ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_response>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %rcx,%r13
  mov    %r8d,0xc(%rsp)
  mov    %r9,%r15
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    %eax,%edi
  call   <asctime@plt>
  mov    %rax,%r14
  movzwl %bx,%edi
  call   <ntohs@plt>
  mov    %eax,%ecx
  sub    $0x8,%rsp
  push   %r15
  mov    %r14,%r9
  mov    %r13,%r8
  mov    %r12,%rdx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fflush@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: %s %d %s %s %s


assistant: ```c
void log_response(FILE *log_file, char *ip, unsigned short port, char *file_name, time_t start, char *result) {
  fprintf(log_file, "%s %d %s %s %s\n", ip, ntohs(port), file_name, asctime(localtime(&start)), result);
  fflush(log_file);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log_response>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  lea    0xc(%rsp),%rdi
  mov    %r8d,0xc(%rsp)
  call   <localtime@plt>
  mov    %eax,%edi
  call   <asctime@plt>
  movzwl %bx,%edi
  mov    %rax,%r14
  call   <ntohs@plt>
  sub    $0x8,%rsp
  mov    %r14,%r9
  mov    %r13,%r8
  push   %r15
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%ecx
  lea    D4(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fflush@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: %s %d %s %s %s


assistant: ```c
void log_response(FILE *log_file, char *ip, unsigned short port, char *file_name, time_t start, char *result) {
  fprintf(log_file, "%s %d %s %s %s\n", ip, ntohs(port), file_name, asctime(localtime(&start)), result);
  fflush(log_file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<log_response>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  lea    0xc(%rsp),%rdi
  mov    %r8d,0xc(%rsp)
  call   <localtime@plt>
  mov    %eax,%edi
  call   <asctime@plt>
  movzwl %bx,%edi
  mov    %rax,%r14
  call   <ntohs@plt>
  sub    $0x8,%rsp
  mov    %r14,%r9
  mov    %r13,%r8
  push   %r15
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%ecx
  lea    D1(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fflush@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D1: %s %d %s %s %s


assistant: ```c
void log_response(FILE *log_file, char *ip, unsigned short port, char *file_name, time_t start, char *result) {
  fprintf(log_file, "%s %d %s %s %s\n", ip, ntohs(port), file_name, asctime(localtime(&start)), result);
  fflush(log_file);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <CreateSocket@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main() {
  int ret;
  ret = CreateSocket();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CreateSocket@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int ret;
  ret = CreateSocket();
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <CreateSocket@plt>
```

assistant: ```c
int main() {
  int ret;
  ret = CreateSocket();
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <CreateSocket@plt>
```

assistant: ```c
int main() {
  int ret;
  ret = CreateSocket();
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L64:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L67
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L67
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L15
L67:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L34
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L34
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x47,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L15
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L15:
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L64
  nop
  pop    %rbp
  ret
```

assistant: ```c
void encrypt(char *cipher, const char *plain, int len, char *key) {
  int i, tmp;
  for (i = 0; i < len; i++) {
    if ('A' <= plain[i] && plain[i] <= 'Z') {
      tmp = plain[i] - 'A';
      cipher[i] = key[tmp];
    } else if ('a' <= plain[i] && plain[i] <= 'z') {
      tmp = plain[i] - 'a' + 26;
      cipher[i] = key[tmp];
    } else
      cipher[i] = plain[i];
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<encrypt>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rcx,%r9
  test   %edx,%edx
  jle    L42
  mov    %edx,%esi
  mov    $0x0,%edx
  jmp    L41
L66:
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  ja     L67
  movsbl %al,%eax
  sub    $0x47,%eax
  cltq
  movzbl (%r9,%rax,1),%eax
  mov    %al,(%r8,%rdx,1)
L12:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L42
L41:
  movzbl (%rdi,%rdx,1),%eax
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L66
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  movzbl (%r9,%rax,1),%eax
  mov    %al,(%r8,%rdx,1)
  jmp    L12
L67:
  mov    %al,(%r8,%rdx,1)
  jmp    L12
L42:
  ret
```

