ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_casilleros_from_index>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xd(%rsp)
  movb   $0x0,0x15(%rsp)
  movq   $0x0,0x16(%rsp)
  movb   $0x0,0x1e(%rsp)
  movq   $0x0,0x1f(%rsp)
  movb   $0x0,0x27(%rsp)
  lea    0xd(%rsp),%rdi
  call   <get_cuadrante_from_index@plt>
  lea    0x16(%rsp),%rdi
  mov    %ebp,%esi
  call   <get_fila_from_index@plt>
  lea    0x1f(%rsp),%rdi
  mov    %ebp,%esi
  call   <get_columna_from_index@plt>
  mov    %rbx,%rax
  lea    0x9(%rbx),%rdx
L32:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L32
  mov    $0x0,%eax
  jmp    L24
L34:
  add    $0x1,%rax
  cmp    $0x9,%rax
  je     L61
L24:
  movzbl 0xd(%rsp,%rax,1),%edx
  test   %dl,%dl
  jle    L68
  movsbq %dl,%rdx
  movb   $0x1,-0x1(%rbx,%rdx,1)
L68:
  movzbl 0x16(%rsp,%rax,1),%edx
  test   %dl,%dl
  jle    L19
  movsbq %dl,%rdx
  movb   $0x1,-0x1(%rbx,%rdx,1)
L19:
  movzbl 0x1f(%rsp,%rax,1),%edx
  test   %dl,%dl
  jle    L34
  movsbq %dl,%rdx
  movb   $0x1,-0x1(%rbx,%rdx,1)
  jmp    L34
L61:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_casilleros_from_index(char *unicos, int index) {
  char cuadrante[9] = {0};
  char fila[9] = {0};
  char columna[9] = {0};
  int i = 0;
  get_cuadrante_from_index(cuadrante, index);
  get_fila_from_index(fila, index);
  get_columna_from_index(columna, index);
  for (i = 0; i < 9; i++) {
    unicos[i] = 0;
  }
  for (i = 0; i < 9; i++) {
    if (cuadrante[i] > 0) {
      unicos[cuadrante[i] - 1] = 1;
    }
    if (fila[i] > 0) {
      unicos[fila[i] - 1] = 1;
    }
    if (columna[i] > 0) {
      unicos[columna[i] - 1] = 1;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_casilleros_from_index>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%r13
  lea    0x16(%rsp),%r12
  movq   $0x0,0xd(%rsp)
  mov    %r13,%rdi
  movb   $0x0,0x15(%rsp)
  lea    0x1f(%rsp),%rbp
  movq   $0x0,0x16(%rsp)
  movb   $0x0,0x1e(%rsp)
  movq   $0x0,0x1f(%rsp)
  movb   $0x0,0x27(%rsp)
  call   <get_cuadrante_from_index@plt>
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <get_fila_from_index@plt>
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <get_columna_from_index@plt>
  movq   $0x0,(%rbx)
  xor    %eax,%eax
  movb   $0x0,0x8(%rbx)
  nopw   0x0(%rax,%rax,1)
L7:
  movsbq 0x0(%r13,%rax,1),%rdx
  test   %dl,%dl
  jle    L43
  movb   $0x1,-0x1(%rbx,%rdx,1)
L43:
  movsbq (%r12,%rax,1),%rdx
  test   %dl,%dl
  jle    L11
  movb   $0x1,-0x1(%rbx,%rdx,1)
L11:
  movsbq 0x0(%rbp,%rax,1),%rdx
  test   %dl,%dl
  jle    L18
  movb   $0x1,-0x1(%rbx,%rdx,1)
L18:
  add    $0x1,%rax
  cmp    $0x9,%rax
  jne    L7
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_casilleros_from_index(char *unicos, int index) {
  char cuadrante[9] = {0};
  char fila[9] = {0};
  char columna[9] = {0};
  int i = 0;
  get_cuadrante_from_index(cuadrante, index);
  get_fila_from_index(fila, index);
  get_columna_from_index(columna, index);
  for (i = 0; i < 9; i++) {
    unicos[i] = 0;
  }
  for (i = 0; i < 9; i++) {
    if (cuadrante[i] > 0) {
      unicos[cuadrante[i] - 1] = 1;
    }
    if (fila[i] > 0) {
      unicos[fila[i] - 1] = 1;
    }
    if (columna[i] > 0) {
      unicos[columna[i] - 1] = 1;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D0: pid -o pid,ppid

assistant: ```c
int main() {
  system("pid -o pid,ppid");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: pid -o pid,ppid

assistant: ```c
int main() {
  system("pid -o pid,ppid");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: pid -o pid,ppid

assistant: ```c
int main() {
  system("pid -o pid,ppid");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: pid -o pid,ppid

assistant: ```c
int main() {
  system("pid -o pid,ppid");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D0(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D43(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <longestValidParentheses@plt>
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <longestValidParentheses@plt>
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <longestValidParentheses@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D34
type_infered: string
name: unpack_data
arguments: data_label: D43
type_infered: string
name: unpack_data
arguments: data_label: D47
type_infered: string
name: unpack_data
arguments: data_label: D54
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string

