ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<Quaternion2RPY>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x30,%rsp
  movss  0xc(%rdi),%xmm5
  movss  0x4(%rdi),%xmm4
  movss  (%rdi),%xmm3
  movss  0x8(%rdi),%xmm2
  movaps %xmm5,%xmm0
  movss  %xmm5,0x2c(%rsp)
  movaps %xmm4,%xmm7
  mulss  %xmm5,%xmm0
  movaps %xmm3,%xmm1
  movaps %xmm2,%xmm6
  movss  %xmm4,0x24(%rsp)
  mulss  %xmm4,%xmm7
  movss  %xmm3,0x20(%rsp)
  mulss  %xmm2,%xmm6
  movss  %xmm2,0x1c(%rsp)
  mulss  %xmm3,%xmm1
  movss  %xmm0,0x18(%rsp)
  movaps %xmm4,%xmm0
  mulss  %xmm5,%xmm0
  movaps %xmm3,%xmm5
  movss  %xmm7,0x10(%rsp)
  mulss  %xmm2,%xmm5
  movss  %xmm6,0x14(%rsp)
  movss  %xmm1,0xc(%rsp)
  subss  %xmm5,%xmm0
  addss  %xmm0,%xmm0
  xorps  D6(%rip),%xmm0
  call   <asinf@plt>
  movss  0x24(%rsp),%xmm4
  movss  0x1c(%rsp),%xmm2
  mulss  D22(%rip),%xmm0
  movss  0x2c(%rsp),%xmm5
  movaps %xmm4,%xmm3
  movss  %xmm2,0x24(%rsp)
  movss  0xc(%rsp),%xmm1
  addss  0x10(%rsp),%xmm1
  mulss  %xmm2,%xmm3
  subss  0x14(%rsp),%xmm1
  subss  0x18(%rsp),%xmm1
  movss  %xmm4,0x28(%rsp)
  movss  %xmm5,0x1c(%rsp)
  movss  %xmm0,0x4(%rbx)
  movaps %xmm3,%xmm0
  movss  0x20(%rsp),%xmm3
  movaps %xmm3,%xmm2
  mulss  %xmm5,%xmm2
  addss  %xmm2,%xmm0
  addss  %xmm0,%xmm0
  call   <atan2f@plt>
  movss  0x1c(%rsp),%xmm5
  movss  0x24(%rsp),%xmm2
  movss  0x20(%rsp),%xmm3
  movss  0x28(%rsp),%xmm4
  mulss  %xmm5,%xmm2
  movss  0xc(%rsp),%xmm1
  subss  0x10(%rsp),%xmm1
  mulss  %xmm4,%xmm3
  subss  0x14(%rsp),%xmm1
  addss  0x18(%rsp),%xmm1
  mulss  D22(%rip),%xmm0
  addss  %xmm3,%xmm2
  movss  %xmm0,0x8(%rbx)
  addss  %xmm2,%xmm2
  movaps %xmm2,%xmm0
  call   <atan2f@plt>
  mulss  D22(%rip),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: byte[16]
name: disassemble_data
arguments: tag: D22
data_type: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D22": [0xe0,0x2e,0x65,0x42]}

