ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_cntrly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L17
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x19,%al
  jne    L10
  mov    $0x1,%eax
  jmp    L21
L10:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
long is_cntrly(instr)
char *instr;
{
  for (; *instr != ((char)0L); instr++) {
    if (*instr == ((char)031))
      return (1L);
  }
  return (0L);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_cntrly>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
L21:
  cmp    $0x19,%al
  je     L18
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L21
  mov    $0x0,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long is_cntrly(instr)
char *instr;
{
  for (; *instr != ((char)0L); instr++) {
    if (*instr == ((char)031))
      return (1L);
  }
  return (0L);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_cntrly>:
  endbr64
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L29:
  cmp    $0x19,%al
  je     L12
  add    $0x1,%rdi
L13:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L29
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long is_cntrly(instr)
char *instr;
{
  for (; *instr != ((char)0L); instr++) {
    if (*instr == ((char)031))
      return (1L);
  }
  return (0L);
}
```
user: What is the c source code of the assembly code below?

```asm
<is_cntrly>:
  endbr64
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmp    $0x19,%al
  je     L5
  add    $0x1,%rdi
L21:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L0
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
long is_cntrly(instr)
char *instr;
{
  for (; *instr != ((char)0L); instr++) {
    if (*instr == ((char)031))
      return (1L);
  }
  return (0L);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_ip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <inet_ntoa@plt>
  leave
  ret
```

assistant: ```c
char *print_ip(uint32_t ip) {
  struct in_addr a;
  a.s_addr = ip;
  return inet_ntoa(a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_ip>:
  endbr64
  sub    $0x8,%rsp
  call   <inet_ntoa@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *print_ip(uint32_t ip) {
  struct in_addr a;
  a.s_addr = ip;
  return inet_ntoa(a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_ip>:
  endbr64
  jmp    1050 <inet_ntoa@plt>
```

assistant: ```c
char *print_ip(uint32_t ip) {
  struct in_addr a;
  a.s_addr = ip;
  return inet_ntoa(a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_ip>:
  endbr64
  jmp    1050 <inet_ntoa@plt>
```

assistant: ```c
char *print_ip(uint32_t ip) {
  struct in_addr a;
  a.s_addr = ip;
  return inet_ntoa(a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sub(double *r, const double *a, const double *b) {
  r[0] = a[0] - b[0];
  r[1] = a[1] - b[1];
  r[2] = a[2] - b[2];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sub>:
  endbr64
  movsd  (%rsi),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  subsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  subsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void sub(double *r, const double *a, const double *b) {
  r[0] = a[0] - b[0];
  r[1] = a[1] - b[1];
  r[2] = a[2] - b[2];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sub>:
  endbr64
  movsd  (%rsi),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  subsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  subsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void sub(double *r, const double *a, const double *b) {
  r[0] = a[0] - b[0];
  r[1] = a[1] - b[1];
  r[2] = a[2] - b[2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sub>:
  endbr64
  movsd  (%rsi),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  subsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  subsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void sub(double *r, const double *a, const double *b) {
  r[0] = a[0] - b[0];
  r[1] = a[1] - b[1];
  r[2] = a[2] - b[2];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test23>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D3(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Pascal2Camelback@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L5
L12:
  mov    $0x0,%eax
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D36
type: string
name: read_data
arguments: data_tag: D31
type: string

tool: D3: AaaBbCccDdd

tool: D30: aaaBbCccDdd

tool: D36: Input is %s


tool: D31: result is %s 


assistant: ```c
int test23() {
  char *camelback_test = "AaaBbCccDdd";
  char *anticipated_test = "aaaBbCccDdd";
  printf("Input is %s\n", camelback_test);
  char *result = Pascal2Camelback(camelback_test);
  printf("result is %s \n", result);
  if (strcmp(anticipated_test, result) == 0) {
    free(result);
    return 1;
  } else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test23>:
  endbr64
  push   %rbx
  lea    D21(%rip),%rbx
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <Pascal2Camelback@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L19
L16:
  pop    %rbx
  ret
L19:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L16
```

