ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<rop3_38_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  or     %eax,%esi
  xor    %eax,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_38_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_38_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  or     %eax,%esi
  xor    %eax,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_38_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<calc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L17
L16:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%ecx
  lea    D7(%rip),%rdx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L30
L45:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x37,%al
  jne    L53
  addl   $0x1,-0x24(%rbp)
L53:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  addq   $0x1,-0x20(%rbp)
L17:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: %d

assistant: ```c
int calc(const char *source) {
  int sevenCount = 0;
  for (char *ptr = source; *ptr != '\0'; ptr++) {
    char buffer[4];
    snprintf(buffer, 4, "%d", (int)*ptr);
    for (char *bufPtr = buffer; *bufPtr; *bufPtr++) {
      if (*bufPtr == '7') {
        sevenCount++;
      }
    }
  }
  return sevenCount * 6;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L46
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
L53:
  movsbl %cl,%ecx
  lea    0x4(%rsp),%rdi
  mov    %r12,%rdx
  mov    $0x4,%esi
  call   <snprintf@plt>
  movzbl 0x4(%rsp),%eax
  test   %al,%al
  je     L47
  lea    0x4(%rsp),%rdx
L39:
  cmp    $0x37,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L39
L47:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  jne    L53
L26:
  lea    (%rbx,%rbx,2),%eax
  add    %eax,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  mov    $0x0,%ebx
  jmp    L26
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: %d

assistant: ```c
int calc(const char *source) {
  int sevenCount = 0;
  for (char *ptr = source; *ptr != '\0'; ptr++) {
    char buffer[4];
    snprintf(buffer, 4, "%d", (int)*ptr);
    for (char *bufPtr = buffer; *bufPtr; *bufPtr++) {
      if (*bufPtr == '7') {
        sevenCount++;
      }
    }
  }
  return sevenCount * 6;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsbl (%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %cl,%cl
  je     L10
  mov    %rdi,%r12
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r13
  lea    D3(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdx
  mov    $0x4,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  movzbl 0x4(%rsp),%eax
  test   %al,%al
  je     L23
  mov    %r13,%rdx
  nopl   0x0(%rax)
L28:
  cmp    $0x37,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %eax,%ebx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L28
L23:
  movsbl 0x1(%r12),%ecx
  add    $0x1,%r12
  test   %cl,%cl
  jne    L14
  lea    (%rbx,%rbx,2),%eax
  add    %eax,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  xor    %eax,%eax
  jmp    L4
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string

tool: D3: %d

assistant: ```c
int calc(const char *source) {
  int sevenCount = 0;
  for (char *ptr = source; *ptr != '\0'; ptr++) {
    char buffer[4];
    snprintf(buffer, 4, "%d", (int)*ptr);
    for (char *bufPtr = buffer; *bufPtr; *bufPtr++) {
      if (*bufPtr == '7') {
        sevenCount++;
      }
    }
  }
  return sevenCount * 6;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsbl (%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %cl,%cl
  je     L22
  mov    %rdi,%r12
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r13
  lea    D8(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdx
  mov    $0x4,%esi
  mov    %r13,%rdi
  call   <snprintf@plt>
  movzbl 0x4(%rsp),%eax
  test   %al,%al
  je     L45
  mov    %r13,%rdx
  nopl   0x0(%rax)
L23:
  cmp    $0x37,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %eax,%ebx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L23
L45:
  movsbl 0x1(%r12),%ecx
  add    $0x1,%r12
  test   %cl,%cl
  jne    L2
  lea    (%rbx,%rbx,2),%eax
  add    %eax,%eax
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  xor    %eax,%eax
  jmp    L31
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string

tool: D8: %d

assistant: ```c
int calc(const char *source) {
  int sevenCount = 0;
  for (char *ptr = source; *ptr != '\0'; ptr++) {
    char buffer[4];
    snprintf(buffer, 4, "%d", (int)*ptr);
    for (char *bufPtr = buffer; *bufPtr; *bufPtr++) {
      if (*bufPtr == '7') {
        sevenCount++;
      }
    }
  }
  return sevenCount * 6;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L8:
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L8
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string

tool: D17: Je suis le maitre !

