ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sms_scaleWindow>:
  endbr64
  mov    %edi,%ecx
  mov    %rsi,%rdx
  test   %edi,%edi
  jle    L28
  cmp    $0x1,%edi
  je     L43
  mov    %rsi,%rax
  mov    %edi,%esi
  lea    0x10(%rdx),%rdi
  shr    %esi
  pxor   %xmm0,%xmm0
  sub    $0x1,%esi
  shl    $0x4,%rsi
  add    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L11:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L11
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  cmp    %eax,%ecx
  je     L57
L26:
  cltq
  movsd  D8(%rip),%xmm1
  addsd  (%rdx,%rax,8),%xmm0
  divsd  %xmm0,%xmm1
  cmp    $0x1,%ecx
  je     L89
  lea    0x10(%rdx),%rdi
L82:
  mov    %ecx,%esi
  movapd %xmm1,%xmm2
  mov    %rdx,%rax
  shr    %esi
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%esi
  shl    $0x4,%rsi
  add    %rdi,%rsi
  nopl   0x0(%rax)
L86:
  movupd (%rax),%xmm0
  add    $0x10,%rax
  mulpd  %xmm2,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L86
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L60
  cltq
  lea    (%rdx,%rax,8),%rax
  mulsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  ret
  nopl   0x0(%rax)
L89:
  xor    %eax,%eax
  cltq
  lea    (%rdx,%rax,8),%rax
  mulsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  ret
  nopl   0x0(%rax)
L57:
  movsd  D8(%rip),%xmm1
  divsd  %xmm0,%xmm1
  jmp    L82
  nopl   0x0(%rax)
L60:
  ret
L43:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L26
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: f64

tool: D8: 2

assistant: ```c
void sms_scaleWindow(int sizeWindow, double *pWindow) {
  int i;
  double fSum = 0;
  double fScale;
  for (i = 0; i < sizeWindow; i++)
    fSum += pWindow[i];
  fScale = 2. / fSum;
  for (i = 0; i < sizeWindow; i++)
    pWindow[i] *= fScale;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D89(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D59(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  D23(%rip),%xmm0
  mulss  0x10(%rsp),%xmm0
  addss  D55(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D60(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D8(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  addss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D8(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D99(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D89
type_infered: string
name: parse_data
arguments: data_tag: D59
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: byte[4]
name: parse_data
arguments: data_tag: D55
type_infered: byte[4]
name: parse_data
arguments: data_tag: D60
type_infered: string
name: parse_data
arguments: data_tag: D40
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: f64
name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D99
type_infered: string

tool: D89: Input x variable

tool: D59: %f

tool: {"D23": [0x00,0x00,0x80,0x40]}

tool: {"D55": [0x00,0x00,0x00,0x41]}

tool: D60: This is the y intercept %f


tool: D40: What is the radius of the circle?

tool: D8: 3.14

tool: D19: This is the area %f


tool: D99: This is the circum %f


assistant: ```c
int main() {
  float x;
  float y;
  y = 5;
  printf("Input x variable\n");
  scanf("%f", &x);
  y = (4 * x + 8);
  printf("This is the y intercept %f\n", y);
  float radius;
  printf("What is the radius of the circle?\n");
  scanf("%f", &radius);
  float circum;
  circum = 3.14 * (2 * radius);
  float area;
  area = 3.14 * (radius * radius);
  printf("This is the area %f\n", area);
  printf("This is the circum %f\n", circum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D86(%rip),%rdi
  lea    D49(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  D44(%rip),%xmm0
  mulss  0x10(%rsp),%xmm0
  lea    D94(%rip),%rdi
  addss  D54(%rip),%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  mov    $0x1,%eax
  lea    D63(%rip),%rdi
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  mulss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D88(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  lea    D60(%rip),%rdi
  mov    $0x1,%eax
  addss  %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  mulsd  D88(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D86
data_type: string
name: parse_data
arguments: data_tag: D49
data_type: string
name: parse_data
arguments: data_tag: D44
data_type: byte[4]
name: parse_data
arguments: data_tag: D94
data_type: string
name: parse_data
arguments: data_tag: D54
data_type: byte[4]
name: parse_data
arguments: data_tag: D30
data_type: string
name: parse_data
arguments: data_tag: D63
data_type: string
name: parse_data
arguments: data_tag: D88
data_type: f64
name: parse_data
arguments: data_tag: D60
data_type: string

tool: D86: Input x variable

tool: D49: %f

tool: {"D44": [0x00,0x00,0x80,0x40]}

tool: D94: This is the y intercept %f


tool: {"D54": [0x00,0x00,0x00,0x41]}

tool: D30: What is the radius of the circle?

