ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dump>:
  endbr64
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L7
  lea    -0x1(%rbp),%eax
  lea    D1(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   (%rax)
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
L7:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string

tool: D17: 

tool: D1: %d 

assistant: ```c
void dump(int a[], int size) {
  int i = 0;
  printf("\r\n");
  for (i = 0; i < size; i++) {
    printf("%d ", a[i]);
  }
  printf("\r\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dump>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L5
  lea    -0x1(%rbp),%eax
  lea    D5(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   (%rax)
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
L5:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
data_type: string
name: parse_data
arguments: data_label: D5
data_type: string

tool: D19: 

tool: D5: %d 

assistant: ```c
void dump(int a[], int size) {
  int i = 0;
  printf("\r\n");
  for (i = 0; i < size; i++) {
    printf("%d ", a[i]);
  }
  printf("\r\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sendUntilDone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L21
L8:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jg     L11
  mov    $0x0,%eax
  jmp    L27
L11:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L8
  mov    $0x1,%eax
L27:
  leave
  ret
```

assistant: ```c
bool sendUntilDone(int sock, const uint8_t *buffer, size_t bytesToWrite) {
  size_t curWritten = 0;
  while (curWritten < bytesToWrite) {
    ssize_t sendResult = send(sock, buffer + curWritten, bytesToWrite - curWritten, 0);
    if (sendResult <= 0) {
      return (false);
    }
    curWritten += (size_t)sendResult;
  }
  return (true);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sendUntilDone>:
  endbr64
  test   %rdx,%rdx
  je     L21
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    $0x0,%ebx
L36:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    0x0(%r13,%rbx,4),%rsi
  mov    $0x0,%ecx
  mov    %r12d,%edi
  call   <send@plt>
  test   %rax,%rax
  jle    L28
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L36
  mov    $0x1,%eax
  jmp    L37
L21:
  mov    $0x1,%eax
  ret
L28:
  mov    $0x0,%eax
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool sendUntilDone(int sock, const uint8_t *buffer, size_t bytesToWrite) {
  size_t curWritten = 0;
  while (curWritten < bytesToWrite) {
    ssize_t sendResult = send(sock, buffer + curWritten, bytesToWrite - curWritten, 0);
    if (sendResult <= 0) {
      return (false);
    }
    curWritten += (size_t)sendResult;
  }
  return (true);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sendUntilDone>:
  endbr64
  test   %rdx,%rdx
  je     L20
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L27
L35:
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jbe    L3
L27:
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  lea    0x0(%r13,%rbx,4),%rsi
  mov    %r12d,%edi
  sub    %rbx,%rdx
  call   <send@plt>
  test   %rax,%rax
  jg     L35
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L3:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool sendUntilDone(int sock, const uint8_t *buffer, size_t bytesToWrite) {
  size_t curWritten = 0;
  while (curWritten < bytesToWrite) {
    ssize_t sendResult = send(sock, buffer + curWritten, bytesToWrite - curWritten, 0);
    if (sendResult <= 0) {
      return (false);
    }
    curWritten += (size_t)sendResult;
  }
  return (true);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sendUntilDone>:
  endbr64
  test   %rdx,%rdx
  je     L18
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L26
L23:
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jbe    L32
L26:
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  lea    0x0(%r13,%rbx,4),%rsi
  mov    %r12d,%edi
  sub    %rbx,%rdx
  call   <send@plt>
  test   %rax,%rax
  jg     L23
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L32:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool sendUntilDone(int sock, const uint8_t *buffer, size_t bytesToWrite) {
  size_t curWritten = 0;
  while (curWritten < bytesToWrite) {
    ssize_t sendResult = send(sock, buffer + curWritten, bytesToWrite - curWritten, 0);
    if (sendResult <= 0) {
      return (false);
    }
    curWritten += (size_t)sendResult;
  }
  return (true);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ether_aton>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ether_aton_r@plt>
  leave
  ret
```

assistant: ```c
struct ether_addr *ether_aton(const char *x) {
  static struct ether_addr a;
  return ether_aton_r(x, &a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ether_aton>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <ether_aton_r@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct ether_addr *ether_aton(const char *x) {
  static struct ether_addr a;
  return ether_aton_r(x, &a);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ether_aton>:
  endbr64
  lea    D6(%rip),%rsi
  jmp    1050 <ether_aton_r@plt>
```

assistant: ```c
struct ether_addr *ether_aton(const char *x) {
  static struct ether_addr a;
  return ether_aton_r(x, &a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ether_aton>:
  endbr64
  lea    D2(%rip),%rsi
  jmp    1050 <ether_aton_r@plt>
```

