user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D98(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x28(%rsp),%r8
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm1
  mov    $0x1,%eax
  movsd  D76(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  lea    D17(%rip),%rdi
  addsd  %xmm1,%xmm1
  addsd  %xmm0,%xmm1
  movsd  D168(%rip),%xmm0
  mulsd  0x20(%rsp),%xmm0
  addsd  %xmm0,%xmm1
  addsd  0x28(%rsp),%xmm1
  divsd  D47(%rip),%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  comisd D136(%rip),%xmm1
  jae    L7
  comisd D18(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
  jae    L33
  lea    D123(%rip),%rdi
  call   <puts@plt>
L0:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L33:
  lea    D85(%rip),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x30(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D95(%rip),%rdi
  call   <printf@plt>
  movsd  D49(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  0x30(%rsp),%xmm0
  comisd D18(%rip),%xmm0
  ja     L16
  lea    D123(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  call   <puts@plt>
  movsd  0x8(%rsp),%xmm1
L10:
  addsd  0x30(%rsp),%xmm1
  movsd  D49(%rip),%xmm0
  mov    $0x1,%eax
  lea    D139(%rip),%rdi
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  jmp    L0
L7:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  jmp    L0
L16:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  movsd  0x8(%rsp),%xmm1
  jmp    L10
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D98
type_infered: string
name: parse_data
arguments: tag: D76
type_infered: byte[8]
name: parse_data
arguments: tag: D17
type_infered: string
name: parse_data
arguments: tag: D168
type_infered: byte[8]
name: parse_data
arguments: tag: D47
type_infered: byte[8]
name: parse_data
arguments: tag: D136
type_infered: f64[2]
name: parse_data
arguments: tag: D18
type_infered: f64[2]
name: parse_data
arguments: tag: D123
type_infered: string
name: parse_data
arguments: tag: D85
type_infered: string
name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D95
type_infered: string
name: parse_data
arguments: tag: D49
type_infered: byte[8]
name: parse_data
arguments: tag: D139
type_infered: string
name: parse_data
arguments: tag: D46
type_infered: string

tool: D98: %lf %lf %lf %lf

tool: {"D76": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D17: Media: %.1f


tool: {"D168": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D136": [7.0,5.0]}

tool: {"D18": [5.0,0.5]}

tool: D123: Aluno reprovado.

tool: D85: Aluno em exame.

tool: D11: %lf

tool: D95: Nota do exame: %.1f


tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D139: Media final: %.1f


tool: D46: Aluno aprovado.

assistant: ```c
int main() {
  double a, b, c, d, last, m;
  scanf("%lf %lf %lf %lf", &a, &b, &c, &d);
  m = (a * 2 + b * 3 + c * 4 + d) / 10;
  printf("Media: %.1f\n", m);
  if (m >= 7.0) {
    printf("Aluno aprovado.\n");
  } else if (m >= 5.0) {
    printf("Aluno em exame.\n");
    scanf("%lf", &last);
    printf("Nota do exame: %.1f\n", last);
    if (last + m / 2.0 > 5.0) {
      printf("Aluno aprovado.\n");
    } else {
      printf("Aluno reprovado.\n");
    }
    printf("Media final: %.1f\n", (last + m) / 2.0);
  } else {
    printf("Aluno reprovado.\n");
  }
  return 0;
}
```