tool_calls: name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D11
type: string
name: parse_data
arguments: data_tag: D16
type: string
name: parse_data
arguments: data_tag: D13
type: string

tool: D21: AaaBbCccDdd

tool: D11: Input is %s


tool: D16: result is %s 


tool: D13: aaaBbCccDdd

assistant: ```c
int test23() {
  char *camelback_test = "AaaBbCccDdd";
  char *anticipated_test = "aaaBbCccDdd";
  printf("Input is %s\n", camelback_test);
  char *result = Pascal2Camelback(camelback_test);
  printf("result is %s \n", result);
  if (strcmp(anticipated_test, result) == 0) {
    free(result);
    return 1;
  } else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test23>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rbp
  lea    D17(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <Pascal2Camelback@plt>
  lea    D12(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D39(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L1
  pop    %rbp
  ret
L1:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D38
data_type: string
name: parse_data
arguments: label: D17
data_type: string
name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D39
data_type: string

tool: D38: AaaBbCccDdd

tool: D17: Input is %s


tool: D12: result is %s 


tool: D39: aaaBbCccDdd

assistant: ```c
int test23() {
  char *camelback_test = "AaaBbCccDdd";
  char *anticipated_test = "aaaBbCccDdd";
  printf("Input is %s\n", camelback_test);
  char *result = Pascal2Camelback(camelback_test);
  printf("result is %s \n", result);
  if (strcmp(anticipated_test, result) == 0) {
    free(result);
    return 1;
  } else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test23>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rbp
  lea    D3(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <Pascal2Camelback@plt>
  lea    D14(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L5
  pop    %rbp
  ret
L5:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D23
type: string

tool: D24: AaaBbCccDdd

tool: D3: Input is %s


tool: D14: result is %s 


tool: D23: aaaBbCccDdd

assistant: ```c
int test23() {
  char *camelback_test = "AaaBbCccDdd";
  char *anticipated_test = "aaaBbCccDdd";
  printf("Input is %s\n", camelback_test);
  char *result = Pascal2Camelback(camelback_test);
  printf("result is %s \n", result);
  if (strcmp(anticipated_test, result) == 0) {
    free(result);
    return 1;
  } else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xc822,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <intlen@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main() {
  int a = 51234;
  printf("%d\n", intlen(a));
  printf("%d\n", a);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xc822,%edi
  call   <intlen@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xc822,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: %d


assistant: ```c
int main() {
  int a = 51234;
  printf("%d\n", intlen(a));
  printf("%d\n", a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xc822,%edi
  lea    D8(%rip),%rbp
  call   <intlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xc822,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: %d


assistant: ```c
int main() {
  int a = 51234;
  printf("%d\n", intlen(a));
  printf("%d\n", a);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xc822,%edi
  lea    D8(%rip),%rbp
  call   <intlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xc822,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: %d


assistant: ```c
int main() {
  int a = 51234;
  printf("%d\n", intlen(a));
  printf("%d\n", a);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   $0x0,-0x18(%rbp)
  mov    $0x3,%edi
  call   <div@plt>
  mov    %rax,%rbx
  mov    $0x5,%edi
  call   <div@plt>
  add    %rax,%rbx
  mov    $0xf,%edi
  call   <div@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x3e7,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: The sum of all the multiples of 3 or 5 below %lu: %lu


assistant: ```c
int main() {
  long ret = 0;
  ret = div(3) + div(5) - div(15);
  printf("The sum of all the multiples of 3 or 5 below %lu: %lu\n", ((long)999), ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3,%edi
  call   <div@plt>
  mov    %rax,%rbx
  mov    $0x5,%edi
  call   <div@plt>
  add    %rax,%rbx
  mov    $0xf,%edi
  call   <div@plt>
  mov    %rbx,%rdx
  sub    %rax,%rdx
  mov    $0x3e7,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: The sum of all the multiples of 3 or 5 below %lu: %lu


