ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D32
type_guessed: string
name: extract_symbolic_data
arguments: label: D46
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D32: fujitsu usb touchscreen utility


tool: D46: usage:


tool: D29: 	orientation 0|1|2|3: set driver orientation


tool: D20: 	calibrate 0|1: activate calibration mode


tool: D4: 	writecalibrate a b c d: write calibration values


assistant: ```c
void show_help(void) {
  printf("fujitsu usb touchscreen utility\n");
  printf("usage:\n");
  printf("	orientation 0|1|2|3: set driver orientation\n");
  printf("	calibrate 0|1: activate calibration mode\n");
  printf("	writecalibrate a b c d: write calibration values\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D25
type_infered: string
name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D1: fujitsu usb touchscreen utility


tool: D23: usage:


tool: D14: 	orientation 0|1|2|3: set driver orientation


tool: D25: 	calibrate 0|1: activate calibration mode


tool: D3: 	writecalibrate a b c d: write calibration values


assistant: ```c
void show_help(void) {
  printf("fujitsu usb touchscreen utility\n");
  printf("usage:\n");
  printf("	orientation 0|1|2|3: set driver orientation\n");
  printf("	calibrate 0|1: activate calibration mode\n");
  printf("	writecalibrate a b c d: write calibration values\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_addsymbol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L4
  mov    $0x0,%eax
  call   <usage@plt>
L4:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <m5_addsymbol@plt>
  nop
  leave
  ret
```

assistant: ```c
void do_addsymbol(int argc, char *argv[]) {
  if (argc != 2)
    usage();
  uint64_t addr = strtoul(argv[0], NULL, 0);
  char *symbol = argv[1];
  m5_addsymbol(addr, symbol);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<do_addsymbol>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jne    L6
L9:
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    (%rbx),%rdi
  call   <strtoul@plt>
  mov    %eax,%edi
  mov    0x8(%rbx),%rsi
  call   <m5_addsymbol@plt>
  pop    %rbx
  ret
L6:
  mov    $0x0,%eax
  call   <usage@plt>
  jmp    L9
```

assistant: ```c
void do_addsymbol(int argc, char *argv[]) {
  if (argc != 2)
    usage();
  uint64_t addr = strtoul(argv[0], NULL, 0);
  char *symbol = argv[1];
  m5_addsymbol(addr, symbol);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_addsymbol>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  je     L7
  xor    %eax,%eax
  call   <usage@plt>
L7:
  mov    (%rbx),%rdi
  xor    %esi,%esi
  xor    %edx,%edx
  call   <strtoul@plt>
  mov    0x8(%rbx),%rsi
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <m5_addsymbol@plt>
```

assistant: ```c
void do_addsymbol(int argc, char *argv[]) {
  if (argc != 2)
    usage();
  uint64_t addr = strtoul(argv[0], NULL, 0);
  char *symbol = argv[1];
  m5_addsymbol(addr, symbol);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_addsymbol>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  je     L4
  xor    %eax,%eax
  call   <usage@plt>
L4:
  mov    (%rbx),%rdi
  xor    %esi,%esi
  xor    %edx,%edx
  call   <strtoul@plt>
  mov    0x8(%rbx),%rsi
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <m5_addsymbol@plt>
```

assistant: ```c
void do_addsymbol(int argc, char *argv[]) {
  if (argc != 2)
    usage();
  uint64_t addr = strtoul(argv[0], NULL, 0);
  char *symbol = argv[1];
  m5_addsymbol(addr, symbol);
}
```
user: What is the c source code of the assembly code below:

```asm
<gpio_filter_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D39(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L98
  mov    $0x1,%eax
  jmp    L2
L98:
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L27
  mov    $0x1,%eax
  jmp    L2
L27:
  mov    -0x8(%rbp),%rax
  lea    D29(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L29
  mov    $0x1,%eax
  jmp    L2
L29:
  mov    -0x8(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L90
  mov    $0x1,%eax
  jmp    L2
L90:
  mov    -0x8(%rbp),%rax
  lea    D42(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L87
  mov    $0x1,%eax
  jmp    L2
L87:
  mov    $0x0,%eax
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D16
datatype: string
name: extract_symbolic_data
arguments: data_tag: D42
datatype: string

