ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D60(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D75(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  jbe    L14
  lea    D35(%rip),%rbx
L82:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  ja     L82
L14:
  cmp    $0x5a,%eax
  jg     L81
  cmp    $0x4f,%eax
  jg     L54
  cmp    $0x45,%eax
  jg     L83
  mov    $0x45,%esi
  cmp    $0x3b,%eax
  jle    L0
  mov    $0x44,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x44,%esi
  jmp    L0
L81:
  mov    $0x41,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x41,%esi
L0:
  movsbl %sil,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L54:
  mov    $0x42,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x42,%esi
  jmp    L0
L83:
  mov    $0x43,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x43,%esi
  jmp    L0
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D60
type_guessed: string
name: retrieve_data
arguments: tag: D75
type_guessed: string
name: retrieve_data
arguments: tag: D35
type_guessed: string
name: retrieve_data
arguments: tag: D34
type_guessed: string

tool: D60: input the score:

tool: D75: %f

tool: D35: error!

tool: D34: the grade is %c


assistant: ```c
int main() {
  int i;
  char n;
  printf("input the score:");
  scanf("%f", &i);
  while (i > 100 || i < 0) {
    printf("error!");
  }
  if (i > 90) {
    n = 'A';
    printf("the grade is %c\n", n);
  } else if (i >= 80) {
    n = 'B';
    printf("the grade is %c\n", n);
  } else if (i >= 70) {
    n = 'C';
    printf("the grade is %c\n", n);
  } else if (i >= 60) {
    n = 'D';
    printf("the grade is %c\n", n);
  } else
    n = 'E';
  printf("the grade is %c\n", n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D63(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  jbe    L69
  lea    D42(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  ja     L4
L69:
  cmp    $0x5a,%eax
  jg     L41
  cmp    $0x4f,%eax
  jg     L80
  cmp    $0x45,%eax
  jg     L55
  mov    $0x45,%esi
  lea    D1(%rip),%rbp
  cmp    $0x3b,%eax
  jg     L97
L25:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L80:
  lea    D1(%rip),%rbp
  mov    $0x42,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x42,%esi
  jmp    L25
L41:
  lea    D1(%rip),%rbp
  mov    $0x41,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  jmp    L25
L55:
  lea    D1(%rip),%rbp
  mov    $0x43,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x43,%esi
  jmp    L25
L97:
  mov    $0x44,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x44,%esi
  jmp    L25
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string
name: parse_data
arguments: data_tag: D63
type_infered: string
name: parse_data
arguments: data_tag: D42
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D5: input the score:

tool: D63: %f

tool: D42: error!

tool: D1: the grade is %c


assistant: ```c
int main() {
  int i;
  char n;
  printf("input the score:");
  scanf("%f", &i);
  while (i > 100 || i < 0) {
    printf("error!");
  }
  if (i > 90) {
    n = 'A';
    printf("the grade is %c\n", n);
  } else if (i >= 80) {
    n = 'B';
    printf("the grade is %c\n", n);
  } else if (i >= 70) {
    n = 'C';
    printf("the grade is %c\n", n);
  } else if (i >= 60) {
    n = 'D';
    printf("the grade is %c\n", n);
  } else
    n = 'E';
  printf("the grade is %c\n", n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D55(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D66(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  jbe    L56
  lea    D33(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L67:
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  ja     L67
L56:
  cmp    $0x5a,%eax
  jg     L88
  cmp    $0x4f,%eax
  jg     L54
  cmp    $0x45,%eax
  jg     L97
  mov    $0x45,%esi
  lea    D42(%rip),%rbp
  cmp    $0x3b,%eax
  jg     L51
L10:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L54:
  lea    D42(%rip),%rbp
  mov    $0x42,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x42,%esi
  jmp    L10
L88:
  lea    D42(%rip),%rbp
  mov    $0x41,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  jmp    L10
L97:
  lea    D42(%rip),%rbp
  mov    $0x43,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x43,%esi
  jmp    L10
L51:
  mov    $0x44,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x44,%esi
  jmp    L10
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D55
data_type: string
name: read_data
arguments: data_tag: D66
data_type: string
name: read_data
arguments: data_tag: D33
data_type: string
name: read_data
arguments: data_tag: D42
data_type: string

tool: D55: input the score:

tool: D66: %f

tool: D33: error!

