ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<nvram_set_boot>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <nvram_get_option@plt>
  test   %eax,%eax
  js     L49
  test   $0x2,%al
  je     L28
  mov    %rbx,%rdi
  call   <nvram_get@plt>
  test   %rax,%rax
  je     L28
  cmpb   $0x0,(%rax)
  jne    L16
L28:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <_nvram_set@plt>
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L49:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jmp    L5
L16:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  jmp    L5
```

assistant: ```c
int nvram_set_boot(const char *name, const char *value) {
  unsigned int opt = nvram_get_option(name);
  int ret = 0;
  if (opt & 0x80000000) {
    return EINVAL;
  }
  if (opt & 0x02) {
    char *exist = nvram_get(name);
    if (exist && *exist) {
      return EACCES;
    }
  }
  ret = _nvram_set(name, value);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nvram_set_boot>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <nvram_get_option@plt>
  test   %eax,%eax
  js     L6
  test   $0x2,%al
  je     L37
  mov    %rbp,%rdi
  call   <nvram_get@plt>
  test   %rax,%rax
  je     L37
  cmpb   $0x0,(%rax)
  jne    L4
L37:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <_nvram_set@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
L20:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  jmp    L20
```

assistant: ```c
int nvram_set_boot(const char *name, const char *value) {
  unsigned int opt = nvram_get_option(name);
  int ret = 0;
  if (opt & 0x80000000) {
    return EINVAL;
  }
  if (opt & 0x02) {
    char *exist = nvram_get(name);
    if (exist && *exist) {
      return EACCES;
    }
  }
  ret = _nvram_set(name, value);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nvram_set_boot>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <nvram_get_option@plt>
  test   %eax,%eax
  js     L36
  test   $0x2,%al
  je     L10
  mov    %rbp,%rdi
  call   <nvram_get@plt>
  test   %rax,%rax
  je     L10
  cmpb   $0x0,(%rax)
  jne    L22
L10:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <_nvram_set@plt>
  nopw   0x0(%rax,%rax,1)
L36:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
L3:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L22:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L3
```

assistant: ```c
int nvram_set_boot(const char *name, const char *value) {
  unsigned int opt = nvram_get_option(name);
  int ret = 0;
  if (opt & 0x80000000) {
    return EINVAL;
  }
  if (opt & 0x02) {
    char *exist = nvram_get(name);
    if (exist && *exist) {
      return EACCES;
    }
  }
  ret = _nvram_set(name, value);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<asm_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L20
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L20:
  cmpq   $0x0,-0xc8(%rbp)
  je     L26
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc8(%rbp),%rax
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc8(%rbp),%rax
  add    $0xfff,%rax
  movb   $0x0,(%rax)
  jmp    L4
L26:
  nop
L4:
  leave
  ret
```

