ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%edi
  test   %edx,%edx
  je     L26
  lea    0x1(%rsi),%r8
  mov    %rcx,%rax
  sub    %r8,%rax
  cmp    $0xe,%rax
  jbe    L117
  cmp    $0x6,%edi
  jbe    L117
  cmp    $0xe,%edi
  jbe    L102
  mov    %edx,%r8d
  xor    %eax,%eax
  shr    $0x4,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L88:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L88
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%r8d
  sub    %eax,%edi
  lea    (%rcx,%r8,1),%r9
  add    %rsi,%r8
  cmp    %eax,%edx
  je     L60
L22:
  sub    %eax,%edx
  lea    -0x1(%rdx),%r10d
  cmp    $0x6,%r10d
  jbe    L120
  mov    (%rsi,%rax,1),%rsi
  mov    %rsi,(%rcx,%rax,1)
  mov    %edx,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%ecx
  sub    %eax,%edi
  add    %rcx,%r9
  add    %rcx,%r8
  cmp    %eax,%edx
  je     L26
L120:
  movzbl (%r8),%eax
  mov    %al,(%r9)
  test   %edi,%edi
  je     L26
  movzbl 0x1(%r8),%eax
  mov    %al,0x1(%r9)
  cmp    $0x1,%edi
  je     L26
  movzbl 0x2(%r8),%eax
  mov    %al,0x2(%r9)
  cmp    $0x2,%edi
  je     L26
  movzbl 0x3(%r8),%eax
  mov    %al,0x3(%r9)
  cmp    $0x3,%edi
  je     L26
  movzbl 0x4(%r8),%eax
  mov    %al,0x4(%r9)
  cmp    $0x4,%edi
  je     L26
  movzbl 0x5(%r8),%eax
  mov    %al,0x5(%r9)
  cmp    $0x5,%edi
  je     L26
  movzbl 0x6(%r8),%eax
  mov    %al,0x6(%r9)
  ret
  nopl   (%rax)
L117:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L72:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L72
L26:
  ret
L102:
  mov    %rsi,%r8
  mov    %rcx,%r9
  xor    %eax,%eax
  jmp    L22
L60:
  ret
```

assistant: ```c
void memcpy(const void *a, void *b, int c) {
  unsigned char *pa = (unsigned char *)a;
  unsigned char *pb = (unsigned char *)b;
  while (c--)
    *pa++ = *pb++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_from_printer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x24(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0x38(%rbp)
  je     L33
  mov    D57(%rip),%rax
  mov    (%rax),%edx
  mov    -0x34(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,%edx
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D10(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x34(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
L33:
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    D53(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x3e8,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <poll@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  js     L60
  mov    -0x48(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  je     L87
  cmpl   $0x0,-0x28(%rbp)
  jns    L81
  mov    D56(%rip),%rax
  mov    (%rax),%rdx
  mov    D42(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L81
L87:
  mov    $0x7d0,%edi
  call   <usleep@plt>
  movl   $0x0,-0x28(%rbp)
L81:
  cmpl   $0x0,-0x28(%rbp)
  jne    L13
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L33
  jmp    L13
L60:
  nop
L13:
  mov    -0x28(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

assistant: ```c
int read_from_printer(int fd, void *buf, size_t bufsize, int nonblocking) {
  int status;
  int retry = 10;
  struct pollfd ufds;
  memset(buf, 0, bufsize);
  if (nonblocking) {
    fcntl(fd, F_SETFL, O_NONBLOCK | fcntl(fd, F_GETFL));
  }
  do {
    ufds.fd = fd;
    ufds.events = POLLIN;
    ufds.revents = 0;
    if ((status = poll(&ufds, 1, 1000)) < 0) {
      break;
    }
    status = read(fd, buf, bufsize - 1);
    if ((status == 0) || ((status < 0) && (errno == EAGAIN))) {
      usleep(2000);
      status = 0;
    }
  } while ((status == 0) && (--retry != 0));
  return status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_from_printer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  jne    L11
L66:
  mov    $0xa,%ebx
  mov    D20(%rip),%r14
  jmp    L18
L11:
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    D11(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D44(%rip),%rax
  mov    (%rax),%esi
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  jmp    L66
L7:
  mov    $0x7d0,%edi
  call   <usleep@plt>
  sub    $0x1,%ebx
  je     L62
L18:
  mov    %ebp,(%rsp)
  mov    (%r14),%eax
  mov    %eax,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rdi
  mov    $0x3e8,%edx
  mov    $0x1,%esi
  call   <poll@plt>
  test   %eax,%eax
  js     L5
