ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  movl   $0x1,(%rax)
  mov    $0xa,%edx
  mov    $0x1,%esi
  mov    $0xa,%edi
  mov    $0x0,%eax
  call   <func_ret_int@plt>
  mov    $0x0,%eax
  call   <func_ret_double@plt>
  mov    $0x6e,%edi
  mov    $0x0,%eax
  call   <func_ret_char_ptr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f() {
  register int i1, i2, i3, i4, i5, i6, i7, i8, i9, i10;
  register char *c1, *c2, *c3, *c4, *c5, *c6, *c7, *c8, *c9, *c10;
  extern int a_very_long_name_to_see_how_long_they_can_be;
  double dbl;
  int func_ret_int();
  double func_ret_double();
  char *func_ret_char_ptr();
  i1 = 1;
  i2 = 2;
  i3 = 3;
  i4 = 4;
  i5 = 5;
  i6 = 6;
  i7 = 7;
  i8 = 8;
  i9 = 9;
  i10 = 10;
  c1 = (char *)110;
  c2 = (char *)120;
  c3 = (char *)130;
  c4 = (char *)140;
  c5 = (char *)150;
  c6 = (char *)160;
  c7 = (char *)170;
  c8 = (char *)180;
  c9 = (char *)190;
  c10 = (char *)200;
  a_very_long_name_to_see_how_long_they_can_be = 1;
  i2 = func_ret_int(10, i1, i10);
  dbl = func_ret_double();
  c1 = func_ret_char_ptr(c1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  mov    $0xa,%edx
  mov    D9(%rip),%rax
  mov    $0x1,%esi
  movl   $0x1,(%rax)
  xor    %eax,%eax
  call   <func_ret_int@plt>
  xor    %eax,%eax
  call   <func_ret_double@plt>
  mov    $0x6e,%edi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <func_ret_char_ptr@plt>
```

assistant: ```c
void f() {
  register int i1, i2, i3, i4, i5, i6, i7, i8, i9, i10;
  register char *c1, *c2, *c3, *c4, *c5, *c6, *c7, *c8, *c9, *c10;
  extern int a_very_long_name_to_see_how_long_they_can_be;
  double dbl;
  int func_ret_int();
  double func_ret_double();
  char *func_ret_char_ptr();
  i1 = 1;
  i2 = 2;
  i3 = 3;
  i4 = 4;
  i5 = 5;
  i6 = 6;
  i7 = 7;
  i8 = 8;
  i9 = 9;
  i10 = 10;
  c1 = (char *)110;
  c2 = (char *)120;
  c3 = (char *)130;
  c4 = (char *)140;
  c5 = (char *)150;
  c6 = (char *)160;
  c7 = (char *)170;
  c8 = (char *)180;
  c9 = (char *)190;
  c10 = (char *)200;
  a_very_long_name_to_see_how_long_they_can_be = 1;
  i2 = func_ret_int(10, i1, i10);
  dbl = func_ret_double();
  c1 = func_ret_char_ptr(c1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  mov    $0xa,%edx
  mov    D8(%rip),%rax
  mov    $0x1,%esi
  movl   $0x1,(%rax)
  xor    %eax,%eax
  call   <func_ret_int@plt>
  xor    %eax,%eax
  call   <func_ret_double@plt>
  mov    $0x6e,%edi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <func_ret_char_ptr@plt>
```

assistant: ```c
void f() {
  register int i1, i2, i3, i4, i5, i6, i7, i8, i9, i10;
  register char *c1, *c2, *c3, *c4, *c5, *c6, *c7, *c8, *c9, *c10;
  extern int a_very_long_name_to_see_how_long_they_can_be;
  double dbl;
  int func_ret_int();
  double func_ret_double();
  char *func_ret_char_ptr();
  i1 = 1;
  i2 = 2;
  i3 = 3;
  i4 = 4;
  i5 = 5;
  i6 = 6;
  i7 = 7;
  i8 = 8;
  i9 = 9;
  i10 = 10;
  c1 = (char *)110;
  c2 = (char *)120;
  c3 = (char *)130;
  c4 = (char *)140;
  c5 = (char *)150;
  c6 = (char *)160;
  c7 = (char *)170;
  c8 = (char *)180;
  c9 = (char *)190;
  c10 = (char *)200;
  a_very_long_name_to_see_how_long_they_can_be = 1;
  i2 = func_ret_int(10, i1, i10);
  dbl = func_ret_double();
  c1 = func_ret_char_ptr(c1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<valid_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L3
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L11
L3:
  mov    $0xf,%edi
  mov    $0x0,%eax
  call   <error@plt>
L11:
  nop
  leave
  ret
```

assistant: ```c
void valid_size(x, y) int x[2], y[2];
{
  if (x[0] != x[1] || y[0] != y[1]) {
