ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<dtime>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm0
  mulsd  D0(%rip),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: byte[8]

tool: {"D0": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
void dtime(double *t) {
  struct timeval timev;
  gettimeofday(&timev, NULL);
  *t = timev.tv_sec + (double)timev.tv_usec * 1e-6;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dtime>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm0
  mulsd  D0(%rip),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: byte[8]

tool: {"D0": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
void dtime(double *t) {
  struct timeval timev;
  gettimeofday(&timev, NULL);
  *t = timev.tv_sec + (double)timev.tv_usec * 1e-6;
}
```
user: What is the c source code of the assembly code below?

```asm
<deinterleave>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xb3(%rbp)
  movb   $0x0,-0xb2(%rbp)
  jmp    L4
L11:
  movzbl -0xb2(%rbp),%eax
  mov    $0x80200802,%edx
  imul   %rdx,%rax
  movabs $0x884422110,%rdx
  and    %rax,%rdx
  movabs $0x101010101,%rax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %al,-0xb1(%rbp)
  cmpb   $0xa1,-0xb1(%rbp)
  ja     L15
  movzbl -0xb1(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xb3(%rbp),%eax
  movzbl (%rdx),%edx
  cltq
  mov    %dl,-0xb0(%rbp,%rax,1)
  addb   $0x1,-0xb3(%rbp)
L15:
  addb   $0x1,-0xb2(%rbp)
L4:
  cmpb   $0xa1,-0xb3(%rbp)
  jbe    L11
  movb   $0x0,-0xb2(%rbp)
  jmp    L48
L44:
  movzbl -0xb2(%rbp),%eax
  movzbl -0xb2(%rbp),%ecx
  mov    -0xc8(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  movzbl -0xb0(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  movzbl -0xb2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xb2(%rbp)
L48:
  cmpb   $0xa1,-0xb2(%rbp)
  jbe    L44
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void deinterleave(unsigned char *sym) {
  unsigned char tmp[162];
  unsigned char p, i, j;
  p = 0;
  i = 0;
  while (p < 162) {
    j = ((i * 0x80200802ULL) & 0x0884422110ULL) * 0x0101010101ULL >> 32;
    if (j < 162) {
      tmp[p] = sym[j];
      p = p + 1;
    }
    i = i + 1;
  }
  for (i = 0; i < 162; i++) {
    sym[i] = tmp[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<deinterleave>:
  endbr64
  sub    $0xb8,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x80200802,%r9d
  movabs $0x884422110,%r8
  movabs $0x101010101,%rdi
  jmp    L48
L34:
  add    $0x1,%edx
  cmp    $0xa1,%sil
  ja     L56
L48:
  movzbl %dl,%eax
  imul   %r9,%rax
  and    %r8,%rax
  imul   %rdi,%rax
  shr    $0x20,%rax
  cmp    $0xa1,%al
  ja     L34
  movzbl %sil,%r10d
  movzbl %al,%eax
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%rsp,%r10,1)
  add    $0x1,%esi
  jmp    L34
L56:
  mov    $0x0,%eax
L51:
  movzbl (%rsp,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    $0xa2,%rax
  jne    L51
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0xb8,%rsp
  ret
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void deinterleave(unsigned char *sym) {
  unsigned char tmp[162];
  unsigned char p, i, j;
  p = 0;
  i = 0;
  while (p < 162) {
    j = ((i * 0x80200802ULL) & 0x0884422110ULL) * 0x0101010101ULL >> 32;
    if (j < 162) {
      tmp[p] = sym[j];
      p = p + 1;
    }
    i = i + 1;
  }
  for (i = 0; i < 162; i++) {
    sym[i] = tmp[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<deinterleave>:
  endbr64
  sub    $0xb8,%rsp
  mov    %rdi,%rcx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    $0x80200802,%r9d
  movabs $0x884422110,%r8
  movabs $0x101010101,%rdi
  nop
L11:
  movzbl %dl,%eax
  imul   %r9,%rax
  and    %r8,%rax
  imul   %rdi,%rax
  shr    $0x20,%rax
  cmp    $0xa1,%al
  ja     L16
  movzbl %al,%eax
  movzbl %sil,%r10d
  add    $0x1,%esi
  add    $0x1,%edx
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%rsp,%r10,1)
  cmp    $0xa2,%sil
  jne    L11
  movdqa (%rsp),%xmm0
  movdqa 0x10(%rsp),%xmm1
  movzwl 0xa0(%rsp),%eax
  movdqa 0x20(%rsp),%xmm2
  movdqa 0x30(%rsp),%xmm3
