ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<stateval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x1,-0x2c(%rbp)
  jne    L38
  movl   $0x64,-0xc(%rbp)
  movl   $0xffffff9c,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L93
L38:
  movl   $0xffffff9c,-0xc(%rbp)
  movl   $0x64,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
L93:
  movl   $0x0,-0x14(%rbp)
  jmp    L61
L46:
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L71
L47:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D6(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L71:
  cmpl   $0x2,-0x10(%rbp)
  jle    L47
  cmpl   $0x3,-0x18(%rbp)
  jne    L54
  mov    -0xc(%rbp),%eax
  jmp    L62
L54:
  cmpl   $0xc,-0x18(%rbp)
  jne    L13
  mov    -0x8(%rbp),%eax
  jmp    L62
L13:
  addl   $0x1,-0x14(%rbp)
L61:
  cmpl   $0x7,-0x14(%rbp)
  jle    L46
  mov    $0x0,%eax
L62:
  pop    %rbp
  ret
```

assistant: ```c
int stateval(board, whosemove)
int board[];
int whosemove;
{
  static int row[8][3] = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, {0, 3, 6}, {1, 4, 7}, {2, 5, 8}, {0, 4, 8}, {2, 4, 6}};
  int temp;
  int i, j;
  int side;
  int win, lose;
  if (whosemove == 1) {
    win = 100;
    lose = -100;
    side = 1;
  } else {
    win = -100;
    lose = 100;
    side = -1;
  }
  for (i = 0; i < 8; i++) {
    temp = 0;
    for (j = 0; j < 3; j++)
      temp += board[row[i][j]];
    if (temp == 3)
      return (win);
    if (temp == 12)
      return (lose);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stateval>:
  endbr64
  cmp    $0x1,%esi
  mov    $0xffffff9c,%eax
  mov    $0x64,%edx
  cmove  %eax,%edx
  mov    %edx,%r11d
  mov    $0x64,%r10d
  cmovne %eax,%r10d
  lea    D1(%rip),%rsi
  lea    0x60(%rsi),%r9
  mov    $0x0,%r8d
  jmp    L35
L44:
  cmp    $0x3,%edx
  je     L54
  cmp    $0xc,%edx
  je     L15
  add    $0xc,%rsi
  cmp    %r9,%rsi
  je     L5
L35:
  mov    $0x0,%eax
  mov    %r8d,%edx
L56:
  movslq (%rsi,%rax,4),%rcx
  add    (%rdi,%rcx,4),%edx
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L56
  jmp    L44
L15:
  mov    %r11d,%r10d
  jmp    L54
L5:
  mov    $0x0,%r10d
L54:
  mov    %r10d,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: 

assistant: ```c
int stateval(board, whosemove)
int board[];
int whosemove;
{
  static int row[8][3] = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, {0, 3, 6}, {1, 4, 7}, {2, 5, 8}, {0, 4, 8}, {2, 4, 6}};
  int temp;
  int i, j;
  int side;
  int win, lose;
  if (whosemove == 1) {
    win = 100;
    lose = -100;
    side = 1;
  } else {
    win = -100;
    lose = 100;
    side = -1;
  }
  for (i = 0; i < 8; i++) {
    temp = 0;
    for (j = 0; j < 3; j++)
      temp += board[row[i][j]];
    if (temp == 3)
      return (win);
    if (temp == 12)
      return (lose);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stateval>:
  endbr64
  mov    $0x64,%eax
  cmp    $0x1,%esi
  mov    $0xffffff9c,%edx
  mov    %rdi,%rcx
  mov    %eax,%r9d
  cmove  %edx,%r9d
  cmove  %eax,%edx
  xor    %eax,%eax
  mov    %edx,%r8d
  lea    D1(%rip),%rdx
  lea    0x60(%rdx),%rdi
  jmp    L5
L23:
  movslq -0x4(%rdx),%rax
L5:
  movslq (%rdx),%rsi
  mov    (%rcx,%rax,4),%eax
  add    (%rcx,%rsi,4),%eax
  movslq 0x4(%rdx),%rsi
  add    (%rcx,%rsi,4),%eax
  cmp    $0x3,%eax
  je     L25
  cmp    $0xc,%eax
  je     L19
  add    $0xc,%rdx
  cmp    %rdx,%rdi
  jne    L23
  xor    %r8d,%r8d
L25:
  mov    %r8d,%eax
  ret
L19:
  mov    %r9d,%r8d
  mov    %r8d,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D1: 

assistant: ```c
int stateval(board, whosemove)
int board[];
int whosemove;
{
  static int row[8][3] = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, {0, 3, 6}, {1, 4, 7}, {2, 5, 8}, {0, 4, 8}, {2, 4, 6}};
  int temp;
  int i, j;
  int side;
  int win, lose;
  if (whosemove == 1) {
    win = 100;
    lose = -100;
    side = 1;
  } else {
    win = -100;
    lose = 100;
    side = -1;
  }
  for (i = 0; i < 8; i++) {
    temp = 0;
    for (j = 0; j < 3; j++)
      temp += board[row[i][j]];
    if (temp == 3)
      return (win);
    if (temp == 12)
      return (lose);
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stateval>:
  endbr64
  mov    %rdi,%rax
  push   %r12
  mov    $0x64,%r8d
  mov    $0xffffff9c,%edx
  push   %rbp
  cmp    $0x1,%esi
  mov    %r8d,%edi
  push   %rbx
  mov    (%rax),%r9d
  cmove  %edx,%edi
  cmovne %edx,%r8d
