ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L2
  cmp    $0x2d,%eax
  jg     L55
L52:
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  mov    $0x1,%eax
  lea    D69(%rip),%r13
L48:
  mov    %ebx,%r12d
  add    %eax,%ebx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  mov    0x4(%rsp),%esi
  mov    %r12d,%eax
  cmp    %ebp,%esi
  jge    L48
L19:
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  lea    D71(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
L45:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jns    L52
  jmp    L19
L55:
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  jmp    L45
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D50
type: string
name: read_data
arguments: tag: D69
type: string
name: read_data
arguments: tag: D46
type: string
name: read_data
arguments: tag: D19
type: string
name: read_data
arguments: tag: D71
type: string
name: read_data
arguments: tag: D24
type: string

tool: D5: How many times do I have to do the Fibonacci?

tool: D50: %d

tool: D69: 
%d

tool: D46: 
 Fibonaccis ran %d times,

tool: D19:  the last number of the sequence was %d 


tool: D71: You can`t set 0 or a negative number, please write a new number: 

tool: D24: For now Fibonaccis doesn`t support more than 45 times, please write a new number: 

assistant: ```c
int main() {
  int prec1 = 1;
  int prec2 = 0;
  int r, i, howmanyt = 0;
  printf("How many times do I have to do the Fibonacci?\n");
  scanf("%d", &howmanyt);
  if (howmanyt < 1) {
    printf("You can`t set 0 or a negative number, please write a new number: ");
    scanf("%d", &howmanyt);
  } else if (howmanyt > 45) {
    printf("For now Fibonaccis doesn`t support more than 45 times, please write a new number: ");
    scanf("%d", &howmanyt);
  }
  for (i = 0; i <= howmanyt; i++) {
    r = prec1 + prec2;
    printf("\n"
           "%d",
           r);
    prec1 = prec2;
    prec2 = r;
  }
  printf("\n Fibonaccis ran %d times,", howmanyt);
  printf(" the last number of the sequence was %d \n", r);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D35(%rip),%rdi
  push   %r12
  lea    D48(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D60(%rip),%rdi
  test   %eax,%eax
  jle    L13
  cmp    $0x2d,%eax
  jg     L42
L34:
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    D33(%rip),%r13
  mov    $0x1,%eax
  nopl   (%rax)
L5:
  mov    %ebp,%r12d
  add    %eax,%ebp
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r12d,%eax
  cmp    %ebx,%esi
  jge    L5
L39:
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  lea    D40(%rip),%rdi
L13:
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jns    L34
  jmp    L39
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D35
type: string
name: extract_symbolic_data
arguments: data_label: D48
type: string
name: extract_symbolic_data
arguments: data_label: D60
type: string
name: extract_symbolic_data
arguments: data_label: D33
type: string
name: extract_symbolic_data
arguments: data_label: D55
type: string
name: extract_symbolic_data
arguments: data_label: D57
type: string
name: extract_symbolic_data
arguments: data_label: D40
type: string

tool: D35: How many times do I have to do the Fibonacci?

tool: D48: %d

tool: D60: You can`t set 0 or a negative number, please write a new number: 

tool: D33: 
%d

tool: D55: 
 Fibonaccis ran %d times,

tool: D57:  the last number of the sequence was %d 


tool: D40: For now Fibonaccis doesn`t support more than 45 times, please write a new number: 

assistant: ```c
int main() {
  int prec1 = 1;
  int prec2 = 0;
  int r, i, howmanyt = 0;
  printf("How many times do I have to do the Fibonacci?\n");
  scanf("%d", &howmanyt);
  if (howmanyt < 1) {
    printf("You can`t set 0 or a negative number, please write a new number: ");
    scanf("%d", &howmanyt);
  } else if (howmanyt > 45) {
    printf("For now Fibonaccis doesn`t support more than 45 times, please write a new number: ");
    scanf("%d", &howmanyt);
  }
  for (i = 0; i <= howmanyt; i++) {
    r = prec1 + prec2;
    printf("\n"
           "%d",
           r);
    prec1 = prec2;
    prec2 = r;
  }
  printf("\n Fibonaccis ran %d times,", howmanyt);
  printf(" the last number of the sequence was %d \n", r);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D60(%rip),%rdi
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D61(%rip),%rdi
  test   %eax,%eax
  jle    L27
  cmp    $0x2d,%eax
  jg     L16
L39:
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    D41(%rip),%r13
  mov    $0x1,%eax
  nopl   (%rax)
L10:
  mov    %ebp,%r12d
  add    %eax,%ebp
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r12d,%eax
  cmp    %ebx,%esi
  jge    L10
L24:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  lea    D67(%rip),%rdi
L27:
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jns    L39
  jmp    L24
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D60
data_type: string
name: disassemble_data
arguments: tag: D21
data_type: string
name: disassemble_data
arguments: tag: D61
data_type: string
name: disassemble_data
arguments: tag: D41
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string
name: disassemble_data
arguments: tag: D67
data_type: string

tool: D60: How many times do I have to do the Fibonacci?

