user: 这段汇编代码用C语言表示是什么样的?

```asm
<InverseModify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %esi,-0x8c(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %rcx,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4344414247484546,%rax
  movabs $0x4b4c494a4f504d4e,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L11
L93:
  mov    -0x78(%rbp),%eax
  cltq
  movl   $0x0,-0x60(%rbp,%rax,4)
  addl   $0x1,-0x78(%rbp)
L11:
  cmpl   $0xf,-0x78(%rbp)
  jle    L93
  mov    -0x8c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x68(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L133
L47:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    -0x78(%rbp),%edx
  add    %edx,%edx
  movslq %edx,%rcx
  mov    -0x68(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  movslq %eax,%rdx
  mov    -0x60(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x78(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x68(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  movslq %eax,%rdx
  mov    -0x60(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
  addl   $0x1,-0x78(%rbp)
L133:
  mov    -0x78(%rbp),%eax
  cmp    -0x8c(%rbp),%eax
  jl     L47
  mov    -0x8c(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x60(%rbp),%eax
  mov    %eax,-0x6c(%rbp)
  movl   $0x1,-0x78(%rbp)
  jmp    L103
L52:
  mov    -0x78(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  cmp    %eax,-0x6c(%rbp)
  jge    L107
  mov    -0x78(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,-0x6c(%rbp)
L107:
  addl   $0x1,-0x78(%rbp)
L103:
  cmpl   $0xf,-0x78(%rbp)
  jle    L52
  mov    -0x6c(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xa0(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xa0(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x98(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x78(%rbp)
  jmp    L10
L90:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x98(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x78(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x78(%rbp)
L10:
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x78(%rbp)
  jl     L90
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L138
L19:
  mov    -0x74(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,-0x70(%rbp)
  jmp    L64
L82:
  mov    -0x98(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x78(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x78(%rbp)
  addl   $0x1,-0x70(%rbp)
L64:
  mov    -0x70(%rbp),%eax
  cmp    -0x6c(%rbp),%eax
  jl     L82
  addl   $0x1,-0x74(%rbp)
L138:
  cmpl   $0xf,-0x74(%rbp)
  jle    L19
  mov    -0x98(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xa0(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

assistant: ```c
void InverseModify(const char *modifiedBuf, const int modifiedLen, char **restoredString, int *restoredLen) {
  char binList[] = "FEHGBADCNMPOJILK";
  int frequencyTable[16];
  char *shellCodeBuffer;
  int i, j, k;
  int maxNum;
  for (i = 0; i < 16; ++i)
    frequencyTable[i] = 0;
  shellCodeBuffer = (char *)malloc(modifiedLen * 2 + 1);
  for (i = 0; i < modifiedLen; ++i) {
    shellCodeBuffer[i * 2] = binList[(unsigned char)modifiedBuf[i] >> 4];
    ++frequencyTable[(unsigned char)modifiedBuf[i] >> 4];
    shellCodeBuffer[i * 2 + 1] = binList[modifiedBuf[i] & 0x0f];
    ++frequencyTable[modifiedBuf[i] & 0x0f];
  }
  shellCodeBuffer[modifiedLen * 2] = 0;
  maxNum = frequencyTable[0];
  for (i = 1; i < 16; ++i)
    if (maxNum < frequencyTable[i])
      maxNum = frequencyTable[i];
  *restoredLen = maxNum * 16;
  *restoredString = (char *)malloc(*restoredLen + 1);
  for (i = 0; i < strlen(shellCodeBuffer); ++i)
    (*restoredString)[i] = shellCodeBuffer[i];
  free(shellCodeBuffer);
  for (j = 0; j < 16; ++j) {
    for (k = frequencyTable[j]; k < maxNum; ++k) {
      (*restoredString)[i] = binList[j];
      ++i;
    }
  }
  (*restoredString)[*restoredLen] = 0;
}
```