ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<hw_fixspisamples>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movq   $0x0,-0x8(%rbp)
  movb   $0x0,-0x13(%rbp)
  movb   $0x0,-0x12(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L3
L27:
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x13(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  shr    $0x7,%al
  or     %edx,%eax
  mov    %al,-0x13(%rbp)
  movzbl -0x12(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x12(%rbp)
  cmpb   $0x8,-0x12(%rbp)
  jne    L60
  mov    -0x8(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jge    L24
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x13(%rbp),%eax
  mov    %al,(%rdx)
L24:
  movb   $0x0,-0x12(%rbp)
  movb   $0x0,-0x13(%rbp)
L60:
  movb   $0x0,-0x11(%rbp)
  jmp    L67
L52:
  movzbl -0x13(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  shr    $0x7,%al
  or     %edx,%eax
  mov    %al,-0x13(%rbp)
  movzbl -0x12(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x12(%rbp)
  cmpb   $0x8,-0x12(%rbp)
  jne    L97
  mov    -0x8(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jge    L57
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x13(%rbp),%eax
  mov    %al,(%rdx)
L57:
  movb   $0x0,-0x12(%rbp)
  movb   $0x0,-0x13(%rbp)
L97:
  shlb   -0x14(%rbp)
  movzbl -0x11(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x11(%rbp)
L67:
  cmpb   $0x7,-0x11(%rbp)
  jbe    L52
  mov    -0x8(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jge    L25
  addq   $0x1,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L27
  jmp    L49
L25:
  nop
L49:
  pop    %rbp
  ret
```

assistant: ```c
void hw_fixspisamples(char *inbuf, long inlen, char *outbuf, long outlen) {
  long inpos, outpos;
  unsigned char c, o, olen, bitpos;
  outpos = 0;
  o = 0;
  olen = 0;
  for (inpos = 0; inpos < inlen; inpos++) {
    c = inbuf[inpos];
    o = (o << 1) | ((c & 0x80) >> 7);
    olen++;
    if (olen == 8) {
      if (outpos < outlen)
        outbuf[outpos++] = o;
      olen = 0;
      o = 0;
    }
    for (bitpos = 0; bitpos < 8; bitpos++) {
      o = (o << 1) | ((c & 0x80) >> 7);
      olen++;
      if (olen == 8) {
        if (outpos < outlen)
          outbuf[outpos++] = o;
        olen = 0;
        o = 0;
      }
      c = c << 1;
    }
    if (outpos >= outlen)
      return;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hw_fixspisamples>:
  endbr64
  test   %rsi,%rsi
  jle    L51
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rcx,%r9
  movzbl (%rdi),%ecx
  mov    %ecx,%eax
  shr    $0x7,%al
  lea    0x1(%rdi),%r10
  lea    (%rdi,%rsi,1),%rbp
  mov    $0x1,%edx
  mov    $0x0,%r8d
  mov    $0x0,%r11d
  jmp    L129
L51:
  ret
L125:
  mov    %al,(%rbx,%r8,1)
  mov    %esi,%eax
  mov    %esi,%edx
  lea    0x1(%r8),%r8
  jmp    L83
L127:
  add    %ecx,%ecx
  sub    $0x1,%sil
  je     L24
L117:
  add    %eax,%eax
  mov    %ecx,%edi
  shr    $0x7,%dil
  or     %edi,%eax
  add    $0x1,%edx
  cmp    $0x8,%dl
  jne    L127
  cmp    %r8,%r9
  jle    L90
  mov    %al,(%rbx,%r8,1)
  lea    0x1(%r8),%r8
  mov    $0x0,%edx
  mov    %r11d,%eax
  jmp    L127
L24:
  cmp    %r9,%r8
  jge    L10
  cmp    %r10,%rbp
  je     L10
  movzbl (%r10),%ecx
  add    %eax,%eax
  mov    %ecx,%edi
  shr    $0x7,%dil
  or     %edi,%eax
  add    $0x1,%edx
  cmp    $0x8,%dl
  je     L125
L83:
  add    $0x1,%r10
L129:
  mov    $0x8,%esi
  jmp    L117
L90:
  add    %ecx,%ecx
  sub    $0x1,%sil
