ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<asc_to_val>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  lea    -0x30(%rbp),%eax
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x9,%eax
  jbe    L28
  mov    %ebp,%edi
  call   <islower@plt>
  test   %eax,%eax
  jne    L0
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L2
  add    $0x8,%rsp
  lea    -0x37(%rbx),%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  lea    -0x57(%rbx),%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x8,%rsp
  lea    -0x30(%rdi),%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D10(%rip),%rcx
  lea    D12(%rip),%rdx
  mov    $0xf7,%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <_assert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string
name: parse_data
arguments: data_tag: D13
data_type: string

tool: D10: !"Invalid character!"

tool: D12: asc_to_val

tool: D13: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/thasenpusch/simplix/refs/heads/master/src/lib/util.c

assistant: ```c
unsigned char asc_to_val(char c) {
  if (isdigit(c))
    return 0 + (unsigned char)(c - '0');
  if (islower(c))
    return 0xa + (unsigned char)(c - 'a');
  if (isupper(c))
    return 0xA + (unsigned char)(c - 'A');
  (!"Invalid character!") ? (void)0 : _assert("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/thasenpusch/simplix/refs/heads/master/src/lib/util.c", 247, __func__, "!\"Invalid character!\"");
}
```
user: Translate the below assembly code into C programming language:

```asm
<waitforit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_get_fd@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <SSL_get_error@plt>
  cmp    $0x80,%eax
  je     L31
  cmp    $0x81,%eax
  jne    L49
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L23
L31:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L23
L49:
  mov    $0x0,%eax
  jmp    L54
L23:
  lea    -0x14(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <poll@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  jne    L30
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  and    %edx,%eax
  test   %eax,%eax
  jne    L38
L30:
  mov    $0x0,%eax
  jmp    L54
L38:
  mov    $0x1,%eax
L54:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int waitforit(SSL *ssl) {
  struct pollfd pfd;
  int ret;
  pfd.fd = SSL_get_fd(ssl);
  pfd.revents = 0;
  switch (SSL_get_error(ssl, -1)) {
  case SSL_ERROR_WANT_READ:
    pfd.events = POLLIN;
    break;
  case SSL_ERROR_WANT_WRITE:
    pfd.events = POLLOUT;
    break;
  default:
    return 0;
  }
  ret = poll(&pfd, 1, -1);
  if (ret != 1 || !(pfd.revents & pfd.events))
    return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<waitforit>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <SSL_get_fd@plt>
  mov    %eax,0x14(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <SSL_get_error@plt>
  cmp    $0x80,%eax
  je     L2
  mov    $0x0,%edx
  cmp    $0x81,%eax
  jne    L0
  mov    D13(%rip),%rax
  mov    (%rax),%eax
L17:
  mov    %eax,0x10(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  call   <poll@plt>
  mov    $0x0,%edx
  cmp    $0x1,%eax
  jne    L0
  mov    0xc(%rsp),%eax
  and    0x10(%rsp),%eax
  setne  %dl
  movzbl %dl,%edx
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %edx,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L17
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int waitforit(SSL *ssl) {
  struct pollfd pfd;
  int ret;
  pfd.fd = SSL_get_fd(ssl);
  pfd.revents = 0;
  switch (SSL_get_error(ssl, -1)) {
  case SSL_ERROR_WANT_READ:
    pfd.events = POLLIN;
    break;
  case SSL_ERROR_WANT_WRITE:
    pfd.events = POLLOUT;
    break;
  default:
    return 0;
  }
  ret = poll(&pfd, 1, -1);
  if (ret != 1 || !(pfd.revents & pfd.events))
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<waitforit>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <SSL_get_fd@plt>
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  movl   $0x0,0xc(%rsp)
  mov    %eax,0x14(%rsp)
  call   <SSL_get_error@plt>
  cmp    $0x80,%eax
  je     L39
  xor    %r8d,%r8d
  cmp    $0x81,%eax
  jne    L21
  mov    D15(%rip),%rax
  mov    (%rax),%eax
L45:
  lea    0xc(%rsp),%rdi
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  mov    %eax,0x10(%rsp)
  call   <poll@plt>
  xor    %r8d,%r8d
  cmp    $0x1,%eax
  je     L55
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x20,%rsp
  mov    %r8d,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L55:
  xor    %r8d,%r8d
  mov    0xc(%rsp),%eax
  and    0x10(%rsp),%eax
  setne  %r8b
  jmp    L21
  nopl   0x0(%rax)
L39:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  jmp    L45
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int waitforit(SSL *ssl) {
  struct pollfd pfd;
  int ret;
  pfd.fd = SSL_get_fd(ssl);
  pfd.revents = 0;
  switch (SSL_get_error(ssl, -1)) {
  case SSL_ERROR_WANT_READ:
    pfd.events = POLLIN;
    break;
  case SSL_ERROR_WANT_WRITE:
    pfd.events = POLLOUT;
    break;
  default:
    return 0;
  }
  ret = poll(&pfd, 1, -1);
  if (ret != 1 || !(pfd.revents & pfd.events))
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<waitforit>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <SSL_get_fd@plt>
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  movl   $0x0,0xc(%rsp)
  mov    %eax,0x14(%rsp)
  call   <SSL_get_error@plt>
  cmp    $0x80,%eax
  je     L38
  xor    %r8d,%r8d
  cmp    $0x81,%eax
  jne    L43
  mov    D10(%rip),%rax
  mov    (%rax),%eax
L58:
  lea    0xc(%rsp),%rdi
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  mov    %eax,0x10(%rsp)
  call   <poll@plt>
  xor    %r8d,%r8d
  cmp    $0x1,%eax
  je     L41
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  mov    %r8d,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L41:
  xor    %r8d,%r8d
  mov    0xc(%rsp),%eax
  and    0x10(%rsp),%eax
  setne  %r8b
  jmp    L43
  nopl   0x0(%rax)
L38:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L58
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int waitforit(SSL *ssl) {
  struct pollfd pfd;
  int ret;
  pfd.fd = SSL_get_fd(ssl);
  pfd.revents = 0;
  switch (SSL_get_error(ssl, -1)) {
  case SSL_ERROR_WANT_READ:
    pfd.events = POLLIN;
    break;
  case SSL_ERROR_WANT_WRITE:
    pfd.events = POLLOUT;
    break;
  default:
    return 0;
  }
  ret = poll(&pfd, 1, -1);
  if (ret != 1 || !(pfd.revents & pfd.events))
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lt2ts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <lt2fd@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fd2ts@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double lt2ts() {
  double tsec;
  char *datestring;
  datestring = lt2fd();
  tsec = fd2ts(datestring);
  free(datestring);
  return (tsec);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lt2ts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <lt2fd@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <fd2ts@plt>
  movq   %xmm0,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  movq   %rbp,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double lt2ts() {
  double tsec;
  char *datestring;
  datestring = lt2fd();
  tsec = fd2ts(datestring);
  free(datestring);
  return (tsec);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lt2ts>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  sub    $0x10,%rsp
  call   <lt2fd@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fd2ts@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
double lt2ts() {
  double tsec;
  char *datestring;
  datestring = lt2fd();
  tsec = fd2ts(datestring);
  free(datestring);
  return (tsec);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lt2ts>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  sub    $0x10,%rsp
  call   <lt2fd@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fd2ts@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
double lt2ts() {
  double tsec;
  char *datestring;
  datestring = lt2fd();
  tsec = fd2ts(datestring);
  free(datestring);
  return (tsec);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movq   $0x7e51052,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  char copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      copy12 = *((char *)(&state[local1]) + 5);
      *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 2);
      *((char *)(&state[local1]) + 2) = copy12;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      copy13 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 6);
      *((char *)(&state[0UL]) + 6) = copy13;
      copy13 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 5);
      *((char *)(&state[0UL]) + 5) = copy13;
      state[local1] = state[0UL] ^ state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 576551744UL) ^ 132452434UL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movq   $0x7e51052,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  char copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      copy12 = *((char *)(&state[local1]) + 5);
      *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 2);
      *((char *)(&state[local1]) + 2) = copy12;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      copy13 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 6);
      *((char *)(&state[0UL]) + 6) = copy13;
      copy13 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 5);
      *((char *)(&state[0UL]) + 5) = copy13;
      state[local1] = state[0UL] ^ state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 576551744UL) ^ 132452434UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movq   $0x7e51052,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  char copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      copy12 = *((char *)(&state[local1]) + 5);
      *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 2);
      *((char *)(&state[local1]) + 2) = copy12;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      copy13 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 6);
      *((char *)(&state[0UL]) + 6) = copy13;
      copy13 = *((char *)(&state[0UL]) + 7);
      *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 5);
      *((char *)(&state[0UL]) + 5) = copy13;
      state[local1] = state[0UL] ^ state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 576551744UL) ^ 132452434UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x80(%rbp)
  jmp    L1
L25:
  movl   $0x0,-0x7c(%rbp)
  jmp    L57
L62:
  lea    -0x70(%rbp),%rcx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x80(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7c(%rbp)
L57:
  cmpl   $0x4,-0x7c(%rbp)
  jle    L62
  addl   $0x1,-0x80(%rbp)
L1:
  cmpl   $0x4,-0x80(%rbp)
  jle    L25
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <swap@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x80(%rbp)
  jmp    L67
L50:
  movl   $0x0,-0x7c(%rbp)
  jmp    L17
L35:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x80(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x70(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x7c(%rbp)
L17:
  cmpl   $0x4,-0x7c(%rbp)
  jle    L35
  addl   $0x1,-0x80(%rbp)
L67:
  cmpl   $0x4,-0x80(%rbp)
  jle    L50
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string
name: unpack_data
arguments: data_label: D39
type: string
name: unpack_data
arguments: data_label: D21
type: string
name: unpack_data
arguments: data_label: D32
type: string

tool: D5: input the matrix:

tool: D39: %d

tool: D21: new matrix is:

tool: D32: %d 

assistant: ```c
int main() {
  void swap(int *p);
  int a[5][5], *p, i, j;
  printf("input the matrix:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      scanf("%d", &a[i][j]);
  p = &a[0][0];
  swap(p);
  printf("new matrix is:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      printf("%d ", a[i][j]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbp
  lea    0x14(%rsp),%r12
  mov    $0x0,%r14d
  lea    D35(%rip),%r13
L39:
  lea    -0x14(%r12),%rbx
L28:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L28
  add    $0x5,%r14
  add    $0x14,%r12
  cmp    $0x19,%r14
  jne    L39
  mov    %rsp,%rdi
  call   <swap@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    0x64(%rbp),%r13
  lea    D5(%rip),%r12
L12:
  mov    $0x0,%ebx
L36:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L36
  add    $0x14,%rbp
  cmp    %r13,%rbp
  jne    L12
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_guessed: string
name: retrieve_data
arguments: data_label: D35
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string
name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D19: input the matrix:

tool: D35: %d

tool: D16: new matrix is:

tool: D5: %d 

assistant: ```c
int main() {
  void swap(int *p);
  int a[5][5], *p, i, j;
  printf("input the matrix:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      scanf("%d", &a[i][j]);
  p = &a[0][0];
  swap(p);
  printf("new matrix is:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      printf("%d ", a[i][j]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D18(%rip),%rdi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D28(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0x14(%rsp),%r12
  call   <puts@plt>
  mov    %r15,%rbp
L20:
  lea    -0x14(%r12),%rbx
L32:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L32
  add    $0x5,%r14
  lea    0x14(%rbx),%r12
  cmp    $0x19,%r14
  jne    L20
  mov    %r15,%rdi
  lea    D1(%rip),%r12
  add    $0x64,%r15
  call   <swap@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
L45:
  xor    %ebx,%ebx
L6:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L6
  add    $0x14,%rbp
  cmp    %r15,%rbp
  jne    L45
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D28
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string

tool: D18: input the matrix:

tool: D28: %d

tool: D1: %d 

tool: D11: new matrix is:

assistant: ```c
int main() {
  void swap(int *p);
  int a[5][5], *p, i, j;
  printf("input the matrix:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      scanf("%d", &a[i][j]);
  p = &a[0][0];
  swap(p);
  printf("new matrix is:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      printf("%d ", a[i][j]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%rdi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0x14(%rsp),%r12
  call   <puts@plt>
  mov    %r15,%rbp
L35:
  lea    -0x14(%r12),%rbx
L30:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L30
  add    $0x5,%r14
  lea    0x14(%rbx),%r12
  cmp    $0x19,%r14
  jne    L35
  mov    %r15,%rdi
  lea    D8(%rip),%r12
  add    $0x64,%r15
  call   <swap@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
L32:
  xor    %ebx,%ebx
L21:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L21
  add    $0x14,%rbp
  cmp    %r15,%rbp
  jne    L32
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D17
type_infered: string

tool: D10: input the matrix:

tool: D5: %d

tool: D8: %d 

tool: D17: new matrix is:

assistant: ```c
int main() {
  void swap(int *p);
  int a[5][5], *p, i, j;
  printf("input the matrix:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      scanf("%d", &a[i][j]);
  p = &a[0][0];
  swap(p);
  printf("new matrix is:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++)
      printf("%d ", a[i][j]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tp_utils_roundedstack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getpagesize@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  je     L19
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L14
L19:
  mov    -0x18(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
size_t tp_utils_roundedstack(size_t stacksize) {
  int pagesize = getpagesize();
  if (stacksize % pagesize) {
    return stacksize + pagesize;
  }
  return stacksize;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tp_utils_roundedstack>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <getpagesize@plt>
  movslq %eax,%rcx
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rcx
  add    %rbx,%rcx
  test   %rdx,%rdx
  cmovne %rcx,%rbx
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t tp_utils_roundedstack(size_t stacksize) {
  int pagesize = getpagesize();
  if (stacksize % pagesize) {
    return stacksize + pagesize;
  }
  return stacksize;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tp_utils_roundedstack>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <getpagesize@plt>
  xor    %edx,%edx
  movslq %eax,%rcx
  mov    %r12,%rax
  div    %rcx
  add    %r12,%rcx
  test   %rdx,%rdx
  cmovne %rcx,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t tp_utils_roundedstack(size_t stacksize) {
  int pagesize = getpagesize();
  if (stacksize % pagesize) {
    return stacksize + pagesize;
  }
  return stacksize;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tp_utils_roundedstack>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <getpagesize@plt>
  xor    %edx,%edx
  movslq %eax,%rcx
  mov    %r12,%rax
  div    %rcx
  add    %r12,%rcx
  test   %rdx,%rdx
  cmovne %rcx,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t tp_utils_roundedstack(size_t stacksize) {
  int pagesize = getpagesize();
  if (stacksize % pagesize) {
    return stacksize + pagesize;
  }
  return stacksize;
}
```