tool: D15: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
#pragma omp master
    { printf("Je suis le maitre !\n"); }
    int i;
#pragma omp for reduction(+ : sum)
    for (i = 0; i < N; i++) {
      sum += i;
    }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  lea    D16(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L1
  mov    $0x0,%eax
  mov    $0x0,%esi
L5:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L5
L25:
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L1:
  mov    $0x0,%esi
  jmp    L25
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D16: Je suis le maitre !

tool: D19: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
#pragma omp master
    { printf("Je suis le maitre !\n"); }
    int i;
#pragma omp for reduction(+ : sum)
    for (i = 0; i < N; i++) {
      sum += i;
    }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L9
  xor    %eax,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L3:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L3
L28:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  xor    %esi,%esi
  jmp    L28
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D17: Je suis le maitre !

tool: D3: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
#pragma omp master
    { printf("Je suis le maitre !\n"); }
    int i;
#pragma omp for reduction(+ : sum)
    for (i = 0; i < N; i++) {
      sum += i;
    }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L64
  lea    -0x1(%rbx),%eax
  cmp    $0x9,%eax
  jbe    L123
  mov    %ebx,%edx
  movdqa D34(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D3(%rip),%xmm3
  shr    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L65:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L65
  movdqa %xmm0,%xmm1
  mov    %ebx,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  test   $0x3,%bl
  je     L116
L77:
  lea    0x1(%rax),%edx
  add    %eax,%esi
  cmp    %edx,%ebx
  jle    L116
  add    %edx,%esi
  lea    0x2(%rax),%edx
  cmp    %edx,%ebx
  jle    L116
  add    %edx,%esi
  lea    0x3(%rax),%edx
  cmp    %edx,%ebx
  jle    L116
  add    %edx,%esi
  lea    0x4(%rax),%edx
  cmp    %edx,%ebx
  jle    L116
  add    %edx,%esi
  lea    0x5(%rax),%edx
  cmp    %edx,%ebx
  jle    L116
  add    %edx,%esi
  lea    0x6(%rax),%edx
  cmp    %edx,%ebx
  jle    L116
  add    %edx,%esi
  lea    0x7(%rax),%edx
  cmp    %edx,%ebx
  jle    L116
  add    %edx,%esi
  lea    0x8(%rax),%edx
  cmp    %edx,%ebx
  jle    L116
  add    $0x9,%eax
  add    %edx,%esi
  cmp    %eax,%ebx
  jle    L116
  add    %eax,%esi
L116:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L64:
  xor    %esi,%esi
  jmp    L116
L123:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L77
```

tool_calls: name: read_data
arguments: data_tag: D16
type_guessed: string
name: read_data
arguments: data_tag: D34
type_guessed: byte[16]
name: read_data
arguments: data_tag: D3
type_guessed: byte[16]
name: read_data
arguments: data_tag: D10
type_guessed: string

tool: D16: Je suis le maitre !

tool: {"D34": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D3": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D10: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
#pragma omp master
    { printf("Je suis le maitre !\n"); }
    int i;
#pragma omp for reduction(+ : sum)
    for (i = 0; i < N; i++) {
      sum += i;
    }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L31:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  comiss -0x10(%rbp),%xmm0
  jbe    L37
  movss  -0x10(%rbp),%xmm0
  jmp    L26
L37:
  movss  -0xc(%rbp),%xmm0
L26:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L31
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void min(long N, float *dst, const float *src1, const float *src2) {
  for (long i = 0; i < N; i++)
    dst[i] = ({
      __typeof(src1[i]) __x = (src1[i]);
      __typeof(src2[i]) __y = (src2[i]);
      (__x < __y) ? __x : __y;
    });
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<min>:
  endbr64
  test   %rdi,%rdi
  jle    L7
  mov    $0x0,%eax
L13:
  movss  (%rdx,%rax,4),%xmm0
  minss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L13
L7:
  ret
```

