ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<d2xy>:
  endbr64
  movl   $0x0,(%rcx)
  movl   $0x0,(%rdx)
  cmp    $0x1,%edi
  jle    L2
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %r12d,%ebx
  mov    %r13d,%edi
  mov    %r15,%rdx
  mov    %r14,%rsi
  shr    $0x1f,%ebx
  add    %r12d,%ebx
  sar    %ebx
  and    $0x1,%ebx
  mov    %ebx,%r8d
  mov    %ebx,%ecx
  xor    %r12d,%r8d
  imul   %r13d,%ebx
  and    $0x1,%r8d
  mov    %r8d,0xc(%rsp)
  call   <rot@plt>
  mov    0xc(%rsp),%r8d
  add    %ebx,(%r14)
  lea    0x3(%r12),%eax
  imul   %r13d,%r8d
  add    %r8d,(%r15)
  test   %r12d,%r12d
  cmovns %r12d,%eax
  add    %r13d,%r13d
  sar    $0x2,%eax
  mov    %eax,%r12d
  cmp    %r13d,%ebp
  jg     L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void d2xy(u_int64_t n, u_int64_t d, u_int32_t *x, u_int32_t *y) {
  u_int64_t s, t = d;
  u_int32_t rx, ry;
  *x = *y = 0;
  for (s = 1; s < n; s *= 2) {
    rx = 1 & (t / 2);
    ry = 1 & (t ^ rx);
    rot(s, x, y, rx, ry);
    *x += s * rx;
    *y += s * ry;
    t /= 4;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<F>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  jne    L15
  mov    -0x4(%rbp),%eax
  jmp    L8
L15:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <F>
  imul   -0x4(%rbp),%eax
L8:
  leave
  ret
```

assistant: ```c
int F(int x, int n) {
  if (n == 1)
    return x;
  else
    return x * F(x, n - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<F>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%esi
  jne    L5
L19:
  mov    %ebx,%eax
  pop    %rbx
  ret
L5:
  sub    $0x1,%esi
  call   <F>
  imul   %eax,%ebx
  jmp    L19
```

assistant: ```c
int F(int x, int n) {
  if (n == 1)
    return x;
  else
    return x * F(x, n - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<F>:
  endbr64
  mov    $0x1,%edx
  cmp    $0x1,%esi
  je     L3
  xchg   %ax,%ax
L15:
  sub    $0x1,%esi
  imul   %edi,%edx
  cmp    $0x1,%esi
  jne    L15
  mov    %edi,%eax
  imul   %edx,%eax
  ret
  nopl   0x0(%rax)
L3:
  mov    %edi,%eax
  ret
```

assistant: ```c
int F(int x, int n) {
  if (n == 1)
    return x;
  else
    return x * F(x, n - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<F>:
  endbr64
  mov    $0x1,%edx
  cmp    $0x1,%esi
  je     L14
  xchg   %ax,%ax
L0:
  sub    $0x1,%esi
  imul   %edi,%edx
  cmp    $0x1,%esi
  jne    L0
  mov    %edi,%eax
  imul   %edx,%eax
  ret
  nopl   0x0(%rax)
L14:
  mov    %edi,%eax
  ret
```

