ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<merge_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L38
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  sar    %r13d
  push   %rbp
  lea    0x0(,%r13,4),%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %ebx,%ebp
  sub    %r13d,%ebp
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    0x0(,%rbp,4),%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    %rax,%r15
  mov    %r13d,%eax
  sub    %r12,%rcx
  lea    (%r12,%rax,4),%rsi
  mov    %r12,%rax
  nopw   0x0(%rax,%rax,1)
L32:
  mov    (%rcx,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L32
  cmp    %r13d,%ebx
  jle    L23
  sub    $0x1,%ebx
  movslq %r13d,%rdx
  mov    %r15,%rax
  sub    %r13d,%ebx
  lea    (%r14,%rdx,4),%rcx
  lea    0x4(%r15,%rbx,4),%rsi
  sub    %r15,%rcx
  nopl   0x0(%rax)
L19:
  mov    (%rcx,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L19
L23:
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <merge_sort>
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <merge_sort>
  mov    %ebp,%r8d
  mov    %r15,%rcx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
  cs nopw 0x0(%rax,%rax,1)
L38:
  ret
```

assistant: ```c
void merge_sort(int *data, int n) {
  if (n < 2)
    return;
  int mid, i, *L, *R;
  mid = n / 2;
  L = (int *)malloc(sizeof(int) * mid);
  R = (int *)malloc(sizeof(int) * (n - mid));
  for (i = 0; i < mid; i++)
    L[i] = data[i];
  for (i = mid; i < n; i++)
    R[i - mid] = data[i];
  merge_sort(L, mid);
  merge_sort(R, n - mid);
  merge(data, L, mid, R, n - mid);
  free(L);
  free(R);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GPUshowScreenPic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <DestroyPic@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <CreatePic@plt>
  jmp    L0
L4:
  nop
L0:
  leave
  ret
```

assistant: ```c
void GPUshowScreenPic(unsigned char *pMem) {
  DestroyPic();
  if (pMem == 0)
    return;
  CreatePic(pMem);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GPUshowScreenPic>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <DestroyPic@plt>
  test   %rbx,%rbx
  je     L5
  mov    %rbx,%rdi
  call   <CreatePic@plt>
L5:
  pop    %rbx
  ret
```

assistant: ```c
void GPUshowScreenPic(unsigned char *pMem) {
  DestroyPic();
  if (pMem == 0)
    return;
  CreatePic(pMem);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GPUshowScreenPic>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <DestroyPic@plt>
  test   %rbp,%rbp
  je     L3
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <CreatePic@plt>
  nopl   (%rax)
L3:
  pop    %rbp
  ret
```

assistant: ```c
void GPUshowScreenPic(unsigned char *pMem) {
  DestroyPic();
  if (pMem == 0)
    return;
  CreatePic(pMem);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GPUshowScreenPic>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <DestroyPic@plt>
  test   %rbp,%rbp
  je     L6
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <CreatePic@plt>
  nopl   (%rax)
L6:
  pop    %rbp
  ret
```

assistant: ```c
void GPUshowScreenPic(unsigned char *pMem) {
  DestroyPic();
  if (pMem == 0)
    return;
  CreatePic(pMem);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<worker_thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <work@plt>
  leave
  ret
```

assistant: ```c
void *worker_thread(void *ptr) {
  struct thread_info *tip = (struct thread_info *)ptr;
  return work(tip);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<worker_thread>:
  endbr64
  sub    $0x8,%rsp
  call   <work@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *worker_thread(void *ptr) {
  struct thread_info *tip = (struct thread_info *)ptr;
  return work(tip);
}
```
user: Translate the below assembly code into C programming language:

```asm
<worker_thread>:
  endbr64
  jmp    1050 <work@plt>
```

assistant: ```c
void *worker_thread(void *ptr) {
  struct thread_info *tip = (struct thread_info *)ptr;
  return work(tip);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<worker_thread>:
  endbr64
  jmp    1050 <work@plt>
```