assistant: ```c
void encrypt(char *cipher, const char *plain, int len, char *key) {
  int i, tmp;
  for (i = 0; i < len; i++) {
    if ('A' <= plain[i] && plain[i] <= 'Z') {
      tmp = plain[i] - 'A';
      cipher[i] = key[tmp];
    } else if ('a' <= plain[i] && plain[i] <= 'z') {
      tmp = plain[i] - 'a' + 26;
      cipher[i] = key[tmp];
    } else
      cipher[i] = plain[i];
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encrypt>:
  endbr64
  mov    %rdi,%r8
  movslq %edx,%r9
  mov    %rsi,%rdi
  xor    %esi,%esi
  test   %edx,%edx
  jg     L7
  jmp    L52
  nopl   (%rax)
L21:
  movsbq %dl,%rdx
  movzbl (%rcx,%rdx,1),%eax
L46:
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %r9,%rsi
  je     L52
L7:
  movzbl (%rdi,%rsi,1),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  jbe    L21
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L46
  sub    $0x47,%eax
  movsbq %al,%rax
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %r9,%rsi
  jne    L7
L52:
  ret
```

assistant: ```c
void encrypt(char *cipher, const char *plain, int len, char *key) {
  int i, tmp;
  for (i = 0; i < len; i++) {
    if ('A' <= plain[i] && plain[i] <= 'Z') {
      tmp = plain[i] - 'A';
      cipher[i] = key[tmp];
    } else if ('a' <= plain[i] && plain[i] <= 'z') {
      tmp = plain[i] - 'a' + 26;
      cipher[i] = key[tmp];
    } else
      cipher[i] = plain[i];
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encrypt>:
  endbr64
  mov    %rdi,%r8
  movslq %edx,%r9
  mov    %rsi,%rdi
  xor    %esi,%esi
  test   %edx,%edx
  jg     L8
  jmp    L44
  nopl   (%rax)
L51:
  movsbq %dl,%rdx
  movzbl (%rcx,%rdx,1),%eax
L53:
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %rsi,%r9
  je     L44
L8:
  movzbl (%rdi,%rsi,1),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  jbe    L51
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L53
  sub    $0x47,%eax
  movsbq %al,%rax
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %rsi,%r9
  jne    L8
L44:
  ret
```

assistant: ```c
void encrypt(char *cipher, const char *plain, int len, char *key) {
  int i, tmp;
  for (i = 0; i < len; i++) {
    if ('A' <= plain[i] && plain[i] <= 'Z') {
      tmp = plain[i] - 'A';
      cipher[i] = key[tmp];
    } else if ('a' <= plain[i] && plain[i] <= 'z') {
      tmp = plain[i] - 'a' + 26;
      cipher[i] = key[tmp];
    } else
      cipher[i] = plain[i];
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<intchk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x7b,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0xffffffee,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
data_type: string
name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string

tool: D28: %15s :, "

tool: D0: ", "

tool: D18: "

assistant: ```c
void intchk(const char *fmt) {
  (void)printf("%15s :, \"", fmt);
  (void)printf(fmt, 0);
  (void)printf("\", \"");
  (void)printf(fmt, 123);
  (void)printf("\", \"");
  (void)printf(fmt, -18);
  (void)printf("\"\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<intchk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7b,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffee,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D27
type_guessed: string
name: disassemble_data
arguments: data_label: D2
type_guessed: string
name: disassemble_data
arguments: data_label: D10
type_guessed: string

tool: D27: %15s :, "

tool: D2: ", "

tool: D10: "

assistant: ```c
void intchk(const char *fmt) {
  (void)printf("%15s :, \"", fmt);
  (void)printf(fmt, 0);
  (void)printf("\", \"");
  (void)printf(fmt, 123);
  (void)printf("\", \"");
  (void)printf(fmt, -18);
  (void)printf("\"\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intchk>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D29(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D15(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7b,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffee,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  lea    D14(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string

tool: D29: ", "

tool: D15: %15s :, "

