ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sum_to_zero>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  call   <quicksort@plt>
  test   %r14,%r14
  je     L21
  lea    -0x1(%r14),%r9
  xor    %r8d,%r8d
L83:
  lea    0x1(%r8),%rdi
  cmp    %r9,%rdi
  jae    L19
  mov    -0x4(%r13,%rdi,4),%esi
  mov    %r9,%rax
  mov    %rdi,%rcx
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L25:
  sub    $0x1,%rax
  cmp    %rax,%rcx
  jae    L19
L78:
  mov    0x0(%r13,%rcx,4),%edx
  add    %esi,%edx
  add    0x0(%r13,%rax,4),%edx
  je     L1
  jns    L25
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jb     L78
L19:
  cmp    %rdi,%r14
  je     L21
  mov    %rdi,%r8
  jmp    L83
  nopl   0x0(%rax)
L1:
  mov    %r8,(%r12)
  mov    %rcx,0x0(%rbp)
  mov    %rax,(%rbx)
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int sum_to_zero(size_t N, int arr[N], size_t *i, size_t *j, size_t *k) {
  quicksort(N, arr);
  size_t arr_i = 0;
  for (arr_i = 0; arr_i < N; arr_i++) {
    size_t front_cursor = arr_i + 1;
    size_t back_cursor = N - 1;
    while (front_cursor < back_cursor) {
      int sum = arr[arr_i] + arr[front_cursor] + arr[back_cursor];
      if (sum == 0) {
        *i = arr_i;
        *j = front_cursor;
        *k = back_cursor;
        return 1;
      } else if (sum < 0) {
        front_cursor++;
      } else {
        back_cursor--;
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_to_zero>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  call   <quicksort@plt>
  test   %r14,%r14
  je     L76
  lea    -0x1(%r14),%r10
  xor    %r11d,%r11d
L37:
  lea    0x1(%r11),%r9
  cmp    %r10,%r9
  jae    L99
  mov    -0x4(%r13,%r9,4),%r8d
  mov    0x0(%r13,%r9,4),%edi
  mov    %r10,%rdx
  mov    %r9,%rcx
  mov    0x0(%r13,%r10,4),%esi
L67:
  lea    (%r8,%rdi,1),%eax
  add    %esi,%eax
  je     L10
L40:
  js     L1
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jbe    L99
  mov    0x0(%r13,%rdx,4),%esi
  lea    (%r8,%rdi,1),%eax
  add    %esi,%eax
  jne    L40
L10:
  mov    %r11,(%r12)
  mov    $0x1,%eax
  mov    %rcx,0x0(%rbp)
  mov    %rdx,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jae    L99
  mov    0x0(%r13,%rcx,4),%edi
  jmp    L67
L99:
  cmp    %r9,%r14
  je     L76
  mov    %r9,%r11
  jmp    L37
L76:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int sum_to_zero(size_t N, int arr[N], size_t *i, size_t *j, size_t *k) {
  quicksort(N, arr);
  size_t arr_i = 0;
  for (arr_i = 0; arr_i < N; arr_i++) {
    size_t front_cursor = arr_i + 1;
    size_t back_cursor = N - 1;
    while (front_cursor < back_cursor) {
      int sum = arr[arr_i] + arr[front_cursor] + arr[back_cursor];
      if (sum == 0) {
        *i = arr_i;
        *j = front_cursor;
        *k = back_cursor;
        return 1;
      } else if (sum < 0) {
        front_cursor++;
      } else {
        back_cursor--;
      }
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L28
L14:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D23(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D23(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D43(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jnp    L11
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L11:
  addl   $0x1,-0x2c(%rbp)
L28:
  cmpl   $0xf423f,-0x2c(%rbp)
  jle    L14
L18:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x28(%rbp),%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jnp    L49
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L49:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D23
datatype: f64
name: unpack_data
arguments: tag: D43
datatype: f64
name: unpack_data
arguments: tag: D45
datatype: string

tool: D23: 100

tool: D43: 50

tool: D45: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double z;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (100.0 * rand_double()) - 0.0;
    y = (100.0 * rand_double()) - 50.0;
    z = pow(x, y);
    if (z != z) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (z != z) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebp
L24:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D36(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movq   %rbx,%xmm0
  mulsd  D36(%rip),%xmm0
  subsd  D23(%rip),%xmm1
  call   <pow@plt>
  ucomisd %xmm0,%xmm0
  jp     L18
  sub    $0x1,%ebp
  jne    L24
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm3
  subsd  %xmm3,%xmm0
  movq   %xmm0,%rbx
  jmp    L25
L18:
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L25:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D23
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string

