ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<vector_fill_unique>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  shl    $0x2,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L17
  mov    %rax,%rbp
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %ebx,(%rax)
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %ebx,%r13d
  jne    L22
  mov    %ebx,%eax
  lea    (%r12,%rax,4),%r13
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  add    $0x4,%rbp
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rsi
  call   <vector_swap@plt>
  cmp    %r13,%rbp
  jne    L21
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *vector_fill_unique(int n) {
  int *v = (int *)malloc(sizeof(int) * n);
  int i;
  for (i = 0; i < n; i++) {
    v[i] = i;
  }
  for (i = 0; i < n; i++) {
    vector_swap(&v[i], &v[rand() % n]);
  }
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vector_fill_unique>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  shl    $0x2,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L11
  lea    -0x1(%rbp),%eax
  cmp    $0x2,%eax
  jbe    L18
  mov    %ebp,%edx
  movdqa D4(%rip),%xmm0
  movdqa D18(%rip),%xmm2
  mov    %r12,%rax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %r12,%rdx
  xchg   %ax,%ax
L71:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L71
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bpl
  je     L74
L73:
  movslq %eax,%rdx
  mov    %eax,(%r12,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L74
  add    $0x2,%eax
  mov    %edx,0x4(%r12,%rcx,1)
  cmp    %eax,%ebp
  jle    L74
  mov    %eax,0x8(%r12,%rcx,1)
L74:
  mov    %ebp,%eax
  mov    %r12,%rbx
  lea    (%r12,%rax,4),%r13
L46:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbx,%rdi
  add    $0x4,%rbx
  cltd
  idiv   %ebp
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rsi
  call   <vector_swap@plt>
  cmp    %r13,%rbx
  jne    L46
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  xor    %eax,%eax
  jmp    L73
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: byte[16]
name: unpack_data
arguments: data_tag: D18
type: byte[16]

