ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<writeppm48>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fopen@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L29
  mov    $0x1,%eax
  jmp    L10
L29:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x30(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L45
L6:
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x30(%rbp),%edx
  sub    -0x18(%rbp),%edx
  sub    $0x1,%edx
  imul   -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  je     L3
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fclose@plt>
  mov    $0x5,%eax
  jmp    L10
L3:
  addl   $0x1,-0x18(%rbp)
L45:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L6
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fclose@plt>
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D22
type: string

tool: D28: wb

tool: D15: P6


tool: D8: %d %d


tool: D22: 65535


assistant: ```c
signed int writeppm48(char *name, signed int xres, signed int yres, unsigned char *imgdata) {
  struct _IO_FILE$link40 *ofp;
  signed int y;
  signed int xbytes = 6 * xres;
  ofp = fopen(name, "wb");
  if (ofp == ((struct _IO_FILE$link40 *)((void *)0)))
    return 1;
  fprintf(ofp, "P6\n");
  fprintf(ofp, "%d %d\n", xres, yres);
  fprintf(ofp, "65535\n");
  y = 0;
  while (!(y >= yres)) {
    unsigned long int return_value_fwrite$1;
    return_value_fwrite$1 = fwrite((const void *)&imgdata[(signed long int)(((yres - y) - 1) * xbytes)], (unsigned long int)1, (unsigned long int)xbytes, ofp);
    if (!(return_value_fwrite$1 == (unsigned long int)xbytes)) {
      fclose(ofp);
      return 5;
    }
    y = y + 1;
  }
  fclose(ofp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writeppm48>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %rcx,%rbx
  lea    D29(%rip),%rsi
  mov    $0x0,%eax
  call   <fopen@plt>
  mov    $0x1,%edx
  test   %eax,%eax
  jne    L34
L53:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  movslq %eax,%r13
  mov    %r13,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D34(%rip),%rdi
  call   <fwrite@plt>
  mov    %r14d,%ecx
  mov    %ebp,%edx
  lea    D13(%rip),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %r13,%rcx
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <fwrite@plt>
  test   %r14d,%r14d
  jle    L42
  lea    0x0(%rbp,%rbp,2),%r12d
  add    %r12d,%r12d
  mov    %r12d,%r15d
  neg    %r15d
  movslq %r15d,%r15
  lea    -0x1(%r14),%eax
  imul   %r12d,%eax
  cltq
  add    %rax,%rbx
  mov    $0x0,%ebp
  movslq %r12d,%r12
L28:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  cmp    %rax,%r12
  jne    L59
  add    $0x1,%ebp
  add    %r15,%rbx
  cmp    %ebp,%r14d
  jne    L28
L42:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <fclose@plt>
  mov    $0x0,%edx
  jmp    L53
L59:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <fclose@plt>
  mov    $0x5,%edx
  jmp    L53
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
data_type: string
name: disassemble_data
arguments: data_tag: D34
data_type: string
name: disassemble_data
arguments: data_tag: D13
data_type: string
name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D29: wb