  je     L10
  mov    $0x0,%edx
  mov    %r11d,%eax
  jmp    L117
L10:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void hw_fixspisamples(char *inbuf, long inlen, char *outbuf, long outlen) {
  long inpos, outpos;
  unsigned char c, o, olen, bitpos;
  outpos = 0;
  o = 0;
  olen = 0;
  for (inpos = 0; inpos < inlen; inpos++) {
    c = inbuf[inpos];
    o = (o << 1) | ((c & 0x80) >> 7);
    olen++;
    if (olen == 8) {
      if (outpos < outlen)
        outbuf[outpos++] = o;
      olen = 0;
      o = 0;
    }
    for (bitpos = 0; bitpos < 8; bitpos++) {
      o = (o << 1) | ((c & 0x80) >> 7);
      olen++;
      if (olen == 8) {
        if (outpos < outlen)
          outbuf[outpos++] = o;
        olen = 0;
        o = 0;
      }
      c = c << 1;
    }
    if (outpos >= outlen)
      return;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hw_fixspisamples>:
  endbr64
  test   %rsi,%rsi
  jle    L28
  push   %rbx
  movzbl (%rdi),%r8d
  mov    %rdx,%r11
  lea    0x1(%rdi),%r10
  lea    (%rdi,%rsi,1),%rbx
  mov    $0x1,%edx
  xor    %r9d,%r9d
  mov    %r8d,%eax
  shr    $0x7,%al
  nopl   0x0(%rax,%rax,1)
L85:
  mov    $0x8,%esi
  nopl   (%rax)
L96:
  mov    %r8d,%edi
  add    %eax,%eax
  add    $0x1,%edx
  shr    $0x7,%dil
  or     %edi,%eax
  cmp    $0x8,%dl
  je     L42
L98:
  add    %r8d,%r8d
  sub    $0x1,%sil
  jne    L96
  cmp    %rcx,%r9
  jge    L34
  cmp    %r10,%rbx
  je     L34
  movzbl (%r10),%r8d
  add    %eax,%eax
  add    $0x1,%edx
  mov    %r8d,%esi
  shr    $0x7,%sil
  or     %esi,%eax
  cmp    $0x8,%dl
  je     L25
L68:
  add    $0x1,%r10
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L42:
  cmp    %r9,%rcx
  jle    L103
  mov    %al,(%r11,%r9,1)
  xor    %edx,%edx
  add    $0x1,%r9
  xor    %eax,%eax
  jmp    L98
  nopl   0x0(%rax,%rax,1)
L103:
  add    %r8d,%r8d
  sub    $0x1,%sil
  je     L34
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %al,(%r11,%r9,1)
  xor    %edx,%edx
  xor    %eax,%eax
  add    $0x1,%r9
  jmp    L68
  xchg   %ax,%ax
L34:
  pop    %rbx
  ret
L28:
  ret
```

assistant: ```c
void hw_fixspisamples(char *inbuf, long inlen, char *outbuf, long outlen) {
  long inpos, outpos;
  unsigned char c, o, olen, bitpos;
  outpos = 0;
  o = 0;
  olen = 0;
  for (inpos = 0; inpos < inlen; inpos++) {
    c = inbuf[inpos];
    o = (o << 1) | ((c & 0x80) >> 7);
    olen++;
    if (olen == 8) {
      if (outpos < outlen)
        outbuf[outpos++] = o;
      olen = 0;
      o = 0;
    }
    for (bitpos = 0; bitpos < 8; bitpos++) {
      o = (o << 1) | ((c & 0x80) >> 7);
      olen++;
      if (olen == 8) {
        if (outpos < outlen)
          outbuf[outpos++] = o;
        olen = 0;
        o = 0;
      }
      c = c << 1;
    }
    if (outpos >= outlen)
      return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L174
  mov    -0x4(%rbp),%eax
  jmp    L95
L174:
  cmpl   $0x0,-0x4(%rbp)
  jne    L18
  mov    -0x8(%rbp),%eax
  jmp    L95
L18:
  cmpl   $0x0,-0x8(%rbp)
  jne    L103
  mov    -0x4(%rbp),%eax
  jmp    L95
L103:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L9
  mov    $0x1,%eax
  jmp    L55
L9:
  mov    $0x0,%eax
L55:
  test   %al,%al
  je     L109
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L178
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <gcd>
  jmp    L95
L178:
  mov    -0x8(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd>
  add    %eax,%eax
  jmp    L95
