ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <read_str_array@plt>
  mov    %rax,%rbx
  mov    0x10(%rsp),%rax
  lea    0x2(%rax),%rcx
  mov    %rcx,0x10(%rsp)
  mov    $0x50,%eax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,%rbp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rcx
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <print_str_array@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <quick_sort1_desc@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rcx
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <print_str_array@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string
name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D8: [Before sorting]


tool: D6: [After sorting]


assistant: ```c
int main() {
  size_t i = 0, n = 0, col_width = 0, col_num = 0, l = 0;
  char **data = read_str_array(&n, &col_width);
  col_width += 2;
  col_num = 80 / col_width;
  printf("[Before sorting]\n");
  print_str_array(data, n, col_width, col_num);
  quick_sort1_desc((void **)data, n);
  printf("[After sorting]\n");
  print_str_array(data, n, col_width, col_num);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <read_str_array@plt>
  xor    %edx,%edx
  lea    D16(%rip),%rdi
  mov    %rax,%rbp
  mov    0x10(%rsp),%rax
  lea    0x2(%rax),%rcx
  mov    $0x50,%eax
  div    %rcx
  mov    %rcx,0x10(%rsp)
  mov    %rax,%r12
  call   <printf@plt>
  mov    0x10(%rsp),%rdx
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    0x8(%rsp),%rsi
  call   <print_str_array@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <quick_sort1_desc@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rdx
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    0x8(%rsp),%rsi
  call   <print_str_array@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D8
type_infered: string

tool: D16: [Before sorting]


tool: D8: [After sorting]


assistant: ```c
int main() {
  size_t i = 0, n = 0, col_width = 0, col_num = 0, l = 0;
  char **data = read_str_array(&n, &col_width);
  col_width += 2;
  col_num = 80 / col_width;
  printf("[Before sorting]\n");
  print_str_array(data, n, col_width, col_num);
  quick_sort1_desc((void **)data, n);
  printf("[After sorting]\n");
  print_str_array(data, n, col_width, col_num);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <read_str_array@plt>
  xor    %edx,%edx
  lea    D8(%rip),%rdi
  mov    %rax,%rbp
  mov    0x10(%rsp),%rax
  lea    0x2(%rax),%rcx
  mov    $0x50,%eax
  div    %rcx
  mov    %rcx,0x10(%rsp)
  mov    %rax,%r12
  call   <printf@plt>
  mov    0x10(%rsp),%rdx
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    0x8(%rsp),%rsi
  call   <print_str_array@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <quick_sort1_desc@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rdx
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    0x8(%rsp),%rsi
  call   <print_str_array@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string
name: retrieve_data
arguments: data_tag: D12
type: string

tool: D8: [Before sorting]


tool: D12: [After sorting]


