ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x9,-0x50(%rbp)
  movl   $0x2,-0x4c(%rbp)
  movl   $0x3,-0x48(%rbp)
  movl   $0x4,-0x44(%rbp)
  movl   $0x5,-0x40(%rbp)
  movl   $0x6,-0x3c(%rbp)
  movl   $0x7,-0x38(%rbp)
  movl   $0xa,-0x34(%rbp)
  movl   $0x9,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0xa,-0x14(%rbp)
  lea    -0x50(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <lprintf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x7,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <qsort@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <lprintf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <lprintf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x7,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <qsort2@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <lprintf@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type_infered: string
name: read_data
arguments: tag: D25
type_infered: string
name: read_data
arguments: tag: D22
type_infered: string

tool: D15: 


tool: D25: --------


tool: D22: ********************************



assistant: ```c
int main() {
  int array[] = {9, 2, 3, 4, 5, 6, 7, 10};
  int array2[] = {9, 2, 3, 4, 5, 6, 7, 10};
  lprintf(array, 8);
  printf("\n");
  qsort(array, 0, 7);
  printf("--------\n");
  lprintf(array, 8);
  printf("********************************\n\n");
  lprintf(array2, 8);
  printf("\n");
  qsort2(array2, 0, 7);
  printf("--------\n");
  lprintf(array2, 8);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x9,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0xa,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0x2,0x24(%rsp)
  movl   $0x3,0x28(%rsp)
  movl   $0x4,0x2c(%rsp)
  movl   $0x5,0x30(%rsp)
  movl   $0x6,0x34(%rsp)
  movl   $0x7,0x38(%rsp)
  movl   $0xa,0x3c(%rsp)
  mov    %rsp,%rbx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <lprintf@plt>
  lea    D2(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x7,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <qsort@plt>
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <lprintf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rbx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <lprintf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x7,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <qsort2@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <lprintf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x1,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string
name: disassemble_data
arguments: data_tag: D7
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D2: 


tool: D7: --------


tool: D4: ********************************



assistant: ```c
int main() {
  int array[] = {9, 2, 3, 4, 5, 6, 7, 10};
  int array2[] = {9, 2, 3, 4, 5, 6, 7, 10};
  lprintf(array, 8);
  printf("\n");
  qsort(array, 0, 7);
  printf("--------\n");
  lprintf(array, 8);
  printf("********************************\n\n");
  lprintf(array2, 8);
  printf("\n");
  qsort2(array2, 0, 7);
  printf("--------\n");
  lprintf(array2, 8);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  movabs $0x200000009,%rsi
  push   %r13
  movabs $0x400000003,%rcx
  movabs $0x600000005,%rdx
  push   %r12
  lea    D11(%rip),%r13
  lea    D10(%rip),%r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rsi,(%rsp)
  movabs $0xa00000007,%rax
  mov    %rbp,%rdi
  mov    %rsi,0x20(%rsp)
  mov    $0x8,%esi
  mov    %rcx,0x8(%rsp)
  mov    %rcx,0x28(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rdx,0x30(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rax,0x38(%rsp)
  call   <lprintf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x7,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <qsort@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  lea    0x20(%rsp),%rbp
  call   <lprintf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <lprintf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x7,%edx
  mov    %rbp,%rdi
  call   <qsort2@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <lprintf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x50,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D11: 


tool: D10: --------


tool: D1: ********************************



assistant: ```c
int main() {
  int array[] = {9, 2, 3, 4, 5, 6, 7, 10};
  int array2[] = {9, 2, 3, 4, 5, 6, 7, 10};
  lprintf(array, 8);
  printf("\n");
  qsort(array, 0, 7);
  printf("--------\n");
  lprintf(array, 8);
  printf("********************************\n\n");
  lprintf(array2, 8);
  printf("\n");
  qsort2(array2, 0, 7);
  printf("--------\n");
  lprintf(array2, 8);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x8,%esi
  lea    D32(%rip),%r13
  push   %r12
  lea    D47(%rip),%r12
  push   %rbp
  sub    $0x50,%rsp
  movdqa D48(%rip),%xmm1
  movdqa D16(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  movaps %xmm1,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm1,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <lprintf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x7,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <qsort@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  lea    0x20(%rsp),%rbp
  call   <lprintf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <lprintf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x7,%edx
  mov    %rbp,%rdi
  call   <qsort2@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <lprintf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x50,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D32
data_type: string
name: extract_symbolic_data
arguments: label: D47
data_type: string
name: extract_symbolic_data
arguments: label: D48
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D16
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D14
data_type: string

