ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<matrix_add_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L3:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x2c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrix_add_float(const float *a, const float *b, float *c, const unsigned int dimX, const unsigned int dimY) {
  for (unsigned int i = 0; i < dimX * dimY; i++) {
    c[i] = a[i] + b[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<matrix_add_float>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  je     L3
  mov    %ecx,%ecx
  mov    $0x0,%eax
L6:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
L3:
  ret
```

assistant: ```c
void matrix_add_float(const float *a, const float *b, float *c, const unsigned int dimX, const unsigned int dimY) {
  for (unsigned int i = 0; i < dimX * dimY; i++) {
    c[i] = a[i] + b[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<matrix_add_float>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  je     L5
  xor    %eax,%eax
  xchg   %ax,%ax
L0:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L0
L5:
  ret
```

assistant: ```c
void matrix_add_float(const float *a, const float *b, float *c, const unsigned int dimX, const unsigned int dimY) {
  for (unsigned int i = 0; i < dimX * dimY; i++) {
    c[i] = a[i] + b[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matrix_add_float>:
  endbr64
  imul   %ecx,%r8d
  test   %r8d,%r8d
  je     L20
  lea    0x4(%rdi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  seta   %cl
  cmp    $0x1,%r8d
  setne  %al
  test   %al,%cl
  je     L82
  lea    0x4(%rsi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L82
  lea    -0x1(%r8),%eax
  cmp    $0x2,%eax
  jbe    L21
  mov    %r8d,%ecx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L99:
  movups (%rdi,%rax,1),%xmm0
  movups (%rsi,%rax,1),%xmm2
  addps  %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L99
  mov    %r8d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r8b
  je     L20
  sub    %eax,%r8d
  cmp    $0x1,%r8d
  je     L62
L74:
  mov    %eax,%ecx
  movq   (%rdi,%rcx,4),%xmm0
  movq   (%rsi,%rcx,4),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rdx,%rcx,4)
  mov    %r8d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r8d
  je     L20
L62:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  ret
  nopl   (%rax)
L82:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L64:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L64
L20:
  ret
L21:
  xor    %eax,%eax
  jmp    L74
```

assistant: ```c
void matrix_add_float(const float *a, const float *b, float *c, const unsigned int dimX, const unsigned int dimY) {
  for (unsigned int i = 0; i < dimX * dimY; i++) {
    c[i] = a[i] + b[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getGroup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  jne    L43
  mov    $0x2,%eax
  jmp    L3
L43:
  cmpl   $0x8,-0x4(%rbp)
  jne    L22
  mov    $0x3,%eax
  jmp    L3
L22:
  cmpl   $0x10,-0x4(%rbp)
  jne    L36
  mov    $0x4,%eax
  jmp    L3
L36:
  mov    $0x1,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int getGroup(int base2) {
  if (base2 == 4) {
    return 2;
  } else if (base2 == 8) {
    return 3;
  } else if (base2 == 16) {
    return 4;
  } else {
    return 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getGroup>:
  endbr64
  cmp    $0x4,%edi
  je     L2
  cmp    $0x8,%edi
  je     L4
  cmp    $0x10,%edi
  sete   %al
  movzbl %al,%eax
  lea    0x1(%rax,%rax,2),%eax
  ret
L2:
  mov    $0x2,%eax
  ret
L4:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int getGroup(int base2) {
  if (base2 == 4) {
    return 2;
  } else if (base2 == 8) {
    return 3;
  } else if (base2 == 16) {
    return 4;
  } else {
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getGroup>:
  endbr64
  cmp    $0x4,%edi
  je     L10
  cmp    $0x8,%edi
  je     L17
  xor    %eax,%eax
  cmp    $0x10,%edi
  sete   %al
  lea    0x1(%rax,%rax,2),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x2,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int getGroup(int base2) {
  if (base2 == 4) {
    return 2;
  } else if (base2 == 8) {
    return 3;
  } else if (base2 == 16) {
    return 4;
  } else {
    return 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getGroup>:
  endbr64
  cmp    $0x4,%edi
  je     L13
  cmp    $0x8,%edi
