ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<mg_base64_update>:
  endbr64
  push   %r14
  mov    $0xaaaaaaab,%ecx
  push   %r13
  movslq %edx,%r13
  mov    %r13d,%edx
  push   %r12
  and    $0x3,%edx
  push   %rbp
  mov    %r13,%rbp
  add    %rsi,%r13
  mov    %edx,%eax
  lea    0x1(%rbp),%r14d
  push   %rbx
  mov    %edi,%ebx
  imul   %rcx,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%ecx
  movslq %r14d,%rax
  lea    (%rsi,%rax,1),%r12
  mov    %edx,%eax
  sub    %ecx,%eax
  je     L2
  movzbl 0x0(%r13),%edx
  cmp    $0x1,%eax
  je     L16
  shr    $0x6,%dil
  and    $0x3f,%ebx
  lea    0x2(%rbp),%r14d
  or     %edx,%edi
  movzbl %dil,%edi
  call   <mg_b64idx@plt>
  mov    %ebx,%edi
  mov    %al,0x0(%r13)
  call   <mg_b64idx@plt>
  mov    %eax,%ebx
  mov    %r14d,%eax
  mov    %bl,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L16:
  shr    $0x4,%dil
  shl    $0x2,%ebx
  or     %edx,%edi
  and    $0x3c,%ebx
  movzbl %dil,%edi
  call   <mg_b64idx@plt>
  mov    %al,0x0(%r13)
  mov    %r14d,%eax
  mov    %bl,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L2:
  shr    $0x2,%dil
  shl    $0x4,%ebx
  movzbl %dil,%edi
  and    $0x30,%ebx
  call   <mg_b64idx@plt>
  mov    %al,0x0(%r13)
  mov    %r14d,%eax
  mov    %bl,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mg_base64_update(unsigned char ch, char *to, int n) {
  unsigned char rem = (n & 3) % 3;
  if (rem == 0) {
    to[n] = mg_b64idx(ch >> 2);
    to[++n] = (ch & 3) << 4;
  } else if (rem == 1) {
    to[n] = mg_b64idx(to[n] | (ch >> 4));
    to[++n] = (ch & 15) << 2;
  } else {
    to[n] = mg_b64idx(to[n] | (ch >> 6));
    to[++n] = mg_b64idx(ch & 63);
    n++;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mg_base64_update>:
  endbr64
  push   %r14
  mov    $0xaaaaaaab,%ecx
  push   %r13
  movslq %edx,%r13
  mov    %r13d,%edx
  push   %r12
  and    $0x3,%edx
  push   %rbp
  mov    %r13,%rbp
  add    %rsi,%r13
  mov    %edx,%eax
  lea    0x1(%rbp),%r14d
  push   %rbx
  mov    %edi,%ebx
  imul   %rcx,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%ecx
  movslq %r14d,%rax
  lea    (%rsi,%rax,1),%r12
  mov    %edx,%eax
  sub    %ecx,%eax
  je     L1
  movzbl 0x0(%r13),%edx
  cmp    $0x1,%eax
  je     L11
  shr    $0x6,%dil
  and    $0x3f,%ebx
  lea    0x2(%rbp),%r14d
  or     %edx,%edi
  movzbl %dil,%edi
  call   <mg_b64idx@plt>
  mov    %ebx,%edi
  mov    %al,0x0(%r13)
  call   <mg_b64idx@plt>
  mov    %eax,%ebx
  mov    %r14d,%eax
  mov    %bl,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L11:
  shr    $0x4,%dil
  shl    $0x2,%ebx
  or     %edx,%edi
  and    $0x3c,%ebx
  movzbl %dil,%edi
  call   <mg_b64idx@plt>
  mov    %al,0x0(%r13)
  mov    %r14d,%eax
  mov    %bl,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L1:
  shr    $0x2,%dil
  shl    $0x4,%ebx
  movzbl %dil,%edi
  and    $0x30,%ebx
  call   <mg_b64idx@plt>
  mov    %al,0x0(%r13)
  mov    %r14d,%eax
  mov    %bl,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mg_base64_update(unsigned char ch, char *to, int n) {
  unsigned char rem = (n & 3) % 3;
  if (rem == 0) {
    to[n] = mg_b64idx(ch >> 2);
    to[++n] = (ch & 3) << 4;
  } else if (rem == 1) {
    to[n] = mg_b64idx(to[n] | (ch >> 4));
    to[++n] = (ch & 15) << 2;
  } else {
    to[n] = mg_b64idx(to[n] | (ch >> 6));
    to[++n] = mg_b64idx(ch & 63);
    n++;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<evf_uinput_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void evf_uinput_destroy(int fd) {
  ioctl(fd, UI_DEV_DESTROY);
  close(fd);
}
```
user: What is the c source code of the assembly code below:

```asm
<evf_uinput_destroy>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %ebx,%edi
  call   <close@plt>
  pop    %rbx
  ret
```

assistant: ```c
void evf_uinput_destroy(int fd) {
  ioctl(fd, UI_DEV_DESTROY);
  close(fd);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<evf_uinput_destroy>:
  endbr64
  mov    D3(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <close@plt>
```

assistant: ```c
void evf_uinput_destroy(int fd) {
  ioctl(fd, UI_DEV_DESTROY);
