user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    -0x3c(%rbp),%rdx
  lea    -0x40(%rbp),%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rdx
  lea    0x0(,%rdx,4),%rax
  mov    %rax,-0x58(%rbp)
  movslq -0x40(%rbp),%rax
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L147:
  cmp    %rdx,%rsp
  je     L44
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L147
L44:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L156
  orq    $0x0,-0x8(%rsp,%rax,1)
L156:
  mov    %rsp,%r13
  lea    D22(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,-0x40(%rbp)
  jle    L7
  mov    -0x58(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  mov    $0x0,%r15d
  lea    D5(%rip),%r14
  jmp    L90
L71:
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x3c(%rbp)
  jg     L71
L91:
  add    $0x1,%r15d
  mov    -0x50(%rbp),%rcx
  add    %rcx,-0x48(%rbp)
  cmp    %r15d,-0x40(%rbp)
  jle    L7
L90:
  mov    -0x48(%rbp),%rax
  lea    0x0(%r13,%rax,4),%r12
  mov    $0x0,%ebx
  cmpl   $0x0,-0x3c(%rbp)
  jg     L71
  jmp    L91
L7:
  lea    D44(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,-0x40(%rbp)
  jle    L110
  mov    -0x58(%rbp),%r15
  shr    $0x2,%r15
  mov    $0x0,%r12d
  lea    D30(%rip),%r14
  jmp    L0
L35:
  movslq %r12d,%rax
  movslq %ebx,%rdx
  imul   %r15,%rdx
  add    %rdx,%rax
  mov    0x0(%r13,%rax,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,-0x3c(%rbp)
  jg     L35
L79:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    %r12d,-0x40(%rbp)
  jle    L110
L0:
  mov    $0x0,%ebx
  cmpl   $0x0,-0x3c(%rbp)
  jg     L35
  jmp    L79
L110:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D56
data_type: string
name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D22
data_type: string
name: read_data
arguments: label: D5
data_type: string
name: read_data
arguments: label: D44
data_type: string
name: read_data
arguments: label: D30
data_type: string

tool: D56: Enter the order of the matrix (m*n): 

tool: D16: %d*%d

tool: D22: Enter the elements of the matrix: 

tool: D5: %d

tool: D44: Transpose of the matrix: 

tool: D30: %d 

assistant: ```c
int main() {
  int i, j, m, n;
  printf("Enter the order of the matrix (m*n): ");
  scanf("%d*%d", &m, &n);
  int matrix[m][n];
  printf("Enter the elements of the matrix: \n");
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", &matrix[i][j]);
    }
  }
  printf("Transpose of the matrix: \n");
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%d ", matrix[j][i]);
    }
    printf("\n");
  }
}
```