ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrop3_63_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movl   $0xff,-0x10(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x18(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  and    -0xc(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_63_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = T & S;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrop3_63_1_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  not    %eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_63_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = T & S;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_63_1_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  not    %eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_63_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = T & S;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: What is the c source code of the assembly code below:

```asm
<xrop3_63_1_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  not    %eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_63_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = T & S;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<put_short_be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  sar    $0x8,%ax
  mov    %eax,%esi
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzwl -0x4(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void put_short_be(short data, unsigned char **bufptr) {
  *(*bufptr)++ = (unsigned char)((data >> 8) & 0xff);
  *(*bufptr)++ = (unsigned char)(data & 0xff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<put_short_be>:
  endbr64
  mov    %edi,%eax
  mov    (%rsi),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  movzbl %ah,%ecx
  mov    %cl,(%rdx)
  mov    (%rsi),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  mov    %dil,(%rdx)
  ret
```

assistant: ```c
void put_short_be(short data, unsigned char **bufptr) {
  *(*bufptr)++ = (unsigned char)((data >> 8) & 0xff);
  *(*bufptr)++ = (unsigned char)(data & 0xff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<put_short_be>:
  endbr64
  mov    (%rsi),%rdx
  mov    %edi,%eax
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  mov    %ah,(%rdx)
  mov    (%rsi),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  mov    %dil,(%rdx)
  ret
```

assistant: ```c
void put_short_be(short data, unsigned char **bufptr) {
  *(*bufptr)++ = (unsigned char)((data >> 8) & 0xff);
  *(*bufptr)++ = (unsigned char)(data & 0xff);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<put_short_be>:
  endbr64
  mov    (%rsi),%rdx
  mov    %edi,%eax
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  mov    %ah,(%rdx)
  mov    (%rsi),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  mov    %dil,(%rdx)
  ret
```

assistant: ```c
void put_short_be(short data, unsigned char **bufptr) {
  *(*bufptr)++ = (unsigned char)((data >> 8) & 0xff);
  *(*bufptr)++ = (unsigned char)(data & 0xff);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strconv_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movb   $0x78,(%rax)
  jmp    L14
L16:
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  mov    $0x7,%eax
  sub    -0x4(%rbp),%eax
  shl    $0x2,%eax
  mov    $0xf,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    %eax,%esi
  mov    %esi,%edx
  mov    $0x7,%eax
  sub    -0x4(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x9,-0x5(%rbp)
  jg     L21
  movzbl -0x5(%rbp),%eax
  lea    0x30(%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  jmp    L15
L21:
  movzbl -0x5(%rbp),%eax
  lea    0x37(%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L15:
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x7,-0x4(%rbp)
  jle    L16
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strconv_ptr(void *val, char *buf) {
  int cpt = 0;
  char c;
  buf[0] = '0';
  buf[1] = 'x';
  while (cpt < 8) {
    c = ((unsigned int)val & (0xF << ((7 - cpt) * 4))) >> ((7 - cpt) * 4);
    if (c < 10)
      buf[cpt + 2] = c + '0';
    else
      buf[cpt + 2] = c - 10 + 'A';
    cpt++;
  }
  buf[cpt + 2] = '\0';
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strconv_ptr>:
  endbr64
  mov    %rsi,%rax
  movb   $0x30,(%rsi)
  movb   $0x78,0x1(%rsi)
  lea    0x2(%rsi),%r8
  mov    $0x1c,%ecx
  mov    $0xf,%r9d
  jmp    L16
L1:
  add    $0x37,%edx
  mov    %dl,(%r8)
L8:
  sub    $0x4,%ecx
  add    $0x1,%r8
  cmp    $0xfffffffc,%ecx
  je     L20
L16:
  mov    %r9d,%edx
  shl    %cl,%edx
  and    %edi,%edx
  shr    %cl,%edx
  cmp    $0x9,%dl
  jg     L1
  add    $0x30,%edx
  mov    %dl,(%r8)
  jmp    L8
L20:
  movb   $0x0,0xa(%rax)
  ret
```

assistant: ```c
char *strconv_ptr(void *val, char *buf) {
  int cpt = 0;
  char c;
  buf[0] = '0';
  buf[1] = 'x';
  while (cpt < 8) {
    c = ((unsigned int)val & (0xF << ((7 - cpt) * 4))) >> ((7 - cpt) * 4);
    if (c < 10)
      buf[cpt + 2] = c + '0';
    else
      buf[cpt + 2] = c - 10 + 'A';
    cpt++;
  }
  buf[cpt + 2] = '\0';
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strconv_ptr>:
  endbr64
  mov    $0x7830,%edx
  mov    %rsi,%rax
  lea    0x2(%rsi),%r9
  mov    $0x1c,%ecx
  mov    %dx,(%rsi)
  mov    $0xf,%r11d
  xchg   %ax,%ax
L6:
  mov    %r11d,%edx
  shl    %cl,%edx
  and    %edi,%edx
  shr    %cl,%edx
  lea    0x30(%rdx),%r10d
  cmp    $0x9,%dl
  lea    0x37(%rdx),%r8d
  mov    %r10d,%edx
  cmovg  %r8d,%edx
  sub    $0x4,%ecx
  add    $0x1,%r9
  mov    %dl,-0x1(%r9)
  cmp    $0xfffffffc,%ecx
  jne    L6
  movb   $0x0,0xa(%rax)
  ret
```

