ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stbi_is_hdr>:
  endbr64
  push   %r12
  lea    D9(%rip),%rsi
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <stbi_is_hdr_from_file@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fclose@plt>
L6:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: rb

assistant: ```c
extern int stbi_is_hdr(char *filename) {
  FILE *f = fopen(filename, "rb");
  int result = 0;
  if (f) {
    result = stbi_is_hdr_from_file(f);
    fclose(f);
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *test(void *ptr) {
  void *newPtr = realloc(ptr, 4);
  if (newPtr == 0) {
    if (ptr)
      free(ptr);
  }
  return newPtr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x4,%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rbx,%rbx
  je     L29
  test   %rax,%rax
  je     L8
L29:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L29
```

assistant: ```c
void *test(void *ptr) {
  void *newPtr = realloc(ptr, 4);
  if (newPtr == 0) {
    if (ptr)
      free(ptr);
  }
  return newPtr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L0
  test   %rax,%rax
  je     L11
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *test(void *ptr) {
  void *newPtr = realloc(ptr, 4);
  if (newPtr == 0) {
    if (ptr)
      free(ptr);
  }
  return newPtr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L0
  test   %rax,%rax
  je     L9
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *test(void *ptr) {
  void *newPtr = realloc(ptr, 4);
  if (newPtr == 0) {
    if (ptr)
      free(ptr);
  }
  return newPtr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L15:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D16(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <expintegral@plt>
  movq   %xmm0,%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D16(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rdx,%xmm1
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x5,-0x4(%rbp)
  jle    L15
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: f64
name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D16: 0.5

tool: D4: 
expintegral(%3.1f)=%5.2f

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\nexpintegral(%3.1f)=%5.2f", 0.5 * n, expintegral(0.5 * n));
  }
  getch();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D13(%rip),%rbp
L6:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D16(%rip),%xmm0
  movq   %xmm0,%r14
  call   <expintegral@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L6
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D16
type_guessed: f64

tool: D13: 
expintegral(%3.1f)=%5.2f

tool: D16: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\nexpintegral(%3.1f)=%5.2f", 0.5 * n, expintegral(0.5 * n));
  }
  getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
L7:
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm2
  mulsd  D17(%rip),%xmm2
  add    $0x1,%ebx
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <expintegral@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %rbp,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L7
  xor    %eax,%eax
  call   <getch@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: f64

tool: D1: 
expintegral(%3.1f)=%5.2f

tool: D17: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\nexpintegral(%3.1f)=%5.2f", 0.5 * n, expintegral(0.5 * n));
  }
  getch();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
L8:
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm2
  mulsd  D2(%rip),%xmm2
  add    $0x1,%ebx
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <expintegral@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %rbp,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L8
  xor    %eax,%eax
  call   <getch@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D2
type: f64

tool: D3: 
expintegral(%3.1f)=%5.2f

tool: D2: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\nexpintegral(%3.1f)=%5.2f", 0.5 * n, expintegral(0.5 * n));
  }
  getch();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<multiplyMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L32
L71:
  movl   $0x1,-0x8(%rbp)
  jmp    L0
L43:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L43
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L71
  movl   $0x1,-0xc(%rbp)
  jmp    L21
L38:
  movl   $0x1,-0x8(%rbp)
  jmp    L88
L34:
  movl   $0x1,-0x4(%rbp)
  jmp    L28
L8:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm1
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L8
  addl   $0x1,-0x8(%rbp)
L88:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L34
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L38
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void multiplyMatrix(double a[][100], double b[][100], double result[][100], int m, int n, int p) {
  int i, j, k;
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= p; j++)
      result[i][j] = 0.0;
  }
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= p; j++) {
      for (k = 1; k <= n; k++)
        result[i][j] += a[i][k] * b[k][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiplyMatrix>:
  endbr64
  test   %ecx,%ecx
