ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<arp_generate_packet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  lea    0xc(%rdx),%rcx
  mov    %eax,%edx
  mov    $0xff,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  add    $0x40,%rax
  mov    %rax,-0x8(%rbp)
  mov    D73(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x30(%rdx)
  mov    D58(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x28(%rdx)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  movl   $0x4,0x4(%rax)
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x20(%rdx)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,%rcx
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void arp_generate_packet(struct in_addr sip, struct in_addr tip, struct ether_addr smac, u_int8_t *packet) {
  struct ether_header *eth_header;
  struct ether_arp *arp_header;
  eth_header = (struct ether_header *)packet;
  memset((void *)&eth_header->ether_dhost, 0xff, ETH_ALEN);
  memcpy((void *)&eth_header->ether_shost, (void *)&smac.ether_addr_octet, ETH_ALEN);
  eth_header->ether_type = htons(ETHERTYPE_ARP);
  arp_header = (struct ether_arp *)(packet + sizeof(struct ether_header));
  arp_header->arp_hrd = htons(ARPHRD_ETHER);
  arp_header->arp_pro = htons(ETHERTYPE_IP);
  arp_header->arp_hln = ETH_ALEN;
  arp_header->arp_pln = 4;
  arp_header->arp_op = htons(ARPOP_REQUEST);
  memcpy((void *)arp_header->arp_sha, (void *)&smac.ether_addr_octet, ETH_ALEN);
  memcpy((void *)arp_header->arp_spa, (void *)&sip.s_addr, 4);
  memcpy((void *)arp_header->arp_tpa, (void *)&tip.s_addr, 4);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<arp_generate_packet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %rcx,%rbx
  mov    D0(%rip),%rbp
  lea    0xc(%rcx),%rdi
  mov    0x0(%rbp),%edx
  mov    $0xff,%esi
  call   <memset@plt>
  lea    0x4(%rsp),%r12
  lea    0x8(%rbx),%rdi
  mov    0x0(%rbp),%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    D46(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    %rax,(%rbx)
  mov    D30(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    %rax,0x70(%rbx)
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    %rax,0x68(%rbx)
  mov    0x0(%rbp),%eax
  mov    %eax,0x40(%rbx)
  movl   $0x4,0x44(%rbx)
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    %rax,0x60(%rbx)
  mov    0x58(%rbx),%rdi
  mov    0x0(%rbp),%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  lea    0xc(%rsp),%rsi
  mov    0x50(%rbx),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x8(%rsp),%rsi
  mov    0x48(%rbx),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void arp_generate_packet(struct in_addr sip, struct in_addr tip, struct ether_addr smac, u_int8_t *packet) {
  struct ether_header *eth_header;
  struct ether_arp *arp_header;
  eth_header = (struct ether_header *)packet;
  memset((void *)&eth_header->ether_dhost, 0xff, ETH_ALEN);
  memcpy((void *)&eth_header->ether_shost, (void *)&smac.ether_addr_octet, ETH_ALEN);
  eth_header->ether_type = htons(ETHERTYPE_ARP);
  arp_header = (struct ether_arp *)(packet + sizeof(struct ether_header));
  arp_header->arp_hrd = htons(ARPHRD_ETHER);
  arp_header->arp_pro = htons(ETHERTYPE_IP);
  arp_header->arp_hln = ETH_ALEN;
  arp_header->arp_pln = 4;
  arp_header->arp_op = htons(ARPOP_REQUEST);
  memcpy((void *)arp_header->arp_sha, (void *)&smac.ether_addr_octet, ETH_ALEN);
  memcpy((void *)arp_header->arp_spa, (void *)&sip.s_addr, 4);
  memcpy((void *)arp_header->arp_tpa, (void *)&tip.s_addr, 4);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arp_generate_packet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    D6(%rip),%rbp
  mov    %edx,0x4(%rsp)
  lea    0x4(%rsp),%r12
  mov    0x0(%rbp),%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rcx),%rdi
  mov    %esi,0x8(%rsp)
  mov    $0xff,%esi
  call   <memset@plt>
  mov    0x0(%rbp),%edx
  mov    %r12,%rsi
  lea    0x8(%rbx),%rdi
  call   <memcpy@plt>
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    %rax,(%rbx)
  mov    D34(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    %rax,0x70(%rbx)
  mov    D41(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  movl   $0x4,0x44(%rbx)
  mov    %rax,0x68(%rbx)
  mov    0x0(%rbp),%eax
  mov    %eax,0x40(%rbx)
