ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sigint_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <curses_stop@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <bail@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: got SIGINT, cleaning up

assistant: ```c
void sigint_handler() {
  curses_stop();
  bail("got SIGINT, cleaning up");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sigint_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <curses_stop@plt>
  lea    D2(%rip),%rdi
  call   <bail@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2: got SIGINT, cleaning up

assistant: ```c
void sigint_handler() {
  curses_stop();
  bail("got SIGINT, cleaning up");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sigint_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <curses_stop@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <bail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: got SIGINT, cleaning up

assistant: ```c
void sigint_handler() {
  curses_stop();
  bail("got SIGINT, cleaning up");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sigint_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <curses_stop@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <bail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: got SIGINT, cleaning up

assistant: ```c
void sigint_handler() {
  curses_stop();
  bail("got SIGINT, cleaning up");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sheet_cell_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x1,-0x10(%rbp)
  jbe    L0
  mov    $0x9,%edi
  call   <putchar@plt>
L0:
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %s

assistant: ```c
int sheet_cell_callback(size_t row, size_t col, const char *value, void *callbackdata) {
  if (col > 1)
    printf("\t");
  if (value)
    printf("%s", value);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<sheet_cell_callback>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  cmp    $0x1,%rsi
  ja     L2
L26:
  test   %rbx,%rbx
  je     L14
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  pop    %rbx
  ret
L2:
  mov    $0x9,%edi
  call   <putchar@plt>
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: %s

assistant: ```c
int sheet_cell_callback(size_t row, size_t col, const char *value, void *callbackdata) {
  if (col > 1)
    printf("\t");
  if (value)
    printf("%s", value);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<sheet_cell_callback>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  cmp    $0x1,%rsi
  jbe    L5
  mov    $0x9,%edi
  call   <putchar@plt>
L5:
  test   %rbp,%rbp
  je     L16
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L16:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string

tool: D7: %s

assistant: ```c
int sheet_cell_callback(size_t row, size_t col, const char *value, void *callbackdata) {
  if (col > 1)
    printf("\t");
  if (value)
    printf("%s", value);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sheet_cell_callback>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  cmp    $0x1,%rsi
  jbe    L15
  mov    $0x9,%edi
  call   <putchar@plt>
L15:
  test   %rbp,%rbp
  je     L9
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L9:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type: string

