ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<deduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x13,-0x8(%rbp)
  jmp    L85
L106:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jb     L97
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L84
L97:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L101:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L38
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  sub    $0x1,%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L84
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0xff,(%rax)
  subl   $0x1,-0x4(%rbp)
  jmp    L101
L84:
  subl   $0x1,-0x8(%rbp)
L85:
  mov    $0x13,%eax
  sub    -0x1c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L106
  mov    $0x13,%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L78
L25:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L57
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x8(%rbp)
L78:
  cmpl   $0x13,-0x8(%rbp)
  jle    L25
  jmp    L30
L57:
  nop
L30:
  mov    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int deduct(unsigned char *a, int a_len, unsigned char *b, int b_len) {
  int i, j, k;
  for (i = 20 - 1; i >= 20 - 1 - a_len; i--) {
    if (a[i] >= b[i])
      a[i] -= b[i];
    else {
      j = i - 1;
      while (1) {
        if (a[j] > 0) {
          a[j]--;
          a[i] += 256 - b[i];
          break;
        } else
          a[j] = 255;
        j--;
      }
    }
  }
  for (i = 20 - 1 - a_len; i <= 20 - 1; i++) {
    if (a[i] > 0)
      break;
    else {
      a[i] = 0;
      a_len--;
    }
  }
  return a_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<deduct>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%eax
  mov    $0x13,%ebx
  sub    %esi,%ebx
  cmp    $0x13,%ebx
  jg     L5
  mov    %rdi,%r9
  mov    %rdx,%r11
  lea    0x12(%rdi),%rdi
  mov    %esi,%edx
  mov    $0x11,%ebp
  sub    %rdx,%rbp
  mov    $0x12,%r8d
  jmp    L44
L1:
  movzbl (%rdi),%ecx
  lea    -0x1(%rdi),%rdx
  mov    %rdi,%rsi
  test   %cl,%cl
  jne    L63
L56:
  movb   $0xff,(%rsi)
  mov    %rdx,%rsi
  sub    $0x1,%rdx
  movzbl 0x1(%rdx),%ecx
  test   %cl,%cl
  je     L56
L63:
  sub    $0x1,%ecx
  mov    %cl,(%rsi)
  movzbl 0x1(%r10),%edx
  sub    0x1(%r11,%r8,1),%dl
L83:
  mov    %dl,0x1(%r10)
  sub    $0x1,%r8
  sub    $0x1,%rdi
  cmp    %rbp,%r8
  je     L26
L44:
  mov    %rdi,%r10
  movzbl 0x1(%rdi),%edx
  movzbl 0x1(%r11,%r8,1),%ecx
  cmp    %cl,%dl
  jb     L1
  sub    %ecx,%edx
  jmp    L83
L26:
  movslq %ebx,%rdx
  add    %r9,%rdx
  lea    -0x14(%rbx,%rax,1),%ecx
L66:
  cmpb   $0x0,(%rdx)
  jne    L5
  sub    $0x1,%eax
  add    $0x1,%rdx
  cmp    %eax,%ecx
  jne    L66
  mov    %ecx,%eax
L5:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int deduct(unsigned char *a, int a_len, unsigned char *b, int b_len) {
  int i, j, k;
  for (i = 20 - 1; i >= 20 - 1 - a_len; i--) {
    if (a[i] >= b[i])
      a[i] -= b[i];
    else {
      j = i - 1;
      while (1) {
        if (a[j] > 0) {
          a[j]--;
          a[i] += 256 - b[i];
          break;
        } else
          a[j] = 255;
        j--;
      }
    }
  }
  for (i = 20 - 1 - a_len; i <= 20 - 1; i++) {
    if (a[i] > 0)
      break;
    else {
      a[i] = 0;
      a_len--;
    }
  }