tool: D34: P6


tool: D13: %d %d


tool: D7: 65535


assistant: ```c
signed int writeppm48(char *name, signed int xres, signed int yres, unsigned char *imgdata) {
  struct _IO_FILE$link40 *ofp;
  signed int y;
  signed int xbytes = 6 * xres;
  ofp = fopen(name, "wb");
  if (ofp == ((struct _IO_FILE$link40 *)((void *)0)))
    return 1;
  fprintf(ofp, "P6\n");
  fprintf(ofp, "%d %d\n", xres, yres);
  fprintf(ofp, "65535\n");
  y = 0;
  while (!(y >= yres)) {
    unsigned long int return_value_fwrite$1;
    return_value_fwrite$1 = fwrite((const void *)&imgdata[(signed long int)(((yres - y) - 1) * xbytes)], (unsigned long int)1, (unsigned long int)xbytes, ofp);
    if (!(return_value_fwrite$1 == (unsigned long int)xbytes)) {
      fclose(ofp);
      return 5;
    }
    y = y + 1;
  }
  fclose(ofp);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<writeppm48>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  lea    D25(%rip),%rsi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    $0x1,%r8d
  test   %eax,%eax
  jne    L36
L13:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L36:
  movslq %eax,%r12
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r12,%rcx
  lea    D12(%rip),%rdi
  call   <fwrite@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12,%rdi
  lea    D39(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <fwrite@plt>
  test   %r13d,%r13d
  jle    L57
  lea    0x0(%rbp,%rbp,2),%edx
  lea    -0x1(%r13),%eax
  xor    %ebp,%ebp
  add    %edx,%edx
  imul   %edx,%eax
  mov    %edx,%r14d
  movslq %edx,%r15
  neg    %r14d
  movslq %r14d,%r14
  cltq
  add    %rax,%rbx
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%ebp
  add    %r14,%rbx
  cmp    %ebp,%r13d
  je     L57
L6:
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  cmp    %r15,%rax
  je     L35
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fclose@plt>
  mov    $0x5,%r8d
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fclose@plt>
  xor    %r8d,%r8d
  jmp    L13
```

tool_calls: name: parse_data
arguments: data_tag: D25
type: string
name: parse_data
arguments: data_tag: D12
type: string
name: parse_data
arguments: data_tag: D39
type: string
name: parse_data
arguments: data_tag: D6
type: string

tool: D25: wb

tool: D12: P6


tool: D39: %d %d


tool: D6: 65535


assistant: ```c
signed int writeppm48(char *name, signed int xres, signed int yres, unsigned char *imgdata) {
  struct _IO_FILE$link40 *ofp;
  signed int y;
  signed int xbytes = 6 * xres;
  ofp = fopen(name, "wb");
  if (ofp == ((struct _IO_FILE$link40 *)((void *)0)))
    return 1;
  fprintf(ofp, "P6\n");
  fprintf(ofp, "%d %d\n", xres, yres);
  fprintf(ofp, "65535\n");
  y = 0;
  while (!(y >= yres)) {
    unsigned long int return_value_fwrite$1;
    return_value_fwrite$1 = fwrite((const void *)&imgdata[(signed long int)(((yres - y) - 1) * xbytes)], (unsigned long int)1, (unsigned long int)xbytes, ofp);
    if (!(return_value_fwrite$1 == (unsigned long int)xbytes)) {
