ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   $0x0,-0x28(%rbp)
  jmp    L20
L24:
  lea    -0x38(%rbp),%rsi
  lea    -0x40(%rbp),%rcx
  lea    -0x48(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <dist@plt>
  mov    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  sub    %rdx,%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <dist@plt>
  sub    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    -0x40(%rbp),%rdx
  sub    %rdx,%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <dist@plt>
  sub    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  sub    %rdx,%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <dist@plt>
  sub    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  sub    %rdx,%rax
  mov    -0x40(%rbp),%rdx
  sub    %rdx,%rax
  sub    $0x2,%rax
  mov    %rax,%rdi
  call   <dist@plt>
  add    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    -0x40(%rbp),%rdx
  sub    %rdx,%rax
  mov    -0x38(%rbp),%rdx
  sub    %rdx,%rax
  sub    $0x2,%rax
  mov    %rax,%rdi
  call   <dist@plt>
  add    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  sub    %rdx,%rax
  mov    -0x38(%rbp),%rdx
  sub    %rdx,%rax
  sub    $0x2,%rax
  mov    %rax,%rdi
  call   <dist@plt>
  add    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  sub    %rdx,%rax
  mov    -0x40(%rbp),%rdx
  sub    %rdx,%rax
  mov    -0x38(%rbp),%rdx
  sub    %rdx,%rax
  sub    $0x3,%rax
  mov    %rax,%rdi
  call   <dist@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x28(%rbp)
L20:
  mov    -0x30(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jl     L24
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type: string
name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D27
type: string

tool: D22: %lld

tool: D4: %lld%lld%lld%lld

tool: D27: %lld


assistant: ```c
int main() {
  long long int N, A, B, C, testcase, i;
  long long int soln;
  scanf("%lld", &testcase);
  for (i = 0; i < testcase; i++) {
    scanf("%lld%lld%lld%lld", &N, &A, &B, &C);
    soln = dist(N) - dist(N - A - 1) - dist(N - B - 1) - dist(N - C - 1) + dist(N - A - B - 2) + dist(N - B - C - 2) + dist(N - A - C - 2) - dist(N - A - B - C - 3);
    printf("%lld\n", soln);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,0x20(%rsp)
  jle    L10
  mov    $0x0,%ebp
  lea    0x18(%rsp),%r15
  lea    0x10(%rsp),%r14
  lea    D22(%rip),%r13
  lea    D10(%rip),%r12
L18:
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rsp),%rdi
  call   <dist@plt>
  mov    %rax,%rbx
  mov    (%rsp),%rdi
  sub    0x8(%rsp),%rdi
  sub    $0x1,%rdi
  call   <dist@plt>
  sub    %rax,%rbx
  mov    (%rsp),%rdi
  sub    0x10(%rsp),%rdi
  sub    $0x1,%rdi
  call   <dist@plt>
  sub    %rax,%rbx
  mov    (%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    $0x1,%rdi
  call   <dist@plt>
  sub    %rax,%rbx
  mov    (%rsp),%rdi
  sub    0x8(%rsp),%rdi
  sub    0x10(%rsp),%rdi
  sub    $0x2,%rdi
  call   <dist@plt>
  add    %rax,%rbx
  mov    (%rsp),%rdi
  sub    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    $0x2,%rdi
  call   <dist@plt>
  add    %rax,%rbx
  mov    (%rsp),%rdi
  sub    0x8(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    $0x2,%rdi
  call   <dist@plt>
  add    %rax,%rbx
  mov    (%rsp),%rdi
  sub    0x8(%rsp),%rdi
  sub    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    $0x3,%rdi
  call   <dist@plt>
  mov    %rbx,%rsi
  sub    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbp
  cmp    %rbp,0x20(%rsp)
  jg     L18
L10:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string
name: retrieve_data
arguments: data_label: D22
data_type: string
name: retrieve_data
arguments: data_label: D10
data_type: string

