ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xbc(%rbp)
  movl   $0x0,-0xb4(%rbp)
  lea    -0xc4(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc0(%rbp)
  jmp    L14
L38:
  lea    -0xb0(%rbp),%rdx
  mov    -0xc0(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xc0(%rbp)
L14:
  mov    -0xc4(%rbp),%eax
  cmp    %eax,-0xc0(%rbp)
  jl     L38
  movl   $0x0,-0xc0(%rbp)
  jmp    L79
L51:
  movl   $0x0,-0xbc(%rbp)
  mov    -0xc0(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,4),%eax
  mov    %eax,-0xb8(%rbp)
  jmp    L52
L61:
  mov    -0xb8(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xb4(%rbp)
  cmpl   $0x0,-0xb4(%rbp)
  je     L102
  mov    -0xc0(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,4),%eax
  cltd
  idivl  -0xb4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L102
  addl   $0x1,-0xbc(%rbp)
L102:
  mov    -0xb8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xb8(%rbp)
L52:
  cmpl   $0x0,-0xb8(%rbp)
  jg     L61
  mov    -0xc0(%rbp),%eax
  cltq
  mov    -0xbc(%rbp),%edx
  mov    %edx,-0x60(%rbp,%rax,4)
  addl   $0x1,-0xc0(%rbp)
L79:
  mov    -0xc4(%rbp),%eax
  cmp    %eax,-0xc0(%rbp)
  jl     L51
  movl   $0x0,-0xc0(%rbp)
  jmp    L23
L5:
  mov    -0xc0(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc0(%rbp)
L23:
  mov    -0xc4(%rbp),%eax
  cmp    %eax,-0xc0(%rbp)
  jl     L5
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D25
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string

tool: D5: %d

tool: D25: 
%d

tool: D16: %d


assistant: ```c
int main() {
  int i, j, t, num, count = 0, temp, rem = 0;
  int arr[20], brr[20];
  scanf("%d", &t);
  for (i = 0; i < t; i++)
    scanf("\n%d", &arr[i]);
  for (i = 0; i < t; i++) {
    count = 0;
    temp = arr[i];
    while (temp > 0) {
      rem = temp % 10;
      if (rem != 0) {
        if (arr[i] % rem == 0)
          count++;
      }
      temp = temp / 10;
    }
    brr[i] = count;
  }
  for (i = 0; i < t; i++) {
    printf("%d\n", brr[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L21
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D8(%rip),%r12
L44:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%r10d
  add    $0x4,%rbp
  cmp    %ebx,%r10d
  jg     L44
  test   %r10d,%r10d
  jle    L21
  mov    %r10d,%r10d
  mov    $0x0,%r9d
  jmp    L94
L36:
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  cmp    $0x9,%esi
  jle    L71
  mov    %eax,%esi
L48:
  movslq %esi,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  mov    %esi,%ecx
  sub    %eax,%ecx
  je     L36
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r8d
  jmp    L36
L113:
  mov    $0x0,%r8d
L71:
  mov    %r8d,0x60(%rsp,%r9,4)
  add    $0x1,%r9
  cmp    %r9,%r10
  je     L61
L94:
  mov    0x10(%rsp,%r9,4),%edi
  test   %edi,%edi
  jle    L113
  mov    %edi,%esi
  mov    $0x0,%r8d
  jmp    L48
L61:
  mov    $0x0,%ebx
  lea    D6(%rip),%rbp
L103:
  mov    0x60(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L103
L21:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D10: %d

