ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<console_gets>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L68:
  xor    %eax,%eax
  call   <console_getc@plt>
  cmp    $0xd,%al
  je     L79
L86:
  cmp    $0x8,%al
  jne    L12
  test   %r12d,%r12d
  je     L88
  movb   $0x20,(%rbx)
  mov    %rbp,%rdi
  lea    -0x1(%rbx),%r13
  sub    $0x1,%r12d
  mov    %r13,%rbx
  call   <console_puts@plt>
  xor    %eax,%eax
  call   <console_getc@plt>
  cmp    $0xd,%al
  jne    L86
L79:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L88:
  mov    %rbx,%r13
L5:
  xor    %eax,%eax
  call   <console_getc@plt>
  cmp    $0xd,%al
  je     L79
  cmp    $0x8,%al
  jne    L92
  xor    %eax,%eax
  call   <console_getc@plt>
  cmp    $0xd,%al
  je     L79
  cmp    $0x8,%al
  je     L5
  nopl   0x0(%rax)
L12:
  add    $0x1,%r12d
  mov    %rbx,%r13
L29:
  mov    %al,0x0(%r13)
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <SerialOutputByte@plt>
  jmp    L68
  nopl   0x0(%rax)
L92:
  mov    $0x1,%r12d
  jmp    L29
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3:  

assistant: ```c
int console_gets(char *s) {
  int cnt = 0;
  char c;
  while ((c = console_getc()) != 0x0d) {
    if (c != 0x08) {
      cnt++;
      *s++ = c;
      SerialOutputByte(c);
    } else {
      if (cnt > 0) {
        cnt--;
        *s-- = ' ';
        console_puts("\b \b");
      }
    }
  }
  *s = 0;
  return cnt;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L19
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jge    L49
L19:
  mov    -0x18(%rbp),%rax
  movb   $0x3f,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  jmp    L48
L49:
  mov    -0x28(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L42:
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L42
  cmpl   $0x0,-0x24(%rbp)
  jle    L39
  mov    -0x18(%rbp),%rax
  movb   $0x2a,(%rax)
L39:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
L48:
  pop    %rbp
  ret
```

assistant: ```c
char *dval(char *start, char *end, int val, int width) {
  char *p;
  if (val < 0 || end - start < width) {
    *start = '?';
    return start + 1;
  }
  p = start + width - 1;
  while (p >= start) {
    *p-- = val % 10 + '0';
    val /= 10;
  }
  if (val > 0)
    *start = '*';
  return start + width;
}
```
user: What is the c source code of the assembly code below:

```asm
<dval>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%edi
  test   %edx,%edx
  js     L40
  sub    %rax,%rsi
  movslq %ecx,%rdx
  cmp    %rdx,%rsi
  jl     L40
  movslq %ecx,%rcx
  lea    -0x1(%rax,%rcx,1),%rsi
  cmp    %rsi,%rax
  ja     L10
  lea    -0x1(%rax),%r9
L18:
  sub    $0x1,%rsi
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %edi,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  lea    (%rdx,%rdx,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edi
  add    $0x30,%edi
  mov    %dil,0x1(%rsi)
  mov    %edx,%edi
  cmp    %rsi,%r9
  jne    L18
L10:
  test   %edi,%edi
  jle    L49
  movb   $0x2a,(%rax)
L49:
  add    %rcx,%rax
  ret
L40:
  movb   $0x3f,(%rax)
  add    $0x1,%rax
  ret
```

