ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<llvm_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L20
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L38:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L7
L54:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L38
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L16
L7:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L16
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t llvm_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<llvm_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L2
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L51:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L24
L6:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L51
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L16
L24:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L16
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t llvm_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sntp_set_time_large>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <settimeofday@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int sntp_set_time_large(unsigned sec, unsigned msec) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  tv.tv_sec += sec;
  tv.tv_usec += msec;
  return settimeofday(&tv, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sntp_set_time_large>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  add    %ebp,0x4(%rsp)
  add    %ebx,(%rsp)
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <settimeofday@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sntp_set_time_large(unsigned sec, unsigned msec) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  tv.tv_sec += sec;
  tv.tv_usec += msec;
  return settimeofday(&tv, NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sntp_set_time_large>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  add    %ebp,0x4(%rsp)
  add    %ebx,(%rsp)
  call   <settimeofday@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sntp_set_time_large(unsigned sec, unsigned msec) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  tv.tv_sec += sec;
  tv.tv_usec += msec;
  return settimeofday(&tv, NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sntp_set_time_large>:
  endbr64
  push   %rbp
  movd   %edi,%xmm2
  movd   %esi,%xmm0
  xor    %esi,%esi
  punpckldq %xmm2,%xmm0
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movq   %xmm0,0x8(%rsp)
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  movq   0x10(%rsp),%xmm1
  xor    %esi,%esi
  mov    %rbp,%rdi
  movq   0x8(%rsp),%xmm0
  paddd  %xmm1,%xmm0
  movq   %xmm0,0x10(%rsp)
  call   <settimeofday@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sntp_set_time_large(unsigned sec, unsigned msec) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  tv.tv_sec += sec;
  tv.tv_usec += msec;
  return settimeofday(&tv, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__ecm_find_factor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x1,-0x18(%rbp)
  jne    L6
  mov    $0x1,%eax
  jmp    L73
L6:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L4
  mov    $0x2,%eax
  jmp    L73
L4:
  movq   $0x3,-0x8(%rbp)
  jmp    L60
L53:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L11
  mov    -0x8(%rbp),%rax
  jmp    L73
L11:
  addq   $0x2,-0x8(%rbp)
L60:
  mov    -0x8(%rbp),%rax
  imul   %rax,%rax
  cmp    %rax,-0x18(%rbp)
  jae    L53
  mov    -0x18(%rbp),%rax
L73:
  leave
  ret
```

assistant: ```c
unsigned long __ecm_find_factor(const unsigned long N) {
  unsigned long i;
  assert(N != 0UL);
  if (N == 1UL)
    return 1UL;
  if (N % 2UL == 0UL)
    return 2UL;
  for (i = 3UL; i * i <= N; i += 2UL)
    if (N % i == 0UL)
      return i;
  return N;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__ecm_find_factor>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x1,%rbx
  je     L52
  test   $0x1,%bl
  je     L30
  cmp    $0x8,%rbx
  jbe    L52
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rbx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    %rax
  and    $0xfffffffffffffffe,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rbx
  je     L61
  mov    $0x3,%ecx
L79:
  add    $0x2,%rcx
  mov    %rcx,%rax
  imul   %rcx,%rax
  cmp    %rbx,%rax
  ja     L52
