ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rw_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L55
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  xor    %edx,%edx
  mov    %rsp,%r15
  lea    -0x1(%rsp),%r14
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L73:
  cmp    $0x25,%al
  je     L83
L70:
  add    $0x1,%ebp
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
  movslq %ebp,%rdx
  movzbl (%r12,%rdx,1),%eax
  test   %al,%al
  je     L78
L10:
  movslq %ebx,%r13
  cmp    $0x2b,%al
  jne    L73
  mov    $0x20,%eax
  jmp    L70
  nopl   0x0(%rax)
L83:
  lea    0x1(%r12,%rdx,1),%rdi
  add    $0x2,%ebp
  call   <rw_get_hexa@plt>
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L78:
  add    %r15,%r13
L33:
  movb   $0x0,0x0(%r13)
  mov    $0x32,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %rsp,%r15
  mov    %r15,%r13
  jmp    L33
L84:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rw_decode(char *s) {
  char buf[50];
  int i, j;
  for (i = 0, j = 0; *(s + i) != '\0'; i++) {
    if (*(s + i) == '+')
      *(buf + j++) = ' ';
    else if (*(s + i) != '%')
      *(buf + j++) = *(s + i);
    else {
      *(buf + j++) = rw_get_hexa(s + i + 1);
      i += 2;
    }
  }
  *(buf + j) = '\0';
  strncpy(s, buf, 50);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rw_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L63
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  xor    %edx,%edx
  mov    %rsp,%r15
  lea    -0x1(%rsp),%r14
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L75:
  cmp    $0x25,%al
  je     L65
L42:
  add    $0x1,%ebp
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
  movslq %ebp,%rdx
  movzbl (%r12,%rdx,1),%eax
  test   %al,%al
  je     L4
L3:
  movslq %ebx,%r13
  cmp    $0x2b,%al
  jne    L75
  mov    $0x20,%eax
  jmp    L42
  nopl   0x0(%rax)
L65:
  lea    0x1(%r12,%rdx,1),%rdi
  add    $0x2,%ebp
  call   <rw_get_hexa@plt>
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L4:
  add    %r15,%r13
L52:
  movb   $0x0,0x0(%r13)
  mov    $0x32,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  mov    %rsp,%r15
  mov    %r15,%r13
  jmp    L52
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rw_decode(char *s) {
  char buf[50];
  int i, j;
  for (i = 0, j = 0; *(s + i) != '\0'; i++) {
    if (*(s + i) == '+')
      *(buf + j++) = ' ';
    else if (*(s + i) != '%')
      *(buf + j++) = *(s + i);
    else {
      *(buf + j++) = rw_get_hexa(s + i + 1);
      i += 2;
    }
  }
  *(buf + j) = '\0';
  strncpy(s, buf, 50);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<register_signal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <sigfillset@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigaction@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void register_signal(int signal, void (*handler)(int)) {
  sigset_t block_mask;
  struct sigaction saction;
  sigfillset(&block_mask);
  saction.sa_handler = handler;
  saction.sa_mask = block_mask;
  saction.sa_flags = SA_RESTART;
  sigaction(signal, &saction, NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<register_signal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <sigfillset@plt>
  mov    %rbp,0x10(%rsp)
  mov    0xc(%rsp),%eax
  mov    %eax,0x1c(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x18(%rsp)
  lea    0x10(%rsp),%rsi
  mov    $0x0,%edx
  mov    %ebx,%edi
  call   <sigaction@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void register_signal(int signal, void (*handler)(int)) {
  sigset_t block_mask;
  struct sigaction saction;
  sigfillset(&block_mask);
  saction.sa_handler = handler;
  saction.sa_mask = block_mask;
  saction.sa_flags = SA_RESTART;
  sigaction(signal, &saction, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<register_signal>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <sigfillset@plt>
  mov    0xc(%rsp),%eax
  xor    %edx,%edx
  lea    0x10(%rsp),%rsi
  mov    %ebp,%edi
  mov    %rbx,0x10(%rsp)
  mov    %eax,0x1c(%rsp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x18(%rsp)
  call   <sigaction@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void register_signal(int signal, void (*handler)(int)) {
  sigset_t block_mask;
  struct sigaction saction;
  sigfillset(&block_mask);
  saction.sa_handler = handler;
  saction.sa_mask = block_mask;
  saction.sa_flags = SA_RESTART;
  sigaction(signal, &saction, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<register_signal>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <sigfillset@plt>
  mov    D9(%rip),%rax
  xor    %edx,%edx
  mov    %ebp,%edi
  movd   0xc(%rsp),%xmm1
  lea    0x10(%rsp),%rsi
  mov    %rbx,0x10(%rsp)
  movd   (%rax),%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x18(%rsp)
  call   <sigaction@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void register_signal(int signal, void (*handler)(int)) {
  sigset_t block_mask;
  struct sigaction saction;
  sigfillset(&block_mask);
  saction.sa_handler = handler;
  saction.sa_mask = block_mask;
  saction.sa_flags = SA_RESTART;
  sigaction(signal, &saction, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pthread_cancel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pthread_cancel(pthread_t __th) {
  ;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pthread_cancel>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int pthread_cancel(pthread_t __th) {
  ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pthread_cancel>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int pthread_cancel(pthread_t __th) {
  ;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pthread_cancel>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int pthread_cancel(pthread_t __th) {
  ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hann>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L1:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movsd  D9(%rip),%xmm1
  subsd  %xmm0,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D10(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D9
type_guessed: f64
name: retrieve_data
arguments: tag: D10
type_guessed: f64