  movdqa 0x40(%rsp),%xmm4
  movups %xmm0,(%rcx)
  movdqa 0x50(%rsp),%xmm5
  movdqa 0x60(%rsp),%xmm6
  movups %xmm1,0x10(%rcx)
  movdqa 0x70(%rsp),%xmm7
  mov    %ax,0xa0(%rcx)
  movdqa 0x80(%rsp),%xmm0
  movups %xmm2,0x20(%rcx)
  movdqa 0x90(%rsp),%xmm1
  movups %xmm3,0x30(%rcx)
  movups %xmm4,0x40(%rcx)
  movups %xmm5,0x50(%rcx)
  movups %xmm6,0x60(%rcx)
  movups %xmm7,0x70(%rcx)
  movups %xmm0,0x80(%rcx)
  movups %xmm1,0x90(%rcx)
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0xb8,%rsp
  ret
  nopl   (%rax)
L16:
  add    $0x1,%edx
  jmp    L11
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void deinterleave(unsigned char *sym) {
  unsigned char tmp[162];
  unsigned char p, i, j;
  p = 0;
  i = 0;
  while (p < 162) {
    j = ((i * 0x80200802ULL) & 0x0884422110ULL) * 0x0101010101ULL >> 32;
    if (j < 162) {
      tmp[p] = sym[j];
      p = p + 1;
    }
    i = i + 1;
  }
  for (i = 0; i < 162; i++) {
    sym[i] = tmp[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<deinterleave>:
  endbr64
  sub    $0xb8,%rsp
  mov    %rdi,%rsi
  xor    %edx,%edx
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    $0x80200802,%r9d
  movabs $0x884422110,%r8
  movabs $0x101010101,%rdi
  nop
L37:
  movzbl %dl,%eax
  imul   %r9,%rax
  and    %r8,%rax
  imul   %rdi,%rax
  shr    $0x20,%rax
  cmp    $0xa1,%al
  ja     L22
  movzbl %al,%eax
  movzbl %cl,%r10d
  add    $0x1,%ecx
  add    $0x1,%edx
  movzbl (%rsi,%rax,1),%eax
  mov    %al,(%rsp,%r10,1)
  cmp    $0xa2,%cl
  jne    L37
L48:
  movdqa (%rsp),%xmm0
  movdqa 0x10(%rsp),%xmm1
  movzwl 0xa0(%rsp),%eax
  movdqa 0x20(%rsp),%xmm2
  movdqa 0x30(%rsp),%xmm3
  movdqa 0x40(%rsp),%xmm4
  movups %xmm0,(%rsi)
  movdqa 0x50(%rsp),%xmm5
  movdqa 0x60(%rsp),%xmm6
  movups %xmm1,0x10(%rsi)
  movdqa 0x70(%rsp),%xmm7
  mov    %ax,0xa0(%rsi)
  movdqa 0x80(%rsp),%xmm0
  movups %xmm2,0x20(%rsi)
  movdqa 0x90(%rsp),%xmm1
  movups %xmm3,0x30(%rsi)
  movups %xmm4,0x40(%rsi)
  movups %xmm5,0x50(%rsi)
  movups %xmm6,0x60(%rsi)
  movups %xmm7,0x70(%rsi)
  movups %xmm0,0x80(%rsi)
  movups %xmm1,0x90(%rsi)
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0xb8,%rsp
  ret
  nopl   0x0(%rax)
L22:
  add    $0x1,%edx
  cmp    $0xa2,%cl
  jne    L37
  jmp    L48
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void deinterleave(unsigned char *sym) {
  unsigned char tmp[162];
  unsigned char p, i, j;
  p = 0;
  i = 0;
  while (p < 162) {
    j = ((i * 0x80200802ULL) & 0x0884422110ULL) * 0x0101010101ULL >> 32;
    if (j < 162) {
      tmp[p] = sym[j];
      p = p + 1;
    }
    i = i + 1;
  }
  for (i = 0; i < 162; i++) {
    sym[i] = tmp[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TestingPathological>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  mov    $0xa,%eax
  jmp    L31
L38:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  cmp    %rax,-0x8(%rbp)
  jge    L33
  mov    $0xb,%eax
  jmp    L31
L33:
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jne    L15
  mov    $0xa,%eax
  jmp    L31
L15:
  mov    $0x9,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
long TestingPathological(long index, long total) {
  if (index == 0)
    return 10;
  else if (index < total / 2)
    return 11;
  else if (index == total - 1)
    return 10;
  return 9;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TestingPathological>:
  endbr64
  mov    $0xa,%eax
  test   %rdi,%rdi
  je     L6
  mov    %rsi,%rdx
  shr    $0x3f,%rdx
  add    %rsi,%rdx
  sar    %rdx
  mov    $0xb,%eax
  cmp    %rdi,%rdx
  jg     L6
  sub    $0x1,%rsi
  cmp    %rdi,%rsi
  sete   %al
  movzbl %al,%eax
  add    $0x9,%rax
L6:
  ret
```

assistant: ```c
long TestingPathological(long index, long total) {
  if (index == 0)
    return 10;
  else if (index < total / 2)
    return 11;
  else if (index == total - 1)
    return 10;
  return 9;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TestingPathological>:
  endbr64
  mov    $0xa,%eax
  test   %rdi,%rdi
  je     L1
  mov    %rsi,%rdx
  mov    $0xb,%eax