tool: D8: %lld

tool: D22: %lld%lld%lld%lld

tool: D10: %lld


assistant: ```c
int main() {
  long long int N, A, B, C, testcase, i;
  long long int soln;
  scanf("%lld", &testcase);
  for (i = 0; i < testcase; i++) {
    scanf("%lld%lld%lld%lld", &N, &A, &B, &C);
    soln = dist(N) - dist(N - A - 1) - dist(N - B - 1) - dist(N - C - 1) + dist(N - A - B - 2) + dist(N - B - C - 2) + dist(N - A - C - 2) - dist(N - A - B - C - 3);
    printf("%lld\n", soln);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rsi
  call   <scanf@plt>
  cmpq   $0x0,0x30(%rsp)
  jle    L10
  xor    %ebp,%ebp
  lea    0x28(%rsp),%r8
  lea    0x20(%rsp),%r15
  lea    0x18(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    D27(%rip),%r12
  nopl   0x0(%rax)
L8:
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %r8,0x8(%rsp)
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    $0x1,%rdi
  mov    %rax,%rbx
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x20(%rsp),%rdi
  sub    $0x1,%rdi
  sub    %rax,%rbx
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x28(%rsp),%rdi
  sub    $0x1,%rdi
  sub    %rax,%rbx
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    0x20(%rsp),%rdi
  sub    %rax,%rbx
  sub    $0x2,%rdi
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x20(%rsp),%rdi
  sub    0x28(%rsp),%rdi
  add    %rax,%rbx
  sub    $0x2,%rdi
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    0x28(%rsp),%rdi
  add    %rax,%rbx
  sub    $0x2,%rdi
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  add    %rax,%rbx
  sub    0x20(%rsp),%rdi
  sub    0x28(%rsp),%rdi
  add    $0x1,%rbp
  sub    $0x3,%rdi
  call   <dist@plt>
  mov    %rbx,%rsi
  lea    D22(%rip),%rdi
  sub    %rax,%rsi
  call   <printf@plt>
  cmp    %rbp,0x30(%rsp)
  mov    0x8(%rsp),%r8
  jg     L8
L10:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D22
datatype: string

tool: D4: %lld

tool: D27: %lld%lld%lld%lld

tool: D22: %lld


assistant: ```c
int main() {
  long long int N, A, B, C, testcase, i;
  long long int soln;
  scanf("%lld", &testcase);
  for (i = 0; i < testcase; i++) {
    scanf("%lld%lld%lld%lld", &N, &A, &B, &C);
    soln = dist(N) - dist(N - A - 1) - dist(N - B - 1) - dist(N - C - 1) + dist(N - A - B - 2) + dist(N - B - C - 2) + dist(N - A - C - 2) - dist(N - A - B - C - 3);
    printf("%lld\n", soln);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D17(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rsi
  call   <scanf@plt>
  cmpq   $0x0,0x30(%rsp)
  jle    L9
  xor    %ebp,%ebp
  lea    0x28(%rsp),%r8
  lea    0x20(%rsp),%r15
  lea    0x18(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    D16(%rip),%r12
  nopl   0x0(%rax)
L22:
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %r8,0x8(%rsp)
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    $0x1,%rdi
  mov    %rax,%rbx
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x20(%rsp),%rdi
  sub    $0x1,%rdi
  sub    %rax,%rbx
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x28(%rsp),%rdi
  sub    $0x1,%rdi
  sub    %rax,%rbx
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    0x20(%rsp),%rdi
  sub    %rax,%rbx
  sub    $0x2,%rdi
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x20(%rsp),%rdi
  sub    0x28(%rsp),%rdi
  add    %rax,%rbx
  sub    $0x2,%rdi
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  sub    0x28(%rsp),%rdi
  add    %rax,%rbx
  sub    $0x2,%rdi
  call   <dist@plt>
  mov    0x10(%rsp),%rdi
  sub    0x18(%rsp),%rdi
  add    %rax,%rbx
  sub    0x20(%rsp),%rdi
  sub    0x28(%rsp),%rdi
  add    $0x1,%rbp
  sub    $0x3,%rdi
  call   <dist@plt>
  mov    %rbx,%rsi
  lea    D22(%rip),%rdi
  sub    %rax,%rsi
  call   <printf@plt>
  cmp    %rbp,0x30(%rsp)
  mov    0x8(%rsp),%r8
  jg     L22
L9:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D22
type: string

