ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode_color_characteristics>:
  endbr64
  push   %rbp
  mov    $0x7,%edx
  mov    %rsi,%rbp
  mov    $0x6,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl 0x19(%rdi),%edi
  call   <get_bits@plt>
  movzbl 0x1b(%rbx),%edi
  mov    %eax,%esi
  call   <decode_fraction@plt>
  mov    $0x4,%edx
  mov    $0x5,%esi
  movsd  %xmm0,0x0(%rbp)
  movzbl 0x19(%rbx),%edi
  call   <get_bits@plt>
  movzbl 0x1c(%rbx),%edi
  mov    %eax,%esi
  call   <decode_fraction@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  movsd  %xmm0,0x8(%rbp)
  movzbl 0x19(%rbx),%edi
  call   <get_bits@plt>
  movzbl 0x1d(%rbx),%edi
  mov    %eax,%esi
  call   <decode_fraction@plt>
  mov    $0x1,%edx
  xor    %esi,%esi
  movsd  %xmm0,0x10(%rbp)
  movzbl 0x19(%rbx),%edi
  call   <get_bits@plt>
  movzbl 0x1e(%rbx),%edi
  mov    %eax,%esi
  call   <decode_fraction@plt>
  mov    $0x7,%edx
  mov    $0x6,%esi
  movsd  %xmm0,0x18(%rbp)
  movzbl 0x1a(%rbx),%edi
  call   <get_bits@plt>
  movzbl 0x1f(%rbx),%edi
  mov    %eax,%esi
  call   <decode_fraction@plt>
  mov    $0x5,%edx
  mov    $0x4,%esi
  movsd  %xmm0,0x20(%rbp)
  movzbl 0x1a(%rbx),%edi
  call   <get_bits@plt>
  movzbl 0x20(%rbx),%edi
  mov    %eax,%esi
  call   <decode_fraction@plt>
  mov    $0x3,%edx
  mov    $0x2,%esi
  movsd  %xmm0,0x28(%rbp)
  movzbl 0x1a(%rbx),%edi
  call   <get_bits@plt>
  movzbl 0x21(%rbx),%edi
  mov    %eax,%esi
  call   <decode_fraction@plt>
  mov    $0x1,%edx
  xor    %esi,%esi
  movsd  %xmm0,0x30(%rbp)
  movzbl 0x1a(%rbx),%edi
  call   <get_bits@plt>
  movzbl 0x22(%rbx),%edi
  mov    %eax,%esi
  call   <decode_fraction@plt>
  mov    $0x1,%eax
  movsd  %xmm0,0x38(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int decode_color_characteristics(const unsigned char *edid, double *c) {
  c[0] = decode_fraction(edid[0x1b], get_bits(edid[0x19], 6, 7));
  c[1] = decode_fraction(edid[0x1c], get_bits(edid[0x19], 5, 4));
  c[2] = decode_fraction(edid[0x1d], get_bits(edid[0x19], 2, 3));
  c[3] = decode_fraction(edid[0x1e], get_bits(edid[0x19], 0, 1));
  c[4] = decode_fraction(edid[0x1f], get_bits(edid[0x1a], 6, 7));
  c[5] = decode_fraction(edid[0x20], get_bits(edid[0x1a], 4, 5));
  c[6] = decode_fraction(edid[0x21], get_bits(edid[0x1a], 2, 3));
  c[7] = decode_fraction(edid[0x22], get_bits(edid[0x1a], 0, 1));
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subtract_a_day>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <long_to_date@plt>
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L94
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  je     L8
  test   %eax,%eax
  jle    L59
  cmp    $0xc,%eax
  jg     L59
  cmp    $0x2,%eax
  jl     L59
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,%rdx
  and    $0xb54,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L122
  mov    %rax,%rdx
  and    $0x14a0,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L12
  and    $0x8,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L73
  jmp    L59
L8:
  movl   $0xc,-0x18(%rbp)
  movl   $0x1f,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L94
L122:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x1f,-0x14(%rbp)
  jmp    L94
L12:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x1e,-0x14(%rbp)
  jmp    L94
L73:
  movl   $0x2,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <is_leap_year@plt>
  test   %eax,%eax
  je     L154
  mov    $0x1d,%eax
  jmp    L87
L154:
  mov    $0x1c,%eax
L87:
  mov    %eax,-0x14(%rbp)
  jmp    L94
L59:
  mov    $0x0,%edi
  call   <assert@plt>
  nop
L94:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <date_to_long@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <is_valid_date@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

assistant: ```c
long subtract_a_day(long l) {
  int y, m, d;
  long_to_date(l, &y, &m, &d);
  --d;
  if (d < 1) {
    switch (m) {
    case 1:
      m = 12;
      d = 31;
      --y;
