ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  lea    D22(%rip),%rdi
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    $0x1,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  call   <printf@plt>
  lea    0x8(%rsp),%rdx
  mov    %r12,%rcx
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  lea    0xc(%rsp),%r9
  lea    0x3(%rsp),%r8
  call   <minscanf@plt>
  mov    0x4(%rsp),%esi
  pxor   %xmm1,%xmm1
  mov    %r12,%rdx
  movsbl 0x3(%rsp),%ecx
  movss  0x8(%rsp),%xmm0
  mov    $0x2,%eax
  lea    D18(%rip),%rdi
  cvtss2sd 0xc(%rsp),%xmm1
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D22
type_infered: string
name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string

tool: D22: %d,%f


tool: D16: %d%f%s%c%e

tool: D18: %d,%f,%s,%c,%e


assistant: ```c
int main() {
  int i = 0;
  float d = 0, e;
  char s[100];
  char c;
  printf("%d,%f\n", i, d);
  minscanf("%d%f%s%c%e", &i, &d, s, &c, &e);
  printf("%d,%f,%s,%c,%e\n", i, d, s, c, e);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  lea    D14(%rip),%rdi
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    $0x1,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  call   <printf@plt>
  lea    0x8(%rsp),%rdx
  mov    %r12,%rcx
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  lea    0xc(%rsp),%r9
  lea    0x3(%rsp),%r8
  call   <minscanf@plt>
  mov    0x4(%rsp),%esi
  pxor   %xmm1,%xmm1
  mov    %r12,%rdx
  movsbl 0x3(%rsp),%ecx
  movss  0x8(%rsp),%xmm0
  mov    $0x2,%eax
  lea    D4(%rip),%rdi
  cvtss2sd 0xc(%rsp),%xmm1
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D0
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D14: %d,%f


tool: D0: %d%f%s%c%e

tool: D4: %d,%f,%s,%c,%e


assistant: ```c
int main() {
  int i = 0;
  float d = 0, e;
  char s[100];
  char c;
  printf("%d,%f\n", i, d);
  minscanf("%d%f%s%c%e", &i, &d, s, &c, &e);
  printf("%d,%f,%s,%c,%e\n", i, d, s, c, e);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L18
L7:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putch@plt>
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s)
    putch(*s++);
}
```
user: What is the c source code of the assembly code below?

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L15
L9:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putch@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
L15:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s)
    putch(*s++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L19:
  call   <putch@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L19
L2:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s)
    putch(*s++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L8
L7:
  call   <putch@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L8:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s)
    putch(*s++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<w_quick_sort_int_save>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void w_quick_sort_int_save(void *data, int i, void *key) {
  int *ints = (int *)data;
  *(int *)key = ints[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<w_quick_sort_int_save>:
  endbr64
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void w_quick_sort_int_save(void *data, int i, void *key) {
  int *ints = (int *)data;
  *(int *)key = ints[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<w_quick_sort_int_save>:
  endbr64
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void w_quick_sort_int_save(void *data, int i, void *key) {
  int *ints = (int *)data;
  *(int *)key = ints[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<w_quick_sort_int_save>:
  endbr64
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void w_quick_sort_int_save(void *data, int i, void *key) {
  int *ints = (int *)data;
  *(int *)key = ints[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cec_ops_request_short_audio_descriptor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x2(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x4,%eax
  jle    L27
  mov    -0x20(%rbp),%rax
  movl   $0x4,(%rax)
L27:
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L8:
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  sar    $0x6,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  and    $0x3f,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cec_ops_request_short_audio_descriptor(const struct cec_msg *msg, __u8 *num_descriptors, __u8 *audio_format_id, __u8 *audio_format_code) {
  unsigned int i;
  *num_descriptors = msg->len - 2;
  if (*num_descriptors > 4) {
    *num_descriptors = 4;
  }
  for (i = 0; i < *num_descriptors; i++) {
    audio_format_id[i] = msg->msg[2 + i] >> 6;
    audio_format_code[i] = msg->msg[2 + i] & 0x3f;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cec_ops_request_short_audio_descriptor>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    (%rdi),%eax
  sub    $0x2,%eax
  cmp    $0x4,%eax
  jg     L2
  mov    %eax,(%rsi)
  test   %eax,%eax
  jne    L14
  ret
L2:
  movl   $0x4,(%rsi)
L14:
  mov    $0x0,%eax
L20:
  lea    0x2(%rax),%edi
  mov    %eax,%esi
  mov    0x8(%r8),%rdx
  mov    (%rdx,%rdi,4),%edx
  sar    $0x6,%edx
  mov    %edx,(%r10,%rsi,4)
  mov    0x8(%r8),%rdx
  mov    (%rdx,%rdi,4),%edx
  and    $0x3f,%edx
  mov    %edx,(%rcx,%rsi,4)
  add    $0x1,%eax
  cmp    %eax,(%r9)
  ja     L20
  ret
```