tool: D17: %lld

tool: D16: %lld%lld%lld%lld

tool: D22: %lld


assistant: ```c
int main() {
  long long int N, A, B, C, testcase, i;
  long long int soln;
  scanf("%lld", &testcase);
  for (i = 0; i < testcase; i++) {
    scanf("%lld%lld%lld%lld", &N, &A, &B, &C);
    soln = dist(N) - dist(N - A - 1) - dist(N - B - 1) - dist(N - C - 1) + dist(N - A - B - 2) + dist(N - B - C - 2) + dist(N - A - C - 2) - dist(N - A - B - C - 3);
    printf("%lld\n", soln);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <nuovaDomanda@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  nuovaDomanda();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <nuovaDomanda@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  nuovaDomanda();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <nuovaDomanda@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  nuovaDomanda();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <nuovaDomanda@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  nuovaDomanda();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FilloutCode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L11
L16:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  movl   $0x0,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
  cmpl   $0x3,-0x18(%rbp)
  jle    L6
  movl   $0x0,-0x18(%rbp)
  mov    $0x0,%eax
  call   <Next4Rands@plt>
L6:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    -0x18(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <LayerRandByte@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
L11:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L16
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void FilloutCode(char *code, int size) {
  int l, i, j, k;
  l = strlen(code);
  for (i = l, j = 0, k = 0; i < size; i++, j++) {
    if (j >= l) {
      j = 0;
      k++;
      if (k > 3) {
        k = 0;
        Next4Rands();
      }
    }
    code[i] = LayerRandByte(code[j], k);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FilloutCode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L6
  mov    %eax,%r13d
  cltq
  lea    (%r14,%rax,1),%rbp
  lea    0x1(%r14,%rax,1),%r15
  sub    $0x1,%ebx
  sub    %r13d,%ebx
  add    %rbx,%r15
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L46
L37:
  movslq %ebx,%rax
  movsbl (%r14,%rax,1),%edi
  mov    %r12d,%esi
  call   <LayerRandByte@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r15,%rbp
  je     L6
L46:
  cmp    %ebx,%r13d
  jg     L37
  add    $0x1,%r12d
  mov    $0x0,%ebx
  cmp    $0x3,%r12d
  jle    L37
  mov    $0x0,%eax
  call   <Next4Rands@plt>
  mov    $0x0,%r12d
  jmp    L37
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void FilloutCode(char *code, int size) {
  int l, i, j, k;
  l = strlen(code);
  for (i = l, j = 0, k = 0; i < size; i++, j++) {
    if (j >= l) {
      j = 0;
      k++;
      if (k > 3) {
        k = 0;
        Next4Rands();
      }
    }
    code[i] = LayerRandByte(code[j], k);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FilloutCode>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  cmp    %ebp,%eax
  jge    L46
  mov    %eax,%r13d
  sub    $0x1,%ebp
  cltq
  lea    0x1(%r14,%rax,1),%r15
  sub    %r13d,%ebp
  lea    (%r14,%rax,1),%rbx
  lea    (%r15,%rbp,1),%rax
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  mov    %rax,0x8(%rsp)
  jmp    L53
  nopl   0x0(%rax)
L57:
  movslq %ebp,%r12
  add    $0x1,%ebp
  add    %r14,%r12
L23:
  movsbl (%r12),%edi
  mov    %r15d,%esi
  add    $0x1,%rbx
  call   <LayerRandByte@plt>
  mov    %al,-0x1(%rbx)
  cmp    0x8(%rsp),%rbx
  je     L46
L53:
  cmp    %ebp,%r13d
  jg     L57
  add    $0x1,%r15d
  mov    %r14,%r12
  mov    $0x1,%ebp
  cmp    $0x3,%r15d
  jle    L23
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <Next4Rands@plt>
  jmp    L23
  nop
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void FilloutCode(char *code, int size) {
  int l, i, j, k;
  l = strlen(code);
  for (i = l, j = 0, k = 0; i < size; i++, j++) {
    if (j >= l) {
      j = 0;
      k++;
      if (k > 3) {
        k = 0;
        Next4Rands();
      }
    }
    code[i] = LayerRandByte(code[j], k);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FilloutCode>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  cmp    %ebp,%eax
  jge    L1
  mov    %eax,%r13d
  sub    $0x1,%ebp
  cltq
  lea    0x1(%r14,%rax,1),%r15
  sub    %r13d,%ebp
  lea    (%r14,%rax,1),%rbx
  lea    (%r15,%rbp,1),%rax
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  mov    %rax,0x8(%rsp)
  jmp    L33
  nopl   0x0(%rax)
L49:
  movslq %ebp,%r12
  add    $0x1,%ebp
  add    %r14,%r12
L8:
  movsbl (%r12),%edi
  mov    %r15d,%esi
  add    $0x1,%rbx
  call   <LayerRandByte@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,0x8(%rsp)
  je     L1
L33:
  cmp    %ebp,%r13d
  jg     L49
  add    $0x1,%r15d
  mov    %r14,%r12
  mov    $0x1,%ebp
  cmp    $0x3,%r15d
  jle    L8
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <Next4Rands@plt>
  jmp    L8
  nop
