ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<safety>:
  endbr64
  sub    $0x5,%edi
  xor    %eax,%eax
  cmp    $0xd,%di
  ja     L1
  movzwl %di,%edi
  lea    D1(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L1:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: 

assistant: ```c
int safety(short card) {
  switch (card) {
  case 5:
  case 10:
  case 15:
    return 15;
  case 6:
  case 11:
  case 16:
    return 16;
  case 7:
  case 12:
  case 17:
    return 17;
  case 13:
  case 8:
  case 18:
  case 9:
  case 14:
    return 18;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<safety>:
  endbr64
  sub    $0x5,%edi
  xor    %eax,%eax
  cmp    $0xd,%di
  ja     L3
  movzwl %di,%edi
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L3:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: 

assistant: ```c
int safety(short card) {
  switch (card) {
  case 5:
  case 10:
  case 15:
    return 15;
  case 6:
  case 11:
  case 16:
    return 16;
  case 7:
  case 12:
  case 17:
    return 17;
  case 13:
  case 8:
  case 18:
  case 9:
  case 14:
    return 18;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strlenm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L18:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlenm(char *s) {
  int i = 0;
  while (*s++ != '\0')
    i++;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlenm>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L23
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L1:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L1
L24:
  mov    %ecx,%eax
  ret
L23:
  mov    $0x0,%ecx
  jmp    L24
```

assistant: ```c
int strlenm(char *s) {
  int i = 0;
  while (*s++ != '\0')
    i++;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlenm>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L15
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L1:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L1
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlenm(char *s) {
  int i = 0;
  while (*s++ != '\0')
    i++;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlenm>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L13
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L0:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L0
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlenm(char *s) {
  int i = 0;
  while (*s++ != '\0')
    i++;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<X509_STORE_load_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <X509_LOOKUP_mem@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <X509_STORE_add_lookup@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L29
  mov    $0x0,%eax
  jmp    L35
L29:
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <X509_LOOKUP_add_mem@plt>
  cmp    $0x1,%eax
  je     L2
  mov    $0x0,%eax
  jmp    L35
L2:
  mov    $0x1,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int X509_STORE_load_mem(X509_STORE *ctx, void *buf, int len) {
  X509_LOOKUP *lookup;
  struct iovec iov;
  lookup = X509_STORE_add_lookup(ctx, X509_LOOKUP_mem());
  if (lookup == NULL)
    return (0);
  iov.iov_base = buf;
  iov.iov_len = len;
  if (X509_LOOKUP_add_mem(lookup, &iov, X509_FILETYPE_PEM) != 1)
    return (0);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<X509_STORE_load_mem>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <X509_LOOKUP_mem@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <X509_STORE_add_lookup@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L10
  mov    %r12,0x8(%rsp)
  mov    %ebp,(%rsp)
  mov    %rsp,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  call   <X509_LOOKUP_add_mem@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int X509_STORE_load_mem(X509_STORE *ctx, void *buf, int len) {
  X509_LOOKUP *lookup;
  struct iovec iov;
  lookup = X509_STORE_add_lookup(ctx, X509_LOOKUP_mem());
  if (lookup == NULL)
    return (0);
  iov.iov_base = buf;
  iov.iov_len = len;
  if (X509_LOOKUP_add_mem(lookup, &iov, X509_FILETYPE_PEM) != 1)
    return (0);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<X509_STORE_load_mem>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <X509_LOOKUP_mem@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <X509_STORE_add_lookup@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L17
