ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strrchr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %esi,%ebx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L16
  nopl   0x0(%rax)
L19:
  lea    0x1(%rax),%rdi
  mov    %ebx,%esi
  mov    %rax,%r12
  call   <strchr@plt>
  test   %rax,%rax
  jne    L19
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *last = NULL;
  char *test = (char *)s;
  while (test != NULL) {
    test = strchr(test, c);
    if (test != NULL) {
      last = test;
      ++test;
    }
  }
  return last;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  D19(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L5
  pxor   %xmm0,%xmm0
  jmp    L22
L5:
  movsd  D2(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L34
  movsd  -0x8(%rbp),%xmm0
  movsd  D19(%rip),%xmm1
  subsd  %xmm1,%xmm0
  jmp    L22
L34:
  movsd  D33(%rip),%xmm0
  subsd  -0x8(%rbp),%xmm0
L22:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type_infered: f64
name: read_data
arguments: data_tag: D2
type_infered: byte[8]
name: read_data
arguments: data_tag: D33
type_infered: byte[8]

tool: D19: 3.14159265

tool: {"D2": [0xb5,0x9f,0xd6,0x7e,0x7c,0xd9,0x12,0x40]}

tool: {"D33": [0xf1,0xd4,0xc8,0x53,0xfb,0x21,0x19,0x40]}

assistant: ```c
double func_(double x) {
  if (x < 3.14159265)
    return 0;
  if (x < (3 * 3.14159265) / 2)
    return x - 3.14159265;
  return -x + 2 * 3.14159265;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func_>:
  endbr64
  movsd  D3(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L26
  movsd  D21(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L29
  movsd  D32(%rip),%xmm1
  subsd  %xmm0,%xmm1
L22:
  movapd %xmm1,%xmm0
  ret
L29:
  movapd %xmm0,%xmm1
  subsd  D3(%rip),%xmm1
  jmp    L22
L26:
  pxor   %xmm1,%xmm1
  jmp    L22
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: f64
name: retrieve_data
arguments: label: D21
type_guessed: byte[8]
name: retrieve_data
arguments: label: D32
type_guessed: byte[8]

tool: D3: 3.14159265

tool: {"D21": [0xb5,0x9f,0xd6,0x7e,0x7c,0xd9,0x12,0x40]}

tool: {"D32": [0xf1,0xd4,0xc8,0x53,0xfb,0x21,0x19,0x40]}

assistant: ```c
double func_(double x) {
  if (x < 3.14159265)
    return 0;
  if (x < (3 * 3.14159265) / 2)
    return x - 3.14159265;
  return -x + 2 * 3.14159265;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func_>:
  endbr64
  movsd  D29(%rip),%xmm2
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm2
  ja     L15
  movsd  D27(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L11
  movsd  D26(%rip),%xmm1
  subsd  %xmm0,%xmm1
L15:
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L11:
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_infered: f64
name: extract_symbolic_data
arguments: tag: D27
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D26
type_infered: byte[8]

tool: D29: 3.14159265

tool: {"D27": [0xb5,0x9f,0xd6,0x7e,0x7c,0xd9,0x12,0x40]}

tool: {"D26": [0xf1,0xd4,0xc8,0x53,0xfb,0x21,0x19,0x40]}

assistant: ```c
double func_(double x) {
  if (x < 3.14159265)
    return 0;
  if (x < (3 * 3.14159265) / 2)
    return x - 3.14159265;
  return -x + 2 * 3.14159265;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func_>:
  endbr64
  movsd  D9(%rip),%xmm2
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm2
  ja     L0
  movsd  D26(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L5
  movsd  D23(%rip),%xmm1
  subsd  %xmm0,%xmm1
L0:
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L5:
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: f64
name: disassemble_data
arguments: data_tag: D26
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D23
type_guessed: byte[8]