tool: D36: 100

tool: D23: 50

tool: D26: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double z;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (100.0 * rand_double()) - 0.0;
    y = (100.0 * rand_double()) - 50.0;
    z = pow(x, y);
    if (z != z) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (z != z) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L0
  xchg   %ax,%ax
L13:
  sub    $0x1,%ebx
  je     L10
L0:
  xor    %eax,%eax
  call   <rand_double@plt>
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  call   <rand_double@plt>
  movsd  D24(%rip),%xmm1
  movsd  (%rsp),%xmm2
  mulsd  %xmm0,%xmm1
  movsd  D24(%rip),%xmm0
  subsd  D5(%rip),%xmm1
  mulsd  %xmm2,%xmm0
  call   <pow@plt>
  ucomisd %xmm0,%xmm0
  jnp    L13
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D24
type: f64
name: disassemble_data
arguments: label: D5
type: f64
name: disassemble_data
arguments: label: D13
type: string

tool: D24: 100

tool: D5: 50

tool: D13: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double z;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (100.0 * rand_double()) - 0.0;
    y = (100.0 * rand_double()) - 50.0;
    z = pow(x, y);
    if (z != z) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (z != z) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L12
  xchg   %ax,%ax
L4:
  sub    $0x1,%ebx
  je     L23
L12:
  xor    %eax,%eax
  call   <rand_double@plt>
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  call   <rand_double@plt>
  movsd  D5(%rip),%xmm1
  movsd  (%rsp),%xmm2
  mulsd  %xmm0,%xmm1
  movsd  D5(%rip),%xmm0
  subsd  D6(%rip),%xmm1
  mulsd  %xmm2,%xmm0
  call   <pow@plt>
  ucomisd %xmm0,%xmm0
  jnp    L4
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L23:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: f64
name: unpack_data
arguments: data_tag: D6
type: f64
name: unpack_data
arguments: data_tag: D0
type: string

tool: D5: 100

tool: D6: 50

tool: D0: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double z;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (100.0 * rand_double()) - 0.0;
    y = (100.0 * rand_double()) - 50.0;
    z = pow(x, y);
    if (z != z) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (z != z) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L52
  jmp    L0
L46:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L64
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L0:
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L46
  jmp    L37
L64:
  nop
L37:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L52
L36:
  addq   $0x1,-0x20(%rbp)
L52:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  const char *s = src;
  if (size) {
    while (--size) {
      if (*src == '\0')
        break;
      *dst++ = *src++;
    }
    *dst = '\0';
  }
  while (*src != '\0')
    src++;
  return src - s;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L8
  cmp    $0x1,%rdx
  je     L48
  mov    %rdi,%rcx
  lea    -0x1(%rdi,%rdx,1),%rdi
L13:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L36
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  cmp    %rdi,%rcx
  jne    L13
L36:
  movb   $0x0,(%rcx)
L8:
  cmpb   $0x0,(%rax)
  je     L47
L69:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L69
L47:
  sub    %rsi,%rax
  ret
L48:
  mov    %rdi,%rcx
  jmp    L36
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  const char *s = src;
  if (size) {
    while (--size) {
      if (*src == '\0')
        break;
      *dst++ = *src++;
    }
    *dst = '\0';
  }
  while (*src != '\0')
    src++;
  return src - s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L65
  cmp    $0x1,%rdx
  je     L64
  lea    -0x1(%rdi,%rdx,1),%rcx
  jmp    L36
  nopl   0x0(%rax)
L59:
  add    $0x1,%rdi
  add    $0x1,%rax
  mov    %dl,-0x1(%rdi)
  cmp    %rcx,%rdi
  je     L64
L36:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L59
L64:
  movb   $0x0,(%rdi)
  cmpb   $0x0,(%rax)
  je     L41
  nop
L61:
  add    $0x1,%rax
L65:
  cmpb   $0x0,(%rax)
  jne    L61
L41:
  sub    %rsi,%rax
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  const char *s = src;
  if (size) {
    while (--size) {
      if (*src == '\0')
        break;
      *dst++ = *src++;
    }
    *dst = '\0';
  }
  while (*src != '\0')
    src++;
  return src - s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L30
  cmp    $0x1,%rdx
  je     L31
  lea    -0x1(%rdi,%rdx,1),%rcx
  jmp    L67
  nopl   0x0(%rax)
L5:
  add    $0x1,%rdi
  add    $0x1,%rax
  mov    %dl,-0x1(%rdi)
  cmp    %rcx,%rdi
  je     L31
L67:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L5
L31:
  movb   $0x0,(%rdi)
  cmpb   $0x0,(%rax)
  je     L37
  nop
L44:
  add    $0x1,%rax
L30:
  cmpb   $0x0,(%rax)
  jne    L44
L37:
  sub    %rsi,%rax
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t size) {
  const char *s = src;
  if (size) {
    while (--size) {
      if (*src == '\0')
        break;
      *dst++ = *src++;
    }
    *dst = '\0';
  }
  while (*src != '\0')
    src++;
  return src - s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compute_correct_result>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L57
L50:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L43
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  neg    %edx
  mov    %edx,(%rax)
  jmp    L36
L43:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  jmp    L36
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L36:
  addl   $0x1,-0x4(%rbp)
L57:
  cmpl   $0x3,-0x4(%rbp)
  jle    L50
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void compute_correct_result(int *i1, int *i2, int *r) {
  int i;
  for (i = 0; i < 4; i++)
    if (i2[i] < 0)
      r[i] = -i1[i];
    else if (i2[i] == 0)
      r[i] = 0;
    else
      r[i] = i1[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compute_correct_result>:
  endbr64
  mov    $0x0,%eax
  jmp    L19
L12:
  mov    (%rdi,%rax,1),%ecx
  neg    %ecx
  mov    %ecx,(%rdx,%rax,1)
L0:
  add    $0x4,%rax
  cmp    $0x10,%rax
  je     L23
L19:
  mov    (%rsi,%rax,1),%ecx
  test   %ecx,%ecx
  js     L12
  jne    L47
  movl   $0x0,(%rdx,%rax,1)
  jmp    L0
L47:
  mov    (%rdi,%rax,1),%ecx
  mov    %ecx,(%rdx,%rax,1)
  jmp    L0
L23:
  ret
```

assistant: ```c
void compute_correct_result(int *i1, int *i2, int *r) {
  int i;
  for (i = 0; i < 4; i++)
    if (i2[i] < 0)
      r[i] = -i1[i];
    else if (i2[i] == 0)
      r[i] = 0;
    else
      r[i] = i1[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compute_correct_result>:
  endbr64
  xor    %eax,%eax
L3:
  mov    (%rsi,%rax,1),%ecx
  test   %ecx,%ecx
  js     L25
  je     L13
  mov    (%rdi,%rax,1),%ecx
L13:
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L3
  ret
L25:
  mov    (%rdi,%rax,1),%ecx
  neg    %ecx
  jmp    L13
```