  mov    D28(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    0x58(%rbx),%rdi
  mov    0x0(%rbp),%edx
  mov    %r12,%rsi
  mov    %rax,0x60(%rbx)
  call   <memcpy@plt>
  mov    0x50(%rbx),%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x48(%rbx),%rdi
  lea    0x8(%rsp),%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void arp_generate_packet(struct in_addr sip, struct in_addr tip, struct ether_addr smac, u_int8_t *packet) {
  struct ether_header *eth_header;
  struct ether_arp *arp_header;
  eth_header = (struct ether_header *)packet;
  memset((void *)&eth_header->ether_dhost, 0xff, ETH_ALEN);
  memcpy((void *)&eth_header->ether_shost, (void *)&smac.ether_addr_octet, ETH_ALEN);
  eth_header->ether_type = htons(ETHERTYPE_ARP);
  arp_header = (struct ether_arp *)(packet + sizeof(struct ether_header));
  arp_header->arp_hrd = htons(ARPHRD_ETHER);
  arp_header->arp_pro = htons(ETHERTYPE_IP);
  arp_header->arp_hln = ETH_ALEN;
  arp_header->arp_pln = 4;
  arp_header->arp_op = htons(ARPOP_REQUEST);
  memcpy((void *)arp_header->arp_sha, (void *)&smac.ether_addr_octet, ETH_ALEN);
  memcpy((void *)arp_header->arp_spa, (void *)&sip.s_addr, 4);
  memcpy((void *)arp_header->arp_tpa, (void *)&tip.s_addr, 4);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<arp_generate_packet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    D15(%rip),%rbp
  mov    %edx,0x4(%rsp)
  lea    0x4(%rsp),%r12
  mov    0x0(%rbp),%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rcx),%rdi
  mov    %esi,0x8(%rsp)
  mov    $0xff,%esi
  call   <memset@plt>
  mov    0x0(%rbp),%edx
  mov    %r12,%rsi
  lea    0x8(%rbx),%rdi
  call   <memcpy@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    %rax,(%rbx)
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    %rax,0x70(%rbx)
  mov    D36(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  movl   $0x4,0x44(%rbx)
  mov    %rax,0x68(%rbx)
  mov    0x0(%rbp),%eax
  mov    %eax,0x40(%rbx)
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <htons@plt>
  mov    0x58(%rbx),%rdi
  mov    0x0(%rbp),%edx
  mov    %r12,%rsi
  mov    %rax,0x60(%rbx)
  call   <memcpy@plt>
  mov    0x50(%rbx),%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x48(%rbx),%rdi
  lea    0x8(%rsp),%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void arp_generate_packet(struct in_addr sip, struct in_addr tip, struct ether_addr smac, u_int8_t *packet) {
  struct ether_header *eth_header;
  struct ether_arp *arp_header;
  eth_header = (struct ether_header *)packet;
  memset((void *)&eth_header->ether_dhost, 0xff, ETH_ALEN);
  memcpy((void *)&eth_header->ether_shost, (void *)&smac.ether_addr_octet, ETH_ALEN);
  eth_header->ether_type = htons(ETHERTYPE_ARP);
  arp_header = (struct ether_arp *)(packet + sizeof(struct ether_header));
  arp_header->arp_hrd = htons(ARPHRD_ETHER);
  arp_header->arp_pro = htons(ETHERTYPE_IP);
  arp_header->arp_hln = ETH_ALEN;
  arp_header->arp_pln = 4;
  arp_header->arp_op = htons(ARPOP_REQUEST);
  memcpy((void *)arp_header->arp_sha, (void *)&smac.ether_addr_octet, ETH_ALEN);
  memcpy((void *)arp_header->arp_spa, (void *)&sip.s_addr, 4);
  memcpy((void *)arp_header->arp_tpa, (void *)&tip.s_addr, 4);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<absdiff_cm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jg     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long absdiff_cm(long x, long y) {
  long result;
  result = x - y;
  long eval = y - x;
  if (x <= y)
    result = eval;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<absdiff_cm>:
  endbr64
  mov    %rdi,%rdx
  sub    %rsi,%rdx
  mov    %rsi,%rax
  sub    %rdi,%rax
  cmp    %rsi,%rdi
  cmovg  %rdx,%rax
  ret
```

assistant: ```c
long absdiff_cm(long x, long y) {
  long result;
  result = x - y;
  long eval = y - x;
  if (x <= y)
    result = eval;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<absdiff_cm>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rax
  sub    %rsi,%rdx
  sub    %rdi,%rax
  cmp    %rsi,%rdi
  cmovg  %rdx,%rax
  ret
```

assistant: ```c
long absdiff_cm(long x, long y) {
  long result;
  result = x - y;
  long eval = y - x;
  if (x <= y)
    result = eval;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<absdiff_cm>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rax
