ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dst_s_dns_key_id>:
  endbr64
  test   %rdi,%rdi
  je     L31
  sub    $0x8,%rsp
  mov    0xc(%rdi),%edx
  cmp    $0x1,%edx
  je     L17
  mov    $0x0,%eax
  cmp    $0x9d,%edx
  jne    L32
L46:
  add    $0x8,%rsp
  ret
L17:
  movslq %esi,%rsi
  lea    -0xc(%rdi,%rsi,4),%rdi
  call   <dst_s_get_int16@plt>
  jmp    L46
L32:
  call   <dst_s_id_calc@plt>
  jmp    L46
L31:
  mov    $0x0,%eax
  ret
```

assistant: ```c
u_int16_t dst_s_dns_key_id(const u_char *dns_key_rdata, const int rdata_len) {
  if (!dns_key_rdata)
    return 0;
  if (dns_key_rdata[3] == 1)
    return dst_s_get_int16((const u_char *)&dns_key_rdata[rdata_len - 3]);
  else if (dns_key_rdata[3] == 157)
    return 0;
  else
    return dst_s_id_calc(dns_key_rdata, rdata_len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dst_s_dns_key_id>:
  endbr64
  test   %rdi,%rdi
  je     L18
  mov    0xc(%rdi),%eax
  cmp    $0x1,%eax
  je     L9
  cmp    $0x9d,%eax
  jne    L5
L18:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  jmp    1060 <dst_s_id_calc@plt>
  nopl   (%rax)
L9:
  movslq %esi,%rsi
  lea    -0xc(%rdi,%rsi,4),%rdi
  jmp    1070 <dst_s_get_int16@plt>
```

assistant: ```c
u_int16_t dst_s_dns_key_id(const u_char *dns_key_rdata, const int rdata_len) {
  if (!dns_key_rdata)
    return 0;
  if (dns_key_rdata[3] == 1)
    return dst_s_get_int16((const u_char *)&dns_key_rdata[rdata_len - 3]);
  else if (dns_key_rdata[3] == 157)
    return 0;
  else
    return dst_s_id_calc(dns_key_rdata, rdata_len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dst_s_dns_key_id>:
  endbr64
  test   %rdi,%rdi
  je     L16
  mov    0xc(%rdi),%eax
  cmp    $0x1,%eax
  je     L9
  cmp    $0x9d,%eax
  jne    L6
L16:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  jmp    1060 <dst_s_id_calc@plt>
  nopl   (%rax)
L9:
  movslq %esi,%rsi
  lea    -0xc(%rdi,%rsi,4),%rdi
  jmp    1070 <dst_s_get_int16@plt>
```

assistant: ```c
u_int16_t dst_s_dns_key_id(const u_char *dns_key_rdata, const int rdata_len) {
  if (!dns_key_rdata)
    return 0;
  if (dns_key_rdata[3] == 1)
    return dst_s_get_int16((const u_char *)&dns_key_rdata[rdata_len - 3]);
  else if (dns_key_rdata[3] == 157)
    return 0;
  else
    return dst_s_id_calc(dns_key_rdata, rdata_len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PWMGenIntTrigEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdi
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rax
  add    $0x4,%rax
  mov    (%rax),%rsi
  lea    (%rcx,%rdx,1),%rax
  add    $0x4,%rax
  mov    %rax,%rdx
  mov    %rdi,%rax
  or     %rsi,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PWMGenIntTrigEnable(uint32_t ui32Base, uint32_t ui32Gen, uint32_t ui32IntTrig) {
  ;
  ;

  ;
  (*((volatile unsigned long *)(((ui32Base) + (ui32Gen)) + 0x00000004))) |= ui32IntTrig;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<PWMGenIntTrigEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    %rdx,-0x18(%rsp)
  mov    -0x18(%rsp),%rcx
  mov    -0x8(%rsp),%rax
  mov    -0x10(%rsp),%rdx
  add    %rdx,%rax
  mov    0x4(%rax),%rdx
  or     %rcx,%rdx
  mov    %rdx,0x4(%rax)
  ret
```

assistant: ```c
void PWMGenIntTrigEnable(uint32_t ui32Base, uint32_t ui32Gen, uint32_t ui32IntTrig) {
  ;
  ;

