ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x30(%rbp)
  movl   $0x41,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0xffffffe1,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x63,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x53,-0x14(%rbp)
  movl   $0x30e,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0xa,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L27
L15:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L27:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  lea    -0x30(%rbp),%rax
  add    %rax,%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <quicksort@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L13
L4:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L13:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: %i 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int v[] = {4, 65, 2, -31, 0, 99, 2, 83, 782, 1};
  int size = sizeof(v) / sizeof(v[0]);
  for (i = 0; i < size; i++) {
    printf("%i ", v[i]);
  }
  printf("\n");
  quicksort(v, v + size - 1);
  for (i = 0; i < size; i++) {
    printf("%i ", v[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x41,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0xffffffe1,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x63,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x53,0x1c(%rsp)
  movl   $0x30e,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
  lea    D0(%rip),%r13
L9:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  lea    0x24(%rsp),%rsi
  call   <quicksort@plt>
  lea    D0(%rip),%rbp
L27:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: %i 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int v[] = {4, 65, 2, -31, 0, 99, 2, 83, 782, 1};
  int size = sizeof(v) / sizeof(v[0]);
  for (i = 0; i < size; i++) {
    printf("%i ", v[i]);
  }
  printf("\n");
  quicksort(v, v + size - 1);
  for (i = 0; i < size; i++) {
    printf("%i ", v[i]);
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x4,%esi
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x4100000004,%rax
  mov    %rsp,%r14
  lea    0x4(%rsp),%rbp
  lea    0x28(%rsp),%r12
  mov    %r14,%rbx
  mov    %rax,(%rsp)
  movabs $0xffffffe100000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x6300000000,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x5300000002,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x10000030e,%rax
  mov    %rax,0x20(%rsp)
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    0x0(%rbp),%esi
  add    $0x4,%rbp
L0:
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x24(%rsp),%rsi
  mov    %r14,%rdi
  call   <quicksort@plt>
  nopl   (%rax)
L32:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L32
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string

tool: D2: %i 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int v[] = {4, 65, 2, -31, 0, 99, 2, 83, 782, 1};
  int size = sizeof(v) / sizeof(v[0]);
  for (i = 0; i < size; i++) {
    printf("%i ", v[i]);
  }
  printf("\n");
  quicksort(v, v + size - 1);
  for (i = 0; i < size; i++) {
    printf("%i ", v[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D32(%rip),%rax
  mov    %rsp,%r14
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D1(%rip),%xmm0
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L5:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x24(%rsp),%rsi
  mov    %r14,%rdi
  call   <quicksort@plt>
  nopl   (%rax)
L11:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D9
type: byte[16]
name: retrieve_data
arguments: tag: D32
type: byte[8]
name: retrieve_data
arguments: tag: D1
type: byte[16]

tool: D0: %i 

tool: {"D9": [0x04,0x00,0x00,0x00,0x41,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0xe1,0xff,0xff,0xff]}

tool: {"D32": [0x0e,0x03,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x63,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x53,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int v[] = {4, 65, 2, -31, 0, 99, 2, 83, 782, 1};
  int size = sizeof(v) / sizeof(v[0]);
  for (i = 0; i < size; i++) {
    printf("%i ", v[i]);
  }
  printf("\n");
  quicksort(v, v + size - 1);
  for (i = 0; i < size; i++) {
    printf("%i ", v[i]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<otherLinesInBox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L16
  cmp    $0x1,%eax
  je     L8
  jmp    L42
L16:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L5
L8:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L5
L42:
  mov    -0x4(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L5:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int otherLinesInBox(const int line, int *line1, int *line2) {
  switch (line % 3) {
  case 0:
    *line1 = line + 1;
    *line2 = line + 2;
    break;
  case 1:
    *line1 = line - 1;
    *line2 = line + 1;
    break;
  default:
    *line1 = line - 2;
    *line2 = line - 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<otherLinesInBox>:
  endbr64
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edi,%eax
  sub    %ecx,%eax
  je     L23
  cmp    $0x1,%eax
  je     L14
  lea    -0x2(%rdi),%eax
  sub    $0x1,%edi
  jmp    L27
L23:
  lea    0x1(%rdi),%eax
  add    $0x2,%edi
L27:
  mov    %eax,(%rsi)
  mov    %edi,(%rdx)
  mov    $0x0,%eax
  ret
L14:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edi
  jmp    L27
```

assistant: ```c
int otherLinesInBox(const int line, int *line1, int *line2) {
  switch (line % 3) {
  case 0:
    *line1 = line + 1;
    *line2 = line + 2;
    break;
  case 1:
    *line1 = line - 1;
    *line2 = line + 1;
    break;
  default:
    *line1 = line - 2;
    *line2 = line - 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<otherLinesInBox>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%ecx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edi,%eax
  sub    %ecx,%eax
  je     L13
  cmp    $0x1,%eax
  je     L15
  lea    -0x2(%rdi),%eax
  sub    $0x1,%edi
  mov    %eax,(%rsi)
  xor    %eax,%eax
  mov    %edi,(%rdx)
  ret
  nopl   0x0(%rax)
L13:
  lea    0x1(%rdi),%eax
  add    $0x2,%edi
  mov    %eax,(%rsi)
  xor    %eax,%eax
  mov    %edi,(%rdx)
  ret
  nopl   (%rax)
L15:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edi
  mov    %eax,(%rsi)
  xor    %eax,%eax
  mov    %edi,(%rdx)
  ret
```

