ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%r8d
  mov    $0x5,%esi
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %rax,(%rsp)
  jmp    L73
  nopw   0x0(%rax,%rax,1)
L71:
  add    $0x2,%esi
  cmp    $0x65,%esi
  je     L22
L73:
  lea    0x8(%rsp),%rdi
  mov    $0x3,%ecx
  cmp    $0x8,%esi
  jle    L14
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L71
  mov    (%rdi),%ecx
  mov    %esi,%eax
  add    $0x4,%rdi
  cltd
  idiv   %ecx
  cmp    %eax,%ecx
  jle    L9
L14:
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %esi,(%rsp,%rax,4)
  add    $0x2,%esi
  cmp    $0x65,%esi
  jne    L73
L22:
  lea    -0x1(%r8),%eax
  mov    %rsp,%rbx
  lea    D2(%rip),%rbp
  lea    0x4(%rsp,%rax,4),%r12
  nopl   (%rax)
L69:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L69
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: byte[8]
name: read_data
arguments: data_label: D2
type_infered: string

tool: {"D8": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D2: %i 

assistant: ```c
int main(void) {
  int p, i, primes[50], primeIndex = 2;
  bool isPrime;
  primes[0] = 2;
  primes[1] = 3;
  for (p = 5; p <= 100; p = p + 2) {
    isPrime = true;
    for (i = 1; isPrime && p / primes[i] >= primes[i]; ++i) {
      if (p % primes[i] == 0)
        isPrime = false;
    }
    if (isPrime == true) {
      primes[primeIndex] = p;
      ++primeIndex;
    }
  }
  for (i = 0; i < primeIndex; ++i)
    printf("%i ", primes[i]);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x11,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: %ld


assistant: ```c
long main() {
  long x;
  x = 2 * 7 + 3;
  printf("%ld\n", x);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D8: %ld


assistant: ```c
long main() {
  long x;
  x = 2 * 7 + 3;
  printf("%ld\n", x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: %ld


assistant: ```c
long main() {
  long x;
  x = 2 * 7 + 3;
  printf("%ld\n", x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D3: %ld


