ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_gquad>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %rdx,0x8(%rsp)
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L106
  cmp    $0x2b,%dl
  je     L106
  mov    $0x1,%eax
L184:
  mov    %eax,%ebx
  movzbl 0x0(%rbp,%rax,1),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L111
  cmp    $0x2b,%dl
  jne    L184
L111:
  mov    $0x0,%r12d
  cmp    $0x2b,%dl
  jne    L25
  mov    $0x0,%r13d
  jmp    L164
L106:
  mov    $0x0,%ebx
  jmp    L111
L38:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmpb   $0x2b,-0x1(%rbp,%rax,1)
  jne    L158
L122:
  lea    -0x2(%rax),%ecx
  lea    -0x1(%rax),%r14d
  test   %r13d,%r13d
  je     L38
  mov    %eax,%edx
  sub    %ebx,%edx
  sub    $0x1,%edx
  cmp    %edx,(%r15)
  jne    L38
  mov    %r14d,%eax
  sub    %ebx,%eax
  mov    %r14d,%r12d
  mov    %ecx,%r14d
L42:
  cmp    %eax,(%r15)
  jne    L139
L14:
  cmp    $0x3,%r13d
  je     L25
L191:
  movslq %r12d,%rax
  lea    0x1(%rbp,%rax,1),%rax
  mov    %r12d,%ebx
L168:
  mov    %ebx,%edx
  add    $0x1,%ebx
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0x2e,-0x1(%rax)
  je     L168
  sub    %r14d,%edx
  mov    0x8(%rsp),%rax
  mov    %edx,(%rax,%r13,4)
  cmpb   $0x2b,(%rcx)
  jne    L188
L107:
  add    $0x1,%r13
  cmp    $0x4,%r13
  je     L25
L164:
  lea    0x1(%rbx),%r12d
  movslq %r12d,%rdx
  lea    0x2(%rbx),%eax
  cltq
  mov    %ebx,%r14d
  cmpb   $0x2b,0x0(%rbp,%rdx,1)
  je     L122
L158:
  mov    %r12d,%eax
  sub    %ebx,%eax
  test   %r13d,%r13d
  jne    L42
  mov    %eax,(%r15)
  jmp    L191
L139:
  lea    D16(%rip),%rdi
  call   <nrerror@plt>
  jmp    L14
L188:
  lea    D19(%rip),%rdi
  call   <nrerror@plt>
  jmp    L107
L25:
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string

tool: D16: unequal stack lengths in gquad

tool: D19: illegal character in gquad linker region

assistant: ```c
int parse_gquad(const char *struc, int *L, int l[3]) {
  int i, il, start, end, len;
  for (i = 0; struc[i] && struc[i] != '+'; i++)
    ;
  if (struc[i] == '+') {
    for (il = 0; il <= 3; il++) {
      start = i;
      while (struc[++i] == '+') {
        if ((il) && (i - start == *L))
          break;
      }
      end = i;
      len = end - start;
      if (il == 0)
        *L = len;
      else if (len != *L)
        nrerror("unequal stack lengths in gquad");
      if (il == 3)
        break;
      while (struc[++i] == '.')
