ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L15
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L16
L15:
  cmpl   $0x1,-0x14(%rbp)
  jle    L39
  cmpl   $0x3,-0x14(%rbp)
  jg     L39
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L48:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L48
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L16
L39:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L16:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D10
type: string
name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D35
type: string

tool: D12: You have no argument. You suck.

tool: D10: Here's your arguments:

tool: D17: %s 

tool: D35: You have too many arguments. You suck.

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  if (argc == 1) {
    printf("You have no argument. You suck.\n");
  } else if (argc > 1 && argc < 4) {
    printf("Here's your arguments:\n");
    for (i = 1; i < argc; i++) {
      printf("%s ", argv[i]);
    }
    printf("\n");
  } else {
    printf("You have too many arguments. You suck.\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L7
  mov    %rsi,%r12
  lea    -0x2(%rdi),%ebp
  cmp    $0x1,%ebp
  jbe    L32
  lea    D31(%rip),%rdi
  call   <puts@plt>
L8:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L8
L32:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%r12),%rbx
  mov    %ebp,%edi
  lea    0x10(%r12,%rdi,8),%r12
  lea    D7(%rip),%rbp
L2:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
type: string
name: retrieve_data
arguments: data_tag: D29
type: string
name: retrieve_data
arguments: data_tag: D38
type: string
name: retrieve_data
arguments: data_tag: D7
type: string

tool: D31: You have too many arguments. You suck.

tool: D29: You have no argument. You suck.

tool: D38: Here's your arguments:

tool: D7: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  if (argc == 1) {
    printf("You have no argument. You suck.\n");
  } else if (argc > 1 && argc < 4) {
    printf("Here's your arguments:\n");
    for (i = 1; i < argc; i++) {
      printf("%s ", argv[i]);
    }
    printf("\n");
  } else {
    printf("You have too many arguments. You suck.\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L41
  lea    -0x2(%rdi),%ebx
  cmp    $0x1,%ebx
  jbe    L9
  lea    D9(%rip),%rdi
  call   <puts@plt>
L38:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  lea    D15(%rip),%rdi
  mov    %rsi,%rbp
  call   <puts@plt>
  mov    %ebx,%edi
  lea    0x8(%rbp),%r12
  lea    D10(%rip),%rbx
  lea    0x10(%rbp,%rdi,8),%rbp
L18:
  mov    (%r12),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x8,%r12
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L38
L41:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string

tool: D9: You have too many arguments. You suck.

tool: D15: Here's your arguments:

tool: D10: %s 

tool: D24: You have no argument. You suck.

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  if (argc == 1) {
    printf("You have no argument. You suck.\n");
  } else if (argc > 1 && argc < 4) {
    printf("Here's your arguments:\n");
    for (i = 1; i < argc; i++) {
      printf("%s ", argv[i]);
    }
    printf("\n");
  } else {
    printf("You have too many arguments. You suck.\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L41
  lea    -0x2(%rdi),%ebx
  cmp    $0x1,%ebx
  jbe    L38
  lea    D2(%rip),%rdi
  call   <puts@plt>
L26:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L38:
  lea    D17(%rip),%rdi
  mov    %rsi,%rbp
  call   <puts@plt>
  mov    %ebx,%edi
  lea    0x8(%rbp),%r12
  lea    D30(%rip),%rbx
  lea    0x10(%rbp,%rdi,8),%rbp
L0:
  mov    (%r12),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x8,%r12
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L26
L41:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D17
type_guessed: string
name: extract_symbolic_data
arguments: label: D30
type_guessed: string
name: extract_symbolic_data
arguments: label: D34
type_guessed: string

tool: D2: You have too many arguments. You suck.

tool: D17: Here's your arguments:

tool: D30: %s 

tool: D34: You have no argument. You suck.