  mov    D3(%rip),%rax
  mov    %rsp,%rsi
  mov    %r12,0x8(%rsp)
  mov    %ebx,(%rsp)
  mov    (%rax),%edx
  call   <X509_LOOKUP_add_mem@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L17:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int X509_STORE_load_mem(X509_STORE *ctx, void *buf, int len) {
  X509_LOOKUP *lookup;
  struct iovec iov;
  lookup = X509_STORE_add_lookup(ctx, X509_LOOKUP_mem());
  if (lookup == NULL)
    return (0);
  iov.iov_base = buf;
  iov.iov_len = len;
  if (X509_LOOKUP_add_mem(lookup, &iov, X509_FILETYPE_PEM) != 1)
    return (0);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<X509_STORE_load_mem>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <X509_LOOKUP_mem@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <X509_STORE_add_lookup@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  mov    D3(%rip),%rax
  mov    %rsp,%rsi
  mov    %r12,0x8(%rsp)
  mov    %ebx,(%rsp)
  mov    (%rax),%edx
  call   <X509_LOOKUP_add_mem@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int X509_STORE_load_mem(X509_STORE *ctx, void *buf, int len) {
  X509_LOOKUP *lookup;
  struct iovec iov;
  lookup = X509_STORE_add_lookup(ctx, X509_LOOKUP_mem());
  if (lookup == NULL)
    return (0);
  iov.iov_base = buf;
  iov.iov_len = len;
  if (X509_LOOKUP_add_mem(lookup, &iov, X509_FILETYPE_PEM) != 1)
    return (0);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jbe    L36
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,%edi
  call   <print_bin>
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edi
  call   <print_bin>
  jmp    L25
L36:
  cmpl   $0x0,-0x4(%rbp)
  je     L15
  mov    $0x31,%eax
  jmp    L1
L15:
  mov    $0x30,%eax
L1:
  mov    %eax,%edi
  call   <print_char@plt>
L25:
  nop
  leave
  ret
```

assistant: ```c
void print_bin(unsigned int i) {
  if (i > 1) {
    print_bin(i / 2);
    print_bin(i % 2);
  } else {
    print_char(i ? '1' : '0');
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_bin>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  ja     L19
  mov    $0x30,%edi
  sbb    $0xffffffff,%edi
  call   <print_char@plt>
L14:
  pop    %rbx
  ret
L19:
  mov    %edi,%ebx
  shr    %edi
  call   <print_bin>
  and    $0x1,%ebx
  mov    %ebx,%edi
  call   <print_bin>
  jmp    L14
```

assistant: ```c
void print_bin(unsigned int i) {
  if (i > 1) {
    print_bin(i / 2);
    print_bin(i % 2);
  } else {
    print_char(i ? '1' : '0');
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_bin>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jbe    L43
  mov    %edi,%eax
  mov    $0x31,%edi
  shr    %eax
  mov    %eax,0x8(%rsp)
  cmp    $0x1,%eax
  je     L38
  mov    %ebx,%eax
  shr    $0x2,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%eax
  je     L46
  mov    %ebx,%r15d
  shr    $0x3,%r15d
  cmp    $0x1,%r15d
  je     L73
  mov    %ebx,%ebp
  shr    $0x4,%ebp
  cmp    $0x1,%ebp
  je     L25
  mov    %ebx,%r12d
  shr    $0x5,%r12d
  cmp    $0x1,%r12d
  je     L55
  mov    %ebx,%r14d
  shr    $0x6,%r14d
  cmp    $0x1,%r14d
  je     L15
  mov    %ebx,%r13d
  shr    $0x7,%r13d
  cmp    $0x1,%r13d
  je     L47
  mov    %ebx,%eax
  shr    $0x8,%eax
  cmp    $0x1,%eax
  mov    %eax,0x4(%rsp)
  je     L76
  mov    %ebx,%edi
  shr    $0x9,%edi
  call   <print_bin>
  mov    0x4(%rsp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
L76:
  call   <print_char@plt>
  and    $0x1,%r13d
  lea    0x30(%r13),%edi
L47:
  call   <print_char@plt>
  and    $0x1,%r14d
  lea    0x30(%r14),%edi
L15:
  call   <print_char@plt>
  and    $0x1,%r12d
  lea    0x30(%r12),%edi
L55:
  call   <print_char@plt>
  and    $0x1,%ebp
  lea    0x30(%rbp),%edi
L25:
  call   <print_char@plt>
  and    $0x1,%r15d
  lea    0x30(%r15),%edi
L73:
  call   <print_char@plt>
  mov    0xc(%rsp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
L46:
  call   <print_char@plt>
  mov    0x8(%rsp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
L38:
  call   <print_char@plt>
  and    $0x1,%ebx
L43:
  add    $0x18,%rsp