  jle    L100
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    %r8d,%r11d
  mov    %r9d,%ebx
  lea    -0x1(%r9),%eax
  lea    0x330(%rdx,%rax,8),%r8
  lea    -0x1(%rcx),%ebp
  lea    0x0(%rbp,%rbp,4),%rcx
  lea    (%rcx,%rcx,4),%rcx
  lea    (%rax,%rcx,4),%rcx
  lea    0x650(%rdx,%rcx,8),%rsi
  neg    %rax
  mov    %rax,%r12
  shl    $0x3,%r12
  mov    %r8,%rdx
  lea    -0x8(%r12),%rcx
  jmp    L17
L100:
  ret
L85:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L85
L117:
  add    $0x320,%rdx
  cmp    %rsi,%rdx
  je     L92
L17:
  lea    (%rcx,%rdx,1),%rax
  test   %ebx,%ebx
  jg     L85
  jmp    L117
L92:
  lea    0x328(%rdi),%r9
  lea    -0x1(%r11),%eax
  lea    0x330(%rdi,%rax,8),%rsi
  lea    0x0(%rbp,%rbp,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x5,%rax
  lea    0x648(%rdi,%rax,1),%rbp
  sub    $0x8,%r12
  jmp    L125
L44:
  movsd  (%rax),%xmm0
  mulsd  0x320(%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  add    $0x320,%rdx
  cmp    %rsi,%rax
  jne    L44
L60:
  add    $0x8,%rdi
  add    $0x8,%rcx
  cmp    %r8,%rcx
  je     L74
L8:
  mov    %rdi,%rdx
  mov    %r9,%rax
  test   %r11d,%r11d
  jg     L44
  jmp    L60
L74:
  add    $0x320,%r8
  add    $0x320,%r9
  add    $0x320,%rsi
  cmp    %rbp,%r9
  je     L31
L125:
  test   %ebx,%ebx
  jle    L74
  lea    0x8(%r10),%rdi
  lea    (%r12,%r8,1),%rcx
  jmp    L8
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void multiplyMatrix(double a[][100], double b[][100], double result[][100], int m, int n, int p) {
  int i, j, k;
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= p; j++)
      result[i][j] = 0.0;
  }
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= p; j++) {
      for (k = 1; k <= n; k++)
        result[i][j] += a[i][k] * b[k][j];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<multiplyMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rdx,0x8(%rsp)
  test   %ecx,%ecx
  jle    L67
  mov    %ecx,%eax
  mov    0x8(%rsp),%rdi
  mov    %rsi,%rbx
  mov    %r8d,%r14d
  sub    $0x1,%eax
  mov    %r9d,%r13d
  lea    (%rax,%rax,4),%rax
  lea    0x328(%rdi),%rcx
  lea    (%rax,%rax,4),%r15
  lea    -0x1(%r9),%eax
  mov    %rax,0x10(%rsp)
  shl    $0x5,%r15
  lea    0x8(,%rax,8),%r12
  lea    0x648(%rdi,%r15,1),%rbp
  nopl   0x0(%rax,%rax,1)
L68:
  test   %r13d,%r13d
  jle    L72
  mov    %rcx,%rdi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
L72:
  add    $0x320,%rcx
  cmp    %rbp,%rcx
  jne    L68
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rdi
  lea    -0x1(%r14),%edx
  mov    $0xfffffffffffffff8,%rbp
  shl    $0x3,%rax
  lea    0x330(%rdi,%rax,1),%r10
  mov    0x18(%rsp),%rdi
  sub    %rax,%rbp
  lea    0x328(%rdi),%r11
  lea    0x330(%rdi,%rdx,8),%rsi
  lea    0x648(%rdi,%r15,1),%r12
  nopl   0x0(%rax)
L32:
  test   %r13d,%r13d
  jle    L47
  lea    0x8(%rbx),%rdi
  lea    0x0(%rbp,%r10,1),%rcx
  xchg   %ax,%ax
L0:
  test   %r14d,%r14d
  jle    L1
  movsd  (%rcx),%xmm1
  mov    %rdi,%rdx
  mov    %r11,%rax
  nop
L76:
  movsd  (%rax),%xmm0
  mulsd  0x320(%rdx),%xmm0
  add    $0x8,%rax
  add    $0x320,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rsi,%rax
  jne    L76
L1:
  add    $0x8,%rcx
  add    $0x8,%rdi
  cmp    %r10,%rcx
  jne    L0
L47:
  add    $0x320,%r11
  add    $0x320,%r10
  add    $0x320,%rsi
  cmp    %r12,%r11
  jne    L32
L67:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void multiplyMatrix(double a[][100], double b[][100], double result[][100], int m, int n, int p) {
  int i, j, k;
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= p; j++)
      result[i][j] = 0.0;
  }
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= p; j++) {
      for (k = 1; k <= n; k++)
        result[i][j] += a[i][k] * b[k][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiplyMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  test   %ecx,%ecx
  jle    L55
  mov    %r9d,%r14d
  test   %r9d,%r9d
  jle    L55
  mov    %ecx,%eax
  movslq %r9d,%rbx
  mov    %rdi,%r12
  mov    %rdx,%r13
  sub    $0x1,%eax
  mov    %r8d,%r15d
  lea    0x328(%rdx),%rcx
  shl    $0x3,%rbx
  mov    %eax,0xc(%rsp)
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x5,%rax
  lea    0x648(%rdx,%rax,1),%rbp
  xchg   %ax,%ax
L50:
  mov    %rcx,%rdi
  mov    %rbx,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
  add    $0x320,%rcx
  cmp    %rbp,%rcx
  jne    L50
  test   %r15d,%r15d
  jle    L55
  lea    -0x1(%r15),%edx
  mov    (%rsp),%rdi
  lea    -0x1(%r14),%eax
  mov    $0xfffffffffffffff8,%r10
  lea    0x330(%r12,%rdx,8),%rsi
  mov    0xc(%rsp),%edx
  shl    $0x3,%rax
  lea    0x328(%r12),%r8
  lea    0x330(%r13,%rax,1),%r9
  lea    0x8(%rdi),%r11
  sub    %rax,%r10
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x5,%rdx
  lea    0x648(%r12,%rdx,1),%rbx
  nopl   0x0(%rax,%rax,1)
L52:
  lea    (%r10,%r9,1),%rcx
  mov    %r11,%rdi
  nop
L7:
  movsd  (%rcx),%xmm1
  mov    %rdi,%rdx
  mov    %r8,%rax
  nopw   0x0(%rax,%rax,1)
L63:
  movsd  (%rax),%xmm0
  mulsd  0x320(%rdx),%xmm0
  add    $0x8,%rax
  add    $0x320,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rsi,%rax
  jne    L63
  add    $0x8,%rcx
