ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <Create2@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L78
L4:
  movl   $0x0,-0x14(%rbp)
  jmp    L74
L61:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L74:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L61
  addl   $0x1,-0x18(%rbp)
L78:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L4
  movl   $0x0,-0x18(%rbp)
  jmp    L31
L38:
  movl   $0x0,-0x14(%rbp)
  jmp    L75
L33:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L75:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L33
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x18(%rbp)
L31:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L38
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D49
type_infered: string
name: retrieve_data
arguments: label: D39
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string
name: retrieve_data
arguments: label: D25
type_infered: string

tool: D49: Please input n and m:

tool: D39: %d%d

tool: D3: Please input %d integers:


tool: D12: %d

tool: D25: %d 

assistant: ```c
int main() {
  int **p, m, n, i, j;
  printf("Please input n and m:");
  scanf("%d%d", &n, &m);
  p = Create2(n, m);
  printf("Please input %d integers:\n", n * m);
  for (i = 0; i < n; i++)
    for (j = 0; j < m; j++)
      scanf("%d", &p[i][j]);
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++)
      printf("%d ", p[i][j]);
    printf("\n");
    free(p[i]);
  }
  free(p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%edi
  mov    $0x0,%eax
  call   <Create2@plt>
  mov    %eax,%r13d
  cltq
  mov    %rax,0x8(%rsp)
  mov    0x14(%rsp),%esi
  imul   0x10(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L48
  movslq %r13d,%r13
  mov    %r13,%r15
  mov    $0x0,%r14d
  lea    D9(%rip),%r12
  jmp    L41
L60:
  mov    0x0(%rbp),%rax
  lea    (%rax,%rbx,4),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x10(%rsp)
  jg     L60
L112:
  add    $0x1,%r14d
  mov    0x14(%rsp),%eax
  add    $0x8,%r15
  cmp    %r14d,%eax
  jle    L56
L41:
  mov    %r15,%rbp
  mov    $0x0,%ebx
  cmpl   $0x0,0x10(%rsp)
  jg     L60
  jmp    L112
L56:
  test   %eax,%eax
  jle    L48
  mov    $0x0,%r14d
  lea    D0(%rip),%r12
  jmp    L85
L115:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x10(%rsp)
  jg     L115
L44:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x0(%r13),%rdi
  call   <free@plt>
  add    $0x1,%r14d
  add    $0x8,%r13
  cmp    %r14d,0x14(%rsp)
  jle    L48
L85:
  mov    %r13,%rbp
  mov    $0x0,%ebx
  cmpl   $0x0,0x10(%rsp)
  jg     L115
  jmp    L44
L48:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D45
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string
name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D25: Please input n and m:

tool: D45: %d%d

tool: D19: Please input %d integers:


tool: D9: %d

tool: D0: %d 

assistant: ```c
int main() {
  int **p, m, n, i, j;
  printf("Please input n and m:");
  scanf("%d%d", &n, &m);
  p = Create2(n, m);
  printf("Please input %d integers:\n", n * m);
  for (i = 0; i < n; i++)
    for (j = 0; j < m; j++)
      scanf("%d", &p[i][j]);
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++)
      printf("%d ", p[i][j]);
    printf("\n");
    free(p[i]);
  }
  free(p);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D48(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rsi
  xor    %eax,%eax
  lea    D47(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  xor    %eax,%eax
  call   <Create2@plt>
  mov    0x4(%rsp),%esi
  imul   (%rsp),%esi
  lea    D2(%rip),%rdi
  movslq %eax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L86
  mov    %r13,%rbp
  mov    %r13,%r15
  lea    D4(%rip),%r12
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L89:
  mov    (%rsp),%edx
  xor    %ebx,%ebx
  test   %edx,%edx
  jle    L32
  nopl   0x0(%rax)
L17:
  mov    (%r15),%rax
  mov    %r12,%rdi
  lea    (%rax,%rbx,4),%rsi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  cmp    %ebx,(%rsp)
  jg     L17
L32:
  mov    0x4(%rsp),%eax
  add    $0x1,%r14d
  add    $0x8,%r15
  cmp    %r14d,%eax
  jg     L89
  test   %eax,%eax
  jle    L86
  xor    %r14d,%r14d
  lea    D24(%rip),%r12
  nopl   0x0(%rax)
L72:
  mov    (%rsp),%eax
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L43
  nopl   0x0(%rax)
L59:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,4),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jg     L59
L43:
  mov    $0xa,%edi
  add    $0x1,%r14d
  add    $0x8,%rbp
  call   <putchar@plt>
  mov    -0x8(%rbp),%rdi
  call   <free@plt>
  cmp    %r14d,0x4(%rsp)
  jg     L72
L86:
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D48
type_infered: string
name: retrieve_data
arguments: tag: D47
type_infered: string
name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D24
type_infered: string

