ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<tabulate>:
  endbr64
  subsd  %xmm0,%xmm1
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  divsd  %xmm2,%xmm1
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm2,0x18(%rsp)
  movapd %xmm1,%xmm0
  call   <floor@plt>
  test   %eax,%eax
  js     L16
  mov    %eax,%ebx
  xor    %r13d,%r13d
  lea    D7(%rip),%r12
  xchg   %ax,%ax
L4:
  pxor   %xmm2,%xmm2
  cvtsi2sd %r13d,%xmm2
  mulsd  0x18(%rsp),%xmm2
  add    $0x1,%r13d
  addsd  0x10(%rsp),%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   *%rbp
  movsd  0x8(%rsp),%xmm2
  mov    %r12,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    %r13d,%ebx
  jge    L4
L16:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: %10.5f %10.5f


assistant: ```c
void tabulate(double (*f)(double), double first, double last, double incr) {
  double x;
  int i, num_intervals;
  num_intervals = floor((last - first) / incr);
  for (i = 0; i <= num_intervals; i++) {
    x = first + i * incr;
    printf("%10.5f %10.5f\n", x, f(x));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__print_sw_title>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D9
data_type: string

tool: D18:  ----------- [%s] ----------- 


tool: D9:  ::. Usage: %s <parameters>



assistant: ```c
void __print_sw_title(char *sw_name) {
  printf(" ----------- [%s] ----------- \n", sw_name);
  printf(" ::. Usage: %s <parameters>\n\n", sw_name);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__print_sw_title>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string

tool: D0:  ----------- [%s] ----------- 


tool: D14:  ::. Usage: %s <parameters>



assistant: ```c
void __print_sw_title(char *sw_name) {
  printf(" ----------- [%s] ----------- \n", sw_name);
  printf(" ::. Usage: %s <parameters>\n\n", sw_name);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__print_sw_title>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D5:  ----------- [%s] ----------- 


tool: D2:  ::. Usage: %s <parameters>



assistant: ```c
void __print_sw_title(char *sw_name) {
  printf(" ----------- [%s] ----------- \n", sw_name);
  printf(" ::. Usage: %s <parameters>\n\n", sw_name);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__print_sw_title>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D9:  ----------- [%s] ----------- 


