ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parse_priv>:
  endbr64
  lea    D65(%rip),%rdx
  and    $0xf,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  lea    D53(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D76(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D1(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D14(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D43(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D13(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D47(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: tag: D53
datatype: string
name: parse_data
arguments: tag: D76
datatype: string
name: parse_data
arguments: tag: D1
datatype: string
name: parse_data
arguments: tag: D14
datatype: string
name: parse_data
arguments: tag: D43
datatype: string
name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D47
datatype: string

tool: D53: Reserved

tool: D76: Operator

tool: D1: Admin 

tool: D14: OEM   

tool: D43: No access

tool: D13: Callback

tool: D47: User  

assistant: ```c
char *parse_priv(unsigned char c) {
  char *p;
  c = (c & 0x0f);
  switch (c) {
  case 1:
    p = "Callback";
    break;
  case 2:
    p = "User  ";
    break;
  case 3:
    p = "Operator";
    break;
  case 4:
    p = "Admin ";
    break;
  case 5:
    p = "OEM   ";
    break;
  case 0x0f:
    p = "No access";
    break;
  default:
    p = "Reserved";
  }
  return (p);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<jp2_write_ftyp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <cio_tell@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x4,%edi
  call   <cio_skip@plt>
  mov    $0x4,%esi
  mov    $0x66747970,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a703220,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x0,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a703220,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a706970,%edi
  call   <cio_write@plt>
  mov    $0x0,%eax
  call   <cio_tell@plt>
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <cio_seek@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <cio_write@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <cio_seek@plt>
  nop
  leave
  ret
```

assistant: ```c
void jp2_write_ftyp() {
  int len, lenp;
  lenp = cio_tell();
  cio_skip(4);
  cio_write(0x66747970, 4);
  cio_write(0x6a703220, 4);
  cio_write(0, 4);
  cio_write(0x6a703220, 4);
  cio_write(0x6a706970, 4);
  len = cio_tell() - lenp;
  cio_seek(lenp);
  cio_write(len, 4);
  cio_seek(lenp + len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jp2_write_ftyp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <cio_tell@plt>
  mov    %eax,%ebp
  mov    $0x4,%edi
  call   <cio_skip@plt>
  mov    $0x4,%esi
  mov    $0x66747970,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a703220,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x0,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a703220,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a706970,%edi
  call   <cio_write@plt>
  mov    $0x0,%eax
  call   <cio_tell@plt>
  mov    %eax,%ebx
  mov    %eax,%r12d
  sub    %ebp,%r12d
  mov    %ebp,%edi
  call   <cio_seek@plt>
  mov    $0x4,%esi
  mov    %r12d,%edi
  call   <cio_write@plt>
  mov    %ebx,%edi
  call   <cio_seek@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void jp2_write_ftyp() {
  int len, lenp;
  lenp = cio_tell();
  cio_skip(4);
  cio_write(0x66747970, 4);
  cio_write(0x6a703220, 4);
  cio_write(0, 4);
  cio_write(0x6a703220, 4);
  cio_write(0x6a706970, 4);
  len = cio_tell() - lenp;
  cio_seek(lenp);
  cio_write(len, 4);
  cio_seek(lenp + len);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<jp2_write_ftyp>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  call   <cio_tell@plt>
  mov    $0x4,%edi
  mov    %eax,%r12d
  call   <cio_skip@plt>
  mov    $0x4,%esi
  mov    $0x66747970,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a703220,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  xor    %edi,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a703220,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a706970,%edi
  call   <cio_write@plt>
  xor    %eax,%eax
  call   <cio_tell@plt>
  mov    %r12d,%edi
  mov    %eax,%r13d
  mov    %eax,%ebp
  call   <cio_seek@plt>
  sub    %r12d,%r13d
  mov    $0x4,%esi
  mov    %r13d,%edi
  call   <cio_write@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <cio_seek@plt>
```

