ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp_long_option>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L132
L127:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L129
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  neg    %eax
  jmp    L160
L129:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L160
L1:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L132:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L127
L48:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L176
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L142
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L176
L142:
  mov    $0x0,%eax
  jmp    L160
L176:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L102
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L160
L102:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L169
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L160
L169:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L138
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  neg    %eax
  jmp    L160
L138:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
L160:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp_long_option(const char *str, const char *str_with_equals) {
  while (*str != '\0' && *str_with_equals != '\0' && *str_with_equals != '=') {
    if (*str != *str_with_equals)
      return (*str < *str_with_equals) ? -*str : *str_with_equals;
    str++;
    str_with_equals++;
  }
  if (*str == '\0' && (*str_with_equals == '\0' || *str_with_equals == '='))
    return 0;
  else if (*str == 0)
    return *str_with_equals;
  else if (*str_with_equals == 0)
    return *str;
  else
    return (*str < *str_with_equals) ? -*str : *str_with_equals;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp_long_option>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L22
L87:
  movzbl (%rsi),%edx
  cmp    $0x3d,%dl
  je     L13
  test   %dl,%dl
  je     L13
  cmp    %cl,%dl
  jne    L75
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L87
L22:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L16
  cmp    $0x3d,%al
  je     L16
  movsbl %al,%eax
  ret
L75:
  movsbl %cl,%esi
  neg    %esi
  movsbl %dl,%eax
  cmp    %cl,%dl
  cmovg  %esi,%eax
  ret
L13:
  test   %cl,%cl
  je     L22
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L72
  movsbl %cl,%eax
  ret
L72:
  movsbl %cl,%esi
  neg    %esi
  movsbl %dl,%eax
  cmp    %cl,%dl
  cmovg  %esi,%eax
  ret
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strcmp_long_option(const char *str, const char *str_with_equals) {
  while (*str != '\0' && *str_with_equals != '\0' && *str_with_equals != '=') {
    if (*str != *str_with_equals)
      return (*str < *str_with_equals) ? -*str : *str_with_equals;
    str++;
    str_with_equals++;
  }
  if (*str == '\0' && (*str_with_equals == '\0' || *str_with_equals == '='))
    return 0;
  else if (*str == 0)
    return *str_with_equals;
  else if (*str_with_equals == 0)
    return *str;
  else
    return (*str < *str_with_equals) ? -*str : *str_with_equals;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp_long_option>:
  endbr64
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L79:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L11
  cmp    $0x3d,%dl
  je     L11
  cmp    %dl,%cl
  jne    L21
  add    $0x1,%rdi
  add    $0x1,%rsi
L38:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L79
  movsbl (%rsi),%eax
  test   %al,%al
  je     L42
  cmp    $0x3d,%al
  je     L42
L17:
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl %cl,%eax
  test   %dl,%dl
  je     L17
  neg    %eax
  movsbl %dl,%esi
  cmp    %dl,%cl
  cmovge %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  movsbl %cl,%esi
  movsbl %dl,%eax
  neg    %esi
  cmp    %dl,%cl
  cmovl  %esi,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcmp_long_option(const char *str, const char *str_with_equals) {
  while (*str != '\0' && *str_with_equals != '\0' && *str_with_equals != '=') {
    if (*str != *str_with_equals)
      return (*str < *str_with_equals) ? -*str : *str_with_equals;
    str++;
    str_with_equals++;
  }
  if (*str == '\0' && (*str_with_equals == '\0' || *str_with_equals == '='))
    return 0;
  else if (*str == 0)
    return *str_with_equals;
  else if (*str_with_equals == 0)
    return *str;
  else
    return (*str < *str_with_equals) ? -*str : *str_with_equals;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp_long_option>:
  endbr64
  jmp    L51
  cs nopw 0x0(%rax,%rax,1)
L58:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L70
  cmp    $0x3d,%dl
  je     L70
  cmp    %dl,%cl
  jne    L60
  add    $0x1,%rdi
  add    $0x1,%rsi
L51:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L58
  movsbl (%rsi),%eax
  test   %al,%al
  je     L9
  cmp    $0x3d,%al
  je     L9
L4:
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  movsbl %cl,%eax
  test   %dl,%dl
  je     L4
  neg    %eax
  movsbl %dl,%esi
  cmp    %dl,%cl
  cmovge %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  movsbl %cl,%esi
  movsbl %dl,%eax
  neg    %esi
  cmp    %dl,%cl
  cmovl  %esi,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcmp_long_option(const char *str, const char *str_with_equals) {
  while (*str != '\0' && *str_with_equals != '\0' && *str_with_equals != '=') {
    if (*str != *str_with_equals)
      return (*str < *str_with_equals) ? -*str : *str_with_equals;
    str++;
    str_with_equals++;
  }
  if (*str == '\0' && (*str_with_equals == '\0' || *str_with_equals == '='))
    return 0;
  else if (*str == 0)
    return *str_with_equals;
  else if (*str_with_equals == 0)
    return *str;
  else
    return (*str < *str_with_equals) ? -*str : *str_with_equals;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x1a8(%rbp)
  jmp    L99
L91:
  mov    -0x1a8(%rbp),%eax
  cltq
  movl   $0x1,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a8(%rbp)
L99:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L91
  movl   $0x2,-0x1a8(%rbp)
  jmp    L20
L58:
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L78
  mov    -0x1a8(%rbp),%eax
  mov    %eax,-0x1a4(%rbp)
  jmp    L96
L22:
  mov    -0x1a8(%rbp),%eax
  imul   -0x1a4(%rbp),%eax
  cltq
  movl   $0x0,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a4(%rbp)
L96:
  mov    -0x1a8(%rbp),%eax
  imul   -0x1a4(%rbp),%eax
  cmp    $0x63,%eax
  jle    L22
L78:
  addl   $0x1,-0x1a8(%rbp)
L20:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L58
  movl   $0x2,-0x1a8(%rbp)
  jmp    L109
L8:
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L37
  mov    -0x1a8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L37:
  addl   $0x1,-0x1a8(%rbp)
L109:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: %d	