tool: D63: This is the area %f


tool: D88: 3.14

tool: D60: This is the circum %f


assistant: ```c
int main() {
  float x;
  float y;
  y = 5;
  printf("Input x variable\n");
  scanf("%f", &x);
  y = (4 * x + 8);
  printf("This is the y intercept %f\n", y);
  float radius;
  printf("What is the radius of the circle?\n");
  scanf("%f", &radius);
  float circum;
  circum = 3.14 * (2 * radius);
  float area;
  area = 3.14 * (radius * radius);
  printf("This is the area %f\n", area);
  printf("This is the circum %f\n", circum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D96(%rip),%rdi
  lea    D87(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  D34(%rip),%xmm0
  mulss  0x10(%rsp),%xmm0
  lea    D98(%rip),%rdi
  addss  D29(%rip),%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  mov    $0x1,%eax
  lea    D9(%rip),%rdi
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  mulss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D36(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  lea    D84(%rip),%rdi
  mov    $0x1,%eax
  addss  %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  mulsd  D36(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D96
type_guessed: string
name: retrieve_data
arguments: label: D87
type_guessed: string
name: retrieve_data
arguments: label: D34
type_guessed: byte[4]
name: retrieve_data
arguments: label: D98
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: byte[4]
name: retrieve_data
arguments: label: D7
type_guessed: string
name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D36
type_guessed: f64
name: retrieve_data
arguments: label: D84
type_guessed: string

tool: D96: Input x variable

tool: D87: %f

tool: {"D34": [0x00,0x00,0x80,0x40]}

tool: D98: This is the y intercept %f


tool: {"D29": [0x00,0x00,0x00,0x41]}

tool: D7: What is the radius of the circle?