tool: D32: 


tool: D47: --------


tool: {"D48": [0x09,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D16": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: D14: ********************************



assistant: ```c
int main() {
  int array[] = {9, 2, 3, 4, 5, 6, 7, 10};
  int array2[] = {9, 2, 3, 4, 5, 6, 7, 10};
  lprintf(array, 8);
  printf("\n");
  qsort(array, 0, 7);
  printf("--------\n");
  lprintf(array, 8);
  printf("********************************\n\n");
  lprintf(array2, 8);
  printf("\n");
  qsort2(array2, 0, 7);
  printf("--------\n");
  lprintf(array2, 8);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L1:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void calc_sum(int *n, int upper) {
  int sum;
  int i;
  sum = 0;
  for (i = 0; i < upper; ++i) {
    sum += i;
  }
  *n = sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calc_sum>:
  endbr64
  test   %esi,%esi
  jle    L23
  mov    $0x0,%eax
  mov    $0x0,%edx
L2:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L2
L25:
  mov    %edx,(%rdi)
  ret
L23:
  mov    $0x0,%edx
  jmp    L25
```

assistant: ```c
void calc_sum(int *n, int upper) {
  int sum;
  int i;
  sum = 0;
  for (i = 0; i < upper; ++i) {
    sum += i;
  }
  *n = sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calc_sum>:
  endbr64
  test   %esi,%esi
  jle    L10
  xor    %eax,%eax
  xor    %edx,%edx
  nopl   0x0(%rax)
L0:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L0
  mov    %edx,(%rdi)
  ret
  nopl   0x0(%rax)
L10:
  xor    %edx,%edx
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void calc_sum(int *n, int upper) {
  int sum;
  int i;
  sum = 0;
  for (i = 0; i < upper; ++i) {
    sum += i;
  }
  *n = sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calc_sum>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  cmp    $0x9,%eax
  jbe    L80
  mov    %esi,%ecx
  movdqa D15(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D18(%rip),%xmm3
  shr    $0x2,%ecx
  nopl   (%rax)
L123:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%ecx
  jne    L123
  movdqa %xmm0,%xmm1
  mov    %edx,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%dl
  je     L88
L114:
  lea    0x1(%rcx),%esi
  add    %ecx,%eax
  cmp    %esi,%edx
  jle    L88
  add    %esi,%eax
  lea    0x2(%rcx),%esi
  cmp    %esi,%edx
  jle    L88
  add    %esi,%eax
  lea    0x3(%rcx),%esi
  cmp    %esi,%edx
  jle    L88
  add    %esi,%eax
  lea    0x4(%rcx),%esi
  cmp    %esi,%edx
  jle    L88
  add    %esi,%eax
  lea    0x5(%rcx),%esi
  cmp    %esi,%edx
  jle    L88
  add    %esi,%eax
  lea    0x6(%rcx),%esi
  cmp    %esi,%edx
  jle    L88
  add    %esi,%eax
  lea    0x7(%rcx),%esi
  cmp    %esi,%edx
  jle    L88
  add    %esi,%eax
  lea    0x8(%rcx),%esi
  cmp    %esi,%edx
  jle    L88
  add    %esi,%eax
  add    $0x9,%ecx
  lea    (%rax,%rcx,1),%esi
  cmp    %ecx,%edx
  cmovg  %esi,%eax
L88:
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  mov    %eax,(%rdi)
  ret
L80:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L114
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D18
type_guessed: byte[16]

tool: {"D15": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D18": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void calc_sum(int *n, int upper) {
  int sum;
  int i;
  sum = 0;
  for (i = 0; i < upper; ++i) {
    sum += i;
  }
  *n = sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shl_closep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L9
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <close@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void shl_closep(int *p) {
  if (*p >= 0)
    close(*p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shl_closep>:
  endbr64
  mov    (%rdi),%edi
  test   %edi,%edi
  jns    L0
  ret
L0:
  sub    $0x8,%rsp
  call   <close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void shl_closep(int *p) {
  if (*p >= 0)
    close(*p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shl_closep>:
  endbr64
  mov    (%rdi),%edi
  test   %edi,%edi
  jns    L5
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  jmp    1050 <close@plt>
```

