ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<decodeAddr>:
  endbr64
  push   %r12
  lea    D27(%rip),%r12
  lea    D24(%rip),%rsi
  mov    %r12,%rdx
  call   <str_replace@plt>
  mov    %r12,%rdx
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  call   <str_replace@plt>
  pop    %r12
  mov    %rax,%rdi
  jmp    1070 <decodeReg@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
datatype: string
name: extract_symbolic_data
arguments: data_label: D24
datatype: string
name: extract_symbolic_data
arguments: data_label: D25
datatype: string

tool: 

tool: D24: [

tool: D25: ]

assistant: ```c
char *decodeAddr(char *token) {
  char *decoded = NULL;
  char *partial, *last;
  partial = str_replace(token, "[", "");
  last = str_replace(partial, "]", "");
  decoded = decodeReg(last);
  return decoded;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: Raj and Kumar: we are present here!


assistant: ```c
main(void) {
  printf("Raj"
         " and "
         "Kumar"
         ": we are present here!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8: Raj and Kumar: we are present here!


assistant: ```c
main(void) {
  printf("Raj"
         " and "
         "Kumar"
         ": we are present here!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: Raj and Kumar: we are present here!


assistant: ```c
main(void) {
  printf("Raj"
         " and "
         "Kumar"
         ": we are present here!\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: Raj and Kumar: we are present here!


assistant: ```c
main(void) {
  printf("Raj"
         " and "
         "Kumar"
         ": we are present here!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L8
L26:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L8:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L26
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
type: string
name: disassemble_data
arguments: label: D5
type: string
name: disassemble_data
arguments: label: D24
type: string
name: disassemble_data
arguments: label: D6
type: string

tool: D11: 
Enter an integer > 

tool: D5: %d

tool: D24: 
%d

tool: D6: 
That's all, have a nice day!

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  while (n > 0) {
    r = n % 10;
    nn = n / 10;
    n = nn;
    printf("\n%d", r);
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L15
  lea    D32(%rip),%rbx
L7:
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jg     L7
L15:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string
name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D32
datatype: string
name: retrieve_data
arguments: tag: D38
datatype: string

tool: D8: 
Enter an integer > 

tool: D22: %d

tool: D32: 
%d

tool: D38: 
That's all, have a nice day!

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  while (n > 0) {
    r = n % 10;
    nn = n / 10;
    n = nn;
    printf("\n%d", r);
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L14
  lea    D32(%rip),%rbp
  mov    $0xcccccccd,%ebx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %esi,%eax
  mov    %rbp,%rdi
  imul   %rbx,%rax
  shr    $0x23,%rax
  mov    %eax,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jg     L16
L14:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D35
type_guessed: string
name: read_data
arguments: tag: D32
type_guessed: string
name: read_data
arguments: tag: D17
type_guessed: string

tool: D8: 
Enter an integer > 

tool: D35: %d

tool: D32: 
%d

tool: D17: 
That's all, have a nice day!

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  while (n > 0) {
    r = n % 10;
    nn = n / 10;
    n = nn;
    printf("\n%d", r);
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L11
  lea    D7(%rip),%rbp
  mov    $0xcccccccd,%ebx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %esi,%eax
  mov    %rbp,%rdi
  imul   %rbx,%rax
  shr    $0x23,%rax
  mov    %eax,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jg     L9
L11:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D11
type_infered: string

tool: D15: 
Enter an integer > 

tool: D14: %d

tool: D7: 
%d

tool: D11: 
That's all, have a nice day!

