ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jg     L26
  xor    %edi,%edi
  xor    %r14d,%r14d
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
L1:
  mov    0x8(%rsp),%rdi
  mov    %r14d,%esi
  call   <pegaMapa@plt>
L54:
  mov    0x8(%rsp),%rdi
  mov    %r14d,%esi
  call   <buscaCaminho@plt>
  xor    %eax,%eax
  call   <move@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    0x0(,%rax,8),%edi
  mov    %eax,%r14d
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
  test   %r14d,%r14d
  jle    L1
  mov    %rax,%rbx
  lea    -0x1(%r14),%eax
  lea    0x8(%rbp,%rax,8),%r13
  nopl   0x0(%rax)
L0:
  mov    %r14d,%edi
  add    $0x8,%rbp
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r13,%rbp
  jne    L0
  mov    0x8(%rsp),%rdi
  mov    %r14d,%esi
  lea    D2(%rip),%r12
  mov    %r14d,%ebp
  call   <pegaMapa@plt>
  nopl   0x0(%rax)
L4:
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L51:
  mov    (%rbx),%rax
  mov    %r12,%rdi
  movsbl (%rax,%r15,1),%esi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L51
  mov    $0xa,%edi
  add    $0x8,%rbx
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L4
  jmp    L54
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string

tool: D2: %c 

assistant: ```c
int main(int argc, char const *argv[]) {
  int map_size = 0, i, j;
  char **map;
  if (argc >= 2) {
    map_size = atoi(argv[1]);
  }
  map = (char **)malloc(sizeof(char *) * map_size);
  for (i = 0; i < map_size; i++) {
    map[i] = (char *)malloc(sizeof(char) * map_size);
  }
  pegaMapa(map, map_size);
  for (i = 0; i < map_size; i++) {
    for (j = 0; j < map_size; j++) {
      printf("%c ", map[i][j]);
    }
    printf("\n");
  }
  buscaCaminho(map, map_size);
  move();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<syscall1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0x1c(%rbp)
  mov    %esi,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x20(%rbp),%edx
  int    $0xff
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long syscall1(int op, unsigned int arg1) {
  long ret;
  asm volatile("int $0xff" : "=a"(ret) : "0"(op), "d"(arg1) : "cc", "ebx", "edi", "esi", "memory");
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<syscall1>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  mov    %esi,%edx
  int    $0xff
  pop    %rbx
  ret
```

assistant: ```c
long syscall1(int op, unsigned int arg1) {
  long ret;
  asm volatile("int $0xff" : "=a"(ret) : "0"(op), "d"(arg1) : "cc", "ebx", "edi", "esi", "memory");
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<syscall1>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  mov    %esi,%edx
  int    $0xff
  pop    %rbx
  ret
```

assistant: ```c
long syscall1(int op, unsigned int arg1) {
  long ret;
  asm volatile("int $0xff" : "=a"(ret) : "0"(op), "d"(arg1) : "cc", "ebx", "edi", "esi", "memory");
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<syscall1>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  mov    %esi,%edx
  int    $0xff
  pop    %rbx
  ret
```

assistant: ```c
long syscall1(int op, unsigned int arg1) {
  long ret;
  asm volatile("int $0xff" : "=a"(ret) : "0"(op), "d"(arg1) : "cc", "ebx", "edi", "esi", "memory");
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x130(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x130(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x11c(%rbp)
  lea    -0x11c(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  je     L36
  mov    -0x118(%rbp),%rcx
  mov    -0x128(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  test   %eax,%eax
  je     L40
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  lea    -0x110(%rbp),%rcx
  mov    -0x130(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L42
L36:
  nop
  jmp    L42
L40:
  nop
L42:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void get_time(const char *format, char *dest) {
  char dest_time[256];
  memset(dest, 0, strlen(dest));
  time_t curtime;
  struct tm *loctime;
  curtime = time(NULL);
  loctime = localtime(&curtime);
  if (!loctime)
    return;
  if (!strftime(dest_time, sizeof(dest_time), format, loctime))
    return;
  strncpy(dest, dest_time, strlen(dest_time) + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_time>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%rcx
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rdx