      fclose(ofp);
      return 5;
    }
    y = y + 1;
  }
  fclose(ofp);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writeppm48>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  lea    D27(%rip),%rsi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    $0x1,%r8d
  test   %eax,%eax
  jne    L21
L11:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  movslq %eax,%r12
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r12,%rcx
  lea    D36(%rip),%rdi
  call   <fwrite@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12,%rdi
  lea    D3(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  call   <fwrite@plt>
  test   %r13d,%r13d
  jle    L42
  lea    0x0(%rbp,%rbp,2),%edx
  lea    -0x1(%r13),%eax
  xor    %ebp,%ebp
  add    %edx,%edx
  imul   %edx,%eax
  mov    %edx,%r14d
  movslq %edx,%r15
  neg    %r14d
  movslq %r14d,%r14
  cltq
  add    %rax,%rbx
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L68:
  add    $0x1,%ebp
  add    %r14,%rbx
  cmp    %ebp,%r13d
  je     L42
L64:
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  cmp    %r15,%rax
  je     L68
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fclose@plt>
  mov    $0x5,%r8d
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fclose@plt>
  xor    %r8d,%r8d
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D36
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string

tool: D27: wb

tool: D36: P6


tool: D3: %d %d


tool: D5: 65535


assistant: ```c
signed int writeppm48(char *name, signed int xres, signed int yres, unsigned char *imgdata) {
  struct _IO_FILE$link40 *ofp;
  signed int y;
  signed int xbytes = 6 * xres;
  ofp = fopen(name, "wb");
  if (ofp == ((struct _IO_FILE$link40 *)((void *)0)))
    return 1;
  fprintf(ofp, "P6\n");
  fprintf(ofp, "%d %d\n", xres, yres);
  fprintf(ofp, "65535\n");
  y = 0;
  while (!(y >= yres)) {
    unsigned long int return_value_fwrite$1;
    return_value_fwrite$1 = fwrite((const void *)&imgdata[(signed long int)(((yres - y) - 1) * xbytes)], (unsigned long int)1, (unsigned long int)xbytes, ofp);
    if (!(return_value_fwrite$1 == (unsigned long int)xbytes)) {
      fclose(ofp);
      return 5;
    }
    y = y + 1;
  }
  fclose(ofp);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<firstTerm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <firstFactor@plt>
  mov    $0x0,%eax
  call   <term1@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void firstTerm() {
  firstFactor();
  term1();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<firstTerm>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <firstFactor@plt>
  mov    $0x0,%eax
  call   <term1@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void firstTerm() {
  firstFactor();
  term1();
}
```
user: What is the c source code of the assembly code below?

```asm
<firstTerm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <firstFactor@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <term1@plt>
```

