ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<memtest>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%eax
  call   <io_load_eflags@plt>
  or     $0x40000,%eax
  mov    %eax,%edi
  call   <io_store_eflags@plt>
  mov    $0x0,%eax
  call   <io_load_eflags@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  and    $0xfffbffff,%edi
  call   <io_store_eflags@plt>
  test   $0x40000,%ebx
  jne    L6
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <memtest_sub@plt>
  mov    %eax,%ebx
L10:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    $0x0,%eax
  call   <load_cr0@plt>
  and    $0x9fffffff,%eax
  mov    %eax,%edi
  call   <store_cr0@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <memtest_sub@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <load_cr0@plt>
  and    $0x9fffffff,%eax
  mov    %eax,%edi
  call   <store_cr0@plt>
  jmp    L10
```

assistant: ```c
unsigned int memtest(unsigned int start, unsigned int end) {
  char flg468 = 0;
  unsigned int eflg, cr0, i;
  eflg = io_load_eflags();
  eflg |= 0x00040000;
  io_store_eflags(eflg);
  eflg = io_load_eflags();
  if ((eflg & 0x00040000) != 0) {
    flg468 = 1;
  }
  eflg &= ~0x00040000;
  io_store_eflags(eflg);
  if (flg468 != 0) {
    cr0 = load_cr0();
    cr0 &= ~0x60000000;
    store_cr0(cr0);
  }
  i = memtest_sub(start, end);
  if (flg468 != 0) {
    cr0 = load_cr0();
    cr0 &= ~0x60000000;
    store_cr0(cr0);
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<memtest>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <io_load_eflags@plt>
  or     $0x40000,%eax
  mov    %eax,%edi
  call   <io_store_eflags@plt>
  xor    %eax,%eax
  call   <io_load_eflags@plt>
  mov    %eax,%edi
  and    $0xfffbffff,%edi
  test   $0x40000,%eax
  jne    L1
  call   <io_store_eflags@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <memtest_sub@plt>
  nop
L1:
  call   <io_store_eflags@plt>
  xor    %eax,%eax
  call   <load_cr0@plt>
  and    $0x9fffffff,%eax
  mov    %eax,%edi
  call   <store_cr0@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <memtest_sub@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <load_cr0@plt>
  and    $0x9fffffff,%eax
  mov    %eax,%edi
  call   <store_cr0@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int memtest(unsigned int start, unsigned int end) {
  char flg468 = 0;
  unsigned int eflg, cr0, i;
  eflg = io_load_eflags();
  eflg |= 0x00040000;
  io_store_eflags(eflg);
  eflg = io_load_eflags();
  if ((eflg & 0x00040000) != 0) {
    flg468 = 1;
  }
  eflg &= ~0x00040000;
  io_store_eflags(eflg);
  if (flg468 != 0) {
    cr0 = load_cr0();
    cr0 &= ~0x60000000;
    store_cr0(cr0);
  }
  i = memtest_sub(start, end);
  if (flg468 != 0) {
    cr0 = load_cr0();
    cr0 &= ~0x60000000;
    store_cr0(cr0);
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memtest>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <io_load_eflags@plt>
  or     $0x40000,%eax
  mov    %eax,%edi
  call   <io_store_eflags@plt>
  xor    %eax,%eax
  call   <io_load_eflags@plt>
  mov    %eax,%edi
  and    $0xfffbffff,%edi
  test   $0x40000,%eax
  jne    L6
  call   <io_store_eflags@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <memtest_sub@plt>
  nop
L6:
  call   <io_store_eflags@plt>
  xor    %eax,%eax
  call   <load_cr0@plt>
  and    $0x9fffffff,%eax
  mov    %eax,%edi
  call   <store_cr0@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <memtest_sub@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <load_cr0@plt>
  and    $0x9fffffff,%eax
  mov    %eax,%edi
  call   <store_cr0@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int memtest(unsigned int start, unsigned int end) {
  char flg468 = 0;
  unsigned int eflg, cr0, i;
  eflg = io_load_eflags();
  eflg |= 0x00040000;
  io_store_eflags(eflg);
  eflg = io_load_eflags();
  if ((eflg & 0x00040000) != 0) {
    flg468 = 1;
  }
  eflg &= ~0x00040000;
  io_store_eflags(eflg);
  if (flg468 != 0) {
    cr0 = load_cr0();
    cr0 &= ~0x60000000;
    store_cr0(cr0);
  }
  i = memtest_sub(start, end);
  if (flg468 != 0) {
    cr0 = load_cr0();
    cr0 &= ~0x60000000;
    store_cr0(cr0);
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
L2:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set(char **var, char *val) {
  if (val)
    *var = val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<set>:
  endbr64
  test   %rsi,%rsi
  je     L8
  mov    %rsi,(%rdi)
L8:
  ret
```

