ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,(%rsp)
  movl   $0x5,0x8(%rsp)
  lea    D16(%rip),%rax
  mov    %rax,0x10(%rsp)
  movl   $0x1,0x18(%rsp)
  lea    D3(%rip),%rax
  mov    %rax,0x20(%rsp)
  movl   $0x6,0x28(%rsp)
  mov    %rsp,%rsi
  mov    $0x3,%edx
  mov    $0x1,%edi
  call   <writev@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D27
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: string
name: disassemble_data
arguments: label: D3
type_infered: string

tool: D27: hello

tool: D16:  

tool: D3: world


assistant: ```c
int main(void) {
  struct iovec buffers[3];
  buffers[0].iov_base = "hello";
  buffers[0].iov_len = 5;
  buffers[1].iov_base = " ";
  buffers[1].iov_len = 1;
  buffers[2].iov_base = "world\n";
  buffers[2].iov_len = 6;
  writev(1, buffers, 3);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x3,%edx
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  lea    D0(%rip),%rax
  mov    %rsp,%rsi
  movl   $0x5,0x8(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x6,0x28(%rsp)
  mov    %rax,(%rsp)
  lea    D19(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D7(%rip),%rax
  mov    %rax,0x20(%rsp)
  call   <writev@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D0: hello

tool: D19:  

tool: D7: world


assistant: ```c
int main(void) {
  struct iovec buffers[3];
  buffers[0].iov_base = "hello";
  buffers[0].iov_len = 5;
  buffers[1].iov_base = " ";
  buffers[1].iov_len = 1;
  buffers[2].iov_base = "world\n";
  buffers[2].iov_len = 6;
  writev(1, buffers, 3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x3,%edx
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  lea    D12(%rip),%rax
  mov    %rsp,%rsi
  movl   $0x5,0x8(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x6,0x28(%rsp)
  mov    %rax,(%rsp)
  lea    D20(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D27(%rip),%rax
  mov    %rax,0x20(%rsp)
  call   <writev@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D20
type: string
name: read_data
arguments: tag: D27
type: string

tool: D12: hello

tool: D20:  

tool: D27: world


assistant: ```c
int main(void) {
  struct iovec buffers[3];
  buffers[0].iov_base = "hello";
  buffers[0].iov_len = 5;
  buffers[1].iov_base = " ";
  buffers[1].iov_len = 1;
  buffers[2].iov_base = "world\n";
  buffers[2].iov_len = 6;
  writev(1, buffers, 3);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L21
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L21:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <getspnam@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L14:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L23:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D24
data_type: string