tool: D0: (()

tool: D34: )()())

tool: D43: ()(()

tool: D47: result of s1 : %d


tool: D54: result of s2 : %d


tool: D19: result of s3 : %d


assistant: ```c
int main(void) {
  char *s1 = "(()";
  char *s2 = ")()())";
  char *s3 = "()(()";
  printf("result of s1 : %d\n", longestValidParentheses(s1));
  printf("result of s2 : %d\n", longestValidParentheses(s2));
  printf("result of s3 : %d\n", longestValidParentheses(s3));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <longestValidParentheses@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <longestValidParentheses@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <longestValidParentheses@plt>
  mov    %eax,%esi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D24
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D41
datatype: string

tool: D0: (()

tool: D21: result of s1 : %d


tool: D24: )()())

tool: D12: result of s2 : %d


tool: D30: ()(()

tool: D41: result of s3 : %d


assistant: ```c
int main(void) {
  char *s1 = "(()";
  char *s2 = ")()())";
  char *s3 = "()(()";
  printf("result of s1 : %d\n", longestValidParentheses(s1));
  printf("result of s2 : %d\n", longestValidParentheses(s2));
  printf("result of s3 : %d\n", longestValidParentheses(s3));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <longestValidParentheses@plt>
  lea    D48(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <longestValidParentheses@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <longestValidParentheses@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D48
datatype: string
name: retrieve_data
arguments: tag: D54
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D30
datatype: string
name: retrieve_data
arguments: tag: D19
datatype: string

tool: D17: (()

tool: D48: result of s1 : %d


tool: D54: )()())

tool: D2: result of s2 : %d


tool: D30: ()(()

tool: D19: result of s3 : %d


assistant: ```c
int main(void) {
  char *s1 = "(()";
  char *s2 = ")()())";
  char *s3 = "()(()";
  printf("result of s1 : %d\n", longestValidParentheses(s1));
  printf("result of s2 : %d\n", longestValidParentheses(s2));
  printf("result of s3 : %d\n", longestValidParentheses(s3));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D27(%rip),%rdi
  call   <longestValidParentheses@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <longestValidParentheses@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <longestValidParentheses@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D27
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D36
type_guessed: string
name: disassemble_data
arguments: tag: D18
type_guessed: string
name: disassemble_data
arguments: tag: D38
type_guessed: string
name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D27: (()

tool: D21: result of s1 : %d


tool: D36: )()())

tool: D18: result of s2 : %d


tool: D38: ()(()

tool: D9: result of s3 : %d


assistant: ```c
int main(void) {
  char *s1 = "(()";
  char *s2 = ")()())";
  char *s3 = "()(()";
  printf("result of s1 : %d\n", longestValidParentheses(s1));
  printf("result of s2 : %d\n", longestValidParentheses(s2));
  printf("result of s3 : %d\n", longestValidParentheses(s3));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <run2@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  run2();
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <run2@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  run2();
  return EXIT_SUCCESS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run2@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  run2();
  return EXIT_SUCCESS;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run2@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  run2();
  return EXIT_SUCCESS;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum_of_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L17
L19:
  mov    -0x28(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <lldiv@plt>
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L17:
  cmpq   $0x0,-0x28(%rbp)
  jne    L19
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long sum_of_digits(long long n) {
  long long sum = 0;
  while (n) {
    lldiv_t d = lldiv(n, 10ull);
    sum += d.rem;
    n = d.quot;
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum_of_digits>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L24
  mov    $0x0,%ebx
L1:
  mov    $0xa,%esi
  call   <lldiv@plt>
  add    %rdx,%rbx
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L1
L4:
  mov    %rbx,%rax
  pop    %rbx
  ret
L24:
  mov    %rdi,%rbx
  jmp    L4
```

assistant: ```c
long long sum_of_digits(long long n) {
  long long sum = 0;
  while (n) {
    lldiv_t d = lldiv(n, 10ull);
    sum += d.rem;
    n = d.quot;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sum_of_digits>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %rdi,%rdi
  je     L6
  xchg   %ax,%ax
L4:
  mov    $0xa,%esi
  call   <lldiv@plt>
  add    %rdx,%r12
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L4
L6:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long long sum_of_digits(long long n) {
  long long sum = 0;
  while (n) {
    lldiv_t d = lldiv(n, 10ull);
    sum += d.rem;
    n = d.quot;
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum_of_digits>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %rdi,%rdi
  je     L18
  xchg   %ax,%ax
L7:
  mov    $0xa,%esi
  call   <lldiv@plt>
  add    %rdx,%r12
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L7
L18:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long long sum_of_digits(long long n) {
  long long sum = 0;
  while (n) {
    lldiv_t d = lldiv(n, 10ull);
    sum += d.rem;
    n = d.quot;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inprec_rstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L15
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <inprec_ru8@plt>
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0x0,%edi
  call   <inprec_ru8@plt>
  nop
  leave
  ret
```