assistant: ```c
char *strconv_ptr(void *val, char *buf) {
  int cpt = 0;
  char c;
  buf[0] = '0';
  buf[1] = 'x';
  while (cpt < 8) {
    c = ((unsigned int)val & (0xF << ((7 - cpt) * 4))) >> ((7 - cpt) * 4);
    if (c < 10)
      buf[cpt + 2] = c + '0';
    else
      buf[cpt + 2] = c - 10 + 'A';
    cpt++;
  }
  buf[cpt + 2] = '\0';
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strconv_ptr>:
  endbr64
  mov    %edi,%ecx
  mov    $0x7830,%edx
  mov    %rsi,%r8
  mov    %rdi,%rax
  shr    $0x1c,%ecx
  mov    %dx,(%rsi)
  cmp    $0xa,%ecx
  lea    0x37(%rcx),%esi
  lea    0x30(%rcx),%edx
  movb   $0x0,0xa(%r8)
  cmovae %esi,%edx
  mov    %dl,0x2(%r8)
  mov    %edi,%edx
  shr    $0x18,%edx
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x30(%rdx),%ecx
  lea    0x37(%rdx),%esi
  mov    %edi,%edx
  cmovb  %ecx,%esi
  shr    $0x14,%edx
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x30(%rdx),%ecx
  mov    %sil,0x3(%r8)
  lea    0x37(%rdx),%esi
  mov    %edi,%edx
  cmovb  %ecx,%esi
  shr    $0x10,%edx
  and    $0xf,%edx
  mov    %sil,0x4(%r8)
  cmp    $0xa,%edx
  lea    0x30(%rdx),%ecx
  lea    0x37(%rdx),%esi
  mov    %edi,%edx
  cmovb  %ecx,%esi
  shr    $0xc,%edx
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x30(%rdx),%ecx
  mov    %sil,0x5(%r8)
  lea    0x37(%rdx),%esi
  mov    %edi,%edx
  cmovb  %ecx,%esi
  shr    $0x8,%edx
  and    $0xf,%edx
  mov    %sil,0x6(%r8)
  cmp    $0xa,%edx
  lea    0x30(%rdx),%ecx
  lea    0x37(%rdx),%esi
  mov    %edi,%edx
  cmovb  %ecx,%esi
  shr    $0x4,%edx
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x30(%rdx),%ecx
  mov    %sil,0x7(%r8)
  lea    0x37(%rdx),%esi
  cmovb  %ecx,%esi
  and    $0xf,%eax
  lea    0x30(%rax),%ecx
  lea    0x37(%rax),%edx
  cmp    $0x9,%eax
  mov    %ecx,%eax
  mov    %sil,0x8(%r8)
  cmova  %edx,%eax
  mov    %al,0x9(%r8)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strconv_ptr(void *val, char *buf) {
  int cpt = 0;
  char c;
  buf[0] = '0';
  buf[1] = 'x';
  while (cpt < 8) {
    c = ((unsigned int)val & (0xF << ((7 - cpt) * 4))) >> ((7 - cpt) * 4);
    if (c < 10)
      buf[cpt + 2] = c + '0';
    else
      buf[cpt + 2] = c - 10 + 'A';
    cpt++;
  }
  buf[cpt + 2] = '\0';
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rnorm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  D22(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
L19:
  mov    $0x0,%eax
  call   <drand48@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <drand48@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  movsd  D4(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x24(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <log@plt>
  mulss  -0x24(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x8(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jae    L5
  jmp    L19
L5:
  nop
  movss  -0xc(%rbp),%xmm0
  divss  -0x10(%rbp),%xmm0
  mulss  -0x18(%rbp),%xmm0
  addss  -0x14(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type: f32
name: extract_symbolic_data
arguments: label: D4
type: f64
name: extract_symbolic_data
arguments: label: D6
type: f64
name: extract_symbolic_data
arguments: label: D10
type: f32[2]

