user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  sub    $0xa4d,%ax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L97
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L34
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L53
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  mov    %ax,-0xa(%rbp)
  jmp    L53
L34:
  movzwl -0xa(%rbp),%eax
  shr    $0x2,%ax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L64
  lea    -0xa(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  lea    -0xa(%rbp),%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl -0xb(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L53
L64:
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  mov    %ax,-0xa(%rbp)
  jmp    L53
L97:
  movzwl -0xa(%rbp),%eax
  shr    $0x2,%ax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L62
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  mov    %ax,-0xa(%rbp)
  jmp    L53
L62:
  lea    -0xa(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  lea    -0xa(%rbp),%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xc(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  movzbl -0xc(%rbp),%edx
  mov    %dl,(%rax)
L53:
  movzwl -0xa(%rbp),%eax
  lea    -0x64fc(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy13;
  char copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    if (state[0UL] & (unsigned short)1) {
      if (state[0UL] & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        }
      } else if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
    } else if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
      state[0UL] += state[0UL];
    } else {
      copy16 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy16;
      copy17 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy17;
    }
    output[0UL] = (state[0UL] - 1059477100UL) + (unsigned short)61808;
  }
}
```