ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<cstring_cmp_ignore_case_and_whitespace>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %r13d,%r13d
  je     L67
  lea    -0x1(%r13),%eax
  xor    %r13d,%r13d
  lea    0x1(%rbx,%rax,1),%r14
L59:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L48
  movzbl (%rbx),%edx
  mov    %r13d,%eax
  add    $0x1,%r13d
  mov    %dl,(%rsp,%rax,1)
L48:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L59
L67:
  movb   $0x0,(%rsp,%r13,1)
  test   %r12d,%r12d
  je     L45
  lea    -0x1(%r12),%eax
  mov    %rbp,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rbp,%rax,1),%rbp
  nopl   0x0(%rax)
L11:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L33
  movzbl (%rbx),%edx
  mov    %r12d,%eax
  add    $0x1,%r12d
  mov    %dl,0x100(%rsp,%rax,1)
L33:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L11
L45:
  lea    0x100(%rsp),%rsi
  mov    %rsp,%rdi
  movb   $0x0,0x100(%rsp,%r12,1)
  call   <strcasecmp@plt>
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cstring_cmp_ignore_case_and_whitespace(const char *str1, const char *str2) {
  char buffer1[256], buffer2[256];
  unsigned str1_len = strlen(str1), str2_len = strlen(str2);
  unsigned i, j;
  i = j = 0;
  while (i < str1_len) {
    if (!isspace(str1[i])) {
      buffer1[j++] = str1[i];
    }
    i++;
  }
  buffer1[j] = '\0';
  i = j = 0;
  while (i < str2_len) {
    if (!isspace(str2[i])) {
      buffer2[j++] = str2[i];
    }
    i++;
  }
  buffer2[j] = '\0';
  return strcasecmp(buffer1, buffer2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cstring_cmp_ignore_case_and_whitespace>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %r13d,%r13d
  je     L6
  lea    -0x1(%r13),%eax
  xor    %r13d,%r13d
  lea    0x1(%rbx,%rax,1),%r14
L67:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L11
  movzbl (%rbx),%edx
  mov    %r13d,%eax
  add    $0x1,%r13d
  mov    %dl,(%rsp,%rax,1)
L11:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L67
L6:
  movb   $0x0,(%rsp,%r13,1)
  test   %r12d,%r12d
  je     L29
  lea    -0x1(%r12),%eax
  mov    %rbp,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rbp,%rax,1),%rbp
  nopl   0x0(%rax)
L13:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L32
  movzbl (%rbx),%edx
  mov    %r12d,%eax
  add    $0x1,%r12d
  mov    %dl,0x100(%rsp,%rax,1)
L32:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L13
L29:
  lea    0x100(%rsp),%rsi
  mov    %rsp,%rdi
  movb   $0x0,0x100(%rsp,%r12,1)
  call   <strcasecmp@plt>
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cstring_cmp_ignore_case_and_whitespace(const char *str1, const char *str2) {
  char buffer1[256], buffer2[256];
  unsigned str1_len = strlen(str1), str2_len = strlen(str2);
  unsigned i, j;
  i = j = 0;
  while (i < str1_len) {
    if (!isspace(str1[i])) {
      buffer1[j++] = str1[i];
    }
    i++;
  }
  buffer1[j] = '\0';
  i = j = 0;
  while (i < str2_len) {
    if (!isspace(str2[i])) {
      buffer2[j++] = str2[i];
    }
    i++;
  }
  buffer2[j] = '\0';
  return strcasecmp(buffer1, buffer2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<atoik>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L90
  movq   $0x8,-0x18(%rbp)
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L104
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L59
L104:
  movq   $0x10,-0x18(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L59
L90:
  movq   $0xa,-0x18(%rbp)
  jmp    L59
L12:
  cmpq   $0x10,-0x18(%rbp)
  jne    L126
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L118
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  add    %rbx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L183
L118:
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L183
L126:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L0
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
L183:
  addq   $0x1,-0x28(%rbp)
L59:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L12
  jmp    L68