  lea    -0x1(%r13),%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  je     L7
  jns    L5
  mov    D39(%rip),%rcx
  mov    D24(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L7
  jmp    L5
L62:
  mov    $0x0,%eax
L5:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L76
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_from_printer(int fd, void *buf, size_t bufsize, int nonblocking) {
  int status;
  int retry = 10;
  struct pollfd ufds;
  memset(buf, 0, bufsize);
  if (nonblocking) {
    fcntl(fd, F_SETFL, O_NONBLOCK | fcntl(fd, F_GETFL));
  }
  do {
    ufds.fd = fd;
    ufds.events = POLLIN;
    ufds.revents = 0;
    if ((status = poll(&ufds, 1, 1000)) < 0) {
      break;
    }
    status = read(fd, buf, bufsize - 1);
    if ((status == 0) || ((status < 0) && (errno == EAGAIN))) {
      usleep(2000);
      status = 0;
    }
  } while ((status == 0) && (--retry != 0));
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_from_printer>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13,%rdi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  test   %ebx,%ebx
  jne    L43
L28:
  mov    D29(%rip),%r15
  mov    $0xa,%ebx
  mov    %rsp,%r14
  sub    $0x1,%r12
  nopl   0x0(%rax)
L55:
  mov    (%r15),%eax
  mov    $0x3e8,%edx
  mov    $0x1,%esi
  mov    %r14,%rdi
  mov    %ebp,(%rsp)
  mov    %eax,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <poll@plt>
  test   %eax,%eax
  js     L41
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  je     L33
  jns    L41
  mov    D4(%rip),%rdx
  mov    D10(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L41
L33:
  mov    $0x7d0,%edi
  call   <usleep@plt>
  sub    $0x1,%ebx
  jne    L55
  xor    %eax,%eax
L41:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  mov    D21(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  mov    D5(%rip),%rdx
  mov    %ebp,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D25(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  jmp    L28
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_from_printer(int fd, void *buf, size_t bufsize, int nonblocking) {
  int status;
  int retry = 10;
  struct pollfd ufds;
  memset(buf, 0, bufsize);
  if (nonblocking) {
    fcntl(fd, F_SETFL, O_NONBLOCK | fcntl(fd, F_GETFL));
  }
  do {
    ufds.fd = fd;
    ufds.events = POLLIN;
    ufds.revents = 0;
    if ((status = poll(&ufds, 1, 1000)) < 0) {
      break;
    }
    status = read(fd, buf, bufsize - 1);
    if ((status == 0) || ((status < 0) && (errno == EAGAIN))) {
      usleep(2000);
      status = 0;
    }
  } while ((status == 0) && (--retry != 0));
  return status;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_from_printer>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13,%rdi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  test   %ebx,%ebx
  jne    L9
L27:
  mov    D57(%rip),%r15
  mov    $0xa,%ebx
  mov    %rsp,%r14
  sub    $0x1,%r12
  nopl   0x0(%rax)
L29:
  mov    (%r15),%eax
  mov    $0x3e8,%edx
  mov    $0x1,%esi
  mov    %r14,%rdi
  mov    %ebp,(%rsp)
  mov    %eax,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <poll@plt>
  test   %eax,%eax
  js     L34
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  je     L10
  jns    L34
  mov    D43(%rip),%rdx
  mov    D24(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L34
L10:
  mov    $0x7d0,%edi
  call   <usleep@plt>
  sub    $0x1,%ebx
  jne    L29
  xor    %eax,%eax
L34:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    D31(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  mov    D41(%rip),%rdx
  mov    %ebp,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D53(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  jmp    L27
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_from_printer(int fd, void *buf, size_t bufsize, int nonblocking) {
  int status;
  int retry = 10;
  struct pollfd ufds;
  memset(buf, 0, bufsize);
  if (nonblocking) {
    fcntl(fd, F_SETFL, O_NONBLOCK | fcntl(fd, F_GETFL));
  }
  do {
    ufds.fd = fd;
    ufds.events = POLLIN;
    ufds.revents = 0;
    if ((status = poll(&ufds, 1, 1000)) < 0) {
      break;
    }
    status = read(fd, buf, bufsize - 1);
    if ((status == 0) || ((status < 0) && (errno == EAGAIN))) {
      usleep(2000);
      status = 0;
    }
  } while ((status == 0) && (--retry != 0));
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L13:
  cmp    %rdx,%rsp
  je     L23