tool: D39: device

tool: D8: subsystem

tool: D29: driver

tool: D16: chip

tool: D42: power

assistant: ```c
int gpio_filter_cb(const char *name) {
  if (!strcmp(name, "device"))
    return 1;
  if (!strcmp(name, "subsystem"))
    return 1;
  if (!strcmp(name, "driver"))
    return 1;
  if (strstr(name, "chip"))
    return 1;
  if (!strcmp(name, "power"))
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gpio_filter_cb>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L1
  lea    D44(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L1
  lea    D23(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L4
L1:
  pop    %rbx
  ret
L4:
  lea    D43(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L1
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L1
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string
name: unpack_data
arguments: tag: D44
type_guessed: string
name: unpack_data
arguments: tag: D23
type_guessed: string
name: unpack_data
arguments: tag: D43
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D2: device

tool: D44: subsystem

tool: D23: driver

tool: D43: chip

tool: D0: power

assistant: ```c
int gpio_filter_cb(const char *name) {
  if (!strcmp(name, "device"))
    return 1;
  if (!strcmp(name, "subsystem"))
    return 1;
  if (!strcmp(name, "driver"))
    return 1;
  if (strstr(name, "chip"))
    return 1;
  if (!strcmp(name, "power"))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<gpio_filter_cb>:
  endbr64
  push   %rbp
  lea    D44(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %eax,%eax
  je     L37
  lea    D38(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L37
  lea    D33(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L37
  lea    D48(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L37
  mov    %rbp,%rdi
  lea    D46(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D44
type_guessed: string
name: parse_data
arguments: tag: D38
type_guessed: string
name: parse_data
arguments: tag: D33
type_guessed: string
name: parse_data
arguments: tag: D48
type_guessed: string
name: parse_data
arguments: tag: D46
type_guessed: string

tool: D44: device

tool: D38: subsystem

tool: D33: driver

tool: D48: chip

tool: D46: power

assistant: ```c
int gpio_filter_cb(const char *name) {
  if (!strcmp(name, "device"))
    return 1;
  if (!strcmp(name, "subsystem"))
    return 1;
  if (!strcmp(name, "driver"))
    return 1;
  if (strstr(name, "chip"))
    return 1;
  if (!strcmp(name, "power"))
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gpio_filter_cb>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %eax,%eax
  je     L14
  lea    D47(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L14
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L14
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L14
  mov    %rbp,%rdi
  lea    D32(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string
name: unpack_data
arguments: data_tag: D47
datatype: string
name: unpack_data
arguments: data_tag: D22
datatype: string
name: unpack_data
arguments: data_tag: D39
datatype: string
name: unpack_data
arguments: data_tag: D32
datatype: string

tool: D9: device

tool: D47: subsystem

tool: D22: driver

tool: D39: chip

tool: D32: power

assistant: ```c
int gpio_filter_cb(const char *name) {
  if (!strcmp(name, "device"))
    return 1;
  if (!strcmp(name, "subsystem"))
    return 1;
  if (!strcmp(name, "driver"))
    return 1;
  if (strstr(name, "chip"))
    return 1;
  if (!strcmp(name, "power"))
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L33
L8:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    $0x0,%eax
  jmp    L0
L33:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0xc(%rbp),%edx
  cmp    %dl,%al
  jne    L8
  mov    -0x8(%rbp),%rax
L0:
  pop    %rbp
  ret
```

assistant: ```c
char *_strchr(const char *s, int c) {
  while (*s != (char)c)
    if (*s++ == '\0')
      return NULL;
  return (char *)s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_strchr>:
  endbr64
  mov    %rdi,%rax
L16:
  movzbl (%rax),%edx
  cmp    %sil,%dl
  je     L6
  add    $0x1,%rax
  test   %dl,%dl
  jne    L16
  mov    $0x0,%eax
  ret
L6:
  ret
```