    error(15);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<valid_size>:
  endbr64
  mov    0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jne    L11
  mov    0x4(%rsi),%eax
  cmp    %eax,(%rsi)
  je     L4
L11:
  sub    $0x8,%rsp
  mov    $0xf,%edi
  mov    $0x0,%eax
  call   <error@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
void valid_size(x, y) int x[2], y[2];
{
  if (x[0] != x[1] || y[0] != y[1]) {
    error(15);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<valid_size>:
  endbr64
  mov    0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jne    L8
  mov    0x4(%rsi),%eax
  cmp    %eax,(%rsi)
  je     L3
L8:
  mov    $0xf,%edi
  xor    %eax,%eax
  jmp    1050 <error@plt>
  xchg   %ax,%ax
L3:
  ret
```

assistant: ```c
void valid_size(x, y) int x[2], y[2];
{
  if (x[0] != x[1] || y[0] != y[1]) {
    error(15);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<valid_size>:
  endbr64
  mov    0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jne    L4
  mov    0x4(%rsi),%eax
  cmp    %eax,(%rsi)
  je     L11
L4:
  mov    $0xf,%edi
  xor    %eax,%eax
  jmp    1050 <error@plt>
  xchg   %ax,%ax
L11:
  ret
```

assistant: ```c
void valid_size(x, y) int x[2], y[2];
{
  if (x[0] != x[1] || y[0] != y[1]) {
    error(15);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__QSUB8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x18,%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  shl    $0x18,%eax
  sar    $0x18,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <__SSAT@plt>
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x10,%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  shl    $0x10,%eax
  sar    $0x18,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <__SSAT@plt>
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x8,%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  shl    $0x8,%eax
  sar    $0x18,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <__SSAT@plt>
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  sar    $0x18,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <__SSAT@plt>
  and    $0xff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0xc(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  or     -0x10(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __QSUB8(uint32_t x, uint32_t y) {
  int32_t r, s, t, u;
  r = __SSAT(((((int32_t)x << 24) >> 24) - (((int32_t)y << 24) >> 24)), 8) & (int32_t)0x000000FF;
  s = __SSAT(((((int32_t)x << 16) >> 24) - (((int32_t)y << 16) >> 24)), 8) & (int32_t)0x000000FF;
  t = __SSAT(((((int32_t)x << 8) >> 24) - (((int32_t)y << 8) >> 24)), 8) & (int32_t)0x000000FF;
  u = __SSAT(((((int32_t)x) >> 24) - (((int32_t)y) >> 24)), 8) & (int32_t)0x000000FF;
  return ((uint32_t)((u << 24) | (t << 16) | (s << 8) | (r)));
}
```
user: What is the c source code of the assembly code below:

```asm
<__QSUB8>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  movsbl %dil,%edi
  movsbl %sil,%eax
  sub    %eax,%edi
  mov    $0x8,%esi
  call   <__SSAT@plt>
  mov    %eax,%ebx
  mov    %ebp,%eax
  movsbl %ah,%edi
  mov    %r14d,%eax
  movsbl %ah,%eax
  sub    %eax,%edi
  mov    $0x8,%esi
  call   <__SSAT@plt>
  mov    %eax,%r12d
  mov    %ebp,%edi
  shl    $0x8,%edi
  sar    $0x18,%edi
  mov    %r14d,%eax
  shl    $0x8,%eax
  sar    $0x18,%eax
  sub    %eax,%edi
  mov    $0x8,%esi
  call   <__SSAT@plt>
  mov    %eax,%r13d
  mov    %ebp,%edi
  sar    $0x18,%edi
  sar    $0x18,%r14d
  sub    %r14d,%edi
  mov    $0x8,%esi
  call   <__SSAT@plt>
  movzbl %bl,%ebx
  shl    $0x18,%eax
  or     %eax,%ebx
  shl    $0x10,%r13d
  and    $0xff0000,%r13d