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L13
L23:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L57
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L57:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x1,0x4(%rax)
  movl   $0x2,-0x2c(%rbp)
  jmp    L27
L11:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%ecx
  mov    -0x2c(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x2c(%rbp)
L27:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L11
  mov    -0x20(%rbp),%rax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %rsi,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n) {
  int f[n + 1];
  int i;
  f[0] = 0;
  f[1] = 1;
  for (i = 2; i <= n; i++)
    f[i] = f[i - 1] + f[i - 2];
  return f[n];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x1(%rdi),%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L46:
  cmp    %rdx,%rsp
  je     L43
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L46
L43:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L48
  orq    $0x0,-0x8(%rsp,%rax,1)
L48:
  lea    0x3(%rsp),%rdi
  mov    %rdi,%rax
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%rdi
  movl   $0x0,0x0(,%rax,4)
  movl   $0x1,0x4(,%rax,4)
  cmp    $0x1,%esi
  jle    L1
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    (%rdi,%rdx,4),%rcx
L38:
  mov    (%rax),%edx
  add    0x4(%rax),%edx
  mov    %edx,0x8(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L38
L1:
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  leave
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fib(int n) {
  int f[n + 1];
  int i;
  f[0] = 0;
  f[1] = 1;
  for (i = 2; i <= n; i++)
    f[i] = f[i - 1] + f[i - 2];
  return f[n];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x1(%rdi),%eax
  mov    %rsp,%rcx
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L38
L75:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L75
L38:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L70
L60:
  movabs $0x100000000,%rsi
  lea    0x3(%rsp),%r8
  mov    %r8,%rax
  and    $0xfffffffffffffffc,%r8
  shr    $0x2,%rax
  mov    %rsi,0x0(,%rax,4)
  cmp    $0x1,%edi
  jle    L50
  lea    -0x2(%rdi),%edx
  lea    0x8(%r8),%rax
  xor    %ecx,%ecx
  lea    0x8(%r8,%rdx,4),%rsi
  mov    $0x1,%edx
  jmp    L66
  nop
L77:
  mov    -0x4(%rax),%ecx
  add    $0x4,%rax
L66:
  add    %ecx,%edx
  mov    %edx,(%rax)
  cmp    %rsi,%rax
  jne    L77
L50:
  movslq %edi,%rdi
  mov    (%r8,%rdi,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L60
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fib(int n) {
  int f[n + 1];
  int i;
  f[0] = 0;
  f[1] = 1;
  for (i = 2; i <= n; i++)
    f[i] = f[i - 1] + f[i - 2];
  return f[n];
}
```
user: Translate the below assembly code into C programming language:

```asm
<fib>:
  endbr64
  push   %rbp
  movslq %edi,%rsi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  mov    %rsp,%rcx
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L89
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L4
L89:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L43
L21:
  lea    0x3(%rsp),%rcx
  mov    D4(%rip),%rdx
  mov    %rcx,%rax
  and    $0xfffffffffffffffc,%rcx
  shr    $0x2,%rax
  mov    %rdx,0x0(,%rax,4)
  cmp    $0x1,%esi
  jle    L72
  cmp    $0x3,%esi
  jle    L26
  lea    -0x4(%rsi),%eax
  mov    $0x4,%edx
  mov    $0x1,%r8d
  xor    %edi,%edi
  shr    %eax
  lea    0x3(%rax),%r9d
  add    %r9,%r9
L35:
  add    %r8d,%edi
  movslq %edx,%rax
  add    %edi,%r8d
  movd   %edi,%xmm0
  movd   %r8d,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x8(%rcx,%rdx,4)
  add    $0x2,%rdx
  cmp    %rdx,%r9
  jne    L35
  nopl   0x0(%rax)
L77:
  mov    -0x4(%rcx,%rax,4),%edx
  add    -0x8(%rcx,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L77
L72:
  mov    (%rcx,%rsi,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  leave
  ret
  nop
L43:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L21
L26:
  mov    $0x2,%eax
  jmp    L77
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int fib(int n) {
  int f[n + 1];
  int i;
  f[0] = 0;
  f[1] = 1;
  for (i = 2; i <= n; i++)
    f[i] = f[i - 1] + f[i - 2];
  return f[n];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_arg_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <find_arg@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L25
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L25
