ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x680,%rsp
  mov    %rdi,-0x668(%rbp)
  mov    %rsi,-0x670(%rbp)
  mov    %edx,-0x674(%rbp)
  mov    %ecx,-0x678(%rbp)
  mov    %r8d,-0x67c(%rbp)
  mov    %r9d,-0x680(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x674(%rbp),%eax
  cmp    -0x67c(%rbp),%eax
  jne    L69
  mov    -0x678(%rbp),%eax
  cmp    -0x680(%rbp),%eax
  jne    L69
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x658(%rbp)
  jmp    L66
L6:
  movl   $0x0,-0x654(%rbp)
  jmp    L35
L38:
  mov    -0x658(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x668(%rbp),%rax
  add    %rax,%rdx
  mov    -0x654(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x658(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x670(%rbp),%rax
  add    %rax,%rdx
  mov    -0x654(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  sub    %eax,%ecx
  mov    -0x654(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x658(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  mov    %ecx,-0x650(%rbp,%rax,4)
  mov    -0x654(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x658(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    -0x650(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x654(%rbp)
L35:
  mov    -0x654(%rbp),%eax
  cmp    -0x678(%rbp),%eax
  jl     L38
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x658(%rbp)
L66:
  mov    -0x658(%rbp),%eax
  cmp    -0x674(%rbp),%eax
  jl     L6
L69:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string

tool: D19: 
Answer:

tool: D15: %d 

assistant: ```c
void subtract(int a[20][20], int b[20][20], int r, int s, int x, int y) {
  int c[20][20];
  int i, j;
  if (r == x && s == y) {
    printf("\nAnswer:\n");
    for (i = 0; i < r; i++) {
      for (j = 0; j < s; j++) {
        c[i][j] = a[i][j] - b[i][j];
        printf("%d ", c[i][j]);
      }
      printf("\n");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subtract>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %ecx,0xc(%rsp)
  cmp    %r8d,%edx
  jne    L47
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  cmp    %r9d,%ecx
  je     L21
L47:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L47
  mov    %rbp,%r15
  mov    %r12,0x10(%rsp)
  lea    -0x1(%rbx),%eax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  lea    0x50(%rbp,%rax,1),%rax
  mov    %rax,0x18(%rsp)
  lea    D2(%rip),%r14
  jmp    L75
L23:
  mov    %r15,%r13
  mov    0x10(%rsp),%r12
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%ebp
  mov    $0x0,%ebx
L38:
  mov    0x0(%r13,%rbx,4),%esi
  sub    (%r12,%rbx,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%rbp
  jne    L38
L39:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x50,%r15
  addq   $0x50,0x10(%rsp)
  cmp    0x18(%rsp),%r15
  je     L47
L75:
  cmpl   $0x0,0xc(%rsp)
  jg     L23
  jmp    L39
```

tool_calls: name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D12: 
Answer:

tool: D2: %d 

assistant: ```c
void subtract(int a[20][20], int b[20][20], int r, int s, int x, int y) {
  int c[20][20];
  int i, j;
  if (r == x && s == y) {
    printf("\nAnswer:\n");
    for (i = 0; i < r; i++) {
      for (j = 0; j < s; j++) {
        c[i][j] = a[i][j] - b[i][j];
        printf("%d ", c[i][j]);
      }
      printf("\n");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<subtract>:
  endbr64
  cmp    %r8d,%edx
  jne    L45
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r9d,%ecx
  je     L11
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rdi,%r15
  mov    %edx,%r12d
  lea    D12(%rip),%rdi
  mov    %rsi,%rbp
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L13
  lea    -0x1(%r12),%eax
  lea    D16(%rip),%r13
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  lea    0x50(%r15,%rax,1),%rax
  mov    %rax,0x8(%rsp)
L1:
  movslq %r14d,%r12
  xor    %ebx,%ebx
  test   %r14d,%r14d
  jle    L30
  nopw   0x0(%rax,%rax,1)
L57:
  mov    (%r15,%rbx,4),%esi
  mov    %r13,%rdi
  sub    0x0(%rbp,%rbx,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L57
L30:
  mov    $0xa,%edi
  add    $0x50,%r15
  add    $0x50,%rbp
  call   <putchar@plt>
  cmp    0x8(%rsp),%r15
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string

tool: D12: 
Answer:

tool: D16: %d 

assistant: ```c
void subtract(int a[20][20], int b[20][20], int r, int s, int x, int y) {
  int c[20][20];
  int i, j;
  if (r == x && s == y) {
    printf("\nAnswer:\n");
    for (i = 0; i < r; i++) {
      for (j = 0; j < s; j++) {
        c[i][j] = a[i][j] - b[i][j];
        printf("%d ", c[i][j]);
      }
      printf("\n");
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<subtract>:
  endbr64
  cmp    %r8d,%edx
  jne    L52
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r9d,%ecx
  je     L3
L47:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rdi,%r15
  mov    %edx,%r12d