assistant: ```c
void set(char **var, char *val) {
  if (val)
    *var = val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<set>:
  endbr64
  test   %rsi,%rsi
  je     L6
  mov    %rsi,(%rdi)
L6:
  ret
```

assistant: ```c
void set(char **var, char *val) {
  if (val)
    *var = val;
}
```
user: What is the c source code of the assembly code below:

```asm
<set>:
  endbr64
  test   %rsi,%rsi
  je     L2
  mov    %rsi,(%rdi)
L2:
  ret
```

assistant: ```c
void set(char **var, char *val) {
  if (val)
    *var = val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <execv@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string
name: retrieve_data
arguments: tag: D7
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string

tool: D1: @ntfs-3g

tool: D7: /usr/bin/ntfs-3g

tool: D13: ntfs-3g-wrapper

assistant: ```c
int main(int argc, char *argv[]) {
  argv[0] = "@ntfs-3g";
  execv("/usr/bin/ntfs-3g", argv);
  perror("ntfs-3g-wrapper");
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rax
  mov    %rax,(%rsi)
  lea    D8(%rip),%rdi
  call   <execv@plt>
  lea    D25(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D20
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: string

tool: D20: @ntfs-3g

tool: D8: /usr/bin/ntfs-3g

tool: D25: ntfs-3g-wrapper

assistant: ```c
int main(int argc, char *argv[]) {
  argv[0] = "@ntfs-3g";
  execv("/usr/bin/ntfs-3g", argv);
  perror("ntfs-3g-wrapper");
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  lea    D5(%rip),%rax
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  mov    %rax,(%rsi)
  call   <execv@plt>
  lea    D23(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D9
data_type: string
name: unpack_data
arguments: data_tag: D23
data_type: string

tool: D5: @ntfs-3g

tool: D9: /usr/bin/ntfs-3g

tool: D23: ntfs-3g-wrapper

assistant: ```c
int main(int argc, char *argv[]) {
  argv[0] = "@ntfs-3g";
  execv("/usr/bin/ntfs-3g", argv);
  perror("ntfs-3g-wrapper");
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  lea    D8(%rip),%rax
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  mov    %rax,(%rsi)
  call   <execv@plt>
  lea    D10(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string

tool: D8: @ntfs-3g

tool: D26: /usr/bin/ntfs-3g

tool: D10: ntfs-3g-wrapper

assistant: ```c
int main(int argc, char *argv[]) {
  argv[0] = "@ntfs-3g";
  execv("/usr/bin/ntfs-3g", argv);
  perror("ntfs-3g-wrapper");
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <my_fputc@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <my_fgetc@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D11
datatype: string

tool: D15: 02.txt

tool: D28: 


tool: D11: pause

assistant: ```c
int main(void) {
  my_fputc("02.txt");
  my_fgetc("02.txt");
  printf("\n");
  system("pause");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <my_fputc@plt>
  mov    %rbx,%rdi
  call   <my_fgetc@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D0
data_type: string
name: retrieve_data
arguments: data_tag: D18
data_type: string

tool: D19: 02.txt

tool: D0: 


tool: D18: pause

assistant: ```c
int main(void) {
  my_fputc("02.txt");
  my_fgetc("02.txt");
  printf("\n");
  system("pause");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  call   <my_fputc@plt>
  mov    %rbp,%rdi
  call   <my_fgetc@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D6
data_type: string
name: parse_data
arguments: data_label: D25
data_type: string

tool: D10: 02.txt

tool: D6: 


tool: D25: pause

assistant: ```c
int main(void) {
  my_fputc("02.txt");
  my_fgetc("02.txt");
  printf("\n");
  system("pause");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  call   <my_fputc@plt>
  mov    %rbp,%rdi
  call   <my_fgetc@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D28
datatype: string

