ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Mat_CalcSingleSudirript>:
  endbr64
  test   %edi,%edi
  jle    L73
  push   %r13
  lea    -0x10(%rsi),%r8
  movslq %edi,%r10
  mov    %rdx,%r11
  push   %r12
  mov    $0xffffffff,%edi
  xor    %r9d,%r9d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  lea    -0x4(%rbx),%rbp
  sub    $0x8,%rsp
  movdqa D17(%rip),%xmm3
  nopl   0x0(%rax)
L2:
  mov    (%r11,%rsi,4),%edx
  cmp    %edx,0x10(%r8)
  jl     L45
  test   %edx,%edx
  jle    L43
  sub    $0x1,%edx
  mov    %edi,%r12d
  test   %rsi,%rsi
  je     L88
  mov    %esi,%r13d
  cmp    $0x1a,%edi
  jbe    L15
  mov    %esi,%eax
  lea    -0x10(%r8),%rcx
  movdqa %xmm3,%xmm1
  shr    $0x2,%eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  sub    %rax,%rcx
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L78:
  movdqu (%rax),%xmm4
  sub    $0x10,%rax
  pshufd $0x1b,%xmm4,%xmm0
  movdqa %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pmuludq %xmm1,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm1,%xmm0
  pshufd $0x8,%xmm2,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  cmp    %rcx,%rax
  jne    L78
  movdqa %xmm1,%xmm0
  mov    %edi,%r12d
  psrldq $0x8,%xmm0
  movdqa %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pmuludq %xmm1,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm1,%xmm0
  pshufd $0x8,%xmm2,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  pmuludq %xmm1,%xmm0
  movd   %xmm0,%eax
  imul   %eax,%edx
  mov    %r13d,%eax
  and    $0xfffffffc,%eax
  sub    %eax,%r12d
  cmp    %r13d,%eax
  je     L88
L15:
  movslq %r12d,%rcx
  mov    %r12d,%r12d
  shl    $0x2,%rcx
  shl    $0x2,%r12
  lea    (%rbx,%rcx,1),%rax
  add    %rbp,%rcx
  sub    %r12,%rcx
L51:
  imul   (%rax),%edx
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L51
L88:
  add    $0x1,%rsi
  add    %edx,%r9d
  add    $0x1,%edi
  add    $0x4,%r8
  cmp    %r10,%rsi
  jne    L2
  add    $0x8,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  lea    D2(%rip),%rdi
  call   <Mat_Critical@plt>
  add    $0x8,%rsp
  mov    $0xffffffff,%r9d
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  add    $0x8,%rsp
  mov    $0xffffffff,%r9d
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L73:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: byte[16]
name: parse_data
arguments: data_tag: D2
datatype: string

tool: {"D17": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D2: Mat_CalcSingleSudirript: index out of bounds

assistant: ```c
int Mat_CalcSingleSudirript(int rank, int *dims, int *subs) {
  int index = 0, i, j, err = 0;
  for (i = 0; i < rank; i++) {
    int k = subs[i];
    if (k > dims[i]) {
      err = 1;
      Mat_Critical("Mat_CalcSingleSudirript: index out of bounds");
      break;
    } else if (k < 1) {
      err = 1;
      break;
    }
    k--;
    for (j = i; j--;)
      k *= dims[j];
    index += k;
  }
  if (err)
    index = -1;
  return index;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lengthOfLastWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  jmp    L64
L60:
  addq   $0x1,-0x28(%rbp)
L64:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L60
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L34
  cmpl   $0x0,-0x14(%rbp)
  jne    L42
L34:
  mov    $0x0,%eax
  jmp    L77
L42:
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L84
L47:
  subq   $0x1,-0x10(%rbp)
L84:
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  test   %rax,%rax
  jle    L88
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L47
L88:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L97
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  setne  %al
  movzbl %al,%eax
  jmp    L77
L97:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L50
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L77
L50:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L77:
  leave
  ret
```

assistant: ```c
int lengthOfLastWord(char *s) {
  while (*s == ' ')
    s++;
  int slen = strlen(s);
  if (!s || !slen)
    return 0;
  char *last = s + slen - 1;
  while (last - s > 0 && *last == ' ')
    last--;
  if (last == s)
    return *last == ' ' ? 0 : 1;
  last[1] = '\0';
  char *lastspace = strrchr(s, ' ');
  if (!lastspace)
    return strlen(s);
  return strlen(lastspace + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lengthOfLastWord>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x20,(%rdi)
  jne    L33
L36:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L36
L33:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L19
  cltq
  sub    $0x1,%rax
  lea    (%rbx,%rax,1),%rdx
  test   %rax,%rax
  jle    L30
L11:
  cmpb   $0x20,(%rdx)
  jne    L30
  sub    $0x1,%rdx
  mov    %rdx,%rax
  sub    %rbx,%rax
  test   %rax,%rax
  jg     L11
L30:
  cmp    %rdx,%rbx
  je     L49
  movb   $0x0,0x1(%rdx)
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L37
  lea    0x1(%rax),%rdi
  call   <strlen@plt>
L19:
  pop    %rbx
  ret
L49:
  cmpb   $0x20,(%rdx)
  setne  %al
  movzbl %al,%eax
  jmp    L19
L37:
  mov    %rbx,%rdi
  call   <strlen@plt>
  jmp    L19
```

