ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<padding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  movb   $0x0,-0x11(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  jg     L28
  movl   $0x10,-0x3c(%rbp)
L28:
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x30(%rbp),%rax
  cqto
  idiv   %rsi
  lea    0x1(%rax),%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  imul   %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L21
L15:
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L15
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  sub    -0x10(%rbp),%rax
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rcx
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  mov    %al,-0x11(%rbp)
  jmp    L33
L31:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
L33:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jl     L31
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *padding(const unsigned char *in, long size, long *p_size, int padding) {
  char p_value = 0;
  long index = 0;
  unsigned char *out = NULL;
  if (padding <= 0) {
    padding = 16;
  }
  *p_size = (size / padding + 1) * padding;
  out = (unsigned char *)malloc(*p_size);
  while (index < size) {
    out[index] = in[index];
    index++;
  }
  p_value = (*p_size - index) % padding;
  while (index < *p_size) {
    out[index++] = p_value;
  }
  return out;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<padding>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  test   %ecx,%ecx
  mov    $0x10,%eax
  cmovle %eax,%ecx
  movslq %ecx,%r12
  mov    %rsi,%rax
  cqto
  idiv   %r12
  lea    0x1(%rax),%rdi
  imul   %r12,%rdi
  mov    %rdi,0x0(%rbp)
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %rbx,%rbx
  jle    L7
  lea    (%rbx,%rax,1),%rdi
  mov    %r13,%rsi
  sub    %rax,%rsi
L14:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L14
L27:
  mov    0x0(%rbp),%rsi
  mov    %rsi,%rax
  sub    %rbx,%rax
  cqto
  idiv   %r12
  cmp    %rbx,%rsi
  jle    L3
L28:
  mov    %rbx,%rax
  add    $0x1,%rbx
  mov    %dl,(%rcx,%rax,1)
  cmp    %rbx,0x0(%rbp)
  jg     L28
L3:
  mov    %rcx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    $0x0,%ebx
  jmp    L27
```

assistant: ```c
unsigned char *padding(const unsigned char *in, long size, long *p_size, int padding) {
  char p_value = 0;
  long index = 0;
  unsigned char *out = NULL;
  if (padding <= 0) {
    padding = 16;
  }
  *p_size = (size / padding + 1) * padding;
  out = (unsigned char *)malloc(*p_size);
  while (index < size) {
    out[index] = in[index];
    index++;
  }
  p_value = (*p_size - index) % padding;
  while (index < *p_size) {
    out[index++] = p_value;
  }
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<padding>:
  endbr64
  push   %r13
  mov    $0x10,%eax
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  cmovle %eax,%ecx
  mov    %rsi,%rax
  cqto
  movslq %ecx,%r12
  idiv   %r12
  lea    0x1(%rax),%rdi
  imul   %r12,%rdi
  mov    %rdi,0x0(%rbp)
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rbx,%rbx
  jle    L5
  mov    %r13,%rcx
  lea    (%rbx,%rax,1),%rsi
  sub    %rax,%rcx
  nop
L44:
  movzbl (%rcx,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rsi
  jne    L44
L20:
  mov    0x0(%rbp),%rcx
  mov    %rcx,%rax
  sub    %rbx,%rax
  cqto
  idiv   %r12
  cmp    %rbx,%rcx
  jle    L29
  nopl   0x0(%rax)
L1:
  mov    %rbx,%rax
  add    $0x1,%rbx
  mov    %dl,(%rax,%r8,1)
  cmp    %rbx,0x0(%rbp)
  jg     L1
L29:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %ebx,%ebx
  jmp    L20
```

assistant: ```c
unsigned char *padding(const unsigned char *in, long size, long *p_size, int padding) {
  char p_value = 0;
  long index = 0;
  unsigned char *out = NULL;
  if (padding <= 0) {
    padding = 16;
  }
  *p_size = (size / padding + 1) * padding;
  out = (unsigned char *)malloc(*p_size);
  while (index < size) {
    out[index] = in[index];
    index++;
  }
  p_value = (*p_size - index) % padding;
  while (index < *p_size) {
    out[index++] = p_value;
  }
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_strlen_recursion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    $0x0,%eax
  jmp    L18
L1:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <_strlen_recursion>
  add    $0x1,%eax
L18:
  leave
  ret
```

assistant: ```c
int _strlen_recursion(char *s) {
  if (*s == '\0')