tool: D21: %d

tool: D61: You can`t set 0 or a negative number, please write a new number: 

tool: D41: 
%d

tool: D6: 
 Fibonaccis ran %d times,

tool: D28:  the last number of the sequence was %d 


tool: D67: For now Fibonaccis doesn`t support more than 45 times, please write a new number: 

assistant: ```c
int main() {
  int prec1 = 1;
  int prec2 = 0;
  int r, i, howmanyt = 0;
  printf("How many times do I have to do the Fibonacci?\n");
  scanf("%d", &howmanyt);
  if (howmanyt < 1) {
    printf("You can`t set 0 or a negative number, please write a new number: ");
    scanf("%d", &howmanyt);
  } else if (howmanyt > 45) {
    printf("For now Fibonaccis doesn`t support more than 45 times, please write a new number: ");
    scanf("%d", &howmanyt);
  }
  for (i = 0; i <= howmanyt; i++) {
    r = prec1 + prec2;
    printf("\n"
           "%d",
           r);
    prec1 = prec2;
    prec2 = r;
  }
  printf("\n Fibonaccis ran %d times,", howmanyt);
  printf(" the last number of the sequence was %d \n", r);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L62
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L61
L62:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L63
L32:
  mov    $0x2a,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L63:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L32
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L30
L28:
  mov    $0x2a,%edi
  call   <putchar@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L2
L34:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L34
  mov    $0x2a,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L28
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L54:
  mov    $0x2a,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L54
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
L61:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: error usage: %s width height


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("error usage: %s width height\n", argv[0]);
    return (0);
  }
  int width = atoi(argv[1]);
  int height = atoi(argv[2]);
  int x, y;
  for (x = 0; x < width; x++) {
    printf("*");
  }
  printf("\n");
  for (y = 1; y < height - 1; y++) {
    printf("*");
    for (x = 1; x < width - 1; x++) {
      printf(" ");
    }
    printf("*");
    printf("\n");
  }
  for (x = 0; x < width; x++) {
    printf("*");
  }
  printf("\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  je     L38
  mov    (%rsi),%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L43:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r14d
  test   %r12d,%r12d
  jle    L57
  mov    $0x0,%ebx
L89:
  mov    $0x2a,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L89
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r14d
  cmp    $0x1,%r14d
  jle    L22
L76:
  mov    $0x1,%r13d
  lea    -0x1(%r12),%ebp
L42:
  mov    $0x2a,%edi
  call   <putchar@plt>
  cmp    $0x2,%r12d
  jle    L83
  mov    $0x1,%ebx
L0:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L0
L83:
  mov    $0x2a,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  cmp    %r14d,%r13d
  jl     L42
  test   %r12d,%r12d
  jle    L6
L22:
  mov    $0x0,%ebx
L94:
  mov    $0x2a,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jg     L94
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L43
L57:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r14d
  cmp    $0x1,%r14d
  jg     L76
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D3: error usage: %s width height


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("error usage: %s width height\n", argv[0]);
    return (0);
  }
  int width = atoi(argv[1]);
  int height = atoi(argv[2]);
  int x, y;
  for (x = 0; x < width; x++) {
    printf("*");
  }
  printf("\n");
  for (y = 1; y < height - 1; y++) {
    printf("*");
    for (x = 1; x < width - 1; x++) {
      printf(" ");
    }
    printf("*");
    printf("\n");
  }
  for (x = 0; x < width; x++) {
    printf("*");
  }
  printf("\n");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  je     L41
  mov    (%rsi),%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L58:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%r13d
  call   <atoi@plt>
  mov    %eax,%r14d
  test   %r13d,%r13d
  jle    L38
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L76:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jne    L76
  mov    $0xa,%edi
  sub    $0x1,%r14d
  call   <putchar@plt>
  cmp    $0x1,%r14d
  jle    L56
L64:
  lea    -0x1(%r13),%ebp
  mov    $0x1,%r12d
  nopl   0x0(%rax,%rax,1)
L85:
  mov    $0x2a,%edi
  mov    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x1,%ebp
  jle    L46
  nopl   0x0(%rax)
L16:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L16
L46:
  mov    $0x2a,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r14d,%r12d
  jl     L85
  test   %r13d,%r13d
  jle    L117
L56:
  xor    %ebx,%ebx
  nopl   (%rax)
L70:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jg     L70
L117:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L58
L38:
  mov    $0xa,%edi
  sub    $0x1,%r14d
  call   <putchar@plt>
  cmp    $0x1,%r14d
  jg     L64
  jmp    L117
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: error usage: %s width height


