ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L77
L12:
  lea    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L37
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L77
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L77
L37:
  mov    -0x14(%rbp),%eax
  mov    -0x18(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L77
  mov    -0x14(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
L77:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L12
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L89
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L71
L89:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L71:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D36
data_type: string
name: unpack_data
arguments: data_tag: D21
data_type: string
name: unpack_data
arguments: data_tag: D32
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string

tool: D36: %d

tool: D21: %d %d

tool: D32: 1 %d

tool: D26: 2 %d

assistant: ```c
int main() {
  int cases, round_score[2], score[2] = {0, 0}, largest[2] = {0, 0};
  scanf("%d", &cases);
  while (cases--) {
    scanf("%d %d", &round_score[0], &round_score[1]);
    score[0] += round_score[0];
    score[1] += round_score[1];
    if (score[0] > score[1]) {
      if (score[0] - score[1] > largest[0])
        largest[0] = score[0] - score[1];
    } else {
      if (score[1] - score[0] > largest[1])
        largest[1] = score[1] - score[0];
    }
  }
  if (largest[0] > largest[1])
    printf("1 %d", largest[0]);
  else
    printf("2 %d", largest[1]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  lea    -0x1(%rbx),%eax
  mov    %eax,0xc(%rsp)
  test   %ebx,%ebx
  je     L17
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    D29(%rip),%r14
  jmp    L64
L10:
  sub    %edx,%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
L15:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L9
L64:
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rdx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %ebp,%edx
  add    0x10(%rsp),%edx
  mov    %edx,%ebp
  mov    %r12d,%eax
  add    0x14(%rsp),%eax
  mov    %eax,%r12d
  cmp    %eax,%edx
  jle    L10
  sub    %eax,%edx
  cmp    %edx,%r13d
  cmovl  %edx,%r13d
  jmp    L15
L9:
  cmp    %r13d,%ebx
  jge    L17
  mov    %r13d,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    %ebx,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D28
datatype: string
name: extract_symbolic_data
arguments: tag: D29
datatype: string
name: extract_symbolic_data
arguments: tag: D26
datatype: string
name: extract_symbolic_data
arguments: tag: D38
datatype: string

tool: D28: %d

tool: D29: %d %d

tool: D26: 1 %d

tool: D38: 2 %d

assistant: ```c
int main() {
  int cases, round_score[2], score[2] = {0, 0}, largest[2] = {0, 0};
  scanf("%d", &cases);
  while (cases--) {
    scanf("%d %d", &round_score[0], &round_score[1]);
    score[0] += round_score[0];
    score[1] += round_score[1];
    if (score[0] > score[1]) {
      if (score[0] - score[1] > largest[0])
        largest[0] = score[0] - score[1];
    } else {
      if (score[1] - score[0] > largest[1])
        largest[1] = score[1] - score[0];
    }
  }
  if (largest[0] > largest[1])
    printf("1 %d", largest[0]);
  else
    printf("2 %d", largest[1]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D11(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%r12d
  lea    -0x1(%r12),%eax
  mov    %eax,0x1c(%rsp)
  test   %r12d,%r12d
  je     L28
  movl   $0x0,0xc(%rsp)
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r15
  lea    0x24(%rsp),%r14
  lea    D16(%rip),%r13
  jmp    L47
  nopl   0x0(%rax)
L40:
  mov    0xc(%rsp),%ecx
  mov    %ebx,%eax
  sub    %ebp,%eax
  cmp    %eax,%ecx
  cmovge %ecx,%eax
  mov    %eax,0xc(%rsp)
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  je     L34
L47:
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    0x20(%rsp),%ebx
  add    0x24(%rsp),%ebp
  cmp    %ebp,%ebx
  jg     L40
  mov    %ebp,%eax
  sub    %ebx,%eax
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  jne    L47
L34:
  mov    0xc(%rsp),%esi
  cmp    %esi,%r12d
  jge    L28
  lea    D1(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    %r12d,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D1
datatype: string
name: retrieve_data
arguments: tag: D32
datatype: string

