ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  cmp    $0x2,%ebp
  jle    L5
L1:
  cmp    0x4(%rsp),%ebp
  jg     L22
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <check_prime@plt>
  cmp    %ebp,0x4(%rsp)
  jge    L15
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  mov    %ebp,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%ebp
  jmp    L1
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D13
datatype: string
name: read_data
arguments: data_label: D17
datatype: string

tool: D13: %d %d

tool: D17: %d

assistant: ```c
int main() {
  int n1, n2, num, j;
  scanf("%d %d", &n1, &n2);
  if (n1 <= 2) {
    printf("%d", n1);
  }
  for (num = n1; num <= n2; num++) {
    check_prime(num);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Rwcsncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x30(%rbp)
  jmp    L37
L26:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L36
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <towlower@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <towlower@plt>
  cmp    %rax,%rbx
  je     L40
L36:
  mov    $0x1,%eax
  jmp    L27
L40:
  addq   $0x1,-0x30(%rbp)
  addq   $0x4,-0x28(%rbp)
  addq   $0x4,-0x20(%rbp)
L37:
  mov    -0x30(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L26
  mov    $0x0,%eax
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int Rwcsncasecmp(const wchar_t *cs1, const wchar_t *s2) {
  size_t i, n = wcslen(cs1);
  const wchar_t *a = cs1, *b = s2;
  for (i = 0; i < n; i++, a++, b++) {
    if (*b == L'\0' || towlower(*a) != towlower(*b))
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Rwcsncasecmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  call   <wcslen@plt>
  test   %rax,%rax
  je     L38
  mov    %rax,%r14
  mov    $0x0,%ebx
L60:
  cmpl   $0x0,(%r12,%rbx,4)
  je     L24
  mov    0x0(%r13,%rbx,4),%edi
  call   <towlower@plt>
  mov    %rax,%rbp
  mov    (%r12,%rbx,4),%edi
  call   <towlower@plt>
  cmp    %rax,%rbp
  jne    L61
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L60
  mov    $0x0,%eax
  jmp    L4
L38:
  mov    $0x0,%eax
  jmp    L4
L24:
  mov    $0x1,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L61:
  mov    $0x1,%eax
  jmp    L4
```

assistant: ```c
int Rwcsncasecmp(const wchar_t *cs1, const wchar_t *s2) {
  size_t i, n = wcslen(cs1);
  const wchar_t *a = cs1, *b = s2;
  for (i = 0; i < n; i++, a++, b++) {
    if (*b == L'\0' || towlower(*a) != towlower(*b))
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Rwcsncasecmp>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  call   <wcslen@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%r13
  xor    %ebx,%ebx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L36:
  mov    (%r14,%rbx,4),%edi
  call   <towlower@plt>
  mov    (%r12,%rbx,4),%edi
  mov    %rax,%rbp
  call   <towlower@plt>
  cmp    %rax,%rbp
  jne    L14
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L1
L16:
  mov    (%r12,%rbx,4),%eax
  test   %eax,%eax
  jne    L36
L14:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int Rwcsncasecmp(const wchar_t *cs1, const wchar_t *s2) {
  size_t i, n = wcslen(cs1);
  const wchar_t *a = cs1, *b = s2;
  for (i = 0; i < n; i++, a++, b++) {
    if (*b == L'\0' || towlower(*a) != towlower(*b))
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Rwcsncasecmp>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  call   <wcslen@plt>
  test   %rax,%rax
  je     L33
  mov    %rax,%r13
  xor    %ebx,%ebx
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L39:
  mov    (%r14,%rbx,4),%edi
  call   <towlower@plt>
  mov    (%r12,%rbx,4),%edi
  mov    %rax,%rbp
  call   <towlower@plt>
  cmp    %rax,%rbp
  jne    L0
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L33
L5:
  mov    (%r12,%rbx,4),%eax
  test   %eax,%eax
  jne    L39
L0:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L33:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int Rwcsncasecmp(const wchar_t *cs1, const wchar_t *s2) {
  size_t i, n = wcslen(cs1);
  const wchar_t *a = cs1, *b = s2;
  for (i = 0; i < n; i++, a++, b++) {
    if (*b == L'\0' || towlower(*a) != towlower(*b))
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hex_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2f,-0x4(%rbp)
  jle    L40
  cmpl   $0x39,-0x4(%rbp)
  jg     L40
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L15
L40:
  cmpl   $0x60,-0x4(%rbp)
  jle    L2
  cmpl   $0x66,-0x4(%rbp)
  jg     L2
  mov    -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L15
L2:
  mov    $0xffffffff,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int hex_digit(int c) {
  if (c >= '0' && c <= '9')
    return c - '0';
  if (c >= 'a' && c <= 'f')
    return c - 'a' + 10;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hex_digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L0
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%eax
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L0:
  ret
```

