ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<patch_get_input_crc>:
  endbr64
  cmp    $0xf,%rsi
  jbe    L33
  push   %r12
  mov    %rdx,%r12
  mov    $0x4,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D14(%rip),%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L42
L44:
  test   %r12,%r12
  je     L20
  sub    $0xc,%ebx
  movslq %ebx,%rbx
  mov    0x0(%rbp,%rbx,4),%eax
  lea    0x0(,%rbx,4),%rcx
  mov    %eax,(%r12)
  mov    0x4(%rbp,%rcx,1),%edx
  shl    $0x8,%edx
  or     %eax,%edx
  mov    %edx,(%r12)
  mov    0x8(%rbp,%rcx,1),%eax
  shl    $0x10,%eax
  or     %edx,%eax
  mov    %eax,(%r12)
  mov    0xc(%rbp,%rcx,1),%edx
  shl    $0x18,%edx
  or     %edx,%eax
  mov    %eax,(%r12)
L20:
  xor    %eax,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    $0x4,%edx
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L44
  mov    $0xffffffff,%eax
  jmp    L11
L33:
  or     $0xffffffff,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string

tool: D14: UPS1

tool: D18: BPS1

assistant: ```c
int patch_get_input_crc(uint8_t *patch, size_t patch_size, uint32_t *crc) {
  if (patch_size < 16)
    return -1;
  if ((memcmp(patch, "UPS1", 4) == 0) || (memcmp(patch, "BPS1", 4) == 0)) {
    int offset = patch_size - 12;
    if (crc) {
      *crc = patch[offset];
      *crc |= patch[offset + 1] << 8;
      *crc |= patch[offset + 2] << 16;
      *crc |= patch[offset + 3] << 24;
    }
    return 0;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<patch_get_input_crc>:
  endbr64
  cmp    $0xf,%rsi
  jbe    L37
  push   %r12
  mov    %rdx,%r12
  mov    $0x4,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D19(%rip),%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L36
L40:
  test   %r12,%r12
  je     L11
  sub    $0xc,%ebx
  movslq %ebx,%rbx
  mov    0x0(%rbp,%rbx,4),%eax
  lea    0x0(,%rbx,4),%rcx
  mov    %eax,(%r12)
  mov    0x4(%rbp,%rcx,1),%edx
  shl    $0x8,%edx
  or     %eax,%edx
  mov    %edx,(%r12)
  mov    0x8(%rbp,%rcx,1),%eax
  shl    $0x10,%eax
  or     %edx,%eax
  mov    %eax,(%r12)
  mov    0xc(%rbp,%rcx,1),%edx
  shl    $0x18,%edx
  or     %edx,%eax
  mov    %eax,(%r12)
L11:
  xor    %eax,%eax
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    $0x4,%edx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L40
  mov    $0xffffffff,%eax
  jmp    L47
L37:
  or     $0xffffffff,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D19: UPS1

tool: D5: BPS1

assistant: ```c
int patch_get_input_crc(uint8_t *patch, size_t patch_size, uint32_t *crc) {
  if (patch_size < 16)
    return -1;
  if ((memcmp(patch, "UPS1", 4) == 0) || (memcmp(patch, "BPS1", 4) == 0)) {
    int offset = patch_size - 12;
    if (crc) {
      *crc = patch[offset];
      *crc |= patch[offset + 1] << 8;
      *crc |= patch[offset + 2] << 16;
      *crc |= patch[offset + 3] << 24;
    }
    return 0;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<common_Frame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <Cbuf_Execute@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <Client_Frame@plt>
  nop
  leave
  ret
```

assistant: ```c
void common_Frame(int msec) {
  Cbuf_Execute();
  Client_Frame(msec);
}
```
user: Translate the below assembly code into C programming language:

```asm
<common_Frame>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <Cbuf_Execute@plt>
  mov    %ebx,%edi
  call   <Client_Frame@plt>
  pop    %rbx
  ret
```

