ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<Assert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L6:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: Assertion Failed: %s


assistant: ```c
void Assert(int assertion, char const *error) {
  if (!assertion) {
    printf("Assertion Failed: %s\n", error);
    exit(-1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Assert>:
  endbr64
  test   %edi,%edi
  je     L8
  ret
L8:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: Assertion Failed: %s


assistant: ```c
void Assert(int assertion, char const *error) {
  if (!assertion) {
    printf("Assertion Failed: %s\n", error);
    exit(-1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Assert>:
  endbr64
  test   %edi,%edi
  je     L7
  ret
  nopl   0x0(%rax)
L7:
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: Assertion Failed: %s


assistant: ```c
void Assert(int assertion, char const *error) {
  if (!assertion) {
    printf("Assertion Failed: %s\n", error);
    exit(-1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Assert>:
  endbr64
  test   %edi,%edi
  je     L1
  ret
  nopl   0x0(%rax)
L1:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: Assertion Failed: %s


assistant: ```c
void Assert(int assertion, char const *error) {
  if (!assertion) {
    printf("Assertion Failed: %s\n", error);
    exit(-1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L202
  cmpl   $0x8,-0x8(%rbp)
  je     L100
  cmpl   $0x8,-0x8(%rbp)
  jg     L128
  cmpl   $0x4,-0x8(%rbp)
  je     L83
  cmpl   $0x4,-0x8(%rbp)
  jg     L128
  cmpl   $0x1,-0x8(%rbp)
  je     L39
  cmpl   $0x2,-0x8(%rbp)
  je     L205
  jmp    L128
L39:
  lea    D86(%rip),%rax
  jmp    L178
L205:
  lea    D6(%rip),%rax
  jmp    L178
L83:
  lea    D14(%rip),%rax
  jmp    L178
L100:
  lea    D78(%rip),%rax
  jmp    L178
L128:
  lea    D50(%rip),%rax
  jmp    L178
L202:
  cmpl   $0x8,-0x8(%rbp)
  je     L77
  cmpl   $0x8,-0x8(%rbp)
  jg     L233
  cmpl   $0x4,-0x8(%rbp)
  je     L144
  cmpl   $0x4,-0x8(%rbp)
  jg     L233
  cmpl   $0x1,-0x8(%rbp)
  je     L80
  cmpl   $0x2,-0x8(%rbp)
  je     L50
  jmp    L233
L80:
  lea    D35(%rip),%rax
  jmp    L178
L50:
  lea    D48(%rip),%rax
  jmp    L178
L144:
  lea    D39(%rip),%rax
  jmp    L178
L77:
  lea    D78(%rip),%rax
  jmp    L178
L233:
  lea    D50(%rip),%rax
L178:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D86
type: string
name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D78
type: string
name: retrieve_data
arguments: tag: D50
type: string
name: retrieve_data
arguments: tag: D35
type: string
name: retrieve_data
arguments: tag: D48
type: string
name: retrieve_data
arguments: tag: D39
type: string

tool: D86: Interfaces.C.signed_char

tool: D6: Interfaces.C.short

tool: D14: Interfaces.C.long

tool: D78: Long_Long_Integer

tool: D50: <invalid>

tool: D35: Interfaces.C.unsigned_char

tool: D48: Interfaces.C.unsigned_short

tool: D39: Interfaces.C.unsigned_long

assistant: ```c
const char *get_type(int is_signed, int size) {
  if (is_signed) {
    switch (size) {
    case 1:
      return "Interfaces.C.signed_char";
    case 2:
      return "Interfaces.C.short";
    case 4:
      if (sizeof(int) == 4) {
        return "Interfaces.C.long";
      } else {
        return "Interfaces.C.int";
      }
    case 8:
      return "Long_Long_Integer";
    default:
      return "<invalid>";
    }
  } else {
    switch (size) {
    case 1:
      return "Interfaces.C.unsigned_char";
    case 2:
      return "Interfaces.C.unsigned_short";
    case 4:
      if (sizeof(int) == 4) {
        return "Interfaces.C.unsigned_long";
      } else {
        return "Interfaces.C.unsigned_int";
      }
    case 8:
      return "Long_Long_Integer";
    default:
      return "<invalid>";
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_type>:
  endbr64
  test   %edi,%edi
  je     L62
  lea    D76(%rip),%rax
  cmp    $0x4,%esi
  je     L47
  jg     L51
  lea    D83(%rip),%rax
  cmp    $0x1,%esi
  je     L47
  cmp    $0x2,%esi
  lea    D91(%rip),%rax
  lea    D51(%rip),%rdx
  cmove  %rdx,%rax
  ret
L51:
  cmp    $0x8,%esi
  lea    D91(%rip),%rax
  lea    D88(%rip),%rdx
  cmove  %rdx,%rax
  ret
L62:
  lea    D63(%rip),%rax
  cmp    $0x4,%esi
  je     L47
  jg     L42
  lea    D75(%rip),%rax
  cmp    $0x1,%esi
  je     L47
  cmp    $0x2,%esi
  lea    D91(%rip),%rax
  lea    D97(%rip),%rdx
  cmove  %rdx,%rax
  ret
L42:
  cmp    $0x8,%esi
  lea    D91(%rip),%rax
  lea    D88(%rip),%rdx
  cmove  %rdx,%rax
L47:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D76
datatype: string
name: parse_data
arguments: data_tag: D83
datatype: string
name: parse_data
arguments: data_tag: D91
datatype: string
name: parse_data
arguments: data_tag: D51
datatype: string
name: parse_data
arguments: data_tag: D88
datatype: string
name: parse_data
arguments: data_tag: D63
datatype: string
name: parse_data
arguments: data_tag: D75
datatype: string
name: parse_data
arguments: data_tag: D97
datatype: string