assistant: ```c
int F(int x, int n) {
  if (n == 1)
    return x;
  else
    return x * F(x, n - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_pitch_contour>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L36
L55:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xfffffc18,%eax
  je     L67
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L67
  cmpl   $0x0,-0x1c(%rbp)
  jns    L19
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  jmp    L7
L19:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  sub    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jle    L9
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <quantize5@plt>
  mov    %eax,(%rbx)
L9:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  add    $0x100,%edx
  mov    %edx,(%rax)
  jmp    L7
L67:
  nop
L7:
  addl   $0x1,-0x18(%rbp)
L36:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L55
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void compute_pitch_contour(int nnotes, int *midipitch, int qntflag) {
  int lastpitch, newpitch;
  int i;
  lastpitch = -1;
  for (i = 0; i < nnotes; i++) {
    if (midipitch[i] == -1000 || midipitch[i] == 0)
      continue;
    if (lastpitch < 0) {
      lastpitch = midipitch[i];
      midipitch[i] = -1;
      continue;
    } else {
      newpitch = midipitch[i];
      midipitch[i] = midipitch[i] - lastpitch;
      lastpitch = newpitch;
      if (qntflag > 0)
        midipitch[i] = quantize5(midipitch[i]);
      midipitch[i] += 256;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compute_pitch_contour>:
  endbr64
  test   %edi,%edi
  jle    L70
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r14d
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r13
  mov    $0xffffffff,%eax
  jmp    L47
L68:
  movl   $0xffffffff,(%rbx)
  mov    %ebp,%eax
  jmp    L45
L11:
  addl   $0x100,(%r12)
  mov    %ebp,%eax
L45:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  je     L35
L47:
  mov    %rbx,%r12
  mov    (%rbx),%ebp
  cmp    $0xfffffc18,%ebp
  je     L45
  test   %ebp,%ebp
  je     L45
  test   %eax,%eax
  js     L68
  mov    %ebp,%edi
  sub    %eax,%edi
  mov    %edi,(%rbx)
  test   %r14d,%r14d
  jle    L11
  call   <quantize5@plt>
  mov    %eax,(%rbx)
  jmp    L11
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L70:
  ret
```

assistant: ```c
void compute_pitch_contour(int nnotes, int *midipitch, int qntflag) {
  int lastpitch, newpitch;
  int i;
  lastpitch = -1;
  for (i = 0; i < nnotes; i++) {
    if (midipitch[i] == -1000 || midipitch[i] == 0)
      continue;
    if (lastpitch < 0) {
      lastpitch = midipitch[i];
      midipitch[i] = -1;
      continue;
    } else {
      newpitch = midipitch[i];
      midipitch[i] = midipitch[i] - lastpitch;
      lastpitch = newpitch;
      if (qntflag > 0)
        midipitch[i] = quantize5(midipitch[i]);
      midipitch[i] += 256;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_pitch_contour>:
  endbr64
  test   %edi,%edi
  jle    L50
  push   %r13
  lea    -0x1(%rdi),%eax
  mov    %edx,%r13d
  push   %r12
  lea    0x4(%rsi,%rax,4),%r12
  mov    $0xffffffff,%eax
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %ebp,%edi
  sub    %eax,%edi
  mov    %edi,(%rbx)
  test   %r13d,%r13d
  jle    L37
  call   <quantize5@plt>
  mov    %eax,%edi
L37:
  add    $0x100,%edi
  mov    %ebp,%eax
  mov    %edi,(%rbx)
L11:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L58
L2:
  mov    (%rbx),%ebp
  cmp    $0xfffffc18,%ebp
  je     L11
  test   %ebp,%ebp
  je     L11
  test   %eax,%eax
  jns    L14
  movl   $0xffffffff,(%rbx)
  add    $0x4,%rbx
  mov    %ebp,%eax
  cmp    %r12,%rbx
  jne    L2
L58:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  ret
```

