ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<init>:
  endbr64
  lea    0x8(%rdi),%rax
  mov    %rsi,%rcx
  mov    %rdx,%r8
  sub    %rax,%rsi
  cmp    $0x10,%rsi
  seta   %sil
  sub    %rax,%r8
  cmp    $0x10,%r8
  seta   %al
  test   %al,%sil
  je     L3
  lea    0x8(%rcx),%rsi
  mov    %rdx,%rax
  sub    %rsi,%rax
  cmp    $0x10,%rax
  jbe    L3
  movdqa D26(%rip),%xmm2
  movdqa D15(%rip),%xmm5
  xor    %eax,%eax
  movdqa D13(%rip),%xmm4
  cs nopw 0x0(%rax,%rax,1)
L23:
  movdqa %xmm2,%xmm1
  paddd  %xmm5,%xmm2
  pshufd $0xee,%xmm1,%xmm0
  cvtdq2pd %xmm1,%xmm3
  movups %xmm3,(%rdi,%rax,1)
  cvtdq2pd %xmm0,%xmm0
  movups %xmm0,0x10(%rdi,%rax,1)
  movups %xmm0,0x10(%rcx,%rax,1)
  movdqa %xmm4,%xmm0
  psubd  %xmm1,%xmm0
  movups %xmm3,(%rcx,%rax,1)
  cvtdq2pd %xmm0,%xmm1
  pshufd $0xee,%xmm0,%xmm0
  movups %xmm1,(%rdx,%rax,1)
  cvtdq2pd %xmm0,%xmm0
  movups %xmm0,0x10(%rdx,%rax,1)
  add    $0x20,%rax
  cmp    $0x320,%rax
  jne    L23
  ret
L3:
  xor    %eax,%eax
  mov    $0x64,%r8d
  nopw   0x0(%rax,%rax,1)
L22:
  pxor   %xmm0,%xmm0
  mov    %r8d,%esi
  cvtsi2sd %eax,%xmm0
  sub    %eax,%esi
  movsd  %xmm0,(%rdi,%rax,8)
  movsd  %xmm0,(%rcx,%rax,8)
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L22
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D15
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D13
data_type: byte[16]

tool: {"D26": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D15": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D13": [0x64,0x00,0x00,0x00,0x64,0x00,0x00,0x00,0x64,0x00,0x00,0x00,0x64,0x00,0x00,0x00]}

assistant: ```c
void init(double *a, double *a_ref, double *b, int n) {
  int i;
  for (i = 0; i < 100; i++) {
    a[i] = i;
    a_ref[i] = i;
    b[i] = 100 - i;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<minipack_pack_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  movq   $0x5,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0xca,(%rax)
  addq   $0x4,-0x18(%rbp)
  lea    -0x1c(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void minipack_pack_float(void *ptr, float value, size_t *sz) {
  *sz = 5;
  uint8_t *buffer = ptr;
  uint32_t *value_ptr = (uint32_t *)&value;
  uint32_t bytes = htonl(*value_ptr);
  buffer[0] = 0xCA;
  buffer = buffer + 1;
  memcpy(buffer, &bytes, 4);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<minipack_pack_float>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  movd   %xmm0,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x5,(%rsi)
  call   <htonl@plt>
  mov    %eax,0x4(%rsp)
  movl   $0xca,(%rbx)
  lea    0x4(%rsp),%rsi
  lea    0x4(%rbx),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void minipack_pack_float(void *ptr, float value, size_t *sz) {
  *sz = 5;
  uint8_t *buffer = ptr;
  uint32_t *value_ptr = (uint32_t *)&value;
  uint32_t bytes = htonl(*value_ptr);
  buffer[0] = 0xCA;
  buffer = buffer + 1;
  memcpy(buffer, &bytes, 4);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<minipack_pack_float>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movd   %xmm0,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x5,(%rsi)
  call   <htonl@plt>
  movl   $0xca,(%rbx)
  lea    0x4(%rsp),%rsi
  lea    0x4(%rbx),%rdi
  mov    $0x4,%edx
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void minipack_pack_float(void *ptr, float value, size_t *sz) {
  *sz = 5;
  uint8_t *buffer = ptr;
  uint32_t *value_ptr = (uint32_t *)&value;
  uint32_t bytes = htonl(*value_ptr);
  buffer[0] = 0xCA;
  buffer = buffer + 1;
  memcpy(buffer, &bytes, 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minipack_pack_float>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movd   %xmm0,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x5,(%rsi)
  call   <htonl@plt>
  movl   $0xca,(%rbx)
  lea    0x4(%rsp),%rsi
  lea    0x4(%rbx),%rdi
  mov    $0x4,%edx
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void minipack_pack_float(void *ptr, float value, size_t *sz) {
  *sz = 5;
  uint8_t *buffer = ptr;
  uint32_t *value_ptr = (uint32_t *)&value;
  uint32_t bytes = htonl(*value_ptr);
  buffer[0] = 0xCA;
  buffer = buffer + 1;
  memcpy(buffer, &bytes, 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<initial_values_length_metric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <validate_values@plt>
  mov    -0x20(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <convert_values_length_metric@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D9: Please enter your values to be converted (Feet, Inches): 

