ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fix_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  and    $0xc0,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%eax
  sar    $0x6,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L54
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0xc(%rbp)
L54:
  mov    -0xc(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L49
  addl   $0x5,-0x8(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  addl   $0x5,-0x8(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  add    $0x24,%rax
  mov    (%rax),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x24(%rax),%eax
  mov    %eax,-0x4(%rbp)
L15:
  cmpl   $0x0,-0x4(%rbp)
  je     L17
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x9,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xff,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  jmp    L14
L17:
  nop
L14:
  leave
  ret
```

assistant: ```c
void fix_header(uint8_t *header_buffer) {
  header_buffer[7] = header_buffer[7] & 0xC0;
  int pts_dts_flag = (header_buffer[7] >> 6);
  int skip_size = 0;
  if (pts_dts_flag == 1) {
    header_buffer[7] = 0;
    pts_dts_flag = 0;
  }
  if (pts_dts_flag & 2)
    skip_size += 5;
  if (pts_dts_flag & 1)
    skip_size += 5;
  int clear_size = header_buffer[9] - skip_size;
  if (clear_size < 0) {
    header_buffer[7] = 0;
    skip_size = 0;
    clear_size = header_buffer[9];
  }
  if (clear_size == 0)
    return;
  memset(header_buffer + 9 + skip_size, 0xFF, clear_size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fix_header>:
  endbr64
  mov    0x1c(%rdi),%edx
  and    $0xc0,%edx
  mov    %edx,%ecx
  sar    $0x6,%ecx
  cmp    $0x40,%edx
  je     L4
  mov    %ecx,%eax
  and    $0x2,%eax
  mov    $0x5,%esi
  cmovne %esi,%eax
  lea    0x5(%rax),%esi
  test   $0x1,%cl
  cmovne %esi,%eax
L9:
  mov    0x24(%rdi),%ecx
  mov    %ecx,%esi
  sub    %eax,%esi
  cmovns %esi,%ecx
  mov    $0x0,%r8d
  cmovs  %r8d,%edx
  mov    $0x0,%esi
  cmovs  %esi,%eax
  mov    %edx,0x1c(%rdi)
  test   %ecx,%ecx
  jne    L8
  ret
L4:
  mov    $0x0,%edx
  mov    $0x0,%eax
  jmp    L9
L8:
  sub    $0x8,%rsp
  add    $0x9,%eax
  cltq
  lea    (%rdi,%rax,4),%rdi
  mov    %ecx,%edx
  mov    $0xff,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fix_header(uint8_t *header_buffer) {
  header_buffer[7] = header_buffer[7] & 0xC0;
  int pts_dts_flag = (header_buffer[7] >> 6);
  int skip_size = 0;
  if (pts_dts_flag == 1) {
    header_buffer[7] = 0;
    pts_dts_flag = 0;
  }
  if (pts_dts_flag & 2)
    skip_size += 5;
  if (pts_dts_flag & 1)
    skip_size += 5;
  int clear_size = header_buffer[9] - skip_size;
  if (clear_size < 0) {
    header_buffer[7] = 0;
    skip_size = 0;
    clear_size = header_buffer[9];
  }
  if (clear_size == 0)
    return;
  memset(header_buffer + 9 + skip_size, 0xFF, clear_size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fix_header>:
  endbr64
  mov    0x1c(%rdi),%eax
  and    $0xc0,%eax
  mov    %eax,%edx
  mov    %eax,0x1c(%rdi)
  sar    $0x6,%edx
  cmp    $0x40,%eax
  je     L48
  mov    %edx,%eax
  mov    $0x5,%ecx
  and    $0x2,%eax
  cmovne %ecx,%eax
  and    $0x1,%edx
  lea    0x5(%rax),%ecx
  cmovne %ecx,%eax
L3:
  mov    0x24(%rdi),%edx
  mov    %edx,%esi
  sub    %eax,%esi
  js     L39
  mov    0x1c(%rdi),%ecx
  mov    %esi,%edx
L2:
  mov    %ecx,0x1c(%rdi)
  test   %edx,%edx
  jne    L8
  ret
  nopl   (%rax)
L8:
  add    $0x9,%eax
  mov    $0xff,%esi
  cltq
  lea    (%rdi,%rax,4),%rdi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L48:
  movl   $0x0,0x1c(%rdi)
  xor    %eax,%eax
  jmp    L3
```

