ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<normrad>:
  endbr64
  sub    $0x8,%rsp
  movsd  D5(%rip),%xmm1
  call   <fmod@plt>
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L9
L12:
  add    $0x8,%rsp
  ret
L9:
  addsd  D5(%rip),%xmm0
  jmp    L12
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: f64

tool: D5: 6.283185307179586

assistant: ```c
double normrad(double r) {
  r = fmod(r, 6.28318530717958647693);
  if (r < 0)
    r += 6.28318530717958647693;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<normrad>:
  endbr64
  sub    $0x8,%rsp
  mov    D10(%rip),%rax
  movq   %rax,%xmm1
  call   <fmod@plt>
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L9
  addsd  D10(%rip),%xmm0
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
datatype: f64

tool: D10: 6.283185307179586

assistant: ```c
double normrad(double r) {
  r = fmod(r, 6.28318530717958647693);
  if (r < 0)
    r += 6.28318530717958647693;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<normrad>:
  endbr64
  sub    $0x8,%rsp
  mov    D12(%rip),%rax
  movq   %rax,%xmm1
  call   <fmod@plt>
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L8
  addsd  D12(%rip),%xmm0
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
datatype: f64

tool: D12: 6.283185307179586

assistant: ```c
double normrad(double r) {
  r = fmod(r, 6.28318530717958647693);
  if (r < 0)
    r += 6.28318530717958647693;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L53
L60:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L69
L73:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L28
  addq   $0x1,-0x10(%rbp)
L69:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L73
  jmp    L66
L28:
  nop
L66:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  addq   $0x1,-0x18(%rbp)
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
  jmp    L61
L12:
  nop
L61:
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strspn(const char *str, const char *accept) {
  const char *ptr = str;
  const char *acc;
  while (*str) {
    for (acc = accept; *acc; ++acc) {
      if (*str == *acc) {
        break;
      }
    }
    if (*acc == '\0') {
      break;
    }
    str++;
  }
  return str - ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L39
  movzbl (%rsi),%r9d
  test   %r9b,%r9b
  sete   %r10b
  mov    %rdi,%rax
  jmp    L18
L47:
  mov    %r9d,%ecx
L66:
  test   %cl,%cl
  je     L69
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  je     L69
L18:
  cmp    %r8b,%r9b
  je     L47
  test   %r10b,%r10b
  jne    L47
  mov    %rsi,%rdx
L84:
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    %r8b,%cl
  je     L66
  test   %cl,%cl
  jne    L84
  jmp    L66
L39:
  mov    %rdi,%rax
L69:
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t strspn(const char *str, const char *accept) {
  const char *ptr = str;
  const char *acc;
  while (*str) {
    for (acc = accept; *acc; ++acc) {
      if (*str == *acc) {
        break;
      }
    }
    if (*acc == '\0') {
      break;
    }
    str++;
  }
  return str - ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L42
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
  nopl   0x0(%rax)
L24:
  test   %r9b,%r9b
  je     L39
  mov    %rsi,%rcx
  mov    %r9d,%edx
  jmp    L40
  nopl   (%rax)
L4:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L39
L40:
  cmp    %r8b,%dl
  jne    L4
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L24
L39:
  sub    %rdi,%rax
  ret
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strspn(const char *str, const char *accept) {
  const char *ptr = str;
  const char *acc;
  while (*str) {
    for (acc = accept; *acc; ++acc) {
      if (*str == *acc) {
        break;
      }
    }
    if (*acc == '\0') {
      break;
    }
    str++;
  }
  return str - ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L12
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
  nopl   0x0(%rax)
L3:
  test   %r9b,%r9b
  je     L52
  mov    %rsi,%rcx
  mov    %r9d,%edx
  jmp    L32
  nopl   (%rax)
L57:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L52
L32:
  cmp    %r8b,%dl
  jne    L57
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L3
L52:
  sub    %rdi,%rax
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strspn(const char *str, const char *accept) {
  const char *ptr = str;
  const char *acc;
  while (*str) {
    for (acc = accept; *acc; ++acc) {
      if (*str == *acc) {
        break;
      }
    }
    if (*acc == '\0') {
      break;
    }
    str++;
  }
  return str - ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<restore_all_records>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <restore_all_records__probe@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L31
L12:
  mov    $0x0,%eax
  call   <are_you_sure@plt>
  test   %eax,%eax
  jne    L21
  mov    $0x0,%eax
  jmp    L31
L21:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <restore_all_records__probe@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L31
L15:
  lea    D32(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L31:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D29
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D32
datatype: string

