ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nasm_skip_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  cmpb   $0x27,-0xe(%rbp)
  je     L176
  cmpb   $0x22,-0xe(%rbp)
  jne    L142
L176:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L113
L44:
  addq   $0x1,-0x8(%rbp)
L113:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L148
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xe(%rbp)
  jne    L44
L148:
  mov    -0x8(%rbp),%rax
  jmp    L83
L142:
  cmpb   $0x60,-0xe(%rbp)
  jne    L49
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L90
  mov    -0x8(%rbp),%rax
  jmp    L83
L196:
  cmpl   $0x0,-0xc(%rbp)
  je     L105
  cmpl   $0x1,-0xc(%rbp)
  je     L138
  jmp    L90
L105:
  movsbl -0xd(%rbp),%eax
  cmp    $0x5c,%eax
  je     L71
  cmp    $0x60,%eax
  je     L146
  jmp    L38
L71:
  movl   $0x1,-0xc(%rbp)
  jmp    L38
L146:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  jmp    L83
L38:
  jmp    L90
L138:
  movl   $0x0,-0xc(%rbp)
  nop
L90:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L196
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  jmp    L83
L49:
  mov    -0x18(%rbp),%rax
L83:
  pop    %rbp
  ret
```

assistant: ```c
char *nasm_skip_string(char *str) {
  char bq;
  char *p;
  char c;
  enum unq_state {
    st_start,
    st_backslash,
  } state;
  bq = str[0];
  if (bq == '\'' || bq == '\"') {
    for (p = str + 1; *p && *p != bq; p++)
      ;
    return p;
  } else if (bq == '`') {
    state = st_start;
    p = str + 1;
    if (!*p)
      return p;
    while ((c = *p++)) {
      switch (state) {
      case st_start:
        switch (c) {
        case '\\':
          state = st_backslash;
          break;
        case '`':
          return p - 1;
        default:
          break;
        }
        break;
      case st_backslash:
        state = st_start;
        break;
      }
    }
    return p - 1;
  } else {
    return str;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<nasm_skip_string>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    $0x27,%cl
  je     L130
  cmp    $0x22,%cl
  je     L130
  mov    %rdi,%rax
  cmp    $0x60,%cl
  jne    L45
  lea    0x1(%rdi),%rax
  movzbl 0x1(%rdi),%edx
  test   %dl,%dl
  je     L45
  add    $0x2,%rdi
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    $0x1,%r8d
  jmp    L53
L130:
  lea    0x1(%rdi),%rax
  movzbl 0x1(%rdi),%edx
  cmp    %dl,%cl
  je     L45
  test   %dl,%dl
  je     L45
L139:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %cl,%dl
  je     L45
  test   %dl,%dl
  jne    L139
  ret
L64:
  cmp    $0x5c,%dl
  je     L145
  cmp    $0x60,%dl
  je     L45
L78:
  lea    0x1(%rdi),%rax
  movzbl -0x1(%rax),%edx
  test   %dl,%dl
  je     L42
  mov    %rax,%rdi
L53:
  lea    -0x1(%rdi),%rax
  test   %ecx,%ecx
  je     L64
  mov    %esi,%ecx
  jmp    L78
L145:
  mov    %r8d,%ecx
  jmp    L78
L42:
  mov    %rdi,%rax
L45:
  ret
```

assistant: ```c
char *nasm_skip_string(char *str) {
  char bq;
  char *p;
  char c;
  enum unq_state {
    st_start,
    st_backslash,
  } state;
  bq = str[0];
  if (bq == '\'' || bq == '\"') {
    for (p = str + 1; *p && *p != bq; p++)
      ;
    return p;
  } else if (bq == '`') {
    state = st_start;
    p = str + 1;
    if (!*p)
      return p;
    while ((c = *p++)) {
      switch (state) {
      case st_start:
        switch (c) {
        case '\\':
          state = st_backslash;
          break;
        case '`':
          return p - 1;
        default:
          break;
        }
        break;
      case st_backslash:
        state = st_start;
        break;
      }
    }
    return p - 1;
  } else {
    return str;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nasm_skip_string>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    $0x27,%cl
  je     L7
  cmp    $0x22,%cl
  je     L7
  mov    %rdi,%rax
  cmp    $0x60,%cl
  jne    L17
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rax
  add    $0x2,%rdi
  test   %dl,%dl
  je     L136
L28:
  mov    %rdi,%rcx
  cmp    $0x5c,%dl
  je     L24
L50:
  cmp    $0x60,%dl
  je     L17
  movzbl (%rcx),%edx
  lea    0x1(%rcx),%rsi
