ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<s_app1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <s_strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <m_write@plt>
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int s_app1(int m, char *s) {
  int p = s_strlen(m);
  m_write(m, p, s, strlen(s) + 1);
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<s_app1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  call   <s_strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rcx
  mov    %rbp,%rdx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <m_write@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int s_app1(int m, char *s) {
  int p = s_strlen(m);
  m_write(m, p, s, strlen(s) + 1);
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<s_app1>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  call   <s_strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %r12d,%edi
  lea    0x1(%rax),%rcx
  call   <m_write@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int s_app1(int m, char *s) {
  int p = s_strlen(m);
  m_write(m, p, s, strlen(s) + 1);
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<s_app1>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  call   <s_strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %r12d,%edi
  lea    0x1(%rax),%rcx
  call   <m_write@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int s_app1(int m, char *s) {
  int p = s_strlen(m);
  m_write(m, p, s, strlen(s) + 1);
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x97000008,%eax
  movq   $0x100000,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L24:
  mov    $0x100,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%eax
  shl    $0x10,%rax
  and    $0xff0000,%eax
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  shl    $0x8,%rax
  movzwl %ax,%eax
  mov    %rdx,%rcx
  or     %rax,%rcx
  mov    -0x4(%rbp),%eax
  xor    $0x80,%al
  mov    %eax,%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rsi
  mov    $0x97000400,%eax
  add    %rsi,%rax
  or     %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0xff,-0x4(%rbp)
  jbe    L24
  mov    $0x97000000,%eax
  mov    $0xffffffff,%edi
  mov    %rdi,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L30:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    -0x4(%rbp),%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <hline@plt>
  mov    -0x4(%rbp),%eax
  add    $0x100,%eax
  mov    %eax,%edx
  mov    $0x100,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x100,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  call   <hline@plt>
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0xf,-0x4(%rbp)
  jbe    L30
  mov    $0xdeaddead,%edi
  call   <report@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned i;
  *((unsigned long *)(0x97000000) + 0x1) = 0x00100000;
  for (i = 0; i < 256; i++)
    *(((unsigned long *)(0x97000000 + 0x400)) + (i)) = (((unsigned long)(256 - i) & 0xff) << 16) | (((unsigned long)(i)&0xff) << 8) | (((unsigned long)(128 ^ i) & 0xff) << 0);
  *((unsigned long *)(0x97000000) + 0x0) = 0xffffffff;
  for (i = 0; i < 16; i++) {
    hline(i, 0, i, i);
    hline(256 - i, 256 - i, 256 + i, i);
  }
  report(0xdeaddead);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x97000008,%eax
  movq   $0x100000,(%rax)
  mov    $0x97000400,%edi
  mov    $0x1000000,%esi
  mov    $0x0,%edx
L2:
  mov    %rdx,%rax
  shl    $0x8,%rax
  movzwl %ax,%eax
  mov    %rsi,%rcx
  and    $0xff0000,%ecx
  or     %rcx,%rax
  mov    %edx,%ecx
  xor    $0x80,%cl
  movzbl %cl,%ecx
  or     %rcx,%rax
  mov    %rax,(%rdi)
  add    $0x1,%rdx
  sub    $0x10000,%rsi
  add    $0x8,%rdi
  cmp    $0x100,%rdx
  jne    L2
  mov    $0xffffffff,%eax
  movabs %rax,0x97000000
  mov    $0x0,%ebx
  mov    $0x100,%ebp
L10:
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <hline@plt>
  mov    %ebp,%edi
  sub    %ebx,%edi
  lea    0x100(%rbx),%edx
  mov    %ebx,%ecx
