ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L55
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D26(%rip),%r12
L26:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L26
L55:
  lea    0xc(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    $0x0,%ebx
  lea    D37(%rip),%rbp
  cmp    %eax,0x8(%rsp)
  jge    L14
L47:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  lea    0x10(%rsp,%rbx,4),%rax
  sub    %ebx,%edx
  lea    -0x1(%rdx),%edx
  add    %rbx,%rdx
  lea    0x14(%rsp,%rdx,4),%rdx
  mov    $0x0,%esi
L7:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L7
L42:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  add    $0x1,%rbx
  mov    0x8(%rsp),%edx
  sub    %eax,%edx
  cmp    %ebx,%edx
  jl     L47
L14:
  lea    (%rax,%rbx,1),%edx
  mov    $0x0,%esi
  cmp    %ebx,%edx
  jg     L38
  jmp    L42
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D26
type_guessed: string
name: read_data
arguments: label: D37
type_guessed: string

tool: D26: %d

tool: D37: %d


assistant: ```c
int main() {
  int N;
  int arr[20];
  int k;
  int i, j, a, sum = 0;
  scanf("%d", &N);
  for (i = 0; i < N; i++) {
    scanf("%d", &arr[i]);
  }
  scanf("%d", &k);
  for (j = 0; j <= (N - k); j++) {
    for (a = j; a < (j + k); a++) {
      sum = sum + arr[a];
    }
    printf("%d\n", sum);
    sum = 0;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L18
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L16:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L16
L18:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  xor    %ebp,%ebp
  call   <scanf@plt>
  lea    D6(%rip),%rbx
  mov    0xc(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  jl     L65
  nopl   0x0(%rax,%rax,1)
L68:
  lea    (%rax,%rbp,1),%edx
  xor    %esi,%esi
  cmp    %ebp,%edx
  jle    L48
  sub    %ebp,%edx
  lea    0x10(%rsp,%rbp,4),%rax
  xor    %esi,%esi
  sub    $0x1,%edx
  add    %rbp,%rdx
  lea    0x14(%rsp,%rdx,4),%rdx
  nopl   (%rax)
L1:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L1
L48:
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%edx
  sub    %eax,%edx
  cmp    %ebp,%edx
  jge    L68
L65:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string

tool: D4: %d

tool: D6: %d


assistant: ```c
int main() {
  int N;
  int arr[20];
  int k;
  int i, j, a, sum = 0;
  scanf("%d", &N);
  for (i = 0; i < N; i++) {
    scanf("%d", &arr[i]);
  }
  scanf("%d", &k);
  for (j = 0; j <= (N - k); j++) {
    for (a = j; a < (j + k); a++) {
      sum = sum + arr[a];
    }
    printf("%d\n", sum);
    sum = 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L132
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L148:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L148
L132:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  jl     L47
  lea    0x10(%rsp),%r12
  xor    %ebx,%ebx
  lea    D16(%rip),%rbp
  nopl   0x0(%rax)
L123:
  lea    (%rax,%rbx,1),%ecx
  xor    %esi,%esi
  cmp    %ebx,%ecx
  jle    L88
  lea    -0x1(%rax),%edx
  cmp    $0x2,%edx
  jbe    L147
  mov    %eax,%edx
  movdqu (%r12),%xmm0
  shr    $0x2,%edx
  cmp    $0x1,%edx
  je     L27
  movdqu 0x10(%r12),%xmm2
  paddd  %xmm2,%xmm0
  cmp    $0x2,%edx
  je     L27
  movdqu 0x20(%r12),%xmm3
  paddd  %xmm3,%xmm0
  cmp    $0x3,%edx
  je     L27
  movdqu 0x30(%r12),%xmm4
  paddd  %xmm4,%xmm0
  cmp    $0x4,%edx
  je     L27
  movdqu 0x40(%r12),%xmm5
  paddd  %xmm5,%xmm0
L27:
  movdqa %xmm0,%xmm1
  mov    %eax,%edi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edi
  paddd  %xmm1,%xmm0
  lea    (%rdi,%rbx,1),%edx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  cmp    %edi,%eax
  je     L88
L0:
  movslq %edx,%rax
  add    0x10(%rsp,%rax,4),%esi
  lea    0x1(%rdx),%eax
  cmp    %ecx,%eax
  jge    L88
  cltq
  add    $0x2,%edx
  add    0x10(%rsp,%rax,4),%esi
  cmp    %edx,%ecx
  jle    L88
  movslq %edx,%rdx
  add    0x10(%rsp,%rdx,4),%esi
L88:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%edx
  sub    %eax,%edx
  cmp    %ebx,%edx
  jge    L123
L47:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L147:
  mov    %ebx,%edx
  xor    %esi,%esi
  jmp    L0
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D2: %d