assistant: ```c
void cec_ops_request_short_audio_descriptor(const struct cec_msg *msg, __u8 *num_descriptors, __u8 *audio_format_id, __u8 *audio_format_code) {
  unsigned int i;
  *num_descriptors = msg->len - 2;
  if (*num_descriptors > 4) {
    *num_descriptors = 4;
  }
  for (i = 0; i < *num_descriptors; i++) {
    audio_format_id[i] = msg->msg[2 + i] >> 6;
    audio_format_code[i] = msg->msg[2 + i] & 0x3f;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cec_ops_request_short_audio_descriptor>:
  endbr64
  mov    (%rdi),%eax
  mov    %rsi,%r9
  sub    $0x2,%eax
  cmp    $0x4,%eax
  jg     L15
  mov    %eax,(%rsi)
  test   %eax,%eax
  je     L8
L29:
  mov    0x8(%rdi),%r10
  xor    %eax,%eax
  nopl   (%rax)
L39:
  lea    0x2(%rax),%esi
  mov    %eax,%edi
  add    $0x1,%eax
  lea    (%r10,%rsi,4),%r8
  mov    (%r8),%esi
  sar    $0x6,%esi
  mov    %esi,(%rdx,%rdi,4)
  mov    (%r8),%esi
  and    $0x3f,%esi
  mov    %esi,(%rcx,%rdi,4)
  cmp    %eax,(%r9)
  ja     L39
  ret
  nopl   0x0(%rax)
L8:
  ret
  nopl   0x0(%rax)
L15:
  movl   $0x4,(%rsi)
  jmp    L29
```

assistant: ```c
void cec_ops_request_short_audio_descriptor(const struct cec_msg *msg, __u8 *num_descriptors, __u8 *audio_format_id, __u8 *audio_format_code) {
  unsigned int i;
  *num_descriptors = msg->len - 2;
  if (*num_descriptors > 4) {
    *num_descriptors = 4;
  }
  for (i = 0; i < *num_descriptors; i++) {
    audio_format_id[i] = msg->msg[2 + i] >> 6;
    audio_format_code[i] = msg->msg[2 + i] & 0x3f;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cec_ops_request_short_audio_descriptor>:
  endbr64
  mov    (%rdi),%eax
  mov    %rsi,%r9
  sub    $0x2,%eax
  cmp    $0x4,%eax
  jg     L36
  mov    %eax,(%rsi)
  test   %eax,%eax
  je     L8
L10:
  mov    0x8(%rdi),%r10
  xor    %eax,%eax
  nopl   (%rax)
L27:
  lea    0x2(%rax),%esi
  mov    %eax,%edi
  add    $0x1,%eax
  lea    (%r10,%rsi,4),%r8
  mov    (%r8),%esi
  sar    $0x6,%esi
  mov    %esi,(%rdx,%rdi,4)
  mov    (%r8),%esi
  and    $0x3f,%esi
  mov    %esi,(%rcx,%rdi,4)
  cmp    %eax,(%r9)
  ja     L27
  ret
  nopl   0x0(%rax)
L8:
  ret
  nopl   0x0(%rax)
L36:
  movl   $0x4,(%rsi)
  jmp    L10
```

assistant: ```c
void cec_ops_request_short_audio_descriptor(const struct cec_msg *msg, __u8 *num_descriptors, __u8 *audio_format_id, __u8 *audio_format_code) {
  unsigned int i;
  *num_descriptors = msg->len - 2;
  if (*num_descriptors > 4) {
    *num_descriptors = 4;
  }
  for (i = 0; i < *num_descriptors; i++) {
    audio_format_id[i] = msg->msg[2 + i] >> 6;
    audio_format_code[i] = msg->msg[2 + i] & 0x3f;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L26
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <core@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L6
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <core@plt>
  mov    %eax,-0x4(%rbp)
L26:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L10
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: a.out

