ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Fibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L25
L0:
  cmpq   $0x2,-0x18(%rbp)
  ja     L2
  mov    $0x1,%eax
  jmp    L25
L2:
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <Fibonacci>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  sub    $0x2,%rax
  mov    %rax,%rdi
  call   <Fibonacci>
  add    %rbx,%rax
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long long Fibonacci(size_t N) {
  if (N == 0) {
    return 0;
  }
  if (N <= 2) {
    return 1;
  }
  return Fibonacci(N - 1) + Fibonacci(N - 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Fibonacci>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L21
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x1,%eax
  cmp    $0x2,%rdi
  ja     L4
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  lea    -0x1(%rdi),%rdi
  call   <Fibonacci>
  mov    %rax,%rbp
  lea    -0x2(%rbx),%rdi
  call   <Fibonacci>
  add    %rbp,%rax
  jmp    L22
L21:
  ret
```

assistant: ```c
long long Fibonacci(size_t N) {
  if (N == 0) {
    return 0;
  }
  if (N <= 2) {
    return 1;
  }
  return Fibonacci(N - 1) + Fibonacci(N - 2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xxfilv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  subq   $0x4,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void xxfilv(float *x, int n1, int n2, float val) {
  int i;
  x--;
  for (i = n1; i <= n2; i++)
    x[i] = val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xxfilv>:
  endbr64
  cmp    %edx,%esi
  jg     L2
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%rax
  sub    %esi,%edx
  add    %rcx,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
L11:
  movss  %xmm0,-0x4(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L11
L2:
  ret
```

assistant: ```c
void xxfilv(float *x, int n1, int n2, float val) {
  int i;
  x--;
  for (i = n1; i <= n2; i++)
    x[i] = val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xxfilv>:
  endbr64
  cmp    %edx,%esi
  jg     L4
  movslq %esi,%rcx
  sub    %esi,%edx
  add    %rcx,%rdx
  lea    (%rdi,%rcx,4),%rax
  lea    0x4(%rdi,%rdx,4),%rdx
  nopl   0x0(%rax)
L1:
  movss  %xmm0,-0x4(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L1
L4:
  ret
```

assistant: ```c
void xxfilv(float *x, int n1, int n2, float val) {
  int i;
  x--;
  for (i = n1; i <= n2; i++)
    x[i] = val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xxfilv>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%ecx
  mov    %edx,%edi
  cmp    %edx,%esi
  jg     L2
  mov    %edx,%eax
  sub    %esi,%eax
  lea    0x1(%rax),%r9d
  cmp    $0x2,%eax
  jbe    L42
  movslq %esi,%rax
  movaps %xmm0,%xmm1
  lea    -0x4(%r8,%rax,4),%rdx
  mov    %r9d,%eax
  shufps $0x0,%xmm1,%xmm1
  shr    $0x2,%eax
  lea    -0x1(%rax),%esi
  lea    0x10(%rdx),%rax
  shl    $0x4,%rsi
  add    %rax,%rsi
  jmp    L3
  nopl   (%rax)
L15:
  add    $0x10,%rax
L3:
  movups %xmm1,(%rdx)
  mov    %rax,%rdx
  cmp    %rsi,%rax
  jne    L15
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%ecx
  cmp    %eax,%r9d
  je     L2
L42:
  movslq %ecx,%rax
  lea    0x1(%rcx),%esi
  lea    0x0(,%rax,4),%rdx
  movss  %xmm0,-0x4(%r8,%rdx,1)
  cmp    %esi,%edi
  jl     L2
  add    $0x2,%ecx
  movss  %xmm0,(%r8,%rax,4)
  cmp    %ecx,%edi
  jl     L2
  movss  %xmm0,0x4(%r8,%rdx,1)
L2:
  ret
```

assistant: ```c
void xxfilv(float *x, int n1, int n2, float val) {
  int i;
  x--;
  for (i = n1; i <= n2; i++)
    x[i] = val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<minmax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L23
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L33
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L33:
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void minmax(int *arr, int size, int *min, int *max) {
  int i;
  for (i = 0; i < size; i++) {
    if (arr[i] < *min)
      *min = arr[i];
    if (arr[i] > *max)
      *max = arr[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<minmax>:
  endbr64
  test   %esi,%esi
  jle    L58
  mov    %rdi,%rax
  lea    -0x1(%rsi),%esi
  lea    0x4(%rdi,%rsi,4),%r8
  jmp    L37
L52:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L58
L37:
  mov    %rax,%rdi
  mov    (%rax),%esi
  cmp    (%rdx),%esi
  jge    L27
  mov    %esi,(%rdx)
L27:
  mov    (%rdi),%esi
  cmp    (%rcx),%esi
  jle    L52
  mov    %esi,(%rcx)
  jmp    L52
L58:
  ret
```

assistant: ```c
void minmax(int *arr, int size, int *min, int *max) {
  int i;
  for (i = 0; i < size; i++) {
    if (arr[i] < *min)
      *min = arr[i];
    if (arr[i] > *max)
      *max = arr[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<minmax>:
  endbr64
  test   %esi,%esi
  jle    L39
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L37:
  mov    (%rdi),%eax
  cmp    (%rdx),%eax
  jge    L16
  mov    %eax,(%rdx)
L16:
  cmp    (%rcx),%eax
  jle    L13
  mov    %eax,(%rcx)
L13:
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L37
L39:
  ret
```

