ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L85
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  je     L24
  cmp    $0x2,%eax
  je     L30
  cmp    $0x3,%eax
  je     L14
L90:
  cmp    $0x4,%ebx
  je     L43
L45:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L85:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  jmp    L45
L24:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <optellen@plt>
  mov    %eax,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L90
L30:
  mov    %ebp,%ecx
  imul   %r12d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L45
L14:
  mov    %ebp,%ecx
  sub    %r12d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L45
L43:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <delen@plt>
  mov    %eax,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L45
```

tool_calls: name: parse_data
arguments: data_label: D27
datatype: string
name: parse_data
arguments: data_label: D47
datatype: string
name: parse_data
arguments: data_label: D42
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D20
datatype: string

tool: D27: 1 is optellen, 2 is vermenigvuldigen, 3 is aftrekken, 4 is delen

tool: D47: de som van %i en %i = %i
	

tool: D42: Het product van %i en %i = %i


tool: D15: Het verschil van %i en %i = %i


tool: D20: Het quotient van %i en %i = %i


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  int term1;
  int term2;
  int operator;
  if (argc == 1) {
    printf("1 is optellen, 2 is vermenigvuldigen, 3 is aftrekken, 4 is delen\n");
    return 0;
  }
  term1 = atoi(argv[1]);
  term2 = atoi(argv[2]);
  operator= atoi(argv[3]);
  if (operator== 1)
    printf("de som van %i en %i = %i\n	", term1, term2, optellen(term1, term2));
  if (operator== 2)
    printf("Het product van %i en %i = %i\n", term1, term2, term1 * term2);
  if (operator== 3)
    printf("Het verschil van %i en %i = %i\n", term1, term2, term1 - term2);
  if (operator== 4) {
    printf("Het quotient van %i en %i = %i\n", term1, term2, delen(term1, term2));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L27
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  cmp    $0x1,%eax
  je     L25
  cmp    $0x2,%eax
  je     L87
  cmp    $0x3,%eax
  je     L10
  cmp    $0x4,%eax
  jne    L67
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <delen@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
L67:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L27:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L67
L87:
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  imul   %r12d,%ecx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L67
L10:
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  sub    %r12d,%ecx
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L67
L25:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <optellen@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L67
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string
name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D1: Het quotient van %i en %i = %i


tool: D11: 1 is optellen, 2 is vermenigvuldigen, 3 is aftrekken, 4 is delen

tool: D8: Het product van %i en %i = %i


tool: D15: Het verschil van %i en %i = %i


tool: D9: de som van %i en %i = %i
	

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  int term1;
  int term2;
  int operator;
  if (argc == 1) {
    printf("1 is optellen, 2 is vermenigvuldigen, 3 is aftrekken, 4 is delen\n");
    return 0;
  }
  term1 = atoi(argv[1]);
  term2 = atoi(argv[2]);
  operator= atoi(argv[3]);
  if (operator== 1)
    printf("de som van %i en %i = %i\n	", term1, term2, optellen(term1, term2));
  if (operator== 2)
    printf("Het product van %i en %i = %i\n", term1, term2, term1 * term2);
  if (operator== 3)
    printf("Het verschil van %i en %i = %i\n", term1, term2, term1 - term2);
  if (operator== 4) {
    printf("Het quotient van %i en %i = %i\n", term1, term2, delen(term1, term2));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L56
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  cmp    $0x1,%eax
  je     L40
  cmp    $0x2,%eax
  je     L85
  cmp    $0x3,%eax
  je     L76
  cmp    $0x4,%eax
  jne    L12
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <delen@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L56:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L12
