ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<insert>:
  endbr64
  cmp    $0x1,%esi
  jle    L32
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r10d
  mov    $0x0,%r8d
  jmp    L39
L48:
  movslq %edx,%rdx
  mov    %esi,0x4(%rdi,%rdx,4)
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  je     L32
L39:
  mov    0x4(%r9),%esi
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L48
L12:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L48
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L12
  jmp    L48
L32:
  ret
```

assistant: ```c
void insert(int *a, int n) {
  int x, i, j;
  i = 1;
  while (i < n) {
    x = a[i];
    j = i - 1;
    while ((j > -1) && (x < a[j])) {
      a[j + 1] = a[j];
      --j;
    }
    a[j + 1] = x;
    ++i;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insert>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L39
L17:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L14
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L13
  mov    %rdi,%rax
L40:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L17
L39:
  ret
  nopl   (%rax)
L14:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L40
```

assistant: ```c
void insert(int *a, int n) {
  int x, i, j;
  i = 1;
  while (i < n) {
    x = a[i];
    j = i - 1;
    while ((j > -1) && (x < a[j])) {
      a[j + 1] = a[j];
      --j;
    }
    a[j + 1] = x;
    ++i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L20
L17:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L21
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L19
  mov    %rdi,%rax
L16:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L17
L20:
  ret
  nopl   (%rax)
L21:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L16
```

assistant: ```c
void insert(int *a, int n) {
  int x, i, j;
  i = 1;
  while (i < n) {
    x = a[i];
    j = i - 1;
    while ((j > -1) && (x < a[j])) {
      a[j + 1] = a[j];
      --j;
    }
    a[j + 1] = x;
    ++i;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L0
L13:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L5
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L0
L5:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L13
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int am;
  int bm;
  am = a;
  bm = b;
  while (am != bm) {
    if (am > bm) {
      bm = bm + b;
    } else {
      am = am + a;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x0,%edx
  mov    $0x0,%eax
  cmp    %eax,%edx
  jne    L11
L9:
  mov    $0x0,%eax
  ret
L2:
  add    %edx,%edx
L39:
  cmp    %eax,%edx
  je     L9
L11:
  cmp    %eax,%edx
  jle    L2
  add    %eax,%eax
  jmp    L39
```

assistant: ```c
int main() {
  int a;
  int b;
  int am;
  int bm;
  am = a;
  bm = b;
  while (am != bm) {
    if (am > bm) {
      bm = bm + b;
    } else {
      am = am + a;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  xor    %edx,%edx
  cmp    %eax,%edx
  jne    L30
  jmp    L41
  xchg   %ax,%ax
L5:
  add    %eax,%eax
  cmp    %edx,%eax
  je     L41
L30:
  cmp    %edx,%eax
  jl     L5
  add    %edx,%edx
  cmp    %edx,%eax
  jne    L30
L41:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int am;
  int bm;
  am = a;
  bm = b;
  while (am != bm) {
    if (am > bm) {
      bm = bm + b;
    } else {
      am = am + a;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %edx,%edx
  xor    %eax,%eax
  cmp    %eax,%edx
  je     L42
  nopl   0x0(%rax)
L18:
  cmp    %eax,%edx
  jle    L29
  add    %eax,%eax
  cmp    %eax,%edx
  jne    L18
L42:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L29:
  add    %edx,%edx
  cmp    %eax,%edx
  jne    L18
  jmp    L42
```

assistant: ```c
int main() {
  int a;
  int b;
  int am;
  int bm;
  am = a;
  bm = b;
  while (am != bm) {
    if (am > bm) {
      bm = bm + b;
    } else {
      am = am + a;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dup2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <fd_close@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <real_dup2@plt>
  leave
  ret
```

assistant: ```c
int dup2(int old, int _new) {
  fd_close(_new);
  return real_dup2(old, _new);
}
```
user: What is the c source code of the assembly code below:

```asm
<dup2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <fd_close@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <real_dup2@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int dup2(int old, int _new) {
  fd_close(_new);
  return real_dup2(old, _new);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dup2>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <fd_close@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <real_dup2@plt>
```

assistant: ```c
int dup2(int old, int _new) {
  fd_close(_new);
  return real_dup2(old, _new);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dup2>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <fd_close@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <real_dup2@plt>
```

assistant: ```c
int dup2(int old, int _new) {
  fd_close(_new);
  return real_dup2(old, _new);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calc_temp_penalty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L9
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L9:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

assistant: ```c
double calc_temp_penalty(temp, tempcrit)
double temp, tempcrit;
{
  double value;
  if (temp > tempcrit)
    value = (temp - tempcrit) * (temp - tempcrit) / (8);
  return (value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_temp_penalty>:
  endbr64
  comisd %xmm1,%xmm0
  jbe    L4
  subsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm0
  movapd %xmm0,%xmm2
  mulsd  D1(%rip),%xmm2
L4:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xc0,0x3f]}

assistant: ```c
double calc_temp_penalty(temp, tempcrit)
double temp, tempcrit;
{
  double value;
  if (temp > tempcrit)
    value = (temp - tempcrit) * (temp - tempcrit) / (8);
  return (value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_temp_penalty>:
  endbr64
  comisd %xmm1,%xmm0
  jbe    L2
  subsd  %xmm1,%xmm0
  movsd  D2(%rip),%xmm2
  mulsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm2
L2:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xc0,0x3f]}

assistant: ```c
double calc_temp_penalty(temp, tempcrit)
double temp, tempcrit;
{
  double value;
  if (temp > tempcrit)
    value = (temp - tempcrit) * (temp - tempcrit) / (8);
  return (value);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calc_temp_penalty>:
  endbr64
  comisd %xmm1,%xmm0
  jbe    L8
  subsd  %xmm1,%xmm0
  movsd  D4(%rip),%xmm2
  mulsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm2
L8:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xc0,0x3f]}

assistant: ```c
double calc_temp_penalty(temp, tempcrit)
double temp, tempcrit;
{
  double value;
  if (temp > tempcrit)
    value = (temp - tempcrit) * (temp - tempcrit) / (8);
  return (value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usrdraw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wl_twdraw@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int usrdraw(w)
struct xtwindow *w;
{
  wl_twdraw(w);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usrdraw>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <wl_twdraw@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int usrdraw(w)
struct xtwindow *w;
{
  wl_twdraw(w);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usrdraw>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <wl_twdraw@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int usrdraw(w)
struct xtwindow *w;
{
  wl_twdraw(w);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usrdraw>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <wl_twdraw@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int usrdraw(w)
struct xtwindow *w;
{
  wl_twdraw(w);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<secure_computing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <current_thread_info@plt>
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <test_ti_thread_flag@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L0
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__secure_computing@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void secure_computing(int this_syscall) {
  if (__builtin_expect(!!(test_ti_thread_flag(current_thread_info(), 8)), 0))
    __secure_computing(this_syscall);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<secure_computing>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <current_thread_info@plt>
  mov    %eax,%edi
  mov    $0x8,%esi
  call   <test_ti_thread_flag@plt>
  test   %eax,%eax
  setne  %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L4
L17:
  pop    %rbx
  ret
L4:
  mov    %ebx,%edi
  call   <__secure_computing@plt>
  jmp    L17
```

assistant: ```c
__attribute__((always_)) void secure_computing(int this_syscall) {
  if (__builtin_expect(!!(test_ti_thread_flag(current_thread_info(), 8)), 0))
    __secure_computing(this_syscall);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<secure_computing>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <current_thread_info@plt>
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <test_ti_thread_flag@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setne  %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L2
  pop    %rbp
  ret
L2:
  mov    %ebp,%edi
  pop    %rbp
  jmp    10a0 <__secure_computing@plt>
```

assistant: ```c
__attribute__((always_)) void secure_computing(int this_syscall) {
  if (__builtin_expect(!!(test_ti_thread_flag(current_thread_info(), 8)), 0))
    __secure_computing(this_syscall);
}
```
user: What is the c source code of the assembly code below?