  return a_len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<deduct>:
  endbr64
  mov    $0x13,%r11d
  mov    %esi,%eax
  sub    %esi,%r11d
  cmp    $0x13,%r11d
  jg     L26
  push   %rbp
  mov    %rdx,%r10
  mov    %eax,%edx
  mov    %rdi,%r9
  push   %rbx
  mov    $0x11,%ebx
  lea    0x12(%rdi),%rsi
  mov    $0x12,%r8d
  sub    %rdx,%rbx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L13:
  sub    %ecx,%edx
  lea    -0x1(%rsi),%rbp
  sub    $0x1,%r8
  mov    %dl,0x1(%rsi)
  mov    %rbp,%rsi
  cmp    %rbx,%r8
  je     L45
L30:
  movzbl 0x1(%rsi),%edx
  movzbl 0x1(%r10,%r8,1),%ecx
  cmp    %cl,%dl
  jae    L13
  movzbl (%rsi),%ecx
  lea    -0x1(%rsi),%rbp
  mov    %rsi,%rdi
  mov    %rbp,%rdx
  test   %cl,%cl
  jne    L0
  nopl   0x0(%rax)
L98:
  movb   $0xff,(%rdi)
  mov    %rdx,%rdi
  movzbl (%rdx),%ecx
  sub    $0x1,%rdx
  test   %cl,%cl
  je     L98
L0:
  sub    $0x1,%ecx
  mov    %cl,(%rdi)
  movzbl 0x1(%rsi),%edx
  sub    0x1(%r10,%r8,1),%dl
  sub    $0x1,%r8
  mov    %dl,0x1(%rsi)
  mov    %rbp,%rsi
  cmp    %rbx,%r8
  jne    L30
L45:
  movslq %r11d,%rdx
  lea    -0x14(%r11,%rax,1),%ecx
  add    %r9,%rdx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L4:
  sub    $0x1,%eax
  add    $0x1,%rdx
  cmp    %eax,%ecx
  je     L81
L19:
  cmpb   $0x0,(%rdx)
  je     L4
L81:
  pop    %rbx
  pop    %rbp
  ret
L26:
  ret
```

assistant: ```c
int deduct(unsigned char *a, int a_len, unsigned char *b, int b_len) {
  int i, j, k;
  for (i = 20 - 1; i >= 20 - 1 - a_len; i--) {
    if (a[i] >= b[i])
      a[i] -= b[i];
    else {
      j = i - 1;
      while (1) {
        if (a[j] > 0) {
          a[j]--;
          a[i] += 256 - b[i];
          break;
        } else
          a[j] = 255;
        j--;
      }
    }
  }
  for (i = 20 - 1 - a_len; i <= 20 - 1; i++) {
    if (a[i] > 0)
      break;
    else {
      a[i] = 0;
      a_len--;
    }
  }
  return a_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<deduct>:
  endbr64
  mov    $0x13,%r11d
  mov    %esi,%eax
  sub    %esi,%r11d
  cmp    $0x13,%r11d
  jg     L94
  push   %rbp
  mov    %rdx,%r10
  mov    %eax,%edx
  mov    %rdi,%r9
  push   %rbx
  mov    $0x11,%ebx
  lea    0x12(%rdi),%rsi
  mov    $0x12,%r8d
  sub    %rdx,%rbx
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L66:
  sub    %ecx,%edx
  lea    -0x1(%rsi),%rbp
  sub    $0x1,%r8
  mov    %dl,0x1(%rsi)
  mov    %rbp,%rsi
  cmp    %rbx,%r8
  je     L64
L32:
  movzbl 0x1(%rsi),%edx
  movzbl 0x1(%r10,%r8,1),%ecx
  cmp    %cl,%dl
  jae    L66
  movzbl (%rsi),%ecx
  lea    -0x1(%rsi),%rbp
  mov    %rsi,%rdi
  mov    %rbp,%rdx
  test   %cl,%cl
  jne    L63
  nopl   0x0(%rax)
L90:
  movb   $0xff,(%rdi)
  mov    %rdx,%rdi
  movzbl (%rdx),%ecx
  sub    $0x1,%rdx
  test   %cl,%cl
  je     L90
L63:
  sub    $0x1,%ecx
  mov    %cl,(%rdi)
  movzbl 0x1(%rsi),%edx
  sub    0x1(%r10,%r8,1),%dl
  sub    $0x1,%r8
  mov    %dl,0x1(%rsi)
  mov    %rbp,%rsi
  cmp    %rbx,%r8
  jne    L32
L64:
  movslq %r11d,%rdx
  lea    -0x14(%r11,%rax,1),%ecx
  add    %r9,%rdx
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L77:
  sub    $0x1,%eax
  add    $0x1,%rdx
  cmp    %eax,%ecx
  je     L60
L36:
  cmpb   $0x0,(%rdx)
  je     L77
L60:
  pop    %rbx
  pop    %rbp
  ret
L94:
  ret
```

