ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<substep>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  movsd  %xmm2,0x8(%rsp)
  call   <calc_grad@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <add_fluxes@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <add_sources@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <calc_prim@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <bc_1L@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <bc_1R@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <bc_2L@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <bc_2R@plt>
  add    $0x18,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <calc_cons@plt>
```

assistant: ```c
void substep(struct grid *g, double rkfac1, double rkfac2, double dt, struct parList *pars) {
  calc_grad(g, pars);
  add_fluxes(g, dt, pars);
  add_sources(g, dt, pars);
  calc_prim(g, pars);
  bc_1L(g, pars);
  bc_1R(g, pars);
  bc_2L(g, pars);
  bc_2R(g, pars);
  calc_cons(g, pars);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0xa,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <twoLoops@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t size = 10;
  float *tabFloat = malloc(sizeof(float) * size);
  twoLoops(tabFloat, size);
  free(tabFloat);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <twoLoops@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t size = 10;
  float *tabFloat = malloc(sizeof(float) * size);
  twoLoops(tabFloat, size);
  free(tabFloat);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    $0xa,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <twoLoops@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t size = 10;
  float *tabFloat = malloc(sizeof(float) * size);
  twoLoops(tabFloat, size);
  free(tabFloat);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    $0xa,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <twoLoops@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t size = 10;
  float *tabFloat = malloc(sizeof(float) * size);
  twoLoops(tabFloat, size);
  free(tabFloat);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<var>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <mean@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L6
L3:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L6:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L3
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double var(double *x, double n) {
  int i;
  double m, r, sum = 0;
  m = mean(x, n);
  for (i = 0; i < n; i++) {
    r = x[i] - m;
    sum += (r * r);
  }
  return sum / n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<var>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movq   %xmm0,%r14
  call   <mean@plt>
  movapd %xmm0,%xmm2
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
  movq   %r14,%xmm4
  comisd %xmm0,%xmm4
  jbe    L29
L3:
  movsd  -0x8(%rbx,%rax,8),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  add    $0x1,%rax
  movq   %r14,%xmm3
  comisd %xmm1,%xmm3
  ja     L3
L18:
  movq   %r14,%xmm5
  divsd  %xmm5,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
L29:
  pxor   %xmm0,%xmm0
  jmp    L18
```

assistant: ```c
double var(double *x, double n) {
  int i;
  double m, r, sum = 0;
  m = mean(x, n);
  for (i = 0; i < n; i++) {
    r = x[i] - m;
    sum += (r * r);
  }
  return sum / n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<var>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <mean@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  comisd %xmm0,%xmm2
  jbe    L0
  mov    $0x1,%eax
L13:
  movsd  -0x8(%rbx,%rax,8),%xmm1
  subsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  add    $0x1,%rax
  comisd %xmm1,%xmm2
  ja     L13
L0:
  divsd  %xmm2,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double var(double *x, double n) {
  int i;
  double m, r, sum = 0;
  m = mean(x, n);
  for (i = 0; i < n; i++) {
    r = x[i] - m;
    sum += (r * r);
  }
  return sum / n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<var>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <mean@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  comisd %xmm0,%xmm2
  jbe    L17
  mov    $0x1,%eax
L13:
  movsd  -0x8(%rbx,%rax,8),%xmm1
  subsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  add    $0x1,%rax
  comisd %xmm1,%xmm2
  ja     L13
L17:
  divsd  %xmm2,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double var(double *x, double n) {
  int i;
  double m, r, sum = 0;
  m = mean(x, n);
  for (i = 0; i < n; i++) {
    r = x[i] - m;
    sum += (r * r);
  }
  return sum / n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ast_new_from_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  test   %eax,%eax
  jg     L18
  mov    $0x0,%eax
  jmp    L5
L18:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <tokenize@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L5
L31:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <build_ast@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <token_stream_free@plt>
  mov    -0x8(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
struct AST *ast_new_from_parse(wchar_t *data) {
  if (wcslen(data) < 1)
    return NULL;
  struct TokenStream *ts = tokenize(data);
  if (ts == NULL)
    return NULL;
  struct AST *ast = build_ast(ts);
  token_stream_free(ts);
  return ast;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ast_new_from_parse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <wcslen@plt>
  mov    $0x0,%ebp
  test   %eax,%eax
  jle    L2
  mov    %rbx,%rdi
  call   <tokenize@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L23
  mov    %rax,%rdi
  call   <build_ast@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <token_stream_free@plt>
L2:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  mov    %rax,%rbp
  jmp    L2
```

assistant: ```c
struct AST *ast_new_from_parse(wchar_t *data) {
  if (wcslen(data) < 1)
    return NULL;
  struct TokenStream *ts = tokenize(data);
  if (ts == NULL)
    return NULL;
  struct AST *ast = build_ast(ts);
  token_stream_free(ts);
  return ast;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ast_new_from_parse>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <wcslen@plt>
  test   %eax,%eax
  jle    L16
  mov    %rbp,%rdi
  call   <tokenize@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
  mov    %rax,%rdi
  call   <build_ast@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <token_stream_free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L16:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct AST *ast_new_from_parse(wchar_t *data) {
  if (wcslen(data) < 1)
    return NULL;
  struct TokenStream *ts = tokenize(data);
  if (ts == NULL)
    return NULL;
  struct AST *ast = build_ast(ts);
  token_stream_free(ts);
  return ast;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ast_new_from_parse>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <wcslen@plt>
  test   %eax,%eax
  jle    L5
  mov    %rbp,%rdi
  call   <tokenize@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L5
  mov    %rax,%rdi
  call   <build_ast@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <token_stream_free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L5:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct AST *ast_new_from_parse(wchar_t *data) {
  if (wcslen(data) < 1)
    return NULL;
  struct TokenStream *ts = tokenize(data);
  if (ts == NULL)
    return NULL;
  struct AST *ast = build_ast(ts);
  token_stream_free(ts);
  return ast;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap_byte2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L27:
  mov    -0x10(%rbp),%eax
  cltq
  mov    $0x1,%edx
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  mov    %dl,-0xc(%rbp,%rax,1)
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jbe    L27
  lea    -0xc(%rbp),%rax
  movzwl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void *swap_byte2(short *theInt) {
  char tmp[4];
  int i;
  for (i = 0; i < sizeof(short); i++)
    tmp[i] = *((char *)theInt + (sizeof(short) - 1 - i));
  *theInt = *((short *)tmp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap_byte2>:
  endbr64
  mov    $0x0,%eax
  mov    0x1(%rdi),%al
  movzbl (%rdi),%edx
  mov    %dl,%ah
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void *swap_byte2(short *theInt) {
  char tmp[4];
  int i;
  for (i = 0; i < sizeof(short); i++)
    tmp[i] = *((char *)theInt + (sizeof(short) - 1 - i));
  *theInt = *((short *)tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap_byte2>:
  endbr64
  rolw   $0x8,(%rdi)
  ret
```