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  while (n > 0) {
    r = n % 10;
    nn = n / 10;
    n = nn;
    printf("\n%d", r);
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<treeReOrderMaxHeap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L19
L67:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L64
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L64:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L3
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L3
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L51
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swapNum@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jg     L67
  jmp    L59
L51:
  nop
L59:
  leave
  ret
```

assistant: ```c
void treeReOrderMaxHeap(int *a, int begin, int end) {
  int start = begin, swapChild, lChild;
  while (start * 2 + 1 < end) {
    lChild = start * 2 + 1;
    swapChild = start;
    if (a[swapChild] < a[lChild]) {
      swapChild = lChild;
    }
    if (lChild + 1 < end && a[swapChild] < a[lChild + 1]) {
      swapChild = lChild + 1;
    }
    if (swapChild != start) {
      swapNum(a + start, a + swapChild);
      start = swapChild;
    } else
      return;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<treeReOrderMaxHeap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %edx,%r12d
  lea    0x1(%rsi,%rsi,1),%eax
  cmp    %eax,%edx
  jg     L42
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  movslq %eax,%rdx
  mov    0x4(%rbp,%rcx,1),%ecx
  cmp    %ecx,0x0(%rbp,%rdx,4)
  cmovge %eax,%ebx
  jmp    L77
L24:
  lea    0x2(%rsi,%rsi,1),%ebx
  cmp    %ebx,%r12d
  jle    L57
  movslq %esi,%rax
  mov    0x4(%rbp,%rcx,1),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jge    L57
L77:
  cmp    %esi,%ebx
  je     L57
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  call   <swapNum@plt>
  lea    0x1(%rbx,%rbx,1),%eax
  cmp    %r12d,%eax
  jge    L57
  mov    %ebx,%esi
L42:
  movslq %esi,%rdx
  lea    0x0(%rbp,%rdx,4),%rdi
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    0x0(%rbp,%rdx,4),%edx
  cmp    %edx,(%rdi)
  jge    L24
  lea    0x2(%rsi,%rsi,1),%ebx
  cmp    %r12d,%ebx
  jl     L46
  mov    %eax,%ebx
  jmp    L77
```

assistant: ```c
void treeReOrderMaxHeap(int *a, int begin, int end) {
  int start = begin, swapChild, lChild;
  while (start * 2 + 1 < end) {
    lChild = start * 2 + 1;
    swapChild = start;
    if (a[swapChild] < a[lChild]) {
      swapChild = lChild;
    }
    if (lChild + 1 < end && a[swapChild] < a[lChild + 1]) {
      swapChild = lChild + 1;
    }
    if (swapChild != start) {
      swapNum(a + start, a + swapChild);
      start = swapChild;
    } else
      return;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<treeReOrderMaxHeap>:
  endbr64
  lea    0x1(%rsi,%rsi,1),%eax
  cmp    %eax,%edx
  jle    L0
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L33:
  cmp    %ebx,%r12d
  jg     L58
  mov    %eax,%ebx
L55:
  cmp    %esi,%ebx
  je     L70
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  call   <swapNum@plt>
  lea    0x1(%rbx,%rbx,1),%eax
  cmp    %r12d,%eax
  jge    L70
  mov    %ebx,%esi
L8:
  movslq %esi,%rdx
  lea    0x2(%rsi,%rsi,1),%ebx
  lea    0x0(%rbp,%rdx,4),%rdi
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%r8
  mov    (%rdi),%ecx
  mov    0x0(%rbp,%rdx,4),%edx
  cmp    %edx,%ecx
  jl     L33
  cmp    %ebx,%r12d
  jle    L70
  cmp    0x4(%rbp,%r8,1),%ecx
  jl     L55
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L58:
  cmp    0x4(%rbp,%r8,1),%edx
  cmovge %eax,%ebx
  jmp    L55
L0:
  ret
```

assistant: ```c
void treeReOrderMaxHeap(int *a, int begin, int end) {
  int start = begin, swapChild, lChild;
  while (start * 2 + 1 < end) {
    lChild = start * 2 + 1;
    swapChild = start;
    if (a[swapChild] < a[lChild]) {
      swapChild = lChild;
    }
    if (lChild + 1 < end && a[swapChild] < a[lChild + 1]) {
      swapChild = lChild + 1;
    }
    if (swapChild != start) {
      swapNum(a + start, a + swapChild);
      start = swapChild;
    } else
      return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<treeReOrderMaxHeap>:
  endbr64
  lea    0x1(%rsi,%rsi,1),%eax
  cmp    %eax,%edx
  jle    L26
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L81:
  cmp    %ebx,%r12d
  jg     L36
  mov    %eax,%ebx
L10:
  cmp    %esi,%ebx
  je     L86
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  call   <swapNum@plt>
  lea    0x1(%rbx,%rbx,1),%eax
  cmp    %r12d,%eax
  jge    L86
  mov    %ebx,%esi
L39:
  movslq %esi,%rdx
  lea    0x2(%rsi,%rsi,1),%ebx
  lea    0x0(%rbp,%rdx,4),%rdi
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%r8
  mov    (%rdi),%ecx
  mov    0x0(%rbp,%rdx,4),%edx
  cmp    %edx,%ecx
  jl     L81
  cmp    %ebx,%r12d
  jle    L86
  cmp    0x4(%rbp,%r8,1),%ecx
  jl     L10
L86:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L36:
  cmp    0x4(%rbp,%r8,1),%edx
  cmovge %eax,%ebx
  jmp    L10
L26:
  ret
```

