ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<call_access>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <access@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void call_access() {
  int buf[100];
  access(buf, 100);
}
```
user: Translate the below assembly code into C programming language:

```asm
<call_access>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x64,%esi
  call   <access@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1a8,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void call_access() {
  int buf[100];
  access(buf, 100);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<call_access>:
  endbr64
  sub    $0x1a8,%rsp
  mov    $0x64,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <access@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x1a8,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void call_access() {
  int buf[100];
  access(buf, 100);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call_access>:
  endbr64
  sub    $0x1a8,%rsp
  mov    $0x64,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <access@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1a8,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void call_access() {
  int buf[100];
  access(buf, 100);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_ciphertext_len_regular_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0xf,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L7
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  add    $0x10,%rax
  mov    %rax,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long calc_ciphertext_len_regular_version(unsigned long long mlen) {
  int tmp;
  unsigned long long ret = 16 + mlen;
  tmp = mlen % 16;
  if (tmp != 0) {
    ret = ret + 16 - tmp;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calc_ciphertext_len_regular_version>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  jne    L4
  lea    0x10(%rdi),%rax
  ret
L4:
  add    $0x20,%rdi
  movslq %eax,%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long calc_ciphertext_len_regular_version(unsigned long long mlen) {
  int tmp;
  unsigned long long ret = 16 + mlen;
  tmp = mlen % 16;
  if (tmp != 0) {
    ret = ret + 16 - tmp;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<calc_ciphertext_len_regular_version>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  jne    L6
  lea    0x10(%rdi),%rax
  ret
L6:
  add    $0x20,%rdi
  movslq %eax,%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long calc_ciphertext_len_regular_version(unsigned long long mlen) {
  int tmp;
  unsigned long long ret = 16 + mlen;
  tmp = mlen % 16;
  if (tmp != 0) {
    ret = ret + 16 - tmp;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_ciphertext_len_regular_version>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  jne    L0
  lea    0x10(%rdi),%rax
  ret
L0:
  add    $0x20,%rdi
  movslq %eax,%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
unsigned long long calc_ciphertext_len_regular_version(unsigned long long mlen) {
  int tmp;
  unsigned long long ret = 16 + mlen;
  tmp = mlen % 16;
  if (tmp != 0) {
    ret = ret + 16 - tmp;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L16
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L10
L16:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D14
type_guessed: string

tool: D7: oi


tool: D14: tchau


assistant: ```c
void f0(int a) {
  int opcao = 0;
  if (a == opcao) {
    printf("oi\n");
  } else {
    printf("tchau\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<f0>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L1
  lea    D14(%rip),%rdi
  call   <printf@plt>
L11:
  add    $0x8,%rsp
  ret
L1:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: tag: D14
datatype: string
name: disassemble_data
arguments: tag: D19
datatype: string

tool: D14: oi


tool: D19: tchau


assistant: ```c
void f0(int a) {
  int opcao = 0;
  if (a == opcao) {
    printf("oi\n");
  } else {
    printf("tchau\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f0>:
  endbr64
  test   %edi,%edi
  jne    L5
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L5:
  lea    D17(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D17
type_guessed: string

tool: D0: oi


tool: D17: tchau


assistant: ```c
void f0(int a) {
  int opcao = 0;
  if (a == opcao) {
    printf("oi\n");
  } else {
    printf("tchau\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f0>:
  endbr64
  test   %edi,%edi
  jne    L3
  lea    D17(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L3:
  lea    D19(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D19
type: string