  close(fd);
}
```
user: Translate the below assembly code into C programming language:

```asm
<evf_uinput_destroy>:
  endbr64
  mov    D3(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <close@plt>
```

assistant: ```c
void evf_uinput_destroy(int fd) {
  ioctl(fd, UI_DEV_DESTROY);
  close(fd);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_dele>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %edi,-0x814(%rbp)
  mov    %rsi,-0x820(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x820(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L49
  lea    -0x810(%rbp),%rdx
  mov    -0x820(%rbp),%rcx
  mov    -0x814(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <checkpath@plt>
  test   %rax,%rax
  je     L37
L49:
  mov    $0x1,%eax
  jmp    L38
L37:
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movzbl -0x810(%rbp,%rax,1),%eax
  cmp    $0x2f,%al
  jne    L8
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,-0x810(%rbp,%rax,1)
L8:
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
L38:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int do_dele(int nr, char *param) {
  char path[2048];
  if (strlen(param) == 0 || checkpath(nr, param, path))
    return 1;
  if (path[strlen(path) - 1] == '/')
    path[strlen(path) - 1] = 0;
  return unlink(path);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_dele>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L7
L46:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rsp,%rdx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <checkpath@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L46
  mov    %rsp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmpb   $0x2f,(%rsp,%rax,1)
  je     L41
L29:
  mov    %rsp,%rdi
  call   <unlink@plt>
  jmp    L46
L41:
  mov    %rsp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  jmp    L29
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_dele(int nr, char *param) {
  char path[2048];
  if (strlen(param) == 0 || checkpath(nr, param, path))
    return 1;
  if (path[strlen(path) - 1] == '/')
    path[strlen(path) - 1] = 0;
  return unlink(path);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_dele>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jne    L38
L26:
  mov    $0x1,%eax
L14:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x810,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %rsp,%r13
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %r13,%rdx
  call   <checkpath@plt>
  test   %rax,%rax
  jne    L26
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmpb   $0x2f,(%rsp,%rax,1)
  je     L8
L34:
  mov    %r13,%rdi
  call   <unlink@plt>
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  jmp    L34
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_dele(int nr, char *param) {
  char path[2048];
  if (strlen(param) == 0 || checkpath(nr, param, path))
    return 1;
  if (path[strlen(path) - 1] == '/')
    path[strlen(path) - 1] = 0;
  return unlink(path);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<do_dele>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jne    L52
L23:
  mov    $0x1,%eax
L59:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x810,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %rsp,%r13
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %r13,%rdx
  call   <checkpath@plt>
  test   %rax,%rax
  jne    L23
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmpb   $0x2f,(%rsp,%rax,1)
  je     L25
L7:
  mov    %r13,%rdi
  call   <unlink@plt>
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  jmp    L7
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_dele(int nr, char *param) {
  char path[2048];
  if (strlen(param) == 0 || checkpath(nr, param, path))
    return 1;
  if (path[strlen(path) - 1] == '/')
    path[strlen(path) - 1] = 0;
  return unlink(path);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<begin_with_timestamp_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D10(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_new@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ol_lrc_get_item@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_item_get_time@plt>
