ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r12
  mov    $0x0,%ebx
  lea    D27(%rip),%r14
  lea    D18(%rip),%r13
L23:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x14,%r12
  cmp    $0x5,%ebx
  jne    L23
  mov    $0x0,%ebx
  lea    D15(%rip),%r12
L13:
  add    $0x1,%ebx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x14,%rbp
  cmp    $0x5,%ebx
  jne    L13
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
type_guessed: string
name: disassemble_data
arguments: data_tag: D18
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string

tool: D27: Type the name %i: 

tool: D18: %s

tool: D15: The name at the line %i is: %s


assistant: ```c
int main() {
  char listOfNames[5][20];
  for (int line = 0; line < 5; line++) {
    printf("Type the name %i: ", (line + 1));
    scanf("%s", listOfNames[line]);
  }
  for (int line = 0; line < 5; line++) {
    printf("The name at the line %i is: %s\n", (line + 1), listOfNames[line]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D25(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r12
L18:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x14,%r12
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L18
  xor    %ebx,%ebx
  lea    D28(%rip),%r12
L7:
  add    $0x1,%ebx
  mov    %rbp,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  add    $0x14,%rbp
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L7
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D25
type: string
name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D28
type: string

tool: D25: Type the name %i: 

tool: D19: %s

tool: D28: The name at the line %i is: %s


assistant: ```c
int main() {
  char listOfNames[5][20];
  for (int line = 0; line < 5; line++) {
    printf("Type the name %i: ", (line + 1));
    scanf("%s", listOfNames[line]);
  }
  for (int line = 0; line < 5; line++) {
    printf("The name at the line %i is: %s\n", (line + 1), listOfNames[line]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r12
L12:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x14,%r12
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L12
  xor    %ebx,%ebx
  lea    D21(%rip),%r12
L15:
  add    $0x1,%ebx
  mov    %rbp,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  add    $0x14,%rbp
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L15
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D22
type_infered: string
name: read_data
arguments: tag: D4
type_infered: string
name: read_data
arguments: tag: D21
type_infered: string

tool: D22: Type the name %i: 

tool: D4: %s

tool: D21: The name at the line %i is: %s


assistant: ```c
int main() {
  char listOfNames[5][20];
  for (int line = 0; line < 5; line++) {
    printf("Type the name %i: ", (line + 1));
    scanf("%s", listOfNames[line]);
  }
  for (int line = 0; line < 5; line++) {
    printf("The name at the line %i is: %s\n", (line + 1), listOfNames[line]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pasarVectorNumero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L8:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  add    %rcx,%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long int pasarVectorNumero(int *n, int k) {
  int i;
  long long int aux = 0;
  for (i = 0; i < k; i++)
    aux += 10 * aux + n[i];
  return aux;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pasarVectorNumero>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdi
  mov    $0x0,%eax
L4:
  lea    (%rax,%rax,4),%rsi
  movslq (%rdx),%rcx
  lea    (%rcx,%rsi,2),%rcx
  add    %rcx,%rax
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L4
  ret
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
long long int pasarVectorNumero(int *n, int k) {
  int i;
  long long int aux = 0;
  for (i = 0; i < k; i++)
    aux += 10 * aux + n[i];
  return aux;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pasarVectorNumero>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  movslq (%rdi),%rdx
  lea    (%rax,%rax,4),%rcx
  add    $0x4,%rdi
  lea    (%rdx,%rcx,2),%rdx
  add    %rdx,%rax
  cmp    %rsi,%rdi
  jne    L13
  ret
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
long long int pasarVectorNumero(int *n, int k) {
  int i;
  long long int aux = 0;
  for (i = 0; i < k; i++)
    aux += 10 * aux + n[i];
  return aux;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pasarVectorNumero>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L18:
  movslq (%rdi),%rdx
  lea    (%rax,%rax,4),%rcx
  add    $0x4,%rdi
  lea    (%rdx,%rcx,2),%rdx
  add    %rdx,%rax
  cmp    %rdi,%rsi
  jne    L18
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
long long int pasarVectorNumero(int *n, int k) {
  int i;
  long long int aux = 0;
  for (i = 0; i < k; i++)
    aux += 10 * aux + n[i];
  return aux;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_full_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <capture@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D9: (\./?[^
]*|/[^
]*)[
]?$

assistant: ```c
char *get_full_path(const char *rawString) {
  char *res;
  char *regexString = "(\\./?[^\r\n]*|/[^\r\n]*)[\r\n]?$";
  res = capture(rawString, regexString);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_full_path>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rsi
  call   <capture@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: (\./?[^
]*|/[^
]*)[
]?$