assistant: ```c
void jp2_write_ftyp() {
  int len, lenp;
  lenp = cio_tell();
  cio_skip(4);
  cio_write(0x66747970, 4);
  cio_write(0x6a703220, 4);
  cio_write(0, 4);
  cio_write(0x6a703220, 4);
  cio_write(0x6a706970, 4);
  len = cio_tell() - lenp;
  cio_seek(lenp);
  cio_write(len, 4);
  cio_seek(lenp + len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jp2_write_ftyp>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  call   <cio_tell@plt>
  mov    $0x4,%edi
  mov    %eax,%r12d
  call   <cio_skip@plt>
  mov    $0x4,%esi
  mov    $0x66747970,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a703220,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  xor    %edi,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a703220,%edi
  call   <cio_write@plt>
  mov    $0x4,%esi
  mov    $0x6a706970,%edi
  call   <cio_write@plt>
  xor    %eax,%eax
  call   <cio_tell@plt>
  mov    %r12d,%edi
  mov    %eax,%r13d
  mov    %eax,%ebp
  call   <cio_seek@plt>
  sub    %r12d,%r13d
  mov    $0x4,%esi
  mov    %r13d,%edi
  call   <cio_write@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <cio_seek@plt>
```

assistant: ```c
void jp2_write_ftyp() {
  int len, lenp;
  lenp = cio_tell();
  cio_skip(4);
  cio_write(0x66747970, 4);
  cio_write(0x6a703220, 4);
  cio_write(0, 4);
  cio_write(0x6a703220, 4);
  cio_write(0x6a706970, 4);
  len = cio_tell() - lenp;
  cio_seek(lenp);
  cio_write(len, 4);
  cio_seek(lenp + len);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x40(%rbp)
  movl   $0xffff,-0x3c(%rbp)
  movl   $0x1ffff,-0x38(%rbp)
  movl   $0xffffffff,-0x34(%rbp)
  movl   $0x20,-0x30(%rbp)
  movl   $0x10,-0x2c(%rbp)
  movl   $0xf,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <count_lz_v4si@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L4
L33:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  je     L10
  mov    $0x0,%eax
  call   <abort@plt>
L10:
  addl   $0x1,-0x44(%rbp)
L4:
  cmpl   $0x3,-0x44(%rbp)
  jle    L33
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int main() {
  unsigned int x[4] = {0x0, 0xFFFF, 0x1FFFF, 0xFFFFFFFF};
  int r[4] = {32, 16, 15, 0};
  int d[4], i;
  count_lz_v4si(x, d);
  for (i = 0; i < 4; i++) {
    if (d[i] != r[i])
      abort();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0xffff,0x4(%rsp)
  movl   $0x1ffff,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  movl   $0x20,0x10(%rsp)
  movl   $0x10,0x14(%rsp)
  movl   $0xf,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  call   <count_lz_v4si@plt>
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rbp
  jmp    L3
L0:
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  je     L13
L3:
  mov    0x0(%rbp,%rbx,1),%eax
  cmp    %eax,0x20(%rsp,%rbx,1)
  je     L0
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L0
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  unsigned int x[4] = {0x0, 0xFFFF, 0x1FFFF, 0xFFFFFFFF};
  int r[4] = {32, 16, 15, 0};
  int d[4], i;
  count_lz_v4si(x, d);
  for (i = 0; i < 4; i++) {
    if (d[i] != r[i])
      abort();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xffff00000000,%rax
  lea    0x20(%rsp),%rbp
  mov    %rsp,%rdi
  movl   $0x10,0x14(%rsp)
  movq   $0xf,0x18(%rsp)
  mov    %rbp,%rsi
  mov    %rax,(%rsp)
  movabs $0xffffffff0001ffff,%rax
  mov    %rax,0x8(%rsp)
  call   <count_lz_v4si@plt>
  mov    $0x20,%eax
  cmp    %eax,0x0(%rbp,%rbx,1)
  je     L8
L1:
  xor    %eax,%eax
  call   <abort@plt>
L8:
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  je     L0
L21:
  mov    0x10(%rsp,%rbx,1),%eax
  cmp    %eax,0x0(%rbp,%rbx,1)
  jne    L1
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  jne    L21
L0:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  unsigned int x[4] = {0x0, 0xFFFF, 0x1FFFF, 0xFFFFFFFF};
  int r[4] = {32, 16, 15, 0};
  int d[4], i;
  count_lz_v4si(x, d);
  for (i = 0; i < 4; i++) {
    if (d[i] != r[i])
      abort();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <count_lz_v4si@plt>
  cmpl   $0x20,0x10(%rsp)
  je     L20
  xor    %eax,%eax
  call   <abort@plt>
L20:
  cmpl   $0x10,0x14(%rsp)
  je     L22
  xor    %eax,%eax
  call   <abort@plt>
L22:
  cmpl   $0xf,0x18(%rsp)
  je     L38
  xor    %eax,%eax
  call   <abort@plt>
L38:
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L26
  xor    %eax,%eax
  call   <abort@plt>
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x00,0xff,0xff,0x00,0x00,0xff,0xff,0x01,0x00,0xff,0xff,0xff,0xff]}

assistant: ```c
int main() {
  unsigned int x[4] = {0x0, 0xFFFF, 0x1FFFF, 0xFFFFFFFF};
  int r[4] = {32, 16, 15, 0};
  int d[4], i;
  count_lz_v4si(x, d);
  for (i = 0; i < 4; i++) {
    if (d[i] != r[i])
      abort();
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ERR_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <ERR_get_state@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <err_get_slot@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <err_clear@plt>
  jmp    L5
L0:
  nop
L5:
  leave
  ret
```