assistant: ```c
void treeReOrderMaxHeap(int *a, int begin, int end) {
  int start = begin, swapChild, lChild;
  while (start * 2 + 1 < end) {
    lChild = start * 2 + 1;
    swapChild = start;
    if (a[swapChild] < a[lChild]) {
      swapChild = lChild;
    }
    if (lChild + 1 < end && a[swapChild] < a[lChild + 1]) {
      swapChild = lChild + 1;
    }
    if (swapChild != start) {
      swapNum(a + start, a + swapChild);
      start = swapChild;
    } else
      return;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dictSdsDestructor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sdsfree@plt>
  nop
  leave
  ret
```

assistant: ```c
void dictSdsDestructor(void *privdata, void *val) {
  ((void)privdata);
  sdsfree(val);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dictSdsDestructor>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <sdsfree@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dictSdsDestructor(void *privdata, void *val) {
  ((void)privdata);
  sdsfree(val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dictSdsDestructor>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <sdsfree@plt>
```

assistant: ```c
void dictSdsDestructor(void *privdata, void *val) {
  ((void)privdata);
  sdsfree(val);
}
```
user: What is the c source code of the assembly code below:

```asm
<dictSdsDestructor>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <sdsfree@plt>
```

assistant: ```c
void dictSdsDestructor(void *privdata, void *val) {
  ((void)privdata);
  sdsfree(val);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<be32enc_vect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L8
L12:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <_sha256_be32enc@plt>
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x28(%rbp),%rax
  shr    $0x2,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void be32enc_vect(unsigned char *dst, const uint32_t *src, size_t len) {
  size_t i;
  for (i = 0; i < len / 4; i++) {
    _sha256_be32enc(dst + i * 4, src[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<be32enc_vect>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  shr    $0x2,%r13
  cmp    $0x3,%rdx
  jbe    L11
  mov    %rsi,%r12
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L5:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  call   <_sha256_be32enc@plt>
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %r13,%rbx
  jb     L5
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void be32enc_vect(unsigned char *dst, const uint32_t *src, size_t len) {
  size_t i;
  for (i = 0; i < len / 4; i++) {
    _sha256_be32enc(dst + i * 4, src[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<be32enc_vect>:
  endbr64
  shr    $0x2,%rdx
  je     L7
  push   %r12
  lea    (%rsi,%rdx,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  add    $0x4,%rbp
  call   <_sha256_be32enc@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
void be32enc_vect(unsigned char *dst, const uint32_t *src, size_t len) {
  size_t i;
  for (i = 0; i < len / 4; i++) {
    _sha256_be32enc(dst + i * 4, src[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<be32enc_vect>:
  endbr64
  shr    $0x2,%rdx
  je     L0
  push   %r12
  lea    (%rsi,%rdx,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  add    $0x4,%rbp
  call   <_sha256_be32enc@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  ret
```

assistant: ```c
void be32enc_vect(unsigned char *dst, const uint32_t *src, size_t len) {
  size_t i;
  for (i = 0; i < len / 4; i++) {
    _sha256_be32enc(dst + i * 4, src[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getnumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  lea    -0x3f4(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x3f4(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int getnumber() {
  int num;
  char s[1000];
  getline(s, 1000);
  atoi(s, &num);
  return num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getnumber>:
  endbr64
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    0xc(%rsp),%eax
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x400,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getnumber() {
  int num;
  char s[1000];
  getline(s, 1000);
  atoi(s, &num);
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getnumber>:
  endbr64
  push   %rbp
  mov    $0x3e8,%esi
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <getline@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    0xc(%rsp),%eax
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x400,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getnumber() {
  int num;
  char s[1000];
  getline(s, 1000);
  atoi(s, &num);
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getnumber>:
  endbr64
  push   %rbp
  mov    $0x3e8,%esi
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <getline@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    0xc(%rsp),%eax
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x400,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getnumber() {
  int num;
  char s[1000];
  getline(s, 1000);
  atoi(s, &num);
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<primeKeyGeneration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <gmp_randinit_default@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gmp_randseed_ui@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L13:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <mpz_set_ui@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x400,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_urandomb@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <millerRabin@plt>
  mov    %eax,-0x8(%rbp)
L1:
  cmpl   $0x0,-0x8(%rbp)
  je     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void primeKeyGeneration(mpz_t p) {
  gmp_randstate_t state;
  gmp_randinit_default(state);
  gmp_randseed_ui(state, time(NULL));
  int isPrime = 0;
  while (isPrime == 0) {
    mpz_set_ui(p, 0);
    mpz_urandomb(p, state, 1024);
    isPrime = millerRabin(p);
  }
}
```