ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<paw_bound_state_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    $0x0,%eax
  call   <paw_N_LogGrid@plt>
  mov    %eax,-0x24(%rbp)
  mov    $0x0,%eax
  call   <paw_r_LogGrid@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  imul   -0x34(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L46
L8:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x10(%rbp),%xmm2
  movsd  D7(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  divsd  -0x8(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L44
  movsd  -0x20(%rbp),%xmm0
  jmp    L56
L44:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x10(%rbp),%xmm2
  movsd  D7(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  divsd  -0x8(%rbp),%xmm0
  addsd  %xmm1,%xmm0
L56:
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x28(%rbp)
L46:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  movsd  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L57
  mov    $0x0,%eax
  jmp    L23
L57:
  mov    $0x1,%eax
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: f64

tool: D7: 0.5

assistant: ```c
int paw_bound_state_test(int l, double *v) {
  int i;
  int Ngrid;
  double L2, r2;
  double Emin;
  double *r;
  Ngrid = paw_N_LogGrid();
  r = (double *)paw_r_LogGrid();
  L2 = ((double)(l * (l + 1)));
  Emin = 0;
  for (i = 0; i < Ngrid; ++i) {
    r2 = r[i];
    r2 = r2 * r2;
    Emin = ((Emin < (v[i] + 0.5 * L2 / r2)) ? Emin : (v[i] + 0.5 * L2 / r2));
  }
  if (Emin >= 0) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<paw_bound_state_test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <paw_N_LogGrid@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <paw_r_LogGrid@plt>
  lea    0x1(%r12),%edx
  imul   %r12d,%edx
  test   %ebp,%ebp
  jle    L13
  pxor   %xmm3,%xmm3
  cvtsi2sd %edx,%xmm3
  mulsd  D17(%rip),%xmm3
  lea    -0x1(%rbp),%edx
  lea    0x8(%rax,%rdx,8),%rsi
  mov    %rax,%rdx
  pxor   %xmm2,%xmm2
  sub    %rax,%rbx
  mov    %rbx,%rcx
L10:
  movsd  (%rdx),%xmm0
  mulsd  %xmm0,%xmm0
  movapd %xmm3,%xmm1
  divsd  %xmm0,%xmm1
  addsd  (%rcx,%rdx,1),%xmm1
  minsd  %xmm1,%xmm2
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L10
L2:
  comisd D18(%rip),%xmm2
  setb   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  pxor   %xmm2,%xmm2
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: tag: D17
type_infered: f64
name: disassemble_data
arguments: tag: D18
type_infered: byte[16]

tool: D17: 0.5

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int paw_bound_state_test(int l, double *v) {
  int i;
  int Ngrid;
  double L2, r2;
  double Emin;
  double *r;
  Ngrid = paw_N_LogGrid();
  r = (double *)paw_r_LogGrid();
  L2 = ((double)(l * (l + 1)));
  Emin = 0;
  for (i = 0; i < Ngrid; ++i) {
    r2 = r[i];
    r2 = r2 * r2;
    Emin = ((Emin < (v[i] + 0.5 * L2 / r2)) ? Emin : (v[i] + 0.5 * L2 / r2));
  }
  if (Emin >= 0) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<paw_bound_state_test>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <paw_N_LogGrid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <paw_r_LogGrid@plt>
  lea    0x1(%rbp),%edx
  imul   %ebp,%edx
  test   %r12d,%r12d
  jle    L5
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  sub    %rax,%rbx
  cvtsi2sd %edx,%xmm3
  mulsd  D8(%rip),%xmm3
  lea    -0x1(%r12),%edx
  lea    0x8(%rax,%rdx,8),%rcx
  movapd %xmm4,%xmm2
  mov    %rbx,%rdx
  nopl   0x0(%rax)
L15:
  movsd  (%rax),%xmm0
  movapd %xmm3,%xmm1
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  addsd  (%rdx,%rax,1),%xmm1
  add    $0x8,%rax
  minsd  %xmm1,%xmm2
  cmp    %rax,%rcx
  jne    L15
  xor    %eax,%eax
  comisd %xmm4,%xmm2
  pop    %rbx
  pop    %rbp
  pop    %r12
  setb   %al
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: f64