assistant: ```c
void ERR_new(void) {
  ERR_STATE *es;
  es = ERR_get_state();
  if (es == NULL)
    return;
  err_get_slot(es);
  err_clear(es, es->top, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ERR_new>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <ERR_get_state@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <err_get_slot@plt>
  mov    $0x0,%edx
  mov    (%rbx),%esi
  mov    %rbx,%rdi
  call   <err_clear@plt>
L5:
  pop    %rbx
  ret
```

assistant: ```c
void ERR_new(void) {
  ERR_STATE *es;
  es = ERR_get_state();
  if (es == NULL)
    return;
  err_get_slot(es);
  err_clear(es, es->top, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ERR_new>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <ERR_get_state@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <err_get_slot@plt>
  mov    0x0(%rbp),%esi
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  jmp    1070 <err_clear@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  pop    %rbp
  ret
```

assistant: ```c
void ERR_new(void) {
  ERR_STATE *es;
  es = ERR_get_state();
  if (es == NULL)
    return;
  err_get_slot(es);
  err_clear(es, es->top, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ERR_new>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <ERR_get_state@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <err_get_slot@plt>
  mov    0x0(%rbp),%esi
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  jmp    1070 <err_clear@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  pop    %rbp
  ret
```

assistant: ```c
void ERR_new(void) {
  ERR_STATE *es;
  es = ERR_get_state();
  if (es == NULL)
    return;
  err_get_slot(es);
  err_clear(es, es->top, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <xmalloc@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xstrdup(const char *string) {
  char *p = xmalloc(strlen(string) + 1);
  strcpy(p, string);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xstrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    $0x0,%eax
  call   <xmalloc@plt>
  movslq %eax,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *xstrdup(const char *string) {
  char *p = xmalloc(strlen(string) + 1);
  strcpy(p, string);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  xor    %eax,%eax
  call   <xmalloc@plt>
  mov    %rbp,%rsi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <strcpy@plt>
  pop    %rbp
  ret
```

assistant: ```c
void *xstrdup(const char *string) {
  char *p = xmalloc(strlen(string) + 1);
  strcpy(p, string);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  xor    %eax,%eax
  call   <xmalloc@plt>
  mov    %rbp,%rsi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <strcpy@plt>
  pop    %rbp
  ret
```

assistant: ```c
void *xstrdup(const char *string) {
  char *p = xmalloc(strlen(string) + 1);
  strcpy(p, string);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gf8_muladd_AC>:
  endbr64
  test   %edx,%edx
  je     L16
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %edx,%ebx
  shl    $0x2,%rbx
  lea    (%rdx,%rdx,1),%esi
  mov    %esi,%r13d
  shl    $0x2,%r13
  add    %edx,%esi
  mov    %esi,%r12d
  shl    $0x2,%r12
  mov    %ebx,%ebp
  shl    $0x2,%rbp
  lea    (%rdx,%rdx,4),%edi
  lea    0x0(,%rdi,4),%r11
  add    %esi,%esi
  mov    %esi,%esi
  lea    0x0(,%rsi,4),%r15
  lea    0x0(,%rdx,8),%esi
  sub    %edx,%esi
  lea    0x0(,%rsi,4),%r14
  lea    (%rcx,%rbx,1),%rsi
  mov    %rsi,-0x8(%rsp)
L4:
  mov    (%rax),%r9d
  mov    (%rax,%rbx,1),%esi
  mov    (%rax,%r13,1),%r8d
  mov    (%rax,%r12,1),%edx
  mov    (%rax,%rbp,1),%r10d
  mov    %r10d,-0x10(%rsp)
  mov    (%rax,%r15,1),%edi
  mov    %edi,-0x14(%rsp)
  mov    (%rax,%r14,1),%edi
  mov    %r9d,%r10d
  xor    %r8d,%r10d
  mov    %r10d,-0xc(%rsp)
  xor    (%rax,%r11,1),%r9d
  mov    %esi,%r10d
  xor    %edx,%r10d
  xor    (%rcx),%r10d
  mov    %r10d,(%rax)
  mov    -0x10(%rsp),%r10d
  xor    %r10d,%r8d
  xor    (%rcx,%rbx,1),%r8d
  mov    %r8d,(%rax,%rbx,1)
  mov    %esi,%r8d
  xor    (%rcx,%r13,1),%r8d
  xor    %r9d,%r8d
  mov    %r8d,(%rax,%r13,1)
  xor    -0x14(%rsp),%edx
  xor    (%rcx,%r12,1),%edx
  mov    -0xc(%rsp),%r8d
  xor    %r8d,%edx
  mov    %edx,(%rax,%r12,1)
  mov    %r10d,%edx
  xor    %edi,%edx
  xor    (%rcx,%rbp,1),%edx
  mov    %edx,(%rax,%rbp,1)
  xor    (%rcx,%r11,1),%r9d
  mov    %r9d,(%rax,%r11,1)
  xor    -0x14(%rsp),%esi
  xor    (%rcx,%r15,1),%esi
  mov    %esi,(%rax,%r15,1)
  xor    (%rcx,%r14,1),%edi
  xor    %r8d,%edi
  mov    %edi,(%rax,%r14,1)
  add    $0x4,%rcx
  add    $0x4,%rax
  cmp    -0x8(%rsp),%rcx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  ret
```

