ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L10:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L12
L27:
  mov    -0xc(%rbp),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L27
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transpose(int ndim, float *m) {
  int i, j;
  float temp;
  for (i = 0; i < ndim; i++)
    for (j = i + 1; j < ndim; j++) {
      temp = *(m + i * ndim + j);
      *(m + i * ndim + j) = *(m + j * ndim + i);
      *(m + j * ndim + i) = temp;
    }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<transpose>:
  endbr64
  test   %edi,%edi
  jle    L21
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  add    $0x1,%rbx
  lea    0x0(,%rbx,4),%rbp
  lea    0x4(%rsi),%r10
  lea    -0x1(%rdi),%r12d
  lea    -0x4(%rbp),%r8
  mov    $0x0,%r11d
  mov    $0x0,%r9d
  lea    -0x8(%rbp),%r13
  sub    $0x2,%edi
  add    $0x8,%rsi
L36:
  cmp    %r12,%r9
  je     L15
  lea    0x0(%r13,%r10,1),%rdx
  mov    %edi,%eax
  sub    %r9d,%eax
  add    %r11,%rax
  lea    (%rsi,%rax,4),%rcx
  mov    %r10,%rax
L16:
  movss  (%rax),%xmm0
  movss  (%rdx),%xmm1
  movss  %xmm1,(%rax)
  movss  %xmm0,(%rdx)
  add    $0x4,%rax
  add    %r8,%rdx
  cmp    %rcx,%rax
  jne    L16
  add    $0x1,%r9
  add    %rbp,%r10
  add    %rbx,%r11
  jmp    L36
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  ret
```

assistant: ```c
void transpose(int ndim, float *m) {
  int i, j;
  float temp;
  for (i = 0; i < ndim; i++)
    for (j = i + 1; j < ndim; j++) {
      temp = *(m + i * ndim + j);
      *(m + i * ndim + j) = *(m + j * ndim + i);
      *(m + j * ndim + i) = temp;
    }
}
```
user: What is the c source code of the assembly code below:

```asm
<transpose>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %r13
  xor    %r9d,%r9d
  lea    0x4(%rsi),%r10
  xor    %r11d,%r11d
  push   %r12
  lea    -0x1(%rdi),%r12d
  add    $0x8,%rsi
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x2,%edi
  add    $0x1,%rbx
  lea    0x0(,%rbx,4),%rbp
  lea    -0x4(%rbp),%r8
  lea    -0x8(%rbp),%r13
  cmp    %r12,%r9
  je     L26
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %edi,%eax
  lea    0x0(%r13,%r10,1),%rdx
  sub    %r9d,%eax
  add    %r11,%rax
  lea    (%rsi,%rax,4),%rcx
  mov    %r10,%rax
  nopl   0x0(%rax)
L12:
  movss  (%rdx),%xmm1
  movss  (%rax),%xmm0
  add    $0x4,%rax
  movss  %xmm1,-0x4(%rax)
  movss  %xmm0,(%rdx)
  add    %r8,%rdx
  cmp    %rcx,%rax
  jne    L12
  add    $0x1,%r9
  add    %rbp,%r10
  add    %rbx,%r11
  cmp    %r12,%r9
  jne    L5
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  ret
```

