ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pv_uuid_print>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rdi),%r9
  mov    %rdi,%rax
  mov    $0x0,%edx
  mov    %rsp,%r8
  sub    %rdi,%r8
L18:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%edx
  add    $0x1,%rax
  cmp    $0x1f,%edx
  jg     L33
  cmp    %rax,%r9
  jg     L18
L33:
  mov    %rsp,%rdi
  call   <lvm_uuid_format@plt>
  mov    %rax,%rbp
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
  add    $0x26,%rbp
L13:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: 	-- PV UUID: 

assistant: ```c
int pv_uuid_print(long int pv_uuid_loc, char *buffer) {
  long int pv_uuid_end;
  char uuid[32], *f_uuid;
  int y = 0, x = 0;
  pv_uuid_end = pv_uuid_loc + 32;
  while (y < 32 && pv_uuid_loc < pv_uuid_end) {
    uuid[y] = buffer[pv_uuid_loc];
    y++;
    pv_uuid_loc++;
  }
  f_uuid = lvm_uuid_format(uuid);
  printf("\t-- PV UUID: ");
  for (x = 0; x < 38; x++)
    printf("%c", f_uuid[x]);
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pv_uuid_print>:
  endbr64
  push   %rbp
  lea    0x20(%rdi),%r8
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  mov    %r9,%rcx
  sub    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl (%rsi,%rdi,1),%edx
  add    $0x1,%eax
  mov    %dl,(%rcx,%rdi,1)
  add    $0x1,%rdi
  cmp    $0x1f,%eax
  jg     L9
  cmp    %rdi,%r8
  jg     L38
L9:
  mov    %r9,%rdi
  call   <lvm_uuid_format@plt>
  lea    D8(%rip),%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x26(%rbx),%rbp
  nopl   (%rax)
L22:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D8: 	-- PV UUID: 

assistant: ```c
int pv_uuid_print(long int pv_uuid_loc, char *buffer) {
  long int pv_uuid_end;
  char uuid[32], *f_uuid;
  int y = 0, x = 0;
  pv_uuid_end = pv_uuid_loc + 32;
  while (y < 32 && pv_uuid_loc < pv_uuid_end) {
    uuid[y] = buffer[pv_uuid_loc];
    y++;
    pv_uuid_loc++;
  }
  f_uuid = lvm_uuid_format(uuid);
  printf("\t-- PV UUID: ");
  for (x = 0; x < 38; x++)
    printf("%c", f_uuid[x]);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pv_uuid_print>:
  endbr64
  push   %rbp
  lea    0x20(%rdi),%r8
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  mov    %r9,%rcx
  sub    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rsi,%rdi,1),%edx
  add    $0x1,%eax
  mov    %dl,(%rcx,%rdi,1)
  add    $0x1,%rdi
  cmp    $0x1f,%eax
  jg     L17
  cmp    %rdi,%r8
  jg     L0
L17:
  mov    %r9,%rdi
  call   <lvm_uuid_format@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x26(%rbx),%rbp
  nopl   (%rax)
L7:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: 	-- PV UUID: 

assistant: ```c
int pv_uuid_print(long int pv_uuid_loc, char *buffer) {
  long int pv_uuid_end;
  char uuid[32], *f_uuid;
  int y = 0, x = 0;
  pv_uuid_end = pv_uuid_loc + 32;
  while (y < 32 && pv_uuid_loc < pv_uuid_end) {
    uuid[y] = buffer[pv_uuid_loc];
    y++;
    pv_uuid_loc++;
  }
  f_uuid = lvm_uuid_format(uuid);
  printf("\t-- PV UUID: ");
  for (x = 0; x < 38; x++)
    printf("%c", f_uuid[x]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parseBody>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L24
  mov    $0x0,%eax
  jmp    L32
L24:
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L11
L14:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <getChar@plt>
  mov    %al,(%rbx)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L14
  mov    -0x18(%rbp),%rax
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *parseBody(int fd, int contentLength) {
  if (contentLength == 0)
    return 0;
  if (0)
    printf("Parse body starting...\n");
  char *body = (char *)malloc(contentLength + 1);
  memset(body, 0, contentLength + 1);
  int i = 0;
  while (i < contentLength)
    body[i++] = getChar(fd);
  if (0)
    printf("HTTP body=[%s]\n", body);
  return body;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parseBody>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r13d
  test   %esi,%esi
  je     L10
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x1(%rsi),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%r13
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L10
  mov    %r14,%rbx
  mov    %ebp,%ebp
  add    %r14,%rbp
L29:
  mov    %r12d,%edi
  call   <getChar@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L29
L10:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *parseBody(int fd, int contentLength) {
  if (contentLength == 0)
    return 0;
  if (0)
    printf("Parse body starting...\n");