  sub    %rsi,%rdx
  sub    %rdi,%rax
  cmp    %rsi,%rdi
  cmovg  %rdx,%rax
  ret
```

assistant: ```c
long absdiff_cm(long x, long y) {
  long result;
  result = x - y;
  long eval = y - x;
  if (x <= y)
    result = eval;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<size_sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <size_sub_check@plt>
  test   %rax,%rax
  je     L3
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L11
L3:
  mov    $0x1,%eax
L11:
  leave
  ret
```

assistant: ```c
int size_sub(size_t *z, const size_t x, const size_t y) {
  assert(z != NULL);
  if (size_sub_check(x, y) != 0) {
    *z = x - y;
    return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<size_sub>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <size_sub_check@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L13
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  sub    %r12,%rbx
  mov    %rbx,0x0(%rbp)
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
int size_sub(size_t *z, const size_t x, const size_t y) {
  assert(z != NULL);
  if (size_sub_check(x, y) != 0) {
    *z = x - y;
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<size_sub>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  setne  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <size_sub_check@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L5
  sub    %r12,%rbx
  xor    %eax,%eax
  mov    %rbx,0x0(%rbp)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int size_sub(size_t *z, const size_t x, const size_t y) {
  assert(z != NULL);
  if (size_sub_check(x, y) != 0) {
    *z = x - y;
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<size_sub>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  setne  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <size_sub_check@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L6
  sub    %r12,%rbx
  xor    %eax,%eax
  mov    %rbx,0x0(%rbp)
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int size_sub(size_t *z, const size_t x, const size_t y) {
  assert(z != NULL);
  if (size_sub_check(x, y) != 0) {
    *z = x - y;
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<psvec2i_bezier4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edi
  mov    -0x28(%rbp),%r8
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  movd   %edi,%xmm0
  mov    %rax,%rdi
  call   <vec2i_bezier4@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2i *psvec2i_bezier4(struct vec2i *result, struct vec2i *a, struct vec2i *b, struct vec2i *c, struct vec2i *d, float p) {
  vec2i_bezier4((int32_t *)result, (int32_t *)a, (int32_t *)b, (int32_t *)c, (int32_t *)d, p);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psvec2i_bezier4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec2i_bezier4@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2i *psvec2i_bezier4(struct vec2i *result, struct vec2i *a, struct vec2i *b, struct vec2i *c, struct vec2i *d, float p) {
  vec2i_bezier4((int32_t *)result, (int32_t *)a, (int32_t *)b, (int32_t *)c, (int32_t *)d, p);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<psvec2i_bezier4>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2i_bezier4@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2i *psvec2i_bezier4(struct vec2i *result, struct vec2i *a, struct vec2i *b, struct vec2i *c, struct vec2i *d, float p) {
  vec2i_bezier4((int32_t *)result, (int32_t *)a, (int32_t *)b, (int32_t *)c, (int32_t *)d, p);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<psvec2i_bezier4>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2i_bezier4@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2i *psvec2i_bezier4(struct vec2i *result, struct vec2i *a, struct vec2i *b, struct vec2i *c, struct vec2i *d, float p) {
  vec2i_bezier4((int32_t *)result, (int32_t *)a, (int32_t *)b, (int32_t *)c, (int32_t *)d, p);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gennot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gentext@plt>
  mov    $0x0,%eax
  call   <cgnot@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gennot(void) {
  gentext();
  cgnot();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gennot>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gentext@plt>
  mov    $0x0,%eax
