ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x25,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  union {
    void *p0;
    struct {
      char c[2];
      int p1;
      int p2;
    } str;
  } data;
  data.p0 = malloc(37U);
  if (__VERIFIER_nondet_int()) {
    data.str.p2 = 20;
  } else {
    data.str.p2 = 30;
  }
  if (20 > data.str.p2) {
    data.str.c[1] = sizeof data.str.p1;
  }
  free(data.p0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x25,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  union {
    void *p0;
    struct {
      char c[2];
      int p1;
      int p2;
    } str;
  } data;
  data.p0 = malloc(37U);
  if (__VERIFIER_nondet_int()) {
    data.str.p2 = 20;
  } else {
    data.str.p2 = 30;
  }
  if (20 > data.str.p2) {
    data.str.c[1] = sizeof data.str.p1;
  }
  free(data.p0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%edi
  call   <messip_sin@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  messip_sin(NULL);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <messip_sin@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  messip_sin(NULL);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <messip_sin@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  messip_sin(NULL);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <messip_sin@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  messip_sin(NULL);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uart0SendChars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %ax,-0xc(%rbp)
  jmp    L4
L12:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart0SendChar@plt>
L4:
  movzwl -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0xc(%rbp)
  test   %ax,%ax
  jne    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart0SendChars(char *pBuff, unsigned short count) {
  while (count--)
    uart0SendChar(*pBuff++);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uart0SendChars>:
  endbr64
  test   %si,%si
  je     L12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  movzwl %ax,%eax
  lea    0x1(%rdi,%rax,1),%rbp
L13:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <uart0SendChar@plt>
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  ret
```

assistant: ```c
void uart0SendChars(char *pBuff, unsigned short count) {
  while (count--)
    uart0SendChar(*pBuff++);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uart0SendChars>:
  endbr64
  test   %si,%si
  je     L3
  push   %rbp
  movzwl %si,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L16:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <uart0SendChar@plt>
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void uart0SendChars(char *pBuff, unsigned short count) {
  while (count--)
    uart0SendChar(*pBuff++);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uart0SendChars>:
  endbr64
  test   %si,%si
  je     L14
  push   %rbp
  movzwl %si,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L15:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <uart0SendChar@plt>
  cmp    %rbx,%rbp
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void uart0SendChars(char *pBuff, unsigned short count) {
  while (count--)
    uart0SendChar(*pBuff++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
time_t time(time_t *tp) {
  time_t seconds;
  time_t milliseconds;
  int rc;
  return seconds;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<time>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
time_t time(time_t *tp) {
  time_t seconds;
  time_t milliseconds;
  int rc;
  return seconds;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<time>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
time_t time(time_t *tp) {
  time_t seconds;
  time_t milliseconds;
  int rc;
  return seconds;
}
```
user: What is the c source code of the assembly code below?

```asm
<time>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
time_t time(time_t *tp) {
  time_t seconds;
  time_t milliseconds;
  int rc;
  return seconds;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_nodelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int set_nodelay(int fd, void *optval, int optlen) {
  errno = EOPNOTSUPP;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_nodelay>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int set_nodelay(int fd, void *optval, int optlen) {
  errno = EOPNOTSUPP;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set_nodelay>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int set_nodelay(int fd, void *optval, int optlen) {
  errno = EOPNOTSUPP;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<set_nodelay>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int set_nodelay(int fd, void *optval, int optlen) {
  errno = EOPNOTSUPP;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trailingZeroes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L5:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x4(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  int res = 0;
  while ((n /= 5) != 0) {
    res += n;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trailingZeroes>:
  endbr64
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sar    $0x1f,%edi
  sub    %edi,%edx
  je     L8
  mov    $0x0,%ecx
L5:
  add    %edx,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  jne    L5
L2:
  mov    %ecx,%eax
  ret
L8:
  mov    %edx,%ecx
  jmp    L2
```

assistant: ```c
int trailingZeroes(int n) {
  int res = 0;
  while ((n /= 5) != 0) {
    res += n;
  }
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<trailingZeroes>:
  endbr64
  movslq %edi,%rdx
  sar    $0x1f,%edi
  xor    %r8d,%r8d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sub    %edi,%edx
  je     L16
  nopl   0x0(%rax)
L14:
  movslq %edx,%rax
  mov    %edx,%ecx
  add    %edx,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  mov    %eax,%edx
  jne    L14
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  int res = 0;
  while ((n /= 5) != 0) {
    res += n;
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trailingZeroes>:
  endbr64
  movslq %edi,%rdx
  sar    $0x1f,%edi
  xor    %r8d,%r8d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sub    %edi,%edx
  je     L5
  nopl   0x0(%rax)
L14:
  movslq %edx,%rax
  mov    %edx,%ecx
  add    %edx,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  mov    %eax,%edx
  jne    L14
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  int res = 0;
  while ((n /= 5) != 0) {
    res += n;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D11(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L1
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L26
L1:
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L26:
  movsd  D6(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  ja     L20
  addl   $0x1,-0x14(%rbp)
  jmp    L11
L20:
  nop
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
datatype: f64
name: unpack_data
arguments: data_label: D6
datatype: byte[8]
name: unpack_data
arguments: data_label: D28
datatype: string