L109:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L29
  mov    $0x1,%eax
  jmp    L96
L29:
  mov    $0x0,%eax
L96:
  test   %al,%al
  je     L50
  mov    -0x8(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd>
  jmp    L95
L50:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jbe    L94
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <gcd>
  jmp    L95
L94:
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <gcd>
L95:
  leave
  ret
```

assistant: ```c
unsigned int gcd(unsigned int u, unsigned int v) {
  if (u == v)
    return u;
  if (u == 0)
    return v;
  if (v == 0)
    return u;
  if ((~u) & 1) {
    if (v & 1) {
      return gcd(u >> 1, v);
    } else {
      return gcd(u >> 1, v >> 1) << 1;
    }
  }
  if ((~v) & 1) {
    return gcd(u, v >> 1);
  }
  if (u > v) {
    return gcd((u - v) >> 1, v);
  }
  return gcd((v - u) >> 1, u);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  je     L1
  test   %edi,%edi
  je     L1
  mov    %edi,%eax
  test   %esi,%esi
  je     L1
  sub    $0x8,%rsp
  test   $0x1,%dil
  jne    L44
  test   $0x1,%sil
  jne    L8
  shr    %esi
  shr    %edi
  call   <gcd>
  add    %eax,%eax
  jmp    L19
L44:
  test   $0x1,%sil
  je     L52
  cmp    %esi,%edi
  ja     L21
  sub    %edi,%esi
  mov    %esi,%eax
  shr    %eax
  mov    %edi,%esi
  mov    %eax,%edi
  call   <gcd>
L19:
  add    $0x8,%rsp
  ret
L8:
  shr    %edi
  call   <gcd>
  jmp    L19
L52:
  shr    %esi
  call   <gcd>
  jmp    L19
L21:
  sub    %esi,%edi
  shr    %edi
  call   <gcd>
  jmp    L19
L1:
  ret
```

assistant: ```c
unsigned int gcd(unsigned int u, unsigned int v) {
  if (u == v)
    return u;
  if (u == 0)
    return v;
  if (v == 0)
    return u;
  if ((~u) & 1) {
    if (v & 1) {
      return gcd(u >> 1, v);
    } else {
      return gcd(u >> 1, v >> 1) << 1;
    }
  }
  if ((~v) & 1) {
    return gcd(u, v >> 1);
  }
  if (u > v) {
    return gcd((u - v) >> 1, v);
  }
  return gcd((v - u) >> 1, u);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  cmp    %edi,%esi
  je     L38
  test   %edi,%edi
  je     L38
  test   %esi,%esi
  je     L2
L8:
  mov    %esi,%eax
  and    $0x1,%eax
  test   $0x1,%dil
  jne    L34
  shr    %edi
  test   %eax,%eax
  je     L128
L29:
  cmp    %edi,%esi
  je     L38
  test   %edi,%edi
  jne    L8
L38:
  mov    %esi,%eax
  ret
  nopl   0x0(%rax)
L34:
  test   %eax,%eax
  je     L36
  cmp    %esi,%edi
  jbe    L66
  sub    %esi,%edi
  shr    %edi
  jmp    L29
  xchg   %ax,%ax
L36:
  shr    %esi
  cmp    %edi,%esi
  je     L38
  test   %esi,%esi
  jne    L8
L2:
  mov    %edi,%eax
  ret
  nopl   (%rax)
L66:
  mov    %esi,%eax
  mov    %edi,%esi
  sub    %edi,%eax
  shr    %eax
  mov    %eax,%edi
  jmp    L29
  nopl   0x0(%rax)
L128:
  sub    $0x8,%rsp
  shr    %esi
  call   <gcd>
  add    $0x8,%rsp
  add    %eax,%eax
  ret
```

assistant: ```c
unsigned int gcd(unsigned int u, unsigned int v) {
  if (u == v)
    return u;
  if (u == 0)
    return v;
  if (v == 0)
    return u;
  if ((~u) & 1) {
    if (v & 1) {
      return gcd(u >> 1, v);
    } else {
      return gcd(u >> 1, v >> 1) << 1;
    }
  }
  if ((~v) & 1) {
    return gcd(u, v >> 1);
  }
  if (u > v) {
    return gcd((u - v) >> 1, v);
  }
  return gcd((v - u) >> 1, u);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  cmp    %edi,%esi
  je     L251
  test   %edi,%edi
  je     L251
  test   %esi,%esi
  je     L168
L256:
  mov    %esi,%eax
  and    $0x1,%eax
  test   $0x1,%dil
  jne    L217
