ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<path_getbasename>:
  endbr64
  push   %r12
  call   <path_getname@plt>
  mov    $0x2e,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax)
L5:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *path_getbasename(const char *path) {
  const char *name = path_getname(path);
  char *ptr = strrchr(name, '.');
  if (ptr != NULL)
    *ptr = '\0';
  return name;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<path_getbasename>:
  endbr64
  push   %r12
  call   <path_getname@plt>
  mov    $0x2e,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strrchr@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
L7:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *path_getbasename(const char *path) {
  const char *name = path_getname(path);
  char *ptr = strrchr(name, '.');
  if (ptr != NULL)
    *ptr = '\0';
  return name;
}
```
user: Translate the below assembly code into C programming language:

```asm
<volatile_fetch_sub_u64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t volatile_fetch_sub_u64(volatile uint64_t *dest, uint64_t val) {
  uint64_t result = *dest;
  *dest = result - val;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<volatile_fetch_sub_u64>:
  endbr64
  mov    %rsi,-0x18(%rsp)
  mov    (%rdi),%rax
  mov    %rax,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    -0x18(%rsp),%rdx
  sub    %rdx,%rax
  mov    %rax,(%rdi)
  mov    -0x8(%rsp),%rax
  ret
```

assistant: ```c
uint64_t volatile_fetch_sub_u64(volatile uint64_t *dest, uint64_t val) {
  uint64_t result = *dest;
  *dest = result - val;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<volatile_fetch_sub_u64>:
  endbr64
  mov    %rsi,-0x18(%rsp)
  mov    (%rdi),%rax
  mov    %rax,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    -0x18(%rsp),%rdx
  sub    %rdx,%rax
  mov    %rax,(%rdi)
  mov    -0x8(%rsp),%rax
  ret
```

