ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcasestr>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L78
  xor    %ebx,%ebx
  mov    %rsi,%rbp
  lea    0x1(%rsi),%r13
  xor    %r12d,%r12d
  test   %rbx,%rbx
  je     L57
  nopw   0x0(%rax,%rax,1)
L83:
  call   <toupper@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r14
  call   <toupper@plt>
  cmp    %rax,%r14
  je     L3
  movsbl 0x1(%r15),%edi
  lea    0x1(%r15),%r12
  test   %dil,%dil
  je     L78
L92:
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%rbx
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L64
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L92
L78:
  xor    %r12d,%r12d
L77:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L3:
  cmpb   $0x0,0x1(%rbx)
  lea    0x1(%rbx),%rdx
  je     L77
  mov    %r15,%rax
  mov    %rdx,%rbx
L72:
  movsbl 0x1(%rax),%edi
  lea    0x1(%rax),%r15
  test   %dil,%dil
  je     L78
  test   %rbx,%rbx
  jne    L83
L57:
  mov    %r15,%r12
  jmp    L92
  nopl   0x0(%rax,%rax,1)
L64:
  mov    %r13,%rbx
  mov    %r12,%rax
  jmp    L72
```

assistant: ```c
char *strcasestr(char *haystack, char *needle) {
  char *p, *startn = NULL, *np = NULL;
  for (p = haystack; *p != '\0'; ++p) {
    if (np != NULL) {
      if (toupper(*p) == toupper(*np)) {
        if (*++np == '\0') {
          return startn;
        }
      } else {
        np = NULL;
      }
    } else if (toupper(*p) == toupper(*needle)) {
      np = needle + 1;
      startn = p;
    }
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcasestr>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L91
  xor    %ebx,%ebx
  mov    %rsi,%rbp
  lea    0x1(%rsi),%r13
  xor    %r12d,%r12d
  test   %rbx,%rbx
  je     L77
  nopw   0x0(%rax,%rax,1)
L11:
  call   <toupper@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r14
  call   <toupper@plt>
  cmp    %rax,%r14
  je     L52
  movsbl 0x1(%r15),%edi
  lea    0x1(%r15),%r12
  test   %dil,%dil
  je     L91
L10:
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%rbx
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L88
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L10
L91:
  xor    %r12d,%r12d
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L52:
  cmpb   $0x0,0x1(%rbx)
  lea    0x1(%rbx),%rdx
  je     L2
  mov    %r15,%rax
  mov    %rdx,%rbx
L30:
  movsbl 0x1(%rax),%edi
  lea    0x1(%rax),%r15
  test   %dil,%dil
  je     L91
  test   %rbx,%rbx
  jne    L11
L77:
  mov    %r15,%r12
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L88:
  mov    %r13,%rbx
  mov    %r12,%rax
  jmp    L30
```

assistant: ```c
char *strcasestr(char *haystack, char *needle) {
  char *p, *startn = NULL, *np = NULL;
  for (p = haystack; *p != '\0'; ++p) {
    if (np != NULL) {
      if (toupper(*p) == toupper(*np)) {
        if (*++np == '\0') {
          return startn;
        }
      } else {
        np = NULL;
      }
    } else if (toupper(*p) == toupper(*needle)) {
      np = needle + 1;
      startn = p;
    }
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int _i, int _j, int _p) {
  int i;
  int j;
  int p;
  i = _i;
  j = _j;
  p = _p;
  i = 0;
  j = 0;
  p = (i == j);
  assert(p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int _i, int _j, int _p) {
  int i;
  int j;
  int p;
  i = _i;
  j = _j;
  p = _p;
  i = 0;
  j = 0;
  p = (i == j);
  assert(p);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int _i, int _j, int _p) {
  int i;
  int j;
  int p;
  i = _i;
  j = _j;
  p = _p;
  i = 0;
  j = 0;
  p = (i == j);
  assert(p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int _i, int _j, int _p) {
  int i;
  int j;
  int p;
  i = _i;
  j = _j;
  p = _p;
  i = 0;
  j = 0;
  p = (i == j);
  assert(p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ModelicaFormatMessage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void ModelicaFormatMessage(const char *string, ...) {
  va_list p_arg;
  va_start(p_arg, string);
  vprintf(string, p_arg);
  va_end(p_arg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ModelicaFormatMessage>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ModelicaFormatMessage(const char *string, ...) {
  va_list p_arg;
  va_start(p_arg, string);
  vprintf(string, p_arg);
  va_end(p_arg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ModelicaFormatMessage>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ModelicaFormatMessage(const char *string, ...) {
  va_list p_arg;
  va_start(p_arg, string);
  vprintf(string, p_arg);
  va_end(p_arg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ModelicaFormatMessage>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ModelicaFormatMessage(const char *string, ...) {
  va_list p_arg;
  va_start(p_arg, string);
  vprintf(string, p_arg);
  va_end(p_arg);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D9: 1st order: %i drinks