assistant: ```c
char *dval(char *start, char *end, int val, int width) {
  char *p;
  if (val < 0 || end - start < width) {
    *start = '?';
    return start + 1;
  }
  p = start + width - 1;
  while (p >= start) {
    *p-- = val % 10 + '0';
    val /= 10;
  }
  if (val > 0)
    *start = '*';
  return start + width;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dval>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  js     L47
  sub    %rdi,%rsi
  movslq %ecx,%rcx
  cmp    %rcx,%rsi
  jl     L47
  lea    -0x1(%rdi,%rcx,1),%rdi
  cmp    %rdi,%rax
  ja     L3
  lea    -0x1(%rax),%r10
  mov    $0xcccccccd,%r9d
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %edx,%esi
  sub    $0x1,%rdi
  imul   %r9,%rsi
  shr    $0x23,%rsi
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rdi)
  mov    %esi,%edx
  cmp    %r10,%rdi
  jne    L33
L3:
  test   %edx,%edx
  je     L28
  movb   $0x2a,(%rax)
L28:
  add    %rcx,%rax
  ret
L47:
  movb   $0x3f,(%rax)
  add    $0x1,%rax
  ret
```

assistant: ```c
char *dval(char *start, char *end, int val, int width) {
  char *p;
  if (val < 0 || end - start < width) {
    *start = '?';
    return start + 1;
  }
  p = start + width - 1;
  while (p >= start) {
    *p-- = val % 10 + '0';
    val /= 10;
  }
  if (val > 0)
    *start = '*';
  return start + width;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dval>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  js     L33
  sub    %rdi,%rsi
  movslq %ecx,%rcx
  cmp    %rcx,%rsi
  jl     L33
  lea    -0x1(%rdi,%rcx,1),%rdi
  cmp    %rdi,%rax
  ja     L37
  lea    -0x1(%rax),%r10
  mov    $0xcccccccd,%r9d
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %edx,%esi
  sub    $0x1,%rdi
  imul   %r9,%rsi
  shr    $0x23,%rsi
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rdi)
  mov    %esi,%edx
  cmp    %r10,%rdi
  jne    L44
L37:
  test   %edx,%edx
  je     L28
  movb   $0x2a,(%rax)
L28:
  add    %rcx,%rax
  ret
L33:
  movb   $0x3f,(%rax)
  add    $0x1,%rax
  ret
```

assistant: ```c
char *dval(char *start, char *end, int val, int width) {
  char *p;
  if (val < 0 || end - start < width) {
    *start = '?';
    return start + 1;
  }
  p = start + width - 1;
  while (p >= start) {
    *p-- = val % 10 + '0';
    val /= 10;
  }
  if (val > 0)
    *start = '*';
  return start + width;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <futimens@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(void) {
  struct timespec foo[2] = {{.tv_sec = 0, .tv_nsec = 0}, {.tv_sec = 0, .tv_nsec = 0}};
  futimens(0, foo);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edi
  call   <futimens@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct timespec foo[2] = {{.tv_sec = 0, .tv_nsec = 0}, {.tv_sec = 0, .tv_nsec = 0}};
  futimens(0, foo);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <futimens@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct timespec foo[2] = {{.tv_sec = 0, .tv_nsec = 0}, {.tv_sec = 0, .tv_nsec = 0}};
  futimens(0, foo);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  call   <futimens@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct timespec foo[2] = {{.tv_sec = 0, .tv_nsec = 0}, {.tv_sec = 0, .tv_nsec = 0}};
  futimens(0, foo);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FilterName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  lea    D2(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: TestFilter

assistant: ```c
const char *FilterName(void *arg) {
  (void)arg;
  return "TestFilter";
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FilterName>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: TestFilter

assistant: ```c
const char *FilterName(void *arg) {
  (void)arg;
  return "TestFilter";
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FilterName>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: TestFilter

assistant: ```c
const char *FilterName(void *arg) {
  (void)arg;
  return "TestFilter";
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FilterName>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: TestFilter

assistant: ```c
const char *FilterName(void *arg) {
  (void)arg;
  return "TestFilter";
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D17
type: string

tool: D7: sbfi - simple brainfuck interpreter


tool: D17: (c) 2015 Bernd Busse v0.3


assistant: ```c
void version() {
  printf("sbfi - simple brainfuck interpreter\n");
  printf("(c) 2015 Bernd Busse v0.3\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D5
data_type: string

tool: D19: sbfi - simple brainfuck interpreter


tool: D5: (c) 2015 Bernd Busse v0.3


assistant: ```c
void version() {
  printf("sbfi - simple brainfuck interpreter\n");
  printf("(c) 2015 Bernd Busse v0.3\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D9: sbfi - simple brainfuck interpreter


