ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x140000000a,%rax
  lea    0xc(%rsp),%rdi
  movl   $0x1e,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <foo@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int arr[3];
  int overflow = 1000;
  arr[0] = 10;
  arr[1] = 20;
  arr[2] = 30;
  foo(arr);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  lea    0x8(%rsp),%rdi
  movl   $0x1e,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <foo@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: byte[8]

tool: {"D9": [0x0a,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int arr[3];
  int overflow = 1000;
  arr[0] = 10;
  arr[1] = 20;
  arr[2] = 30;
  foo(arr);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_in_bound>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L23
L2:
  mov    $0x0,%eax
  jmp    L11
L23:
  mov    $0x1,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int is_in_bound(int *arr, int size, int *ptr) {
  if (ptr < arr || ptr > arr + size)
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_in_bound>:
  endbr64
  mov    $0x0,%eax
  cmp    %rdi,%rdx
  jb     L4
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdx
  setbe  %al
  movzbl %al,%eax
L4:
  ret
```

assistant: ```c
int is_in_bound(int *arr, int size, int *ptr) {
  if (ptr < arr || ptr > arr + size)
    return 0;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_in_bound>:
  endbr64
  xor    %eax,%eax
  cmp    %rdi,%rdx
  jb     L3
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdx
  setbe  %al
  movzbl %al,%eax
L3:
  ret
```

assistant: ```c
int is_in_bound(int *arr, int size, int *ptr) {
  if (ptr < arr || ptr > arr + size)
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_in_bound>:
  endbr64
  xor    %eax,%eax
  cmp    %rdi,%rdx
  jb     L8
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdx
  setbe  %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int is_in_bound(int *arr, int size, int *ptr) {
  if (ptr < arr || ptr > arr + size)
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TiCheckHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  cmpl   $0x15,-0x24(%rbp)
  jg     L10
  mov    $0x8,%eax
  jmp    L3
L10:
  mov    -0x8(%rbp),%rax
  mov    $0x15,%esi
  mov    %rax,%rdi
  call   <check_sum@plt>
  mov    -0x8(%rbp),%rdx
  add    $0x15,%rdx
  movzbl (%rdx),%edx
  cmp    %dl,%al
  je     L0
  mov    $0x8,%eax
  jmp    L3
L0:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int TiCheckHeader(unsigned char *stream, int *img_width, int *img_height, int *img_type, int stream_size) {
  if (stream_size < (22))
    return (8);
  if (check_sum(stream, (22) - 1) != stream[21])
    return (8);
  (*img_width = (int)((stream[2 + 0] << 8) | (stream[2 + 1] << 0)));
  (*img_height = (int)((stream[4 + 0] << 8) | (stream[4 + 1] << 0)));
  (*img_type = (int)(stream[7 + 0]));
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TiCheckHeader>:
  endbr64
  mov    $0x8,%eax
  cmp    $0x15,%r8d
  jle    L6
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    $0x15,%esi
  call   <check_sum@plt>
  mov    %eax,%edx
  mov    $0x8,%eax
  cmp    0x15(%rbx),%dl
  jne    L19
  movzbl 0x2(%rbx),%eax
  shl    $0x8,%eax
  movzbl 0x3(%rbx),%edx
  or     %edx,%eax
  mov    %eax,0x0(%r13)
  movzbl 0x4(%rbx),%eax
  shl    $0x8,%eax
  movzbl 0x5(%rbx),%edx
  or     %edx,%eax
  mov    %eax,(%r12)
  movzbl 0x7(%rbx),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  ret
```

assistant: ```c
int TiCheckHeader(unsigned char *stream, int *img_width, int *img_height, int *img_type, int stream_size) {
  if (stream_size < (22))
    return (8);
  if (check_sum(stream, (22) - 1) != stream[21])
    return (8);
  (*img_width = (int)((stream[2 + 0] << 8) | (stream[2 + 1] << 0)));
  (*img_height = (int)((stream[4 + 0] << 8) | (stream[4 + 1] << 0)));
  (*img_type = (int)(stream[7 + 0]));
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TiCheckHeader>:
  endbr64
  cmp    $0x15,%r8d
  jle    L18
  push   %r13
  mov    %rsi,%r13
  mov    $0x15,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <check_sum@plt>
  cmp    0x15(%rbx),%al
  jne    L14
  movzwl 0x2(%rbx),%eax
  rol    $0x8,%ax
  movzwl %ax,%eax
  mov    %eax,0x0(%r13)
  movzwl 0x4(%rbx),%eax
  rol    $0x8,%ax
  movzwl %ax,%eax
  mov    %eax,(%r12)
  movzbl 0x7(%rbx),%eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L14:
  add    $0x8,%rsp
  mov    $0x8,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x8,%eax
  ret
```

