ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebp
  lea    D29(%rip),%r12
  jmp    L41
L36:
  mov    $0x1,%eax
L37:
  mov    %eax,0x10(%rsp,%rbp,4)
  add    $0x1,%rbp
L41:
  mov    %ebp,%ebx
  lea    0xf(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x31,%al
  je     L36
  cmp    $0x30,%al
  jne    L55
  mov    $0x0,%eax
  jmp    L37
L55:
  sub    $0x1,%ebx
  js     L51
  movslq %ebx,%rbx
  mov    $0x0,%r12d
L72:
  mov    0x10(%rsp,%rbx,4),%ebp
  lea    0x1(%rbx),%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   %eax,%ebp
  add    %ebp,%r12d
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L72
L8:
  mov    %r12d,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  mov    $0x0,%r12d
  jmp    L8
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string

tool: D11: Entre com um binario: 

tool: D29: %c

tool: D14: O decimal eh: %d


assistant: ```c
int main() {
  int bin[50];
  int binSize = 0;
  char binChar;
  int dec = 0;
  printf("Entre com um binario: ");
  while (1) {
    scanf("%c", &binChar);
    if (binChar == '1')
      bin[binSize] = 1;
    else if (binChar == '0')
      bin[binSize] = 0;
    else
      break;
    binSize++;
  }
  int i;
  for (i = binSize - 1; i >= 0; i--) {
    dec += ((int)bin[i] * pow(2, i + 1));
  }
  printf("O decimal eh: %d\n", dec);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%rdi
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%r13
  call   <printf@plt>
  jmp    L3
L62:
  cmp    $0x30,%al
  jne    L19
  xor    %eax,%eax
L1:
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
L3:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %ebx,%ebp
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x31,%al
  jne    L62
  mov    $0x1,%eax
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rbx),%ebx
  test   %ebp,%ebp
  je     L6
  movslq %ebx,%rbx
  xor    %r12d,%r12d
  lea    0x10(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L31:
  mov    0x0(%r13,%rbx,4),%ebp
  lea    0x1(%rbx),%esi
  mov    $0x2,%edi
  sub    $0x1,%rbx
  call   <pow@plt>
  imul   %eax,%ebp
  add    %ebp,%r12d
  cmp    $0xffffffff,%ebx
  jne    L31
L7:
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  xor    %r12d,%r12d
  jmp    L7
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D24
type_guessed: string

tool: D6: Entre com um binario: 

tool: D18: %c

tool: D24: O decimal eh: %d


assistant: ```c
int main() {
  int bin[50];
  int binSize = 0;
  char binChar;
  int dec = 0;
  printf("Entre com um binario: ");
  while (1) {
    scanf("%c", &binChar);
    if (binChar == '1')
      bin[binSize] = 1;
    else if (binChar == '0')
      bin[binSize] = 0;
    else
      break;
    binSize++;
  }
  int i;
  for (i = binSize - 1; i >= 0; i--) {
    dec += ((int)bin[i] * pow(2, i + 1));
  }
  printf("O decimal eh: %d\n", dec);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%rdi
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%r13
  call   <printf@plt>
  jmp    L37
L63:
  cmp    $0x30,%al
  jne    L42
  xor    %eax,%eax
L60:
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
L37:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %ebx,%ebp
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x31,%al
  jne    L63
  mov    $0x1,%eax
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L42:
  lea    -0x1(%rbx),%ebx
  test   %ebp,%ebp
  je     L3
  movslq %ebx,%rbx
  xor    %r12d,%r12d
  lea    0x10(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L19:
  mov    0x0(%r13,%rbx,4),%ebp
  lea    0x1(%rbx),%esi
  mov    $0x2,%edi
  sub    $0x1,%rbx
  call   <pow@plt>
  imul   %eax,%ebp
  add    %ebp,%r12d
  cmp    $0xffffffff,%ebx
  jne    L19
L72:
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  xor    %r12d,%r12d
  jmp    L72
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D25
type_guessed: string

tool: D13: Entre com um binario: 

