ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<test_MatrixLog3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D50(%rip),%xmm0
  movsd  %xmm0,-0xa8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0xa0(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x98(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x90(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x88(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x80(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x78(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x70(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x68(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x60(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x50(%rbp),%rdx
  lea    -0xa0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <MatrixLog3@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xac(%rbp)
  jmp    L4
L18:
  mov    -0xac(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rbp,%rax
  sub    $0x40,%rax
  movsd  (%rax),%xmm1
  mov    -0xac(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rbp,%rax
  sub    $0x48,%rax
  movsd  (%rax),%xmm0
  mov    -0xac(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rbp,%rax
  sub    $0x50,%rax
  mov    (%rax),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  addl   $0x1,-0xac(%rbp)
L4:
  cmpl   $0x2,-0xac(%rbp)
  jle    L18
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D50
type: byte[8]
name: parse_data
arguments: data_label: D1
type: byte[8]
name: parse_data
arguments: data_label: D30
type: string
name: parse_data
arguments: data_label: D43
type: string

tool: {"D50": [0x65,0x73,0x2d,0x38,0x52,0xc1,0xe0,0x3f]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D30: so3Mat:

tool: D43: %lf %lf %lf


assistant: ```c
void test_MatrixLog3() {
  double theta = 30 * 3.14159265358979323846 / 180;
  double R[3][3] = {0, 0, 1, 1, 0, 0, 0, 1, 0};
  double so3Mat[3][3] = {0};
  MatrixLog3(R, so3Mat);
  printf("so3Mat:\n");
  int i;
  for (i = 0; i < 3; i++) {
    printf("%lf %lf %lf\n", so3Mat[i][0], so3Mat[i][1], so3Mat[i][2]);
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_MatrixLog3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movsd  %xmm0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  lea    0x50(%rsp),%rbx
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <MatrixLog3@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    0x98(%rsp),%r12
  lea    D3(%rip),%rbp
L15:
  movsd  0x10(%rbx),%xmm2
  movsd  0x8(%rbx),%xmm1
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  add    $0x18,%rbx
  cmp    %r12,%rbx
  jne    L15
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type: byte[8]
name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D3
type: string

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D17: so3Mat:

tool: D3: %lf %lf %lf


assistant: ```c
void test_MatrixLog3() {
  double theta = 30 * 3.14159265358979323846 / 180;
  double R[3][3] = {0, 0, 1, 1, 0, 0, 0, 1, 0};
  double so3Mat[3][3] = {0};
  MatrixLog3(R, so3Mat);
  printf("so3Mat:\n");
  int i;
  for (i = 0; i < 3; i++) {
    printf("%lf %lf %lf\n", so3Mat[i][0], so3Mat[i][1], so3Mat[i][2]);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_MatrixLog3>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0xa0,%rsp
  movsd  D24(%rip),%xmm0
  lea    0x50(%rsp),%rbx
  mov    %rsp,%rdi
  lea    0x98(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rbx,%rsi
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm0,0x38(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x90(%rsp)
  call   <MatrixLog3@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
L6:
  movsd  0x10(%rbx),%xmm2
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x18,%rbx
  movsd  -0x10(%rbx),%xmm1
  mov    $0x3,%eax
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D24
data_type: byte[8]
name: read_data
arguments: data_label: D11
data_type: string

tool: D5: %lf %lf %lf


tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D11: so3Mat:

assistant: ```c
void test_MatrixLog3() {
  double theta = 30 * 3.14159265358979323846 / 180;
  double R[3][3] = {0, 0, 1, 1, 0, 0, 0, 1, 0};
  double so3Mat[3][3] = {0};
  MatrixLog3(R, so3Mat);
  printf("so3Mat:\n");
  int i;
  for (i = 0; i < 3; i++) {
    printf("%lf %lf %lf\n", so3Mat[i][0], so3Mat[i][1], so3Mat[i][2]);
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_MatrixLog3>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0xa0,%rsp
  movapd D14(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  lea    0x50(%rsp),%rbx
  mov    %rsp,%rdi
  movaps %xmm0,0x20(%rsp)
  mov    %rbx,%rsi
  movapd D8(%rip),%xmm0
  lea    0x98(%rsp),%r12
  movaps %xmm1,0x10(%rsp)
  movaps %xmm0,0x30(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x90(%rsp)
  call   <MatrixLog3@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
L9:
  movsd  0x10(%rbx),%xmm2
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x18,%rbx
  movsd  -0x10(%rbx),%xmm1
  mov    $0x3,%eax
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L9
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D14
type_infered: byte[16]
name: read_data
arguments: data_label: D8
type_infered: byte[16]
name: read_data
arguments: data_label: D29
type_infered: string