assistant: ```c
int deduct(unsigned char *a, int a_len, unsigned char *b, int b_len) {
  int i, j, k;
  for (i = 20 - 1; i >= 20 - 1 - a_len; i--) {
    if (a[i] >= b[i])
      a[i] -= b[i];
    else {
      j = i - 1;
      while (1) {
        if (a[j] > 0) {
          a[j]--;
          a[i] += 256 - b[i];
          break;
        } else
          a[j] = 255;
        j--;
      }
    }
  }
  for (i = 20 - 1 - a_len; i <= 20 - 1; i++) {
    if (a[i] > 0)
      break;
    else {
      a[i] = 0;
      a_len--;
    }
  }
  return a_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L3
L24:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  call   <stdlib_base_ceil@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x3c(%rbp)
L3:
  cmpl   $0x3,-0x3c(%rbp)
  jle    L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D1
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string

tool: D15: 3.14

tool: {"D1": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x09,0xc0]}

tool: D27: ceil(%lf) = %lf


assistant: ```c
int main() {
  double x[] = {3.14, -3.14, 0.0, 0.0 / 0.0};
  double y;
  int i;
  for (i = 0; i < 4; i++) {
    y = stdlib_base_ceil(x[i]);
    printf("ceil(%lf) = %lf\n", x[i], y);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  mov    %rax,(%rsp)
  mov    D23(%rip),%rax
  mov    %rax,0x8(%rsp)
  pxor   %xmm0,%xmm0
  movq   $0x0,0x10(%rsp)
  divsd  %xmm0,%xmm0
  movsd  %xmm0,0x18(%rsp)
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r13
  lea    D21(%rip),%r12
L15:
  mov    (%rbx),%rbp
  movq   %rbp,%xmm0
  call   <stdlib_base_ceil@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L15
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
data_type: f64
name: extract_symbolic_data
arguments: label: D23
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D21
data_type: string

tool: D11: 3.14

tool: {"D23": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x09,0xc0]}

tool: D21: ceil(%lf) = %lf


assistant: ```c
int main() {
  double x[] = {3.14, -3.14, 0.0, 0.0 / 0.0};
  double y;
  int i;
  for (i = 0; i < 4; i++) {
    y = stdlib_base_ceil(x[i]);
    printf("ceil(%lf) = %lf\n", x[i], y);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %r12
  divsd  %xmm0,%xmm0
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  movsd  D3(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  lea    0x10(%rsp),%rbx
  movq   $0x0,0x20(%rsp)
  lea    0x30(%rsp),%r12
  mov    %rax,0x18(%rsp)
  movsd  %xmm0,0x28(%rsp)
L13:
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  add    $0x8,%rbx
  call   <stdlib_base_ceil@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %rbp,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L5
  movsd  (%rbx),%xmm2
  jmp    L13
  nopl   0x0(%rax)
L5:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D28
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: f64
name: unpack_data
arguments: data_label: D17
data_type: byte[8]