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  if (argc == 1) {
    printf("You have no argument. You suck.\n");
  } else if (argc > 1 && argc < 4) {
    printf("Here's your arguments:\n");
    for (i = 1; i < argc; i++) {
      printf("%s ", argv[i]);
    }
    printf("\n");
  } else {
    printf("You have too many arguments. You suck.\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<find_gzip_sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x5,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L59
L49:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  cmp    $0x1f,%eax
  jne    L14
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  cmp    $0x8b,%eax
  jne    L14
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  cmp    $0x8,%eax
  jne    L14
  mov    -0x20(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L14
  movl   $0x1,-0xc(%rbp)
  jmp    L37
L14:
  subl   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x1388,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L59:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x1388,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L37
  cmpl   $0x0,-0x8(%rbp)
  jne    L49
L37:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int find_gzip_sign(FILE *fd, char *line, int *line_len) {
  int ret = 0;
  int cnt = 5;
  int last_len = ftell(fd);
  while (fgets(line, 5000, fd) != NULL && cnt != 0) {
    *line_len = ftell(fd) - last_len;
    last_len = ftell(fd);
    if ((line[0] & 0xff) == 0x1f && (line[1] & 0xff) == 0x8b && (line[2] & 0xff) == 0x08 && (line[3] & 0xff) == 0x00) {
      ret = 1;
      break;
    }
    cnt--;
    memset(line, 0, 5000);
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_gzip_sign>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r14
  call   <ftell@plt>
  mov    %eax,%ebx
  mov    $0x5,%r13d
  jmp    L63
L45:
  sub    $0x1,%r13d
  mov    $0x1388,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
L63:
  mov    %r12,%rdx
  mov    $0x1388,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %r13d,%r13d
  je     L59
  test   %rax,%rax
  je     L59
  mov    %r12,%rdi
  call   <ftell@plt>
  sub    %ebx,%eax
  mov    %eax,(%r14)
  mov    %r12,%rdi
  call   <ftell@plt>
  mov    %eax,%ebx
  cmpb   $0x1f,0x0(%rbp)
  jne    L45
  cmpb   $0x8b,0x1(%rbp)
  jne    L45
  cmpb   $0x8,0x2(%rbp)
  jne    L45
  cmpb   $0x0,0x3(%rbp)
  jne    L45
  mov    $0x1,%eax
  jmp    L0
L59:
  mov    $0x0,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int find_gzip_sign(FILE *fd, char *line, int *line_len) {
  int ret = 0;
  int cnt = 5;
  int last_len = ftell(fd);
  while (fgets(line, 5000, fd) != NULL && cnt != 0) {
    *line_len = ftell(fd) - last_len;
    last_len = ftell(fd);
    if ((line[0] & 0xff) == 0x1f && (line[1] & 0xff) == 0x8b && (line[2] & 0xff) == 0x08 && (line[3] & 0xff) == 0x00) {
      ret = 1;
      break;
    }
    cnt--;
    memset(line, 0, 5000);
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_gzip_sign>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    $0x5,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <ftell@plt>
  mov    %eax,%ebx
  jmp    L69
  nopl   0x0(%rax)
L9:
  mov    $0x1388,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x1,%r13d
  call   <memset@plt>
L69:
  mov    %r12,%rdx
  mov    $0x1388,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L18
  test   %r13d,%r13d
  je     L18
  mov    %r12,%rdi
  call   <ftell@plt>
  mov    %r12,%rdi
  sub    %ebx,%eax
  mov    %eax,(%r14)
  call   <ftell@plt>
  cmpb   $0x1f,0x0(%rbp)
  mov    %eax,%ebx
  jne    L9
  cmpb   $0x8b,0x1(%rbp)
  jne    L9
  cmpb   $0x8,0x2(%rbp)
  jne    L9
  cmpb   $0x0,0x3(%rbp)
  jne    L9
  mov    $0x1,%eax
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
L74:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int find_gzip_sign(FILE *fd, char *line, int *line_len) {
  int ret = 0;
  int cnt = 5;
  int last_len = ftell(fd);
  while (fgets(line, 5000, fd) != NULL && cnt != 0) {
    *line_len = ftell(fd) - last_len;
    last_len = ftell(fd);
    if ((line[0] & 0xff) == 0x1f && (line[1] & 0xff) == 0x8b && (line[2] & 0xff) == 0x08 && (line[3] & 0xff) == 0x00) {
      ret = 1;
      break;
    }
    cnt--;
    memset(line, 0, 5000);
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_gzip_sign>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    $0x5,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <ftell@plt>
  mov    %eax,%ebx
  jmp    L72
  nopl   0x0(%rax)
L54:
  mov    $0x1388,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  sub    $0x1,%r13d
  call   <memset@plt>
L72:
  mov    %r12,%rdx
  mov    $0x1388,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L41
  test   %r13d,%r13d
  je     L41
  mov    %r12,%rdi
  call   <ftell@plt>
  mov    %r12,%rdi
  sub    %ebx,%eax
  mov    %eax,(%r14)
  call   <ftell@plt>
  cmpb   $0x1f,0x0(%rbp)
  mov    %eax,%ebx
  jne    L54
  cmpb   $0x8b,0x1(%rbp)
  jne    L54
  cmpb   $0x8,0x2(%rbp)
  jne    L54
  cmpb   $0x0,0x3(%rbp)
  jne    L54
  mov    $0x1,%eax
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L41:
  xor    %eax,%eax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int find_gzip_sign(FILE *fd, char *line, int *line_len) {
  int ret = 0;
  int cnt = 5;
  int last_len = ftell(fd);
  while (fgets(line, 5000, fd) != NULL && cnt != 0) {
    *line_len = ftell(fd) - last_len;
    last_len = ftell(fd);
    if ((line[0] & 0xff) == 0x1f && (line[1] & 0xff) == 0x8b && (line[2] & 0xff) == 0x08 && (line[3] & 0xff) == 0x00) {
      ret = 1;
      break;
    }
    cnt--;
    memset(line, 0, 5000);
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printimatl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L54
L42:
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L32:
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L13
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L13
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L13:
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L32
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L54:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L42
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string
name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D9: %10d 