tool: D42: the grade is %c


assistant: ```c
int main() {
  int i;
  char n;
  printf("input the score:");
  scanf("%f", &i);
  while (i > 100 || i < 0) {
    printf("error!");
  }
  if (i > 90) {
    n = 'A';
    printf("the grade is %c\n", n);
  } else if (i >= 80) {
    n = 'B';
    printf("the grade is %c\n", n);
  } else if (i >= 70) {
    n = 'C';
    printf("the grade is %c\n", n);
  } else if (i >= 60) {
    n = 'D';
    printf("the grade is %c\n", n);
  } else
    n = 'E';
  printf("the grade is %c\n", n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movl   $0x1,-0x70(%rbp)
  movl   $0x2,-0x6c(%rbp)
  movl   $0x3,-0x68(%rbp)
  movl   $0x4,-0x64(%rbp)
  movl   $0x5,-0x60(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L64
L26:
  mov    -0x78(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%edx
  mov    -0x78(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x78(%rbp)
L64:
  cmpl   $0x9,-0x78(%rbp)
  jle    L26
  movl   $0x0,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x3,-0x34(%rbp)
  movl   $0x4,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0xc,-0x28(%rbp)
  movl   $0xd,-0x24(%rbp)
  movl   $0x2a,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0x0,-0x74(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L5
L67:
  mov    -0x78(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  add    %eax,-0x74(%rbp)
  addl   $0x1,-0x78(%rbp)
L5:
  cmpl   $0x9,-0x78(%rbp)
  jle    L67
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x74(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x20727564,-0xe(%rbp)
  movw   $0x7474,-0xa(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L62
L4:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0xe(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x78(%rbp)
L62:
  lea    -0xe(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x78(%rbp)
  jl     L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D5
type: f64
name: retrieve_data
arguments: label: D25
type: string
name: retrieve_data
arguments: label: D11
type: string

tool: D12: Am Index %d liegt der Wert %d


tool: D5: 10

tool: D25: Durchschnitt: %f


tool: D11: %c

assistant: ```c
int main() {
  int i = 0;
  int arr1[10] = {1, 2, 3, 4, 5};
  for (i = 0; i < 10; i++) {
    printf("Am Index %d liegt der Wert %d\n", i, arr1[i]);
  }
  int arr[10] = {0, 1, 2, 3, 4, 5, 12, 13, 42, 10};
  int sum = 0;
  for (i = 0; i < 10; i++) {
    sum = sum + arr[i];
  }
  printf("Durchschnitt: %f\n", sum / 10.0);
  char arr3[] = {'d', 'u', 'r', ' ', 't', 't'};
  for (i = 0; i < strlen(arr3); i++) {
    printf("%c", arr3[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  mov    $0x0,%ebx
  lea    D24(%rip),%rbp
L42:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L42
  movl   $0x0,0x30(%rsp)
  movl   $0x1,0x34(%rsp)
  movl   $0x2,0x38(%rsp)
  movl   $0x3,0x3c(%rsp)
  movl   $0x4,0x40(%rsp)
  movl   $0x5,0x44(%rsp)
  movl   $0xc,0x48(%rsp)
  movl   $0xd,0x4c(%rsp)
  movl   $0x2a,0x50(%rsp)
  movl   $0xa,0x54(%rsp)
  lea    0x30(%rsp),%rax
  lea    0x58(%rsp),%rcx
  mov    $0x0,%edx
L1:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  D36(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  movsbl %sil,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x20727564,0x62(%rsp)
  movw   $0x7474,0x66(%rsp)
  mov    $0x0,%ebx
  lea    D35(%rip),%rbp
  jmp    L15
L25:
  movsbl 0x62(%rsp,%rbx,1),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
L15:
  lea    0x62(%rsp),%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L25
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D24
type_infered: string
name: extract_symbolic_data
arguments: data_label: D36
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D35
type_infered: string

