ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <readinput@plt>
  test   %eax,%eax
  je     L81
  cmp    $0x1,%eax
  je     L58
  cmp    $0xffffffff,%eax
  je     L16
  cmp    $0xfffffffe,%eax
  je     L1
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L81:
  mov    %rbp,%rsi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L16:
  mov    %rbp,%rsi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L1:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L3
L58:
  mov    %rbp,%rsi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string
name: disassemble_data
arguments: data_tag: D40
type_infered: string
name: disassemble_data
arguments: data_tag: D47
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D46
type_infered: string

tool: D5: abort: something is not right


tool: D40: client says %s which means yes


tool: D47: can't translate client response %s


tool: D9: message length longer than 10 characters

tool: D46: client says %s which means no


assistant: ```c
main() {
  int x;
  char c[10];
  x = readinput(c);
  if (x == 0) {
    printf("client says %s which means yes\n", c);
  } else if (x == 1) {
    printf("client says %s which means no\n", c);
  } else if (x == -1) {
    printf("can't translate client response %s\n", c);
  } else if (x == -2) {
    printf("message length longer than 10 characters\n");
  } else {
    printf("abort: something is not right\n", c);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L122
  mov    $0x1,%eax
  jmp    L108
L122:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L53
  mov    $0x1,%eax
  jmp    L108
L53:
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L158
  mov    $0x1,%eax
  jmp    L108
L158:
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L100
  mov    $0x1,%eax
  jmp    L108
L100:
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L89
  mov    $0x1,%eax
  jmp    L108
L89:
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L76
  mov    $0x1,%eax
  jmp    L108
L76:
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L12
  mov    $0x1,%eax
  jmp    L108
L12:
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L147
  mov    $0x1,%eax
  jmp    L108
L147:
  mov    $0x0,%eax
L108:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (test__subvdi3(0x8000000000000000LL, -1))
    return 1;
  if (test__subvdi3(0x8000000000000000LL, 0))
    return 1;
  if (test__subvdi3(-1, 0x8000000000000000LL))
    return 1;
  if (test__subvdi3(0x7FFFFFFFFFFFFFFLL, 1))
    return 1;
  if (test__subvdi3(0x7FFFFFFFFFFFFFFFLL, 0))
    return 1;
  if (test__subvdi3(1, 0x7FFFFFFFFFFFFFFLL))
    return 1;
  if (test__subvdi3(0, 0x7FFFFFFFFFFFFFFFLL))
    return 1;
  if (test__subvdi3(-1, 0x7FFFFFFFFFFFFFFFLL))
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <test__subvdi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L67
L62:
  add    $0x8,%rsp
  ret
L67:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <test__subvdi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L62
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <test__subvdi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L62
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <test__subvdi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L62
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <test__subvdi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L62
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <test__subvdi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L62
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <test__subvdi3@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L62
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L62
```

assistant: ```c
int main() {
  if (test__subvdi3(0x8000000000000000LL, -1))
    return 1;
  if (test__subvdi3(0x8000000000000000LL, 0))
    return 1;
  if (test__subvdi3(-1, 0x8000000000000000LL))
    return 1;
  if (test__subvdi3(0x7FFFFFFFFFFFFFFLL, 1))
    return 1;
  if (test__subvdi3(0x7FFFFFFFFFFFFFFFLL, 0))
    return 1;
  if (test__subvdi3(1, 0x7FFFFFFFFFFFFFFLL))
    return 1;
  if (test__subvdi3(0, 0x7FFFFFFFFFFFFFFFLL))
    return 1;
  if (test__subvdi3(-1, 0x7FFFFFFFFFFFFFFFLL))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  mov    $0xffffffff,%esi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L13
L51:
  mov    $0x1,%eax
L50:
  add    $0x8,%rsp
  ret
L13:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L51
  xor    %esi,%esi
  or     $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L51
  or     $0xffffffff,%edi
  mov    $0x1,%esi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L51
  xor    %esi,%esi
  or     $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L51
  or     $0xffffffff,%esi
  mov    $0x1,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L51
  or     $0xffffffff,%esi
  xor    %edi,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L51
  or     $0xffffffff,%esi
  or     $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L50
```

