ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<bwb_QUEST>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <bwx_DEBUG@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <bwb_PRINT@plt>
  pop    %rbp
  cltq
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: bwb_QUEST

assistant: ```c
struct bwb_line *bwb_QUEST(struct bwb_line *l) {
  bwx_DEBUG(__FUNCTION__);
  return bwb_PRINT(l);
}
```
user: What is the c source code of the assembly code below:

```asm
<SHAMD5IntDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x44034000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x8,-0x8(%rbp)
  je     L20
  cmpl   $0x4,-0x8(%rbp)
  je     L20
  cmpl   $0x2,-0x8(%rbp)
  je     L20
  cmpl   $0x1,-0x8(%rbp)
  jne    L18
L20:
  mov    $0x1,%eax
  jmp    L29
L18:
  mov    $0x0,%eax
L29:
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x3ff0,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  sar    $0xe,%eax
  and    $0x4,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  and    $0x2,%eax
  or     %edx,%eax
  not    %eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  sub    $0x3ff0,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  and    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0x11c,%eax
  cltq
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  movzwl %ax,%eax
  not    %eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  add    $0x11c,%eax
  cltq
  mov    %rax,%rdx
  mov    %ecx,%eax
  and    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0x11c,%eax
  cltq
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L8
  mov    -0x4(%rbp),%eax
  add    $0x110,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x110,%edx
  movslq %edx,%rdx
  and    $0xfffffffb,%eax
  mov    %eax,(%rdx)
L8:
  nop
  leave
  ret
```

assistant: ```c
void SHAMD5IntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x44034000);
  ASSERT((ui32IntFlags == 0x00000008) || (ui32IntFlags == 0x00000004) || (ui32IntFlags == 0x00000002) || (ui32IntFlags == 0x00000001));
  (*((volatile uint32_t *)(ui32Base + 0xFFFFC010))) &= ~(((ui32IntFlags & 0x00010000) >> 14) | ((ui32IntFlags & 0x00020000) >> 16) | ((ui32IntFlags & 0x00040000) >> 19));
  (*((volatile uint32_t *)(ui32Base + 0x0000011C))) &= ~(ui32IntFlags & 0x0000ffff);
  if ((*((volatile uint32_t *)(ui32Base + 0x0000011C))) == 0x0) {
    (*((volatile uint32_t *)(ui32Base + 0x00000110))) &= ~0x00000004;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SHAMD5IntDisable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  cmp    $0x44034000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  lea    -0x4(%rbx),%eax
  mov    $0x1,%edi
  test   $0xfffffffb,%eax
  je     L3
  lea    -0x1(%rbx),%eax
  cmp    $0x1,%eax
  setbe  %dil
  movzbl %dil,%edi
L3:
  call   <ASSERT@plt>
  mov    -0x3ff0(%ebp),%ecx
  mov    %ebx,%eax
  sar    $0xe,%eax
  and    $0x4,%eax
  mov    %ebx,%edx
  sar    $0x10,%edx
  and    $0x2,%edx
  or     %edx,%eax
  not    %eax
  and    %ecx,%eax
  mov    %eax,-0x3ff0(%ebp)
  lea    0x11c(%rbp),%eax
  cltq
  mov    (%rax),%edx
  movzwl %bx,%ebx
  not    %ebx
  and    %edx,%ebx
  mov    %ebx,(%rax)
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L17
  add    $0x110,%ebp
  movslq %ebp,%rbp
  mov    0x0(%rbp),%eax
  and    $0xfffffffb,%eax
  mov    %eax,0x0(%rbp)
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SHAMD5IntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x44034000);
  ASSERT((ui32IntFlags == 0x00000008) || (ui32IntFlags == 0x00000004) || (ui32IntFlags == 0x00000002) || (ui32IntFlags == 0x00000001));
  (*((volatile uint32_t *)(ui32Base + 0xFFFFC010))) &= ~(((ui32IntFlags & 0x00010000) >> 14) | ((ui32IntFlags & 0x00020000) >> 16) | ((ui32IntFlags & 0x00040000) >> 19));