tool: D17: %c

tool: D25: O decimal eh: %d


assistant: ```c
int main() {
  int bin[50];
  int binSize = 0;
  char binChar;
  int dec = 0;
  printf("Entre com um binario: ");
  while (1) {
    scanf("%c", &binChar);
    if (binChar == '1')
      bin[binSize] = 1;
    else if (binChar == '0')
      bin[binSize] = 0;
    else
      break;
    binSize++;
  }
  int i;
  for (i = binSize - 1; i >= 0; i--) {
    dec += ((int)bin[i] * pow(2, i + 1));
  }
  printf("O decimal eh: %d\n", dec);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ADCIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  cmpl   $0x40038000,-0x14(%rbp)
  je     L26
  cmpl   $0x40039000,-0x14(%rbp)
  jne    L29
L26:
  mov    $0x1,%eax
  jmp    L23
L29:
  mov    $0x0,%eax
L23:
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x3,-0x18(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_ADCIntNumberGet@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <IntRegister@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void ADCIntRegister(uint32_t ui32Base, uint32_t ui32SequenceNum, void (*pfnHandler)(void)) {
  uint_fast8_t ui8Int;
  ASSERT((ui32Base == 0x40038000) || (ui32Base == 0x40039000));
  ASSERT(ui32SequenceNum < 4);
  ui8Int = _ADCIntNumberGet(ui32Base, ui32SequenceNum);
  ASSERT(ui8Int != 0);
  IntRegister(ui8Int, pfnHandler);
  IntEnable(ui8Int);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ADCIntRegister>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %edi,%eax
  and    $0xef,%ah
  cmp    $0x40038000,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  cmp    $0x3,%ebp
  setle  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <_ADCIntNumberGet@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <IntRegister@plt>
  mov    %rbx,%rdi
  call   <IntEnable@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ADCIntRegister(uint32_t ui32Base, uint32_t ui32SequenceNum, void (*pfnHandler)(void)) {
  uint_fast8_t ui8Int;
  ASSERT((ui32Base == 0x40038000) || (ui32Base == 0x40039000));
  ASSERT(ui32SequenceNum < 4);
  ui8Int = _ADCIntNumberGet(ui32Base, ui32SequenceNum);
  ASSERT(ui8Int != 0);
  IntRegister(ui8Int, pfnHandler);
  IntEnable(ui8Int);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ADCIntRegister>:
  endbr64
  mov    %edi,%eax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  and    $0xef,%ah
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  cmp    $0x40038000,%eax
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x3,%r12d
  setle  %dil
  call   <ASSERT@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <_ADCIntNumberGet@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <ASSERT@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <IntRegister@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <IntEnable@plt>
```

assistant: ```c
void ADCIntRegister(uint32_t ui32Base, uint32_t ui32SequenceNum, void (*pfnHandler)(void)) {
  uint_fast8_t ui8Int;
  ASSERT((ui32Base == 0x40038000) || (ui32Base == 0x40039000));
  ASSERT(ui32SequenceNum < 4);
  ui8Int = _ADCIntNumberGet(ui32Base, ui32SequenceNum);
  ASSERT(ui8Int != 0);
  IntRegister(ui8Int, pfnHandler);
  IntEnable(ui8Int);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ADCIntRegister>:
  endbr64
  mov    %edi,%eax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  and    $0xef,%ah
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  cmp    $0x40038000,%eax
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x3,%r12d
  setle  %dil
  call   <ASSERT@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <_ADCIntNumberGet@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <ASSERT@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <IntRegister@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <IntEnable@plt>
```

assistant: ```c
void ADCIntRegister(uint32_t ui32Base, uint32_t ui32SequenceNum, void (*pfnHandler)(void)) {
  uint_fast8_t ui8Int;
  ASSERT((ui32Base == 0x40038000) || (ui32Base == 0x40039000));
  ASSERT(ui32SequenceNum < 4);
  ui8Int = _ADCIntNumberGet(ui32Base, ui32SequenceNum);
  ASSERT(ui8Int != 0);
  IntRegister(ui8Int, pfnHandler);
  IntEnable(ui8Int);
}
```
user: Translate the below assembly code into C programming language:

