ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initHeap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
  mov    $0x1000,%edx
  mov    $0xa,%eax
  syscall
  nop
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long initHeap() {
  unsigned long long new_space = 0x0;
  asm volatile("mov $4096, %edx");
  asm volatile("mov $10, %eax");
  asm volatile("syscall");
  asm volatile("nop" : "=d"(new_space));
  return new_space;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initHeap>:
  endbr64
  mov    $0x1000,%edx
  mov    $0xa,%eax
  syscall
  nop
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long initHeap() {
  unsigned long long new_space = 0x0;
  asm volatile("mov $4096, %edx");
  asm volatile("mov $10, %eax");
  asm volatile("syscall");
  asm volatile("nop" : "=d"(new_space));
  return new_space;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initHeap>:
  endbr64
  mov    $0x1000,%edx
  mov    $0xa,%eax
  syscall
  nop
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long initHeap() {
  unsigned long long new_space = 0x0;
  asm volatile("mov $4096, %edx");
  asm volatile("mov $10, %eax");
  asm volatile("syscall");
  asm volatile("nop" : "=d"(new_space));
  return new_space;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<initHeap>:
  endbr64
  mov    $0x1000,%edx
  mov    $0xa,%eax
  syscall
  nop
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long initHeap() {
  unsigned long long new_space = 0x0;
  asm volatile("mov $4096, %edx");
  asm volatile("mov $10, %eax");
  asm volatile("syscall");
  asm volatile("nop" : "=d"(new_space));
  return new_space;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isVariable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L15
  mov    $0x1,%eax
  jmp    L16
L15:
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int isVariable(char x) {
  if (isupper(x))
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isVariable>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <isupper@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int isVariable(char x) {
  if (isupper(x))
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isVariable>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <isupper@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int isVariable(char x) {
  if (isupper(x))
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isVariable>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <isupper@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int isVariable(char x) {
  if (isupper(x))
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getqzname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  jmp    L11
L22:
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L22
L2:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((__pure__)) const char *getqzname(const char *strp, const int delim) {
  int c;
  while ((c = *strp) != '\0' && c != delim)
    ++strp;
  return strp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getqzname>:
  endbr64
  mov    %rdi,%rax
  movsbl (%rdi),%edx
  cmp    %edx,%esi
  je     L39
  test   %edx,%edx
  je     L39
L20:
  add    $0x1,%rax
  movsbl (%rax),%edx
  cmp    %esi,%edx
  je     L39
  test   %edx,%edx
  jne    L20
L39:
  ret
```

assistant: ```c
__attribute__((__pure__)) const char *getqzname(const char *strp, const int delim) {
  int c;
  while ((c = *strp) != '\0' && c != delim)
    ++strp;
  return strp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getqzname>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    %edx,%esi
  jne    L11
  jmp    L31
L26:
  movsbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %esi,%edx
  je     L31
L11:
  test   %edx,%edx
  jne    L26
L31:
  ret
```