assistant: ```c
void fix_header(uint8_t *header_buffer) {
  header_buffer[7] = header_buffer[7] & 0xC0;
  int pts_dts_flag = (header_buffer[7] >> 6);
  int skip_size = 0;
  if (pts_dts_flag == 1) {
    header_buffer[7] = 0;
    pts_dts_flag = 0;
  }
  if (pts_dts_flag & 2)
    skip_size += 5;
  if (pts_dts_flag & 1)
    skip_size += 5;
  int clear_size = header_buffer[9] - skip_size;
  if (clear_size < 0) {
    header_buffer[7] = 0;
    skip_size = 0;
    clear_size = header_buffer[9];
  }
  if (clear_size == 0)
    return;
  memset(header_buffer + 9 + skip_size, 0xFF, clear_size);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fix_header>:
  endbr64
  mov    0x1c(%rdi),%edx
  and    $0xc0,%edx
  mov    %edx,%ecx
  sar    $0x6,%ecx
  cmp    $0x40,%edx
  je     L15
  mov    %ecx,%esi
  mov    $0x5,%eax
  and    $0x2,%esi
  je     L9
  mov    $0xa,%eax
  mov    $0x5,%esi
L9:
  and    $0x1,%ecx
  cmove  %esi,%eax
L48:
  mov    0x24(%rdi),%ecx
  mov    %ecx,%r8d
  sub    %eax,%r8d
  jns    L24
  mov    %ecx,%r8d
  xor    %edx,%edx
  xor    %eax,%eax
L24:
  mov    %edx,0x1c(%rdi)
  test   %r8d,%r8d
  jne    L8
  ret
  xchg   %ax,%ax
L8:
  add    $0x9,%eax
  mov    %r8d,%edx
  mov    $0xff,%esi
  cltq
  lea    (%rdi,%rax,4),%rdi
  jmp    1050 <memset@plt>
  cs nopw 0x0(%rax,%rax,1)
L15:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
void fix_header(uint8_t *header_buffer) {
  header_buffer[7] = header_buffer[7] & 0xC0;
  int pts_dts_flag = (header_buffer[7] >> 6);
  int skip_size = 0;
  if (pts_dts_flag == 1) {
    header_buffer[7] = 0;
    pts_dts_flag = 0;
  }
  if (pts_dts_flag & 2)
    skip_size += 5;
  if (pts_dts_flag & 1)
    skip_size += 5;
  int clear_size = header_buffer[9] - skip_size;
  if (clear_size < 0) {
    header_buffer[7] = 0;
    skip_size = 0;
    clear_size = header_buffer[9];
  }
  if (clear_size == 0)
    return;
  memset(header_buffer + 9 + skip_size, 0xFF, clear_size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <uname@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D40
type_guessed: string
name: extract_symbolic_data
arguments: label: D13
type_guessed: string
name: extract_symbolic_data
arguments: label: D44
type_guessed: string
name: extract_symbolic_data
arguments: label: D31
type_guessed: string

tool: D23: os name is %s


tool: D40: node name is %s


tool: D13: release is %s


tool: D44: version is %s


tool: D31: machine is %s


assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname utsn;
  uname(&utsn);
  printf("os name is %s\n", utsn.sysname);
  printf("node name is %s\n", utsn.nodename);
  printf("release is %s\n", utsn.release);
  printf("version is %s\n", utsn.version);
  printf("machine is %s\n", utsn.machine);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  mov    (%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string
name: extract_symbolic_data
arguments: data_tag: D45
type: string
name: extract_symbolic_data
arguments: data_tag: D35
type: string
name: extract_symbolic_data
arguments: data_tag: D40
type: string