L85:
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  imul   %r12d,%ecx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L76:
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  sub    %r12d,%ecx
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L40:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <optellen@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D26
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D30
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string

tool: D18: Het quotient van %i en %i = %i


tool: D26: 1 is optellen, 2 is vermenigvuldigen, 3 is aftrekken, 4 is delen

tool: D9: Het product van %i en %i = %i


tool: D30: Het verschil van %i en %i = %i


tool: D10: de som van %i en %i = %i
	

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  int term1;
  int term2;
  int operator;
  if (argc == 1) {
    printf("1 is optellen, 2 is vermenigvuldigen, 3 is aftrekken, 4 is delen\n");
    return 0;
  }
  term1 = atoi(argv[1]);
  term2 = atoi(argv[2]);
  operator= atoi(argv[3]);
  if (operator== 1)
    printf("de som van %i en %i = %i\n	", term1, term2, optellen(term1, term2));
  if (operator== 2)
    printf("Het product van %i en %i = %i\n", term1, term2, term1 * term2);
  if (operator== 3)
    printf("Het verschil van %i en %i = %i\n", term1, term2, term1 - term2);
  if (operator== 4) {
    printf("Het quotient van %i en %i = %i\n", term1, term2, delen(term1, term2));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compare_tile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %edx,-0xc4(%rbp)
  mov    %ecx,-0xc8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa4(%rbp)
  jmp    L2
L55:
  mov    -0xc8(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0xa4(%rbp),%eax
  add    %edx,%eax
  shl    $0x7,%eax
  movslq %eax,%rdx
  mov    -0xc4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0xc0(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xa4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x90(%rbp),%rax
  add    %rdx,%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0xa4(%rbp)
L2:
  cmpl   $0x7,-0xa4(%rbp)
  jle    L55
  movl   $0x0,-0xa4(%rbp)
  jmp    L8
L33:
  mov    -0xa4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xb8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0xa0(%rbp)
  mov    -0xa4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x90(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x98(%rbp)
  mov    -0xa0(%rbp),%rax
  cmp    -0x98(%rbp),%rax
  je     L60
  mov    $0x0,%eax
  jmp    L6
L60:
  addl   $0x1,-0xa4(%rbp)
L8:
  cmpl   $0x7,-0xa4(%rbp)
  jle    L33
  mov    $0x1,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int compare_tile(uint8_t *tile, uint8_t *level, int x, int y) {
  int row;
  uint8_t buffer[32];
  for (row = 0; row < 8; ++row) {
    memcpy(buffer + row * 4, level + (y * 8 + row) * 128 + x * 4, 4);
  }
  for (row = 0; row < 8; ++row) {
    uint32_t src = *(uint32_t *)(tile + row * 4);
    uint32_t dst = *(uint32_t *)(buffer + row * 4);
    if (src != dst) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compare_tile>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  shl    $0x2,%edx
  movslq %edx,%rdx
  shl    $0xa,%ecx
  movslq %ecx,%rcx
  add    %rcx,%rdx
  lea    (%rsi,%rdx,4),%rbp
  lea    0x80(%rsp),%r12
L31:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x10,%rbx
  add    $0x200,%rbp
  cmp    %r12,%rbx
  jne    L31
  mov    $0x0,%eax
  mov    %rsp,%rdx
L45:
  mov    (%rdx,%rax,1),%rcx
  cmp    %rcx,0x0(%r13,%rax,1)
  jne    L9
  add    $0x10,%rax
  cmp    $0x80,%rax
  jne    L45
  mov    $0x1,%eax
L22:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0x0,%eax
  jmp    L22
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int compare_tile(uint8_t *tile, uint8_t *level, int x, int y) {
  int row;
  uint8_t buffer[32];
  for (row = 0; row < 8; ++row) {
    memcpy(buffer + row * 4, level + (y * 8 + row) * 128 + x * 4, 4);
  }
  for (row = 0; row < 8; ++row) {
    uint32_t src = *(uint32_t *)(tile + row * 4);
    uint32_t dst = *(uint32_t *)(buffer + row * 4);
    if (src != dst) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compare_tile>:
  endbr64
  push   %r14