tool: D8: 
%d

tool: D6: %d


assistant: ```c
int main() {
  int i, j, t, num, count = 0, temp, rem = 0;
  int arr[20], brr[20];
  scanf("%d", &t);
  for (i = 0; i < t; i++)
    scanf("\n%d", &arr[i]);
  for (i = 0; i < t; i++) {
    count = 0;
    temp = arr[i];
    while (temp > 0) {
      rem = temp % 10;
      if (rem != 0) {
        if (arr[i] % rem == 0)
          count++;
      }
      temp = temp / 10;
    }
    brr[i] = count;
  }
  for (i = 0; i < t; i++) {
    printf("%d\n", brr[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L108
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D20(%rip),%r13
  mov    %rbx,%r12
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebp,%eax
  jg     L16
  test   %eax,%eax
  jle    L108
  movslq %eax,%r12
  xor    %r11d,%r11d
  lea    0x60(%rsp),%rbp
  mov    $0xcccccccd,%r8d
  nopl   0x0(%rax,%rax,1)
L89:
  mov    (%rbx,%r11,4),%r9d
  test   %r9d,%r9d
  jle    L49
  mov    %r9d,%edi
  xor    %r10d,%r10d
  jmp    L94
  nopl   (%rax)
L42:
  mov    %esi,%edi
L94:
  mov    %edi,%esi
  mov    %rsi,%rcx
  imul   %r8,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%eax
  mov    %edi,%ecx
  add    %eax,%eax
  sub    %eax,%ecx
  je     L55
  mov    %r9d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r10d
L55:
  imul   %r8,%rsi
  shr    $0x23,%rsi
  cmp    $0x9,%edi
  jg     L42
  mov    %r10d,0x0(%rbp,%r11,4)
  add    $0x1,%r11
  cmp    %r11,%r12
  jne    L89
L112:
  xor    %ebx,%ebx
  lea    D8(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L29
L108:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L49:
  xor    %r10d,%r10d
  mov    %r10d,0x0(%rbp,%r11,4)
  add    $0x1,%r11
  cmp    %r11,%r12
  jne    L89
  jmp    L112
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string
name: unpack_data
arguments: tag: D8
data_type: string

tool: D22: %d

tool: D20: 
%d

tool: D8: %d


assistant: ```c
int main() {
  int i, j, t, num, count = 0, temp, rem = 0;
  int arr[20], brr[20];
  scanf("%d", &t);
  for (i = 0; i < t; i++)
    scanf("\n%d", &arr[i]);
  for (i = 0; i < t; i++) {
    count = 0;
    temp = arr[i];
    while (temp > 0) {
      rem = temp % 10;
      if (rem != 0) {
        if (arr[i] % rem == 0)
          count++;
      }
      temp = temp / 10;
    }
    brr[i] = count;
  }
  for (i = 0; i < t; i++) {
    printf("%d\n", brr[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L83
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D6(%rip),%r13
  mov    %rbx,%r12
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebp,%eax
  jg     L55
  test   %eax,%eax
  jle    L83
  movslq %eax,%r12
  xor    %r11d,%r11d
  lea    0x60(%rsp),%rbp
  mov    $0xcccccccd,%r8d
  nopl   0x0(%rax,%rax,1)
L22:
  mov    (%rbx,%r11,4),%r9d
  test   %r9d,%r9d
  jle    L81
  mov    %r9d,%edi
  xor    %r10d,%r10d
  jmp    L64
  nopl   (%rax)
L2:
  mov    %esi,%edi
L64:
  mov    %edi,%esi
  mov    %rsi,%rcx
  imul   %r8,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%eax
  mov    %edi,%ecx
  add    %eax,%eax
  sub    %eax,%ecx
  je     L57
  mov    %r9d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r10d
L57:
  imul   %r8,%rsi
  shr    $0x23,%rsi
  cmp    $0x9,%edi
  jg     L2
  mov    %r10d,0x0(%rbp,%r11,4)
  add    $0x1,%r11
  cmp    %r11,%r12
  jne    L22
L42:
  xor    %ebx,%ebx
  lea    D14(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L31:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L31
L83:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L81:
  xor    %r10d,%r10d
  mov    %r10d,0x0(%rbp,%r11,4)
  add    $0x1,%r11
  cmp    %r11,%r12
  jne    L22
  jmp    L42
L109:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
datatype: string
name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D14
datatype: string