  mov    %edi,%esi
  call   <hline@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L10
  mov    $0xdeaddead,%edi
  call   <report@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  unsigned i;
  *((unsigned long *)(0x97000000) + 0x1) = 0x00100000;
  for (i = 0; i < 256; i++)
    *(((unsigned long *)(0x97000000 + 0x400)) + (i)) = (((unsigned long)(256 - i) & 0xff) << 16) | (((unsigned long)(i)&0xff) << 8) | (((unsigned long)(128 ^ i) & 0xff) << 0);
  *((unsigned long *)(0x97000000) + 0x0) = 0xffffffff;
  for (i = 0; i < 16; i++) {
    hline(i, 0, i, i);
    hline(256 - i, 256 - i, 256 + i, i);
  }
  report(0xdeaddead);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x97000008,%eax
  mov    $0x97000400,%esi
  mov    $0x1000000,%ecx
  push   %rbx
  xor    %edx,%edx
  sub    $0x8,%rsp
  movq   $0x100000,(%rax)
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rcx,%rax
  mov    %rdx,%rdi
  add    $0x8,%rsi
  sub    $0x10000,%rcx
  shl    $0x8,%rdi
  and    $0xff0000,%eax
  or     %rdi,%rax
  mov    %edx,%edi
  add    $0x1,%rdx
  xor    $0x80,%edi
  or     %rdi,%rax
  mov    %rax,-0x8(%rsi)
  cmp    $0x100,%rdx
  jne    L14
  mov    $0xffffffff,%eax
  xor    %ebx,%ebx
  mov    $0x100,%ebp
  movabs %rax,0x97000000
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %ebx,%edi
  xor    %esi,%esi
  call   <hline@plt>
  mov    %ebp,%edi
  lea    0x100(%rbx),%edx
  mov    %ebx,%ecx
  sub    %ebx,%edi
  add    $0x1,%ebx
  mov    %edi,%esi
  call   <hline@plt>
  cmp    $0x10,%ebx
  jne    L1
  mov    $0xdeaddead,%edi
  call   <report@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  unsigned i;
  *((unsigned long *)(0x97000000) + 0x1) = 0x00100000;
  for (i = 0; i < 256; i++)
    *(((unsigned long *)(0x97000000 + 0x400)) + (i)) = (((unsigned long)(256 - i) & 0xff) << 16) | (((unsigned long)(i)&0xff) << 8) | (((unsigned long)(128 ^ i) & 0xff) << 0);
  *((unsigned long *)(0x97000000) + 0x0) = 0xffffffff;
  for (i = 0; i < 16; i++) {
    hline(i, 0, i, i);
    hline(256 - i, 256 - i, 256 + i, i);
  }
  report(0xdeaddead);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x97000008,%eax
  mov    $0x97000400,%esi
  mov    $0x1000000,%ecx
  push   %rbx
  xor    %edx,%edx
  sub    $0x8,%rsp
  movq   $0x100000,(%rax)
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rcx,%rax
  mov    %rdx,%rdi
  add    $0x8,%rsi
  sub    $0x10000,%rcx
  shl    $0x8,%rdi
  and    $0xff0000,%eax
  or     %rdi,%rax
  mov    %edx,%edi
  add    $0x1,%rdx
  xor    $0x80,%edi
  or     %rdi,%rax
  mov    %rax,-0x8(%rsi)
  cmp    $0x100,%rdx
  jne    L11
  mov    $0xffffffff,%eax
  xor    %ebx,%ebx
  mov    $0x100,%ebp
  movabs %rax,0x97000000
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %ebx,%edi
  xor    %esi,%esi
  call   <hline@plt>
  mov    %ebp,%edi
  lea    0x100(%rbx),%edx
  mov    %ebx,%ecx
  sub    %ebx,%edi
  add    $0x1,%ebx
  mov    %edi,%esi
  call   <hline@plt>
  cmp    $0x10,%ebx
  jne    L2
  mov    $0xdeaddead,%edi
  call   <report@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  unsigned i;
  *((unsigned long *)(0x97000000) + 0x1) = 0x00100000;
  for (i = 0; i < 256; i++)
    *(((unsigned long *)(0x97000000 + 0x400)) + (i)) = (((unsigned long)(256 - i) & 0xff) << 16) | (((unsigned long)(i)&0xff) << 8) | (((unsigned long)(128 ^ i) & 0xff) << 0);
  *((unsigned long *)(0x97000000) + 0x0) = 0xffffffff;
  for (i = 0; i < 16; i++) {
    hline(i, 0, i, i);
    hline(256 - i, 256 - i, 256 + i, i);
  }
  report(0xdeaddead);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sck_recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L5
  mov    $0xffffffff,%eax
  jmp    L12
L5:
  mov    -0x4(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int sck_recv(int s, char *buffer, size_t size) {
  int rc;
  rc = recv(s, buffer, size, 0);
  if (rc <= 0)
    return -1;
  return rc;
}
```
user: What is the c source code of the assembly code below?