assistant: ```c
void minmax(int *arr, int size, int *min, int *max) {
  int i;
  for (i = 0; i < size; i++) {
    if (arr[i] < *min)
      *min = arr[i];
    if (arr[i] > *max)
      *max = arr[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<minmax>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L6:
  mov    (%rdi),%eax
  cmp    (%rdx),%eax
  jge    L34
  mov    %eax,(%rdx)
L34:
  cmp    (%rcx),%eax
  jle    L23
  mov    %eax,(%rcx)
L23:
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L6
L18:
  ret
```

assistant: ```c
void minmax(int *arr, int size, int *min, int *max) {
  int i;
  for (i = 0; i < size; i++) {
    if (arr[i] < *min)
      *min = arr[i];
    if (arr[i] > *max)
      *max = arr[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x338(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x33c(%rbp)
  jmp    L7
L22:
  mov    -0x338(%rbp),%rdx
  mov    -0x33c(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x338(%rbp),%xmm0
  movsd  D16(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x338(%rbp)
  addl   $0x1,-0x33c(%rbp)
L7:
  cmpl   $0x63,-0x33c(%rbp)
  jle    L22
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string
name: read_data
arguments: data_tag: D15
type: string
name: read_data
arguments: data_tag: D16
type: byte[8]

tool: D4: %lf

tool: D15: N[%d] = %.4lf


tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
int main() {
  double a, b, ar[100];
  int i;
  scanf("%lf", &a);
  for (i = 0; i < 100; i++) {
    printf("N[%d] = %.4lf\n", i, a);
    a = a / 2;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
L7:
  movsd  (%rsp),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D2(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L7
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: byte[8]

tool: D14: %lf

tool: D4: N[%d] = %.4lf


tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  double a, b, ar[100];
  int i;
  scanf("%lf", &a);
  for (i = 0; i < 100; i++) {
    printf("N[%d] = %.4lf\n", i, a);
    a = a / 2;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  movsd  D24(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x64,%ebx
  jne    L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
data_type: string
name: read_data
arguments: tag: D9
data_type: string
name: read_data
arguments: tag: D24
data_type: byte[8]

tool: D28: %lf

tool: D9: N[%d] = %.4lf


tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  double a, b, ar[100];
  int i;
  scanf("%lf", &a);
  for (i = 0; i < 100; i++) {
    printf("N[%d] = %.4lf\n", i, a);
    a = a / 2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  movsd  D27(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x64,%ebx
  jne    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D8
type_guessed: string
name: read_data
arguments: data_tag: D27
type_guessed: byte[8]

tool: D6: %lf

tool: D8: N[%d] = %.4lf


tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  double a, b, ar[100];
  int i;
  scanf("%lf", &a);
  for (i = 0; i < 100; i++) {
    printf("N[%d] = %.4lf\n", i, a);
    a = a / 2;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ds_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L11
L24:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L25
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L25:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  shr    %eax
  mov    %eax,-0x18(%rbp)
L11:
  cmpl   $0x0,-0x18(%rbp)
  jne    L24
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _ds_pow(int base, unsigned int exp) {
  int result = 1;
  while (exp > 0) {
    if (exp & 1)
      result *= base;
    base *= base;
    exp /= 2;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ds_pow>:
  endbr64
  test   %esi,%esi
  je     L45
  mov    $0x1,%edx
  jmp    L20
L43:
  imul   %edi,%edi
  mov    %esi,%eax
  shr    %eax
  cmp    $0x1,%esi
  jbe    L1
  mov    %eax,%esi
L20:
  test   $0x1,%sil
  je     L43
  imul   %edi,%edx
  jmp    L43
L45:
  mov    $0x1,%edx
L1:
  mov    %edx,%eax
  ret
```

