ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  jne    L55
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
L55:
  mov    -0x10(%rbp),%eax
  lea    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  jne    L17
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
L17:
  mov    -0xc(%rbp),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  jne    L74
  lea    D34(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
L74:
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  jne    L15
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  je     L15
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L40
L15:
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D48(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <errx@plt>
L40:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jne    L49
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <errx@plt>
L49:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D34
type_infered: string
name: unpack_data
arguments: data_label: D48
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D32
type_infered: string

tool: D7: FAIL: pipe

tool: D1: FAIL: fstat st1

tool: D34: FAIL: fstat st2

tool: D48: FAIL: wrong dev number %d %d

tool: D10: FAIL: inode numbers are equal: %d

tool: D32: PASS


assistant: ```c
int main(void) {
  int pipefd[2];
  struct stat st1, st2;
  if (pipe(pipefd) == -1)
    err(1, "FAIL: pipe");
  if (fstat(pipefd[0], &st1) == -1)
    err(1, "FAIL: fstat st1");
  if (fstat(pipefd[1], &st2) == -1)
    err(1, "FAIL: fstat st2");
  if (st1.st_dev != st2.st_dev || st1.st_dev == 0 || st2.st_dev == 0)
    errx(1, "FAIL: wrong dev number %d %d", st1.st_dev, st2.st_dev);
  if (st1.st_ino == st2.st_ino)
    errx(1, "FAIL: inode numbers are equal: %d", st1.st_ino);
  close(pipefd[0]);
  close(pipefd[1]);
  printf("PASS\n");
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  je     L63
L40:
  mov    %rsp,%rsi
  mov    0x20(%rsp),%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L54
L95:
  lea    0x10(%rsp),%rsi
  mov    0x24(%rsp),%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L38
L15:
  mov    (%rsp),%rdx
  mov    0x10(%rsp),%rcx
  test   %rdx,%rdx
  sete   %al
  cmp    %rcx,%rdx
  setne  %sil
  or     %sil,%al
  jne    L10
  test   %rcx,%rcx
  jne    L81
L10:
  lea    D22(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <errx@plt>
L81:
  mov    0x8(%rsp),%rdx
  cmp    0x18(%rsp),%rdx
  je     L1
L4:
  mov    0x20(%rsp),%edi
  call   <close@plt>
  mov    0x24(%rsp),%edi
  call   <close@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L63:
  lea    D49(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L40
L54:
  lea    D55(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L95
L38:
  lea    D28(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L15
L1:
  lea    D33(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <errx@plt>
  jmp    L4
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
datatype: string
name: parse_data
arguments: data_label: D19
datatype: string
name: parse_data
arguments: data_label: D49
datatype: string
name: parse_data
arguments: data_label: D55
datatype: string
name: parse_data
arguments: data_label: D28
datatype: string
name: parse_data
arguments: data_label: D33
datatype: string

tool: D22: FAIL: wrong dev number %d %d

tool: D19: PASS


tool: D49: FAIL: pipe

tool: D55: FAIL: fstat st1

tool: D28: FAIL: fstat st2

tool: D33: FAIL: inode numbers are equal: %d

assistant: ```c
int main(void) {
  int pipefd[2];
  struct stat st1, st2;
  if (pipe(pipefd) == -1)
    err(1, "FAIL: pipe");
  if (fstat(pipefd[0], &st1) == -1)
    err(1, "FAIL: fstat st1");
  if (fstat(pipefd[1], &st2) == -1)
    err(1, "FAIL: fstat st2");
  if (st1.st_dev != st2.st_dev || st1.st_dev == 0 || st2.st_dev == 0)
    errx(1, "FAIL: wrong dev number %d %d", st1.st_dev, st2.st_dev);
  if (st1.st_ino == st2.st_ino)
    errx(1, "FAIL: inode numbers are equal: %d", st1.st_ino);
  close(pipefd[0]);
  close(pipefd[1]);
  printf("PASS\n");
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  je     L39
L109:
  mov    0x20(%rsp),%edi
  mov    %rsp,%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L100
L21:
  mov    0x24(%rsp),%edi
  lea    0x10(%rsp),%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L3
L38:
  mov    (%rsp),%rdx
  mov    0x10(%rsp),%rcx
  cmp    %rcx,%rdx
  setne  %al
  test   %rdx,%rdx
  sete   %sil
  or     %sil,%al
  jne    L15
  test   %rcx,%rcx
  jne    L16
L15:
  lea    D41(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <errx@plt>
L16:
  mov    0x8(%rsp),%rdx
  cmp    0x18(%rsp),%rdx
  je     L62
L54:
  mov    0x20(%rsp),%edi
  call   <close@plt>
  mov    0x24(%rsp),%edi
  call   <close@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L39:
  lea    D19(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L109
L62:
  lea    D34(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <errx@plt>
  jmp    L54
L3:
  lea    D57(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L38
L100:
  lea    D9(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L21
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D41
data_type: string
name: retrieve_data
arguments: data_tag: D22
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D34
data_type: string
name: retrieve_data
arguments: data_tag: D57
data_type: string
name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D41: FAIL: wrong dev number %d %d

