ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<key_esc>:
  endbr64
  cmp    $0x1b,%dil
  je     L0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %edi,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void key_esc(unsigned char key, int x, int y) {
  if (key == 27)
    exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6569642f706d742f,%rax
  movabs $0x61662d6362696c74,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x65742d6573697664,%rax
  movabs $0x58585858582e7473,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x58,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <mkstemp@plt>
  mov    %eax,-0x34(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x34(%rbp),%eax
  mov    %edx,%ecx
  mov    $0x2a,%edx
  mov    $0x17,%esi
  mov    %eax,%edi
  call   <posix_fadvise@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(void) {
  char file[] = "/tmp/dietlibc-fadvise-test.XXXXXX";
  int fd;
  fd = mkstemp(file);
  unlink(file);
  assert(posix_fadvise(fd, 23, 42, POSIX_FADV_RANDOM) == 0);
  close(fd);
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6569642f706d742f,%rax
  movabs $0x61662d6362696c74,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x65742d6573697664,%rax
  movabs $0x58585858582e7473,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movw   $0x58,0x20(%rsp)
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <mkstemp@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x2a,%edx
  mov    $0x17,%esi
  mov    %ebx,%edi
  call   <posix_fadvise@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char file[] = "/tmp/dietlibc-fadvise-test.XXXXXX";
  int fd;
  fd = mkstemp(file);
  unlink(file);
  assert(posix_fadvise(fd, 23, 42, POSIX_FADV_RANDOM) == 0);
  close(fd);
  return EXIT_SUCCESS;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<array_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L5:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int array_length(Atom *a) {
  int n = 0;
  while (a[n])
    n++;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<array_length>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L25
  mov    $0x1,%eax
L4:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L4
L0:
  mov    %edx,%eax
  ret
L25:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
int array_length(Atom *a) {
  int n = 0;
  while (a[n])
    n++;
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_length>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L11
  mov    $0x1,%eax
  nop
L6:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L6
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int array_length(Atom *a) {
  int n = 0;
  while (a[n])
    n++;
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_length>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L7
  mov    $0x1,%eax
  nop
L19:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L19
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int array_length(Atom *a) {
  int n = 0;
  while (a[n])
    n++;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vsub(const float *src1, const float *src2, float *dst) {
  dst[0] = src1[0] - src2[0];
  dst[1] = src1[1] - src2[1];
  dst[2] = src1[2] - src2[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vsub>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void vsub(const float *src1, const float *src2, float *dst) {
  dst[0] = src1[0] - src2[0];
  dst[1] = src1[1] - src2[1];
  dst[2] = src1[2] - src2[2];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vsub>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void vsub(const float *src1, const float *src2, float *dst) {
  dst[0] = src1[0] - src2[0];
  dst[1] = src1[1] - src2[1];
  dst[2] = src1[2] - src2[2];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vsub>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdx)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void vsub(const float *src1, const float *src2, float *dst) {
  dst[0] = src1[0] - src2[0];
  dst[1] = src1[1] - src2[1];
  dst[2] = src1[2] - src2[2];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<buildMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L2
L15:
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L18
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  imul   -0x30(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L19
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L15
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **buildMat(const int *elems, int r, int c) {
  int **xs = (int **)malloc(sizeof(int *) * r);
  for (int i = 0; i < r; i++) {
    int *cs = (int *)malloc(sizeof(int) * c);
    for (int j = i * c; j < (i + 1) * c; j++)
      cs[j % c] = elems[j];
    xs[i] = cs;
  }
  return xs;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<buildMat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %r12d,%r12d
  jle    L31
  movslq %ebx,%rdi
  mov    %rdi,0x8(%rsp)
  lea    0x0(,%rbx,4),%edi
  mov    %edi,0x10(%rsp)
  mov    %rax,%r13
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r15
  mov    %ebx,%r12d
  mov    $0x0,%r14d
  lea    (%rbx,%rbx,1),%eax
  mov    %eax,0x14(%rsp)
L17:
  mov    0x10(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %r12d,%r9d
  sub    %ebx,%r9d
  mov    %r12d,%r8d
  cmp    %r12d,%r9d
  jge    L16
  mov    %r14,%rcx
L32:
  mov    0x0(%rbp,%rcx,4),%esi
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  mov    %esi,(%rdi,%rdx,4)
  add    $0x1,%rcx
  cmp    %ecx,%r8d
  jg     L32
L16:
  mov    %rdi,0x0(%r13)
  mov    0x14(%rsp),%eax
  lea    (%rax,%r9,1),%r12d
  add    $0x8,%r13
  add    0x8(%rsp),%r14
  cmp    %r15,%r13
  jne    L17
L31:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **buildMat(const int *elems, int r, int c) {
  int **xs = (int **)malloc(sizeof(int *) * r);
  for (int i = 0; i < r; i++) {
    int *cs = (int *)malloc(sizeof(int) * c);
    for (int j = i * c; j < (i + 1) * c; j++)
      cs[j % c] = elems[j];
    xs[i] = cs;
  }
  return xs;
}
```
user: What is the c source code of the assembly code below?

