ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<view_frontEnd>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L38:
  cmp    $0xa,%ebx
  je     L35
L116:
  xor    %eax,%eax
  call   <view_displayMenu@plt>
  xor    %eax,%eax
  call   <view_selectMenu@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  ja     L38
  mov    %eax,%eax
  movslq 0x0(%rbp,%rax,4),%rax
  add    %rbp,%rax
  notrack jmp *%rax
  nop
  xor    %eax,%eax
  call   <view_exit@plt>
  cmp    $0xa,%ebx
  jne    L116
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <view_doBubbleSort@plt>
  jmp    L38
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_displayArray@plt>
  jmp    L38
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_makeAnArrayFromStack@plt>
  jmp    L38
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_popANumber@plt>
  jmp    L38
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_pushANumber@plt>
  jmp    L38
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_clearStack@plt>
  jmp    L38
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_displayStack@plt>
  jmp    L38
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_writeAFileFromStack@plt>
  jmp    L38
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_makeAStackFromFile@plt>
  jmp    L38
```

assistant: ```c
void view_frontEnd(void) {
  int selectedItem = 0;
  while (selectedItem != 10) {
    view_displayMenu();
    selectedItem = view_selectMenu();
    switch (selectedItem) {
    case 1:
      view_makeAStackFromFile();
      break;
    case 2:
      view_writeAFileFromStack();
      break;
    case 3:
      view_displayStack();
      break;
    case 4:
      view_clearStack();
      break;
    case 5:
      view_pushANumber();
      break;
    case 6:
      view_popANumber();
      break;
    case 7:
      view_makeAnArrayFromStack();
      break;
    case 8:
      view_displayArray();
      break;
    case 9:
      view_doBubbleSort();
      break;
    case 10:
      view_exit();
      break;
    default:
      break;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<view_frontEnd>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L82:
  cmp    $0xa,%ebx
  je     L98
L19:
  xor    %eax,%eax
  call   <view_displayMenu@plt>
  xor    %eax,%eax
  call   <view_selectMenu@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  ja     L82
  mov    %eax,%eax
  movslq 0x0(%rbp,%rax,4),%rax
  add    %rbp,%rax
  notrack jmp *%rax
  nop
  xor    %eax,%eax
  call   <view_exit@plt>
  cmp    $0xa,%ebx
  jne    L19
L98:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <view_doBubbleSort@plt>
  jmp    L82
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_displayArray@plt>
  jmp    L82
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_makeAnArrayFromStack@plt>
  jmp    L82
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_popANumber@plt>
  jmp    L82
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_pushANumber@plt>
  jmp    L82
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_clearStack@plt>
  jmp    L82
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_displayStack@plt>
  jmp    L82
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_writeAFileFromStack@plt>
  jmp    L82
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <view_makeAStackFromFile@plt>
  jmp    L82
```

assistant: ```c
void view_frontEnd(void) {
  int selectedItem = 0;
  while (selectedItem != 10) {
    view_displayMenu();
    selectedItem = view_selectMenu();
    switch (selectedItem) {
    case 1:
      view_makeAStackFromFile();
      break;
    case 2:
      view_writeAFileFromStack();
      break;
    case 3:
      view_displayStack();
      break;
    case 4:
      view_clearStack();
      break;
    case 5:
      view_pushANumber();
      break;
    case 6:
      view_popANumber();
      break;
    case 7:
      view_makeAnArrayFromStack();
      break;
    case 8:
      view_displayArray();
      break;
    case 9:
      view_doBubbleSort();
      break;
    case 10:
      view_exit();
      break;
    default:
      break;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pr_title>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <pr_indent@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0xc(%rbp),%eax
  add    $0x3,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: %s:


assistant: ```c
int pr_title(FILE *fp, int indent, char *title) {
  (void)pr_indent(fp, indent);
  (void)fprintf(fp, "%s:\n", title);
  return (indent + 3);
}
```
user: What is the c source code of the assembly code below:

```asm
<pr_title>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  call   <pr_indent@plt>
  mov    %r12,%rdx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  lea    0x3(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: %s:


assistant: ```c
int pr_title(FILE *fp, int indent, char *title) {
  (void)pr_indent(fp, indent);
  (void)fprintf(fp, "%s:\n", title);
  return (indent + 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pr_title>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <pr_indent@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  call   <fprintf@plt>
  lea    0x3(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: %s:


assistant: ```c
int pr_title(FILE *fp, int indent, char *title) {
  (void)pr_indent(fp, indent);
  (void)fprintf(fp, "%s:\n", title);
  return (indent + 3);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pr_title>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <pr_indent@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <fprintf@plt>
  lea    0x3(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2: %s:


assistant: ```c
int pr_title(FILE *fp, int indent, char *title) {
  (void)pr_indent(fp, indent);
  (void)fprintf(fp, "%s:\n", title);
  return (indent + 3);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: %d 


assistant: ```c
main() {
  void *x;
  int y = 8;
  x = &y;
  int *temp = (int *)x;
  printf("%d \n", *temp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: %d 


