ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L11
  cmp    $0x10000000,%edi
  ja     L11
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0x180,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/xarray.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/xarray.c", 384));
  return word_ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InstructionSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D43(%rip),%eax
  test   %eax,%eax
  js     L34
  mov    D43(%rip),%eax
  jmp    L74
L34:
  movl   $0x0,D43(%rip)
  mov    $0x1,%esi
  lea    D122(%rip),%rax
  mov    %rax,%rdi
  call   <__cpuid@plt>
  mov    D185(%rip),%eax
  mov    %eax,D116(%rip)
  mov    D195(%rip),%eax
  mov    %eax,D123(%rip)
  movl   $0x4,D43(%rip)
  mov    D123(%rip),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L85
  mov    D43(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D169(%rip)
  mov    D123(%rip),%eax
  and    $0x200,%eax
  test   %eax,%eax
  je     L91
  mov    D169(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D169(%rip)
  mov    D123(%rip),%eax
  and    $0x80000,%eax
  test   %eax,%eax
  je     L69
  movl   $0x8,D169(%rip)
  mov    D123(%rip),%eax
  and    $0x100000,%eax
  test   %eax,%eax
  je     L22
  movl   $0xa,D169(%rip)
  jmp    L59
L85:
  nop
  jmp    L59
L91:
  nop
  jmp    L59
L69:
  nop
  jmp    L59
L22:
  nop
L59:
  mov    D169(%rip),%eax
L74:
  pop    %rbp
  ret
```

assistant: ```c
int InstructionSet() {
  static int _rv = -1;
  static int cpuinfo[4];
  static unsigned _feat_edx, _feat_ecx;
  if (_rv >= 0) {
    return _rv;
  }
  _rv = 0;
  __cpuid(&cpuinfo, 1);
  _feat_edx = (unsigned)cpuinfo[3];
  _feat_ecx = (unsigned)cpuinfo[2];
  if (sizeof(void *) == 4) {
    if (!((_feat_edx >> 23) & 1))
      goto done;
    ++_rv;
    if (!((_feat_edx >> 24) & 1))
      goto done;
    if (!((_feat_edx >> 25) & 1))
      goto done;
    _rv = 3;
    if (!((_feat_edx >> 26) & 1))
      goto done;
    ++_rv;
  } else {
    _rv = 4;
  }
  if (!((_feat_ecx >> 0) & 1))
    goto done;
  ++_rv;
  if (!((_feat_ecx >> 9) & 1))
    goto done;
  ++_rv;
  if (!((_feat_ecx >> 19) & 1))
    goto done;
  _rv = 8;
  if (!((_feat_ecx >> 20) & 1))
    goto done;
  _rv = 10;
done:
  return _rv;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<InstructionSet>:
  endbr64
  mov    D62(%rip),%eax
  test   %eax,%eax
  js     L43
  ret
L43:
  sub    $0x8,%rsp
  movl   $0x0,D62(%rip)
  mov    $0x1,%esi
  lea    D32(%rip),%rdi
  call   <__cpuid@plt>
  mov    D3(%rip),%eax
  test   $0x1,%al
  je     L49
  test   $0x2,%ah
  je     L51
  test   $0x80000,%eax
  je     L6
  and    $0x100000,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0xfffffffe,%eax
  add    $0xa,%eax
  mov    %eax,D36(%rip)
  jmp    L9
L49:
  movl   $0x4,D36(%rip)
L9:
  mov    D36(%rip),%eax
  add    $0x8,%rsp
  ret
L51:
  movl   $0x5,D36(%rip)
  jmp    L9
L6:
  movl   $0x6,D36(%rip)
  jmp    L9
```

assistant: ```c
int InstructionSet() {
  static int _rv = -1;
  static int cpuinfo[4];
  static unsigned _feat_edx, _feat_ecx;
  if (_rv >= 0) {
    return _rv;
  }
  _rv = 0;
  __cpuid(&cpuinfo, 1);
  _feat_edx = (unsigned)cpuinfo[3];
  _feat_ecx = (unsigned)cpuinfo[2];
  if (sizeof(void *) == 4) {
    if (!((_feat_edx >> 23) & 1))
      goto done;
    ++_rv;
    if (!((_feat_edx >> 24) & 1))
      goto done;
    if (!((_feat_edx >> 25) & 1))
      goto done;
    _rv = 3;
    if (!((_feat_edx >> 26) & 1))
      goto done;
    ++_rv;
  } else {
    _rv = 4;
  }
  if (!((_feat_ecx >> 0) & 1))
    goto done;
  ++_rv;
  if (!((_feat_ecx >> 9) & 1))
    goto done;
  ++_rv;
  if (!((_feat_ecx >> 19) & 1))
    goto done;
  _rv = 8;
  if (!((_feat_ecx >> 20) & 1))
    goto done;
  _rv = 10;
done:
  return _rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InstructionSet>:
  endbr64
  mov    D25(%rip),%eax
  test   %eax,%eax
  js     L72
  ret
  nop
L72:
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D56(%rip),%rdi