tool: D22: 1

tool: D4: 0.5

tool: D6: 1.71552776992141

tool: {"D10": [0.0,-2.25]}

assistant: ```c
float rnorm(void) {
  const float sig = 1.0;
  const float mu = 0.0;
  float u, v;
  float x, y;
  for (;;) {
    u = drand48();
    v = drand48();
    v = (v - 0.5) * 1.71552776992141;
    x = u * u * log(u) * -4.0;
    y = v * v;
    if (x >= y)
      break;
  }
  return mu + sig * (v / u);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rnorm>:
  endbr64
  sub    $0x18,%rsp
L9:
  mov    $0x0,%eax
  call   <drand48@plt>
  movss  %xmm0,0x4(%rsp)
  mov    $0x0,%eax
  call   <drand48@plt>
  cvtss2sd %xmm0,%xmm0
  subsd  D16(%rip),%xmm0
  mulsd  D38(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  movss  %xmm1,0x8(%rsp)
  movss  0x4(%rsp),%xmm0
  movaps %xmm0,%xmm2
  mulss  %xmm0,%xmm2
  movss  %xmm2,0xc(%rsp)
  call   <log@plt>
  mulss  0xc(%rsp),%xmm0
  mulss  D32(%rip),%xmm0
  movss  0x8(%rsp),%xmm3
  movaps %xmm3,%xmm1
  mulss  %xmm3,%xmm1
  comiss %xmm1,%xmm0
  jb     L9
  movaps %xmm3,%xmm0
  divss  0x4(%rsp),%xmm0
  addss  D16(%rip),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D38
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D32
type_infered: byte[4]