  mov    0x4(%rax),%ebx
  mov    0x8(%rax),%ecx
  lea    (%rbx,%r9,1),%edx
  add    %ecx,%edx
  cmp    $0x3,%edx
  je     L49
  cmp    $0xc,%edx
  je     L64
  mov    0xc(%rax),%edx
  mov    0x10(%rax),%r11d
  mov    0x14(%rax),%esi
  lea    (%rdx,%r11,1),%r10d
  add    %esi,%r10d
  cmp    $0x3,%r10d
  je     L49
  cmp    $0xc,%r10d
  je     L64
  mov    0x18(%rax),%r10d
  mov    0x1c(%rax),%ebp
  mov    0x20(%rax),%eax
  lea    (%r10,%rbp,1),%r12d
  add    %eax,%r12d
  cmp    $0x3,%r12d
  je     L49
  cmp    $0xc,%r12d
  je     L64
  add    %r9d,%edx
  add    %r10d,%edx
  cmp    $0x3,%edx
  je     L49
  cmp    $0xc,%edx
  je     L64
  add    %r11d,%ebx
  add    %ebx,%ebp
  cmp    $0x3,%ebp
  je     L49
  cmp    $0xc,%ebp
  je     L64
  add    %ecx,%esi
  add    %eax,%esi
  cmp    $0x3,%esi
  je     L49
  cmp    $0xc,%esi
  je     L64
  add    %r11d,%r9d
  add    %r9d,%eax
  cmp    $0x3,%eax
  je     L49
  cmp    $0xc,%eax
  je     L64
  add    %r11d,%ecx
  add    %r10d,%ecx
  cmp    $0x3,%ecx
  je     L49
  xor    %r8d,%r8d
  cmp    $0xc,%ecx
  cmove  %edi,%r8d
L49:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
L64:
  mov    %edi,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  ret
```

assistant: ```c
int stateval(board, whosemove)
int board[];
int whosemove;
{
  static int row[8][3] = {{0, 1, 2}, {3, 4, 5}, {6, 7, 8}, {0, 3, 6}, {1, 4, 7}, {2, 5, 8}, {0, 4, 8}, {2, 4, 6}};
  int temp;
  int i, j;
  int side;
  int win, lose;
  if (whosemove == 1) {
    win = 100;
    lose = -100;
    side = 1;
  } else {
    win = -100;
    lose = 100;
    side = -1;
  }
  for (i = 0; i < 8; i++) {
    temp = 0;
    for (j = 0; j < 3; j++)
      temp += board[row[i][j]];
    if (temp == 3)
      return (win);
    if (temp == 12)
      return (lose);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<destroySSL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ERR_free_strings@plt>
  mov    $0x0,%eax
  call   <EVP_cleanup@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void destroySSL() {
  ERR_free_strings();
  EVP_cleanup();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<destroySSL>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ERR_free_strings@plt>
  mov    $0x0,%eax
  call   <EVP_cleanup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void destroySSL() {
  ERR_free_strings();
  EVP_cleanup();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<destroySSL>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ERR_free_strings@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <EVP_cleanup@plt>
```

assistant: ```c
void destroySSL() {
  ERR_free_strings();
  EVP_cleanup();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<destroySSL>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ERR_free_strings@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <EVP_cleanup@plt>
```

assistant: ```c
void destroySSL() {
  ERR_free_strings();
  EVP_cleanup();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f14>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f14(void *a, int b, int *c, int *d) {
  asm volatile("" : : "r"(a), "r"(b), "r"(c), "r"(d) : "memory");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f14>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f14(void *a, int b, int *c, int *d) {
  asm volatile("" : : "r"(a), "r"(b), "r"(c), "r"(d) : "memory");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f14>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f14(void *a, int b, int *c, int *d) {
  asm volatile("" : : "r"(a), "r"(b), "r"(c), "r"(d) : "memory");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f14>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f14(void *a, int b, int *c, int *d) {
  asm volatile("" : : "r"(a), "r"(b), "r"(c), "r"(d) : "memory");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CG_ParseTagConnects>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x33d,-0x4(%rbp)
  jmp    L12
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <CG_ParseTagConnect@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x37c,-0x4(%rbp)
  jle    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void CG_ParseTagConnects(void) {
  int i;
  for (i = ((((((((((((64 + 256) + 256) + 32) + 1) + 64) + 16) + 64) + 16) + 18) + 18) + 16) + 8); i < ((((((((((((64 + 256) + 256) + 32) + 1) + 64) + 16) + 64) + 16) + 18) + 18) + 16) + 8) + 64; i++) {
