user: 这段汇编代码用C语言表示是什么样的：

```asm
<DumpData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  cmp    %rax,-0x30(%rbp)
  jae    L0
  mov    -0x48(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x30(%rbp)
L0:
  cmpq   $0x0,-0x30(%rbp)
  jne    L11
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L28
L11:
  addq   $0x1,-0x30(%rbp)
L28:
  mov    -0x50(%rbp),%rax
  lea    D27(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x28(%rbp)
  lea    -0x11(%rbp),%rax
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x4(%rax),%rdx
  mov    -0x30(%rbp),%rcx
  lea    -0x11(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x11(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D42(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  lea    -0x38(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ReadFile@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L4
L50:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x28(%rbp),%rax
  lea    D47(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x34(%rbp)
  je     L67
  mov    -0x28(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
L67:
  addl   $0x1,-0x34(%rbp)
L4:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L50
  mov    -0x28(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x5,%edx
  mov    $0x1,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D42
type_infered: string
name: unpack_data
arguments: tag: D47
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D30
type_infered: string

tool: D27: wb

tool: D42: char far %s[] ={


tool: D47: %d

tool: D3: ,


tool: D30:  };


assistant: ```c
void DumpData(const char *infn, const char *outfn, int skip) {
  FILE *f;
  int i;
  int insize;
  char symname[9];
  const char *in;
  const char *infn_stripped = strrchr(infn, '/');
  if (strrchr(infn, '\\') > infn_stripped)
    infn_stripped = strrchr(infn, '\\');
  if (infn_stripped == NULL)
    infn_stripped = infn;
  else
    ++infn_stripped;
  f = fopen(outfn, "wb");
  memset(symname, 0, 9);
  memcpy(symname, infn_stripped, strlen(infn_stripped) - 4);
  fprintf(f, "char far %s[] ={\r\n", symname);
  in = ReadFile(infn, &insize);
  for (i = skip; i < insize; ++i) {
    fprintf(f, "%d", (unsigned char)in[i]);
    if (i != insize - 1)
      fprintf(f, ",\r\n");
  }
  fprintf(f, " };\r\n");
  fclose(f);
  free((char *)in);
}
```