ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L193:
  xor    %eax,%eax
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L180
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L180
  jle    L21
  mov    $0x4e,%r12d
  xor    %r15d,%r15d
  lea    0x3(%rsp),%rbx
  jmp    L127
L153:
  cmp    $0x53,%r12b
  je     L168
  cmp    $0x4c,%r12b
  je     L172
  cmp    $0x4f,%r12b
  jne    L209
  movzbl 0x3(%rsp),%eax
  cmp    $0x45,%al
  je     L26
  cmp    $0x44,%al
  mov    $0x4e,%eax
  cmove  %eax,%r12d
  nopw   0x0(%rax,%rax,1)
L209:
  add    $0x1,%r15d
  cmp    %r15d,0x4(%rsp)
  jle    L84
L127:
  xor    %eax,%eax
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x4e,%r12b
  jne    L153
  movzbl 0x3(%rsp),%eax
  cmp    $0x45,%al
  je     L45
  cmp    $0x44,%al
  mov    $0x4c,%eax
  cmove  %eax,%r12d
  add    $0x1,%r15d
  cmp    %r15d,0x4(%rsp)
  jg     L127
L84:
  movsbl %r12b,%esi
L182:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L193
  nopw   0x0(%rax,%rax,1)
L168:
  movzbl 0x3(%rsp),%eax
  cmp    $0x45,%al
  je     L56
  cmp    $0x44,%al
  mov    $0x4f,%eax
  cmove  %eax,%r12d
  jmp    L209
  cs nopw 0x0(%rax,%rax,1)
L172:
  movzbl 0x3(%rsp),%eax
  cmp    $0x45,%al
  je     L133
  cmp    $0x44,%al
  mov    $0x53,%eax
  cmove  %eax,%r12d
  jmp    L209
  nopl   0x0(%rax)
L45:
  mov    $0x4f,%r12d
  jmp    L209
  nopl   0x0(%rax,%rax,1)
L56:
  mov    $0x4c,%r12d
  jmp    L209
  nopl   0x0(%rax,%rax,1)
L133:
  mov    $0x4e,%r12d
  jmp    L209
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0x53,%r12d
  jmp    L209
  nopl   0x0(%rax,%rax,1)
L180:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  mov    $0x4e,%esi
  jmp    L182
L95:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D27
type_infered: string
name: read_data
arguments: label: D5
type_infered: string

tool: D0: %d

tool: D27:  %c

tool: D5: %c


assistant: ```c
int main() {
  int a, i;
  char c, p = 'N';
  while (scanf("%d", &a)) {
    if (a == 0) {
      break;
    }
    for (i = 0; i < a; i++) {
      scanf(" %c", &c);
      if (p == 'N' && c == 'E') {
        p = 'O';
      } else if (p == 'N' && c == 'D') {
        p = 'L';
      } else if (p == 'S' && c == 'E') {
        p = 'L';
      } else if (p == 'S' && c == 'D') {
        p = 'O';
      } else if (p == 'L' && c == 'E') {
        p = 'N';
      } else if (p == 'L' && c == 'D') {
        p = 'S';
      } else if (p == 'O' && c == 'E') {
        p = 'S';
      } else if (p == 'O' && c == 'D') {
        p = 'N';
      }
    }
    printf("%c\n", p);
    p = 'N';
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uart_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L18
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart_putchar@plt>
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart_puts(char *c) {
  while (*c) {
    uart_putchar(*c);
    c++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uart_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L10:
  movsbl %dil,%edi
  call   <uart_putchar@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L10
L2:
  pop    %rbx
  ret
```

assistant: ```c
void uart_puts(char *c) {
  while (*c) {
    uart_putchar(*c);
    c++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
L7:
  call   <uart_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L10:
  pop    %rbx
  ret
```

