ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L32:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L32
  sub    $0x28,%rsp
  mov    $0x10000,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x20018(%rsp)
  xor    %eax,%eax
  lea    0x10010(%rsp),%rax
  lea    0x10111(%rsp),%r13
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  lea    0x30e(%rsp),%r12
  call   <memset@plt>
  lea    D37(%rip),%rsi
  lea    D40(%rip),%rdi
  call   <fopen@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x10000,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fread@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    0x1010e(%rsp),%rax
  mov    %rax,(%rsp)
L24:
  lea    -0xfe(%r12),%rbx
  lea    -0x1fe(%r12),%r14
  mov    %r13,%r15
  lea    -0x2fe(%r12),%rbp
  cs nopw 0x0(%rax,%rax,1)
L35:
  movzbl 0x2(%rbx),%eax
  sub    $0x8,%rsp
  movzbl (%r14),%ecx
  add    $0x1,%rbx
  movzbl 0x2(%rbp),%edx
  movzbl 0x1(%rbp),%esi
  add    $0x1,%r14
  add    $0x1,%rbp
  movzbl 0x1(%r14),%r9d
  movzbl (%r14),%r8d
  add    $0x1,%r15
  movzbl -0x1(%rbp),%edi
  push   %rax
  movzbl (%rbx),%eax
  push   %rax
  movzbl -0x1(%rbx),%eax
  push   %rax
  call   <laplacian@plt>
  add    $0x20,%rsp
  mov    %al,-0x1(%r15)
  cmp    %r12,%rbx
  jne    L35
  add    $0x100,%r13
  lea    0x100(%rbx),%r12
  cmp    (%rsp),%r12
  jne    L24
  lea    D26(%rip),%rsi
  lea    D28(%rip),%rdi
  call   <fopen@plt>
  mov    0x8(%rsp),%rdi
  mov    $0x10000,%edx
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D19(%rip),%rdi
  call   <system@plt>
  mov    0x20018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x20028,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D37
type: string
name: retrieve_data
arguments: data_label: D40
type: string
name: retrieve_data
arguments: data_label: D26
type: string
name: retrieve_data
arguments: data_label: D28
type: string
name: retrieve_data
arguments: data_label: D19
type: string

tool: D37: rb

tool: D40: girl.dat

tool: D26: wb

tool: D28: girl_laplacian.dat

tool: D19: zsh plot_ex1-2.sh

assistant: ```c
int main() {
  unsigned char image[256][256];
  unsigned char image_w[256][256] = {0};
  FILE *fp;
  fp = fopen("girl.dat", "rb");
  fread(image, sizeof(unsigned char), 256 * 256, fp);
  fclose(fp);
  for (int i = 1; i < 256 - 1; i++) {
    for (int j = 1; j < 256 - 1; j++) {
      image_w[i][j] = laplacian(image[i - 1][j - 1], image[i - 1][j], image[i - 1][j + 1], image[i][j - 1], image[i][j], image[i][j + 1], image[i + 1][j - 1], image[i + 1][j], image[i + 1][j + 1]);
    }
  }
  fp = fopen("girl_laplacian.dat", "wb");
  fwrite(image_w, sizeof(unsigned char), 256 * 256, fp);
  fclose(fp);
  system("zsh plot_ex1-2.sh");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f6620736b656547,%rax
  movabs $0x736b6565472072,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L6
L17:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L6:
  mov    -0x30(%rbp),%rax
  lea    -0x30(%rbp),%rdx
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtok_r@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string

tool: D6: %s


tool: D11:  

assistant: ```c
int main() {
  char str[] = "Geeks for Geeks";
  char *token;
  char *rest = str;
  while ((token = strtok_r(rest, " ", &rest)))
    printf("%s\n", token);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6f6620736b656547,%rax
  movabs $0x736b6565472072,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  lea    D8(%rip),%rbx
  lea    D12(%rip),%r12
  jmp    L23
L10:
  mov    %r12,%rdi
  call   <printf@plt>
L23:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <strtok_r@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L10
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string
name: retrieve_data
arguments: tag: D12
type_infered: string

tool: D8:  

tool: D12: %s


assistant: ```c
int main() {
  char str[] = "Geeks for Geeks";
  char *token;
  char *rest = str;
  while ((token = strtok_r(rest, " ", &rest)))
    printf("%s\n", token);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x30,%rsp
  movdqa D23(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0x8(%rsp),%rbp
  mov    %rdi,0x8(%rsp)
  movaps %xmm0,0x10(%rsp)
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
L13:
  mov    %rbx,%rsi
  mov    %rbp,%rdx
  call   <strtok_r@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L8
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: byte[16]

