user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D45(%rip),%r15
  push   %r14
  mov    $0xffffffff,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x58,%rsp
  movdqa D10(%rip),%xmm0
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x38,0x40(%rsp)
  lea    0x10(%rsp),%r12
  movaps %xmm0,0x10(%rsp)
  movdqa D1(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D38(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <atoi@plt>
  mov    %eax,%r13d
  nopl   0x0(%rax)
L40:
  mov    (%r12,%rbx,4),%ebp
  xor    %eax,%eax
  mov    %r15,%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  cmp    %r13d,%ebp
  cmove  %ebx,%r14d
  add    $0x1,%rbx
  cmp    $0xd,%rbx
  jne    L40
  mov    %r13d,%esi
  lea    D64(%rip),%rdi
  xor    %eax,%eax
  movslq %r14d,%r13
  add    $0x1,%r14d
  lea    -0x4(%r12,%r13,4),%rbx
  lea    D28(%rip),%rbp
  call   <printf@plt>
  movslq %r14d,%r14
  lea    0x44(%rsp),%rax
  lea    (%r12,%r14,4),%r15
  mov    %rax,(%rsp)
  xor    %r14d,%r14d
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L112:
  mov    %edx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <printf@plt>
L11:
  cmp    $0x4,%r14d
  je     L84
L60:
  mov    %r15,%rax
  sub    %rbx,%rax
  cmp    $0x30,%rax
  jg     L84
  cmp    %r12,%rbx
  jb     L91
  mov    (%rbx),%esi
  cmp    (%rsp),%r15
  jae    L94
  mov    0x10(%rsp,%r13,4),%eax
  mov    (%r15),%edx
  mov    %eax,%r10d
  mov    %edx,%edi
  sub    %esi,%r10d
  sub    %eax,%edi
  cmp    %edi,%r10d
  jl     L94
  add    $0x4,%r15
  cmp    %edi,%r10d
  jg     L112
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  add    $0x2,%r14d
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x4,%r14d
  jne    L60
  nopw   0x0(%rax,%rax,1)
L84:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L94:
  mov    %rbp,%rdi
  xor    %eax,%eax
  sub    $0x4,%rbx
  add    $0x1,%r14d
  call   <printf@plt>
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L91:
  lea    0x4(%r15),%rax
  mov    (%r15),%esi
  mov    %rbp,%rdi
  add    $0x1,%r14d
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r15
  jmp    L11
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D45
data_type: string
name: read_data
arguments: tag: D10
data_type: byte[16]
name: read_data
arguments: tag: D1
data_type: byte[16]
name: read_data
arguments: tag: D38
data_type: byte[16]
name: read_data
arguments: tag: D64
data_type: string
name: read_data
arguments: tag: D28
data_type: string
name: read_data
arguments: tag: D29
data_type: string

tool: D45: %d 

tool: {"D10": [0x0c,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x16,0x00,0x00,0x00,0x1e,0x00,0x00,0x00]}

tool: {"D1": [0x23,0x00,0x00,0x00,0x27,0x00,0x00,0x00,0x2a,0x00,0x00,0x00,0x2d,0x00,0x00,0x00]}

tool: {"D38": [0x30,0x00,0x00,0x00,0x32,0x00,0x00,0x00,0x35,0x00,0x00,0x00,0x37,0x00,0x00,0x00]}

tool: D64: 
number: %d


tool: D28:  %d 

tool: D29:  %d  %d

assistant: ```c
int main(int argc, char *argv[]) {
  int seq[13] = {12, 16, 22, 30, 35, 39, 42, 45, 48, 50, 53, 55, 56};
  int *left = seq;
  int *right = seq + 13;
  int k = 4;
  int index = -1;
  int found = 0;
  int i;
  int number = atoi(argv[1]);
  for (i = 0; i < 13; i++) {
    printf("%d ", seq[i]);
    if (seq[i] == number) {
      index = i;
    }
  }
  printf("\nnumber: %d\n", number);
  left = seq + index - 1;
  right = seq + index + 1;
  while (found != k && right - left < 13) {
    if (left < seq) {
      printf(" %d ", *right++);
      found++;
      continue;
    }
    if (right >= seq + 13) {
      printf(" %d ", *left--);
      found++;
      continue;
    }
    if ((seq[index] - *left) < (*right - seq[index])) {
      printf(" %d ", *left--);
      found++;
    } else if ((seq[index] - *left) > (*right - seq[index])) {
      printf(" %d ", *right++);
      found++;
    } else {
      printf(" %d  %d", *left--, *right++);
      found += 2;
    }
  }
  printf("\n");
}
```