ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  je     L6
  mov    $0xffffffff,%eax
  jmp    L16
L6:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <strupncmp@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
signed int compare(const char *a, const char *b) {
  unsigned long int return_value_strlen$1;
  return_value_strlen$1 = strlen(a);
  unsigned long int return_value_strlen$2;
  return_value_strlen$2 = strlen(b);
  if (!(return_value_strlen$1 == return_value_strlen$2))
    return -1;
  unsigned long int return_value_strlen$3;
  return_value_strlen$3 = strlen(a);
  signed int return_value_strupncmp$4;
  return_value_strupncmp$4 = strupncmp(a, b, (signed int)return_value_strlen$3);
  return return_value_strupncmp$4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compare>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jne    L12
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <strupncmp@plt>
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
signed int compare(const char *a, const char *b) {
  unsigned long int return_value_strlen$1;
  return_value_strlen$1 = strlen(a);
  unsigned long int return_value_strlen$2;
  return_value_strlen$2 = strlen(b);
  if (!(return_value_strlen$1 == return_value_strlen$2))
    return -1;
  unsigned long int return_value_strlen$3;
  return_value_strlen$3 = strlen(a);
  signed int return_value_strupncmp$4;
  return_value_strupncmp$4 = strupncmp(a, b, (signed int)return_value_strlen$3);
  return return_value_strupncmp$4;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compare>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jne    L2
  mov    %ebx,%edx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1060 <strupncmp@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
signed int compare(const char *a, const char *b) {
  unsigned long int return_value_strlen$1;
  return_value_strlen$1 = strlen(a);
  unsigned long int return_value_strlen$2;
  return_value_strlen$2 = strlen(b);
  if (!(return_value_strlen$1 == return_value_strlen$2))
    return -1;
  unsigned long int return_value_strlen$3;
  return_value_strlen$3 = strlen(a);
  signed int return_value_strupncmp$4;
  return_value_strupncmp$4 = strupncmp(a, b, (signed int)return_value_strlen$3);
  return return_value_strupncmp$4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L53
L15:
  addq   $0x1,-0x18(%rbp)
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L109
  mov    $0x0,%eax
  jmp    L121
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x22,%eax
  je     L4
  cmp    $0x5c,%eax
  je     L56
  jmp    L11
L4:
  mov    $0x1,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L79
L56:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L79
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L110
  cmpl   $0x0,-0x4(%rbp)
  jne    L110
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L121
L110:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  nop
L79:
  addq   $0x1,-0x18(%rbp)
L109:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L121:
  leave
  ret
```

assistant: ```c
char *get_token(char *inp, char *buf) {
  int quoted = 0;
  while (*inp && isspace(*inp))
    inp++;
  if (*inp == 0)
    return 0;
  while (*inp) {
    switch (*inp) {
    case '"':
      quoted = 1 - quoted;
      break;
    case '\\':
      *buf++ = *inp;
      *buf++ = *++inp;
      break;
    default:
      if (isspace(*inp) && !quoted) {
        *buf = 0;
        return inp;
      }
      *buf++ = *inp;
      break;
    }
    inp++;
  }
  *buf = 0;
  return inp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_token>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L134
L92:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L74
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L92
L134:
  mov    $0x0,%eax
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L74:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L62
  mov    $0x0,%r12d
  mov    $0x1,%r13d
  jmp    L66
L85:
  mov    %r13d,%eax
  sub    %r12d,%eax
  mov    %eax,%r12d
  mov    %rbx,%rax
L28:
  lea    0x1(%rax),%rbx
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L121
L66:
  cmp    $0x22,%dil
  je     L85
  cmp    $0x5c,%dil
  je     L98
