ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_numberic>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_numeric_bin_to_dec@plt>
  mov    $0x0,%eax
  call   <test_numeric_bin_to_oct@plt>
  mov    $0x0,%eax
  call   <test_numeric_dec_to_bin@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_numberic() {
  test_numeric_bin_to_dec();
  test_numeric_bin_to_oct();
  test_numeric_dec_to_bin();
}
```
user: What is the c source code of the assembly code below?

```asm
<test_numberic>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_numeric_bin_to_dec@plt>
  xor    %eax,%eax
  call   <test_numeric_bin_to_oct@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <test_numeric_dec_to_bin@plt>
```

assistant: ```c
void test_numberic() {
  test_numeric_bin_to_dec();
  test_numeric_bin_to_oct();
  test_numeric_dec_to_bin();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_numberic>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_numeric_bin_to_dec@plt>
  xor    %eax,%eax
  call   <test_numeric_bin_to_oct@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <test_numeric_dec_to_bin@plt>
```

assistant: ```c
void test_numberic() {
  test_numeric_bin_to_dec();
  test_numeric_bin_to_oct();
  test_numeric_dec_to_bin();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L14:
  mov    -0x4(%rbp),%eax
  shl    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x1c(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int hash_fn(const char *key, int table_size) {
  unsigned int hashed = 0;
  while (*key) {
    hashed = (hashed << 7) ^ *key++;
  }
  return hashed % table_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_fn>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L10
  mov    $0x0,%eax
L2:
  shl    $0x7,%eax
  add    $0x1,%rdi
  movsbl %dl,%edx
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L2
L8:
  mov    $0x0,%edx
  div    %esi
  mov    %edx,%eax
  ret
L10:
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
int hash_fn(const char *key, int table_size) {
  unsigned int hashed = 0;
  while (*key) {
    hashed = (hashed << 7) ^ *key++;
  }
  return hashed % table_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_fn>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L14
  xor    %eax,%eax
  nopl   (%rax)
L13:
  shl    $0x7,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L13
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hash_fn(const char *key, int table_size) {
  unsigned int hashed = 0;
  while (*key) {
    hashed = (hashed << 7) ^ *key++;
  }
  return hashed % table_size;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash_fn>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L5
  xor    %eax,%eax
  nopl   (%rax)
L18:
  shl    $0x7,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L18
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hash_fn(const char *key, int table_size) {
  unsigned int hashed = 0;
  while (*key) {
    hashed = (hashed << 7) ^ *key++;
  }
  return hashed % table_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<blklen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    $0x0,%ebx
  jmp    L7
L12:
  add    $0x1,%ebx
L7:
  mov    %rax,%rdx
  lea    0x8(%rdx),%rax
  mov    (%rdx),%rdx
  test   %rdx,%rdx
  jne    L12
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
blklen(av) register char **av;
{
  register int i = 0;
  while (*av++)
    i++;
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<blklen>:
  endbr64
  lea    0x8(%rdi),%rax
  cmpq   $0x0,(%rdi)
  je     L21
  mov    $0x0,%edx
L11:
  add    $0x1,%edx
  add    $0x8,%rax
  cmpq   $0x0,-0x8(%rax)
  jne    L11
L3:
  mov    %edx,%eax
  ret
L21:
  mov    $0x0,%edx
  jmp    L3
```

assistant: ```c
blklen(av) register char **av;
{
  register int i = 0;
  while (*av++)
    i++;
  return (i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<blklen>:
  endbr64
  xor    %r8d,%r8d
  cmpq   $0x0,(%rdi)
  lea    0x8(%rdi),%rax
  je     L11
  nopl   0x0(%rax)
L3:
  add    $0x8,%rax
  add    $0x1,%r8d
  cmpq   $0x0,-0x8(%rax)
  jne    L3
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
blklen(av) register char **av;
{
  register int i = 0;
  while (*av++)
    i++;
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<blklen>:
  endbr64
  xor    %r8d,%r8d
  cmpq   $0x0,(%rdi)
  lea    0x8(%rdi),%rax
  je     L15
  nopl   0x0(%rax)
L19:
  add    $0x8,%rax
  add    $0x1,%r8d
  cmpq   $0x0,-0x8(%rax)
  jne    L19
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
blklen(av) register char **av;
{
  register int i = 0;
  while (*av++)
    i++;
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<g_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void g_error() {
  int args;
  args = 3;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<g_error>:
  endbr64
  ret
```

assistant: ```c
void g_error() {
  int args;
  args = 3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<g_error>:
  endbr64
  ret
```

assistant: ```c
void g_error() {
  int args;
  args = 3;
}
```
user: What is the c source code of the assembly code below:

```asm
<g_error>:
  endbr64
  ret
```

assistant: ```c
void g_error() {
  int args;
  args = 3;
}
```
user: What is the c source code of the assembly code below:

```asm
<array_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x2,-0x4(%rbp)
  jle    L19
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int array_sum(int arr[3]) {
  int sum = 0;
  for (int i = 0; i < 3; i++) {
    sum += arr[i];
  }
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<array_sum>:
  endbr64
  mov    0x4(%rdi),%eax
  add    (%rdi),%eax
  add    0x8(%rdi),%eax
  ret
```

assistant: ```c
int array_sum(int arr[3]) {
  int sum = 0;
  for (int i = 0; i < 3; i++) {
    sum += arr[i];
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<array_sum>:
  endbr64
  mov    0x4(%rdi),%eax
  add    (%rdi),%eax
  add    0x8(%rdi),%eax
  ret
```

assistant: ```c
int array_sum(int arr[3]) {
  int sum = 0;
  for (int i = 0; i < 3; i++) {
    sum += arr[i];
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<array_sum>:
  endbr64
  mov    0x4(%rdi),%eax
  add    (%rdi),%eax
  add    0x8(%rdi),%eax
  ret
```

assistant: ```c
int array_sum(int arr[3]) {
  int sum = 0;
  for (int i = 0; i < 3; i++) {
    sum += arr[i];
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L1
L10:
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skipspace(char *str) {
  while (isspace(*str))
    ++str;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skipspace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L13
L3:
  add    $0x1,%rbx
L13:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skipspace(char *str) {
  while (isspace(*str))
    ++str;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skipspace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%r12
L7:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L11
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipspace(char *str) {
  while (isspace(*str))
    ++str;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<skipspace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%r12
L7:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipspace(char *str) {
  while (isspace(*str))
    ++str;
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_striter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L4
L12:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  while (*s != '\0')
    f(s++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_striter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x0,(%rdi)
  je     L2
L10:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L10
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  while (*s != '\0')
    f(s++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_striter>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L2
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L1:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  while (*s != '\0')
    f(s++);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_striter>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L7:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L10:
  ret
```

assistant: ```c
void ft_striter(char *s, void (*f)(char *)) {
  while (*s != '\0')
    f(s++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x12c,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L16
L12:
  mov    -0x14(%rbp),%eax
  lea    -0x20(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  add    %eax,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L12
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: %3d %6d


assistant: ```c
int main(int argc, char *argv[]) {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%3d %6d\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xffffff60,%ebp
  mov    $0x0,%ebx
  lea    D9(%rip),%r12
L9:
  movslq %ebp,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  add    $0x64,%ebp
  cmp    $0x140,%ebx
  jne    L9
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: %3d %6d


assistant: ```c
int main(int argc, char *argv[]) {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%3d %6d\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffff60,%r12d
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%eax
  add    $0x14,%ebx
  add    $0x64,%r12d
  sar    $0x21,%rdx
  sub    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: %3d %6d


assistant: ```c
int main(int argc, char *argv[]) {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%3d %6d\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffff60,%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%eax
  add    $0x14,%ebx
  add    $0x64,%r12d
  sar    $0x21,%rdx
  sub    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D2: %3d %6d


assistant: ```c
int main(int argc, char *argv[]) {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%3d %6d\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compute_all_bingham_dF3_3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  movsd  %xmm4,-0x48(%rbp)
  movsd  %xmm5,-0x50(%rbp)
  movsd  %xmm6,-0x58(%rbp)
  movsd  %xmm7,-0x60(%rbp)
  movl   $0x0,-0x1c(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L18
L23:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L82
L46:
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L13
L52:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L77
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L77
  movsd  -0x8(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <bingham_dF3_3d@plt>
  movq   %xmm0,%rax
  jmp    L16
L77:
  mov    D45(%rip),%rax
L16:
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L13:
  movsd  -0x48(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jae    L52
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L82:
  movsd  -0x30(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jae    L46
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movsd  -0x8(%rbp),%xmm0
  addsd  0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L18:
  movsd  -0x60(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jae    L23
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D42
type: string
name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D45
type: f64
name: disassemble_data
arguments: label: D4
type: string
name: disassemble_data
arguments: label: D54
type: string
name: disassemble_data
arguments: label: D31
type: string

tool: D42: dF3 = [];


tool: D0: dF3(:,:,%d) = [ ...


tool: D45: 0

tool: D4: %f 

tool: D54: ; ...

