ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L22
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L22:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xea68efb,%esi
  je     L38
L4:
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L38:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L4
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D24
type: string
name: unpack_data
arguments: label: D13
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D24: Call this program with %i arguments


tool: D13: %u


tool: D11: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 245796603U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L22
  lea    D14(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L22:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xea68efb,%esi
  je     L4
L18:
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L18
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string

tool: D14: Call this program with %i arguments


tool: D5: %u


tool: D4: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 245796603U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x61,0x4(%rsp)
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D15(%rip),%r13
  mov    %r13,%rdi
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  movsbl 0x5(%rsp),%edx
  movsbl 0x4(%rsp),%esi
  movsbl 0x7(%rsp),%r8d
  lea    D28(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D40(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movb   $0x5a,0x4(%rsp)
  movb   $0x65,0x5(%rsp)
  movb   $0x64,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    $0x38,%r8d
  mov    $0x37,%ecx
  mov    $0x36,%edx
  mov    $0x35,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  movsbl 0x5(%rsp),%edx
  movsbl 0x4(%rsp),%esi
  movsbl 0x7(%rsp),%r8d
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D18(%rip),%rbx
  mov    %rbx,%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D40
datatype: string
name: retrieve_data
arguments: label: D18
datatype: string
name: retrieve_data
arguments: label: D30
datatype: string
name: retrieve_data
arguments: label: D38
datatype: string

tool: D15: numbers: %d %d %d %d


tool: D28: name each: %c %c %c %c


tool: D40: name: %s


tool: D18: Zed

tool: D30: another: %s


tool: D38: another each: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int numbers[4] = {0};
  char name[4] = {"a"};
  printf("numbers: %d %d %d %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c %c %c %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  numbers[0] = '5';
  numbers[1] = '6';
  numbers[2] = '7';
  numbers[3] = '8';
  name[0] = 'Z';
  name[1] = 'e';
  name[2] = 'd';
  name[3] = '\0';
  printf("numbers: %d %d %d %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c %c %c %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  char *another = "Zed";
  printf("another: %s\n", another);
  printf("another each: %s\n", another);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  lea    D35(%rip),%r14
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   %r13
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  push   %r12
  lea    D28(%rip),%r13
  push   %rbp
  lea    D8(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x61,0x4(%rsp)
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x38,%r8d
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0x37,%ecx
  mov    $0x36,%edx
  mov    $0x35,%esi
  movl   $0x64655a,0x4(%rsp)
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rbp
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D48
type_infered: string
name: retrieve_data
arguments: data_tag: D33
type_infered: string

tool: D35: numbers: %d %d %d %d


tool: D28: name each: %c %c %c %c


tool: D8: name: %s


tool: D10: Zed

tool: D48: another: %s


tool: D33: another each: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int numbers[4] = {0};
  char name[4] = {"a"};
  printf("numbers: %d %d %d %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c %c %c %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  numbers[0] = '5';
  numbers[1] = '6';
  numbers[2] = '7';
  numbers[3] = '8';
  name[0] = 'Z';
  name[1] = 'e';
  name[2] = 'd';
  name[3] = '\0';
  printf("numbers: %d %d %d %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c %c %c %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  char *another = "Zed";
  printf("another: %s\n", another);
  printf("another each: %s\n", another);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D41(%rip),%r14
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   %r13
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  push   %r12
  lea    D8(%rip),%r13
  push   %rbp
  lea    D57(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x61,0x4(%rsp)
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x38,%r8d
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0x37,%ecx
  mov    $0x36,%edx
  mov    $0x35,%esi
  movl   $0x64655a,0x4(%rsp)
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D50(%rip),%rbp
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D41
data_type: string
name: retrieve_data
arguments: data_label: D8
data_type: string
name: retrieve_data
arguments: data_label: D57
data_type: string
name: retrieve_data
arguments: data_label: D50
data_type: string
name: retrieve_data
arguments: data_label: D56
data_type: string
name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D41: numbers: %d %d %d %d


