user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_xmlfixup>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L195
  mov    $0x1,%edx
  mov    $0x0,%edi
  lea    D32(%rip),%rcx
  jmp    L26
  add    $0x5,%edi
L34:
  mov    %edx,%esi
  add    $0x1,%rdx
  movzbl -0x1(%rbx,%rdx,1),%eax
  test   %al,%al
  je     L99
L26:
  sub    $0x22,%eax
  cmp    $0x1c,%al
  ja     L41
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  add    $0x8,%edi
  jmp    L34
  add    $0x6,%edi
  jmp    L34
  add    $0x4,%edi
  jmp    L34
  add    $0x4,%edi
  jmp    L34
L41:
  add    $0x1,%edi
  jmp    L34
L99:
  cmp    %esi,%edi
  je     L195
  add    $0x1,%edi
  call   <smalloc@plt>
  mov    %rax,%r12
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L159
  add    $0x1,%rbx
  mov    $0x0,%ebp
  lea    D27(%rip),%r13
  lea    D31(%rip),%r15
  lea    D4(%rip),%r14
  jmp    L160
L195:
  mov    %rbx,%rdi
  call   <string_dup@plt>
  mov    %rax,%r12
  jmp    L110
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    $0x5,%edx
  lea    D69(%rip),%rsi
  call   <strncpy@plt>
  add    $0x5,%ebp
L18:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edx
  test   %dl,%dl
  je     L91
L160:
  lea    -0x22(%rdx),%eax
  cmp    $0x1c,%al
  ja     L58
  movzbl %al,%eax
  movslq 0x0(%r13,%rax,4),%rax
  add    %r13,%rax
  notrack jmp *%rax
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    $0x8,%edx
  lea    D33(%rip),%rsi
  call   <strncpy@plt>
  add    $0x8,%ebp
  jmp    L18
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    $0x6,%edx
  lea    D64(%rip),%rsi
  call   <strncpy@plt>
  add    $0x6,%ebp
  jmp    L18
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    $0x4,%edx
  mov    %r14,%rsi
  call   <strncpy@plt>
  add    $0x4,%ebp
  jmp    L18
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    $0x4,%edx
  mov    %r15,%rsi
  call   <strncpy@plt>
  add    $0x4,%ebp
  jmp    L18
L58:
  movslq %ebp,%rax
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%ebp
  jmp    L18
L159:
  mov    $0x0,%ebp
L91:
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
L110:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D31
datatype: string
name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D69
datatype: string
name: retrieve_data
arguments: tag: D33
datatype: string
name: retrieve_data
arguments: tag: D64
datatype: string

tool: D31: &gt;

tool: D4: &lt;

tool: D69: &amp;

tool: D33: &dquote;

tool: D64: &apos;

assistant: ```c
char *string_xmlfixup(const char *str, int cdata) {
  int ich, i;
  char *nstr;
  for (i = 0, ich = 0; str[i]; i++) {
    switch (str[i]) {
    case '&':
      ich += 5;
      break;
    case '\"':
      ich += 8;
      break;
    case '\'':
      ich += 6;
      break;
    case '<':
      ich += 4;
      break;
    case '>':
      ich += 4;
      break;
    default:
      ich++;
      break;
    }
  }
  if (ich == i) {
    return string_dup(str);
  }
  nstr = (char *)smalloc(ich + 1);
  for (i = 0, ich = 0; str[i]; i++) {
    switch (str[i]) {
    case '&':
      strncpy(nstr + ich, "&amp;", 5);
      ich += 5;
      break;
    case '\"':
      strncpy(nstr + ich, "&dquote;", 8);
      ich += 8;
      break;
    case '\'':
      strncpy(nstr + ich, "&apos;", 6);
      ich += 6;
      break;
    case '<':
      strncpy(nstr + ich, "&lt;", 4);
      ich += 4;
      break;
    case '>':
      strncpy(nstr + ich, "&gt;", 4);
      ich += 4;
      break;
    default:
      nstr[ich] = str[i];
      ich++;
      break;
    }
  }
  nstr[ich] = '\0';
  return nstr;
}
```