assistant: ```c
void min(long N, float *dst, const float *src1, const float *src2) {
  for (long i = 0; i < N; i++)
    dst[i] = ({
      __typeof(src1[i]) __x = (src1[i]);
      __typeof(src2[i]) __y = (src2[i]);
      (__x < __y) ? __x : __y;
    });
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<min>:
  endbr64
  test   %rdi,%rdi
  jle    L18
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L6:
  movss  (%rdx,%rax,4),%xmm0
  minss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L6
L18:
  ret
```

assistant: ```c
void min(long N, float *dst, const float *src1, const float *src2) {
  for (long i = 0; i < N; i++)
    dst[i] = ({
      __typeof(src1[i]) __x = (src1[i]);
      __typeof(src2[i]) __y = (src2[i]);
      (__x < __y) ? __x : __y;
    });
}
```
user: What is the c source code of the assembly code below?

```asm
<min>:
  endbr64
  test   %rdi,%rdi
  jle    L39
  lea    0x4(%rdx),%r8
  mov    %rsi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  lea    -0x1(%rdi),%rax
  seta   %r8b
  cmp    $0x2,%rax
  seta   %al
  test   %al,%r8b
  je     L51
  lea    0x4(%rcx),%r8
  mov    %rsi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L51
  mov    %rdi,%r8
  xor    %eax,%eax
  shr    $0x2,%r8
  shl    $0x4,%r8
  nopl   0x0(%rax)
L69:
  movups (%rdx,%rax,1),%xmm0
  movups (%rcx,%rax,1),%xmm1
  minps  %xmm1,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L69
  mov    %rdi,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%dil
  je     L39
  movss  (%rdx,%rax,4),%xmm0
  minss  (%rcx,%rax,4),%xmm0
  lea    0x1(%rax),%r8
  movss  %xmm0,(%rsi,%rax,4)
  cmp    %r8,%rdi
  jle    L39
  movss  (%rdx,%r8,4),%xmm0
  minss  (%rcx,%r8,4),%xmm0
  add    $0x2,%rax
  lea    0x0(,%r8,4),%r9
  movss  %xmm0,(%rsi,%r8,4)
  cmp    %rax,%rdi
  jle    L39
  movss  0x4(%rdx,%r9,1),%xmm0
  minss  0x4(%rcx,%r9,1),%xmm0
  movss  %xmm0,0x4(%rsi,%r9,1)
  ret
  xchg   %ax,%ax
L51:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L30:
  movss  (%rdx,%rax,4),%xmm0
  minss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L30
L39:
  ret
```

assistant: ```c
void min(long N, float *dst, const float *src1, const float *src2) {
  for (long i = 0; i < N; i++)
    dst[i] = ({
      __typeof(src1[i]) __x = (src1[i]);
      __typeof(src2[i]) __y = (src2[i]);
      (__x < __y) ? __x : __y;
    });
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ns2line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  %xmm3,-0x10(%rbp)
  movss  %xmm4,-0x14(%rbp)
  movss  %xmm5,-0x18(%rbp)
  movss  %xmm6,-0x1c(%rbp)
  movss  %xmm7,-0x20(%rbp)
  movss  -0x20(%rbp),%xmm7
  movss  -0x1c(%rbp),%xmm6
  movss  -0x18(%rbp),%xmm5
  movss  -0x14(%rbp),%xmm4
  movss  -0x10(%rbp),%xmm3
  movss  -0xc(%rbp),%xmm2
  movss  -0x8(%rbp),%xmm1
  mov    -0x4(%rbp),%eax
  sub    $0x8,%rsp
  movss  0x10(%rbp),%xmm0
  lea    -0x8(%rsp),%rsp
  movss  %xmm0,(%rsp)
  mov    $0x1,%edi
  movd   %eax,%xmm0
  call   <ns2thline@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

assistant: ```c
void ns2line(float ix1, float iy1, float iz1, float ix2, float iy2, float iz2, float ired, float igreen, float iblue) {
  ns2thline(ix1, iy1, iz1, ix2, iy2, iz2, ired, igreen, iblue, 1.);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ns2line>:
  endbr64
  sub    $0x18,%rsp
  movss  0x20(%rsp),%xmm8
  movss  %xmm8,(%rsp)
  mov    $0x1,%edi
  call   <ns2thline@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void ns2line(float ix1, float iy1, float iz1, float ix2, float iy2, float iz2, float ired, float igreen, float iblue) {
  ns2thline(ix1, iy1, iz1, ix2, iy2, iz2, ired, igreen, iblue, 1.);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ns2line>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <ns2thline@plt>
```

assistant: ```c
void ns2line(float ix1, float iy1, float iz1, float ix2, float iy2, float iz2, float ired, float igreen, float iblue) {
  ns2thline(ix1, iy1, iz1, ix2, iy2, iz2, ired, igreen, iblue, 1.);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ns2line>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <ns2thline@plt>
```