  je     L19
  xor    %eax,%eax
  cmp    $0x10,%edi
  sete   %al
  lea    0x1(%rax,%rax,2),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0x2,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int getGroup(int base2) {
  if (base2 == 4) {
    return 2;
  } else if (base2 == 8) {
    return 3;
  } else if (base2 == 16) {
    return 4;
  } else {
    return 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<val2id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <StrDup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <itos@plt>
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <val_exist@plt>
  test   %eax,%eax
  jne    L10
  mov    -0x1c(%rbp),%eax
  jmp    L3
L10:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int val2id(char *valist, int num, char *delm) {
  char *id;
  int i;
  id = StrDup(valist);
  if (!val_exist(id, itos(num), delm))
    return num;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<val2id>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%r12
  call   <StrDup@plt>
  mov    %rax,%rbp
  mov    %ebx,%edi
  call   <itos@plt>
  mov    %eax,%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <val_exist@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int val2id(char *valist, int num, char *delm) {
  char *id;
  int i;
  id = StrDup(valist);
  if (!val_exist(id, itos(num), delm))
    return num;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<val2id>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  call   <StrDup@plt>
  mov    %r12d,%edi
  mov    %rax,%rbp
  call   <itos@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <val_exist@plt>
  pop    %rbp
  test   %eax,%eax
  mov    $0x0,%eax
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int val2id(char *valist, int num, char *delm) {
  char *id;
  int i;
  id = StrDup(valist);
  if (!val_exist(id, itos(num), delm))
    return num;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<val2id>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  call   <StrDup@plt>
  mov    %r12d,%edi
  mov    %rax,%rbp
  call   <itos@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <val_exist@plt>
  pop    %rbp
  test   %eax,%eax
  mov    $0x0,%eax
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int val2id(char *valist, int num, char *delm) {
  char *id;
  int i;
  id = StrDup(valist);
  if (!val_exist(id, itos(num), delm))
    return num;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_1st_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <get_field_pos@plt>
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L20
  mov    -0x38(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
L20:
  cmpl   $0x0,-0xc(%rbp)
  je     L30
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L22
L30:
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
char *get_1st_field(char *str, int len, const char *prejumpset, const char *delemiters, int *field_len) {
  int subpos = 0;
  int sublen = get_field_pos(str, len, prejumpset, delemiters, &subpos);
  if (field_len) {
    *field_len = sublen;
  }
  return sublen ? &str[subpos] : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_1st_field>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %r8,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%r8
  call   <get_field_pos@plt>
  test   %rbp,%rbp
  je     L14
  mov    %eax,0x0(%rbp)
L14:
  mov    $0x0,%edx
  test   %eax,%eax
  je     L9
  movslq 0x4(%rsp),%rdx
  add    %rbx,%rdx
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    %rdx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_1st_field(char *str, int len, const char *prejumpset, const char *delemiters, int *field_len) {
  int subpos = 0;
  int sublen = get_field_pos(str, len, prejumpset, delemiters, &subpos);
  if (field_len) {
    *field_len = sublen;
  }
  return sublen ? &str[subpos] : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_1st_field>:
  endbr64
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r8
  movl   $0x0,0x4(%rsp)
  call   <get_field_pos@plt>
  test   %rbp,%rbp
  je     L6
  mov    %eax,0x0(%rbp)
L6:
  xor    %r8d,%r8d
  test   %eax,%eax
  je     L9
  movslq 0x4(%rsp),%r8
  add    %rbx,%r8
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_1st_field(char *str, int len, const char *prejumpset, const char *delemiters, int *field_len) {
  int subpos = 0;
