user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x7a1000(%rsp),%r11
L7:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L7
  sub    $0x230,%rsp
  mov    %edi,-0x7a1224(%rbp)
  mov    %rsi,-0x7a1230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7a1220(%rbp)
  jmp    L30
L63:
  movl   $0x0,-0x7a121c(%rbp)
  jmp    L103
L20:
  mov    -0x7a1220(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x7a121c(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x7a121c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x7a1220(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rdx,%rax
  movsd  %xmm0,-0x7a1210(%rbp,%rax,8)
  addl   $0x1,-0x7a121c(%rbp)
L103:
  cmpl   $0x3e7,-0x7a121c(%rbp)
  jle    L20
  addl   $0x1,-0x7a1220(%rbp)
L30:
  cmpl   $0x3e7,-0x7a1220(%rbp)
  jle    L63
  movl   $0x0,-0x7a1220(%rbp)
  jmp    L75
L130:
  movl   $0x0,-0x7a121c(%rbp)
  jmp    L90
L41:
  mov    -0x7a121c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x7a1220(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rdx,%rax
  movsd  -0x7a1210(%rbp,%rax,8),%xmm1
  movsd  D14(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    -0x7a121c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x7a1220(%rbp),%edx
  movslq %edx,%rdx
  imul   $0x3e8,%rdx,%rdx
  add    %rcx,%rdx
  mov    %rax,-0x7a1210(%rbp,%rdx,8)
  addl   $0x1,-0x7a121c(%rbp)
L90:
  cmpl   $0x3e7,-0x7a121c(%rbp)
  jle    L41
  addl   $0x1,-0x7a1220(%rbp)
L75:
  cmpl   $0x3e7,-0x7a1220(%rbp)
  jle    L130
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x7a1218(%rbp)
  movl   $0x0,-0x7a1220(%rbp)
  jmp    L47
L131:
  movl   $0x0,-0x7a121c(%rbp)
  jmp    L94
L32:
  mov    -0x7a121c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x7a1220(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rdx,%rax
  mov    -0x7a1210(%rbp,%rax,8),%rdx
  mov    -0x7a1218(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <fprintf@plt>
  addl   $0x1,-0x7a121c(%rbp)
L94:
  cmpl   $0x3e7,-0x7a121c(%rbp)
  jle    L32
  mov    -0x7a1218(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  addl   $0x1,-0x7a1220(%rbp)
L47:
  cmpl   $0x3e7,-0x7a1220(%rbp)
  jle    L131
  mov    -0x7a1218(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L133
  call   <__stack_chk_fail@plt>
L133:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type: f64
name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D28
type: string
name: retrieve_data
arguments: data_label: D10
type: string

tool: D14: 1e-05

tool: D15: w

tool: D28: result.simple.txt

tool: D10: %f 

assistant: ```c
int main(int argc, char **argv) {
  double a[1000][1000];
  int i, j;
  FILE *ff;
  for (i = 0; i < 1000; i++) {
    for (j = 0; j < 1000; j++) {
      a[i][j] = 10 * i + j;
    }
  }
  for (i = 0; i < 1000; i++) {
    for (j = 0; j < 1000; j++) {
      a[i][j] = sin(0.00001 * a[i][j]);
    }
  }
  ff = fopen("result.simple.txt", "w");
  for (i = 0; i < 1000; i++) {
    for (j = 0; j < 1000; j++) {
      fprintf(ff, "%f ", a[i][j]);
    }
    fprintf(ff, "\n");
  }
  fclose(ff);
  return 0;
}
```