assistant: ```c
int main(void) {
  int i;
  int j;
  int prime[100];
  for (i = 2; i < 100; i++) {
    prime[i] = 1;
  }
  for (i = 2; i < 100; i++) {
    if (prime[i]) {
      for (j = i; i * j < 100; j++) {
        prime[i * j] = 0;
      }
    }
  }
  for (i = 2; i < 100; i++) {
    if (prime[i]) {
      printf("%d\t", i);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rax
  lea    0x190(%rsp),%rdx
L24:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L24
  mov    $0x2,%ecx
  mov    %rsp,%r8
  jmp    L62
L105:
  add    $0x1,%rcx
  cmp    $0x64,%rcx
  je     L2
L62:
  mov    %ecx,%esi
  cmpl   $0x0,(%r8,%rcx,4)
  je     L105
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    $0x63,%eax
  jg     L105
  lea    0x1(%rcx),%edx
  imul   %ecx,%edx
L119:
  cltq
  movl   $0x0,(%rsp,%rax,4)
  mov    %edx,%eax
  add    %esi,%edx
  cmp    $0x63,%eax
  jle    L119
  jmp    L105
L2:
  mov    $0x2,%ebx
  lea    D8(%rip),%rbp
  jmp    L88
L69:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L34
L88:
  mov    %ebx,%esi
  cmpl   $0x0,(%rsp,%rbx,4)
  je     L69
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L69
L34:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string

tool: D8: %d	

assistant: ```c
int main(void) {
  int i;
  int j;
  int prime[100];
  for (i = 2; i < 100; i++) {
    prime[i] = 1;
  }
  for (i = 2; i < 100; i++) {
    if (prime[i]) {
      for (j = i; i * j < 100; j++) {
        prime[i * j] = 0;
      }
    }
  }
  for (i = 2; i < 100; i++) {
    if (prime[i]) {
      printf("%d\t", i);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  lea    0x190(%rsp),%rdx
  lea    0x8(%rsp),%rax
  nop
L20:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L20
  mov    $0x2,%ecx
  mov    %rsp,%rbp
  jmp    L60
  nopl   0x0(%rax)
L108:
  add    $0x1,%rcx
  cmp    $0x64,%rcx
  je     L116
L60:
  mov    0x0(%rbp,%rcx,4),%edx
  mov    %ecx,%esi
  test   %edx,%edx
  je     L108
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    $0x63,%eax
  jg     L108
  lea    0x1(%rcx),%edx
  imul   %ecx,%edx
  nopl   0x0(%rax)
L18:
  cltq
  movl   $0x0,(%rsp,%rax,4)
  mov    %edx,%eax
  add    %esi,%edx
  cmp    $0x63,%eax
  jle    L18
  add    $0x1,%rcx
  cmp    $0x64,%rcx
  jne    L60
L116:
  mov    $0x2,%ebx
  lea    D8(%rip),%r12
  jmp    L111
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L64
L111:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %ebx,%esi
  test   %eax,%eax
  je     L22
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L111
L64:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d	

