ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<SK_clearsockflags>:
  endbr64
  push   %r12
  xor    %edx,%edx
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L8
  not    %ebx
  mov    %r12d,%edi
  mov    %ebx,%edx
  and    %eax,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L8
L11:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    $0xffffffff,%r12d
  jmp    L11
```

assistant: ```c
int SK_clearsockflags(int socket, int flags) {
  int old_flags;
  if ((old_flags = fcntl(socket, F_GETFL, 0)) == -1) {
    return -1;
  }
  if (fcntl(socket, F_SETFL, old_flags & ~flags) == -1) {
    return -1;
  }
  return socket;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<chr_get_skip_delta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movw   $0x0,-0x2(%rbp)
  jmp    L12
L36:
  movzwl -0x2(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x3(%rbp)
  cmpb   $0x0,-0x3(%rbp)
  jne    L13
  movzwl -0x2(%rbp),%eax
  jmp    L37
L13:
  movzbl -0x3(%rbp),%eax
  add    %ax,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x1c(%rbp)
L12:
  cmpb   $0x0,-0x1c(%rbp)
  jne    L36
  movzwl -0x2(%rbp),%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
unsigned short chr_get_skip_delta(unsigned char *cbuf, unsigned char skip_cnt) {
  unsigned short pos = 0;
  unsigned char len;
  while (skip_cnt > 0) {
    len = ((cbuf + pos)[0]);
    if (len == 0)
      return pos;
    pos += len;
    skip_cnt--;
  }
  return pos;
}
```
user: What is the c source code of the assembly code below?

```asm
<chr_get_skip_delta>:
  endbr64
  mov    %esi,%ecx
  test   %sil,%sil
  je     L7
  mov    $0x0,%edx
L15:
  movzwl %dx,%eax
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  je     L21
  movzbl %al,%eax
  add    %eax,%edx
  sub    $0x1,%cl
  jne    L15
L21:
  mov    %edx,%eax
  ret
L7:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
unsigned short chr_get_skip_delta(unsigned char *cbuf, unsigned char skip_cnt) {
  unsigned short pos = 0;
  unsigned char len;
  while (skip_cnt > 0) {
    len = ((cbuf + pos)[0]);
    if (len == 0)
      return pos;
    pos += len;
    skip_cnt--;
  }
  return pos;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chr_get_skip_delta>:
  endbr64
  mov    %esi,%edx
  xor    %r8d,%r8d
  test   %sil,%sil
  jne    L29
  jmp    L27
L22:
  add    %eax,%r8d
  sub    $0x1,%dl
  je     L27
L29:
  movzwl %r8w,%eax
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  jne    L22
L27:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short chr_get_skip_delta(unsigned char *cbuf, unsigned char skip_cnt) {
  unsigned short pos = 0;
  unsigned char len;
  while (skip_cnt > 0) {
    len = ((cbuf + pos)[0]);
    if (len == 0)
      return pos;
    pos += len;
    skip_cnt--;
  }
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<chr_get_skip_delta>:
  endbr64
  mov    %esi,%edx
  xor    %r8d,%r8d
  test   %sil,%sil
  jne    L13
  jmp    L29
L25:
  add    %eax,%r8d
  sub    $0x1,%dl
  je     L29
L13:
  movzwl %r8w,%eax
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  jne    L25
L29:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short chr_get_skip_delta(unsigned char *cbuf, unsigned char skip_cnt) {
  unsigned short pos = 0;
  unsigned char len;
  while (skip_cnt > 0) {
    len = ((cbuf + pos)[0]);
    if (len == 0)
      return pos;
    pos += len;
    skip_cnt--;
  }
  return pos;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L2
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <_exit@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
int kill(int pid, int sig) {
  if (pid == 1) {
    _exit(sig);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kill>:
  endbr64
  cmp    $0x1,%edi
  je     L9
  ret
L9:
  sub    $0x8,%rsp
  mov    %esi,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int kill(int pid, int sig) {
  if (pid == 1) {
    _exit(sig);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kill>:
  endbr64
  cmp    $0x1,%edi
  je     L2
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %esi,%edi
  jmp    1050 <_exit@plt>
```