tool: D0: wrong argument

tool: D28: shaow passwd = %s


tool: D24: there is no username %s


assistant: ```c
int main(int argc, const char *argv[]) {
  struct spwd *ptr;
  if (argc != 2) {
    printf("wrong argument\n");
    exit(-1);
  }
  if ((ptr = getspnam(argv[1])) != NULL) {
    printf("shaow passwd = %s\n", ptr->sp_pwdp);
  } else {
    printf("there is no username %s\n", argv[1]);
    exit(-1);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jne    L12
L6:
  mov    0x8(%rbx),%rdi
  call   <getspnam@plt>
  test   %rax,%rax
  je     L13
  mov    (%rax),%rsi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  mov    $0x0,%eax
  pop    %rbx
  ret
L12:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L6
L13:
  mov    0x8(%rbx),%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L25
```

tool_calls: name: unpack_data
arguments: tag: D20
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string

tool: D20: shaow passwd = %s


tool: D19: wrong argument

tool: D18: there is no username %s


assistant: ```c
int main(int argc, const char *argv[]) {
  struct spwd *ptr;
  if (argc != 2) {
    printf("wrong argument\n");
    exit(-1);
  }
  if ((ptr = getspnam(argv[1])) != NULL) {
    printf("shaow passwd = %s\n", ptr->sp_pwdp);
  } else {
    printf("there is no username %s\n", argv[1]);
    exit(-1);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  je     L12
  lea    D1(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L12:
  mov    0x8(%rbx),%rdi
  call   <getspnam@plt>
  test   %rax,%rax
  je     L27
  mov    (%rax),%rsi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L19:
  xor    %eax,%eax
  pop    %rbx
  ret
L27:
  mov    0x8(%rbx),%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L19
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string
name: unpack_data
arguments: tag: D15
data_type: string

tool: D1: wrong argument

tool: D20: shaow passwd = %s


tool: D15: there is no username %s


assistant: ```c
int main(int argc, const char *argv[]) {
  struct spwd *ptr;
  if (argc != 2) {
    printf("wrong argument\n");
    exit(-1);
  }
  if ((ptr = getspnam(argv[1])) != NULL) {
    printf("shaow passwd = %s\n", ptr->sp_pwdp);
  } else {
    printf("there is no username %s\n", argv[1]);
    exit(-1);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  je     L25
  lea    D2(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L25:
  mov    0x8(%rbx),%rdi
  call   <getspnam@plt>
  test   %rax,%rax
  je     L1
  mov    (%rax),%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  mov    0x8(%rbx),%rsi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string
name: retrieve_data
arguments: label: D18
type: string
name: retrieve_data
arguments: label: D20
type: string

tool: D2: wrong argument

tool: D18: shaow passwd = %s


tool: D20: there is no username %s


assistant: ```c
int main(int argc, const char *argv[]) {
  struct spwd *ptr;
  if (argc != 2) {
    printf("wrong argument\n");
    exit(-1);
  }
  if ((ptr = getspnam(argv[1])) != NULL) {
    printf("shaow passwd = %s\n", ptr->sp_pwdp);
  } else {
    printf("there is no username %s\n", argv[1]);
    exit(-1);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_passwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x746c7561666564,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffffa57eb503,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x63,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    0x1(%rdx),%eax
  mov    %eax,-0x2c(%rbp)
  movsbq -0x11(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %al,-0x11(%rbp)
  movsbl -0x11(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int test_passwd(char *passwd, int seed, char **passwds) {
  char i, def[] = "default";
  srand(seed);
  seed = (rand() % 99) + 1;
  i = strcmp(passwd, passwds[i]);
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_passwd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %rdx,%rbp
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    0x0(%rbp),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  movsbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int test_passwd(char *passwd, int seed, char **passwds) {
  char i, def[] = "default";
  srand(seed);
  seed = (rand() % 99) + 1;
  i = strcmp(passwd, passwds[i]);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_passwd>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  movsbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int test_passwd(char *passwd, int seed, char **passwds) {
  char i, def[] = "default";
  srand(seed);
  seed = (rand() % 99) + 1;
  i = strcmp(passwd, passwds[i]);
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_passwd>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  movsbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int test_passwd(char *passwd, int seed, char **passwds) {
  char i, def[] = "default";
  srand(seed);
  seed = (rand() % 99) + 1;
  i = strcmp(passwd, passwds[i]);
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x1,-0x18(%rbp)
  jmp    L32
L51:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L8
L0:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jge    L29
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  subq   $0x1,-0x10(%rbp)
L8:
  cmpq   $0x0,-0x10(%rbp)
  jns    L0
  jmp    L25
L29:
  nop
L25:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L51
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(long long int a[], long long int s) {
  long long int current, t, x;
  for (t = 1; t < s; t++) {
    current = a[t];
    for (x = t - 1; x >= 0; x--) {
      if (current < a[x])
        a[x + 1] = a[x];
      else
        break;
    }
    a[x + 1] = current;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sort>:
  endbr64
  cmp    $0x1,%rsi
  jle    L52
  lea    -0x1(%rsi),%r8
  mov    $0x0,%esi
  jmp    L65
L50:
  mov    %rcx,0x8(%rdi,%rax,8)
  add    $0x1,%rsi
  cmp    %r8,%rsi
  je     L52
L65:
  mov    0x8(%rdi,%rsi,8),%rcx
  mov    %rsi,%rax
  test   %rsi,%rsi
  js     L50
L16:
  mov    (%rdi,%rax,8),%rdx
  cmp    %rcx,%rdx
  jle    L50
  mov    %rdx,0x8(%rdi,%rax,8)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L16
  jmp    L50
L52:
  ret
```