assistant: ```c
void Quaternion2RPY(const float q[4], float rpy[3]) {
  float R13, R11, R12, R23, R33;
  float q0s = q[0] * q[0];
  float q1s = q[1] * q[1];
  float q2s = q[2] * q[2];
  float q3s = q[3] * q[3];
  R13 = 2.0f * (q[1] * q[3] - q[0] * q[2]);
  R11 = q0s + q1s - q2s - q3s;
  R12 = 2.0f * (q[1] * q[2] + q[0] * q[3]);
  R23 = 2.0f * (q[2] * q[3] + q[0] * q[1]);
  R33 = q0s - q1s - q2s + q3s;
  rpy[1] = (180.0f / 3.14159265358979323846f) * asinf(-R13);
  rpy[2] = (180.0f / 3.14159265358979323846f) * atan2f(R12, R11);
  rpy[0] = (180.0f / 3.14159265358979323846f) * atan2f(R23, R33);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Quaternion2RPY>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x30,%rsp
  movss  0xc(%rdi),%xmm5
  movss  0x4(%rdi),%xmm4
  movss  (%rdi),%xmm3
  movss  0x8(%rdi),%xmm2
  movaps %xmm5,%xmm0
  movss  %xmm5,0x2c(%rsp)
  movaps %xmm4,%xmm7
  mulss  %xmm5,%xmm0
  movaps %xmm3,%xmm1
  movaps %xmm2,%xmm6
  movss  %xmm4,0x24(%rsp)
  mulss  %xmm4,%xmm7
  movss  %xmm3,0x20(%rsp)
  mulss  %xmm2,%xmm6
  movss  %xmm2,0x1c(%rsp)
  mulss  %xmm3,%xmm1
  movss  %xmm0,0x18(%rsp)
  movaps %xmm4,%xmm0
  mulss  %xmm5,%xmm0
  movaps %xmm3,%xmm5
  movss  %xmm7,0x10(%rsp)
  mulss  %xmm2,%xmm5
  movss  %xmm6,0x14(%rsp)
  movss  %xmm1,0xc(%rsp)
  subss  %xmm5,%xmm0
  addss  %xmm0,%xmm0
  xorps  D30(%rip),%xmm0
  call   <asinf@plt>
  movss  0x24(%rsp),%xmm4
  movss  0x1c(%rsp),%xmm2
  mulss  D14(%rip),%xmm0
  movss  0x2c(%rsp),%xmm5
  movaps %xmm4,%xmm3
  movss  %xmm2,0x24(%rsp)
  movss  0xc(%rsp),%xmm1
  addss  0x10(%rsp),%xmm1
  mulss  %xmm2,%xmm3
  subss  0x14(%rsp),%xmm1
  subss  0x18(%rsp),%xmm1
  movss  %xmm4,0x28(%rsp)
  movss  %xmm5,0x1c(%rsp)
  movss  %xmm0,0x4(%rbx)
  movaps %xmm3,%xmm0
  movss  0x20(%rsp),%xmm3
  movaps %xmm3,%xmm2
  mulss  %xmm5,%xmm2
  addss  %xmm2,%xmm0
  addss  %xmm0,%xmm0
  call   <atan2f@plt>
  movss  0x1c(%rsp),%xmm5
  movss  0x24(%rsp),%xmm2
  movss  0x20(%rsp),%xmm3
  movss  0x28(%rsp),%xmm4
  mulss  %xmm5,%xmm2
  movss  0xc(%rsp),%xmm1
  subss  0x10(%rsp),%xmm1
  mulss  %xmm4,%xmm3
  subss  0x14(%rsp),%xmm1
  addss  0x18(%rsp),%xmm1
  mulss  D14(%rip),%xmm0
  addss  %xmm3,%xmm2
  movss  %xmm0,0x8(%rbx)
  addss  %xmm2,%xmm2
  movaps %xmm2,%xmm0
  call   <atan2f@plt>
  mulss  D14(%rip),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
type_guessed: byte[16]
name: extract_symbolic_data
arguments: tag: D14
type_guessed: byte[4]

tool: {"D30": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D14": [0xe0,0x2e,0x65,0x42]}

assistant: ```c
void Quaternion2RPY(const float q[4], float rpy[3]) {
  float R13, R11, R12, R23, R33;
  float q0s = q[0] * q[0];
  float q1s = q[1] * q[1];
  float q2s = q[2] * q[2];
  float q3s = q[3] * q[3];
  R13 = 2.0f * (q[1] * q[3] - q[0] * q[2]);
  R11 = q0s + q1s - q2s - q3s;
  R12 = 2.0f * (q[1] * q[2] + q[0] * q[3]);
  R23 = 2.0f * (q[2] * q[3] + q[0] * q[1]);
  R33 = q0s - q1s - q2s + q3s;
  rpy[1] = (180.0f / 3.14159265358979323846f) * asinf(-R13);
  rpy[2] = (180.0f / 3.14159265358979323846f) * atan2f(R12, R11);
  rpy[0] = (180.0f / 3.14159265358979323846f) * atan2f(R23, R33);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0xd,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0xfffffff7,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x5,-0x2c(%rbp)
  jmp    L26
L19:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x2c(%rbp)
L26:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: %d 

assistant: ```c
int main() {
  int a[] = {2, 7, 13, 1, -9};
  int ctr;
  int *ptr;
  ptr = &a;
  for (ctr = 5; ctr > 0; ctr--)
    printf("%d ", *(ptr + ctr - 1));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x7,0x4(%rsp)
  movl   $0xd,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0xfffffff7,0x10(%rsp)
  mov    %rsp,%rbx
  lea    -0x14(%rsp),%r12
  lea    D4(%rip),%rbp
L11:
  mov    0x10(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L11
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D4: %d 

