ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<trnspt>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <ivector@plt>
  mov    0x4(%rbp),%r10d
  mov    %rax,%rdi
  mov    0x8(%rbp),%eax
  sub    %r10d,%eax
  add    %r12d,%eax
  cltd
  idiv   %r12d
  mov    0x14(%rbp),%eax
  add    %r12d,%eax
  sub    0x10(%rbp),%eax
  mov    %edx,%r9d
  cltd
  idiv   %r12d
  mov    0xc(%rbp),%eax
  add    %r12d,%eax
  sub    0x18(%rbp),%eax
  mov    %edx,%r11d
  cltd
  idiv   %r12d
  mov    %edx,%r8d
  test   %r9d,%r9d
  js     L48
  mov    %r9d,%esi
  mov    $0x1,%ecx
  add    $0x2,%rsi
  jmp    L24
  nopl   0x0(%rax)
L23:
  mov    0x4(%rbp),%r10d
L24:
  lea    -0x2(%r10,%rcx,1),%eax
  cltd
  idiv   %r12d
  add    $0x1,%edx
  movslq %edx,%rdx
  mov    (%rbx,%rdx,4),%eax
  mov    %eax,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L23
  add    $0x2,%r9d
L3:
  test   %r11d,%r11d
  js     L14
  movslq %r9d,%rax
  lea    0x2(%r11),%r10d
  mov    $0x1,%ecx
  lea    (%rdi,%rax,4),%rsi
  nopl   0x0(%rax,%rax,1)
L62:
  mov    0x10(%rbp),%eax
  add    $0x4,%rsi
  add    %ecx,%eax
  add    $0x1,%ecx
  sub    $0x2,%eax
  cltd
  idiv   %r12d
  add    $0x1,%edx
  movslq %edx,%rdx
  mov    (%rbx,%rdx,4),%eax
  mov    %eax,-0x4(%rsi)
  cmp    %r10d,%ecx
  jne    L62
  lea    0x1(%r9,%r11,1),%r9d
L14:
  test   %r8d,%r8d
  js     L99
  movslq %r9d,%r9
  add    $0x2,%r8d
  mov    $0x1,%ecx
  lea    (%rdi,%r9,4),%rsi
  xchg   %ax,%ax
L70:
  mov    0x18(%rbp),%eax
  add    $0x4,%rsi
  add    %ecx,%eax
  add    $0x1,%ecx
  sub    $0x2,%eax
  cltd
  idiv   %r12d
  add    $0x1,%edx
  movslq %edx,%rdx
  mov    (%rbx,%rdx,4),%eax
  mov    %eax,-0x4(%rsi)
  cmp    %r8d,%ecx
  jne    L70
L99:
  lea    0x1(%r12),%ecx
  mov    $0x1,%eax
  test   %r12d,%r12d
  jle    L13
  nopl   0x0(%rax,%rax,1)
L28:
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L28
L13:
  pop    %rbx
  mov    %r12d,%edx
  pop    %rbp
  mov    $0x1,%esi
  pop    %r12
  jmp    1070 <free_ivector@plt>
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x1,%r9d
  jmp    L3
```

assistant: ```c
void trnspt(int iorder[], int ncity, int n[]) {
  int m1, m2, m3, nn, j, jj, *jorder;
  jorder = ivector(1, ncity);
  m1 = 1 + ((n[2] - n[1] + ncity) % ncity);
  m2 = 1 + ((n[5] - n[4] + ncity) % ncity);
  m3 = 1 + ((n[3] - n[6] + ncity) % ncity);
  nn = 1;
  for (j = 1; j <= m1; j++) {
    jj = 1 + ((j + n[1] - 2) % ncity);
    jorder[nn++] = iorder[jj];
  }
  for (j = 1; j <= m2; j++) {
    jj = 1 + ((j + n[4] - 2) % ncity);
    jorder[nn++] = iorder[jj];
  }
  for (j = 1; j <= m3; j++) {
    jj = 1 + ((j + n[6] - 2) % ncity);
    jorder[nn++] = iorder[jj];
  }
  for (j = 1; j <= ncity; j++)
    iorder[j] = jorder[j];
  free_ivector(jorder, 1, ncity);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<query_format>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x437,-0x4(%rbp)
  cmpl   $0x32315659,-0x14(%rbp)
  jne    L26
  mov    -0x4(%rbp),%eax
  jmp    L3
L26:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ax
  cmp    $0x1dc70000,%eax
  jne    L36
  mov    -0x4(%rbp),%eax
  jmp    L3
L36:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int query_format(unsigned int format) {
  unsigned int i;
  int flag = 0x1 | 0x2 | 0x10 | 0x20 | 0x4 | 0x400;
  if (format == 0x32315659)
    return flag;
  if ((((format)&0xFFFF0000) == 0x1DC70000))
    return flag;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<query_format>:
  endbr64
  cmp    $0x32315659,%edi
  je     L8
  mov    $0x0,%di
  cmp    $0x1dc70000,%edi
  mov    $0x0,%eax
  mov    $0x437,%edx
  cmove  %edx,%eax
  ret
L8:
  mov    $0x437,%eax
  ret
```

assistant: ```c
int query_format(unsigned int format) {
  unsigned int i;
  int flag = 0x1 | 0x2 | 0x10 | 0x20 | 0x4 | 0x400;
