ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L17:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  imul   %rdx,%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  cmpl   $0xff,-0xc(%rbp)
  jle    L17
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long foo(long long *__restrict a, int *__restrict b, int *__restrict c) {
  int i;
  long long sum = 0;
  for (i = 0; i < 256; i++)
    sum += (long long)b[i] * c[i];
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  mov    $0x0,%eax
  mov    $0x0,%edi
L2:
  movslq (%rsi,%rax,1),%rcx
  movslq (%rdx,%rax,1),%r8
  imul   %r8,%rcx
  add    %rcx,%rdi
  add    $0x4,%rax
  cmp    $0x400,%rax
  jne    L2
  mov    %rdi,%rax
  ret
```

assistant: ```c
long long foo(long long *__restrict a, int *__restrict b, int *__restrict c) {
  int i;
  long long sum = 0;
  for (i = 0; i < 256; i++)
    sum += (long long)b[i] * c[i];
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L3:
  movslq (%rsi,%rax,1),%rcx
  movslq (%rdx,%rax,1),%rdi
  add    $0x4,%rax
  imul   %rdi,%rcx
  add    %rcx,%r8
  cmp    $0x400,%rax
  jne    L3
  mov    %r8,%rax
  ret
```

assistant: ```c
long long foo(long long *__restrict a, int *__restrict b, int *__restrict c) {
  int i;
  long long sum = 0;
  for (i = 0; i < 256; i++)
    sum += (long long)b[i] * c[i];
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm4,%xmm4
  pxor   %xmm5,%xmm5
  xchg   %ax,%ax
L4:
  movdqu (%rsi,%rax,1),%xmm1
  movdqu (%rdx,%rax,1),%xmm0
  movdqa %xmm5,%xmm3
  movdqa %xmm5,%xmm6
  add    $0x10,%rax
  movdqa %xmm0,%xmm2
  movdqa %xmm1,%xmm7
  punpckldq %xmm0,%xmm2
  punpckldq %xmm1,%xmm7
  punpckhdq %xmm0,%xmm0
  pcmpgtd %xmm2,%xmm3
  pcmpgtd %xmm7,%xmm6
  punpckhdq %xmm1,%xmm1
  pmuludq %xmm2,%xmm6
  pmuludq %xmm7,%xmm3
  pmuludq %xmm7,%xmm2
  paddq  %xmm6,%xmm3
  psllq  $0x20,%xmm3
  paddq  %xmm3,%xmm2
  movdqa %xmm5,%xmm3
  paddq  %xmm2,%xmm4
  pcmpgtd %xmm1,%xmm3
  movdqa %xmm5,%xmm2
  pcmpgtd %xmm0,%xmm2
  pmuludq %xmm0,%xmm3
  pmuludq %xmm1,%xmm0
  pmuludq %xmm1,%xmm2
  paddq  %xmm3,%xmm2
  psllq  $0x20,%xmm2
  paddq  %xmm2,%xmm0
  paddq  %xmm0,%xmm4
  cmp    $0x400,%rax
  jne    L4
  movdqa %xmm4,%xmm0
  psrldq $0x8,%xmm0
  paddq  %xmm0,%xmm4
  movq   %xmm4,%rax
  ret
```

assistant: ```c
long long foo(long long *__restrict a, int *__restrict b, int *__restrict c) {
  int i;
  long long sum = 0;
  for (i = 0; i < 256; i++)
    sum += (long long)b[i] * c[i];
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <glPushMatrix@plt>
  movsd  -0x8(%rbp),%xmm1
  movsd  D21(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D21(%rip),%xmm1
  mov    D21(%rip),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <glTranslated@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  movq   %rax,%xmm0
  mov    $0x1,%edi
  call   <glScaled@plt>
  mov    D22(%rip),%rax
  movq   %rax,%xmm0
  call   <glutSolidCube@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
data_type: f64
name: retrieve_data
arguments: data_tag: D22
data_type: f64

tool: D21: 0.5

tool: D22: 1

assistant: ```c
void wall(double thick) {
  glPushMatrix();
  glTranslated(0.5, .5 * thick, .5);
  glScaled(1, thick, 1);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wall>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%eax
  call   <glPushMatrix@plt>
  movsd  D18(%rip),%xmm0
  movapd %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  call   <glTranslated@plt>
  mov    $0x1,%esi
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%edi
  call   <glScaled@plt>
  movsd  D11(%rip),%xmm0
  call   <glutSolidCube@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_guessed: f64
name: parse_data
arguments: label: D11
type_guessed: f64

tool: D18: 0.5

tool: D11: 1

assistant: ```c
void wall(double thick) {
  glPushMatrix();
  glTranslated(0.5, .5 * thick, .5);
  glScaled(1, thick, 1);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wall>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <glPushMatrix@plt>
  movsd  D16(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm0,%xmm2
  call   <glTranslated@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <glScaled@plt>
  movsd  D3(%rip),%xmm0
  call   <glutSolidCube@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  jmp    10c0 <glPopMatrix@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type: f64
name: parse_data
arguments: tag: D3
type: f64

tool: D16: 0.5

tool: D3: 1

assistant: ```c
void wall(double thick) {
  glPushMatrix();
  glTranslated(0.5, .5 * thick, .5);
  glScaled(1, thick, 1);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wall>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <glPushMatrix@plt>
  movsd  D7(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm0,%xmm2
  call   <glTranslated@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <glScaled@plt>
  movsd  D5(%rip),%xmm0
  call   <glutSolidCube@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  jmp    10c0 <glPopMatrix@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: f64
name: unpack_data
arguments: tag: D5
type_infered: f64

tool: D7: 0.5

tool: D5: 1

assistant: ```c
void wall(double thick) {
  glPushMatrix();
  glTranslated(0.5, .5 * thick, .5);
