ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <sock_print@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void sock_info(int sockfd, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  sock_print(sockfd, LOG_INFO, fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sock_info>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  mov    %r12d,%edi
  call   <sock_print@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sock_info(int sockfd, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  sock_print(sockfd, LOG_INFO, fmt, ap);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sock_info>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%edi
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <sock_print@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sock_info(int sockfd, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  sock_print(sockfd, LOG_INFO, fmt, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sock_info>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%edi
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <sock_print@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sock_info(int sockfd, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  sock_print(sockfd, LOG_INFO, fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mjpeg_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <mjpeg_logv@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void mjpeg_error(const char format[], ...) {
  va_list args;
  va_start(args, format);
  mjpeg_logv(4, format, args);
  va_end(args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mjpeg_error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x4,%edi
  call   <mjpeg_logv@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mjpeg_error(const char format[], ...) {
  va_list args;
  va_start(args, format);
  mjpeg_logv(4, format, args);
  va_end(args);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mjpeg_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x4,%edi
  call   <mjpeg_logv@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mjpeg_error(const char format[], ...) {
  va_list args;
  va_start(args, format);
  mjpeg_logv(4, format, args);
  va_end(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mjpeg_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x4,%edi
  call   <mjpeg_logv@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mjpeg_error(const char format[], ...) {
  va_list args;
  va_start(args, format);
  mjpeg_logv(4, format, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<decimal_number_part>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movzbl -0x1c(%rbp),%eax
  mov    %eax,%edx
  sar    $0x7,%dl
  shr    $0x6,%dl
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %al,-0xd(%rbp)
  movq   $0x0,-0x8(%rbp)
  movzbl -0xd(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <big_endian_number@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  xor    -0x20(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L12
L0:
  movzbl -0xd(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <big_endian_number@plt>
  mov    %eax,-0xc(%rbp)
  addb   $0x4,-0xd(%rbp)
  mov    -0x8(%rbp),%rax
  imul   $0x3b9aca00,%rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  xor    -0x20(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L12:
  movzbl -0xd(%rbp),%edx
  movsbl -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jl     L0
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long int decimal_number_part(const char *buf, char len, int mask) {
  int tmp;
  unsigned char comp = len % 4;
  long int number = 0;
  tmp = big_endian_number(buf, comp);
  number = tmp ^ mask;
  while (comp < len) {
    tmp = big_endian_number(buf + comp, 4);
    comp += 4;
    number *= 1000000000;
    number += tmp ^ mask;
  }
  return number;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<decimal_number_part>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %esi,%eax
  sar    $0x7,%al
  shr    $0x6,%al
  lea    (%rax,%rsi,1),%r15d
  and    $0x3,%r15d
  sub    %eax,%r15d
  mov    %r15d,%ebx
  movzbl %r15b,%r15d
  mov    %r15d,%esi
  call   <big_endian_number@plt>
  xor    %r12d,%eax
  movslq %eax,%r14
  movsbl %bpl,%ebp
  cmp    %ebp,%r15d
  jge    L15
L16:
  movzbl %bl,%edi
  add    %r13,%rdi
  mov    $0x4,%esi
  call   <big_endian_number@plt>
  add    $0x4,%ebx
  imul   $0x3b9aca00,%r14,%r14
  xor    %r12d,%eax
  cltq
  add    %rax,%r14
  movzbl %bl,%eax
  cmp    %ebp,%eax
  jl     L16
L15:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
long int decimal_number_part(const char *buf, char len, int mask) {
  int tmp;
  unsigned char comp = len % 4;
  long int number = 0;
  tmp = big_endian_number(buf, comp);
  number = tmp ^ mask;
  while (comp < len) {
    tmp = big_endian_number(buf + comp, 4);
    comp += 4;
    number *= 1000000000;
    number += tmp ^ mask;
  }
  return number;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decimal_number_part>:
  endbr64
  mov    %esi,%eax
  push   %r15
  sar    $0x7,%al
  push   %r14
  shr    $0x6,%al
  push   %r13