  or     %r13d,%ebx
  shl    $0x8,%r12d
  movzwl %r12w,%r12d
  or     %r12d,%ebx
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __QSUB8(uint32_t x, uint32_t y) {
  int32_t r, s, t, u;
  r = __SSAT(((((int32_t)x << 24) >> 24) - (((int32_t)y << 24) >> 24)), 8) & (int32_t)0x000000FF;
  s = __SSAT(((((int32_t)x << 16) >> 24) - (((int32_t)y << 16) >> 24)), 8) & (int32_t)0x000000FF;
  t = __SSAT(((((int32_t)x << 8) >> 24) - (((int32_t)y << 8) >> 24)), 8) & (int32_t)0x000000FF;
  u = __SSAT(((((int32_t)x) >> 24) - (((int32_t)y) >> 24)), 8) & (int32_t)0x000000FF;
  return ((uint32_t)((u << 24) | (t << 16) | (s << 8) | (r)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__QSUB8>:
  endbr64
  mov    %esi,%eax
  push   %r14
  mov    %rsi,%r14
  mov    $0x8,%esi
  push   %r13
  shl    $0x18,%eax
  push   %r12
  sar    $0x18,%eax
  push   %rbp
  mov    %rdi,%rbp
  shl    $0x18,%edi
  push   %rbx
  sar    $0x18,%edi
  sub    %eax,%edi
  call   <__SSAT@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  mov    %eax,%ebx
  mov    %r14d,%eax
  shl    $0x10,%edi
  shl    $0x10,%eax
  sar    $0x18,%edi
  movzbl %bl,%ebx
  sar    $0x18,%eax
  sub    %eax,%edi
  call   <__SSAT@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  mov    %eax,%r12d
  mov    %r14d,%eax
  shl    $0x8,%edi
  shl    $0x8,%eax
  sar    $0x18,%edi
  sar    $0x18,%eax
  sar    $0x18,%r14d
  sub    %eax,%edi
  shl    $0x8,%r12d
  call   <__SSAT@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  movzwl %r12w,%r12d
  sar    $0x18,%edi
  mov    %eax,%r13d
  sub    %r14d,%edi
  shl    $0x10,%r13d
  call   <__SSAT@plt>
  and    $0xff0000,%r13d
  shl    $0x18,%eax
  or     %eax,%ebx
  or     %r13d,%ebx
  or     %r12d,%ebx
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __QSUB8(uint32_t x, uint32_t y) {
  int32_t r, s, t, u;
  r = __SSAT(((((int32_t)x << 24) >> 24) - (((int32_t)y << 24) >> 24)), 8) & (int32_t)0x000000FF;
  s = __SSAT(((((int32_t)x << 16) >> 24) - (((int32_t)y << 16) >> 24)), 8) & (int32_t)0x000000FF;
  t = __SSAT(((((int32_t)x << 8) >> 24) - (((int32_t)y << 8) >> 24)), 8) & (int32_t)0x000000FF;
  u = __SSAT(((((int32_t)x) >> 24) - (((int32_t)y) >> 24)), 8) & (int32_t)0x000000FF;
  return ((uint32_t)((u << 24) | (t << 16) | (s << 8) | (r)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__QSUB8>:
  endbr64
  mov    %esi,%eax
  push   %r14
  mov    %rsi,%r14
  mov    $0x8,%esi
  push   %r13
  shl    $0x18,%eax
  push   %r12
  sar    $0x18,%eax
  push   %rbp
  mov    %rdi,%rbp
  shl    $0x18,%edi
  push   %rbx
  sar    $0x18,%edi
  sub    %eax,%edi
  call   <__SSAT@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  mov    %eax,%ebx
  mov    %r14d,%eax
  shl    $0x10,%edi
  shl    $0x10,%eax
  sar    $0x18,%edi
  movzbl %bl,%ebx
  sar    $0x18,%eax
  sub    %eax,%edi
  call   <__SSAT@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  mov    %eax,%r12d
  mov    %r14d,%eax
  shl    $0x8,%edi
  shl    $0x8,%eax
  sar    $0x18,%edi
  sar    $0x18,%eax
  sar    $0x18,%r14d
  sub    %eax,%edi
  shl    $0x8,%r12d
  call   <__SSAT@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  movzwl %r12w,%r12d
  sar    $0x18,%edi
  mov    %eax,%r13d
  sub    %r14d,%edi
  shl    $0x10,%r13d
  call   <__SSAT@plt>
  and    $0xff0000,%r13d
  shl    $0x18,%eax
  or     %eax,%ebx
  or     %r13d,%ebx
  or     %r12d,%ebx
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t __QSUB8(uint32_t x, uint32_t y) {
  int32_t r, s, t, u;
  r = __SSAT(((((int32_t)x << 24) >> 24) - (((int32_t)y << 24) >> 24)), 8) & (int32_t)0x000000FF;