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("error usage: %s width height\n", argv[0]);
    return (0);
  }
  int width = atoi(argv[1]);
  int height = atoi(argv[2]);
  int x, y;
  for (x = 0; x < width; x++) {
    printf("*");
  }
  printf("\n");
  for (y = 1; y < height - 1; y++) {
    printf("*");
    for (x = 1; x < width - 1; x++) {
      printf(" ");
    }
    printf("*");
    printf("\n");
  }
  for (x = 0; x < width; x++) {
    printf("*");
  }
  printf("\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  je     L26
  mov    (%rsi),%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%r13d
  call   <atoi@plt>
  mov    %eax,%r14d
  test   %r13d,%r13d
  jle    L25
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L56:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jne    L56
  mov    $0xa,%edi
  sub    $0x1,%r14d
  call   <putchar@plt>
  cmp    $0x1,%r14d
  jle    L17
L72:
  lea    -0x1(%r13),%ebp
  mov    $0x1,%r12d
  nopl   0x0(%rax,%rax,1)
L80:
  mov    $0x2a,%edi
  call   <putchar@plt>
  cmp    $0x1,%ebp
  jle    L111
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L48:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L48
L111:
  mov    $0x2a,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r14d,%r12d
  jl     L80
  test   %r13d,%r13d
  jle    L51
L17:
  xor    %ebx,%ebx
  nopl   (%rax)
L9:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jg     L9
L51:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L12
L25:
  mov    $0xa,%edi
  sub    $0x1,%r14d
  call   <putchar@plt>
  cmp    $0x1,%r14d
  jg     L72
  jmp    L51
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D8: error usage: %s width height


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("error usage: %s width height\n", argv[0]);
    return (0);
  }
  int width = atoi(argv[1]);
  int height = atoi(argv[2]);
  int x, y;
  for (x = 0; x < width; x++) {
    printf("*");
  }
  printf("\n");
  for (y = 1; y < height - 1; y++) {
    printf("*");
    for (x = 1; x < width - 1; x++) {
      printf(" ");
    }
    printf("*");
    printf("\n");
  }
  for (x = 0; x < width; x++) {
    printf("*");
  }
  printf("\n");
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<clamp24_from_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  D19(%rip),%xmm0
  comiss -0x4(%rbp),%xmm0
  jb     L33
  mov    $0xff800000,%eax
  jmp    L26
L33:
  movss  D15(%rip),%xmm1
  movss  -0x4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jb     L5
  mov    $0x7fffff,%eax
  jmp    L26
L5:
  movss  D22(%rip),%xmm0
  movss  -0x4(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jbe    L58
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L26
L58:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
L26:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
type_infered: byte[4]
name: disassemble_data
arguments: label: D15
type_infered: byte[4]
name: disassemble_data
arguments: label: D22
type_infered: byte[4]
name: disassemble_data
arguments: label: D9
type_infered: f64

tool: {"D19": [0x00,0x00,0x80,0xbf]}

tool: {"D15": [0xfe,0xff,0x7f,0x3f]}

tool: {"D22": [0x00,0x00,0x00,0x4b]}

tool: D9: 0.5

assistant: ```c
int32_t clamp24_from_float(float f) {
  static const float scale = (float)(1 << 23);
  static const float limpos = 0x7fffff / (float)(1 << 23);
  static const float limneg = -0x800000 / (float)(1 << 23);
  if (f <= limneg) {
    return -0x800000;
  } else if (f >= limpos) {
    return 0x7fffff;
  }
  f *= scale;
  return f > 0 ? f + 0.5 : f - 0.5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clamp24_from_float>:
  endbr64
  movss  D0(%rip),%xmm1
  comiss %xmm0,%xmm1
  jae    L4
  mov    $0x7fffff,%eax
  comiss D22(%rip),%xmm0
  jae    L18
  mulss  D17(%rip),%xmm0
  comiss D37(%rip),%xmm0
  jbe    L6
  cvtss2sd %xmm0,%xmm0
  addsd  D37(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
L6:
  cvtss2sd %xmm0,%xmm0
  subsd  D37(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
L4:
  mov    $0xff800000,%eax
L18:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D22
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D17
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D37
type_infered: f64

