ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  lea    -0x34(%rbp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L80:
  cmp    %rcx,%rsp
  je     L42
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L80
L42:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L38
  orq    $0x0,-0x8(%rsp,%rax,1)
L38:
  mov    %rsp,%r12
  shl    $0x2,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0x34(%rbp)
  jle    L85
  mov    $0x0,%ebx
  lea    D3(%rip),%r13
L77:
  lea    -0x2c(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,-0x34(%rbp)
  jg     L77
L85:
  lea    -0x30(%rbp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%edx
  test   %edx,%edx
  jle    L23
  mov    -0x30(%rbp),%edi
  mov    %r12,%rax
  mov    %edx,%edx
  lea    (%r12,%rdx,4),%rcx
  mov    $0x0,%esi
L89:
  cmp    %edi,(%rax)
  setne  %dl
  movzbl %dl,%edx
  add    %edx,%esi
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L89
L34:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    $0x0,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L23:
  mov    $0x0,%esi
  jmp    L34
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string
name: extract_symbolic_data
arguments: tag: D37
data_type: string

tool: D3: %d

tool: D37: %d


assistant: ```c
int main() {
  int a = 0, b = 0, c = 0, counter = 0;
  scanf("%d", &a);
  int arr[a];
  memset(arr, 0, sizeof(arr));
  for (int count = 0; count < a; ++count) {
    scanf("%d", &c);
    arr[count] = c;
  }
  scanf("%d", &b);
  for (int cc = 0; cc < a; ++cc) {
    if (arr[cc] != b)
      ++counter;
  }
  printf("%d\n", counter);
  counter = 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D2(%rip),%r13
  lea    -0x34(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  call   <scanf@plt>
  movslq -0x34(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L76
L16:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L16
L76:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L64
L67:
  mov    %rsp,%rbx
  shl    $0x2,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0x34(%rbp)
  jle    L27
  xor    %r12d,%r12d
  lea    -0x2c(%rbp),%r14
  nopl   (%rax)
L56:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,(%rbx,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,-0x34(%rbp)
  jg     L56
L27:
  lea    -0x30(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%edx
  test   %edx,%edx
  jle    L34
  mov    -0x30(%rbp),%edi
  mov    %rbx,%rax
  lea    (%rbx,%rdx,4),%rcx
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L93:
  xor    %edx,%edx
  cmp    %edi,(%rax)
  setne  %dl
  add    $0x4,%rax
  add    %edx,%esi
  cmp    %rcx,%rax
  jne    L93
L7:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L64:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L67
L34:
  xor    %esi,%esi
  jmp    L7
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D2: %d

tool: D6: %d


assistant: ```c
int main() {
  int a = 0, b = 0, c = 0, counter = 0;
  scanf("%d", &a);
  int arr[a];
  memset(arr, 0, sizeof(arr));
  for (int count = 0; count < a; ++count) {
    scanf("%d", &c);
    arr[count] = c;
  }
  scanf("%d", &b);
  for (int cc = 0; cc < a; ++cc) {
    if (arr[cc] != b)
      ++counter;
  }
  printf("%d\n", counter);
  counter = 0;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <hog@plt>
  mov    $0x0,%eax
  call   <hog@plt>
  mov    $0x0,%eax
  call   <hog@plt>
  mov    $0x0,%eax
  call   <cat@plt>
  mov    $0x0,%eax
  call   <waitall@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  hog();
  hog();
  hog();
  cat();
  waitall();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <hog@plt>
  mov    $0x0,%eax
  call   <hog@plt>
  mov    $0x0,%eax
  call   <hog@plt>
  mov    $0x0,%eax
  call   <cat@plt>
  mov    $0x0,%eax
  call   <waitall@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  hog();
  hog();
  hog();
  cat();
  waitall();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hog@plt>
  xor    %eax,%eax
  call   <hog@plt>
  xor    %eax,%eax
  call   <hog@plt>
  xor    %eax,%eax
  call   <cat@plt>
  xor    %eax,%eax
  call   <waitall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  hog();
  hog();
  hog();
  cat();
  waitall();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hog@plt>
  xor    %eax,%eax
  call   <hog@plt>
  xor    %eax,%eax
  call   <hog@plt>
  xor    %eax,%eax
  call   <cat@plt>
  xor    %eax,%eax
  call   <waitall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  hog();
  hog();
  hog();
  cat();
  waitall();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<simple_threshold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x30(%rbp)
  jge    L10
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0xff,(%rax)
  jmp    L23
L10:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L20
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void simple_threshold(const unsigned char *source, int source_stride, unsigned char *dest, int width, int height, int threshold) {
  const unsigned char *p = source;
  int count = width * height;
  int i;
  for (i = 0; i < count; ++i) {
    if (*p > threshold)
      dest[i] = 255;
    else
      dest[i] = 0;
    p += source_stride;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<simple_threshold>:
  endbr64
  mov    %esi,%r10d
  imul   %ecx,%r8d
  test   %r8d,%r8d
  jle    L8
  mov    %rdx,%rax
  lea    -0x1(%r8),%ecx
  lea    0x1(%rdx,%rcx,1),%rsi
  movslq %r10d,%rcx
  jmp    L26
L39:
  movb   $0x0,(%rax)
L30:
  add    %rcx,%rdi
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L8
L26:
  movzbl (%rdi),%edx
  cmp    %r9d,%edx
  jle    L39
  movb   $0xff,(%rax)
  jmp    L30
L8:
  ret
```

assistant: ```c
void simple_threshold(const unsigned char *source, int source_stride, unsigned char *dest, int width, int height, int threshold) {
  const unsigned char *p = source;
  int count = width * height;
  int i;
  for (i = 0; i < count; ++i) {
    if (*p > threshold)
      dest[i] = 255;
    else
      dest[i] = 0;
    p += source_stride;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simple_threshold>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  jle    L4
  lea    -0x1(%rcx),%eax
  movslq %esi,%rsi
  lea    0x1(%rdx,%rax,1),%rcx
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%rdi),%eax
  cmp    %r9d,%eax
  setg   %al
  add    $0x1,%rdx
  add    %rsi,%rdi
  neg    %eax
  mov    %al,-0x1(%rdx)
  cmp    %rdx,%rcx
  jne    L15
L4:
  ret
```