assistant: ```c
int main(int argc, char const *argv[]) {
  int drinks[] = {4, 2, 3};
  printf("1st order: %i drinks\n", drinks[0]);
  printf("1st order: %i drinks\n", *drinks);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D5: 1st order: %i drinks


assistant: ```c
int main(int argc, char const *argv[]) {
  int drinks[] = {4, 2, 3};
  printf("1st order: %i drinks\n", drinks[0]);
  printf("1st order: %i drinks\n", *drinks);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: 1st order: %i drinks


assistant: ```c
int main(int argc, char const *argv[]) {
  int drinks[] = {4, 2, 3};
  printf("1st order: %i drinks\n", drinks[0]);
  printf("1st order: %i drinks\n", *drinks);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 1st order: %i drinks


assistant: ```c
int main(int argc, char const *argv[]) {
  int drinks[] = {4, 2, 3};
  printf("1st order: %i drinks\n", drinks[0]);
  printf("1st order: %i drinks\n", *drinks);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cl,-0x4(%rbp)
  mov    %esi,%ecx
  mov    %cl,-0x8(%rbp)
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x4(%rbp),%eax
  sub    $0x2b,%eax
  mov    %al,D18(%rip)
  movzbl -0x8(%rbp),%eax
  sub    $0x2d,%eax
  mov    %al,D54(%rip)
  movzbl -0xc(%rbp),%eax
  sub    $0x23,%eax
  mov    %al,D0(%rip)
  movzbl -0x10(%rbp),%eax
  sub    $0x26,%eax
  mov    %al,D30(%rip)
  movzbl -0x14(%rbp),%eax
  sub    $0x25,%eax
  mov    %al,D50(%rip)
  movb   $0x0,D25(%rip)
  lea    D18(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *decr(a, b, c, d, e)
char a, b, c, d, e;
{
  static char buf[6];
  buf[0] = a - '+';
  buf[1] = b - '-';
  buf[2] = c - '#';
  buf[3] = d - '&';
  buf[4] = e - '%';
  buf[5] = 0;
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decr>:
  endbr64
  sub    $0x2b,%edi
  mov    %dil,D60(%rip)
  sub    $0x2d,%esi
  mov    %sil,D31(%rip)
  sub    $0x23,%edx
  mov    %dl,D36(%rip)
  sub    $0x26,%ecx
  mov    %cl,D27(%rip)
  sub    $0x25,%r8d
  mov    %r8b,D65(%rip)
  movb   $0x0,D19(%rip)
  lea    D60(%rip),%rax
  ret
```

assistant: ```c
char *decr(a, b, c, d, e)
char a, b, c, d, e;
{
  static char buf[6];
  buf[0] = a - '+';
  buf[1] = b - '-';
  buf[2] = c - '#';
  buf[3] = d - '&';
  buf[4] = e - '%';
  buf[5] = 0;
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decr>:
  endbr64
  sub    $0x2b,%edi
  sub    $0x2d,%esi
  sub    $0x23,%edx
  sub    $0x26,%ecx
  sub    $0x25,%r8d
  mov    %dil,D58(%rip)
  lea    D58(%rip),%rax
  mov    %sil,D26(%rip)
  mov    %dl,D37(%rip)
  mov    %cl,D4(%rip)
  mov    %r8b,D52(%rip)
  movb   $0x0,D10(%rip)
  ret
```