tool: D6:   ...

assistant: ```c
void printimatl(int *a, int m, int n) {
  int i, j, jmod;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%10d ", a[i * n + j]);
      jmod = (j + 1) % 10;
      if ((jmod == 0) && (j < (n - 1))) {
        printf("  ...\n");
      }
    }
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printimatl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L80
  movl   $0x0,0x10(%rsp)
  mov    $0x0,%r15d
  lea    D11(%rip),%r13
  lea    -0x1(%rdx),%r14d
  jmp    L77
L86:
  add    $0x1,%rbx
L16:
  cmp    %rbp,%rbx
  je     L68
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %eax,%edx
  jne    L86
  cmp    %ebx,%r14d
  jle    L86
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L86
L68:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r15d
  mov    0xc(%rsp),%edi
  add    %edi,0x10(%rsp)
  cmp    %r15d,0x14(%rsp)
  je     L80
L77:
  mov    0xc(%rsp),%ebx
  test   %ebx,%ebx
  jle    L68
  movslq 0x10(%rsp),%rax
  mov    0x18(%rsp),%rdi
  lea    (%rdi,%rax,4),%r12
  mov    (%r12),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%ebp
  mov    $0x1,%ebx
  jmp    L16
L80:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string

tool: D11: %10d 

tool: D12:   ...

assistant: ```c
void printimatl(int *a, int m, int n) {
  int i, j, jmod;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%10d ", a[i * n + j]);
      jmod = (j + 1) % 10;
      if ((jmod == 0) && (j < (n - 1))) {
        printf("  ...\n");
      }
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printimatl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L41
  movl   $0x0,0x10(%rsp)
  xor    %r14d,%r14d
  lea    D3(%rip),%r12
  lea    -0x1(%rdx),%r13d
  nopl   (%rax)
L7:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L11
  movslq 0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  mov    %r12,%rdi
  mov    %r13d,%ebx
  add    $0x1,%rbx
  mov    $0x1,%r15d
  lea    (%rdx,%rax,4),%rbp
  xor    %eax,%eax
  mov    0x0(%rbp),%esi
  call   <printf@plt>
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%r15
L32:
  cmp    %r15,%rbx
  je     L11
  mov    0x0(%rbp,%r15,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%r15),%eax
  imul   $0xcccccccd,%eax,%eax
  ror    %eax
  cmp    $0x19999999,%eax
  ja     L4
  cmp    %r15d,%r13d
  jle    L4
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0xa,%edi
  add    $0x1,%r14d
  call   <putchar@plt>
  mov    0xc(%rsp),%ecx
  add    %ecx,0x10(%rsp)
  cmp    %r14d,0x14(%rsp)
  jne    L7
L41:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D10
datatype: string

tool: D3: %10d 

tool: D10:   ...

