ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<obsolete>:
  endbr64
  mov    (%rdi),%rax
  test   %rax,%rax
  je     L71
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D6(%rip),%r13
  lea    D19(%rip),%r12
  lea    D18(%rip),%rbp
  jmp    L56
L70:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
L39:
  add    $0x8,%rbx
  mov    (%rbx),%rax
  test   %rax,%rax
  je     L119
L56:
  cmpb   $0x2d,(%rax)
  jne    L39
  mov    0x8(%rbx),%rdx
  test   %rdx,%rdx
  je     L13
  cmpb   $0x2d,(%rdx)
  jne    L39
L13:
  movzbl 0x1(%rax),%edx
  mov    %edx,%ecx
  and    $0xfffffffd,%ecx
  cmp    $0x69,%cl
  je     L60
  cmp    $0x65,%dl
  jne    L39
L60:
  cmpb   $0x0,0x2(%rax)
  jne    L39
  cmp    $0x69,%dl
  je     L70
  cmp    $0x6b,%dl
  je     L114
  cmp    $0x65,%dl
  jne    L39
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L39
L114:
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L39
L119:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D19
type: string
name: disassemble_data
arguments: data_tag: D18
type: string

tool: D6: -i^C

tool: D19: -k^U

tool: D18: -e^H

assistant: ```c
void obsolete(char *argv[]) {
  for (; *argv; ++argv) {
    if (argv[0][0] != '-' || (argv[1] && argv[1][0] != '-') || (argv[0][1] != 'e' && argv[0][1] != 'i' && argv[0][1] != 'k') || argv[0][2] != '\0')
      continue;
    switch (argv[0][1]) {
    case 'e':
      argv[0] = strdup("-e^H");
      break;
    case 'i':
      argv[0] = strdup("-i^C");
      break;
    case 'k':
      argv[0] = strdup("-k^U");
      break;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<obsolete>:
  endbr64
  mov    (%rdi),%rax
  test   %rax,%rax
  je     L6
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L150
  nopw   0x0(%rax,%rax,1)
L85:
  movzbl 0x1(%rax),%edx
  mov    %edx,%ecx
  and    $0xfffffffd,%ecx
  cmp    $0x69,%cl
  je     L173
  cmp    $0x65,%dl
  jne    L171
L173:
  cmpb   $0x0,0x2(%rax)
  jne    L171
L42:
  cmp    $0x69,%dl
  je     L26
  cmp    $0x6b,%dl
  je     L94
  cmp    $0x65,%dl
  je     L180
L27:
  add    $0x8,%rbx
  test   %rbp,%rbp
  je     L40
L56:
  mov    %rbp,%rax
L150:
  cmpb   $0x2d,(%rax)
  mov    0x8(%rbx),%rbp
  jne    L27
  test   %rbp,%rbp
  je     L80
  cmpb   $0x2d,0x0(%rbp)
  je     L85
L171:
  add    $0x8,%rbx
  jmp    L56
  cs nopw 0x0(%rax,%rax,1)
L80:
  movzbl 0x1(%rax),%edx
  mov    %edx,%ecx
  and    $0xfffffffd,%ecx
  cmp    $0x69,%cl
  je     L76
  cmp    $0x65,%dl
  jne    L40
L76:
  cmpb   $0x0,0x2(%rax)
  je     L42
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r14,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L27
  nopl   (%rax)
L180:
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L27
  nopl   (%rax)
L94:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D16
datatype: string