assistant: ```c
char *decr(a, b, c, d, e)
char a, b, c, d, e;
{
  static char buf[6];
  buf[0] = a - '+';
  buf[1] = b - '-';
  buf[2] = c - '#';
  buf[3] = d - '&';
  buf[4] = e - '%';
  buf[5] = 0;
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decr>:
  endbr64
  xor    %eax,%eax
  sub    $0x2b,%edi
  push   %rbx
  sub    $0x23,%edx
  lea    -0x2d(%rsi),%ebx
  mov    %dil,%al
  movzbl %dl,%edx
  sub    $0x26,%ecx
  mov    %bl,%ah
  shl    $0x10,%edx
  sub    $0x25,%r8d
  movb   $0x0,D9(%rip)
  movzwl %ax,%eax
  shl    $0x18,%ecx
  mov    %r8b,D33(%rip)
  pop    %rbx
  or     %edx,%eax
  or     %ecx,%eax
  mov    %eax,D38(%rip)
  lea    D38(%rip),%rax
  ret
```

assistant: ```c
char *decr(a, b, c, d, e)
char a, b, c, d, e;
{
  static char buf[6];
  buf[0] = a - '+';
  buf[1] = b - '-';
  buf[2] = c - '#';
  buf[3] = d - '&';
  buf[4] = e - '%';
  buf[5] = 0;
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<orderedmap_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <orderedmap_destroy_contents@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *orderedmap_destroy(struct orderedmap *o) {
  orderedmap_destroy_contents(o);
  free(o);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<orderedmap_destroy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <orderedmap_destroy_contents@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *orderedmap_destroy(struct orderedmap *o) {
  orderedmap_destroy_contents(o);
  free(o);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<orderedmap_destroy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <orderedmap_destroy_contents@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *orderedmap_destroy(struct orderedmap *o) {
  orderedmap_destroy_contents(o);
  free(o);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<orderedmap_destroy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <orderedmap_destroy_contents@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *orderedmap_destroy(struct orderedmap *o) {
  orderedmap_destroy_contents(o);
  free(o);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L6:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *src = s;
  while (*s++ != '\0')
    ;
  return (s - src - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rax
L0:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L0
  sub    %rdi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *src = s;
  while (*s++ != '\0')
    ;
  return (s - src - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L3
  sub    %rdi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *src = s;
  while (*s++ != '\0')
    ;
  return (s - src - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlen>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L9
  sub    %rdi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *src = s;
  while (*s++ != '\0')
    ;
  return (s - src - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quadInOut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  %xmm3,-0x10(%rbp)
  movss  D1(%rip),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L5
  movss  -0xc(%rbp),%xmm0
  movss  D22(%rip),%xmm1
  movaps %xmm0,%xmm3
  divss  %xmm1,%xmm3
  movss  -0x4(%rbp),%xmm0
  addss  %xmm0,%xmm0
  cvttss2si %xmm0,%eax
  movss  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%edx
  movaps %xmm0,%xmm2
  movaps %xmm3,%xmm1
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <quadIn@plt>
  jmp    L1
L5:
  movss  -0xc(%rbp),%xmm0
  movss  D22(%rip),%xmm1
  movaps %xmm0,%xmm3
  divss  %xmm1,%xmm3
  movss  -0xc(%rbp),%xmm0
  movss  D22(%rip),%xmm1
  divss  %xmm1,%xmm0
  addss  -0x8(%rbp),%xmm0
  movd   %xmm0,%edx
  movss  -0x4(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  D42(%rip),%xmm1
  subss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm2
  movaps %xmm3,%xmm1
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <quadOut@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: f32
name: parse_data
arguments: data_tag: D22
data_type: byte[4]
name: parse_data
arguments: data_tag: D42
data_type: byte[4]

tool: D1: 0.5

tool: {"D22": [0x00,0x00,0x00,0x40]}

tool: {"D42": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float quadInOut(float fraction, float start, float delta, float slope) {
  if (fraction < 0.5)
    return quadIn(2 * fraction, start, delta / 2, slope);
  return quadOut(2 * fraction - 1, start + delta / 2, delta / 2, slope);
}
```
user: What is the c source code of the assembly code below?

```asm
<quadInOut>:
  endbr64
  sub    $0x8,%rsp
  movaps %xmm0,%xmm4
  movaps %xmm1,%xmm0
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm2
  movss  D20(%rip),%xmm3
  comiss %xmm4,%xmm3
  ja     L2
  mulss  D20(%rip),%xmm1
  addss  %xmm1,%xmm0
  addss  %xmm4,%xmm4
  subss  D1(%rip),%xmm4
  cvttss2si %xmm4,%edi
  call   <quadOut@plt>
L14:
  add    $0x8,%rsp
  ret
L2:
  addss  %xmm4,%xmm4
  cvttss2si %xmm4,%edi
  mulss  %xmm3,%xmm1
  call   <quadIn@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: data_label: D20
type_guessed: f32
name: unpack_data
arguments: data_label: D1
type_guessed: byte[4]

tool: D20: 0.5

tool: {"D1": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float quadInOut(float fraction, float start, float delta, float slope) {
  if (fraction < 0.5)
    return quadIn(2 * fraction, start, delta / 2, slope);
  return quadOut(2 * fraction - 1, start + delta / 2, delta / 2, slope);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<quadInOut>:
  endbr64
  movss  D12(%rip),%xmm5
  movaps %xmm0,%xmm4
  movaps %xmm1,%xmm0
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm5,%xmm1
  comiss %xmm4,%xmm5
  addss  %xmm4,%xmm3
  ja     L7
  subss  D13(%rip),%xmm3
  addss  %xmm1,%xmm0
  cvttss2si %xmm3,%edi
  jmp    1070 <quadOut@plt>
  nopl   (%rax)
L7:
  cvttss2si %xmm3,%edi
  jmp    1060 <quadIn@plt>
```

