ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wcschr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rsi,%rsi
  je     L30
  mov    (%rdi),%rax
  test   %rax,%rax
  jne    L43
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L27:
  mov    0x8(%rbx),%rax
  add    $0x8,%rbx
  test   %rax,%rax
  je     L32
L43:
  cmp    %rax,%rsi
  jne    L27
  mov    %rbx,%rax
L42:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L30:
  call   <wcslen@plt>
  cltq
  lea    (%rbx,%rax,8),%rax
  pop    %rbx
  ret
```

assistant: ```c
wchar_t *wcschr(const wchar_t *s, wchar_t c) {
  if (!c)
    return (wchar_t *)s + wcslen(s);
  for (; *s && *s != c; s++)
    ;
  return *s ? (wchar_t *)s : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wcschr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rsi,%rsi
  je     L3
  mov    (%rdi),%rax
  test   %rax,%rax
  jne    L46
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x8(%rbx),%rax
  add    $0x8,%rbx
  test   %rax,%rax
  je     L30
L46:
  cmp    %rax,%rsi
  jne    L0
  mov    %rbx,%rax
L17:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  call   <wcslen@plt>
  cltq
  lea    (%rbx,%rax,8),%rax
  pop    %rbx
  ret
```

assistant: ```c
wchar_t *wcschr(const wchar_t *s, wchar_t c) {
  if (!c)
    return (wchar_t *)s + wcslen(s);
  for (; *s && *s != c; s++)
    ;
  return *s ? (wchar_t *)s : 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<led_breathes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  and    $0x2,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0x2,%eax
  and    $0x4,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  shl    $0x3,%eax
  and    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x4,%eax
  and    $0x10,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%eax
  shl    $0x5,%eax
  and    $0x20,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <cap1166_blink@plt>
  nop
  leave
  ret
```

assistant: ```c
void led_breathes(int s0, int s1, int s2, int s3, int s4, int s5) {
  unsigned int l;
  l = s0 & 0x01;
  l |= (s1 & 0x01) << 1;
  l |= (s2 & 0x01) << 2;
  l |= (s3 & 0x01) << 3;
  l |= (s4 & 0x01) << 4;
  l |= (s5 & 0x01) << 5;
  cap1166_blink(l);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<led_breathes>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x4,%r8d
  and    $0x10,%r8d
  shl    $0x5,%r9d
  and    $0x20,%r9d
  or     %r9d,%r8d
  shl    $0x3,%ecx
  and    $0x8,%ecx
  or     %ecx,%r8d
  shl    $0x2,%edx
  and    $0x4,%edx
  or     %edx,%r8d
  and    $0x1,%edi
  or     %edi,%r8d
  lea    (%rsi,%rsi,1),%edi
  and    $0x2,%edi
  or     %r8d,%edi
  call   <cap1166_blink@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void led_breathes(int s0, int s1, int s2, int s3, int s4, int s5) {
  unsigned int l;
  l = s0 & 0x01;
  l |= (s1 & 0x01) << 1;
  l |= (s2 & 0x01) << 2;
  l |= (s3 & 0x01) << 3;
  l |= (s4 & 0x01) << 4;
  l |= (s5 & 0x01) << 5;
  cap1166_blink(l);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<led_breathes>:
  endbr64
  shl    $0x4,%r8d
  shl    $0x5,%r9d
  and    $0x1,%edi
  shl    $0x3,%ecx
  and    $0x10,%r8d
  and    $0x20,%r9d
  shl    $0x2,%edx
  or     %r9d,%r8d
  and    $0x8,%ecx
  and    $0x4,%edx
  or     %ecx,%r8d
  or     %edx,%r8d
  or     %edi,%r8d
  lea    (%rsi,%rsi,1),%edi
  and    $0x2,%edi
  or     %r8d,%edi
  jmp    1050 <cap1166_blink@plt>
```

assistant: ```c
void led_breathes(int s0, int s1, int s2, int s3, int s4, int s5) {
  unsigned int l;
  l = s0 & 0x01;
  l |= (s1 & 0x01) << 1;
  l |= (s2 & 0x01) << 2;
  l |= (s3 & 0x01) << 3;
  l |= (s4 & 0x01) << 4;
  l |= (s5 & 0x01) << 5;
  cap1166_blink(l);
}
```
user: What is the c source code of the assembly code below?