assistant: ```c
void uart_puts(char *c) {
  while (*c) {
    uart_putchar(*c);
    c++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uart_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L5:
  call   <uart_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L5
L17:
  pop    %rbx
  ret
```

assistant: ```c
void uart_puts(char *c) {
  while (*c) {
    uart_putchar(*c);
    c++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<adjust>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L58
L40:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jge    L1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L1
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L35
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L58:
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L40
  jmp    L49
L35:
  nop
L49:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void adjust(int array[], int n) {
  int item, i, j;
  j = 0;
  item = array[j];
  i = 2 * j + 1;
  while (i <= n - 1) {
    if (i + 1 <= n - 1)
      if (array[i] < array[i + 1])
        i++;
    if (item < array[i]) {
      array[j] = array[i];
      j = i;
      i = 2 * j + 1;
    } else
      break;
  }
  array[j] = item;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<adjust>:
  endbr64
  mov    (%rdi),%r9d
  cmp    $0x1,%esi
  jle    L72
  mov    $0x0,%ecx
  mov    $0x1,%eax
  lea    -0x1(%rsi),%r10d
  jmp    L73
L47:
  movslq %edx,%rax
  mov    (%rdi,%rax,4),%eax
  cmp    %r9d,%eax
  jle    L10
  movslq %ecx,%rcx
  mov    %eax,(%rdi,%rcx,4)
  lea    0x1(%rdx,%rdx,1),%eax
  cmp    %eax,%esi
  jle    L76
  mov    %edx,%ecx
L73:
  mov    %eax,%edx
  cmp    %eax,%r10d
  jle    L47
  movslq %eax,%r8
  mov    0x4(%rdi,%r8,4),%r11d
  cmp    %r11d,(%rdi,%r8,4)
  jge    L47
  lea    0x1(%rax),%edx
  jmp    L47
L76:
  mov    %edx,%ecx
L10:
  movslq %ecx,%rcx
  mov    %r9d,(%rdi,%rcx,4)
  ret
L72:
  mov    $0x0,%ecx
  jmp    L10
```

assistant: ```c
void adjust(int array[], int n) {
  int item, i, j;
  j = 0;
  item = array[j];
  i = 2 * j + 1;
  while (i <= n - 1) {
    if (i + 1 <= n - 1)
      if (array[i] < array[i + 1])
        i++;
    if (item < array[i]) {
      array[j] = array[i];
      j = i;
      i = 2 * j + 1;
    } else
      break;
  }
  array[j] = item;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<adjust>:
  endbr64
  mov    (%rdi),%r11d
  mov    %rdi,%r9
  cmp    $0x1,%esi
  jle    L28
  push   %rbx
  xor    %ecx,%ecx
  lea    -0x1(%rsi),%ebx
  mov    $0x1,%edi
  jmp    L41
  nopl   0x0(%rax)
L11:
  lea    0x1(%rdx,%rdx,1),%edi
  mov    %r8d,(%rax)
  cmp    %edi,%esi
  jle    L23
  mov    %edx,%ecx
L41:
  movslq %edi,%rax
  mov    %edi,%edx
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%r10
  mov    (%r10),%r8d
  cmp    %ebx,%edi
  jge    L5
  lea    0x4(%r9,%rax,1),%rax
  mov    (%rax),%edi
  cmp    %r8d,%edi
  jle    L5
  add    $0x1,%edx
  mov    %edi,%r8d
  mov    %rax,%r10
L5:
  movslq %ecx,%rax
  lea    (%r9,%rax,4),%rax
  cmp    %r8d,%r11d
  jl     L11
  mov    %r11d,(%rax)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %r10,%rax
  mov    %r11d,(%rax)
  pop    %rbx
  ret
L28:
  mov    %r11d,(%rdi)
  ret
```

assistant: ```c
void adjust(int array[], int n) {
  int item, i, j;
  j = 0;
  item = array[j];
  i = 2 * j + 1;
  while (i <= n - 1) {
    if (i + 1 <= n - 1)
      if (array[i] < array[i + 1])
        i++;
    if (item < array[i]) {
      array[j] = array[i];
      j = i;
      i = 2 * j + 1;
    } else
      break;
  }
  array[j] = item;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adjust>:
  endbr64
  mov    (%rdi),%r11d
  mov    %rdi,%r9
  cmp    $0x1,%esi
  jle    L2
  push   %rbx
  xor    %ecx,%ecx
  lea    -0x1(%rsi),%ebx
  mov    $0x1,%edi
  jmp    L55
  nopl   0x0(%rax)
L54:
  lea    0x1(%rdx,%rdx,1),%edi
  mov    %r8d,(%rax)
  cmp    %edi,%esi
  jle    L49
  mov    %edx,%ecx
L55:
  movslq %edi,%rax
  mov    %edi,%edx
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%r10
  mov    (%r10),%r8d
  cmp    %ebx,%edi
  jge    L45
  lea    0x4(%r9,%rax,1),%rax
  mov    (%rax),%edi
  cmp    %r8d,%edi
  jle    L45
  add    $0x1,%edx
  mov    %edi,%r8d
  mov    %rax,%r10
L45:
  movslq %ecx,%rax
  lea    (%r9,%rax,4),%rax
  cmp    %r8d,%r11d
  jl     L54
  mov    %r11d,(%rax)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %r10,%rax
  mov    %r11d,(%rax)
  pop    %rbx
  ret
L2:
  mov    %r11d,(%rdi)
  ret
```

