user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<atof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rdi,%rbx
  mov    $0x0,%r12d
  jmp    L18
L80:
  add    $0x1,%r12d
L18:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L80
  movzbl 0x0(%rbp),%eax
  cmp    $0x2d,%al
  je     L64
  sub    $0x2b,%eax
  movl   $0x1,0x1c(%rsp)
  test   $0xfd,%al
  je     L166
L191:
  movslq %r12d,%r14
  add    %r13,%r14
  mov    %r14,%rbx
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
  jmp    L147
L64:
  movl   $0xffffffff,0x1c(%rsp)
L166:
  add    $0x1,%r12d
  jmp    L191
L83:
  movsd  0x8(%rsp),%xmm0
  mulsd  D24(%rip),%xmm0
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  add    $0x1,%rbx
L147:
  mov    %r12d,%ebp
  sub    %r14d,%ebp
  add    %ebx,%ebp
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L83
  cmpb   $0x2e,(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebp
  movslq %ebp,%r14
  add    %r13,%r14
  mov    %r14,%rbx
  movsd  D16(%rip),%xmm6
  movsd  %xmm6,0x10(%rsp)
  jmp    L8
L34:
  movsd  0x8(%rsp),%xmm0
  mulsd  D24(%rip),%xmm0
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  movsd  0x10(%rsp),%xmm2
  mulsd  D24(%rip),%xmm2
  movsd  %xmm2,0x10(%rsp)
  add    $0x1,%rbx
L8:
  mov    %ebp,%r12d
  sub    %r14d,%r12d
  add    %ebx,%r12d
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L34
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x1c(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  movq   %xmm0,%rbp
  movzbl (%rbx),%eax
  and    $0xffffffdf,%eax
  cmp    $0x45,%al
  jne    L118
  lea    0x1(%r12),%ebx
  movslq %ebx,%rax
  movzbl 0x0(%r13,%rax,1),%eax
  cmp    $0x2d,%al
  je     L56
  sub    $0x2b,%eax
  mov    $0x1,%r14d
  test   $0xfd,%al
  je     L112
L206:
  movslq %ebx,%rbx
  add    %r13,%rbx
  mov    $0x0,%r12d
L57:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L202
  lea    (%r12,%r12,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%r12d
  add    $0x1,%rbx
  jmp    L57
L56:
  mov    $0xffffffff,%r14d
L112:
  lea    0x2(%r12),%ebx
  jmp    L206
L202:
  cmp    $0x1,%r14d
  je     L87
  lea    -0x1(%r12),%eax
  movsd  D24(%rip),%xmm0
  test   %r12d,%r12d
  jle    L118
L153:
  movq   %rbp,%xmm3
  divsd  %xmm0,%xmm3
  movq   %xmm3,%rbp
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  jne    L153
L118:
  movq   %rbp,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L87:
  lea    -0x1(%r12),%eax
  test   %r12d,%r12d
  jle    L118
  movsd  D24(%rip),%xmm0
L88:
  movq   %rbp,%xmm4
  mulsd  %xmm0,%xmm4
  movq   %xmm4,%rbp
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  jne    L88
  jmp    L118
```

tool_calls: name: unpack_data
arguments: label: D24
data_type: f64
name: unpack_data
arguments: label: D16
data_type: f64

tool: D24: 10

tool: D16: 1

assistant: ```c
double atof(char s[]) {
  double val, power;
  int exp, i, sign;
  for (i = 0; isspace(s[i]); i++)
    ;
  sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  for (val = 0.0; isdigit(s[i]); i++)
    val = 10.0 * val + (s[i] - '0');
  if (s[i] == '.')
    i++;
  for (power = 1.0; isdigit(s[i]); i++) {
    val = 10.0 * val + (s[i] - '0');
    power *= 10.0;
  }
  val = sign * val / power;
  if (s[i] == 'e' || s[i] == 'E') {
    sign = (s[++i] == '-') ? -1 : 1;
    if (s[i] == '+' || s[i] == '-')
      i++;
    for (exp = 0; isdigit(s[i]); i++)
      exp = 10 * exp + (s[i] - '0');
    if (sign == 1)
      while (exp-- > 0)
        val *= 10;
    else
      while (exp-- > 0)
        val /= 10;
  }
  return val;
}
```