```asm
<buildMat>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,8),%edi
  sub    $0x28,%rsp
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %ebx,%ebx
  jle    L15
  mov    %rax,%r13
  lea    (%rax,%rbx,8),%rax
  movslq %r15d,%rdi
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  lea    (%r15,%r15,1),%ebx
  mov    %rdi,(%rsp)
  lea    0x0(,%r15,4),%edi
  mov    %ebx,0x14(%rsp)
  mov    %edi,%ebp
  mov    %r13,%rbx
  mov    %r12,%r13
  mov    %r14,%r12
  mov    %r15d,%r14d
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %r14d,%r11d
  sub    %r15d,%r11d
  mov    %rax,%rdi
  cmp    %r14d,%r11d
  jge    L38
  mov    %r12,%rcx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ecx,%eax
  mov    0x0(%r13,%rcx,4),%esi
  add    $0x1,%rcx
  cltd
  idiv   %r15d
  movslq %edx,%rdx
  mov    %esi,(%rdi,%rdx,4)
  cmp    %ecx,%r14d
  jg     L0
L38:
  mov    0x14(%rsp),%eax
  add    $0x8,%rbx
  add    (%rsp),%r12
  mov    %rdi,-0x8(%rbx)
  lea    (%rax,%r11,1),%r14d
  cmp    0x8(%rsp),%rbx
  jne    L24
L15:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **buildMat(const int *elems, int r, int c) {
  int **xs = (int **)malloc(sizeof(int *) * r);
  for (int i = 0; i < r; i++) {
    int *cs = (int *)malloc(sizeof(int) * c);
    for (int j = i * c; j < (i + 1) * c; j++)
      cs[j % c] = elems[j];
    xs[i] = cs;
  }
  return xs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buildMat>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,8),%edi
  sub    $0x28,%rsp
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %ebx,%ebx
  jle    L35
  mov    %rax,%r13
  lea    (%rax,%rbx,8),%rax
  movslq %r15d,%rdi
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  lea    (%r15,%r15,1),%ebx
  mov    %rdi,(%rsp)
  lea    0x0(,%r15,4),%edi
  mov    %ebx,0x14(%rsp)
  mov    %edi,%ebp
  mov    %r13,%rbx
  mov    %r12,%r13
  mov    %r14,%r12
  mov    %r15d,%r14d
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %r14d,%r11d
  sub    %r15d,%r11d
  mov    %rax,%rdi
  cmp    %r11d,%r14d
  jle    L10
  mov    %r12,%rcx
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %ecx,%eax
  mov    0x0(%r13,%rcx,4),%esi
  add    $0x1,%rcx
  cltd
  idiv   %r15d
  movslq %edx,%rdx
  mov    %esi,(%rdi,%rdx,4)
  cmp    %ecx,%r14d
  jg     L33
L10:
  mov    0x14(%rsp),%eax
  add    $0x8,%rbx
  add    (%rsp),%r12
  mov    %rdi,-0x8(%rbx)
  lea    (%rax,%r11,1),%r14d
  cmp    0x8(%rsp),%rbx
  jne    L3
L35:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **buildMat(const int *elems, int r, int c) {
  int **xs = (int **)malloc(sizeof(int *) * r);
  for (int i = 0; i < r; i++) {
    int *cs = (int *)malloc(sizeof(int) * c);
    for (int j = i * c; j < (i + 1) * c; j++)
      cs[j % c] = elems[j];
    xs[i] = cs;
  }
  return xs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gfarm_timeval_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <gfarm_timeval_normalize@plt>
  nop
  leave
  ret
```

assistant: ```c
void gfarm_timeval_add(struct timeval *t1, const struct timeval *t2) {
  t1->tv_sec += t2->tv_sec;
  t1->tv_usec += t2->tv_usec;
  gfarm_timeval_normalize(t1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gfarm_timeval_add>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  add    %rax,0x8(%rdi)
  mov    (%rsi),%rax
  add    %rax,(%rdi)
  call   <gfarm_timeval_normalize@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gfarm_timeval_add(struct timeval *t1, const struct timeval *t2) {
  t1->tv_sec += t2->tv_sec;
  t1->tv_usec += t2->tv_usec;
  gfarm_timeval_normalize(t1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gfarm_timeval_add>:
  endbr64
  mov    0x8(%rsi),%rax
  add    %rax,0x8(%rdi)
  mov    (%rsi),%rax
  add    %rax,(%rdi)
  jmp    1050 <gfarm_timeval_normalize@plt>
```

