  pop    %r10
  add    $0x8,%rsp
  ret
```

assistant: ```c
void matrix23Rotate(struct matrix23 *m, int width, int height, int angle) {
  switch (angle) {
  case 0:
    matrix23Set(m, 1, 0, 0, 0, 1, 0);
    break;
  case 90:
    matrix23Set(m, 0, 1, 0, -1, 0, width);
    break;
  case 180:
    matrix23Set(m, -1, 0, width, 0, -1, height);
    break;
  case 270:
    matrix23Set(m, 0, -1, height, 1, 0, 0);
    break;
  default:;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<matrix23Rotate>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xb4,%ecx
  je     L42
  jg     L15
  test   %ecx,%ecx
  je     L46
  cmp    $0x5a,%ecx
  jne    L5
  sub    $0x8,%rsp
  mov    $0xffffffff,%r8d
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  push   %rsi
  mov    $0x1,%edx
  xor    %esi,%esi
  call   <matrix23Set@plt>
  pop    %rdi
  pop    %r8
L5:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  cmp    $0x10e,%ecx
  jne    L5
  sub    $0x8,%rsp
  mov    %edx,%ecx
  xor    %r9d,%r9d
  mov    $0xffffffff,%edx
  push   $0x0
  mov    $0x1,%r8d
  xor    %esi,%esi
  call   <matrix23Set@plt>
  pop    %rax
  pop    %rdx
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L42:
  sub    $0x8,%rsp
  mov    %esi,%ecx
  mov    $0xffffffff,%r9d
  xor    %r8d,%r8d
  push   %rdx
  mov    $0xffffffff,%esi
  xor    %edx,%edx
  call   <matrix23Set@plt>
  pop    %rcx
  pop    %rsi
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  sub    $0x8,%rsp
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   $0x0
  xor    %edx,%edx
  mov    $0x1,%esi
  call   <matrix23Set@plt>
  pop    %r9
  pop    %r10
  add    $0x8,%rsp
  ret
```

assistant: ```c
void matrix23Rotate(struct matrix23 *m, int width, int height, int angle) {
  switch (angle) {
  case 0:
    matrix23Set(m, 1, 0, 0, 0, 1, 0);
    break;
  case 90:
    matrix23Set(m, 0, 1, 0, -1, 0, width);
    break;
  case 180:
    matrix23Set(m, -1, 0, width, 0, -1, height);
    break;
  case 270:
    matrix23Set(m, 0, -1, height, 1, 0, 0);
    break;
  default:;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L36
L28:
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L25
  mov    $0x0,%eax
  jmp    L36
L25:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int is_file(const char *path) {
  if (!path) {
    return 0;
  }
  struct stat st;
  if (stat(path, &st) != 0) {
    return 0;
  }
  return S_ISREG(st.st_mode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L24
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L23
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  ret
L23:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  jmp    L24
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_file(const char *path) {
  if (!path) {
    return 0;
  }
  struct stat st;
  if (stat(path, &st) != 0) {
    return 0;
  }
  return S_ISREG(st.st_mode);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L12
L0:
  xor    %eax,%eax
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  jmp    L31
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_file(const char *path) {
  if (!path) {
    return 0;
  }
  struct stat st;
  if (stat(path, &st) != 0) {
    return 0;
  }
  return S_ISREG(st.st_mode);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L14
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L17
L14:
  xor    %eax,%eax
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  jmp    L36
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_file(const char *path) {
  if (!path) {
    return 0;
  }
  struct stat st;
  if (stat(path, &st) != 0) {
    return 0;
  }
  return S_ISREG(st.st_mode);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<group_getname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  lea    D0(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: Group

assistant: ```c
const char *group_getname(void *unused) {
  (void)unused;
  return "Group";
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<group_getname>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string

tool: D8: Group

assistant: ```c
const char *group_getname(void *unused) {
  (void)unused;
  return "Group";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<group_getname>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: Group

assistant: ```c
const char *group_getname(void *unused) {
  (void)unused;
  return "Group";
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<group_getname>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type: string

tool: D2: Group

assistant: ```c
const char *group_getname(void *unused) {
  (void)unused;
  return "Group";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x40,-0x30(%rbp)
  movl   $0x22,-0x2c(%rbp)
  movl   $0x19,-0x28(%rbp)
  movl   $0xc,-0x24(%rbp)
  movl   $0x16,-0x20(%rbp)
  movl   $0xb,-0x1c(%rbp)
  movl   $0x5a,-0x18(%rbp)
  movl   $0x7,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubbleSort@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: Sorted array: 