tool: D11: %d

tool: D16: %d %d

tool: D1: 1 %d

tool: D32: 2 %d

assistant: ```c
int main() {
  int cases, round_score[2], score[2] = {0, 0}, largest[2] = {0, 0};
  scanf("%d", &cases);
  while (cases--) {
    scanf("%d %d", &round_score[0], &round_score[1]);
    score[0] += round_score[0];
    score[1] += round_score[1];
    if (score[0] > score[1]) {
      if (score[0] - score[1] > largest[0])
        largest[0] = score[0] - score[1];
    } else {
      if (score[1] - score[0] > largest[1])
        largest[1] = score[1] - score[0];
    }
  }
  if (largest[0] > largest[1])
    printf("1 %d", largest[0]);
  else
    printf("2 %d", largest[1]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D35(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%r12d
  lea    -0x1(%r12),%eax
  mov    %eax,0x1c(%rsp)
  test   %r12d,%r12d
  je     L31
  movl   $0x0,0xc(%rsp)
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r15
  lea    0x24(%rsp),%r14
  lea    D37(%rip),%r13
  jmp    L11
  nopl   0x0(%rax)
L4:
  mov    0xc(%rsp),%ecx
  mov    %ebx,%eax
  sub    %ebp,%eax
  cmp    %eax,%ecx
  cmovge %ecx,%eax
  mov    %eax,0xc(%rsp)
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  je     L62
L11:
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    0x20(%rsp),%ebx
  add    0x24(%rsp),%ebp
  cmp    %ebp,%ebx
  jg     L4
  mov    %ebp,%eax
  sub    %ebx,%eax
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  jne    L11
L62:
  mov    0xc(%rsp),%esi
  cmp    %esi,%r12d
  jge    L31
  lea    D11(%rip),%rdi
  call   <printf@plt>
L69:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  mov    %r12d,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D35
data_type: string
name: disassemble_data
arguments: data_label: D37
data_type: string
name: disassemble_data
arguments: data_label: D11
data_type: string
name: disassemble_data
arguments: data_label: D33
data_type: string

tool: D35: %d

tool: D37: %d %d

tool: D11: 1 %d

tool: D33: 2 %d

assistant: ```c
int main() {
  int cases, round_score[2], score[2] = {0, 0}, largest[2] = {0, 0};
  scanf("%d", &cases);
  while (cases--) {
    scanf("%d %d", &round_score[0], &round_score[1]);
    score[0] += round_score[0];
    score[1] += round_score[1];
    if (score[0] > score[1]) {
      if (score[0] - score[1] > largest[0])
        largest[0] = score[0] - score[1];
    } else {
      if (score[1] - score[0] > largest[1])
        largest[1] = score[1] - score[0];
    }
  }
  if (largest[0] > largest[1])
    printf("1 %d", largest[0]);
  else
    printf("2 %d", largest[1]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <PrinterError@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char string[100] = {0};
  fflush(stdin);
  gets(string);
  char *result = PrinterError(string);
  puts(result);
  free(result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <PrinterError@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char string[100] = {0};
  fflush(stdin);
  gets(string);
  char *result = PrinterError(string);
  puts(result);
  free(result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  mov    (%rax),%edi
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <PrinterError@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char string[100] = {0};
  fflush(stdin);
  gets(string);
  char *result = PrinterError(string);
  puts(result);
  free(result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  mov    (%rax),%edi
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movl   $0x0,0x60(%rsp)
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <PrinterError@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char string[100] = {0};
  fflush(stdin);
  gets(string);
  char *result = PrinterError(string);
  puts(result);
  free(result);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ntoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isnum@plt>
  test   %rax,%rax
  je     L2
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L19
L2:
  mov    $0xffffffff,%eax
L19:
  leave
  ret
```

assistant: ```c
int ntoi(char c) {
  if (isnum(c))
    return c - '0';
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ntoi>:
  endbr64
  push   %rbx
  movsbl %dil,%ebx
  mov    %ebx,%edi
  call   <isnum@plt>
  sub    $0x30,%ebx
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ntoi(char c) {
  if (isnum(c))
    return c - '0';
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ntoi>:
  endbr64
  push   %rbx
  movsbl %dil,%ebx
  mov    %ebx,%edi
  sub    $0x30,%ebx
  call   <isnum@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ntoi(char c) {
  if (isnum(c))
    return c - '0';
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ntoi>:
  endbr64
  push   %rbx
  movsbl %dil,%ebx
  mov    %ebx,%edi
  sub    $0x30,%ebx
  call   <isnum@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ntoi(char c) {
  if (isnum(c))
    return c - '0';
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fgetl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0x1,%esi
  mov    $0x80,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L97
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  mov    $0x80,%r14d
  jmp    L141
L143:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L51
  mov    D13(%rip),%rax
  cmp    %ebx,(%rax)
  je     L61
  mov    %bl,(%r12,%rbp,1)
  add    $0x1,%rbp
L141:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L61
  mov    %r14d,%ebx
  cmp    %rbp,%rbx
  ja     L143
  lea    (%r14,%r14,1),%r15d
  mov    %r15d,%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  lea    (%rax,%rbx,1),%rdi
  mov    %r14d,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %r15d,%r14d
  jmp    L143
L61:
  test   %rbp,%rbp
  jne    L67
  cmp    $0xd,%ebx
  je     L81
  cmp    $0xa,%ebx
  je     L81
  mov    D13(%rip),%rax
  cmp    %ebx,(%rax)
  je     L81
L107:
  movb   $0x0,(%r12,%rbp,1)
L97:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L81:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%r12d
  jmp    L97
L51:
  test   %rbp,%rbp
  je     L81
L67:
  lea    -0x1(%r12,%rbp,1),%rax
  cmpb   $0xd,(%rax)
  jne    L107
  cmpb   $0xa,(%r12,%rbp,1)
  jne    L107
  movb   $0x0,(%rax)
  jmp    L107
```