tool: D16: %d

tool: D6: 
%d

tool: D14: %d


assistant: ```c
int main() {
  int i, j, t, num, count = 0, temp, rem = 0;
  int arr[20], brr[20];
  scanf("%d", &t);
  for (i = 0; i < t; i++)
    scanf("\n%d", &arr[i]);
  for (i = 0; i < t; i++) {
    count = 0;
    temp = arr[i];
    while (temp > 0) {
      rem = temp % 10;
      if (rem != 0) {
        if (arr[i] % rem == 0)
          count++;
      }
      temp = temp / 10;
    }
    brr[i] = count;
  }
  for (i = 0; i < t; i++) {
    printf("%d\n", brr[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str2uint>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %esi,%r8d
  mov    $0xa,%esi
  mov    $0x0,%eax
  mov    $0x1,%ebx
  mov    $0x0,%r9d
  mov    $0x10,%r11d
  mov    $0x2,%r10d
  jmp    L122
L127:
  add    $0x1,%eax
  mov    %ebx,%edi
  jmp    L153
L154:
  mov    %r9d,%edi
L153:
  lea    0x1(%rax),%edx
  movzbl (%rcx,%rdx,1),%edx
  and    $0xffffffdf,%edx
  cmp    $0x58,%dl
  jne    L53
  add    $0x2,%eax
  mov    %r11d,%esi
L53:
  lea    0x1(%rax),%edx
  movzbl (%rcx,%rdx,1),%edx
  and    $0xffffffdf,%edx
  cmp    $0x42,%dl
  jne    L123
  add    $0x2,%eax
  mov    %r10d,%esi
L123:
  test   %edi,%edi
  je     L184
L122:
  mov    %eax,%edx
  movzbl (%rcx,%rdx,1),%edx
  cmp    $0x20,%dl
  je     L127
  cmp    $0x30,%dl
  je     L154
L184:
  cmp    %eax,%r8d
  jbe    L24
  mov    %eax,%edx
  lea    (%rcx,%rdx,1),%rdi
  sub    $0x1,%r8d
  sub    %eax,%r8d
  lea    0x1(%rcx,%rdx,1),%rax
  add    %rax,%r8
  mov    $0x0,%eax
  movswl %si,%r9d
  jmp    L109
L74:
  cmp    $0x5f,%dl
  je     L161
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L13
  movsbw %dl,%dx
  sub    $0x57,%edx
  jmp    L164
L170:
  movsbw %dl,%dx
  sub    $0x37,%edx
  jmp    L164
L161:
  add    $0x1,%rdi
  cmp    %r8,%rdi
  je     L13
L109:
  movzbl (%rdi),%edx
  cmp    $0x46,%dl
  jg     L74
  cmp    $0x40,%dl
  jg     L170
  cmp    $0x20,%dl
  je     L161
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L13
  movsbw %dl,%dx
  sub    $0x30,%edx
L164:
  cmp    %si,%dx
  jge    L161
  imul   %r9d,%eax
  movswl %dx,%edx
  add    %edx,%eax
  jmp    L161
L24:
  mov    $0x0,%eax
L13:
  pop    %rbx
  ret
```

assistant: ```c
unsigned str2uint(const char *fmt, unsigned len) {
  unsigned count, result;
  count = result = 0;
  short carry = 10, bitnum;
  int again;
  do {
    again = 0;
    switch (fmt[count]) {
    case ' ':
      count++;
      again = 1;
    case '0':
      if ((fmt[count + 1] == 'x') || (fmt[count + 1] == 'X')) {
        count += 2;
        carry = 16;
      }
      if ((fmt[count + 1] == 'b') || (fmt[count + 1] == 'B')) {
        count += 2;
        carry = 2;
      }
      break;
    default:
      break;
    }
  } while (again);
  for (; count < len; count++) {
    switch (fmt[count]) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      bitnum = fmt[count] - '0';
      break;
    case 'a':
    case 'b':
    case 'c':
    case 'd':
    case 'e':
    case 'f':
      bitnum = fmt[count] - 'a' + 10;
      break;
    case 'A':
    case 'B':
    case 'C':
    case 'D':
    case 'E':
    case 'F':
      bitnum = fmt[count] - 'A' + 10;
      break;
    case ' ':
    case '_':
      continue;
    default:
      return result;
    }
    if (bitnum < carry) {
      result *= carry;
      result += bitnum;
    }
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str2uint>:
  endbr64
  xor    %eax,%eax
  mov    %rdi,%rcx
  mov    $0xa,%r8d
  mov    %eax,%edx
  movzbl (%rcx,%rdx,1),%edx
  cmp    $0x20,%dl
  je     L90
  xchg   %ax,%ax
L171:
  cmp    $0x30,%dl
  je     L107
L52:
  cmp    %eax,%esi
  jbe    L172
  mov    %eax,%edx
  sub    $0x1,%esi
  movswl %r8w,%r9d
  sub    %eax,%esi
  lea    (%rcx,%rdx,1),%rdi
  lea    0x1(%rcx,%rdx,1),%rdx
  xor    %eax,%eax
  add    %rdx,%rsi
L30:
  movsbw (%rdi),%dx
  cmp    $0x46,%dl
  jg     L5
  cmp    $0x40,%dl
  jg     L27
  cmp    $0x20,%dl
  je     L66
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L129
  sub    $0x30,%edx
L42:
  cmp    %r8w,%dx
  jge    L66
  imul   %r9d,%eax
  movswl %dx,%edx
  add    %edx,%eax
L66:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L30
  ret
  nopl   0x0(%rax)
L107:
  xor    %edi,%edi
L83:
  lea    0x1(%rax),%edx
  movzbl (%rcx,%rdx,1),%edx
  and    $0xffffffdf,%edx
  cmp    $0x58,%dl
  jne    L153
  lea    0x3(%rax),%edx
  mov    $0x10,%r8d
  add    $0x2,%eax
  movzbl (%rcx,%rdx,1),%edx
  and    $0xffffffdf,%edx
L153:
  cmp    $0x42,%dl
  jne    L97
  add    $0x2,%eax
  mov    $0x2,%r8d
L97:
  test   %edi,%edi
  je     L52
  mov    %eax,%edx
  movzbl (%rcx,%rdx,1),%edx
  cmp    $0x20,%dl
  jne    L171
L90:
  add    $0x1,%eax
  mov    $0x1,%edi
  jmp    L83
  nopl   0x0(%rax,%rax,1)
L5:
  cmp    $0x5f,%dl
  je     L66
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L129
  sub    $0x57,%edx
  jmp    L42
L172:
  xor    %eax,%eax
L129:
  ret
L27:
  sub    $0x37,%edx
  jmp    L42
```