tool: D6: %s

assistant: ```c
int sheet_cell_callback(size_t row, size_t col, const char *value, void *callbackdata) {
  if (col > 1)
    printf("\t");
  if (value)
    printf("%s", value);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <perfect_shuffle3@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L15
L14:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x2,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void shuffle(int *a, int n) {
  int i, t, n2 = n * 2;
  perfect_shuffle3(a, n);
  for (i = 2; i <= n2; i += 2) {
    t = a[i - 1];
    a[i - 1] = a[i];
    a[i] = t;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shuffle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    (%rsi,%rsi,1),%ebx
  call   <perfect_shuffle3@plt>
  cmp    $0x1,%ebx
  jle    L17
  lea    0x4(%rbp),%rax
  sub    $0x2,%ebx
  shr    %ebx
  mov    %ebx,%ebx
  lea    0xc(%rbp,%rbx,8),%rsi
L12:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L12
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void shuffle(int *a, int n) {
  int i, t, n2 = n * 2;
  perfect_shuffle3(a, n);
  for (i = 2; i <= n2; i += 2) {
    t = a[i - 1];
    a[i - 1] = a[i];
    a[i] = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    (%rsi,%rsi,1),%ebx
  sub    $0x8,%rsp
  call   <perfect_shuffle3@plt>
  cmp    $0x1,%ebx
  jle    L15
  sub    $0x2,%ebx
  lea    0x4(%rbp),%rax
  shr    %ebx
  lea    0xc(%rbp,%rbx,8),%rsi
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  add    $0x8,%rax
  mov    %ecx,-0x8(%rax)
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L13
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void shuffle(int *a, int n) {
  int i, t, n2 = n * 2;
  perfect_shuffle3(a, n);
  for (i = 2; i <= n2; i += 2) {
    t = a[i - 1];
    a[i - 1] = a[i];
    a[i] = t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shuffle>:
  endbr64
  push   %rbp
  lea    (%rsi,%rsi,1),%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <perfect_shuffle3@plt>
  cmp    $0x1,%ebp
  jle    L15
  sub    $0x2,%ebp
  mov    %ebp,%ecx
  shr    %ecx
  add    $0x1,%ecx
  cmp    $0x1,%ebp
  jbe    L14
  mov    %ecx,%edx
  lea    0x4(%rbx),%rax
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x14(%rbx,%rdx,1),%rdx
  nopl   (%rax)
L47:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  pshufd $0xb1,%xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L47
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L15
L10:
  rolq   $0x20,0x4(%rbx,%rax,8)
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  xor    %eax,%eax
  jmp    L10
```

assistant: ```c
void shuffle(int *a, int n) {
  int i, t, n2 = n * 2;
  perfect_shuffle3(a, n);
  for (i = 2; i <= n2; i += 2) {
    t = a[i - 1];
    a[i - 1] = a[i];
    a[i] = t;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <createArray@plt>
  mov    %rax,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <display@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D0: How many elements would you like to have on your list?


tool: D19: %d

tool: D5: The elements you have entered are 

assistant: ```c
int main() {
  int len = 0, *arr = NULL;
  printf("How many elements would you like to have on your list?\n");
  scanf("%d", &len);
  arr = createArray(len);
  printf("The elements you have entered are ");
  display(arr, len);
  free(arr);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <createArray@plt>
  mov    %rax,%rbx
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <display@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D5
type: string
name: read_data
arguments: label: D17
type: string

tool: D29: How many elements would you like to have on your list?


tool: D5: %d

tool: D17: The elements you have entered are 

assistant: ```c
int main() {
  int len = 0, *arr = NULL;
  printf("How many elements would you like to have on your list?\n");
  scanf("%d", &len);
  arr = createArray(len);
  printf("The elements you have entered are ");
  display(arr, len);
  free(arr);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <createArray@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <display@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D0: How many elements would you like to have on your list?


tool: D10: %d

tool: D4: The elements you have entered are 

assistant: ```c
int main() {
  int len = 0, *arr = NULL;
  printf("How many elements would you like to have on your list?\n");
  scanf("%d", &len);
  arr = createArray(len);
  printf("The elements you have entered are ");
  display(arr, len);
  free(arr);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <createArray@plt>
  lea    D11(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <display@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D27
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D27: How many elements would you like to have on your list?


tool: D1: %d

tool: D11: The elements you have entered are 

assistant: ```c
int main() {
  int len = 0, *arr = NULL;
  printf("How many elements would you like to have on your list?\n");
  scanf("%d", &len);
  arr = createArray(len);
  printf("The elements you have entered are ");
  display(arr, len);
