ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<AddNonCompressedBlock>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%esi
  mov    $0xffffffff,%r15d
  jmp    L11
L1:
  add    %r14,%rbx
  mov    %r13,%rsi
L11:
  lea    0xffff(%rsi),%rax
  mov    %r12d,%edx
  sub    %esi,%edx
  cmp    %r12,%rax
  cmovbe %r15d,%edx
  movzwl %dx,%r14d
  lea    (%r14,%rsi,1),%r13
  mov    %edx,%eax
  not    %eax
  cmp    %r12,%r13
  setae  0x0(%rbp,%rbx,1)
  mov    %dl,0x1(%rbp,%rbx,1)
  movzbl %dh,%ecx
  mov    %cl,0x2(%rbp,%rbx,1)
  mov    %al,0x3(%rbp,%rbx,1)
  movzbl %ah,%eax
  mov    %al,0x4(%rbp,%rbx,1)
  add    $0x5,%rbx
  movzwl %dx,%edx
  add    0x8(%rsp),%rsi
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <memcpy@plt>
  cmp    %r12,%r13
  jb     L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AddNonCompressedBlock(const unsigned char *in, size_t insize, unsigned char *out) {
  size_t pos = 0;
  size_t outpos = 0;
  for (;;) {
    unsigned short blocksize = 65535;
    unsigned short nlen;
    if (pos + blocksize > insize)
      blocksize = insize - pos;
    int currentfinal = pos + blocksize >= insize;
    nlen = ~blocksize;
    out[outpos] = currentfinal;
    out[outpos + 1] = blocksize % 256;
    out[outpos + 2] = blocksize / 256;
    out[outpos + 3] = nlen % 256;
    out[outpos + 4] = nlen / 256;
    outpos += 5;
    memcpy(out + outpos, in + pos, blocksize);
    if (currentfinal)
      break;
    pos += blocksize;
    outpos += blocksize;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<AddNonCompressedBlock>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %rsi,%r14
  xor    %esi,%esi
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L8
  nopl   0x0(%rax)
L20:
  mov    %r14d,%edx
  sub    %esi,%edx
  mov    %edx,%ecx
  movzwl %dx,%r15d
  movzbl %dh,%ebx
  mov    %edx,%r9d
  not    %ecx
  lea    (%rsi,%r15,1),%r13
  mov    %ebx,%r8d
  movzwl %dx,%edx
  mov    %ecx,%edi
  movzbl %ch,%ecx
L15:
  mov    %dil,0x3(%rbp,%rax,1)
  cmp    %r13,%r14
  lea    0x5(%rax),%rbx
  mov    %r9b,0x1(%rbp,%rax,1)
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r8b,0x2(%rbp,%rax,1)
  mov    %cl,0x4(%rbp,%rax,1)
  setbe  0x0(%rbp,%rax,1)
  add    %r12,%rsi
  call   <memcpy@plt>
  cmp    %r13,%r14
  jbe    L31
  lea    (%rbx,%r15,1),%rax
  mov    %r13,%rsi
L8:
  lea    0xffff(%rsi),%r13
  cmp    %r14,%r13
  ja     L20
  mov    $0xffff,%edx
  xor    %ecx,%ecx
  xor    %edi,%edi
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%r9d
  mov    $0xffff,%r15d
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AddNonCompressedBlock(const unsigned char *in, size_t insize, unsigned char *out) {
  size_t pos = 0;
  size_t outpos = 0;
  for (;;) {
    unsigned short blocksize = 65535;
    unsigned short nlen;
    if (pos + blocksize > insize)
      blocksize = insize - pos;
    int currentfinal = pos + blocksize >= insize;
    nlen = ~blocksize;
    out[outpos] = currentfinal;
    out[outpos + 1] = blocksize % 256;
    out[outpos + 2] = blocksize / 256;
    out[outpos + 3] = nlen % 256;
    out[outpos + 4] = nlen / 256;
    outpos += 5;
    memcpy(out + outpos, in + pos, blocksize);
    if (currentfinal)
      break;
    pos += blocksize;
    outpos += blocksize;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AddNonCompressedBlock>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %rsi,%r14
  xor    %esi,%esi
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L10
  nopl   0x0(%rax)
L6:
  mov    %r14d,%edx
  sub    %esi,%edx
  mov    %edx,%ecx
  movzwl %dx,%r15d
  movzbl %dh,%ebx
  mov    %edx,%r9d
  not    %ecx
  lea    (%rsi,%r15,1),%r13
  mov    %ebx,%r8d
  movzwl %dx,%edx
  mov    %ecx,%edi
  movzbl %ch,%ecx
L12:
  mov    %dil,0x3(%rbp,%rax,1)
  cmp    %r13,%r14
  lea    0x5(%rax),%rbx
  mov    %r9b,0x1(%rbp,%rax,1)
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r8b,0x2(%rbp,%rax,1)
  mov    %cl,0x4(%rbp,%rax,1)
  setbe  0x0(%rbp,%rax,1)