assistant: ```c
char *get_full_path(const char *rawString) {
  char *res;
  char *regexString = "(\\./?[^\r\n]*|/[^\r\n]*)[\r\n]?$";
  res = capture(rawString, regexString);
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_full_path>:
  endbr64
  lea    D5(%rip),%rsi
  jmp    1050 <capture@plt>
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: (\./?[^
]*|/[^
]*)[
]?$

assistant: ```c
char *get_full_path(const char *rawString) {
  char *res;
  char *regexString = "(\\./?[^\r\n]*|/[^\r\n]*)[\r\n]?$";
  res = capture(rawString, regexString);
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_full_path>:
  endbr64
  lea    D9(%rip),%rsi
  jmp    1050 <capture@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: (\./?[^
]*|/[^
]*)[
]?$

assistant: ```c
char *get_full_path(const char *rawString) {
  char *res;
  char *regexString = "(\\./?[^\r\n]*|/[^\r\n]*)[\r\n]?$";
  res = capture(rawString, regexString);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <ez_daemonize@plt>
L5:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D5: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  ez_daemonize();
  while (1) {
    printf("%lld\n", (long long int)time(((void *)0)));
    sleep(1);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <ez_daemonize@plt>
  lea    D4(%rip),%rbx
L6:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  ez_daemonize();
  while (1) {
    printf("%lld\n", (long long int)time(((void *)0)));
    sleep(1);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  lea    D1(%rip),%rbx
  call   <ez_daemonize@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %edi,%edi
  call   <time@plt>
  mov    %rbx,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  ez_daemonize();
  while (1) {
    printf("%lld\n", (long long int)time(((void *)0)));
    sleep(1);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  lea    D4(%rip),%rbx
  call   <ez_daemonize@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %edi,%edi
  call   <time@plt>
  mov    %rbx,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  ez_daemonize();
  while (1) {
    printf("%lld\n", (long long int)time(((void *)0)));
    sleep(1);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  D0(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x1c(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <log@plt>
  movss  -0x14(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  -0x10(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  nop
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: f32
name: read_data
arguments: tag: D74
data_type: string
name: read_data
arguments: tag: D64
data_type: string
name: read_data
arguments: tag: D68
data_type: string
name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D1
data_type: string

tool: D0: 9.82

tool: D74: Input total mass:

tool: D64: %f

tool: D68: 
Input dry mass:

tool: D23: 
Input specific impulse

tool: D1: 
Your delta v is:	%f.3

assistant: ```c
int main(int argc, char *argv[]) {
  float m_total, m_dry, delta_v, impulse = 0;
  float g_const = 9.82;
  printf("Input total mass:\n");
  scanf("%f", &m_total);
  printf("\nInput dry mass:\n");
  scanf("%f", &m_dry);
  printf("\nInput specific impulse\n");
  scanf("%f", &impulse);
  delta_v = impulse * log(m_total / m_dry) * g_const;
  printf("\nYour delta v is:\t%f.3", delta_v);
  getch();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D58(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  divss  0x10(%rsp),%xmm0
  call   <log@plt>
  mulss  0x14(%rsp),%xmm0
  mulss  D4(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D9(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D40
data_type: string
name: retrieve_data
arguments: label: D58
data_type: string
name: retrieve_data
arguments: label: D55
data_type: string
name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D4
data_type: f32
name: retrieve_data
arguments: label: D9
data_type: string

tool: D40: Input total mass:

tool: D58: %f

tool: D55: 
Input dry mass:

tool: D1: 
Input specific impulse

tool: D4: 9.82

tool: D9: 
Your delta v is:	%f.3

assistant: ```c
int main(int argc, char *argv[]) {
  float m_total, m_dry, delta_v, impulse = 0;
  float g_const = 9.82;
  printf("Input total mass:\n");
  scanf("%f", &m_total);
  printf("\nInput dry mass:\n");
  scanf("%f", &m_dry);
  printf("\nInput specific impulse\n");
  scanf("%f", &impulse);
  delta_v = impulse * log(m_total / m_dry) * g_const;
  printf("\nYour delta v is:\t%f.3", delta_v);
  getch();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D38(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D50(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  divss  0x10(%rsp),%xmm0
  call   <log@plt>
  mulss  0x14(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D22(%rip),%rdi
  mulss  D20(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
type: string
name: read_data
arguments: tag: D38
type: string
name: read_data
arguments: tag: D27
type: string
name: read_data
arguments: tag: D50
type: string
name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D20
type: f32