  mov    %rcx,%rax
  test   %dl,%dl
  je     L108
  mov    %rsi,%rcx
  cmp    $0x5c,%dl
  jne    L50
L24:
  cmpb   $0x0,(%rcx)
  lea    0x1(%rcx),%rax
  je     L104
  movzbl 0x1(%rcx),%edx
  lea    0x2(%rcx),%rdi
  test   %dl,%dl
  jne    L28
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rax
  cmp    %dl,%cl
  je     L17
  test   %dl,%dl
  jne    L115
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L124:
  test   %dl,%dl
  je     L110
L115:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L124
L17:
  ret
  nopl   0x0(%rax)
L110:
  ret
  nopl   0x0(%rax)
L136:
  ret
L108:
  ret
L104:
  mov    %rcx,%rax
  ret
```

assistant: ```c
char *nasm_skip_string(char *str) {
  char bq;
  char *p;
  char c;
  enum unq_state {
    st_start,
    st_backslash,
  } state;
  bq = str[0];
  if (bq == '\'' || bq == '\"') {
    for (p = str + 1; *p && *p != bq; p++)
      ;
    return p;
  } else if (bq == '`') {
    state = st_start;
    p = str + 1;
    if (!*p)
      return p;
    while ((c = *p++)) {
      switch (state) {
      case st_start:
        switch (c) {
        case '\\':
          state = st_backslash;
          break;
        case '`':
          return p - 1;
        default:
          break;
        }
        break;
      case st_backslash:
        state = st_start;
        break;
      }
    }
    return p - 1;
  } else {
    return str;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<nasm_skip_string>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    $0x27,%cl
  je     L19
  cmp    $0x22,%cl
  je     L19
  mov    %rdi,%rax
  cmp    $0x60,%cl
  jne    L65
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rax
  add    $0x2,%rdi
  test   %dl,%dl
  je     L76
L85:
  mov    %rdi,%rcx
  cmp    $0x5c,%dl
  je     L94
L109:
  cmp    $0x60,%dl
  je     L65
  movzbl (%rcx),%edx
  lea    0x1(%rcx),%rsi
  mov    %rcx,%rax
  test   %dl,%dl
  je     L75
  mov    %rsi,%rcx
  cmp    $0x5c,%dl
  jne    L109
L94:
  cmpb   $0x0,(%rcx)
  lea    0x1(%rcx),%rax
  je     L148
  movzbl 0x1(%rcx),%edx
  lea    0x2(%rcx),%rdi
  test   %dl,%dl
  jne    L85
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%rax
  cmp    %dl,%cl
  je     L65
  test   %dl,%dl
  jne    L135
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L3:
  test   %dl,%dl
  je     L138
L135:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L3
L65:
  ret
  nopl   0x0(%rax)
L138:
  ret
  nopl   0x0(%rax)
L76:
  ret
L75:
  ret
L148:
  mov    %rcx,%rax
  ret
```

assistant: ```c
char *nasm_skip_string(char *str) {
  char bq;
  char *p;
  char c;
  enum unq_state {
    st_start,
    st_backslash,
  } state;
  bq = str[0];
  if (bq == '\'' || bq == '\"') {
    for (p = str + 1; *p && *p != bq; p++)
      ;
    return p;
  } else if (bq == '`') {
    state = st_start;
    p = str + 1;
    if (!*p)
      return p;
    while ((c = *p++)) {
      switch (state) {
      case st_start:
        switch (c) {
        case '\\':
          state = st_backslash;
          break;
        case '`':
          return p - 1;
        default:
          break;
        }
        break;
      case st_backslash:
        state = st_start;
        break;
      }
    }
    return p - 1;
  } else {
    return str;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memselect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8d,-0x54(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x50(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x54(%rbp),%eax
  and    $0x1,%eax
  sub    $0x1,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  not    %eax
  mov    %eax,-0x24(%rbp)
  jmp    L0
L2:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%eax
  and    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  and    -0x28(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  xor    %ecx,%esi
  mov    %esi,%edx
  mov    %edx,(%rax)
L0:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memselect(void *out, const void *pa, const void *pb, size_t max, int flag) {
  uint8_t *a = (uint8_t *)pa;
  uint8_t *b = (uint8_t *)pb;
  uint8_t *p = (uint8_t *)out;
  uint8_t *endp = p + max;
