ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L78
  movl   $0x1,-0x8(%rbp)
  jmp    L104
L78:
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L91
  movl   $0x1,-0x8(%rbp)
  jmp    L104
L91:
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L65
  movl   $0x1,-0x8(%rbp)
  jmp    L104
L65:
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L23
  cmpl   $0x3,-0x4(%rbp)
  je     L23
  cmpl   $0x5,-0x4(%rbp)
  jne    L28
L23:
  movl   $0x0,-0x8(%rbp)
L28:
  nop
L104:
  cmpl   $0x0,-0x8(%rbp)
  jne    L86
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L38
L86:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L38:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D1
type_infered: string

tool: D5: 1


tool: D1: 0


assistant: ```c
void is_prime(int num, int pom) {
  while (1) {
    if (num % 2 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num % 3 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num % 5 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num == 2 || num == 3 || num == 5)
      pom = 0;
    break;
  }
  if (pom == 0)
    printf("1\n");
  else
    printf("0\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_prime>:
  endbr64
  sub    $0x8,%rsp
  test   $0x1,%dil
  je     L37
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  je     L37
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%edi
  jne    L31
L37:
  lea    D16(%rip),%rdi
  call   <printf@plt>
L39:
  add    $0x8,%rsp
  ret
L31:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L39
```

tool_calls: name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D4
type: string

tool: D16: 0


tool: D4: 1


assistant: ```c
void is_prime(int num, int pom) {
  while (1) {
    if (num % 2 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num % 3 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num % 5 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num == 2 || num == 3 || num == 5)
      pom = 0;
    break;
  }
  if (pom == 0)
    printf("1\n");
  else
    printf("0\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_prime>:
  endbr64
  test   $0x1,%dil
  je     L21
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L15
L21:
  lea    D19(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  imul   $0xcccccccd,%edi,%edi
  add    $0x19999999,%edi
  cmp    $0x33333332,%edi
  jbe    L21
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D19
data_type: string
name: read_data
arguments: tag: D8
data_type: string

tool: D19: 0


tool: D8: 1


assistant: ```c
void is_prime(int num, int pom) {
  while (1) {
    if (num % 2 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num % 3 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num % 5 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num == 2 || num == 3 || num == 5)
      pom = 0;
    break;
  }
  if (pom == 0)
    printf("1\n");
  else
    printf("0\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_prime>:
  endbr64
  test   $0x1,%dil
  je     L1
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L16
L1:
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L16:
  imul   $0xcccccccd,%edi,%edi
  add    $0x19999999,%edi
  cmp    $0x33333332,%edi
  jbe    L1
  lea    D19(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string

tool: D3: 0


tool: D19: 1


assistant: ```c
void is_prime(int num, int pom) {
  while (1) {
    if (num % 2 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num % 3 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num % 5 == 0) {
      pom = 1;
      break;
    } else
      pom = 0;
    if (num == 2 || num == 3 || num == 5)
      pom = 0;
    break;
  }
  if (pom == 0)
    printf("1\n");
  else
    printf("0\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<store_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L37
L19:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7b,%al
  je     L33
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L37
L33:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L37:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D1:  

tool: D0: }

assistant: ```c
void store_string(char *tgt, char *src, char *special) {
  char *p;
  if (strcmp(src, special) == 0) {
    *tgt = '\0';
  } else if (*src != '{') {
    strcpy(tgt, src);
  } else {
    strcpy(tgt, src);
    strcat(tgt, " ");
    p = strtok(NULL, "}");
    strcat(tgt, p);
    strcat(tgt, "}");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<store_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L31
  movb   $0x0,0x0(%rbp)
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  cmpb   $0x7b,(%rbx)
  je     L21
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L20
L21:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D10(%rip),%rbx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L20
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D10
data_type: string

tool: D17:  

tool: D10: }

assistant: ```c
void store_string(char *tgt, char *src, char *special) {
  char *p;
  if (strcmp(src, special) == 0) {
    *tgt = '\0';
  } else if (*src != '{') {
    strcpy(tgt, src);
  } else {
    strcpy(tgt, src);
    strcat(tgt, " ");
    p = strtok(NULL, "}");
    strcat(tgt, p);
    strcat(tgt, "}");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L18:
  cmpb   $0x7b,0x0(%rbp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  je     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <strcpy@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  call   <strcpy@plt>
  lea    D11(%rip),%rbp
  mov    %r12,%rdi
  lea    D12(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strcat@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D12
type_guessed: string

tool: D11: }

tool: D12:  

assistant: ```c
void store_string(char *tgt, char *src, char *special) {
  char *p;
  if (strcmp(src, special) == 0) {
    *tgt = '\0';
  } else if (*src != '{') {
    strcpy(tgt, src);
  } else {
    strcpy(tgt, src);
    strcat(tgt, " ");
    p = strtok(NULL, "}");
    strcat(tgt, p);
    strcat(tgt, "}");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L5:
  cmpb   $0x7b,0x0(%rbp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  je     L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <strcpy@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  call   <strcpy@plt>
  lea    D14(%rip),%rbp
  mov    %r12,%rdi
  lea    D17(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strcat@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string

tool: D14: }

tool: D17:  

assistant: ```c
void store_string(char *tgt, char *src, char *special) {
  char *p;
  if (strcmp(src, special) == 0) {
    *tgt = '\0';
  } else if (*src != '{') {
    strcpy(tgt, src);
  } else {
    strcpy(tgt, src);
    strcat(tgt, " ");
    p = strtok(NULL, "}");
    strcat(tgt, p);
    strcat(tgt, "}");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stream_request_writecb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <EVBUFFER_OUTPUT@plt>
  mov    %eax,%edi
  call   <EVBUFFER_LENGTH@plt>
  test   %rax,%rax
  jne    L5
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bufferevent_enable@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void stream_request_writecb(struct bufferevent *bev, void *arg) {
  do {
    ;
  } while (0);
  if (EVBUFFER_LENGTH(EVBUFFER_OUTPUT(bev)) == 0) {
    bufferevent_enable(bev, EV_READ);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stream_request_writecb>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <EVBUFFER_OUTPUT@plt>
  mov    %eax,%edi
  call   <EVBUFFER_LENGTH@plt>
  test   %rax,%rax
  je     L19
L10:
  pop    %rbx
  ret
L19:
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <bufferevent_enable@plt>
  jmp    L10
```

