ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_string_number>:
  endbr64
  test   %rdi,%rdi
  je     L79
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  cmp    $0x2d,%dil
  jne    L4
L23:
  movsbl 0x1(%rbx),%edi
  add    $0x2,%rbx
  test   %dil,%dil
  jne    L75
  jmp    L22
  nopl   (%rax)
L76:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L22
L75:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L76
  xor    %eax,%eax
L13:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L23
  xor    %eax,%eax
  jmp    L13
  nopl   (%rax)
L22:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nop
L79:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_string_number(const char *str) {
  int i;
  if (str == NULL) {
    return 0;
  }
  if (*str != '-' && !(isdigit(*str))) {
    return 0;
  }
  for (i = 1; str[i] != 0; i++) {
    if (!isdigit(str[i])) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_string_number>:
  endbr64
  test   %rdi,%rdi
  je     L40
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  cmp    $0x2d,%dil
  jne    L23
L1:
  movsbl 0x1(%rbx),%edi
  add    $0x2,%rbx
  test   %dil,%dil
  jne    L21
  jmp    L49
  nopl   (%rax)
L68:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L49
L21:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L68
  xor    %eax,%eax
L53:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L23:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L1
  xor    %eax,%eax
  jmp    L53
  nopl   (%rax)
L49:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nop
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_string_number(const char *str) {
  int i;
  if (str == NULL) {
    return 0;
  }
  if (*str != '-' && !(isdigit(*str))) {
    return 0;
  }
  for (i = 1; str[i] != 0; i++) {
    if (!isdigit(str[i])) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L31:
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L28
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L28:
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x13,-0xc(%rbp)
  jle    L31
  movl   $0x0,-0xc(%rbp)
  jmp    L46
L45:
  mov    $0x0,%edi
  call   <wait@plt>
  addl   $0x1,-0xc(%rbp)
L46:
  cmpl   $0x13,-0xc(%rbp)
  jle    L45
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D14
type: string

tool: D18: Child %d sum %d


tool: D14: Parent sum %d


assistant: ```c
int main() {
  int i, child, sum = 0;
  for (i = 0; i < 20; i++) {
    child = fork();
    if (child == 0) {
      sum += 1;
      printf("Child %d sum %d\n", i, sum);
      exit(0);
    }
  }
  for (i = 0; i < 20; i++) {
    wait(0);
  }
  printf("Parent sum %d\n", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
  jmp    L19
L11:
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  je     L9
L19:
  call   <fork@plt>
  test   %eax,%eax
  jne    L11
  add    $0x1,%ebp
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L11
L9:
  mov    $0x0,%edi
  call   <wait@plt>
  sub    $0x1,%ebx
  jne    L9
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D4: Child %d sum %d


tool: D3: Parent sum %d


assistant: ```c
int main() {
  int i, child, sum = 0;
  for (i = 0; i < 20; i++) {
    child = fork();
    if (child == 0) {
      sum += 1;
      printf("Child %d sum %d\n", i, sum);
      exit(0);
    }
  }
  for (i = 0; i < 20; i++) {
    wait(0);
  }
  printf("Parent sum %d\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L12
  nopl   (%rax)
L26:
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  je     L23
L12:
  call   <fork@plt>
  test   %eax,%eax
  jne    L26
  add    $0x1,%ebp
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  mov    %ebp,%edx
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  cmp    $0x14,%ebx
  jne    L12
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %edi,%edi
  call   <wait@plt>
  sub    $0x1,%ebx
  jne    L23
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string

tool: D10: Child %d sum %d


tool: D3: Parent sum %d


assistant: ```c
int main() {
  int i, child, sum = 0;
  for (i = 0; i < 20; i++) {
    child = fork();
    if (child == 0) {
      sum += 1;
      printf("Child %d sum %d\n", i, sum);
      exit(0);
    }
  }
  for (i = 0; i < 20; i++) {
    wait(0);
  }
  printf("Parent sum %d\n", sum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L24
  nopl   (%rax)
L14:
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  je     L27
L24:
  call   <fork@plt>
  test   %eax,%eax
  jne    L14
  add    $0x1,%ebp
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  mov    %ebp,%edx
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  cmp    $0x14,%ebx
  jne    L24
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %edi,%edi
  call   <wait@plt>
  sub    $0x1,%ebx
  jne    L27
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D11
type_infered: string