tool: D11: 1

tool: {"D6": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D28: %.6lf


assistant: ```c
int main() {
  int i;
  double sum = 0;
  for (i = 0;; i++) {
    double term = 1.0 / (i * 2 + 1);
    if (i % 2 == 0)
      sum += term;
    else
      sum -= term;
    if (term < 1e-6)
      break;
  }
  printf("%.6lf\n", sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  pxor   %xmm1,%xmm1
  mov    $0x0,%edx
  movsd  D12(%rip),%xmm4
  movsd  D15(%rip),%xmm3
  jmp    L33
L27:
  addsd  %xmm0,%xmm1
L21:
  add    $0x2,%eax
  comisd %xmm0,%xmm3
  ja     L13
  add    $0x1,%edx
L33:
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movapd %xmm4,%xmm0
  divsd  %xmm2,%xmm0
  test   $0x1,%dl
  je     L27
  subsd  %xmm0,%xmm1
  jmp    L21
L13:
  movapd %xmm1,%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
type_infered: f64
name: parse_data
arguments: data_label: D15
type_infered: byte[8]
name: parse_data
arguments: data_label: D8
type_infered: string

tool: D12: 1

tool: {"D15": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D8: %.6lf


assistant: ```c
int main() {
  int i;
  double sum = 0;
  for (i = 0;; i++) {
    double term = 1.0 / (i * 2 + 1);
    if (i % 2 == 0)
      sum += term;
    else
      sum -= term;
    if (term < 1e-6)
      break;
  }
  printf("%.6lf\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  pxor   %xmm1,%xmm1
  xor    %edx,%edx
  movsd  D14(%rip),%xmm4
  movsd  D29(%rip),%xmm3
  jmp    L22
  nopl   (%rax)
L28:
  add    $0x2,%eax
  comisd %xmm0,%xmm3
  addsd  %xmm0,%xmm1
  ja     L36
L7:
  add    $0x1,%edx
L22:
  pxor   %xmm2,%xmm2
  movapd %xmm4,%xmm0
  cvtsi2sd %eax,%xmm2
  divsd  %xmm2,%xmm0
  test   $0x1,%dl
  je     L28
  add    $0x2,%eax
  comisd %xmm0,%xmm3
  subsd  %xmm0,%xmm1
  jbe    L7
L36:
  movapd %xmm1,%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
datatype: f64
name: unpack_data
arguments: tag: D29
datatype: byte[8]
name: unpack_data
arguments: tag: D1
datatype: string

tool: D14: 1

tool: {"D29": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D1: %.6lf


assistant: ```c
int main() {
  int i;
  double sum = 0;
  for (i = 0;; i++) {
    double term = 1.0 / (i * 2 + 1);
    if (i % 2 == 0)
      sum += term;
    else
      sum -= term;
    if (term < 1e-6)
      break;
  }
  printf("%.6lf\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  pxor   %xmm1,%xmm1
  xor    %edx,%edx
  movsd  D5(%rip),%xmm4
  movsd  D6(%rip),%xmm3
  jmp    L1
  nopl   (%rax)
L3:
  add    $0x2,%eax
  comisd %xmm0,%xmm3
  addsd  %xmm0,%xmm1
  ja     L37
L5:
  add    $0x1,%edx
L1:
  pxor   %xmm2,%xmm2
  movapd %xmm4,%xmm0
  cvtsi2sd %eax,%xmm2
  divsd  %xmm2,%xmm0
  test   $0x1,%dl
  je     L3
  add    $0x2,%eax
  comisd %xmm0,%xmm3
  subsd  %xmm0,%xmm1
  jbe    L5
L37:
  movapd %xmm1,%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: f64
name: disassemble_data
arguments: label: D6
type_guessed: byte[8]
name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D5: 1

tool: {"D6": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D1: %.6lf


assistant: ```c
int main() {
  int i;
  double sum = 0;
  for (i = 0;; i++) {
    double term = 1.0 / (i * 2 + 1);
    if (i % 2 == 0)
      sum += term;
    else
      sum -= term;
    if (term < 1e-6)
      break;
  }
  printf("%.6lf\n", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x30(%rbp)
  movl   $0x9,-0x2c(%rbp)
  movl   $0x4,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x8,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x8,-0x40(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x40(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <array_print@plt>
  mov    -0x40(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quick_sort@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x40(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <array_print@plt>
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D36
type: string
name: retrieve_data
arguments: data_tag: D35
type: string
name: retrieve_data
arguments: data_tag: D32
type: string
name: retrieve_data
arguments: data_tag: D10
type: string

tool: D36:  Input

tool: D35: Output

tool: D32: Iteration = %d


tool: D10: Press any key to end...

