ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pthread_mutex_lock>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <lksmith_prelock@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L7
  mov    %rbp,%rdi
  call   <r_pthread_mutex_lock@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <lksmith_postlock@plt>
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int pthread_mutex_lock(pthread_mutex_t *mutex) {
  int ret = lksmith_prelock(mutex, 1);
  if (ret)
    return ret;
  ret = r_pthread_mutex_lock(mutex);
  lksmith_postlock(mutex, ret);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ISandBox_wcstombs_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L40:
  cmp    %rdx,%rsp
  je     L49
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L40
L49:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L9
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L9:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x38(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L30
L54:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  lea    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <wcrtomb@plt>
  mov    %eax,-0x2c(%rbp)
  addl   $0x1,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  add    %eax,-0x30(%rbp)
L30:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L54
  mov    -0x30(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int ISandBox_wcstombs_len(const wchar_t *src) {
  int src_idx, dest_idx;
  int status;
  char dummy[MB_LEN_MAX];
  mbstate_t ps;
  memset(&ps, 0, sizeof(mbstate_t));
  for (src_idx = dest_idx = 0; src[src_idx] != L'\0';) {
    status = wcrtomb(dummy, src[src_idx], &ps);
    src_idx++;
    dest_idx += status;
  }
  return dest_idx;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ISandBox_wcstombs_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L18:
  cmp    %rdx,%rsp
  je     L10
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L18
L10:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L38
  orq    $0x0,-0x8(%rsp,%rax,1)
L38:
  mov    %rsp,%r14
  lea    -0x2c(%rbp),%rdi
  mov    $0x4,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L62
  add    $0x4,%rbx
  mov    $0x0,%r12d
  lea    -0x2c(%rbp),%r13
L9:
  mov    %r13,%rdx
  mov    %r14,%rdi
  call   <wcrtomb@plt>
  add    %eax,%r12d
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  test   %esi,%esi
  jne    L9
L7:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %r12d,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L62:
  mov    %esi,%r12d
  jmp    L7
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ISandBox_wcstombs_len(const wchar_t *src) {
  int src_idx, dest_idx;
  int status;
  char dummy[MB_LEN_MAX];
  mbstate_t ps;
  memset(&ps, 0, sizeof(mbstate_t));
  for (src_idx = dest_idx = 0; src[src_idx] != L'\0';) {
    status = wcrtomb(dummy, src[src_idx], &ps);
    src_idx++;
    dest_idx += status;
  }
  return dest_idx;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ISandBox_wcstombs_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D8(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L37
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L68
L37:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L30
L72:
  lea    -0x2c(%rbp),%r12
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %rsp,%r13
  mov    %r12,%rdi
  call   <memset@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L28
  add    $0x4,%rbx
  xor    %r14d,%r14d
  nop
L77:
  mov    %r12,%rdx
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <wcrtomb@plt>
  mov    -0x4(%rbx),%esi
  add    %eax,%r14d
  test   %esi,%esi
  jne    L77
L66:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  lea    -0x20(%rbp),%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L72
L28:
  xor    %r14d,%r14d
  jmp    L66
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ISandBox_wcstombs_len(const wchar_t *src) {
  int src_idx, dest_idx;
  int status;
  char dummy[MB_LEN_MAX];
  mbstate_t ps;
  memset(&ps, 0, sizeof(mbstate_t));
  for (src_idx = dest_idx = 0; src[src_idx] != L'\0';) {
    status = wcrtomb(dummy, src[src_idx], &ps);
    src_idx++;
    dest_idx += status;
  }
  return dest_idx;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ISandBox_wcstombs_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D3(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L47
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L4
L47:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L14
L54:
  lea    -0x2c(%rbp),%r12
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %rsp,%r13
  mov    %r12,%rdi
  call   <memset@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L61
  add    $0x4,%rbx
  xor    %r14d,%r14d
  nop
L76:
  mov    %r12,%rdx
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <wcrtomb@plt>
  mov    -0x4(%rbx),%esi
  add    %eax,%r14d
  test   %esi,%esi
  jne    L76
L0:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  lea    -0x20(%rbp),%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L54
L61:
  xor    %r14d,%r14d
  jmp    L0
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ISandBox_wcstombs_len(const wchar_t *src) {
  int src_idx, dest_idx;
  int status;
  char dummy[MB_LEN_MAX];
  mbstate_t ps;
  memset(&ps, 0, sizeof(mbstate_t));
  for (src_idx = dest_idx = 0; src[src_idx] != L'\0';) {
    status = wcrtomb(dummy, src[src_idx], &ps);
    src_idx++;
    dest_idx += status;
  }
  return dest_idx;
}
```
user: What is the c source code of the assembly code below?