  add    %r12,%rsi
  call   <memcpy@plt>
  cmp    %r13,%r14
  jbe    L13
  lea    (%rbx,%r15,1),%rax
  mov    %r13,%rsi
L10:
  lea    0xffff(%rsi),%r13
  cmp    %r14,%r13
  ja     L6
  mov    $0xffff,%edx
  xor    %ecx,%ecx
  xor    %edi,%edi
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%r9d
  mov    $0xffff,%r15d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AddNonCompressedBlock(const unsigned char *in, size_t insize, unsigned char *out) {
  size_t pos = 0;
  size_t outpos = 0;
  for (;;) {
    unsigned short blocksize = 65535;
    unsigned short nlen;
    if (pos + blocksize > insize)
      blocksize = insize - pos;
    int currentfinal = pos + blocksize >= insize;
    nlen = ~blocksize;
    out[outpos] = currentfinal;
    out[outpos + 1] = blocksize % 256;
    out[outpos + 2] = blocksize / 256;
    out[outpos + 3] = nlen % 256;
    out[outpos + 4] = nlen / 256;
    outpos += 5;
    memcpy(out + outpos, in + pos, blocksize);
    if (currentfinal)
      break;
    pos += blocksize;
    outpos += blocksize;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fatalError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void fatalError(char *fmt, ...) {
  va_list argp;
  va_start(argp, fmt);
  vfprintf(stderr, fmt, argp);
  va_end(argp);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fatalError>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fatalError(char *fmt, ...) {
  va_list argp;
  va_start(argp, fmt);
  vfprintf(stderr, fmt, argp);
  va_end(argp);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fatalError>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fatalError(char *fmt, ...) {
  va_list argp;
  va_start(argp, fmt);
  vfprintf(stderr, fmt, argp);
  va_end(argp);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<fatalError>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fatalError(char *fmt, ...) {
  va_list argp;
  va_start(argp, fmt);
  vfprintf(stderr, fmt, argp);
  va_end(argp);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<selectionSortArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L8:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L24:
  addl   $0x1,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L36
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L36:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L24
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L8
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int selectionSortArray(int N, int *a) {
  int count = 0;
  int jmin;
  for (int i = 0; i < N - 1; i++) {
    jmin = i;
    for (int j = i + 1; j < N; j++) {
      count++;
      if (a[j] < a[jmin]) {
        jmin = j;
      }
      swap(&a[i], &a[jmin]);
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<selectionSortArray>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  cmp    $0x1,%edi
  jle    L24
  mov    %edi,%eax
  mov    %rsi,%r12
  lea    -0x2(%rdi),%edx
  mov    %edx,0x18(%rsp)
  mov    %edx,%ecx
  mov    %rcx,0x10(%rsp)
  mov    $0x0,%r13d
  movl   $0x0,0x4(%rsp)
  sub    $0x1,%eax
  mov    %eax,0x1c(%rsp)
  jmp    L38
L21:
  mov    %rax,%r13
L38:
  mov    %r13d,0x8(%rsp)
  mov    %r13d,%ebp
  lea    0x1(%r13),%eax
  cmp    %eax,0xc(%rsp)
  jle    L43
  lea    (%r12,%r13,4),%r15
  lea    0x1(%r13),%rbx
  mov    0x18(%rsp),%eax
  sub    %r13d,%eax
  lea    0x2(%r13,%rax,1),%r14
L59:
  movslq %ebp,%rax
  mov    (%r12,%rax,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  cmovl  %ebx,%ebp
  movslq %ebp,%rax
  lea    (%r12,%rax,4),%rsi
  mov    %r15,%rdi
  call   <swap@plt>
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L59
  mov    0x4(%rsp),%eax
  add    0x1c(%rsp),%eax
  sub    0x8(%rsp),%eax
  mov    %eax,0x4(%rsp)
L43:
  lea    0x1(%r13),%rax
  cmp    0x10(%rsp),%r13
  jne    L21
L10:
  mov    0x4(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  movl   $0x0,0x4(%rsp)
  jmp    L10
```

assistant: ```c
int selectionSortArray(int N, int *a) {