  add    $0x8,%rdi
  cmp    %r9,%rcx
  jne    L7
  add    $0x320,%r8
  add    $0x320,%r9
  add    $0x320,%rsi
  cmp    %rbx,%r8
  jne    L52
L55:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void multiplyMatrix(double a[][100], double b[][100], double result[][100], int m, int n, int p) {
  int i, j, k;
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= p; j++)
      result[i][j] = 0.0;
  }
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= p; j++) {
      for (k = 1; k <= n; k++)
        result[i][j] += a[i][k] * b[k][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x11,-0x8(%rbp)
  movl   $0xffffffe8,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: %d*%d = %d


assistant: ```c
int main(void) {
  int a = 17;
  int b = -24;
  printf("%d*%d = %d\n", a, b, a * b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xfffffe68,%ecx
  mov    $0xffffffe8,%edx
  mov    $0x11,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string

tool: D4: %d*%d = %d


assistant: ```c
int main(void) {
  int a = 17;
  int b = -24;
  printf("%d*%d = %d\n", a, b, a * b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xfffffe68,%ecx
  mov    $0xffffffe8,%edx
  mov    $0x11,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type: string

tool: D6: %d*%d = %d


assistant: ```c
int main(void) {
  int a = 17;
  int b = -24;
  printf("%d*%d = %d\n", a, b, a * b);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xfffffe68,%ecx
  mov    $0xffffffe8,%edx
  mov    $0x11,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d*%d = %d


assistant: ```c
int main(void) {
  int a = 17;
  int b = -24;
  printf("%d*%d = %d\n", a, b, a * b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x74(%rbp)
  jle    L5
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  lea    -0x70(%rbp),%rax
  mov    $0x64,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0xd(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L39
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <doHash@plt>
  mov    %eax,%edx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L39
L5:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L39:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string
name: read_data
arguments: data_label: D5
type: string

tool: D8: Passcode for %s is %d


tool: D5: Usage:callpass <callsign>

assistant: ```c
int main(int argc, char *argv[]) {
  char temp[100];
  if (argc > 1) {
    strncpy(temp, argv[1], 100);
    temp[99] = '\0';
    if (strlen(temp) > 0)
      printf("Passcode for %s is %d\n", temp, doHash(temp));
  } else
    printf("Usage:callpass <callsign>\n");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L11
  mov    0x8(%rsi),%rsi
  mov    %rsp,%rbx
  mov    $0x64,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x63(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L36
  mov    %rbx,%rdi
  call   <doHash@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L11:
  lea    D3(%rip),%rdi
  call   <puts@plt>
L36:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D6: Passcode for %s is %d


tool: D3: Usage:callpass <callsign>

assistant: ```c
int main(int argc, char *argv[]) {
  char temp[100];
  if (argc > 1) {
    strncpy(temp, argv[1], 100);
    temp[99] = '\0';
    if (strlen(temp) > 0)
      printf("Passcode for %s is %d\n", temp, doHash(temp));
  } else
    printf("Usage:callpass <callsign>\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L29
  mov    %rsp,%rbp
  mov    0x8(%rsi),%rsi
  mov    $0x64,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  movb   $0x0,0x63(%rsp)
  call   <strlen@plt>
  test   %rax,%rax
  jne    L31
L40:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L29:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L40
L31:
  mov    %rbp,%rdi
  call   <doHash@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L40
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D15: Usage:callpass <callsign>

tool: D2: Passcode for %s is %d


assistant: ```c
int main(int argc, char *argv[]) {
  char temp[100];
  if (argc > 1) {
    strncpy(temp, argv[1], 100);
    temp[99] = '\0';
    if (strlen(temp) > 0)
      printf("Passcode for %s is %d\n", temp, doHash(temp));
  } else
    printf("Usage:callpass <callsign>\n");
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L45
  mov    %rsp,%rbp
  mov    0x8(%rsi),%rsi
  mov    $0x64,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  movb   $0x0,0x63(%rsp)
  call   <strlen@plt>
  test   %rax,%rax
  jne    L24
L17:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L45:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L17
L24:
  mov    %rbp,%rdi
  call   <doHash@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L17
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D7: Usage:callpass <callsign>

tool: D3: Passcode for %s is %d


assistant: ```c
int main(int argc, char *argv[]) {
  char temp[100];
  if (argc > 1) {
    strncpy(temp, argv[1], 100);
    temp[99] = '\0';
    if (strlen(temp) > 0)
      printf("Passcode for %s is %d\n", temp, doHash(temp));
  } else
    printf("Usage:callpass <callsign>\n");
  return (0);
}
```