```asm
<zip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L43
L6:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L45
  addl   $0x1,-0x8(%rbp)
  jmp    L48
L45:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x4f,%al
  jne    L48
  addl   $0x2,-0x8(%rbp)
L48:
  addl   $0x1,-0x4(%rbp)
L43:
  cmpl   $0x9,-0x4(%rbp)
  jne    L6
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int zip(char env[]) {
  int state = 0;
  for (int z = 0; z != 9; z++) {
    state *= 3;
    if (env[z] == 'X')
      state += 1;
    else if (env[z] == 'O')
      state += 2;
  }
  return state;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zip>:
  endbr64
  lea    0x9(%rdi),%rsi
  mov    $0x0,%eax
  jmp    L22
L30:
  lea    0x1(%rdx),%eax
L10:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L34
L22:
  lea    (%rax,%rax,2),%edx
  mov    %edx,%eax
  movzbl (%rdi),%ecx
  cmp    $0x58,%cl
  je     L30
  add    $0x2,%edx
  cmp    $0x4f,%cl
  cmove  %edx,%eax
  jmp    L10
L34:
  ret
```

assistant: ```c
int zip(char env[]) {
  int state = 0;
  for (int z = 0; z != 9; z++) {
    state *= 3;
    if (env[z] == 'X')
      state += 1;
    else if (env[z] == 'O')
      state += 2;
  }
  return state;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zip>:
  endbr64
  lea    0x9(%rdi),%rsi
  xor    %eax,%eax
  jmp    L35
  nopl   0x0(%rax)
L7:
  cmp    $0x4f,%dl
  lea    0x2(%rax),%ecx
  cmove  %ecx,%eax
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L26
L35:
  movzbl (%rdi),%edx
  lea    (%rax,%rax,2),%eax
  cmp    $0x58,%dl
  jne    L7
  add    $0x1,%rdi
  add    $0x1,%eax
  cmp    %rsi,%rdi
  jne    L35
L26:
  ret
```

