ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ptrCompare>:
  endbr64
  cmp    %rdx,%rdi
  je     L6
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ptrCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (pKey1 == pKey2)
    return 0;
  if (pKey1 < pKey2)
    return -1;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ptrCompare>:
  endbr64
  cmp    %rdx,%rdi
  je     L5
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
  nop
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ptrCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (pKey1 == pKey2)
    return 0;
  if (pKey1 < pKey2)
    return -1;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<ptrCompare>:
  endbr64
  cmp    %rdx,%rdi
  je     L9
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
  nop
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ptrCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (pKey1 == pKey2)
    return 0;
  if (pKey1 < pKey2)
    return -1;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xc30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x78,-0x2c30(%rbp)
  movl   $0x5a,-0x2c2c(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,-0x2c20(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,-0x2c18(%rbp)
  movl   $0xa,-0x2c28(%rbp)
  mov    -0x2c2c(%rbp),%edi
  mov    -0x2c30(%rbp),%esi
  mov    -0x2c20(%rbp),%rcx
  mov    -0x2c28(%rbp),%edx
  lea    -0x2c10(%rbp),%rax
  sub    $0x8,%rsp
  push   -0x2c18(%rbp)
  mov    %edi,%r9d
  mov    %esi,%r8d
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  call   <avcodec_register_all@plt>
  mov    $0x0,%eax
  call   <av_register_all@plt>
  mov    $0x0,%eax
  call   <avformat_network_init@plt>
  lea    -0x2810(%rbp),%rdx
  mov    -0x2c20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ffprobe@plt>
  mov    %eax,-0x2c24(%rbp)
  cmpl   $0x0,-0x2c24(%rbp)
  je     L5
  mov    -0x2c24(%rbp),%eax
  jmp    L18
L5:
  lea    -0x2810(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x2c10(%rbp),%rax
  mov    %rax,%rdi
  call   <ffmpeg@plt>
  mov    %eax,-0x2c24(%rbp)
  cmpl   $0x0,-0x2c24(%rbp)
  je     L39
  mov    -0x2c24(%rbp),%eax
  jmp    L18
L39:
  mov    $0x0,%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D28
type_guessed: string
name: parse_data
arguments: data_label: D23
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string
name: parse_data
arguments: data_label: D26
type_guessed: string

tool: D28: /root/1.3gp

tool: D23: /root/1.jpg

tool: D19: ffmpeg -ss %d -i %s -y -vframes 1 -s %d*%d %s

tool: D26: info is [%s]


assistant: ```c
int main() {
  int ret, argc;
  char info[10240];
  int width = 120;
  int height = 90;
  char *inputfile = "/root/1.3gp";
  char *outputfile = "/root/1.jpg";
  int starttime = 10;
  char cmd[1024];
  sprintf(cmd, "ffmpeg -ss %d -i %s -y -vframes 1 -s %d*%d %s", starttime, inputfile, width, height, outputfile);
  avcodec_register_all();
  av_register_all();
  avformat_network_init();
  ret = ffprobe(inputfile, info);
  if (ret)
    return ret;
  printf("info is [%s]\n", info);
  ret = ffmpeg(cmd);
  if (ret)
    return ret;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xc10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2c08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  sub    $0x8,%rsp
  lea    D28(%rip),%rax
  push   %rax
  mov    $0x5a,%r9d
  mov    $0x78,%r8d
  lea    D38(%rip),%rbx
  mov    %rbx,%rcx
  mov    $0xa,%edx
  lea    D31(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x0,%eax
  call   <avcodec_register_all@plt>
  mov    $0x0,%eax
  call   <av_register_all@plt>
  mov    $0x0,%eax
  call   <avformat_network_init@plt>
  lea    0x410(%rsp),%rsi
  mov    %rbx,%rdi
  call   <ffprobe@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  je     L11
L20:
  mov    0x2c08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x2c10,%rsp
  pop    %rbx
  ret
L11:
  lea    0x400(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <ffmpeg@plt>
  jmp    L20
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
data_type: string
name: disassemble_data
arguments: data_label: D38
data_type: string
name: disassemble_data
arguments: data_label: D31
data_type: string
name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D28: /root/1.jpg

tool: D38: /root/1.3gp

tool: D31: ffmpeg -ss %d -i %s -y -vframes 1 -s %d*%d %s

tool: D6: info is [%s]


