ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<extract_digits>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x1,%edi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  movsbl (%r15),%edi
  mov    $0x1,%esi
  mov    %rax,%r12
  test   %dil,%dil
  je     L13
  xor    %ebx,%ebx
  mov    $0x1,%r14d
  jmp    L50
  nopl   (%rax)
L41:
  movsbl (%r15,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L4
L48:
  add    $0x1,%rbx
  movsbl (%r15,%rbx,1),%edi
  test   %dil,%dil
  je     L3
L50:
  mov    %r14d,%ebp
  test   %rbx,%rbx
  jne    L41
  call   <isdigit@plt>
  test   %rax,%rax
  je     L48
  movzbl (%r15),%eax
  add    $0x1,%rbx
  add    $0x1,%r14d
  mov    %al,(%r12,%r13,1)
  movsbl (%r15,%rbx,1),%edi
  movslq %ebp,%r13
  test   %dil,%dil
  jne    L50
  nopl   0x0(%rax)
L3:
  mov    %r14d,%esi
L13:
  mov    %r12,%rdi
  call   <realloc@plt>
  movb   $0x0,(%rax,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L4:
  mov    %r14d,%esi
  mov    %r12,%rdi
  add    $0x1,%r14d
  call   <realloc@plt>
  mov    %rax,%r12
  movzbl (%r15,%rbx,1),%eax
  mov    %al,(%r12,%r13,1)
  movslq %ebp,%r13
  jmp    L48
```

assistant: ```c
char *extract_digits(char *str) {
  char *final = NULL;
  int i = 0, n = 0;
  final = (char *)malloc(sizeof(char));
  while (1) {
    if (str[i] == '\0') {
      final = (char *)realloc(final, (sizeof(char) * (n + 1)));
      final[n] = '\0';
      break;
    }
    if ((i == 0) && isdigit(str[i])) {
      final[n] = str[i];
      n++;
    }
    if ((i > 0) && isdigit(str[i])) {
      final = (char *)realloc(final, (sizeof(char) * (n + 1)));
      final[n] = str[i];
      n++;
    }
    i++;
  }
  return final;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rop3_206_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_206_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = *D & stk3;
  stk1 = S | stk2;
  *D = stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_206_0_0>:
  endbr64
  not    %edx
  and    (%rdi),%dl
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_206_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = *D & stk3;
  stk1 = S | stk2;
  *D = stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_206_0_0>:
  endbr64
  not    %edx
  and    (%rdi),%dl
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_206_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = *D & stk3;
  stk1 = S | stk2;
  *D = stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_206_0_0>:
  endbr64
  not    %edx
  and    (%rdi),%dl
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_206_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~T;
  stk2 = *D & stk3;
  stk1 = S | stk2;
  *D = stk1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LastIndexOf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L27
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L50
L8:
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L21:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L55
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L21
  jmp    L18
L55:
  nop
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L45
  mov    -0x10(%rbp),%eax
  jmp    L17
L45:
  subl   $0x1,-0x10(%rbp)
L50:
  cmpl   $0x0,-0x10(%rbp)
  jns    L8
L27:
  mov    $0xffffffff,%eax
L17:
  leave
  ret
```

assistant: ```c
int LastIndexOf(const char *str, const char *findThis) {
  int i, j, strLen, ftLen;
  strLen = (int)strlen(str);
  ftLen = (int)strlen(findThis);
  if (ftLen <= strLen) {
    for (i = strLen - ftLen; i >= 0; i--) {
      for (j = 0; j < ftLen; j++) {
