ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: Hello world


assistant: ```c
int main(int argc, char **argv) {
  printf("Hello world\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  movzbl (%rax),%esi
  sub    $0x6b,%esi
  test   $0x8,%sil
  je     L2
  test   $0x1,%sil
  je     L17
  lea    0x0(,%rsi,8),%edx
  and    $0x78,%edx
  or     %esi,%edx
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %edx,%eax
  jmp    L16
L17:
  mov    %esi,%eax
  imul   %esi,%eax
  mov    %eax,%esi
  lea    (%rsi,%rsi,1),%eax
  jmp    L16
L2:
  movzbl %sil,%eax
  mov    %esi,%r8d
  and    $0xe,%r8d
  or     $0x1,%r8d
  mov    $0x8,%ecx
  sub    %r8d,%ecx
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%eax
  or     %eax,%edx
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %esi,%eax
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%al
L16:
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        if (state[0UL] & (unsigned char)1) {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
          state[0UL] |= (state[0UL] & (unsigned char)7) << 2UL;
        } else {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
          state[0UL] |= (((state[0UL] >> ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] << (8 - ((state[0UL] & (unsigned char)15) | 1UL)))) & (unsigned char)31) << 4UL;
        }
      } else {
        state[0UL] *= state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - ((state[0UL] & (unsigned char)15) | 1UL)))) & (unsigned char)7) << 2UL;
      state[0UL] = (state[0UL] << ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - ((state[0UL] & (unsigned char)15) | 1UL)));
    }
    output[0UL] = (((state[0UL] >> (unsigned char)7) | (state[0UL] << (unsigned char)1)) >> (unsigned char)1) | (((state[0UL] >> (unsigned char)7) | (state[0UL] << (unsigned char)1)) << (unsigned char)7);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  movzbl (%r8),%esi
  sub    $0x6b,%esi
  movzbl %sil,%eax
  test   $0x8,%sil
  je     L19
  test   $0x1,%sil
  je     L17
  lea    0x0(,%rax,8),%edx
  and    $0x78,%edx
  or     %esi,%edx
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
  nopl   0x0(%rax)
L19:
  mov    %esi,%r8d
  mov    $0x8,%ecx
  and    $0xe,%r8d
  or     $0x1,%r8d
  movzbl %r8b,%edx
  sub    %edx,%ecx
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%eax
  or     %eax,%edx
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %esi,%eax
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%al
  mov    %al,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %esi,%eax
  imul   %esi,%eax
  mov    %eax,%esi
  lea    (%rsi,%rsi,1),%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        if (state[0UL] & (unsigned char)1) {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
          state[0UL] |= (state[0UL] & (unsigned char)7) << 2UL;
        } else {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
          state[0UL] |= (((state[0UL] >> ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] << (8 - ((state[0UL] & (unsigned char)15) | 1UL)))) & (unsigned char)31) << 4UL;
        }
      } else {
        state[0UL] *= state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - ((state[0UL] & (unsigned char)15) | 1UL)))) & (unsigned char)7) << 2UL;
      state[0UL] = (state[0UL] << ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - ((state[0UL] & (unsigned char)15) | 1UL)));
    }
    output[0UL] = (((state[0UL] >> (unsigned char)7) | (state[0UL] << (unsigned char)1)) >> (unsigned char)1) | (((state[0UL] >> (unsigned char)7) | (state[0UL] << (unsigned char)1)) << (unsigned char)7);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  movzbl (%r8),%esi
  sub    $0x6b,%esi
  movzbl %sil,%eax
  test   $0x8,%sil
  je     L3
  test   $0x1,%sil
  je     L17
  lea    0x0(,%rax,8),%edx
  and    $0x78,%edx
  or     %esi,%edx
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
  nopl   0x0(%rax)
L3:
  mov    %esi,%r8d
  mov    $0x8,%ecx
  and    $0xe,%r8d
  or     $0x1,%r8d
  movzbl %r8b,%edx
  sub    %edx,%ecx
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%eax
  or     %eax,%edx
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %esi,%eax
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%al
  mov    %al,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %esi,%eax
  imul   %esi,%eax
  mov    %eax,%esi
  lea    (%rsi,%rsi,1),%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    if ((state[0UL] >> (unsigned char)3) & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        if (state[0UL] & (unsigned char)1) {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
          state[0UL] |= (state[0UL] & (unsigned char)7) << 2UL;
        } else {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
          state[0UL] |= (((state[0UL] >> ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] << (8 - ((state[0UL] & (unsigned char)15) | 1UL)))) & (unsigned char)31) << 4UL;
        }
      } else {
        state[0UL] *= state[0UL];
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] |= (((state[0UL] << ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - ((state[0UL] & (unsigned char)15) | 1UL)))) & (unsigned char)7) << 2UL;