tool: D14: -i^C

tool: D29: -k^U

tool: D16: -e^H

assistant: ```c
void obsolete(char *argv[]) {
  for (; *argv; ++argv) {
    if (argv[0][0] != '-' || (argv[1] && argv[1][0] != '-') || (argv[0][1] != 'e' && argv[0][1] != 'i' && argv[0][1] != 'k') || argv[0][2] != '\0')
      continue;
    switch (argv[0][1]) {
    case 'e':
      argv[0] = strdup("-e^H");
      break;
    case 'i':
      argv[0] = strdup("-i^C");
      break;
    case 'k':
      argv[0] = strdup("-k^U");
      break;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<obsolete>:
  endbr64
  mov    (%rdi),%rax
  test   %rax,%rax
  je     L2
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L50:
  movzbl 0x1(%rax),%edx
  mov    %edx,%ecx
  and    $0xfffffffd,%ecx
  cmp    $0x69,%cl
  je     L132
  cmp    $0x65,%dl
  jne    L149
L132:
  cmpb   $0x0,0x2(%rax)
  jne    L149
L134:
  cmp    $0x69,%dl
  je     L118
  cmp    $0x6b,%dl
  je     L111
  cmp    $0x65,%dl
  je     L36
L101:
  add    $0x8,%rbx
  test   %rbp,%rbp
  je     L11
L137:
  mov    %rbp,%rax
L88:
  cmpb   $0x2d,(%rax)
  mov    0x8(%rbx),%rbp
  jne    L101
  test   %rbp,%rbp
  je     L152
  cmpb   $0x2d,0x0(%rbp)
  je     L50
L149:
  add    $0x8,%rbx
  jmp    L137
  cs nopw 0x0(%rax,%rax,1)
L152:
  movzbl 0x1(%rax),%edx
  mov    %edx,%ecx
  and    $0xfffffffd,%ecx
  cmp    $0x69,%cl
  je     L150
  cmp    $0x65,%dl
  jne    L11
L150:
  cmpb   $0x0,0x2(%rax)
  je     L134
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L118:
  mov    %r14,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L101
  nopl   (%rax)
L36:
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L101
  nopl   (%rax)
L111:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D21
type_guessed: string
name: parse_data
arguments: data_label: D26
type_guessed: string
name: parse_data
arguments: data_label: D25
type_guessed: string

tool: D21: -i^C

tool: D26: -k^U

tool: D25: -e^H

assistant: ```c
void obsolete(char *argv[]) {
  for (; *argv; ++argv) {
    if (argv[0][0] != '-' || (argv[1] && argv[1][0] != '-') || (argv[0][1] != 'e' && argv[0][1] != 'i' && argv[0][1] != 'k') || argv[0][2] != '\0')
      continue;
    switch (argv[0][1]) {
    case 'e':
      argv[0] = strdup("-e^H");
      break;
    case 'i':
      argv[0] = strdup("-i^C");
      break;
    case 'k':
      argv[0] = strdup("-k^U");
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<action_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  imul   -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xc8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
int action_hash(void *vstr) {
  char *str = vstr;
  int len = strlen(str);
  return (len * str[0]) % 200;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<action_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movsbl (%rbx),%edx
  imul   %eax,%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x26,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xc8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int action_hash(void *vstr) {
  char *str = vstr;
  int len = strlen(str);
  return (len * str[0]) % 200;
}
```
user: What is the c source code of the assembly code below?

```asm
<action_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movsbl (%rbx),%edx
  pop    %rbx
  imul   %eax,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  imul   $0xc8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int action_hash(void *vstr) {
  char *str = vstr;
  int len = strlen(str);
  return (len * str[0]) % 200;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<action_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movsbl (%rbx),%edx
  pop    %rbx
  imul   %eax,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  imul   $0xc8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int action_hash(void *vstr) {
  char *str = vstr;
  int len = strlen(str);
  return (len * str[0]) % 200;
}
```
user: Translate the below assembly code into C programming language:

```asm
<graph_xstrerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <graph_strerror@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  jmp    L19
L7:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
L19:
  leave
  ret
```

assistant: ```c
char const *graph_xstrerror(int err) {
  char const *st = graph_strerror(err);
  if (st != NULL)
    return st;
  return strerror(err);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<graph_xstrerror>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <graph_strerror@plt>
  test   %rax,%rax
  je     L19
L17:
  pop    %rbx
  ret
L19:
  mov    %ebx,%edi
  call   <strerror@plt>
  jmp    L17
```

assistant: ```c
char const *graph_xstrerror(int err) {
  char const *st = graph_strerror(err);
  if (st != NULL)
    return st;
  return strerror(err);
}
```
user: What is the c source code of the assembly code below:

```asm
<graph_xstrerror>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <graph_strerror@plt>
  test   %rax,%rax
  je     L0
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <strerror@plt>
```

assistant: ```c
char const *graph_xstrerror(int err) {
  char const *st = graph_strerror(err);
  if (st != NULL)
    return st;
  return strerror(err);
}
```
user: What is the c source code of the assembly code below:

```asm
<graph_xstrerror>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <graph_strerror@plt>
  test   %rax,%rax
  je     L4
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <strerror@plt>
```

assistant: ```c
char const *graph_xstrerror(int err) {
  char const *st = graph_strerror(err);
  if (st != NULL)
    return st;
  return strerror(err);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L79
L44:
  cmpl   $0x1,-0x1c(%rbp)
  jne    L53
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_rate_drop_factor@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L79
L53:
  cmpl   $0x2,-0x1c(%rbp)
  jne    L15
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <fig_ml_hr@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L79
L15:
  cmpl   $0x3,-0x1c(%rbp)
  jne    L67
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_kg_rate_conc@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L79
L67:
  cmpl   $0x4,-0x1c(%rbp)
  jne    L79
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_units_conc@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L79:
  mov    $0x0,%eax
  call   <get_problem@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x5,-0x1c(%rbp)
  jne    L44
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D22
type: string
name: read_data
arguments: data_label: D47
type: string
name: read_data
arguments: data_label: D42
type: string
name: read_data
arguments: data_label: D43
type: string
name: read_data
arguments: data_label: D53
type: string

tool: D22: 
INTRAVENOUS RATE ASSISTANT

tool: D47: 
The drop rate per minute is %.2f

tool: D42: 
Enter number of hours=>

tool: D43: %lf

tool: D53: 
The rate in milliliters per hour is %.2f

assistant: ```c
void main() {
  int choice;
  printf("\nINTRAVENOUS RATE ASSISTANT");
  while ((choice = get_problem()) != 5) {
    double rate;
    if (choice == 1) {
      get_rate_drop_factor(&rate);
      printf("\nThe drop rate per minute is %.2f", rate);
    } else if (choice == 2) {
      double no_hrs;
      printf("\nEnter number of hours=>");
      scanf("%lf", &no_hrs);
      rate = fig_ml_hr(no_hrs);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    } else if (choice == 3) {
      get_kg_rate_conc(&rate);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    } else if (choice == 4) {
      get_units_conc(&rate);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    }
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rbx
  lea    D10(%rip),%r13
  lea    D11(%rip),%r12
  lea    D29(%rip),%rbp
  jmp    L5
L88:
  lea    0x8(%rsp),%rdi
  call   <get_rate_drop_factor@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L5:
  mov    $0x0,%eax
  call   <get_problem@plt>
  cmp    $0x5,%eax
  je     L67
  cmp    $0x1,%eax
  je     L88
  cmp    $0x2,%eax
  je     L28
  cmp    $0x3,%eax
  je     L35
  cmp    $0x4,%eax
  jne    L5
  lea    0x8(%rsp),%rdi
  call   <get_units_conc@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L5
L28:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  call   <fig_ml_hr@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L5
L35:
  lea    0x8(%rsp),%rdi
  call   <get_kg_rate_conc@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L5
L67:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D11
datatype: string
name: extract_symbolic_data
arguments: tag: D29
datatype: string