  shr    %edi
  test   %eax,%eax
  je     L90
L258:
  cmp    %edi,%esi
  je     L251
  test   %edi,%edi
  jne    L256
L251:
  mov    %esi,%eax
  ret
  nopl   0x0(%rax)
L217:
  test   %eax,%eax
  jne    L26
  shr    %esi
  cmp    %edi,%esi
  je     L251
  test   %esi,%esi
  jne    L256
L168:
  mov    %edi,%eax
  ret
  nopl   0x0(%rax)
L26:
  cmp    %esi,%edi
  jbe    L210
  sub    %esi,%edi
  shr    %edi
  jmp    L258
  nopw   0x0(%rax,%rax,1)
L210:
  mov    %esi,%eax
  mov    %edi,%esi
  sub    %edi,%eax
  shr    %eax
  mov    %eax,%edi
  jmp    L258
  nopl   0x0(%rax)
L90:
  mov    %esi,%eax
  shr    %eax
  cmp    %edi,%eax
  je     L132
  test   %edi,%edi
  je     L132
L187:
  test   %eax,%eax
  je     L39
L122:
  mov    %eax,%edx
  and    $0x1,%edx
  test   $0x1,%dil
  jne    L151
  shr    %edi
  test   %edx,%edx
  je     L227
L87:
  cmp    %eax,%edi
  je     L132
  test   %edi,%edi
  jne    L122
L132:
  add    %eax,%eax
  ret
  nopl   0x0(%rax)
L151:
  test   %edx,%edx
  je     L240
  cmp    %eax,%edi
  jbe    L14
  sub    %eax,%edi
  shr    %edi
  jmp    L87
  cs nopw 0x0(%rax,%rax,1)
L240:
  shr    %eax
  cmp    %edi,%eax
  jne    L187
  jmp    L132
  nopl   0x0(%rax,%rax,1)
L14:
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edi,%eax
  shr    %edx
  mov    %edx,%edi
  jmp    L87
L39:
  mov    %edi,%eax
  jmp    L132
L227:
  shr    %eax
  sub    $0x8,%rsp
  mov    %eax,%esi
  call   <gcd>
  add    $0x8,%rsp
  add    %eax,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
unsigned int gcd(unsigned int u, unsigned int v) {
  if (u == v)
    return u;
  if (u == 0)
    return v;
  if (v == 0)
    return u;
  if ((~u) & 1) {
    if (v & 1) {
      return gcd(u >> 1, v);
    } else {
      return gcd(u >> 1, v >> 1) << 1;
    }
  }
  if ((~v) & 1) {
    return gcd(u, v >> 1);
  }
  if (u > v) {
    return gcd((u - v) >> 1, v);
  }
  return gcd((v - u) >> 1, u);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<priority>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x26,%eax
  cmp    $0x56,%eax
  ja     L96
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D18(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D18(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L89
  mov    $0x5,%eax
  jmp    L89
  mov    $0xa,%eax
  jmp    L89
  mov    $0xf,%eax
  jmp    L89
  mov    $0x14,%eax
  jmp    L89
  mov    $0x19,%eax
  jmp    L89
  mov    $0x1e,%eax
  jmp    L89
  mov    $0x23,%eax
  jmp    L89
  mov    $0x28,%eax
  jmp    L89
L96:
  mov    $0x0,%eax
L89:
  pop    %rbp
  ret
```

assistant: ```c
int priority(char ch) {
  switch (ch) {
  case '(':
    return 0;
  case 'l':
  case 'h':
    return 5;
  case '=':
  case '<':
  case '>':
  case 'o':
  case 'g':
  case 's':
    return 10;
  case '+':
  case '-':
    return 15;
  case '*':
  case '/':
  case 'u':
    return 20;
  case '|':
  case '^':
    return 25;
  case '&':
    return 30;
  case 'm':
  case 'd':
    return 35;
  case 'n':
  case 'i':
  case 't':
    return 40;
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<priority>:
  endbr64
  sub    $0x26,%edi
  cmp    $0x56,%dil
  ja     L9
  movzbl %dil,%edi
  lea    D5(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x5,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0xf,%eax
  ret
  mov    $0x14,%eax
  ret
  mov    $0x19,%eax
  ret
  mov    $0x1e,%eax
  ret
  mov    $0x23,%eax
  ret
  mov    $0x28,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int priority(char ch) {