assistant: ```c
int main() {
  int ret, argc;
  char info[10240];
  int width = 120;
  int height = 90;
  char *inputfile = "/root/1.3gp";
  char *outputfile = "/root/1.jpg";
  int starttime = 10;
  char cmd[1024];
  sprintf(cmd, "ffmpeg -ss %d -i %s -y -vframes 1 -s %d*%d %s", starttime, inputfile, width, height, outputfile);
  avcodec_register_all();
  av_register_all();
  avformat_network_init();
  ret = ffprobe(inputfile, info);
  if (ret)
    return ret;
  printf("info is [%s]\n", info);
  ret = ffmpeg(cmd);
  if (ret)
    return ret;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xc10,%rsp
  lea    D28(%rip),%rbp
  mov    $0x5a,%r9d
  mov    $0x78,%r8d
  mov    %rbp,%rcx
  mov    $0xa,%edx
  lea    D8(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x2c08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    D39(%rip),%rax
  sub    $0x8,%rsp
  push   %rax
  mov    %r12,%rdi
  call   <sprintf@plt>
  xor    %eax,%eax
  lea    0x410(%rsp),%r13
  call   <avcodec_register_all@plt>
  xor    %eax,%eax
  call   <av_register_all@plt>
  xor    %eax,%eax
  call   <avformat_network_init@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <ffprobe@plt>
  mov    %r12,%rsp
  test   %eax,%eax
  jne    L19
  lea    D31(%rip),%rdi
  mov    %r13,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <ffmpeg@plt>
L19:
  mov    0x2c08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x2c10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D28
type_infered: string
name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D39
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string

tool: D28: /root/1.3gp

tool: D8: ffmpeg -ss %d -i %s -y -vframes 1 -s %d*%d %s

tool: D39: /root/1.jpg

tool: D31: info is [%s]


assistant: ```c
int main() {
  int ret, argc;
  char info[10240];
  int width = 120;
  int height = 90;
  char *inputfile = "/root/1.3gp";
  char *outputfile = "/root/1.jpg";
  int starttime = 10;
  char cmd[1024];
  sprintf(cmd, "ffmpeg -ss %d -i %s -y -vframes 1 -s %d*%d %s", starttime, inputfile, width, height, outputfile);
  avcodec_register_all();
  av_register_all();
  avformat_network_init();
  ret = ffprobe(inputfile, info);
  if (ret)
    return ret;
  printf("info is [%s]\n", info);
  ret = ffmpeg(cmd);
  if (ret)
    return ret;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xc10,%rsp
  lea    D29(%rip),%rbp
  mov    $0x5a,%r9d
  mov    $0x78,%r8d
  mov    %rbp,%rcx
  mov    $0xa,%edx
  lea    D3(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x2c08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    D1(%rip),%rax
  sub    $0x8,%rsp
  push   %rax
  mov    %r12,%rdi
  call   <sprintf@plt>
  xor    %eax,%eax
  lea    0x410(%rsp),%r13
  call   <avcodec_register_all@plt>
  xor    %eax,%eax
  call   <av_register_all@plt>
  xor    %eax,%eax
  call   <avformat_network_init@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <ffprobe@plt>
  mov    %r12,%rsp
  test   %eax,%eax
  jne    L18
  lea    D31(%rip),%rdi
  mov    %r13,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <ffmpeg@plt>
L18:
  mov    0x2c08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x2c10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D29
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D31
type_infered: string

tool: D29: /root/1.3gp

tool: D3: ffmpeg -ss %d -i %s -y -vframes 1 -s %d*%d %s

tool: D1: /root/1.jpg

tool: D31: info is [%s]


