user: 这段汇编代码用C语言表示是什么样的？

```asm
<PartitionErAlgorithmIIR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L55
  mov    -0x40(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jne    L37
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x10(%rbp)
  jmp    L9
L66:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L106
L54:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jne    L44
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L44:
  addq   $0x1,-0x8(%rbp)
L106:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L54
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L66
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x10(%rbp),%rax
  add    $0x1,%rax
  jmp    L65
L37:
  mov    0x10(%rbp),%rax
  jmp    L65
L55:
  movq   $0x0,-0x10(%rbp)
  jmp    L46
L95:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdi
  mov    -0x40(%rbp),%r8
  mov    -0x38(%rbp),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  sub    $0x8,%rsp
  push   0x10(%rbp)
  mov    %r8,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  call   <PartitionErAlgorithmIIR>
  add    $0x10,%rsp
  mov    %rax,0x10(%rbp)
  addq   $0x1,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L95
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x40(%rbp),%rdx
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  lea    0x1(%rax),%r8
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdi
  mov    -0x38(%rbp),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  sub    $0x8,%rsp
  push   0x10(%rbp)
  mov    %r8,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  call   <PartitionErAlgorithmIIR>
  add    $0x10,%rsp
  mov    %rax,0x10(%rbp)
  mov    0x10(%rbp),%rax
L65:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D32
type: string
name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D22
type: string
name: disassemble_data
arguments: data_label: D12
type: string

tool: D32: partition: 

tool: D4: { 

tool: D22: %d 

tool: D12: }  

assistant: ```c
size_t PartitionErAlgorithmIIR(size_t pos, int *val, int *sol, size_t n, size_t k, size_t m, size_t count) {
  size_t i, j;
  if (pos >= n) {
    if (m == k) {
      printf("partition: ");
      for (i = 0; i < m; i++) {
        printf("{ ");
        for (j = 0; j < n; j++) {
          if (sol[j] == i)
            printf("%d ", val[j]);
        }
        printf("}  ");
      }
      printf("\n");
      return (count + 1);
    }
    return (count);
  }
  for (i = 0; i < m; i++) {
    sol[pos] = i;
    count = PartitionErAlgorithmIIR(pos + 1, val, sol, n, k, m, count);
  }
  sol[pos] = m;
  count = PartitionErAlgorithmIIR(pos + 1, val, sol, n, k, m + 1, count);
  return (count);
}
```