  switch (ch) {
  case '(':
    return 0;
  case 'l':
  case 'h':
    return 5;
  case '=':
  case '<':
  case '>':
  case 'o':
  case 'g':
  case 's':
    return 10;
  case '+':
  case '-':
    return 15;
  case '*':
  case '/':
  case 'u':
    return 20;
  case '|':
  case '^':
    return 25;
  case '&':
    return 30;
  case 'm':
  case 'd':
    return 35;
  case 'n':
  case 'i':
  case 't':
    return 40;
  default:
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<priority>:
  endbr64
  sub    $0x26,%edi
  xor    %eax,%eax
  cmp    $0x56,%dil
  ja     L3
  movzbl %dil,%edi
  lea    D8(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L3:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: 

assistant: ```c
int priority(char ch) {
  switch (ch) {
  case '(':
    return 0;
  case 'l':
  case 'h':
    return 5;
  case '=':
  case '<':
  case '>':
  case 'o':
  case 'g':
  case 's':
    return 10;
  case '+':
  case '-':
    return 15;
  case '*':
  case '/':
  case 'u':
    return 20;
  case '|':
  case '^':
    return 25;
  case '&':
    return 30;
  case 'm':
  case 'd':
    return 35;
  case 'n':
  case 'i':
  case 't':
    return 40;
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<priority>:
  endbr64
  sub    $0x26,%edi
  xor    %eax,%eax
  cmp    $0x56,%dil
  ja     L0
  movzbl %dil,%edi
  lea    D3(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L0:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: 

assistant: ```c
int priority(char ch) {
  switch (ch) {
  case '(':
    return 0;
  case 'l':
  case 'h':
    return 5;
  case '=':
  case '<':
  case '>':
  case 'o':
  case 'g':
  case 's':
    return 10;
  case '+':
  case '-':
    return 15;
  case '*':
  case '/':
  case 'u':
    return 20;
  case '|':
  case '^':
    return 25;
  case '&':
    return 30;
  case 'm':
  case 'd':
    return 35;
  case 'n':
  case 'i':
  case 't':
    return 40;
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<odd_bit_toggle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x20,-0x8(%rbp)
  jmp    L12
L7:
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x14(%rbp)
  shll   $0x2,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L12:
  cmpl   $0x0,-0x8(%rbp)
  jg     L7
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int odd_bit_toggle(int o_num) {
  int bit_length;
  int mask;
  mask = 1;
  bit_length = 4 * sizeof(void *);
  for (; bit_length >= 1; bit_length--) {
    o_num = o_num ^ mask;
    mask = mask << 2;
  }
  return o_num;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<odd_bit_toggle>:
  endbr64
  mov    %edi,%eax
  mov    $0x20,%ecx
  mov    $0x1,%edx
L9:
  xor    %edx,%eax
  shl    $0x2,%edx
  sub    $0x1,%ecx
  jne    L9
  ret
```

assistant: ```c
int odd_bit_toggle(int o_num) {
  int bit_length;
  int mask;
  mask = 1;
  bit_length = 4 * sizeof(void *);
  for (; bit_length >= 1; bit_length--) {
    o_num = o_num ^ mask;
    mask = mask << 2;
  }
  return o_num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<odd_bit_toggle>:
  endbr64
  mov    %edi,%eax
  mov    $0x20,%ecx
  mov    $0x1,%edx
L3:
  xor    %edx,%eax
  shl    $0x2,%edx
  sub    $0x1,%ecx
  jne    L3
  ret
```

assistant: ```c
int odd_bit_toggle(int o_num) {
  int bit_length;
  int mask;
  mask = 1;
  bit_length = 4 * sizeof(void *);
  for (; bit_length >= 1; bit_length--) {
    o_num = o_num ^ mask;
    mask = mask << 2;
  }