assistant: ```c
struct ether_addr *ether_aton(const char *x) {
  static struct ether_addr a;
  return ether_aton_r(x, &a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<blank_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L26
L35:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L35
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  mov    $0x1,%eax
  jmp    L18
L41:
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
int blank_line(char *s) {
  while (*s && isspace((int)*s))
    s++;
  if (!*s)
    return (1);
  else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<blank_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L4
L28:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L4
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L28
L4:
  cmpb   $0x0,(%rbx)
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int blank_line(char *s) {
  while (*s && isspace((int)*s))
    s++;
  if (!*s)
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<blank_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L3
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L4:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L29
L3:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  movzbl (%rbx),%edi
L29:
  xor    %eax,%eax
  test   %dil,%dil
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
int blank_line(char *s) {
  while (*s && isspace((int)*s))
    s++;
  if (!*s)
    return (1);
  else
    return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<blank_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L39
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L32:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L22
L39:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
  movzbl (%rbx),%edi
L22:
  xor    %eax,%eax
  test   %dil,%dil
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
int blank_line(char *s) {
  while (*s && isspace((int)*s))
    s++;
  if (!*s)
    return (1);
  else
    return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: %d

assistant: ```c
main() {
  char c;
  c = getchar();
  printf("%d", c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string

tool: D7: %d

assistant: ```c
main() {
  char c;
  c = getchar();
  printf("%d", c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D9(%rip),%rdi
  movsbl %al,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: %d

assistant: ```c
main() {
  char c;
  c = getchar();
  printf("%d", c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D6(%rip),%rdi
  movsbl %al,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string

