ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_long>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    D2(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%r12)
  call   <strtol@plt>
  xor    %r8d,%r8d
  mov    %rax,0x0(%rbp)
  mov    (%rsp),%rax
  cmp    %rbx,%rax
  je     L41
  cmpq   $0x0,(%r12)
  je     L5
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rax
  mov    %rax,(%rsp)
L5:
  movsbl (%rax),%edi
  call   <isspace@plt>
  test   %rax,%rax
  mov    (%rsp),%rax
  jne    L22
  xor    %r8d,%r8d
  cmpb   $0x0,(%rax)
  sete   %r8b
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_long(const char *s, long *val) {
  char *end;
  errno = 0;
  *val = strtol(s, &end, 10);
  if ((end == s) || (errno != 0)) {
    return 0;
  }
  while (isspace(*end))
    end++;
  if (*end != '\0') {
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ms_genfactmult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x20(%rbp)
  je     L61
  cmpq   $0x0,-0x28(%rbp)
  jne    L73
L61:
  mov    $0xffffffff,%eax
  jmp    L26
L73:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L60
  movsd  D11(%rip),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L60:
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L9
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jne    L9
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L26
L9:
  movsd  -0x18(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L53
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <ms_reduce_rate@plt>
  test   %rax,%rax
  jne    L47
  mov    -0x10(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L26
L53:
  movsd  D5(%rip),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <ms_reduce_rate@plt>
  test   %rax,%rax
  jne    L47
  mov    -0x10(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L26
L47:
  mov    $0xffffffff,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L81
  call   <__stack_chk_fail@plt>
L81:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
datatype: f32[2]
name: extract_symbolic_data
arguments: tag: D5
datatype: f64

tool: {"D11": [0.0,-1.875]}

tool: D5: 1

assistant: ```c
int ms_genfactmult(double samprate, int16_t *factor, int16_t *multiplier) {
  int16_t factor1;
  int16_t factor2;
  if (!factor || !multiplier)
    return -1;
  if (samprate < 0.0)
    samprate = -1.0 / samprate;
  if (samprate == 0.0) {
    *factor = 0;
    *multiplier = 0;
    return 0;
  } else if (samprate >= 1.0) {
    if (ms_reduce_rate(samprate, &factor1, &factor2) == 0) {
      *factor = factor1;
      *multiplier = factor2;
      return 0;
    }
  } else {
    if (ms_reduce_rate(1.0 / samprate, &factor1, &factor2) == 0) {
      *factor = -factor1;
      *multiplier = -factor2;
      return 0;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ms_genfactmult>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L99
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L99
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L78
L79:
  ucomisd D21(%rip),%xmm0
  jp     L121
  je     L10
L121:
  comisd D13(%rip),%xmm0
  jb     L22
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <ms_reduce_rate@plt>
  test   %rax,%rax
  jne    L2
  mov    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
L42:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L78:
  movsd  D24(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  jmp    L79
L10:
  movl   $0x0,(%rbx)
  movl   $0x0,0x0(%rbp)
  mov    $0x0,%eax
  jmp    L42
L22:
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movsd  D13(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <ms_reduce_rate@plt>
  test   %rax,%rax
  jne    L98
  mov    (%rsp),%eax
  neg    %eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  neg    %eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
  jmp    L42
L99:
  mov    $0xffffffff,%eax
  jmp    L42
L2:
  mov    $0xffffffff,%eax
  jmp    L42
L98:
  mov    $0xffffffff,%eax
  jmp    L42
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
datatype: f64
name: unpack_data
arguments: data_label: D13
datatype: f64
name: unpack_data
arguments: data_label: D24
datatype: byte[8]

tool: D21: 0

tool: D13: 1

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
int ms_genfactmult(double samprate, int16_t *factor, int16_t *multiplier) {
  int16_t factor1;
  int16_t factor2;
  if (!factor || !multiplier)
    return -1;
  if (samprate < 0.0)
    samprate = -1.0 / samprate;
  if (samprate == 0.0) {
    *factor = 0;
    *multiplier = 0;
    return 0;
  } else if (samprate >= 1.0) {
    if (ms_reduce_rate(samprate, &factor1, &factor2) == 0) {
      *factor = factor1;
      *multiplier = factor2;
      return 0;
    }
  } else {
    if (ms_reduce_rate(1.0 / samprate, &factor1, &factor2) == 0) {
      *factor = -factor1;
      *multiplier = -factor2;
      return 0;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ms_genfactmult>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L92
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L92
  pxor   %xmm1,%xmm1
  mov    %rdi,%rbx
  comisd %xmm0,%xmm1
  jbe    L33
  movsd  D5(%rip),%xmm2
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
L33:
  ucomisd %xmm1,%xmm0
  jp     L54
  je     L19
L54:
  movsd  D9(%rip),%xmm1
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  comisd %xmm1,%xmm0
  jb     L20
  call   <ms_reduce_rate@plt>
  test   %rax,%rax
  jne    L92
  mov    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
L64:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L75
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <ms_reduce_rate@plt>
  test   %rax,%rax
  jne    L92
  mov    (%rsp),%eax
  neg    %eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  neg    %eax
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  jmp    L64
  cs nopw 0x0(%rax,%rax,1)
L19:
  movl   $0x0,(%rbx)
  xor    %eax,%eax
  movl   $0x0,0x0(%rbp)
  jmp    L64
  nopl   0x0(%rax)
L92:
  mov    $0xffffffff,%eax
  jmp    L64
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: f32[2]
name: unpack_data
arguments: data_tag: D9
data_type: f64

