ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prime_factors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L50
L5:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L3:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x24(%rbp)
L15:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L5
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L15
  cmpl   $0x1,-0x24(%rbp)
  jle    L57
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L57
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
L57:
  nop
  leave
  ret
```

assistant: ```c
void prime_factors(int *dest, int *size, int n) {
  n = abs(n);
  for (int i = 2; i < sqrt(n) + 1; ++i) {
    while (n % i == 0) {
      if (!contains(dest, *size, i))
        dest[(*size)++] = i;
      n /= i;
    }
  }
  if (n > 1) {
    if (!contains(dest, *size, n))
      dest[(*size)++] = n;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prime_factors>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebp
  neg    %ebp
  cmovs  %edx,%ebp
  mov    $0x2,%ebx
  jmp    L65
L75:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %eax,%ebp
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L33
L8:
  mov    %ebx,%edx
  mov    (%r12),%esi
  mov    %r13,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L75
  mov    (%r12),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%r12)
  cltq
  mov    %ebx,0x0(%r13,%rax,4)
  jmp    L75
L33:
  add    $0x1,%ebx
L65:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L25
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L8
  jmp    L33
L25:
  cmp    $0x1,%ebp
  jg     L16
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    %ebp,%edx
  mov    (%r12),%esi
  mov    %r13,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L50
  mov    (%r12),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%r12)
  cltq
  mov    %ebp,0x0(%r13,%rax,4)
  jmp    L50
```

assistant: ```c
void prime_factors(int *dest, int *size, int n) {
  n = abs(n);
  for (int i = 2; i < sqrt(n) + 1; ++i) {
    while (n % i == 0) {
      if (!contains(dest, *size, i))
        dest[(*size)++] = i;
      n /= i;
    }
  }
  if (n > 1) {
    if (!contains(dest, *size, n))
      dest[(*size)++] = n;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<prime_factors>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  neg    %r12d
  cmovs  %edx,%r12d
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L7
  nop
L24:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L42
  nopw   0x0(%rax,%rax,1)
L69:
  mov    0x0(%rbp),%esi
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L54
  movslq 0x0(%rbp),%rax
  lea    0x1(%rax),%edx
  mov    %edx,0x0(%rbp)
  mov    %ebx,0x0(%r13,%rax,4)
L54:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  cltd
  mov    %eax,%r12d
  idiv   %ebx
  test   %edx,%edx
  je     L69
L42:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L24
L7:
  cmp    $0x1,%r12d
  jg     L55
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L55:
  mov    0x0(%rbp),%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L32
  movslq 0x0(%rbp),%rax
  lea    0x1(%rax),%edx
  mov    %edx,0x0(%rbp)
  mov    %r12d,0x0(%r13,%rax,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void prime_factors(int *dest, int *size, int n) {
  n = abs(n);
  for (int i = 2; i < sqrt(n) + 1; ++i) {
    while (n % i == 0) {
      if (!contains(dest, *size, i))
        dest[(*size)++] = i;
      n /= i;
    }
  }
  if (n > 1) {
    if (!contains(dest, *size, n))
      dest[(*size)++] = n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prime_factors>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  neg    %r12d
  cmovs  %edx,%r12d
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L37
  nop
L8:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L66
  nopw   0x0(%rax,%rax,1)
L29:
  mov    0x0(%rbp),%esi
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L17
  movslq 0x0(%rbp),%rax
  lea    0x1(%rax),%edx
  mov    %edx,0x0(%rbp)
  mov    %ebx,0x0(%r13,%rax,4)
L17:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  cltd
  mov    %eax,%r12d
  idiv   %ebx
  test   %edx,%edx
  je     L29
L66:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L8
L37:
  cmp    $0x1,%r12d
  jg     L49
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  mov    0x0(%rbp),%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L43
  movslq 0x0(%rbp),%rax
  lea    0x1(%rax),%edx
  mov    %edx,0x0(%rbp)
