ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<mytime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
char *mytime() {
  time_t t;
  char *s;
  t = time(NULL);
  s = ctime(&t);
  s[strlen(s) - 1] = '\0';
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mytime>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <ctime@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *mytime() {
  time_t t;
  char *s;
  t = time(NULL);
  s = ctime(&t);
  s[strlen(s) - 1] = '\0';
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mytime>:
  endbr64
  push   %r12
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *mytime() {
  time_t t;
  char *s;
  t = time(NULL);
  s = ctime(&t);
  s[strlen(s) - 1] = '\0';
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mytime>:
  endbr64
  push   %r12
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *mytime() {
  time_t t;
  char *s;
  t = time(NULL);
  s = ctime(&t);
  s[strlen(s) - 1] = '\0';
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func_13f8_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L0:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%esi
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  xor    %ecx,%esi
  mov    %esi,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x7,-0x4(%rbp)
  jle    L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func_13f8_c(uint32_t *out, uint32_t *in_1, uint32_t *in_2) {
  for (int i = 0; i < 8; i++) {
    *out++ = *in_1++ ^ *in_2++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<func_13f8_c>:
  endbr64
  mov    $0x0,%eax
L4:
  mov    (%rsi,%rax,1),%ecx
  xor    (%rdx,%rax,1),%ecx
  mov    %ecx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x20,%rax
  jne    L4
  ret
```

assistant: ```c
void func_13f8_c(uint32_t *out, uint32_t *in_1, uint32_t *in_2) {
  for (int i = 0; i < 8; i++) {
    *out++ = *in_1++ ^ *in_2++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<func_13f8_c>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    (%rsi,%rax,1),%ecx
  xor    (%rdx,%rax,1),%ecx
  mov    %ecx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x20,%rax
  jne    L4
  ret
```

assistant: ```c
void func_13f8_c(uint32_t *out, uint32_t *in_1, uint32_t *in_2) {
  for (int i = 0; i < 8; i++) {
    *out++ = *in_1++ ^ *in_2++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func_13f8_c>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  lea    0x4(%rsi),%rdi
  mov    %rax,%rsi
  sub    %rdi,%rsi
  cmp    $0x8,%rsi
  jbe    L4
  lea    0x4(%rdx),%rdi
  mov    %rax,%rsi
  sub    %rdi,%rsi
  cmp    $0x8,%rsi
  jbe    L4
  movdqu (%rcx),%xmm0
  movdqu (%rdx),%xmm2
  pxor   %xmm2,%xmm0
  movups %xmm0,(%rax)
  movdqu 0x10(%rcx),%xmm0
  movdqu 0x10(%rdx),%xmm1
  pxor   %xmm1,%xmm0
  movups %xmm0,0x10(%rax)
  ret
  nopl   0x0(%rax)
L4:
  mov    (%rcx),%esi
  xor    (%rdx),%esi
  mov    %esi,(%rax)
  mov    0x4(%rcx),%esi
  xor    0x4(%rdx),%esi
  mov    %esi,0x4(%rax)
  mov    0x8(%rcx),%esi
  xor    0x8(%rdx),%esi
  mov    %esi,0x8(%rax)
  mov    0xc(%rcx),%esi
  xor    0xc(%rdx),%esi
  mov    %esi,0xc(%rax)
  mov    0x10(%rcx),%esi
  xor    0x10(%rdx),%esi
  mov    %esi,0x10(%rax)
  mov    0x14(%rcx),%esi
  xor    0x14(%rdx),%esi
  mov    %esi,0x14(%rax)
  mov    0x18(%rcx),%esi
  xor    0x18(%rdx),%esi
  mov    %esi,0x18(%rax)
  mov    0x1c(%rcx),%ecx
  xor    0x1c(%rdx),%ecx
  mov    %ecx,0x1c(%rax)
  ret
```

assistant: ```c
void func_13f8_c(uint32_t *out, uint32_t *in_1, uint32_t *in_2) {
  for (int i = 0; i < 8; i++) {