        ;
      l[il] = i - end;
      if (struc[i] != '+')
        nrerror("illegal character in gquad linker region");
    }
  } else
    return 0;
  return end;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_gquad>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%edx
  cmp    $0x2b,%dl
  je     L136
  test   %dl,%dl
  je     L136
  mov    $0x1,%eax
  nopl   0x0(%rax)
L60:
  movzbl 0x0(%r13,%rax,1),%edx
  mov    %eax,%ebx
  add    $0x1,%rax
  test   %dl,%dl
  je     L125
  cmp    $0x2b,%dl
  jne    L60
L127:
  xor    %r14d,%r14d
  lea    D1(%rip),%rbp
L69:
  lea    0x1(%rbx),%edx
  lea    0x2(%rbx),%eax
  movslq %edx,%rsi
  cltq
  cmpb   $0x2b,0x0(%r13,%rsi,1)
  jne    L50
  nopw   0x0(%rax,%rax,1)
L101:
  lea    -0x2(%rax),%esi
  lea    -0x1(%rax),%r8d
  test   %r14,%r14
  je     L120
  mov    %eax,%edx
  sub    %ebx,%edx
  sub    $0x1,%edx
  cmp    (%r15),%edx
  je     L89
L120:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x2b,-0x1(%r13,%rax,1)
  je     L101
  mov    %edx,%eax
  sub    %ebx,%eax
L103:
  test   %r14,%r14
  jne    L39
  mov    %eax,(%r15)
  mov    %edx,%ebx
L52:
  movslq %ebx,%rax
  lea    0x1(%r13,%rax,1),%rax
  nopl   0x0(%rax,%rax,1)
L164:
  mov    %rax,%rsi
  add    $0x1,%rax
  mov    %ebx,%edx
  add    $0x1,%ebx
  cmpb   $0x2e,-0x1(%rax)
  je     L164
  sub    %r8d,%edx
  mov    %edx,(%r12,%r14,4)
  cmpb   $0x2b,(%rsi)
  je     L84
  mov    %rbp,%rdi
  call   <nrerror@plt>
L84:
  add    $0x1,%r14
  jmp    L69
  nop
L39:
  cmp    %eax,(%r15)
  je     L104
  lea    D15(%rip),%rdi
  mov    %r8d,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  call   <nrerror@plt>
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%r8d
L89:
  cmp    $0x3,%r14
  je     L33
  mov    %r8d,%ebx
  mov    %esi,%r8d
  jmp    L52
L136:
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L125:
  cmp    $0x2b,%dl
  je     L127
  xor    %r8d,%r8d
L33:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  mov    %ebx,%r8d
  mov    $0x1,%eax
  jmp    L103
L104:
  mov    %r8d,%esi
  mov    %edx,%r8d
  jmp    L89
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D1: illegal character in gquad linker region

tool: D15: unequal stack lengths in gquad

assistant: ```c
int parse_gquad(const char *struc, int *L, int l[3]) {
  int i, il, start, end, len;
  for (i = 0; struc[i] && struc[i] != '+'; i++)
    ;
  if (struc[i] == '+') {
    for (il = 0; il <= 3; il++) {
      start = i;
      while (struc[++i] == '+') {
        if ((il) && (i - start == *L))
          break;
      }
      end = i;
      len = end - start;
      if (il == 0)
        *L = len;
      else if (len != *L)
        nrerror("unequal stack lengths in gquad");
      if (il == 3)
        break;
      while (struc[++i] == '.')
        ;
      l[il] = i - end;
      if (struc[i] != '+')
        nrerror("illegal character in gquad linker region");
    }
  } else
    return 0;
  return end;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<compute>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%r9d
  mov    %esi,%r10d
  mov    %rdx,%r11
  lea    -0x1(%rdi),%r8d
  test   %r8d,%r8d
  jle    L116
  movslq %esi,%rbx
  lea    (%rdx,%rbx,4),%rdx
  lea    -0x2(%rdi),%eax
  lea    (%rax,%rax,4),%rax
  add    %rbx,%rax
  lea    0x14(%r11,%rax,4),%rbp
  neg    %rbx
  shl    $0x2,%rbx
  lea    -0x1(%rsi),%ecx
  jmp    L131
L37:
  lea    (%rdx,%rbx,1),%rsi
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
L105:
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,-0x4(%rdx)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L105