assistant: ```c
void stream_request_writecb(struct bufferevent *bev, void *arg) {
  do {
    ;
  } while (0);
  if (EVBUFFER_LENGTH(EVBUFFER_OUTPUT(bev)) == 0) {
    bufferevent_enable(bev, EV_READ);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stream_request_writecb>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <EVBUFFER_OUTPUT@plt>
  mov    %eax,%edi
  call   <EVBUFFER_LENGTH@plt>
  test   %rax,%rax
  je     L5
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    D3(%rip),%rax
  mov    %rbp,%rdi
  pop    %rbp
  mov    (%rax),%esi
  jmp    1070 <bufferevent_enable@plt>
```

assistant: ```c
void stream_request_writecb(struct bufferevent *bev, void *arg) {
  do {
    ;
  } while (0);
  if (EVBUFFER_LENGTH(EVBUFFER_OUTPUT(bev)) == 0) {
    bufferevent_enable(bev, EV_READ);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stream_request_writecb>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <EVBUFFER_OUTPUT@plt>
  mov    %eax,%edi
  call   <EVBUFFER_LENGTH@plt>
  test   %rax,%rax
  je     L9
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    D2(%rip),%rax
  mov    %rbp,%rdi
  pop    %rbp
  mov    (%rax),%esi
  jmp    1070 <bufferevent_enable@plt>
```

assistant: ```c
void stream_request_writecb(struct bufferevent *bev, void *arg) {
  do {
    ;
  } while (0);
  if (EVBUFFER_LENGTH(EVBUFFER_OUTPUT(bev)) == 0) {
    bufferevent_enable(bev, EV_READ);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L6
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
L6:
  lea    D15(%rip),%rax
  mov    %rax,-0x8(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
datatype: string
name: extract_symbolic_data
arguments: data_label: D15
datatype: string

tool: D14: no way


tool: D15: FLAG_{chuck_norris_way}

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("no way\n");
  } else {
    char *flag = "FLAG_{chuck_norris_way}";
    printf("no way\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L9
  lea    D0(%rip),%rdi
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L9:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: no way


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("no way\n");
  } else {
    char *flag = "FLAG_{chuck_norris_way}";
    printf("no way\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: no way


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("no way\n");
  } else {
    char *flag = "FLAG_{chuck_norris_way}";
    printf("no way\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: no way


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("no way\n");
  } else {
    char *flag = "FLAG_{chuck_norris_way}";
    printf("no way\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<draw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L86
L10:
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L86:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L67
L68:
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x8(%rbp)
  jmp    L57
L23:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L57:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L23
  cmpl   $0x1,-0x18(%rbp)
  jle    L77
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L77:
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L67:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L68
  cmpl   $0x1,-0x14(%rbp)
  jle    L98
  movl   $0x0,-0x4(%rbp)
  jmp    L80
L26:
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L80:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L26
L98:
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D40
type: string
name: extract_symbolic_data
arguments: data_label: D42
type: string
name: extract_symbolic_data
arguments: data_label: D34
type: string
name: extract_symbolic_data
arguments: data_label: D58
type: string

tool: D40: *

tool: D42: 


tool: D34: .