assistant: ```c
char *_strchr(const char *s, int c) {
  while (*s != (char)c)
    if (*s++ == '\0')
      return NULL;
  return (char *)s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_strchr>:
  endbr64
  mov    %rdi,%rax
  jmp    L23
  nopl   0x0(%rax)
L21:
  add    $0x1,%rax
  test   %dl,%dl
  je     L14
L23:
  movzbl (%rax),%edx
  cmp    %sil,%dl
  jne    L21
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *_strchr(const char *s, int c) {
  while (*s != (char)c)
    if (*s++ == '\0')
      return NULL;
  return (char *)s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_strchr>:
  endbr64
  mov    %rdi,%rax
  jmp    L25
  nopl   0x0(%rax)
L17:
  add    $0x1,%rax
  test   %dl,%dl
  je     L6
L25:
  movzbl (%rax),%edx
  cmp    %sil,%dl
  jne    L17
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *_strchr(const char *s, int c) {
  while (*s != (char)c)
    if (*s++ == '\0')
      return NULL;
  return (char *)s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<jam_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x6(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movsbl -0x6(%rbp),%eax
  movsbl -0x5(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L18
  cmpb   $0x0,-0x6(%rbp)
  je     L18
  cmpb   $0x0,-0x5(%rbp)
  jne    L7
L18:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int jam_strcmp(char *left, char *right) {
  int result = 0;
  char l, r;
  do {
    l = *left;
    r = *right;
    result = l - r;
    ++left;
    ++right;
  } while ((result == 0) && (l != '\0') && (r != '\0'));
  return (result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<jam_strcmp>:
  endbr64
  mov    $0x0,%edx
L3:
  movzbl (%rdi,%rdx,1),%r8d
  movzbl (%rsi,%rdx,1),%ecx
  movsbl %r8b,%eax
  movsbl %cl,%r9d
  sub    %r9d,%eax
  add    $0x1,%rdx
  test   %r8b,%r8b
  setne  %r8b
  test   %cl,%cl
  setne  %cl
  test   %cl,%r8b
  je     L18
  test   %eax,%eax
  je     L3
L18:
  ret
```

assistant: ```c
int jam_strcmp(char *left, char *right) {
  int result = 0;
  char l, r;
  do {
    l = *left;
    r = *right;
    result = l - r;
    ++left;
    ++right;
  } while ((result == 0) && (l != '\0') && (r != '\0'));
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<jam_strcmp>:
  endbr64
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L15:
  movsbl (%rdi,%rdx,1),%eax
  movsbl (%rsi,%rdx,1),%ecx
  mov    %eax,%r8d
  sub    %ecx,%eax
  jne    L6
  test   %r8b,%r8b
  je     L6
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L15
  xor    %eax,%eax
L6:
  ret
```

assistant: ```c
int jam_strcmp(char *left, char *right) {
  int result = 0;
  char l, r;
  do {
    l = *left;
    r = *right;
    result = l - r;
    ++left;
    ++right;
  } while ((result == 0) && (l != '\0') && (r != '\0'));
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<jam_strcmp>:
  endbr64
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L8:
  movsbl (%rdi,%rdx,1),%eax
  movsbl (%rsi,%rdx,1),%ecx
  mov    %eax,%r8d
  sub    %ecx,%eax
  jne    L11
  test   %r8b,%r8b
  je     L11
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  xor    %eax,%eax
L11:
  ret
```

assistant: ```c
int jam_strcmp(char *left, char *right) {
  int result = 0;
  char l, r;
  do {
    l = *left;
    r = *right;
    result = l - r;
    ++left;
    ++right;
  } while ((result == 0) && (l != '\0') && (r != '\0'));
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_channel_from_frequency>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x96b,-0x4(%rbp)
  jle    L29
  cmpl   $0x9a8,-0x4(%rbp)
  jg     L29
  mov    -0x4(%rbp),%eax
  sub    $0x967,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L69
L29:
  cmpl   $0x9b4,-0x4(%rbp)
  jne    L56
  mov    $0xe,%eax
  jmp    L69
L56:
  cmpl   $0x1387,-0x4(%rbp)
  jle    L46
  cmpl   $0x17d4,-0x4(%rbp)
  jg     L46
  mov    -0x4(%rbp),%eax
  sub    $0x1388,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L69
L46:
  mov    $0xffffffff,%eax
L69:
  pop    %rbp
  ret
```