  shl    $0x2,%edx
  shl    $0xa,%ecx
  push   %r13
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    %rdi,%r13
  push   %r12
  add    %rcx,%rdx
  push   %rbp
  lea    (%rsi,%rdx,4),%rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x80(%rsp),%r12
  mov    %r14,%rbx
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x4,%edx
  add    $0x10,%rbx
  call   <memcpy@plt>
  add    $0x200,%rbp
  cmp    %r12,%rbx
  jne    L21
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%r14,%rax,1),%rcx
  cmp    %rcx,0x0(%r13,%rax,1)
  jne    L20
  add    $0x10,%rax
  cmp    $0x80,%rax
  jne    L6
  mov    $0x1,%eax
L4:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  jmp    L4
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int compare_tile(uint8_t *tile, uint8_t *level, int x, int y) {
  int row;
  uint8_t buffer[32];
  for (row = 0; row < 8; ++row) {
    memcpy(buffer + row * 4, level + (y * 8 + row) * 128 + x * 4, 4);
  }
  for (row = 0; row < 8; ++row) {
    uint32_t src = *(uint32_t *)(tile + row * 4);
    uint32_t dst = *(uint32_t *)(buffer + row * 4);
    if (src != dst) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compare_tile>:
  endbr64
  push   %r13
  shl    $0x2,%edx
  shl    $0xa,%ecx
  push   %r12
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    %rdi,%r12
  push   %rbp
  add    %rcx,%rdx
  push   %rbx
  lea    (%rsi,%rdx,4),%rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x80(%rsp),%r13
  nopl   (%rax)
L0:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x4,%edx
  add    $0x10,%rbx
  call   <memcpy@plt>
  add    $0x200,%rbp
  cmp    %rbx,%r13
  jne    L0
  mov    (%r12),%rax
  cmp    %rax,(%rsp)
  jne    L25
  mov    0x10(%r12),%rax
  cmp    %rax,0x10(%rsp)
  jne    L25
  mov    0x20(%rsp),%rax
  cmp    %rax,0x20(%r12)
  jne    L25
  mov    0x30(%rsp),%rax
  cmp    %rax,0x30(%r12)
  jne    L25
  mov    0x40(%rsp),%rax
  cmp    %rax,0x40(%r12)
  jne    L25
  mov    0x50(%rsp),%rax
  cmp    %rax,0x50(%r12)
  jne    L25
  mov    0x60(%rsp),%rax
  cmp    %rax,0x60(%r12)
  jne    L25
  mov    0x70(%rsp),%rax
  cmp    %rax,0x70(%r12)
  sete   %al
  movzbl %al,%eax
L6:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L81
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  jmp    L6
L81:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int compare_tile(uint8_t *tile, uint8_t *level, int x, int y) {
  int row;
  uint8_t buffer[32];
  for (row = 0; row < 8; ++row) {
    memcpy(buffer + row * 4, level + (y * 8 + row) * 128 + x * 4, 4);
  }
  for (row = 0; row < 8; ++row) {
    uint32_t src = *(uint32_t *)(tile + row * 4);
    uint32_t dst = *(uint32_t *)(buffer + row * 4);
    if (src != dst) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<invSqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x24(%rbp),%xmm1
  movss  D0(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    $0x5f3759df,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0xc(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  D5(%rip),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D5
type_guessed: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x3f]}

tool: {"D5": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float invSqrt(float x) {
  float halfx = 0.5f * x;
  float y = x;
  int32_t i = *(int32_t *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (1.5f - (halfx * y * y));
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<invSqrt>:
  endbr64
  movd   %xmm0,%edx
  sar    %edx
  mov    $0x5f3759df,%eax
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  D2(%rip),%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  movss  D13(%rip),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: byte[4]
name: read_data
arguments: data_label: D13
type_guessed: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

tool: {"D13": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float invSqrt(float x) {
  float halfx = 0.5f * x;
  float y = x;
  int32_t i = *(int32_t *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (1.5f - (halfx * y * y));
  return y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<invSqrt>:
  endbr64
  movd   %xmm0,%edx
  mov    $0x5f3759df,%eax
  movss  D18(%rip),%xmm1
  mulss  D2(%rip),%xmm0
  sar    %edx
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