  cmp    $0x2710,%eax
  je     L8
  lea    D8(%rip),%rax
  mov    %rax,%rdx
  mov    $0x6b,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_free@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D8
type: string
name: retrieve_data
arguments: data_label: D23
type: string

tool: D10: lrc_tail.lrc

tool: D8: ol_lrc_item_get_time (item) == 10000

tool: D23: ERROR[%d]: EXPECT %s failed


assistant: ```c
void begin_with_timestamp_test() {
  const char *DATAFILE = "lrc_tail.lrc";
  struct OlLrc *lrc = ol_lrc_new(DATAFILE);
  const struct OlLrcItem *item = ol_lrc_get_item(lrc, 0);
  if (!(ol_lrc_item_get_time(item) == 10000)) {
    printf("ERROR[%d]: EXPECT %s failed\n", 107, "ol_lrc_item_get_time (item) == 10000");
  };
  ol_lrc_free(lrc);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<begin_with_timestamp_test>:
  endbr64
  push   %rbx
  lea    D25(%rip),%rdi
  call   <ol_lrc_new@plt>
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ol_lrc_get_item@plt>
  mov    %rax,%rdi
  call   <ol_lrc_item_get_time@plt>
  cmp    $0x2710,%eax
  jne    L17
L3:
  mov    %rbx,%rdi
  call   <ol_lrc_free@plt>
  pop    %rbx
  ret
L17:
  lea    D6(%rip),%rdx
  mov    $0x6b,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: tag: D25
datatype: string
name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D22
datatype: string

tool: D25: lrc_tail.lrc

tool: D6: ol_lrc_item_get_time (item) == 10000

tool: D22: ERROR[%d]: EXPECT %s failed


assistant: ```c
void begin_with_timestamp_test() {
  const char *DATAFILE = "lrc_tail.lrc";
  struct OlLrc *lrc = ol_lrc_new(DATAFILE);
  const struct OlLrcItem *item = ol_lrc_get_item(lrc, 0);
  if (!(ol_lrc_item_get_time(item) == 10000)) {
    printf("ERROR[%d]: EXPECT %s failed\n", 107, "ol_lrc_item_get_time (item) == 10000");
  };
  ol_lrc_free(lrc);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<begin_with_timestamp_test>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  call   <ol_lrc_new@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <ol_lrc_get_item@plt>
  mov    %rax,%rdi
  call   <ol_lrc_item_get_time@plt>
  cmp    $0x2710,%eax
  je     L1
  lea    D16(%rip),%rdx
  mov    $0x6b,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
L1:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10c0 <ol_lrc_free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string

tool: D2: lrc_tail.lrc

tool: D16: ol_lrc_item_get_time (item) == 10000

tool: D14: ERROR[%d]: EXPECT %s failed


assistant: ```c
void begin_with_timestamp_test() {
  const char *DATAFILE = "lrc_tail.lrc";
  struct OlLrc *lrc = ol_lrc_new(DATAFILE);
  const struct OlLrcItem *item = ol_lrc_get_item(lrc, 0);
  if (!(ol_lrc_item_get_time(item) == 10000)) {
    printf("ERROR[%d]: EXPECT %s failed\n", 107, "ol_lrc_item_get_time (item) == 10000");
  };
  ol_lrc_free(lrc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<begin_with_timestamp_test>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  call   <ol_lrc_new@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <ol_lrc_get_item@plt>
  mov    %rax,%rdi
  call   <ol_lrc_item_get_time@plt>
  cmp    $0x2710,%eax
  je     L9
  lea    D10(%rip),%rdx
  mov    $0x6b,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
L9:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    10c0 <ol_lrc_free@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string
name: retrieve_data
arguments: data_tag: D18
type_guessed: string

tool: D12: lrc_tail.lrc

tool: D10: ol_lrc_item_get_time (item) == 10000

tool: D18: ERROR[%d]: EXPECT %s failed


assistant: ```c
void begin_with_timestamp_test() {
  const char *DATAFILE = "lrc_tail.lrc";
  struct OlLrc *lrc = ol_lrc_new(DATAFILE);
  const struct OlLrcItem *item = ol_lrc_get_item(lrc, 0);
  if (!(ol_lrc_item_get_time(item) == 10000)) {
    printf("ERROR[%d]: EXPECT %s failed\n", 107, "ol_lrc_item_get_time (item) == 10000");
  };
  ol_lrc_free(lrc);
}
```
user: What is the c source code of the assembly code below?

