ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<test_all_pvals>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  movslq %edx,%rbp
  mov    %r12,%rdi
  push   %rbx
  mov    %ebp,%edx
  sub    $0x8,%rsp
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L14
  xor    %ebx,%ebx
  lea    D9(%rip),%r15
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%edi
  mov    %r14d,%edx
  mov    %r13d,%esi
  call   <test_pval@plt>
  mov    %r15,%rdi
  mov    %eax,(%r12,%rbx,4)
  mov    %eax,%esi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L15
L14:
  add    $0x8,%rsp
  lea    D6(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D9: %d	

tool: 

assistant: ```c
void test_all_pvals(int *pvals, int *collisions, int num, int num_runs, int len) {
  int i;
  memset(collisions, 0, num);
  for (i = 0; i < num; i++) {
    collisions[i] = test_pval(i, num_runs, len);
    printf("%d\t", collisions[i]);
  }
  puts("");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %edi,-0x1c4(%rbp)
  mov    %rsi,-0x1d0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1b8(%rbp)
  movl   $0x0,-0x1b4(%rbp)
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1bc(%rbp)
  jmp    L47
L44:
  mov    -0x1bc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x1b0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1bc(%rbp),%eax
  cltq
  mov    -0x1b0(%rbp,%rax,4),%eax
  add    %eax,-0x1b8(%rbp)
  addl   $0x1,-0x1bc(%rbp)
L47:
  mov    -0x1c0(%rbp),%eax
  cmp    %eax,-0x1bc(%rbp)
  jl     L44
  mov    -0x1c0(%rbp),%ecx
  mov    -0x1b8(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x1b8(%rbp)
  movl   $0x0,-0x1bc(%rbp)
  jmp    L50
L1:
  mov    -0x1bc(%rbp),%eax
  cltq
  mov    -0x1b0(%rbp,%rax,4),%eax
  cmp    %eax,-0x1b8(%rbp)
  je     L22
  mov    -0x1bc(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x1b0(%rbp,%rax,4),%ecx
  mov    -0x1bc(%rbp),%eax
  cltq
  mov    -0x1b0(%rbp,%rax,4),%eax
  sub    -0x1b8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1bc(%rbp),%eax
  add    $0x1,%eax
  add    %ecx,%edx
  cltq
  mov    %edx,-0x1b0(%rbp,%rax,4)
  mov    -0x1bc(%rbp),%eax
  cltq
  mov    -0x1b8(%rbp),%edx
  mov    %edx,-0x1b0(%rbp,%rax,4)
  addl   $0x1,-0x1b4(%rbp)
  jmp    L43
L22:
  nop
L43:
  addl   $0x1,-0x1bc(%rbp)
L50:
  mov    -0x1c0(%rbp),%eax
  cmp    %eax,-0x1bc(%rbp)
  jl     L1
  mov    -0x1b4(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D25
type: string

tool: D18: %d

tool: D25: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, a[105], i, average = 0, ans = 0;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", a + i);
    average += a[i];
  }
  average /= n;
  for (i = 0; i < n; i++) {
    if (a[i] == average)
      continue;
    a[i + 1] += a[i] - average;
    a[i] = average;
    ans++;
  }
  printf("%d\n", ans);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L86
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  lea    D5(%rip),%r13
L31:
  lea    0x10(%rsp),%rbx
  lea    (%rbx,%rbp,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    (%rbx,%rbp,4),%r12d
  mov    0xc(%rsp),%ecx
  add    $0x1,%rbp
  cmp    %ebp,%ecx
  jg     L31
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %ecx,%ecx
  jle    L76
  lea    -0x1(%rcx),%edx
  lea    0x4(%rbx,%rdx,4),%rcx
  mov    $0x0,%esi
  jmp    L27
L45:
  add    $0x4,%rbx
  cmp    %rcx,%rbx
  je     L46
L27:
  mov    (%rbx),%edx
  cmp    %eax,%edx
  je     L45
  sub    %eax,%edx
  add    %edx,0x4(%rbx)
  mov    %eax,(%rbx)
  add    $0x1,%esi
  jmp    L45
L86:
  mov    $0x0,%esi
L46:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L76:
  mov    $0x0,%esi
  jmp    L46
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D5: %d