tool: {"D0": [0x00,0x00,0x80,0xbf]}

tool: {"D22": [0xfe,0xff,0x7f,0x3f]}

tool: {"D17": [0x00,0x00,0x00,0x4b]}

tool: D37: 0.5

assistant: ```c
int32_t clamp24_from_float(float f) {
  static const float scale = (float)(1 << 23);
  static const float limpos = 0x7fffff / (float)(1 << 23);
  static const float limneg = -0x800000 / (float)(1 << 23);
  if (f <= limneg) {
    return -0x800000;
  } else if (f >= limpos) {
    return 0x7fffff;
  }
  f *= scale;
  return f > 0 ? f + 0.5 : f - 0.5;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clamp24_from_float>:
  endbr64
  movss  D6(%rip),%xmm1
  comiss %xmm0,%xmm1
  jae    L4
  comiss D29(%rip),%xmm0
  mov    $0x7fffff,%eax
  jae    L22
  mulss  D30(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comiss D51(%rip),%xmm0
  cvtss2sd %xmm0,%xmm1
  jbe    L14
  addsd  D51(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  ret
L4:
  mov    $0xff800000,%eax
L22:
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  subsd  D51(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: byte[4]
name: disassemble_data
arguments: data_label: D29
type_infered: byte[4]
name: disassemble_data
arguments: data_label: D30
type_infered: byte[4]
name: disassemble_data
arguments: data_label: D51
type_infered: f64

tool: {"D6": [0x00,0x00,0x80,0xbf]}

tool: {"D29": [0xfe,0xff,0x7f,0x3f]}

tool: {"D30": [0x00,0x00,0x00,0x4b]}

tool: D51: 0.5

assistant: ```c
int32_t clamp24_from_float(float f) {
  static const float scale = (float)(1 << 23);
  static const float limpos = 0x7fffff / (float)(1 << 23);
  static const float limneg = -0x800000 / (float)(1 << 23);
  if (f <= limneg) {
    return -0x800000;
  } else if (f >= limpos) {
    return 0x7fffff;
  }
  f *= scale;
  return f > 0 ? f + 0.5 : f - 0.5;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clamp24_from_float>:
  endbr64
  movss  D11(%rip),%xmm1
  comiss %xmm0,%xmm1
  jae    L6
  comiss D20(%rip),%xmm0
  mov    $0x7fffff,%eax
  jae    L1
  mulss  D3(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comiss D17(%rip),%xmm0
  cvtss2sd %xmm0,%xmm1
  jbe    L29
  addsd  D17(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  ret
L6:
  mov    $0xff800000,%eax
L1:
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  subsd  D17(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type: byte[4]
name: retrieve_data
arguments: data_label: D20
type: byte[4]
name: retrieve_data
arguments: data_label: D3
type: byte[4]
name: retrieve_data
arguments: data_label: D17
type: f64

tool: {"D11": [0x00,0x00,0x80,0xbf]}

tool: {"D20": [0xfe,0xff,0x7f,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0x4b]}

tool: D17: 0.5

assistant: ```c
int32_t clamp24_from_float(float f) {
  static const float scale = (float)(1 << 23);
  static const float limpos = 0x7fffff / (float)(1 << 23);
  static const float limneg = -0x800000 / (float)(1 << 23);
  if (f <= limneg) {
    return -0x800000;
  } else if (f >= limpos) {
    return 0x7fffff;
  }
  f *= scale;
  return f > 0 ? f + 0.5 : f - 0.5;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<realloc_util>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L14
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fatal_util@plt>
  jmp    L25
L14:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <fatal_util@plt>
L25:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string
name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D8: Call to realloc_util with a null pointer

tool: D7: realloc_util: out of memory

assistant: ```c
void *realloc_util(void *ptr, size_t bytes) {
  void *ret = NULL;
  if (ptr == NULL)
    fatal_util("Call to realloc_util with a null pointer");
  else {
    if ((ret = realloc(ptr, bytes)) == NULL)
      fatal_util("realloc_util: out of memory");
  }
  return ret;
}
```