assistant: ```c
int main(void) {
  int i;
  int j;
  int prime[100];
  for (i = 2; i < 100; i++) {
    prime[i] = 1;
  }
  for (i = 2; i < 100; i++) {
    if (prime[i]) {
      for (j = i; i * j < 100; j++) {
        prime[i * j] = 0;
      }
    }
  }
  for (i = 2; i < 100; i++) {
    if (prime[i]) {
      printf("%d\t", i);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  lea    0x188(%rsp),%rdx
  lea    0x8(%rsp),%rax
  nopw   0x0(%rax,%rax,1)
L32:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L32
  mov    D5(%rip),%rax
  mov    $0x2,%ecx
  mov    %rsp,%rbp
  mov    %rax,0x188(%rsp)
  jmp    L17
  nopl   (%rax)
L19:
  add    $0x1,%rcx
  cmp    $0x64,%rcx
  je     L52
L17:
  mov    0x0(%rbp,%rcx,4),%edx
  mov    %ecx,%esi
  test   %edx,%edx
  je     L19
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    $0x63,%eax
  jg     L19
  lea    0x1(%rcx),%edx
  imul   %ecx,%edx
  nopl   0x0(%rax)
L95:
  cltq
  movl   $0x0,(%rsp,%rax,4)
  mov    %edx,%eax
  add    %esi,%edx
  cmp    $0x63,%eax
  jle    L95
  add    $0x1,%rcx
  cmp    $0x64,%rcx
  jne    L17
L52:
  mov    $0x2,%ebx
  lea    D15(%rip),%r12
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L46
L48:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %ebx,%esi
  test   %eax,%eax
  je     L49
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L48
L46:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: byte[16]
name: read_data
arguments: tag: D15
type_infered: string