tool: D16: 0.5

tool: D38: 1.71552776992141

tool: {"D32": [0x00,0x00,0x80,0xc0]}

assistant: ```c
float rnorm(void) {
  const float sig = 1.0;
  const float mu = 0.0;
  float u, v;
  float x, y;
  for (;;) {
    u = drand48();
    v = drand48();
    v = (v - 0.5) * 1.71552776992141;
    x = u * u * log(u) * -4.0;
    y = v * v;
    if (x >= y)
      break;
  }
  return mu + sig * (v / u);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rnorm>:
  endbr64
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <drand48@plt>
  xor    %eax,%eax
  movss  %xmm0,0x4(%rsp)
  call   <drand48@plt>
  movss  0x4(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  subsd  D7(%rip),%xmm1
  mulsd  D19(%rip),%xmm1
  movaps %xmm2,%xmm4
  movaps %xmm2,%xmm0
  movss  %xmm2,0x8(%rsp)
  mulss  %xmm2,%xmm4
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0xc(%rsp)
  movss  %xmm4,0x4(%rsp)
  call   <log@plt>
  movss  0xc(%rsp),%xmm1
  mulss  0x4(%rsp),%xmm0
  mulss  D21(%rip),%xmm0
  movss  0x8(%rsp),%xmm2
  movaps %xmm1,%xmm3
  mulss  %xmm1,%xmm3
  comiss %xmm3,%xmm0
  jb     L2
  divss  %xmm2,%xmm1
  addss  D7(%rip),%xmm1
  add    $0x18,%rsp
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: f64
name: unpack_data
arguments: data_tag: D19
type: f64
name: unpack_data
arguments: data_tag: D21
type: byte[4]

tool: D7: 0.5

tool: D19: 1.71552776992141

tool: {"D21": [0x00,0x00,0x80,0xc0]}

assistant: ```c
float rnorm(void) {
  const float sig = 1.0;
  const float mu = 0.0;
  float u, v;
  float x, y;
  for (;;) {
    u = drand48();
    v = drand48();
    v = (v - 0.5) * 1.71552776992141;
    x = u * u * log(u) * -4.0;
    y = v * v;
    if (x >= y)
      break;
  }
  return mu + sig * (v / u);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rnorm>:
  endbr64
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <drand48@plt>
  xor    %eax,%eax
  movss  %xmm0,0x4(%rsp)
  call   <drand48@plt>
  movss  0x4(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  subsd  D19(%rip),%xmm1
  mulsd  D11(%rip),%xmm1
  movaps %xmm2,%xmm4
  movaps %xmm2,%xmm0
  movss  %xmm2,0x8(%rsp)
  mulss  %xmm2,%xmm4
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0xc(%rsp)
  movss  %xmm4,0x4(%rsp)
  call   <log@plt>
  movss  0xc(%rsp),%xmm1
  mulss  0x4(%rsp),%xmm0
  mulss  D10(%rip),%xmm0
  movss  0x8(%rsp),%xmm2
  movaps %xmm1,%xmm3
  mulss  %xmm1,%xmm3
  comiss %xmm3,%xmm0
  jb     L0
  divss  %xmm2,%xmm1
  addss  D19(%rip),%xmm1
  add    $0x18,%rsp
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_infered: f64
name: unpack_data
arguments: tag: D11
type_infered: f64
name: unpack_data
arguments: tag: D10
type_infered: byte[4]

tool: D19: 0.5

tool: D11: 1.71552776992141

tool: {"D10": [0x00,0x00,0x80,0xc0]}

assistant: ```c
float rnorm(void) {
  const float sig = 1.0;
  const float mu = 0.0;
  float u, v;
  float x, y;
  for (;;) {
    u = drand48();
    v = drand48();
    v = (v - 0.5) * 1.71552776992141;
    x = u * u * log(u) * -4.0;
    y = v * v;
    if (x >= y)
      break;
  }
  return mu + sig * (v / u);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D24(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x28(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  D24(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    $0x0,%eax
  call   <trap_me@plt>
  lea    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D24
datatype: byte[8]
name: disassemble_data
arguments: tag: D10
datatype: byte[8]
name: disassemble_data
arguments: tag: D34
datatype: string

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D34: d: %.6f c: 0x%llx


assistant: ```c
int main() {
  double a, b, c, d;
  unsigned long long cc;
  a = 1;
  b = 3;
  c = 0;
  d = a / b;
  c = 1 / c;
  trap_me();
  cc = *(unsigned long long *)&c;
  printf("d: %.6f c: 0x%llx\n", d, cc);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  movsd  D33(%rip),%xmm0
  divsd  D39(%rip),%xmm0
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <trap_me@plt>
  mov    %rbx,%rsi
  movsd  D9(%rip),%xmm0
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D33
type_infered: byte[8]
name: read_data
arguments: data_tag: D39
type_infered: byte[8]
name: read_data
arguments: data_tag: D9
type_infered: byte[8]
name: read_data
arguments: data_tag: D6
type_infered: string