  s = __SSAT(((((int32_t)x << 16) >> 24) - (((int32_t)y << 16) >> 24)), 8) & (int32_t)0x000000FF;
  t = __SSAT(((((int32_t)x << 8) >> 24) - (((int32_t)y << 8) >> 24)), 8) & (int32_t)0x000000FF;
  u = __SSAT(((((int32_t)x) >> 24) - (((int32_t)y) >> 24)), 8) & (int32_t)0x000000FF;
  return ((uint32_t)((u << 24) | (t << 16) | (s << 8) | (r)));
}
```
user: What is the c source code of the assembly code below?

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setge  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setge  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setge  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func1(int var1, int var2) {
  var1 = var2 | var1;
  var1 = var2 | var1;
  var1 = var2 | var1;
  var1 = var2 & var1;
  var1 = var2 & var1;
  var1 = var2 & var1;
  var1 = var2 ^ var1;
  var1 = var2 ^ var1;
  var1 = var2 ^ var1;
  var1 = var2 <= var1;
  var1 = var2 <= var1;
  var1 = var2 <= var1;
  var1 = var2 >= var1;
  var1 = var2 >= var1;
  var1 = var2 >= var1;
  var1 = var2 == var1;
  var1 = var2 == var1;
  var1 = var2 == var1;
  var1 = var2 != var1;
  var1 = var2 != var1;
  var1 = var2 != var1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func1>:
  endbr64
  ret
```

assistant: ```c
void func1(int var1, int var2) {
  var1 = var2 | var1;
  var1 = var2 | var1;
  var1 = var2 | var1;
  var1 = var2 & var1;
  var1 = var2 & var1;
  var1 = var2 & var1;
  var1 = var2 ^ var1;
  var1 = var2 ^ var1;
  var1 = var2 ^ var1;
  var1 = var2 <= var1;
  var1 = var2 <= var1;
  var1 = var2 <= var1;
  var1 = var2 >= var1;
  var1 = var2 >= var1;
  var1 = var2 >= var1;
  var1 = var2 == var1;
  var1 = var2 == var1;
  var1 = var2 == var1;
  var1 = var2 != var1;
  var1 = var2 != var1;
  var1 = var2 != var1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func1>:
  endbr64
  ret
```

assistant: ```c
void func1(int var1, int var2) {
  var1 = var2 | var1;
  var1 = var2 | var1;
  var1 = var2 | var1;
  var1 = var2 & var1;
  var1 = var2 & var1;
  var1 = var2 & var1;
  var1 = var2 ^ var1;
  var1 = var2 ^ var1;
  var1 = var2 ^ var1;
  var1 = var2 <= var1;
  var1 = var2 <= var1;
  var1 = var2 <= var1;
  var1 = var2 >= var1;
  var1 = var2 >= var1;
  var1 = var2 >= var1;
  var1 = var2 == var1;
  var1 = var2 == var1;
  var1 = var2 == var1;
  var1 = var2 != var1;
  var1 = var2 != var1;
  var1 = var2 != var1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func1>:
  endbr64
  ret
```

assistant: ```c
void func1(int var1, int var2) {
  var1 = var2 | var1;
  var1 = var2 | var1;
  var1 = var2 | var1;
  var1 = var2 & var1;
  var1 = var2 & var1;
  var1 = var2 & var1;
  var1 = var2 ^ var1;
  var1 = var2 ^ var1;
  var1 = var2 ^ var1;
  var1 = var2 <= var1;
  var1 = var2 <= var1;
  var1 = var2 <= var1;
  var1 = var2 >= var1;
  var1 = var2 >= var1;
  var1 = var2 >= var1;
  var1 = var2 == var1;
  var1 = var2 == var1;
  var1 = var2 == var1;
  var1 = var2 != var1;
  var1 = var2 != var1;
  var1 = var2 != var1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%edx
  shl    $0x2,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x4,-0xc(%rbp)
  ja     L12
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D1(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D80
type_guessed: string
name: retrieve_data
arguments: label: D28
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D88
type_guessed: string
name: retrieve_data
arguments: label: D82
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string
name: retrieve_data
arguments: label: D48
type_guessed: string

tool: D80: Think of your favorite number and enter it:


tool: D28: %d

tool: D6: Absolutely Certain.


