user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x20,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L218
  mov    $0x0,%ebp
  lea    D28(%rip),%rbx
L278:
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%ecx
  mov    0xc(%rsp),%esi
  movslq %esi,%rax
  movslq %ecx,%rdx
  lea    (%rax,%rdx,8),%rdx
  movl   $0x1,0x10(%rsp,%rdx,4)
  cmpl   $0x1,0x10(%rsp,%rax,4)
  jne    L244
  test   %ecx,%ecx
  jne    L196
L244:
  movslq %esi,%r8
  lea    0x30(%rsp,%r8,4),%rdx
  mov    $0x1,%eax
  jmp    L261
L147:
  add    $0x1,%eax
  add    $0x20,%rdx
  cmp    $0x8,%eax
  je     L219
L261:
  cmpl   $0x1,(%rdx)
  jne    L147
  cmp    %eax,%ecx
  je     L147
L196:
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L187
L219:
  movslq %ecx,%rax
  shl    $0x5,%rax
  cmpl   $0x1,0x10(%rsp,%rax,1)
  jne    L286
  test   %esi,%esi
  jne    L96
L286:
  movslq %ecx,%r9
  mov    %r9,%rax
  shl    $0x5,%rax
  lea    0x10(%rsp,%rax,1),%rdx
  mov    $0x1,%eax
  jmp    L56
L247:
  add    $0x1,%rax
  cmp    $0x8,%rax
  je     L188
L56:
  cmpl   $0x1,(%rdx,%rax,4)
  jne    L247
  cmp    %eax,%esi
  je     L247
L96:
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L187
L188:
  lea    -0x1(%rcx),%eax
  mov    %ecx,%edx
  neg    %edx
  jns    L113
  test   %esi,%esi
  jle    L113
  lea    (%r8,%r9,8),%rdx
  lea    0x10(%rsp,%rdx,4),%rdx
L108:
  cmpl   $0x1,-0x24(%rdx)
  je     L288
  sub    $0x1,%eax
  sub    $0x24,%rdx
  lea    (%rsi,%rax,1),%edi
  cmp    %ecx,%edi
  js     L113
  test   %eax,%eax
  jns    L108
L113:
  lea    0x1(%rcx),%eax
  cmp    $0x7,%eax
  jg     L126
  cmp    $0x6,%esi
  jg     L126
  lea    (%r8,%r9,8),%rdx
  lea    0x10(%rsp,%rdx,4),%rdi
L88:
  cmpl   $0x1,0x24(%rdi)
  je     L245
  add    $0x1,%eax
  add    $0x24,%rdi
  lea    (%rsi,%rax,1),%edx
  sub    %ecx,%edx
  cmp    $0x7,%edx
  jg     L126
  cmp    $0x7,%eax
  jle    L88
L126:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jg     L278
L218:
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L187
L288:
  lea    D62(%rip),%rdi
  call   <printf@plt>
L187:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L149
  mov    $0x0,%eax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L245:
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L187
L149:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D34
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D62
type_guessed: string
name: disassemble_data
arguments: tag: D69
type_guessed: string

tool: D34: %d

tool: D28: %d %d


tool: D62: no

tool: D69: yes

assistant: ```c
int main() {
  int mat[8][8] = {};
  int n, i, j, k, r, c;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d %d\n", &r, &c);
    mat[r][c] = 1;
    k = c;
    for (j = 0; j < 8; j++) {
      if (mat[j][k] == 1 && j != r) {
        printf("no");
        return 0;
      }
    }
    j = r;
    for (k = 0; k < 8; k++) {
      if (mat[j][k] == 1 && k != c) {
        printf("no");
        return 0;
      }
    }
    k = c - 1;
    for (j = r - 1; j >= 0 && k >= 0; j--) {
      if (mat[j][k] == 1) {
        printf("no");
        return 0;
      }
      k = k - 1;
    }
    k = c + 1;
    for (j = r + 1; j < 8 && k < 8; j++) {
      if (mat[j][k] == 1) {
        printf("no");
        return 0;
      }
      k = k + 1;
    }
  }
  printf("yes");
  return 0;
}
```