    return (0);
  return (_strlen_recursion(s + 1) + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_strlen_recursion>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  jne    L0
  ret
L0:
  sub    $0x8,%rsp
  add    $0x1,%rdi
  call   <_strlen_recursion>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _strlen_recursion(char *s) {
  if (*s == '\0')
    return (0);
  return (_strlen_recursion(s + 1) + 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_strlen_recursion>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  mov    $0x1,%eax
  je     L4
  nopl   0x0(%rax)
L12:
  add    $0x1,%rdi
  mov    %eax,%r8d
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L12
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _strlen_recursion(char *s) {
  if (*s == '\0')
    return (0);
  return (_strlen_recursion(s + 1) + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<_strlen_recursion>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  mov    $0x1,%eax
  je     L11
  nopl   0x0(%rax)
L18:
  add    $0x1,%rdi
  mov    %eax,%r8d
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L18
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _strlen_recursion(char *s) {
  if (*s == '\0')
    return (0);
  return (_strlen_recursion(s + 1) + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x40,-0x20(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  sub    $0x4,%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x20(%rbp),%rax
  sub    $0x4,%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    -0x8(%rbp),%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <close@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L2
L19:
  mov    $0xffffffff,%edi
  call   <exit@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D26
data_type: string

tool: D4: w

tool: D26: #define MALLOC_BASE 0x%lx


assistant: ```c
main() {
  static char file[] = "Emulator/malloc_base.h";
  unsigned long int wordsize = sizeof(unsigned long int) * 8;
  char *mp = (char *)malloc(1024);
  unsigned long int word = (unsigned long int)mp >> wordsize - 4;
  FILE *fd;
  if ((fd = fopen(file, "w")) != NULL) {
    fprintf(fd, "#define MALLOC_BASE 0x%lx\n", (word << wordsize - 4));
    close(fd);
    exit(0);
  } else {
    exit(-1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D0(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbx
  movabs $0xf000000000000000,%rax
  mov    %rbp,%rdx
  and    %rax,%rdx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <close@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L16:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D9
type: string

tool: D0: w

tool: D9: #define MALLOC_BASE 0x%lx


assistant: ```c
main() {
  static char file[] = "Emulator/malloc_base.h";
  unsigned long int wordsize = sizeof(unsigned long int) * 8;
  char *mp = (char *)malloc(1024);
  unsigned long int word = (unsigned long int)mp >> wordsize - 4;
  FILE *fd;
  if ((fd = fopen(file, "w")) != NULL) {
    fprintf(fd, "#define MALLOC_BASE 0x%lx\n", (word << wordsize - 4));
    close(fd);
    exit(0);
  } else {
    exit(-1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x400,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D7(%rip),%rsi
  lea    D15(%rip),%rdi
  mov    %rax,%rbx
  call   <fopen@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbp
  lea    D26(%rip),%rsi
  movabs $0xf000000000000000,%rax
  and    %rax,%rbx
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <close@plt>
  xor    %edi,%edi
  call   <exit@plt>
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string

tool: D7: w

tool: D26: #define MALLOC_BASE 0x%lx


assistant: ```c
main() {
  static char file[] = "Emulator/malloc_base.h";
  unsigned long int wordsize = sizeof(unsigned long int) * 8;
  char *mp = (char *)malloc(1024);
  unsigned long int word = (unsigned long int)mp >> wordsize - 4;
  FILE *fd;
  if ((fd = fopen(file, "w")) != NULL) {
    fprintf(fd, "#define MALLOC_BASE 0x%lx\n", (word << wordsize - 4));
    close(fd);
    exit(0);
  } else {
    exit(-1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x400,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D19(%rip),%rsi
  lea    D20(%rip),%rdi
  mov    %rax,%rbx
  call   <fopen@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rbp
  lea    D0(%rip),%rsi
  movabs $0xf000000000000000,%rax
  and    %rax,%rbx
