ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_unlink>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _unlink(const char *n) {
  assert(0);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_unlink>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _unlink(const char *n) {
  assert(0);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_unlink>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _unlink(const char *n) {
  assert(0);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <grep_for_word@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L17
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D1: find word %s


tool: D2: not find word %s


assistant: ```c
int main(int argc, char *argv[]) {
  char *word = argv[1];
  int rval = grep_for_word(word);
  if (rval == 0) {
    printf("find word %s\n", word);
  } else {
    printf("not find word %s\n", word);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rbx
  mov    %rbx,%rdi
  call   <grep_for_word@plt>
  test   %eax,%eax
  jne    L13
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
L15:
  mov    $0x0,%eax
  pop    %rbx
  ret
L13:
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D2: find word %s


tool: D1: not find word %s


assistant: ```c
int main(int argc, char *argv[]) {
  char *word = argv[1];
  int rval = grep_for_word(word);
  if (rval == 0) {
    printf("find word %s\n", word);
  } else {
    printf("not find word %s\n", word);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rdi
  call   <grep_for_word@plt>
  mov    %rbp,%rsi
  test   %eax,%eax
  jne    L15
  lea    D8(%rip),%rdi
  call   <printf@plt>
L0:
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D8: find word %s


tool: D6: not find word %s


assistant: ```c
int main(int argc, char *argv[]) {
  char *word = argv[1];
  int rval = grep_for_word(word);
  if (rval == 0) {
    printf("find word %s\n", word);
  } else {
    printf("not find word %s\n", word);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rdi
  call   <grep_for_word@plt>
  mov    %rbp,%rsi
  test   %eax,%eax
  jne    L15
  lea    D2(%rip),%rdi
  call   <printf@plt>
L18:
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string

tool: D2: find word %s


tool: D11: not find word %s


assistant: ```c
int main(int argc, char *argv[]) {
  char *word = argv[1];
  int rval = grep_for_word(word);
  if (rval == 0) {
    printf("find word %s\n", word);
  } else {
    printf("not find word %s\n", word);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jne    L2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <findtoday@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int days_before = 0;
  if (argc == 2)
    days_before = atoi(argv[1]);
  findtoday(days_before);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    $0x0,%edi
  cmp    $0x2,%eax
  je     L3
L11:
  call   <findtoday@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  jmp    L11
```

assistant: ```c
int main(int argc, char **argv) {
  int days_before = 0;
  if (argc == 2)
    days_before = atoi(argv[1]);
  findtoday(days_before);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  xor    %edi,%edi
  cmp    $0x2,%r8d
  je     L14
L2:
  call   <findtoday@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L14:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  jmp    L2
```

assistant: ```c
int main(int argc, char **argv) {
  int days_before = 0;
  if (argc == 2)
    days_before = atoi(argv[1]);
  findtoday(days_before);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  xor    %edi,%edi
  cmp    $0x2,%r8d
  je     L17
L8:
  call   <findtoday@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L17:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  jmp    L8
```

assistant: ```c
int main(int argc, char **argv) {
  int days_before = 0;
  if (argc == 2)
    days_before = atoi(argv[1]);
  findtoday(days_before);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <substring@plt>
  test   %rax,%rax
  je     L7
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L17
L7:
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string

tool: D5: %s is substring of %s


tool: D18: %s is NOT a substring of %s


assistant: ```c
int main() {
  char s1[100], s2[100];
  gets(s1);
  gets(s2);
  if (substring(s1, s2))
    printf("%s is substring of %s\n", s1, s2);
  else
    printf("%s is NOT a substring of %s\n", s1, s2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    0x70(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <substring@plt>
  test   %rax,%rax
  je     L22
  mov    %rbp,%rdx
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    0x70(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string

tool: D17: %s is substring of %s


tool: D13: %s is NOT a substring of %s


assistant: ```c
int main() {
  char s1[100], s2[100];
  gets(s1);
  gets(s2);
  if (substring(s1, s2))
    printf("%s is substring of %s\n", s1, s2);
  else
    printf("%s is NOT a substring of %s\n", s1, s2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <substring@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  test   %rax,%rax
  je     L1
  lea    D1(%rip),%rdi
  call   <printf@plt>
L16:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D1: %s is substring of %s


tool: D7: %s is NOT a substring of %s


assistant: ```c
int main() {
  char s1[100], s2[100];
  gets(s1);
  gets(s2);
  if (substring(s1, s2))
    printf("%s is substring of %s\n", s1, s2);
  else
    printf("%s is NOT a substring of %s\n", s1, s2);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <substring@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  test   %rax,%rax
  je     L24
  lea    D5(%rip),%rdi
  call   <printf@plt>
L15:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L24:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string

tool: D5: %s is substring of %s


tool: D3: %s is NOT a substring of %s


assistant: ```c
int main() {
  char s1[100], s2[100];
  gets(s1);
  gets(s2);
  if (substring(s1, s2))
    printf("%s is substring of %s\n", s1, s2);
  else
    printf("%s is NOT a substring of %s\n", s1, s2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dotproduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L19
L7:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L7
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dotproduct(double *a, double *b, long long int N) {
  long long int i;
  double dot = 0;
  for (i = 0; i < N; i++)
    dot += a[i] * b[i];
  return dot;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dotproduct>:
  endbr64
  test   %rdx,%rdx
  jle    L2
  pxor   %xmm1,%xmm1
  mov    $0x0,%eax
L1:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L1
L14:
  movapd %xmm1,%xmm0
  ret
L2:
  pxor   %xmm1,%xmm1
  jmp    L14
```

