ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<str2int>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L7:
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12d
L12:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L7
  mov    %rbx,0x0(%rbp)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str2int(const char *str, const char **p) {
  int r = 0;
  while (isdigit(*str)) {
    r = r * 10 + *str - '0';
    ++str;
  }
  *p = str;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str2int>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L10:
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12d
L0:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L10
  mov    %rbx,0x0(%rbp)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str2int(const char *str, const char **p) {
  int r = 0;
  while (isdigit(*str)) {
    r = r * 10 + *str - '0';
    ++str;
  }
  *p = str;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prf_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <addr_to_bytes@plt>
  lea    -0x50(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <haraka256_sk@plt>
  lea    -0x30(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void prf_addr(unsigned char *out, const unsigned char *key, const uint32_t addr[8]) {
  unsigned char buf[32];
  unsigned char outbuf[32];
  (void)key;
  addr_to_bytes(buf, addr);
  haraka256_sk(outbuf, buf);
  memcpy(out, outbuf, 16);
}
```
user: What is the c source code of the assembly code below:

```asm
<prf_addr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <addr_to_bytes@plt>
  lea    0x20(%rsp),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <haraka256_sk@plt>
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void prf_addr(unsigned char *out, const unsigned char *key, const uint32_t addr[8]) {
  unsigned char buf[32];
  unsigned char outbuf[32];
  (void)key;
  addr_to_bytes(buf, addr);
  haraka256_sk(outbuf, buf);
  memcpy(out, outbuf, 16);
}
```
user: Translate the below assembly code into C programming language:

```asm
<prf_addr>:
  endbr64
  push   %r13
  mov    %rdx,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x20(%rsp),%r12
  mov    %r13,%rdi
  call   <addr_to_bytes@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <haraka256_sk@plt>
  mov    $0x10,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void prf_addr(unsigned char *out, const unsigned char *key, const uint32_t addr[8]) {
  unsigned char buf[32];
  unsigned char outbuf[32];
  (void)key;
  addr_to_bytes(buf, addr);
  haraka256_sk(outbuf, buf);
  memcpy(out, outbuf, 16);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prf_addr>:
  endbr64
  push   %r13
  mov    %rdx,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x20(%rsp),%r12
  mov    %r13,%rdi
  call   <addr_to_bytes@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <haraka256_sk@plt>
  mov    $0x10,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void prf_addr(unsigned char *out, const unsigned char *key, const uint32_t addr[8]) {
  unsigned char buf[32];
  unsigned char outbuf[32];
  (void)key;
  addr_to_bytes(buf, addr);
  haraka256_sk(outbuf, buf);
  memcpy(out, outbuf, 16);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<qqsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L26
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swapj@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swapm@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L4:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L19
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swapj@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swapm@plt>
L19:
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L4
  mov    -0x4(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swapj@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swapm@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <qqsort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <qqsort>
  jmp    L11
L26:
  nop
L11:
  leave
  ret
```

assistant: ```c
void qqsort(int *ja, double *ma, int left, int right) {
  int i, last;
  if (left >= right)
    return;
  swapj(ja, left, (left + right) / 2);
  swapm(ma, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++) {
    if (ja[i] < ja[left]) {
      swapj(ja, ++last, i);
      swapm(ma, last, i);
    }
  }
  swapj(ja, left, last);
  swapm(ma, left, last);