tool: D24: Am Index %d liegt der Wert %d


tool: D36: 10

tool: D19: Durchschnitt: %f


tool: D35: %c

assistant: ```c
int main() {
  int i = 0;
  int arr1[10] = {1, 2, 3, 4, 5};
  for (i = 0; i < 10; i++) {
    printf("Am Index %d liegt der Wert %d\n", i, arr1[i]);
  }
  int arr[10] = {0, 1, 2, 3, 4, 5, 12, 13, 42, 10};
  int sum = 0;
  for (i = 0; i < 10; i++) {
    sum = sum + arr[i];
  }
  printf("Durchschnitt: %f\n", sum / 10.0);
  char arr3[] = {'d', 'u', 'r', ' ', 't', 't'};
  for (i = 0; i < strlen(arr3); i++) {
    printf("%c", arr3[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x1,%edx
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  jmp    L36
  xchg   %ax,%ax
L62:
  mov    (%rsp,%rbx,4),%edx
L36:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L62
  movabs $0x300000002,%rax
  movl   $0x1,0x34(%rsp)
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rax,0x38(%rsp)
  lea    0x58(%rsp),%rsi
  movabs $0x500000004,%rax
  mov    %rax,0x40(%rsp)
  movabs $0xd0000000c,%rax
  mov    %rax,0x48(%rsp)
  movabs $0xa0000002a,%rax
  mov    %rax,0x50(%rsp)
  lea    0x34(%rsp),%rax
  jmp    L12
  nopl   (%rax)
L31:
  mov    (%rax),%ecx
  add    $0x4,%rax
L12:
  add    %ecx,%edx
  cmp    %rsi,%rax
  jne    L31
  pxor   %xmm0,%xmm0
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  cvtsi2sd %edx,%xmm0
  divsd  D13(%rip),%xmm0
  lea    0x62(%rsp),%rbp
  cvttsd2si %xmm0,%esi
  lea    D19(%rip),%r12
  movsbl %sil,%esi
  call   <printf@plt>
  mov    $0x7474,%eax
  movl   $0x20727564,0x62(%rsp)
  mov    %ax,0x66(%rsp)
  jmp    L63
  nopl   (%rax)
L1:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
L63:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L1
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
type_infered: string
name: unpack_data
arguments: label: D15
type_infered: string
name: unpack_data
arguments: label: D13
type_infered: f64
name: unpack_data
arguments: label: D19
type_infered: string

tool: D29: Am Index %d liegt der Wert %d


tool: D15: Durchschnitt: %f


tool: D13: 10

tool: D19: %c

assistant: ```c
int main() {
  int i = 0;
  int arr1[10] = {1, 2, 3, 4, 5};
  for (i = 0; i < 10; i++) {
    printf("Am Index %d liegt der Wert %d\n", i, arr1[i]);
  }
  int arr[10] = {0, 1, 2, 3, 4, 5, 12, 13, 42, 10};
  int sum = 0;
  for (i = 0; i < 10; i++) {
    sum = sum + arr[i];
  }
  printf("Durchschnitt: %f\n", sum / 10.0);
  char arr3[] = {'d', 'u', 'r', ' ', 't', 't'};
  for (i = 0; i < strlen(arr3); i++) {
    printf("%c", arr3[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D33(%rip),%xmm0
  mov    %rsp,%r12
  movq   $0x0,0x20(%rsp)
  movl   $0x5,0x10(%rsp)
  movaps %xmm0,(%rsp)
  xchg   %ax,%ax
L33:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L33
  mov    $0x9,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  mov    $0x7474,%eax
  movl   $0x20727564,0x32(%rsp)
  lea    0x32(%rsp),%rbp
  mov    %ax,0x36(%rsp)
  lea    D13(%rip),%r12
  jmp    L25
  nop
L10:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L10
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D33
data_type: byte[16]
name: disassemble_data
arguments: label: D20
data_type: string
name: disassemble_data
arguments: label: D13
data_type: string

tool: D2: Am Index %d liegt der Wert %d


tool: {"D33": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D20: Durchschnitt: %f