tool: D4: (c) 2015 Bernd Busse v0.3


assistant: ```c
void version() {
  printf("sbfi - simple brainfuck interpreter\n");
  printf("(c) 2015 Bernd Busse v0.3\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D9
data_type: string

tool: D12: sbfi - simple brainfuck interpreter


tool: D9: (c) 2015 Bernd Busse v0.3


assistant: ```c
void version() {
  printf("sbfi - simple brainfuck interpreter\n");
  printf("(c) 2015 Bernd Busse v0.3\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<open_userfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <username_sane@plt>
  test   %eax,%eax
  jne    L21
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L8
L21:
  movabs $0x2f7372657375,%rax
  mov    $0x0,%edx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movw   $0x0,-0x18(%rbp)
  movb   $0x0,-0x16(%rbp)
  lea    -0x30(%rbp),%rax
  add    $0x6,%rax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x3c(%rbp),%ecx
  lea    -0x30(%rbp),%rax
  mov    $0x1c0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int open_userfile(char *user, int flags) {
  if (!username_sane(user)) {
    errno = EACCES;
    return -1;
  }
  char path[6 + 20 + 1] = "users/";
  strcpy(path + 6, user);
  return open(path, flags, 0700);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<open_userfile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <username_sane@plt>
  test   %eax,%eax
  je     L1
  movabs $0x2f7372657375,%rax
  mov    $0x0,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movw   $0x0,0x18(%rsp)
  movb   $0x0,0x1a(%rsp)
  mov    %rsp,%r12
  lea    0x6(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  mov    $0x1c0,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <open@plt>
L29:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L29
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_userfile(char *user, int flags) {
  if (!username_sane(user)) {
    errno = EACCES;
    return -1;
  }
  char path[6 + 20 + 1] = "users/";
  strcpy(path + 6, user);
  return open(path, flags, 0700);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<open_userfile>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <username_sane@plt>
  test   %eax,%eax
  je     L17
  xor    %edx,%edx
  lea    0x6(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %rsp,%r13
  movabs $0x2f7372657375,%rax
  mov    %rdx,0x8(%rsp)
  mov    %rax,(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  mov    %ax,0x18(%rsp)
  movb   $0x0,0x1a(%rsp)
  call   <strcpy@plt>
  mov    $0x1c0,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <open@plt>
L1:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L1
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_userfile(char *user, int flags) {
  if (!username_sane(user)) {
    errno = EACCES;
    return -1;
  }
  char path[6 + 20 + 1] = "users/";
  strcpy(path + 6, user);
  return open(path, flags, 0700);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<open_userfile>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <username_sane@plt>
  test   %eax,%eax
  je     L16
  xor    %edx,%edx
  lea    0x6(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %rsp,%r13
  movabs $0x2f7372657375,%rax
  mov    %rdx,0x8(%rsp)
  mov    %rax,(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  mov    %ax,0x18(%rsp)
  movb   $0x0,0x1a(%rsp)
  call   <strcpy@plt>
  mov    $0x1c0,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <open@plt>
L0:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L0
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_userfile(char *user, int flags) {
  if (!username_sane(user)) {
    errno = EACCES;
    return -1;
  }
  char path[6 + 20 + 1] = "users/";
  strcpy(path + 6, user);
  return open(path, flags, 0700);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pdist_yule_bool>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L19
L4:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L38
L20:
  mov    -0x38(%rbp),%eax
  imul   -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <yule_distance_bool@plt>
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  addq   $0x8,-0x18(%rbp)
L38:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L20
  addl   $0x1,-0x20(%rbp)
L19:
  mov    -0x20(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void pdist_yule_bool(const char *X, double *dm, int m, int n) {
  int i, j;
  const char *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = yule_distance_bool(u, v, n);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pdist_yule_bool>:
  endbr64
  test   %edx,%edx
  jle    L4
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %ecx,%r14d
  lea    -0x2(%rdx),%eax
  mov    %eax,0xc(%rsp)
  movslq %ecx,%rax
  mov    %rax,(%rsp)
  mov    %rdi,%r15
L20:
  mov    0xc(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L31
  mov    %r15,%r13
  add    (%rsp),%r15
  mov    %eax,%eax
  lea    0x8(%rbx,%rax,8),%r12
  mov    %r15,%rbp
L24:
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <yule_distance_bool@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  add    (%rsp),%rbp
  cmp    %r12,%rbx
  jne    L24
  subl   $0x1,0xc(%rsp)
  mov    %r12,%rbx
  jmp    L20
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  ret
```

assistant: ```c
void pdist_yule_bool(const char *X, double *dm, int m, int n) {
  int i, j;
  const char *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = yule_distance_bool(u, v, n);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pdist_yule_bool>:
  endbr64
  test   %edx,%edx
  jle    L3
  push   %r15
  lea    -0x2(%rdx),%eax
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rbx
  sub    $0x18,%rsp
  mov    %eax,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    %rdi,0x8(%rsp)
  cmp    $0xffffffff,%eax
  je     L23
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x8(%rsp),%r14
  lea    0x1(%rax),%edx
  lea    (%r15,%rdx,8),%rbp
  mov    %r14,%r12
  add    %rbx,%r14
  mov    %r14,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %r12,%rdi
  add    $0x8,%r15
  call   <yule_distance_bool@plt>
  add    %rbx,%r14
  movsd  %xmm0,-0x8(%r15)
  cmp    %rbp,%r15
  jne    L18
  subl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  cmp    $0xffffffff,%eax
  jne    L5
L23:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  ret
```

