user: 这段汇编代码用C语言表示是什么样的：

```asm
<RSA_sign_ASN1_OCTET_STRING>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x48(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    %r9,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x3c(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <i2d_ASN1_OCTET_STRING@plt>
  mov    %eax,-0x38(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <RSA_size@plt>
  mov    %eax,-0x34(%rbp)
  mov    D52(%rip),%rax
  mov    (%rax),%edx
  mov    -0x34(%rbp),%eax
  sub    %edx,%eax
  cmp    %eax,-0x38(%rbp)
  jle    L30
  mov    D62(%rip),%rax
  mov    (%rax),%edx
  mov    D69(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L7
L30:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L25
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D69(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L7
L25:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <i2d_ASN1_OCTET_STRING@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  mov    -0x68(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x38(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <RSA_private_encrypt@plt>
  mov    %eax,-0x38(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  jg     L2
  movl   $0x0,-0x3c(%rbp)
  jmp    L68
L2:
  mov    -0x38(%rbp),%edx
  mov    -0x60(%rbp),%rax
  mov    %edx,(%rax)
L68:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <explicit_bzero@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x3c(%rbp),%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

assistant: ```c
int RSA_sign_ASN1_OCTET_STRING(int type, const unsigned char *m, unsigned int m_len, unsigned char *sigret, unsigned int *siglen, RSA *rsa) {
  ASN1_OCTET_STRING sig;
  int i, j, ret = 1;
  unsigned char *p, *s;
  sig.type = V_ASN1_OCTET_STRING;
  sig.length = m_len;
  sig.data = (unsigned char *)m;
  i = i2d_ASN1_OCTET_STRING(&sig, NULL);
  j = RSA_size(rsa);
  if (i > (j - RSA_PKCS1_PADDING_SIZE)) {
    RSAerr(RSA_F_RSA_SIGN_ASN1_OCTET_STRING, RSA_R_DIGEST_TOO_BIG_FOR_RSA_KEY);
    return 0;
  }
  s = malloc(j + 1);
  if (s == NULL) {
    RSAerr(RSA_F_RSA_SIGN_ASN1_OCTET_STRING, ERR_R_MALLOC_FAILURE);
    return 0;
  }
  p = s;
  i2d_ASN1_OCTET_STRING(&sig, &p);
  i = RSA_private_encrypt(i, s, sigret, rsa, RSA_PKCS1_PADDING);
  if (i <= 0)
    ret = 0;
  else
    *siglen = i;
  explicit_bzero(s, (unsigned int)j + 1);
  free(s);
  return ret;
}
```