```asm
<led_breathes>:
  endbr64
  shl    $0x4,%r8d
  shl    $0x5,%r9d
  and    $0x1,%edi
  shl    $0x3,%ecx
  and    $0x10,%r8d
  and    $0x20,%r9d
  shl    $0x2,%edx
  or     %r9d,%r8d
  and    $0x8,%ecx
  and    $0x4,%edx
  or     %ecx,%r8d
  or     %edx,%r8d
  or     %edi,%r8d
  lea    (%rsi,%rsi,1),%edi
  and    $0x2,%edi
  or     %r8d,%edi
  jmp    1050 <cap1166_blink@plt>
```

assistant: ```c
void led_breathes(int s0, int s1, int s2, int s3, int s4, int s5) {
  unsigned int l;
  l = s0 & 0x01;
  l |= (s1 & 0x01) << 1;
  l |= (s2 & 0x01) << 2;
  l |= (s3 & 0x01) << 3;
  l |= (s4 & 0x01) << 4;
  l |= (s5 & 0x01) << 5;
  cap1166_blink(l);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<maxProfit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L23
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  add    %eax,-0x8(%rbp)
L23:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int maxProfit(int *prices, int pricesSize) {
  int ret = 0;
  for (int i = 0; i < pricesSize - 1; ++i) {
    if (prices[i] < prices[i + 1]) {
      ret += prices[i + 1] - prices[i];
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<maxProfit>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%r8
  mov    $0x0,%ecx
L5:
  mov    (%rax),%edi
  mov    0x4(%rax),%esi
  mov    %esi,%edx
  sub    %edi,%edx
  add    %ecx,%edx
  cmp    %esi,%edi
  cmovl  %edx,%ecx
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L5
L19:
  mov    %ecx,%eax
  ret
L15:
  mov    $0x0,%ecx
  jmp    L19
```

assistant: ```c
int maxProfit(int *prices, int pricesSize) {
  int ret = 0;
  for (int i = 0; i < pricesSize - 1; ++i) {
    if (prices[i] < prices[i + 1]) {
      ret += prices[i + 1] - prices[i];
    }
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<maxProfit>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  lea    -0x2(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rsi
  nopl   0x0(%rax)
L5:
  mov    0x4(%rdi),%edx
  mov    (%rdi),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    %r8d,%eax
  cmp    %edx,%ecx
  cmovl  %eax,%r8d
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L5
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxProfit(int *prices, int pricesSize) {
  int ret = 0;
  for (int i = 0; i < pricesSize - 1; ++i) {
    if (prices[i] < prices[i + 1]) {
      ret += prices[i + 1] - prices[i];
    }
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<maxProfit>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    %rdi,%rdx
  test   %ecx,%ecx
  jle    L28
  sub    $0x2,%esi
  cmp    $0x2,%esi
  jbe    L58
  mov    %ecx,%esi
  mov    %rdi,%rax
  pxor   %xmm1,%xmm1
  shr    $0x2,%esi
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  cs nopw 0x0(%rax,%rax,1)
L19:
  movdqu 0x4(%rax),%xmm0
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  movdqa %xmm0,%xmm2
  pcmpgtd %xmm3,%xmm0
  psubd  %xmm3,%xmm2
  pand   %xmm2,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L19
  movdqa %xmm1,%xmm0
  mov    %ecx,%esi
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%esi
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x3,%cl
  je     L40
L34:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r9
  mov    (%rdx,%rdi,4),%r10d
  mov    0x4(%rdx,%r9,1),%edi
  mov    %edi,%r8d
  sub    %r10d,%r8d
  add    %eax,%r8d
  cmp    %edi,%r10d
  cmovl  %r8d,%eax
  lea    0x1(%rsi),%r8d
  cmp    %r8d,%ecx
  jle    L1
  mov    0x8(%rdx,%r9,1),%r8d
  mov    %r8d,%r10d
  sub    %edi,%r10d
  add    %eax,%r10d
  cmp    %r8d,%edi
  cmovl  %r10d,%eax
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L1
  mov    0xc(%rdx,%r9,1),%ecx
  mov    %ecx,%edx
  sub    %r8d,%edx
  add    %eax,%edx
  cmp    %ecx,%r8d
  cmovl  %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
L1:
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  ret
L58:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L34
```

assistant: ```c
int maxProfit(int *prices, int pricesSize) {
  int ret = 0;
  for (int i = 0; i < pricesSize - 1; ++i) {
    if (prices[i] < prices[i + 1]) {
      ret += prices[i + 1] - prices[i];
    }
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L13
L17:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L17
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D5: r

tool: D6: %s

assistant: ```c
void cat(const char *path) {
  FILE *f = fopen(path, "r");
  char *buff = malloc(1024);
  while ((fgets(buff, sizeof(buff), f))) {
    printf("%s", buff);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D15(%rip),%r12
  jmp    L1
L17:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L1:
  mov    %rbp,%rdx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
data_type: string
name: read_data
arguments: data_label: D15
data_type: string

tool: D10: r

tool: D15: %s

assistant: ```c
void cat(const char *path) {
  FILE *f = fopen(path, "r");
  char *buff = malloc(1024);
  while ((fgets(buff, sizeof(buff), f))) {
