ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L4:
  mov    $0x0,%eax
  call   <E@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x9,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: 


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < 10; i++) {
    E();
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%ebx
  lea    D6(%rip),%rbp
L6:
  mov    $0x0,%eax
  call   <E@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: 


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < 10; i++) {
    E();
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <E@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string

tool: D9: 


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < 10; i++) {
    E();
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <E@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: 


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < 10; i++) {
    E();
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L38
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L22
L38:
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    D42(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L22
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read_string_safe@plt>
L22:
  leave
  ret
```

assistant: ```c
ssize_t read_string(int fd, char *buf, size_t size) {
  if (!buf) {
    errno = EINVAL;
    return (ssize_t)-errno;
  } else if (!size) {
    errno = ENOBUFS;
    return (ssize_t)-errno;
  }
  return read_string_safe(fd, buf, size);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_string>:
  endbr64
  test   %rsi,%rsi
  je     L13
  test   %rdx,%rdx
  jne    L1
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  mov    D17(%rip),%rdx
  mov    %eax,(%rdx)
  neg    %eax
  ret
L13:
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  mov    D17(%rip),%rdx
  mov    %eax,(%rdx)
  neg    %eax
  ret
L1:
  sub    $0x8,%rsp
  call   <read_string_safe@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
ssize_t read_string(int fd, char *buf, size_t size) {
  if (!buf) {
    errno = EINVAL;
    return (ssize_t)-errno;
  } else if (!size) {
    errno = ENOBUFS;
    return (ssize_t)-errno;
  }
  return read_string_safe(fd, buf, size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_string>:
  endbr64
  test   %rsi,%rsi
  je     L6
  test   %rdx,%rdx
  jne    L7
  mov    D1(%rip),%rax
  mov    D15(%rip),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  neg    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  jmp    1050 <read_string_safe@plt>
  nopl   (%rax)
L6:
  mov    D33(%rip),%rax
  mov    D15(%rip),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  neg    %eax
  ret
```

assistant: ```c
ssize_t read_string(int fd, char *buf, size_t size) {
  if (!buf) {
    errno = EINVAL;
    return (ssize_t)-errno;
  } else if (!size) {
    errno = ENOBUFS;
    return (ssize_t)-errno;
  }
  return read_string_safe(fd, buf, size);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_string>:
  endbr64
  test   %rsi,%rsi
  je     L7
  test   %rdx,%rdx
  jne    L10
  mov    D19(%rip),%rax
  mov    D31(%rip),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  neg    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  jmp    1050 <read_string_safe@plt>
  nopl   (%rax)
L7:
  mov    D23(%rip),%rax
  mov    D31(%rip),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  neg    %eax
  ret
```

assistant: ```c
ssize_t read_string(int fd, char *buf, size_t size) {
  if (!buf) {
    errno = EINVAL;
    return (ssize_t)-errno;
  } else if (!size) {
    errno = ENOBUFS;
    return (ssize_t)-errno;
  }
  return read_string_safe(fd, buf, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_virtual_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x17,%esi
  mov    %rax,%rdi
  call   <parse_stat@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L19
L11:
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <calculate_size@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L19:
  leave
  ret
```

assistant: ```c
char *get_virtual_memory(char *pid) {
  char *vm = parse_stat(pid, 23);
  if (vm == NULL)
    return NULL;
  char *vm_conv = calculate_size(vm, 0);
  return vm_conv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_virtual_memory>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17,%esi
  call   <parse_stat@plt>
  test   %rax,%rax
  je     L5
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <calculate_size@plt>
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_virtual_memory(char *pid) {
  char *vm = parse_stat(pid, 23);
  if (vm == NULL)
    return NULL;
  char *vm_conv = calculate_size(vm, 0);
  return vm_conv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_virtual_memory>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17,%esi
  call   <parse_stat@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  xor    %esi,%esi
  add    $0x8,%rsp
  jmp    1060 <calculate_size@plt>
  nopl   (%rax)
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_virtual_memory(char *pid) {
  char *vm = parse_stat(pid, 23);
  if (vm == NULL)
    return NULL;
  char *vm_conv = calculate_size(vm, 0);
  return vm_conv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_virtual_memory>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17,%esi
  call   <parse_stat@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  xor    %esi,%esi
  add    $0x8,%rsp
  jmp    1060 <calculate_size@plt>
  nopl   (%rax)
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_virtual_memory(char *pid) {
  char *vm = parse_stat(pid, 23);
  if (vm == NULL)
    return NULL;
  char *vm_conv = calculate_size(vm, 0);
  return vm_conv;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,-0x8(%rbp)
  jmp    L7
L18:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <estimate_pi@plt>
  movq   %xmm0,%rax
  mov    -0x4(%rbp),%edx
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0x8,-0x8(%rbp)
  jle    L18
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D7: No. of points: %d, Pi: %f