assistant: ```c
int main() {
  if (test__subvdi3(0x8000000000000000LL, -1))
    return 1;
  if (test__subvdi3(0x8000000000000000LL, 0))
    return 1;
  if (test__subvdi3(-1, 0x8000000000000000LL))
    return 1;
  if (test__subvdi3(0x7FFFFFFFFFFFFFFLL, 1))
    return 1;
  if (test__subvdi3(0x7FFFFFFFFFFFFFFFLL, 0))
    return 1;
  if (test__subvdi3(1, 0x7FFFFFFFFFFFFFFLL))
    return 1;
  if (test__subvdi3(0, 0x7FFFFFFFFFFFFFFFLL))
    return 1;
  if (test__subvdi3(-1, 0x7FFFFFFFFFFFFFFFLL))
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  mov    $0xffffffff,%esi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  je     L27
L63:
  mov    $0x1,%eax
L51:
  add    $0x8,%rsp
  ret
L27:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L63
  xor    %esi,%esi
  or     $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L63
  or     $0xffffffff,%edi
  mov    $0x1,%esi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L63
  xor    %esi,%esi
  or     $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L63
  or     $0xffffffff,%esi
  mov    $0x1,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L63
  or     $0xffffffff,%esi
  xor    %edi,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  jne    L63
  or     $0xffffffff,%esi
  or     $0xffffffff,%edi
  call   <test__subvdi3@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L51
```

assistant: ```c
int main() {
  if (test__subvdi3(0x8000000000000000LL, -1))
    return 1;
  if (test__subvdi3(0x8000000000000000LL, 0))
    return 1;
  if (test__subvdi3(-1, 0x8000000000000000LL))
    return 1;
  if (test__subvdi3(0x7FFFFFFFFFFFFFFLL, 1))
    return 1;
  if (test__subvdi3(0x7FFFFFFFFFFFFFFFLL, 0))
    return 1;
  if (test__subvdi3(1, 0x7FFFFFFFFFFFFFFLL))
    return 1;
  if (test__subvdi3(0, 0x7FFFFFFFFFFFFFFFLL))
    return 1;
  if (test__subvdi3(-1, 0x7FFFFFFFFFFFFFFFLL))
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_rudimentary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <read_header@plt>
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  jne    L91
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0x40(%rbp)
  jne    L91
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x44(%rbp)
  je     L60
L91:
  mov    $0x0,%eax
  jmp    L14
L60:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <check_for_done@plt>
  test   %eax,%eax
  jne    L59
  mov    $0x0,%eax
  jmp    L14
L59:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  lea    -0x18(%rbp),%rdi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <compute_queue_size@plt>
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jne    L69
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x40(%rbp)
  jl     L69
  mov    -0x24(%rbp),%eax
  test   %eax,%eax
  jne    L69
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  je     L74
L69:
  mov    $0x0,%eax
  jmp    L14
L74:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    -0x44(%rbp),%edx
  mov    -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <check_executed@plt>
  test   %eax,%eax
  jne    L105
  mov    $0x0,%eax
  jmp    L14
L105:
  mov    $0x1,%eax
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L132
  call   <__stack_chk_fail@plt>
L132:
  leave
  ret
```