assistant: ```c
int main() {
  int a[] = {2, 7, 13, 1, -9};
  int ctr;
  int *ptr;
  ptr = &a;
  for (ctr = 5; ctr > 0; ctr--)
    printf("%d ", *(ptr + ctr - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x700000002,%rax
  movl   $0xfffffff7,0x10(%rsp)
  mov    %rsp,%rbx
  lea    -0x14(%rsp),%r12
  mov    %rax,(%rsp)
  movabs $0x10000000d,%rax
  mov    %rax,0x8(%rsp)
L9:
  mov    0x10(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
int main() {
  int a[] = {2, 7, 13, 1, -9};
  int ctr;
  int *ptr;
  ptr = &a;
  for (ctr = 5; ctr > 0; ctr--)
    printf("%d ", *(ptr + ctr - 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xfffffff7,0x10(%rsp)
  mov    %rsp,%rbx
  lea    -0x14(%rsp),%r12
  movaps %xmm0,(%rsp)
L10:
  mov    0x10(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L10
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: byte[16]

tool: D14: %d 

tool: {"D13": [0x02,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[] = {2, 7, 13, 1, -9};
  int ctr;
  int *ptr;
  ptr = &a;
  for (ctr = 5; ctr > 0; ctr--)
    printf("%d ", *(ptr + ctr - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ecryptfs_contains_ecryptfs_marker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <host_is_big_endian@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  cmpl   $0x0,-0xc(%rbp)
  jne    L40
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    %eax,-0x14(%rbp)
L40:
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  cmpl   $0x0,-0xc(%rbp)
  jne    L37
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    %eax,-0x10(%rbp)
L37:
  mov    -0x14(%rbp),%eax
  xor    $0x3c81b7f5,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L48
  mov    $0x1,%eax
  jmp    L18
L48:
  mov    $0x0,%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
int ecryptfs_contains_ecryptfs_marker(char *data) {
  uint32_t m_1, m_2;
  int big_endian;
  big_endian = host_is_big_endian();
  memcpy(&m_1, data, 4);
  if (!big_endian)
    m_1 = ntohl(m_1);
  memcpy(&m_2, (data + 4), 4);
  if (!big_endian)
    m_2 = ntohl(m_2);
  if ((m_1 ^ 0x3c81b7f5) == m_2)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ecryptfs_contains_ecryptfs_marker>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <host_is_big_endian@plt>
  mov    %eax,%ebp
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  test   %ebp,%ebp
  je     L8
  lea    0x4(%rbx),%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
L22:
  mov    (%rsp),%eax
  xor    $0x3c81b7f5,%eax
  cmp    0x4(%rsp),%eax
  sete   %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    (%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rbx),%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,0x4(%rsp)
  jmp    L22
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ecryptfs_contains_ecryptfs_marker(char *data) {
  uint32_t m_1, m_2;
  int big_endian;
  big_endian = host_is_big_endian();
  memcpy(&m_1, data, 4);
  if (!big_endian)
    m_1 = ntohl(m_1);
  memcpy(&m_2, (data + 4), 4);
  if (!big_endian)
    m_2 = ntohl(m_2);
  if ((m_1 ^ 0x3c81b7f5) == m_2)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ecryptfs_contains_ecryptfs_marker>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <host_is_big_endian@plt>
  mov    %rbp,%rsi
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    %eax,%r12d
  add    $0x4,%rbp
  call   <memcpy@plt>
  test   %r12d,%r12d
  je     L27
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
L3:
  mov    (%rsp),%edx
  xor    $0x3c81b7f5,%edx
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L27:
  mov    (%rsp),%edi
  call   <ntohl@plt>
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %eax,(%rsp)
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  jmp    L3
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ecryptfs_contains_ecryptfs_marker(char *data) {
  uint32_t m_1, m_2;
  int big_endian;
  big_endian = host_is_big_endian();
  memcpy(&m_1, data, 4);
  if (!big_endian)
    m_1 = ntohl(m_1);
  memcpy(&m_2, (data + 4), 4);
  if (!big_endian)
    m_2 = ntohl(m_2);
  if ((m_1 ^ 0x3c81b7f5) == m_2)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ecryptfs_contains_ecryptfs_marker>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <host_is_big_endian@plt>
  mov    %rbp,%rsi
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    %eax,%r12d
  add    $0x4,%rbp
  call   <memcpy@plt>
  test   %r12d,%r12d
  je     L29
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
L0:
  mov    (%rsp),%edx
  xor    $0x3c81b7f5,%edx
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L29:
  mov    (%rsp),%edi
  call   <ntohl@plt>
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %eax,(%rsp)
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  jmp    L0
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ecryptfs_contains_ecryptfs_marker(char *data) {
  uint32_t m_1, m_2;
  int big_endian;
  big_endian = host_is_big_endian();
  memcpy(&m_1, data, 4);
  if (!big_endian)
    m_1 = ntohl(m_1);
  memcpy(&m_2, (data + 4), 4);
  if (!big_endian)
    m_2 = ntohl(m_2);
  if ((m_1 ^ 0x3c81b7f5) == m_2)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inverseOfMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4f0,%rsp
  mov    %rdi,-0x4d8(%rbp)
  mov    %rsi,-0x4e0(%rbp)
  mov    %edx,-0x4e4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4c8(%rbp),%rcx
  lea    -0x4c0(%rbp),%rdx
  mov    -0x4e4(%rbp),%esi
  mov    -0x4d8(%rbp),%rax
  mov    %rax,%rdi
  call   <luDecomposition@plt>
  movl   $0x1,-0x4cc(%rbp)
  jmp    L47
L57:
  movl   $0x1,-0x4d0(%rbp)
  jmp    L28
L37:
  mov    -0x4d0(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x330(%rbp,%rax,8)
  addl   $0x1,-0x4d0(%rbp)
L28:
  mov    -0x4d0(%rbp),%eax
  cmp    -0x4e4(%rbp),%eax
  jle    L37
  mov    -0x4cc(%rbp),%eax
  cltq
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x330(%rbp,%rax,8)
  lea    -0x330(%rbp),%rcx
  lea    -0x4c0(%rbp),%rdx
  mov    -0x4e4(%rbp),%esi
  mov    -0x4d8(%rbp),%rax
  mov    %rax,%rdi
  call   <lubksb@plt>
  movl   $0x1,-0x4d0(%rbp)
  jmp    L49
L16:
  mov    -0x4d0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x4e0(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4d0(%rbp),%eax
  cltq
  movsd  -0x330(%rbp,%rax,8),%xmm0
  mov    -0x4cc(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x4d0(%rbp)
L49:
  mov    -0x4d0(%rbp),%eax
  cmp    -0x4e4(%rbp),%eax
  jle    L16
  addl   $0x1,-0x4cc(%rbp)
L47:
  mov    -0x4cc(%rbp),%eax
  cmp    -0x4e4(%rbp),%eax
  jle    L57
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: f64