tool: D8: 0.5

assistant: ```c
int paw_bound_state_test(int l, double *v) {
  int i;
  int Ngrid;
  double L2, r2;
  double Emin;
  double *r;
  Ngrid = paw_N_LogGrid();
  r = (double *)paw_r_LogGrid();
  L2 = ((double)(l * (l + 1)));
  Emin = 0;
  for (i = 0; i < Ngrid; ++i) {
    r2 = r[i];
    r2 = r2 * r2;
    Emin = ((Emin < (v[i] + 0.5 * L2 / r2)) ? Emin : (v[i] + 0.5 * L2 / r2));
  }
  if (Emin >= 0) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<paw_bound_state_test>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <paw_N_LogGrid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <paw_r_LogGrid@plt>
  lea    0x1(%rbp),%edx
  imul   %ebp,%edx
  test   %r12d,%r12d
  jle    L10
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  sub    %rax,%rbx
  cvtsi2sd %edx,%xmm3
  mulsd  D7(%rip),%xmm3
  lea    -0x1(%r12),%edx
  lea    0x8(%rax,%rdx,8),%rcx
  movapd %xmm4,%xmm2
  mov    %rbx,%rdx
  nopl   0x0(%rax)
L4:
  movsd  (%rax),%xmm0
  movapd %xmm3,%xmm1
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  addsd  (%rdx,%rax,1),%xmm1
  add    $0x8,%rax
  minsd  %xmm1,%xmm2
  cmp    %rax,%rcx
  jne    L4
  xor    %eax,%eax
  comisd %xmm4,%xmm2
  pop    %rbx
  pop    %rbp
  pop    %r12
  setb   %al
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: f64

