ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<collatz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L48
L40:
  addl   $0x1,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L33
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  jmp    L38
L33:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L38:
  cmpl   $0x0,-0x14(%rbp)
  jns    L48
  mov    $0xffffffff,%eax
  jmp    L27
L48:
  cmpl   $0x1,-0x14(%rbp)
  jg     L40
  mov    -0x4(%rbp),%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int collatz(int wert) {
  int anzahl = 0;
  while (wert > 1) {
    ++anzahl;
    if (wert % 2 == 0)
      wert /= 2;
    else
      wert = (wert * 3) + 1;
    if (wert < 0) {
      return -1;
      break;
    }
  }
  return anzahl;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<collatz>:
  endbr64
  mov    $0x0,%eax
  jmp    L19
L0:
  lea    0x1(%rdi,%rdi,2),%edi
L19:
  cmp    $0x1,%edi
  jle    L14
  add    $0x1,%eax
  test   $0x1,%dil
  jne    L0
  mov    %edi,%edx
  shr    $0x1f,%edx
  add    %edx,%edi
  sar    %edi
  jmp    L19
L14:
  ret
```

assistant: ```c
int collatz(int wert) {
  int anzahl = 0;
  while (wert > 1) {
    ++anzahl;
    if (wert % 2 == 0)
      wert /= 2;
    else
      wert = (wert * 3) + 1;
    if (wert < 0) {
      return -1;
      break;
    }
  }
  return anzahl;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<collatz>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L28
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x1,%eax
  test   $0x1,%dil
  jne    L31
  sar    %edi
  cmp    $0x1,%edi
  jne    L26
  ret
  nopl   0x0(%rax)
L31:
  lea    0x1(%rdi,%rdi,2),%edi
  jmp    L26
  xchg   %ax,%ax
L28:
  ret
```