  int count = 0;
  int jmin;
  for (int i = 0; i < N - 1; i++) {
    jmin = i;
    for (int j = i + 1; j < N; j++) {
      count++;
      if (a[j] < a[jmin]) {
        jmin = j;
      }
      swap(&a[i], &a[jmin]);
    }
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<selectionSortArray>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0x1c(%rsp)
  cmp    $0x1,%edi
  jle    L20
  mov    %edi,%eax
  lea    -0x2(%rdi),%ecx
  movl   $0x0,0xc(%rsp)
  mov    %rsi,%r15
  sub    $0x1,%eax
  mov    %ecx,0x28(%rsp)
  xor    %r13d,%r13d
  mov    %rcx,0x20(%rsp)
  mov    %eax,0x2c(%rsp)
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %r13d,0x18(%rsp)
  mov    %r13d,%ebx
  lea    0x1(%r13),%eax
  cmp    %eax,0x1c(%rsp)
  jle    L28
  lea    0x1(%r13),%rax
  lea    (%r15,%r13,4),%r12
  mov    %rax,0x10(%rsp)
  mov    %rax,%r14
  mov    0x28(%rsp),%eax
  sub    %r13d,%eax
  lea    0x2(%r13,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L49:
  movslq %ebx,%rax
  lea    (%r15,%r14,4),%rdi
  lea    (%r15,%rax,4),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%r15,%r14,4)
  jge    L7
  mov    %rdi,%rsi
  mov    %r14d,%ebx
L7:
  mov    %r12,%rdi
  add    $0x1,%r14
  call   <swap@plt>
  cmp    %rbp,%r14
  jne    L49
  mov    0xc(%rsp),%eax
  add    0x2c(%rsp),%eax
  sub    0x18(%rsp),%eax
  mov    %eax,0xc(%rsp)
L51:
  cmp    0x20(%rsp),%r13
  je     L54
  mov    0x10(%rsp),%r13
  jmp    L37
L20:
  movl   $0x0,0xc(%rsp)
L54:
  mov    0xc(%rsp),%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    0x1(%r13),%rax
  mov    %rax,0x10(%rsp)
  jmp    L51
```

assistant: ```c
int selectionSortArray(int N, int *a) {
  int count = 0;
  int jmin;
  for (int i = 0; i < N - 1; i++) {
    jmin = i;
    for (int j = i + 1; j < N; j++) {
      count++;
      if (a[j] < a[jmin]) {
        jmin = j;
      }
      swap(&a[i], &a[jmin]);
    }
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<selectionSortArray>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0x1c(%rsp)
  cmp    $0x1,%edi
  jle    L47
  mov    %edi,%eax
  movq   $0x0,(%rsp)
  lea    -0x2(%rdi),%ecx
  mov    %rsi,%r15
  sub    $0x1,%eax
  mov    %ecx,0x28(%rsp)
  mov    %eax,0x2c(%rsp)
  mov    (%rsp),%rax
  mov    %rcx,0x20(%rsp)
  mov    %eax,0xc(%rsp)
  add    $0x1,%eax
  movl   $0x0,0x18(%rsp)
  cmp    %eax,0x1c(%rsp)
  jle    L45
  nopl   0x0(%rax)
L87:
  mov    (%rsp),%rdx
  movslq 0xc(%rsp),%r13
  lea    0x1(%rdx),%rax
  lea    (%r15,%rdx,4),%rbp
  mov    %rax,0x10(%rsp)
  mov    %rax,%r14
  mov    0x28(%rsp),%eax
  sub    %edx,%eax
  lea    0x2(%rdx,%rax,1),%rbx
  nopl   0x0(%rax)
L46:
  lea    (%r15,%r13,4),%rsi
  mov    %r14d,%r12d
  lea    (%r15,%r14,4),%r8
  mov    (%rsi),%eax
  cmp    %eax,(%r15,%r14,4)
  jl     L94
  mov    %rbp,%rdi
  add    $0x1,%r14
  call   <swap@plt>
  cmp    %rbx,%r14
  jne    L46
L50:
  mov    0x18(%rsp),%r13d
  add    0x2c(%rsp),%r13d
  sub    0xc(%rsp),%r13d
  mov    0x20(%rsp),%rcx
  mov    %r13d,0x18(%rsp)
  cmp    %rcx,(%rsp)
  je     L80
L20:
  mov    0x10(%rsp),%rax
  mov    %rax,(%rsp)
  mov    %eax,0xc(%rsp)
  add    $0x1,%eax
  cmp    %eax,0x1c(%rsp)
  jg     L87
L45:
  mov    (%rsp),%rax
  mov    0x20(%rsp),%rcx
  add    $0x1,%rax
  mov    %rax,0x10(%rsp)
  cmp    %rcx,(%rsp)
  jne    L20
L80:
  mov    0x18(%rsp),%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L94:
  mov    %r8,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r14
  call   <swap@plt>
  cmp    %rbx,%r14
  je     L50
  movslq %r12d,%r13
  jmp    L46
L47:
  movl   $0x0,0x18(%rsp)
  jmp    L80
```

assistant: ```c
int selectionSortArray(int N, int *a) {
  int count = 0;
  int jmin;
  for (int i = 0; i < N - 1; i++) {
    jmin = i;
    for (int j = i + 1; j < N; j++) {
      count++;
      if (a[j] < a[jmin]) {
        jmin = j;
      }
      swap(&a[i], &a[jmin]);
    }
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<log_debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc8(%rbp),%rsi