tool: {"D19": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D9: 1

tool: D10: 0.5

assistant: ```c
void hann(double *window, const int N) {
  int n;
  const double M = N - 1;
  for (n = 0; n < N; n++)
    window[n] = 0.5 * (1.0 - cos(2.0 * 3.14159265358979323846264338327 * (double)n / M));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hann>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  movsd  %xmm3,0x8(%rsp)
  test   %esi,%esi
  jle    L1
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
L17:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D17(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movsd  D29(%rip),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D4(%rip),%xmm0
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
L1:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D17
data_type: byte[8]
name: read_data
arguments: tag: D29
data_type: f64
name: read_data
arguments: tag: D4
data_type: f64

tool: {"D17": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D29: 1

tool: D4: 0.5

assistant: ```c
void hann(double *window, const int N) {
  int n;
  const double M = N - 1;
  for (n = 0; n < N; n++)
    window[n] = 0.5 * (1.0 - cos(2.0 * 3.14159265358979323846264338327 * (double)n / M));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hann>:
  endbr64
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  push   %r12
  cvtsi2sd %eax,%xmm3
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm3,0x8(%rsp)
  test   %esi,%esi
  jle    L5
  mov    %rdi,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L13:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D3(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movsd  D10(%rip),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D25(%rip),%xmm0
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L13
L5:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: byte[8]
name: extract_symbolic_data
arguments: label: D10
type: f64
name: extract_symbolic_data
arguments: label: D25
type: f64

tool: {"D3": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D10: 1

tool: D25: 0.5

assistant: ```c
void hann(double *window, const int N) {
  int n;
  const double M = N - 1;
  for (n = 0; n < N; n++)
    window[n] = 0.5 * (1.0 - cos(2.0 * 3.14159265358979323846264338327 * (double)n / M));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hann>:
  endbr64
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  push   %r12
  cvtsi2sd %eax,%xmm3
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm3,0x8(%rsp)
  test   %esi,%esi
  jle    L16
  mov    %rdi,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L1:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D10(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movsd  D29(%rip),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D24(%rip),%xmm0
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L1
L16:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D29
type_infered: f64
name: retrieve_data
arguments: data_tag: D24
type_infered: f64

tool: {"D10": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D29: 1

tool: D24: 0.5

assistant: ```c
void hann(double *window, const int N) {
  int n;
  const double M = N - 1;
  for (n = 0; n < N; n++)
    window[n] = 0.5 * (1.0 - cos(2.0 * 3.14159265358979323846264338327 * (double)n / M));
}
```
user: What is the c source code of the assembly code below?