  free(arr);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<subst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L23
L9:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L24
  addq   $0x1,-0x8(%rbp)
  jmp    L23
L24:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L23:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void subst(char *buf, const char *from, const char *to) {
  char *p = buf;
  int fromlen = strlen(from);
  int tolen = strlen(to);
  while (p = strstr(p, from)) {
    if (isalnum(p[fromlen])) {
      p++;
      continue;
    }
    memmove(p + tolen, p + fromlen, strlen(p + fromlen) + 1);
    memcpy(p, to, tolen);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<subst>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  movslq %ebp,%rbp
  jmp    L20
L28:
  mov    %r15,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  movslq %r13d,%rdi
  add    %rbx,%rdi
  mov    %r15,%rsi
  call   <memmove@plt>
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
L20:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L25
  lea    (%rbx,%rbp,1),%r15
  movsbl (%r15),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L28
  add    $0x1,%rbx
  jmp    L20
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void subst(char *buf, const char *from, const char *to) {
  char *p = buf;
  int fromlen = strlen(from);
  int tolen = strlen(to);
  while (p = strstr(p, from)) {
    if (isalnum(p[fromlen])) {
      p++;
      continue;
    }
    memmove(p + tolen, p + fromlen, strlen(p + fromlen) + 1);
    memcpy(p, to, tolen);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<subst>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r15,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    %eax,%r14d
  nopl   0x0(%rax)
L10:
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L24
  lea    0x0(%rbp,%rbx,1),%r12
  movsbl (%r12),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L16
  add    $0x1,%rbp
  jmp    L10
  nopl   (%rax)
L16:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %r14d,%rdi
  mov    %r12,%rsi
  add    %rbp,%rdi
  lea    0x1(%rax),%edx
  call   <memmove@plt>
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  jmp    L10
  nopl   0x0(%rax)
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void subst(char *buf, const char *from, const char *to) {
  char *p = buf;
  int fromlen = strlen(from);
  int tolen = strlen(to);
  while (p = strstr(p, from)) {
    if (isalnum(p[fromlen])) {
      p++;
      continue;
    }
    memmove(p + tolen, p + fromlen, strlen(p + fromlen) + 1);
    memcpy(p, to, tolen);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<subst>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r15,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    %eax,%r14d
  nopl   0x0(%rax)
L8:
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L5
  lea    0x0(%rbp,%rbx,1),%r12
  movsbl (%r12),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L25
  add    $0x1,%rbp
  jmp    L8
  nopl   (%rax)
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %r14d,%rdi
  mov    %r12,%rsi
  add    %rbp,%rdi
  lea    0x1(%rax),%edx
  call   <memmove@plt>
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  jmp    L8
  nopl   0x0(%rax)
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void subst(char *buf, const char *from, const char *to) {
  char *p = buf;
  int fromlen = strlen(from);
  int tolen = strlen(to);
  while (p = strstr(p, from)) {
    if (isalnum(p[fromlen])) {
      p++;
      continue;
    }
    memmove(p + tolen, p + fromlen, strlen(p + fromlen) + 1);
    memcpy(p, to, tolen);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convert_to_hex>:
  endbr64
  push   %rbx
  movb   $0x23,(%rdi)
  mov    %rsi,%r10
  mov    $0x2,%r9d
  lea    D0(%rip),%r8
  lea    -0x2(%rdi),%r11
  jmp    L20
L74:
  sub    $0xa,%eax
  cmp    $0x5,%eax
  ja     L17
  mov    %eax,%eax
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  movslq %ecx,%rax
  movb   $0x61,(%rdi,%rax,1)
L17:
  mov    (%rsi),%edx
  test   %edx,%edx
  jle    L34
  sub    $0x1,%ecx
L3:
  mov    %edx,%ebx
  sar    $0x1f,%ebx
  shr    $0x1c,%ebx
  lea    (%rdx,%rbx,1),%eax
  and    $0xf,%eax
  sub    %ebx,%eax
  lea    0xf(%rdx),%ebx
  test   %edx,%edx
  cmovs  %ebx,%edx
  sar    $0x4,%edx
  mov    %edx,(%rsi)
  cmp    $0x9,%eax
  jg     L74
  movslq %ecx,%rdx
  add    $0x30,%eax
  mov    %al,(%rdi,%rdx,1)
  jmp    L17
  movslq %ecx,%rax
  movb   $0x62,(%rdi,%rax,1)
  jmp    L17
  movslq %ecx,%rax
  movb   $0x63,(%rdi,%rax,1)
  jmp    L17
  movslq %ecx,%rax
  movb   $0x64,(%rdi,%rax,1)
  jmp    L17
  movslq %ecx,%rax
  movb   $0x65,(%rdi,%rax,1)
  jmp    L17
  movslq %ecx,%rax
  movb   $0x66,(%rdi,%rax,1)
  jmp    L17
L34:
  lea    -0x1(%r9),%eax
  cmp    %eax,%ecx
  jle    L18
  movslq %ecx,%rdx
  lea    -0x1(%rdi,%rdx,1),%rax
  add    %r11,%rdx
  sub    %r9d,%ecx
  sub    %rcx,%rdx
L135:
  movb   $0x30,(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L135
L18:
  add    $0x4,%r10
  add    $0x2,%r9d
  cmp    $0x8,%r9d
  je     L88
L20:
  mov    %r9d,%ecx
  mov    %r10,%rsi
  mov    (%r10),%edx
  test   %edx,%edx
  jg     L3
  jmp    L34
L88:
  pop    %rbx
  ret
```