tool: D5: %d %lf

assistant: ```c
void initial_values_length_metric() {
  int main_value, scanf_return;
  double sec_value, main_value_db;
  printf("Please enter your values to be converted (Feet, Inches): ");
  scanf_return = scanf("%d %lf", &main_value, &sec_value);
  validate_values(&main_value, &sec_value, scanf_return);
  main_value_db = main_value;
  convert_values_length_metric(&main_value_db, &sec_value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<initial_values_length_metric>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rbx
  lea    0x4(%rsp),%rbp
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <validate_values@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x4(%rsp),%xmm0
  movsd  %xmm0,0x10(%rsp)
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <convert_values_length_metric@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D13
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string

tool: D13: Please enter your values to be converted (Feet, Inches): 

tool: D15: %d %lf

assistant: ```c
void initial_values_length_metric() {
  int main_value, scanf_return;
  double sec_value, main_value_db;
  printf("Please enter your values to be converted (Feet, Inches): ");
  scanf_return = scanf("%d %lf", &main_value, &sec_value);
  validate_values(&main_value, &sec_value, scanf_return);
  main_value_db = main_value;
  convert_values_length_metric(&main_value_db, &sec_value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<initial_values_length_metric>:
  endbr64
  push   %r12
  lea    D19(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <validate_values@plt>
  pxor   %xmm0,%xmm0
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  cvtsi2sdl 0x4(%rsp),%xmm0
  movsd  %xmm0,0x10(%rsp)
  call   <convert_values_length_metric@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D14
type: string

tool: D19: Please enter your values to be converted (Feet, Inches): 

tool: D14: %d %lf

assistant: ```c
void initial_values_length_metric() {
  int main_value, scanf_return;
  double sec_value, main_value_db;
  printf("Please enter your values to be converted (Feet, Inches): ");
  scanf_return = scanf("%d %lf", &main_value, &sec_value);
  validate_values(&main_value, &sec_value, scanf_return);
  main_value_db = main_value;
  convert_values_length_metric(&main_value_db, &sec_value);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<initial_values_length_metric>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <validate_values@plt>
  pxor   %xmm0,%xmm0
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  cvtsi2sdl 0x4(%rsp),%xmm0
  movsd  %xmm0,0x10(%rsp)
  call   <convert_values_length_metric@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string

tool: D3: Please enter your values to be converted (Feet, Inches): 