    *out++ = *in_1++ ^ *in_2++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fitwidth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    $0x41,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0x20,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    D38(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  cmpq   $0x0,-0x18(%rbp)
  je     L0
  cmpl   $0x42,-0x1c(%rbp)
  je     L0
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L24
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <memcpy@plt>
L0:
  lea    D38(%rip),%rax
  leave
  ret
```

assistant: ```c
char *fitwidth(char *str, int decr) {
  static char buf[65 + 1];
  int len = strlen(str);
  int maxlen = sizeof(buf) - 1 - decr;
  memset(buf, ' ', maxlen);
  buf[maxlen] = 0;
  if (str && sizeof(buf) - decr >= 1) {
    if (len > maxlen)
      len = maxlen;
    memcpy(buf, str, len);
  }
  return (buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fitwidth>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    $0x41,%ebx
  sub    %r12d,%ebx
  mov    %ebx,%edx
  mov    $0x20,%esi
  lea    D14(%rip),%r14
  mov    %r14,%rdi
  call   <memset@plt>
  movslq %ebx,%rax
  movb   $0x0,(%r14,%rax,1)
  test   %rbp,%rbp
  je     L2
  cmp    $0x42,%r12d
  jne    L4
L2:
  lea    D14(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  cmp    %ebx,%r13d
  mov    %ebx,%edx
  cmovle %r13d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L2
```

assistant: ```c
char *fitwidth(char *str, int decr) {
  static char buf[65 + 1];
  int len = strlen(str);
  int maxlen = sizeof(buf) - 1 - decr;
  memset(buf, ' ', maxlen);
  buf[maxlen] = 0;
  if (str && sizeof(buf) - decr >= 1) {
    if (len > maxlen)
      len = maxlen;
    memcpy(buf, str, len);
  }
  return (buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fitwidth>:
  endbr64
  push   %r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x41,%ebx
  sub    %r12d,%ebx
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    $0x20,%esi
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <memset@plt>
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  test   %rbp,%rbp
  je     L4
  cmp    $0x42,%r12d
  jne    L15
L4:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  cmp    %ebx,%r14d
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  cmovle %r14d,%edx
  call   <memcpy@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *fitwidth(char *str, int decr) {
  static char buf[65 + 1];
  int len = strlen(str);
  int maxlen = sizeof(buf) - 1 - decr;
  memset(buf, ' ', maxlen);
  buf[maxlen] = 0;
  if (str && sizeof(buf) - decr >= 1) {
    if (len > maxlen)
      len = maxlen;
    memcpy(buf, str, len);
  }
  return (buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fitwidth>:
  endbr64
  push   %r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x41,%ebx
  sub    %r12d,%ebx
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    $0x20,%esi
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <memset@plt>
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  test   %rbp,%rbp
  je     L12
  cmp    $0x42,%r12d
  jne    L3
L12:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  cmp    %ebx,%r14d
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  cmovle %r14d,%edx
  call   <memcpy@plt>
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *fitwidth(char *str, int decr) {
  static char buf[65 + 1];
  int len = strlen(str);
  int maxlen = sizeof(buf) - 1 - decr;
  memset(buf, ' ', maxlen);
  buf[maxlen] = 0;
  if (str && sizeof(buf) - decr >= 1) {
    if (len > maxlen)
      len = maxlen;
    memcpy(buf, str, len);
  }
  return (buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CRYPTO_dbg_pop_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <is_MemCheck_on@plt>
  test   %rax,%rax
  je     L8
  mov    $0x0,%eax