assistant: ```c
void firstTerm() {
  firstFactor();
  term1();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<firstTerm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <firstFactor@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <term1@plt>
```

assistant: ```c
void firstTerm() {
  firstFactor();
  term1();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<edit_distn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rdx,%rbx
  mov    %rcx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
L35:
  mov    %eax,(%rsp,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%r8
  jne    L35
  test   %r11,%r11
  je     L60
  mov    $0x1,%ebp
  lea    0x104(%rsp),%rsi
  mov    %rsp,%rdi
  jmp    L58
L13:
  mov    %rax,%rbp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rax,%rsi
L58:
  mov    %ebp,(%rsi)
  test   %r8,%r8
  je     L34
  movzbl -0x1(%r10,%rbp,1),%r9d
  mov    $0x0,%edx
L31:
  add    $0x1,%rdx
  mov    (%rdi,%rdx,4),%eax
  add    $0x1,%eax
  mov    -0x4(%rsi,%rdx,4),%ecx
  add    $0x1,%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  cmp    %r9b,-0x1(%rbx,%rdx,1)
  setne  %r12b
  movzbl %r12b,%r12d
  mov    -0x4(%rdi,%rdx,4),%ecx
  lea    (%rcx,%r12,2),%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%rsi,%rdx,4)
  cmp    %r8,%rdx
  jne    L31
L34:
  lea    0x1(%rbp),%rax
  cmp    %rbp,%r11
  jne    L13
L1:
  mov    (%rsi,%r8,4),%eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L73
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L60:
  mov    %rsp,%rsi
  jmp    L1
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int edit_distn(const char *s1, size_t s1len, const char *s2, size_t s2len) {
  int t[2][64 + 1];
  int *t1 = t[0];
  int *t2 = t[1];
  int *t3;
  size_t i1, i2;
  for (i2 = 0; i2 <= s2len; i2++)
    t[0][i2] = i2 * 1;
  for (i1 = 0; i1 < s1len; i1++) {
    t2[0] = (i1 + 1) * 1;
    for (i2 = 0; i2 < s2len; i2++) {
      int cost_a = t1[i2 + 1] + 1;
      int cost_d = t2[i2] + 1;
      int cost_r = t1[i2] + (s1[i1] == s2[i2] ? 0 : 2);
      t2[i2 + 1] = ((((cost_a) < (cost_d) ? (cost_a) : (cost_d))) < (cost_r) ? (((cost_a) < (cost_d) ? (cost_a) : (cost_d))) : (cost_r));
    }
    t3 = t1;
    t1 = t2;
    t2 = t3;
  }
  return t1[s2len];
}
```
user: Translate the below assembly code into C programming language:

```asm
<edit_distn>:
  endbr64
  push   %r12
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rcx,%r9
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  nopl   0x0(%rax)
L26:
  mov    %rax,%rdx
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%r9
  jne    L26
  test   %r11,%r11
  je     L11
  mov    $0x1,%ebp
  lea    0x104(%rsp),%r8
  nopl   0x0(%rax)
L42:
  mov    %ebp,(%r8)
  mov    %ebp,%ecx
  test   %r9,%r9
  je     L32
  movzbl -0x1(%r10,%rbp,1),%r12d
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L65:
  add    $0x1,%rdx
  xor    %esi,%esi
  mov    -0x4(%rdi,%rdx,4),%eax
  cmp    %r12b,-0x1(%rbx,%rdx,1)
  setne  %sil
  add    $0x1,%ecx
  lea    (%rax,%rsi,2),%esi
  mov    (%rdi,%rdx,4),%eax
  add    $0x1,%eax
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  cmp    %eax,%esi
  cmovle %esi,%eax
  mov    %eax,(%r8,%rdx,4)
  mov    %eax,%ecx
  cmp    %r9,%rdx
  jne    L65
L32:
  lea    0x1(%rbp),%rax
  cmp    %rbp,%r11
  je     L31
  mov    %rax,%rbp
  mov    %rdi,%rax
  mov    %r8,%rdi
  mov    %rax,%r8
  jmp    L42
L11:
  mov    %rdi,%r8
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    (%r8,%r9,4),%eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int edit_distn(const char *s1, size_t s1len, const char *s2, size_t s2len) {
  int t[2][64 + 1];
  int *t1 = t[0];
  int *t2 = t[1];
  int *t3;
  size_t i1, i2;
  for (i2 = 0; i2 <= s2len; i2++)
    t[0][i2] = i2 * 1;
  for (i1 = 0; i1 < s1len; i1++) {
    t2[0] = (i1 + 1) * 1;
    for (i2 = 0; i2 < s2len; i2++) {
      int cost_a = t1[i2 + 1] + 1;
      int cost_d = t2[i2] + 1;
      int cost_r = t1[i2] + (s1[i1] == s2[i2] ? 0 : 2);
      t2[i2 + 1] = ((((cost_a) < (cost_d) ? (cost_a) : (cost_d))) < (cost_r) ? (((cost_a) < (cost_d) ? (cost_a) : (cost_d))) : (cost_r));
    }
    t3 = t1;
    t1 = t2;
    t2 = t3;
  }
  return t1[s2len];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%esi
  mov    -0x28(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <__syscall@plt>
  add    $0x10,%rsp
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L13
L17:
  mov    -0x4(%rbp),%eax
L13:
  leave
  ret
```