data_type: byte[4]
name: parse_data
arguments: data_tag: D2
data_type: byte[4]

tool: {"D18": [0x00,0x00,0xc0,0x3f]}

tool: {"D2": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float invSqrt(float x) {
  float halfx = 0.5f * x;
  float y = x;
  int32_t i = *(int32_t *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (1.5f - (halfx * y * y));
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<invSqrt>:
  endbr64
  movd   %xmm0,%edx
  mov    $0x5f3759df,%eax
  movss  D5(%rip),%xmm1
  mulss  D17(%rip),%xmm0
  sar    %edx
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: byte[4]
name: parse_data
arguments: label: D17
type_infered: byte[4]

tool: {"D5": [0x00,0x00,0xc0,0x3f]}

tool: {"D17": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float invSqrt(float x) {
  float halfx = 0.5f * x;
  float y = x;
  int32_t i = *(int32_t *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (1.5f - (halfx * y * y));
  return y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmd_curs_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L15
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L26
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L49
L26:
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <curs_set@plt>
  mov    %eax,%edi
  call   <report_int@plt>
  jmp    L49
L15:
  nop
L49:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string

tool: D7: %d

tool: D19: BAD ARGUMENT

assistant: ```c
void cmd_curs_set(int nargs, char **args) {
  int vis;
  if (check_arg_count(nargs, 1) == 1)
    return;
  if (sscanf(args[0], "%d", &vis) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_int(curs_set(vis));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_curs_set>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L17
  lea    0x4(%rsp),%rdx
  lea    D7(%rip),%rsi
  mov    (%rbx),%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L22
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0x4(%rsp),%edi
  call   <curs_set@plt>
  mov    %eax,%edi
  call   <report_int@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  ret
L22:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D19(%rip),%rdi
  call   <report_error@plt>
  jmp    L17
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D19
type: string

tool: D7: %d

tool: D19: BAD ARGUMENT

assistant: ```c
void cmd_curs_set(int nargs, char **args) {
  int vis;
  if (check_arg_count(nargs, 1) == 1)
    return;
  if (sscanf(args[0], "%d", &vis) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_int(curs_set(vis));
}
```
user: What is the c source code of the assembly code below:

```asm
<cmd_curs_set>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L2
  mov    (%rbx),%rdi
  lea    0x4(%rsp),%rdx
  lea    D13(%rip),%rsi
  call   <sscanf@plt>
  mov    $0x1,%edi
  test   %rax,%rax
  je     L4
  call   <report_count@plt>
  mov    0x4(%rsp),%edi
  call   <curs_set@plt>
  mov    %eax,%edi
  call   <report_int@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  call   <report_count@plt>
  lea    D15(%rip),%rdi
  call   <report_error@plt>
  jmp    L2
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D13: %d

tool: D15: BAD ARGUMENT

assistant: ```c
void cmd_curs_set(int nargs, char **args) {
  int vis;
  if (check_arg_count(nargs, 1) == 1)
    return;
  if (sscanf(args[0], "%d", &vis) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_int(curs_set(vis));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmd_curs_set>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L29
  mov    (%rbx),%rdi
  lea    0x4(%rsp),%rdx
  lea    D7(%rip),%rsi
  call   <sscanf@plt>
  mov    $0x1,%edi
  test   %rax,%rax
  je     L23
  call   <report_count@plt>
  mov    0x4(%rsp),%edi
  call   <curs_set@plt>
  mov    %eax,%edi
  call   <report_int@plt>
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L23:
  call   <report_count@plt>
  lea    D4(%rip),%rdi
  call   <report_error@plt>
  jmp    L29
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D7: %d

tool: D4: BAD ARGUMENT

assistant: ```c
void cmd_curs_set(int nargs, char **args) {
  int vis;
  if (check_arg_count(nargs, 1) == 1)
    return;
  if (sscanf(args[0], "%d", &vis) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_int(curs_set(vis));
}
```