      state[0UL] = (state[0UL] << ((state[0UL] & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - ((state[0UL] & (unsigned char)15) | 1UL)));
    }
    output[0UL] = (((state[0UL] >> (unsigned char)7) | (state[0UL] << (unsigned char)1)) >> (unsigned char)1) | (((state[0UL] >> (unsigned char)7) | (state[0UL] << (unsigned char)1)) << (unsigned char)7);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<checksum_datagram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <checksum_ipv4_hdr@plt>
  test   %rax,%rax
  je     L39
  mov    $0xffffffff,%eax
  jmp    L32
L39:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <checksum_tcp_hdr@plt>
  test   %rax,%rax
  je     L19
  mov    $0xffffffff,%eax
  jmp    L32
L19:
  mov    $0x0,%eax
L32:
  leave
  ret
```

assistant: ```c
int checksum_datagram(struct tcp_ip_datagram *datagram) {
  if (checksum_ipv4_hdr(datagram) != 0) {
    return -1;
  }
  if (checksum_tcp_hdr(datagram) != 0) {
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checksum_datagram>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <checksum_ipv4_hdr@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbx,%rdi
  call   <checksum_tcp_hdr@plt>
  neg    %rax
  sbb    %eax,%eax
L0:
  pop    %rbx
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
int checksum_datagram(struct tcp_ip_datagram *datagram) {
  if (checksum_ipv4_hdr(datagram) != 0) {
    return -1;
  }
  if (checksum_tcp_hdr(datagram) != 0) {
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum_datagram>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <checksum_ipv4_hdr@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rdi
  call   <checksum_tcp_hdr@plt>
  pop    %rbp
  neg    %rax
  sbb    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int checksum_datagram(struct tcp_ip_datagram *datagram) {
  if (checksum_ipv4_hdr(datagram) != 0) {
    return -1;
  }
  if (checksum_tcp_hdr(datagram) != 0) {
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checksum_datagram>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <checksum_ipv4_hdr@plt>
  test   %rax,%rax
  jne    L6
  mov    %rbp,%rdi
  call   <checksum_tcp_hdr@plt>
  pop    %rbp
  neg    %rax
  sbb    %eax,%eax
  ret
  nopl   0x0(%rax)
L6:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int checksum_datagram(struct tcp_ip_datagram *datagram) {
  if (checksum_ipv4_hdr(datagram) != 0) {
    return -1;
  }
  if (checksum_tcp_hdr(datagram) != 0) {
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f6c6c6548,%rax
  mov    %rax,-0x2c(%rbp)
  movl   $0x0,-0x24(%rbp)
  movabs $0x646c726f57,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x2c(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x2c(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string
name: parse_data
arguments: data_label: D18
type: string
name: parse_data
arguments: data_label: D17
type: string

tool: D0: strcpy( str3, str1) :  %s


tool: D18: strcat( str1, str2):   %s


tool: D17: strlen(str1) :  %d


assistant: ```c
int main() {
  char str1[12] = "Hello";
  char str2[12] = "World";
  char str3[12] = "";
  int len;
  strcpy(str3, str1);
  printf("strcpy( str3, str1) :  %s\n", str3);
  strcat(str1, str2);
  printf("strcat( str1, str2):   %s\n", str1);
  len = strlen(str1);
  printf("strlen(str1) :  %d\n", len);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6f6c6c6548,%rax
  mov    %rax,0x4(%rsp)
  movl   $0x0,0xc(%rsp)
  movabs $0x646c726f57,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  movq   $0x0,0x1c(%rsp)
  movl   $0x0,0x24(%rsp)
  lea    0x4(%rsp),%rbx
  lea    0x1c(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D29
type_guessed: string
name: read_data
arguments: data_tag: D22
type_guessed: string

tool: D5: strcpy( str3, str1) :  %s


tool: D29: strcat( str1, str2):   %s


tool: D22: strlen(str1) :  %d


assistant: ```c
int main() {
  char str1[12] = "Hello";
  char str2[12] = "World";
  char str3[12] = "";
  int len;
  strcpy(str3, str1);
  printf("strcpy( str3, str1) :  %s\n", str3);
  strcat(str1, str2);
  printf("strcat( str1, str2):   %s\n", str1);
  len = strlen(str1);
  printf("strlen(str1) :  %d\n", len);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x6f6c6c6548,%rax
  lea    0x4(%rsp),%rbp
  lea    0x1c(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movl   $0x0,0x18(%rsp)
  movq   $0x0,0x1c(%rsp)
  movl   $0x0,0x24(%rsp)
  mov    %rax,0x4(%rsp)
  movabs $0x646c726f57,%rax
  mov    %rax,0x10(%rsp)
  call   <strcpy@plt>
  mov    %r12,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D27
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D21
datatype: string

tool: D27: strcpy( str3, str1) :  %s


tool: D4: strcat( str1, str2):   %s


tool: D21: strlen(str1) :  %d


assistant: ```c
int main() {
  char str1[12] = "Hello";
  char str2[12] = "World";
  char str3[12] = "";
  int len;
  strcpy(str3, str1);
  printf("strcpy( str3, str1) :  %s\n", str3);
  strcat(str1, str2);
  printf("strcat( str1, str2):   %s\n", str1);
  len = strlen(str1);
  printf("strlen(str1) :  %d\n", len);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x6f6c6c6548,%rax
  lea    0x4(%rsp),%rbp
