ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<sp_ienv>:
  endbr64
  sub    $0x18,%rsp
  sub    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x5,%edi
  ja     L5
  lea    D4(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
  nop
L5:
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  movl   $0x1,0x4(%rsp)
  call   <xerbla_@plt>
  xor    %eax,%eax
  jmp    L17
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string

tool: D4: 


tool: D6: sp_ienv

assistant: ```c
int sp_ienv(int ispec) {
  int i;
  switch (ispec) {
  case 1:
    return (10);
  case 2:
    return (5);
  case 3:
    return (100);
  case 4:
    return (200);
  case 5:
    return (40);
  case 6:
    return (20);
  }
  i = 1;
  xerbla_("sp_ienv", &i);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<proto_check_numeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L75
L13:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L87
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L75
L87:
  cmpl   $0x0,-0xc(%rbp)
  jne    L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L80
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L16
L80:
  mov    $0x1,%eax
  jmp    L62
L16:
  mov    $0x0,%eax
  jmp    L62
L75:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L13
  mov    $0x1,%eax
L62:
  pop    %rbp
  ret
```

assistant: ```c
int proto_check_numeric(char *p, int len) {
  while ((len--) > 0) {
    if ((p[len] < '0') || (p[len] > '9')) {
      if ((0 == len) && (('-' == p[len]) || ('+' == p[len]))) {
        return 1;
      }
      return 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<proto_check_numeric>:
  endbr64
  sub    $0x1,%esi
  movslq %esi,%rsi
L37:
  mov    %esi,%ecx
  lea    0x1(%rsi),%eax
  test   %eax,%eax
  jle    L15
  movzbl (%rdi,%rsi,1),%eax
  sub    $0x1,%rsi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L37
  mov    $0x0,%edx
  test   %ecx,%ecx
  jne    L10
  sub    $0x2b,%eax
  test   $0xfd,%al
  sete   %dl
  movzbl %dl,%edx
  jmp    L10
L15:
  mov    $0x1,%edx
L10:
  mov    %edx,%eax
  ret
```

assistant: ```c
int proto_check_numeric(char *p, int len) {
  while ((len--) > 0) {
    if ((p[len] < '0') || (p[len] > '9')) {
      if ((0 == len) && (('-' == p[len]) || ('+' == p[len]))) {
        return 1;
      }
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<proto_check_numeric>:
  endbr64
  sub    $0x1,%esi
  movslq %esi,%rsi
  jmp    L26
  nopl   0x0(%rax)
L39:
  movzbl (%rdi,%rsi,1),%eax
  sub    $0x1,%rsi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L24
L26:
  lea    0x1(%rsi),%eax
  mov    %esi,%ecx
  test   %eax,%eax
  jg     L39
  mov    $0x1,%r8d
L27:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %r8d,%r8d
  test   %ecx,%ecx
  jne    L27
  sub    $0x2b,%eax
  xor    %r8d,%r8d
  test   $0xfd,%al
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int proto_check_numeric(char *p, int len) {
  while ((len--) > 0) {
    if ((p[len] < '0') || (p[len] > '9')) {
      if ((0 == len) && (('-' == p[len]) || ('+' == p[len]))) {
        return 1;
      }
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<proto_check_numeric>:
  endbr64
  sub    $0x1,%esi
  movslq %esi,%rsi
  jmp    L8
  nopl   0x0(%rax)
L20:
  movzbl (%rdi,%rsi,1),%eax
  sub    $0x1,%rsi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L39
L8:
  lea    0x1(%rsi),%eax
  mov    %esi,%ecx
  test   %eax,%eax
  jg     L20
  mov    $0x1,%r8d
L30:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %r8d,%r8d
  test   %ecx,%ecx
  jne    L30
  sub    $0x2b,%eax
  xor    %r8d,%r8d
  test   $0xfd,%al
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int proto_check_numeric(char *p, int len) {
