ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D56(%rip),%rdi
  lea    D26(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L60
  nopl   (%rax)
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L0
L60:
  lea    D32(%rip),%rdi
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  call   <puts@plt>
  mov    %r12,%rdi
  lea    0xc(%rsp),%rsi
  lea    D42(%rip),%r12
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jg     L30
  jmp    L22
  nopl   0x0(%rax)
L16:
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jle    L22
L30:
  mov    0xc(%rsp),%esi
  add    $0x1,%ebx
  cmp    %esi,0x0(%rbp)
  jne    L16
  mov    %ebx,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L30
  nopl   0x0(%rax,%rax,1)
L22:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D56
type: string
name: unpack_data
arguments: label: D26
type: string
name: unpack_data
arguments: label: D5
type: string
name: unpack_data
arguments: label: D32
type: string
name: unpack_data
arguments: label: D42
type: string
name: unpack_data
arguments: label: D22
type: string

tool: D56: Enter the size of the array

tool: D26: %d

tool: D5: Enter the elements in the array

tool: D32: Enter the element to be searched

tool: D42: The key %d is found at index %d 


tool: D22: The key is not found in the array

assistant: ```c
int main(int argc, char const *argv[]) {
  int i, j, mid, high, low, size, key;
  int a[1000];
  printf("Enter the size of the array\n");
  scanf("%d", &size);
  printf("Enter the elements in the array\n");
  for (i = 0; i < size; ++i) {
    scanf("%d", &a[i]);
  }
  printf("Enter the element to be searched\n");
  scanf("%d", &key);
  for (i = 0; i < size; i++) {
    if (a[i] == key) {
      printf("The key %d is found at index %d \n", key, i + 1);
      exit(0);
    }
  }
  printf("The key is not found in the array\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D44(%rip),%rdi
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L1
  nopl   (%rax)
L47:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L47
L1:
  lea    D55(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L43
  mov    0xc(%rsp),%esi
  xor    %ebx,%ebx
  lea    0x10(%rsp),%rbp
  lea    D25(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L53:
  lea    0x1(%rbx),%edx
  cmp    %esi,0x0(%rbp,%rbx,4)
  je     L9
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L53
L43:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L9:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jle    L43
  mov    0xc(%rsp),%esi
  jmp    L53
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D44
data_type: string
name: unpack_data
arguments: label: D3
data_type: string
name: unpack_data
arguments: label: D2
data_type: string
name: unpack_data
arguments: label: D55
data_type: string
name: unpack_data
arguments: label: D25
data_type: string
name: unpack_data
arguments: label: D34
data_type: string