  mov    $0x100,%esi
  call   <strftime@plt>
  test   %eax,%eax
  jne    L32
L22:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  jmp    L22
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_time(const char *format, char *dest) {
  char dest_time[256];
  memset(dest, 0, strlen(dest));
  time_t curtime;
  struct tm *loctime;
  curtime = time(NULL);
  loctime = localtime(&curtime);
  if (!loctime)
    return;
  if (!strftime(dest_time, sizeof(dest_time), format, loctime))
    return;
  strncpy(dest, dest_time, strlen(dest_time) + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_time>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  call   <memset@plt>
  xor    %edi,%edi
  call   <time@plt>
  lea    0xc(%rsp),%rdi
  mov    %eax,0xc(%rsp)
  call   <localtime@plt>
  test   %rax,%rax
  je     L33
  lea    0x10(%rsp),%r12
  mov    %rax,%rcx
  mov    %r13,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <strftime@plt>
  test   %eax,%eax
  jne    L20
L33:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L20:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <strncpy@plt>
  jmp    L33
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_time(const char *format, char *dest) {
  char dest_time[256];
  memset(dest, 0, strlen(dest));
  time_t curtime;
  struct tm *loctime;
  curtime = time(NULL);
  loctime = localtime(&curtime);
  if (!loctime)
    return;
  if (!strftime(dest_time, sizeof(dest_time), format, loctime))
    return;
  strncpy(dest, dest_time, strlen(dest_time) + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_time>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  call   <memset@plt>
  xor    %edi,%edi
  call   <time@plt>
  lea    0xc(%rsp),%rdi
  mov    %eax,0xc(%rsp)
  call   <localtime@plt>
  test   %rax,%rax
  je     L12
  lea    0x10(%rsp),%r12
  mov    %rax,%rcx
  mov    %r13,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <strftime@plt>
  test   %eax,%eax
  jne    L29
L12:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <strncpy@plt>
  jmp    L12
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_time(const char *format, char *dest) {
  char dest_time[256];
  memset(dest, 0, strlen(dest));
  time_t curtime;
  struct tm *loctime;
  curtime = time(NULL);
  loctime = localtime(&curtime);
  if (!loctime)
    return;
  if (!strftime(dest_time, sizeof(dest_time), format, loctime))
    return;
  strncpy(dest, dest_time, strlen(dest_time) + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<create_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <state_size@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  jmp    L6
L5:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
void *create_state(const int type) {
  size_t statesize;
  statesize = state_size(type);
  if (statesize)
    return malloc(statesize);
  else
    return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<create_state>:
  endbr64
  sub    $0x8,%rsp
  call   <state_size@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L7
  call   <malloc@plt>
L7:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *create_state(const int type) {
  size_t statesize;
  statesize = state_size(type);
  if (statesize)
    return malloc(statesize);
  else
    return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<create_state>:
  endbr64
  sub    $0x8,%rsp
  call   <state_size@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <malloc@plt>
  xchg   %ax,%ax
L8:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *create_state(const int type) {
  size_t statesize;
  statesize = state_size(type);
  if (statesize)
    return malloc(statesize);
  else
    return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<create_state>:
  endbr64
  sub    $0x8,%rsp
  call   <state_size@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <malloc@plt>
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *create_state(const int type) {
  size_t statesize;
  statesize = state_size(type);
  if (statesize)
    return malloc(statesize);
  else
    return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L63
L54:
  movl   $0x0,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L34
L69:
  addl   $0x1,-0x18(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jge    L22
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x64,%eax