    CG_ParseTagConnect(i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CG_ParseTagConnects>:
  endbr64
  push   %rbx
  mov    $0x33d,%ebx
L1:
  mov    %ebx,%edi
  call   <CG_ParseTagConnect@plt>
  add    $0x1,%ebx
  cmp    $0x37d,%ebx
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
void CG_ParseTagConnects(void) {
  int i;
  for (i = ((((((((((((64 + 256) + 256) + 32) + 1) + 64) + 16) + 64) + 16) + 18) + 18) + 16) + 8); i < ((((((((((((64 + 256) + 256) + 32) + 1) + 64) + 16) + 64) + 16) + 18) + 18) + 16) + 8) + 64; i++) {
    CG_ParseTagConnect(i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CG_ParseTagConnects>:
  endbr64
  push   %rbx
  mov    $0x33d,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <CG_ParseTagConnect@plt>
  cmp    $0x37d,%ebx
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void CG_ParseTagConnects(void) {
  int i;
  for (i = ((((((((((((64 + 256) + 256) + 32) + 1) + 64) + 16) + 64) + 16) + 18) + 18) + 16) + 8); i < ((((((((((((64 + 256) + 256) + 32) + 1) + 64) + 16) + 64) + 16) + 18) + 18) + 16) + 8) + 64; i++) {
    CG_ParseTagConnect(i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CG_ParseTagConnects>:
  endbr64
  push   %rbx
  mov    $0x33d,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <CG_ParseTagConnect@plt>
  cmp    $0x37d,%ebx
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void CG_ParseTagConnects(void) {
  int i;
  for (i = ((((((((((((64 + 256) + 256) + 32) + 1) + 64) + 16) + 64) + 16) + 18) + 18) + 16) + 8); i < ((((((((((((64 + 256) + 256) + 32) + 1) + 64) + 16) + 64) + 16) + 18) + 18) + 16) + 8) + 64; i++) {
    CG_ParseTagConnect(i);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%eax
  add    $0x20,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <foo@plt>
  cmpl   $0x3,-0xc(%rbp)
  jbe    L15
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%eax
  add    $0x10,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <foo@plt>
  jmp    L8
L15:
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%eax
  add    $0x30,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <foo@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void f(int *p, unsigned int n) {
  foo(*(p + n * 4));
  foo(*(p + 32 + n * 4));
  if (n > 3)
    foo(*(p + 16 + n * 4));
  else
    foo(*(p + 48 + n * 4));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    0x0(,%rsi,4),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%r12
  mov    (%rdi,%rax,4),%edi
  call   <foo@plt>
  mov    0x80(%rbx,%r12,1),%edi
  call   <foo@plt>
  cmp    $0x3,%ebp
  jbe    L7
  mov    0x40(%rbx,%r12,1),%edi
  call   <foo@plt>
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    0xc0(%rbx,%r12,1),%edi
  call   <foo@plt>
  jmp    L0
```

assistant: ```c
void f(int *p, unsigned int n) {
  foo(*(p + n * 4));
  foo(*(p + 32 + n * 4));
  if (n > 3)
    foo(*(p + 16 + n * 4));
  else
    foo(*(p + 48 + n * 4));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  push   %r12
  lea    0x0(,%rsi,4),%eax
  push   %rbp
  lea    0x0(,%rax,4),%r12
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi,%rax,4),%edi
  call   <foo@plt>
  mov    0x80(%rbx,%r12,1),%edi
  call   <foo@plt>
  cmp    $0x3,%ebp
  jbe    L9
  mov    0x40(%rbx,%r12,1),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <foo@plt>
  nopl   0x0(%rax)
L9:
  mov    0xc0(%rbx,%r12,1),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <foo@plt>
```

assistant: ```c
void f(int *p, unsigned int n) {
  foo(*(p + n * 4));
  foo(*(p + 32 + n * 4));
  if (n > 3)
    foo(*(p + 16 + n * 4));
  else
    foo(*(p + 48 + n * 4));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  push   %r12
  lea    0x0(,%rsi,4),%eax
  push   %rbp
  lea    0x0(,%rax,4),%r12
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi,%rax,4),%edi
  call   <foo@plt>
  mov    0x80(%rbx,%r12,1),%edi
  call   <foo@plt>
  cmp    $0x3,%ebp
  jbe    L6
  mov    0x40(%rbx,%r12,1),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <foo@plt>
  nopl   0x0(%rax)
L6:
  mov    0xc0(%rbx,%r12,1),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <foo@plt>
```

assistant: ```c
void f(int *p, unsigned int n) {
  foo(*(p + n * 4));
  foo(*(p + 32 + n * 4));
  if (n > 3)
    foo(*(p + 16 + n * 4));
  else
    foo(*(p + 48 + n * 4));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string

tool: D9: %d