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rcx
  test   %rdx,%rdx
  jne    L79
  mov    %rcx,%rbx
L52:
  mov    %rbx,%rax
  pop    %rbx
  ret
L30:
  mov    $0x2,%ebx
  jmp    L52
L61:
  mov    $0x3,%ebx
  jmp    L52
```

assistant: ```c
unsigned long __ecm_find_factor(const unsigned long N) {
  unsigned long i;
  assert(N != 0UL);
  if (N == 1UL)
    return 1UL;
  if (N % 2UL == 0UL)
    return 2UL;
  for (i = 3UL; i * i <= N; i += 2UL)
    if (N % i == 0UL)
      return i;
  return N;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__ecm_find_factor>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x1,%r12
  je     L67
  test   $0x1,%r12b
  je     L11
  cmp    $0x8,%r12
  jbe    L67
  movabs $0xaaaaaaaaaaaaaaab,%rax
  movabs $0x5555555555555555,%rdx
  imul   %r12,%rax
  cmp    %rdx,%rax
  jbe    L6
  mov    $0x3,%ecx
  jmp    L45
  nop
L58:
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rcx
  test   %rdx,%rdx
  je     L66
L45:
  add    $0x2,%rcx
  mov    %rcx,%rax
  imul   %rcx,%rax
  cmp    %r12,%rax
  jbe    L58
L67:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %rcx,%r12
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x2,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
L6:
  mov    $0x3,%r12d
  jmp    L67
```

assistant: ```c
unsigned long __ecm_find_factor(const unsigned long N) {
  unsigned long i;
  assert(N != 0UL);
  if (N == 1UL)
    return 1UL;
  if (N % 2UL == 0UL)
    return 2UL;
  for (i = 3UL; i * i <= N; i += 2UL)
    if (N % i == 0UL)
      return i;
  return N;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__ecm_find_factor>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x1,%r12
  je     L73
  test   $0x1,%r12b
  je     L27
  cmp    $0x8,%r12
  jbe    L73
  movabs $0xaaaaaaaaaaaaaaab,%rax
  movabs $0x5555555555555555,%rdx
  imul   %r12,%rax
  cmp    %rdx,%rax
  jbe    L4
  mov    $0x3,%ecx
  jmp    L18
  nop
L17:
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rcx
  test   %rdx,%rdx
  je     L66
L18:
  add    $0x2,%rcx
  mov    %rcx,%rax
  imul   %rcx,%rax
  cmp    %r12,%rax
  jbe    L17
L73:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %rcx,%r12
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  mov    $0x2,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
L4:
  mov    $0x3,%r12d
  jmp    L73
```

assistant: ```c
unsigned long __ecm_find_factor(const unsigned long N) {
  unsigned long i;
  assert(N != 0UL);
  if (N == 1UL)
    return 1UL;
  if (N % 2UL == 0UL)
    return 2UL;
  for (i = 3UL; i * i <= N; i += 2UL)
    if (N % i == 0UL)
      return i;
  return N;
}
```
user: Translate the below assembly code into C programming language:

```asm
<estrito>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L13
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  jmp    L11
L13:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <estrito>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L1
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L11
L1:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int estrito(int n, int v[]) {
  if (n == 1) {
    return v[0];
  } else {
    int x = estrito(n - 1, v);
    if (v[n - 1] > 0) {
      return x += v[n - 1];
    } else {
      return 0;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<estrito>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  cmp    $0x1,%edi
  je     L18
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <estrito>
  movslq %ebx,%rbx
  mov    -0x4(%rbp,%rbx,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    (%rsi),%eax
  jmp    L0
```

assistant: ```c
int estrito(int n, int v[]) {
  if (n == 1) {
    return v[0];
  } else {
    int x = estrito(n - 1, v);
    if (v[n - 1] > 0) {
      return x += v[n - 1];
    } else {
      return 0;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<estrito>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x18,%rsp
  cmp    $0x1,%ebx
  je     L108
  lea    -0x1(%rbx),%r12d
  cmp    $0x2,%ebx
  je     L97
  lea    -0x2(%rbx),%r13d
  cmp    $0x3,%ebx
  je     L106
  lea    -0x3(%rbx),%r14d
  cmp    $0x4,%ebx
  je     L68
  lea    -0x4(%rbx),%r15d
  cmp    $0x5,%ebx
  je     L22
  lea    -0x5(%rbx),%ebp
  cmp    $0x6,%ebx
  je     L1
  lea    -0x6(%rbx),%edi
  mov    %rsi,0x8(%rsp)
  call   <estrito>
