ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<centroid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movsd  D21(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movsd  D21(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  D21(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
data_type: f64

tool: D21: 3

assistant: ```c
void centroid(double *out, double *a, double *b, double *c) {
  *(out++) = (*(a++) + *(b++) + *(c++)) / 3.;
  *(out++) = (*(a++) + *(b++) + *(c++)) / 3.;
  *(out) = (*(a) + *(b) + *(c)) / 3.;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<centroid>:
  endbr64
  movsd  (%rsi),%xmm0
  addsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  D3(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  addsd  0x8(%rdx),%xmm0
  addsd  0x8(%rcx),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  addsd  0x10(%rdx),%xmm0
  addsd  0x10(%rcx),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: f64

tool: D3: 3

assistant: ```c
void centroid(double *out, double *a, double *b, double *c) {
  *(out++) = (*(a++) + *(b++) + *(c++)) / 3.;
  *(out++) = (*(a++) + *(b++) + *(c++)) / 3.;
  *(out) = (*(a) + *(b) + *(c)) / 3.;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<centroid>:
  endbr64
  movsd  (%rsi),%xmm0
  addsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  addsd  0x8(%rdx),%xmm0
  addsd  0x8(%rcx),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  addsd  0x10(%rdx),%xmm0
  addsd  0x10(%rcx),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: f64

tool: D6: 3

assistant: ```c
void centroid(double *out, double *a, double *b, double *c) {
  *(out++) = (*(a++) + *(b++) + *(c++)) / 3.;
  *(out++) = (*(a++) + *(b++) + *(c++)) / 3.;
  *(out) = (*(a) + *(b) + *(c)) / 3.;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<centroid>:
  endbr64
  movsd  (%rsi),%xmm0
  addsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  D3(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  addsd  0x8(%rdx),%xmm0
  addsd  0x8(%rcx),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  addsd  0x10(%rdx),%xmm0
  addsd  0x10(%rcx),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: f64

tool: D3: 3

assistant: ```c
void centroid(double *out, double *a, double *b, double *c) {
  *(out++) = (*(a++) + *(b++) + *(c++)) / 3.;
  *(out++) = (*(a++) + *(b++) + *(c++)) / 3.;
  *(out) = (*(a) + *(b) + *(c)) / 3.;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SplitIRCPrefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L36
  cmpq   $0x0,-0x20(%rbp)
  jne    L58
L36:
  mov    $0x0,%eax
  jmp    L43
L58:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L7
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L43
L7:
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
L43:
  leave
  ret
```

assistant: ```c
int SplitIRCPrefix(char *strCommand, char **strPrefix) {
  ;
  ;
  if (!strCommand || !strPrefix)
    return 0;
  if (*strCommand == ':') {
    char *str = strchr(++strCommand, ' ');
    if (str) {
      *strPrefix = strCommand;
      *str = '\0';
      return 1;
    }
  }
  *strPrefix = 0;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SplitIRCPrefix>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L21
  cmpb   $0x3a,(%rdi)
  je     L53
L44:
  movq   $0x0,0x0(%rbp)
  mov    $0x0,%eax
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L53:
  lea    0x1(%rdi),%rbx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L44
  mov    %rbx,0x0(%rbp)
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L20
L21:
  mov    $0x0,%eax
  jmp    L20
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int SplitIRCPrefix(char *strCommand, char **strPrefix) {
  ;
  ;
  if (!strCommand || !strPrefix)
    return 0;
  if (*strCommand == ':') {
    char *str = strchr(++strCommand, ' ');
    if (str) {
      *strPrefix = strCommand;
      *str = '\0';
      return 1;
    }
  }
  *strPrefix = 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SplitIRCPrefix>:
  endbr64
  test   %rdi,%rdi
  je     L30
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L16
  cmpb   $0x3a,(%rdi)
  je     L48
L3:
  movq   $0x0,0x0(%rbp)
  xor    %eax,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  lea    0x1(%rdi),%rbx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  mov    %rbx,0x0(%rbp)
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L17
  nopl   0x0(%rax)
L30:
  xor    %eax,%eax
  ret
```

