ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rect_to_polar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rcx,%r12
  test   %rdx,%rdx
  je     L4
  mov    %rdx,%r13
  mov    0x4(%rsi),%esi
  sub    0x4(%rdi),%esi
  mov    0x0(%rbp),%edi
  sub    (%rbx),%edi
  call   <hypot@plt>
  movsd  %xmm0,0x0(%r13)
L4:
  test   %r12,%r12
  je     L18
  mov    0x4(%rbp),%esi
  sub    0x4(%rbx),%esi
  mov    0x0(%rbp),%edi
  sub    (%rbx),%edi
  call   <atan2@plt>
  movsd  %xmm0,(%r12)
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rect_to_polar(const int a[2], const int b[2], double *r, double *th) {
  if (r)
    *r = hypot(b[0] - a[0], b[1] - a[1]);
  if (th)
    *th = atan2(b[0] - a[0], b[1] - a[1]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rect_to_polar>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L12
  mov    0x4(%rsi),%esi
  sub    0x4(%rdi),%esi
  mov    %rdx,%r13
  mov    0x0(%rbp),%edi
  sub    (%rbx),%edi
  call   <hypot@plt>
  movsd  %xmm0,0x0(%r13)
L12:
  test   %r12,%r12
  je     L7
  mov    0x4(%rbp),%esi
  mov    0x0(%rbp),%edi
  sub    0x4(%rbx),%esi
  sub    (%rbx),%edi
  call   <atan2@plt>
  movsd  %xmm0,(%r12)
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rect_to_polar(const int a[2], const int b[2], double *r, double *th) {
  if (r)
    *r = hypot(b[0] - a[0], b[1] - a[1]);
  if (th)
    *th = atan2(b[0] - a[0], b[1] - a[1]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rect_to_polar>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L6
  mov    0x4(%rsi),%esi
  sub    0x4(%rdi),%esi
  mov    %rdx,%r13
  mov    0x0(%rbp),%edi
  sub    (%rbx),%edi
  call   <hypot@plt>
  movsd  %xmm0,0x0(%r13)
L6:
  test   %r12,%r12
  je     L0
  mov    0x4(%rbp),%esi
  mov    0x0(%rbp),%edi
  sub    0x4(%rbx),%esi
  sub    (%rbx),%edi
  call   <atan2@plt>
  movsd  %xmm0,(%r12)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rect_to_polar(const int a[2], const int b[2], double *r, double *th) {
  if (r)
    *r = hypot(b[0] - a[0], b[1] - a[1]);
  if (th)
    *th = atan2(b[0] - a[0], b[1] - a[1]);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strclr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L1
L5:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  while (*s != '\0') {
    *s = '\0';
    s++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strclr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
L2:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L2
L12:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  while (*s != '\0') {
    *s = '\0';
    s++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strclr>:
  endbr64
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L17:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
L18:
  cmpb   $0x0,(%rdi)
  jne    L17
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  while (*s != '\0') {
    *s = '\0';
    s++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strclr>:
  endbr64
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L16:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
L1:
  cmpb   $0x0,(%rdi)
  jne    L16
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  while (*s != '\0') {
    *s = '\0';
    s++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<outs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L16
L2:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <outc@plt>
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void outs(const char *str) {
  while (*str != '\0') {
    outc(*str++);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<outs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L8
L15:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <outc@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L15
L8:
  pop    %rbx
  ret
```

assistant: ```c
void outs(const char *str) {
  while (*str != '\0') {
    outc(*str++);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<outs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L0
L5:
  call   <outc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L5
L0:
  pop    %rbx
  ret
```

assistant: ```c
void outs(const char *str) {
  while (*str != '\0') {
    outc(*str++);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<outs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L18:
  call   <outc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L18
L17:
  pop    %rbx
  ret
```

assistant: ```c
void outs(const char *str) {
  while (*str != '\0') {
    outc(*str++);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Move_Ret_To_Mem_L>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D23
data_type: string

tool: D2: $13,%s

tool: D28: la

tool: D31: $2,%d($13)

tool: D23: sw

assistant: ```c
void Move_Ret_To_Mem_L(char *name, int index) {
  Inst_Printf("la", "$13,%s", name);
  Inst_Printf("sw", "$2,%d($13)", index * 4);
}
```
user: What is the c source code of the assembly code below?