assistant: ```c
main() {
  void *x;
  int y = 8;
  x = &y;
  int *temp = (int *)x;
  printf("%d \n", *temp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: %d 


assistant: ```c
main() {
  void *x;
  int y = 8;
  x = &y;
  int *temp = (int *)x;
  printf("%d \n", *temp);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: %d 


assistant: ```c
main() {
  void *x;
  int y = 8;
  x = &y;
  int *temp = (int *)x;
  printf("%d \n", *temp);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sys$hiber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xf,%rax
  int    $0x81
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sys$hiber(void) {
  return ({
    unsigned long resultvar;
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(15)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sys$hiber>:
  endbr64
  mov    $0xf,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$hiber(void) {
  return ({
    unsigned long resultvar;
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(15)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sys$hiber>:
  endbr64
  mov    $0xf,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$hiber(void) {
  return ({
    unsigned long resultvar;
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(15)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_nbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_nbits(uint32_t v) {
  int c;
  v = v - ((v >> 1) & (((uint32_t) ~(uint32_t)0) / 3));
  v = (v & (((uint32_t) ~(uint32_t)0) / 15 * 3)) + ((v >> 2) & (((uint32_t) ~(uint32_t)0) / 15 * 3));
  v = (v + (v >> 4)) & (((uint32_t) ~(uint32_t)0) / 255 * 15);
  c = (uint32_t)(v * (((uint32_t) ~(uint32_t)0) / 255)) >> ((sizeof(uint32_t) - 1) * 8);
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_nbits>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int get_nbits(uint32_t v) {
  int c;
  v = v - ((v >> 1) & (((uint32_t) ~(uint32_t)0) / 3));
  v = (v & (((uint32_t) ~(uint32_t)0) / 15 * 3)) + ((v >> 2) & (((uint32_t) ~(uint32_t)0) / 15 * 3));
  v = (v + (v >> 4)) & (((uint32_t) ~(uint32_t)0) / 255 * 15);
  c = (uint32_t)(v * (((uint32_t) ~(uint32_t)0) / 255)) >> ((sizeof(uint32_t) - 1) * 8);
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_nbits>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_nbits(uint32_t v) {
  int c;
  v = v - ((v >> 1) & (((uint32_t) ~(uint32_t)0) / 3));
  v = (v & (((uint32_t) ~(uint32_t)0) / 15 * 3)) + ((v >> 2) & (((uint32_t) ~(uint32_t)0) / 15 * 3));
  v = (v + (v >> 4)) & (((uint32_t) ~(uint32_t)0) / 255 * 15);
  c = (uint32_t)(v * (((uint32_t) ~(uint32_t)0) / 255)) >> ((sizeof(uint32_t) - 1) * 8);
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<replace_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L50
  cmpq   $0x0,-0x20(%rbp)
  je     L50
  cmpq   $0x0,-0x28(%rbp)
  jne    L40
L50:
  mov    $0x0,%eax
  jmp    L25
L40:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  mov    -0x18(%rbp),%rax
  jmp    L25
L21:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  lea    D39(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rcx
  lea    D39(%rip),%rax
  lea    (%rcx,%rax,1),%rdi
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  call   <sprintf@plt>
  lea    D39(%rip),%rax
L25:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: %s%s

assistant: ```c
char *replace_one(char *st, char *orig, char *repl) {
  static char buffer[4096];
  char *ch;
  if (!st || !orig || !repl) {
    return NULL;
  }
  if (!(ch = strstr(st, orig))) {
    return st;
  }
  strncpy(buffer, st, ch - st);
  buffer[ch - st] = 0;
  sprintf(buffer + (ch - st), "%s%s", repl, ch + strlen(orig));
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<replace_one>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r13
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L21
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L21
  call   <strstr@plt>
  mov    %rax,%r12
  mov    %rbx,%rax
  test   %r12,%r12
  je     L11
  mov    %r12,%r14
  sub    %rbx,%r14
  mov    %r14d,%edx
  mov    %rbx,%rsi
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r14,1)
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    (%r12,%rax,1),%rcx
  lea    (%r14,%rbx,1),%rdi
  mov    %r13,%rdx
  lea    D1(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbx,%rax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  mov    $0x0,%eax
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: %s%s

assistant: ```c
char *replace_one(char *st, char *orig, char *repl) {
  static char buffer[4096];
  char *ch;
  if (!st || !orig || !repl) {
    return NULL;
  }
  if (!(ch = strstr(st, orig))) {
    return st;
  }
  strncpy(buffer, st, ch - st);
  buffer[ch - st] = 0;
  sprintf(buffer + (ch - st), "%s%s", repl, ch + strlen(orig));
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<replace_one>:
  endbr64
  test   %rsi,%rsi
  push   %r14
  mov    %rdx,%r14
  sete   %al
  test   %rdx,%rdx
  push   %r13
  sete   %dl
  push   %r12
  or     %dl,%al
  push   %rbp
  push   %rbx
  jne    L11
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L11
  mov    %rsi,%rbp
  call   <strstr@plt>
  mov    %rax,%r12
  mov    %rbx,%rax
  test   %r12,%r12
  je     L16
  mov    %r12,%r13
  mov    %rbx,%rsi
  sub    %rbx,%r13
  lea    D3(%rip),%rbx
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r13,1)
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r14,%rdx
  lea    D7(%rip),%rsi
  cltq
  lea    (%r12,%rax,1),%rcx
  call   <sprintf@plt>
  mov    %rbx,%rax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: %s%s