assistant: ```c
int kill(int pid, int sig) {
  if (pid == 1) {
    _exit(sig);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kill>:
  endbr64
  cmp    $0x1,%edi
  je     L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %esi,%edi
  jmp    1050 <_exit@plt>
```

assistant: ```c
int kill(int pid, int sig) {
  if (pid == 1) {
    _exit(sig);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rowexchange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <quadrant@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <quadrant@plt>
  cmp    %eax,%ebx
  je     L20
  mov    $0x0,%eax
  jmp    L34
L20:
  movl   $0x0,-0x18(%rbp)
  jmp    L31
L39:
  mov    -0x18(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L31:
  cmpl   $0x8,-0x18(%rbp)
  jle    L39
  mov    $0x1,%eax
L34:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int rowexchange(sudoku, a, b)
int sudoku[];
int a, b;
{
  if (quadrant(a) != quadrant(b)) {
    return (0);
  }
  int c;
  int d;
  for (c = 0; c < 9; c++) {
    d = sudoku[c + a];
    sudoku[c + a] = sudoku[c + b];
    sudoku[c + b] = d;
  }
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rowexchange>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %esi,%edi
  mov    $0x0,%eax
  call   <quadrant@plt>
  mov    %eax,%r13d
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <quadrant@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%r13d
  jne    L15
  movslq %ebx,%rbx
  shl    $0x2,%rbx
  lea    0x0(%rbp,%rbx,1),%rax
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,4),%rdx
  lea    0x24(%rbp,%rbx,1),%rdi
L7:
  mov    (%rax),%ecx
  mov    (%rdx),%esi
  mov    %esi,(%rax)
  mov    %ecx,(%rdx)
  add    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rdi,%rax
  jne    L7
  mov    $0x1,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int rowexchange(sudoku, a, b)
int sudoku[];
int a, b;
{
  if (quadrant(a) != quadrant(b)) {
    return (0);
  }
  int c;
  int d;
  for (c = 0; c < 9; c++) {
    d = sudoku[c + a];
    sudoku[c + a] = sudoku[c + b];
    sudoku[c + b] = d;
  }
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rowexchange>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <quadrant@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <quadrant@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%r13d
  jne    L14
  shl    $0x2,%rbx
  lea    (%r12,%rbp,4),%rdx
  lea    (%r12,%rbx,1),%rax
  lea    0x24(%r12,%rbx,1),%rdi
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rdx),%esi
  mov    (%rax),%ecx
  add    $0x4,%rax