tool: D9: This is the area %f


tool: D36: 3.14

tool: D84: This is the circum %f


assistant: ```c
int main() {
  float x;
  float y;
  y = 5;
  printf("Input x variable\n");
  scanf("%f", &x);
  y = (4 * x + 8);
  printf("This is the y intercept %f\n", y);
  float radius;
  printf("What is the radius of the circle?\n");
  scanf("%f", &radius);
  float circum;
  circum = 3.14 * (2 * radius);
  float area;
  area = 3.14 * (radius * radius);
  printf("This is the area %f\n", area);
  printf("This is the circum %f\n", circum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<hash_proto_aes_decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <AES_set_decrypt_key@plt>
  cmpl   $0x0,0x10(%rbp)
  je     L31
  cmpl   $0x1,0x10(%rbp)
  je     L39
  jmp    L37
L31:
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <AES_ecb_encrypt@plt>
  jmp    L37
L39:
  mov    D9(%rip),%rax
  mov    (%rax),%r8d
  mov    -0x30(%rbp),%rdi
  lea    -0xc(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <AES_cbc_encrypt@plt>
  nop
L37:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
void hash_proto_aes_decrypt(const unsigned char *key, int keysize, const unsigned char *in, int len, unsigned char *vec, unsigned char *out, int mode) {
  AES_KEY akey;
  AES_set_decrypt_key(key, keysize * 8, &akey);
  switch (mode) {
  case 0:
    AES_ecb_encrypt(in, out, &akey, AES_DECRYPT);
    break;
  case 1:
    AES_cbc_encrypt(in, out, len, &akey, vec, AES_DECRYPT);
    break;
  default:
    return;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_proto_aes_decrypt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  mov    %r8,%r13
  mov    %r9,%rbp
  mov    0x40(%rsp),%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  shl    $0x3,%esi
  call   <AES_set_decrypt_key@plt>
  test   %r14d,%r14d
  je     L44
  cmp    $0x1,%r14d
  je     L29
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  lea    0x4(%rsp),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <AES_ecb_encrypt@plt>
  jmp    L43
L29:
  lea    0x4(%rsp),%rcx
  mov    D8(%rip),%rax
  mov    (%rax),%r9d
  mov    %r13,%r8
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <AES_cbc_encrypt@plt>
  jmp    L43
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hash_proto_aes_decrypt(const unsigned char *key, int keysize, const unsigned char *in, int len, unsigned char *vec, unsigned char *out, int mode) {
  AES_KEY akey;
  AES_set_decrypt_key(key, keysize * 8, &akey);
  switch (mode) {
  case 0:
    AES_ecb_encrypt(in, out, &akey, AES_DECRYPT);
    break;
  case 1:
    AES_cbc_encrypt(in, out, len, &akey, vec, AES_DECRYPT);
    break;
  default:
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash_proto_aes_decrypt>:
  endbr64
  push   %r15
  shl    $0x3,%esi
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x50(%rsp),%ebp
  lea    0x4(%rsp),%r15
  mov    %r15,%rdx
  call   <AES_set_decrypt_key@plt>
  test   %ebp,%ebp
  je     L38
  cmp    $0x1,%ebp
  jne    L1
  mov    D5(%rip),%rax
  mov    %rbx,%r8
  mov    %r15,%rcx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    (%rax),%r9d
  call   <AES_cbc_encrypt@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    D5(%rip),%rax
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    (%rax),%ecx
  call   <AES_ecb_encrypt@plt>
  jmp    L1
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hash_proto_aes_decrypt(const unsigned char *key, int keysize, const unsigned char *in, int len, unsigned char *vec, unsigned char *out, int mode) {
  AES_KEY akey;
  AES_set_decrypt_key(key, keysize * 8, &akey);
  switch (mode) {
  case 0:
    AES_ecb_encrypt(in, out, &akey, AES_DECRYPT);
    break;
  case 1:
    AES_cbc_encrypt(in, out, len, &akey, vec, AES_DECRYPT);
    break;
  default:
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash_proto_aes_decrypt>:
  endbr64
  push   %r15
  shl    $0x3,%esi
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x50(%rsp),%ebp
  lea    0x4(%rsp),%r15
  mov    %r15,%rdx
  call   <AES_set_decrypt_key@plt>
  test   %ebp,%ebp
  je     L36
  cmp    $0x1,%ebp
  jne    L32
  mov    D9(%rip),%rax
  mov    %rbx,%r8
  mov    %r15,%rcx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    (%rax),%r9d
  call   <AES_cbc_encrypt@plt>
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    D9(%rip),%rax
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    (%rax),%ecx
  call   <AES_ecb_encrypt@plt>
  jmp    L32
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hash_proto_aes_decrypt(const unsigned char *key, int keysize, const unsigned char *in, int len, unsigned char *vec, unsigned char *out, int mode) {
  AES_KEY akey;
  AES_set_decrypt_key(key, keysize * 8, &akey);
  switch (mode) {
  case 0:
    AES_ecb_encrypt(in, out, &akey, AES_DECRYPT);
    break;
  case 1:
    AES_cbc_encrypt(in, out, len, &akey, vec, AES_DECRYPT);
    break;
  default:
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<runversion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <procversion@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int runversion(int argc, char **argv) {
  int rv = procversion();
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<runversion>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <procversion@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int runversion(int argc, char **argv) {
  int rv = procversion();
  return rv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<runversion>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <procversion@plt>
```

assistant: ```c
int runversion(int argc, char **argv) {
  int rv = procversion();
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<runversion>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <procversion@plt>
```