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L22
L25:
  mov    -0x30(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
char *find_arg_str(int argc, char *argv[], char *key, char *def) {
  int i = find_arg(argc, argv, key);
  return (i > 0 && i < argc - 1) ? argv[i + 1] : def;
}
```
user: What is the c source code of the assembly code below?

```asm
<find_arg_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rcx,%rbp
  call   <find_arg@plt>
  test   %eax,%eax
  jle    L13
  sub    $0x1,%ebx
  cmp    %eax,%ebx
  jle    L13
  cltq
  mov    0x8(%r12,%rax,8),%rbp
L13:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *find_arg_str(int argc, char *argv[], char *key, char *def) {
  int i = find_arg(argc, argv, key);
  return (i > 0 && i < argc - 1) ? argv[i + 1] : def;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_arg_str>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  call   <find_arg@plt>
  test   %eax,%eax
  jle    L14
  sub    $0x1,%ebx
  cmp    %eax,%ebx
  jle    L14
  add    $0x1,%eax
  cltq
  mov    0x0(%rbp,%rax,8),%r12
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *find_arg_str(int argc, char *argv[], char *key, char *def) {
  int i = find_arg(argc, argv, key);
  return (i > 0 && i < argc - 1) ? argv[i + 1] : def;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_arg_str>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  call   <find_arg@plt>
  test   %eax,%eax
  jle    L10
  sub    $0x1,%ebx
  cmp    %eax,%ebx
  jle    L10
  add    $0x1,%eax
  cltq
  mov    0x0(%rbp,%rax,8),%r12
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *find_arg_str(int argc, char *argv[], char *key, char *def) {
  int i = find_arg(argc, argv, key);
  return (i > 0 && i < argc - 1) ? argv[i + 1] : def;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HMM_LogF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <logf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float HMM_LogF(float Float) {
  float Result = logf(Float);
  return (Result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HMM_LogF>:
  endbr64
  sub    $0x8,%rsp
  call   <logf@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
float HMM_LogF(float Float) {
  float Result = logf(Float);
  return (Result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<HMM_LogF>:
  endbr64
  jmp    1050 <logf@plt>
```

assistant: ```c
float HMM_LogF(float Float) {
  float Result = logf(Float);
  return (Result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HMM_LogF>:
  endbr64
  jmp    1050 <logf@plt>
```

assistant: ```c
float HMM_LogF(float Float) {
  float Result = logf(Float);
  return (Result);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_crunch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L27:
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L5:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L5
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L27
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: string
name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D14: #

tool: D6: 


assistant: ```c
void print_crunch(int n) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j <= i; j++) {
      printf("#");
    }
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_crunch>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    $0x0,%ebp
  lea    D2(%rip),%r12
  lea    D19(%rip),%r14
  test   %edi,%edi
  jg     L32
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L11
L19:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  je     L20
L32:
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jns    L11
  jmp    L19
```

tool_calls: name: read_data
arguments: data_label: D2
type: string
name: read_data
arguments: data_label: D19
type: string

tool: D2: #

tool: D19: 


assistant: ```c
void print_crunch(int n) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j <= i; j++) {
      printf("#");
    }
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_crunch>:
  endbr64
  test   %edi,%edi
  jle    L24
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L26
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,%r13d
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D5: 


tool: D1: #

assistant: ```c
void print_crunch(int n) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j <= i; j++) {
      printf("#");
    }
    printf("\n");
  }
}
```