tool: {"D4": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D18": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int *vector_fill_unique(int n) {
  int *v = (int *)malloc(sizeof(int) * n);
  int i;
  for (i = 0; i < n; i++) {
    v[i] = i;
  }
  for (i = 0; i < n; i++) {
    vector_swap(&v[i], &v[rand() % n]);
  }
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <smallest_multiple@plt>
  cmp    $0x3c,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0xa,%edi
  call   <smallest_multiple@plt>
  cmp    $0x9d8,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x14,%edi
  call   <smallest_multiple@plt>
  cmp    $0xde021f0,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <smallest_multiple@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x5,%edi
  call   <smallest_multiple_efficient@plt>
  cmp    $0x3c,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0xa,%edi
  call   <smallest_multiple_efficient@plt>
  cmp    $0x9d8,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x14,%edi
  call   <smallest_multiple_efficient@plt>
  cmp    $0xde021f0,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <smallest_multiple_efficient@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  assert(60 == smallest_multiple(5));
  assert(2520 == smallest_multiple(10));
  assert(232792560 == smallest_multiple(20));
  assert(2329089562800 == smallest_multiple(30));
  assert(60 == smallest_multiple_efficient(5));
  assert(2520 == smallest_multiple_efficient(10));
  assert(232792560 == smallest_multiple_efficient(20));
  assert(2329089562800 == smallest_multiple_efficient(30));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <smallest_multiple@plt>
  cmp    $0x3c,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xa,%edi
  call   <smallest_multiple@plt>
  cmp    $0x9d8,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x14,%edi
  call   <smallest_multiple@plt>
  cmp    $0xde021f0,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <smallest_multiple@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x5,%edi
  call   <smallest_multiple_efficient@plt>
  cmp    $0x3c,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xa,%edi
  call   <smallest_multiple_efficient@plt>
  cmp    $0x9d8,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x14,%edi
  call   <smallest_multiple_efficient@plt>
  cmp    $0xde021f0,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <smallest_multiple_efficient@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(60 == smallest_multiple(5));
  assert(2520 == smallest_multiple(10));
  assert(232792560 == smallest_multiple(20));
  assert(2329089562800 == smallest_multiple(30));
  assert(60 == smallest_multiple_efficient(5));
  assert(2520 == smallest_multiple_efficient(10));
  assert(232792560 == smallest_multiple_efficient(20));
  assert(2329089562800 == smallest_multiple_efficient(30));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <smallest_multiple@plt>
  xor    %edi,%edi
  cmp    $0x3c,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%edi
  call   <smallest_multiple@plt>
  xor    %edi,%edi
  cmp    $0x9d8,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x14,%edi
  call   <smallest_multiple@plt>
  xor    %edi,%edi
  cmp    $0xde021f0,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <smallest_multiple@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x5,%edi
  call   <smallest_multiple_efficient@plt>
  xor    %edi,%edi
  cmp    $0x3c,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%edi
  call   <smallest_multiple_efficient@plt>
  xor    %edi,%edi
  cmp    $0x9d8,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x14,%edi
  call   <smallest_multiple_efficient@plt>
  xor    %edi,%edi
  cmp    $0xde021f0,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <smallest_multiple_efficient@plt>
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(60 == smallest_multiple(5));
  assert(2520 == smallest_multiple(10));
  assert(232792560 == smallest_multiple(20));
  assert(2329089562800 == smallest_multiple(30));
  assert(60 == smallest_multiple_efficient(5));
  assert(2520 == smallest_multiple_efficient(10));
  assert(232792560 == smallest_multiple_efficient(20));
  assert(2329089562800 == smallest_multiple_efficient(30));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <smallest_multiple@plt>
  xor    %edi,%edi
  cmp    $0x3c,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%edi
  call   <smallest_multiple@plt>
  xor    %edi,%edi
  cmp    $0x9d8,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x14,%edi
  call   <smallest_multiple@plt>
  xor    %edi,%edi
  cmp    $0xde021f0,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <smallest_multiple@plt>
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0x5,%edi
  call   <smallest_multiple_efficient@plt>
  xor    %edi,%edi
  cmp    $0x3c,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%edi
  call   <smallest_multiple_efficient@plt>
  xor    %edi,%edi
  cmp    $0x9d8,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x14,%edi
  call   <smallest_multiple_efficient@plt>
  xor    %edi,%edi
  cmp    $0xde021f0,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1e,%edi
  call   <smallest_multiple_efficient@plt>
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(60 == smallest_multiple(5));
  assert(2520 == smallest_multiple(10));
  assert(232792560 == smallest_multiple(20));
  assert(2329089562800 == smallest_multiple(30));
  assert(60 == smallest_multiple_efficient(5));
  assert(2520 == smallest_multiple_efficient(10));
  assert(232792560 == smallest_multiple_efficient(20));
  assert(2329089562800 == smallest_multiple_efficient(30));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hwrev_is_valid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L57
  mov    $0x1,%eax
  jmp    L41
L57:
  movl   $0x0,-0x4(%rbp)
  jmp    L40
L48:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L11
  mov    $0x1,%eax
  jmp    L41
L11:
  addl   $0x1,-0x4(%rbp)
L40:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L48
  mov    $0x0,%eax
L41:
  pop    %rbp
  ret
```

assistant: ```c
int hwrev_is_valid(const int16_t *hwrevs, int16_t hwrev) {
  int i;
  if (!hwrevs)
    return 1;
  for (i = 0; hwrevs[i] != -1; ++i)
    if (hwrev == hwrevs[i])
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hwrev_is_valid>:
  endbr64
  test   %rdi,%rdi
  je     L16
  mov    (%rdi),%eax
  cmp    $0xffffffff,%eax
  je     L27
  add    $0x4,%rdi
L28:
  cmp    %eax,%esi
  je     L29
  add    $0x4,%rdi
  mov    -0x4(%rdi),%eax
  cmp    $0xffffffff,%eax
  jne    L28
  mov    $0x0,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
L27:
  mov    $0x0,%eax
  ret
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int hwrev_is_valid(const int16_t *hwrevs, int16_t hwrev) {
  int i;
  if (!hwrevs)
    return 1;
  for (i = 0; hwrevs[i] != -1; ++i)
    if (hwrev == hwrevs[i])
      return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hwrev_is_valid>:
  endbr64
  test   %rdi,%rdi
  je     L29
  mov    (%rdi),%eax
  cmp    $0xffffffff,%eax
  je     L20
  add    $0x4,%rdi
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  cmp    $0xffffffff,%eax
  je     L20
L11:
  cmp    %eax,%esi
  jne    L30
L29:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hwrev_is_valid(const int16_t *hwrevs, int16_t hwrev) {
  int i;
  if (!hwrevs)
    return 1;
  for (i = 0; hwrevs[i] != -1; ++i)
    if (hwrev == hwrevs[i])
      return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hwrev_is_valid>:
  endbr64
  test   %rdi,%rdi
  je     L26
  mov    (%rdi),%eax
  cmp    $0xffffffff,%eax
  je     L39
  add    $0x4,%rdi
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  cmp    $0xffffffff,%eax
  je     L39
L32:
  cmp    %eax,%esi
  jne    L24
L26:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hwrev_is_valid(const int16_t *hwrevs, int16_t hwrev) {
  int i;
  if (!hwrevs)
    return 1;
  for (i = 0; hwrevs[i] != -1; ++i)
    if (hwrev == hwrevs[i])
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<px_strdupv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L14
L44:
  movl   $0x0,-0x20(%rbp)
  jmp    L53
L34:
  addl   $0x1,-0x20(%rbp)
L53:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L34
  addl   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <px_malloc0@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L22
L41:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <px_strdup@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L22:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L41
  mov    -0x18(%rbp),%rax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **px_strdupv(const char **sv) {
  int count;
  if (!sv)
    return NULL;
  for (count = 0; sv[count]; count++)
    ;
  char **output = px_malloc0(sizeof(char *) * ++count);
  for (int i = 0; sv[i]; i++)
    output[i] = px_strdup(sv[i]);
  return output;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<px_strdupv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L28
  cmpq   $0x0,(%rdi)
  je     L53
  mov    $0x1,%eax
L23:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rbx,%rax,8)
  jne    L23
L8:
  lea    0x8(,%rdx,8),%edi
  call   <px_malloc0@plt>
  mov    %rax,%r12
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L24
  mov    %rax,%rbp
  add    $0x8,%rbx
L31:
  call   <px_strdup@plt>
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rdi
  add    $0x8,%rbp
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L31
L24:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  mov    $0x0,%edx
  jmp    L8
L28:
  mov    %rdi,%r12
  jmp    L24
```

