ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<prepName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tokenLen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <tokenLen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L23
L7:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L7
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  addl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L30
L25:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L25
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *prepName(char *currPath, char *argv0) {
  int curPathLength = tokenLen(currPath);
  int argLength = tokenLen(argv0);
  char *newName = (char *)calloc((curPathLength + 1 + argLength + 1), 1);
  int i = 0;
  int j = 0;
  while (j < curPathLength) {
    newName[i] = currPath[j];
    i++;
    j++;
  }
  newName[i] = '/';
  i++;
  j = 0;
  while (j < argLength) {
    newName[i] = argv0[j];
    i++;
    j++;
  }
  newName[i] = 0;
  return newName;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prepName>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  call   <tokenLen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <tokenLen@plt>
  mov    %eax,%ebx
  lea    0x2(%r12,%rax,1),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rsi
  test   %r12d,%r12d
  jle    L36
  lea    -0x1(%r12),%eax
  lea    0x1(%rsi,%rax,1),%rdi
  mov    %rsi,%rax
  mov    %r13,%rcx
  sub    %rsi,%rcx
L27:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L27
L34:
  movslq %r12d,%rdx
  movb   $0x2f,(%rsi,%rdx,1)
  add    $0x1,%r12d
  test   %ebx,%ebx
  jle    L26
  movslq %r12d,%rax
  add    %rsi,%rax
  lea    -0x1(%rbx),%ecx
  lea    0x2(%rsi,%rcx,1),%rcx
  add    %rdx,%rcx
  add    %rsi,%rdx
  sub    %rdx,%rbp
L0:
  movzbl -0x1(%rbp,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L0
  add    %ebx,%r12d
L26:
  movslq %r12d,%r12
  movb   $0x0,(%rsi,%r12,1)
  mov    %rsi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  mov    $0x0,%r12d
  jmp    L34
```

assistant: ```c
char *prepName(char *currPath, char *argv0) {
  int curPathLength = tokenLen(currPath);
  int argLength = tokenLen(argv0);
  char *newName = (char *)calloc((curPathLength + 1 + argLength + 1), 1);
  int i = 0;
  int j = 0;
  while (j < curPathLength) {
    newName[i] = currPath[j];
    i++;
    j++;
  }
  newName[i] = '/';
  i++;
  j = 0;
  while (j < argLength) {
    newName[i] = argv0[j];
    i++;
    j++;
  }
  newName[i] = 0;
  return newName;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prepName>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <tokenLen@plt>
  mov    %rbx,%rdi
  movslq %eax,%r12
  call   <tokenLen@plt>
  mov    $0x1,%esi
  lea    0x2(%r12,%rax,1),%edi
  mov    %eax,%r13d
  call   <calloc@plt>
  mov    %rax,%r8
  test   %r12d,%r12d
  jle    L30
  lea    -0x1(%r12),%eax
  mov    %rbp,%rcx
  lea    0x1(%r12),%r14d
  lea    0x1(%r8,%rax,1),%rsi
  sub    %r8,%rcx
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl (%rcx,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L21
  add    %r8,%r12
  movslq %r14d,%rax
L36:
  movb   $0x2f,(%r12)
  test   %r13d,%r13d
  jle    L40
  lea    -0x1(%r13),%edx
  movslq %r14d,%rax
  lea    0x1(%r8,%rdx,1),%rsi
  add    %rax,%rsi
  add    %r8,%rax
  sub    %rax,%rbx
  mov    %rbx,%rcx
  nopl   0x0(%rax,%rax,1)
L39:
  movzbl (%rcx,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L39
  add    %r13d,%r14d
  movslq %r14d,%rax
L40:
  movb   $0x0,(%r8,%rax,1)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %rax,%r12
  mov    $0x1,%r14d
  mov    $0x1,%eax
  jmp    L36
```

