ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<fp_poch_rising>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpf_init@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mpf_set@plt>
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <mpf_set_ui@plt>
  test   %r13d,%r13d
  je     L17
  mov    $0x0,%ebp
L1:
  mov    $0x0,%ebx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r12d,%edi
  call   <mpf_mul@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpf_add_ui@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L1
L17:
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpf_clear@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void fp_poch_rising(mpf_t poch, mpf_t x, unsigned int n) {
  mpf_t term;
  mpf_init(term);
  mpf_set(term, x);
  mpf_set_ui(poch, 1);
  unsigned int i;
  for (i = 0; i < n; i++) {
    mpf_mul(poch, poch, term);
    mpf_add_ui(term, term, 1);
  }
  mpf_clear(term);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fp_poch_rising>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  call   <mpf_init@plt>
  mov    %r14d,%esi
  mov    %ebp,%edi
  call   <mpf_set@plt>
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <mpf_set_ui@plt>
  test   %r13d,%r13d
  je     L18
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  xor    %ebp,%ebp
  mov    %r12d,%esi
  mov    %r12d,%edi
  add    $0x1,%ebx
  mov    %ebp,%edx
  call   <mpf_mul@plt>
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpf_add_ui@plt>
  cmp    %ebx,%r13d
  jne    L8
L18:
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <mpf_clear@plt>
```

assistant: ```c
void fp_poch_rising(mpf_t poch, mpf_t x, unsigned int n) {
  mpf_t term;
  mpf_init(term);
  mpf_set(term, x);
  mpf_set_ui(poch, 1);
  unsigned int i;
  for (i = 0; i < n; i++) {
    mpf_mul(poch, poch, term);
    mpf_add_ui(term, term, 1);
  }
  mpf_clear(term);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fp_poch_rising>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  call   <mpf_init@plt>
  mov    %r14d,%esi
  mov    %ebp,%edi
  call   <mpf_set@plt>
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <mpf_set_ui@plt>
  test   %r13d,%r13d
  je     L18
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L10:
  xor    %ebp,%ebp
  mov    %r12d,%esi
  mov    %r12d,%edi
  add    $0x1,%ebx
  mov    %ebp,%edx
  call   <mpf_mul@plt>
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpf_add_ui@plt>
  cmp    %ebx,%r13d
  jne    L10
L18:
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <mpf_clear@plt>
```

assistant: ```c
void fp_poch_rising(mpf_t poch, mpf_t x, unsigned int n) {
  mpf_t term;
  mpf_init(term);
  mpf_set(term, x);
  mpf_set_ui(poch, 1);
  unsigned int i;
  for (i = 0; i < n; i++) {
    mpf_mul(poch, poch, term);
    mpf_add_ui(term, term, 1);
  }
  mpf_clear(term);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dotestAnn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <array2StringLongLong@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <ann@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <array2StringLongLong@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L2
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: Error. Expected %s
 but got %s


assistant: ```c
void dotestAnn(int n, long long *exp) {
  char *s1 = array2StringLongLong(exp, n);
  long long *act = ann(n);
  char *s2 = array2StringLongLong(act, n);
  if (strcmp(s1, s2) != 0)
    printf("Error. Expected %s\n but got %s\n", s1, s2);
  assert(strcmp(s1, s2) == 0);
  free(s1);
  s1 = NULL;
  free(s2);
  s2 = NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dotestAnn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rdi
  mov    %ebx,%esi
  call   <array2StringLongLong@plt>
  mov    %rax,%rbp
  mov    %ebx,%edi
  call   <ann@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <array2StringLongLong@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
L0:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: Error. Expected %s
 but got %s


