user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    D25(%rip),%rax
  movl   $0x41200000,0x28(%rsp)
  lea    0x20(%rsp),%rbp
  mov    %rbp,%r15
  mov    %r13,%rbp
  mov    %rax,0x20(%rsp)
  lea    0x50(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x80(%rsp),%rax
  mov    %rax,0x18(%rsp)
L80:
  mov    %rbx,%rax
  mov    0x18(%rsp),%r13
  lea    0x1(%rbp),%r14d
  xor    %r12d,%r12d
  neg    %rax
  mov    %rax,0x8(%rsp)
  mov    %r15,%rax
  sub    %rbx,%r13
  mov    %r14d,%r15d
  mov    %rax,%r14
L77:
  mov    %r12d,0x4(%rsp)
  add    $0x1,%r12d
  mov    %r15d,%edx
  lea    D65(%rip),%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  lea    D124(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rcx
  lea    0x0(%r13,%rbx,1),%rax
  movss  (%r14,%rbp,4),%xmm1
  movss  (%rax,%rcx,1),%xmm0
  comiss %xmm0,%xmm1
  jb     L69
  mov    0x10(%rsp),%rcx
  mov    0x4(%rsp),%eax
  movss  %xmm0,(%r14,%rbp,4)
  mov    %eax,(%rcx,%rbp,4)
L69:
  add    $0x4,%r13
  cmp    $0x3,%r12d
  jne    L77
  mov    $0xa,%edi
  mov    %r14,%r15
  sub    $0xc,%rbx
  call   <putchar@plt>
  cmp    $0x1,%rbp
  je     L42
  mov    $0x1,%ebp
  jmp    L80
  nopl   0x0(%rax)
L42:
  lea    D32(%rip),%rdi
  lea    D59(%rip),%rbx
  mov    %rbp,%r13
  mov    %r14,%rbp
  call   <puts@plt>
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  xor    %r14d,%r14d
  call   <printf@plt>
  mov    %rbx,%rdi
  lea    D97(%rip),%r12
  call   <puts@plt>
  movl   $0x0,0x8(%rsp)
  lea    D93(%rip),%rdx
  movl   $0x0,0x4(%rsp)
L70:
  mov    %rdx,%rdi
  mov    %r13d,%esi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd -0x4(%rbp,%r13,4),%xmm0
  call   <printf@plt>
  mov    %r12,%rdi
  mov    0x10(%rsp),%rax
  mov    -0x4(%rax,%r13,4),%r15d
  xor    %eax,%eax
  lea    0x1(%r15),%esi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  test   %r15d,%r15d
  lea    D93(%rip),%rdx
  jne    L20
  add    $0x1,%r14d
L64:
  cmp    $0x2,%r13
  jne    L81
  mov    %r14d,%esi
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D95(%rip),%rdi
  call   <puts@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  add    $0x108,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L20:
  cmp    $0x1,%r15d
  je     L101
  cmp    $0x2,%r15d
  jne    L64
  addl   $0x1,0x8(%rsp)
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L81:
  mov    $0x2,%r13d
  jmp    L70
L101:
  addl   $0x1,0x4(%rsp)
  jmp    L64
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D65
type_guessed: string
name: disassemble_data
arguments: tag: D124
type_guessed: string
name: disassemble_data
arguments: tag: D32
type_guessed: string
name: disassemble_data
arguments: tag: D59
type_guessed: string
name: disassemble_data
arguments: tag: D56
type_guessed: string
name: disassemble_data
arguments: tag: D97
type_guessed: string
name: disassemble_data
arguments: tag: D93
type_guessed: string
name: disassemble_data
arguments: tag: D60
type_guessed: string
name: disassemble_data
arguments: tag: D45
type_guessed: string
name: disassemble_data
arguments: tag: D47
type_guessed: string
name: disassemble_data
arguments: tag: D95
type_guessed: string

tool: {"D25": [0x00,0x00,0x20,0x41,0x00,0x00,0x20,0x41]}

tool: D65: Please, insert the note %d for the student %d: 

tool: D124: %f

tool: D32: 
------------------------------

tool: D59: 
------------------------------


tool: D56: -- Calculating, please wait.

tool: D97:  | On test: %d

tool: D93: The student %d, have small note: %2.f

tool: D60: 
The total of student, have small note in P1 is: %d

tool: D45: 
The total of student, have small note in P2 is: %d

tool: D47: 
The total of student, have small note in P3 is: %d

tool: D95: 
Finished!!!


assistant: ```c
int main() {
  float studentAndNote[10][3];
  float studentSmallNote[10][1] = {10, 10, 10, 10, 10, 10, 10, 10, 10, 10};
  int studentSmallNoteTest[10][1];
  int totalSmallNoteP1;
  int totalSmallNoteP2;
  int totalSmallNoteP3;
  int i, j;
  totalSmallNoteP1 = 0;
  totalSmallNoteP2 = 0;
  totalSmallNoteP3 = 0;
  for (i = 0; i < 2; i++) {
    for (j = 0; j < 3; j++) {
      printf("Please, insert the note %d for the student %d: ", j + 1, i + 1);
      scanf("%f", &studentAndNote[i][j]);
      if (studentAndNote[i][j] <= studentSmallNote[i][0]) {
        studentSmallNote[i][0] = studentAndNote[i][j];
        studentSmallNoteTest[i][0] = j;
      }
    }
    printf("\n");
  }
  printf("\n------------------------------\n");
  printf("-- Calculating, please wait.");
  printf("\n------------------------------\n\n");
  for (i = 0; i < 2; i++) {
    printf("The student %d, have small note: %2.f", i + 1, studentSmallNote[i][0]);
    printf(" | On test: %d", studentSmallNoteTest[i][0] + 1);
    printf("\n------------------------------\n\n");
    if (studentSmallNoteTest[i][0] == 0) {
      totalSmallNoteP1++;
    } else if (studentSmallNoteTest[i][0] == 1) {
      totalSmallNoteP2++;
    } else if (studentSmallNoteTest[i][0] == 2) {
      totalSmallNoteP3++;
    }
  }
  printf("\nThe total of student, have small note in P1 is: %d", totalSmallNoteP1);
  printf("\nThe total of student, have small note in P2 is: %d", totalSmallNoteP2);
  printf("\nThe total of student, have small note in P3 is: %d", totalSmallNoteP3);
  printf("\nFinished!!!\n\n");
}
```