tool: D7: 0.5

assistant: ```c
int paw_bound_state_test(int l, double *v) {
  int i;
  int Ngrid;
  double L2, r2;
  double Emin;
  double *r;
  Ngrid = paw_N_LogGrid();
  r = (double *)paw_r_LogGrid();
  L2 = ((double)(l * (l + 1)));
  Emin = 0;
  for (i = 0; i < Ngrid; ++i) {
    r2 = r[i];
    r2 = r2 * r2;
    Emin = ((Emin < (v[i] + 0.5 * L2 / r2)) ? Emin : (v[i] + 0.5 * L2 / r2));
  }
  if (Emin >= 0) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strjoin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L1
L12:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_strcat@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, char const *s2) {
  char *tab;
  if ((tab = (char *)malloc(sizeof(tab) * (ft_strlen(s1) + ft_strlen(s2) + 1))) == NULL)
    return (NULL);
  ft_strcpy(tab, s1);
  ft_strcat(tab, s2);
  free((void *)s1);
  return (tab);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strjoin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <ft_strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <ft_strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    $0x0,%r13d
  test   %rax,%rax
  je     L8
  mov    %rax,%rbx
  mov    %rax,%r13
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <ft_strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L8:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, char const *s2) {
  char *tab;
  if ((tab = (char *)malloc(sizeof(tab) * (ft_strlen(s1) + ft_strlen(s2) + 1))) == NULL)
    return (NULL);
  ft_strcpy(tab, s1);
  ft_strcat(tab, s2);
  free((void *)s1);
  return (tab);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_strjoin>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <ft_strlen@plt>
  lea    0x1(%r13,%rax,1),%edi
  xor    %r13d,%r13d
  shl    $0x3,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%r13
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  mov    %r13,%rdi
  mov    %r12,%rsi
  call   <ft_strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L3:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, char const *s2) {
  char *tab;
  if ((tab = (char *)malloc(sizeof(tab) * (ft_strlen(s1) + ft_strlen(s2) + 1))) == NULL)
    return (NULL);
  ft_strcpy(tab, s1);
  ft_strcat(tab, s2);
  free((void *)s1);
  return (tab);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strjoin>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ft_strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <ft_strlen@plt>
  lea    0x1(%r13,%rax,1),%edi
  xor    %r13d,%r13d
  shl    $0x3,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%r13
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  mov    %r13,%rdi
  mov    %r12,%rsi
  call   <ft_strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L4:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strjoin(char const *s1, char const *s2) {
  char *tab;
  if ((tab = (char *)malloc(sizeof(tab) * (ft_strlen(s1) + ft_strlen(s2) + 1))) == NULL)
    return (NULL);
  ft_strcpy(tab, s1);
  ft_strcat(tab, s2);
  free((void *)s1);
  return (tab);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movl   $0x55,-0x14(%rbp)
  movl   $0x33,-0x10(%rbp)
  movl   $0xf,-0xc(%rbp)
  movl   $0xff00ff,-0x8(%rbp)
  movl   $0xffff,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x10,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x8,%eax
  add    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x10,%eax
  add    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x8,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x10,%eax
  add    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sar    %eax
  and    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sar    $0x2,%eax
  and    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sar    $0x4,%eax
  and    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sar    $0x8,%eax
  and    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sar    $0x10,%eax
  and    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitCount(int x) {
  int mask_1 = 0x55;
  int mask_2 = 0x33;
  int mask_3 = 0x0f;
  int mask_4 = 0xff + (0xff << 16);
  int mask_5 = 0xff + (0xff << 8);
  mask_1 = mask_1 + (mask_1 << 8);
  mask_1 = mask_1 + (mask_1 << 16);
  mask_2 = mask_2 + (mask_2 << 8);
  mask_2 = mask_2 + (mask_2 << 16);
  mask_3 = mask_3 + (mask_3 << 8);
  mask_3 = mask_3 + (mask_3 << 16);
  x = (x & mask_1) + (x >> 1 & mask_1);
  x = (x & mask_2) + (x >> 2 & mask_2);
  x = (x & mask_3) + (x >> 4 & mask_3);
  x = (x & mask_4) + (x >> 8 & mask_4);
  x = (x & mask_5) + (x >> 16 & mask_5);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitCount>:
  endbr64
  mov    %edi,%eax
  and    $0x55555555,%eax
  sar    %edi
  and    $0x55555555,%edi
  add    %edi,%eax
  mov    %eax,%edx
  and    $0x33333333,%edx
  sar    $0x2,%eax
  and    $0x33333333,%eax
  add    %eax,%edx
  mov    %edx,%eax
  and    $0xf0f0f0f,%eax
  sar    $0x4,%edx
  and    $0xf0f0f0f,%edx
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xff00ff,%edx