  lea    (%rax,%rsi,1),%r14d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  and    $0x3,%r14d
  mov    %edx,%ebp
  push   %rbx
  sub    %eax,%r14d
  mov    %esi,%ebx
  movzbl %r14b,%r15d
  movsbl %bl,%ebx
  mov    %r15d,%esi
  sub    $0x8,%rsp
  call   <big_endian_number@plt>
  xor    %ebp,%eax
  movslq %eax,%r13
  cmp    %ebx,%r15d
  jge    L6
  nopl   (%rax)
L7:
  movzbl %r14b,%edi
  mov    $0x4,%esi
  add    $0x4,%r14d
  add    %r12,%rdi
  imul   $0x3b9aca00,%r13,%r13
  call   <big_endian_number@plt>
  xor    %ebp,%eax
  cltq
  add    %rax,%r13
  movzbl %r14b,%eax
  cmp    %ebx,%eax
  jl     L7
L6:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
long int decimal_number_part(const char *buf, char len, int mask) {
  int tmp;
  unsigned char comp = len % 4;
  long int number = 0;
  tmp = big_endian_number(buf, comp);
  number = tmp ^ mask;
  while (comp < len) {
    tmp = big_endian_number(buf + comp, 4);
    comp += 4;
    number *= 1000000000;
    number += tmp ^ mask;
  }
  return number;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<decimal_number_part>:
  endbr64
  mov    %esi,%eax
  push   %r15
  sar    $0x7,%al
  push   %r14
  shr    $0x6,%al
  push   %r13
  lea    (%rax,%rsi,1),%r14d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  and    $0x3,%r14d
  mov    %edx,%ebp
  push   %rbx
  sub    %eax,%r14d
  mov    %esi,%ebx
  movzbl %r14b,%r15d
  movsbl %bl,%ebx
  mov    %r15d,%esi
  sub    $0x8,%rsp
  call   <big_endian_number@plt>
  xor    %ebp,%eax
  movslq %eax,%r13
  cmp    %ebx,%r15d
  jge    L15
  nopl   (%rax)
L3:
  movzbl %r14b,%edi
  mov    $0x4,%esi
  add    $0x4,%r14d
  add    %r12,%rdi
  imul   $0x3b9aca00,%r13,%r13
  call   <big_endian_number@plt>
  xor    %ebp,%eax
  cltq
  add    %rax,%r13
  movzbl %r14b,%eax
  cmp    %ebx,%eax
  jl     L3
L15:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
long int decimal_number_part(const char *buf, char len, int mask) {
  int tmp;
  unsigned char comp = len % 4;
  long int number = 0;
  tmp = big_endian_number(buf, comp);
  number = tmp ^ mask;
  while (comp < len) {
    tmp = big_endian_number(buf + comp, 4);
    comp += 4;
    number *= 1000000000;
    number += tmp ^ mask;
  }
  return number;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <raise@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int ac, const char **av) {
  raise(SIGSEGV);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int ac, const char **av) {
  raise(SIGSEGV);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int ac, const char **av) {
  raise(SIGSEGV);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int ac, const char **av) {
  raise(SIGSEGV);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chizu_internal_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *chizu_internal_strdup(const char *s) {
  size_t n = strlen(s);
  char *p = (char *)malloc(n + 1);
  if (p)
    strcpy(p, s);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chizu_internal_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L5
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L10
```

assistant: ```c
char *chizu_internal_strdup(const char *s) {
  size_t n = strlen(s);
  char *p = (char *)malloc(n + 1);
  if (p)
    strcpy(p, s);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chizu_internal_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L6:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *chizu_internal_strdup(const char *s) {
  size_t n = strlen(s);
  char *p = (char *)malloc(n + 1);
  if (p)
    strcpy(p, s);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<chizu_internal_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L7:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *chizu_internal_strdup(const char *s) {
  size_t n = strlen(s);
  char *p = (char *)malloc(n + 1);
  if (p)
    strcpy(p, s);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dot_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dot_product(double *v1, double *v2) {
  double product;
  product = v1[0] * v2[0] + v1[1] * v2[1] + v1[2] * v2[2];
  return product;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dot_product>:
  endbr64
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double dot_product(double *v1, double *v2) {
  double product;
  product = v1[0] * v2[0] + v1[1] * v2[1] + v1[2] * v2[2];
  return product;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dot_product>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double dot_product(double *v1, double *v2) {
  double product;
  product = v1[0] * v2[0] + v1[1] * v2[1] + v1[2] * v2[2];
  return product;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dot_product>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double dot_product(double *v1, double *v2) {
  double product;
  product = v1[0] * v2[0] + v1[1] * v2[1] + v1[2] * v2[2];
  return product;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L46
L4:
  addq   $0x1,-0x18(%rbp)
L46:
  cmpq   $0x0,-0x18(%rbp)
  je     L16
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L4
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x8,%al
