user: 这段汇编代码用C语言表示是什么样的:

```asm
<radixsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%edx
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  cmp    $0x1,%esi
  jle    L107
  lea    -0x2(%rsi),%eax
  lea    -0x1(%rsi),%ecx
  cmp    $0x2,%eax
  jbe    L114
  movd   %edx,%xmm3
  mov    %ecx,%edx
  lea    0x4(%rdi),%rax
  shr    $0x2,%edx
  pshufd $0x0,%xmm3,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x14(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L51:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rdx,%rax
  jne    L51
  movdqa %xmm2,%xmm1
  mov    %ecx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  movdqa %xmm1,%xmm0
  lea    0x1(%rsi),%eax
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movd   %xmm1,%edx
  cmp    %ecx,%esi
  je     L107
L103:
  mov    (%rsp),%rdi
  movslq %eax,%rcx
  mov    0xc(%rsp),%ebx
  lea    0x0(,%rcx,4),%rsi
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  lea    0x1(%rax),%ecx
  cmp    %ecx,%ebx
  jle    L107
  mov    0x4(%rdi,%rsi,1),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x2,%eax
  cmp    %eax,%ebx
  jle    L107
  mov    0x8(%rdi,%rsi,1),%eax
  cmp    %eax,%edx
  cmovl  %eax,%edx
L107:
  test   %edx,%edx
  je     L53
  xor    %esi,%esi
  nopl   0x0(%rax)
L62:
  movslq %edx,%rax
  mov    %edx,%ecx
  mov    %esi,%r14d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  lea    0x1(%rsi),%esi
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%edx
  jne    L62
  mov    0xc(%rsp),%eax
  mov    (%rsp),%rdi
  mov    $0xa,%ebx
  sub    $0x1,%eax
  lea    0x4(%rdi,%rax,4),%r13
  nopl   0x0(%rax)
L88:
  mov    0xc(%rsp),%eax
  mov    (%rsp),%r15
  test   %eax,%eax
  jle    L58
  nopl   0x0(%rax)
L25:
  mov    (%r15),%r9d
  mov    %rbp,%rdi
  add    $0x4,%r15
  lea    (%r9,%r9,4),%eax
  add    %eax,%eax
  cltd
  idiv   %ebx
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  mov    %r12,%rcx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %r9d,%edx
  mov    %eax,%esi
  call   <enqueue@plt>
  cmp    %r13,%r15
  jne    L25
L58:
  mov    (%rsp),%rdx
  lea    (%rbx,%rbx,4),%ebx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    %ebx,%ebx
  call   <dequeue@plt>
  sub    $0x1,%r14d
  jae    L88
L53:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L114:
  mov    $0x1,%eax
  jmp    L103
```

assistant: ```c
void radixsort(int *a, int n, int queue[][10], int *head) {
  int max = a[0], x, k = 10, i, temp;
  for (i = 1; i < n; i++) {
    if (max < a[i])
      max = a[i];
  }
  temp = max;
  max = 0;
  while (temp) {
    max = max + 1;
    temp = temp / 10;
  }
  while (max--) {
    for (i = 0; i < n; i++) {
      x = (a[i] * 10 / k) % 10;
      enqueue(queue, x, a[i], head);
    }
    k = k * 10;
    dequeue(queue, head, a);
  }
}
```