ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<verify_valid_date>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %edx,%edi
  call   <verify_leap_years@plt>
  movl   $0x1f,(%rsp)
  movl   $0x1c,0x4(%rsp)
  movl   $0x1f,0x8(%rsp)
  movl   $0x1e,0xc(%rsp)
  movl   $0x1f,0x10(%rsp)
  movl   $0x1e,0x14(%rsp)
  movl   $0x1f,0x18(%rsp)
  movl   $0x1f,0x1c(%rsp)
  movl   $0x1e,0x20(%rsp)
  movl   $0x1f,0x24(%rsp)
  movl   $0x1e,0x28(%rsp)
  movl   $0x1f,0x2c(%rsp)
  cmp    $0xc,%ebx
  jg     L42
  lea    -0x1(%rbx),%edx
  movslq %edx,%rdx
  mov    (%rsp,%rdx,4),%edx
  cmp    $0x1,%eax
  jne    L63
  cmp    $0x2,%ebx
  jne    L63
  add    $0x1,%edx
  cmp    %ebp,%edx
  jge    L37
L35:
  mov    %ebp,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L67:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L85
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  mov    %ebx,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L67
L37:
  mov    %r12d,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L35
L63:
  cmp    $0x1,%eax
  je     L35
  cmp    %ebp,%edx
  jl     L35
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L67
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D47
type_guessed: string
name: parse_data
arguments: data_tag: D40
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D29: The day %i is invalid


tool: D47: Please, enter a valid date!

tool: D40: The month %i is invalid


tool: D3: %i: Yeap, it is a leap year!


tool: D4: %i: This year is not a leap, but the date is valid.


assistant: ```c
int verify_valid_date(int day, int month, int year) {
  bool leap = verify_leap_years(year);
  int days_in_month[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  if (month > 12) {
    printf("The month %i is invalid\n", month);
    return -1;
  }
  int month_at_index = days_in_month[month - 1];
  if ((leap == true) && (month == 2) && (day <= month_at_index + 1)) {
    printf("%i: Yeap, it is a leap year!\n", year);
  }
  if (!(leap == true) && day <= month_at_index) {
    printf("%i: This year is not a leap, but the date is valid.\n", year);
    return 0;
  } else {
    printf("The day %i is invalid\n", day);
  }
  printf("Please, enter a valid date!");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<verify_valid_date>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %edx,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <verify_leap_years@plt>
  movabs $0x1e0000001f,%rdx
  movabs $0x1c0000001f,%rcx
  mov    %rcx,(%rsp)
  movabs $0x1f0000001f,%rcx
  mov    %rdx,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  movabs $0x1f0000001e,%rdx
  mov    %rcx,0x18(%rsp)
  mov    %rdx,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  cmp    $0xc,%ebp
  jg     L64
  lea    -0x1(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rsp,%rdx,4),%edx
  cmp    $0x1,%eax
  jne    L51
  cmp    $0x2,%ebp
  jne    L10
  add    $0x1,%edx
  cmp    %r12d,%edx
  jge    L86
L91:
  mov    %r12d,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L41:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L83
  add    $0x40,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  cmp    $0x1,%eax
  je     L91
L51:
  cmp    %r12d,%edx
  jl     L91
  mov    %r13d,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L41
  nop
L86:
  mov    %r13d,%esi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L91
L64:
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L41
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
datatype: string
name: parse_data
arguments: data_label: D49
datatype: string
name: parse_data
arguments: data_label: D40
datatype: string
name: parse_data
arguments: data_label: D45
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D14: The day %i is invalid


tool: D49: Please, enter a valid date!

tool: D40: %i: This year is not a leap, but the date is valid.


tool: D45: %i: Yeap, it is a leap year!


