ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gcd>:
  endbr64
  mov    $0x1,%eax
  mov    %edi,%edx
  or     %esi,%edx
  js     L76
  test   $0x1,%dl
  jne    L37
  mov    $0x1,%edx
L16:
  sar    %edi
  sar    %esi
  add    %edx,%edx
  mov    %edi,%eax
  or     %esi,%eax
  test   $0x1,%al
  je     L16
L51:
  mov    %edi,%eax
  test   $0x1,%dil
  jne    L21
L17:
  test   %eax,%eax
  jle    L8
  sar    %eax
L103:
  test   $0x1,%al
  je     L17
  test   %eax,%eax
  jle    L45
L111:
  mov    %eax,%ecx
  sub    %esi,%ecx
  jne    L41
  imul   %edx,%eax
L76:
  ret
L37:
  mov    $0x1,%edx
  jmp    L51
L21:
  mov    %esi,%eax
  neg    %eax
  jmp    L103
L41:
  mov    %eax,%edi
  mov    %ecx,%eax
  jmp    L17
L8:
  neg    %eax
  sar    %eax
  neg    %eax
  jmp    L103
L45:
  neg    %eax
  mov    %eax,%esi
  mov    %edi,%eax
  jmp    L111
```

assistant: ```c
gcd(u, v) int u, v;
{
  int t, f;
  if ((u < 0) || (v < 0))
    return (1);
  f = 1;
  while ((0 == (u % 2)) && (0 == (v % 2))) {
    u >>= 1;
    v >>= 1, f *= 2;
  }
  if (u & 01) {
    t = -v;
    goto B4;
  } else {
    t = u;
  }
B3:
  if (t > 0) {
    t >>= 1;
  } else {
    t = -((-t) >> 1);
  }
B4:
  if (0 == (t % 2))
    goto B3;
  if (t > 0)
    u = t;
  else
    v = -t;
  if (0 != (t = u - v))
    goto B3;
  return (u * f);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  or     %esi,%edx
  js     L64
  and    $0x1,%edx
  mov    $0x1,%edx
  jne    L57
  nopl   0x0(%rax)
L48:
  sar    %edi
  sar    %esi
  add    %edx,%edx
  mov    %edi,%eax
  or     %esi,%eax
  test   $0x1,%al
  je     L48
L57:
  mov    %edi,%ecx
  test   $0x1,%dil
  jne    L6
L45:
  test   %ecx,%ecx
  jle    L38
L83:
  mov    %ecx,%eax
  sar    %eax
L42:
  test   $0x1,%al
  je     L18
  test   %eax,%eax
  jg     L29
  neg    %eax
  mov    %eax,%esi
L117:
  mov    %edi,%eax
L29:
  mov    %eax,%ecx
  sub    %esi,%ecx
  jne    L58
  imul   %edx,%eax
L64:
  ret
  cs nopw 0x0(%rax,%rax,1)
L38:
  neg    %ecx
  sar    %ecx
  mov    %ecx,%eax
  neg    %eax
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %esi,%ecx
  neg    %ecx
  test   $0x1,%sil
  jne    L117
  test   %ecx,%ecx
  jg     L83
  jmp    L38
L58:
  mov    %eax,%edi
  jmp    L45
L18:
  mov    %eax,%ecx
  jmp    L45
```