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <print_char@plt>
```

assistant: ```c
void print_bin(unsigned int i) {
  if (i > 1) {
    print_bin(i / 2);
    print_bin(i % 2);
  } else {
    print_char(i ? '1' : '0');
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_bin>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jbe    L25
  mov    %edi,%eax
  mov    $0x31,%edi
  shr    %eax
  mov    %eax,0x8(%rsp)
  cmp    $0x1,%eax
  je     L13
  mov    %ebx,%eax
  shr    $0x2,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%eax
  je     L36
  mov    %ebx,%r15d
  shr    $0x3,%r15d
  cmp    $0x1,%r15d
  je     L23
  mov    %ebx,%ebp
  shr    $0x4,%ebp
  cmp    $0x1,%ebp
  je     L38
  mov    %ebx,%r12d
  shr    $0x5,%r12d
  cmp    $0x1,%r12d
  je     L12
  mov    %ebx,%r14d
  shr    $0x6,%r14d
  cmp    $0x1,%r14d
  je     L33
  mov    %ebx,%r13d
  shr    $0x7,%r13d
  cmp    $0x1,%r13d
  je     L83
  mov    %ebx,%eax
  shr    $0x8,%eax
  cmp    $0x1,%eax
  mov    %eax,0x4(%rsp)
  je     L20
  mov    %ebx,%edi
  shr    $0x9,%edi
  call   <print_bin>
  mov    0x4(%rsp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
L20:
  call   <print_char@plt>
  and    $0x1,%r13d
  lea    0x30(%r13),%edi
L83:
  call   <print_char@plt>
  and    $0x1,%r14d
  lea    0x30(%r14),%edi
L33:
  call   <print_char@plt>
  and    $0x1,%r12d
  lea    0x30(%r12),%edi
L12:
  call   <print_char@plt>
  and    $0x1,%ebp
  lea    0x30(%rbp),%edi
L38:
  call   <print_char@plt>
  and    $0x1,%r15d
  lea    0x30(%r15),%edi
L23:
  call   <print_char@plt>
  mov    0xc(%rsp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
L36:
  call   <print_char@plt>
  mov    0x8(%rsp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%edi
L13:
  call   <print_char@plt>
  and    $0x1,%ebx
L25:
  add    $0x18,%rsp
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <print_char@plt>
```

assistant: ```c
void print_bin(unsigned int i) {
  if (i > 1) {
    print_bin(i / 2);
    print_bin(i % 2);
  } else {
    print_char(i ? '1' : '0');
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L26
  jmp    L15
L30:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_cat@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_puterr@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L30
  mov    $0x0,%eax
  jmp    L8
L26:
  mov    $0x1,%eax
L8:
  leave
  ret
```

assistant: ```c
int main(int ac, char **av) {
  int i;
  i = 1;
  if (ac >= 2) {
    while (i < ac) {
      ft_puterr(av[i], ft_cat(av[i]));
      i++;
    }
    return (0);
  } else
    return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L6
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L7:
  mov    (%rbx),%rdi
  call   <ft_cat@plt>
  mov    %eax,%esi
  mov    (%rbx),%rdi
  call   <ft_puterr@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L7
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  ret
```

assistant: ```c
int main(int ac, char **av) {
  int i;
  i = 1;
  if (ac >= 2) {
    while (i < ac) {
      ft_puterr(av[i], ft_cat(av[i]));
      i++;
    }
    return (0);
  } else
    return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L16
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  push   %rcx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <ft_cat@plt>
  mov    -0x8(%rbx),%rdi
  mov    %eax,%esi
  call   <ft_puterr@plt>
  cmp    %rbp,%rbx
  jne    L18
  pop    %rdx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main(int ac, char **av) {
  int i;
  i = 1;
  if (ac >= 2) {
    while (i < ac) {
      ft_puterr(av[i], ft_cat(av[i]));
      i++;
    }
    return (0);
  } else
    return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L6
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  push   %rcx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <ft_cat@plt>
  mov    -0x8(%rbx),%rdi
  mov    %eax,%esi
  call   <ft_puterr@plt>
  cmp    %rbp,%rbx
  jne    L18
  pop    %rdx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main(int ac, char **av) {
  int i;
  i = 1;
  if (ac >= 2) {
    while (i < ac) {
      ft_puterr(av[i], ft_cat(av[i]));
      i++;
    }
    return (0);
  } else