tool: D44: Enter the size of the array

tool: D3: %d

tool: D2: Enter the elements in the array

tool: D55: Enter the element to be searched

tool: D25: The key %d is found at index %d 


tool: D34: The key is not found in the array

assistant: ```c
int main(int argc, char const *argv[]) {
  int i, j, mid, high, low, size, key;
  int a[1000];
  printf("Enter the size of the array\n");
  scanf("%d", &size);
  printf("Enter the elements in the array\n");
  for (i = 0; i < size; ++i) {
    scanf("%d", &a[i]);
  }
  printf("Enter the element to be searched\n");
  scanf("%d", &key);
  for (i = 0; i < size; i++) {
    if (a[i] == key) {
      printf("The key %d is found at index %d \n", key, i + 1);
      exit(0);
    }
  }
  printf("The key is not found in the array\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ChapMS_v2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x4c(%rbp)
  mov    %r8,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L2:
  cmp    %rdx,%rsp
  je     L69
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L2
L69:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L64
  orq    $0x0,-0x8(%rsp,%rax,1)
L64:
  mov    %rsp,%r15
  mov    D3(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L63:
  cmp    %rdx,%rsp
  je     L14
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L63
L14:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L12
  orq    $0x0,-0x8(%rsp,%rax,1)
L12:
  mov    $0x31,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x10,%edx
  mov    $0x66,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    -0x3c(%rbp),%r14
  mov    %r14,%rdi
  call   <SHA_Init@plt>
  mov    $0x10,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <SHA1_Update@plt>
  mov    $0x10,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <SHA1_Update@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <SHA1_Update@plt>
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <SHA1_Final@plt>
  mov    %r15,%rdx
  mov    -0x4c(%rbp),%esi
  mov    -0x48(%rbp),%rdi
  call   <NtPasswordHash@plt>
  lea    0x18(%rbx),%rdx
  mov    %r15,%rsi
  mov    %rsp,%rdi
  call   <ChallengeResponse@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ChapMS_v2(unsigned char *resp, unsigned char *chl, unsigned char *secret, int secret_len, char *username) {
  unsigned char pwdhash[MD4_DIGEST_LENGTH];
  SHA_CTX ctx;
  unsigned char digest[SHA_DIGEST_LENGTH];
  memset(resp, 0, 49);
  memset(resp, 0x66, 16);
  SHA_Init(&ctx);
  SHA1_Update(&ctx, resp, 16);
  SHA1_Update(&ctx, chl, 16);
  SHA1_Update(&ctx, username, strlen(username));
  SHA1_Final(digest, &ctx);
  NtPasswordHash(secret, secret_len, pwdhash);
  ChallengeResponse(digest, pwdhash, resp + 16 + 8);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ChapMS_v2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D10(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L84
L28:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L28
L84:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L33
L15:
  mov    D15(%rip),%rax
  mov    %rsp,%rcx
  mov    %rsp,%r8
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L43
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L38
L43:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L71
L76:
  xor    %esi,%esi
  mov    $0x31,%edx
  mov    %rbx,%rdi
  mov    %r8,-0x50(%rbp)
  call   <memset@plt>
  mov    $0x10,%edx
  mov    $0x66,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    -0x3c(%rbp),%r9
  mov    %r9,%rdi
  mov    %r9,-0x48(%rbp)
  call   <SHA_Init@plt>
  mov    -0x48(%rbp),%rdi
  mov    $0x10,%edx
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <SHA1_Update@plt>
  mov    -0x48(%rbp),%rdi
  mov    $0x10,%edx
  xor    %eax,%eax
  mov    %r15,%rsi
  call   <SHA1_Update@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    -0x48(%rbp),%rdi
  mov    %r12,%rsi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <SHA1_Update@plt>
  mov    -0x48(%rbp),%rsi
  mov    %rsp,%rdi
  call   <SHA1_Final@plt>
  mov    -0x50(%rbp),%r8
  mov    %r14d,%esi
  mov    %r13,%rdi
  mov    %r8,%rdx
  mov    %r8,-0x48(%rbp)
  call   <NtPasswordHash@plt>
  mov    -0x48(%rbp),%rsi
  lea    0x18(%rbx),%rdx
  mov    %rsp,%rdi
  call   <ChallengeResponse@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L71:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L76
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ChapMS_v2(unsigned char *resp, unsigned char *chl, unsigned char *secret, int secret_len, char *username) {
  unsigned char pwdhash[MD4_DIGEST_LENGTH];
  SHA_CTX ctx;
  unsigned char digest[SHA_DIGEST_LENGTH];
  memset(resp, 0, 49);
  memset(resp, 0x66, 16);
  SHA_Init(&ctx);
  SHA1_Update(&ctx, resp, 16);
  SHA1_Update(&ctx, chl, 16);
  SHA1_Update(&ctx, username, strlen(username));