        if (str[i + j] != findThis[j])
          break;
      }
      if (j == ftLen)
        return i;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LastIndexOf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L74
  mov    %rax,%rdx
  mov    %eax,%r9d
  mov    %r12d,%eax
  sub    %edx,%eax
  movslq %eax,%rcx
  lea    (%rbx,%rcx,1),%rdi
  lea    -0x1(%rdx),%r8d
  mov    $0x0,%r10d
  mov    $0x0,%r11d
  jmp    L44
L20:
  mov    %rsi,%rdx
L48:
  mov    %edx,%ecx
  movzbl 0x0(%rbp,%rdx,1),%ebx
  cmp    %bl,(%rdi,%rdx,1)
  jne    L73
  lea    0x1(%rdx),%ecx
  lea    0x1(%rdx),%rsi
  cmp    %r8,%rdx
  jne    L20
L73:
  cmp    %ecx,%r9d
  je     L67
  sub    $0x1,%eax
  sub    $0x1,%rdi
  cmp    $0xffffffff,%eax
  je     L67
L44:
  mov    %r10,%rdx
  mov    %r11d,%ecx
  test   %r9d,%r9d
  jg     L48
  jmp    L73
L74:
  mov    $0xffffffff,%eax
L67:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int LastIndexOf(const char *str, const char *findThis) {
  int i, j, strLen, ftLen;
  strLen = (int)strlen(str);
  ftLen = (int)strlen(findThis);
  if (ftLen <= strLen) {
    for (i = strLen - ftLen; i >= 0; i--) {
      for (j = 0; j < ftLen; j++) {
        if (str[i + j] != findThis[j])
          break;
      }
      if (j == ftLen)
        return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<LastIndexOf>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L66
  mov    %rax,%rdx
  mov    %eax,%r8d
  mov    %r12d,%eax
  sub    %edx,%eax
  lea    -0x1(%rdx),%edi
  movslq %eax,%rcx
  add    $0x2,%rdi
  add    %rbx,%rcx
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%edx
  xor    %esi,%esi
  test   %r8d,%r8d
  jg     L17
  jmp    L13
  xchg   %ax,%ax
L21:
  mov    %edx,%esi
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L13
L17:
  movzbl -0x1(%rbp,%rdx,1),%ebx
  cmp    %bl,-0x1(%rdx,%rcx,1)
  je     L21
  sub    $0x1,%eax
  sub    $0x1,%rcx
  cmp    $0xffffffff,%eax
  jne    L22
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  cmp    %esi,%r8d
  je     L29
  sub    $0x1,%eax
  sub    $0x1,%rcx
  cmp    $0xffffffff,%eax
  jne    L22
  jmp    L29
L66:
  mov    $0xffffffff,%eax
  jmp    L29
```

assistant: ```c
int LastIndexOf(const char *str, const char *findThis) {
  int i, j, strLen, ftLen;
  strLen = (int)strlen(str);
  ftLen = (int)strlen(findThis);
  if (ftLen <= strLen) {
    for (i = strLen - ftLen; i >= 0; i--) {
      for (j = 0; j < ftLen; j++) {
        if (str[i + j] != findThis[j])
          break;
      }
      if (j == ftLen)
        return i;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<LastIndexOf>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L96
  mov    %rax,%rdx
  mov    %eax,%r8d
  mov    %r12d,%eax
  sub    %edx,%eax
  lea    -0x1(%rdx),%edi
  movslq %eax,%rcx
  add    $0x2,%rdi
  add    %rbx,%rcx
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0x1,%edx
  xor    %esi,%esi
  test   %r8d,%r8d
  jg     L32
  jmp    L50
  xchg   %ax,%ax
L36:
  mov    %edx,%esi
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  je     L50
L32:
  movzbl -0x1(%rbp,%rdx,1),%ebx
  cmp    %bl,-0x1(%rcx,%rdx,1)
  je     L36
  sub    $0x1,%eax
  sub    $0x1,%rcx
  cmp    $0xffffffff,%eax
  jne    L43
L83:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  cmp    %esi,%r8d
  je     L83
  sub    $0x1,%eax
  sub    $0x1,%rcx
  cmp    $0xffffffff,%eax
  jne    L43
  jmp    L83
L96:
  mov    $0xffffffff,%eax
  jmp    L83
```

assistant: ```c
int LastIndexOf(const char *str, const char *findThis) {
  int i, j, strLen, ftLen;
  strLen = (int)strlen(str);
  ftLen = (int)strlen(findThis);