assistant: ```c
uint64_t volatile_fetch_sub_u64(volatile uint64_t *dest, uint64_t val) {
  uint64_t result = *dest;
  *dest = result - val;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<volatile_fetch_sub_u64>:
  endbr64
  mov    %rsi,-0x18(%rsp)
  mov    (%rdi),%rax
  mov    %rax,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    -0x18(%rsp),%rdx
  sub    %rdx,%rax
  mov    %rax,(%rdi)
  mov    -0x8(%rsp),%rax
  ret
```

assistant: ```c
uint64_t volatile_fetch_sub_u64(volatile uint64_t *dest, uint64_t val) {
  uint64_t result = *dest;
  *dest = result - val;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jachelval>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movsd  (%rdi),%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  %xmm1,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm3
  movsd  %xmm1,0x8(%rsp)
  mulsd  D16(%rip),%xmm1
  mulsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi)
  movsd  D15(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  D41(%rip),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movapd %xmm0,%xmm4
  mulsd  (%rdi),%xmm4
  pxor   %xmm0,%xmm0
  ucomisd %xmm3,%xmm0
  ja     L5
  sqrtsd %xmm3,%xmm3
  movapd %xmm3,%xmm0
  divsd  %xmm3,%xmm4
  movsd  %xmm4,0x18(%rbx)
  movsd  D41(%rip),%xmm1
  mulsd  0x8(%rdi),%xmm1
  movq   %xmm1,%rbp
L10:
  movq   %rbp,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x20(%rbx)
  movq   $0x0,0x28(%rbx)
  movq   $0x0,0x30(%rbx)
  movq   $0x0,0x38(%rbx)
  mov    D35(%rip),%rax
  mov    %rax,0x40(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L5:
  movq   %xmm4,%r14
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  movq   %r14,%xmm5
  divsd  %xmm0,%xmm5
  movsd  %xmm5,0x18(%rbx)
  movsd  D41(%rip),%xmm0
  movapd %xmm0,%xmm6
  mulsd  0x8(%rbp),%xmm6
  movq   %xmm6,%rbp
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: data_label: D16
type: f64
name: read_data
arguments: data_label: D1
type: f64
name: read_data
arguments: data_label: D15
type: f32[2]
name: read_data
arguments: data_label: D41
type: f64
name: read_data
arguments: data_label: D35
type: f64

tool: D16: 3.141592653589793

tool: D1: 50

tool: {"D15": [0.0,-3.140625]}

tool: D41: 10

tool: D35: 1

assistant: ```c
void jachelval(double *p, double *jac, int m, int n, void *data) {
  register int i = 0;
  double tmp;
  tmp = p[0] * p[0] + p[1] * p[1];
  jac[i++] = 50.0 * p[1] / (3.14159265358979323846 * tmp);
  jac[i++] = -50.0 * p[0] / (3.14159265358979323846 * tmp);
  jac[i++] = 10.0;
  jac[i++] = 10.0 * p[0] / sqrt(tmp);
  jac[i++] = 10.0 * p[1] / sqrt(tmp);
  jac[i++] = 0.0;
  jac[i++] = 0.0;
  jac[i++] = 0.0;
  jac[i++] = 1.0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jachelval>:
  endbr64
  sub    $0x28,%rsp
  movsd  0x8(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  %xmm1,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  D23(%rip),%xmm0
  addsd  %xmm2,%xmm1
  movsd  D18(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm0
  movsd  %xmm0,(%rsi)
  movsd  D59(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  divsd  %xmm2,%xmm0
  movsd  D8(%rip),%xmm2
  movsd  %xmm2,0x10(%rsi)
  movsd  %xmm0,0x8(%rsi)
  pxor   %xmm0,%xmm0
  movsd  (%rdi),%xmm3
  ucomisd %xmm1,%xmm0
  mulsd  %xmm2,%xmm3
  ja     L5
  sqrtsd %xmm1,%xmm1
  divsd  %xmm1,%xmm3
  movsd  %xmm3,0x18(%rsi)
  mulsd  0x8(%rdi),%xmm2
L6:
  divsd  %xmm1,%xmm2
  mov    D52(%rip),%rax
  movq   $0x0,0x28(%rsi)
  movq   $0x0,0x30(%rsi)
  movq   $0x0,0x38(%rsi)
  mov    %rax,0x40(%rsi)
  movsd  %xmm2,0x20(%rsi)
  add    $0x28,%rsp
  ret
L5:
  movapd %xmm1,%xmm0
  mov    %rsi,0x8(%rsp)
  mov    %rdi,0x18(%rsp)
  movsd  %xmm3,(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm3
  mov    0x8(%rsp),%rsi
  mov    0x18(%rsp),%rdi
  mov    D8(%rip),%rax
  divsd  %xmm0,%xmm3
  movsd  0x10(%rsp),%xmm1
  movq   %rax,%xmm2
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x18(%rsi)
  mulsd  0x8(%rdi),%xmm2
  movsd  %xmm2,(%rsp)
  call   <sqrt@plt>
  mov    0x8(%rsp),%rsi
  movsd  (%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_label: D23
datatype: f64
name: parse_data
arguments: data_label: D18
datatype: f64
name: parse_data
arguments: data_label: D59
datatype: f32[2]
name: parse_data
arguments: data_label: D8
datatype: f64
name: parse_data
arguments: data_label: D52
datatype: f64

tool: D23: 50

tool: D18: 3.141592653589793

tool: {"D59": [0.0,-3.140625]}

tool: D8: 10

tool: D52: 1

assistant: ```c
void jachelval(double *p, double *jac, int m, int n, void *data) {
  register int i = 0;
  double tmp;
  tmp = p[0] * p[0] + p[1] * p[1];
  jac[i++] = 50.0 * p[1] / (3.14159265358979323846 * tmp);
  jac[i++] = -50.0 * p[0] / (3.14159265358979323846 * tmp);
  jac[i++] = 10.0;
  jac[i++] = 10.0 * p[0] / sqrt(tmp);
  jac[i++] = 10.0 * p[1] / sqrt(tmp);
  jac[i++] = 0.0;
  jac[i++] = 0.0;
  jac[i++] = 0.0;
  jac[i++] = 1.0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jachelval>:
  endbr64
  sub    $0x28,%rsp
  movsd  0x8(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  %xmm1,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  D30(%rip),%xmm0
  addsd  %xmm2,%xmm1
  movsd  D39(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm0
  movsd  %xmm0,(%rsi)
  movsd  D51(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  divsd  %xmm2,%xmm0
  movsd  D56(%rip),%xmm2
  movsd  %xmm2,0x10(%rsi)
  movsd  %xmm0,0x8(%rsi)
  pxor   %xmm0,%xmm0
  movsd  (%rdi),%xmm3
  ucomisd %xmm1,%xmm0
  mulsd  %xmm2,%xmm3
  ja     L4
  sqrtsd %xmm1,%xmm1
  divsd  %xmm1,%xmm3
  movsd  %xmm3,0x18(%rsi)
  mulsd  0x8(%rdi),%xmm2
L9:
  divsd  %xmm1,%xmm2
  mov    D14(%rip),%rax
  movq   $0x0,0x28(%rsi)
  movq   $0x0,0x30(%rsi)
  movq   $0x0,0x38(%rsi)
  mov    %rax,0x40(%rsi)
  movsd  %xmm2,0x20(%rsi)
  add    $0x28,%rsp
  ret
L4:
  movapd %xmm1,%xmm0
  mov    %rsi,0x8(%rsp)
  mov    %rdi,0x18(%rsp)
  movsd  %xmm3,(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm3
  mov    0x8(%rsp),%rsi
  mov    0x18(%rsp),%rdi
  mov    D56(%rip),%rax
  divsd  %xmm0,%xmm3
  movsd  0x10(%rsp),%xmm1
  movq   %rax,%xmm2
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x18(%rsi)
  mulsd  0x8(%rdi),%xmm2
  movsd  %xmm2,(%rsp)
  call   <sqrt@plt>
  mov    0x8(%rsp),%rsi
  movsd  (%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L9
```