  shr    $0x3f,%rdx
  add    %rsi,%rdx
  sar    %rdx
  cmp    %rdi,%rdx
  jg     L1
  sub    $0x1,%rsi
  xor    %eax,%eax
  cmp    %rdi,%rsi
  sete   %al
  add    $0x9,%rax
L1:
  ret
```

assistant: ```c
long TestingPathological(long index, long total) {
  if (index == 0)
    return 10;
  else if (index < total / 2)
    return 11;
  else if (index == total - 1)
    return 10;
  return 9;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TestingPathological>:
  endbr64
  mov    $0xa,%eax
  test   %rdi,%rdi
  je     L16
  mov    %rsi,%rdx
  mov    $0xb,%eax
  shr    $0x3f,%rdx
  add    %rsi,%rdx
  sar    %rdx
  cmp    %rdi,%rdx
  jg     L16
  sub    $0x1,%rsi
  xor    %eax,%eax
  cmp    %rdi,%rsi
  sete   %al
  add    $0x9,%rax
L16:
  ret
```

assistant: ```c
long TestingPathological(long index, long total) {
  if (index == 0)
    return 10;
  else if (index < total / 2)
    return 11;
  else if (index == total - 1)
    return 10;
  return 9;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  imul   $0x9f65fb16,(%rdi),%eax
  sub    $0x1a4602e4,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%ecx
  test   %ecx,%ecx
  je     L60
  lea    0x4(%rsp),%rdx
  mov    $0x0,%eax
L58:
  mov    0x4(%rsp),%edi
  cmp    %eax,%edi
  jae    L34
  movzwl (%rdx),%edi
  movzwl 0x2(%rdx),%r8d
  mov    %r8w,(%rdx)
  mov    %di,0x2(%rdx)
L43:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L58
L60:
  mov    0x4(%rsp),%eax
  add    $0x3f26566c,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x18,%rsp
  ret
L34:
  jne    L31
  movzbl 0x7(%rsp),%edi
  movzbl 0x5(%rsp),%r8d
  mov    %r8b,0x7(%rsp)
  mov    %dil,0x5(%rsp)
  jmp    L43
L31:
  movl   $0x0,(%rdx)
  jmp    L43
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
        copy14 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
      } else {
        state[0UL] -= state[local1];
        state[local1] = state[0UL] + state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] + 1059477100UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  imul   $0x9f65fb16,(%rdi),%eax
  mov    0x4(%rdi),%edi
  sub    $0x1a4602e4,%eax
  mov    %eax,0x4(%rsp)
  test   %edi,%edi
  je     L17
  lea    0x4(%rsp),%rdx
  xor    %ecx,%ecx
L10:
  cmp    %eax,%ecx
  jbe    L33
  movzwl (%rdx),%r8d
  movzwl 0x2(%rdx),%r9d
  mov    %r8w,0x2(%rdx)
  mov    %r9w,(%rdx)
L53:
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %edi,%ecx
  jne    L10
L17:
  add    $0x3f26566c,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  jne    L46
  movzbl 0x7(%rsp),%eax
  movzbl 0x5(%rsp),%r8d
  mov    %al,0x5(%rsp)
  mov    %r8b,0x7(%rsp)
  mov    0x4(%rsp),%eax
  jmp    L53
  nopl   0x0(%rax)
L46:
  movl   $0x0,(%rdx)
  xor    %eax,%eax
  jmp    L53
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
        copy14 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
      } else {
        state[0UL] -= state[local1];
        state[local1] = state[0UL] + state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] + 1059477100UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%ecx
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  imul   $0x9f65fb16,(%rdi),%eax
  sub    $0x1a4602e4,%eax
  mov    %eax,0x4(%rsp)
  test   %ecx,%ecx
  je     L140
  test   %eax,%eax
  je     L45
  movl   $0x0,0x4(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%ecx
  je     L140
L90:
  movzwl 0x8(%rsp),%esi
  movzwl 0xa(%rsp),%eax
  shl    $0x10,%esi
  or     %esi,%eax
  mov    %eax,0x8(%rsp)
  xor    %eax,%eax
L134:
  cmp    $0x2,%ecx
  jbe    L140
  lea    0x4(%rsp),%rdi
  mov    $0x2,%esi
L130:
  cmp    %esi,%eax
  jae    L7
  movzwl 0x8(%rdi),%r9d
  movzwl 0xa(%rdi),%r8d
  shl    $0x10,%r9d
  or     %r9d,%r8d
  mov    %r8d,0x8(%rdi)
L71:
  add    $0x1,%esi
  add    $0x4,%rdi
  cmp    %ecx,%esi
  jne    L130
  nopl   0x0(%rax)
L140:
  add    $0x3f26566c,%eax
  mov    %eax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L154
  add    $0x18,%rsp
  ret
L45:
  movb   $0x0,0x7(%rsp)
  movb   $0x0,0x5(%rsp)
  mov    0x4(%rsp),%esi
