ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_ensure_allocator_alloc_returns_null_when_allocator_fails>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <allocator_always_fail@plt>
  mov    %eax,%esi
  mov    $0x400,%edi
  call   <allocator_alloc@plt>
  test   %rax,%rax
  jne    L11
L15:
  add    $0x8,%rsp
  ret
L11:
  lea    D13(%rip),%rcx
  mov    $0x31,%edx
  lea    D8(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: label: D13
type: string
name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D6
type: string

tool: D13: allocator_alloc( 1024, allocator_always_fail( ) ) == 0

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/allocator_tests.c

tool: D6: %s:%d - test '%s' failed


assistant: ```c
void _ensure_allocator_alloc_returns_null_when_allocator_fails(void) {
  if (!(allocator_alloc(1024, allocator_always_fail()) == 0)) {
    printf("%s:%d - test '%s' failed\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/allocator_tests.c", 49, "allocator_alloc( 1024, allocator_always_fail( ) ) == 0");
    exit(1);
  };
}
```
user: What is the c source code of the assembly code below:

```asm
<_ensure_allocator_alloc_returns_null_when_allocator_fails>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <allocator_always_fail@plt>
  mov    $0x400,%edi
  mov    %eax,%esi
  call   <allocator_alloc@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L8:
  lea    D26(%rip),%rdi
  lea    D29(%rip),%rcx
  mov    $0x31,%edx
  lea    D24(%rip),%rsi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    10b0 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D26
type_guessed: string
name: disassemble_data
arguments: tag: D29
type_guessed: string
name: disassemble_data
arguments: tag: D24
type_guessed: string

tool: D26: %s:%d - test '%s' failed


tool: D29: allocator_alloc( 1024, allocator_always_fail( ) ) == 0

tool: D24: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/allocator_tests.c

assistant: ```c
void _ensure_allocator_alloc_returns_null_when_allocator_fails(void) {
  if (!(allocator_alloc(1024, allocator_always_fail()) == 0)) {
    printf("%s:%d - test '%s' failed\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/allocator_tests.c", 49, "allocator_alloc( 1024, allocator_always_fail( ) ) == 0");
    exit(1);
  };
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_ensure_allocator_alloc_returns_null_when_allocator_fails>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <allocator_always_fail@plt>
  mov    $0x400,%edi
  mov    %eax,%esi
  call   <allocator_alloc@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L3:
  lea    D22(%rip),%rdi
  lea    D23(%rip),%rcx
  mov    $0x31,%edx
  lea    D0(%rip),%rsi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    10b0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D23
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string

tool: D22: %s:%d - test '%s' failed


tool: D23: allocator_alloc( 1024, allocator_always_fail( ) ) == 0

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/allocator_tests.c

assistant: ```c
void _ensure_allocator_alloc_returns_null_when_allocator_fails(void) {
  if (!(allocator_alloc(1024, allocator_always_fail()) == 0)) {
    printf("%s:%d - test '%s' failed\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/allocator_tests.c", 49, "allocator_alloc( 1024, allocator_always_fail( ) ) == 0");
    exit(1);
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printUsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: 
Usage:
   %s <input file> <output directory>


assistant: ```c
void printUsage(char *fname) {
  printf("\nUsage:\n"
         "   %s <input file> <output directory>\n",
         fname);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printUsage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: 
Usage:
   %s <input file> <output directory>


assistant: ```c
void printUsage(char *fname) {
  printf("\nUsage:\n"
         "   %s <input file> <output directory>\n",
         fname);
}
```
user: What is the c source code of the assembly code below:

```asm
<printUsage>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: 
Usage:
   %s <input file> <output directory>


assistant: ```c
void printUsage(char *fname) {
  printf("\nUsage:\n"
         "   %s <input file> <output directory>\n",
         fname);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printUsage>:
  endbr64
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: 
Usage:
   %s <input file> <output directory>


assistant: ```c
void printUsage(char *fname) {
  printf("\nUsage:\n"
         "   %s <input file> <output directory>\n",
         fname);
}
```
user: What is the c source code of the assembly code below:

```asm
<isID>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %ecx,%eax
  mov    %r8d,%edi
  mov    %esi,%ecx
  mov    %cl,-0xc(%rbp)
  mov    %dl,-0x10(%rbp)
  mov    %al,-0x14(%rbp)
  mov    %edi,%eax
  mov    %al,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x10(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x18(%rbp)
  jne    L7
  mov    $0x1,%eax
  jmp    L47
L7:
  mov    $0x0,%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int isID(const void *data, char c1, char c2, char c3, char c4) {
  if (((const char *)data)[0] == c1 && ((const char *)data)[1] == c2 && ((const char *)data)[2] == c3 && ((const char *)data)[3] == c4)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isID>:
  endbr64
  mov    $0x0,%eax
  cmp    %sil,(%rdi)
  jne    L14
  cmp    %dl,0x1(%rdi)
  jne    L14
  cmp    %cl,0x2(%rdi)
  jne    L14
  cmp    %r8b,0x3(%rdi)
  sete   %al
  movzbl %al,%eax
L14:
  ret
```

assistant: ```c
int isID(const void *data, char c1, char c2, char c3, char c4) {
  if (((const char *)data)[0] == c1 && ((const char *)data)[1] == c2 && ((const char *)data)[2] == c3 && ((const char *)data)[3] == c4)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isID>:
  endbr64
  xor    %eax,%eax
  cmp    %sil,(%rdi)
  jne    L10
  cmp    %dl,0x1(%rdi)
  jne    L10
  cmp    %cl,0x2(%rdi)
  jne    L10
  xor    %eax,%eax
  cmp    %r8b,0x3(%rdi)
  sete   %al
L10:
  ret
```