assistant: ```c
void gfarm_timeval_add(struct timeval *t1, const struct timeval *t2) {
  t1->tv_sec += t2->tv_sec;
  t1->tv_usec += t2->tv_usec;
  gfarm_timeval_normalize(t1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gfarm_timeval_add>:
  endbr64
  movdqu (%rsi),%xmm0
  movdqu (%rdi),%xmm1
  paddq  %xmm1,%xmm0
  movups %xmm0,(%rdi)
  jmp    1050 <gfarm_timeval_normalize@plt>
```

assistant: ```c
void gfarm_timeval_add(struct timeval *t1, const struct timeval *t2) {
  t1->tv_sec += t2->tv_sec;
  t1->tv_usec += t2->tv_usec;
  gfarm_timeval_normalize(t1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<alloc_wkb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_wkb@plt>
  nop
  leave
  ret
```

assistant: ```c
void alloc_wkb(const char *parser) {
  ((void)0);
  parse_wkb(&parser);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<alloc_wkb>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <parse_wkb@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void alloc_wkb(const char *parser) {
  ((void)0);
  parse_wkb(&parser);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alloc_wkb>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <parse_wkb@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void alloc_wkb(const char *parser) {
  ((void)0);
  parse_wkb(&parser);
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_wkb>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <parse_wkb@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void alloc_wkb(const char *parser) {
  ((void)0);
  parse_wkb(&parser);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <setup_screen@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <draw_string@plt>
  mov    $0x0,%eax
  call   <show_screen@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <cleanup_screen@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: Hello CAB202.

assistant: ```c
int main(void) {
  setup_screen();
  draw_string(0, 0, "Hello CAB202.");
  show_screen();
  sleep(10);
  cleanup_screen();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <setup_screen@plt>
  lea    D4(%rip),%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <draw_string@plt>
  mov    $0x0,%eax
  call   <show_screen@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <cleanup_screen@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Hello CAB202.

assistant: ```c
int main(void) {
  setup_screen();
  draw_string(0, 0, "Hello CAB202.");
  show_screen();
  sleep(10);
  cleanup_screen();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_screen@plt>
  lea    D5(%rip),%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <draw_string@plt>
  xor    %eax,%eax
  call   <show_screen@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  call   <cleanup_screen@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string

tool: D5: Hello CAB202.

assistant: ```c
int main(void) {
  setup_screen();
  draw_string(0, 0, "Hello CAB202.");
  show_screen();
  sleep(10);
  cleanup_screen();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_screen@plt>
  lea    D5(%rip),%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <draw_string@plt>
  xor    %eax,%eax
  call   <show_screen@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  call   <cleanup_screen@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: Hello CAB202.

assistant: ```c
int main(void) {
  setup_screen();
  draw_string(0, 0, "Hello CAB202.");
  show_screen();
  sleep(10);
  cleanup_screen();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Com_BlockChecksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mdfour@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  xor    %eax,%edx
  mov    -0x18(%rbp),%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned Com_BlockChecksum(void *buffer, int length) {
  int digest[4];
  unsigned val;
  mdfour((unsigned char *)digest, (unsigned char *)buffer, length);
  val = digest[0] ^ digest[1] ^ digest[2] ^ digest[3];
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Com_BlockChecksum>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <mdfour@plt>
  mov    (%rsp),%eax
  xor    0x4(%rsp),%eax
  xor    0x8(%rsp),%eax
  xor    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned Com_BlockChecksum(void *buffer, int length) {
  int digest[4];
  unsigned val;
  mdfour((unsigned char *)digest, (unsigned char *)buffer, length);
  val = digest[0] ^ digest[1] ^ digest[2] ^ digest[3];
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<Com_BlockChecksum>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %r8,%rsi
  call   <mdfour@plt>
  mov    (%rsp),%eax
  xor    0x4(%rsp),%eax
  xor    0x8(%rsp),%eax
  xor    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned Com_BlockChecksum(void *buffer, int length) {
  int digest[4];
  unsigned val;
  mdfour((unsigned char *)digest, (unsigned char *)buffer, length);
  val = digest[0] ^ digest[1] ^ digest[2] ^ digest[3];
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Com_BlockChecksum>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %r8,%rsi
  call   <mdfour@plt>
  mov    (%rsp),%eax
  xor    0x4(%rsp),%eax
  xor    0x8(%rsp),%eax
  xor    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned Com_BlockChecksum(void *buffer, int length) {
  int digest[4];
  unsigned val;
  mdfour((unsigned char *)digest, (unsigned char *)buffer, length);
  val = digest[0] ^ digest[1] ^ digest[2] ^ digest[3];
  return val;
}
```