  cmp    $0x1,%ecx
  je     L149
  test   %esi,%esi
  je     L90
  cmp    $0x1,%esi
  je     L11
  movl   $0x0,0x8(%rsp)
  jmp    L134
  nopl   (%rax)
L149:
  mov    %esi,%eax
  jmp    L140
  nopl   0x0(%rax)
L7:
  jne    L18
  movzbl 0x7(%rsp),%eax
  movzbl 0x5(%rsp),%r8d
  mov    %al,0x5(%rsp)
  mov    %r8b,0x7(%rsp)
  mov    0x4(%rsp),%eax
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  jmp    L134
  nopw   0x0(%rax,%rax,1)
L18:
  movl   $0x0,0x8(%rdi)
  xor    %eax,%eax
  jmp    L71
L154:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
        copy14 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
      } else {
        state[0UL] -= state[local1];
        state[local1] = state[0UL] + state[0UL];
      }
      local1++;
    }
    output[0UL] = state[0UL] + 1059477100UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<cel_bkdr_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    $0x0,%ebx
  movl   $0x83,-0xc(%rbp)
  jmp    L19
L12:
  mov    %ebx,%ecx
  imul   -0xc(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    (%rcx,%rax,1),%ebx
L19:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    %ebx,%eax
  and    $0x7fffffff,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
extern uint32_t cel_bkdr_hash(const char *str) {
  register uint32_t h = 0;
  uint32_t seed = 131;
  while (*str != '\0') {
    h = h * seed + (*str++);
  }
  return (h & 0x7FFFFFFF);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cel_bkdr_hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L28
  mov    $0x0,%eax
L25:
  imul   $0x83,%eax,%eax
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L25
L10:
  and    $0x7fffffff,%eax
  ret
L28:
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
extern uint32_t cel_bkdr_hash(const char *str) {
  register uint32_t h = 0;
  uint32_t seed = 131;
  while (*str != '\0') {
    h = h * seed + (*str++);
  }
  return (h & 0x7FFFFFFF);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cel_bkdr_hash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L13
  nopl   (%rax)
L4:
  imul   $0x83,%eax,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L4
  and    $0x7fffffff,%eax
  ret
  nopl   0x0(%rax)
L13:
  ret
```

assistant: ```c
extern uint32_t cel_bkdr_hash(const char *str) {
  register uint32_t h = 0;
  uint32_t seed = 131;
  while (*str != '\0') {
    h = h * seed + (*str++);
  }
  return (h & 0x7FFFFFFF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cel_bkdr_hash>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L13
  nopl   (%rax)
L7:
  imul   $0x83,%eax,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L7
  and    $0x7fffffff,%eax
  ret
  nopl   0x0(%rax)
L13:
  ret
```

assistant: ```c
extern uint32_t cel_bkdr_hash(const char *str) {
  register uint32_t h = 0;
  uint32_t seed = 131;
  while (*str != '\0') {
    h = h * seed + (*str++);
  }
  return (h & 0x7FFFFFFF);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void permute(int n, double *vector, int *p) {
  double *temp_vector = (double *)malloc(sizeof(int) * n);
  int i = 0;
  for (i = 0; i < n; i++)
    temp_vector[i] = vector[i];
  for (i = 0; i < n; i++) {
    vector[i] = temp_vector[p[i]];
  }
  free(temp_vector);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<permute>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L23
  mov    %r12d,%eax
  lea    (%rdi,%rax,8),%rcx
  mov    %rdi,%rdx
  mov    %rbx,%rax
  sub    %rdi,%rax
L17:
  movsd  (%rax,%rdx,1),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L17
  mov    %r12d,%eax
  mov    $0x0,%edx
L16:
  movslq 0x0(%rbp,%rdx,4),%rcx
  movsd  (%rdi,%rcx,8),%xmm0
  movsd  %xmm0,(%rbx,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L16
L23:
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void permute(int n, double *vector, int *p) {
  double *temp_vector = (double *)malloc(sizeof(int) * n);
  int i = 0;
  for (i = 0; i < n; i++)
    temp_vector[i] = vector[i];
  for (i = 0; i < n; i++) {
    vector[i] = temp_vector[p[i]];
  }
  free(temp_vector);
}
```