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <close@plt>
  xor    %edi,%edi
  call   <exit@plt>
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D19: w

tool: D0: #define MALLOC_BASE 0x%lx


assistant: ```c
main() {
  static char file[] = "Emulator/malloc_base.h";
  unsigned long int wordsize = sizeof(unsigned long int) * 8;
  char *mp = (char *)malloc(1024);
  unsigned long int word = (unsigned long int)mp >> wordsize - 4;
  FILE *fd;
  if ((fd = fopen(file, "w")) != NULL) {
    fprintf(fd, "#define MALLOC_BASE 0x%lx\n", (word << wordsize - 4));
    close(fd);
    exit(0);
  } else {
    exit(-1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <check_for_hvm@plt>
  test   %rax,%rax
  je     L9
  mov    $0x0,%eax
  jmp    L3
L9:
  mov    $0x1,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  if (check_for_hvm())
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <check_for_hvm@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  if (check_for_hvm())
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <check_for_hvm@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int main(void) {
  if (check_for_hvm())
    return 0;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <check_for_hvm@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int main(void) {
  if (check_for_hvm())
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <poDebugInit@plt>
  mov    $0xc8,%edx
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x32,%esi
  mov    $0x32,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x14,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0xc8,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0x64,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0x1f4,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  poDebugInit();
  runScenario(10, 10, 200);
  runScenario(50, 50, 100);
  runScenario(200, 20, 100);
  runScenario(500, 100, 100);
  runScenario(200, 200, 10);
  runScenario(200, 100, 10);
  runScenario(500, 500, 10);
  ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <poDebugInit@plt>
  mov    $0xc8,%edx
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x32,%esi
  mov    $0x32,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x14,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0xc8,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0x64,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0x1f4,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  poDebugInit();
  runScenario(10, 10, 200);
  runScenario(50, 50, 100);
  runScenario(200, 20, 100);
  runScenario(500, 100, 100);
  runScenario(200, 200, 10);
  runScenario(200, 100, 10);
  runScenario(500, 500, 10);
  ;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <poDebugInit@plt>
  mov    $0xc8,%edx
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x32,%esi
  mov    $0x32,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x14,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0xc8,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0x64,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0x1f4,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  poDebugInit();
  runScenario(10, 10, 200);
  runScenario(50, 50, 100);
  runScenario(200, 20, 100);
  runScenario(500, 100, 100);
  runScenario(200, 200, 10);
  runScenario(200, 100, 10);
  runScenario(500, 500, 10);
  ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <poDebugInit@plt>
  mov    $0xc8,%edx
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x32,%esi
  mov    $0x32,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x14,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0xc8,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0x64,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0xa,%edx
  mov    $0x1f4,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  poDebugInit();
  runScenario(10, 10, 200);
  runScenario(50, 50, 100);
  runScenario(200, 20, 100);
  runScenario(500, 100, 100);
  runScenario(200, 200, 10);
  runScenario(200, 100, 10);
  runScenario(500, 500, 10);
  ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<computec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edi,%edx
  movsd  %xmm2,-0x30(%rbp)
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  cmpb   $0x0,-0x28(%rbp)
  je     L30
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <cosh@plt>
  movq   %xmm0,%rax
  jmp    L25
L30:
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
L25:
  mov    %rax,-0x8(%rbp)
  cmpb   $0x0,-0x24(%rbp)
  je     L4
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cosh@plt>
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <cosh@plt>
  mulsd  -0x38(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sinh@plt>
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <sinh@plt>
  mulsd  -0x40(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm3
  divsd  %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <acosh@plt>
  movq   %xmm0,%rax
  jmp    L35
L4:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x38(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mulsd  -0x40(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm4
  divsd  %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <acosh@plt>
  movq   %xmm0,%rax
L35:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double computec(double al, double be, char imag1, double ga, char imag2) {
  double t = imag2 ? cosh(ga) : cos(ga);
  if (imag1)
    return acosh((t + cosh(al) * cosh(be)) / (sinh(al) * sinh(be)));
  else
    return acosh((t + cos(al) * cos(be)) / (sin(al) * sin(be)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<computec>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbp
  movq   %xmm1,%rbx
  mov    %edi,%r12d
  movapd %xmm2,%xmm0
  test   %sil,%sil
  jne    L0
  call   <cos@plt>
  movq   %xmm0,%r15
L5:
  test   %r12b,%r12b
  je     L34
  movq   %rbp,%xmm0
  call   <cosh@plt>
  movq   %xmm0,%r14
  movq   %rbx,%xmm0
  call   <cosh@plt>
  movq   %xmm0,%r12
  movq   %rbp,%xmm0
  call   <sinh@plt>
  movq   %xmm0,%rbp
  movq   %rbx,%xmm0
  call   <sinh@plt>
  movapd %xmm0,%xmm1
  movq   %r12,%xmm0
  movq   %r14,%xmm4
  mulsd  %xmm4,%xmm0
  movq   %r15,%xmm5
  addsd  %xmm5,%xmm0
  movq   %rbp,%xmm3
  mulsd  %xmm1,%xmm3
  divsd  %xmm3,%xmm0
  call   <acosh@plt>
L21:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <cosh@plt>
  movq   %xmm0,%r15
  jmp    L5
L34:
  lea    0x8(%rsp),%r13
  mov    %rsp,%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  movq   %rbx,%xmm0
  call   <sincos@plt>
  mov    (%rsp),%rbx
  mov    0x8(%rsp),%r12
  mov    %r14,%rsi
  mov    %r13,%rdi
  movq   %rbp,%xmm0
  call   <sincos@plt>
  movq   %rbx,%xmm0
  mulsd  (%rsp),%xmm0
  movq   %r15,%xmm6
  addsd  %xmm6,%xmm0
  movq   %r12,%xmm1
  mulsd  0x8(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  call   <acosh@plt>
  jmp    L21
```

assistant: ```c
double computec(double al, double be, char imag1, double ga, char imag2) {
  double t = imag2 ? cosh(ga) : cos(ga);
  if (imag1)
    return acosh((t + cosh(al) * cosh(be)) / (sinh(al) * sinh(be)));
  else
    return acosh((t + cos(al) * cos(be)) / (sin(al) * sin(be)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<computec>:
  endbr64
  push   %r15
  movq   %xmm1,%r15
  push   %r14
  movq   %xmm0,%r14
  movapd %xmm2,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  test   %sil,%sil
  jne    L8
  call   <cos@plt>
  movsd  %xmm0,(%rsp)
L19:
  test   %bl,%bl
  je     L32
  movq   %r14,%xmm0
  call   <cosh@plt>
  movsd  %xmm0,0x8(%rsp)
  movq   %r15,%xmm0
  call   <cosh@plt>
  movsd  %xmm0,0x10(%rsp)
  movq   %r14,%xmm0
  call   <sinh@plt>
  movsd  %xmm0,0x18(%rsp)
  movq   %r15,%xmm0
  call   <sinh@plt>
  movsd  0x8(%rsp),%xmm3
  mulsd  0x10(%rsp),%xmm3
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm1
  addsd  %xmm3,%xmm0
L14:
  divsd  %xmm1,%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  jmp    10d0 <acosh@plt>
  nopl   (%rax)
L32:
  lea    0x28(%rsp),%rbp
  lea    0x20(%rsp),%r12
  movq   %r15,%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sincos@plt>
  mov    0x20(%rsp),%rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x28(%rsp),%xmm1
  movq   %r14,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sincos@plt>
  movq   %rbx,%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  0x20(%rsp),%xmm0
  mulsd  0x28(%rsp),%xmm1
  addsd  (%rsp),%xmm0
  jmp    L14
  nopl   0x0(%rax)
L8:
  call   <cosh@plt>
  movsd  %xmm0,(%rsp)
  jmp    L19
```

assistant: ```c
double computec(double al, double be, char imag1, double ga, char imag2) {
  double t = imag2 ? cosh(ga) : cos(ga);
  if (imag1)
    return acosh((t + cosh(al) * cosh(be)) / (sinh(al) * sinh(be)));
  else
    return acosh((t + cos(al) * cos(be)) / (sin(al) * sin(be)));
}
```