  call   <MemCheck_off@plt>
  mov    $0x0,%eax
  call   <pop_info@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <MemCheck_on@plt>
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int CRYPTO_dbg_pop_info(void) {
  int ret = 0;
  if (is_MemCheck_on()) {
    MemCheck_off();
    ret = (pop_info() != NULL);
    MemCheck_on();
  }
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CRYPTO_dbg_pop_info>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <is_MemCheck_on@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  jne    L14
L18:
  mov    %ebx,%eax
  pop    %rbx
  ret
L14:
  mov    $0x0,%eax
  call   <MemCheck_off@plt>
  mov    $0x0,%eax
  call   <pop_info@plt>
  test   %rax,%rax
  setne  %bl
  movzbl %bl,%ebx
  mov    $0x0,%eax
  call   <MemCheck_on@plt>
  jmp    L18
```

assistant: ```c
int CRYPTO_dbg_pop_info(void) {
  int ret = 0;
  if (is_MemCheck_on()) {
    MemCheck_off();
    ret = (pop_info() != NULL);
    MemCheck_on();
  }
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<CRYPTO_dbg_pop_info>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <is_MemCheck_on@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <MemCheck_off@plt>
  xor    %eax,%eax
  call   <pop_info@plt>
  test   %rax,%rax
  setne  %r12b
  xor    %eax,%eax
  call   <MemCheck_on@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int CRYPTO_dbg_pop_info(void) {
  int ret = 0;
  if (is_MemCheck_on()) {
    MemCheck_off();
    ret = (pop_info() != NULL);
    MemCheck_on();
  }
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CRYPTO_dbg_pop_info>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <is_MemCheck_on@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <MemCheck_off@plt>
  xor    %eax,%eax
  call   <pop_info@plt>
  test   %rax,%rax
  setne  %r12b
  xor    %eax,%eax
  call   <MemCheck_on@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int CRYPTO_dbg_pop_info(void) {
  int ret = 0;
  if (is_MemCheck_on()) {
    MemCheck_off();
    ret = (pop_info() != NULL);
    MemCheck_on();
  }
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<tk_print_decimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %edi,-0x134(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x134(%rbp)
  jne    L132
  mov    $0x30,%edi
  call   <tk_putc@plt>
  jmp    L7
L132:
  cmpl   $0x80000000,-0x134(%rbp)
  jne    L0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <tk_puts@plt>
  jmp    L7
L0:
  mov    -0x134(%rbp),%eax
  mov    %eax,-0x12c(%rbp)
  movl   $0x0,-0x128(%rbp)
  cmpl   $0x0,-0x12c(%rbp)
  jns    L28
  negl   -0x12c(%rbp)
  movl   $0x1,-0x128(%rbp)
L28:
  lea    -0x110(%rbp),%rax
  mov    %rax,-0x120(%rbp)
  lea    -0x110(%rbp),%rax
  add    $0x12,%rax
  mov    %rax,-0x118(%rbp)
  cmpl   $0x0,-0x12c(%rbp)
  jne    L136
  mov    -0x120(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x120(%rbp)
  movb   $0x30,(%rax)
  jmp    L136
L106:
  mov    -0x12c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x124(%rbp)
  mov    -0x124(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x120(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x120(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x12c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x12c(%rbp)
L136:
  cmpl   $0x0,-0x12c(%rbp)
  jle    L14
  mov    -0x120(%rbp),%rax
  cmp    -0x118(%rbp),%rax
  jb     L106
L14:
  cmpl   $0x0,-0x128(%rbp)
  je     L37
  mov    -0x120(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x120(%rbp)
  movb   $0x2d,(%rax)
L37:
  movzbl -0x110(%rbp),%eax
  cmp    $0x2d,%al
  jne    L16
  mov    $0xffffffffffffffff,%rax
  movl   $0xffffffff,(%rax)
  jmp    L16
L34:
  subq   $0x1,-0x120(%rbp)