assistant: ```c
double dotproduct(double *a, double *b, long long int N) {
  long long int i;
  double dot = 0;
  for (i = 0; i < N; i++)
    dot += a[i] * b[i];
  return dot;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dotproduct>:
  endbr64
  pxor   %xmm1,%xmm1
  test   %rdx,%rdx
  jle    L1
  xor    %eax,%eax
  nop
L14:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L14
L1:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dotproduct(double *a, double *b, long long int N) {
  long long int i;
  double dot = 0;
  for (i = 0; i < N; i++)
    dot += a[i] * b[i];
  return dot;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dotproduct>:
  endbr64
  test   %rdx,%rdx
  jle    L16
  cmp    $0x1,%rdx
  je     L10
  mov    %rdx,%rcx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %rcx
  shl    $0x4,%rcx
  nop
L12:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L12
  mov    %rdx,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%edx
  je     L27
L39:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L27:
  ret
  nopl   0x0(%rax)
L16:
  pxor   %xmm0,%xmm0
  ret
L10:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L39
```

assistant: ```c
double dotproduct(double *a, double *b, long long int N) {
  long long int i;
  double dot = 0;
  for (i = 0; i < N; i++)
    dot += a[i] * b[i];
  return dot;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<idris_utf8_findOffset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <idris_utf8_charlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
L9:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L7
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int idris_utf8_findOffset(char *str, int i) {
  int offset = 0;
  while (i > 0) {
    int len = idris_utf8_charlen(str);
    str += len;
    offset += len;
    i--;
  }
  return offset;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<idris_utf8_findOffset>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L7
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x0,%r12d
L23:
  mov    %rbp,%rdi
  call   <idris_utf8_charlen@plt>
  movslq %eax,%rdx
  add    %rdx,%rbp
  add    %eax,%r12d
  sub    $0x1,%ebx
  jne    L23
L17:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    $0x0,%r12d
  jmp    L17
```

assistant: ```c
int idris_utf8_findOffset(char *str, int i) {
  int offset = 0;
  while (i > 0) {
    int len = idris_utf8_charlen(str);
    str += len;
    offset += len;
    i--;
  }
  return offset;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<idris_utf8_findOffset>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rbp
  mov    %esi,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L6:
  mov    %rbp,%rdi
  call   <idris_utf8_charlen@plt>
  movslq %eax,%rdx
  add    %eax,%r12d
  add    %rdx,%rbp
  sub    $0x1,%ebx
  jne    L6
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int idris_utf8_findOffset(char *str, int i) {
  int offset = 0;
  while (i > 0) {
    int len = idris_utf8_charlen(str);
    str += len;
    offset += len;
    i--;
  }
  return offset;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<idris_utf8_findOffset>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L15
  mov    %rdi,%rbp
  mov    %esi,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L16:
  mov    %rbp,%rdi
  call   <idris_utf8_charlen@plt>
  movslq %eax,%rdx
  add    %eax,%r12d
  add    %rdx,%rbp
  sub    $0x1,%ebx
  jne    L16
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int idris_utf8_findOffset(char *str, int i) {
  int offset = 0;
  while (i > 0) {
    int len = idris_utf8_charlen(str);
    str += len;
    offset += len;
    i--;
  }
  return offset;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_new_car>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  cmpl   $0x7,-0xc(%rbp)
  jg     L22
  mov    $0x1,%eax
  jmp    L12
L22:
  mov    $0x0,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int is_new_car(void) {
  time_t t;
  int n;
  srand((unsigned)time(&t));
  n = rand() % 10;
  if (n <= 7) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_new_car>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cmp    $0x7,%eax
  setle  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_new_car(void) {
  time_t t;
  int n;
  srand((unsigned)time(&t));
  n = rand() % 10;
  if (n <= 7) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_new_car>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cmp    $0x7,%eax
  setle  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_new_car(void) {
  time_t t;
  int n;
  srand((unsigned)time(&t));
  n = rand() % 10;
  if (n <= 7) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_new_car>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cmp    $0x7,%eax
  setle  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_new_car(void) {
  time_t t;
  int n;
  srand((unsigned)time(&t));
  n = rand() % 10;
  if (n <= 7) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiCircularMean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L16
L14:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L11
L9:
  mov    -0x28(%rbp),%eax
  imul   -0x38(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  imul   -0x38(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x28(%rbp)
L11:
  mov    -0x28(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L9
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x34(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x34(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x48(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movapd %xmm2,%xmm1
  movq   %rax,%xmm0
  call   <atan2@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L30
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
L30:
  addl   $0x1,-0x24(%rbp)
L16:
  mov    -0x24(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L14
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void multiCircularMean(int n, int p, double *data, double *mean) {
  double c, s;
  int i, j;
  for (j = 0; j < p; j++) {
    c = s = 0.0;
    for (i = 0; i < n; i++) {
      c += cos(data[i * p + j]);
      s += sin(data[i * p + j]);
    }
    mean[j] = atan2(s / n, c / n);
    if (mean[j] < 0)
      mean[j] += 2 * M_PI;
  }
}
```