ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x1c7,-0xc(%rbp)
  movl   $0x183,-0x8(%rbp)
  movl   $0x3b,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x3b,-0x14(%rbp)
  jle    L108
  cmpl   $0x1c6,-0x14(%rbp)
  jle    L108
  cmpl   $0x1c6,-0x14(%rbp)
  jg     L108
  cmpl   $0x0,-0x14(%rbp)
  js     L108
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    $0x3b,%eax
  jle    L108
  cmpl   $0x1c7,-0xc(%rbp)
  jne    L108
  cmpl   $0x183,-0x8(%rbp)
  jne    L108
  cmpl   $0x3b,-0x4(%rbp)
  jne    L108
  mov    $0x1,%eax
  jmp    L45
L108:
  mov    $0x0,%eax
L45:
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  jmp    L90
L165:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L90:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L165
  movl   $0x0,-0x14(%rbp)
  jmp    L146
L84:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L146:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L84
  movl   $0x0,-0x14(%rbp)
  jmp    L124
L85:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L124:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L85
  movl   $0x0,-0x14(%rbp)
  jmp    L89
L191:
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L89:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L191
  movl   $0x0,-0x14(%rbp)
  jmp    L150
L170:
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L150:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L170
  movl   $0x0,-0x14(%rbp)
  jmp    L69
L106:
  cmpl   $0x0,-0x10(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L69:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L106
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main_test() {
  int n0 = 455;
  int n1 = 387;
  int n2 = 59;
  int i = 0;
  int k = 0;
  __ESBMC_assume(i > 59 && i >= 455 && i < 455 && i >= 0 && i + k > 59 && n0 == 455 && n1 == 387 && n2 == 59);
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k--;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    assert(k > 0);
    i++;
    k--;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main_test>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1c7,%eax
L38:
  sub    $0x1,%eax
  jne    L38
  mov    $0x183,%eax
L46:
  sub    $0x1,%eax
  jne    L46
  mov    $0x3b,%eax
L2:
  sub    $0x1,%eax
  jne    L2
  mov    $0x3b,%eax
L24:
  sub    $0x1,%eax
  jne    L24
  mov    $0x183,%eax
L6:
  sub    $0x1,%eax
  jne    L6
  mov    $0x1c7,%ebx
L3:
  test   %ebx,%ebx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L3
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main_test() {
  int n0 = 455;
  int n1 = 387;
  int n2 = 59;
  int i = 0;
  int k = 0;
  __ESBMC_assume(i > 59 && i >= 455 && i < 455 && i >= 0 && i + k > 59 && n0 == 455 && n1 == 387 && n2 == 59);
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k--;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    assert(k > 0);
    i++;
    k--;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main_test>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  mov    $0x1c7,%ebx
  call   <__ESBMC_assume@plt>
  nopl   0x0(%rax)
L6:
  mov    $0x1,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L6
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main_test() {
  int n0 = 455;
  int n1 = 387;
  int n2 = 59;
  int i = 0;
  int k = 0;
  __ESBMC_assume(i > 59 && i >= 455 && i < 455 && i >= 0 && i + k > 59 && n0 == 455 && n1 == 387 && n2 == 59);
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k--;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    assert(k > 0);
    i++;
    k--;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main_test>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  mov    $0x1c7,%ebx
  call   <__ESBMC_assume@plt>
  nopl   0x0(%rax)
L6:
  mov    $0x1,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L6
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main_test() {
  int n0 = 455;
  int n1 = 387;
  int n2 = 59;
  int i = 0;
  int k = 0;
  __ESBMC_assume(i > 59 && i >= 455 && i < 455 && i >= 0 && i + k > 59 && n0 == 455 && n1 == 387 && n2 == 59);
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k--;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    assert(k > 0);
    i++;
    k--;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L23
L11:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jle    L12
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L12:
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x8(%rbp)
  jb     L11
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t hash(const char *str) {
  uint64_t h = 0;
  for (uint8_t i = 0; i < strlen(str); i++) {
    if (str[i] > 0xd) {
      h = ((h << 5) + h) + str[i];
    }
  }
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdx
  lea    (%rbx,%rax,1),%rdi
  mov    $0x0,%eax
  jmp    L27
L28:
  add    $0x1,%rdx
L27:
  cmp    %rdi,%rdx
  je     L26
  movzbl (%rdx),%ecx
  cmp    $0xd,%cl
  jle    L28
  mov    %eax,%esi
  shl    $0x5,%esi
  add    %esi,%eax
  movsbl %cl,%ecx
  add    %ecx,%eax
  jmp    L28
L26:
  pop    %rbx
  ret
```

assistant: ```c
uint64_t hash(const char *str) {
  uint64_t h = 0;
  for (uint8_t i = 0; i < strlen(str); i++) {
    if (str[i] > 0xd) {
      h = ((h << 5) + h) + str[i];
    }
  }
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  lea    (%rbx,%rax,1),%rcx
  xor    %eax,%eax
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl (%rdi),%edx
  cmp    $0xd,%dl
  jle    L2
  mov    %eax,%esi
  shl    $0x5,%esi
  add    %esi,%eax
  add    %edx,%eax
L2:
  add    $0x1,%rdi
L13:
  cmp    %rcx,%rdi
  jne    L17
  pop    %rbx
  ret
```

assistant: ```c
uint64_t hash(const char *str) {
  uint64_t h = 0;
  for (uint8_t i = 0; i < strlen(str); i++) {
    if (str[i] > 0xd) {
      h = ((h << 5) + h) + str[i];
    }
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L26
  lea    (%rbx,%rax,1),%rcx
  mov    %rbx,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L28:
  movsbl (%rdi),%edx
  cmp    $0xd,%dl
  jle    L16
  mov    %eax,%esi
  shl    $0x5,%esi
  add    %esi,%eax
  add    %edx,%eax
L16:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L28
  pop    %rbx
  ret
  nopl   0x0(%rax)
L26:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint64_t hash(const char *str) {
  uint64_t h = 0;
  for (uint8_t i = 0; i < strlen(str); i++) {
    if (str[i] > 0xd) {
      h = ((h << 5) + h) + str[i];
    }
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CleanLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L19:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L31
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L5
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L5:
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void CleanLine(char *buff) {
  int j, l;
  l = strlen(buff);
  for (j = 0; j < l; j++) {
    if ((buff[j] == '\n') || (buff[j] == '\r'))
      buff[j] = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CleanLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L38
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  jmp    L57
L8:
  movb   $0x0,(%rcx)
L55:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L38
L57:
  mov    %rdx,%rcx
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L8
  cmp    $0xd,%al
  jne    L55
  jmp    L8
L38:
  pop    %rbx
  ret
```

assistant: ```c
void CleanLine(char *buff) {
  int j, l;
  l = strlen(buff);
  for (j = 0; j < l; j++) {
    if ((buff[j] == '\n') || (buff[j] == '\r'))
      buff[j] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CleanLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L19
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rdx
  jmp    L26
  xchg   %ax,%ax
L38:
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  je     L19
L26:
  movzbl (%rdi),%eax
  cmp    $0xa,%al
  je     L23
  cmp    $0xd,%al
  jne    L38
L23:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  jne    L26
L19:
  pop    %rbx
  ret
```

assistant: ```c
void CleanLine(char *buff) {
  int j, l;
  l = strlen(buff);
  for (j = 0; j < l; j++) {
    if ((buff[j] == '\n') || (buff[j] == '\r'))
      buff[j] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CleanLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L1
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rdx
  jmp    L52
  xchg   %ax,%ax
L57:
  add    $0x1,%rdi
  cmp    %rdi,%rdx
  je     L1
L52:
  movzbl (%rdi),%eax
  cmp    $0xa,%al
  je     L59
  cmp    $0xd,%al
  jne    L57
L59:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  cmp    %rdi,%rdx
  jne    L52
L1:
  pop    %rbx
  ret
```

assistant: ```c
void CleanLine(char *buff) {
  int j, l;
  l = strlen(buff);
  for (j = 0; j < l; j++) {
    if ((buff[j] == '\n') || (buff[j] == '\r'))
      buff[j] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<warp_pointer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <XOpenDisplay@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <XRootWindow@plt>
  mov    %eax,%edi
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x18(%rbp),%edx
  push   %rdx
  mov    -0x14(%rbp),%edx
  push   %rdx
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <XWarpPointer@plt>
  add    $0x20,%rsp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <XFlush@plt>
  nop
  leave
  ret
```

assistant: ```c
void warp_pointer(int x, int y) {
  Display *dpy = XOpenDisplay(0);
  XWarpPointer(dpy, None, XRootWindow(dpy, 0), 0, 0, 0, 0, x, y);
  XFlush(dpy);