L0:
  nop
  jmp    L68
L176:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  movsbl %al,%eax
  cmp    $0x4b,%eax
  je     L191
  cmp    $0x4d,%eax
  je     L13
  jmp    L96
L191:
  shlq   $0xa,-0x20(%rbp)
  jmp    L166
L13:
  shlq   $0x14,-0x20(%rbp)
  jmp    L166
L96:
  mov    -0x20(%rbp),%rax
  jmp    L25
L166:
  addq   $0x1,-0x28(%rbp)
L68:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L176
  mov    -0x20(%rbp),%rax
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
size_t atoik(char *s) {
  size_t ret = 0;
  size_t base;
  if (*s == '0') {
    base = 8;
    if (*++s == 'x' || *s == 'X') {
      base = 16;
      s++;
    }
  } else
    base = 10;
  for (; isxdigit(*s); s++) {
    if (base == 16)
      if (isalpha(*s))
        ret = base * ret + (toupper(*s) - 'A');
      else
        ret = base * ret + (*s - '0');
    else if (isdigit(*s))
      ret = base * ret + (*s - '0');
    else
      break;
  }
  for (; isalpha(*s); s++) {
    switch (toupper(*s)) {
    case 'K':
      ret *= 1024;
      break;
    case 'M':
      ret *= 1024 * 1024;
      break;
    default:
      return ret;
    }
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atoik>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%r12d
  cmpb   $0x30,(%rdi)
  je     L73
L77:
  mov    $0x0,%ebp
  jmp    L112
L73:
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L20
  add    $0x2,%rbx
  mov    $0x10,%r12d
  jmp    L77
L20:
  add    $0x1,%rbx
  mov    $0x8,%r12d
  jmp    L77
L78:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L60
  shl    $0x4,%rbp
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
  add    %rax,%rbp
L132:
  add    $0x1,%rbx
L112:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L138
  cmp    $0x10,%r12
  je     L78
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L138
  imul   %r12,%rbp
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
  add    %rax,%rbp
  jmp    L132
L60:
  shl    $0x4,%rbp
  movsbl (%rbx),%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  add    %rax,%rbp
  jmp    L132
L104:
  shl    $0xa,%rbp
L115:
  add    $0x1,%rbx
L138:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L129
  movsbl (%rbx),%edi
  call   <toupper@plt>
  cmp    $0x4b,%al
  je     L104
  cmp    $0x4d,%al
  je     L121
L129:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L121:
  shl    $0x14,%rbp
  jmp    L115
```

assistant: ```c
size_t atoik(char *s) {
  size_t ret = 0;
  size_t base;
  if (*s == '0') {
    base = 8;
    if (*++s == 'x' || *s == 'X') {
      base = 16;
      s++;
    }
  } else
    base = 10;
  for (; isxdigit(*s); s++) {
    if (base == 16)
      if (isalpha(*s))
        ret = base * ret + (toupper(*s) - 'A');
      else
        ret = base * ret + (*s - '0');
    else if (isdigit(*s))
      ret = base * ret + (*s - '0');
    else
      break;
  }
  for (; isalpha(*s); s++) {
    switch (toupper(*s)) {
    case 'K':
      ret *= 1024;
      break;
    case 'M':
      ret *= 1024 * 1024;
      break;
    default:
      return ret;
    }
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atoik>:
  endbr64
  push   %r12
  push   %rbp
  mov    $0xa,%ebp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  cmp    $0x30,%dil
  je     L112
L102:
  xor    %r12d,%r12d
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L68:
  call   <isdigit@plt>
  test   %rax,%rax
  je     L72
  imul   %rbp,%r12
L130:
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
  add    %rax,%r12
L114:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L60:
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L72
  movsbl (%rbx),%edi
  cmp    $0x10,%rbp
  jne    L68
  call   <isalpha@plt>
  shl    $0x4,%r12
  test   %rax,%rax
  je     L130
  movsbl (%rbx),%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  add    %rax,%r12
  jmp    L114
  nop
L72:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L41
L29:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  cmp    $0x4b,%al