assistant: ```c
int isID(const void *data, char c1, char c2, char c3, char c4) {
  if (((const char *)data)[0] == c1 && ((const char *)data)[1] == c2 && ((const char *)data)[2] == c3 && ((const char *)data)[3] == c4)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isID>:
  endbr64
  xor    %eax,%eax
  cmp    %sil,(%rdi)
  jne    L9
  cmp    %dl,0x1(%rdi)
  jne    L9
  cmp    %cl,0x2(%rdi)
  jne    L9
  xor    %eax,%eax
  cmp    %r8b,0x3(%rdi)
  sete   %al
L9:
  ret
```

assistant: ```c
int isID(const void *data, char c1, char c2, char c3, char c4) {
  if (((const char *)data)[0] == c1 && ((const char *)data)[1] == c2 && ((const char *)data)[2] == c3 && ((const char *)data)[3] == c4)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L133:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cmp    $0x3,%eax
  je     L77
  cmp    $0x3,%eax
  jg     L143
  cmp    $0x1,%eax
  je     L72
  cmp    $0x2,%eax
  je     L168
  jmp    L143
L72:
  addl   $0x1,-0x18(%rbp)
  jmp    L152
L168:
  addl   $0x1,-0x10(%rbp)
  jmp    L152
L77:
  addl   $0x1,-0x14(%rbp)
  jmp    L152
L143:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L152:
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L133
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L117
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L117
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L94
L117:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L121
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L121
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L94
L121:
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L94:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D71
datatype: string
name: retrieve_data
arguments: data_label: D70
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string
name: retrieve_data
arguments: data_label: D40
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string
name: retrieve_data
arguments: data_label: D61
datatype: string

tool: D71: 1)ADMK 2)BJP 3)DMK Enter number of voters

tool: D70: %d

tool: D12:  Enter your choice

tool: D9: Wrong choice

tool: D40: The winner is ADMK

tool: D15: The winner is DMK

tool: D61: The winner is BJP

assistant: ```c
main() {
  int admk = 0, dmk = 0, bjp = 0, ch = 0, n = 0, i;
  printf("1)ADMK 2)BJP 3)DMK Enter number of voters");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    printf(" Enter your choice");
    scanf("%d", &ch);
    switch (ch) {
    case 1:
      admk++;
      break;
    case 2:
      bjp++;
      break;
    case 3:
      dmk++;
      break;
    default:
      printf("Wrong choice");
    }
  }
  if (admk > dmk && admk > bjp)
    printf("The winner is ADMK");
  else if (dmk > admk && dmk > bjp)
    printf("The winner is DMK");
  else
    printf("The winner is BJP");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    D70(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L31
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  mov    $0x0,%r15d
  movl   $0x0,0xc(%rsp)
  lea    D3(%rip),%r13
  lea    0x10(%rsp),%r12
  lea    D28(%rip),%rbp
  jmp    L89
L60:
  addl   $0x1,0xc(%rsp)
L115:
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jle    L48
L89:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    $0x2,%eax
  je     L61
  cmp    $0x3,%eax
  je     L105
  cmp    $0x1,%eax
  je     L60
  lea    D63(%rip),%rdi
  call   <printf@plt>
  jmp    L115
L61:
  add    $0x1,%r14d
  jmp    L115
L105:
  add    $0x1,%r15d
  jmp    L115
L48:
  cmp    %r14d,%r15d
  mov    %r14d,%eax
  cmovge %r15d,%eax
  cmp    %eax,0xc(%rsp)
  jg     L102
  mov    0xc(%rsp),%eax
  cmp    %r14d,%eax
  cmovl  %r14d,%eax
  cmp    %eax,%r15d
  jle    L31
  lea    D13(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L102:
  lea    D73(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L31:
  lea    D52(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D70
type: string
name: unpack_data
arguments: data_tag: D28
type: string
name: unpack_data
arguments: data_tag: D3
type: string
name: unpack_data
arguments: data_tag: D63
type: string
name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D73
type: string
name: unpack_data
arguments: data_tag: D52
type: string

tool: D70: 1)ADMK 2)BJP 3)DMK Enter number of voters

tool: D28: %d

tool: D3:  Enter your choice

tool: D63: Wrong choice

tool: D13: The winner is DMK

tool: D73: The winner is ADMK

tool: D52: The winner is BJP

assistant: ```c
main() {
  int admk = 0, dmk = 0, bjp = 0, ch = 0, n = 0, i;
  printf("1)ADMK 2)BJP 3)DMK Enter number of voters");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    printf(" Enter your choice");
    scanf("%d", &ch);
    switch (ch) {
    case 1:
      admk++;
      break;
    case 2:
      bjp++;
      break;
    case 3:
      dmk++;
      break;
    default:
      printf("Wrong choice");
    }
  }
  if (admk > dmk && admk > bjp)
    printf("The winner is ADMK");
  else if (dmk > admk && dmk > bjp)
    printf("The winner is DMK");
  else
    printf("The winner is BJP");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D40(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L109
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  lea    D33(%rip),%r12
  xor    %r15d,%r15d
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  jmp    L137
  nopl   (%rax)
L93:
  cmp    $0x1,%eax
  je     L4
  lea    D47(%rip),%rdi
  call   <printf@plt>
L14:
  add    $0x1,%r13d
  cmp    %r13d,0x14(%rsp)
  jle    L63
L137:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    $0x2,%eax
  je     L95
  cmp    $0x3,%eax
  jne    L93
  add    $0x1,%r15d
  add    $0x1,%r13d
  cmp    %r13d,0x14(%rsp)
  jg     L137
L63:
  cmp    %r14d,%r15d
  mov    %r14d,%eax
  cmovge %r15d,%eax
  cmp    %eax,0xc(%rsp)
  jg     L106
  mov    0xc(%rsp),%eax
  cmp    %r14d,%eax