tool: D9: %d %lf

assistant: ```c
void initial_values_length_metric() {
  int main_value, scanf_return;
  double sec_value, main_value_db;
  printf("Please enter your values to be converted (Feet, Inches): ");
  scanf_return = scanf("%d %lf", &main_value, &sec_value);
  validate_values(&main_value, &sec_value, scanf_return);
  main_value_db = main_value;
  convert_values_length_metric(&main_value_db, &sec_value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rotate_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  neg    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    $0x20,%eax
  sub    %edx,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  and    %ecx,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned rotate_left(unsigned x, int n) {
  int z_mask = -!n;
  unsigned left = x << n;
  unsigned right = x >> ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotate_left>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  sete   %dl
  movzbl %dl,%edx
  lea    -0x1(%rdx),%eax
  mov    %edi,%esi
  rol    %cl,%esi
  and    %esi,%eax
  neg    %edx
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_left(unsigned x, int n) {
  int z_mask = -!n;
  unsigned left = x << n;
  unsigned right = x >> ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotate_left>:
  endbr64
  xor    %edx,%edx
  test   %esi,%esi
  mov    %esi,%ecx
  mov    %edi,%esi
  sete   %dl
  rol    %cl,%esi
  lea    -0x1(%rdx),%eax
  neg    %edx
  and    %esi,%eax
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_left(unsigned x, int n) {
  int z_mask = -!n;
  unsigned left = x << n;
  unsigned right = x >> ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rotate_left>:
  endbr64
  xor    %edx,%edx
  test   %esi,%esi
  mov    %esi,%ecx
  mov    %edi,%esi
  sete   %dl
  rol    %cl,%esi
  lea    -0x1(%rdx),%eax
  neg    %edx
  and    %esi,%eax
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_left(unsigned x, int n) {
  int z_mask = -!n;
  unsigned left = x << n;
  unsigned right = x >> ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dehex_nibble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jle    L14
  subl   $0x7,-0x4(%rbp)
L14:
  cmpl   $0xf,-0x4(%rbp)
  jle    L10
  subl   $0x20,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int dehex_nibble(int n) {
  int x;
  x = n - 0x30;
  if (x > 9)
    x -= 0x07;
  if (x > 15)
    x -= 0x20;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dehex_nibble>:
  endbr64
  lea    -0x30(%rdi),%eax
  sub    $0x37,%edi
  cmp    $0x9,%eax
  cmovg  %edi,%eax
  lea    -0x20(%rax),%edx
  cmp    $0xf,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int dehex_nibble(int n) {
  int x;
  x = n - 0x30;
  if (x > 9)
    x -= 0x07;
  if (x > 15)
    x -= 0x20;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dehex_nibble>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jle    L15
  lea    -0x37(%rdi),%eax
  cmp    $0xf,%eax
  jle    L15
  lea    -0x57(%rdi),%eax
L15:
  ret
```

assistant: ```c
int dehex_nibble(int n) {
  int x;
  x = n - 0x30;
  if (x > 9)
    x -= 0x07;
  if (x > 15)
    x -= 0x20;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dehex_nibble>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jle    L3
  lea    -0x37(%rdi),%eax
  cmp    $0xf,%eax
  jle    L3
  lea    -0x57(%rdi),%eax
L3:
  ret
```