tool_calls: name: read_data
arguments: tag: D12
data_type: f32
name: read_data
arguments: tag: D13
data_type: byte[4]

tool: D12: 0.5

tool: {"D13": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float quadInOut(float fraction, float start, float delta, float slope) {
  if (fraction < 0.5)
    return quadIn(2 * fraction, start, delta / 2, slope);
  return quadOut(2 * fraction - 1, start + delta / 2, delta / 2, slope);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quadInOut>:
  endbr64
  movss  D12(%rip),%xmm5
  movaps %xmm0,%xmm4
  movaps %xmm1,%xmm0
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm5,%xmm1
  comiss %xmm4,%xmm5
  addss  %xmm4,%xmm3
  ja     L7
  subss  D4(%rip),%xmm3
  addss  %xmm1,%xmm0
  cvttss2si %xmm3,%edi
  jmp    1070 <quadOut@plt>
  nopl   (%rax)
L7:
  cvttss2si %xmm3,%edi
  jmp    1060 <quadIn@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: f32
name: retrieve_data
arguments: label: D4
datatype: byte[4]

tool: D12: 0.5

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float quadInOut(float fraction, float start, float delta, float slope) {
  if (fraction < 0.5)
    return quadIn(2 * fraction, start, delta / 2, slope);
  return quadOut(2 * fraction - 1, start + delta / 2, delta / 2, slope);
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_rchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L12
L15:
  mov    -0x1c(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
unsigned int byte_rchr(const void *s, unsigned int n, int c) {
  const void *p;
  return (p = memrchr(s, c, n)) == 0 ? n : (p - s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<byte_rchr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    %ebx,%edx
  call   <memrchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  mov    %edx,%eax
  cmove  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int byte_rchr(const void *s, unsigned int n, int c) {
  const void *p;
  return (p = memrchr(s, c, n)) == 0 ? n : (p - s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_rchr>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    %ebx,%edx
  sub    $0x8,%rsp
  call   <memrchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  mov    %edx,%eax
  cmove  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int byte_rchr(const void *s, unsigned int n, int c) {
  const void *p;
  return (p = memrchr(s, c, n)) == 0 ? n : (p - s);
}
```
user: What is the c source code of the assembly code below?

```asm
<byte_rchr>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    %ebx,%edx
  sub    $0x8,%rsp
  call   <memrchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  mov    %edx,%eax
  cmove  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int byte_rchr(const void *s, unsigned int n, int c) {
  const void *p;
  return (p = memrchr(s, c, n)) == 0 ? n : (p - s);
}
```