```asm
<str_skip_whitespaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L50
L25:
  addq   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L25
L47:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *str_skip_whitespaces(char *str) {
  while (*str && (*str == ' ' || *str == '\t' || *str == '\n' || *str == '\r'))
    str++;
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_skip_whitespaces>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  movabs $0x100002600,%rcx
  test   %dl,%dl
  jne    L10
  ret
L15:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L11
L10:
  cmp    $0x20,%dl
  ja     L11
  bt     %rdx,%rcx
  jb     L15
L11:
  ret
```

assistant: ```c
char *str_skip_whitespaces(char *str) {
  while (*str && (*str == ' ' || *str == '\t' || *str == '\n' || *str == '\r'))
    str++;
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_skip_whitespaces>:
  endbr64
  movabs $0x100002600,%rcx
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L27
  nopl   0x0(%rax,%rax,1)
L18:
  cmp    $0x20,%dl
  ja     L11
  bt     %rdx,%rcx
  jb     L8
L11:
  ret
  nopl   0x0(%rax)
L8:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L18
  ret
L27:
  ret
```

assistant: ```c
char *str_skip_whitespaces(char *str) {
  while (*str && (*str == ' ' || *str == '\t' || *str == '\n' || *str == '\r'))
    str++;
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_skip_whitespaces>:
  endbr64
  movabs $0x100002600,%rcx
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L8
  nopl   0x0(%rax,%rax,1)
L25:
  cmp    $0x20,%dl
  ja     L4
  bt     %rdx,%rcx
  jb     L37
L4:
  ret
  nopl   0x0(%rax)
L37:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L25
  ret
L8:
  ret
```

assistant: ```c
char *str_skip_whitespaces(char *str) {
  while (*str && (*str == ' ' || *str == '\t' || *str == '\n' || *str == '\r'))
    str++;
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<four_branch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L3:
  movl   $0x1,-0x4(%rbp)
  jmp    L11
L9:
  cmpl   $0x0,-0x4(%rbp)
  je     L32
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L32:
  movl   $0x1,-0x4(%rbp)
L11:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void four_branch() {
  int x;
  if (x) {
    if (x) {
      x = 0;
    } else {
      x = 1;
    }
  } else {
    if (x) {
      x = 0;
    } else {
      x = 1;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<four_branch>:
  endbr64
  ret
```

assistant: ```c
void four_branch() {
  int x;
  if (x) {
    if (x) {
      x = 0;
    } else {
      x = 1;
    }
  } else {
    if (x) {
      x = 0;
    } else {
      x = 1;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<four_branch>:
  endbr64
  ret
```

assistant: ```c
void four_branch() {
  int x;
  if (x) {
    if (x) {
      x = 0;
    } else {
      x = 1;
    }
  } else {
    if (x) {
      x = 0;
    } else {
      x = 1;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<four_branch>:
  endbr64
  ret
```

