ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<gen_swap_stack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <output_line@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D15
type_infered: string

tool: D1: ldx ,s

tool: D12: std ,s

tool: D15: tfr x,d

assistant: ```c
void gen_swap_stack(void) {
  output_line("ldx ,s");
  output_line("std ,s");
  output_line("tfr x,d");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gen_swap_stack>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <output_line@plt>
  lea    D10(%rip),%rdi
  call   <output_line@plt>
  lea    D14(%rip),%rdi
  call   <output_line@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: string

tool: D23: ldx ,s

tool: D10: std ,s

tool: D14: tfr x,d

assistant: ```c
void gen_swap_stack(void) {
  output_line("ldx ,s");
  output_line("std ,s");
  output_line("tfr x,d");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen_swap_stack>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <output_line@plt>
  lea    D10(%rip),%rdi
  call   <output_line@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <output_line@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D10
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D7: ldx ,s

tool: D10: std ,s

tool: D1: tfr x,d

assistant: ```c
void gen_swap_stack(void) {
  output_line("ldx ,s");
  output_line("std ,s");
  output_line("tfr x,d");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen_swap_stack>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <output_line@plt>
  lea    D29(%rip),%rdi
  call   <output_line@plt>
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <output_line@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D15: ldx ,s

tool: D29: std ,s

tool: D6: tfr x,d

assistant: ```c
void gen_swap_stack(void) {
  output_line("ldx ,s");
  output_line("std ,s");
  output_line("tfr x,d");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <publish_and_consume_single_message@plt>
  mov    $0x0,%eax
  call   <publish_and_wrap_multiple_messages@plt>
  mov    $0x0,%eax
  call   <stop_accepting_messages_when_full@plt>
  mov    $0x0,%eax
  call   <stop_accepting_messages_when_full_when_polled_not_released@plt>
  mov    $0x0,%eax
  call   <return_null_when_no_messages_available@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  publish_and_consume_single_message();
  publish_and_wrap_multiple_messages();
  stop_accepting_messages_when_full();
  stop_accepting_messages_when_full_when_polled_not_released();
  return_null_when_no_messages_available();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <publish_and_consume_single_message@plt>
  mov    $0x0,%eax
  call   <publish_and_wrap_multiple_messages@plt>
  mov    $0x0,%eax
  call   <stop_accepting_messages_when_full@plt>
  mov    $0x0,%eax
  call   <stop_accepting_messages_when_full_when_polled_not_released@plt>
  mov    $0x0,%eax
  call   <return_null_when_no_messages_available@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  publish_and_consume_single_message();
  publish_and_wrap_multiple_messages();
  stop_accepting_messages_when_full();
  stop_accepting_messages_when_full_when_polled_not_released();
  return_null_when_no_messages_available();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <publish_and_consume_single_message@plt>
  xor    %eax,%eax
  call   <publish_and_wrap_multiple_messages@plt>
  xor    %eax,%eax
  call   <stop_accepting_messages_when_full@plt>
  xor    %eax,%eax
  call   <stop_accepting_messages_when_full_when_polled_not_released@plt>
  xor    %eax,%eax
  call   <return_null_when_no_messages_available@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  publish_and_consume_single_message();
  publish_and_wrap_multiple_messages();
  stop_accepting_messages_when_full();
  stop_accepting_messages_when_full_when_polled_not_released();
  return_null_when_no_messages_available();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <publish_and_consume_single_message@plt>
  xor    %eax,%eax
  call   <publish_and_wrap_multiple_messages@plt>
  xor    %eax,%eax
  call   <stop_accepting_messages_when_full@plt>
  xor    %eax,%eax
  call   <stop_accepting_messages_when_full_when_polled_not_released@plt>
  xor    %eax,%eax
  call   <return_null_when_no_messages_available@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  publish_and_consume_single_message();
  publish_and_wrap_multiple_messages();
  stop_accepting_messages_when_full();
  stop_accepting_messages_when_full_when_polled_not_released();
  return_null_when_no_messages_available();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jg     L9
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L26
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L26
L9:
  mov    $0x1,%eax
  jmp    L43
L26:
  mov    $0x0,%eax
L43:
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D33
type_infered: string
name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D76
type_infered: string
name: disassemble_data
arguments: tag: D24
type_infered: string

tool: D3: a: 

tool: D14: %d

tool: D33: b: 

tool: D21: c: 

tool: D76: (a >= 2 || b == 1 && c > 0)

tool: D24: %d


assistant: ```c
main() {
  int a, b, c;
  printf("a: ");
  scanf("%d", &a);
  printf("b: ");
  scanf("%d", &b);
  printf("c: ");
  scanf("%d", &c);
  printf("(a >= 2 || b == 1 && c > 0)\n");
  printf("%d\n", a >= 2 || b == 1 && c > 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D45(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  cmpl   $0x1,0xc(%rsp)
  jle    L27
L28:
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L27:
  mov    $0x0,%esi
  cmpl   $0x1,0x10(%rsp)
  jne    L28
  cmpl   $0x0,0x14(%rsp)
  setg   %sil
  movzbl %sil,%esi
  jmp    L28
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D45
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D56
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D26
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D32
type_infered: string

tool: D8: a: 

tool: D45: %d

tool: D10: b: 

tool: D56: c: 

tool: D26: (a >= 2 || b == 1 && c > 0)

