ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  movsd  0x8(%rsp),%xmm0
  call   <modf@plt>
  movq   %xmm0,%r14
  mov    0x10(%rsp),%rbx
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  lea    D48(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  D49(%rip),%xmm0
  movq   %r14,%xmm2
  comisd %xmm2,%xmm0
  ja     L13
  movq   %rbx,%xmm3
  addsd  D41(%rip),%xmm3
  movq   %xmm3,%rbx
L13:
  movq   %rbx,%xmm0
  lea    D38(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string
name: retrieve_data
arguments: label: D48
type: string
name: retrieve_data
arguments: label: D49
type: f64
name: retrieve_data
arguments: label: D41
type: byte[8]
name: retrieve_data
arguments: label: D38
type: string

tool: D2: %lf

tool: D48: %.0lf
%.4lf


tool: D49: 0.5

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D38: %.0lf

assistant: ```c
int main(void) {
  double num, frac, ni, arred;
  scanf("%lf", &num);
  frac = modf(num, &ni);
  printf("%.0lf\n%.4lf\n", ni, frac);
  if (frac < 0.5) {
    arred = ni;
  } else {
    arred = ni + 1;
  }
  printf("%.0lf", arred);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x18(%rsp),%xmm0
  lea    0x20(%rsp),%rdi
  call   <modf@plt>
  lea    D34(%rip),%rdi
  mov    $0x2,%eax
  movapd %xmm0,%xmm1
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  movsd  D32(%rip),%xmm2
  comisd %xmm1,%xmm2
  ja     L19
  addsd  D43(%rip),%xmm0
L19:
  lea    D27(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string
name: extract_symbolic_data
arguments: data_label: D34
data_type: string
name: extract_symbolic_data
arguments: data_label: D32
data_type: f64
name: extract_symbolic_data
arguments: data_label: D43
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D27
data_type: string

tool: D0: %lf

tool: D34: %.0lf
%.4lf


tool: D32: 0.5

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D27: %.0lf

assistant: ```c
int main(void) {
  double num, frac, ni, arred;
  scanf("%lf", &num);
  frac = modf(num, &ni);
  printf("%.0lf\n%.4lf\n", ni, frac);
  if (frac < 0.5) {
    arred = ni;
  } else {
    arred = ni + 1;
  }
  printf("%.0lf", arred);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x18(%rsp),%xmm0
  lea    0x20(%rsp),%rdi
  call   <modf@plt>
  lea    D2(%rip),%rdi
  mov    $0x2,%eax
  movapd %xmm0,%xmm1
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  movsd  D14(%rip),%xmm2
  comisd %xmm1,%xmm2
  ja     L1
  addsd  D4(%rip),%xmm0
L1:
  lea    D31(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D30
type: string
name: extract_symbolic_data
arguments: data_tag: D2
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: f64
name: extract_symbolic_data
arguments: data_tag: D4
type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D31
type: string

tool: D30: %lf

tool: D2: %.0lf
%.4lf


tool: D14: 0.5

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D31: %.0lf

assistant: ```c
int main(void) {
  double num, frac, ni, arred;
  scanf("%lf", &num);
  frac = modf(num, &ni);
  printf("%.0lf\n%.4lf\n", ni, frac);
  if (frac < 0.5) {
    arred = ni;
  } else {
    arred = ni + 1;
  }
  printf("%.0lf", arred);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xd,-0x14(%rbp)
  movl   $0x2f,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  movl   $0x57,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D26
type_infered: string
name: parse_data
arguments: label: D17
type_infered: string

tool: D26: %p 


tool: D17: %d 


assistant: ```c
int main(void) {
  int j = 13, k = 47, *p = &k;
  printf("%p \n", &p);
  printf("%p \n", p);
  printf("%p \n", &k);
  printf("%d \n", *p);
  printf("%d \n", k);
  *p = 87;
  printf("%d \n", *p);
  printf("%d \n", k);
  printf("%d \n", **&p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2f,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  mov    %rbp,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  movl   $0x57,(%rax)
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
data_type: string
name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D14: %p 


tool: D6: %d 


assistant: ```c
int main(void) {
  int j = 13, k = 47, *p = &k;
  printf("%p \n", &p);
  printf("%p \n", p);
  printf("%p \n", &k);
  printf("%d \n", *p);
  printf("%d \n", k);
  *p = 87;
  printf("%d \n", *p);
  printf("%d \n", k);
  printf("%d \n", **&p);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rsi
  movl   $0x2f,0xc(%rsp)
  mov    %r12,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    $0x57,%esi
  mov    %rbp,%rdi
  movl   $0x57,(%rax)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D7
type: string

