user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L88
L64:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L64
L88:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L109
L49:
  mov    -0x30(%rbp),%r8d
  lea    0x3(%rsp),%rbx
  mov    %rbx,%rax
  and    $0xfffffffffffffffc,%rbx
  movd   %r8d,%xmm2
  shr    $0x2,%rax
  pshufd $0xe0,%xmm2,%xmm0
  movq   %xmm0,0x0(,%rax,4)
  cmp    $0x2,%ecx
  jle    L71
  cmp    $0x4,%ecx
  jle    L78
  lea    -0x5(%rcx),%eax
  mov    %r8d,%edi
  mov    %r8d,%esi
  mov    $0x4,%edx
  shr    %eax
  lea    0x3(%rax),%r9d
  add    %r9,%r9
L83:
  add    %edi,%esi
  movslq %edx,%rax
  add    %esi,%edi
  movd   %esi,%xmm0
  movd   %edi,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x8(%rbx,%rdx,4)
  add    $0x2,%rdx
  cmp    %rdx,%r9
  jne    L83
  nop
L112:
  mov    -0x8(%rbx,%rax,4),%edx
  add    -0x4(%rbx,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L112
L71:
  mov    %r8d,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jle    L60
  xor    %r12d,%r12d
  lea    D3(%rip),%r13
  nopl   (%rax)
L113:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L113
L60:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  lea    -0x18(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L109:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L49
L78:
  mov    $0x2,%eax
  jmp    L112
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D49
type_guessed: string
name: parse_data
arguments: data_tag: D24
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D61
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D39
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D49: ===== Exercise 8 =====

tool: D24: %i

tool: D4: FIBONACCI NUMBERS!

tool: D61: Enter the first number. : 

tool: D9: How many numbers will be shown?: 

tool: D39: --> %i First Fibonacci Numbers


tool: D3: %i


assistant: ```c
int main(int argc, const char *argv[]) {
  int number;
  printf("===== Exercise 8 =====\n");
  printf("FIBONACCI NUMBERS!\n");
  printf("Enter the first number. : ");
  scanf("%i", &number);
  printf("How many numbers will be shown?: ");
  int TheNumberOfNumber;
  scanf("%i", &TheNumberOfNumber);
  int fibonacci[TheNumberOfNumber];
  fibonacci[0] = number;
  fibonacci[1] = number;
  for (int i = 2; i < TheNumberOfNumber; i++) {
    fibonacci[i] = fibonacci[i - 2] + fibonacci[i - 1];
  }
  printf("--> %i First Fibonacci Numbers\n", number);
  for (int j = 0; j < TheNumberOfNumber; j++) {
    printf("%i\n", fibonacci[j]);
  }
  return 0;
}
```