ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xfffffffe,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    $0x5,%esi
  call   <threeSum@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L5
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
L12:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L12
L5:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: %d %d %d


assistant: ```c
int main(void) {
  int i, count;
  int nums[] = {-2, 0, 0, 2, 2};
  int **triplets = threeSum(nums, sizeof(nums) / sizeof(*nums), &count);
  for (i = 0; i < count; i++) {
    printf("%d %d %d\n", triplets[i][0], triplets[i][1], triplets[i][2]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    $0xfffffffe,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  movl   $0x2,0x20(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x200000000,%rax
  mov    %rax,0x18(%rsp)
  call   <threeSum@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L8
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D0(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L28:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %r12,%rdi
  add    $0x1,%rbx
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L28
L8:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d %d %d


assistant: ```c
int main(void) {
  int i, count;
  int nums[] = {-2, 0, 0, 2, 2};
  int **triplets = threeSum(nums, sizeof(nums) / sizeof(*nums), &count);
  for (i = 0; i < count; i++) {
    printf("%d %d %d\n", triplets[i][0], triplets[i][1], triplets[i][2]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  movl   $0x2,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <threeSum@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L27
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D5(%rip),%r12
  nopl   0x0(%rax)
L1:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %r12,%rdi
  add    $0x1,%rbx
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L1
L27:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: byte[16]
name: read_data
arguments: tag: D5
type_infered: string

tool: {"D4": [0xfe,0xff,0xff,0xff,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D5: %d %d %d


assistant: ```c
int main(void) {
  int i, count;
  int nums[] = {-2, 0, 0, 2, 2};
  int **triplets = threeSum(nums, sizeof(nums) / sizeof(*nums), &count);
  for (i = 0; i < count; i++) {
    printf("%d %d %d\n", triplets[i][0], triplets[i][1], triplets[i][2]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log2i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x7,-0x8(%rbp)
  jmp    L2
L9:
  subq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  and    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int log2i(size_t x) {
  assert(x != 0);
  size_t i = sizeof(size_t) - 1;
  while (!(x & (1 << i))) {
    i--;
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<log2i>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   $0x80,%bl
  jne    L6
  mov    $0x7,%ecx
  mov    $0x1,%eax
L14:
  sub    $0x1,%rcx
  mov    %eax,%edx
  shl    %cl,%edx
  movslq %edx,%rdx
  test   %rbx,%rdx
  je     L14
L21:
  mov    %ecx,%eax
  pop    %rbx
  ret
L6:
  mov    $0x7,%ecx
  jmp    L21
```

assistant: ```c
int log2i(size_t x) {
  assert(x != 0);
  size_t i = sizeof(size_t) - 1;
  while (!(x & (1 << i))) {
    i--;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<log2i>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   $0x80,%bl
  jne    L9
  mov    $0x7,%ecx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  sub    $0x1,%rcx
  mov    %eax,%edx
  shl    %cl,%edx
  movslq %edx,%rdx
  test   %rbx,%rdx
  je     L10
  mov    %ecx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  mov    $0x7,%eax
  pop    %rbx
  ret
```