assistant: ```c
void asm_printf(char *asm_instr, const char *format, ...) {
  va_list ap;
  if (!asm_instr) {
    return;
  }
  va_start(ap, format);
  vsnprintf(asm_instr, 4096, format, ap);
  va_end(ap);
  asm_instr[4096 - 1] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<asm_printf>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  movb   $0x0,0xfff(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  ret
```

assistant: ```c
void asm_printf(char *asm_instr, const char *format, ...) {
  va_list ap;
  if (!asm_instr) {
    return;
  }
  va_start(ap, format);
  vsnprintf(asm_instr, 4096, format, ap);
  va_end(ap);
  asm_instr[4096 - 1] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<asm_printf>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    $0x1000,%esi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  movb   $0x0,0xfff(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void asm_printf(char *asm_instr, const char *format, ...) {
  va_list ap;
  if (!asm_instr) {
    return;
  }
  va_start(ap, format);
  vsnprintf(asm_instr, 4096, format, ap);
  va_end(ap);
  asm_instr[4096 - 1] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<asm_printf>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    $0x1000,%esi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  movb   $0x0,0xfff(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void asm_printf(char *asm_instr, const char *format, ...) {
  va_list ap;
  if (!asm_instr) {
    return;
  }
  va_start(ap, format);
  vsnprintf(asm_instr, 4096, format, ap);
  va_end(ap);
  asm_instr[4096 - 1] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<concatenate_paths>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L35
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
L4:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x2f,(%rax)
  jmp    L12
L14:
  addq   $0x1,-0x30(%rbp)
L12:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L14
  mov    -0x30(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  lea    D5(%rip),%rdx
  mov    %rax,%rdi
  call   <strlcatf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: %s

assistant: ```c
void concatenate_paths(char *buffer, int maxbufsize, char *p1, char *p2) {
  int i;
  memset(buffer, 0, maxbufsize);
  for (i = 0; (p1[i]) && (p1[i] != '/' || p1[i + 1]); i++)
    *(buffer++) = p1[i];
  *(buffer++) = '/';
  while (*p2 == '/')
    p2++;
  strlcatf(buffer, maxbufsize, "%s", p2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<concatenate_paths>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    %rcx,%r13
  mov    %esi,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L22
  lea    0x1(%rbx),%rdx
  jmp    L37
L34:
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L22
L37:
  cmp    $0x2f,%al
  jne    L34
  cmpb   $0x0,(%rdx)
  jne    L34
L22:
  lea    0x1(%rbp),%rdi
  movb   $0x2f,0x0(%rbp)
  cmpb   $0x2f,0x0(%r13)
  jne    L40
L42:
  add    $0x1,%r13
  cmpb   $0x2f,0x0(%r13)
  je     L42
L40:
  mov    %r13,%rcx
  lea    D6(%rip),%rdx
  mov    %r12d,%esi
  call   <strlcatf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: %s

assistant: ```c
void concatenate_paths(char *buffer, int maxbufsize, char *p1, char *p2) {
  int i;
  memset(buffer, 0, maxbufsize);
  for (i = 0; (p1[i]) && (p1[i] != '/' || p1[i + 1]); i++)
    *(buffer++) = p1[i];
  *(buffer++) = '/';
  while (*p2 == '/')
    p2++;
  strlcatf(buffer, maxbufsize, "%s", p2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<concatenate_paths>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <memset@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L33
  lea    0x1(%rbx),%rdx
  jmp    L25
L16:
  add    $0x1,%rdx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L33
L25:
  cmp    $0x2f,%al
  jne    L16
  cmpb   $0x0,(%rdx)
  jne    L16
L33:
  movb   $0x2f,0x0(%rbp)
  cmpb   $0x2f,(%r12)
  lea    0x1(%rbp),%rdi
  jne    L43
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%r12
  cmpb   $0x2f,(%r12)
  je     L23
L43:
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %r13d,%esi
  pop    %rbx
  lea    D5(%rip),%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <strlcatf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %s

assistant: ```c
void concatenate_paths(char *buffer, int maxbufsize, char *p1, char *p2) {
  int i;
  memset(buffer, 0, maxbufsize);
  for (i = 0; (p1[i]) && (p1[i] != '/' || p1[i + 1]); i++)
    *(buffer++) = p1[i];
  *(buffer++) = '/';
  while (*p2 == '/')
    p2++;
  strlcatf(buffer, maxbufsize, "%s", p2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<concatenate_paths>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <memset@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L32
  lea    0x1(%rbx),%rdx
  jmp    L50
L24:
  add    $0x1,%rdx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L32
L50:
  cmp    $0x2f,%al
  jne    L24
  cmpb   $0x0,(%rdx)
  jne    L24
L32:
  movb   $0x2f,0x0(%rbp)
  cmpb   $0x2f,(%r12)
  lea    0x1(%rbp),%rdi
  jne    L47
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%r12
  cmpb   $0x2f,(%r12)
  je     L28
L47:
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %r13d,%esi
  pop    %rbx
  lea    D1(%rip),%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <strlcatf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %s

assistant: ```c
void concatenate_paths(char *buffer, int maxbufsize, char *p1, char *p2) {
  int i;
  memset(buffer, 0, maxbufsize);
  for (i = 0; (p1[i]) && (p1[i] != '/' || p1[i + 1]); i++)
    *(buffer++) = p1[i];
  *(buffer++) = '/';
  while (*p2 == '/')
    p2++;
  strlcatf(buffer, maxbufsize, "%s", p2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sendShiftEvKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <pressEvKey@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sendEvKey@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <releaseEvKey@plt>
  nop
  leave
  ret
```

