ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dienice>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D14
type_infered: string
name: parse_data
arguments: tag: D16
type_infered: string

tool: D5: <html>
<head>
<title>fatal error</title>
</head>
<body>


tool: D14: FATAL ERROR: couldn't extract running PID!


tool: D16: </body>
</html>


assistant: ```c
void dienice() {
  printf("<html>\n<head>\n<title>fatal error</title>\n</head>\n<body>\n");
  printf("FATAL ERROR: couldn't extract running PID!\n");
  printf("</body>\n</html>\n");
  exit(-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L4
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L7
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L7:
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L0
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int partition(char **A, int s, int t) {
  int i = s - 1;
  char *x = A[t - 1];
  for (int j = s; j < t - 1; j++) {
    if (strcmp(A[j], x) < 0) {
      swap(&A[++i], &A[j]);
    }
  }
  swap(&A[++i], &A[t - 1]);
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<partition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  lea    -0x1(%rsi),%ebp
  movslq %edx,%rax
  lea    -0x8(%rdi,%rax,8),%r15
  mov    (%r15),%r12
  lea    -0x1(%rdx),%eax
  cmp    %eax,%esi
  jge    L17
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%rbx
  sub    $0x2,%edx
  sub    %esi,%edx
  add    %rax,%rdx
  lea    0x8(%rdi,%rdx,8),%r13
  jmp    L13
L28:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L17
L13:
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L28
  add    $0x1,%ebp
  movslq %ebp,%rax
  lea    (%r14,%rax,8),%rdi
  mov    %rbx,%rsi
  call   <swap@plt>
  jmp    L28
L17:
  add    $0x1,%ebp
  movslq %ebp,%rax
  lea    (%r14,%rax,8),%rdi
  mov    %r15,%rsi
  call   <swap@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int partition(char **A, int s, int t) {
  int i = s - 1;
  char *x = A[t - 1];
  for (int j = s; j < t - 1; j++) {
    if (strcmp(A[j], x) < 0) {
      swap(&A[++i], &A[j]);
    }
  }
  swap(&A[++i], &A[t - 1]);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<partition>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  lea    -0x8(%rdi,%rax,8),%r15
  lea    -0x1(%rdx),%eax
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%r15),%rbp
  cmp    %eax,%esi
  jge    L6
  sub    $0x2,%edx
  movslq %esi,%rax
  lea    -0x1(%rsi),%r14d
  sub    %esi,%edx
  lea    (%rdi,%rax,8),%rbx
  add    %rax,%rdx
  lea    0x8(%rdi,%rdx,8),%r12
  jmp    L9
  nopl   (%rax)
L59:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  je     L8
L9:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L59
  add    $0x1,%r14d
  mov    %rbx,%rsi
  add    $0x8,%rbx
  movslq %r14d,%rax
  lea    0x0(%r13,%rax,8),%rdi
  call   <swap@plt>
  cmp    %rbx,%r12
  jne    L9
L8:
  add    $0x1,%r14d
L45:
  movslq %r14d,%rax
  mov    %r15,%rsi
  lea    0x0(%r13,%rax,8),%rdi
  call   <swap@plt>
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L6:
  mov    %esi,%r14d
  jmp    L45
```

assistant: ```c
int partition(char **A, int s, int t) {
  int i = s - 1;
  char *x = A[t - 1];
  for (int j = s; j < t - 1; j++) {
    if (strcmp(A[j], x) < 0) {
      swap(&A[++i], &A[j]);
    }
  }
  swap(&A[++i], &A[t - 1]);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<partition>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  lea    -0x8(%rdi,%rax,8),%r15
  lea    -0x1(%rdx),%eax
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%r15),%rbp
  cmp    %eax,%esi
  jge    L7
  sub    $0x2,%edx
  movslq %esi,%rax
  lea    -0x1(%rsi),%r14d
  sub    %esi,%edx
  lea    (%rdi,%rax,8),%rbx
  add    %rax,%rdx
  lea    0x8(%rdi,%rdx,8),%r12
  jmp    L19
  nopl   (%rax)
L40:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  je     L27
L19:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L40
  add    $0x1,%r14d
  mov    %rbx,%rsi
  add    $0x8,%rbx
  movslq %r14d,%rax
  lea    0x0(%r13,%rax,8),%rdi
  call   <swap@plt>
  cmp    %rbx,%r12
  jne    L19
L27:
  add    $0x1,%r14d
L20:
  movslq %r14d,%rax
  mov    %r15,%rsi
  lea    0x0(%r13,%rax,8),%rdi
  call   <swap@plt>
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L7:
  mov    %esi,%r14d
  jmp    L20
```