  int sublen = get_field_pos(str, len, prejumpset, delemiters, &subpos);
  if (field_len) {
    *field_len = sublen;
  }
  return sublen ? &str[subpos] : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_1st_field>:
  endbr64
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r8
  movl   $0x0,0x4(%rsp)
  call   <get_field_pos@plt>
  test   %rbp,%rbp
  je     L15
  mov    %eax,0x0(%rbp)
L15:
  xor    %r8d,%r8d
  test   %eax,%eax
  je     L9
  movslq 0x4(%rsp),%r8
  add    %rbx,%r8
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_1st_field(char *str, int len, const char *prejumpset, const char *delemiters, int *field_len) {
  int subpos = 0;
  int sublen = get_field_pos(str, len, prejumpset, delemiters, &subpos);
  if (field_len) {
    *field_len = sublen;
  }
  return sublen ? &str[subpos] : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Mode_Decision_for_new_Intra8x8Macroblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D16(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L33:
  lea    -0x14(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rcx,%rsi
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <Mode_Decision_for_new_8x8IntraBlocks@plt>
  test   %rax,%rax
  je     L30
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x10(%rbp)
L30:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L11:
  cmpl   $0x3,-0xc(%rbp)
  jle    L33
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: f64
name: unpack_data
arguments: label: D16
type_infered: f64

tool: D1: 6

tool: D16: 0.4999

assistant: ```c
int Mode_Decision_for_new_Intra8x8Macroblock(double lambda, int *min_cost) {
  int cbp = 0, b8, cost8x8;
  *min_cost = (int)floor(6.0 * lambda + 0.4999);
  for (b8 = 0; b8 < 4; b8++) {
    if (Mode_Decision_for_new_8x8IntraBlocks(b8, lambda, &cost8x8)) {
      cbp |= (1 << b8);
    }
    *min_cost += cost8x8;
  }
  return cbp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Mode_Decision_for_new_Intra8x8Macroblock>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%r12
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mulsd  D3(%rip),%xmm0
  addsd  D7(%rip),%xmm0
  call   <floor@plt>
  mov    %eax,0x0(%rbp)
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  lea    0x4(%rsp),%r14
  jmp    L22
L9:
  mov    0x4(%rsp),%eax
  add    %eax,0x0(%rbp)
  add    $0x1,%ebx
  cmp    $0x4,%ebx
  je     L4
L22:
  mov    %r14,%rsi
  movq   %r12,%xmm0
  mov    %ebx,%edi
  call   <Mode_Decision_for_new_8x8IntraBlocks@plt>
  test   %rax,%rax
  je     L9
  mov    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  or     %eax,%r13d
  jmp    L9
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %r13d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: f64
name: disassemble_data
arguments: label: D7
type_guessed: f64

tool: D3: 6

tool: D7: 0.4999

assistant: ```c
int Mode_Decision_for_new_Intra8x8Macroblock(double lambda, int *min_cost) {
  int cbp = 0, b8, cost8x8;
  *min_cost = (int)floor(6.0 * lambda + 0.4999);
  for (b8 = 0; b8 < 4; b8++) {
    if (Mode_Decision_for_new_8x8IntraBlocks(b8, lambda, &cost8x8)) {
      cbp |= (1 << b8);
    }
    *min_cost += cost8x8;
  }
  return cbp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Mode_Decision_for_new_Intra8x8Macroblock>:
  endbr64
  push   %r15
  movq   %xmm0,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mulsd  D18(%rip),%xmm0
  lea    0x4(%rsp),%rbp
  addsd  D0(%rip),%xmm0
  call   <floor@plt>
  mov    %eax,(%r14)
L5:
  mov    %rbp,%rsi
  mov    %r13d,%edi
  movq   %r15,%xmm0
  call   <Mode_Decision_for_new_8x8IntraBlocks@plt>
  mov    %r13d,%ecx
  mov    %ebx,%esi
  mov    %r12d,%edx
  shl    %cl,%esi
  or     %esi,%r12d
  test   %rax,%rax
  mov    0x4(%rsp),%eax
  cmove  %edx,%r12d
  add    $0x1,%r13d
  add    %eax,(%r14)
  cmp    $0x4,%r13d
  jne    L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
type_infered: f64
name: disassemble_data
arguments: label: D0
type_infered: f64

tool: D18: 6

tool: D0: 0.4999

assistant: ```c
int Mode_Decision_for_new_Intra8x8Macroblock(double lambda, int *min_cost) {
  int cbp = 0, b8, cost8x8;
  *min_cost = (int)floor(6.0 * lambda + 0.4999);
  for (b8 = 0; b8 < 4; b8++) {
    if (Mode_Decision_for_new_8x8IntraBlocks(b8, lambda, &cost8x8)) {
      cbp |= (1 << b8);
    }
    *min_cost += cost8x8;
  }
  return cbp;
}
```
user: What is the c source code of the assembly code below?