```asm
<secure_computing>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <current_thread_info@plt>
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <test_ti_thread_flag@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setne  %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L1
  pop    %rbp
  ret
L1:
  mov    %ebp,%edi
  pop    %rbp
  jmp    10a0 <__secure_computing@plt>
```

assistant: ```c
__attribute__((always_)) void secure_computing(int this_syscall) {
  if (__builtin_expect(!!(test_ti_thread_flag(current_thread_info(), 8)), 0))
    __secure_computing(this_syscall);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unicode_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L32:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <append_unicode_char@plt>
  test   %rax,%rax
  je     L1
  mov    $0xffffffff,%eax
  jmp    L34
L1:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L32
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
L34:
  leave
  ret
```

assistant: ```c
int unicode_decode(uint8_t *srcbuf, size_t srcbuflen, int mode, uint8_t **destbuf, size_t *destbuflen, size_t *destbufpos) {
  size_t i;
  uint32_t msb = mode << 8;
  for (i = 0; i < srcbuflen; i++) {
    if (append_unicode_char(destbuf, destbuflen, destbufpos, msb + srcbuf[i]))
      return -1;
  }
  return *destbufpos;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unicode_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %r9,%rbp
  shl    $0x8,%edx
  test   %rsi,%rsi
  je     L7
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %r8,%r15
  mov    %edx,%r13d
  mov    $0x0,%ebx
L26:
  mov    %r13d,%ecx
  add    (%r14,%rbx,4),%ecx
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    0x8(%rsp),%rdi
  call   <append_unicode_char@plt>
  test   %rax,%rax
  jne    L0
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L26
L7:
  mov    0x0(%rbp),%eax
L32:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L32
```

assistant: ```c
int unicode_decode(uint8_t *srcbuf, size_t srcbuflen, int mode, uint8_t **destbuf, size_t *destbuflen, size_t *destbufpos) {
  size_t i;
  uint32_t msb = mode << 8;
  for (i = 0; i < srcbuflen; i++) {
    if (append_unicode_char(destbuf, destbuflen, destbufpos, msb + srcbuf[i]))
      return -1;
  }
  return *destbufpos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<unicode_decode>:
  endbr64
  push   %r15
  shl    $0x8,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rsi,%rsi
  je     L27
  mov    %rdi,%r13
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    %edx,%r12d
  xor    %ebp,%ebp
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rbp
  cmp    %rbp,0x8(%rsp)
  je     L27
L17:
  mov    0x0(%r13,%rbp,4),%ecx
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    %r12d,%ecx
  call   <append_unicode_char@plt>
  test   %rax,%rax
  je     L15
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    (%rbx),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int unicode_decode(uint8_t *srcbuf, size_t srcbuflen, int mode, uint8_t **destbuf, size_t *destbuflen, size_t *destbufpos) {
  size_t i;
  uint32_t msb = mode << 8;
  for (i = 0; i < srcbuflen; i++) {
    if (append_unicode_char(destbuf, destbuflen, destbufpos, msb + srcbuf[i]))
      return -1;
  }
  return *destbufpos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unicode_decode>:
  endbr64
  push   %r15
  shl    $0x8,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %rsi,%rsi
  je     L39
  mov    %rdi,%r13
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    %edx,%r12d
  xor    %ebp,%ebp
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rbp
  cmp    %rbp,0x8(%rsp)
  je     L39
L19:
  mov    0x0(%r13,%rbp,4),%ecx
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    %r12d,%ecx
  call   <append_unicode_char@plt>
  test   %rax,%rax
  je     L6
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    (%rbx),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int unicode_decode(uint8_t *srcbuf, size_t srcbuflen, int mode, uint8_t **destbuf, size_t *destbuflen, size_t *destbufpos) {
  size_t i;
  uint32_t msb = mode << 8;
  for (i = 0; i < srcbuflen; i++) {
    if (append_unicode_char(destbuf, destbuflen, destbufpos, msb + srcbuf[i]))
      return -1;
  }
  return *destbufpos;
}
```
user: What is the c source code of the assembly code below?

```asm
<to_wide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L29:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jle    L2
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movsbl %al,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
  jmp    L18
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x1,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x1,%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  addl   $0x3,-0x8(%rbp)
L18:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void to_wide(char *input, unsigned int *wide) {
  int count = 0;
  int count_2 = 0;
  while (input[count]) {
    if (input[count] > 0) {
      wide[count_2] = input[count];
      count++;
    } else {
      wide[count_2] = (0x10000 * (input[count] + 1)) + (0x100 * (input[count + 1] + 1)) + (0x1 * input[count + 2]);
      count += 3;
    }
    count_2++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<to_wide>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L13
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L35
L21:
  movsbl %al,%eax
  mov    %eax,(%rsi)
  add    $0x1,%edx
L28:
  movslq %edx,%rcx
  movzbl (%rdi,%rcx,1),%eax
  add    $0x4,%rsi
  test   %al,%al
  je     L13
L35:
  test   %al,%al
  jg     L21
  movsbl 0x1(%rdi,%rcx,1),%r8d
  movsbl %al,%eax
  add    $0x1,%eax
  shl    $0x8,%eax
  lea    0x1(%r8,%rax,1),%eax
  shl    $0x8,%eax
  movsbl 0x2(%rdi,%rcx,1),%ecx
  add    %ecx,%eax
  mov    %eax,(%rsi)
  add    $0x3,%edx
  jmp    L28
L13:
  ret
```

