ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <getuid@plt>
  mov    D20(%rip),%rbp
  mov    D24(%rip),%rbx
  mov    %eax,%r12d
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <QCMD@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    D34(%rip),%rax
  mov    (%rax),%edi
  call   <QCMD@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <quotactl@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <QCMD@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    $0xffffffffffffffff,%rsi
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <QCMD@plt>
  mov    %r13,%rcx
  mov    $0xffffffff,%edx
  xor    %esi,%esi
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <QCMD@plt>
  xor    %esi,%esi
  mov    $0xffffffffffffffff,%rcx
  mov    %r12d,%edx
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct dqblk dqblk;
  uid_t uid;
  uid = getuid();
  quotactl(QCMD(Q_GETQUOTA, USRQUOTA), NULL, uid, (caddr_t)&dqblk);
  quotactl(QCMD(Q_SYNC, GRPQUOTA), NULL, 0, NULL);
  quotactl(-1, NULL, uid, (caddr_t)&dqblk);
  quotactl(QCMD(Q_GETQUOTA, USRQUOTA), (char *)-1, uid, (caddr_t)&dqblk);
  quotactl(QCMD(Q_GETQUOTA, USRQUOTA), NULL, -1, (caddr_t)&dqblk);
  quotactl(QCMD(Q_GETQUOTA, USRQUOTA), NULL, uid, (caddr_t)-1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <getuid@plt>
  mov    D30(%rip),%rbp
  mov    D10(%rip),%rbx
  mov    %eax,%r12d
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <QCMD@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <QCMD@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <quotactl@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <QCMD@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    $0xffffffffffffffff,%rsi
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <QCMD@plt>
  mov    %r13,%rcx
  mov    $0xffffffff,%edx
  xor    %esi,%esi
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <QCMD@plt>
  xor    %esi,%esi
  mov    $0xffffffffffffffff,%rcx
  mov    %r12d,%edx
  mov    %eax,%edi
  call   <quotactl@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct dqblk dqblk;
  uid_t uid;
  uid = getuid();
  quotactl(QCMD(Q_GETQUOTA, USRQUOTA), NULL, uid, (caddr_t)&dqblk);
  quotactl(QCMD(Q_SYNC, GRPQUOTA), NULL, 0, NULL);
  quotactl(-1, NULL, uid, (caddr_t)&dqblk);
  quotactl(QCMD(Q_GETQUOTA, USRQUOTA), (char *)-1, uid, (caddr_t)&dqblk);
  quotactl(QCMD(Q_GETQUOTA, USRQUOTA), NULL, -1, (caddr_t)&dqblk);
  quotactl(QCMD(Q_GETQUOTA, USRQUOTA), NULL, uid, (caddr_t)-1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PreEchoControl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movss  %xmm0,-0x20(%rbp)
  movss  %xmm1,-0x24(%rbp)
  mov    %rdx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L27:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x20(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x24(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L31
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
L31:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  movss  -0x4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L8
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
L8:
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PreEchoControl(float *pbThresholdNm1, int numPb, float maxAllowedIncreaseFactor, float minRemainingThresholdFactor, float *pbThreshold) {
  int i;
  float tmpThreshold1, tmpThreshold2;
  ;
  ;
  ;
  for (i = 0; i < numPb; i++) {
    ;
    tmpThreshold1 = maxAllowedIncreaseFactor * (pbThresholdNm1[i]);
    tmpThreshold2 = minRemainingThresholdFactor * pbThreshold[i];
    ;
    pbThresholdNm1[i] = pbThreshold[i];
    ;
    ;
    if (pbThreshold[i] > tmpThreshold1) {
      ;
      pbThreshold[i] = tmpThreshold1;
    };
    ;
    if (tmpThreshold2 > pbThreshold[i]) {
      ;
      pbThreshold[i] = tmpThreshold2;
    }
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PreEchoControl>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rsi
  jmp    L47
L6:
  add    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rsi,%rax
  je     L8
L47:
  movaps %xmm0,%xmm4
  mulss  (%rax),%xmm4
  mov    %rdx,%rcx
  movss  (%rdx),%xmm2
  movaps %xmm2,%xmm3
  mulss  %xmm1,%xmm3
  movss  %xmm2,(%rax)
  comiss %xmm4,%xmm2
  jbe    L9
  movss  %xmm4,(%rdx)
L9:
  comiss (%rcx),%xmm3
  jbe    L6
  movss  %xmm3,(%rcx)
  jmp    L6
L8:
  ret
```

assistant: ```c
void PreEchoControl(float *pbThresholdNm1, int numPb, float maxAllowedIncreaseFactor, float minRemainingThresholdFactor, float *pbThreshold) {
  int i;
  float tmpThreshold1, tmpThreshold2;
  ;
  ;
  ;
  for (i = 0; i < numPb; i++) {
    ;
    tmpThreshold1 = maxAllowedIncreaseFactor * (pbThresholdNm1[i]);
    tmpThreshold2 = minRemainingThresholdFactor * pbThreshold[i];
    ;
    pbThresholdNm1[i] = pbThreshold[i];
    ;
    ;
    if (pbThreshold[i] > tmpThreshold1) {
      ;
      pbThreshold[i] = tmpThreshold1;
    };
    ;
    if (tmpThreshold2 > pbThreshold[i]) {
      ;
      pbThreshold[i] = tmpThreshold2;
    }
  };
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PreEchoControl>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
L10:
  movss  (%rdi),%xmm3
  movss  (%rdx),%xmm2
  mulss  %xmm0,%xmm3
  movaps %xmm2,%xmm4
  movss  %xmm2,(%rdi)
  mulss  %xmm1,%xmm4
  comiss %xmm3,%xmm2
  jbe    L25
  movss  %xmm3,(%rdx)
  movaps %xmm3,%xmm2
L25:
  comiss %xmm2,%xmm4
  jbe    L39
  movss  %xmm4,(%rdx)
L39:
  add    $0x4,%rdi
  add    $0x4,%rdx
  cmp    %rax,%rdi
  jne    L10
L21:
  ret
```