tool: D7:  ::. Usage: %s <parameters>



assistant: ```c
void __print_sw_title(char *sw_name) {
  printf(" ----------- [%s] ----------- \n", sw_name);
  printf(" ::. Usage: %s <parameters>\n\n", sw_name);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r15
  mov    %rdx,-0x10(%rsp)
  movl   $0x0,-0x1c(%rsp)
  movl   $0x0,-0x14(%rsp)
  lea    0x20(%rsi),%rax
  mov    %rax,-0x8(%rsp)
  pxor   %xmm7,%xmm7
  jmp    L57
L91:
  add    $0xc0,%rdi
  add    $0x2,%esi
  add    $0x20,%rcx
  cmp    $0x6,%esi
  je     L92
L117:
  lea    -0x20(%rcx),%rax
  mov    %rdi,%rdx
L69:
  movsd  (%rax),%xmm0
  movsd  (%rdx),%xmm4
  movapd %xmm0,%xmm3
  mulsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm2
  movsd  0x8(%rax),%xmm3
  movsd  0x8(%rdx),%xmm5
  movapd %xmm3,%xmm6
  mulsd  %xmm5,%xmm6
  subsd  %xmm6,%xmm2
  mulsd  %xmm5,%xmm0
  addsd  %xmm0,%xmm1
  mulsd  %xmm3,%xmm4
  addsd  %xmm4,%xmm1
  add    $0x10,%rax
  add    $0x60,%rdx
  cmp    %rcx,%rax
  jne    L69
  jmp    L91
L92:
  movsd  %xmm2,(%r8)
  movsd  %xmm1,0x8(%r8)
  add    $0x1,%r9d
  add    $0x10,%r8
  add    $0x10,%r10
  cmp    $0x2,%r9d
  je     L70
L93:
  mov    %r11,%rcx
  mov    %r10,%rdi
  mov    $0x0,%esi
  movapd %xmm7,%xmm1
  movapd %xmm7,%xmm2
  jmp    L117
L70:
  add    $0x1,%ebx
  add    $0x2,%ebp
  add    $0x20,%r12
  cmp    $0x3,%ebx
  je     L45
L29:
  lea    0x0(%rbp,%rbp,1),%eax
  cltq
  lea    (%r15,%rax,8),%r8
  mov    %r12,%r10
  mov    $0x0,%r9d
  jmp    L93
L45:
  add    $0x3,%r13d
  add    $0x6,%r14d
  cmp    -0x18(%rsp),%r13d
  je     L64
L41:
  mov    -0x10(%rsp),%r12
  lea    0x0(%r13,%r13,1),%r11d
  movslq %r11d,%r11
  shl    $0x4,%r11
  add    -0x8(%rsp),%r11
  mov    %r14d,%ebp
  mov    $0x0,%ebx
  jmp    L29
L64:
  addl   $0x6,-0x14(%rsp)
  addl   $0x2,-0x1c(%rsp)
  mov    -0x1c(%rsp),%eax
  cmp    $0x6,%eax
  je     L9
L57:
  mov    -0x14(%rsp),%r13d
  lea    0x0(%r13,%r13,1),%r14d
  mov    -0x1c(%rsp),%eax
  lea    0x6(%rax,%rax,2),%eax
  mov    %eax,-0x18(%rsp)
  jmp    L41
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mul(double v[], const double x[], const double y[]) {
  int a, i, b, j;
  int c, k;
  for (a = 0; a < 3; a++)
    for (i = 0; i < 2; i++) {
      for (b = 0; b < 3; b++)
        for (j = 0; j < 2; j++) {
          double vr = 0;
          double vi = 0;
          for (c = 0; c < 3; c++)
            for (k = 0; k < 2; k++) {
              vr += (&((x)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[0] * (&((y)[2 * ((j) + 2 * ((b) + 3 * ((k) + 2 * (c))))]))[0];
              vr -= (&((x)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[1] * (&((y)[2 * ((j) + 2 * ((b) + 3 * ((k) + 2 * (c))))]))[1];
              vi += (&((x)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[0] * (&((y)[2 * ((j) + 2 * ((b) + 3 * ((k) + 2 * (c))))]))[1];
              vi += (&((x)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[1] * (&((y)[2 * ((j) + 2 * ((b) + 3 * ((k) + 2 * (c))))]))[0];
            }
          (&((v)[2 * ((j) + 2 * ((b) + 3 * ((i) + 2 * (a))))]))[0] = vr;
          (&((v)[2 * ((j) + 2 * ((b) + 3 * ((i) + 2 * (a))))]))[1] = vi;
        }
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mul>:
  endbr64
  push   %r15
  lea    0x20(%rsi),%rax
  mov    %rdi,%r15
  pxor   %xmm7,%xmm7
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,-0x8(%rsp)
  mov    %rax,-0x10(%rsp)
L26:
  lea    0x6(%r13),%eax
  mov    -0x10(%rsp),%r12
  lea    0x0(%r13,%r13,1),%r14d
  mov    %eax,-0x14(%rsp)
L65:
  mov    -0x8(%rsp),%rbp
  mov    %r14d,%ebx
  xor    %r11d,%r11d
L35:
  lea    (%rbx,%rbx,1),%eax
  mov    %rbp,%r9
  xor    %r10d,%r10d
  cltq
  lea    (%r15,%rax,8),%r8
L56:
  mov    %r12,%rcx
  mov    %r9,%rdi
  movapd %xmm7,%xmm1
  xor    %esi,%esi
  movapd %xmm7,%xmm2
L18:
  lea    -0x20(%rcx),%rax
  mov    %rdi,%rdx
L33:
  movsd  (%rax),%xmm0
  movsd  (%rdx),%xmm4
  add    $0x10,%rax
  add    $0x60,%rdx
  movsd  -0x58(%rdx),%xmm5
  movapd %xmm0,%xmm3
  mulsd  %xmm4,%xmm3
  mulsd  %xmm5,%xmm0
  addsd  %xmm3,%xmm2
  movsd  -0x8(%rax),%xmm3
  addsd  %xmm0,%xmm1
  mulsd  %xmm3,%xmm4
  movapd %xmm3,%xmm6
  mulsd  %xmm5,%xmm6
  addsd  %xmm4,%xmm1
  subsd  %xmm6,%xmm2
  cmp    %rax,%rcx
  jne    L33
  add    $0x2,%esi
  add    $0xc0,%rdi
  add    $0x20,%rcx
  cmp    $0x6,%esi
  jne    L18
  movsd  %xmm2,(%r8)
  add    $0x10,%r9
  add    $0x10,%r8
  movsd  %xmm1,-0x8(%r8)
  cmp    $0x1,%r10d
  je     L34
  mov    $0x1,%r10d
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%r11d
  add    $0x2,%ebx
  add    $0x20,%rbp
  cmp    $0x3,%r11d
  jne    L35
  add    $0x60,%r12
  add    $0x3,%r13d
  add    $0x6,%r14d
  cmp    %r13d,-0x14(%rsp)
  jne    L65
  addq   $0xc0,-0x10(%rsp)
  mov    -0x14(%rsp),%r13d
  cmp    $0x12,%r13d
  jne    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mul(double v[], const double x[], const double y[]) {