assistant: ```c
int main(void) {
  int A[] = {2, 9, 4, 7, 1, 5, 8, 3};
  int n = sizeof(A) / sizeof(A[0]);
  int *pA, ncnt;
  pA = A;
  array_print(" Input", pA, n);
  ncnt = quick_sort(A, 0, n - 1);
  array_print("Output", pA, n);
  printf("Iteration = %d\n", ncnt);
  printf("Press any key to end...");
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x8,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  mov    %rsp,%rbp
  mov    $0x8,%edx
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  call   <array_print@plt>
  mov    $0x7,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <quick_sort@plt>
  mov    %eax,%ebx
  mov    $0x8,%edx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <array_print@plt>
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D35
data_type: string
name: extract_symbolic_data
arguments: data_tag: D4
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string
name: extract_symbolic_data
arguments: data_tag: D38
data_type: string

tool: D35:  Input

tool: D4: Output

tool: D1: Iteration = %d


tool: D38: Press any key to end...

assistant: ```c
int main(void) {
  int A[] = {2, 9, 4, 7, 1, 5, 8, 3};
  int n = sizeof(A) / sizeof(A[0]);
  int *pA, ncnt;
  pA = A;
  array_print(" Input", pA, n);
  ncnt = quick_sort(A, 0, n - 1);
  array_print("Output", pA, n);
  printf("Iteration = %d\n", ncnt);
  printf("Press any key to end...");
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x8,%edx
  lea    D21(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x900000002,%rax
  mov    %rsp,%r12
  mov    %r12,%rsi
  mov    %rax,(%rsp)
  movabs $0x700000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x300000008,%rax
  mov    %rax,0x18(%rsp)
  call   <array_print@plt>
  xor    %esi,%esi
  mov    $0x7,%edx
  mov    %r12,%rdi
  call   <quick_sort@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  mov    %eax,%ebp
  call   <array_print@plt>
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D21
datatype: string
name: unpack_data
arguments: label: D6
datatype: string
name: unpack_data
arguments: label: D10
datatype: string
name: unpack_data
arguments: label: D32
datatype: string

tool: D21:  Input

tool: D6: Output

tool: D10: Iteration = %d


tool: D32: Press any key to end...

assistant: ```c
int main(void) {
  int A[] = {2, 9, 4, 7, 1, 5, 8, 3};
  int n = sizeof(A) / sizeof(A[0]);
  int *pA, ncnt;
  pA = A;
  array_print(" Input", pA, n);
  ncnt = quick_sort(A, 0, n - 1);
  array_print("Output", pA, n);
  printf("Iteration = %d\n", ncnt);
  printf("Press any key to end...");
  getchar();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x8,%edx
  lea    D19(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  movdqa D47(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movdqa D43(%rip),%xmm0
  mov    %r12,%rsi
  movaps %xmm0,0x10(%rsp)
  call   <array_print@plt>
  xor    %esi,%esi
  mov    $0x7,%edx
  mov    %r12,%rdi
  call   <quick_sort@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  mov    %eax,%ebp
  call   <array_print@plt>
  mov    %ebp,%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D47
type: byte[16]
name: retrieve_data
arguments: data_tag: D43
type: byte[16]
name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D32
type: string
name: retrieve_data
arguments: data_tag: D55
type: string

tool: D19:  Input

tool: {"D47": [0x02,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D43": [0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D2: Output

tool: D32: Iteration = %d


tool: D55: Press any key to end...

assistant: ```c
int main(void) {
  int A[] = {2, 9, 4, 7, 1, 5, 8, 3};
  int n = sizeof(A) / sizeof(A[0]);
  int *pA, ncnt;
  pA = A;
  array_print(" Input", pA, n);
  ncnt = quick_sort(A, 0, n - 1);
  array_print("Output", pA, n);
  printf("Iteration = %d\n", ncnt);
  printf("Press any key to end...");
  getchar();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x118(%rbp)
  jmp    L59
L86:
  movl   $0x0,-0x114(%rbp)
  jmp    L60
L19:
  mov    -0x118(%rbp),%eax
  imul   -0x114(%rbp),%eax
  mov    -0x114(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x118(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %eax,-0x110(%rbp,%rdx,4)
  addl   $0x1,-0x114(%rbp)
L60:
  cmpl   $0x7,-0x114(%rbp)
  jle    L19
  addl   $0x1,-0x118(%rbp)
L59:
  cmpl   $0x7,-0x118(%rbp)
  jle    L86
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x118(%rbp)
  jmp    L41
L58:
  movl   $0x0,-0x114(%rbp)
  jmp    L8
L18:
  mov    -0x114(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x118(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    -0x110(%rbp,%rax,4),%ecx
  mov    -0x114(%rbp),%edx
  mov    -0x118(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x114(%rbp)
L8:
  cmpl   $0x7,-0x114(%rbp)
  jle    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x118(%rbp)
L41:
  cmpl   $0x7,-0x118(%rbp)
  jle    L58
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
datatype: string
name: disassemble_data
arguments: data_tag: D13
datatype: string

tool: D11: Array Indicies:

tool: D13: [%d][%d]=%d

assistant: ```c
int main() {
  int x;
  int y;
  int array[8][8];
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      array[x][y] = x * y;
    }
  }
  printf("Array Indicies:\n");
  for (x = 0; x < 8; x++) {
    for (y = 0; y < 8; y++) {
      printf("[%d][%d]=%d", x, y, array[x][y]);
    }
    printf("\n");
  }
  getchar();
}
```