tool: D17: oi


tool: D19: tchau


assistant: ```c
void f0(int a) {
  int opcao = 0;
  if (a == opcao) {
    printf("oi\n");
  } else {
    printf("tchau\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x15(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L114
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jns    L98
L114:
  mov    $0xffffffffffffffff,%rax
  jmp    L122
L98:
  cmpl   $0x2,-0x14(%rbp)
  jne    L60
  movzbl -0x15(%rbp),%eax
  movsbl %al,%eax
  cmp    $0xa,%eax
  je     L24
  cmp    $0xa,%eax
  jl     L134
  cmp    $0x6d,%eax
  jg     L134
  cmp    $0x42,%eax
  jl     L134
  sub    $0x42,%eax
  cmp    $0x2b,%eax
  ja     L134
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D14(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D14(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x10(%rbp),%rax
  shl    $0xa,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L60
  mov    -0x10(%rbp),%rax
  shl    $0x14,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L60
  mov    -0x10(%rbp),%rax
  shl    $0x1e,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L60
L134:
  mov    $0xffffffffffffffff,%rax
  jmp    L122
L24:
  nop
L60:
  mov    -0x10(%rbp),%rax
L122:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D29
type_infered: string

tool: D29: %ld%c

assistant: ```c
long get_num(const char *str) {
  long n;
  char c;
  int ret = sscanf(str, "%ld%c", &n, &c);
  if (ret < 1 || n < 0)
    return -1;
  if (ret == 2)
    switch (c) {
    case 'b':
    case 'B':
    case '\n':
      break;
    case 'k':
    case 'K':
      n = n << 10;
      break;
    case 'm':
    case 'M':
      n = n << 20;
      break;
    case 'g':
    case 'G':
      n = n << 30;
      break;
    default:
      return -1;
    }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_num>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D9(%rip),%rsi
  call   <sscanf@plt>
  test   %eax,%eax
  jle    L116
  mov    0x10(%rsp),%rdx
  test   %rdx,%rdx
  js     L131
  cmp    $0x2,%eax
  je     L48
L110:
  mov    0x10(%rsp),%rax
L82:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L122
  add    $0x28,%rsp
  ret
L48:
  movzbl 0xf(%rsp),%eax
  cmp    $0xa,%al
  je     L110
  lea    -0x42(%rax),%ecx
  cmp    $0x2b,%cl
  ja     L92
  ja     L89
  movzbl %cl,%eax
  lea    D18(%rip),%rcx
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  shl    $0xa,%rdx
  mov    %rdx,0x10(%rsp)
  jmp    L110
  shl    $0x14,%rdx
  mov    %rdx,0x10(%rsp)
  jmp    L110
  shl    $0x1e,%rdx
  mov    %rdx,0x10(%rsp)
  jmp    L110
L116:
  mov    $0xffffffffffffffff,%rax
  jmp    L82
L131:
  mov    $0xffffffffffffffff,%rax
  jmp    L82
L92:
  mov    $0xffffffffffffffff,%rax
  jmp    L82
L89:
  mov    $0xffffffffffffffff,%rax
  jmp    L82
L122:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: %ld%c

assistant: ```c
long get_num(const char *str) {
  long n;
  char c;
  int ret = sscanf(str, "%ld%c", &n, &c);
  if (ret < 1 || n < 0)
    return -1;
  if (ret == 2)
    switch (c) {
    case 'b':
    case 'B':
    case '\n':
      break;
    case 'k':
    case 'K':
      n = n << 10;
      break;
    case 'm':
    case 'M':
      n = n << 20;
      break;
    case 'g':
    case 'G':
      n = n << 30;
      break;
    default:
      return -1;
    }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_num>:
  endbr64
  sub    $0x28,%rsp
  lea    D10(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  call   <sscanf@plt>
  test   %eax,%eax
  jle    L5
  mov    0x10(%rsp),%r8
  test   %r8,%r8
  js     L5
  cmp    $0x2,%eax
  je     L8
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  mov    %r8,%rax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L8:
  movzbl 0xf(%rsp),%eax
  cmp    $0xa,%al
  je     L29
  sub    $0x42,%eax
  cmp    $0x2b,%al
  ja     L5
  lea    D9(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L5:
  mov    $0xffffffffffffffff,%r8
  jmp    L29
  nopl   0x0(%rax)
  shl    $0x14,%r8
  jmp    L29
  xchg   %ax,%ax
  shl    $0xa,%r8
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
  shl    $0x1e,%r8
  jmp    L29
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: string

