ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <do_bio_get_host_ip_tests@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <do_bio_get_port_tests@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int ret = 0;
  ret |= do_bio_get_host_ip_tests();
  ret |= do_bio_get_port_tests();
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CharToDecimalA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L8
L15:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <Find_DecimalA@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L8:
  cmpl   $0x3,-0x1c(%rbp)
  jle    L15
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long *CharToDecimalA(char *M) {
  int i;
  long *m = malloc(4 * sizeof(long));
  for (i = 0; i < 4; ++i) {
    m[i] = Find_DecimalA(M[i]);
  }
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CharToDecimalA>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
L9:
  movsbl (%r12,%rbx,1),%edi
  call   <Find_DecimalA@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L9
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long *CharToDecimalA(char *M) {
  int i;
  long *m = malloc(4 * sizeof(long));
  for (i = 0; i < 4; ++i) {
    m[i] = Find_DecimalA(M[i]);
  }
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CharToDecimalA>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x20,%edi
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
L7:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <Find_DecimalA@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L7
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long *CharToDecimalA(char *M) {
  int i;
  long *m = malloc(4 * sizeof(long));
  for (i = 0; i < 4; ++i) {
    m[i] = Find_DecimalA(M[i]);
  }
  return m;
}
```
user: What is the c source code of the assembly code below?

```asm
<CharToDecimalA>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x20,%edi
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
L3:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <Find_DecimalA@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L3
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long *CharToDecimalA(char *M) {
  int i;
  long *m = malloc(4 * sizeof(long));
  for (i = 0; i < 4; ++i) {
    m[i] = Find_DecimalA(M[i]);
  }
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sender_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sender@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *sender_t(void *data) {
  sender(data);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sender_t>:
  endbr64
  sub    $0x8,%rsp
  call   <sender@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *sender_t(void *data) {
  sender(data);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sender_t>:
  endbr64
  sub    $0x8,%rsp
  call   <sender@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *sender_t(void *data) {
  sender(data);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sender_t>:
  endbr64
  sub    $0x8,%rsp
  call   <sender@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *sender_t(void *data) {
  sender(data);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <strnchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L5
L14:
  mov    -0x28(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
size_t strcnlen(const char *string, int stop, size_t maxlen) {
  const char *end = strnchr(string, stop, maxlen);
  return end ? (size_t)(end - string) : maxlen;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcnlen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  call   <strnchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t strcnlen(const char *string, int stop, size_t maxlen) {
  const char *end = strnchr(string, stop, maxlen);
  return end ? (size_t)(end - string) : maxlen;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcnlen>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strnchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t strcnlen(const char *string, int stop, size_t maxlen) {
  const char *end = strnchr(string, stop, maxlen);
  return end ? (size_t)(end - string) : maxlen;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strcnlen>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strnchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t strcnlen(const char *string, int stop, size_t maxlen) {
  const char *end = strnchr(string, stop, maxlen);
  return end ? (size_t)(end - string) : maxlen;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xaa,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x64,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D13
data_type: f64
name: read_data
arguments: label: D0
data_type: string

tool: D13: 0.9

tool: D0: %.1f


assistant: ```c
int main() {
  int length;
  float basicWeight;
  length = 170;
  basicWeight = (length - 100) * 0.9;
  printf("%.1f\n", basicWeight);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D8(%rip),%xmm0
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: byte[4]
name: extract_symbolic_data
arguments: tag: D11
data_type: string

tool: {"D8": [0x00,0x00,0x7c,0x42]}

tool: D11: %.1f


assistant: ```c
int main() {
  int length;
  float basicWeight;
  length = 170;
  basicWeight = (length - 100) * 0.9;
  printf("%.1f\n", basicWeight);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D19(%rip),%xmm0
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
datatype: byte[4]
name: read_data
arguments: data_label: D18
datatype: string

tool: {"D19": [0x00,0x00,0x7c,0x42]}

tool: D18: %.1f


assistant: ```c
int main() {
  int length;
  float basicWeight;
  length = 170;
  basicWeight = (length - 100) * 0.9;
  printf("%.1f\n", basicWeight);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D0(%rip),%xmm0
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: {"D0": [0x00,0x00,0x7c,0x42]}

tool: D6: %.1f


assistant: ```c
int main() {
  int length;
  float basicWeight;
  length = 170;
  basicWeight = (length - 100) * 0.9;
  printf("%.1f\n", basicWeight);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L13:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L13
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <add@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: string

tool: D15: %d

assistant: ```c
int main(void) {
  int size, i;
  int *arr;
  scanf("%d", &size);
  arr = (int *)malloc(sizeof(int) * size);
  for (i = 0; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  add(arr, size);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L18
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D12(%rip),%r12
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L23
L18:
  mov    %r13,%rdi
  call   <add@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type_infered: string

tool: D12: %d

assistant: ```c
int main(void) {
  int size, i;
  int *arr;
  scanf("%d", &size);
  arr = (int *)malloc(sizeof(int) * size);
  for (i = 0; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  add(arr, size);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%esi
  mov    %rax,%r13
  test   %esi,%esi
  jle    L21
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L19
L21:
  mov    %r13,%rdi
  call   <add@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: %d

assistant: ```c
int main(void) {
  int size, i;
  int *arr;
  scanf("%d", &size);
  arr = (int *)malloc(sizeof(int) * size);
  for (i = 0; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  add(arr, size);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%esi
  mov    %rax,%r13
  test   %esi,%esi
  jle    L22
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L23
L22:
  mov    %r13,%rdi
  call   <add@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: %d