tool: D10: 02.txt

tool: D1: 


tool: D28: pause

assistant: ```c
int main(void) {
  my_fputc("02.txt");
  my_fgetc("02.txt");
  printf("\n");
  system("pause");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_crc16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L24
L27:
  cmpl   $0x1,-0x10(%rbp)
  jne    L14
  movl   $0x0,D37(%rip)
L14:
  mov    D37(%rip),%eax
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <crc32@plt>
  mov    %eax,D8(%rip)
  mov    D8(%rip),%eax
  movzwl %ax,%eax
L24:
  leave
  ret
```

assistant: ```c
uint16_t get_crc16(uint8_t *buffer, uint32_t size, int init_flag) {
  static uint32_t crc = 0;
  if (buffer == NULL)
    return 0;
  if (init_flag == 1)
    crc = 0;
  crc = crc32(crc, buffer, size);
  return (uint16_t)(0xffff & crc);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_crc16>:
  endbr64
  test   %rdi,%rdi
  je     L17
  sub    $0x8,%rsp
  cmp    $0x1,%edx
  je     L19
L8:
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    D28(%rip),%edi
  call   <crc32@plt>
  mov    %eax,D21(%rip)
  movzwl %ax,%eax
  add    $0x8,%rsp
  ret
L19:
  movl   $0x0,D21(%rip)
  jmp    L8
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint16_t get_crc16(uint8_t *buffer, uint32_t size, int init_flag) {
  static uint32_t crc = 0;
  if (buffer == NULL)
    return 0;
  if (init_flag == 1)
    crc = 0;
  crc = crc32(crc, buffer, size);
  return (uint16_t)(0xffff & crc);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_crc16>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    D21(%rip),%edi
  cmp    $0x1,%edx
  jne    L10
  movl   $0x0,D21(%rip)
  xor    %edi,%edi
L10:
  mov    %esi,%edx
  mov    %r8,%rsi
  call   <crc32@plt>
  mov    %eax,D23(%rip)
  movzwl %ax,%eax
  add    $0x8,%rsp
  ret
  nop
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint16_t get_crc16(uint8_t *buffer, uint32_t size, int init_flag) {
  static uint32_t crc = 0;
  if (buffer == NULL)
    return 0;
  if (init_flag == 1)
    crc = 0;
  crc = crc32(crc, buffer, size);
  return (uint16_t)(0xffff & crc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_crc16>:
  endbr64
  test   %rdi,%rdi
  je     L15
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    D16(%rip),%edi
  cmp    $0x1,%edx
  jne    L3
  movl   $0x0,D16(%rip)
  xor    %edi,%edi
L3:
  mov    %esi,%edx
  mov    %r8,%rsi
  call   <crc32@plt>
  mov    %eax,D0(%rip)
  movzwl %ax,%eax
  add    $0x8,%rsp
  ret
  nop
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint16_t get_crc16(uint8_t *buffer, uint32_t size, int init_flag) {
  static uint32_t crc = 0;
  if (buffer == NULL)
    return 0;
  if (init_flag == 1)
    crc = 0;
  crc = crc32(crc, buffer, size);
  return (uint16_t)(0xffff & crc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L21:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L10
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
L10:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *str0, const char *str1) {
  size_t i;
  for (i = 0; str0[i] == str1[i] && str0[i] != 0; i++)
    ;
  int ret = str0[i] - str1[i];
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  test   %al,%al
  je     L21
  cmp    %cl,%al
  jne    L21
  mov    $0x0,%edx
L14:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  test   %al,%al
  je     L21
  cmp    %cl,%al
  je     L14
L21:
  movsbl %al,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str0, const char *str1) {
  size_t i;
  for (i = 0; str0[i] == str1[i] && str0[i] != 0; i++)
    ;
  int ret = str0[i] - str1[i];
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  xor    %eax,%eax
  cmp    %cl,%dl
  je     L4
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L28
L4:
  test   %dl,%dl
  jne    L32
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L28:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str0, const char *str1) {
  size_t i;
  for (i = 0; str0[i] == str1[i] && str0[i] != 0; i++)
    ;
  int ret = str0[i] - str1[i];
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  xor    %eax,%eax
  cmp    %cl,%dl
  je     L36
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L10
L36:
  test   %dl,%dl
  jne    L37
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L10:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *str0, const char *str1) {
  size_t i;
  for (i = 0; str0[i] == str1[i] && str0[i] != 0; i++)
    ;
  int ret = str0[i] - str1[i];
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<e_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L12
L99:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L57
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L39
L57:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L97
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L39
L97:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L78
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L39
L78:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L99
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L45
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L39
L45:
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int e_strcmp(char const *p, char const *q) {
  while (*p) {
    if (*q == '\0')
      return *p - *q;
    if (*p > *q)
      return *p - *q;
    if (*p < *q)
      return *p - *q;
    p++;
    q++;
  }
  if (*q)
    return *p - *q;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<e_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
L41:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L15
  cmp    %al,%dl
  jl     L47
  jg     L23
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L41
L2:
  movzbl (%rsi),%edx
  movsbl %dl,%eax
  neg    %eax
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %edx,%eax
  ret
L15:
  movsbl %al,%eax
  ret
L47:
  movsbl %al,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  ret
L23:
  movsbl %al,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int e_strcmp(char const *p, char const *q) {
  while (*p) {
    if (*q == '\0')
      return *p - *q;
    if (*p > *q)
      return *p - *q;
    if (*p < *q)
      return *p - *q;
    p++;
    q++;
  }
  if (*q)
    return *p - *q;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<e_strcmp>:
  endbr64
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L38:
  movsbl (%rsi),%edx
  test   %dl,%dl
  je     L27
  cmp    %al,%dl
  jl     L45
  jg     L45
  add    $0x1,%rdi
  add    $0x1,%rsi
L18:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L38
  movsbl (%rsi),%eax
  mov    %eax,%edx
  neg    %eax
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %edx,%eax
L27:
  ret
  xchg   %ax,%ax
L45:
  sub    %edx,%eax
  ret
```