assistant: ```c
char **px_strdupv(const char **sv) {
  int count;
  if (!sv)
    return NULL;
  for (count = 0; sv[count]; count++)
    ;
  char **output = px_malloc0(sizeof(char *) * ++count);
  for (int i = 0; sv[i]; i++)
    output[i] = px_strdup(sv[i]);
  return output;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<px_strdupv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L53
  cmpq   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L5
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rbp,%rax,8)
  jne    L32
  lea    0x8(,%rdx,8),%edi
L18:
  call   <px_malloc0@plt>
  mov    0x0(%rbp),%rdi
  mov    %rax,%r12
  test   %rdi,%rdi
  je     L66
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L35:
  call   <px_strdup@plt>
  mov    %rax,(%r12,%rbx,1)
  add    $0x8,%rbx
  mov    0x0(%rbp,%rbx,1),%rdi
  test   %rdi,%rdi
  jne    L35
L66:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L5:
  mov    $0x8,%edi
  jmp    L18
L53:
  xor    %r12d,%r12d
  jmp    L66
```

assistant: ```c
char **px_strdupv(const char **sv) {
  int count;
  if (!sv)
    return NULL;
  for (count = 0; sv[count]; count++)
    ;
  char **output = px_malloc0(sizeof(char *) * ++count);
  for (int i = 0; sv[i]; i++)
    output[i] = px_strdup(sv[i]);
  return output;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<px_strdupv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L54
  cmpq   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L62
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rbp,%rax,8)
  jne    L23
  lea    0x8(,%rdx,8),%edi
L64:
  call   <px_malloc0@plt>
  mov    0x0(%rbp),%rdi
  mov    %rax,%r12
  test   %rdi,%rdi
  je     L19
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L12:
  call   <px_strdup@plt>
  mov    %rax,(%r12,%rbx,1)
  add    $0x8,%rbx
  mov    0x0(%rbp,%rbx,1),%rdi
  test   %rdi,%rdi
  jne    L12
L19:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L62:
  mov    $0x8,%edi
  jmp    L64
L54:
  xor    %r12d,%r12d
  jmp    L19
```