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %r12d,%r12d
  jne    L91
  test   %rax,%rax
  jne    L29
L91:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  mov    %rbx,%rax
  jmp    L28
L98:
  movb   $0x5c,0x0(%rbp)
  lea    0x1(%rbx),%rax
  movzbl 0x1(%rbx),%edx
  mov    %dl,0x1(%rbp)
  lea    0x2(%rbp),%rbp
  jmp    L28
L29:
  movb   $0x0,0x0(%rbp)
  mov    %rbx,%rax
  jmp    L62
L121:
  movb   $0x0,0x0(%rbp)
  mov    %rbx,%rax
  jmp    L62
```

assistant: ```c
char *get_token(char *inp, char *buf) {
  int quoted = 0;
  while (*inp && isspace(*inp))
    inp++;
  if (*inp == 0)
    return 0;
  while (*inp) {
    switch (*inp) {
    case '"':
      quoted = 1 - quoted;
      break;
    case '\\':
      *buf++ = *inp;
      *buf++ = *++inp;
      break;
    default:
      if (isspace(*inp) && !quoted) {
        *buf = 0;
        return inp;
      }
      *buf++ = *inp;
      break;
    }
    inp++;
  }
  *buf = 0;
  return inp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_token>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L46
  jmp    L91
  nopl   0x0(%rax)
L57:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L91
L46:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L57
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L91
  xor    %r13d,%r13d
  mov    $0x1,%r12d
  jmp    L93
  nopw   0x0(%rax,%rax,1)
L81:
  call   <isspace@plt>
  test   $0x1,%r13b
  jne    L21
  test   %rax,%rax
  jne    L73
L21:
  movzbl (%rbx),%eax
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  mov    %rbx,%rax
L47:
  movsbl 0x1(%rax),%edi
  lea    0x1(%rax),%rbx
  test   %dil,%dil
  je     L73
L93:
  cmp    $0x22,%dil
  je     L61
  cmp    $0x5c,%dil
  jne    L81
  movb   $0x5c,0x0(%rbp)
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rax
  add    $0x2,%rbp
  lea    0x1(%rax),%rbx
  mov    %dl,-0x1(%rbp)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  jne    L93
L73:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L91:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L61:
  mov    %r12d,%eax
  sub    %r13d,%eax
  mov    %eax,%r13d
  mov    %rbx,%rax
  jmp    L47
```

assistant: ```c
char *get_token(char *inp, char *buf) {
  int quoted = 0;
  while (*inp && isspace(*inp))
    inp++;
  if (*inp == 0)
    return 0;
  while (*inp) {
    switch (*inp) {
    case '"':
      quoted = 1 - quoted;
      break;
    case '\\':
      *buf++ = *inp;
      *buf++ = *++inp;
      break;
    default:
      if (isspace(*inp) && !quoted) {
        *buf = 0;
        return inp;
      }
      *buf++ = *inp;
      break;
    }
    inp++;
  }
  *buf = 0;
  return inp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_token>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L118
  jmp    L2
  nopl   0x0(%rax)
L77:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L2
L118:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L77
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L2
  xor    %r13d,%r13d
  mov    $0x1,%r12d
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L6:
  call   <isspace@plt>
  test   $0x1,%r13b
  jne    L105
  test   %rax,%rax
  jne    L79
L105:
  movzbl (%rbx),%eax
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  mov    %rbx,%rax
L4:
  movsbl 0x1(%rax),%edi
  lea    0x1(%rax),%rbx
  test   %dil,%dil
  je     L79
L52:
  cmp    $0x22,%dil
  je     L120
  cmp    $0x5c,%dil
  jne    L6
  movb   $0x5c,0x0(%rbp)
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rax
  add    $0x2,%rbp
  lea    0x1(%rax),%rbx
  mov    %dl,-0x1(%rbp)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  jne    L52
L79:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L120:
  mov    %r12d,%eax
  sub    %r13d,%eax
  mov    %eax,%r13d
  mov    %rbx,%rax
  jmp    L4
```

assistant: ```c
char *get_token(char *inp, char *buf) {
  int quoted = 0;
  while (*inp && isspace(*inp))
    inp++;
  if (*inp == 0)
    return 0;
  while (*inp) {
    switch (*inp) {
    case '"':
      quoted = 1 - quoted;
      break;
    case '\\':
      *buf++ = *inp;
      *buf++ = *++inp;
      break;
    default:
      if (isspace(*inp) && !quoted) {
        *buf = 0;
        return inp;
      }
      *buf++ = *inp;
      break;
    }