tool: D76: Interfaces.C.long

tool: D83: Interfaces.C.signed_char

tool: D91: <invalid>

tool: D51: Interfaces.C.short

tool: D88: Long_Long_Integer

tool: D63: Interfaces.C.unsigned_long

tool: D75: Interfaces.C.unsigned_char

tool: D97: Interfaces.C.unsigned_short

assistant: ```c
const char *get_type(int is_signed, int size) {
  if (is_signed) {
    switch (size) {
    case 1:
      return "Interfaces.C.signed_char";
    case 2:
      return "Interfaces.C.short";
    case 4:
      if (sizeof(int) == 4) {
        return "Interfaces.C.long";
      } else {
        return "Interfaces.C.int";
      }
    case 8:
      return "Long_Long_Integer";
    default:
      return "<invalid>";
    }
  } else {
    switch (size) {
    case 1:
      return "Interfaces.C.unsigned_char";
    case 2:
      return "Interfaces.C.unsigned_short";
    case 4:
      if (sizeof(int) == 4) {
        return "Interfaces.C.unsigned_long";
      } else {
        return "Interfaces.C.unsigned_int";
      }
    case 8:
      return "Long_Long_Integer";
    default:
      return "<invalid>";
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_type>:
  endbr64
  test   %edi,%edi
  je     L4
  lea    D45(%rip),%rax
  cmp    $0x4,%esi
  je     L58
  jg     L63
  lea    D13(%rip),%rax
  cmp    $0x1,%esi
  je     L58
  cmp    $0x2,%esi
  lea    D87(%rip),%rdx
  lea    D2(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  cmp    $0x8,%esi
  lea    D2(%rip),%rax
  lea    D71(%rip),%rdx
  cmove  %rdx,%rax
L58:
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  lea    D61(%rip),%rax
  cmp    $0x4,%esi
  je     L58
  jg     L63
  lea    D75(%rip),%rax
  cmp    $0x1,%esi
  je     L58
  cmp    $0x2,%esi
  lea    D38(%rip),%rdx
  lea    D2(%rip),%rax
  cmove  %rdx,%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D45
data_type: string
name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D87
data_type: string
name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D71
data_type: string
name: parse_data
arguments: label: D61
data_type: string
name: parse_data
arguments: label: D75
data_type: string
name: parse_data
arguments: label: D38
data_type: string