tool: D9: 3.14159265

tool: {"D26": [0xb5,0x9f,0xd6,0x7e,0x7c,0xd9,0x12,0x40]}

tool: {"D23": [0xf1,0xd4,0xc8,0x53,0xfb,0x21,0x19,0x40]}

assistant: ```c
double func_(double x) {
  if (x < 3.14159265)
    return 0;
  if (x < (3 * 3.14159265) / 2)
    return x - 3.14159265;
  return -x + 2 * 3.14159265;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<concatestrings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L34
L18:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
L34:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x1c(%rbp)
  jl     L18
  movl   $0x0,-0x1c(%rbp)
  jmp    L23
L32:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
L23:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x1c(%rbp)
  jl     L32
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *concatestrings(char *s1, char *s2) {
  char *result = malloc(strlen(s1) + strlen(s2) + 1);
  int i = 0;
  int j;
  for (j = 0; j < strlen(s1); j++) {
    result[i] = s1[j];
    i++;
  }
  for (j = 0; j < strlen(s2); j++) {
    result[i] = s2[j];
    i++;
  }
  result[i] = '\0';
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<concatestrings>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  jmp    L24
L0:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  mov    $0x0,%ebp
  movslq %ebx,%r14
  jmp    L3
L26:
  movzbl 0x0(%r13,%rbp,1),%edx
  lea    (%r12,%r14,1),%rax
  mov    %dl,(%rax,%rbp,1)
  add    $0x1,%rbp
L3:
  lea    (%rbx,%rbp,1),%r15d
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L26
  movslq %r15d,%r15
  movb   $0x0,(%r12,%r15,1)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *concatestrings(char *s1, char *s2) {
  char *result = malloc(strlen(s1) + strlen(s2) + 1);
  int i = 0;
  int j;
  for (j = 0; j < strlen(s1); j++) {
    result[i] = s1[j];
    i++;
  }
  for (j = 0; j < strlen(s2); j++) {
    result[i] = s2[j];
    i++;
  }
  result[i] = '\0';
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<concatestrings>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  jmp    L11
  nopl   0x0(%rax)
L20:
  movzbl (%r14,%rbx,1),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L11:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L20
  movslq %ebx,%rbx
  xor    %ebp,%ebp
  add    %r13,%rbx
  jmp    L4
  nopl   0x0(%rax)
L27:
  movzbl (%r12,%rbp,1),%eax
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbx)
L4:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L27
  movb   $0x0,(%rbx)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *concatestrings(char *s1, char *s2) {
  char *result = malloc(strlen(s1) + strlen(s2) + 1);
  int i = 0;
  int j;
  for (j = 0; j < strlen(s1); j++) {
    result[i] = s1[j];
    i++;
  }
  for (j = 0; j < strlen(s2); j++) {
    result[i] = s2[j];
    i++;
  }
  result[i] = '\0';
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<concatestrings>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  jmp    L17
  nopl   0x0(%rax)
L3:
  movzbl (%r14,%rbx,1),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L17:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L3
  movslq %ebx,%rbx
  xor    %ebp,%ebp
  add    %r13,%rbx
  jmp    L20
  nopl   0x0(%rax)
L31:
  movzbl (%r12,%rbp,1),%eax
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbx)
L20:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L31
  movb   $0x0,(%rbx)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *concatestrings(char *s1, char *s2) {
  char *result = malloc(strlen(s1) + strlen(s2) + 1);
  int i = 0;
  int j;
  for (j = 0; j < strlen(s1); j++) {
    result[i] = s1[j];
    i++;
  }
  for (j = 0; j < strlen(s2); j++) {
    result[i] = s2[j];
    i++;
  }
  result[i] = '\0';
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string

tool: D5: Hell! O' world, why won't my code compile?



assistant: ```c
int main(void) {
  printf("Hell! O' world, why won't my code compile?\n\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: Hell! O' world, why won't my code compile?



assistant: ```c
int main(void) {
  printf("Hell! O' world, why won't my code compile?\n\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Hell! O' world, why won't my code compile?



assistant: ```c
int main(void) {
  printf("Hell! O' world, why won't my code compile?\n\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: Hell! O' world, why won't my code compile?



assistant: ```c
int main(void) {
  printf("Hell! O' world, why won't my code compile?\n\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sock_set_recvtimeout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,-0xc(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int sock_set_recvtimeout(int sock, int seconds) {
  struct timeval timeval;
  memset(&timeval, 0, sizeof(timeval));
  timeval.tv_sec = 1;
  return setsockopt(sock, SOL_SOCKET, SO_RCVTIMEO, &timeval, sizeof(timeval));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sock_set_recvtimeout>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  movl   $0x1,0x4(%rsp)
  mov    $0x4,%r8d
  mov    %rbp,%rcx
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_set_recvtimeout(int sock, int seconds) {
  struct timeval timeval;
  memset(&timeval, 0, sizeof(timeval));
  timeval.tv_sec = 1;
  return setsockopt(sock, SOL_SOCKET, SO_RCVTIMEO, &timeval, sizeof(timeval));
}
```
user: What is the c source code of the assembly code below?