tool: D15: The month %i is invalid


assistant: ```c
int verify_valid_date(int day, int month, int year) {
  bool leap = verify_leap_years(year);
  int days_in_month[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  if (month > 12) {
    printf("The month %i is invalid\n", month);
    return -1;
  }
  int month_at_index = days_in_month[month - 1];
  if ((leap == true) && (month == 2) && (day <= month_at_index + 1)) {
    printf("%i: Yeap, it is a leap year!\n", year);
  }
  if (!(leap == true) && day <= month_at_index) {
    printf("%i: This year is not a leap, but the date is valid.\n", year);
    return 0;
  } else {
    printf("The day %i is invalid\n", day);
  }
  printf("Please, enter a valid date!");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<piececount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L1:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int piececount(int *player, int startrow, int endrow) {
  int sum;
  sum = 0;
  while (startrow <= endrow)
    sum += player[startrow++];
  return (sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<piececount>:
  endbr64
  cmp    %edx,%esi
  jg     L18
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%rax
  sub    %esi,%edx
  add    %rcx,%rdx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L6:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L6
L16:
  mov    %edx,%eax
  ret
L18:
  mov    $0x0,%edx
  jmp    L16
```

assistant: ```c
int piececount(int *player, int startrow, int endrow) {
  int sum;
  sum = 0;
  while (startrow <= endrow)
    sum += player[startrow++];
  return (sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<piececount>:
  endbr64
  cmp    %edx,%esi
  jg     L3
  movslq %esi,%rcx
  sub    %esi,%edx
  xor    %r8d,%r8d
  add    %rcx,%rdx
  lea    (%rdi,%rcx,4),%rax
  lea    0x4(%rdi,%rdx,4),%rdx
  nopl   0x0(%rax)
L9:
  add    (%rax),%r8d
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L9
  mov    %r8d,%eax
  ret
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int piececount(int *player, int startrow, int endrow) {
  int sum;
  sum = 0;
  while (startrow <= endrow)
    sum += player[startrow++];
  return (sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<piececount>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%ecx
  mov    %edx,%edi
  cmp    %edx,%esi
  jg     L8
  mov    %edx,%eax
  sub    %esi,%eax
  lea    0x1(%rax),%r9d
  cmp    $0x2,%eax
  jbe    L64
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  lea    (%r8,%rax,4),%rdx
  mov    %r9d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%esi
  lea    0x10(%rdx),%rax
  shl    $0x4,%rsi
  add    %rax,%rsi
  jmp    L73
  nopl   (%rax)
L38:
  add    $0x10,%rax
L73:
  movdqu (%rdx),%xmm1
  mov    %rax,%rdx
  paddd  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L38
  movdqa %xmm0,%xmm1
  mov    %r9d,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  add    %edx,%ecx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%r9d
  je     L60
L58:
  movslq %ecx,%rdx
  lea    0x0(,%rdx,4),%rsi
  add    (%r8,%rdx,4),%eax
  lea    0x1(%rcx),%edx
  cmp    %edx,%edi
  jl     L47
  add    $0x2,%ecx
  add    0x4(%r8,%rsi,1),%eax
  cmp    %ecx,%edi
  jl     L47
  add    0x8(%r8,%rsi,1),%eax
  ret
  nop
L8:
  xor    %eax,%eax
L47:
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  ret
L64:
  xor    %eax,%eax
  jmp    L58
```