tool: D0: %lf %lf %lf


tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D29: so3Mat:

assistant: ```c
void test_MatrixLog3() {
  double theta = 30 * 3.14159265358979323846 / 180;
  double R[3][3] = {0, 0, 1, 1, 0, 0, 0, 1, 0};
  double so3Mat[3][3] = {0};
  MatrixLog3(R, so3Mat);
  printf("so3Mat:\n");
  int i;
  for (i = 0; i < 3; i++) {
    printf("%lf %lf %lf\n", so3Mat[i][0], so3Mat[i][1], so3Mat[i][2]);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x136ff696,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    0x401d24e5(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
        state[0UL] = state[local1] * state[local1];
      } else {
        state[0UL] += state[0UL];
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy12;
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1075651813UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x538d1b7b,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
        state[0UL] = state[local1] * state[local1];
      } else {
        state[0UL] += state[0UL];
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy12;
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1075651813UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x538d1b7b,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
        state[0UL] = state[local1] * state[local1];
      } else {
        state[0UL] += state[0UL];
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy12;
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1075651813UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x538d1b7b,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
        state[0UL] = state[local1] * state[local1];
      } else {
        state[0UL] += state[0UL];
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy12;
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1075651813UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L23
L5:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L5
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D1: %d

tool: D5: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int i, n, sum = 1;
  scanf("%d", &n);
  for (i = 1; i < n; i++) {
    sum = 2 * sum + 2;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    $0x1,%edx
  jle    L6
  mov    $0x1,%esi
  mov    $0x1,%eax
L3:
  lea    0x2(%rsi,%rsi,1),%esi
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L3
L10:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  mov    $0x1,%esi
  jmp    L10
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string

tool: D7: %d

tool: D6: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int i, n, sum = 1;
  scanf("%d", &n);
  for (i = 1; i < n; i++) {
    sum = 2 * sum + 2;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    $0x1,%esi
  cmp    $0x1,%edx
  jle    L5
  mov    $0x1,%eax
  nopl   0x0(%rax)
L22:
  add    $0x1,%eax
  lea    0x2(%rsi,%rsi,1),%esi
  cmp    %edx,%eax
  jne    L22
L5:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string

tool: D0: %d

tool: D7: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int i, n, sum = 1;
  scanf("%d", &n);
  for (i = 1; i < n; i++) {
    sum = 2 * sum + 2;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    $0x1,%esi
  cmp    $0x1,%edx
  jle    L27
  mov    $0x1,%eax
  nopl   0x0(%rax)
L16:
  add    $0x1,%eax
  lea    0x2(%rsi,%rsi,1),%esi
  cmp    %edx,%eax
  jne    L16
L27:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D7: %d

tool: D2: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int i, n, sum = 1;
  scanf("%d", &n);
  for (i = 1; i < n; i++) {
    sum = 2 * sum + 2;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<correct_det_by_minor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x7b,%edi
  call   <random_seed@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x9,%edi
  call   <uniform_01@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <det_by_minor@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x60(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0x50(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  -0x28(%rbp),%xmm3
  movsd  -0x18(%rbp),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x58(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0x48(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  -0x28(%rbp),%xmm3
  movsd  -0x20(%rbp),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x58(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm2
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  -0x30(%rbp),%xmm3
  movsd  -0x20(%rbp),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x58(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0x60(%rbp),%xmm0
  divsd  -0x58(%rbp),%xmm0
  movsd  D3(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L2
  mov    $0x1,%eax
  jmp    L7
L2:
  mov    $0x0,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: f64

