ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  jne    L2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  je     L57
L2:
  mov    $0x0,%eax
  call   <showhelp@plt>
  mov    $0xffffffff,%eax
  jmp    L28
L57:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x70,%eax
  je     L52
  cmp    $0x75,%eax
  je     L87
  jmp    L76
L52:
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pack@plt>
  jmp    L20
L87:
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <unpack@plt>
  jmp    L20
L76:
  mov    $0x0,%eax
  call   <showhelp@plt>
  mov    $0xffffffff,%eax
  jmp    L28
L20:
  mov    $0x0,%eax
L28:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 4 || argv[1][0] != '-' || strlen(argv[1]) != 2) {
    showhelp();
    return -1;
  }
  switch (argv[1][1]) {
  case 'p':
    pack(argv[2], argv[3]);
    break;
  case 'u':
    unpack(argv[2], argv[3]);
    break;
  default:
    showhelp();
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x4,%edi
  jne    L46
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  cmpb   $0x2d,(%rdi)
  jne    L46
  call   <strlen@plt>
  cmp    $0x2,%eax
  jne    L46
  mov    0x8(%rbx),%rax
  movzbl 0x1(%rax),%eax
  cmp    $0x70,%al
  je     L48
  cmp    $0x75,%al
  je     L36
  mov    $0x0,%eax
  call   <showhelp@plt>
  mov    $0xffffffff,%eax
  jmp    L42
L46:
  mov    $0x0,%eax
  call   <showhelp@plt>
  mov    $0xffffffff,%eax
  jmp    L42
L48:
  mov    0x18(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <pack@plt>
  mov    $0x0,%eax
L42:
  pop    %rbx
  ret
L36:
  mov    0x18(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <unpack@plt>
  mov    $0x0,%eax
  jmp    L42
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 4 || argv[1][0] != '-' || strlen(argv[1]) != 2) {
    showhelp();
    return -1;
  }
  switch (argv[1][1]) {
  case 'p':
    pack(argv[2], argv[3]);
    break;
  case 'u':
    unpack(argv[2], argv[3]);
    break;
  default:
    showhelp();
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x4,%edi
  jne    L42
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  cmpb   $0x2d,(%rdi)
  jne    L42
  call   <strlen@plt>
  cmp    $0x2,%eax
  jne    L42
  mov    0x8(%rbx),%rax
  movzbl 0x1(%rax),%eax
  cmp    $0x70,%al
  je     L13
  cmp    $0x75,%al
  je     L31
L42:
  xor    %eax,%eax
  call   <showhelp@plt>
  or     $0xffffffff,%eax
  pop    %rbx
  ret
L31:
  mov    0x18(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <unpack@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L13:
  mov    0x18(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <pack@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 4 || argv[1][0] != '-' || strlen(argv[1]) != 2) {
    showhelp();
    return -1;
  }
  switch (argv[1][1]) {
  case 'p':
    pack(argv[2], argv[3]);
    break;
  case 'u':
    unpack(argv[2], argv[3]);
    break;
  default:
    showhelp();
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x4,%edi
  jne    L49
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  cmpb   $0x2d,(%rdi)
  jne    L49
  call   <strlen@plt>
  cmp    $0x2,%eax
  jne    L49
  mov    0x8(%rbx),%rax
  movzbl 0x1(%rax),%eax
  cmp    $0x70,%al
  je     L34
  cmp    $0x75,%al
  je     L8
L49:
  xor    %eax,%eax
  call   <showhelp@plt>
  or     $0xffffffff,%eax
  pop    %rbx
  ret
L8:
  mov    0x18(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <unpack@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L34:
  mov    0x18(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <pack@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 4 || argv[1][0] != '-' || strlen(argv[1]) != 2) {
    showhelp();
    return -1;
  }
  switch (argv[1][1]) {
  case 'p':
    pack(argv[2], argv[3]);
    break;
  case 'u':
    unpack(argv[2], argv[3]);
    break;
  default:
    showhelp();
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transfer_RGBA8888_to_RGBA8888>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x3(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_RGBA8888_to_RGBA8888(unsigned char *(*output), unsigned char *input) {
  (*output)[0] = input[0];
  (*output)[1] = input[1];
  (*output)[2] = input[2];
  (*output)[3] = input[3];
  (*output) += 4;
}
```
user: What is the c source code of the assembly code below?