tool: D13: %c

assistant: ```c
int main() {
  int i = 0;
  int arr1[10] = {1, 2, 3, 4, 5};
  for (i = 0; i < 10; i++) {
    printf("Am Index %d liegt der Wert %d\n", i, arr1[i]);
  }
  int arr[10] = {0, 1, 2, 3, 4, 5, 12, 13, 42, 10};
  int sum = 0;
  for (i = 0; i < 10; i++) {
    sum = sum + arr[i];
  }
  printf("Durchschnitt: %f\n", sum / 10.0);
  char arr3[] = {'d', 'u', 'r', ' ', 't', 't'};
  for (i = 0; i < strlen(arr3); i++) {
    printf("%c", arr3[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<yxz_to_linear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movss  0x8(%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x8(%rbp),%xmm1
  movss  D35(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm2
  movss  D68(%rip),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movss  -0x4(%rbp),%xmm2
  movss  D37(%rip),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  movss  -0x8(%rbp),%xmm1
  movss  D40(%rip),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm2
  movss  D55(%rip),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  -0x4(%rbp),%xmm2
  movss  D17(%rip),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  movss  -0x8(%rbp),%xmm1
  movss  D59(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm2
  movss  D32(%rip),%xmm1
  mulss  %xmm1,%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x4(%rbp),%xmm2
  movss  D3(%rip),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D68
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D37
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D40
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D55
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D17
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D59
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D32
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D3
type_guessed: byte[4]

tool: {"D35": [0x02,0x64,0x4f,0x40]}

tool: {"D68": [0x55,0xc1,0xc4,0x3f]}

tool: {"D37": [0xfb,0x3f,0xff,0x3e]}

tool: {"D40": [0x29,0x21,0x78,0xbf]}

tool: {"D55": [0x79,0x20,0xf0,0x3f]}

tool: {"D17": [0xa0,0x36,0x2a,0x3d]}

tool: {"D59": [0x28,0xef,0x63,0x3d]}

tool: {"D32": [0xa6,0xf0,0x50,0x3e]}

tool: {"D3": [0xf8,0x55,0x87,0x3f]}

assistant: ```c
void yxz_to_linear(float *yxz) {
  const float Y = yxz[0];
  const float X = yxz[1];
  const float Z = yxz[2];
  yxz[2] = 3.240479f * X - 1.53715f * Y - 0.498535f * Z;
  yxz[1] = -0.969256f * X + 1.875991f * Y + 0.041556f * Z;
  yxz[0] = 0.055648f * X - 0.204043f * Y + 1.057311f * Z;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<yxz_to_linear>:
  endbr64
  movss  (%rdi),%xmm2
  movss  0x4(%rdi),%xmm0
  movss  0x8(%rdi),%xmm1
  movaps %xmm0,%xmm3
  mulss  D8(%rip),%xmm3
  movaps %xmm2,%xmm4
  mulss  D68(%rip),%xmm4
  subss  %xmm4,%xmm3
  movaps %xmm1,%xmm4
  mulss  D57(%rip),%xmm4
  subss  %xmm4,%xmm3
  movss  %xmm3,0x8(%rdi)
  movaps %xmm0,%xmm3
  mulss  D40(%rip),%xmm3
  movaps %xmm2,%xmm4
  mulss  D67(%rip),%xmm4
  addss  %xmm4,%xmm3
  movaps %xmm1,%xmm4
  mulss  D38(%rip),%xmm4
  addss  %xmm4,%xmm3
  movss  %xmm3,0x4(%rdi)
  mulss  D19(%rip),%xmm0
  mulss  D45(%rip),%xmm2
  subss  %xmm2,%xmm0
  mulss  D58(%rip),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: byte[4]
name: unpack_data
arguments: label: D68
datatype: byte[4]
name: unpack_data
arguments: label: D57
datatype: byte[4]
name: unpack_data
arguments: label: D40
datatype: byte[4]
name: unpack_data
arguments: label: D67
datatype: byte[4]
name: unpack_data
arguments: label: D38
datatype: byte[4]
name: unpack_data
arguments: label: D19
datatype: byte[4]
name: unpack_data
arguments: label: D45
datatype: byte[4]
name: unpack_data
arguments: label: D58
datatype: byte[4]