tool: D10: %ld%c

assistant: ```c
long get_num(const char *str) {
  long n;
  char c;
  int ret = sscanf(str, "%ld%c", &n, &c);
  if (ret < 1 || n < 0)
    return -1;
  if (ret == 2)
    switch (c) {
    case 'b':
    case 'B':
    case '\n':
      break;
    case 'k':
    case 'K':
      n = n << 10;
      break;
    case 'm':
    case 'M':
      n = n << 20;
      break;
    case 'g':
    case 'G':
      n = n << 30;
      break;
    default:
      return -1;
    }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_num>:
  endbr64
  sub    $0x28,%rsp
  lea    D11(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  call   <sscanf@plt>
  test   %eax,%eax
  jle    L33
  mov    0x10(%rsp),%r8
  test   %r8,%r8
  js     L33
  cmp    $0x2,%eax
  je     L58
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    %r8,%rax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L58:
  movzbl 0xf(%rsp),%eax
  cmp    $0xa,%al
  je     L44
  sub    $0x42,%eax
  cmp    $0x2b,%al
  ja     L33
  lea    D9(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L33:
  mov    $0xffffffffffffffff,%r8
  jmp    L44
  nopl   0x0(%rax)
  shl    $0x14,%r8
  jmp    L44
  xchg   %ax,%ax
  shl    $0xa,%r8
  jmp    L44
  cs nopw 0x0(%rax,%rax,1)
  shl    $0x1e,%r8
  jmp    L44
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
data_type: string

tool: D11: %ld%c

assistant: ```c
long get_num(const char *str) {
  long n;
  char c;
  int ret = sscanf(str, "%ld%c", &n, &c);
  if (ret < 1 || n < 0)
    return -1;
  if (ret == 2)
    switch (c) {
    case 'b':
    case 'B':
    case '\n':
      break;
    case 'k':
    case 'K':
      n = n << 10;
      break;
    case 'm':
    case 'M':
      n = n << 20;
      break;
    case 'g':
    case 'G':
      n = n << 30;
      break;
    default:
      return -1;
    }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<short2sec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  and    $0x7f,%eax
  mov    %al,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  and    $0x3f,%eax
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    $0x3f,%eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x4,%eax
  and    $0xc,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x6,%al
  or     %edx,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%ecx
  movzbl -0x2(%rbp),%edx
  movzbl -0x3(%rbp),%esi
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hmst2sec@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double short2sec(unsigned char pos[]) {
  unsigned char hours = pos[2] & 0x7f;
  unsigned char minutes = pos[1] & 0x3f;
  unsigned char seconds = pos[0] & 0x3f;
  unsigned char tenths = ((pos[1] & 0xc0) >> 4) | ((pos[0] & 0xc0) >> 6);
  return hmst2sec(hours, minutes, seconds, tenths);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<short2sec>:
  endbr64
  sub    $0x8,%rsp
  movzbl 0x1(%rdi),%esi
  movzbl (%rdi),%edx
  mov    %esi,%ecx
  shr    $0x4,%cl
  and    $0xc,%ecx
  mov    %edx,%eax
  shr    $0x6,%al
  or     %eax,%ecx
  movzbl %cl,%ecx
  and    $0x3f,%edx
  and    $0x3f,%esi
  movzbl 0x2(%rdi),%edi
  and    $0x7f,%edi
  call   <hmst2sec@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double short2sec(unsigned char pos[]) {
  unsigned char hours = pos[2] & 0x7f;
  unsigned char minutes = pos[1] & 0x3f;
  unsigned char seconds = pos[0] & 0x3f;
  unsigned char tenths = ((pos[1] & 0xc0) >> 4) | ((pos[0] & 0xc0) >> 6);
  return hmst2sec(hours, minutes, seconds, tenths);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<short2sec>:
  endbr64
  movzbl 0x1(%rdi),%esi
  movzbl (%rdi),%edx
  movzbl 0x2(%rdi),%edi
  mov    %esi,%ecx
  mov    %edx,%eax
  and    $0x3f,%esi
  and    $0x3f,%edx
  shr    $0x4,%cl
  shr    $0x6,%al
  and    $0x7f,%edi
  and    $0xc,%ecx
  or     %eax,%ecx
  movzbl %cl,%ecx
  jmp    1050 <hmst2sec@plt>
```

assistant: ```c
double short2sec(unsigned char pos[]) {
  unsigned char hours = pos[2] & 0x7f;
  unsigned char minutes = pos[1] & 0x3f;
  unsigned char seconds = pos[0] & 0x3f;
  unsigned char tenths = ((pos[1] & 0xc0) >> 4) | ((pos[0] & 0xc0) >> 6);
  return hmst2sec(hours, minutes, seconds, tenths);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<short2sec>:
  endbr64
  movzbl 0x1(%rdi),%esi
  movzbl (%rdi),%edx
  movzbl 0x2(%rdi),%edi
  mov    %esi,%ecx
  mov    %edx,%eax
  and    $0x3f,%esi
  and    $0x3f,%edx
  shr    $0x4,%cl
  shr    $0x6,%al
  and    $0x7f,%edi
  and    $0xc,%ecx
  or     %eax,%ecx
  movzbl %cl,%ecx
  jmp    1050 <hmst2sec@plt>
```