  add    $0x4,%rdx
  mov    %esi,-0x4(%rax)
  mov    %ecx,-0x4(%rdx)
  cmp    %rdi,%rax
  jne    L15
  mov    $0x1,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int rowexchange(sudoku, a, b)
int sudoku[];
int a, b;
{
  if (quadrant(a) != quadrant(b)) {
    return (0);
  }
  int c;
  int d;
  for (c = 0; c < 9; c++) {
    d = sudoku[c + a];
    sudoku[c + a] = sudoku[c + b];
    sudoku[c + b] = d;
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rowexchange>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <quadrant@plt>
  mov    %r12d,%edi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <quadrant@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%r13d
  jne    L13
  movslq %ebx,%rax
  movslq %r12d,%rcx
  lea    0x10(,%rax,4),%rsi
  shl    $0x2,%rcx
  shl    $0x2,%rax
  lea    0x10(%rcx),%rdx
  cmp    %rsi,%rcx
  jge    L23
  cmp    %rdx,%rax
  jl     L1
L23:
  add    %rbp,%rax
  lea    0x0(%rbp,%rcx,1),%rdx
  movdqu (%rax),%xmm0
  movdqu (%rdx),%xmm1
  movups %xmm1,(%rax)
  movdqu 0x10(%rdx),%xmm2
  movups %xmm0,(%rdx)
  movdqu 0x10(%rax),%xmm0
  movups %xmm2,0x10(%rax)
  movups %xmm0,0x10(%rdx)
L0:
  lea    0x20(%rbp,%rcx,1),%rax
  lea    0x10(%rbp,%rsi,1),%rdx
  mov    (%rax),%ecx
  mov    (%rdx),%esi
  mov    %ecx,(%rdx)
  mov    %esi,(%rax)
  mov    $0x1,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  add    %rbp,%rax
  lea    0x0(%rbp,%rcx,1),%rdi
  add    %rbp,%rdx
  mov    (%rax),%r8d
  mov    (%rdi),%r9d
  mov    %r9d,(%rax)
  lea    0x4(%rbp,%rcx,1),%rax
  mov    %r8d,(%rdi)
  lea    -0xc(%rbp,%rsi,1),%rdi
  mov    (%rax),%r9d
  mov    (%rdi),%r8d
  mov    %r9d,(%rdi)
  lea    -0x8(%rbp,%rsi,1),%rdi
  mov    %r8d,(%rax)
  lea    0x8(%rbp,%rcx,1),%rax
  mov    (%rdi),%r8d
  mov    (%rax),%r9d
  mov    %r9d,(%rdi)
  lea    -0x4(%rbp,%rsi,1),%rdi
  mov    %r8d,(%rax)
  lea    0xc(%rbp,%rcx,1),%rax
  mov    (%rdi),%r8d
  mov    (%rax),%r9d
  mov    %r9d,(%rdi)
  mov    %r8d,(%rax)
  lea    0x0(%rbp,%rsi,1),%rax
  mov    (%rdx),%r8d
  mov    (%rax),%edi
  mov    %r8d,(%rax)
  lea    0x14(%rbp,%rcx,1),%rax
  mov    %edi,(%rdx)
  lea    0x4(%rbp,%rsi,1),%rdx
  mov    (%rax),%r8d
  mov    (%rdx),%edi
  mov    %r8d,(%rdx)
  lea    0x8(%rbp,%rsi,1),%rdx
  mov    %edi,(%rax)
  lea    0x18(%rbp,%rcx,1),%rax
  mov    (%rdx),%edi
  mov    (%rax),%r8d
  mov    %r8d,(%rdx)
  lea    0xc(%rbp,%rsi,1),%rdx
  mov    %edi,(%rax)
  lea    0x1c(%rbp,%rcx,1),%rax
  mov    (%rdx),%edi
  mov    (%rax),%r8d
  mov    %r8d,(%rdx)
  mov    %edi,(%rax)
  jmp    L0
```