tool: D45: Interfaces.C.long

tool: D13: Interfaces.C.signed_char

tool: D87: Interfaces.C.short

tool: D2: <invalid>

tool: D71: Long_Long_Integer

tool: D61: Interfaces.C.unsigned_long

tool: D75: Interfaces.C.unsigned_char

tool: D38: Interfaces.C.unsigned_short

assistant: ```c
const char *get_type(int is_signed, int size) {
  if (is_signed) {
    switch (size) {
    case 1:
      return "Interfaces.C.signed_char";
    case 2:
      return "Interfaces.C.short";
    case 4:
      if (sizeof(int) == 4) {
        return "Interfaces.C.long";
      } else {
        return "Interfaces.C.int";
      }
    case 8:
      return "Long_Long_Integer";
    default:
      return "<invalid>";
    }
  } else {
    switch (size) {
    case 1:
      return "Interfaces.C.unsigned_char";
    case 2:
      return "Interfaces.C.unsigned_short";
    case 4:
      if (sizeof(int) == 4) {
        return "Interfaces.C.unsigned_long";
      } else {
        return "Interfaces.C.unsigned_int";
      }
    case 8:
      return "Long_Long_Integer";
    default:
      return "<invalid>";
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_type>:
  endbr64
  test   %edi,%edi
  je     L33
  lea    D8(%rip),%rax
  cmp    $0x4,%esi
  je     L6
  jg     L36
  lea    D41(%rip),%rax
  cmp    $0x1,%esi
  je     L6
  cmp    $0x2,%esi
  lea    D82(%rip),%rdx
  lea    D32(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  cmp    $0x8,%esi
  lea    D32(%rip),%rax
  lea    D50(%rip),%rdx
  cmove  %rdx,%rax
L6:
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  lea    D14(%rip),%rax
  cmp    $0x4,%esi
  je     L6
  jg     L36
  lea    D51(%rip),%rax
  cmp    $0x1,%esi
  je     L6
  cmp    $0x2,%esi
  lea    D1(%rip),%rdx
  lea    D32(%rip),%rax
  cmove  %rdx,%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D41
type: string
name: read_data
arguments: tag: D82
type: string
name: read_data
arguments: tag: D32
type: string
name: read_data
arguments: tag: D50
type: string
name: read_data
arguments: tag: D14
type: string
name: read_data
arguments: tag: D51
type: string
name: read_data
arguments: tag: D1
type: string

tool: D8: Interfaces.C.long

tool: D41: Interfaces.C.signed_char

tool: D82: Interfaces.C.short

tool: D32: <invalid>

tool: D50: Long_Long_Integer

tool: D14: Interfaces.C.unsigned_long

tool: D51: Interfaces.C.unsigned_char

tool: D1: Interfaces.C.unsigned_short

assistant: ```c
const char *get_type(int is_signed, int size) {
  if (is_signed) {
    switch (size) {
    case 1:
      return "Interfaces.C.signed_char";
    case 2:
      return "Interfaces.C.short";
    case 4:
      if (sizeof(int) == 4) {
        return "Interfaces.C.long";
      } else {
        return "Interfaces.C.int";
      }
    case 8:
      return "Long_Long_Integer";
    default:
      return "<invalid>";
    }
  } else {
    switch (size) {
    case 1:
      return "Interfaces.C.unsigned_char";
    case 2:
      return "Interfaces.C.unsigned_short";
    case 4:
      if (sizeof(int) == 4) {
        return "Interfaces.C.unsigned_long";
      } else {
        return "Interfaces.C.unsigned_int";
      }
    case 8:
      return "Long_Long_Integer";
    default:
      return "<invalid>";
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L14
L29:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%edi
  call   <path3@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
data_type: string
name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D23: %d

tool: D13: %d %d

tool: D1: %I64u


assistant: ```c
int main() {
  int n = 0;
  int i, j;
  scanf("%d", &n);
  while (n-- > 0) {
    scanf("%d %d", &i, &j);
    printf("%I64u\n", path3(j - i));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L20
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D4(%rip),%rbp
  lea    D11(%rip),%rbx
L22:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  sub    0x10(%rsp),%edi
  call   <path3@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L22
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D4
datatype: string
name: disassemble_data
arguments: tag: D11
datatype: string

tool: D16: %d

tool: D4: %d %d

tool: D11: %I64u


assistant: ```c
int main() {
  int n = 0;
  int i, j;
  scanf("%d", &n);
  while (n-- > 0) {
    scanf("%d %d", &i, &j);
    printf("%I64u\n", path3(j - i));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L16
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D25(%rip),%rbp
  lea    D5(%rip),%rbx
  xchg   %ax,%ax
L4:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  sub    0x10(%rsp),%edi
  call   <path3@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L4
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
type: string
name: disassemble_data
arguments: data_tag: D25
type: string
name: disassemble_data
arguments: data_tag: D5
type: string

tool: D22: %d

tool: D25: %d %d

tool: D5: %I64u


assistant: ```c
int main() {
  int n = 0;
  int i, j;
  scanf("%d", &n);
  while (n-- > 0) {
    scanf("%d %d", &i, &j);
    printf("%I64u\n", path3(j - i));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L3
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D5(%rip),%rbp
  lea    D12(%rip),%rbx
  xchg   %ax,%ax
L16:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  sub    0x10(%rsp),%edi
  call   <path3@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L16
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string