tool: D22: PASS


tool: D19: FAIL: pipe

tool: D34: FAIL: inode numbers are equal: %d

tool: D57: FAIL: fstat st2

tool: D9: FAIL: fstat st1

assistant: ```c
int main(void) {
  int pipefd[2];
  struct stat st1, st2;
  if (pipe(pipefd) == -1)
    err(1, "FAIL: pipe");
  if (fstat(pipefd[0], &st1) == -1)
    err(1, "FAIL: fstat st1");
  if (fstat(pipefd[1], &st2) == -1)
    err(1, "FAIL: fstat st2");
  if (st1.st_dev != st2.st_dev || st1.st_dev == 0 || st2.st_dev == 0)
    errx(1, "FAIL: wrong dev number %d %d", st1.st_dev, st2.st_dev);
  if (st1.st_ino == st2.st_ino)
    errx(1, "FAIL: inode numbers are equal: %d", st1.st_ino);
  close(pipefd[0]);
  close(pipefd[1]);
  printf("PASS\n");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  je     L76
L73:
  mov    0x20(%rsp),%edi
  mov    %rsp,%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L70
L36:
  mov    0x24(%rsp),%edi
  lea    0x10(%rsp),%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L30
L79:
  mov    (%rsp),%rdx
  mov    0x10(%rsp),%rcx
  cmp    %rcx,%rdx
  setne  %al
  test   %rdx,%rdx
  sete   %sil
  or     %sil,%al
  jne    L27
  test   %rcx,%rcx
  jne    L96
L27:
  lea    D37(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <errx@plt>
L96:
  mov    0x8(%rsp),%rdx
  cmp    0x18(%rsp),%rdx
  je     L81
L11:
  mov    0x20(%rsp),%edi
  call   <close@plt>
  mov    0x24(%rsp),%edi
  call   <close@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L76:
  lea    D49(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L73
L81:
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <errx@plt>
  jmp    L11
L30:
  lea    D14(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L79
L70:
  lea    D26(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L36
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D37
type_infered: string
name: disassemble_data
arguments: data_label: D45
type_infered: string
name: disassemble_data
arguments: data_label: D49
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string
name: disassemble_data
arguments: data_label: D26
type_infered: string