assistant: ```c
int piececount(int *player, int startrow, int endrow) {
  int sum;
  sum = 0;
  while (startrow <= endrow)
    sum += player[startrow++];
  return (sum);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L7
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L7
L48:
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L48
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L14
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L14:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L15:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int a, b, c;
  if (a < b) {
    a = a + b;
  }
  while (a < b) {
    a = a + b;
  }
  if (a <= b) {
    c = a - b;
  } else {
    c = a + b;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int a, b, c;
  if (a < b) {
    a = a + b;
  }
  while (a < b) {
    a = a + b;
  }
  if (a <= b) {
    c = a - b;
  } else {
    c = a + b;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int a, b, c;
  if (a < b) {
    a = a + b;
  }
  while (a < b) {
    a = a + b;
  }
  if (a <= b) {
    c = a - b;
  } else {
    c = a + b;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int a, b, c;
  if (a < b) {
    a = a + b;
  }
  while (a < b) {
    a = a + b;
  }
  if (a <= b) {
    c = a - b;
  } else {
    c = a + b;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gf2v_get_ele>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char gf2v_get_ele(const uint8_t *a, unsigned i) {
  unsigned char r = a[i >> 3];
  r = r >> (i & 7);
  return r & 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gf2v_get_ele>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  movzbl (%rdi,%rax,1),%eax
  and    $0x7,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned char gf2v_get_ele(const uint8_t *a, unsigned i) {
  unsigned char r = a[i >> 3];
  r = r >> (i & 7);
  return r & 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gf2v_get_ele>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%ecx
  shr    $0x3,%eax
  and    $0x7,%ecx
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned char gf2v_get_ele(const uint8_t *a, unsigned i) {
  unsigned char r = a[i >> 3];
  r = r >> (i & 7);
  return r & 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gf2v_get_ele>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%ecx
  shr    $0x3,%eax
  and    $0x7,%ecx
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned char gf2v_get_ele(const uint8_t *a, unsigned i) {
  unsigned char r = a[i >> 3];
  r = r >> (i & 7);
  return r & 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<base64_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x18(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <BIO_set_flags@plt>
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_push@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_flush@plt>
  cmp    $0x1,%eax
  je     L21
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free_all@plt>
  mov    $0x1,%eax
  jmp    L20
L21:
  lea    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_get_mem_ptr@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x38(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free_all@plt>
  mov    $0x1,%eax
  jmp    L20
L17:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free_all@plt>
  mov    $0x0,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
int base64_encode(unsigned char *in, unsigned int in_len, char **encoded) {
  BIO *bmem, *b64;
  BUF_MEM *bptr;
  b64 = BIO_new(BIO_f_base64());
  BIO_set_flags(b64, BIO_FLAGS_BASE64_NO_NL);
  bmem = BIO_new(BIO_s_mem());
  b64 = BIO_push(b64, bmem);
  BIO_write(b64, in, in_len);
  if (BIO_flush(b64) != 1) {
    BIO_free_all(b64);
    return 1;
  }
  BIO_get_mem_ptr(b64, &bptr);
  *encoded = malloc(bptr->length + 1);
  if (!(*encoded)) {
    BIO_free_all(b64);
    return 1;
  }
  memcpy(*encoded, bptr->data, bptr->length);
  (*encoded)[bptr->length] = '\0';
  BIO_free_all(b64);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<base64_encode>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <BIO_set_flags@plt>
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <BIO_push@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    %rbx,%rdi
  call   <BIO_flush@plt>
  cmp    $0x1,%eax
  je     L42
  mov    %rbx,%rdi
  call   <BIO_free_all@plt>
  mov    $0x1,%ebp
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  mov    %eax,%ebp
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <BIO_get_mem_ptr@plt>
  mov    (%rsp),%rax
  mov    (%rax),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L18
  mov    (%rsp),%rax
  mov    0x4(%rax),%esi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    (%rsp),%rax
  movslq (%rax),%rax
  mov    0x0(%r13),%rdx
  movb   $0x0,(%rdx,%rax,1)
  mov    %rbx,%rdi
  call   <BIO_free_all@plt>
  mov    $0x0,%ebp
  jmp    L4