assistant: ```c
int main() {
  size_t i = 0, n = 0, col_width = 0, col_num = 0, l = 0;
  char **data = read_str_array(&n, &col_width);
  col_width += 2;
  col_num = 80 / col_width;
  printf("[Before sorting]\n");
  print_str_array(data, n, col_width, col_num);
  quick_sort1_desc((void **)data, n);
  printf("[After sorting]\n");
  print_str_array(data, n, col_width, col_num);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strmdelsp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r12
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x48(%rbp)
  je     L61
  mov    %rsp,%rax
  mov    %rax,%r12
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strmlen@plt>
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L40:
  cmp    %rdx,%rsp
  je     L75
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L40
L75:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L35
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L35:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x30(%rbp)
  mov    $0x1,%ebx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strmlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x48(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L39
L5:
  lea    -0x1(%rbx),%ecx
  mov    -0x30(%rbp),%rax
  mov    %ebx,%edx
  movzbl (%rax,%rdx,1),%edx
  mov    -0x30(%rbp),%rax
  mov    %ecx,%ecx
  mov    %dl,(%rax,%rcx,1)
  mov    -0x30(%rbp),%rax
  mov    %ebx,%edx
  movzbl (%rax,%rdx,1),%eax
  cmp    $0x1f,%al
  jg     L73
  sub    $0x1,%ebx
  mov    -0x30(%rbp),%rax
  mov    %ebx,%edx
  movb   $0x0,(%rax,%rdx,1)
L73:
  add    $0x1,%ebx
L39:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strmlen@plt>
  cmp    %eax,%ebx
  jb     L5
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strmlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rsp
L61:
  nop
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void strmdelsp(char *s) {
  if (s != NULL) {
    char test[strmlen(s) + 1];
    register unsigned int counter = 1;
    memcpy(test, s, strmlen(s) + 1);
    for (; counter < (strmlen(test)); ++counter) {
      test[counter - 1] = test[counter];
      if (test[counter] < 32)
        test[--counter] = 0;
    }
    memcpy(s, test, strmlen(test) + 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strmdelsp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L16
  mov    %rdi,%r13
  mov    %rsp,%r15
  call   <strmlen@plt>
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L69:
  cmp    %rdx,%rsp
  je     L44
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L69
L44:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L12
  orq    $0x0,-0x8(%rsp,%rax,1)
L12:
  mov    %rsp,%r12
  mov    %r13,%rdi
  call   <strmlen@plt>
  lea    0x1(%rax),%edx
  mov    %r13,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    $0x1,%ebx
  mov    $0x0,%r14d
  jmp    L67
L8:
  mov    %eax,%ebx
  mov    %r14d,%edx
L21:
  mov    %eax,%eax
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%ebx
L67:
  mov    %r12,%rdi
  call   <strmlen@plt>
  cmp    %ebx,%eax
  jbe    L79
  lea    -0x1(%rbx),%eax
  mov    %ebx,%edx
  movzbl (%r12,%rdx,1),%edx
  mov    %eax,%ecx
  mov    %dl,(%r12,%rcx,1)
  cmp    $0x1f,%dl
  jle    L8
  mov    %eax,%edx
  movzbl (%r12,%rdx,1),%edx
  jmp    L21
L79:
  mov    %r12,%rdi
  call   <strmlen@plt>
  lea    0x1(%rax),%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r15,%rsp
L16:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strmdelsp(char *s) {
  if (s != NULL) {
    char test[strmlen(s) + 1];
    register unsigned int counter = 1;
    memcpy(test, s, strmlen(s) + 1);
    for (; counter < (strmlen(test)); ++counter) {
      test[counter - 1] = test[counter];
      if (test[counter] < 32)
        test[--counter] = 0;
    }
    memcpy(s, test, strmlen(test) + 1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strmdelsp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L11
  mov    %rdi,%r12
  mov    %rsp,%r13
  call   <strmlen@plt>
  mov    %rsp,%rcx
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L76
L19:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L19
L76:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L13
  orq    $0x0,-0x8(%rsp,%rdx,1)
L13:
  mov    %r12,%rdi
  mov    %rsp,%r14
  mov    $0x1,%ebx
  call   <strmlen@plt>
  mov    %r12,%rsi
  mov    %rsp,%rdi
  lea    0x1(%rax),%edx
  call   <memcpy@plt>
  jmp    L70
L67:
  add    $0x1,%ebx
L57:
  mov    %dl,(%r14,%rax,1)
L70:
  mov    %r14,%rdi
  call   <strmlen@plt>
  cmp    %ebx,%eax
  jbe    L21
  mov    %ebx,%edx
  lea    -0x1(%rbx),%eax
  movzbl (%r14,%rdx,1),%edx
  cmp    $0x1f,%dl
  jg     L67
  xor    %edx,%edx
  jmp    L57