assistant: ```c
gcd(u, v) int u, v;
{
  int t, f;
  if ((u < 0) || (v < 0))
    return (1);
  f = 1;
  while ((0 == (u % 2)) && (0 == (v % 2))) {
    u >>= 1;
    v >>= 1, f *= 2;
  }
  if (u & 01) {
    t = -v;
    goto B4;
  } else {
    t = u;
  }
B3:
  if (t > 0) {
    t >>= 1;
  } else {
    t = -((-t) >> 1);
  }
B4:
  if (0 == (t % 2))
    goto B3;
  if (t > 0)
    u = t;
  else
    v = -t;
  if (0 != (t = u - v))
    goto B3;
  return (u * f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  or     %esi,%edx
  js     L133
  and    $0x1,%edx
  mov    $0x1,%edx
  jne    L132
  nopl   0x0(%rax)
L89:
  sar    %edi
  sar    %esi
  add    %edx,%edx
  mov    %edi,%eax
  or     %esi,%eax
  test   $0x1,%al
  je     L89
L132:
  mov    %edi,%ecx
  test   $0x1,%dil
  jne    L127
L49:
  test   %ecx,%ecx
  jle    L138
L126:
  mov    %ecx,%eax
  sar    %eax
L92:
  test   $0x1,%al
  je     L46
  test   %eax,%eax
  jg     L41
  neg    %eax
  mov    %eax,%esi
L33:
  mov    %edi,%eax
L41:
  mov    %eax,%ecx
  sub    %esi,%ecx
  jne    L87
  imul   %edx,%eax
L133:
  ret
  cs nopw 0x0(%rax,%rax,1)
L138:
  neg    %ecx
  sar    %ecx
  mov    %ecx,%eax
  neg    %eax
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L127:
  mov    %esi,%ecx
  neg    %ecx
  test   $0x1,%sil
  jne    L33
  test   %ecx,%ecx
  jg     L126
  jmp    L138
L87:
  mov    %eax,%edi
  jmp    L49
L46:
  mov    %eax,%ecx
  jmp    L49
```

assistant: ```c
gcd(u, v) int u, v;
{
  int t, f;
  if ((u < 0) || (v < 0))
    return (1);
  f = 1;
  while ((0 == (u % 2)) && (0 == (v % 2))) {
    u >>= 1;
    v >>= 1, f *= 2;
  }
  if (u & 01) {
    t = -v;
    goto B4;
  } else {
    t = u;
  }
B3:
  if (t > 0) {
    t >>= 1;
  } else {
    t = -((-t) >> 1);
  }
B4:
  if (0 == (t % 2))
    goto B3;
  if (t > 0)
    u = t;
  else
    v = -t;
  if (0 != (t = u - v))
    goto B3;
  return (u * f);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ViewLog@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  ViewLog();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ViewLog@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ViewLog();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ViewLog@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ViewLog();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ViewLog@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ViewLog();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_spaces@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L30
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <qe_isspace@plt>
  test   %rax,%rax
  jne    L30
  mov    -0x14(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L30
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  cmp    %rax,%rdx
  jge    L37
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
L37:
  addq   $0x1,-0x8(%rbp)
  jmp    L10
L30:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_spaces@plt>
  nop
  leave
  ret
```