  ;
  (*((volatile unsigned long *)(((ui32Base) + (ui32Gen)) + 0x00000004))) |= ui32IntTrig;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PWMGenIntTrigEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    %rdx,-0x18(%rsp)
  mov    -0x18(%rsp),%rcx
  mov    -0x8(%rsp),%rax
  mov    -0x10(%rsp),%rdx
  add    %rdx,%rax
  mov    0x4(%rax),%rdx
  or     %rcx,%rdx
  mov    %rdx,0x4(%rax)
  ret
```

assistant: ```c
void PWMGenIntTrigEnable(uint32_t ui32Base, uint32_t ui32Gen, uint32_t ui32IntTrig) {
  ;
  ;

  ;
  (*((volatile unsigned long *)(((ui32Base) + (ui32Gen)) + 0x00000004))) |= ui32IntTrig;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PWMGenIntTrigEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    %rdx,-0x18(%rsp)
  mov    -0x18(%rsp),%rcx
  mov    -0x8(%rsp),%rax
  mov    -0x10(%rsp),%rdx
  add    %rdx,%rax
  mov    0x4(%rax),%rdx
  or     %rcx,%rdx
  mov    %rdx,0x4(%rax)
  ret
```

assistant: ```c
void PWMGenIntTrigEnable(uint32_t ui32Base, uint32_t ui32Gen, uint32_t ui32IntTrig) {
  ;
  ;

  ;
  (*((volatile unsigned long *)(((ui32Base) + (ui32Gen)) + 0x00000004))) |= ui32IntTrig;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<switcheroo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  je     L89
  cmpl   $0x6,-0x4(%rbp)
  jg     L74
  cmpl   $0x2,-0x4(%rbp)
  jg     L44
  cmpl   $0x0,-0x4(%rbp)
  jns    L62
  jmp    L74
L44:
  cmpl   $0x4,-0x4(%rbp)
  je     L42
  jmp    L74
L62:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <frobulate@plt>
  jmp    L72
L42:
  mov    -0x4(%rbp),%eax
  sub    $0x3,%eax
  mov    %eax,%edi
  call   <frobulate@plt>
  jmp    L72
L89:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bazulate@plt>
L74:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <bazulate@plt>
L72:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  leave
  ret
```

assistant: ```c
int switcheroo(int arg) {
  switch (arg) {
  case 0:
  case 1:
  case 2:
    frobulate(arg);
    break;
  case 4:
    frobulate(arg - 3);
    break;
  case 6:
    bazulate(arg, arg);
  default:
    bazulate(0, 0);
  }
  return arg + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<switcheroo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x4,%edi
  je     L18
  jg     L9
  cmp    $0x2,%edi
  ja     L28
  call   <frobulate@plt>
  jmp    L7
L9:
  cmp    $0x6,%edi
  jne    L28
  mov    $0x6,%esi
  mov    $0x6,%edi
  call   <bazulate@plt>
L28:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <bazulate@plt>
L7:
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
L18:
  mov    $0x1,%edi
  call   <frobulate@plt>
  jmp    L7
```

assistant: ```c
int switcheroo(int arg) {
  switch (arg) {
  case 0:
  case 1:
  case 2:
    frobulate(arg);
    break;
  case 4:
    frobulate(arg - 3);
    break;
  case 6:
    bazulate(arg, arg);
  default:
    bazulate(0, 0);
  }
  return arg + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<switcheroo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x4,%edi
  je     L38
  jg     L37
  cmp    $0x2,%edi
  ja     L12
  call   <frobulate@plt>
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
  nopl   (%rax)
L37:
  cmp    $0x6,%edi
  jne    L12
  mov    $0x6,%esi
  mov    $0x6,%edi
  call   <bazulate@plt>
L12:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <bazulate@plt>
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0x1,%edi
  call   <frobulate@plt>
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int switcheroo(int arg) {
  switch (arg) {
  case 0:
  case 1:
  case 2:
    frobulate(arg);
    break;
  case 4:
    frobulate(arg - 3);
    break;
  case 6:
    bazulate(arg, arg);
  default:
    bazulate(0, 0);
  }
  return arg + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<switcheroo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x4,%edi
  je     L19
  jg     L33
  cmp    $0x2,%edi
  ja     L6
  call   <frobulate@plt>
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
  nopl   (%rax)
L33:
  cmp    $0x6,%edi
  jne    L6
  mov    $0x6,%esi
  mov    $0x6,%edi
  call   <bazulate@plt>
L6:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <bazulate@plt>
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0x1,%edi
  call   <frobulate@plt>
  lea    0x1(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int switcheroo(int arg) {
  switch (arg) {
  case 0:
  case 1:
  case 2:
    frobulate(arg);
    break;
  case 4:
    frobulate(arg - 3);
    break;
  case 6:
    bazulate(arg, arg);
  default:
    bazulate(0, 0);
  }
  return arg + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <sieve@plt>
  jmp    L64
L33:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <rev@plt>
  cmp    $0x1,%eax
  jne    L21
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L21
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L21:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L45
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L45:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L64:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L33
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
data_type: string
name: retrieve_data
arguments: data_label: D33
data_type: string
name: retrieve_data
arguments: data_label: D37
data_type: string
name: retrieve_data
arguments: data_label: D31
data_type: string

tool: D17: %d is emirp.