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %r14,%rdi
  call   <strmlen@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%edx
  call   <memcpy@plt>
  mov    %r13,%rsp
L11:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strmdelsp(char *s) {
  if (s != NULL) {
    char test[strmlen(s) + 1];
    register unsigned int counter = 1;
    memcpy(test, s, strmlen(s) + 1);
    for (; counter < (strmlen(test)); ++counter) {
      test[counter - 1] = test[counter];
      if (test[counter] < 32)
        test[--counter] = 0;
    }
    memcpy(s, test, strmlen(test) + 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strmdelsp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L15
  mov    %rdi,%r12
  mov    %rsp,%r13
  call   <strmlen@plt>
  mov    %rsp,%rcx
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L71
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L38
L71:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L63
  orq    $0x0,-0x8(%rsp,%rdx,1)
L63:
  mov    %r12,%rdi
  mov    %rsp,%r14
  mov    $0x1,%ebx
  call   <strmlen@plt>
  mov    %r12,%rsi
  mov    %rsp,%rdi
  lea    0x1(%rax),%edx
  call   <memcpy@plt>
  jmp    L64
L86:
  add    $0x1,%ebx
L5:
  mov    %dl,(%r14,%rax,1)
L64:
  mov    %r14,%rdi
  call   <strmlen@plt>
  cmp    %ebx,%eax
  jbe    L76
  mov    %ebx,%edx
  lea    -0x1(%rbx),%eax
  movzbl (%r14,%rdx,1),%edx
  cmp    $0x1f,%dl
  jg     L86
  xor    %edx,%edx
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L76:
  mov    %r14,%rdi
  call   <strmlen@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%edx
  call   <memcpy@plt>
  mov    %r13,%rsp
L15:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strmdelsp(char *s) {
  if (s != NULL) {
    char test[strmlen(s) + 1];
    register unsigned int counter = 1;
    memcpy(test, s, strmlen(s) + 1);
    for (; counter < (strmlen(test)); ++counter) {
      test[counter - 1] = test[counter];
      if (test[counter] < 32)
        test[--counter] = 0;
    }
    memcpy(s, test, strmlen(test) + 1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<varfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L22
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L22:
  cmpl   $0x0,-0xb4(%rbp)
  je     L26
  mov    -0xb4(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <varfunc>
  jmp    L29
L26:
  nop
L29:
  mov    $0x17,%eax
  leave
  ret
```

assistant: ```c
int varfunc(int num, ...) {
  if (!num)
    goto end;
  varfunc(num - 1, 0, 0);
end:
  return 23;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<varfunc>:
  endbr64
  test   %edi,%edi
  jne    L5
  mov    $0x17,%eax
  ret
L5:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%eax
  call   <varfunc>
  mov    $0x17,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int varfunc(int num, ...) {
  if (!num)
    goto end;
  varfunc(num - 1, 0, 0);
end:
  return 23;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<varfunc>:
  endbr64
  cmp    $0x3,%edi
  ja     L3
  mov    $0x17,%eax
  ret
  nop
L3:
  sub    $0x8,%rsp
  sub    $0x4,%edi
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %eax,%eax
  call   <varfunc>
  mov    $0x17,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int varfunc(int num, ...) {
  if (!num)
    goto end;
  varfunc(num - 1, 0, 0);
end:
  return 23;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<varfunc>:
  endbr64
  cmp    $0x3,%edi
  ja     L4
  mov    $0x17,%eax
  ret
  nop
L4:
  sub    $0x8,%rsp
  sub    $0x4,%edi
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %eax,%eax
  call   <varfunc>
  mov    $0x17,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int varfunc(int num, ...) {
  if (!num)
    goto end;
  varfunc(num - 1, 0, 0);
end:
  return 23;
}
```
user: Translate the below assembly code into C programming language:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %esi,-0xc8(%rbp)
  mov    %rdx,-0xd0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L48
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L48:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  cmpl   $0x0,-0xc8(%rbp)
  jne    L52
  cmpl   $0x0,-0xc4(%rbp)
  jne    L67
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vwarnx@plt>
  jmp    L5
L67:
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <verrx@plt>
  jmp    L5
L52:
  cmpl   $0x0,-0xc4(%rbp)
  jne    L0
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vwarn@plt>
  jmp    L5
L0:
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <verr@plt>
L5:
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(int status, int errnum, const char *format, ...) {
  va_list arg;
  va_start(arg, format);
  if (errnum == 0) {
    if (status == 0)
      vwarnx(format, arg);