  SHA1_Final(digest, &ctx);
  NtPasswordHash(secret, secret_len, pwdhash);
  ChallengeResponse(digest, pwdhash, resp + 16 + 8);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ChapMS_v2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D10(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L44
L12:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L12
L44:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L46
L18:
  mov    D15(%rip),%rax
  mov    %rsp,%rcx
  mov    %rsp,%r8
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L36
L37:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L37
L36:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L88
L89:
  xor    %esi,%esi
  mov    $0x31,%edx
  mov    %rbx,%rdi
  mov    %r8,-0x50(%rbp)
  call   <memset@plt>
  mov    $0x10,%edx
  mov    $0x66,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    -0x3c(%rbp),%r9
  mov    %r9,%rdi
  mov    %r9,-0x48(%rbp)
  call   <SHA_Init@plt>
  mov    -0x48(%rbp),%rdi
  mov    $0x10,%edx
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <SHA1_Update@plt>
  mov    -0x48(%rbp),%rdi
  mov    $0x10,%edx
  xor    %eax,%eax
  mov    %r15,%rsi
  call   <SHA1_Update@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    -0x48(%rbp),%rdi
  mov    %r12,%rsi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <SHA1_Update@plt>
  mov    -0x48(%rbp),%rsi
  mov    %rsp,%rdi
  call   <SHA1_Final@plt>
  mov    -0x50(%rbp),%r8
  mov    %r14d,%esi
  mov    %r13,%rdi
  mov    %r8,%rdx
  mov    %r8,-0x48(%rbp)
  call   <NtPasswordHash@plt>
  mov    -0x48(%rbp),%rsi
  lea    0x18(%rbx),%rdx
  mov    %rsp,%rdi
  call   <ChallengeResponse@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L88:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L89
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ChapMS_v2(unsigned char *resp, unsigned char *chl, unsigned char *secret, int secret_len, char *username) {
  unsigned char pwdhash[MD4_DIGEST_LENGTH];
  SHA_CTX ctx;
  unsigned char digest[SHA_DIGEST_LENGTH];
  memset(resp, 0, 49);
  memset(resp, 0x66, 16);
  SHA_Init(&ctx);
  SHA1_Update(&ctx, resp, 16);
  SHA1_Update(&ctx, chl, 16);
  SHA1_Update(&ctx, username, strlen(username));
  SHA1_Final(digest, &ctx);
  NtPasswordHash(secret, secret_len, pwdhash);
  ChallengeResponse(digest, pwdhash, resp + 16 + 8);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<factorial_norecursive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x670,%rsp
  mov    %edi,-0x664(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,-0x658(%rbp)
  addq   $0x1,-0x658(%rbp)
  mov    -0x664(%rbp),%eax
  cltq
  mov    %rax,-0x650(%rbp)
  movq   $0x0,-0x648(%rbp)
L18:
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x650,%rax
  mov    (%rax),%rax
  cmp    $0x1,%rax
  jne    L36
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x648,%rax
  movq   $0x1,(%rax)
L36:
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x650,%rax
  mov    (%rax),%rax
  cmp    $0x1,%rax
  jbe    L42
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x648,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L42
  addq   $0x1,-0x658(%rbp)
  mov    -0x658(%rbp),%rax
  sub    $0x1,%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x650,%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x650,%rax
  mov    %rdx,(%rax)
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x648,%rax
  movq   $0x0,(%rax)
L42:
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x648,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L58
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x648,%rax
  mov    (%rax),%rdx
  mov    -0x658(%rbp),%rax
  sub    $0x1,%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x650,%rax
  mov    (%rax),%rax
  mov    -0x658(%rbp),%rcx
  sub    $0x1,%rcx
  imul   %rdx,%rax
  shl    $0x4,%rcx
  mov    %rcx,%rdx
  add    %rbp,%rdx
  sub    $0x648,%rdx
  mov    %rax,(%rdx)
  subq   $0x1,-0x658(%rbp)
L58:
  cmpq   $0x0,-0x658(%rbp)
  jne    L18
  mov    -0x658(%rbp),%rax
  shl    $0x4,%rax
  add    %rbp,%rax
  sub    $0x648,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
unsigned long factorial_norecursive(int num) {
  unsigned long stack[100][2], top = -1;
  top++;
  stack[0][0] = num;
  stack[0][1] = 0;
  do {
    if (stack[top][0] == 1)
      stack[top][1] = 1;
    if (stack[top][0] > 1 && stack[top][1] == 0) {
      top++;
      stack[top][0] = stack[top - 1][0] - 1;
      stack[top][1] = 0;
    }
    if (stack[top][1] != 0) {
      stack[top - 1][1] = stack[top][1] * stack[top - 1][0];
      top--;
    }
  } while (top > 0);
  return stack[top][1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<factorial_norecursive>:
  endbr64
