user: 这段汇编代码用C语言表示是什么样的:

```asm
<lm_printout_std>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L91
  mov    -0x34(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L33
  cmpl   $0x2,0x10(%rbp)
  jne    L153
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
L153:
  cmpl   $0x1,0x10(%rbp)
  jne    L17
  mov    0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
L17:
  cmpl   $0x0,0x10(%rbp)
  jne    L12
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
L12:
  cmpl   $0xffffffff,0x10(%rbp)
  jne    L33
  mov    0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L33:
  mov    -0x34(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L13
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L149
L56:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L149:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L56
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <lm_enorm@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L13:
  mov    -0x34(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L189
  mov    $0xa,%edi
  call   <putchar@plt>
L189:
  mov    -0x34(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L29
  mov    -0x34(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L110
  cmpl   $0xffffffff,0x10(%rbp)
  jne    L110
L29:
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L136
L133:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L136:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L133
  jmp    L110
L91:
  nop
L110:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D63
data_type: string
name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D72
data_type: string
name: read_data
arguments: tag: D61
data_type: string
name: read_data
arguments: tag: D79
data_type: string
name: read_data
arguments: tag: D55
data_type: string
name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D68
data_type: string
name: read_data
arguments: tag: D0
data_type: string

tool: D63: trying step in gradient direction  

tool: D8: determining gradient (iteration %2d)

tool: D72: starting minimization              

tool: D61: terminated after %3d evaluations   

tool: D79:   par: 

tool: D55:  %18.11g

tool: D7:  => norm: %18.11g

tool: D68:   residuals:

tool: D0:     fvec[%2d]=%12g


assistant: ```c
void lm_printout_std(int n_par, const double *par, int m_dat, const void *data, const double *fvec, int printflags, int iflag, int iter, int nfev) {
  if (!printflags)
    return;
  int i;
  if (printflags & 1) {
    if (iflag == 2) {
      printf("trying step in gradient direction  ");
    } else if (iflag == 1) {
      printf("determining gradient (iteration %2d)", iter);
    } else if (iflag == 0) {
      printf("starting minimization              ");
    } else if (iflag == -1) {
      printf("terminated after %3d evaluations   ", nfev);
    }
  }
  if (printflags & 2) {
    printf("  par: ");
    for (i = 0; i < n_par; ++i)
      printf(" %18.11g", par[i]);
    printf(" => norm: %18.11g", lm_enorm(m_dat, fvec));
  }
  if (printflags & 3)
    printf("\n");
  if ((printflags & 8) || ((printflags & 4) && iflag == -1)) {
    printf("  residuals:\n");
    for (i = 0; i < m_dat; ++i)
      printf("    fvec[%2d]=%12g\n", i, fvec[i]);
  }
}
```