```asm
<wrint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x4,-0xc(%rbp)
  jmp    L24
L36:
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L46:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L46
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L13
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x30(%rdx),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <writec@plt>
L13:
  subl   $0x1,-0xc(%rbp)
L24:
  cmpl   $0x0,-0xc(%rbp)
  jg     L36
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x30(%rdx),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <writec@plt>
  nop
  leave
  ret
```

assistant: ```c
void wrint(n) int n;
{
  int i, j, t;
  for (i = 4; i > 0; i--) {
    t = 1;
    for (j = 0; j < i; j++)
      t *= 10;
    if (n > t - 1)
      writec((n / t) % 10 + '0');
  }
  writec(n % 10 + '0');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wrint>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x4,%ebx
  mov    $0x1,%r12d
  jmp    L30
L4:
  sub    $0x1,%ebx
  je     L40
L30:
  mov    %r12d,%ecx
  mov    $0x0,%edx
  test   %ebx,%ebx
  jle    L56
L13:
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  add    $0x1,%edx
  cmp    %ebx,%edx
  jne    L13
L56:
  cmp    %ecx,%ebp
  jl     L4
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x30(%rax),%edi
  mov    $0x0,%eax
  call   <writec@plt>
  jmp    L4
L40:
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  mov    $0x0,%eax
  call   <writec@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void wrint(n) int n;
{
  int i, j, t;
  for (i = 4; i > 0; i--) {
    t = 1;
    for (j = 0; j < i; j++)
      t *= 10;
    if (n > t - 1)
      writec((n / t) % 10 + '0');
  }
  writec(n % 10 + '0');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<wrint>:
  endbr64
  push   %r12
  mov    $0xcccccccd,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x4,%ebx
L7:
  mov    $0x1,%ecx
  xor    %edx,%edx
L32:
  lea    (%rcx,%rcx,4),%ecx
  add    $0x1,%edx
  add    %ecx,%ecx
  cmp    %edx,%ebx
  jg     L32
  cmp    %ecx,%ebp
  jge    L5
L31:
  sub    $0x1,%ebx
  jne    L7
  movslq %ebp,%rax
  mov    %ebp,%edx
  pop    %rbx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  xor    %eax,%eax
  lea    0x30(%rbp),%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <writec@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edx
  imul   %r12,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x30(%rax),%edi
  xor    %eax,%eax
  call   <writec@plt>
  jmp    L31
```

assistant: ```c
void wrint(n) int n;
{
  int i, j, t;
  for (i = 4; i > 0; i--) {
    t = 1;
    for (j = 0; j < i; j++)
      t *= 10;
    if (n > t - 1)
      writec((n / t) % 10 + '0');
  }
  writec(n % 10 + '0');
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wrint>:
  endbr64
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x270f,%edi
  jg     L17
  cmp    $0x3e7,%edi
  jg     L9
  cmp    $0x63,%edi
  jg     L34
  cmp    $0x9,%edi
  jg     L40
L8:
  imul   $0x66666667,%rbp,%rbp
  mov    %ebx,%eax
  add    $0x8,%rsp
  sar    $0x1f,%eax
  sar    $0x22,%rbp
  sub    %eax,%ebp
  lea    0x0(%rbp,%rbp,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  xor    %eax,%eax
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <writec@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  imul   $0x68db8bad,%rbp,%rdi
  mov    %ebx,%eax
  mov    $0xcccccccd,%edx
  sar    $0x1f,%eax
  sar    $0x2c,%rdi
  sub    %eax,%edi
  mov    %edi,%eax
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  xor    %eax,%eax
  add    $0x30,%edi
  call   <writec@plt>
L9:
  imul   $0x10624dd3,%rbp,%rdi
  mov    %ebx,%eax
  mov    $0xcccccccd,%edx
  sar    $0x1f,%eax
  sar    $0x26,%rdi
  sub    %eax,%edi
  mov    %edi,%eax
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  xor    %eax,%eax
  add    $0x30,%edi
  call   <writec@plt>
L34:
  imul   $0x51eb851f,%rbp,%rdi
  mov    %ebx,%eax
  mov    $0xcccccccd,%edx
  sar    $0x1f,%eax
  sar    $0x25,%rdi
  sub    %eax,%edi
  mov    %edi,%eax
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  xor    %eax,%eax
  add    $0x30,%edi
  call   <writec@plt>
L40:
  imul   $0x66666667,%rbp,%rdi
  mov    %ebx,%eax
  mov    $0xcccccccd,%edx
  sar    $0x1f,%eax
  sar    $0x22,%rdi
  sub    %eax,%edi
  mov    %edi,%eax
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  xor    %eax,%eax
  add    $0x30,%edi
  call   <writec@plt>
  jmp    L8
```

assistant: ```c
void wrint(n) int n;
{
  int i, j, t;
  for (i = 4; i > 0; i--) {
    t = 1;
    for (j = 0; j < i; j++)
      t *= 10;
    if (n > t - 1)
      writec((n / t) % 10 + '0');
  }
  writec(n % 10 + '0');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void initArray(int array[], int arraySize, int value) {
  for (int i = 0; i < arraySize; i++)
    array[i] = value;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<initArray>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rcx
L16:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L16
L13:
  ret
```