  if (ftLen <= strLen) {
    for (i = strLen - ftLen; i >= 0; i--) {
      for (j = 0; j < ftLen; j++) {
        if (str[i + j] != findThis[j])
          break;
      }
      if (j == ftLen)
        return i;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cro_MinMaxBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x34(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  mov    -0x28(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x34(%rbp),%eax
  mov    -0x2c(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  mov    -0x30(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L15
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L17
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L7
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L19
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  cmovl  %eax,%edx
  mov    0x10(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cro_MinMaxBits(int n1, int n2, int n3, int n4, int bitShifts, int *min, int *max) {
  int byte1 = (n1 >> bitShifts) & 0xff;
  int byte2 = (n2 >> bitShifts) & 0xff;
  int byte3 = (n3 >> bitShifts) & 0xff;
  int byte4 = (n4 >> bitShifts) & 0xff;
  int max1, max2, min1, min2;
  if (byte1 > byte2) {
    max1 = byte1;
    min1 = byte2;
  } else {
    max1 = byte2;
    min1 = byte1;
  }
  if (byte3 > byte4) {
    max2 = byte3;
    min2 = byte4;
  } else {
    max2 = byte4;
    min2 = byte3;
  }
  *min = ((min1) < (min2) ? (min1) : (min2));
  *max = ((max1) > (max2) ? (max1) : (max2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cro_MinMaxBits>:
  endbr64
  mov    %ecx,%eax
  mov    %r8d,%ecx
  sar    %cl,%edi
  movzbl %dil,%edi
  sar    %cl,%esi
  movzbl %sil,%esi
  sar    %cl,%edx
  movzbl %dl,%edx
  sar    %cl,%eax
  movzbl %al,%eax
  cmp    %esi,%edi
  jg     L9
  mov    %edi,%ecx
  mov    %esi,%edi
  mov    %ecx,%esi
L9:
  cmp    %eax,%edx
  jg     L12
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    %ecx,%eax
L12:
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    %esi,(%r9)
  cmp    %edx,%edi
  cmovl  %edx,%edi
  mov    0x8(%rsp),%rax
  mov    %edi,(%rax)
  ret
```

assistant: ```c
void cro_MinMaxBits(int n1, int n2, int n3, int n4, int bitShifts, int *min, int *max) {
  int byte1 = (n1 >> bitShifts) & 0xff;
  int byte2 = (n2 >> bitShifts) & 0xff;
  int byte3 = (n3 >> bitShifts) & 0xff;
  int byte4 = (n4 >> bitShifts) & 0xff;
  int max1, max2, min1, min2;
  if (byte1 > byte2) {
    max1 = byte1;
    min1 = byte2;
  } else {
    max1 = byte2;
    min1 = byte1;
  }
  if (byte3 > byte4) {
    max2 = byte3;
    min2 = byte4;
  } else {
    max2 = byte4;
    min2 = byte3;
  }
  *min = ((min1) < (min2) ? (min1) : (min2));
  *max = ((max1) > (max2) ? (max1) : (max2));
}
```
user: What is the c source code of the assembly code below:

```asm
<cro_MinMaxBits>:
  endbr64
  mov    %ecx,%eax
  mov    %r8d,%ecx
  sar    %cl,%edi
  sar    %cl,%esi
  sar    %cl,%edx
  sar    %cl,%eax
  movzbl %dil,%edi
  movzbl %sil,%esi
  movzbl %dl,%edx
  movzbl %al,%eax
  cmp    %esi,%edi
  jg     L2
  mov    %edi,%ecx
  mov    %esi,%edi
  mov    %ecx,%esi
L2:
  cmp    %eax,%edx
  jg     L12
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    %ecx,%eax
L12:
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    %edx,%edi
  mov    0x8(%rsp),%rax
  cmovl  %edx,%edi
  mov    %esi,(%r9)
  mov    %edi,(%rax)
  ret
```

assistant: ```c
void cro_MinMaxBits(int n1, int n2, int n3, int n4, int bitShifts, int *min, int *max) {
  int byte1 = (n1 >> bitShifts) & 0xff;
  int byte2 = (n2 >> bitShifts) & 0xff;