assistant: ```c
void get_str(const char **pp, char *buf, int buf_size, const char *stop) {
  char *q;
  const char *p;
  int c;
  skip_spaces(pp);
  p = *pp;
  q = buf;
  for (;;) {
    c = *p;
    if (c == '\0' || qe_isspace(c) || strchr(stop, c))
      break;
    if ((q - buf) < buf_size - 1)
      *q++ = c;
    p++;
  }
  *q = '\0';
  *pp = p;
  skip_spaces(pp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r12
  mov    %rsi,(%rsp)
  mov    %edx,%r15d
  mov    %rcx,%r14
  call   <skip_spaces@plt>
  mov    (%rbx),%rbp
  movzbl 0x0(%rbp),%r13d
  movsbl %r13b,%ebx
  test   %ebx,%ebx
  je     L37
  sub    $0x1,%r15d
  jmp    L15
L45:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%r13d
  movsbl %r13b,%ebx
  test   %ebx,%ebx
  je     L14
L15:
  mov    %ebx,%edi
  call   <qe_isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L14
  mov    %r12,%rdx
  sub    (%rsp),%rdx
  movslq %r15d,%rax
  cmp    %rax,%rdx
  jge    L45
  mov    %r13b,(%r12)
  lea    0x1(%r12),%r12
  jmp    L45
L37:
  mov    (%rsp),%r12
L14:
  movb   $0x0,(%r12)
  mov    0x8(%rsp),%rax
  mov    %rbp,(%rax)
  mov    %rax,%rdi
  call   <skip_spaces@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void get_str(const char **pp, char *buf, int buf_size, const char *stop) {
  char *q;
  const char *p;
  int c;
  skip_spaces(pp);
  p = *pp;
  q = buf;
  for (;;) {
    c = *p;
    if (c == '\0' || qe_isspace(c) || strchr(stop, c))
      break;
    if ((q - buf) < buf_size - 1)
      *q++ = c;
    p++;
  }
  *q = '\0';
  *pp = p;
  skip_spaces(pp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_str>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  call   <skip_spaces@plt>
  mov    (%rbx),%rbx
  movsbl (%rbx),%r15d
  test   %r15d,%r15d
  je     L33
  mov    0x4(%rsp),%eax
  mov    %r15d,%r12d
  mov    %r13,%rbp
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  jmp    L13
  nopl   0x0(%rax)
L3:
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L10
  mov    %rbp,%rdx
  movslq 0x4(%rsp),%rax
  sub    %r13,%rdx
  cmp    %rax,%rdx
  jge    L25
  mov    %r12b,0x0(%rbp)
  add    $0x1,%rbp
L25:
  movsbl 0x1(%rbx),%r15d
  add    $0x1,%rbx
  mov    %r15d,%r12d
  test   %r15d,%r15d
  je     L10
L13:
  mov    %r15d,%edi
  call   <qe_isspace@plt>
  test   %rax,%rax
  je     L3
L10:
  mov    0x8(%rsp),%rax
  movb   $0x0,0x0(%rbp)
  mov    %rbx,(%rax)
  add    $0x18,%rsp
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <skip_spaces@plt>
L33:
  mov    %r13,%rbp
  jmp    L10
```

assistant: ```c
void get_str(const char **pp, char *buf, int buf_size, const char *stop) {
  char *q;
  const char *p;
  int c;
  skip_spaces(pp);
  p = *pp;
  q = buf;
  for (;;) {
    c = *p;
    if (c == '\0' || qe_isspace(c) || strchr(stop, c))
      break;
    if ((q - buf) < buf_size - 1)
      *q++ = c;
    p++;
  }
  *q = '\0';
  *pp = p;
  skip_spaces(pp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_str>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  call   <skip_spaces@plt>
  mov    (%rbx),%rbx
  movsbl (%rbx),%r15d
  test   %r15d,%r15d
  je     L56
  mov    0x4(%rsp),%eax
  mov    %r15d,%ebp
  mov    %r13,%r12
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r15d,%edi
  call   <qe_isspace@plt>
  test   %rax,%rax
  jne    L67
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L67
  mov    %r12,%rdx
  movslq 0x4(%rsp),%rax
  sub    %r13,%rdx
  cmp    %rax,%rdx
  jge    L74
  add    $0x1,%rbx
  mov    %bpl,(%r12)
  lea    0x1(%r12),%rax
  movsbl (%rbx),%r15d
  mov    %rax,%r12
  mov    %r15d,%ebp
  test   %r15d,%r15d
  jne    L38
L67:
  mov    0x8(%rsp),%rax
  movb   $0x0,(%r12)
  mov    %rbx,(%rax)
  add    $0x18,%rsp
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <skip_spaces@plt>
  nopl   0x0(%rax)
L74:
  movsbl 0x1(%rbx),%r15d
  add    $0x1,%rbx
  mov    %r15d,%ebp
  test   %r15d,%r15d
  jne    L38
  jmp    L67
L56:
  mov    %r13,%r12
  jmp    L67
```

assistant: ```c
void get_str(const char **pp, char *buf, int buf_size, const char *stop) {
  char *q;
  const char *p;
  int c;
  skip_spaces(pp);
  p = *pp;
  q = buf;
  for (;;) {
    c = *p;
    if (c == '\0' || qe_isspace(c) || strchr(stop, c))
      break;
    if ((q - buf) < buf_size - 1)
      *q++ = c;
    p++;
  }
  *q = '\0';
  *pp = p;
  skip_spaces(pp);
}
```
user: What is the c source code of the assembly code below?