  jle    L16
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jle    L4
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L100
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L40
L100:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L40
  movl   $0xfffffff,-0x4(%rbp)
  jmp    L40
L32:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L32
L34:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  int count;
  int sign;
  count = 0x00;
  sign = 0x01;
  while (str && ((*str == 0x20) || (*str > 0x08 && *str < 0x0e)))
    str++;
  if (*str == 0x2b || *str == 0x2d) {
    if (*str++ == 0x2d)
      sign = 0xfffffff;
  }
  while (*str && ft_isdigit(*str))
    count = (count << 0x03) + (count << 0x01) + (*str++) - 0x30;
  return (count * sign);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  jne    L24
  jmp    L27
L75:
  add    $0x1,%rbx
L24:
  movzbl (%rbx),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L75
  cmp    $0x20,%al
  je     L75
L27:
  movzbl (%rbx),%eax
  lea    -0x2b(%rax),%edx
  mov    $0x1,%r12d
  test   $0xfd,%dl
  jne    L68
  add    $0x1,%rbx
  cmp    $0x2d,%al
  mov    $0xfffffff,%edx
  cmove  %edx,%r12d
L68:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L69
  mov    $0x0,%ebp
L44:
  movsbl %dil,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  je     L46
  add    $0x1,%rbx
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl -0x1(%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L44
L46:
  mov    %r12d,%eax
  imul   %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L69:
  mov    $0x0,%ebp
  jmp    L46
```

assistant: ```c
int ft_atoi(const char *str) {
  int count;
  int sign;
  count = 0x00;
  sign = 0x01;
  while (str && ((*str == 0x20) || (*str > 0x08 && *str < 0x0e)))
    str++;
  if (*str == 0x2b || *str == 0x2d) {
    if (*str++ == 0x2d)
      sign = 0xfffffff;
  }
  while (*str && ft_isdigit(*str))
    count = (count << 0x03) + (count << 0x01) + (*str++) - 0x30;
  return (count * sign);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_atoi>:
  endbr64
  test   %rdi,%rdi
  je     L73
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L92
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x1,%rbx
L92:
  movsbl (%rbx),%edi
  lea    -0x9(%rdi),%eax
  cmp    $0x4,%al
  jbe    L6
  cmp    $0x20,%dil
  je     L6
  lea    -0x2b(%rdi),%eax
  mov    $0x1,%r12d
  test   $0xfd,%al
  je     L94
L105:
  test   %dil,%dil
  je     L108
  xor    %ebp,%ebp
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L49:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
  test   %dil,%dil
  je     L68
L22:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L49
  mov    %r12d,%eax
  imul   %ebp,%eax
L82:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L94:
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rax
  cmp    $0x2d,%dil
  mov    %rax,%rbx
  movsbl %dl,%edi
  jne    L105
  mov    $0xfffffff,%r12d
  jmp    L105
  nopl   0x0(%rax)
L68:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  imul   %r12d,%eax
  pop    %r12
  ret
L108:
  xor    %eax,%eax
  jmp    L82
L73:
  jmp    1060 <ft_atoi.cold>
```

assistant: ```c
int ft_atoi(const char *str) {
  int count;
  int sign;
  count = 0x00;
  sign = 0x01;
  while (str && ((*str == 0x20) || (*str > 0x08 && *str < 0x0e)))
    str++;
  if (*str == 0x2b || *str == 0x2d) {
    if (*str++ == 0x2d)
      sign = 0xfffffff;
  }
  while (*str && ft_isdigit(*str))
    count = (count << 0x03) + (count << 0x01) + (*str++) - 0x30;
  return (count * sign);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_atoi>:
  endbr64
  test   %rdi,%rdi
  je     1060 <ft_atoi.cold>
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  lea    -0x9(%rdi),%eax
  cmp    $0x4,%al
  ja     L84
  xchg   %ax,%ax
L63:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  lea    -0x9(%rdi),%eax
  cmp    $0x4,%al
  jbe    L63
L84:
  cmp    $0x20,%dil
  je     L63
  lea    -0x2b(%rdi),%eax
  mov    $0x1,%r12d
  test   $0xfd,%al
  je     L28
L22:
  test   %dil,%dil
  je     L33
  xor    %ebp,%ebp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L51:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
  test   %dil,%dil
  je     L15
L4:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L51
  mov    %r12d,%eax
  imul   %ebp,%eax
L69:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L28:
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rax
  cmp    $0x2d,%dil
  mov    %rax,%rbx
  movsbl %dl,%edi
  jne    L22
  mov    $0xfffffff,%r12d
  jmp    L22
  nopl   0x0(%rax)
L15:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  imul   %r12d,%eax
  pop    %r12
  ret
L33:
  xor    %eax,%eax
  jmp    L69
```

assistant: ```c
int ft_atoi(const char *str) {
  int count;
  int sign;
  count = 0x00;
  sign = 0x01;
  while (str && ((*str == 0x20) || (*str > 0x08 && *str < 0x0e)))
    str++;
  if (*str == 0x2b || *str == 0x2d) {
    if (*str++ == 0x2d)
      sign = 0xfffffff;
  }
  while (*str && ft_isdigit(*str))
    count = (count << 0x03) + (count << 0x01) + (*str++) - 0x30;
  return (count * sign);
}
```