  int byte3 = (n3 >> bitShifts) & 0xff;
  int byte4 = (n4 >> bitShifts) & 0xff;
  int max1, max2, min1, min2;
  if (byte1 > byte2) {
    max1 = byte1;
    min1 = byte2;
  } else {
    max1 = byte2;
    min1 = byte1;
  }
  if (byte3 > byte4) {
    max2 = byte3;
    min2 = byte4;
  } else {
    max2 = byte4;
    min2 = byte3;
  }
  *min = ((min1) < (min2) ? (min1) : (min2));
  *max = ((max1) > (max2) ? (max1) : (max2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cro_MinMaxBits>:
  endbr64
  mov    %ecx,%eax
  mov    %r8d,%ecx
  sar    %cl,%edi
  sar    %cl,%esi
  sar    %cl,%edx
  sar    %cl,%eax
  movzbl %dil,%edi
  movzbl %sil,%esi
  movzbl %dl,%edx
  movzbl %al,%eax
  cmp    %esi,%edi
  jg     L16
  mov    %edi,%ecx
  mov    %esi,%edi
  mov    %ecx,%esi
L16:
  cmp    %eax,%edx
  jg     L12
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    %ecx,%eax
L12:
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    %edx,%edi
  mov    0x8(%rsp),%rax
  cmovl  %edx,%edi
  mov    %esi,(%r9)
  mov    %edi,(%rax)
  ret
```

assistant: ```c
void cro_MinMaxBits(int n1, int n2, int n3, int n4, int bitShifts, int *min, int *max) {
  int byte1 = (n1 >> bitShifts) & 0xff;
  int byte2 = (n2 >> bitShifts) & 0xff;
  int byte3 = (n3 >> bitShifts) & 0xff;
  int byte4 = (n4 >> bitShifts) & 0xff;
  int max1, max2, min1, min2;
  if (byte1 > byte2) {
    max1 = byte1;
    min1 = byte2;
  } else {
    max1 = byte2;
    min1 = byte1;
  }
  if (byte3 > byte4) {
    max2 = byte3;
    min2 = byte4;
  } else {
    max2 = byte4;
    min2 = byte3;
  }
  *min = ((min1) < (min2) ? (min1) : (min2));
  *max = ((max1) > (max2) ? (max1) : (max2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<createbtree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  movl   $0x2,-0x4(%rbp)
  jmp    L25
L6:
  movl   $0x1,-0x8(%rbp)
  jmp    L55
L31:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L33
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L55
L33:
  shll   -0x8(%rbp)
L55:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L31
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void createbtree(int *btree, int *data, int len) {
  int level;
  int i;
  btree[1] = data[1];
  for (i = 2; i <= len; i++) {
    level = 1;
    while (btree[level] != 0) {
      if (data[i] > btree[level]) {
        level = level * 2 + 1;
      } else {
        level = level * 2;
      }
    }
    btree[level] = data[i];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<createbtree>:
  endbr64
  mov    0x4(%rsi),%eax
  mov    %eax,0x4(%rdi)
  cmp    $0x1,%edx
  jle    L21
  lea    0x8(%rsi),%r8
  lea    -0x2(%rdx),%eax
  lea    0xc(%rsi,%rax,4),%r9
  lea    0x4(%rdi),%r11
  mov    $0x1,%r10d
  jmp    L9
L24:
  mov    (%r8),%esi
  mov    %r10d,%eax
L12:
  lea    0x1(%rax,%rax,1),%ecx
  add    %eax,%eax
  cmp    %edx,%esi
  cmovg  %ecx,%eax
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    (%rcx),%edx
  test   %edx,%edx
  jne    L12
L26:
  mov    (%r8),%eax
  mov    %eax,(%rcx)
  add    $0x4,%r8
  cmp    %r9,%r8
  je     L21
L9:
  mov    0x4(%rdi),%edx
  mov    %r11,%rcx
  test   %edx,%edx
  jne    L24
  jmp    L26
L21:
  ret
```

assistant: ```c
void createbtree(int *btree, int *data, int len) {
  int level;
  int i;
  btree[1] = data[1];
  for (i = 2; i <= len; i++) {
    level = 1;
    while (btree[level] != 0) {
      if (data[i] > btree[level]) {
        level = level * 2 + 1;
      } else {
        level = level * 2;
      }
    }
    btree[level] = data[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<createbtree>:
  endbr64