assistant: ```c
int lengthOfLastWord(char *s) {
  while (*s == ' ')
    s++;
  int slen = strlen(s);
  if (!s || !slen)
    return 0;
  char *last = s + slen - 1;
  while (last - s > 0 && *last == ' ')
    last--;
  if (last == s)
    return *last == ' ' ? 0 : 1;
  last[1] = '\0';
  char *lastspace = strrchr(s, ' ');
  if (!lastspace)
    return strlen(s);
  return strlen(lastspace + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lengthOfLastWord>:
  endbr64
  push   %rbp
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbp
  jne    L25
  nopl   (%rax)
L38:
  add    $0x1,%rbp
  cmpb   $0x20,0x0(%rbp)
  je     L38
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L22
  cltq
  sub    $0x1,%rax
  lea    0x0(%rbp,%rax,1),%rdx
  test   %rax,%rax
  jg     L9
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L10:
  sub    $0x1,%rdx
  mov    %rdx,%rax
  sub    %rbp,%rax
  test   %rax,%rax
  jle    L12
L9:
  cmpb   $0x20,(%rdx)
  je     L10
L12:
  cmp    %rbp,%rdx
  je     L76
  movb   $0x0,0x1(%rdx)
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L21
  lea    0x1(%rax),%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
  nopl   0x0(%rax)
L76:
  xor    %eax,%eax
  cmpb   $0x20,(%rdx)
  setne  %al
L22:
  pop    %rbp
  ret
L21:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
int lengthOfLastWord(char *s) {
  while (*s == ' ')
    s++;
  int slen = strlen(s);
  if (!s || !slen)
    return 0;
  char *last = s + slen - 1;
  while (last - s > 0 && *last == ' ')
    last--;
  if (last == s)
    return *last == ' ' ? 0 : 1;
  last[1] = '\0';
  char *lastspace = strrchr(s, ' ');
  if (!lastspace)
    return strlen(s);
  return strlen(lastspace + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lengthOfLastWord>:
  endbr64
  push   %rbp
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbp
  jne    L56
  nopl   (%rax)
L88:
  add    $0x1,%rbp
  cmpb   $0x20,0x0(%rbp)
  je     L88
L56:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L51
  cltq
  sub    $0x1,%rax
  lea    0x0(%rbp,%rax,1),%rdx
  test   %rax,%rax
  jg     L3
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L75:
  sub    $0x1,%rdx
  mov    %rdx,%rax
  sub    %rbp,%rax
  test   %rax,%rax
  jle    L25
L3:
  cmpb   $0x20,(%rdx)
  je     L75
L25:
  cmp    %rbp,%rdx
  je     L29
  movb   $0x0,0x1(%rdx)
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L63
  lea    0x1(%rax),%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
  nopl   0x0(%rax)
L29:
  xor    %eax,%eax
  cmpb   $0x20,(%rdx)
  setne  %al
L51:
  pop    %rbp
  ret
L63:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
int lengthOfLastWord(char *s) {
  while (*s == ' ')
    s++;
  int slen = strlen(s);
  if (!s || !slen)
    return 0;
  char *last = s + slen - 1;
  while (last - s > 0 && *last == ' ')
    last--;
  if (last == s)
    return *last == ' ' ? 0 : 1;
  last[1] = '\0';
  char *lastspace = strrchr(s, ' ');
  if (!lastspace)
    return strlen(s);
  return strlen(lastspace + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<free_dependencies>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L2:
  mov    $0x0,%eax
  call   <pop_dependency@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void free_dependencies(int ndependencies) {
  int i;
  for (i = 0; i < ndependencies; i++)
    pop_dependency();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_dependencies>:
  endbr64
  test   %edi,%edi
  jle    L12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L15:
  mov    $0x0,%eax
  call   <pop_dependency@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  ret
```

assistant: ```c
void free_dependencies(int ndependencies) {
  int i;
  for (i = 0; i < ndependencies; i++)
    pop_dependency();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_dependencies>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <pop_dependency@plt>
  cmp    %ebx,%ebp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L5:
  ret
```