  while ((len--) > 0) {
    if ((p[len] < '0') || (p[len] > '9')) {
      if ((0 == len) && (('-' == p[len]) || ('+' == p[len]))) {
        return 1;
      }
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L31
  cmpl   $0x1,-0x14(%rbp)
  jne    L19
L31:
  mov    $0x0,%eax
  jmp    L9
L19:
  movl   $0x2,-0x4(%rbp)
  jmp    L17
L38:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L38
  mov    -0x8(%rbp),%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int Fib(int n) {
  int tn_minus_1 = 1;
  int tn_minus_2 = 0;
  int tn = 0;
  int i = 0;
  if (n == 0 || n == 1) {
    return 0;
  }
  for (i = 2; i <= n; i++) {
    tn = tn_minus_1 + tn_minus_2;
    tn_minus_2 = tn_minus_1;
    tn_minus_1 = tn;
  }
  return tn;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Fib>:
  endbr64
  cmp    $0x1,%edi
  jle    L11
  add    $0x1,%edi
  mov    $0x2,%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  jmp    L7
L36:
  mov    %esi,%edx
L7:
  lea    (%rdx,%rcx,1),%esi
  add    $0x1,%eax
  mov    %edx,%ecx
  cmp    %eax,%edi
  jne    L36
L15:
  mov    %esi,%eax
  ret
L11:
  mov    $0x0,%esi
  jmp    L15
```

assistant: ```c
int Fib(int n) {
  int tn_minus_1 = 1;
  int tn_minus_2 = 0;
  int tn = 0;
  int i = 0;
  if (n == 0 || n == 1) {
    return 0;
  }
  for (i = 2; i <= n; i++) {
    tn = tn_minus_1 + tn_minus_2;
    tn_minus_2 = tn_minus_1;
    tn_minus_1 = tn;
  }
  return tn;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Fib>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  add    $0x1,%edi
  mov    $0x2,%eax
  xor    %ecx,%ecx
  mov    $0x1,%edx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r8d,%edx
L23:
  add    $0x1,%eax
  lea    (%rdx,%rcx,1),%r8d
  mov    %edx,%ecx
  cmp    %eax,%edi
  jne    L2
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Fib(int n) {
  int tn_minus_1 = 1;
  int tn_minus_2 = 0;
  int tn = 0;
  int i = 0;
  if (n == 0 || n == 1) {
    return 0;
  }
  for (i = 2; i <= n; i++) {
    tn = tn_minus_1 + tn_minus_2;
    tn_minus_2 = tn_minus_1;
    tn_minus_1 = tn;
  }
  return tn;
}
```
user: What is the c source code of the assembly code below:

```asm
<Fib>:
  endbr64
  cmp    $0x1,%edi
  jle    L3
  add    $0x1,%edi
  mov    $0x2,%eax
  xor    %ecx,%ecx
  mov    $0x1,%edx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r8d,%edx
L13:
  add    $0x1,%eax
  lea    (%rdx,%rcx,1),%r8d
  mov    %edx,%ecx
  cmp    %eax,%edi
  jne    L15
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Fib(int n) {
  int tn_minus_1 = 1;
  int tn_minus_2 = 0;
  int tn = 0;
  int i = 0;
  if (n == 0 || n == 1) {
    return 0;
  }
  for (i = 2; i <= n; i++) {
    tn = tn_minus_1 + tn_minus_2;
    tn_minus_2 = tn_minus_1;
    tn_minus_1 = tn;
  }
  return tn;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <revelation@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main() {
  revelation();
  char buf0[10];
  gets(buf0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <revelation@plt>
  lea    0xe(%rsp),%rdi
  call   <gets@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  revelation();
  char buf0[10];
  gets(buf0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <revelation@plt>
  lea    0xe(%rsp),%rdi
  call   <gets@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  revelation();
  char buf0[10];
  gets(buf0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <revelation@plt>
  lea    0xe(%rsp),%rdi
  call   <gets@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  revelation();
  char buf0[10];
  gets(buf0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L68
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L68
  addq   $0x2,-0x28(%rbp)
  jmp    L11
L88:
  mov    -0x18(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hexval@plt>
  add    %rbx,%rax
  mov    %rax,-0x18(%rbp)
L11:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L88
  jmp    L48
L68:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L13
  movl   $0x1,-0x1c(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L13
L51:
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x18(%rbp)
L13:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L51
  jmp    L22
L48:
  nop
L22:
  cmpl   $0x0,-0x1c(%rbp)
  je     L94
  negq   -0x18(%rbp)
L94:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long atol(const char *num) {
  long value = 0;
  int neg = 0;
  if (num[0] == '0' && num[1] == 'x') {
    num += 2;
    while (*num && isxdigit(*num))
      value = value * 16 + hexval(*num++);
  } else {
    if (num[0] == '-') {
      neg = 1;
      num++;
    }
    while (*num && isdigit(*num))
      value = value * 10 + *num++ - '0';
  }
  if (neg)
    value = -value;
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atol>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  cmp    $0x30,%dil
  je     L95
  cmp    $0x2d,%dil
  je     L45
  mov    $0x0,%r12d
  test   %dil,%dil
  je     L122
L127:
  mov    $0x0,%ebp
L94:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L43
  add    $0x1,%rbx
  lea    0x0(%rbp,%rbp,4),%rdx
  movsbq -0x1(%rbx),%rax
  lea    -0x30(%rax,%rdx,2),%rbp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L94
L43:
  test   %r12d,%r12d
  je     L116
L134:
  neg    %rbp
L116:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L95:
  mov    $0x0,%r12d
  cmpb   $0x78,0x1(%rbx)
  jne    L127
  lea    0x2(%rbx),%r12
  movzbl 0x2(%rbx),%edi
  mov    $0x0,%ebp
  test   %dil,%dil
  je     L116
L136:
  movsbl %dil,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L116
  shl    $0x4,%rbp
  add    $0x1,%r12
  movsbl -0x1(%r12),%edi
  call   <hexval@plt>
  add    %rax,%rbp
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L136
  jmp    L116
L45:
  movzbl 0x1(%rbx),%edi
  lea    0x1(%rbx),%rbx
  mov    $0x1,%r12d
  mov    $0x0,%ebp
  test   %dil,%dil
  jne    L127
  jmp    L134
L122:
  mov    $0x0,%ebp
  jmp    L116
```

assistant: ```c
long atol(const char *num) {
  long value = 0;
  int neg = 0;
  if (num[0] == '0' && num[1] == 'x') {
    num += 2;
    while (*num && isxdigit(*num))
      value = value * 16 + hexval(*num++);
  } else {
    if (num[0] == '-') {
      neg = 1;
      num++;
    }
    while (*num && isdigit(*num))
      value = value * 10 + *num++ - '0';
  }
  if (neg)
    value = -value;
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atol>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  cmp    $0x30,%dil
  je     L86
  cmp    $0x2d,%dil
  je     L23
  test   %dil,%dil
  je     L122
  xor    %ebp,%ebp
L4:
  xor    %r12d,%r12d
  jmp    L105
  cs nopw 0x0(%rax,%rax,1)
L71:
  movsbq (%rbx),%rax
  movsbl 0x1(%rbx),%edi
  lea    (%r12,%r12,4),%rdx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12
  test   %dil,%dil
  je     L25
L105:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L71
L25:
  mov    %r12,%rax
  neg    %rax
  test   %ebp,%ebp
  cmovne %rax,%r12
L21:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  movsbl 0x1(%rbx),%edi
  mov    $0x1,%ebp
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L4
L122:
  xor    %r12d,%r12d
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L86:
  xor    %ebp,%ebp
  cmpb   $0x78,0x1(%rbx)
  jne    L4
  movsbl 0x2(%rbx),%edi
  lea    0x2(%rbx),%rbp
  xor    %r12d,%r12d
  test   %dil,%dil
  jne    L128
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L9:
  movsbl 0x0(%rbp),%edi
  shl    $0x4,%r12
  add    $0x1,%rbp
