ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8_to_unicode>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L67
L30:
  movzbl 0x0(%rbp),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbp
L25:
  add    $0x2,%rbx
L67:
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L26
  movzbl %dil,%edi
  call   <cal_utf8_num_bytes@plt>
  test   %eax,%eax
  je     L30
  cmp    $0x3,%eax
  je     L46
L7:
  cltq
  add    %rax,%rbp
  jmp    L25
L46:
  movzbl 0x1(%rbp),%edx
  sar    $0x2,%dl
  and    $0xf,%edx
  movsbl 0x0(%rbp),%ecx
  shl    $0x4,%ecx
  or     %ecx,%edx
  mov    %dl,0x1(%r13,%rbx,1)
  movsbl 0x1(%rbp),%ecx
  shl    $0x6,%ecx
  movzbl 0x2(%rbp),%edx
  and    $0x3f,%edx
  add    %ecx,%edx
  mov    %dl,0x0(%r13,%rbx,1)
  jmp    L7
L0:
  mov    $0x0,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  ret
L26:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int utf8_to_unicode(const char *utf8, char *unicode) {
  int i, num;
  const char *str = utf8;
  unsigned char ch;
  i = 0;
  while (str) {
    ch = (unsigned char)*str;
    if (ch == '\0')
      break;
    num = cal_utf8_num_bytes(ch);
    switch (num) {
    case 0:
      unicode[i] = utf8[0];
      break;
    case 2:
      break;
    case 3:
      unicode[i + 1] = ((utf8[0] & 0x0F) << 4) | ((utf8[1] >> 2) & 0x0F);
      unicode[i] = ((utf8[1] & 0x03) << 6) + (utf8[2] & 0x3F);
      break;
    default:
      break;
    }
    if (num)
      utf8 += num;
    else
      ++utf8;
    i += 2;
  }
  return i / 2;
}
```
user: What is the c source code of the assembly code below?

```asm
<utf8_to_unicode>:
  endbr64
  test   %rdi,%rdi
  je     L7
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L1
  nopl   (%rax)
L2:
  cmp    $0x3,%eax
  jne    L4
  movzbl 0x1(%r13),%edx
  movsbl 0x0(%r13),%ecx
  sar    $0x2,%dl
  shl    $0x4,%ecx
  and    $0xf,%edx
  or     %ecx,%edx
  mov    %dl,0x1(%rbp,%r12,1)
  movsbl 0x1(%r13),%ecx
  movzbl 0x2(%r13),%edx
  shl    $0x6,%ecx
  and    $0x3f,%edx
  add    %ecx,%edx
  mov    %dl,0x0(%rbp,%r12,1)
L4:
  cltq
  add    %rax,%r13
L10:
  add    $0x2,%r12
L1:
  movzbl (%rbx),%edi
  mov    %r12d,%eax
  test   %dil,%dil
  je     L48
  call   <cal_utf8_num_bytes@plt>
  test   %eax,%eax
  jne    L2
  movzbl 0x0(%r13),%eax
  add    $0x1,%r13
  mov    %al,0x0(%rbp,%r12,1)
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L48:
  add    $0x8,%rsp
  sar    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int utf8_to_unicode(const char *utf8, char *unicode) {
  int i, num;
  const char *str = utf8;
  unsigned char ch;
  i = 0;
  while (str) {
    ch = (unsigned char)*str;
    if (ch == '\0')
      break;
    num = cal_utf8_num_bytes(ch);
    switch (num) {
    case 0:
      unicode[i] = utf8[0];
      break;
    case 2:
      break;
    case 3:
      unicode[i + 1] = ((utf8[0] & 0x0F) << 4) | ((utf8[1] >> 2) & 0x0F);
      unicode[i] = ((utf8[1] & 0x03) << 6) + (utf8[2] & 0x3F);
      break;
    default:
      break;
    }
    if (num)
      utf8 += num;
    else
      ++utf8;
    i += 2;
  }
  return i / 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<utf8_to_unicode>:
  endbr64
  test   %rdi,%rdi
  je     L70
  push   %r13
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%r13
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L50
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L21:
  cmp    $0x3,%eax
  jne    L16
  movzbl 0x1(%r13),%edx
  movsbl 0x0(%r13),%ecx
  sar    $0x2,%dl
  shl    $0x4,%ecx
  and    $0xf,%edx
  or     %ecx,%edx
  mov    %dl,-0x1(%rbp,%r12,1)
  movsbl 0x1(%r13),%ecx
  movzbl 0x2(%r13),%edx
  shl    $0x6,%ecx
  and    $0x3f,%edx
  add    %ecx,%edx
  mov    %dl,-0x2(%rbp,%r12,1)
L16:
  movzbl (%rbx),%edi
  cltq
  add    %rax,%r13
  mov    %r12d,%eax
  add    $0x2,%r12
  test   %dil,%dil
  je     L28
L50:
  call   <cal_utf8_num_bytes@plt>
  test   %eax,%eax
  jne    L21
  movzbl 0x0(%r13),%eax
  add    $0x1,%r13
  mov    %al,-0x2(%rbp,%r12,1)
  movzbl (%rbx),%edi
  mov    %r12d,%eax
  add    $0x2,%r12
  test   %dil,%dil
  jne    L50
L28:
  add    $0x8,%rsp
  sar    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L70:
  xor    %eax,%eax
  ret
L40:
  xor    %eax,%eax
  jmp    L28
```

assistant: ```c
int utf8_to_unicode(const char *utf8, char *unicode) {
  int i, num;
  const char *str = utf8;
  unsigned char ch;
  i = 0;
  while (str) {
    ch = (unsigned char)*str;
    if (ch == '\0')
      break;
    num = cal_utf8_num_bytes(ch);
    switch (num) {
    case 0:
      unicode[i] = utf8[0];
      break;
    case 2:
      break;
    case 3:
      unicode[i + 1] = ((utf8[0] & 0x0F) << 4) | ((utf8[1] >> 2) & 0x0F);
      unicode[i] = ((utf8[1] & 0x03) << 6) + (utf8[2] & 0x3F);
      break;
    default:
      break;
    }
    if (num)
      utf8 += num;
    else
      ++utf8;
    i += 2;
  }
  return i / 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L7
L109:
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  cmp    %eax,%edx
  jge    L3
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
L3:
  movl   $0x0,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L92
L6:
  movl   $0x1,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L71
L0:
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L44
  mov    -0x20(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
  jmp    L71
L79:
  sarl   -0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
L44:
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L79
L71:
  cmpl   $0x1,-0x20(%rbp)
  jne    L0
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L72
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L72:
  addl   $0x1,-0x24(%rbp)
L92:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L6
  mov    -0x18(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  lea    -0x28(%rbp),%rdx
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L109
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D17: %d %d %d


tool: D1: %d %d

assistant: ```c
int main() {
  int l_bound, u_bound;
  int l_bound_org, u_bound_org, temp;
  int i, j, length, max_length;
  while (scanf("%d %d", &l_bound, &u_bound) == 2) {
    l_bound_org = l_bound;
    u_bound_org = u_bound;
    if (u_bound < l_bound) {
      temp = u_bound;
      u_bound = l_bound;
      l_bound = temp;
    }
    max_length = 0;
    for (i = l_bound; i <= u_bound; i++) {
      length = 1;
      j = i;
      while (j != 1) {
        if (j & 1) {
          j = 3 * j + 1;
          length++;
        } else {
          while (!(j & 1)) {
            j >>= 1;
            length++;
          }
        }
      }
      if (max_length < length)
        max_length = length;
    }
    printf("%d %d %d\n", l_bound_org, u_bound_org, max_length);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  lea    D3(%rip),%rbx
  lea    D11(%rip),%r13
  jmp    L32
L73:
  sar    %eax
  add    $0x1,%edx
  test   $0x1,%al
  je     L73
L111:
  cmp    $0x1,%eax
  je     L3
L110:
  test   $0x1,%al
  je     L73
  lea    0x1(%rax,%rax,2),%eax
  add    $0x1,%edx
  jmp    L111
L3:
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x1,%ecx
  cmp    %edi,%ecx
  jg     L56
L101:
  mov    %ecx,%eax
  mov    $0x1,%edx
  cmp    $0x1,%ecx
  jne    L110
  mov    %ecx,%edx
  jmp    L3
L56:
  mov    %esi,%ecx
  mov    %r9d,%edx
  mov    %r8d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L32:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L26
  mov    (%rsp),%r8d
  mov    0x4(%rsp),%r9d
  cmp    %r9d,%r8d
  jle    L85
  mov    %r8d,0x4(%rsp)
  mov    %r9d,(%rsp)
L85:
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edi
  mov    $0x0,%esi
  jmp    L101
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L114
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L114:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D3: %d %d

tool: D11: %d %d %d


assistant: ```c
int main() {
  int l_bound, u_bound;
  int l_bound_org, u_bound_org, temp;
  int i, j, length, max_length;
  while (scanf("%d %d", &l_bound, &u_bound) == 2) {
    l_bound_org = l_bound;
    u_bound_org = u_bound;
    if (u_bound < l_bound) {
      temp = u_bound;
      u_bound = l_bound;
      l_bound = temp;
    }
    max_length = 0;
    for (i = l_bound; i <= u_bound; i++) {
      length = 1;
      j = i;
      while (j != 1) {
        if (j & 1) {
          j = 3 * j + 1;
          length++;
        } else {
          while (!(j & 1)) {
            j >>= 1;
            length++;
          }
        }
      }
      if (max_length < length)
        max_length = length;
    }
    printf("%d %d %d\n", l_bound_org, u_bound_org, max_length);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
L15:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L110
  mov    (%rsp),%r9d
  mov    0x4(%rsp),%r10d
  cmp    %r10d,%r9d
  jle    L100
  mov    %r9d,0x4(%rsp)
  mov    %r10d,%ecx
  mov    %r9d,%esi
  mov    %r10d,(%rsp)
L84:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %ecx,%eax
  mov    $0x1,%edx
  cmp    $0x1,%ecx
  jne    L53
  jmp    L126
  xchg   %ax,%ax
L77:
  add    $0x1,%edx
  lea    0x1(%rax,%rax,2),%eax
L23:
  cmp    $0x1,%eax
  je     L126
L53:
  test   $0x1,%al
  jne    L77
L13:
  sar    %eax