    return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printDiskRW>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%r8
  mov    $0x1,%ecx
  lea    D11(%rip),%rax
  mov    %rax,%rdx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <getLineFromFile@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L50
L20:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L12
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L12:
  cmpl   $0x9,-0x14(%rbp)
  jne    L22
  cmpl   $0x0,-0x1c(%rbp)
  jne    L49
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x1c(%rbp)
L49:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L22:
  cmpl   $0xd,-0x14(%rbp)
  jne    L61
  cmpl   $0x1,-0x1c(%rbp)
  jne    L70
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x2,-0x1c(%rbp)
L70:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L61:
  addl   $0x1,-0x18(%rbp)
L50:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D11
type: string
name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D40
type: string
name: read_data
arguments: tag: D29
type: string

tool: D15: 

-- Number of disk read and writes:
		

tool: D11:  

tool: D1: rb

tool: D22: /proc/diskstats

tool: D40: Disk Reads:  

tool: D29: 
		Disk Writes: 

assistant: ```c
int printDiskRW() {
  printf("\n\n-- Number of disk read and writes:\n\t\t");
  int lineLength = 0;
  char *lineFromFile = getLineFromFile("/proc/diskstats", "rb", " ", 1, &lineLength);
  int flag = 0;
  int k = 0;
  int wordNumber = 1;
  while (k < lineLength) {
    if (lineFromFile[k] == ' ') {
      wordNumber++;
      k++;
    }
    if (wordNumber == 9) {
      if (flag == 0) {
        printf("Disk Reads:  ");
        flag = 1;
      }
      printf("%c", lineFromFile[k]);
    }
    if (wordNumber == 13) {
      if (flag == 1) {
        printf("\n\t\tDisk Writes: ");
        flag = 2;
      }
      printf("%c", lineFromFile[k]);
    }
    k++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printDiskRW>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <printf@plt>
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%r8
  mov    $0x1,%ecx
  lea    D57(%rip),%rdx
  lea    D50(%rip),%rsi
  lea    D30(%rip),%rdi
  call   <getLineFromFile@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L36
  mov    %rax,%r12
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  lea    D8(%rip),%r15
  lea    D13(%rip),%r14
  jmp    L117
L114:
  add    $0x1,%ebp
  add    $0x1,%ebx
  jmp    L70
L54:
  test   %r13d,%r13d
  je     L20
L62:
  movslq %ebx,%rax
  movsbl (%r12,%rax,1),%edi
  call   <putchar@plt>
L120:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jle    L36
L117:
  movslq %ebx,%rax
  cmpb   $0x20,(%r12,%rax,1)
  je     L114
L70:
  cmp    $0x9,%ebp
  je     L54
  cmp    $0xd,%ebp
  jne    L120
  cmp    $0x1,%r13d
  je     L83
L38:
  movslq %ebx,%rax
  movsbl (%r12,%rax,1),%edi
  call   <putchar@plt>
  jmp    L120
L20:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%r13d
  jmp    L62
L83:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%r13d
  jmp    L38
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D52
datatype: string
name: retrieve_data
arguments: tag: D57
datatype: string
name: retrieve_data
arguments: tag: D50
datatype: string
name: retrieve_data
arguments: tag: D30
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: string

tool: D52: 

-- Number of disk read and writes:
		

tool: D57:  

tool: D50: rb

tool: D30: /proc/diskstats

tool: D8: 
		Disk Writes: 

tool: D13: Disk Reads:  

assistant: ```c
int printDiskRW() {
  printf("\n\n-- Number of disk read and writes:\n\t\t");
  int lineLength = 0;
  char *lineFromFile = getLineFromFile("/proc/diskstats", "rb", " ", 1, &lineLength);
  int flag = 0;
  int k = 0;
  int wordNumber = 1;
  while (k < lineLength) {
    if (lineFromFile[k] == ' ') {
      wordNumber++;
      k++;
    }
    if (wordNumber == 9) {
      if (flag == 0) {
        printf("Disk Reads:  ");
        flag = 1;
      }
      printf("%c", lineFromFile[k]);
    }
    if (wordNumber == 13) {
      if (flag == 1) {
        printf("\n\t\tDisk Writes: ");
        flag = 2;
      }
      printf("%c", lineFromFile[k]);
    }
    k++;
  }
  return 0;
}
```