  if (format == 0x32315659)
    return flag;
  if ((((format)&0xFFFF0000) == 0x1DC70000))
    return flag;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<query_format>:
  endbr64
  cmp    $0x32315659,%edi
  je     L2
  xor    %di,%di
  mov    $0x0,%edx
  mov    $0x437,%eax
  cmp    $0x1dc70000,%edi
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x437,%eax
  ret
```

assistant: ```c
int query_format(unsigned int format) {
  unsigned int i;
  int flag = 0x1 | 0x2 | 0x10 | 0x20 | 0x4 | 0x400;
  if (format == 0x32315659)
    return flag;
  if ((((format)&0xFFFF0000) == 0x1DC70000))
    return flag;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<query_format>:
  endbr64
  cmp    $0x32315659,%edi
  je     L7
  xor    %di,%di
  mov    $0x0,%edx
  mov    $0x437,%eax
  cmp    $0x1dc70000,%edi
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x437,%eax
  ret
```

assistant: ```c
int query_format(unsigned int format) {
  unsigned int i;
  int flag = 0x1 | 0x2 | 0x10 | 0x20 | 0x4 | 0x400;
  if (format == 0x32315659)
    return flag;
  if ((((format)&0xFFFF0000) == 0x1DC70000))
    return flag;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<YMOutput_ConvertTempData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <YMOutput_ValidateVersion@plt>
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L6:
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L4:
  mov    -0xc(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L4
  addl   $0x1,-0x10(%rbp)
L2:
  cmpl   $0xd,-0x10(%rbp)
  jle    L6
  cmpl   $0x5,-0x34(%rbp)
  jne    L41
  mov    -0x38(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L41:
  nop
  leave
  ret
```

assistant: ```c
void YMOutput_ConvertTempData(const unsigned char *pSrcData, unsigned char *pOutputData, int nVersion, int nVBL) {
  int j, i;
  unsigned long nPos = 0;
  nVersion = YMOutput_ValidateVersion(nVersion);
  for (j = 0; j < 14; j++) {
    for (i = 0; i < nVBL; i++) {
      unsigned char Data = pSrcData[(i * 16) + j];
      pOutputData[nPos] = Data;
      nPos++;
    }
  }
  if (nVersion == 5) {
    memset(pOutputData, 0, (nVBL * 2));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<YMOutput_ConvertTempData>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%edi
  mov    %ecx,%ebx
  call   <YMOutput_ValidateVersion@plt>
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  lea    -0x1(%rbx),%edx
  lea    0x1(%rbp,%rdx,1),%r10
  mov    %ebx,%r11d
  jmp    L53
L45:
  movzbl (%rcx),%esi
  mov    %sil,(%rdx)
  add    $0x10,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L45
  add    %r11,%r9
L31:
  add    $0x1,%r8
  cmp    $0xe,%r8
  je     L69
L53:
  lea    (%r12,%r8,1),%rcx
  lea    0x0(%rbp,%r9,1),%rdx
  lea    (%r10,%r9,1),%rdi
  test   %ebx,%ebx
  jg     L45
  jmp    L31
L69:
  cmp    $0x5,%eax
  je     L62
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L62:
  lea    (%rbx,%rbx,1),%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  jmp    L23
```

assistant: ```c
void YMOutput_ConvertTempData(const unsigned char *pSrcData, unsigned char *pOutputData, int nVersion, int nVBL) {
  int j, i;
  unsigned long nPos = 0;
  nVersion = YMOutput_ValidateVersion(nVersion);
  for (j = 0; j < 14; j++) {
    for (i = 0; i < nVBL; i++) {
      unsigned char Data = pSrcData[(i * 16) + j];
      pOutputData[nPos] = Data;
      nPos++;
    }
  }
  if (nVersion == 5) {
    memset(pOutputData, 0, (nVBL * 2));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<YMOutput_ConvertTempData>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %edx,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  call   <YMOutput_ValidateVersion@plt>
  lea    -0x1(%rbx),%edx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  lea    0x1(%rbp,%rdx,1),%r10