assistant: ```c
void compute_pitch_contour(int nnotes, int *midipitch, int qntflag) {
  int lastpitch, newpitch;
  int i;
  lastpitch = -1;
  for (i = 0; i < nnotes; i++) {
    if (midipitch[i] == -1000 || midipitch[i] == 0)
      continue;
    if (lastpitch < 0) {
      lastpitch = midipitch[i];
      midipitch[i] = -1;
      continue;
    } else {
      newpitch = midipitch[i];
      midipitch[i] = midipitch[i] - lastpitch;
      lastpitch = newpitch;
      if (qntflag > 0)
        midipitch[i] = quantize5(midipitch[i]);
      midipitch[i] += 256;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compute_pitch_contour>:
  endbr64
  test   %edi,%edi
  jle    L35
  test   %edx,%edx
  jg     L136
  lea    -0x1(%rdi),%eax
  mov    $0xffffffff,%ecx
  lea    0x4(%rsi,%rax,4),%rdi
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %eax,%edx
  sub    %ecx,%edx
  mov    %eax,%ecx
  add    $0x100,%edx
  mov    %edx,(%rsi)
L76:
  add    $0x4,%rsi
  cmp    %rdi,%rsi
  je     L47
L78:
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L76
  cmp    $0xfffffc18,%eax
  je     L76
  test   %ecx,%ecx
  jns    L29
  movl   $0xffffffff,(%rsi)
  add    $0x4,%rsi
  mov    %eax,%ecx
  cmp    %rdi,%rsi
  jne    L78
L47:
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  ret
  nopl   0x0(%rax)
L136:
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r12
  push   %rbp
  mov    $0xffffffff,%eax
  push   %rbx
  mov    %rsi,%rbx
  jmp    L39
  xchg   %ax,%ax
L73:
  mov    %ebp,%edi
  sub    %eax,%edi
  mov    %edi,(%rbx)
  call   <quantize5@plt>
  add    $0x100,%eax
  mov    %eax,(%rbx)
  mov    %ebp,%eax
L23:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L19
L39:
  mov    (%rbx),%ebp
  cmp    $0xfffffc18,%ebp
  je     L23
  test   %ebp,%ebp
  je     L23
  test   %eax,%eax
  jns    L73
  movl   $0xffffffff,(%rbx)
  add    $0x4,%rbx
  mov    %ebp,%eax
  cmp    %r12,%rbx
  jne    L39
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void compute_pitch_contour(int nnotes, int *midipitch, int qntflag) {
  int lastpitch, newpitch;
  int i;
  lastpitch = -1;
  for (i = 0; i < nnotes; i++) {
    if (midipitch[i] == -1000 || midipitch[i] == 0)
      continue;
    if (lastpitch < 0) {
      lastpitch = midipitch[i];
      midipitch[i] = -1;
      continue;
    } else {
      newpitch = midipitch[i];
      midipitch[i] = midipitch[i] - lastpitch;
      lastpitch = newpitch;
      if (qntflag > 0)
        midipitch[i] = quantize5(midipitch[i]);
      midipitch[i] += 256;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x61000(%rsp),%r11
L34:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L34
  sub    $0xf60,%rsp
  mov    %rdi,-0x61f58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x61f58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x61f44(%rbp)
  movl   $0x0,-0x61f4c(%rbp)
  movl   $0xffffffff,-0x61f48(%rbp)
  movl   $0x0,-0x61f50(%rbp)
  jmp    L44
L24:
  mov    -0x61f50(%rbp),%eax
  cltq
  movl   $0xffffffff,-0x61f40(%rbp,%rax,4)
  addl   $0x1,-0x61f50(%rbp)
L44:
  cmpl   $0xff,-0x61f50(%rbp)
  jle    L24
  movl   $0x0,-0x61f50(%rbp)
  jmp    L36
L17:
  mov    -0x61f50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x61f58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x61f40(%rbp,%rax,4),%edx
  mov    -0x61f50(%rbp),%eax
  cltq
  mov    %edx,-0x61a90(%rbp,%rax,4)
  mov    -0x61f50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x61f58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x61f50(%rbp),%edx
  mov    %edx,-0x61f40(%rbp,%rax,4)
  mov    -0x61f50(%rbp),%eax
  cltq
  mov    -0x61a90(%rbp,%rax,4),%eax
  mov    -0x61f48(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x61f48(%rbp)
  mov    -0x61f50(%rbp),%eax
  sub    -0x61f48(%rbp),%eax
  cmp    %eax,-0x61f4c(%rbp)
  jge    L55
  mov    -0x61f50(%rbp),%eax
  sub    -0x61f48(%rbp),%eax
  mov    %eax,-0x61f4c(%rbp)
L55:
  addl   $0x1,-0x61f50(%rbp)
L36:
  mov    -0x61f50(%rbp),%eax