```asm
<transfer_RGBA8888_to_RGBA8888>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x2(%rsi),%edx
  mov    %dl,0x2(%rax)
  mov    (%rdi),%rax
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x3(%rax)
  addq   $0x4,(%rdi)
  ret
```

assistant: ```c
void transfer_RGBA8888_to_RGBA8888(unsigned char *(*output), unsigned char *input) {
  (*output)[0] = input[0];
  (*output)[1] = input[1];
  (*output)[2] = input[2];
  (*output)[3] = input[3];
  (*output) += 4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<transfer_RGBA8888_to_RGBA8888>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x2(%rsi),%edx
  mov    %dl,0x2(%rax)
  mov    (%rdi),%rax
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x3(%rax)
  addq   $0x4,(%rdi)
  ret
```

assistant: ```c
void transfer_RGBA8888_to_RGBA8888(unsigned char *(*output), unsigned char *input) {
  (*output)[0] = input[0];
  (*output)[1] = input[1];
  (*output)[2] = input[2];
  (*output)[3] = input[3];
  (*output) += 4;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<transfer_RGBA8888_to_RGBA8888>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x2(%rsi),%edx
  mov    %dl,0x2(%rax)
  mov    (%rdi),%rax
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x3(%rax)
  addq   $0x4,(%rdi)
  ret
```

assistant: ```c
void transfer_RGBA8888_to_RGBA8888(unsigned char *(*output), unsigned char *input) {
  (*output)[0] = input[0];
  (*output)[1] = input[1];
  (*output)[2] = input[2];
  (*output)[3] = input[3];
  (*output) += 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <addition@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiplication@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D32
datatype: string
name: unpack_data
arguments: data_tag: D44
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D66
datatype: string
name: unpack_data
arguments: data_tag: D57
datatype: string
name: unpack_data
arguments: data_tag: D14
datatype: string

tool: D32: Add and multiply two numbers!

tool: D44: Enter first number 

tool: D19: %d

tool: D66: Enter second number 

tool: D57: 
Sum of two numbers is %d

tool: D14: 
Multiplication of two numbers is %d

assistant: ```c
int main() {
  int a, b, sum, mult;
  printf("Add and multiply two numbers!\n");
  printf("Enter first number ");
  scanf("%d", &a);
  printf("Enter second number ");
  scanf("%d", &b);
  sum = addition(a, b);
  printf("\nSum of two numbers is %d", sum);
  mult = multiplication(a, b);
  printf("\nMultiplication of two numbers is %d", mult);
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <addition@plt>
  mov    %eax,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <multiplication@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D32
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D48
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D24: Add and multiply two numbers!

tool: D32: Enter first number 

tool: D7: %d

tool: D48: Enter second number 

tool: D34: 
Sum of two numbers is %d

tool: D3: 
Multiplication of two numbers is %d

assistant: ```c
int main() {
  int a, b, sum, mult;
  printf("Add and multiply two numbers!\n");
  printf("Enter first number ");
  scanf("%d", &a);
  printf("Enter second number ");
  scanf("%d", &b);
  sum = addition(a, b);
  printf("\nSum of two numbers is %d", sum);
  mult = multiplication(a, b);
  printf("\nMultiplication of two numbers is %d", mult);
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  lea    D12(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <addition@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <multiplication@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string
name: extract_symbolic_data
arguments: data_label: D47
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: string
name: extract_symbolic_data
arguments: data_label: D23
type_infered: string
name: extract_symbolic_data
arguments: data_label: D13
type_infered: string

tool: D10: Add and multiply two numbers!

tool: D12: %d

tool: D47: Enter first number 

tool: D25: Enter second number 

tool: D23: 
Sum of two numbers is %d

tool: D13: 
Multiplication of two numbers is %d

assistant: ```c
int main() {
  int a, b, sum, mult;
  printf("Add and multiply two numbers!\n");
  printf("Enter first number ");
  scanf("%d", &a);
  printf("Enter second number ");
  scanf("%d", &b);
  sum = addition(a, b);
  printf("\nSum of two numbers is %d", sum);
  mult = multiplication(a, b);
  printf("\nMultiplication of two numbers is %d", mult);
  getchar();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D59(%rip),%rdi
  lea    D1(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <addition@plt>
  lea    D54(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <multiplication@plt>
  lea    D58(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D59
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D23
datatype: string
name: unpack_data
arguments: data_tag: D52
datatype: string
name: unpack_data
arguments: data_tag: D54
datatype: string
name: unpack_data
arguments: data_tag: D58
datatype: string

tool: D59: Add and multiply two numbers!

tool: D1: %d

tool: D23: Enter first number 

tool: D52: Enter second number 

tool: D54: 
Sum of two numbers is %d

tool: D58: 
Multiplication of two numbers is %d

assistant: ```c
int main() {
  int a, b, sum, mult;
  printf("Add and multiply two numbers!\n");
  printf("Enter first number ");
  scanf("%d", &a);
  printf("Enter second number ");
  scanf("%d", &b);
  sum = addition(a, b);
  printf("\nSum of two numbers is %d", sum);
  mult = multiplication(a, b);
  printf("\nMultiplication of two numbers is %d", mult);
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  f(&main);
  return sizeof(main);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  f(&main);
  return sizeof(main);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rdi
  xor    %eax,%eax
  call   <f@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  f(&main);
  return sizeof(main);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D1(%rip),%rdi
  xor    %eax,%eax
  call   <f@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  f(&main);
  return sizeof(main);
}
```
user: What is the c source code of the assembly code below?

```asm
<maximize_fdlimit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D0(%rip),%eax
  test   %eax,%eax
  jle    L7
  mov    D0(%rip),%eax
  jmp    L1
L7:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int maximize_fdlimit() {
  struct rlimit r;
  static int maxfds = -1;
  if (maxfds > 0)
    return maxfds;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<maximize_fdlimit>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int maximize_fdlimit() {
  struct rlimit r;
  static int maxfds = -1;
  if (maxfds > 0)
    return maxfds;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<maximize_fdlimit>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int maximize_fdlimit() {
  struct rlimit r;
  static int maxfds = -1;
  if (maxfds > 0)
    return maxfds;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<maximize_fdlimit>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int maximize_fdlimit() {
  struct rlimit r;
  static int maxfds = -1;
  if (maxfds > 0)
    return maxfds;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L21
  mov    $0x1,%eax
  jmp    L7
L21:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L15
  mov    $0xffffffff,%eax
  jmp    L7
L15:
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int check_cmp(int *a, int *b) {
  if (*a > *b)
    return 1;
  if (*a < *b)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_cmp>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  jg     L4
  setl   %al
  movzbl %al,%eax
  neg    %eax
L4:
  ret
```