  mov    %eax,-0x24(%rbp)
L22:
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L89
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L34
L89:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L34
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L34
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L34:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jge    L81
  mov    -0x28(%rbp),%eax
  test   %eax,%eax
  jle    L61
L81:
  cmpl   $0x270f,-0x18(%rbp)
  jle    L69
L61:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L63:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L54
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L87
  call   <__stack_chk_fail@plt>
L87:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D26
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D10
type_infered: string

tool: D26: %d

tool: D12: %d %d %d

tool: D10: 
%d

assistant: ```c
int main() {
  int t, A, B, C, tcents, it, i, max, temp, maxa, maxb;
  scanf("%d", &t);
  while (t--) {
    i = it = 0;
    scanf("%d %d %d", &A, &B, &C);
    maxa = A;
    maxb = B;
    while ((B >= C || A > 0) && i < 10000) {
      i++;
      if (B < C) {
        A--;
        B = B + 100;
      }
      B -= C;
      temp = B;
      B = A;
      A = temp;
      if (A > maxa) {
        maxa = A;
        it = i;
      } else if (maxa == A && B > maxb) {
        it = i;
        maxb = B;
      }
    }
    printf("\n%d", it);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L119
  lea    D18(%rip),%r12
  mov    $0x1,%ebx
  lea    D2(%rip),%rbp
  jmp    L43
L71:
  mov    %eax,%r8d
  mov    %r9d,%r10d
L64:
  add    $0x1,%edx
  mov    %ebx,%edi
  mov    %ebx,%r9d
L175:
  cmp    %ecx,%esi
  jle    L140
  test   %eax,%eax
  jle    L139
  cmp    $0x270f,%edx
  jg     L137
  lea    0x1(%rdx),%r9d
  lea    0x64(%rcx),%edi
  lea    -0x1(%rax),%ecx
L129:
  mov    %edi,%eax
  sub    %esi,%eax
  cmp    %r8d,%eax
  jg     L71
  cmp    %ecx,%r11d
  jge    L64
  cmp    %r8d,%eax
  cmove  %ecx,%r11d
  cmove  %r9d,%r10d
  jmp    L64
L139:
  test   %dil,%dil
  je     L105
  mov    %eax,0xc(%rsp)
L105:
  test   %r9b,%r9b
  je     L188
  mov    %ecx,0x10(%rsp)
L188:
  mov    %r10d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L119
L43:
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    0x10(%rsp),%r11d
  mov    0x14(%rsp),%esi
  mov    %r8d,%eax
  mov    %r11d,%ecx
  mov    $0x0,%edx
  mov    $0x0,%edi
  mov    $0x0,%r9d
  mov    $0x0,%r10d
  jmp    L175
L119:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L137:
  test   %dil,%dil
  je     L117
  mov    %eax,0xc(%rsp)
L117:
  test   %r9b,%r9b
  je     L188
  mov    %ecx,0x10(%rsp)
  jmp    L188
L140:
  cmp    $0x270f,%edx
  jg     L79
  lea    0x1(%rdx),%r9d
  mov    %ecx,%edi
  mov    %eax,%ecx
  jmp    L129
L79:
  test   %dil,%dil
  je     L177
  mov    %eax,0xc(%rsp)
L177:
  test   %r9b,%r9b
  je     L188
  mov    %ecx,0x10(%rsp)
  jmp    L188
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D18
type: string
name: disassemble_data
arguments: label: D2
type: string

tool: D3: %d

tool: D18: %d %d %d

tool: D2: 
%d

assistant: ```c
int main() {
  int t, A, B, C, tcents, it, i, max, temp, maxa, maxb;
  scanf("%d", &t);
  while (t--) {
    i = it = 0;
    scanf("%d %d %d", &A, &B, &C);
    maxa = A;
    maxb = B;
    while ((B >= C || A > 0) && i < 10000) {
      i++;
      if (B < C) {
        A--;
        B = B + 100;
      }
      B -= C;
      temp = B;
      B = A;
      A = temp;
      if (A > maxa) {
        maxa = A;
        it = i;
      } else if (maxa == A && B > maxb) {
        it = i;
        maxb = B;
      }
    }
    printf("\n%d", it);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  lea    D3(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L117
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D27(%rip),%rbp
  lea    D10(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L133:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  xor    %ecx,%ecx
  mov    0x14(%rsp),%r8d
  mov    $0x1,%esi
  xor    %edi,%edi
  xor    %r11d,%r11d
  mov    %edx,%r15d
  mov    %eax,%r10d
  jmp    L52
  nopl   0x0(%rax)
L86:
  cmp    $0x2710,%ecx
  je     L90
  test   %eax,%eax
  jle    L90
  lea    0x64(%rdx),%r9d
  lea    -0x1(%rax),%edx
  mov    %esi,%edi
  mov    %r9d,%eax
  sub    %r8d,%eax
