user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0xffffffff,-0x18(%rbp)
  jmp    L111
L54:
  mov    -0x18(%rbp),%eax
  cmp    $0xffffffff,%eax
  jne    L102
  mov    $0x0,%eax
  call   <menu@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L111
L102:
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jne    L111
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x9,-0x10(%rbp)
L124:
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x64,%edx
  mov    $0x0,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  js     L40
  mov    -0x14(%rbp),%eax
  cmp    $0x64,%eax
  jg     L40
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L29
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L135
L29:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L135
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L135:
  subl   $0x1,-0x10(%rbp)
  jmp    L22
L40:
  nop
L22:
  cmpl   $0x0,-0x10(%rbp)
  je     L120
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L124
L120:
  cmpl   $0x0,-0x10(%rbp)
  jne    L149
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L157
L149:
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L157:
  movl   $0xffffffff,-0x18(%rbp)
L111:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L54
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D32
type_guessed: string
name: parse_data
arguments: label: D31
type_guessed: string
name: parse_data
arguments: label: D60
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string
name: parse_data
arguments: label: D51
type_guessed: string
name: parse_data
arguments: label: D44
type_guessed: string

tool: D32: %d

tool: D31: Try a value [%d - %d], %d lives remaining :


tool: D60: Try more (+) !


tool: D12: Try less (-) !


tool: D51: You loose, mystery number was %d


tool: D44: Congratulations, you win !

assistant: ```c
int main(void) {
  srand(time(NULL));
  int menu_choice = -1;
  while (menu_choice) {
    if (menu_choice == -1) {
      menu();
      scanf("%d", &menu_choice);
    } else if (menu_choice == 1) {
      int mystery_num = rand() % (100 - 0) + 0;
      int try;
      int lives = 9;
      do {
        printf("Try a value [%d - %d], %d lives remaining :\n", 0, 100, lives);
        scanf("%d", &try);
        if (try < 0 || try > 100) {
          continue;
        } else {
          if (try < mystery_num) {
            printf("Try more (+) !\n\n");
          } else if (try > mystery_num) {
            printf("Try less (-) !\n\n");
          }
          lives--;
        }
      } while (lives != 0 && try != mystery_num);
      if (!lives) {
        printf("You loose, mystery number was %d\n", mystery_num);
      } else {
        printf("Congratulations, you win !\n");
      }
      menu_choice = -1;
    }
  }
  return 0;
}
```