assistant: ```c
void adjust(int array[], int n) {
  int item, i, j;
  j = 0;
  item = array[j];
  i = 2 * j + 1;
  while (i <= n - 1) {
    if (i + 1 <= n - 1)
      if (array[i] < array[i + 1])
        i++;
    if (item < array[i]) {
      array[j] = array[i];
      j = i;
      i = 2 * j + 1;
    } else
      break;
  }
  array[j] = item;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binary_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L77
  mov    $0xffffffff,%eax
  jmp    L20
L77:
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L43
L21:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L23
  mov    -0x4(%rbp),%eax
  jmp    L20
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L41
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L43
L41:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L43:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L21
  mov    $0xffffffff,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int binary_search(int *nums, int nums_size, int target) {
  if (nums_size < 1) {
    return -1;
  }
  int low = 0, high = nums_size - 1, mid;
  while (low <= high) {
    mid = low + (high - low) / 2;
    if (nums[mid] == target) {
      return mid;
    } else if (nums[mid] < target) {
      low = mid + 1;
    } else {
      high = mid - 1;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<binary_search>:
  endbr64
  mov    %rdi,%r8
  test   %esi,%esi
  jle    L2
  sub    $0x1,%esi
  mov    $0x0,%ecx
  jmp    L38
L11:
  lea    -0x1(%rax),%esi
L44:
  cmp    %esi,%ecx
  jg     L14
L38:
  mov    %esi,%edi
  sub    %ecx,%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  cmp    %edx,%edi
  je     L48
  jge    L11
  lea    0x1(%rax),%ecx
  jmp    L44
L14:
  mov    $0xffffffff,%eax
  ret
L2:
  mov    $0xffffffff,%eax
L48:
  ret
```

assistant: ```c
int binary_search(int *nums, int nums_size, int target) {
  if (nums_size < 1) {
    return -1;
  }
  int low = 0, high = nums_size - 1, mid;
  while (low <= high) {
    mid = low + (high - low) / 2;
    if (nums[mid] == target) {
      return mid;
    } else if (nums[mid] < target) {
      low = mid + 1;
    } else {
      high = mid - 1;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binary_search>:
  endbr64
  test   %esi,%esi
  jle    L40
  sub    $0x1,%esi
  xor    %ecx,%ecx
  jmp    L6
  nop
L14:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jg     L40
L6:
  mov    %esi,%eax
  sub    %ecx,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L19
  jl     L14
  lea    -0x1(%rax),%esi
  cmp    %esi,%ecx
  jle    L6
L40:
  mov    $0xffffffff,%eax
L19:
  ret
```

assistant: ```c
int binary_search(int *nums, int nums_size, int target) {
  if (nums_size < 1) {
    return -1;
  }
  int low = 0, high = nums_size - 1, mid;
  while (low <= high) {
    mid = low + (high - low) / 2;
    if (nums[mid] == target) {
      return mid;
    } else if (nums[mid] < target) {
      low = mid + 1;
    } else {
      high = mid - 1;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<binary_search>:
  endbr64
  test   %esi,%esi
  jle    L20
  sub    $0x1,%esi
  xor    %ecx,%ecx
  nopl   (%rax)
L31:
  mov    %esi,%eax
  sub    %ecx,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L0
  jge    L34
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L31
L20:
  mov    $0xffffffff,%eax
L0:
  ret
L34:
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L31
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
int binary_search(int *nums, int nums_size, int target) {
  if (nums_size < 1) {
    return -1;
  }
  int low = 0, high = nums_size - 1, mid;
  while (low <= high) {
    mid = low + (high - low) / 2;
    if (nums[mid] == target) {
      return mid;
    } else if (nums[mid] < target) {
      low = mid + 1;
    } else {
      high = mid - 1;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type_infered: string

tool: D12: %s

assistant: ```c
void main(void) {
  char s[30];
  scanf("%s", s);
  printf("%s", s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string

tool: D8: %s

assistant: ```c
void main(void) {
  char s[30];
  scanf("%s", s);
  printf("%s", s);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string

tool: D2: %s

assistant: ```c
void main(void) {
  char s[30];
  scanf("%s", s);
  printf("%s", s);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: %s

assistant: ```c
void main(void) {
  char s[30];
  scanf("%s", s);
  printf("%s", s);
}
```
user: What is the c source code of the assembly code below:

```asm
<UI_OpponentLeaderHead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <UI_OpponentLeaderName@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <UI_AIFromName@plt>
  leave
  ret
```

assistant: ```c
const char *UI_OpponentLeaderHead(void) {
  const char *leader = UI_OpponentLeaderName();
  return UI_AIFromName(leader);
}
```
user: What is the c source code of the assembly code below?

```asm
<UI_OpponentLeaderHead>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <UI_OpponentLeaderName@plt>
  mov    %rax,%rdi
  call   <UI_AIFromName@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
const char *UI_OpponentLeaderHead(void) {
  const char *leader = UI_OpponentLeaderName();
  return UI_AIFromName(leader);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UI_OpponentLeaderHead>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <UI_OpponentLeaderName@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <UI_AIFromName@plt>
```

assistant: ```c
const char *UI_OpponentLeaderHead(void) {
  const char *leader = UI_OpponentLeaderName();
  return UI_AIFromName(leader);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L49:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L43
  ucomisd %xmm1,%xmm0
  je     L50
L43:
  mov    $0x0,%eax
  call   <abort@plt>
L50:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd D13(%rip),%xmm0
  jp     L33
  ucomisd D13(%rip),%xmm0
  je     L47
L33:
  mov    $0x0,%eax
  call   <abort@plt>
L47:
  addl   $0x1,-0x4(%rbp)
L38:
  cmpl   $0xff,-0x4(%rbp)
  jle    L49
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
type_infered: f64

tool: D13: 5

assistant: ```c
__attribute__((no)) void bar(double *pd, double *pa, double *pb, double *pc) {
  int i;
  for (i = 0; i < 256; i++) {
    if (pa[i] != (pb[i] * pc[i]))
      abort();
    if (pd[i] != 5.0)
      abort();
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bar>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    $0x0,%ebx
  jmp    L63
L53:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L51
L32:
  mov    $0x0,%eax
  call   <abort@plt>
L55:
  add    $0x8,%rbx
  cmp    $0x800,%rbx
  je     L9
L63:
  movsd  (%r14,%rbx,1),%xmm0
  mulsd  0x0(%r13,%rbx,1),%xmm0
  ucomisd 0x0(%rbp,%rbx,1),%xmm0
  jp     L53
  jne    L53
L51:
  movsd  D2(%rip),%xmm1
  ucomisd (%r12,%rbx,1),%xmm1
  jp     L32
  je     L55
  jmp    L32
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: f64

tool: D2: 5

assistant: ```c
__attribute__((no)) void bar(double *pd, double *pa, double *pb, double *pc) {
  int i;
  for (i = 0; i < 256; i++) {
    if (pa[i] != (pb[i] * pc[i]))
      abort();
    if (pd[i] != 5.0)
      abort();
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bar>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L20
  nopl   0x0(%rax)
L70:
  movsd  D1(%rip),%xmm1
  ucomisd 0x0(%r13,%rbx,1),%xmm1
  jp     L18
  jne    L18
  add    $0x8,%rbx
  cmp    $0x800,%rbx
  je     L6
L20:
  movsd  (%r14,%rbx,1),%xmm0
  mulsd  0x0(%rbp,%rbx,1),%xmm0
  ucomisd (%r12,%rbx,1),%xmm0
  jp     L30
  je     L70
L30:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L70
  nop
L18:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <abort@plt>
  cmp    $0x800,%rbx
  jne    L20
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: f64

tool: D1: 5

assistant: ```c
__attribute__((no)) void bar(double *pd, double *pa, double *pb, double *pc) {
  int i;
  for (i = 0; i < 256; i++) {
    if (pa[i] != (pb[i] * pc[i]))
      abort();
    if (pd[i] != 5.0)
      abort();
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bar>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L27
  nopl   0x0(%rax)
L71:
  movsd  D8(%rip),%xmm1
  ucomisd 0x0(%r13,%rbx,1),%xmm1
  jp     L31
  jne    L31
  add    $0x8,%rbx
  cmp    $0x800,%rbx
  je     L50
L27:
  movsd  (%r14,%rbx,1),%xmm0
  mulsd  0x0(%rbp,%rbx,1),%xmm0
  ucomisd (%r12,%rbx,1),%xmm0
  jp     L57
  je     L71
L57:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L71
  nop
L31:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <abort@plt>
  cmp    $0x800,%rbx
  jne    L27
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: f64

tool: D8: 5

assistant: ```c
__attribute__((no)) void bar(double *pd, double *pa, double *pb, double *pc) {
  int i;
  for (i = 0; i < 256; i++) {
    if (pa[i] != (pb[i] * pc[i]))
      abort();
    if (pd[i] != 5.0)
      abort();
  }
  return;
}
```