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  printf("%d", is_prime(num));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: %d

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  printf("%d", is_prime(num));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: %d

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  printf("%d", is_prime(num));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  printf("%d", is_prime(num));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<readInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L20
L21:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L20:
  cmpl   $0x1f,-0x14(%rbp)
  jg     L16
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L21
L16:
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int readInput(char string[]) {
  int i;
  for (i = 0; i < 32 && string[i - 1] != '\n'; i++)
    string[i] = getchar();
  string[i - 1] = '\0';
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readInput>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L10:
  cmpb   $0xa,-0x1(%rbx)
  je     L9
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    $0x20,%ebp
  jne    L10
L9:
  movslq %ebp,%rbp
  movb   $0x0,-0x1(%r12,%rbp,1)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int readInput(char string[]) {
  int i;
  for (i = 0; i < 32 && string[i - 1] != '\n'; i++)
    string[i] = getchar();
  string[i - 1] = '\0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readInput>:
  endbr64
  push   %r12
  lea    0x1f(%rdi),%r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdi),%rbx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %al,0x1(%rbx)
  lea    0x1(%rbp),%rbx
  cmp    %rbx,%r12
  je     L10
L26:
  cmpb   $0xa,(%rbx)
  mov    %rbx,%rbp
  jne    L17
  movb   $0x0,0x0(%rbp)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L10:
  mov    %r12,%rbp
  xor    %eax,%eax
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int readInput(char string[]) {
  int i;
  for (i = 0; i < 32 && string[i - 1] != '\n'; i++)
    string[i] = getchar();
  string[i - 1] = '\0';
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readInput>:
  endbr64
  push   %r12
  lea    0x1f(%rdi),%r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdi),%rbx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %al,0x1(%rbx)
  lea    0x1(%rbp),%rbx
  cmp    %r12,%rbx
  je     L0
L13:
  cmpb   $0xa,(%rbx)
  mov    %rbx,%rbp
  jne    L2
  movb   $0x0,0x0(%rbp)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  mov    %rbx,%rbp
  xor    %eax,%eax
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int readInput(char string[]) {
  int i;
  for (i = 0; i < 32 && string[i - 1] != '\n'; i++)
    string[i] = getchar();
  string[i - 1] = '\0';
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_check_null>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x79,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <_throw_null_fn@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pippijn/cyclone/refs/heads/master/old/bin/cyc-lib/vc_cyc_include.h

assistant: ```c
void *_check_null(void *ptr) {
  if (ptr == 0)
    (_throw_null_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pippijn/cyclone/refs/heads/master/old/bin/cyc-lib/vc_cyc_include.h", 121));
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_check_null>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L11
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
L11:
  mov    $0x79,%esi
  lea    D2(%rip),%rdi
  call   <_throw_null_fn@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pippijn/cyclone/refs/heads/master/old/bin/cyc-lib/vc_cyc_include.h

assistant: ```c
void *_check_null(void *ptr) {
  if (ptr == 0)
    (_throw_null_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pippijn/cyclone/refs/heads/master/old/bin/cyc-lib/vc_cyc_include.h", 121));
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_check_null>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L9
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    $0x79,%esi
  lea    D3(%rip),%rdi
  call   <_throw_null_fn@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pippijn/cyclone/refs/heads/master/old/bin/cyc-lib/vc_cyc_include.h

assistant: ```c
void *_check_null(void *ptr) {
  if (ptr == 0)
    (_throw_null_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pippijn/cyclone/refs/heads/master/old/bin/cyc-lib/vc_cyc_include.h", 121));
  return ptr;
}
```