assistant: ```c
void shl_closep(int *p) {
  if (*p >= 0)
    close(*p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shl_closep>:
  endbr64
  mov    (%rdi),%edi
  test   %edi,%edi
  jns    L0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  jmp    1050 <close@plt>
```

assistant: ```c
void shl_closep(int *p) {
  if (*p >= 0)
    close(*p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checkWinner>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%r12
  lea    0x9(%rdi),%r13
  mov    %rdi,%rbx
L48:
  movsbl 0x2(%rbx),%edx
  movsbl 0x1(%rbx),%esi
  movsbl (%rbx),%edi
  mov    %rbp,%rcx
  call   <solidLineMade@plt>
  test   %eax,%eax
  jne    L56
  add    $0x3,%rbx
  cmp    %r13,%rbx
  jne    L48
  lea    0x3(%rbp),%rbx
L15:
  movsbl 0x6(%r12),%edx
  movsbl 0x3(%r12),%esi
  movsbl (%r12),%edi
  mov    %rbp,%rcx
  call   <solidLineMade@plt>
  test   %eax,%eax
  jne    L56
  add    $0x1,%r12
  cmp    %rbx,%r12
  jne    L15
  movsbl 0x8(%rbp),%edx
  movsbl 0x4(%rbp),%esi
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%rcx
  call   <solidLineMade@plt>
  test   %eax,%eax
  je     L36
L56:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  movsbl 0x6(%rbp),%edx
  movsbl 0x4(%rbp),%esi
  movsbl 0x2(%rbp),%edi
  mov    %rbp,%rcx
  call   <solidLineMade@plt>
  jmp    L56
```

assistant: ```c
int checkWinner(char board[3][3]) {
  char a = '_';
  char b = '_';
  char c = '_';
  int i = 0;
  int j = 0;
  int retVal;
  for (i = 0; i < 3; i++) {
    a = board[i][0];
    b = board[i][1];
    c = board[i][2];
    retVal = solidLineMade(a, b, c, board);
    if (retVal) {
      return retVal;
    }
  }
  for (j = 0; j < 3; j++) {
    a = board[0][j];
    b = board[1][j];
    c = board[2][j];
    retVal = solidLineMade(a, b, c, board);
    if (retVal) {
      return retVal;
    }
  }
  a = board[0][0];
  b = board[1][1];
  c = board[2][2];
  retVal = solidLineMade(a, b, c, board);
  if (retVal) {
    return retVal;
  }
  a = board[0][2];
  b = board[1][1];
  c = board[2][0];
  retVal = solidLineMade(a, b, c, board);
  if (retVal) {
    return retVal;
  }
  return retVal;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<checkWinner>:
  endbr64
  push   %r13
  lea    0x9(%rdi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L39:
  movsbl 0x2(%rbx),%edx
  movsbl 0x1(%rbx),%esi
  mov    %r12,%rcx
  movsbl (%rbx),%edi
  call   <solidLineMade@plt>
  test   %eax,%eax
  jne    L44
  add    $0x3,%rbx
  cmp    %r13,%rbx
  jne    L39
  lea    0x3(%r12),%rbx
L37:
  movsbl 0x6(%rbp),%edx
  movsbl 0x3(%rbp),%esi
  mov    %r12,%rcx
  movsbl 0x0(%rbp),%edi
  call   <solidLineMade@plt>
  test   %eax,%eax
  jne    L44
  add    $0x1,%rbp
  cmp    %rbp,%rbx
  jne    L37
  movsbl 0x8(%r12),%edx
  movsbl 0x4(%r12),%esi
  mov    %r12,%rcx
  movsbl (%r12),%edi
  call   <solidLineMade@plt>
  test   %eax,%eax
  je     L5
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  movsbl 0x6(%r12),%edx
  movsbl 0x4(%r12),%esi
  mov    %r12,%rcx
  movsbl 0x2(%r12),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <solidLineMade@plt>
```

assistant: ```c
int checkWinner(char board[3][3]) {
  char a = '_';
  char b = '_';
  char c = '_';
  int i = 0;
  int j = 0;
  int retVal;
  for (i = 0; i < 3; i++) {
    a = board[i][0];
    b = board[i][1];
    c = board[i][2];
    retVal = solidLineMade(a, b, c, board);
    if (retVal) {
      return retVal;
    }
  }
  for (j = 0; j < 3; j++) {
    a = board[0][j];
    b = board[1][j];
    c = board[2][j];
    retVal = solidLineMade(a, b, c, board);
    if (retVal) {
      return retVal;
    }
  }
  a = board[0][0];
  b = board[1][1];
  c = board[2][2];
  retVal = solidLineMade(a, b, c, board);
  if (retVal) {
    return retVal;
  }
  a = board[0][2];
  b = board[1][1];
  c = board[2][0];
  retVal = solidLineMade(a, b, c, board);
  if (retVal) {
    return retVal;
  }
  return retVal;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checkWinner>:
  endbr64
  push   %r13
  lea    0x9(%rdi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L9:
  movsbl 0x2(%rbx),%edx
  movsbl 0x1(%rbx),%esi
  mov    %r12,%rcx
  movsbl (%rbx),%edi
  call   <solidLineMade@plt>
  test   %eax,%eax
  jne    L7
  add    $0x3,%rbx
  cmp    %r13,%rbx
  jne    L9
  lea    0x3(%r12),%rbx
L15:
  movsbl 0x6(%rbp),%edx
  movsbl 0x3(%rbp),%esi
  mov    %r12,%rcx
  movsbl 0x0(%rbp),%edi
  call   <solidLineMade@plt>
  test   %eax,%eax
  jne    L7
  add    $0x1,%rbp
  cmp    %rbp,%rbx
  jne    L15
  movsbl 0x8(%r12),%edx
  movsbl 0x4(%r12),%esi
  mov    %r12,%rcx
  movsbl (%r12),%edi
  call   <solidLineMade@plt>
  test   %eax,%eax
  je     L16
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L16:
  movsbl 0x6(%r12),%edx
  movsbl 0x4(%r12),%esi
  mov    %r12,%rcx
  movsbl 0x2(%r12),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <solidLineMade@plt>
```