  mov    0x8(%rsp),%rsi
  movslq %ebp,%rdx
  mov    -0x4(%rsi,%rdx,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L82:
  movslq %r15d,%r15
  mov    -0x4(%rsi,%r15,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L70:
  movslq %r14d,%r14
  mov    -0x4(%rsi,%r14,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L72:
  movslq %r13d,%r13
  mov    -0x4(%rsi,%r13,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L37:
  movslq %r12d,%r12
  mov    -0x4(%rsi,%r12,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
  jmp    L9
  nopl   (%rax)
L97:
  mov    (%rsi),%eax
L9:
  mov    -0x4(%rsi,%rbx,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L108:
  mov    (%rsi),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L68:
  mov    (%rsi),%eax
  jmp    L72
  nopl   0x0(%rax)
L106:
  mov    (%rsi),%eax
  jmp    L37
  nopl   0x0(%rax)
L22:
  mov    (%rsi),%eax
  jmp    L70
  nop
L1:
  mov    (%rsi),%eax
  jmp    L82
```

assistant: ```c
int estrito(int n, int v[]) {
  if (n == 1) {
    return v[0];
  } else {
    int x = estrito(n - 1, v);
    if (v[n - 1] > 0) {
      return x += v[n - 1];
    } else {
      return 0;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<estrito>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x18,%rsp
  cmp    $0x1,%ebx
  je     L43
  lea    -0x1(%rbx),%r12d
  cmp    $0x2,%ebx
  je     L84
  lea    -0x2(%rbx),%r13d
  cmp    $0x3,%ebx
  je     L35
  lea    -0x3(%rbx),%r14d
  cmp    $0x4,%ebx
  je     L52
  lea    -0x4(%rbx),%r15d
  cmp    $0x5,%ebx
  je     L74
  lea    -0x5(%rbx),%ebp
  cmp    $0x6,%ebx
  je     L34
  lea    -0x6(%rbx),%edi
  mov    %rsi,0x8(%rsp)
  call   <estrito>
  mov    0x8(%rsp),%rsi
  movslq %ebp,%rdx
  mov    -0x4(%rsi,%rdx,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L15:
  movslq %r15d,%r15
  mov    -0x4(%rsi,%r15,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L38:
  movslq %r14d,%r14
  mov    -0x4(%rsi,%r14,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L85:
  movslq %r13d,%r13
  mov    -0x4(%rsi,%r13,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
L90:
  movslq %r12d,%r12
  mov    -0x4(%rsi,%r12,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
  jmp    L42
  nopl   (%rax)
L84:
  mov    (%rsi),%eax
L42:
  mov    -0x4(%rsi,%rbx,4),%edx
  add    %edx,%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L43:
  mov    (%rsi),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L52:
  mov    (%rsi),%eax
  jmp    L85
  nopl   0x0(%rax)
L35:
  mov    (%rsi),%eax
  jmp    L90
  nopl   0x0(%rax)
L74:
  mov    (%rsi),%eax
  jmp    L38
  nop
L34:
  mov    (%rsi),%eax
  jmp    L15
```

assistant: ```c
int estrito(int n, int v[]) {
  if (n == 1) {
    return v[0];
  } else {
    int x = estrito(n - 1, v);
    if (v[n - 1] > 0) {
      return x += v[n - 1];
    } else {
      return 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intMalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x124(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <superlu_malloc@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  jne    L13
  lea    -0x110(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rcx
  lea    D15(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <sprintf_s@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <WriteSLUErrorMessage@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <superlu_abort_and_exit@plt>
L13:
  mov    -0x118(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string
name: disassemble_data
arguments: tag: D15
type: string

tool: D6: SUPERLU_MALLOC fails for buf in intMalloc()

tool: D15: Error: %s

assistant: ```c
int *intMalloc(int n) {
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf_s(msg, 256, "Error: %s", "SUPERLU_MALLOC fails for buf in intMalloc()");
      WriteSLUErrorMessage(msg);
      superlu_abort_and_exit(msg);
    };
  }
  return (buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intMalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  shl    $0x2,%edi
  call   <superlu_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L3:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %rbx,%rax
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %rsp,%rbp
  lea    D17(%rip),%rcx
  lea    D19(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <sprintf_s@plt>