```asm
<test_get_job_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D14(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <get_job_directory@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    $0x1,%edi
  call   <exit@plt>
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D18
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D14: /tmp/taskTracker/user/jobcache/job_200906101234_0001

tool: D18: job_200906101234_0001

tool: D5: user

tool: D7: /tmp

assistant: ```c
void test_get_job_directory() {
  char *expected = "/tmp/taskTracker/user/jobcache/job_200906101234_0001";
  char *job_dir = (char *)get_job_directory("/tmp", "user", "job_200906101234_0001");
  if (strcmp(job_dir, expected) != 0) {
    exit(1);
  }
  free(job_dir);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_get_job_directory>:
  endbr64
  push   %rbx
  lea    D21(%rip),%rdx
  lea    D11(%rip),%rsi
  lea    D34(%rip),%rdi
  call   <get_job_directory@plt>
  mov    %rax,%rbx
  lea    D23(%rip),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
L15:
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L9:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D34
datatype: string
name: read_data
arguments: data_label: D23
datatype: string

tool: D21: job_200906101234_0001

tool: D11: user

tool: D34: /tmp

tool: D23: /tmp/taskTracker/user/jobcache/job_200906101234_0001

assistant: ```c
void test_get_job_directory() {
  char *expected = "/tmp/taskTracker/user/jobcache/job_200906101234_0001";
  char *job_dir = (char *)get_job_directory("/tmp", "user", "job_200906101234_0001");
  if (strcmp(job_dir, expected) != 0) {
    exit(1);
  }
  free(job_dir);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_get_job_directory>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rsi
  lea    D32(%rip),%rdi
  lea    D13(%rip),%rdx
  call   <get_job_directory@plt>
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
  nop
L4:
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
type: string
name: retrieve_data
arguments: data_tag: D32
type: string
name: retrieve_data
arguments: data_tag: D13
type: string
name: retrieve_data
arguments: data_tag: D0
type: string