L141:
  add    $0x14,%rdx
  cmp    %rbp,%rdx
  je     L5
L131:
  mov    %ecx,%edi
  test   %ecx,%ecx
  jg     L37
  jmp    L141
L5:
  test   %edi,%edi
  jle    L100
L68:
  mov    %r11,%rbx
  movslq %r9d,%rax
  lea    (%rax,%rax,4),%rax
  lea    -0x14(%r11,%rax,4),%rcx
  lea    -0x2(%r9),%eax
  lea    (%rax,%rax,4),%rax
  lea    0x14(%r11,%rax,4),%rdx
  mov    $0x0,%esi
L86:
  mov    %rbx,%rax
  pxor   %xmm0,%xmm0
  test   %r8d,%r8d
  jle    L70
  pxor   %xmm2,%xmm2
  cvtsi2ss %r8d,%xmm2
L40:
  addss  (%rax),%xmm0
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,(%rcx)
  add    $0x14,%rax
  cmp    %rdx,%rax
  jne    L40
L70:
  add    $0x1,%esi
  add    $0x4,%rbx
  add    $0x4,%rcx
  add    $0x4,%rdx
  cmp    %esi,%edi
  jg     L86
  test   %r8d,%r8d
  jle    L41
L100:
  movslq %r10d,%r10
  lea    (%r11,%r10,4),%rax
  lea    -0x2(%r9),%edx
  lea    (%rdx,%rdx,4),%rdx
  add    %r10,%rdx
  lea    0x14(%r11,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L66:
  addss  (%rax),%xmm0
  add    $0x14,%rax
  cmp    %rdx,%rax
  jne    L66
L17:
  movslq %r9d,%r9
  lea    (%r9,%r9,4),%rax
  lea    -0x14(%r11,%rax,4),%rax
  movslq %edi,%rdi
  pxor   %xmm1,%xmm1
  cvtsi2ss %r8d,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax,%rdi,4)
  pop    %rbx
  pop    %rbp
  ret
L41:
  pxor   %xmm0,%xmm0
  jmp    L17
L116:
  lea    -0x1(%rsi),%edi
  pxor   %xmm0,%xmm0
  test   %edi,%edi
  jg     L68
  jmp    L17
```

assistant: ```c
void compute(int m, int n, float a[][5]) {
  int i, j;
  float s = 0;
  for (i = 0; i < m - 1; i++) {
    for (j = 0; j < n - 1; j++) {
      s += a[i][j];
      a[i][n - 1] = s;
    }
    s = 0;
  }
  for (j = 0; j < n - 1; j++) {
    for (i = 0; i < m - 1; i++) {
      s += a[i][j];
      a[m - 1][j] = s / (m - 1);
    }
    s = 0;
  }
  for (i = 0; i < m - 1; i++)
    s += a[i][n];
  a[m - 1][n - 1] = s / (m - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compute>:
  endbr64
  movslq %esi,%r10
  movslq %edi,%rax
  lea    -0x1(%rdi),%r8d
  push   %r13
  pxor   %xmm2,%xmm2
  lea    (%rax,%rax,4),%rax
  lea    -0x1(%r10),%ecx
  push   %r12
  cvtsi2ss %r8d,%xmm2
  push   %rbp
  mov    %rdx,%r9
  movslq %ecx,%r11
  push   %rbx
  lea    -0x14(%rdx,%rax,4),%rbx
  test   %r8d,%r8d
  jle    L81
  lea    -0x2(%rdi),%eax
  lea    0x0(,%r11,4),%r13
  pxor   %xmm3,%xmm3
  mov    %rax,%rsi
  lea    (%rax,%rax,4),%rax
  lea    0x14(%r9),%rdi
  add    %r11,%rax
  lea    (%rdx,%r13,1),%rdx
  lea    (%rdi,%rax,4),%r12
  xchg   %ax,%ax
L63:
  test   %ecx,%ecx
  jle    L65
  mov    %rdx,%rbp
  xor    %eax,%eax
  movaps %xmm3,%xmm0
  sub    %r13,%rbp
  nop
L93:
  addss  0x0(%rbp,%rax,4),%xmm0
  add    $0x1,%rax
  movss  %xmm0,(%rdx)
  cmp    %eax,%ecx
  jg     L93
L65:
  add    $0x14,%rdx
  cmp    %rdx,%r12
  jne    L63
  test   %ecx,%ecx
  jle    L36
L108:
  mov    %esi,%eax
  mov    %r9,%r13
  mov    %rbx,%rbp
  xor    %r12d,%r12d
  lea    (%rax,%rax,4),%rax
  lea    (%rdi,%rax,4),%rdx
  nopw   0x0(%rax,%rax,1)
L101:
  mov    %r13,%rax
  movaps %xmm3,%xmm0
  test   %r8d,%r8d
  jle    L23
  nopl   0x0(%rax,%rax,1)
L27:
  addss  (%rax),%xmm0
  add    $0x14,%rax
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,0x0(%rbp)
  cmp    %rdx,%rax
  jne    L27
L23:
  add    $0x1,%r12d
  add    $0x4,%r13
  add    $0x4,%rbp
  add    $0x4,%rdx
  cmp    %ecx,%r12d
  jl     L101
  test   %r8d,%r8d
  jle    L44
L36:
  lea    (%rsi,%rsi,4),%rdx
  lea    (%r9,%r10,4),%rax
  movaps %xmm3,%xmm0
  add    %r10,%rdx