assistant: ```c
void *worker_thread(void *ptr) {
  struct thread_info *tip = (struct thread_info *)ptr;
  return work(tip);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<all_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <test_heap_property@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  jmp    L12
L14:
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
char *all_tests() {
  do {
    char *run_test_msg = test_heap_property();
    if (run_test_msg)
      return run_test_msg;
  } while (0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<all_tests>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_heap_property@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *all_tests() {
  do {
    char *run_test_msg = test_heap_property();
    if (run_test_msg)
      return run_test_msg;
  } while (0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<all_tests>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <test_heap_property@plt>
```

assistant: ```c
char *all_tests() {
  do {
    char *run_test_msg = test_heap_property();
    if (run_test_msg)
      return run_test_msg;
  } while (0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<all_tests>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <test_heap_property@plt>
```

assistant: ```c
char *all_tests() {
  do {
    char *run_test_msg = test_heap_property();
    if (run_test_msg)
      return run_test_msg;
  } while (0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<file_store>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  jmp    L0
L19:
  nop
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D2: w+

tool: D7: %s

assistant: ```c
void file_store(char *file, char *content) {
  FILE *f;
  if (!(f = fopen(file, "w+"))) {
    return;
  }
  fprintf(f, "%s", content);
  fclose(f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<file_store>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    D19(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    %rbp,%rdx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type_infered: string
name: unpack_data
arguments: label: D8
type_infered: string

tool: D19: w+

tool: D8: %s

assistant: ```c
void file_store(char *file, char *content) {
  FILE *f;
  if (!(f = fopen(file, "w+"))) {
    return;
  }
  fprintf(f, "%s", content);
  fclose(f);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_store>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D18(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L1
  mov    %r12,%rdx
  mov    %rax,%rdi
  lea    D13(%rip),%rsi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string

tool: D18: w+

tool: D13: %s

assistant: ```c
void file_store(char *file, char *content) {
  FILE *f;
  if (!(f = fopen(file, "w+"))) {
    return;
  }
  fprintf(f, "%s", content);
  fclose(f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<file_store>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D14(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L3
  mov    %r12,%rdx
  mov    %rax,%rdi
  lea    D1(%rip),%rsi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fclose@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D14: w+