assistant: ```c
char **px_strdupv(const char **sv) {
  int count;
  if (!sv)
    return NULL;
  for (count = 0; sv[count]; count++)
    ;
  char **output = px_malloc0(sizeof(char *) * ++count);
  for (int i = 0; sv[i]; i++)
    output[i] = px_strdup(sv[i]);
  return output;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,-0x18(%rbp)
  jmp    L36
L17:
  movl   $0x0,-0x14(%rbp)
  jmp    L30
L22:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,%esi
  mov    %ebx,%eax
  cltd
  idiv   %esi
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x18(%rbp)
L36:
  cmpl   $0x9,-0x18(%rbp)
  jle    L17
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: %d	

assistant: ```c
void main() {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j <= i; j++)
      printf("%d\t", fact(i) / fact(j) / fact(i - j));
    printf("\n");
  }
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  lea    D8(%rip),%r13
  jmp    L20
L8:
  mov    %r12d,%edi
  call   <fact@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <fact@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebx
  mov    %r12d,%edi
  sub    %ebp,%edi
  call   <fact@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %r12d,%ebp
  jle    L8
L42:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  je     L31
L20:
  mov    $0x0,%ebp
  test   %r12d,%r12d
  jns    L8
  jmp    L42
L31:
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: %d	

assistant: ```c
void main() {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j <= i; j++)
      printf("%d\t", fact(i) / fact(j) / fact(i - j));
    printf("\n");
  }
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  nopl   0x0(%rax)
L8:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12d,%edi
  call   <fact@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <fact@plt>
  mov    %r12d,%edi
  mov    %eax,%r8d
  mov    %ebx,%eax
  sub    %ebp,%edi
  add    $0x1,%ebp
  cltd
  idiv   %r8d
  mov    %eax,%ebx
  call   <fact@plt>
  mov    %r14,%rdi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r13d,%ebp
  jne    L19
  mov    $0xa,%edi
  add    $0x1,%r12d
  lea    0x1(%rbp),%r13d
  call   <putchar@plt>
  cmp    $0xa,%r12d
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <getchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: %d	

assistant: ```c
void main() {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j <= i; j++)
      printf("%d\t", fact(i) / fact(j) / fact(i - j));
    printf("\n");
  }
  getchar();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  nopl   0x0(%rax)
L17:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %r12d,%edi
  call   <fact@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <fact@plt>
  mov    %r12d,%edi
  mov    %eax,%r8d
  mov    %ebx,%eax
  sub    %ebp,%edi
  add    $0x1,%ebp
  cltd
  idiv   %r8d
  mov    %eax,%ebx
  call   <fact@plt>
  mov    %r14,%rdi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r13d,%ebp
  jne    L11
  mov    $0xa,%edi
  add    $0x1,%r12d
  lea    0x1(%rbp),%r13d
  call   <putchar@plt>
  cmp    $0xa,%r12d
  jne    L17
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <getchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string

tool: D8: %d	

assistant: ```c
void main() {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j <= i; j++)
      printf("%d\t", fact(i) / fact(j) / fact(i - j));
    printf("\n");
  }
  getchar();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SUB_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x29,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  or     $0xc0,%al
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  or     %edx,%eax
  mov    %eax,%edi
  call   <addbyte@plt>
  nop
  leave
  ret
```

assistant: ```c
void SUB_HOST_REG_L(int dst_reg, int src_reg) {
  addbyte(0x29);
  addbyte(0xc0 | dst_reg | (src_reg << 3));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<SUB_HOST_REG_L>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x29,%edi
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  or     %ebp,%edi
  or     $0xc0,%dil
  call   <addbyte@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SUB_HOST_REG_L(int dst_reg, int src_reg) {
  addbyte(0x29);
  addbyte(0xc0 | dst_reg | (src_reg << 3));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SUB_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x29,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  or     %ebp,%edi
  pop    %rbx
  pop    %rbp
  or     $0xc0,%dil
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void SUB_HOST_REG_L(int dst_reg, int src_reg) {
  addbyte(0x29);
  addbyte(0xc0 | dst_reg | (src_reg << 3));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SUB_HOST_REG_L>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x29,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <addbyte@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  or     %ebp,%edi
  pop    %rbx
  pop    %rbp
  or     $0xc0,%dil
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void SUB_HOST_REG_L(int dst_reg, int src_reg) {
  addbyte(0x29);
  addbyte(0xc0 | dst_reg | (src_reg << 3));
}
```