ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    0x10(%rsi),%rsi
  movabs $0xd333333333333334,%rax
  mov    $0x4001,%edx
  push   %rdx
  push   %rax
  lea    D6(%rip),%rdi
  call   <cov_log@plt>
  mov    0x18(%rbx),%rdx
  mov    0x8(%rbx),%rsi
  mov    0x10(%rbx),%rdi
  call   <cov_check@plt>
  movabs $0xd333333333333334,%rax
  mov    $0x4001,%edx
  push   %rdx
  push   %rax
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  push   $0x4000
  push   $0xffffffffcccccccd
  movl   $0x8ccccccc,0x4(%rsp)
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D12
type_guessed: string

tool: D6: result

tool: D12: %1.15Le


assistant: ```c
int main(int argc, char *argv[]) {
  long double a = 2.2L;
  long double b = 2.2L;
  long double c = b + b + a;
  cov_log(c, "result", argv[2]);
  cov_check(argv[2], argv[1], argv[3]);
  printf("%1.15Le\n", c);
  printf("%1.15Le\n", (long double)a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4001,%edx
  movabs $0xd333333333333334,%rax
  lea    D16(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  lea    D17(%rip),%rbp
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rsi
  push   %rdx
  push   %rax
  call   <cov_log@plt>
  mov    0x8(%rbx),%rsi
  mov    0x18(%rbx),%rdx
  mov    0x10(%rbx),%rdi
  call   <cov_check@plt>
  mov    $0x4001,%edx
  mov    %rbp,%rdi
  movabs $0xd333333333333334,%rax
  push   %rdx
  push   %rax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    %rbp,%rdi
  movabs $0x8ccccccccccccccd,%rax
  push   $0x4000
  push   %rax
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string

tool: D16: result

tool: D17: %1.15Le


assistant: ```c
int main(int argc, char *argv[]) {
  long double a = 2.2L;
  long double b = 2.2L;
  long double c = b + b + a;
  cov_log(c, "result", argv[2]);
  cov_check(argv[2], argv[1], argv[3]);
  printf("%1.15Le\n", c);
  printf("%1.15Le\n", (long double)a);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4001,%edx
  movabs $0xd333333333333334,%rax
  lea    D17(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  lea    D12(%rip),%rbp
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rsi
  push   %rdx
  push   %rax
  call   <cov_log@plt>
  mov    0x8(%rbx),%rsi
  mov    0x18(%rbx),%rdx
  mov    0x10(%rbx),%rdi
  call   <cov_check@plt>
  mov    $0x4001,%edx
  mov    %rbp,%rdi
  movabs $0xd333333333333334,%rax
  push   %rdx
  push   %rax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    %rbp,%rdi
  movabs $0x8ccccccccccccccd,%rax
  push   $0x4000
  push   %rax
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D12
datatype: string

tool: D17: result

tool: D12: %1.15Le


assistant: ```c
int main(int argc, char *argv[]) {
  long double a = 2.2L;
  long double b = 2.2L;
  long double c = b + b + a;
  cov_log(c, "result", argv[2]);
  cov_check(argv[2], argv[1], argv[3]);
  printf("%1.15Le\n", c);
  printf("%1.15Le\n", (long double)a);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ccol_strstarts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  leave
  ret
```

assistant: ```c
int ccol_strstarts(const char *s, const char *token) {
  int len = strlen(token);
  return strncmp(s, token, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ccol_strstarts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ccol_strstarts(const char *s, const char *token) {
  int len = strlen(token);
  return strncmp(s, token, len);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ccol_strstarts>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <strncmp@plt>
```

assistant: ```c
int ccol_strstarts(const char *s, const char *token) {
  int len = strlen(token);
  return strncmp(s, token, len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ccol_strstarts>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <strncmp@plt>
```

assistant: ```c
int ccol_strstarts(const char *s, const char *token) {
  int len = strlen(token);
  return strncmp(s, token, len);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x10,%edi
  call   <A@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0x8,%edi
  call   <B@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: 0X%.8X


assistant: ```c
int main(void) {
  unsigned x = A(16);
  printf("0X%.8X\n", x);
  unsigned y = B(8, 8);
  printf("0X%.8X\n", y);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x10,%edi
  call   <A@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0x8,%edi
  call   <B@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: 0X%.8X


assistant: ```c
int main(void) {
  unsigned x = A(16);
  printf("0X%.8X\n", x);
  unsigned y = B(8, 8);
  printf("0X%.8X\n", y);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x10,%edi
  lea    D2(%rip),%rbp
  call   <A@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0x8,%edi
  call   <B@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: 0X%.8X


assistant: ```c
int main(void) {
  unsigned x = A(16);
  printf("0X%.8X\n", x);
  unsigned y = B(8, 8);
  printf("0X%.8X\n", y);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x10,%edi
  lea    D8(%rip),%rbp
  call   <A@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0x8,%edi
  call   <B@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D8: 0X%.8X


assistant: ```c
int main(void) {
  unsigned x = A(16);
  printf("0X%.8X\n", x);
  unsigned y = B(8, 8);
  printf("0X%.8X\n", y);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_map_symbol_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jle    L24
L42:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jle    L24
L47:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L23
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L24
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L24
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  jne    L59
L24:
  mov    $0x1,%eax
  jmp    L81
L59:
  mov    $0x0,%eax
L81:
  pop    %rbp
  ret
```