assistant: ```c
void compute_correct_result(int *i1, int *i2, int *r) {
  int i;
  for (i = 0; i < 4; i++)
    if (i2[i] < 0)
      r[i] = -i1[i];
    else if (i2[i] == 0)
      r[i] = 0;
    else
      r[i] = i1[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<compute_correct_result>:
  endbr64
  mov    (%rsi),%eax
  test   %eax,%eax
  js     L122
  jne    L14
L43:
  mov    %eax,(%rdx)
  mov    0x4(%rsi),%eax
  test   %eax,%eax
  js     L96
L51:
  jne    L50
L6:
  mov    %eax,0x4(%rdx)
  mov    0x8(%rsi),%eax
  test   %eax,%eax
  js     L26
L57:
  jne    L36
L11:
  mov    %eax,0x8(%rdx)
  mov    0xc(%rsi),%eax
  test   %eax,%eax
  js     L137
L86:
  jne    L61
  mov    %eax,0xc(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  mov    0xc(%rdi),%eax
  mov    %eax,0xc(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    0x8(%rdi),%eax
  mov    %eax,0x8(%rdx)
  mov    0xc(%rsi),%eax
  test   %eax,%eax
  jns    L86
L137:
  mov    0xc(%rdi),%eax
  neg    %eax
  mov    %eax,0xc(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    0x4(%rdi),%eax
  mov    %eax,0x4(%rdx)
  mov    0x8(%rsi),%eax
  test   %eax,%eax
  jns    L57
L26:
  mov    0x8(%rdi),%eax
  neg    %eax
  jmp    L11
  nopl   0x0(%rax)
L14:
  mov    (%rdi),%eax
  mov    %eax,(%rdx)
  mov    0x4(%rsi),%eax
  test   %eax,%eax
  jns    L51
L96:
  mov    0x4(%rdi),%eax
  neg    %eax
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L122:
  mov    (%rdi),%eax
  neg    %eax
  jmp    L43
```

assistant: ```c
void compute_correct_result(int *i1, int *i2, int *r) {
  int i;
  for (i = 0; i < 4; i++)
    if (i2[i] < 0)
      r[i] = -i1[i];
    else if (i2[i] == 0)
      r[i] = 0;
    else
      r[i] = i1[i];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str_is_cmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L66
L29:
  addq   $0x1,-0x10(%rbp)
L66:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L17
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L29
L17:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L93
  mov    $0x0,%eax
  jmp    L57
L93:
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L23
  mov    $0x0,%eax
  jmp    L57
L23:
  cmpq   $0x0,-0x30(%rbp)
  je     L60
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
L60:
  cmpq   $0x0,-0x38(%rbp)
  je     L71
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x20(%rbp)
  jbe    L53
  mov    -0x20(%rbp),%rax
  sub    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  jmp    L26
L53:
  mov    $0x0,%edx
L26:
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L71:
  mov    $0x1,%eax
L57:
  leave
  ret
```