assistant: ```c
char *fgetl(FILE *stream) {
  unsigned int length = 128, old_length;
  char *line;
  int byte, previous_byte;
  size_t idx_line;
  line = calloc(length, sizeof(*line));
  if (!line)
    return NULL;
  previous_byte = 0;
  byte = 0;
  idx_line = 0;
  while (!feof(stream)) {
    if (idx_line >= length) {
      old_length = length;
      length = length * 2;
      line = realloc(line, length * sizeof(*line));
      memset(line + old_length, 0, old_length);
    }
    byte = fgetc(stream);
    if ((previous_byte == '\r' && byte == '\n') || (previous_byte != '\r' && byte == '\n') || byte == EOF)
      break;
    previous_byte = byte;
    line[idx_line] = byte;
    idx_line++;
  }
  if (idx_line == 0 && (byte == '\r' || byte == '\n' || byte == EOF)) {
    free(line);
    return NULL;
  }
  if (idx_line && line[idx_line - 1] == '\r' && line[idx_line] == '\n')
    line[idx_line - 1] = '\0';
  line[idx_line] = '\0';
  return line;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fgetl>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x80,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L58
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  mov    $0x80,%r14d
  jmp    L134
  nopl   0x0(%rax)
L10:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L52
L136:
  mov    D12(%rip),%rax
  cmp    %ebx,(%rax)
  je     L40
  mov    %bl,(%r12,%rbp,1)
  add    $0x1,%rbp
L134:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L40
  mov    %r14d,%ebx
  cmp    %rbp,%rbx
  ja     L10
  lea    (%r14,%r14,1),%r15d
  mov    %r12,%rdi
  mov    %r15d,%esi
  call   <realloc@plt>
  mov    %r14d,%edx
  xor    %esi,%esi
  mov    %r15d,%r14d
  lea    (%rax,%rbx,1),%rdi
  mov    %rax,%r12
  call   <memset@plt>
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  jne    L136
L52:
  test   %rbp,%rbp
  je     L143
L139:
  lea    -0x1(%r12,%rbp,1),%rax
  add    %r12,%rbp
  cmpb   $0xd,(%rax)
  jne    L94
  cmpb   $0xa,0x0(%rbp)
  jne    L94
  movb   $0x0,(%rax)
  jmp    L94
  nopl   (%rax)
L40:
  test   %rbp,%rbp
  jne    L139
  cmp    $0xd,%ebx
  je     L143
  cmp    $0xa,%ebx
  je     L143
  mov    D12(%rip),%rax
  mov    %r12,%rbp
  cmp    %ebx,(%rax)
  je     L143
L94:
  movb   $0x0,0x0(%rbp)
L58:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L143:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L58
```

assistant: ```c
char *fgetl(FILE *stream) {
  unsigned int length = 128, old_length;
  char *line;
  int byte, previous_byte;
  size_t idx_line;
  line = calloc(length, sizeof(*line));
  if (!line)
    return NULL;
  previous_byte = 0;
  byte = 0;
  idx_line = 0;
  while (!feof(stream)) {
    if (idx_line >= length) {
      old_length = length;
      length = length * 2;
      line = realloc(line, length * sizeof(*line));