tool_calls: name: parse_data
arguments: data_label: D30
data_type: f64
name: parse_data
arguments: data_label: D39
data_type: f64
name: parse_data
arguments: data_label: D51
data_type: f32[2]
name: parse_data
arguments: data_label: D56
data_type: f64
name: parse_data
arguments: data_label: D14
data_type: f64

tool: D30: 50

tool: D39: 3.141592653589793

tool: {"D51": [0.0,-3.140625]}

tool: D56: 10

tool: D14: 1

assistant: ```c
void jachelval(double *p, double *jac, int m, int n, void *data) {
  register int i = 0;
  double tmp;
  tmp = p[0] * p[0] + p[1] * p[1];
  jac[i++] = 50.0 * p[1] / (3.14159265358979323846 * tmp);
  jac[i++] = -50.0 * p[0] / (3.14159265358979323846 * tmp);
  jac[i++] = 10.0;
  jac[i++] = 10.0 * p[0] / sqrt(tmp);
  jac[i++] = 10.0 * p[1] / sqrt(tmp);
  jac[i++] = 0.0;
  jac[i++] = 0.0;
  jac[i++] = 0.0;
  jac[i++] = 1.0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x21(%rbp),%rdx
  lea    -0x22(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl -0x21(%rbp),%eax
  movsbl %al,%edi
  movzbl -0x22(%rbp),%eax
  movsbl %al,%ecx
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rsi
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edi,%r8d
  movapd %xmm0,%xmm1
  movq   %rsi,%xmm0
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D21
type: string
name: unpack_data
arguments: data_tag: D41
type: string
name: unpack_data
arguments: data_tag: D60
type: string
name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D43
type: string
name: unpack_data
arguments: data_tag: D28
type: string

tool: D21: input a and b

tool: D41: a = %d,b = %d

tool: D60: input x and y

tool: D1: %d%d

tool: D17: input c1 and c2

tool: D43: %c%c

tool: D28: a=%d,b=%d,x=%d,y=%d,c1=%c,c2=%c


assistant: ```c
int main() {
  int a, b;
  double x, y;
  char c1, c2;
  printf("input a and b");
  scanf("a = %d,b = %d", &a, &b);
  printf("input x and y");
  scanf("%d%d", &x, &y);
  printf("input c1 and c2");
  scanf("%c%c", &c1, &c2);
  printf("a=%d,b=%d,x=%d,y=%d,c1=%c,c2=%c\n", a, b, x, y, c1, c2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rdx
  lea    0xe(%rsp),%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsbl 0xe(%rsp),%ecx
  movsbl 0xf(%rsp),%r8d
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D20
type_guessed: string
name: unpack_data
arguments: data_tag: D46
type_guessed: string
name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D67
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string
name: unpack_data
arguments: data_tag: D6
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string