tool: D8: name each: %c %c %c %c


tool: D57: name: %s


tool: D50: Zed

tool: D56: another: %s


tool: D7: another each: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int numbers[4] = {0};
  char name[4] = {"a"};
  printf("numbers: %d %d %d %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c %c %c %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  numbers[0] = '5';
  numbers[1] = '6';
  numbers[2] = '7';
  numbers[3] = '8';
  name[0] = 'Z';
  name[1] = 'e';
  name[2] = 'd';
  name[3] = '\0';
  printf("numbers: %d %d %d %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c %c %c %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  char *another = "Zed";
  printf("another: %s\n", another);
  printf("another each: %s\n", another);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fc8150_i2c_deinit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x13,%esi
  mov    %rax,%rdi
  call   <bbm_write@plt>
  mov    $0x0,%eax
  call   <OAL_DELETE_SEMAPHORE@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fc8150_i2c_deinit(void *hDevice) {
  bbm_write(hDevice, 0x0013, 0x00);
  OAL_DELETE_SEMAPHORE();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fc8150_i2c_deinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x13,%esi
  call   <bbm_write@plt>
  mov    $0x0,%eax
  call   <OAL_DELETE_SEMAPHORE@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fc8150_i2c_deinit(void *hDevice) {
  bbm_write(hDevice, 0x0013, 0x00);
  OAL_DELETE_SEMAPHORE();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fc8150_i2c_deinit>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x13,%esi
  call   <bbm_write@plt>
  xor    %eax,%eax
  call   <OAL_DELETE_SEMAPHORE@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fc8150_i2c_deinit(void *hDevice) {
  bbm_write(hDevice, 0x0013, 0x00);
  OAL_DELETE_SEMAPHORE();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<fc8150_i2c_deinit>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x13,%esi
  call   <bbm_write@plt>
  xor    %eax,%eax
  call   <OAL_DELETE_SEMAPHORE@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fc8150_i2c_deinit(void *hDevice) {
  bbm_write(hDevice, 0x0013, 0x00);
  OAL_DELETE_SEMAPHORE();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ps001s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <xaxis@plt>
  mov    $0x0,%eax
  call   <yaxis@plt>
  mov    $0x0,%eax
  call   <zaxis@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ps001s() {
#pragma omp parallel sections
  {
#pragma omp section
    xaxis();
#pragma omp section
    yaxis();
#pragma omp section
    zaxis();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ps001s>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <xaxis@plt>
  mov    $0x0,%eax
  call   <yaxis@plt>
  mov    $0x0,%eax
  call   <zaxis@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ps001s() {
#pragma omp parallel sections
  {
#pragma omp section
    xaxis();
#pragma omp section
    yaxis();
#pragma omp section
    zaxis();
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ps001s>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <xaxis@plt>
  xor    %eax,%eax
  call   <yaxis@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <zaxis@plt>
```

assistant: ```c
void ps001s() {
#pragma omp parallel sections
  {
#pragma omp section
    xaxis();
#pragma omp section
    yaxis();
#pragma omp section
    zaxis();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ps001s>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <xaxis@plt>
  xor    %eax,%eax
  call   <yaxis@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <zaxis@plt>
```

assistant: ```c
void ps001s() {
#pragma omp parallel sections
  {
#pragma omp section
    xaxis();
#pragma omp section
    yaxis();
#pragma omp section
    zaxis();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Bsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L6
L61:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L12
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L6
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L46
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L6
L46:
  mov    -0x4(%rbp),%eax
  jmp    L51
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L61
L51:
  pop    %rbp
  ret
```

assistant: ```c
int Bsearch(int ara[], int n, int x) {
  int mid, low, high, index;
  low = 0, high = n;
  while (low <= high) {
    mid = (low + high) / 2;
    if (x < ara[mid]) {
      high = mid - 1;
    } else if (x > ara[mid]) {
      low = mid + 1;
    } else
      return mid;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Bsearch>:
  endbr64
  test   %esi,%esi
  js     L48
  mov    $0x0,%r8d
  jmp    L36
L35:
  jge    L48
  lea    0x1(%rax),%r8d
L21:
  cmp    %esi,%r8d
  jg     L48
L36:
  lea    (%r8,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %edx,%ecx
  jle    L35
  lea    -0x1(%rax),%esi
  jmp    L21
L48:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int Bsearch(int ara[], int n, int x) {
  int mid, low, high, index;
  low = 0, high = n;
  while (low <= high) {
    mid = (low + high) / 2;
    if (x < ara[mid]) {
      high = mid - 1;
    } else if (x > ara[mid]) {
      low = mid + 1;
    } else
      return mid;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Bsearch>:
  endbr64
  test   %esi,%esi
  js     L38
  xor    %ecx,%ecx
  jmp    L10
  nopl   0x0(%rax)
L30:
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jl     L38
L10:
  lea    (%rcx,%rsi,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  jg     L30
  jge    L38
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jge    L10
L38:
  ret
```