assistant: ```c
void PreEchoControl(float *pbThresholdNm1, int numPb, float maxAllowedIncreaseFactor, float minRemainingThresholdFactor, float *pbThreshold) {
  int i;
  float tmpThreshold1, tmpThreshold2;
  ;
  ;
  ;
  for (i = 0; i < numPb; i++) {
    ;
    tmpThreshold1 = maxAllowedIncreaseFactor * (pbThresholdNm1[i]);
    tmpThreshold2 = minRemainingThresholdFactor * pbThreshold[i];
    ;
    pbThresholdNm1[i] = pbThreshold[i];
    ;
    ;
    if (pbThreshold[i] > tmpThreshold1) {
      ;
      pbThreshold[i] = tmpThreshold1;
    };
    ;
    if (tmpThreshold2 > pbThreshold[i]) {
      ;
      pbThreshold[i] = tmpThreshold2;
    }
  };
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PreEchoControl>:
  endbr64
  test   %esi,%esi
  jle    L36
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
L8:
  movss  (%rdi),%xmm3
  movss  (%rdx),%xmm2
  mulss  %xmm0,%xmm3
  movaps %xmm2,%xmm4
  movss  %xmm2,(%rdi)
  mulss  %xmm1,%xmm4
  comiss %xmm3,%xmm2
  jbe    L39
  movss  %xmm3,(%rdx)
  movaps %xmm3,%xmm2
L39:
  comiss %xmm2,%xmm4
  jbe    L9
  movss  %xmm4,(%rdx)
L9:
  add    $0x4,%rdi
  add    $0x4,%rdx
  cmp    %rax,%rdi
  jne    L8
L36:
  ret
```

assistant: ```c
void PreEchoControl(float *pbThresholdNm1, int numPb, float maxAllowedIncreaseFactor, float minRemainingThresholdFactor, float *pbThreshold) {
  int i;
  float tmpThreshold1, tmpThreshold2;
  ;
  ;
  ;
  for (i = 0; i < numPb; i++) {
    ;
    tmpThreshold1 = maxAllowedIncreaseFactor * (pbThresholdNm1[i]);
    tmpThreshold2 = minRemainingThresholdFactor * pbThreshold[i];
    ;
    pbThresholdNm1[i] = pbThreshold[i];
    ;
    ;
    if (pbThreshold[i] > tmpThreshold1) {
      ;
      pbThreshold[i] = tmpThreshold1;
    };
    ;
    if (tmpThreshold2 > pbThreshold[i]) {
      ;
      pbThreshold[i] = tmpThreshold2;
    }
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_cr0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %cr0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long read_cr0(void) {
  unsigned long cr0;
  asm volatile("mov %%cr0, %0" : "=r"(cr0));
  return cr0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_cr0>:
  endbr64
  mov    %cr0,%rax
  ret
```