assistant: ```c
int main() {
  int ret, argc;
  char info[10240];
  int width = 120;
  int height = 90;
  char *inputfile = "/root/1.3gp";
  char *outputfile = "/root/1.jpg";
  int starttime = 10;
  char cmd[1024];
  sprintf(cmd, "ffmpeg -ss %d -i %s -y -vframes 1 -s %d*%d %s", starttime, inputfile, width, height, outputfile);
  avcodec_register_all();
  av_register_all();
  avformat_network_init();
  ret = ffprobe(inputfile, info);
  if (ret)
    return ret;
  printf("info is [%s]\n", info);
  ret = ffmpeg(cmd);
  if (ret)
    return ret;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<kernel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L35
L10:
  mov    -0x20(%rbp),%eax
  add    $0x1f,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L38
L41:
  mov    -0x24(%rbp),%eax
  add    $0x1f,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L47
L51:
  mov    -0x28(%rbp),%eax
  add    $0x1f,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%eax
  shl    $0xa,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x24(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0xa,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  addss  %xmm0,%xmm1
  mov    -0x24(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  shl    $0xa,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%eax
  shl    $0xa,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x28(%rbp)
L47:
  cmpl   $0x1f,-0x28(%rbp)
  jle    L51
  addl   $0x1,-0x24(%rbp)
L38:
  cmpl   $0x1f,-0x24(%rbp)
  jle    L41
  addl   $0x1,-0x20(%rbp)
L35:
  cmpl   $0x1f,-0x20(%rbp)
  jle    L10
  nop
  pop    %rbp
  ret
```

assistant: ```c
void kernel(float *g1, float *g2) {
  int x, y, z;
  for (z = 0; z < 32; ++z) {
    int zp = ((z - 1) + 32) % 32;
    int zn = (z + 1) % 32;
    for (y = 0; y < 32; ++y) {
      int yp = ((y - 1) + 32) % 32;
      int yn = (y + 1) % 32;
      for (x = 0; x < 32; ++x) {
        int xp = ((x - 1) + 32) % 32;
        int xn = (x + 1) % 32;
        float v = g1[((x) + (y)*32 + (z)*32 * 32)] + g1[((x) + (y)*32 + (zn)*32 * 32)] + g1[((x) + (y)*32 + (zp)*32 * 32)];
        g2[((x) + (y)*32 + (z)*32 * 32)] = v;
      }
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kernel>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rcx
  mov    $0x0,%ebx
  mov    $0x0,%r11d
  mov    $0x0,%r10d
  mov    $0x80,%ebp
L13:
  lea    0x1f(%r10),%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,%edi
  add    $0x1,%r10d
  mov    %rbp,%rdx
  sub    %r11,%rdx
  mov    %r10d,%r8d
  sar    $0x1f,%r8d
  shr    $0x1b,%r8d
  lea    (%r10,%r8,1),%eax
  and    $0x1f,%eax
  sub    %r8d,%eax
  shl    $0xa,%eax
  cltq
  lea    (%r11,%rax,4),%r8
  add    %rcx,%r8
  mov    %edi,%eax
  shl    $0xa,%eax
  cltq
  lea    (%r11,%rax,4),%rdi
  add    %rcx,%rdi
  lea    0x1080(,%rbx,4),%r9
L29:
  lea    -0x80(%rdx),%rax
L19:
  movss  (%rcx,%rax,1),%xmm0
  addss  (%r8,%rax,1),%xmm0
  addss  (%rdi,%rax,1),%xmm0
  movss  %xmm0,(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L19
  sub    $0xffffffffffffff80,%rdx
  cmp    %r9,%rdx
  jne    L29
  sub    $0x1000,%r11
  add    $0x400,%rbx
  cmp    $0x20,%r10d
  jne    L13
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kernel(float *g1, float *g2) {
  int x, y, z;
  for (z = 0; z < 32; ++z) {
    int zp = ((z - 1) + 32) % 32;
    int zn = (z + 1) % 32;
    for (y = 0; y < 32; ++y) {
      int yp = ((y - 1) + 32) % 32;
      int yn = (y + 1) % 32;
      for (x = 0; x < 32; ++x) {
        int xp = ((x - 1) + 32) % 32;
        int xn = (x + 1) % 32;
        float v = g1[((x) + (y)*32 + (z)*32 * 32)] + g1[((x) + (y)*32 + (zn)*32 * 32)] + g1[((x) + (y)*32 + (zp)*32 * 32)];
        g2[((x) + (y)*32 + (z)*32 * 32)] = v;
      }
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<kernel>:
  endbr64
  push   %rbp
  mov    %rsi,%r8
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  push   %rbx
  xor    %r9d,%r9d
  mov    $0x80,%ebx
L20:
  lea    0x1f(%r9),%ecx
  add    $0x1,%r9d
  mov    %rbx,%rdx
  mov    %r9,%rsi
  shl    $0xc,%rcx
  sub    %r10,%rdx
  lea    0x1080(,%r11,4),%rbp
  shl    $0xc,%rsi
  and    $0x1f000,%ecx
  and    $0x1f000,%esi
  add    %r10,%rcx
  add    %r10,%rsi
  add    %rdi,%rcx
  add    %rdi,%rsi
L18:
  lea    -0x80(%rdx),%rax
  nopl   0x0(%rax)
L15:
  movss  (%rdi,%rax,1),%xmm0
  addss  (%rsi,%rax,1),%xmm0
  addss  (%rcx,%rax,1),%xmm0
  movss  %xmm0,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L15
  sub    $0xffffffffffffff80,%rdx
  cmp    %rdx,%rbp
  jne    L18
  sub    $0x1000,%r10
  add    $0x400,%r11
  cmp    $0x20,%r9d
  jne    L20
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void kernel(float *g1, float *g2) {
  int x, y, z;
  for (z = 0; z < 32; ++z) {
    int zp = ((z - 1) + 32) % 32;
    int zn = (z + 1) % 32;
    for (y = 0; y < 32; ++y) {
      int yp = ((y - 1) + 32) % 32;
      int yn = (y + 1) % 32;
      for (x = 0; x < 32; ++x) {
        int xp = ((x - 1) + 32) % 32;
        int xn = (x + 1) % 32;
        float v = g1[((x) + (y)*32 + (z)*32 * 32)] + g1[((x) + (y)*32 + (zn)*32 * 32)] + g1[((x) + (y)*32 + (zp)*32 * 32)];
        g2[((x) + (y)*32 + (z)*32 * 32)] = v;
      }
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quick_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x4000,-0x4(%rbp)
  je     L26
  cmpl   $0x4000,-0x4(%rbp)
  ja     L48
  cmpl   $0x2000,-0x4(%rbp)
  je     L57
  cmpl   $0x2000,-0x4(%rbp)
  ja     L48
  cmpl   $0x1000,-0x4(%rbp)
  je     L171
  cmpl   $0x1000,-0x4(%rbp)
  ja     L48
  cmpl   $0x800,-0x4(%rbp)
  je     L135
  cmpl   $0x800,-0x4(%rbp)
  ja     L48
  cmpl   $0x400,-0x4(%rbp)
  je     L139
  cmpl   $0x400,-0x4(%rbp)
  ja     L48
  cmpl   $0x200,-0x4(%rbp)
  je     L281
  cmpl   $0x200,-0x4(%rbp)
  ja     L48
  cmpl   $0x100,-0x4(%rbp)
  je     L71
  cmpl   $0x100,-0x4(%rbp)
  ja     L48
  cmpl   $0x80,-0x4(%rbp)
  je     L200
  cmpl   $0x80,-0x4(%rbp)
  ja     L48
  cmpl   $0x20,-0x4(%rbp)
  ja     L117
  cmpl   $0x0,-0x4(%rbp)
  je     L48
  cmpl   $0x20,-0x4(%rbp)
  ja     L48
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D11(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L117:
  cmpl   $0x40,-0x4(%rbp)
  je     L337
  jmp    L48
  mov    $0x0,%eax
  jmp    L326
  mov    $0x1,%eax
  jmp    L326
  mov    $0x2,%eax
  jmp    L326
  mov    $0x3,%eax
  jmp    L326
  mov    $0x4,%eax
  jmp    L326
  mov    $0x5,%eax
  jmp    L326
L337:
  mov    $0x6,%eax
  jmp    L326
L200:
  mov    $0x7,%eax
  jmp    L326
L71:
  mov    $0x8,%eax
  jmp    L326
L281:
  mov    $0x9,%eax
  jmp    L326
L139:
  mov    $0xa,%eax
  jmp    L326
L135:
  mov    $0xb,%eax
  jmp    L326
L171:
  mov    $0xc,%eax
  jmp    L326
L57:
  mov    $0xd,%eax
  jmp    L326
L26:
  mov    $0xe,%eax
  jmp    L326
L48:
  mov    $0xffffffff,%eax
L326:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int quick_log2(unsigned int x) {
  switch (x) {
  case 1:
    return 0;
  case 2:
    return 1;
  case 4:
    return 2;
  case 8:
    return 3;
  case 16:
    return 4;
  case 32:
    return 5;
  case 64:
    return 6;
  case 128:
    return 7;
  case 256:
    return 8;
  case 512:
    return 9;
  case 1024:
    return 10;
  case 2048:
    return 11;
  case 4096:
    return 12;
  case 8192:
    return 13;
  case 16384:
    return 14;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quick_log2>:
  endbr64
  cmp    $0x80,%edi
  je     L6
  ja     L19
  cmp    $0x20,%edi
  ja     L7
  test   %edi,%edi
  je     L89
  cmp    $0x20,%edi
  ja     L44
  mov    %edi,%edi
  lea    D5(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
L44:
  mov    $0xffffffff,%eax
  ret
L7:
  cmp    $0x40,%edi
  mov    $0xffffffff,%eax
  mov    $0x6,%edx
  cmove  %edx,%eax
  ret
L19:
  cmp    $0x800,%edi
  je     L4
  jbe    L105
  mov    $0xd,%eax
  cmp    $0x2000,%edi
  je     L13
  cmp    $0x4000,%edi
  jne    L8
  mov    $0xe,%eax
L13:
  ret
L105:
  mov    $0x9,%eax
  cmp    $0x200,%edi
  je     L13
  cmp    $0x400,%edi
  jne    L57
  mov    $0xa,%eax
  ret
L57:
  cmp    $0x100,%edi
  sete   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,8),%eax
  ret
L8:
  cmp    $0x1000,%edi
  mov    $0xffffffff,%eax
  mov    $0xc,%edx
  cmove  %edx,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
L6:
  mov    $0x7,%eax
  ret
L89:
  mov    $0xffffffff,%eax
  ret
  mov    $0x0,%eax
  ret
L4:
  mov    $0xb,%eax
  ret
```

