user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%ebx
  nopw   0x0(%rax,%rax,1)
L103:
  xor    %eax,%eax
  call   <gang@plt>
  sub    $0x1,%ebx
  jne    L103
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
  call   <worker@plt>
  sub    $0x1,%ebx
  jne    L40
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
  call   <vector@plt>
  sub    $0x1,%ebx
  jne    L24
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L117:
  xor    %eax,%eax
  call   <gang@plt>
  sub    $0x1,%ebx
  jne    L117
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L100:
  xor    %eax,%eax
  call   <gang@plt>
  sub    $0x1,%ebx
  jne    L100
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
  call   <gang@plt>
  sub    $0x1,%ebx
  jne    L33
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L131:
  xor    %eax,%eax
  call   <worker@plt>
  sub    $0x1,%ebx
  jne    L131
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <worker@plt>
  sub    $0x1,%ebx
  jne    L8
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  call   <worker@plt>
  sub    $0x1,%ebx
  jne    L23
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L70:
  xor    %eax,%eax
  call   <vector@plt>
  sub    $0x1,%ebx
  jne    L70
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L43:
  xor    %eax,%eax
  call   <vector@plt>
  sub    $0x1,%ebx
  jne    L43
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L148:
  xor    %eax,%eax
  call   <vector@plt>
  sub    $0x1,%ebx
  jne    L148
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
  call   <seq@plt>
  sub    $0x1,%ebx
  jne    L20
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L112:
  xor    %eax,%eax
  call   <seq@plt>
  sub    $0x1,%ebx
  jne    L112
  mov    $0xa,%ebx
  nopl   0x0(%rax)
L47:
  xor    %eax,%eax
  call   <seq@plt>
  sub    $0x1,%ebx
  jne    L47
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int red = 0;
#pragma acc parallel copy(red)
  {
#pragma acc loop reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += gang();
#pragma acc loop reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += worker();
#pragma acc loop reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += vector();
#pragma acc loop gang reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += gang();
#pragma acc loop worker reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += gang();
#pragma acc loop vector reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += gang();
#pragma acc loop gang reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += worker();
#pragma acc loop worker reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += worker();
#pragma acc loop vector reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += worker();
#pragma acc loop gang reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += vector();
#pragma acc loop worker reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += vector();
#pragma acc loop vector reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += vector();
#pragma acc loop gang reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += seq();
#pragma acc loop worker reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += seq();
#pragma acc loop vector reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += seq();
  }
  return 0;
}
```