ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_datafs_from_flash>:
  endbr64
  push   %rbx
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x4000,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x0,%edx
  mov    $0x4000,%esi
  mov    %rbx,%rdi
  call   <sysPersistentGet@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *read_datafs_from_flash() {
  char *big_buf = malloc((1024 * 16));
  memset(big_buf, 0, (1024 * 16));
  sysPersistentGet(big_buf, (1024 * 16), 0);
  return big_buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_datafs_from_flash>:
  endbr64
  push   %r12
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    $0x4000,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r12,%rdi
  xor    %edx,%edx
  mov    $0x4000,%esi
  call   <sysPersistentGet@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *read_datafs_from_flash() {
  char *big_buf = malloc((1024 * 16));
  memset(big_buf, 0, (1024 * 16));
  sysPersistentGet(big_buf, (1024 * 16), 0);
  return big_buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_datafs_from_flash>:
  endbr64
  push   %r12
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    $0x4000,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r12,%rdi
  xor    %edx,%edx
  mov    $0x4000,%esi
  call   <sysPersistentGet@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *read_datafs_from_flash() {
  char *big_buf = malloc((1024 * 16));
  memset(big_buf, 0, (1024 * 16));
  sysPersistentGet(big_buf, (1024 * 16), 0);
  return big_buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read16bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <to16bit@plt>
  leave
  ret
```

assistant: ```c
int read16bit() {
  int c1, c2;
  c1 = egetc();
  c2 = egetc();
  return to16bit(c1, c2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read16bit>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <to16bit@plt>
  pop    %rbx
  ret
```

assistant: ```c
int read16bit() {
  int c1, c2;
  c1 = egetc();
  c2 = egetc();
  return to16bit(c1, c2);
}
```
user: What is the c source code of the assembly code below?

```asm
<read16bit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <to16bit@plt>
```

assistant: ```c
int read16bit() {
  int c1, c2;
  c1 = egetc();
  c2 = egetc();
  return to16bit(c1, c2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read16bit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <egetc@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <to16bit@plt>
```

assistant: ```c
int read16bit() {
  int c1, c2;
  c1 = egetc();
  c2 = egetc();
  return to16bit(c1, c2);
}
```
user: What is the c source code of the assembly code below:

```asm
<sjs__nonblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
L12:
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x18(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L7
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L12
L7:
  cmpl   $0x0,-0x4(%rbp)
  je     L20
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L34
L20:
  mov    $0x0,%eax
L34:
  leave
  ret
```

assistant: ```c
int sjs__nonblock(int fd, int set) {
  int r;
  do
    r = ioctl(fd, FIONBIO, &set);
  while (r == -1 && errno == EINTR);
  if (r)
    return -errno;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sjs__nonblock>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rbp
L38:
  mov    %rbp,%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  jne    L5
  mov    D11(%rip),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  je     L38
L32:
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L7
L5:
  test   %eax,%eax
  jne    L32
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int sjs__nonblock(int fd, int set) {
  int r;
  do
    r = ioctl(fd, FIONBIO, &set);
  while (r == -1 && errno == EINTR);
  if (r)
    return -errno;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sjs__nonblock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    D34(%rip),%rbp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%r12
  jmp    L22
L34:
  mov    D12(%rip),%rax
  mov    D0(%rip),%rdx
  mov    (%rax),%eax
  cmp    (%rdx),%eax
  jne    L21
L22:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdx
  mov    %ebx,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L34
  test   %eax,%eax
  jne    L37
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
L21:
  add    $0x10,%rsp
  neg    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sjs__nonblock(int fd, int set) {
  int r;
  do
    r = ioctl(fd, FIONBIO, &set);
  while (r == -1 && errno == EINTR);
  if (r)
    return -errno;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sjs__nonblock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    D15(%rip),%rbp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%r12
  jmp    L19
L17:
  mov    D32(%rip),%rax
  mov    D37(%rip),%rdx
  mov    (%rax),%eax
  cmp    (%rdx),%eax
  jne    L36
L19:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdx
  mov    %ebx,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L17
  test   %eax,%eax
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    D32(%rip),%rax
  mov    (%rax),%eax
L36:
  add    $0x10,%rsp
  neg    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sjs__nonblock(int fd, int set) {
  int r;
  do
    r = ioctl(fd, FIONBIO, &set);
  while (r == -1 && errno == EINTR);
  if (r)
    return -errno;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x2,0x24(%rsp)
  movl   $0x2,0x28(%rsp)
  movl   $0x2,0x2c(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0x2,0x34(%rsp)
  movl   $0x0,0x38(%rsp)
  movl   $0x2,0x3c(%rsp)
  movl   $0x0,0x40(%rsp)
  movl   $0x2,0x44(%rsp)
  movl   $0x0,0x48(%rsp)
  movl   $0x1,0x4c(%rsp)
  mov    %rsp,%rbx
  lea    0x50(%rsp),%rbp
  mov    %rbx,%rax
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%ecx
  jmp    L117
L73:
  cmp    $0x1,%edx
  je     L12
  add    $0x1,%esi
L15:
  add    $0x4,%rax
  cmp    %rbp,%rax
  je     L43
L117:
  mov    (%rax),%edx
  test   %edx,%edx
  jne    L73
  add    $0x1,%ecx
  jmp    L15
L12:
  add    $0x1,%edi
  jmp    L15
L43:
  test   %ecx,%ecx
  jle    L37
  lea    -0x1(%rcx),%eax
  lea    0x4(%rbx,%rax,4),%rdx
  mov    %rbx,%rax
L98:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L98
L37:
  lea    (%rcx,%rdi,1),%r8d
  lea    (%rsi,%r8,1),%r9d
  cmp    %r8d,%ecx
  jge    L97
  movslq %ecx,%rcx
  lea    (%rsp,%rcx,4),%rax
  lea    -0x1(%rdi),%edx
  add    %rcx,%rdx
  lea    0x4(%rbx,%rdx,4),%rdx
L20:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L20
L97:
  cmp    %r9d,%r8d
  jge    L108
  movslq %r8d,%r8
  lea    (%rsp,%r8,4),%rax
  lea    -0x1(%rsi),%edx
  add    %r8,%rdx
  lea    0x4(%rbx,%rdx,4),%rdx
L124:
  movl   $0x2,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L124
L108:
  lea    D1(%rip),%r12
L60:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L60
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: %d	

assistant: ```c
int main() {
  int a[20] = {0, 1, 0, 2, 0, 0, 1, 1, 0, 2, 2, 2, 1, 2, 0, 2, 0, 2, 0, 1};
  int ac = 0;
  int b = 0;
  int c = 0;
  int i = 0;
  int temp = 0;
  int temp1 = 0;
  for (i = 0; i < 20; i++) {
    if (a[i] == 0) {
      ac++;
    } else if (a[i] == 1) {
      b++;
    } else {
      c++;
    }
  }
  for (i = 0; i < ac; i++) {
    a[i] = 0;
  }
  temp = ac + b;
  temp1 = ac + b + c;
  for (i = ac; i < temp; i++) {
    a[i] = 1;
  }
  for (i = temp; i < temp1; i++) {
    a[i] = 2;
  }
  for (i = 0; i < 20; i++) {
    printf("%d\t", a[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  movabs $0x100000001,%rcx
  push   %r14
  xor    %r14d,%r14d
  movabs $0x100000000,%rdx
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rcx,0x18(%rsp)
  lea    0x50(%rsp),%rbp
  movabs $0x200000002,%rcx
  movabs $0x200000000,%rax
  mov    %rcx,0x28(%rsp)
  sub    $0x1,%rcx
  mov    %rcx,0x30(%rsp)
  mov    %rsp,%rcx
  mov    %rdx,(%rsp)
  mov    %rcx,%rbx
  mov    %rax,0x8(%rsp)
  mov    %rax,0x20(%rsp)
  mov    %rax,0x38(%rsp)
  mov    %rax,0x40(%rsp)
  lea    0x4(%rsp),%rax
  mov    %rdx,0x48(%rsp)
