ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<all_unique_characters_using_memory>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%esi
  mov    $0x100,%edi
  call   <calloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L24
  lea    0x1(%rbx),%rdi
L45:
  movsbq %dl,%rdx
  lea    (%rax,%rdx,4),%rdx
  cmpl   $0x0,(%rdx)
  jne    L10
  movl   $0x1,(%rdx)
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L45
  mov    $0x1,%eax
  jmp    L15
L24:
  mov    $0x1,%eax
  jmp    L15
L10:
  mov    $0x0,%eax
L15:
  pop    %rbx
  ret
```

assistant: ```c
bool all_unique_characters_using_memory(char *str) {
  int c;
  int *seen = (int *)calloc(256, sizeof(int));
  for (c = 0; str[c] != '\0'; c++) {
    if (seen[(int)str[c]])
      return false;
    seen[(int)str[c]] = 1;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<all_unique_characters_using_memory>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    %rdi,%rbx
  mov    $0x100,%edi
  call   <calloc@plt>
  movsbq (%rbx),%rdx
  test   %dl,%dl
  je     L7
  lea    0x1(%rbx),%rdi
  jmp    L29
  nopl   (%rax)
L24:
  add    $0x1,%rdi
  movl   $0x1,(%rdx)
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  je     L7
L29:
  lea    (%rax,%rdx,4),%rdx
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  je     L24
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool all_unique_characters_using_memory(char *str) {
  int c;
  int *seen = (int *)calloc(256, sizeof(int));
  for (c = 0; str[c] != '\0'; c++) {
    if (seen[(int)str[c]])
      return false;
    seen[(int)str[c]] = 1;
  }
  return true;
}
```
user: What is the c source code of the assembly code below:

```asm
<all_unique_characters_using_memory>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    %rdi,%rbx
  mov    $0x100,%edi
  call   <calloc@plt>
  movsbq (%rbx),%rdx
  test   %dl,%dl
  je     L25
  lea    0x1(%rbx),%rdi
  jmp    L33
  nopl   (%rax)
L15:
  add    $0x1,%rdi
  movl   $0x1,(%rdx)
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  je     L25
L33:
  lea    (%rax,%rdx,4),%rdx
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  je     L15
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L25:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool all_unique_characters_using_memory(char *str) {
  int c;
  int *seen = (int *)calloc(256, sizeof(int));
  for (c = 0; str[c] != '\0'; c++) {
    if (seen[(int)str[c]])
      return false;
    seen[(int)str[c]] = 1;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wait_for_pid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L55
L26:
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L55:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L54
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L26
L54:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L37
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L37:
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D31
type_guessed: string
name: read_data
arguments: data_label: D18
type_guessed: string
name: read_data
arguments: data_label: D22
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string

tool: D31: %d: waiting for children to die


tool: D18: %d: Unexpected child %d exited with status 0x%.4X


tool: D22: %d: Child %d exited with status 0x%.4X


tool: D2: %d: Child %d died without its death being tracked


assistant: ```c
void wait_for_pid(int pid) {
  int status;
  int corpse;
  int curpid = getpid();
  printf("%d: waiting for children to die\n", curpid);
  while ((corpse = wait(&status)) >= 0 && corpse != pid)
    printf("%d: Unexpected child %d exited with status 0x%.4X\n", curpid, corpse, status);
  if (corpse == pid)
    printf("%d: Child %d exited with status 0x%.4X\n", curpid, corpse, status);
  else
    printf("%d: Child %d died without its death being tracked\n", curpid, pid);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wait_for_pid>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D37(%rip),%r12
L11:
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    %eax,%edx
  cmp    %ebx,%eax
  je     L0
  test   %eax,%eax
  js     L0
  mov    0x4(%rsp),%ecx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L0:
  cmp    %ebx,%edx
  je     L16
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L43
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D37
data_type: string
name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string

tool: D22: %d: waiting for children to die


tool: D37: %d: Unexpected child %d exited with status 0x%.4X


tool: D31: %d: Child %d died without its death being tracked


tool: D6: %d: Child %d exited with status 0x%.4X


assistant: ```c
void wait_for_pid(int pid) {
  int status;
  int corpse;
  int curpid = getpid();
  printf("%d: waiting for children to die\n", curpid);
  while ((corpse = wait(&status)) >= 0 && corpse != pid)
    printf("%d: Unexpected child %d exited with status 0x%.4X\n", curpid, corpse, status);
  if (corpse == pid)
    printf("%d: Child %d exited with status 0x%.4X\n", curpid, corpse, status);
  else
    printf("%d: Child %d died without its death being tracked\n", curpid, pid);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wait_for_pid>:
  endbr64
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  call   <getpid@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    0x4(%rsp),%ecx
  cmp    %r12d,%eax
  je     L0
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L22:
  mov    %rbx,%rdi
  call   <wait@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L38
  cmp    %r12d,%eax
  je     L36
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  mov    0x4(%rsp),%ecx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebp,%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L45
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D35
datatype: string
name: parse_data
arguments: tag: D32
datatype: string

tool: D11: %d: Unexpected child %d exited with status 0x%.4X


tool: D13: %d: waiting for children to die


tool: D35: %d: Child %d died without its death being tracked


tool: D32: %d: Child %d exited with status 0x%.4X


assistant: ```c
void wait_for_pid(int pid) {
  int status;
  int corpse;
  int curpid = getpid();
  printf("%d: waiting for children to die\n", curpid);