tool: D11: Input total mass:

tool: D38: %f

tool: D27: 
Input dry mass:

tool: D50: 
Input specific impulse

tool: D22: 
Your delta v is:	%f.3

tool: D20: 9.82

assistant: ```c
int main(int argc, char *argv[]) {
  float m_total, m_dry, delta_v, impulse = 0;
  float g_const = 9.82;
  printf("Input total mass:\n");
  scanf("%f", &m_total);
  printf("\nInput dry mass:\n");
  scanf("%f", &m_dry);
  printf("\nInput specific impulse\n");
  scanf("%f", &impulse);
  delta_v = impulse * log(m_total / m_dry) * g_const;
  printf("\nYour delta v is:\t%f.3", delta_v);
  getch();
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D36(%rip),%rdi
  lea    D59(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  divss  0x10(%rsp),%xmm0
  call   <log@plt>
  mulss  0x14(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D51(%rip),%rdi
  mulss  D10(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D36
type_infered: string
name: extract_symbolic_data
arguments: label: D59
type_infered: string
name: extract_symbolic_data
arguments: label: D7
type_infered: string
name: extract_symbolic_data
arguments: label: D5
type_infered: string
name: extract_symbolic_data
arguments: label: D51
type_infered: string
name: extract_symbolic_data
arguments: label: D10
type_infered: f32

tool: D36: Input total mass:

tool: D59: %f

tool: D7: 
Input dry mass:

tool: D5: 
Input specific impulse

tool: D51: 
Your delta v is:	%f.3

tool: D10: 9.82

assistant: ```c
int main(int argc, char *argv[]) {
  float m_total, m_dry, delta_v, impulse = 0;
  float g_const = 9.82;
  printf("Input total mass:\n");
  scanf("%f", &m_total);
  printf("\nInput dry mass:\n");
  scanf("%f", &m_dry);
  printf("\nInput specific impulse\n");
  scanf("%f", &impulse);
  delta_v = impulse * log(m_total / m_dry) * g_const;
  printf("\nYour delta v is:\t%f.3", delta_v);
  getch();
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cjson_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <cjson_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L13
L9:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L13:
  leave
  ret
```

assistant: ```c
char *cjson_strdup(const char *str) {
  size_t len;
  char *copy;
  len = strlen(str) + 1;
  if (!(copy = (char *)cjson_malloc(len)))
    return 0;
  memcpy(copy, str, len);
  return copy;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cjson_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <cjson_malloc@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  mov    %rax,%r12
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L4:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *cjson_strdup(const char *str) {
  size_t len;
  char *copy;
  len = strlen(str) + 1;
  if (!(copy = (char *)cjson_malloc(len)))
    return 0;
  memcpy(copy, str, len);
  return copy;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cjson_strdup>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <cjson_malloc@plt>
  test   %rax,%rax
  je     L9
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
L9:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *cjson_strdup(const char *str) {
  size_t len;
  char *copy;
  len = strlen(str) + 1;
  if (!(copy = (char *)cjson_malloc(len)))
    return 0;
  memcpy(copy, str, len);
  return copy;
}
```
user: What is the c source code of the assembly code below:

```asm
<cjson_strdup>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <cjson_malloc@plt>
  test   %rax,%rax
  je     L7
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
L7:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *cjson_strdup(const char *str) {
  size_t len;
  char *copy;
  len = strlen(str) + 1;
  if (!(copy = (char *)cjson_malloc(len)))
    return 0;
  memcpy(copy, str, len);
  return copy;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reg_str_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <reg_str_r_i@plt>
  leave
  ret
```

assistant: ```c
char *reg_str_i(int r) {
  static char buf[4];
  return reg_str_r_i(buf, r);
}
```
user: Translate the below assembly code into C programming language:

```asm
<reg_str_i>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  call   <reg_str_r_i@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *reg_str_i(int r) {
  static char buf[4];
  return reg_str_r_i(buf, r);
}
```
user: Translate the below assembly code into C programming language:

```asm
<reg_str_i>:
  endbr64
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <reg_str_r_i@plt>
```

assistant: ```c
char *reg_str_i(int r) {
  static char buf[4];
  return reg_str_r_i(buf, r);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reg_str_i>:
  endbr64
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <reg_str_r_i@plt>
```

assistant: ```c
char *reg_str_i(int r) {
  static char buf[4];
  return reg_str_r_i(buf, r);
}
```