  mov    %r12d,0x0(%r13,%rax,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void prime_factors(int *dest, int *size, int n) {
  n = abs(n);
  for (int i = 2; i < sqrt(n) + 1; ++i) {
    while (n % i == 0) {
      if (!contains(dest, *size, i))
        dest[(*size)++] = i;
      n /= i;
    }
  }
  if (n > 1) {
    if (!contains(dest, *size, n))
      dest[(*size)++] = n;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitfmt2int>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  jne    L73
L48:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L73:
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%r14d
  lea    (%r14,%r14,1),%r13d
  lea    0x4(,%r14,8),%edi
  lea    D3(%rip),%rcx
  mov    $0x41f,%edx
  lea    D6(%rip),%rsi
  call   <slurm_xmalloc@plt>
  mov    %rax,%r12
  test   %r14d,%r14d
  jle    L95
  mov    %ebp,%edi
  mov    $0x0,%edx
  mov    $0xffffffff,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%ebp
  mov    $0x0,%r9d
  jmp    L65
L126:
  cmp    $0x2d,%al
  je     L91
  cmp    $0x2c,%al
  je     L92
  test   %al,%al
  jne    L117
L92:
  test   %edx,%edx
  jne    L30
L74:
  cmp    %ebp,%r13d
  setge  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movslq %ebp,%rbp
  movl   $0xffffffff,(%r12,%rbp,4)
  mov    %r12,%rbx
  jmp    L48
L30:
  cmp    $0xffffffff,%r8d
  cmove  %ecx,%r8d
  movslq %ebp,%rax
  mov    %r8d,(%r12,%rax,4)
  add    $0x2,%ebp
  mov    %ecx,0x4(%r12,%rax,4)
  mov    $0xffffffff,%r8d
  mov    %r9d,%ecx
  jmp    L117
L91:
  mov    %ecx,%r8d
  mov    %r9d,%ecx
L117:
  lea    0x1(%rdx),%rax
  cmp    %rdi,%rdx
  je     L74
  mov    %rax,%rdx
L65:
  movzbl (%rbx,%rdx,1),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L126
  lea    (%rcx,%rcx,4),%ecx
  movsbl %al,%eax
  lea    -0x30(%rax,%rcx,2),%ecx
  jmp    L117
L95:
  mov    $0x0,%ebp
  jmp    L74
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string

tool: 

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Q-Leap-Networks/debian-slurm/refs/heads/master/src/common/bitstring.c

assistant: ```c
int32_t *bitfmt2int(char *bit_str_ptr) {
  int32_t *bit_int_ptr, i, bit_inx, size, sum, start_val;
  if (bit_str_ptr == NULL)
    return NULL;
  size = strlen(bit_str_ptr) + 1;
  bit_int_ptr = slurm_xmalloc(sizeof(int32_t) * (size * 2 + 1), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Q-Leap-Networks/debian-slurm/refs/heads/master/src/common/bitstring.c", 1055, "");
  bit_inx = sum = 0;
  start_val = -1;
  for (i = 0; i < size; i++) {
    if (bit_str_ptr[i] >= '0' && bit_str_ptr[i] <= '9') {
      sum = (sum * 10) + (bit_str_ptr[i] - '0');
    } else if (bit_str_ptr[i] == '-') {
      start_val = sum;
      sum = 0;
    } else if (bit_str_ptr[i] == ',' || bit_str_ptr[i] == '\0') {
      if (i == 0)
        break;
      if (start_val == -1)
        start_val = sum;
      bit_int_ptr[bit_inx++] = start_val;
      bit_int_ptr[bit_inx++] = sum;
      start_val = -1;
      sum = 0;
    }
  }
  assert(bit_inx < (size * 2 + 1));
  bit_int_ptr[bit_inx] = -1;
  return bit_int_ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitfmt2int>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  jne    L4
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <strlen@plt>
  lea    D9(%rip),%rcx
  mov    $0x41f,%edx
  lea    D16(%rip),%rsi
  lea    0x1(%rax),%r14d
  mov    %eax,%ebp
  lea    0x4(,%r14,8),%edi
  lea    (%r14,%r14,1),%ebx
  call   <slurm_xmalloc@plt>
  mov    %rax,%r13
  test   %r14d,%r14d
  jle    L33
  xor    %edx,%edx
  mov    %ebp,%eax
  mov    $0xffffffff,%r9d
  xor    %edi,%edi
  movzbl (%r12,%rdx,1),%esi
  xor    %r8d,%r8d
  lea    -0x30(%rsi),%ecx
  cmp    $0x9,%cl
  ja     L116
L111:
  lea    (%rdi,%rdi,4),%esi
  movsbl %cl,%ecx
  lea    (%rcx,%rsi,2),%edi
L55:
  lea    0x1(%rdx),%rcx
  cmp    %rdx,%rax
  je     L75
  mov    %rcx,%rdx
  movzbl (%r12,%rdx,1),%esi
  lea    -0x30(%rsi),%ecx
  cmp    $0x9,%cl
  jbe    L111
L116:
  cmp    $0x2d,%sil
  je     L59
  cmp    $0x2c,%sil
  je     L81
  test   %sil,%sil
  jne    L55
L81:
  test   %rdx,%rdx
  jne    L89
L75:
  movslq %r8d,%rax
  lea    0x0(%r13,%rax,4),%rbp
L88:
  xor    %edi,%edi
  cmp    %r8d,%ebx
  mov    %r13,%r12
  setge  %dil
  call   <assert@plt>
  movl   $0xffffffff,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %edi,%r9d
  xor    %edi,%edi
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %rax,%rbp
  xor    %r8d,%r8d
  jmp    L88
L89:
  cmp    $0xffffffff,%r9d