assistant: ```c
void sort(long long int a[], long long int s) {
  long long int current, t, x;
  for (t = 1; t < s; t++) {
    current = a[t];
    for (x = t - 1; x >= 0; x--) {
      if (current < a[x])
        a[x + 1] = a[x];
      else
        break;
    }
    a[x + 1] = current;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  cmp    $0x1,%rsi
  jle    L6
  lea    0x8(%rdi),%r9
  lea    (%rdi,%rsi,8),%r11
  xor    %r10d,%r10d
  nopl   (%rax)
L8:
  mov    (%r9),%r8
  mov    %r10,%rdx
  mov    %r9,%rax
  nopl   0x0(%rax)
L7:
  mov    -0x8(%rax),%rcx
  mov    %rax,%rsi
  cmp    %r8,%rcx
  jle    L37
  sub    $0x1,%rdx
  mov    %rcx,(%rax)
  lea    -0x8(%rax),%rax
  cmp    $0xffffffffffffffff,%rdx
  jne    L7
  mov    %rdi,%rsi
L37:
  add    $0x8,%r9
  mov    %r8,(%rsi)
  add    $0x1,%r10
  cmp    %r9,%r11
  jne    L8
L6:
  ret
```

assistant: ```c
void sort(long long int a[], long long int s) {
  long long int current, t, x;
  for (t = 1; t < s; t++) {
    current = a[t];
    for (x = t - 1; x >= 0; x--) {
      if (current < a[x])
        a[x + 1] = a[x];
      else
        break;
    }
    a[x + 1] = current;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sort>:
  endbr64
  cmp    $0x1,%rsi
  jle    L25
  lea    0x8(%rdi),%r9
  lea    (%rdi,%rsi,8),%r11
  xor    %r10d,%r10d
  nopl   (%rax)
L29:
  mov    (%r9),%r8
  mov    %r10,%rdx
  mov    %r9,%rax
  nopl   0x0(%rax)
L35:
  mov    -0x8(%rax),%rcx
  mov    %rax,%rsi
  cmp    %r8,%rcx
  jle    L3
  sub    $0x1,%rdx
  mov    %rcx,(%rax)
  lea    -0x8(%rax),%rax
  cmp    $0xffffffffffffffff,%rdx
  jne    L35
  mov    %rdi,%rsi
L3:
  add    $0x8,%r9
  mov    %r8,(%rsi)
  add    $0x1,%r10
  cmp    %r9,%r11
  jne    L29
L25:
  ret
```

assistant: ```c
void sort(long long int a[], long long int s) {
  long long int current, t, x;
  for (t = 1; t < s; t++) {
    current = a[t];
    for (x = t - 1; x >= 0; x--) {
      if (current < a[x])
        a[x + 1] = a[x];
      else
        break;
    }
    a[x + 1] = current;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x3,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f(int z) {
  int x, y;
#pragma omp task private(x) depend(out : x)
  { x = 3; }
#pragma omp task private(x, y) depend(in : x) depend(out : y)
  { y = x + 1; }
#pragma omp taskwait
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int z) {
  int x, y;
#pragma omp task private(x) depend(out : x)
  { x = 3; }
#pragma omp task private(x, y) depend(in : x) depend(out : y)
  { y = x + 1; }
#pragma omp taskwait
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int z) {
  int x, y;
#pragma omp task private(x) depend(out : x)
  { x = 3; }
#pragma omp task private(x, y) depend(in : x) depend(out : y)
  { y = x + 1; }
#pragma omp taskwait
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int z) {
  int x, y;
#pragma omp task private(x) depend(out : x)
  { x = 3; }
#pragma omp task private(x, y) depend(in : x) depend(out : y)
  { y = x + 1; }
#pragma omp taskwait
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  movl   $0x7,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <findSingleOccurenceNumber@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d


assistant: ```c
int main() {
  int A[] = {2, 2, 2, 3, 3, 3, 7, 6, 6, 6};
  int len = 7;
  printf("%d\n", findSingleOccurenceNumber(A, len));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  mov    %rsp,%rdi
  mov    $0x7,%esi
  call   <findSingleOccurenceNumber@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: %d