  call   <cgnot@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gennot(void) {
  gentext();
  cgnot();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gennot>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gentext@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cgnot@plt>
```

assistant: ```c
void gennot(void) {
  gentext();
  cgnot();
}
```
user: Translate the below assembly code into C programming language:

```asm
<gennot>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gentext@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cgnot@plt>
```

assistant: ```c
void gennot(void) {
  gentext();
  cgnot();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  sub    $0x96a,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  lea    -0x258d(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      copy11 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy11;
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy11;
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 760496316UL) + (unsigned short)39351;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x2ef7,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      copy11 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy11;
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy11;
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 760496316UL) + (unsigned short)39351;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x2ef7,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      copy11 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy11;
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy11;
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 760496316UL) + (unsigned short)39351;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x2ef7,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      copy11 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy11;
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy11;
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 760496316UL) + (unsigned short)39351;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<aclamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L18
L17:
  addq   $0x1a,-0x8(%rbp)
L18:
  cmpq   $0x0,-0x8(%rbp)
  js     L17
  mov    -0x8(%rbp),%rcx
  movabs $0x4ec4ec4ec4ec4ec5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x3,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int aclamp(long val) {
  while (val < 0)
    val += 26;
  return val % 26;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aclamp>:
  endbr64
  test   %rdi,%rdi
  jns    L19
L1:
  add    $0x1a,%rdi
  js     L1
L19:
  movabs $0x4ec4ec4ec4ec4ec5,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x3,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,2),%rax
  lea    (%rdx,%rax,4),%rdx
  add    %rdx,%rdx
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int aclamp(long val) {
  while (val < 0)
    val += 26;
  return val % 26;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aclamp>:
  endbr64
  test   %rdi,%rdi
  jns    L1
  nopl   0x0(%rax)
L19:
  add    $0x1a,%rdi
  js     L19
L1:
  movabs $0x4ec4ec4ec4ec4ec5,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,2),%rax
  lea    (%rdx,%rax,4),%rdx
  mov    %edi,%eax
  add    %rdx,%rdx
  sub    %edx,%eax
  ret
```

assistant: ```c
int aclamp(long val) {
  while (val < 0)
    val += 26;
  return val % 26;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<aclamp>:
  endbr64
  test   %rdi,%rdi
  jns    L7
  nopl   0x0(%rax)
L18:
  add    $0x1a,%rdi
  js     L18
L7:
  movabs $0x4ec4ec4ec4ec4ec5,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,2),%rax
  lea    (%rdx,%rax,4),%rdx
  mov    %edi,%eax
  add    %rdx,%rdx
  sub    %edx,%eax
  ret
```

assistant: ```c
int aclamp(long val) {
  while (val < 0)
    val += 26;
  return val % 26;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<validate_license>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0xffffffff,%eax
  jmp    L6
L27:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x32,%eax
  jle    L20
  mov    $0xffffffff,%eax
  jmp    L6
L20:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
int validate_license(const char *license) {
  if (license == NULL) {
    return -1;
  }
  if (strlen(license) > 50) {
    return -1;
  }
  return 0;
}
```