tool: D14: "

assistant: ```c
void intchk(const char *fmt) {
  (void)printf("%15s :, \"", fmt);
  (void)printf(fmt, 0);
  (void)printf("\", \"");
  (void)printf(fmt, 123);
  (void)printf("\", \"");
  (void)printf(fmt, -18);
  (void)printf("\"\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<intchk>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D29(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7b,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffee,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  lea    D4(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type_guessed: string
name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D29: ", "

tool: D8: %15s :, "

tool: D4: "

assistant: ```c
void intchk(const char *fmt) {
  (void)printf("%15s :, \"", fmt);
  (void)printf(fmt, 0);
  (void)printf("\", \"");
  (void)printf(fmt, 123);
  (void)printf("\", \"");
  (void)printf(fmt, -18);
  (void)printf("\"\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_bzipped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  jle    L5
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  mov    $0x1,%eax
  jmp    L18
L5:
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: .bz2

assistant: ```c
int is_bzipped(char *name) {
  int len = strlen(name);
  return len >= 5 && strcmp(&name[len - 4], ".bz2") == 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_bzipped>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    $0x4,%eax
  jg     L17
L5:
  mov    %edx,%eax
  pop    %rbx
  ret
L17:
  cltq
  lea    -0x4(%rbx,%rax,1),%rdi
  lea    D7(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: .bz2

assistant: ```c
int is_bzipped(char *name) {
  int len = strlen(name);
  return len >= 5 && strcmp(&name[len - 4], ".bz2") == 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_bzipped>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    $0x4,%eax
  jg     L7
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  cltq
  lea    D7(%rip),%rsi
  lea    -0x4(%rbx,%rax,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  pop    %rbx
  test   %rax,%rax
  sete   %r8b
  mov    %r8d,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: .bz2

assistant: ```c
int is_bzipped(char *name) {
  int len = strlen(name);
  return len >= 5 && strcmp(&name[len - 4], ".bz2") == 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_bzipped>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    $0x4,%eax
  jg     L8
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  cltq
  lea    D4(%rip),%rsi
  lea    -0x4(%rbx,%rax,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  pop    %rbx
  test   %rax,%rax
  sete   %r8b
  mov    %r8d,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: .bz2