  uint8_t mB = (flag & 1) - 1;
  uint8_t mA = ~mB;
  while (p < endp)
    *p++ = (mA & *a++) ^ (mB & *b++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memselect>:
  endbr64
  mov    %rsi,%r9
  mov    %rdx,%r10
  shl    $0x2,%rcx
  and    $0x1,%r8d
  lea    -0x1(%r8),%r11d
  neg    %r8d
  lea    (%rdi,%rcx,1),%rax
  cmp    %rax,%rdi
  jae    L3
  sub    $0x1,%rcx
  shr    $0x2,%rcx
  mov    $0x0,%eax
L12:
  mov    %r8d,%edx
  and    (%r9,%rax,4),%edx
  mov    %r11d,%esi
  and    (%r10,%rax,4),%esi
  xor    %esi,%edx
  mov    %edx,(%rdi,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L12
L3:
  ret
```

assistant: ```c
void memselect(void *out, const void *pa, const void *pb, size_t max, int flag) {
  uint8_t *a = (uint8_t *)pa;
  uint8_t *b = (uint8_t *)pb;
  uint8_t *p = (uint8_t *)out;
  uint8_t *endp = p + max;
  uint8_t mB = (flag & 1) - 1;
  uint8_t mA = ~mB;
  while (p < endp)
    *p++ = (mA & *a++) ^ (mB & *b++);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memselect>:
  endbr64
  shl    $0x2,%rcx
  and    $0x1,%r8d
  mov    %rsi,%r9
  mov    %rdx,%r10
  lea    (%rdi,%rcx,1),%rax
  lea    -0x1(%r8),%r11d
  neg    %r8d
  cmp    %rax,%rdi
  jae    L4
  sub    $0x1,%rcx
  xor    %eax,%eax
  shr    $0x2,%rcx
  nopl   0x0(%rax)
L9:
  mov    (%r9,%rax,4),%edx
  mov    (%r10,%rax,4),%esi
  and    %r8d,%edx
  and    %r11d,%esi
  xor    %esi,%edx
  mov    %edx,(%rdi,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L9
L4:
  ret
```

assistant: ```c
void memselect(void *out, const void *pa, const void *pb, size_t max, int flag) {
  uint8_t *a = (uint8_t *)pa;
  uint8_t *b = (uint8_t *)pb;
  uint8_t *p = (uint8_t *)out;
  uint8_t *endp = p + max;
  uint8_t mB = (flag & 1) - 1;
  uint8_t mA = ~mB;
  while (p < endp)
    *p++ = (mA & *a++) ^ (mB & *b++);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memselect>:
  endbr64
  shl    $0x2,%rcx
  and    $0x1,%r8d
  mov    %rsi,%r9
  mov    %rdx,%rsi
  lea    (%rdi,%rcx,1),%rax
  lea    -0x1(%r8),%edx
  neg    %r8d
  cmp    %rax,%rdi
  jae    L3
  lea    0x4(%rsi),%r10
  mov    %rdi,%rax
  sub    $0x1,%rcx
  sub    %r10,%rax
  cmp    $0x8,%rax
  seta   %r10b
  cmp    $0x3,%rcx
  seta   %al
  test   %al,%r10b
  je     L97
  lea    0x4(%r9),%r10
  mov    %rdi,%rax
  sub    %r10,%rax
  cmp    $0x8,%rax
  jbe    L97
  push   %rbp
  mov    %rcx,%rbp
  shr    $0x2,%rbp
  push   %rbx
  lea    0x1(%rbp),%rbx
  cmp    $0xb,%rcx
  jbe    L46
  mov    %rbx,%rcx
  movd   %r8d,%xmm6
  movd   %edx,%xmm7
  xor    %eax,%eax
  shr    $0x2,%rcx
  pshufd $0x0,%xmm6,%xmm3
  pshufd $0x0,%xmm7,%xmm2
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L78:
  movdqu (%r9,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm1
  pand   %xmm3,%xmm0
  pand   %xmm2,%xmm1
  pxor   %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L78
  mov    %rbx,%r11
  and    $0xfffffffffffffffc,%r11
  lea    0x0(,%r11,4),%rax
  lea    (%r9,%rax,1),%r10
  lea    (%rsi,%rax,1),%rcx
  add    %rdi,%rax
  cmp    %r11,%rbx
  je     L16
  sub    %r11,%rbx
  cmp    %r11,%rbp
  je     L9
L77:
  movq   (%r9,%r11,4),%xmm0
  movd   %r8d,%xmm4
  movd   %edx,%xmm5
  pshufd $0xe0,%xmm4,%xmm1
  pshufd $0xe0,%xmm5,%xmm2
  pand   %xmm1,%xmm0
  movq   (%rsi,%r11,4),%xmm1
  pand   %xmm2,%xmm1
  pxor   %xmm1,%xmm0
  movq   %xmm0,(%rdi,%r11,4)
  mov    %rbx,%rdi
  and    $0xfffffffffffffffe,%rdi
  lea    0x0(,%rdi,4),%rsi
  add    %rsi,%r10
  add    %rsi,%rcx
  add    %rsi,%rax
  cmp    %rdi,%rbx
  je     L16
L9:
  and    (%r10),%r8d
  and    (%rcx),%edx
  xor    %edx,%r8d
  mov    %r8d,(%rax)
L16:
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L97:
  shr    $0x2,%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    (%r9,%rax,4),%r10d
  mov    (%rsi,%rax,4),%r11d
  and    %r8d,%r10d
  and    %edx,%r11d
  xor    %r11d,%r10d
  mov    %r10d,(%rdi,%rax,4)
  mov    %rax,%r10
  add    $0x1,%rax
  cmp    %rcx,%r10
  jne    L28
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
L46:
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %r9,%r10
  xor    %r11d,%r11d
  jmp    L77
```

assistant: ```c