assistant: ```c
void dotestAnn(int n, long long *exp) {
  char *s1 = array2StringLongLong(exp, n);
  long long *act = ann(n);
  char *s2 = array2StringLongLong(act, n);
  if (strcmp(s1, s2) != 0)
    printf("Error. Expected %s\n but got %s\n", s1, s2);
  assert(strcmp(s1, s2) == 0);
  free(s1);
  s1 = NULL;
  free(s2);
  s2 = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dotestAnn>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <array2StringLongLong@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <ann@plt>
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <array2StringLongLong@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <free@plt>
  xchg   %ax,%ax
L9:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: Error. Expected %s
 but got %s


assistant: ```c
void dotestAnn(int n, long long *exp) {
  char *s1 = array2StringLongLong(exp, n);
  long long *act = ann(n);
  char *s2 = array2StringLongLong(act, n);
  if (strcmp(s1, s2) != 0)
    printf("Error. Expected %s\n but got %s\n", s1, s2);
  assert(strcmp(s1, s2) == 0);
  free(s1);
  s1 = NULL;
  free(s2);
  s2 = NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<dotestAnn>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <array2StringLongLong@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <ann@plt>
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <array2StringLongLong@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <free@plt>
  xchg   %ax,%ax
L18:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: Error. Expected %s
 but got %s


assistant: ```c
void dotestAnn(int n, long long *exp) {
  char *s1 = array2StringLongLong(exp, n);
  long long *act = ann(n);
  char *s2 = array2StringLongLong(act, n);
  if (strcmp(s1, s2) != 0)
    printf("Error. Expected %s\n but got %s\n", s1, s2);
  assert(strcmp(s1, s2) == 0);
  free(s1);
  s1 = NULL;
  free(s2);
  s2 = NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<row_shift_from_symbol_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x14(%rbp)
  jmp    L7
L3:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  ja     L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned row_shift_from_symbol_count(unsigned symbol_count) {
  unsigned row_shift = 1;
  symbol_count++;
  while ((unsigned)(1 << row_shift) < symbol_count)
    row_shift++;
  return row_shift;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<row_shift_from_symbol_count>:
  endbr64
  add    $0x1,%edi
  cmp    $0x2,%edi
  jbe    L12
  mov    $0x1,%ecx
  mov    $0x1,%edx
L1:
  add    $0x1,%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %edi,%eax
  jb     L1
L8:
  mov    %ecx,%eax
  ret
L12:
  mov    $0x1,%ecx
  jmp    L8
```

assistant: ```c
unsigned row_shift_from_symbol_count(unsigned symbol_count) {
  unsigned row_shift = 1;
  symbol_count++;
  while ((unsigned)(1 << row_shift) < symbol_count)
    row_shift++;
  return row_shift;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<row_shift_from_symbol_count>:
  endbr64
  add    $0x1,%edi
  mov    $0x1,%ecx
  cmp    $0x2,%edi
  jbe    L13
  mov    $0x1,%edx
  cs nopw 0x0(%rax,%rax,1)
L7:
  add    $0x1,%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %edi,%eax
  jb     L7
L13:
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned row_shift_from_symbol_count(unsigned symbol_count) {
  unsigned row_shift = 1;
  symbol_count++;
  while ((unsigned)(1 << row_shift) < symbol_count)
    row_shift++;
  return row_shift;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<row_shift_from_symbol_count>:
  endbr64
  add    $0x1,%edi
  mov    $0x1,%ecx
  cmp    $0x2,%edi
  jbe    L17
  mov    $0x1,%edx
  cs nopw 0x0(%rax,%rax,1)
L12:
  add    $0x1,%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %edi,%eax
  jb     L12
L17:
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned row_shift_from_symbol_count(unsigned symbol_count) {
  unsigned row_shift = 1;
  symbol_count++;
  while ((unsigned)(1 << row_shift) < symbol_count)
    row_shift++;
  return row_shift;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
L20:
  cmpl   $0x4,-0x4(%rbp)
  jg     L21
  addl   $0x1,-0x4(%rbp)
  jmp    L20
L21:
  cmpl   $0x4,-0x4(%rbp)
  jne    L39
  nop
L23:
  jmp    L23
L39:
  nop
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int counter;
  {
    counter = 0;
  LOOPSTART:
    if (counter < 5) {
      counter = counter + 1;
      goto LOOPSTART;
    } else {
    }
    if (counter == 4) {
      goto ERROR;
    } else {
      goto END;
    }
  ERROR:
    goto ERROR;
  END:
    return (0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int counter;
  {
    counter = 0;
  LOOPSTART:
    if (counter < 5) {
      counter = counter + 1;
      goto LOOPSTART;
    } else {
    }
    if (counter == 4) {
      goto ERROR;
    } else {
      goto END;
    }
  ERROR:
    goto ERROR;
  END:
    return (0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int counter;
  {
    counter = 0;
  LOOPSTART:
    if (counter < 5) {
      counter = counter + 1;
      goto LOOPSTART;
    } else {
    }
    if (counter == 4) {
      goto ERROR;
    } else {
      goto END;
    }
  ERROR:
    goto ERROR;
  END:
    return (0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int counter;
  {
    counter = 0;
  LOOPSTART:
    if (counter < 5) {
      counter = counter + 1;
      goto LOOPSTART;
    } else {
    }
    if (counter == 4) {
      goto ERROR;
    } else {
      goto END;
    }
  ERROR:
    goto ERROR;
  END:
    return (0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    D2(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double foo(double y) {
  double yy = 0;
  errno = 0;
  yy = log(y);
  return yy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  movq   $0x0,(%rax)
  call   <log@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double foo(double y) {
  double yy = 0;
  errno = 0;
  yy = log(y);
  return yy;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  mov    D9(%rip),%rax
  movq   $0x0,(%rax)
  jmp    1050 <log@plt>
```