tool: {"D8": [0x02,0x64,0x4f,0x40]}

tool: {"D68": [0x55,0xc1,0xc4,0x3f]}

tool: {"D57": [0xfb,0x3f,0xff,0x3e]}

tool: {"D40": [0x29,0x21,0x78,0xbf]}

tool: {"D67": [0x79,0x20,0xf0,0x3f]}

tool: {"D38": [0xa0,0x36,0x2a,0x3d]}

tool: {"D19": [0x28,0xef,0x63,0x3d]}

tool: {"D45": [0xa6,0xf0,0x50,0x3e]}

tool: {"D58": [0xf8,0x55,0x87,0x3f]}

assistant: ```c
void yxz_to_linear(float *yxz) {
  const float Y = yxz[0];
  const float X = yxz[1];
  const float Z = yxz[2];
  yxz[2] = 3.240479f * X - 1.53715f * Y - 0.498535f * Z;
  yxz[1] = -0.969256f * X + 1.875991f * Y + 0.041556f * Z;
  yxz[0] = 0.055648f * X - 0.204043f * Y + 1.057311f * Z;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<yxz_to_linear>:
  endbr64
  movss  (%rdi),%xmm2
  movss  0x4(%rdi),%xmm0
  movss  D74(%rip),%xmm3
  movss  D18(%rip),%xmm4
  movss  0x8(%rdi),%xmm1
  mulss  %xmm2,%xmm4
  mulss  %xmm0,%xmm3
  subss  %xmm4,%xmm3
  movss  D42(%rip),%xmm4
  mulss  %xmm1,%xmm4
  subss  %xmm4,%xmm3
  movss  D3(%rip),%xmm4
  mulss  %xmm2,%xmm4
  movss  %xmm3,0x8(%rdi)
  movss  D61(%rip),%xmm3
  mulss  D7(%rip),%xmm2
  mulss  %xmm0,%xmm3
  mulss  D25(%rip),%xmm0
  addss  %xmm4,%xmm3
  movss  D57(%rip),%xmm4
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm4
  mulss  D56(%rip),%xmm1
  addss  %xmm4,%xmm3
  addss  %xmm1,%xmm0
  movss  %xmm3,0x4(%rdi)
  movss  %xmm0,(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D74
data_type: byte[4]
name: unpack_data
arguments: tag: D18
data_type: byte[4]
name: unpack_data
arguments: tag: D42
data_type: byte[4]
name: unpack_data
arguments: tag: D3
data_type: byte[4]
name: unpack_data
arguments: tag: D61
data_type: byte[4]
name: unpack_data
arguments: tag: D7
data_type: byte[4]
name: unpack_data
arguments: tag: D25
data_type: byte[4]
name: unpack_data
arguments: tag: D57
data_type: byte[4]
name: unpack_data
arguments: tag: D56
data_type: byte[4]

tool: {"D74": [0x02,0x64,0x4f,0x40]}

tool: {"D18": [0x55,0xc1,0xc4,0x3f]}

tool: {"D42": [0xfb,0x3f,0xff,0x3e]}

tool: {"D3": [0x79,0x20,0xf0,0x3f]}

tool: {"D61": [0x29,0x21,0x78,0xbf]}

tool: {"D7": [0xa6,0xf0,0x50,0x3e]}

tool: {"D25": [0x28,0xef,0x63,0x3d]}

tool: {"D57": [0xa0,0x36,0x2a,0x3d]}

tool: {"D56": [0xf8,0x55,0x87,0x3f]}

assistant: ```c
void yxz_to_linear(float *yxz) {
  const float Y = yxz[0];
  const float X = yxz[1];
  const float Z = yxz[2];
  yxz[2] = 3.240479f * X - 1.53715f * Y - 0.498535f * Z;
  yxz[1] = -0.969256f * X + 1.875991f * Y + 0.041556f * Z;
  yxz[0] = 0.055648f * X - 0.204043f * Y + 1.057311f * Z;
}
```