assistant: ```c
unsigned int quick_log2(unsigned int x) {
  switch (x) {
  case 1:
    return 0;
  case 2:
    return 1;
  case 4:
    return 2;
  case 8:
    return 3;
  case 16:
    return 4;
  case 32:
    return 5;
  case 64:
    return 6;
  case 128:
    return 7;
  case 256:
    return 8;
  case 512:
    return 9;
  case 1024:
    return 10;
  case 2048:
    return 11;
  case 4096:
    return 12;
  case 8192:
    return 13;
  case 16384:
    return 14;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zeroit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L5:
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L8:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x31f,-0x4(%rbp)
  jle    L8
  addl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x7cf,-0x8(%rbp)
  jle    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zeroit(int **bdarr, int nrows, int ncols) {
  int i, j;
  for (i = 0; i < 2000; i++)
    for (j = 0; j < 800; j++)
      bdarr[i][j] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<zeroit>:
  endbr64
  mov    %rdi,%rcx
  lea    0x3e80(%rdi),%rsi
L8:
  mov    $0x0,%eax
L14:
  mov    (%rcx),%rdx
  movl   $0x0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0xc80,%rax
  jne    L14
  add    $0x8,%rcx
  cmp    %rsi,%rcx
  jne    L8
  ret
```

assistant: ```c
void zeroit(int **bdarr, int nrows, int ncols) {
  int i, j;
  for (i = 0; i < 2000; i++)
    for (j = 0; j < 800; j++)
      bdarr[i][j] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zeroit>:
  endbr64
  mov    %rdi,%rsi
  lea    0x3e80(%rdi),%r8
  xor    %eax,%eax
L9:
  mov    (%rsi),%rdx
  add    $0x8,%rsi
  lea    0x8(%rdx),%rdi
  movq   $0x0,(%rdx)
  movq   $0x0,0xc78(%rdx)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rdx
  lea    0xc80(%rdx),%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  cmp    %rsi,%r8
  jne    L9
  ret
```