assistant: ```c
int runversion(int argc, char **argv) {
  int rv = procversion();
  return rv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<itob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L49
  mov    -0x14(%rbp),%eax
  neg    %eax
  jmp    L52
L49:
  mov    -0x14(%rbp),%eax
L52:
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
L54:
  mov    -0x18(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%ecx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    %ecx,%ecx
  lea    D4(%rip),%rax
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%esi
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  div    %esi
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L54
  cmpl   $0x0,-0x4(%rbp)
  jns    L35
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L35:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L58
L53:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L58:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x24(%rbp)
  jg     L53
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
void itob(int n, char s[], int b, int f) {
  int i, sign;
  unsigned un;
  un = ((sign = n) < 0) ? -n : n;
  i = 0;
  do {
    s[i++] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[un % b];
  } while ((un /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  while (strlen(s) < f) {
    s[i++] = ' ';
    s[i] = '\0';
  }
  reverse(s);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<itob>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r8d
  mov    %rsi,%rbp
  mov    %edx,%esi
  mov    %ecx,%r12d
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  mov    %rbp,%rdi
  mov    $0x0,%ebx
  lea    D3(%rip),%r10
L4:
  mov    %ebx,%r9d
  add    $0x1,%ebx
  mov    %ecx,%eax
  mov    $0x0,%edx
  div    %esi
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,(%rdi)
  mov    %ecx,%edx
  mov    %eax,%ecx
  add    $0x1,%rdi
  cmp    %edx,%esi
  jbe    L4
  test   %r8d,%r8d
  js     L26
L21:
  movslq %ebx,%rbx
  add    %rbp,%rbx
  movb   $0x0,(%rbx)
  jmp    L31
L26:
  movslq %ebx,%rbx
  movb   $0x2d,0x0(%rbp,%rbx,1)
  lea    0x2(%r9),%ebx
  jmp    L21
L47:
  movb   $0x20,-0x1(%rbx)
  movb   $0x0,(%rbx)
L31:
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x1,%rbx
  cmp    %r12d,%eax
  jl     L47
  mov    %rbp,%rdi
  call   <reverse@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D3: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
void itob(int n, char s[], int b, int f) {
  int i, sign;
  unsigned un;
  un = ((sign = n) < 0) ? -n : n;
  i = 0;
  do {
    s[i++] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[un % b];
  } while ((un /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  while (strlen(s) < f) {
    s[i++] = ' ';
    s[i] = '\0';
  }
  reverse(s);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<itob>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edi,%r8d
  mov    %edx,%esi
  push   %rbp
  mov    %ecx,%ebp
  mov    %edi,%ecx
  lea    D1(%rip),%r10
  neg    %ecx
  push   %rbx
  cmovs  %edi,%ecx
  mov    %r12,%rdi
  xor    %ebx,%ebx
  nopl   (%rax)
L25:
  mov    %ecx,%eax
  xor    %edx,%edx
  mov    %ebx,%r9d
  div    %esi
  add    $0x1,%ebx
  add    $0x1,%rdi
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%rdi)
  mov    %ecx,%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jae    L25
  test   %r8d,%r8d
  jns    L37
  movslq %ebx,%rbx
  movb   $0x2d,(%r12,%rbx,1)
  lea    0x2(%r9),%ebx
L37:
  movslq %ebx,%rbx
  add    %r12,%rbx
  movb   $0x0,(%rbx)
  jmp    L39
  nopl   0x0(%rax)
L26:
  movb   $0x20,-0x1(%rbx)
  movb   $0x0,(%rbx)
L39:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  cmp    %ebp,%eax
  jl     L26
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <reverse@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
void itob(int n, char s[], int b, int f) {
  int i, sign;
  unsigned un;
  un = ((sign = n) < 0) ? -n : n;
  i = 0;
  do {
    s[i++] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[un % b];
  } while ((un /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  while (strlen(s) < f) {
    s[i++] = ' ';
    s[i] = '\0';
  }
  reverse(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itob>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edi,%r8d
  mov    %edx,%esi
  push   %rbp
  mov    %ecx,%ebp
  mov    %edi,%ecx
  lea    D8(%rip),%r10
  neg    %ecx
  push   %rbx
  cmovs  %edi,%ecx
  mov    %r12,%rdi
  xor    %ebx,%ebx
  nopl   (%rax)
L36:
  mov    %ecx,%eax
  xor    %edx,%edx
  mov    %ebx,%r9d
  div    %esi
  add    $0x1,%ebx
  add    $0x1,%rdi
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%rdi)
  mov    %ecx,%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jae    L36
  test   %r8d,%r8d
  jns    L5
  movslq %ebx,%rbx
  movb   $0x2d,(%r12,%rbx,1)
  lea    0x2(%r9),%ebx
L5:
  movslq %ebx,%rbx
  add    %r12,%rbx
  movb   $0x0,(%rbx)
  jmp    L27
  nopl   0x0(%rax)
L37:
  movb   $0x20,-0x1(%rbx)
  movb   $0x0,(%rbx)
L27:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  cmp    %ebp,%eax
  jl     L37
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <reverse@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
void itob(int n, char s[], int b, int f) {
  int i, sign;
  unsigned un;
  un = ((sign = n) < 0) ? -n : n;
  i = 0;
  do {
    s[i++] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[un % b];
  } while ((un /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  while (strlen(s) < f) {
    s[i++] = ' ';
    s[i] = '\0';
  }
  reverse(s);
}
```