  call   <hexval@plt>
  movsbl 0x0(%rbp),%edi
  add    %rax,%r12
  test   %dil,%dil
  je     L21
L128:
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L9
  jmp    L21
```

assistant: ```c
long atol(const char *num) {
  long value = 0;
  int neg = 0;
  if (num[0] == '0' && num[1] == 'x') {
    num += 2;
    while (*num && isxdigit(*num))
      value = value * 16 + hexval(*num++);
  } else {
    if (num[0] == '-') {
      neg = 1;
      num++;
    }
    while (*num && isdigit(*num))
      value = value * 10 + *num++ - '0';
  }
  if (neg)
    value = -value;
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<atol>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  cmp    $0x30,%dil
  je     L38
  cmp    $0x2d,%dil
  je     L85
  test   %dil,%dil
  je     L112
  xor    %ebp,%ebp
L40:
  xor    %r12d,%r12d
  jmp    L92
  cs nopw 0x0(%rax,%rax,1)
L132:
  movsbq (%rbx),%rax
  movsbl 0x1(%rbx),%edi
  lea    (%r12,%r12,4),%rdx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12
  test   %dil,%dil
  je     L0
L92:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L132
L0:
  mov    %r12,%rax
  neg    %rax
  test   %ebp,%ebp
  cmovne %rax,%r12
L79:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L85:
  movsbl 0x1(%rbx),%edi
  mov    $0x1,%ebp
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L40
L112:
  xor    %r12d,%r12d
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L38:
  xor    %ebp,%ebp
  cmpb   $0x78,0x1(%rbx)
  jne    L40
  movsbl 0x2(%rbx),%edi
  lea    0x2(%rbx),%rbp
  xor    %r12d,%r12d
  test   %dil,%dil
  jne    L124
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L9:
  movsbl 0x0(%rbp),%edi
  shl    $0x4,%r12
  add    $0x1,%rbp
  call   <hexval@plt>
  movsbl 0x0(%rbp),%edi
  add    %rax,%r12
  test   %dil,%dil
  je     L79
L124:
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L9
  jmp    L79
```

assistant: ```c
long atol(const char *num) {
  long value = 0;
  int neg = 0;
  if (num[0] == '0' && num[1] == 'x') {
    num += 2;
    while (*num && isxdigit(*num))
      value = value * 16 + hexval(*num++);
  } else {
    if (num[0] == '-') {
      neg = 1;
      num++;
    }
    while (*num && isdigit(*num))
      value = value * 10 + *num++ - '0';
  }
  if (neg)
    value = -value;
  return value;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<emit_rotlsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <emit_shrimm@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <emit_rotl@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_adc@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_rotlsr(int t, int sr) {
  emit_shrimm(sr, 1, sr);
  emit_rotl(t);
  emit_adc(sr, sr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emit_rotlsr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %esi,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <emit_shrimm@plt>
  mov    %ebp,%edi
  call   <emit_rotl@plt>
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <emit_adc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void emit_rotlsr(int t, int sr) {
  emit_shrimm(sr, 1, sr);
  emit_rotl(t);
  emit_adc(sr, sr);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<emit_rotlsr>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <emit_shrimm@plt>
  mov    %r12d,%edi
  call   <emit_rotl@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <emit_adc@plt>
```

assistant: ```c
void emit_rotlsr(int t, int sr) {
  emit_shrimm(sr, 1, sr);
  emit_rotl(t);
  emit_adc(sr, sr);
}
```
user: What is the c source code of the assembly code below:

```asm
<emit_rotlsr>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <emit_shrimm@plt>
  mov    %r12d,%edi