assistant: ```c
char *prepName(char *currPath, char *argv0) {
  int curPathLength = tokenLen(currPath);
  int argLength = tokenLen(argv0);
  char *newName = (char *)calloc((curPathLength + 1 + argLength + 1), 1);
  int i = 0;
  int j = 0;
  while (j < curPathLength) {
    newName[i] = currPath[j];
    i++;
    j++;
  }
  newName[i] = '/';
  i++;
  j = 0;
  while (j < argLength) {
    newName[i] = argv0[j];
    i++;
    j++;
  }
  newName[i] = 0;
  return newName;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scale3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void scale3d(double *v1, double v0, double *v2) {
  v2[0] = v1[0] * v0;
  v2[1] = v1[1] * v0;
  v2[2] = v1[2] * v0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scale3d>:
  endbr64
  movapd %xmm0,%xmm1
  mulsd  (%rdi),%xmm1
  movsd  %xmm1,(%rsi)
  movapd %xmm0,%xmm1
  mulsd  0x8(%rdi),%xmm1
  movsd  %xmm1,0x8(%rsi)
  mulsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void scale3d(double *v1, double v0, double *v2) {
  v2[0] = v1[0] * v0;
  v2[1] = v1[1] * v0;
  v2[2] = v1[2] * v0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<scale3d>:
  endbr64
  movsd  (%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  movsd  0x8(%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsi)
  mulsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void scale3d(double *v1, double v0, double *v2) {
  v2[0] = v1[0] * v0;
  v2[1] = v1[1] * v0;
  v2[2] = v1[2] * v0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scale3d>:
  endbr64
  movsd  (%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  movsd  0x8(%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsi)
  mulsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void scale3d(double *v1, double v0, double *v2) {
  v2[0] = v1[0] * v0;
  v2[1] = v1[1] * v0;
  v2[2] = v1[2] * v0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ReverseBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L3:
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  sarl   -0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ReverseBits(int index, int NumBits) {
  int i, rev;
  for (i = rev = 0; i < NumBits; i++) {
    rev = (rev << 1) | (index & 1);
    index >>= 1;
  }
  return rev;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ReverseBits>:
  endbr64
  test   %esi,%esi
  jle    L11
  mov    $0x0,%eax
  mov    $0x0,%edx
L9:
  add    %eax,%eax
  mov    %edi,%ecx
  and    $0x1,%ecx
  or     %ecx,%eax
  sar    %edi
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L9
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ReverseBits(int index, int NumBits) {
  int i, rev;
  for (i = rev = 0; i < NumBits; i++) {
    rev = (rev << 1) | (index & 1);
    index >>= 1;
  }
  return rev;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ReverseBits>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jle    L18
  xor    %edx,%edx
  nopl   0x0(%rax)
L2:
  mov    %edi,%ecx
  add    %eax,%eax
  add    $0x1,%edx
  sar    %edi
  and    $0x1,%ecx
  or     %ecx,%eax
  cmp    %edx,%esi
  jne    L2
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
int ReverseBits(int index, int NumBits) {
  int i, rev;
  for (i = rev = 0; i < NumBits; i++) {
    rev = (rev << 1) | (index & 1);
    index >>= 1;
  }
  return rev;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ReverseBits>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jle    L11
  xor    %edx,%edx
  nopl   0x0(%rax)
L8:
  mov    %edi,%ecx
  add    %eax,%eax
  add    $0x1,%edx
  sar    %edi
  and    $0x1,%ecx
  or     %ecx,%eax
  cmp    %edx,%esi
  jne    L8
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
int ReverseBits(int index, int NumBits) {
  int i, rev;
  for (i = rev = 0; i < NumBits; i++) {
    rev = (rev << 1) | (index & 1);
    index >>= 1;
  }
  return rev;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D19(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D19
type: byte[4]
name: read_data
arguments: label: D9
type: string

tool: {"D19": [0x76,0x62,0xa7,0x3f]}

tool: D9: %.2f


assistant: ```c
int main(void) {
  float answer = 17 / (float)13;
  printf("%.2f\n", answer);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D19(%rip),%xmm0
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_infered: byte[4]
name: unpack_data
arguments: data_label: D5
type_infered: string