assistant: ```c
int SplitIRCPrefix(char *strCommand, char **strPrefix) {
  ;
  ;
  if (!strCommand || !strPrefix)
    return 0;
  if (*strCommand == ':') {
    char *str = strchr(++strCommand, ' ');
    if (str) {
      *strPrefix = strCommand;
      *str = '\0';
      return 1;
    }
  }
  *strPrefix = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SplitIRCPrefix>:
  endbr64
  test   %rdi,%rdi
  je     L33
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L41
  cmpb   $0x3a,(%rdi)
  je     L22
L47:
  movq   $0x0,0x0(%rbp)
  xor    %eax,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L41:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L22:
  lea    0x1(%rdi),%rbx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L47
  mov    %rbx,0x0(%rbp)
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L15
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
int SplitIRCPrefix(char *strCommand, char **strPrefix) {
  ;
  ;
  if (!strCommand || !strPrefix)
    return 0;
  if (*strCommand == ':') {
    char *str = strchr(++strCommand, ' ');
    if (str) {
      *strPrefix = strCommand;
      *str = '\0';
      return 1;
    }
  }
  *strPrefix = 0;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stdimpl_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %rdi,-0x108(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L14
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L14:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  lea    -0x108(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0xf8(%rbp)
  mov    -0x108(%rbp),%rcx
  mov    -0xf8(%rbp),%rdx
  lea    -0xf0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <stdimpl_sprintf@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void stdimpl_print(const char *string, ...) {
  char outString[50];
  char **va_args = &string + 1;
  stdimpl_sprintf(outString, string, va_args);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stdimpl_print>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%rsi
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    %rdi,%rdx
  call   <stdimpl_sprintf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x58,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stdimpl_print(const char *string, ...) {
  char outString[50];
  char **va_args = &string + 1;
  stdimpl_sprintf(outString, string, va_args);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stdimpl_print>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%rsi
  mov    %rdi,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <stdimpl_sprintf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x58,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stdimpl_print(const char *string, ...) {
  char outString[50];
  char **va_args = &string + 1;
  stdimpl_sprintf(outString, string, va_args);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stdimpl_print>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%rsi
  mov    %rdi,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <stdimpl_sprintf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stdimpl_print(const char *string, ...) {
  char outString[50];
  char **va_args = &string + 1;
  stdimpl_sprintf(outString, string, va_args);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xxstrndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  nop
L11:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L11
L19:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xxmalloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L20:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *xxstrndup(const char *s, size_t n) {
  char *r = NULL;
  const char *p = s;
  while (*p++ && n--)
    ;
  n = p - s - 1;
  r = (char *)xxmalloc(n + 1);
  if (r != NULL) {
    memcpy(r, s, n);
    r[n] = 0;
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xxstrndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rdx
  mov    $0x1,%ecx
L2:
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  je     L29
  mov    %rcx,%rax
  sub    %rdx,%rax
  add    %rsi,%rax
  add    %rbp,%rax
  jne    L2
L29:
  mov    %rdx,%rbx
  sub    %rbp,%rbx
  mov    %rbx,%rdi
  call   <xxmalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L17
L12:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  jmp    L12
```

assistant: ```c
char *xxstrndup(const char *s, size_t n) {
  char *r = NULL;
  const char *p = s;
  while (*p++ && n--)
    ;
  n = p - s - 1;
  r = (char *)xxmalloc(n + 1);
  if (r != NULL) {
    memcpy(r, s, n);
    r[n] = 0;
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xxstrndup>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    $0x1,%ecx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L35
  nopl   (%rax)
L14:
  mov    %rcx,%rax
  sub    %rdx,%rax
  add    %rsi,%rax
  add    %rbp,%rax
  je     L37
L35:
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L14
L37:
  mov    %rdx,%rbx
  sub    %rbp,%rbx
  mov    %rbx,%rdi
  call   <xxmalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L8
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L8:
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *xxstrndup(const char *s, size_t n) {
  char *r = NULL;
  const char *p = s;
  while (*p++ && n--)
    ;
  n = p - s - 1;
  r = (char *)xxmalloc(n + 1);
  if (r != NULL) {
    memcpy(r, s, n);
    r[n] = 0;
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xxstrndup>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    $0x1,%ecx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L38
  nopl   (%rax)
L25:
  mov    %rcx,%rax
  sub    %rdx,%rax
  add    %rsi,%rax
  add    %rbp,%rax
  je     L9
L38:
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L25
L9:
  mov    %rdx,%rbx
  sub    %rbp,%rbx
  mov    %rbx,%rdi
  call   <xxmalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L32
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L32:
  lea    -0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *xxstrndup(const char *s, size_t n) {
  char *r = NULL;
  const char *p = s;
  while (*p++ && n--)
    ;
  n = p - s - 1;
  r = (char *)xxmalloc(n + 1);
  if (r != NULL) {
    memcpy(r, s, n);
    r[n] = 0;
  }
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cpu_pulse_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <nmi_device_reset@plt>
  mov    $0x0,%eax
  call   <output_device_reset@plt>
  mov    $0x0,%eax
  call   <input_device_reset@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cpu_pulse_reset(void) {
  nmi_device_reset();
  output_device_reset();
  input_device_reset();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cpu_pulse_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nmi_device_reset@plt>
  mov    $0x0,%eax
  call   <output_device_reset@plt>
  mov    $0x0,%eax
  call   <input_device_reset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cpu_pulse_reset(void) {
  nmi_device_reset();
  output_device_reset();
  input_device_reset();
}
```
user: What is the c source code of the assembly code below?

```asm
<cpu_pulse_reset>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nmi_device_reset@plt>
  xor    %eax,%eax
  call   <output_device_reset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <input_device_reset@plt>
```