tool: D7: 1

assistant: ```c
void inverseOfMatrix(double a[][100], double y[][100], int n) {
  double d, col[100];
  int i, j, indx[100];
  luDecomposition(a, n, indx, &d);
  for (j = 1; j <= n; j++) {
    for (i = 1; i <= n; i++)
      col[i] = 0.0;
    col[j] = 1.0;
    lubksb(a, n, indx, col);
    for (i = 1; i <= n; i++)
      y[i][j] = col[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inverseOfMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4d8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %r13d,%esi
  call   <luDecomposition@plt>
  test   %r13d,%r13d
  jle    L26
  lea    -0x1(%r13),%eax
  lea    0x1b0(%rsp,%rax,8),%rbp
  mov    $0x1,%r12d
L23:
  lea    0x1a8(%rsp),%rbx
  mov    %rbx,%rax
L44:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rbp,%rax
  jne    L44
  lea    0x1a0(%rsp),%rcx
  mov    D5(%rip),%rax
  mov    %rax,(%rcx,%r12,8)
  lea    0x10(%rsp),%rdx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <lubksb@plt>
  lea    (%r15,%r12,8),%rax
L45:
  movsd  (%rbx),%xmm0
  movsd  %xmm0,0x320(%rax)
  add    $0x8,%rbx
  add    $0x320,%rax
  cmp    %rbp,%rbx
  jne    L45
  add    $0x1,%r12
  cmp    %r12d,%r13d
  jge    L23
L26:
  mov    0x4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x4d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: f64

