user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<radb2>:
  endbr64
  push   %r15
  mov    %edi,%r9d
  mov    %esi,%r10d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,-0x10(%rsp)
  test   %esi,%esi
  jle    L87
  lea    (%rdi,%rdi,1),%ecx
  movslq %edi,%r11
  mov    %esi,%edi
  mov    -0x10(%rsp),%rax
  imul   %r9d,%edi
  movslq %ecx,%rcx
  shl    $0x3,%r11
  mov    %r14,%rdx
  shl    $0x3,%rcx
  xor    %esi,%esi
  movslq %edi,%rdi
  nopl   0x0(%rax)
L10:
  movsd  (%rax),%xmm0
  addsd  -0x8(%rax,%rcx,1),%xmm0
  add    $0x1,%esi
  movsd  %xmm0,(%rdx)
  movsd  (%rax),%xmm0
  subsd  -0x8(%rax,%rcx,1),%xmm0
  add    %rcx,%rax
  movsd  %xmm0,(%rdx,%rdi,8)
  add    %r11,%rdx
  cmp    %esi,%r10d
  jne    L10
L87:
  cmp    $0x1,%r9d
  jle    L98
  cmp    $0x2,%r9d
  je     L63
  mov    %r9d,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  test   %r10d,%r10d
  jle    L98
  mov    %r10d,%eax
  lea    (%r9,%r9,1),%r13d
  movslq %r9d,%r11
  mov    -0x10(%rsp),%rbx
  imul   %r9d,%eax
  movslq %r13d,%r13
  mov    %r14,%rdi
  xor    %ebp,%ebp
  shl    $0x3,%r13
  lea    0x0(,%r11,8),%r12
  lea    -0x18(%r13),%r15
  cltq
  lea    (%r14,%rax,8),%rsi
  nopl   0x0(%rax,%rax,1)
L78:
  lea    (%r15,%rbx,1),%rcx
  mov    %rbx,%rdx
  mov    $0x2,%eax
  nopl   0x0(%rax)
L50:
  movsd  0x8(%rdx),%xmm0
  addsd  (%rcx),%xmm0
  add    $0x10,%rdx
  sub    $0x10,%rcx
  movsd  %xmm0,-0x8(%rdi,%rax,8)
  movsd  (%rdx),%xmm0
  subsd  0x18(%rcx),%xmm0
  movsd  -0x8(%rdx),%xmm1
  subsd  0x10(%rcx),%xmm1
  movsd  %xmm0,(%rdi,%rax,8)
  movsd  (%rdx),%xmm0
  addsd  0x18(%rcx),%xmm0
  movsd  -0x10(%r8,%rax,8),%xmm2
  movsd  -0x8(%r8,%rax,8),%xmm3
  mulsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm2
  movsd  %xmm2,-0x8(%rsi,%rax,8)
  mulsd  -0x10(%r8,%rax,8),%xmm0
  mulsd  -0x8(%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x2,%rax
  cmp    %eax,%r9d
  jg     L50
  add    $0x1,%ebp
  add    %r13,%rbx
  add    %r12,%rdi
  add    %r12,%rsi
  cmp    %ebp,%r10d
  jne    L78
  mov    -0x4(%rsp),%eax
  test   %eax,%eax
  jne    L98
L28:
  lea    (%r9,%r9,1),%esi
  mov    -0x10(%rsp),%rax
  shl    $0x3,%r11
  xor    %ecx,%ecx
  imul   %r10d,%r9d
  movslq %esi,%rsi
  lea    -0x8(%r14,%r11,1),%rdx
  movsd  D1(%rip),%xmm1
  shl    $0x3,%rsi
  add    %r11,%rax
  movslq %r9d,%rdi
  nopw   0x0(%rax,%rax,1)
L19:
  movsd  -0x8(%rax),%xmm0
  add    $0x1,%ecx
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  (%rax),%xmm0
  add    %rsi,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rdi,8)
  add    %r11,%rdx
  cmp    %ecx,%r10d
  jg     L19
L98:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  test   %r10d,%r10d
  jle    L98
  mov    $0x2,%r11d
  jmp    L28
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
void radb2(int ido, int l1, const double cc[], double ch[], const double wa1[]) {
  int i, k, ic;
  double ti2, tr2;
  for (k = 0; k < l1; k++) {
    ch[k * ido] = cc[2 * k * ido] + cc[ido - 1 + (2 * k + 1) * ido];
    ch[(k + l1) * ido] = cc[2 * k * ido] - cc[ido - 1 + (2 * k + 1) * ido];
  }
  if (ido < 2)
    return;
  if (ido != 2) {
    for (k = 0; k < l1; ++k) {
      for (i = 2; i < ido; i += 2) {
        ic = ido - i;
        ch[i - 1 + k * ido] = cc[i - 1 + 2 * k * ido] + cc[ic - 1 + (2 * k + 1) * ido];
        tr2 = cc[i - 1 + 2 * k * ido] - cc[ic - 1 + (2 * k + 1) * ido];
        ch[i + k * ido] = cc[i + 2 * k * ido] - cc[ic + (2 * k + 1) * ido];
        ti2 = cc[i + (2 * k) * ido] + cc[ic + (2 * k + 1) * ido];
        ch[i - 1 + (k + l1) * ido] = wa1[i - 2] * tr2 - wa1[i - 1] * ti2;
        ch[i + (k + l1) * ido] = wa1[i - 2] * ti2 + wa1[i - 1] * tr2;
      }
    }
    if (ido % 2 == 1)
      return;
  }
  for (k = 0; k < l1; k++) {
    ch[ido - 1 + k * ido] = 2 * cc[ido - 1 + 2 * k * ido];
    ch[ido - 1 + (k + l1) * ido] = -2 * cc[(2 * k + 1) * ido];
  }
}
```