assistant: ```c
void free_dependencies(int ndependencies) {
  int i;
  for (i = 0; i < ndependencies; i++)
    pop_dependency();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<free_dependencies>:
  endbr64
  test   %edi,%edi
  jle    L16
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <pop_dependency@plt>
  cmp    %ebx,%ebp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L16:
  ret
```

assistant: ```c
void free_dependencies(int ndependencies) {
  int i;
  for (i = 0; i < ndependencies; i++)
    pop_dependency();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rolling_window>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  add    $0x1,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L0:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L0
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L17
L20:
  mov    -0xc(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jb     L20
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned int *rolling_window(unsigned int const *const ist, unsigned int const w_size, unsigned int const size) {
  unsigned int *const totals = malloc(sizeof(unsigned int) * (size + 1 - w_size));
  unsigned int rollingadd = 0;
  for (unsigned int i = 0; i < w_size; i++) {
    rollingadd += ist[i];
  }
  totals[0] = rollingadd;
  for (unsigned int i = w_size; i < size; i++) {
    rollingadd -= ist[i - w_size];
    rollingadd += ist[i];
    totals[i - w_size + 1] = rollingadd;
  }
  return totals;
}
```
user: What is the c source code of the assembly code below:

```asm
<rolling_window>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %edx,%r13d
  sub    %esi,%r13d
  lea    0x4(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  test   %ebp,%ebp
  je     L31
  mov    %rbx,%rdx
  lea    -0x1(%rbp),%eax
  lea    0x4(%rbx,%rax,4),%rcx
  mov    $0x0,%eax
L23:
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L23
L39:
  mov    %eax,(%rsi)
  cmp    %ebp,%r12d
  jbe    L32
  lea    -0x1(%r13),%r8d
  mov    %ebp,%ebp
  lea    (%rbx,%rbp,4),%rdi
  mov    $0x0,%edx
L3:
  mov    %edx,%ecx
  add    (%rdi,%rdx,4),%eax
  sub    (%rbx,%rcx,4),%eax
  lea    0x1(%rdx),%ecx
  mov    %eax,(%rsi,%rcx,4)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %r8,%rcx
  jne    L3
L32:
  mov    %rsi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  mov    %ebp,%eax
  jmp    L39
```

