ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<rpsls>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L62
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L62
  lea    D33(%rip),%rax
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  mov    %rsp,%r12
  lea    D24(%rip),%rcx
  movq   %rax,%xmm1
  lea    D40(%rip),%rax
  movq   %rcx,%xmm0
  movq   %rax,%xmm2
  lea    D13(%rip),%rdx
  punpcklqdq %xmm1,%xmm0
  lea    D27(%rip),%rax
  movaps %xmm0,(%rsp)
  movq   %rdx,%xmm0
  mov    %rax,0x20(%rsp)
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L77:
  mov    (%r12,%r14,8),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L88
L74:
  add    $0x1,%r14
  cmp    $0x5,%r14
  jne    L77
L62:
  xor    %eax,%eax
L11:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L88:
  mov    %r14d,%r13d
  xor    %r15d,%r15d
L20:
  cmp    $0x4,%r13d
  lea    -0x5(%r13),%eax
  mov    %rbp,%rdi
  cmovle %r13d,%eax
  cltq
  mov    (%rsp,%rax,8),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L16
  add    $0x1,%r15d
  add    $0x1,%r13d
  cmp    $0x5,%r15d
  jne    L20
  jmp    L74
  nopl   (%rax)
L16:
  test   %r15d,%r15d
  je     L62
  xor    %eax,%eax
  cmp    $0x3,%r15d
  setl   %al
  lea    -0x1(%rax,%rax,1),%eax
  jmp    L11
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D33
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D40
datatype: string
name: read_data
arguments: tag: D13
datatype: string
name: read_data
arguments: tag: D27
datatype: string

