user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D58(%rip),%rdi
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D73(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  js     L33
  lea    D75(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L93
  add    $0x1,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    $0x4,%esi
  mov    %rax,%r14
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edi
  call   <calloc@plt>
  lea    D36(%rip),%rdi
  mov    %rax,%r13
  call   <puts@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L117
  lea    0x4(%r14),%rbx
  mov    $0x1,%ebp
  jmp    L83
  xchg   %ax,%ax
L70:
  cmp    (%rsp),%eax
  jg     L32
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,0x4(%rsp)
  jl     L117
L83:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jns    L70
L32:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  jmp    L29
L93:
  lea    D106(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  jmp    L29
L117:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <countingSort@plt>
  lea    D67(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L52
  add    $0x4,%r13
  mov    $0x1,%ebp
  lea    D56(%rip),%r12
  nopl   0x0(%rax)
L23:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %ebp,0x4(%rsp)
  jge    L23
L52:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  jmp    L29
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D58
datatype: string
name: extract_symbolic_data
arguments: label: D15
datatype: string
name: extract_symbolic_data
arguments: label: D33
datatype: string
name: extract_symbolic_data
arguments: label: D73
datatype: string
name: extract_symbolic_data
arguments: label: D75
datatype: string
name: extract_symbolic_data
arguments: label: D36
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D106
datatype: string
name: extract_symbolic_data
arguments: label: D67
datatype: string
name: extract_symbolic_data
arguments: label: D56
datatype: string

tool: D58: Counting Sort 

tool: D15: %d

tool: D33: Range of Input ( 0 - k ) 

tool: D73: k = 

tool: D75: Total Elements : 

tool: D36: Unsorted Input 

tool: D13: Input Out of Range! 

tool: D23: Incorrect Range 

tool: D106: Invalid Input 

tool: D67: Sorted Output 

tool: D56: %d 


assistant: ```c
int main() {
  printf("Counting Sort \n");
  printf("\n");
  int i, k, n;
  printf("Range of Input ( 0 - k ) \n");
  printf("k = ");
  scanf("%d", &k);
  printf("\n");
  if (k < 0) {
    printf("Incorrect Range \n");
    printf("\n");
    return 1;
  }
  printf("Total Elements : ");
  scanf("%d", &n);
  printf("\n");
  if (n < 1) {
    printf("Invalid Input \n");
    printf("\n");
    return 1;
  }
  int *A = (int *)calloc((n + 1), sizeof(int));
  int *B = (int *)calloc((n + 1), sizeof(int));
  printf("Unsorted Input \n");
  for (i = 1; i <= n; i++) {
    scanf("%d", (A + i));
    if (*(A + i) < 0 || *(A + i) > k) {
      printf("Input Out of Range! \n");
      printf("\n");
      return 1;
    }
  }
  printf("\n");
  countingSort(A, B, k, n);
  printf("Sorted Output \n");
  for (i = 1; i <= n; i++) {
    printf("%d \n", *(B + i));
  }
  printf("\n");
  return 0;
}
```