assistant: ```c
int check_cmp(int *a, int *b) {
  if (*a > *b)
    return 1;
  if (*a < *b)
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_cmp>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L2
  setl   %al
  movzbl %al,%eax
  neg    %eax
L2:
  ret
```

assistant: ```c
int check_cmp(int *a, int *b) {
  if (*a > *b)
    return 1;
  if (*a < *b)
    return -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_cmp>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L8
  setl   %al
  movzbl %al,%eax
  neg    %eax
L8:
  ret
```

assistant: ```c
int check_cmp(int *a, int *b) {
  if (*a > *b)
    return 1;
  if (*a < *b)
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<binString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L3:
  mov    -0x14(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L35
  mov    $0x31,%ecx
  jmp    L20
L35:
  mov    $0x30,%ecx
L20:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D5(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  shll   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0xf,-0x4(%rbp)
  jle    L3
  movb   $0x0,D20(%rip)
  lea    D5(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *binString(int n) {
  static char bin[17];
  int x;
  for (x = 0; x < 16; x++) {
    bin[x] = n & 0x8000 ? '1' : '0';
    n <<= 1;
  }
  bin[16] = '\0';
  return (bin);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<binString>:
  endbr64
  lea    D7(%rip),%rax
  lea    0x10(%rax),%rcx
L6:
  test   $0x8000,%edi
  setne  %dl
  add    $0x30,%edx
  mov    %dl,(%rax)
  add    %edi,%edi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
  movb   $0x0,D21(%rip)
  lea    D7(%rip),%rax
  ret
```

assistant: ```c
char *binString(int n) {
  static char bin[17];
  int x;
  for (x = 0; x < 16; x++) {
    bin[x] = n & 0x8000 ? '1' : '0';
    n <<= 1;
  }
  bin[16] = '\0';
  return (bin);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<binString>:
  endbr64
  lea    D12(%rip),%r8
  mov    %r8,%rax
  lea    0x10(%r8),%rcx
  nopw   0x0(%rax,%rax,1)
L5:
  test   $0x8000,%edi
  setne  %dl
  add    $0x1,%rax
  add    %edi,%edi
  add    $0x30,%edx
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  jne    L5
  movb   $0x0,D11(%rip)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *binString(int n) {
  static char bin[17];
  int x;
  for (x = 0; x < 16; x++) {
    bin[x] = n & 0x8000 ? '1' : '0';
    n <<= 1;
  }
  bin[16] = '\0';
  return (bin);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binString>:
  endbr64
  mov    %edi,%eax
  movb   $0x0,D17(%rip)
  test   $0x80,%ah
  setne  %dl
  add    $0x30,%edx
  test   $0x40,%ah
  mov    %dl,D61(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x20,%ah
  mov    %dl,D132(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x10,%ah
  mov    %dl,D116(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x8,%ah
  mov    %dl,D86(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x4,%ah
  mov    %dl,D100(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x2,%ah
  mov    %dl,D49(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x1,%ah
  mov    %dl,D9(%rip)
  setne  %dl
  add    $0x30,%edx
  mov    %dl,D163(%rip)
  mov    %edi,%edx
  shr    $0x7,%dl
  add    $0x30,%edx
  test   $0x40,%al
  mov    %dl,D169(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x20,%al
  mov    %dl,D175(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x10,%al
  mov    %dl,D94(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x8,%al
  mov    %dl,D23(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x4,%al
  mov    %dl,D37(%rip)
  setne  %dl
  add    $0x30,%edx
  test   $0x2,%al
  mov    %dl,D118(%rip)
  setne  %dl
  and    $0x1,%eax
  add    $0x30,%eax
  add    $0x30,%edx
  mov    %al,D142(%rip)
  lea    D61(%rip),%rax
  mov    %dl,D176(%rip)
  ret
```

assistant: ```c
char *binString(int n) {
  static char bin[17];
  int x;
  for (x = 0; x < 16; x++) {
    bin[x] = n & 0x8000 ? '1' : '0';
    n <<= 1;
  }
  bin[16] = '\0';
  return (bin);
}
```