tool: D28: ceil(%lf) = %lf


tool: D3: 3.14

tool: {"D17": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x09,0xc0]}

assistant: ```c
int main() {
  double x[] = {3.14, -3.14, 0.0, 0.0 / 0.0};
  double y;
  int i;
  for (i = 0; i < 4; i++) {
    y = stdlib_base_ceil(x[i]);
    printf("ceil(%lf) = %lf\n", x[i], y);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  movapd D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x30(%rsp),%r12
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movsd  %xmm0,0x28(%rsp)
L16:
  movsd  (%rbx),%xmm2
  add    $0x8,%rbx
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <stdlib_base_ceil@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %rbp,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D6
type: f64[2]

tool: D19: ceil(%lf) = %lf


tool: {"D6": [3.14,-3.14]}

assistant: ```c
int main() {
  double x[] = {3.14, -3.14, 0.0, 0.0 / 0.0};
  double y;
  int i;
  for (i = 0; i < 4; i++) {
    y = stdlib_base_ceil(x[i]);
    printf("ceil(%lf) = %lf\n", x[i], y);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<pm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L28:
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L38:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  addq   $0x8,-0x18(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L38
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L28
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: %4.2f 

assistant: ```c
void pm(double *p, int c, int r) {
  int i, j;
  for (i = 0; i < c; i++) {
    for (j = 0; j < r; j++, p++)
      printf("%4.2f ", *p);
    printf("\n");
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L48
  mov    %rdi,%rbx
  mov    %esi,%r14d
  mov    %edx,%r15d
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r13d
  lea    D7(%rip),%r12
  jmp    L7
L51:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L51
  mov    %rbp,%rbx
L30:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  je     L48
L7:
  mov    0x8(%rsp),%rax
  lea    (%rbx,%rax,1),%rbp
  test   %r15d,%r15d
  jg     L51
  jmp    L30
L48:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: string

tool: D7: %4.2f 

assistant: ```c
void pm(double *p, int c, int r) {
  int i, j;
  for (i = 0; i < c; i++) {
    for (j = 0; j < r; j++, p++)
      printf("%4.2f ", *p);
    printf("\n");
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r13
  mov    %edx,%r14d
  xor    %r12d,%r12d
  lea    0x8(,%rax,8),%r15
  lea    D4(%rip),%rbp
  nopl   (%rax)
L17:
  lea    0x0(%r13,%r15,1),%rbx
  test   %r14d,%r14d
  jle    L29
  nopw   0x0(%rax,%rax,1)
L35:
  movsd  0x0(%r13),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%r13
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L35
L29:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r12d,0xc(%rsp)
  jne    L17
L11:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string

tool: D4: %4.2f 

assistant: ```c
void pm(double *p, int c, int r) {
  int i, j;
  for (i = 0; i < c; i++) {
    for (j = 0; j < r; j++, p++)
      printf("%4.2f ", *p);
    printf("\n");
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  jle    L23
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r13
  mov    %edx,%r14d
  xor    %r12d,%r12d
  lea    0x8(,%rax,8),%r15
  lea    D8(%rip),%rbp
  nopl   (%rax)
L35:
  lea    0x0(%r13,%r15,1),%rbx
  test   %r14d,%r14d
  jle    L12
  nopw   0x0(%rax,%rax,1)
L17:
  movsd  0x0(%r13),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%r13
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L17
L12:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r12d,0xc(%rsp)
  jne    L35
L23:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type: string