      memset(line + old_length, 0, old_length);
    }
    byte = fgetc(stream);
    if ((previous_byte == '\r' && byte == '\n') || (previous_byte != '\r' && byte == '\n') || byte == EOF)
      break;
    previous_byte = byte;
    line[idx_line] = byte;
    idx_line++;
  }
  if (idx_line == 0 && (byte == '\r' || byte == '\n' || byte == EOF)) {
    free(line);
    return NULL;
  }
  if (idx_line && line[idx_line - 1] == '\r' && line[idx_line] == '\n')
    line[idx_line - 1] = '\0';
  line[idx_line] = '\0';
  return line;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fgetl>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x80,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L35
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  mov    $0x80,%r14d
  jmp    L70
  nopl   0x0(%rax)
L113:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L155
L43:
  mov    D8(%rip),%rax
  cmp    %ebx,(%rax)
  je     L129
  mov    %bl,(%r12,%rbp,1)
  add    $0x1,%rbp
L70:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L129
  mov    %r14d,%ebx
  cmp    %rbp,%rbx
  ja     L113
  lea    (%r14,%r14,1),%r15d
  mov    %r12,%rdi
  mov    %r15d,%esi
  call   <realloc@plt>
  mov    %r14d,%edx
  xor    %esi,%esi
  mov    %r15d,%r14d
  lea    (%rax,%rbx,1),%rdi
  mov    %rax,%r12
  call   <memset@plt>
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  jne    L43
L155:
  test   %rbp,%rbp
  je     L46
L21:
  lea    -0x1(%r12,%rbp,1),%rax
  add    %r12,%rbp
  cmpb   $0xd,(%rax)
  jne    L50
  cmpb   $0xa,0x0(%rbp)
  jne    L50
  movb   $0x0,(%rax)
  jmp    L50
  nopl   (%rax)
L129:
  test   %rbp,%rbp
  jne    L21
  cmp    $0xd,%ebx
  je     L46
  cmp    $0xa,%ebx
  je     L46
  mov    D8(%rip),%rax
  mov    %r12,%rbp
  cmp    %ebx,(%rax)
  je     L46
L50:
  movb   $0x0,0x0(%rbp)
L35:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L35
```

assistant: ```c
char *fgetl(FILE *stream) {
  unsigned int length = 128, old_length;
  char *line;
  int byte, previous_byte;
  size_t idx_line;
  line = calloc(length, sizeof(*line));
  if (!line)
    return NULL;
  previous_byte = 0;
  byte = 0;
  idx_line = 0;
  while (!feof(stream)) {
    if (idx_line >= length) {
      old_length = length;
      length = length * 2;
      line = realloc(line, length * sizeof(*line));
      memset(line + old_length, 0, old_length);
    }
    byte = fgetc(stream);
    if ((previous_byte == '\r' && byte == '\n') || (previous_byte != '\r' && byte == '\n') || byte == EOF)
      break;
    previous_byte = byte;
    line[idx_line] = byte;
    idx_line++;
  }
  if (idx_line == 0 && (byte == '\r' || byte == '\n' || byte == EOF)) {
    free(line);
    return NULL;
  }
  if (idx_line && line[idx_line - 1] == '\r' && line[idx_line] == '\n')
    line[idx_line - 1] = '\0';
  line[idx_line] = '\0';
  return line;
}
```