assistant: ```c
int main(int ac, char **av) {
  int i;
  int err;
  i = 0;
  err = 0;
  if (ac == 1)
    err = core("a.out");
  else {
    while (av[++i])
      err = core(av[i]);
  }
  return (err);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  je     L25
  mov    0x8(%rsi),%rdi
  lea    0x10(%rsi),%rbx
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L9
L7:
  call   <core@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L7
L9:
  pop    %rbx
  ret
L25:
  lea    D6(%rip),%rdi
  call   <core@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: a.out

assistant: ```c
int main(int ac, char **av) {
  int i;
  int err;
  i = 0;
  err = 0;
  if (ac == 1)
    err = core("a.out");
  else {
    while (av[++i])
      err = core(av[i]);
  }
  return (err);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  je     L29
  mov    0x8(%rsi),%rdi
  push   %rbx
  xor    %eax,%eax
  lea    0x10(%rsi),%rbx
  test   %rdi,%rdi
  je     L19
  nopl   0x0(%rax)
L8:
  call   <core@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L8
L19:
  pop    %rbx
  ret
L29:
  lea    D5(%rip),%rdi
  jmp    1050 <core@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: a.out

assistant: ```c
int main(int ac, char **av) {
  int i;
  int err;
  i = 0;
  err = 0;
  if (ac == 1)
    err = core("a.out");
  else {
    while (av[++i])
      err = core(av[i]);
  }
  return (err);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  je     L20
  mov    0x8(%rsi),%rdi
  push   %rbx
  xor    %eax,%eax
  lea    0x10(%rsi),%rbx
  test   %rdi,%rdi
  je     L5
  nopl   0x0(%rax)
L12:
  call   <core@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L12
L5:
  pop    %rbx
  ret
L20:
  lea    D0(%rip),%rdi
  jmp    1050 <core@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: a.out

assistant: ```c
int main(int ac, char **av) {
  int i;
  int err;
  i = 0;
  err = 0;
  if (ac == 1)
    err = core("a.out");
  else {
    while (av[++i])
      err = core(av[i]);
  }
  return (err);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L6:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x8010,-0x4(%rbp)
  jbe    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((no)) Foo(int *ary) {
  int ix;
#pragma acc parallel num_workers(32) vector_length(32) copyout(ary [0:N])
  {
#pragma acc loop worker vector
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      ary[ix] = ix;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<Foo>:
  endbr64
  mov    $0x0,%eax
L7:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x8011,%rax
  jne    L7
  ret
```

assistant: ```c
void __attribute__((no)) Foo(int *ary) {
  int ix;
#pragma acc parallel num_workers(32) vector_length(32) copyout(ary [0:N])
  {
#pragma acc loop worker vector
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      ary[ix] = ix;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Foo>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x8011,%rax
  jne    L8
  ret
```

assistant: ```c
void __attribute__((no)) Foo(int *ary) {
  int ix;
#pragma acc parallel num_workers(32) vector_length(32) copyout(ary [0:N])
  {
#pragma acc loop worker vector
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      ary[ix] = ix;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Foo>:
  endbr64
  movdqa D6(%rip),%xmm0
  movdqa D10(%rip),%xmm2
  mov    %rdi,%rax
  lea    0x20040(%rdi),%rdx
  xchg   %ax,%ax
L9:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L9
  movl   $0x8010,0x20040(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: byte[16]
name: extract_symbolic_data
arguments: label: D10
type: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D10": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void __attribute__((no)) Foo(int *ary) {
  int ix;
#pragma acc parallel num_workers(32) vector_length(32) copyout(ary [0:N])
  {
#pragma acc loop worker vector
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      ary[ix] = ix;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D41(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  lea    -0x38(%rbp),%rcx
  lea    -0x40(%rbp),%rdx
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x30(%rbp),%xmm0
  movsd  D35(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x38(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x48(%rbp),%xmm1
  movsd  -0x48(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm2
  movsd  -0x40(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x58(%rbp)
  movsd  -0x48(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm1,%xmm3
  mulsd  %xmm0,%xmm3
  movsd  %xmm3,-0x60(%rbp)
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x60(%rbp),%xmm0
  movsd  -0x58(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  movsd  -0x48(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x58(%rbp)
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mulsd  -0x58(%rbp),%xmm0
  movsd  D15(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x48(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  -0x48(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D41
type_infered: f64
name: disassemble_data
arguments: data_label: D29
type_infered: string
name: disassemble_data
arguments: data_label: D35
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D15
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D12
type_infered: string