  (*((volatile uint32_t *)(ui32Base + 0x0000011C))) &= ~(ui32IntFlags & 0x0000ffff);
  if ((*((volatile uint32_t *)(ui32Base + 0x0000011C))) == 0x0) {
    (*((volatile uint32_t *)(ui32Base + 0x00000110))) &= ~0x00000004;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SHAMD5IntDisable>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x44034000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  lea    -0x4(%rbx),%eax
  mov    $0x1,%edi
  and    $0xfffffffb,%eax
  je     L14
  lea    -0x1(%rbx),%eax
  xor    %edi,%edi
  cmp    $0x1,%eax
  setbe  %dil
L14:
  call   <ASSERT@plt>
  mov    %ebx,%eax
  mov    %ebx,%edx
  mov    -0x3ff0(%ebp),%ecx
  sar    $0xe,%eax
  sar    $0x10,%edx
  movzwl %bx,%ebx
  and    $0x2,%edx
  and    $0x4,%eax
  not    %ebx
  or     %edx,%eax
  not    %eax
  and    %ecx,%eax
  mov    %eax,-0x3ff0(%ebp)
  lea    0x11c(%rbp),%eax
  cltq
  mov    (%rax),%edx
  and    %edx,%ebx
  mov    %ebx,(%rax)
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L15
  add    $0x110,%ebp
  movslq %ebp,%rbp
  mov    0x0(%rbp),%eax
  and    $0xfffffffb,%eax
  mov    %eax,0x0(%rbp)
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SHAMD5IntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x44034000);
  ASSERT((ui32IntFlags == 0x00000008) || (ui32IntFlags == 0x00000004) || (ui32IntFlags == 0x00000002) || (ui32IntFlags == 0x00000001));
  (*((volatile uint32_t *)(ui32Base + 0xFFFFC010))) &= ~(((ui32IntFlags & 0x00010000) >> 14) | ((ui32IntFlags & 0x00020000) >> 16) | ((ui32IntFlags & 0x00040000) >> 19));
  (*((volatile uint32_t *)(ui32Base + 0x0000011C))) &= ~(ui32IntFlags & 0x0000ffff);
  if ((*((volatile uint32_t *)(ui32Base + 0x0000011C))) == 0x0) {
    (*((volatile uint32_t *)(ui32Base + 0x00000110))) &= ~0x00000004;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SHAMD5IntDisable>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x44034000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  lea    -0x4(%rbx),%eax
  mov    $0x1,%edi
  and    $0xfffffffb,%eax
  je     L17
  lea    -0x1(%rbx),%eax
  xor    %edi,%edi
  cmp    $0x1,%eax
  setbe  %dil
L17:
  call   <ASSERT@plt>
  mov    %ebx,%eax
  mov    %ebx,%edx
  mov    -0x3ff0(%ebp),%ecx
  sar    $0xe,%eax
  sar    $0x10,%edx
  movzwl %bx,%ebx
  and    $0x2,%edx
  and    $0x4,%eax
  not    %ebx
  or     %edx,%eax
  not    %eax
  and    %ecx,%eax
  mov    %eax,-0x3ff0(%ebp)
  lea    0x11c(%rbp),%eax
  cltq
  mov    (%rax),%edx
  and    %edx,%ebx
  mov    %ebx,(%rax)
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L3
  add    $0x110,%ebp
  movslq %ebp,%rbp
  mov    0x0(%rbp),%eax
  and    $0xfffffffb,%eax
  mov    %eax,0x0(%rbp)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SHAMD5IntDisable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x44034000);
  ASSERT((ui32IntFlags == 0x00000008) || (ui32IntFlags == 0x00000004) || (ui32IntFlags == 0x00000002) || (ui32IntFlags == 0x00000001));
  (*((volatile uint32_t *)(ui32Base + 0xFFFFC010))) &= ~(((ui32IntFlags & 0x00010000) >> 14) | ((ui32IntFlags & 0x00020000) >> 16) | ((ui32IntFlags & 0x00040000) >> 19));
  (*((volatile uint32_t *)(ui32Base + 0x0000011C))) &= ~(ui32IntFlags & 0x0000ffff);
  if ((*((volatile uint32_t *)(ui32Base + 0x0000011C))) == 0x0) {
    (*((volatile uint32_t *)(ui32Base + 0x00000110))) &= ~0x00000004;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<task_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <task_vprint@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int task_print(char *fmt, ...) {
  int n;
  va_list arg;
  va_start(arg, fmt);
  n = task_vprint(fmt, arg);