  qqsort(ja, ma, left, last - 1);
  qqsort(ja, ma, last + 1, right);
}
```
user: What is the c source code of the assembly code below:

```asm
<qqsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  cmp    %ecx,%edx
  jl     L12
L21:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %edx,%r14d
  mov    %ecx,%r12d
  lea    (%rdx,%rcx,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,%edx
  mov    %r14d,%esi
  call   <swapj@plt>
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <swapm@plt>
  lea    0x1(%r14),%ebx
  cmp    %ebx,%r12d
  jl     L62
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,4),%r15
  movslq %ebx,%rbx
  mov    %r14d,%r13d
  jmp    L30
L26:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L35
L30:
  mov    %ebx,0x4(%rsp)
  mov    (%r15),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L26
  add    $0x1,%r13d
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swapj@plt>
  mov    0x4(%rsp),%edx
  mov    %r13d,%esi
  mov    0x8(%rsp),%rdi
  call   <swapm@plt>
  jmp    L26
L62:
  mov    %r14d,%r13d
L35:
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swapj@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    0x8(%rsp),%rbx
  mov    %rbx,%rdi
  call   <swapm@plt>
  lea    -0x1(%r13),%ecx
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <qqsort>
  lea    0x1(%r13),%edx
  mov    %r12d,%ecx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <qqsort>
  jmp    L21
```

assistant: ```c
void qqsort(int *ja, double *ma, int left, int right) {
  int i, last;
  if (left >= right)
    return;
  swapj(ja, left, (left + right) / 2);
  swapm(ma, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++) {
    if (ja[i] < ja[left]) {
      swapj(ja, ++last, i);
      swapm(ma, last, i);
    }
  }
  swapj(ja, left, last);
  swapm(ma, left, last);
  qqsort(ja, ma, left, last - 1);
  qqsort(ja, ma, last + 1, right);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<qqsort>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
L36:
  cmp    %r15d,%r14d
  jge    L39
L29:
  lea    (%r15,%r14,1),%eax
  mov    %r14d,%esi
  lea    0x1(%r14),%ebx
  mov    %r12,%rdi
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <swapj@plt>
  mov    0x8(%rsp),%rdi
  mov    %r13d,%edx
  mov    %r14d,%esi
  call   <swapm@plt>
  cmp    %ebx,%r15d
  jl     L33
  movslq %r14d,%rax
  movslq %ebx,%rbx
  mov    %r14d,%ebp
  lea    (%r12,%rax,4),%rcx
  jmp    L32
  nopl   0x0(%rax)
L3:
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jl     L57
L32:
  mov    (%rcx),%eax
  cmp    %eax,(%r12,%rbx,4)
  jge    L3
  add    $0x1,%ebp
  mov    %ebx,%edx
  mov    %r12,%rdi
  mov    %rcx,(%rsp)
  mov    %ebp,%esi
  call   <swapj@plt>
  mov    0x8(%rsp),%rdi
  mov    %ebx,%edx
  mov    %ebp,%esi
  add    $0x1,%rbx
  call   <swapm@plt>
  mov    (%rsp),%rcx
  cmp    %ebx,%r15d
  jge    L32
L57:
  mov    %r14d,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <swapj@plt>
  mov    0x8(%rsp),%rbx
  mov    %r14d,%esi
  mov    %ebp,%edx
  mov    %rbx,%rdi
  call   <swapm@plt>
  mov    %r14d,%edx
  lea    -0x1(%rbp),%ecx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  lea    0x1(%rbp),%r14d
  call   <qqsort>
  cmp    %r15d,%r14d
  jl     L29
L39:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%r15d
  mov    %r12,%rdi
  call   <swapj@plt>
  mov    0x8(%rsp),%rdi
  mov    %r14d,%edx
  mov    %r14d,%esi
  call   <swapm@plt>
  jmp    L36
```

assistant: ```c
void qqsort(int *ja, double *ma, int left, int right) {
  int i, last;
  if (left >= right)
    return;
  swapj(ja, left, (left + right) / 2);
  swapm(ma, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++) {
    if (ja[i] < ja[left]) {
      swapj(ja, ++last, i);
      swapm(ma, last, i);
    }
  }
  swapj(ja, left, last);
  swapm(ma, left, last);
  qqsort(ja, ma, left, last - 1);
  qqsort(ja, ma, last + 1, right);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qqsort>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
L50:
  cmp    %r15d,%r14d
  jge    L63
L44:
  lea    (%r15,%r14,1),%eax
  mov    %r14d,%esi
  lea    0x1(%r14),%ebx
  mov    %r12,%rdi
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <swapj@plt>
  mov    0x8(%rsp),%rdi
  mov    %r13d,%edx
  mov    %r14d,%esi
  call   <swapm@plt>
  cmp    %ebx,%r15d
  jl     L24
  movslq %r14d,%rax
  movslq %ebx,%rbx
  mov    %r14d,%ebp
  lea    (%r12,%rax,4),%rcx
  jmp    L64