tool: D41: 3.1415926

tool: D29: %lf%lf%lf

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D12: %.13lf
%.13lf
%.13lf


assistant: ```c
int main() {
  const double pi = 3.1415926;
  double a, b, c, C, S, L, h;
  scanf("%lf%lf%lf", &a, &b, &C);
  C *= pi / 180;
  c = sqrt(a * a + b * b - 2 * a * b * cos(C));
  S = a * b * sin(C) / 2;
  L = a + b + c;
  h = 2 * S / a;
  printf("%.13lf\n%.13lf\n%.13lf\n", S, L, h);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  movsd  D20(%rip),%xmm2
  mulsd  0x20(%rsp),%xmm2
  movsd  %xmm2,0x20(%rsp)
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  addsd  %xmm4,%xmm0
  movsd  %xmm0,(%rsp)
  addsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm1
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <cos@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L16
  sqrtsd %xmm0,%xmm0
  movsd  %xmm0,(%rsp)
L22:
  mov    0x10(%rsp),%rbp
  mov    0x18(%rsp),%rbx
  movsd  0x20(%rsp),%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  movq   %rbx,%xmm6
  mulsd  %xmm6,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  D36(%rip),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  movq   %rbx,%xmm1
  movq   %rbp,%xmm7
  addsd  %xmm7,%xmm1
  divsd  %xmm7,%xmm2
  addsd  (%rsp),%xmm1
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <sqrt@plt>
  movsd  %xmm0,(%rsp)
  jmp    L22
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
datatype: string
name: retrieve_data
arguments: label: D20
datatype: byte[8]
name: retrieve_data
arguments: label: D36
datatype: byte[8]
name: retrieve_data
arguments: label: D1
datatype: string

tool: D18: %lf%lf%lf

tool: {"D20": [0x18,0x39,0x35,0x9d,0x46,0xdf,0x91,0x3f]}

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D1: %.13lf
%.13lf
%.13lf


assistant: ```c
int main() {
  const double pi = 3.1415926;
  double a, b, c, C, S, L, h;
  scanf("%lf%lf%lf", &a, &b, &C);
  C *= pi / 180;
  c = sqrt(a * a + b * b - 2 * a * b * cos(C));
  S = a * b * sin(C) / 2;
  L = a + b + c;
  h = 2 * S / a;
  printf("%.13lf\n%.13lf\n%.13lf\n", S, L, h);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rcx
  lea    0x28(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm4
  movsd  D22(%rip),%xmm3
  mulsd  0x30(%rsp),%xmm3
  movapd %xmm2,%xmm0
  movapd %xmm4,%xmm1
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm2
  mulsd  %xmm4,%xmm1
  mulsd  %xmm4,%xmm2
  movsd  %xmm3,0x30(%rsp)
  addsd  %xmm0,%xmm1
  movapd %xmm3,%xmm0
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <cos@plt>
  pxor   %xmm2,%xmm2
  movsd  0x10(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm2
  mulsd  0x8(%rsp),%xmm2
  subsd  %xmm2,%xmm1
  ucomisd %xmm1,%xmm0
  ja     L21
  sqrtsd %xmm1,%xmm1
  movsd  %xmm1,0x8(%rsp)
L16:
  movsd  0x20(%rsp),%xmm3
  movsd  0x28(%rsp),%xmm1
  movsd  0x30(%rsp),%xmm0
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sin@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  lea    D27(%rip),%rdi
  movapd %xmm0,%xmm2
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm1
  addsd  0x8(%rsp),%xmm1
  mulsd  %xmm2,%xmm0
  mulsd  D7(%rip),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm3,%xmm2
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L21:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L16
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
datatype: string
name: disassemble_data
arguments: label: D22
datatype: byte[8]
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D7
datatype: byte[8]

tool: D10: %lf%lf%lf

tool: {"D22": [0x18,0x39,0x35,0x9d,0x46,0xdf,0x91,0x3f]}

tool: D27: %.13lf
%.13lf
%.13lf


tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  const double pi = 3.1415926;
  double a, b, c, C, S, L, h;
  scanf("%lf%lf%lf", &a, &b, &C);
  C *= pi / 180;
  c = sqrt(a * a + b * b - 2 * a * b * cos(C));
  S = a * b * sin(C) / 2;
  L = a + b + c;
  h = 2 * S / a;
  printf("%.13lf\n%.13lf\n%.13lf\n", S, L, h);
  return 0;
}
```