assistant: ```c
int collatz(int wert) {
  int anzahl = 0;
  while (wert > 1) {
    ++anzahl;
    if (wert % 2 == 0)
      wert /= 2;
    else
      wert = (wert * 3) + 1;
    if (wert < 0) {
      return -1;
      break;
    }
  }
  return anzahl;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<collatz>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L15
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%eax
  test   $0x1,%dil
  jne    L33
  sar    %edi
  cmp    $0x1,%edi
  jne    L13
  ret
  nopl   0x0(%rax)
L33:
  lea    0x1(%rdi,%rdi,2),%edi
  jmp    L13
  xchg   %ax,%ax
L15:
  ret
```

assistant: ```c
int collatz(int wert) {
  int anzahl = 0;
  while (wert > 1) {
    ++anzahl;
    if (wert % 2 == 0)
      wert /= 2;
    else
      wert = (wert * 3) + 1;
    if (wert < 0) {
      return -1;
      break;
    }
  }
  return anzahl;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_strdelim>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    (%rsp),%rdi
  call   <strncpy@plt>
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    (%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strdelim@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strdelim@plt>
  mov    %rax,%r12
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    %r12,%rdx
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rax,%r15
  jne    L57
  mov    %rax,%r14
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %rax,%r15
  je     L32
L57:
  mov    %rbx,%rdi
  call   <free@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L53
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L57
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L57
  mov    %rbx,%rdi
  call   <free@plt>
  lea    D30(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L2
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D10
type: string
name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D30
type: string

tool: D22:    strdelim( '%s', '%s', '%s')

tool: D10:  = '%s', '%s' 

tool: D0: failed

tool: D30: passed

assistant: ```c
int test_strdelim(char *line, char *var, char *val) {
  char *l;
  char *keyword;
  char *value;
  l = (char *)malloc(strlen(line) + 1);
  memset(l, 0, strlen(line) + 1);
  strncpy(l, line, strlen(line));
  printf("   strdelim( '%s', '%s', '%s')", l, var, val);
  keyword = strdelim(&l);
  value = strdelim(&l);
  free(l);
  printf(" = '%s', '%s' ", keyword, value);
  if (strlen(keyword) == strlen(var) && strlen(value) == strlen(val)) {
    if (strncmp(keyword, var, strlen(var)) == 0 && strncmp(value, val, strlen(val)) == 0) {
      free(keyword);
      printf("passed\n");
      return (0);
    }
  }
  free(keyword);
  printf("failed\n");
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_strdelim>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    %rax,(%rsp)
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %rsp,%r13
  lea    0x1(%rax),%rdx
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%rsp),%rdi
  mov    %rbp,%rsi
  mov    %rax,%rdx
  call   <strncpy@plt>
  mov    (%rsp),%rsi
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <strdelim@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strdelim@plt>
  mov    (%rsp),%rdi
  mov    %rax,%r13
  call   <free@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  cmp    %rax,%r15
  jne    L46
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  je     L17
L46:
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L46
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%rdx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L46
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L2
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string
name: unpack_data
arguments: data_label: D21
data_type: string
name: unpack_data
arguments: data_label: D31
data_type: string
name: unpack_data
arguments: data_label: D10
data_type: string

tool: D0:    strdelim( '%s', '%s', '%s')

tool: D21:  = '%s', '%s' 

tool: D31: failed

tool: D10: passed

assistant: ```c
int test_strdelim(char *line, char *var, char *val) {
  char *l;
  char *keyword;
  char *value;
  l = (char *)malloc(strlen(line) + 1);
  memset(l, 0, strlen(line) + 1);
  strncpy(l, line, strlen(line));
  printf("   strdelim( '%s', '%s', '%s')", l, var, val);
  keyword = strdelim(&l);
  value = strdelim(&l);
  free(l);
  printf(" = '%s', '%s' ", keyword, value);
  if (strlen(keyword) == strlen(var) && strlen(value) == strlen(val)) {
    if (strncmp(keyword, var, strlen(var)) == 0 && strncmp(value, val, strlen(val)) == 0) {
      free(keyword);
      printf("passed\n");
      return (0);
    }
  }
  free(keyword);
  printf("failed\n");
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_strdelim>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    %rax,(%rsp)
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %rsp,%r13
  lea    0x1(%rax),%rdx
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%rsp),%rdi
  mov    %rbp,%rsi
  mov    %rax,%rdx
  call   <strncpy@plt>
  mov    (%rsp),%rsi
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <strdelim@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strdelim@plt>
  mov    (%rsp),%rdi
  mov    %rax,%r13
  call   <free@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  cmp    %rax,%r15
  jne    L1
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  je     L6
L1:
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L1
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%rdx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L1
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L36
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D34
type_infered: string
name: unpack_data
arguments: data_tag: D3
type_infered: string
name: unpack_data
arguments: data_tag: D10
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D34:    strdelim( '%s', '%s', '%s')

tool: D3:  = '%s', '%s' 

tool: D10: failed

tool: D8: passed

assistant: ```c
int test_strdelim(char *line, char *var, char *val) {
  char *l;
  char *keyword;
  char *value;
  l = (char *)malloc(strlen(line) + 1);
  memset(l, 0, strlen(line) + 1);
  strncpy(l, line, strlen(line));
  printf("   strdelim( '%s', '%s', '%s')", l, var, val);
  keyword = strdelim(&l);
  value = strdelim(&l);
  free(l);
  printf(" = '%s', '%s' ", keyword, value);
  if (strlen(keyword) == strlen(var) && strlen(value) == strlen(val)) {
    if (strncmp(keyword, var, strlen(var)) == 0 && strncmp(value, val, strlen(val)) == 0) {
      free(keyword);
      printf("passed\n");
      return (0);
    }
  }
  free(keyword);
  printf("failed\n");
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x58,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sscanf(char *x, char *y, ...) {
  int a;
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<sscanf>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int sscanf(char *x, char *y, ...) {
  int a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sscanf>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int sscanf(char *x, char *y, ...) {
  int a;
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sscanf>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int sscanf(char *x, char *y, ...) {
  int a;
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<log_wrapper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   *%rcx
  nop
  leave
  ret
```

assistant: ```c
void log_wrapper(int level, const char *msg, void *usrptr) {
  void (*xlog)(int level, char *msg) = usrptr;
  xlog(level, (char *)msg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<log_wrapper>:
  endbr64
  sub    $0x8,%rsp
  call   *%rdx
  add    $0x8,%rsp
  ret
```

assistant: ```c
void log_wrapper(int level, const char *msg, void *usrptr) {
  void (*xlog)(int level, char *msg) = usrptr;
  xlog(level, (char *)msg);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<log_wrapper>:
  endbr64
  jmp    *%rdx
```