  int a, i, b, j;
  int c, k;
  for (a = 0; a < 3; a++)
    for (i = 0; i < 2; i++) {
      for (b = 0; b < 3; b++)
        for (j = 0; j < 2; j++) {
          double vr = 0;
          double vi = 0;
          for (c = 0; c < 3; c++)
            for (k = 0; k < 2; k++) {
              vr += (&((x)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[0] * (&((y)[2 * ((j) + 2 * ((b) + 3 * ((k) + 2 * (c))))]))[0];
              vr -= (&((x)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[1] * (&((y)[2 * ((j) + 2 * ((b) + 3 * ((k) + 2 * (c))))]))[1];
              vi += (&((x)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[0] * (&((y)[2 * ((j) + 2 * ((b) + 3 * ((k) + 2 * (c))))]))[1];
              vi += (&((x)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[1] * (&((y)[2 * ((j) + 2 * ((b) + 3 * ((k) + 2 * (c))))]))[0];
            }
          (&((v)[2 * ((j) + 2 * ((b) + 3 * ((i) + 2 * (a))))]))[0] = vr;
          (&((v)[2 * ((j) + 2 * ((b) + 3 * ((i) + 2 * (a))))]))[1] = vi;
        }
    }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <test_getaddrinfo@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_getaddrinfo(argv[1], argv[2]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%rdi
  mov    %rax,%rsi
  call   <test_getaddrinfo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_getaddrinfo(argv[1], argv[2]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x10(%rsi),%r8
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  call   <test_getaddrinfo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_getaddrinfo(argv[1], argv[2]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x10(%rsi),%r8
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  call   <test_getaddrinfo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_getaddrinfo(argv[1], argv[2]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L36
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L9
L36:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L24
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, int maxlen) {
  int i;
  for (i = 0; i < maxlen; i++) {
    if (s1[i] != s2[i])
      return s1[i] - s2[i];
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncmp>:
  endbr64
  test   %edx,%edx
  jle    L11
  mov    %edx,%edx
  mov    $0x0,%eax
L29:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L17
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L29
  mov    $0x0,%eax
  ret
L17:
  movsbl %cl,%eax
  movsbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, int maxlen) {
  int i;
  for (i = 0; i < maxlen; i++) {
    if (s1[i] != s2[i])
      return s1[i] - s2[i];
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncmp>:
  endbr64
  test   %edx,%edx
  jle    L13
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L24
  nop
L38:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L13
L24:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L38
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, int maxlen) {
  int i;
  for (i = 0; i < maxlen; i++) {
    if (s1[i] != s2[i])
      return s1[i] - s2[i];
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp>:
  endbr64
  test   %edx,%edx
  jle    L28
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L30
  nop
L37:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L28
L30:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L37
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, int maxlen) {
  int i;
  for (i = 0; i < maxlen; i++) {
    if (s1[i] != s2[i])
      return s1[i] - s2[i];
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<qacc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  %xmm6,-0x48(%rbp)
  movsd  %xmm7,-0x50(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  D0(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movapd %xmm0,%xmm4
  subsd  -0x48(%rbp),%xmm4
  movsd  %xmm4,-0x60(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm5
  divsd  -0x20(%rbp),%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mulsd  -0x60(%rbp),%xmm0
  movapd %xmm0,%xmm6
  addsd  -0x58(%rbp),%xmm6
  movsd  %xmm6,-0x58(%rbp)
  movsd  -0x8(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  -0x20(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x40(%rbp),%xmm0
  addsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0x30(%rbp),%xmm0
  addsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm7
  addsd  -0x40(%rbp),%xmm7
  movapd %xmm7,%xmm1
  movsd  D7(%rip),%xmm0
  movapd %xmm1,%xmm3
  addsd  %xmm0,%xmm3
  movsd  %xmm3,-0x60(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm2
  movsd  D0(%rip),%xmm1
  addsd  %xmm2,%xmm1
  movapd %xmm0,%xmm5
  divsd  %xmm1,%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mulsd  -0x60(%rbp),%xmm0
  movsd  -0x58(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: f64
name: read_data
arguments: data_tag: D7
type_infered: f64