assistant: ```c
void sendShiftEvKey(int evKey) {
  pressEvKey(KEY_LEFTSHIFT);
  sendEvKey(evKey);
  releaseEvKey(KEY_LEFTSHIFT);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sendShiftEvKey>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    D7(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <pressEvKey@plt>
  mov    %ebx,%edi
  call   <sendEvKey@plt>
  mov    0x0(%rbp),%edi
  call   <releaseEvKey@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sendShiftEvKey(int evKey) {
  pressEvKey(KEY_LEFTSHIFT);
  sendEvKey(evKey);
  releaseEvKey(KEY_LEFTSHIFT);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sendShiftEvKey>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rbx
  mov    (%rbx),%edi
  call   <pressEvKey@plt>
  mov    %ebp,%edi
  call   <sendEvKey@plt>
  mov    (%rbx),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1090 <releaseEvKey@plt>
```

assistant: ```c
void sendShiftEvKey(int evKey) {
  pressEvKey(KEY_LEFTSHIFT);
  sendEvKey(evKey);
  releaseEvKey(KEY_LEFTSHIFT);
}
```
user: What is the c source code of the assembly code below:

```asm
<sendShiftEvKey>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rbx
  mov    (%rbx),%edi
  call   <pressEvKey@plt>
  mov    %ebp,%edi
  call   <sendEvKey@plt>
  mov    (%rbx),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1090 <releaseEvKey@plt>
```

assistant: ```c
void sendShiftEvKey(int evKey) {
  pressEvKey(KEY_LEFTSHIFT);
  sendEvKey(evKey);
  releaseEvKey(KEY_LEFTSHIFT);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L7
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L7:
  nop
  leave
  ret
```

assistant: ```c
void Free(void **ptr) {
  if (*ptr) {
    free(*ptr);
    *ptr = NULL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L7
  call   <free@plt>
  movq   $0x0,(%rbx)
L7:
  pop    %rbx
  ret
```

assistant: ```c
void Free(void **ptr) {
  if (*ptr) {
    free(*ptr);
    *ptr = NULL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  call   <free@plt>
  movq   $0x0,(%rbx)
L9:
  pop    %rbx
  ret
```

assistant: ```c
void Free(void **ptr) {
  if (*ptr) {
    free(*ptr);
    *ptr = NULL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L0
  call   <free@plt>
  movq   $0x0,(%rbx)
L0:
  pop    %rbx
  ret
```