assistant: ```c
void *swap_byte2(short *theInt) {
  char tmp[4];
  int i;
  for (i = 0; i < sizeof(short); i++)
    tmp[i] = *((char *)theInt + (sizeof(short) - 1 - i));
  *theInt = *((short *)tmp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap_byte2>:
  endbr64
  rolw   $0x8,(%rdi)
  ret
```

assistant: ```c
void *swap_byte2(short *theInt) {
  char tmp[4];
  int i;
  for (i = 0; i < sizeof(short); i++)
    tmp[i] = *((char *)theInt + (sizeof(short) - 1 - i));
  *theInt = *((short *)tmp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<grecs_list_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <grecs_list_clear@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <grecs_free@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void grecs_list_free(struct grecs_list *lp) {
  if (lp) {
    grecs_list_clear(lp);
    grecs_free(lp);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<grecs_list_free>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbx
  mov    %rdi,%rbx
  call   <grecs_list_clear@plt>
  mov    %rbx,%rdi
  call   <grecs_free@plt>
  pop    %rbx
  ret
L4:
  ret
```

assistant: ```c
void grecs_list_free(struct grecs_list *lp) {
  if (lp) {
    grecs_list_clear(lp);
    grecs_free(lp);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<grecs_list_free>:
  endbr64
  test   %rdi,%rdi
  je     L7
  push   %rbp
  mov    %rdi,%rbp
  call   <grecs_list_clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <grecs_free@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void grecs_list_free(struct grecs_list *lp) {
  if (lp) {
    grecs_list_clear(lp);
    grecs_free(lp);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<grecs_list_free>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  call   <grecs_list_clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <grecs_free@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void grecs_list_free(struct grecs_list *lp) {
  if (lp) {
    grecs_list_clear(lp);
    grecs_free(lp);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %edi,-0x224(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L15
L42:
  movl   $0x0,-0x214(%rbp)
  jmp    L40
L20:
  mov    -0x214(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x210(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x214(%rbp)
L40:
  mov    -0x218(%rbp),%eax
  cmp    %eax,-0x214(%rbp)
  jl     L20
  mov    -0x218(%rbp),%edx
  mov    -0x21c(%rbp),%ecx
  lea    -0x210(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <binary_search@plt>
  test   %eax,%eax
  je     L59
  lea    D6(%rip),%rax
  jmp    L52
L59:
  lea    D4(%rip),%rax
L52:
  mov    %rax,%rdi
  call   <puts@plt>
L15:
  lea    -0x218(%rbp),%rdx
  lea    -0x21c(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  jne    L42
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D12
type_infered: string