  movl   $0x0,D25(%rip)
  call   <__cpuid@plt>
  mov    D60(%rip),%eax
  test   $0x1,%al
  je     L74
  test   $0x2,%ah
  je     L49
  test   $0x80000,%eax
  je     L22
  test   $0x100000,%eax
  je     L48
  movl   $0xa,D25(%rip)
  mov    $0xa,%eax
L62:
  add    $0x8,%rsp
  ret
L49:
  movl   $0x5,D25(%rip)
  mov    $0x5,%eax
  jmp    L62
  nopl   0x0(%rax)
L74:
  movl   $0x4,D25(%rip)
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L22:
  movl   $0x6,D25(%rip)
  mov    $0x6,%eax
  jmp    L62
  nopl   0x0(%rax)
L48:
  movl   $0x8,D25(%rip)
  mov    $0x8,%eax
  jmp    L62
```

assistant: ```c
int InstructionSet() {
  static int _rv = -1;
  static int cpuinfo[4];
  static unsigned _feat_edx, _feat_ecx;
  if (_rv >= 0) {
    return _rv;
  }
  _rv = 0;
  __cpuid(&cpuinfo, 1);
  _feat_edx = (unsigned)cpuinfo[3];
  _feat_ecx = (unsigned)cpuinfo[2];
  if (sizeof(void *) == 4) {
    if (!((_feat_edx >> 23) & 1))
      goto done;
    ++_rv;
    if (!((_feat_edx >> 24) & 1))
      goto done;
    if (!((_feat_edx >> 25) & 1))
      goto done;
    _rv = 3;
    if (!((_feat_edx >> 26) & 1))
      goto done;
    ++_rv;
  } else {
    _rv = 4;
  }
  if (!((_feat_ecx >> 0) & 1))
    goto done;
  ++_rv;
  if (!((_feat_ecx >> 9) & 1))
    goto done;
  ++_rv;
  if (!((_feat_ecx >> 19) & 1))
    goto done;
  _rv = 8;
  if (!((_feat_ecx >> 20) & 1))
    goto done;
  _rv = 10;
done:
  return _rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InstructionSet>:
  endbr64
  mov    D38(%rip),%eax
  test   %eax,%eax
  js     L58
  ret
  nop
L58:
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  movl   $0x0,D38(%rip)
  call   <__cpuid@plt>
  mov    D62(%rip),%eax
  test   $0x1,%al
  je     L29
  test   $0x2,%ah
  je     L44
  test   $0x80000,%eax
  je     L3
  test   $0x100000,%eax
  je     L59
  movl   $0xa,D38(%rip)
  mov    $0xa,%eax
L30:
  add    $0x8,%rsp
  ret
L44:
  movl   $0x5,D38(%rip)
  mov    $0x5,%eax
  jmp    L30
  nopl   0x0(%rax)
L29:
  movl   $0x4,D38(%rip)
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  movl   $0x6,D38(%rip)
  mov    $0x6,%eax
  jmp    L30
  nopl   0x0(%rax)
L59:
  movl   $0x8,D38(%rip)
  mov    $0x8,%eax
  jmp    L30
```

assistant: ```c
int InstructionSet() {
  static int _rv = -1;
  static int cpuinfo[4];
  static unsigned _feat_edx, _feat_ecx;
  if (_rv >= 0) {
    return _rv;
  }
  _rv = 0;
  __cpuid(&cpuinfo, 1);
  _feat_edx = (unsigned)cpuinfo[3];
  _feat_ecx = (unsigned)cpuinfo[2];
  if (sizeof(void *) == 4) {
    if (!((_feat_edx >> 23) & 1))
      goto done;
    ++_rv;
    if (!((_feat_edx >> 24) & 1))
      goto done;
    if (!((_feat_edx >> 25) & 1))
      goto done;
    _rv = 3;
    if (!((_feat_edx >> 26) & 1))
      goto done;
    ++_rv;
  } else {
    _rv = 4;
  }
  if (!((_feat_ecx >> 0) & 1))
    goto done;
  ++_rv;
  if (!((_feat_ecx >> 9) & 1))
    goto done;
  ++_rv;
  if (!((_feat_ecx >> 19) & 1))
    goto done;
  _rv = 8;
  if (!((_feat_ecx >> 20) & 1))
    goto done;
  _rv = 10;
done:
  return _rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L1:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_strcpy(char *dest, const char *src) {
  char *save = dest;
  while ((*dest++ = *src++))
    ;
  return save;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L5:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L5
  ret
```

assistant: ```c
char *my_strcpy(char *dest, const char *src) {
  char *save = dest;
  while ((*dest++ = *src++))
    ;
  return save;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L0:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L0
  ret
```

assistant: ```c
char *my_strcpy(char *dest, const char *src) {
  char *save = dest;
  while ((*dest++ = *src++))
    ;
  return save;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L0:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L0
  ret
```

assistant: ```c
char *my_strcpy(char *dest, const char *src) {