assistant: ```c
int is_map_symbol_name(char *s) {
  if ((*s >= 'a' && *s <= 'z') || (*s >= 'A' && *s <= 'Z') || (*s >= '0' && *s <= '9') || *s == '.' || *s == '_')
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_map_symbol_name>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  mov    $0x1,%eax
  cmp    $0x19,%dl
  jbe    L5
  sub    $0x2e,%ecx
  cmp    $0x31,%cl
  ja     L17
  movabs $0x2000000000ffd,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L17:
  mov    $0x0,%eax
L5:
  ret
```

assistant: ```c
int is_map_symbol_name(char *s) {
  if ((*s >= 'a' && *s <= 'z') || (*s >= 'A' && *s <= 'Z') || (*s >= '0' && *s <= '9') || *s == '.' || *s == '_')
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_map_symbol_name>:
  endbr64
  movzbl (%rdi),%ecx
  mov    $0x1,%eax
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L1
  sub    $0x2e,%ecx
  cmp    $0x31,%cl
  ja     L3
  movabs $0x2000000000ffd,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
L1:
  ret
```

assistant: ```c
int is_map_symbol_name(char *s) {
  if ((*s >= 'a' && *s <= 'z') || (*s >= 'A' && *s <= 'Z') || (*s >= '0' && *s <= '9') || *s == '.' || *s == '_')
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_map_symbol_name>:
  endbr64
  movzbl (%rdi),%ecx
  mov    $0x1,%eax
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L3
  sub    $0x2e,%ecx
  cmp    $0x31,%cl
  ja     L18
  movabs $0x2000000000ffd,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
L3:
  ret
```

assistant: ```c
int is_map_symbol_name(char *s) {
  if ((*s >= 'a' && *s <= 'z') || (*s >= 'A' && *s <= 'Z') || (*s >= '0' && *s <= '9') || *s == '.' || *s == '_')
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mystrcpy@plt>
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mystrncpy@plt>
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mystrncpy@plt>
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mystrlen@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D31
type_guessed: string
name: read_data
arguments: label: D51
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string

tool: D16: helloworld

tool: D31: strcpy of helloworld %s 


tool: D51: %s 


tool: D15: length of helloworld = %d

assistant: ```c
int main() {
  char *current = "helloworld";
  char destination[12];
  printf("strcpy of helloworld %s \n", mystrcpy(current, destination));
  printf("%s \n", mystrncpy(current, destination, 1));
  printf("%s \n", mystrncpy(current, destination, 0));
  printf("length of helloworld = %d", mystrlen("helloworld"));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  call   <mystrcpy@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <mystrncpy@plt>
  mov    %eax,%esi
  lea    D34(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <mystrncpy@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <mystrlen@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D34
datatype: string
name: unpack_data
arguments: tag: D8
datatype: string

tool: D24: helloworld

tool: D5: strcpy of helloworld %s 


tool: D34: %s 


tool: D8: length of helloworld = %d

assistant: ```c
int main() {
  char *current = "helloworld";
  char destination[12];
  printf("strcpy of helloworld %s \n", mystrcpy(current, destination));
  printf("%s \n", mystrncpy(current, destination, 1));
  printf("%s \n", mystrncpy(current, destination, 0));
  printf("length of helloworld = %d", mystrlen("helloworld"));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  lea    D31(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rsi
  call   <mystrcpy@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mystrncpy@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mystrncpy@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mystrlen@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type: string
name: extract_symbolic_data
arguments: tag: D31
type: string
name: extract_symbolic_data
arguments: tag: D15
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D10: %s 


tool: D31: helloworld

tool: D15: strcpy of helloworld %s 


tool: D2: length of helloworld = %d

assistant: ```c
int main() {
  char *current = "helloworld";
  char destination[12];
  printf("strcpy of helloworld %s \n", mystrcpy(current, destination));
  printf("%s \n", mystrncpy(current, destination, 1));
  printf("%s \n", mystrncpy(current, destination, 0));
  printf("length of helloworld = %d", mystrlen("helloworld"));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rsi
  call   <mystrcpy@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mystrncpy@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mystrncpy@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <mystrlen@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
data_type: string
name: parse_data
arguments: data_label: D5
data_type: string
name: parse_data
arguments: data_label: D29