  glScaled(1, thick, 1);
  glutSolidCube(1.0);
  glPopMatrix();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bar@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D17
data_type: string

tool: D12: foo(%d) = %d


tool: D17: bar(%d) = %d


assistant: ```c
int main() {
  int x = 10;
  printf("foo(%d) = %d\n", x, foo(x));
  printf("bar(%d) = %d\n", x, bar(x));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <foo@plt>
  mov    %eax,%edx
  mov    $0xa,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <bar@plt>
  mov    %eax,%edx
  mov    $0xa,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: D2: foo(%d) = %d


tool: D0: bar(%d) = %d


assistant: ```c
int main() {
  int x = 10;
  printf("foo(%d) = %d\n", x, foo(x));
  printf("bar(%d) = %d\n", x, bar(x));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <foo@plt>
  mov    $0xa,%esi
  lea    D13(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <bar@plt>
  mov    $0xa,%esi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
datatype: string
name: retrieve_data
arguments: label: D0
datatype: string

tool: D13: foo(%d) = %d


tool: D0: bar(%d) = %d


assistant: ```c
int main() {
  int x = 10;
  printf("foo(%d) = %d\n", x, foo(x));
  printf("bar(%d) = %d\n", x, bar(x));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <foo@plt>
  mov    $0xa,%esi
  lea    D16(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <bar@plt>
  mov    $0xa,%esi
  lea    D14(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D16: foo(%d) = %d


tool: D14: bar(%d) = %d


assistant: ```c
int main() {
  int x = 10;
  printf("foo(%d) = %d\n", x, foo(x));
  printf("bar(%d) = %d\n", x, bar(x));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa9fe0000,%edi
  call   <getnetbyaddr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa9fe0000,%edi
  call   <getnetbyaddr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  struct netent *entry;
  entry = getnetbyaddr(2851995648, AF_INET);
  assert(entry == NULL);
  entry = getnetbyaddr(2851995648, AF_INET);
  assert(entry == NULL);
  return errno;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D3(%rip),%rbx
  mov    (%rbx),%esi
  mov    $0xa9fe0000,%edi
  call   <getnetbyaddr@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%esi
  mov    $0xa9fe0000,%edi
  call   <getnetbyaddr@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  struct netent *entry;
  entry = getnetbyaddr(2851995648, AF_INET);
  assert(entry == NULL);
  entry = getnetbyaddr(2851995648, AF_INET);
  assert(entry == NULL);
  return errno;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D19(%rip),%rbx
  mov    $0xa9fe0000,%edi
  mov    (%rbx),%esi
  call   <getnetbyaddr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    (%rbx),%esi
  mov    $0xa9fe0000,%edi
  call   <getnetbyaddr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    D6(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  struct netent *entry;
  entry = getnetbyaddr(2851995648, AF_INET);
  assert(entry == NULL);
  entry = getnetbyaddr(2851995648, AF_INET);
  assert(entry == NULL);
  return errno;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rbx
  mov    $0xa9fe0000,%edi
  mov    (%rbx),%esi
  call   <getnetbyaddr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    (%rbx),%esi
  mov    $0xa9fe0000,%edi
  call   <getnetbyaddr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    D15(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  struct netent *entry;
  entry = getnetbyaddr(2851995648, AF_INET);
  assert(entry == NULL);
  entry = getnetbyaddr(2851995648, AF_INET);
  assert(entry == NULL);
  return errno;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<list_replace_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <list_replace@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <INIT_LIST_HEAD@plt>
  nop
  leave
  ret
```

assistant: ```c
void list_replace_init(struct list_head *old, struct list_head *new_node) {
  list_replace(old, new_node);
  INIT_LIST_HEAD(old);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_replace_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <list_replace@plt>
  mov    %rbx,%rdi
  call   <INIT_LIST_HEAD@plt>
  pop    %rbx
  ret
```

assistant: ```c
void list_replace_init(struct list_head *old, struct list_head *new_node) {
  list_replace(old, new_node);
  INIT_LIST_HEAD(old);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<list_replace_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <list_replace@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <INIT_LIST_HEAD@plt>
```

assistant: ```c
void list_replace_init(struct list_head *old, struct list_head *new_node) {
  list_replace(old, new_node);
  INIT_LIST_HEAD(old);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<list_replace_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <list_replace@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <INIT_LIST_HEAD@plt>
```

assistant: ```c
void list_replace_init(struct list_head *old, struct list_head *new_node) {
  list_replace(old, new_node);
  INIT_LIST_HEAD(old);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<two_cycle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void two_cycle(int arr[], int ind0, int ind1) {