assistant: ```c
unsigned long read_cr0(void) {
  unsigned long cr0;
  asm volatile("mov %%cr0, %0" : "=r"(cr0));
  return cr0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_cr0>:
  endbr64
  mov    %cr0,%rax
  ret
```

assistant: ```c
unsigned long read_cr0(void) {
  unsigned long cr0;
  asm volatile("mov %%cr0, %0" : "=r"(cr0));
  return cr0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_cr0>:
  endbr64
  mov    %cr0,%rax
  ret
```

assistant: ```c
unsigned long read_cr0(void) {
  unsigned long cr0;
  asm volatile("mov %%cr0, %0" : "=r"(cr0));
  return cr0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: Hello world (%s)!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello world (%s)!\n", argv[0]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: Hello world (%s)!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello world (%s)!\n", argv[0]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: Hello world (%s)!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello world (%s)!\n", argv[0]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: Hello world (%s)!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello world (%s)!\n", argv[0]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insertionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L39
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L35
L37:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swapValue@plt>
  subl   $0x1,-0xc(%rbp)
L35:
  cmpl   $0x0,-0xc(%rbp)
  js     L43
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L37
L43:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void insertionSort(int arr[], int arrLength) {
  int j = 0;
  for (int i = 1; i < arrLength; ++i) {
    int tempValue = arr[i];
    for (j = i - 1; j >= 0 && arr[j] > tempValue; --j) {
      swapValue(arr, j, j + 1);
    }
    arr[j + 1] = tempValue;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertionSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L33
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r14d
  mov    $0x0,%r13d
  jmp    L69
L24:
  movslq %esi,%rsi
  mov    %r12d,0x4(%rbp,%rsi,4)
  add    $0x1,%r13
  cmp    %r14,%r13
  je     L37
L69:
  mov    0x4(%rbp,%r13,4),%r12d
  mov    %r13d,%esi
  mov    %r13,%rbx
  test   %r13d,%r13d
  js     L24
L6:
  mov    %ebx,%esi
  cmp    %r12d,0x0(%rbp,%rbx,4)
  jle    L24
  lea    0x1(%rbx),%edx
  mov    %rbp,%rdi
  call   <swapValue@plt>
  lea    -0x1(%rbx),%esi
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L6
  jmp    L24
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  ret
```

assistant: ```c
void insertionSort(int arr[], int arrLength) {
  int j = 0;
  for (int i = 1; i < arrLength; ++i) {
    int tempValue = arr[i];
    for (j = i - 1; j >= 0 && arr[j] > tempValue; --j) {
      swapValue(arr, j, j + 1);
    }
    arr[j + 1] = tempValue;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertionSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L46
  push   %r14
  lea    -0x1(%rsi),%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    0x4(%rbp,%r13,4),%r12d
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %ebx,%esi
  lea    0x1(%rbx),%edx
  cmp    %r12d,0x0(%rbp,%rbx,4)
  jle    L1
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <swapValue@plt>
  cmp    $0xffffffff,%ebx
  jne    L23
  mov    %rbp,%rax
L47:
  add    $0x1,%r13
  mov    %r12d,(%rax)
  cmp    %r13,%r14
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L1:
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rax
  jmp    L47
L46:
  ret
```

