ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L31
  call   <strdup@plt>
  xor    %ebx,%ebx
  mov    %rax,%rbp
  jmp    L67
  cs nopw 0x0(%rax,%rax,1)
L65:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%rbp,%rbx,1),%r13
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %eax,%eax
  je     L39
L67:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L65
L85:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L83
  movslq %ebx,%rbx
  jmp    L66
  xchg   %ax,%ax
L68:
  lea    -0x1(%rbx),%rax
  test   %ebx,%ebx
  je     L75
  mov    %rax,%rbx
L66:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %ebx,%r13d
  call   <isspace@plt>
  test   %eax,%eax
  jne    L68
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%r13d
  call   <strncpy@plt>
  movslq %r13d,%rbx
L75:
  mov    %rbp,%rdi
  call   <free@plt>
  movb   $0x0,(%r12,%rbx,1)
L31:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L85
L83:
  movslq %eax,%rbx
  jmp    L75
```

assistant: ```c
char *trim(char *string) {
  if (string == NULL) {
    return NULL;
  }
  char *string_2;
  int i;
  string_2 = strdup(string);
  for (i = 0; i < strlen(string_2); i++) {
    if (!(isspace(string_2[i]))) {
      strcpy(string, &string_2[i]);
      break;
    }
  }
  free(string_2);
  string_2 = strdup(string);
  for (i = strlen(string_2) - 1; i >= 0; i--) {
    if (!(isspace(string_2[i]))) {
      strncpy(string, string_2, i);
      break;
    }
  }
  free(string_2);
  string[i + 1] = '\0';
  return string;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L28
  call   <strdup@plt>
  xor    %ebx,%ebx
  mov    %rax,%rbp
  jmp    L93
  cs nopw 0x0(%rax,%rax,1)
L87:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%rbp,%rbx,1),%r13
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %eax,%eax
  je     L22
L93:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L87
L43:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L23
  movslq %ebx,%rbx
  jmp    L45
  xchg   %ax,%ax
L19:
  lea    -0x1(%rbx),%rax
  test   %ebx,%ebx
  je     L55
  mov    %rax,%rbx
L45:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %ebx,%r13d
  call   <isspace@plt>
  test   %eax,%eax
  jne    L19
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%r13d
  call   <strncpy@plt>
  movslq %r13d,%rbx
L55:
  mov    %rbp,%rdi
  call   <free@plt>
  movb   $0x0,(%r12,%rbx,1)
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L43
L23:
  movslq %eax,%rbx
  jmp    L55
```

assistant: ```c
char *trim(char *string) {
  if (string == NULL) {
    return NULL;
  }
  char *string_2;
  int i;
  string_2 = strdup(string);
  for (i = 0; i < strlen(string_2); i++) {
    if (!(isspace(string_2[i]))) {
      strcpy(string, &string_2[i]);
      break;
    }
  }
  free(string_2);
  string_2 = strdup(string);
  for (i = strlen(string_2) - 1; i >= 0; i--) {
    if (!(isspace(string_2[i]))) {
      strncpy(string, string_2, i);
      break;
    }
  }
  free(string_2);
  string[i + 1] = '\0';
  return string;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<QuickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L13
L38:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L7
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
L7:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L13
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
L13:
  cmpl   $0x0,-0x10(%rbp)
  jns    L38
  nop
  nop
  leave
  ret
```

assistant: ```c
void QuickSort(int *array, int l, int h) {
  int *stack = malloc(sizeof(int) * (h - l + 1));
  int top = -1;
  *(stack + ++top) = l;
  *(stack + ++top) = h;
  while (top >= 0) {
    h = *(stack + top--);
    l = *(stack + top--);
    int p = partition(array, l, h);
    if (p - 1 > l) {
      *(stack + ++top) = l;
      *(stack + ++top) = p - 1;
    }
    if (p + 1 < h) {