tool: D1: %s

assistant: ```c
void file_store(char *file, char *content) {
  FILE *f;
  if (!(f = fopen(file, "w+"))) {
    return;
  }
  fprintf(f, "%s", content);
  fclose(f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fpsconv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L55
L46:
  mov    -0x1c(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L55:
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L46
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L36
L17:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L32
L15:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x30(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x30(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L15
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x2,-0x1c(%rbp)
L36:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fpsconv(double *x_in, int lx, double *h0, double *h1, int lhm1, double *x_outl, double *x_outh) {
  int i, j, ind;
  double x0, x1;
  for (i = lx; i < lx + lhm1; i++)
    x_in[i] = *(x_in + (i - lx));
  ind = 0;
  for (i = 0; i < (lx); i += 2) {
    x0 = 0;
    x1 = 0;
    for (j = 0; j <= lhm1; j++) {
      x0 = x0 + x_in[i + j] * h0[lhm1 - j];
      x1 = x1 + x_in[i + j] * h1[lhm1 - j];
    }
    x_outl[ind] = x0;
    x_outh[ind++] = x1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<fpsconv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rdx,%rdi
  mov    %rcx,%r10
  mov    0x28(%rsp),%rbx
  lea    (%rsi,%r8,1),%eax
  cmp    %eax,%esi
  jge    L29
  mov    %r11,%rax
  lea    -0x1(%r8),%edx
  lea    0x8(%r11,%rdx,8),%rcx
  movslq %esi,%rdx
L49:
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L49
L29:
  test   %esi,%esi
  jle    L67
  sub    $0x1,%esi
  shr    %esi
  lea    0x1(%rsi),%ebp
  movslq %r8d,%rsi
  lea    0x0(,%rsi,8),%r12
  mov    %r8d,%eax
  sub    %rax,%rsi
  shl    $0x3,%rsi
  mov    $0x0,%r13d
  jmp    L40
L14:
  mov    %r12,%rax
  mov    %r11,%rdx
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm2
L11:
  movsd  (%rdx),%xmm0
  movapd %xmm0,%xmm3
  mulsd  (%rdi,%rax,1),%xmm3
  addsd  %xmm3,%xmm2
  mulsd  (%r10,%rax,1),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rdx
  mov    %rax,%rcx
  sub    $0x8,%rax
  cmp    %rsi,%rcx
  jne    L11
L3:
  movsd  %xmm2,(%r9,%r13,8)
  movsd  %xmm1,(%rbx,%r13,8)
  add    $0x1,%r13
  add    $0x10,%r11
  cmp    %rbp,%r13
  je     L67
L40:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm2
  test   %r8d,%r8d
  jns    L14
  jmp    L3
L67:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void fpsconv(double *x_in, int lx, double *h0, double *h1, int lhm1, double *x_outl, double *x_outh) {
  int i, j, ind;
  double x0, x1;
  for (i = lx; i < lx + lhm1; i++)
    x_in[i] = *(x_in + (i - lx));
  ind = 0;
  for (i = 0; i < (lx); i += 2) {
    x0 = 0;
    x1 = 0;
    for (j = 0; j <= lhm1; j++) {
      x0 = x0 + x_in[i + j] * h0[lhm1 - j];
      x1 = x1 + x_in[i + j] * h1[lhm1 - j];
    }
    x_outl[ind] = x0;
    x_outh[ind++] = x1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fpsconv>:
  endbr64
  lea    (%rsi,%r8,1),%eax
  push   %r13
  mov    %rdi,%r11
  mov    %rcx,%r10
  push   %r12
  mov    %rdx,%rdi
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  mov    0x28(%rsp),%rbp
  cmp    %eax,%esi
  jge    L43
  lea    -0x1(%r8),%edx
  mov    %r11,%rax
  lea    0x8(%r11,%rdx,8),%rcx
  movslq %esi,%rdx
  nopw   0x0(%rax,%rax,1)
L15:
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L15
L43:
  test   %esi,%esi
  jle    L42
  sub    $0x1,%esi
  mov    %ebx,%eax
  pxor   %xmm4,%xmm4
  mov    %r11,%r8
  shr    %esi
  xor    %r11d,%r11d
  lea    0x1(%rsi),%r12d
  movslq %ebx,%rsi
  lea    0x0(,%rsi,8),%r13
  sub    %rax,%rsi
  shl    $0x3,%rsi
  nopl   0x0(%rax)
L35:
  movapd %xmm4,%xmm2
  movapd %xmm4,%xmm1
  test   %ebx,%ebx
  js     L7
  mov    %r13,%rax
  movapd %xmm4,%xmm2
  movapd %xmm4,%xmm1
  mov    %r8,%rdx
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  (%rdx),%xmm0
  movsd  (%rdi,%rax,1),%xmm3
  mov    %rax,%rcx
  add    $0x8,%rdx
  mulsd  %xmm0,%xmm3
  mulsd  (%r10,%rax,1),%xmm0
  sub    $0x8,%rax
  addsd  %xmm3,%xmm1
  addsd  %xmm0,%xmm2
  cmp    %rcx,%rsi
  jne    L2
L7:
  movsd  %xmm1,(%r9,%r11,8)
  add    $0x10,%r8
  movsd  %xmm2,0x0(%rbp,%r11,8)
  add    $0x1,%r11
  cmp    %r11,%r12
  jne    L35
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void fpsconv(double *x_in, int lx, double *h0, double *h1, int lhm1, double *x_outl, double *x_outh) {
  int i, j, ind;
  double x0, x1;
  for (i = lx; i < lx + lhm1; i++)
    x_in[i] = *(x_in + (i - lx));
  ind = 0;
  for (i = 0; i < (lx); i += 2) {
    x0 = 0;
    x1 = 0;
    for (j = 0; j <= lhm1; j++) {
      x0 = x0 + x_in[i + j] * h0[lhm1 - j];
      x1 = x1 + x_in[i + j] * h1[lhm1 - j];
    }
    x_outl[ind] = x0;
    x_outh[ind++] = x1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L29
  mov    $0x1,%eax
  jmp    L14
L29:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int check_float(char a[]) {
  int i = 0;
  while (a[i] != '\0') {
    if (a[i] == '.')
      return 1;