}
```
user: What is the c source code of the assembly code below:

```asm
<warp_pointer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%edi
  call   <XOpenDisplay@plt>
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <XRootWindow@plt>
  mov    %eax,%edx
  sub    $0x8,%rsp
  push   %r12
  push   %rbp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <XWarpPointer@plt>
  add    $0x20,%rsp
  mov    %rbx,%rdi
  call   <XFlush@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void warp_pointer(int x, int y) {
  Display *dpy = XOpenDisplay(0);
  XWarpPointer(dpy, None, XRootWindow(dpy, 0), 0, 0, 0, 0, x, y);
  XFlush(dpy);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<warp_pointer>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  call   <XOpenDisplay@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <XRootWindow@plt>
  sub    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %r9d,%r9d
  mov    %eax,%edx
  mov    D6(%rip),%rax
  push   %r12
  xor    %r8d,%r8d
  push   %rbx
  xor    %ecx,%ecx
  push   $0x0
  mov    (%rax),%esi
  call   <XWarpPointer@plt>
  add    $0x20,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <XFlush@plt>
```

assistant: ```c
void warp_pointer(int x, int y) {
  Display *dpy = XOpenDisplay(0);
  XWarpPointer(dpy, None, XRootWindow(dpy, 0), 0, 0, 0, 0, x, y);
  XFlush(dpy);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<warp_pointer>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  call   <XOpenDisplay@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <XRootWindow@plt>
  sub    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %r9d,%r9d
  mov    %eax,%edx
  mov    D7(%rip),%rax
  push   %r12
  xor    %r8d,%r8d
  push   %rbx
  xor    %ecx,%ecx
  push   $0x0
  mov    (%rax),%esi
  call   <XWarpPointer@plt>
  add    $0x20,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <XFlush@plt>
```

assistant: ```c
void warp_pointer(int x, int y) {
  Display *dpy = XOpenDisplay(0);
  XWarpPointer(dpy, None, XRootWindow(dpy, 0), 0, 0, 0, 0, x, y);
  XFlush(dpy);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_human_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x60(%rbp)
  cmpq   $0x0,-0x68(%rbp)
  jne    L104
  mov    $0x0,%eax
  jmp    L100
L104:
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x58(%rbp)
  cmpq   $0x0,-0x58(%rbp)
  je     L11
  cmpq   $0x3f,-0x58(%rbp)
  ja     L11
  mov    -0x58(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x47,%al
  jne    L41
  movq   $0x40000000,-0x60(%rbp)
  jmp    L32
L41:
  mov    -0x58(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x4d,%al
  jne    L86
  movq   $0x100000,-0x60(%rbp)
  jmp    L32
L86:
  mov    -0x58(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x4b,%al
  jne    L32
  movq   $0x400,-0x60(%rbp)
L32:
  cmpq   $0x0,-0x60(%rbp)
  je     L117
  mov    -0x58(%rbp),%rdx
  mov    -0x68(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  imul   -0x60(%rbp),%rax
  jmp    L100
L117:
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  jmp    L100
L11:
  mov    -0x60(%rbp),%rax
L100:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
long parse_human_number(char *num) {
  long ret = 0;
  char buf[64];
  if (!num)
    return 0;
  size_t l = strlen(num);
  if (l && l < sizeof(buf)) {
    if (num[l - 1] == 'G')
      ret = 1024 * 1024 * 1024;
    else if (num[l - 1] == 'M')
      ret = 1024 * 1024;
    else if (num[l - 1] == 'K')
      ret = 1024;
    if (ret) {
      memcpy(buf, num, l);
      buf[l] = 0;
      return atol(buf) * ret;
    }
    return atol(num);
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_human_number>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L95
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    -0x1(%rax),%rdx
  mov    $0x0,%eax
  cmp    $0x3e,%rdx
  ja     L61
  movzbl -0x1(%rbx,%rbp,1),%eax
  cmp    $0x47,%al
  je     L98
  cmp    $0x4d,%al
  je     L25
  mov    $0x400,%r13d
  cmp    $0x4b,%al
  jne    L34
L18:
  mov    %rsp,%r12
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rsp,%rbp,1)
  mov    %r12,%rdi
  call   <atol@plt>
  imul   %r13,%rax
L61:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    %rbx,%rdi
  call   <atol@plt>
  jmp    L61
L98:
  mov    $0x40000000,%r13d
  jmp    L18
L25:
  mov    $0x100000,%r13d
  jmp    L18
L95:
  mov    $0x0,%eax
  jmp    L61
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long parse_human_number(char *num) {
  long ret = 0;
  char buf[64];
  if (!num)
    return 0;
  size_t l = strlen(num);
  if (l && l < sizeof(buf)) {
    if (num[l - 1] == 'G')
      ret = 1024 * 1024 * 1024;
    else if (num[l - 1] == 'M')
      ret = 1024 * 1024;
    else if (num[l - 1] == 'K')