assistant: ```c
int main() {
  int A[] = {2, 2, 2, 3, 3, 3, 7, 6, 6, 6};
  int len = 7;
  printf("%d\n", findSingleOccurenceNumber(A, len));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x7,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000002,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  add    $0x1,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x600000007,%rax
  mov    %rax,0x18(%rsp)
  sub    $0x1,%rax
  mov    %rax,0x20(%rsp)
  call   <findSingleOccurenceNumber@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main() {
  int A[] = {2, 2, 2, 3, 3, 3, 7, 6, 6, 6};
  int len = 7;
  printf("%d\n", findSingleOccurenceNumber(A, len));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D35(%rip),%xmm0
  mov    $0x7,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D27(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D1(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <findSingleOccurenceNumber@plt>
  lea    D36(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
datatype: byte[16]
name: extract_symbolic_data
arguments: label: D27
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D1
datatype: byte[16]
name: extract_symbolic_data
arguments: label: D36
datatype: string

tool: {"D35": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D27": [0x06,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D1": [0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D36: %d


assistant: ```c
int main() {
  int A[] = {2, 2, 2, 3, 3, 3, 7, 6, 6, 6};
  int len = 7;
  printf("%d\n", findSingleOccurenceNumber(A, len));
}
```
user: Translate the below assembly code into C programming language:

```asm
<qromb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %rdi,%r15
  cvtsd2ss %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,0x84(%rsp)
  cvtss2sd %xmm1,%xmm1
  movsd  %xmm1,0x8(%rsp)
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movsd  %xmm3,(%rsp)
  mov    $0x1,%esi
  movapd %xmm3,%xmm0
  mov    $0x2,%eax
  call   <trapzd@plt>
  movss  %xmm0,0x24(%rsp)
  lea    0x74(%rsp),%r12
  lea    0x14(%rsp),%rbx
  mov    $0x1,%ebp
  jmp    L56
L2:
  add    $0x4,%r12
  add    $0x4,%rbx
L56:
  add    $0x1,%ebp
  mov    %rbx,%r14
  movss  0x10(%rbx),%xmm0
  movss  %xmm0,0x14(%rbx)
  mov    %r12,%r13
  movss  D5(%rip),%xmm0
  mulss  0x10(%r12),%xmm0
  movss  %xmm0,0x14(%r12)
  cmp    $0x15,%ebp
  je     L37
  mov    %ebp,%esi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    %r15,%rdi
  mov    $0x2,%eax
  call   <trapzd@plt>
  movss  %xmm0,0x14(%rbx)
  cmp    $0x4,%ebp
  jle    L2
  lea    0x18(%rsp),%rcx
  lea    0x1c(%rsp),%r8
  pxor   %xmm0,%xmm0
  mov    $0x5,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <polint@plt>
  movss  0x18(%rsp),%xmm2
  movss  0x1c(%rsp),%xmm0
  andps  D47(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  movaps %xmm2,%xmm1
  andps  D47(%rip),%xmm1
  cvtss2sd %xmm1,%xmm1
  mulsd  D4(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L2
  jmp    L13
L37:
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <nrerror@plt>
L13:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  movaps %xmm2,%xmm0
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: f32
name: retrieve_data
arguments: data_label: D47
datatype: dword[4]
name: retrieve_data
arguments: data_label: D4
datatype: byte[8]
name: retrieve_data
arguments: data_label: D41
datatype: string

tool: D5: 0.25

tool: {"D47": [0x7fffffff,0x00000000,0x00000000,0x00000000]}

tool: {"D4": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xd4,0x3e]}

tool: D41: Too many steps in routine QROMB

assistant: ```c
float qromb(func, a, b)
float a, b;
float (*func)();
{
  float ss, dss, trapzd();
  float s[20 + 1 + 1], h[20 + 1 + 1];
  int j;
  void polint(), nrerror();
  h[1] = 1.0;
  for (j = 1; j <= 20; j++) {
    s[j] = trapzd(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) < 0.5e-5 * fabs(ss))
        return ss;
    }
    s[j + 1] = s[j];
    h[j + 1] = 0.25 * h[j];
  }
  nrerror("Too many steps in routine QROMB");
}
```