void memselect(void *out, const void *pa, const void *pb, size_t max, int flag) {
  uint8_t *a = (uint8_t *)pa;
  uint8_t *b = (uint8_t *)pb;
  uint8_t *p = (uint8_t *)out;
  uint8_t *endp = p + max;
  uint8_t mB = (flag & 1) - 1;
  uint8_t mA = ~mB;
  while (p < endp)
    *p++ = (mA & *a++) ^ (mB & *b++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x2,-0x20(%rbp)
  movq   $0x2,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  cqto
  shr    $0x3f,%rdx
  add    %rdx,%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jne    L10
  mov    -0x18(%rbp),%rax
  add    %rax,-0x20(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x3d08ff,-0x18(%rbp)
  jle    L17
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D8: Sum is: %ld


assistant: ```c
int main() {
  long int sum = 2;
  long int fib_a = 2;
  long int fib_b = 1;
  long int fib_aux;
  do {
    if (fib_a % 2 == 1)
      sum += fib_a;
    fib_aux = fib_a;
    fib_a += fib_b;
    fib_b = fib_aux;
  } while (fib_a < 4000000);
  printf("Sum is: %ld\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x2,%ecx
  mov    $0x2,%esi
  jmp    L16
L11:
  mov    %rax,%rdi
  shr    $0x3f,%rdi
  lea    (%rax,%rdi,1),%rdx
  and    $0x1,%edx
  sub    %rdi,%rdx
  lea    (%rsi,%rax,1),%rdi
  cmp    $0x1,%rdx
  cmove  %rdi,%rsi
  mov    %rcx,%rdx
  mov    %rax,%rcx
L16:
  lea    (%rcx,%rdx,1),%rax
  cmp    $0x3d08ff,%rax
  jle    L11
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D0: Sum is: %ld


assistant: ```c
int main() {
  long int sum = 2;
  long int fib_a = 2;
  long int fib_b = 1;
  long int fib_aux;
  do {
    if (fib_a % 2 == 1)
      sum += fib_a;
    fib_aux = fib_a;
    fib_a += fib_b;
    fib_b = fib_aux;
  } while (fib_a < 4000000);
  printf("Sum is: %ld\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x2,%esi
  jmp    L1
  nopl   0x0(%rax)
L0:
  lea    (%rsi,%rax,1),%rcx
  test   $0x1,%al
  cmovne %rcx,%rsi
  mov    %rdx,%rcx
  mov    %rax,%rdx
L1:
  lea    (%rdx,%rcx,1),%rax
  cmp    $0x3d08ff,%rax
  jle    L0
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: Sum is: %ld


assistant: ```c
int main() {
  long int sum = 2;
  long int fib_a = 2;
  long int fib_b = 1;
  long int fib_aux;
  do {
    if (fib_a % 2 == 1)
      sum += fib_a;
    fib_aux = fib_a;
    fib_a += fib_b;
    fib_b = fib_aux;
  } while (fib_a < 4000000);
  printf("Sum is: %ld\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x3,%eax
  mov    $0x2,%esi
  jmp    L7
  nopl   0x0(%rax)
L1:
  mov    %rdx,%rax
L7:
  lea    (%rsi,%rax,1),%rdx
  test   $0x1,%al
  cmovne %rdx,%rsi
  lea    (%rcx,%rax,1),%rdx
  mov    %rax,%rcx
  cmp    $0x3d08ff,%rdx
  jle    L1
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: Sum is: %ld


assistant: ```c
int main() {
  long int sum = 2;
  long int fib_a = 2;
  long int fib_b = 1;
  long int fib_aux;
  do {
    if (fib_a % 2 == 1)
      sum += fib_a;
    fib_aux = fib_a;
    fib_a += fib_b;
    fib_b = fib_aux;
  } while (fib_a < 4000000);
  printf("Sum is: %ld\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<QEIVelocityGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x4002c000,-0x4(%rbp)
  je     L4
  cmpl   $0x4002d000,-0x4(%rbp)
  jne    L12
L4:
  mov    $0x1,%eax
  jmp    L3
L12:
  mov    $0x0,%eax
L3:
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x1c,%eax
  cltq
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
uint32_t QEIVelocityGet(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  return ((*((volatile uint32_t *)(ui32Base + 0x0000001C))));
}
```
user: What is the c source code of the assembly code below:

```asm
<QEIVelocityGet>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%eax
  and    $0xef,%ah
  cmp    $0x4002c000,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x1c,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t QEIVelocityGet(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  return ((*((volatile uint32_t *)(ui32Base + 0x0000001C))));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<QEIVelocityGet>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  and    $0xef,%ah
  cmp    $0x4002c000,%eax
  sete   %dil