```asm
<Mode_Decision_for_new_Intra8x8Macroblock>:
  endbr64
  push   %r15
  movq   %xmm0,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mulsd  D9(%rip),%xmm0
  lea    0x4(%rsp),%rbp
  addsd  D11(%rip),%xmm0
  call   <floor@plt>
  mov    %eax,(%r14)
L13:
  mov    %rbp,%rsi
  mov    %r13d,%edi
  movq   %r15,%xmm0
  call   <Mode_Decision_for_new_8x8IntraBlocks@plt>
  mov    %r13d,%ecx
  mov    %ebx,%esi
  mov    %r12d,%edx
  shl    %cl,%esi
  or     %esi,%r12d
  test   %rax,%rax
  mov    0x4(%rsp),%eax
  cmove  %edx,%r12d
  add    $0x1,%r13d
  add    %eax,(%r14)
  cmp    $0x4,%r13d
  jne    L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: f64
name: unpack_data
arguments: data_tag: D11
type: f64

tool: D9: 6

tool: D11: 0.4999

assistant: ```c
int Mode_Decision_for_new_Intra8x8Macroblock(double lambda, int *min_cost) {
  int cbp = 0, b8, cost8x8;
  *min_cost = (int)floor(6.0 * lambda + 0.4999);
  for (b8 = 0; b8 < 4; b8++) {
    if (Mode_Decision_for_new_8x8IntraBlocks(b8, lambda, &cost8x8)) {
      cbp |= (1 << b8);
    }
    *min_cost += cost8x8;
  }
  return cbp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <BCLMarkFunc@plt>
  mov    $0x0,%eax
  call   <initRaspberryConnections@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D2
type_infered: string

tool: D12: init

tool: D2: init

assistant: ```c
int init() {
  BCLMarkFunc(__PRETTY_FUNCTION__, __FUNCTION__);
  initRaspberryConnections();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <BCLMarkFunc@plt>
  mov    $0x0,%eax
  call   <initRaspberryConnections@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D12: init

tool: D7: init

assistant: ```c
int init() {
  BCLMarkFunc(__PRETTY_FUNCTION__, __FUNCTION__);
  initRaspberryConnections();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <BCLMarkFunc@plt>
  xor    %eax,%eax
  call   <initRaspberryConnections@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string
name: parse_data
arguments: data_label: D19
datatype: string

tool: D7: init

tool: D19: init

assistant: ```c
int init() {
  BCLMarkFunc(__PRETTY_FUNCTION__, __FUNCTION__);
  initRaspberryConnections();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <BCLMarkFunc@plt>
  xor    %eax,%eax
  call   <initRaspberryConnections@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string
name: unpack_data
arguments: label: D15
type_infered: string

tool: D5: init

tool: D15: init

assistant: ```c
int init() {
  BCLMarkFunc(__PRETTY_FUNCTION__, __FUNCTION__);
  initRaspberryConnections();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x2,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x4,-0x40(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x40(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x40(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x3c(%rbp),%edx
  lea    -0x20(%rbp),%rsi
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <multiply@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <disp@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int m1[] = {1, 1, 0, 1};
  int m2[] = {2, 2, 0, 2};
  int tot = sizeof(m1) / sizeof(int);
  int sz = (int)sqrt((double)tot);
  int *ret = malloc(tot * sizeof(int));
  multiply(m1, m2, sz, ret);
  disp(ret, sz);
  free(ret);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movsd  D5(%rip),%xmm0
  call   <sqrt@plt>
  mov    %eax,%ebp
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %rax,%rcx
  mov    %ebp,%edx
  call   <multiply@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <disp@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

assistant: ```c
int main(int argc, char *argv[]) {
  int m1[] = {1, 1, 0, 1};
  int m2[] = {2, 2, 0, 2};
  int tot = sizeof(m1) / sizeof(int);
  int sz = (int)sqrt((double)tot);
  int *ret = malloc(tot * sizeof(int));
  multiply(m1, m2, sz, ret);
  disp(ret, sz);
  free(ret);
  return 0;
}
```