assistant: ```c
long main() {
  long x;
  x = 2 * 7 + 3;
  printf("%ld\n", x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_final_slashes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L11
L7:
  subl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L7
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void remove_final_slashes(char *path) {
  int n;
  n = strlen(path);
  while (path[n - 1] == '/') {
    n--;
  }
  path[n] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<remove_final_slashes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  cmpb   $0x2f,-0x1(%rbx,%rdx,1)
  jne    L3
  sub    $0x1,%eax
  cltq
L16:
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmpb   $0x2f,(%rbx,%rax,1)
  je     L16
L3:
  movb   $0x0,(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
void remove_final_slashes(char *path) {
  int n;
  n = strlen(path);
  while (path[n - 1] == '/') {
    n--;
  }
  path[n] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_final_slashes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  jne    L16
  lea    -0x1(%rax),%rdx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rdx,%rax
  sub    $0x1,%rdx
  cmpb   $0x2f,(%rbx,%rdx,1)
  je     L2
L16:
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void remove_final_slashes(char *path) {
  int n;
  n = strlen(path);
  while (path[n - 1] == '/') {
    n--;
  }
  path[n] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<remove_final_slashes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  jne    L10
  lea    -0x1(%rax),%rdx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdx,%rax
  sub    $0x1,%rdx
  cmpb   $0x2f,(%rbx,%rdx,1)
  je     L6
L10:
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void remove_final_slashes(char *path) {
  int n;
  n = strlen(path);
  while (path[n - 1] == '/') {
    n--;
  }
  path[n] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<make_absolute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L3
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L0
L3:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L59
L0:
  cmpq   $0x0,-0x30(%rbp)
  je     L33
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x2(%rax),%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L62
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L62
L33:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x2e,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x2f,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movb   $0x0,(%rax)
  movl   $0x2,-0x1c(%rbp)
L62:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
L59:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *make_absolute(char const *string, char const *dot_path) {
  char *result;
  int result_len;
  if (!dot_path || *string == '/') {
    result = strdup(string);
  } else {
    if (dot_path && dot_path[0]) {
      result = malloc(2 + strlen(dot_path) + strlen(string));
      strcpy(result, dot_path);
      result_len = (int)strlen(result);
      if (result[result_len - 1] != '/') {
        result[result_len++] = '/';
        result[result_len] = '\0';
      }
    } else {
      result = malloc(3 + strlen(string));
      result[0] = '.';
      result[1] = '/';
      result[2] = '\0';
      result_len = 2;
    }
    strcpy(result + result_len, string);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<make_absolute>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L23
  mov    %rsi,%r12
  cmpb   $0x2f,(%rdi)
  je     L23
  cmpb   $0x0,(%rsi)
  je     L6
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  movslq %eax,%rdx
  cmpb   $0x2f,-0x1(%rbx,%rdx,1)
  je     L47
  lea    0x1(%rax),%edi
  movb   $0x2f,(%rbx,%rdx,1)
  movslq %edi,%rax
  movb   $0x0,(%rbx,%rax,1)
  jmp    L47
L23:
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  jmp    L10
L6:
  call   <strlen@plt>
  lea    0x3(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  movb   $0x2e,(%rax)
  movb   $0x2f,0x1(%rax)
  movb   $0x0,0x2(%rax)
  mov    $0x2,%edi
L47:
  movslq %edi,%rdi
  add    %rbx,%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
L10:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *make_absolute(char const *string, char const *dot_path) {
  char *result;
  int result_len;
  if (!dot_path || *string == '/') {
    result = strdup(string);
  } else {
    if (dot_path && dot_path[0]) {
      result = malloc(2 + strlen(dot_path) + strlen(string));
      strcpy(result, dot_path);
      result_len = (int)strlen(result);
      if (result[result_len - 1] != '/') {
        result[result_len++] = '/';
        result[result_len] = '\0';
      }
    } else {
      result = malloc(3 + strlen(string));
      result[0] = '.';
      result[1] = '/';
      result[2] = '\0';
      result_len = 2;
    }
    strcpy(result + result_len, string);
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<make_absolute>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L14
  cmpb   $0x2f,(%rdi)
  je     L14
  mov    %rsi,%r12
  call   <strlen@plt>
  cmpb   $0x0,(%r12)
  mov    %rax,%r13
  jne    L18
  lea    0x3(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x2f2e,%eax
  mov    %ax,0x0(%r13)
  lea    0x2(%r13),%rdi
  movb   $0x0,0x2(%r13)
L10:
  mov    %rbp,%rsi
  call   <strcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%r13,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  cmpb   $0x2f,-0x1(%r13,%rdx,1)
  lea    0x0(%r13,%rdx,1),%rdi
  je     L10
  lea    0x1(%rax),%edi
  movb   $0x2f,0x0(%r13,%rdx,1)
  movslq %edi,%rdi
  add    %r13,%rdi
  movb   $0x0,(%rdi)
  jmp    L10
  nopl   0x0(%rax)
L14:
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <strdup@plt>
```

assistant: ```c
char *make_absolute(char const *string, char const *dot_path) {
  char *result;
  int result_len;
  if (!dot_path || *string == '/') {
    result = strdup(string);
  } else {
    if (dot_path && dot_path[0]) {
      result = malloc(2 + strlen(dot_path) + strlen(string));
      strcpy(result, dot_path);
      result_len = (int)strlen(result);
      if (result[result_len - 1] != '/') {
        result[result_len++] = '/';
        result[result_len] = '\0';
      }
    } else {
      result = malloc(3 + strlen(string));
      result[0] = '.';
      result[1] = '/';
      result[2] = '\0';
      result_len = 2;
    }
    strcpy(result + result_len, string);
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<make_absolute>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L41
  cmpb   $0x2f,(%rdi)
  je     L41
  mov    %rsi,%r12
  call   <strlen@plt>
  cmpb   $0x0,(%r12)
  mov    %rax,%r13
  jne    L17
  lea    0x3(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x2f2e,%eax
  mov    %ax,0x0(%r13)
  lea    0x2(%r13),%rdi
  movb   $0x0,0x2(%r13)
L13:
  mov    %rbp,%rsi
  call   <strcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%r13,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  cmpb   $0x2f,-0x1(%r13,%rdx,1)
  lea    0x0(%r13,%rdx,1),%rdi
  je     L13
  lea    0x1(%rax),%edi
  movb   $0x2f,0x0(%r13,%rdx,1)
  movslq %edi,%rdi
  add    %r13,%rdi
  movb   $0x0,(%rdi)
  jmp    L13
  nopl   0x0(%rax)
L41:
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <strdup@plt>
```