L1:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void FilloutCode(char *code, int size) {
  int l, i, j, k;
  l = strlen(code);
  for (i = l, j = 0, k = 0; i < size; i++, j++) {
    if (j >= l) {
      j = 0;
      k++;
      if (k > 3) {
        k = 0;
        Next4Rands();
      }
    }
    code[i] = LayerRandByte(code[j], k);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmpstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L49
  mov    $0x0,%eax
  jmp    L4
L49:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
  mov    $0x1,%eax
  jmp    L4
L53:
  addl   $0x1,-0x4(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L23
  mov    $0x1,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int cmpstr(char *str1, char *str2, int j) {
  int i;
  for (i = 0; i < j; i++)
    if (str1[i] != str2[i])
      return 0;
    else if (str1[i] == 0x0)
      return 1;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmpstr>:
  endbr64
  test   %edx,%edx
  jle    L9
  mov    %edx,%edx
  mov    $0x0,%eax
L25:
  movzbl (%rdi,%rax,1),%ecx
  cmp    (%rsi,%rax,1),%cl
  jne    L39
  test   %cl,%cl
  je     L7
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L25
  mov    $0x1,%eax
  ret
L9:
  mov    $0x1,%eax
  ret
L39:
  mov    $0x0,%eax
  ret
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cmpstr(char *str1, char *str2, int j) {
  int i;
  for (i = 0; i < j; i++)
    if (str1[i] != str2[i])
      return 0;
    else if (str1[i] == 0x0)
      return 1;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmpstr>:
  endbr64
  test   %edx,%edx
  jle    L43
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L31
  nop
L20:
  test   %cl,%cl
  je     L43
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L43
L31:
  movzbl (%rdi,%rax,1),%ecx
  cmp    (%rsi,%rax,1),%cl
  je     L20
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L43:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cmpstr(char *str1, char *str2, int j) {
  int i;
  for (i = 0; i < j; i++)
    if (str1[i] != str2[i])
      return 0;
    else if (str1[i] == 0x0)
      return 1;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmpstr>:
  endbr64
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L18
  nop
L8:
  test   %cl,%cl
  je     L2
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L2
L18:
  movzbl (%rdi,%rax,1),%ecx
  cmp    (%rsi,%rax,1),%cl
  je     L8
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cmpstr(char *str1, char *str2, int j) {
  int i;
  for (i = 0; i < j; i++)
    if (str1[i] != str2[i])
      return 0;
    else if (str1[i] == 0x0)
      return 1;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<okn_time_wait_nsec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x14(%rbp)
  jns    L59
  mov    $0xfffffffb,%eax
  jmp    L24
L59:
  movl   $0x0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  test   %eax,%eax
  je     L28
  cmp    $0x80,%eax
  je     L28
  mov    $0xffffffff,%eax
  jmp    L24
L28:
  nop
  mov    $0x1,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int okn_time_wait_nsec(int nsec) {
  if (nsec < 0)
    return -5;
  struct timespec spec = {0, nsec};
  switch (nanosleep(&spec, NULL)) {
  case 0:
  case EINTR:
    break;
  default:
    return -1;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<okn_time_wait_nsec>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L29
  movl   $0x0,(%rsp)
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  and    $0x7f,%al
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  ret
L29:
  mov    $0xfffffffb,%eax
  jmp    L5
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int okn_time_wait_nsec(int nsec) {
  if (nsec < 0)
    return -5;
  struct timespec spec = {0, nsec};
  switch (nanosleep(&spec, NULL)) {
  case 0:
  case EINTR:
    break;
  default:
    return -1;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<okn_time_wait_nsec>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L28
  mov    %edi,0x4(%rsp)
  xor    %esi,%esi
  mov    %rsp,%rdi
  movl   $0x0,(%rsp)
  call   <nanosleep@plt>
  and    $0x7f,%al
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0xfffffffb,%eax
  jmp    L2
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int okn_time_wait_nsec(int nsec) {
  if (nsec < 0)
    return -5;
  struct timespec spec = {0, nsec};
  switch (nanosleep(&spec, NULL)) {
  case 0:
  case EINTR:
    break;
  default:
    return -1;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<okn_time_wait_nsec>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L9
  mov    %edi,0x4(%rsp)
  xor    %esi,%esi
  mov    %rsp,%rdi
  movl   $0x0,(%rsp)
  call   <nanosleep@plt>
  and    $0x7f,%al
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0xfffffffb,%eax
  jmp    L7
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int okn_time_wait_nsec(int nsec) {
  if (nsec < 0)
    return -5;
  struct timespec spec = {0, nsec};
  switch (nanosleep(&spec, NULL)) {
  case 0:
  case EINTR:
    break;
  default:
    return -1;
  }
  return 1;
}
```