user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    $0x8,%esi
  mov    0xc(%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    $0x8,%esi
  mov    0xc(%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    $0x8,%esi
  mov    0xc(%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    $0x8,%esi
  mov    0xc(%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%r12
  cmpl   $0x0,0x4(%rsp)
  jle    L65
  mov    $0x0,%r14d
  lea    D9(%rip),%r15
L78:
  lea    0x10(%rsp),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  addq   $0x1,-0x8(%rbx,%rax,8)
  add    $0x1,%r14d
  cmp    %r14d,0x4(%rsp)
  jg     L78
L65:
  cmpl   $0x0,0x8(%rsp)
  jle    L82
  mov    $0x0,%r14d
  lea    D9(%rip),%r15
L31:
  lea    0x10(%rsp),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  addq   $0x1,-0x8(%r12,%rax,8)
  mov    0x10(%rsp),%rax
  shl    $0x3,%rax
  mov    -0x8(%r12,%rax,1),%rdx
  imul   -0x8(%rbx,%rax,1),%rdx
  mov    %rdx,-0x8(%rbp,%rax,1)
  mov    0x10(%rsp),%rax
  mov    %rdx,-0x8(%r13,%rax,8)
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  jg     L31
L82:
  mov    $0x0,%r12d
  sub    %r13,%rbp
  movabs $0x89705f3112a28fe5,%rbx
  lea    D8(%rip),%r14
  cmpl   $0x0,0xc(%rsp)
  jg     L45
L46:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  mov    %r13,%rdi
  mov    $0x0,%r9d
  mov    $0x0,%esi
  mov    $0x0,%r8d
L76:
  mov    (%rdi),%r10
  mov    0x0(%rbp,%rdi,1),%rcx
  mov    %rcx,%rax
  imul   %rbx
  add    %rcx,%rdx
  sar    $0x1d,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rcx
  mov    %rsi,%rax
  imul   %rbx
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  mov    %rsi,%rax
  sub    %rdx,%rax
  imul   %rax,%rcx
  mov    %rcx,%rax
  imul   %rbx
  add    %rcx,%rdx
  sar    $0x1d,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,(%rdi)
  add    %rcx,%r9
  add    %r10,%rsi
  add    $0x1,%r8d
  add    $0x8,%rdi
  cmp    %r8d,0xc(%rsp)
  jg     L76
L49:
  mov    %r9,%rax
  imul   %rbx
  lea    (%rdx,%r9,1),%rax
  sar    $0x1d,%rax
  mov    %r9,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rax
  mov    %r9,%rsi
  sub    %rax,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jle    L46
L45:
  mov    $0x0,%r9d
  cmpl   $0x0,0xc(%rsp)
  jg     L52
  jmp    L49
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type_infered: string
name: extract_symbolic_data
arguments: data_label: D9
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D30: %d %d %d

tool: D9: %lld

tool: D8: %lld 

assistant: ```c
int main(void) {
  int n, m, c;
  scanf("%d %d %d", &n, &m, &c);
  long long int *spheres = (long long int *)calloc(c, 8);
  long long int *dup = (long long int *)calloc(c, 8);
  long long int *u = (long long int *)calloc(c, 8);
  long long int *l = (long long int *)calloc(c, 8);
  int i, j;
  long long int x;
  for (i = 0; i < n; i++) {
    scanf("%lld", &x);
    u[x - 1]++;
  }
  for (i = 0; i < m; i++) {
    scanf("%lld", &x);
    l[x - 1]++;
    dup[x - 1] = spheres[x - 1] = l[x - 1] * u[x - 1];
  }
  long long int sum;
  long long int aux;
  for (j = 0; j < c; j++) {
    sum = 0;
    aux = 0;
    for (i = 0; i < c; i++) {
      long long int y = dup[i];
      dup[i] = ((spheres[i] % 1000000007) * (sum % 1000000007)) % 1000000007;
      aux += (dup[i] % 1000000007);
      sum += y;
    }
    printf("%lld ", (aux % 1000000007));
  }
  return 0;
}
```