assistant: ```c
int partition(char **A, int s, int t) {
  int i = s - 1;
  char *x = A[t - 1];
  for (int j = s; j < t - 1; j++) {
    if (strcmp(A[j], x) < 0) {
      swap(&A[++i], &A[j]);
    }
  }
  swap(&A[++i], &A[t - 1]);
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_aic_default_irq_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L6:
  jmp    L6
```

assistant: ```c
void _aic_default_irq_handler(void) {
  while (1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_aic_default_irq_handler>:
  endbr64
L3:
  jmp    L3
```

assistant: ```c
void _aic_default_irq_handler(void) {
  while (1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_aic_default_irq_handler>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
void _aic_default_irq_handler(void) {
  while (1)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_aic_default_irq_handler>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
void _aic_default_irq_handler(void) {
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_nextKey_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%edx
  lea    -0x12(%rbp),%rax
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  js     L13
  cmpl   $0x0,-0x28(%rbp)
  jns    L75
L13:
  mov    $0x0,%eax
  jmp    L36
L75:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x28(%rbp),%edx
  add    %edx,%eax
  add    $0x2,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L36
L2:
  lea    -0x12(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L61
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L36
L61:
  mov    -0x20(%rbp),%rax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D14
datatype: string

tool: D16: %d

tool: D14: %s-%s

assistant: ```c
char *make_nextKey_str(char *key, int nextId) {
  int idlen;
  char id_str[10];
  char *nextKey;
  int r;
  idlen = sprintf(id_str, "%d", nextId);
  if (nextId < 0 || idlen < 0)
    return NULL;
  r = strlen(key) + idlen + 1 + 1;
  nextKey = (char *)malloc(r * sizeof(char) + 2);
  if (nextKey == NULL)
    return NULL;
  r = sprintf(nextKey, "%s-%s", key, id_str);
  if (r < 0) {
    free(nextKey);
    return NULL;
  }
  return nextKey;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<make_nextKey_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  mov    %esi,%edx
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x0,%r13d
  or     %eax,%ebx
  js     L36
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x4(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L36
  mov    %rax,%r13
  lea    0xe(%rsp),%rcx
  mov    %r12,%rdx
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  test   %eax,%eax
  js     L5
L36:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %r13,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%r13d
  jmp    L36
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string

tool: D4: %d

tool: D1: %s-%s

assistant: ```c
char *make_nextKey_str(char *key, int nextId) {
  int idlen;
  char id_str[10];
  char *nextKey;
  int r;
  idlen = sprintf(id_str, "%d", nextId);
  if (nextId < 0 || idlen < 0)
    return NULL;
  r = strlen(key) + idlen + 1 + 1;
  nextKey = (char *)malloc(r * sizeof(char) + 2);
  if (nextKey == NULL)
    return NULL;
  r = sprintf(nextKey, "%s-%s", key, id_str);
  if (r < 0) {
    free(nextKey);
    return NULL;
  }
  return nextKey;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<make_nextKey_str>:
  endbr64
  push   %r14
  mov    %esi,%edx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  lea    D11(%rip),%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  or     %eax,%ebx
  js     L20
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x4(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L20
  mov    %rax,%rdi
  mov    %r14,%rcx
  xor    %eax,%eax
  mov    %r13,%rdx
  lea    D17(%rip),%rsi
  call   <sprintf@plt>
  test   %eax,%eax
  jns    L24
  mov    %r12,%rdi
  call   <free@plt>
  xchg   %ax,%ax
L20:
  xor    %r12d,%r12d
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: string