```asm
<sck_recv>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  call   <recv@plt>
  test   %eax,%eax
  jle    L4
L9:
  add    $0x8,%rsp
  ret
L4:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int sck_recv(int s, char *buffer, size_t size) {
  int rc;
  rc = recv(s, buffer, size, 0);
  if (rc <= 0)
    return -1;
  return rc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sck_recv>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  call   <recv@plt>
  test   %eax,%eax
  jle    L0
L5:
  add    $0x8,%rsp
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int sck_recv(int s, char *buffer, size_t size) {
  int rc;
  rc = recv(s, buffer, size, 0);
  if (rc <= 0)
    return -1;
  return rc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sck_recv>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  call   <recv@plt>
  test   %eax,%eax
  jle    L9
L14:
  add    $0x8,%rsp
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int sck_recv(int s, char *buffer, size_t size) {
  int rc;
  rc = recv(s, buffer, size, 0);
  if (rc <= 0)
    return -1;
  return rc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string
name: parse_data
arguments: data_label: D8
type: string

tool: D9: My stack looks like:
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p



tool: D8: Now the stack looks like:
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p



assistant: ```c
void foo(const char *input) {
  char buf[10];
  printf("My stack looks like:\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n\n");
  strcpy(buf, input);
  printf("%s\n", buf);
  printf("Now the stack looks like:\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    0xe(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_guessed: string
name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D19: My stack looks like:
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p



tool: D8: Now the stack looks like:
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p



assistant: ```c
void foo(const char *input) {
  char buf[10];
  printf("My stack looks like:\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n\n");
  strcpy(buf, input);
  printf("%s\n", buf);
  printf("Now the stack looks like:\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D16(%rip),%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string

tool: D16: My stack looks like:
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p



tool: D11: Now the stack looks like:
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p



assistant: ```c
void foo(const char *input) {
  char buf[10];
  printf("My stack looks like:\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n\n");
  strcpy(buf, input);
  printf("%s\n", buf);
  printf("Now the stack looks like:\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D18(%rip),%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D9
type: string

tool: D18: My stack looks like:
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p



tool: D9: Now the stack looks like:
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p
%p