assistant: ```c
void gf8_muladd_AC(uint8_t *out, uint8_t *in, unsigned int width) {
  unsigned int i;
  uint64_t *in_ptr = (uint64_t *)in;
  uint64_t *out_ptr = (uint64_t *)out;
  for (i = 0; i < width; i++) {
    uint64_t out0, out1, out2, out3, out4, out5, out6, out7;
    uint64_t tmp0;
    uint64_t in0 = out_ptr[0];
    uint64_t in1 = out_ptr[width];
    uint64_t in2 = out_ptr[width * 2];
    uint64_t in3 = out_ptr[width * 3];
    uint64_t in4 = out_ptr[width * 4];
    uint64_t in5 = out_ptr[width * 5];
    uint64_t in6 = out_ptr[width * 6];
    uint64_t in7 = out_ptr[width * 7];
    out0 = in1 ^ in3;
    out1 = in2 ^ in4;
    tmp0 = in0 ^ in2;
    out4 = in4 ^ in7;
    out5 = in0 ^ in5;
    out6 = in1 ^ in6;
    out7 = tmp0 ^ in7;
    out3 = tmp0 ^ in3 ^ in6;
    out2 = out5 ^ in1;
    out_ptr[0] = out0 ^ in_ptr[0];
    out_ptr[width] = out1 ^ in_ptr[width];
    out_ptr[width * 2] = out2 ^ in_ptr[width * 2];
    out_ptr[width * 3] = out3 ^ in_ptr[width * 3];
    out_ptr[width * 4] = out4 ^ in_ptr[width * 4];
    out_ptr[width * 5] = out5 ^ in_ptr[width * 5];
    out_ptr[width * 6] = out6 ^ in_ptr[width * 6];
    out_ptr[width * 7] = out7 ^ in_ptr[width * 7];
    in_ptr++;
    out_ptr++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x36,%eax
  ja     L130
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D2(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L50
  mov    $0x1,%eax
  jmp    L50
  mov    $0x2,%eax
  jmp    L50
  mov    $0x3,%eax
  jmp    L50
  mov    $0x4,%eax
  jmp    L50
  mov    $0x5,%eax
  jmp    L50
  mov    $0x6,%eax
  jmp    L50
  mov    $0x7,%eax
  jmp    L50
  mov    $0x8,%eax
  jmp    L50
  mov    $0x9,%eax
  jmp    L50
  mov    $0xa,%eax
  jmp    L50
  mov    $0xb,%eax
  jmp    L50
  mov    $0xc,%eax
  jmp    L50
  mov    $0xd,%eax
  jmp    L50
  mov    $0xe,%eax
  jmp    L50
  mov    $0xf,%eax
  jmp    L50
L130:
  mov    $0xffffffff,%eax
L50:
  pop    %rbp
  ret
```

assistant: ```c
int hex2int(char c) {
  switch (c) {
  case '0':
    return 0;
  case '1':
    return 1;
  case '2':
    return 2;
  case '3':
    return 3;
  case '4':
    return 4;
  case '5':
    return 5;
  case '6':
    return 6;
  case '7':
    return 7;
  case '8':
    return 8;
  case '9':
    return 9;
  case 'a':
  case 'A':
    return 10;
  case 'b':
  case 'B':
    return 11;
  case 'c':
  case 'C':
    return 12;
  case 'd':
  case 'D':
    return 13;
  case 'e':
  case 'E':
    return 14;
  case 'f':
  case 'F':
    return 15;
  default:
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hex2int>:
  endbr64
  sub    $0x30,%edi
  cmp    $0x36,%dil
  ja     L1
  movzbl %dil,%edi
  lea    D2(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0xd,%eax
  ret
  mov    $0xe,%eax
  ret
  mov    $0xf,%eax
  ret
L1:
  mov    $0xffffffff,%eax
  ret
  mov    $0x0,%eax
  ret
```