  cmp    -0x61f44(%rbp),%eax
  jl     L17
  mov    -0x61f4c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int i;
  int len = strlen(s);
  int abc[300];
  int toleft[100000];
  int ans = 0, tail = -1;
  for (i = 0; i < 256; i++)
    abc[i] = -1;
  for (i = 0; i < len; i++) {
    toleft[i] = abc[s[i]];
    abc[s[i]] = i;
    tail = tail > toleft[i] ? tail : toleft[i];
    if (i - tail > ans) {
      ans = i - tail;
    }
  }
  return ans;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbx
  sub    $0x4c0,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rdx
  lea    0x400(%rsp),%rcx
L26:
  movl   $0xffffffff,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L26
  test   %eax,%eax
  jle    L8
  mov    %eax,%r8d
  mov    $0x0,%eax
  mov    $0xffffffff,%edx
  mov    $0x0,%ecx
L40:
  movsbq (%rbx,%rax,1),%rdi
  mov    (%rsp,%rdi,4),%esi
  mov    %eax,(%rsp,%rdi,4)
  cmp    %esi,%edx
  cmovl  %esi,%edx
  mov    %eax,%esi
  sub    %edx,%esi
  cmp    %esi,%ecx
  cmovl  %esi,%ecx
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L40
L19:
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %ecx,%eax
  add    $0x4c0,%rsp
  pop    %rbx
  ret
L8:
  mov    $0x0,%ecx
  jmp    L19
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int i;
  int len = strlen(s);
  int abc[300];
  int toleft[100000];
  int ans = 0, tail = -1;
  for (i = 0; i < 256; i++)
    abc[i] = -1;
  for (i = 0; i < len; i++) {
    toleft[i] = abc[s[i]];
    abc[s[i]] = i;
    tail = tail > toleft[i] ? tail : toleft[i];
    if (i - tail > ans) {
      ans = i - tail;
    }
  }
  return ans;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x4c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  mov    $0x80,%ecx
  mov    %eax,%edx
  mov    %rsi,%rdi
  mov    $0xffffffffffffffff,%rax
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L30
  movslq %edx,%rdi
  xor    %eax,%eax
  mov    $0xffffffff,%edx
  xor    %r8d,%r8d
  nop
L17:
  movsbq (%rbx,%rax,1),%rsi
  mov    (%rsp,%rsi,4),%ecx
  mov    %eax,(%rsp,%rsi,4)
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %eax,%ecx
  sub    %edx,%ecx
  cmp    %ecx,%r8d
  cmovl  %ecx,%r8d
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L17
L7:
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x4c0,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L30:
  xor    %r8d,%r8d
  jmp    L7
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int i;
  int len = strlen(s);
  int abc[300];
  int toleft[100000];
  int ans = 0, tail = -1;
  for (i = 0; i < 256; i++)
    abc[i] = -1;
  for (i = 0; i < len; i++) {
    toleft[i] = abc[s[i]];
    abc[s[i]] = i;
    tail = tail > toleft[i] ? tail : toleft[i];
    if (i - tail > ans) {
      ans = i - tail;
    }
  }
  return ans;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x4c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  mov    $0x80,%ecx
  mov    %eax,%edx
  mov    %rsi,%rdi
  mov    $0xffffffffffffffff,%rax
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L3
  movslq %edx,%rdi
  xor    %eax,%eax
  mov    $0xffffffff,%edx
  xor    %r8d,%r8d
  nop
L32:
  movsbq (%rbx,%rax,1),%rsi
  mov    (%rsp,%rsi,4),%ecx
  mov    %eax,(%rsp,%rsi,4)
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %eax,%ecx
  sub    %edx,%ecx
  cmp    %ecx,%r8d
  cmovl  %ecx,%r8d
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L32
L15:
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x4c0,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L3:
  xor    %r8d,%r8d
  jmp    L15
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int i;
  int len = strlen(s);
  int abc[300];
  int toleft[100000];
  int ans = 0, tail = -1;
  for (i = 0; i < 256; i++)
    abc[i] = -1;
  for (i = 0; i < len; i++) {
    toleft[i] = abc[s[i]];
    abc[s[i]] = i;
    tail = tail > toleft[i] ? tail : toleft[i];
    if (i - tail > ans) {
      ans = i - tail;
    }
  }
  return ans;
}
```
user: What is the c source code of the assembly code below?