assistant: ```c
int Bsearch(int ara[], int n, int x) {
  int mid, low, high, index;
  low = 0, high = n;
  while (low <= high) {
    mid = (low + high) / 2;
    if (x < ara[mid]) {
      high = mid - 1;
    } else if (x > ara[mid]) {
      low = mid + 1;
    } else
      return mid;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Bsearch>:
  endbr64
  test   %esi,%esi
  js     L0
  xor    %ecx,%ecx
  jmp    L30
  nopl   0x0(%rax)
L29:
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jl     L0
L30:
  lea    (%rcx,%rsi,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  jg     L29
  jge    L0
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jge    L30
L0:
  ret
```

assistant: ```c
int Bsearch(int ara[], int n, int x) {
  int mid, low, high, index;
  low = 0, high = n;
  while (low <= high) {
    mid = (low + high) / 2;
    if (x < ara[mid]) {
      high = mid - 1;
    } else if (x > ara[mid]) {
      low = mid + 1;
    } else
      return mid;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mapcon_coefficients_of_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x48(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1b4,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int mapcon_coefficients_of_map(int dim, int ind, int nvr, double *cff) {
  int a[3], *b, fail;
  a[0] = dim;
  a[1] = ind;
  a[2] = nvr;
  fail = _ada_use_c2phc(436, a, b, cff);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mapcon_coefficients_of_map>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0xc(%rsp)
  mov    %esi,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x0,%edx
  mov    $0x1b4,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mapcon_coefficients_of_map(int dim, int ind, int nvr, double *cff) {
  int a[3], *b, fail;
  a[0] = dim;
  a[1] = ind;
  a[2] = nvr;
  fail = _ada_use_c2phc(436, a, b, cff);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mapcon_coefficients_of_map>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0xc(%rsp)
  mov    $0x1b4,%edi
  mov    %esi,0x10(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %edx,0x14(%rsp)
  xor    %edx,%edx
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mapcon_coefficients_of_map(int dim, int ind, int nvr, double *cff) {
  int a[3], *b, fail;
  a[0] = dim;
  a[1] = ind;
  a[2] = nvr;
  fail = _ada_use_c2phc(436, a, b, cff);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mapcon_coefficients_of_map>:
  endbr64
  sub    $0x28,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  mov    $0x1b4,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  punpckldq %xmm1,%xmm0
  mov    %edx,0x10(%rsp)
  lea    0x8(%rsp),%rsi
  xor    %edx,%edx
  movq   %xmm0,0x8(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mapcon_coefficients_of_map(int dim, int ind, int nvr, double *cff) {
  int a[3], *b, fail;
  a[0] = dim;
  a[1] = ind;
  a[2] = nvr;
  fail = _ada_use_c2phc(436, a, b, cff);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_dir_is_not_recognized_as_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <is_dir@plt>
  mov    %eax,%ecx
  mov    $0xe,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  mov    $0x0,%eax
  call   <seatest_assert_true@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string

tool: D0: test-data/existing-files

tool: D8: test_dir_is_not_recognized_as_dir

assistant: ```c
void test_dir_is_not_recognized_as_dir(void) {
  do {
    seatest_assert_true(is_dir("test-data/existing-files"), __FUNCTION__, 14);
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_dir_is_not_recognized_as_dir>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <is_dir@plt>
  mov    %eax,%edi
  mov    $0xe,%edx
  lea    D17(%rip),%rsi
  mov    $0x0,%eax
  call   <seatest_assert_true@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D11: test-data/existing-files

tool: D17: test_dir_is_not_recognized_as_dir

assistant: ```c
void test_dir_is_not_recognized_as_dir(void) {
  do {
    seatest_assert_true(is_dir("test-data/existing-files"), __FUNCTION__, 14);
  } while (0);
}
```