tool: D15: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, a[105], i, average = 0, ans = 0;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", a + i);
    average += a[i];
  }
  average /= n;
  for (i = 0; i < n; i++) {
    if (a[i] == average)
      continue;
    a[i + 1] += a[i] - average;
    a[i] = average;
    ans++;
  }
  printf("%d\n", ans);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L6
L34:
  lea    0x0(%r13,%rbp,4),%rsi
  mov    %r14,%rdi
  mov    %r13,%rbx
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  add    0x0(%r13,%rbp,4),%r12d
  add    $0x1,%rbp
  cmp    %ebp,%ecx
  jg     L34
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %ecx,%ecx
  jle    L6
  lea    -0x1(%rcx),%edx
  xor    %esi,%esi
  lea    0x14(%rsp,%rdx,4),%rcx
  nopl   (%rax)
L36:
  mov    (%rbx),%edx
  cmp    %eax,%edx
  je     L1
  sub    %eax,%edx
  add    %edx,0x4(%rbx)
  add    $0x1,%esi
  mov    %eax,(%rbx)
L1:
  add    $0x4,%rbx
  cmp    %rbx,%rcx
  jne    L36
L57:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x1c0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  xor    %esi,%esi
  jmp    L57
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D10: %d

tool: D5: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, a[105], i, average = 0, ans = 0;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", a + i);
    average += a[i];
  }
  average /= n;
  for (i = 0; i < n; i++) {
    if (a[i] == average)
      continue;
    a[i + 1] += a[i] - average;
    a[i] = average;
    ans++;
  }
  printf("%d\n", ans);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L50
L54:
  lea    0x0(%r13,%rbp,4),%rsi
  mov    %r14,%rdi
  mov    %r13,%rbx
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  add    0x0(%r13,%rbp,4),%r12d
  add    $0x1,%rbp
  cmp    %ebp,%ecx
  jg     L54
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %ecx,%ecx
  jle    L50
  lea    -0x1(%rcx),%edx
  xor    %esi,%esi
  lea    0x14(%rsp,%rdx,4),%rcx
  nopl   (%rax)
L58:
  mov    (%rbx),%edx
  cmp    %eax,%edx
  je     L11
  sub    %eax,%edx
  add    0x4(%rbx),%edx
  movd   %eax,%xmm0
  add    $0x1,%esi
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rbx)
L11:
  add    $0x4,%rbx
  cmp    %rcx,%rbx
  jne    L58
L30:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x1c0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L50:
  xor    %esi,%esi
  jmp    L30
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string

tool: D3: %d

tool: D18: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, a[105], i, average = 0, ans = 0;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", a + i);
    average += a[i];
  }
  average /= n;
  for (i = 0; i < n; i++) {
    if (a[i] == average)
      continue;
    a[i + 1] += a[i] - average;
    a[i] = average;
    ans++;
  }
  printf("%d\n", ans);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1e,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string
name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D5: 30: %ld


tool: D6: 5: %ld


assistant: ```c
long main() {
  printf("30: %ld\n", 10 + 20);
  printf("5: %ld\n", 1 + 2 + 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string

tool: D3: 30: %ld


tool: D18: 5: %ld


assistant: ```c
long main() {
  printf("30: %ld\n", 10 + 20);
  printf("5: %ld\n", 1 + 2 + 2);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string

tool: D5: 30: %ld


tool: D16: 5: %ld


assistant: ```c
long main() {
  printf("30: %ld\n", 10 + 20);
  printf("5: %ld\n", 1 + 2 + 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: D8: 30: %ld