```asm
<Move_Ret_To_Mem_L>:
  endbr64
  push   %rbx
  mov    %rdi,%rdx
  mov    %esi,%ebx
  lea    D20(%rip),%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  lea    0x0(,%rbx,4),%edx
  lea    D21(%rip),%rsi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string

tool: D20: $13,%s

tool: D30: la

tool: D21: $2,%d($13)

tool: D32: sw

assistant: ```c
void Move_Ret_To_Mem_L(char *name, int index) {
  Inst_Printf("la", "$13,%s", name);
  Inst_Printf("sw", "$2,%d($13)", index * 4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Move_Ret_To_Mem_L>:
  endbr64
  push   %rbx
  mov    %rdi,%rdx
  mov    %esi,%ebx
  lea    D33(%rip),%rdi
  lea    D2(%rip),%rsi
  xor    %eax,%eax
  call   <Inst_Printf@plt>
  lea    0x0(,%rbx,4),%edx
  lea    D38(%rip),%rsi
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  pop    %rbx
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D33
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D38
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D33: la

tool: D2: $13,%s

tool: D38: $2,%d($13)

tool: D0: sw

assistant: ```c
void Move_Ret_To_Mem_L(char *name, int index) {
  Inst_Printf("la", "$13,%s", name);
  Inst_Printf("sw", "$2,%d($13)", index * 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Move_Ret_To_Mem_L>:
  endbr64
  push   %rbx
  mov    %rdi,%rdx
  mov    %esi,%ebx
  lea    D23(%rip),%rdi
  lea    D17(%rip),%rsi
  xor    %eax,%eax
  call   <Inst_Printf@plt>
  lea    0x0(,%rbx,4),%edx
  lea    D14(%rip),%rsi
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  pop    %rbx
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D14
type: string
name: parse_data
arguments: data_label: D30
type: string

tool: D23: la

tool: D17: $13,%s

tool: D14: $2,%d($13)

tool: D30: sw

assistant: ```c
void Move_Ret_To_Mem_L(char *name, int index) {
  Inst_Printf("la", "$13,%s", name);
  Inst_Printf("sw", "$2,%d($13)", index * 4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cgi_ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L35
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L35
  jmp    L54
L9:
  addq   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L35
  nop
L46:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
L35:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *cgi_ltrim(char *str) {
  char *r, *s;
  r = s = str;
  if (str && *str) {
    while (isspace(*s))
      s++;
    if (s > r)
      while ((*r++ = *s++))
        ;
  }
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cgi_ltrim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L45
  cmpb   $0x0,(%rdi)
  jne    L28
L45:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  add    $0x1,%rbx
L22:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
  cmp    %rbp,%rbx
  jbe    L45
L54:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L54
  jmp    L45
L28:
  mov    %rdi,%rbx
  jmp    L22
```

assistant: ```c
char *cgi_ltrim(char *str) {
  char *r, *s;
  r = s = str;
  if (str && *str) {
    while (isspace(*s))
      s++;
    if (s > r)
      while ((*r++ = *s++))
        ;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cgi_ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L55
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L55
  mov    %r12,%rbx
  jmp    L42
L8:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L42:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
  cmp    %r12,%rbx
  jbe    L55
  nopw   0x0(%rax,%rax,1)
L47:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L47
L55:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *cgi_ltrim(char *str) {
  char *r, *s;
  r = s = str;
  if (str && *str) {
    while (isspace(*s))
      s++;
    if (s > r)
      while ((*r++ = *s++))
        ;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cgi_ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L59
  cmpb   $0x0,(%rdi)
  je     L59
  mov    %rdi,%rbx
  jmp    L5
  nopl   (%rax)
L13:
  add    $0x1,%rbx
L5:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
  cmp    %r12,%rbx
  jbe    L59
  cs nopw 0x0(%rax,%rax,1)
L23:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L23
L59:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *cgi_ltrim(char *str) {
  char *r, *s;
  r = s = str;
  if (str && *str) {
    while (isspace(*s))
      s++;
    if (s > r)
      while ((*r++ = *s++))
        ;
  }
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<my_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L9:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  jmp    L37
L17:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L37:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_strcat(char *str1, char *str2) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str1[i])
    i++;
  while (str2[j])
    str1[i++] = str2[j++];
  str1[i] = '\0';
  return (str1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<my_strcat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%edx
L31:
  mov    %edx,%r8d
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rax,%rdx,1)
  jne    L31
L35:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L16
  lea    0x1(%r8),%edx
  movslq %edx,%rdx
  movslq %r8d,%r8
  sub    %r8,%rsi
L36:
  mov    %edx,%r8d
  mov    %cl,-0x1(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L36
L16:
  movslq %r8d,%r8
  movb   $0x0,(%rax,%r8,1)
  ret
L1:
  mov    $0x0,%r8d
  jmp    L35
```

assistant: ```c
char *my_strcat(char *str1, char *str2) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str1[i])
    i++;
  while (str2[j])
    str1[i++] = str2[j++];
  str1[i] = '\0';
  return (str1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L21
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L14:
  lea    (%rcx,%rdx,1),%edi
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L14