assistant: ```c
int otherLinesInBox(const int line, int *line1, int *line2) {
  switch (line % 3) {
  case 0:
    *line1 = line + 1;
    *line2 = line + 2;
    break;
  case 1:
    *line1 = line - 1;
    *line2 = line + 1;
    break;
  default:
    *line1 = line - 2;
    *line2 = line - 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<otherLinesInBox>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%ecx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edi,%eax
  sub    %ecx,%eax
  je     L5
  cmp    $0x1,%eax
  je     L18
  lea    -0x2(%rdi),%eax
  sub    $0x1,%edi
  mov    %eax,(%rsi)
  xor    %eax,%eax
  mov    %edi,(%rdx)
  ret
  nopl   0x0(%rax)
L5:
  lea    0x1(%rdi),%eax
  add    $0x2,%edi
  mov    %eax,(%rsi)
  xor    %eax,%eax
  mov    %edi,(%rdx)
  ret
  nopl   (%rax)
L18:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edi
  mov    %eax,(%rsi)
  xor    %eax,%eax
  mov    %edi,(%rdx)
  ret
```

assistant: ```c
int otherLinesInBox(const int line, int *line1, int *line2) {
  switch (line % 3) {
  case 0:
    *line1 = line + 1;
    *line2 = line + 2;
    break;
  case 1:
    *line1 = line - 1;
    *line2 = line + 1;
    break;
  default:
    *line1 = line - 2;
    *line2 = line - 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L61
  mov    $0x0,%eax
  call   <error_memory@plt>
L61:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L23
  movl   $0x0,-0x14(%rbp)
  jmp    L97
L23:
  movl   $0x1,-0x14(%rbp)
L97:
  cmpl   $0x0,-0x14(%rbp)
  jne    L57
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L79
L52:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L71
L79:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  jmp    L118
L71:
  nop
L118:
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L83
L57:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L40:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L103
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L103
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L103
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  movzbl 0x1(%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x28(%rbp)
  jmp    L8
L103:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L102
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L8:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  jmp    L62
L102:
  nop
L62:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L83:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_string(char *str) {
  char *tmpstr;
  char *retstr;
  int c;
  if (!(tmpstr = malloc(strlen(str))))
    error_memory();
  if (*str != '"')
    c = 0;
  else
    c = 1;
  if (!c) {
    retstr = str;
    free(tmpstr);
    while (*str++ != '\0') {
      if (isspace(*str)) {
        break;
      }
    }
    *str = '\0';
  } else {
    retstr = tmpstr;
    while (*str++ != '\0') {
      if (*str == '\\' && *(str + 1) && *(str + 1) == '"') {
        *tmpstr++ = *(str + 1);
        str++;
      } else if (*str == '"')
        break;
      else
        *tmpstr++ = *str;
    }
    *tmpstr = '\0';
  }
  return retstr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
L110:
  cmpb   $0x22,(%rbx)
  jne    L115
  lea    0x1(%rbx),%rsi
  lea    0x1(%rbp),%rax
  jmp    L107
L28:
  mov    $0x0,%eax
  call   <error_memory@plt>
  jmp    L110
L115:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rbp
L45:
  add    $0x1,%rbp
  cmpb   $0x0,-0x1(%rbp)
  je     L83
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L45
L83:
  movb   $0x0,0x0(%rbp)
  mov    %rbx,%rbp
  jmp    L103
L84:
  movzbl 0x2(%rbx),%edi
  cmp    $0x22,%dil
  je     L48
L17:
  mov    %rax,%rcx
  mov    %rsi,%rbx
L33:
  mov    %dl,-0x1(%rax)
  lea    0x1(%rbx),%rsi
  add    $0x1,%rax
  cmpb   $0x0,(%rbx)
  je     L100
L107:
  lea    -0x1(%rax),%rcx
  movzbl 0x1(%rbx),%edx
  cmp    $0x5c,%dl
  je     L84
  cmp    $0x22,%dl
  jne    L17
L100:
  movb   $0x0,(%rcx)
L103:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    %rax,%rcx
  add    $0x2,%rbx
  mov    %edi,%edx
  jmp    L33
```