  xor    %edx,%edx
  movq   $0x0,0x10(%rsp)
  jmp    L106
  xchg   %ax,%ax
L71:
  add    $0x1,%r12d
L49:
  cmp    %rbp,%rax
  je     L16
L118:
  mov    (%rax),%edx
  add    $0x4,%rax
L106:
  test   %edx,%edx
  je     L71
  cmp    $0x1,%edx
  je     L85
  add    $0x1,%r13d
  cmp    %rbp,%rax
  jne    L118
L16:
  test   %r12d,%r12d
  je     L26
  movslq %r12d,%rdx
  mov    %rcx,%rdi
  xor    %esi,%esi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
L26:
  lea    (%r12,%r14,1),%esi
  lea    0x0(%r13,%rsi,1),%edi
  cmp    %esi,%r12d
  jge    L93
  movslq %r12d,%r12
  lea    -0x1(%r14),%edx
  add    %r12,%rdx
  lea    (%rcx,%r12,4),%rax
  lea    0x4(%rcx,%rdx,4),%rdx
  nop
L95:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L95
L93:
  cmp    %edi,%esi
  jge    L19
  movslq %esi,%rsi
  lea    -0x1(%r13),%edx
  add    %rsi,%rdx
  lea    (%rcx,%rsi,4),%rax
  lea    0x4(%rcx,%rdx,4),%rdx
  cs nopw 0x0(%rax,%rax,1)
L34:
  movl   $0x2,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L34
L19:
  lea    D8(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L129:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L129
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  add    $0x1,%r14d
  jmp    L49
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string

tool: D8: %d	

assistant: ```c
int main() {
  int a[20] = {0, 1, 0, 2, 0, 0, 1, 1, 0, 2, 2, 2, 1, 2, 0, 2, 0, 2, 0, 1};
  int ac = 0;
  int b = 0;
  int c = 0;
  int i = 0;
  int temp = 0;
  int temp1 = 0;
  for (i = 0; i < 20; i++) {
    if (a[i] == 0) {
      ac++;
    } else if (a[i] == 1) {
      b++;
    } else {
      c++;
    }
  }
  for (i = 0; i < ac; i++) {
    a[i] = 0;
  }
  temp = ac + b;
  temp1 = ac + b + c;
  for (i = ac; i < temp; i++) {
    a[i] = 1;
  }
  for (i = temp; i < temp1; i++) {
    a[i] = 2;
  }
  for (i = 0; i < 20; i++) {
    printf("%d\t", a[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  movaps %xmm0,(%rsp)
  mov    %rsp,%rbx
  movaps %xmm0,0x10(%rsp)
  movdqa D21(%rip),%xmm0
  lea    0x50(%rsp),%r12
  movl   $0x1,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  movdqa D26(%rip),%xmm0
  movl   $0x2,0x44(%rsp)
  mov    %rax,0x48(%rsp)
  movups %xmm0,0x34(%rsp)
  xchg   %ax,%ax
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D26
datatype: byte[16]
name: extract_symbolic_data
arguments: label: D21
datatype: byte[16]

tool: D5: %d	

tool: {"D26": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D21": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[20] = {0, 1, 0, 2, 0, 0, 1, 1, 0, 2, 2, 2, 1, 2, 0, 2, 0, 2, 0, 1};
  int ac = 0;
  int b = 0;
  int c = 0;
  int i = 0;
  int temp = 0;
  int temp1 = 0;
  for (i = 0; i < 20; i++) {
    if (a[i] == 0) {
      ac++;
    } else if (a[i] == 1) {
      b++;
    } else {
      c++;
    }
  }
  for (i = 0; i < ac; i++) {
    a[i] = 0;
  }
  temp = ac + b;
  temp1 = ac + b + c;
  for (i = ac; i < temp; i++) {
    a[i] = 1;
  }
  for (i = temp; i < temp1; i++) {
    a[i] = 2;
  }
  for (i = 0; i < 20; i++) {
    printf("%d\t", a[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D18
datatype: string

tool: D18: %d


assistant: ```c
int main() {
  int a = 10, *pInt;
  pInt = &a;
  printf("%d\n", pInt);
  printf("%d\n", *pInt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: %d


assistant: ```c
int main() {
  int a = 10, *pInt;
  pInt = &a;
  printf("%d\n", pInt);
  printf("%d\n", *pInt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0xa,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string

tool: D3: %d


assistant: ```c
int main() {
  int a = 10, *pInt;
  pInt = &a;
  printf("%d\n", pInt);
  printf("%d\n", *pInt);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0xa,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: %d


assistant: ```c
int main() {
  int a = 10, *pInt;
  pInt = &a;
  printf("%d\n", pInt);
  printf("%d\n", *pInt);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lBrack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <peekList@plt>