assistant: ```c
int TiCheckHeader(unsigned char *stream, int *img_width, int *img_height, int *img_type, int stream_size) {
  if (stream_size < (22))
    return (8);
  if (check_sum(stream, (22) - 1) != stream[21])
    return (8);
  (*img_width = (int)((stream[2 + 0] << 8) | (stream[2 + 1] << 0)));
  (*img_height = (int)((stream[4 + 0] << 8) | (stream[4 + 1] << 0)));
  (*img_type = (int)(stream[7 + 0]));
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<TiCheckHeader>:
  endbr64
  cmp    $0x15,%r8d
  jle    L19
  push   %r13
  mov    %rsi,%r13
  mov    $0x15,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <check_sum@plt>
  cmp    0x15(%rbx),%al
  jne    L11
  movzwl 0x2(%rbx),%eax
  rol    $0x8,%ax
  movzwl %ax,%eax
  mov    %eax,0x0(%r13)
  movzwl 0x4(%rbx),%eax
  rol    $0x8,%ax
  movzwl %ax,%eax
  mov    %eax,(%r12)
  movzbl 0x7(%rbx),%eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  add    $0x8,%rsp
  mov    $0x8,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0x8,%eax
  ret
```

assistant: ```c
int TiCheckHeader(unsigned char *stream, int *img_width, int *img_height, int *img_type, int stream_size) {
  if (stream_size < (22))
    return (8);
  if (check_sum(stream, (22) - 1) != stream[21])
    return (8);
  (*img_width = (int)((stream[2 + 0] << 8) | (stream[2 + 1] << 0)));
  (*img_height = (int)((stream[4 + 0] << 8) | (stream[4 + 1] << 0)));
  (*img_type = (int)(stream[7 + 0]));
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<choisirMenu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
L17:
  cmpl   $0x0,-0xc(%rbp)
  je     L6
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <viderBuffer@plt>
L6:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    $0xffffffff,%eax
  jge    L34
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jb     L17
L34:
  mov    $0x0,%eax
  call   <viderBuffer@plt>
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D9
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string

tool: D22: Veuillez entrer un nombre correct !


tool: D9: > 

tool: D14: %d

assistant: ```c
int choisirMenu(const unsigned int maximum) {
  int choixJoueur;
  unsigned int compteurErreur;
  compteurErreur = 0;
  do {
    if (compteurErreur > 0) {
      printf("Veuillez entrer un nombre correct !\n");
      viderBuffer();
    }
    printf("> ");
    scanf("%d", &choixJoueur);
    ++compteurErreur;
  } while (choixJoueur < -1 && choixJoueur > maximum);
  viderBuffer();
  return choixJoueur;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<choisirMenu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D28(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D22(%rip),%r12
  lea    D14(%rip),%r15
  jmp    L23
L25:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <viderBuffer@plt>
L23:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    $0xffffffff,%eax
  jge    L12
  cmp    %ebp,%eax
  jbe    L12
  test   %ebx,%ebx
  jne    L25
  jmp    L23
L12:
  mov    $0x0,%eax
  call   <viderBuffer@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D22
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string

tool: D28: > 

tool: D22: %d

tool: D14: Veuillez entrer un nombre correct !


assistant: ```c
int choisirMenu(const unsigned int maximum) {
  int choixJoueur;
  unsigned int compteurErreur;
  compteurErreur = 0;
  do {
    if (compteurErreur > 0) {
      printf("Veuillez entrer un nombre correct !\n");
      viderBuffer();
    }
    printf("> ");
    scanf("%d", &choixJoueur);
    ++compteurErreur;
  } while (choixJoueur < -1 && choixJoueur > maximum);
  viderBuffer();
  return choixJoueur;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<choisirMenu>:
  endbr64
  push   %r15
  lea    D5(%rip),%r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
L32:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xffffffff,%eax
  jge    L20