tool: D58: 



assistant: ```c
void draw(int l, int c) {
  for (int x = 0; x < c; ++x) {
    printf("*");
  }
  printf("\n");
  for (int m = 1; m < l - 1; ++m) {
    printf("*");
    for (int n = 1; n < c - 1; ++n) {
      printf(".");
    }
    if (c > 1) {
      printf("*");
    }
    printf("\n");
  }
  if (l > 1) {
    for (int x = 0; x < c; ++x) {
      printf("*");
    }
  }
  printf("\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<draw>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,%r13d
  test   %esi,%esi
  jle    L35
  mov    $0x0,%ebx
  lea    D63(%rip),%rbp
L119:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L119
L35:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x2,%eax
  jle    L26
  sub    $0x1,%eax
  mov    %eax,0x8(%rsp)
  mov    $0x1,%r14d
  lea    D63(%rip),%r15
  lea    -0x1(%r13),%r12d
  lea    D68(%rip),%rbp
  jmp    L76
L52:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  je     L26
L76:
  mov    %r15,%rdi
  call   <printf@plt>
  cmp    $0x2,%r13d
  jle    L101
  mov    $0x1,%ebx
L75:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L75
L101:
  cmp    $0x1,%r13d
  jle    L52
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L52
L26:
  cmpl   $0x1,0xc(%rsp)
  jle    L117
  test   %r13d,%r13d
  jle    L117
  mov    $0x0,%ebx
  lea    D63(%rip),%rbp
L17:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L17
L117:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D63
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D68
type_guessed: string
name: retrieve_data
arguments: data_label: D50
type_guessed: string

tool: D63: *

tool: D7: 


tool: D68: .

tool: D50: 



assistant: ```c
void draw(int l, int c) {
  for (int x = 0; x < c; ++x) {
    printf("*");
  }
  printf("\n");
  for (int m = 1; m < l - 1; ++m) {
    printf("*");
    for (int n = 1; n < c - 1; ++n) {
      printf(".");
    }
    if (c > 1) {
      printf("*");
    }
    printf("\n");
  }
  if (l > 1) {
    for (int x = 0; x < c; ++x) {
      printf("*");
    }
  }
  printf("\n\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<draw>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  lea    D53(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  test   %esi,%esi
  jle    L82
  cs nopw 0x0(%rax,%rax,1)
L85:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r13d
  jne    L85
L82:
  lea    D62(%rip),%rdi
  lea    -0x1(%r13),%ebx
  mov    $0x1,%r14d
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    D53(%rip),%r12
  lea    D35(%rip),%rbp
  sub    $0x1,%eax
  mov    %eax,0x8(%rsp)
  cmp    $0x1,%eax
  jle    L22
  nopl   0x0(%rax)
L62:
  mov    %r12,%rdi
  mov    $0x1,%r15d
  call   <printf@plt>
  cmp    $0x1,%ebx
  jle    L20
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %rbp,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,%ebx
  jne    L54
L20:
  cmp    $0x1,%r13d
  jle    L52
  mov    %r12,%rdi
  call   <printf@plt>
L52:
  lea    D62(%rip),%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    0x8(%rsp),%r14d
  jne    L62
L22:
  cmpl   $0x1,0xc(%rsp)
  jle    L21
  test   %r13d,%r13d
  jle    L21
  xor    %ebx,%ebx
  lea    D53(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r13d
  jne    L39
L21:
  add    $0x18,%rsp
  lea    D40(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D53
datatype: string
name: read_data
arguments: label: D62
datatype: string
name: read_data
arguments: label: D35
datatype: string
name: read_data
arguments: label: D40
datatype: string

tool: D53: *

tool: D62: 


tool: D35: .

tool: D40: 



assistant: ```c
void draw(int l, int c) {
  for (int x = 0; x < c; ++x) {
    printf("*");
  }
  printf("\n");
  for (int m = 1; m < l - 1; ++m) {
    printf("*");
    for (int n = 1; n < c - 1; ++n) {
      printf(".");
    }
    if (c > 1) {
      printf("*");
    }
    printf("\n");
  }
  if (l > 1) {
    for (int x = 0; x < c; ++x) {
      printf("*");
    }
  }
  printf("\n\n");
}
```