  add    $0x1,%edx
  test   $0x1,%al
  jne    L23
  sar    %eax
  add    $0x1,%edx
  test   $0x1,%al
  je     L13
  jmp    L23
  nopl   0x0(%rax)
L126:
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L41
  mov    %r8d,%ecx
  mov    %r10d,%edx
  mov    %r9d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L15
L100:
  mov    %r9d,%ecx
  mov    %r10d,%esi
  jmp    L84
L110:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D15
type_guessed: string

tool: D8: %d %d %d


tool: D15: %d %d

assistant: ```c
int main() {
  int l_bound, u_bound;
  int l_bound_org, u_bound_org, temp;
  int i, j, length, max_length;
  while (scanf("%d %d", &l_bound, &u_bound) == 2) {
    l_bound_org = l_bound;
    u_bound_org = u_bound;
    if (u_bound < l_bound) {
      temp = u_bound;
      u_bound = l_bound;
      l_bound = temp;
    }
    max_length = 0;
    for (i = l_bound; i <= u_bound; i++) {
      length = 1;
      j = i;
      while (j != 1) {
        if (j & 1) {
          j = 3 * j + 1;
          length++;
        } else {
          while (!(j & 1)) {
            j >>= 1;
            length++;
          }
        }
      }
      if (max_length < length)
        max_length = length;
    }
    printf("%d %d %d\n", l_bound_org, u_bound_org, max_length);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
L59:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L54
  mov    (%rsp),%r9d
  mov    0x4(%rsp),%r10d
  cmp    %r10d,%r9d
  jle    L122
  mov    %r9d,0x4(%rsp)
  mov    %r10d,%ecx
  mov    %r9d,%esi
  mov    %r10d,(%rsp)
L22:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L124:
  mov    %ecx,%eax
  mov    $0x1,%edx
  cmp    $0x1,%ecx
  jne    L91
  jmp    L55
  xchg   %ax,%ax
L86:
  add    $0x1,%edx
  lea    0x1(%rax,%rax,2),%eax
L5:
  cmp    $0x1,%eax
  je     L55
L91:
  test   $0x1,%al
  jne    L86
L102:
  sar    %eax
  add    $0x1,%edx
  test   $0x1,%al
  jne    L5
  sar    %eax
  add    $0x1,%edx
  test   $0x1,%al
  je     L102
  jmp    L5
  nopl   0x0(%rax)
L55:
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L124
  mov    %r8d,%ecx
  mov    %r10d,%edx
  mov    %r9d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L59
L122:
  mov    %r9d,%ecx
  mov    %r10d,%esi
  jmp    L22
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L100
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L100:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
data_type: string
name: parse_data
arguments: data_tag: D1
data_type: string

tool: D12: %d %d %d


tool: D1: %d %d

assistant: ```c
int main() {
  int l_bound, u_bound;
  int l_bound_org, u_bound_org, temp;
  int i, j, length, max_length;
  while (scanf("%d %d", &l_bound, &u_bound) == 2) {
    l_bound_org = l_bound;
    u_bound_org = u_bound;
    if (u_bound < l_bound) {
      temp = u_bound;
      u_bound = l_bound;
      l_bound = temp;
    }
    max_length = 0;
    for (i = l_bound; i <= u_bound; i++) {
      length = 1;
      j = i;
      while (j != 1) {
        if (j & 1) {
          j = 3 * j + 1;
          length++;
        } else {
          while (!(j & 1)) {
            j >>= 1;
            length++;
          }
        }
      }
      if (max_length < length)
        max_length = length;
    }
    printf("%d %d %d\n", l_bound_org, u_bound_org, max_length);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<list_splice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <list_empty@plt>
  test   %eax,%eax
  jne    L4
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_list_splice@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void list_splice(struct list_head *list, struct list_head *head) {
  if (!list_empty(list))
    _list_splice(list, head);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<list_splice>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L10
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <_list_splice@plt>
  jmp    L14
```

assistant: ```c
void list_splice(struct list_head *list, struct list_head *head) {
  if (!list_empty(list))
    _list_splice(list, head);
}
```
user: Translate the below assembly code into C programming language:

```asm
<list_splice>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L9
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_list_splice@plt>
```

assistant: ```c
void list_splice(struct list_head *list, struct list_head *head) {
  if (!list_empty(list))
    _list_splice(list, head);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<list_splice>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <_list_splice@plt>
```

assistant: ```c