tool: D0: 1

tool: D7: 2

assistant: ```c
double qacc(double w, double v, double s, double a1, double a2, double a3, double alpha, double beta) {
  double r;
  r = s / (s - 1.0);
  return beta * (w - v) + (a1 + 1.0 - alpha) * log(w / v) + a3 * log((r + w) / (r + v)) - (a1 + a2 + a3 + 2.0) * log((1.0 + w) / (1.0 + v));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<qacc>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movapd %xmm0,%xmm8
  movsd  %xmm3,0x20(%rsp)
  movq   %xmm4,%r15
  movsd  %xmm5,0x28(%rsp)
  movq   %xmm6,%rbp
  movq   %xmm7,%r12
  movapd %xmm2,%xmm0
  subsd  D12(%rip),%xmm0
  divsd  %xmm0,%xmm2
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm8,0x8(%rsp)
  movapd %xmm8,%xmm0
  movsd  %xmm1,0x10(%rsp)
  divsd  %xmm1,%xmm0
  call   <log@plt>
  movq   %xmm0,%r14
  movsd  0x18(%rsp),%xmm6
  movapd %xmm6,%xmm2
  addsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm0
  addsd  0x10(%rsp),%xmm6
  divsd  %xmm6,%xmm0
  call   <log@plt>
  movq   %xmm0,%rbx
  movsd  D12(%rip),%xmm2
  addsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm0
  movsd  D12(%rip),%xmm4
  addsd  0x10(%rsp),%xmm4
  divsd  %xmm4,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movsd  D12(%rip),%xmm7
  movsd  0x20(%rsp),%xmm3
  addsd  %xmm3,%xmm7
  movq   %rbp,%xmm2
  subsd  %xmm2,%xmm7
  movq   %r14,%xmm4
  mulsd  %xmm4,%xmm7
  movsd  0x8(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  movq   %r12,%xmm6
  mulsd  %xmm6,%xmm0
  addsd  %xmm0,%xmm7
  movq   %rbx,%xmm0
  movsd  0x28(%rsp),%xmm5
  mulsd  %xmm5,%xmm0
  addsd  %xmm7,%xmm0
  movq   %r15,%xmm7
  addsd  %xmm7,%xmm3
  movapd %xmm3,%xmm4
  addsd  %xmm5,%xmm4
  addsd  D14(%rip),%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
datatype: f64
name: read_data
arguments: data_tag: D14
datatype: f64