tool: D88: Ask again.


tool: D82: The answer is no.


tool: D18: Outcome Unclear.


tool: D48: Definitely not.


assistant: ```c
int main() {
  int number;
  int turn;
  printf("Think of your favorite number and enter it:\n");
  scanf("%d", &number);
  srand(time(NULL));
  turn = rand() % 5;
  switch (turn) {
  case 0:
    printf("Absolutely Certain.\n");
    break;
  case 1:
    printf("Ask again.\n");
    break;
  case 2:
    printf("The answer is no.\n");
    break;
  case 3:
    printf("Outcome Unclear.\n");
    break;
  case 4:
    printf("Definitely not.\n");
    break;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  cmp    $0x4,%eax
  ja     L42
  mov    %eax,%eax
  lea    D46(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D24(%rip),%rdi
  call   <printf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L42
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L42
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L42
  lea    D67(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D38
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D24
data_type: string
name: parse_data
arguments: data_label: D5
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D34
data_type: string
name: parse_data
arguments: data_label: D67
data_type: string

tool: D38: Think of your favorite number and enter it:


tool: D10: %d

tool: D24: Absolutely Certain.


tool: D5: Ask again.


tool: D7: The answer is no.


tool: D34: Outcome Unclear.


tool: D67: Definitely not.


assistant: ```c
int main() {
  int number;
  int turn;
  printf("Think of your favorite number and enter it:\n");
  scanf("%d", &number);
  srand(time(NULL));
  turn = rand() % 5;
  switch (turn) {
  case 0:
    printf("Absolutely Certain.\n");
    break;
  case 1:
    printf("Ask again.\n");
    break;
  case 2:
    printf("The answer is no.\n");
    break;
  case 3:
    printf("Outcome Unclear.\n");
    break;
  case 4:
    printf("Definitely not.\n");
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D62(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x21,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  cmp    $0x4,%eax
  ja     L4
  lea    D57(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D15(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L4
  lea    D72(%rip),%rdi
  call   <printf@plt>
  jmp    L4
  lea    D49(%rip),%rdi
  call   <printf@plt>
  jmp    L4
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D62
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D72
type_guessed: string
name: extract_symbolic_data
arguments: tag: D49
type_guessed: string
name: extract_symbolic_data
arguments: tag: D45
type_guessed: string

tool: D62: Think of your favorite number and enter it:


tool: D9: %d

tool: D15: Definitely not.


tool: D19: Outcome Unclear.


tool: D72: Absolutely Certain.


tool: D49: Ask again.


tool: D45: The answer is no.


assistant: ```c
int main() {
  int number;
  int turn;
  printf("Think of your favorite number and enter it:\n");
  scanf("%d", &number);
  srand(time(NULL));
  turn = rand() % 5;
  switch (turn) {
  case 0:
    printf("Absolutely Certain.\n");
    break;
  case 1:
    printf("Ask again.\n");
    break;
  case 2:
    printf("The answer is no.\n");
    break;
  case 3:
    printf("Outcome Unclear.\n");
    break;
  case 4:
    printf("Definitely not.\n");
    break;
  }
  return 0;
}
```