```asm
<sock_set_recvtimeout>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x4,%r8d
  mov    %r12,%rcx
  mov    %ebp,%edi
  mov    D1(%rip),%rax
  movl   $0x1,0x4(%rsp)
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_set_recvtimeout(int sock, int seconds) {
  struct timeval timeval;
  memset(&timeval, 0, sizeof(timeval));
  timeval.tv_sec = 1;
  return setsockopt(sock, SOL_SOCKET, SO_RCVTIMEO, &timeval, sizeof(timeval));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sock_set_recvtimeout>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x4,%r8d
  mov    %r12,%rcx
  mov    %ebp,%edi
  mov    D13(%rip),%rax
  movl   $0x1,0x4(%rsp)
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_set_recvtimeout(int sock, int seconds) {
  struct timeval timeval;
  memset(&timeval, 0, sizeof(timeval));
  timeval.tv_sec = 1;
  return setsockopt(sock, SOL_SOCKET, SO_RCVTIMEO, &timeval, sizeof(timeval));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CalcCols>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x4,-0x1(%rbp)
  jmp    L32
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L10
  mov    $0x1b,%eax
  jmp    L14
L10:
  mov    $0x0,%eax
L14:
  xor    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  movzbl -0x1(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x1(%rbp)
L32:
  cmpb   $0x0,-0x1(%rbp)
  jne    L37
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CalcCols(unsigned char *col) {
  unsigned char i;
  for (i = 4; i > 0; i--) {
    *col = (*col << 1) ^ (*col & 0x80 ? 0x1b : 0);
    col++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CalcCols>:
  endbr64
  lea    0x4(%rdi),%rcx
L7:
  movzbl (%rdi),%eax
  lea    (%rax,%rax,1),%edx
  sar    $0x7,%al
  and    $0x1b,%eax
  xor    %edx,%eax
  mov    %al,(%rdi)
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L7
  ret
```

assistant: ```c
void CalcCols(unsigned char *col) {
  unsigned char i;
  for (i = 4; i > 0; i--) {
    *col = (*col << 1) ^ (*col & 0x80 ? 0x1b : 0);
    col++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CalcCols>:
  endbr64
  lea    0x4(%rdi),%rsi
L3:
  movzbl (%rdi),%eax
  mov    %eax,%edx
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x1b,%ecx
  test   %dl,%dl
  cmovs  %ecx,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rsi,%rdi
  jne    L3
  ret
```