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string

tool: D17: %s 


tool: D5: helloworld

tool: D29: strcpy of helloworld %s 


tool: D15: length of helloworld = %d

assistant: ```c
int main() {
  char *current = "helloworld";
  char destination[12];
  printf("strcpy of helloworld %s \n", mystrcpy(current, destination));
  printf("%s \n", mystrncpy(current, destination, 1));
  printf("%s \n", mystrncpy(current, destination, 0));
  printf("length of helloworld = %d", mystrlen("helloworld"));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<res_dnok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L34
L42:
  cmpl   $0x20,-0x4(%rbp)
  jle    L37
  cmpl   $0x7e,-0x4(%rbp)
  jle    L34
L37:
  mov    $0x0,%eax
  jmp    L40
L34:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L42
  mov    $0x1,%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int res_dnok(dn) const char *dn;
{
  int ch;
  while ((ch = *dn++) != '\0')
    if (!((ch) > 0x20 && (ch) < 0x7f))
      return (0);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<res_dnok>:
  endbr64
L8:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L6
  movsbl %al,%eax
  sub    $0x21,%eax
  cmp    $0x5d,%eax
  jbe    L8
  mov    $0x0,%eax
  ret
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int res_dnok(dn) const char *dn;
{
  int ch;
  while ((ch = *dn++) != '\0')
    if (!((ch) > 0x20 && (ch) < 0x7f))
      return (0);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<res_dnok>:
  endbr64
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L13:
  sub    $0x21,%eax
  cmp    $0x5d,%eax
  ja     L15
L3:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L13
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int res_dnok(dn) const char *dn;
{
  int ch;
  while ((ch = *dn++) != '\0')
    if (!((ch) > 0x20 && (ch) < 0x7f))
      return (0);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<res_dnok>:
  endbr64
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L6:
  sub    $0x21,%eax
  cmp    $0x5d,%eax
  ja     L1
L17:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L6
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int res_dnok(dn) const char *dn;
{
  int ch;
  while ((ch = *dn++) != '\0')
    if (!((ch) > 0x20 && (ch) < 0x7f))
      return (0);
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_encoding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L28
L11:
  mov    -0x4(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L4
  mov    $0x31,%edx
  jmp    L29
L4:
  mov    $0x30,%edx
L29:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fputc@plt>
  subl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x0,-0x4(%rbp)
  jns    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_encoding(FILE *f, uint8_t *encoding, unsigned size) {
  int i;
  for (i = size - 1; i >= 0; --i) {
    fputc((encoding[i / 8] & (1 << (i % 8))) ? '1' : '0', f);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_encoding>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  sub    $0x1,%edx
  mov    %edx,%ebx
  js     L11
L6:
  lea    0x7(%rbx),%eax
  test   %ebx,%ebx
  cmovns %ebx,%eax
  sar    $0x3,%eax
  cltq
  mov    %ebx,%ecx
  and    $0x7,%ecx
  mov    0x0(%rbp,%rax,4),%edi
  sar    %cl,%edi
  and    $0x1,%edi
  add    $0x30,%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  sub    $0x1,%ebx
  jns    L6
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void print_encoding(FILE *f, uint8_t *encoding, unsigned size) {
  int i;
  for (i = size - 1; i >= 0; --i) {
    fputc((encoding[i / 8] & (1 << (i % 8))) ? '1' : '0', f);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_encoding>:
  endbr64
  sub    $0x1,%edx
  js     L4
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %r12d,%eax
  mov    %r12d,%ecx
  mov    %rbp,%rsi
  sar    $0x3,%eax
  and    $0x7,%ecx
  cltq
  mov    (%rbx,%rax,4),%edi
  sar    %cl,%edi
  and    $0x1,%edi
  add    $0x30,%edi
  call   <fputc@plt>
  sub    $0x1,%r12d
  jae    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void print_encoding(FILE *f, uint8_t *encoding, unsigned size) {
  int i;
  for (i = size - 1; i >= 0; --i) {
    fputc((encoding[i / 8] & (1 << (i % 8))) ? '1' : '0', f);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_encoding>:
  endbr64
  sub    $0x1,%edx
  js     L15
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %r12d,%eax
  mov    %r12d,%ecx
  mov    %rbp,%rsi
  sar    $0x3,%eax
  and    $0x7,%ecx
  cltq
  mov    (%rbx,%rax,4),%edi
  sar    %cl,%edi
  and    $0x1,%edi
  add    $0x30,%edi
  call   <fputc@plt>
  sub    $0x1,%r12d
  jae    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  ret
```

assistant: ```c
void print_encoding(FILE *f, uint8_t *encoding, unsigned size) {
  int i;
  for (i = size - 1; i >= 0; --i) {
    fputc((encoding[i / 8] & (1 << (i % 8))) ? '1' : '0', f);
  }
}
```