  sub    $0x658,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x648(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  mov    %rdi,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    $0x1,%esi
  jmp    L33
L84:
  mov    %rax,%rdx
  shl    $0x4,%rdx
  movq   $0x1,0x8(%rsp,%rdx,1)
  mov    %rsi,%rcx
L32:
  sub    $0x1,%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  imul   (%rsp,%rdx,1),%rcx
  mov    %rcx,0x8(%rsp,%rdx,1)
L47:
  test   %rax,%rax
  je     L50
L33:
  mov    %rax,%rdx
  shl    $0x4,%rdx
  mov    (%rsp,%rdx,1),%rdx
  cmp    $0x1,%rdx
  je     L84
  jbe    L70
  mov    %rax,%rcx
  shl    $0x4,%rcx
  mov    0x8(%rsp,%rcx,1),%rcx
  test   %rcx,%rcx
  jne    L32
  add    $0x1,%rax
  mov    %rax,%rcx
  shl    $0x4,%rcx
  sub    $0x1,%rdx
  mov    %rdx,(%rsp,%rcx,1)
  movq   $0x0,0x8(%rsp,%rcx,1)
  jmp    L47
L70:
  mov    %rax,%rdx
  shl    $0x4,%rdx
  mov    0x8(%rsp,%rdx,1),%rcx
  test   %rcx,%rcx
  je     L47
  jmp    L32
L50:
  mov    0x8(%rsp),%rax
  mov    0x648(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x658,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long factorial_norecursive(int num) {
  unsigned long stack[100][2], top = -1;
  top++;
  stack[0][0] = num;
  stack[0][1] = 0;
  do {
    if (stack[top][0] == 1)
      stack[top][1] = 1;
    if (stack[top][0] > 1 && stack[top][1] == 0) {
      top++;
      stack[top][0] = stack[top - 1][0] - 1;
      stack[top][1] = 0;
    }
    if (stack[top][1] != 0) {
      stack[top - 1][1] = stack[top][1] * stack[top - 1][0];
      top--;
    }
  } while (top > 0);
  return stack[top][1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<factorial_norecursive>:
  endbr64
  sub    $0x658,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x648(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  movq   $0x0,0x8(%rsp)
  jmp    L35
L73:
  mov    0x8(%rsp,%rdx,1),%rdx
  cmp    $0x1,%rdi
  jbe    L51
  test   %rdx,%rdx
  jne    L45
  add    $0x1,%rax
  sub    $0x1,%rdi
  mov    %rax,%rdx
  shl    $0x4,%rdx
  mov    %rdi,(%rsp,%rdx,1)
  movq   $0x0,0x8(%rsp,%rdx,1)
L6:
  test   %rax,%rax
  je     L71
L88:
  mov    %rax,%rdx
  shl    $0x4,%rdx
  mov    (%rsp,%rdx,1),%rdi
L35:
  mov    %rax,%rdx
  shl    $0x4,%rdx
  cmp    $0x1,%rdi
  jne    L73
  movq   $0x1,0x8(%rsp,%rdx,1)
  mov    $0x1,%edx
L45:
  sub    $0x1,%rax
  mov    %rax,%rcx
  shl    $0x4,%rcx
  imul   (%rsp,%rcx,1),%rdx
  mov    %rdx,0x8(%rsp,%rcx,1)
  test   %rax,%rax
  jne    L88
L71:
  mov    0x8(%rsp),%rax
  mov    0x648(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x658,%rsp
  ret
  nopl   (%rax)
L51:
  test   %rdx,%rdx
  je     L6
  jmp    L45
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long factorial_norecursive(int num) {
  unsigned long stack[100][2], top = -1;
  top++;
  stack[0][0] = num;
  stack[0][1] = 0;
  do {
    if (stack[top][0] == 1)
      stack[top][1] = 1;
    if (stack[top][0] > 1 && stack[top][1] == 0) {
      top++;
      stack[top][0] = stack[top - 1][0] - 1;
      stack[top][1] = 0;
    }
    if (stack[top][1] != 0) {
      stack[top - 1][1] = stack[top][1] * stack[top - 1][0];
      top--;
    }
  } while (top > 0);
  return stack[top][1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<factorial_norecursive>:
  endbr64
  sub    $0x658,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x648(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  movq   $0x0,0x8(%rsp)
  jmp    L13
L34:
  mov    0x8(%rsp,%rdx,1),%rdx
  cmp    $0x1,%rdi
  jbe    L27
  test   %rdx,%rdx
  jne    L26
  add    $0x1,%rax
  sub    $0x1,%rdi
  mov    %rax,%rdx
  shl    $0x4,%rdx
  mov    %rdi,(%rsp,%rdx,1)
  movq   $0x0,0x8(%rsp,%rdx,1)
L86:
  test   %rax,%rax
  je     L62
L76:
  mov    %rax,%rdx
  shl    $0x4,%rdx
  mov    (%rsp,%rdx,1),%rdi
L13:
  mov    %rax,%rdx
  shl    $0x4,%rdx
  cmp    $0x1,%rdi
  jne    L34
  movq   $0x1,0x8(%rsp,%rdx,1)
  mov    $0x1,%edx
L26:
  sub    $0x1,%rax
  mov    %rax,%rcx
  shl    $0x4,%rcx
  imul   (%rsp,%rcx,1),%rdx
  mov    %rdx,0x8(%rsp,%rcx,1)
  test   %rax,%rax
  jne    L76
L62:
  mov    0x8(%rsp),%rax
  mov    0x648(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L71
  add    $0x658,%rsp
  ret
  nopl   (%rax)
L27:
  test   %rdx,%rdx
  je     L86
  jmp    L26
L71:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long factorial_norecursive(int num) {
  unsigned long stack[100][2], top = -1;
  top++;
  stack[0][0] = num;
  stack[0][1] = 0;
  do {
    if (stack[top][0] == 1)
      stack[top][1] = 1;
    if (stack[top][0] > 1 && stack[top][1] == 0) {
      top++;
      stack[top][0] = stack[top - 1][0] - 1;
      stack[top][1] = 0;
    }
    if (stack[top][1] != 0) {
      stack[top - 1][1] = stack[top][1] * stack[top - 1][0];
      top--;
    }
  } while (top > 0);
  return stack[top][1];
}
```
user: What is the c source code of the assembly code below?

