ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<fetch_proxy_settings>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8d,%ebx
  mov    %r9d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %r8b,%r8b
  lea    D19(%rip),%rdi
  lea    D0(%rip),%rax
  cmove  %rax,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    0x8(%rsp),%rsi
  sub    $0x8,%rsp
  push   %r15
  push   %r14
  lea    0x28(%rsp),%rax
  push   %rax
  movsbl %bl,%r9d
  movsbl %r13b,%r8d
  mov    %r12,%rcx
  mov    %rbp,%rdx
  call   <interpret_url@plt>
  add    $0x20,%rsp
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D19: https_proxy

tool: D0: http_proxy

assistant: ```c
void fetch_proxy_settings(char **proxy_user, char **proxy_password, char **proxy_host, int *proxy_port, char use_ssl, char use_ipv6) {
  char *str = getenv(use_ssl ? "https_proxy" : "http_proxy");
  if (!str) {
  }
  if (str) {
    char *path = NULL, *url = NULL;
    interpret_url(str, &path, proxy_host, proxy_port, use_ipv6, use_ssl, &url, proxy_user, proxy_password);
    free(url);
    free(path);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fetch_proxy_settings>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D11(%rip),%rdi
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %r8b,%r8b
  lea    D16(%rip),%rax
  cmove  %rax,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L19
  lea    0x8(%rsp),%rsi
  sub    $0x8,%rsp
  mov    %rax,%rdi
  movsbl %r15b,%r9d
  movq   $0x0,0x10(%rsp)
  movsbl %bl,%r8d
  mov    %r14,%rcx
  mov    %r12,%rdx
  movq   $0x0,0x18(%rsp)
  push   %r13
  push   %rbp
  lea    0x28(%rsp),%rax
  push   %rax
  call   <interpret_url@plt>
  mov    0x30(%rsp),%rdi
  add    $0x20,%rsp
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string

tool: D11: https_proxy

tool: D16: http_proxy

assistant: ```c
void fetch_proxy_settings(char **proxy_user, char **proxy_password, char **proxy_host, int *proxy_port, char use_ssl, char use_ipv6) {
  char *str = getenv(use_ssl ? "https_proxy" : "http_proxy");
  if (!str) {
  }
  if (str) {
    char *path = NULL, *url = NULL;
    interpret_url(str, &path, proxy_host, proxy_port, use_ipv6, use_ssl, &url, proxy_user, proxy_password);
    free(url);
    free(path);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fetch_proxy_settings>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %r8b,%r8b
  lea    D12(%rip),%rax
  cmove  %rax,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L13
  lea    0x8(%rsp),%rsi
  sub    $0x8,%rsp
  mov    %rax,%rdi
  movsbl %r15b,%r9d
  movq   $0x0,0x10(%rsp)
  movsbl %bl,%r8d
  mov    %r14,%rcx
  mov    %r12,%rdx
  movq   $0x0,0x18(%rsp)
  push   %r13
  push   %rbp
  lea    0x28(%rsp),%rax
  push   %rax
  call   <interpret_url@plt>
  mov    0x30(%rsp),%rdi
  add    $0x20,%rsp
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string
name: unpack_data
arguments: data_label: D12
type: string