tool: D11: %d

tool: D17: %s-%s

assistant: ```c
char *make_nextKey_str(char *key, int nextId) {
  int idlen;
  char id_str[10];
  char *nextKey;
  int r;
  idlen = sprintf(id_str, "%d", nextId);
  if (nextId < 0 || idlen < 0)
    return NULL;
  r = strlen(key) + idlen + 1 + 1;
  nextKey = (char *)malloc(r * sizeof(char) + 2);
  if (nextKey == NULL)
    return NULL;
  r = sprintf(nextKey, "%s-%s", key, id_str);
  if (r < 0) {
    free(nextKey);
    return NULL;
  }
  return nextKey;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_nextKey_str>:
  endbr64
  push   %r14
  mov    %esi,%edx
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  lea    D1(%rip),%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  or     %eax,%ebx
  js     L25
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x4(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L25
  mov    %rax,%rdi
  mov    %r14,%rcx
  xor    %eax,%eax
  mov    %r13,%rdx
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
  test   %eax,%eax
  jns    L23
  mov    %r12,%rdi
  call   <free@plt>
  xchg   %ax,%ax
L25:
  xor    %r12d,%r12d
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D4
type_guessed: string

tool: D1: %d

tool: D4: %s-%s

assistant: ```c
char *make_nextKey_str(char *key, int nextId) {
  int idlen;
  char id_str[10];
  char *nextKey;
  int r;
  idlen = sprintf(id_str, "%d", nextId);
  if (nextId < 0 || idlen < 0)
    return NULL;
  r = strlen(key) + idlen + 1 + 1;
  nextKey = (char *)malloc(r * sizeof(char) + 2);
  if (nextKey == NULL)
    return NULL;
  r = sprintf(nextKey, "%s-%s", key, id_str);
  if (r < 0) {
    free(nextKey);
    return NULL;
  }
  return nextKey;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_128_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_128_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & S;
  stk1 = D & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_128_1_1>:
  endbr64
  or     %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_128_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & S;
  stk1 = D & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xrop3_128_1_1>:
  endbr64
  or     %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_128_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & S;
  stk1 = D & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xrop3_128_1_1>:
  endbr64
  or     %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_128_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & S;
  stk1 = D & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_svector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %ax,-0x2c(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzwl -0x2c(%rbp),%eax
  mov    %ax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_svector(short *v, long nl, long nh, short cte) {
  int i;
  for (i = nl; i <= nh; i++)
    v[i] = cte;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_svector>:
  endbr64
  movslq %esi,%rax
  cmp    %rax,%rdx
  jl     L0
  lea    (%rdi,%rax,2),%rax
  lea    0x2(%rdi,%rdx,2),%rdx
L4:
  mov    %cx,(%rax)
  add    $0x2,%rax
  cmp    %rdx,%rax
  jne    L4
L0:
  ret
```

assistant: ```c
void set_svector(short *v, long nl, long nh, short cte) {
  int i;
  for (i = nl; i <= nh; i++)
    v[i] = cte;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_svector>:
  endbr64
  movslq %esi,%rsi
  cmp    %rsi,%rdx
  jl     L12
  lea    (%rdi,%rsi,2),%rax
  lea    0x2(%rdi,%rdx,2),%rdx
  nopl   (%rax)
L15:
  mov    %cx,(%rax)
  add    $0x2,%rax
  cmp    %rdx,%rax
  jne    L15
L12:
  ret
```