assistant: ```c
void convert_to_hex(char number[], int con_nums[]) {
  number[0] = '#';
  int check, position;
  for (int i = 0; i < 3; i++) {
    position = 2 + i * 2;
    while (con_nums[i] > 0) {
      check = con_nums[i] % 16;
      con_nums[i] /= 16;
      if (check < 10) {
        number[position] = check + '0';
      } else {
        switch (check) {
        case 10:
          number[position] = 'a';
          break;
        case 11:
          number[position] = 'b';
          break;
        case 12:
          number[position] = 'c';
          break;
        case 13:
          number[position] = 'd';
          break;
        case 14:
          number[position] = 'e';
          break;
        case 15:
          number[position] = 'f';
          break;
        }
      }
      if (con_nums[i] > 0) {
        position--;
      }
    }
    while (position > i * 2 + 1) {
      position--;
      number[position] = '0';
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_to_hex>:
  endbr64
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movb   $0x23,(%rdi)
L121:
  mov    (%rbx),%edx
  mov    %r13d,%esi
  test   %edx,%edx
  jle    L114
  nopl   (%rax)
L74:
  mov    %edx,%eax
  movslq %esi,%rcx
  sar    $0x4,%edx
  and    $0xf,%eax
  add    %rbp,%rcx
  cmp    $0x9,%eax
  jg     L12
  add    $0x30,%eax
L88:
  mov    %edx,(%rbx)
  mov    %al,(%rcx)
  mov    (%rbx),%edx
  test   %edx,%edx
  jle    L114
L113:
  sub    $0x1,%esi
  jmp    L74
  nopl   (%rax)
L12:
  sub    $0xb,%eax
  cmp    $0x4,%eax
  ja     L9
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  xchg   %ax,%ax
  mov    $0x62,%eax
  mov    %edx,(%rbx)
  mov    %al,(%rcx)
  mov    (%rbx),%edx
  test   %edx,%edx
  jg     L113
  nop
L114:
  lea    -0x1(%r13),%eax
  cmp    %esi,%eax
  jge    L51
  mov    %esi,%eax
  movslq %esi,%rdi
  mov    $0x30,%esi
  sub    %r13d,%eax
  sub    $0x1,%rdi
  sub    %rax,%rdi
  lea    0x1(%rax),%rdx
  add    %rbp,%rdi
  call   <memset@plt>
L51:
  add    $0x2,%r13d
  add    $0x4,%rbx
  cmp    $0x8,%r13d
  jne    L121
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
  mov    $0x66,%eax
  jmp    L88
  nopw   0x0(%rax,%rax,1)
  mov    $0x65,%eax
  jmp    L88
  nopw   0x0(%rax,%rax,1)
  mov    $0x64,%eax
  jmp    L88
  nopw   0x0(%rax,%rax,1)
  mov    $0x63,%eax
  jmp    L88
L9:
  mov    $0x61,%eax
  jmp    L88
```

assistant: ```c
void convert_to_hex(char number[], int con_nums[]) {
  number[0] = '#';
  int check, position;
  for (int i = 0; i < 3; i++) {
    position = 2 + i * 2;
    while (con_nums[i] > 0) {
      check = con_nums[i] % 16;
      con_nums[i] /= 16;
      if (check < 10) {
        number[position] = check + '0';
      } else {
        switch (check) {
        case 10:
          number[position] = 'a';
          break;
        case 11:
          number[position] = 'b';
          break;
        case 12:
          number[position] = 'c';
          break;
        case 13:
          number[position] = 'd';
          break;
        case 14:
          number[position] = 'e';
          break;
        case 15:
          number[position] = 'f';
          break;
        }
      }
      if (con_nums[i] > 0) {
        position--;
      }
    }
    while (position > i * 2 + 1) {
      position--;
      number[position] = '0';
    }
  }
}
```