tool: D29: backup consistency check failed

tool: D23: %s


tool: D32: backup sequence restored

assistant: ```c
int restore_all_records(char *device_name) {
  int result;
  result = restore_all_records__probe(device_name, (!(0)));
  if (result == ((0))) {
    printf("%s"
           "\n",
           "backup consistency check failed");
    return ((0));
  };
  if (are_you_sure() == (0))
    return ((0));
  result = restore_all_records__probe(device_name, (0));
  if (result == ((0))) {
    ;
    return ((0));
  };
  printf("%s"
         "\n",
         "backup sequence restored");
  return ((!(0)));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<restore_all_records>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x1,%esi
  call   <restore_all_records__probe@plt>
  test   %eax,%eax
  je     L7
  mov    $0x0,%eax
  call   <are_you_sure@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L3
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <restore_all_records__probe@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L3
  lea    D18(%rip),%rsi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  jmp    L3
L7:
  mov    %eax,%ebx
  lea    D25(%rip),%rsi
  lea    D34(%rip),%rdi
  call   <printf@plt>
L3:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D34
datatype: string
name: extract_symbolic_data
arguments: label: D25
datatype: string

tool: D18: backup sequence restored

tool: D34: %s


tool: D25: backup consistency check failed

assistant: ```c
int restore_all_records(char *device_name) {
  int result;
  result = restore_all_records__probe(device_name, (!(0)));
  if (result == ((0))) {
    printf("%s"
           "\n",
           "backup consistency check failed");
    return ((0));
  };
  if (are_you_sure() == (0))
    return ((0));
  result = restore_all_records__probe(device_name, (0));
  if (result == ((0))) {
    ;
    return ((0));
  };
  printf("%s"
         "\n",
         "backup sequence restored");
  return ((!(0)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<restore_all_records>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <restore_all_records__probe@plt>
  test   %eax,%eax
  je     L0
  xor    %eax,%eax
  call   <are_you_sure@plt>
  test   %eax,%eax
  jne    L21
L22:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L21:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <restore_all_records__probe@plt>
  test   %eax,%eax
  je     L22
  lea    D11(%rip),%rsi
  lea    D35(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D17(%rip),%rsi
  lea    D35(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D35
type_guessed: string
name: disassemble_data
arguments: data_label: D17
type_guessed: string

tool: D11: backup sequence restored

tool: D35: %s


tool: D17: backup consistency check failed

assistant: ```c
int restore_all_records(char *device_name) {
  int result;
  result = restore_all_records__probe(device_name, (!(0)));
  if (result == ((0))) {
    printf("%s"
           "\n",
           "backup consistency check failed");
    return ((0));
  };
  if (are_you_sure() == (0))
    return ((0));
  result = restore_all_records__probe(device_name, (0));
  if (result == ((0))) {
    ;
    return ((0));
  };
  printf("%s"
         "\n",
         "backup sequence restored");
  return ((!(0)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<restore_all_records>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <restore_all_records__probe@plt>
  test   %eax,%eax
  je     L18
  xor    %eax,%eax
  call   <are_you_sure@plt>
  test   %eax,%eax
  jne    L26
L16:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L26:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <restore_all_records__probe@plt>
  test   %eax,%eax
  je     L16
  lea    D15(%rip),%rsi
  lea    D17(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  lea    D3(%rip),%rsi
  lea    D17(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D3
type: string