assistant: ```c
unsigned str2uint(const char *fmt, unsigned len) {
  unsigned count, result;
  count = result = 0;
  short carry = 10, bitnum;
  int again;
  do {
    again = 0;
    switch (fmt[count]) {
    case ' ':
      count++;
      again = 1;
    case '0':
      if ((fmt[count + 1] == 'x') || (fmt[count + 1] == 'X')) {
        count += 2;
        carry = 16;
      }
      if ((fmt[count + 1] == 'b') || (fmt[count + 1] == 'B')) {
        count += 2;
        carry = 2;
      }
      break;
    default:
      break;
    }
  } while (again);
  for (; count < len; count++) {
    switch (fmt[count]) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      bitnum = fmt[count] - '0';
      break;
    case 'a':
    case 'b':
    case 'c':
    case 'd':
    case 'e':
    case 'f':
      bitnum = fmt[count] - 'a' + 10;
      break;
    case 'A':
    case 'B':
    case 'C':
    case 'D':
    case 'E':
    case 'F':
      bitnum = fmt[count] - 'A' + 10;
      break;
    case ' ':
    case '_':
      continue;
    default:
      return result;
    }
    if (bitnum < carry) {
      result *= carry;
      result += bitnum;
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str2uint>:
  endbr64
  xor    %eax,%eax
  mov    %rdi,%rcx
  mov    $0xa,%r8d
  mov    %eax,%edx
  movzbl (%rcx,%rdx,1),%edx
  cmp    $0x20,%dl
  je     L76
  xchg   %ax,%ax
L124:
  cmp    $0x30,%dl
  je     L104
L110:
  cmp    %eax,%esi
  jbe    L37
  mov    %eax,%edx
  sub    $0x1,%esi
  movswl %r8w,%r9d
  sub    %eax,%esi
  lea    (%rcx,%rdx,1),%rdi
  lea    0x1(%rcx,%rdx,1),%rdx
  xor    %eax,%eax
  add    %rdx,%rsi
L167:
  movsbw (%rdi),%dx
  cmp    $0x46,%dl
  jg     L77
  cmp    $0x40,%dl
  jg     L7
  cmp    $0x20,%dl
  je     L13
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L16
  sub    $0x30,%edx
L58:
  cmp    %r8w,%dx
  jge    L13
  imul   %r9d,%eax
  movswl %dx,%edx
  add    %edx,%eax
L13:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L167
  ret
  nopl   0x0(%rax)
L104:
  xor    %edi,%edi
L52:
  lea    0x1(%rax),%edx
  movzbl (%rcx,%rdx,1),%edx
  and    $0xffffffdf,%edx
  cmp    $0x58,%dl
  jne    L27
  lea    0x3(%rax),%edx
  mov    $0x10,%r8d
  add    $0x2,%eax
  movzbl (%rcx,%rdx,1),%edx
  and    $0xffffffdf,%edx
L27:
  cmp    $0x42,%dl
  jne    L129
  add    $0x2,%eax
  mov    $0x2,%r8d
L129:
  test   %edi,%edi
  je     L110
  mov    %eax,%edx
  movzbl (%rcx,%rdx,1),%edx
  cmp    $0x20,%dl
  jne    L124
L76:
  add    $0x1,%eax
  mov    $0x1,%edi
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L77:
  cmp    $0x5f,%dl
  je     L13
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L16
  sub    $0x57,%edx
  jmp    L58
L37:
  xor    %eax,%eax
L16:
  ret
L7:
  sub    $0x37,%edx
  jmp    L58
```

assistant: ```c
unsigned str2uint(const char *fmt, unsigned len) {
  unsigned count, result;
  count = result = 0;
  short carry = 10, bitnum;
  int again;
  do {
    again = 0;
    switch (fmt[count]) {
    case ' ':
      count++;
      again = 1;
    case '0':
      if ((fmt[count + 1] == 'x') || (fmt[count + 1] == 'X')) {
        count += 2;
        carry = 16;
      }
      if ((fmt[count + 1] == 'b') || (fmt[count + 1] == 'B')) {
        count += 2;
        carry = 2;
      }
      break;
    default:
      break;
    }
  } while (again);
  for (; count < len; count++) {
    switch (fmt[count]) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      bitnum = fmt[count] - '0';
      break;
    case 'a':
    case 'b':
    case 'c':