tool: D12: 1

tool: D14: 2

assistant: ```c
double qacc(double w, double v, double s, double a1, double a2, double a3, double alpha, double beta) {
  double r;
  r = s / (s - 1.0);
  return beta * (w - v) + (a1 + 1.0 - alpha) * log(w / v) + a3 * log((r + w) / (r + v)) - (a1 + a2 + a3 + 2.0) * log((1.0 + w) / (1.0 + v));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<qacc>:
  endbr64
  sub    $0x58,%rsp
  movapd %xmm0,%xmm8
  movapd %xmm2,%xmm0
  subsd  D3(%rip),%xmm0
  movsd  %xmm3,0x48(%rsp)
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm6,0x28(%rsp)
  divsd  %xmm0,%xmm2
  movapd %xmm8,%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm7,0x30(%rsp)
  movsd  %xmm8,0x8(%rsp)
  movsd  %xmm5,0x40(%rsp)
  divsd  %xmm1,%xmm0
  movsd  %xmm2,0x38(%rsp)
  call   <log@plt>
  movsd  0x38(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm5
  movsd  %xmm0,0x18(%rsp)
  addsd  %xmm2,%xmm5
  addsd  0x10(%rsp),%xmm2
  movapd %xmm5,%xmm0
  divsd  %xmm2,%xmm0
  call   <log@plt>
  movsd  D3(%rip),%xmm9
  addsd  0x10(%rsp),%xmm9
  movsd  %xmm0,0x38(%rsp)
  movsd  D3(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  divsd  %xmm9,%xmm0
  call   <log@plt>
  movsd  0x48(%rsp),%xmm3
  movsd  D3(%rip),%xmm1
  movsd  0x8(%rsp),%xmm2
  movsd  0x38(%rsp),%xmm4
  movapd %xmm0,%xmm6
  addsd  %xmm3,%xmm1
  subsd  0x10(%rsp),%xmm2
  mulsd  0x30(%rsp),%xmm2
  subsd  0x28(%rsp),%xmm1
  addsd  0x20(%rsp),%xmm3
  movapd %xmm4,%xmm0
  mulsd  0x18(%rsp),%xmm1
  movsd  0x40(%rsp),%xmm5
  mulsd  %xmm5,%xmm0
  addsd  %xmm5,%xmm3
  addsd  D41(%rip),%xmm3
  add    $0x58,%rsp
  addsd  %xmm2,%xmm1
  mulsd  %xmm6,%xmm3
  addsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: f64
name: read_data
arguments: data_tag: D41
type_infered: f64