assistant: ```c
int zip(char env[]) {
  int state = 0;
  for (int z = 0; z != 9; z++) {
    state *= 3;
    if (env[z] == 'X')
      state += 1;
    else if (env[z] == 'O')
      state += 2;
  }
  return state;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zip>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rdx
  mov    $0x1,%eax
  cmp    $0x58,%cl
  je     L54
  xor    %eax,%eax
  cmp    $0x4f,%cl
  sete   %al
  add    %eax,%eax
L54:
  movzbl 0x1(%rdx),%esi
  lea    (%rax,%rax,2),%ecx
  lea    0x1(%rcx),%eax
  cmp    $0x58,%sil
  je     L78
  lea    0x2(%rcx),%eax
  cmp    $0x4f,%sil
  cmovne %ecx,%eax
L78:
  movzbl 0x2(%rdx),%esi
  lea    (%rax,%rax,2),%ecx
  lea    0x1(%rcx),%eax
  cmp    $0x58,%sil
  je     L1
  lea    0x2(%rcx),%eax
  cmp    $0x4f,%sil
  cmovne %ecx,%eax
L1:
  movzbl 0x3(%rdx),%esi
  lea    (%rax,%rax,2),%ecx
  lea    0x1(%rcx),%eax
  cmp    $0x58,%sil
  je     L22
  lea    0x2(%rcx),%eax
  cmp    $0x4f,%sil
  cmovne %ecx,%eax
L22:
  movzbl 0x4(%rdx),%esi
  lea    (%rax,%rax,2),%ecx
  lea    0x1(%rcx),%eax
  cmp    $0x58,%sil
  je     L56
  lea    0x2(%rcx),%eax
  cmp    $0x4f,%sil
  cmovne %ecx,%eax
L56:
  movzbl 0x5(%rdx),%esi
  lea    (%rax,%rax,2),%ecx
  lea    0x1(%rcx),%eax
  cmp    $0x58,%sil
  je     L51
  lea    0x2(%rcx),%eax
  cmp    $0x4f,%sil
  cmovne %ecx,%eax
L51:
  movzbl 0x6(%rdx),%esi
  lea    (%rax,%rax,2),%ecx
  lea    0x1(%rcx),%eax
  cmp    $0x58,%sil
  je     L64
  lea    0x2(%rcx),%eax
  cmp    $0x4f,%sil
  cmovne %ecx,%eax
L64:
  movzbl 0x7(%rdx),%esi
  lea    (%rax,%rax,2),%ecx
  lea    0x1(%rcx),%eax
  cmp    $0x58,%sil
  je     L21
  lea    0x2(%rcx),%eax
  cmp    $0x4f,%sil
  cmovne %ecx,%eax
L21:
  movzbl 0x8(%rdx),%edx
  lea    (%rax,%rax,2),%eax
  cmp    $0x58,%dl
  je     L9
  lea    0x2(%rax),%ecx
  cmp    $0x4f,%dl
  cmove  %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%eax
  ret
```

assistant: ```c
int zip(char env[]) {
  int state = 0;
  for (int z = 0; z != 9; z++) {
    state *= 3;
    if (env[z] == 'X')
      state += 1;
    else if (env[z] == 'O')
      state += 2;
  }
  return state;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<backupRawTextFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <getPositionRawTextFile@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <setPositionRawTextFile@plt>
  nop
  leave
  ret
```

assistant: ```c
void backupRawTextFile(Selection, Offset) int Selection;
int Offset;
{
  auto int Position;
  Position = getPositionRawTextFile(Selection);
  setPositionRawTextFile(Selection, Position - Offset);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<backupRawTextFile>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <getPositionRawTextFile@plt>
  sub    %ebp,%eax
  mov    %eax,%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <setPositionRawTextFile@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void backupRawTextFile(Selection, Offset) int Selection;
int Offset;
{
  auto int Position;
  Position = getPositionRawTextFile(Selection);
  setPositionRawTextFile(Selection, Position - Offset);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<backupRawTextFile>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <getPositionRawTextFile@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    1060 <setPositionRawTextFile@plt>
```

assistant: ```c
void backupRawTextFile(Selection, Offset) int Selection;
int Offset;
{
  auto int Position;
  Position = getPositionRawTextFile(Selection);
  setPositionRawTextFile(Selection, Position - Offset);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<backupRawTextFile>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <getPositionRawTextFile@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    1060 <setPositionRawTextFile@plt>
```

assistant: ```c
void backupRawTextFile(Selection, Offset) int Selection;
int Offset;
{
  auto int Position;
  Position = getPositionRawTextFile(Selection);
  setPositionRawTextFile(Selection, Position - Offset);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nondet_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int nondet_uint() {
  unsigned int ui;
  return ui;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nondet_uint>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int nondet_uint() {
  unsigned int ui;
  return ui;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nondet_uint>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int nondet_uint() {
  unsigned int ui;
  return ui;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nondet_uint>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int nondet_uint() {
  unsigned int ui;
  return ui;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D125(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x9,%eax
  ja     L85
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D20(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D20(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D108(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D111(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
L85:
  nop
L67:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D125
type: string
name: unpack_data
arguments: tag: D53
type: string
name: unpack_data
arguments: tag: D48
type: string
name: unpack_data
arguments: tag: D35
type: string
name: unpack_data
arguments: tag: D36
type: string
name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D58
type: string
name: unpack_data
arguments: tag: D98
type: string
name: unpack_data
arguments: tag: D108
type: string
name: unpack_data
arguments: tag: D111
type: string
name: unpack_data
arguments: tag: D37
type: string

