ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<do_exit>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jg     L13
  je     L16
  xor    %edi,%edi
  pop    %rbx
  jmp    1090 <m5_exit@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <usage@plt>
L16:
  mov    (%rbx),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <m5_exit@plt>
```

assistant: ```c
void do_exit(int argc, char *argv[]) {
  if (argc > 1)
    usage();
  m5_exit((argc > 0) ? strtoul(argv[0], NULL, 0) : 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<a_to_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L15:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L4
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L15
L4:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int a_to_i(char s[]) {
  int n = 0;
  for (; *s >= '0' && *s <= '9'; ++s)
    n = 10 * n + (*s - '0');
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<a_to_i>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L0
  mov    $0x0,%edx
L2:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L2
L11:
  mov    %edx,%eax
  ret
L0:
  mov    $0x0,%edx
  jmp    L11
```

assistant: ```c
int a_to_i(char s[]) {
  int n = 0;
  for (; *s >= '0' && *s <= '9'; ++s)
    n = 10 * n + (*s - '0');
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<a_to_i>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L5
  nopw   0x0(%rax,%rax,1)
L10:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L10
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int a_to_i(char s[]) {
  int n = 0;
  for (; *s >= '0' && *s <= '9'; ++s)
    n = 10 * n + (*s - '0');
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<a_to_i>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L15
  nopw   0x0(%rax,%rax,1)
L10:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L10
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int a_to_i(char s[]) {
  int n = 0;
  for (; *s >= '0' && *s <= '9'; ++s)
    n = 10 * n + (*s - '0');
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vfprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x8000(%rsp),%r11
L48:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L48
  sub    $0x40,%rsp
  mov    %rdi,-0x8028(%rbp)
  mov    %rsi,-0x8030(%rbp)
  mov    %edx,-0x8034(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x8034(%rbp),%ecx
  mov    -0x8030(%rbp),%rdx
  lea    -0x8010(%rbp),%rax
  mov    $0x8000,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0x8014(%rbp)
  cmpl   $0x0,-0x8014(%rbp)
  jns    L9
  mov    -0x8014(%rbp),%eax
  jmp    L49
L9:
  cmpl   $0x7fff,-0x8014(%rbp)
  jle    L28
  movl   $0x7fff,-0x8014(%rbp)
L28:
  mov    -0x8028(%rbp),%rdx
  mov    -0x8014(%rbp),%ecx
  lea    -0x8010(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <_fwrite@plt>
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int vfprintf(FILE *file, const char *format, va_list ap) {
  int rv;
  char buffer[32768];
  rv = vsnprintf(buffer, 32768, format, ap);
  if (rv < 0)
    return rv;
  if (rv > 32768 - 1)
    rv = 32768 - 1;
  return _fwrite(buffer, rv, file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vfprintf>:
  endbr64
  push   %rbx
  lea    -0x8000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  mov    $0x8000,%esi
  call   <vsnprintf@plt>
  test   %eax,%eax
  js     L14
  mov    $0x7fff,%edx
  cmp    %edx,%eax
  cmovle %eax,%edx
  mov    %edx,%esi
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  call   <_fwrite@plt>
L14:
  mov    0x8008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x8010,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vfprintf(FILE *file, const char *format, va_list ap) {
  int rv;
  char buffer[32768];
  rv = vsnprintf(buffer, 32768, format, ap);
  if (rv < 0)
    return rv;
  if (rv > 32768 - 1)
    rv = 32768 - 1;
  return _fwrite(buffer, rv, file);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vfprintf>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x8000(%rsp),%r11
L20:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L20
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rdi,%r12
  mov    %edx,%ecx
  mov    %rbp,%rdi