assistant: ```c
int main(void) {
  int i, N;
  srand(time(NULL));
  for (i = 1; i < 9; i++) {
    N = (int)pow(10, i);
    printf("No. of points: %d, Pi: %f\n", N, estimate_pi(N));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x1,%ebp
  lea    D1(%rip),%r12
L8:
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <estimate_pi@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    $0x9,%ebp
  jne    L8
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D1
type: string

tool: D1: No. of points: %d, Pi: %f


assistant: ```c
int main(void) {
  int i, N;
  srand(time(NULL));
  for (i = 1; i < 9; i++) {
    N = (int)pow(10, i);
    printf("No. of points: %d, Pi: %f\n", N, estimate_pi(N));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%esi
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <pow@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <estimate_pi@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x9,%ebx
  jne    L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string

tool: D5: No. of points: %d, Pi: %f


assistant: ```c
int main(void) {
  int i, N;
  srand(time(NULL));
  for (i = 1; i < 9; i++) {
    N = (int)pow(10, i);
    printf("No. of points: %d, Pi: %f\n", N, estimate_pi(N));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%esi
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <pow@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <estimate_pi@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x9,%ebx
  jne    L2
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: No. of points: %d, Pi: %f


assistant: ```c
int main(void) {
  int i, N;
  srand(time(NULL));
  for (i = 1; i < 9; i++) {
    N = (int)pow(10, i);
    printf("No. of points: %d, Pi: %f\n", N, estimate_pi(N));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string2uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L20
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L9
L20:
  mov    -0x8(%rbp),%rax
  movb   $0x30,(%rax)
L9:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,-0x10(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t string2uint64(char *s) {
  uint64_t u = 0;
  char *p = s;
  while (*p) {
    if (*p < '0' || *p > '9')
      *p = '0';
    u = 10LL * u + (*p++ - 48);
  }
  return u;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string2uint64>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  mov    $0x0,%edx
  jmp    L14
L46:
  lea    (%rdx,%rdx,4),%rdx
  add    $0x1,%rdi
  movsbl -0x1(%rdi),%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
L14:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L46
  movb   $0x30,(%rdi)
  jmp    L46
L12:
  mov    $0x0,%edx
L3:
  mov    %rdx,%rax
  ret
```

assistant: ```c
uint64_t string2uint64(char *s) {
  uint64_t u = 0;
  char *p = s;
  while (*p) {
    if (*p < '0' || *p > '9')
      *p = '0';
    u = 10LL * u + (*p++ - 48);
  }
  return u;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<string2uint64>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L20
  jmp    L28
L39:
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  cltq
L43:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
L20:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L39
  movb   $0x30,(%rdi)
  xor    %eax,%eax
  jmp    L43
  nopl   0x0(%rax)
L28:
  mov    %r8,%rax
  ret
```