```asm
<dt_days_in_quarter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L24
  cmpl   $0x4,-0x8(%rbp)
  jle    L2
L24:
  mov    $0x0,%eax
  jmp    L15
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <dt_leap_year@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%eax
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: 

assistant: ```c
int dt_days_in_quarter(int y, int q) {
  static const int days_in_quarter[2][5] = {{0, 90, 91, 92, 92}, {0, 91, 91, 92, 92}};
  if (q < 1 || q > 4)
    return 0;
  return days_in_quarter[dt_leap_year(y)][q];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dt_days_in_quarter>:
  endbr64
  lea    -0x1(%rsi),%edx
  mov    $0x0,%eax
  cmp    $0x3,%edx
  jbe    L3
  ret
L3:
  push   %rbx
  mov    %esi,%ebx
  call   <dt_leap_year@plt>
  movslq %ebx,%rbx
  lea    (%rax,%rax,4),%rax
  add    %rbx,%rax
  lea    D4(%rip),%rdx
  mov    (%rdx,%rax,4),%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: 

assistant: ```c
int dt_days_in_quarter(int y, int q) {
  static const int days_in_quarter[2][5] = {{0, 90, 91, 92, 92}, {0, 91, 91, 92, 92}};
  if (q < 1 || q > 4)
    return 0;
  return days_in_quarter[dt_leap_year(y)][q];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dt_days_in_quarter>:
  endbr64
  push   %rbx
  movslq %esi,%rbx
  xor    %eax,%eax
  lea    -0x1(%rbx),%edx
  cmp    $0x3,%edx
  jbe    L0
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  call   <dt_leap_year@plt>
  lea    D7(%rip),%rdx
  lea    (%rax,%rax,4),%rax
  add    %rbx,%rax
  pop    %rbx
  mov    (%rdx,%rax,4),%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: 

assistant: ```c
int dt_days_in_quarter(int y, int q) {
  static const int days_in_quarter[2][5] = {{0, 90, 91, 92, 92}, {0, 91, 91, 92, 92}};
  if (q < 1 || q > 4)
    return 0;
  return days_in_quarter[dt_leap_year(y)][q];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dt_days_in_quarter>:
  endbr64
  push   %rbx
  movslq %esi,%rbx
  xor    %eax,%eax
  lea    -0x1(%rbx),%edx
  cmp    $0x3,%edx
  jbe    L1
  pop    %rbx
  ret
  nopl   0x0(%rax)
L1:
  call   <dt_leap_year@plt>
  lea    D4(%rip),%rdx
  lea    (%rax,%rax,4),%rax
  add    %rbx,%rax
  pop    %rbx
  mov    (%rdx,%rax,4),%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: string

tool: 

assistant: ```c
int dt_days_in_quarter(int y, int q) {
  static const int days_in_quarter[2][5] = {{0, 90, 91, 92, 92}, {0, 91, 91, 92, 92}};
  if (q < 1 || q > 4)
    return 0;
  return days_in_quarter[dt_leap_year(y)][q];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D17
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string

tool: D35: Enter a word to be reversed : 

tool: D4: %s

tool: D17: Entered Word :: %s 


tool: D29: Reversed  Word :: %s 


assistant: ```c
int main() {
  char str[200];
  printf("Enter a word to be reversed : ");
  scanf("%s", str);
  printf("Entered Word :: %s \n", str);
  reverse(str);
  printf("Reversed  Word :: %s \n", str);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D23
data_type: string
name: parse_data
arguments: tag: D34
data_type: string
name: parse_data
arguments: tag: D5
data_type: string

tool: D15: Enter a word to be reversed : 

tool: D23: %s

tool: D34: Entered Word :: %s 


tool: D5: Reversed  Word :: %s 


assistant: ```c
int main() {
  char str[200];
  printf("Enter a word to be reversed : ");
  scanf("%s", str);
  printf("Entered Word :: %s \n", str);
  reverse(str);
  printf("Reversed  Word :: %s \n", str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <reverse@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D33
type: string
name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D25
type: string
name: parse_data
arguments: label: D19
type: string

tool: D33: Enter a word to be reversed : 

tool: D16: %s

tool: D25: Entered Word :: %s 


tool: D19: Reversed  Word :: %s 


assistant: ```c
int main() {
  char str[200];
  printf("Enter a word to be reversed : ");
  scanf("%s", str);
  printf("Entered Word :: %s \n", str);
  reverse(str);
  printf("Reversed  Word :: %s \n", str);
  return 0;
}
```