    inp++;
  }
  *buf = 0;
  return inp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<normalize_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  movb   $0x2f,(%rax)
L19:
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  jmp    L45
L50:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0xc(%rbp)
L45:
  cmpl   $0x1,-0xc(%rbp)
  jle    L8
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L50
L8:
  nop
  leave
  ret
```

assistant: ```c
void normalize_path(char *path) {
  int len = strlen(path);
  char *c;
  for (c = path; *c; c++)
    if ('\\' == *c)
      *c = '/';
  while (len > 1 && path[len - 1] == '/') {
    path[len - 1] = '\0';
    len--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<normalize_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%esi
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L70
  mov    %rbx,%rdx
  jmp    L24
L8:
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L70
L24:
  cmp    $0x5c,%cl
  jne    L8
  movb   $0x2f,(%rdx)
  jmp    L8
L70:
  cmp    $0x1,%esi
  jle    L16
  movslq %esi,%rax
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x2(%rbx,%rax,1),%rax
  lea    -0x2(%rsi),%ecx
  sub    %rcx,%rax
L50:
  cmpb   $0x2f,(%rdx)
  jne    L16
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L50
L16:
  pop    %rbx
  ret
```

assistant: ```c
void normalize_path(char *path) {
  int len = strlen(path);
  char *c;
  for (c = path; *c; c++)
    if ('\\' == *c)
      *c = '/';
  while (len > 1 && path[len - 1] == '/') {
    path[len - 1] = '\0';
    len--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<normalize_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movzbl (%rbx),%ecx
  mov    %eax,%esi
  test   %cl,%cl
  je     L17
  mov    %rbx,%rdx
  nopl   0x0(%rax)
L63:
  cmp    $0x5c,%cl
  jne    L55
  movb   $0x2f,(%rdx)
L55:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L63
L17:
  cmp    $0x1,%esi
  jle    L0
  movslq %esi,%rax
  lea    -0x2(%rsi),%ecx
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x2(%rbx,%rax,1),%rax
  sub    %rcx,%rax
  jmp    L25
  xchg   %ax,%ax
L40:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L0
L25:
  cmpb   $0x2f,(%rdx)
  je     L40
L0:
  pop    %rbx
  ret
```

assistant: ```c
void normalize_path(char *path) {
  int len = strlen(path);
  char *c;
  for (c = path; *c; c++)
    if ('\\' == *c)
      *c = '/';
  while (len > 1 && path[len - 1] == '/') {
    path[len - 1] = '\0';
    len--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<normalize_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movzbl (%rbx),%ecx
  mov    %eax,%esi
  test   %cl,%cl
  je     L82
  mov    %rbx,%rdx
  nopl   0x0(%rax)
L64:
  cmp    $0x5c,%cl
  je     L17
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L64
L82:
  cmp    $0x1,%esi
  jle    L44
  movslq %esi,%rax
  lea    -0x2(%rsi),%ecx
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x2(%rbx,%rax,1),%rax
  sub    %rcx,%rax
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L35:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L44
L21:
  cmpb   $0x2f,(%rdx)
  je     L35
L44:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movb   $0x2f,(%rdx)
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L64
  jmp    L82
```

assistant: ```c
void normalize_path(char *path) {
  int len = strlen(path);
  char *c;
  for (c = path; *c; c++)
    if ('\\' == *c)
      *c = '/';
  while (len > 1 && path[len - 1] == '/') {
    path[len - 1] = '\0';
    len--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L35
L15:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0x0,%eax
  jmp    L23
L7:
  addq   $0x1,-0x10(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L15
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int my_strcmp(const char *p, const char *q) {
  while (*p == *q) {
    if (*p++ == 0) {
      return 0;
    }
    q++;
  }
  return *p - *q;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L8
  mov    $0x1,%eax
L18:
  test   %dl,%dl
  je     L20
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L18
L8:
  movsbl %dl,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int my_strcmp(const char *p, const char *q) {
  while (*p == *q) {
    if (*p++ == 0) {
      return 0;