assistant: ```c
void insertionSort(int arr[], int arrLength) {
  int j = 0;
  for (int i = 1; i < arrLength; ++i) {
    int tempValue = arr[i];
    for (j = i - 1; j >= 0 && arr[j] > tempValue; --j) {
      swapValue(arr, j, j + 1);
    }
    arr[j + 1] = tempValue;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insertionSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L38
  push   %r14
  lea    -0x1(%rsi),%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    0x4(%rbp,%r13,4),%r12d
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %ebx,%esi
  lea    0x1(%rbx),%edx
  cmp    %r12d,0x0(%rbp,%rbx,4)
  jle    L46
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <swapValue@plt>
  cmp    $0xffffffff,%ebx
  jne    L21
  mov    %rbp,%rax
L47:
  add    $0x1,%r13
  mov    %r12d,(%rax)
  cmp    %r13,%r14
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L46:
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rax
  jmp    L47
L38:
  ret
```

assistant: ```c
void insertionSort(int arr[], int arrLength) {
  int j = 0;
  for (int i = 1; i < arrLength; ++i) {
    int tempValue = arr[i];
    for (j = i - 1; j >= 0 && arr[j] > tempValue; --j) {
      swapValue(arr, j, j + 1);
    }
    arr[j + 1] = tempValue;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ClearIntegerArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ClearIntegerArray(int array[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    array[i] = 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ClearIntegerArray>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L5:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L5
L4:
  ret
```

assistant: ```c
void ClearIntegerArray(int array[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    array[i] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ClearIntegerArray>:
  endbr64
  test   %esi,%esi
  jle    L9
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void ClearIntegerArray(int array[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    array[i] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ClearIntegerArray>:
  endbr64
  test   %esi,%esi
  jle    L6
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void ClearIntegerArray(int array[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    array[i] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x4(%rbp)
  mov    $0x0,%eax
  call   <foo@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = -1;
  x = foo();
#pragma omp taskwait
  assert(x == 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = -1;
  x = foo();
#pragma omp taskwait
  assert(x == 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = -1;
  x = foo();
#pragma omp taskwait
  assert(x == 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = -1;
  x = foo();
#pragma omp taskwait
  assert(x == 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getEnumWhoriz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%edx
  lea    -0x17(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x1,-0x2c(%rbp)
  jmp    L8
L22:
  mov    -0x2c(%rbp),%edx
  lea    -0x17(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x17(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x2c(%rbp)
L8:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L22
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5: %d

assistant: ```c
int *getEnumWhoriz(int max) {
  int i;
  char buf[15];
  sprintf(buf, "%d", max);
  int *horizontalSpacingWidth = malloc(sizeof(int) * max);
  int tmp_width;
  const int sep = 3;
  for (i = 1; i <= max; i++) {
    sprintf(buf, "%d", i);
    tmp_width = strlen(buf);
    horizontalSpacingWidth[i] = sep - tmp_width;
  }
  return horizontalSpacingWidth;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getEnumWhoriz>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rdi
  mov    %ebp,%edx
  lea    D14(%rip),%rsi
  call   <sprintf@plt>
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L2
  mov    $0x1,%ebx
  lea    D14(%rip),%r13
L7:
  lea    0x9(%rsp),%r14
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L7
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    %r12,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
datatype: string

tool: D14: %d

assistant: ```c
int *getEnumWhoriz(int max) {
  int i;
  char buf[15];
  sprintf(buf, "%d", max);
  int *horizontalSpacingWidth = malloc(sizeof(int) * max);
  int tmp_width;
  const int sep = 3;
  for (i = 1; i <= max; i++) {
    sprintf(buf, "%d", i);
    tmp_width = strlen(buf);
    horizontalSpacingWidth[i] = sep - tmp_width;
  }
  return horizontalSpacingWidth;
}
```