assistant: ```c
int check_rudimentary(FILE *in, int workers, int queue_size, int iterations) {
  int final_threads, threads_max, threads_min, admitted_threads;
  int actual_workers, actual_queue_size, actual_iterations;
  rewind(in);
  read_header(in, &actual_workers, &actual_queue_size, &actual_iterations);
  if (!((workers == actual_workers) && (queue_size == actual_queue_size) && (iterations == actual_iterations)))
    return 0;
  rewind(in);
  if (!check_for_done(in))
    return 0;
  rewind(in);
  compute_queue_size(in, &final_threads, &threads_max, &threads_min, &admitted_threads);
  if (!((threads_min == 0) && (threads_max <= queue_size) && (final_threads == 0) && (admitted_threads == workers)))
    return 0;
  rewind(in);
  if (!check_executed(in, workers, iterations))
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_rudimentary>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <rewind@plt>
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  mov    %rbx,%rdi
  call   <read_header@plt>
  mov    $0x0,%eax
  cmp    %ebp,0x1c(%rsp)
  jne    L45
  cmp    %r12d,0x20(%rsp)
  jne    L45
  cmp    %r13d,0x24(%rsp)
  je     L11
L45:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    %rbx,%rdi
  call   <rewind@plt>
  mov    %rbx,%rdi
  call   <check_for_done@plt>
  test   %eax,%eax
  je     L45
  mov    %rbx,%rdi
  call   <rewind@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x18(%rsp),%r8
  mov    %rbx,%rdi
  call   <compute_queue_size@plt>
  mov    $0x0,%eax
  cmp    %r12d,0x10(%rsp)
  jg     L45
  mov    0x14(%rsp),%eax
  or     0xc(%rsp),%eax
  jne    L23
  cmp    %ebp,0x18(%rsp)
  jne    L45
  mov    %rbx,%rdi
  call   <rewind@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <check_executed@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L45
L23:
  mov    $0x0,%eax
  jmp    L45
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_rudimentary(FILE *in, int workers, int queue_size, int iterations) {
  int final_threads, threads_max, threads_min, admitted_threads;
  int actual_workers, actual_queue_size, actual_iterations;
  rewind(in);
  read_header(in, &actual_workers, &actual_queue_size, &actual_iterations);
  if (!((workers == actual_workers) && (queue_size == actual_queue_size) && (iterations == actual_iterations)))
    return 0;
  rewind(in);
  if (!check_for_done(in))
    return 0;
  rewind(in);
  compute_queue_size(in, &final_threads, &threads_max, &threads_min, &admitted_threads);
  if (!((threads_min == 0) && (threads_max <= queue_size) && (final_threads == 0) && (admitted_threads == workers)))
    return 0;
  rewind(in);
  if (!check_executed(in, workers, iterations))
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_rudimentary>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <rewind@plt>
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0x1c(%rsp),%rsi
  call   <read_header@plt>
  cmp    %r12d,0x1c(%rsp)
  jne    L39
  cmp    %ebx,0x20(%rsp)
  je     L7
L39:
  xor    %eax,%eax
L2:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    %r13d,0x24(%rsp)
  jne    L39
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    %rbp,%rdi
  call   <check_for_done@plt>
  test   %eax,%eax
  je     L39
  mov    %rbp,%rdi
  call   <rewind@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  lea    0x18(%rsp),%r8
  call   <compute_queue_size@plt>
  mov    0x14(%rsp),%eax
  cmp    %ebx,0x10(%rsp)
  jg     L39
  or     0xc(%rsp),%eax
  jne    L39
  cmp    %r12d,0x18(%rsp)
  jne    L39
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <check_executed@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L2
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_rudimentary(FILE *in, int workers, int queue_size, int iterations) {
  int final_threads, threads_max, threads_min, admitted_threads;
  int actual_workers, actual_queue_size, actual_iterations;
  rewind(in);
  read_header(in, &actual_workers, &actual_queue_size, &actual_iterations);
  if (!((workers == actual_workers) && (queue_size == actual_queue_size) && (iterations == actual_iterations)))
    return 0;
  rewind(in);
  if (!check_for_done(in))
    return 0;
  rewind(in);
  compute_queue_size(in, &final_threads, &threads_max, &threads_min, &admitted_threads);
  if (!((threads_min == 0) && (threads_max <= queue_size) && (final_threads == 0) && (admitted_threads == workers)))
    return 0;
  rewind(in);
  if (!check_executed(in, workers, iterations))
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_rudimentary>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <rewind@plt>
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0x1c(%rsp),%rsi
  call   <read_header@plt>
  cmp    %r12d,0x1c(%rsp)
  jne    L50
  cmp    %ebx,0x20(%rsp)
  je     L5
L50:
  xor    %eax,%eax
L29:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  cmp    %r13d,0x24(%rsp)
  jne    L50
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    %rbp,%rdi
  call   <check_for_done@plt>
  test   %eax,%eax
  je     L50
  mov    %rbp,%rdi
  call   <rewind@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  lea    0x18(%rsp),%r8
  call   <compute_queue_size@plt>
  mov    0x14(%rsp),%eax
  cmp    %ebx,0x10(%rsp)
  jg     L50
  or     0xc(%rsp),%eax
  jne    L50
  cmp    %r12d,0x18(%rsp)
  jne    L50
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <check_executed@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L29
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_rudimentary(FILE *in, int workers, int queue_size, int iterations) {
  int final_threads, threads_max, threads_min, admitted_threads;
  int actual_workers, actual_queue_size, actual_iterations;
  rewind(in);
  read_header(in, &actual_workers, &actual_queue_size, &actual_iterations);
  if (!((workers == actual_workers) && (queue_size == actual_queue_size) && (iterations == actual_iterations)))
    return 0;
  rewind(in);
  if (!check_for_done(in))
    return 0;
  rewind(in);
  compute_queue_size(in, &final_threads, &threads_max, &threads_min, &admitted_threads);
  if (!((threads_min == 0) && (threads_max <= queue_size) && (final_threads == 0) && (admitted_threads == workers)))
    return 0;
  rewind(in);
  if (!check_executed(in, workers, iterations))
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L3
  mov    -0x4(%rbp),%eax
  jmp    L10
L3:
  mov    -0x8(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a < b)
    return a;
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a < b)
    return a;
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a < b)
    return a;
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dozenify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0xb,%eax
  je     L62
  cmp    $0xb,%eax
  jg     L35
  cmp    $0x9,%eax
  jg     L15
  test   %eax,%eax
  jns    L29
  jmp    L35
L15:
  cmp    $0xa,%eax
  je     L84
  jmp    L35
L29:
  movzbl -0x4(%rbp),%edx
  mov    $0x67,%ecx
  mov    %ecx,%eax
  imul   %dl
  shr    $0x8,%ax
  sar    $0x2,%al
  mov    %edx,%esi
  sar    $0x7,%sil
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  jmp    L35
L84:
  mov    $0x58,%eax
  jmp    L35
L62:
  mov    $0x45,%eax
  jmp    L35
L35:
  pop    %rbp
  ret
```

assistant: ```c
char dozenify(char num) {
  switch (num) {
  case 0:
  case 1:
  case 2:
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
    return (num % 10) + '0';
  case 10:
    return 'X';
  case 11:
    return 'E';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dozenify>:
  endbr64
  mov    $0x58,%eax
  cmp    $0xa,%dil
  je     L17
  jg     L0
  cmp    $0x9,%dil
  ja     L17
  mov    $0x67,%edx
  mov    %edx,%eax
  imul   %dil
  sar    $0xa,%ax
  mov    %edi,%edx
  sar    $0x7,%dl
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  lea    0x30(%rdi),%eax
  ret
L0:
  mov    $0x45,%eax
  cmp    $0xb,%dil
L17:
  ret
```