assistant: ```c
int checkWinner(char board[3][3]) {
  char a = '_';
  char b = '_';
  char c = '_';
  int i = 0;
  int j = 0;
  int retVal;
  for (i = 0; i < 3; i++) {
    a = board[i][0];
    b = board[i][1];
    c = board[i][2];
    retVal = solidLineMade(a, b, c, board);
    if (retVal) {
      return retVal;
    }
  }
  for (j = 0; j < 3; j++) {
    a = board[0][j];
    b = board[1][j];
    c = board[2][j];
    retVal = solidLineMade(a, b, c, board);
    if (retVal) {
      return retVal;
    }
  }
  a = board[0][0];
  b = board[1][1];
  c = board[2][2];
  retVal = solidLineMade(a, b, c, board);
  if (retVal) {
    return retVal;
  }
  a = board[0][2];
  b = board[1][1];
  c = board[2][0];
  retVal = solidLineMade(a, b, c, board);
  if (retVal) {
    return retVal;
  }
  return retVal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L33:
  cmp    %rdx,%rsp
  je     L2
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L33
L2:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L25
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L25:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x20(%rbp),%rdx
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x34(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bar1@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void foo1(int size) {
  char temp[size];
  temp[size - 1] = '\0';
  bar1(temp, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L26:
  cmp    %rdx,%rsp
  je     L3
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L26
L3:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L28
  orq    $0x0,-0x8(%rsp,%rax,1)
L28:
  lea    -0x1(%rdi),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    %edi,%esi
  mov    %rsp,%rdi
  call   <bar1@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  leave
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo1(int size) {
  char temp[size];
  temp[size - 1] = '\0';
  bar1(temp, size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L31
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L38
L31:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L20
L39:
  lea    -0x1(%rdi),%eax
  mov    %edi,%esi
  mov    %rsp,%rdi
  cltq
  movb   $0x0,(%rsp,%rax,1)
  call   <bar1@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  leave
  ret
  nopl   0x0(%rax)
L20:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L39
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo1(int size) {
  char temp[size];
  temp[size - 1] = '\0';
  bar1(temp, size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L10
L5:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L5
L10:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L29
L40:
  lea    -0x1(%rdi),%eax
  mov    %edi,%esi
  mov    %rsp,%rdi
  cltq
  movb   $0x0,(%rsp,%rax,1)
  call   <bar1@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  leave
  ret
  nopl   0x0(%rax)
L29:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo1(int size) {
  char temp[size];
  temp[size - 1] = '\0';
  bar1(temp, size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<all_ada_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_ada_comments@plt>
  mov    $0x0,%eax
  call   <test_ada_comment_entities@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void all_ada_tests() {
  test_ada_comments();
  test_ada_comment_entities();
}
```