  mov    -0x120(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tk_putc@plt>
L16:
  lea    -0x110(%rbp),%rax
  cmp    %rax,-0x120(%rbp)
  ja     L34
L7:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: -2147483648

assistant: ```c
void tk_print_decimal(int val) {
  char tb[256];
  char *t, *te;
  int i, k, s;
  if (val == 0) {
    tk_putc('0');
    return;
  }
  if (val == (1 << 31)) {
    tk_puts("-2147483648");
    return;
  }
  k = val;
  s = 0;
  if (k < 0) {
    k = -k;
    s = 1;
  }
  t = tb;
  te = tb + 18;
  if (!k)
    *t++ = '0';
  while ((k > 0) && (t < te)) {
    i = k % 10;
    *t++ = '0' + i;
    k = k / 10;
  }
  if (s)
    *t++ = '-';
  if (tb[0] == '-')
    *(int *)-1 = -1;
  while (t > tb) {
    t--;
    tk_putc(*t);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tk_print_decimal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L115
  cmp    $0x80000000,%edi
  je     L49
  test   %edi,%edi
  js     L110
  jle    L3
  mov    $0x0,%r8d
L139:
  mov    %rsp,%rbx
  lea    0x12(%rsp),%rsi
L66:
  add    $0x1,%rbx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edi,%edx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,-0x1(%rbx)
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  jle    L158
  cmp    %rsi,%rbx
  jb     L66
L158:
  test   %r8d,%r8d
  je     L99
  movb   $0x2d,(%rbx)
  lea    0x1(%rbx),%rbx
L99:
  cmpb   $0x2d,(%rsp)
  je     L133
L51:
  mov    %rsp,%rax
  cmp    %rax,%rbx
  jbe    L41
  mov    %rsp,%rbp
L147:
  sub    $0x1,%rbx
  movsbl (%rbx),%edi
  call   <tk_putc@plt>
  cmp    %rbp,%rbx
  jne    L147
L41:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L115:
  mov    $0x30,%edi
  call   <tk_putc@plt>
  jmp    L41
L49:
  lea    D4(%rip),%rdi
  call   <tk_puts@plt>
  jmp    L41
L110:
  neg    %edi
  mov    $0x1,%r8d
  jmp    L139
L3:
  mov    $0x0,%r8d
  mov    %rsp,%rbx
  jmp    L158
L133:
  movl   $0xffffffff,0xffffffffffffffff
  jmp    L51
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: -2147483648

assistant: ```c
void tk_print_decimal(int val) {
  char tb[256];
  char *t, *te;
  int i, k, s;
  if (val == 0) {
    tk_putc('0');
    return;
  }
  if (val == (1 << 31)) {
    tk_puts("-2147483648");
    return;
  }
  k = val;
  s = 0;
  if (k < 0) {
    k = -k;
    s = 1;
  }
  t = tb;
  te = tb + 18;
  if (!k)
    *t++ = '0';
  while ((k > 0) && (t < te)) {
    i = k % 10;
    *t++ = '0' + i;
    k = k / 10;
  }
  if (s)
    *t++ = '-';
  if (tb[0] == '-')
    *(int *)-1 = -1;
  while (t > tb) {
    t--;
    tk_putc(*t);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tk_print_decimal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L124
  mov    %edi,%edx
  cmp    $0x80000000,%edi
  je     L133
  xor    %r10d,%r10d
  test   %edi,%edi
  js     L88
L79:
  mov    %rsp,%rbp
  mov    $0xcccccccd,%edi
  lea    0x12(%rsp),%r9
  mov    %rbp,%rbx
  nopl   0x0(%rax)
L73:
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %rbx,%r8
  add    $0x1,%rbx
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%rbx)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jle    L70
  cmp    %r9,%rbx
  jb     L73
L70:
  test   %r10d,%r10d
  je     L20
  movb   $0x2d,(%rbx)
  lea    0x2(%r8),%rbx
L20:
  cmpb   $0x2d,(%rsp)
  je     L110
L91:
  cmp    %rbp,%rbx
  jbe    L15
  nopl   (%rax)
L57:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <tk_putc@plt>
  cmp    %rbp,%rbx
  jne    L57
L15:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L88:
  neg    %edx
  mov    $0x1,%r10d
  jmp    L79
  nopl   (%rax)
L110:
  movl   $0xffffffff,0xffffffffffffffff
  jmp    L91
  nopl   (%rax)
L124:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x118,%rsp