  lea    D9(%rip),%rdi
  mov    %rsi,%rbp
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L47
  lea    -0x1(%r12),%eax
  lea    D4(%rip),%r13
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  lea    0x50(%r15,%rax,1),%rax
  mov    %rax,0x8(%rsp)
L39:
  movslq %r14d,%r12
  xor    %ebx,%ebx
  test   %r14d,%r14d
  jle    L51
  nopw   0x0(%rax,%rax,1)
L33:
  mov    (%r15,%rbx,4),%esi
  mov    %r13,%rdi
  sub    0x0(%rbp,%rbx,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L33
L51:
  mov    $0xa,%edi
  add    $0x50,%r15
  add    $0x50,%rbp
  call   <putchar@plt>
  cmp    0x8(%rsp),%r15
  jne    L39
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D9: 
Answer:

tool: D4: %d 

assistant: ```c
void subtract(int a[20][20], int b[20][20], int r, int s, int x, int y) {
  int c[20][20];
  int i, j;
  if (r == x && s == y) {
    printf("\nAnswer:\n");
    for (i = 0; i < r; i++) {
      for (j = 0; j < s; j++) {
        c[i][j] = a[i][j] - b[i][j];
        printf("%d ", c[i][j]);
      }
      printf("\n");
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<at_send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D16: AT

tool: D4: 


assistant: ```c
void at_send(FILE *fp, const char *fmt, va_list ap) {
  fprintf(fp, "AT");
  vfprintf(fp, fmt, ap);
  fprintf(fp, "\r\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<at_send>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  lea    D11(%rip),%rsi
  call   <fprintf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vfprintf@plt>
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
data_type: string
name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D11: AT

tool: D9: 


assistant: ```c
void at_send(FILE *fp, const char *fmt, va_list ap) {
  fprintf(fp, "AT");
  vfprintf(fp, fmt, ap);
  fprintf(fp, "\r\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<at_send>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  lea    D13(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  call   <fprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  call   <vfprintf@plt>
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <fprintf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D13: AT

tool: D7: 


assistant: ```c
void at_send(FILE *fp, const char *fmt, va_list ap) {
  fprintf(fp, "AT");
  vfprintf(fp, fmt, ap);
  fprintf(fp, "\r\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<at_send>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  lea    D11(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  call   <fprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  call   <vfprintf@plt>
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <fprintf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D11: AT

tool: D15: 


assistant: ```c
void at_send(FILE *fp, const char *fmt, va_list ap) {
  fprintf(fp, "AT");
  vfprintf(fp, fmt, ap);
  fprintf(fp, "\r\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<le_n_numeros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string
name: read_data
arguments: tag: D4
data_type: string

tool: D3: A ler inteiros...


tool: D4: %d

assistant: ```c
void le_n_numeros(int n, int vector[]) {
  int i;
  printf("A ler inteiros...\n");
  for (i = 0; i < n; ++i)
    scanf("%d", &vector[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<le_n_numeros>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    D13(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L5
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D16(%rip),%rbp
L6:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string

tool: D13: A ler inteiros...


tool: D16: %d

assistant: ```c
void le_n_numeros(int n, int vector[]) {
  int i;
  printf("A ler inteiros...\n");
  for (i = 0; i < n; ++i)
    scanf("%d", &vector[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<le_n_numeros>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D2(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L10
  lea    -0x1(%rbp),%eax
  lea    D1(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L17:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L17
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string
name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D2: A ler inteiros...


tool: D1: %d

assistant: ```c
void le_n_numeros(int n, int vector[]) {
  int i;
  printf("A ler inteiros...\n");
  for (i = 0; i < n; ++i)
    scanf("%d", &vector[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<le_n_numeros>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D16(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L0
  lea    -0x1(%rbp),%eax
  lea    D1(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L14:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L14
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D16: A ler inteiros...