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  add    %eax,%edx
  movzwl %dx,%eax
  shr    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int bitCount(int x) {
  int mask_1 = 0x55;
  int mask_2 = 0x33;
  int mask_3 = 0x0f;
  int mask_4 = 0xff + (0xff << 16);
  int mask_5 = 0xff + (0xff << 8);
  mask_1 = mask_1 + (mask_1 << 8);
  mask_1 = mask_1 + (mask_1 << 16);
  mask_2 = mask_2 + (mask_2 << 8);
  mask_2 = mask_2 + (mask_2 << 16);
  mask_3 = mask_3 + (mask_3 << 8);
  mask_3 = mask_3 + (mask_3 << 16);
  x = (x & mask_1) + (x >> 1 & mask_1);
  x = (x & mask_2) + (x >> 2 & mask_2);
  x = (x & mask_3) + (x >> 4 & mask_3);
  x = (x & mask_4) + (x >> 8 & mask_4);
  x = (x & mask_5) + (x >> 16 & mask_5);
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitCount>:
  endbr64
  mov    %edi,%eax
  sar    %edi
  and    $0x55555555,%eax
  and    $0x55555555,%edi
  add    %edi,%eax
  mov    %eax,%edx
  sar    $0x2,%eax
  and    $0x33333333,%eax
  and    $0x33333333,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x4,%edx
  and    $0xf0f0f0f,%edx
  and    $0xf0f0f0f,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  and    $0xff00ff,%edx
  add    %eax,%edx
  movzwl %dx,%eax
  sar    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int bitCount(int x) {
  int mask_1 = 0x55;
  int mask_2 = 0x33;
  int mask_3 = 0x0f;
  int mask_4 = 0xff + (0xff << 16);
  int mask_5 = 0xff + (0xff << 8);
  mask_1 = mask_1 + (mask_1 << 8);
  mask_1 = mask_1 + (mask_1 << 16);
  mask_2 = mask_2 + (mask_2 << 8);
  mask_2 = mask_2 + (mask_2 << 16);
  mask_3 = mask_3 + (mask_3 << 8);
  mask_3 = mask_3 + (mask_3 << 16);
  x = (x & mask_1) + (x >> 1 & mask_1);
  x = (x & mask_2) + (x >> 2 & mask_2);
  x = (x & mask_3) + (x >> 4 & mask_3);
  x = (x & mask_4) + (x >> 8 & mask_4);
  x = (x & mask_5) + (x >> 16 & mask_5);
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitCount>:
  endbr64
  mov    %edi,%eax
  sar    %edi
  and    $0x55555555,%eax
  and    $0x55555555,%edi
  add    %edi,%eax
  mov    %eax,%edx
  sar    $0x2,%eax
  and    $0x33333333,%eax
  and    $0x33333333,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x4,%edx
  and    $0xf0f0f0f,%edx
  and    $0xf0f0f0f,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  and    $0xff00ff,%edx
  add    %eax,%edx
  movzwl %dx,%eax
  sar    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int bitCount(int x) {
  int mask_1 = 0x55;
  int mask_2 = 0x33;
  int mask_3 = 0x0f;
  int mask_4 = 0xff + (0xff << 16);
  int mask_5 = 0xff + (0xff << 8);
  mask_1 = mask_1 + (mask_1 << 8);
  mask_1 = mask_1 + (mask_1 << 16);
  mask_2 = mask_2 + (mask_2 << 8);
  mask_2 = mask_2 + (mask_2 << 16);
  mask_3 = mask_3 + (mask_3 << 8);
  mask_3 = mask_3 + (mask_3 << 16);
  x = (x & mask_1) + (x >> 1 & mask_1);
  x = (x & mask_2) + (x >> 2 & mask_2);
  x = (x & mask_3) + (x >> 4 & mask_3);
  x = (x & mask_4) + (x >> 8 & mask_4);
  x = (x & mask_5) + (x >> 16 & mask_5);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binario_para_inteiro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movw   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x11,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L2
L32:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  addl   $0x1,-0x10(%rbp)
  shll   -0x14(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L32
  addl   $0x1,-0xc(%rbp)
L24:
  cmpl   $0x10,-0xc(%rbp)
  jle    L35
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void binario_para_inteiro(short *binarios, short *inteiros) {
  int start, n, i, j;
  int end = 0;
  for (j = 0; j < 1 * 17; j++) {
    inteiros[j] = 0;
    start = end;
    end += 17;
    n = 1;
    for (i = start; i < end; i++, n = n << 1) {
      inteiros[j] += binarios[i] * n;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binario_para_inteiro>:
  endbr64
  lea    0x22(%rdi),%r8
  mov    $0x0,%r9d
L1:
  mov    %rsi,%rcx
  movw   $0x0,(%rsi)
  add    $0x11,%r9d
  lea    -0x22(%r8),%rax
  mov    $0x1,%edx
L15:
  mov    %edx,%edi
  imul   (%rax),%di
  add    %di,(%rcx)
  add    %edx,%edx
  add    $0x2,%rax
  cmp    %r8,%rax
  jne    L15
  add    $0x2,%rsi
  add    $0x22,%r8
  cmp    $0x121,%r9d
  jne    L1
  ret
```

assistant: ```c
void binario_para_inteiro(short *binarios, short *inteiros) {
  int start, n, i, j;
  int end = 0;
  for (j = 0; j < 1 * 17; j++) {
    inteiros[j] = 0;
    start = end;
    end += 17;
    n = 1;
    for (i = start; i < end; i++, n = n << 1) {
      inteiros[j] += binarios[i] * n;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<binario_para_inteiro>:
  endbr64
  lea    0x22(%rdi),%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  add    $0x11,%r9d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %ax,(%rsi)
  lea    -0x22(%r8),%rax
  nopl   0x0(%rax)
L8:
  movzwl (%rax),%edi
  add    $0x2,%rax
  imul   %edx,%edi
  add    %edx,%edx
  add    %edi,%ecx
  mov    %cx,(%rsi)
  cmp    %rax,%r8
  jne    L8
  add    $0x2,%rsi
  add    $0x22,%r8
  cmp    $0x121,%r9d
  jne    L10
  ret
```