tool: D12: %p 


tool: D7: %d 


assistant: ```c
int main(void) {
  int j = 13, k = 47, *p = &k;
  printf("%p \n", &p);
  printf("%p \n", p);
  printf("%p \n", &k);
  printf("%d \n", *p);
  printf("%d \n", k);
  *p = 87;
  printf("%d \n", *p);
  printf("%d \n", k);
  printf("%d \n", **&p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rsi
  movl   $0x2f,0xc(%rsp)
  mov    %r12,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    $0x57,%esi
  mov    %rbp,%rdi
  movl   $0x57,(%rax)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D4
type: string

tool: D16: %p 


tool: D4: %d 


assistant: ```c
int main(void) {
  int j = 13, k = 47, *p = &k;
  printf("%p \n", &p);
  printf("%p \n", p);
  printf("%p \n", &k);
  printf("%d \n", *p);
  printf("%d \n", k);
  *p = 87;
  printf("%d \n", *p);
  printf("%d \n", k);
  printf("%d \n", **&p);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strconcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L3
L22:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L3:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  jmp    L37
L0:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L37:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strconcat(char *strA, char *strB) {
  char *result = (char *)malloc((strlen(strA) + strlen(strB) + 1) * sizeof(char));
  int posA = 0, posB = 0;
  while (strA[posA])
    result[posA++] = strA[posA];
  while (strB[posB])
    result[posA++] = strB[posB++];
  result[posA] = '\0';
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strconcat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L33
  mov    $0x1,%edx
L16:
  mov    %edx,%esi
  mov    %cl,-0x1(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl -0x1(%rbp,%rdx,1),%ecx
  test   %cl,%cl
  jne    L16
L5:
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L34
  lea    0x1(%rsi),%edx
  movslq %edx,%rdx
  movslq %esi,%rsi
  sub    %rsi,%rbx
L7:
  mov    %edx,%esi
  mov    %cl,-0x1(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl -0x1(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L7
L34:
  movslq %esi,%rsi
  movb   $0x0,(%rax,%rsi,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    $0x0,%esi
  jmp    L5
```

assistant: ```c
char *strconcat(char *strA, char *strB) {
  char *result = (char *)malloc((strlen(strA) + strlen(strB) + 1) * sizeof(char));
  int posA = 0, posB = 0;
  while (strA[posA])
    result[posA++] = strA[posA];
  while (strB[posB])
    result[posA++] = strB[posB++];
  result[posA] = '\0';
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strconcat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L27
  mov    $0x1,%edx
  nopl   0x0(%rax)
L38:
  mov    %cl,-0x1(%rax,%rdx,1)
  mov    %edx,%edi
  mov    %rdx,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L38
  add    %rax,%rsi
L47:
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L12
  lea    0x1(%rdi),%edx
  movslq %edi,%rsi
  mov    %rbp,%rdi
  movslq %edx,%rdx
  sub    %rsi,%rdi
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %cl,-0x1(%rax,%rdx,1)
  movslq %edx,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L3
  add    %rax,%rsi
L12:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L27:
  mov    %rax,%rsi
  xor    %edi,%edi
  jmp    L47
```

assistant: ```c
char *strconcat(char *strA, char *strB) {
  char *result = (char *)malloc((strlen(strA) + strlen(strB) + 1) * sizeof(char));
  int posA = 0, posB = 0;
  while (strA[posA])
    result[posA++] = strA[posA];
  while (strB[posB])
    result[posA++] = strB[posB++];
  result[posA] = '\0';
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strconcat>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L10
  mov    $0x1,%edx
  nopl   0x0(%rax)
L23:
  mov    %cl,-0x1(%rax,%rdx,1)
  mov    %edx,%edi
  mov    %rdx,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L23
  add    %rax,%rsi
L49:
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L22
  lea    0x1(%rdi),%edx
  movslq %edi,%rsi
  mov    %rbp,%rdi
  movslq %edx,%rdx
  sub    %rsi,%rdi
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %cl,-0x1(%rax,%rdx,1)
  movslq %edx,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L36
  add    %rax,%rsi
L22:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L10:
  mov    %rax,%rsi
  xor    %edi,%edi
  jmp    L49
```

assistant: ```c
char *strconcat(char *strA, char *strB) {
  char *result = (char *)malloc((strlen(strA) + strlen(strB) + 1) * sizeof(char));
  int posA = 0, posB = 0;
  while (strA[posA])
    result[posA++] = strA[posA];
  while (strB[posB])
    result[posA++] = strB[posB++];
  result[posA] = '\0';
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kpageflags_flags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <expand_overloaded_flags@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <well_known_flags@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t kpageflags_flags(uint64_t flags) {
  flags = expand_overloaded_flags(flags);
  flags = well_known_flags(flags);
  return flags;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kpageflags_flags>:
  endbr64
  sub    $0x8,%rsp
  call   <expand_overloaded_flags@plt>
  mov    %eax,%edi
  call   <well_known_flags@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint64_t kpageflags_flags(uint64_t flags) {
  flags = expand_overloaded_flags(flags);
  flags = well_known_flags(flags);
  return flags;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<kpageflags_flags>:
  endbr64
  sub    $0x8,%rsp
  call   <expand_overloaded_flags@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <well_known_flags@plt>
```