  mov    %eax,%edx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L5
  mov    $0x0,%eax
  jmp    L0
L5:
  mov    $0x0,%eax
  call   <dequeueList@plt>
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: [

assistant: ```c
int lBrack() {
  if (strcmp(peekList(), "[") != 0) {
    return 0;
  }
  dequeueList();
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lBrack>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <peekList@plt>
  mov    %eax,%edi
  lea    D0(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L0
L12:
  add    $0x8,%rsp
  ret
L0:
  call   <dequeueList@plt>
  mov    $0x1,%eax
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: [

assistant: ```c
int lBrack() {
  if (strcmp(peekList(), "[") != 0) {
    return 0;
  }
  dequeueList();
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<lBrack>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <peekList@plt>
  lea    D7(%rip),%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L8
  call   <dequeueList@plt>
  mov    $0x1,%eax
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: [

assistant: ```c
int lBrack() {
  if (strcmp(peekList(), "[") != 0) {
    return 0;
  }
  dequeueList();
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lBrack>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <peekList@plt>
  lea    D0(%rip),%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L9
  call   <dequeueList@plt>
  mov    $0x1,%eax
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: [

assistant: ```c
int lBrack() {
  if (strcmp(peekList(), "[") != 0) {
    return 0;
  }
  dequeueList();
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<box_map_local>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x30(%rbp),%edi
  mov    -0x2c(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <box_map_local_entry@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int box_map_local(const int box_local[][2], const int ghost, const int box_local_map[], const int local_x, const int local_y, const int local_z) {
  int result = box_map_local_entry(box_local, ghost, local_x, local_y, local_z);
  if (0 <= result) {
    result = box_local_map[result];
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<box_map_local>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    %ecx,%edx
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  call   <box_map_local_entry@plt>
  test   %eax,%eax
  js     L2
  cltq
  mov    (%rbx,%rax,4),%eax
L2:
  pop    %rbx
  ret
```

assistant: ```c
int box_map_local(const int box_local[][2], const int ghost, const int box_local_map[], const int local_x, const int local_y, const int local_z) {
  int result = box_map_local_entry(box_local, ghost, local_x, local_y, local_z);
  if (0 <= result) {
    result = box_local_map[result];
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<box_map_local>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    %ecx,%edx
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  call   <box_map_local_entry@plt>
  test   %eax,%eax
  js     L2
  cltq
  mov    (%rbx,%rax,4),%eax
L2:
  pop    %rbx
  ret
```

assistant: ```c
int box_map_local(const int box_local[][2], const int ghost, const int box_local_map[], const int local_x, const int local_y, const int local_z) {
  int result = box_map_local_entry(box_local, ghost, local_x, local_y, local_z);
  if (0 <= result) {
    result = box_local_map[result];
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<box_map_local>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    %ecx,%edx
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  call   <box_map_local_entry@plt>
  test   %eax,%eax
  js     L3
  cltq
  mov    (%rbx,%rax,4),%eax
L3:
  pop    %rbx
  ret
```

assistant: ```c
int box_map_local(const int box_local[][2], const int ghost, const int box_local_map[], const int local_x, const int local_y, const int local_z) {
  int result = box_map_local_entry(box_local, ghost, local_x, local_y, local_z);
  if (0 <= result) {
    result = box_local_map[result];
  }
  return result;
}
```