user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D84(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D109(%rip),%rbp
  push   %rbx
  sub    $0x68,%rsp
  movdqa D94(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D28(%rip),%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D5(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
L38:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L38
  lea    D67(%rip),%rbp
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0xa,%esi
  call   <printf@plt>
  lea    0x30(%rsp),%rbx
  movabs $0x400000002,%rax
  lea    D44(%rip),%rdi
  mov    %rax,0x30(%rsp)
  lea    0x44(%rsp),%r12
  mov    %rbx,%rbp
  movabs $0x800000006,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%r13
  movl   $0xa,0x40(%rsp)
  call   <printf@plt>
L19:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L19
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  lea    D68(%rip),%rbp
  call   <printf@plt>
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D84
type: string
name: retrieve_data
arguments: tag: D109
type: string
name: retrieve_data
arguments: tag: D94
type: byte[16]
name: retrieve_data
arguments: tag: D28
type: byte[8]
name: retrieve_data
arguments: tag: D5
type: byte[16]
name: retrieve_data
arguments: tag: D67
type: string
name: retrieve_data
arguments: tag: D35
type: string
name: retrieve_data
arguments: tag: D44
type: string
name: retrieve_data
arguments: tag: D3
type: string
name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D68
type: string

tool: D84: 
--- Vetor ---

tool: D109: 
valor : %d 

tool: {"D94": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D28": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D5": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: D67: 
Numero Par : %d 

tool: D35: 

--- Ponteiro Vetor para Numero Pares ---

tool: D44: 


--- Novo Vetor ---

tool: D3: 
valor: %d 

tool: D0: 

--- Ponteiro Novo Vetor ---

tool: D68: 
Novo Vetor : %d 

assistant: ```c
int main(void) {
  int vetor[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int *ptr_vetor;
  int novo_vetor[10];
  int *ptr_novo_vetor;
  ptr_vetor = &vetor[0];
  printf("\n--- Vetor ---");
  for (int i = 0; i < 10; i++)
    printf("\nvalor : %d ", vetor[i]);
  printf("\n\n--- Ponteiro Vetor para Numero Pares ---");
  for (int i = 0; i < 10; i++) {
    if (ptr_vetor[i] % 2 == 0) {
      printf("\nNumero Par : %d ", ptr_vetor[i]);
      novo_vetor[i / 2] = ptr_vetor[i];
    }
  }
  ptr_novo_vetor = novo_vetor;
  printf("\n\n\n--- Novo Vetor ---");
  for (int i = 0; i < 10 / 2; i++)
    printf("\nvalor: %d ", novo_vetor[i]);
  printf("\n\n--- Ponteiro Novo Vetor ---");
  for (int i = 0; i < 10 / 2; i++)
    printf("\nNovo Vetor : %d ", *(ptr_novo_vetor + i));
}
```