  cmp    %ebp,%eax
  jbe    L20
  test   %ebx,%ebx
  je     L32
  mov    %r15,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <viderBuffer@plt>
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  call   <viderBuffer@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D5: Veuillez entrer un nombre correct !


tool: D1: > 

tool: D8: %d

assistant: ```c
int choisirMenu(const unsigned int maximum) {
  int choixJoueur;
  unsigned int compteurErreur;
  compteurErreur = 0;
  do {
    if (compteurErreur > 0) {
      printf("Veuillez entrer un nombre correct !\n");
      viderBuffer();
    }
    printf("> ");
    scanf("%d", &choixJoueur);
    ++compteurErreur;
  } while (choixJoueur < -1 && choixJoueur > maximum);
  viderBuffer();
  return choixJoueur;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<choisirMenu>:
  endbr64
  push   %r15
  lea    D26(%rip),%r15
  push   %r14
  lea    D23(%rip),%r14
  push   %r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
L47:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xffffffff,%eax
  jge    L39
  cmp    %ebp,%eax
  jbe    L39
  test   %ebx,%ebx
  je     L47
  mov    %r15,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <viderBuffer@plt>
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  call   <viderBuffer@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D26
type: string
name: retrieve_data
arguments: data_label: D23
type: string
name: retrieve_data
arguments: data_label: D21
type: string

tool: D26: Veuillez entrer un nombre correct !


tool: D23: > 

tool: D21: %d

assistant: ```c
int choisirMenu(const unsigned int maximum) {
  int choixJoueur;
  unsigned int compteurErreur;
  compteurErreur = 0;
  do {
    if (compteurErreur > 0) {
      printf("Veuillez entrer un nombre correct !\n");
      viderBuffer();
    }
    printf("> ");
    scanf("%d", &choixJoueur);
    ++compteurErreur;
  } while (choixJoueur < -1 && choixJoueur > maximum);
  viderBuffer();
  return choixJoueur;
}
```
user: What is the c source code of the assembly code below:

```asm
<_convert_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L35
L45:
  addl   $0x1,-0x24(%rbp)
L35:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L45
  addl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x1c(%rbp)
  jmp    L39
L5:
  addl   $0x1,-0x24(%rbp)
L39:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L5
  addl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x18(%rbp)
  jmp    L13
L19:
  addl   $0x1,-0x24(%rbp)
L13:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L19
  addl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x20(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x1c(%rbp),%xmm2
  movsd  D0(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x40(%rbp)
  fldl   -0x40(%rbp)
  fildl  -0x18(%rbp)
  faddp  %st,%st(1)
  fildl  -0x14(%rbp)
  fldt   0xdeb(%rip)        # 2010 <_fini+0xddc>
  fdivrp %st,%st(1)
  faddp  %st,%st(1)
  fstpt  -0x10(%rbp)
  fldt   -0x10(%rbp)
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
datatype: f64
name: read_data
arguments: data_tag: D0
datatype: f64

tool: D10: 3600

tool: D0: 60

assistant: ```c
long double _convert_time(char *c) {
  long double time;
  int H, m, s, i, f;
  H = atoi(c);
  for (i = 0; c[i] != ':'; i++)
    ;
  m = atoi(&c[++i]);
  for (; c[i] != ':'; i++)
    ;
  s = atoi(&c[++i]);
  for (; c[i] != ':'; i++)
    ;
  f = atoi(&c[++i]);
  time = (H * 3600.) + (m * 60.) + (long double)s + (long double)f / 1000000.;
  return time;
}
```
user: What is the c source code of the assembly code below:

```asm
<_convert_time>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  call   <atoi@plt>
  mov    %eax,%r13d
  cmpb   $0x3a,0x0(%rbp)
  je     L4
  mov    $0x1,%eax
L67:
  mov    %eax,%r14d
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%rbp,%rax,1)
  jne    L67
L11:
  lea    0x1(%r14),%ebx