  mov    %rsi,%rdx
  mov    $0x8000,%esi
  call   <vsnprintf@plt>
  test   %eax,%eax
  js     L24
  mov    $0x7fff,%edx
  mov    %rbp,%rdi
  cmp    %edx,%eax
  mov    %edx,%esi
  mov    %r12,%rdx
  cmovle %eax,%esi
  call   <_fwrite@plt>
L24:
  mov    0x8008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x8018,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vfprintf(FILE *file, const char *format, va_list ap) {
  int rv;
  char buffer[32768];
  rv = vsnprintf(buffer, 32768, format, ap);
  if (rv < 0)
    return rv;
  if (rv > 32768 - 1)
    rv = 32768 - 1;
  return _fwrite(buffer, rv, file);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vfprintf>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x8000(%rsp),%r11
L27:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L27
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rdi,%r12
  mov    %edx,%ecx
  mov    %rbp,%rdi
  mov    %rsi,%rdx
  mov    $0x8000,%esi
  call   <vsnprintf@plt>
  test   %eax,%eax
  js     L22
  mov    $0x7fff,%edx
  mov    %rbp,%rdi
  cmp    %edx,%eax
  mov    %edx,%esi
  mov    %r12,%rdx
  cmovle %eax,%esi
  call   <_fwrite@plt>
L22:
  mov    0x8008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x8018,%rsp
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vfprintf(FILE *file, const char *format, va_list ap) {
  int rv;
  char buffer[32768];
  rv = vsnprintf(buffer, 32768, format, ap);
  if (rv < 0)
    return rv;
  if (rv > 32768 - 1)
    rv = 32768 - 1;
  return _fwrite(buffer, rv, file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<to2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L39
L13:
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L39:
  cmpl   $0x0,-0xc(%rbp)
  jne    L13
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L38
L3:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  subl   $0x1,-0x8(%rbp)
L38:
  cmpl   $0x0,-0x8(%rbp)
  jns    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void to2(int a, char s[]) {
  int shang, yu;
  int i = 0;
  shang = a;
  while (shang != 0) {
    yu = shang % 2;
    s[i] = yu + '0';
    shang = shang / 2;
    i++;
  }
  s[i] = '\0';
  for (i = (strlen(s) - 1); i >= 0; i--)
    printf("%c", s[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<to2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  test   %edi,%edi
  je     L35
  mov    $0x1,%edx
L48:
  mov    %edi,%ecx
  shr    $0x1f,%ecx
  lea    (%rdi,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rbx,%rdx,1)
  mov    %ecx,%eax
  add    %edi,%eax
  sar    %eax
  mov    %eax,%edi
  mov    %edx,%ecx
  add    $0x1,%rdx
  test   %eax,%eax
  jne    L48
L11:
  movslq %ecx,%rcx
  movb   $0x0,(%rbx,%rcx,1)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  sub    $0x1,%ebp
  js     L7
  movslq %ebp,%rbp
  add    %rbx,%rbp
  movslq %eax,%rdx
  lea    -0x2(%rbx,%rdx,1),%rbx
  lea    -0x1(%rax),%eax
  sub    %rax,%rbx
L36:
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
  sub    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L36
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    %edi,%ecx
  jmp    L11
```

assistant: ```c
void to2(int a, char s[]) {
  int shang, yu;
  int i = 0;
  shang = a;
  while (shang != 0) {
    yu = shang % 2;
    s[i] = yu + '0';
    shang = shang / 2;
    i++;
  }
  s[i] = '\0';
  for (i = (strlen(s) - 1); i >= 0; i--)
    printf("%c", s[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<to2>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L30
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %edi,%ecx
  shr    $0x1f,%ecx
  lea    (%rdi,%rcx,1),%eax
  add    %ecx,%edi
  and    $0x1,%eax
  sub    %ecx,%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rbp,%rdx,1)
  movslq %edx,%rax
  add    $0x1,%rdx
  sar    %edi
  jne    L34
  add    %rbp,%rax
L37:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L41
  movslq %edx,%rbx
  cltq
  mov    %edx,%edx
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
  nopl   0x0(%rax,%rax,1)
L13:
  movsbl (%rbx),%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L13
L41:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L30:
  mov    %rsi,%rax