assistant: ```c
int dehex_nibble(int n) {
  int x;
  x = n - 0x30;
  if (x > 9)
    x -= 0x07;
  if (x > 15)
    x -= 0x20;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L1:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <send@plt>
L2:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void send_block(const uint8_t *data, const uint32_t size) {
  uint32_t cnt = size;
  while (cnt--)
    send(*(data++));
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_block>:
  endbr64
  test   %esi,%esi
  je     L9
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rbp
L7:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%edi
  call   <send@plt>
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  ret
```

assistant: ```c
void send_block(const uint8_t *data, const uint32_t size) {
  uint32_t cnt = size;
  while (cnt--)
    send(*(data++));
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_block>:
  endbr64
  test   %esi,%esi
  je     L12
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <send@plt>
  cmp    %rbp,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void send_block(const uint8_t *data, const uint32_t size) {
  uint32_t cnt = size;
  while (cnt--)
    send(*(data++));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_block>:
  endbr64
  test   %esi,%esi
  je     L8
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <send@plt>
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void send_block(const uint8_t *data, const uint32_t size) {
  uint32_t cnt = size;
  while (cnt--)
    send(*(data++));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parrot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %rdi,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  mulsd  -0x20(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  D1(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: f64
name: retrieve_data
arguments: tag: D1
type_guessed: f64

tool: D8: 0.2

tool: D1: 1.2

assistant: ```c
double *parrot(double t, double X[]) {
  double x = X[0], y = X[1];
  double x_dot, y_dot;
  double *X_dot = malloc(2 * sizeof(double));
  x_dot = y + pow(y, 2);
  y_dot = -x + 0.2 * y - x * y + 1.2 * pow(y, 2);
  X_dot[0] = x_dot;
  X_dot[1] = y_dot;
  return X_dot;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parrot>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%r12
  mov    0x8(%rdi),%rbp
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x2,%edi
  movq   %rbp,%xmm0
  call   <pow@plt>
  movq   %rbp,%xmm2
  addsd  %xmm2,%xmm0
  movq   %xmm0,%r13
  movq   %rbp,%xmm1
  mulsd  D14(%rip),%xmm1
  movq   %r12,%xmm3
  subsd  %xmm3,%xmm1
  movq   %r12,%xmm0
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  mov    $0x2,%edi
  movq   %rbp,%xmm0
  call   <pow@plt>
  mov    %r13,(%rbx)
  mulsd  D16(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rbx)
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: f64
name: disassemble_data
arguments: data_label: D16
type: f64

tool: D14: 0.2

tool: D16: 1.2

assistant: ```c
double *parrot(double t, double X[]) {
  double x = X[0], y = X[1];
  double x_dot, y_dot;
  double *X_dot = malloc(2 * sizeof(double));
  x_dot = y + pow(y, 2);
  y_dot = -x + 0.2 * y - x * y + 1.2 * pow(y, 2);
  X_dot[0] = x_dot;
  X_dot[1] = y_dot;
  return X_dot;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parrot>:
  endbr64
  push   %r12
  sub    $0x20,%rsp
  movsd  (%rdi),%xmm2
  movsd  0x8(%rdi),%xmm1
  mov    $0x10,%edi
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <malloc@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x2,%edi
  mov    %rax,%r12
  movapd %xmm1,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  mov    $0x2,%edi
  movapd %xmm0,%xmm3
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm3
  mulsd  %xmm1,%xmm0
  movsd  %xmm3,0x10(%rsp)
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mulsd  D13(%rip),%xmm0
  movsd  0x10(%rsp),%xmm3
  mov    %r12,%rax
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm3,(%r12)
  movsd  %xmm0,0x8(%r12)
  add    $0x20,%rsp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D2
datatype: f64
name: read_data
arguments: tag: D13
datatype: f64

tool: D2: 0.2

tool: D13: 1.2

assistant: ```c
double *parrot(double t, double X[]) {
  double x = X[0], y = X[1];
  double x_dot, y_dot;
  double *X_dot = malloc(2 * sizeof(double));
  x_dot = y + pow(y, 2);
  y_dot = -x + 0.2 * y - x * y + 1.2 * pow(y, 2);
  X_dot[0] = x_dot;
  X_dot[1] = y_dot;
  return X_dot;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parrot>:
  endbr64
  push   %r12
  sub    $0x20,%rsp
  movsd  (%rdi),%xmm3
  movsd  0x8(%rdi),%xmm2
  mov    $0x10,%edi
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <malloc@plt>
  movsd  0x8(%rsp),%xmm2
  mov    $0x2,%edi
  mov    %rax,%r12
  movapd %xmm2,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  mov    $0x2,%edi
  movapd %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  movsd  %xmm1,0x10(%rsp)
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm3
  subsd  %xmm3,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <pow@plt>
  mulsd  D18(%rip),%xmm0
  movsd  0x10(%rsp),%xmm1
  mov    %r12,%rax
  addsd  0x8(%rsp),%xmm0
  unpcklpd %xmm0,%xmm1
  movups %xmm1,(%r12)
  add    $0x20,%rsp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: f64
name: unpack_data
arguments: data_tag: D18
data_type: f64

tool: D2: 0.2

tool: D18: 1.2

assistant: ```c
double *parrot(double t, double X[]) {
  double x = X[0], y = X[1];
  double x_dot, y_dot;
  double *X_dot = malloc(2 * sizeof(double));
  x_dot = y + pow(y, 2);
  y_dot = -x + 0.2 * y - x * y + 1.2 * pow(y, 2);
  X_dot[0] = x_dot;
  X_dot[1] = y_dot;
  return X_dot;
}
```