assistant: ```c
uint8_t str_is_cmd(char *s, uint16_t l, char *cmd, char **args, uint16_t *args_len) {
  uint16_t cmd_l;
  uint16_t s_l;
  cmd_l = strlen(cmd);
  s_l = 0;
  while ((s_l < l) && (s[s_l] != ' ')) {
    s_l = s_l + 1;
  }
  if (s_l != cmd_l) {
    return 0;
  }
  if (memcmp(s, cmd, s_l)) {
    return 0;
  }
  if (args) {
    *args = &(s[s_l + 1]);
  }
  if (args_len) {
    *args_len = ((s_l + 1) < l) ? (l - (s_l + 1)) : 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_is_cmd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r15
  mov    %r8,%r14
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    $0x0,%ebx
  test   %rbp,%rbp
  je     L73
L46:
  cmpb   $0x20,(%r12,%rbx,1)
  je     L2
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L46
  mov    %rbp,%rbx
L2:
  mov    $0x0,%edx
  cmp    %rbx,%rax
  je     L72
L5:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L73:
  mov    %rbp,%rbx
  jmp    L2
L72:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  jne    L5
  test   %r15,%r15
  je     L3
  lea    0x1(%r12,%rbx,1),%rax
  mov    %rax,(%r15)
L3:
  mov    $0x1,%edx
  test   %r14,%r14
  je     L5
  lea    0x1(%rbx),%rdx
  lea    -0x1(%rbp),%rax
  sub    %rbx,%rax
  cmp    %rbp,%rdx
  mov    $0x0,%edx
  cmovae %rdx,%rax
  mov    %rax,(%r14)
  mov    $0x1,%edx
  jmp    L5
```

assistant: ```c
uint8_t str_is_cmd(char *s, uint16_t l, char *cmd, char **args, uint16_t *args_len) {
  uint16_t cmd_l;
  uint16_t s_l;
  cmd_l = strlen(cmd);
  s_l = 0;
  while ((s_l < l) && (s[s_l] != ' ')) {
    s_l = s_l + 1;
  }
  if (s_l != cmd_l) {
    return 0;
  }
  if (memcmp(s, cmd, s_l)) {
    return 0;
  }
  if (args) {
    *args = &(s[s_l + 1]);
  }
  if (args_len) {
    *args_len = ((s_l + 1) < l) ? (l - (s_l + 1)) : 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_is_cmd>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rbp,%rbp
  jne    L15
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L57
L15:
  cmpb   $0x20,(%r12,%rbx,1)
  jne    L27
L57:
  cmp    %rbx,%rax
  je     L64
L76:
  xor    %eax,%eax
L77:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L64:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L76
  test   %r15,%r15
  je     L25
  lea    0x1(%r12,%rbx,1),%rax
  mov    %rax,(%r15)
L25:
  mov    $0x1,%eax
  test   %r14,%r14
  je     L77
  lea    0x1(%rbx),%rcx
  lea    -0x1(%rbp),%rdx
  sub    %rbx,%rdx
  cmp    %rbp,%rcx
  mov    $0x0,%ecx
  cmovae %rcx,%rdx
  mov    %rdx,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint8_t str_is_cmd(char *s, uint16_t l, char *cmd, char **args, uint16_t *args_len) {
  uint16_t cmd_l;
  uint16_t s_l;
  cmd_l = strlen(cmd);
  s_l = 0;
  while ((s_l < l) && (s[s_l] != ' ')) {
    s_l = s_l + 1;
  }
  if (s_l != cmd_l) {
    return 0;
  }
  if (memcmp(s, cmd, s_l)) {
    return 0;
  }
  if (args) {
    *args = &(s[s_l + 1]);
  }
  if (args_len) {
    *args_len = ((s_l + 1) < l) ? (l - (s_l + 1)) : 0;
  }
  return 1;
}
```