L18:
  mov    %rbx,%rdi
  call   <BIO_free_all@plt>
  jmp    L4
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int base64_encode(unsigned char *in, unsigned int in_len, char **encoded) {
  BIO *bmem, *b64;
  BUF_MEM *bptr;
  b64 = BIO_new(BIO_f_base64());
  BIO_set_flags(b64, BIO_FLAGS_BASE64_NO_NL);
  bmem = BIO_new(BIO_s_mem());
  b64 = BIO_push(b64, bmem);
  BIO_write(b64, in, in_len);
  if (BIO_flush(b64) != 1) {
    BIO_free_all(b64);
    return 1;
  }
  BIO_get_mem_ptr(b64, &bptr);
  *encoded = malloc(bptr->length + 1);
  if (!(*encoded)) {
    BIO_free_all(b64);
    return 1;
  }
  memcpy(*encoded, bptr->data, bptr->length);
  (*encoded)[bptr->length] = '\0';
  BIO_free_all(b64);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<base64_encode>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbp
  mov    D7(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <BIO_set_flags@plt>
  xor    %eax,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <BIO_push@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  call   <BIO_flush@plt>
  cmp    $0x1,%eax
  je     L28
  mov    %rbp,%rdi
  mov    $0x1,%r12d
  call   <BIO_free_all@plt>
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <BIO_get_mem_ptr@plt>
  mov    (%rsp),%rax
  mov    (%rax),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L24
  mov    (%rsp),%rax
  xor    %r12d,%r12d
  mov    0x4(%rax),%esi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    (%rsp),%rax
  mov    (%rbx),%rdx
  mov    %rbp,%rdi
  movslq (%rax),%rax
  movb   $0x0,(%rdx,%rax,1)
  call   <BIO_free_all@plt>
  jmp    L19
L24:
  mov    %rbp,%rdi
  call   <BIO_free_all@plt>
  jmp    L19
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int base64_encode(unsigned char *in, unsigned int in_len, char **encoded) {
  BIO *bmem, *b64;
  BUF_MEM *bptr;
  b64 = BIO_new(BIO_f_base64());
  BIO_set_flags(b64, BIO_FLAGS_BASE64_NO_NL);
  bmem = BIO_new(BIO_s_mem());
  b64 = BIO_push(b64, bmem);
  BIO_write(b64, in, in_len);
  if (BIO_flush(b64) != 1) {
    BIO_free_all(b64);
    return 1;
  }
  BIO_get_mem_ptr(b64, &bptr);
  *encoded = malloc(bptr->length + 1);
  if (!(*encoded)) {
    BIO_free_all(b64);
    return 1;
  }
  memcpy(*encoded, bptr->data, bptr->length);
  (*encoded)[bptr->length] = '\0';
  BIO_free_all(b64);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base64_encode>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbp
  mov    D2(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <BIO_set_flags@plt>
  xor    %eax,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <BIO_push@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  call   <BIO_flush@plt>
  cmp    $0x1,%eax
  je     L39
  mov    %rbp,%rdi
  mov    $0x1,%r12d
  call   <BIO_free_all@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <BIO_get_mem_ptr@plt>
  mov    (%rsp),%rax
  mov    (%rax),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L7
  mov    (%rsp),%rax
  xor    %r12d,%r12d
  mov    0x4(%rax),%esi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    (%rsp),%rax
  mov    (%rbx),%rdx
  mov    %rbp,%rdi
  movslq (%rax),%rax
  movb   $0x0,(%rdx,%rax,1)
  call   <BIO_free_all@plt>
  jmp    L12
L7:
  mov    %rbp,%rdi
  call   <BIO_free_all@plt>
  jmp    L12
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int base64_encode(unsigned char *in, unsigned int in_len, char **encoded) {
  BIO *bmem, *b64;
  BUF_MEM *bptr;
  b64 = BIO_new(BIO_f_base64());
  BIO_set_flags(b64, BIO_FLAGS_BASE64_NO_NL);
  bmem = BIO_new(BIO_s_mem());
  b64 = BIO_push(b64, bmem);
  BIO_write(b64, in, in_len);
  if (BIO_flush(b64) != 1) {
    BIO_free_all(b64);
    return 1;
  }
  BIO_get_mem_ptr(b64, &bptr);
  *encoded = malloc(bptr->length + 1);
  if (!(*encoded)) {
    BIO_free_all(b64);
    return 1;
  }
  memcpy(*encoded, bptr->data, bptr->length);
  (*encoded)[bptr->length] = '\0';
  BIO_free_all(b64);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<arithmatic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <yyselect@plt>
  sub    $0x2f,%eax
  cmp    $0x9,%eax
  ja     L26
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D18(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D18(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  jmp    L26
  mov    $0x0,%eax
  call   <get_lexval@plt>
  nop
L26:
  nop
  pop    %rbp
  ret
```

assistant: ```c
arithmatic() {
  switch (yyselect()) {
  case 47: {
    get_lexval();
  } break;
  case 48: {
    get_lexval();
  } break;
  case 49: {
    get_lexval();
  } break;
  case 50: {
    get_lexval();
  } break;
  case 51: {
    get_lexval();
  } break;
  case 52: {
    get_lexval();
  } break;
  case 53: {
    get_lexval();
  } break;
  case 54: {
    get_lexval();
  } break;
  case 55: {
    get_lexval();
  } break;
  case 56: {
    get_lexval();
  } break;
  }
}
```