user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movl   $0x0,0xd0(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  movq   $0x0,0x100(%rsp)
  movq   $0x0,0x108(%rsp)
  movq   $0x0,0x110(%rsp)
  movq   $0x0,0x118(%rsp)
  movq   $0x0,0x120(%rsp)
  movq   $0x0,0x128(%rsp)
  movq   $0x0,0x130(%rsp)
  movq   $0x0,0x138(%rsp)
  movl   $0x0,0x140(%rsp)
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    0x70(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl (%rsp),%ecx
  test   %cl,%cl
  je     L35
  movzbl 0x70(%rsp),%r8d
  lea    0x1(%rsp),%rsi
  mov    $0x0,%edi
  jmp    L40
L35:
  mov    $0x0,%edi
L52:
  movslq %edi,%rdi
  movb   $0x0,0xe0(%rsp,%rdi,1)
  lea    0xe0(%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x158,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  movslq %edi,%rax
  mov    %cl,0xe0(%rsp,%rax,1)
  lea    0x1(%rdi),%edi
L54:
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%ecx
  test   %cl,%cl
  je     L52
L40:
  lea    0x71(%rsp),%rdx
  mov    %r8d,%eax
  test   %r8b,%r8b
  je     L37
L56:
  cmp    %cl,%al
  je     L54
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L56
  jmp    L37
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D35
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D23
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D35: Enter orig_str: 

tool: D16:  %s

tool: D23: orig_str : %s


tool: D9: Enter string(whose chars)to remove

tool: D15: new str : %s


assistant: ```c
int main() {
  char orig_str[100] = {0};
  char squeeze_str[100] = {0};
  char new_str[100] = {0};
  int i, j, k;
  int flag = 0;
  printf("Enter orig_str: ");
  scanf(" %s", orig_str);
  printf("orig_str : %s\n", orig_str);
  printf("Enter string(whose chars)to remove\n");
  scanf(" %s", squeeze_str);
  for (i = 0, k = 0; orig_str[i] != '\0'; i++) {
    flag = 0;
    for (j = 0; squeeze_str[j] != '\0'; j++) {
      if (orig_str[i] == squeeze_str[j]) {
        flag = 1;
        break;
      }
    }
    if (flag != 1) {
      new_str[k++] = orig_str[i];
    }
  }
  new_str[k] = '\0';
  printf("new str : %s\n", new_str);
  return 0;
}
```