assistant: ```c
void printimatl(int *a, int m, int n) {
  int i, j, jmod;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%10d ", a[i * n + j]);
      jmod = (j + 1) % 10;
      if ((jmod == 0) && (j < (n - 1))) {
        printf("  ...\n");
      }
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printimatl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %esi,0x18(%rsp)
  test   %esi,%esi
  jle    L54
  lea    -0x2(%rdx),%eax
  mov    %edx,%r13d
  lea    D7(%rip),%r12
  xor    %r14d,%r14d
  movl   $0x0,0xc(%rsp)
  mov    %eax,0x1c(%rsp)
  nop
L79:
  test   %r13d,%r13d
  jle    L26
  movslq 0xc(%rsp),%rax
  mov    0x10(%rsp),%rcx
  mov    %r12,%rdi
  mov    $0x1,%r15d
  lea    (%rcx,%rax,4),%rbp
  xor    %eax,%eax
  mov    0x0(%rbp),%esi
  call   <printf@plt>
  mov    0x1c(%rsp),%ebx
  add    $0x2,%rbx
  cmp    $0x1,%r13d
  jne    L17
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L42:
  add    $0x1,%r15
  cmp    %r15,%rbx
  je     L26
L17:
  mov    0x0(%rbp,%r15,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%r15),%eax
  imul   $0xcccccccd,%eax,%eax
  ror    %eax
  cmp    $0x19999999,%eax
  ja     L42
  lea    -0x1(%r13),%eax
  cmp    %r15d,%eax
  jle    L42
  lea    D2(%rip),%rdi
  add    $0x1,%r15
  call   <puts@plt>
  cmp    %r15,%rbx
  jne    L17
  nopl   0x0(%rax)
L26:
  mov    $0xa,%edi
  add    $0x1,%r14d
  call   <putchar@plt>
  add    %r13d,0xc(%rsp)
  cmp    %r14d,0x18(%rsp)
  jne    L79
L54:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D7: %10d 

tool: D2:   ...

assistant: ```c
void printimatl(int *a, int m, int n) {
  int i, j, jmod;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%10d ", a[i * n + j]);
      jmod = (j + 1) % 10;
      if ((jmod == 0) && (j < (n - 1))) {
        printf("  ...\n");
      }
    }
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x78(%rbp)
  mov    -0x78(%rbp),%edx
  mov    -0x7c(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    -0x74(%rbp),%rdi
  lea    -0x7d(%rbp),%rsi
  lea    -0x70(%rbp),%rcx
  lea    -0x78(%rbp),%rdx
  lea    -0x7c(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <minscanf@plt>
  movss  -0x74(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movzbl -0x7d(%rbp),%eax
  movsbl %al,%ecx
  mov    -0x78(%rbp),%esi
  mov    -0x7c(%rbp),%eax
  lea    -0x70(%rbp),%rdx
  movapd %xmm0,%xmm1
  movd   %esi,%xmm0
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D19
data_type: string
name: read_data
arguments: tag: D3
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: D19: %d,%f


tool: D3: %d%f%s%c%e

tool: D9: %d,%f,%s,%c,%e


assistant: ```c
int main() {
  int i = 0;
  float d = 0, e;
  char s[100];
  char c;
  printf("%d,%f\n", i, d);
  minscanf("%d%f%s%c%e", &i, &d, s, &c, &e);
  printf("%d,%f,%s,%c,%e\n", i, d, s, c, e);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  mov    $0x0,%esi
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0xc(%rsp),%r9
  lea    0x3(%rsp),%r8
  mov    %rbx,%rcx
  lea    D1(%rip),%rdi
  call   <minscanf@plt>
  movsbl 0x3(%rsp),%ecx
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  mov    %rbx,%rdx
  movss  0x8(%rsp),%xmm0
  mov    0x4(%rsp),%esi
  lea    D29(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type: string
name: disassemble_data
arguments: data_tag: D1
type: string
name: disassemble_data
arguments: data_tag: D29
type: string

tool: D19: %d,%f


tool: D1: %d%f%s%c%e

tool: D29: %d,%f,%s,%c,%e


assistant: ```c
int main() {
  int i = 0;
  float d = 0, e;
  char s[100];
  char c;
  printf("%d,%f\n", i, d);
  minscanf("%d%f%s%c%e", &i, &d, s, &c, &e);
  printf("%d,%f,%s,%c,%e\n", i, d, s, c, e);
  return 0;
}
```