tool: D2: https_proxy

tool: D12: http_proxy

assistant: ```c
void fetch_proxy_settings(char **proxy_user, char **proxy_password, char **proxy_host, int *proxy_port, char use_ssl, char use_ipv6) {
  char *str = getenv(use_ssl ? "https_proxy" : "http_proxy");
  if (!str) {
  }
  if (str) {
    char *path = NULL, *url = NULL;
    interpret_url(str, &path, proxy_host, proxy_port, use_ipv6, use_ssl, &url, proxy_user, proxy_password);
    free(url);
    free(path);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<normcdfQ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movsd  D6(%rip),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L22
  movsd  D6(%rip),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jne    L22
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <unitcdfP@plt>
  movq   %xmm0,%rax
  jmp    L15
L22:
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  -0x20(%rbp),%xmm3
  divsd  %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <unitcdfP@plt>
  movq   %xmm0,%rax
L15:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double normcdfQ(double x, double mean, double var) {
  assert(var >= 0);
  if (var == 1)
    return unitcdfP(mean - x);
  return unitcdfP((mean - x) / sqrt(var));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<normcdfQ>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  movq   %xmm0,%r14
  movq   %xmm1,%rbp
  movq   %xmm2,%rbx
  comisd D15(%rip),%xmm2
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movq   %rbx,%xmm4
  ucomisd D13(%rip),%xmm4
  jp     L22
  je     L39
L22:
  movq   %rbp,%xmm6
  movq   %r14,%xmm7
  subsd  %xmm7,%xmm6
  movq   %xmm6,%rbp
  pxor   %xmm0,%xmm0
  movq   %rbx,%xmm7
  ucomisd %xmm7,%xmm0
  ja     L18
  movq   %rbx,%xmm2
  sqrtsd %xmm2,%xmm2
L38:
  movq   %rbp,%xmm0
  divsd  %xmm2,%xmm0
  call   <unitcdfP@plt>
L46:
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L39:
  movq   %rbp,%xmm0
  movq   %r14,%xmm6
  subsd  %xmm6,%xmm0
  call   <unitcdfP@plt>
  jmp    L46
L18:
  movq   %rbx,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L38
```

tool_calls: name: read_data
arguments: label: D15
type_infered: byte[16]
name: read_data
arguments: label: D13
type_infered: byte[8]

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double normcdfQ(double x, double mean, double var) {
  assert(var >= 0);
  if (var == 1)
    return unitcdfP(mean - x);
  return unitcdfP((mean - x) / sqrt(var));
}
```
user: What is the c source code of the assembly code below:

```asm
<normcdfQ>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x28,%rsp
  comisd %xmm3,%xmm2
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  0x10(%rsp),%xmm2
  ucomisd D5(%rip),%xmm2
  movsd  0x18(%rsp),%xmm1
  subsd  0x8(%rsp),%xmm1
  jp     L37
  je     L4
L37:
  pxor   %xmm5,%xmm5
  ucomisd %xmm2,%xmm5
  ja     L39
  sqrtsd %xmm2,%xmm2
L20:
  movapd %xmm1,%xmm0
  add    $0x28,%rsp
  divsd  %xmm2,%xmm0
  jmp    1090 <unitcdfP@plt>
  nopl   0x0(%rax)
L4:
  movapd %xmm1,%xmm0
  add    $0x28,%rsp
  jmp    1090 <unitcdfP@plt>
L39:
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  jmp    L20
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double normcdfQ(double x, double mean, double var) {
  assert(var >= 0);
  if (var == 1)
    return unitcdfP(mean - x);
  return unitcdfP((mean - x) / sqrt(var));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<normcdfQ>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x28,%rsp
  comisd %xmm3,%xmm2
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  0x10(%rsp),%xmm2
  ucomisd D8(%rip),%xmm2
  movsd  0x18(%rsp),%xmm1
  subsd  0x8(%rsp),%xmm1
  jp     L38
  je     L1
L38:
  pxor   %xmm5,%xmm5
  ucomisd %xmm2,%xmm5
  ja     L5
  sqrtsd %xmm2,%xmm2
L24:
  movapd %xmm1,%xmm0
  add    $0x28,%rsp
  divsd  %xmm2,%xmm0
  jmp    1090 <unitcdfP@plt>
  nopl   0x0(%rax)
L1:
  movapd %xmm1,%xmm0
  add    $0x28,%rsp
  jmp    1090 <unitcdfP@plt>
L5:
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  jmp    L24
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double normcdfQ(double x, double mean, double var) {
  assert(var >= 0);
  if (var == 1)
    return unitcdfP(mean - x);
  return unitcdfP((mean - x) / sqrt(var));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L14
L0:
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
void *my_memdup(const void *src, size_t len) {
  void *dup = malloc(len);
  return dup ? memcpy(dup, src, len) : NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<my_memdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *my_memdup(const void *src, size_t len) {
  void *dup = malloc(len);
  return dup ? memcpy(dup, src, len) : NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<my_memdup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
L1:
  pop    %rdx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *my_memdup(const void *src, size_t len) {
  void *dup = malloc(len);
  return dup ? memcpy(dup, src, len) : NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_memdup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
L2:
  pop    %rdx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *my_memdup(const void *src, size_t len) {
  void *dup = malloc(len);
  return dup ? memcpy(dup, src, len) : NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_utime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x24(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%edi
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%esi
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edi,%r9d
  mov    %esi,%r8d
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0:  %d%02d%02d%lu

assistant: ```c
char *get_utime(void) {
  struct timeval tv;
  struct timezone tz;
  struct tm *tm;
  char *utime = (char *)malloc(16);
  gettimeofday(&tv, &tz);
  tm = localtime(&tv.tv_sec);
  sprintf(utime, " %d%02d%02d%lu", tm->tm_hour, tm->tm_min, tm->tm_sec, tv.tv_usec);
  return utime;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_utime>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  lea    0x14(%rsp),%rdi
  call   <localtime@plt>
  mov    0x4(%rax),%ecx
  mov    0x10(%rsp),%r9d
  mov    0x8(%rax),%r8d
  mov    (%rax),%edx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %rbx,%rax
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7:  %d%02d%02d%lu

assistant: ```c
char *get_utime(void) {
  struct timeval tv;
  struct timezone tz;
  struct tm *tm;
  char *utime = (char *)malloc(16);
  gettimeofday(&tv, &tz);
  tm = localtime(&tv.tv_sec);
  sprintf(utime, " %d%02d%02d%lu", tm->tm_hour, tm->tm_min, tm->tm_sec, tv.tv_usec);
  return utime;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_utime>:
  endbr64
  push   %r12
  mov    $0x10,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %rax,%r12
  call   <gettimeofday@plt>
  lea    0x14(%rsp),%rdi
  call   <localtime@plt>
  mov    0x10(%rsp),%r9d
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%r8d
  mov    (%rax),%edx
  call   <sprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4:  %d%02d%02d%lu

assistant: ```c
char *get_utime(void) {
  struct timeval tv;
  struct timezone tz;
  struct tm *tm;
  char *utime = (char *)malloc(16);
  gettimeofday(&tv, &tz);
  tm = localtime(&tv.tv_sec);
  sprintf(utime, " %d%02d%02d%lu", tm->tm_hour, tm->tm_min, tm->tm_sec, tv.tv_usec);
  return utime;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_utime>:
  endbr64
  push   %r12
  mov    $0x10,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %rax,%r12
  call   <gettimeofday@plt>
  lea    0x14(%rsp),%rdi
  call   <localtime@plt>
  mov    0x10(%rsp),%r9d
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%r8d
  mov    (%rax),%edx
  call   <sprintf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4:  %d%02d%02d%lu

assistant: ```c
char *get_utime(void) {
  struct timeval tv;
  struct timezone tz;
  struct tm *tm;
  char *utime = (char *)malloc(16);
  gettimeofday(&tv, &tz);
  tm = localtime(&tv.tv_sec);
  sprintf(utime, " %d%02d%02d%lu", tm->tm_hour, tm->tm_min, tm->tm_sec, tv.tv_usec);
  return utime;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  negl   -0x14(%rbp)
L16:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%edi
  call   <abs@plt>
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L13:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void itoa(int n, char s[]) {
  int i = 0, sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itoa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %rsi,%r14
  neg    %edi
  cmovs  %r13d,%edi
  mov    %rsi,%r12
  mov    $0x0,%ebp
L13:
  movslq %edi,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %ebp,%edx
  add    $0x1,%ebp
  add    $0x30,%eax
  mov    %al,(%r12)
  mov    %ebx,%edi
  add    $0x1,%r12
  test   %ebx,%ebx
  jne    L13
  test   %r13d,%r13d
  js     L4
L11:
  movslq %ebp,%rbp
  movb   $0x0,(%r14,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  movslq %ebp,%rbp
  movb   $0x2d,(%r14,%rbp,1)
  lea    0x2(%rdx),%ebp
  jmp    L11
```