assistant: ```c
void common_Frame(int msec) {
  Cbuf_Execute();
  Client_Frame(msec);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<common_Frame>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <Cbuf_Execute@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <Client_Frame@plt>
```

assistant: ```c
void common_Frame(int msec) {
  Cbuf_Execute();
  Client_Frame(msec);
}
```
user: Translate the below assembly code into C programming language:

```asm
<common_Frame>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <Cbuf_Execute@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <Client_Frame@plt>
```

assistant: ```c
void common_Frame(int msec) {
  Cbuf_Execute();
  Client_Frame(msec);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_dtype_normalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3e,%eax
  jg     L20
  cmp    $0x3c,%eax
  jge    L38
  jmp    L23
L20:
  cmp    $0x7c,%eax
  jne    L23
L38:
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L11
L23:
  mov    -0x8(%rbp),%rax
  movb   $0x3d,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x7,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
L11:
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L43
  mov    $0x0,%eax
  call   <MACHINE_ENDIAN_F@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
L43:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  jne    L63
  mov    $0x0,%eax
  call   <MACHINE_ENDIAN_F@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
L63:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int _dtype_normalize(char *dst, const char *src) {
  memset(dst, 0, 8);
  switch (src[0]) {
  case '<':
  case '>':
  case '|':
  case '=':
    strncpy(dst, src, 8);
    break;
  default:
    dst[0] = '=';
    strncpy(dst + 1, src, 7);
  }
  dst[7] = '\0';
  if (dst[0] == '=') {
    dst[0] = MACHINE_ENDIAN_F();
  }
  if (dst[0] == '|') {
    dst[0] = MACHINE_ENDIAN_F();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<_dtype_normalize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movzbl 0x0(%rbp),%eax
  cmp    $0x3e,%al
  jg     L19
  cmp    $0x3b,%al
  jg     L12
L66:
  movb   $0x3d,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    $0x7,%edx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  jmp    L49
L19:
  cmp    $0x7c,%al
  jne    L66
L12:
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
L49:
  movb   $0x0,0x7(%rbx)
  cmpb   $0x3d,(%rbx)
  je     L50
L26:
  cmpb   $0x7c,(%rbx)
  je     L16
L23:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  mov    $0x0,%eax
  call   <MACHINE_ENDIAN_F@plt>
  mov    %al,(%rbx)
  jmp    L26
L16:
  mov    $0x0,%eax
  call   <MACHINE_ENDIAN_F@plt>
  mov    %al,(%rbx)
  jmp    L23
```

assistant: ```c
int _dtype_normalize(char *dst, const char *src) {
  memset(dst, 0, 8);
  switch (src[0]) {
  case '<':
  case '>':
  case '|':
  case '=':
    strncpy(dst, src, 8);
    break;
  default:
    dst[0] = '=';
    strncpy(dst + 1, src, 7);
  }
  dst[7] = '\0';
  if (dst[0] == '=') {
    dst[0] = MACHINE_ENDIAN_F();
  }
  if (dst[0] == '|') {
    dst[0] = MACHINE_ENDIAN_F();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_dtype_normalize>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  movzbl 0x0(%rbp),%eax