assistant: ```c
int log2i(size_t x) {
  assert(x != 0);
  size_t i = sizeof(size_t) - 1;
  while (!(x & (1 << i))) {
    i--;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<log2i>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   $0x80,%bl
  jne    L10
  mov    $0x7,%ecx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%rcx
  mov    %eax,%edx
  shl    %cl,%edx
  movslq %edx,%rdx
  test   %rbx,%rdx
  je     L9
  mov    %ecx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x7,%eax
  pop    %rbx
  ret
```

assistant: ```c
int log2i(size_t x) {
  assert(x != 0);
  size_t i = sizeof(size_t) - 1;
  while (!(x & (1 << i))) {
    i--;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InputCheck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <InputIsReady@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L7
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fileno@plt>
  mov    %eax,%ecx
  lea    -0xd(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <read@plt>
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  jmp    L6
L7:
  mov    $0xffffffff,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int InputCheck() {
  int ready = InputIsReady();
  if (ready) {
    char c;
    read(fileno(stdin), &c, 1);
    return c;
  } else {
    return -1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<InputCheck>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <InputIsReady@plt>
  test   %eax,%eax
  je     L27
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <fileno@plt>
  mov    %eax,%edi
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  movsbl 0x7(%rsp),%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L27:
  mov    $0xffffffff,%eax
  jmp    L2
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int InputCheck() {
  int ready = InputIsReady();
  if (ready) {
    char c;
    read(fileno(stdin), &c, 1);
    return c;
  } else {
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InputCheck>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <InputIsReady@plt>
  test   %eax,%eax
  je     L27
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fileno@plt>
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <read@plt>
  movsbl 0x7(%rsp),%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%eax
  jmp    L9
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int InputCheck() {
  int ready = InputIsReady();
  if (ready) {
    char c;
    read(fileno(stdin), &c, 1);
    return c;
  } else {
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InputCheck>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <InputIsReady@plt>
  test   %eax,%eax
  je     L27
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fileno@plt>
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <read@plt>
  movsbl 0x7(%rsp),%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%eax
  jmp    L18
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int InputCheck() {
  int ready = InputIsReady();
  if (ready) {
    char c;
    read(fileno(stdin), &c, 1);
    return c;
  } else {
    return -1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x47554f52,0x22(%rsp)
  movw   $0x45,0x26(%rsp)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  lea    D55(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%r12d
  mov    %rsp,%rbp
  lea    D32(%rip),%r15
  lea    D18(%rip),%r14
  lea    D39(%rip),%r13
  jmp    L3
L63:
  mov    $0x2a,%edi
  call   <putchar@plt>
L10:
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  je     L20
L55:
  cmpl   $0x0,0x0(%rbp,%rbx,4)
  je     L63
  movsbl 0x22(%rsp,%rbx,1),%edi
  call   <putchar@plt>
  jmp    L10
L20:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <lireCaractere@plt>
  lea    0x22(%rsp),%rsi
  movsbl %al,%edi
  mov    %rbp,%rdx
  call   <rechercheLettre@plt>
  cmp    $0x1,%eax
  sbb    $0x0,%r12d
  test   %r12d,%r12d
  jle    L64
L3:
  mov    %rbp,%rdi
  call   <gagne@plt>
  test   %rax,%rax
  jne    L64
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L55
L64:
  mov    %rsp,%rdi
  call   <gagne@plt>
  test   %rax,%rax
  je     L58
  lea    0x22(%rsp),%rsi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L75:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  lea    0x22(%rsp),%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L75
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D55
type: string
name: retrieve_data
arguments: tag: D32
type: string
name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D39
type: string
name: retrieve_data
arguments: tag: D43
type: string
name: retrieve_data
arguments: tag: D36
type: string

tool: D55: Bienvenu dans le pendu !


tool: D32: 

Il vous reste %d coups a jouer

tool: D18: 
Quel est le mot secret ? 

tool: D39: 
Proposez une lettre : 

tool: D43: 

Gagne ! Le mot secret etait bien : %s

tool: D36: 

Perdu ! Le mot secret etait : %s

assistant: ```c
int main(int argc, char *argv[]) {
  int coups = 10;
  char lettre = 0;
  char chaine[] = "ROUGE";
  int i = 0;
  int tableauGagne[5] = {0};
  printf("Bienvenu dans le pendu !\n\n");
  while (coups > 0 && !gagne(tableauGagne)) {
    printf("\n\nIl vous reste %d coups a jouer", coups);
    printf("\nQuel est le mot secret ? ");
    for (i = 0; i < 5; i++) {
      if (tableauGagne[i])
        printf("%c", chaine[i]);
      else
        printf("*");
    }
    printf("\nProposez une lettre : ");
    lettre = lireCaractere();
    if (!rechercheLettre(lettre, chaine, tableauGagne)) {
      coups--;
    }
  }
  if (gagne(tableauGagne))
    printf("\n\nGagne ! Le mot secret etait bien : %s", chaine);
  else
    printf("\n\nPerdu ! Le mot secret etait : %s", chaine);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D34
type: string
name: retrieve_data
arguments: data_tag: D29
type: string
name: retrieve_data
arguments: data_tag: D39
type: string
name: retrieve_data
arguments: data_tag: D0
type: string

tool: D34: %d + %d = %d


tool: D29: %d %d = %d


tool: D39: %d * %d = %d


tool: D0: %d / %d = %d

assistant: ```c
int main() {
  int num1, num2, res;
  num1 = 5, num2 = 2;