```asm
<add_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L125
L115:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0xff000000,%eax
  test   %eax,%eax
  je     L8
  movl   $0x4,-0x8(%rbp)
  jmp    L7
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0xff0000,%eax
  test   %eax,%eax
  je     L37
  cmpl   $0x3,-0x8(%rbp)
  jg     L37
  movl   $0x3,-0x8(%rbp)
  jmp    L7
L37:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0xff00,%eax
  test   %eax,%eax
  je     L100
  cmpl   $0x2,-0x8(%rbp)
  jg     L100
  movl   $0x2,-0x8(%rbp)
  jmp    L7
L100:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movzbl %al,%eax
  test   %eax,%eax
  je     L7
  cmpl   $0x1,-0x8(%rbp)
  jg     L7
  movl   $0x1,-0x8(%rbp)
L7:
  addl   $0x1,-0xc(%rbp)
L125:
  cmpl   $0xff,-0xc(%rbp)
  jle    L115
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    D12(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L15
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L15:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D5
type: string

tool: D12: %c

tool: D5: Failure to output size of the frequency byte number.


assistant: ```c
int add_size(FILE *file, int freq[256]) {
  int i = 0, num_bytes = 0, ret = 0;
  for (i = 0; i < 256; i++) {
    if (freq[i] & 0xFF000000) {
      num_bytes = 4;
    } else if ((freq[i] & 0x00FF0000) && num_bytes < 4) {
      num_bytes = 3;
    } else if ((freq[i] & 0x0000FF00) && num_bytes < 3) {
      num_bytes = 2;
    } else if ((freq[i] & 0x000000FF) && num_bytes < 2) {
      num_bytes = 1;
    }
  }
  if ((ret = fprintf(file, "%c", num_bytes)) != 1) {
    printf("Failure to output size of the frequency byte number.\n");
    exit(1);
  }
  return num_bytes;
}
```