assistant: ```c
void transpose(int ndim, float *m) {
  int i, j;
  float temp;
  for (i = 0; i < ndim; i++)
    for (j = i + 1; j < ndim; j++) {
      temp = *(m + i * ndim + j);
      *(m + i * ndim + j) = *(m + j * ndim + i);
      *(m + j * ndim + i) = temp;
    }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<transpose>:
  endbr64
  test   %edi,%edi
  jle    L18
  cmp    $0x1,%edi
  je     L3
  movslq %edi,%r10
  mov    $0x1,%r8d
  lea    0x0(,%r10,4),%rcx
  lea    0x4(,%r10,4),%r11
  lea    (%rsi,%rcx,1),%r9
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r9,%rdx
  mov    %r8,%rax
  cs nopw 0x0(%rax,%rax,1)
L30:
  movss  (%rdx),%xmm1
  movss  (%rsi,%rax,4),%xmm0
  movss  %xmm1,(%rsi,%rax,4)
  add    $0x1,%rax
  movss  %xmm0,(%rdx)
  add    %rcx,%rdx
  cmp    %eax,%edi
  jg     L30
  add    $0x1,%r8
  add    %r11,%r9
  add    %rcx,%rsi
  cmp    %r10,%r8
  jne    L10
  ret
L18:
  ret
L3:
  ret
```

assistant: ```c
void transpose(int ndim, float *m) {
  int i, j;
  float temp;
  for (i = 0; i < ndim; i++)
    for (j = i + 1; j < ndim; j++) {
      temp = *(m + i * ndim + j);
      *(m + i * ndim + j) = *(m + j * ndim + i);
      *(m + j * ndim + i) = temp;
    }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L8:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L15:
  cmpq   $0x0,-0x28(%rbp)
  jg     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memcpy(void *buffer, const void *buffer2, uint32_t size) {
  char *cBuffer = (char *)buffer, *cBuffer2 = (char *)buffer2;
  while (size > 0) {
    *cBuffer++ = *cBuffer2++;
    size--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcpy>:
  endbr64
  test   %rdx,%rdx
  jle    L7
  mov    $0x0,%eax
L17:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L17
L7:
  ret
```

assistant: ```c
void memcpy(void *buffer, const void *buffer2, uint32_t size) {
  char *cBuffer = (char *)buffer, *cBuffer2 = (char *)buffer2;
  while (size > 0) {
    *cBuffer++ = *cBuffer2++;
    size--;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<memcpy>:
  endbr64
  test   %rdx,%rdx
  jle    L9
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L10:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L10
L9:
  ret
```

assistant: ```c
void memcpy(void *buffer, const void *buffer2, uint32_t size) {
  char *cBuffer = (char *)buffer, *cBuffer2 = (char *)buffer2;
  while (size > 0) {
    *cBuffer++ = *cBuffer2++;
    size--;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %rdx,%rdx
  jle    L103
  lea    0x1(%rsi),%r8
  lea    -0x1(%rdx),%rax
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L145
  cmp    $0x6,%rax
  jbe    L145
  mov    %rdx,%r9
  cmp    $0xe,%rax
  jbe    L37
  mov    %rdx,%rdi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rdi
  nopl   (%rax)
L13:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L13
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  sub    %rax,%rdx
  lea    (%rcx,%rax,1),%rdi
  lea    (%rsi,%rax,1),%r8
  cmp    %rax,%r9
  je     L94
L9:
  sub    %rax,%r9
  lea    -0x1(%r9),%r10
  cmp    $0x6,%r10
  jbe    L46
  mov    (%rsi,%rax,1),%rsi
  mov    %rsi,(%rcx,%rax,1)
  mov    %r9,%rax
  and    $0xfffffffffffffff8,%rax
  sub    %rax,%rdx
  add    %rax,%rdi
  add    %rax,%r8
  cmp    %rax,%r9
  je     L103
L46:
  movzbl (%r8),%eax
  mov    %al,(%rdi)
  cmp    $0x1,%rdx
  je     L103
  movzbl 0x1(%r8),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x2,%rdx
  je     L103
  movzbl 0x2(%r8),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x3,%rdx
  je     L103
  movzbl 0x3(%r8),%eax
  mov    %al,0x3(%rdi)
  cmp    $0x4,%rdx
  je     L103
  movzbl 0x4(%r8),%eax
  mov    %al,0x4(%rdi)
  cmp    $0x5,%rdx
  je     L103
  movzbl 0x5(%r8),%eax
  mov    %al,0x5(%rdi)
  cmp    $0x6,%rdx
  je     L103
  movzbl 0x6(%r8),%eax
  mov    %al,0x6(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L145:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L137:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L137
L103:
  ret
L37:
  mov    %rsi,%r8
  mov    %rcx,%rdi
  xor    %eax,%eax
  jmp    L9
L94:
  ret
```