assistant: ```c
void Free(void **ptr) {
  if (*ptr) {
    free(*ptr);
    *ptr = NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<files_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L26:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  mov    %cl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L18
  mov    $0x0,%eax
  jmp    L35
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L26
L42:
  mov    $0x1,%eax
L35:
  leave
  ret
```

assistant: ```c
int files_equal(char *file1, char *file2) {
  char *endfile1 = &file1[strlen(file1) - 1];
  char *endfile2 = &file2[strlen(file2) - 1];
  for (; *endfile1 != '/' && *endfile2 != '/';) {
    if (--*endfile1 != --*endfile2)
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<files_equal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
L21:
  movzbl (%rbx),%eax
  cmp    $0x2f,%al
  je     L40
  cmpb   $0x2f,(%rcx)
  je     L14
  sub    $0x1,%eax
  mov    %al,(%rbx)
  movzbl (%rcx),%esi
  lea    -0x1(%rsi),%edx
  mov    %dl,(%rcx)
  cmp    %dl,%al
  je     L21
  mov    $0x0,%eax
  jmp    L37
L14:
  mov    $0x1,%eax
  jmp    L37
L40:
  mov    $0x1,%eax
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int files_equal(char *file1, char *file2) {
  char *endfile1 = &file1[strlen(file1) - 1];
  char *endfile2 = &file2[strlen(file2) - 1];
  for (; *endfile1 != '/' && *endfile2 != '/';) {
    if (--*endfile1 != --*endfile2)
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<files_equal>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  cltq
  lea    -0x1(%rbx,%rax,1),%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
  jmp    L33
  nopl   (%rax)
L38:
  cmpb   $0x2f,(%rcx)
  je     L13
  sub    $0x1,%eax
  mov    %al,(%rbx)
  movzbl (%rcx),%esi
  lea    -0x1(%rsi),%edx
  mov    %dl,(%rcx)
  cmp    %dl,%al
  jne    L16
L33:
  movzbl (%rbx),%eax
  cmp    $0x2f,%al
  jne    L38
L13:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int files_equal(char *file1, char *file2) {
  char *endfile1 = &file1[strlen(file1) - 1];
  char *endfile2 = &file2[strlen(file2) - 1];
  for (; *endfile1 != '/' && *endfile2 != '/';) {
    if (--*endfile1 != --*endfile2)
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<files_equal>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  cltq
  lea    -0x1(%rbx,%rax,1),%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
  jmp    L26
  nopl   (%rax)
L29:
  cmpb   $0x2f,(%rcx)
  je     L7
  sub    $0x1,%eax
  mov    %al,(%rbx)
  movzbl (%rcx),%esi
  lea    -0x1(%rsi),%edx
  mov    %dl,(%rcx)
  cmp    %dl,%al
  jne    L18
L26:
  movzbl (%rbx),%eax
  cmp    $0x2f,%al
  jne    L29
L7:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int files_equal(char *file1, char *file2) {
  char *endfile1 = &file1[strlen(file1) - 1];
  char *endfile2 = &file2[strlen(file2) - 1];
  for (; *endfile1 != '/' && *endfile2 != '/';) {
    if (--*endfile1 != --*endfile2)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<processEntry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x80,-0x14(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <isVisible@plt>
  test   %eax,%eax
  je     L24
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <isVideoFile@plt>
  test   %eax,%eax
  je     L24
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <processFile@plt>
  jmp    L24
L18:
  nop
  jmp    L39
L24:
  nop
L39:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int processEntry(const char *path, const struct stat *fileStat, const int typeflag) {
  switch (typeflag) {
  case FTW_F:
    if (isVisible(path) && isVideoFile(path)) {
      processFile(&path[1], fileStat);
    }
    break;
  default:
    break;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<processEntry>:
  endbr64
  cmp    $0x80,%edx
  je     L19
  mov    $0x0,%eax
  ret
L19:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <isVisible@plt>
  test   %eax,%eax
  jne    L11
L16:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rbx,%rdi
  call   <isVideoFile@plt>
  test   %eax,%eax
  je     L16
  lea    0x1(%rbx),%rdi
  mov    %rbp,%rsi
  call   <processFile@plt>
  jmp    L16
```

assistant: ```c
int processEntry(const char *path, const struct stat *fileStat, const int typeflag) {
  switch (typeflag) {
  case FTW_F:
    if (isVisible(path) && isVideoFile(path)) {
      processFile(&path[1], fileStat);
    }
    break;
  default:
    break;
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<processEntry>:
  endbr64
  cmp    $0x80,%edx
  je     L28
  xor    %eax,%eax
  ret
  nop
L28:
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <isVisible@plt>
  test   %eax,%eax
  jne    L4
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L4:
  mov    %rbx,%rdi
  call   <isVideoFile@plt>
  test   %eax,%eax
  je     L10
  lea    0x1(%rbx),%rdi
  mov    %rbp,%rsi
  call   <processFile@plt>
  jmp    L10
```

assistant: ```c
int processEntry(const char *path, const struct stat *fileStat, const int typeflag) {
  switch (typeflag) {
  case FTW_F:
    if (isVisible(path) && isVideoFile(path)) {
      processFile(&path[1], fileStat);
    }
    break;
  default:
    break;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<processEntry>:
  endbr64
  cmp    $0x80,%edx
  je     L34
  xor    %eax,%eax
  ret
  nop
L34:
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <isVisible@plt>
  test   %eax,%eax
  jne    L19
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L19:
  mov    %rbx,%rdi
  call   <isVideoFile@plt>
  test   %eax,%eax
  je     L18
  lea    0x1(%rbx),%rdi
  mov    %rbp,%rsi
  call   <processFile@plt>
  jmp    L18
```

assistant: ```c
int processEntry(const char *path, const struct stat *fileStat, const int typeflag) {
  switch (typeflag) {
  case FTW_F:
    if (isVisible(path) && isVideoFile(path)) {
      processFile(&path[1], fileStat);
    }
    break;
  default:
    break;
  }
  return (0);
}
```