assistant: ```c
void set_svector(short *v, long nl, long nh, short cte) {
  int i;
  for (i = nl; i <= nh; i++)
    v[i] = cte;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_svector>:
  endbr64
  mov    %rsi,%r9
  mov    %ecx,%esi
  mov    %rdx,%r8
  movslq %r9d,%rcx
  mov    %r9d,%eax
  cmp    %rcx,%rdx
  jl     L19
  mov    %rdx,%r10
  sub    %rcx,%r10
  lea    0x1(%r10),%r11
  cmp    $0x6,%r10
  jbe    L49
  mov    %r11,%rdx
  movd   %esi,%xmm0
  lea    (%rdi,%rcx,2),%rax
  shr    $0x3,%rdx
  punpcklwd %xmm0,%xmm0
  shl    $0x4,%rdx
  pshufd $0x0,%xmm0,%xmm0
  add    %rax,%rdx
  xchg   %ax,%ax
L36:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L36
  mov    %r11,%rdx
  and    $0xfffffffffffffff8,%rdx
  lea    (%r9,%rdx,1),%eax
  cmp    %rdx,%r11
  je     L2
L53:
  sub    %rdx,%r10
  lea    0x1(%r10),%r9
  cmp    $0x2,%r10
  jbe    L87
  add    %rdx,%rcx
  movd   %esi,%xmm2
  mov    %r9,%rdx
  pshuflw $0x0,%xmm2,%xmm1
  and    $0xfffffffffffffffc,%rdx
  movq   %xmm1,(%rdi,%rcx,2)
  add    %edx,%eax
  cmp    %rdx,%r9
  je     L19
L87:
  movslq %eax,%rdx
  mov    %si,(%rdi,%rdx,2)
  lea    (%rdx,%rdx,1),%rcx
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    %rdx,%r8
  jl     L19
  add    $0x2,%eax
  mov    %si,0x2(%rdi,%rcx,1)
  cltq
  cmp    %rax,%r8
  jl     L19
  mov    %si,0x4(%rdi,%rcx,1)
L19:
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
L49:
  xor    %edx,%edx
  jmp    L53
```

assistant: ```c
void set_svector(short *v, long nl, long nh, short cte) {
  int i;
  for (i = nl; i <= nh; i++)
    v[i] = cte;
}
```
user: What is the c source code of the assembly code below:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L8
L2:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L8:
  cmpl   $0x0,-0x18(%rbp)
  jne    L2
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int64_t gcd(int64_t x, int64_t y) {
  int64_t t;
  while (y != 0) {
    t = x % y;
    x = y;
    y = t;
  }
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L14
L9:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L9
L1:
  mov    %ecx,%eax
  ret
L14:
  mov    %edi,%ecx
  jmp    L1
```

assistant: ```c
int64_t gcd(int64_t x, int64_t y) {
  int64_t t;
  while (y != 0) {
    t = x % y;
    x = y;
    y = t;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L5
  nopl   0x0(%rax)
L15:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L15
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int64_t gcd(int64_t x, int64_t y) {
  int64_t t;
  while (y != 0) {
    t = x % y;
    x = y;
    y = t;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L2
  nopl   0x0(%rax)
L17:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L17
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int64_t gcd(int64_t x, int64_t y) {
  int64_t t;
  while (y != 0) {
    t = x % y;
    x = y;
    y = t;
  }
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<__argz_stringify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L25
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  cmp    $0x1,%rax
  jbe    L27
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L1
L27:
  nop
L25:
  nop
  leave
  ret
```

assistant: ```c
void __argz_stringify(char *argz, size_t len, int sep) {
  if (len > 0)
    while (1) {
      size_t part_len = strnlen(argz, len);
      argz += part_len;
      len -= part_len;
      if (len-- <= 1)
        break;
      *argz++ = sep;
    }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__argz_stringify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  test   %rsi,%rsi
  jne    L2
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  lea    0x1(%rcx),%rbp
  mov    %r12b,(%rcx)
L2:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strnlen@plt>
  lea    0x0(%rbp,%rax,1),%rcx
  sub    %rax,%rbx
  mov    %rbx,%rdx
  lea    -0x1(%rbx),%rbx
  cmp    $0x1,%rdx
  ja     L22
  jmp    L21
```

assistant: ```c
void __argz_stringify(char *argz, size_t len, int sep) {
  if (len > 0)
    while (1) {
      size_t part_len = strnlen(argz, len);
      argz += part_len;
      len -= part_len;
      if (len-- <= 1)
        break;
      *argz++ = sep;
    }
}
```