tool: D48: Please input n and m:

tool: D47: %d%d

tool: D2: Please input %d integers:


tool: D4: %d

tool: D24: %d 

assistant: ```c
int main() {
  int **p, m, n, i, j;
  printf("Please input n and m:");
  scanf("%d%d", &n, &m);
  p = Create2(n, m);
  printf("Please input %d integers:\n", n * m);
  for (i = 0; i < n; i++)
    for (j = 0; j < m; j++)
      scanf("%d", &p[i][j]);
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++)
      printf("%d ", p[i][j]);
    printf("\n");
    free(p[i]);
  }
  free(p);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D37(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rsi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  xor    %eax,%eax
  call   <Create2@plt>
  mov    0x4(%rsp),%esi
  imul   (%rsp),%esi
  lea    D44(%rip),%rdi
  movslq %eax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L21
  mov    (%rsp),%eax
  mov    %r13,%rbp
  mov    %r13,%r15
  xor    %r14d,%r14d
  lea    D21(%rip),%r12
  test   %eax,%eax
  jle    L61
  xchg   %ax,%ax
L113:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L106:
  mov    (%r15),%rax
  mov    %r12,%rdi
  lea    (%rax,%rbx,4),%rsi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jg     L106
  mov    0x4(%rsp),%edx
  add    $0x1,%r14d
  cmp    %edx,%r14d
  jge    L5
  add    $0x8,%r15
  test   %eax,%eax
  jg     L113
L61:
  add    $0x1,%r14d
  cmp    %edx,%r14d
  jge    L5
L88:
  xor    %r14d,%r14d
  lea    D6(%rip),%r12
  nopl   0x0(%rax)
L50:
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L18
  cs nopw 0x0(%rax,%rax,1)
L98:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,4),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jg     L98
L18:
  mov    $0xa,%edi
  add    $0x1,%r14d
  add    $0x8,%rbp
  call   <putchar@plt>
  mov    -0x8(%rbp),%rdi
  call   <free@plt>
  cmp    %r14d,0x4(%rsp)
  jle    L21
  mov    (%rsp),%eax
  jmp    L50
L5:
  test   %edx,%edx
  jg     L88
  nopl   (%rax)
L21:
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L112
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L112:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D37
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D44
type_infered: string
name: parse_data
arguments: data_tag: D21
type_infered: string
name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D37: Please input n and m:

tool: D27: %d%d

tool: D44: Please input %d integers:


tool: D21: %d

tool: D6: %d 

assistant: ```c
int main() {
  int **p, m, n, i, j;
  printf("Please input n and m:");
  scanf("%d%d", &n, &m);
  p = Create2(n, m);
  printf("Please input %d integers:\n", n * m);
  for (i = 0; i < n; i++)
    for (j = 0; j < m; j++)
      scanf("%d", &p[i][j]);
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++)
      printf("%d ", p[i][j]);
    printf("\n");
    free(p[i]);
  }
  free(p);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<evaluationStart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x20(%rbp),%xmm1
  mov    -0x18(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  D7(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type: f64

tool: D7: 1000000

assistant: ```c
extern double evaluationStart(void *data) {
  struct timeval tv;
  (void)data;
  gettimeofday(&tv, NULL);
  return tv.tv_usec + tv.tv_sec * 1000000.;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<evaluationStart>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D7(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: f64

tool: D7: 1000000

assistant: ```c
extern double evaluationStart(void *data) {
  struct timeval tv;
  (void)data;
  gettimeofday(&tv, NULL);
  return tv.tv_usec + tv.tv_sec * 1000000.;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<evaluationStart>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D6(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: f64

tool: D6: 1000000

assistant: ```c
extern double evaluationStart(void *data) {
  struct timeval tv;
  (void)data;
  gettimeofday(&tv, NULL);
  return tv.tv_usec + tv.tv_sec * 1000000.;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<evaluationStart>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D3(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: f64

tool: D3: 1000000

assistant: ```c
extern double evaluationStart(void *data) {
  struct timeval tv;
  (void)data;
  gettimeofday(&tv, NULL);
  return tv.tv_usec + tv.tv_sec * 1000000.;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sprint_mov_direct_to_direct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: MOV   0x%02X, 0x%02X                