  cmp    $0x3e,%al
  jg     L5
  cmp    $0x3b,%al
  jg     L23
L67:
  movb   $0x3d,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    $0x7,%edx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  movzbl (%rbx),%eax
  movb   $0x0,0x7(%rbx)
  cmp    $0x3d,%al
  je     L15
L53:
  cmp    $0x7c,%al
  je     L56
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  cmp    $0x7c,%al
  jne    L67
L23:
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movzbl (%rbx),%eax
  movb   $0x0,0x7(%rbx)
  cmp    $0x3d,%al
  jne    L53
L15:
  xor    %eax,%eax
  call   <MACHINE_ENDIAN_F@plt>
  mov    %al,(%rbx)
  cmp    $0x7c,%al
  jne    L19
L56:
  xor    %eax,%eax
  call   <MACHINE_ENDIAN_F@plt>
  mov    %al,(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _dtype_normalize(char *dst, const char *src) {
  memset(dst, 0, 8);
  switch (src[0]) {
  case '<':
  case '>':
  case '|':
  case '=':
    strncpy(dst, src, 8);
    break;
  default:
    dst[0] = '=';
    strncpy(dst + 1, src, 7);
  }
  dst[7] = '\0';
  if (dst[0] == '=') {
    dst[0] = MACHINE_ENDIAN_F();
  }
  if (dst[0] == '|') {
    dst[0] = MACHINE_ENDIAN_F();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_dtype_normalize>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  movzbl 0x0(%rbp),%eax
  cmp    $0x3e,%al
  jg     L67
  cmp    $0x3b,%al
  jg     L36
L14:
  movb   $0x3d,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    $0x7,%edx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  movzbl (%rbx),%eax
  movb   $0x0,0x7(%rbx)
  cmp    $0x3d,%al
  je     L6
L51:
  cmp    $0x7c,%al
  je     L12
L24:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L67:
  cmp    $0x7c,%al
  jne    L14
L36:
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movzbl (%rbx),%eax
  movb   $0x0,0x7(%rbx)
  cmp    $0x3d,%al
  jne    L51
L6:
  xor    %eax,%eax
  call   <MACHINE_ENDIAN_F@plt>
  mov    %al,(%rbx)
  cmp    $0x7c,%al
  jne    L24
L12:
  xor    %eax,%eax
  call   <MACHINE_ENDIAN_F@plt>
  mov    %al,(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _dtype_normalize(char *dst, const char *src) {
  memset(dst, 0, 8);
  switch (src[0]) {
  case '<':
  case '>':
  case '|':
  case '=':
    strncpy(dst, src, 8);
    break;
  default:
    dst[0] = '=';
    strncpy(dst + 1, src, 7);
  }
  dst[7] = '\0';
  if (dst[0] == '=') {
    dst[0] = MACHINE_ENDIAN_F();
  }
  if (dst[0] == '|') {
    dst[0] = MACHINE_ENDIAN_F();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<videoinput_get_norm_height>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  cmpl   $0x6,-0x4(%rbp)
  je     L13
  cmpl   $0x4,-0x4(%rbp)
  je     L13
  cmpl   $0x7,-0x4(%rbp)
  jne    L45
L13:
  mov    $0x1e0,%eax
  jmp    L11
L45:
  mov    $0x240,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int videoinput_get_norm_height(int norm) {
  if (norm == 0 || norm == 6 || norm == 4 || norm == 7) {
    return 480;
  } else {
    return 576;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<videoinput_get_norm_height>:
  endbr64
  cmp    $0x7,%edi
  ja     L7
  mov    $0xd1,%eax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x60,%eax
  add    $0x1e0,%eax
  ret
L7:
  mov    $0x240,%eax
  ret
```