      *(stack + ++top) = p + 1;
      *(stack + ++top) = h;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<QuickSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %edx,%eax
  sub    %esi,%eax
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %ebp,(%rax)
  mov    %ebx,0x4(%rax)
  mov    $0x1,%ebp
  jmp    L45
L25:
  mov    %ebx,(%r14)
  mov    %edx,0x0(%r13)
L43:
  add    $0x1,%eax
  cmp    %r12d,%eax
  jl     L35
L45:
  test   %ebp,%ebp
  js     L7
  movslq %ebp,%rax
  shl    $0x2,%rax
  lea    (%r15,%rax,1),%r13
  mov    0x0(%r13),%r12d
  lea    -0x4(%r15,%rax,1),%r14
  mov    (%r14),%ebx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    0x8(%rsp),%rdi
  call   <partition@plt>
  lea    -0x1(%rax),%edx
  cmp    %ebx,%edx
  jg     L25
  sub    $0x2,%ebp
  jmp    L43
L35:
  lea    0x1(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,(%r15,%rdx,4)
  add    $0x2,%ebp
  mov    %r12d,0x4(%r15,%rdx,4)
  jmp    L45
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void QuickSort(int *array, int l, int h) {
  int *stack = malloc(sizeof(int) * (h - l + 1));
  int top = -1;
  *(stack + ++top) = l;
  *(stack + ++top) = h;
  while (top >= 0) {
    h = *(stack + top--);
    l = *(stack + top--);
    int p = partition(array, l, h);
    if (p - 1 > l) {
      *(stack + ++top) = l;
      *(stack + ++top) = p - 1;
    }
    if (p + 1 < h) {
      *(stack + ++top) = p + 1;
      *(stack + ++top) = h;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<QuickSort>:
  endbr64
  push   %r15
  mov    %edx,%eax
  push   %r14
  sub    %esi,%eax
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %r12d,(%rax)
  mov    %rax,%r15
  mov    $0x1,%r12d
  mov    %ebp,0x4(%rax)
  jmp    L11
  nopl   (%rax)
L7:
  add    $0x1,%eax
  sub    $0x2,%r12d
  cmp    %r13d,%eax
  jl     L50
L11:
  test   %r12d,%r12d
  js     L5
L17:
  movslq %r12d,%rax
  mov    0x8(%rsp),%rdi
  shl    $0x2,%rax
  lea    (%r15,%rax,1),%r14
  lea    -0x4(%r15,%rax,1),%rbx
  mov    (%r14),%r13d
  mov    (%rbx),%ebp
  mov    %r13d,%edx
  mov    %ebp,%esi
  call   <partition@plt>
  lea    -0x1(%rax),%edx
  cmp    %ebp,%edx
  jle    L7
  add    $0x1,%eax
  mov    %ebp,(%rbx)
  mov    %edx,(%r14)
  cmp    %r13d,%eax
  jge    L11
L50:
  lea    0x1(%r12),%edx
  add    $0x2,%r12d
  movslq %edx,%rdx
  mov    %eax,(%r15,%rdx,4)
  mov    %r13d,0x4(%r15,%rdx,4)
  test   %r12d,%r12d
  jns    L17
L5:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void QuickSort(int *array, int l, int h) {
  int *stack = malloc(sizeof(int) * (h - l + 1));
  int top = -1;
  *(stack + ++top) = l;
  *(stack + ++top) = h;
  while (top >= 0) {
    h = *(stack + top--);
    l = *(stack + top--);
    int p = partition(array, l, h);
    if (p - 1 > l) {
      *(stack + ++top) = l;
      *(stack + ++top) = p - 1;
    }
    if (p + 1 < h) {
      *(stack + ++top) = p + 1;
      *(stack + ++top) = h;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<QuickSort>:
  endbr64
  push   %r15
  movd   %edx,%xmm3
  movd   %esi,%xmm2
  sub    %esi,%edx
  push   %r14
  punpckldq %xmm3,%xmm2
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x4(,%rdx,4),%edi
  push   %rbx
  movq   %xmm2,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbx,(%rax)
  mov    %rax,%r14
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x1,%eax
  sub    $0x2,%r12d
  cmp    %r13d,%eax
  jl     L58
L51:
  test   %r12d,%r12d
  js     L33
L11:
  movslq %r12d,%rax
  mov    %rbp,%rdi
  lea    -0x4(%r14,%rax,4),%r15
  mov    (%r14,%rax,4),%r13d
  mov    (%r15),%ebx
  mov    %r13d,%edx
  mov    %ebx,%esi
  call   <partition@plt>
  movd   %ebx,%xmm0
  lea    -0x1(%rax),%edx
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  cmp    %ebx,%edx
  jle    L27
  add    $0x1,%eax
  movq   %xmm0,(%r15)
  cmp    %r13d,%eax
  jge    L51
L58:
  lea    0x1(%r12),%edx
  movd   %eax,%xmm0
  movd   %r13d,%xmm4
  add    $0x2,%r12d
  movslq %edx,%rdx
  punpckldq %xmm4,%xmm0
  movq   %xmm0,(%r14,%rdx,4)
  test   %r12d,%r12d
  jns    L11
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void QuickSort(int *array, int l, int h) {
  int *stack = malloc(sizeof(int) * (h - l + 1));
  int top = -1;
  *(stack + ++top) = l;
  *(stack + ++top) = h;
  while (top >= 0) {
    h = *(stack + top--);
    l = *(stack + top--);
    int p = partition(array, l, h);
    if (p - 1 > l) {
      *(stack + ++top) = l;
      *(stack + ++top) = p - 1;
    }
    if (p + 1 < h) {
      *(stack + ++top) = p + 1;
      *(stack + ++top) = h;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovbe %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L62
L34:
  subl   $0x1,-0xc(%rbp)
L62:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L34
  mov    -0x10(%rbp),%eax
  mov    $0x0,%edx
  divl   -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L34
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    $0x0,%edx
  divl   -0xc(%rbp)
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovae %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L12
L65:
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L65
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L65
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    $0x0,%edx
  divl   -0xc(%rbp)
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: tag: D17
type_guessed: string

tool: D29: Enter two +ve integers:

tool: D3:  %u %u%*c

tool: D24: 
HCF = %u
LCM = %u


tool: D17: 
LCM = %u
HCF = %u


assistant: ```c
int main() {
  unsigned a, b, i;
  printf("Enter two +ve integers:\n");
  scanf(" %u %u%*c", &a, &b);
  {
    for (i = a < b ? a : b; a % i || b % i; --i)
      ;
    printf("\nHCF = %u\nLCM = %u\n", i, a * b / i);
  }
  {
    for (i = a > b ? a : b; i % a || i % b; ++i)
      ;
    printf("\nLCM = %u\nHCF = %u\n", i, a * b / i);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovbe %edi,%esi
  jmp    L33
L51:
  sub    $0x1,%esi
L33:
  mov    %ecx,%eax
  mov    $0x0,%edx
  div    %esi
  test   %edx,%edx
  jne    L51
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  test   %edx,%edx
  jne    L51
  mov    %edi,%eax
  imul   %ecx,%eax
  mov    $0x0,%edx
  div    %esi
  mov    %eax,%edx
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovae %edi,%esi
  jmp    L15
L32:
  add    $0x1,%esi
L15:
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %ecx
  test   %edx,%edx
  jne    L32
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %edi
  test   %edx,%edx
  jne    L32
  mov    %edi,%eax
  imul   %ecx,%eax
  mov    $0x0,%edx
  div    %esi
  mov    %eax,%edx
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string

tool: D36: Enter two +ve integers:

tool: D8:  %u %u%*c

tool: D5: 
HCF = %u
LCM = %u


tool: D10: 
LCM = %u
HCF = %u


assistant: ```c
int main() {
  unsigned a, b, i;
  printf("Enter two +ve integers:\n");
  scanf(" %u %u%*c", &a, &b);
  {
    for (i = a < b ? a : b; a % i || b % i; --i)
      ;
    printf("\nHCF = %u\nLCM = %u\n", i, a * b / i);
  }
  {
    for (i = a > b ? a : b; i % a || i % b; ++i)
      ;
    printf("\nLCM = %u\nHCF = %u\n", i, a * b / i);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovbe %edi,%esi
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L13:
  sub    $0x1,%esi
L54:
  mov    %ecx,%eax
  xor    %edx,%edx
  div    %esi
  test   %edx,%edx
  jne    L13
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  test   %edx,%edx
  jne    L13
  mov    %edi,%eax
  xor    %edx,%edx
  lea    D3(%rip),%rdi
  imul   %ecx,%eax
  div    %esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovae %edi,%esi
  jmp    L8
L38:
  add    $0x1,%esi
L8:
  mov    %esi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  jne    L38
  mov    %esi,%eax
  xor    %edx,%edx
  div    %edi
  test   %edx,%edx
  jne    L38
  mov    %edi,%eax
  xor    %edx,%edx
  lea    D19(%rip),%rdi
  imul   %ecx,%eax
  div    %esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D30
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string
name: retrieve_data
arguments: data_label: D19
type_guessed: string

tool: D30: Enter two +ve integers:

tool: D1:  %u %u%*c

tool: D3: 
HCF = %u
LCM = %u


tool: D19: 
LCM = %u
HCF = %u


assistant: ```c
int main() {
  unsigned a, b, i;
  printf("Enter two +ve integers:\n");
  scanf(" %u %u%*c", &a, &b);
  {
    for (i = a < b ? a : b; a % i || b % i; --i)
      ;
    printf("\nHCF = %u\nLCM = %u\n", i, a * b / i);
  }
  {
    for (i = a > b ? a : b; i % a || i % b; ++i)
      ;
    printf("\nLCM = %u\nHCF = %u\n", i, a * b / i);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D20(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovbe %edi,%esi
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L7:
  sub    $0x1,%esi
L42:
  mov    %ecx,%eax
  xor    %edx,%edx
  div    %esi
  test   %edx,%edx
  jne    L7
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  test   %edx,%edx
  jne    L7
  mov    %edi,%eax
  xor    %edx,%edx
  lea    D7(%rip),%rdi
  imul   %ecx,%eax
  div    %esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovae %edi,%esi
  jmp    L45
L49:
  add    $0x1,%esi
L45:
  mov    %esi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  jne    L49
  mov    %esi,%eax
  xor    %edx,%edx
  div    %edi
  test   %edx,%edx
  jne    L49
  mov    %edi,%eax
  xor    %edx,%edx
  lea    D13(%rip),%rdi
  imul   %ecx,%eax
  div    %esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D18
type_infered: string
name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D13
type_infered: string

tool: D20: Enter two +ve integers:

tool: D18:  %u %u%*c

tool: D7: 
HCF = %u
LCM = %u


tool: D13: 
LCM = %u
HCF = %u


assistant: ```c
int main() {
  unsigned a, b, i;
  printf("Enter two +ve integers:\n");
  scanf(" %u %u%*c", &a, &b);
  {
    for (i = a < b ? a : b; a % i || b % i; --i)
      ;
    printf("\nHCF = %u\nLCM = %u\n", i, a * b / i);
  }
  {
    for (i = a > b ? a : b; i % a || i % b; ++i)
      ;
    printf("\nLCM = %u\nHCF = %u\n", i, a * b / i);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%ecx
  mov    -0xc8(%rbp),%rdx
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <_log_print@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_print(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  _log_print(0, LOG_NOTICE, fmt, ap, -1, 0);
  va_end(ap);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<log_print>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <_log_print@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void log_print(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  _log_print(0, LOG_NOTICE, fmt, ap, -1, 0);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log_print>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %ebp,%ecx
  xor    %edi,%edi
  mov    %r12,%rdx
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  mov    (%rax),%esi
  call   <_log_print@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_print(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  _log_print(0, LOG_NOTICE, fmt, ap, -1, 0);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<log_print>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %ebp,%ecx
  xor    %edi,%edi
  mov    %r12,%rdx
  xor    %r9d,%r9d
  mov    $0xffffffff,%r8d
  mov    (%rax),%esi
  call   <_log_print@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_print(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  _log_print(0, LOG_NOTICE, fmt, ap, -1, 0);
  va_end(ap);
}
```