assistant: ```c
int main(void) {
  int size, i;
  int *arr;
  scanf("%d", &size);
  arr = (int *)malloc(sizeof(int) * size);
  for (i = 0; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  add(arr, size);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ConvertCToPStr255>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xff,-0x4(%rbp)
  jle    L3
  movl   $0xff,-0x4(%rbp)
L3:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void ConvertCToPStr255(const char *pSrc, unsigned char *pDest) {
  int nLen = strlen(pSrc);
  if (nLen > 255)
    nLen = 255;
  memcpy(pDest + 1, pSrc, nLen);
  *pDest = (unsigned char)nLen;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ConvertCToPStr255>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    $0xff,%edx
  cmp    %edx,%eax
  mov    %edx,%ebx
  cmovle %eax,%ebx
  lea    0x1(%rbp),%rdi
  mov    %ebx,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %bl,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ConvertCToPStr255(const char *pSrc, unsigned char *pDest) {
  int nLen = strlen(pSrc);
  if (nLen > 255)
    nLen = 255;
  memcpy(pDest + 1, pSrc, nLen);
  *pDest = (unsigned char)nLen;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ConvertCToPStr255>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    $0xff,%edx
  lea    0x1(%rbp),%rdi
  mov    %r12,%rsi
  cmp    %edx,%eax
  mov    %edx,%ebx
  cmovle %eax,%ebx
  mov    %ebx,%edx
  call   <memcpy@plt>
  mov    %bl,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ConvertCToPStr255(const char *pSrc, unsigned char *pDest) {
  int nLen = strlen(pSrc);
  if (nLen > 255)
    nLen = 255;
  memcpy(pDest + 1, pSrc, nLen);
  *pDest = (unsigned char)nLen;
}
```
user: What is the c source code of the assembly code below:

```asm
<ConvertCToPStr255>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    $0xff,%edx
  lea    0x1(%rbp),%rdi
  mov    %r12,%rsi
  cmp    %edx,%eax
  mov    %edx,%ebx
  cmovle %eax,%ebx
  mov    %ebx,%edx
  call   <memcpy@plt>
  mov    %bl,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ConvertCToPStr255(const char *pSrc, unsigned char *pDest) {
  int nLen = strlen(pSrc);
  if (nLen > 255)
    nLen = 255;
  memcpy(pDest + 1, pSrc, nLen);
  *pDest = (unsigned char)nLen;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<display_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L0
L9:
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L0:
  lea    -0x9(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L9
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
void display_file(int fd) {
  char buffer;
  while (read(fd, &buffer, 1) != 0)
    write(1, &buffer, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<display_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  jmp    L21
L3:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L21:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L3
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void display_file(int fd) {
  char buffer;
  while (read(fd, &buffer, 1) != 0)
    write(1, &buffer, 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<display_file>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L21:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L7
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void display_file(int fd) {
  char buffer;
  while (read(fd, &buffer, 1) != 0)
    write(1, &buffer, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display_file>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L18:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void display_file(int fd) {
  char buffer;
  while (read(fd, &buffer, 1) != 0)
    write(1, &buffer, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<its_birthday>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x3fe03,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x28(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x28(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jne    L37
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  cmp    %eax,%edx
  jne    L37
  mov    $0x1,%eax
  jmp    L27
L37:
  mov    $0x0,%eax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int its_birthday(FILE *firmware) {
  int day = 0;
  int month = 0;
  time_t t = 0;
  struct tm *tm = NULL;
  t = time(NULL);
  tm = localtime(&t);
  fseek(firmware, 0x03FE03, SEEK_SET);
  fread(&month, 1, 1, firmware);
  fread(&day, 1, 1, firmware);
  return ((day == tm->tm_mday) && (month - 1 == tm->tm_mon));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<its_birthday>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x14(%rsp)
  lea    0x14(%rsp),%rdi
  call   <localtime@plt>
  mov    %rax,%rbp
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    $0x3fe03,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  lea    0xc(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    $0x0,%eax
  mov    0xc(%rsp),%ecx
  cmp    %ecx,0x0(%rbp)
  je     L21
L5:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    0x10(%rsp),%eax
  sub    $0x1,%eax
  cmp    0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  jmp    L5
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int its_birthday(FILE *firmware) {
  int day = 0;
  int month = 0;
  time_t t = 0;
  struct tm *tm = NULL;
  t = time(NULL);
  tm = localtime(&t);
  fseek(firmware, 0x03FE03, SEEK_SET);
  fread(&month, 1, 1, firmware);
  fread(&day, 1, 1, firmware);
  return ((day == tm->tm_mday) && (month - 1 == tm->tm_mon));
}
```
user: What is the c source code of the assembly code below:

```asm
<its_birthday>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <time@plt>
  lea    0x14(%rsp),%rdi
  mov    %eax,0x14(%rsp)
  call   <localtime@plt>
  mov    $0x3fe03,%esi
  mov    %r12,%rdi
  mov    %rax,%rbx
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  lea    0x10(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    %r12,%rcx
  lea    0xc(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    0xc(%rsp),%ecx
  xor    %eax,%eax
  cmp    %ecx,(%rbx)
  jne    L18
  mov    0x10(%rsp),%eax
  sub    $0x1,%eax
  cmp    0x4(%rbx),%eax
  sete   %al
  movzbl %al,%eax
L18:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int its_birthday(FILE *firmware) {
  int day = 0;
  int month = 0;
  time_t t = 0;
  struct tm *tm = NULL;
  t = time(NULL);
  tm = localtime(&t);
  fseek(firmware, 0x03FE03, SEEK_SET);
  fread(&month, 1, 1, firmware);
  fread(&day, 1, 1, firmware);
  return ((day == tm->tm_mday) && (month - 1 == tm->tm_mon));
}
```