ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc0(%rbp),%rax
  mov    %rax,%rdi
  call   <read_string@plt>
  mov    %eax,-0xd0(%rbp)
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <read_string@plt>
  mov    %eax,-0xcc(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <read_string@plt>
  mov    %eax,-0xc8(%rbp)
  mov    -0xcc(%rbp),%ecx
  mov    -0xd0(%rbp),%edx
  lea    -0x80(%rbp),%rsi
  lea    -0xc0(%rbp),%rax
  mov    %rax,%rdi
  call   <check_substring@plt>
  mov    %eax,-0xc4(%rbp)
  cmpl   $0x0,-0xc4(%rbp)
  jne    L58
  movl   $0x0,-0xd4(%rbp)
  jmp    L47
L65:
  mov    -0xd4(%rbp),%eax
  cltq
  movzbl -0xc0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xd4(%rbp)
L47:
  mov    -0xd4(%rbp),%eax
  cmp    -0xd0(%rbp),%eax
  jl     L65
  jmp    L60
L58:
  movl   $0x0,-0xd4(%rbp)
  jmp    L67
L101:
  mov    -0xd4(%rbp),%eax
  cltq
  movzbl -0xc0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xd4(%rbp)
L67:
  mov    -0xd4(%rbp),%eax
  cmp    -0xc4(%rbp),%eax
  jl     L101
  movl   $0x0,-0xd4(%rbp)
  jmp    L86
L103:
  mov    -0xd4(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xd4(%rbp)
L86:
  mov    -0xd4(%rbp),%eax
  cmp    -0xc8(%rbp),%eax
  jl     L103
  mov    -0xc4(%rbp),%eax
  mov    %eax,-0xd4(%rbp)
  jmp    L17
L95:
  mov    -0xd4(%rbp),%eax
  cltq
  movzbl -0xc0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xd4(%rbp)
L17:
  mov    -0xd4(%rbp),%eax
  cmp    -0xd0(%rbp),%eax
  jl     L95
L60:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
type_guessed: string

tool: D20: %c

assistant: ```c
int main() {
  char str[50], s1[50], s2[50];
  int length, length1, length2, place, i, newlength;
  length = read_string(str);
  length1 = read_string(s1);
  length2 = read_string(s2);
  place = check_substring(str, s1, length, length1);
  if (place == 0) {
    for (i = 0; i < length; i++) {
      printf("%c", str[i]);
    }
  } else {
    for (i = 0; i < place; i++) {
      printf("%c", str[i]);
    }
    for (i = 0; i < length2; i++) {
      printf("%c", s2[i]);
    }
    for (i = place; i < length; i++) {
      printf("%c", str[i]);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <read_string@plt>
  mov    %eax,%ebp
  lea    0x40(%rsp),%r13
  mov    %r13,%rdi
  call   <read_string@plt>
  mov    %eax,%ebx
  lea    0x80(%rsp),%rdi
  call   <read_string@plt>
  mov    %eax,%r14d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <check_substring@plt>
  test   %eax,%eax
  je     L19
  mov    %eax,%r12d
  jle    L54
  mov    %rsp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rsp,%rax,1),%r15
  lea    D10(%rip),%r13
L76:
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L76
L54:
  test   %r14d,%r14d
  jle    L28
  lea    0x80(%rsp),%rbx
  lea    -0x1(%r14),%eax
  lea    0x81(%rsp,%rax,1),%r14
  lea    D10(%rip),%r13
L24:
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L24
L28:
  cmp    %r12d,%ebp
  jle    L17
  movslq %r12d,%rax
  lea    (%rsp,%rax,1),%rbx
  lea    0x1(%rsp,%rax,1),%rax
  sub    $0x1,%ebp
  sub    %r12d,%ebp
  add    %rax,%rbp
  lea    D10(%rip),%r12
L35:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L35
  jmp    L17
L19:
  test   %ebp,%ebp
  jle    L17
  mov    %rsp,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%rsp,%rax,1),%r12
  lea    D10(%rip),%rbp
L8:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L8
L17:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0xc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
datatype: string