  movslq %ebx,%r15
  add    %rbp,%r15
  mov    %r15,%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  cmpb   $0x3a,(%r15)
  je     L53
  lea    0x2(%r14),%eax
  cltq
L55:
  mov    %eax,%ebx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%rbp,%rax,1)
  jne    L55
L53:
  lea    0x1(%rbx),%r14d
  movslq %r14d,%r15
  add    %rbp,%r15
  mov    %r15,%rdi
  call   <atoi@plt>
  mov    %eax,0x4(%rsp)
  cmpb   $0x3a,(%r15)
  je     L28
  lea    0x2(%rbx),%eax
  cltq
L41:
  mov    %eax,%r14d
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%rbp,%rax,1)
  jne    L41
L28:
  add    $0x1,%r14d
  movslq %r14d,%r14
  lea    0x0(%rbp,%r14,1),%rdi
  call   <atoi@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %r13d,%xmm1
  mulsd  D14(%rip),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  mulsd  D13(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  fildl  0x4(%rsp)
  faddl  0x8(%rsp)
  mov    %eax,0x4(%rsp)
  fildl  0x4(%rsp)
  fdivs  0xe0d(%rip)        # 2010 <_fini+0xdf0>
  faddp  %st,%st(1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    $0x0,%r14d
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: f64
name: disassemble_data
arguments: tag: D13
type: f64

tool: D14: 3600

tool: D13: 60

assistant: ```c
long double _convert_time(char *c) {
  long double time;
  int H, m, s, i, f;
  H = atoi(c);
  for (i = 0; c[i] != ':'; i++)
    ;
  m = atoi(&c[++i]);
  for (; c[i] != ':'; i++)
    ;
  s = atoi(&c[++i]);
  for (; c[i] != ':'; i++)
    ;
  f = atoi(&c[++i]);
  time = (H * 3600.) + (m * 60.) + (long double)s + (long double)f / 1000000.;
  return time;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_convert_time>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <atoi@plt>
  cmpb   $0x3a,(%r14)
  mov    %eax,%r12d
  je     L45
  mov    $0x1,%eax
  nopl   0x0(%rax)
L52:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%r14,%rax,1)
  jne    L52
  lea    0x1(%rdx),%r13d
  lea    0x2(%rdx),%ebx
  add    $0x3,%edx
  movslq %r13d,%rax
  movslq %ebx,%rcx
  movslq %edx,%r15
L48:
  lea    (%r14,%rax,1),%rdx
  mov    %rcx,0x8(%rsp)
  mov    %rdx,%rdi
  mov    %rdx,(%rsp)
  call   <atoi@plt>
  mov    (%rsp),%rdx
  mov    0x8(%rsp),%rcx
  mov    %eax,%ebp
  cmpb   $0x3a,(%rdx)
  je     L28
  lea    0x1(%r13),%eax
  cltq
  nopl   0x0(%rax)
L56:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%r14,%rax,1)
  jne    L56
  lea    0x1(%rdx),%ebx
  add    $0x2,%edx
  movslq %ebx,%rcx
  movslq %edx,%r15
L28:
  lea    (%r14,%rcx,1),%r13
  mov    %r13,%rdi
  call   <atoi@plt>
  cmpb   $0x3a,0x0(%r13)
  mov    %eax,(%rsp)
  je     L12
  lea    0x1(%rbx),%eax
  cltq
  nopl   (%rax)
L22:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%r14,%rax,1)
  jne    L22
  add    $0x1,%edx
  movslq %edx,%r15
L12:
  lea    (%r14,%r15,1),%rdi
  call   <atoi@plt>
  fildl  (%rsp)
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm1
  mov    %eax,(%rsp)
  mulsd  D19(%rip),%xmm1
  cvtsi2sd %ebp,%xmm0
  mulsd  D4(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  faddl  0x8(%rsp)
  fildl  (%rsp)
  fdivs  0xddd(%rip)        # 2010 <_fini+0xda8>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  faddp  %st,%st(1)
  ret
  nopl   0x0(%rax)
L45:
  mov    $0x3,%r15d
  mov    $0x2,%ecx
  mov    $0x2,%ebx
  mov    $0x1,%eax
  mov    $0x1,%r13d
  jmp    L48
```

tool_calls: name: parse_data
arguments: label: D19
type_infered: f64
name: parse_data
arguments: label: D4
type_infered: f64

tool: D19: 3600

tool: D4: 60

assistant: ```c
long double _convert_time(char *c) {
  long double time;
  int H, m, s, i, f;
  H = atoi(c);
  for (i = 0; c[i] != ':'; i++)
    ;
  m = atoi(&c[++i]);
  for (; c[i] != ':'; i++)
    ;
  s = atoi(&c[++i]);
  for (; c[i] != ':'; i++)
    ;
  f = atoi(&c[++i]);
  time = (H * 3600.) + (m * 60.) + (long double)s + (long double)f / 1000000.;
  return time;
}
```