assistant: ```c
void zeroit(int **bdarr, int nrows, int ncols) {
  int i, j;
  for (i = 0; i < 2000; i++)
    for (j = 0; j < 800; j++)
      bdarr[i][j] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zeroit>:
  endbr64
  mov    %rdi,%rsi
  lea    0x3e80(%rdi),%r8
  xor    %eax,%eax
L6:
  mov    (%rsi),%rdx
  add    $0x8,%rsi
  lea    0x8(%rdx),%rdi
  movq   $0x0,(%rdx)
  movq   $0x0,0xc78(%rdx)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rdx
  lea    0xc80(%rdx),%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  cmp    %rsi,%r8
  jne    L6
  ret
```

assistant: ```c
void zeroit(int **bdarr, int nrows, int ncols) {
  int i, j;
  for (i = 0; i < 2000; i++)
    for (j = 0; j < 800; j++)
      bdarr[i][j] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_palindrome_rec_ex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L8
  mov    $0x0,%eax
  jmp    L2
L8:
  cmpl   $0x2,-0xc(%rbp)
  jg     L27
  mov    $0x1,%eax
  jmp    L2
L27:
  mov    -0xc(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <is_palindrome_rec_ex>
L2:
  leave
  ret
```

assistant: ```c
int is_palindrome_rec_ex(char *str, int str_len) {
  if (str[0] != str[str_len - 1])
    return 0;
  if (str_len <= 2)
    return 1;
  return is_palindrome_rec_ex(str + 1, str_len - 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_palindrome_rec_ex>:
  endbr64
  movslq %esi,%rdx
  mov    $0x0,%eax
  movzbl -0x1(%rdi,%rdx,1),%ecx
  cmp    %cl,(%rdi)
  jne    L14
  mov    $0x1,%eax
  cmp    $0x2,%esi
  jg     L17
L14:
  ret
L17:
  sub    $0x8,%rsp
  sub    $0x2,%esi
  add    $0x1,%rdi
  call   <is_palindrome_rec_ex>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_palindrome_rec_ex(char *str, int str_len) {
  if (str[0] != str[str_len - 1])
    return 0;
  if (str_len <= 2)
    return 1;
  return is_palindrome_rec_ex(str + 1, str_len - 2);
}
```