assistant: ```c
void to_wide(char *input, unsigned int *wide) {
  int count = 0;
  int count_2 = 0;
  while (input[count]) {
    if (input[count] > 0) {
      wide[count_2] = input[count];
      count++;
    } else {
      wide[count_2] = (0x10000 * (input[count] + 1)) + (0x100 * (input[count + 1] + 1)) + (0x1 * input[count + 2]);
      count += 3;
    }
    count_2++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<to_wide>:
  endbr64
  movsbl (%rdi),%eax
  xor    %edx,%edx
  xor    %ecx,%ecx
  test   %al,%al
  jne    L32
  jmp    L12
  nopl   0x0(%rax)
L2:
  add    $0x1,%edx
L47:
  movslq %edx,%rcx
  mov    %eax,(%rsi)
  add    $0x4,%rsi
  movsbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L12
L32:
  test   %al,%al
  jg     L2
  add    $0x1,%eax
  movsbl 0x1(%rdi,%rcx,1),%r8d
  movsbl 0x2(%rdi,%rcx,1),%ecx
  add    $0x3,%edx
  movsbl %al,%eax
  shl    $0x8,%eax
  lea    0x1(%r8,%rax,1),%eax
  shl    $0x8,%eax
  add    %ecx,%eax
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void to_wide(char *input, unsigned int *wide) {
  int count = 0;
  int count_2 = 0;
  while (input[count]) {
    if (input[count] > 0) {
      wide[count_2] = input[count];
      count++;
    } else {
      wide[count_2] = (0x10000 * (input[count] + 1)) + (0x100 * (input[count + 1] + 1)) + (0x1 * input[count + 2]);
      count += 3;
    }
    count_2++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<to_wide>:
  endbr64
  movsbl (%rdi),%eax
  xor    %edx,%edx
  xor    %ecx,%ecx
  test   %al,%al
  je     L25
  nop
L30:
  test   %al,%al
  jle    L22
  add    $0x1,%edx
  mov    %eax,(%rsi)
  add    $0x4,%rsi
  movslq %edx,%rcx
  movsbl (%rdi,%rcx,1),%eax
  test   %al,%al
  jne    L30
  ret
  nopl   0x0(%rax)
L22:
  add    $0x1,%eax
  movsbl 0x1(%rdi,%rcx,1),%r8d
  add    $0x3,%edx
  add    $0x4,%rsi
  movsbl %al,%eax
  movsbl 0x2(%rdi,%rcx,1),%ecx
  shl    $0x8,%eax
  lea    0x1(%r8,%rax,1),%eax
  shl    $0x8,%eax
  add    %ecx,%eax
  movslq %edx,%rcx
  mov    %eax,-0x4(%rsi)
  movsbl (%rdi,%rcx,1),%eax
  test   %al,%al
  jne    L30
L25:
  ret
```

assistant: ```c
void to_wide(char *input, unsigned int *wide) {
  int count = 0;
  int count_2 = 0;
  while (input[count]) {
    if (input[count] > 0) {
      wide[count_2] = input[count];
      count++;
    } else {
      wide[count_2] = (0x10000 * (input[count] + 1)) + (0x100 * (input[count + 1] + 1)) + (0x1 * input[count + 2]);
      count += 3;
    }
    count_2++;
  }
}
```