  jmp    L37
```

assistant: ```c
void to2(int a, char s[]) {
  int shang, yu;
  int i = 0;
  shang = a;
  while (shang != 0) {
    yu = shang % 2;
    s[i] = yu + '0';
    shang = shang / 2;
    i++;
  }
  s[i] = '\0';
  for (i = (strlen(s) - 1); i >= 0; i--)
    printf("%c", s[i]);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<to2>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L21
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %edi,%ecx
  shr    $0x1f,%ecx
  lea    (%rdi,%rcx,1),%eax
  add    %ecx,%edi
  and    $0x1,%eax
  sub    %ecx,%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rbp,%rdx,1)
  movslq %edx,%rax
  add    $0x1,%rdx
  sar    %edi
  jne    L8
  add    %rbp,%rax
L0:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L27
  movslq %edx,%rbx
  cltq
  mov    %edx,%edx
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
  nopl   0x0(%rax,%rax,1)
L31:
  movsbl (%rbx),%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L31
L27:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L21:
  mov    %rsi,%rax
  jmp    L0
```

assistant: ```c
void to2(int a, char s[]) {
  int shang, yu;
  int i = 0;
  shang = a;
  while (shang != 0) {
    yu = shang % 2;
    s[i] = yu + '0';
    shang = shang / 2;
    i++;
  }
  s[i] = '\0';
  for (i = (strlen(s) - 1); i >= 0; i--)
    printf("%c", s[i]);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L18
L20:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L2
  mov    -0x8(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L2
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x3e5,-0x8(%rbp)
  jle    L20
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D8: %d %d


tool: D15: Total: %d


assistant: ```c
int main() {
  int i, count = 0;
  for (i = 1; i < 998; ++i) {
    if (prime(i) && prime(i + 2)) {
      printf("%d %d\n", i, i + 2);
      ++count;
    }
  }
  printf("Total: %d\n", count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  lea    D13(%rip),%r13
  jmp    L12
L6:
  add    $0x1,%ebx
  cmp    $0x3e6,%ebx
  je     L48
L12:
  mov    %ebx,%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L6
  lea    0x2(%rbx),%ebp
  mov    %ebp,%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L6
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r12d
  jmp    L6
L48:
  mov    %r12d,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
data_type: string
name: unpack_data
arguments: data_label: D14
data_type: string

tool: D13: %d %d


tool: D14: Total: %d


assistant: ```c
int main() {
  int i, count = 0;
  for (i = 1; i < 998; ++i) {
    if (prime(i) && prime(i + 2)) {
      printf("%d %d\n", i, i + 2);
      ++count;
    }
  }
  printf("Total: %d\n", count);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L1
  xchg   %ax,%ax
L12:
  add    $0x1,%ebx
  cmp    $0x3e6,%ebx
  je     L19
L1:
  mov    %ebx,%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L12
  lea    0x2(%rbx),%r12d
  mov    %r12d,%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L12
  mov    %ebx,%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x1,%ebp
  cmp    $0x3e6,%ebx
  jne    L1
L19:
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D16
type: string

tool: D18: %d %d


tool: D16: Total: %d


assistant: ```c
int main() {
  int i, count = 0;
  for (i = 1; i < 998; ++i) {
    if (prime(i) && prime(i + 2)) {
      printf("%d %d\n", i, i + 2);
      ++count;
    }
  }
  printf("Total: %d\n", count);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L11
  xchg   %ax,%ax
L47:
  add    $0x1,%ebx
  cmp    $0x3e6,%ebx
  je     L1
L11:
  mov    %ebx,%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L47
  lea    0x2(%rbx),%r12d
  mov    %r12d,%edi
  call   <prime@plt>
  test   %rax,%rax
  je     L47
  mov    %ebx,%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x1,%ebp
  cmp    $0x3e6,%ebx
  jne    L11
L1:
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string

tool: D7: %d %d


tool: D13: Total: %d


assistant: ```c
int main() {
  int i, count = 0;
  for (i = 1; i < 998; ++i) {
    if (prime(i) && prime(i + 2)) {
      printf("%d %d\n", i, i + 2);
      ++count;
    }