assistant: ```c
int videoinput_get_norm_height(int norm) {
  if (norm == 0 || norm == 6 || norm == 4 || norm == 7) {
    return 480;
  } else {
    return 576;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<videoinput_get_norm_height>:
  endbr64
  cmp    $0x7,%edi
  ja     L8
  mov    %edi,%ecx
  mov    $0xd1,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    %eax,%eax
  and    $0x60,%eax
  add    $0x1e0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x240,%eax
  ret
```

assistant: ```c
int videoinput_get_norm_height(int norm) {
  if (norm == 0 || norm == 6 || norm == 4 || norm == 7) {
    return 480;
  } else {
    return 576;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<videoinput_get_norm_height>:
  endbr64
  cmp    $0x7,%edi
  ja     L1
  mov    %edi,%ecx
  mov    $0xd1,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    %eax,%eax
  and    $0x60,%eax
  add    $0x1e0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x240,%eax
  ret
```

assistant: ```c
int videoinput_get_norm_height(int norm) {
  if (norm == 0 || norm == 6 || norm == 4 || norm == 7) {
    return 480;
  } else {
    return 576;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uses_allocator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <allocate@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x2a,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void uses_allocator() {
  int *p;
  p = allocate();
  *p = 42;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uses_allocator>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <allocate@plt>
  movl   $0x2a,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uses_allocator() {
  int *p;
  p = allocate();
  *p = 42;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uses_allocator>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <allocate@plt>
  movl   $0x2a,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uses_allocator() {
  int *p;
  p = allocate();
  *p = 42;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uses_allocator>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <allocate@plt>
  movl   $0x2a,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uses_allocator() {
  int *p;
  p = allocate();
  *p = 42;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SkipUntilWhiteSpaceReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L39
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L13
  subq   $0x1,-0x8(%rbp)
L39:
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L16
L13:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *SkipUntilWhiteSpaceReverse(const char *pSrc, const char *pStart) {
  while (pSrc && (pSrc > pStart)) {
    if ((*pSrc == ' ') || (*pSrc == '\t')) {
      break;
    }
    pSrc--;
  }
  return pSrc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SkipUntilWhiteSpaceReverse>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L13
  cmp    %rsi,%rdi
  jbe    L13
L33:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L13
  cmp    $0x9,%dl
  je     L13
  sub    $0x1,%rax
  cmp    %rax,%rsi
  jb     L33
L13:
  ret
```

assistant: ```c
const char *SkipUntilWhiteSpaceReverse(const char *pSrc, const char *pStart) {
  while (pSrc && (pSrc > pStart)) {
    if ((*pSrc == ' ') || (*pSrc == '\t')) {
      break;
    }
    pSrc--;
  }
  return pSrc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SkipUntilWhiteSpaceReverse>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jbe    L7
  test   %rdi,%rdi
  je     L7
  nopl   0x0(%rax)
L45:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L7
  cmp    $0x9,%dl
  je     L7
  sub    $0x1,%rax
  cmp    %rax,%rsi
  jb     L45
L7:
  ret
```