assistant: ```c
int hex_digit(int c) {
  if (c >= '0' && c <= '9')
    return c - '0';
  if (c >= 'a' && c <= 'f')
    return c - 'a' + 10;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex_digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L3
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%eax
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L3:
  ret
```

assistant: ```c
int hex_digit(int c) {
  if (c >= '0' && c <= '9')
    return c - '0';
  if (c >= 'a' && c <= 'f')
    return c - 'a' + 10;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hex_digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L3
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%eax
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
L3:
  ret
```

assistant: ```c
int hex_digit(int c) {
  if (c >= '0' && c <= '9')
    return c - '0';
  if (c >= 'a' && c <= 'f')
    return c - 'a' + 10;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find_the_two_nearest_keys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    0x10(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L12:
  mov    -0xc(%rbp),%eax
  imul   -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  lea    -0x18(%rbp),%r8
  lea    -0x1c(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  mov    -0x30(%rbp),%eax
  mov    %r8,%r9
  mov    %rsi,%r8
  mov    %eax,%esi
  call   <find_array_two_min@plt>
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L12
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void find_the_two_nearest_keys(const float *dist, int n1, int n2, int *indexA, int *indexB, float *distA, float *distB) {
  for (int i = 0; i < n1; i++) {
    int iA, iB;
    float dA, dB;
    find_array_two_min(&dist[i * n2], n2, &dA, &dB, &iA, &iB);
    indexA[i] = iA;
    indexB[i] = iB;
    distA[i] = dA;
    distB[i] = dB;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_the_two_nearest_keys>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %esi,%eax
  mov    %edx,%esi
  mov    %edx,0x4(%rsp)
  mov    0x80(%rsp),%r15
  mov    %fs:0x28,%rdx
  mov    %rdx,0x38(%rsp)
  xor    %edx,%edx
  test   %eax,%eax
  jle    L14
  mov    %rdi,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9,%r14
  movslq %esi,%rdx
  lea    0x0(,%rdx,4),%rdi
  mov    %rdi,0x8(%rsp)
  mov    %eax,%eax
  mov    %rax,0x10(%rsp)
  mov    $0x0,%ebx
  lea    0x2c(%rsp),%rax
  mov    %rax,0x18(%rsp)
L13:
  lea    0x34(%rsp),%rcx
  lea    0x30(%rsp),%rdx
  mov    0x18(%rsp),%r9
  lea    0x28(%rsp),%r8
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <find_array_two_min@plt>
  mov    0x28(%rsp),%eax
  mov    %eax,(%r12,%rbx,4)
  mov    0x2c(%rsp),%eax
  mov    %eax,0x0(%r13,%rbx,4)
  movss  0x30(%rsp),%xmm0
  movss  %xmm0,(%r14,%rbx,4)
  movss  0x34(%rsp),%xmm0
  movss  %xmm0,(%r15,%rbx,4)
  add    $0x1,%rbx
  add    0x8(%rsp),%rbp
  cmp    0x10(%rsp),%rbx
  jne    L13
L14:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void find_the_two_nearest_keys(const float *dist, int n1, int n2, int *indexA, int *indexB, float *distA, float *distB) {
  for (int i = 0; i < n1; i++) {
    int iA, iB;
    float dA, dB;
    find_array_two_min(&dist[i * n2], n2, &dA, &dB, &iA, &iB);
    indexA[i] = iA;
    indexB[i] = iB;
    distA[i] = dA;
    distB[i] = dB;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_the_two_nearest_keys>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x68,%rsp
  mov    0xa0(%rsp),%rdx