  call   <emit_rotl@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <emit_adc@plt>
```

assistant: ```c
void emit_rotlsr(int t, int sr) {
  emit_shrimm(sr, 1, sr);
  emit_rotl(t);
  emit_adc(sr, sr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<convert_mantissa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0xd,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L12:
  shll   -0x8(%rbp)
  subl   $0x800000,-0x4(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  and    $0x800000,%eax
  test   %eax,%eax
  je     L12
  andl   $0xff7fffff,-0x8(%rbp)
  addl   $0x38800000,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned convert_mantissa(unsigned i) {
  unsigned m = i << 13;
  unsigned e = 0;
  while (!(m & 0x00800000)) {
    m <<= 1;
    e -= 0x00800000;
  }
  m &= ~0x00800000;
  e += 0x38800000;
  return m | e;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convert_mantissa>:
  endbr64
  shl    $0xd,%edi
  mov    %edi,%eax
  and    $0x800000,%eax
  jne    L15
L23:
  add    %edi,%edi
  sub    $0x800000,%eax
  test   $0x800000,%edi
  je     L23
L4:
  and    $0xff7fffff,%edi
  add    $0x38800000,%eax
  or     %edi,%eax
  ret
L15:
  mov    $0x0,%eax
  jmp    L4
```

assistant: ```c
unsigned convert_mantissa(unsigned i) {
  unsigned m = i << 13;
  unsigned e = 0;
  while (!(m & 0x00800000)) {
    m <<= 1;
    e -= 0x00800000;
  }
  m &= ~0x00800000;
  e += 0x38800000;
  return m | e;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_mantissa>:
  endbr64
  shl    $0xd,%edi
  mov    %edi,%eax
  and    $0x800000,%eax
  jne    L15
L13:
  add    %edi,%edi
  mov    %eax,%edx
  sub    $0x800000,%eax
  test   $0x800000,%edi
  je     L13
  and    $0xff7fffff,%edi
  add    $0x38000000,%edx
  mov    %edi,%eax
  or     %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  and    $0xff7fffff,%edi
  mov    $0x38800000,%edx
  mov    %edi,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned convert_mantissa(unsigned i) {
  unsigned m = i << 13;
  unsigned e = 0;
  while (!(m & 0x00800000)) {
    m <<= 1;
    e -= 0x00800000;
  }
  m &= ~0x00800000;
  e += 0x38800000;
  return m | e;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_mantissa>:
  endbr64
  shl    $0xd,%edi
  mov    %edi,%eax
  and    $0x800000,%eax
  jne    L15
L10:
  add    %edi,%edi
  mov    %eax,%edx
  sub    $0x800000,%eax
  test   $0x800000,%edi
  je     L10
  and    $0xff7fffff,%edi
  add    $0x38000000,%edx
  mov    %edi,%eax
  or     %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  and    $0xff7fffff,%edi
  mov    $0x38800000,%edx
  mov    %edi,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned convert_mantissa(unsigned i) {
  unsigned m = i << 13;
  unsigned e = 0;
  while (!(m & 0x00800000)) {
    m <<= 1;
    e -= 0x00800000;
  }
  m &= ~0x00800000;
  e += 0x38800000;
  return m | e;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L9
  mov    $0x0,%eax
  call   <abort@plt>
L9:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
#pragma acc kernels
  {
    if (argc != 1)
      abort();
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jne    L2
  mov    $0x0,%eax
  ret
L2:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
#pragma acc kernels
  {
    if (argc != 1)
      abort();
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jne    L4
  xor    %eax,%eax
  ret
L4:
  push   %rax
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
#pragma acc kernels
  {
    if (argc != 1)
      abort();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jne    L1
  xor    %eax,%eax
  ret
L1:
  push   %rax
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
#pragma acc kernels
  {
    if (argc != 1)
      abort();
  }
  return 0;
}
```