  movslq %r8d,%rcx
  cmove  %edi,%r9d
  mov    %edi,0x4(%r13,%rcx,4)
  add    $0x2,%r8d
  xor    %edi,%edi
  mov    %r9d,0x0(%r13,%rcx,4)
  or     $0xffffffff,%r9d
  jmp    L55
```

tool_calls: name: unpack_data
arguments: label: D9
type: string
name: unpack_data
arguments: label: D16
type: string

tool: 

tool: D16: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Q-Leap-Networks/debian-slurm/refs/heads/master/src/common/bitstring.c

assistant: ```c
int32_t *bitfmt2int(char *bit_str_ptr) {
  int32_t *bit_int_ptr, i, bit_inx, size, sum, start_val;
  if (bit_str_ptr == NULL)
    return NULL;
  size = strlen(bit_str_ptr) + 1;
  bit_int_ptr = slurm_xmalloc(sizeof(int32_t) * (size * 2 + 1), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Q-Leap-Networks/debian-slurm/refs/heads/master/src/common/bitstring.c", 1055, "");
  bit_inx = sum = 0;
  start_val = -1;
  for (i = 0; i < size; i++) {
    if (bit_str_ptr[i] >= '0' && bit_str_ptr[i] <= '9') {
      sum = (sum * 10) + (bit_str_ptr[i] - '0');
    } else if (bit_str_ptr[i] == '-') {
      start_val = sum;
      sum = 0;
    } else if (bit_str_ptr[i] == ',' || bit_str_ptr[i] == '\0') {
      if (i == 0)
        break;
      if (start_val == -1)
        start_val = sum;
      bit_int_ptr[bit_inx++] = start_val;
      bit_int_ptr[bit_inx++] = sum;
      start_val = -1;
      sum = 0;
    }
  }
  assert(bit_inx < (size * 2 + 1));
  bit_int_ptr[bit_inx] = -1;
  return bit_int_ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<EncodeSQLString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L65
L78:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  je     L64
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L64
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L59
L64:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    %rax,%rdi
  call   <BufferDiff@plt>
  test   %rax,%rax
  jns    L58
  mov    $0xffffffff,%eax
  jmp    L62
L58:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  lea    -0xc(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xc(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xb(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xa(%rbp),%eax
  mov    %al,(%rdx)
L59:
  addl   $0x1,-0x10(%rbp)
L65:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L62:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: %%%2x

assistant: ```c
int EncodeSQLString(char *sString, int dMaxSize) {
  int i;
  char sAccum[4];
  i = 0;
  while (sString[i] != 0) {
    if ((sString[i] == '%') || (sString[i] == 34) || (sString[i] == 39)) {
      if (BufferDiff(sString, i, 2, dMaxSize) < 0) {
        return -1;
      }
      sprintf(sAccum, "%%%2x", sString[i]);
      sString[i++] = sAccum[0];
      sString[i++] = sAccum[1];
      sString[i] = sAccum[2];
    }
    i++;
  }
  return strlen(sString);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EncodeSQLString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  movabs $0xa400000000,%r13
  lea    0x14(%rsp),%r15
  lea    D8(%rip),%r14
  jmp    L22
L84:
  add    $0x1,%ebp
  movslq %ebp,%rbx
  add    %r12,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L3
L22:
  cmp    $0x27,%al
  ja     L84
  bt     %rax,%r13
  jae    L84
  mov    0xc(%rsp),%ecx
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <BufferDiff@plt>
  test   %rax,%rax
  js     L57
  movsbl (%rbx),%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  lea    0x1(%rbp),%eax
  movzbl 0x14(%rsp),%edx
  mov    %dl,(%rbx)
  add    $0x2,%ebp
  cltq
  movzbl 0x15(%rsp),%edx
  mov    %dl,(%r12,%rax,1)
  movslq %ebp,%rax
  movzbl 0x16(%rsp),%edx
  mov    %dl,(%r12,%rax,1)
  jmp    L84
L3:
  mov    %r12,%rdi
  call   <strlen@plt>
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L78
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  mov    $0xffffffff,%eax
  jmp    L14
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: %%%2x

assistant: ```c
int EncodeSQLString(char *sString, int dMaxSize) {
  int i;
  char sAccum[4];
  i = 0;
  while (sString[i] != 0) {
    if ((sString[i] == '%') || (sString[i] == 34) || (sString[i] == 39)) {
      if (BufferDiff(sString, i, 2, dMaxSize) < 0) {
        return -1;
      }
      sprintf(sAccum, "%%%2x", sString[i]);
      sString[i++] = sAccum[0];
      sString[i++] = sAccum[1];
      sString[i] = sAccum[2];
    }
    i++;
  }
  return strlen(sString);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EncodeSQLString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L63