      break;
    case 2:
    case 4:
    case 6:
    case 8:
    case 9:
    case 11:
      --m;
      d = 31;
      break;
    case 5:
    case 7:
    case 10:
    case 12:
      --m;
      d = 30;
      break;
    case 3:
      m = 2;
      d = is_leap_year(y) ? 29 : 28;
      break;
    default:
      assert(0);
      break;
    }
  }
  long l2 = date_to_long(y, m, d);
  assert(is_valid_date(l2));
  return l2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<subtract_a_day>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <long_to_date@plt>
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  test   %eax,%eax
  jle    L9
L1:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <date_to_long@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <is_valid_date@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %rbx,%rax
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  mov    0x10(%rsp),%ecx
  cmp    $0x1,%ecx
  je     L32
  lea    -0x2(%rcx),%eax
  cmp    $0xa,%eax
  ja     L29
  mov    $0x1,%eax
  shl    %cl,%rax
  test   $0xb54,%eax
  je     L66
  sub    $0x1,%ecx
  mov    %ecx,0x10(%rsp)
  movl   $0x1f,0x14(%rsp)
  jmp    L1
L66:
  test   $0x14a0,%eax
  je     L38
  sub    $0x1,%ecx
  mov    %ecx,0x10(%rsp)
  movl   $0x1e,0x14(%rsp)
  jmp    L1
L38:
  cmp    $0x3,%ecx
  jne    L29
  movl   $0x2,0x10(%rsp)
  mov    0xc(%rsp),%edi
  call   <is_leap_year@plt>
  cmp    $0x1,%eax
  mov    $0x1c,%eax
  sbb    $0xffffffff,%eax
  mov    %eax,0x14(%rsp)
  jmp    L1
L32:
  movl   $0xc,0x10(%rsp)
  movl   $0x1f,0x14(%rsp)
  subl   $0x1,0xc(%rsp)
  jmp    L1
L29:
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L1
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long subtract_a_day(long l) {
  int y, m, d;
  long_to_date(l, &y, &m, &d);
  --d;
  if (d < 1) {
    switch (m) {
    case 1:
      m = 12;
      d = 31;
      --y;
      break;
    case 2:
    case 4:
    case 6:
    case 8:
    case 9:
    case 11:
      --m;
      d = 31;
      break;
    case 5:
    case 7:
    case 10:
    case 12:
      --m;
      d = 30;
      break;
    case 3:
      m = 2;
      d = is_leap_year(y) ? 29 : 28;
      break;
    default:
      assert(0);
      break;
    }
  }
  long l2 = date_to_long(y, m, d);
  assert(is_valid_date(l2));
  return l2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<subtract_a_day>:
  endbr64
  push   %r12
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x14(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  call   <long_to_date@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x14(%rsp)
  test   %edx,%edx
  jle    L62
L65:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
L99:
  call   <date_to_long@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <is_valid_date@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L62:
  mov    0x10(%rsp),%ecx
  cmp    $0x1,%ecx
  je     L98
  lea    -0x2(%rcx),%eax
  cmp    $0xa,%eax
  ja     L2
  mov    $0x1,%eax
  shl    %cl,%rax
  test   $0xb54,%eax
  je     L61
  lea    -0x1(%rcx),%esi
  mov    0xc(%rsp),%edi
  mov    $0x1f,%edx
  movl   $0x1f,0x14(%rsp)
  mov    %esi,0x10(%rsp)
  jmp    L99
  nopw   0x0(%rax,%rax,1)
L61:
  test   $0x14a0,%eax
  je     L90
  lea    -0x1(%rcx),%esi
  mov    0xc(%rsp),%edi
  mov    $0x1e,%edx
  movl   $0x1e,0x14(%rsp)
  mov    %esi,0x10(%rsp)
  jmp    L99
  nopl   0x0(%rax)
L2:
  xor    %edi,%edi
  call   <assert@plt>
  mov    0x14(%rsp),%edx
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L98:
  mov    0xc(%rsp),%eax
  mov    $0xc,%esi
  mov    $0x1f,%edx
  movl   $0xc,0x10(%rsp)
  movl   $0x1f,0x14(%rsp)
  lea    -0x1(%rax),%edi
  mov    %edi,0xc(%rsp)
  jmp    L99
  nopw   0x0(%rax,%rax,1)
L90:
  cmp    $0x3,%ecx
  jne    L2
  mov    0xc(%rsp),%edi
  movl   $0x2,0x10(%rsp)
  call   <is_leap_year@plt>
  mov    $0x1c,%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  cmp    $0x1,%eax
  sbb    $0xffffffff,%edx
  mov    %edx,0x14(%rsp)
  jmp    L99