tool: D37: FAIL: wrong dev number %d %d

tool: D45: PASS


tool: D49: FAIL: pipe

tool: D0: FAIL: inode numbers are equal: %d

tool: D14: FAIL: fstat st2

tool: D26: FAIL: fstat st1

assistant: ```c
int main(void) {
  int pipefd[2];
  struct stat st1, st2;
  if (pipe(pipefd) == -1)
    err(1, "FAIL: pipe");
  if (fstat(pipefd[0], &st1) == -1)
    err(1, "FAIL: fstat st1");
  if (fstat(pipefd[1], &st2) == -1)
    err(1, "FAIL: fstat st2");
  if (st1.st_dev != st2.st_dev || st1.st_dev == 0 || st2.st_dev == 0)
    errx(1, "FAIL: wrong dev number %d %d", st1.st_dev, st2.st_dev);
  if (st1.st_ino == st2.st_ino)
    errx(1, "FAIL: inode numbers are equal: %d", st1.st_ino);
  close(pipefd[0]);
  close(pipefd[1]);
  printf("PASS\n");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L65
  movl   $0x1,-0xc(%rbp)
  jmp    L49
L8:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L58
L42:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L58:
  cmpl   $0x0,-0x8(%rbp)
  jle    L63
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L42
L63:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  jmp    L9
L65:
  nop
L9:
  pop    %rbp
  ret
```

assistant: ```c
void insertionSort(int *array, const int size) {
  if (size < 2)
    return;
  int value;
  int i;
  int j;
  i = 1;
  while (i < size) {
    j = i;
    value = array[i];
    while (j > 0 && array[j - 1] > value) {
      array[j] = array[j - 1];
      --j;
    }
    array[j] = value;
    ++i;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insertionSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L21
  lea    0x4(%rdi),%r10
  mov    $0x1,%r9d
  jmp    L45
L4:
  movslq %edx,%rdx
  mov    %r8d,(%rdi,%rdx,4)
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %r9d,%esi
  je     L21
L45:
  mov    (%r10),%r8d
  mov    %r10,%rax
  mov    %r9d,%edx
  test   %r9d,%r9d
  jle    L4
L69:
  mov    -0x4(%rax),%ecx
  cmp    %r8d,%ecx
  jle    L4
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L69
  jmp    L4
L21:
  ret
```

assistant: ```c
void insertionSort(int *array, const int size) {
  if (size < 2)
    return;
  int value;
  int i;
  int j;
  i = 1;
  while (i < size) {
    j = i;
    value = array[i];
    while (j > 0 && array[j - 1] > value) {
      array[j] = array[j - 1];
      --j;
    }
    array[j] = value;
    ++i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertionSort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L23
  nopl   0x0(%rax,%rax,1)
L7:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L26:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L29
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rdi,%rax
  jne    L26
  mov    %rdi,%rcx
L29:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L7
L23:
  ret
```

assistant: ```c
void insertionSort(int *array, const int size) {
  if (size < 2)
    return;
  int value;
  int i;
  int j;
  i = 1;
  while (i < size) {
    j = i;
    value = array[i];
    while (j > 0 && array[j - 1] > value) {
      array[j] = array[j - 1];
      --j;
    }
    array[j] = value;
    ++i;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<insertionSort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L29
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L23:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L19
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rdi,%rax
  jne    L23
  mov    %rdi,%rcx
L19:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L2
L29:
  ret
```

assistant: ```c
void insertionSort(int *array, const int size) {
  if (size < 2)
    return;
  int value;
  int i;
  int j;
  i = 1;
  while (i < size) {
    j = i;
    value = array[i];
    while (j > 0 && array[j - 1] > value) {
      array[j] = array[j - 1];
      --j;
    }
    array[j] = value;
    ++i;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_cpuconfig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D6: #define V9


tool: D0: #define DTB_ENTRIES 32


assistant: ```c
void get_cpuconfig(void) {
  printf("#define V9\n");
  printf("#define DTB_ENTRIES 32\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<get_cpuconfig>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
datatype: string
name: unpack_data
arguments: label: D3
datatype: string

tool: D17: #define V9


tool: D3: #define DTB_ENTRIES 32


assistant: ```c
void get_cpuconfig(void) {
  printf("#define V9\n");
  printf("#define DTB_ENTRIES 32\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_cpuconfig>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D6
type_infered: string

tool: D12: #define V9


tool: D6: #define DTB_ENTRIES 32


assistant: ```c
void get_cpuconfig(void) {
  printf("#define V9\n");
  printf("#define DTB_ENTRIES 32\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_cpuconfig>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D10
data_type: string

