ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<salto_atras>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L67
L99:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  subl   $0x1,-0x18(%rbp)
  subl   $0x1,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L90
  subl   $0x1,-0x24(%rbp)
L90:
  mov    -0x24(%rbp),%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %esi,%r8d
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <impresionMapa@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L83
L66:
  addl   $0x1,-0x8(%rbp)
L83:
  cmpl   $0x5f5e0ff,-0x8(%rbp)
  jle    L66
  addl   $0x1,-0xc(%rbp)
L67:
  cmpl   $0x1,-0xc(%rbp)
  jle    L99
  movl   $0x0,-0xc(%rbp)
  jmp    L78
L19:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L69
  subl   $0x1,-0x24(%rbp)
L69:
  mov    -0x24(%rbp),%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %esi,%r8d
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <impresionMapa@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L89
L94:
  addl   $0x1,-0x4(%rbp)
L89:
  cmpl   $0x5f5e0ff,-0x4(%rbp)
  jle    L94
  addl   $0x1,-0xc(%rbp)
L78:
  cmpl   $0x1,-0xc(%rbp)
  jle    L19
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D34
type: string
name: parse_data
arguments: data_tag: D36
type: string

tool: D34: clear

tool: D36: cls

assistant: ```c
void salto_atras(int posicioHorizontalMario, int posicionVerticalMario, int nivel1[14][212], int posicionHorizontalMarioRelativa) {
  int i, j;
  for (i = 0; i < 2; ++i) {
    system("clear");
    system("cls");
    posicionVerticalMario--;
    posicionVerticalMario--;
    if (posicionHorizontalMarioRelativa > 0)
      posicionHorizontalMarioRelativa--;
    impresionMapa(nivel1, 40, posicioHorizontalMario, posicionVerticalMario, posicionHorizontalMarioRelativa);
    for (int j = 0; j < 100000000; ++j) {
    }
  }
  for (i = 0; i < 2; ++i) {
    system("clear");
    system("cls");
    posicionVerticalMario++;
    posicionVerticalMario++;
    if (posicionHorizontalMarioRelativa > 0)
      posicionHorizontalMarioRelativa--;
    impresionMapa(nivel1, 40, posicioHorizontalMario, posicionVerticalMario, posicionHorizontalMarioRelativa);
    for (int j = 0; j < 100000000; ++j) {
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<salto_atras>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %rdx,%r14
  mov    %ecx,%ebx
  lea    -0x4(%rsi),%r15d
  mov    %esi,%ebp
L35:
  lea    D25(%rip),%rdi
  call   <system@plt>
  lea    D22(%rip),%rdi
  call   <system@plt>
  sub    $0x2,%ebp
  test   %ebx,%ebx
  setg   %al
  movzbl %al,%eax
  sub    %eax,%ebx
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    $0x28,%esi
  mov    %r14,%rdi
  call   <impresionMapa@plt>
  mov    $0x5f5e100,%eax
L3:
  sub    $0x1,%eax
  jne    L3
  cmp    %ebp,%r15d
  jne    L35
  lea    -0x4(%r12),%ebp
  lea    D25(%rip),%r15
L4:
  mov    %r15,%rdi
  call   <system@plt>
  lea    D22(%rip),%rdi
  call   <system@plt>
  add    $0x2,%ebp
  test   %ebx,%ebx
  setg   %al
  movzbl %al,%eax
  sub    %eax,%ebx
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    $0x28,%esi
  mov    %r14,%rdi
  call   <impresionMapa@plt>
  mov    $0x5f5e100,%eax
L26:
  sub    $0x1,%eax
  jne    L26
  cmp    %ebp,%r12d
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D22
type_guessed: string