assistant: ```c
int main() {
  long ret = 0;
  ret = div(3) + div(5) - div(15);
  printf("The sum of all the multiples of 3 or 5 below %lu: %lu\n", ((long)999), ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3,%edi
  call   <div@plt>
  mov    $0x5,%edi
  mov    %rax,%rbx
  call   <div@plt>
  mov    $0xf,%edi
  add    %rax,%rbx
  call   <div@plt>
  mov    %rbx,%rdx
  mov    $0x3e7,%esi
  lea    D3(%rip),%rdi
  sub    %rax,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: The sum of all the multiples of 3 or 5 below %lu: %lu


assistant: ```c
int main() {
  long ret = 0;
  ret = div(3) + div(5) - div(15);
  printf("The sum of all the multiples of 3 or 5 below %lu: %lu\n", ((long)999), ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3,%edi
  call   <div@plt>
  mov    $0x5,%edi
  mov    %rax,%rbx
  call   <div@plt>
  mov    $0xf,%edi
  add    %rax,%rbx
  call   <div@plt>
  mov    %rbx,%rdx
  mov    $0x3e7,%esi
  lea    D7(%rip),%rdi
  sub    %rax,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: string

tool: D7: The sum of all the multiples of 3 or 5 below %lu: %lu


assistant: ```c
int main() {
  long ret = 0;
  ret = div(3) + div(5) - div(15);
  printf("The sum of all the multiples of 3 or 5 below %lu: %lu\n", ((long)999), ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_cmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L14:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  subq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jge    L14
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_cmatrix(unsigned char **m, long nrl, long nrh, long ncl, long nch) {
  long i;
  for (i = nrh; i >= nrl; i--)
    free((unsigned char *)(m[i] + ncl));
  free((unsigned char *)(m + nrl));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<free_cmatrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rcx,%r13
  cmp    %rsi,%rdx
  jl     L12
L8:
  mov    %r13,%rdi
  add    (%r12,%rbx,8),%rdi
  call   <free@plt>
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jle    L8
L12:
  lea    (%r12,%rbp,8),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void free_cmatrix(unsigned char **m, long nrl, long nrh, long ncl, long nch) {
  long i;
  for (i = nrh; i >= nrl; i--)
    free((unsigned char *)(m[i] + ncl));
  free((unsigned char *)(m + nrl));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<free_cmatrix>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  cmp    %rsi,%rdx
  jl     L9
  nop
L8:
  mov    (%r12,%rbx,8),%rdi
  sub    $0x1,%rbx
  add    %r13,%rdi
  call   <free@plt>
  cmp    %rbx,%rbp
  jle    L8
L9:
  add    $0x8,%rsp
  lea    (%r12,%rbp,8),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <free@plt>
```

assistant: ```c
void free_cmatrix(unsigned char **m, long nrl, long nrh, long ncl, long nch) {
  long i;
  for (i = nrh; i >= nrl; i--)
    free((unsigned char *)(m[i] + ncl));
  free((unsigned char *)(m + nrl));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<free_cmatrix>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  cmp    %rsi,%rdx
  jl     L10
  nop
L13:
  mov    (%r12,%rbx,8),%rdi
  sub    $0x1,%rbx
  add    %r13,%rdi
  call   <free@plt>
  cmp    %rbx,%rbp
  jle    L13
L10:
  add    $0x8,%rsp
  lea    (%r12,%rbp,8),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <free@plt>
```

assistant: ```c
void free_cmatrix(unsigned char **m, long nrl, long nrh, long ncl, long nch) {
  long i;
  for (i = nrh; i >= nrl; i--)
    free((unsigned char *)(m[i] + ncl));
  free((unsigned char *)(m + nrl));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wav_channels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L0
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  or     $0x8,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D11
type_infered: string

tool: D4: 

tool: D11: 

assistant: ```c
int wav_channels(int flags, uint32_t *speaker_flags) {
  static const uint32_t speaker_tbl[] = {
      0x4, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2 | 0x4, 0x1 | 0x2 | 0x100, 0x1 | 0x2 | 0x4 | 0x100, 0x1 | 0x2 | 0x10 | 0x20, 0x1 | 0x2 | 0x4 | 0x10 | 0x20,
  };
  static const uint8_t nfchans_tbl[] = {1, 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6, 6, 7, 8, 8};
  int chans;
  *speaker_flags = speaker_tbl[flags & 0x3F];
  chans = nfchans_tbl[flags & 0x3F];
  if (flags & 0x80) {
    *speaker_flags |= 0x8;
    chans++;
  }
  return chans;
}
```
user: What is the c source code of the assembly code below:

```asm
<wav_channels>:
  endbr64
  mov    %edi,%edx
  and    $0x3f,%edx
  lea    D14(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  mov    %eax,(%rsi)
  lea    D9(%rip),%rcx
  mov    (%rcx,%rdx,4),%edx
  test   $0x80,%dil
  je     L4
  or     $0x8,%eax
  mov    %eax,(%rsi)
  add    $0x1,%edx
L4:
  mov    %edx,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type_guessed: string
name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D14: 

tool: D9: 

assistant: ```c
int wav_channels(int flags, uint32_t *speaker_flags) {
  static const uint32_t speaker_tbl[] = {
      0x4, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2 | 0x4, 0x1 | 0x2 | 0x100, 0x1 | 0x2 | 0x4 | 0x100, 0x1 | 0x2 | 0x10 | 0x20, 0x1 | 0x2 | 0x4 | 0x10 | 0x20,
  };
  static const uint8_t nfchans_tbl[] = {1, 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6, 6, 7, 8, 8};
  int chans;
  *speaker_flags = speaker_tbl[flags & 0x3F];
  chans = nfchans_tbl[flags & 0x3F];
  if (flags & 0x80) {
    *speaker_flags |= 0x8;
    chans++;
  }
  return chans;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wav_channels>:
  endbr64
  mov    %edi,%edx
  lea    D6(%rip),%rax
  lea    D1(%rip),%rcx
  and    $0x3f,%edx
  and    $0x80,%edi
  mov    (%rax,%rdx,4),%eax
  mov    (%rcx,%rdx,4),%r8d
  mov    %eax,(%rsi)
  je     L6
  or     $0x8,%eax
  add    $0x1,%r8d
  mov    %eax,(%rsi)
L6:
  mov    %r8d,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D6: 

tool: D1: 

assistant: ```c
int wav_channels(int flags, uint32_t *speaker_flags) {
  static const uint32_t speaker_tbl[] = {
      0x4, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2 | 0x4, 0x1 | 0x2 | 0x100, 0x1 | 0x2 | 0x4 | 0x100, 0x1 | 0x2 | 0x10 | 0x20, 0x1 | 0x2 | 0x4 | 0x10 | 0x20,
  };
  static const uint8_t nfchans_tbl[] = {1, 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6, 6, 7, 8, 8};
  int chans;
  *speaker_flags = speaker_tbl[flags & 0x3F];
  chans = nfchans_tbl[flags & 0x3F];
  if (flags & 0x80) {
    *speaker_flags |= 0x8;
    chans++;
  }
  return chans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wav_channels>:
  endbr64
  mov    %edi,%edx
  lea    D5(%rip),%rax
  lea    D1(%rip),%rcx
  and    $0x3f,%edx
  and    $0x80,%edi
  mov    (%rax,%rdx,4),%eax
  mov    (%rcx,%rdx,4),%r8d
  mov    %eax,(%rsi)
  je     L5
  or     $0x8,%eax
  add    $0x1,%r8d
  mov    %eax,(%rsi)
L5:
  mov    %r8d,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string

tool: D5: 

tool: D1: 

assistant: ```c
int wav_channels(int flags, uint32_t *speaker_flags) {
  static const uint32_t speaker_tbl[] = {
      0x4, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2, 0x1 | 0x2 | 0x4, 0x1 | 0x2 | 0x100, 0x1 | 0x2 | 0x4 | 0x100, 0x1 | 0x2 | 0x10 | 0x20, 0x1 | 0x2 | 0x4 | 0x10 | 0x20,
  };
  static const uint8_t nfchans_tbl[] = {1, 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6, 6, 7, 8, 8};
  int chans;
  *speaker_flags = speaker_tbl[flags & 0x3F];
  chans = nfchans_tbl[flags & 0x3F];
  if (flags & 0x80) {
    *speaker_flags |= 0x8;
    chans++;
  }
  return chans;
}
```