  mov    %rbp,%rdi
  call   <WriteSLUErrorMessage@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L3
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D17: SUPERLU_MALLOC fails for buf in intMalloc()

tool: D19: Error: %s

assistant: ```c
int *intMalloc(int n) {
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf_s(msg, 256, "Error: %s", "SUPERLU_MALLOC fails for buf in intMalloc()");
      WriteSLUErrorMessage(msg);
      superlu_abort_and_exit(msg);
    };
  }
  return (buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<intMalloc>:
  endbr64
  push   %r12
  shl    $0x2,%edi
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <superlu_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
L5:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x118,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rsp,%rbp
  lea    D11(%rip),%rcx
  mov    $0x100,%esi
  lea    D13(%rip),%rdx
  mov    %rbp,%rdi
  call   <sprintf_s@plt>
  mov    %rbp,%rdi
  call   <WriteSLUErrorMessage@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L5
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D11: SUPERLU_MALLOC fails for buf in intMalloc()

tool: D13: Error: %s

assistant: ```c
int *intMalloc(int n) {
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf_s(msg, 256, "Error: %s", "SUPERLU_MALLOC fails for buf in intMalloc()");
      WriteSLUErrorMessage(msg);
      superlu_abort_and_exit(msg);
    };
  }
  return (buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intMalloc>:
  endbr64
  push   %r12
  shl    $0x2,%edi
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <superlu_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L7:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x118,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rsp,%rbp
  lea    D15(%rip),%rcx
  mov    $0x100,%esi
  lea    D18(%rip),%rdx
  mov    %rbp,%rdi
  call   <sprintf_s@plt>
  mov    %rbp,%rdi
  call   <WriteSLUErrorMessage@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L7
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D15
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string

tool: D15: SUPERLU_MALLOC fails for buf in intMalloc()

tool: D18: Error: %s

assistant: ```c
int *intMalloc(int n) {
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf_s(msg, 256, "Error: %s", "SUPERLU_MALLOC fails for buf in intMalloc()");
      WriteSLUErrorMessage(msg);
      superlu_abort_and_exit(msg);
    };
  }
  return (buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <print_str_and_int@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <print_str_and_int@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <print_str_and_int@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type: string
name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D23
type: string

tool: D11: Hello

tool: D13: 3

tool: D23: 0

assistant: ```c
int main(void) {
  print_str_and_int("Hello");
  print_str_and_int("3");
  print_str_and_int("0");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D25(%rip),%rdi
  call   <print_str_and_int@plt>
  lea    D18(%rip),%rdi
  call   <print_str_and_int@plt>
  lea    D21(%rip),%rdi
  call   <print_str_and_int@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string

tool: D25: Hello

tool: D18: 3

tool: D21: 0

assistant: ```c
int main(void) {
  print_str_and_int("Hello");
  print_str_and_int("3");
  print_str_and_int("0");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <print_str_and_int@plt>
  lea    D10(%rip),%rdi
  call   <print_str_and_int@plt>
  lea    D13(%rip),%rdi
  call   <print_str_and_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string

tool: D20: Hello

tool: D10: 3

tool: D13: 0

assistant: ```c
int main(void) {
  print_str_and_int("Hello");
  print_str_and_int("3");
  print_str_and_int("0");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <print_str_and_int@plt>
  lea    D19(%rip),%rdi
  call   <print_str_and_int@plt>
  lea    D8(%rip),%rdi
  call   <print_str_and_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D8
type: string

tool: D13: Hello

tool: D19: 3

tool: D8: 0

assistant: ```c
int main(void) {
  print_str_and_int("Hello");
  print_str_and_int("3");
  print_str_and_int("0");
  return 0;
}
```