  return o_num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<odd_bit_toggle>:
  endbr64
  mov    %edi,%eax
  mov    $0x20,%ecx
  mov    $0x1,%edx
L7:
  xor    %edx,%eax
  shl    $0x2,%edx
  sub    $0x1,%ecx
  jne    L7
  ret
```

assistant: ```c
int odd_bit_toggle(int o_num) {
  int bit_length;
  int mask;
  mask = 1;
  bit_length = 4 * sizeof(void *);
  for (; bit_length >= 1; bit_length--) {
    o_num = o_num ^ mask;
    mask = mask << 2;
  }
  return o_num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  jle    L7
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: sum of first 5 natural numbers = %d

assistant: ```c
int main() {
  int sum = 0, i = 1;
  do {
    sum += i;
    ++i;
  } while (i <= 5);
  printf("sum of first 5 natural numbers = %d", sum);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: sum of first 5 natural numbers = %d

assistant: ```c
int main() {
  int sum = 0, i = 1;
  do {
    sum += i;
    ++i;
  } while (i <= 5);
  printf("sum of first 5 natural numbers = %d", sum);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: sum of first 5 natural numbers = %d

assistant: ```c
int main() {
  int sum = 0, i = 1;
  do {
    sum += i;
    ++i;
  } while (i <= 5);
  printf("sum of first 5 natural numbers = %d", sum);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: sum of first 5 natural numbers = %d

assistant: ```c
int main() {
  int sum = 0, i = 1;
  do {
    sum += i;
    ++i;
  } while (i <= 5);
  printf("sum of first 5 natural numbers = %d", sum);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<phi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x2,-0x8(%rbp)
  jmp    L56
L15:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L27
  jmp    L0
L5:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rax,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  je     L5
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  sub    %rax,-0x10(%rbp)
L27:
  addq   $0x1,-0x8(%rbp)
L56:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  cmp    %rax,-0x8(%rbp)
  jle    L15
  cmpq   $0x1,-0x18(%rbp)
  je     L28
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x18(%rbp)
  sub    %rax,-0x10(%rbp)
L28:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long int phi(long long int n) {
  long long int res = n, i, j, k;
  for (i = 2; i <= sqrt(n); i++) {
    if (n % i == 0) {
      while (n % i == 0)
        n = n / i;
      res = res - res / i;
    }
  }
  if (n != 1) {
    res = res - res / n;
  }
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<phi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%r12
  mov    $0x2,%ebp
  jmp    L43
L9:
  mov    %r12,%rax
  cqto
  idiv   %rbp
  sub    %rax,%r12
L29:
  add    $0x1,%rbp
L43:
  mov    %rbx,%rdi
  call   <sqrt@plt>
  cmp    %rbp,%rax
  jl     L16
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  test   %rdx,%rdx
  jne    L29
L53:
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  mov    %rax,%rbx
  cqto
  idiv   %rbp
  test   %rdx,%rdx
  je     L53
  jmp    L9
L16:
  cmp    $0x1,%rbx
  je     L48
  mov    %r12,%rax
  cqto
  idiv   %rbx
  sub    %rax,%r12
L48:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long int phi(long long int n) {
  long long int res = n, i, j, k;
  for (i = 2; i <= sqrt(n); i++) {
    if (n % i == 0) {
      while (n % i == 0)
        n = n / i;
      res = res - res / i;
    }
  }
  if (n != 1) {
    res = res - res / n;
  }
  return res;
}
```