tool: D31: ];


assistant: ```c
void compute_all_bingham_dF3_3d(double z1_min, double z1_max, double z1_step, double z2_min, double z2_max, double z2_step, double z3_min, double z3_max, double z3_step) {
  double z1, z2, z3;
  int k = 0;
  printf("dF3 = [];\n\n");
  for (z3 = z3_min; z3 <= z3_max; z3 += z3_step) {
    k++;
    printf("dF3(:,:,%d) = [ ...\n", k);
    for (z1 = z1_min; z1 <= z1_max; z1 += z1_step) {
      for (z2 = z2_min; z2 <= z2_max; z2 += z2_step)
        printf("%f ", z1 <= z2 && z2 <= z3 ? bingham_dF3_3d(z1, z2, z3) : 0.0);
      printf("; ...\n");
    }
    printf("];\n\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compute_all_bingham_dF3_3d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  movsd  %xmm0,0x48(%rsp)
  movsd  %xmm1,0x30(%rsp)
  movsd  %xmm2,0x38(%rsp)
  movsd  %xmm3,0x40(%rsp)
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm5,0x20(%rsp)
  movsd  %xmm6,0x28(%rsp)
  movq   %xmm7,%r15
  lea    D41(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r13d
  lea    D1(%rip),%r14
  mov    D44(%rip),%r12
  movq   %r15,%xmm1
  comisd 0x28(%rsp),%xmm1
  jae    L34
L39:
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm3
  addsd  0x20(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
  movsd  0x18(%rsp),%xmm7
  comisd %xmm3,%xmm7
  jb     L41
L81:
  movsd  0x8(%rsp),%xmm4
  movq   %rbp,%xmm0
  comisd 0x10(%rsp),%xmm4
  jb     L72
  movsd  0x28(%rsp),%xmm1
  movq   %r12,%xmm0
  comisd %xmm4,%xmm1
  jb     L72
  movapd %xmm1,%xmm2
  movapd %xmm4,%xmm1
  movsd  0x10(%rsp),%xmm0
  call   <bingham_dF3_3d@plt>
  jmp    L72
L41:
  lea    D55(%rip),%rdi
  call   <puts@plt>
  movsd  0x10(%rsp),%xmm2
  addsd  0x38(%rsp),%xmm2
  movsd  %xmm2,0x10(%rsp)
  movsd  0x30(%rsp),%xmm1
  comisd %xmm2,%xmm1
  jb     L33
L107:
  movsd  0x40(%rsp),%xmm2
  movsd  %xmm2,0x8(%rsp)
  movsd  0x18(%rsp),%xmm1
  comisd %xmm2,%xmm1
  jae    L81
  jmp    L41
L33:
  lea    D42(%rip),%rdi
  call   <puts@plt>
  movsd  0x28(%rsp),%xmm1
  addsd  0x90(%rsp),%xmm1
  movsd  %xmm1,0x28(%rsp)
  movq   %r15,%xmm7
  comisd %xmm1,%xmm7
  jb     L39
L34:
  add    $0x1,%r13d
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  0x48(%rsp),%xmm5
  movsd  %xmm5,0x10(%rsp)
  mov    D44(%rip),%rbp
  lea    D58(%rip),%rbx
  movsd  0x30(%rsp),%xmm6
  comisd %xmm5,%xmm6
  jae    L107
  jmp    L33
```

tool_calls: name: extract_symbolic_data
arguments: label: D41
type: string
name: extract_symbolic_data
arguments: label: D1
type: string
name: extract_symbolic_data
arguments: label: D44
type: f64
name: extract_symbolic_data
arguments: label: D55
type: string
name: extract_symbolic_data
arguments: label: D42
type: string
name: extract_symbolic_data
arguments: label: D58
type: string

tool: D41: dF3 = [];


tool: D1: dF3(:,:,%d) = [ ...


tool: D44: 0

tool: D55: ; ...

tool: D42: ];


tool: D58: %f 

assistant: ```c
void compute_all_bingham_dF3_3d(double z1_min, double z1_max, double z1_step, double z2_min, double z2_max, double z2_step, double z3_min, double z3_max, double z3_step) {
  double z1, z2, z3;
  int k = 0;
  printf("dF3 = [];\n\n");
  for (z3 = z3_min; z3 <= z3_max; z3 += z3_step) {
    k++;
    printf("dF3(:,:,%d) = [ ...\n", k);
    for (z1 = z1_min; z1 <= z1_max; z1 += z1_step) {
      for (z2 = z2_min; z2 <= z2_max; z2 += z2_step)
        printf("%f ", z1 <= z2 && z2 <= z3 ? bingham_dF3_3d(z1, z2, z3) : 0.0);
      printf("; ...\n");
    }
    printf("];\n\n");
  }
}
```