user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  lea    D25(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D88(%rip),%rdi
  call   <scanf@plt>
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L31:
  add    $0x1,%ebx
L4:
  mov    0x14(%rsp),%r12d
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L31
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
  mov    %ebx,0xc(%rsp)
  jmp    L40
  nopl   (%rax)
L18:
  cmp    %r14d,%r15d
  jge    L43
L68:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  cmp    0xc(%rsp),%r12d
  je     L58
L40:
  mov    %r12d,%ebx
  add    $0x1,%r12d
  mov    $0xa,%edi
  mov    %r12d,%esi
  call   <power@plt>
  lea    D63(%rip),%rdi
  mov    %eax,%r14d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  lea    D39(%rip),%rdi
  cltd
  idiv   %r14d
  mov    %eax,%r13d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   %r13d,%r14d
  mov    0x14(%rsp),%r15d
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  sub    %r14d,%r15d
  mov    %r15d,%esi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <power@plt>
  lea    D98(%rip),%rdi
  mov    %eax,%r14d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   %r14d,%r13d
  lea    (%r14,%r14,1),%eax
  add    %r13d,%ebp
  cmp    %r15d,%eax
  jg     L18
  lea    D104(%rip),%rdi
  add    %r14d,%ebp
  call   <puts@plt>
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L43:
  sub    %r14d,%r15d
  lea    D92(%rip),%rdi
  lea    0x1(%rbp,%r15,1),%ebp
  call   <puts@plt>
  jmp    L68
  nopl   0x0(%rax)
L58:
  mov    %ebp,%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
type_guessed: string
name: retrieve_data
arguments: data_label: D88
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D69
type_guessed: string
name: retrieve_data
arguments: data_label: D63
type_guessed: string
name: retrieve_data
arguments: data_label: D39
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D98
type_guessed: string
name: retrieve_data
arguments: data_label: D104
type_guessed: string
name: retrieve_data
arguments: data_label: D92
type_guessed: string
name: retrieve_data
arguments: data_label: D38
type_guessed: string

tool: D25: Enter a number: 

tool: D88: %d

tool: D7: the digit is: %d



tool: D69: The n1 is: %d



tool: D63: The base is: %d


tool: D39: The fra is: %d


tool: D1: The mod is: %d


tool: D98: The quan is: %d


tool: D104: A

tool: D92: B

tool: D38: The number of ones is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int num;
  int frac = 1;
  int digit = 1;
  printf("Enter a number: ");
  scanf("%d", &num);
  while (1) {
    frac = num / power(10, digit);
    if (frac == 0)
      break;
    digit += 1;
  }
  printf("the digit is: %d\n\n", digit);
  int j;
  int n1;
  for (j = 0, n1 = 0; j < digit; j++) {
    int base = power(10, j + 1);
    printf("The base is: %d\n", base);
    int fra = num / base;
    printf("The fra is: %d\n", fra);
    int mod = num - base * fra;
    printf("The mod is: %d\n", mod);
    int quan = power(10, j);
    printf("The quan is: %d\n", quan);
    n1 += fra * quan;
    if (mod > 2 * quan - 1) {
      n1 += quan;
      printf("A\n");
    } else if (mod > quan - 1) {
      n1 += mod - quan + 1;
      printf("B\n");
    }
    printf("The n1 is: %d\n\n", n1);
  }
  printf("The number of ones is: %d\n", n1);
  getchar();
  getchar();
  return 0;
}
```