  cmp    %r10d,%eax
  jg     L71
L29:
  jne    L18
  cmp    %edx,%r15d
  jge    L18
  mov    %edx,%r15d
L4:
  mov    %edi,%r11d
  add    $0x1,%ecx
  add    $0x1,%esi
  mov    $0x1,%edi
L52:
  cmp    %edx,%r8d
  jg     L86
  cmp    $0x2710,%ecx
  je     L90
  mov    %edx,%r9d
  mov    %eax,%edx
  mov    %esi,%edi
  mov    %r9d,%eax
  sub    %r8d,%eax
  cmp    %r10d,%eax
  jle    L29
L71:
  mov    %eax,%r10d
  jmp    L4
  nopl   0x0(%rax)
L18:
  mov    %r11d,%edi
  jmp    L4
  nopl   (%rax)
L90:
  test   %dil,%dil
  je     L138
  mov    %eax,0xc(%rsp)
  mov    %edx,0x10(%rsp)
L138:
  mov    %r11d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L133
L117:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string
name: extract_symbolic_data
arguments: label: D27
data_type: string
name: extract_symbolic_data
arguments: label: D10
data_type: string

tool: D3: %d

tool: D27: %d %d %d

tool: D10: 
%d

assistant: ```c
int main() {
  int t, A, B, C, tcents, it, i, max, temp, maxa, maxb;
  scanf("%d", &t);
  while (t--) {
    i = it = 0;
    scanf("%d %d %d", &A, &B, &C);
    maxa = A;
    maxb = B;
    while ((B >= C || A > 0) && i < 10000) {
      i++;
      if (B < C) {
        A--;
        B = B + 100;
      }
      B -= C;
      temp = B;
      B = A;
      A = temp;
      if (A > maxa) {
        maxa = A;
        it = i;
      } else if (maxa == A && B > maxb) {
        it = i;
        maxb = B;
      }
    }
    printf("\n%d", it);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D1(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L78
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D15(%rip),%rbp
  lea    D5(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L138:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  xor    %ecx,%ecx
  mov    0x14(%rsp),%r8d
  mov    $0x1,%esi
  xor    %edi,%edi
  xor    %r11d,%r11d
  mov    %edx,%r15d
  mov    %eax,%r10d
  jmp    L109
  nopl   0x0(%rax)
L43:
  cmp    $0x2710,%ecx
  je     L80
  test   %eax,%eax
  jle    L80
  lea    0x64(%rdx),%r9d
  lea    -0x1(%rax),%edx
  mov    %esi,%edi
  mov    %r9d,%eax
  sub    %r8d,%eax
  cmp    %r10d,%eax
  jg     L88
L144:
  jne    L64
  cmp    %edx,%r15d
  jge    L64
  mov    %edx,%r15d
L95:
  mov    %edi,%r11d
  add    $0x1,%ecx
  add    $0x1,%esi
  mov    $0x1,%edi
L109:
  cmp    %edx,%r8d
  jg     L43
  cmp    $0x2710,%ecx
  je     L80
  mov    %edx,%r9d
  mov    %eax,%edx
  mov    %esi,%edi
  mov    %r9d,%eax
  sub    %r8d,%eax
  cmp    %r10d,%eax
  jle    L144
L88:
  mov    %eax,%r10d
  jmp    L95
  nopl   0x0(%rax)
L64:
  mov    %r11d,%edi
  jmp    L95
  nopl   (%rax)
L80:
  test   %dil,%dil
  je     L140
  mov    %eax,0xc(%rsp)
  mov    %edx,0x10(%rsp)
L140:
  mov    %r11d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L138
L78:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
datatype: string
name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D5
datatype: string

tool: D1: %d

tool: D15: %d %d %d

tool: D5: 
%d

assistant: ```c
int main() {
  int t, A, B, C, tcents, it, i, max, temp, maxa, maxb;
  scanf("%d", &t);
  while (t--) {
    i = it = 0;
    scanf("%d %d %d", &A, &B, &C);
    maxa = A;
    maxb = B;
    while ((B >= C || A > 0) && i < 10000) {
      i++;
      if (B < C) {
        A--;
        B = B + 100;
      }
      B -= C;
      temp = B;
      B = A;
      A = temp;
      if (A > maxa) {
        maxa = A;
        it = i;
      } else if (maxa == A && B > maxb) {
        it = i;
        maxb = B;
      }
    }
    printf("\n%d", it);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  lea    D0(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *foo2(unsigned long x) {
  (void)x;
  static int bar = 0xbee;
  return &bar;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo2>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

assistant: ```c
void *foo2(unsigned long x) {
  (void)x;
  static int bar = 0xbee;
  return &bar;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo2>:
  endbr64
  lea    D5(%rip),%rax
  ret
```

assistant: ```c
void *foo2(unsigned long x) {
  (void)x;
  static int bar = 0xbee;
  return &bar;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo2>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

assistant: ```c
void *foo2(unsigned long x) {
  (void)x;
  static int bar = 0xbee;
  return &bar;
}
```