assistant: ```c
void CalcCols(unsigned char *col) {
  unsigned char i;
  for (i = 4; i > 0; i--) {
    *col = (*col << 1) ^ (*col & 0x80 ? 0x1b : 0);
    col++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CalcCols>:
  endbr64
  movzbl (%rdi),%edx
  mov    %edx,%ecx
  add    %edx,%edx
  mov    %edx,%esi
  xor    $0x1b,%esi
  test   %cl,%cl
  cmovs  %esi,%edx
  mov    %dl,(%rdi)
  movzbl 0x1(%rdi),%edx
  mov    %edx,%ecx
  add    %edx,%edx
  mov    %edx,%esi
  xor    $0x1b,%esi
  test   %cl,%cl
  cmovs  %esi,%edx
  mov    %dl,0x1(%rdi)
  movzbl 0x2(%rdi),%edx
  mov    %edx,%ecx
  add    %edx,%edx
  mov    %edx,%esi
  xor    $0x1b,%esi
  test   %cl,%cl
  cmovs  %esi,%edx
  mov    %dl,0x2(%rdi)
  movzbl 0x3(%rdi),%edx
  mov    %edx,%ecx
  add    %edx,%edx
  mov    %edx,%esi
  xor    $0x1b,%esi
  test   %cl,%cl
  cmovs  %esi,%edx
  mov    %dl,0x3(%rdi)
  ret
```

assistant: ```c
void CalcCols(unsigned char *col) {
  unsigned char i;
  for (i = 4; i > 0; i--) {
    *col = (*col << 1) ^ (*col & 0x80 ? 0x1b : 0);
    col++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bit_array_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L46
L37:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L35
  mov    $0xffffffff,%eax
  jmp    L25
L35:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L11
  mov    $0x1,%eax
  jmp    L25
L11:
  addl   $0x1,-0x4(%rbp)
L46:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L37
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int bit_array_cmp(int len, uint64_t *a, uint64_t *b) {
  for (int i = 0; i < len; i++) {
    if (a[i] < b[i])
      return -1;
    if (a[i] > b[i])
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bit_array_cmp>:
  endbr64
  test   %edi,%edi
  jle    L19
  mov    %edi,%edi
  mov    $0x0,%eax
L28:
  mov    (%rsi,%rax,8),%r8
  mov    (%rdx,%rax,8),%rcx
  cmp    %rcx,%r8
  jl     L35
  jg     L11
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L28
  mov    $0x0,%eax
  ret
L19:
  mov    $0x0,%eax
  ret
L35:
  mov    $0xffffffff,%eax
  ret
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int bit_array_cmp(int len, uint64_t *a, uint64_t *b) {
  for (int i = 0; i < len; i++) {
    if (a[i] < b[i])
      return -1;
    if (a[i] > b[i])
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bit_array_cmp>:
  endbr64
  test   %edi,%edi
  jle    L45
  movslq %edi,%rdi
  xor    %eax,%eax
  jmp    L2
  nop
L46:
  jg     L9
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L45
L2:
  mov    (%rdx,%rax,8),%rcx
  cmp    %rcx,(%rsi,%rax,8)
  jge    L46
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int bit_array_cmp(int len, uint64_t *a, uint64_t *b) {
  for (int i = 0; i < len; i++) {
    if (a[i] < b[i])
      return -1;
    if (a[i] > b[i])
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bit_array_cmp>:
  endbr64
  test   %edi,%edi
  jle    L22
  movslq %edi,%rdi
  xor    %eax,%eax
  jmp    L32
  nop
L48:
  jg     L10
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L22
L32:
  mov    (%rdx,%rax,8),%rcx
  cmp    %rcx,(%rsi,%rax,8)
  jge    L48
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int bit_array_cmp(int len, uint64_t *a, uint64_t *b) {
  for (int i = 0; i < len; i++) {
    if (a[i] < b[i])
      return -1;
    if (a[i] > b[i])
      return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  jmp    L66
L34:
  nop
L66:
  mov    $0x0,%eax
  call   <read_char@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x20,-0x8(%rbp)
  je     L34
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L65:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L68
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L68:
  mov    $0x0,%eax
  call   <read_char@plt>
  mov    %eax,-0x8(%rbp)
L9:
  cmpl   $0x20,-0x8(%rbp)
  je     L11
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L65
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0x13,-0x4(%rbp)
  jle    L59
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L59
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  movb   $0x2a,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x15,%rax
  movb   $0x0,(%rax)
L59:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_word(char *word, int len) {
  int ch;
  while ((ch = read_char()) == ' ') {
    continue;
  }
  int pos = 0;
  while (ch != ' ' && ch != EOF) {
    if (pos < len) {
      word[pos] = ch;
      pos += 1;
    }
    ch = read_char();
  }
  word[pos] = '\0';
  if (pos >= 20 && word[20] != '\0') {
    word[20] = '*';
    word[20 + 1] = '\0';
  }
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_word>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
L55:
  mov    $0x0,%eax
  call   <read_char@plt>
  cmp    $0x20,%eax
  je     L55
  mov    $0x0,%ebx
  mov    D5(%rip),%r13
  jmp    L29
L11:
  mov    $0x0,%eax
  call   <read_char@plt>
  cmp    $0x20,%eax
  je     L16
L29:
  cmp    %eax,0x0(%r13)
  je     L16
  cmp    %ebx,%ebp
  jle    L11
  movslq %ebx,%rdx
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%ebx
  jmp    L11
L16:
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
  cmp    $0x13,%ebx
  jle    L33
  cmpb   $0x0,0x14(%r12)
  je     L33
  movb   $0x2a,0x14(%r12)
  movb   $0x0,0x15(%r12)
L33:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int read_word(char *word, int len) {
  int ch;
  while ((ch = read_char()) == ' ') {
    continue;
  }
  int pos = 0;
  while (ch != ' ' && ch != EOF) {
    if (pos < len) {
      word[pos] = ch;
      pos += 1;
    }
    ch = read_char();
  }
  word[pos] = '\0';
  if (pos >= 20 && word[20] != '\0') {
    word[20] = '*';
    word[20 + 1] = '\0';
  }
  return pos;
}
```