tool: D10: %c

assistant: ```c
int main() {
  char str[50], s1[50], s2[50];
  int length, length1, length2, place, i, newlength;
  length = read_string(str);
  length1 = read_string(s1);
  length2 = read_string(s2);
  place = check_substring(str, s1, length, length1);
  if (place == 0) {
    for (i = 0; i < length; i++) {
      printf("%c", str[i]);
    }
  } else {
    for (i = 0; i < place; i++) {
      printf("%c", str[i]);
    }
    for (i = 0; i < length2; i++) {
      printf("%c", s2[i]);
    }
    for (i = place; i < length; i++) {
      printf("%c", str[i]);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x50(%rsp),%r14
  mov    %rbx,%rdi
  call   <read_string@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <read_string@plt>
  mov    %eax,%r12d
  lea    0x90(%rsp),%rax
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <read_string@plt>
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    %eax,0x4(%rsp)
  call   <check_substring@plt>
  test   %eax,%eax
  je     L69
  mov    %eax,%r14d
  jle    L10
  lea    -0x1(%rax),%eax
  mov    %rbx,%rbp
  lea    D13(%rip),%r12
  lea    0x11(%rsp,%rax,1),%r15
  nopl   0x0(%rax)
L16:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L16
L10:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L20
  sub    $0x1,%eax
  mov    0x8(%rsp),%rbp
  lea    D13(%rip),%r12
  lea    0x91(%rsp,%rax,1),%r15
  nopl   0x0(%rax)
L3:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L3
L20:
  cmp    %r14d,%r13d
  jle    L11
  movslq %r14d,%rax
  sub    $0x1,%r13d
  lea    D13(%rip),%r12
  lea    0x11(%rsp,%rax,1),%rbp
  sub    %r14d,%r13d
  add    %rax,%rbx
  add    %r13,%rbp
  cs nopw 0x0(%rax,%rax,1)
L97:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L97
L11:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  test   %r13d,%r13d
  jle    L11
  lea    -0x1(%r13),%eax
  lea    D13(%rip),%r12
  lea    0x11(%rsp,%rax,1),%rbp
L101:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L101
  jmp    L11
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string

tool: D13: %c

assistant: ```c
int main() {
  char str[50], s1[50], s2[50];
  int length, length1, length2, place, i, newlength;
  length = read_string(str);
  length1 = read_string(s1);
  length2 = read_string(s2);
  place = check_substring(str, s1, length, length1);
  if (place == 0) {
    for (i = 0; i < length; i++) {
      printf("%c", str[i]);
    }
  } else {
    for (i = 0; i < place; i++) {
      printf("%c", str[i]);
    }
    for (i = 0; i < length2; i++) {
      printf("%c", s2[i]);
    }
    for (i = place; i < length; i++) {
      printf("%c", str[i]);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x50(%rsp),%r14
  mov    %rbx,%rdi
  call   <read_string@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <read_string@plt>
  mov    %eax,%r12d
  lea    0x90(%rsp),%rax
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <read_string@plt>
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    %eax,0x4(%rsp)
  call   <check_substring@plt>
  test   %eax,%eax
  je     L73
  mov    %eax,%r14d
  jle    L102
  lea    -0x1(%rax),%eax
  mov    %rbx,%rbp
  lea    D3(%rip),%r12
  lea    0x11(%rsp,%rax,1),%r15
  nopl   0x0(%rax)
L49:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L49
L102:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L77
  sub    $0x1,%eax
  mov    0x8(%rsp),%rbp
  lea    D3(%rip),%r12
  lea    0x91(%rsp,%rax,1),%r15
  nopl   0x0(%rax)
L67:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L67
L77:
  cmp    %r14d,%r13d
  jle    L63
  movslq %r14d,%rax
  sub    $0x1,%r13d
  lea    D3(%rip),%r12
  lea    0x11(%rsp,%rax,1),%rbp
  sub    %r14d,%r13d
  add    %rax,%rbx
  add    %r13,%rbp
  cs nopw 0x0(%rax,%rax,1)
L42:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L42
L63:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L73:
  test   %r13d,%r13d
  jle    L63
  lea    -0x1(%r13),%eax
  lea    D3(%rip),%r12
  lea    0x11(%rsp,%rax,1),%rbp
L107:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L107
  jmp    L63
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: %c

assistant: ```c
int main() {
  char str[50], s1[50], s2[50];
  int length, length1, length2, place, i, newlength;
  length = read_string(str);
  length1 = read_string(s1);
  length2 = read_string(s2);
  place = check_substring(str, s1, length, length1);
  if (place == 0) {
    for (i = 0; i < length; i++) {
      printf("%c", str[i]);
    }
  } else {
    for (i = 0; i < place; i++) {
      printf("%c", str[i]);
    }
    for (i = 0; i < length2; i++) {
      printf("%c", s2[i]);
    }
    for (i = place; i < length; i++) {
      printf("%c", str[i]);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recv_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <mkstemp@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L0
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <recv_file_nowrite@plt>
  jmp    L27
L0:
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <actually_recv_file@plt>
L27:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string