  res = num1 + num2;
  printf("%d + %d = %d\n", num1, num2, res);
  printf("%d %d = %d\n", num1, num2, num1 % num2);
  printf("%d * %d = %d\n", num1, num2, num1 * num2);
  printf("%d / %d = %d", num1, num2, num1 / num2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D31
datatype: string
name: unpack_data
arguments: data_tag: D33
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D39
datatype: string

tool: D31: %d + %d = %d


tool: D33: %d %d = %d


tool: D27: %d * %d = %d


tool: D39: %d / %d = %d

assistant: ```c
int main() {
  int num1, num2, res;
  num1 = 5, num2 = 2;
  res = num1 + num2;
  printf("%d + %d = %d\n", num1, num2, res);
  printf("%d %d = %d\n", num1, num2, num1 % num2);
  printf("%d * %d = %d\n", num1, num2, num1 * num2);
  printf("%d / %d = %d", num1, num2, num1 / num2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D22
type_infered: string
name: read_data
arguments: data_label: D11
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D20
type_infered: string

tool: D22: %d + %d = %d


tool: D11: %d %d = %d


tool: D0: %d * %d = %d


tool: D20: %d / %d = %d

assistant: ```c
int main() {
  int num1, num2, res;
  num1 = 5, num2 = 2;
  res = num1 + num2;
  printf("%d + %d = %d\n", num1, num2, res);
  printf("%d %d = %d\n", num1, num2, num1 % num2);
  printf("%d * %d = %d\n", num1, num2, num1 * num2);
  printf("%d / %d = %d", num1, num2, num1 / num2);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0x5,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D32
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string
name: retrieve_data
arguments: label: D29
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string

tool: D32: %d + %d = %d


tool: D3: %d %d = %d


tool: D29: %d * %d = %d


tool: D19: %d / %d = %d

assistant: ```c
int main() {
  int num1, num2, res;
  num1 = 5, num2 = 2;
  res = num1 + num2;
  printf("%d + %d = %d\n", num1, num2, res);
  printf("%d %d = %d\n", num1, num2, num1 % num2);
  printf("%d * %d = %d\n", num1, num2, num1 * num2);
  printf("%d / %d = %d", num1, num2, num1 / num2);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x23,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <str2int@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
datatype: string
name: unpack_data
arguments: label: D12
datatype: string

tool: D10: z

tool: D12: 35:%d


assistant: ```c
int main() {
  printf("35:%d\n", str2int("z", 35));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%esi
  lea    D2(%rip),%rdi
  call   <str2int@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D2: z

tool: D3: 35:%d


assistant: ```c
int main() {
  printf("35:%d\n", str2int("z", 35));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%esi
  lea    D1(%rip),%rdi
  call   <str2int@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D1: z

tool: D0: 35:%d


assistant: ```c
int main() {
  printf("35:%d\n", str2int("z", 35));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%esi
  lea    D19(%rip),%rdi
  call   <str2int@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
type_infered: string
name: disassemble_data
arguments: label: D8
type_infered: string

tool: D19: z

tool: D8: 35:%d


assistant: ```c
int main() {
  printf("35:%d\n", str2int("z", 35));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_denormalized>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <get_exp@plt>
  test   %eax,%eax
  jne    L19
  mov    $0x1,%eax
  jmp    L2
L19:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int is_denormalized(float f) {
  if (get_exp(f) == 0x00000000) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_denormalized>:
  endbr64
  sub    $0x8,%rsp
  call   <get_exp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_denormalized(float f) {
  if (get_exp(f) == 0x00000000) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_denormalized>:
  endbr64
  sub    $0x8,%rsp
  call   <get_exp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_denormalized(float f) {
  if (get_exp(f) == 0x00000000) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_denormalized>:
  endbr64
  sub    $0x8,%rsp
  call   <get_exp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_denormalized(float f) {
  if (get_exp(f) == 0x00000000) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mem_swap_near_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %eax,%edx
  mov    -0x2c(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L91
  cmpl   $0x0,-0x34(%rbp)
  je     L91
  mov    -0x28(%rbp),%rax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L21
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L21
  mov    -0x10(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L68
L21:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
L5:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  ja     L36
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    -0x14(%rbp),%eax
  jmp    L63
L36:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
L63:
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  cmpl   $0x0,-0x18(%rbp)
  jne    L5
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x19(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L95
L68:
  mov    -0x10(%rbp),%eax
  shr    $0x2,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  shr    $0x2,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mem_swap_near_block_32@plt>
  jmp    L95
L91:
  nop
L95:
  leave
  ret
```

assistant: ```c
void mem_swap_near_block(void *base, unsigned int elem_size, unsigned int cnt1, unsigned int cnt2) {
  unsigned int sz = elem_size * (cnt1 + cnt2);
  unsigned int shift = elem_size * cnt1;
  if (cnt1 == 0 || cnt2 == 0) {
    return;
  }
  if (((unsigned int)base & 3) || (sz & 3) || (shift & 3)) {
    unsigned int i0 = 0;
    unsigned int i1 = 0;
    char *p = base;
    char tmp = p[i0];
    do {
      i0 = i1;
      i1 = (((shift + i0) >= (sz)) ? ((shift + i0) - (sz)) : (shift + i0));
      p[i0] = p[i1];
    } while (i1 != 0);
    p[i0] = tmp;
  } else {
    mem_swap_near_block_32(base, sz / 4, shift / 4);
  }
}
```