assistant: ```c
char *make_absolute(char const *string, char const *dot_path) {
  char *result;
  int result_len;
  if (!dot_path || *string == '/') {
    result = strdup(string);
  } else {
    if (dot_path && dot_path[0]) {
      result = malloc(2 + strlen(dot_path) + strlen(string));
      strcpy(result, dot_path);
      result_len = (int)strlen(result);
      if (result[result_len - 1] != '/') {
        result[result_len++] = '/';
        result[result_len] = '\0';
      }
    } else {
      result = malloc(3 + strlen(string));
      result[0] = '.';
      result[1] = '/';
      result[2] = '\0';
      result_len = 2;
    }
    strcpy(result + result_len, string);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_sequences_stockholm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L30:
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <byg_start@plt>
  test   %eax,%eax
  je     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <byg_end@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L26
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <byg_end@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0xffffffff,-0x10(%rbp)
  jne    L30
  jmp    L18
L0:
  nop
L18:
  cmpl   $0x0,-0x14(%rbp)
  jne    L58
  mov    $0x0,%eax
  jmp    L15
L58:
  mov    -0x14(%rbp),%eax
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D27
data_type: string

tool: D6: //

tool: D23: #

tool: D27: 


assistant: ```c
int count_sequences_stockholm(char *string) {
  char *p1 = string;
  int i = 0;
  int j = 0;
  int n = 0;
  while ((i = byg_end("\n", p1)) != -1) {
    p1 += i;
    if (!(byg_start("//", p1))) {
      break;
    }
    j = byg_end("#", p1);
    if (j != 1) {
      n++;
    }
  }
  if (!n) {
    return 0;
  }
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<count_sequences_stockholm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  lea    D9(%rip),%r12
  lea    D7(%rip),%r13
  lea    D24(%rip),%r14
  jmp    L28
L1:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <byg_end@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  add    %eax,%ebp
L28:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <byg_end@plt>
  cmp    $0xffffffff,%eax
  je     L25
  cltq
  add    %rax,%rbx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <byg_start@plt>
  test   %eax,%eax
  jne    L1
L25:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D24
datatype: string

tool: D9: 


tool: D7: //

tool: D24: #

assistant: ```c
int count_sequences_stockholm(char *string) {
  char *p1 = string;
  int i = 0;
  int j = 0;
  int n = 0;
  while ((i = byg_end("\n", p1)) != -1) {
    p1 += i;
    if (!(byg_start("//", p1))) {
      break;
    }
    j = byg_end("#", p1);
    if (j != 1) {
      n++;
    }
  }
  if (!n) {
    return 0;
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<count_sequences_stockholm>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D28(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  lea    D26(%rip),%rbx
  jmp    L11
  nopl   0x0(%rax)
L22:
  cltq
  mov    %rbp,%rdi
  add    %rax,%r14
  mov    %r14,%rsi
  call   <byg_start@plt>
  test   %eax,%eax
  je     L4
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <byg_end@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  add    %eax,%r12d
L11:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <byg_end@plt>
  cmp    $0xffffffff,%eax
  jne    L22
L4:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D26
type_infered: string