  mov    %ebx,%r11d
  nopl   0x0(%rax,%rax,1)
L9:
  lea    (%r12,%r8,1),%rcx
  lea    0x0(%rbp,%r9,1),%rdx
  lea    (%r10,%r9,1),%rdi
  test   %ebx,%ebx
  jle    L3
  nopl   0x0(%rax)
L25:
  movzbl (%rcx),%esi
  add    $0x1,%rdx
  add    $0x10,%rcx
  mov    %sil,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L25
  add    %r11,%r9
L3:
  add    $0x1,%r8
  cmp    $0xe,%r8
  jne    L9
  cmp    $0x5,%eax
  je     L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  lea    (%rbx,%rbx,1),%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  jmp    1060 <memset@plt>
```

assistant: ```c
void YMOutput_ConvertTempData(const unsigned char *pSrcData, unsigned char *pOutputData, int nVersion, int nVBL) {
  int j, i;
  unsigned long nPos = 0;
  nVersion = YMOutput_ValidateVersion(nVersion);
  for (j = 0; j < 14; j++) {
    for (i = 0; i < nVBL; i++) {
      unsigned char Data = pSrcData[(i * 16) + j];
      pOutputData[nPos] = Data;
      nPos++;
    }
  }
  if (nVersion == 5) {
    memset(pOutputData, 0, (nVBL * 2));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L38
L59:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L11
  mov    $0xffffffff,%eax
  jmp    L53
L11:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L9
  mov    $0x1,%eax
  jmp    L53
L9:
  addq   $0x1,-0x18(%rbp)
L38:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L59
  mov    $0x0,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *aptr, const void *bptr, size_t size) {
  const unsigned char *a = (const unsigned char *)aptr;
  const unsigned char *b = (const unsigned char *)bptr;
  for (size_t i = 0; i < size; i++)
    if (a[i] < b[i]) {
      return -1;
    } else if (b[i] < a[i]) {
      return 1;
    }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L21
  mov    $0x0,%eax
L30:
  movzbl (%rdi,%rax,1),%r8d
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%r8b
  jb     L5
  ja     L3
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L30
  mov    $0x0,%eax
  ret
L21:
  mov    $0x0,%eax
  ret
L5:
  mov    $0xffffffff,%eax
  ret
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *aptr, const void *bptr, size_t size) {
  const unsigned char *a = (const unsigned char *)aptr;
  const unsigned char *b = (const unsigned char *)bptr;
  for (size_t i = 0; i < size; i++)
    if (a[i] < b[i]) {
      return -1;
    } else if (b[i] < a[i]) {
      return 1;
    }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L39
  xor    %eax,%eax
  jmp    L15
  nopl   (%rax)
L29:
  ja     L37
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L39
L15:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jae    L29
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *aptr, const void *bptr, size_t size) {
  const unsigned char *a = (const unsigned char *)aptr;
  const unsigned char *b = (const unsigned char *)bptr;
  for (size_t i = 0; i < size; i++)
    if (a[i] < b[i]) {
      return -1;
    } else if (b[i] < a[i]) {
      return 1;
    }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L11
  xor    %eax,%eax
  jmp    L2
  nopl   (%rax)
L5:
  ja     L14
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L11
L2:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jae    L5
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *aptr, const void *bptr, size_t size) {
  const unsigned char *a = (const unsigned char *)aptr;
  const unsigned char *b = (const unsigned char *)bptr;
  for (size_t i = 0; i < size; i++)
    if (a[i] < b[i]) {
      return -1;
    } else if (b[i] < a[i]) {
      return 1;
    }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: OK

assistant: ```c
int main() {
  switch (2) {
  case 0:
  case 1:
    printf("ERRO");
    break;
  case 2:
    printf("OK");
    break;