assistant: ```c
char *get_string(char *str) {
  char *tmpstr;
  char *retstr;
  int c;
  if (!(tmpstr = malloc(strlen(str))))
    error_memory();
  if (*str != '"')
    c = 0;
  else
    c = 1;
  if (!c) {
    retstr = str;
    free(tmpstr);
    while (*str++ != '\0') {
      if (isspace(*str)) {
        break;
      }
    }
    *str = '\0';
  } else {
    retstr = tmpstr;
    while (*str++ != '\0') {
      if (*str == '\\' && *(str + 1) && *(str + 1) == '"') {
        *tmpstr++ = *(str + 1);
        str++;
      } else if (*str == '"')
        break;
      else
        *tmpstr++ = *str;
    }
    *tmpstr = '\0';
  }
  return retstr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L42
L58:
  cmpb   $0x22,(%rbx)
  jne    L77
  lea    0x1(%rbx),%rdi
  lea    0x1(%r12),%rdx
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L11:
  cmp    $0x22,%cl
  je     L117
L98:
  mov    %rdi,%rbx
  mov    %cl,-0x1(%rdx)
  mov    %rdx,%rsi
  add    $0x1,%rdx
  cmpb   $0x0,(%rbx)
  lea    0x1(%rbx),%rdi
  je     L117
L67:
  movzbl 0x1(%rbx),%ecx
  lea    -0x1(%rdx),%rsi
  cmp    $0x5c,%cl
  jne    L11
  cmpb   $0x22,0x2(%rbx)
  jne    L98
  add    $0x2,%rbx
  mov    $0x22,%ecx
  mov    %rdx,%rsi
  add    $0x1,%rdx
  mov    %cl,-0x2(%rdx)
  cmpb   $0x0,(%rbx)
  lea    0x1(%rbx),%rdi
  jne    L67
L117:
  movb   $0x0,(%rsi)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L77:
  mov    %r12,%rdi
  mov    %rbx,%rbp
  call   <free@plt>
  jmp    L115
  nopl   (%rax)
L89:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L101
L115:
  add    $0x1,%rbp
  cmpb   $0x0,-0x1(%rbp)
  jne    L89
L101:
  mov    %rbx,%r12
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  xor    %eax,%eax
  call   <error_memory@plt>
  jmp    L58
```

assistant: ```c
char *get_string(char *str) {
  char *tmpstr;
  char *retstr;
  int c;
  if (!(tmpstr = malloc(strlen(str))))
    error_memory();
  if (*str != '"')
    c = 0;
  else
    c = 1;
  if (!c) {
    retstr = str;
    free(tmpstr);
    while (*str++ != '\0') {
      if (isspace(*str)) {
        break;
      }
    }
    *str = '\0';
  } else {
    retstr = tmpstr;
    while (*str++ != '\0') {
      if (*str == '\\' && *(str + 1) && *(str + 1) == '"') {
        *tmpstr++ = *(str + 1);
        str++;
      } else if (*str == '"')
        break;
      else
        *tmpstr++ = *str;
    }
    *tmpstr = '\0';
  }
  return retstr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L30
L7:
  cmpb   $0x22,(%rbx)
  jne    L94
  lea    0x1(%rbx),%rdi
  lea    0x1(%r12),%rdx
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L118:
  cmp    $0x22,%cl
  je     L36
L65:
  mov    %rdi,%rbx
  mov    %cl,-0x1(%rdx)
  mov    %rdx,%rsi
  add    $0x1,%rdx
  cmpb   $0x0,(%rbx)
  lea    0x1(%rbx),%rdi
  je     L36
L55:
  movzbl 0x1(%rbx),%ecx
  lea    -0x1(%rdx),%rsi
  cmp    $0x5c,%cl
  jne    L118
  cmpb   $0x22,0x2(%rbx)
  jne    L65
  add    $0x2,%rbx
  mov    $0x22,%ecx
  mov    %rdx,%rsi
  add    $0x1,%rdx
  mov    %cl,-0x2(%rdx)
  cmpb   $0x0,(%rbx)
  lea    0x1(%rbx),%rdi
  jne    L55
L36:
  movb   $0x0,(%rsi)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L94:
  mov    %r12,%rdi
  mov    %rbx,%rbp
  call   <free@plt>
  jmp    L50
  nopl   (%rax)
L73:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L62
L50:
  add    $0x1,%rbp
  cmpb   $0x0,-0x1(%rbp)
  jne    L73
L62:
  mov    %rbx,%r12
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  call   <error_memory@plt>
  jmp    L7
```