  char *body = (char *)malloc(contentLength + 1);
  memset(body, 0, contentLength + 1);
  int i = 0;
  while (i < contentLength)
    body[i++] = getChar(fd);
  if (0)
    printf("HTTP body=[%s]\n", body);
  return body;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parseBody>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  test   %ebp,%ebp
  je     L4
  lea    0x1(%rbp),%r14d
  mov    %edi,%r12d
  mov    %r14d,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r14d,%edx
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L4
  mov    %r13,%rbx
  add    %r13,%rbp
  nop
L13:
  mov    %r12d,%edi
  add    $0x1,%rbx
  call   <getChar@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L13
L4:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *parseBody(int fd, int contentLength) {
  if (contentLength == 0)
    return 0;
  if (0)
    printf("Parse body starting...\n");
  char *body = (char *)malloc(contentLength + 1);
  memset(body, 0, contentLength + 1);
  int i = 0;
  while (i < contentLength)
    body[i++] = getChar(fd);
  if (0)
    printf("HTTP body=[%s]\n", body);
  return body;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<parseBody>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  test   %ebp,%ebp
  je     L24
  lea    0x1(%rbp),%r14d
  mov    %edi,%r12d
  mov    %r14d,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r14d,%edx
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L24
  mov    %r13,%rbx
  add    %r13,%rbp
  nop
L21:
  mov    %r12d,%edi
  add    $0x1,%rbx
  call   <getChar@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L21
L24:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *parseBody(int fd, int contentLength) {
  if (contentLength == 0)
    return 0;
  if (0)
    printf("Parse body starting...\n");
  char *body = (char *)malloc(contentLength + 1);
  memset(body, 0, contentLength + 1);
  int i = 0;
  while (i < contentLength)
    body[i++] = getChar(fd);
  if (0)
    printf("HTTP body=[%s]\n", body);
  return body;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fibo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L37
  mov    $0x0,%eax
  jmp    L14
L37:
  cmpl   $0x2,-0x14(%rbp)
  jne    L33
  mov    $0x1,%eax
  jmp    L14
L33:
  cmpl   $0x2,-0x14(%rbp)
  jle    L14
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibo>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibo>
  add    %ebx,%eax
  jmp    L14
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibo(int n) {
  if (n == 1)
    return 0;
  if (n == 2)
    return 1;
  if (n > 2)
    return fibo(n - 1) + fibo(n - 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fibo>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L7
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L20
  jg     L19
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  lea    -0x1(%rdi),%edi
  call   <fibo>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fibo>
  add    %ebp,%eax
  jmp    L20
L7:
  ret
```

assistant: ```c
int fibo(int n) {
  if (n == 1)
    return 0;
  if (n == 2)
    return 1;
  if (n > 2)
    return fibo(n - 1) + fibo(n - 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<glmTanD3f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <glmRadians3f@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <glmTan3f@plt>
  nop
  leave
  ret
```

assistant: ```c
void glmTanD3f(float out[3], const float angle[3]) {
  glmRadians3f(out, angle);
  glmTan3f(out, out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<glmTanD3f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <glmRadians3f@plt>
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <glmTan3f@plt>
  pop    %rbx
  ret
```

assistant: ```c
void glmTanD3f(float out[3], const float angle[3]) {
  glmRadians3f(out, angle);
  glmTan3f(out, out);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<glmTanD3f>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <glmRadians3f@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <glmTan3f@plt>
```

assistant: ```c
void glmTanD3f(float out[3], const float angle[3]) {
  glmRadians3f(out, angle);
  glmTan3f(out, out);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<glmTanD3f>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <glmRadians3f@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <glmTan3f@plt>
```

assistant: ```c
void glmTanD3f(float out[3], const float angle[3]) {
  glmRadians3f(out, angle);
  glmTan3f(out, out);
}
```
user: What is the c source code of the assembly code below?

