user: 下面的汇编指令对应的C源代码是什么:

```asm
<sample1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  movl   $0xb,0x28(%rsp)
  movl   $0xc,0x2c(%rsp)
  lea    0x10(%rsp),%rbp
  lea    0x40(%rsp),%r13
  lea    D3(%rip),%r12
L5:
  lea    -0x10(%rbp),%rbx
L0:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x10,%rbp
  cmp    %r13,%rbp
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rbx
  lea    0x10(%rsp),%rdx
  mov    %rbx,%rsi
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  mov    %rbx,%rsi
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,0x30(%rsp)
  movl   $0x2,0x34(%rsp)
  movl   $0x3,0x38(%rsp)
  movl   $0x4,0x3c(%rsp)
  movl   $0x5,0x40(%rsp)
  movl   $0x6,0x44(%rsp)
  movl   $0x7,0x48(%rsp)
  movl   $0x8,0x4c(%rsp)
  movl   $0x9,0x50(%rsp)
  movl   $0xa,0x54(%rsp)
  movl   $0xb,0x58(%rsp)
  movl   $0xc,0x5c(%rsp)
  lea    0x30(%rsp),%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x44(%rsp),%rdx
  lea    0x40(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D73(%rip),%rdi
  mov    $0x0,%eax
  call   <system@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string
name: extract_symbolic_data
arguments: tag: D67
type: string
name: extract_symbolic_data
arguments: tag: D14
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string
name: extract_symbolic_data
arguments: tag: D53
type: string
name: extract_symbolic_data
arguments: tag: D57
type: string
name: extract_symbolic_data
arguments: tag: D73
type: string

tool: D3: %d 

tool: D67: a:%d, a+1:%d


tool: D14: %d, %d


tool: D2: a:%d


tool: D27: sizeof(a[0]):%d


tool: D53: a[1]:%d, a[1]+1:%d


tool: D57: *(a+1):%d


tool: D73: pause

assistant: ```c
int sample1(void) {
  int a1[3][4] = {{1, 2, 3, 4}, {5, 6, 7, 8}, {9, 10, 11, 12}};
  int a2[3][4] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12};
  int a3[][4] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12};
  int i = 0;
  int j = 0;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      printf("%d ", a3[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  printf("a:%d, a+1:%d\n", a3, a3 + 1);
  printf("%d, %d\n", *(a3 + 0), *(a3 + 0) + 1);
  printf("%d, %d\n", a3[0], a3[0] + 1);
  int a[][4] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12};
  printf("a:%d\n", a);
  printf("sizeof(a[0]):%d\n", sizeof(a[0]));
  printf("a[1]:%d, a[1]+1:%d\n", a[1], a[1] + 1);
  printf("*(a+1):%d\n", *(a + 1));
  printf("\n");
  system("pause");
  return 0;
}
```