assistant: ```c
char *get_string(char *str) {
  char *tmpstr;
  char *retstr;
  int c;
  if (!(tmpstr = malloc(strlen(str))))
    error_memory();
  if (*str != '"')
    c = 0;
  else
    c = 1;
  if (!c) {
    retstr = str;
    free(tmpstr);
    while (*str++ != '\0') {
      if (isspace(*str)) {
        break;
      }
    }
    *str = '\0';
  } else {
    retstr = tmpstr;
    while (*str++ != '\0') {
      if (*str == '\\' && *(str + 1) && *(str + 1) == '"') {
        *tmpstr++ = *(str + 1);
        str++;
      } else if (*str == '"')
        break;
      else
        *tmpstr++ = *str;
    }
    *tmpstr = '\0';
  }
  return retstr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floats_quat_xyz_to_xyt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rdx
  mov    -0x60(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <floats_quat_xyz_to_mat44@plt>
  mov    -0x68(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <floats_mat44_to_xyt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void floats_quat_xyz_to_xyt(const float q[4], const float xyz[3], float xyt[3]) {
  float M[16];
  floats_quat_xyz_to_mat44(q, xyz, M);
  floats_mat44_to_xyt(M, xyt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<floats_quat_xyz_to_xyt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <floats_quat_xyz_to_mat44@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <floats_mat44_to_xyt@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_quat_xyz_to_xyt(const float q[4], const float xyz[3], float xyt[3]) {
  float M[16];
  floats_quat_xyz_to_mat44(q, xyz, M);
  floats_mat44_to_xyt(M, xyt);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<floats_quat_xyz_to_xyt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdx
  call   <floats_quat_xyz_to_mat44@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <floats_mat44_to_xyt@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_quat_xyz_to_xyt(const float q[4], const float xyz[3], float xyt[3]) {
  float M[16];
  floats_quat_xyz_to_mat44(q, xyz, M);
  floats_mat44_to_xyt(M, xyt);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<floats_quat_xyz_to_xyt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdx
  call   <floats_quat_xyz_to_mat44@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <floats_mat44_to_xyt@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_quat_xyz_to_xyt(const float q[4], const float xyz[3], float xyt[3]) {
  float M[16];
  floats_quat_xyz_to_mat44(q, xyz, M);
  floats_mat44_to_xyt(M, xyt);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<eg_ctl_filt_table_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  cmpl   $0x17,-0x8(%rbp)
  jbe    L5
  mov    $0xffffffff,%eax
  jmp    L18
L5:
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%r8
  mov    $0x3,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <eg_indirect_table_set@plt>
L18:
  leave
  ret
```

assistant: ```c
int eg_ctl_filt_table_set(unsigned int dev_id, unsigned int index, unsigned int *pentry) {
  if ((index < 0) || (index > 23)) {
    return -1;
  }
  return eg_indirect_table_set(dev_id, 0, index, 3, pentry);
}
```