assistant: ```c
int e_strcmp(char const *p, char const *q) {
  while (*p) {
    if (*q == '\0')
      return *p - *q;
    if (*p > *q)
      return *p - *q;
    if (*p < *q)
      return *p - *q;
    p++;
    q++;
  }
  if (*q)
    return *p - *q;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<e_strcmp>:
  endbr64
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L41:
  movsbl (%rsi),%edx
  test   %dl,%dl
  je     L23
  cmp    %al,%dl
  jl     L33
  jg     L33
  add    $0x1,%rdi
  add    $0x1,%rsi
L29:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L41
  movsbl (%rsi),%eax
  mov    %eax,%edx
  neg    %eax
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %edx,%eax
L23:
  ret
  xchg   %ax,%ax
L33:
  sub    %edx,%eax
  ret
```

assistant: ```c
int e_strcmp(char const *p, char const *q) {
  while (*p) {
    if (*q == '\0')
      return *p - *q;
    if (*p > *q)
      return *p - *q;
    if (*p < *q)
      return *p - *q;
    p++;
    q++;
  }
  if (*q)
    return *p - *q;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__munmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0xffffffff,%edi
  call   <__vm_lock@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xb,%edi
  call   <syscall@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <__vm_unlock@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __munmap(void *start, size_t len) {
  int ret;
  __vm_lock(-1);
  ret = syscall(11, start, len);
  __vm_unlock();
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__munmap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0xffffffff,%edi
  call   <__vm_lock@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    $0xb,%edi
  call   <syscall@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__vm_unlock@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int __munmap(void *start, size_t len) {
  int ret;
  __vm_lock(-1);
  ret = syscall(11, start, len);
  __vm_unlock();
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__munmap>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    $0xffffffff,%edi
  sub    $0x8,%rsp
  call   <__vm_lock@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0xb,%edi
  call   <syscall@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <__vm_unlock@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int __munmap(void *start, size_t len) {
  int ret;
  __vm_lock(-1);
  ret = syscall(11, start, len);
  __vm_unlock();
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<__munmap>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    $0xffffffff,%edi
  sub    $0x8,%rsp
  call   <__vm_lock@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0xb,%edi
  call   <syscall@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <__vm_unlock@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int __munmap(void *start, size_t len) {
  int ret;
  __vm_lock(-1);
  ret = syscall(11, start, len);
  __vm_unlock();
  return ret;
}
```