assistant: ```c
__attribute__((__pure__)) const char *getqzname(const char *strp, const int delim) {
  int c;
  while ((c = *strp) != '\0' && c != delim)
    ++strp;
  return strp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getqzname>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    %edx,%esi
  jne    L14
  jmp    L32
L37:
  movsbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %esi,%edx
  je     L32
L14:
  test   %edx,%edx
  jne    L37
L32:
  ret
```

assistant: ```c
__attribute__((__pure__)) const char *getqzname(const char *strp, const int delim) {
  int c;
  while ((c = *strp) != '\0' && c != delim)
    ++strp;
  return strp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L36
L43:
  addl   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L69
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
L69:
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L15:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
  jmp    L35
L60:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0x0,-0x4(%rbp)
  js     L17
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L60
L17:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim(char *str) {
  int start, i;
  for (start = 0; isspace(str[start]) && str[start]; ++start)
    ;
  for (i = 0; str[i + start]; ++i)
    str[i] = str[i + start];
  str[i] = '\0';
  for (--i; i >= 0 && isspace(str[i]); --i)
    str[i] = '\0';
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  mov    $0x0,%r12d
  jmp    L55
L63:
  add    $0x1,%r12d
L55:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L36
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  jne    L63
L64:
  movb   $0x0,0x0(%rbp)
  jmp    L38
L36:
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L64
  mov    %rbp,%rax
  mov    $0x0,%edx
  movslq %r12d,%r12
L6:
  mov    %cl,(%rax)
  mov    %edx,%esi
  add    $0x1,%edx
  add    $0x1,%rax
  movzbl (%rax,%r12,1),%ecx
  test   %cl,%cl
  jne    L6
  movslq %edx,%rdx
  movb   $0x0,0x0(%rbp,%rdx,1)
  test   %esi,%esi
  js     L38
  movslq %esi,%rax
  lea    0x0(%rbp,%rax,1),%rbx
  lea    -0x1(%rbp,%rax,1),%r12
  mov    %esi,%esi
  sub    %rsi,%r12
L83:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L38
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L83
L38:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *trim(char *str) {
  int start, i;
  for (start = 0; isspace(str[start]) && str[start]; ++start)
    ;
  for (i = 0; str[i + start]; ++i)
    str[i] = str[i + start];
  str[i] = '\0';
  for (--i; i >= 0 && isspace(str[i]); --i)
    str[i] = '\0';
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L60
  add    $0x1,%ebp
L76:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L45
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L60
  mov    %r12,%rax
  xor    %edx,%edx
  movslq %ebp,%rbp
  nopl   0x0(%rax)
L48:
  mov    %cl,(%rax)
  movzbl 0x1(%rax,%rbp,1),%ecx
  movslq %edx,%rsi
  add    $0x1,%rax
  add    $0x1,%edx
  test   %cl,%cl
  jne    L48
  movslq %edx,%rdx
  lea    -0x1(%r12,%rsi,1),%rbp
  lea    (%r12,%rsi,1),%rbx
  movb   $0x0,(%r12,%rdx,1)
  sub    %rsi,%rbp
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L4:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L80
L5:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
L80:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L60:
  movb   $0x0,(%r12)
  jmp    L80
```

assistant: ```c
char *trim(char *str) {
  int start, i;
  for (start = 0; isspace(str[start]) && str[start]; ++start)
    ;
  for (i = 0; str[i + start]; ++i)
    str[i] = str[i + start];
  str[i] = '\0';
  for (--i; i >= 0 && isspace(str[i]); --i)
    str[i] = '\0';
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L80:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L55
  add    $0x1,%ebp
L78:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L80
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L55
  mov    %r12,%rax
  xor    %edx,%edx
  movslq %ebp,%rbp
  nopl   0x0(%rax)
L30:
  mov    %cl,(%rax)
  movzbl 0x1(%rax,%rbp,1),%ecx
  movslq %edx,%rsi
  add    $0x1,%rax
  add    $0x1,%edx
  test   %cl,%cl
  jne    L30
  movslq %edx,%rdx
  lea    -0x1(%r12,%rsi,1),%rbp
  lea    (%r12,%rsi,1),%rbx
  movb   $0x0,(%r12,%rdx,1)
  sub    %rsi,%rbp
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L68:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L73
L59:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L68
L73:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L55:
  movb   $0x0,(%r12)
  jmp    L73
```

assistant: ```c
char *trim(char *str) {
  int start, i;
  for (start = 0; isspace(str[start]) && str[start]; ++start)
    ;
  for (i = 0; str[i + start]; ++i)
    str[i] = str[i + start];
  str[i] = '\0';
  for (--i; i >= 0 && isspace(str[i]); --i)
    str[i] = '\0';
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fabsl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  fldt   0x10(%rbp)
  fabs
  fstpt  0x10(%rbp)
  fldt   0x10(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
long double fabsl(long double x) {
  __asm__("fabs" : "+t"(x));
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fabsl>:
  endbr64
  fldt   0x8(%rsp)
  fabs
  ret
```

assistant: ```c
long double fabsl(long double x) {
  __asm__("fabs" : "+t"(x));
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fabsl>:
  endbr64
  fldt   0x8(%rsp)
  fabs
  ret
```

assistant: ```c
long double fabsl(long double x) {
  __asm__("fabs" : "+t"(x));
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fabsl>:
  endbr64
  fldt   0x8(%rsp)
  fabs
  ret
```