  lea    (%rdi,%rdx,4),%rdx
  nopl   (%rax)
L87:
  addss  (%rax),%xmm0
  add    $0x14,%rax
  cmp    %rax,%rdx
  jne    L87
L34:
  divss  %xmm2,%xmm0
  movss  %xmm0,(%rbx,%r11,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L81:
  pxor   %xmm3,%xmm3
  test   %ecx,%ecx
  jle    L44
  lea    -0x2(%rdi),%esi
  pxor   %xmm3,%xmm3
  lea    0x14(%rdx),%rdi
  jmp    L108
L44:
  movaps %xmm3,%xmm0
  jmp    L34
```

assistant: ```c
void compute(int m, int n, float a[][5]) {
  int i, j;
  float s = 0;
  for (i = 0; i < m - 1; i++) {
    for (j = 0; j < n - 1; j++) {
      s += a[i][j];
      a[i][n - 1] = s;
    }
    s = 0;
  }
  for (j = 0; j < n - 1; j++) {
    for (i = 0; i < m - 1; i++) {
      s += a[i][j];
      a[m - 1][j] = s / (m - 1);
    }
    s = 0;
  }
  for (i = 0; i < m - 1; i++)
    s += a[i][n];
  a[m - 1][n - 1] = s / (m - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compute>:
  endbr64
  movslq %esi,%r8
  lea    -0x1(%rdi),%eax
  pxor   %xmm2,%xmm2
  mov    %rdx,%rsi
  movslq %edi,%rdx
  cvtsi2ss %eax,%xmm2
  lea    (%rdx,%rdx,4),%rdx
  lea    -0x14(%rsi,%rdx,4),%r9
  lea    -0x1(%r8),%edx
  test   %eax,%eax
  jle    L21
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L98
  sub    $0x2,%edi
  movslq %edx,%r10
  pxor   %xmm3,%xmm3
  mov    %rsi,%rax
  lea    (%rdi,%rdi,4),%rbx
  mov    %rdi,%rcx
  lea    0x14(%rsi),%rdi
  lea    (%rsi,%r10,4),%r11
  lea    (%rdi,%rbx,4),%rbx
  nopl   0x0(%rax)
L66:
  movss  (%rax),%xmm0
  addss  %xmm3,%xmm0
  movss  %xmm0,(%r11)
  cmp    $0x1,%edx
  je     L97
  addss  0x4(%rax),%xmm0
  movss  %xmm0,(%r11)
  cmp    $0x2,%edx
  je     L97
  addss  0x8(%rax),%xmm0
  movss  %xmm0,(%r11)
  cmp    $0x3,%edx
  je     L97
  addss  0xc(%rax),%xmm0
  movss  %xmm0,(%r11)
  cmp    $0x4,%edx
  je     L97
  addss  0x10(%rax),%xmm0
  movss  %xmm0,(%r11)
  cmp    $0x5,%edx
  je     L97
  addss  0x14(%rax),%xmm0
  mov    $0x6,%ebp
  movss  %xmm0,(%r11)
  cmp    $0x6,%edx
  je     L97
L31:
  addss  (%rax,%rbp,4),%xmm0
  add    $0x1,%rbp
  movss  %xmm0,(%r11)
  cmp    %ebp,%edx
  jg     L31
  nopl   0x0(%rax)
L97:
  add    $0x14,%rax
  add    $0x14,%r11
  cmp    %rbx,%rax
  jne    L66
  mov    %ecx,%eax
  mov    %rsi,%r12
  mov    %r9,%rbx
  xor    %ebp,%ebp
  lea    (%rax,%rax,4),%rax
  lea    (%rdi,%rax,4),%r11
  nopl   0x0(%rax,%rax,1)
L92:
  mov    %r12,%rax
  movaps %xmm3,%xmm0
  cs nopw 0x0(%rax,%rax,1)
L115:
  addss  (%rax),%xmm0
  add    $0x14,%rax
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,(%rbx)
  cmp    %rax,%r11
  jne    L115
  add    $0x1,%ebp
  add    $0x4,%r12
  add    $0x4,%rbx
  add    $0x4,%r11
  cmp    %edx,%ebp
  jl     L92
L24:
  lea    (%rcx,%rcx,4),%rdx
  lea    (%rsi,%r8,4),%rax
  movaps %xmm3,%xmm0
  add    %r8,%rdx
  lea    (%rdi,%rdx,4),%rdx
  nopl   (%rax)
L95:
  addss  (%rax),%xmm0
  add    $0x14,%rax
  cmp    %rax,%rdx
  jne    L95
  divss  %xmm2,%xmm0
  movss  %xmm0,(%r9,%r10,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L98:
  lea    -0x2(%rdi),%ecx
  pxor   %xmm3,%xmm3
  lea    0x14(%rsi),%rdi
  movslq %edx,%r10
  jmp    L24
L21:
  pxor   %xmm0,%xmm0
  movslq %edx,%r10
  divss  %xmm2,%xmm0
  movss  %xmm0,(%r9,%r10,4)
  ret
```

assistant: ```c
void compute(int m, int n, float a[][5]) {
  int i, j;
  float s = 0;
  for (i = 0; i < m - 1; i++) {
    for (j = 0; j < n - 1; j++) {
      s += a[i][j];
      a[i][n - 1] = s;
    }
    s = 0;
  }
  for (j = 0; j < n - 1; j++) {
    for (i = 0; i < m - 1; i++) {
      s += a[i][j];
      a[m - 1][j] = s / (m - 1);