tool: D33: scissors

tool: D24: rock

tool: D40: paper

tool: D13: lizard

tool: D27: Spock

assistant: ```c
int rpsls(const char *player1, const char *player2) {
  if (!player1 || !player2)
    return 0;
  const char *cycle[] = {"rock", "scissors", "lizard", "paper", "Spock"};
  int i, j, tmp;
  for (i = 0; i < 5; i++) {
    if (strcmp(player1, cycle[i]) == 0) {
      for (j = 0; j <= 4; j++) {
        tmp = (i + j < 5) ? (i + j) : (i + j - 5);
        if (strcmp(player2, cycle[tmp]) == 0) {
          if (j == 0)
            return 0;
          else if (j <= 2)
            return 1;
          else
            return -1;
        }
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fillintarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L109
L90:
  addq   $0x1,-0x30(%rbp)
L109:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L99
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  je     L99
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7b,%al
  jne    L90
L99:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  je     L75
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7b,%al
  jne    L94
L75:
  addq   $0x1,-0x30(%rbp)
L94:
  movl   $0x0,-0x14(%rbp)
  jmp    L41
L71:
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtod@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x30(%rbp)
  je     L98
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L114
L88:
  addq   $0x1,-0x30(%rbp)
L114:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L88
  addl   $0x1,-0x14(%rbp)
L41:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jge    L12
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  je     L12
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7d,%al
  jne    L71
  jmp    L12
L98:
  nop
L12:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L101
  call   <__stack_chk_fail@plt>
L101:
  leave
  ret
```

assistant: ```c
void fillintarray(int *array, char *start, int maxentries) {
  int i;
  char *end;
  while (*start != '\0' && *start != '[' && *start != '{')
    ++start;
  if (*start == '[' || *start == '{')
    ++start;
  for (i = 0; i < maxentries && *start != ']' && *start != '}'; ++i) {
    array[i] = (int)strtod(start, &end);
    if (start == end)
      return;
    start = end;
    while (isspace(*start))
      ++start;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fillintarray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%eax
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x5b,%cl
  je     L83
  test   %al,%al
  je     L83
L44:
  add    $0x1,%r14
  movzbl (%r14),%eax
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x5b,%cl
  je     L83
  test   %al,%al
  jne    L44
L83:
  and    $0xffffffdf,%eax
  cmp    $0x5b,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%r14
  test   %edx,%edx
  jle    L90
  mov    %rdi,%rbp
  lea    -0x1(%rdx),%eax
  lea    0x4(%rdi,%rax,4),%r13
  mov    %rsp,%r12
  jmp    L104
L15:
  add    $0x1,%rbx
L27:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  add    $0x4,%rbp
  cmp    %rbp,%r13
  je     L90
  mov    %rbx,%r14
L104:
  movzbl (%r14),%eax
  and    $0xffffffdf,%eax
  cmp    $0x5d,%al
  je     L90
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strtod@plt>
  mov    %eax,0x0(%rbp)
  mov    (%rsp),%rbx
  cmp    %r14,%rbx
  jne    L27
L90:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fillintarray(int *array, char *start, int maxentries) {
  int i;
  char *end;
  while (*start != '\0' && *start != '[' && *start != '{')
    ++start;
  if (*start == '[' || *start == '{')
    ++start;
  for (i = 0; i < maxentries && *start != ']' && *start != '}'; ++i) {
    array[i] = (int)strtod(start, &end);
    if (start == end)
      return;
    start = end;
    while (isspace(*start))
      ++start;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fillintarray>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L138
  jmp    L5
  nop
L27:
  movzbl (%r14),%eax
  test   %al,%al
  je     L5
L138:
  cmp    $0x5b,%al
  je     L5
  mov    %r14,%rcx
  add    $0x1,%r14
  cmp    $0x7b,%al
  jne    L27
L123:
  lea    0x1(%rcx),%r14
L58:
  test   %edx,%edx
  jle    L134
  lea    -0x1(%rdx),%eax
  mov    %rdi,%rbp
  mov    %rsp,%r12
  lea    0x4(%rdi,%rax,4),%r13
  movzbl (%r14),%eax
  and    $0xffffffdf,%eax
  cmp    $0x5d,%al
  je     L134
L23:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strtod@plt>
  mov    (%rsp),%rbx
  mov    %eax,0x0(%rbp)
  cmp    %r14,%rbx
  jne    L15
  jmp    L134
  nopl   0x0(%rax)
L86:
  add    $0x1,%rbx
L15:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L86
  add    $0x4,%rbp
  cmp    %rbp,%r13
  je     L134
  mov    %rbx,%r14
  movzbl (%r14),%eax
  and    $0xffffffdf,%eax
  cmp    $0x5d,%al
  jne    L23
L134:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  and    $0xffffffdf,%eax
  cmp    $0x5b,%al
  jne    L58
  mov    %r14,%rcx
  jmp    L123
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fillintarray(int *array, char *start, int maxentries) {
  int i;
  char *end;
  while (*start != '\0' && *start != '[' && *start != '{')
    ++start;
  if (*start == '[' || *start == '{')
    ++start;
  for (i = 0; i < maxentries && *start != ']' && *start != '}'; ++i) {
    array[i] = (int)strtod(start, &end);
    if (start == end)
      return;
    start = end;
    while (isspace(*start))
      ++start;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fillintarray>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L47
  jmp    L5
  nop
L125:
  movzbl (%r14),%eax
  test   %al,%al
  je     L5
L47:
  cmp    $0x5b,%al
  je     L5
  mov    %r14,%rcx
  add    $0x1,%r14
  cmp    $0x7b,%al
  jne    L125
L56:
  lea    0x1(%rcx),%r14
L33:
  test   %edx,%edx
  jle    L111
  lea    -0x1(%rdx),%eax
  mov    %rdi,%rbp
  mov    %rsp,%r12
  lea    0x4(%rdi,%rax,4),%r13
  movzbl (%r14),%eax
  and    $0xffffffdf,%eax
  cmp    $0x5d,%al
  je     L111
L123:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strtod@plt>
  mov    (%rsp),%rbx
  mov    %eax,0x0(%rbp)
  cmp    %r14,%rbx
  jne    L31
  jmp    L111
  nopl   0x0(%rax)
L141:
  add    $0x1,%rbx
L31:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L141
  add    $0x4,%rbp
  cmp    %rbp,%r13
  je     L111
  mov    %rbx,%r14
  movzbl (%r14),%eax
  and    $0xffffffdf,%eax
  cmp    $0x5d,%al
  jne    L123
L111:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  and    $0xffffffdf,%eax
  cmp    $0x5b,%al
  jne    L33
  mov    %r14,%rcx
  jmp    L56
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fillintarray(int *array, char *start, int maxentries) {
  int i;
  char *end;
  while (*start != '\0' && *start != '[' && *start != '{')
    ++start;
  if (*start == '[' || *start == '{')
    ++start;
  for (i = 0; i < maxentries && *start != ']' && *start != '}'; ++i) {
    array[i] = (int)strtod(start, &end);
    if (start == end)
      return;
    start = end;
    while (isspace(*start))
      ++start;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<double_rotation_with_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <single_rotation_with_right@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <single_rotation_with_left@plt>
  leave
  ret
```