tool: D33: %d is prime.


tool: D37: %d is not prime.


tool: D31: %d

assistant: ```c
int main() {
  int n;
  sieve();
  while (scanf("%d", &n) == 1) {
    if (rev(n) == 1 && is_prime(n) == 1)
      printf("%d is emirp.\n", n);
    else if (is_prime(n) == 1)
      printf("%d is prime.\n", n);
    else
      printf("%d is not prime.\n", n);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <sieve@plt>
  lea    D17(%rip),%rbx
  lea    D20(%rip),%rbp
  lea    D28(%rip),%r12
  lea    D34(%rip),%r13
  jmp    L57
L69:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L65
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L57
L54:
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
L57:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L62
  mov    0x4(%rsp),%edi
  call   <rev@plt>
  cmp    $0x1,%eax
  je     L69
L65:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  je     L54
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L57
L62:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string
name: retrieve_data
arguments: label: D28
type_guessed: string
name: retrieve_data
arguments: label: D34
type_guessed: string

tool: D17: %d

tool: D20: %d is not prime.


tool: D28: %d is prime.


tool: D34: %d is emirp.


assistant: ```c
int main() {
  int n;
  sieve();
  while (scanf("%d", &n) == 1) {
    if (rev(n) == 1 && is_prime(n) == 1)
      printf("%d is emirp.\n", n);
    else if (is_prime(n) == 1)
      printf("%d is prime.\n", n);
    else
      printf("%d is not prime.\n", n);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <sieve@plt>
L68:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L13
L78:
  mov    0x4(%rsp),%edi
  call   <rev@plt>
  cmp    $0x1,%eax
  je     L53
L44:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%eax
  je     L37
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L78
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L53:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L44
  mov    0x4(%rsp),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L68
  nop
L37:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L68
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D23
type_guessed: string
name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D33
type_guessed: string

tool: D17: %d is emirp.


tool: D23: %d is prime.


tool: D26: %d is not prime.


tool: D33: %d

assistant: ```c
int main() {
  int n;
  sieve();
  while (scanf("%d", &n) == 1) {
    if (rev(n) == 1 && is_prime(n) == 1)
      printf("%d is emirp.\n", n);
    else if (is_prime(n) == 1)
      printf("%d is prime.\n", n);
    else
      printf("%d is not prime.\n", n);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  lea    D37(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D29(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <sieve@plt>
L36:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L44
L14:
  mov    0x4(%rsp),%edi
  call   <rev@plt>
  cmp    $0x1,%eax
  je     L58
L78:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%eax
  je     L32
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L14
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L58:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L78
  mov    0x4(%rsp),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L36
  nop
L32:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L36
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D23
type: string
name: parse_data
arguments: tag: D37
type: string
name: parse_data
arguments: tag: D29
type: string

tool: D0: %d is emirp.


tool: D23: %d is prime.


tool: D37: %d is not prime.


tool: D29: %d

assistant: ```c
int main() {
  int n;
  sieve();
  while (scanf("%d", &n) == 1) {
    if (rev(n) == 1 && is_prime(n) == 1)
      printf("%d is emirp.\n", n);
    else if (is_prime(n) == 1)
      printf("%d is prime.\n", n);
    else
      printf("%d is not prime.\n", n);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcrop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L10
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L3
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L31:
  subq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
L47:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L38
L10:
  nop
  jmp    L38
L3:
  nop
L38:
  leave
  ret
```

assistant: ```c
void strcrop(char *str) {
  char *last;
  int len;
  if (!str)
    return;
  len = strlen(str);
  if (len == 0)
    return;
  last = str + (len - 1);
  while ((last != str) && (isspace((int)*last)))
    last--;
  last++;
  *last = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcrop>:
  endbr64
  test   %rdi,%rdi
  je     L25
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  je     L39
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  je     L35
L27:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L35
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L27
L35:
  movb   $0x0,0x1(%rbx)
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  ret
```

