user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  xor    %edx,%edx
  lea    D10(%rip),%rdi
  movabs $0x676e656e696c,%rcx
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x676e616978696c,%rax
  lea    0x14(%rsp),%r12
  mov    %rcx,0x14(%rsp)
  xor    %ecx,%ecx
  mov    %si,0x26(%rsp)
  lea    0xa(%rsp),%rbp
  mov    $0x1e,%esi
  mov    %dx,0x12(%rsp)
  mov    %cx,0x1c(%rsp)
  mov    %rax,0xa(%rsp)
  mov    %rax,0x1e(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L46
L67:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L15
L12:
  lea    0x1e(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L31
  lea    D88(%rip),%rdi
  mov    %rbp,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
L50:
  movsd  D92(%rip),%xmm0
  mov    $0x1e,%esi
  lea    D23(%rip),%rdi
  mov    $0x1,%eax
  lea    D101(%rip),%rbp
  call   <printf@plt>
  mov    D92(%rip),%rax
  mov    $0x1e,%esi
  lea    D103(%rip),%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  mov    $0x4,%esi
  xor    %eax,%eax
  lea    D117(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x1e,%edi
  call   <max@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movss  D57(%rip),%xmm1
  movss  D38(%rip),%xmm0
  call   <fun@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L31:
  lea    D120(%rip),%rdi
  call   <puts@plt>
  jmp    L50
L46:
  mov    %rbp,%rsi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L67
L15:
  mov    %rbp,%rsi
  lea    D88(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L12
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D88
type_infered: string
name: retrieve_data
arguments: data_tag: D92
type_infered: f64
name: retrieve_data
arguments: data_tag: D23
type_infered: string
name: retrieve_data
arguments: data_tag: D101
type_infered: string
name: retrieve_data
arguments: data_tag: D103
type_infered: string
name: retrieve_data
arguments: data_tag: D117
type_infered: string
name: retrieve_data
arguments: data_tag: D57
type_infered: f32
name: retrieve_data
arguments: data_tag: D38
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D120
type_infered: string

tool: D10: i	=%d


tool: D88: %s 

tool: D92: 4.5

tool: D23: 
i=%f,m=%d

tool: D101: 
%d

tool: D103: 
i=%d,m=%f

tool: D117: 
sizeof i=%d,m=%d

tool: D57: 5.5

tool: {"D38": [0x00,0x00,0x90,0x40]}

tool: D120: Then are equal.

assistant: ```c
int main(int argc, char **argv) {
  int i = 30, j = -1;
  float m = 4.5, n = 5.5;
  char str1[10] = "lixiang", str2[10] = "lineng", str3[10] = "lixiang";
  if (j) {
    printf("i\t=%d\n", i);
  }
  j = 0;
  if (j) {
    printf("i\t=%d\n", i);
  }
  if (strcmp(str1, str2)) {
    printf("%s ", str1);
    printf("%s\n", str2);
  }
  if (!strcmp(str2, str1)) {
    printf("%s ", str1);
    printf("%s\n", str2);
  }
  if (strcmp(str3, str1)) {
    printf("%s ", str1);
    printf("%s\n", str2);
  } else {
    printf("Then are equal.\n");
  }
  printf("\ni=%f,m=%d", i, m);
  printf("\ni=%d,m=%f", i, m);
  printf("\nsizeof i=%d,m=%d", sizeof(int), sizeof(float));
  printf("\n%d", max(i, j));
  printf("\n%d", fun(m, n));
}
```