assistant: ```c
struct node *double_rotation_with_right(struct node *p_node) {
  p_node = single_rotation_with_right(p_node);
  return single_rotation_with_left(p_node);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<double_rotation_with_right>:
  endbr64
  sub    $0x8,%rsp
  call   <single_rotation_with_right@plt>
  mov    %rax,%rdi
  call   <single_rotation_with_left@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct node *double_rotation_with_right(struct node *p_node) {
  p_node = single_rotation_with_right(p_node);
  return single_rotation_with_left(p_node);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<double_rotation_with_right>:
  endbr64
  sub    $0x8,%rsp
  call   <single_rotation_with_right@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <single_rotation_with_left@plt>
```

assistant: ```c
struct node *double_rotation_with_right(struct node *p_node) {
  p_node = single_rotation_with_right(p_node);
  return single_rotation_with_left(p_node);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<double_rotation_with_right>:
  endbr64
  sub    $0x8,%rsp
  call   <single_rotation_with_right@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <single_rotation_with_left@plt>
```

assistant: ```c
struct node *double_rotation_with_right(struct node *p_node) {
  p_node = single_rotation_with_right(p_node);
  return single_rotation_with_left(p_node);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  jmp    L47
L29:
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x24(%rbp)
L47:
  cmpl   $0x4,-0x24(%rbp)
  jle    L29
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <bubbleSort@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L26
L42:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L26:
  cmpl   $0x4,-0x24(%rbp)
  jle    L42
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: string
name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D10: %d

tool: D9: %d


assistant: ```c
int main() {
  int arr[5], i;
  for (i = 0; i < 5; i++)
    scanf("%d", &arr[i]);
  bubbleSort(arr, 5);
  for (i = 0; i < 5; i++)
    printf("%d\n", arr[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  mov    %rbx,%rbp
  lea    D11(%rip),%r13
L14:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L14
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <bubbleSort@plt>
  lea    D2(%rip),%rbp
L23:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L23
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D11: %d

tool: D2: %d


assistant: ```c
int main() {
  int arr[5], i;
  for (i = 0; i < 5; i++)
    scanf("%d", &arr[i]);
  bubbleSort(arr, 5);
  for (i = 0; i < 5; i++)
    printf("%d\n", arr[i]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x14(%rsp),%r12
  mov    %r14,%rbx
  mov    %r14,%rbp
L19:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L19
  mov    $0x5,%esi
  mov    %r14,%rdi
  lea    D10(%rip),%rbp
  call   <bubbleSort@plt>
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string

tool: D13: %d

tool: D10: %d


assistant: ```c
int main() {
  int arr[5], i;
  for (i = 0; i < 5; i++)
    scanf("%d", &arr[i]);
  bubbleSort(arr, 5);
  for (i = 0; i < 5; i++)
    printf("%d\n", arr[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x14(%rsp),%r12
  mov    %r14,%rbx
  mov    %r14,%rbp
L14:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L14
  mov    $0x5,%esi
  mov    %r14,%rdi
  lea    D19(%rip),%rbp
  call   <bubbleSort@plt>
L22:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L22
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string

tool: D10: %d

tool: D19: %d


assistant: ```c
int main() {
  int arr[5], i;
  for (i = 0; i < 5; i++)
    scanf("%d", &arr[i]);
  bubbleSort(arr, 5);
  for (i = 0; i < 5; i++)
    printf("%d\n", arr[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trm_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L18
L16:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <trm_chr@plt>
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void trm_str(char *str) {
  while (*str)
    trm_chr(*str++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trm_str>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L13:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <trm_chr@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L13
L2:
  pop    %rbx
  ret
```

assistant: ```c
void trm_str(char *str) {
  while (*str)
    trm_chr(*str++);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trm_str>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L19:
  call   <trm_chr@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L19
L14:
  pop    %rbx
  ret
```