  char *save = dest;
  while ((*dest++ = *src++))
    ;
  return save;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scalarMultiplyVector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <allocateDoubleVector@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *scalarMultiplyVector(double *a, double scalar, int n) {
  int i;
  double *b;
  b = allocateDoubleVector(n);
  for (i = 0; i < n; i++)
    b[i] = scalar * a[i];
  return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<scalarMultiplyVector>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movq   %xmm0,%r12
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <allocateDoubleVector@plt>
  test   %ebx,%ebx
  jle    L12
  mov    %ebx,%esi
  mov    $0x0,%edx
L11:
  movq   %r12,%xmm0
  mulsd  0x0(%rbp,%rdx,8),%xmm0
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L11
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *scalarMultiplyVector(double *a, double scalar, int n) {
  int i;
  double *b;
  b = allocateDoubleVector(n);
  for (i = 0; i < n; i++)
    b[i] = scalar * a[i];
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<scalarMultiplyVector>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <allocateDoubleVector@plt>
  test   %ebx,%ebx
  jle    L12
  movsd  0x8(%rsp),%xmm0
  movslq %ebx,%rsi
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L2:
  movsd  0x0(%rbp,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L2
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *scalarMultiplyVector(double *a, double scalar, int n) {
  int i;
  double *b;
  b = allocateDoubleVector(n);
  for (i = 0; i < n; i++)
    b[i] = scalar * a[i];
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scalarMultiplyVector>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <allocateDoubleVector@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L50
  lea    0x8(%rbx),%rax
  movsd  0x8(%rsp),%xmm0
  cmp    %rax,%r8
  je     L33
  lea    -0x1(%rbp),%eax
  cmp    $0x1,%eax
  jbe    L33
  mov    %ebp,%edx
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rdx
  nopl   0x0(%rax)
L48:
  movupd (%rbx,%rax,1),%xmm1
  mulpd  %xmm2,%xmm1
  movups %xmm1,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L48
  mov    %ebp,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ebp
  je     L50
  mulsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
L50:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L23:
  movsd  (%rbx,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rbp
  jne    L23
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *scalarMultiplyVector(double *a, double scalar, int n) {
  int i;
  double *b;
  b = allocateDoubleVector(n);
  for (i = 0; i < n; i++)
    b[i] = scalar * a[i];
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sumEvenAfterQueries>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  mov    %ecx,(%r9)
  movl   $0x2,(%r8)
  lea    0x0(,%rcx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r9
  test   %r13d,%r13d
  jle    L4
  mov    %rbx,%rdx
  lea    -0x1(%r13),%eax
  lea    0x4(%rbx,%rax,4),%rdi
  mov    $0x0,%eax
L77:
  mov    (%rdx),%ecx
  lea    (%rax,%rcx,1),%esi
  test   $0x1,%cl
  cmove  %esi,%eax
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L77
L68:
  test   %r12d,%r12d
  jle    L21
  mov    %r12d,%r12d
  mov    $0x0,%edx
  jmp    L53
L4:
  mov    $0x0,%eax
  jmp    L68
L11:
  lea    (%rax,%rcx,1),%esi
  test   $0x1,%cl
  cmove  %esi,%eax
L39:
  mov    %eax,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r12
  je     L21
L53:
  mov    0x0(%rbp,%rdx,8),%rcx
  mov    (%rcx),%esi
  movslq 0x4(%rcx),%rcx
  lea    (%rbx,%rcx,4),%r8
  mov    (%r8),%edi
  lea    (%rsi,%rdi,1),%ecx
  mov    %ecx,(%r8)
  test   $0x1,%dil
  jne    L11
  mov    %eax,%r8d
  sub    %edi,%r8d
  add    %eax,%esi
  test   $0x1,%cl
  mov    %r8d,%eax
  cmove  %esi,%eax
  jmp    L39
L21:
  mov    %r9,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *sumEvenAfterQueries(int *A, int ASize, int **queries, int queriesSize, int *queriesColSize, int *returnSize) {
  *returnSize = queriesSize;
  *queriesColSize = 2;
  int *answer = malloc(sizeof(int) * queriesSize);
  int sum = 0;
  for (int i = 0; i < ASize; i++) {
    if (A[i] % 2 == 0) {
      sum += A[i];
    }
  }
  int j, k, l;
  for (int i = 0; i < queriesSize; i++) {
    j = queries[i][1];
    k = queries[i][0];
    l = A[j];
    A[j] += k;
    if (l % 2 == 0) {
      if (A[j] % 2 != 0) {
        sum -= l;
      } else {
        sum += k;
      }
    } else {
      if (A[j] % 2 == 0) {
        sum += A[j];
      }
    }
    answer[i] = sum;
  }
  return answer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sumEvenAfterQueries>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rcx,4),%edi
  sub    $0x8,%rsp
  mov    %ecx,(%r9)
  movl   $0x2,(%r8)
  call   <malloc@plt>
  mov    %rax,%r9
  test   %r13d,%r13d
  jle    L26
  lea    -0x1(%r13),%eax
  mov    %rbx,%rdx
  lea    0x4(%rbx,%rax,4),%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L76:
  mov    (%rdx),%ecx
  lea    (%rax,%rcx,1),%esi
  and    $0x1,%ecx
  cmove  %esi,%eax
  add    $0x4,%rdx
  cmp    %rdx,%rdi
  jne    L76
L75:
  movslq %r12d,%r10
  xor    %edx,%edx
  test   %r12d,%r12d
  jg     L48
  jmp    L10
L16:
  mov    %eax,%ecx
  add    %eax,%esi
  sub    %edi,%ecx
  test   %r8d,%r8d
  mov    %ecx,%eax
  cmove  %esi,%eax
  mov    %eax,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r10
  je     L10
L48:
  mov    0x0(%rbp,%rdx,8),%rcx
  mov    (%rcx),%esi
  movslq 0x4(%rcx),%rcx
  lea    (%rbx,%rcx,4),%r8
  mov    (%r8),%edi
  lea    (%rsi,%rdi,1),%ecx
  mov    %ecx,(%r8)
  mov    %ecx,%r8d
  and    $0x1,%r8d
  test   $0x1,%dil
  je     L16
  add    %eax,%ecx
  test   %r8d,%r8d
  cmove  %ecx,%eax
  mov    %eax,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r10
  jne    L48
L10:
  add    $0x8,%rsp
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  jmp    L75
```

assistant: ```c
int *sumEvenAfterQueries(int *A, int ASize, int **queries, int queriesSize, int *queriesColSize, int *returnSize) {
  *returnSize = queriesSize;
  *queriesColSize = 2;
  int *answer = malloc(sizeof(int) * queriesSize);
  int sum = 0;
  for (int i = 0; i < ASize; i++) {
    if (A[i] % 2 == 0) {
      sum += A[i];
    }
  }
  int j, k, l;
  for (int i = 0; i < queriesSize; i++) {
    j = queries[i][1];
    k = queries[i][0];
    l = A[j];
    A[j] += k;
    if (l % 2 == 0) {
      if (A[j] % 2 != 0) {
        sum -= l;
      } else {
        sum += k;
      }
    } else {
      if (A[j] % 2 == 0) {
        sum += A[j];
      }
    }
    answer[i] = sum;
  }
  return answer;
}
```
user: What is the c source code of the assembly code below:

```asm
<free_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int free_list(void *ptr, void *data) {
  free(data);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<free_list>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int free_list(void *ptr, void *data) {
  free(data);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_list>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int free_list(void *ptr, void *data) {
  free(data);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<free_list>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int free_list(void *ptr, void *data) {
  free(data);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L23
  mov    $0x0,%eax
  jmp    L19
L23:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L20
L22:
  shll   -0x14(%rbp)
  subl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x0,-0x14(%rbp)
  js     L14
  cmpl   $0x0,-0x4(%rbp)
  jg     L22
L14:
  mov    -0x4(%rbp),%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int fls(int i) {
  int count;
  if (!i)
    return (0);
  for (count = INTBITS; !(i & 0x80000000) && (count > 0); count--)
    i <<= 1;