tool: {"D5": [0.0,-1.875]}

tool: D9: 1

assistant: ```c
int ms_genfactmult(double samprate, int16_t *factor, int16_t *multiplier) {
  int16_t factor1;
  int16_t factor2;
  if (!factor || !multiplier)
    return -1;
  if (samprate < 0.0)
    samprate = -1.0 / samprate;
  if (samprate == 0.0) {
    *factor = 0;
    *multiplier = 0;
    return 0;
  } else if (samprate >= 1.0) {
    if (ms_reduce_rate(samprate, &factor1, &factor2) == 0) {
      *factor = factor1;
      *multiplier = factor2;
      return 0;
    }
  } else {
    if (ms_reduce_rate(1.0 / samprate, &factor1, &factor2) == 0) {
      *factor = -factor1;
      *multiplier = -factor2;
      return 0;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ms_genfactmult>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L75
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L75
  pxor   %xmm1,%xmm1
  mov    %rdi,%rbx
  comisd %xmm0,%xmm1
  jbe    L86
  movsd  D2(%rip),%xmm2
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
L86:
  ucomisd %xmm1,%xmm0
  jp     L106
  je     L12
L106:
  movsd  D12(%rip),%xmm1
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  comisd %xmm1,%xmm0
  jb     L59
  call   <ms_reduce_rate@plt>
  test   %rax,%rax
  jne    L75
  mov    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L59:
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <ms_reduce_rate@plt>
  test   %rax,%rax
  jne    L75
  mov    (%rsp),%eax
  neg    %eax
  mov    %eax,(%rbx)
  mov    0x4(%rsp),%eax
  neg    %eax
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  jmp    L34
  cs nopw 0x0(%rax,%rax,1)
L12:
  movl   $0x0,(%rbx)
  xor    %eax,%eax
  movl   $0x0,0x0(%rbp)
  jmp    L34
  nopl   0x0(%rax)
L75:
  mov    $0xffffffff,%eax
  jmp    L34
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: f32[2]
name: extract_symbolic_data
arguments: tag: D12
type: f64