tool: {"D19": [0x76,0x62,0xa7,0x3f]}

tool: D5: %.2f


assistant: ```c
int main(void) {
  float answer = 17 / (float)13;
  printf("%.2f\n", answer);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D1(%rip),%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: byte[4]
name: retrieve_data
arguments: tag: D8
type: string

tool: {"D1": [0x76,0x62,0xa7,0x3f]}

tool: D8: %.2f


assistant: ```c
int main(void) {
  float answer = 17 / (float)13;
  printf("%.2f\n", answer);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D1(%rip),%xmm0
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: byte[4]
name: read_data
arguments: data_tag: D4
type_infered: string

tool: {"D1": [0x76,0x62,0xa7,0x3f]}

tool: D4: %.2f


assistant: ```c
int main(void) {
  float answer = 17 / (float)13;
  printf("%.2f\n", answer);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<create_homotopy_with_given_gamma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x48(%rbp)
  movsd  %xmm1,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x99,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int create_homotopy_with_given_gamma(double gamma_re, double gamma_im) {
  int *a, *b, fail;
  double c[2];
  c[0] = gamma_re;
  c[1] = gamma_im;
  fail = _ada_use_c2phc4c(153, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<create_homotopy_with_given_gamma>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  mov    %rsp,%rcx
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x99,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_homotopy_with_given_gamma(double gamma_re, double gamma_im) {
  int *a, *b, fail;
  double c[2];
  c[0] = gamma_re;
  c[1] = gamma_im;
  fail = _ada_use_c2phc4c(153, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<create_homotopy_with_given_gamma>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  mov    $0x99,%edi
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_homotopy_with_given_gamma(double gamma_re, double gamma_im) {
  int *a, *b, fail;
  double c[2];
  c[0] = gamma_re;
  c[1] = gamma_im;
  fail = _ada_use_c2phc4c(153, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<create_homotopy_with_given_gamma>:
  endbr64
  sub    $0x28,%rsp
  unpcklpd %xmm1,%xmm0
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %esi,%esi
  mov    %rsp,%rcx
  mov    $0x99,%edi
  movaps %xmm0,(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_homotopy_with_given_gamma(double gamma_re, double gamma_im) {
  int *a, *b, fail;
  double c[2];
  c[0] = gamma_re;
  c[1] = gamma_im;
  fail = _ada_use_c2phc4c(153, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6,-0x30(%rbp)
  movl   $0xf,-0x2c(%rbp)
  movl   $0xc,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  movl   $0x17,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0xa,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  movl   $0x14,-0xc(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L78
L11:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L78:
  cmpl   $0x9,-0x44(%rbp)
  jle    L11
  movl   $0x0,-0x44(%rbp)
  jmp    L84
L37:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x40(%rbp)
  jmp    L24
L16:
  mov    -0x40(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x40(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  subl   $0x1,-0x40(%rbp)
L24:
  cmpl   $0x0,-0x40(%rbp)
  jle    L62
  mov    -0x40(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L16
L62:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x44(%rbp)
L84:
  cmpl   $0x9,-0x44(%rbp)
  jle    L37
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L19
L12:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L19:
  cmpl   $0x9,-0x44(%rbp)
  jle    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
data_type: string