assistant: ```c
void ns2line(float ix1, float iy1, float iz1, float ix2, float iy2, float iz2, float ired, float igreen, float iblue) {
  ns2thline(ix1, iy1, iz1, ix2, iy2, iz2, ired, igreen, iblue, 1.);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <memclr@plt>
  movq   $0x0,-0x58(%rbp)
  jmp    L51
L22:
  mov    -0x70(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  shr    $0x4,%rax
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x70(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    -0x70(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  shr    $0x4,%rax
  or     %esi,%edx
  mov    %edx,-0x50(%rbp,%rax,4)
  addq   $0x1,-0x58(%rbp)
L51:
  mov    -0x70(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  movq   $0x0,-0x58(%rbp)
  jmp    L11
L52:
  mov    -0x68(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  shr    $0x4,%rax
  mov    -0x50(%rbp,%rax,4),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x68(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L20
  addq   $0x1,-0x58(%rbp)
L11:
  mov    -0x68(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  jmp    L16
L20:
  nop
L16:
  mov    -0x58(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
size_t strspn(const char *s, const char *accept) {
  uint16_t mask[16];
  size_t i;
  memclr(mask, sizeof(uint16_t) * 16);
  for (i = 0; accept[i]; i++) {
    mask[(size_t)accept[i] >> 4] |= (1 << ((size_t)accept[i] & 0xF));
  }
  for (i = 0; s[i]; i++) {
    if (~mask[(size_t)s[i] >> 4] & (1 << ((size_t)s[i] & 0xF))) {
      break;
    }
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strspn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x40,%esi
  call   <memclr@plt>
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L36
  lea    0x1(%rbp),%rsi
  mov    $0x1,%edi
L60:
  movsbq %cl,%rax
  shr    $0x4,%rax
  and    $0xf,%ecx
  mov    %edi,%edx
  shl    %cl,%edx
  or     %edx,(%rsp,%rax,4)
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%ecx
  test   %cl,%cl
  jne    L60
L36:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L29
  mov    $0x0,%ecx
L63:
  movsbq %al,%rdx
  shr    $0x4,%rdx
  mov    (%rsp,%rdx,4),%edx
  not    %edx
  and    $0xf,%eax
  bt     %eax,%edx
  jb     L25
  add    $0x1,%rcx
  movzbl (%rbx,%rcx,1),%eax
  test   %al,%al
  jne    L63
L25:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %rcx,%rax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    $0x0,%ecx
  jmp    L25
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t strspn(const char *s, const char *accept) {
  uint16_t mask[16];
  size_t i;
  memclr(mask, sizeof(uint16_t) * 16);
  for (i = 0; accept[i]; i++) {
    mask[(size_t)accept[i] >> 4] |= (1 << ((size_t)accept[i] & 0xF));
  }
  for (i = 0; s[i]; i++) {
    if (~mask[(size_t)s[i] >> 4] & (1 << ((size_t)s[i] & 0xF))) {
      break;
    }
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x40,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memclr@plt>
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L59
  lea    0x1(%rbp),%rsi
  mov    $0x1,%edi
  xchg   %ax,%ax
L57:
  movsbq %cl,%rax
  mov    %edi,%edx
  and    $0xf,%ecx
  add    $0x1,%rsi
  shl    %cl,%edx
  movzbl -0x1(%rsi),%ecx
  shr    $0x4,%rax
  or     %edx,(%rsp,%rax,4)
  test   %cl,%cl
  jne    L57
L59:
  movzbl (%rbx),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L1
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L67:
  add    $0x1,%r8
  movzbl (%rbx,%r8,1),%eax
  test   %al,%al
  je     L18
L1:
  movsbq %al,%rdx
  and    $0xf,%eax
  shr    $0x4,%rdx
  mov    (%rsp,%rdx,4),%edx
  not    %edx
  bt     %eax,%edx
  jae    L67
L18:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x58,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t strspn(const char *s, const char *accept) {
  uint16_t mask[16];
  size_t i;
  memclr(mask, sizeof(uint16_t) * 16);
  for (i = 0; accept[i]; i++) {
    mask[(size_t)accept[i] >> 4] |= (1 << ((size_t)accept[i] & 0xF));
  }
  for (i = 0; s[i]; i++) {
    if (~mask[(size_t)s[i] >> 4] & (1 << ((size_t)s[i] & 0xF))) {
      break;
    }
  }
  return i;
}
```