assistant: ```c
void initArray(int array[], int arraySize, int value) {
  for (int i = 0; i < arraySize; i++)
    array[i] = value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<initArray>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
L11:
  mov    %edx,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L11
L13:
  ret
```

assistant: ```c
void initArray(int array[], int arraySize, int value) {
  for (int i = 0; i < arraySize; i++)
    array[i] = value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initArray>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L65
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L43
  shr    $0x2,%esi
  movd   %edx,%xmm1
  mov    %rdi,%rax
  sub    $0x1,%esi
  pshufd $0x0,%xmm1,%xmm0
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   (%rax)
L21:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L21
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%cl
  je     L10
L2:
  movslq %eax,%rsi
  mov    %edx,(%rdi,%rsi,4)
  lea    0x0(,%rsi,4),%r8
  lea    0x1(%rax),%esi
  cmp    %esi,%ecx
  jle    L65
  add    $0x2,%eax
  mov    %edx,0x4(%rdi,%r8,1)
  cmp    %eax,%ecx
  jle    L65
  mov    %edx,0x8(%rdi,%r8,1)
L65:
  ret
  nopl   (%rax)
L10:
  ret
L43:
  xor    %eax,%eax
  jmp    L2
```

assistant: ```c
void initArray(int array[], int arraySize, int value) {
  for (int i = 0; i < arraySize; i++)
    array[i] = value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vec_mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L1:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  cmp    %rax,-0x30(%rbp)
  ja     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vec_mult(double *Y, double *X1, double *X2, unsigned long N) {
  long k;
  for (k = 0; k < N; k++) {
    *(Y + k) = *(X1 + k) * *(X2 + k);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec_mult>:
  endbr64
  test   %rcx,%rcx
  je     L5
  mov    $0x0,%eax
L13:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L13
L5:
  ret
```

assistant: ```c
void vec_mult(double *Y, double *X1, double *X2, unsigned long N) {
  long k;
  for (k = 0; k < N; k++) {
    *(Y + k) = *(X1 + k) * *(X2 + k);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec_mult>:
  endbr64
  test   %rcx,%rcx
  je     L10
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L1:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L1
L10:
  ret
```

assistant: ```c
void vec_mult(double *Y, double *X1, double *X2, unsigned long N) {
  long k;
  for (k = 0; k < N; k++) {
    *(Y + k) = *(X1 + k) * *(X2 + k);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vec_mult>:
  endbr64
  test   %rcx,%rcx
  je     L0
  lea    0x8(%rdx),%rax
  cmp    %rax,%rdi
  lea    0x8(%rsi),%rax
  setne  %r8b
  cmp    %rax,%rdi
  setne  %al
  test   %al,%r8b
  je     L28
  lea    -0x1(%rcx),%rax
  cmp    $0x1,%rax
  jbe    L28
  mov    %rcx,%r8
  xor    %eax,%eax
  shr    %r8
  shl    $0x4,%r8
  nopl   (%rax)
L38:
  movupd (%rsi,%rax,1),%xmm0
  movupd (%rdx,%rax,1),%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L38
  mov    %rcx,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%ecx
  je     L0
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L37:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L37
L0:
  ret
```

assistant: ```c
void vec_mult(double *Y, double *X1, double *X2, unsigned long N) {
  long k;
  for (k = 0; k < N; k++) {
    *(Y + k) = *(X1 + k) * *(X2 + k);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <sync@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D11: Synchronizing filesystems...

tool: D9: OK


assistant: ```c
int main(int argc, char **argv, char **envp) {
  printf("Synchronizing filesystems...");
  sync();
  printf("OK\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <sync@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D0
type: string

tool: D4: Synchronizing filesystems...

tool: D0: OK


assistant: ```c
int main(int argc, char **argv, char **envp) {
  printf("Synchronizing filesystems...");
  sync();
  printf("OK\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <sync@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
data_type: string
name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D11: Synchronizing filesystems...

tool: D6: OK


assistant: ```c
int main(int argc, char **argv, char **envp) {
  printf("Synchronizing filesystems...");
  sync();
  printf("OK\n");
}
```