assistant: ```c
void memcpy(void *buffer, const void *buffer2, uint32_t size) {
  char *cBuffer = (char *)buffer, *cBuffer2 = (char *)buffer2;
  while (size > 0) {
    *cBuffer++ = *cBuffer2++;
    size--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: *
**
***
****
*****


assistant: ```c
int main(void) {
  printf("*\n**\n***\n****\n*****\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: *
**
***
****
*****


assistant: ```c
int main(void) {
  printf("*\n**\n***\n****\n*****\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D0: *
**
***
****
*****


assistant: ```c
int main(void) {
  printf("*\n**\n***\n****\n*****\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: *
**
***
****
*****


assistant: ```c
int main(void) {
  printf("*\n**\n***\n****\n*****\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_long_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <get_int_code@plt>
  mov    $0x0,%eax
  call   <get_int_code@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_long_code(void) {
  get_int_code();
  get_int_code();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_long_code>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_int_code@plt>
  mov    $0x0,%eax
  call   <get_int_code@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void get_long_code(void) {
  get_int_code();
  get_int_code();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_long_code>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_int_code@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <get_int_code@plt>
```

assistant: ```c
void get_long_code(void) {
  get_int_code();
  get_int_code();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_long_code>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_int_code@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <get_int_code@plt>
```

assistant: ```c
void get_long_code(void) {
  get_int_code();
  get_int_code();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dumpmapentry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: %s=%s


assistant: ```c
void dumpmapentry(void *data, const void *key, void *value) {
  FILE *fi = (FILE *)data;
  fprintf(fi, "%s=%s\n", (char *)key, (char *)value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dumpmapentry>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D9(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: %s=%s


assistant: ```c
void dumpmapentry(void *data, const void *key, void *value) {
  FILE *fi = (FILE *)data;
  fprintf(fi, "%s=%s\n", (char *)key, (char *)value);
}
```
user: What is the c source code of the assembly code below:

```asm
<dumpmapentry>:
  endbr64
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D0(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: %s=%s


assistant: ```c
void dumpmapentry(void *data, const void *key, void *value) {
  FILE *fi = (FILE *)data;
  fprintf(fi, "%s=%s\n", (char *)key, (char *)value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dumpmapentry>:
  endbr64
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D7(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: %s=%s