  int temp;
  temp = arr[ind0];
  arr[ind0] = arr[ind1];
  arr[ind1] = temp;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<two_cycle>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void two_cycle(int arr[], int ind0, int ind1) {
  int temp;
  temp = arr[ind0];
  arr[ind0] = arr[ind1];
  arr[ind1] = temp;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<two_cycle>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void two_cycle(int arr[], int ind0, int ind1) {
  int temp;
  temp = arr[ind0];
  arr[ind0] = arr[ind1];
  arr[ind1] = temp;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<two_cycle>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void two_cycle(int arr[], int ind0, int ind1) {
  int temp;
  temp = arr[ind0];
  arr[ind0] = arr[ind1];
  arr[ind1] = temp;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0xd,%eax
  ja     L36
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D22(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D22(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L36:
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L45:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D77
type: string
name: unpack_data
arguments: data_tag: D97
type: string
name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D93
type: string
name: unpack_data
arguments: data_tag: D49
type: string
name: unpack_data
arguments: data_tag: D32
type: string
name: unpack_data
arguments: data_tag: D79
type: string

tool: D77: %d

tool: D97: Digite um numero de um canal de tv:


tool: D11: SBT

tool: D0: BAND

tool: D93: REDETV!

tool: D49: RECORD

tool: D32: GLOBO

tool: D79: Canal Invalido

assistant: ```c
int main(int argc, char const *argv[]) {
  int a;
  scanf("%d", &a);
  printf("Digite um numero de um canal de tv:\n");
  switch (a) {
  case 2:
    printf("SBT");
    break;
  case 4:
    printf("BAND");
    break;
  case 6:
    printf("REDETV!");
    break;
  case 9:
    printf("RECORD");
    break;
  case 13:
    printf("GLOBO");
    break;
  default:
    printf("Canal Invalido");
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D62(%rip),%rdi
  call   <scanf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  cmpl   $0xd,0x4(%rsp)
  ja     L31
  mov    0x4(%rsp),%eax
  lea    D25(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D29(%rip),%rdi
  call   <printf@plt>
L59:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L59
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L59
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L59
  lea    D84(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L31:
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D62
type: string
name: parse_data
arguments: data_label: D64
type: string
name: parse_data
arguments: data_label: D29
type: string
name: parse_data
arguments: data_label: D36
type: string
name: parse_data
arguments: data_label: D21
type: string
name: parse_data
arguments: data_label: D32
type: string
name: parse_data
arguments: data_label: D84
type: string
name: parse_data
arguments: data_label: D35
type: string

tool: D62: %d

tool: D64: Digite um numero de um canal de tv:


tool: D29: SBT

tool: D36: BAND

tool: D21: REDETV!

tool: D32: RECORD

tool: D84: GLOBO

tool: D35: Canal Invalido

assistant: ```c
int main(int argc, char const *argv[]) {
  int a;
  scanf("%d", &a);
  printf("Digite um numero de um canal de tv:\n");
  switch (a) {
  case 2:
    printf("SBT");
    break;
  case 4:
    printf("BAND");
    break;
  case 6:
    printf("REDETV!");
    break;
  case 9:
    printf("RECORD");
    break;
  case 13:
    printf("GLOBO");
    break;
  default:
    printf("Canal Invalido");
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D84(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  cmpl   $0xd,0x4(%rsp)
  ja     L38
  mov    0x4(%rsp),%eax
  lea    D13(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L38:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  nopl   (%rax)
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D55(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D66(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D84
type: string
name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D24
type: string
name: retrieve_data
arguments: tag: D62
type: string
name: retrieve_data
arguments: tag: D31
type: string
name: retrieve_data
arguments: tag: D55
type: string
name: retrieve_data
arguments: tag: D66
type: string
name: retrieve_data
arguments: tag: D41
type: string

tool: D84: %d

tool: D18: Digite um numero de um canal de tv:


tool: D24: Canal Invalido

tool: D62: SBT

tool: D31: BAND

tool: D55: REDETV!

tool: D66: RECORD

tool: D41: GLOBO

assistant: ```c
int main(int argc, char const *argv[]) {
  int a;
  scanf("%d", &a);
  printf("Digite um numero de um canal de tv:\n");
  switch (a) {
  case 2:
    printf("SBT");
    break;
  case 4:
    printf("BAND");
    break;
  case 6:
    printf("REDETV!");
    break;
  case 9:
    printf("RECORD");
    break;
  case 13:
    printf("GLOBO");
    break;
  default:
    printf("Canal Invalido");
    break;
  }
  return 0;
}
```