tool: D8: %4.2f 

assistant: ```c
void pm(double *p, int c, int r) {
  int i, j;
  for (i = 0; i < c; i++) {
    for (j = 0; j < r; j++, p++)
      printf("%4.2f ", *p);
    printf("\n");
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L37
  mov    $0x0,%eax
  jmp    L32
L37:
  movq   $0x0,-0x10(%rbp)
  jmp    L16
L28:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  addq   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L28
  mov    -0x8(%rbp),%rax
L32:
  leave
  ret
```

assistant: ```c
int *make_array(const long array_size) {
  int *a = malloc(array_size * sizeof(int));
  if (a == NULL) {
    return NULL;
  }
  for (long i = 0; i < array_size; i++) {
    a[i] = 10 * i;
  }
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<make_array>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x0(,%rdi,4),%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L2
  test   %rbp,%rbp
  jle    L2
  mov    %rax,%rdx
  lea    (%rbx,%rax,1),%rsi
  mov    $0x0,%ecx
L9:
  mov    %ecx,(%rdx)
  add    $0xa,%ecx
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L9
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *make_array(const long array_size) {
  int *a = malloc(array_size * sizeof(int));
  if (a == NULL) {
    return NULL;
  }
  for (long i = 0; i < array_size; i++) {
    a[i] = 10 * i;
  }
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<make_array>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x0(,%rdi,4),%rbx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L3
  test   %rbp,%rbp
  jle    L3
  mov    %rax,%rdx
  lea    (%rbx,%rax,1),%rsi
  xor    %ecx,%ecx
L1:
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  add    $0xa,%ecx
  cmp    %rsi,%rdx
  jne    L1
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *make_array(const long array_size) {
  int *a = malloc(array_size * sizeof(int));
  if (a == NULL) {
    return NULL;
  }
  for (long i = 0; i < array_size; i++) {
    a[i] = 10 * i;
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<make_array>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L17
  test   %rbx,%rbx
  jle    L17
  lea    -0x1(%rbx),%rax
  cmp    $0x2,%rax
  jbe    L30
  mov    %rbx,%rdx
  movdqa D28(%rip),%xmm2
  mov    %r8,%rax
  movdqa D21(%rip),%xmm4
  shr    $0x2,%rdx
  movdqa D15(%rip),%xmm3
  shl    $0x4,%rdx
  add    %r8,%rdx
  nopl   (%rax)
L9:
  movdqa %xmm2,%xmm1
  add    $0x10,%rax
  paddq  %xmm4,%xmm2
  movdqa %xmm1,%xmm0
  paddq  %xmm3,%xmm0
  shufps $0x88,%xmm0,%xmm1
  movdqa %xmm1,%xmm0
  pslld  $0x2,%xmm0
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L9
  mov    %rbx,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%bl
  je     L17
L26:
  lea    (%rax,%rax,4),%edx
  lea    0x0(,%rax,4),%rcx
  add    %edx,%edx
  mov    %edx,(%r8,%rax,4)
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rbx
  jle    L17
  lea    (%rdx,%rdx,4),%edx
  add    $0x2,%rax
  add    %edx,%edx
  mov    %edx,0x4(%r8,%rcx,1)
  cmp    %rax,%rbx
  jle    L17
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,0x8(%r8,%rcx,1)
L17:
  mov    %r8,%rax
  pop    %rbx
  ret
L30:
  xor    %eax,%eax
  jmp    L26
```

tool_calls: name: read_data
arguments: label: D28
data_type: byte[16]
name: read_data
arguments: label: D21
data_type: byte[16]
name: read_data
arguments: label: D15
data_type: byte[16]

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D21": [0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D15": [0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int *make_array(const long array_size) {
  int *a = malloc(array_size * sizeof(int));
  if (a == NULL) {
    return NULL;
  }
  for (long i = 0; i < array_size; i++) {
    a[i] = 10 * i;
  }
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L15
L19:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putc@plt>
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    $0xd,%edi
  call   <putc@plt>
  mov    $0xa,%edi
  call   <putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s)
    putc(*s++);
  putc('\r');
  putc('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L10
L0:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putc@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L0
L10:
  mov    $0xd,%edi
  call   <putc@plt>
  mov    $0xa,%edi
  call   <putc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s)
    putc(*s++);
  putc('\r');
  putc('\n');
}
```