user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rsi
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x30(%rbp)
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,-0x2c(%rbp)
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    -0x30(%rbp),%r8d
  lea    (%r8,%r8,1),%edi
  lea    -0x1(%rdi),%r9d
  movslq %r9d,%r12
  movslq %r8d,%rax
  imul   %r12,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L126:
  cmp    %rdx,%rsp
  je     L106
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L126
L106:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L42
  orq    $0x0,-0x8(%rsp,%rax,1)
L42:
  mov    %rsp,%r13
  mov    -0x2c(%rbp),%r11d
  test   %r11d,%r11d
  je     L30
  test   %r8d,%r8d
  jle    L97
  lea    -0x2(%r8,%r8,1),%r10d
  mov    %r13,%r11
  mov    $0x0,%esi
  sub    $0x1,%edi
  jmp    L195
L30:
  test   %r8d,%r8d
  jle    L97
  sub    $0x1,%r8d
  mov    %r13,%r10
  mov    %r8d,%esi
  sub    $0x1,%edi
  jmp    L227
L20:
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %eax,%edi
  je     L202
L244:
  movb   $0x20,(%rdx)
  cmp    %esi,%eax
  jl     L20
  cmp    %r8d,%eax
  jg     L20
  cmpb   $0x2a,-0x1(%rdx)
  je     L20
  movb   $0x2a,(%rdx)
  jmp    L20
L202:
  add    $0x1,%r8d
  add    %r12,%r10
  sub    $0x1,%esi
  cmp    $0xffffffff,%esi
  je     L299
L227:
  mov    %r10,%rdx
  mov    %r11d,%eax
  test   %r9d,%r9d
  jg     L244
  jmp    L202
L11:
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %edi,%eax
  je     L212
L4:
  movb   $0x20,(%rdx)
  cmp    %eax,%esi
  jg     L11
  cmp    %r10d,%eax
  jg     L11
  cmpb   $0x2a,-0x1(%rdx)
  je     L11
  movb   $0x2a,(%rdx)
  jmp    L11
L212:
  add    $0x1,%esi
  sub    $0x1,%r10d
  add    %r12,%r11
  cmp    %esi,%r8d
  je     L299
L195:
  mov    %r11,%rdx
  mov    $0x0,%eax
  test   %r9d,%r9d
  jg     L4
  jmp    L212
L149:
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax,%rax,1),%eax
  cmp    %ebx,%eax
  jg     L149
L41:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r14d
  add    %r12,%r13
  cmp    %r14d,-0x30(%rbp)
  jle    L97
L175:
  mov    -0x30(%rbp),%eax
  add    %eax,%eax
  mov    $0x0,%ebx
  cmp    $0x1,%eax
  jg     L149
  jmp    L41
L97:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L260
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L299:
  mov    $0x0,%r14d
  jmp    L175
L260:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D20
type: string
name: extract_symbolic_data
arguments: label: D5
type: string

tool: D13: Please enter the number of rows you would like in your pyramid: 

tool: D20: %d

tool: D5: Please enter 1 if you would like your pyramid to be inverted, 0 otherwise: 

assistant: ```c
int main(int argc, const char *argv[]) {
  int n = 0, inverted = 0, i = 0, j = 0;
  printf("Please enter the number of rows you would like in your pyramid: ");
  scanf("%d", &n);
  assert(n > 0);
  printf("Please enter 1 if you would like your pyramid to be inverted, 0 otherwise: ");
  scanf("%d", &inverted);
  assert(inverted == 0 || inverted == 1);
  char a[n][n * 2 - 1];
  if (!inverted) {
    for (i = 0; i < n; i++) {
      for (j = 0; j < n * 2 - 1; j++) {
        a[i][j] = ' ';
        if (n - 1 - i <= j && j <= n - 1 + i && a[i][j - 1] != '*') {
          a[i][j] = '*';
        }
      }
    }
  } else {
    for (i = 0; i < n; i++) {
      for (j = 0; j < n * 2 - 1; j++) {
        a[i][j] = ' ';
        if (n - 1 - (n - 1 - i) <= j && j <= n - 1 + (n - 1 - i) && a[i][j - 1] != '*') {
          a[i][j] = '*';
        }
      }
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n * 2 - 1; j++) {
      printf("%c", a[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```