L15:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L3
  lea    0x1(%rdi),%edx
  movslq %edi,%rdi
  movslq %edx,%rdx
  sub    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %cl,-0x1(%rax,%rdx,1)
  movslq %edx,%r8
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L46
  add    %rax,%r8
L3:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax)
L21:
  mov    %rdi,%r8
  xor    %edi,%edi
  jmp    L15
```

assistant: ```c
char *my_strcat(char *str1, char *str2) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str1[i])
    i++;
  while (str2[j])
    str1[i++] = str2[j++];
  str1[i] = '\0';
  return (str1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L45
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L33:
  lea    (%rcx,%rdx,1),%edi
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L33
L44:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L17
  lea    0x1(%rdi),%edx
  movslq %edi,%rdi
  movslq %edx,%rdx
  sub    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %cl,-0x1(%rax,%rdx,1)
  movslq %edx,%r8
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L42
  add    %rax,%r8
L17:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax)
L45:
  mov    %rdi,%r8
  xor    %edi,%edi
  jmp    L44
```

assistant: ```c
char *my_strcat(char *str1, char *str2) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str1[i])
    i++;
  while (str2[j])
    str1[i++] = str2[j++];
  str1[i] = '\0';
  return (str1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<from_sixbit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %edx,-0x70(%rbp)
  mov    %rcx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4746454443424140,%rax
  movabs $0x4f4e4d4c4b4a4948,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x5756555453525150,%rax
  movabs $0x2d5e5d5c5b5a5958,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x2726252423222120,%rax
  movabs $0x2f2e2d2c2b2a2928,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x3736353433323130,%rax
  movabs $0x3f3e3d3c3b3a3938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L62
L13:
  mov    -0x54(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x6c(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x68(%rbp),%rax
  mov    $0x6,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <ubits@plt>
  movzbl -0x50(%rbp,%rax,1),%eax
  mov    %al,-0x55(%rbp)
  cmpb   $0x40,-0x55(%rbp)
  je     L33
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x55(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x54(%rbp)
L62:
  mov    -0x70(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x54(%rbp)
  jl     L13
  jmp    L82
L33:
  nop
L82:
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x70(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x54(%rbp)
  jmp    L6
L41:
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L15
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jne    L39
L15:
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x54(%rbp)
L6:
  cmpl   $0x0,-0x54(%rbp)
  jns    L41
L39:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L84
  call   <__stack_chk_fail@plt>
L84:
  leave
  ret
```

assistant: ```c
void from_sixbit(unsigned char *bitvec, unsigned int start, int count, char *to) {
  const char sixchr[64] = "@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^- !\"#$%&'()*+,-./0123456789:;<=>?";
  int i;
  char newchar;
  for (i = 0; i < count - 1; i++) {
    newchar = sixchr[ubits(bitvec, start + 6 * i, 6U)];
    if (newchar == '@')
      break;
    else
      to[i] = newchar;
  }
  to[i] = '\0';
  for (i = count - 2; i >= 0; i--)
    if (to[i] == ' ' || to[i] == '@')
      to[i] = '\0';
    else
      break;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<from_sixbit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %edx,%r15d
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movabs $0x4746454443424140,%rax
  movabs $0x4f4e4d4c4b4a4948,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x5756555453525150,%rax
  movabs $0x2d5e5d5c5b5a5958,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x2726252423222120,%rax
  movabs $0x2f2e2d2c2b2a2928,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x3736353433323130,%rax
  movabs $0x3f3e3d3c3b3a3938,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  cmp    $0x1,%r15d
  jle    L1
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %rcx,%r12
  lea    -0x1(%r15),%r14d
  mov    $0x0,%ebx
L55:
  mov    $0x6,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <ubits@plt>
  movzbl 0x10(%rsp,%rax,1),%eax
  cmp    $0x40,%al
  je     L9
  mov    %al,(%r12)
  add    $0x1,%ebx
  add    $0x6,%ebp
  add    $0x1,%r12
  cmp    %r14d,%ebx
  jne    L55
  mov    %r14d,%ebx
L9:
  movslq %ebx,%rbx
  mov    0x8(%rsp),%rdi
  movb   $0x0,(%rdi,%rbx,1)
  mov    %r15d,%eax
  sub    $0x2,%eax
  js     L66
  cltq
  add    %rdi,%rax
  movslq %r15d,%rdx
  lea    -0x3(%rdi,%rdx,1),%rcx
  lea    -0x2(%r15),%edx
  sub    %rdx,%rcx
L53:
  movzbl (%rax),%esi
  lea    -0x20(%rsi),%edx
  test   $0xdf,%dl
  jne    L66
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L53
L66:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  mov    $0x0,%ebx
  jmp    L9
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void from_sixbit(unsigned char *bitvec, unsigned int start, int count, char *to) {
  const char sixchr[64] = "@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^- !\"#$%&'()*+,-./0123456789:;<=>?";
  int i;
  char newchar;
  for (i = 0; i < count - 1; i++) {
    newchar = sixchr[ubits(bitvec, start + 6 * i, 6U)];
    if (newchar == '@')
      break;
    else
      to[i] = newchar;
  }
  to[i] = '\0';
  for (i = count - 2; i >= 0; i--)
    if (to[i] == ' ' || to[i] == '@')
      to[i] = '\0';
    else
      break;
}
```