assistant: ```c
int rowexchange(sudoku, a, b)
int sudoku[];
int a, b;
{
  if (quadrant(a) != quadrant(b)) {
    return (0);
  }
  int c;
  int d;
  for (c = 0; c < 9; c++) {
    d = sudoku[c + a];
    sudoku[c + a] = sudoku[c + b];
    sudoku[c + b] = d;
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getFileLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %rax,-0x8(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t getFileLength(FILE *fp) {
  fseek(fp, 0L, SEEK_END);
  size_t fileLen = ftell(fp);
  fseek(fp, 0L, SEEK_SET);
  return (fileLen);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getFileLength>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <fseek@plt>
  mov    %rbx,%rdi
  call   <ftell@plt>
  mov    %rax,%rbp
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t getFileLength(FILE *fp) {
  fseek(fp, 0L, SEEK_END);
  size_t fileLen = ftell(fp);
  fseek(fp, 0L, SEEK_SET);
  return (fileLen);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getFileLength>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    %rax,%r12
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t getFileLength(FILE *fp) {
  fseek(fp, 0L, SEEK_END);
  size_t fileLen = ftell(fp);
  fseek(fp, 0L, SEEK_SET);
  return (fileLen);
}
```
user: What is the c source code of the assembly code below:

```asm
<getFileLength>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    %rax,%r12
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t getFileLength(FILE *fp) {
  fseek(fp, 0L, SEEK_END);
  size_t fileLen = ftell(fp);
  fseek(fp, 0L, SEEK_SET);
  return (fileLen);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0xc,%eax
  ja     L32
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L43
L49:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  add    %eax,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L43:
  cmpl   $0x0,-0xc(%rbp)
  jg     L49
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L40
L32:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L40:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D14: %u

tool: D8: %u


tool: D7: overflow

assistant: ```c
int main() {
  unsigned int num, sum = 0;
  int i = 0;
  scanf("%u", &num);
  if (num <= 12) {
    for (i = num; i >= 1; i--) {
      sum += fact(i);
    }
    printf("%u\n", sum);
  } else
    printf("overflow");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xc,%eax
  ja     L38
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L18
  mov    $0x0,%ebp
L22:
  mov    %ebx,%edi
  call   <fact@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L22
L51:
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0x0,%ebp
  jmp    L51
L38:
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D24
type: string

tool: D10: %u

tool: D19: %u


tool: D24: overflow

assistant: ```c
int main() {
  unsigned int num, sum = 0;
  int i = 0;
  scanf("%u", &num);
  if (num <= 12) {
    for (i = num; i >= 1; i--) {
      sum += fact(i);
    }
    printf("%u\n", sum);
  } else
    printf("overflow");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  cmp    $0xc,%ebp
  ja     L41
  mov    %ebp,%ebx
  test   %ebp,%ebp
  je     L42
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L32:
  mov    %ebx,%edi
  call   <fact@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L32
L42:
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L41:
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L38
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D8
type_infered: string

tool: D21: %u

tool: D6: %u


tool: D8: overflow

assistant: ```c
int main() {
  unsigned int num, sum = 0;
  int i = 0;
  scanf("%u", &num);
  if (num <= 12) {
    for (i = num; i >= 1; i--) {
      sum += fact(i);
    }
    printf("%u\n", sum);
  } else
    printf("overflow");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  cmp    $0xc,%ebp
  ja     L2
  mov    %ebp,%ebx
  test   %ebp,%ebp
  je     L23
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L25:
  mov    %ebx,%edi
  call   <fact@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L25
L23:
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L28
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string

tool: D24: %u

tool: D22: %u


tool: D25: overflow

assistant: ```c
int main() {
  unsigned int num, sum = 0;
  int i = 0;
  scanf("%u", &num);
  if (num <= 12) {
    for (i = num; i >= 1; i--) {
      sum += fact(i);
    }
    printf("%u\n", sum);
  } else
    printf("overflow");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<finalPrint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <parseToFloatCelsius@plt>
  movq   %xmm0,%rax
  mov    -0x4(%rbp),%edx
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x14,-0x4(%rbp)
L12:
  cmpl   $0x12c,-0x4(%rbp)
  jle    L3
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: %3d	%5.1f


assistant: ```c
void finalPrint() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr += 20) {
    printf("%3d\t%5.1f\n", fahr, parseToFloatCelsius(fahr));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<finalPrint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
L1:
  mov    %ebx,%edi
  call   <parseToFloatCelsius@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  cmp    $0x140,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string

tool: D1: %3d	%5.1f


assistant: ```c
void finalPrint() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr += 20) {
    printf("%3d\t%5.1f\n", fahr, parseToFloatCelsius(fahr));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<finalPrint>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  call   <parseToFloatCelsius@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x14,%ebx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: %3d	%5.1f


assistant: ```c
void finalPrint() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr += 20) {
    printf("%3d\t%5.1f\n", fahr, parseToFloatCelsius(fahr));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<finalPrint>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  call   <parseToFloatCelsius@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x14,%ebx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: %3d	%5.1f


assistant: ```c
void finalPrint() {
  int fahr;
  for (fahr = 0; fahr <= 300; fahr += 20) {
    printf("%3d\t%5.1f\n", fahr, parseToFloatCelsius(fahr));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<energenie_off>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <output_0@plt>
  mov    $0x0,%eax
  call   <output_0@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void energenie_off() {
  output_0();
  output_0();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<energenie_off>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <output_0@plt>
  mov    $0x0,%eax
  call   <output_0@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void energenie_off() {
  output_0();
  output_0();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<energenie_off>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <output_0@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <output_0@plt>
```

assistant: ```c
void energenie_off() {
  output_0();
  output_0();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<energenie_off>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <output_0@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <output_0@plt>
```

assistant: ```c
void energenie_off() {
  output_0();
  output_0();
}
```