  nopl   0x0(%rax)
L22:
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jl     L33
L64:
  mov    (%rcx),%eax
  cmp    %eax,(%r12,%rbx,4)
  jge    L22
  add    $0x1,%ebp
  mov    %ebx,%edx
  mov    %r12,%rdi
  mov    %rcx,(%rsp)
  mov    %ebp,%esi
  call   <swapj@plt>
  mov    0x8(%rsp),%rdi
  mov    %ebx,%edx
  mov    %ebp,%esi
  add    $0x1,%rbx
  call   <swapm@plt>
  mov    (%rsp),%rcx
  cmp    %ebx,%r15d
  jge    L64
L33:
  mov    %r14d,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <swapj@plt>
  mov    0x8(%rsp),%rbx
  mov    %r14d,%esi
  mov    %ebp,%edx
  mov    %rbx,%rdi
  call   <swapm@plt>
  mov    %r14d,%edx
  lea    -0x1(%rbp),%ecx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  lea    0x1(%rbp),%r14d
  call   <qqsort>
  cmp    %r15d,%r14d
  jl     L44
L63:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%r15d
  mov    %r12,%rdi
  call   <swapj@plt>
  mov    0x8(%rsp),%rdi
  mov    %r14d,%edx
  mov    %r14d,%esi
  call   <swapm@plt>
  jmp    L50
```

assistant: ```c
void qqsort(int *ja, double *ma, int left, int right) {
  int i, last;
  if (left >= right)
    return;
  swapj(ja, left, (left + right) / 2);
  swapm(ma, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++) {
    if (ja[i] < ja[left]) {
      swapj(ja, ++last, i);
      swapm(ma, last, i);
    }
  }
  swapj(ja, left, last);
  swapm(ma, left, last);
  qqsort(ja, ma, left, last - 1);
  qqsort(ja, ma, last + 1, right);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<neighbours_stress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %ecx,-0x48(%rbp)
  movsd  %xmm0,-0x50(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L47
L44:
  movl   $0x0,-0x24(%rbp)
  jmp    L3
L7:
  mov    -0x44(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <ed@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x50(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jae    L9
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L34
L9:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x10(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L34:
  addl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x24(%rbp)
L3:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L7
  addl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x28(%rbp)
L47:
  mov    -0x28(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L44
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double neighbours_stress(double *s, double *d_coords, int dim, int elemsn, double rco) {
  double denom = 0.0;
  double numer = 0.0;
  double dab = 0.0;
  double delta = 0.0;
  int k = 0;
  for (int i = 0; i < elemsn; i++) {
    for (int j = 0; j < i; j++) {
      dab = ed(d_coords, i, j, dim);
      if (s[k] <= rco || dab < s[k]) {
        denom += s[k];
        delta = dab - s[k];
        numer += delta * delta / s[k];
      }
      k++;
    }
    k++;
  }
  return (numer / denom);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<neighbours_stress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x28(%rsp)
  movsd  %xmm0,0x10(%rsp)
  test   %ecx,%ecx
  jle    L52
  mov    %rsi,%r15
  mov    %edx,%r14d
  mov    %ecx,%eax
  mov    %rax,0x20(%rsp)
  mov    $0x1,%ebp
  movl   $0x0,0x18(%rsp)
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
  movsd  %xmm5,(%rsp)
  jmp    L90
L21:
  movsd  (%rsp),%xmm2
  addsd  %xmm1,%xmm2
  movsd  %xmm2,(%rsp)
  subsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
L29:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L28
L79:
  mov    %r14d,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <ed@plt>
  movsd  0x8(%r13,%rbx,8),%xmm1
  movsd  0x10(%rsp),%xmm3
  comisd %xmm1,%xmm3
  jae    L21
  comisd %xmm0,%xmm1
  jbe    L29
  jmp    L21
L28:
  mov    0x18(%rsp),%eax
  mov    0x1c(%rsp),%ecx
  lea    0x2(%rax,%rcx,1),%eax
  mov    %eax,0x18(%rsp)
L6:
  add    $0x1,%rbp
L90:
  lea    -0x1(%rbp),%eax
  mov    %eax,0x1c(%rsp)
  mov    0x18(%rsp),%eax
  add    $0x1,%eax
  mov    %ebp,%r12d
  cmp    0x20(%rsp),%rbp
  je     L83
  test   %ebp,%ebp
  jle    L9
  movslq 0x18(%rsp),%rax
  mov    0x28(%rsp),%rdi
  lea    (%rdi,%rax,8),%r13
  mov    $0x0,%ebx
  jmp    L79
L9:
  mov    %eax,0x18(%rsp)
  jmp    L6
L52:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  movsd  %xmm7,(%rsp)
L83:
  movsd  0x8(%rsp),%xmm0
  divsd  (%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double neighbours_stress(double *s, double *d_coords, int dim, int elemsn, double rco) {