L84:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long subtract_a_day(long l) {
  int y, m, d;
  long_to_date(l, &y, &m, &d);
  --d;
  if (d < 1) {
    switch (m) {
    case 1:
      m = 12;
      d = 31;
      --y;
      break;
    case 2:
    case 4:
    case 6:
    case 8:
    case 9:
    case 11:
      --m;
      d = 31;
      break;
    case 5:
    case 7:
    case 10:
    case 12:
      --m;
      d = 30;
      break;
    case 3:
      m = 2;
      d = is_leap_year(y) ? 29 : 28;
      break;
    default:
      assert(0);
      break;
    }
  }
  long l2 = date_to_long(y, m, d);
  assert(is_valid_date(l2));
  return l2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<subtract_a_day>:
  endbr64
  push   %r12
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x14(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  call   <long_to_date@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x14(%rsp)
  test   %edx,%edx
  jle    L98
L117:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
L40:
  call   <date_to_long@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <is_valid_date@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L98:
  mov    0x10(%rsp),%ecx
  cmp    $0x1,%ecx
  je     L97
  lea    -0x2(%rcx),%eax
  cmp    $0xa,%eax
  ja     L95
  mov    $0x1,%eax
  shl    %cl,%rax
  test   $0xb54,%eax
  je     L51
  lea    -0x1(%rcx),%esi
  mov    0xc(%rsp),%edi
  mov    $0x1f,%edx
  movl   $0x1f,0x14(%rsp)
  mov    %esi,0x10(%rsp)
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L51:
  test   $0x14a0,%eax
  je     L77
  lea    -0x1(%rcx),%esi
  mov    0xc(%rsp),%edi
  mov    $0x1e,%edx
  movl   $0x1e,0x14(%rsp)
  mov    %esi,0x10(%rsp)
  jmp    L40
  nopl   0x0(%rax)
L95:
  xor    %edi,%edi
  call   <assert@plt>
  mov    0x14(%rsp),%edx
  jmp    L117
  nopl   0x0(%rax,%rax,1)
L97:
  mov    0xc(%rsp),%eax
  mov    $0xc,%esi
  mov    $0x1f,%edx
  movl   $0xc,0x10(%rsp)
  movl   $0x1f,0x14(%rsp)
  lea    -0x1(%rax),%edi
  mov    %edi,0xc(%rsp)
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L77:
  cmp    $0x3,%ecx
  jne    L95
  mov    0xc(%rsp),%edi
  movl   $0x2,0x10(%rsp)
  call   <is_leap_year@plt>
  mov    $0x1c,%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  cmp    $0x1,%eax
  sbb    $0xffffffff,%edx
  mov    %edx,0x14(%rsp)
  jmp    L40
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long subtract_a_day(long l) {
  int y, m, d;
  long_to_date(l, &y, &m, &d);
  --d;
  if (d < 1) {
    switch (m) {
    case 1:
      m = 12;
      d = 31;
      --y;
      break;
    case 2:
    case 4:
    case 6:
    case 8:
    case 9:
    case 11:
      --m;
      d = 31;
      break;
    case 5:
    case 7:
    case 10:
    case 12:
      --m;
      d = 30;
      break;
    case 3:
      m = 2;
      d = is_leap_year(y) ? 29 : 28;
      break;
    default:
      assert(0);
      break;
    }
  }
  long l2 = date_to_long(y, m, d);
  assert(is_valid_date(l2));
  return l2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<TimerDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  cltq
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%eax
  and    $0x101,%eax
  not    %eax
  movslq %eax,%rcx
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  cltq
  mov    %rax,%rdx
  mov    %rsi,%rax
  and    %rcx,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TimerDisable(uint32_t ui32Base, uint32_t ui32Timer) {
  ;

  ;
  (*((volatile unsigned long *)(ui32Base + 0x0000000C))) &= ~(ui32Timer & (0x00000001 | 0x00000100));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TimerDisable>:
  endbr64
  add    $0xc,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rax
  and    $0x101,%esi
  not    %esi
  movslq %esi,%rsi
  and    %rax,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void TimerDisable(uint32_t ui32Base, uint32_t ui32Timer) {
  ;

  ;
  (*((volatile unsigned long *)(ui32Base + 0x0000000C))) &= ~(ui32Timer & (0x00000001 | 0x00000100));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TimerDisable>:
  endbr64
  add    $0xc,%edi
  and    $0x101,%esi
  movslq %edi,%rdi
  not    %esi
  mov    (%rdi),%rax
  movslq %esi,%rsi
  and    %rax,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void TimerDisable(uint32_t ui32Base, uint32_t ui32Timer) {
  ;

  ;
  (*((volatile unsigned long *)(ui32Base + 0x0000000C))) &= ~(ui32Timer & (0x00000001 | 0x00000100));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<TimerDisable>:
  endbr64
  add    $0xc,%edi
  and    $0x101,%esi
  movslq %edi,%rdi
  not    %esi
  mov    (%rdi),%rax
  movslq %esi,%rsi
  and    %rax,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void TimerDisable(uint32_t ui32Base, uint32_t ui32Timer) {
  ;

  ;
  (*((volatile unsigned long *)(ui32Base + 0x0000000C))) &= ~(ui32Timer & (0x00000001 | 0x00000100));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L6:
  cmpl   $0x0,-0x14(%rbp)
  je     L4
  addl   $0x1,-0x4(%rbp)
L4:
  addl   $0x1,-0x8(%rbp)
L15:
  cmpl   $0x63,-0x8(%rbp)
  jle    L6
  cmpl   $0x0,-0x14(%rbp)
  je     L11
  cmpl   $0x64,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <static_assert@plt>
L11:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int flag, int a) {
  int b;
  int j = 0;
  for (b = 0; b < 100; ++b) {
    if (flag)
      j = j + 1;
  }
  if (flag)
    static_assert(j == 100);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  mov    $0x64,%eax
  mov    $0x0,%edx
L13:
  cmp    $0x1,%edi
  sbb    $0xffffffff,%edx
  sub    $0x1,%eax
  jne    L13
  test   %edi,%edi
  jne    L2
  mov    $0x0,%eax
  ret
L2:
  sub    $0x8,%rsp
  cmp    $0x64,%edx
  sete   %dil
  movzbl %dil,%edi
  call   <static_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int flag, int a) {
  int b;
  int j = 0;
  for (b = 0; b < 100; ++b) {
    if (flag)
      j = j + 1;
  }
  if (flag)
    static_assert(j == 100);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x64,%eax
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L4:
  cmp    $0x1,%edi
  sbb    $0xffffffff,%edx
  sub    $0x1,%eax
  jne    L4
  test   %edi,%edi
  jne    L5
  xor    %eax,%eax
  ret
L5:
  push   %rax
  xor    %edi,%edi
  cmp    $0x64,%edx
  sete   %dil
  call   <static_assert@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

assistant: ```c
int main(int flag, int a) {
  int b;
  int j = 0;
  for (b = 0; b < 100; ++b) {
    if (flag)
      j = j + 1;
  }
  if (flag)
    static_assert(j == 100);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  test   %edi,%edi
  je     L6
  push   %rax
  mov    $0x1,%edi
  call   <static_assert@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int flag, int a) {
  int b;
  int j = 0;
  for (b = 0; b < 100; ++b) {
    if (flag)
      j = j + 1;
  }
  if (flag)
    static_assert(j == 100);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<oneAway>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jg     L85
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jle    L15
L85:
  mov    $0x0,%eax
  jmp    L10
L15:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L76
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L76:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L34:
  movl   $0x0,-0x1c(%rbp)
  jmp    L13
L27:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L55
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L105
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L10
L105:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L10
L55:
  addl   $0x1,-0x1c(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L27
  mov    $0x1,%eax
L10:
  leave
  ret
```

assistant: ```c
bool oneAway(char str1[], char str2[]) {
  int len1 = strlen(str1);
  int len2 = strlen(str2);
  if (len1 - len2 > 1 || len2 - len1 > 1) {
    return false;
  }
  char *bigStr;
  char *smallStr;
  int smallLen;
  if (len1 > len2) {
    smallLen = len2;
    bigStr = str1;
    smallStr = str2;
  } else {