tool: D8: %s.XXXXXX

assistant: ```c
void recv_file(char *fname) {
  int tmpfd;
  char *tempfile;
  asprintf(&tempfile, "%s.XXXXXX", fname);
  tmpfd = mkstemp(tempfile);
  if (tmpfd < 0)
    recv_file_nowrite(fname);
  else
    actually_recv_file(fname, tempfile, tmpfd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<recv_file>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  lea    D5(%rip),%rsi
  call   <asprintf@plt>
  mov    (%rsp),%rdi
  call   <mkstemp@plt>
  test   %eax,%eax
  js     L3
  mov    %eax,%edx
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  call   <actually_recv_file@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  mov    %rbx,%rdi
  call   <recv_file_nowrite@plt>
  jmp    L25
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: %s.XXXXXX

assistant: ```c
void recv_file(char *fname) {
  int tmpfd;
  char *tempfile;
  asprintf(&tempfile, "%s.XXXXXX", fname);
  tmpfd = mkstemp(tempfile);
  if (tmpfd < 0)
    recv_file_nowrite(fname);
  else
    actually_recv_file(fname, tempfile, tmpfd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recv_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D2(%rip),%rsi
  mov    %rbp,%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rdi
  call   <mkstemp@plt>
  test   %eax,%eax
  js     L26
  mov    (%rsp),%rsi
  mov    %eax,%edx
  mov    %rbp,%rdi
  call   <actually_recv_file@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  pop    %rbp
  ret
  nop
L26:
  mov    %rbp,%rdi
  call   <recv_file_nowrite@plt>
  jmp    L1
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: %s.XXXXXX

assistant: ```c
void recv_file(char *fname) {
  int tmpfd;
  char *tempfile;
  asprintf(&tempfile, "%s.XXXXXX", fname);
  tmpfd = mkstemp(tempfile);
  if (tmpfd < 0)
    recv_file_nowrite(fname);
  else
    actually_recv_file(fname, tempfile, tmpfd);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<recv_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D4(%rip),%rsi
  mov    %rbp,%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rdi
  call   <mkstemp@plt>
  test   %eax,%eax
  js     L28
  mov    (%rsp),%rsi
  mov    %eax,%edx
  mov    %rbp,%rdi
  call   <actually_recv_file@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  pop    %rbp
  ret
  nop
L28:
  mov    %rbp,%rdi
  call   <recv_file_nowrite@plt>
  jmp    L9
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D4: %s.XXXXXX

assistant: ```c
void recv_file(char *fname) {
  int tmpfd;
  char *tempfile;
  asprintf(&tempfile, "%s.XXXXXX", fname);
  tmpfd = mkstemp(tempfile);
  if (tmpfd < 0)
    recv_file_nowrite(fname);
  else
    actually_recv_file(fname, tempfile, tmpfd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L1
L15:
  cmpl   $0x1,-0x14(%rbp)
  jne    L7
  mov    $0x1,%eax
  jmp    L1
L7:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 0)
    return 0;
  if (n == 1)
    return 1;
  return fib(n - 1) + fib(n - 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  je     L3
  cmp    $0x1,%edi
  je     L3
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  lea    0x0(%rbp,%rax,1),%ebx
L3:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 0)
    return 0;
  if (n == 1)
    return 1;
  return fib(n - 1) + fib(n - 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ti_wad_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ti_wad_start(double const *options) {
  (void)options;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ti_wad_start>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ti_wad_start(double const *options) {
  (void)options;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ti_wad_start>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ti_wad_start(double const *options) {
  (void)options;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ti_wad_start>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ti_wad_start(double const *options) {
  (void)options;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<multiply282>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L0
L6:
  movl   $0x0,-0x3c(%rbp)
  jmp    L1
L34:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L1:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L34
  addl   $0x1,-0x40(%rbp)
L0:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L6
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply282(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<multiply282>:
  endbr64
  test   %edi,%edi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L14:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L21:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L21
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  ret
```

assistant: ```c
void multiply282(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply282>:
  endbr64
  test   %edi,%edi
  jle    L16
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L6
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L18
  pop    %rbx
  ret
L16:
  ret
```

assistant: ```c
void multiply282(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```