assistant: ```c
void dumpmapentry(void *data, const void *key, void *value) {
  FILE *fi = (FILE *)data;
  fprintf(fi, "%s=%s\n", (char *)key, (char *)value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<NearestPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L40:
  movl   $0x2,-0x4(%rbp)
  jmp    L12
L37:
  addl   $0x1,-0x4(%rbp)
L12:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x8(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  cmp    %eax,-0x4(%rbp)
  jg     L46
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L37
L46:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L21
  addl   $0x1,-0x8(%rbp)
  jmp    L40
L21:
  nop
  mov    -0x8(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
unsigned long int NearestPrime(unsigned int n) {
  int p;
  int i;
  for (p = n;; p++) {
    for (i = 2; i <= (int)sqrt((double)p) && p % i != 0; i++)
      ;
    if (p % i != 0) {
      break;
    }
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NearestPrime>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  jmp    L31
L28:
  add    $0x1,%ebx
L7:
  movq   %r14,%xmm0
  call   <sqrt@plt>
  cmp    %eax,%ebx
  jg     L22
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L28
L18:
  add    $0x1,%ebp
L31:
  mov    $0x2,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  movq   %xmm1,%r14
  jmp    L7
L22:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L18
  movslq %ebp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
unsigned long int NearestPrime(unsigned int n) {
  int p;
  int i;
  for (p = n;; p++) {
    for (i = 2; i <= (int)sqrt((double)p) && p % i != 0; i++)
      ;
    if (p % i != 0) {
      break;
    }
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<NearestPrime>:
  endbr64
  push   %r14
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L6:
  pxor   %xmm1,%xmm1
  mov    $0x2,%ebx
  cvtsi2sd %ebp,%xmm1
  movq   %xmm1,%r14
  jmp    L19
  nopl   0x0(%rax)
L13:
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L12
  add    $0x1,%ebx
L19:
  movq   %r14,%xmm0
  call   <sqrt@plt>
  cmp    %eax,%ebx
  mov    %ebp,%eax
  jle    L13
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L4
L12:
  add    $0x1,%ebp
  jmp    L6
  xchg   %ax,%ax
L4:
  movslq %ebp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
unsigned long int NearestPrime(unsigned int n) {
  int p;
  int i;
  for (p = n;; p++) {
    for (i = 2; i <= (int)sqrt((double)p) && p % i != 0; i++)
      ;
    if (p % i != 0) {
      break;
    }
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NearestPrime>:
  endbr64
  push   %r14
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L49:
  pxor   %xmm1,%xmm1
  mov    $0x2,%ebx
  cvtsi2sd %ebp,%xmm1
  movq   %xmm1,%r14
  jmp    L0
  nopl   0x0(%rax)
L21:
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L20
  add    $0x1,%ebx
L0:
  movq   %r14,%xmm0
  call   <sqrt@plt>
  cmp    %eax,%ebx
  mov    %ebp,%eax
  jle    L21
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L12
L20:
  add    $0x1,%ebp
  jmp    L49
  xchg   %ax,%ax
L12:
  movslq %ebp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
unsigned long int NearestPrime(unsigned int n) {
  int p;
  int i;
  for (p = n;; p++) {
    for (i = 2; i <= (int)sqrt((double)p) && p % i != 0; i++)
      ;
    if (p % i != 0) {
      break;
    }
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_capacity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void get_capacity(int nfrags, int max_mesh_num, int cap[]) {
  for (int i = 0; i < nfrags; ++i)
    cap[i] = max_mesh_num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_capacity>:
  endbr64
  test   %edi,%edi
  jle    L16
  mov    %rdx,%rax
  lea    -0x1(%rdi),%ecx
  lea    0x4(%rdx,%rcx,4),%rdx
L0:
  mov    %esi,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L0
L16:
  ret
```

assistant: ```c
void get_capacity(int nfrags, int max_mesh_num, int cap[]) {
  for (int i = 0; i < nfrags; ++i)
    cap[i] = max_mesh_num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_capacity>:
  endbr64
  test   %edi,%edi
  jle    L14
  lea    -0x1(%rdi),%eax
  lea    0x4(%rdx,%rax,4),%rax
L1:
  mov    %esi,(%rdx)
  add    $0x4,%rdx
  cmp    %rax,%rdx
  jne    L1
L14:
  ret
```