    smallLen = len1;
    bigStr = str2;
    smallStr = str1;
  }
  for (int i = 0; i < smallLen; i++) {
    if (bigStr[i] != smallStr[i]) {
      if (len1 != len2) {
        return strcmp(bigStr + (i + 1) * sizeof(char), smallStr + i * sizeof(char)) == 0;
      } else {
        return strcmp(bigStr + (i + 1) * sizeof(char), smallStr + (i + 1) * sizeof(char)) == 0;
      }
    }
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<oneAway>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12d,%ecx
  sub    %eax,%ecx
  mov    $0x0,%edx
  cmp    $0x1,%ecx
  jg     L48
  mov    %eax,%ecx
  sub    %r12d,%ecx
  cmp    $0x1,%ecx
  jg     L48
  mov    %eax,%ecx
  cmp    %eax,%r12d
  jg     L88
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rbp
  mov    %rdx,%rbx
L88:
  test   %ecx,%ecx
  jle    L94
  mov    %ecx,%ecx
  mov    $0x0,%edx
L17:
  mov    %edx,%esi
  lea    (%rbx,%rdx,1),%r8
  movzbl (%rbx,%rdx,1),%edi
  cmp    %dil,0x0(%rbp,%rdx,1)
  jne    L25
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L17
  mov    $0x1,%edx
L48:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  cmp    %eax,%r12d
  je     L71
  lea    0x1(%rdx),%edi
  movslq %edi,%rdi
  add    %rbp,%rdi
  mov    %r8,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L48
L71:
  add    $0x1,%esi
  movslq %esi,%rax
  lea    (%rbx,%rax,1),%rsi
  lea    0x0(%rbp,%rax,1),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L48
L94:
  mov    $0x1,%edx
  jmp    L48
```

assistant: ```c
bool oneAway(char str1[], char str2[]) {
  int len1 = strlen(str1);
  int len2 = strlen(str2);
  if (len1 - len2 > 1 || len2 - len1 > 1) {
    return false;
  }
  char *bigStr;
  char *smallStr;
  int smallLen;
  if (len1 > len2) {
    smallLen = len2;
    bigStr = str1;
    smallStr = str2;
  } else {
    smallLen = len1;
    bigStr = str2;
    smallStr = str1;
  }
  for (int i = 0; i < smallLen; i++) {
    if (bigStr[i] != smallStr[i]) {
      if (len1 != len2) {
        return strcmp(bigStr + (i + 1) * sizeof(char), smallStr + i * sizeof(char)) == 0;
      } else {
        return strcmp(bigStr + (i + 1) * sizeof(char), smallStr + (i + 1) * sizeof(char)) == 0;
      }
    }
  }
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<oneAway>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r12d,%edx
  xor    %r8d,%r8d
  sub    %eax,%edx
  cmp    $0x1,%edx
  jg     L82
  mov    %eax,%edx
  sub    %r12d,%edx
  cmp    $0x1,%edx
  jg     L82
  movslq %eax,%rcx
  cmp    %eax,%r12d
  jle    L15
L98:
  test   %ecx,%ecx
  jle    L53
  xor    %edx,%edx
  jmp    L45
  nopl   (%rax)
L22:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L53
L45:
  movzbl (%rbx,%rdx,1),%edi
  lea    (%rbx,%rdx,1),%r8
  lea    0x1(%rdx),%esi
  cmp    %dil,0x0(%rbp,%rdx,1)
  je     L22
  movslq %esi,%rsi
  lea    0x0(%rbp,%rsi,1),%rdi
  cmp    %eax,%r12d
  je     L70
  mov    %r8,%rsi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L82:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rdx
  movslq %r12d,%rcx
  mov    %rbx,%rbp
  mov    %rdx,%rbx
  jmp    L98
  xchg   %ax,%ax
L53:
  mov    $0x1,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L70:
  add    %rbx,%rsi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
  jmp    L82
```

assistant: ```c
bool oneAway(char str1[], char str2[]) {
  int len1 = strlen(str1);
  int len2 = strlen(str2);
  if (len1 - len2 > 1 || len2 - len1 > 1) {
    return false;
  }
  char *bigStr;
  char *smallStr;
  int smallLen;
  if (len1 > len2) {
    smallLen = len2;
    bigStr = str1;
    smallStr = str2;
  } else {
    smallLen = len1;
    bigStr = str2;
    smallStr = str1;
  }
  for (int i = 0; i < smallLen; i++) {
    if (bigStr[i] != smallStr[i]) {
      if (len1 != len2) {
        return strcmp(bigStr + (i + 1) * sizeof(char), smallStr + i * sizeof(char)) == 0;
      } else {
        return strcmp(bigStr + (i + 1) * sizeof(char), smallStr + (i + 1) * sizeof(char)) == 0;
      }
    }
  }
  return true;
}
```