tool: D125: %d

tool: D53: zero


tool: D48: one


tool: D35: two


tool: D36: three


tool: D24: four


tool: D58: five


tool: D98: six


tool: D108: seven


tool: D111: eight


tool: D37: nine


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  switch (n) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  default:
    break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D60(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L80
  mov    0x4(%rsp),%eax
  lea    D53(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D86(%rip),%rdi
  call   <printf@plt>
L80:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D94(%rip),%rdi
  call   <printf@plt>
  jmp    L80
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L80
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L80
  lea    D72(%rip),%rdi
  call   <printf@plt>
  jmp    L80
  lea    D101(%rip),%rdi
  call   <printf@plt>
  jmp    L80
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L80
  lea    D97(%rip),%rdi
  call   <printf@plt>
  jmp    L80
  lea    D75(%rip),%rdi
  call   <printf@plt>
  jmp    L80
  lea    D108(%rip),%rdi
  call   <printf@plt>
  jmp    L80
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D60
data_type: string
name: extract_symbolic_data
arguments: data_label: D86
data_type: string
name: extract_symbolic_data
arguments: data_label: D94
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D38
data_type: string
name: extract_symbolic_data
arguments: data_label: D72
data_type: string
name: extract_symbolic_data
arguments: data_label: D101
data_type: string
name: extract_symbolic_data
arguments: data_label: D50
data_type: string
name: extract_symbolic_data
arguments: data_label: D97
data_type: string
name: extract_symbolic_data
arguments: data_label: D75
data_type: string
name: extract_symbolic_data
arguments: data_label: D108
data_type: string

tool: D60: %d

tool: D86: zero


tool: D94: one


tool: D8: two


tool: D38: three


tool: D72: four


tool: D101: five


tool: D50: six


tool: D97: seven


tool: D75: eight


tool: D108: nine


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  switch (n) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  default:
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D74(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  ja     L68
  mov    0x4(%rsp),%eax
  lea    D119(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D52(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L68:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L68
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L68
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L68
  lea    D68(%rip),%rdi
  call   <printf@plt>
  jmp    L68
  lea    D61(%rip),%rdi
  call   <printf@plt>
  jmp    L68
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L68
  lea    D110(%rip),%rdi
  call   <printf@plt>
  jmp    L68
  lea    D113(%rip),%rdi
  call   <printf@plt>
  jmp    L68
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L68
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D74
datatype: string
name: unpack_data
arguments: data_label: D52
datatype: string
name: unpack_data
arguments: data_label: D50
datatype: string
name: unpack_data
arguments: data_label: D41
datatype: string
name: unpack_data
arguments: data_label: D53
datatype: string
name: unpack_data
arguments: data_label: D68
datatype: string
name: unpack_data
arguments: data_label: D61
datatype: string
name: unpack_data
arguments: data_label: D38
datatype: string
name: unpack_data
arguments: data_label: D110
datatype: string
name: unpack_data
arguments: data_label: D113
datatype: string
name: unpack_data
arguments: data_label: D3
datatype: string

tool: D74: %d

tool: D52: zero


tool: D50: eight


tool: D41: nine


tool: D53: one


tool: D68: two


tool: D61: three


tool: D38: four


tool: D110: five


tool: D113: six


tool: D3: seven


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  switch (n) {
  case 0:
    printf("zero\n");
    break;
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  case 3:
    printf("three\n");
    break;
  case 4:
    printf("four\n");
    break;
  case 5:
    printf("five\n");
    break;
  case 6:
    printf("six\n");
    break;
  case 7:
    printf("seven\n");
    break;
  case 8:
    printf("eight\n");
    break;
  case 9:
    printf("nine\n");
    break;
  default:
    break;
  }
  return 0;
}
```