assistant: ```c
void pdist_yule_bool(const char *X, double *dm, int m, int n) {
  int i, j;
  const char *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = yule_distance_bool(u, v, n);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pdist_yule_bool>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  cmp    $0x1,%edx
  jle    L7
  mov    %edx,%eax
  mov    %rdi,0x10(%rsp)
  mov    %ecx,%r13d
  movslq %ecx,%rbp
  sub    $0x1,%eax
  movl   $0x1,0x18(%rsp)
  mov    %eax,0x1c(%rsp)
L22:
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%r14
  mov    0x18(%rsp),%r15d
  mov    %rax,%r12
  add    %rbp,%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,%rbx
  nopl   (%rax)
L19:
  mov    %rbx,%rsi
  mov    %r13d,%edx
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <yule_distance_bool@plt>
  add    $0x8,%r14
  add    %rbp,%rbx
  movsd  %xmm0,-0x8(%r14)
  cmp    %r15d,0x4(%rsp)
  jg     L19
  mov    0x18(%rsp),%ecx
  mov    0x1c(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %ecx,%eax
  add    $0x1,%ecx
  lea    0x8(%rdx,%rax,8),%rax
  mov    %ecx,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  cmp    %ecx,0x4(%rsp)
  jne    L22
L7:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pdist_yule_bool(const char *X, double *dm, int m, int n) {
  int i, j;
  const char *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = yule_distance_bool(u, v, n);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gcc_current_sp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %esp,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int gcc_current_sp(void) {
  register unsigned sp asm("sp");
  return sp;
}
```
user: What is the c source code of the assembly code below?

```asm
<gcc_current_sp>:
  endbr64
  mov    %esp,%eax
  ret
```

assistant: ```c
unsigned int gcc_current_sp(void) {
  register unsigned sp asm("sp");
  return sp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gcc_current_sp>:
  endbr64
  mov    %esp,%eax
  ret
```

assistant: ```c
unsigned int gcc_current_sp(void) {
  register unsigned sp asm("sp");
  return sp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcc_current_sp>:
  endbr64
  mov    %esp,%eax
  ret
```

assistant: ```c
unsigned int gcc_current_sp(void) {
  register unsigned sp asm("sp");
  return sp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
L8:
  jmp    L8
```

assistant: ```c
void _exit(int code) {
  while (1) {
    ;
  }
}
```