assistant: ```c
double foo(double y) {
  double yy = 0;
  errno = 0;
  yy = log(y);
  return yy;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  mov    D2(%rip),%rax
  movq   $0x0,(%rax)
  jmp    1050 <log@plt>
```

assistant: ```c
double foo(double y) {
  double yy = 0;
  errno = 0;
  yy = log(y);
  return yy;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L46
  movl   $0x2,-0x4(%rbp)
  jmp    L20
L3:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L12
  mov    $0x0,%eax
  jmp    L7
L12:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L3
L46:
  mov    $0x1,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int isPrime(int n) {
  int r;
  if (n)
    for (r = 2; r * r < n; r++) {
      if (n % r == 0)
        return 0;
    }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPrime>:
  endbr64
  cmp    $0x4,%edi
  jle    L47
  test   $0x1,%dil
  je     L5
  mov    $0x2,%ecx
L10:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jge    L3
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L10
L39:
  ret
L3:
  mov    $0x1,%eax
  ret
L47:
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
int isPrime(int n) {
  int r;
  if (n)
    for (r = 2; r * r < n; r++) {
      if (n % r == 0)
        return 0;
    }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isPrime>:
  endbr64
  cmp    $0x4,%edi
  jle    L36
  test   $0x1,%dil
  je     L33
  mov    $0x2,%ecx
  jmp    L42
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L59
L42:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jl     L55
L36:
  mov    $0x1,%edx
L59:
  mov    %edx,%eax
  ret
L33:
  xor    %edx,%edx
  jmp    L59
```