assistant: ```c
void strcrop(char *str) {
  char *last;
  int len;
  if (!str)
    return;
  len = strlen(str);
  if (len == 0)
    return;
  last = str + (len - 1);
  while ((last != str) && (isspace((int)*last)))
    last--;
  last++;
  *last = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcrop>:
  endbr64
  test   %rdi,%rdi
  je     L45
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L35
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jne    L11
  jmp    L57
  nopl   0x0(%rax)
L32:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L57
L11:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
L57:
  movb   $0x0,0x1(%rbx)
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L45:
  ret
```

assistant: ```c
void strcrop(char *str) {
  char *last;
  int len;
  if (!str)
    return;
  len = strlen(str);
  if (len == 0)
    return;
  last = str + (len - 1);
  while ((last != str) && (isspace((int)*last)))
    last--;
  last++;
  *last = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcrop>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L51
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jne    L26
  jmp    L50
  nopl   0x0(%rax)
L1:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L50
L26:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
L50:
  movb   $0x0,0x1(%rbx)
L51:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
void strcrop(char *str) {
  char *last;
  int len;
  if (!str)
    return;
  len = strlen(str);
  if (len == 0)
    return;
  last = str + (len - 1);
  while ((last != str) && (isspace((int)*last)))
    last--;
  last++;
  *last = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reverse_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse_line(char s[], char reversed_s[], int len) {
  int i, j;
  j = len - 1;
  for (i = 0; i < len; i++) {
    reversed_s[i] = s[j];
    j--;
  }
  reversed_s[len] = '\0';
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse_line>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L13
  cltq
  add    %rdi,%rax
  mov    %rsi,%rcx
  movslq %edx,%r8
  lea    -0x2(%rdi,%r8,1),%r8
  lea    -0x1(%rdx),%edi
  sub    %rdi,%r8
L5:
  movzbl (%rax),%edi
  mov    %dil,(%rcx)
  sub    $0x1,%rax
  add    $0x1,%rcx
  cmp    %r8,%rax
  jne    L5
L13:
  movslq %edx,%rdx
  movb   $0x0,(%rsi,%rdx,1)
  ret
```

assistant: ```c
void reverse_line(char s[], char reversed_s[], int len) {
  int i, j;
  j = len - 1;
  for (i = 0; i < len; i++) {
    reversed_s[i] = s[j];
    j--;
  }
  reversed_s[len] = '\0';
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse_line>:
  endbr64
  lea    -0x1(%rdx),%r9d
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  movslq %r9d,%rax
  mov    %r9d,%r9d
  mov    %rsi,%rcx
  lea    -0x2(%rdi,%rdx,1),%r8
  add    %rdi,%rax
  sub    %r9,%r8
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl (%rax),%edi
  sub    $0x1,%rax
  add    $0x1,%rcx
  mov    %dil,-0x1(%rcx)
  cmp    %r8,%rax
  jne    L1
  movb   $0x0,(%rsi,%rdx,1)
  ret
  nopl   0x0(%rax)
L11:
  movslq %edx,%rdx
  movb   $0x0,(%rsi,%rdx,1)
  ret
```

assistant: ```c
void reverse_line(char s[], char reversed_s[], int len) {
  int i, j;
  j = len - 1;
  for (i = 0; i < len; i++) {
    reversed_s[i] = s[j];
    j--;
  }
  reversed_s[len] = '\0';
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse_line>:
  endbr64
  lea    -0x1(%rdx),%r9d
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  movslq %r9d,%rax
  mov    %r9d,%r9d
  mov    %rsi,%rcx
  lea    -0x2(%rdi,%rdx,1),%r8
  add    %rdi,%rax
  sub    %r9,%r8
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl (%rax),%edi
  sub    $0x1,%rax
  add    $0x1,%rcx
  mov    %dil,-0x1(%rcx)
  cmp    %r8,%rax
  jne    L8
  movb   $0x0,(%rsi,%rdx,1)
  ret
  nopl   0x0(%rax)
L2:
  movslq %edx,%rdx
  movb   $0x0,(%rsi,%rdx,1)
  ret
```

assistant: ```c
void reverse_line(char s[], char reversed_s[], int len) {
  int i, j;
  j = len - 1;
  for (i = 0; i < len; i++) {
    reversed_s[i] = s[j];
    j--;
  }
  reversed_s[len] = '\0';
  return;
}
```