    case 'd':
    case 'e':
    case 'f':
      bitnum = fmt[count] - 'a' + 10;
      break;
    case 'A':
    case 'B':
    case 'C':
    case 'D':
    case 'E':
    case 'F':
      bitnum = fmt[count] - 'A' + 10;
      break;
    case ' ':
    case '_':
      continue;
    default:
      return result;
    }
    if (bitnum < carry) {
      result *= carry;
      result += bitnum;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmp_long_des>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L1
  mov    $0xffffffff,%eax
  jmp    L16
L1:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L3
  mov    $0x1,%eax
  jmp    L16
L3:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_long_des(const void *x, const void *y) {
  if (*(long *)x > *(long *)y) {
    return -1;
  } else if (*(long *)x < *(long *)y) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp_long_des>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jg     L8
  setl   %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int cmp_long_des(const void *x, const void *y) {
  if (*(long *)x > *(long *)y) {
    return -1;
  } else if (*(long *)x < *(long *)y) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp_long_des>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  setl   %al
  movzbl %al,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int cmp_long_des(const void *x, const void *y) {
  if (*(long *)x > *(long *)y) {
    return -1;
  } else if (*(long *)x < *(long *)y) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cmp_long_des>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  setl   %al
  movzbl %al,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int cmp_long_des(const void *x, const void *y) {
  if (*(long *)x > *(long *)y) {
    return -1;
  } else if (*(long *)x < *(long *)y) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pair_tailcorr_switch3_eidip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double pair_tailcorr_switch3_eidip(void *pair_data, long center_index, long other_index, double rcut, double width) {
  double t1 = 0.0;
  return t1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pair_tailcorr_switch3_eidip>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double pair_tailcorr_switch3_eidip(void *pair_data, long center_index, long other_index, double rcut, double width) {
  double t1 = 0.0;
  return t1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pair_tailcorr_switch3_eidip>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double pair_tailcorr_switch3_eidip(void *pair_data, long center_index, long other_index, double rcut, double width) {
  double t1 = 0.0;
  return t1;
}
```
user: What is the c source code of the assembly code below:

```asm
<pair_tailcorr_switch3_eidip>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double pair_tailcorr_switch3_eidip(void *pair_data, long center_index, long other_index, double rcut, double width) {
  double t1 = 0.0;
  return t1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dotVectors_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dotVectors_double(const double *u, const double *v) {
  double ans;
  ans = u[0] * v[0] + u[1] * v[1] + u[2] * v[2];
  return ans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dotVectors_double>:
  endbr64
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double dotVectors_double(const double *u, const double *v) {
  double ans;
  ans = u[0] * v[0] + u[1] * v[1] + u[2] * v[2];
  return ans;
}
```