tool: D3: 1

assistant: ```c
int correct_det_by_minor(void) {
  double a[9], det, check;
  random_seed(123);
  uniform_01(9, a);
  det = det_by_minor(a, 3);
  check = 0.;
  check += a[0] * (a[4] * a[8] - a[5] * a[7]);
  check -= a[1] * (a[3] * a[8] - a[5] * a[6]);
  check += a[2] * (a[3] * a[7] - a[4] * a[6]);
  if (fabs(det / check - 1.0) < 1e-10)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<correct_det_by_minor>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x7b,%edi
  call   <random_seed@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    $0x9,%edi
  call   <uniform_01@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <det_by_minor@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  0x40(%rsp),%xmm3
  movsd  0x28(%rsp),%xmm5
  movsd  0x38(%rsp),%xmm1
  movapd %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  movapd %xmm5,%xmm6
  mulsd  %xmm1,%xmm6
  subsd  %xmm6,%xmm2
  mulsd  (%rsp),%xmm2
  addsd  D11(%rip),%xmm2
  movsd  0x18(%rsp),%xmm7
  movsd  0x30(%rsp),%xmm6
  mulsd  %xmm7,%xmm3
  mulsd  %xmm6,%xmm5
  subsd  %xmm5,%xmm3
  mulsd  0x8(%rsp),%xmm3
  subsd  %xmm3,%xmm2
  mulsd  %xmm7,%xmm1
  mulsd  %xmm6,%xmm4
  subsd  %xmm4,%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  subsd  D16(%rip),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  setle  %al
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x50,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D11
type: f64
name: parse_data
arguments: label: D16
type: f64

tool: D11: 0

tool: D16: 1

assistant: ```c
int correct_det_by_minor(void) {
  double a[9], det, check;
  random_seed(123);
  uniform_01(9, a);
  det = det_by_minor(a, 3);
  check = 0.;
  check += a[0] * (a[4] * a[8] - a[5] * a[7]);
  check -= a[1] * (a[3] * a[8] - a[5] * a[6]);
  check += a[2] * (a[3] * a[7] - a[4] * a[6]);
  if (fabs(det / check - 1.0) < 1e-10)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<correct_det_by_minor>:
  endbr64
  push   %rbp
  mov    $0x7b,%edi
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <random_seed@plt>
  mov    %rbp,%rsi
  mov    $0x9,%edi
  call   <uniform_01@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <det_by_minor@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm5
  movsd  0x40(%rsp),%xmm3
  movsd  0x38(%rsp),%xmm1
  movapd %xmm4,%xmm2
  movapd %xmm5,%xmm6
  movsd  0x18(%rsp),%xmm7
  mulsd  %xmm1,%xmm6
  mulsd  %xmm3,%xmm2
  mulsd  %xmm7,%xmm3
  mulsd  %xmm7,%xmm1
  subsd  %xmm6,%xmm2
  movsd  0x30(%rsp),%xmm6
  mulsd  (%rsp),%xmm2
  addsd  D14(%rip),%xmm2
  mulsd  %xmm6,%xmm5
  mulsd  %xmm6,%xmm4
  subsd  %xmm5,%xmm3
  mulsd  0x8(%rsp),%xmm3
  subsd  %xmm4,%xmm1
  mulsd  0x10(%rsp),%xmm1
  subsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  subsd  D15(%rip),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  setle  %al
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x50,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_guessed: f64
name: disassemble_data
arguments: data_tag: D15
type_guessed: f64

tool: D14: 0

tool: D15: 1

assistant: ```c
int correct_det_by_minor(void) {
  double a[9], det, check;
  random_seed(123);
  uniform_01(9, a);
  det = det_by_minor(a, 3);
  check = 0.;
  check += a[0] * (a[4] * a[8] - a[5] * a[7]);
  check -= a[1] * (a[3] * a[8] - a[5] * a[6]);
  check += a[2] * (a[3] * a[7] - a[4] * a[6]);
  if (fabs(det / check - 1.0) < 1e-10)
    return 1;
  return 0;
}
```