tool: D32: %d


assistant: ```c
main() {
  int a, b, c;
  printf("a: ");
  scanf("%d", &a);
  printf("b: ");
  scanf("%d", &b);
  printf("c: ");
  scanf("%d", &c);
  printf("(a >= 2 || b == 1 && c > 0)\n");
  printf("%d\n", a >= 2 || b == 1 && c > 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D54(%rip),%rdi
  lea    D34(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x1,0xc(%rsp)
  mov    $0x1,%esi
  jle    L7
L19:
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  xor    %esi,%esi
  cmpl   $0x1,0x10(%rsp)
  jne    L19
  xor    %esi,%esi
  cmpl   $0x0,0x14(%rsp)
  setg   %sil
  jmp    L19
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D54
datatype: string
name: parse_data
arguments: tag: D34
datatype: string
name: parse_data
arguments: tag: D3
datatype: string
name: parse_data
arguments: tag: D31
datatype: string
name: parse_data
arguments: tag: D37
datatype: string
name: parse_data
arguments: tag: D17
datatype: string

tool: D54: a: 

tool: D34: %d

tool: D3: b: 

tool: D31: c: 

tool: D37: (a >= 2 || b == 1 && c > 0)

tool: D17: %d


assistant: ```c
main() {
  int a, b, c;
  printf("a: ");
  scanf("%d", &a);
  printf("b: ");
  scanf("%d", &b);
  printf("c: ");
  scanf("%d", &c);
  printf("(a >= 2 || b == 1 && c > 0)\n");
  printf("%d\n", a >= 2 || b == 1 && c > 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  lea    D18(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x1,0xc(%rsp)
  mov    $0x1,%esi
  jle    L31
L8:
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L31:
  xor    %esi,%esi
  cmpl   $0x1,0x10(%rsp)
  jne    L8
  xor    %esi,%esi
  cmpl   $0x0,0x14(%rsp)
  setg   %sil
  jmp    L8
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D17
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D20
data_type: string

tool: D5: a: 

tool: D18: %d

tool: D25: b: 

tool: D17: c: 

tool: D0: (a >= 2 || b == 1 && c > 0)

tool: D20: %d


assistant: ```c
main() {
  int a, b, c;
  printf("a: ");
  scanf("%d", &a);
  printf("b: ");
  scanf("%d", &b);
  printf("c: ");
  scanf("%d", &c);
  printf("(a >= 2 || b == 1 && c > 0)\n");
  printf("%d\n", a >= 2 || b == 1 && c > 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  lea    -0x1c319d14(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
      }
      if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 943156777UL) - 1416170301U;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x8c1a67e,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
      }
      if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 943156777UL) - 1416170301U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x8c1a67e,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
      }
      if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 943156777UL) - 1416170301U;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
type_guessed: string
name: read_data
arguments: data_tag: D18
type_guessed: string

tool: D15: git tag -a %s -m "%s"


tool: D18: git push origin %s


assistant: ```c
void tag(const char *tagName) {
  printf("git tag -a %s -m \"%s\"\n", tagName, tagName);
  printf("git push origin %s\n", tagName);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tag>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rdx
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D15
type_guessed: string

tool: D5: git tag -a %s -m "%s"


tool: D15: git push origin %s


assistant: ```c
void tag(const char *tagName) {
  printf("git tag -a %s -m \"%s\"\n", tagName, tagName);
  printf("git push origin %s\n", tagName);
}
```
user: What is the c source code of the assembly code below?

```asm
<tag>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  mov    %rdi,%rdx
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string

tool: D7: git tag -a %s -m "%s"


tool: D15: git push origin %s


assistant: ```c
void tag(const char *tagName) {
  printf("git tag -a %s -m \"%s\"\n", tagName, tagName);
  printf("git push origin %s\n", tagName);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tag>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  mov    %rdi,%rdx
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D11
type_guessed: string

tool: D6: git tag -a %s -m "%s"


tool: D11: git push origin %s


assistant: ```c
void tag(const char *tagName) {
  printf("git tag -a %s -m \"%s\"\n", tagName, tagName);
  printf("git push origin %s\n", tagName);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L58:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0xffffffff,%eax
  je     L32
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jns    L28
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L34
L28:
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  cmp    $0xffffffff,%eax
  jne    L58
  jmp    L5
L32:
  nop
L5:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D43
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D40
type_infered: string

tool: D17: Notlari giriniz. Eger baska not girmeyecekseniz -1 giriniz...

tool: D43: %d. not: 

tool: D14: %d

tool: D20: Pozitif bir sayi giriniz...

tool: D40: %d not girdiniz. Notlarin ortalamasi: %d


assistant: ```c
int main() {
  int i = 1;
  int notlar = 0;
  int toplam = 0;
  printf("Notlari giriniz. Eger baska not girmeyecekseniz -1 giriniz...\n");
  do {
    printf("%d. not: ", i);
    scanf("%d", &notlar);
    if (notlar == -1) {
      break;
    }
    if (notlar < 0) {
      printf("Pozitif bir sayi giriniz...\n");
      continue;
    } else {
      toplam += notlar;
    }
    i++;
  } while (notlar != -1);
  printf("%d not girdiniz. Notlarin ortalamasi: %d\n", (i - 1), toplam / (i - 1));
  return 0;
}
```