  va_end(arg);
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<task_print>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <task_vprint@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int task_print(char *fmt, ...) {
  int n;
  va_list arg;
  va_start(arg, fmt);
  n = task_vprint(fmt, arg);
  va_end(arg);
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<task_print>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <task_vprint@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int task_print(char *fmt, ...) {
  int n;
  va_list arg;
  va_start(arg, fmt);
  n = task_vprint(fmt, arg);
  va_end(arg);
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<task_print>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <task_vprint@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int task_print(char *fmt, ...) {
  int n;
  va_list arg;
  va_start(arg, fmt);
  n = task_vprint(fmt, arg);
  va_end(arg);
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ConfigConvertSpeedToInt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  je     L65
  add    $0x8,%rdi
  mov    $0x1,%ecx
  mov    %rsp,%r8
  mov    $0x1,%r10d
  lea    0x4(%rsp),%r9
L137:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L119
L21:
  add    $0x8,%rdi
  mov    -0x8(%rdi),%rdx
  test   %rdx,%rdx
  jne    L137
L65:
  mov    (%rsp),%eax
  jmp    L28
L44:
  cmp    $0x4d,%al
  je     L45
  jg     L140
  cmp    $0x2e,%al
  je     L17
  cmp    $0x4b,%al
  jne    L53
L103:
  mov    $0x400,%eax
  cltd
  idiv   %ecx
  imul   0x4(%rsp),%eax
  mov    (%rsp),%edx
  shl    $0xa,%edx
  add    %edx,%eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L70
  add    $0x18,%rsp
  ret
L140:
  cmp    $0x6b,%al
  je     L103
  cmp    $0x6d,%al
  jne    L53
L45:
  mov    $0x100000,%eax
  cltd
  idiv   %ecx
  imul   0x4(%rsp),%eax
  mov    (%rsp),%edx
  shl    $0x14,%edx
  add    %edx,%eax
  jmp    L28
L17:
  mov    %r10d,%ecx
  mov    %r9,%r8
L53:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L21
L119:
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L44
  mov    (%r8),%esi
  lea    (%rsi,%rsi,4),%esi
  movsbl %al,%eax
  lea    -0x30(%rax,%rsi,2),%eax
  mov    %eax,(%r8)
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  jmp    L53
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ConfigConvertSpeedToInt(char **tb) {
  const char *str;
  int nb = 0;
  int div = 0;
  int i, j;
  int *ptr = &nb;
  int len = 1;
  for (j = 0; tb[j]; j++) {
    str = tb[j];
    for (i = 0; str[i] != '\0'; i++) {
      if (str[i] >= '0' && str[i] <= '9') {
        *ptr = *ptr * 10 + ((int)str[i] - (int)'0');
        len *= 10;
      } else
        switch (str[i]) {
        case 'k':
        case 'K':
          return (nb * 1024 + div * (1024 / len));
        case 'm':
        case 'M':
          return (nb * 1024 * 1024 + div * ((1024 * 1024) / len));
        case '.':
          ptr = &div;
          len = 1;
          break;
        }
    }
  }
  return (nb);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ConfigConvertSpeedToInt>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%rdx
  mov    $0x1,%ecx
  add    $0x8,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  lea    0x4(%rsp),%r9
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  test   %rdx,%rdx
  je     L79
L124:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L64
L94:
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L5
  mov    (%r8),%eax
  movsbl %sil,%esi
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  lea    (%rax,%rax,4),%eax
  lea    (%rsi,%rax,2),%eax
  mov    %eax,(%r8)
L11:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L94
L64:
  mov    (%rdi),%rdx