assistant: ```c
void log_wrapper(int level, const char *msg, void *usrptr) {
  void (*xlog)(int level, char *msg) = usrptr;
  xlog(level, (char *)msg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log_wrapper>:
  endbr64
  jmp    *%rdx
```

assistant: ```c
void log_wrapper(int level, const char *msg, void *usrptr) {
  void (*xlog)(int level, char *msg) = usrptr;
  xlog(level, (char *)msg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<malloc_and_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L110
L14:
  addl   $0x1,-0x10(%rbp)
L91:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L89
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x28(%rbp)
  je     L14
L89:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L112
L19:
  addl   $0x1,-0x10(%rbp)
L112:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L113
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x28(%rbp)
  jne    L19
L113:
  mov    -0x10(%rbp),%eax
  sub    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    (%rdx),%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L107
  mov    $0x0,%eax
  jmp    L118
L107:
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L48:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    (%rsi,%rax,1),%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L48
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L110:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L96
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L91
L96:
  mov    -0x24(%rbp),%eax
L118:
  leave
  ret
```

assistant: ```c
int malloc_and_copy(char *s, char ***tab, int words, char c) {
  int i;
  int j;
  int k;
  int flag;
  i = 0;
  j = 0;
  while (s[i] && j < words) {
    while (s[i] && s[i] == c)
      i++;
    flag = i;
    while (s[i] && s[i] != c)
      i++;
    (*tab)[j] = (char *)malloc(sizeof(char) * (i - flag + 1));
    if ((*tab)[j] == 0)
      return (0);
    k = 0;
    while (flag < i)
      (*tab)[j][k++] = s[flag++];
    (*tab)[j][k] = '\0';
    j++;
  }
  return (words);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<malloc_and_copy>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmpb   $0x0,(%rdi)
  je     L124
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %ecx,%ebp
  mov    $0x0,%r15d
  mov    $0x0,%r12d
  test   %edx,%edx
  jg     L32
  jmp    L124
L176:
  mov    %r12d,%edi
  sub    0x8(%rsp),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  lea    0x0(,%r15,8),%rsi
  mov    (%r14),%rdx
  mov    %rax,(%rdx,%r15,8)
  mov    (%r14),%rax
  cmpq   $0x0,(%rax,%r15,8)
  je     L113
  mov    0x8(%rsp),%edi
  cmp    %edi,%r12d
  jle    L75
  mov    %edi,%r8d
  mov    (%rsp),%eax
  sub    %edi,%eax
  lea    -0x1(%rax),%edi
  mov    $0x0,%eax
L130:
  movzbl 0x0(%r13,%rax,1),%ecx
  mov    (%r14),%rdx
  mov    (%rdx,%rsi,1),%rdx
  mov    %cl,(%rdx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdi,%rdx
  jne    L130
  mov    (%rsp),%eax
  sub    %r8d,%eax
L208:
  mov    (%r14),%rdx
  cltq
  mov    (%rdx,%rsi,1),%rdx
  movb   $0x0,(%rdx,%rax,1)
  movslq %r12d,%rax
  cmpb   $0x0,(%rbx,%rax,1)
  setne  %dl
  lea    0x1(%r15),%eax
  cmp    %eax,0xc(%rsp)
  setg   %al
  add    $0x1,%r15
  test   %al,%dl
  je     L124
L32:
  movslq %r12d,%rax
  movzbl (%rbx,%rax,1),%eax
  cmp    %al,%bpl
  jne    L157
  test   %al,%al
  setne  %dl
  lea    0x1(%r12),%eax
  cltq
  test   %dl,%dl
  je     L157
L193:
  mov    %eax,0x8(%rsp)
  movzbl (%rbx,%rax,1),%edx
  add    $0x1,%rax
  cmp    %bpl,%dl
  jne    L117
  test   %dl,%dl
  jne    L193
L117:
  mov    0x8(%rsp),%esi
  movslq %esi,%r13
  add    %rbx,%r13
  movzbl 0x0(%r13),%eax
  cmp    %al,%bpl
  je     L206
  test   %al,%al
  je     L206
  lea    0x1(%rsi),%eax
  cltq
L100:
  mov    %eax,%r12d
  movzbl (%rbx,%rax,1),%edx
  mov    %rax,(%rsp)
  add    $0x1,%rax
  cmp    %bpl,%dl
  je     L176
  test   %dl,%dl
  jne    L100
  jmp    L176
L75:
  mov    $0x0,%eax
  jmp    L208
L157:
  mov    %r12d,0x8(%rsp)
  jmp    L117
L113:
  movl   $0x0,0xc(%rsp)
L124:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L104:
  movl   $0x0,0xc(%rsp)
  jmp    L124
L206:
  mov    $0x1,%edi
  call   <malloc@plt>
  lea    0x0(,%r15,8),%rsi
  mov    (%r14),%rdx
  mov    %rax,(%rdx,%r15,8)
  mov    (%r14),%rax
  cmpq   $0x0,(%rax,%r15,8)
  je     L104
  mov    0x8(%rsp),%r12d
  mov    $0x0,%eax
  jmp    L208
```

assistant: ```c
int malloc_and_copy(char *s, char ***tab, int words, char c) {
  int i;
  int j;
  int k;
  int flag;
  i = 0;
  j = 0;
  while (s[i] && j < words) {
    while (s[i] && s[i] == c)
      i++;
    flag = i;
    while (s[i] && s[i] != c)
      i++;
    (*tab)[j] = (char *)malloc(sizeof(char) * (i - flag + 1));
    if ((*tab)[j] == 0)
      return (0);
    k = 0;
    while (flag < i)
      (*tab)[j][k++] = s[flag++];
    (*tab)[j][k] = '\0';
    j++;
  }
  return (words);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<LittleEndianWriteF64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <LittleEndianWriteU64@plt>
  nop
  leave
  ret
```