  }
  printf("Total: %d\n", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utf8_char_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0x7f,-0x14(%rbp)
  jg     L47
  movl   $0x1,-0x4(%rbp)
  jmp    L74
L47:
  cmpl   $0x7ff,-0x14(%rbp)
  jg     L99
  movl   $0x2,-0x4(%rbp)
  jmp    L74
L99:
  cmpl   $0xffff,-0x14(%rbp)
  jg     L83
  movl   $0x3,-0x4(%rbp)
  jmp    L74
L83:
  cmpl   $0x1fffff,-0x14(%rbp)
  jg     L50
  movl   $0x4,-0x4(%rbp)
  jmp    L74
L50:
  cmpl   $0x3ffffff,-0x14(%rbp)
  jg     L70
  movl   $0x5,-0x4(%rbp)
  jmp    L74
L70:
  movl   $0x6,-0x4(%rbp)
L74:
  cmpl   $0x6,-0x4(%rbp)
  ja     L10
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D2(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  sarl   $0x6,-0x14(%rbp)
  orl    $0x4000000,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  sarl   $0x6,-0x14(%rbp)
  orl    $0x200000,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  sarl   $0x6,-0x14(%rbp)
  orl    $0x10000,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  sarl   $0x6,-0x14(%rbp)
  orl    $0x800,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  sarl   $0x6,-0x14(%rbp)
  orl    $0xc0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
L10:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int utf8_char_decode(int unicode, unsigned char *utf) {
  int count = -1;
  if (unicode < 0x80)
    count = 1;
  else if (unicode < 0x800)
    count = 2;
  else if (unicode < 0x10000)
    count = 3;
  else if (unicode < 0x200000)
    count = 4;
  else if (unicode < 0x4000000)
    count = 5;
  else if (unicode <= 0x7fffffff)
    count = 6;
  else
    return count;
  switch (count) {
  case 6:
    utf[5] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0x4000000;
  case 5:
    utf[4] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0x200000;
  case 4:
    utf[3] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0x10000;
  case 3:
    utf[2] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0x800;
  case 2:
    utf[1] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0xc0;
  case 1:
    utf[0] = (char)unicode;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<utf8_char_decode>:
  endbr64
  mov    %rsi,%rax
  mov    $0x1,%edx
  cmp    $0x7f,%edi
  jle    L38
  mov    $0x2,%edx
  cmp    $0x7ff,%edi
  jle    L5
  mov    $0x3,%edx
  cmp    $0xffff,%edi
  jle    L39
  mov    $0x4,%edx
  cmp    $0x1fffff,%edi
  jle    L2
  mov    $0x5,%edx
  cmp    $0x3ffffff,%edi
  jle    L21
  mov    %edi,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,0x5(%rsi)
  sar    $0x6,%edi
  or     $0x4000000,%edi
  mov    $0x6,%edx
L21:
  mov    %edi,%ecx
  and    $0x3f,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x4(%rax)
  sar    $0x6,%edi
  or     $0x200000,%edi
L2:
  mov    %edi,%ecx
  and    $0x3f,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x3(%rax)
  sar    $0x6,%edi
  or     $0x10000,%edi
L39:
  mov    %edi,%ecx
  and    $0x3f,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x2(%rax)
  sar    $0x6,%edi
  or     $0x800,%edi
L5:
  mov    %edi,%ecx
  and    $0x3f,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x1(%rax)
  sar    $0x6,%edi
  or     $0xc0,%dil
L38:
  mov    %dil,(%rax)
  mov    %edx,%eax
  ret
```

assistant: ```c
int utf8_char_decode(int unicode, unsigned char *utf) {
  int count = -1;
  if (unicode < 0x80)
    count = 1;
  else if (unicode < 0x800)
    count = 2;
  else if (unicode < 0x10000)
    count = 3;
  else if (unicode < 0x200000)
    count = 4;
  else if (unicode < 0x4000000)
    count = 5;
  else if (unicode <= 0x7fffffff)
    count = 6;
  else
    return count;
  switch (count) {
  case 6:
    utf[5] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0x4000000;
  case 5:
    utf[4] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0x200000;
  case 4:
    utf[3] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0x10000;
  case 3:
    utf[2] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0x800;
  case 2:
    utf[1] = 0x80 | (unicode & 0x3f);
    unicode = unicode >> 6;
    unicode |= 0xc0;
  case 1:
    utf[0] = (char)unicode;
  }
  return count;
}
```