assistant: ```c
void simple_threshold(const unsigned char *source, int source_stride, unsigned char *dest, int width, int height, int threshold) {
  const unsigned char *p = source;
  int count = width * height;
  int i;
  for (i = 0; i < count; ++i) {
    if (*p > threshold)
      dest[i] = 255;
    else
      dest[i] = 0;
    p += source_stride;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<simple_threshold>:
  endbr64
  imul   %r8d,%ecx
  mov    %rdi,%rax
  test   %ecx,%ecx
  jle    L12
  sub    $0x1,%ecx
  cmp    $0x1,%esi
  movslq %esi,%rdi
  lea    0x1(%rdx,%rcx,1),%rsi
  jne    L78
  nop
L48:
  movzbl (%rax),%ecx
  cmp    %ecx,%r9d
  jl     L16
  movb   $0x0,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rsi
  jne    L48
  ret
  nopl   0x0(%rax)
L18:
  movb   $0xff,(%rdx)
  add    $0x1,%rdx
  add    %rdi,%rax
  cmp    %rsi,%rdx
  je     L1
L78:
  movzbl (%rax),%ecx
  cmp    %ecx,%r9d
  jl     L18
  movb   $0x0,(%rdx)
  add    $0x1,%rdx
  add    %rdi,%rax
  cmp    %rsi,%rdx
  jne    L78
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  movb   $0xff,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rsi
  jne    L48
L12:
  ret
L1:
  ret
```

assistant: ```c
void simple_threshold(const unsigned char *source, int source_stride, unsigned char *dest, int width, int height, int threshold) {
  const unsigned char *p = source;
  int count = width * height;
  int i;
  for (i = 0; i < count; ++i) {
    if (*p > threshold)
      dest[i] = 255;
    else
      dest[i] = 0;
    p += source_stride;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <countPrimes@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x270f,-0x4(%rbp)
  jle    L8
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D0: done


assistant: ```c
int main(void) {
  for (int i = 1; i < 10000; i++) {
    countPrimes(i);
  }
  printf("done\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
L7:
  mov    %ebx,%edi
  call   <countPrimes@plt>
  add    $0x1,%ebx
  cmp    $0x2710,%ebx
  jne    L7
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string

tool: D7: done


assistant: ```c
int main(void) {
  for (int i = 1; i < 10000; i++) {
    countPrimes(i);
  }
  printf("done\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <countPrimes@plt>
  cmp    $0x2710,%ebx
  jne    L2
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: done


assistant: ```c
int main(void) {
  for (int i = 1; i < 10000; i++) {
    countPrimes(i);
  }
  printf("done\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <countPrimes@plt>
  cmp    $0x2710,%ebx
  jne    L4
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: done


assistant: ```c
int main(void) {
  for (int i = 1; i < 10000; i++) {
    countPrimes(i);
  }
  printf("done\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpu_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gdt_init@plt>
  mov    $0x0,%eax
  call   <tss_init@plt>
  mov    $0x0,%eax
  call   <idt_init@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cpu_init(void) {
  gdt_init();
  tss_init();
  idt_init();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpu_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gdt_init@plt>
  mov    $0x0,%eax
  call   <tss_init@plt>
  mov    $0x0,%eax
  call   <idt_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cpu_init(void) {
  gdt_init();
  tss_init();
  idt_init();
}
```
user: What is the c source code of the assembly code below?

```asm
<cpu_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gdt_init@plt>
  xor    %eax,%eax
  call   <tss_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <idt_init@plt>
```