tool: {"D2": [0.0,-1.875]}

tool: D12: 1

assistant: ```c
int ms_genfactmult(double samprate, int16_t *factor, int16_t *multiplier) {
  int16_t factor1;
  int16_t factor2;
  if (!factor || !multiplier)
    return -1;
  if (samprate < 0.0)
    samprate = -1.0 / samprate;
  if (samprate == 0.0) {
    *factor = 0;
    *multiplier = 0;
    return 0;
  } else if (samprate >= 1.0) {
    if (ms_reduce_rate(samprate, &factor1, &factor2) == 0) {
      *factor = factor1;
      *multiplier = factor2;
      return 0;
    }
  } else {
    if (ms_reduce_rate(1.0 / samprate, &factor1, &factor2) == 0) {
      *factor = -factor1;
      *multiplier = -factor2;
      return 0;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void xfree(void *ptr) {
  assert(ptr != NULL);
  free(ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xfree>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void xfree(void *ptr) {
  assert(ptr != NULL);
  free(ptr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void xfree(void *ptr) {
  assert(ptr != NULL);
  free(ptr);
}
```
user: What is the c source code of the assembly code below:

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void xfree(void *ptr) {
  assert(ptr != NULL);
  free(ptr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L11
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L11:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x3fe,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0xa,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L13
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <strcat@plt>
L13:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3: 


assistant: ```c
void debug(char *format, ...) {
  va_list ap;
  static char debug_buf[1024];
  va_start(ap, format);
  vsnprintf(debug_buf, sizeof(debug_buf) - 2, format, ap);
  va_end(ap);
  if (strchr(debug_buf, '\n') == NULL)
    strcat(debug_buf, "\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<debug>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x3fe,%esi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type: string

tool: D11: 


assistant: ```c
void debug(char *format, ...) {
  va_list ap;
  static char debug_buf[1024];
  va_start(ap, format);
  vsnprintf(debug_buf, sizeof(debug_buf) - 2, format, ap);
  va_end(ap);
  if (strchr(debug_buf, '\n') == NULL)
    strcat(debug_buf, "\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<debug>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x3fe,%esi
  mov    %ebp,%ecx
  lea    D15(%rip),%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    %r12,%rdi
  lea    D16(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
datatype: string

tool: D16: 


assistant: ```c
void debug(char *format, ...) {
  va_list ap;
  static char debug_buf[1024];
  va_start(ap, format);
  vsnprintf(debug_buf, sizeof(debug_buf) - 2, format, ap);
  va_end(ap);
  if (strchr(debug_buf, '\n') == NULL)
    strcat(debug_buf, "\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<debug>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x3fe,%esi
  mov    %ebp,%ecx
  lea    D1(%rip),%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  mov    %r12,%rdi
  lea    D12(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
data_type: string

tool: D12: 


assistant: ```c
void debug(char *format, ...) {
  va_list ap;
  static char debug_buf[1024];
  va_start(ap, format);
  vsnprintf(debug_buf, sizeof(debug_buf) - 2, format, ap);
  va_end(ap);
  if (strchr(debug_buf, '\n') == NULL)
    strcat(debug_buf, "\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  imul   $0x9f65fb16,%eax,%eax
  sub    $0x1a4602e4,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L46:
  movl   $0x0,-0x14(%rbp)
  jmp    L20
L8:
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x1(%rax),%rdx
  movzbl -0x15(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L20:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jb     L8
  addl   $0x1,-0x10(%rbp)
L28:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L46
  mov    -0xc(%rbp),%eax
  lea    0x102a1fae(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        copy11 = *((char *)(&state[local2]) + 0);
        *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
        *((char *)(&state[local2]) + 1) = copy11;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 690137161UL) + 3876026213U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  imul   $0x9f65fb16,(%rdi),%eax
  sub    $0x1a4602e4,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%r9d
  test   %r9d,%r9d
  je     L34
  lea    0x4(%rsp),%r10
  lea    -0x1(%r9),%eax
  lea    0x8(%rsp,%rax,4),%rdi
  mov    $0x0,%r8d
L28:
  mov    %r10,%rax
L5:
  movzbl (%rax),%edx
  movzbl 0x1(%rax),%ecx
  mov    %cl,(%rax)
  mov    %dl,0x1(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L5
  add    $0x1,%r8d
  cmp    %r9d,%r8d
  jne    L28
L34:
  mov    0x4(%rsp),%eax
  add    $0x102a1fae,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        copy11 = *((char *)(&state[local2]) + 0);
        *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
        *((char *)(&state[local2]) + 1) = copy11;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 690137161UL) + 3876026213U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  imul   $0x9f65fb16,(%rdi),%eax
  sub    $0x1a4602e4,%eax
  mov    %eax,0x4(%rsp)
  test   %r9d,%r9d
  je     L3
  lea    -0x1(%r9),%eax
  lea    0x4(%rsp),%r10
  xor    %r8d,%r8d
  lea    0x8(%rsp,%rax,4),%rdi
  nopl   0x0(%rax)
L2:
  mov    %r10,%rax
  nopl   0x0(%rax,%rax,1)
L30:
  movzbl (%rax),%edx
  movzbl 0x1(%rax),%ecx
  add    $0x4,%rax
  mov    %cl,-0x4(%rax)
  mov    %dl,-0x3(%rax)
  cmp    %rdi,%rax
  jne    L30
  add    $0x1,%r8d
  cmp    %r9d,%r8d
  jne    L2
  mov    0x4(%rsp),%eax
L3:
  add    $0x102a1fae,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        copy11 = *((char *)(&state[local2]) + 0);
        *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
        *((char *)(&state[local2]) + 1) = copy11;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 690137161UL) + 3876026213U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L38
L12:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L4
  mov    -0x10(%rbp),%rax
  jmp    L32
L4:
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  addq   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    $0x0,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  const char *s1, *s2;
  for (s1 = s; *s1; s1++) {
    for (s2 = accept; *s2; s2++) {
      if (*s1 == *s2) {
        return (char *)s1;
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strpbrk>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L7
  movzbl (%rsi),%edi
L17:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  je     L26
L6:
  cmp    %r8b,%dl
  je     L3
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L6
L26:
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  jne    L17
  mov    $0x0,%eax
L3:
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  const char *s1, *s2;
  for (s1 = s; *s1; s1++) {
    for (s2 = accept; *s2; s2++) {
      if (*s1 == *s2) {
        return (char *)s1;
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L17
  movzbl (%rsi),%edi
L12:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  jne    L29
  jmp    L42
  nop
L56:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L42
L29:
  cmp    %r8b,%dl
  jne    L56
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L12
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  const char *s1, *s2;
  for (s1 = s; *s1; s1++) {
    for (s2 = accept; *s2; s2++) {
      if (*s1 == *s2) {
        return (char *)s1;
      }
    }
  }
  return 0;
}
```