tool: D20: input a and b

tool: D46: a = %d,b = %d

tool: D8: input x and y

tool: D67: %d%d

tool: D2: input c1 and c2

tool: D6: %c%c

tool: D22: a=%d,b=%d,x=%d,y=%d,c1=%c,c2=%c


assistant: ```c
int main() {
  int a, b;
  double x, y;
  char c1, c2;
  printf("input a and b");
  scanf("a = %d,b = %d", &a, &b);
  printf("input x and y");
  scanf("%d%d", &x, &y);
  printf("input c1 and c2");
  scanf("%c%c", &c1, &c2);
  printf("a=%d,b=%d,x=%d,y=%d,c1=%c,c2=%c\n", a, b, x, y, c1, c2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D45(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  xor    %eax,%eax
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rdx
  lea    0xe(%rsp),%rsi
  xor    %eax,%eax
  lea    D62(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xe(%rsp),%ecx
  mov    0x14(%rsp),%edx
  lea    D19(%rip),%rdi
  movsbl 0xf(%rsp),%r8d
  movsd  0x20(%rsp),%xmm1
  mov    $0x2,%eax
  movsd  0x18(%rsp),%xmm0
  mov    0x10(%rsp),%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D45
type_guessed: string
name: disassemble_data
arguments: tag: D43
type_guessed: string
name: disassemble_data
arguments: tag: D52
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string
name: disassemble_data
arguments: tag: D32
type_guessed: string
name: disassemble_data
arguments: tag: D62
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D45: input a and b

tool: D43: a = %d,b = %d

tool: D52: input x and y

tool: D17: %d%d

tool: D32: input c1 and c2

tool: D62: %c%c

tool: D19: a=%d,b=%d,x=%d,y=%d,c1=%c,c2=%c


assistant: ```c
int main() {
  int a, b;
  double x, y;
  char c1, c2;
  printf("input a and b");
  scanf("a = %d,b = %d", &a, &b);
  printf("input x and y");
  scanf("%d%d", &x, &y);
  printf("input c1 and c2");
  scanf("%c%c", &c1, &c2);
  printf("a=%d,b=%d,x=%d,y=%d,c1=%c,c2=%c\n", a, b, x, y, c1, c2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D56(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rdx
  lea    0xe(%rsp),%rsi
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xe(%rsp),%ecx
  mov    0x14(%rsp),%edx
  lea    D44(%rip),%rdi
  movsbl 0xf(%rsp),%r8d
  movsd  0x20(%rsp),%xmm1
  mov    $0x2,%eax
  movsd  0x18(%rsp),%xmm0
  mov    0x10(%rsp),%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D56
data_type: string
name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D60
data_type: string
name: parse_data
arguments: label: D42
data_type: string
name: parse_data
arguments: label: D38
data_type: string
name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D44
data_type: string