tool: D3: 1

tool: D41: 2

assistant: ```c
double qacc(double w, double v, double s, double a1, double a2, double a3, double alpha, double beta) {
  double r;
  r = s / (s - 1.0);
  return beta * (w - v) + (a1 + 1.0 - alpha) * log(w / v) + a3 * log((r + w) / (r + v)) - (a1 + a2 + a3 + 2.0) * log((1.0 + w) / (1.0 + v));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qacc>:
  endbr64
  sub    $0x58,%rsp
  movapd %xmm0,%xmm8
  movapd %xmm2,%xmm0
  subsd  D27(%rip),%xmm0
  movsd  %xmm3,0x48(%rsp)
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm6,0x28(%rsp)
  divsd  %xmm0,%xmm2
  movapd %xmm8,%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm7,0x30(%rsp)
  movsd  %xmm8,0x8(%rsp)
  movsd  %xmm5,0x40(%rsp)
  divsd  %xmm1,%xmm0
  movsd  %xmm2,0x38(%rsp)
  call   <log@plt>
  movsd  0x38(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm5
  movsd  %xmm0,0x18(%rsp)
  addsd  %xmm2,%xmm5
  addsd  0x10(%rsp),%xmm2
  movapd %xmm5,%xmm0
  divsd  %xmm2,%xmm0
  call   <log@plt>
  movsd  D27(%rip),%xmm9
  addsd  0x10(%rsp),%xmm9
  movsd  %xmm0,0x38(%rsp)
  movsd  D27(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  divsd  %xmm9,%xmm0
  call   <log@plt>
  movsd  0x48(%rsp),%xmm3
  movsd  D27(%rip),%xmm1
  movsd  0x8(%rsp),%xmm2
  movsd  0x38(%rsp),%xmm4
  movapd %xmm0,%xmm6
  addsd  %xmm3,%xmm1
  subsd  0x10(%rsp),%xmm2
  mulsd  0x30(%rsp),%xmm2
  subsd  0x28(%rsp),%xmm1
  addsd  0x20(%rsp),%xmm3
  movapd %xmm4,%xmm0
  mulsd  0x18(%rsp),%xmm1
  movsd  0x40(%rsp),%xmm5
  mulsd  %xmm5,%xmm0
  addsd  %xmm5,%xmm3
  addsd  D24(%rip),%xmm3
  add    $0x58,%rsp
  addsd  %xmm2,%xmm1
  mulsd  %xmm6,%xmm3
  addsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D27
data_type: f64
name: read_data
arguments: data_tag: D24
data_type: f64

tool: D27: 1

tool: D24: 2

assistant: ```c
double qacc(double w, double v, double s, double a1, double a2, double a3, double alpha, double beta) {
  double r;
  r = s / (s - 1.0);
  return beta * (w - v) + (a1 + 1.0 - alpha) * log(w / v) + a3 * log((r + w) / (r + v)) - (a1 + a2 + a3 + 2.0) * log((1.0 + w) / (1.0 + v));
}
```
user: What is the c source code of the assembly code below:

```asm
<hextoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isascii@plt>
  test   %eax,%eax
  jne    L59
  mov    $0xffffffff,%eax
  jmp    L28
L59:
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L13
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L28
L13:
  cmpl   $0x60,-0x4(%rbp)
  jle    L16
  cmpl   $0x66,-0x4(%rbp)
  jg     L16
  mov    -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L28
L16:
  cmpl   $0x40,-0x4(%rbp)
  jle    L38
  cmpl   $0x46,-0x4(%rbp)
  jg     L38
  mov    -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L28
L38:
  mov    $0xffffffff,%eax
L28:
  leave
  ret
```

assistant: ```c
int hextoint(int c) {
  if (!isascii((unsigned char)c))
    return -1;
  if (isdigit((unsigned char)c))
    return c - '0';
  if ((c >= 'a') && (c <= 'f'))
    return c + 10 - 'a';
  if ((c >= 'A') && (c <= 'F'))
    return c + 10 - 'A';
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hextoint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movzbl %dil,%ebp
  mov    %ebp,%edi
  call   <isascii@plt>
  test   %eax,%eax
  je     L36
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L59
  lea    -0x61(%rbx),%eax
  cmp    $0x5,%eax
  jbe    L52
  lea    -0x41(%rbx),%eax
  sub    $0x37,%ebx
  cmp    $0x6,%eax
  mov    $0xffffffff,%eax
  cmovb  %ebx,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L59:
  lea    -0x30(%rbx),%eax
  jmp    L10
L52:
  lea    -0x57(%rbx),%eax
  jmp    L10
L36:
  mov    $0xffffffff,%eax
  jmp    L10
```

assistant: ```c
int hextoint(int c) {
  if (!isascii((unsigned char)c))
    return -1;
  if (isdigit((unsigned char)c))
    return c - '0';
  if ((c >= 'a') && (c <= 'f'))
    return c + 10 - 'a';
  if ((c >= 'A') && (c <= 'F'))
    return c + 10 - 'A';
  return -1;
}
```