assistant: ```c
ssize_t write(int fd, const void *buf, size_t count) {
  int ret = __syscall(1, fd, (uint64_t)buf, count, 0, 0, 0);
  if (ret < 0) {
    errno = -ret;
    return -1;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write>:
  endbr64
  sub    $0x10,%rsp
  mov    %rdx,%rcx
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %esi,%edx
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <__syscall@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  js     L9
L19:
  add    $0x8,%rsp
  ret
L9:
  neg    %eax
  mov    D2(%rip),%rdx
  mov    %eax,(%rdx)
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
ssize_t write(int fd, const void *buf, size_t count) {
  int ret = __syscall(1, fd, (uint64_t)buf, count, 0, 0, 0);
  if (ret < 0) {
    errno = -ret;
    return -1;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write>:
  endbr64
  sub    $0x10,%rsp
  mov    %rdx,%rcx
  xor    %r9d,%r9d
  mov    %esi,%edx
  push   $0x0
  mov    %edi,%esi
  xor    %r8d,%r8d
  mov    $0x1,%edi
  call   <__syscall@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  js     L4
L1:
  add    $0x8,%rsp
  ret
L4:
  mov    D9(%rip),%rdx
  neg    %eax
  mov    %eax,(%rdx)
  mov    $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
ssize_t write(int fd, const void *buf, size_t count) {
  int ret = __syscall(1, fd, (uint64_t)buf, count, 0, 0, 0);
  if (ret < 0) {
    errno = -ret;
    return -1;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write>:
  endbr64
  sub    $0x10,%rsp
  mov    %rdx,%rcx
  xor    %r9d,%r9d
  mov    %esi,%edx
  push   $0x0
  mov    %edi,%esi
  xor    %r8d,%r8d
  mov    $0x1,%edi
  call   <__syscall@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  js     L7
L14:
  add    $0x8,%rsp
  ret
L7:
  mov    D7(%rip),%rdx
  neg    %eax
  mov    %eax,(%rdx)
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
ssize_t write(int fd, const void *buf, size_t count) {
  int ret = __syscall(1, fd, (uint64_t)buf, count, 0, 0, 0);
  if (ret < 0) {
    errno = -ret;
    return -1;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<algo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  jmp    L94
L19:
  movl   $0x0,-0x14(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  jmp    L97
L106:
  movl   $0xffffffff,-0x18(%rbp)
  jmp    L65
L52:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L71
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xb,%al
  jne    L65
L71:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <get_value@plt>
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  cmp    %dl,%al
  je     L65
  addl   $0x1,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <get_value@plt>
  mov    %al,(%rbx)
L65:
  addl   $0x1,-0x18(%rbp)
  cmpl   $0x8,-0x18(%rbp)
  jle    L52
L97:
  addl   $0x1,-0x1c(%rbp)
  cmpl   $0x8,-0x1c(%rbp)
  jle    L106
  cmpl   $0x0,-0x14(%rbp)
  jne    L94
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <check_per_square@plt>
  cmp    $0xffffffff,%eax
  jne    L94
  mov    $0xffffffff,%eax
  jmp    L8
L94:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <is_solved@plt>
  test   %eax,%eax
  je     L19
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int algo(char **map) {
  int i;
  int j;
  int status;
  while (!is_solved(map)) {
    status = 0;
    i = -1;
    while (++i < 9) {
      j = -1;
      while (++j < 9) {
        if ((map[i][j] == 0 || map[i][j] == 11) && get_value(i, j, map) != map[i][j]) {
          ++status;
          map[i][j] = get_value(i, j, map);
        }
      }
    }
    if (status == 0 && check_per_square(map) == -1)
      return (-1);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<algo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
L122:
  mov    %r15,%rdi
  call   <is_solved@plt>
  mov    %eax,%r14d
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jne    L94
  mov    %r15,%rbp
  jmp    L85
L55:
  mov    %r15,%rdx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <get_value@plt>
  mov    %rbx,%rcx
  add    0x0(%r13),%rcx
  mov    %rcx,%r13
  cmp    (%rcx),%al
  jne    L38
L97:
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  je     L92
L102:
  mov    %ebx,%r12d
  mov    %rbp,%r13
  mov    0x0(%rbp),%rax
  movzbl (%rax,%rbx,1),%eax
  test   %al,%al
  je     L55
  cmp    $0xb,%al
  jne    L97
  jmp    L55
L38:
  addl   $0x1,0xc(%rsp)
  mov    %r15,%rdx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <get_value@plt>
  mov    %al,0x0(%r13)
  jmp    L97
L92:
  add    $0x1,%r14d
  add    $0x8,%rbp
  cmp    $0x9,%r14d
  je     L49
L85:
  mov    $0x0,%ebx
  jmp    L102
L49:
  cmpl   $0x0,0xc(%rsp)
  jne    L122
  mov    %r15,%rdi
  call   <check_per_square@plt>
  cmp    $0xffffffff,%eax
  jne    L122
L41:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L94:
  mov    $0x0,%eax
  jmp    L41
```

assistant: ```c
int algo(char **map) {
  int i;
  int j;
  int status;
  while (!is_solved(map)) {
    status = 0;
    i = -1;
    while (++i < 9) {
      j = -1;
      while (++j < 9) {
        if ((map[i][j] == 0 || map[i][j] == 11) && get_value(i, j, map) != map[i][j]) {
          ++status;
          map[i][j] = get_value(i, j, map);
        }
      }
    }
    if (status == 0 && check_per_square(map) == -1)
      return (-1);
  }
  return (0);
}
```