tool: D19: %s


tool: D16:  

tool: {"D23": [0x47,0x65,0x65,0x6b,0x73,0x20,0x66,0x6f,0x72,0x20,0x47,0x65,0x65,0x6b,0x73,0x00]}

assistant: ```c
int main() {
  char str[] = "Geeks for Geeks";
  char *token;
  char *rest = str;
  while ((token = strtok_r(rest, " ", &rest)))
    printf("%s\n", token);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D26(%rip),%rbx
  sub    $0x30,%rsp
  movdqa D20(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0x8(%rsp),%rbp
  mov    %rdi,0x8(%rsp)
  movaps %xmm0,0x10(%rsp)
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
L28:
  mov    %rbx,%rsi
  mov    %rbp,%rdx
  call   <strtok_r@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L18
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D26
datatype: string
name: unpack_data
arguments: label: D20
datatype: byte[16]

tool: D4: %s


tool: D26:  

tool: {"D20": [0x47,0x65,0x65,0x6b,0x73,0x20,0x66,0x6f,0x72,0x20,0x47,0x65,0x65,0x6b,0x73,0x00]}

assistant: ```c
int main() {
  char str[] = "Geeks for Geeks";
  char *token;
  char *rest = str;
  while ((token = strtok_r(rest, " ", &rest)))
    printf("%s\n", token);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <rush@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  rush(5, 3);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <rush@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  rush(5, 3);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <rush@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  rush(5, 3);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <rush@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  rush(5, 3);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hexchar_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L26
  cmpb   $0x39,-0x4(%rbp)
  jg     L26
  movzbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L75
L26:
  cmpb   $0x60,-0x4(%rbp)
  jle    L39
  cmpb   $0x66,-0x4(%rbp)
  jg     L39
  movzbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L75
L39:
  cmpb   $0x40,-0x4(%rbp)
  jle    L89
  cmpb   $0x46,-0x4(%rbp)
  jg     L89
  movzbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L75
L89:
  mov    $0xffffffff,%eax
L75:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char hexchar_to_int(char c) {
  if (((c) >= '0' && (c) <= '9'))
    return c - '0';
  else if (((c) >= 'a' && (c) <= 'f'))
    return c - ('a' - 0xa);
  else if (((c) >= 'A' && (c) <= 'F'))
    return c - ('A' - 0xa);
  else
    return 0xff;
}
```
user: What is the c source code of the assembly code below:

```asm
<hexchar_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L14
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L6
  lea    -0x41(%rdi),%eax
  sub    $0x37,%edi
  cmp    $0x6,%al
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L14:
  ret
L6:
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
unsigned char hexchar_to_int(char c) {
  if (((c) >= '0' && (c) <= '9'))
    return c - '0';
  else if (((c) >= 'a' && (c) <= 'f'))
    return c - ('a' - 0xa);
  else if (((c) >= 'A' && (c) <= 'F'))
    return c - ('A' - 0xa);
  else
    return 0xff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hexchar_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L9
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L14
  lea    -0x41(%rdi),%eax
  sub    $0x37,%edi
  cmp    $0x6,%al
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L9:
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
unsigned char hexchar_to_int(char c) {
  if (((c) >= '0' && (c) <= '9'))
    return c - '0';
  else if (((c) >= 'a' && (c) <= 'f'))
    return c - ('a' - 0xa);
  else if (((c) >= 'A' && (c) <= 'F'))
    return c - ('A' - 0xa);
  else
    return 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<hexchar_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L5
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L2
  lea    -0x41(%rdi),%eax
  sub    $0x37,%edi
  cmp    $0x6,%al
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L5:
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
unsigned char hexchar_to_int(char c) {
  if (((c) >= '0' && (c) <= '9'))
    return c - '0';
  else if (((c) >= 'a' && (c) <= 'f'))
    return c - ('a' - 0xa);
  else if (((c) >= 'A' && (c) <= 'F'))
    return c - ('A' - 0xa);
  else
    return 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<select_kth_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L78
L61:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L38:
  nop
L16:
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L16
  nop
L26:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L26
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L9
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L38
L9:
  nop
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L41
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L41:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jg     L78
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L78:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L61
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int select_kth_int(int a[], int N, int k) {
  int i, j, l, r, v, w;
  l = 0;
  r = N - 1;
  while (r > l) {
    v = a[r];
    i = l - 1;
    j = r;
    for (;;) {
      while (a[++i] < v)
        ;
      while (a[--j] > v)
        ;
      if (i >= j)
        break;
      w = a[i];
      a[i] = a[j];
      a[j] = w;
    }
    w = a[i];
    a[i] = a[r];
    a[r] = w;
    if (i >= k)
      r = i - 1;
    if (i <= k)
      l = i + 1;
  }
  return a[k];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<select_kth_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %edx,%r15d
  lea    -0x1(%rsi),%r13d
  test   %r13d,%r13d
  jle    L101
  mov    $0x0,%r14d
  jmp    L62
L84:
  add    $0x4,%r8
  mov    %r9d,%r11d
L51:
  lea    0x1(%r11),%r9d
  mov    %r8,%rbx
  mov    (%r8),%r10d
  cmp    %esi,%r10d
  jl     L84
  movslq %edx,%rax
  lea    -0x4(%rbp,%rax,4),%rax
L19:
  sub    $0x1,%edx
  mov    %rax,%rdi
  sub    $0x4,%rax
  mov    0x4(%rax),%ecx
  cmp    %esi,%ecx
  jg     L19
  cmp    %edx,%r9d
  jge    L107
  mov    %ecx,(%rbx)
  mov    %r10d,(%rdi)
  jmp    L84
L107:
  mov    (%r12),%eax
  mov    %eax,(%rbx)
  mov    %r10d,(%r12)
  cmp    %r9d,%r15d
  jg     L99
  je     L18
  mov    %r11d,%r13d
  jmp    L70
L18:
  mov    %r11d,%r13d
L99:
  lea    0x2(%r11),%r14d
L70:
  cmp    %r13d,%r14d
  jge    L101
L62:
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%r12
  mov    (%r12),%esi
  lea    -0x1(%r14),%r11d
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,4),%r8
  mov    %r13d,%edx
  jmp    L51
L101:
  movslq %r15d,%r15
  mov    0x0(%rbp,%r15,4),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int select_kth_int(int a[], int N, int k) {
  int i, j, l, r, v, w;
  l = 0;
  r = N - 1;
  while (r > l) {
    v = a[r];
    i = l - 1;
    j = r;
    for (;;) {
      while (a[++i] < v)
        ;
      while (a[--j] > v)
        ;
      if (i >= j)
        break;
      w = a[i];
      a[i] = a[j];
      a[j] = w;
    }
    w = a[i];
    a[i] = a[r];
    a[r] = w;
    if (i >= k)
      r = i - 1;
    if (i <= k)
      l = i + 1;
  }
  return a[k];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<select_kth_int>:
  endbr64
  push   %r14
  movslq %edx,%r14
  push   %r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %r12d,%r12d
  jle    L48
  xor    %r13d,%r13d
  xchg   %ax,%ax
L16:
  movslq %r12d,%rax
  lea    -0x1(%r13),%r11d
  mov    %r12d,%edx
  lea    (%rbx,%rax,4),%rbp
  movslq %r13d,%rax
  mov    0x0(%rbp),%esi
  lea    (%rbx,%rax,4),%r8
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%r8),%r10d
  lea    0x1(%r11),%r9d
  cmp    %esi,%r10d
  jl     L78
  movslq %edx,%rax
  lea    -0x4(%rbx,%rax,4),%rax
  nopl   0x0(%rax)
L19:
  mov    %rax,%rdi
  mov    (%rax),%ecx
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %esi,%ecx
  jg     L19
  cmp    %edx,%r9d
  jge    L1
  mov    %ecx,(%r8)
  mov    %r10d,(%rdi)
L78:
  add    $0x4,%r8
  mov    %r9d,%r11d
  jmp    L18
  nopl   0x0(%rax)
L1:
  mov    0x0(%rbp),%eax
  mov    %eax,(%r8)
  mov    %r10d,0x0(%rbp)
  cmp    %r9d,%r14d
  jg     L21
  mov    %r11d,%r12d
  je     L21
L65:
  cmp    %r13d,%r12d
  jg     L16
L48:
  mov    (%rbx,%r14,4),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  lea    0x2(%r11),%r13d
  jmp    L65
```

assistant: ```c
int select_kth_int(int a[], int N, int k) {
  int i, j, l, r, v, w;
  l = 0;
  r = N - 1;
  while (r > l) {
    v = a[r];
    i = l - 1;
    j = r;
    for (;;) {
      while (a[++i] < v)
        ;
      while (a[--j] > v)
        ;
      if (i >= j)
        break;
      w = a[i];
      a[i] = a[j];
      a[j] = w;
    }
    w = a[i];
    a[i] = a[r];
    a[r] = w;
    if (i >= k)
      r = i - 1;
    if (i <= k)
      l = i + 1;
  }
  return a[k];
}
```
user: Translate the below assembly code into C programming language:

```asm
<select_kth_int>:
  endbr64
  push   %r14
  movslq %edx,%r14
  push   %r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %r12d,%r12d
  jle    L15
  xor    %r13d,%r13d
  xchg   %ax,%ax
L74:
  movslq %r12d,%rax
  lea    -0x1(%r13),%r11d
  mov    %r12d,%edx
  lea    (%rbx,%rax,4),%rbp
  movslq %r13d,%rax
  mov    0x0(%rbp),%esi
  lea    (%rbx,%rax,4),%r8
  nopl   0x0(%rax,%rax,1)
L36:
  mov    (%r8),%r10d
  lea    0x1(%r11),%r9d
  cmp    %esi,%r10d
  jl     L39
  movslq %edx,%rax
  lea    -0x4(%rbx,%rax,4),%rax
  nopl   0x0(%rax)
L19:
  mov    %rax,%rdi
  mov    (%rax),%ecx
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %esi,%ecx
  jg     L19
  cmp    %edx,%r9d
  jge    L47
  mov    %ecx,(%r8)
  mov    %r10d,(%rdi)
L39:
  add    $0x4,%r8
  mov    %r9d,%r11d
  jmp    L36
  nopl   0x0(%rax)
L47:
  mov    0x0(%rbp),%eax
  mov    %eax,(%r8)
  mov    %r10d,0x0(%rbp)
  cmp    %r9d,%r14d
  jg     L23
  mov    %r11d,%r12d
  je     L23
L17:
  cmp    %r13d,%r12d
  jg     L74
L15:
  mov    (%rbx,%r14,4),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  lea    0x2(%r11),%r13d
  jmp    L17
```