  je     L61
  cmp    $0x4d,%al
  jne    L41
  shl    $0x14,%r12
L120:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L29
L41:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L61:
  shl    $0xa,%r12
  jmp    L120
  cs nopw 0x0(%rax,%rax,1)
L112:
  movsbl 0x1(%rbx),%edi
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L87
  movsbl 0x2(%rbx),%edi
  mov    $0x10,%ebp
  add    $0x2,%rbx
  jmp    L102
  nop
L87:
  add    $0x1,%rbx
  mov    $0x8,%ebp
  jmp    L102
```

assistant: ```c
size_t atoik(char *s) {
  size_t ret = 0;
  size_t base;
  if (*s == '0') {
    base = 8;
    if (*++s == 'x' || *s == 'X') {
      base = 16;
      s++;
    }
  } else
    base = 10;
  for (; isxdigit(*s); s++) {
    if (base == 16)
      if (isalpha(*s))
        ret = base * ret + (toupper(*s) - 'A');
      else
        ret = base * ret + (*s - '0');
    else if (isdigit(*s))
      ret = base * ret + (*s - '0');
    else
      break;
  }
  for (; isalpha(*s); s++) {
    switch (toupper(*s)) {
    case 'K':
      ret *= 1024;
      break;
    case 'M':
      ret *= 1024 * 1024;
      break;
    default:
      return ret;
    }
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atoik>:
  endbr64
  push   %r12
  push   %rbp
  mov    $0xa,%ebp
  push   %rbx
  cmpb   $0x30,(%rdi)
  mov    %rdi,%rbx
  je     L22
L124:
  xor    %r12d,%r12d
  jmp    L103
  xchg   %ax,%ax
L45:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L115
  movsbl (%rbx),%eax
  imul   %rbp,%r12
  add    $0x1,%rbx
  sub    $0x30,%eax
  cltq
  add    %rax,%r12
L103:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L45
L115:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L141
L123:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  cmp    $0x4b,%al
  je     L49
  cmp    $0x4d,%al
  jne    L141
  shl    $0x14,%r12
L9:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L123
L141:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  shl    $0xa,%r12
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L22:
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L70
  add    $0x2,%rbx
  xor    %r12d,%r12d
  jmp    L64
  nopl   0x0(%rax)
L57:
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
  add    %rax,%r12
L146:
  add    $0x1,%rbx
L64:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L115
  movsbl (%rbx),%edi
  shl    $0x4,%r12
  call   <isalpha@plt>
  test   %rax,%rax
  je     L57
  movsbl (%rbx),%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  add    %rax,%r12
  jmp    L146
  xchg   %ax,%ax
L70:
  add    $0x1,%rbx
  mov    $0x8,%ebp
  jmp    L124
```

assistant: ```c
size_t atoik(char *s) {
  size_t ret = 0;
  size_t base;
  if (*s == '0') {
    base = 8;
    if (*++s == 'x' || *s == 'X') {
      base = 16;
      s++;
    }
  } else
    base = 10;
  for (; isxdigit(*s); s++) {
    if (base == 16)
      if (isalpha(*s))
        ret = base * ret + (toupper(*s) - 'A');
      else
        ret = base * ret + (*s - '0');
    else if (isdigit(*s))
      ret = base * ret + (*s - '0');
    else
      break;
  }
  for (; isalpha(*s); s++) {
    switch (toupper(*s)) {
    case 'K':
      ret *= 1024;
      break;
    case 'M':
      ret *= 1024 * 1024;
      break;
    default:
      return ret;
    }
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<put_long_little>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void put_long_little(unsigned val, char *buf) {
  buf[0] = val & 0xFF;
  buf[1] = (val >> 8) & 0xFF;
  buf[2] = (val >> 16) & 0xFF;
  buf[3] = (val >> 24) & 0xFF;
}
```
user: Translate the below assembly code into C programming language:

```asm
<put_long_little>:
  endbr64
  mov    %edi,%eax
  mov    %dil,(%rsi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rsi)
  mov    %edi,%edx
  shr    $0x10,%edx
  mov    %dl,0x2(%rsi)
  shr    $0x18,%eax
  mov    %al,0x3(%rsi)
  ret
```

assistant: ```c
void put_long_little(unsigned val, char *buf) {
  buf[0] = val & 0xFF;