assistant: ```c
void LittleEndianWriteF64(double value, uint8_t *bytes) {
  union {
    double f64;
    uint64_t u64;
  } u;
  u.f64 = value;
  LittleEndianWriteU64(u.u64, bytes);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LittleEndianWriteF64>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  movq   %xmm0,%rdi
  call   <LittleEndianWriteU64@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void LittleEndianWriteF64(double value, uint8_t *bytes) {
  union {
    double f64;
    uint64_t u64;
  } u;
  u.f64 = value;
  LittleEndianWriteU64(u.u64, bytes);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<LittleEndianWriteF64>:
  endbr64
  mov    %rdi,%rsi
  movq   %xmm0,%rdi
  jmp    1050 <LittleEndianWriteU64@plt>
```

assistant: ```c
void LittleEndianWriteF64(double value, uint8_t *bytes) {
  union {
    double f64;
    uint64_t u64;
  } u;
  u.f64 = value;
  LittleEndianWriteU64(u.u64, bytes);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LittleEndianWriteF64>:
  endbr64
  mov    %rdi,%rsi
  movq   %xmm0,%rdi
  jmp    1050 <LittleEndianWriteU64@plt>
```

assistant: ```c
void LittleEndianWriteF64(double value, uint8_t *bytes) {
  union {
    double f64;
    uint64_t u64;
  } u;
  u.f64 = value;
  LittleEndianWriteU64(u.u64, bytes);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Kartik>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x1f,-0x18(%rbp)
  jg     L57
  cmpq   $0xc,-0x20(%rbp)
  jg     L57
  cmpq   $0x3e8,-0x28(%rbp)
  jle    L57
  cmpq   $0xf,-0x18(%rbp)
  jg     L54
  mov    -0x28(%rbp),%rax
  sub    $0x251,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xf,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L54:
  mov    -0x28(%rbp),%rax
  sub    $0x251,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0xf,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L57:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D0
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string

tool: D20: %ld-Ashshin-%ld


tool: D0: %ld-Kartik-%ld


tool: D13: Invalid Input.
Please Check Your Input..........

assistant: ```c
int Kartik(long int day, long int month, long int year) {
  long int date, bangla;
  if (day <= 31 && month < 13 && year > 1000) {
    if (day < 16) {
      bangla = year - 593;
      date = day + 15;
      printf("%ld-Ashshin-%ld\n", date, bangla);
    } else {
      bangla = year - 593;
      date = day - 15;
      printf("%ld-Kartik-%ld\n", date, bangla);
    }
  } else
    printf("Invalid Input.\nPlease Check Your Input..........\n");
  return 0;
}
```