assistant: ```c
void inprec_rstr(const char *s) {
  while (*s) {
    inprec_ru8(*s);
    s++;
  }
  inprec_ru8(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inprec_rstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L13
L19:
  movsbl %dil,%edi
  call   <inprec_ru8@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L13:
  mov    $0x0,%edi
  call   <inprec_ru8@plt>
  pop    %rbx
  ret
```

assistant: ```c
void inprec_rstr(const char *s) {
  while (*s) {
    inprec_ru8(*s);
    s++;
  }
  inprec_ru8(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inprec_rstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L3:
  call   <inprec_ru8@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
L14:
  xor    %edi,%edi
  pop    %rbx
  jmp    1050 <inprec_ru8@plt>
```

assistant: ```c
void inprec_rstr(const char *s) {
  while (*s) {
    inprec_ru8(*s);
    s++;
  }
  inprec_ru8(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inprec_rstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L18
L3:
  call   <inprec_ru8@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
L18:
  xor    %edi,%edi
  pop    %rbx
  jmp    1050 <inprec_ru8@plt>
```

assistant: ```c
void inprec_rstr(const char *s) {
  while (*s) {
    inprec_ru8(*s);
    s++;
  }
  inprec_ru8(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<promedio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L8:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L8
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x2c(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double promedio(double valores[], int size) {
  double suma, promedio;
  int i;
  for (i = 0; i < size; i++) {
    suma += valores[i];
  }
  promedio = (double)suma / size;
  return promedio;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<promedio>:
  endbr64
  test   %esi,%esi
  jle    L14
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L1:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L1
L14:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double promedio(double valores[], int size) {
  double suma, promedio;
  int i;
  for (i = 0; i < size; i++) {
    suma += valores[i];
  }
  promedio = (double)suma / size;
  return promedio;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<promedio>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
L11:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L11
L8:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double promedio(double valores[], int size) {
  double suma, promedio;
  int i;
  for (i = 0; i < size; i++) {
    suma += valores[i];
  }
  promedio = (double)suma / size;
  return promedio;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<promedio>:
  endbr64
  test   %esi,%esi
  jle    L7
  cmp    $0x1,%esi
  je     L46
  mov    %esi,%edx
  mov    %rdi,%rax
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L8:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L8
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%sil
  je     L7
L40:
  cltq
  addsd  (%rdi,%rax,8),%xmm0
L7:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L46:
  xor    %eax,%eax
  jmp    L40
```

assistant: ```c
double promedio(double valores[], int size) {
  double suma, promedio;
  int i;
  for (i = 0; i < size; i++) {
    suma += valores[i];
  }
  promedio = (double)suma / size;
  return promedio;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<StrUtil_copyTString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jg     L61
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L34
  lea    D25(%rip),%rax
  mov    %rax,%rcx
  mov    $0x2,%edx
  lea    D51(%rip),%rax
  mov    %rax,%rsi
  mov    $0xd,%edi
  call   <Error_write@plt>
  mov    $0x0,%eax
  jmp    L27
L34:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  jmp    L7
L61:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L19
  lea    D33(%rip),%rax
  mov    %rax,%rcx
  mov    $0x2,%edx
  lea    D51(%rip),%rax
  mov    %rax,%rsi
  mov    $0xd,%edi
  call   <Error_write@plt>
  mov    $0x0,%eax
  jmp    L27
L19:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <StrUtil_rmEndSpaces@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L7
  lea    D25(%rip),%rax
  mov    %rax,%rcx
  mov    $0x2,%edx
  lea    D51(%rip),%rax
  mov    %rax,%rsi
  mov    $0xf,%edi
  call   <Error_write@plt>
  mov    $0x0,%eax
  jmp    L27
L7:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D25
data_type: string
name: disassemble_data
arguments: tag: D51
data_type: string
name: disassemble_data
arguments: tag: D33
data_type: string

tool: D25: to

tool: D51: StrUtil_copyTString

tool: D33: *to

assistant: ```c
char *StrUtil_copyTString(char **to, char *from, int Start) {
  int lenTo;
  int lenFrom = strlen(from);
  if (lenFrom - 1 < Start) {
    if ((*to = (char *)calloc(1, sizeof(char))) == NULL) {
      Error_write(13, "StrUtil_copyTString", 2, "to");
      return NULL;
    }
    (*to)[0] = '\0';
  } else {
    if ((*to = (char *)calloc(lenFrom + 1, sizeof(char))) == NULL) {
      Error_write(13, "StrUtil_copyTString", 2, "*to");
      return NULL;
    }
    strcpy(*to, &(from[Start]));
    lenTo = StrUtil_rmEndSpaces(*to);
    if ((*to = (char *)realloc(*to, (lenTo + 1) * sizeof(char))) == NULL) {
      Error_write(15, "StrUtil_copyTString", 2, "to");
      return NULL;
    }
  }
  return *to;
}
```