tool: D5: 1

assistant: ```c
void inverseOfMatrix(double a[][100], double y[][100], int n) {
  double d, col[100];
  int i, j, indx[100];
  luDecomposition(a, n, indx, &d);
  for (j = 1; j <= n; j++) {
    for (i = 1; i <= n; i++)
      col[i] = 0.0;
    col[j] = 1.0;
    lubksb(a, n, indx, col);
    for (i = 1; i <= n; i++)
      y[i][j] = col[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inverseOfMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x4f8,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x30(%rsp),%r15
  lea    0x28(%rsp),%rcx
  mov    %ebx,%esi
  mov    %r15,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x4e8(%rsp)
  xor    %eax,%eax
  call   <luDecomposition@plt>
  test   %ebx,%ebx
  jle    L10
  mov    %ebx,%r14d
  lea    0x1c8(%rsp),%rdi
  lea    0x1c0(%rsp),%r12
  lea    0x0(,%r14,8),%rax
  mov    %rdi,0x18(%rsp)
  mov    $0x1,%r14d
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rbx),%eax
  lea    0x1d0(%rsp,%rax,8),%rbp
  nopl   0x0(%rax)
L4:
  mov    0x10(%rsp),%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    %r13,%rdi
  mov    D0(%rip),%rax
  mov    %ebx,%esi
  mov    %rax,(%r12,%r14,8)
  call   <lubksb@plt>
  mov    0x18(%rsp),%rax
  mov    0x8(%rsp),%rcx
  mov    %rax,%rdi
  lea    (%rcx,%r14,8),%rdx
L1:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  add    $0x320,%rdx
  movsd  %xmm0,(%rdx)
  cmp    %rbp,%rax
  jne    L1
  add    $0x1,%r14
  cmp    %r14d,%ebx
  jge    L4
L10:
  mov    0x4e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x4f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type: f64

tool: D0: 1

assistant: ```c
void inverseOfMatrix(double a[][100], double y[][100], int n) {
  double d, col[100];
  int i, j, indx[100];
  luDecomposition(a, n, indx, &d);
  for (j = 1; j <= n; j++) {
    for (i = 1; i <= n; i++)
      col[i] = 0.0;
    col[j] = 1.0;
    lubksb(a, n, indx, col);
    for (i = 1; i <= n; i++)
      y[i][j] = col[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inverseOfMatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %r14d,%esi
  push   %rbx
  sub    $0x508,%rsp
  mov    %rdi,0x10(%rsp)
  lea    0x38(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x4f8(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rax
  mov    %rax,%rdx
  mov    %rax,0x18(%rsp)
  call   <luDecomposition@plt>
  test   %r14d,%r14d
  jle    L45
  movslq %r14d,%rax
  mov    $0x1,%r15d
  lea    0x328(%rbp),%r10
  shl    $0x3,%rax
  lea    0x1d8(%rsp),%r8
  lea    0x1d0(%rsp),%r13
  mov    %r10,%r9
  mov    %rax,0x20(%rsp)
  mov    %r14d,%eax
  shr    %eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x1e8(%rsp,%rax,1),%r12
  mov    %r14d,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x28(%rsp)
  mov    %r14d,%eax
  or     $0x1,%eax
  mov    %eax,0x2c(%rsp)
  mov    %r14d,%eax
  mov    %r15,%r14
  mov    %eax,%r15d
  nopl   0x0(%rax,%rax,1)
L38:
  mov    0x20(%rsp),%rdx
  mov    %r8,%rdi
  xor    %esi,%esi
  mov    %r9,0x8(%rsp)
  mov    %r8,(%rsp)
  movslq %r14d,%rbx
  call   <memset@plt>
  mov    0x18(%rsp),%rdx
  mov    %r13,%rcx
  mov    %r15d,%esi
  mov    D9(%rip),%rax
  mov    0x10(%rsp),%rdi
  mov    %rax,0x0(%r13,%r14,8)
  call   <lubksb@plt>
  cmp    $0x1,%r15d
  mov    (%rsp),%r8
  mov    0x8(%rsp),%r9
  je     L50
  mov    %r8,%rdx
  mov    %r9,%rax
  nopl   (%rax)
L57:
  movupd (%rdx),%xmm0
  add    $0x10,%rdx
  add    $0x640,%rax
  movlpd %xmm0,-0x640(%rax)
  movhpd %xmm0,-0x320(%rax)
  cmp    %r12,%rdx
  jne    L57
  cmp    0x28(%rsp),%r15d
  je     L47
  movslq 0x2c(%rsp),%rdx
L8:
  movsd  0x1d0(%rsp,%rdx,8),%xmm0
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x5,%rax
  add    %rbp,%rax
  movsd  %xmm0,(%rax,%rbx,8)
L47:
  add    $0x1,%r14
  add    $0x8,%r9
  cmp    %r14d,%r15d
  jge    L38
L45:
  mov    0x4f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x508,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  mov    $0x1,%edx
  jmp    L8
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: f64

tool: D9: 1

assistant: ```c
void inverseOfMatrix(double a[][100], double y[][100], int n) {
  double d, col[100];
  int i, j, indx[100];
  luDecomposition(a, n, indx, &d);
  for (j = 1; j <= n; j++) {
    for (i = 1; i <= n; i++)
      col[i] = 0.0;
    col[j] = 1.0;
    lubksb(a, n, indx, col);
    for (i = 1; i <= n; i++)
      y[i][j] = col[i];
  }
}
```