user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %edx,%r10d
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  sub    %esi,%r14d
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x1(%r14),%eax
  mov    %rsp,%rcx
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L219
L205:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L205
L219:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L7
L2:
  mov    %r12d,%r15d
  mov    %rsp,%rcx
  mov    %rsp,%r9
  sub    %r10d,%r15d
  movslq %r15d,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L245
L60:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L60
L245:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L257
L35:
  mov    %rsp,%r8
  cmp    %ebx,%r10d
  jl     L125
  mov    %r10d,%eax
  mov    %r9,%rdi
  mov    %r8,-0x50(%rbp)
  sub    %ebx,%eax
  mov    %r10d,-0x48(%rbp)
  lea    0x4(,%rax,4),%rdx
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,4),%rsi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%r10d
  mov    -0x50(%rbp),%r8
  mov    %rax,%r9
L125:
  lea    0x1(%r10),%eax
  cmp    %eax,%r12d
  jl     L192
  lea    -0x1(%r12),%edx
  cltq
  mov    %r8,%rdi
  mov    %r9,-0x48(%rbp)
  sub    %r10d,%edx
  lea    0x0(%r13,%rax,4),%rsi
  lea    0x4(,%rdx,4),%rdx
  call   <memcpy@plt>
  mov    -0x48(%rbp),%r9
  mov    %rax,%r8
L192:
  xor    %ecx,%ecx
  xor    %edx,%edx
  cmp    %r12d,%ebx
  jg     L56
  test   %r14d,%r14d
  js     L46
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %edi,%edi
  test   %r15d,%r15d
  jg     L170
  jmp    L220
  nop
L109:
  add    $0x1,%edx
  lea    0x1(%rbx),%r10d
  movslq %ebx,%rbx
  movslq %edx,%rdi
  mov    %esi,0x0(%r13,%rbx,4)
  mov    %r10d,%ebx
  cmp    (%r9,%rdi,4),%eax
  jge    L177
  cmp    %r12d,%ebx
  jg     L56
L19:
  cmp    %edx,%r14d
  jl     L94
  cmp    %r15d,%ecx
  jge    L220
L170:
  movslq %ecx,%rax
  mov    (%r9,%rdi,4),%esi
  mov    (%r8,%rax,4),%eax
  cmp    %eax,%esi
  jg     L109
L177:
  movslq %ebx,%rsi
  add    $0x1,%ebx
  add    $0x1,%ecx
  mov    %eax,0x0(%r13,%rsi,4)
  cmp    %r12d,%ebx
  jle    L19
L56:
  cmp    %ebx,%r12d
  setge  %sil
  cmp    %edx,%r14d
  jl     L301
  movslq %edx,%rdi
  test   %sil,%sil
  je     L301
L220:
  movslq %ebx,%rsi
  lea    0x1(%rbx),%eax
  sub    %ebx,%edx
  sub    %rsi,%rdi
  cltq
  lea    (%r9,%rdi,4),%r9
  jmp    L263
  nopw   0x0(%rax,%rax,1)
L107:
  test   %sil,%sil
  je     L301
L263:
  mov    -0x4(%r9,%rax,4),%esi
  cmp    %eax,%r12d
  lea    (%rdx,%rax,1),%edi
  mov    %eax,%ebx
  mov    %esi,-0x4(%r13,%rax,4)
  setge  %sil
  add    $0x1,%rax
  cmp    %edi,%r14d
  jge    L107
L301:
  cmp    %ecx,%r15d
  jle    L148
  test   %sil,%sil
  je     L148
  movslq %ecx,%rsi
  movslq %ebx,%rdx
  lea    0x1(%rcx),%eax
  sub    %ecx,%ebx
  sub    %rsi,%rdx
  cltq
  lea    0x0(%r13,%rdx,4),%rsi
  nopl   0x0(%rax,%rax,1)
L292:
  mov    -0x4(%r8,%rax,4),%edx
  mov    %edx,-0x4(%rsi,%rax,4)
  lea    (%rbx,%rax,1),%edx
  cmp    %edx,%r12d
  setge  %cl
  cmp    %eax,%r15d
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L292
L148:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L114
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L94:
  mov    $0x1,%esi
  jmp    L301
L257:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L35
L46:
  mov    $0x1,%esi
  xor    %ecx,%ecx
  jmp    L301
L114:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int arr[], int low, int mid, int high) {
  int A1[mid - low + 1];
  int A2[high - mid];
  int i = 0, j = 0;
  for (i = low; i <= mid; i++)
    A1[i - low] = arr[i];
  for (j = mid + 1; j <= high; j++)
    A2[j - mid - 1] = arr[j];
  int k = low;
  j = 0;
  i = 0;
  while (k <= high && i <= mid - low && j <= high - mid - 1) {
    if (A1[i] > A2[j])
      arr[k++] = A1[i++];
    if (A2[j] >= A1[i])
      arr[k++] = A2[j++];
  }
  while (i <= mid - low && k <= high)
    arr[k++] = A1[i++];
  while (j <= high - mid - 1 && k <= high)
    arr[k++] = A2[j++];
}
```