  mov    %eax,%edi
  call   <_log_tag@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_debug(const char *src, const char *format, ...) {
  va_list args;
  va_start(args, format);
  _log_tag(LOG_DEBUG, src, format, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<log_debug>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <_log_tag@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_debug(const char *src, const char *format, ...) {
  va_list args;
  va_start(args, format);
  _log_tag(LOG_DEBUG, src, format, args);
  va_end(args);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log_debug>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <_log_tag@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void log_debug(const char *src, const char *format, ...) {
  va_list args;
  va_start(args, format);
  _log_tag(LOG_DEBUG, src, format, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<log_debug>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <_log_tag@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void log_debug(const char *src, const char *format, ...) {
  va_list args;
  va_start(args, format);
  _log_tag(LOG_DEBUG, src, format, args);
  va_end(args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Decrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%ebx
  mov    %esi,0x1c(%rsp)
  mov    %rdx,%r12
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <StrToMD5@plt>
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,0x18(%rsp)
  mov    %ebx,%r14d
  sub    %eax,%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  cmp    %ebx,%ebp
  jge    L26
  mov    %rax,%r15
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L3
L4:
  movsbl (%r12,%rbx,1),%eax
  add    %eax,%ebp
  add    $0x1,%rbx
L3:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L4
  mov    0x1c(%rsp),%ecx
  mov    %ecx,%eax
  sub    $0x1,%eax
  js     L39
  movslq %eax,%rdx
  mov    0x8(%rsp),%rbx
  add    %rbx,%rdx
  mov    %eax,%ecx
  sub    %r14d,%ecx
  mov    %r15,%rdi
  sub    %rbx,%rdi
  jmp    L94
L108:
  movslq 0x18(%rsp),%rdx
  mov    0x8(%rsp),%rax
  movzbl (%rax),%eax
  sub    -0x1(%r13,%rdx,1),%al
  sub    %ebp,%eax
  mov    %al,(%r15)
L39:
  lea    D4(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x10(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L95:
  movzbl (%rdx),%esi
  sub    %ebp,%esi
  sub    -0x1(%rdx),%sil
  movzbl %sil,%esi
  movslq %ecx,%r8
  movsbl 0x0(%r13,%r8,1),%r8d
  cmp    %r8d,%esi
  jne    L63
L86:
  sub    $0x1,%eax
  sub    $0x1,%rdx
  sub    $0x1,%ecx
  cmp    $0xffffffff,%eax
  je     L39
L94:
  test   %eax,%eax
  je     L108
  cmp    %eax,%r14d
  jle    L95
  movzbl (%rdx),%esi
  sub    %ebp,%esi
  sub    -0x1(%rdx),%sil
  mov    %sil,(%rdi,%rdx,1)
  jmp    L86
L26:
  movq   $0x0,0x10(%rsp)
  jmp    L9
L63:
  movq   $0x0,0x10(%rsp)
  jmp    L9
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: 


assistant: ```c
unsigned char *Decrypt(const unsigned char *puchData, int iSize, const char *pchPass) {
  int iSeed = 0;
  unsigned char *puchReturnData;
  char *pchCodeHash = StrToMD5(pchPass, (int)strlen(pchPass));
  int iHashSize = (int)strlen(pchCodeHash);
  puchReturnData = (unsigned char *)malloc(iSize - iHashSize);
  if (iSize <= iHashSize) {
    return NULL;
  }
  for (int i = 0; i < strlen(pchPass); ++i) {
    iSeed += pchPass[i];
  }
  for (int i = (iSize - 1); i >= 0; --i) {
    if (i == 0) {
      puchReturnData[i] = (unsigned char)(((int)puchData[i] - (int)pchCodeHash[iHashSize - 1] - iSeed) & 0xff);
    } else if (i < (iSize - iHashSize)) {
      puchReturnData[i] = (unsigned char)(((int)puchData[i] - (int)puchData[i - 1] - iSeed) & 0xff);
    } else {
      if ((unsigned char)(((int)puchData[i] - (int)puchData[i - 1] - iSeed) & 0xff) != pchCodeHash[i - (iSize - iHashSize)]) {
        return NULL;
      }
    }
  }
  printf("\n");
  return puchReturnData;
}
```