tool: D25: clear

tool: D22: cls

assistant: ```c
void salto_atras(int posicioHorizontalMario, int posicionVerticalMario, int nivel1[14][212], int posicionHorizontalMarioRelativa) {
  int i, j;
  for (i = 0; i < 2; ++i) {
    system("clear");
    system("cls");
    posicionVerticalMario--;
    posicionVerticalMario--;
    if (posicionHorizontalMarioRelativa > 0)
      posicionHorizontalMarioRelativa--;
    impresionMapa(nivel1, 40, posicioHorizontalMario, posicionVerticalMario, posicionHorizontalMarioRelativa);
    for (int j = 0; j < 100000000; ++j) {
    }
  }
  for (i = 0; i < 2; ++i) {
    system("clear");
    system("cls");
    posicionVerticalMario++;
    posicionVerticalMario++;
    if (posicionHorizontalMarioRelativa > 0)
      posicionHorizontalMarioRelativa--;
    impresionMapa(nivel1, 40, posicioHorizontalMario, posicionVerticalMario, posicionHorizontalMarioRelativa);
    for (int j = 0; j < 100000000; ++j) {
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<salto_atras>:
  endbr64
  push   %r15
  lea    D17(%rip),%r15
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r15,%rdi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  call   <system@plt>
  mov    %r14,%rdi
  call   <system@plt>
  mov    %r13d,0x8(%rsp)
  lea    -0x2(%r13),%r10d
  test   %ebx,%ebx
  jle    1080 <salto_atras.cold>
  lea    -0x1(%rbx),%r13d
  mov    %r10d,%ecx
  mov    %r12d,%edx
  mov    $0x28,%esi
  mov    %r13d,%r8d
  mov    %rbp,%rdi
  mov    %r10d,0xc(%rsp)
  sub    $0x2,%ebx
  call   <impresionMapa@plt>
  mov    %r15,%rdi
  call   <system@plt>
  mov    %r14,%rdi
  call   <system@plt>
  test   %r13d,%r13d
  mov    0x8(%rsp),%eax
  mov    %r12d,%edx
  cmovne %ebx,%r13d
  mov    $0x28,%esi
  mov    %rbp,%rdi
  lea    -0x4(%rax),%ecx
  mov    %r13d,%r8d
  call   <impresionMapa@plt>
  mov    %r15,%rdi
  call   <system@plt>
  mov    %r14,%rdi
  call   <system@plt>
  test   %r13d,%r13d
  mov    0xc(%rsp),%r10d
  jle    L7
  lea    -0x1(%r13),%ebx
  mov    %r12d,%edx
  mov    %r10d,%ecx
  mov    $0x28,%esi
  mov    %ebx,%r8d
  mov    %rbp,%rdi
  call   <impresionMapa@plt>
  mov    %r15,%rdi
  call   <system@plt>
  mov    %r14,%rdi
  call   <system@plt>
  test   %ebx,%ebx
  lea    -0x2(%r13),%r8d
  mov    0x8(%rsp),%ecx
  cmove  %ebx,%r8d
  add    $0x18,%rsp
  mov    %r12d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  mov    $0x28,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <impresionMapa@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string

tool: D17: clear

tool: D18: cls

assistant: ```c
void salto_atras(int posicioHorizontalMario, int posicionVerticalMario, int nivel1[14][212], int posicionHorizontalMarioRelativa) {
  int i, j;
  for (i = 0; i < 2; ++i) {
    system("clear");
    system("cls");
    posicionVerticalMario--;
    posicionVerticalMario--;
    if (posicionHorizontalMarioRelativa > 0)
      posicionHorizontalMarioRelativa--;
    impresionMapa(nivel1, 40, posicioHorizontalMario, posicionVerticalMario, posicionHorizontalMarioRelativa);
    for (int j = 0; j < 100000000; ++j) {
    }
  }
  for (i = 0; i < 2; ++i) {
    system("clear");
    system("cls");
    posicionVerticalMario++;
    posicionVerticalMario++;
    if (posicionHorizontalMarioRelativa > 0)
      posicionHorizontalMarioRelativa--;
    impresionMapa(nivel1, 40, posicioHorizontalMario, posicionVerticalMario, posicionHorizontalMarioRelativa);
    for (int j = 0; j < 100000000; ++j) {
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L14
L13:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    $0x0,%eax
  jmp    L4
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(s1, s2)
char *s1, *s2;
{
  while (*s1 == *s2++)
    if (*s1++ == '\0')
      return 0;
  return (*s1 - *--s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  mov    $0x0,%eax
L9:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L15
  add    $0x1,%rax
  test   %dl,%dl
  jne    L9
  mov    $0x0,%eax
  ret
L15:
  movsbl %dl,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(s1, s2)
char *s1, *s2;
{
  while (*s1 == *s2++)
    if (*s1++ == '\0')
      return 0;
  return (*s1 - *--s2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rax
  test   %dl,%dl
  je     L14
L3:
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L13
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcmp(s1, s2)
char *s1, *s2;
{
  while (*s1 == *s2++)
    if (*s1++ == '\0')
      return 0;
  return (*s1 - *--s2);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rax
  test   %dl,%dl
  je     L12
L14:
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L11
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strcmp(s1, s2)
char *s1, *s2;
{
  while (*s1 == *s2++)
    if (*s1++ == '\0')
      return 0;
  return (*s1 - *--s2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <read_until_delim@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L5
  subl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_str(int s, char *buf, size_t len) {
  int r = read_until_delim(s, buf, len, 0);
  if (r > 0)
    r--;
  return (r);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_str>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  call   <read_until_delim@plt>
  test   %eax,%eax
  setg   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int get_str(int s, char *buf, size_t len) {
  int r = read_until_delim(s, buf, len, 0);
  if (r > 0)
    r--;
  return (r);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_str>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  call   <read_until_delim@plt>
  xor    %edx,%edx
  test   %eax,%eax
  setg   %dl
  add    $0x8,%rsp
  sub    %edx,%eax
  ret
```

assistant: ```c
int get_str(int s, char *buf, size_t len) {
  int r = read_until_delim(s, buf, len, 0);
  if (r > 0)
    r--;
  return (r);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_str>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  call   <read_until_delim@plt>
  xor    %edx,%edx
  test   %eax,%eax
  setg   %dl
  add    $0x8,%rsp
  sub    %edx,%eax
  ret
```