tool: D6: %d

assistant: ```c
main() {
  char c;
  c = getchar();
  printf("%d", c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<breakdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L6
  addl   $0x1,-0x8(%rbp)
  jmp    L39
L6:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rsi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  add    %rsi,%rdx
  mov    %rdx,(%rax)
L39:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L29
  nop
  nop
  leave
  ret
```

assistant: ```c
void breakdown(char *string, long long *num) {
  unsigned int num_pos = 0;
  for (int i = 0; i < strlen(string); i++) {
    if (string[i] == '-') {
      num_pos++;
      continue;
    }
    num[num_pos] = num[num_pos] * 10 + (string[i] - 48);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<breakdown>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L4
L10:
  add    $0x1,%r12d
L0:
  add    $0x1,%rbx
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L7
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2d,%al
  je     L10
  mov    %r12d,%edx
  lea    0x0(%r13,%rdx,8),%rdx
  mov    (%rdx),%rcx
  lea    (%rcx,%rcx,4),%rcx
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rcx,2),%rax
  mov    %rax,(%rdx)
  jmp    L0
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void breakdown(char *string, long long *num) {
  unsigned int num_pos = 0;
  for (int i = 0; i < strlen(string); i++) {
    if (string[i] == '-') {
      num_pos++;
      continue;
    }
    num[num_pos] = num[num_pos] * 10 + (string[i] - 48);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<breakdown>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edx
  sub    $0x30,%eax
  lea    0x0(%rbp,%rdx,8),%rdx
  cltq
  mov    (%rdx),%rcx
  lea    (%rcx,%rcx,4),%rcx
  lea    (%rax,%rcx,2),%rax
  mov    %rax,(%rdx)
L32:
  add    $0x1,%r12
L13:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L15
  movsbl 0x0(%r13,%r12,1),%eax
  cmp    $0x2d,%al
  jne    L5
  add    $0x1,%ebx
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void breakdown(char *string, long long *num) {
  unsigned int num_pos = 0;
  for (int i = 0; i < strlen(string); i++) {
    if (string[i] == '-') {
      num_pos++;
      continue;
    }
    num[num_pos] = num[num_pos] * 10 + (string[i] - 48);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<breakdown>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %ebx,%edx
  sub    $0x30,%eax
  lea    0x0(%rbp,%rdx,8),%rdx
  cltq
  mov    (%rdx),%rcx
  lea    (%rcx,%rcx,4),%rcx
  lea    (%rax,%rcx,2),%rax
  mov    %rax,(%rdx)
L8:
  add    $0x1,%r12
L6:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L26
  movsbl 0x0(%r13,%r12,1),%eax
  cmp    $0x2d,%al
  jne    L34
  add    $0x1,%ebx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void breakdown(char *string, long long *num) {
  unsigned int num_pos = 0;
  for (int i = 0; i < strlen(string); i++) {
    if (string[i] == '-') {
      num_pos++;
      continue;
    }
    num[num_pos] = num[num_pos] * 10 + (string[i] - 48);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<medium_test_suite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x90(%rbp),%rdx
  mov    -0x98(%rbp),%rax
  mov    $0x80,%ecx
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  lea    -0x90(%rbp),%rdx
  mov    -0x98(%rbp),%rax
  mov    $0x80,%ecx
  lea    D31(%rip),%rsi
  mov    %rax,%rdi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  lea    -0x90(%rbp),%rdx
  mov    -0x98(%rbp),%rax
  mov    $0x80,%ecx
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
datatype: string
name: disassemble_data
arguments: tag: D18
datatype: string
name: disassemble_data
arguments: tag: D31
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string

tool: D15: File Name,Propagation Type,Number of Nodes,Number of Edges,Diameter,Number of Iterations,BP Run Time(s)


tool: D18: alarm.bif

tool: D31: insurance.bif

tool: D14: water.bif

assistant: ```c
void medium_test_suite(const char *root_dir) {
  char file_name_buffer[128];
  printf("File Name,Propagation Type,Number of Nodes,Number of Edges,Diameter,Number of Iterations,BP Run Time(s)\n");
  run_tests_with_file(build_full_file_path(root_dir, "alarm.bif", file_name_buffer, 128), 1);
  run_tests_with_file(build_full_file_path(root_dir, "insurance.bif", file_name_buffer, 128), 1);
  run_tests_with_file(build_full_file_path(root_dir, "water.bif", file_name_buffer, 128), 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<medium_test_suite>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbp
  mov    $0x80,%ecx
  mov    %rbp,%rdx
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <build_full_file_path@plt>
  mov    %eax,%edi
  mov    $0x1,%esi
  call   <run_tests_with_file@plt>
  mov    $0x80,%ecx
  mov    %rbp,%rdx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <build_full_file_path@plt>
  mov    %eax,%edi
  mov    $0x1,%esi
  call   <run_tests_with_file@plt>
  mov    $0x80,%ecx
  mov    %rbp,%rdx
  lea    D19(%rip),%rsi
  mov    %rbx,%rdi
  call   <build_full_file_path@plt>
  mov    %eax,%edi
  mov    $0x1,%esi
  call   <run_tests_with_file@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string

tool: D15: File Name,Propagation Type,Number of Nodes,Number of Edges,Diameter,Number of Iterations,BP Run Time(s)


tool: D16: alarm.bif

tool: D2: insurance.bif

tool: D19: water.bif

assistant: ```c
void medium_test_suite(const char *root_dir) {
  char file_name_buffer[128];
  printf("File Name,Propagation Type,Number of Nodes,Number of Edges,Diameter,Number of Iterations,BP Run Time(s)\n");
  run_tests_with_file(build_full_file_path(root_dir, "alarm.bif", file_name_buffer, 128), 1);
  run_tests_with_file(build_full_file_path(root_dir, "insurance.bif", file_name_buffer, 128), 1);
  run_tests_with_file(build_full_file_path(root_dir, "water.bif", file_name_buffer, 128), 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<medium_test_suite>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D22(%rip),%rdi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <printf@plt>
  mov    $0x80,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  mov    $0x80,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D28(%rip),%rsi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  mov    %rbp,%rdi
  mov    $0x80,%ecx
  mov    %r12,%rdx
  lea    D3(%rip),%rsi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x98,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D22
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D28
datatype: string
name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D22: File Name,Propagation Type,Number of Nodes,Number of Edges,Diameter,Number of Iterations,BP Run Time(s)


tool: D10: alarm.bif

tool: D28: insurance.bif

tool: D3: water.bif

assistant: ```c
void medium_test_suite(const char *root_dir) {
  char file_name_buffer[128];
  printf("File Name,Propagation Type,Number of Nodes,Number of Edges,Diameter,Number of Iterations,BP Run Time(s)\n");
  run_tests_with_file(build_full_file_path(root_dir, "alarm.bif", file_name_buffer, 128), 1);
  run_tests_with_file(build_full_file_path(root_dir, "insurance.bif", file_name_buffer, 128), 1);
  run_tests_with_file(build_full_file_path(root_dir, "water.bif", file_name_buffer, 128), 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<medium_test_suite>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D25(%rip),%rdi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <printf@plt>
  mov    $0x80,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  mov    $0x80,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D9(%rip),%rsi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  mov    %rbp,%rdi
  mov    $0x80,%ecx
  mov    %r12,%rdx
  lea    D10(%rip),%rsi
  call   <build_full_file_path@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <run_tests_with_file@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x98,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D25
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string

tool: D25: File Name,Propagation Type,Number of Nodes,Number of Edges,Diameter,Number of Iterations,BP Run Time(s)


tool: D8: alarm.bif

tool: D9: insurance.bif

tool: D10: water.bif

assistant: ```c
void medium_test_suite(const char *root_dir) {
  char file_name_buffer[128];
  printf("File Name,Propagation Type,Number of Nodes,Number of Edges,Diameter,Number of Iterations,BP Run Time(s)\n");
  run_tests_with_file(build_full_file_path(root_dir, "alarm.bif", file_name_buffer, 128), 1);
  run_tests_with_file(build_full_file_path(root_dir, "insurance.bif", file_name_buffer, 128), 1);
  run_tests_with_file(build_full_file_path(root_dir, "water.bif", file_name_buffer, 128), 1);
}
```