assistant: ```c
const char *SkipUntilWhiteSpaceReverse(const char *pSrc, const char *pStart) {
  while (pSrc && (pSrc > pStart)) {
    if ((*pSrc == ' ') || (*pSrc == '\t')) {
      break;
    }
    pSrc--;
  }
  return pSrc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SkipUntilWhiteSpaceReverse>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jbe    L1
  test   %rdi,%rdi
  je     L1
  nopl   0x0(%rax)
L9:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L1
  cmp    $0x9,%dl
  je     L1
  sub    $0x1,%rax
  cmp    %rax,%rsi
  jb     L9
L1:
  ret
```

assistant: ```c
const char *SkipUntilWhiteSpaceReverse(const char *pSrc, const char *pStart) {
  while (pSrc && (pSrc > pStart)) {
    if ((*pSrc == ' ') || (*pSrc == '\t')) {
      break;
    }
    pSrc--;
  }
  return pSrc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x50(%rbp)
  jmp    L40
L51:
  mov    -0x50(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x50(%rbp),%eax
  cltq
  mov    %edx,-0x2c(%rbp,%rax,4)
  addl   $0x1,-0x50(%rbp)
L40:
  cmpl   $0x2,-0x50(%rbp)
  jle    L51
  movl   $0x1,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L70
L43:
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x2c(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4c(%rbp)
L70:
  cmpl   $0x2,-0x4c(%rbp)
  jle    L43
  movl   $0x0,-0x48(%rbp)
  jmp    L5
L9:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%eax
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x40(%rbp)
  addl   $0x1,-0x48(%rbp)
L5:
  cmpl   $0x2,-0x48(%rbp)
  jle    L9
  movl   $0x0,-0x44(%rbp)
  jmp    L28
L62:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x2c(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L28:
  cmpl   $0x2,-0x44(%rbp)
  jle    L62
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x8,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subq   $0x8,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x8,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D31
datatype: string

tool: D31: %d


assistant: ```c
int main() {
  int i[3];
  int *ii;
  for (int j = 0; j < 3; ++j) {
    i[j] = j + 1;
  }
  i[0] = 1;
  i[1] = 2;
  i[2] = 3;
  ii = i;
  for (int j = 0; j < 3; ++j) {
    printf("%d\n", i[j]);
  }
  for (int j = 0; j < 3; ++j) {
    *ii = *ii + j + 1;
    ii = ii + 1;
  }
  for (int j = 0; j < 3; ++j) {
    printf("%d\n", i[j]);
  }
  int k[2][2];
  k[0][0] = 5;
  k[1][0] = 6;
  int(*kk)[2] = k;
  printf("%d\n", (*kk)[0]);
  ++kk;
  printf("%d\n", (*kk)[0]);
  --kk;
  printf("%d\n", (*kk)[0]);
  kk = kk - (-1);
  printf("%d\n", (*kk)[0]);
  0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  mov    $0x1,%esi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  lea    0xc(%rsp),%rax
L8:
  mov    %edx,%ecx
  add    (%rax),%ecx
  add    $0x1,%ecx
  mov    %ecx,(%rax)
  add    $0x4,%rax
  add    $0x1,%edx
  cmp    $0x3,%edx
  jne    L8
  mov    0xc(%rsp),%esi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string

tool: D14: %d


assistant: ```c
int main() {
  int i[3];
  int *ii;
  for (int j = 0; j < 3; ++j) {
    i[j] = j + 1;
  }
  i[0] = 1;
  i[1] = 2;
  i[2] = 3;
  ii = i;
  for (int j = 0; j < 3; ++j) {
    printf("%d\n", i[j]);
  }
  for (int j = 0; j < 3; ++j) {
    *ii = *ii + j + 1;
    ii = ii + 1;
  }
  for (int j = 0; j < 3; ++j) {
    printf("%d\n", i[j]);
  }
  int k[2][2];
  k[0][0] = 5;
  k[1][0] = 6;
  int(*kk)[2] = k;
  printf("%d\n", (*kk)[0]);
  ++kk;
  printf("%d\n", (*kk)[0]);
  --kk;
  printf("%d\n", (*kk)[0]);
  kk = kk - (-1);
  printf("%d\n", (*kk)[0]);
  0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: %d


assistant: ```c
int main() {
  int i[3];
  int *ii;
  for (int j = 0; j < 3; ++j) {
    i[j] = j + 1;
  }
  i[0] = 1;
  i[1] = 2;
  i[2] = 3;
  ii = i;
  for (int j = 0; j < 3; ++j) {
    printf("%d\n", i[j]);
  }
  for (int j = 0; j < 3; ++j) {
    *ii = *ii + j + 1;
    ii = ii + 1;
  }
  for (int j = 0; j < 3; ++j) {
    printf("%d\n", i[j]);
  }
  int k[2][2];
  k[0][0] = 5;
  k[1][0] = 6;
  int(*kk)[2] = k;
  printf("%d\n", (*kk)[0]);
  ++kk;
  printf("%d\n", (*kk)[0]);
  --kk;
  printf("%d\n", (*kk)[0]);
  kk = kk - (-1);
  printf("%d\n", (*kk)[0]);
  0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: %d


assistant: ```c
int main() {
  int i[3];
  int *ii;
  for (int j = 0; j < 3; ++j) {
    i[j] = j + 1;
  }
  i[0] = 1;
  i[1] = 2;
  i[2] = 3;
  ii = i;
  for (int j = 0; j < 3; ++j) {
    printf("%d\n", i[j]);
  }
  for (int j = 0; j < 3; ++j) {
    *ii = *ii + j + 1;
    ii = ii + 1;
  }
  for (int j = 0; j < 3; ++j) {
    printf("%d\n", i[j]);
  }
  int k[2][2];
  k[0][0] = 5;
  k[1][0] = 6;
  int(*kk)[2] = k;
  printf("%d\n", (*kk)[0]);
  ++kk;
  printf("%d\n", (*kk)[0]);
  --kk;
  printf("%d\n", (*kk)[0]);
  kk = kk - (-1);
  printf("%d\n", (*kk)[0]);
  0;
  return 0;
}
```