    printf("%s", buff);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cat>:
  endbr64
  push   %r12
  lea    D12(%rip),%rsi
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  call   <fopen@plt>
  mov    $0x400,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  jmp    L18
  nopl   (%rax)
L17:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L18:
  mov    %rbp,%rdx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D12
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string

tool: D12: r

tool: D10: %s

assistant: ```c
void cat(const char *path) {
  FILE *f = fopen(path, "r");
  char *buff = malloc(1024);
  while ((fgets(buff, sizeof(buff), f))) {
    printf("%s", buff);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cat>:
  endbr64
  push   %r12
  lea    D1(%rip),%rsi
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  call   <fopen@plt>
  mov    $0x400,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  jmp    L15
  nopl   (%rax)
L16:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L15:
  mov    %rbp,%rdx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D13
type: string

tool: D1: r

tool: D13: %s

assistant: ```c
void cat(const char *path) {
  FILE *f = fopen(path, "r");
  char *buff = malloc(1024);
  while ((fgets(buff, sizeof(buff), f))) {
    printf("%s", buff);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i915_get_instruction_src0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %esi,-0xac(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xac(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x9c(%rbp)
  mov    -0xac(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x98(%rbp)
  mov    -0x9c(%rbp),%eax
  sar    $0x2,%eax
  and    $0x1f,%eax
  mov    %eax,-0x94(%rbp)
  mov    -0x98(%rbp),%eax
  shr    $0x1c,%eax
  mov    %eax,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,-0x90(%rbp)
  mov    -0x98(%rbp),%eax
  sar    $0x18,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,-0x88(%rbp)
  mov    -0x98(%rbp),%eax
  sar    $0x14,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,-0x80(%rbp)
  mov    -0x98(%rbp),%eax
  sar    $0x10,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x9c(%rbp),%eax
  sar    $0x7,%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  mov    -0xb8(%rbp),%rdx
  mov    -0x94(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <i915_get_instruction_src_name@plt>
  mov    -0x78(%rbp),%rdi
  mov    -0x80(%rbp),%rsi
  mov    -0x88(%rbp),%rcx
  mov    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L13
  lea    -0x70(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L13:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D13: .%s%s%s%s

tool: D4: .xyzw

assistant: ```c
void i915_get_instruction_src0(uint32_t *data, int i, char *srcname) {
  uint32_t a0 = data[i];
  uint32_t a1 = data[i + 1];
  int src_nr = (a0 >> 2) & 0x1f;
  const char *swizzle_x = i915_get_channel_swizzle((a1 >> 28) & 0xf);
  const char *swizzle_y = i915_get_channel_swizzle((a1 >> 24) & 0xf);
  const char *swizzle_z = i915_get_channel_swizzle((a1 >> 20) & 0xf);
  const char *swizzle_w = i915_get_channel_swizzle((a1 >> 16) & 0xf);
  char swizzle[100];
  i915_get_instruction_src_name((a0 >> 7) & 0x7, src_nr, srcname);
  sprintf(swizzle, ".%s%s%s%s", swizzle_x, swizzle_y, swizzle_z, swizzle_w);
  if (strcmp(swizzle, ".xyzw") != 0)
    strcat(srcname, swizzle);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<i915_get_instruction_src0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%ebp
  mov    0x4(%rdi,%rsi,4),%ebx
  mov    %ebx,%edi
  shr    $0x1c,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,%r13
  mov    %ebx,%edi
  sar    $0x18,%edi
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,%r14
  mov    %ebx,%edi
  sar    $0x14,%edi
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,%r15
  sar    $0x10,%ebx
  mov    %ebx,%edi
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %rax,%rbx
  mov    %ebp,%esi
  sar    $0x2,%esi
  and    $0x1f,%esi
  mov    %ebp,%edi
  sar    $0x7,%edi
  and    $0x7,%edi
  mov    %r12,%rdx
  call   <i915_get_instruction_src_name@plt>
  mov    %rsp,%rbp
  mov    %rbx,%r9
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L24
L23:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L23
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type_infered: string
name: parse_data
arguments: tag: D4
type_infered: string

tool: D15: .%s%s%s%s

tool: D4: .xyzw

assistant: ```c
void i915_get_instruction_src0(uint32_t *data, int i, char *srcname) {
  uint32_t a0 = data[i];
  uint32_t a1 = data[i + 1];
  int src_nr = (a0 >> 2) & 0x1f;
  const char *swizzle_x = i915_get_channel_swizzle((a1 >> 28) & 0xf);
  const char *swizzle_y = i915_get_channel_swizzle((a1 >> 24) & 0xf);
  const char *swizzle_z = i915_get_channel_swizzle((a1 >> 20) & 0xf);
  const char *swizzle_w = i915_get_channel_swizzle((a1 >> 16) & 0xf);