    else
      verrx(status, format, arg);
  } else {
    if (status == 0)
      vwarn(format, arg);
    else
      verr(status, format, arg);
  }
  va_end(arg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%edi
  call   <va_start@plt>
  test   %r12d,%r12d
  jne    L45
  test   %ebp,%ebp
  jne    L56
  mov    $0x0,%edi
  mov    %edi,%esi
  mov    %rbx,%rdi
  call   <vwarnx@plt>
L0:
  mov    $0x0,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  mov    $0x0,%edi
  mov    %edi,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <verrx@plt>
  jmp    L0
L45:
  test   %ebp,%ebp
  jne    L44
  mov    $0x0,%edi
  mov    %edi,%esi
  mov    %rbx,%rdi
  call   <vwarn@plt>
  jmp    L0
L44:
  mov    $0x0,%edi
  mov    %edi,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <verr@plt>
  jmp    L0
```

assistant: ```c
void error(int status, int errnum, const char *format, ...) {
  va_list arg;
  va_start(arg, format);
  if (errnum == 0) {
    if (status == 0)
      vwarnx(format, arg);
    else
      verrx(status, format, arg);
  } else {
    if (status == 0)
      vwarn(format, arg);
    else
      verr(status, format, arg);
  }
  va_end(arg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<error>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  call   <va_start@plt>
  xor    %edi,%edi
  test   %ebx,%ebx
  jne    L22
  test   %r12d,%r12d
  jne    L27
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <vwarnx@plt>
  xor    %edi,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  test   %r12d,%r12d
  je     L20
  mov    %edi,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <verr@plt>
  xor    %edi,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L20:
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <vwarn@plt>
  xor    %edi,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %edi,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <verrx@plt>
  xor    %edi,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(int status, int errnum, const char *format, ...) {
  va_list arg;
  va_start(arg, format);
  if (errnum == 0) {
    if (status == 0)
      vwarnx(format, arg);
    else
      verrx(status, format, arg);
  } else {
    if (status == 0)
      vwarn(format, arg);
    else
      verr(status, format, arg);
  }
  va_end(arg);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<error>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  call   <va_start@plt>
  xor    %edi,%edi
  test   %ebx,%ebx
  jne    L26
  test   %r12d,%r12d
  jne    L29
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <vwarnx@plt>
  xor    %edi,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  test   %r12d,%r12d
  je     L4
  mov    %edi,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <verr@plt>
  xor    %edi,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L4:
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <vwarn@plt>
  xor    %edi,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    %edi,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <verrx@plt>
  xor    %edi,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(int status, int errnum, const char *format, ...) {
  va_list arg;
  va_start(arg, format);
  if (errnum == 0) {
    if (status == 0)
      vwarnx(format, arg);
    else
      verrx(status, format, arg);
  } else {
    if (status == 0)
      vwarn(format, arg);
    else
      verr(status, format, arg);
  }
  va_end(arg);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <sub@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string

tool: D15: sum = %d


tool: D17: sub = %d


assistant: ```c
int main() {
  printf("sum = %d\n", add(5, 3));
  printf("sub = %d\n", sub(5, 3));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <sub@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D12
type_infered: string

tool: D10: sum = %d


tool: D12: sub = %d


assistant: ```c
int main() {
  printf("sum = %d\n", add(5, 3));
  printf("sub = %d\n", sub(5, 3));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <add@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <sub@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D8: sum = %d


tool: D2: sub = %d


assistant: ```c
int main() {
  printf("sum = %d\n", add(5, 3));
  printf("sub = %d\n", sub(5, 3));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <add@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <sub@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string
name: read_data
arguments: tag: D11
datatype: string

tool: D9: sum = %d


tool: D11: sub = %d


assistant: ```c
int main() {
  printf("sum = %d\n", add(5, 3));
  printf("sub = %d\n", sub(5, 3));
  return 0;
}
```