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
  case 10:
  case 11:
  case 12:
  case 13:
  case 14:
  case 15:
  case 16:
  case 17:
  case 18:
  case 19:
  case 20:
  case 21:
  case 22:
  case 23:
  case 24:
  case 25:
  case 26:
  case 27:
  case 28:
  case 29:
  case 30:
  case 31:
  case 32:
  case 33:
  case 34:
  case 35:
  case 36:
  case 37:
  case 38:
  case 39:
  case 40:
  case 41:
  case 42:
  case 43:
  case 44:
  case 45:
  case 46:
  case 47:
  case 48:
  case 49:
  case 50:
  case 51:
  case 52:
  case 53:
  case 54:
  case 55:
  case 56:
  case 57:
  case 58:
  case 59:
  case 60:
  case 61:
  case 62:
  case 63:
  case 64:
  case 65:
  case 66:
  case 67:
  case 68:
  case 69:
  case 70:
  case 71:
  case 72:
  case 73:
  case 74:
  case 75:
  case 76:
  case 77:
  case 78:
  case 79:
  case 80:
  case 81:
  case 82:
  case 83:
  case 84:
  case 85:
  case 86:
  case 87:
  case 88:
  case 89:
  case 90:
  case 91:
  case 92:
  case 93:
  case 94:
  case 95:
  case 96:
  case 97:
  case 98:
  case 99:
  case 100:
    printf("ERRO");
    break;
  default:
    printf("ERRO");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: OK

assistant: ```c
int main() {
  switch (2) {
  case 0:
  case 1:
    printf("ERRO");
    break;
  case 2:
    printf("OK");
    break;
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
  case 10:
  case 11:
  case 12:
  case 13:
  case 14:
  case 15:
  case 16:
  case 17:
  case 18:
  case 19:
  case 20:
  case 21:
  case 22:
  case 23:
  case 24:
  case 25:
  case 26:
  case 27:
  case 28:
  case 29:
  case 30:
  case 31:
  case 32:
  case 33:
  case 34:
  case 35:
  case 36:
  case 37:
  case 38:
  case 39:
  case 40:
  case 41:
  case 42:
  case 43:
  case 44:
  case 45:
  case 46:
  case 47:
  case 48:
  case 49:
  case 50:
  case 51:
  case 52:
  case 53:
  case 54:
  case 55:
  case 56:
  case 57:
  case 58:
  case 59:
  case 60:
  case 61:
  case 62:
  case 63:
  case 64:
  case 65:
  case 66:
  case 67:
  case 68:
  case 69:
  case 70:
  case 71:
  case 72:
  case 73:
  case 74:
  case 75:
  case 76:
  case 77:
  case 78:
  case 79:
  case 80:
  case 81:
  case 82:
  case 83:
  case 84:
  case 85:
  case 86:
  case 87:
  case 88:
  case 89:
  case 90:
  case 91:
  case 92:
  case 93:
  case 94:
  case 95:
  case 96:
  case 97:
  case 98:
  case 99:
  case 100:
    printf("ERRO");
    break;
  default:
    printf("ERRO");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: OK

assistant: ```c
int main() {
  switch (2) {
  case 0:
  case 1:
    printf("ERRO");
    break;
  case 2:
    printf("OK");
    break;
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
  case 10:
  case 11:
  case 12:
  case 13:
  case 14:
  case 15:
  case 16:
  case 17:
  case 18:
  case 19:
  case 20:
  case 21:
  case 22:
  case 23:
  case 24:
  case 25:
  case 26:
  case 27:
  case 28:
  case 29:
  case 30:
  case 31:
  case 32:
  case 33:
  case 34:
  case 35:
  case 36:
  case 37:
  case 38:
  case 39:
  case 40:
  case 41:
  case 42:
  case 43:
  case 44:
  case 45:
  case 46:
  case 47:
  case 48:
  case 49:
  case 50:
  case 51:
  case 52:
  case 53:
  case 54:
  case 55:
  case 56:
  case 57:
  case 58:
  case 59:
  case 60:
  case 61:
  case 62:
  case 63:
  case 64:
  case 65:
  case 66:
  case 67:
  case 68:
  case 69:
  case 70:
  case 71:
  case 72:
  case 73:
  case 74:
  case 75:
  case 76:
  case 77:
  case 78:
  case 79:
  case 80:
  case 81:
  case 82:
  case 83:
  case 84:
  case 85:
  case 86:
  case 87:
  case 88:
  case 89:
  case 90:
  case 91:
  case 92:
  case 93:
  case 94:
  case 95:
  case 96:
  case 97:
  case 98:
  case 99:
  case 100:
    printf("ERRO");
    break;
  default:
    printf("ERRO");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: OK

assistant: ```c
int main() {
  switch (2) {
  case 0:
  case 1:
    printf("ERRO");
    break;
  case 2:
    printf("OK");
    break;
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
  case 10:
  case 11:
  case 12:
  case 13:
  case 14:
  case 15:
  case 16:
  case 17:
  case 18:
  case 19:
  case 20:
  case 21:
  case 22:
  case 23:
  case 24:
  case 25:
  case 26:
  case 27:
  case 28:
  case 29:
  case 30:
  case 31:
  case 32:
  case 33:
  case 34:
  case 35:
  case 36:
  case 37:
  case 38:
  case 39:
  case 40:
  case 41:
  case 42:
  case 43:
  case 44:
  case 45:
  case 46:
  case 47:
  case 48:
  case 49:
  case 50:
  case 51:
  case 52:
  case 53:
  case 54:
  case 55:
  case 56:
  case 57:
  case 58:
  case 59:
  case 60:
  case 61:
  case 62:
  case 63:
  case 64:
  case 65:
  case 66:
  case 67:
  case 68:
  case 69:
  case 70:
  case 71:
  case 72:
  case 73:
  case 74:
  case 75:
  case 76:
  case 77:
  case 78:
  case 79:
  case 80:
  case 81:
  case 82:
  case 83:
  case 84:
  case 85:
  case 86:
  case 87:
  case 88:
  case 89:
  case 90:
  case 91:
  case 92:
  case 93:
  case 94:
  case 95:
  case 96:
  case 97:
  case 98:
  case 99:
  case 100:
    printf("ERRO");
    break;
  default:
    printf("ERRO");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xcc(%rbp)
  movl   $0x0,-0xc8(%rbp)
  movl   $0x0,-0xc4(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L18
L3:
  mov    -0xcc(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  cmp    $0x2f,%al
  jle    L78
  mov    -0xcc(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  cmp    $0x39,%al
  jg     L78
  movl   $0x0,-0xc8(%rbp)
  jmp    L94
L58:
  mov    -0xc8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc8(%rbp)
  mov    -0xcc(%rbp),%edx
  movslq %edx,%rdx
  movzbl -0x80(%rbp,%rdx,1),%edx
  cltq
  mov    %dl,-0x8a(%rbp,%rax,1)
  addl   $0x1,-0xcc(%rbp)
L94:
  mov    -0xcc(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  test   %al,%al
  je     L38
  mov    -0xcc(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  cmp    $0x2f,%al
  jle    L38
  mov    -0xcc(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  cmp    $0x39,%al
  jle    L58
L38:
  mov    -0xc8(%rbp),%eax
  cltq
  movb   $0x0,-0x8a(%rbp,%rax,1)
  mov    -0xc4(%rbp),%ebx
  lea    0x1(%rbx),%eax
  mov    %eax,-0xc4(%rbp)
  lea    -0x8a(%rbp),%rax
  mov    %rax,%rdi
  call   <chtoint@plt>
  movslq %ebx,%rdx
  mov    %eax,-0xc0(%rbp,%rdx,4)
L78:
  addl   $0x1,-0xcc(%rbp)
L18:
  mov    -0xcc(%rbp),%eax
  cltq
  movzbl -0x80(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L3
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xcc(%rbp)
  jmp    L106
L25:
  mov    -0xcc(%rbp),%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L16
  mov    -0xcc(%rbp),%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L16:
  addl   $0x1,-0xcc(%rbp)
L106:
  cmpl   $0x9,-0xcc(%rbp)
  jle    L25
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_guessed: string
name: read_data
arguments: data_tag: D10
type_guessed: string
name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D12: Enter the string:

tool: D10: The number is:

tool: D9: %3d 

assistant: ```c
void main() {
  char str[100], ch[10];
  int i = 0, j = 0, k = 0, a[10] = {0};
  int chtoint(char *p);
  printf("Enter the string:\n");
  gets(str);
  while (str[i]) {
    if (str[i] >= '0' && str[i] <= '9') {
      j = 0;
      while (str[i] != '\0' && str[i] >= '0' && str[i] <= '9') {
        ch[j++] = str[i];
        i++;
      }
      ch[j] = '\0';
      a[k++] = chtoint(ch);
    }
    i++;
  }
  printf("The number is:\n");
  for (i = 0; i < 10; i++) {
    if (a[i] != 0)
      printf("%3d ", a[i]);
  }
}
```