tool: D22: %d

tool: D5: %d %d

tool: D12: %I64u


assistant: ```c
int main() {
  int n = 0;
  int i, j;
  scanf("%d", &n);
  while (n-- > 0) {
    scanf("%d %d", &i, &j);
    printf("%I64u\n", path3(j - i));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mystrncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L19
L23:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L19:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jg     L23
L20:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mystrnlen@plt>
  sub    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L47
L13:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L47:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jg     L13
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void mystrncpy(char *dest, char *source, int n) {
  while (*source && n-- > 0)
    *dest++ = *source++;
  int extra = mystrnlen(dest) - n;
  while (extra-- > 0) {
    *dest++;
  }
  *dest = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mystrncpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rsi),%eax
  test   %al,%al
  je     L23
  lea    -0x1(%rdx),%ebp
  test   %edx,%edx
  jle    L68
L26:
  add    $0x1,%rsi
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movzbl (%rsi),%eax
  test   %al,%al
  je     L68
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  jne    L26
L68:
  mov    %rbx,%rdi
  call   <mystrnlen@plt>
  sub    %ebp,%eax
  lea    -0x1(%rax),%edx
  test   %eax,%eax
  jle    L48
L6:
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  jne    L6
  mov    %eax,%eax
  add    %rax,%rbx
L48:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  mov    %edx,%ebp
  jmp    L68
```

assistant: ```c
void mystrncpy(char *dest, char *source, int n) {
  while (*source && n-- > 0)
    *dest++ = *source++;
  int extra = mystrnlen(dest) - n;
  while (extra-- > 0) {
    *dest++;
  }
  *dest = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mystrncpy>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  je     L38
  lea    -0x1(%rdx),%ebp
  test   %edx,%edx
  jg     L36
  jmp    L6
  nopl   (%rax)
L3:
  sub    $0x1,%ebp
  jb     L6
L36:
  add    $0x1,%rsi
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L3
L6:
  mov    %rbx,%rdi
  call   <mystrnlen@plt>
  sub    %ebp,%eax
  movslq %eax,%rdx
  add    %rbx,%rdx
  test   %eax,%eax
  cmovg  %rdx,%rbx
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    %edx,%ebp
  jmp    L6
```

assistant: ```c
void mystrncpy(char *dest, char *source, int n) {
  while (*source && n-- > 0)
    *dest++ = *source++;
  int extra = mystrnlen(dest) - n;
  while (extra-- > 0) {
    *dest++;
  }
  *dest = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<mystrncpy>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  je     L22
  lea    -0x1(%rdx),%ebp
  test   %edx,%edx
  jg     L3
  jmp    L17
  nopl   (%rax)
L45:
  sub    $0x1,%ebp
  jb     L17
L3:
  add    $0x1,%rsi
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L45
L17:
  mov    %rbx,%rdi
  call   <mystrnlen@plt>
  sub    %ebp,%eax
  movslq %eax,%rdx
  add    %rbx,%rdx
  test   %eax,%eax
  cmovg  %rdx,%rbx
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    %edx,%ebp
  jmp    L17
```

assistant: ```c
void mystrncpy(char *dest, char *source, int n) {
  while (*source && n-- > 0)
    *dest++ = *source++;
  int extra = mystrnlen(dest) - n;
  while (extra-- > 0) {
    *dest++;
  }
  *dest = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bubbles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L34:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L45
L3:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L19
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L19:
  subl   $0x1,-0x8(%rbp)
L45:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L3
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubbles(int n[], int num) {
  int temp;
  int i, j;
  for (i = 0; i < num - 2; i++) {
    for (j = num - 1; i < j; j--) {
      if (n[j - 1] > n[j]) {
        temp = n[j];
        n[j] = n[j - 1];
        n[j - 1] = temp;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bubbles>:
  endbr64
  cmp    $0x2,%esi
  jle    L20
  lea    -0x2(%rsi),%r10d
  lea    -0x1(%rsi),%eax
  cltq
  lea    (%rdi,%rax,4),%r11
  movslq %esi,%rax
  mov    $0x0,%r8d
  lea    -0x1(%rsi),%r9d
  lea    -0x8(%rdi,%rax,4),%rdi
  jmp    L2
L42:
  sub    $0x4,%rax
  cmp    %rsi,%rax
  je     L19
L14:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L42
  mov    %ecx,(%rax)
  mov    %edx,-0x4(%rax)
  jmp    L42
L19:
  add    $0x1,%r8d
  cmp    %r10d,%r8d
  je     L20
L2:
  cmp    %r8d,%r9d
  jle    L19
  mov    %r10d,%eax
  sub    %r8d,%eax
  shl    $0x2,%rax
  mov    %rdi,%rsi
  sub    %rax,%rsi
  mov    %r11,%rax
  jmp    L14
L20:
  ret
```

assistant: ```c
void bubbles(int n[], int num) {
  int temp;
  int i, j;
  for (i = 0; i < num - 2; i++) {
    for (j = num - 1; i < j; j--) {
      if (n[j - 1] > n[j]) {
        temp = n[j];
        n[j] = n[j - 1];
        n[j - 1] = temp;
      }
    }
  }
}
```