tool: D27: 
INTRAVENOUS RATE ASSISTANT

tool: D7: 
The rate in milliliters per hour is %.2f

tool: D10: 
Enter number of hours=>

tool: D11: %lf

tool: D29: 
The drop rate per minute is %.2f

assistant: ```c
void main() {
  int choice;
  printf("\nINTRAVENOUS RATE ASSISTANT");
  while ((choice = get_problem()) != 5) {
    double rate;
    if (choice == 1) {
      get_rate_drop_factor(&rate);
      printf("\nThe drop rate per minute is %.2f", rate);
    } else if (choice == 2) {
      double no_hrs;
      printf("\nEnter number of hours=>");
      scanf("%lf", &no_hrs);
      rate = fig_ml_hr(no_hrs);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    } else if (choice == 3) {
      get_kg_rate_conc(&rate);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    } else if (choice == 4) {
      get_units_conc(&rate);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    }
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D26(%rip),%rdi
  lea    D17(%rip),%r13
  push   %r12
  lea    D45(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  lea    D44(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L47:
  xor    %eax,%eax
  call   <get_problem@plt>
  cmp    $0x5,%eax
  je     L10
L18:
  cmp    $0x1,%eax
  je     L87
  cmp    $0x2,%eax
  je     L86
  cmp    $0x3,%eax
  je     L76
  cmp    $0x4,%eax
  jne    L47
  lea    0x8(%rsp),%rdi
  call   <get_units_conc@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <get_problem@plt>
  cmp    $0x5,%eax
  jne    L18
  nopl   0x0(%rax)
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <putchar@plt>
L87:
  lea    0x8(%rsp),%rdi
  call   <get_rate_drop_factor@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L86:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  call   <fig_ml_hr@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L76:
  lea    0x8(%rsp),%rdi
  call   <get_kg_rate_conc@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L47
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_guessed: string
name: disassemble_data
arguments: data_label: D17
type_guessed: string
name: disassemble_data
arguments: data_label: D45
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D44
type_guessed: string

tool: D26: 
INTRAVENOUS RATE ASSISTANT

tool: D17: 
Enter number of hours=>

tool: D45: %lf

tool: D11: 
The drop rate per minute is %.2f

tool: D44: 
The rate in milliliters per hour is %.2f

assistant: ```c
void main() {
  int choice;
  printf("\nINTRAVENOUS RATE ASSISTANT");
  while ((choice = get_problem()) != 5) {
    double rate;
    if (choice == 1) {
      get_rate_drop_factor(&rate);
      printf("\nThe drop rate per minute is %.2f", rate);
    } else if (choice == 2) {
      double no_hrs;
      printf("\nEnter number of hours=>");
      scanf("%lf", &no_hrs);
      rate = fig_ml_hr(no_hrs);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    } else if (choice == 3) {
      get_kg_rate_conc(&rate);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    } else if (choice == 4) {
      get_units_conc(&rate);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    }
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%rdi
  lea    D11(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D42(%rip),%rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L37:
  xor    %eax,%eax
  call   <get_problem@plt>
  cmp    $0x5,%eax
  je     L44
L1:
  cmp    $0x1,%eax
  je     L69
  cmp    $0x2,%eax
  je     L68
  cmp    $0x3,%eax
  je     L78
  cmp    $0x4,%eax
  jne    L37
  lea    0x8(%rsp),%rdi
  call   <get_units_conc@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <get_problem@plt>
  cmp    $0x5,%eax
  jne    L1
  nopl   0x0(%rax)
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <putchar@plt>
L69:
  lea    0x8(%rsp),%rdi
  call   <get_rate_drop_factor@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L68:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  call   <fig_ml_hr@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L78:
  lea    0x8(%rsp),%rdi
  call   <get_kg_rate_conc@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L37
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string
name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D42
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D10: 
INTRAVENOUS RATE ASSISTANT

tool: D11: 
Enter number of hours=>

tool: D1: %lf

tool: D42: 
The drop rate per minute is %.2f

tool: D5: 
The rate in milliliters per hour is %.2f

assistant: ```c
void main() {
  int choice;
  printf("\nINTRAVENOUS RATE ASSISTANT");
  while ((choice = get_problem()) != 5) {
    double rate;
    if (choice == 1) {
      get_rate_drop_factor(&rate);
      printf("\nThe drop rate per minute is %.2f", rate);
    } else if (choice == 2) {
      double no_hrs;
      printf("\nEnter number of hours=>");
      scanf("%lf", &no_hrs);
      rate = fig_ml_hr(no_hrs);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    } else if (choice == 3) {
      get_kg_rate_conc(&rate);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    } else if (choice == 4) {
      get_units_conc(&rate);
      printf("\nThe rate in milliliters per hour is %.2f", rate);
    }
  }
  printf("\n");
}
```