user: 这段汇编代码用C语言表示是什么样的？

```asm
<XTL_FindClosingSquareBrace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <TracePrintf@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L101
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L101
  cmpq   $0x0,-0x20(%rbp)
  je     L101
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jg     L109
L101:
  mov    $0x0,%eax
  jmp    L65
L109:
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <DoTrace@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <XTL_FindComment@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L7
L66:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5d,%eax
  je     L208
  cmp    $0x5d,%eax
  jg     L46
  cmp    $0x5c,%eax
  je     L74
  cmp    $0x5c,%eax
  jg     L46
  cmp    $0x25,%eax
  je     L203
  cmp    $0x5b,%eax
  je     L78
  jmp    L46
L74:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L166
  subq   $0x1,-0x10(%rbp)
  jmp    L166
L78:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L46
L208:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L222
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <DoTrace@plt>
  mov    -0x10(%rbp),%rax
  jmp    L65
L203:
  cmpq   $0x0,-0x8(%rbp)
  je     L198
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L198
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <DoTrace@plt>
  mov    $0x0,%eax
  jmp    L65
L166:
  nop
  jmp    L46
L222:
  nop
  jmp    L46
L198:
  nop
L46:
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L66
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <DoTrace@plt>
  mov    $0x0,%eax
L65:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D41
type_guessed: string
name: read_data
arguments: tag: D49
type_guessed: string
name: read_data
arguments: tag: D35
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string

tool: D16: start - XTL_FindClosingSquareBrace, %p, %p


tool: D41: in - XTL_FindClosingSquareBrace

tool: D49: out1 - XTL_FindClosingSquareBrace

tool: D35: out2 - XTL_FindClosingSquareBrace

tool: D1: out - XTL_FindClosingSquareBrace

assistant: ```c
char *XTL_FindClosingSquareBrace(char *line, int *Braces) {
  char *p;
  char *comment;
  TracePrintf("start - XTL_FindClosingSquareBrace, %p, %p\n", (void *)line, (void *)Braces);
  if (line == NULL || *line == 0 || Braces == NULL || *Braces < 1)
    return NULL;
  DoTrace("in - XTL_FindClosingSquareBrace");
  comment = XTL_FindComment(line);
  for (p = line; *p != 0; p++) {
    switch (*p) {
    case '\\':
      ++p;
      if (*p == 0)
        --p;
      break;
    case '[':
      ++(*Braces);
      break;
    case ']':
      --(*Braces);
      if (*Braces == 0) {
        DoTrace("out1 - XTL_FindClosingSquareBrace");
        return p;
      }
      break;
    case '%':
      if (comment != NULL && p == comment) {
        DoTrace("out2 - XTL_FindClosingSquareBrace");
        return NULL;
      }
      break;
    }
  }
  DoTrace("out - XTL_FindClosingSquareBrace");
  return NULL;
}
```