  mov    %rcx,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %r9,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x58(%rsp)
  xor    %edx,%edx
  test   %eax,%eax
  jle    L2
  movslq %ebx,%rdx
  mov    %rax,0x38(%rsp)
  xor    %r13d,%r13d
  lea    0x4c(%rsp),%r12
  shl    $0x2,%rdx
  lea    0x48(%rsp),%r8
  mov    %r12,%r9
  mov    %rdi,%rbp
  mov    %rdx,0x30(%rsp)
  mov    %r13,%r12
  lea    0x54(%rsp),%r15
  mov    %r8,%r13
  lea    0x50(%rsp),%r14
  nop
L18:
  mov    %r15,%rcx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %r13,%r8
  mov    %r14,%rdx
  mov    %r9,0x8(%rsp)
  call   <find_array_two_min@plt>
  mov    0x48(%rsp),%eax
  mov    0x10(%rsp),%rcx
  mov    0x18(%rsp),%rsi
  movss  0x50(%rsp),%xmm0
  add    0x30(%rsp),%rbp
  mov    0x8(%rsp),%r9
  mov    %eax,(%rcx,%r12,4)
  mov    0x4c(%rsp),%eax
  mov    %eax,(%rsi,%r12,4)
  mov    0x20(%rsp),%rax
  movss  %xmm0,(%rax,%r12,4)
  movss  0x54(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  movss  %xmm0,(%rax,%r12,4)
  add    $0x1,%r12
  cmp    0x38(%rsp),%r12
  jne    L18
L2:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void find_the_two_nearest_keys(const float *dist, int n1, int n2, int *indexA, int *indexB, float *distA, float *distB) {
  for (int i = 0; i < n1; i++) {
    int iA, iB;
    float dA, dB;
    find_array_two_min(&dist[i * n2], n2, &dA, &dB, &iA, &iB);
    indexA[i] = iA;
    indexB[i] = iB;
    distA[i] = dA;
    distB[i] = dB;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_the_two_nearest_keys>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x68,%rsp
  mov    0xa0(%rsp),%rdx
  mov    %rcx,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %r9,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x58(%rsp)
  xor    %edx,%edx
  test   %eax,%eax
  jle    L11
  movslq %ebx,%rdx
  mov    %rax,0x30(%rsp)
  xor    %r13d,%r13d
  lea    0x4c(%rsp),%r12
  shl    $0x2,%rdx
  lea    0x48(%rsp),%r8
  mov    %r12,%r9
  mov    %r13,%rbp
  mov    %rdx,0x38(%rsp)
  lea    0x54(%rsp),%r15
  mov    %rdi,%r12
  mov    %r8,%r13
  lea    0x50(%rsp),%r14
  nop
L20:
  mov    %r15,%rcx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    %r13,%r8
  mov    %r14,%rdx
  mov    %r9,0x8(%rsp)
  call   <find_array_two_min@plt>
  mov    0x48(%rsp),%eax
  mov    0x10(%rsp),%rcx
  mov    0x18(%rsp),%rsi
  movss  0x50(%rsp),%xmm0
  add    0x38(%rsp),%r12
  mov    0x8(%rsp),%r9
  mov    %eax,(%rcx,%rbp,4)
  mov    0x4c(%rsp),%eax
  mov    %eax,(%rsi,%rbp,4)
  mov    0x20(%rsp),%rax
  movss  %xmm0,(%rax,%rbp,4)
  movss  0x54(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  movss  %xmm0,(%rax,%rbp,4)
  add    $0x1,%rbp
  cmp    %rbp,0x30(%rsp)
  jne    L20
L11:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void find_the_two_nearest_keys(const float *dist, int n1, int n2, int *indexA, int *indexB, float *distA, float *distB) {
  for (int i = 0; i < n1; i++) {
    int iA, iB;
    float dA, dB;
    find_array_two_min(&dist[i * n2], n2, &dA, &dB, &iA, &iB);
    indexA[i] = iA;
    indexB[i] = iB;
    distA[i] = dA;
    distB[i] = dB;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<display_prompt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <get_working_directory@plt>
  mov    %rax,-0x28(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <gethostname@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,%rsi
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D7: USER