tool: D16: %d


assistant: ```c
int main() {
  int N;
  int arr[20];
  int k;
  int i, j, a, sum = 0;
  scanf("%d", &N);
  for (i = 0; i < N; i++) {
    scanf("%d", &arr[i]);
  }
  scanf("%d", &k);
  for (j = 0; j <= (N - k); j++) {
    for (a = j; a < (j + k); a++) {
      sum = sum + arr[a];
    }
    printf("%d\n", sum);
    sum = 0;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<move_back_skip_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L8:
  subq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *move_back_skip_space(char *p) {
  char *p1;
  p1 = p;
  while (isspace(*p1))
    p1--;
  p1++;
  return p1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<move_back_skip_space>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L14
L0:
  sub    $0x1,%rbx
L14:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L0
  lea    0x1(%rbx),%rax
  pop    %rbx
  ret
```

assistant: ```c
char *move_back_skip_space(char *p) {
  char *p1;
  p1 = p;
  while (isspace(*p1))
    p1--;
  p1++;
  return p1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<move_back_skip_space>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L0:
  sub    $0x1,%rbx
L5:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L0
  lea    0x1(%rbx),%rax
  pop    %rbx
  ret
```

assistant: ```c
char *move_back_skip_space(char *p) {
  char *p1;
  p1 = p;
  while (isspace(*p1))
    p1--;
  p1++;
  return p1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<move_back_skip_space>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L16:
  sub    $0x1,%rbx
L14:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L16
  lea    0x1(%rbx),%rax
  pop    %rbx
  ret
```

assistant: ```c
char *move_back_skip_space(char *p) {
  char *p1;
  p1 = p;
  while (isspace(*p1))
    p1--;
  p1++;
  return p1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm1
  movss  D11(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D10
type_infered: string
name: parse_data
arguments: data_tag: D11
type_infered: byte[4]
name: parse_data
arguments: data_tag: D36
type_infered: string

tool: D4: Insira o peso: 

tool: D10: %f

tool: {"D11": [0x00,0x00,0x7a,0x44]}

tool: D36: Seu peso em gramas eh: %.2f

assistant: ```c
void main(void) {
  float peso;
  printf("Insira o peso: ");
  scanf("%f", &peso);
  peso *= 1000;
  printf("Seu peso em gramas eh: %.2f", peso);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  movss  D6(%rip),%xmm0
  mulss  0x4(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  cvtss2sd %xmm0,%xmm0
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D16
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: byte[4]
name: retrieve_data
arguments: label: D21
type_guessed: string

tool: D15: Insira o peso: 

tool: D16: %f

tool: {"D6": [0x00,0x00,0x7a,0x44]}

tool: D21: Seu peso em gramas eh: %.2f

assistant: ```c
void main(void) {
  float peso;
  printf("Insira o peso: ");
  scanf("%f", &peso);
  peso *= 1000;
  printf("Seu peso em gramas eh: %.2f", peso);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D36(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  D33(%rip),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  movss  %xmm0,0x4(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D36
type: string
name: extract_symbolic_data
arguments: data_tag: D33
type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D21
type: string

tool: D13: Insira o peso: 

tool: D36: %f

tool: {"D33": [0x00,0x00,0x7a,0x44]}

tool: D21: Seu peso em gramas eh: %.2f

assistant: ```c
void main(void) {
  float peso;
  printf("Insira o peso: ");
  scanf("%f", &peso);
  peso *= 1000;
  printf("Seu peso em gramas eh: %.2f", peso);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D35(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  D14(%rip),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  movss  %xmm0,0x4(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D35