assistant: ```c
void binario_para_inteiro(short *binarios, short *inteiros) {
  int start, n, i, j;
  int end = 0;
  for (j = 0; j < 1 * 17; j++) {
    inteiros[j] = 0;
    start = end;
    end += 17;
    n = 1;
    for (i = start; i < end; i++, n = n << 1) {
      inteiros[j] += binarios[i] * n;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binario_para_inteiro>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdx
  lea    0x242(%rdi),%rdi
  nopl   0x0(%rax)
L2:
  xor    %ecx,%ecx
  add    $0x22,%rax
  add    $0x2,%rdx
  mov    %cx,-0x2(%rdx)
  movzwl -0x22(%rax),%ecx
  mov    %cx,-0x2(%rdx)
  movzwl -0x20(%rax),%esi
  lea    (%rcx,%rsi,2),%esi
  mov    %si,-0x2(%rdx)
  movzwl -0x1e(%rax),%ecx
  lea    (%rsi,%rcx,4),%ecx
  mov    %cx,-0x2(%rdx)
  movzwl -0x1c(%rax),%esi
  lea    (%rcx,%rsi,8),%esi
  mov    %si,-0x2(%rdx)
  movzwl -0x1a(%rax),%ecx
  shl    $0x4,%ecx
  add    %esi,%ecx
  mov    %cx,-0x2(%rdx)
  movzwl -0x18(%rax),%esi
  shl    $0x5,%esi
  add    %ecx,%esi
  mov    %si,-0x2(%rdx)
  movzwl -0x16(%rax),%ecx
  shl    $0x6,%ecx
  add    %esi,%ecx
  mov    %cx,-0x2(%rdx)
  movzwl -0x14(%rax),%esi
  shl    $0x7,%esi
  add    %ecx,%esi
  mov    %si,-0x2(%rdx)
  movzwl -0x12(%rax),%ecx
  shl    $0x8,%ecx
  add    %esi,%ecx
  mov    %cx,-0x2(%rdx)
  movzwl -0x10(%rax),%esi
  shl    $0x9,%esi
  add    %ecx,%esi
  mov    %si,-0x2(%rdx)
  movzwl -0xe(%rax),%ecx
  shl    $0xa,%ecx
  add    %esi,%ecx
  mov    %cx,-0x2(%rdx)
  movzwl -0xc(%rax),%esi
  shl    $0xb,%esi
  add    %ecx,%esi
  mov    %si,-0x2(%rdx)
  movzwl -0xa(%rax),%ecx
  shl    $0xc,%ecx
  add    %esi,%ecx
  mov    %cx,-0x2(%rdx)
  movzwl -0x8(%rax),%esi
  shl    $0xd,%esi
  add    %ecx,%esi
  mov    %si,-0x2(%rdx)
  movzwl -0x6(%rax),%ecx
  shl    $0xe,%ecx
  add    %esi,%ecx
  mov    %cx,-0x2(%rdx)
  movzwl -0x4(%rax),%esi
  shl    $0xf,%esi
  add    %esi,%ecx
  mov    %cx,-0x2(%rdx)
  cmp    %rdi,%rax
  jne    L2
  ret
```

assistant: ```c
void binario_para_inteiro(short *binarios, short *inteiros) {
  int start, n, i, j;
  int end = 0;
  for (j = 0; j < 1 * 17; j++) {
    inteiros[j] = 0;
    start = end;
    end += 17;
    n = 1;
    for (i = start; i < end; i++, n = n << 1) {
      inteiros[j] += binarios[i] * n;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<scanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfscanf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int scanf(const char *restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vfscanf(stdin, format, ap);
  va_end(ap);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scanf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <vfscanf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int scanf(const char *restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vfscanf(stdin, format, ap);
  va_end(ap);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int scanf(const char *restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vfscanf(stdin, format, ap);
  va_end(ap);
  return result;
}
```