```asm
<format>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x9,-0x84(%rbp)
  jg     L29
  mov    -0x84(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  jmp    L2
L29:
  mov    -0x84(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string
name: parse_data
arguments: tag: D9
data_type: string

tool: D4: 0%d

tool: D9: %d

assistant: ```c
char *format(int number) {
  char *retorno, ret[100];
  int i;
  if (number < 10) {
    sprintf(ret, "0%d", number);
    retorno = ret;
    return retorno;
  } else {
    sprintf(ret, "%d", number);
    retorno = ret;
    return retorno;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<format>:
  endbr64
  sub    $0x78,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%edi
  jg     L20
  mov    %rsp,%rdi
  lea    D16(%rip),%rsi
  call   <sprintf@plt>
L18:
  mov    %rsp,%rax
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x78,%rsp
  ret
L20:
  mov    %rsp,%rdi
  lea    D1(%rip),%rsi
  call   <sprintf@plt>
  jmp    L18
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D1
data_type: string

tool: D16: 0%d

tool: D1: %d

assistant: ```c
char *format(int number) {
  char *retorno, ret[100];
  int i;
  if (number < 10) {
    sprintf(ret, "0%d", number);
    retorno = ret;
    return retorno;
  } else {
    sprintf(ret, "%d", number);
    retorno = ret;
    return retorno;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<format>:
  endbr64
  sub    $0x78,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%edi
  mov    %rsp,%rdi
  jg     L1
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
L28:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
  nopl   (%rax)
L1:
  lea    D1(%rip),%rsi
  call   <sprintf@plt>
  jmp    L28
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: string

tool: D4: 0%d

tool: D1: %d

assistant: ```c
char *format(int number) {
  char *retorno, ret[100];
  int i;
  if (number < 10) {
    sprintf(ret, "0%d", number);
    retorno = ret;
    return retorno;
  } else {
    sprintf(ret, "%d", number);
    retorno = ret;
    return retorno;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<format>:
  endbr64
  sub    $0x78,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%edi
  mov    %rsp,%rdi
  jg     L2
  lea    D9(%rip),%rsi
  call   <sprintf@plt>
L18:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
  nopl   (%rax)
L2:
  lea    D10(%rip),%rsi
  call   <sprintf@plt>
  jmp    L18
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string

tool: D9: 0%d

tool: D10: %d

assistant: ```c
char *format(int number) {
  char *retorno, ret[100];
  int i;
  if (number < 10) {
    sprintf(ret, "0%d", number);
    retorno = ret;
    return retorno;
  } else {
    sprintf(ret, "%d", number);
    retorno = ret;
    return retorno;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nc_nvr_htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L15
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x8(%rbp)
L15:
  cmpl   $0x2f,-0x8(%rbp)
  jle    L49
  cmpl   $0x39,-0x8(%rbp)
  jg     L49
  mov    -0x8(%rbp),%eax
  sub    $0x30,%eax
  shl    $0x4,%eax
  jmp    L64
L49:
  mov    -0x8(%rbp),%eax
  sub    $0x57,%eax
  shl    $0x4,%eax
L64:
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L74
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x8(%rbp)
L74:
  cmpl   $0x2f,-0x8(%rbp)
  jle    L46
  cmpl   $0x39,-0x8(%rbp)
  jg     L46
  mov    -0x8(%rbp),%eax
  sub    $0x30,%eax
  jmp    L36
L46:
  mov    -0x8(%rbp),%eax
  sub    $0x57,%eax