  lea    0x1c(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movl   $0x0,0x18(%rsp)
  movq   $0x0,0x1c(%rsp)
  movl   $0x0,0x24(%rsp)
  mov    %rax,0x4(%rsp)
  movabs $0x646c726f57,%rax
  mov    %rax,0x10(%rsp)
  call   <strcpy@plt>
  mov    %r12,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D28
type: string
name: read_data
arguments: data_label: D13
type: string
name: read_data
arguments: data_label: D7
type: string

tool: D28: strcpy( str3, str1) :  %s


tool: D13: strcat( str1, str2):   %s


tool: D7: strlen(str1) :  %d


assistant: ```c
int main() {
  char str1[12] = "Hello";
  char str2[12] = "World";
  char str3[12] = "";
  int len;
  strcpy(str3, str1);
  printf("strcpy( str3, str1) :  %s\n", str3);
  strcat(str1, str2);
  printf("strcat( str1, str2):   %s\n", str1);
  len = strlen(str1);
  printf("strlen(str1) :  %d\n", len);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<size_roundup_power2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    %eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int size_roundup_power2(int size) {
  size--;
  size |= size >> 1;
  size |= size >> 2;
  size |= size >> 4;
  size |= size >> 8;
  size |= size >> 16;
  size++;
  return size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<size_roundup_power2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  sar    %eax
  or     %edi,%eax
  mov    %eax,%edi
  sar    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  sar    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int size_roundup_power2(int size) {
  size--;
  size |= size >> 1;
  size |= size >> 2;
  size |= size >> 4;
  size |= size >> 8;
  size |= size >> 16;
  size++;
  return size;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<size_roundup_power2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  sar    %eax
  or     %edi,%eax
  mov    %eax,%edi
  sar    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  sar    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int size_roundup_power2(int size) {
  size--;
  size |= size >> 1;
  size |= size >> 2;
  size |= size >> 4;
  size |= size >> 8;
  size |= size >> 16;
  size++;
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<size_roundup_power2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  sar    %eax
  or     %edi,%eax
  mov    %eax,%edi
  sar    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  sar    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int size_roundup_power2(int size) {
  size--;
  size |= size >> 1;
  size |= size >> 2;
  size |= size >> 4;
  size |= size >> 8;
  size |= size >> 16;
  size++;
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_one_mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  jne    L21
  mov    -0x2c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L55
L21:
  cmpl   $0x1,-0x30(%rbp)
  jne    L34
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L55
L34:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L23
L68:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
L23:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jg     L68
  cmpl   $0x0,-0x18(%rbp)
  je     L55
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L55:
  nop
  leave
  ret
```

assistant: ```c
void _one_mult(char *num, int size, int digit, char *result) {
  int carry, value;
  char *nptr;
  char *rptr;
  if (digit == 0)
    memset(result, 0, size);
  else {
    if (digit == 1)
      memcpy(result, num, size);
    else {
      nptr = num + size - 1;
      rptr = result + size - 1;
      carry = 0;
      while (size-- > 0) {
        value = *nptr-- * digit + carry;
        *rptr-- = value % 10;
        carry = value / 10;
      }
      if (carry != 0)
        *rptr = carry;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_one_mult>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L38
  mov    %edx,%r8d
  cmp    $0x1,%edx
  je     L56
  movslq %esi,%rax
  sub    $0x1,%rax
  lea    (%rdi,%rax,1),%r9
  lea    (%rcx,%rax,1),%rdi
  lea    -0x1(%rsi),%r10d
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%esi
  not    %rsi
  mov    $0x0,%ecx
  mov    $0x0,%eax
L47:
  movsbl (%r9,%rcx,1),%edx
  imul   %r8d,%edx
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%eax
  lea    (%rax,%rax,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%edx
  mov    %dl,(%rdi,%rcx,1)
  sub    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L47
  mov    %r10d,%r10d
  not    %r10
  add    %r10,%rdi
  test   %eax,%eax
  je     L11
  mov    %al,(%rdi)
  jmp    L11
L38:
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
L11:
  add    $0x8,%rsp
  ret
L56:
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  jmp    L11
```

assistant: ```c
void _one_mult(char *num, int size, int digit, char *result) {
  int carry, value;
  char *nptr;
  char *rptr;
  if (digit == 0)
    memset(result, 0, size);
  else {
    if (digit == 1)
      memcpy(result, num, size);
    else {
      nptr = num + size - 1;
      rptr = result + size - 1;
      carry = 0;
      while (size-- > 0) {
        value = *nptr-- * digit + carry;
        *rptr-- = value % 10;
        carry = value / 10;
      }
      if (carry != 0)
        *rptr = carry;
    }
  }
}
```