```asm
<PT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  movsd  %xmm0,-0x48(%rbp)
  movsd  %xmm1,-0x50(%rbp)
  movsd  %xmm2,-0x58(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x48(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L13
L9:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm4
  movsd  %xmm4,-0x60(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movsd  D1(%rip),%xmm0
  movq   %rax,%xmm2
  divsd  %xmm0,%xmm2
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm3
  addsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x60(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L9
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: f64

tool: D1: 2

assistant: ```c
void PT(double *u_init, double *x, double *u_future, int n_points, double c, double L, double dt) {
  int i;
  double dx = x[1] - x[0];
  double r = c * dt / dx;
  for (i = 1; i < n_points - 1; i++) {
    u_future[i] = u_init[i] + pow(r, 2) / 2.0 * (u_init[i + 1] - 2 * u_init[i] - u_init[i - 1]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PT>:
  endbr64
  mulsd  %xmm2,%xmm0
  movsd  0x8(%rsi),%xmm1
  subsd  (%rsi),%xmm1
  divsd  %xmm1,%xmm0
  cmp    $0x2,%ecx
  jle    L14
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%r14
  mov    %rdi,%rbx
  lea    0x8(%rdx),%rbp
  lea    -0x3(%rcx),%eax
  lea    0x8(%rdi,%rax,8),%r12
L10:
  mov    0x8(%rbx),%r13
  mov    $0x2,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movsd  0x8(%rbx),%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movsd  0x10(%rbx),%xmm1
  subsd  %xmm2,%xmm1
  subsd  (%rbx),%xmm1
  mulsd  D3(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %r13,%xmm3
  addsd  %xmm3,%xmm1
  movsd  %xmm1,0x0(%rbp)
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %r12,%rbx
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: f32[2]

tool: {"D3": [0.0,1.75]}

assistant: ```c
void PT(double *u_init, double *x, double *u_future, int n_points, double c, double L, double dt) {
  int i;
  double dx = x[1] - x[0];
  double r = c * dt / dx;
  for (i = 1; i < n_points - 1; i++) {
    u_future[i] = u_init[i] + pow(r, 2) / 2.0 * (u_init[i + 1] - 2 * u_init[i] - u_init[i - 1]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<PT>:
  endbr64
  mulsd  %xmm2,%xmm0
  movsd  0x8(%rsi),%xmm1
  subsd  (%rsi),%xmm1
  divsd  %xmm1,%xmm0
  cmp    $0x2,%ecx
  jle    L15
  push   %r14
  lea    -0x3(%rcx),%eax
  movq   %xmm0,%r14
  push   %r12
  lea    0x8(%rdx),%r12
  push   %rbp
  lea    0x8(%rdi,%rax,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L11:
  movsd  0x8(%rbx),%xmm3
  mov    $0x2,%edi
  add    $0x8,%rbx
  add    $0x8,%r12
  movq   %r14,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <pow@plt>
  movsd  (%rbx),%xmm1
  mulsd  D2(%rip),%xmm0
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movsd  0x8(%rbx),%xmm1
  subsd  %xmm2,%xmm1
  subsd  -0x8(%rbx),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  0x8(%rsp),%xmm1
  movsd  %xmm1,-0x8(%r12)
  cmp    %rbp,%rbx
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopl   (%rax)
L15:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: f32[2]

tool: {"D2": [0.0,1.75]}

assistant: ```c
void PT(double *u_init, double *x, double *u_future, int n_points, double c, double L, double dt) {
  int i;
  double dx = x[1] - x[0];
  double r = c * dt / dx;
  for (i = 1; i < n_points - 1; i++) {
    u_future[i] = u_init[i] + pow(r, 2) / 2.0 * (u_init[i + 1] - 2 * u_init[i] - u_init[i - 1]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PT>:
  endbr64
  mulsd  %xmm2,%xmm0
  movsd  0x8(%rsi),%xmm1
  subsd  (%rsi),%xmm1
  divsd  %xmm1,%xmm0
  cmp    $0x2,%ecx
  jle    L14
  push   %r14
  lea    -0x3(%rcx),%eax
  movq   %xmm0,%r14
  push   %r12
  lea    0x8(%rdx),%r12
  push   %rbp
  lea    0x8(%rdi,%rax,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L11:
  movsd  0x8(%rbx),%xmm3
  mov    $0x2,%edi
  add    $0x8,%rbx
  add    $0x8,%r12
  movq   %r14,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <pow@plt>
  movsd  (%rbx),%xmm1
  mulsd  D9(%rip),%xmm0
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  movsd  0x8(%rbx),%xmm1
  subsd  %xmm2,%xmm1
  subsd  -0x8(%rbx),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  0x8(%rsp),%xmm1
  movsd  %xmm1,-0x8(%r12)
  cmp    %rbp,%rbx
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopl   (%rax)