  mov    %eax,%r13d
  cmovl  %r14d,%r13d
  cmp    %r13d,%r15d
  jle    L109
  lea    D24(%rip),%rdi
  call   <printf@plt>
L122:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L95:
  add    $0x1,%r14d
  jmp    L14
  nopl   0x0(%rax)
L4:
  addl   $0x1,0xc(%rsp)
  jmp    L14
L109:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  jmp    L122
L106:
  lea    D48(%rip),%rdi
  call   <printf@plt>
  jmp    L122
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D40
type: string
name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D33
type: string
name: parse_data
arguments: label: D47
type: string
name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D37
type: string
name: parse_data
arguments: label: D48
type: string

tool: D40: 1)ADMK 2)BJP 3)DMK Enter number of voters

tool: D6: %d

tool: D33:  Enter your choice

tool: D47: Wrong choice

tool: D24: The winner is DMK

tool: D37: The winner is BJP

tool: D48: The winner is ADMK

assistant: ```c
main() {
  int admk = 0, dmk = 0, bjp = 0, ch = 0, n = 0, i;
  printf("1)ADMK 2)BJP 3)DMK Enter number of voters");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    printf(" Enter your choice");
    scanf("%d", &ch);
    switch (ch) {
    case 1:
      admk++;
      break;
    case 2:
      bjp++;
      break;
    case 3:
      dmk++;
      break;
    default:
      printf("Wrong choice");
    }
  }
  if (admk > dmk && admk > bjp)
    printf("The winner is ADMK");
  else if (dmk > admk && dmk > bjp)
    printf("The winner is DMK");
  else
    printf("The winner is BJP");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D43(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D27(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L53
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  lea    D37(%rip),%r12
  xor    %r15d,%r15d
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  jmp    L21
  nopl   (%rax)
L35:
  cmp    $0x1,%eax
  je     L8
  lea    D57(%rip),%rdi
  call   <printf@plt>
L6:
  add    $0x1,%r13d
  cmp    %r13d,0x14(%rsp)
  jle    L129
L21:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    $0x2,%eax
  je     L60
  cmp    $0x3,%eax
  jne    L35
  add    $0x1,%r15d
  add    $0x1,%r13d
  cmp    %r13d,0x14(%rsp)
  jg     L21
L129:
  cmp    %r14d,%r15d
  mov    %r14d,%eax
  cmovge %r15d,%eax
  cmp    %eax,0xc(%rsp)
  jg     L85
  mov    0xc(%rsp),%eax
  cmp    %r14d,%eax
  mov    %eax,%r13d
  cmovl  %r14d,%r13d
  cmp    %r13d,%r15d
  jle    L53
  lea    D35(%rip),%rdi
  call   <printf@plt>
L136:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  add    $0x1,%r14d
  jmp    L6
  nopl   0x0(%rax)
L8:
  addl   $0x1,0xc(%rsp)
  jmp    L6
L53:
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L136
L85:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L136
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D43
type_guessed: string
name: retrieve_data
arguments: data_label: D27
type_guessed: string
name: retrieve_data
arguments: data_label: D37
type_guessed: string
name: retrieve_data
arguments: data_label: D57
type_guessed: string
name: retrieve_data
arguments: data_label: D35
type_guessed: string
name: retrieve_data
arguments: data_label: D51
type_guessed: string
name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D43: 1)ADMK 2)BJP 3)DMK Enter number of voters

tool: D27: %d

tool: D37:  Enter your choice

tool: D57: Wrong choice

tool: D35: The winner is DMK

tool: D51: The winner is BJP

tool: D5: The winner is ADMK

assistant: ```c
main() {
  int admk = 0, dmk = 0, bjp = 0, ch = 0, n = 0, i;
  printf("1)ADMK 2)BJP 3)DMK Enter number of voters");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    printf(" Enter your choice");
    scanf("%d", &ch);
    switch (ch) {
    case 1:
      admk++;
      break;
    case 2:
      bjp++;
      break;
    case 3:
      dmk++;
      break;
    default:
      printf("Wrong choice");
    }
  }
  if (admk > dmk && admk > bjp)
    printf("The winner is ADMK");
  else if (dmk > admk && dmk > bjp)
    printf("The winner is DMK");
  else
    printf("The winner is BJP");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<c_postgresql_copy_escape_bytea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L26
L40:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x5c,-0x1(%rbp)
  jne    L56
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x5c,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x5c,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x5c,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x5c,(%rax)
  jmp    L26
L56:
  cmpb   $0x1f,-0x1(%rbp)
  jbe    L69
  cmpb   $0x7e,-0x1(%rbp)
  ja     L69
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L26
L69:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x5c,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x5c,(%rax)
  movzbl -0x1(%rbp),%eax
  shr    $0x6,%al
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  lea    0x30(%rcx),%edx
  mov    %dl,(%rax)
  movzbl -0x1(%rbp),%eax
  shr    $0x3,%al
  and    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  lea    0x30(%rcx),%edx
  mov    %dl,(%rax)
  movzbl -0x1(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  lea    0x30(%rcx),%edx
  mov    %dl,(%rax)
L26:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L40
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *c_postgresql_copy_escape_bytea(const unsigned char *in, size_t in_size, unsigned char *out) {
  while (in_size-- > 0) {
    unsigned char c = *in++;
    if (c == '\\') {
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '\\';
    } else if (c >= 32 && c <= 126) {
      *out++ = c;
    } else {
      *out++ = '\\';
      *out++ = '\\';
      *out++ = '0' + ((c >> 6) & 0x7);
      *out++ = '0' + ((c >> 3) & 0x7);
      *out++ = '0' + (c & 0x7);
    }
  }
  return out;
}
```