    }
    s = 0;
  }
  for (i = 0; i < m - 1; i++)
    s += a[i][n];
  a[m - 1][n - 1] = s / (m - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<touch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string
name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D4: w

tool: D5: x

assistant: ```c
void touch(char *file) {
  FILE *fd;
  fd = fopen(file, "w");
  fwrite("x", 1, 1, fd);
  fclose(fd);
}
```
user: What is the c source code of the assembly code below?

```asm
<touch>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D9: w

tool: D4: x

assistant: ```c
void touch(char *file) {
  FILE *fd;
  fd = fopen(file, "w");
  fwrite("x", 1, 1, fd);
  fclose(fd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<touch>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rsi
  call   <fopen@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D13(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D13
datatype: string

tool: D8: w

tool: D13: x

assistant: ```c
void touch(char *file) {
  FILE *fd;
  fd = fopen(file, "w");
  fwrite("x", 1, 1, fd);
  fclose(fd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<touch>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rsi
  call   <fopen@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
type: string
name: disassemble_data
arguments: label: D17
type: string

tool: D11: w

tool: D17: x

assistant: ```c
void touch(char *file) {
  FILE *fd;
  fd = fopen(file, "w");
  fwrite("x", 1, 1, fd);
  fclose(fd);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<in_cksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%r12d
  mov    -0x38(%rbp),%r13
  mov    $0x0,%ebx
  movl   $0x0,-0x2c(%rbp)
  jmp    L26
L3:
  mov    %r13,%rax
  lea    0x4(%rax),%r13
  mov    (%rax),%eax
  add    %eax,%ebx
  sub    $0x2,%r12d
L26:
  cmp    $0x1,%r12d
  jg     L3
  cmp    $0x1,%r12d
  jne    L27
  lea    -0x2c(%rbp),%rax
  mov    0x0(%r13),%edx
  mov    %edx,(%rax)
  mov    -0x2c(%rbp),%eax
  add    %eax,%ebx
L27:
  mov    %ebx,%edx
  sar    $0x10,%edx
  movzwl %bx,%eax
  lea    (%rdx,%rax,1),%ebx
  mov    %ebx,%eax
  sar    $0x10,%eax
  add    %eax,%ebx
  mov    %ebx,%eax
  not    %eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int in_cksum(u_short *addr, int len) {
  register int nleft = len;
  register u_short *w = addr;
  register int sum = 0;
  u_short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(u_char *)(&answer) = *(u_char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<in_cksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L25
  lea    -0x2(%rsi),%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,4),%rdx
  mov    $0x0,%eax
L20:
  add    $0x4,%rdi
  add    -0x4(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L20
  neg    %ecx
  lea    -0x2(%rsi,%rcx,2),%esi
L34:
  cmp    $0x1,%esi
  je     L0
L12:
  mov    %eax,%edx
  sar    $0x10,%edx
  movzwl %ax,%eax
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
L25:
  mov    %rdi,%rdx
  mov    $0x0,%eax
  jmp    L34
L0:
  add    (%rdx),%eax
  jmp    L12
```

assistant: ```c
int in_cksum(u_short *addr, int len) {
  register int nleft = len;
  register u_short *w = addr;
  register int sum = 0;
  u_short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(u_char *)(&answer) = *(u_char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<in_cksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L17
  sub    $0x2,%esi
  mov    %esi,%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L26:
  add    $0x4,%rdi