tool: D13: %d

tool: D6: True

tool: D4: False

tool: D12: %d%d

assistant: ```c
int main(int argc, char const *argv[]) {
  int x, n;
  int nums[128];
  while (~scanf("%d%d", &x, &n)) {
    for (int i = 0; i < n; ++i)
      scanf("%d", nums + i);
    printf("%s\n", binary_search(nums, x, n) ? "True" : "False");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%r13
  lea    D15(%rip),%r12
  lea    D3(%rip),%r15
  lea    D19(%rip),%r14
  jmp    L25
L37:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%edx
  add    $0x4,%rbp
  cmp    %ebx,%edx
  jg     L37
L55:
  lea    0x10(%rsp),%rdi
  mov    0x8(%rsp),%esi
  mov    $0x0,%eax
  call   <binary_search@plt>
  test   %eax,%eax
  mov    %r14,%rdi
  cmovne %r15,%rdi
  call   <puts@plt>
L25:
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  je     L12
  mov    0xc(%rsp),%edx
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  test   %edx,%edx
  jg     L37
  jmp    L55
L12:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string
name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D19
datatype: string

tool: D9: %d%d

tool: D15: %d

tool: D3: True

tool: D19: False

assistant: ```c
int main(int argc, char const *argv[]) {
  int x, n;
  int nums[128];
  while (~scanf("%d%d", &x, &n)) {
    for (int i = 0; i < n; ++i)
      scanf("%d", nums + i);
    printf("%s\n", binary_search(nums, x, n) ? "True" : "False");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r14
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%rbp
  xchg   %ax,%ax
L23:
  xor    %eax,%eax
  mov    %r14,%rdx
  lea    D10(%rip),%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  je     L40
  mov    0xc(%rsp),%r8d
  mov    %rbp,%r12
  xor    %r15d,%r15d
  test   %r8d,%r8d
  jle    L43
  nopl   0x0(%rax)
L22:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  add    $0x4,%r12
  cmp    %r15d,%r8d
  jg     L22
L43:
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  mov    %r8d,%edx
  xor    %eax,%eax
  call   <binary_search@plt>
  lea    D2(%rip),%rdi
  test   %eax,%eax
  lea    D39(%rip),%rax
  cmovne %rax,%rdi
  call   <puts@plt>
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L40:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string
name: unpack_data
arguments: tag: D10
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D39
datatype: string

tool: D0: %d

tool: D10: %d%d

tool: D2: False

tool: D39: True

assistant: ```c
int main(int argc, char const *argv[]) {
  int x, n;
  int nums[128];
  while (~scanf("%d%d", &x, &n)) {
    for (int i = 0; i < n; ++i)
      scanf("%d", nums + i);
    printf("%s\n", binary_search(nums, x, n) ? "True" : "False");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r14
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%rbp
  xchg   %ax,%ax
L11:
  xor    %eax,%eax
  mov    %r14,%rdx
  lea    D10(%rip),%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    0xc(%rsp),%r8d
  mov    %rbp,%r12
  xor    %r15d,%r15d
  test   %r8d,%r8d
  jle    L37
  nopl   0x0(%rax)
L3:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  add    $0x4,%r12
  cmp    %r15d,%r8d
  jg     L3
L37:
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  mov    %r8d,%edx
  xor    %eax,%eax
  call   <binary_search@plt>
  lea    D21(%rip),%rdi
  test   %eax,%eax
  lea    D25(%rip),%rax
  cmovne %rax,%rdi
  call   <puts@plt>
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D33
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string
name: parse_data
arguments: label: D21
type_guessed: string
name: parse_data
arguments: label: D25
type_guessed: string

tool: D33: %d

tool: D10: %d%d

tool: D21: False

tool: D25: True

assistant: ```c
int main(int argc, char const *argv[]) {
  int x, n;
  int nums[128];
  while (~scanf("%d%d", &x, &n)) {
    for (int i = 0; i < n; ++i)
      scanf("%d", nums + i);
    printf("%s\n", binary_search(nums, x, n) ? "True" : "False");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L26
L2:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0xa,-0x1(%rbp)
  jne    L0
L26:
  nop
  leave
  ret
```

assistant: ```c
void readLine(char cadena[], int tam) {
  char c;
  fgets(cadena, tam, stdin);
  if (cadena[strlen(cadena) - 1] == '\n')
    cadena[strlen(cadena) - 1] = '\0';
  else {
    cadena[tam - 1] = '\0';
    while ((c = getchar()) != '\n') {
    };
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<readLine>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L21
  movslq %ebp,%rbp
  movb   $0x0,-0x1(%rbx,%rbp,1)
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L3
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L11
```

assistant: ```c
void readLine(char cadena[], int tam) {
  char c;
  fgets(cadena, tam, stdin);
  if (cadena[strlen(cadena) - 1] == '\n')
    cadena[strlen(cadena) - 1] = '\0';
  else {
    cadena[tam - 1] = '\0';
    while ((c = getchar()) != '\n') {
    };
  }
}
```