assistant: ```c
uint64_t string2uint64(char *s) {
  uint64_t u = 0;
  char *p = s;
  while (*p) {
    if (*p < '0' || *p > '9')
      *p = '0';
    u = 10LL * u + (*p++ - 48);
  }
  return u;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string2uint64>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L3
  xchg   %ax,%ax
L35:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L17
  movsbq %al,%rax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L35
L3:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  movb   $0x30,(%rdi)
  movzbl 0x1(%rdi),%eax
  lea    (%r8,%r8,4),%r8
  add    $0x1,%rdi
  add    %r8,%r8
  test   %al,%al
  jne    L35
  mov    %r8,%rax
  ret
```

assistant: ```c
uint64_t string2uint64(char *s) {
  uint64_t u = 0;
  char *p = s;
  while (*p) {
    if (*p < '0' || *p > '9')
      *p = '0';
    u = 10LL * u + (*p++ - 48);
  }
  return u;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movw   $0xffff,-0xa(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L9:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  movsbl -0xb(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  xor    %edx,%eax
  mov    %ax,-0xa(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L58
L21:
  movzwl -0xa(%rbp),%eax
  test   %ax,%ax
  jns    L23
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  xor    $0x1021,%ax
  mov    %ax,-0xa(%rbp)
  jmp    L5
L23:
  shlw   -0xa(%rbp)
L5:
  addl   $0x1,-0x4(%rbp)
L58:
  cmpl   $0x7,-0x4(%rbp)
  jle    L21
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  movzwl -0xa(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short checksum(const char *key, int len) {
  unsigned short crc = 0xFFFF;
  int i, j;
  for (i = 0; i < len; ++i) {
    char data = key[i];
    crc = crc ^ (data << 8);
    for (j = 0; j < 8; ++j) {
      if ((crc & 0x8000) != 0) {
        crc = (crc << 1) ^ 0x1021;
      } else {
        crc <<= 1;
      }
    }
  }
  return crc;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checksum>:
  endbr64
  test   %esi,%esi
  jle    L21
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rdi
  mov    $0xffffffff,%eax
  jmp    L2
L27:
  add    $0x1,%r8
  cmp    %rdi,%r8
  je     L7
L2:
  movsbl (%r8),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%ecx
L32:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  lea    (%rax,%rax,1),%esi
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%ecx
  jne    L32
  jmp    L27
L7:
  ret
L21:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short checksum(const char *key, int len) {
  unsigned short crc = 0xFFFF;
  int i, j;
  for (i = 0; i < len; ++i) {
    char data = key[i];
    crc = crc ^ (data << 8);
    for (j = 0; j < 8; ++j) {
      if ((crc & 0x8000) != 0) {
        crc = (crc << 1) ^ 0x1021;
      } else {
        crc <<= 1;
      }
    }
  }
  return crc;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checksum>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r8
  mov    $0xffffffff,%eax
  nopl   (%rax)
L20:
  movsbl (%rdi),%edx
  mov    $0x8,%ecx
  shl    $0x8,%edx
  xor    %edx,%eax
  nopl   (%rax)
L18:
  lea    (%rax,%rax,1),%edx
  lea    (%rax,%rax,1),%esi
  xor    $0x1021,%dx
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%ecx
  jne    L18
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L20
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short checksum(const char *key, int len) {
  unsigned short crc = 0xFFFF;
  int i, j;
  for (i = 0; i < len; ++i) {
    char data = key[i];
    crc = crc ^ (data << 8);
    for (j = 0; j < 8; ++j) {
      if ((crc & 0x8000) != 0) {
        crc = (crc << 1) ^ 0x1021;
      } else {
        crc <<= 1;
      }
    }
  }
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checksum>:
  endbr64
  test   %esi,%esi
  jle    L51
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rcx
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0xffffffff,%eax
  jmp    L132
  xchg   %ax,%ax
L118:
  lea    (%rax,%rax,1),%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L156
L99:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L87
L44:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L126
L83:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L108
L48:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L9
L117:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L23
L31:
  add    %edx,%edx
  mov    %edx,%edi
L4:
  lea    (%rdx,%rdx,1),%r8d
  mov    %r8d,%eax
  xor    $0x1021,%ax
  test   %di,%di
  mov    %eax,%edx
  mov    %r8d,%eax
  cmovs  %edx,%eax
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  je     L169
L132:
  movsbl (%rcx),%edx
  shl    $0x8,%edx
  xor    %dx,%ax
  jns    L118
  add    %eax,%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L99
L156:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L44
L87:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L83
L126:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L48
L108:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L117
L9:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L31
L23:
  lea    (%rdx,%rdx,1),%edi
  xor    $0x1021,%di
  mov    %edi,%edx
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L169:
  ret
L51:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short checksum(const char *key, int len) {
  unsigned short crc = 0xFFFF;
  int i, j;
  for (i = 0; i < len; ++i) {
    char data = key[i];
    crc = crc ^ (data << 8);
    for (j = 0; j < 8; ++j) {
      if ((crc & 0x8000) != 0) {
        crc = (crc << 1) ^ 0x1021;
      } else {
        crc <<= 1;
      }
    }
  }
  return crc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_notice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vsyslog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_notice(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(LOG_NOTICE, format, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<log_notice>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void log_notice(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(LOG_NOTICE, format, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log_notice>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_notice(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(LOG_NOTICE, format, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_notice>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_notice(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsyslog(LOG_NOTICE, format, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<b_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L19:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x20(%rbp),%edx
  mov    %dl,(%rax)
L6:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void b_set(void *x, int n, char c) {
  char *b = x;
  while (n--) {
    *b++ = c;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<b_set>:
  endbr64
  test   %esi,%esi
  je     L19
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rax
L5:
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  cmp    %rax,%rdi
  jne    L5
L19:
  ret
```

assistant: ```c
void b_set(void *x, int n, char c) {
  char *b = x;
  while (n--) {
    *b++ = c;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<b_set>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %esi,%esi
  je     L4
  lea    0x1(%rax),%r8
  movsbl %dl,%esi
  mov    %r8,%rdx
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void b_set(void *x, int n, char c) {
  char *b = x;
  while (n--) {
    *b++ = c;
  }
}
```