assistant: ```c
long double fabsl(long double x) {
  __asm__("fabs" : "+t"(x));
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<taa_h264_inverse_hadamard_2x2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x40(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x80(%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0xc0(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    -0x18(%rbp),%rdx
  add    $0x40,%rdx
  sub    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    -0x8(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    $0xffffffffffffff80,%rdx
  sub    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0xc0,%rax
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x40,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x40,%rax
  sar    %edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  sar    %edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0xc0,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0xc0,%rax
  sar    %edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void taa_h264_inverse_hadamard_2x2(int16_t *coeffs) {
  int c1 = coeffs[0 * 16];
  int c2 = coeffs[1 * 16];
  int c3 = coeffs[2 * 16];
  int c4 = coeffs[3 * 16];
  coeffs[0 * 16] = (int16_t)(c1 + c2 + c3 + c4);
  coeffs[1 * 16] = (int16_t)(c1 - c2 + c3 - c4);
  coeffs[2 * 16] = (int16_t)(c1 + c2 - c3 - c4);
  coeffs[3 * 16] = (int16_t)(c1 - c2 - c3 + c4);
  coeffs[0 * 16] >>= 1;
  coeffs[1 * 16] >>= 1;
  coeffs[2 * 16] >>= 1;
  coeffs[3 * 16] >>= 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<taa_h264_inverse_hadamard_2x2>:
  endbr64
  mov    %rdi,%rdx
  mov    (%rdi),%eax
  mov    0x80(%rdi),%edi
  mov    %eax,%ecx
  add    0x40(%rdx),%ecx
  sub    0x40(%rdx),%eax
  lea    (%rcx,%rdi,1),%esi
  add    0xc0(%rdx),%esi
  sar    %esi
  mov    %esi,(%rdx)
  lea    (%rax,%rdi,1),%esi
  sub    0xc0(%rdx),%esi
  sar    %esi
  mov    %esi,0x40(%rdx)
  sub    %edi,%ecx
  sub    0xc0(%rdx),%ecx
  sar    %ecx
  mov    %ecx,0x80(%rdx)
  sub    %edi,%eax
  add    0xc0(%rdx),%eax
  sar    %eax
  mov    %eax,0xc0(%rdx)
  ret
```

assistant: ```c
void taa_h264_inverse_hadamard_2x2(int16_t *coeffs) {
  int c1 = coeffs[0 * 16];
  int c2 = coeffs[1 * 16];
  int c3 = coeffs[2 * 16];
  int c4 = coeffs[3 * 16];
  coeffs[0 * 16] = (int16_t)(c1 + c2 + c3 + c4);
  coeffs[1 * 16] = (int16_t)(c1 - c2 + c3 - c4);
  coeffs[2 * 16] = (int16_t)(c1 + c2 - c3 - c4);
  coeffs[3 * 16] = (int16_t)(c1 - c2 - c3 + c4);
  coeffs[0 * 16] >>= 1;
  coeffs[1 * 16] >>= 1;
  coeffs[2 * 16] >>= 1;
  coeffs[3 * 16] >>= 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<taa_h264_inverse_hadamard_2x2>:
  endbr64
  mov    %rdi,%rdx
  mov    (%rdi),%eax
  mov    0x80(%rdi),%edi
  mov    0x40(%rdx),%ecx
  add    %eax,%ecx
  sub    0x40(%rdx),%eax
  lea    (%rcx,%rdi,1),%esi
  add    0xc0(%rdx),%esi
  sub    %edi,%ecx
  sub    0xc0(%rdx),%ecx
  sar    %esi
  sar    %ecx
  mov    %esi,(%rdx)
  lea    (%rax,%rdi,1),%esi
  sub    %edi,%eax
  sub    0xc0(%rdx),%esi
  add    0xc0(%rdx),%eax
  sar    %esi
  mov    %ecx,0x80(%rdx)
  sar    %eax
  mov    %esi,0x40(%rdx)
  mov    %eax,0xc0(%rdx)
  ret
```