assistant: ```c
int isPrime(int n) {
  int r;
  if (n)
    for (r = 2; r * r < n; r++) {
      if (n % r == 0)
        return 0;
    }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isPrime>:
  endbr64
  cmp    $0x4,%edi
  jle    L40
  test   $0x1,%dil
  je     L35
  mov    $0x2,%ecx
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L25
L1:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jl     L44
L40:
  mov    $0x1,%edx
L25:
  mov    %edx,%eax
  ret
L35:
  xor    %edx,%edx
  jmp    L25
```

assistant: ```c
int isPrime(int n) {
  int r;
  if (n)
    for (r = 2; r * r < n; r++) {
      if (n % r == 0)
        return 0;
    }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverseBits_fun_uint32_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1f,-0x4(%rbp)
  jmp    L2
L7:
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L2:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    -0x4(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t reverseBits_fun_uint32_t(uint32_t x) {
  uint32_t r = x;
  int i = 31;
  while (x >>= 1) {
    r = (r << 1) | (x & 1);
    --i;
  }
  return r << i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverseBits_fun_uint32_t>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    %edx
  je     L23
  mov    $0x1f,%ecx
L11:
  add    %eax,%eax
  mov    %edx,%esi
  and    $0x1,%esi
  or     %esi,%eax
  sub    $0x1,%ecx
  sar    %edx
  jne    L11
L15:
  shl    %cl,%eax
  ret
L23:
  mov    $0x1f,%ecx
  jmp    L15
```

assistant: ```c
uint32_t reverseBits_fun_uint32_t(uint32_t x) {
  uint32_t r = x;
  int i = 31;
  while (x >>= 1) {
    r = (r << 1) | (x & 1);
    --i;
  }
  return r << i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverseBits_fun_uint32_t>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  mov    $0x1f,%ecx
  sar    %edx
  je     L18
  nopl   0x0(%rax)
L10:
  mov    %edx,%esi
  add    %eax,%eax
  sub    $0x1,%ecx
  and    $0x1,%esi
  or     %esi,%eax
  sar    %edx
  jne    L10
L18:
  shl    %cl,%eax
  ret
```

assistant: ```c
uint32_t reverseBits_fun_uint32_t(uint32_t x) {
  uint32_t r = x;
  int i = 31;
  while (x >>= 1) {
    r = (r << 1) | (x & 1);
    --i;
  }
  return r << i;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverseBits_fun_uint32_t>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  mov    $0x1f,%ecx
  sar    %edx
  je     L18
  nopl   0x0(%rax)
L13:
  mov    %edx,%esi
  add    %eax,%eax
  sub    $0x1,%ecx
  and    $0x1,%esi
  or     %esi,%eax
  sar    %edx
  jne    L13
L18:
  shl    %cl,%eax
  ret
```

assistant: ```c
uint32_t reverseBits_fun_uint32_t(uint32_t x) {
  uint32_t r = x;
  int i = 31;
  while (x >>= 1) {
    r = (r << 1) | (x & 1);
    --i;
  }
  return r << i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<editdist_dp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %ecx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    -0x48(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  cmpl   $0x0,-0x44(%rbp)
  jne    L41
  mov    -0x48(%rbp),%eax
  jmp    L3
L41:
  cmpl   $0x0,-0x48(%rbp)
  jne    L10
  mov    -0x44(%rbp),%eax
  jmp    L3
L10:
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x48(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L15
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x48(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  jmp    L3
L15:
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%edx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <editdist_dp>
  add    $0x1,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x48(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x50(%rbp),%rdi
  mov    -0x44(%rbp),%edx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <editdist_dp>
  add    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x48(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x50(%rbp),%rdi
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <editdist_dp>
  mov    %eax,%ecx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x48(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x40(%rbp),%rax
  add    %rsi,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  setne  %al
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <minthree@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    -0x1c(%rbp),%eax
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int editdist_dp(char str1[], char str2[], int m, int n, int table[][n]) {
  if (m == 0) {
    return n;
  }
  if (n == 0) {
    return m;
  }
  if (table[m][n] != 0) {
    return table[m][n];
  }
  int left = editdist_dp(str1, str2, m - 1, n, table) + 1;
  int right = editdist_dp(str1, str2, m, n - 1, table) + 1;
  int corner = editdist_dp(str1, str2, m - 1, n - 1, table) + (str1[m] == str2[n] ? 0 : 1);
  int res = minthree(left, right, corner);
  table[m][n] = res;
  return res;
}
```