assistant: ```c
int hex2int(char c) {
  switch (c) {
  case '0':
    return 0;
  case '1':
    return 1;
  case '2':
    return 2;
  case '3':
    return 3;
  case '4':
    return 4;
  case '5':
    return 5;
  case '6':
    return 6;
  case '7':
    return 7;
  case '8':
    return 8;
  case '9':
    return 9;
  case 'a':
  case 'A':
    return 10;
  case 'b':
  case 'B':
    return 11;
  case 'c':
  case 'C':
    return 12;
  case 'd':
  case 'D':
    return 13;
  case 'e':
  case 'E':
    return 14;
  case 'f':
  case 'F':
    return 15;
  default:
    return -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hex2int>:
  endbr64
  sub    $0x30,%edi
  mov    $0xffffffff,%eax
  cmp    $0x36,%dil
  ja     L0
  movzbl %dil,%edi
  lea    D4(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: 

assistant: ```c
int hex2int(char c) {
  switch (c) {
  case '0':
    return 0;
  case '1':
    return 1;
  case '2':
    return 2;
  case '3':
    return 3;
  case '4':
    return 4;
  case '5':
    return 5;
  case '6':
    return 6;
  case '7':
    return 7;
  case '8':
    return 8;
  case '9':
    return 9;
  case 'a':
  case 'A':
    return 10;
  case 'b':
  case 'B':
    return 11;
  case 'c':
  case 'C':
    return 12;
  case 'd':
  case 'D':
    return 13;
  case 'e':
  case 'E':
    return 14;
  case 'f':
  case 'F':
    return 15;
  default:
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex2int>:
  endbr64
  sub    $0x30,%edi
  mov    $0xffffffff,%eax
  cmp    $0x36,%dil
  ja     L2
  movzbl %dil,%edi
  lea    D8(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L2:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: 

assistant: ```c
int hex2int(char c) {
  switch (c) {
  case '0':
    return 0;
  case '1':
    return 1;
  case '2':
    return 2;
  case '3':
    return 3;
  case '4':
    return 4;
  case '5':
    return 5;
  case '6':
    return 6;
  case '7':
    return 7;
  case '8':
    return 8;
  case '9':
    return 9;
  case 'a':
  case 'A':
    return 10;
  case 'b':
  case 'B':
    return 11;
  case 'c':
  case 'C':
    return 12;
  case 'd':
  case 'D':
    return 13;
  case 'e':
  case 'E':
    return 14;
  case 'f':
  case 'F':
    return 15;
  default:
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L30:
  shll   -0xc(%rbp)
L15:
  cmpl   $0x63,-0xc(%rbp)
  jle    L30
  movl   $0x0,-0x8(%rbp)
  jmp    L42
L51:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L25:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x31,-0x4(%rbp)
  jle    L25
  addl   $0x1,-0x8(%rbp)
L42:
  cmpl   $0x18,-0x8(%rbp)
  jle    L51
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int sum = 0;
  int i, j;
  while (sum < 100) {
    sum = sum * 2;
  }
  for (i = 0; i < 25; i++) {
    for (j = 0; j < 50; j++) {
      sum = sum + i * j;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
L1:
  jmp    L1
```

assistant: ```c
int main() {
  int sum = 0;
  int i, j;
  while (sum < 100) {
    sum = sum * 2;
  }
  for (i = 0; i < 25; i++) {
    for (j = 0; j < 50; j++) {
      sum = sum + i * j;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L1:
  jmp    L1
```

assistant: ```c
int main() {
  int sum = 0;
  int i, j;
  while (sum < 100) {
    sum = sum * 2;
  }
  for (i = 0; i < 25; i++) {
    for (j = 0; j < 50; j++) {
      sum = sum + i * j;
    }
  }
}
```