type: string
name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D14
type: byte[4]
name: retrieve_data
arguments: tag: D3
type: string

tool: D35: Insira o peso: 

tool: D29: %f

tool: {"D14": [0x00,0x00,0x7a,0x44]}

tool: D3: Seu peso em gramas eh: %.2f

assistant: ```c
void main(void) {
  float peso;
  printf("Insira o peso: ");
  scanf("%f", &peso);
  peso *= 1000;
  printf("Seu peso em gramas eh: %.2f", peso);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pack_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cl,-0x14(%rbp)
  mov    %esi,%ecx
  mov    %cl,-0x18(%rbp)
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  movsbl -0x18(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  movsbl -0x1c(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  movsbl -0x20(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pack_char(char cha, char chb, char chc, char chd) {
  int integer_val = cha;
  integer_val = (integer_val << CHAR_BIT) | chb;
  integer_val = (integer_val << CHAR_BIT) | chc;
  integer_val = (integer_val << CHAR_BIT) | chd;
  return integer_val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pack_char>:
  endbr64
  mov    %ecx,%eax
  mov    D8(%rip),%rcx
  mov    (%rcx),%ecx
  movsbl %dil,%edi
  shl    %cl,%edi
  movsbl %sil,%esi
  or     %edi,%esi
  shl    %cl,%esi
  movsbl %dl,%edx
  or     %esi,%edx
  shl    %cl,%edx
  movsbl %al,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int pack_char(char cha, char chb, char chc, char chd) {
  int integer_val = cha;
  integer_val = (integer_val << CHAR_BIT) | chb;
  integer_val = (integer_val << CHAR_BIT) | chc;
  integer_val = (integer_val << CHAR_BIT) | chd;
  return integer_val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pack_char>:
  endbr64
  mov    %ecx,%r8d
  movsbl %dil,%edi
  movsbl %sil,%esi
  movsbl %dl,%edx
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  movsbl %r8b,%eax
  shl    %cl,%edi
  or     %edi,%esi
  shl    %cl,%esi
  or     %esi,%edx
  shl    %cl,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int pack_char(char cha, char chb, char chc, char chd) {
  int integer_val = cha;
  integer_val = (integer_val << CHAR_BIT) | chb;
  integer_val = (integer_val << CHAR_BIT) | chc;
  integer_val = (integer_val << CHAR_BIT) | chd;
  return integer_val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pack_char>:
  endbr64
  mov    %ecx,%r8d
  movsbl %dil,%edi
  movsbl %sil,%esi
  movsbl %dl,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%ecx
  movsbl %r8b,%eax
  shl    %cl,%edi
  or     %edi,%esi
  shl    %cl,%esi
  or     %esi,%edx
  shl    %cl,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int pack_char(char cha, char chb, char chc, char chd) {
  int integer_val = cha;
  integer_val = (integer_val << CHAR_BIT) | chb;
  integer_val = (integer_val << CHAR_BIT) | chc;
  integer_val = (integer_val << CHAR_BIT) | chd;
  return integer_val;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<phmmUnpackMommy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  movzbl -0x4(%rbp),%eax
  sar    $0x5,%eax
  and    $0x1,%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  movzbl -0x4(%rbp),%eax
  sar    $0x6,%eax
  and    $0x1,%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void phmmUnpackMommy(unsigned char mommy, int *retStateIx, int *retQoff, int *retToff) {
  *retStateIx = (mommy & 31);
  *retQoff = -((mommy & 32) >> 5);
  *retToff = -((mommy & 64) >> 6);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<phmmUnpackMommy>:
  endbr64
  mov    %edi,%eax
  and    $0x1f,%eax
  mov    %eax,(%rsi)
  mov    %edi,%eax
  shl    $0x1a,%eax
  sar    $0x1f,%eax
  mov    %eax,(%rdx)
  shl    $0x19,%edi
  sar    $0x1f,%edi
  mov    %edi,(%rcx)
  ret
```

