user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%r13
  cmp    $0x1,%r13d
  jle    L146
  lea    0x10(%rsp),%r12
  xor    %ebx,%ebx
  nop
L190:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  movslq 0x8(%rsp),%r13
  lea    -0x1(%r13),%eax
  cmp    %ebx,%eax
  jg     L190
L146:
  test   %r13d,%r13d
  jle    L182
  movslq %r13d,%rdx
  lea    0x60(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L182:
  movslq 0xc(%rsp),%r9
  cmp    %r13d,%r9d
  jl     L72
  lea    -0x1(%r13),%esi
  lea    0x60(%rsp,%r13,4),%rcx
  xor    %edi,%edi
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L183:
  lea    0x1(%rsi),%r10d
  mov    %r10d,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%eax
  cmp    $0x2,%eax
  jbe    L21
  movdqu -0x10(%rcx),%xmm2
  mov    %r8d,%eax
  shr    $0x2,%eax
  pshufd $0x1b,%xmm2,%xmm0
  cmp    $0x1,%eax
  je     L37
  movdqu -0x20(%rcx),%xmm3
  pshufd $0x1b,%xmm3,%xmm1
  paddd  %xmm1,%xmm0
  cmp    $0x2,%eax
  je     L37
  movdqu -0x30(%rcx),%xmm4
  pshufd $0x1b,%xmm4,%xmm1
  paddd  %xmm1,%xmm0
  cmp    $0x3,%eax
  je     L37
  movdqu -0x40(%rcx),%xmm5
  pshufd $0x1b,%xmm5,%xmm1
  paddd  %xmm1,%xmm0
  cmp    $0x4,%eax
  je     L37
  movdqu -0x50(%rcx),%xmm6
  pshufd $0x1b,%xmm6,%xmm1
  paddd  %xmm1,%xmm0
  cmp    $0x5,%eax
  je     L37
  movdqu -0x60(%rcx),%xmm7
  pshufd $0x1b,%xmm7,%xmm1
  paddd  %xmm1,%xmm0
  cmp    $0x6,%eax
  je     L37
  movdqu -0x70(%rcx),%xmm7
  pshufd $0x1b,%xmm7,%xmm1
  paddd  %xmm1,%xmm0
L37:
  movdqa %xmm0,%xmm1
  mov    %r8d,%r11d
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%r11d
  paddd  %xmm1,%xmm0
  sub    %r11d,%edx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %r11d,%r8d
  je     L117
L9:
  movslq %edx,%rsi
  add    0x60(%rsp,%rsi,4),%eax
  lea    -0x1(%rdx),%esi
  cmp    %edi,%esi
  jl     L117
  movslq %esi,%rsi
  sub    $0x2,%edx
  add    0x60(%rsp,%rsi,4),%eax
  cmp    %edi,%edx
  jl     L117
  movslq %edx,%rdx
  add    0x60(%rsp,%rdx,4),%eax
L117:
  mov    %eax,(%rcx)
  add    $0x1,%edi
  mov    %r10d,%esi
  add    $0x4,%rcx
  cmp    %r9d,%r10d
  je     L72
L86:
  mov    %esi,%edx
  cmp    %edi,%esi
  jge    L183
  xor    %eax,%eax
  lea    0x1(%rsi),%r10d
  jmp    L117
  xchg   %ax,%ax
L72:
  mov    0x60(%rsp,%r9,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  xor    %eax,%eax
  jmp    L9
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string
name: parse_data
arguments: tag: D13
data_type: string
name: parse_data
arguments: tag: D1
data_type: string

tool: D8: %d 

tool: D13: %d

tool: D1: %d


assistant: ```c
int main() {
  int d;
  scanf("%d ", &d);
  int N;
  scanf("%d\n", &N);
  int i;
  int b[20];
  for (i = 0; i < d - 1; i = i + 1)
    scanf("%d", &b[i]);
  int a[30];
  for (i = 0; i >= 0 && i < d; i = i + 1) {
    a[i] = b[i];
  }
  for (i = d; i <= N; i = i + 1) {
    int sum;
    sum = 0;
    int c;
    c = i - d;
    int j;
    for (j = i - 1; j >= c; j--)
      sum = sum + a[j];
    a[i] = sum;
  }
  printf("%d", a[N]);
  return 0;
}
```