assistant: ```c
int select_kth_int(int a[], int N, int k) {
  int i, j, l, r, v, w;
  l = 0;
  r = N - 1;
  while (r > l) {
    v = a[r];
    i = l - 1;
    j = r;
    for (;;) {
      while (a[++i] < v)
        ;
      while (a[--j] > v)
        ;
      if (i >= j)
        break;
      w = a[i];
      a[i] = a[j];
      a[j] = w;
    }
    w = a[i];
    a[i] = a[r];
    a[r] = w;
    if (i >= k)
      r = i - 1;
    if (i <= k)
      l = i + 1;
  }
  return a[k];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_app_final>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ogs_dbi_final@plt>
  mov    $0x0,%eax
  call   <ogs_sctp_final@plt>
  mov    $0x0,%eax
  call   <test_context_final@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_app_final(void) {
  ogs_dbi_final();
  ogs_sctp_final();
  test_context_final();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_app_final>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ogs_dbi_final@plt>
  mov    $0x0,%eax
  call   <ogs_sctp_final@plt>
  mov    $0x0,%eax
  call   <test_context_final@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_app_final(void) {
  ogs_dbi_final();
  ogs_sctp_final();
  test_context_final();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_app_final>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ogs_dbi_final@plt>
  xor    %eax,%eax
  call   <ogs_sctp_final@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <test_context_final@plt>
```

assistant: ```c
void test_app_final(void) {
  ogs_dbi_final();
  ogs_sctp_final();
  test_context_final();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_app_final>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ogs_dbi_final@plt>
  xor    %eax,%eax
  call   <ogs_sctp_final@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <test_context_final@plt>
```

assistant: ```c
void test_app_final(void) {
  ogs_dbi_final();
  ogs_sctp_final();
  test_context_final();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ALT_to_SP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D29(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D36(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  D36(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    D18(%rip),%rdx
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <pow@plt>
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D29
datatype: f64
name: parse_data
arguments: label: D36
datatype: f64
name: parse_data
arguments: label: D18
datatype: f64

tool: D29: 0.0065

tool: D36: 288

tool: D18: 5.2561

assistant: ```c
double ALT_to_SP(double in, double meters) {
  double sp = in * pow((288 - 0.0065 * meters) / 288, 5.2561);
  return sp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ALT_to_SP>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  mulsd  D0(%rip),%xmm1
  movsd  D18(%rip),%xmm2
  movapd %xmm2,%xmm0
  subsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%edi
  movsd  D25(%rip),%xmm0
  call   <pow@plt>
  movq   %rbx,%xmm3
  mulsd  %xmm3,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: f64
name: parse_data
arguments: data_tag: D18
datatype: f64
name: parse_data
arguments: data_tag: D25
datatype: f64

tool: D0: 0.0065

tool: D18: 288

tool: D25: 5.2561

assistant: ```c
double ALT_to_SP(double in, double meters) {
  double sp = in * pow((288 - 0.0065 * meters) / 288, 5.2561);
  return sp;
}
```