  buf[1] = (val >> 8) & 0xFF;
  buf[2] = (val >> 16) & 0xFF;
  buf[3] = (val >> 24) & 0xFF;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<put_long_little>:
  endbr64
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void put_long_little(unsigned val, char *buf) {
  buf[0] = val & 0xFF;
  buf[1] = (val >> 8) & 0xFF;
  buf[2] = (val >> 16) & 0xFF;
  buf[3] = (val >> 24) & 0xFF;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<put_long_little>:
  endbr64
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void put_long_little(unsigned val, char *buf) {
  buf[0] = val & 0xFF;
  buf[1] = (val >> 8) & 0xFF;
  buf[2] = (val >> 16) & 0xFF;
  buf[3] = (val >> 24) & 0xFF;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_00>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  setne  %al
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0xffffffff,(%rax)
  cmpl   $0x0,-0x1c(%rbp)
  je     L0
  cmpl   $0x0,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  jmp    L1
L0:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int test_00(int a, int b, int *c, short *d, int x) {
  *d = x != 0;
  *c = -1;
  if (x != 0)
    return a > 0;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_00>:
  endbr64
  mov    %r8d,%eax
  test   %r8d,%r8d
  setne  %sil
  movzbl %sil,%esi
  mov    %si,(%rcx)
  movl   $0xffffffff,(%rdx)
  jne    L10
L12:
  ret
L10:
  test   %edi,%edi
  setg   %al
  movzbl %al,%eax
  jmp    L12
```

assistant: ```c
int test_00(int a, int b, int *c, short *d, int x) {
  *d = x != 0;
  *c = -1;
  if (x != 0)
    return a > 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_00>:
  endbr64
  xor    %esi,%esi
  test   %r8d,%r8d
  mov    %r8d,%eax
  setne  %sil
  mov    %si,(%rcx)
  movl   $0xffffffff,(%rdx)
  jne    L3
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  test   %edi,%edi
  setg   %al
  ret
```

assistant: ```c
int test_00(int a, int b, int *c, short *d, int x) {
  *d = x != 0;
  *c = -1;
  if (x != 0)
    return a > 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_00>:
  endbr64
  xor    %esi,%esi
  test   %r8d,%r8d
  mov    %r8d,%eax
  setne  %sil
  mov    %si,(%rcx)
  movl   $0xffffffff,(%rdx)
  jne    L7
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  test   %edi,%edi
  setg   %al
  ret
```

assistant: ```c
int test_00(int a, int b, int *c, short *d, int x) {
  *d = x != 0;
  *c = -1;
  if (x != 0)
    return a > 0;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<changeValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x14,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x15f,(%rax)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int changeValue() {
  int intArray[10];
  int *intPtr1 = intArray;
  int *intPtr2;
  intPtr2 = intPtr1 + 5;
  *intPtr2 = 351;
  return intArray[5];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<changeValue>:
  endbr64
  mov    $0x15f,%eax
  ret
```

assistant: ```c
int changeValue() {
  int intArray[10];
  int *intPtr1 = intArray;
  int *intPtr2;
  intPtr2 = intPtr1 + 5;
  *intPtr2 = 351;
  return intArray[5];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<changeValue>:
  endbr64
  mov    $0x15f,%eax
  ret
```

assistant: ```c
int changeValue() {
  int intArray[10];
  int *intPtr1 = intArray;
  int *intPtr2;
  intPtr2 = intPtr1 + 5;
  *intPtr2 = 351;
  return intArray[5];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<changeValue>:
  endbr64
  mov    $0x15f,%eax
  ret
```

assistant: ```c
int changeValue() {
  int intArray[10];
  int *intPtr1 = intArray;
  int *intPtr2;
  intPtr2 = intPtr1 + 5;
  *intPtr2 = 351;
  return intArray[5];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<FreeFontInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L19
L17:
  nop
L19:
  leave
  ret
```

assistant: ```c
void FreeFontInfo(struct FontBitmapInfo *font_bitmap_info) {
  if (font_bitmap_info == NULL)
    return;
  free(font_bitmap_info);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<FreeFontInfo>:
  endbr64
  test   %rdi,%rdi
  je     L2
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L2:
  ret
```

assistant: ```c
void FreeFontInfo(struct FontBitmapInfo *font_bitmap_info) {
  if (font_bitmap_info == NULL)
    return;
  free(font_bitmap_info);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<FreeFontInfo>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
void FreeFontInfo(struct FontBitmapInfo *font_bitmap_info) {
  if (font_bitmap_info == NULL)
    return;
  free(font_bitmap_info);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FreeFontInfo>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L5:
  ret
```

assistant: ```c
void FreeFontInfo(struct FontBitmapInfo *font_bitmap_info) {
  if (font_bitmap_info == NULL)
    return;
  free(font_bitmap_info);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  shrq   $0x2,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L2:
  mov    -0x8(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
L19:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L2
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *_memcpy(void *a, const void *b, size_t n) {
  int *wa, *wb;
  n >>= 2;
  for (wa = (int *)a, wb = (int *)b; n-- > 0;)
    *wa++ = *wb++;
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<_memcpy>:
  endbr64
  mov    %rdi,%rax
  shr    $0x2,%rdx
  je     L3
  shl    $0x2,%rdx
  mov    $0x0,%ecx
L2:
  mov    (%rsi,%rcx,1),%r8d
  mov    %r8d,(%rax,%rcx,1)
  add    $0x4,%rcx
  cmp    %rcx,%rdx
  jne    L2
L3:
  ret
```

assistant: ```c
void *_memcpy(void *a, const void *b, size_t n) {
  int *wa, *wb;
  n >>= 2;
  for (wa = (int *)a, wb = (int *)b; n-- > 0;)
    *wa++ = *wb++;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_memcpy>:
  endbr64
  shr    $0x2,%rdx
  mov    %rdi,%rax
  je     L6
  shl    $0x2,%rdx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rsi,%rcx,1),%r8d
  mov    %r8d,(%rax,%rcx,1)
  add    $0x4,%rcx
  cmp    %rcx,%rdx
  jne    L9
L6:
  ret
```

assistant: ```c
void *_memcpy(void *a, const void *b, size_t n) {
  int *wa, *wb;
  n >>= 2;
  for (wa = (int *)a, wb = (int *)b; n-- > 0;)
    *wa++ = *wb++;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rdi
  mov    %rsi,%rcx
  shr    $0x2,%rdi
  lea    -0x1(%rdi),%r9
  je     L37
  lea    0x4(%rsi),%rsi
  mov    %r8,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L13
  cmp    $0x2,%r9
  jbe    L13
  mov    %rdx,%rsi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rdx
  shr    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L1:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L1
  mov    %rsi,%rax
  lea    0x0(,%rsi,4),%r10
  shl    $0x4,%rax
  sub    %r10,%r9
  lea    (%r8,%rax,1),%rdx
  add    %rcx,%rax
  cmp    %r10,%rdi
  je     L37
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  test   %r9,%r9
  je     L37
  mov    0x4(%rax),%ecx
  mov    %ecx,0x4(%rdx)
  cmp    $0x1,%r9
  je     L37
  mov    0x8(%rax),%eax
  mov    %eax,0x8(%rdx)
L37:
  mov    %r8,%rax
  ret
L13:
  shl    $0x2,%rdi
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    (%rcx,%rax,1),%edx
  mov    %edx,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L36
  mov    %r8,%rax
  ret
```

assistant: ```c
void *_memcpy(void *a, const void *b, size_t n) {
  int *wa, *wb;
  n >>= 2;
  for (wa = (int *)a, wb = (int *)b; n-- > 0;)
    *wa++ = *wb++;
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<__bswap_variable_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  xchg   %al,%ah
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_, const)) uint16_t __bswap_variable_16(uint16_t x) {
  __asm__("xchgb %b0,%h0" : "=q"(x) : "0"(x));
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__bswap_variable_16>:
  endbr64
  mov    %rdi,%rax
  xchg   %al,%ah
  ret
```

assistant: ```c
__attribute__((always_, const)) uint16_t __bswap_variable_16(uint16_t x) {
  __asm__("xchgb %b0,%h0" : "=q"(x) : "0"(x));
  return x;
}
```