assistant: ```c
void four_branch() {
  int x;
  if (x) {
    if (x) {
      x = 0;
    } else {
      x = 1;
    }
  } else {
    if (x) {
      x = 0;
    } else {
      x = 1;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<format_comma_separated_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jns    L29
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2d,(%rax)
  negl   -0x2c(%rbp)
L29:
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L43
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x30,(%rax)
  jmp    L23
L43:
  movl   $0x0,-0x18(%rbp)
  jmp    L12
L37:
  cmpl   $0x3,-0x18(%rbp)
  jne    L40
  movl   $0x0,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2c,(%rax)
L40:
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x18(%rbp)
L12:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L37
L23:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
  jmp    L77
L31:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl -0x19(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  subq   $0x1,-0x10(%rbp)
L77:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  ja     L31
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void format_comma_separated_integer(char **dest, int value) {
  int digit, groupIndex;
  char *dst = *dest;
  char *finish;
  char tmp;
  if (value < 0) {
    *dst++ = '-';
    value = -value;
  }
  *dest = dst;
  if (value == 0) {
    *dst++ = '0';
  } else {
    groupIndex = 0;
    while (value > 0) {
      if (groupIndex == 3) {
        groupIndex = 0;
        *dst++ = ',';
      }
      digit = value % 10;
      value /= 10;
      *dst++ = '0' + digit;
      groupIndex++;
    }
  }
  finish = dst;
  dst--;
  while (*dest < dst) {
    tmp = **dest;
    **dest = *dst;
    *dst = tmp;
    (*dest)++;
    dst--;
  }
  *dest = finish;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<format_comma_separated_integer>:
  endbr64
  mov    %rdi,%rcx
  mov    (%rdi),%rax
  test   %esi,%esi
  js     L47
  jne    L1
  lea    0x1(%rax),%r10
  movb   $0x30,(%rax)
L62:
  lea    -0x1(%r10),%rdx
  mov    (%rcx),%rax
  cmp    %rax,%rdx
  jbe    L36
L81:
  movzbl (%rax),%esi
  movzbl (%rdx),%edi
  mov    %dil,(%rax)
  mov    %sil,(%rdx)
  mov    (%rcx),%rax
  add    $0x1,%rax
  mov    %rax,(%rcx)
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  jb     L81
L36:
  mov    %r10,(%rcx)
  ret
L47:
  lea    0x1(%rax),%r8
  movb   $0x2d,(%rax)
  neg    %esi
  mov    %r8,(%rdi)
L68:
  mov    $0x0,%r9d
  jmp    L89
L1:
  mov    %rax,%r10
  jle    L62
  mov    %rax,%r8
  jmp    L68
L69:
  mov    %eax,%esi
  mov    %r10,%r8
L89:
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x1(%r8),%r10
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  mov    %esi,%edx
  sub    %edi,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  add    $0x1,%r9d
  cmp    $0x9,%esi
  jle    L62
  cmp    $0x3,%r9d
  jne    L69
  lea    0x2(%r8),%r10
  movb   $0x2c,0x1(%r8)
  mov    $0x0,%r9d
  jmp    L69
```

assistant: ```c
void format_comma_separated_integer(char **dest, int value) {
  int digit, groupIndex;
  char *dst = *dest;
  char *finish;
  char tmp;
  if (value < 0) {
    *dst++ = '-';
    value = -value;
  }
  *dest = dst;
  if (value == 0) {
    *dst++ = '0';
  } else {
    groupIndex = 0;
    while (value > 0) {
      if (groupIndex == 3) {
        groupIndex = 0;
        *dst++ = ',';
      }
      digit = value % 10;
      value /= 10;
      *dst++ = '0' + digit;
      groupIndex++;
    }
  }
  finish = dst;
  dst--;
  while (*dest < dst) {
    tmp = **dest;
    **dest = *dst;
    *dst = tmp;
    (*dest)++;
    dst--;
  }
  *dest = finish;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<format_comma_separated_integer>:
  endbr64
  mov    (%rdi),%rax
  mov    %rdi,%rcx
  lea    0x1(%rax),%r10
  test   %esi,%esi
  js     L32
  jne    L68
  movb   $0x30,(%rax)
L43:
  mov    (%rcx),%rdx
  cmp    %rdx,%rax
  jbe    L64
  nop
L73:
  movzbl (%rdx),%esi
  movzbl (%rax),%edi
  sub    $0x1,%rax
  mov    %dil,(%rdx)
  mov    %sil,0x1(%rax)
  mov    (%rcx),%rsi
  lea    0x1(%rsi),%rdx
  mov    %rdx,(%rcx)
  cmp    %rax,%rdx
  jb     L73
L64:
  mov    %r10,(%rcx)
  ret
  nopl   0x0(%rax)
L32:
  movb   $0x2d,(%rax)
  neg    %esi
  mov    %r10,%rax
  mov    %r10,(%rdi)
  add    $0x1,%r10
L68:
  xor    %r9d,%r9d
  mov    $0xcccccccd,%r11d
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L44:
  cmp    $0x3,%r9d
  jne    L63
  movb   $0x2c,0x1(%rax)
  lea    0x2(%rax),%rdi
  xor    %r9d,%r9d
L63:
  mov    %rdi,%rax
  lea    0x1(%rdi),%r10
L0:
  mov    %esi,%edx
  add    $0x1,%r9d
  imul   %r11,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r8d
  mov    %edx,%edi
  add    %r8d,%r8d
  sub    %r8d,%esi
  mov    %esi,%edx
  mov    %edi,%esi
  mov    %r10,%rdi
  add    $0x30,%edx
  mov    %dl,(%rax)
  test   %esi,%esi
  jne    L44
  jmp    L43
```

assistant: ```c
void format_comma_separated_integer(char **dest, int value) {
  int digit, groupIndex;
  char *dst = *dest;
  char *finish;
  char tmp;
  if (value < 0) {
    *dst++ = '-';
    value = -value;
  }
  *dest = dst;
  if (value == 0) {
    *dst++ = '0';
  } else {
    groupIndex = 0;
    while (value > 0) {
      if (groupIndex == 3) {
        groupIndex = 0;
        *dst++ = ',';
      }
      digit = value % 10;
      value /= 10;
      *dst++ = '0' + digit;
      groupIndex++;
    }
  }
  finish = dst;
  dst--;
  while (*dest < dst) {
    tmp = **dest;
    **dest = *dst;
    *dst = tmp;
    (*dest)++;
    dst--;
  }
  *dest = finish;
}
```