ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L2
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %rax,%rbp
  test   %al,%al
  jle    L23
  xor    %eax,%eax
  movsbl %bpl,%ebp
  call   <exploit@plt>
  mov    %ebp,%esi
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D47(%rip),%rsi
  lea    D65(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  mov    %rsp,%r13
  mov    %rax,%rcx
  mov    %ebp,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <vuln@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L36:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L60
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  lea    D54(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L36
L18:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L36
L23:
  movsbl %al,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L36
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D58
type_guessed: string
name: unpack_data
arguments: tag: D47
type_guessed: string
name: unpack_data
arguments: tag: D65
type_guessed: string
name: unpack_data
arguments: tag: D23
type_guessed: string
name: unpack_data
arguments: tag: D54
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string

tool: D58: Reading %d bytes from file


tool: D47: r

tool: D65: overflow.txt

tool: D23: Control has returned to main()
Normal operation.

tool: D54: Missing first argument (integer).
Using number 24 as the first argument seems interesting.
Exiting...

tool: D16: Input file does not exist. Exiting...

tool: D13: Incorrect first argument (%d). Exiting...


assistant: ```c
int main(int argc, char **argv) {
  char count;
  FILE *f;
  char overflow[64];
  if (argc < 2) {
    printf("Missing first argument (integer).\nUsing number 24 as the first argument seems interesting.\nExiting...\n");
    return 0;
  }
  count = (char)atoi(argv[1]);
  if (!(count > 0)) {
    printf("Incorrect first argument (%d). Exiting...\n", count);
    return 0;
  }
  exploit();
  printf("Reading %d bytes from file\n", count);
  f = fopen("overflow.txt", "r");
  if (f != NULL) {
    fread(overflow, sizeof(char), count, f);
    fclose(f);
    vuln(overflow, count);
  } else {
    printf("Input file does not exist. Exiting...\n");
    return 0;
  }
  printf("Control has returned to main()\nNormal operation.\n");
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L56
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %rax,%rbp
  test   %al,%al
  jle    L37
  xor    %eax,%eax
  movsbl %bpl,%ebp
  call   <exploit@plt>
  mov    %ebp,%esi
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D20(%rip),%rsi
  lea    D62(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rsp,%r13
  mov    %rax,%rcx
  mov    %ebp,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <vuln@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L10:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L60
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L56:
  lea    D66(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L10
L0:
  lea    D65(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L10
L37:
  movsbl %al,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L10
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D53
type_infered: string
name: read_data
arguments: data_tag: D20
type_infered: string
name: read_data
arguments: data_tag: D62
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D66
type_infered: string
name: read_data
arguments: data_tag: D65
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string

tool: D53: Reading %d bytes from file


tool: D20: r

tool: D62: overflow.txt

tool: D12: Control has returned to main()
Normal operation.

tool: D66: Missing first argument (integer).
Using number 24 as the first argument seems interesting.
Exiting...

tool: D65: Input file does not exist. Exiting...

tool: D13: Incorrect first argument (%d). Exiting...


assistant: ```c
int main(int argc, char **argv) {
  char count;
  FILE *f;
  char overflow[64];
  if (argc < 2) {
    printf("Missing first argument (integer).\nUsing number 24 as the first argument seems interesting.\nExiting...\n");
    return 0;
  }
  count = (char)atoi(argv[1]);
  if (!(count > 0)) {
    printf("Incorrect first argument (%d). Exiting...\n", count);
    return 0;
  }
  exploit();
  printf("Reading %d bytes from file\n", count);
  f = fopen("overflow.txt", "r");
  if (f != NULL) {
    fread(overflow, sizeof(char), count, f);
    fclose(f);
    vuln(overflow, count);
  } else {
    printf("Input file does not exist. Exiting...\n");
    return 0;
  }
  printf("Control has returned to main()\nNormal operation.\n");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SwapBuffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L68
  cmpq   $0x0,-0x20(%rbp)
  je     L68
  mov    $0x1,%eax
  jmp    L19
L68:
  mov    $0x0,%eax
L19:
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x24(%rbp)
  je     L106
  cmpl   $0x1,-0x24(%rbp)
  je     L108
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  jmp    L74
L108:
  mov    $0x0,%eax
L74:
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L5
L17:
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L28:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L28
  jmp    L5
L106:
  nop
L5:
  leave
  ret
```

assistant: ```c
void SwapBuffer(char *p1, char *p2, unsigned len) {
  char temp;
  char *buf;
  unsigned i;
  assert(p1 && p2);
  if (!len)
    return;
  buf = (len == 1) ? 0 : (char *)malloc(len);
  if (buf) {
    memcpy(buf, p1, len);
    memmove(p1, p2, len);
    memcpy(p2, buf, len);
    free(buf);
  } else {
    for (i = 0; i < len; i++) {
      temp = p1[i];
      p1[i] = p2[i];
      p2[i] = temp;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SwapBuffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  test   %r12d,%r12d
  je     L26
  cmp    $0x1,%r12d
  jne    L13
L28:
  mov    %r12d,%esi
  mov    $0x0,%eax
L47:
  movzbl 0x0(%rbp,%rax,1),%edx
  movzbl (%rbx,%rax,1),%ecx
  mov    %cl,0x0(%rbp,%rax,1)
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L47
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L28
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L26
```