  add    $0x1c,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t QEIVelocityGet(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  return ((*((volatile uint32_t *)(ui32Base + 0x0000001C))));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<QEIVelocityGet>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  and    $0xef,%ah
  cmp    $0x4002c000,%eax
  sete   %dil
  add    $0x1c,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t QEIVelocityGet(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  return ((*((volatile uint32_t *)(ui32Base + 0x0000001C))));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getpty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getpt@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L28
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L44
L28:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <grantpt@plt>
  test   %rax,%rax
  js     L29
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <unlockpt@plt>
  test   %rax,%rax
  jns    L22
L29:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L44
L22:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ptsname@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x4(%rbp),%eax
L44:
  leave
  ret
```

assistant: ```c
int getpty(char *line) {
  int p;
  p = getpt();
  if (p < 0) {
    ;
    close(p);
    return -1;
  }
  if (grantpt(p) < 0 || unlockpt(p) < 0) {
    ;
    close(p);
    return -1;
  };
  strcpy(line, (const char *)ptsname(p));
  return (p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getpty>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <getpt@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L31
  mov    %eax,%edi
  call   <grantpt@plt>
  test   %rax,%rax
  js     L23
  mov    %ebx,%edi
  call   <unlockpt@plt>
  test   %rax,%rax
  js     L23
  mov    %ebx,%edi
  call   <ptsname@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
L32:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebx
  jmp    L32
L23:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebx
  jmp    L32
```

assistant: ```c
int getpty(char *line) {
  int p;
  p = getpt();
  if (p < 0) {
    ;
    close(p);
    return -1;
  }
  if (grantpt(p) < 0 || unlockpt(p) < 0) {
    ;
    close(p);
    return -1;
  };
  strcpy(line, (const char *)ptsname(p));
  return (p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getpty>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getpt@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  test   %eax,%eax
  js     L2
  call   <grantpt@plt>
  test   %rax,%rax
  js     L38
  mov    %r12d,%edi
  call   <unlockpt@plt>
  test   %rax,%rax
  js     L38
  mov    %r12d,%edi
  call   <ptsname@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
L20:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r12d,%edi
L2:
  call   <close@plt>
  mov    $0xffffffff,%r12d
  jmp    L20
```

assistant: ```c
int getpty(char *line) {
  int p;
  p = getpt();
  if (p < 0) {
    ;
    close(p);
    return -1;
  }
  if (grantpt(p) < 0 || unlockpt(p) < 0) {
    ;
    close(p);
    return -1;
  };
  strcpy(line, (const char *)ptsname(p));
  return (p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getpty>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getpt@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  test   %eax,%eax
  js     L11
  call   <grantpt@plt>
  test   %rax,%rax
  js     L6
  mov    %r12d,%edi
  call   <unlockpt@plt>
  test   %rax,%rax
  js     L6
  mov    %r12d,%edi
  call   <ptsname@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r12d,%edi
L11:
  call   <close@plt>
  mov    $0xffffffff,%r12d
  jmp    L7
```

assistant: ```c
int getpty(char *line) {
  int p;
  p = getpt();
  if (p < 0) {
    ;
    close(p);
    return -1;
  }
  if (grantpt(p) < 0 || unlockpt(p) < 0) {
    ;
    close(p);
    return -1;
  };
  strcpy(line, (const char *)ptsname(p));
  return (p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<char_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *char_to_str(char src) {
  char *ret = malloc(sizeof(char) * 2);
  *ret = src;
  *(ret + 1) = '\0';
  return ret;
}
```