tool: {"D5": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D15: %d	

assistant: ```c
int main(void) {
  int i;
  int j;
  int prime[100];
  for (i = 2; i < 100; i++) {
    prime[i] = 1;
  }
  for (i = 2; i < 100; i++) {
    if (prime[i]) {
      for (j = i; i * j < 100; j++) {
        prime[i * j] = 0;
      }
    }
  }
  for (i = 2; i < 100; i++) {
    if (prime[i]) {
      printf("%d\t", i);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<scanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfscanf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int scanf(const char *fmt, ...) {
  int count;
  va_list ap;
  va_start(ap, fmt);
  count = vfscanf(stdin, fmt, ap);
  va_end(ap);
  return (count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<scanf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <vfscanf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int scanf(const char *fmt, ...) {
  int count;
  va_list ap;
  va_start(ap, fmt);
  count = vfscanf(stdin, fmt, ap);
  va_end(ap);
  return (count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int scanf(const char *fmt, ...) {
  int count;
  va_list ap;
  va_start(ap, fmt);
  count = vfscanf(stdin, fmt, ap);
  va_end(ap);
  return (count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int scanf(const char *fmt, ...) {
  int count;
  va_list ap;
  va_start(ap, fmt);
  count = vfscanf(stdin, fmt, ap);
  va_end(ap);
  return (count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clicon_signal_unblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  cmpl   $0x0,-0x14(%rbp)
  je     L8
  mov    -0x14(%rbp),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  jmp    L17
L8:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <sigfillset@plt>
L17:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void clicon_signal_unblock(int sig) {
  sigset_t set;
  sigemptyset(&set);
  if (sig)
    sigaddset(&set, sig);
  else
    sigfillset(&set);
  sigprocmask(SIG_UNBLOCK, &set, NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clicon_signal_unblock>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <sigemptyset@plt>
  test   %ebx,%ebx
  je     L17
  lea    0x4(%rsp),%rdi
  mov    %ebx,%esi
  call   <sigaddset@plt>
L12:
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  lea    0x4(%rsp),%rdi
  call   <sigfillset@plt>
  jmp    L12
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void clicon_signal_unblock(int sig) {
  sigset_t set;
  sigemptyset(&set);
  if (sig)
    sigaddset(&set, sig);
  else
    sigfillset(&set);
  sigprocmask(SIG_UNBLOCK, &set, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clicon_signal_unblock>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <sigemptyset@plt>
  test   %ebp,%ebp
  je     L20
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <sigaddset@plt>
L5:
  mov    D1(%rip),%rax
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r12,%rdi
  call   <sigfillset@plt>
  jmp    L5
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void clicon_signal_unblock(int sig) {
  sigset_t set;
  sigemptyset(&set);
  if (sig)
    sigaddset(&set, sig);
  else
    sigfillset(&set);
  sigprocmask(SIG_UNBLOCK, &set, NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clicon_signal_unblock>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <sigemptyset@plt>
  test   %ebp,%ebp
  je     L23
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <sigaddset@plt>
L12:
  mov    D3(%rip),%rax
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r12,%rdi
  call   <sigfillset@plt>
  jmp    L12
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void clicon_signal_unblock(int sig) {
  sigset_t set;
  sigemptyset(&set);
  if (sig)
    sigaddset(&set, sig);
  else
    sigfillset(&set);
  sigprocmask(SIG_UNBLOCK, &set, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x5,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L85
L68:
  lea    -0x40(%rbp),%rdx
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  addl   $0x1,-0x44(%rbp)
L85:
  cmpl   $0x4,-0x44(%rbp)
  jle    L68
  movl   $0x0,-0x44(%rbp)
  jmp    L33
L50:
  mov    -0x44(%rbp),%eax
  cltq
  movss  -0x40(%rbp,%rax,4),%xmm0
  mov    -0x44(%rbp),%eax
  cltq
  movss  %xmm0,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x44(%rbp)
L33:
  cmpl   $0x4,-0x44(%rbp)
  jle    L50
  movl   $0x0,-0x44(%rbp)
  jmp    L25
L41:
  mov    -0x44(%rbp),%eax
  cltq
  movss  -0x40(%rbp,%rax,4),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x44(%rbp),%eax
  cltq
  movss  %xmm0,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x44(%rbp)
L25:
  cmpl   $0x4,-0x44(%rbp)
  jle    L41
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L43
L75:
  mov    -0x44(%rbp),%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    -0x44(%rbp),%eax
  cltq
  movss  -0x40(%rbp,%rax,4),%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  movq   %xmm2,%rax
  mov    -0x44(%rbp),%edx
  add    $0x1,%edx
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L43:
  cmpl   $0x4,-0x44(%rbp)
  jle    L75
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
datatype: string
name: unpack_data
arguments: label: D18
datatype: string
name: unpack_data
arguments: label: D6
datatype: f64
name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D38
datatype: string

tool: D12: Please enter %d values for euro[]:


tool: D18: %f

tool: D6: 1.3

tool: D1: 
Euro - Dollar
----------------------------

tool: D38: (%d) Euro: %.2f		 Dollar: %.2f


assistant: ```c
int main() {
  float euro[5], dollar[5];
  int i;
  printf("Please enter %d values for euro[]:\n", 5);
  for (i = 0; i < 5; i++) {
    scanf("%f", &euro[i]);
    getchar();
  }
  for (i = 0; i < 5; i++) {
    dollar[i] = euro[i];
  }
  for (i = 0; i < 5; i++) {
    dollar[i] = euro[i] * 1.3;
  }
  printf("\nEuro - Dollar\n----------------------------\n");
  for (i = 0; i < 5; i++) {
    printf("(%d) Euro: %.2f\t\t Dollar: %.2f\n", i + 1, euro[i], dollar[i]);
  }
  return 0;
}
```