  char swizzle[100];
  i915_get_instruction_src_name((a0 >> 7) & 0x7, src_nr, srcname);
  sprintf(swizzle, ".%s%s%s%s", swizzle_x, swizzle_y, swizzle_z, swizzle_w);
  if (strcmp(swizzle, ".xyzw") != 0)
    strcat(srcname, swizzle);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i915_get_instruction_src0>:
  endbr64
  push   %r15
  movslq %esi,%rsi
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    0x4(%rdi,%rsi,4),%ebx
  mov    (%rdi,%rsi,4),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %ebx,%edi
  shr    $0x1c,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  sar    $0x18,%edi
  mov    %rax,%r13
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  sar    $0x10,%ebx
  sar    $0x14,%edi
  mov    %rax,%r14
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  and    $0xf,%edi
  mov    %rax,%r15
  call   <i915_get_channel_swizzle@plt>
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %r12,%rdx
  sar    $0x2,%esi
  sar    $0x7,%edi
  mov    %rax,%rbx
  mov    %rsp,%rbp
  and    $0x1f,%esi
  and    $0x7,%edi
  call   <i915_get_instruction_src_name@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r9
  mov    %r15,%r8
  lea    D18(%rip),%rsi
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <sprintf@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
L29:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L12:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L29
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
data_type: string
name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D18: .%s%s%s%s

tool: D3: .xyzw

assistant: ```c
void i915_get_instruction_src0(uint32_t *data, int i, char *srcname) {
  uint32_t a0 = data[i];
  uint32_t a1 = data[i + 1];
  int src_nr = (a0 >> 2) & 0x1f;
  const char *swizzle_x = i915_get_channel_swizzle((a1 >> 28) & 0xf);
  const char *swizzle_y = i915_get_channel_swizzle((a1 >> 24) & 0xf);
  const char *swizzle_z = i915_get_channel_swizzle((a1 >> 20) & 0xf);
  const char *swizzle_w = i915_get_channel_swizzle((a1 >> 16) & 0xf);
  char swizzle[100];
  i915_get_instruction_src_name((a0 >> 7) & 0x7, src_nr, srcname);
  sprintf(swizzle, ".%s%s%s%s", swizzle_x, swizzle_y, swizzle_z, swizzle_w);
  if (strcmp(swizzle, ".xyzw") != 0)
    strcat(srcname, swizzle);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<i915_get_instruction_src0>:
  endbr64
  push   %r15
  movslq %esi,%rsi
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    0x4(%rdi,%rsi,4),%ebx
  mov    (%rdi,%rsi,4),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %ebx,%edi
  shr    $0x1c,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  sar    $0x18,%edi
  mov    %rax,%r13
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  sar    $0x10,%ebx
  sar    $0x14,%edi
  mov    %rax,%r14
  and    $0xf,%edi
  call   <i915_get_channel_swizzle@plt>
  mov    %ebx,%edi
  and    $0xf,%edi
  mov    %rax,%r15
  call   <i915_get_channel_swizzle@plt>
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %r12,%rdx
  sar    $0x2,%esi
  sar    $0x7,%edi
  mov    %rax,%rbx
  mov    %rsp,%rbp
  and    $0x1f,%esi
  and    $0x7,%edi
  call   <i915_get_instruction_src_name@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r9
  mov    %r15,%r8
  lea    D17(%rip),%rsi
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <sprintf@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
L21:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L22:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L21
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type: string
name: disassemble_data
arguments: data_tag: D3
type: string

tool: D17: .%s%s%s%s

tool: D3: .xyzw

assistant: ```c
void i915_get_instruction_src0(uint32_t *data, int i, char *srcname) {
  uint32_t a0 = data[i];
  uint32_t a1 = data[i + 1];
  int src_nr = (a0 >> 2) & 0x1f;
  const char *swizzle_x = i915_get_channel_swizzle((a1 >> 28) & 0xf);
  const char *swizzle_y = i915_get_channel_swizzle((a1 >> 24) & 0xf);
  const char *swizzle_z = i915_get_channel_swizzle((a1 >> 20) & 0xf);
  const char *swizzle_w = i915_get_channel_swizzle((a1 >> 16) & 0xf);
  char swizzle[100];
  i915_get_instruction_src_name((a0 >> 7) & 0x7, src_nr, srcname);
  sprintf(swizzle, ".%s%s%s%s", swizzle_x, swizzle_y, swizzle_z, swizzle_w);
  if (strcmp(swizzle, ".xyzw") != 0)
    strcat(srcname, swizzle);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printEquation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L18:
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L31:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0x2,-0x4(%rbp)
  jle    L31
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: %d 

assistant: ```c
void printEquation(int *equ, int numClauses) {
  int ind = 0;
  for (int i = 0; i < numClauses; i++) {
    for (int j = 0; j < 3; j++)
      printf("%d ", equ[ind++]);
    printf("\n");
  }
}
```