user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D27(%rip),%rdi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <system@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rcx
  lea    0xa0(%rsp),%rax
  mov    %rcx,0x10(%rsp)
  mov    %rax,%rbp
  mov    %rax,0x20(%rsp)
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rbp,0x28(%rsp)
  mov    %eax,%ebp
L22:
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%r15
  add    $0x1,%ebp
  xor    %ebx,%ebx
  mov    %rax,0x18(%rsp)
  sub    %r12,%rax
  mov    %rax,%r14
L44:
  add    $0x1,%ebx
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  mov    %ebx,%edx
  add    $0x14,%r15
  call   <printf@plt>
  mov    %r14,%rsi
  lea    D68(%rip),%rdi
  call   <scanf@plt>
  lea    (%r14,%r12,1),%rax
  add    $0x4,%r14
  mov    (%rax,%r13,1),%eax
  mov    %eax,-0x14(%r15)
  cmp    $0x5,%ebx
  jne    L44
  mov    $0xa,%edi
  sub    $0x14,%r12
  add    $0x14,%r13
  call   <putchar@plt>
  addq   $0x4,0x8(%rsp)
  cmp    $0x5,%ebp
  jne    L22
  lea    D27(%rip),%rdi
  mov    0x28(%rsp),%rbp
  mov    0x18(%rsp),%rbx
  lea    D14(%rip),%r12
  call   <system@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rax
  lea    0x64(%rax),%r13
L67:
  xor    %r14d,%r14d
L56:
  mov    (%rbx,%r14,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    $0x5,%r14
  jne    L56
  mov    $0xa,%edi
  add    $0x14,%rbx
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L67
  lea    D87(%rip),%rdi
  call   <puts@plt>
  lea    D77(%rip),%rdi
  call   <puts@plt>
  mov    0x20(%rsp),%rax
  lea    0x64(%rax),%r13
L63:
  xor    %ebx,%ebx
L55:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L55
  mov    $0xa,%edi
  add    $0x14,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L63
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x20(%rsp),%rsi
  mov    0x10(%rsp),%rdi
  call   <karsilikliEsit@plt>
  lea    D79(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x118,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D58
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D68
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string
name: extract_symbolic_data
arguments: tag: D28
data_type: string
name: extract_symbolic_data
arguments: tag: D87
data_type: string
name: extract_symbolic_data
arguments: tag: D77
data_type: string
name: extract_symbolic_data
arguments: tag: D79
data_type: string

tool: D27: clear

tool: D58: 
Lutfen 5x5 matris tam sayi elemanlarini giriniz!


tool: D19: %d. satir, %d. sutun elemani giriniz: 

tool: D68:  %d

tool: D14: %d	

tool: D28: ---Matris---


tool: D87: 


tool: D77: ---Transpoz---


tool: D79: Esit eleman sayisi = %d


assistant: ```c
int main() {
  system("clear");
  int i, j;
  int matris[5][5], transpoz[5][5];
  int esit_eleman;
  printf("\nLutfen 5x5 matris tam sayi elemanlarini giriniz!\n\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d. satir, %d. sutun elemani giriniz: ", i + 1, j + 1);
      scanf(" %d", &matris[i][j]);
      transpoz[j][i] = matris[i][j];
    }
    printf("\n");
  }
  system("clear");
  printf("---Matris---\n\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d\t", matris[i][j]);
    }
    printf("\n");
  }
  printf("\n\n");
  printf("---Transpoz---\n\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d\t", transpoz[i][j]);
    }
    printf("\n");
  }
  printf("\n");
  esit_eleman = karsilikliEsit(matris, transpoz);
  printf("Esit eleman sayisi = %d\n", esit_eleman);
  return 0;
}
```