assistant: ```c
int get_channel_from_frequency(int32_t frequency) {
  if (frequency >= 2412 && frequency <= 2472)
    return (frequency - 2407) / 5;
  if (frequency == 2484)
    return 14;
  if (frequency >= 5000 && frequency <= 6100)
    return (frequency - 5000) / 5;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_channel_from_frequency>:
  endbr64
  lea    -0x96c(%rdi),%eax
  cmp    $0x3c,%eax
  jbe    L15
  cmp    $0x9b4,%edi
  je     L4
  lea    -0x1388(%rdi),%eax
  cmp    $0x44c,%eax
  ja     L12
  mov    %eax,%edi
  cltq
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  ret
L15:
  sub    $0x967,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  ret
L4:
  mov    $0xe,%eax
  ret
L12:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_channel_from_frequency(int32_t frequency) {
  if (frequency >= 2412 && frequency <= 2472)
    return (frequency - 2407) / 5;
  if (frequency == 2484)
    return 14;
  if (frequency >= 5000 && frequency <= 6100)
    return (frequency - 5000) / 5;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_channel_from_frequency>:
  endbr64
  lea    -0x96c(%rdi),%eax
  cmp    $0x3c,%eax
  jbe    L22
  cmp    $0x9b4,%edi
  je     L28
  sub    $0x1388,%edi
  cmp    $0x44c,%edi
  ja     L23
  mov    %edi,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   (%rax)
L22:
  lea    -0x967(%rdi),%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax)
L28:
  mov    $0xe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_channel_from_frequency(int32_t frequency) {
  if (frequency >= 2412 && frequency <= 2472)
    return (frequency - 2407) / 5;
  if (frequency == 2484)
    return 14;
  if (frequency >= 5000 && frequency <= 6100)
    return (frequency - 5000) / 5;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_channel_from_frequency>:
  endbr64
  lea    -0x96c(%rdi),%eax
  cmp    $0x3c,%eax
  jbe    L24
  cmp    $0x9b4,%edi
  je     L22
  sub    $0x1388,%edi
  cmp    $0x44c,%edi
  ja     L9
  mov    %edi,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   (%rax)
L24:
  lea    -0x967(%rdi),%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x22,%rax
  ret
  nopl   0x0(%rax)
L22:
  mov    $0xe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_channel_from_frequency(int32_t frequency) {
  if (frequency >= 2412 && frequency <= 2472)
    return (frequency - 2407) / 5;
  if (frequency == 2484)
    return 14;
  if (frequency >= 5000 && frequency <= 6100)
    return (frequency - 5000) / 5;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L10
L26:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L10
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
L10:
  cmpl   $0x3d08ff,-0xc(%rbp)
  jle    L26
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0: %d


assistant: ```c
int main() {
  int32_t a = 1, b = 2, aux, sum = 2;
  while (b < 4000000) {
    aux = a + b;
    a = b;
    b = aux;
    if (b % 2 == 0)
      sum += b;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  jmp    L19
L5:
  mov    %eax,%edx
L19:
  lea    (%rdx,%rcx,1),%eax
  lea    (%rsi,%rax,1),%ecx
  test   $0x1,%al
  cmove  %ecx,%esi
  mov    %edx,%ecx
  cmp    $0x3d08ff,%eax
  jle    L5
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string

tool: D2: %d


assistant: ```c
int main() {
  int32_t a = 1, b = 2, aux, sum = 2;
  while (b < 4000000) {
    aux = a + b;
    a = b;
    b = aux;
    if (b % 2 == 0)
      sum += b;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%eax
  mov    $0x2,%edx
  mov    $0x2,%esi
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %eax,%ecx
  add    %edx,%eax
  lea    (%rsi,%rax,1),%edx
  test   $0x1,%al
  cmove  %edx,%esi
  mov    %ecx,%edx
  cmp    $0x3d08ff,%eax
  jle    L1
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string

tool: D2: %d


assistant: ```c
int main() {
  int32_t a = 1, b = 2, aux, sum = 2;
  while (b < 4000000) {
    aux = a + b;
    a = b;
    b = aux;
    if (b % 2 == 0)
      sum += b;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%eax
  mov    $0x2,%edx
  mov    $0x2,%esi
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %eax,%ecx
  add    %edx,%eax
  lea    (%rsi,%rax,1),%edx
  test   $0x1,%al
  cmove  %edx,%esi
  mov    %ecx,%edx
  cmp    $0x3d08ff,%eax
  jle    L8
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main() {
  int32_t a = 1, b = 2, aux, sum = 2;
  while (b < 4000000) {
    aux = a + b;
    a = b;
    b = aux;
    if (b % 2 == 0)
      sum += b;
  }
  printf("%d\n", sum);
  return 0;
}
```