assistant: ```c
void itoa(int n, char s[]) {
  int i = 0, sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<itoa>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  sub    $0x8,%rsp
  neg    %edi
  cmovs  %r12d,%edi
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L17:
  mov    %edi,%ebx
  add    $0x1,%r15
  imul   %rbp,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r14d,%edx
  mov    %ebx,%edi
  add    $0x1,%r14d
  add    $0x30,%eax
  mov    %al,-0x1(%r15)
  test   %ebx,%ebx
  jne    L17
  test   %r12d,%r12d
  jns    L13
  movslq %r14d,%r14
  movb   $0x2d,0x0(%r13,%r14,1)
  lea    0x2(%rdx),%r14d
L13:
  movslq %r14d,%r14
  movb   $0x0,0x0(%r13,%r14,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void itoa(int n, char s[]) {
  int i = 0, sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itoa>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  sub    $0x8,%rsp
  neg    %edi
  cmovs  %r12d,%edi
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L8:
  mov    %edi,%ebx
  add    $0x1,%r15
  imul   %rbp,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r14d,%edx
  mov    %ebx,%edi
  add    $0x1,%r14d
  add    $0x30,%eax
  mov    %al,-0x1(%r15)
  test   %ebx,%ebx
  jne    L8
  test   %r12d,%r12d
  jns    L12
  movslq %r14d,%r14
  movb   $0x2d,0x0(%r13,%r14,1)
  lea    0x2(%rdx),%r14d
L12:
  movslq %r14d,%r14
  movb   $0x0,0x0(%r13,%r14,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void itoa(int n, char s[]) {
  int i = 0, sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kernel_assert_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    $0x0,%ebx
  jmp    L5
L15:
  add    $0x1,%ebx
L5:
  mov    %ebx,%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int kernel_assert_strlen(const char *str) {
  register unsigned int i = 0;
  while (str[i] != 0)
    ++i;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kernel_assert_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  mov    $0x0,%eax
L2:
  add    $0x1,%eax
  mov    %eax,%edx
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L2
  ret
L19:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int kernel_assert_strlen(const char *str) {
  register unsigned int i = 0;
  while (str[i] != 0)
    ++i;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<kernel_assert_strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L9
  nopl   0x0(%rax,%rax,1)
L19:
  lea    0x1(%rax),%edx
  cmpb   $0x0,(%rdi,%rdx,1)
  mov    %rdx,%rax
  jne    L19
  ret
  nopl   (%rax)
L9:
  ret
```

assistant: ```c
unsigned int kernel_assert_strlen(const char *str) {
  register unsigned int i = 0;
  while (str[i] != 0)
    ++i;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<kernel_assert_strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L4
  nopl   0x0(%rax,%rax,1)
L19:
  lea    0x1(%rax),%edx
  cmpb   $0x0,(%rdi,%rdx,1)
  mov    %rdx,%rax
  jne    L19
  ret
  nopl   (%rax)
L4:
  ret
```

assistant: ```c
unsigned int kernel_assert_strlen(const char *str) {
  register unsigned int i = 0;
  while (str[i] != 0)
    ++i;
  return i;
}
```