  mov    0x4(%rsi),%eax
  mov    %eax,0x4(%rdi)
  cmp    $0x1,%edx
  jle    L41
  sub    $0x2,%edx
  lea    0x4(%rdi),%r10
  lea    0x8(%rsi),%r8
  lea    0xc(%rsi,%rdx,4),%r9
  nop
L38:
  mov    (%r8),%esi
  mov    $0x1,%edx
  mov    %r10,%rcx
  test   %eax,%eax
  je     L34
  nop
L12:
  cmp    %esi,%eax
  setl   %al
  movzbl %al,%eax
  lea    (%rax,%rdx,2),%edx
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rcx
  mov    (%rcx),%eax
  test   %eax,%eax
  jne    L12
L34:
  add    $0x4,%r8
  mov    %esi,(%rcx)
  cmp    %r8,%r9
  je     L41
  mov    0x4(%rdi),%eax
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L41:
  ret
```

assistant: ```c
void createbtree(int *btree, int *data, int len) {
  int level;
  int i;
  btree[1] = data[1];
  for (i = 2; i <= len; i++) {
    level = 1;
    while (btree[level] != 0) {
      if (data[i] > btree[level]) {
        level = level * 2 + 1;
      } else {
        level = level * 2;
      }
    }
    btree[level] = data[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<createbtree>:
  endbr64
  mov    0x4(%rsi),%eax
  mov    %eax,0x4(%rdi)
  cmp    $0x1,%edx
  jle    L42
  sub    $0x2,%edx
  lea    0x4(%rdi),%r10
  lea    0x8(%rsi),%r8
  lea    0xc(%rsi,%rdx,4),%r9
  nop
L28:
  mov    (%r8),%esi
  mov    $0x1,%edx
  mov    %r10,%rcx
  test   %eax,%eax
  je     L29
  nop
L18:
  cmp    %esi,%eax
  setl   %al
  movzbl %al,%eax
  lea    (%rax,%rdx,2),%edx
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rcx
  mov    (%rcx),%eax
  test   %eax,%eax
  jne    L18
L29:
  add    $0x4,%r8
  mov    %esi,(%rcx)
  cmp    %r8,%r9
  je     L42
  mov    0x4(%rdi),%eax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L42:
  ret
```

assistant: ```c
void createbtree(int *btree, int *data, int len) {
  int level;
  int i;
  btree[1] = data[1];
  for (i = 2; i <= len; i++) {
    level = 1;
    while (btree[level] != 0) {
      if (data[i] > btree[level]) {
        level = level * 2 + 1;
      } else {
        level = level * 2;
      }
    }
    btree[level] = data[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r12
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edx,%rbx
  lea    0xf(%rbx),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L48:
  cmp    %rdx,%rsp
  je     L50
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L48
L50:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L36
  orq    $0x0,-0x8(%rsp,%rax,1)
L36:
  mov    %rsp,%r15
  lea    -0x1(%rcx),%r13d
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,-0x54(%rbp)
  cmp    $0x1,%ecx
  jle    L24
  movslq %r13d,%r13
  imul   %rbx,%r13
  add    %r12,%r13
  mov    $0x0,%r14d
  lea    0xf(%rbx),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  mov    %rcx,-0x50(%rbp)
  and    $0xfffffffffffff000,%rax
  mov    %rax,-0x48(%rbp)
  jmp    L52
L38:
  mov    -0x50(%rbp),%rcx
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L93
  mov    %rcx,%rax
  and    $0xfff,%eax
  orq    $0x0,-0x8(%rsp,%rax,1)
L93:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdx
  mov    %rsp,%rdi
  call   <memcpy@plt>
  add    $0x1,%r14d
  sub    %rbx,%r13
  add    %rbx,%r12
  cmp    -0x54(%rbp),%r14d
  jge    L24
L52:
  mov    %rsp,%rax
  sub    -0x48(%rbp),%rax
L5:
  cmp    %rax,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L5
L24:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void reverse(void *x, int y, int z) {
  struct {
    char w[z];
  } *p = x, a;
  int i, j;
  for (i = y - 1, j = 0; j < y / 2; i--, j++)
    ({
      a = p[i];
      p[i] = p[j];
      p[j] = a;
    });
}
```