  add    $0x8,%rdi
  test   %rdx,%rdx
  jne    L124
  mov    (%rsp),%eax
  nopl   0x0(%rax,%rax,1)
L79:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L5:
  cmp    $0x4d,%al
  je     L13
  jg     L142
  cmp    $0x2e,%al
  jne    L97
  mov    $0x1,%ecx
  mov    %r9,%r8
  jmp    L11
  nopl   0x0(%rax)
L142:
  cmp    $0x6b,%al
  je     L0
  cmp    $0x6d,%al
  jne    L11
L13:
  mov    $0x100000,%eax
  cltd
  idiv   %ecx
  mov    (%rsp),%edx
  shl    $0x14,%edx
  imul   0x4(%rsp),%eax
  add    %edx,%eax
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L97:
  cmp    $0x4b,%al
  jne    L11
L0:
  mov    $0x400,%eax
  cltd
  idiv   %ecx
  mov    (%rsp),%edx
  shl    $0xa,%edx
  imul   0x4(%rsp),%eax
  add    %edx,%eax
  jmp    L79
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ConfigConvertSpeedToInt(char **tb) {
  const char *str;
  int nb = 0;
  int div = 0;
  int i, j;
  int *ptr = &nb;
  int len = 1;
  for (j = 0; tb[j]; j++) {
    str = tb[j];
    for (i = 0; str[i] != '\0'; i++) {
      if (str[i] >= '0' && str[i] <= '9') {
        *ptr = *ptr * 10 + ((int)str[i] - (int)'0');
        len *= 10;
      } else
        switch (str[i]) {
        case 'k':
        case 'K':
          return (nb * 1024 + div * (1024 / len));
        case 'm':
        case 'M':
          return (nb * 1024 * 1024 + div * ((1024 * 1024) / len));
        case '.':
          ptr = &div;
          len = 1;
          break;
        }
    }
  }
  return (nb);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ConfigConvertSpeedToInt>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%rdx
  mov    $0x1,%ecx
  add    $0x8,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  lea    0x4(%rsp),%r9
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  test   %rdx,%rdx
  je     L26
L95:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L47
L80:
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L116
  mov    (%r8),%eax
  movsbl %sil,%esi
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  lea    (%rax,%rax,4),%eax
  lea    (%rsi,%rax,2),%eax
  mov    %eax,(%r8)
L27:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L80
L47:
  mov    (%rdi),%rdx
  add    $0x8,%rdi
  test   %rdx,%rdx
  jne    L95
  mov    (%rsp),%eax
  nopl   0x0(%rax,%rax,1)
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L116:
  cmp    $0x4d,%al
  je     L125
  jg     L13
  cmp    $0x2e,%al
  jne    L89
  mov    $0x1,%ecx
  mov    %r9,%r8
  jmp    L27
  nopl   0x0(%rax)
L13:
  cmp    $0x6b,%al
  je     L118
  cmp    $0x6d,%al
  jne    L27
L125:
  mov    $0x100000,%eax
  cltd
  idiv   %ecx
  mov    (%rsp),%edx
  shl    $0x14,%edx
  imul   0x4(%rsp),%eax
  add    %edx,%eax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L89:
  cmp    $0x4b,%al
  jne    L27
L118:
  mov    $0x400,%eax
  cltd
  idiv   %ecx
  mov    (%rsp),%edx
  shl    $0xa,%edx
  imul   0x4(%rsp),%eax
  add    %edx,%eax
  jmp    L26
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ConfigConvertSpeedToInt(char **tb) {
  const char *str;
  int nb = 0;
  int div = 0;
  int i, j;
  int *ptr = &nb;
  int len = 1;
  for (j = 0; tb[j]; j++) {
    str = tb[j];
    for (i = 0; str[i] != '\0'; i++) {
      if (str[i] >= '0' && str[i] <= '9') {
        *ptr = *ptr * 10 + ((int)str[i] - (int)'0');
        len *= 10;
      } else
        switch (str[i]) {
        case 'k':
        case 'K':
          return (nb * 1024 + div * (1024 / len));
        case 'm':
        case 'M':
          return (nb * 1024 * 1024 + div * ((1024 * 1024) / len));
        case '.':
          ptr = &div;
          len = 1;
          break;
        }
    }
  }