    }
    q++;
  }
  return *p - *q;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %dl,%cl
  jne    L6
  mov    $0x1,%eax
  jmp    L29
  nopl   (%rax)
L3:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L6
L29:
  test   %dl,%dl
  jne    L3
  xor    %eax,%eax
  ret
L6:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int my_strcmp(const char *p, const char *q) {
  while (*p == *q) {
    if (*p++ == 0) {
      return 0;
    }
    q++;
  }
  return *p - *q;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %dl,%cl
  jne    L21
  mov    $0x1,%eax
  jmp    L23
  nopl   (%rax)
L30:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L21
L23:
  test   %dl,%dl
  jne    L30
  xor    %eax,%eax
  ret
L21:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int my_strcmp(const char *p, const char *q) {
  while (*p == *q) {
    if (*p++ == 0) {
      return 0;
    }
    q++;
  }
  return *p - *q;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<freeColumnList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sqlite3_free@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L11
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sqlite3_free@plt>
  nop
  leave
  ret
```

assistant: ```c
void freeColumnList(char **azCol) {
  int i;
  for (i = 1; azCol[i]; i++) {
    sqlite3_free(azCol[i]);
  }
  sqlite3_free(azCol);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<freeColumnList>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L5
  lea    0x10(%rbp),%rbx
L2:
  mov    $0x0,%eax
  call   <sqlite3_free@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L2
L5:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sqlite3_free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void freeColumnList(char **azCol) {
  int i;
  for (i = 1; azCol[i]; i++) {
    sqlite3_free(azCol[i]);
  }
  sqlite3_free(azCol);
}
```
user: What is the c source code of the assembly code below?

```asm
<freeColumnList>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L2
  lea    0x10(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <sqlite3_free@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L6
L2:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <sqlite3_free@plt>
```

assistant: ```c
void freeColumnList(char **azCol) {
  int i;
  for (i = 1; azCol[i]; i++) {
    sqlite3_free(azCol[i]);
  }
  sqlite3_free(azCol);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<freeColumnList>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L14
  lea    0x10(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <sqlite3_free@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L10
L14:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <sqlite3_free@plt>
```

assistant: ```c
void freeColumnList(char **azCol) {
  int i;
  for (i = 1; azCol[i]; i++) {
    sqlite3_free(azCol[i]);
  }
  sqlite3_free(azCol);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x2,-0x20(%rbp)
  movq   $0x15,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  imul   %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo() {
  unsigned long long a[] = {2, 21};
  return a[0] * a[1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo() {
  unsigned long long a[] = {2, 21};
  return a[0] * a[1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo() {
  unsigned long long a[] = {2, 21};
  return a[0] * a[1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo() {
  unsigned long long a[] = {2, 21};
  return a[0] * a[1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<validate_repo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  cmp    $0xffffffff,%eax
  jne    L29
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L32
L29:
  mov    -0x10(%rbp),%rax
  lea    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  movl   $0x0,-0x14(%rbp)
  jmp    L32
L3:
  movl   $0x1,-0x14(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: %s.hg/%s

assistant: ```c
int validate_repo(const char *repo_root, const char *subdir) {
  char *abs_path;
  struct stat st;
  int ret;
  if (asprintf(&abs_path, "%s.hg/%s", repo_root, subdir) == -1) {
    ret = -1;
    goto bail;
  }
  if (stat(abs_path, &st) == -1) {
    ret = 0;
  } else {
    ret = 1;
  }
bail:
  return ret;
}
```