user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D83(%rip),%r15
  push   %r14
  lea    D86(%rip),%r14
  push   %r13
  lea    D49(%rip),%r13
  push   %r12
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  lea    D113(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x14(%rsp),%r12
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L6:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x4,0x10(%rsp)
  ja     L69
  mov    0x10(%rsp),%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  mov    0x14(%rsp),%esi
  lea    D87(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <reverse_original@plt>
  mov    0x14(%rsp),%esi
  lea    D90(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
  mov    0x14(%rsp),%esi
  lea    D67(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%edi
  call   <reverse@plt>
  lea    D90(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
  mov    0x14(%rsp),%edi
  call   <no_of_digits@plt>
  mov    0x14(%rsp),%esi
  lea    D11(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
  lea    D88(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
  mov    0x14(%rsp),%edi
  call   <isPalindrome@plt>
  jmp    L6
L69:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L6
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D83
data_type: string
name: parse_data
arguments: label: D86
data_type: string
name: parse_data
arguments: label: D49
data_type: string
name: parse_data
arguments: label: D20
data_type: string
name: parse_data
arguments: label: D87
data_type: string
name: parse_data
arguments: label: D90
data_type: string
name: parse_data
arguments: label: D67
data_type: string
name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D88
data_type: string
name: parse_data
arguments: label: D26
data_type: string

tool: D83: 
Enter a number:

tool: D86: Enter 1 to print the no of digits,2 to reverse the no using pass by value,3 to reverse no using pass by reference and 4 to check if entered no is pallindrome or not

tool: D49: Enter a menu indice:

tool: D20: %d

tool: D87: The original no is %d 


tool: D90: The reversed no is %d

tool: D67: The original no is: %d 


tool: D11: The no of digits in %d is %d 


tool: D88: Program terminates

tool: D26: Im sorry I dont understand you:

assistant: ```c
int main() {
  int choice, no;
  int i = 1;
  while (i == 1) {
    puts("\nEnter a number:");
    scanf("%d", &no);
    puts("Enter 1 to print the no of digits,2 to reverse the no using pass by value,3 to reverse no using pass by reference and 4 to check if entered no is pallindrome or not");
    puts("Enter a menu indice:");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      printf("The no of digits in %d is %d \n", no, no_of_digits(no));
      break;
    case 2: {
      printf("The original no is: %d \n", no);
      printf("The reversed no is %d", reverse(no));
      break;
    }
    case 3: {
      printf("The original no is %d \n", no);
      reverse_original(&no);
      printf("The reversed no is %d", no);
      break;
    }
    case 0: {
      puts("Program terminates");
      i = 2;
      break;
    }
    case 4:
      isPalindrome(no);
      break;
    default:
      puts("Im sorry I dont understand you:");
      break;
    }
  }
  return 0;
}
```