tool: D1: %d

assistant: ```c
void le_n_numeros(int n, int vector[]) {
  int i;
  printf("A ler inteiros...\n");
  for (i = 0; i < n; ++i)
    scanf("%d", &vector[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: WRAPPED:a is:%d


assistant: ```c
void fff(void) {
  int a = 1;
  a++;
  printf("WRAPPED:a is:%d\n", a);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fff>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: WRAPPED:a is:%d


assistant: ```c
void fff(void) {
  int a = 1;
  a++;
  printf("WRAPPED:a is:%d\n", a);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fff>:
  endbr64
  mov    $0x2,%esi
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: WRAPPED:a is:%d


assistant: ```c
void fff(void) {
  int a = 1;
  a++;
  printf("WRAPPED:a is:%d\n", a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fff>:
  endbr64
  mov    $0x2,%esi
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: WRAPPED:a is:%d


assistant: ```c
void fff(void) {
  int a = 1;
  a++;
  printf("WRAPPED:a is:%d\n", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<glmGenerateTransposeMatrix2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void glmGenerateTransposeMatrix2d(double t[4], const double m[4]) {
  t[0] = m[0];
  t[2] = m[1];
  t[1] = m[2];
  t[3] = m[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<glmGenerateTransposeMatrix2d>:
  endbr64
  movsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void glmGenerateTransposeMatrix2d(double t[4], const double m[4]) {
  t[0] = m[0];
  t[2] = m[1];
  t[1] = m[2];
  t[3] = m[3];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<glmGenerateTransposeMatrix2d>:
  endbr64
  movsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void glmGenerateTransposeMatrix2d(double t[4], const double m[4]) {
  t[0] = m[0];
  t[2] = m[1];
  t[1] = m[2];
  t[3] = m[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glmGenerateTransposeMatrix2d>:
  endbr64
  movsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void glmGenerateTransposeMatrix2d(double t[4], const double m[4]) {
  t[0] = m[0];
  t[2] = m[1];
  t[1] = m[2];
  t[3] = m[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clEnqueueTask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x42c,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
cl_int clEnqueueTask(cl_command_queue command_queue, cl_kernel kernel, cl_uint num_events_in_wait_list, const cl_event *event_wait_list, cl_event *event) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)command_queue;
  sys_args[1] = (unsigned int)kernel;
  sys_args[2] = (unsigned int)num_events_in_wait_list;
  sys_args[3] = (unsigned int)event_wait_list;
  sys_args[4] = (unsigned int)event;
  return (cl_int)syscall(325, 1068, sys_args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clEnqueueTask>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %rsp,%rdx
  mov    $0x42c,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clEnqueueTask(cl_command_queue command_queue, cl_kernel kernel, cl_uint num_events_in_wait_list, const cl_event *event_wait_list, cl_event *event) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)command_queue;
  sys_args[1] = (unsigned int)kernel;
  sys_args[2] = (unsigned int)num_events_in_wait_list;
  sys_args[3] = (unsigned int)event_wait_list;
  sys_args[4] = (unsigned int)event;
  return (cl_int)syscall(325, 1068, sys_args);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clEnqueueTask>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    $0x145,%edi
  mov    %esi,0x4(%rsp)
  mov    $0x42c,%esi
  mov    %edx,0x8(%rsp)
  mov    %rsp,%rdx
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clEnqueueTask(cl_command_queue command_queue, cl_kernel kernel, cl_uint num_events_in_wait_list, const cl_event *event_wait_list, cl_event *event) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)command_queue;
  sys_args[1] = (unsigned int)kernel;
  sys_args[2] = (unsigned int)num_events_in_wait_list;
  sys_args[3] = (unsigned int)event_wait_list;
  sys_args[4] = (unsigned int)event;
  return (cl_int)syscall(325, 1068, sys_args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clEnqueueTask>:
  endbr64
  sub    $0x28,%rsp
  movq   %rdi,%xmm0
  movq   %rsi,%xmm2
  mov    $0x145,%edi
  movq   %rdx,%xmm1
  movq   %rcx,%xmm3
  punpcklqdq %xmm2,%xmm0
  mov    %rsp,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  punpcklqdq %xmm3,%xmm1
  mov    $0x42c,%esi
  mov    %r8d,0x10(%rsp)
  shufps $0x88,%xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clEnqueueTask(cl_command_queue command_queue, cl_kernel kernel, cl_uint num_events_in_wait_list, const cl_event *event_wait_list, cl_event *event) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)command_queue;
  sys_args[1] = (unsigned int)kernel;
  sys_args[2] = (unsigned int)num_events_in_wait_list;
  sys_args[3] = (unsigned int)event_wait_list;
  sys_args[4] = (unsigned int)event;
  return (cl_int)syscall(325, 1068, sys_args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<VarNameEnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rbx
  movzbl (%rbx),%eax
  cmp    $0x7b,%al
  jne    L26
L7:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x7d,%al
  je     L57
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L7
  jmp    L57
L21:
  add    $0x1,%rbx
L26:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L21
  movzbl (%rbx),%eax
  cmp    $0x5f,%al
  je     L21
  movzbl (%rbx),%eax
  cmp    $0x28,%al
  jne    L57
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L57
  lea    0x1(%rbx),%rax
  mov    $0x29,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <QuoteEnd@plt>
  cltq
  mov    %rax,%rbx
L57:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *VarNameEnd(string)
char *string;
{
  register char *p = string + 1;
  if (*p == '{') {
    do {
      p++;
    } while ((*p != '}') && (*p != 0));
  } else {
    while (isalnum(*p) || (*p == '_')) {
      p++;
    }
    if ((*p == '(') && (p != string + 1)) {
      p = QuoteEnd(p + 1, ')');
    }
  }
  return p;
}
```