tool: D56: input a and b

tool: D12: a = %d,b = %d

tool: D60: input x and y

tool: D42: %d%d

tool: D38: input c1 and c2

tool: D16: %c%c

tool: D44: a=%d,b=%d,x=%d,y=%d,c1=%c,c2=%c


assistant: ```c
int main() {
  int a, b;
  double x, y;
  char c1, c2;
  printf("input a and b");
  scanf("a = %d,b = %d", &a, &b);
  printf("input x and y");
  scanf("%d%d", &x, &y);
  printf("input c1 and c2");
  scanf("%c%c", &c1, &c2);
  printf("a=%d,b=%d,x=%d,y=%d,c1=%c,c2=%c\n", a, b, x, y, c1, c2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<internal_fast_random_safe_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <internal_naive_random_prime@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_sub_ui@plt>
  mov    -0x8(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_divexact_ui@plt>
  mov    -0x8(%rbp),%eax
  mov    $0x19,%esi
  mov    %eax,%edi
  call   <mpz_probab_prime_p@plt>
  test   %rax,%rax
  je     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void internal_fast_random_safe_prime(mpz_t rop1, mpz_t rop2, gmp_randstate_t rstate, mp_bitcnt_t bitcnt) {
  do {
    internal_naive_random_prime(rop1, rstate, bitcnt);
    mpz_sub_ui(rop2, rop1, 1);
    mpz_divexact_ui(rop2, rop2, 2);
  } while (mpz_probab_prime_p(rop2, 25) == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<internal_fast_random_safe_prime>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %ecx,%r12d
L7:
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <internal_naive_random_prime@plt>
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mpz_sub_ui@plt>
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_divexact_ui@plt>
  mov    $0x19,%esi
  mov    %ebx,%edi
  call   <mpz_probab_prime_p@plt>
  test   %rax,%rax
  je     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void internal_fast_random_safe_prime(mpz_t rop1, mpz_t rop2, gmp_randstate_t rstate, mp_bitcnt_t bitcnt) {
  do {
    internal_naive_random_prime(rop1, rstate, bitcnt);
    mpz_sub_ui(rop2, rop1, 1);
    mpz_divexact_ui(rop2, rop2, 2);
  } while (mpz_probab_prime_p(rop2, 25) == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<internal_fast_random_safe_prime>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <internal_naive_random_prime@plt>
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mpz_sub_ui@plt>
  mov    %ebx,%esi
  mov    %ebx,%edi
  mov    $0x2,%edx
  call   <mpz_divexact_ui@plt>
  mov    $0x19,%esi
  mov    %ebx,%edi
  call   <mpz_probab_prime_p@plt>
  test   %rax,%rax
  je     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void internal_fast_random_safe_prime(mpz_t rop1, mpz_t rop2, gmp_randstate_t rstate, mp_bitcnt_t bitcnt) {
  do {
    internal_naive_random_prime(rop1, rstate, bitcnt);
    mpz_sub_ui(rop2, rop1, 1);
    mpz_divexact_ui(rop2, rop2, 2);
  } while (mpz_probab_prime_p(rop2, 25) == 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<internal_fast_random_safe_prime>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <internal_naive_random_prime@plt>
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mpz_sub_ui@plt>
  mov    %ebx,%esi
  mov    %ebx,%edi
  mov    $0x2,%edx
  call   <mpz_divexact_ui@plt>
  mov    $0x19,%esi
  mov    %ebx,%edi
  call   <mpz_probab_prime_p@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void internal_fast_random_safe_prime(mpz_t rop1, mpz_t rop2, gmp_randstate_t rstate, mp_bitcnt_t bitcnt) {
  do {
    internal_naive_random_prime(rop1, rstate, bitcnt);
    mpz_sub_ui(rop2, rop1, 1);
    mpz_divexact_ui(rop2, rop2, 2);
  } while (mpz_probab_prime_p(rop2, 25) == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cross>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%edi
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <line@plt>
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <line@plt>
  nop
  leave
  ret
```

assistant: ```c
cross(x, y, r) {
  line(x - r, y, x + r, y);
  line(x, y - r, x, y + r);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cross>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  lea    (%rdi,%rdx,1),%edx
  sub    %r12d,%edi
  mov    %esi,%ecx
  mov    $0x0,%eax
  call   <line@plt>
  lea    (%r12,%rbx,1),%ecx
  sub    %r12d,%ebx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <line@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
cross(x, y, r) {
  line(x - r, y, x + r, y);
  line(x, y - r, x, y + r);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cross>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  mov    %esi,%ecx
  lea    (%rdi,%rdx,1),%edx
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  sub    %r12d,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <line@plt>
  lea    (%r12,%rbx,1),%ecx
  sub    %r12d,%ebx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1050 <line@plt>
```

assistant: ```c
cross(x, y, r) {
  line(x - r, y, x + r, y);
  line(x, y - r, x, y + r);
}
```