  add    -0x4(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L26
  neg    %ecx
  lea    (%rsi,%rcx,2),%esi
L31:
  cmp    $0x1,%esi
  jne    L19
  add    (%rdx),%eax
L19:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax)
L17:
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L31
```

assistant: ```c
int in_cksum(u_short *addr, int len) {
  register int nleft = len;
  register u_short *w = addr;
  register int sum = 0;
  u_short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(u_char *)(&answer) = *(u_char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<in_cksum>:
  endbr64
  mov    %rdi,%rdx
  cmp    $0x1,%esi
  jle    L0
  lea    -0x2(%rsi),%r10d
  mov    %r10d,%r9d
  shr    %r9d
  lea    0x1(%r9),%ecx
  cmp    $0x5,%r10d
  jbe    L36
  mov    %rdi,%rax
  mov    %ecx,%edi
  pxor   %xmm0,%xmm0
  shr    $0x2,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
L55:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rax,%rdi
  jne    L55
  movdqa %xmm0,%xmm1
  mov    %ecx,%edi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edi
  paddd  %xmm1,%xmm0
  mov    %edi,%r8d
  movdqa %xmm0,%xmm1
  neg    %r8d
  psrldq $0x4,%xmm1
  lea    (%rsi,%r8,2),%esi
  mov    %edi,%r8d
  paddd  %xmm1,%xmm0
  lea    (%rdx,%r8,4),%r8
  movd   %xmm0,%eax
  cmp    %edi,%ecx
  je     L37
L24:
  lea    -0x2(%rsi),%edi
  add    (%r8),%eax
  cmp    $0x1,%edi
  jle    L37
  add    0x4(%r8),%eax
  cmp    $0x5,%esi
  jle    L37
  add    0x8(%r8),%eax
L37:
  mov    %ecx,%esi
  mov    %r9d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,4),%rdx
  lea    (%r10,%rcx,2),%esi
L15:
  cmp    $0x1,%esi
  jne    L70
  add    (%rdx),%eax
L70:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  jmp    L15
L36:
  mov    %rdi,%r8
  xor    %eax,%eax
  jmp    L24
```

assistant: ```c
int in_cksum(u_short *addr, int len) {
  register int nleft = len;
  register u_short *w = addr;
  register int sum = 0;
  u_short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(u_char *)(&answer) = *(u_char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lagrange_interp_2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x50(%rbp)
  mov    %r8,-0x60(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L29
L4:
  mov    -0x4c(%rbp),%edx
  mov    -0x48(%rbp),%rsi
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %eax,%edi
  call   <lagrange_basis@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L38
L14:
  mov    -0x50(%rbp),%edx
  mov    -0x58(%rbp),%rsi
  mov    -0x40(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %eax,%edi
  call   <lagrange_basis@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x50(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x4c(%rbp),%esi
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <index_2D_to_1D@plt>
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L38:
  mov    -0x24(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  jl     L14
  addl   $0x1,-0x28(%rbp)
L29:
  mov    -0x28(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L4
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double lagrange_interp_2D(double x, double y, const double x_values[], int num_x, const double y_values[], int num_y, const double z_values[]) {
  double out = 0;
  double lx, ly, z;
  for (int i = 0; i < num_x; i++) {
    lx = lagrange_basis(i, x, x_values, num_x);
    for (int j = 0; j < num_y; j++) {
      ly = lagrange_basis(j, y, y_values, num_y);
      z = z_values[index_2D_to_1D(i, num_x, j, num_y)];
      out += z * lx * ly;
    }
  }
  return out;
}
```