tool: D27: os name is %s


tool: D17: node name is %s


tool: D45: release is %s


tool: D35: version is %s


tool: D40: machine is %s


assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname utsn;
  uname(&utsn);
  printf("os name is %s\n", utsn.sysname);
  printf("node name is %s\n", utsn.nodename);
  printf("release is %s\n", utsn.release);
  printf("version is %s\n", utsn.version);
  printf("machine is %s\n", utsn.machine);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  mov    (%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D34
type_infered: string
name: unpack_data
arguments: label: D41
type_infered: string
name: unpack_data
arguments: label: D47
type_infered: string
name: unpack_data
arguments: label: D24
type_infered: string

tool: D2: os name is %s


tool: D34: node name is %s


tool: D41: release is %s


tool: D47: version is %s


tool: D24: machine is %s


assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname utsn;
  uname(&utsn);
  printf("os name is %s\n", utsn.sysname);
  printf("node name is %s\n", utsn.nodename);
  printf("release is %s\n", utsn.release);
  printf("version is %s\n", utsn.version);
  printf("machine is %s\n", utsn.machine);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <uname@plt>
  mov    (%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D41
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D42
type_guessed: string

tool: D15: os name is %s


tool: D41: node name is %s


tool: D1: release is %s


tool: D18: version is %s


tool: D42: machine is %s


assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname utsn;
  uname(&utsn);
  printf("os name is %s\n", utsn.sysname);
  printf("node name is %s\n", utsn.nodename);
  printf("release is %s\n", utsn.release);
  printf("version is %s\n", utsn.version);
  printf("machine is %s\n", utsn.machine);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vdprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int dprintf(int fd, const char *restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vdprintf(fd, format, ap);
  va_end(ap);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <vdprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int dprintf(int fd, const char *restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vdprintf(fd, format, ap);
  va_end(ap);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <vdprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int dprintf(int fd, const char *restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vdprintf(fd, format, ap);
  va_end(ap);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <vdprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int dprintf(int fd, const char *restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vdprintf(fd, format, ap);
  va_end(ap);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <myvararg@plt>
  cmp    $0xa,%eax
  je     L11
  mov    $0x1,%eax
  jmp    L9
L11:
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: 1234

assistant: ```c
int main() {
  if (10 != myvararg("1234", 1, 2, 3, 4))
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <myvararg@plt>
  cmp    $0xa,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: 1234

assistant: ```c
int main() {
  if (10 != myvararg("1234", 1, 2, 3, 4))
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D0(%rip),%rdi
  call   <myvararg@plt>
  cmp    $0xa,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: 1234

assistant: ```c
int main() {
  if (10 != myvararg("1234", 1, 2, 3, 4))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <myvararg@plt>
  cmp    $0xa,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: 1234