assistant: ```c
void taa_h264_inverse_hadamard_2x2(int16_t *coeffs) {
  int c1 = coeffs[0 * 16];
  int c2 = coeffs[1 * 16];
  int c3 = coeffs[2 * 16];
  int c4 = coeffs[3 * 16];
  coeffs[0 * 16] = (int16_t)(c1 + c2 + c3 + c4);
  coeffs[1 * 16] = (int16_t)(c1 - c2 + c3 - c4);
  coeffs[2 * 16] = (int16_t)(c1 + c2 - c3 - c4);
  coeffs[3 * 16] = (int16_t)(c1 - c2 - c3 + c4);
  coeffs[0 * 16] >>= 1;
  coeffs[1 * 16] >>= 1;
  coeffs[2 * 16] >>= 1;
  coeffs[3 * 16] >>= 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<taa_h264_inverse_hadamard_2x2>:
  endbr64
  mov    %rdi,%rdx
  mov    (%rdi),%eax
  mov    0x80(%rdi),%edi
  mov    0x40(%rdx),%ecx
  add    %eax,%ecx
  sub    0x40(%rdx),%eax
  lea    (%rcx,%rdi,1),%esi
  add    0xc0(%rdx),%esi
  sub    %edi,%ecx
  sub    0xc0(%rdx),%ecx
  sar    %esi
  sar    %ecx
  mov    %esi,(%rdx)
  lea    (%rax,%rdi,1),%esi
  sub    %edi,%eax
  sub    0xc0(%rdx),%esi
  add    0xc0(%rdx),%eax
  sar    %esi
  mov    %ecx,0x80(%rdx)
  sar    %eax
  mov    %esi,0x40(%rdx)
  mov    %eax,0xc0(%rdx)
  ret
```

assistant: ```c
void taa_h264_inverse_hadamard_2x2(int16_t *coeffs) {
  int c1 = coeffs[0 * 16];
  int c2 = coeffs[1 * 16];
  int c3 = coeffs[2 * 16];
  int c4 = coeffs[3 * 16];
  coeffs[0 * 16] = (int16_t)(c1 + c2 + c3 + c4);
  coeffs[1 * 16] = (int16_t)(c1 - c2 + c3 - c4);
  coeffs[2 * 16] = (int16_t)(c1 + c2 - c3 - c4);
  coeffs[3 * 16] = (int16_t)(c1 - c2 - c3 + c4);
  coeffs[0 * 16] >>= 1;
  coeffs[1 * 16] >>= 1;
  coeffs[2 * 16] >>= 1;
  coeffs[3 * 16] >>= 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(int arr[], int n) {
  int sum = 0;
  for (int i = 0; i < n; i++)
    sum += arr[i];
  return sum + n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L11
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdi
  mov    $0x0,%ecx
L4:
  add    (%rdx),%ecx
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L4
L29:
  lea    (%rsi,%rcx,1),%eax
  ret
L11:
  mov    $0x0,%ecx
  jmp    L29
```

assistant: ```c
int sum(int arr[], int n) {
  int sum = 0;
  for (int i = 0; i < n; i++)
    sum += arr[i];
  return sum + n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  lea    0x4(%rdi,%rax,4),%rcx
  nopw   0x0(%rax,%rax,1)
L2:
  add    (%rdi),%edx
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L2
  lea    (%rsi,%rdx,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %esi,%eax
  ret
```

assistant: ```c
int sum(int arr[], int n) {
  int sum = 0;
  for (int i = 0; i < n; i++)
    sum += arr[i];
  return sum + n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L51
  lea    -0x1(%rsi),%edx
  cmp    $0x2,%edx
  jbe    L18
  mov    %esi,%ecx
  mov    %rdi,%rdx
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L19:
  movdqu (%rdx),%xmm2
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rdx
  jne    L19
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%edx
  test   $0x3,%sil
  je     L40
L64:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rax,%rdi,4),%edx
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L40
  add    $0x2,%ecx
  add    0x4(%rax,%r8,1),%edx
  cmp    %ecx,%esi
  jle    L40
  add    0x8(%rax,%r8,1),%edx
L40:
  lea    (%rsi,%rdx,1),%eax
  ret
  nopl   0x0(%rax)
L51:
  mov    %esi,%eax
  ret
L18:
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    L64
```

assistant: ```c
int sum(int arr[], int n) {
  int sum = 0;
  for (int i = 0; i < n; i++)
    sum += arr[i];
  return sum + n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L18:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitcount(unsigned x) {
  int count;
  for (count = 0; x != 0; ++count)
    x &= x - 1;
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitcount>:
  endbr64
  test   %edi,%edi
  je     L19
  mov    $0x0,%edx
L12:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edx
  and    %eax,%edi
  jne    L12
L6:
  mov    %edx,%eax
  ret
L19:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int bitcount(unsigned x) {
  int count;
  for (count = 0; x != 0; ++count)
    x &= x - 1;
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitcount>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L3
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L6
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitcount(unsigned x) {
  int count;
  for (count = 0; x != 0; ++count)
    x &= x - 1;
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitcount>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L9
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L6
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitcount(unsigned x) {
  int count;
  for (count = 0; x != 0; ++count)
    x &= x - 1;
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D7: argc --> %d


tool: D14: %d --> %s || %c


assistant: ```c
int main(int argc, char *argv[]) {
  printf("argc --> %d\n", argc);
  int i = 0;
  for (; i < argc; i++) {
    printf("%d --> %s || %c\n", i, argv[i], argv[i][0]);
  }
  return 0;
}
```