tool: D16: 5: %ld


assistant: ```c
long main() {
  printf("30: %ld\n", 10 + 20);
  printf("5: %ld\n", 1 + 2 + 2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<testRandMN>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x3,(%rsp)
  movl   $0x5a,0x4(%rsp)
  movl   $0xc8,0x8(%rsp)
  movl   $0x131,0xc(%rsp)
  movl   $0x1e7,0x10(%rsp)
  movl   $0x1f7,0x14(%rsp)
  movl   $0x1f4,0x18(%rsp)
  movl   $0x1f5,0x1c(%rsp)
  movl   $0x1f6,0x20(%rsp)
  movl   $0x1f8,0x24(%rsp)
  mov    $0xa,%ecx
  mov    $0x21c,%edx
  mov    $0x1ea,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%ebx
  mov    %rsp,%rcx
  mov    $0xa,%r8d
  mov    $0xa,%edx
  mov    $0x21c,%esi
  mov    $0x1ea,%edi
  call   <RandNumberMN@plt>
  mov    %rax,%r13
  mov    $0x0,%edi
  call   <time@plt>
  sub    %ebx,%eax
  mov    %eax,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r13,%r13
  je     L35
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %r13,%rbx
  lea    0x28(%r13),%r12
  lea    D17(%rip),%rbp
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  call   <free@plt>
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  jmp    L13
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
type_infered: string
name: parse_data
arguments: data_label: D30
type_infered: string
name: parse_data
arguments: data_label: D12
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D33
type_infered: string

tool: D22: m = %d, n = %d, k = %d


tool: D30: time = %d



tool: D12: RandNumber success!

tool: D17: %d, 

tool: D33: RandNumber failed!


assistant: ```c
void testRandMN(void) {
  time_t start, end;
  int *result = NULL;
  int m = 490, n = 540, k = 10;
  int inum[] = {3, 90, 200, 305, 487, 503, 500, 501, 502, 504};
  printf("m = %d, n = %d, k = %d\n", m, n, k);
  start = time(NULL);
  result = RandNumberMN(m, n, k, inum, sizeof(inum) / sizeof(inum[0]));
  end = time(NULL);
  printf("time = %d\n\n", end - start);
  if (result) {
    printf("RandNumber success!\n");
    if (k < 200) {
      int i;
      for (i = 0; i < k; i++) {
        printf("%d, ", result[i]);
      }
      printf("\n");
    }
    free(result);
    result = NULL;
  } else {
    printf("RandNumber failed!\n\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<testRandMN>:
  endbr64
  push   %r13
  mov    $0xa,%ecx
  mov    $0x21c,%edx
  mov    $0x1ea,%esi
  push   %r12
  lea    D37(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x5a00000003,%rax
  mov    %rax,(%rsp)
  movabs $0x131000000c8,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x1f7000001e7,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x1f5000001f4,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x1f8000001f6,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    $0x21c,%esi
  mov    %rsp,%rcx
  mov    $0xa,%r8d
  mov    $0xa,%edx
  mov    $0x1ea,%edi
  mov    %eax,%ebx
  call   <RandNumberMN@plt>
  xor    %edi,%edi
  mov    %rax,%r13
  call   <time@plt>
  lea    D1(%rip),%rdi
  sub    %ebx,%eax
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %r13,%r13
  je     L12
  lea    D25(%rip),%rdi
  mov    %r13,%rbx
  lea    0x28(%r13),%r12
  call   <puts@plt>
  lea    D0(%rip),%rbp
  nopl   0x0(%rax)
L36:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L36
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  call   <free@plt>
L16:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L16
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D37
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string
name: parse_data
arguments: label: D25
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string

tool: D37: m = %d, n = %d, k = %d


tool: D1: time = %d



tool: D25: RandNumber success!

tool: D0: %d, 

tool: D26: RandNumber failed!