tool: D8: Child %d sum %d


tool: D11: Parent sum %d


assistant: ```c
int main() {
  int i, child, sum = 0;
  for (i = 0; i < 20; i++) {
    child = fork();
    if (child == 0) {
      sum += 1;
      printf("Child %d sum %d\n", i, sum);
      exit(0);
    }
  }
  for (i = 0; i < 20; i++) {
    wait(0);
  }
  printf("Parent sum %d\n", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_gets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L1:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
L29:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x23,-0x5(%rbp)
  je     L48
  cmpb   $0xa,-0x5(%rbp)
  je     L48
  mov    $0x1,%eax
  jmp    L32
L48:
  mov    $0x0,%eax
L32:
  test   %eax,%eax
  jne    L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void my_gets(char *a) {
  char c;
  int i = 0;
  while ((c = getchar()), c != '#' && c != '\n')
    a[i++] = c;
  a[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_gets>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebx
  jmp    L29
L11:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L29:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L24
  cmp    $0xa,%al
  jne    L11
L24:
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void my_gets(char *a) {
  char c;
  int i = 0;
  while ((c = getchar()), c != '#' && c != '\n')
    a[i++] = c;
  a[i] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_gets>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %al,(%rbx)
  add    $0x1,%rbx
L7:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L4
  cmp    $0xa,%al
  jne    L23
L4:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void my_gets(char *a) {
  char c;
  int i = 0;
  while ((c = getchar()), c != '#' && c != '\n')
    a[i++] = c;
  a[i] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<my_gets>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %al,(%rbx)
  add    $0x1,%rbx
L19:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L13
  cmp    $0xa,%al
  jne    L2
L13:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void my_gets(char *a) {
  char c;
  int i = 0;
  while ((c = getchar()), c != '#' && c != '\n')
    a[i++] = c;
  a[i] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<basePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L20
  mov    -0x28(%rbp),%rax
  jmp    L25
L20:
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L24
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L24:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L25:
  leave
  ret
```

assistant: ```c
char *basePath(const char *path) {
  char *last = strrchr(path, '/');
  if (last == NULL) {
    return (char *)path;
  } else {
    int len = last - path;
    char *str = (char *)malloc(len + 1);
    if (len > 0) {
      memcpy(str, path, len);
    }
    str[len] = '\0';
    return str;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<basePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x2f,%esi
  call   <strrchr@plt>
  mov    %rbp,%r12
  test   %rax,%rax
  je     L5
  mov    %rax,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jg     L13
L15:
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
L5:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L15
```

assistant: ```c
char *basePath(const char *path) {
  char *last = strrchr(path, '/');
  if (last == NULL) {
    return (char *)path;
  } else {
    int len = last - path;
    char *str = (char *)malloc(len + 1);
    if (len > 0) {
      memcpy(str, path, len);
    }
    str[len] = '\0';
    return str;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<basePath>:
  endbr64
  push   %r13
  mov    $0x2f,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%r12
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jg     L0
L15:
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
L22:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L0:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L15
```

assistant: ```c
char *basePath(const char *path) {
  char *last = strrchr(path, '/');
  if (last == NULL) {
    return (char *)path;
  } else {
    int len = last - path;
    char *str = (char *)malloc(len + 1);
    if (len > 0) {
      memcpy(str, path, len);
    }
    str[len] = '\0';
    return str;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<basePath>:
  endbr64
  push   %r13
  mov    $0x2f,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%r12
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L25
  mov    %rax,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jg     L20
L19:
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
L25:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L20:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L19
```

assistant: ```c
char *basePath(const char *path) {
  char *last = strrchr(path, '/');
  if (last == NULL) {
    return (char *)path;
  } else {
    int len = last - path;
    char *str = (char *)malloc(len + 1);
    if (len > 0) {
      memcpy(str, path, len);
    }
    str[len] = '\0';
    return str;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vspltish>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L4:
  mov    -0x1c(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x2,-0x4(%rbp)
L8:
  cmpl   $0xf,-0x4(%rbp)
  jle    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vspltish(char *v, int val) {
  int i;
  for (i = 0; i < 16; i += 2)
    v[i] = val >> 7, v[i + 1] = val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vspltish>:
  endbr64
  mov    %esi,%edx
  sar    $0x7,%edx
  mov    %rdi,%rax
  add    $0x10,%rdi
L3:
  mov    %dl,(%rax)
  mov    %sil,0x1(%rax)
  add    $0x2,%rax
  cmp    %rdi,%rax
  jne    L3
  ret
```

assistant: ```c
void vspltish(char *v, int val) {
  int i;
  for (i = 0; i < 16; i += 2)
    v[i] = val >> 7, v[i + 1] = val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vspltish>:
  endbr64
  mov    %esi,%eax
  lea    0x10(%rdi),%rdx
  sar    $0x7,%eax
  nopl   (%rax)
L2:
  mov    %al,(%rdi)
  add    $0x2,%rdi
  mov    %sil,-0x1(%rdi)
  cmp    %rdx,%rdi
  jne    L2
  ret
```

assistant: ```c
void vspltish(char *v, int val) {
  int i;
  for (i = 0; i < 16; i += 2)
    v[i] = val >> 7, v[i + 1] = val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vspltish>:
  endbr64
  mov    %esi,%edx
  movzbl %sil,%esi
  sar    $0x7,%edx
  mov    %rsi,%rax
  movzbl %dl,%edx
  shl    $0x8,%rax
  or     %rdx,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,-0x18(%rsp)
  mov    %rax,-0x10(%rsp)
  movdqa -0x18(%rsp),%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void vspltish(char *v, int val) {
  int i;
  for (i = 0; i < 16; i += 2)
    v[i] = val >> 7, v[i + 1] = val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<polarLUV_to_LUV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <cosf@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x8(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinf@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x8(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: byte[8]