tool: D5: [%s@%s %s]$ 

assistant: ```c
void display_prompt() {
  char *working_directory = get_working_directory();
  char host_name[16];
  gethostname(host_name, sizeof(host_name));
  printf("[%s@%s %s]$ ", getenv("USER"), host_name, working_directory);
  free(working_directory);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display_prompt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <get_working_directory@plt>
  mov    %rax,%rbx
  mov    %rsp,%rbp
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <gethostname@plt>
  lea    D10(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rsi
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D10: USER

tool: D13: [%s@%s %s]$ 

assistant: ```c
void display_prompt() {
  char *working_directory = get_working_directory();
  char host_name[16];
  gethostname(host_name, sizeof(host_name));
  printf("[%s@%s %s]$ ", getenv("USER"), host_name, working_directory);
  free(working_directory);
}
```
user: Translate the below assembly code into C programming language:

```asm
<display_prompt>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <get_working_directory@plt>
  mov    $0x10,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <gethostname@plt>
  lea    D4(%rip),%rdi
  call   <getenv@plt>
  lea    D1(%rip),%rdi
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D4: USER

tool: D1: [%s@%s %s]$ 

assistant: ```c
void display_prompt() {
  char *working_directory = get_working_directory();
  char host_name[16];
  gethostname(host_name, sizeof(host_name));
  printf("[%s@%s %s]$ ", getenv("USER"), host_name, working_directory);
  free(working_directory);
}
```
user: What is the c source code of the assembly code below?

```asm
<display_prompt>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <get_working_directory@plt>
  mov    $0x10,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <gethostname@plt>
  lea    D14(%rip),%rdi
  call   <getenv@plt>
  lea    D8(%rip),%rdi
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D8
datatype: string

tool: D14: USER

tool: D8: [%s@%s %s]$ 

assistant: ```c
void display_prompt() {
  char *working_directory = get_working_directory();
  char host_name[16];
  gethostname(host_name, sizeof(host_name));
  printf("[%s@%s %s]$ ", getenv("USER"), host_name, working_directory);
  free(working_directory);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<revinplc2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void revinplc2(void *in) {
  unsigned char tmp;
  tmp = ((unsigned char *)in)[0];
  ((unsigned char *)in)[0] = ((unsigned char *)in)[1];
  ((unsigned char *)in)[1] = tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<revinplc2>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  mov    %dl,(%rdi)
  mov    %al,0x1(%rdi)
  ret
```

assistant: ```c
void revinplc2(void *in) {
  unsigned char tmp;
  tmp = ((unsigned char *)in)[0];
  ((unsigned char *)in)[0] = ((unsigned char *)in)[1];
  ((unsigned char *)in)[1] = tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<revinplc2>:
  endbr64
  rolw   $0x8,(%rdi)
  ret
```

assistant: ```c
void revinplc2(void *in) {
  unsigned char tmp;
  tmp = ((unsigned char *)in)[0];
  ((unsigned char *)in)[0] = ((unsigned char *)in)[1];
  ((unsigned char *)in)[1] = tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<revinplc2>:
  endbr64
  rolw   $0x8,(%rdi)
  ret
```

assistant: ```c
void revinplc2(void *in) {
  unsigned char tmp;
  tmp = ((unsigned char *)in)[0];
  ((unsigned char *)in)[0] = ((unsigned char *)in)[1];
  ((unsigned char *)in)[1] = tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D6(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printUpper@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printUpperP@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Fulano de_tal-cicrano

assistant: ```c
int main() {
  char *test = "Fulano de_tal-cicrano";
  printUpper(test);
  printUpperP(test);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printUpper@plt>
  mov    %rbx,%rdi
  call   <printUpperP@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: Fulano de_tal-cicrano

assistant: ```c
int main() {
  char *test = "Fulano de_tal-cicrano";
  printUpper(test);
  printUpperP(test);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <printUpper@plt>
  mov    %rbp,%rdi
  call   <printUpperP@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: Fulano de_tal-cicrano

assistant: ```c
int main() {
  char *test = "Fulano de_tal-cicrano";
  printUpper(test);
  printUpperP(test);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <printUpper@plt>
  mov    %rbp,%rdi
  call   <printUpperP@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: Fulano de_tal-cicrano

assistant: ```c
int main() {
  char *test = "Fulano de_tal-cicrano";
  printUpper(test);
  printUpperP(test);
  return 0;
}
```