assistant: ```c
unsigned int *rolling_window(unsigned int const *const ist, unsigned int const w_size, unsigned int const size) {
  unsigned int *const totals = malloc(sizeof(unsigned int) * (size + 1 - w_size));
  unsigned int rollingadd = 0;
  for (unsigned int i = 0; i < w_size; i++) {
    rollingadd += ist[i];
  }
  totals[0] = rollingadd;
  for (unsigned int i = w_size; i < size; i++) {
    rollingadd -= ist[i - w_size];
    rollingadd += ist[i];
    totals[i - w_size + 1] = rollingadd;
  }
  return totals;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rolling_window>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    %esi,%r12d
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x4(,%r12,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %r13d,%r13d
  je     L14
  lea    -0x1(%r13),%eax
  mov    %rbx,%rcx
  lea    0x4(%rbx,%rax,4),%rsi
  xor    %eax,%eax
  nop
L24:
  add    (%rcx),%eax
  add    $0x4,%rcx
  cmp    %rcx,%rsi
  jne    L24
L4:
  mov    %eax,(%r8)
  cmp    %r13d,%ebp
  jbe    L33
  mov    %r13d,%edx
  lea    -0x1(%r12),%edi
  lea    (%rbx,%rdx,4),%rsi
  xor    %edx,%edx
  nopl   0x0(%rax)
L6:
  add    (%rsi,%rdx,4),%eax
  lea    0x1(%rdx),%ecx
  sub    (%rbx,%rdx,4),%eax
  mov    %eax,(%r8,%rcx,4)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rcx
  jne    L6
L33:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L14:
  xor    %eax,%eax
  jmp    L4
```

assistant: ```c
unsigned int *rolling_window(unsigned int const *const ist, unsigned int const w_size, unsigned int const size) {
  unsigned int *const totals = malloc(sizeof(unsigned int) * (size + 1 - w_size));
  unsigned int rollingadd = 0;
  for (unsigned int i = 0; i < w_size; i++) {
    rollingadd += ist[i];
  }
  totals[0] = rollingadd;
  for (unsigned int i = w_size; i < size; i++) {
    rollingadd -= ist[i - w_size];
    rollingadd += ist[i];
    totals[i - w_size + 1] = rollingadd;
  }
  return totals;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rolling_window>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    %ebp,%r13d
  mov    %rdi,%rbx
  lea    0x4(,%r13,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  je     L6
  lea    -0x1(%rbp),%eax
  cmp    $0x2,%eax
  jbe    L35
  mov    %ebp,%edx
  mov    %rbx,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rbx,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L84:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rdx,%rax
  jne    L84
  movdqa %xmm0,%xmm1
  mov    %ebp,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%bpl
  je     L9
L39:
  mov    %edx,%ecx
  add    (%rbx,%rcx,4),%eax
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%ebp
  jbe    L9
  add    $0x2,%edx
  add    (%rbx,%rcx,4),%eax
  cmp    %ebp,%edx
  jae    L9
  add    (%rbx,%rdx,4),%eax
L9:
  mov    %eax,(%r8)
  cmp    %ebp,%r12d
  jbe    L92
  lea    -0x1(%r13),%edi
  lea    (%rbx,%rbp,4),%rsi
  xor    %edx,%edx
  nopl   (%rax)
L50:
  add    (%rsi,%rdx,4),%eax
  lea    0x1(%rdx),%ecx
  sub    (%rbx,%rdx,4),%eax
  mov    %eax,(%r8,%rcx,4)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  jne    L50
L92:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L6:
  xor    %eax,%eax
  jmp    L9
L35:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L39
```

assistant: ```c
unsigned int *rolling_window(unsigned int const *const ist, unsigned int const w_size, unsigned int const size) {
  unsigned int *const totals = malloc(sizeof(unsigned int) * (size + 1 - w_size));
  unsigned int rollingadd = 0;
  for (unsigned int i = 0; i < w_size; i++) {
    rollingadd += ist[i];
  }
  totals[0] = rollingadd;
  for (unsigned int i = w_size; i < size; i++) {
    rollingadd -= ist[i - w_size];
    rollingadd += ist[i];
    totals[i - w_size + 1] = rollingadd;
  }
  return totals;
}
```
user: Translate the below assembly code into C programming language:

```asm
<heatindex_C>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x3e7,-0x4(%rbp)
  je     L5
  cmpl   $0x14,-0x4(%rbp)
  jle    L5
  cmpl   $0x0,-0x8(%rbp)
  jns    L20
L5:
  mov    $0x3e7,%eax
  jmp    L9
L20:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <temp_C2F@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <heatindex_F@plt>
L9:
  leave
  ret
```

assistant: ```c
int heatindex_C(int temp_C, int rh) {
  if (temp_C == 999 || temp_C < 21 || rh < 0)
    return 999;
  return heatindex_F(temp_C2F(temp_C), rh);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heatindex_C>:
  endbr64
  cmp    $0x3e7,%edi
  sete   %al
  cmp    $0x14,%edi
  setle  %dl
  or     %dl,%al
  jne    L6
  push   %rbx
  mov    %esi,%ebx
  mov    $0x3e7,%eax
  test   %esi,%esi
  js     L1
  call   <temp_C2F@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <heatindex_F@plt>
L1:
  pop    %rbx
  ret
L6:
  mov    $0x3e7,%eax
  ret
```

assistant: ```c
int heatindex_C(int temp_C, int rh) {
  if (temp_C == 999 || temp_C < 21 || rh < 0)
    return 999;
  return heatindex_F(temp_C2F(temp_C), rh);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<heatindex_C>:
  endbr64
  cmp    $0x3e7,%edi
  sete   %al
  cmp    $0x14,%edi
  setle  %dl
  or     %dl,%al
  jne    L0
  push   %rbp
  mov    %esi,%ebp
  test   %esi,%esi
  js     L13
  call   <temp_C2F@plt>
  mov    %ebp,%esi
  pop    %rbp
  mov    %eax,%edi
  jmp    1060 <heatindex_F@plt>
  nopl   (%rax)
L13:
  mov    $0x3e7,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x3e7,%eax
  ret
```

assistant: ```c
int heatindex_C(int temp_C, int rh) {
  if (temp_C == 999 || temp_C < 21 || rh < 0)
    return 999;
  return heatindex_F(temp_C2F(temp_C), rh);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heatindex_C>:
  endbr64
  cmp    $0x3e7,%edi
  sete   %al
  cmp    $0x14,%edi
  setle  %dl
  or     %dl,%al
  jne    L19
  push   %rbp
  mov    %esi,%ebp
  test   %esi,%esi
  js     L9
  call   <temp_C2F@plt>
  mov    %ebp,%esi
  pop    %rbp
  mov    %eax,%edi
  jmp    1060 <heatindex_F@plt>
  nopl   (%rax)
L9:
  mov    $0x3e7,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0x3e7,%eax
  ret
```

assistant: ```c
int heatindex_C(int temp_C, int rh) {
  if (temp_C == 999 || temp_C < 21 || rh < 0)
    return 999;
  return heatindex_F(temp_C2F(temp_C), rh);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x11(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(void) {
  char *ptr;
  {
    char my_char[9];
    ptr = &my_char[0];
  }
  return *(ptr + 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsbl 0x17(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char *ptr;
  {
    char my_char[9];
    ptr = &my_char[0];
  }
  return *(ptr + 8);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsbl 0x17(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char *ptr;
  {
    char my_char[9];
    ptr = &my_char[0];
  }
  return *(ptr + 8);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsbl 0x17(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char *ptr;
  {
    char my_char[9];
    ptr = &my_char[0];
  }
  return *(ptr + 8);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shell_q_bugreport>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <myMessageBox@plt>
  cmp    $0x5,%eax
  je     L2
  cmp    $0x6,%eax
  jne    L28
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L2:
  movl   $0x2,-0x4(%rbp)
  jmp    L4
L28:
  movl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int shell_q_bugreport(const char *text) {
  int reakce;
  switch (myMessageBox(text, 6)) {
  case 6:
    reakce = 0;
    break;
  case 5:
    reakce = 2;
    break;
  default:
    reakce = 1;
  }
  return reakce;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shell_q_bugreport>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%esi
  call   <myMessageBox@plt>
  mov    $0x2,%edx
  cmp    $0x5,%eax
  je     L8
  cmp    $0x6,%eax
  setne  %dl
  movzbl %dl,%edx
L8:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int shell_q_bugreport(const char *text) {
  int reakce;
  switch (myMessageBox(text, 6)) {
  case 6:
    reakce = 0;
    break;
  case 5:
    reakce = 2;
    break;
  default:
    reakce = 1;
  }
  return reakce;
}
```