assistant: ```c
void SwapBuffer(char *p1, char *p2, unsigned len) {
  char temp;
  char *buf;
  unsigned i;
  assert(p1 && p2);
  if (!len)
    return;
  buf = (len == 1) ? 0 : (char *)malloc(len);
  if (buf) {
    memcpy(buf, p1, len);
    memmove(p1, p2, len);
    memcpy(p2, buf, len);
    free(buf);
  } else {
    for (i = 0; i < len; i++) {
      temp = p1[i];
      p1[i] = p2[i];
      p2[i] = temp;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<SwapBuffer>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  test   %r13d,%r13d
  je     L11
  cmp    $0x1,%r13d
  jne    L19
  movzbl (%r12),%eax
  movzbl 0x0(%rbp),%edx
  mov    %dl,(%r12)
  mov    %al,0x0(%rbp)
L11:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L19:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L0
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  mov    %rbp,%rdi
  mov    %r13d,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <free@plt>
  nopl   (%rax)
L0:
  mov    %r13d,%edx
  xor    %eax,%eax
  nopl   (%rax)
L14:
  movzbl (%r12,%rax,1),%ecx
  movzbl 0x0(%rbp,%rax,1),%esi
  mov    %sil,(%r12,%rax,1)
  mov    %cl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L14
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void SwapBuffer(char *p1, char *p2, unsigned len) {
  char temp;
  char *buf;
  unsigned i;
  assert(p1 && p2);
  if (!len)
    return;
  buf = (len == 1) ? 0 : (char *)malloc(len);
  if (buf) {
    memcpy(buf, p1, len);
    memmove(p1, p2, len);
    memcpy(p2, buf, len);
    free(buf);
  } else {
    for (i = 0; i < len; i++) {
      temp = p1[i];
      p1[i] = p2[i];
      p2[i] = temp;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L6
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
L6:
  leave
  ret
```

assistant: ```c
char *gstrdup(const char *str) {
  if (!str)
    return NULL;
  return strdup(str);
}
```
user: What is the c source code of the assembly code below?

```asm
<gstrdup>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <strdup@plt>
  add    $0x8,%rsp
  ret
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *gstrdup(const char *str) {
  if (!str)
    return NULL;
  return strdup(str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gstrdup>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <strdup@plt>
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *gstrdup(const char *str) {
  if (!str)
    return NULL;
  return strdup(str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gstrdup>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <strdup@plt>
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *gstrdup(const char *str) {
  if (!str)
    return NULL;
  return strdup(str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x19(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L15:
  movl   $0x0,-0xc(%rbp)
  jmp    L44
L3:
  movzbl -0x19(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L44:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: %d %d
%c

assistant: ```c
int main() {
  int n, m;
  char c;
  scanf("%d %d\n%c", &n, &m, &c);
  for (int i = 0; i < n; ++i) {
    for (int j = 0; j < m; ++j)
      printf("%c", c);
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
  cmpl   $0x0,0x10(%rsp)
  jg     L23
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  movsbl 0xf(%rsp),%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jg     L27
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x10(%rsp)
  jle    L0
L23:
  mov    $0x0,%ebx
  cmpl   $0x0,0x14(%rsp)
  jg     L27
  jmp    L34
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: %d %d
%c

assistant: ```c
int main() {
  int n, m;
  char c;
  scanf("%d %d\n%c", &n, &m, &c);
  for (int i = 0; i < n; ++i) {
    for (int j = 0; j < m; ++j)
      printf("%c", c);
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xf(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  jle    L1
  nop
L43:
  mov    0x14(%rsp),%eax
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L46
  nopw   0x0(%rax,%rax,1)
L30:
  movsbl 0xf(%rsp),%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L30
L46:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x10(%rsp)
  jg     L43
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string

tool: D9: %d %d
%c

assistant: ```c
int main() {
  int n, m;
  char c;
  scanf("%d %d\n%c", &n, &m, &c);
  for (int i = 0; i < n; ++i) {
    for (int j = 0; j < m; ++j)
      printf("%c", c);
    printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xf(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  jle    L44
  nop
L1:
  mov    0x14(%rsp),%eax
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L31
  nopw   0x0(%rax,%rax,1)
L35:
  movsbl 0xf(%rsp),%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L35
L31:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x10(%rsp)
  jg     L1
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: %d %d
%c

assistant: ```c
int main() {
  int n, m;
  char c;
  scanf("%d %d\n%c", &n, &m, &c);
  for (int i = 0; i < n; ++i) {
    for (int j = 0; j < m; ++j)
      printf("%c", c);
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x4f,%eax
  jle    L9
  mov    -0x8(%rbp),%rax
  add    $0x4f,%rax
  movb   $0x0,(%rax)
L9:
  nop
  leave
  ret
```