    i++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_float>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  add    $0x1,%rdi
L7:
  cmp    $0x2e,%al
  je     L3
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L7
  mov    $0x0,%eax
  ret
L16:
  mov    $0x0,%eax
  ret
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_float(char a[]) {
  int i = 0;
  while (a[i] != '\0') {
    if (a[i] == '.')
      return 1;
    i++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_float>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  add    $0x1,%rdi
  jmp    L26
  nopl   0x0(%rax)
L25:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L16
L26:
  cmp    $0x2e,%al
  jne    L25
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_float(char a[]) {
  int i = 0;
  while (a[i] != '\0') {
    if (a[i] == '.')
      return 1;
    i++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_float>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  add    $0x1,%rdi
  jmp    L22
  nopl   0x0(%rax)
L36:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L16
L22:
  cmp    $0x2e,%al
  jne    L36
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_float(char a[]) {
  int i = 0;
  while (a[i] != '\0') {
    if (a[i] == '.')
      return 1;
    i++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<blFgetsany>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x50,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L119
  mov    $0x0,%eax
  jmp    L110
L119:
  mov    -0x28(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L73
  mov    D31(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L110
L73:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L122
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L122
  addl   $0x50,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L122
  mov    D31(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L110
L122:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L24
  cmpl   $0xa,-0xc(%rbp)
  jne    L73
L24:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L114
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L114
  mov    D31(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L110
L114:
  mov    -0x8(%rbp),%rax
L110:
  leave
  ret
```

assistant: ```c
char *blFgetsany(FILE *fp) {
  int bufflen = 80, buffpos = 0, ch;
  char *buffer = NULL;
  if ((ch = fgetc(fp)) == EOF)
    return (NULL);
  ungetc(ch, fp);
  if ((buffer = (char *)malloc(bufflen * sizeof(char))) == NULL) {
    errno = ENOMEM;
    return (NULL);
  }
  do {
    ch = fgetc(fp);
    if (ch != EOF) {
      buffer[buffpos] = ch;
      if (++buffpos == bufflen) {
        bufflen += 80;
        if ((buffer = realloc(buffer, bufflen)) == NULL) {
          errno = ENOMEM;
          return (NULL);
        }
      }
    }
  } while ((ch != EOF) && (ch != '\n'));
  buffer[buffpos] = '\0';
  if (++buffpos < bufflen) {
    if ((buffer = realloc(buffer, bufflen)) == NULL) {
      errno = ENOMEM;
      return (NULL);
    }
  }
  return (buffer);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<blFgetsany>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  call   <fgetc@plt>
  mov    %eax,%edi
  mov    D24(%rip),%rax
  cmp    %edi,(%rax)
  je     L108
  mov    %r15,%rsi
  call   <ungetc@plt>
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ebp
  mov    $0x50,%r14d
  test   %rax,%rax
  jne    L21
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  jmp    L14
L7:
  add    $0x1,%rbp
  mov    D24(%rip),%rax
  cmp    %ebx,(%rax)
  je     L2
  cmp    $0xa,%ebx
  je     L2
L21:
  mov    %ebp,%r12d
  mov    %r15,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    D24(%rip),%rax
  cmp    %ebx,(%rax)
  je     L2
  mov    %bl,0x0(%r13,%rbp,1)
  lea    0x1(%rbp),%r12d
  cmp    %r12d,%r14d
  jne    L7
  add    $0x50,%r14d
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <realloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L7
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  jmp    L14
L2:
  movslq %r12d,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  add    $0x1,%r12d
  cmp    %r14d,%r12d
  jl     L88
L14:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L88:
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <realloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L14
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  jmp    L14
L108:
  mov    $0x0,%r13d
  jmp    L14
```

assistant: ```c
char *blFgetsany(FILE *fp) {
  int bufflen = 80, buffpos = 0, ch;
  char *buffer = NULL;
  if ((ch = fgetc(fp)) == EOF)
    return (NULL);
  ungetc(ch, fp);
  if ((buffer = (char *)malloc(bufflen * sizeof(char))) == NULL) {
    errno = ENOMEM;
    return (NULL);
  }
  do {
    ch = fgetc(fp);
    if (ch != EOF) {
      buffer[buffpos] = ch;
      if (++buffpos == bufflen) {
        bufflen += 80;
        if ((buffer = realloc(buffer, bufflen)) == NULL) {
          errno = ENOMEM;
          return (NULL);
        }
      }
    }
  } while ((ch != EOF) && (ch != '\n'));
  buffer[buffpos] = '\0';
  if (++buffpos < bufflen) {
    if ((buffer = realloc(buffer, bufflen)) == NULL) {
      errno = ENOMEM;
      return (NULL);
    }
  }
  return (buffer);
}
```