assistant: ```c
int main() {
  int arr[] = {64, 34, 25, 12, 22, 11, 90};
  int n = sizeof(arr) / sizeof(arr[0]);
  bubbleSort(arr, n);
  printf("Sorted array: \n");
  printArray(arr, n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x40,(%rsp)
  movl   $0x22,0x4(%rsp)
  movl   $0x19,0x8(%rsp)
  movl   $0xc,0xc(%rsp)
  movl   $0x16,0x10(%rsp)
  movl   $0xb,0x14(%rsp)
  movl   $0x5a,0x18(%rsp)
  mov    %rsp,%rbx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <bubbleSort@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: Sorted array: 


assistant: ```c
int main() {
  int arr[] = {64, 34, 25, 12, 22, 11, 90};
  int n = sizeof(arr) / sizeof(arr[0]);
  bubbleSort(arr, n);
  printf("Sorted array: \n");
  printArray(arr, n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x7,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x2200000040,%rax
  mov    %rsp,%rbp
  movl   $0x5a,0x18(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0xc00000019,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xb00000016,%rax
  mov    %rax,0x10(%rsp)
  call   <bubbleSort@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: Sorted array: 


assistant: ```c
int main() {
  int arr[] = {64, 34, 25, 12, 22, 11, 90};
  int n = sizeof(arr) / sizeof(arr[0]);
  bubbleSort(arr, n);
  printf("Sorted array: \n");
  printArray(arr, n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x7,%esi
  sub    $0x30,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D1(%rip),%rax
  movl   $0x5a,0x18(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <bubbleSort@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: byte[16]
name: parse_data
arguments: data_label: D1
datatype: byte[8]
name: parse_data
arguments: data_label: D18
datatype: string

tool: {"D0": [0x40,0x00,0x00,0x00,0x22,0x00,0x00,0x00,0x19,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: {"D1": [0x16,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: D18: Sorted array: 


assistant: ```c
int main() {
  int arr[] = {64, 34, 25, 12, 22, 11, 90};
  int n = sizeof(arr) / sizeof(arr[0]);
  bubbleSort(arr, n);
  printf("Sorted array: \n");
  printArray(arr, n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memfile_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <fputc@plt>
  test   %rax,%rax
  je     L19
  mov    $0xffffffff,%eax
  jmp    L12
L19:
  mov    $0x0,%eax
L12:
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  cmpl   $0x0,-0x4(%rbp)
  jne    L13
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L25
L13:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
L25:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int memfile_close(FILE *file, char **buffer, size_t *size) {
  int rc;
  rc = fputc(0, file) ? -1 : 0;
  fclose(file);
  if (rc == 0)
    (*size)--;
  else {
    free(*buffer);
    *buffer = NULL;
    *size = 0;
  }
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memfile_close>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rdi,%rsi
  mov    $0x0,%edi
  call   <fputc@plt>
  mov    %rax,%rbx
  neg    %rax
  sbb    %r14d,%r14d
  mov    %rbp,%rdi
  call   <fclose@plt>
  test   %rbx,%rbx
  jne    L4
  mov    (%r12),%rax
  sub    $0x1,%rax
L10:
  mov    %rax,(%r12)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    0x0(%r13),%rdi
  call   <free@plt>
  movq   $0x0,0x0(%r13)
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
int memfile_close(FILE *file, char **buffer, size_t *size) {
  int rc;
  rc = fputc(0, file) ? -1 : 0;
  fclose(file);
  if (rc == 0)
    (*size)--;
  else {
    free(*buffer);
    *buffer = NULL;
    *size = 0;
  }
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memfile_close>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rdx,%rbx
  call   <fputc@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L2
  call   <fclose@plt>
  mov    (%rbx),%rax
  xor    %r8d,%r8d
  sub    $0x1,%rax
  mov    %rax,(%rbx)
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L2:
  call   <fclose@plt>
  mov    (%r12),%rdi
  call   <free@plt>
  xor    %eax,%eax
  mov    $0xffffffff,%r8d
  movq   $0x0,(%r12)
  mov    %rax,(%rbx)
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int memfile_close(FILE *file, char **buffer, size_t *size) {
  int rc;
  rc = fputc(0, file) ? -1 : 0;
  fclose(file);
  if (rc == 0)
    (*size)--;
  else {
    free(*buffer);
    *buffer = NULL;
    *size = 0;
  }
  return rc;
}
```