tool: D10: %2d 

assistant: ```c
int main() {
  int num[10] = {6, 15, 12, 7, 9, 23, 2, 10, 4, 20};
  int temp;
  int i, j;
  int key = 0;
  int data = 0;
  for (i = 0; i < 10; i++)
    printf("%2d ", num[i]);
  for (i = 0; i < 10; i++) {
    temp = num[i];
    for (j = i; j > 0 && num[j - 1] > temp; j--) {
      num[j] = num[j - 1];
    }
    num[j] = temp;
  }
  printf("\n");
  for (i = 0; i < 10; i++)
    printf("%2d ", num[i]);
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x6,(%rsp)
  movl   $0xf,0x4(%rsp)
  movl   $0xc,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  movl   $0x17,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0xa,0x1c(%rsp)
  movl   $0x4,0x20(%rsp)
  movl   $0x14,0x24(%rsp)
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%r12
  lea    D19(%rip),%r13
L24:
  mov    (%r12),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L24
  mov    %rbx,%r9
  mov    $0x0,%r8d
  mov    $0x6,%edi
  mov    $0x0,%esi
  jmp    L75
L28:
  mov    %r8d,%esi
L68:
  add    $0x4,%r9
L75:
  movslq %esi,%rsi
  mov    %edi,(%rsp,%rsi,4)
  add    $0x1,%r8d
  cmp    $0xa,%r8d
  je     L52
  mov    0x4(%r9),%edi
  test   %r8d,%r8d
  jle    L28
  mov    %r9,%rdx
  mov    %r8d,%eax
L63:
  mov    %eax,%esi
  sub    $0x1,%eax
  mov    (%rdx),%ecx
  cmp    %edi,%ecx
  jle    L68
  mov    %ecx,0x4(%rdx)
  sub    $0x4,%rdx
  test   %eax,%eax
  jne    L63
  mov    %eax,%esi
  jmp    L68
L52:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D19(%rip),%r12
L82:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L82
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_infered: string

tool: D19: %2d 

assistant: ```c
int main() {
  int num[10] = {6, 15, 12, 7, 9, 23, 2, 10, 4, 20};
  int temp;
  int i, j;
  int key = 0;
  int data = 0;
  for (i = 0; i < 10; i++)
    printf("%2d ", num[i]);
  for (i = 0; i < 10; i++) {
    temp = num[i];
    for (j = i; j > 0 && num[j - 1] > temp; j--) {
      num[j] = num[j - 1];
    }
    num[j] = temp;
  }
  printf("\n");
  for (i = 0; i < 10; i++)
    printf("%2d ", num[i]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x6,%esi
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xf00000006,%rax
  mov    %rsp,%r13
  lea    0x4(%rsp),%r14
  lea    0x28(%rsp),%rbp
  mov    %r13,%rbx
  mov    %rax,(%rsp)
  movabs $0x70000000c,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x1700000009,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xa00000002,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x1400000004,%rax
  mov    %rax,0x20(%rsp)
  jmp    L47
  cs nopw 0x0(%rax,%rax,1)
L111:
  mov    (%r14),%esi
  add    $0x4,%r14
L47:
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %rbp,%r14
  jne    L111
  mov    %r13,%r8
  xor    %edx,%edx
  mov    $0x6,%edi
  lea    0x1(%rdx),%r9d
  mov    %r8,%rax
  test   %edx,%edx
  jne    L116
  jmp    L30
  nopl   (%rax)
L104:
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  test   %edx,%edx
  je     L14
L116:
  mov    -0x4(%rax),%ecx
  movslq %edx,%rsi
  lea    -0x1(%rsi),%edx
  cmp    %edi,%ecx
  jg     L104
  mov    %edi,(%rsp,%rsi,4)
  cmp    $0xa,%r9d
  je     L5
L113:
  mov    0x4(%r8),%edi
  mov    %r9d,%edx
  add    $0x4,%r8
  lea    0x1(%rdx),%r9d
  mov    %r8,%rax
  test   %edx,%edx
  jne    L116
L30:
  mov    %edi,(%rsp)
  jmp    L113
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %esi,%esi
  mov    %edi,(%rsp,%rsi,4)
  cmp    $0xa,%r9d
  jne    L113
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  nopl   (%rax)
L50:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L50
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string

tool: D6: %2d 

assistant: ```c
int main() {
  int num[10] = {6, 15, 12, 7, 9, 23, 2, 10, 4, 20};
  int temp;
  int i, j;
  int key = 0;
  int data = 0;
  for (i = 0; i < 10; i++)
    printf("%2d ", num[i]);
  for (i = 0; i < 10; i++) {
    temp = num[i];
    for (j = i; j > 0 && num[j - 1] > temp; j--) {
      num[j] = num[j - 1];
    }
    num[j] = temp;
  }
  printf("\n");
  for (i = 0; i < 10; i++)
    printf("%2d ", num[i]);
  printf("\n");
  return 0;
}
```