  return (nb);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_striteri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  cmpq   $0x0,-0x20(%rbp)
  je     L12
  jmp    L9
L46:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   *%rdx
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  jmp    L6
L12:
  nop
L6:
  leave
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  unsigned int i;
  i = 0;
  if (!s || !f)
    return;
  while (s[i]) {
    f(i, s + i);
    ++i;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L20
  cmpb   $0x0,(%rdi)
  je     L20
  mov    %rdi,%rsi
  mov    $0x0,%ebx
L27:
  mov    %ebx,%edi
  call   *%r12
  add    $0x1,%ebx
  mov    %ebx,%esi
  add    %rbp,%rsi
  cmpb   $0x0,(%rsi)
  jne    L27
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  unsigned int i;
  i = 0;
  if (!s || !f)
    return;
  while (s[i]) {
    f(i, s + i);
    ++i;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L36
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L35
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L35
  mov    %rdi,%rsi
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %ebx,%edi
  call   *%r12
  lea    0x1(%rbx),%esi
  mov    %rsi,%rbx
  add    %rbp,%rsi
  cmpb   $0x0,(%rsi)
  jne    L34
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  unsigned int i;
  i = 0;
  if (!s || !f)
    return;
  while (s[i]) {
    f(i, s + i);
    ++i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L19
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L19
  mov    %rdi,%rsi
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %ebx,%edi
  call   *%r12
  lea    0x1(%rbx),%esi
  mov    %rsi,%rbx
  add    %rbp,%rsi
  cmpb   $0x0,(%rsi)
  jne    L22
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  unsigned int i;
  i = 0;
  if (!s || !f)
    return;
  while (s[i]) {
    f(i, s + i);
    ++i;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<doThatArgThing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D8: argument %i = %s


assistant: ```c
void doThatArgThing(int argc, char *argv[]) {
  int i;
  char *buffer;
  for (i = 0; i < argc; i++) {
    printf("argument %i = %s\n", i, argv[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doThatArgThing>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D6(%rip),%r13
L10:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: argument %i = %s


assistant: ```c
void doThatArgThing(int argc, char *argv[]) {
  int i;
  char *buffer;
  for (i = 0; i < argc; i++) {
    printf("argument %i = %s\n", i, argv[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<doThatArgThing>:
  endbr64
  test   %edi,%edi
  jle    L15
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L11:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: argument %i = %s


assistant: ```c
void doThatArgThing(int argc, char *argv[]) {
  int i;
  char *buffer;
  for (i = 0; i < argc; i++) {
    printf("argument %i = %s\n", i, argv[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<doThatArgThing>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: argument %i = %s


assistant: ```c
void doThatArgThing(int argc, char *argv[]) {
  int i;
  char *buffer;
  for (i = 0; i < argc; i++) {
    printf("argument %i = %s\n", i, argv[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die_perror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%edi
  call   <die@plt>
  nop
  leave
  ret
```

assistant: ```c
void die_perror(const char *msg) {
  perror(msg);
  die(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<die_perror>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x0,%edi
  call   <die@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die_perror(const char *msg) {
  perror(msg);
  die(0);
}
```