assistant: ```c
uint64_t kpageflags_flags(uint64_t flags) {
  flags = expand_overloaded_flags(flags);
  flags = well_known_flags(flags);
  return flags;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kpageflags_flags>:
  endbr64
  sub    $0x8,%rsp
  call   <expand_overloaded_flags@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <well_known_flags@plt>
```

assistant: ```c
uint64_t kpageflags_flags(uint64_t flags) {
  flags = expand_overloaded_flags(flags);
  flags = well_known_flags(flags);
  return flags;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<polevl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %esi,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L1:
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double polevl(double x, const double coef[], int N) {
  double ans;
  int i;
  const double *p;
  p = coef;
  ans = *p++;
  i = N;
  do
    ans = ans * x + *p++;
  while (--i);
  return (ans);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<polevl>:
  endbr64
  movapd %xmm0,%xmm1
  lea    0x8(%rdi),%rax
  movsd  (%rdi),%xmm0
  lea    -0x1(%rsi),%edx
  lea    0x10(%rdi,%rdx,8),%rdx
L9:
  mulsd  %xmm1,%xmm0
  add    $0x8,%rax
  addsd  -0x8(%rax),%xmm0
  cmp    %rdx,%rax
  jne    L9
  ret
```

assistant: ```c
double polevl(double x, const double coef[], int N) {
  double ans;
  int i;
  const double *p;
  p = coef;
  ans = *p++;
  i = N;
  do
    ans = ans * x + *p++;
  while (--i);
  return (ans);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<polevl>:
  endbr64
  movapd %xmm0,%xmm1
  lea    -0x1(%rsi),%edx
  movsd  (%rdi),%xmm0
  lea    0x8(%rdi),%rax
  lea    0x10(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L6:
  mulsd  %xmm1,%xmm0
  add    $0x8,%rax
  addsd  -0x8(%rax),%xmm0
  cmp    %rdx,%rax
  jne    L6
  ret
```

assistant: ```c
double polevl(double x, const double coef[], int N) {
  double ans;
  int i;
  const double *p;
  p = coef;
  ans = *p++;
  i = N;
  do
    ans = ans * x + *p++;
  while (--i);
  return (ans);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<polevl>:
  endbr64
  movapd %xmm0,%xmm1
  lea    -0x1(%rsi),%edx
  movsd  (%rdi),%xmm0
  lea    0x8(%rdi),%rax
  lea    0x10(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L7:
  mulsd  %xmm1,%xmm0
  add    $0x8,%rax
  addsd  -0x8(%rax),%xmm0
  cmp    %rax,%rdx
  jne    L7
  ret
```

assistant: ```c
double polevl(double x, const double coef[], int N) {
  double ans;
  int i;
  const double *p;
  p = coef;
  ans = *p++;
  i = N;
  do
    ans = ans * x + *p++;
  while (--i);
  return (ans);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<updateRssItems>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x14,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <isNumericOk@plt>
  test   %rax,%rax
  je     L15
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <setConfigTextValue@plt>
  mov    $0x1,%eax
  jmp    L9
L15:
  mov    $0x0,%eax
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: web.rss.items

assistant: ```c
int updateRssItems(char *value) {
  if (isNumericOk(value, 1, 20)) {
    setConfigTextValue("web.rss.items", value);
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<updateRssItems>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x14,%edx
  mov    $0x1,%esi
  call   <isNumericOk@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L2
L10:
  pop    %rbx
  ret
L2:
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  call   <setConfigTextValue@plt>
  mov    $0x1,%eax
  jmp    L10
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: web.rss.items

assistant: ```c
int updateRssItems(char *value) {
  if (isNumericOk(value, 1, 20)) {
    setConfigTextValue("web.rss.items", value);
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<updateRssItems>:
  endbr64
  push   %rbp
  mov    $0x14,%edx
  mov    $0x1,%esi
  mov    %rdi,%rbp
  call   <isNumericOk@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L6
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <setConfigTextValue@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: web.rss.items

assistant: ```c
int updateRssItems(char *value) {
  if (isNumericOk(value, 1, 20)) {
    setConfigTextValue("web.rss.items", value);
    return 1;
  } else {
    return 0;
  }
}
```