ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<StrLower>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  mov    %rsi,%rcx
  test   %dl,%dl
  je     L23
  nopl   0x0(%rax)
L19:
  lea    -0x41(%rdx),%r8d
  add    $0x1,%rdi
  add    $0x1,%rcx
  cmp    $0x19,%r8b
  ja     L1
  add    $0x20,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
L23:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %dl,-0x1(%rcx)
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *StrLower(const char *in, char *out) {
  char *scan = out;
  while (*in != '\0')
    if ((*in >= 'A') && (*in <= 'Z'))
      *scan++ = *in++ + 'a' - 'A';
    else
      *scan++ = *in++;
  *scan = '\0';
  return out;
}
```
user: What is the c source code of the assembly code below?

```asm
<vec_mult_ref>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <init@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    %ecx,%eax
  imul   %edx,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L12
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <init_again@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    %ecx,%eax
  imul   %edx,%eax
  lea    (%rsi,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void vec_mult_ref(char *p, char *v1, char *v2, int N) {
  int i;
  init(v1, v2, N);
  for (i = 0; i < N; i++)
    p[i] = v1[i] * v2[i];
  init_again(v1, v2, N);
  for (i = 0; i < N; i++)
    p[i] = p[i] + (v1[i] * v2[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec_mult_ref>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %ecx,%r14d
  mov    %ecx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <init@plt>
  test   %r14d,%r14d
  jle    L6
  mov    %r14d,%r13d
  mov    $0x0,%edx
L0:
  movzbl 0x0(%rbp,%rdx,1),%eax
  mulb   (%r12,%rdx,1)
  mov    %al,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %r13,%rdx
  jne    L0
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <init_again@plt>
  mov    $0x0,%edx
L1:
  movzbl 0x0(%rbp,%rdx,1),%eax
  mulb   (%r12,%rdx,1)
  add    %al,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %r13,%rdx
  jne    L1
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <init_again@plt>
  jmp    L21
```

assistant: ```c
void vec_mult_ref(char *p, char *v1, char *v2, int N) {
  int i;
  init(v1, v2, N);
  for (i = 0; i < N; i++)
    p[i] = v1[i] * v2[i];
  init_again(v1, v2, N);
  for (i = 0; i < N; i++)
    p[i] = p[i] + (v1[i] * v2[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec_mult_ref>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  mov    %rdx,%r12
  mov    %ecx,%edx
  push   %rbp
  mov    %rsi,%rbp
  mov    %r12,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  call   <init@plt>
  test   %r14d,%r14d
  jle    L5
  movslq %r14d,%r13
  xor    %r8d,%r8d
L21:
  movzbl 0x0(%rbp,%r8,1),%eax
  mulb   (%r12,%r8,1)
  mov    %al,(%rbx,%r8,1)
  add    $0x1,%r8
  cmp    %r8,%r13
  jne    L21
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <init_again@plt>
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl 0x0(%rbp,%rdx,1),%eax
  mulb   (%r12,%rdx,1)
  add    %al,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%r13
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L5:
  pop    %rbx
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <init_again@plt>
```

assistant: ```c
void vec_mult_ref(char *p, char *v1, char *v2, int N) {
  int i;
  init(v1, v2, N);
  for (i = 0; i < N; i++)
    p[i] = v1[i] * v2[i];
  init_again(v1, v2, N);
  for (i = 0; i < N; i++)
    p[i] = p[i] + (v1[i] * v2[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x88(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L25
  mov    -0x88(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L68
  mov    -0x88(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L25
L68:
  addq   $0x2,-0x88(%rbp)
L25:
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x78(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L7
L69:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L30
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    -0x7c(%rbp),%eax
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  jmp    L63
L30:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  lea    -0x57(%rax),%edx
  mov    -0x7c(%rbp),%eax
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
L63:
  addl   $0x1,-0x7c(%rbp)
L7:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L69
  movl   $0x0,-0x7c(%rbp)
  jmp    L3
L65:
  mov    -0x7c(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%ebx
  mov    -0x74(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x7c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x10,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,-0x78(%rbp)
  addl   $0x1,-0x7c(%rbp)
L3:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L65
  mov    -0x78(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    s += 2;
  int hex[20], len = strlen(s), result = 0;
  for (i = 0; i < len; ++i) {
    if (isdigit(s[i]))
      hex[i] = s[i] - 48;
    else
      hex[i] = tolower(s[i]) - 87;
  }
  for (i = 0; i < len; ++i)
    result += hex[i] * pow(16, (len - 1) - i);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<htoi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  cmpb   $0x30,(%rdi)
  je     L37
L99:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L2
  mov    %eax,%r13d
  mov    $0x0,%ebx
  jmp    L16
L37:
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  lea    0x2(%rdi),%rdx
  cmp    $0x58,%al
  cmove  %rdx,%rbp