assistant: ```c
void cpu_init(void) {
  gdt_init();
  tss_init();
  idt_init();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cpu_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gdt_init@plt>
  xor    %eax,%eax
  call   <tss_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <idt_init@plt>
```

assistant: ```c
void cpu_init(void) {
  gdt_init();
  tss_init();
  idt_init();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x54,-0x1(%rbp)
  jne    L19
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L11
L19:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D5: done!

tool: D10: nope!

assistant: ```c
int main(int argc, char *argv[]) {
  char test = argv[1][0];
  if ('T' == test)
    printf("done!");
  else
    printf("nope!");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  cmpb   $0x54,(%rax)
  je     L14
  lea    D7(%rip),%rdi
  call   <printf@plt>
L1:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L14:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string

tool: D7: nope!

tool: D18: done!

assistant: ```c
int main(int argc, char *argv[]) {
  char test = argv[1][0];
  if ('T' == test)
    printf("done!");
  else
    printf("nope!");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  cmpb   $0x54,(%rax)
  je     L17
  lea    D18(%rip),%rdi
  call   <printf@plt>
L10:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L17:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: data_label: D18
data_type: string
name: disassemble_data
arguments: data_label: D14
data_type: string

tool: D18: nope!

tool: D14: done!

assistant: ```c
int main(int argc, char *argv[]) {
  char test = argv[1][0];
  if ('T' == test)
    printf("done!");
  else
    printf("nope!");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  cmpb   $0x54,(%rax)
  je     L2
  lea    D2(%rip),%rdi
  call   <printf@plt>
L9:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L2:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D2: nope!

tool: D11: done!

assistant: ```c
int main(int argc, char *argv[]) {
  char test = argv[1][0];
  if ('T' == test)
    printf("done!");
  else
    printf("nope!");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x17447d68,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  rol    $0x7,%rax
  lea    0x7f580d9e(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[local1] |= ((state[local1] | state[local2]) & 31UL) << 4UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] << 7UL) | (state[0UL] >> 57UL)) + 2136477086UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x17447d68,%rax
  rol    $0x7,%rax
  add    $0x7f580d9e,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[local1] |= ((state[local1] | state[local2]) & 31UL) << 4UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] << 7UL) | (state[0UL] >> 57UL)) + 2136477086UL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x17447d68,%rax
  rol    $0x7,%rax
  add    $0x7f580d9e,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[local1] |= ((state[local1] | state[local2]) & 31UL) << 4UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] << 7UL) | (state[0UL] >> 57UL)) + 2136477086UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x17447d68,%rax
  rol    $0x7,%rax
  add    $0x7f580d9e,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[local1] |= ((state[local1] | state[local2]) & 31UL) << 4UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] << 7UL) | (state[0UL] >> 57UL)) + 2136477086UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compar_external>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  jmp    L40
L38:
  addq   $0x1,-0x10(%rbp)
L40:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L39
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L38
L39:
  addq   $0x1,-0x8(%rbp)
  jmp    L30
L14:
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L14
L6:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int compar_external(const void *a, const void *b) {
  char *key_a = *((char **)a);
  char *key_b = *((char **)b);
  for (key_a++; key_a[0] && key_a[-1] != '"'; key_a++)
    ;
  for (key_b++; key_b[0] && key_b[-1] != '"'; key_b++)
    ;
  return strcmp(key_a, key_b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compar_external>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rdx
  mov    (%rsi),%rax
  lea    0x1(%rdx),%rdi
  cmpb   $0x0,0x1(%rdx)
  je     L8
L13:
  cmpb   $0x22,-0x1(%rdi)
  je     L8
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L13
L8:
  lea    0x1(%rax),%rsi
  cmpb   $0x0,0x1(%rax)
  je     L54
L55:
  cmpb   $0x22,-0x1(%rsi)
  je     L54
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  jne    L55
L54:
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int compar_external(const void *a, const void *b) {
  char *key_a = *((char **)a);
  char *key_b = *((char **)b);
  for (key_a++; key_a[0] && key_a[-1] != '"'; key_a++)
    ;
  for (key_b++; key_b[0] && key_b[-1] != '"'; key_b++)
    ;
  return strcmp(key_a, key_b);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<compar_external>:
  endbr64
  mov    (%rdi),%rdx
  mov    (%rsi),%rax
  cmpb   $0x0,0x1(%rdx)
  lea    0x1(%rdx),%rdi
  jne    L52
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L78:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  je     L35
L52:
  cmpb   $0x22,-0x1(%rdi)
  jne    L78
L35:
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rsi
  jne    L72
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  je     L75
L72:
  cmpb   $0x22,-0x1(%rsi)
  jne    L15
L75:
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int compar_external(const void *a, const void *b) {
  char *key_a = *((char **)a);
  char *key_b = *((char **)b);
  for (key_a++; key_a[0] && key_a[-1] != '"'; key_a++)
    ;
  for (key_b++; key_b[0] && key_b[-1] != '"'; key_b++)
    ;
  return strcmp(key_a, key_b);
}
```