assistant: ```c
void testRandMN(void) {
  time_t start, end;
  int *result = NULL;
  int m = 490, n = 540, k = 10;
  int inum[] = {3, 90, 200, 305, 487, 503, 500, 501, 502, 504};
  printf("m = %d, n = %d, k = %d\n", m, n, k);
  start = time(NULL);
  result = RandNumberMN(m, n, k, inum, sizeof(inum) / sizeof(inum[0]));
  end = time(NULL);
  printf("time = %d\n\n", end - start);
  if (result) {
    printf("RandNumber success!\n");
    if (k < 200) {
      int i;
      for (i = 0; i < k; i++) {
        printf("%d, ", result[i]);
      }
      printf("\n");
    }
    free(result);
    result = NULL;
  } else {
    printf("RandNumber failed!\n\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<testRandMN>:
  endbr64
  push   %r13
  mov    $0xa,%ecx
  mov    $0x21c,%edx
  mov    $0x1ea,%esi
  push   %r12
  lea    D3(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movdqa D16(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D48(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D68(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    $0x21c,%esi
  mov    %rsp,%rcx
  mov    $0xa,%r8d
  mov    $0xa,%edx
  mov    $0x1ea,%edi
  mov    %eax,%ebx
  call   <RandNumberMN@plt>
  xor    %edi,%edi
  mov    %rax,%r13
  call   <time@plt>
  lea    D20(%rip),%rdi
  sub    %ebx,%eax
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %r13,%r13
  je     L2
  lea    D13(%rip),%rdi
  mov    %r13,%rbx
  lea    0x28(%r13),%r12
  call   <puts@plt>
  lea    D5(%rip),%rbp
  nopl   0x0(%rax)
L33:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  call   <free@plt>
L20:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L20
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: byte[16]
name: disassemble_data
arguments: label: D48
type_infered: byte[8]
name: disassemble_data
arguments: label: D68
type_infered: byte[16]
name: disassemble_data
arguments: label: D20
type_infered: string
name: disassemble_data
arguments: label: D13
type_infered: string
name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D38
type_infered: string

tool: D3: m = %d, n = %d, k = %d


tool: {"D16": [0x03,0x00,0x00,0x00,0x5a,0x00,0x00,0x00,0xc8,0x00,0x00,0x00,0x31,0x01,0x00,0x00]}

tool: {"D48": [0xf6,0x01,0x00,0x00,0xf8,0x01,0x00,0x00]}

tool: {"D68": [0xe7,0x01,0x00,0x00,0xf7,0x01,0x00,0x00,0xf4,0x01,0x00,0x00,0xf5,0x01,0x00,0x00]}

tool: D20: time = %d



tool: D13: RandNumber success!

tool: D5: %d, 

tool: D38: RandNumber failed!


assistant: ```c
void testRandMN(void) {
  time_t start, end;
  int *result = NULL;
  int m = 490, n = 540, k = 10;
  int inum[] = {3, 90, 200, 305, 487, 503, 500, 501, 502, 504};
  printf("m = %d, n = %d, k = %d\n", m, n, k);
  start = time(NULL);
  result = RandNumberMN(m, n, k, inum, sizeof(inum) / sizeof(inum[0]));
  end = time(NULL);
  printf("time = %d\n\n", end - start);
  if (result) {
    printf("RandNumber success!\n");
    if (k < 200) {
      int i;
      for (i = 0; i < k; i++) {
        printf("%d, ", result[i]);
      }
      printf("\n");
    }
    free(result);
    result = NULL;
  } else {
    printf("RandNumber failed!\n\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_best_eci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x3,-0x2c(%rbp)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L67:
  cmp    %rdx,%rsp
  je     L104
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L67
L104:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L51
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L51:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
L58:
  cmpl   $0xe,-0x2c(%rbp)
  jne    L80
  movl   $0xf,-0x2c(%rbp)
  jmp    L82
L80:
  cmpl   $0x13,-0x2c(%rbp)
  jne    L82
  movl   $0x15,-0x2c(%rbp)
L82:
  lea    -0x3c(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <utf8_to_eci@plt>
  test   %rax,%rax
  jne    L33
  mov    -0x2c(%rbp),%eax
  jmp    L62
L33:
  addl   $0x1,-0x2c(%rbp)
  cmpl   $0x18,-0x2c(%rbp)
  jle    L58
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <is_valid_utf8@plt>
  test   %eax,%eax
  jne    L65
  mov    $0x0,%eax
  jmp    L62
L65:
  mov    $0x1a,%eax
L62:
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
__attribute__((visibility("hidden"))) int get_best_eci(const unsigned char source[], int length) {
  int eci = 3;
  unsigned char local_source[length + 1];
  do {
    if (eci == 14) {
      eci = 15;
    } else if (eci == 19) {
      eci = 21;
    }
    if (utf8_to_eci(eci, source, local_source, &length) == 0) {
      return eci;
    }
    eci++;
  } while (eci < 25);
  if (!is_valid_utf8(source, length)) {
    return 0;
  }
  return 26;
}
```