tool: D17: #define V9


tool: D10: #define DTB_ENTRIES 32


assistant: ```c
void get_cpuconfig(void) {
  printf("#define V9\n");
  printf("#define DTB_ENTRIES 32\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add_obstacle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int add_obstacle(long obs[2 * 10 + 1]) {
  obs[0] = obs[0];
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<add_obstacle>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int add_obstacle(long obs[2 * 10 + 1]) {
  obs[0] = obs[0];
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_obstacle>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int add_obstacle(long obs[2 * 10 + 1]) {
  obs[0] = obs[0];
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_obstacle>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int add_obstacle(long obs[2 * 10 + 1]) {
  obs[0] = obs[0];
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L16:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_int(int *arr1, int *arr2, int nb_elements) {
  int i, tmp;
  for (i = 0; i < nb_elements; i++) {
    tmp = arr1[i];
    arr1[i] = arr2[i];
    arr2[i] = tmp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_int>:
  endbr64
  test   %edx,%edx
  jle    L13
  mov    %edx,%edx
  mov    $0x0,%eax
L17:
  mov    (%rdi,%rax,4),%ecx
  mov    (%rsi,%rax,4),%r8d
  mov    %r8d,(%rdi,%rax,4)
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L13:
  ret
```

assistant: ```c
void swap_int(int *arr1, int *arr2, int nb_elements) {
  int i, tmp;
  for (i = 0; i < nb_elements; i++) {
    tmp = arr1[i];
    arr1[i] = arr2[i];
    arr2[i] = tmp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap_int>:
  endbr64
  test   %edx,%edx
  jle    L8
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L10:
  mov    (%rdi,%rax,4),%ecx
  mov    (%rsi,%rax,4),%r8d
  mov    %r8d,(%rdi,%rax,4)
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
L8:
  ret
```

assistant: ```c
void swap_int(int *arr1, int *arr2, int nb_elements) {
  int i, tmp;
  for (i = 0; i < nb_elements; i++) {
    tmp = arr1[i];
    arr1[i] = arr2[i];
    arr2[i] = tmp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap_int>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L0
  lea    0xf(%rdi),%rax
  sub    %rsi,%rax
  cmp    $0x1e,%rax
  jbe    L13
  cmp    $0x1,%edx
  je     L13
  lea    -0x1(%rdx),%eax
  mov    %edx,%r8d
  cmp    $0x2,%eax
  jbe    L8
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L20:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm1
  movups %xmm1,(%rcx,%rax,1)
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L20
  mov    %edx,%edi
  and    $0xfffffffc,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L0
  sub    %edi,%edx
  mov    %edx,%r8d
  cmp    $0x1,%edx
  je     L62
L6:
  shl    $0x2,%rdi
  lea    (%rcx,%rdi,1),%rdx
  add    %rsi,%rdi
  mov    (%rdi),%r10
  mov    (%rdx),%r9
  mov    %r10,(%rdx)
  mov    %r8d,%edx
  and    $0xfffffffe,%edx
  mov    %r9,(%rdi)
  add    %edx,%eax
  cmp    %edx,%r8d
  je     L0
L62:
  cltq
  shl    $0x2,%rax
  add    %rax,%rcx
  add    %rsi,%rax
  mov    (%rcx),%edx
  mov    (%rax),%esi
  mov    %esi,(%rcx)
  mov    %edx,(%rax)
  ret
  nopl   0x0(%rax)
L13:
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L24:
  mov    (%rcx,%rax,4),%edi
  mov    (%rsi,%rax,4),%r8d
  mov    %r8d,(%rcx,%rax,4)
  mov    %edi,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L24
L0:
  ret
L8:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L6
```

assistant: ```c
void swap_int(int *arr1, int *arr2, int nb_elements) {
  int i, tmp;
  for (i = 0; i < nb_elements; i++) {
    tmp = arr1[i];
    arr1[i] = arr2[i];
    arr2[i] = tmp;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L18:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0xa,-0x8(%rbp)
  jle    L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int a;
  int b = 0;
  for (a = 0; a <= 0xa; a = a + 1) {
    b = b + 1;
  }
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0xb,%eax
  ret
```

assistant: ```c
int main(void) {
  int a;
  int b = 0;
  for (a = 0; a <= 0xa; a = a + 1) {
    b = b + 1;
  }
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    $0xb,%eax
  ret
```

assistant: ```c
int main(void) {
  int a;
  int b = 0;
  for (a = 0; a <= 0xa; a = a + 1) {
    b = b + 1;
  }
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<equivalenceTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L26:
  movl   $0x0,-0x4(%rbp)
  jmp    L57
L4:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L43
  mov    $0x0,%eax
  jmp    L5
L43:
  addl   $0x1,-0x4(%rbp)
L57:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L4
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L26
  mov    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int equivalenceTest(int **matrixA, int **matrixB, int n, int m) {
  for (int i = 0; i < n; i++)
    for (int j = 0; j < m; j++)
      if (matrixA[i][j] != matrixB[i][j])
        return 0;
  return 1;
}
```