  double denom = 0.0;
  double numer = 0.0;
  double dab = 0.0;
  double delta = 0.0;
  int k = 0;
  for (int i = 0; i < elemsn; i++) {
    for (int j = 0; j < i; j++) {
      dab = ed(d_coords, i, j, dim);
      if (s[k] <= rco || dab < s[k]) {
        denom += s[k];
        delta = dab - s[k];
        numer += delta * delta / s[k];
      }
      k++;
    }
    k++;
  }
  return (numer / denom);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<neighbours_stress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x28(%rsp)
  movsd  %xmm0,0x10(%rsp)
  test   %ecx,%ecx
  jle    L33
  movslq %ecx,%rax
  pxor   %xmm5,%xmm5
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    %rax,0x20(%rsp)
  mov    $0x1,%ebx
  movl   $0x0,0x18(%rsp)
  movsd  %xmm5,0x8(%rsp)
  movsd  %xmm5,(%rsp)
  nop
L67:
  lea    -0x1(%rbx),%eax
  mov    %ebx,%ebp
  mov    %eax,0x1c(%rsp)
  mov    0x18(%rsp),%eax
  add    $0x1,%eax
  cmp    0x20(%rsp),%rbx
  je     L7
  test   %ebx,%ebx
  jle    L18
  movslq 0x18(%rsp),%rax
  mov    0x28(%rsp),%rdi
  xor    %r15d,%r15d
  lea    (%rdi,%rax,8),%r12
L50:
  mov    %r14d,%ecx
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <ed@plt>
  movsd  0x8(%r12,%r15,8),%xmm1
  movsd  0x10(%rsp),%xmm3
  comisd %xmm1,%xmm3
  jae    L40
  comisd %xmm0,%xmm1
  jbe    L59
L40:
  subsd  %xmm1,%xmm0
  movsd  (%rsp),%xmm2
  addsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm0
  movsd  %xmm2,(%rsp)
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
L59:
  add    $0x1,%r15
  cmp    %r15,%rbx
  jne    L50
  mov    0x18(%rsp),%eax
  mov    0x1c(%rsp),%ecx
  lea    0x2(%rax,%rcx,1),%eax
L18:
  mov    %eax,0x18(%rsp)
  add    $0x1,%rbx
  jmp    L67
L33:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  movsd  %xmm7,(%rsp)
L7:
  movsd  0x8(%rsp),%xmm0
  divsd  (%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double neighbours_stress(double *s, double *d_coords, int dim, int elemsn, double rco) {
  double denom = 0.0;
  double numer = 0.0;
  double dab = 0.0;
  double delta = 0.0;
  int k = 0;
  for (int i = 0; i < elemsn; i++) {
    for (int j = 0; j < i; j++) {
      dab = ed(d_coords, i, j, dim);
      if (s[k] <= rco || dab < s[k]) {
        denom += s[k];
        delta = dab - s[k];
        numer += delta * delta / s[k];
      }
      k++;
    }
    k++;
  }
  return (numer / denom);
}
```
user: Translate the below assembly code into C programming language:

```asm
<neighbours_stress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x20(%rsp)
  movsd  %xmm0,0x10(%rsp)
  test   %ecx,%ecx
  jle    L18
  cmp    $0x1,%ecx
  je     L18
  movslq %ecx,%rax
  pxor   %xmm5,%xmm5
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    %rax,0x28(%rsp)
  mov    $0x1,%ebx
  movl   $0x1,0x18(%rsp)
  movsd  %xmm5,0x8(%rsp)
  movsd  %xmm5,(%rsp)
  nopl   0x0(%rax,%rax,1)
L54:
  lea    -0x1(%rbx),%eax
  mov    0x20(%rsp),%rdi
  mov    %ebx,%r12d
  xor    %r15d,%r15d
  mov    %eax,0x1c(%rsp)
  movslq 0x18(%rsp),%rax
  lea    (%rdi,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L63:
  mov    %r14d,%ecx
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <ed@plt>
  movsd  0x0(%rbp,%r15,8),%xmm1
  movsd  0x10(%rsp),%xmm3
  comisd %xmm1,%xmm3
  jae    L44
  comisd %xmm0,%xmm1
  jbe    L42
L44:
  subsd  %xmm1,%xmm0
  movsd  (%rsp),%xmm2
  addsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm0
  movsd  %xmm2,(%rsp)
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
L42:
  add    $0x1,%r15
  cmp    %r15,%rbx
  jne    L63
  mov    0x18(%rsp),%eax
  mov    0x1c(%rsp),%esi
  add    $0x1,%rbx
  lea    0x2(%rax,%rsi,1),%eax
  mov    %eax,0x18(%rsp)
  cmp    0x28(%rsp),%rbx
  jne    L54
L29:
  movsd  0x8(%rsp),%xmm0
  divsd  (%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  movsd  %xmm7,(%rsp)
  jmp    L29
```

assistant: ```c
double neighbours_stress(double *s, double *d_coords, int dim, int elemsn, double rco) {
  double denom = 0.0;
  double numer = 0.0;
  double dab = 0.0;
  double delta = 0.0;
  int k = 0;
  for (int i = 0; i < elemsn; i++) {
    for (int j = 0; j < i; j++) {
      dab = ed(d_coords, i, j, dim);
      if (s[k] <= rco || dab < s[k]) {
        denom += s[k];
        delta = dab - s[k];
        numer += delta * delta / s[k];
      }
      k++;
    }
    k++;
  }
  return (numer / denom);
}
```