assistant: ```c
int main() {
  if (10 != myvararg("1234", 1, 2, 3, 4))
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_LZ_WriteVarSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x5,-0xc(%rbp)
  jmp    L1
L7:
  mov    -0x10(%rbp),%eax
  and    $0xfe000000,%eax
  test   %eax,%eax
  jne    L19
  shll   $0x7,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L1:
  cmpl   $0x1,-0xc(%rbp)
  jg     L7
  jmp    L57
L19:
  nop
L57:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L62
L10:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0x7f,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L65
  orl    $0x80,-0x4(%rbp)
L65:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x8(%rbp)
L62:
  cmpl   $0x0,-0x8(%rbp)
  jns    L10
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _LZ_WriteVarSize(unsigned int x, unsigned char *buf) {
  unsigned int y;
  int num_bytes, i, b;
  y = x >> 3;
  for (num_bytes = 5; num_bytes >= 2; --num_bytes) {
    if (y & 0xfe000000)
      break;
    y <<= 7;
  }
  for (i = num_bytes - 1; i >= 0; --i) {
    b = (x >> (i * 7)) & 0x0000007f;
    if (i > 0) {
      b |= 0x00000080;
    }
    *buf++ = (unsigned char)b;
  }
  return num_bytes;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_LZ_WriteVarSize>:
  endbr64
  mov    %edi,%r8d
  mov    %edi,%eax
  shr    $0x3,%eax
  test   $0xfe000000,%eax
  jne    L31
  mov    %eax,%edx
  shl    $0x7,%edx
  test   $0xfe000000,%edx
  jne    L115
  mov    %eax,%edx
  shl    $0xe,%edx
  test   $0xfe000000,%edx
  jne    L54
  shl    $0x15,%eax
  test   $0xfe000000,%eax
  jne    L90
  mov    $0x1,%r9d
  mov    $0x0,%edx
L102:
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  add    $0x1,%rsi
  sub    $0x1,%edx
  jmp    L71
L115:
  mov    $0x4,%r9d
  jmp    L63
L54:
  mov    $0x3,%r9d
  jmp    L63
L90:
  mov    $0x2,%r9d
  jmp    L63
L10:
  mov    %al,-0x1(%rsi)
  test   %edx,%edx
  js     L83
L105:
  sub    $0x7,%ecx
  add    $0x1,%rsi
  sub    $0x1,%edx
L71:
  mov    %r8d,%eax
  shr    %cl,%eax
  and    $0x7f,%eax
  lea    0x1(%rdx),%edi
  test   %edi,%edi
  jle    L10
  or     $0x80,%al
  mov    %al,-0x1(%rsi)
  jmp    L105
L31:
  mov    $0x5,%r9d
L63:
  lea    -0x1(%r9),%edx
  jmp    L102
L83:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int _LZ_WriteVarSize(unsigned int x, unsigned char *buf) {
  unsigned int y;
  int num_bytes, i, b;
  y = x >> 3;
  for (num_bytes = 5; num_bytes >= 2; --num_bytes) {
    if (y & 0xfe000000)
      break;
    y <<= 7;
  }
  for (i = num_bytes - 1; i >= 0; --i) {
    b = (x >> (i * 7)) & 0x0000007f;
    if (i > 0) {
      b |= 0x00000080;
    }
    *buf++ = (unsigned char)b;
  }
  return num_bytes;
}
```
user: What is the c source code of the assembly code below:

```asm
<_LZ_WriteVarSize>:
  endbr64
  mov    %edi,%eax
  mov    $0x5,%r8d
  shr    $0x3,%eax
L23:
  mov    %r8d,%edx
  sub    $0x1,%r8d
  test   $0xfe000000,%eax
  jne    L19
  shl    $0x7,%eax
  cmp    $0x1,%r8d
  jne    L23
  xor    %eax,%eax
L40:
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edi,%eax
  shr    %cl,%eax
  and    $0x7f,%eax
  test   %ecx,%ecx
  je     L3
L0:
  or     $0x80,%al
  sub    $0x7,%ecx
  add    $0x1,%rsi
  mov    %al,-0x1(%rsi)
  mov    %edi,%eax
  shr    %cl,%eax
  and    $0x7f,%eax
  test   %ecx,%ecx
  jne    L0
L3:
  mov    %al,(%rsi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L19:
  mov    %r8d,%eax
  mov    %edx,%r8d
  jmp    L40
```

assistant: ```c
int _LZ_WriteVarSize(unsigned int x, unsigned char *buf) {
  unsigned int y;
  int num_bytes, i, b;
  y = x >> 3;
  for (num_bytes = 5; num_bytes >= 2; --num_bytes) {
    if (y & 0xfe000000)
      break;
    y <<= 7;
  }
  for (i = num_bytes - 1; i >= 0; --i) {
    b = (x >> (i * 7)) & 0x0000007f;
    if (i > 0) {
      b |= 0x00000080;
    }
    *buf++ = (unsigned char)b;
  }
  return num_bytes;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_LZ_WriteVarSize>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdx
  shr    $0x3,%eax
  test   $0x1e000000,%eax
  jne    L63
  mov    %eax,%ecx
  shl    $0x7,%ecx
  and    $0xfe000000,%ecx
  jne    L83
  mov    %eax,%ecx
  shl    $0xe,%ecx
  and    $0xfe000000,%ecx
  jne    L72
  shl    $0x15,%eax
  test   $0xfe000000,%eax
  mov    %edi,%eax
  jne    L38
  and    $0x7f,%eax
  mov    $0x1,%r9d
L86:
  mov    %al,(%rdx)
  mov    %r9d,%eax
  ret
L83:
  mov    %edi,%eax
  mov    $0x3,%r8d
  mov    $0x15,%esi
  mov    $0x4,%r9d
  shr    $0x15,%eax
L16:
  or     $0x80,%al
  lea    -0x7(%rsi),%ecx
  lea    0x2(%rdx),%r10
  mov    %al,(%rdx)
  mov    %edi,%eax
  shr    %cl,%eax
  lea    -0xe(%rsi),%ecx
  and    $0x7f,%eax
  or     $0x80,%al
  mov    %al,0x1(%rdx)
  mov    %edi,%eax
  shr    %cl,%eax
  and    $0x7f,%eax
  sub    $0x2,%r8d
  je     L65
  or     $0x80,%al
  lea    -0x15(%rsi),%ecx
  lea    0x3(%rdx),%r10
  mov    %al,0x2(%rdx)
  mov    %edi,%eax
  shr    %cl,%eax
  and    $0x7f,%eax
  cmp    $0x1,%r8d
  je     L65
  or     $0x80,%al
  lea    -0x1c(%rsi),%ecx
  add    $0x4,%rdx
  mov    %al,-0x1(%rdx)
  mov    %edi,%eax
  shr    %cl,%eax
  and    $0x7f,%eax
  mov    %al,(%rdx)
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L65:
  mov    %r10,%rdx
  mov    %al,(%rdx)
  mov    %r9d,%eax
  ret
L72:
  mov    %edi,%eax
  mov    $0x2,%r8d
  mov    $0xe,%esi
  mov    $0x3,%r9d
  shr    $0xe,%eax
  and    $0x7f,%eax
  jmp    L16
L38:
  shr    $0x7,%eax
  add    $0x1,%rdx
  mov    $0x2,%r9d
  and    $0x7f,%eax
  or     $0x80,%al
  mov    %al,(%rsi)
  mov    %edi,%eax
  and    $0x7f,%eax
  jmp    L86
L63:
  mov    %edi,%eax
  mov    $0x4,%r8d
  mov    $0x1c,%esi
  mov    $0x5,%r9d
  shr    $0x1c,%eax
  jmp    L16
```

assistant: ```c
int _LZ_WriteVarSize(unsigned int x, unsigned char *buf) {
  unsigned int y;
  int num_bytes, i, b;
  y = x >> 3;
  for (num_bytes = 5; num_bytes >= 2; --num_bytes) {
    if (y & 0xfe000000)
      break;
    y <<= 7;
  }
  for (i = num_bytes - 1; i >= 0; --i) {
    b = (x >> (i * 7)) & 0x0000007f;
    if (i > 0) {
      b |= 0x00000080;
    }
    *buf++ = (unsigned char)b;
  }
  return num_bytes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<v4l2_set_control>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%eax
  call   <init@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <x_set_control@plt>
  leave
  ret
```

assistant: ```c
int v4l2_set_control(int fd, int id, int val) {
  init();
  return x_set_control(fd, id, val);
}
```