  mov    %esi,%r12d
  mov    %rdi,%rbx
  lea    0x4(%rsp),%r14
  xor    %r15d,%r15d
  movabs $0xa400000000,%rbp
  nopl   0x0(%rax,%rax,1)
L45:
  cmp    $0x27,%al
  ja     L19
  bt     %rax,%rbp
  jae    L19
  mov    %r12d,%ecx
  mov    $0x2,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <BufferDiff@plt>
  test   %rax,%rax
  js     L29
  movsbl (%rbx),%edx
  lea    D6(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  movzbl 0x4(%rsp),%edx
  lea    0x1(%r15),%eax
  add    $0x2,%r15d
  cltq
  mov    %dl,(%rbx)
  movzbl 0x5(%rsp),%edx
  mov    %dl,0x0(%r13,%rax,1)
  movzbl 0x6(%rsp),%edx
  movslq %r15d,%rax
  mov    %dl,0x0(%r13,%rax,1)
L19:
  add    $0x1,%r15d
  movslq %r15d,%rbx
  add    %r13,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L45
L63:
  mov    %r13,%rdi
  call   <strlen@plt>
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L67
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  mov    $0xffffffff,%eax
  jmp    L25
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string

tool: D6: %%%2x

assistant: ```c
int EncodeSQLString(char *sString, int dMaxSize) {
  int i;
  char sAccum[4];
  i = 0;
  while (sString[i] != 0) {
    if ((sString[i] == '%') || (sString[i] == 34) || (sString[i] == 39)) {
      if (BufferDiff(sString, i, 2, dMaxSize) < 0) {
        return -1;
      }
      sprintf(sAccum, "%%%2x", sString[i]);
      sString[i++] = sAccum[0];
      sString[i++] = sAccum[1];
      sString[i] = sAccum[2];
    }
    i++;
  }
  return strlen(sString);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<EncodeSQLString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  mov    %esi,%r12d
  mov    %rdi,%rbx
  lea    0x4(%rsp),%r14
  xor    %r15d,%r15d
  movabs $0xa400000000,%rbp
  nopl   0x0(%rax,%rax,1)
L29:
  cmp    $0x27,%al
  ja     L39
  bt     %rax,%rbp
  jae    L39
  mov    %r12d,%ecx
  mov    $0x2,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <BufferDiff@plt>
  test   %rax,%rax
  js     L12
  movsbl (%rbx),%edx
  lea    D3(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  movzbl 0x4(%rsp),%edx
  lea    0x1(%r15),%eax
  add    $0x2,%r15d
  cltq
  mov    %dl,(%rbx)
  movzbl 0x5(%rsp),%edx
  mov    %dl,0x0(%r13,%rax,1)
  movzbl 0x6(%rsp),%edx
  movslq %r15d,%rax
  mov    %dl,0x0(%r13,%rax,1)
L39:
  add    $0x1,%r15d
  movslq %r15d,%rbx
  add    %r13,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L29
L2:
  mov    %r13,%rdi
  call   <strlen@plt>
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L12:
  mov    $0xffffffff,%eax
  jmp    L22
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: %%%2x

assistant: ```c
int EncodeSQLString(char *sString, int dMaxSize) {
  int i;
  char sAccum[4];
  i = 0;
  while (sString[i] != 0) {
    if ((sString[i] == '%') || (sString[i] == 34) || (sString[i] == 39)) {
      if (BufferDiff(sString, i, 2, dMaxSize) < 0) {
        return -1;
      }
      sprintf(sAccum, "%%%2x", sString[i]);
      sString[i++] = sAccum[0];
      sString[i++] = sAccum[1];
      sString[i] = sAccum[2];
    }
    i++;
  }
  return strlen(sString);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<my_str_tw_put>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0xffffffff,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L26
L20:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <my_str_tw_is_separator@plt>
  test   %rax,%rax
  je     L47
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L30
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rsi
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <my_str_tw_put_to@plt>
  addl   $0x1,-0x1c(%rbp)
L30:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L26
L47:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L26:
  addl   $0x1,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L20
  mov    -0x20(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void my_str_tw_put(char *str, char **dest, int total) {
  int i;
  int tab_i;
  int car_pos;
  int sep_pos;
  i = -1;
  tab_i = 0;
  car_pos = -1;
  sep_pos = -1;
  while ((i = i + 1) == 0 || str[i - 1]) {
    if (my_str_tw_is_separator(str[i])) {
      if (car_pos > sep_pos) {
        dest[tab_i] = malloc(sizeof(char) * (car_pos - sep_pos));
        my_str_tw_put_to(str, dest[tab_i], sep_pos + 1, car_pos);
        tab_i = tab_i + 1;
      }
      sep_pos = i;
    } else
      car_pos = i;
  }
}
```