  jmp    L99
L39:
  movsbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x30,%eax
L60:
  mov    %eax,(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L73
L16:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  sub    $0x57,%eax
  jmp    L60
L73:
  lea    0x1(%r12),%r14d
  mov    $0x1,%ebx
  mov    $0x0,%r13d
L9:
  mov    -0x4(%rsp,%rbx,4),%ebp
  mov    %r12d,%esi
  sub    %ebx,%esi
  mov    $0x10,%edi
  call   <pow@plt>
  imul   %eax,%ebp
  add    %ebp,%r13d
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L9
L69:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %r13d,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  mov    $0x0,%r13d
  jmp    L69
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int htoi(char s[]) {
  int i;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    s += 2;
  int hex[20], len = strlen(s), result = 0;
  for (i = 0; i < len; ++i) {
    if (isdigit(s[i]))
      hex[i] = s[i] - 48;
    else
      hex[i] = tolower(s[i]) - 87;
  }
  for (i = 0; i < len; ++i)
    result += hex[i] * pow(16, (len - 1) - i);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<htoi>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  cmpb   $0x30,(%rdi)
  jne    L6
  movzbl 0x1(%rdi),%eax
  lea    0x2(%rdi),%rdx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  cmove  %rdx,%r13
L6:
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L84
  lea    -0x1(%rax),%r12d
  mov    %eax,%r14d
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L69:
  movsbl 0x0(%r13,%rbx,1),%eax
  sub    $0x30,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L27
L74:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L69
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <tolower@plt>
  sub    $0x57,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L74
L27:
  mov    %rbp,%rbx
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L32:
  mov    (%rbx),%ebp
  mov    %r12d,%esi
  mov    $0x10,%edi
  add    $0x4,%rbx
  call   <pow@plt>
  imul   %eax,%ebp
  add    %ebp,%r13d
  sub    $0x1,%r12d
  jae    L32
L64:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0x60,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L84:
  xor    %r13d,%r13d
  jmp    L64
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int htoi(char s[]) {
  int i;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    s += 2;
  int hex[20], len = strlen(s), result = 0;
  for (i = 0; i < len; ++i) {
    if (isdigit(s[i]))
      hex[i] = s[i] - 48;
    else
      hex[i] = tolower(s[i]) - 87;
  }
  for (i = 0; i < len; ++i)
    result += hex[i] * pow(16, (len - 1) - i);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<htoi>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  cmpb   $0x30,(%rdi)
  jne    L41
  movzbl 0x1(%rdi),%eax
  lea    0x2(%rdi),%rdx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  cmove  %rdx,%r13
L41:
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L73
  lea    -0x1(%rax),%r12d
  mov    %eax,%r14d
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  nopl   (%rax)
L82:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L83
  movsbl 0x0(%r13,%rbx,1),%eax
  sub    $0x30,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L82
L21:
  mov    %rbp,%rbx
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L39:
  mov    (%rbx),%ebp
  mov    %r12d,%esi
  mov    $0x10,%edi
  add    $0x4,%rbx
  call   <pow@plt>
  imul   %eax,%ebp
  add    %ebp,%r13d
  sub    $0x1,%r12d
  jae    L39
L34:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x60,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L83:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <tolower@plt>
  sub    $0x57,%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L82
  jmp    L21
  nopl   0x0(%rax)
L73:
  xor    %r13d,%r13d
  jmp    L34
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int htoi(char s[]) {
  int i;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    s += 2;
  int hex[20], len = strlen(s), result = 0;
  for (i = 0; i < len; ++i) {
    if (isdigit(s[i]))
      hex[i] = s[i] - 48;
    else
      hex[i] = tolower(s[i]) - 87;
  }
  for (i = 0; i < len; ++i)
    result += hex[i] * pow(16, (len - 1) - i);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L19
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L19:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L4
L28:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int isPrime(int x, int knownPrimes[], int numberOfKnownPrimes) {
  int ret = 1;
  int i;
  for (i = 0; i < numberOfKnownPrimes; i++) {
    if (x % knownPrimes[i] == 0) {
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPrime>:
  endbr64
  test   %edx,%edx
  jle    L20
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%eax
  lea    0x4(%rsi,%rax,4),%rsi
L3:
  mov    %edi,%eax
  cltd
  idivl  (%rcx)
  mov    %edx,%eax
  test   %edx,%edx
  je     L9
  add    $0x4,%rcx
  cmp    %rsi,%rcx
  jne    L3
  mov    $0x1,%eax
  ret
L20:
  mov    $0x1,%eax
L9:
  ret
```

assistant: ```c
int isPrime(int x, int knownPrimes[], int numberOfKnownPrimes) {
  int ret = 1;
  int i;
  for (i = 0; i < numberOfKnownPrimes; i++) {
    if (x % knownPrimes[i] == 0) {
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<isPrime>:
  endbr64
  test   %edx,%edx
  jle    L28
  lea    -0x1(%rdx),%eax
  lea    0x4(%rsi,%rax,4),%rcx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x4,%rsi
  cmp    %rcx,%rsi
  je     L28
L27:
  mov    %edi,%eax
  cltd