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D9": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D6: d: %.6f c: 0x%llx


assistant: ```c
int main() {
  double a, b, c, d;
  unsigned long long cc;
  a = 1;
  b = 3;
  c = 0;
  d = a / b;
  c = 1 / c;
  trap_me();
  cc = *(unsigned long long *)&c;
  printf("d: %.6f c: 0x%llx\n", d, cc);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  movsd  D1(%rip),%xmm0
  divsd  D36(%rip),%xmm0
  movq   %xmm0,%rbx
  call   <trap_me@plt>
  movsd  D25(%rip),%xmm0
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: byte[8]
name: read_data
arguments: data_tag: D36
type_guessed: byte[8]
name: read_data
arguments: data_tag: D25
type_guessed: byte[8]
name: read_data
arguments: data_tag: D10
type_guessed: string

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D25": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D10: d: %.6f c: 0x%llx


assistant: ```c
int main() {
  double a, b, c, d;
  unsigned long long cc;
  a = 1;
  b = 3;
  c = 0;
  d = a / b;
  c = 1 / c;
  trap_me();
  cc = *(unsigned long long *)&c;
  printf("d: %.6f c: 0x%llx\n", d, cc);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  movsd  D21(%rip),%xmm0
  divsd  D10(%rip),%xmm0
  movq   %xmm0,%rbx
  call   <trap_me@plt>
  movsd  D2(%rip),%xmm0
  mov    %rbx,%rsi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D21
type: byte[8]
name: unpack_data
arguments: label: D10
type: byte[8]
name: unpack_data
arguments: label: D2
type: byte[8]
name: unpack_data
arguments: label: D37
type: string

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D2": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D37: d: %.6f c: 0x%llx


assistant: ```c
int main() {
  double a, b, c, d;
  unsigned long long cc;
  a = 1;
  b = 3;
  c = 0;
  d = a / b;
  c = 1 / c;
  trap_me();
  cc = *(unsigned long long *)&c;
  printf("d: %.6f c: 0x%llx\n", d, cc);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *substring(unsigned char *in, int from, int length) {
  char *result = (char *)malloc(length + 1);
  memcpy(result, &in[from], length);
  result[length] = '\0';
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<substring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  lea    0x1(%rdx),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movslq %r13d,%r13
  lea    (%r12,%r13,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substring(unsigned char *in, int from, int length) {
  char *result = (char *)malloc(length + 1);
  memcpy(result, &in[from], length);
  result[length] = '\0';
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<substring>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x1(%rbx),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substring(unsigned char *in, int from, int length) {
  char *result = (char *)malloc(length + 1);
  memcpy(result, &in[from], length);
  result[length] = '\0';
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<substring>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x1(%rbx),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substring(unsigned char *in, int from, int length) {
  char *result = (char *)malloc(length + 1);
  memcpy(result, &in[from], length);
  result[length] = '\0';
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fen_board@plt>
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <play@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string

tool: D9: 8/8/2p5/8/8/4k3/2p1q3/7K w - - 0 2

assistant: ```c
void test(void) {
  char *fen = "8/8/2p5/8/8/4k3/2p1q3/7K w - - 0 2";
  fen_board(fen);
  play(4, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <fen_board@plt>
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <play@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: 8/8/2p5/8/8/4k3/2p1q3/7K w - - 0 2

assistant: ```c
void test(void) {
  char *fen = "8/8/2p5/8/8/4k3/2p1q3/7K w - - 0 2";
  fen_board(fen);
  play(4, 0);
}
```