L14:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: f32[2]

tool: {"D9": [0.0,1.75]}

assistant: ```c
void PT(double *u_init, double *x, double *u_future, int n_points, double c, double L, double dt) {
  int i;
  double dx = x[1] - x[0];
  double r = c * dt / dx;
  for (i = 1; i < n_points - 1; i++) {
    u_future[i] = u_init[i] + pow(r, 2) / 2.0 * (u_init[i + 1] - 2 * u_init[i] - u_init[i - 1]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test7b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L2
  movl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test7b(int y) {
  int x = x;
  if (y)
    x = 1;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test7b>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test7b(int y) {
  int x = x;
  if (y)
    x = 1;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test7b>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int test7b(int y) {
  int x = x;
  if (y)
    x = 1;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wildcards_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L34:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  je     L18
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wildcards_aux>
  jmp    L5
L18:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wildcards_aux>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x31,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wildcards_aux>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3f,(%rax)
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: %s


assistant: ```c
void wildcards_aux(char *str, size_t str_i) {
  if (str[str_i] == '\0') {
    printf("%s\n", str);
    return;
  }
  if (str[str_i] != '?') {
    wildcards_aux(str, str_i + 1);
  } else {
    str[str_i] = '0';
    wildcards_aux(str, str_i);
    str[str_i] = '1';
    wildcards_aux(str, str_i);
    str[str_i] = '?';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<wildcards_aux>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    (%rdi,%rsi,1),%r12
  movzbl (%r12),%eax
  test   %al,%al
  je     L35
  mov    %rsi,%rbx
  cmp    $0x3f,%al
  je     L8
  lea    0x1(%rsi),%rsi
  call   <wildcards_aux>
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L8:
  movb   $0x30,(%r12)
  call   <wildcards_aux>
  movb   $0x31,(%r12)
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <wildcards_aux>
  movb   $0x3f,(%r12)
  jmp    L25
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: %s


assistant: ```c
void wildcards_aux(char *str, size_t str_i) {
  if (str[str_i] == '\0') {
    printf("%s\n", str);
    return;
  }
  if (str[str_i] != '?') {
    wildcards_aux(str, str_i + 1);
  } else {
    str[str_i] = '0';
    wildcards_aux(str, str_i);
    str[str_i] = '1';
    wildcards_aux(str, str_i);
    str[str_i] = '?';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wildcards_aux>:
  endbr64
  lea    (%rdi,%rsi,1),%rdx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdx),%eax
  sub    %rsi,%rdx
  test   %al,%al
  jne    L34
  jmp    L17
  xchg   %ax,%ax
L10:
  add    $0x1,%rbp
  movzbl (%r12,%rbp,1),%eax
  test   %al,%al
  je     L17
L34:
  lea    (%rdx,%rbp,1),%rbx
  cmp    $0x3f,%al
  jne    L10
  movb   $0x30,(%rbx)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <wildcards_aux>
  movb   $0x31,(%rbx)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <wildcards_aux>
  movb   $0x3f,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  pop    %rbx
  mov    %r12,%rsi
  lea    D1(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string

tool: D1: %s


assistant: ```c
void wildcards_aux(char *str, size_t str_i) {
  if (str[str_i] == '\0') {
    printf("%s\n", str);
    return;
  }
  if (str[str_i] != '?') {
    wildcards_aux(str, str_i + 1);
  } else {
    str[str_i] = '0';
    wildcards_aux(str, str_i);
    str[str_i] = '1';
    wildcards_aux(str, str_i);
    str[str_i] = '?';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D27
type_infered: string
name: read_data
arguments: tag: D24
type_infered: string
name: read_data
arguments: tag: D23
type_infered: string

tool: D27: Enter two number:

tool: D24: %lf %lf

tool: D23: Result = %.2lf


assistant: ```c
int main() {
  double firstNumber, secondNumber, result;
  printf("Enter two number:\n");
  scanf("%lf %lf", &firstNumber, &secondNumber);
  result = firstNumber * secondNumber;
  printf("Result = %.2lf\n", result);
  return 0;
}
```