tool: {"D0": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

assistant: ```c
void polarLUV_to_LUV(float l, float c, float h, float *L, float *U, float *V) {
  h = (.01745329251994329576 * (h));
  *L = l;
  *U = c * cosf(h);
  *V = c * sinf(h);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<polarLUV_to_LUV>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movd   %xmm0,%r13d
  movss  %xmm1,0x4(%rsp)
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  cvtss2sd %xmm2,%xmm2
  mulsd  D0(%rip),%xmm2
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm2,%xmm0
  call   <sincosf@plt>
  mov    %r13d,(%r12)
  movss  0x4(%rsp),%xmm3
  movaps %xmm3,%xmm0
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp)
  mulss  0xc(%rsp),%xmm3
  movss  %xmm3,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: byte[8]

tool: {"D0": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

assistant: ```c
void polarLUV_to_LUV(float l, float c, float h, float *L, float *U, float *V) {
  h = (.01745329251994329576 * (h));
  *L = l;
  *U = c * cosf(h);
  *V = c * sinf(h);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<polarLUV_to_LUV>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  movss  %xmm0,0x4(%rsp)
  pxor   %xmm0,%xmm0
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  cvtss2sd %xmm2,%xmm0
  mulsd  D5(%rip),%xmm0
  movss  %xmm1,(%rsp)
  cvtsd2ss %xmm0,%xmm0
  call   <sincosf@plt>
  movss  (%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  movss  0x4(%rsp),%xmm3
  mulss  %xmm1,%xmm0
  mulss  0xc(%rsp),%xmm1
  movss  %xmm3,(%r12)
  movss  %xmm0,0x0(%rbp)
  movss  %xmm1,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: byte[8]

tool: {"D5": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

assistant: ```c
void polarLUV_to_LUV(float l, float c, float h, float *L, float *U, float *V) {
  h = (.01745329251994329576 * (h));
  *L = l;
  *U = c * cosf(h);
  *V = c * sinf(h);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<polarLUV_to_LUV>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  movss  %xmm0,0x4(%rsp)
  pxor   %xmm0,%xmm0
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  cvtss2sd %xmm2,%xmm0
  mulsd  D4(%rip),%xmm0
  movss  %xmm1,(%rsp)
  cvtsd2ss %xmm0,%xmm0
  call   <sincosf@plt>
  movss  (%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  movss  0x4(%rsp),%xmm3
  mulss  %xmm1,%xmm0
  mulss  0xc(%rsp),%xmm1
  movss  %xmm3,(%r12)
  movss  %xmm0,0x0(%rbp)
  movss  %xmm1,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: byte[8]

tool: {"D4": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

assistant: ```c
void polarLUV_to_LUV(float l, float c, float h, float *L, float *U, float *V) {
  h = (.01745329251994329576 * (h));
  *L = l;
  *U = c * cosf(h);
  *V = c * sinf(h);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L0
L19:
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x64,%al
  je     L11
  movzbl -0x9(%rbp),%eax
  cmp    $0x63,%al
  jne    L0
L11:
  mov    $0x0,%eax
  call   <CoderRot13@plt>
L0:
  movzbl -0x9(%rbp),%eax
  cmp    $0x71,%al
  jne    L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: %c

assistant: ```c
int main() {
  char mode;
  while (mode != 'q') {
    scanf("%c", &mode);
    if (mode == 'd' || mode == 'c') {
      CoderRot13();
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rbx
L28:
  cmpb   $0x71,0x7(%rsp)
  je     L2
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x63,%eax
  cmp    $0x1,%al
  ja     L28
  mov    $0x0,%eax
  call   <CoderRot13@plt>
  jmp    L28
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: %c

assistant: ```c
int main() {
  char mode;
  while (mode != 'q') {
    scanf("%c", &mode);
    if (mode == 'd' || mode == 'c') {
      CoderRot13();
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
L14:
  movzbl 0x7(%rsp),%eax
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L17:
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x63(%rax),%edx
  cmp    $0x1,%dl
  jbe    L49
L27:
  cmp    $0x71,%al
  jne    L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L49:
  xor    %eax,%eax
  call   <CoderRot13@plt>
  jmp    L14
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: %c

assistant: ```c
int main() {
  char mode;
  while (mode != 'q') {
    scanf("%c", &mode);
    if (mode == 'd' || mode == 'c') {
      CoderRot13();
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
L13:
  movzbl 0x7(%rsp),%eax
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L31:
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x63(%rax),%edx
  cmp    $0x1,%dl
  jbe    L38
L29:
  cmp    $0x71,%al
  jne    L31
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  call   <CoderRot13@plt>
  jmp    L13
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: %c

assistant: ```c
int main() {
  char mode;
  while (mode != 'q') {
    scanf("%c", &mode);
    if (mode == 'd' || mode == 'c') {
      CoderRot13();
    }
  }
  return 0;
}
```