assistant: ```c
void phmmUnpackMommy(unsigned char mommy, int *retStateIx, int *retQoff, int *retToff) {
  *retStateIx = (mommy & 31);
  *retQoff = -((mommy & 32) >> 5);
  *retToff = -((mommy & 64) >> 6);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<phmmUnpackMommy>:
  endbr64
  mov    %edi,%eax
  and    $0x1f,%eax
  mov    %eax,(%rsi)
  mov    %edi,%eax
  shl    $0x19,%edi
  shl    $0x1a,%eax
  sar    $0x1f,%edi
  sar    $0x1f,%eax
  mov    %eax,(%rdx)
  mov    %edi,(%rcx)
  ret
```

assistant: ```c
void phmmUnpackMommy(unsigned char mommy, int *retStateIx, int *retQoff, int *retToff) {
  *retStateIx = (mommy & 31);
  *retQoff = -((mommy & 32) >> 5);
  *retToff = -((mommy & 64) >> 6);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<phmmUnpackMommy>:
  endbr64
  mov    %edi,%eax
  and    $0x1f,%eax
  mov    %eax,(%rsi)
  mov    %edi,%eax
  shl    $0x19,%edi
  shl    $0x1a,%eax
  sar    $0x1f,%edi
  sar    $0x1f,%eax
  mov    %eax,(%rdx)
  mov    %edi,(%rcx)
  ret
```

assistant: ```c
void phmmUnpackMommy(unsigned char mommy, int *retStateIx, int *retQoff, int *retToff) {
  *retStateIx = (mommy & 31);
  *retQoff = -((mommy & 32) >> 5);
  *retToff = -((mommy & 64) >> 6);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dav1d_inv_identity16_1d_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L2:
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  imul   $0x6a1,%eax,%eax
  add    $0x400,%eax
  sar    $0xb,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0xf,-0x8(%rbp)
  jle    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void dav1d_inv_identity16_1d_c(int32_t *const c, const ptrdiff_t stride, const int min, const int max) {
  assert(stride > 0);
  for (int i = 0; i < 16; i++) {
    const int in = c[stride * i];
    c[stride * i] = 2 * in + ((in * 1697 + 1024) >> 11);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dav1d_inv_identity16_1d_c>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   %esi,%esi
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movslq %ebp,%rsi
  shl    $0x2,%rsi
  mov    %rbx,%rdi
  mov    $0x10,%edx
L4:
  mov    (%rdi),%ecx
  imul   $0x6a1,%ecx,%eax
  add    $0x400,%eax
  sar    $0xb,%eax
  lea    (%rax,%rcx,2),%eax
  mov    %eax,(%rdi)
  add    %rsi,%rdi
  sub    $0x1,%edx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void dav1d_inv_identity16_1d_c(int32_t *const c, const ptrdiff_t stride, const int min, const int max) {
  assert(stride > 0);
  for (int i = 0; i < 16; i++) {
    const int in = c[stride * i];
    c[stride * i] = 2 * in + ((in * 1697 + 1024) >> 11);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dav1d_inv_identity16_1d_c>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %esi,%esi
  setg   %dil
  call   <assert@plt>
  movslq %ebp,%rsi
  mov    %rbx,%rdi
  mov    $0x10,%edx
  shl    $0x2,%rsi
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rdi),%ecx
  imul   $0x6a1,%ecx,%eax
  add    $0x400,%eax
  sar    $0xb,%eax
  lea    (%rax,%rcx,2),%eax
  mov    %eax,(%rdi)
  add    %rsi,%rdi
  sub    $0x1,%edx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void dav1d_inv_identity16_1d_c(int32_t *const c, const ptrdiff_t stride, const int min, const int max) {
  assert(stride > 0);
  for (int i = 0; i < 16; i++) {
    const int in = c[stride * i];
    c[stride * i] = 2 * in + ((in * 1697 + 1024) >> 11);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<gffi_set_uint_64_swapped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0x1c(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0x14(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x5,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x6,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x7,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gffi_set_uint_64_swapped(uint8_t *location, int offset, uint64_t value) {
  uint8_t *buf = (uint8_t *)&value;
  location[offset + 0] = buf[7];
  location[offset + 1] = buf[6];
  location[offset + 2] = buf[5];
  location[offset + 3] = buf[4];
  location[offset + 4] = buf[3];
  location[offset + 5] = buf[2];
  location[offset + 6] = buf[1];
  location[offset + 7] = buf[0];
}
```