assistant: ```c
double short2sec(unsigned char pos[]) {
  unsigned char hours = pos[2] & 0x7f;
  unsigned char minutes = pos[1] & 0x3f;
  unsigned char seconds = pos[0] & 0x3f;
  unsigned char tenths = ((pos[1] & 0xc0) >> 4) | ((pos[0] & 0xc0) >> 6);
  return hmst2sec(hours, minutes, seconds, tenths);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fun_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fun_3(int a, int b) {
  int c = a * a;
  int d = 2 * a * b;
  int e = b * b;
  int sum = c + d + e;
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fun_3>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  imul   %edi,%edi
  lea    (%rdi,%rax,2),%eax
  imul   %esi,%esi
  add    %esi,%eax
  ret
```

assistant: ```c
int fun_3(int a, int b) {
  int c = a * a;
  int d = 2 * a * b;
  int e = b * b;
  int sum = c + d + e;
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fun_3>:
  endbr64
  mov    %edi,%eax
  imul   %edi,%edi
  imul   %esi,%eax
  imul   %esi,%esi
  lea    (%rdi,%rax,2),%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int fun_3(int a, int b) {
  int c = a * a;
  int d = 2 * a * b;
  int e = b * b;
  int sum = c + d + e;
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fun_3>:
  endbr64
  mov    %edi,%eax
  imul   %edi,%edi
  imul   %esi,%eax
  imul   %esi,%esi
  lea    (%rdi,%rax,2),%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int fun_3(int a, int b) {
  int c = a * a;
  int d = 2 * a * b;
  int e = b * b;
  int sum = c + d + e;
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_205_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x20(%rbp),%al
  mov    %al,-0x2(%rbp)
  notb   -0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_205_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | T;
  stk2 = ~stk2;
  stk1 = S | stk2;
  *D = stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_205_0_0>:
  endbr64
  or     (%rdi),%dl
  not    %edx
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_205_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | T;
  stk2 = ~stk2;
  stk1 = S | stk2;
  *D = stk1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rop3_205_0_0>:
  endbr64
  or     (%rdi),%dl
  not    %edx
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_205_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | T;
  stk2 = ~stk2;
  stk1 = S | stk2;
  *D = stk1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_205_0_0>:
  endbr64
  or     (%rdi),%dl
  not    %edx
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_205_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | T;
  stk2 = ~stk2;
  stk1 = S | stk2;
  *D = stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fromRep32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
float fromRep32(uint32_t x) {
  float ret;
  memcpy(&ret, &x, 4);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fromRep32>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  movss  0x14(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float fromRep32(uint32_t x) {
  float ret;
  memcpy(&ret, &x, 4);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<fromRep32>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  movss  0x14(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float fromRep32(uint32_t x) {
  float ret;
  memcpy(&ret, &x, 4);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fromRep32>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  movss  0x14(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float fromRep32(uint32_t x) {
  float ret;
  memcpy(&ret, &x, 4);
  return ret;
}
```