assistant: ```c
char *replace_one(char *st, char *orig, char *repl) {
  static char buffer[4096];
  char *ch;
  if (!st || !orig || !repl) {
    return NULL;
  }
  if (!(ch = strstr(st, orig))) {
    return st;
  }
  strncpy(buffer, st, ch - st);
  buffer[ch - st] = 0;
  sprintf(buffer + (ch - st), "%s%s", repl, ch + strlen(orig));
  return buffer;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<replace_one>:
  endbr64
  test   %rsi,%rsi
  push   %r14
  mov    %rdx,%r14
  sete   %al
  test   %rdx,%rdx
  push   %r13
  sete   %dl
  push   %r12
  or     %dl,%al
  push   %rbp
  push   %rbx
  jne    L12
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L12
  mov    %rsi,%rbp
  call   <strstr@plt>
  mov    %rax,%r12
  mov    %rbx,%rax
  test   %r12,%r12
  je     L14
  mov    %r12,%r13
  mov    %rbx,%rsi
  sub    %rbx,%r13
  lea    D1(%rip),%rbx
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r13,1)
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r14,%rdx
  lea    D11(%rip),%rsi
  cltq
  lea    (%r12,%rax,1),%rcx
  call   <sprintf@plt>
  mov    %rbx,%rax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type: string

tool: D11: %s%s

assistant: ```c
char *replace_one(char *st, char *orig, char *repl) {
  static char buffer[4096];
  char *ch;
  if (!st || !orig || !repl) {
    return NULL;
  }
  if (!(ch = strstr(st, orig))) {
    return st;
  }
  strncpy(buffer, st, ch - st);
  buffer[ch - st] = 0;
  sprintf(buffer + (ch - st), "%s%s", repl, ch + strlen(orig));
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x40091eb8,-0x24(%rbp)
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L66
L32:
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <stdlib_base_float64_set_high_word@plt>
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L4
  ucomisd %xmm1,%xmm0
  je     L72
L4:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L58
L72:
  addl   $0x1,-0x28(%rbp)
L66:
  cmpl   $0xf423f,-0x28(%rbp)
  jle    L32
L58:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L69
  ucomisd %xmm1,%xmm0
  je     L55
L69:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L55:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D27
type: f64
name: retrieve_data
arguments: tag: D13
type: string

tool: D27: 3.14

tool: D13: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  uint32_t h;
  double x;
  double t;
  int i;
  x = 3.14;
  h = 1074339512;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    stdlib_base_float64_set_high_word(h + i, &x);
    if (x != x) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (x != x) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<benchmark>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D24(%rip),%rax
  mov    %rax,(%rsp)
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r14
  mov    $0x40091eb8,%ebx
  mov    %rsp,%rbp
L42:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <stdlib_base_float64_set_high_word@plt>
  movsd  (%rsp),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L4
  add    $0x1,%ebx
  cmp    $0x401860f8,%ebx
  jne    L42
  jmp    L46
L4:
  lea    D15(%rip),%rdi
  call   <printf@plt>
L46:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r14,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  movsd  (%rsp),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L35
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  movq   %rbx,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L35:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
type_guessed: f64
name: retrieve_data
arguments: tag: D15
type_guessed: string

tool: D24: 3.14

tool: D15: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  uint32_t h;
  double x;
  double t;
  int i;
  x = 3.14;
  h = 1074339512;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    stdlib_base_float64_set_high_word(h + i, &x);
    if (x != x) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (x != x) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<benchmark>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x40091eb8,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D29(%rip),%rax
  lea    0x10(%rsp),%rbp
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L22
  nop
L24:
  add    $0x1,%ebx
  cmp    $0x401860f8,%ebx
  je     L53
L22:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <stdlib_base_float64_set_high_word@plt>
  movsd  0x10(%rsp),%xmm0
  ucomisd %xmm0,%xmm0
  jnp    L24
  lea    D16(%rip),%rdi
  call   <printf@plt>
L53:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  0x10(%rsp),%xmm1
  subsd  0x8(%rsp),%xmm0
  ucomisd %xmm1,%xmm1
  jp     L6
L33:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L6:
  lea    D16(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L33
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type_guessed: f64
name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D29: 3.14

tool: D16: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  uint32_t h;
  double x;
  double t;
  int i;
  x = 3.14;
  h = 1074339512;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    stdlib_base_float64_set_high_word(h + i, &x);
    if (x != x) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (x != x) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```