tool: D15: backup sequence restored

tool: D17: %s


tool: D3: backup consistency check failed

assistant: ```c
int restore_all_records(char *device_name) {
  int result;
  result = restore_all_records__probe(device_name, (!(0)));
  if (result == ((0))) {
    printf("%s"
           "\n",
           "backup consistency check failed");
    return ((0));
  };
  if (are_you_sure() == (0))
    return ((0));
  result = restore_all_records__probe(device_name, (0));
  if (result == ((0))) {
    ;
    return ((0));
  };
  printf("%s"
         "\n",
         "backup sequence restored");
  return ((!(0)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kasai_lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x50(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L66:
  cmp    %rdx,%rsp
  je     L20
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L66
L20:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L151
  orq    $0x0,-0x8(%rsp,%rax,1)
L151:
  mov    %rsp,%r12
  test   %ecx,%ecx
  jle    L105
  mov    %ecx,%ebx
  mov    $0x0,%eax
L2:
  movslq 0x0(%r13,%rax,4),%rdx
  mov    %eax,(%r12,%rdx,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L2
  mov    $0x0,%r11d
  mov    $0x0,%eax
  lea    -0x1(%rcx),%r15d
  jmp    L122
L37:
  mov    -0x48(%rbp),%rdi
  mov    %eax,-0x4(%rdi,%r14,1)
  test   %eax,%eax
  setg   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
L23:
  add    $0x1,%r11
  cmp    %rbx,%r11
  je     L105
L122:
  mov    %r11d,%r9d
  mov    (%r12,%r11,4),%edx
  cmp    %r15d,%edx
  je     L68
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%r14
  mov    0x0(%r13,%rdx,4),%r10d
  lea    (%rax,%r11,1),%edi
  cmp    %edi,%ecx
  jle    L37
  lea    (%r10,%rax,1),%r8d
  cmp    %r8d,%ecx
  jle    L37
  movslq %edi,%rdi
  mov    -0x50(%rbp),%rdx
  add    %rdi,%rdx
  movslq %r8d,%r8
L73:
  mov    %rdx,%rsi
  sub    %rdi,%rsi
  movzbl (%rsi,%r8,1),%esi
  cmp    %sil,(%rdx)
  jne    L37
  add    $0x1,%eax
  lea    (%rax,%r9,1),%esi
  cmp    %esi,%ecx
  jle    L37
  add    $0x1,%rdx
  lea    (%r10,%rax,1),%esi
  cmp    %esi,%ecx
  jg     L73
  jmp    L37
L68:
  mov    $0x0,%eax
  jmp    L23
L105:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void kasai_lcp(char *text, int *lcp, int *suffArr, int n) {
  int i;
  int invSuff[n];
  for (i = 0; i < n; i++) {
    invSuff[suffArr[i]] = i;
  }
  int k = 0;
  for (i = 0; i < n; i++) {
    if (invSuff[i] == n - 1) {
      k = 0;
      continue;
    }
    int j = suffArr[invSuff[i] + 1];
    while (i + k < n && j + k < n && text[i + k] == text[j + k]) {
      k++;
    }
    lcp[invSuff[i]] = k;
    if (k > 0) {
      k--;
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kasai_lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  movslq %ecx,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,-0x50(%rbp)
  mov    %r12,%rsi
  mov    %rdi,-0x58(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r12,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L49
L70:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L70
L49:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L144
L45:
  mov    %rsp,%r13
  xor    %eax,%eax
  test   %esi,%esi
  jle    L150
  nopl   0x0(%rax)
L11:
  movslq (%r14,%rax,4),%rdx
  mov    %eax,0x0(%r13,%rdx,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L11
  lea    -0x1(%rsi),%eax
  xor    %ebx,%ebx
  xor    %ecx,%ecx
  mov    %eax,-0x44(%rbp)
  nopl   0x0(%rax)
L104:
  movslq 0x0(%r13,%rbx,4),%rax
  mov    %ebx,%r10d
  cmp    -0x44(%rbp),%eax
  je     L46
  add    $0x1,%rax
  lea    (%rcx,%rbx,1),%r8d
  mov    (%r14,%rax,4),%r11d
  lea    0x0(,%rax,4),%r15
  cmp    %r8d,%esi
  jle    L83
  lea    (%r11,%rcx,1),%r9d
  cmp    %r9d,%esi
  jle    L83
  mov    -0x58(%rbp),%rax
  movslq %r8d,%r8
  movslq %r9d,%r9
  add    %r8,%rax
  jmp    L21
  xchg   %ax,%ax
L133:
  lea    0x1(%rcx),%edx
  lea    (%rdx,%r10,1),%edi
  cmp    %edi,%esi
  jle    L141
  lea    (%r11,%rdx,1),%edi
  add    $0x1,%rax
  cmp    %edi,%esi
  jle    L141
  mov    %edx,%ecx
L21:
  mov    %rax,%rdx
  sub    %r8,%rdx
  movzbl (%rdx,%r9,1),%edi
  cmp    %dil,(%rax)
  je     L133
L83:
  mov    -0x50(%rbp),%rax
  mov    %ecx,-0x4(%rax,%r15,1)
  test   %ecx,%ecx
  jne    L5
L46:
  xor    %ecx,%ecx
L7:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L104
L150:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L141:
  mov    -0x50(%rbp),%rax
  mov    %edx,-0x4(%rax,%r15,1)
  jmp    L7
L144:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L45
L92:
  call   <__stack_chk_fail@plt>
L5:
  sub    $0x1,%ecx
  jmp    L7
```

assistant: ```c
void kasai_lcp(char *text, int *lcp, int *suffArr, int n) {
  int i;
  int invSuff[n];
  for (i = 0; i < n; i++) {
    invSuff[suffArr[i]] = i;
  }
  int k = 0;
  for (i = 0; i < n; i++) {
    if (invSuff[i] == n - 1) {
      k = 0;
      continue;
    }
    int j = suffArr[invSuff[i] + 1];
    while (i + k < n && j + k < n && text[i + k] == text[j + k]) {
      k++;
    }
    lcp[invSuff[i]] = k;
    if (k > 0) {
      k--;
    }
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kasai_lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  movslq %ecx,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,-0x50(%rbp)
  mov    %r12,%rsi
  mov    %rdi,-0x58(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r12,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L77
L37:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L37
L77:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L20
L83:
  mov    %rsp,%r13
  xor    %eax,%eax
  test   %esi,%esi
  jle    L48
  nopl   0x0(%rax)
L80:
  movslq (%r14,%rax,4),%rdx
  mov    %eax,0x0(%r13,%rdx,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L80
  lea    -0x1(%rsi),%eax
  xor    %ebx,%ebx
  xor    %ecx,%ecx
  mov    %eax,-0x44(%rbp)
  nopl   0x0(%rax)
L131:
  movslq 0x0(%r13,%rbx,4),%rax
  mov    %ebx,%r10d
  cmp    -0x44(%rbp),%eax
  je     L68
  add    $0x1,%rax
  lea    (%rcx,%rbx,1),%r8d
  mov    (%r14,%rax,4),%r11d
  lea    0x0(,%rax,4),%r15
  cmp    %r8d,%esi
  jle    L40
  lea    (%r11,%rcx,1),%r9d
  cmp    %r9d,%esi
  jle    L40
  mov    -0x58(%rbp),%rax
  movslq %r8d,%r8
  movslq %r9d,%r9
  add    %r8,%rax
  jmp    L170
  xchg   %ax,%ax
L93:
  lea    0x1(%rcx),%edx
  lea    (%r10,%rdx,1),%edi
  cmp    %edi,%esi
  jle    L177
  lea    (%r11,%rdx,1),%edi
  add    $0x1,%rax
  cmp    %edi,%esi
  jle    L177
  mov    %edx,%ecx
L170:
  mov    %rax,%rdx
  sub    %r8,%rdx
  movzbl (%rdx,%r9,1),%edi
  cmp    %dil,(%rax)
  je     L93
L40:
  mov    -0x50(%rbp),%rax
  mov    %ecx,-0x4(%rax,%r15,1)
  test   %ecx,%ecx
  jne    L97
L68:
  xor    %ecx,%ecx
L19:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L131
L48:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L177:
  mov    -0x50(%rbp),%rax
  mov    %edx,-0x4(%rax,%r15,1)
  jmp    L19
L20:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L83
L28:
  call   <__stack_chk_fail@plt>
L97:
  sub    $0x1,%ecx
  jmp    L19
```