tool: D28: #

tool: D7: //

tool: D26: 


assistant: ```c
int count_sequences_stockholm(char *string) {
  char *p1 = string;
  int i = 0;
  int j = 0;
  int n = 0;
  while ((i = byg_end("\n", p1)) != -1) {
    p1 += i;
    if (!(byg_start("//", p1))) {
      break;
    }
    j = byg_end("#", p1);
    if (j != 1) {
      n++;
    }
  }
  if (!n) {
    return 0;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_sequences_stockholm>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  lea    D6(%rip),%rbx
  jmp    L23
  nopl   0x0(%rax)
L18:
  cltq
  mov    %rbp,%rdi
  add    %rax,%r14
  mov    %r14,%rsi
  call   <byg_start@plt>
  test   %eax,%eax
  je     L2
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <byg_end@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  add    %eax,%r12d
L23:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <byg_end@plt>
  cmp    $0xffffffff,%eax
  jne    L18
L2:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
datatype: string
name: retrieve_data
arguments: tag: D1
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string

tool: D13: #

tool: D1: //

tool: D6: 


assistant: ```c
int count_sequences_stockholm(char *string) {
  char *p1 = string;
  int i = 0;
  int j = 0;
  int n = 0;
  while ((i = byg_end("\n", p1)) != -1) {
    p1 += i;
    if (!(byg_start("//", p1))) {
      break;
    }
    j = byg_end("#", p1);
    if (j != 1) {
      n++;
    }
  }
  if (!n) {
    return 0;
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L8:
  mov    $0x0,%eax
  call   <yylex@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  while (yylex())
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L3:
  mov    $0x0,%eax
  call   <yylex@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  while (yylex())
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <yylex@plt>
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  while (yylex())
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <yylex@plt>
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  while (yylex())
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cdeque_dump_str_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L10
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x10(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r8
  mov    %esi,%ecx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L4
L10:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string

tool: D8: %p = [len: %d] "%s"


tool: D6: %p = NULL


assistant: ```c
int cdeque_dump_str_cb(FILE *o, void *data) {
  if (data != (void *)NULL) {
    return fprintf(o, "%p = [len: %d] \"%s\"\n", data, (int)strlen((char *)data), (char *)data);
  } else {
    return fprintf(o, "%p = NULL\n", data);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cdeque_dump_str_cb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L8
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%r8
  mov    %eax,%ecx
  mov    %rbx,%rdx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x0,%edx
  lea    D9(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D9
datatype: string

tool: D0: %p = [len: %d] "%s"


tool: D9: %p = NULL


assistant: ```c
int cdeque_dump_str_cb(FILE *o, void *data) {
  if (data != (void *)NULL) {
    return fprintf(o, "%p = [len: %d] \"%s\"\n", data, (int)strlen((char *)data), (char *)data);
  } else {
    return fprintf(o, "%p = NULL\n", data);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cdeque_dump_str_cb>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L2
  mov    %rsi,%rdi
  mov    %rsi,%r12
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%r8
  mov    %r12,%rdx
  mov    %eax,%ecx
  mov    %rbp,%rdi
  lea    D19(%rip),%rsi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1070 <fprintf@plt>
  xchg   %ax,%ax
L2:
  add    $0x8,%rsp
  xor    %edx,%edx
  lea    D10(%rip),%rsi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <fprintf@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
data_type: string
name: parse_data
arguments: tag: D10
data_type: string

tool: D19: %p = [len: %d] "%s"


tool: D10: %p = NULL


assistant: ```c
int cdeque_dump_str_cb(FILE *o, void *data) {
  if (data != (void *)NULL) {
    return fprintf(o, "%p = [len: %d] \"%s\"\n", data, (int)strlen((char *)data), (char *)data);
  } else {
    return fprintf(o, "%p = NULL\n", data);
  }
}
```