assistant: ```c
int _ds_pow(int base, unsigned int exp) {
  int result = 1;
  while (exp > 0) {
    if (exp & 1)
      result *= base;
    base *= base;
    exp /= 2;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_ds_pow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L26
  nopl   (%rax)
L21:
  test   $0x1,%sil
  je     L22
  imul   %edi,%eax
L22:
  imul   %edi,%edi
  shr    %esi
  jne    L21
  ret
  nopl   0x0(%rax)
L26:
  ret
```

assistant: ```c
int _ds_pow(int base, unsigned int exp) {
  int result = 1;
  while (exp > 0) {
    if (exp & 1)
      result *= base;
    base *= base;
    exp /= 2;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ds_pow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L10
  nopl   (%rax)
L17:
  test   $0x1,%sil
  je     L8
  imul   %edi,%eax
L8:
  imul   %edi,%edi
  shr    %esi
  jne    L17
  ret
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
int _ds_pow(int base, unsigned int exp) {
  int result = 1;
  while (exp > 0) {
    if (exp & 1)
      result *= base;
    base *= base;
    exp /= 2;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<any_less_than_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L6:
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  movss  D8(%rip),%xmm0
  comiss %xmm1,%xmm0
  ja     L41
  jmp    L31
L41:
  mov    $0x1,%eax
  jmp    L44
L31:
  mov    -0x8(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  cmp    %rax,-0x18(%rbp)
  jb     L6
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: byte[4]

tool: {"D8": [0xac,0xc5,0x27,0xb7]}

assistant: ```c
unsigned any_less_than_zero(const float *const __restrict v, const unsigned n) {
  const float *c = v + n;
  while (c-- > v)
    if (*c < -(1e-5f))
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<any_less_than_zero>:
  endbr64
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
  movss  D8(%rip),%xmm0
L2:
  cmp    %rax,%rdi
  jae    L1
  sub    $0x4,%rax
  comiss (%rax),%xmm0
  jbe    L2
  mov    $0x1,%eax
  ret
L1:
  mov    $0x0,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: byte[4]

tool: {"D8": [0xac,0xc5,0x27,0xb7]}

assistant: ```c
unsigned any_less_than_zero(const float *const __restrict v, const unsigned n) {
  const float *c = v + n;
  while (c-- > v)
    if (*c < -(1e-5f))
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<any_less_than_zero>:
  endbr64
  mov    %esi,%esi
  movss  D1(%rip),%xmm0
  lea    (%rdi,%rsi,4),%rax
  jmp    L28
  nopl   0x0(%rax)
L21:
  sub    $0x4,%rax
  comiss (%rax),%xmm0
  ja     L7
L28:
  cmp    %rax,%rdi
  jb     L21
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: byte[4]

tool: {"D1": [0xac,0xc5,0x27,0xb7]}

assistant: ```c
unsigned any_less_than_zero(const float *const __restrict v, const unsigned n) {
  const float *c = v + n;
  while (c-- > v)
    if (*c < -(1e-5f))
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<any_less_than_zero>:
  endbr64
  mov    %esi,%esi
  movss  D0(%rip),%xmm0
  lea    (%rdi,%rsi,4),%rax
  jmp    L16
  nopl   0x0(%rax)
L5:
  sub    $0x4,%rax
  comiss (%rax),%xmm0
  ja     L0
L16:
  cmp    %rax,%rdi
  jb     L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x1,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: byte[4]

tool: {"D0": [0xac,0xc5,0x27,0xb7]}

assistant: ```c
unsigned any_less_than_zero(const float *const __restrict v, const unsigned n) {
  const float *c = v + n;
  while (c-- > v)
    if (*c < -(1e-5f))
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rsi
  lea    -0x20(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm3
  movapd %xmm0,%xmm2
  subsd  %xmm3,%xmm2
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm3
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
type: string
name: parse_data
arguments: data_tag: D6
type: string

tool: D14: %lf %lf %lf %lf

tool: D6: %.4lf


assistant: ```c
int main() {
  double x1, x2, y1, y2;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  printf("%.4lf\n", sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1)));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x20(%rsp),%r8
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  subsd  0x8(%rsp),%xmm0
  movsd  0x20(%rsp),%xmm1
  subsd  0x18(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  call   <sqrt@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D0: %lf %lf %lf %lf

tool: D1: %.4lf


assistant: ```c
int main() {
  double x1, x2, y1, y2;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  printf("%.4lf\n", sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1)));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D7(%rip),%rdi
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rdx
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  movsd  0x20(%rsp),%xmm1
  subsd  0x8(%rsp),%xmm0
  subsd  0x18(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  call   <sqrt@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string

tool: D7: %lf %lf %lf %lf

tool: D11: %.4lf


assistant: ```c
int main() {
  double x1, x2, y1, y2;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  printf("%.4lf\n", sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1)));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D2(%rip),%rdi
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rdx
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  movsd  0x20(%rsp),%xmm1
  subsd  0x8(%rsp),%xmm0
  subsd  0x18(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  call   <sqrt@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D16
data_type: string

tool: D2: %lf %lf %lf %lf

tool: D16: %.4lf


assistant: ```c
int main() {
  double x1, x2, y1, y2;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  printf("%.4lf\n", sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1)));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wmemcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  leave
  ret
```

assistant: ```c
wchar_t *wmemcpy(wchar_t *d, const wchar_t *s, size_t n) {
  assert(d != NULL);
  assert(s != NULL);
  return (wchar_t *)memcpy(d, s, n * sizeof(wchar_t));
}
```