tool: D26: user

tool: D32: /tmp

tool: D13: job_200906101234_0001

tool: D0: /tmp/taskTracker/user/jobcache/job_200906101234_0001

assistant: ```c
void test_get_job_directory() {
  char *expected = "/tmp/taskTracker/user/jobcache/job_200906101234_0001";
  char *job_dir = (char *)get_job_directory("/tmp", "user", "job_200906101234_0001");
  if (strcmp(job_dir, expected) != 0) {
    exit(1);
  }
  free(job_dir);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_get_job_directory>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rsi
  lea    D3(%rip),%rdi
  lea    D39(%rip),%rdx
  call   <get_job_directory@plt>
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L0
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
  nop
L0:
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
```

tool_calls: name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D39
type: string
name: read_data
arguments: label: D9
type: string

tool: D29: user

tool: D3: /tmp

tool: D39: job_200906101234_0001

tool: D9: /tmp/taskTracker/user/jobcache/job_200906101234_0001

assistant: ```c
void test_get_job_directory() {
  char *expected = "/tmp/taskTracker/user/jobcache/job_200906101234_0001";
  char *job_dir = (char *)get_job_directory("/tmp", "user", "job_200906101234_0001");
  if (strcmp(job_dir, expected) != 0) {
    exit(1);
  }
  free(job_dir);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtnl_receive_multi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rtnl_receive@plt>
  test   %rax,%rax
  jle    L13
  jmp    L10
L13:
  nop
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int rtnl_receive_multi(struct rtnl_handle *rtnl_handle) {
  while (1) {
    if (rtnl_receive(rtnl_handle) <= 0)
      break;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rtnl_receive_multi>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L3:
  mov    %rbx,%rdi
  call   <rtnl_receive@plt>
  test   %rax,%rax
  jg     L3
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rtnl_receive_multi(struct rtnl_handle *rtnl_handle) {
  while (1) {
    if (rtnl_receive(rtnl_handle) <= 0)
      break;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rtnl_receive_multi>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rdi
  call   <rtnl_receive@plt>
  test   %rax,%rax
  jg     L5
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rtnl_receive_multi(struct rtnl_handle *rtnl_handle) {
  while (1) {
    if (rtnl_receive(rtnl_handle) <= 0)
      break;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rtnl_receive_multi>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  call   <rtnl_receive@plt>
  test   %rax,%rax
  jg     L3
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rtnl_receive_multi(struct rtnl_handle *rtnl_handle) {
  while (1) {
    if (rtnl_receive(rtnl_handle) <= 0)
      break;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ldbl_canonicalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x10(%rbp),%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ldbl_canonicalize(double *a, double *aa) {
  double xh, xl;
  xh = *a + *aa;
  xl = (*a - xh) + *aa;
  *a = xh;
  *aa = xl;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ldbl_canonicalize>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  movsd  %xmm2,(%rdi)
  subsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void ldbl_canonicalize(double *a, double *aa) {
  double xh, xl;
  xh = *a + *aa;
  xl = (*a - xh) + *aa;
  *a = xh;
  *aa = xl;
}
```
user: What is the c source code of the assembly code below:

```asm
<ldbl_canonicalize>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm2,(%rdi)
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void ldbl_canonicalize(double *a, double *aa) {
  double xh, xl;
  xh = *a + *aa;
  xl = (*a - xh) + *aa;
  *a = xh;
  *aa = xl;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ldbl_canonicalize>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm2,(%rdi)
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void ldbl_canonicalize(double *a, double *aa) {
  double xh, xl;
  xh = *a + *aa;
  xl = (*a - xh) + *aa;
  *a = xh;
  *aa = xl;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__wcschr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rax
  jmp    L28
L26:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L18
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
wchar_t *__wcschr(const wchar_t *wcs, const wchar_t wc) {
  do
    if (*wcs == wc)
      return (wchar_t *)wcs;
  while (*wcs++ != L'\0');
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__wcschr>:
  endbr64
  mov    %rdi,%rax
L18:
  mov    (%rax),%rdx
  cmp    %rsi,%rdx
  je     L10
  add    $0x8,%rax
  test   %rdx,%rdx
  jne    L18
  mov    $0x0,%eax
L10:
  ret
```

assistant: ```c
wchar_t *__wcschr(const wchar_t *wcs, const wchar_t wc) {
  do
    if (*wcs == wc)
      return (wchar_t *)wcs;
  while (*wcs++ != L'\0');
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__wcschr>:
  endbr64
  mov    %rdi,%rax
  jmp    L27
  nopl   0x0(%rax)
L21:
  add    $0x8,%rax
  test   %rdx,%rdx
  je     L8
L27:
  mov    (%rax),%rdx
  cmp    %rsi,%rdx
  jne    L21
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
wchar_t *__wcschr(const wchar_t *wcs, const wchar_t wc) {
  do
    if (*wcs == wc)
      return (wchar_t *)wcs;
  while (*wcs++ != L'\0');
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__wcschr>:
  endbr64
  mov    %rdi,%rax
  jmp    L18
  nopl   0x0(%rax)
L9:
  add    $0x8,%rax
  test   %rdx,%rdx
  je     L23
L18:
  mov    (%rax),%rdx
  cmp    %rsi,%rdx
  jne    L9
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
wchar_t *__wcschr(const wchar_t *wcs, const wchar_t wc) {
  do
    if (*wcs == wc)
      return (wchar_t *)wcs;
  while (*wcs++ != L'\0');
  return NULL;
}
```