user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3d4000(%rsp),%r11
L146:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L146
  sub    $0x7b0,%rsp
  mov    $0x3d4790,%edx
  xor    %esi,%esi
  xor    %ebp,%ebp
  mov    $0x1,%r12d
  mov    $0x2,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x3d47a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  call   <memset@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r11d
  mov    $0x1,%ecx
  mov    $0xffffffff,%edi
  mov    %r11d,%edx
  lea    0x1(%r11),%r10d
  lea    0x2(%r11),%r13d
  mov    %r11d,%r9d
  shr    $0x1f,%edx
  imul   %r11d,%r9d
  add    %r11d,%edx
  sar    %edx
  add    $0x1,%edx
  mov    %edx,%esi
  jmp    L123
  nopl   0x0(%rax)
L135:
  mov    %ebx,%eax
  sub    %edi,%eax
  add    %eax,%edx
  cmp    %ecx,%r9d
  jl     L79
L123:
  movslq %edx,%rax
  movslq %esi,%r8
  imul   $0x3ea,%rax,%rax
  add    %r8,%rax
  mov    %ecx,0x10(%rsp,%rax,4)
  mov    %ecx,%eax
  add    $0x1,%ecx
  cmp    %esi,%edx
  je     L122
  lea    (%rdx,%rsi,1),%r8d
  add    %ebp,%eax
  cmp    %r10d,%r8d
  cmove  %eax,%ebp
  cmp    %esi,%edx
  jge    L36
  cmp    %r13d,%r8d
  je     L82
L128:
  test   $0x1,%dil
  jne    L135
  mov    %r12d,%eax
  sub    %edi,%eax
  add    %eax,%esi
  cmp    %ecx,%r9d
  jge    L123
L79:
  sub    $0x1,%r11d
  cmp    $0x63,%r11d
  ja     L6
  lea    0xfb8(%rsp),%r12
  mov    $0x1,%r14d
  lea    D27(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L41:
  mov    $0x1,%ebx
  nopl   (%rax)
L98:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L98
  mov    $0xa,%edi
  add    $0x1,%r14d
  add    $0xfa8,%r12
  call   <putchar@plt>
  cmp    %r14d,0xc(%rsp)
  jge    L41
L6:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x3d47a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x3d47b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L122:
  add    %eax,%ebp
L82:
  add    $0x1,%edi
  and    $0x3,%edi
  jmp    L128
  nopl   (%rax)
L36:
  jle    L128
  cmp    %r10d,%r8d
  jne    L128
  add    $0x1,%edi
  and    $0x3,%edi
  jmp    L128
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D39
type_guessed: string
name: retrieve_data
arguments: data_tag: D27
type_guessed: string
name: retrieve_data
arguments: data_tag: D20
type_guessed: string

tool: D23: Enter value of n:

tool: D39: %d

tool: D27: %4d 

tool: D20: Sum of all diagonal elements is : %d


assistant: ```c
int main(int argc, char *argv[]) {
  int square[1002][1002] = {{0}};
  int i, j, direction, count, sum, n;
  count = 1;
  direction = -1;
  sum = 0;
  printf("Enter value of n:");
  scanf("%d", &n);
  i = j = (n / 2) + 1;
  do {
    square[i][j] = count;
    count++;
    if (i == j || (i + j) == (n + 1))
      sum += square[i][j];
    if (i == j || (i < j && i + j == (n + 2)) || (i > j && i + j == (n + 1)))
      direction = (direction + 1) % 4;
    if (direction & 1)
      i += (2 - direction);
    else
      j += (1 - direction);
  } while (count <= (n * n));
  if (n <= 100) {
    for (i = 1; i <= n; i++, printf("\n"))
      for (j = 1; j <= n; j++)
        printf("%4d ", square[i][j]);
  }
  printf("Sum of all diagonal elements is : %d\n", sum);
  return 0;
}
```