  mov    $0x30,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <tk_putc@plt>
  xchg   %ax,%ax
L133:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x118,%rsp
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1090 <tk_puts@plt>
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: -2147483648

assistant: ```c
void tk_print_decimal(int val) {
  char tb[256];
  char *t, *te;
  int i, k, s;
  if (val == 0) {
    tk_putc('0');
    return;
  }
  if (val == (1 << 31)) {
    tk_puts("-2147483648");
    return;
  }
  k = val;
  s = 0;
  if (k < 0) {
    k = -k;
    s = 1;
  }
  t = tb;
  te = tb + 18;
  if (!k)
    *t++ = '0';
  while ((k > 0) && (t < te)) {
    i = k % 10;
    *t++ = '0' + i;
    k = k / 10;
  }
  if (s)
    *t++ = '-';
  if (tb[0] == '-')
    *(int *)-1 = -1;
  while (t > tb) {
    t--;
    tk_putc(*t);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tk_print_decimal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L68
  mov    %edi,%edx
  cmp    $0x80000000,%edi
  je     L14
  xor    %r10d,%r10d
  test   %edi,%edi
  js     L124
L9:
  mov    %rsp,%rbp
  mov    $0xcccccccd,%edi
  lea    0x12(%rsp),%r9
  mov    %rbp,%rbx
  nopl   0x0(%rax)
L21:
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %rbx,%r8
  add    $0x1,%rbx
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%rbx)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jle    L115
  cmp    %r9,%rbx
  jb     L21
L115:
  test   %r10d,%r10d
  je     L107
  movb   $0x2d,(%rbx)
  lea    0x2(%r8),%rbx
L107:
  cmpb   $0x2d,(%rsp)
  je     L110
L55:
  cmp    %rbp,%rbx
  jbe    L138
  nopl   (%rax)
L30:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <tk_putc@plt>
  cmp    %rbp,%rbx
  jne    L30
L138:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L124:
  neg    %edx
  mov    $0x1,%r10d
  jmp    L9
  nopl   (%rax)
L110:
  movl   $0xffffffff,0xffffffffffffffff
  jmp    L55
  nopl   (%rax)
L68:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x118,%rsp
  mov    $0x30,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <tk_putc@plt>
  xchg   %ax,%ax
L14:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x118,%rsp
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1090 <tk_puts@plt>
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: -2147483648

assistant: ```c
void tk_print_decimal(int val) {
  char tb[256];
  char *t, *te;
  int i, k, s;
  if (val == 0) {
    tk_putc('0');
    return;
  }
  if (val == (1 << 31)) {
    tk_puts("-2147483648");
    return;
  }
  k = val;
  s = 0;
  if (k < 0) {
    k = -k;
    s = 1;
  }
  t = tb;
  te = tb + 18;
  if (!k)
    *t++ = '0';
  while ((k > 0) && (t < te)) {
    i = k % 10;
    *t++ = '0' + i;
    k = k / 10;
  }
  if (s)
    *t++ = '-';
  if (tb[0] == '-')
    *(int *)-1 = -1;
  while (t > tb) {
    t--;
    tk_putc(*t);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scanp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L4
L0:
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L0
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *scanp(char *p) {
  while (isspace((unsigned char)*p))
    p++;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scanp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L4
L8:
  add    $0x1,%rbx
L4:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *scanp(char *p) {
  while (isspace((unsigned char)*p))
    p++;
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scanp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%r12
L8:
  movzbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L16
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *scanp(char *p) {
  while (isspace((unsigned char)*p))
    p++;
  return p;
}
```