assistant: ```c
int is_bzipped(char *name) {
  int len = strlen(name);
  return len >= 5 && strcmp(&name[len - 4], ".bz2") == 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ehnlc_memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L11
  mov    -0x8(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jae    L11
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L0
L66:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subq   $0x1,-0x18(%rbp)
L0:
  cmpq   $0x0,-0x18(%rbp)
  jne    L66
  jmp    L18
L11:
  movq   $0x0,-0x18(%rbp)
  jmp    L39
L9:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L9
L18:
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *ehnlc_memmove(void *d, const void *s, size_t n) {
  const unsigned char *src;
  unsigned char *dest;
  size_t i;
  dest = d;
  src = s;
  if (src < dest && dest < src + n) {
    for (i = n; i; i--) {
      dest[i - 1] = src[i - 1];
    }
  } else {
    for (i = 0; i < n; ++i) {
      dest[i] = src[i];
    }
  }
  return d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ehnlc_memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  ja     L27
L13:
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L43
L48:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L48
L15:
  ret
L43:
  ret
L27:
  lea    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rdi
  jae    L13
  test   %rdx,%rdx
  je     L15
L20:
  sub    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  jne    L20
  ret
```

assistant: ```c
void *ehnlc_memmove(void *d, const void *s, size_t n) {
  const unsigned char *src;
  unsigned char *dest;
  size_t i;
  dest = d;
  src = s;
  if (src < dest && dest < src + n) {
    for (i = n; i; i--) {
      dest[i - 1] = src[i - 1];
    }
  } else {
    for (i = 0; i < n; ++i) {
      dest[i] = src[i];
    }
  }
  return d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ehnlc_memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jbe    L27
  lea    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rdi
  jae    L27
  test   %rdx,%rdx
  je     L17
  nopw   0x0(%rax,%rax,1)
L26:
  sub    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  jne    L26
  ret
  xchg   %ax,%ax
L27:
  xor    %ecx,%ecx
  test   %rdx,%rdx
  je     L4
  nopw   0x0(%rax,%rax,1)
L23:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L23
L17:
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void *ehnlc_memmove(void *d, const void *s, size_t n) {
  const unsigned char *src;
  unsigned char *dest;
  size_t i;
  dest = d;
  src = s;
  if (src < dest && dest < src + n) {
    for (i = n; i; i--) {
      dest[i - 1] = src[i - 1];
    }
  } else {
    for (i = 0; i < n; ++i) {
      dest[i] = src[i];
    }
  }
  return d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ehnlc_memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rax
  mov    %rsi,%rdi
  cmp    %rsi,%r8
  jbe    L166
  lea    (%rsi,%rdx,1),%rdx
  cmp    %rdx,%r8
  jb     L196
L166:
  test   %rax,%rax
  je     L174
  lea    0x1(%rdi),%rsi
  mov    %r8,%rcx
  lea    -0x1(%rax),%rdx
  sub    %rsi,%rcx
  cmp    $0xe,%rcx
  jbe    L101
  cmp    $0x6,%rdx
  jbe    L101
  mov    %rax,%rcx
  cmp    $0xe,%rdx
  jbe    L181
  and    $0xfffffffffffffff0,%rcx
  xor    %edx,%edx
  nopl   (%rax)
L38:
  movdqu (%rdi,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rcx
  jne    L38
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rdx
  test   $0xf,%al
  je     L174
  mov    %rax,%rcx
  sub    %rdx,%rcx
  lea    -0x1(%rcx),%rsi
  cmp    $0x6,%rsi
  jbe    L24
L128:
  mov    (%rdi,%rdx,1),%rsi
  mov    %rsi,(%r8,%rdx,1)
  mov    %rcx,%rsi
  and    $0xfffffffffffffff8,%rsi
  add    %rsi,%rdx
  cmp    %rsi,%rcx
  je     L174
L24:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L174
  movzbl 0x1(%rdi,%rdx,1),%ecx
  mov    %cl,0x1(%r8,%rdx,1)
  lea    0x2(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L174
  movzbl 0x2(%rdi,%rdx,1),%ecx
  mov    %cl,0x2(%r8,%rdx,1)
  lea    0x3(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L174
  movzbl 0x3(%rdi,%rdx,1),%ecx
  mov    %cl,0x3(%r8,%rdx,1)
  lea    0x4(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L174
  movzbl 0x4(%rdi,%rdx,1),%ecx
  mov    %cl,0x4(%r8,%rdx,1)
  lea    0x5(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L174
  movzbl 0x5(%rdi,%rdx,1),%ecx
  mov    %cl,0x5(%r8,%rdx,1)
  lea    0x6(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L174
  movzbl 0x6(%rdi,%rdx,1),%eax
  mov    %al,0x6(%r8,%rdx,1)
L174:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L196:
  test   %rax,%rax
  je     L174
  nopl   (%rax)
L44:
  sub    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  jne    L44
  mov    %r8,%rax
  ret
L181:
  xor    %edx,%edx
  jmp    L128
  nopl   0x0(%rax)
L101:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L195:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L195
  mov    %r8,%rax
  ret
```

assistant: ```c
void *ehnlc_memmove(void *d, const void *s, size_t n) {
  const unsigned char *src;
  unsigned char *dest;
  size_t i;
  dest = d;
  src = s;
  if (src < dest && dest < src + n) {
    for (i = n; i; i--) {
      dest[i - 1] = src[i - 1];
    }
  } else {
    for (i = 0; i < n; ++i) {
      dest[i] = src[i];
    }
  }
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<slp_noblockcheck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L6
  mov    $0xffffffff,%eax
  jmp    L8
L6:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int slp_noblockcheck(void) {
  if (errno != EWOULDBLOCK)
    return -1;
  return 0;
}
```