assistant: ```c
char dozenify(char num) {
  switch (num) {
  case 0:
  case 1:
  case 2:
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
    return (num % 10) + '0';
  case 10:
    return 'X';
  case 11:
    return 'E';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dozenify>:
  endbr64
  mov    $0x58,%eax
  cmp    $0xa,%dil
  je     L26
  jg     L20
  cmp    $0x9,%dil
  ja     L26
  lea    0x30(%rdi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0x45,%eax
L26:
  ret
```

assistant: ```c
char dozenify(char num) {
  switch (num) {
  case 0:
  case 1:
  case 2:
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
    return (num % 10) + '0';
  case 10:
    return 'X';
  case 11:
    return 'E';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dozenify>:
  endbr64
  mov    $0x58,%eax
  cmp    $0xa,%dil
  je     L10
  jg     L15
  cmp    $0x9,%dil
  ja     L10
  lea    0x30(%rdi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x45,%eax
L10:
  ret
```

assistant: ```c
char dozenify(char num) {
  switch (num) {
  case 0:
  case 1:
  case 2:
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
    return (num % 10) + '0';
  case 10:
    return 'X';
  case 11:
    return 'E';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<send_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L13:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x24(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L46
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L13
  jmp    L34
L46:
  nop
L34:
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L16
  mov    -0x8(%rbp),%eax
  jmp    L49
L16:
  mov    $0xffffffff,%eax
L49:
  leave
  ret
```

assistant: ```c
int send_all(int s, char *buf, int len, int flags) {
  int total = 0;
  int n;
  while (total < len) {
    n = send(s, buf + total, len - total, flags);
    if (n == -1)
      break;
    total += n;
  }
  return (n == -1 ? -1 : total);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<send_all>:
  endbr64
  test   %edx,%edx
  jle    L12
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    %ecx,%r14d
  mov    $0x0,%ebx
L19:
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r13,%rsi
  mov    %r14d,%ecx
  mov    %r12d,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  je     L13
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jg     L19
  mov    %ebx,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int send_all(int s, char *buf, int len, int flags) {
  int total = 0;
  int n;
  while (total < len) {
    n = send(s, buf + total, len - total, flags);
    if (n == -1)
      break;
    total += n;
  }
  return (n == -1 ? -1 : total);
}
```