  idivl  (%rsi)
  test   %edx,%edx
  jne    L8
  mov    %edx,%eax
  ret
  nopl   (%rax)
L28:
  mov    $0x1,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int isPrime(int x, int knownPrimes[], int numberOfKnownPrimes) {
  int ret = 1;
  int i;
  for (i = 0; i < numberOfKnownPrimes; i++) {
    if (x % knownPrimes[i] == 0) {
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPrime>:
  endbr64
  test   %edx,%edx
  jle    L15
  lea    -0x1(%rdx),%eax
  lea    0x4(%rsi,%rax,4),%rcx
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x4,%rsi
  cmp    %rcx,%rsi
  je     L15
L34:
  mov    %edi,%eax
  cltd
  idivl  (%rsi)
  test   %edx,%edx
  jne    L24
  mov    %edx,%eax
  ret
  nopl   (%rax)
L15:
  mov    $0x1,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int isPrime(int x, int knownPrimes[], int numberOfKnownPrimes) {
  int ret = 1;
  int i;
  for (i = 0; i < numberOfKnownPrimes; i++) {
    if (x % knownPrimes[i] == 0) {
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_from_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x24(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L18
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L1
L18:
  mov    -0x4(%rbp),%eax
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: recv

assistant: ```c
int read_from_socket(int sockfd, char *buf, unsigned int total, unsigned int remaining) {
  int data_read = 0;
  if ((data_read = recv(sockfd, &buf[total - remaining], remaining, 0)) < 0) {
    perror("recv");
    return -1;
  }
  return data_read;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_from_socket>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%eax
  mov    %ecx,%edx
  sub    %ecx,%eax
  add    %rax,%rsi
  mov    $0x0,%ecx
  call   <recv@plt>
  test   %eax,%eax
  js     L10
L0:
  add    $0x8,%rsp
  ret
L10:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L0
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string

tool: D0: recv

assistant: ```c
int read_from_socket(int sockfd, char *buf, unsigned int total, unsigned int remaining) {
  int data_read = 0;
  if ((data_read = recv(sockfd, &buf[total - remaining], remaining, 0)) < 0) {
    perror("recv");
    return -1;
  }
  return data_read;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_from_socket>:
  endbr64
  mov    %edx,%r8d
  sub    $0x8,%rsp
  mov    %ecx,%edx
  sub    %ecx,%r8d
  xor    %ecx,%ecx
  add    %r8,%rsi
  call   <recv@plt>
  test   %eax,%eax
  js     L0
L4:
  add    $0x8,%rsp
  ret
L0:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string

tool: D2: recv

assistant: ```c
int read_from_socket(int sockfd, char *buf, unsigned int total, unsigned int remaining) {
  int data_read = 0;
  if ((data_read = recv(sockfd, &buf[total - remaining], remaining, 0)) < 0) {
    perror("recv");
    return -1;
  }
  return data_read;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_from_socket>:
  endbr64
  mov    %edx,%r8d
  sub    $0x8,%rsp
  mov    %ecx,%edx
  sub    %ecx,%r8d
  xor    %ecx,%ecx
  add    %r8,%rsi
  call   <recv@plt>
  test   %eax,%eax
  js     L16
L6:
  add    $0x8,%rsp
  ret
L16:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L6
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string

tool: D5: recv

assistant: ```c
int read_from_socket(int sockfd, char *buf, unsigned int total, unsigned int remaining) {
  int data_read = 0;
  if ((data_read = recv(sockfd, &buf[total - remaining], remaining, 0)) < 0) {
    perror("recv");
    return -1;
  }
  return data_read;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L55:
  cmp    %rdx,%rsp
  je     L20
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L55
L20:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L46
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L46:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x40(%rbp)
  movq   $0x0,-0x50(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L48
L54:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  add    %rax,-0x50(%rbp)
  addl   $0x1,-0x54(%rbp)
L48:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L54
  mov    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D24
type: string
name: disassemble_data
arguments: data_label: D27
type: string

tool: D0: %d

tool: D24: %ld

tool: D27: %ld


assistant: ```c
int main() {
  int a, i;
  scanf("%d", &a);
  long int arr[a], c = 0;
  for (i = 0; i < a; i++) {
    scanf("%ld", &arr[i]);
    c = c + arr[i];
  }
  printf("%ld\n", c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L37:
  cmp    %rcx,%rsp
  je     L23
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L37
L23:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L18
  orq    $0x0,-0x8(%rsp,%rax,1)
L18:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L34
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  lea    D12(%rip),%r14
L62:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    (%rbx),%r13
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,-0x2c(%rbp)
  jg     L62
L10:
  mov    %r13,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L34:
  mov    $0x0,%r13d
  jmp    L10
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D12
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string

tool: D11: %d

tool: D12: %ld

tool: D29: %ld


assistant: ```c
int main() {
  int a, i;
  scanf("%d", &a);
  long int arr[a], c = 0;
  for (i = 0; i < a; i++) {
    scanf("%ld", &arr[i]);
    c = c + arr[i];
  }
  printf("%ld\n", c);
  return 0;
}
```