assistant: ```c
int get_str(int s, char *buf, size_t len) {
  int r = read_until_delim(s, buf, len, 0);
  if (r > 0)
    r--;
  return (r);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_only_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x26,-0x9(%rbp)
  lea    -0xb(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xa(%rbp)
  jmp    L28
L61:
  cmpb   $0xa,-0xa(%rbp)
  jne    L51
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xb(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xa(%rbp)
  jmp    L28
L51:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L45:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x9(%rbp)
  cmpb   $0xa,-0x9(%rbp)
  jne    L45
  lea    -0xb(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xa(%rbp)
L28:
  movzbl -0xb(%rbp),%eax
  cmp    $0x6e,%al
  je     L69
  movzbl -0xb(%rbp),%eax
  cmp    $0x79,%al
  jne    L61
L69:
  cmpb   $0xa,-0xa(%rbp)
  jne    L61
  movzbl -0xb(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D30
type_infered: string
name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D30: %c

tool: D9: Invalid [y/n]:

assistant: ```c
char get_only_char() {
  char n;
  char ch = '&';
  printf("%s", "");
  scanf("%c", &n);
  char f;
  f = getchar();
  while ((n != 'n' && n != 'y') || f != '\n') {
    if (f == '\n') {
      printf("Invalid [y/n]:");
      scanf("%c", &n);
      f = getchar();
    } else {
      printf("Invalid [y/n]:");
      while ((ch = getchar()) != '\n')
        ;
      scanf("%c", &n);
      f = getchar();
    }
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_only_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movzbl 0x7(%rsp),%edx
  cmp    $0x6e,%dl
  setne  %sil
  cmp    $0x79,%dl
  setne  %cl
  test   %cl,%sil
  jne    L79
  cmp    $0xa,%al
  je     L71
L79:
  lea    D23(%rip),%r12
  lea    0x7(%rsp),%rbp
  lea    D19(%rip),%rbx
L6:
  cmp    $0xa,%al
  jne    L1
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
L29:
  movzbl 0x7(%rsp),%edx
  cmp    $0x6e,%dl
  setne  %sil
  cmp    $0x79,%dl
  setne  %cl
  test   %cl,%sil
  jne    L6
  cmp    $0xa,%al
  jne    L6
L71:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L58:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L58
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  jmp    L29
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string

tool: D19: %c

tool: D23: Invalid [y/n]:

assistant: ```c
char get_only_char() {
  char n;
  char ch = '&';
  printf("%s", "");
  scanf("%c", &n);
  char f;
  f = getchar();
  while ((n != 'n' && n != 'y') || f != '\n') {
    if (f == '\n') {
      printf("Invalid [y/n]:");
      scanf("%c", &n);
      f = getchar();
    } else {
      printf("Invalid [y/n]:");
      while ((ch = getchar()) != '\n')
        ;
      scanf("%c", &n);
      f = getchar();
    }
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_only_char>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L69:
  cmp    $0x79,%r8b
  je     L53
  cmp    $0xa,%al
  jne    L67
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L66:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
L46:
  movzbl 0x7(%rsp),%r8d
  cmp    $0x6e,%r8b
  jne    L69
L53:
  cmp    $0xa,%al
  je     L5
L67:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L27
  jmp    L66
  nopl   (%rax)
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D11: Invalid [y/n]:

tool: D8: %c

assistant: ```c
char get_only_char() {
  char n;
  char ch = '&';
  printf("%s", "");
  scanf("%c", &n);
  char f;
  f = getchar();
  while ((n != 'n' && n != 'y') || f != '\n') {
    if (f == '\n') {
      printf("Invalid [y/n]:");
      scanf("%c", &n);
      f = getchar();
    } else {
      printf("Invalid [y/n]:");
      while ((ch = getchar()) != '\n')
        ;
      scanf("%c", &n);
      f = getchar();
    }
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_only_char>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L2:
  cmp    $0x79,%r8b
  je     L29
  cmp    $0xa,%al
  jne    L62
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L67:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
L30:
  movzbl 0x7(%rsp),%r8d
  cmp    $0x6e,%r8b
  jne    L2
L29:
  cmp    $0xa,%al
  je     L72
L62:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L12
  jmp    L67
  nopl   (%rax)
L72:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D1: Invalid [y/n]:

tool: D3: %c

assistant: ```c
char get_only_char() {
  char n;
  char ch = '&';
  printf("%s", "");
  scanf("%c", &n);
  char f;
  f = getchar();
  while ((n != 'n' && n != 'y') || f != '\n') {
    if (f == '\n') {
      printf("Invalid [y/n]:");
      scanf("%c", &n);
      f = getchar();
    } else {
      printf("Invalid [y/n]:");
      while ((ch = getchar()) != '\n')
        ;
      scanf("%c", &n);
      f = getchar();
    }
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fts_palloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  addq   $0x100,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jae    L30
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L58
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L58:
  mov    -0x18(%rbp),%rax
  movq   $0x0,0x8(%rax)
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L13
L30:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L55
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L43
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L43:
  mov    -0x18(%rbp),%rax
  movq   $0x0,0x8(%rax)
  mov    $0x1,%eax
  jmp    L13
L55:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,0x8(%rax)
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int fts_palloc(FTS *sp, size_t more) {
  char *p;
  more += 256;
  if (sp->fts_pathlen + more < sp->fts_pathlen) {
    if (sp->fts_path)
      free(sp->fts_path);
    sp->fts_path = NULL;
    errno = ENAMETOOLONG;
    return (1);
  }
  sp->fts_pathlen += more;
  p = realloc(sp->fts_path, sp->fts_pathlen);
  if (p == NULL) {
    if (sp->fts_path)
      free(sp->fts_path);
    sp->fts_path = NULL;
    return (1);
  }
  sp->fts_path = p;
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fts_palloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  lea    0x100(%rax,%rsi,1),%rsi
  cmp    %rsi,%rax
  jbe    L23
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L3
  call   <free@plt>
L3:
  movq   $0x0,0x8(%rbx)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
L25:
  pop    %rbx
  ret
L23:
  mov    %rsi,(%rdi)
  mov    0x8(%rdi),%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L40
  mov    %rax,0x8(%rbx)
  mov    $0x0,%eax
  jmp    L25
L40:
  mov    0x8(%rbx),%rdi
  test   %rdi,%rdi
  je     L15
  call   <free@plt>
L15:
  movq   $0x0,0x8(%rbx)
  mov    $0x1,%eax
  jmp    L25
```

assistant: ```c
int fts_palloc(FTS *sp, size_t more) {
  char *p;
  more += 256;
  if (sp->fts_pathlen + more < sp->fts_pathlen) {
    if (sp->fts_path)
      free(sp->fts_path);
    sp->fts_path = NULL;
    errno = ENAMETOOLONG;
    return (1);
  }
  sp->fts_pathlen += more;
  p = realloc(sp->fts_path, sp->fts_pathlen);
  if (p == NULL) {
    if (sp->fts_path)
      free(sp->fts_path);
    sp->fts_path = NULL;
    return (1);
  }
  sp->fts_path = p;
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fts_palloc>:
  endbr64
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  mov    0x8(%rdi),%rdi
  lea    0x100(%rax,%rsi,1),%rsi
  cmp    %rsi,%rax
  jbe    L25
  test   %rdi,%rdi
  je     L24
  call   <free@plt>
L24:
  mov    D14(%rip),%rax
  movq   $0x0,0x8(%rbx)
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rsi,(%rbx)
  call   <realloc@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,0x8(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L10:
  mov    0x8(%rbx),%rdi
  test   %rdi,%rdi
  je     L32
  call   <free@plt>
L32:
  movq   $0x0,0x8(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fts_palloc(FTS *sp, size_t more) {
  char *p;
  more += 256;
  if (sp->fts_pathlen + more < sp->fts_pathlen) {
    if (sp->fts_path)
      free(sp->fts_path);
    sp->fts_path = NULL;
    errno = ENAMETOOLONG;
    return (1);
  }
  sp->fts_pathlen += more;
  p = realloc(sp->fts_path, sp->fts_pathlen);
  if (p == NULL) {
    if (sp->fts_path)
      free(sp->fts_path);
    sp->fts_path = NULL;
    return (1);
  }
  sp->fts_path = p;
  return (0);
}
```