  while ((corpse = wait(&status)) >= 0 && corpse != pid)
    printf("%d: Unexpected child %d exited with status 0x%.4X\n", curpid, corpse, status);
  if (corpse == pid)
    printf("%d: Child %d exited with status 0x%.4X\n", curpid, corpse, status);
  else
    printf("%d: Child %d died without its death being tracked\n", curpid, pid);
}
```
user: What is the c source code of the assembly code below:

```asm
<wait_for_pid>:
  endbr64
  push   %r13
  lea    D33(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  call   <getpid@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    0x4(%rsp),%ecx
  cmp    %r12d,%eax
  je     L36
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L8:
  mov    %rbx,%rdi
  call   <wait@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L58
  cmp    %r12d,%eax
  je     L47
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  mov    0x4(%rsp),%ecx
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %ebp,%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L46
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D33
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D38
type_guessed: string

tool: D33: %d: Unexpected child %d exited with status 0x%.4X


tool: D12: %d: waiting for children to die


tool: D8: %d: Child %d died without its death being tracked


tool: D38: %d: Child %d exited with status 0x%.4X


assistant: ```c
void wait_for_pid(int pid) {
  int status;
  int corpse;
  int curpid = getpid();
  printf("%d: waiting for children to die\n", curpid);
  while ((corpse = wait(&status)) >= 0 && corpse != pid)
    printf("%d: Unexpected child %d exited with status 0x%.4X\n", curpid, corpse, status);
  if (corpse == pid)
    printf("%d: Child %d exited with status 0x%.4X\n", curpid, corpse, status);
  else
    printf("%d: Child %d died without its death being tracked\n", curpid, pid);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L2
L29:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L39:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L3:
  cmpl   $0x2,-0x14(%rbp)
  jle    L39
  addl   $0x1,-0x18(%rbp)
L2:
  cmpl   $0x6,-0x18(%rbp)
  jle    L29
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D28
type: string

tool: D2: dnanvariancepn

tool: D6: # c::%s:len=%d


tool: D28: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanvariancepn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D18(%rip),%r15
  jmp    L33
L1:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L19
L33:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L18:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L18
  jmp    L1
L19:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D0
datatype: string

tool: D18: dnanvariancepn

tool: D13: # c::%s:len=%d


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanvariancepn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D2(%rip),%r15
  push   %r14
  lea    D27(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L16:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L3:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L3
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L16
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string
name: parse_data
arguments: data_label: D29
type_infered: string

tool: D2: dnanvariancepn

tool: D27: # c::%s:len=%d


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanvariancepn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D5(%rip),%r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L15:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L11:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L11
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L15
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type: string
name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D14
type: string

tool: D5: dnanvariancepn

tool: D8: # c::%s:len=%d


tool: D14: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanvariancepn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<b_twist_u_on_edgeperm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <b_edgeperm_unpack@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <four_cycle@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <b_edgeperm_pack@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int b_twist_u_on_edgeperm(eperm)
int eperm;
{
  int temp_arr[8];
  b_edgeperm_unpack(eperm, temp_arr);
  four_cycle(temp_arr, 1, 2, 3, 0);
  return b_edgeperm_pack(temp_arr);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<b_twist_u_on_edgeperm>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <b_edgeperm_unpack@plt>
  mov    $0x0,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <four_cycle@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <b_edgeperm_pack@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int b_twist_u_on_edgeperm(eperm)
int eperm;
{
  int temp_arr[8];
  b_edgeperm_unpack(eperm, temp_arr);
  four_cycle(temp_arr, 1, 2, 3, 0);
  return b_edgeperm_pack(temp_arr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<b_twist_u_on_edgeperm>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <b_edgeperm_unpack@plt>
  xor    %r8d,%r8d
  mov    $0x2,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x3,%ecx
  mov    $0x1,%esi
  call   <four_cycle@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <b_edgeperm_pack@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int b_twist_u_on_edgeperm(eperm)
int eperm;
{
  int temp_arr[8];
  b_edgeperm_unpack(eperm, temp_arr);
  four_cycle(temp_arr, 1, 2, 3, 0);
  return b_edgeperm_pack(temp_arr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<b_twist_u_on_edgeperm>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <b_edgeperm_unpack@plt>
  xor    %r8d,%r8d
  mov    $0x2,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x3,%ecx
  mov    $0x1,%esi
  call   <four_cycle@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <b_edgeperm_pack@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x30,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int b_twist_u_on_edgeperm(eperm)
int eperm;
{
  int temp_arr[8];
  b_edgeperm_unpack(eperm, temp_arr);
  four_cycle(temp_arr, 1, 2, 3, 0);
  return b_edgeperm_pack(temp_arr);
}
```