user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x44(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x44(%rbp)
  test   %eax,%eax
  je     L57
  lea    -0x3c(%rbp),%rax
  mov    $0x1,%r12d
  mov    %rax,-0x68(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  xchg   %ax,%ax
L121:
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rsi
  xor    %eax,%eax
  mov    %rsp,-0x58(%rbp)
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L97
L35:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L35
L97:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  je     L98
  orq    $0x0,-0x8(%rsp,%rcx,1)
L98:
  mov    %rsp,%r13
  test   %edx,%edx
  jle    L10
  mov    %r13,%r14
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <scanf@plt>
  mov    -0x3c(%rbp),%edx
  add    $0x4,%r14
  cmp    %r15d,%edx
  jg     L48
L10:
  sub    $0x1,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <quicksort@plt>
  mov    -0x40(%rbp),%ecx
  movslq -0x3c(%rbp),%rax
  test   %ecx,%ecx
  jle    L56
  lea    0x0(%r13,%rax,4),%rdx
  xor    %r13d,%r13d
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L90:
  add    -0x4(%rdx),%eax
  add    $0x1,%r13d
  sub    $0x4,%rdx
  cmp    %ecx,%eax
  jl     L90
L75:
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  cmp    %r13d,-0x3c(%rbp)
  jge    L37
  lea    D18(%rip),%rdi
  call   <puts@plt>
L22:
  mov    -0x44(%rbp),%eax
  mov    -0x58(%rbp),%rsp
  add    $0x1,%r12d
  lea    -0x1(%rax),%edx
  mov    %edx,-0x44(%rbp)
  test   %eax,%eax
  jne    L121
L57:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L116
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %r13d,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L56:
  xor    %r13d,%r13d
  jmp    L75
L116:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string
name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D39
data_type: string
name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D16
data_type: string

tool: D2: %d

tool: D9: %d %d

tool: D39: Scenario #%d:


tool: D18: impossible


tool: D16: %d



assistant: ```c
int main() {
  int t, s, f, i, x, j = 1, k;
  scanf("%d", &t);
  while (t--) {
    k = 0;
    x = 0;
    scanf("%d %d", &s, &f);
    int sf[f];
    for (i = 0; i < f; i++)
      scanf("%d", &sf[i]);
    quicksort(sf, 0, f - 1);
    for (i = f - 1; x < s; i--) {
      x += sf[i];
      k++;
    }
    printf("Scenario #%d:\n", j);
    if (k > f)
      printf("impossible\n\n");
    else
      printf("%d\n\n", k);
    j++;
  }
  return 0;
}
```