  return (count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fls>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L29
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  js     L29
  test   %eax,%eax
  jle    L29
L11:
  sub    $0x1,%eax
  add    %edi,%edi
  js     L29
  test   %eax,%eax
  jg     L11
L29:
  ret
```

assistant: ```c
int fls(int i) {
  int count;
  if (!i)
    return (0);
  for (count = INTBITS; !(i & 0x80000000) && (count > 0); count--)
    i <<= 1;
  return (count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L27
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  jns    L31
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%eax
  add    %edi,%edi
  js     L27
L31:
  test   %eax,%eax
  jg     L9
L27:
  ret
```

assistant: ```c
int fls(int i) {
  int count;
  if (!i)
    return (0);
  for (count = INTBITS; !(i & 0x80000000) && (count > 0); count--)
    i <<= 1;
  return (count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L20
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jns    L47
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x1,%eax
  add    %edi,%edi
  js     L20
L47:
  test   %eax,%eax
  jg     L5
L20:
  ret
```

assistant: ```c
int fls(int i) {
  int count;
  if (!i)
    return (0);
  for (count = INTBITS; !(i & 0x80000000) && (count > 0); count--)
    i <<= 1;
  return (count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<move_plane>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%ebx
  mov    %esi,%r15d
  mov    %edx,%r12d
  mov    %r8d,%ebp
  mov    %r9d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  je     L77
  cmp    $0x1,%ecx
  je     L86
L25:
  mov    %ebx,%edi
  call   <vis5d_invalidate_dtx_frames@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L77:
  lea    0x20(%rsp),%r14
  mov    %r14,%rdx
  mov    %r8d,%esi
  call   <vis5d_get_hclip@plt>
  lea    0x34(%rsp),%rdx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <vis5d_get_clip_mode@plt>
  mov    %r13d,%r9d
  mov    %r14,%r8
  mov    %r12d,%ecx
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <move_hclip@plt>
  test   %rax,%rax
  je     L25
  cmpl   $0x0,0x34(%rsp)
  je     L25
  movss  0x20(%rsp),%xmm0
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <vis5d_set_hclip@plt>
  jmp    L25
L86:
  lea    0x30(%rsp),%rax
  lea    0x2c(%rsp),%r14
  lea    0x28(%rsp),%rsi
  lea    0x24(%rsp),%rdx
  mov    %rax,0x8(%rsp)
  mov    %rax,%r9
  mov    %r14,%r8
  mov    %rsi,0x10(%rsp)
  mov    %rsi,%rcx
  mov    %rdx,0x18(%rsp)
  mov    %ebp,%esi
  call   <vis5d_get_vclip@plt>
  lea    0x34(%rsp),%rdx
  lea    0x2(%rbp),%esi
  mov    %ebx,%edi
  call   <vis5d_get_clip_mode@plt>
  sub    $0x8,%rsp
  push   %r13
  push   0x18(%rsp)
  push   %r14
  mov    0x30(%rsp),%r9
  mov    0x38(%rsp),%r8
  mov    %r12d,%ecx
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <move_vclip@plt>
  add    $0x20,%rsp
  test   %rax,%rax
  je     L25
  cmpl   $0x0,0x34(%rsp)
  je     L25
  movss  0x30(%rsp),%xmm3
  movss  0x2c(%rsp),%xmm2
  movss  0x28(%rsp),%xmm1
  movss  0x24(%rsp),%xmm0
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <vis5d_set_vclip@plt>
  jmp    L25
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void move_plane(int index, int curx, int cury, int planetype, int planenum, int corner) {
  float level, r1, c1, r2, c2;
  int current;
  if (planetype == 0) {
    vis5d_get_hclip(index, planenum, &level);
    vis5d_get_clip_mode(index, planenum, &current);
    if (move_hclip(index, planenum, curx, cury, &level, corner) && current) {
      vis5d_set_hclip(index, planenum, level);
    }
  } else if (planetype == 1) {
    vis5d_get_vclip(index, planenum, &r1, &c1, &r2, &c2);
    vis5d_get_clip_mode(index, planenum + 2, &current);
    if (move_vclip(index, planenum, curx, cury, &r1, &c1, &r2, &c2, corner) && current) {
      vis5d_set_vclip(index, planenum, r1, c1, r2, c2);
    }
  }
  vis5d_invalidate_dtx_frames(index);
}
```