assistant: ```c
void trm_str(char *str) {
  while (*str)
    trm_chr(*str++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trm_str>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L4:
  call   <trm_chr@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L4
L14:
  pop    %rbx
  ret
```

assistant: ```c
void trm_str(char *str) {
  while (*str)
    trm_chr(*str++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L2
L7:
  addl   $0x1,-0x4(%rbp)
  sarl   -0x8(%rbp)
L2:
  cmpl   $0x1,-0x8(%rbp)
  jg     L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int log_2(int N) {
  int i;
  int log_N = 0;
  for (i = N; i > 1; i >>= 1) {
    log_N++;
  }
  return log_N;
}
```
user: What is the c source code of the assembly code below:

```asm
<log_2>:
  endbr64
  cmp    $0x1,%edi
  jle    L16
  mov    $0x0,%eax
L4:
  add    $0x1,%eax
  sar    %edi
  cmp    $0x1,%edi
  jg     L4
  ret
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int log_2(int N) {
  int i;
  int log_N = 0;
  for (i = N; i > 1; i >>= 1) {
    log_N++;
  }
  return log_N;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log_2>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L11
  nopl   0x0(%rax,%rax,1)
L4:
  sar    %edi
  add    $0x1,%eax
  cmp    $0x1,%edi
  jne    L4
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
int log_2(int N) {
  int i;
  int log_N = 0;
  for (i = N; i > 1; i >>= 1) {
    log_N++;
  }
  return log_N;
}
```
user: What is the c source code of the assembly code below:

```asm
<log_2>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L18
  nopl   0x0(%rax,%rax,1)
L12:
  sar    %edi
  add    $0x1,%eax
  cmp    $0x1,%edi
  jne    L12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
int log_2(int N) {
  int i;
  int log_N = 0;
  for (i = N; i > 1; i >>= 1) {
    log_N++;
  }
  return log_N;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_depth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L37
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L55
L37:
  cmpl   $0x2,-0x4(%rbp)
  jne    L41
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L55
L41:
  cmpl   $0x3,-0x4(%rbp)
  jne    L26
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L55
L26:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L55:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D22
type_infered: string
name: read_data
arguments: data_label: D31
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string
name: read_data
arguments: data_label: D39
type_infered: string

tool: D22: 
.   .   

tool: D31: 
.   

tool: D28: 
.

tool: D39: 


assistant: ```c
void print_depth(int depth) {
  if (depth == 1) {
    printf("\n.   .   ");
  } else if (depth == 2) {
    printf("\n.   ");
  } else if (depth == 3) {
    printf("\n.");
  } else {
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_depth>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L20
  cmp    $0x2,%edi
  je     L32
  cmp    $0x3,%edi
  je     L17
  lea    D28(%rip),%rdi
  call   <printf@plt>
L14:
  add    $0x8,%rsp
  ret
L20:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L32:
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L17:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string
name: retrieve_data
arguments: label: D35
datatype: string
name: retrieve_data
arguments: label: D33
datatype: string

tool: D28: 


tool: D7: 
.   .   

tool: D35: 
.   

tool: D33: 
.

assistant: ```c
void print_depth(int depth) {
  if (depth == 1) {
    printf("\n.   .   ");
  } else if (depth == 2) {
    printf("\n.   ");
  } else if (depth == 3) {
    printf("\n.");
  } else {
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_depth>:
  endbr64
  cmp    $0x1,%edi
  je     L24
  cmp    $0x2,%edi
  je     L17
  cmp    $0x3,%edi
  je     L16
  lea    D20(%rip),%rdi
  jmp    1050 <printf@plt>
  nop
L16:
  lea    D36(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L24:
  lea    D33(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L17:
  lea    D32(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D36
type: string
name: parse_data
arguments: data_label: D33
type: string
name: parse_data
arguments: data_label: D32
type: string

tool: D20: 


tool: D36: 
.

tool: D33: 
.   .   

tool: D32: 
.   

assistant: ```c
void print_depth(int depth) {
  if (depth == 1) {
    printf("\n.   .   ");
  } else if (depth == 2) {
    printf("\n.   ");
  } else if (depth == 3) {
    printf("\n.");
  } else {
    printf("\n");
  }
}
```