      ret = 1024;
    if (ret) {
      memcpy(buf, num, l);
      buf[l] = 0;
      return atol(buf) * ret;
    }
    return atol(num);
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_human_number>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    -0x1(%rax),%rax
  cmp    $0x3e,%rax
  ja     L0
  movzbl -0x1(%rbp,%rbx,1),%eax
  cmp    $0x47,%al
  je     L85
  cmp    $0x4d,%al
  je     L75
  mov    $0x400,%r13d
  cmp    $0x4b,%al
  jne    L41
L63:
  mov    %rsp,%r12
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <atol@plt>
  imul   %r13,%rax
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
L37:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L41:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x58,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <atol@plt>
  nopw   0x0(%rax,%rax,1)
L75:
  mov    $0x100000,%r13d
  jmp    L63
L85:
  mov    $0x40000000,%r13d
  jmp    L63
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long parse_human_number(char *num) {
  long ret = 0;
  char buf[64];
  if (!num)
    return 0;
  size_t l = strlen(num);
  if (l && l < sizeof(buf)) {
    if (num[l - 1] == 'G')
      ret = 1024 * 1024 * 1024;
    else if (num[l - 1] == 'M')
      ret = 1024 * 1024;
    else if (num[l - 1] == 'K')
      ret = 1024;
    if (ret) {
      memcpy(buf, num, l);
      buf[l] = 0;
      return atol(buf) * ret;
    }
    return atol(num);
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_human_number>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L93
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    -0x1(%rax),%rax
  cmp    $0x3e,%rax
  ja     L93
  movzbl -0x1(%rbp,%rbx,1),%eax
  cmp    $0x47,%al
  je     L24
  cmp    $0x4d,%al
  je     L94
  mov    $0x400,%r13d
  cmp    $0x4b,%al
  jne    L98
L2:
  mov    %rsp,%r12
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <atol@plt>
  imul   %r13,%rax
  jmp    L66
  cs nopw 0x0(%rax,%rax,1)
L93:
  xor    %eax,%eax
L66:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L65
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L98:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x58,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <atol@plt>
  nopw   0x0(%rax,%rax,1)
L94:
  mov    $0x100000,%r13d
  jmp    L2
L24:
  mov    $0x40000000,%r13d
  jmp    L2
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long parse_human_number(char *num) {
  long ret = 0;
  char buf[64];
  if (!num)
    return 0;
  size_t l = strlen(num);
  if (l && l < sizeof(buf)) {
    if (num[l - 1] == 'G')
      ret = 1024 * 1024 * 1024;
    else if (num[l - 1] == 'M')
      ret = 1024 * 1024;
    else if (num[l - 1] == 'K')
      ret = 1024;
    if (ret) {
      memcpy(buf, num, l);
      buf[l] = 0;
      return atol(buf) * ret;
    }
    return atol(num);
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<wdelch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <_wputc@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_wcursback@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int wdelch(WINDOW *win) {
  _wputc(win, ' ', 1);
  _wcursback(win);
  return OK;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wdelch>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edx
  mov    $0x20,%esi
  call   <_wputc@plt>
  mov    %rbx,%rdi
  call   <_wcursback@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  pop    %rbx
  ret
```

assistant: ```c
int wdelch(WINDOW *win) {
  _wputc(win, ' ', 1);
  _wcursback(win);
  return OK;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wdelch>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  mov    %rdi,%rbp
  mov    $0x20,%esi
  call   <_wputc@plt>
  mov    %rbp,%rdi
  call   <_wcursback@plt>
  mov    D2(%rip),%rax
  pop    %rbp
  mov    (%rax),%eax
  ret
```

assistant: ```c
int wdelch(WINDOW *win) {
  _wputc(win, ' ', 1);
  _wcursback(win);
  return OK;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wdelch>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  mov    %rdi,%rbp
  mov    $0x20,%esi
  call   <_wputc@plt>
  mov    %rbp,%rdi
  call   <_wcursback@plt>
  mov    D5(%rip),%rax
  pop    %rbp
  mov    (%rax),%eax
  ret
```

assistant: ```c
int wdelch(WINDOW *win) {
  _wputc(win, ' ', 1);
  _wcursback(win);
  return OK;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strleft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *strleft(char *val, int cnt) {
  val[cnt] = '\0';
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strleft>:
  endbr64
  mov    %rdi,%rax
  movslq %esi,%rsi
  movb   $0x0,(%rdi,%rsi,1)
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *strleft(char *val, int cnt) {
  val[cnt] = '\0';
  return val;
}
```