assistant: ```c
void get_capacity(int nfrags, int max_mesh_num, int cap[]) {
  for (int i = 0; i < nfrags; ++i)
    cap[i] = max_mesh_num;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_capacity>:
  endbr64
  mov    %edi,%ecx
  test   %edi,%edi
  jle    L28
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L4
  shr    $0x2,%edi
  movd   %esi,%xmm1
  mov    %rdx,%rax
  sub    $0x1,%edi
  pshufd $0x0,%xmm1,%xmm0
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopl   (%rax)
L23:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L23
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%cl
  je     L47
L49:
  movslq %eax,%rdi
  mov    %esi,(%rdx,%rdi,4)
  lea    0x0(,%rdi,4),%r8
  lea    0x1(%rax),%edi
  cmp    %edi,%ecx
  jle    L28
  add    $0x2,%eax
  mov    %esi,0x4(%rdx,%r8,1)
  cmp    %eax,%ecx
  jle    L28
  mov    %esi,0x8(%rdx,%r8,1)
L28:
  ret
  nopl   (%rax)
L47:
  ret
L4:
  xor    %eax,%eax
  jmp    L49
```

assistant: ```c
void get_capacity(int nfrags, int max_mesh_num, int cap[]) {
  for (int i = 0; i < nfrags; ++i)
    cap[i] = max_mesh_num;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rbp,%rbx
  test   %rdx,%rdx
  je     L124
  lea    -0x1(%rdx),%rcx
  mov    %rbp,%rax
  xor    %rsi,%rax
  test   $0x7,%al
  jne    L79
  test   $0x7,%sil
  je     L62
  test   %rcx,%rcx
  je     L62
L41:
  movzbl (%rdi),%eax
  mov    %al,(%rbx)
  test   %al,%al
  je     L54
  sub    $0x1,%rcx
  add    $0x1,%rdi
  add    $0x1,%rbx
  test   $0x7,%dil
  je     L54
  test   %rcx,%rcx
  jne    L41
L54:
  test   %rcx,%rcx
  je     L178
  cmpb   $0x0,(%rdi)
  je     L149
  cmp    $0x7,%rcx
  jbe    L203
  mov    D3(%rip),%r10
  mov    $0xffffffffffffffff,%r9
L191:
  mov    (%rdi),%r8
  mov    (%r10),%rsi
  mov    %r9,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %r8,%rdx
  sub    %rax,%rdx
  mov    %r8,%r11
  not    %r11
  and    %r11,%rdx
  shr    %rsi
  add    $0x1,%rsi
  imul   %rax,%rsi
  test   %rsi,%rdx
  jne    L98
  mov    %r8,(%rbx)
  sub    $0x8,%rcx
  add    $0x8,%rdi
  add    $0x8,%rbx
  cmp    $0x7,%rcx
  ja     L191
  mov    %rbx,%rdx
  jmp    L152
L62:
  mov    %rbp,%rbx
  jmp    L54
L79:
  mov    %rbp,%rdx
L152:
  test   %rcx,%rcx
  je     L94
L126:
  mov    %rdx,%rbx
  add    %rcx,%rdx
L130:
  movzbl (%rdi),%eax
  mov    %al,(%rbx)
  test   %al,%al
  je     L178
  add    $0x1,%rdi
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  jne    L130
L178:
  movb   $0x0,(%rbx)
L124:
  call   <strlen@plt>
  sub    %rbp,%rbx
  add    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L94:
  mov    %rdx,%rbx
  jmp    L178
L203:
  mov    %rbx,%rdx
  jmp    L126
L98:
  mov    %rbx,%rdx
  jmp    L152
L149:
  mov    %rbx,%rdx
  jmp    L126
```

assistant: ```c
size_t strlcpy(char *d, const char *s, size_t n) {
  char *d0 = d;
  size_t *wd;
  const size_t *ws;
  if (!n--)
    goto finish;
  if (((uintptr_t)s & (sizeof(size_t) - 1)) == ((uintptr_t)d & (sizeof(size_t) - 1))) {
    for (; ((uintptr_t)s & (sizeof(size_t) - 1)) && n && (*d = *s); n--, s++, d++)
      ;
    if (n && *s) {
      wd = (void *)d;
      ws = (const void *)s;
      for (; n >= sizeof(size_t) && !((*ws) - ((size_t)-1 / UCHAR_MAX) & ~(*ws) & (((size_t)-1 / UCHAR_MAX) * (UCHAR_MAX / 2 + 1))); n -= sizeof(size_t), ws++, wd++)
        *wd = *ws;
      d = (void *)wd;
      s = (const void *)ws;
    }
  }
  for (; n && (*d = *s); n--, s++, d++)
    ;
  *d = 0;
finish:
  return d - d0 + strlen(s);
}
```