assistant: ```c
void sprint_mov_direct_to_direct(char *str, uint8_t direct_src, uint8_t direct_dst) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", "
          "0x%02X"
          "                ",
          direct_dst, direct_src);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sprint_mov_direct_to_direct>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%ecx
  lea    D7(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: MOV   0x%02X, 0x%02X                

assistant: ```c
void sprint_mov_direct_to_direct(char *str, uint8_t direct_src, uint8_t direct_dst) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", "
          "0x%02X"
          "                ",
          direct_dst, direct_src);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sprint_mov_direct_to_direct>:
  endbr64
  mov    %esi,%ecx
  lea    D9(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: MOV   0x%02X, 0x%02X                

assistant: ```c
void sprint_mov_direct_to_direct(char *str, uint8_t direct_src, uint8_t direct_dst) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", "
          "0x%02X"
          "                ",
          direct_dst, direct_src);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sprint_mov_direct_to_direct>:
  endbr64
  mov    %esi,%ecx
  lea    D4(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string

tool: D4: MOV   0x%02X, 0x%02X                

assistant: ```c
void sprint_mov_direct_to_direct(char *str, uint8_t direct_src, uint8_t direct_dst) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", "
          "0x%02X"
          "                ",
          direct_dst, direct_src);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <__xalloc_failed@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *__xmalloc(const char *_file, int _line, size_t size) {
  void *p = malloc(size);
  if (!p)
    __xalloc_failed(_file, _line, (size));
  return p;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__xmalloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L16:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <__xalloc_failed@plt>
  jmp    L16
```

assistant: ```c
void *__xmalloc(const char *_file, int _line, size_t size) {
  void *p = malloc(size);
  if (!p)
    __xalloc_failed(_file, _line, (size));
  return p;
  ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__xmalloc>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    %r13,%rdx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <__xalloc_failed@plt>
  jmp    L18
```

assistant: ```c
void *__xmalloc(const char *_file, int _line, size_t size) {
  void *p = malloc(size);
  if (!p)
    __xalloc_failed(_file, _line, (size));
  return p;
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__xmalloc>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  mov    %r13,%rdx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <__xalloc_failed@plt>
  jmp    L13
```

assistant: ```c
void *__xmalloc(const char *_file, int _line, size_t size) {
  void *p = malloc(size);
  if (!p)
    __xalloc_failed(_file, _line, (size));
  return p;
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
FILE *test_open(const char *filename, const char *mode) {
  FILE *file;
  file = fopen(filename, mode);
  return file;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_open>:
  endbr64
  sub    $0x8,%rsp
  call   <fopen@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
FILE *test_open(const char *filename, const char *mode) {
  FILE *file;
  file = fopen(filename, mode);
  return file;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_open>:
  endbr64
  jmp    1050 <fopen@plt>
```

assistant: ```c
FILE *test_open(const char *filename, const char *mode) {
  FILE *file;
  file = fopen(filename, mode);
  return file;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_open>:
  endbr64
  jmp    1050 <fopen@plt>
```

assistant: ```c
FILE *test_open(const char *filename, const char *mode) {
  FILE *file;
  file = fopen(filename, mode);
  return file;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L41
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jne    L90
L41:
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L58
L69:
  movl   $0x0,-0xc(%rbp)
  jmp    L115
L96:
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L115:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L96
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L111:
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L111
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x2,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L90:
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L69
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L58
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L21:
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L21
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L58:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D63
type_guessed: string
name: extract_symbolic_data
arguments: label: D77
type_guessed: string
name: extract_symbolic_data
arguments: label: D51
type_guessed: string
name: extract_symbolic_data
arguments: label: D79
type_guessed: string
name: extract_symbolic_data
arguments: label: D72
type_guessed: string
name: extract_symbolic_data
arguments: label: D66
type_guessed: string

tool: D63: 
Enter the size of tree


tool: D77: %d

tool: D51: cannot build a three

tool: D79:  

tool: D72: *

tool: D66: 


assistant: ```c
main() {
  int size, spaces, stars = 1;
  int i;
  printf("\nEnter the size of tree\n");
  scanf("%d", &size);
  spaces = size - 1;
  if (size == 0 || size == 1) {
    printf("cannot build a three");
  } else {
    while (spaces != -1) {
      for (i = 0; i < spaces; i++) {
        printf(" ");
      }
      for (i = 0; i < stars; i++) {
        printf("*");
      }
      printf("\n");
      stars = stars + 2;
      spaces = spaces - 1;
    }
    if (spaces == -1) {
      for (i = 0; i < size - 1; i++) {
        printf(" ");
      }
      printf("*");
    }
  }
}
```