assistant: ```c
void foo(const char *input) {
  char buf[10];
  printf("My stack looks like:\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n\n");
  strcpy(buf, input);
  printf("%s\n", buf);
  printf("Now the stack looks like:\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n%p\n\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strTrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L44
L32:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L35
  cmpq   $0x0,-0x28(%rbp)
  je     L35
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L106
L34:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L106:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L114
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L34
L114:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L35:
  cmpl   $0x0,-0xc(%rbp)
  je     L111
  cmpq   $0x0,-0x20(%rbp)
  je     L111
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L57
L90:
  addq   $0x1,-0x8(%rbp)
L57:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L116
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L90
L116:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L40
L115:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L115
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L111:
  mov    -0xc(%rbp),%eax
L44:
  leave
  ret
```

assistant: ```c
int strTrim(char *s, char *left, char *right) {
  int len;
  char *cp;
  if (!s)
    return 0;
  len = strlen(s);
  if (len && right) {
    cp = s + len - 1;
    while (cp >= s && strchr(right, *cp))
      *cp-- = '\0';
    len = cp - s + 1;
  }
  if (len && left) {
    cp = s;
    while (*cp && strchr(left, *cp))
      ++cp;
    len = len - (cp - s);
    while (*cp)
      *s++ = *cp++;
    *s = '\0';
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strTrim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  test   %rdi,%rdi
  je     L37
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  call   <strlen@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L111
  test   %r14,%r14
  je     L111
  movslq %eax,%rbp
  lea    -0x1(%r12,%rbp,1),%rbx
  cmp    %rbx,%r12
  ja     L28
L94:
  movsbl (%rbx),%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L28
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%r12
  jbe    L94
L28:
  sub    %r12,%rbx
  lea    0x1(%rbx),%ebp
L111:
  test   %ebp,%ebp
  je     L37
  test   %r13,%r13
  je     L37
  movzbl (%r12),%esi
  mov    %r12,%rbx
  test   %sil,%sil
  je     L48
L91:
  movsbl %sil,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L62
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L91
L48:
  sub    %r12,%rbx
  sub    %ebx,%ebp
  jmp    L102
L62:
  mov    %rbx,%rax
  sub    %r12,%rax
  sub    %eax,%ebp
  movzbl (%rbx),%eax
  test   %al,%al
  je     L102
L114:
  add    $0x1,%rbx
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L114
L102:
  movb   $0x0,(%r12)
L37:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strTrim(char *s, char *left, char *right) {
  int len;
  char *cp;
  if (!s)
    return 0;
  len = strlen(s);
  if (len && right) {
    cp = s + len - 1;
    while (cp >= s && strchr(right, *cp))
      *cp-- = '\0';
    len = cp - s + 1;
  }
  if (len && left) {
    cp = s;
    while (*cp && strchr(left, *cp))
      ++cp;
    len = len - (cp - s);
    while (*cp)
      *s++ = *cp++;
    *s = '\0';
  }
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strTrim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L151
  mov    %rdx,%r14
  mov    %rdi,%rbx
  mov    %rsi,%r13
  call   <strlen@plt>
  movslq %eax,%r12
  test   %r12d,%r12d
  setne  %al
  mov    %eax,%edx
  test   %r14,%r14
  je     L107
  test   %al,%al
  je     L107
  lea    -0x1(%rbx,%r12,1),%rbp
  cmp    %rbp,%rbx
  jbe    L149
  jmp    L104
  cs nopw 0x0(%rax,%rax,1)
L118:
  sub    $0x1,%rbp
  movb   $0x0,0x1(%rbp)
  cmp    %rbp,%rbx
  ja     L104
L149:
  movsbl 0x0(%rbp),%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L118
L104:
  sub    %rbx,%rbp
  mov    %ebp,%r12d
  add    $0x1,%r12d
  setne  %dl
L107:
  test   %r13,%r13
  je     L151
  test   %dl,%dl
  je     L151
  movsbl (%rbx),%esi
  mov    %rbx,%rbp
  test   %sil,%sil
  jne    L2
  jmp    L30
  nopl   0x0(%rax)
L84:
  movsbl 0x1(%rbp),%esi
  add    $0x1,%rbp
  test   %sil,%sil
  je     L98
L2:
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L84
  mov    %rbp,%rax
  sub    %rbx,%rax
  sub    %eax,%r12d
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L163
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x1,%rbp
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L56
L163:
  movb   $0x0,(%rbx)
L151:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L98:
  sub    %ebx,%ebp
L101:
  sub    %ebp,%r12d
  jmp    L163
L30:
  xor    %ebp,%ebp
  jmp    L101
```

assistant: ```c
int strTrim(char *s, char *left, char *right) {
  int len;
  char *cp;
  if (!s)
    return 0;
  len = strlen(s);
  if (len && right) {
    cp = s + len - 1;
    while (cp >= s && strchr(right, *cp))
      *cp-- = '\0';
    len = cp - s + 1;
  }
  if (len && left) {
    cp = s;
    while (*cp && strchr(left, *cp))
      ++cp;
    len = len - (cp - s);
    while (*cp)
      *s++ = *cp++;
    *s = '\0';
  }
  return len;
}
```