assistant: ```c
void kasai_lcp(char *text, int *lcp, int *suffArr, int n) {
  int i;
  int invSuff[n];
  for (i = 0; i < n; i++) {
    invSuff[suffArr[i]] = i;
  }
  int k = 0;
  for (i = 0; i < n; i++) {
    if (invSuff[i] == n - 1) {
      k = 0;
      continue;
    }
    int j = suffArr[invSuff[i] + 1];
    while (i + k < n && j + k < n && text[i + k] == text[j + k]) {
      k++;
    }
    lcp[invSuff[i]] = k;
    if (k > 0) {
      k--;
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strict_strtoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L53
  mov    $0xffffffea,%eax
  jmp    L40
L53:
  mov    -0x2c(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <simple_strtoul@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L72
  mov    $0xffffffea,%eax
  jmp    L40
L72:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L56
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x18(%rbp)
  jne    L57
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L57
L56:
  mov    -0x38(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L40
L57:
  mov    $0xffffffea,%eax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int strict_strtoul(const char *cp, unsigned int base, unsigned long *res) {
  char *tail;
  unsigned long val;
  size_t len;
  *res = 0;
  len = strlen(cp);
  if (len == 0)
    return -22;
  val = simple_strtoul(cp, &tail, base);
  if (tail == cp)
    return -22;
  if ((*tail == '\0') || ((len == (size_t)(tail - cp) + 1) && (*tail == '\n'))) {
    *res = val;
    return 0;
  }
  return -22;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strict_strtoul>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rdx)
  call   <strlen@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%r12
  mov    %rsp,%rsi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <simple_strtoul@plt>
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L57
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L2
  sub    %rbx,%rdx
  add    $0x1,%rdx
  cmp    %r12,%rdx
  jne    L5
  cmp    $0xa,%cl
  jne    L5
L2:
  mov    %rax,0x0(%rbp)
  mov    $0x0,%eax
L89:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    $0xffffffea,%eax
  jmp    L89
L57:
  mov    $0xffffffea,%eax
  jmp    L89
L5:
  mov    $0xffffffea,%eax
  jmp    L89
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int strict_strtoul(const char *cp, unsigned int base, unsigned long *res) {
  char *tail;
  unsigned long val;
  size_t len;
  *res = 0;
  len = strlen(cp);
  if (len == 0)
    return -22;
  val = simple_strtoul(cp, &tail, base);
  if (tail == cp)
    return -22;
  if ((*tail == '\0') || ((len == (size_t)(tail - cp) + 1) && (*tail == '\n'))) {
    *res = val;
    return 0;
  }
  return -22;
}
```