L36:
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int nc_nvr_htoi(char *s) {
  int value;
  int c;
  c = ((unsigned char *)s)[0];
  if (isupper(c))
    c = tolower(c);
  value = (c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10) * 16;
  c = ((unsigned char *)s)[1];
  if (isupper(c))
    c = tolower(c);
  value += c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10;
  return (value);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nc_nvr_htoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movzbl (%rdi),%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L15
  mov    %ebp,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
L15:
  lea    -0x30(%rbp),%eax
  cmp    $0x9,%eax
  ja     L36
  mov    %eax,%ebp
  shl    $0x4,%ebp
L4:
  movzbl 0x1(%r12),%ebx
  mov    %ebx,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L35
  mov    %ebx,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
L35:
  lea    -0x30(%rbx),%edx
  sub    $0x57,%ebx
  cmp    $0x9,%edx
  cmovbe %edx,%ebx
  lea    0x0(%rbp,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  sub    $0x57,%ebp
  shl    $0x4,%ebp
  jmp    L4
```

assistant: ```c
int nc_nvr_htoi(char *s) {
  int value;
  int c;
  c = ((unsigned char *)s)[0];
  if (isupper(c))
    c = tolower(c);
  value = (c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10) * 16;
  c = ((unsigned char *)s)[1];
  if (isupper(c))
    c = tolower(c);
  value += c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10;
  return (value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nc_nvr_htoi>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L2
  mov    %ebp,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
L2:
  lea    -0x30(%rbp),%eax
  sub    $0x57,%ebp
  mov    %eax,%edx
  shl    $0x4,%ebp
  shl    $0x4,%edx
  cmp    $0x9,%eax
  mov    %edx,%ebx
  cmova  %ebp,%ebx
  movzbl 0x1(%r12),%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L10
  mov    %ebp,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
L10:
  lea    -0x30(%rbp),%eax
  sub    $0x57,%ebp
  cmp    $0x9,%eax
  cmovbe %eax,%ebp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int nc_nvr_htoi(char *s) {
  int value;
  int c;
  c = ((unsigned char *)s)[0];
  if (isupper(c))
    c = tolower(c);
  value = (c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10) * 16;
  c = ((unsigned char *)s)[1];
  if (isupper(c))
    c = tolower(c);
  value += c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10;
  return (value);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nc_nvr_htoi>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L4
  mov    %ebp,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
L4:
  lea    -0x30(%rbp),%eax
  sub    $0x57,%ebp
  mov    %eax,%edx
  shl    $0x4,%ebp
  shl    $0x4,%edx
  cmp    $0x9,%eax
  mov    %edx,%ebx
  cmova  %ebp,%ebx
  movzbl 0x1(%r12),%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L12
  mov    %ebp,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
L12:
  lea    -0x30(%rbp),%eax
  sub    $0x57,%ebp
  cmp    $0x9,%eax
  cmovbe %eax,%ebp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int nc_nvr_htoi(char *s) {
  int value;
  int c;
  c = ((unsigned char *)s)[0];
  if (isupper(c))
    c = tolower(c);
  value = (c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10) * 16;
  c = ((unsigned char *)s)[1];
  if (isupper(c))
    c = tolower(c);
  value += c >= '0' && c <= '9' ? c - '0' : c - 'a' + 10;
  return (value);
}
```