assistant: ```c
void cpu_pulse_reset(void) {
  nmi_device_reset();
  output_device_reset();
  input_device_reset();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cpu_pulse_reset>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nmi_device_reset@plt>
  xor    %eax,%eax
  call   <output_device_reset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <input_device_reset@plt>
```

assistant: ```c
void cpu_pulse_reset(void) {
  nmi_device_reset();
  output_device_reset();
  input_device_reset();
}
```
user: Translate the below assembly code into C programming language:

```asm
<uputcmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,-0x14(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <pushw@plt>
  test   %eax,%eax
  je     L0
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <pushw@plt>
  test   %eax,%eax
  je     L0
  movsbl -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <pushw@plt>
  test   %eax,%eax
  je     L0
  mov    $0x1,%eax
  jmp    L34
L0:
  mov    $0x0,%eax
L34:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int uputcmd(u, size, start, cmd)
register struct undostack *u;
int size, start;
char cmd;
{ return (pushw(u, size) && pushw(u, start) && pushw(u, cmd)); }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uputcmd>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r12d
  mov    %ecx,%ebp
  mov    $0x0,%eax
  call   <pushw@plt>
  test   %eax,%eax
  jne    L4
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <pushw@plt>
  test   %eax,%eax
  je     L26
  movsbl %bpl,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <pushw@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L26
```

assistant: ```c
int uputcmd(u, size, start, cmd)
register struct undostack *u;
int size, start;
char cmd;
{ return (pushw(u, size) && pushw(u, start) && pushw(u, cmd)); }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uputcmd>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  call   <pushw@plt>
  test   %eax,%eax
  jne    L10
L11:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <pushw@plt>
  test   %eax,%eax
  je     L11
  movsbl %bl,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <pushw@plt>
  pop    %rbx
  pop    %rbp
  test   %eax,%eax
  pop    %r12
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int uputcmd(u, size, start, cmd)
register struct undostack *u;
int size, start;
char cmd;
{ return (pushw(u, size) && pushw(u, start) && pushw(u, cmd)); }
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<uputcmd>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  call   <pushw@plt>
  test   %eax,%eax
  jne    L1
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <pushw@plt>
  test   %eax,%eax
  je     L7
  movsbl %bl,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <pushw@plt>
  pop    %rbx
  pop    %rbp
  test   %eax,%eax
  pop    %r12
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int uputcmd(u, size, start, cmd)
register struct undostack *u;
int size, start;
char cmd;
{ return (pushw(u, size) && pushw(u, start) && pushw(u, cmd)); }
```
user: What would the C source look like for the assembly code provided here:

```asm
<calculatePid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isDigit@plt>
  test   %rax,%rax
  je     L25
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  jmp    L46
L25:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isDigit@plt>
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isDigit@plt>
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  jmp    L46
L1:
  mov    $0xffffffff,%eax
L46:
  leave
  ret
```

assistant: ```c
int calculatePid(char *string) {
  if (isDigit(string[0]) && string[1] == 0) {
    return string[0] - '0';
  } else if (isDigit(string[1]) && isDigit(string[0]) && string[2] == 0) {
    return (string[0] - '0') * 10 + string[1] - '0';
  } else {
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculatePid>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <isDigit@plt>
  test   %rax,%rax
  je     L43
  cmpb   $0x0,0x1(%rbx)
  je     L22
L43:
  movsbl 0x1(%rbx),%edi
  call   <isDigit@plt>
  test   %rax,%rax
  je     L66
  movsbl (%rbx),%edi
  call   <isDigit@plt>
  test   %rax,%rax
  je     L67
  cmpb   $0x0,0x2(%rbx)
  jne    L44
  movsbl (%rbx),%eax
  lea    -0xf0(%rax,%rax,4),%edx
  movsbl 0x1(%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%eax
L40:
  pop    %rbx
  ret
L22:
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  jmp    L40
L66:
  mov    $0xffffffff,%eax
  jmp    L40
L67:
  mov    $0xffffffff,%eax
  jmp    L40
L44:
  mov    $0xffffffff,%eax
  jmp    L40
```

assistant: ```c
int calculatePid(char *string) {
  if (isDigit(string[0]) && string[1] == 0) {
    return string[0] - '0';
  } else if (isDigit(string[1]) && isDigit(string[0]) && string[2] == 0) {
    return (string[0] - '0') * 10 + string[1] - '0';
  } else {
    return -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calculatePid>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <isDigit@plt>
  movsbl 0x1(%rbx),%edi
  test   %rax,%rax
  je     L23
  test   %dil,%dil
  je     L34
L23:
  call   <isDigit@plt>
  test   %rax,%rax
  je     L49
  movsbl (%rbx),%edi
  call   <isDigit@plt>
  test   %rax,%rax
  je     L49
  cmpb   $0x0,0x2(%rbx)
  jne    L49
  movsbl (%rbx),%eax
  lea    -0xf0(%rax,%rax,4),%edx
  movsbl 0x1(%rbx),%eax
  pop    %rbx
  lea    -0x30(%rax,%rdx,2),%eax
  ret
  nop
L34:
  movsbl (%rbx),%eax
  pop    %rbx
  sub    $0x30,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int calculatePid(char *string) {
  if (isDigit(string[0]) && string[1] == 0) {
    return string[0] - '0';
  } else if (isDigit(string[1]) && isDigit(string[0]) && string[2] == 0) {
    return (string[0] - '0') * 10 + string[1] - '0';
  } else {
    return -1;
  }
}
```