void list_splice(struct list_head *list, struct list_head *head) {
  if (!list_empty(list))
    _list_splice(list, head);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getPosFromTaggedString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L42
L53:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  jne    L37
  movl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
L37:
  cmpl   $0x0,-0x1c(%rbp)
  je     L9
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L9
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  lea    -0xa(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L9:
  addl   $0x1,-0x20(%rbp)
L42:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
char *getPosFromTaggedString(char *str) {
  char *result = malloc(sizeof(char) * 256);
  char cToStr[2];
  cToStr[1] = '\0';
  int i = 0;
  int past = 0;
  while (str[i] != 0) {
    if (str[i] == '_') {
      past = 1;
      i++;
    }
    if (past && str[i] != '\n') {
      cToStr[0] = str[i];
      strcat(result, cToStr);
    }
    i++;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getPosFromTaggedString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movb   $0x0,0x7(%rsp)
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L21
  mov    $0x0,%edx
  mov    $0x0,%ebx
  mov    $0x1,%r12d
  jmp    L38
L59:
  add    $0x1,%ebx
L85:
  movslq %ebx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  mov    %r12d,%edx
  cmp    $0xa,%al
  jne    L7
L48:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  test   %al,%al
  je     L21
L38:
  cmp    $0x5f,%al
  je     L59
  test   %edx,%edx
  je     L48
  jmp    L85
L7:
  mov    %al,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %r12d,%edx
  jmp    L48
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *getPosFromTaggedString(char *str) {
  char *result = malloc(sizeof(char) * 256);
  char cToStr[2];
  cToStr[1] = '\0';
  int i = 0;
  int past = 0;
  while (str[i] != 0) {
    if (str[i] == '_') {
      past = 1;
      i++;
    }
    if (past && str[i] != '\n') {
      cToStr[0] = str[i];
      strcat(result, cToStr);
    }
    i++;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getPosFromTaggedString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x100,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  movb   $0x0,0x7(%rsp)
  mov    %rax,%r13
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L25
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L11:
  test   %r12d,%r12d
  je     L40
L64:
  movslq %ebx,%rax
  mov    $0x1,%r12d
  movzbl 0x0(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  je     L40
  lea    0x6(%rsp),%rsi
  mov    %r13,%rdi
  mov    %al,0x6(%rsp)
  call   <strcat@plt>
L40:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  test   %al,%al
  je     L25
L65:
  cmp    $0x5f,%al
  jne    L11
  add    $0x1,%ebx
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *getPosFromTaggedString(char *str) {
  char *result = malloc(sizeof(char) * 256);
  char cToStr[2];
  cToStr[1] = '\0';
  int i = 0;
  int past = 0;
  while (str[i] != 0) {
    if (str[i] == '_') {
      past = 1;
      i++;
    }
    if (past && str[i] != '\n') {
      cToStr[0] = str[i];
      strcat(result, cToStr);
    }
    i++;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getPosFromTaggedString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x100,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  movb   $0x0,0x7(%rsp)
  mov    %rax,%r13
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L60
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L21:
  test   %r12d,%r12d
  je     L52
L16:
  mov    $0x1,%r12d
  cmp    $0xa,%al
  je     L52
  lea    0x6(%rsp),%rsi
  mov    %r13,%rdi
  mov    %al,0x6(%rsp)
  call   <strcat@plt>
L52:
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  test   %al,%al
  je     L60
L15:
  cmp    $0x5f,%al
  jne    L21
  add    $0x1,%ebx
  movslq %ebx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L60:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *getPosFromTaggedString(char *str) {
  char *result = malloc(sizeof(char) * 256);
  char cToStr[2];
  cToStr[1] = '\0';
  int i = 0;
  int past = 0;
  while (str[i] != 0) {
    if (str[i] == '_') {
      past = 1;
      i++;
    }
    if (past && str[i] != '\n') {
      cToStr[0] = str[i];
      strcat(result, cToStr);
    }
    i++;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ldiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
ldiv_t ldiv(long numer, long denom) {
  ldiv_t ret;
  ret.quot = numer / denom;
  ret.rem = numer % denom;
  return ret;
}
```