assistant: ```c
void check_length(char *name) {
  if (strlen(name) > 80 - 1)
    name[80 - 1] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_length>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x4f,%eax
  jle    L0
  movb   $0x0,0x4f(%rbx)
L0:
  pop    %rbx
  ret
```

assistant: ```c
void check_length(char *name) {
  if (strlen(name) > 80 - 1)
    name[80 - 1] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_length>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x4f,%eax
  jle    L1
  movb   $0x0,0x4f(%rbx)
L1:
  pop    %rbx
  ret
```

assistant: ```c
void check_length(char *name) {
  if (strlen(name) > 80 - 1)
    name[80 - 1] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_length>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x4f,%eax
  jle    L0
  movb   $0x0,0x4f(%rbx)
L0:
  pop    %rbx
  ret
```

assistant: ```c
void check_length(char *name) {
  if (strlen(name) > 80 - 1)
    name[80 - 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4d8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x97,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  lea    0x8(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L11
  lea    0x10(%rsp),%rbx
  mov    $0x1,%ebp
  lea    D7(%rip),%r12
  jmp    L0
L55:
  cmp    $0x3,%edx
  je     L58
  mov    $0x3,%eax
  sub    %edx,%eax
  movslq %edx,%rdx
  movslq %ebp,%rsi
  lea    (%rsi,%rsi,2),%rsi
  add    %rsi,%rdx
  cltq
  movslq %edi,%rdi
  lea    (%rdi,%rdi,2),%rdi
  add    %rax,%rdi
  mov    0x10(%rsp,%rdi,4),%edi
  cmp    %ecx,%edi
  cmovg  %ecx,%edi
  mov    %edi,0x10(%rsp,%rdx,4)
  add    %rax,%rsi
  movl   $0x65,0x10(%rsp,%rsi,4)
L32:
  add    $0x1,%ebp
  mov    0x8(%rsp),%eax
  add    $0xc,%rbx
  cmp    %ebp,%eax
  jl     L11
L0:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    -0x1(%rbp),%edi
  mov    (%rbx),%ecx
  mov    0x8(%rbx),%esi
  mov    0x4(%rbx),%eax
  cmp    %eax,%ecx
  cmovle %ecx,%eax
  cmp    %eax,%esi
  mov    %eax,%edx
  cmovle %esi,%edx
  add    $0x1,%edx
  mov    %edx,0xc(%rbx)
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jne    L55
  movl   $0x65,0x10(%rbx)
  movl   $0x65,0x14(%rbx)
  jmp    L32
L58:
  cmp    %esi,%ecx
  cmovle %ecx,%esi
  mov    %esi,0x10(%rbx)
  mov    %eax,0x14(%rbx)
  jmp    L32
L11:
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    (%rdx,%rax,1),%rsi
  mov    %rsi,%rcx
  mov    0x10(%rsp,%rsi,4),%esi
  mov    0x14(%rsp,%rcx,4),%ecx
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  add    %rax,%rdx
  mov    0x18(%rsp,%rdx,4),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x4d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x4e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D28
type: string
name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D28: %d


tool: D7: %d

assistant: ```c
int main() {
  int n, i, c, t[101][3] = {0};
  scanf("%d\n", &n);
  for (i = 1; i <= n; ++i) {
    scanf("%d", &c);
    t[i][0] = (t[i - 1][0] > (t[i - 1][1] > t[i - 1][2] ? t[i - 1][2] : t[i - 1][1]) ? (t[i - 1][1] > t[i - 1][2] ? t[i - 1][2] : t[i - 1][1]) : t[i - 1][0]) + 1;
    if (!c) {
      t[i][1] = 101;
      t[i][2] = 101;
    } else if (c == 3) {
      t[i][1] = (t[i - 1][0] > t[i - 1][2] ? t[i - 1][2] : t[i - 1][0]);
      t[i][2] = (t[i - 1][0] > t[i - 1][1] ? t[i - 1][1] : t[i - 1][0]);
    } else {
      t[i][c] = (t[i - 1][0] > t[i - 1][3 - c] ? t[i - 1][3 - c] : t[i - 1][0]);
      t[i][3 - c] = 101;
    }
  }
  printf("%d\n", (t[n][0] > (t[n][1] > t[n][2] ? t[n][2] : t[n][1]) ? (t[n][1] > t[n][2] ? t[n][2] : t[n][1]) : t[n][0]));
}
```